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+[
+  {
+    "id": "1",
+    "unit": "第一单元 长度单位",
+    "question_type": "选择题",
+    "difficulty": 0.94,
+    "question": "测量北京到杭州的铁路的长度一般用( )作单位。",
+    "options": [
+      "A. 分米",
+      "B. 米",
+      "C. 千米"
+    ],
+    "answer": "C",
+    "solution": "【分析】根据生活经验，对长度单位和数据大小的认识，可知测量铁路的长度，一般使用千米作单位.\n【详解】A。分米，较小长度单位，通常用于日常短距离测量，错误。B。米，较小长度单位，通常用于日常短距离测量，错误。C。千米，可知测量铁路的长度，正确。故答案为:C",
+    "knowledge_points": [
+      "长度单位的选择"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "2",
+    "unit": "第一单元 长度单位",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "一根木棍长 20 厘米,( )根这样的木棍连起来长 1 米。",
+    "options": [
+      "A. 3",
+      "B. 4",
+      "C. 5"
+    ],
+    "answer": "C",
+    "solution": "【分析】根据1米 = 100 厘米，先进行单位换算统一单位。再利用减法求出 100 里面有几个 20，有几个 20 就是需要几根木棍。由此即可解答.\n【详解】根据分析可得:100 - 20 = 80;80 - 20 = 60;60 - 20 = 40;40 - 20 = 20;20 - 20=0。共减去了 5 个 20，所以 100 里面有 5 个 20，即 5 根这样的木棍连起来长 1 米。故答案为:C",
+    "knowledge_points": [
+      "两位数与整十数的减法",
+      "厘米和米之间的进率与换算"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "3",
+    "unit": "第一单元 长度单位",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "测量篮球场的长时，用( )作单位比较合适。",
+    "options": [
+      "A. 厘米",
+      "B. 分米",
+      "C. 米"
+    ],
+    "answer": "C",
+    "solution": "【分析】根据生活经验，对长度单位认识可知,1米大约为小学生双臂伸展开的长度;1分米大约手掌的宽度;1厘米大约指甲盖的宽度，由此进行判断即可.\n【详解】根据分析可得：篮球场属于较大的场地，而厘米和分米属于较小的长度单位，所以用米作为测量单位更合适。故答案为:C",
+    "knowledge_points": [
+      "厘米的认识",
+      "米的认识",
+      "毫米和分米的认识",
+      "长度单位的选择"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "4",
+    "unit": "第一单元 长度单位",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "长方形有( )条线段。",
+    "options": [
+      "A. 4",
+      "B. 2",
+      "C. 无数"
+    ],
+    "answer": "A",
+    "solution": "【分析】线段有2个端点，中间是直直的线，长度可测量;长方形是长长方方的，有4条直直的边，对边相等，据此解答.\n【详解】由分析可知：长方形是由 4 条线段围成的图形。",
+    "knowledge_points": [
+      "长方形，正方形，三角形和圆的初步认识",
+      "线段的初步认识"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "5",
+    "unit": "第一单元 长度单位",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "![](images/0d07785d679b1560aadaecbb9e9a497082d0fd11362135406276fb1c40c7d9f0.jpg)左图中铅笔的长度( )。",
+    "options": [
+      "A. 等于 7 厘米",
+      "B. 小于7厘米",
+      "C. 大于 7 厘米"
+    ],
+    "answer": "C",
+    "solution": "【分析】尺子测量物体时应将0刻度移动到被测物体的边缘，将直尺与被测物体重合，再观察被测物体另一端的刻度即可。当0刻度与被测物体的边缘不对齐时，用末端的刻度值减去开始的刻度值即可。铅笔是倾斜着放的，实际长度比刻度尺上测出的长度大.\n【详解】上图中铅笔的长度大于7厘米。 故答案为:C",
+    "knowledge_points": [
+      "长度的测量方法"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "6",
+    "unit": "第一单元 长度单位",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "画一条长 4 厘米的线段，可以( )。",
+    "options": [
+      "A. 从刻度\"2\"画到刻度\"4\"",
+      "B. 从刻度\"1\"画到刻度 \"5\"",
+      "C. 从刻度\"0\"画到刻度\"6\"",
+      "D. 从刻度\"3\"画到刻度 \"8\""
+    ],
+    "answer": "B",
+    "solution": "【分析】尺子测量物体时应将0刻度移动到被测物体的边缘，将直尺与被测物体重合，再观察被测物体另一端的刻度即可。当0刻度与被测物体的边缘不对齐时，用末端的刻度值减去开始的刻度值即可。算出各选项表示的长度即可求解.\n【详解】A。4 - 2 = 2(厘米),不符合;B。5 - 1 = 4(厘米),符合;C。6 厘米，不符合;D。8 - 3 = 5(厘米),不符合。画一条长4厘米的线段，可以从刻度\"1\"画到刻度\"5\"。故答案为:B",
+    "knowledge_points": [
+      "长度的测量方法"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "7",
+    "unit": "第一单元 长度单位",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "小朋友身上的尺子，最接近 1 米的是( )。",
+    "options": [
+      "A. 一指宽",
+      "B. 一脚长",
+      "C. 双手张开的距离",
+      "D. 一步长"
+    ],
+    "answer": "C",
+    "solution": "【分析】根据生活经验，对长度单位和数据大小的认识可知：计量较长的物体用米作单位，二年级学生双臂展开的长度大约是1米，计量比较短的物体的长度，通常用厘米作单位，食指的宽大约是1厘米，由此分析各选项的长度选择即可.\n【详解】A。一指宽接近 1 厘米，不符合题意;B。小朋友一脚大约长 15 至 20 厘米，不符合题意;C。双手张开的距离大约是 1 米，符合题意;D。一步长大约是30至50厘米，不符合题意。所以最接近 1 米的是双手张开的距离。故答案为:C",
+    "knowledge_points": [
+      "厘米的认识",
+      "米的认识",
+      "长度的估测"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "8",
+    "unit": "第一单元 长度单位",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "适合用米尺进行测量的是( )。",
+    "options": [
+      "A. 数学书封面的长",
+      "B. 教室门的高度",
+      "C. 铅笔的长"
+    ],
+    "answer": "B",
+    "solution": "【分析】数学书封面的长和铅笔的长属于比较短，使用厘米尺或直尺即可测量。教室门的高度属于比较长，使用米尺更为合适。据此解决即可.\n【详解】由分析可知:A.\"数学书封面的长\"适合用厘米尺进行测量;B.\"教室门的高度\"适合用米尺进行测量;C.\"铅笔的长\"适合用厘米尺进行测量;故答案为:B",
+    "knowledge_points": [
+      "长度的估测"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "9",
+    "unit": "第一单元 长度单位",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "同样用\"庹\"量同一间教室的宽，老师量的结果是5庹，而小明量的结果是7庹，这是因为( )。",
+    "options": [
+      "A. 老师量错",
+      "B. 小明量错",
+      "C. 没有同一间教室",
+      "D. 测量标准不一样"
+    ],
+    "answer": "D",
+    "solution": "【分析】庹是指两臂左右平伸时两手之间的距离，人与人庹的长度不一定相等.\n【详解】同样用\"庹\"量同一间教室的宽，老师量的结果是5庹，而小明量的结果是7庹，这是因为测量标准不一样。故答案为:D",
+    "knowledge_points": [
+      "长度的测量方法",
+      "\"身体尺\"的认识及应用"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "10",
+    "unit": "第一单元 长度单位",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面大约是 10 米的是( )。",
+    "options": [
+      "A. 小树苗的高度",
+      "B. 公共汽车的长度",
+      "C. 铅笔的长度"
+    ],
+    "answer": "B",
+    "solution": "【分析】根据生活经验以及对长度单位和数据大小的认识，量比较短的物体的长度，通常用厘米作单位。食指的宽大约是1厘米。量比较长的物体，通常用米作单位。二年级学生双臂展开的长度大约是1米，据此结合题干要求进行解答即可.\n【详解】A。10米是大树的高度，小树苗的高度一般是一米多，不符合题意;B。公共汽车的长度大约是 10 米，符合题意;C。铅笔的长度一般是 10 厘米。故答案为:B",
+    "knowledge_points": [
+      "厘米的认识",
+      "米的认识",
+      "长度单位的选择"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "11",
+    "unit": "第一单元 长度单位",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "一条巨蟒身形巨大，长度较长，一条巨蟒的长度大约为( )。",
+    "options": [
+      "A. 80 厘米",
+      "B. 8 厘米",
+      "C. 80 米",
+      "D. 8 米"
+    ],
+    "answer": "D",
+    "solution": "【分析】根据生活常识，数据大小的认识和对不同长度单位的认识来选择正确答案。计量比较短的物体，可以用\"厘米\"作单位;计量比较长的物体，通常用\"米\"作单位;1 厘米大约是食指的宽度,1 米大约是二年级小朋友双臂伸开的长度，所以计量一条巨蟒的长度用\"米\"作单位比较合适;据此解答.\n【详解】根据分析可得:A。一条巨蟒的长度大约为80厘米，太短了，不合适;B。一条巨蟒的长度大约为8厘米，太短了，不合适;C。一条巨蟒的长度大约为80米，太长了，不合适;D。一条巨蟒的长度大约为8米，比较合适。故答案为:D",
+    "knowledge_points": [
+      "厘米的认识",
+      "米的认识",
+      "长度单位的选择"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "12",
+    "unit": "第一单元 长度单位",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "小东参加跑步比赛，他大约用了 11 秒跑了 60( )。",
+    "options": [
+      "A. 厘米",
+      "B. 米",
+      "C. 元"
+    ],
+    "answer": "B",
+    "solution": "【分析】根据生活经验以及对长度单位和数据大小的认识，量比较短的物体的长度，通常用厘米作单位。食指的宽大约是1厘米，量比较长的物体，通常用米作单位。二年级学生双臂展开的长度大约是1米，据此解答即可。元是货币单位.\n【详解】根据生活经验可知：小东参加跑步比赛，他大约用了11秒跑60米。故答案为:B",
+    "knowledge_points": [
+      "长度单位的选择"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "13",
+    "unit": "第一单元 长度单位",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面谁的长度可能是 2 米( )。",
+    "options": [
+      "A. 跳绳",
+      "B. 公交车",
+      "C. 数学书"
+    ],
+    "answer": "A",
+    "solution": "【分析】根据生活经验以及对长度单位和数据大小的认识，量比较短的物体的长度，通常用厘米作单位。食指的宽大约是1厘米，所以计量数学书长度用\"厘米\"作单位比较合适。量比较长的物体，通常用米作单位。二年级学生双臂展开的长度大约是1米，所以计量公交车的长度用\"米\"作单位比较合适。计量跳绳的长度用\"米\"作单位比较合适。据此解答即可.\n【详解】A。跳绳的长度可能是2米;B。公交车的长度大于2米;C。数学书的长度可能是20厘米。故答案为:A",
+    "knowledge_points": [
+      "厘米的认识",
+      "米的认识"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "14",
+    "unit": "第一单元 长度单位",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "躲猫猫是一种经典的儿童游戏。小华玩躲猫猫游戏，他藏在一棵高3米的小树后面，小华的身高大约是( )。",
+    "options": [
+      "A. 3 米",
+      "B. 1 米",
+      "C. 3 厘米"
+    ],
+    "answer": "B",
+    "solution": "【分析】根据实际可知，食指宽大约是1厘米，米尺的长度是 1 米。而通常情况下，小朋友的身高会远低于3米的小树;3厘米对于小朋友来说又太短，不符合实际;故，小华的身高大约是 1 米.\n【详解】A。3米与小树高度相同，不符合小朋友的身高实际情况。B。1米的身高对于小朋友来说是比较合理的。C。3 厘米太短，不符合小朋友的身高特征。即，小华的身高大约是1米。故答案为:B",
+    "knowledge_points": [
+      "长度的估测"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "15",
+    "unit": "第一单元 长度单位",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面属于线段的是( )。",
+    "options": [
+      "A. ![](images/2026-02-04%20175313.jpg)",
+      "B. ![](images/2026-02-04%20175327.jpg)",
+      "C. ![](images/2026-02-04%20175345.jpg)"
+    ],
+    "answer": "B",
+    "solution": "【分析】线段有两个端点，中间是直直的线，长度可测量，由此解答.\n【详解】A。没有两个端点，不是线段;B。有两个端点，中间是直直的线，是线段;C。没有两个端点，不是直直的线，不是线段。属于线段的是B。故答案为:B",
+    "knowledge_points": [
+      "线段的初步认识"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "16",
+    "unit": "第一单元 长度单位",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "如图，蜡笔长( ).\n\n![](images/d11e8622747832045bfb1150ac30dbe43abaf28ffb948ef1b006ec99e6054353.jpg)",
+    "options": [
+      "A. 7 厘米",
+      "B. 4 厘米",
+      "C. 3 厘米"
+    ],
+    "answer": "C",
+    "solution": "【分析】被测物体的长度 = 测量结束刻度 - 测量起始刻度;据此解决.\n【详解】7 - 4 = 3(厘米)即，如上图，蜡笔长3厘米。故答案为:C",
+    "knowledge_points": [
+      "长度的测量方法"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "17",
+    "unit": "第一单元 长度单位",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "下列物品中，厚度或者长度超过 1 米的是( )。",
+    "options": [
+      "A. 数学书",
+      "B. 课桌的高度",
+      "C. 一节动车车厢的长度"
+    ],
+    "answer": "C",
+    "solution": "【分析】根据生活经验以及对长度单位的认识来解决此题。食指宽大约是1厘米，而数学书的厚度不到1厘米;米尺的长度是1米(1米 = 100 厘米),而课桌的高度不到1 米，大约是 70 厘米;一节动车车厢的长度大约 25 米.\n【详解】A。数学书厚度不到1厘米;B。课桌的高度大约是70厘米;C。一节动车车厢的长度大约25米。即，厚度或者长度超过1米的是(一节动车车厢的长度)故答案为:C",
+    "knowledge_points": [
+      "长度的估测"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "18",
+    "unit": "第一单元 长度单位",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "两根绳子都长 1 米，第一根用去 35 厘米，第二根用去 28 厘米,( )绳子剩下的长。",
+    "options": [
+      "A. 第一根",
+      "B. 第二根",
+      "C. 无法确定"
+    ],
+    "answer": "B",
+    "solution": "【分析】用去的越短则剩下的越长，直接比较用去的长度即可.\n【详解】35 > 28，第二根绳子剩下的长。故答案为:B",
+    "knowledge_points": [
+      "100以内数的比大小",
+      "厘米的认识"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "19",
+    "unit": "第一单元 长度单位",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "我们的身体尺中，一步的长度大约( )。",
+    "options": [
+      "A. 1米",
+      "B. 1厘米",
+      "C. 50厘米"
+    ],
+    "answer": "C",
+    "solution": "【分析】大拇指的指甲长度大约1厘米，小学生两臂伸开的长度大约1米，据此逐项分析.\n【详解】A。1 米较长，一步走 1 米比较费力，不符合;B。1 厘米太短，几乎没有前进，不符合;C。50 厘米差不多是一步的长度，符合。我们的身体尺中，一步的长度大约 50 厘米。故答案为:C",
+    "knowledge_points": [
+      "厘米的认识",
+      "米的认识",
+      "长度的估测",
+      "\"身体尺\"的认识及应用"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "20",
+    "unit": "第一单元 长度单位",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "诸葛亮铜像是襄阳市诸葛亮广场中央的标志性建筑，整个铜像高约 18( )。",
+    "options": [
+      "A. 米",
+      "B. 厘米",
+      "C. 以上均有可能"
+    ],
+    "answer": "A",
+    "solution": "【分析】根据生活常识和对不同长度单位的认识来选择合适的单位。量比较短的物体，可以用厘米作单位,1厘米大约是食指的宽度;量比较长的物体，通常用米作单位,1米和米尺一样长;据此解答.\n【详解】根据分析可得：诸葛亮铜像是襄阳市诸葛亮广场中央的标志性建筑，整个铜像高约 18 米。故答案为:A",
+    "knowledge_points": [
+      "米的认识",
+      "长度单位的选择"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "21",
+    "unit": "第一单元 长度单位",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面测量方法正确的是( )。",
+    "options": [
+      "A. ![](images/43922c4a0eb3ab41e5fe2fabe2278813ca6d10e83e97105d9f12f2237f98b460.jpg)",
+      "B. ![](images/a1638d082ddc0dcea953409cc90728c3955432c50c35a1822c673df12f10da36.jpg)",
+      "C. ![](images/a83d825da007d0027e5ed5d08e33f538a1c1db3e97b7f0e201583e110428c712.jpg)"
+    ],
+    "answer": "A",
+    "solution": "【分析】用尺子测量物体长度的方法：尺子的0刻度要与被测物体的一端对齐，再看物体另一端对应的刻度。测量时要注意：尺子要放正，尺子与被测物体要紧贴，不能歪斜.\n【详解】A。尺子放正,0 刻度与左侧对齐，正确;B。尺子0刻度没有与物体左侧对齐，不正确;C。尺子没有放正，不正确。故答案为:A",
+    "knowledge_points": [
+      "长度的测量方法"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "22",
+    "unit": "第一单元 长度单位",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面大约是 1 米的是( )。",
+    "options": [
+      "A. 树苗的高度",
+      "B. 数学书的长度",
+      "C. 教室的长度"
+    ],
+    "answer": "A",
+    "solution": "【分析】根据生活经验，对长度单位和数据大小的认识可知：测量较长的物体用米作单位，二年级学生双臂展开的长度大约是 1 米，由此逐项分析可得.\n【详解】A。树苗的高度和二年级学生的双臂展开的长度差不多大约是 1 米，符合题意;B。数学书的长度比1米少得多，不符合题意;C。教室的长度比 1 米多得多，不符合题意。故答案为:A",
+    "knowledge_points": [
+      "米的认识"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "23",
+    "unit": "第一单元 长度单位",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "小华一步的长大约是( )。",
+    "options": [
+      "A. 4 厘米",
+      "B. 4 米",
+      "C. 40 厘米"
+    ],
+    "answer": "C",
+    "solution": "【分析】根据生活经验可知，小学生走一步的距离大约是30至50厘米;故，小华一步的长大约是40厘米，比较符合实际情况.\n【详解】A。4 厘米太短，不符合实际;B。4 米太长，不符合实际;C。40 厘米比较符合实际。故答案为:C",
+    "knowledge_points": [
+      "长度的估测"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "24",
+    "unit": "第一单元 长度单位",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "下图中的木板有多长。( )\n\n![](images/e5e5b6194df942376d8eea510a4b119e98945664568a61efac80d3b882505b9e.jpg)",
+    "options": [
+      "A. 5 厘米",
+      "B. 4厘米",
+      "C. 3 厘米"
+    ],
+    "answer": "B",
+    "solution": "【分析】尺子测量物体时应将0刻度移动到被测物体的边缘，将直尺与被测物体重合，再观察被测物体另一端的刻度即可。当0刻度与被测物体的边缘不对齐时，用末端的刻度值减去开始的刻度值即可.\n【详解】5 - 1 = 4(厘米)。看图可得木板长4厘米。故答案为:B",
+    "knowledge_points": [
+      "长度的测量方法",
+      "厘米的认识"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "25",
+    "unit": "第一单元 长度单位",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面的图形中,()是线段。",
+    "options": [
+      "A. ![](images/2026-02-04%20180218.jpg)",
+      "B. ![](images/2026-02-04%20180233.jpg)",
+      "C. ![](images/2026-02-04%20180249.jpg)"
+    ],
+    "answer": "C",
+    "solution": "【分析】线段有两个端点，且中间是一条直线，有限长，可测量.\n【详解】A。是曲线，不符合题意;B。有两个端点，但中间是曲线，不是线段，不符合题意;C。有两个端点，中间是直线，符合题意。故答案为:C",
+    "knowledge_points": [
+      "线段的初步认识",
+      "线段，直线，射线的认识及特征"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "26",
+    "unit": "第一单元 长度单位",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "一条红领巾最长的边约长( )。",
+    "options": [
+      "A. 2 米",
+      "B. 20 厘米",
+      "C. 100 厘米"
+    ],
+    "answer": "C",
+    "solution": "【分析】大拇指的指甲长度大约1厘米，小学生两臂伸开的长度大约1米，联系生活实际，计量单位和数据的大小，灵活的选择.\n【详解】A。2 米太长，不符合;B。20厘米大概直尺的长度，太短，不符合;C。100厘米符合一条红领巾最长的边的长度。一条红领巾最长的边约长100厘米。故答案为:C",
+    "knowledge_points": [
+      "厘米的认识",
+      "米的认识",
+      "长度的估测"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "27",
+    "unit": "第一单元 长度单位",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "厚度最接近 1 厘米的物体是( )。",
+    "options": [
+      "A. 汉语词典",
+      "B. 数学课本",
+      "C. 直尺"
+    ],
+    "answer": "B",
+    "solution": "【分析】1厘米相当于我们食指的宽度，据此选择出厚度大约和我们食指的宽度一致的物体即可.\n【详解】A。汉语词典比较厚，比食指的宽度多出很多;B。数学书的厚度和食指的宽度差不多一致;C。直尺的厚度很薄，比食指的宽度少很多;则厚度最接近 1 厘米的物体是数学课本。故答案为:B",
+    "knowledge_points": [
+      "厘米的认识"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "28",
+    "unit": "第一单元 长度单位",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面是二年级学生的\"身体尺\"，长约 1 米的是( )。",
+    "options": [
+      "A. 一拃长",
+      "B. 一庹长",
+      "C. 一脚长"
+    ],
+    "answer": "B",
+    "solution": "【分析】根据生活经验，对长度单位和数据大小的认识可知：计量较长的物体用米作单位，二年级学生双臂展开的长度大约是1米，计量比较短的物体的长度，通常用厘米作单位，食指的宽大约是1厘米，由此选择即可.\n【详解】A。张开大拇指和中指，两端的距离为一拃，二年级学生一拃大约是 15 厘米，不符合题意;B。两臂向左右伸开的长度是一庹，二年级学生一庹大约是1米，符合题意;C。脚尖到脚跟的长度为一脚，二年级学生一脚大约是20厘米，不符合题意。所以长约1米的是一庹长。故答案为:B",
+    "knowledge_points": [
+      "厘米的认识",
+      "米的认识",
+      "长度的估测",
+      "\"身体尺\"的认识及应用"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "29",
+    "unit": "第一单元 长度单位",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下列选项中，是线段的为( )",
+    "options": [
+      "A. ![](images/2026-02-04%20180722.jpg)",
+      "B. ![](images/2026-02-04%20180734.jpg)",
+      "C. ![](images/2026-02-04%20180746.jpg)"
+    ],
+    "answer": "C",
+    "solution": "【分析】线段两端都有端点，不可延长，两个端点间的线条是直的，据此解答.\n【详解】A。线条不是直的，不是线段;B。线条不是直的，不是线段;C。两端都有端点，不可延长，两个端点间的线条是直的，是线段。是线段的为C。故答案为:C",
+    "knowledge_points": [
+      "线段的初步认识"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "30",
+    "unit": "第一单元 长度单位",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "下面( )的长度大约是1 厘米。",
+    "options": [
+      "A. 一拃",
+      "B. 一庹",
+      "C. 食指的宽"
+    ],
+    "answer": "C",
+    "solution": "【分析】尺子是测量长度的工具，尺子上的\"厘米\"就是一个统一的长度单位。量比较短的物体，可以用\"厘米\"作单位。如图![](images/7eee68b87a1ae564db4faedfbbfd5441332b07329d0d3f44b962346c04973133.jpg)这是1厘米的长度.\n【详解】A。一拃是张开大拇指和中指，两端的距离为1拃，二年级小学生1拃长大约是14厘米，不符合题意;B。一庹是两臂向左右伸开的长度，二年级同学一庹大约是1米，不符合题意;C。食指的宽大约是1厘米，符合题意。故答案为:C",
+    "knowledge_points": [
+      "厘米的认识",
+      "长度的估测",
+      "\"身体尺\"的认识及应用"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "31",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "在学生用的直尺上，从刻度 1 到刻度 10 的长度是( )厘米。",
+    "options": [],
+    "answer": "9",
+    "solution": "【分析】用直尺的\"0\"刻度线和线段的一个端点重合，另一个端点在直尺上的刻度，就是该线段的长度。相邻两个刻度之间的长度是1厘米。如果没有从0刻度开始，就用结束的刻度减去开始的刻度，就是线段或者物体的长度.\n【详解】10 - 1 = 9(厘米),所以，在学生用的直尺上，从刻度 1 到刻度 10 的长度是 9厘米。",
+    "knowledge_points": [
+      "长度的测量方法",
+      "厘米的认识"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "32",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "这支铅笔长( )厘米,( )支这样的铅笔长 1 米.\n\n![](images/f5159e0d1e1bef95a8b6f919d4e05906e1121c7c5c0bb109ccc1960afffa8600.jpg)",
+    "options": [],
+    "answer": "10;10",
+    "solution": "【分析】铅笔一端和0对齐，另一端和10厘米对齐,10厘米就是铅笔的长度;根据1米 = 100 厘米,100 厘米里有 10 个 10 厘米，也就是说 10 支这样的铅笔长 1 米.\n【详解】根据分析，这支铅笔长 10 厘米,10 支这样长的铅笔长 1 米。",
+    "knowledge_points": [
+      "厘米的认识",
+      "厘米和米之间的进率与换算"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "33",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "8 千米=( )米;80毫米 = ( )厘米;50 米-6 米=( )分米 1 米-3 分米 = ( )分米",
+    "options": [],
+    "answer": "8000;8;440;7",
+    "solution": "【分析】根据长度单位换算关系:1 千米 = 1000 米,1 厘米 = 10 毫米,1 米 = 10 分米，先进行单位换算或计算，再转换为目标单位.\n【详解】1 千米 = 1000 米，所以8 千米 = 8000 米;1 厘米 = 10 毫米，所以80 毫米 = 8 厘米;50 米 - 6 米 = 44 米,1 米 = 10 分米,44 米 = 440 分米，所以50 米 - 6 米 = 440 分米;1 米 = 10 分米，所以10 分米 - 3 分米 = 7 分米。",
+    "knowledge_points": [
+      "毫米，厘米，分米，米之间的进率与换算"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "34",
+    "unit": "第一单元 长度单位",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "测量学校跑道的长度，选择用米作单位比较合适。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】根据生活经验，对长度单位和数据大小的认知可知：量比较长的物体，通常用米作单位，一圈跑道长度是400米，所以测量学校跑道的长度，选择用米作单位比较合适.\n【详解】测量学校跑道的长度，选择用米作单位比较合适，原题说法正确。故答案为:√",
+    "knowledge_points": [
+      "米的认识",
+      "长度单位的选择"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "35",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "在( )里填上合适的长度单位。学校课桌高 75( );铅笔长 17( );一棵大树高 8( )",
+    "options": [],
+    "answer": "厘米或cm;厘米或cm;米或m",
+    "solution": "【分析】根据生活经验，对长度单位，质量单位，时间单位认识可知,1米大约为小学生双臂伸展开的长度;1分米大约手掌的宽度;1 厘米大约指甲盖的宽度;由此即可解答.\n【详解】1厘米大约是指甲盖的宽度，所以计量学校课桌的高度用\"厘米\"作单位比较合适，则学校课桌高75厘米;1厘米大约是指甲盖的宽度，所以计量铅笔的长度用\"厘米\"作单位比较合适，则铅笔长 17 厘米;1米大约为小学生双臂伸展开的长度，所以计量一棵大树的高度用\"米\"作单位比较合适，则一棵大树高8米。",
+    "knowledge_points": [
+      "长度单位的选择"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "36",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "在括号里填上合适的数。 \n3 元 6 角=( )角;1 元 - 7 角=( )角 \n47 厘米 - 40 厘米=( )厘米;500 厘米=( )米",
+    "options": [],
+    "answer": "36;3;7;5",
+    "solution": "【分析】根据 1 元 = 10 角,1 米 = 100 厘米进行单位换算，统一单位后再进行计算即可解答.\n【详解】3 元 = 30 角, 30 + 6 = 36，所以 3 元 6 角 = 36 角;1 元 = 10 角, 10 - 7 = 3，所以 1 元 - 7 角 = 3 角;47 - 40 = 7，所以 47 厘米 - 40 厘米 = 7 厘米;500 厘米 = 5 米",
+    "knowledge_points": [
+      "元，角，分的认识及换算",
+      "厘米和米之间的进率与换算"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "37",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "尺子上的刻度从 0到 8 是( )厘米，从 6 到 15 是( )厘米。",
+    "options": [],
+    "answer": "8;9",
+    "solution": "【分析】尺子测量物体时应将0刻度移动到被测物体的边缘，将直尺与被测物体重合，再观察被测物体另一端的刻度即可。当0刻度与被测物体的边缘不对齐时，用末端的刻度值减去开始的刻度值即可.\n【详解】15 - 6 = 9(厘米),尺子上的刻度从 0 到 8 是 8 厘米，从 6 到 15 是 9 厘米。",
+    "knowledge_points": [
+      "长度的测量方法",
+      "厘米的认识"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "38",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "如图,![](images/2026-02-04%20181400.jpg),这支铅笔长( )厘米。",
+    "options": [],
+    "answer": "7",
+    "solution": "【分析】用直尺的\"0\"刻度线和线段的一个端点重合，另一个端点在直尺上的刻度，就是该线段的长度;取一整刻度线为零刻线的，切莫忘记最后读数中减掉取代零刻线的刻度值，据此解答即可.\n【详解】9 - 2 = 7(厘米),所以这支铅笔长7厘米。",
+    "knowledge_points": [
+      "长度的测量方法"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "39",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "30角 = ( )元 4 米=( )厘米",
+    "options": [],
+    "answer": "3;400",
+    "solution": "【分析】10 角 = 1 元,1 米 = 100 厘米，据此进行单位换算.\n【详解】30 角就是 3 个 10 角，即 3 个 1 元，则 30 角 = 3 元;4米就是4个1米，即4个100厘米，则4米 = 400 厘米。",
+    "knowledge_points": [
+      "元，角，分的认识及换算",
+      "厘米和米之间的进率与换算"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "40",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "在括号里填上合适的长度单位。铅笔长约 18( );教室高约 3( )。",
+    "options": [],
+    "answer": "厘米或cm;米或m",
+    "solution": "【分析】根据生活经验以及对长度单位和数据大小的认识，量比较短的物体的长度，通常用厘米作单位。食指的宽大约是1厘米，所以计量一支铅笔长度用\"厘米\"作单位比较合适。量比较长的物体，通常用米作单位。二年级学生双臂展开的长度大约是1米，所以计量教室高度用\"米\"作单位比较合适.\n【详解】据分析可知：铅笔长约 18 厘米;教室高约 3 米。",
+    "knowledge_points": [
+      "厘米的认识",
+      "米的认识",
+      "长度单位的选择"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "41",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "一根绳子长 1 米，第一次剪去 40 厘米，第二次剪去 30 厘米，剩下( )厘米。",
+    "options": [],
+    "answer": "30",
+    "solution": "【分析】先把1米换算成100厘米，然后用100厘米减去第一次减去的长度，求出差，再减去第二次减去的长度，求出差，就是还剩的长度.\n【详解】1米 = 100厘米;100 - 40 - 30 = 60 - 30 = 30(厘米)。即，一根绳子长1米，第一次剪去40厘米，第二次剪去30厘米，剩下30厘米。",
+    "knowledge_points": [
+      "100以内数的连减运算",
+      "厘米的认识",
+      "米的认识",
+      "厘米和米之间的进率与换算"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "42",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "50 毫米=( )厘米;2000 米=( )千米",
+    "options": [],
+    "answer": "5;2",
+    "solution": "【分析】进行单位之间的换算,1厘米 = 10 毫米,1千米=1000米，根据换算的进率即可得出答案.\n【详解】1 厘米 = 10 毫米，所以:50 毫米 = 5 厘米;1000 米 = 1 千米，所以:2000 米 = 2 千米。",
+    "knowledge_points": [
+      "毫米，厘米，分米，米之间的进率与换算",
+      "千米和米之间的进率与换算"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "43",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "1 元 = ( )角;1 米=( )厘米",
+    "options": [],
+    "answer": "10;100",
+    "solution": "【分析】根据对人民币的认识可知,1 元里有 10 个 1 角，也就是 1 元 = 10 角;根据对长度单位的认识可知,1 米里有100 个 1 厘米，也就是 1 米 = 100 厘米.\n【详解】1 元 = 10 角;1 米 = 100 厘米。",
+    "knowledge_points": [
+      "元，角，分的认识及换算",
+      "厘米和米之间的进率与换算"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "44",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "1 米 = ( )厘米，教室的黑板长约 4( )(填\"米\"或\"厘米\")。",
+    "options": [],
+    "answer": "100;米或m",
+    "solution": "【分析】根据 1 米等于 100 厘米，直接填写\"100\"即可;教室黑板是较长的物体，通常长度在3-5米之间，因此填\"米\";若填\"厘米\"，显然不合理.\n【详解】根据分析可得:1 米 =(100)厘米，教室的黑板长约 4(米)。",
+    "knowledge_points": [
+      "米的认识",
+      "毫米，厘米，分米，米之间的进率与换算",
+      "长度单位的选择"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "45",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "3 元 5 角=( )角;1 米=( )厘米",
+    "options": [],
+    "answer": "35;100",
+    "solution": "【分析】1元 = 10 角，先统一单位后再计算;1米 = 100 厘米，直接填写即可.\n【详解】1 元 = 10 角，因此 3 元 = 30 角,30 角 + 5 角 = 35 角;故3 元 5 角 =(35)角;1 米 = (100)厘米",
+    "knowledge_points": [
+      "元，角，分的认识及换算",
+      "毫米，厘米，分米，米之间的进率与换算"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "46",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "在括号里填上合适的单位.\n小明身高 130( );一棵大树高 15( )",
+    "options": [],
+    "answer": "厘米或cm;米或m",
+    "solution": "【分析】结合经验及数据大小选择合适单位即可。计量较短的物体，用\"厘米\"作单位，食指的宽度约为1厘米。则计量小明的高度用\"厘米\"作单位。计量较长的物体，用\"米\"作单位，学生的双臂展开约为1米。则计量一棵大树高度用\"米\"作单位.\n【详解】小明身高 130(厘米);一棵大树高 15(米)",
+    "knowledge_points": [
+      "长度单位的选择"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "47",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "直尺上从刻度 0 到 6是( )厘米,4 到 9 是( )厘米。",
+    "options": [],
+    "answer": "6;5",
+    "solution": "【分析】用直尺的\"0\"刻度线和线段的一个端点重合，另个端点在直尺上的刻度，就是该线段的长度;取一整刻度线为零刻线的，切莫忘记最后读数中减掉取代零刻度线的刻度值，据此解答即可.\n【详解】9 - 4 = 5(厘米),则直尺上从刻度 0 到 6 是(6)厘米,4 到 9 是(5)厘米。",
+    "knowledge_points": [
+      "长度的测量方法"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "48",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "我们看书眼睛距离书本大约 30( )比较好。",
+    "options": [],
+    "answer": "厘米或cm",
+    "solution": "【分析】小学生的食指宽大约1厘米，数学课本封面的宽大约1分米，洗衣机高大约1米。看书时眼睛距离书本，不能太近也不能太远，太近影响视力，太远看不清。结合题中数据可知,30 厘米比较好,30 分米或 30 米都太远了.\n【详解】我们看书眼睛距离书本大约 30 厘米比较好。",
+    "knowledge_points": [
+      "厘米的认识",
+      "长度单位的选择"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "49",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "小小测量课桌面的长度。用铅笔量，有4支铅笔的长度：用钢笔量，有6支钢笔的长度。铅笔的长度( )钢笔的长度。(填\"大于\"\"小于\"或\"等于\")",
+    "options": [],
+    "answer": "大于",
+    "solution": "【分析】根据题意可知：用物体测量同样的长度，则用的物体数量越少则说明该物体的长度越长，用的物体数量越多则说明该物体越短.\n【详解】4 < 6，则铅笔长，钢笔短。由此可知小小测量课桌面的长度。用铅笔量，有 4 支铅笔的长度：用钢笔量，有 6 支钢笔的长度。铅笔的长度(大于)钢笔的长度。(填\"大于\"\"小于\"或\"等于\")",
+    "knowledge_points": [
+      "长度的测量方法"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "50",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "一根 1 米长的彩带，第一次用去 40 厘米，第二次用去 30 厘米，两次一共用去( )厘米，现在还剩下( )厘米。",
+    "options": [],
+    "answer": "70;30",
+    "solution": "【分析】将两次用的长度相加即可求出两次共用去多少厘米;将1米换算成100厘米，然后减去两次共用去的长度即可求出剩下的长度.\n【详解】40 + 30 = 70(厘米);1 米 = 100 厘米;100 - 70 = 30(厘米)。即，一根1米长的彩带，第一次用去40厘米，第二次用去30 厘米，两次一共用去 70 厘米，现在还剩下 30 厘米。",
+    "knowledge_points": [
+      "整十数之间的加减法",
+      "厘米和米之间的进率与换算"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "51",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "在括号里填上合适的长度单位.\n一根跳绳长 3( );小刚高 135( )。",
+    "options": [],
+    "answer": "米或m;厘米或cm",
+    "solution": "【分析】联系生活实际，计量单位和数据的大小，灵活的选择。小学生两臂伸开的长度大约 1 米，计量跳绳的长度用\"米\"作单位比较合适。大拇指的指甲长度大约1厘米，计量小朋友的身高用\"厘米\"作单位比较合适.\n【详解】一根跳绳长 3 米;小刚高 135 厘米。",
+    "knowledge_points": [
+      "厘米的认识",
+      "米的认识",
+      "长度单位的选择"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "52",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "一把学生尺长约20厘米，大约( )把这样的学生尺长1米。",
+    "options": [],
+    "answer": "5",
+    "solution": "【分析】根据1米 = 100 厘米，将单位换算统一，然后再将学生尺的长度相加，直到结果为 1 米即可.\n【详解】1米 = 100 厘米,20 + 20 + 20 + 20 + 20 = 100(厘米)。则一把学生尺长约20厘米，大约5把这样的学生尺长1米。",
+    "knowledge_points": [
+      "厘米和米之间的进率与换算"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "53",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "在括号里填上合适的单位.\n一支铅笔长约 20( );旗杆高约 13( )\n学校跑道长 250();小明身高 125( )",
+    "options": [],
+    "answer": "厘米或cm;米或m;米或m;厘米或cm",
+    "solution": "【分析】根据生活经验及结合给出的数据，来选择合适的长度单位。食指宽大约是1厘米，所以，计量一支铅笔长和小明身高用\"厘米\"作单位比较合适;米尺的长度是 1 米，所以，计量旗杆高和学校跑道长用\"米\"作单位比较合适.\n【详解】由题意分析得：一支铅笔长约20厘米;旗杆高约13米;学校跑道长250米;小明身高125厘米",
+    "knowledge_points": [
+      "长度单位的选择"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "54",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "在括号里填\"米\"或\"厘米\".\n妈妈身高 1( )62( ).\n一张课桌高 60( )。",
+    "options": [],
+    "answer": "米或m;厘米或cm;厘米或cm",
+    "solution": "【分析】要注意联系生活实际，计量单位和数据的大小，灵活的选择。大拇指的指甲长度大约1厘米，小学生两臂伸开的长度大约1米。成年人的身高一般是一百多厘米,100厘米 = 1 米，也就是大约1米几十厘米。大拇指的指甲长度大约1厘米，计量课桌的高度用\"厘米\"作单位比较合适.\n【详解】妈妈身高1米62厘米。一张课桌高60厘米。",
+    "knowledge_points": [
+      "厘米的认识",
+      "米的认识",
+      "长度单位的选择"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "55",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "如图,2 条 2 厘米长的线段连接在一起形成一条( )厘米长的线段.\n\n![](images/65f8c7b2b15b519411ed17fcd9811758f9e3998490e8bad38548280458f4249e.jpg)",
+    "options": [],
+    "answer": "4",
+    "solution": "【分析】根据题意，两条线段连接在一起且没有重叠，总长度就是两条线段的长度之和，由此解答.\n【详解】2 + 2 = 4(厘米)。如图,2 条 2 厘米长的线段连接在一起形成一条 4 厘米长的线段。",
+    "knowledge_points": [
+      "厘米的认识"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "56",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "填合适的单位.\n数学书长 26( );妈妈身高 162( )\n教学楼高 15( );铅笔长约 18( )",
+    "options": [],
+    "answer": "厘米或cm;厘米或cm;米或m;厘米或cm",
+    "solution": "【分析】注意联系生活实际，计量单位和数据的大小，灵活的选择。大拇指的指甲长度大约1厘米，计量数学书长度，妈妈身高和铅笔长度用\"厘米\"作单位比较合适。小学生两臂伸开的长度大约 1 米，计量教学楼高度用\"米\"作单位比较合适.\n【详解】数学书长 26 厘米;妈妈身高 162 厘米;教学楼高15米;铅笔长约18厘米。",
+    "knowledge_points": [
+      "厘米的认识",
+      "米的认识",
+      "长度单位的选择"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "57",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "在下面的( )里填上\"厘米\"或\"米\".\n铅笔长 20( );大树高 6( )\n水杯高 18( );旗杆高 12( )",
+    "options": [],
+    "answer": "厘米或cm;米或m;厘米或cm;米或m",
+    "solution": "【分析】根据生活经验和数据大小的认识可知,1厘米大约是食指的宽度，二年级小学生双臂展开的长度大约是1米，所以计量铅笔长和水杯高用\"厘米\"作单位比较合适，计量大树高和旗杆高用\"米\"作单位比较合适.\n【详解】由分析可知：铅笔长 20 厘米;大树高 6 米;水杯高18厘米;旗杆高12米",
+    "knowledge_points": [
+      "厘米的认识",
+      "米的认识",
+      "长度单位的选择"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "58",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "在括号里填上\"米\"或\"厘米\".\n(1)剪刀长约 13( );(2)跳绳长约 3( );(3)杯子高约 8( );(4)教室长约 10( )。",
+    "options": [],
+    "answer": "厘米或cm;米或m;厘米或cm;米或m",
+    "solution": "【分析】根据生活经验以及数据的大小，选择合适的计量单位来解决此题。食指宽大约是1厘米，所以，计量剪刀长和杯子高用\"厘米\"作单位比较合适;米尺长是1米，所以，计量跳绳长和教室长用\"米\"作单位比较合适.\n【详解】(1)剪刀长约 13 厘米。(2)跳绳长约3米。(3)杯子高约8厘米。(4)教室长约10米。",
+    "knowledge_points": [
+      "长度单位的选择"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "59",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "在括号里填上合适的长度单位.\n一棵树高约 8( );数学课本长约 26( );课桌高约 60();一个篮球场长约 28( )。",
+    "options": [],
+    "answer": "米或m;厘米或cm;厘米或cm;米或m",
+    "solution": "【分析】根据生活经验及结合给出的数据，来选择合适的长度单位。食指宽大约是1厘米，所以，计量数学课本长和课桌高用\"厘米\"作单位比较合适;米尺的长度是1米，所以，计量一棵树高和一个篮球场长用\"米\"作单位比较合适.\n【详解】由题意分析得：一棵树高约 8 米;数学课本长约 26 厘米;课桌高约 60 厘米;一个篮球场长约 28 米。",
+    "knowledge_points": [
+      "厘米的认识",
+      "米的认识",
+      "长度单位的选择"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "60",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "填上合适的单位名称(米或厘米).\n杨树高 7( )。一条路长 100( )。",
+    "options": [],
+    "answer": "米或m;米或m",
+    "solution": "【分析】根据对生活经验和数据大小的认识可知,1厘米大约是食指的宽度，二年级学生双臂展开的长度大约是1米，所以计量杨树高和一条路长用\"米\"作单位比较合适;【详解】根据分析可知：杨树高7米。一条路长100米。",
+    "knowledge_points": [
+      "厘米的认识",
+      "米的认识",
+      "长度单位的选择"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "61",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "在括号内填上合适的单位.\n教室的宽约 6( );一块橡皮长约 5( );床长是1( )90( )。",
+    "options": [],
+    "answer": "米或m;厘米或cm;米或m;厘米或cm",
+    "solution": "【分析】计量较长的物体，用\"米\"作单位，学生的双臂展开约为1米。则计量教室的宽度;床的长度用\"米\"作单位。计量较短的物体，用\"厘米\"作单位，食指的宽度约为1厘米。则计量一块橡皮的长度用\"厘米\"作单位.\n【详解】教室的宽约 6(米);一块橡皮长约 5(厘米);床长是 1(米)90(厘米)。",
+    "knowledge_points": [
+      "长度单位的选择"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "62",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "在括号填上合适的单位.\n数学课本的封面长约 26( );旗杆高约 15( );1 支粉笔长约 8( )",
+    "options": [],
+    "answer": "厘米或cm;米或m;厘米或cm",
+    "solution": "【分析】根据生活常识和对不同长度单位的认识来选择合适的单位。量比较短的物体，可以用\"厘米\"作单位;量比较长的物体，通常用\"米\"作单位;据此解答。(1)1厘米大约是食指的宽度，所以计量数学课本的封面长用\"厘米\"作单位比较合适;(2)1米大约是二年级小朋友双臂伸开的长度，所以计量旗杆高用\"米\"作单位计较合适。(3)1厘米大约是食指的宽度，所以计量1支粉笔长用\"厘米\"作单位比较合适\n【详解】根据分析可得：数学课本的封面长约 26 厘米;旗杆高约 15 米;1 支粉笔长约 8 厘米",
+    "knowledge_points": [
+      "厘米的认识",
+      "米的认识",
+      "长度单位的选择"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "63",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.94,
+    "question": "这支铅笔长( )cm.\n\n![](images/d0998af866c3ecee3b14b92163a18800cfd6b343e72fa6a4b2827697dcd3b060.jpg)",
+    "options": [],
+    "answer": "6",
+    "solution": "【分析】根据测量物体的方法：用直尺去测量物体的长度时，要把直尺的\"0\"刻度线和物体的左端对齐，物体的右端对应数字几，就表示这个物体有多长。若测量时，不是\"0\"刻度线与左端对齐的话，就用结束的刻度减去测量起始的刻度即可.\n【详解】根据分析可得:7 - 1 = 6(cm),这支铅笔长 6cm。",
+    "knowledge_points": [
+      "长度的测量方法",
+      "厘米的认识"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "64",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "在括号里填上合适的单位名称。床长约 2( );课桌高约 70( );跑道一圈长 400( );小丽的身高约是 145( )。",
+    "options": [],
+    "answer": "米或m;厘米或cm;米或m;厘米或cm",
+    "solution": "【分析】根据生活经验及结合给出的数据，来选择合适的长度单位。食指宽大约是1厘米，所以，计量课桌高和小丽的身高用\"厘米\"作单位比较合适;米尺的长度是1米，所以，计量床长和跑道一圈长用\"米\"作单位比较合适.\n【详解】由题意分析得：床长约 2 米;课桌高约 70 厘米;跑道一圈长400米;小丽的身高约是145厘米。",
+    "knowledge_points": [
+      "长度单位的选择"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "65",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "8 米 - 7 米 = ( )厘米;1 米 - 50 厘米=( )厘米",
+    "options": [],
+    "answer": "100;50",
+    "solution": "【分析】根据整数加减法的计算法则及\"1米 = 100 厘米\"来解决此题即可.\n【详解】8 米 - 7 米 = 1 米,1 米 = 100 厘米，即,8 米 - 7 米= 100 厘米;1 米 = 100 厘米,100 厘米 - 50 厘米 = 50 厘米，即,1 米 - 50 厘米 = 50 厘米。",
+    "knowledge_points": [
+      "8,9的加减法",
+      "整十数之间的加减法",
+      "厘米和米之间的进率与换算"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "66",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "这枚铁钉长( )厘米.\n\n![](images/5e9a4b91552a8a5e8c834b481bb24518b54f48e4e3502613e1d7105c46555fd8.jpg)",
+    "options": [],
+    "answer": "5",
+    "solution": "【分析】当0刻度与被测物体的边缘不对齐时，如果零刻度线磨损可以另取一整数刻度线为零刻度线，最后读数中减掉取代零刻度线的刻度值。用末端的刻度值减去开始的刻度值即可.\n【详解】9 - 4 = 5(厘米),则这枚铁钉长5厘米。",
+    "knowledge_points": [
+      "长度的测量方法",
+      "8,9的加减法"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "67",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "小强参加了男子跳高比赛，他的成绩是90厘米，他再跳( )厘米就正好是1 米。",
+    "options": [],
+    "answer": "10",
+    "solution": "【分析】先根据\"1 米 = 100 厘米\"进行换算单位，然后再用 100 厘米减去 90 厘米，求出差即可解决.\n【详解】1米 = 100 厘米,100 厘米 - 90 厘米 = 10 厘米。即，小强参加了男子跳高比赛，他的成绩是90厘米，他再跳10厘米就正好是1米。",
+    "knowledge_points": [
+      "整十数之间的加减法",
+      "厘米和米之间的进率与换算"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "68",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "在一次学校跳高比赛中，明明跳的高度比1米少3厘米，文文跳的高度比1米少 7 厘米，那么( )跳得高。",
+    "options": [],
+    "answer": "明明",
+    "solution": "【分析】根据求比一个数少几的数是多少，用减法计算，单位变统一后分别算出两个同学跳的高度，再比较大小即可解答.\n【详解】1 米 = 100 厘米;明明跳高成绩:100 厘米 - 3 厘米 = 97 厘米;文文跳高成绩:100 厘米 - 7 厘米 = 93 厘米;97 厘米>93 厘米;所以明明跳得高。",
+    "knowledge_points": [
+      "厘米和米之间的进率与换算"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "69",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "在( )里填上合适的长度单位.\n琪琪比去年长高了 5( );一辆小轿车长约 3( )",
+    "options": [],
+    "answer": "厘米或cm;米或m",
+    "solution": "【分析】大拇指的指甲长度大约1厘米，计量小朋友一年内身高的增加情况用\"厘米\"作单位比较合适。小学生两臂伸开的长度大约1米，计量小轿车的长度用\"米\"作单位比较合适.\n【详解】琪琪比去年长高了 5 厘米;一辆小轿车长约 3 米。",
+    "knowledge_points": [
+      "厘米的认识",
+      "米的认识",
+      "长度单位的选择"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "70",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "在括号里填上适当的长度单位.\n黑板长 4( );小明身高 145( )\n铅笔长 15( );一棵大树高约 10( )",
+    "options": [],
+    "answer": "米或m;厘米或cm;厘米或cm;米或m",
+    "solution": "【分析】根据生活经验，对长度单位和数据大小的认识可知：计量较长的物体用米作单位，二年级学生双臂展开的长度大约是1米，所以计量黑板的长度，大树的高度用米作单位比较合适;计量比较短的物体的长度，通常用厘米作单位，食指的宽大约是 1 厘米，所以计量小明的身高，铅笔的长度用厘米作单位比较合适.\n【详解】黑板长4米小明身高145厘米铅笔长 15 厘米;一棵大树高约 10 米",
+    "knowledge_points": [
+      "长度单位的选择"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "71",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "一段绳子长 50 厘米，两段这样的绳子一共长( )厘米，也就是( )米。",
+    "options": [],
+    "answer": "100;1",
+    "solution": "【分析】将两段绳子的长度相加即可求出一共长多少厘米,100 厘米 = 1 米，据此换算成\"米\"作单位.\n【详解】50 + 50 = 100(厘米);100 厘米 = 1 米，段绳子长 50 厘米，两段这样的绳子一共长 100 厘米，也就是 1 米。",
+    "knowledge_points": [
+      "厘米和米之间的进率与换算"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "72",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "在括号里填上适当的长度单位。篮球场长 28( );小红一步长约 40( )",
+    "options": [],
+    "answer": "米或m;厘米或cm",
+    "solution": "【分析】根据生活经验，对长度单位和数据大小的认识可知，量比较长的物体，通常用米作单位。二年级学生双臂展开的长度大约是1米，所以计量篮球场长度用\"米\"作单位比较合适。量比较短的物体的长度，通常用厘米作单位。食指的宽大约是1厘米，所以计量小红一步长度用\"厘米\"作单位比较合适.\n【详解】篮球场的长 28 米;小红的一步长约 40 厘米。",
+    "knowledge_points": [
+      "厘米的认识",
+      "米的认识",
+      "长度单位的选择"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "73",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "在括号里填上\"厘米\"或\"米\".\n(1)小华的文具盒长 25( ).\n(2)教室的门高 2( ).\n(3)黑板长 4( ).\n(4)一条毛巾长 64( )。",
+    "options": [],
+    "answer": "厘米或cm;米或m;米或m;厘米或cm",
+    "solution": "【分析】根据生活经验及结合给出的数据，来选择合适的长度单位。食指宽大约是1厘米，所以，计量小华的文具盒长和一条毛巾长用\"厘米\"作单位比较合适;米尺的长度是1米，所以，计量教室的门高和黑板长用\"米\"作单位比较合适.\n【详解】(1)小华的文具盒长25厘米。(2)教室的门高2米。(3)黑板长4米。(4)一条毛巾长64厘米。",
+    "knowledge_points": [
+      "长度单位的选择"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "74",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "如下图，铅笔长( )厘米，纸条长( )厘米.\n\n![](images/4f10bddf2dd6f51b822493783d41e5bc2179ce1b03ab456487293e0fccc3f3f0.jpg)",
+    "options": [],
+    "answer": "7;5",
+    "solution": "【分析】测量物体长度时，将物体的一侧与直尺的 0 刻度线对齐，物体与直尺放平不要倾斜，物体另一侧与直尺所对应的刻度就是物体的长度;若测量时，物体的一侧未与直尺的0刻度线对齐，则用测量结束的刻度 - 测量开始的刻度= 物体的长度.\n【详解】6 - 1 = 5(厘米)。如图，铅笔长 7 厘米，纸条长 5 厘米。",
+    "knowledge_points": [
+      "长度的测量方法",
+      "厘米的认识"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "75",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "在括号里填上\"厘米\"或\"米\".\n蓝蓝是二年级学生，身高 1( )32( ),坐在长约 8( )的教室里，用一本厚约3( )的字典查找生字。",
+    "options": [],
+    "answer": "米或m;厘米或cm;米或m;厘米或cm",
+    "solution": "【分析】根据生活经验，对长度单位和数据大小的认识可知：计量较长的物体用米作单位，二年级学生双臂展开的长度大约是1米，所以计量教室的长度用米作单位比较合适;计量比较短的物体的长度，通常用厘米作单位，食指的宽大约是1厘米，所以计量字典的厚度用厘米作单位比较合适;蓝蓝的身高应写作1米32厘米.\n【详解】蓝蓝是二年级学生，身高1米32厘米，坐在长约8米的教室里，用一本厚约3厘米的字典查找生字。",
+    "knowledge_points": [
+      "长度单位的选择"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "76",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "![](images/a12a28435387bf9aa370c4e60fc0f732acb8723163dec87b908524b48484f83a.jpg)\n\n铅笔长( )厘米，橡皮长( )厘米。",
+    "options": [],
+    "answer": "6;3",
+    "solution": "【分析】测量物体长度时，将物体的一侧与直尺的 0 刻度线对齐，物体与直尺放平不要倾斜，物体另一侧与直尺所对应的刻度就是物体的长度。若测量时，物体的一侧未与直尺的0刻度线对齐，则用测量结束的刻度 - 测量开始的刻度= 物体的长度.\n【详解】10 - 7 = 3(厘米),铅笔长6厘米，橡皮长3厘米。",
+    "knowledge_points": [
+      "长度的测量方法",
+      "厘米的认识"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "77",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "填上合适的单位名称.\n一支粉笔长 10( );妈妈身高 1( )65 厘米\n教室黑板长 4( );数学书长约 23( )",
+    "options": [],
+    "answer": "厘米或cm;米或m;米或m;厘米或cm",
+    "solution": "【分析】根据生活常识和对不同长度单位的认识来选择合适的单位。量比较短的物体，可以用厘米作单位;量比较长的物体，通常用米作单位;据此解答.\n【详解】(1)1厘米大约是食指的宽度，所以计量一支粉笔的长度用\"厘米\"作单位比较合适，一支粉笔长 10 厘米;(2)1米和米尺一样长，因为妈妈身高比一个米尺还要多，所以妈妈身高 1 米 65 厘米;(3)教室的黑板长有4个米尺那样长，所以教室黑板长4米;(4)1厘米大约是食指的宽度，所以计量数学书的长用\"厘米\"作单位比较合适，数学书长约23厘米。",
+    "knowledge_points": [
+      "厘米的认识",
+      "米的认识",
+      "长度单位的选择"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "78",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "( )是测量长度的工具，量比较短的物体可以用( )作单位。",
+    "options": [],
+    "answer": "尺子;厘米或cm",
+    "solution": "【分析】尺子是测量长度的工具。根据生活经验，对长度单位和数据大小的认识可知：计量比较短的物体的长度，通常用厘米作单位，食指的宽大约是 1 厘米，由此解答.\n【详解】尺子是测量长度的工具，量比较短的物体可以用厘米作单位。",
+    "knowledge_points": [
+      "厘米的认识"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "79",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "一根绳子剪去 80 厘米，还剩 20 厘米，这根绳子原来长( )米。",
+    "options": [],
+    "answer": "1",
+    "solution": "【分析】用剪去的长度加还剩的长度求出一共多少厘米,100 厘米 = 1 米，据此换算成\"米\"作单位.\n【详解】80 + 20 = 100(厘米),100 厘米 = 1 米。这根绳子原来长1米。",
+    "knowledge_points": [
+      "厘米和米之间的进率与换算"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "80",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "在括号里填上合适的长度单位.\n汽车长 4( );铅笔盒长 20( );大树高 16( )。",
+    "options": [],
+    "answer": "米或m;厘米或cm;米或m",
+    "solution": "【分析】根据生活经验及结合给出的数据，来选择合适的长度单位。食指宽大约是1厘米，所以，计量铅笔盒长\"厘米\"作单位比较合适;米尺的长度是1米，所以，计量汽车长，大树高用\"米\"作单位比较合适.\n【详解】汽车长 4 米;铅笔盒长 20 厘米;大树高 16 米。",
+    "knowledge_points": [
+      "厘米的认识",
+      "米的认识",
+      "长度单位的选择"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "81",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "在括号里填上合适的单位.\n一支铅笔长约 18( );一本字典厚约 2( )\n黑板长约 4( );爸爸身高大约 1( )80( )",
+    "options": [],
+    "answer": "厘米或cm;厘米或cm;米或m;米或m;厘米或cm",
+    "solution": "【分析】根据生活经验，对长度单位和数据大小的认识可知：计量比较短的物体的长度，通常用厘米作单位，食指的宽大约是1厘米，所以计量铅笔的长度，字典的厚度用厘米作单位比较合适;计量较长的物体用米作单位，二年级学生双臂展开的长度大约是1米，所以计量黑板的长度用米作单位比较合适;爸爸的身高应写作1米80厘米.\n【详解】一支铅笔长约18厘米;一本字典厚约2厘米;黑板长约4米;爸爸身高大约1米80厘米。",
+    "knowledge_points": [
+      "长度单位的选择"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "82",
+    "unit": "第一单元 长度单位",
+    "question_type": "排序题",
+    "difficulty": 0.85,
+    "question": "将下面的长度按照从小到大的顺序进行排列.\n4 米20 厘米;20 厘米;402 厘米;4 米;90 厘米\n( )<( )<( )<( )<( )",
+    "options": [],
+    "answer": "20 厘米;90 厘米;4 米;402 厘米;4 米20 厘米",
+    "solution": "【分析】先根据\"1 米 = 100 厘米\"来换算单位，再按照整数比较大小的方法进行比较，并从小到大排序即可.\n【详解】4 米20 厘米 = 420 厘米,4 米 = 400 厘米。20 厘米<90 厘米<400 厘米<402 厘米<420 厘米，所以 20 厘米<90 厘米<4 米<402 厘米<4 米20 厘米。",
+    "knowledge_points": [
+      "毫米，厘米，分米，米之间的进率与换算"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "83",
+    "unit": "第一单元 长度单位",
+    "question_type": "判断题",
+    "difficulty": 0.65,
+    "question": "一本小学生字典厚 4厘米。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】厘米是常用的长度单位。食指宽大约1厘米。据此解答.\n【详解】由分析得，一本小学生字典厚4厘米，即字典的厚度比食指的宽度厚一些，符合实际情况。原题说法正确。故答案为:√",
+    "knowledge_points": [
+      "厘米的认识"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "84",
+    "unit": "第一单元 长度单位",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "文具盒的长度大约是 20 米。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】判断文具盒的长度单位是否合理，需结合生活实际和常见物体的长度认知。文具盒属于小型学习用品，通常使用厘米作为单位,20米相当于约6层楼的高度，明显不符合实际.\n【详解】根据分析可得：文具盒的长度大约是 20 厘米。原题说法错误。故答案为: ×",
+    "knowledge_points": [
+      "厘米的认识",
+      "米的认识",
+      "长度单位的选择"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "85",
+    "unit": "第一单元 长度单位",
+    "question_type": "判断题",
+    "difficulty": 0.65,
+    "question": "5 米比 4 米 99厘米短。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】1 米 = 100 厘米，可以将 5 米分成 4 米和 1 米，然后用 1 米和 99 厘米比较.\n【详解】5 米 = 4 米 + 1 米 = 4 米 100 厘米,100 厘米 > 99 厘米，所以 5 米比 4 米 99 厘米长，原题说法错误。故答案为: ×",
+    "knowledge_points": [
+      "厘米和米之间的进率与换算"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "86",
+    "unit": "第一单元 长度单位",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "100 厘米比 1 米长。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】根据题意，先将单位统一后再比较,1米 = 100 厘米，据此解答.\n【详解】100厘米 = 1 米，则100厘米和1米同样长，原题说法错误。故答案为: ×",
+    "knowledge_points": [
+      "厘米和米之间的进率与换算"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "87",
+    "unit": "第一单元 长度单位",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "学习时，眼睛与书本的距离要保持在 30 厘米左右。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】根据生活经验，对长度单位和数据大小的认识可知：计量比较短的物体的长度，通常用厘米作单位，食指的宽大约是1厘米。根据用眼健康知识，学习时应保持眼睛与书本约 30 厘米的距离，有助于预防近视，减轻眼睛疲劳.\n【详解】由分析可知：学习时，眼睛与书本的距离要保持在30厘米左右。原题说法正确。故答案为:√",
+    "knowledge_points": [
+      "厘米的认识"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "88",
+    "unit": "第一单元 长度单位",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "一张成年人的床长是 2 厘米。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】结合经验及数据大小选择合适单位即可。计量较短的物体，用\"厘米\"作单位，食指的宽度约为1厘米。计量较长的物体，用\"米\"作单位，学生的双臂展开约为1米。则计量成年人的床的长度，用\"米\"作单位.\n【详解】由分析可得：一张成年人的床长是2米。则原题说法错误。故答案为: ×",
+    "knowledge_points": [
+      "米的认识",
+      "长度单位的选择"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "89",
+    "unit": "第一单元 长度单位",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "同一把尺子上，刻度 2 到 7 和刻度 4 到 9 的长度是不一样的。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】测量物体长度时，将物体的一侧与直尺的0刻度线对齐，物体与直尺放平，不要倾斜，物体另一侧与直尺所对应的刻度就是物体的长度。若测量时，物体的一侧未与直尺的0刻度线对齐，则用测量结束的刻度-测量开始的刻度 = 物体的长度。即刻度2到7，用7减2计算;刻度4到9，用9减4计算，得出结果即可解答.\n【详解】假设刻度为厘米作单位7 - 2 = 5(厘米),9 - 4 = 5(厘米)。同一把尺子上，刻度2到7和刻度4到9的长度是一样的。原题说法错误。故答案为: ×",
+    "knowledge_points": [
+      "长度的测量方法"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "90",
+    "unit": "第一单元 长度单位",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "小明一拃长约10m。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】根据生活经验，对长度单位和数据大小的认识可知：计量较长的物体用 m 作单位，二年级学生双臂展开的长度大约是 1 m,计量比较短的物体的长度，通常用 cm 作单位，食指的宽大约是 1 cm,据此判断.\n【详解】由分析可知，小明一拃长约 10 cm,原题说法错误。故答案为: ×",
+    "knowledge_points": [
+      "厘米的认识",
+      "米的认识",
+      "长度的估测",
+      "\"身体尺\"的认识及应用"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "91",
+    "unit": "第一单元 长度单位",
+    "question_type": "判断题",
+    "difficulty": 0.65,
+    "question": "下面的两条线段一样长。( )\n\n![](images/2411221df0839e7639159dcf0fbd238cf9eccef89f216fe4eafc2bcd25ed142d.jpg)",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】尺子测量物体时应将0刻度移动到被测物体的边缘，将直尺与被测物体重合，再观察被测物体另一端的刻度即可。当0刻度与被测物体的边缘不对齐时，用末端的刻度值减去开始的刻度值即可.\n【详解】第一条:5厘米。第二条:5 - 1 = 4(厘米)。5>4，图中两条线段不一样长。原题说法错误。故答案为: ×",
+    "knowledge_points": [
+      "长度的测量方法"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "92",
+    "unit": "第一单元 长度单位",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "米和厘米都是长度单位。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】根据生活经验，对长度单位和数据大小的认识可知：计量较长的物体用米作单位，二年级学生双臂展开的长度大约是 1 米，计量比较短的物体的长度，通常用厘米作单位，食指的宽大约是 1 厘米，由此解答.\n【详解】由分析可知：米和厘米都是长度单位。原题说法正确。故答案为:√",
+    "knowledge_points": [
+      "厘米的认识",
+      "米的认识"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "93",
+    "unit": "第一单元 长度单位",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "一张课桌的高约 60米。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】根据生活经验以及对长度单位的认识来解决此题。食指宽大约是1厘米，米尺长1米，故，计量一张课桌的高时，用\"厘米\"作单位最合适.\n【详解】由题意分析得：一张课桌的高约 60 厘米;原题说法错误。故答案为: ×",
+    "knowledge_points": [
+      "米的认识",
+      "长度单位的选择"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "94",
+    "unit": "第一单元 长度单位",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "同一把尺子，刻度 1到 5 和刻度 6 到 10 的距离一样长。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】被测物体的长度 = 测量结束刻度 - 测量起始刻度，据此即可解决此题.\n【详解】5 - 1 = 4;10 - 6 = 4，即，同一把尺子，刻度 1 到 5 和刻度 6 到 10 的距离一样长;此说法正确。故答案为:√",
+    "knowledge_points": [
+      "长度的测量方法"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "95",
+    "unit": "第一单元 长度单位",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "一张课桌的高约 50米。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】1厘米大约是食指的宽度，表示一张课桌的高度，一般选择用\"厘米\"作单位，如：一张课桌的高约50厘米.\n【详解】由题意可知：一张课桌的高约50厘米，所以原题说法错误。故答案为: ×",
+    "knowledge_points": [
+      "厘米的认识",
+      "米的认识",
+      "长度单位的选择"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "96",
+    "unit": "第一单元 长度单位",
+    "question_type": "判断题",
+    "difficulty": 0.65,
+    "question": "爸爸的身高175cm。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】1 m = 100 cm,成年人大拇指宽大约是1厘米，所以结合数字175，爸爸的身高是175厘米比较合适.\n【详解】175 cm = 1.75 m,所以爸爸的身高 175cm 正确，所以此说法正确。故答案为:√",
+    "knowledge_points": [
+      "厘米的认识",
+      "米的认识",
+      "厘米和米之间的进率与换算"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "97",
+    "unit": "第一单元 长度单位",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "1 米的绳子比 100 厘米的绳子短。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】将单位统一后再比较,1 米 = 100 厘米，据此解答.\n【详解】1米 = 100 厘米，则1米的绳子和100厘米的绳子一样长，原题说法错误。故答案为: ×",
+    "knowledge_points": [
+      "厘米和米之间的进率与换算"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "98",
+    "unit": "第一单元 长度单位",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "字典长 6 厘米。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】根据生活经验以及对长度单位和数据大小的认识，小朋友手掌的大小大约为十几厘米，而字典的大小远远大于小朋友的手掌，一把直尺的长度是20厘米，字典的单位是可用厘米作为单位的，据此判断即可.\n【详解】据分析可得：直尺长20厘米，字典的长可用厘米作为单位，但是字典的大小远远大于小朋友的手掌，所以6厘米不正确。故答案为: ×",
+    "knowledge_points": [
+      "厘米的认识",
+      "长度单位的选择"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "99",
+    "unit": "第一单元 长度单位",
+    "question_type": "判断题",
+    "difficulty": 0.65,
+    "question": "1米-3厘米 = 7 厘米。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】根据\"1 米 = 100 厘米\"单位换算即可解答.\n【详解】1米 = 100 厘米;100 厘米 - 3 厘米 = 97 厘米，即1米 - 3厘米 = 97 厘米。原题说法错误。故答案为: ×",
+    "knowledge_points": [
+      "一位数与两位数的退位减法",
+      "厘米和米之间的进率与换算"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "100",
+    "unit": "第一单元 长度单位",
+    "question_type": "作图题",
+    "difficulty": 0.85,
+    "question": "画一条线段，长度是 5 厘米。",
+    "options": [],
+    "answer": "见详解",
+    "solution": "【分析】准备一把直尺。将直尺平放在纸上。在直尺的 0 刻度线处点一个点作为线段的起点。找到直尺上的5厘米刻度线处，再点一个点作为线段的终点。用直线将起点和终点连接起来，这样就得到了一条 5 厘米长的线段.\n【详解】根据分析，作图如下:\n5厘米",
+    "knowledge_points": [
+      "用直尺画线段"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "101",
+    "unit": "第一单元 长度单位",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面的物体中,()的高度最接近1米。",
+    "options": [
+      "A. 课桌",
+      "B. 水杯",
+      "C. 教室的门"
+    ],
+    "answer": "A",
+    "solution": "【分析】根据生活经验，对长度单位和数据大小的认识可知：计量较长的物体用米作单位，教室黑板的高度大约是1米，计量比较短的物体的长度，通常用厘米作单位，食指的宽大约是1厘米，由此解答.\n【详解】A。课桌比黑板低一点，课桌的高度接近是1米，符合题意;B。水杯比黑板低很多，水杯的高度大约是20厘米，不符合题意;C。水杯比黑板高很多，教室门的高度大约是2米，不符合题意。故答案为:A",
+    "knowledge_points": [
+      "厘米的认识",
+      "米的认识",
+      "长度的估测"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "102",
+    "unit": "第一单元 长度单位",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "姐姐给妹妹用卷尺测量身高，妹妹用脚踩着卷尺的15厘米刻度处，头顶的刻度处是 1 米 35 厘米。妹妹的身高是( )。",
+    "options": [
+      "A. 50厘米",
+      "B. 1米35厘米",
+      "C. 1米20厘米"
+    ],
+    "answer": "C",
+    "solution": "【分析】用刻度尺对准头顶的刻度减脚踩的刻度，求出差，就是妹妹的身高;据此解决.\n【详解】1米35厘米 - 15厘米 = 1 米20厘米，即，妹妹的身高是 1 米 20 厘米。故答案为:C",
+    "knowledge_points": [
+      "厘米的认识",
+      "长度的测量方法"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "103",
+    "unit": "第一单元 长度单位",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面( )的长度最接近 10 厘米。",
+    "options": [
+      "A. 粉笔",
+      "B. 筷子",
+      "C. 牙签"
+    ],
+    "answer": "A",
+    "solution": "【分析】大拇指的指甲长度大约1厘米，小学生一拃的长度大约是10厘米，联系生活实际灵活的选择.\n【详解】A。粉笔大概10厘米长，符合;B。筷子大概 20 厘米长，不符合;C。牙签大概 5 厘米长，不符合。粉笔的长度最接近10厘米。故答案为:A",
+    "knowledge_points": [
+      "厘米的认识",
+      "长度的估测"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "104",
+    "unit": "第一单元 长度单位",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "这支铅笔的长度是( )厘米.\n\n![](images/9123a78be1705e6f044527db64e85f3076fd7bdb6f6da9c0d8eb947814e0f049.jpg)",
+    "options": [
+      "A. 7",
+      "B. 9",
+      "C. 8"
+    ],
+    "answer": "A",
+    "solution": "【分析】根据\"被测物体的长度 = 测量结束刻度 - 测量起始刻度\"来解决此题.\n【详解】9 - 2 = 7(厘米),即，这支铅笔的长度是 7 厘米。故答案为:A",
+    "knowledge_points": [
+      "长度的测量方法"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "105",
+    "unit": "第一单元 长度单位",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "10个同学肩并肩并排站立的宽度约是( )。",
+    "options": [
+      "A. 3m",
+      "B. 6m",
+      "C. 10m"
+    ],
+    "answer": "A",
+    "solution": "【分析】小学生两臂伸开的长度大约1米，站立的时候两肩的宽度一般不到1米的一半，则两个同学不到1米,10里面有5个2，则10个同学肩并肩并排站立的宽度应该不到5m,据此解答.\n【详解】3 < 5 < 6 < 10,10 个同学肩并肩并排站立的宽度约是 3 m。故答案为:A",
+    "knowledge_points": [
+      "米的认识",
+      "长度的估测"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "106",
+    "unit": "第一单元 长度单位",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "蜗牛爬了 70 厘米，蚂蚁爬了 1 米，蚂蚁比蜗牛多爬( )。",
+    "options": [
+      "A. 71厘米",
+      "B. 69 厘米",
+      "C. 30 厘米"
+    ],
+    "answer": "C",
+    "solution": "【分析】用蚂蚁爬的距离减去蜗牛爬的距离，求出差，即可解决此题。计算时，要先换算单位(1米 = 100 厘米).\n【详解】1 米 = 100 厘米,100 - 70 = 30(厘米),即，蜗牛爬了70厘米，蚂蚁爬了1米，蚂蚁比蜗牛多爬30厘米。故答案为:C",
+    "knowledge_points": [
+      "整十数之间的加减法",
+      "厘米和米之间的进率与换算"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "107",
+    "unit": "第一单元 长度单位",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面测量物体长度的方法正确的是( )。",
+    "options": [
+      "A. ![](images/9b37ca31466f00821afbd3575fa58ce423df10415ebd553406e1171543655044.jpg)",
+      "B. ![](images/c8295f1d4b0a8fde7b2f46f398190832eab9e5870688484c711621f24d8a768c.jpg)",
+      "C. ![](images/212cd69adc7478e977207c1a350924c1d0c989126a610bf75b5fe4a54b16d138.jpg)"
+    ],
+    "answer": "A",
+    "solution": "【分析】尺子测量物体时应将0刻度移动到被测物体的边缘，将直尺与被测物体重合，再观察被测物体另一端的刻度即可。当0刻度与被测物体的边缘不对齐时，用末端的刻度值减去开始的刻度值即可.\n【详解】A。测量物体长度的方法正确;B。直尺没有与被测物体重合，不正确;C。0刻度没有移动到被测物体的边缘，不正确。测量物体长度的方法正确的是A。故答案为:A",
+    "knowledge_points": [
+      "长度的测量方法"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "108",
+    "unit": "第一单元 长度单位",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "这两只笔长度相比,( ).\n\n![](images/bba9c8f9adf8e57bbcafc96368e291dfd51312e7d9cc7aacf7098a34c3225536.jpg)\n\n![](images/3c0443a7b3cc39b648038e1a3a58bec2587634f0cffb535401d65d96013b620a.jpg)",
+    "options": [
+      "A. 一样长",
+      "B. 上面一支长",
+      "C. 下面一支长"
+    ],
+    "answer": "A",
+    "solution": "【分析】根据给出的图片，上面的笔是从直尺的1厘米刻度开始到6厘米刻度结束，下面笔是从2厘米刻度开始到7厘米刻度结束，数一数可得出答案，或者用减法计算也可得出答案.\n【详解】据分析可得:6厘米 - 1厘米 = 5 厘米;7厘米 - 2厘米 = 5 厘米，所以两只笔的长度是一样的都是 5 厘米。故答案为:A",
+    "knowledge_points": [
+      "厘米的认识",
+      "长度的测量方法",
+      "数一数"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "109",
+    "unit": "第一单元 长度单位",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "如下图，有 4 个点，连接每两个点画一条线段，一共能画出( )条线段.\n\n![](images/2026-02-04%20230908.jpg)",
+    "options": [
+      "A. 7",
+      "B. 6",
+      "C. 8"
+    ],
+    "answer": "B",
+    "solution": "【分析】线段是一条直直的线，有限长，有两个端点，可以测量，据此在图中把所有的线段画出来再计数即可.\n【详解】作图如下:![](images/1792828522059e2784b163eed39780360703fb86cf323682966d2031ced5ffa2.jpg)所以连接每两个点画一条线段，一共能画出6条线段。故答案为:B",
+    "knowledge_points": [
+      "线段的初步认识"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "110",
+    "unit": "第一单元 长度单位",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "( )的长度大约是 1 厘米。",
+    "options": [
+      "A. 1 根跳绳",
+      "B. 食指宽",
+      "C. 一庹(tuǒ)"
+    ],
+    "answer": "B",
+    "solution": "【分析】根据生活经验，对长度单位和数据大小的认识可知：计量较长的物体用米作单位，二年级学生双臂展开的长度大约是1米，计量比较短的物体的长度，通常用厘米作单位，食指的宽大约是1厘米，由此选择即可.\n【详解】A。1根跳绳的长度大约是2米，不符合题意;B。食指的宽度大约是1厘米，符合题意;C。一庹是指两臂左右平伸时两手之间的距离，二年级学生一庹大约是 1 米，不符合题意。所以食指宽大约是 1 厘米。故答案为:B",
+    "knowledge_points": [
+      "厘米的认识",
+      "\"身体尺\"的认识及应用",
+      "米的认识",
+      "长度的估测"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "111",
+    "unit": "第一单元 长度单位",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "小明和妈妈同时用拃量同一根彩带，小明量的是 7 拃，妈妈量的是 4 拃,()。",
+    "options": [
+      "A. 小明量的彩带长",
+      "B. 妈妈量的彩带长",
+      "C. 俩人量的同样长"
+    ],
+    "answer": "C",
+    "solution": "【分析】由题可知，小明和妈妈量的是同一根彩带，所以无论两人各量出的是几拃，彩带的长是不变的。两人量的拃数不同，是因为两人拃的长度不同，由此解答.\n【详解】由分析可知：小明和妈妈同时用拃量同一根彩带，小明量的是7拃，妈妈量的是4拃，俩人量的同样长。故答案为:C",
+    "knowledge_points": [
+      "长度的测量方法",
+      "\"身体尺\"的认识及应用"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "112",
+    "unit": "第一单元 长度单位",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "柜子里最多可以横着放( )个箱子.\n\n![](images/ce12ba5372094805297703cd54caf260d551fab1ad33c467a24cff6358cc302a.jpg)\n1米\n\n![](images/a605c994b55721d2dc3c208801d4aec0361342ec7d883e8e48f0056156a455ab.jpg)\n40厘米",
+    "options": [
+      "A. 1",
+      "B. 2",
+      "C. 3"
+    ],
+    "answer": "B",
+    "solution": "【分析】先把1米换成100厘米，再用减法计算100厘米里面有几个40厘米，就表示柜子里最多可以横着放几个箱子.\n【详解】1米 = 100 厘米;100 - 40 = 60(厘米);60 - 40 = 20(厘米),即,100 厘米里面有 2 个 40 厘米，故，柜子里最多可以横着放 2 个箱子。故答案为:B",
+    "knowledge_points": [
+      "整十数之间的加减法",
+      "厘米和米之间的进率与换算"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "113",
+    "unit": "第一单元 长度单位",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "李力的身高是 96 厘米，赵志比李力矮 4 厘米，赵志的身高是( )。",
+    "options": [
+      "A. 100 厘米",
+      "B. 92厘米",
+      "C. 94厘米"
+    ],
+    "answer": "B",
+    "solution": "【分析】李力的身高是96厘米，赵志比李力矮4厘米，求赵志的身高是多少，就是比一个数少几的数是多少，用减法列式解决.\n【详解】96 - 4 = 92(厘米),赵志的身高是 92 厘米。故答案为:B",
+    "knowledge_points": [
+      "厘米的认识",
+      "两位数与一位数的减法(不退位)"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "114",
+    "unit": "第一单元 长度单位",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "( )最接近 1 米。",
+    "options": [
+      "A. 餐桌的高",
+      "B. 教室的长",
+      "C. 小朋友的一步长"
+    ],
+    "answer": "A",
+    "solution": "【分析】根据生活经验，对长度单位和数据大小的认识可知：计量较长的物体用米作单位，二年级学生双臂展开的长度大约是1米;计量较短的物体用厘米作单位，食指的宽大约是1厘米。由此选择.\n【详解】A。餐桌的高大约是1米;B。教室的长大约是 4 米;C。小朋友的一步长大约是 30 厘米。所以餐桌的高最接近 1 米。故答案为:A",
+    "knowledge_points": [
+      "厘米的认识",
+      "米的认识",
+      "长度的估测"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "115",
+    "unit": "第一单元 长度单位",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面的测量正确的是( )。",
+    "options": [
+      "A. ![](images/afcf9ce454b0f2a12618508d7ef9617b401f6a8d41ef3af8f27030f180639a0f.jpg) 7厘米",
+      "B. ![](images/dd2566174aeb8f4396eda6ea6e38908183b601adc745b671ecf6fcf3dbef2a17.jpg) 5厘米",
+      "C. ![](images/ea12bd4db41a9352124b983946b03c689b28d82df3a43a7c51f60a5535f151c0.jpg) 6厘米"
+    ],
+    "answer": "C",
+    "solution": "【分析】测量长度时，要把刻度尺放到被测物体的上面(容易观察数据),用刻度尺的0刻度对准被测物体的一端，且刻度尺要与被测物体对齐(不能倾斜),再看看另一端所对的刻度是几，被测物体的长度就是几;如果没有用0刻度对准被测物体的一端，则结束刻度 - 起始刻度 = 被测物体长度.\n【详解】A。 测量时没有用刻度尺的0刻度对准被测物体的一端，被测物体的长度为:7 - 1 = 6(厘米),测量不正确，不符合题意;B. 测量时没有把刻度尺放到被测物体的上面(不易观察数据),并且起始刻度对应0，结束刻度对应6，被测物体的长度为6厘米，测量不正确，不符合题意;C。测量时把刻度尺放到被测物体的上面，用刻度尺的0刻度对准被测物体的一端，且刻度尺与被测物体对齐(不能倾斜),刻度尺的另一端对准6，被测物体的长度为6厘米，测量正确，符合题意。故答案为:C",
+    "knowledge_points": [
+      "长度的测量方法"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "116",
+    "unit": "第一单元 长度单位",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "下面的说法正确的是( )。",
+    "options": [
+      "A. 量比较短的物体，通常用\"米\"作单位;",
+      "B. 指甲宽大约是\"1 米。",
+      "C. 一根旗杆的高度大约是 13 米。"
+    ],
+    "answer": "C",
+    "solution": "【分析】测量较短的物体时通常用\"厘米\"作单位，指甲宽大约为1厘米;测量较长的物体时通常用\"米\"作单位，讲桌大约长 1 米.\n【详解】A。量比较短的物体，通常用\"厘米\"作单位，说法错误;B。指甲宽大约是\"1 厘米\"，说法错误;C。测量较长的物体时通常用\"米\"作单位，讲桌大约长1米;旗杆的高度用\"米\"作单位比较合适，所以一根旗杆的高度大约是13米，说法正确。故答案为:C",
+    "knowledge_points": [
+      "厘米的认识",
+      "米的认识"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "117",
+    "unit": "第一单元 长度单位",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "直尺上从刻度 3 到刻度 7 之间长( )。",
+    "options": [
+      "A. 3cm",
+      "B. 4cm",
+      "C. 7cm"
+    ],
+    "answer": "B",
+    "solution": "【分析】测量物体时，把尺的0刻度对准物体的左端，再看末端对着几，长度就是几。若测量的物体不是对准 0 刻度，则用测量物体的末尾刻度减去开始刻度即可求出物体长度，据此解答.\n【详解】7 - 3 = 4(cm),直尺上从刻度 3 到刻度 7 之间长 4 cm。故答案为:B",
+    "knowledge_points": [
+      "厘米的认识",
+      "长度的测量方法"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "118",
+    "unit": "第一单元 长度单位",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "100 厘米和 1 米比较,( )是正确的。",
+    "options": [
+      "A. 100 厘米比 1 米长",
+      "B. 1 米比 100 厘米长",
+      "C. 100 厘米和 1 米一样长"
+    ],
+    "answer": "C",
+    "solution": "【分析】根据\"1米 = 100 厘米\"来解决此题即可.\n【详解】由题意分析得:1 米 = 100 厘米，即,100厘米和1米比较,100厘米和1米一样长。故答案为:C",
+    "knowledge_points": [
+      "厘米和米之间的进率与换算"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "119",
+    "unit": "第一单元 长度单位",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "我们用的直尺，从刻度 0 到刻度 7 是( )厘米。",
+    "options": [
+      "A. 0",
+      "B. 7",
+      "C. 8"
+    ],
+    "answer": "B",
+    "solution": "【分析】根据测量物体的方法：用直尺去测量物体的长度时，要把直尺上的\"0\"刻度线和物体的左端对齐，物体的右端对应数字是几，就表示这个物体有多长。若测量时，不是\"0\"刻度线与左侧对齐的话，就用测量结束的刻度减去测量起始的刻度即可.\n【详解】由分析可得：从刻度0到刻度7是(7)厘米。故答案为:B",
+    "knowledge_points": [
+      "长度的测量方法"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "120",
+    "unit": "第一单元 长度单位",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "图中有( )条线段.\n\n![](images/2026-02-04%20232006.jpg)",
+    "options": [
+      "A. 3",
+      "B. 1",
+      "C. 6"
+    ],
+    "answer": "C",
+    "solution": "【分析】线段是直的，有两个端点，可以测量长度;第一个点向右数有3条线段，第二个点向右数有2条线段，第三个点向右数有 1 条线段，相加即可求出一共有多少线段.\n【详解】1 + 2 + 3 = 3 + 3 = 6(条),图中有6条线段。故答案为:C",
+    "knowledge_points": [
+      "数图形(线段，直线，射线)",
+      "线段的初步认识"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "121",
+    "unit": "第一单元 长度单位",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "这根绳子的长度是( ).\n\n![](images/1d16b0341b75cd1ebb9628f7e2c0fde9c2f68d0c94fbbf9ec638827b0b3d0e93.jpg)",
+    "options": [
+      "A. 16厘米",
+      "B. 9厘米",
+      "C. 7 厘米"
+    ],
+    "answer": "B",
+    "solution": "【分析】用直尺测量物体长度时，要把直尺的0刻度线对准物体的左端，物体的另一端与直尺对应的刻度就是物体的长度。若物体的一端未与0刻度线对齐，则用测量结束的刻度减去测量开始的刻度得到物体的长度。由图可知，这根绳子左端对着刻度7厘米，右端对着刻度16厘米，直接用减法即可算出这根绳子的长度.\n【详解】16 - 7 = 9(厘米),即这根绳子的长度是 9 厘米。故答案为:B",
+    "knowledge_points": [
+      "长度的测量方法"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "122",
+    "unit": "第一单元 长度单位",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "一根绳子长 1 米，先用去 40 厘米，现在又要用 60 厘米,( )。",
+    "options": [
+      "A. 正好够用",
+      "B. 不够用",
+      "C. 还能剩下"
+    ],
+    "answer": "A",
+    "solution": "【分析】先把1米换算成100厘米，然后用100厘米减去先用去的长度，求出差，再与又要用的长度比较一下，即可解决.\n【详解】1米 = 100 厘米,100 - 40 = 60(厘米),即，一根绳子长 1 米，先用去 40 厘米，现在又要用 60 厘米，正好够用。故答案为:A",
+    "knowledge_points": [
+      "整十数之间的加减法",
+      "厘米和米之间的进率与换算"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "123",
+    "unit": "第一单元 长度单位",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "如图，这根细绳大约长( )厘米.\n\n![](images/05f3482c2e61775f17364caac355216e13e21885465834acc70e94578e86af9f.jpg)",
+    "options": [
+      "A. 7",
+      "B. 6",
+      "C. 5"
+    ],
+    "answer": "A",
+    "solution": "【分析】用直尺测量物体长度时，要把直尺的0刻度线对准物体的左端，物体的另一端与直尺对应的刻度就是物体的长度。若物体的一端未与0刻度线对齐，则用测量结束的刻度减去测量开始的刻度算出物体的长度。由图可知，这根绳子有三段，先把三段的长度算出来，然后再把它们加起来即可算出这根细绳大约长多少厘米.\n【详解】第一段:6 - 3 = 3(厘米),第二段:6 - 5 = 1(厘米),第三段:8 - 5 = 3(厘米)。3 + 1 + 3 = 4 + 3 = 7(厘米),即这根细绳大约长 7 厘米。故答案为:A",
+    "knowledge_points": [
+      "长度的测量方法"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "124",
+    "unit": "第一单元 长度单位",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面是线段的是()。",
+    "options": [
+      "A. ![](images/2026-02-04%20232335.jpg)",
+      "B. ![](images/2026-02-04%20232409.jpg)",
+      "C. ![](images/2026-02-04%20232450.jpg)"
+    ],
+    "answer": "C",
+    "solution": "【分析】线段有两个端点，中间是直直的线，长度可测量，由此解答.\n【详解】A。没有两个端点，不是线段;B。中间不是直直的线，不是线段;C。是线段。所以C是线段。故答案为:C",
+    "knowledge_points": [
+      "线段的初步认识"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "125",
+    "unit": "第一单元 长度单位",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面说法正确的是( )。",
+    "options": [
+      "A. 86厘米 > 5 米",
+      "B. 一个二年级小朋友高约120 米",
+      "C. 一根铅笔长约 20 厘米",
+      "D. 1 米的铁线比 100 厘米的绳子短"
+    ],
+    "answer": "C",
+    "solution": "【分析】根据生活经验，对长度单位和数据大小的认识可知：测量较长的物体用米作单位，二年级学生双臂展开的长度大约是1米，量比较短的物体的长度，通常用厘米作单位，食指的宽大约是 1 厘米，由此选择合适的单位;同单位的直接比较大小，不同单位的根据1米 = 100 厘米统一单位再比较.\n【详解】A。86 厘米<100 厘米;100 厘米 = 1 米,1 米 < 5 米，则 86 厘米 < 5 米，原题说法错误;B。二年级小朋友的身高约为 120 厘米，原题说法错误;C。一根铅笔长约 20 厘米，原题说法正确;D。1米 = 100 厘米，则1米的铁线和100厘米的绳子一样长，原题说法错误。所以说法正确的是一根铅笔长约 20 厘米。故答案为:C",
+    "knowledge_points": [
+      "长度的估测",
+      "厘米和米之间的进率与换算",
+      "长度单位的选择"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "126",
+    "unit": "第一单元 长度单位",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "漳平西站到龙岩站的动车途经雁石南，这班列车往返一共可以售出( )种车票.\n\n![](images/2026-02-04%20232802.jpg)",
+    "options": [
+      "A. 6",
+      "B. 4",
+      "C. 3",
+      "D. 2"
+    ],
+    "answer": "A",
+    "solution": "【分析】线段有两个端点，中间是直直的线，长度可测量。根据题意，每两站都可以看成是一段线段，先数出有多少条线段，往返都可以售票，每条线段中都能售出2种票，也就是售出车票的种类是线段的数量加上线段的数量的和.\n【详解】![](images/e854da4bcfbaa429c57a61cd2f0bb97752b1ef78d6240fdb0452112b93a51c27.jpg)3 + 3 = 6(种),这班列车往返一共可以售出6种车票。故答案为:A",
+    "knowledge_points": [
+      "线段的初步认识"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "127",
+    "unit": "第一单元 长度单位",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面 4 个图形中,( )是线段。",
+    "options": [
+      "A. ![](images/2026-02-04%20232955.jpg)",
+      "B. ![](images/2026-02-04%20233008.jpg)",
+      "C. ![](images/2026-02-04%20233025.jpg)",
+      "D. ![](images/2026-02-04%20233042.jpg)"
+    ],
+    "answer": "B",
+    "solution": "【分析】线段有两个端点，中间是直直的线，长度可测量，由此解答.\n【详解】A。没有两个端点，不是线段;B。是线段;C。只有一个端点，不是线段;D。中间不是直直的线，不是线段。所以 B 是线段。故答案为:B",
+    "knowledge_points": [
+      "线段的初步认识"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "128",
+    "unit": "第一单元 长度单位",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "篮球架的高度大约是( ).\n\n![](images/c57afbe2b6e92405fd3af9041a2116f8fe565d93989c90fbbc7b7bcb350a08c9.jpg)",
+    "options": [
+      "A. 3厘米",
+      "B. 3米",
+      "C. 6 米",
+      "D. 2 米"
+    ],
+    "answer": "B",
+    "solution": "【分析】由图可知，篮球架的高度大约是3个小朋友的身高，也就是3个1米的高度，由此用加法计算出篮球架大约高多少即可。![](images/8be992fb0e70e2604f2491c7bf3a82640991d1104571a6a759637ecf953fe637.jpg)\n【详解】1 + 1 + 1 = 3(米),篮球架的高度大约是3米。故答案为:B",
+    "knowledge_points": [
+      "米的认识",
+      "长度的估测"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "129",
+    "unit": "第一单元 长度单位",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "用一根皮绳量一条线段的长度，这条线段长( ).\n\n![](images/c3d807f146475eae789915b91fec22b8b6d2286fe539f5cc993bee75e50182c6.jpg)",
+    "options": [
+      "A. 52 厘米",
+      "B. 62 厘米",
+      "C. 72 厘米"
+    ],
+    "answer": "A",
+    "solution": "【分析】观察图片可知：一大格是10厘米，则这个线段的长度是10到62厘米，则根据若左端未与0刻度线对齐，则用测量结束的刻度 - 测量开始的刻度 = 物体的长度即可求出该线段的长度.\n【详解】62 - 10 = 52(厘米),则这条线段长52厘米。故答案为:A",
+    "knowledge_points": [
+      "长度的测量方法",
+      "两位数与整十数的减法"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "130",
+    "unit": "第一单元 长度单位",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "小明的床宽 120()。",
+    "options": [
+      "A. 厘米",
+      "B. 分米",
+      "C. 米"
+    ],
+    "answer": "A",
+    "solution": "【分析】在选择长度单位时，应根据测量对象的长度来决定使用厘米，分米还是米。较短物体，例如，一支铅笔的长度，一本书的厚度等，这些物体的长度通常在几厘米到几十厘米之间，因此使用厘米作为单位更为合适。较长物体，例如，一栋大楼的高度，一个房间的长度等，这些物体都比较长，因此使用米作为单位更为合适。分米一般作为中间单位，在厘米和米之间进行转换时使用。例如，测量一个物体的长度为 40 厘米时，可以说成 4 分米.\n【详解】根据分析可知，小明的床虽然是比较长的物体，用米做单位更合适，但是前面的数是120，已经比较大了，所以我们选择厘米作为单位即可;小明的床宽120厘米。故答案为:A.",
+    "knowledge_points": [
+      "长度单位的选择"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "131",
+    "unit": "第一单元 长度单位",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "要知道学校操场的长度应该用( )来测量。",
+    "options": [
+      "A. 卷尺",
+      "B. 直尺",
+      "C. 三角尺"
+    ],
+    "answer": "A",
+    "solution": "【分析】测量物体的长度，应该选择合适的工具，比较大的物体，应该用卷尺，较小的物体用米尺，再小的用三角尺.\n【详解】A。卷尺，可以卷起来的尺子，可以变形，一般有3 米,5 米,50 米等，适合用来测量操场的长度;B。直尺，长度一般为20厘米，常用来测量书本，桌子的长度等，不适合用来测量操场的长度;C。三角尺，大多数尺寸在10厘米左右，一般用来测量较短的物体，不适合用来测量操场的长度;所以要知道学校操场的长度应该用卷尺来测量。故答案为:A",
+    "knowledge_points": [
+      "长度的测量方法"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "132",
+    "unit": "第一单元 长度单位",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面说法错误的是( )。",
+    "options": [
+      "A. 长颈鹿高约 5 米",
+      "B. 爸爸腿很长，一步能跨 65米",
+      "C. 状状立定跳远的成绩是 130 厘米"
+    ],
+    "answer": "B",
+    "solution": "【分析】大拇指的指甲长度大约1厘米，小学生两臂伸开的长度大约1米。根据情景选择合适的计量单位，要注意联系生活实际，计量单位和数据的大小，灵活的选择.\n【详解】A。长颈鹿高约 5 米，原题说法正确。B。爸爸腿很长，一步能跨65厘米，原题说法错误。C。状状立定跳远的成绩是 130 厘米，原题说法正确。错误的是：爸爸腿很长，一步能跨 65 米。故答案为:B",
+    "knowledge_points": [
+      "厘米的认识",
+      "米的认识",
+      "长度单位的选择"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "133",
+    "unit": "第一单元 长度单位",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面物品中,( )比较接近 1 厘米。",
+    "options": [
+      "A. 1 本数学书的厚度",
+      "B. 1个文具盒的宽度",
+      "C. 1 支铅笔的长度"
+    ],
+    "answer": "A",
+    "solution": "【分析】根据生活经验，对长度单位和数据大小的认识可知：量比较短的物体的长度，通常用厘米作单位，食指的宽大约是1厘米，由此选择.\n【详解】A。1本数学书的厚度大约是1厘米，符合题意;B。1 个文具盒的宽度大约是 10 厘米，不符合题意;C。1 支铅笔的长度大约是 20 厘米，不符合题意。所以1本数学书的厚度比较接近1厘米。故答案为:A",
+    "knowledge_points": [
+      "厘米的认识",
+      "长度的估测"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "134",
+    "unit": "第一单元 长度单位",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "借助学生尺量一量，线段①和线段②相比( ).\n\n![](images/a2b3aed72d9ac805032ebe6166dc43bf44c6bb5394815fcc625ae48b75139d7c.jpg)",
+    "options": [
+      "A. 线段①长",
+      "B. 线段②长",
+      "C. 一样长"
+    ],
+    "answer": "C",
+    "solution": "【分析】直尺的\"0\"刻度线和所量图形的一个端点重合，另一个端点在直尺上的刻度，就是该线段的长度。用尺子量出两条线段的长度都是 1 厘米，所以两条线段一样长.\n【详解】由分析可知，线段①和线段②相比一样长。故答案为:C",
+    "knowledge_points": [
+      "厘米的认识",
+      "长度的测量方法",
+      "线段的初步认识"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "135",
+    "unit": "第一单元 长度单位",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下图中，铅笔的长度是( )厘米.\n\n![](images/a2ffc8dcf2bbf439587d4e075fb7b14b376eb282e9072b101188927487cc1140.jpg)",
+    "options": [
+      "A. 1",
+      "B. 11",
+      "C. 12"
+    ],
+    "answer": "B",
+    "solution": "【分析】物体的长度 = 测量结束刻度 - 测量开始刻度，据此填空即可.\n【详解】12 - 1 = 11(厘米),铅笔的长度是11厘米。故答案为:B",
+    "knowledge_points": [
+      "长度的测量方法"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "136",
+    "unit": "第一单元 长度单位",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "昆虫王国举行跳远比赛，蚂蚱从直尺上刻度0跳到刻度5，蟋蟀从刻度7跳到刻度8，比赛结果是( )。",
+    "options": [
+      "A. 蚂蚱获胜",
+      "B. 蟋蟀获胜",
+      "C. 无法确定"
+    ],
+    "answer": "A",
+    "solution": "【分析】直尺上的单位是厘米。算出它们各自跳的距离，然后比较，跳的距离长的获胜.\n【详解】5 - 0 = 5(厘米),8 - 7 = 1(厘米),5 > 1，因此蚂蚱获胜。故答案为:A",
+    "knowledge_points": [
+      "长度的测量方法"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "137",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "在括号里填上适当的长度单位.\n课桌长是 60( );篮球场长 28( );哥哥的身高是1( )52( )",
+    "options": [],
+    "answer": "厘米或cm;米或m;米或m;厘米或cm",
+    "solution": "【分析】根据生活经验，对长度单位和数据大小的认识可知：计量比较短的物体的长度，通常用厘米作单位;计量较长的物体用米作单位;哥哥的身高应写作1米52厘米.\n【详解】课桌长是60厘米;篮球场长28米;哥哥的身高是1米52厘米。",
+    "knowledge_points": [
+      "长度单位的选择"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "138",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "学校旗杆的高度大约是 15( )。",
+    "options": [],
+    "answer": "米或m",
+    "solution": "【分析】根据生活经验，对长度单位和数据大小的认识可知：计量较长的物体用米作单位，计量旗杆的高度用米作单位比较合适.\n【详解】学校旗杆的高度大约是 15 米。",
+    "knowledge_points": [
+      "米的认识",
+      "长度单位的选择"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "139",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "填一填\n\n![](images/2e0aade022493223488653d40f44a22829bc2625e3666c5a283308367bef674a.jpg)\n\n![](images/ca7db74d83416fd1dde64b1f2b39edfc627a30f32d82e685e8672229943b0933.jpg)\n\n钉子长( )厘米;铅笔长( )厘米。",
+    "options": [],
+    "answer": "3;9",
+    "solution": "【分析】测量物体长度时，将物体的一侧与直尺的0刻度线对齐，物体与直尺放平不倾斜;若一侧未与0刻度线对齐，则用测量结束的刻度 - 测量开始的刻度 = 物体的长度.\n【详解】10 - 1 = 9(厘米),钉子长3厘米，铅笔长9厘米。",
+    "knowledge_points": [
+      "厘米的认识",
+      "长度的测量方法"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "140",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "在下面的括号里填上合适的长度单位。龙龙同学今年上二年级，他的身高是 1( )25( ),他喜欢数学课，数学书封面长21( )。他也喜欢体育锻炼，每天带着长2( )的跳绳练习，经过长期锻炼，身高达到了130( )。",
+    "options": [],
+    "answer": "米或m;厘米或cm;厘米或cm;米或m;厘米或cm",
+    "solution": "【分析】联系生活实际，计量单位和数据的大小，灵活选择。身高一般用米和厘米表示;数学书封面用厘米;跳绳长度用米;最后一空用厘米.\n【详解】龙龙身高是1米25厘米;数学书封面长21厘米;跳绳长2米;身高达到了130厘米。",
+    "knowledge_points": [
+      "厘米的认识",
+      "米的认识",
+      "长度单位的选择"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "141",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "在括号里填上米或厘米.\n(1)桌子高 80( ).\n(2)毛巾长 50( ).\n(3)一棵树高 7( ).\n(4)一本故事书宽 15( )。",
+    "options": [],
+    "answer": "厘米或cm;厘米或cm;米或m;厘米或cm",
+    "solution": "【分析】结合生活经验与数据大小选择合适单位.\n【详解】(1)桌子高 80 厘米。(2)毛巾长 50 厘米。(3)一棵树高 7 米。(4)一本故事书宽15厘米。",
+    "knowledge_points": [
+      "厘米的认识",
+      "米的认识",
+      "长度单位的选择"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "142",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "拉紧一条线，可以看作一条( ),它是( )的，可以测量出( )。",
+    "options": [],
+    "answer": "线段;直;长度",
+    "solution": "【分析】线段两端都有端点，不可延长，两个端点间的线条是直的，可以度量.\n【详解】拉紧一条线，可以看作一条线段，它是直的，可以测量出长度。",
+    "knowledge_points": [
+      "线段的初步认识"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "143",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "尺子是用来测量()的工具，尺子上的\"厘米\"就是一个统一的( )单位，它可以用字母( )表示，它是用来测量比较( )的物体长度.\n\n![](images/d912994ff5680c558a52f7edbf730a6925d6e2bf20072dc5040a07073f059b75.jpg)",
+    "options": [],
+    "answer": "长度;长度;cm;短",
+    "solution": "【详解】尺子是用来测量长度的工具，尺子上的\"厘米\"就是一个统一的长度单位，它可以用字母 cm 表示，它是用来测量比较短的物体长度。",
+    "knowledge_points": [
+      "厘米的认识"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "144",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "一根跳绳长约 2( ),一本字典厚约 5( )。",
+    "options": [],
+    "answer": "米或m;厘米或cm",
+    "solution": "【分析】食指的宽大约是1厘米，小学生一庹的长度大约是1米，据此选择合适单位.\n【详解】一根跳绳长 2 米，一本字典厚约 5 厘米。",
+    "knowledge_points": [
+      "厘米的认识",
+      "米的认识",
+      "长度单位的选择"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "145",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "铅笔长( )厘米;橡皮长( )厘米.\n\n![](images/9a95a805d3d20df0acce3b2874295757e3f787428469e2da46af179bc23cdd0f.jpg)\n\n![](images/37052d610e792a717b7de72738d3f1a4a58659f20edad782a3360f7f434ed93b.jpg)",
+    "options": [],
+    "answer": "6;4",
+    "solution": "【分析】用直尺的\"0\"刻度线和线段的一个端点重合，另一个端点在直尺上的刻度，就是该线段的长度;若未从0开始，则用结束刻度减开始刻度.\n【详解】从图上可得：铅笔的长度是 6 厘米;7 - 3 = 4(厘米),所以橡皮长 4 厘米。",
+    "knowledge_points": [
+      "长度的测量方法"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "146",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "在括号里填上\"米\"或\"厘米\".\n\n![](images/fe621600358535976dee47b2236c89b6a9624b1866b6d54684a3ee74b12662d7.jpg)\n长约 5( )\n\n![](images/5c096593770aa27cfa49cea2c99ba8a639a9d9f5e28af52b4fe7e3e444a2972d.jpg)\n厚约 4( )\n\n![](images/92ce3fb2372a879f7334ed8337625bb9a0efcd9d1513fbd6ac26c25580aebd16.jpg)\n高约 45( )",
+    "options": [],
+    "answer": "米或m;厘米或cm;米或m",
+    "solution": "【分析】根据生活经验，对长度单位和数据大小的认识可知：计量较长的物体用米作单位;计量较短的物体用厘米作单位.\n【详解】汽车长约5米，字典厚约4厘米，高楼高约45米。",
+    "knowledge_points": [
+      "长度单位的选择"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "147",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "在括号里填上\"米\"或\"厘米\".\n黑板长 4( );筷子长约 20( );小梦的身高是 1( )32( )",
+    "options": [],
+    "answer": "米或m;厘米或cm;米或m;厘米或cm",
+    "solution": "【分析】联系生活实际，计量单位和数据的大小，灵活选择.\n【详解】黑板长 4 米;筷子长约 20 厘米;小梦的身高是 1 米 32 厘米。",
+    "knowledge_points": [
+      "厘米的认识",
+      "米的认识",
+      "长度单位的选择"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "148",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "在( )里填上合适的长度单位.\n教室的长约 8( );跳绳长约 2( )\n一支铅笔长约 16( );一本新华字典的厚约 5( )",
+    "options": [],
+    "answer": "米或m;米或m;厘米或cm;厘米或cm",
+    "solution": "【分析】根据生活经验，对长度单位和数据大小的认识可知：计量较长的物体用米作单位;计量较短的物体用厘米作单位.\n【详解】教室的长约8米，跳绳长约2米，一支铅笔长约16厘米，一本新华字典的厚约5厘米。",
+    "knowledge_points": [
+      "长度单位的选择"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "149",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "填上合适的单位.\n(1)一棵大树高 4( ).\n(2)一本字典厚约 3( )。",
+    "options": [],
+    "answer": "米或m;厘米或cm",
+    "solution": "【分析】计量较长的物体用米作单位;计量较短的物体用厘米作单位.\n【详解】(1)一棵大树高4米。(2)一本字典厚约3厘米。",
+    "knowledge_points": [
+      "长度单位的选择"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "150",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "1 米 = ( )厘米;33 厘米 - 6 厘米=( )厘米;图钉的长大约是 1( );一棵大树高约 12( )",
+    "options": [],
+    "answer": "100;27;厘米或cm;米或m",
+    "solution": "【分析】同单位的直接相加减，不同单位的根据1米 = 100 厘米换算单位即可;结合生活经验选择合适单位.\n【详解】1 米 = 100 厘米,33 厘米 - 6 厘米 = 27 厘米，图钉的长大约是 1 厘米，一棵大树高约 12 米。",
+    "knowledge_points": [
+      "厘米和米之间的进率与换算",
+      "长度单位的选择"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "151",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "在括号里填上\"厘米\"或\"米\".\n\n![](images/a56278a6b02696a05a099e6c360d9de3b2ba501ed32b396ececaa670114a9771.jpg)\n\n![](images/c60bb6f1d6e01184662f63ec699df52029e7d1a4db22f21662252428e143ce61.jpg)\n\n![](images/7263b29fd90d5b9d663b491919cc12c9242e0264bc6023d729e8f19b4466574f.jpg)\n\n树高约 15( );轿车长约 4( );叶子长约 10( )",
+    "options": [],
+    "answer": "米或m;米或m;厘米或cm",
+    "solution": "【分析】根据生活经验，对长度单位和数据大小的认识可知：计量较长的物体用米作单位;计量较短的物体用厘米作单位.\n【详解】树高约15米;轿车长约4米;叶子长约10厘米。",
+    "knowledge_points": [
+      "长度单位的选择"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "152",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "在括号里填上合适的长度单位.\n\n![](images/dae838c374784394a904f51653e0b8a8b949670cc253043312026b5af84cb2fb.jpg)\n\n![](images/96ba127977728a42e63dac59a67011cf4d9a2188e3998280e8111dce0fdd1553.jpg)\n\n![](images/a24804a7ade3e435ded2be8246e5cd46297cc76ad2e92d04f9ea26cf05bbc5ef.jpg)\n\n桌子高 80( );大树高 9( );数学书宽 18( )",
+    "options": [],
+    "answer": "厘米或cm;米或m;厘米或cm",
+    "solution": "【分析】根据生活经验和实际数据相结合，计量桌子高度用厘米作单位;计量大树高度用米作单位;计量数学书宽用厘米作单位.\n【详解】桌子高80厘米;大树高9米;数学书宽18厘米。",
+    "knowledge_points": [
+      "厘米的认识",
+      "米的认识",
+      "长度单位的选择"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "153",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "在括号里填上合适的长度单位.\n\n![](images/bc271dd8b7901274e44a0530bbcee68374a6ffdc43383d1254cec2c8ae40e06f.jpg)\n\n![](images/ecde10a55f2f9ce81d75385a8c9aafe9954974c72c453fcf2ff30f0a665f96c0.jpg)\n\n小树高约 7( );牙刷长 15( )",
+    "options": [],
+    "answer": "米或m;厘米或cm",
+    "solution": "【分析】根据生活经验，对长度单位和数据大小的认识可知：测量较长的物体用米作单位;量比较短的物体用厘米作单位.\n【详解】小树高约 7 米;牙刷长 15 厘米。",
+    "knowledge_points": [
+      "长度单位的选择"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "154",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "丽丽身高 1( )25( );她的课桌高 67( );她家的大树高 5( );她的文具盒长 24( )。",
+    "options": [],
+    "answer": "米或m;厘米或cm;厘米或cm;米或m;厘米或cm",
+    "solution": "【分析】结合数据大小与生活经验选择合适的长度单位.\n【详解】丽丽身高为1米25厘米;她的课桌高67厘米;她家的大树高5米;她的文具盒长24厘米。",
+    "knowledge_points": [
+      "长度单位的选择"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "155",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "在括号里填上合适的单位。大树高约 8( ),小明高 1( )35( ),读书时，眼睛与书本的距离约为 30( )。",
+    "options": [],
+    "answer": "米或m;米或m;厘米或cm;厘米或cm",
+    "solution": "【分析】根据生活经验以及对长度单位和数据大小的认识，结合实际情况选择合适的单位即可.\n【详解】大树高约 8 米，小明高 1 米 35 厘米，读书时眼睛与书本的距离约为 30 厘米。",
+    "knowledge_points": [
+      "厘米的认识",
+      "米的认识",
+      "长度单位的选择"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "156",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "![](images/a11157052983021f9ba7715ec2ef8cad6c1d50fbd65b58f21b135216175ed5db.jpg)\n\n![](images/eb9a98e1f756580902f55c0c4c9526302beaeddbcf923037982930711a2db710.jpg)\n\n橡皮擦长( )厘米;蜡笔长( )厘米",
+    "options": [],
+    "answer": "3;6",
+    "solution": "【分析】用直尺测量物体长度时，若未从0刻度对齐，则用测量结束的刻度 - 测量起始的刻度.\n【详解】5 - 2 = 3(厘米);7 - 1 = 6(厘米),所以橡皮擦长3厘米，蜡笔长6厘米。",
+    "knowledge_points": [
+      "厘米的认识",
+      "长度的测量方法"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "157",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "在直尺上，从刻度\"0\"到刻度\"1\"是( )厘米，从刻度\"5\"到刻度\"12\"是( )厘米。",
+    "options": [],
+    "answer": "1;7",
+    "solution": "【分析】被测物体的长度 = 测量结束刻度 - 测量起始刻度.\n【详解】1 - 0 = 1(厘米);12 - 5 = 7(厘米),即从刻度\"0\"到刻度\"1\"是 1 厘米，从刻度\"5\"到刻度\"12\"是 7 厘米。",
+    "knowledge_points": [
+      "长度的测量方法"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "158",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "这枝铅笔长( )厘米.\n\n![](images/a1a2e2319a73396284bf29d5641861c8ad87ff766b9f523e284b3d6e9adda232.jpg)",
+    "options": [],
+    "answer": "4",
+    "solution": "【分析】铅笔的长度在直尺上从5厘米刻度到9厘米刻度，用减法计算即可.\n【详解】9厘米 - 5厘米 = 4 厘米。这枝铅笔长(4)厘米。",
+    "knowledge_points": [
+      "厘米的认识",
+      "长度的测量方法"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "159",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "在括号里填入合适的长度单位.\n(1)一座楼房大约高 18( ).\n(2)一张床长 2( ).\n(3)一个牙刷长 17( ).\n(4)一个图钉长约 1( )。",
+    "options": [],
+    "answer": "米或m;米或m;厘米或cm;厘米或cm",
+    "solution": "【分析】计量较长的物体用米作单位;计量比较短的物体用厘米作单位.\n【详解】(1)一座楼房大约高18米。(2)一张床长2米。(3)一个牙刷长17厘米。(4)一个图钉长约1厘米。",
+    "knowledge_points": [
+      "长度单位的选择"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "160",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "在括号里填上\"米\"或\"厘米\".\n凳子高约 50( );教室黑板长约 4( );铅笔长约 18( )",
+    "options": [],
+    "answer": "厘米或cm;米或m;厘米或cm",
+    "solution": "【分析】计量比较短的物体用厘米作单位;计量较长的物体用米作单位.\n【详解】凳子高约50厘米;教室黑板长约4米;铅笔长约18厘米。",
+    "knowledge_points": [
+      "长度单位的选择"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "161",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "在( )里填上合适的长度单位.\n一本成语词典厚约 4( );我们班小华同学高约 125( )\n一个跳绳长约 2( );一部手机宽约 7( )",
+    "options": [],
+    "answer": "厘米或cm;厘米或cm;米或m;厘米或cm",
+    "solution": "【分析】根据生活经验对长度单位和数据的认知：量比较长的物体用米作单位;量比较短的物体用厘米作单位.\n【详解】一本成语词典厚约4厘米;小华同学高约125厘米;一个跳绳长约2米;一部手机宽约7厘米。",
+    "knowledge_points": [
+      "厘米的认识",
+      "米的认识",
+      "长度单位的选择"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "162",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "如图，回形针长( )厘米，电池长( )厘米.\n\n![](images/eec6de810f54412faecea2fa39b6b7188aa9360d9219cbaafb217b615a4a9ef6.jpg)",
+    "options": [],
+    "answer": "2;4",
+    "solution": "【分析】测量物体长度时，将物体的一侧与直尺的0刻度线对齐;若未对齐，则用结束刻度减开始刻度.\n【详解】9 - 5 = 4(厘米),所以回形针长2厘米，电池长4厘米。",
+    "knowledge_points": [
+      "厘米的认识",
+      "长度的测量方法"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "163",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "橡皮长( )厘米，铅笔长( )厘米.\n\n![](images/402dd89c55a6401f7f352680b3307292a8df2f79316888d103af9797bee727b8.jpg)",
+    "options": [],
+    "answer": "3;5",
+    "solution": "【分析】测量物体长度时，若未从0刻度开始，则用结束刻度 - 开始刻度计算长度.\n【详解】10 - 7 = 3(厘米),所以橡皮长3厘米，铅笔长5厘米。",
+    "knowledge_points": [
+      "厘米的认识",
+      "长度的测量方法"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "164",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "扎西的身高约 145( )。",
+    "options": [],
+    "answer": "厘米或cm",
+    "solution": "【分析】计量身高通常用厘米作单位更合适.\n【详解】1厘米大约是食指的宽度，计量身高用\"厘米\"作单位比较适合，所以扎西的身高约 145 厘米。",
+    "knowledge_points": [
+      "厘米的认识",
+      "长度单位的选择"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "165",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "在括号里填上合适的长度单位.\n铅笔盒长约 30( );旗杆高约 13( );小明身高为128( );跳绳长约 2( )",
+    "options": [],
+    "answer": "厘米或cm;米或m;厘米或cm;米或m",
+    "solution": "【分析】根据生活经验及长度单位换算关系选择合适单位.\n【详解】铅笔盒长约30厘米;旗杆高约13米;小明身高为128厘米;跳绳长约2米。",
+    "knowledge_points": [
+      "厘米的认识",
+      "米的认识",
+      "长度单位的选择"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "166",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "在括号里填上合适的长度单位.\n铅笔长约 18( )。双人床长约 200( ).\n妹妹身高约 1( )。一个台阶高约 20( )。",
+    "options": [],
+    "answer": "厘米或cm;厘米或cm;米或m;厘米或cm",
+    "solution": "【分析】根据生活经验与单位换算(100 厘米 = 1 米),选择合适单位.\n【详解】铅笔长约18厘米。双人床长约200厘米。妹妹身高约1米。一个台阶高约20厘米。",
+    "knowledge_points": [
+      "厘米和米之间的进率与换算",
+      "长度单位的选择"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "167",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "一只蚂蚁从尺子的 9厘米处爬到 2 厘米处，它爬了( )厘米。",
+    "options": [],
+    "answer": "7",
+    "solution": "【分析】若不从0刻度开始测量，则用测量结束的刻度 - 测量开始的刻度 = 物体的长度.\n【详解】9 - 2 = 7(厘米),它爬了 7 厘米。",
+    "knowledge_points": [
+      "长度的测量方法"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "168",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "铅笔长约17( )。课桌高约 70( )。小亮身高约 1( )35( )。",
+    "options": [],
+    "answer": "厘米或cm;厘米或cm;米或m;厘米或cm",
+    "solution": "【分析】根据经验与数据大小选择合适的长度单位.\n【详解】铅笔长约17厘米。课桌高约70厘米。小亮身高约1米35厘米。",
+    "knowledge_points": [
+      "长度单位的选择"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "169",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "联系生活，填上适当的长度单位\"厘米\"或\"米\".\n一个笔袋长 22( );一棵大树高 16( );一个人的身高136( )",
+    "options": [],
+    "answer": "厘米或cm;米或m;厘米或cm",
+    "solution": "【分析】根据生活经验及结合给出的数据，来选择合适的长度单位.\n【详解】一个笔袋长22厘米;一棵大树高16米;一个人的身高136厘米。",
+    "knowledge_points": [
+      "长度单位的选择"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "170",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "在下面的括号里填上\"米\"或\"厘米\".\n早上，我从 2( )长的床上爬起来，拿起 13( )长的牙刷刷牙，随后洗脸，吃早饭。学校离我家才 95( ),到学校后，从书包里拿出 10( )长的铅笔开始做笔记。",
+    "options": [],
+    "answer": "米或m;厘米或cm;米或m;厘米或cm",
+    "solution": "【分析】根据生活经验对长度单位和数据的认知：量比较长的物体的长度，通常用米作单位;量比较短的物体的长度，通常用厘米作单位.\n【详解】床的长度为2米;牙刷长13厘米;学校离我家95米;铅笔长10厘米。",
+    "knowledge_points": [
+      "厘米的认识",
+      "米的认识",
+      "长度单位的选择"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "171",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "在括号里填上合适的单位.\n手掌宽约 8( )。书桌高约 65( ).\n一条跳绳长 2( )。哥哥的身高 1( )28( )。",
+    "options": [],
+    "answer": "厘米或cm;厘米或cm;米或m;米或m;厘米或cm",
+    "solution": "【分析】根据经验，数据大小选择合适单位：较短用厘米，较长用米.\n【详解】手掌宽约8厘米;书桌高约65厘米;跳绳长2米;哥哥身高1米28厘米。",
+    "knowledge_points": [
+      "长度单位的选择"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "172",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "在括号里填上合适的长度单位.\n一支粉笔长约 10( )。数学书的宽度是 15( ).\n一根跳绳长 2( )。篮球场长约 45( )。",
+    "options": [],
+    "answer": "厘米或cm;厘米或cm;米或m;米或m",
+    "solution": "【分析】量比较长的物体通常用米作单位;量比较短的物体通常用厘米作单位.\n【详解】粉笔长约10厘米;数学书宽15厘米;跳绳长2米;篮球场长约45米。",
+    "knowledge_points": [
+      "厘米的认识",
+      "米的认识",
+      "长度单位的选择"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "173",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "下图是莉莉测量铅笔的图片，铅笔的长度是( )厘米.\n\n![](images/0d9d42325dbb9e7c9e61b8f5a69af24ace292480134cd5f350a79284c75d4e7b.jpg)",
+    "options": [],
+    "answer": "16",
+    "solution": "【分析】测量物体长度时，将物体的一侧与直尺的0刻度线对齐;若一侧未与0刻度线对齐，则用测量结束的刻度 - 测量开始的刻度 = 物体的长度.\n【详解】17 - 1 = 16(厘米),所以铅笔的长度是16厘米。",
+    "knowledge_points": [
+      "厘米的认识",
+      "长度的测量方法"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "174",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "![](images/5d9eb73fb277c98d8fbca093b5cf8ca35a636708103320f7d3a79616d773e0ba.jpg)\n\n铅笔长( )厘米，钉子长( )厘米。",
+    "options": [],
+    "answer": "6;3",
+    "solution": "【分析】测量物体长度时，将物体的一侧与直尺的0刻度线对齐;若一侧未与0刻度线对齐，则用测量结束的刻度 - 测量开始的刻度 = 物体的长度.\n【详解】6 - 0 = 6(厘米);5 - 2 = 3(厘米),所以铅笔长6厘米，钉子长3厘米。",
+    "knowledge_points": [
+      "厘米的认识",
+      "长度的测量方法"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "175",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "在括号里填上合适的单位名称.\n一本字典厚 6( );数学书长 22( );小红的身高是 1( )35( )",
+    "options": [],
+    "answer": "厘米或cm;厘米或cm;米或m;厘米或cm",
+    "solution": "【分析】根据经验，数据大小可知：较短用厘米，较长用米.\n【详解】一本字典厚6厘米;数学书长22厘米;小红身高1米35厘米。",
+    "knowledge_points": [
+      "厘米的认识",
+      "米的认识",
+      "长度单位的选择"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "176",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "75 厘米+25 厘米=( )米;3 米=( )厘米;175 厘米=( )米( )厘米;( )米=700 厘米",
+    "options": [],
+    "answer": "1;300;1;75;7",
+    "solution": "【分析】同单位的直接相加减，不同单位的根据1米 = 100 厘米换算单位即可.\n【详解】75厘米 + 25厘米 = 100厘米 = 1米;3米 = 300厘米;175厘米 = 1米75厘米;7米 = 700厘米。",
+    "knowledge_points": [
+      "厘米和米之间的进率与换算"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "177",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "50 厘米+30 厘米=( )厘米;1 米=( )厘米;90 米+3 米=( )米;1 米-20 厘米=( )厘米",
+    "options": [],
+    "answer": "80;100;93;80",
+    "solution": "【分析】根据 1 米 = 100 厘米换算统一单位后计算.\n【详解】50 + 30 = 80(厘米);1 米 = 100 厘米;90 + 3 = 93(米);1 米 - 20 厘米 = 100 厘米 - 20 厘米 = 80 厘米。",
+    "knowledge_points": [
+      "整十数之间的加减法",
+      "厘米和米之间的进率与换算"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "178",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "在括号里填上合适的单位名称.\n一支铅笔长约 20( );数学书长约 20( );课桌高约 80( )\n学校教学楼高约 12( );一棵大树高约 4( )",
+    "options": [],
+    "answer": "厘米或cm;厘米或cm;厘米或cm;米或m;米或m",
+    "solution": "【分析】量比较长的物体通常用米作单位;量比较短的物体通常用厘米作单位.\n【详解】铅笔长约20厘米;数学书长约20厘米;课桌高约80厘米;学校教学楼高约12米;一棵大树高约4米。",
+    "knowledge_points": [
+      "厘米的认识",
+      "米的认识",
+      "长度单位的选择"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "179",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "下图中线段的长是( )厘米.\n\n![](images/2026-02-05%20110444.jpg)",
+    "options": [],
+    "answer": "6",
+    "solution": "【分析】尺子测量物体时应将0刻度移动到被测物体的边缘，将直尺与被测物体重合，再观察被测物体另一端的刻度即可。当0刻度与被测物体的边缘不对齐时，用末端的刻度值减去开始的刻度值即可.\n【详解】8 - 2 = 6(厘米),所以图中线段的长是6厘米。",
+    "knowledge_points": [
+      "长度的测量方法"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "180",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "在括号里填上\">\"\"<\"或\"=\".\n5 米( )8 米;32 厘米( )40 厘米;8 米( )800 厘米\n8 米 10 厘米( )8 米 1 厘米;1 米 8 厘米( )180 厘米",
+    "options": [],
+    "answer": "<;<;=;>;<",
+    "solution": "【分析】同单位的根据整数比较大小的方法直接比较;不同单位的根据1米 = 100 厘米统一单位后再比较.\n【详解】5米 < 8米;32厘米 < 40厘米;8米 = 800厘米;8米10厘米 > 8米1厘米;1米8厘米 < 180厘米。",
+    "knowledge_points": [
+      "厘米和米之间的进率与换算"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "181",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "在括号里填上\">\"\"<\"或\"=\".\n50 厘米( )5 米;60 厘米 + 4 厘米( )1 米;1 米 - 20 厘米( )80 厘米",
+    "options": [],
+    "answer": "<;<;=",
+    "solution": "【分析】1米 = 100厘米，统一单位后再比较;含有算式的先计算再比较.\n【详解】50厘米 < 5米;60厘米 + 4厘米 = 64厘米 < 1米;1米 - 20厘米 = 80厘米。",
+    "knowledge_points": [
+      "厘米和米之间的进率与换算"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "182",
+    "unit": "第一单元 长度单位",
+    "question_type": "排序题",
+    "difficulty": 0.85,
+    "question": "把各数从小到大排列.\n9 厘米;2 米;7 厘米;70 厘米;7 米\n( )<( )<( )<( )<( )",
+    "options": [],
+    "answer": "7 厘米;9 厘米;70 厘米;2 米;7 米",
+    "solution": "【分析】先统一单位(1 米 = 100 厘米),再比较大小并排序.\n【详解】2 米 < 7 米;7 厘米 < 9 厘米 < 70 厘米;70 厘米 < 2 米;所以 7 厘米 < 9 厘米 < 70 厘米 < 2 米 < 7 米。",
+    "knowledge_points": [
+      "100以内数的比大小",
+      "厘米和米之间的进率与换算"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "183",
+    "unit": "第一单元 长度单位",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "一条小路宽 3 厘米。()",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】计量小路的宽度用\"米\"作单位更合适.\n【详解】一条小路宽 3 米。原题说法错误。故答案为: ×",
+    "knowledge_points": [
+      "厘米的认识",
+      "米的认识"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "184",
+    "unit": "第一单元 长度单位",
+    "question_type": "判断题",
+    "difficulty": 0.65,
+    "question": "小丽家距离学校 200米，她选择步行的方式上学最合适。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】200米距离相对较短，步行上学是合适的方式.\n【详解】小丽家距离学校200米，她选择步行的方式上学最合适。原题说法正确。故答案为:√",
+    "knowledge_points": [
+      "米的认识"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "185",
+    "unit": "第一单元 长度单位",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "操场跑道一圈的长度大约是 400 米。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】操场跑道一圈长度约400米，符合生活常识.\n【详解】操场跑道一圈的长度大约是400米。原题说法正确。故答案为:√",
+    "knowledge_points": [
+      "长度的估测",
+      "长度单位的选择"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "186",
+    "unit": "第一单元 长度单位",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "教室的高是 98 厘米。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】教室的高度一般是几米,98厘米不到1米，明显不符合实际.\n【详解】教室的高比98厘米高很多。原题说法错误。故答案为: ×",
+    "knowledge_points": [
+      "长度的估测"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "187",
+    "unit": "第一单元 长度单位",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "二(1)班的小马虎同学说，他家的床长 2 cm。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】床的长度应以米作单位,2厘米明显不符合实际.\n【详解】床长应约2米。原题说法错误。故答案为: ×",
+    "knowledge_points": [
+      "米的认识"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "188",
+    "unit": "第一单元 长度单位",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "长颈鹿高约 3 米。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】计量长颈鹿高度用\"米\"作单位比较合适,3米符合生活常识.\n【详解】长颈鹿高约3米。原题说法正确。故答案为:√",
+    "knowledge_points": [
+      "米的认识"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "189",
+    "unit": "第一单元 长度单位",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "一条线段长6厘米。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】线段有两个端点，两个端点间的距离就是线段的长度，可以用厘米表示.\n【详解】可以说一条线段长6厘米，原题说法正确。故答案为:√",
+    "knowledge_points": [
+      "线段的初步认识"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "190",
+    "unit": "第一单元 长度单位",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "线段不能量出长度。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】线段有限长，可测量长度.\n【详解】线段能量出长度。原题说法错误。故答案为: ×",
+    "knowledge_points": [
+      "线段，直线，射线的认识及特征"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "191",
+    "unit": "第一单元 长度单位",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "100 厘米比 1 米要长。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】1 米 = 100 厘米，统一单位后再比较.\n【详解】100 厘米 = 1 米，二者同样长，原题说法错误。故答案为: ×",
+    "knowledge_points": [
+      "厘米和米之间的进率与换算"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "192",
+    "unit": "第一单元 长度单位",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "每两个点用线段连接起来，只能连一条线段。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】线段连接两点，两点确定一条线段.\n【详解】两个点用线段连接起来，只能连一条线段，原题说法正确。故答案为:√",
+    "knowledge_points": [
+      "线段的初步认识"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "193",
+    "unit": "第一单元 长度单位",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "判断图片是否正确。( )\n\n![](images/5e97dbcdbf748257f595116148b9960f9404e99a7dd78e6ca28ddd77ddd43164.jpg)",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】测量物体长度时，应将物体的一侧与直尺的0刻度线对齐，物体与直尺放平不倾斜.\n【详解】测量时左侧未与0刻度线对齐，所以长度不是4厘米。图片错误。故答案为: ×",
+    "knowledge_points": [
+      "长度的测量方法"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "194",
+    "unit": "第一单元 长度单位",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "小明卧室的床长约 2 米。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】床的长度通常用米作单位,2米符合生活实际.\n【详解】小明卧室的床长约2米。原题说法正确。故答案为:√",
+    "knowledge_points": [
+      "长度的估测",
+      "长度单位的选择"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "195",
+    "unit": "第一单元 长度单位",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "一根绳子长100 cm,另一条绳子长 1 m,两条绳子一样长。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】熟练掌握米和厘米之间的进率,1 m = 100 cm.\n【详解】1 m = 100 cm,两条绳子一样长。原题说法正确。故答案为:√",
+    "knowledge_points": [
+      "厘米和米之间的进率与换算"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "196",
+    "unit": "第一单元 长度单位",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "1米的绳子比100厘米的彩带长。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】1米 = 100厘米，统一单位后再比较.\n【详解】1米和100厘米一样长，原题说法错误。故答案为: ×",
+    "knowledge_points": [
+      "厘米和米之间的进率与换算"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "197",
+    "unit": "第一单元 长度单位",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "画一条长 5 cm 长的线段，就是从尺子的刻度\"1\"画到刻度\"5\"。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】画线段时通常从0刻度线开始;若从1刻度开始，则结束刻度应为起始刻度 + 线段长度.\n【详解】1 + 5 = 6(cm),应从刻度\"1\"画到刻度\"6\"。原题说法错误。故答案为: ×",
+    "knowledge_points": [
+      "用直尺画线段"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "198",
+    "unit": "第一单元 长度单位",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "便利贴小条宽大约 1厘米。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】量比较短的物体的长度，通常用厘米作单位，食指的宽大约是1厘米，据此判断.\n【详解】便利贴小条宽大约是1厘米，原题说法正确.\n![](images/98ef769455a2d3df64ad4294fc4cbeba0614e036e182ff5f3a9553afa5857276.jpg)\n故答案为:√",
+    "knowledge_points": [
+      "长度的估测"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "199",
+    "unit": "第一单元 长度单位",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "1 米长的彩带和 100 厘米长的铁丝一样长。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】1米 = 100厘米，长度单位换算后可知二者一样长.\n【详解】1米长的彩带和100厘米长的铁丝一样长，是正确的。故答案为:√",
+    "knowledge_points": [
+      "厘米和米之间的进率与换算"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "200",
+    "unit": "第一单元 长度单位",
+    "question_type": "作图题",
+    "difficulty": 0.85,
+    "question": "先量出下面这条线段的长度，再在下面画一条比它长2厘米的线段.\n( )厘米",
+    "options": [],
+    "answer": "3 厘米",
+    "solution": "【分析】用直尺测量，将0刻度线与线段的起点对齐，尺子与线段重合，读出数即可得出线段的长度为3厘米;画一条比它长2厘米的线段，相加得到新线段长度，再用直尺画出来.\n【详解】![](images/0b78e9de7be994d7aca52f326364388470bd75158b4543efef69802b540f85f9.jpg)",
+    "knowledge_points": [
+      "厘米的认识",
+      "长度的测量方法"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "201",
+    "unit": "第一单元 长度单位",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "教室后面的黑板大约长( )。",
+    "options": [
+      "A. 4 米",
+      "B. 4 厘米",
+      "C. 100 厘米",
+      "D. 40 厘米"
+    ],
+    "answer": "A",
+    "solution": "【分析】大拇指的指甲长度大约1厘米，小学生两臂伸开的长度大约1米，据此逐项分析.\n【详解】A。4 米符合黑板的长度;B。4厘米太短不符合;C。100厘米大概比课桌高一点点，不符合;D。40厘米还不到课桌的高度，不符合。教室后面的黑板大约长4米。故答案为:A",
+    "knowledge_points": [
+      "长度单位的选择",
+      "厘米的认识",
+      "米的认识"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "202",
+    "unit": "第一单元 长度单位",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "观察下图，下边尺子不能测量( ).\n\n![](images/2026-02-05%20121031.jpg)",
+    "options": [
+      "A. 3厘米",
+      "B. 4厘米",
+      "C. 6厘米"
+    ],
+    "answer": "B",
+    "solution": "【分析】若左端与0刻度线对齐，另一端对应刻度即长度;若左端未与0刻度线对齐，则用测量结束的刻度 - 测量开始的刻度 = 物体的长度.\n【详解】A。有刻度2厘米和5厘米,5 - 2 = 3(厘米),可以测量3厘米;B。无论直接测量或求刻度差都不能测量4厘米;C。有刻度5厘米和11厘米,11 - 5 = 6(厘米),可以测量6厘米。故答案为:B",
+    "knowledge_points": [
+      "长度的测量方法"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "203",
+    "unit": "第一单元 长度单位",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "下面测量纸条长度方法正确的是( ).\n\n![](images/6ac73b974d206cbef614558b8760c7d05205d1c59ec51bfa8df192ac182b083c.jpg)\n\n![](images/6f2e80488422d932055532896daaaa9a14e9f1fa443d421a38b76324d91c3cdb.jpg)\n\n![](images/4103922f9c52d6f1d136dc007461cabb247d785c49ddd811712269cb04ead0e8.jpg)\n\n![](images/8b95dff27f03d1b92066352c670534d160fd566d3dc6370a5d284d9e0a2f3533.jpg)",
+    "options": [
+      "A. b 和 c",
+      "B. b 和 d",
+      "C. a 和 d"
+    ],
+    "answer": "A",
+    "solution": "【分析】测量时直尺与纸条放平，一端与0刻度线对齐;若不从0刻度开始，则用结束刻度 - 开始刻度计算.\n【详解】a。左端没有对齐刻度线，不正确;b。从刻度\"1\"开始量,5 - 1 = 4(厘米),正确;c。从刻度\"0\"开始量，长度4厘米，正确;d。直尺倾斜，不正确。所以正确的是 b 和 c。故答案为:A",
+    "knowledge_points": [
+      "长度的测量方法"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "204",
+    "unit": "第一单元 长度单位",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "有3根同样长的铁丝，甲铁丝用去1米，乙铁丝用去1厘米，丙铁丝用去10厘米。现在( )铁丝最短。",
+    "options": [
+      "A. 甲",
+      "B. 乙",
+      "C. 丙"
+    ],
+    "answer": "A",
+    "solution": "【分析】先根据1米 = 100厘米统一单位，再比较用去的长度，用去最多的现在最短.\n【详解】1米 = 100厘米,100厘米 > 10厘米 > 1厘米，所以甲用去最多，即现在甲最短。故答案为:A",
+    "knowledge_points": [
+      "厘米和米之间的进率与换算"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "205",
+    "unit": "第一单元 长度单位",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "小丽的身高是 92 厘米，小云比小丽矮 8 厘米。小云的身高是( )厘米。",
+    "options": [
+      "A. 100",
+      "B. 84",
+      "C. 86"
+    ],
+    "answer": "B",
+    "solution": "【分析】用小丽的身高减去8厘米就是小云的身高.\n【详解】92 - 8 = 84(厘米),小云的身高是84厘米。故答案为:B",
+    "knowledge_points": [
+      "厘米的认识",
+      "一位数与两位数的退位减法"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "206",
+    "unit": "第一单元 长度单位",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "下面的故事中，你觉得不可能比 1 米高的物体是( )。",
+    "options": [
+      "A. 《司马光砸缸》中缸的高度",
+      "B. 《曹冲称象》中大象的身高",
+      "C. 《孔融让梨》中梨的高度"
+    ],
+    "answer": "C",
+    "solution": "【分析】结合生活经验判断哪些物体高度应以米计，哪些应以厘米计.\n【详解】缸和大象的身高可能用米作单位且可能超过1米;梨的高度应以厘米计，不可能比1米高。故答案为:C",
+    "knowledge_points": [
+      "厘米的认识",
+      "米的认识"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "207",
+    "unit": "第一单元 长度单位",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "你的手臂的长度约是( )。",
+    "options": [
+      "A. 3 厘米",
+      "B. 3 米",
+      "C. 30 厘米"
+    ],
+    "answer": "C",
+    "solution": "【分析】根据生活经验判断:3厘米太短,3米太长，手臂约几十厘米.\n【详解】30厘米大约是手臂的长度。故答案为:C",
+    "knowledge_points": [
+      "长度的估测"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "208",
+    "unit": "第一单元 长度单位",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "画一条 4 厘米长的线段，下列选项正确的是( )。",
+    "options": [
+      "A. ![](images/2a99103399b336d84cab3e433166ef6281c88d70a3e9e56f43d53c4e8dc71f9d.jpg)",
+      "B. ![](images/383c2ac2822981f585694f79b82ec9ec1d1189788810ca8cd1b1c076b64a8a32.jpg)",
+      "C. ![](images/bbf9b1f10412e086cb3bafee8480c405d2b3f53e8500a54bfec20569bb3c7674.jpg)"
+    ],
+    "answer": "C",
+    "solution": "【分析】画线段时可从0刻度开始画到所需刻度;若不从0开始，则两端刻度差应等于线段长度.\n【详解】A。超过4厘米刻度，不符合;B。4 - 1 = 3(厘米),不符合;C。5 - 1 = 4(厘米),符合。故答案为:C",
+    "knowledge_points": [
+      "用直尺画线段"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "209",
+    "unit": "第一单元 长度单位",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "一根牙签长约()。",
+    "options": [
+      "A. 6 厘米",
+      "B. 6 米",
+      "C. 1 厘米"
+    ],
+    "answer": "A",
+    "solution": "【分析】牙签长度应以厘米计，结合生活经验判断.\n【详解】6厘米符合牙签长度;6米太长;1厘米太短。故答案为:A",
+    "knowledge_points": [
+      "长度单位的选择",
+      "厘米的认识",
+      "米的认识"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "210",
+    "unit": "第一单元 长度单位",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "国庆节期间，商店搞优惠活动，林老师买回一台冰箱，冰箱高 195( )。",
+    "options": [
+      "A. 厘米",
+      "B. 米",
+      "C. 元"
+    ],
+    "answer": "A",
+    "solution": "【分析】括号里应填长度单位。冰箱高度一般用厘米更合适.\n【详解】冰箱高195厘米。故答案为:A",
+    "knowledge_points": [
+      "长度单位的选择",
+      "厘米的认识",
+      "米的认识"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "211",
+    "unit": "第一单元 长度单位",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面测量方法正确的是( )。",
+    "options": [
+      "A. ![](images/b50810a48466c11e0adeb084b49d93c6dee7242c9338994e25325975c6639e10.jpg)",
+      "B. ![](images/c5d192c7d422b1c7a3bda28f8698da4ddc1cf9b2112d5d5e041352a518a73e53.jpg)",
+      "C. ![](images/225a2932a2e822900a3a0c6d870f05d5c1a3e60b877dcd53516249c1184454bf.jpg)"
+    ],
+    "answer": "B",
+    "solution": "【分析】用刻度尺0刻度对准物体一端，刻度尺与物体对齐且不能斜放.\n【详解】A。0刻度未对齐;B。0刻度对齐且不斜放，正确;C。刻度尺斜放不正确。故答案为:B",
+    "knowledge_points": [
+      "长度的测量方法"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "212",
+    "unit": "第一单元 长度单位",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面的长度中，最接近1米的是( )。",
+    "options": [
+      "A. 讲台桌的高度",
+      "B. 数学书的长度",
+      "C. 教室的宽度"
+    ],
+    "answer": "A",
+    "solution": "【分析】根据生活经验：讲台桌高度接近1米，数学书远小于1米，教室宽度远大于1米.\n【详解】最接近1米的是讲台桌的高度。故答案为:A",
+    "knowledge_points": [
+      "长度的估测"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "213",
+    "unit": "第一单元 长度单位",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "我的食指长( )厘米。",
+    "options": [
+      "A. 5",
+      "B. 50",
+      "C. 500"
+    ],
+    "answer": "A",
+    "solution": "【分析】1厘米约为指甲盖宽度，食指约为5,6个指甲盖宽度.\n【详解】食指长约5厘米。故答案为:A",
+    "knowledge_points": [
+      "厘米的认识",
+      "长度的估测"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "214",
+    "unit": "第一单元 长度单位",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "李军身高是( )。",
+    "options": [
+      "A. 1 米 40 厘米",
+      "B. 3 米",
+      "C. 18 厘米"
+    ],
+    "answer": "A",
+    "solution": "【分析】结合生活经验判断人的身高数量级.\n【详解】1米40厘米符合小学生身高;3米太高;18厘米太矮。故答案为:A",
+    "knowledge_points": [
+      "厘米的认识",
+      "米的认识",
+      "长度的估测"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "215",
+    "unit": "第一单元 长度单位",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面物体的厚度最接近 1 厘米的是( )。",
+    "options": [
+      "A. 新华字典",
+      "B. 1 元硬币",
+      "C. 数学课本",
+      "D. 一张 A4 纸"
+    ],
+    "answer": "C",
+    "solution": "【分析】1厘米约为大拇指宽度，比较各物品厚度与其接近程度.\n【详解】数学课本厚度与大拇指宽度相近;字典更厚;硬币与A4纸更薄。故答案为:C",
+    "knowledge_points": [
+      "长度单位的选择",
+      "长度的估测"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "216",
+    "unit": "第一单元 长度单位",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面物体的长度最接近 1 米的是( )。",
+    "options": [
+      "A. 文具盒",
+      "B. 爸爸的长裤",
+      "C. 2 支铅笔的长度"
+    ],
+    "answer": "B",
+    "solution": "【分析】结合生活经验：文具盒与铅笔长度远小于1米，长裤接近1米.\n【详解】最接近1米的是爸爸的长裤。故答案为:B",
+    "knowledge_points": [
+      "长度的估测"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "217",
+    "unit": "第一单元 长度单位",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "一棵树高约( )。",
+    "options": [
+      "A. 6 米",
+      "B. 60 米",
+      "C. 600 米"
+    ],
+    "answer": "A",
+    "solution": "【分析】树的高度通常用米计，一棵树相当于两层楼左右.\n【详解】约6米比较合理。故答案为:A",
+    "knowledge_points": [
+      "米的认识",
+      "长度的估测"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "218",
+    "unit": "第一单元 长度单位",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "由四条线段围成的图形是( )。",
+    "options": [
+      "A. ![](images/77b26e32b34f1e40bc52c2743dc7ec18483dfac4430c3d3ade98610382264d1e.jpg)",
+      "B. ![](images/9a923f502d80a31acd3bd4a078053b3c866ce84973510d6fd9cd8a96e8b281c6.jpg)",
+      "C. ![](images/e6523a8f7d14d2c33f1a7395e88843bb2666acfd2d6b37162a17fabc8644a04e.jpg)"
+    ],
+    "answer": "C",
+    "solution": "【分析】线段是直的，有两个端点，判断各图形由几条线段围成.\n【详解】A由3条线段围成;B含曲线不符合;C由4条线段围成。故答案为:C",
+    "knowledge_points": [
+      "线段的初步认识"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "219",
+    "unit": "第一单元 长度单位",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "如图中纸条的长度是( )厘米.\n\n![](images/480fba5affb3dfc38b80f00995a349ee101bb310098e5ad4d0070db1fbaa27a6.jpg)",
+    "options": [
+      "A. 3",
+      "B. 4",
+      "C. 5"
+    ],
+    "answer": "B",
+    "solution": "【分析】若左端未与0刻度线对齐，则用结束刻度 - 开始刻度计算长度.\n【详解】5 - 1 = 4(厘米),纸条长4厘米。故答案为:B",
+    "knowledge_points": [
+      "长度的测量方法",
+      "厘米的认识"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "220",
+    "unit": "第一单元 长度单位",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "下面( )测量长方形木板长度的方法是正确的。",
+    "options": [
+      "A. ![](images/26cb3c43afa82451cb895f8278176ffedc26c3ac2262739ba0bba2d50797de22.jpg)",
+      "B. ![](images/7de8a865ca86f9cf7c701bb6f97717881856fe42d1e8e2571e01ad837ef2b71e.jpg)",
+      "C. ![](images/ca7538e9d04b34ab29fd07d09ac2425c19e25e9d8d473c72e2f50f959d708f70.jpg)"
+    ],
+    "answer": "B",
+    "solution": "【分析】测量时应将0刻度对齐木板一端，直尺与木板重合.\n【详解】A木板未与直尺重合;B方法正确;C左端未与0刻度线对齐。故答案为:B",
+    "knowledge_points": [
+      "长度的测量方法"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "221",
+    "unit": "第一单元 长度单位",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "欢欢身高 70 厘米，再长( )厘米，他就1米高了。",
+    "options": [
+      "A. 3",
+      "B. 20",
+      "C. 30"
+    ],
+    "answer": "C",
+    "solution": "【分析】1米 = 100厘米，用100厘米减去70厘米.\n【详解】100 - 70 = 30(厘米)。故答案为:C",
+    "knowledge_points": [
+      "厘米和米之间的进率与换算"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "222",
+    "unit": "第一单元 长度单位",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "老师的大三角尺上的直角与学生的小三角尺上的直角相比,( )。",
+    "options": [
+      "A. 大三角尺上的直角大",
+      "B. 小三角尺上的直角大",
+      "C. 一样大"
+    ],
+    "answer": "C",
+    "solution": "【分析】角的大小只和边的开叉大小有关，和边的长短无关.\n【详解】两个都是直角，一样大。故答案为:C",
+    "knowledge_points": [
+      "角的初步认识及辨认",
+      "角的大小比较"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "223",
+    "unit": "第一单元 长度单位",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "我们教室里黑板的长度大约是( )。",
+    "options": [
+      "A. 10 米",
+      "B. 20 厘米",
+      "C. 4 米"
+    ],
+    "answer": "C",
+    "solution": "【分析】黑板长度应以米计，结合生活经验判断.\n【详解】10米太长;20厘米太短;4米符合。故答案为:C",
+    "knowledge_points": [
+      "厘米的认识",
+      "米的认识",
+      "长度的估测"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "224",
+    "unit": "第一单元 长度单位",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "测量结果对的是()。",
+    "options": [
+      "A. ![](images/e0496519dafb6f721897704fcb71c1a77af29c06bc02d56d4fcadd9132b22439.jpg),长 5 厘米",
+      "B. ![](images/cdfd00cb80d82125bf8d99d25e412d4c6ec61fea1f30fce6a7ad9705f7642158.jpg),长 4 厘米",
+      "C. ![](images/c97b4a6edb7df3b7ff5828e071471c5352914097904cffd3052ef8bd9c83530f.jpg),长 5 厘米"
+    ],
+    "answer": "B",
+    "solution": "【分析】测量时应将左端与0刻度线对齐，物体与直尺放平.\n【详解】A左侧未对齐0刻度;B正确;C未放平。故答案为:B",
+    "knowledge_points": [
+      "长度的测量方法"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "225",
+    "unit": "第一单元 长度单位",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下图中的火柴棒长( )cm.\n\n![](images/dfc1eb484a68ed1656d2438ba761e7842e82dfb3bc2e615e802e1cd155d8a4df.jpg)",
+    "options": [
+      "A. 5",
+      "B. 6",
+      "C. 15"
+    ],
+    "answer": "A",
+    "solution": "【分析】若不从0刻度开始，用末端刻度减去开始刻度.\n【详解】15 - 10 = 5(cm),火柴棒长5cm。故答案为:A",
+    "knowledge_points": [
+      "长度的测量方法"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "226",
+    "unit": "第一单元 长度单位",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "下面测量方法中，正确的是( )。",
+    "options": [
+      "A. ![](images/957ca335e2f6cd584e3f566a81d010037af183620e4efd3ed0a9c095a6b2581c.jpg)",
+      "B. ![](images/a769c9dae276af6a6987156d8e954900e3cc484baae40c3be4afa7cb2b876f9b.jpg)",
+      "C. ![](images/acb7c2c38681b8cf95c07dd9d7da6472bf44cfc4dba76cd5e44511a9dd737eae.jpg)"
+    ],
+    "answer": "B",
+    "solution": "【分析】尺子的0刻度要与被测物体的一端对齐，尺子放正且紧贴，不歪斜.\n【详解】A尺子没放正;B放正且0刻度对齐;C 0刻度未对齐。故答案为:B",
+    "knowledge_points": [
+      "长度的测量方法"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "227",
+    "unit": "第一单元 长度单位",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "100 厘米长的铁丝和1 米长的绳子相比较,( )。",
+    "options": [
+      "A. 100厘米长的铁丝长",
+      "B. 1米长的绳子长",
+      "C. 长度相等"
+    ],
+    "answer": "C",
+    "solution": "【分析】根据1米 = 100厘米统一单位后比较.\n【详解】100厘米 = 1米，长度相等。故答案为:C",
+    "knowledge_points": [
+      "厘米和米之间的进率与换算"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "228",
+    "unit": "第一单元 长度单位",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "3米和下面( )同样长。",
+    "options": [
+      "A. 30厘米",
+      "B. 300 厘米",
+      "C. 10厘米 + 2厘米"
+    ],
+    "answer": "B",
+    "solution": "【分析】根据1米 = 100厘米换算,3米 = 300厘米.\n【详解】只有300厘米与3米相等。故答案为:B",
+    "knowledge_points": [
+      "厘米和米之间的进率与换算"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "229",
+    "unit": "第一单元 长度单位",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面的物体中,()的高度大约1米。",
+    "options": [
+      "A. 课桌",
+      "B. 教室的门",
+      "C. 台灯"
+    ],
+    "answer": "A",
+    "solution": "【分析】根据生活经验：课桌高度约1米，门约2米，台灯远小于1米.\n【详解】课桌的高度大约1米。故答案为:A",
+    "knowledge_points": [
+      "米的认识",
+      "长度的估测"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "230",
+    "unit": "第一单元 长度单位",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面( )是线段。",
+    "options": [
+      "A. ![](images/2026-02-05%20122704.jpg)",
+      "B. ![](images/2026-02-05%20122712.jpg)",
+      "C. ![](images/4d33be5556be9ce00bda9582415e52bc1206001c7684a052714b89919672ff73.jpg)"
+    ],
+    "answer": "C",
+    "solution": "【分析】线段有两个端点，中间是直直的线，长度可测量.\n【详解】A只有一个端点;B中间不是直线;C是线段。故答案为:C",
+    "knowledge_points": [
+      "线段的初步认识"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "231",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "橡皮长( )厘米，铅笔长( )厘米.\n\n![](images/10b50a4e99625f0faa29610d686e9c176ca6ecbd2393e07ab7dea2cd41722fc6.jpg)",
+    "options": [],
+    "answer": "3;8",
+    "solution": "【分析】测量时若未从0刻度开始，用结束刻度 - 开始刻度计算长度.\n【详解】9 - 1 = 8(厘米),所以橡皮长3厘米，铅笔长8厘米。",
+    "knowledge_points": [
+      "长度的测量方法",
+      "厘米的认识"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "232",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "下面线段长( )厘米.\n\n![](images/f8163d4bd6666aa7bd5b88c39ec276c83e5c46cd1534b9d0a6d3c8003300a988.jpg)",
+    "options": [],
+    "answer": "4",
+    "solution": "【分析】测量时将一端与0刻度对齐;若未对齐，用结束刻度 - 开始刻度计算.\n【详解】7 - 3 = 4(厘米),该线段长4厘米。",
+    "knowledge_points": [
+      "长度的测量方法"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "233",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "在括号里填上\"厘米\"或\"米\".\n(1)小明身高 120( ).\n(2)教室的门高 2( ).\n(3)一本英文词典厚 3( )。",
+    "options": [],
+    "answer": "厘米或cm;米或m;厘米或cm",
+    "solution": "【分析】联系生活实际与数据大小，灵活选择计量单位.\n【详解】小明身高120厘米;教室的门高2米;一本英文词典厚3厘米。",
+    "knowledge_points": [
+      "长度单位的选择",
+      "厘米的认识",
+      "米的认识"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "234",
+    "unit": "第一单元 长度单位",
+    "question_type": "作图题",
+    "difficulty": 0.85,
+    "question": "画一条 3 厘米长的线段，从刻度 0 开始，画到刻度( );从刻度 3 开始，画到刻度( )。",
+    "options": [],
+    "answer": "3;6",
+    "solution": "【分析】线段的画法：在直尺的0刻度线处点一个端点，根据需要的线段长度，在直尺的相应刻度处点上另一个端点，连接两个端点即可。若不是从0刻度线开始画，则用测量开始的刻度 + 线段的长度 = 测量结束的刻度.\n【详解】0 + 3 = 3(厘米);3 + 3 = 6(厘米)。从刻度0开始，画到刻度3;从刻度3开始，画到刻度6。",
+    "knowledge_points": [
+      "用直尺画线段",
+      "长度的测量方法"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "235",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "1 米 = ( )厘米;30 厘米 + 20 厘米 = ( )厘米;1 米 - 50 厘米 = ( )厘米",
+    "options": [],
+    "answer": "100;50;50",
+    "solution": "【分析】根据1米 = 100厘米进行单位换算;单位相同的两个数直接相加减.\n【详解】1 米 = 100 厘米;30厘米 + 20厘米 = 50 厘米;1米 - 50厘米 = 100 厘米 - 50厘米 = 50 厘米。",
+    "knowledge_points": [
+      "厘米和米之间的进率与换算"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "236",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "苗苗每步长50厘米，她沿着床的长走了 4 步，沿着宽走了 3 步，则床的长约( )米，宽约( )米( )厘米。",
+    "options": [],
+    "answer": "2;1;50",
+    "solution": "【分析】根据题意：走2步是2个50厘米=100厘米=1米。床长4步=2个2步长;床宽3步=2步长+1步长.\n【详解】2步长:50 + 50 = 100(厘米)= 1米;4步长:1米 + 1米 = 2米;3步长:1米 + 50厘米 = 1米50厘米。",
+    "knowledge_points": [
+      "厘米和米之间的进率与换算"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "237",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "在( )里填上合适的长度单位。轩轩是二年级学生，他的身高是 1( )45( ),坐在长约 9( )的教室里，正在用一本厚度约 3( )的《新华字典》查找生字。",
+    "options": [],
+    "answer": "米或m;厘米或cm;米或m;厘米或cm",
+    "solution": "【分析】身高一般是一百多厘米，可写作1米几十厘米;教室长度较长用米;字典厚度较短用厘米.\n【详解】轩轩身高1米45厘米，教室长约9米，字典厚度约3厘米。",
+    "knowledge_points": [
+      "长度单位的选择",
+      "厘米的认识",
+      "米的认识"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "238",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "一块木板长20厘米，那么( )块这样的木板长是1米。",
+    "options": [],
+    "answer": "5",
+    "solution": "【分析】1米 = 100厘米,100里面有几个20就需要几块.\n【详解】100 - 20 = 80,80 - 20 = 60,60 - 20 = 40,40 - 20 = 20,20 - 20 = 0，减了5次，即需要5块。",
+    "knowledge_points": [
+      "整十数之间的加减法",
+      "厘米和米之间的进率与换算"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "239",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "在括号内填上合适的单位.\n课桌长 60( );大树高 10( );爸爸的身高 1( )75( )",
+    "options": [],
+    "answer": "厘米或cm;米或m;米或m;厘米或cm",
+    "solution": "【分析】量比较短的物体通常用厘米作单位;测量较长的物体用米作单位;身高可写成米和厘米.\n【详解】课桌长60厘米;大树高10米;爸爸身高1米75厘米。",
+    "knowledge_points": [
+      "长度单位的选择"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "240",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "在下面的括号里填上合适的长度单位.\n(1)小明家客厅的长约是 5( ).\n(2)一本字典厚约 3( ).\n(3)篮球场长 28( )。",
+    "options": [],
+    "answer": "米或m;厘米或cm;米或m",
+    "solution": "【分析】结合生活经验：客厅与篮球场较长用米;字典厚度较短用厘米.\n【详解】(1)5米;(2)3厘米;(3)28米。",
+    "knowledge_points": [
+      "长度单位的选择"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "241",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "78 厘米 + 22 厘米 = ( )米;1 米 - 40 厘米 = ( )厘米",
+    "options": [],
+    "answer": "1;60",
+    "solution": "【分析】1米 = 100厘米，据此计算并换算.\n【详解】78 + 22 = 100(厘米)= 1米;1米 - 40厘米 = 100厘米 - 40厘米 = 60厘米。",
+    "knowledge_points": [
+      "厘米和米之间的进率与换算"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "242",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "1 米 - 30 厘米 = ( )厘米;400 厘米 = ( )米;15 厘米 + 85 厘米 = ( )米;26 米 + 24 米 = ( )米",
+    "options": [],
+    "answer": "70;4;1;50",
+    "solution": "【分析】根据1米 = 100厘米进行单位换算，单位相同直接计算.\n【详解】1米 - 30厘米 = 100厘米 - 30厘米 = 70厘米;400厘米 = 4米;15厘米 + 85厘米 = 100厘米 = 1米;26米 + 24米 = 50米。",
+    "knowledge_points": [
+      "厘米和米之间的进率与换算"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "243",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "在括号里填上合适的长度单位.\n黑板长约 4( );小东身高约 140( );数学课本宽约 18( );游泳池长 60( )",
+    "options": [],
+    "answer": "米或m;厘米或cm;厘米或cm;米或m",
+    "solution": "【分析】较长用米，较短用厘米.\n【详解】黑板长约4米;小东身高约140厘米;数学课本宽约18厘米;游泳池长60米。",
+    "knowledge_points": [
+      "长度单位的选择",
+      "厘米的认识",
+      "米的认识"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "244",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "在括号填上\"厘米\"或\"米\".\n一支铅笔长约20( ),课桌高约 70( ),教学楼高约18( ),小明的身高约 130( )。",
+    "options": [],
+    "answer": "厘米或cm;厘米或cm;米或m;厘米或cm",
+    "solution": "【分析】根据生活经验判断：铅笔，课桌高，身高用厘米;教学楼高度用米.\n【详解】铅笔约20厘米;课桌高约70厘米;教学楼高约18米;小明身高约130厘米。",
+    "knowledge_points": [
+      "长度单位的选择",
+      "厘米的认识",
+      "米的认识"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "245",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "我们学过的长度单位中,( )适用于测量比较短的物体,( )适用于测量比较长的物体。",
+    "options": [],
+    "answer": "厘米或cm;米或m",
+    "solution": "【分析】厘米通常用来测量比较短的物体;米通常用来测量比较长的物体.\n【详解】厘米适用于测量比较短的物体，米适用于测量比较长的物体。例如：铅笔约9厘米;教室长度约8米。",
+    "knowledge_points": [
+      "厘米的认识",
+      "米的认识"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "246",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "30 厘米 + 7 厘米 = ( )厘米;8 米 + 15 米 = ( )米;55 厘米 + 45 厘米 = ( )厘米 = ( )米",
+    "options": [],
+    "answer": "37;23;100;1",
+    "solution": "【分析】同单位直接相加;根据1米 = 100厘米进行换算.\n【详解】30+7=37(厘米);8+15=23(米);55+45=100(厘米)=1米。",
+    "knowledge_points": [
+      "厘米和米之间的进率与换算"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "247",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "在括号里填合适的长度单位.\n(1)一根黄瓜长 19( ).\n(2)国旗旗杆高 13( ).\n(3)我的床高 60( ),宽 120( )。",
+    "options": [],
+    "answer": "厘米或cm;米或m;厘米或cm;厘米或cm",
+    "solution": "【分析】黄瓜和床的高宽较短用厘米;旗杆较高用米.\n【详解】黄瓜长19厘米;旗杆高13米;床高60厘米，宽120厘米。",
+    "knowledge_points": [
+      "长度单位的选择",
+      "厘米的认识",
+      "米的认识"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "248",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "填上合适的长度单位.\n课桌的高是 60( );小明的身高 1( )26( );作业本封皮长 21( );旗杆高 15( )",
+    "options": [],
+    "answer": "厘米或cm;米或m;厘米或cm;厘米或cm;米或m",
+    "solution": "【分析】课桌高与作业本长较短用厘米;旗杆高较长用米;身高写作1米26厘米.\n【详解】课桌高60厘米;小明身高1米26厘米;作业本封皮长21厘米;旗杆高15米。",
+    "knowledge_points": [
+      "厘米和米之间的进率与换算",
+      "长度单位的选择",
+      "厘米的认识",
+      "米的认识"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "249",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "量物体的长度时，要把尺的刻度( )对准物体的左端，再看看物体的右端对着几.\n\n![](images/2bf11647b9e782be9cdbe13275dca6a191d28c8362408785a09b0ff236997301.jpg)",
+    "options": [],
+    "answer": "0或零",
+    "solution": "【详解】量物体的长度时，先把尺子放平，把尺子的刻度0对准物体的左端，再看物体的右端对着几，长度就是几厘米。",
+    "knowledge_points": [
+      "长度的测量方法",
+      "厘米的认识"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "250",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "一本书厚约为 1( );一支粉笔长约( )。",
+    "options": [],
+    "answer": "厘米或cm;8厘米",
+    "solution": "【分析】1厘米约为指甲盖宽度，书的厚度可用厘米;粉笔约长8厘米.\n【详解】一本书厚约1厘米;一支粉笔长约8厘米。",
+    "knowledge_points": [
+      "长度单位的选择",
+      "厘米的认识",
+      "长度的估测"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "251",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "填上合适的单位.\n课桌宽约 60( );篮球场大约长 28( );长颈鹿的身高大约是 6( );牙刷大约长 15( )",
+    "options": [],
+    "answer": "厘米或cm;米或m;米或m;厘米或cm",
+    "solution": "【分析】课桌宽和牙刷长较短用厘米;篮球场长与长颈鹿身高较长用米.\n【详解】课桌宽约60厘米;篮球场长约28米;长颈鹿身高约6米;牙刷长约15厘米。",
+    "knowledge_points": [
+      "长度单位的选择"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "252",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "100 厘米 = ( )米，课桌高 90( ),小明身高 120( )。",
+    "options": [],
+    "answer": "1;厘米或cm;厘米或cm",
+    "solution": "【分析】1米 = 100厘米;课桌高和身高通常用厘米作单位.\n【详解】100厘米 = 1米，课桌高90厘米，小明身高120厘米。",
+    "knowledge_points": [
+      "厘米和米之间的进率与换算",
+      "长度单位的选择"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "253",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "填上合适的长度单位.\n一座楼房大约高 18( );小红的身高约 145( );一张木床长 2( );数学书长 26( )",
+    "options": [],
+    "answer": "米或m;厘米或cm;米或m;厘米或cm",
+    "solution": "【分析】楼房高度与床长较长用米;身高与数学书长较短用厘米.\n【详解】楼房高约18米;小红身高约145厘米;木床长2米;数学书长26厘米。",
+    "knowledge_points": [
+      "长度单位的选择",
+      "厘米的认识",
+      "米的认识"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "254",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "在直尺上，从刻度\"0\"到刻度\"7\"是( )厘米，从刻度\"1\"到刻度\"5\"是( )厘米。",
+    "options": [],
+    "answer": "7;4",
+    "solution": "【分析】从刻度1到刻度5的距离用5 - 1计算.\n【详解】5 - 1 = 4(厘米)。从刻度0到刻度7是7厘米，从刻度1到刻度5是4厘米。",
+    "knowledge_points": [
+      "长度的测量方法",
+      "厘米的认识"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "255",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "在括号里填上合适的长度单位.\n课桌桌面的宽大约为 70( )。楼房高约为 20( )。床长约为 2( )。小明身高约为 135( )。",
+    "options": [],
+    "answer": "厘米或cm;米或m;米或m;厘米或cm",
+    "solution": "【分析】较短用厘米，较长用米.\n【详解】课桌宽约70厘米;楼房高约20米;床长约2米;小明身高约135厘米。",
+    "knowledge_points": [
+      "长度单位的选择"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "256",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "2 米 = ( )厘米;45 厘米 + 55 厘米 = ( )米;86 米 - 27 米 = ( )米;1 米 - 53 厘米 = ( )厘米",
+    "options": [],
+    "answer": "200;1;59;47",
+    "solution": "【分析】1米 = 100厘米，进行单位换算后计算.\n【详解】2米=200厘米;45+55=100厘米=1米;86-27=59米;1米-53厘米=100厘米-53厘米=47厘米。",
+    "knowledge_points": [
+      "厘米和米之间的进率与换算"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "257",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "长度单位间的换算.\n5 米 = ( )厘米;66 厘米 + 34 厘米 = ( )米;300 厘米 = ( )米;46 厘米 - 9 厘米 = ( )厘米",
+    "options": [],
+    "answer": "500;1;3;37",
+    "solution": "【分析】1米 = 100厘米，按换算关系与算式计算.\n【详解】5米=500厘米;66+34=100厘米=1米;300厘米=3米;46-9=37厘米。",
+    "knowledge_points": [
+      "厘米和米之间的进率与换算"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "258",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "在下面的括号里填上\"厘米\"或\"米\".\n(1)长颈鹿高约 3( )。(2)小明的身高 1( )38( )。(3)铅笔长 13( )。(4)一座楼房高 15( )。",
+    "options": [],
+    "answer": "米或m;米或m;厘米或cm;厘米或cm;米或m",
+    "solution": "【分析】根据生活经验与数据大小选择合适单位.\n【详解】长颈鹿高约3米;小明身高1米38厘米;铅笔长13厘米;楼房高15米。",
+    "knowledge_points": [
+      "长度单位的选择",
+      "厘米的认识",
+      "米的认识"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "259",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "6 米 = ( )厘米;2 米 + 3 米 = ( )米;30 厘米 + ( )厘米 = 1 米",
+    "options": [],
+    "answer": "600;5;70",
+    "solution": "【分析】1米 = 100厘米，先换算再计算.\n【详解】6米=600厘米;2+3=5米;100-30=70，所以30厘米+70厘米=1米。",
+    "knowledge_points": [
+      "厘米和米之间的进率与换算"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "260",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "![](images/824f698bc96a0890608a7848a6b92a6600a442849a1612c32ab85f791ed25010.jpg)\n这张纸条长( )厘米。",
+    "options": [],
+    "answer": "7",
+    "solution": "【分析】若左端未与0刻度线对齐，则用结束刻度 - 开始刻度计算长度.\n【详解】8 - 1 = 7(厘米),所以这张纸条长7厘米。",
+    "knowledge_points": [
+      "长度的测量方法",
+      "厘米的认识"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "261",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "先估一估数学书长约( ),再量一量数学书长约( ),大约( )本数学书的长是 1 m.",
+    "options": [],
+    "answer": "20cm;25cm;4",
+    "solution": "【分析】先根据食指宽约1cm估计数学书长;再按测量方法量出长度。1m = 100cm,算出几本数学书的实际长度约为100cm.\n【详解】25 + 25 + 25 + 25 = 100(cm),100cm = 1m。估一估数学书长约20cm,量一量数学书长约25cm,大约4本数学书的长是1m。(答案不唯一，合理即可)",
+    "knowledge_points": [
+      "长度的测量方法",
+      "长度的估测"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "262",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "![](images/552129209b8f6fdd815c15254949127500db4b2f97207f4788225abfdc1b9645.jpg)\n小刀比铅笔短( )厘米。铅笔和小刀一共长( )厘米。",
+    "options": [],
+    "answer": "2;12",
+    "solution": "【分析】铅笔从0到7是7厘米;小刀从2到7是5厘米。短多少用减法;一共多长用加法.\n【详解】7 - 5 = 2(厘米),7 + 5 = 12(厘米),所以小刀比铅笔短2厘米，一共长12厘米。",
+    "knowledge_points": [
+      "比长短",
+      "厘米的认识",
+      "7的加减法"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "263",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "在括号里填上合适的长度单位.\n(1)学校的国旗杆高 10( )。(2)课桌长 60( )。(3)1 拃大约长 12( )。(4)一根跳绳大约长 2( )。",
+    "options": [],
+    "answer": "米或m;厘米或cm;厘米或cm;米或m",
+    "solution": "【分析】较长用米，较短用厘米.\n【详解】国旗杆高10米;课桌长60厘米;1拃约12厘米;跳绳约2米。",
+    "knowledge_points": [
+      "长度单位的选择",
+      "\"身体尺\"的认识及应用"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "264",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "在括号里填上合适的长度单位.\n一支笔长约 15( ),学校大门高约 2( ),旗杆高约 13( )。",
+    "options": [],
+    "answer": "厘米或cm;米或m;米或m",
+    "solution": "【分析】较短用厘米，较长用米.\n【详解】一支笔长约15厘米;学校大门高约2米;旗杆高约13米。",
+    "knowledge_points": [
+      "长度单位的选择"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "265",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "在括号里填上\"米\"或者\"厘米\".\n麻雀的足印长 3( )。房间高 3( )。",
+    "options": [],
+    "answer": "厘米或cm;米或m",
+    "solution": "【分析】足印较短用厘米;房间高度较长用米.\n【详解】麻雀足印长3厘米;房间高3米。",
+    "knowledge_points": [
+      "长度单位的选择",
+      "厘米的认识",
+      "米的认识"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "266",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "200 厘米 = ( )米;3 米 = ( )厘米;1 米 - 40 厘米 = ( )厘米",
+    "options": [],
+    "answer": "2;300;60",
+    "solution": "【分析】1米=100厘米，先换算再计算.\n【详解】200厘米=2米;3米=300厘米;1米-40厘米=100厘米-40厘米=60厘米。",
+    "knowledge_points": [
+      "厘米和米之间的进率与换算"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "267",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "在括号填上适当的单位名称.\n在跳蚤市场活动中，小明组的摊位长 2( ),宽 1( ),身高 1( )30( )的小明手拿喇叭像模像样地推销着本组售卖的物品，他很快推销出去了一个高 15( )的玩具小熊。",
+    "options": [],
+    "answer": "米或m;米或m;米或m;厘米或cm;厘米或cm",
+    "solution": "【分析】摊位长宽较长用米;身高写作1米30厘米;玩具小熊较矮用厘米.\n【详解】摊位长2米，宽1米;小明身高1米30厘米;玩具小熊高15厘米。",
+    "knowledge_points": [
+      "长度单位的选择"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "268",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "直尺上刻度 5 到刻度 12 之间长( )厘米。",
+    "options": [],
+    "answer": "7",
+    "solution": "【分析】长度 = 结束刻度 - 开始刻度.\n【详解】12 - 5 = 7(厘米)。",
+    "knowledge_points": [
+      "长度的测量方法",
+      "厘米的认识"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "269",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "填上合适的长度单位.\n(1)汽车长约 4( )。(2)数学课本长约 24( )。(3)红红身高 1( )25( )。(4)水瓶高约 20( )。",
+    "options": [],
+    "answer": "米或m;厘米或cm;米或m;厘米或cm;厘米或cm",
+    "solution": "【分析】汽车较长用米;数学课本较短用厘米;身高写作1米25厘米;水瓶较矮用厘米.\n【详解】汽车长约4米;数学课本长约24厘米;红红身高1米25厘米;水瓶高约20厘米。",
+    "knowledge_points": [
+      "长度单位的选择"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "270",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "在括号里填上合适的长度单位.\n大树高约 8( );数学书长约 26( );冰箱高约为 2( )。",
+    "options": [],
+    "answer": "米或m;厘米或cm;米或m",
+    "solution": "【分析】根据生活经验和实际数据：计量大树高度用\"米\"，计量数学书长度用\"厘米\"，计量冰箱高度用\"米\".\n【详解】大树高约8米;数学书长约26厘米;冰箱高约为2米。",
+    "knowledge_points": [
+      "长度单位的选择",
+      "厘米的认识",
+      "米的认识"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "271",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "在括号里填上适当的长度单位.\n一支铅笔长约 15( )。课桌高约 80( ).\n教学楼高约 10( )。小明的身高是 120( )。",
+    "options": [],
+    "answer": "厘米或cm;厘米或cm;米或m;厘米或cm",
+    "solution": "【分析】量比较短的物体用厘米作单位;测量较长的物体用米作单位.\n【详解】铅笔长约15厘米;课桌高约80厘米;教学楼高约10米;小明身高120厘米。",
+    "knowledge_points": [
+      "长度单位的选择"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "272",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "在( )里填上\"厘米\"或\"米\".\n一支铅笔长 20( );课桌高 70( );教学楼高 18( );篮球场长 28( )。",
+    "options": [],
+    "answer": "厘米或cm;厘米或cm;米或m;米或m",
+    "solution": "【分析】量比较短的物体通常用厘米作单位;量比较长的物体通常用米作单位.\n【详解】铅笔长20厘米;课桌高70厘米;教学楼高18米;篮球场长28米。",
+    "knowledge_points": [
+      "长度单位的选择",
+      "厘米的认识",
+      "米的认识"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "273",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "1 米 = ( )厘米;20 厘米 + 30 厘米 = ( )厘米;30 米 - 7 米 = ( )米;1 米 - 60 厘米 = ( )厘米",
+    "options": [],
+    "answer": "100;50;23;40",
+    "solution": "【分析】根据1米 = 100厘米换算统一单位后计算.\n【详解】1米=100厘米;20+30=50厘米;30-7=23米;1米-60厘米=100厘米-60厘米=40厘米。",
+    "knowledge_points": [
+      "厘米和米之间的进率与换算"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "274",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "![](images/d0c1bbb5f54851226417e6bcbe77d77f521a1cdca361538dfe904241c976e472.jpg)\n\n![](images/fdaacbc1fdbb137ea0320e2343ad2ccdf2956433905f88b4dff8ee86e221b64b.jpg)\n\n回形针长( )厘米;铅笔长( )厘米",
+    "options": [],
+    "answer": "6;3",
+    "solution": "【分析】用直尺测量：若未从0刻度开始，用结束刻度减开始刻度.\n【详解】8 - 2 = 6(厘米),回形针长6厘米;3 - 0 = 3(厘米),铅笔长3厘米。",
+    "knowledge_points": [
+      "长度的测量方法",
+      "厘米的认识"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "275",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "30 厘米 + 70 厘米 = ( )米;15 米 + 7 米 = ( )米;145 厘米 = ( )米( )厘米",
+    "options": [],
+    "answer": "1;22;1;45",
+    "solution": "【分析】(1)先计算后根据1米=100厘米换算;(2)直接相加;(3)145厘米=1米45厘米.\n【详解】30+70=100厘米=1米;15+7=22米;145厘米=1米45厘米。",
+    "knowledge_points": [
+      "整十数之间的加减法",
+      "厘米和米之间的进率与换算"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "276",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "在括号里填上\"厘米\"或\"米\".\n(1)一块橡皮长 4( )。(2)大象高 4( ).\n(3)小明家的客厅长 5( )。(4)牙刷长 18( )。",
+    "options": [],
+    "answer": "厘米或cm;米或m;米或m;厘米或cm",
+    "solution": "【分析】结合生活经验：较短用厘米，较长用米.\n【详解】橡皮长4厘米;大象高4米;客厅长5米;牙刷长18厘米。",
+    "knowledge_points": [
+      "长度单位的选择",
+      "厘米的认识",
+      "米的认识"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "277",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "200 厘米 = ( )米;15 厘米 - 8 厘米 = ( )厘米;5 米 + 8 米 = ( )米;90 厘米 + 10 厘米 = ( )厘米 = ( )米",
+    "options": [],
+    "answer": "2;7;13;100;1",
+    "solution": "【分析】同单位直接相加减;不同单位按1米=100厘米换算.\n【详解】200厘米=2米;15-8=7厘米;5+8=13米;90+10=100厘米=1米。",
+    "knowledge_points": [
+      "厘米和米之间的进率与换算"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "278",
+    "unit": "第一单元 长度单位",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "爸爸比叔叔高 3 米。()",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】人的身高差不可能达到3米.\n【详解】爸爸比叔叔高3米不符合实际，原题说法错误。故答案为: ×",
+    "knowledge_points": [
+      "厘米的认识",
+      "米的认识"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "279",
+    "unit": "第一单元 长度单位",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "拉紧的跳绳，可以看作一条线段。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】线段有两个端点，有限长，拉紧的跳绳可近似看作线段.\n【详解】拉紧的跳绳可以看作一条线段，原题说法正确。故答案为:√",
+    "knowledge_points": [
+      "线段的初步认识",
+      "线段，直线，射线的认识及特征"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "280",
+    "unit": "第一单元 长度单位",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "书桌高约 70 米。()",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】书桌高度应以厘米计,70米明显不符合实际.\n【详解】书桌高约70厘米，原题说法错误。故答案为: ×",
+    "knowledge_points": [
+      "长度单位的选择",
+      "厘米的认识",
+      "米的认识"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "281",
+    "unit": "第一单元 长度单位",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "100 厘米比 1 米长得多。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】100厘米 = 1米.\n【详解】100厘米和1米一样长，原题说法错误。故答案为: ×",
+    "knowledge_points": [
+      "厘米和米之间的进率与换算"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "282",
+    "unit": "第一单元 长度单位",
+    "question_type": "判断题",
+    "difficulty": 0.65,
+    "question": "把1米长的绳子剪成 1 厘米长的小段，要剪 100 次。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】1米=100厘米，可剪成100段;剪的次数=段数-1.\n【详解】100 - 1 = 99(次),要剪99次。原题说法错误。故答案为: ×",
+    "knowledge_points": [
+      "厘米和米之间的进率与换算",
+      "植树问题(两端都不栽)"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "283",
+    "unit": "第一单元 长度单位",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "1 米长的铁丝和 100 厘米长的丝巾一样长。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】1米 = 100厘米，单位统一后相等.\n【详解】两者一样长，原题说法正确。故答案为:√",
+    "knowledge_points": [
+      "厘米和米之间的进率与换算"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "284",
+    "unit": "第一单元 长度单位",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "30 厘米 + 70 厘米 = 100 米。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】30+70=100厘米,100厘米=1米.\n【详解】30厘米+70厘米=100厘米=1米，不是100米。原题说法错误。故答案为: ×",
+    "knowledge_points": [
+      "厘米和米之间的进率与换算"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "285",
+    "unit": "第一单元 长度单位",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "学校里升国旗的旗杆高约 12 厘米。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】旗杆高度应以米计,12厘米太短.\n【详解】旗杆高约12米较合理，原说法错误。故答案为: ×",
+    "knowledge_points": [
+      "长度单位的选择"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "286",
+    "unit": "第一单元 长度单位",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "20 厘米的线段比 1 米的线段长。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】1米=100厘米,100厘米>20厘米.\n【详解】20厘米比1米短，原题说法错误。故答案为: ×",
+    "knowledge_points": [
+      "厘米和米之间的进率与换算"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "287",
+    "unit": "第一单元 长度单位",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "图形![](images/667c3165d291e48084e33d1a8dd38380fdb9486dd7c3e49db1d45b87d7a50f72.jpg)是由 6条线段组成的。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】线段有端点且是直的，数出图形中线段条数即可.\n【详解】图形由6条线段组成，原题说法正确。故答案为:√",
+    "knowledge_points": [
+      "线段的初步认识"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "288",
+    "unit": "第一单元 长度单位",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "餐桌长约 4 厘米。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】4厘米很短，与餐桌长度不符.\n【详解】4厘米约为橡皮长度，餐桌远长于4厘米。原题说法错误。故答案为: ×",
+    "knowledge_points": [
+      "厘米的认识",
+      "长度的估测"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "289",
+    "unit": "第一单元 长度单位",
+    "question_type": "判断题",
+    "difficulty": 0.65,
+    "question": "一根跳绳比 1 米长，一只小猫比 1 米矮。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】跳绳一般约2米，小猫约20厘米左右，符合题意.\n【详解】2米 > 1米 > 20厘米，所以跳绳比1米长，小猫比1米矮，原题说法正确。故答案为:√",
+    "knowledge_points": [
+      "厘米和米之间的进率与换算",
+      "厘米的认识",
+      "米的认识"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "290",
+    "unit": "第一单元 长度单位",
+    "question_type": "判断题",
+    "difficulty": 0.65,
+    "question": "妹妹现在的身高是 50 厘米，再长 50 厘米就够 1 米了。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】50厘米+50厘米=100厘米=1米.\n【详解】再长50厘米就到1米，原题说法正确。故答案为:√",
+    "knowledge_points": [
+      "厘米和米之间的进率与换算"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "291",
+    "unit": "第一单元 长度单位",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "一根竹竿长 1 米，插入水中后，水上部分是 10 厘米，水下部分是 9 厘米。()",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】总长度-水上部分=水下部分。先把1米换算成100厘米.\n【详解】100 - 10 = 90(厘米),水下部分应为90厘米，不是9厘米。原题说法错误。故答案为: ×",
+    "knowledge_points": [
+      "厘米和米之间的进率与换算"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "292",
+    "unit": "第一单元 长度单位",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "尺子是测量长度的工具，尺子上的\"厘米\"就是一个统一的长度单位。()",
+    "options": [],
+    "answer": "√",
+    "solution": "【详解】尺子是测量长度的工具，尺子上的\"厘米\"就是一个统一的长度单位。原题说法正确.\n![](images/fc575e40501fd50eb5681dfeb4773533a006ab34d9d86b449b0cbc8569caeb3a.jpg)\n故答案为:√",
+    "knowledge_points": [
+      "厘米的认识"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "293",
+    "unit": "第一单元 长度单位",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "小强认为 100 厘米的铁丝比 1 米的细线长。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】1米 = 100厘米.\n【详解】100厘米的铁丝和1米的细线同样长，原题说法错误。故答案为: ×",
+    "knowledge_points": [
+      "厘米和米之间的进率与换算"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "294",
+    "unit": "第一单元 长度单位",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "食指的宽大约 1 米。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】食指的宽大约是1厘米.\n【详解】食指的宽大约1厘米，原题说法错误。故答案为: ×",
+    "knowledge_points": [
+      "长度单位的选择",
+      "长度的估测"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "295",
+    "unit": "第一单元 长度单位",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "两点连在一起就是线段。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】线段是直的，有限长，有两个端点;两点连在一起不一定形成线段.\n【详解】两点连在一起不一定就是线段，原题说法错误。故答案为: ×",
+    "knowledge_points": [
+      "线段的初步认识"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "296",
+    "unit": "第一单元 长度单位",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "一名二年级小学生的身高约 135 厘米。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】身高一般用厘米作单位,135厘米符合二年级学生身高范围.\n【详解】原题说法正确。故答案为:√",
+    "knowledge_points": [
+      "厘米的认识",
+      "米的认识"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "297",
+    "unit": "第一单元 长度单位",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "小明走一步大约是40 米。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】走一步的长度应以厘米计,40米明显不符合实际.\n【详解】小明走一步大约40厘米，原题说法错误。故答案为: ×",
+    "knowledge_points": [
+      "厘米的认识",
+      "米的认识"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "298",
+    "unit": "第一单元 长度单位",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "长 100 厘米的线段比 1米的线段长。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】1米 = 100厘米.\n【详解】100厘米和1米一样长，原说法错误。故答案为: ×",
+    "knowledge_points": [
+      "厘米和米之间的进率与换算"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "299",
+    "unit": "第一单元 长度单位",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "小明的身高是 229 米。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】人的身高通常不会超过3米,229米明显不符合实际.\n【详解】原题说法错误。故答案为: ×",
+    "knowledge_points": [
+      "长度单位的选择",
+      "米的认识"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "300",
+    "unit": "第一单元 长度单位",
+    "question_type": "解答题",
+    "difficulty": 0.65,
+    "question": "课桌高 1 米，椅子高50厘米。课桌比椅子高多少厘米。",
+    "options": [],
+    "answer": "50厘米",
+    "solution": "【分析】先将1米换算成100厘米，再用课桌高度减去椅子高度.\n【详解】1米 = 100厘米,100 - 50 = 50(厘米),答：课桌比椅子高50厘米。",
+    "knowledge_points": [
+      "整十数之间的加减法",
+      "厘米和米之间的进率与换算"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "301",
+    "unit": "第一单元 长度单位",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "生活中( )最接近1米。",
+    "options": [
+      "A. 写字台的高度",
+      "B. 数学书的长",
+      "C. 教室的高度"
+    ],
+    "answer": "A",
+    "solution": "【分析】计量较长的物体用\"米\"作单位，计量较短的物体用\"厘米\"作单位，据此判断.\n【详解】写字台高度约1米符合;数学书长约20厘米不符合;教室高度约3米不符合。故答案为:A",
+    "knowledge_points": [
+      "米的认识",
+      "厘米的认识"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "302",
+    "unit": "第一单元 长度单位",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "下面选项中，最接近图中铅笔长度的是( ).\n\n![](images/c6f928dd17801568952eee18cfbaf652eb0ca138d81ffe081ecad01156d393c5.jpg)",
+    "options": [
+      "A. 10厘米",
+      "B. 9厘米",
+      "C. 8厘米"
+    ],
+    "answer": "B",
+    "solution": "【分析】尺子测量：长度 = 结束刻度 - 开始刻度，再结合图中超过整数刻度的部分估计.\n【详解】10 - 2 = 8(厘米),还多出将近1厘米，约为9厘米。故答案为:B",
+    "knowledge_points": [
+      "长度的测量方法",
+      "长度的估测"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "303",
+    "unit": "第一单元 长度单位",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "小狗选第( )条路回家最近.\n\n![](images/fe3badbb9fd9fb12d9ff5b786721e95660a1755111b26dc8523aa422a9f1d020.jpg)",
+    "options": [
+      "A. ①",
+      "B. ②",
+      "C. ③"
+    ],
+    "answer": "B",
+    "solution": "【分析】弯曲越少的路线越短.\n【详解】第②条路线弯曲最少，最近。故答案为:B",
+    "knowledge_points": [
+      "比长短"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "304",
+    "unit": "第一单元 长度单位",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "1 米 75 厘米可能是( )的高度。",
+    "options": [
+      "A. 教学楼",
+      "B. 旗杆",
+      "C. 冰箱"
+    ],
+    "answer": "C",
+    "solution": "【分析】根据生活经验判断数量级.\n【详解】教学楼，旗杆高度一般十米左右;冰箱高度约一米多。故答案为:C",
+    "knowledge_points": [
+      "米的认识",
+      "长度的估测",
+      "厘米的认识"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "305",
+    "unit": "第一单元 长度单位",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "有三条彩带，红色的长80厘米，黄色的长8厘米，蓝色的长8米，三条彩带的长度相比，结果是( )。",
+    "options": [
+      "A. 红色长",
+      "B. 黄色长",
+      "C. 蓝色长",
+      "D. 同样长"
+    ],
+    "answer": "C",
+    "solution": "【分析】单位不同先根据1米=100厘米统一单位再比较.\n【详解】8厘米 < 80厘米 < 8米。故答案为:C",
+    "knowledge_points": [
+      "厘米和米之间的进率与换算"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "306",
+    "unit": "第一单元 长度单位",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "加加用\"身体尺\"在班级里进行测量，下面哪句话是正确的。( )",
+    "options": [
+      "A. 教室大约长3步",
+      "B. 数学书大约厚3拃",
+      "C. 黑板大约长 3 庹"
+    ],
+    "answer": "C",
+    "solution": "【分析】结合\"身体尺\"常识:1步约70厘米,1拃约15厘米,1庹约1米，逐项判断.\n【详解】教室长8~9米,3步不够;数学书厚度不到一拃;黑板约4米，约3庹合理。故答案为:C",
+    "knowledge_points": [
+      "长度的测量方法",
+      "\"身体尺\"的认识及应用",
+      "长度的估测"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "307",
+    "unit": "第一单元 长度单位",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "用尺子画一条长5厘米的线段，正确的画法是( )。",
+    "options": [
+      "A. 沿尺子上的刻度1画到刻度5",
+      "B. 沿尺子上的刻度3画到刻度9",
+      "C. 沿尺子上的刻度0画到刻度5"
+    ],
+    "answer": "C",
+    "solution": "【分析】画线段从0刻度开始，或两端刻度差等于线段长度.\n【详解】A:5 - 1 = 4厘米;B:9 - 3 = 6厘米;C:5 - 0 = 5厘米。故答案为:C",
+    "knowledge_points": [
+      "用直尺画线段"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "308",
+    "unit": "第一单元 长度单位",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "一辆宽 1 米的三轮车( )从宽99厘米的门洞里顺利通过。",
+    "options": [
+      "A. 能",
+      "B. 不能",
+      "C. 无法确定能不能"
+    ],
+    "answer": "B",
+    "solution": "【分析】把1米化成100厘米，与99厘米比较.\n【详解】100厘米 > 99厘米，三轮车更宽，不能通过。故答案为:B",
+    "knowledge_points": [
+      "厘米和米之间的进率与换算",
+      "100 以内数的比大小"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "309",
+    "unit": "第一单元 长度单位",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "乐乐和爸爸要给妈妈做一条新围裙。爸爸用手量了量，妈妈的围裙正好五拃长，乐乐用手在布上量出五拃做成一条围裙。请你猜一猜，乐乐做的这条围裙，妈妈穿上后,( )。",
+    "options": [
+      "A. 会小",
+      "B. 会大",
+      "C. 正好"
+    ],
+    "answer": "A",
+    "solution": "【分析】同量五拃，但乐乐的手更小，一拃更短，所以做出的围裙更小.\n【详解】妈妈穿上会小。故答案为:A",
+    "knowledge_points": [
+      "长度的测量方法",
+      "\"身体尺\"的认识及应用"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "310",
+    "unit": "第一单元 长度单位",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "童童的爸爸高1米70厘米，童童高1米30厘米，爸爸比童童高( )。",
+    "options": [
+      "A. 1 米",
+      "B. 100 厘米",
+      "C. 40 厘米"
+    ],
+    "answer": "C",
+    "solution": "【分析】同为1米多，比较厘米部分即可.\n【详解】1米70厘米 - 1米30厘米 = 40厘米。故答案为:C",
+    "knowledge_points": [
+      "厘米和米之间的进率与换算"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "311",
+    "unit": "第一单元 长度单位",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "蜡笔比橡皮长( )厘米.\n\n![](images/1df3a33b6f73c16d8cb4db658904e1dc8c25ccaa22ad6735f5ced52b493a4070.jpg)",
+    "options": [
+      "A. 4",
+      "B. 2",
+      "C. 8"
+    ],
+    "answer": "B",
+    "solution": "【分析】先分别求蜡笔和橡皮长度，再相减.\n【详解】8-2=6(厘米),6-4=2(厘米),蜡笔比橡皮长2厘米。故答案为:B",
+    "knowledge_points": [
+      "长度的测量方法",
+      "厘米的认识"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "312",
+    "unit": "第一单元 长度单位",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "小明用手测量一根绳子的长度，正好 4 拃。这根绳子长约( ).\n\n![](images/2b6679b8f801c75def57aa11493ac10715606cc99c63a1e9594e35f5a64545bd.jpg)",
+    "options": [
+      "A. 15厘米",
+      "B. 50厘米",
+      "C. 2米",
+      "D. 4米"
+    ],
+    "answer": "B",
+    "solution": "【分析】一拃约10~15厘米,4拃约50厘米.\n【详解】约50厘米。故答案为:B",
+    "knowledge_points": [
+      "长度单位的选择",
+      "\"身体尺\"的认识及应用",
+      "长度的估测"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "313",
+    "unit": "第一单元 长度单位",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "下列线段中，长度最接近 2 厘米的是( )。",
+    "options": [
+      "A. ![](images/2026-02-05%20160324.jpg)",
+      "B. ![](images/2026-02-05%20160338.jpg)",
+      "C. ![](images/2026-02-05%20160351.jpg)",
+      "D. ![](images/2026-02-05%20160400.jpg)"
+    ],
+    "answer": "B",
+    "solution": "【分析】用尺子测量各选项线段长度，判断哪个最接近2厘米.\n【详解】第二个线段长2厘米，最接近2厘米。故答案为:B",
+    "knowledge_points": [
+      "长度的测量方法"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "314",
+    "unit": "第一单元 长度单位",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "福建土楼，原是用于防御，城墙坚厚，可高达 11( )。",
+    "options": [
+      "A. 厘米",
+      "B. 米",
+      "C. 分"
+    ],
+    "answer": "B",
+    "solution": "【分析】城墙高度很高，应以\"米\"为单位.\n【详解】可高达11米。故答案为:B",
+    "knowledge_points": [
+      "长度单位的选择",
+      "米的认识",
+      "厘米的认识"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "315",
+    "unit": "第一单元 长度单位",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "公交车大约高( ).\n\n![](images/7c90fcc91975a4ffc254ff32d7822ad8db6852b57f9670462cfb43fa304eb406.jpg)",
+    "options": [
+      "A. 1米",
+      "B. 3米",
+      "C. 3厘米"
+    ],
+    "answer": "B",
+    "solution": "【分析】公交车高度高于成人身高，应为几米.\n【详解】3米合理;1米太矮;3厘米太小。故答案为:B",
+    "knowledge_points": [
+      "米的认识",
+      "长度的估测",
+      "厘米的认识"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "316",
+    "unit": "第一单元 长度单位",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面( )的高度，大约是 20 米。",
+    "options": [
+      "A. 餐桌",
+      "B. 数学课本的长",
+      "C. 5 层楼"
+    ],
+    "answer": "C",
+    "solution": "【分析】根据生活经验估测：餐桌高约1米，数学书长约20厘米,5层楼高约20米.\n【详解】5层楼的高度大约是20米。故答案为:C",
+    "knowledge_points": [
+      "长度的估测"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "317",
+    "unit": "第一单元 长度单位",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面说法正确的是( )。",
+    "options": [
+      "A. 课桌边，圆桌边都可以看作线段",
+      "B. 牙刷长 15 米",
+      "C. 我们用的直尺上，从刻度\"4\"到刻度\"8\"的长度是 4厘米"
+    ],
+    "answer": "C",
+    "solution": "【分析】圆桌边是曲线不是线段;牙刷不可能15米;直尺上8-4=4厘米.\n【详解】只有C正确。故答案为:C",
+    "knowledge_points": [
+      "长度单位的选择",
+      "线段，直线，射线的认识及特征",
+      "长度的测量方法",
+      "厘米的认识"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "318",
+    "unit": "第一单元 长度单位",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "10 米可能是( )。",
+    "options": [
+      "A. 爸爸的身高",
+      "B. 小草的高度",
+      "C. 楼房的高度"
+    ],
+    "answer": "C",
+    "solution": "【分析】爸爸身高约1~2米，小草约厘米，楼房可能约10米.\n【详解】三层楼约10米，符合。故答案为:C",
+    "knowledge_points": [
+      "米的认识",
+      "长度的估测",
+      "厘米的认识"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "319",
+    "unit": "第一单元 长度单位",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "( )根 10 厘米连起来长 1 米。",
+    "options": [
+      "A. 2",
+      "B. 5",
+      "C. 10"
+    ],
+    "answer": "C",
+    "solution": "【分析】1米=100厘米,100里有10个10.\n【详解】10根10厘米连起来长1米。故答案为:C",
+    "knowledge_points": [
+      "厘米和米之间的进率与换算"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "320",
+    "unit": "第一单元 长度单位",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "![](images/2026-02-05%20160801.jpg)\n左图中有( )条线段。",
+    "options": [
+      "A. 3",
+      "B. 6",
+      "C. 4"
+    ],
+    "answer": "B",
+    "solution": "【分析】分别数出由1条,2条,3条小线段组成的线段条数并相加.\n【详解】3+2+1=6条。故答案为:B",
+    "knowledge_points": [
+      "线段的初步认识"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "321",
+    "unit": "第一单元 长度单位",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "菲菲在练习本上画了一条 4 米长的线段。这句话( )。",
+    "options": [
+      "A. 合理",
+      "B. 不合理",
+      "C. 无法判断"
+    ],
+    "answer": "B",
+    "solution": "【分析】练习本上画线段应以厘米计.\n【详解】画4米长线段不合理。故答案为:B",
+    "knowledge_points": [
+      "长度单位的选择"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "322",
+    "unit": "第一单元 长度单位",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "校园里的旗杆高是15( )。",
+    "options": [
+      "A. 厘米",
+      "B. 分",
+      "C. 米"
+    ],
+    "answer": "C",
+    "solution": "【分析】旗杆较高，应用米作单位.\n【详解】旗杆高15米。故答案为:C",
+    "knowledge_points": [
+      "长度单位的选择",
+      "米的认识",
+      "厘米的认识"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "323",
+    "unit": "第一单元 长度单位",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "线段是直的，有( )个端点。",
+    "options": [
+      "A. 1",
+      "B. 2",
+      "C. 0"
+    ],
+    "answer": "B",
+    "solution": "【分析】线段有两个端点，中间是直直的线，长度可测量.\n【详解】线段有2个端点。故答案为:B",
+    "knowledge_points": [
+      "线段的初步认识"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "324",
+    "unit": "第一单元 长度单位",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下图中,( )是线段.\n\n![](images/5b938ec4595f89fd1bb277918f8cd9a7cfe4ef23f804e93cc5e4dae3e0111fdc.jpg)",
+    "options": [],
+    "answer": "C",
+    "solution": "【分析】线段有2个端点且是直直的线.\n【详解】C是线段。故答案为:C",
+    "knowledge_points": [
+      "线段的初步认识"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "325",
+    "unit": "第一单元 长度单位",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下图由( )条线段组成.\n\n![](images/713aa604658bda4a7100062fa54bcf4b49851c62afa447e87404acf2c99d38fd.jpg)",
+    "options": [
+      "A. 5",
+      "B. 6",
+      "C. 7"
+    ],
+    "answer": "B",
+    "solution": "【分析】数出图形中线段条数.\n【详解】一共由6条线段组成。故答案为:B\n![](images/80f88f11a14e397a6825879c868eb59f9851293bcb53a8b76eb6361433fdeaa8.jpg)",
+    "knowledge_points": [
+      "线段的初步认识",
+      "数图形(线段，直线，射线)"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "326",
+    "unit": "第一单元 长度单位",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面木条( )的长度正好 5 厘米。",
+    "options": [
+      "A. ![](images/c3d9b8ed49833790e427c18e3574737955143e545985ec345950b89cc69261ae.jpg)",
+      "B. ![](images/ddf27609141c9184b79c9fb59aaa1f0f28db25db00658fbcbd73af284e930257.jpg)",
+      "C. ![](images/2d5a6321718a10a4783f83bf8fa0be48869b5e8b6bdc724db2caa385eba14dfb.jpg)"
+    ],
+    "answer": "B",
+    "solution": "【分析】测量时看两端刻度，若不从0开始用结束刻度-开始刻度.\n【详解】B:6 - 1 = 5(厘米),正好5厘米。故答案为:B",
+    "knowledge_points": [
+      "长度的测量方法"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "327",
+    "unit": "第一单元 长度单位",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "有三根绳子，红色的长5米，黄色的长55厘米，绿色的长50厘米。三根绳子比较,( )。",
+    "options": [
+      "A. 红色的最短",
+      "B. 黄色的最短",
+      "C. 绿色的最短"
+    ],
+    "answer": "C",
+    "solution": "【分析】1米=100厘米，把长度与1米比较并排序.\n【详解】5米最长;55厘米>50厘米，所以绿色最短。故答案为:C",
+    "knowledge_points": [
+      "厘米和米之间的进率与换算"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "328",
+    "unit": "第一单元 长度单位",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面( )的测量方法正确。",
+    "options": [
+      "A. ![](images/fc4babd22b3bb77f7ddab90177bb90679e6d9d0a63bbfee994b0e2dd702faae9.jpg)",
+      "B. ![](images/fba8a2e9b6ffcce2f1927008cf930904521fd9c66360dbcafcdd78c73e4e6da6.jpg)",
+      "C. ![](images/5982fb2ad317a1d6f49b120f12f14b4c227d59b9af0903bf959a0aea71087139.jpg)"
+    ],
+    "answer": "B",
+    "solution": "【分析】测量时物体一端与0刻度对齐，直尺与物体放平.\n【详解】只有B测量方法正确。故答案为:B",
+    "knowledge_points": [
+      "长度的测量方法"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "329",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "在括号里填上合适的数.\n500 厘米 = ( )米;3 米 = ( )厘米\n50 厘米 + 50 厘米 = ( )米;25 厘米 - 7 厘米 = ( )厘米",
+    "options": [],
+    "answer": "5;300;1;18",
+    "solution": "【分析】同单位直接相加减，不同单位按1米=100厘米换算.\n【详解】500厘米=5米;3米=300厘米;50+50=100厘米=1米;25-7=18厘米。",
+    "knowledge_points": [
+      "厘米和米之间的进率与换算"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "330",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "填一填。1 米 - 40 厘米( )20 厘米",
+    "options": [],
+    "answer": ">",
+    "solution": "【分析】1米=100厘米，先计算再比较.\n【详解】100-40=60厘米,60>20，所以填\">\"。",
+    "knowledge_points": [
+      "整十数之间的加减法",
+      "厘米和米之间的进率与换算"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "331",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "填一填。( )厘米 = 1 米",
+    "options": [],
+    "answer": "100",
+    "solution": "【分析】1米里面有100个1厘米.\n【详解】100厘米=1米。",
+    "knowledge_points": [
+      "厘米和米之间的进率与换算"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "332",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "一个水杯大约高10厘米,( )个这样的水杯叠起来高 1 米。",
+    "options": [],
+    "answer": "10",
+    "solution": "【分析】1米=100厘米,100里面有10个10.\n【详解】10个这样的水杯叠起来约1米高。",
+    "knowledge_points": [
+      "厘米和米之间的进率与换算"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "333",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "华华用一根长5米的竹竿测量水深，竹竿露出水面的部分是 2 米，水深( )米。",
+    "options": [],
+    "answer": "3",
+    "solution": "【分析】用竹竿总长减去露出水面的长度.\n【详解】5 - 2 = 3(米),水深3米。",
+    "knowledge_points": [
+      "长度的测量方法"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "334",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "兵马俑被誉为\"世界第八大奇迹\"。奇奇和妈妈参观秦始皇兵马俑，导游介绍一号坑深 5( )左右，每隔约 300( )架起一道由东向西的承重墙，俑坑中的武士俑，身高在1( )85( )左右。(填\"厘米\"或\"米\")",
+    "options": [],
+    "answer": "米或m;厘米或cm;米或m;厘米或cm",
+    "solution": "【分析】根据经验，数据大小可知：计量较长的物体，用\"米\"作单位，学生的双臂展开约为 1米。计量较短的物体，用\"厘米\"作单位，食指的宽度约为1厘米.\n【详解】兵马俑被誉为\"世界第八大奇迹\"。奇奇和妈妈参观秦始皇兵马俑，导游介绍一号坑深5(米)左右，每隔约300(厘米)架起一道由东向西的承重墙，俑坑中的武士俑，身高在1(米)85(厘米)左右。(填\"厘米\"或\"米\")",
+    "knowledge_points": [
+      "长度单位的选择",
+      "米的认识",
+      "厘米的认识"
+    ],
+    "source": "24-25 二年级上·全国·单元测试"
+  },
+  {
+    "id": "335",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "在括号里填上\"厘米\"或\"米\".\n\n旗杆高约 9( );房门宽约 90( );游泳池水深约 2( );冰箱高约 1( )70( )。",
+    "options": [],
+    "answer": "米或m;厘米或cm;米或m;米或m;厘米或cm",
+    "solution": "【分析】根据情景选择合适的计量单位，要注意联系生活实际，计量单位和数据的大小，灵活的选择。大拇指的指甲长度大约1厘米，计量房门的宽用\"厘米\"作单位比较合适。小学生两臂伸开的长度大约1米，计量旗杆的高度和游泳池的深度用\"米\"作单位比较合适。冰箱高度和成年人身高差不多，成年人的身高一般是一百多厘米,100厘米 = 1 米，也就是大约1米几十厘米.\n【详解】旗杆高约 9 米;房门宽约 90 厘米;游泳池水深约 2 米;冰箱高约 1 米 70 厘米。",
+    "knowledge_points": [
+      "长度单位的选择",
+      "米的认识",
+      "厘米的认识"
+    ],
+    "source": "24-25 二年级上·福建泉州·期中"
+  },
+  {
+    "id": "336",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "在括号里填上\">\" \"<\"或\"=\" .\n\n10 米( )100 厘米;50 厘米( )5 米;100 厘米( )1 米10 厘米\n1 米+99 厘米( )100厘米;2 米( )100 厘米+1 米",
+    "options": [],
+    "answer": ">;<;<;>;=",
+    "solution": "【分析】据题意，先进行单位换算,1米 = 100厘米，再计算出算式的结果，进行比较即可.\n【详解】100厘米 = 1米，所以10米 > 100厘米;5米 = 500厘米，所以50厘米 < 5米;1米 = 100厘米,1米10厘米 = 110厘米，所以100厘米 < 1米10厘米;1米 = 100厘米,1米 + 99厘米 = 199厘米，所以1米 + 99厘米 > 100厘米;1米 = 100厘米,100厘米 + 1米 = 200厘米,2米 = 200厘米，所以2米 = 100厘米 + 1米。",
+    "knowledge_points": [
+      "厘米和米之间的进率与换算"
+    ],
+    "source": "24-25 二年级上·福建福州·期中"
+  },
+  {
+    "id": "337",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "在( )里填上\"厘米\"或\"米\".\n\n小鼓的食指宽约 1( );壮壮张开双臂的长度约是 1( )\n\n一间教室长约 8( );老师的身高是 1( )65( )",
+    "options": [],
+    "answer": "厘米或cm;米或m;米或m;米或m;厘米或cm",
+    "solution": "【分析】联系生活实际，计量单位和数据的大小，灵活的选择。大拇指的指甲长度大约 1 厘米，计量食指的宽度用\"厘米\"作单位比较合适。小学生两臂伸开的长度大约1米，计量双臂张开的长度和教室的长度用\"米\"作单位比较合适。成年人的身高一般是一百多厘米,100厘米 = 1 米，也就是大约 1 米几十厘米.\n【详解】小鼓的食指宽约1厘米;壮壮张开双臂的长度约是1米;一间教室长约8米;老师的身高是1米65厘米。",
+    "knowledge_points": [
+      "厘米和米之间的进率与换算",
+      "长度单位的选择",
+      "米的认识",
+      "厘米的认识"
+    ],
+    "source": "24-25 二年级上·福建福州·期中"
+  },
+  {
+    "id": "338",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "在下列括号里填上合适的单位名称.\n\n数学课本长 26( );火车一节车厢长 23( );门高 190( )。",
+    "options": [],
+    "answer": "厘米或cm;米或m;厘米或cm",
+    "solution": "【分析】根据生活经验和数据大小选择合适单位。计量较短的物体用\"厘米\"，计量较长的物体用\"米\".\n【详解】数学课本长26厘米;火车一节车厢长23米;门高190厘米。",
+    "knowledge_points": [
+      "长度单位的选择",
+      "米的认识",
+      "厘米的认识"
+    ],
+    "source": "24-25 二年级上·福建三明·期中"
+  },
+  {
+    "id": "339",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "2 米 = ( )厘米;( )米 = 400 厘米;55 厘米+45 厘米=( )米",
+    "options": [],
+    "answer": "200;4;1",
+    "solution": "【分析】根据1米 = 100厘米进行单位换算，同单位相加减.\n【详解】2米=200厘米;400厘米=4米;55厘米+45厘米=100厘米=1米。",
+    "knowledge_points": [
+      "厘米和米之间的进率与换算"
+    ],
+    "source": "24-25 二年级上·湖南怀化·期中"
+  },
+  {
+    "id": "340",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "在括号里填上\">\" \"<\"或 \"=\".\n\n73 厘米( )37 厘米;73 厘米( )7 米\n3 米-2 米( )99 厘米;40 厘米+60 厘米( )1 米",
+    "options": [],
+    "answer": ">;<;>;=",
+    "solution": "【分析】先把单位统一为厘米或米，再计算比较.\n【详解】73厘米>37厘米;7米=700厘米，所以73厘米<7米;3米-2米=1米=100厘米，所以>99厘米;40厘米+60厘米=100厘米=1米，所以=。",
+    "knowledge_points": [
+      "整十数之间的加减法",
+      "厘米和米之间的进率与换算",
+      "100以内数的比大小"
+    ],
+    "source": "24-25 二年级上·福建龙岩·期中"
+  },
+  {
+    "id": "341",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "在括号里填上合适的单位.\n\n铅笔盒长约 25( );天安门广场的国旗旗杆高约 30( )\n\n一拃长约 16( );明明身高 1( )36( )",
+    "options": [],
+    "answer": "厘米或cm;米或m;厘米或cm;米或m;厘米或cm",
+    "solution": "【分析】联系生活实际，根据物体长短选择合适的长度单位.\n【详解】铅笔盒长约25厘米;国旗旗杆高约30米;一拃长约16厘米;明明身高1米36厘米。",
+    "knowledge_points": [
+      "长度单位的选择",
+      "\"身体尺\"的认识及应用",
+      "米的认识",
+      "厘米的认识"
+    ],
+    "source": "24-25 二年级上·福建龙岩·期中"
+  },
+  {
+    "id": "342",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "在括号里填上合适的长度单位.\n\n早晨，身高 138( )的明明从长 2( )的单人床上起来，吃过早饭，来到学校，就看到了高 15( )的教学楼，走进教室，他坐到长 1( ),高 75( )的课桌前，拿起书读了起来。",
+    "options": [],
+    "answer": "厘米或cm;米或m;米或m;米或m;厘米或cm",
+    "solution": "【分析】根据生活经验与数据大小选择单位：较长用米，较短用厘米.\n【详解】身高138厘米;单人床长2米;教学楼高15米;课桌长1米，高75厘米。",
+    "knowledge_points": [
+      "长度单位的选择"
+    ],
+    "source": "24-25 二年级上·福建漳州·期中"
+  },
+  {
+    "id": "343",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "1 米=()厘米;500 厘米=( )米;18 厘米+4 厘米=( )厘米;450 厘米=( )米( )厘米",
+    "options": [],
+    "answer": "100;5;22;4;50",
+    "solution": "【分析】利用1米=100厘米进行单位换算，统一单位后计算.\n【详解】1米=100厘米;500厘米=5米;18厘米+4厘米=22厘米;450厘米=4米50厘米。",
+    "knowledge_points": [
+      "厘米和米之间的进率与换算"
+    ],
+    "source": "24-25 二年级上·湖北省直辖县级单位·期中"
+  },
+  {
+    "id": "344",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "在下面的括号里填上合适的长度单位.\n\n齐齐今年上二年级，身高 1( )35( ),手掌宽约 8( ),他跨出一步大约长 40( )。今天他成为了学校里光荣的升旗手，他将站在高 15( )的旗杆旁升起五星红旗。",
+    "options": [],
+    "answer": "米或m;厘米或cm;厘米或cm;厘米或cm;米或m",
+    "solution": "【分析】结合生活经验，较长用米，较短用厘米.\n【详解】身高1米35厘米;手掌宽8厘米;一步长40厘米;旗杆高15米。",
+    "knowledge_points": [
+      "长度单位的选择",
+      "米的认识",
+      "厘米的认识"
+    ],
+    "source": "24-25 二年级上·河南三门峡·期中"
+  },
+  {
+    "id": "345",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "在括号里填上合适的长度单位.\n\n小明身高 130( );一棵大树高约 8( )\n\n一张床长约 2( );一块橡皮长约 2( )",
+    "options": [],
+    "answer": "厘米或cm;米或m;米或m;厘米或cm",
+    "solution": "【分析】根据生活经验选择单位：身高，橡皮较短用厘米;大树，床较长用米.\n【详解】小明身高130厘米;大树高约8米;床长约2米;橡皮长约2厘米。",
+    "knowledge_points": [
+      "长度单位的选择"
+    ],
+    "source": "24-25 二年级上·贵州六盘水·期中"
+  },
+  {
+    "id": "346",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "![](images/429a708e907f1282f2341e25ab600376b2522e7aeb2fbbfa6e1094513f0d3bdb.jpg)\n\n小刀长( )厘米。",
+    "options": [],
+    "answer": "6",
+    "solution": "【分析】测量时物体一端对齐0刻度，另一端对应刻度即长度.\n【详解】小刀长6厘米。",
+    "knowledge_points": [
+      "长度的测量方法",
+      "厘米的认识"
+    ],
+    "source": "23-24 二年级上·山西晋中·期中"
+  },
+  {
+    "id": "347",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "测量铅笔的长度用()作单位比较合适，测量运动场跑道的长度用( )作单位比较合适。冬冬的橡皮长约4( ),学校的旗杆高约10( )。",
+    "options": [],
+    "answer": "厘米或cm;米或m;厘米或cm;米或m",
+    "solution": "【分析】较短用厘米，较长用米.\n【详解】铅笔用厘米，跑道用米;橡皮约4厘米;旗杆高约10米。",
+    "knowledge_points": [
+      "长度单位的选择"
+    ],
+    "source": "24-25 二年级上·河南南阳·期中"
+  },
+  {
+    "id": "348",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "在括号里填上\"厘米\"或\"米\".\n\n一块橡皮长约4( );大树高约 6( );小红身高是 1( )21( )。",
+    "options": [],
+    "answer": "厘米或cm;米或m;米或m;厘米或cm",
+    "solution": "【分析】根据生活经验选择合适单位：橡皮较短用厘米;大树较高用米;身高用米和厘米.\n【详解】橡皮约4厘米;大树高约6米;小红身高1米21厘米。",
+    "knowledge_points": [
+      "长度单位的选择",
+      "米的认识",
+      "厘米的认识"
+    ],
+    "source": "24-25 二年级上·湖南衡阳·期中"
+  },
+  {
+    "id": "349",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "有一根1米长的绳子，小红用了 30 厘米，还剩( )厘米。",
+    "options": [],
+    "answer": "70",
+    "solution": "【分析】1米=100厘米，用减法求剩余:100-30.\n【详解】100厘米-30厘米=70厘米。",
+    "knowledge_points": [
+      "厘米和米之间的进率与换算"
+    ],
+    "source": "24-25 二年级上·贵州六盘水·期中"
+  },
+  {
+    "id": "350",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "在括号里填上\"米\"或\"厘米\".\n\n(1)学校教学楼高约 15( )。 (2)一本《汉语字典》大约厚 5( ).\n(3)一根跳绳长约 2( )。 (4)一支铅笔长约 15( )。",
+    "options": [],
+    "answer": "米或m;厘米或cm;米或m;厘米或cm",
+    "solution": "【分析】较长用米，较短用厘米.\n【详解】教学楼高约15米;字典厚约5厘米;跳绳长约2米;铅笔长约15厘米。",
+    "knowledge_points": [
+      "长度单位的选择",
+      "米的认识",
+      "厘米的认识"
+    ],
+    "source": "24-25 二年级上·河南南阳·期中"
+  },
+  {
+    "id": "351",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "课桌高约 75( );一支新铅笔大约长( )厘米",
+    "options": [],
+    "answer": "厘米或cm;18",
+    "solution": "【分析】大拇指的指甲长度大约1厘米，结合数据75，计量课桌的高度用\"厘米\"作单位比较合适。一支新铅笔是20 厘米左右，据此填上合适的数即可，答案不唯一，可以填 18 .\n【详解】课桌高约75厘米;一支新铅笔大约长18厘米。",
+    "knowledge_points": [
+      "长度单位的选择",
+      "厘米的认识"
+    ],
+    "source": "24-25 二年级上·广东东莞·期中"
+  },
+  {
+    "id": "352",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "下图纸条的长度是()厘米.\n\n![](images/8d2eaedff253ea66093000cce8d962a20551810ed7a0914f3a3475ff9fa2b748.jpg)",
+    "options": [],
+    "answer": "6",
+    "solution": "【分析】当0刻度不对齐时，用末端刻度值减去开始刻度值.\n【详解】13 - 7 = 6(厘米)。",
+    "knowledge_points": [
+      "长度的测量方法"
+    ],
+    "source": "24-25 二年级上·福建莆田·期中"
+  },
+  {
+    "id": "353",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "在括号里填上合适的长度单位.\n\n一棵银杏树高约 4( );一个枕头长约 45( )\n\n教室门高 200( );篮球场上篮筐高约 3( )",
+    "options": [],
+    "answer": "米或m;厘米或cm;厘米或cm;米或m",
+    "solution": "【分析】根据生活经验及数据大小选择合适单位.\n【详解】银杏树高约4米;枕头长约45厘米;教室门高200厘米;篮筐高约3米。",
+    "knowledge_points": [
+      "长度单位的选择",
+      "米的认识",
+      "厘米的认识"
+    ],
+    "source": "24-25 二年级上·福建福州·期中"
+  },
+  {
+    "id": "354",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "在括号里填上合适的长度单位.\n\n![](images/d0786f80c72fbe2baa5e028a94e4b551542cfbfe823b9e1a3850d24753fea409.jpg)\n\n![](images/d1a25673b3a60888ac449d1a7b7721fe5a787de4df8463104c31e286476117f5.jpg)\n\n![](images/8a0bb5c27541d2050d6943bb0aeea5c3e89bb9cbef683e3a8e657faf1b993d14.jpg)\n\n电视机长 70( );小明身高 1( )30( );小汽车约长3( )",
+    "options": [],
+    "answer": "厘米或cm;米或m;厘米或cm;米或m",
+    "solution": "【分析】电视机长度较短用厘米;身高用米和厘米;小汽车较长用米.\n【详解】电视机长70厘米;小明身高1米30厘米;小汽车约长3米。",
+    "knowledge_points": [
+      "长度单位的选择",
+      "米的认识",
+      "厘米的认识"
+    ],
+    "source": "23-24 二年级上·湖北孝感·期中"
+  },
+  {
+    "id": "355",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "35 厘米+27 厘米=( )厘米;1 米-30 厘米=( )厘米",
+    "options": [],
+    "answer": "62;70",
+    "solution": "【分析】单位相同直接计算;1米先换算成100厘米.\n【详解】35+27=62厘米;100-30=70厘米。",
+    "knowledge_points": [
+      "厘米和米之间的进率与换算"
+    ],
+    "source": "24-25 二年级上·河北沧州·期中"
+  },
+  {
+    "id": "356",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "在括号里填上合适的数.\n\n1 米=( )厘米;400 厘米=( )米\n\n35 厘米+65 厘米=( )米;100 厘米+2 米=( )米",
+    "options": [],
+    "answer": "100;4;1;3",
+    "solution": "【分析】利用1米=100厘米换算单位后计算.\n【详解】1米=100厘米;400厘米=4米;35+65=100厘米=1米;100厘米+2米=1米+2米=3米。",
+    "knowledge_points": [
+      "厘米和米之间的进率与换算"
+    ],
+    "source": "24-25 二年级上·福建福州·期中"
+  },
+  {
+    "id": "357",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "32厘米 - 8厘米 = ( )厘米;1米 - 30厘米 = ( )厘米;1米 + 200厘米 = ( )米;1米5厘米 + 3米 = ( )米( )厘米",
+    "options": [],
+    "answer": "24;70;3;4;5",
+    "solution": "【分析】先统一单位再计算,1米 = 100厘米.\n【详解】32 - 8 = 24厘米;100 - 30 = 70厘米;1米 + 200厘米 = 1米 + 2米 = 3米;1米5厘米 + 3米 = 4米5厘米。",
+    "knowledge_points": [
+      "厘米和米之间的进率与换算"
+    ],
+    "source": "24-25 二年级上·广东东莞·期中"
+  },
+  {
+    "id": "358",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "在括号里填上\"米\"或\"厘米\"或数据.\n\n(1)教室的门高 2( )。 (2)一本字典的厚度约为 6( ).\n\n(3)黑板的长约 4( )。 (4)一支铅笔的长度约为 18( )。 (5)下边的铅笔大约长( )厘米.\n\n![](images/9776893ea8fe8f44eda2147ea9802bd173a185c7ba6fcb013323409e370085ec.jpg)",
+    "options": [],
+    "answer": "米或m;厘米或cm;米或m;厘米或cm;8",
+    "solution": "【分析】较长用米，较短用厘米;测量图形中铅笔的长度，用末端刻度减去起始刻度.\n【详解】(1)米;(2)厘米;(3)米;(4)厘米;(5)10 - 2 = 8(厘米)。",
+    "knowledge_points": [
+      "长度单位的选择",
+      "长度的测量方法",
+      "米的认识",
+      "厘米的认识"
+    ],
+    "source": "23-24 二年级上·山东临沂·期中"
+  },
+  {
+    "id": "359",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "小方用一把20厘米的尺子量一条彩带的长度，量了5次，正好量完。这条彩带长( )厘米，也就是( )米。",
+    "options": [],
+    "answer": "100;1",
+    "solution": "【分析】每次量20厘米，量5次，总长为20×5=100厘米，换算成米.\n【详解】20+20+20+20+20=100厘米=1米。",
+    "knowledge_points": [
+      "厘米和米之间的进率与换算"
+    ],
+    "source": "24-25 二年级上·北京平谷·期中"
+  },
+  {
+    "id": "360",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "填上合适的长度单位.\n\n一本字典厚大约 5( )。小丽的身高是 1( )26( )。",
+    "options": [],
+    "answer": "厘米或cm;米或m;厘米或cm",
+    "solution": "【分析】字典厚度较小用厘米;身高用米和厘米.\n【详解】5厘米;1米26厘米。",
+    "knowledge_points": [
+      "长度单位的选择",
+      "米的认识",
+      "厘米的认识"
+    ],
+    "source": "24-25 二年级上·北京平谷·期中"
+  },
+  {
+    "id": "361",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "在括号填上合适的长度单位.\n\n一块橡皮的长度是 5( );小明弟弟的身高是 100()\n\n一棵大树高 15( );我的鞋子长约 20( )",
+    "options": [],
+    "answer": "厘米或cm;厘米或cm;米或m;厘米或cm",
+    "solution": "【分析】橡皮，身高100，鞋子较短用厘米;大树较高用米.\n【详解】5厘米;100厘米;15米;20厘米。",
+    "knowledge_points": [
+      "长度单位的选择",
+      "米的认识",
+      "厘米的认识"
+    ],
+    "source": "24-25 二年级上·河北沧州·期中"
+  },
+  {
+    "id": "362",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "填上合适的长度单位.\n\n一块橡皮长约 3( );文具盒长约 20( )\n\n一根旗杆高约 12( );自行车高约 1( )",
+    "options": [],
+    "answer": "厘米或cm;厘米或cm;米或m;米或m",
+    "solution": "【分析】根据生活经验选择单位.\n【详解】3厘米;20厘米;12米;1米。",
+    "knowledge_points": [
+      "长度单位的选择",
+      "米的认识",
+      "厘米的认识"
+    ],
+    "source": "24-25 二年级上·湖北襄阳·期中"
+  },
+  {
+    "id": "363",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "在括号里填上合适的长度单位.\n\n妈妈的鞋长 24( )。 一根跳绳长 1( )。",
+    "options": [],
+    "answer": "厘米或cm;米或m",
+    "solution": "【分析】鞋子长度较短用厘米;跳绳较长用米.\n【详解】24厘米;1米。",
+    "knowledge_points": [
+      "长度单位的选择"
+    ],
+    "source": "24-25 二年级上·河北保定·期中"
+  },
+  {
+    "id": "364",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "100 厘米-80 厘米=( )厘米;1 米-40 厘米=( )厘米",
+    "options": [],
+    "answer": "20;60",
+    "solution": "【分析】单位相同直接减;1米先换算成100厘米.\n【详解】100-80=20厘米;100-40=60厘米。",
+    "knowledge_points": [
+      "厘米和米之间的进率与换算"
+    ],
+    "source": "24-25 二年级上·河北保定·期中"
+  },
+  {
+    "id": "365",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "1 米里面有( )个 1 厘米，食指的宽大约是 1( )。",
+    "options": [],
+    "answer": "100;厘米或cm",
+    "solution": "【分析】1米=100厘米，所以1米里面有100个1厘米;食指宽约1厘米.\n【详解】100;厘米。",
+    "knowledge_points": [
+      "厘米和米之间的进率与换算",
+      "长度单位的选择"
+    ],
+    "source": "24-25 二年级上·内蒙古鄂尔多斯·期中"
+  },
+  {
+    "id": "366",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "100 厘米=( )米;30 米+6 米=( )米;74 厘米+26 厘米=( )米;1 米-20 厘米=( )厘米",
+    "options": [],
+    "answer": "1;36;1;80",
+    "solution": "【分析】利用1米=100厘米，统一单位后计算.\n【详解】100厘米=1米;30+6=36米;74+26=100厘米=1米;100-20=80厘米。",
+    "knowledge_points": [
+      "厘米和米之间的进率与换算"
+    ],
+    "source": "22-23 二年级上·浙江绍兴·期中"
+  },
+  {
+    "id": "367",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "在( )里填上\"米\"或\"厘米\".\n\n笔记本长约 24( );一棵树高约 10( )\n\n操场长约 200( );铅笔长约 15( )",
+    "options": [],
+    "answer": "厘米或cm;米或m;米或m;厘米或cm",
+    "solution": "【分析】根据生活经验选择单位.\n【详解】24厘米;10米;200米;15厘米。",
+    "knowledge_points": [
+      "长度单位的选择"
+    ],
+    "source": "23-24 二年级上·湖南常德·期中"
+  },
+  {
+    "id": "368",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "在( )里填上\"厘米\"或\"米\".\n\n数学课本封面长 26( );一棵树高 15( )\n\n一块橡皮长 3( );爸爸的身高 1( )70( )",
+    "options": [],
+    "answer": "厘米或cm;米或m;厘米或cm;米或m;厘米或cm",
+    "solution": "【分析】较短用厘米，较长用米，身高用米和厘米.\n【详解】26厘米;15米;3厘米;1米70厘米。",
+    "knowledge_points": [
+      "长度单位的选择",
+      "米的认识",
+      "厘米的认识"
+    ],
+    "source": "24-25 二年级上·云南红河·期中"
+  },
+  {
+    "id": "369",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "![](images/7ad5be6fe76e93dc6db95f3e0ff91ed5b07299349fbdf3ab9dc353f3b749d4f5.jpg)\n\n![](images/dc55ef8c26763baff5ce31c9c6852e98a8328ead36765518c8d87fa1d351720c.jpg)\n\n铅笔长( )厘米;纸条长( )厘米",
+    "options": [],
+    "answer": "8;5",
+    "solution": "【分析】尺子测量时0刻度对齐物体一端;若不对齐，用末端刻度减起始刻度.\n【详解】铅笔长8厘米;6-1=5厘米，纸条长5厘米。",
+    "knowledge_points": [
+      "长度的测量方法",
+      "厘米的认识"
+    ],
+    "source": "24-25 二年级上·云南红河·期中"
+  },
+  {
+    "id": "370",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "在括号里填上\"厘米\"或\"米\".\n\n铅笔长约 15( );课桌高约 70( )\n中央电视塔高 405( );我的身高是 1( )20( )。",
+    "options": [],
+    "answer": "厘米或cm;厘米或cm;米或m;米或m;厘米或cm",
+    "solution": "【分析】长度单位:1 米(m)大约为小学生双臂伸展开的长度;1 厘米(cm)大约为指甲盖的宽度。根据生活经验和实际数据相结合，计量铅笔的长度应该用\"厘米\"作单位;计量课桌的高度应该用\"厘米\"作单位;计量中央电视塔的高度应该用\"米\"作单位;1 米 = 100 厘米，我的身高应该是 1 米 20 厘米.\n【详解】铅笔长约15厘米;课桌高约 70 厘米;中央电视塔高405米;我的身高是1米20厘米",
+    "knowledge_points": [
+      "厘米和米之间的进率与换算",
+      "长度单位的选择",
+      "米的认识",
+      "厘米的认识"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "371",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "昆虫王国举办跳远比赛，蚂蚱从直尺的刻度 0 跳到了刻度 5，蟋蟀从直尺的刻度 7 跳到刻度 9，比赛结果是( )胜利。",
+    "options": [],
+    "answer": "蚂蚱",
+    "solution": "【分析】尺子测量物体时应将0刻度移动到被测物体的边缘，将直尺与被测物体重合，再观察被测物体另一端的刻度即可。当0刻度与被测物体的边缘不对齐时，用末端的刻度值减去开始的刻度值即可。算出它们分别跳了多远，然后比较，谁跳得远谁就胜利.\n【详解】5 - 0 = 5(厘米),9 - 7 = 2(厘米),5>2，赛结果是蚂蚱胜利。",
+    "knowledge_points": [
+      "长度的测量方法",
+      "5以内数的比大小"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "372",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "量较短的物体，用()作单位，量比较长的物体或距离，通常用( )作单位。",
+    "options": [],
+    "answer": "厘米或cm;米或m",
+    "solution": "【分析】大拇指的指甲长度大约1厘米，小学生两臂伸开的长度大约 1 米，据此解答.\n【详解】量较短的物体，用厘米作单位，量比较长的物体或距离，通常用米作单位。",
+    "knowledge_points": [
+      "米的认识",
+      "厘米的认识"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "373",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "填上合适的长度单位\"厘米\"或\"米\".\n\n课桌高约 70( );学校旗杆高约 12( )\n床长约 2( );亚运火炬长 73( )",
+    "options": [],
+    "answer": "厘米或cm;米或m;米或m;厘米或cm",
+    "solution": "【分析】长度单位:1米(m)大约为小学生双臂伸展开的长度;1 厘米(cm)大约为指甲盖的宽度。根据生活经验和实际数据相结合，计量课桌的高度应该用\"厘米\"作单位;计量学校旗杆的高度应该用\"米\"作单位;计量床的长度应该用\"米\"作单位;计量亚运火炬的长度应该用\"厘米\"作单位.\n【详解】课桌高约 70 厘米;学校旗杆高约 12 米;床长约2米;亚运火炬长73厘米",
+    "knowledge_points": [
+      "长度单位的选择",
+      "米的认识",
+      "厘米的认识"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "374",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "青青测量铅笔时，从尺子刻度线的 5 开始量，量到刻度( ),最后知道铅笔长 9 厘米。",
+    "options": [],
+    "answer": "14",
+    "solution": "【分析】由\"被测物体的长度 = 测量结束刻度-测量起始刻度\"得\"测量结束刻度 = 测量起始刻度+被测物体的长度\";据此解决.\n【详解】5 + 9 = 14，即，青青测量铅笔时，从尺子刻度线的5开始量，量到刻度14，最后知道铅笔长9厘米。",
+    "knowledge_points": [
+      "长度的测量方法"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "375",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "填写合适的长度单位.\n\n回形针的长约 3( );一张床长是 2( )\n一根旗杆高是 13( );妈妈的身高是 1( )62( )",
+    "options": [],
+    "answer": "厘米或cm;米或m;米或m;米或m;厘米或cm",
+    "solution": "【分析】根据生活经验，对长度单位和数据大小的认识可知：量比较短的物体的长度，通常用厘米作单位，食指的宽大约是 1 厘米，所以计量回形针的长度用厘米作单位比较合适;测量较长的物体用米作单位，二年级学生双臂伸开的长度大约是 1 米，所以计量床的长度，旗杆的高度用米作单位比较合适;妈妈的身高应写作 1 米 62 厘米.\n【详解】回形针的长约 3 厘米;一张床长是 2 米;一根旗杆高是 13 米;妈妈的身高是 1 米 62 厘米",
+    "knowledge_points": [
+      "长度单位的选择",
+      "米的认识",
+      "厘米的认识"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "376",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "小乐身高 70 厘米，再长()厘米就是 1 米，因为 1 米=( )厘米。",
+    "options": [],
+    "answer": "30;100",
+    "solution": "【分析】根据1米 = 100厘米，先把1米换算成100厘米，再用需要的总长度减去小乐的身高，即可求出再长多少厘米.\n【详解】1米 = 100厘米,100厘米 - 70厘米 = 30厘米，则小乐身高70厘米，再长30厘米就是1米，因为1米 = 100厘米。",
+    "knowledge_points": [
+      "整十数之间的加减法",
+      "厘米和米之间的进率与换算"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "377",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "填上合适的长度单位\"厘米\"或\"米\".\n\n旗杆高度约 13( );我走一步的距离约 40 ( )\n课桌的高度约 70( );小朋友身高 1( )40( )",
+    "options": [],
+    "answer": "米或m;厘米或cm;厘米或cm;米或m;厘米或cm",
+    "solution": "【分析】大拇指的指甲长度大约1厘米，计量走一步的距离和课桌的高度用\"厘米\"作单位比较合适。小学生两臂伸开的长度大约1米，计量旗杆的高度用\"米\"作单位比较合适。1 米 = 100 厘米。小朋友的身高一般是一百多厘米，也就是1 米几十厘米.\n【详解】旗杆高度约 13 米;我走一步的距离约 40 厘米;课桌的高度约 70 厘米;小朋友身高 1 米 40 厘米。",
+    "knowledge_points": [
+      "长度单位的选择",
+      "米的认识",
+      "厘米的认识"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "378",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "在( )里填上\"米\"或\"厘米\".\n\n一根跳绳长约 2( );小明身高 135( )\n\n一棵大树高约 18( );一本字典厚约 5( )",
+    "options": [],
+    "answer": "米或m;厘米或cm;米或m;厘米或cm",
+    "solution": "【分析】根据生活经验以及对长度单位和数据大小的认识，结合实际情况选择合适的单位即可二年级学生的双臂展开约为1米，则计量绳长，树的高度用\"米\"作单位;食指的宽度约为1厘米，计量小明的身高，字典的厚度用\"厘米\"作单位.\n【详解】一根跳绳长约2(米);小明身高135(厘米);一棵大树高约 18(米);一本字典厚约 5(厘米)",
+    "knowledge_points": [
+      "长度单位的选择",
+      "米的认识",
+      "厘米的认识"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "379",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "在括号里填上\"米\"或\"厘米\".\n\n教室高约 3( );黑板长 3( )60( )\n\n老师的茶杯高 20( );一支铅笔长 18( )",
+    "options": [],
+    "answer": "米或m;米或m;厘米或cm;厘米或cm;厘米或cm",
+    "solution": "【分析】大拇指的指甲长度大约1厘米，计量茶杯的高度和铅笔的长度用\"厘米\"作单位比较合适。小学生两臂伸开的长度大约 1 米，计量教室的长度用\"米\"作单位比较合适。1 米 = 100 厘米，黑板一般3到4米长，应该是几米几十厘米.\n【详解】教室高约3米;黑板长3米60厘米;老师的茶杯高 20 厘米;一支铅笔长 18 厘米。",
+    "knowledge_points": [
+      "长度单位的选择",
+      "米的认识",
+      "厘米的认识"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "380",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "在括号里填上合适的单位.\n\n(1)篮球场长约 45( )。 (2)爸爸身高 1( )80( )。",
+    "options": [],
+    "answer": "米或m;米或m;厘米或cm",
+    "solution": "【分析】(1)小学生两臂伸开的长度大约 1 米，计量篮球场的长用\"米\"作单位比较合适。(2)大拇指的指甲长度大约1厘米，成年人的身高一般是一百多厘米,100 厘米 = 1 米，也就是1米几十厘米.\n【详解】(1)篮球场长约45米。(2)爸爸身高1米80厘米。",
+    "knowledge_points": [
+      "长度单位的选择",
+      "米的认识",
+      "厘米的认识"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "381",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "在括号里填上合适的长度单位.\n\n旗杆高约 8( );成人手臂长约 100( )",
+    "options": [],
+    "answer": "米或m;厘米或cm",
+    "solution": "【分析】长度单位:1米(m)大约为小学生双臂伸展开的长度;1厘米(cm)大约为指甲盖的宽度。根据生活经验和实际数据相结合，计量旗杆的高度应该用\"米\"作单位;计量成人手臂的长度应该用\"厘米\"作单位.\n【详解】由分析可得，旗杆高约8米，成人手臂长约100厘米。",
+    "knowledge_points": [
+      "长度单位的选择",
+      "米的认识",
+      "厘米的认识"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "382",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "在括号里填上\"厘米\"或\"米\".\n\n(1)书桌宽 60( )。 (2)小汽车长 5( ).\n(3)苹果树高 4( )。 (4)筷子长 25( )。",
+    "options": [],
+    "answer": "厘米或cm;米或m;米或m;厘米或cm",
+    "solution": "【分析】根据生活经验，对长度单位和数据大小的认识可知，大拇指的指甲长度大约1厘米，计量书桌的宽度和筷子的长度用\"厘米\"作单位比较合适。小学生两臂伸开的长度大约1米，计量小汽车的长度和苹果树的高度用\"米\"作单位比较合适.\n【详解】(1)书桌宽60厘米。(2)小汽车长5米。(3)苹果树高4米。(4)筷子长 25 厘米。",
+    "knowledge_points": [
+      "长度单位的选择",
+      "米的认识",
+      "厘米的认识"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "383",
+    "unit": "第一单元 长度单位",
+    "question_type": "排序题",
+    "difficulty": 0.65,
+    "question": "把下面的数用\"<\"连接起来.\n\n100 厘米;3 米;50 厘米;5 米;1 米 20 厘米\n\n( )<( )<( )<( )<( )。",
+    "options": [],
+    "answer": "50 厘米;100 厘米;1 米 20 厘米;3 米;5 米",
+    "solution": "【分析】根据题意，同单位的根据整数比较大小的方法直接比较长短，不同单位的根据1米 = 100厘米统一单位再比较.\n【详解】50厘米 < 100厘米;100厘米 = 1米;1米20厘米 = 120厘米;3米 = 300厘米;5米 = 500厘米。所以 50厘米 < 100厘米 < 1米20厘米 < 3米 < 5米。",
+    "knowledge_points": [
+      "厘米和米之间的进率与换算"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "384",
+    "unit": "第一单元 长度单位",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "一间教室长约 9 厘米。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】根据经验，数据大小可知：计量较长的物体，用\"米\"作单位，学生的双臂展开约为1米。计量较短的物体，用\"厘米\"作单位，食指的宽度约为1厘米。则计量教室的长度用\"米\"作单位比较合适.\n【详解】由分析可得：一间教室长约9米，原题说法错误。故答案为: ×",
+    "knowledge_points": [
+      "长度单位的选择",
+      "米的认识",
+      "厘米的认识"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "385",
+    "unit": "第一单元 长度单位",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "一枚图钉的长度大约 是 1 厘米。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】大拇指的指甲长度大约1厘米，计量图钉的长度用\"厘米\"作单位比较合适.\n【详解】一枚图钉的长度大约是1厘米。原题说法正确。故答案为:√",
+    "knowledge_points": [
+      "厘米的认识"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "386",
+    "unit": "第一单元 长度单位",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "一支粉笔长约 90 厘米。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】根据经验，数据大小可知：计量较长的物体，用\"米\"作单位，学生的双臂展开约为1米。计量较短的物体，用\"厘米\"作单位，食指的宽度约为1厘米。则计量一支粉笔长用厘米比较合适。1 米 = 100 厘米\n【详解】由分析可得：一支粉笔长约9厘米，则原题说法错误。故答案为: ×",
+    "knowledge_points": [
+      "长度单位的选择",
+      "厘米的认识"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "387",
+    "unit": "第一单元 长度单位",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "奶奶给小明买了一条毛巾，这条毛巾长 60 厘米。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】根据生活经验，以及对长度单位和数据大小的认识，可知：测量比较短的物体的长度，可以用厘米作单位，食指的指甲盖的长度约是1厘米长，所以计量这条毛巾的长度用\"厘米\"作单位比较合适;据此判断即可.\n【详解】结合生活实际可知，奶奶给小明买了一条毛巾，这条毛巾长 60 厘米，所以原题说法正确。故答案为:√",
+    "knowledge_points": [
+      "长度单位的选择",
+      "厘米的认识"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "388",
+    "unit": "第一单元 长度单位",
+    "question_type": "判断题",
+    "difficulty": 0.65,
+    "question": "二年级数学书的宽 大约是 1 拃，教室的黑板长大约是 1 庹。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】拃长：张开大姆指和中指(或小指)量长度，约 8厘米;庹长：以成人两臂左右伸直的长度为标准，约1米;由此结合实际解答即可.\n【详解】据分析可知：二年级数学书的宽大约是2拃，教室的黑板长大约是3庹。原题说法错误。故答案为: ×",
+    "knowledge_points": [
+      "\"身体尺\"的认识及应用",
+      "长度的估测"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "389",
+    "unit": "第一单元 长度单位",
+    "question_type": "判断题",
+    "difficulty": 0.65,
+    "question": "1 米长的绳子和 100厘米长的丝带一样长。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】将单位统一后再作比较,1米 = 100 厘米，据此解答.\n【详解】1 米 = 100 厘米,1 米长的绳子和 100 厘米长的丝带一样长。原题说法正确。故答案为:√",
+    "knowledge_points": [
+      "厘米和米之间的进率与换算"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "390",
+    "unit": "第一单元 长度单位",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "小学生读书写字时，眼离书本约 30 厘米，手离笔尖约 3 厘米。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】根据生活经验，对长度单位和数据大小的认识可知：量比较短的物体的长度，通常用厘米作单位，食指的宽大约是1厘米。眼睛距离书本大约30厘米，手离笔尖大约3厘米，由此解答.\n【详解】小学生读书写字时，眼离书本约30厘米，手离笔尖约3厘米。原题说法正确。故答案为:√",
+    "knowledge_points": [
+      "长度的估测",
+      "厘米的认识"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "391",
+    "unit": "第一单元 长度单位",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "拉紧的一段线可以看成一条线段。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】线段两端都有端点，不可延长，两个端点间的线条是直的，据此解答.\n【详解】拉紧的一段线两端都有端点，两个端点间的线条是直的，所以拉紧的一段线可以看成一条线段。原题说法正确。故答案为:√",
+    "knowledge_points": [
+      "线段的初步认识"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "392",
+    "unit": "第一单元 长度单位",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "橡皮的长是 3 米。()",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】根据生活经验，对长度单位和数据大小的认识可知：测量较长的物体用米作单位，二年级学生双臂展开的长度大约是 1 米，量比较短的物体的长度，通常用厘米作单位，食指的宽大约是1厘米，橡皮的长度较短，用厘米作单位比较合适.\n【详解】由分析可知，橡皮的长是3厘米，原题说法错误。故答案为: ×",
+    "knowledge_points": [
+      "长度单位的选择",
+      "米的认识",
+      "厘米的认识"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "393",
+    "unit": "第一单元 长度单位",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "一幢楼房高约 18 米。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】根据生活经验，对长度单位和数据大小的认识可知：测量较长的物体用米作单位，二年级学生双臂展开的长度大约是1米，由此判断18米是否符合楼房的高度即可.\n【详解】由分析可知，楼房的高度较高，一幢楼房高约18米，原题说法正确。故答案为:√",
+    "knowledge_points": [
+      "米的认识",
+      "长度的估测"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "394",
+    "unit": "第一单元 长度单位",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "数学课本长约 25 厘米。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】根据生活经验，对长度单位和数据大小的认识可知：量比较短的物体的长度，通常用厘米作单位，食指的宽大约是1厘米，数学课本长度大约是25厘米，由此解答.\n【详解】由分析可知，数学课本长约25厘米。原题说法正确。故答案为:√",
+    "knowledge_points": [
+      "长度的估测",
+      "厘米的认识"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "395",
+    "unit": "第一单元 长度单位",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "小红用尺子画线段时，从刻度\"3\"画到刻度\"8\"，她画的这条线段长5厘米。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】根据用直尺测量长度的方法，用末端刻度减去起始刻度即可求出线段长度。据此解答即可.\n【详解】8 - 3 = 5(厘米),所以从刻度\"3\"画到刻度\"8\"，她画的这条线段长5厘米。原题说法正确。故答案为:√",
+    "knowledge_points": [
+      "长度的测量方法"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "396",
+    "unit": "第一单元 长度单位",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "![](images/2026-02-05%20170310.jpg) 左图是由3 条线段围成的。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】线段有两个端点，中间是直直的线，长度可测量，由此数出线段的数量即可。![](images/22d1320d96d0ff0b2e4f603aa61076724fb8f7eb5ffbcbd47ff2c95ae54264ae.jpg)\n【详解】该图是由3条线段围成的。原题说法正确。故答案为:√",
+    "knowledge_points": [
+      "线段的初步认识"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "397",
+    "unit": "第一单元 长度单位",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "1 米长的绳子和 100厘米长的线段一样长。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】根据1米 = 100厘米，把单位统一后再比较即可.\n【详解】1米 = 100厘米，所以1米长的绳子和100厘米长的线段一样长。原题说法正确。故答案为:√",
+    "knowledge_points": [
+      "厘米和米之间的进率与换算"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "398",
+    "unit": "第一单元 长度单位",
+    "question_type": "解答题",
+    "difficulty": 0.85,
+    "question": "赛道全长 1 米，蜗牛已经爬了 70 厘米，还剩多少厘米到达终点。",
+    "options": [],
+    "answer": "30厘米",
+    "solution": "【分析】求还剩多少厘米到终点，也就是求还没爬的长度是多少，用减法计算，即赛道的全长减去已经爬了的长度。根据1米 = 100厘米换算单位再计算.\n【详解】1米 = 100厘米,100 - 70 = 30(厘米),答：还剩30厘米到达终点。",
+    "knowledge_points": [
+      "整十数之间的加减法",
+      "厘米和米之间的进率与换算"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "399",
+    "unit": "第一单元 长度单位",
+    "question_type": "解答题",
+    "difficulty": 0.4,
+    "question": "西瓜虫，小蜗牛和小蟋蟀的家在同一条直线上，西瓜虫家距离小蜗牛家有50厘米，距离小蟋蟀家有30厘米，那么小蜗牛家与小蟋蟀家的距离是多少厘米呢。",
+    "options": [],
+    "answer": "80厘米或20厘米",
+    "solution": "【分析】当小蜗牛家与小蟋蟀家在西瓜虫家的两边时，用西瓜虫家距离小蜗牛家的距离加上西瓜虫家距离小蟋蟀家的距离即可。当小蜗牛家与小蟋蟀家在西瓜虫家的同一边时，用较大距离减去较小距离即可。关键是分清这两种情况，然后分别计算.\n【详解】30 + 50 = 80(厘米),50 - 30 = 20(厘米),答：小蜗牛家与小蟋蟀家的距离是80厘米或20厘米。",
+    "knowledge_points": [
+      "厘米的认识"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "400",
+    "unit": "第一单元 长度单位",
+    "question_type": "解答题",
+    "difficulty": 0.65,
+    "question": "有一把磨损严重的直尺，上面的大部分刻度都看不清了，能看清的只有4个刻度(如下图)。用这把直尺能直接测量出哪几种不同的长度。\n\n![](images/7e885baa9fcf9490088c78fd201a1ee0350362f66826abf8db72f2c01d1d985f.jpg)",
+    "options": [],
+    "answer": "6 种",
+    "solution": "【分析】直尺上能看清的刻度有4个，任选两个刻度就可以直接测量一种长度。从左到右，以0刻度为起点可以测量出1厘米,4厘米,10厘米这3种长度;以1厘米为起点可以测量出3厘米,9厘米这2种长度;以4厘米为起点可以测量出6厘米，所以能直接测量出6种不同的长度.\n【详解】由分析可知：直尺上的刻度有0厘米,1厘米,4厘米,10厘米，所以能直接测量出1厘米,4厘米,10厘米。4 - 1 = 3(厘米),10 - 1 = 9(厘米),10 - 4 = 6(厘米),分别测量出1厘米,3厘米,4厘米,6厘米,9厘米,10厘米，共6种不同的长度。答：用这把直尺能直接测量出6种不同的长度。",
+    "knowledge_points": [
+      "长度的测量方法",
+      "厘米的认识"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "401",
+    "unit": "第一单元 长度单位",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "一个 ![](images/2026-02-06%20123914.jpg) 中有( )条线段。",
+    "options": [
+      "A. 8",
+      "B. 12",
+      "C. 6"
+    ],
+    "answer": "B",
+    "solution": "【分析】根据线段的含义：线段有2个端点，有限长，可以度量，数出线段的数量即可.\n【详解】数出该图中有 12 条线段。故答案为:B",
+    "knowledge_points": [
+      "线段的初步认识",
+      "数一数"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "402",
+    "unit": "第一单元 长度单位",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "你的椅子大约高( )。",
+    "options": [
+      "A. 4 米 5 厘米",
+      "B. 45厘米",
+      "C. 45 米"
+    ],
+    "answer": "B",
+    "solution": "【分析】根据实际生活经验以及具体数据来进行填空。计量较短的物体一般用厘米作单位，食指的宽度约为1厘米。则计量椅子的高度用\"厘米\"作单位。计量较长的物体一般用米作单位，二年级学生的双臂打开约1米.\n【详解】你的椅子大约高45厘米。故答案为:B",
+    "knowledge_points": [
+      "长度单位的选择",
+      "米的认识",
+      "厘米的认识"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "403",
+    "unit": "第一单元 长度单位",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "要量数学课本的宽，用( )作单位比较合适。",
+    "options": [
+      "A. 米",
+      "B. 厘米",
+      "C. 以上都可以"
+    ],
+    "answer": "B",
+    "solution": "【分析】大拇指的指甲长度大约1厘米。根据生活经验以及对长度单位的认识，结合实际情况可知，要量数学课本的宽，用\"厘米\"作单位比较合适.\n【详解】由分析可知，要量数学课本的宽，用\"厘米\"作单位比较合适。故答案为:B",
+    "knowledge_points": [
+      "长度单位的选择",
+      "米的认识",
+      "厘米的认识"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "404",
+    "unit": "第一单元 长度单位",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "三条彩带，黄色的长 2 米，绿色的长170厘米，紫色的长1米90厘米,( )的彩带最短。",
+    "options": [
+      "A. 黄色",
+      "B. 绿色",
+      "C. 紫色"
+    ],
+    "answer": "B",
+    "solution": "【分析】根据 1 米 = 100 厘米统一单位再比较。2 米 = 200 厘米,1 米 90 厘米 = 190 厘米，再比较 200 厘米,190 厘米,170 厘米的大小即可.\n【详解】200厘米>190厘米>170厘米，则2米>1米90 厘米>170 厘米。也就是绿色的彩带最短。故答案为:B",
+    "knowledge_points": [
+      "厘米和米之间的进率与换算"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "405",
+    "unit": "第一单元 长度单位",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "教室的长度约为9( )。",
+    "options": [
+      "A. 厘米",
+      "B. 米",
+      "C. 时"
+    ],
+    "answer": "B",
+    "solution": "【分析】长度单位:1米(m)大约为小学生双臂伸展开的长度;1 厘米(cm)大约为指甲盖的宽度。根据生活经验和实际数据相结合，计量教室的长度应该用\"米\"作单位.\n【详解】由分析可得，教室的长度约为 9 米。故答案为:B",
+    "knowledge_points": [
+      "长度单位的选择",
+      "米的认识",
+      "厘米的认识"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "406",
+    "unit": "第一单元 长度单位",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "过两个点能画( )条线段。",
+    "options": [
+      "A. 1",
+      "B. 2",
+      "C. 无数"
+    ],
+    "answer": "A",
+    "solution": "【分析】线段有两个端点，有限长，两点之间可以作一条线段.\n【详解】由分析可得：过两个点能画(1)条线段。故答案为:A",
+    "knowledge_points": [
+      "线段的初步认识"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "407",
+    "unit": "第一单元 长度单位",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "图中一共有( )条线段.\n\n![](images/2026-02-06%20124231.jpg)",
+    "options": [
+      "A. 3",
+      "B. 5",
+      "C. 6"
+    ],
+    "answer": "C",
+    "solution": "【分析】线段有两个端点，有限长，两点之间可以作一条线段。根据图片可知：从前往后数：一共有3条短的线段，前两条组成一条较长的线段，后面两条短的组成 1 条较长的线段,3条短线段组成一条长线段。分别把这个几条相加求出共有的即可.\n【详解】3 + 1 + 1 + 1 = 4 + 1 + 1 = 5 + 1 = 6(条),所以一共有 6 条线段。故答案为:C",
+    "knowledge_points": [
+      "线段的初步认识",
+      "数图形(线段，直线，射线)"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "408",
+    "unit": "第一单元 长度单位",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "黑板长( )厘米。",
+    "options": [
+      "A. 300",
+      "B. 30",
+      "C. 3"
+    ],
+    "answer": "A",
+    "solution": "【分析】联系生活实际，结合长度单位和数据的大小可知，米尺的长度是1米，故黑板长3米比较合适,3米也就是300厘米;据此解答.\n【详解】300厘米 = 3 米，黑板长约3米符合生活实际。故答案为:A",
+    "knowledge_points": [
+      "厘米和米之间的进率与换算",
+      "长度的估测"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "409",
+    "unit": "第一单元 长度单位",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面是线段的是()。",
+    "options": [
+      "A. ![](images/4ac18daf585ad47590894de7f00f7355771d4c66396827fb5e8cbad2754b44ce.jpg)",
+      "B. ![](images/2241e5542bfe684940be23e713e49c4da1f6fad752467ff74f3d13984dc94d91.jpg)",
+      "C. ![](images/98d8c3ea27bcd6ad489f34be8a2361cb328d7c425dc7f02c58c0cc4b09fa9c54.jpg)"
+    ],
+    "answer": "A",
+    "solution": "【分析】线段是直的，有两个端点.\n【详解】A 是线段;B 只有一个端点且不是直的;C 有两个端点但不是直的。故答案为:A",
+    "knowledge_points": [
+      "线段的初步认识",
+      "线段，直线，射线的认识及特征"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "410",
+    "unit": "第一单元 长度单位",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "一根绳子剪去 46 厘米，还剩 50 厘米，这根绳子原来长( )。",
+    "options": [
+      "A. 4 厘米",
+      "B. 86 厘米",
+      "C. 96 厘米"
+    ],
+    "answer": "C",
+    "solution": "【分析】根据加法的意义，剪去的长度加上还剩的长度，即可计算出这根绳子原来长多少厘米.\n【详解】46 + 50 = 96(厘米),这根绳子原来长96厘米。故答案为:C",
+    "knowledge_points": [
+      "厘米的认识"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "411",
+    "unit": "第一单元 长度单位",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "如图，铅笔的长度是( )厘米.\n\n![](images/250ef7df0af045af073624005437360d76992c11920a865c818e17785f2f4933.jpg)",
+    "options": [
+      "A. 7",
+      "B. 6",
+      "C. 5"
+    ],
+    "answer": "B",
+    "solution": "【分析】用直尺测量物体的长度时，将物体的左侧与直尺的0刻度线对齐，物体右侧与直尺所对应的刻度就是物体的长度;若测量时物体的左侧未与直尺的0刻度线对齐，则用测量结束的刻度 - 测量开始的刻度 = 物体的长度.\n【详解】7 - 1 = 6(厘米),铅笔的长度是6厘米。故答案为:B",
+    "knowledge_points": [
+      "长度的测量方法",
+      "厘米的认识"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "412",
+    "unit": "第一单元 长度单位",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下列选项中,( )是线段。",
+    "options": [
+      "A. ![](images/2026-02-06%20124659.jpg)",
+      "B. ![](images/2026-02-06%20124735.jpg)",
+      "C. ![](images/2026-02-06%20124757.jpg)"
+    ],
+    "answer": "B",
+    "solution": "【分析】线段有两个端点，中间是直直的线，长度可测量，由此解答.\n【详解】A,C 有两个端点但中间不是直线，不是线段;B 是线段。故答案为:B",
+    "knowledge_points": [
+      "线段的初步认识"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "413",
+    "unit": "第一单元 长度单位",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面物体中,( )的高度最接近 1 米。",
+    "options": [
+      "A. 高楼",
+      "B. 课桌",
+      "C. 铅笔"
+    ],
+    "answer": "B",
+    "solution": "【分析】根据生活经验，对长度单位和数据大小的认识可知：测量较长的物体用米作单位，二年级学生双臂展开的长度大约是1米，由此选择接近1米的即可.\n【详解】高楼远高于1米;课桌高度接近1米;铅笔长度远小于1米。故答案为:B",
+    "knowledge_points": [
+      "米的认识",
+      "长度的估测"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "414",
+    "unit": "第一单元 长度单位",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "铅笔的长度是( ).\n\n![](images/b94bb191bc3eda4fa82c719e52b88ca02389b8e475cffacf2696ffcd3b7e3536.jpg)",
+    "options": [
+      "A. 6厘米",
+      "B. 7 厘米",
+      "C. 8 厘米"
+    ],
+    "answer": "A",
+    "solution": "【分析】线段的长度 = 测量结束刻度 - 测量开始刻度;据此解答.\n【详解】7 - 1 = 6(厘米),铅笔长6厘米。故答案为:A",
+    "knowledge_points": [
+      "长度的测量方法",
+      "厘米的认识"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "415",
+    "unit": "第一单元 长度单位",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "有 90 厘米,9 厘米和 9 米三条绳子，最长的是( )的绳子。",
+    "options": [
+      "A. 9 米",
+      "B. 9 厘米",
+      "C. 90 厘米"
+    ],
+    "answer": "A",
+    "solution": "【分析】根据1米 = 100 厘米，将单位换算统一，然后再进行比较，最大的数即最长的.\n【详解】9米 = 900 厘米,900 厘米 > 90 厘米 > 9 厘米，所以最长的是9米的绳子。故答案为:A",
+    "knowledge_points": [
+      "厘米和米之间的进率与换算"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "416",
+    "unit": "第一单元 长度单位",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面测量方法正确的是( )。",
+    "options": [
+      "A. ![](images/1f7a93e260b03a0275362c685f37af318dae8282ea7f9e06e8d1e3b786f662bc.jpg)",
+      "B. ![](images/48a81eb01fca444efeae07313a4efd53359ce42bfabf6c8ad3f153807232776c.jpg)",
+      "C. ![](images/9841f034edf63b703e92b60b657de4706ecbc2f784e0ec5acc466cfdc7b0ea04.jpg)"
+    ],
+    "answer": "B",
+    "solution": "【分析】用直尺的\"0\"刻度线和物体的一个端点重合，另个端点在直尺上的刻度，就是该物体的长度;据此解答即可.\n【详解】A 物体一端在直尺测量区域外;C 直尺方向与物体不一致;B 的\"0\"刻度线与物体一端重合且方向一致，方法正确。故答案为:B",
+    "knowledge_points": [
+      "长度的测量方法"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "417",
+    "unit": "第一单元 长度单位",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "华华和同同用测量同一张纸条，华华用 5 拃量完，同同用 4 拃量完，两个人的\"一拃\"相比,( )。",
+    "options": [
+      "A. 华华的一拃长一些",
+      "B. 同同的一拃长一些",
+      "C. 两个人的一拃同样长"
+    ],
+    "answer": "B",
+    "solution": "【分析】测量同样的一张纸条，一个人量的\"拃数\"多，表示他的\"一拃\"短;拃数少，表示他的\"一拃\"长.\n【详解】华华用 5 拃量完，同同用 4 拃量完，华华拃数更多说明一拃更短，同同拃数更少说明一拃更长。故答案为:B",
+    "knowledge_points": [
+      "\"身体尺\"的认识及应用",
+      "长度的测量方法"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "418",
+    "unit": "第一单元 长度单位",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "两根一样长的绳子：第一根用去35厘米，第二根用去27厘米,( )绳子剩下的长。",
+    "options": [
+      "A. 第一根",
+      "B. 第二根",
+      "C. 无法确定"
+    ],
+    "answer": "B",
+    "solution": "【分析】两根绳子一样长，用去的长度越长，剩下的长度越短.\n【详解】35厘米 > 27厘米，第一根用去更多，剩下更短;第二根剩下更长。故答案为:B",
+    "knowledge_points": [
+      "100以内数的比大小"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "419",
+    "unit": "第一单元 长度单位",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "一颗大树高约 5()。",
+    "options": [
+      "A. 厘米",
+      "B. 米",
+      "C. 分米"
+    ],
+    "answer": "B",
+    "solution": "【分析】根据生活经验和数据选择合适的单位即可。一般计量较长的物体用\"米\"做单位.\n【详解】一颗大树高约5米。故答案为:B",
+    "knowledge_points": [
+      "长度单位的选择"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "420",
+    "unit": "第一单元 长度单位",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "小光参加了 50()的跑步比赛。",
+    "options": [
+      "A. 米",
+      "B. 厘米",
+      "C. 元"
+    ],
+    "answer": "A",
+    "solution": "【分析】根据生活经验，对长度单位，人民币单位和数据大小的认识判断。跑步比赛的路程应使用长度单位，且50米合理.\n【详解】50米适合跑步比赛;50厘米太短;元不是长度单位。故答案为:A",
+    "knowledge_points": [
+      "长度单位的选择",
+      "元，角，分的认识及换算"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "421",
+    "unit": "第一单元 长度单位",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "测量黑板的长度，一般用( )作为单位。",
+    "options": [
+      "A. 厘米",
+      "B. 米",
+      "C. 千克"
+    ],
+    "answer": "B",
+    "solution": "【分析】黑板长度较长，通常用\"米\"作单位更合适.\n【详解】测量黑板的长度，一般用\"米\"作为单位。故答案为:B",
+    "knowledge_points": [
+      "长度单位的选择",
+      "米的认识",
+      "厘米的认识"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "422",
+    "unit": "第一单元 长度单位",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "1 米 60 厘米可能是( )。",
+    "options": [
+      "A. 大树的高度",
+      "B. 吃饭桌的高度",
+      "C. 妈妈的高度"
+    ],
+    "answer": "C",
+    "solution": "【分析】1米60厘米接近成年人的身高;大树更高，餐桌更矮.\n【详解】大树高度约几米，餐桌约80厘米，妈妈身高约1米60厘米。故答案为:C",
+    "knowledge_points": [
+      "米的认识",
+      "长度的估测",
+      "厘米的认识"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "423",
+    "unit": "第一单元 长度单位",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面的线段长( ).\n\n![](images/23e31fad0fc6df05a7d32e6ef4c458e121667ccb691d424a53659b35c82a8c9a.jpg)",
+    "options": [
+      "A. 6 厘米",
+      "B. 4 厘米",
+      "C. 6 米"
+    ],
+    "answer": "B",
+    "solution": "【分析】物体长度 = 测量结束刻度 - 测量开始刻度.\n【详解】6 - 2 = 4(厘米),线段长4厘米。故答案为:B",
+    "knowledge_points": [
+      "长度的测量方法"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "424",
+    "unit": "第一单元 长度单位",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面物体的厚度，最接近 1 厘米的是( )。",
+    "options": [
+      "A. 一张写字纸",
+      "B. 一本语文书",
+      "C. 一本《新华字典》"
+    ],
+    "answer": "B",
+    "solution": "【分析】结合生活经验，写字纸很薄，字典较厚，语文书厚度更接近1厘米.\n【详解】最接近 1 厘米的是一本语文书。故答案为:B",
+    "knowledge_points": [
+      "长度的估测",
+      "厘米的认识"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "425",
+    "unit": "第一单元 长度单位",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "小明参加赛跑，他大约用1分钟跑了100( )。",
+    "options": [
+      "A. 元",
+      "B. 米",
+      "C. 厘米"
+    ],
+    "answer": "B",
+    "solution": "【分析】1分钟跑的是路程，路程应使用长度单位;100厘米太短，元不是长度单位.\n【详解】小明大约用1分钟跑了100米。故答案为:B",
+    "knowledge_points": [
+      "长度单位的选择",
+      "米的认识",
+      "厘米的认识"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "426",
+    "unit": "第一单元 长度单位",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面的线段长是().\n\n![](images/0620da6ca4e44ae38d3260e8bb4435e78536b49ae0d993d9d0553283bcb6e2ca.jpg)",
+    "options": [
+      "A. 6厘米",
+      "B. 4厘米",
+      "C. 2厘米",
+      "D. 4米"
+    ],
+    "answer": "B",
+    "solution": "【分析】线段的长度 = 测量结束刻度 - 测量起始刻度.\n【详解】6 - 2 = 4(厘米),线段长 4 厘米。故答案为:B",
+    "knowledge_points": [
+      "长度的测量方法"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "427",
+    "unit": "第一单元 长度单位",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "2 米的铁丝与 200 厘米的铁丝相比,( )。",
+    "options": [
+      "A. 200厘米的铁丝长",
+      "B. 2米的铁丝长",
+      "C. 一样长",
+      "D. 无法确定"
+    ],
+    "answer": "C",
+    "solution": "【分析】1 米 = 100 厘米，先统一单位再比较.\n【详解】2 米 = 200 厘米，所以一样长。故答案为:C",
+    "knowledge_points": [
+      "厘米和米之间的进率与换算"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "428",
+    "unit": "第一单元 长度单位",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "教室黑板的长大约是( )。",
+    "options": [
+      "A. 4米",
+      "B. 20厘米",
+      "C. 60厘米"
+    ],
+    "answer": "A",
+    "solution": "【分析】黑板长度较长，应以米为单位，结合实际约4米.\n【详解】教室黑板的长大约是 4 米。故答案为:A",
+    "knowledge_points": [
+      "长度单位的选择",
+      "米的认识"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "429",
+    "unit": "第一单元 长度单位",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面的图形中，第( )条是线段。",
+    "options": [
+      "A. ![](images/a60beff7e2569945eb1928c0b7304bd8f5770129b163de98364a65758ce42e7d.jpg)",
+      "B. ![](images/2026-02-06%20125648.jpg)",
+      "C. ![](images/210faa5ef27a57a18c579ba3e8ca8f4b7eec8babe148ceaf99f0d57d529eb0ea.jpg)"
+    ],
+    "answer": "B",
+    "solution": "【分析】线段是一条直直的线，有两个端点.\n【详解】A,C 为曲线不符合;B 是线段。故答案为:B",
+    "knowledge_points": [
+      "线段的初步认识"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "430",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "1 米=( )厘米;500 厘米=( )米;49 厘米 - 30 厘米=( )厘米;1 米 - 30 厘米=( )厘米",
+    "options": [],
+    "answer": "100;5;19;70",
+    "solution": "【分析】根据 1 米 = 100 厘米，将单位换算统一即可.\n【详解】1 米 =(100)厘米;500 厘米 =(5)米;49 厘米 - 30 厘米 =(19)厘米;1 米 - 30 厘米 = 100 厘米 - 30 厘米 =(70)厘米",
+    "knowledge_points": [
+      "厘米和米之间的进率与换算"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "431",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "1 米=( )厘米;37 厘米+5 厘米=( )厘米;45 厘米 - 6 厘米=( )厘米;23 米 - 8 米=( )米",
+    "options": [],
+    "answer": "100;42;39;15",
+    "solution": "【分析】根据1米 = 100 厘米换算，计算时厘米和厘米相加减，米和米相加减.\n【详解】1 米 = 100 厘米;37厘米+5厘米 = 42 厘米;45厘米 - 6厘米 = 39 厘米;23 米 - 8 米 = 15 米",
+    "knowledge_points": [
+      "厘米和米之间的进率与换算"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "432",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "在括号填上合适的数.\n\n3 米=( )厘米 50 厘米+50 厘米=( )米",
+    "options": [],
+    "answer": "300;1",
+    "solution": "【分析】根据1米 = 100 厘米进行填空。3 米=3个100厘米;50厘米+50厘米=100厘米=1米.\n【详解】3 米 = 300 厘米;50 厘米+50 厘米 = 1 米",
+    "knowledge_points": [
+      "厘米和米之间的进率与换算"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "433",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "填合适的单位.\n\n一根粉笔长约 7( );操场一周长约 400( );小红身高1( )30( )",
+    "options": [],
+    "answer": "厘米或cm;米或m;米或m;厘米或cm",
+    "solution": "【分析】根据生活经验，对长度单位和数据大小的认识：较短用厘米，较长用米;小红身高应写作 1 米 30 厘米.\n【详解】一根粉笔长约 7 厘米;操场一周长约 400 米;小红身高 1 米 30 厘米",
+    "knowledge_points": [
+      "长度单位的选择"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "434",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "在括号里填上\">\" \"<\"或 \"=\".\n\n1 米( )90 厘米;98 厘米( )1 米 30 厘米;2 米( )200 厘米",
+    "options": [],
+    "answer": ">;<;=",
+    "solution": "【分析】单位不统一时，先化成相同单位，再比较大小。1米 = 100 厘米，几米就等于几百厘米，据此换算比较。整数的大小比较：比较数的大小，先看位数的多少，位数多的数就大;位数相同，从高位开始比较，高位上的数大则这个数大，高位上的数相同，就比较下一位.\n【详解】1 米 = 100 厘米，所以 1 米>90 厘米;1 米 = 100 厘米,98 厘米 < 1 米 < 1 米 30 厘米，所以 98 厘米 < 1 米 30 厘米;2 米 = 200 厘米。",
+    "knowledge_points": [
+      "厘米和米之间的进率与换算",
+      "100以内数的比大小"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "435",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "在括号里填上\"米\"或\"厘米\".\n\n爸爸身高 175( );一根跳绳长约 2( );黑板长约 4( );一张课桌高约 80( )。",
+    "options": [],
+    "answer": "厘米;米;米;厘米",
+    "solution": "【分析】根据生活经验以及对长度单位和数据大小的认识，选择合适的计量单位，即可解答。大拇指的指甲长度大约1厘米，计量爸爸的身高和课桌的高度用\"厘米\"作单位比较合适。小学生两臂伸开的长度大约1米，计量跳绳的长度和黑板的长度用\"米\"作单位比较合适.\n【详解】爸爸身高 175 厘米;一根跳绳长约 2 米;黑板长约4米;一张课桌高约 80 厘米。",
+    "knowledge_points": [
+      "长度单位的选择",
+      "米的认识",
+      "厘米的认识"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "436",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "在括号里填上\"厘米\"或\"米\".\n\n杯子高 8 ( )。 小华的床长 2( ).\n动物园里的长颈鹿高 5( )。 一支钢笔长 17 ( )。",
+    "options": [],
+    "answer": "厘米;米;米;厘米",
+    "solution": "【分析】大拇指的指甲长度大约1厘米，计量杯子的高度和钢笔的长度用\"厘米\"作单位比较合适。小学生两臂伸开的长度大约1米，计量床的长度和长颈鹿的高度用\"米\"作单位比较合适.\n【详解】杯子高 8 厘米。小华的床长 2 米。动物园里的长颈鹿高 5 米。一支钢笔长 17 厘米。",
+    "knowledge_points": [
+      "长度单位的选择",
+      "米的认识",
+      "厘米的认识"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "437",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "在括号里填上合适的长度单位。(\"米\"或者\"厘米\")\n\n手掌的宽约 8( );黑板长 4( )\n手指宽 1( );铅笔长 18( )",
+    "options": [],
+    "answer": "厘米或cm;米或m;厘米或cm;厘米或cm",
+    "solution": "【分析】根据实际生活经验以及具体数据来进行填空。计量较短的物体一般用厘米作单位，食指的宽度约为1厘米。则计量手掌的宽度，手指宽度，铅笔的长度用\"厘米\"作单位。计量较长的物体一般用米作单位，二年级学生的双臂打开约 1 米，则计量黑板的长度，用\"米\"作单位.\n【详解】手掌的宽约 8(厘米);黑板长 4(米);手指宽 1(厘米);铅笔长 18(厘米)",
+    "knowledge_points": [
+      "长度单位的选择"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "438",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "在括号里填上合适的长度单位.\n\n一根粉笔长 8( );教室门高 2( )\n\n一块橡皮长 4( );一座桥长 30( )",
+    "options": [],
+    "answer": "厘米或cm;米或m;厘米或cm;米或m",
+    "solution": "【分析】根据生活经验，对长度单位和数据大小的认识可知：量比较短的物体的长度，通常用厘米作单位，食指的宽大约是1厘米，所以粉笔的长度，橡皮的长度用厘米作单位比较合适;测量较长的物体用米作单位，二年级学生双臂展开的长度大约是1米，所以门的高度，桥的长度用米作单位比较合适.\n【详解】一根粉笔长8厘米;教室门高2米;一块橡皮长 4 厘米;一座桥长 30 米",
+    "knowledge_points": [
+      "长度单位的选择"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "439",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "直尺上的刻度从 0到 3 是( )厘米，从 3 到 9 是( )厘米。",
+    "options": [],
+    "answer": "3;6",
+    "solution": "【分析】物体的长度 = 直尺测量时结束的刻度 - 开始测量时的刻度.\n【详解】3 - 0 = 3(厘米),9 - 3 = 6(厘米),直尺上的刻度从 0 到 3 是 3 厘米，从 3 到 9 是 6 厘米。",
+    "knowledge_points": [
+      "长度的测量方法"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "440",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "在括号里填上厘米或米.\n\n门高 2( );钢笔长约 14( );长颈鹿高约 5( )。",
+    "options": [],
+    "answer": "米;厘米;米",
+    "solution": "【分析】根据实际生活经验以及具体数据来进行填空。计量较长的物体一般用米作单位，计量较短的物体一般用厘米作单位.\n【详解】门高 2 米;钢笔长14厘米;长颈鹿高约5米。",
+    "knowledge_points": [
+      "长度单位的选择",
+      "米的认识",
+      "厘米的认识"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "441",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "在括号填上\"厘米\"或\"米\".\n\n铅笔长 15( );一张桌子高 60( )\n\n小红身高 1( )25( );一根跳绳长约 2( )",
+    "options": [],
+    "answer": "厘米;厘米;米;厘米;米",
+    "solution": "【分析】根据生活经验，对长度单位和数据大小的认识可知：较短用厘米，较长用米;小红身高应写作1米25厘米.\n【详解】铅笔长15厘米;一张桌子高60厘米;小红身高1米25厘米;一根跳绳长约2米。",
+    "knowledge_points": [
+      "长度单位的选择"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "442",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "在括号里填上合适的长度单位.\n\n篮球场长 28( );杯子高约 10( );字典厚大约 6( )\n\n大树高约 15( );一支铅笔大约长 15( )",
+    "options": [],
+    "answer": "米;厘米;厘米;米;厘米",
+    "solution": "【分析】根据生活经验和数据选择合适的单位即可。一般计量较长的物体用\"米\"作单位;一般计量较短的物体用\"厘米\"作单位.\n【详解】篮球场长 28(米);杯子高约 10(厘米);字典厚大约 6(厘米);大树高约 15(米);一支铅笔大约长 15(厘米)",
+    "knowledge_points": [
+      "长度单位的选择"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "443",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "在下面的括号填上合适的长度单位.\n\n(1)小丽家厨房的长是 4( )。 (2)一本故事书长 18( ).\n(3)书桌高 90( )。 (4)学校里的旗杆高 15( )。",
+    "options": [],
+    "answer": "米或m;厘米或cm;厘米或cm;米或m",
+    "solution": "【分析】长度单位:1米(m)大约为小学生双臂伸展开的长度;1 厘米(cm)大约为指甲盖的宽度。根据生活经验和实际数据相结合，分别选择合适单位.\n【详解】(1)小丽家厨房的长是4米。(2)一本故事书长18厘米。(3)书桌高 90 厘米。(4)学校里的旗杆高15米。",
+    "knowledge_points": [
+      "长度单位的选择",
+      "米的认识",
+      "厘米的认识"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "444",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "测量铅笔的长用()作单位，测量大树的高用( )作单位。",
+    "options": [],
+    "answer": "厘米或cm;米或m",
+    "solution": "【分析】大拇指的指甲长度大约1厘米;小学生两臂伸开的长度大约1米。根据生活经验以及数据的大小，选择合适的计量单位.\n【详解】测量铅笔的长用厘米作单位，测量大树的高用米作单位。",
+    "knowledge_points": [
+      "长度单位的选择",
+      "米的认识",
+      "厘米的认识"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "445",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "在括号填上合适的单位.\n\n数学课本长 26( );一张双人床长 2( )\n\n一棵树高 15( );课桌高 60( )",
+    "options": [],
+    "answer": "厘米或cm;米或m;米或m;厘米或cm",
+    "solution": "【分析】根据生活经验及结合给出的数据，来选择合适的长度单位：较短用厘米，较长用米.\n【详解】数学课本长 26 厘米;一张双人床长 2 米;一棵树高 15 米;课桌高 60 厘米",
+    "knowledge_points": [
+      "长度单位的选择"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "446",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "在括号里填上合适的长度单位.\n\n教室长 9( );小明的身高 120( );一支铅笔长 18( )",
+    "options": [],
+    "answer": "米;厘米;厘米",
+    "solution": "【分析】大拇指的指甲长度大约1厘米，计量身高和铅笔长度用\"厘米\"作单位比较合适。小学生两臂伸开的长度大约1米，计量教室长度用\"米\"作单位比较合适.\n【详解】教室长 9 米;小明的身高 120 厘米;一支铅笔长18 厘米。",
+    "knowledge_points": [
+      "长度单位的选择",
+      "米的认识",
+      "厘米的认识"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "447",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "在括号里填上合适的长度单位.\n\n李红的身高 138( );一棵大树高约 12( )",
+    "options": [],
+    "answer": "厘米或cm;米或m",
+    "solution": "【分析】根据生活经验以及对长度单位和数据大小的认识，结合实际情况选择合适的单位即可.\n【详解】李红的身高 138 厘米;一棵大树高约 12 米。",
+    "knowledge_points": [
+      "长度单位的选择",
+      "米的认识",
+      "厘米的认识"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "448",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "在括号里填上合适的长度单位.\n\n牙刷长 15( ),跳绳长 2( ),铅笔长约 18( ),教室长约 10( )。",
+    "options": [],
+    "answer": "厘米或cm;米或m;厘米或cm;米或m",
+    "solution": "【分析】根据生活经验及结合给出的数据，来选择合适的长度单位。食指宽大约是1厘米，所以计量牙刷长和铅笔长用\"厘米\"作单位比较合适;米尺的长度是1米，所以计量跳绳长和教室长用\"米\"作单位比较合适.\n【详解】牙刷长15厘米，跳绳长2米，铅笔长约18厘米，教室长约10 米。",
+    "knowledge_points": [
+      "长度单位的选择"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "449",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "在括号里填上合适的长度单位.\n\n数学课本长约 20( )。小明的身高是 1( )25( )。篮球场长约 28( )。",
+    "options": [],
+    "answer": "厘米;米;厘米;米",
+    "solution": "【分析】根据生活经验，对长度单位和数据大小的认识可知：较短用厘米，较长用米;小明的身高应写作 1 米 25 厘米.\n【详解】数学课本长约 20 厘米。小明的身高是 1 米 25 厘米。篮球场长约 28 米。",
+    "knowledge_points": [
+      "长度单位的选择"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "450",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "要量一下作业本的长度，一般用( )作单位;量我家的长度，一般用( )作单位。",
+    "options": [],
+    "answer": "厘米或cm;米或m",
+    "solution": "【分析】作业本长度较短用厘米，房屋长度较长用米.\n【详解】要量一下作业本的长度，一般用厘米作单位;量我家的长度，一般用米作单位。",
+    "knowledge_points": [
+      "长度单位的选择"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "451",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "在括号里填上合适的单位.\n\n一张床长 2( );小红的身高大约 1( )35( )\n\n数学书宽约 18( );教室长 9( )",
+    "options": [],
+    "answer": "米或m;米或m;厘米或cm;厘米或cm;米或m",
+    "solution": "【分析】根据生活经验，对长度单位和数据大小的认识：较长用米，较短用厘米;小红身高应写作 1 米 35 厘米.\n【详解】一张床长2米;小红的身高大约1米35厘米;数学书宽约 18 厘米;教室长 9 米",
+    "knowledge_points": [
+      "长度单位的选择"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "452",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "100 厘米=( )米;1 米 30 厘米=( )厘米;1 米 - 30 厘米=( )厘米;40 厘米+( )厘米 = 1 米",
+    "options": [],
+    "answer": "1;130;70;60",
+    "solution": "【分析】根据1米 = 100 厘米将单位换算统一然后再进行计算.\n【详解】100厘米 = 1 米,1 米 30 厘米 = 100 厘米+30 厘米 = 130 厘米,1米 - 30厘米 = 100 厘米 - 30厘米 = 70 厘米,1 米 = 100 厘米,100 - 40 = 60，则40厘米 + 60 厘米 = 1 米。",
+    "knowledge_points": [
+      "整十数之间的加减法",
+      "厘米和米之间的进率与换算"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "453",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "填上合适的长度单位.\n\n一本字典厚 3( );一层楼高 4( )\n\n一支粉笔长 7( );老师身高 1( )65( )",
+    "options": [],
+    "answer": "厘米或cm;米或m;厘米或cm;米或m;厘米或cm",
+    "solution": "【分析】根据生活经验和数据选择合适的单位即可：较短用厘米，较长用米.\n【详解】一本字典厚 3(厘米);一层楼高 4(米);一支粉笔长 7(厘米);老师身高 1(米)65(厘米)",
+    "knowledge_points": [
+      "长度单位的选择"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "454",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "在括号里填上合适的单位名称.\n\n一支铅笔长约 20( );亮亮的身高是 128( )\n\n学校教学楼高约 12( );手机长约 15( )",
+    "options": [],
+    "answer": "厘米或cm;厘米或cm;米或m;厘米或cm",
+    "solution": "【分析】根据生活经验及结合给出的数据，来选择合适的长度单位：较短用厘米，较长用米.\n【详解】一支铅笔长约 20 厘米;亮亮的身高是 128 厘米;学校教学楼高约 12 米;手机长约 15 厘米",
+    "knowledge_points": [
+      "长度单位的选择"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "455",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "在括号填上合适的单位.\n\n一根跳绳长 2( )。教学楼高 17( ).\n\n一个杯子高 12( )。手机长约 13( )。",
+    "options": [],
+    "answer": "米或m;米或m;厘米或cm;厘米或cm",
+    "solution": "【分析】根据生活经验及结合给出的数据，选择合适的长度单位：较短用厘米，较长用米.\n【详解】一根跳绳长 2 米;教学楼高 17 米;一个杯子高 12 厘米;手机长约13厘米。",
+    "knowledge_points": [
+      "长度单位的选择"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "456",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "填上合适的长度单位.\n\n一块橡皮长 4( );课桌高 70( )\n\n一棵大树高 8( );小强高 1( )28( )",
+    "options": [],
+    "answer": "厘米或cm;厘米或cm;米或m;米或m;厘米或cm",
+    "solution": "【分析】大拇指的指甲长度大约 1 厘米，计量橡皮的长度，课桌的高度用\"厘米\"作单位比较合适。小学生两臂伸开的长度大约1米，计量大树的高度用\"米\"作单位比较合适。小朋友的身高应该是一百多厘米，大概是 1 米几十厘米.\n【详解】一块橡皮长 4 厘米;课桌高 70 厘米;一棵大树高 8 米;小强高 1 米 28 厘米。",
+    "knowledge_points": [
+      "长度单位的选择",
+      "米的认识",
+      "厘米的认识"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "457",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "在括号里填上\"米\"或\"厘米\".\n\n一支铅笔长约 18( ),教室的宽约 5( )。小明身高 1( )20( )。",
+    "options": [],
+    "answer": "厘米或cm;米或m;米或m;厘米或cm",
+    "solution": "【分析】根据实际情境生活经验及数据的大小选择合适的单位。铅笔长度结合数据18用厘米;教室宽度结合数据5用米;身高结合数据1用米,20用厘米.\n【详解】一支铅笔长约 18(厘米),教室的宽约 5(米),小明身高 1(米)20(厘米)。",
+    "knowledge_points": [
+      "长度单位的选择",
+      "米的认识",
+      "厘米的认识"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "458",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "在括号里填上\">\" \"<\"或 \"=\" .\n\n3 米( )8 米;1 米( )30 厘米+70 厘米;10 米 - 5 米( )14 米 - 9 米;40 厘米( )60 厘米",
+    "options": [],
+    "answer": "<;=;=;<",
+    "solution": "【分析】先计算出结果，统一单位后再比较大小即可.\n【详解】3米 < 8 米;30 厘米+70 厘米 = 100 厘米 = 1 米，则 1 米 = 30 厘米+70 厘米;10 米 - 5 米 = 5 米;14 米 - 9 米 = 5 米，则相等;40 厘米 < 60 厘米。",
+    "knowledge_points": [
+      "厘米和米之间的进率与换算"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "459",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "一只蚂蚁从一把尺子的 3 厘米处开始沿直线爬，爬到 15 厘米处时它爬了()厘米。",
+    "options": [],
+    "answer": "12",
+    "solution": "【分析】经过的路线 = 结束刻度 - 开始刻度.\n【详解】15 - 3 = 12(厘米),所以它爬了 12 厘米。",
+    "knowledge_points": [
+      "不退位减法(20 以内)",
+      "长度的测量方法",
+      "厘米的认识"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "460",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "在下面的括号里填上合适的单位名称.\n\n教室的黑板大约长 4( );一支彩笔长约 10( )。",
+    "options": [],
+    "answer": "米或m;厘米或cm",
+    "solution": "【分析】根据生活经验及结合给出的数据选择单位：黑板长用米，彩笔长用厘米.\n【详解】教室的黑板大约长 4 米;一支彩笔长约 10 厘米。",
+    "knowledge_points": [
+      "长度单位的选择"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "461",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "60 厘米+40 厘米=( )米;15 米 - 6 米=( )米",
+    "options": [],
+    "answer": "1;9",
+    "solution": "【分析】60厘米+40厘米=100厘米，再根据100厘米=1米换算;单位相同直接计算.\n【详解】60厘米+40厘米 = 100 厘米 = 1 米;15 米 - 6 米 = 9 米",
+    "knowledge_points": [
+      "厘米和米之间的进率与换算"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "462",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "在括号里填上\">\" \"<\"或 \"=\"\n\n42+39( )49+32;7×9+9( )9×9;5 米( )50 厘米",
+    "options": [],
+    "answer": "=;<;>",
+    "solution": "【分析】先计算再比较;有乘法和加法先算乘法;1 米 = 100 厘米.\n【详解】42 + 39 = 81,49 + 32 = 81，所以相等;7×9+9 = 72,9×9 = 81，所以小于;5 米 = 500 厘米，大于 50 厘米。",
+    "knowledge_points": [
+      "用 7~9 的乘法口诀求商",
+      "毫米，厘米，分米，米之间的进率与换算",
+      "100以内数的比大小"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "463",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "在括号里填入\">\" \"<\"或 \"=\" .\n\n4 米( )5 米;53 厘米( )35 厘米;1 米( )100 厘米\n\n6 厘米( )6 米;150 厘米( )1 米;1 米 - 1 厘米( )99 厘米",
+    "options": [],
+    "answer": "<;>;=;<;>;=",
+    "solution": "【分析】单位相同直接比较，单位不相同先根据1米 = 100 厘米换算单位再比较.\n【详解】4 米 < 5 米;53 厘米 > 35 厘米;1 米 = 100 厘米;6 米 = 600 厘米，所以 6 厘米 < 6 米;150 厘米 > 1 米;1米 - 1厘米 = 99 厘米，所以相等。",
+    "knowledge_points": [
+      "厘米和米之间的进率与换算",
+      "100 以内数的比大小"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "464",
+    "unit": "第一单元 长度单位",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "下面一共有( )条线段.\n\n![](images/dcd9a300dd4dfb46fcd12e5da7d65817cbdce146d68e522ce561e05b55178bf6.jpg)",
+    "options": [],
+    "answer": "6",
+    "solution": "【分析】线段有两个端点，是直的，可测量。由此数出线段的数量即可.\n【详解】以 A 点为左端点的线段有 3 条。![](images/85000ffbbd4e8bbf5f6cf5c8832cf9271e6887a1e761d3c26d483e7933ab8587.jpg)以B点为左端点的线段有2条。![](images/142e8cc46e5a85ba493f8f923a0085047e7ccf19e7a14e0d70484fcbf36b537f.jpg)以C点为左端点的线段有1条。![](images/b3134b70bab716e73c4d05b2b27d48841a98c77a57025403b3e0bc2bfffdfe98.jpg)3 + 2 + 1 = 6(条),一共有 6 条线段。",
+    "knowledge_points": [
+      "线段的初步认识"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "465",
+    "unit": "第一单元 长度单位",
+    "question_type": "判断题",
+    "difficulty": 0.65,
+    "question": "在刻度尺上从刻度 2到刻度 9 是 7 厘米。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】用直尺测量长度时，长度 = 结束刻度 - 开始刻度.\n【详解】9 - 2 = 7(厘米),所以从刻度2到刻度9是7厘米。故答案为:√",
+    "knowledge_points": [
+      "长度的测量方法",
+      "厘米的认识"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "466",
+    "unit": "第一单元 长度单位",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "大树高 80 厘米。()",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】根据生活经验，大树很高，通常用米作单位且远大于80厘米.\n【详解】大树不可能高80厘米，原题说法错误。故答案为: ×",
+    "knowledge_points": [
+      "长度单位的选择",
+      "米的认识"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "467",
+    "unit": "第一单元 长度单位",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "5 厘米比 1 米长。()",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】不同单位先统一单位。1米 = 100厘米.\n【详解】5 厘米 < 100 厘米，所以 5 厘米 < 1 米。原题说法错误。故答案为: ×",
+    "knowledge_points": [
+      "厘米和米之间的进率与换算"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "468",
+    "unit": "第一单元 长度单位",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "东东每天上学走 100厘米。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】1米=100厘米,100厘米的路程很短，不符合每天上学走的实际情况.\n【详解】东东每天上学走 100 厘米不符合实际，用米作单位比较合适，原题说法错误。故答案为: ×",
+    "knowledge_points": [
+      "米的认识",
+      "长度的估测",
+      "厘米的认识"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "469",
+    "unit": "第一单元 长度单位",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "数学书封面的四条边都可以看成线段。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】线段有两个端点，中间是直直的线，长度可测量.\n【详解】数学书的封面是一个长方形，长方形有四条边，可以看成四条线段，所以原题说法正确。![](images/0c0837bc1222d8ebb5c179a35074d66ccd27deeec01e4fc417109ba6d82b5622.jpg)故答案为:√",
+    "knowledge_points": [
+      "线段的初步认识"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "470",
+    "unit": "第一单元 长度单位",
+    "question_type": "判断题",
+    "difficulty": 0.65,
+    "question": "一把断了的尺子，就没有办法测量物体的长度了。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】把断尺左端的一个整刻度对准物体的一端，且尺子要与被测物体重合(不能斜放),再看看尺子的右端所对的刻度是几，然后用右端的刻度减去左端的刻度，求出差就可以得出物体的长度.\n【详解】由题意分析得：把断了的尺子，也可以测量物体的长度。原题说法错误。故答案为: ×",
+    "knowledge_points": [
+      "长度的测量方法"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "471",
+    "unit": "第一单元 长度单位",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "桌子高 74 厘米。()",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】根据生活经验以及数据的大小，选择合适的计量单位。计量较短的物体长度用\"厘米\"作单位，食指的宽度约是1厘米，则计量桌子的高度用\"厘米\"作单位.\n【详解】桌子高74厘米。符合实际，原题说法正确。故答案为:√",
+    "knowledge_points": [
+      "长度单位的选择"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "472",
+    "unit": "第一单元 长度单位",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "100 厘米 = 1 米。()",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】米和厘米都是长度单位,1 米 = 100 厘米.\n【详解】1根1米长的米尺上有100个1厘米，也就是100厘米。原题说法正确。故答案为:√",
+    "knowledge_points": [
+      "厘米和米之间的进率与换算"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "473",
+    "unit": "第一单元 长度单位",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "小明身高 132 厘米。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】结合生活经验，计量身高通常用厘米作单位，数据132表示132厘米.\n【详解】小明身高132厘米，原题说法正确。故答案为:√",
+    "knowledge_points": [
+      "长度单位的选择"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "474",
+    "unit": "第一单元 长度单位",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "90 厘米的线段比 1米的线段短。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】单位不同先统一单位,1米 = 100厘米，再比较大小.\n【详解】1米 = 100 厘米,90 厘米<100 厘米，即 90 厘米 < 1 米。原题说法正确。故答案为:√",
+    "knowledge_points": [
+      "厘米和米之间的进率与换算"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "475",
+    "unit": "第一单元 长度单位",
+    "question_type": "判断题",
+    "difficulty": 0.65,
+    "question": "比 90 米短 10 厘米的是 80 米。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】90 米减去 10 厘米，需先统一单位。可将90米分成89米和1米,1米=100厘米.\n【详解】100 厘米 - 10 厘米 = 90 厘米，剩下的 89 米和 90 厘米合起来是 89 米 90 厘米。所以比90米短10厘米的是89米90厘米，原题说法错误。故答案为: ×",
+    "knowledge_points": [
+      "厘米和米之间的进率与换算"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "476",
+    "unit": "第一单元 长度单位",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "100 厘米的细线比 1米的铁丝长。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】根据1米 = 100 厘米将单位换算统一再进行比较.\n【详解】100厘米 = 1 米，则 100 厘米的细线和 1 米的铁丝一样长，原题说法错误。故答案为: ×",
+    "knowledge_points": [
+      "厘米和米之间的进率与换算"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "477",
+    "unit": "第一单元 长度单位",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "一只小花猫比一米高。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】猫的身高大约30厘米左右,1 米 = 100 厘米，所以小花猫比1米矮.\n【详解】一只小花猫比一米矮。原题说法错误。故答案为: ×",
+    "knowledge_points": [
+      "米的认识",
+      "厘米的认识"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "478",
+    "unit": "第一单元 长度单位",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "铅笔盒长 100 厘米。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】100厘米约等于1米，比铅笔盒长得多，不符合生活实际.\n【详解】100 厘米大约是二年级小朋友双臂展开的长度，比铅笔盒要长得多，不符合实际，所以说法错误。故答案为: ×",
+    "knowledge_points": [
+      "长度的估测",
+      "厘米的认识"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "479",
+    "unit": "第一单元 长度单位",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "1 米长的红彩带和100 厘米长的绿彩带一样长。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】根据 1 米 = 100 厘米，单位统一后可直接判断.\n【详解】1米 = 100 厘米，所以1米长的红彩带和100厘米长的绿彩带一样长。原题说法正确。故答案为:√",
+    "knowledge_points": [
+      "厘米和米之间的进率与换算"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "480",
+    "unit": "第一单元 长度单位",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "小芳的身高是 137厘米。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】计量身高通常用\"厘米\"作单位,137厘米符合小学生身高的实际情况.\n【详解】计量小芳的身高用\"厘米\"做单位，即小芳的身高是137厘米。原题说法正确。故答案为:√",
+    "knowledge_points": [
+      "长度单位的选择",
+      "厘米的认识"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "481",
+    "unit": "第一单元 长度单位",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "线段是直的，有两个端点。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】线段有2个端点，有限长，可以度量.\n【详解】线段是直的，有两个端点，是有限长的，所以本题说法正确。故答案为:√",
+    "knowledge_points": [
+      "线段，直线，射线的认识及特征"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "482",
+    "unit": "第一单元 长度单位",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "四边形由4条线段围成。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】四边形有四条边，每条边都可以看作一条线段.\n【详解】长方形，正方形等四边形都是由4条线段围成。故答案为:√",
+    "knowledge_points": [
+      "线段的初步认识"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "483",
+    "unit": "第一单元 长度单位",
+    "question_type": "判断题",
+    "difficulty": 0.65,
+    "question": "两点之间一定可以画一条线段。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】线段是直直的，并且每个线段都有两个端点.\n【详解】如图:![](images/2026-02-06%20140809.jpg)所以两点之间一定可以画一条线段。故答案为:√",
+    "knowledge_points": [
+      "线段的初步认识"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "484",
+    "unit": "第一单元 长度单位",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "线段一定都是直的。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【详解】拉紧的一段线，可以看作一条线段;黑板的边，桌子的边，书的边都可以看作线段;线段是直的。下面这些都是线段:![](images/2026-02-06%20140914.jpg)原题说法正确。故答案为:√",
+    "knowledge_points": [
+      "线段的初步认识"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "485",
+    "unit": "第一单元 长度单位",
+    "question_type": "作图题",
+    "difficulty": 0.85,
+    "question": "画两条线段，使它们的总长为 8 厘米。",
+    "options": [],
+    "answer": "见详解",
+    "solution": "【分析】线段是直的，有两个端点。画线段时，先点一个点，然后用尺子的0刻度线对准这个点，接着找出所要画的线段的刻度，并点上一个点，最后把这两个点连起来，即可画出线段。要将长度标注出来。两条线段总长为8厘米，可画2条长4厘米的线段.\n【详解】4厘米+4厘米 = 8 厘米作图如下:4厘米4厘米(答案不唯一)",
+    "knowledge_points": [
+      "线段的初步认识",
+      "用直尺画线段",
+      "厘米的认识"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "486",
+    "unit": "第一单元 长度单位",
+    "question_type": "解答题",
+    "difficulty": 0.85,
+    "question": "有一根 58 米长的绳子，剪去20米，还剩下多少米。",
+    "options": [],
+    "answer": "38 米",
+    "solution": "【分析】根据减法的意义，用绳子的总长度减去剪掉的长度即可求出还剩下的长度.\n【详解】58 - 20 = 38(米),答：还剩下 38 米。",
+    "knowledge_points": [
+      "两位数与整十数的减法"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "487",
+    "unit": "第一单元 长度单位",
+    "question_type": "解答题",
+    "difficulty": 0.65,
+    "question": "小桃红家的小区每层楼高3米，小桃红家住在3楼，她从一楼乘电梯回家，上升了多少米。她从家乘电梯到住在6楼的小石头家玩，上升了多少米。",
+    "options": [],
+    "answer": "6 米;9 米",
+    "solution": "【分析】每层楼高3米，从1楼到3楼上升2层即2个3米;从3楼到6楼上升3层即3个3米.\n【详解】3 - 1 = 2(层),3 + 3 = 6(米);6 - 3 = 3(层),3+3+3 = 9(米)。答：从一楼乘电梯回家上升6米;从家乘电梯到6楼上升9米。",
+    "knowledge_points": [
+      "米的认识",
+      "植树问题(两端都不栽)",
+      "连加，连减(10 以内)",
+      "6,7 的分与合(组成)"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "488",
+    "unit": "第一单元 长度单位",
+    "question_type": "解答题",
+    "difficulty": 0.65,
+    "question": "一段绳子，截去了40厘米，还剩下30厘米，这段绳子原来有多长。",
+    "options": [],
+    "answer": "70 厘米",
+    "solution": "【分析】截去的长度加上剩下的长度即可得到原来的长度.\n【详解】40 + 30 = 70(厘米),答：这段绳子原来长70厘米。",
+    "knowledge_points": [
+      "整十数之间的加减法",
+      "厘米的认识"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "489",
+    "unit": "第一单元 长度单位",
+    "question_type": "解答题",
+    "difficulty": 0.85,
+    "question": "一座桥的桥洞限高 3米，一艘船高 3 米 10 厘米(不含水中的部分),船能够顺利过桥吗。",
+    "options": [],
+    "answer": "船不能够顺利过桥",
+    "solution": "【分析】先比较桥洞高与船高的大小关系;若船比桥洞高则不能通过.\n【详解】3 米 10 厘米 > 3 米，即船比桥洞高;答：船不能够顺利过桥。",
+    "knowledge_points": [
+      "米的认识",
+      "厘米的认识"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "490",
+    "unit": "第一单元 长度单位",
+    "question_type": "解答题",
+    "difficulty": 0.65,
+    "question": "小红家，小丽家和公园在一条直线上.\n\n![](images/2026-02-06%20141336.jpg)\n小红家和小丽家相距多少米。",
+    "options": [],
+    "answer": "100米或60米",
+    "solution": "【分析】分两种情况：当两家在公园两侧用加法;在公园同一侧用减法。①当小红家和小丽家在公园的两侧时，用加法求距离。![](images/d8f3efe550e111fcc027a5c38fb147ebbf2ef8ec78705f05370f86d8d7b24523.jpg)\n②当小红家和小丽家在公园的同一侧时，用减法求距离。![](images/75f43c93fcdeb7cbef38d59f191db63957fa5311f27a56794625dae6a7cc39e1.jpg)\n【详解】80 + 20 = 100(米),80 - 20 = 60(米),答：小红家和小丽家相距 100 米或 60 米。",
+    "knowledge_points": [
+      "整十数之间的加减法",
+      "米的认识"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "491",
+    "unit": "第一单元 长度单位",
+    "question_type": "解答题",
+    "difficulty": 0.65,
+    "question": "一条线段剪去3厘米后，剩下的长度如图所示，原来这条线段长多少厘米。\n\n![](images/55ab2d5619f0d259bfe7ef9f5c4058eef6b7a7101b2295c9a735046b4d26e8c3.jpg)",
+    "options": [],
+    "answer": "8厘米",
+    "solution": "【分析】剪去的长度+剩下的长度 = 原来的长度。先由刻度求出剩下的长度，再相加.\n【详解】9 - 4 = 5(厘米),3 + 5 = 8(厘米),答：原来这条线段长 8 厘米。",
+    "knowledge_points": [
+      "长度的测量方法",
+      "厘米的认识"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "492",
+    "unit": "第一单元 长度单位",
+    "question_type": "解答题",
+    "difficulty": 0.4,
+    "question": "井底一只蜗牛要爬出 5 米深的井，它每天往上爬 3 米后，会滑下 2 米，它这样连续几天可以爬到井口。",
+    "options": [],
+    "answer": "3 天",
+    "solution": "【分析】每天实际前进 3 - 2 = 1(米),最后一天爬到井口后不再下滑。先算最后一天前还剩多少米，再算前面天数.\n【详解】3 - 2 = 1(米),5 - 3 = 2(米),2 + 1 = 3(天),答：它这样连续 3 天可以爬到井口。",
+    "knowledge_points": [
+      "米的认识"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "493",
+    "unit": "第一单元 长度单位",
+    "question_type": "解答题",
+    "difficulty": 0.65,
+    "question": "超市，肯德基和儿童活动中心在一条直线上，超市和肯德基相距 80 米，超市和儿童活动中心相距 60 米。肯德基和儿童活动中心相距多少米。",
+    "options": [],
+    "answer": "140米或20米",
+    "solution": "【分析】分两种情况：两点在超市两侧用加法;在同一侧用减法。①在两侧:![](images/2026-02-06%20142544.jpg)②在同一侧:![](images/1de64afdd50a353152930a15c29fc74527ebb2036df7c473044291c02f799427.jpg)\n【详解】80 + 60 = 140(米),80 - 60 = 20(米),答：肯德基和儿童活动中心相距 140 米或 20 米。",
+    "knowledge_points": [
+      "整十数之间的加减法",
+      "米的认识"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "494",
+    "unit": "第一单元 长度单位",
+    "question_type": "解答题",
+    "difficulty": 0.65,
+    "question": "爸爸把三根 1 米长的木棒绑在一起，每处接头长3厘米，接好后木棒的总长度是多少厘米。",
+    "options": [],
+    "answer": "294 厘米",
+    "solution": "【分析】先把 1 米换算成 100 厘米，三根总长 300 厘米;绑成一根有两个接头，每个接头重合3厘米，需要减去两次重合长度.\n【详解】1米 = 100 厘米,100 + 100 + 100 = 300(厘米),300 - 3 - 3 = 294(厘米),答：接好后的木棒总长度是294厘米。",
+    "knowledge_points": [
+      "厘米和米之间的进率与换算"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "495",
+    "unit": "第一单元 长度单位",
+    "question_type": "解答题",
+    "difficulty": 0.85,
+    "question": "下图是小芳从家到学校的路线图，你认为走哪条路最近。\n\n![](images/e1779d0f542a412ac3c981db9845d960d8dce4250ad3fd33dde2c201e8dec399.jpg)",
+    "options": [],
+    "answer": "从小芳家走中间的路到中间的那一点，再从那一点走直直的路到学校为最近的路线。",
+    "solution": "【分析】两点之间，弯曲的线比直直的线段长，所以最近路线不能选择弯曲的路线;小芳家到少年宫再到中间的点，比小芳家直接到中间的点要远，所以也不是最近线路;只有图中红色线路为最近线路.\n【详解】从小芳家走中间的路到中间的那一点，再从那一点走直直的路到学校为最近的路线。![](images/c9839d261d670817ffabcb38e55c6073a2120860f7142512793e8fdc21656d4a.jpg)",
+    "knowledge_points": [
+      "线段的初步认识",
+      "两点间线段最短与两点间的距离"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "496",
+    "unit": "第一单元 长度单位",
+    "question_type": "解答题",
+    "difficulty": 0.65,
+    "question": "用下面的尺子画出一条长5厘米的线段，有哪些画法。\n\n![](images/f8a956ed2f85834e31c9196ce0640c0d9b6de413c3fe221ed4520734971c5a72.jpg)",
+    "options": [],
+    "answer": "从刻度3画到刻度8;从刻度4画到刻度9;从刻度5画到刻度10",
+    "solution": "【分析】在尺子上找到相差5的两个刻度，它们之间的长度就是5厘米.\n【详解】8 - 3 = 5(厘米),9 - 4 = 5(厘米),10 - 5 = 5(厘米),答：从刻度3画到刻度8;从刻度4画到刻度9;从刻度5画到刻度10。",
+    "knowledge_points": [
+      "长度的测量方法"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "497",
+    "unit": "第一单元 长度单位",
+    "question_type": "解答题",
+    "difficulty": 0.85,
+    "question": "这两张纸条共长多少厘米。\n\n![](images/67de7c2d1f12dcde601a3569adb21453f6ad21998633fff379b2ea5c5c324829.jpg)",
+    "options": [],
+    "answer": "4 厘米",
+    "solution": "【分析】分别用\"结束刻度 - 开始刻度\"求出两张纸条的长度，再相加.\n【详解】4 - 2 = 2(厘米),5 - 3 = 2(厘米),2 + 2 = 4(厘米),答：这两张纸条共长4厘米。",
+    "knowledge_points": [
+      "长度的测量方法",
+      "厘米的认识"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "498",
+    "unit": "第一单元 长度单位",
+    "question_type": "解答题",
+    "difficulty": 0.85,
+    "question": "下面这根绳子大约长多少厘米。\n\n![](images/f9fb9623906fe75795a69a457466ca828e03351fab1f4cc311fc391b955e1a3c.jpg)",
+    "options": [],
+    "answer": "8厘米",
+    "solution": "【分析】把弯曲的绳子分为上，中，下三段分别求长度，再相加.\n【详解】上段从1到4是3厘米，中段从3到4是1厘米，下段从3到7是4厘米,3 + 1 + 4 = 8(厘米);答：这根绳子大约长8厘米。",
+    "knowledge_points": [
+      "长度的测量方法"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "499",
+    "unit": "第一单元 长度单位",
+    "question_type": "解答题",
+    "difficulty": 0.85,
+    "question": "一条线段长 3 厘米，另一条线段比它长 6 厘米，另一条线段长多少厘米。",
+    "options": [],
+    "answer": "9 厘米",
+    "solution": "【分析】用加法：原线段长度 + 比它长的长度 = 另一条线段长度.\n【详解】3 + 6 = 9(厘米),答：另一条线段长9厘米。",
+    "knowledge_points": [
+      "8,9的加减法",
+      "厘米的认识"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "500",
+    "unit": "第一单元 长度单位",
+    "question_type": "解答题",
+    "difficulty": 0.85,
+    "question": "一张桌子高 70 厘米，比椅子高 20 厘米，椅子高多少厘米。",
+    "options": [],
+    "answer": "50厘米",
+    "solution": "【分析】桌子高度 - 桌子比椅子高的高度 = 椅子高度.\n【详解】70 - 20 = 50(厘米),答：椅子高50厘米。",
+    "knowledge_points": [
+      "整十数之间的加减法",
+      "厘米的认识"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  }
+]
diff --git "a/\344\272\214\345\271\264\347\272\247\351\242\230\351\233\206/\344\272\214\345\271\264\347\272\247\344\270\212/\344\272\214\345\271\264\347\272\247\344\270\212\347\254\254\344\270\203\345\215\225\345\205\203\350\256\244\350\257\206\346\227\266\351\227\264.json" "b/\344\272\214\345\271\264\347\272\247\351\242\230\351\233\206/\344\272\214\345\271\264\347\272\247\344\270\212/\344\272\214\345\271\264\347\272\247\344\270\212\347\254\254\344\270\203\345\215\225\345\205\203\350\256\244\350\257\206\346\227\266\351\227\264.json"
new file mode 100644
index 0000000000000000000000000000000000000000..ce27d7b493c9ddbf4ea1c19b14d4901be264c2bf
--- /dev/null
+++ "b/\344\272\214\345\271\264\347\272\247\351\242\230\351\233\206/\344\272\214\345\271\264\347\272\247\344\270\212/\344\272\214\345\271\264\347\272\247\344\270\212\347\254\254\344\270\203\345\215\225\345\205\203\350\256\244\350\257\206\346\227\266\351\227\264.json"
@@ -0,0 +1,8160 @@
+[
+  {
+    "id": "1",
+    "unit": "第七单元认识时间",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "六一儿童节文艺表演![](images/29f05cb782fedd61c721239e33060bb1c865b209fb05dc7d425de4c9838e485d.jpg)原计划开始，由于天气原因，现推迟1小时30分钟，推迟后( )开始表演。",
+    "options": [
+      "A. 9:00",
+      "B. 10:00",
+      "C. 9:30"
+    ],
+    "answer": "C",
+    "solution": "【分析】从题干可知：分针指向12，时针指向8，所以钟面所显示的时刻是8:00，要求推迟1小时30分钟之后的时刻是多少，用开始时刻+经过时间=结束时间.\n【详解】8:00+1小时30分=9:30，所以推迟到9:30开始表演。故答案为:C",
+    "knowledge_points": [
+      "时，分，秒时间的推算"
+    ],
+    "source": "24-25二年级下·贵州铜仁·期末"
+  },
+  {
+    "id": "2",
+    "unit": "第七单元认识时间",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "钟面上，分针走半圈经过的时间是( )。",
+    "options": [
+      "A. 6分",
+      "B. 30秒",
+      "C. 30分"
+    ],
+    "answer": "C",
+    "solution": "【分析】观察钟面上分针的转动情况，转一圈正好是1小时，转一个大格是5分钟。据此解答即可.\n【详解】钟面上，分针走半圈是走了6个大格，即30分钟，所以分针走半圈经过的时间是30分。故答案为:C",
+    "knowledge_points": [
+      "一般时间与钟面指针的位置"
+    ],
+    "source": "25-26三年级上·海南海口·单元测试"
+  },
+  {
+    "id": "3",
+    "unit": "第七单元认识时间",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "三位叔叔参加沙坪坝区全球校友半程马拉松比赛，谁跑得最快。( )",
+    "options": [
+      "A. 张叔叔用1时10分",
+      "B. 马叔叔用1时半",
+      "C. 刘叔叔用89分"
+    ],
+    "answer": "A",
+    "solution": "【分析】根据1时=60分，把单位换算统一后再进行比较，时间越短则跑得越快.\n【详解】A。张叔叔用1时10分,1时10分=60分+10分=70分。B。马叔叔用1时半,1时半=60分+30分=90分。C。刘叔叔用89分。70分<89分<90分，则三位叔叔参加沙坪坝区全球校友半程马拉松比赛，张叔叔跑得最快。故答案为:A",
+    "knowledge_points": [
+      "时间快慢的比较",
+      "时，分，秒之间的换算与比较"
+    ],
+    "source": "24-25二年级下·重庆沙坪坝·期末"
+  },
+  {
+    "id": "4",
+    "unit": "第七单元认识时间",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "钟面上，分针从\"2\"走到\"5\"经过的时间是( )。",
+    "options": [
+      "A. 3分",
+      "B. 3时",
+      "C. 15分"
+    ],
+    "answer": "C",
+    "solution": "【分析】钟面上有12个大格,60个小格,1个大格里面有5个小格，分针走1小格是1分，走1大格是5分.\n【详解】分针从\"2\"走到\"5\"走了3大格，所以走了3×5=15(个)小格，即是15分，所以经过了15分。故答案为:C",
+    "knowledge_points": [
+      "时，分，秒有关的计算"
+    ],
+    "source": "24-25二年级下·广东揭阳·期末"
+  },
+  {
+    "id": "5",
+    "unit": "第七单元认识时间",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "上午第二节课9时15分上课,9时55分下课。这节课上了( )。",
+    "options": [
+      "A. 30分",
+      "B. 35分",
+      "C. 40分"
+    ],
+    "answer": "C",
+    "solution": "【分析】用下课的时刻减去上课的时刻，即可求出这节课上了多长时间.\n【详解】9时55分-9时15分=40分，这节课上了40分。故答案为:C",
+    "knowledge_points": [
+      "时，分，秒有关的计算"
+    ],
+    "source": "24-25二年级下·天津静海·期末"
+  },
+  {
+    "id": "6",
+    "unit": "第七单元认识时间",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "8时10分再过1小时是( )。",
+    "options": [
+      "A. 8时11分",
+      "B. 9时10分",
+      "C. 9时11分"
+    ],
+    "answer": "B",
+    "solution": "【分析】已知起始时间是8时10分，求再过1小时是什么时刻，小时数增加1，分钟数不变.\n【详解】8时10分+1小时=9时10分,8时10分再过1小时是9时10分。故答案为:B",
+    "knowledge_points": [
+      "时，分，秒时间的推算"
+    ],
+    "source": "23-24二年级上·新疆乌鲁木齐·期末"
+  },
+  {
+    "id": "7",
+    "unit": "第七单元认识时间",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "分针从12走到6，走了( )。",
+    "options": [
+      "A. 3时",
+      "B. 30分",
+      "C. 一刻"
+    ],
+    "answer": "B",
+    "solution": "【分析】钟面上分针走1小格是1分，走1大格是5分，先数一数分针走了几个大格，再乘5分即可，据此解答.\n【详解】分针从12走到6，走了6大格，走了6×5=30(分)。故答案为:B",
+    "knowledge_points": [
+      "时，分的认识及换算"
+    ],
+    "source": "23-24二年级上·新疆乌鲁木齐·期末"
+  },
+  {
+    "id": "8",
+    "unit": "第七单元认识时间",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "小亮每天晚上7:30开始阅读半小时书，晚上( )阅读结束。",
+    "options": [
+      "A. 8:00",
+      "B. 7:50",
+      "C. 8:10"
+    ],
+    "answer": "A",
+    "solution": "【分析】由题意可知：用7:30加上半小时(30分钟),即是阅读结束时间;据此解答.\n【详解】由分析可得:1时=60分，半小时=30分,7:30+30分=8:00，晚上8:00阅读结束。故答案为:A",
+    "knowledge_points": [
+      "时，分的认识及换算",
+      "时，分，秒时间的推算"
+    ],
+    "source": "23-24二年级上·新疆乌鲁木齐·期末"
+  },
+  {
+    "id": "9",
+    "unit": "第七单元认识时间",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "100米赛跑，小刚用了15秒，小强用了18秒,( )跑得快。",
+    "options": [
+      "A. 小刚",
+      "B. 小强",
+      "C. 一样快"
+    ],
+    "answer": "A",
+    "solution": "【分析】距离一样，用时越少则跑得越快.\n【详解】15秒<18秒,100米赛跑，小刚用了15秒，小强用了18秒，小刚跑得快。故答案为:A",
+    "knowledge_points": [
+      "时间快慢的比较"
+    ],
+    "source": "24-25二年级下·湖南邵阳·期中"
+  },
+  {
+    "id": "10",
+    "unit": "第七单元认识时间",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "分针从数字3走到数字9，经过的时间是( )。",
+    "options": [
+      "A. 6分钟",
+      "B. 30分钟",
+      "C. 60分钟"
+    ],
+    "answer": "B",
+    "solution": "【分析】钟面上较短的针是时针，较长的针是分针。时针走一大格是1时;分针走1小格是1分，走1大格是5分;秒针走1小格是1秒，走1大格是5秒。分针从3走到9走了6大格，用大格数乘5即可求解.\n【详解】9 - 3 = 6(大格),6×5 = 30(分),分针从数字3走到数字9，经过的时间是30分钟。故答案为:B",
+    "knowledge_points": [
+      "6的乘法口诀及应用 ",
+      "一般时间与钟面指针的位置"
+    ],
+    "source": "24-25二年级下·湖南邵阳·期中"
+  },
+  {
+    "id": "11",
+    "unit": "第七单元认识时间",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "1秒可以( )。",
+    "options": [
+      "A. 写一个字",
+      "B. 读一篇文章",
+      "C. 跑100米"
+    ],
+    "answer": "A",
+    "solution": "【分析】心脏跳动一次的时间大约是1秒，据此逐项分析.\n【详解】A。写一个字的时间较短,1秒可以完成;B。读一篇文章花的时间较长,1秒不能完成;C。跑100米一般需要十多秒。1秒可以写一个字。故答案为:A",
+    "knowledge_points": [
+      "秒的认识"
+    ],
+    "source": "23-24二年级下·广西贵港·期末"
+  },
+  {
+    "id": "12",
+    "unit": "第七单元认识时间",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "钟面上，时针走1大格，分针走( )大格。",
+    "options": [
+      "A. 60",
+      "B. 12",
+      "C. 10"
+    ],
+    "answer": "B",
+    "solution": "【分析】钟面上一共有12大格，分针走1大格表示5分钟，时针走1大格表示1小时，据此解答即可.\n【详解】钟面上，时针走1大格，表示1小时。所以分针要走一圈，一共12大格。故答案为:B",
+    "knowledge_points": [
+      "时，分的认识及换算"
+    ],
+    "source": "24-25二年级下·贵州铜仁·期末"
+  },
+  {
+    "id": "13",
+    "unit": "第七单元认识时间",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "动物们进行50米游泳比赛。海龟用了15秒，海豹用了12秒，海象用了20秒。( )游的最快。",
+    "options": [
+      "A. 海豹",
+      "B. 海象",
+      "C. 海龟"
+    ],
+    "answer": "A",
+    "solution": "【分析】动物们进行50米游泳比赛，谁用的时间少，谁的速度就快，据此解答.\n【详解】12秒<15秒<20秒，海豹用的时间最少，所以海豹游的最快。故答案为:A",
+    "knowledge_points": [
+      "时间快慢的比较"
+    ],
+    "source": "24-25一年级下·河北张家口·期末"
+  },
+  {
+    "id": "14",
+    "unit": "第七单元认识时间",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面哪个时间可以用\"刚过11时\"表示。( )",
+    "options": [
+      "A. 10:55",
+      "B. 11:10",
+      "C. 11:30"
+    ],
+    "answer": "B",
+    "solution": "【分析】钟面上长针是分针，短针是时针。刚过11时，表示时间在11点之后不久，通常指分针刚走过12的位置几分钟内，由此解答.\n【详解】A。10:55，还不到11时，属于快到11时，不符合题意;B。11:10，已经过了11点10分钟，时间较短，属于刚过11时，符合题意;C。11:30，已经过了11点30分钟，明显超过\"刚过\"的范围，不符合题意。则\"刚过11时\"可以用11:10表示。故答案为:B",
+    "knowledge_points": [
+      "半点时间与钟面指针的位置",
+      "一般时间与钟面指针的位置"
+    ],
+    "source": "24-25一年级下·湖南岳阳·期中"
+  },
+  {
+    "id": "15",
+    "unit": "第七单元认识时间",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "钟面上分针指向6，时针指向3和4之间，这时是( )。",
+    "options": [
+      "A. 3:30",
+      "B. 4:30",
+      "C. 3:06"
+    ],
+    "answer": "A",
+    "solution": "【分析】钟面上分针指向6，每个数字代表5分钟，因此分针指向6时表示时间为30分钟，时针指向3和4之间，说明时间在3点之后,4点之前，此时应该是3点，按照时针，分针对应的时间即可得出答案.\n【详解】A。3:30，时针指向3和4中间，分针指向6，符合题意;B。4:30，时针指向4和5中间，分针指向6，不符合题意;C。3:06，时针指向3，分针指向1，不符合题意。故答案为:A",
+    "knowledge_points": [
+      "整点时间与钟面指针的位置",
+      "半点时间与钟面指针的位置",
+      "一般时间与钟面指针的位置"
+    ],
+    "source": "24-25二年级下·湖南岳阳·期中"
+  },
+  {
+    "id": "16",
+    "unit": "第七单元认识时间",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "8:05也可以表示成( )。",
+    "options": [
+      "A. 8:05分",
+      "B. 8时50分",
+      "C. 8时5分"
+    ],
+    "answer": "C",
+    "solution": "【分析】时间的正确写法通常是几时几分，或者时和分中间用冒号隔开，例如8点5分可以写成\"8时5分\"或者简写为\"8:05\"，逐项分析.\n【详解】A。冒号后面加\"分\"是错误的;B。时间错误，是8时50分，明显不对;C。写法正确。8:05也可以表示成8时5分。故答案为:C",
+    "knowledge_points": [
+      "时，分的认识及换算"
+    ],
+    "source": "24-25二年级上·湖北荆州·期末"
+  },
+  {
+    "id": "17",
+    "unit": "第七单元认识时间",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "从9点整开始到10点整(包括9点整和10点整),手表的秒针指向12点处( )次。",
+    "options": [
+      "A. 59",
+      "B. 60",
+      "C. 61",
+      "D. 62"
+    ],
+    "answer": "C",
+    "solution": "【分析】明确秒针的运动规律：秒针每分钟转一圈，即每60秒转一圈，一圈后回到12点处。计算从9点整到10点整经过的分钟数：从9点整到10点整刚好经过1小时，因为1小时=60分钟。由于秒针每分钟都会转回到12点处一次，在这60分钟内，秒针会转60圈，所以秒针指向12点处60次。因为包括9点整和10点整这两个时刻，所以一共有61次.\n【详解】根据分析可得：从9点整开始到10点整，手表的秒针指向12点处61次。故答案为:C",
+    "knowledge_points": [
+      "整点时间与钟面指针的位置",
+      "时，分，秒有关的计算"
+    ],
+    "source": "24-25二年级上·浙江温州·期末"
+  },
+  {
+    "id": "18",
+    "unit": "第七单元认识时间",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "时钟上的分针从\"1\"走向\"7\"，过去了( )分钟。",
+    "options": [
+      "A. 25",
+      "B. 30",
+      "C. 35",
+      "D. 40"
+    ],
+    "answer": "B",
+    "solution": "【分析】钟面上分12个大格，每个大格5个小格，分针走一个大格是5分，分针从1走到7，走了7-1=6(大格)走过5×6=30(分钟).\n【详解】7-1=6(大格),5×6=30(分钟),即，时钟上的分针从\"1\"走向\"7\"，过去了30分钟。故答案为:B",
+    "knowledge_points": [
+      "6的乘法口诀及应用",
+      "时，分的认识及换算",
+      "时，分，秒有关的计算"
+    ],
+    "source": "24-25二年级上·浙江温州·期末"
+  },
+  {
+    "id": "19",
+    "unit": "第七单元认识时间",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "孙晓8:00吃完早餐,8:15到达了足球场，过了2小时少35分钟后从足球场出来，出来的时间是( )。",
+    "options": [
+      "A. 10:15",
+      "B. 10:50",
+      "C. 10:35",
+      "D. 9:40"
+    ],
+    "answer": "D",
+    "solution": "【分析】先求出孙晓在足球场的时间，再用到达足球场时刻加上在足球场的时间，就是从足球场出来的时刻.\n【详解】2小时-35分钟=1小时25分钟,8时15分+1小时25分钟=9时40分，孙晓从足球场出来的时间为9时40分。故答案为:D",
+    "knowledge_points": [
+      "时，分，秒时间的推算"
+    ],
+    "source": "24-25二年级上·浙江温州·期末"
+  },
+  {
+    "id": "20",
+    "unit": "第七单元认识时间",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "测量体育场上跑道的长度，一般用( )作单位。",
+    "options": [
+      "A. 厘米",
+      "B. 米",
+      "C. 时"
+    ],
+    "answer": "B",
+    "solution": "【分析】小学生两臂伸开的长度大约1米，大拇指的指甲长度大约1厘米，做一顿家常饭的时间大约是1小时，据此逐项分析.\n【详解】A。厘米太短，不合适;B。测量体育场上跑道的长度，用米作单位比较合适;C。时是时间单位，不合适。测量体育场上跑道的长度，一般用米作单位。故答案为:B",
+    "knowledge_points": [
+      "时，分的认识及换算",
+      "长度单位的选择"
+    ],
+    "source": "24-25二年级上·河南信阳·期末"
+  },
+  {
+    "id": "21",
+    "unit": "第七单元认识时间",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "周末，小光8:30吃完早餐，先去图书馆借书,10:00去少年宫练习乒乓球。他到图书馆的时间可能是( )。",
+    "options": [
+      "A. ![](images/1aebcf559bfdf8bd388049fcec28027339d38709c83f7067c5b602583d381952.jpg)",
+      "B. ![](images/b4b754140e9ecd314bcd39f3c520bb3a5084b46dbb3474de9bb6c04e5f1c9500.jpg)",
+      "C. ![](images/27d51e7b4e06448ce1229852633eba08706d6dd30930d707cb6422cbdeed16f0.jpg)"
+    ],
+    "answer": "C",
+    "solution": "【分析】由题意可知，小光8:30吃完早餐，先去图书馆借书,10:00去练习乒乓球，去图书馆的时间在8:30与10:00之间即可，据此解答.\n【详解】A。钟面显示的时间是8:20，没有在8:30与10:00之间，不符合题意;B。钟面显示的时间是10:00，此时在少年宫练习乒乓球，不符合题意;C。钟面显示的时间是8:50，在8:30与10:00之间，符合题意。故答案为:C",
+    "knowledge_points": [
+      "整点时间与钟面指针的位置",
+      "一般时间与钟面指针的位置"
+    ],
+    "source": "24-25二年级上·湖北武汉·期末"
+  },
+  {
+    "id": "22",
+    "unit": "第七单元认识时间",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "周末，明明早上7:30开始吃早餐，然后和爸爸一起去城南公园玩，上午11:30回家吃午饭。明明和爸爸可能在( )正在城南公园玩。",
+    "options": [
+      "A. 12:00",
+      "B. 10:00",
+      "C. 7:20"
+    ],
+    "answer": "B",
+    "solution": "【分析】由题意可知，周末，明明早上7:30开始吃早餐，然后和爸爸一起去城南公园玩，上午11:30回家吃午饭，问题是明明和爸爸可能什么时候正在城南公园玩，那么游玩时间只要在7:30与11:30之间，就是符合题意的，据此解答即可.\n【详解】A。12:00超过了11:30，不符合题意;B。10:00在7:30和11:30之间，符合题意;C。7:20比7:30要早，不符合题意;所以明明和爸爸可能在10:00正在城南公园玩。故答案为:B",
+    "knowledge_points": [
+      "时，分，秒时间的推算"
+    ],
+    "source": "24-25二年级上·贵州铜仁·期末"
+  },
+  {
+    "id": "23",
+    "unit": "第七单元认识时间",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "时针在7和8之间，分针指着9，此时的时间是( )。",
+    "options": [
+      "A. 7:09",
+      "B. 7:45",
+      "C. 7:50"
+    ],
+    "answer": "B",
+    "solution": "【分析】钟面上长针是分针，短针是时针，有12个大格，分针走1大格是5分钟，时针走1大格是1小时。时针在7和8之间，是7时;分针指向9，是5×9=45(分),由此解答.\n【详解】由分析可知：时针在7和8之间，分针指着9，此时的时间是7:45。故答案为:B",
+    "knowledge_points": [
+      "一般时间与钟面指针的位置"
+    ],
+    "source": "24-25二年级上·湖北黄冈·期末"
+  },
+  {
+    "id": "24",
+    "unit": "第七单元认识时间",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "星期天，小丽8:30开始写作业，然后跟爸爸去打羽毛球,11:30去奶奶家。小丽可能在( )打羽毛球。",
+    "options": [
+      "A. ![](images/7d9eb18c0a86154b42df9df7fb5524ee4c37b0d0be2cc606bacbd7071c171140.jpg)",
+      "B. ![](images/6f056fcd509e92fc0a3ba44f7d08d14f3d2cb2924f635a29c0c90de556eb82d6.jpg)",
+      "C. ![](images/b1829a3fae704772603e293ed1ba5da4f78db4f1ebbe6b678c8003ab77fb0755.jpg)"
+    ],
+    "answer": "B",
+    "solution": "【分析】由题意可知，小丽打羽毛球时间是8:30到11:30之间，逐项分析即可;对于分针，走过的数字格数乘5就是经过的分钟数;对于时针，看它走过的数字格数就能知道经过的小时数;同时要知道分针走一圈是60分钟即1小时，时针走一圈是12小时.\n【详解】A。时针走过了8个数字格，是8:00，分针走了2个数字格,2×5=10(分),合起来是8:10，不符合题意;B。时针走过了9个数字格，是9:00，分针走了11个数字格，是55分，合起来是9:55，符合题意;C。时针走过了11个数字格，是11:00，分针走了8个数字格,8×5=40(分)是11:40，不符合题意。故答案为:B",
+    "knowledge_points": [
+      "一般时间与钟面指针的位置",
+      "时，分，秒时间的推算"
+    ],
+    "source": "24-25二年级上·青海西宁·期末"
+  },
+  {
+    "id": "25",
+    "unit": "第七单元认识时间",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "钟面上分针走两圈是( )。",
+    "options": [
+      "A. 2分钟",
+      "B. 2小时",
+      "C. 2天"
+    ],
+    "answer": "B",
+    "solution": "【分析】钟面上长针是分针，短针是时针，有12个大格，分针走1大格是5分钟，走1圈是1小时，走两圈是2小时，据此解答.\n【详解】由分析可知，钟面上分针走两圈是2小时。故答案为:B",
+    "knowledge_points": [
+      "时，分的认识及换算",
+      "时，分，秒时间的推算"
+    ],
+    "source": "24-25二年级上·河南郑州·期末"
+  },
+  {
+    "id": "26",
+    "unit": "第七单元认识时间",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "分针从2走到8，走了( )。",
+    "options": [
+      "A. 6分",
+      "B. 6时",
+      "C. 30分"
+    ],
+    "answer": "C",
+    "solution": "【分析】对于分针，走过的数字格数乘5就是经过的分钟数;分针从2走到8，走了6个数字格，据此解答.\n【详解】根据分析可得:6×5=30(分),分针从2走到8，走了30分。故答案为:C",
+    "knowledge_points": [
+      "时，分，秒有关的计算"
+    ],
+    "source": "24-25二年级上·山东济宁·期末"
+  },
+  {
+    "id": "27",
+    "unit": "第七单元认识时间",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "教学楼大约高16( )。",
+    "options": [
+      "A. 米",
+      "B. 厘米",
+      "C. 分"
+    ],
+    "answer": "A",
+    "solution": "【分析】根据生活经验及结合给出的数据，来选择合适的单位。食指宽大约是1厘米，米尺的长度是1米，所以计量教学楼大约高用\"米\"作单位比较合适.\"分\"是时间单位，不是长度单位.\n【详解】A。教学楼大约高16米，符合实际情况;B。教学楼大约高16厘米，太矮了，不符合实际情况;C.\"分\"是时间单位，不是长度单位。故答案为:A",
+    "knowledge_points": [
+      "时，分的认识及换算",
+      "长度单位的选择"
+    ],
+    "source": "24-25二年级上·辽宁抚顺·期末"
+  },
+  {
+    "id": "28",
+    "unit": "第七单元认识时间",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "分针从6走到9，走了( )。",
+    "options": [
+      "A. 3时",
+      "B. 30分钟",
+      "C. 15分钟"
+    ],
+    "answer": "C",
+    "solution": "【分析】对于分针，走过的数字格数乘5就是经过的分钟数，分针从\"6\"走到\"9\"，走了3个数字格，每走一个数字格代表5分钟,3×5=15(分钟);据此解答.\n【详解】根据分析可得：分针从6走到9，走了15分钟。故答案为:C",
+    "knowledge_points": [
+      "时，分，秒有关的计算"
+    ],
+    "source": "24-25二年级上·湖南娄底·期末"
+  },
+  {
+    "id": "29",
+    "unit": "第七单元认识时间",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "周末，小明8:30开始做作业，做完作业后去踢球,11:30吃午饭。小明开始踢球的时间可能是( )。",
+    "options": [
+      "A. 8:00",
+      "B. 10:20",
+      "C. 11:45"
+    ],
+    "answer": "B",
+    "solution": "【分析】根据题意可知，小明踢球的时间应该是在8:30至11:30之间，由此找到合适的时间即可.\n【详解】A。小明还没有做作业，题目说写完作业后去踢球，不符合题意，答案错误;B。可能在踢球，符合题意，答案正确;C。正在吃饭或者刚吃完饭，不符合题意，答案错误。故答案为:B",
+    "knowledge_points": [
+      "时，分，秒时间的推算"
+    ],
+    "source": "24-25二年级上·湖北黄石·期末"
+  },
+  {
+    "id": "30",
+    "unit": "第七单元认识时间",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "一只蜻蜓的身长大约是8( );一节课40( )。",
+    "options": [
+      "A. 厘米;分",
+      "B. 米;米",
+      "C. 厘米;时"
+    ],
+    "answer": "A",
+    "solution": "【分析】根据对生活经验，长度单位，时间单位和数据大小的认识可知,1厘米大约是食指的宽度，所以计量一只蜻蜓的身长用\"厘米\"作单位比较合适;1分钟大约能写20个字，所以计量一节课用\"分\"作单位比较合适.\n【详解】一只蜻蜓的身长大约是8厘米;一节课40分。故答案为:A",
+    "knowledge_points": [
+      "时，分的认识及换算",
+      "时间单位的选择",
+      "厘米的认识",
+      "长度单位的选择"
+    ],
+    "source": "20-21二年级上·湖南长沙·期末"
+  },
+  {
+    "id": "31",
+    "unit": "第七单元认识时间",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下表是周二上午二(1)班的课程安排时间表.\n\n<table><tr><td>时间</td><td>8:30~9:10</td><td>9:20~10:00</td><td>10:10~10:50</td><td>11:00~11:40</td></tr><tr><td>课程</td><td>数学</td><td>足球</td><td>语文</td><td>音乐</td></tr></table>\n\n下面时间小文可能在踢球的是( )。",
+    "options": [
+      "A. ![](images/3cdaeffc639af26fdebe457853204ebd9e9f5892e44820975b6bacee78c4aba7.jpg)",
+      "B. ![](images/2510a65f26bf3f7bde77586f73ab8e7ac4a9405826b7d36c0d273741c8aec8ff.jpg)",
+      "C. ![](images/77e79defb305afb95ee5e843357516a5706e5fffb658dc48902dd7b61315bcc9.jpg)"
+    ],
+    "answer": "B",
+    "solution": "【分析】钟表上较长针是分针，短针是时针;分针指向12，时针指向几就是几时;分针指向6，时针刚过几就是几时半。时针走一大格是1时;分针走1小格是1分，走1大格是5分;秒针走1小格是1秒，走1大格是5秒。时针刚过几就是几时，分针指向第多少个小格就是多少分。据此写出每个时钟上的时间.\n【详解】A。时针指向9，分针指向1，则表示的是9:05，不在9:20-10:00之间，则不符合题意;B。时针指向9和10之间，分针指向11，则表示的是9:55，则在9:20-10:00之间，符合题意;C。时针指向10和11之间，分针指向9，则表示的是10:45，则超过10点，则不符合题意。故答案为:B",
+    "knowledge_points": [
+      "一般时间与钟面指针的位置"
+    ],
+    "source": "24-25二年级上·浙江杭州·期末"
+  },
+  {
+    "id": "32",
+    "unit": "第七单元认识时间",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下图中，钟面上的时间再过10分钟后是( ).\n\n![](images/dcd4072bd1c034d4d20dea7c963208ef78e12dcc15c48397f79a6d73ecde6c08.jpg)",
+    "options": [
+      "A. 2:10",
+      "B. 2:30",
+      "C. 2:50"
+    ],
+    "answer": "B",
+    "solution": "【分析】对于分针，走过的数字格数乘5就是经过的分钟数;对于时针，看它走过的数字格数就能知道经过的小时数;分针从\"12\"走到\"4\"，走了4个数字格，每走一个数字格代表5分,4×5=20(分);时针从\"12\"走到\"2\"，走了2个数字格，是2时，钟面的时间是2时20分，经过10分钟后的时间是原来的时间加10分即可.\n【详解】2时20分+10分=2时30分,2时30分也可以用2:30表示。故答案为:B",
+    "knowledge_points": [
+      "整点时间与钟面指针的位置",
+      "一般时间与钟面指针的位置",
+      "时，分，秒时间的推算"
+    ],
+    "source": "24-25二年级上·陕西延安·期末"
+  },
+  {
+    "id": "33",
+    "unit": "第七单元认识时间",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "图中，钟面显示的时间比正确时间快了5分钟，正确的时间是( ).\n\n![](images/c14263dd0f5d2455c4dd306a60e043a840e010e44f38034fa348e72324653e21.jpg)",
+    "options": [
+      "A. 8:05",
+      "B. 7:55",
+      "C. 11:35"
+    ],
+    "answer": "B",
+    "solution": "【分析】由图可知现在钟面显示的时间是8:00，因为比正确时间快了5分钟，所以用现在钟面时间减去5分钟，即为正确的时间.\n【详解】8:00-5分=7:55，正确的时间是7:55。故答案为:B",
+    "knowledge_points": [
+      "整点时间与钟面指针的位置",
+      "时，分，秒时间的推算"
+    ],
+    "source": "24-25二年级上·浙江台州·期末"
+  },
+  {
+    "id": "34",
+    "unit": "第七单元认识时间",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "请你根据以下信息填一填，画一画。果果星期六去老师家学古筝。她8:25到达老师家，这时离上课还有( )分钟。这节课1小时，下课时间是( ).\n\n![](images/b98752929a39c175406745819cc7e8e8f4baaf72ea81dd81a585ec6e534705c4.jpg)",
+    "options": [],
+    "answer": "5;9时30分",
+    "solution": "【分析】确定开始上课时间：根据图片中\"开始上课\"的钟表，时针指向8和9之间，分针指向6，此时时间为8时30分。计算到达时离上课的时间：果果8时25分到达，上课时间为8时30分，两者相差5分钟。计算下课时间：课程时长1小时，从8:30开始上课，下课时间为8时30分+1小时=9时30分.\n【详解】(1)30 - 25 = 5(分钟);(2)8时30分+1小时=9时30分。果果8:25到达老师家，这时离上课还有5分钟。这节课1小时，下课时间是9时30分。",
+    "knowledge_points": [
+      "时，分，秒时间的推算"
+    ],
+    "source": "24-25三年级上·福建漳州·期中"
+  },
+  {
+    "id": "35",
+    "unit": "第七单元认识时间",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "分针从4走到8，走了( )分钟。",
+    "options": [],
+    "answer": "20",
+    "solution": "【分析】分针在钟面上每走1个大格是5分钟。从4走到8，经过4个大格，用乘法计算总时间即可.\n【详解】8-4=4(大格),4×5=20(分钟),所以分针从4走到8，走了20分钟。",
+    "knowledge_points": [
+      "时，分，秒有关的计算"
+    ],
+    "source": "25-26二年级上·陕西咸阳·月考"
+  },
+  {
+    "id": "36",
+    "unit": "第七单元认识时间",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "时针从12走到4是( )时，分针从10到12是( )分。",
+    "options": [],
+    "answer": "4;10",
+    "solution": "【分析】钟面上有12个大格，时针每走1个大格是1小时。时针从12走到4，共经过4个大格。分针每走1个大格是5分钟。分针从10走到12，经过2个大格，就是2个5分钟.\n【详解】5×2=10(分),所以时针从12走到4是4时，分针从10到12是10分。",
+    "knowledge_points": [
+      "时，分的认识及换算"
+    ],
+    "source": "25-26三年级上·福建莆田·阶段练习"
+  },
+  {
+    "id": "37",
+    "unit": "第七单元认识时间",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "3:30时，钟面上时针和分针组成的角是( )角;( )时整或( )时整，时针和分针的夹角是直角。",
+    "options": [],
+    "answer": "锐;3;9",
+    "solution": "【分析】3:30时，分针指向6，时针指向3和4的中间，时针和分针组成的角比直角小，是锐角;分针指向12，时针指向3或9时，时针和分针的夹角是直角.\n【详解】3:30时，钟面上时针和分针组成的角是锐角;3时整或9时整，时针和分针的夹角是直角。",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征",
+      "整点时间与钟面指针的位置",
+      "半点时间与钟面指针的位置"
+    ],
+    "source": "2025·河北石家庄·小升初真题"
+  },
+  {
+    "id": "38",
+    "unit": "第七单元认识时间",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "钟面上时针从数字3走到数字6，经过了( )小时。",
+    "options": [],
+    "answer": "3",
+    "solution": "【分析】钟面12个数字把钟面分成12大格，时针走一大格是1小时，走一圈12大格就是12小时。据此计算出时针走了几格，即经过了几小时.\n【详解】6-3=3(格),所以钟面上时针从数字3走到数字6，经过了3小时。",
+    "knowledge_points": [
+      "时，分的认识及换算"
+    ],
+    "source": "24-25二年级下·黑龙江佳木斯·期末"
+  },
+  {
+    "id": "39",
+    "unit": "第七单元认识时间",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "时针从12走到2，经过的时间是( )时;分针从12走到5，经过的时间是( )分。",
+    "options": [],
+    "answer": "2;25",
+    "solution": "【分析】钟面上长针是分针，短针是时针，时针走一大格是1小时，分针走1小格是1分，走1大格是5分，据此解答.\n【详解】时针从12走到2，走了2大格，经过的时间是2时;分针从12走到5，走了5大格，经过的时间是5×5=25分。",
+    "knowledge_points": [
+      "时，分，秒有关的计算"
+    ],
+    "source": "24-25二年级下·天津静海·期末"
+  },
+  {
+    "id": "40",
+    "unit": "第七单元认识时间",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "林林6:58从家出发去学校,33分后到达，林林到学校的时间是( )。",
+    "options": [],
+    "answer": "7:31",
+    "solution": "【分析】根据题意可知，林林从家出发去学校的时间加上到达时用的时间，等于林林到学校的时间，据此解答.\n【详解】6时58分+33分=7时31分，林林到学校的时间是7:31。",
+    "knowledge_points": [
+      "时，分，秒时间的推算"
+    ],
+    "source": "24-25二年级下·广东揭阳·期末"
+  },
+  {
+    "id": "41",
+    "unit": "第七单元认识时间",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "200厘米=( )米,1时=( )分，半小时=( )分。",
+    "options": [],
+    "answer": "2;60;30",
+    "solution": "【分析】根据1米=100厘米,1时=60分进行单位换算即可.\n【详解】1米=100厘米，所以200厘米=2米;1时=60分;1时=60分，所以半小时=30分。",
+    "knowledge_points": [
+      "时，分的认识及换算",
+      "厘米和米之间的进率与换算"
+    ],
+    "source": "23-24二年级上·新疆乌鲁木齐·期末"
+  },
+  {
+    "id": "42",
+    "unit": "第七单元认识时间",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "在括号里填上合适的单位。篮球场长28( );数学书长约26( );妈妈一天工作约8( );一节数学课的时间是40( )。",
+    "options": [],
+    "answer": "米或m;厘米或cm;小时或h;分钟或min",
+    "solution": "【分析】米尺的长度是1米，所以计量篮球场的长用\"米\"作单位比较合适;大拇指的宽度大约是1厘米，所以数学书的长用\"厘米\"作单位比较合适;计量较长的时间用\"小时\"作单位，妈妈一天工作的时间较长，用\"小时\"作单位比较合适;1分钟心脏大约跳80下，所以计量一节课的时间用\"分钟\"作单位比较合适.\n【详解】篮球场长28米，数学书长约26厘米，妈妈一天工作约8小时，一节数学课的时间是40分钟。",
+    "knowledge_points": [
+      "时间单位的选择",
+      "长度单位的选择"
+    ],
+    "source": "23-24二年级上·新疆乌鲁木齐·期末"
+  },
+  {
+    "id": "43",
+    "unit": "第七单元认识时间",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "分针从12旋转到6经过的时间是( )分。",
+    "options": [],
+    "answer": "30",
+    "solution": "【分析】钟面上分针走1小格是1分，走1大格是5分，先数出分针走了几格，再乘5分，即可求出经过的时间.\n【详解】分针走了6大格，即经过的时间为6×5=30分，因此，分针从12旋转到6经过的时间是30分。",
+    "knowledge_points": [
+      "时，分的认识及换算"
+    ],
+    "source": "22-23二年级下·新疆乌鲁木齐·期中"
+  },
+  {
+    "id": "44",
+    "unit": "第七单元认识时间",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "分针从3走到6是( )分;时针从5走到9是( )时。",
+    "options": [],
+    "answer": "15;4",
+    "solution": "【分析】分针走1大格是5分，时针走1大格是1时;先用减法求出分针和时针分别走了几大格，然后用乘法求出时针和分针分别走了几分和几时.\n【详解】6 - 3 = 3(大格),3×5 = 15(分);9 - 5 = 4(大格),1×4 = 4(时)。分针从3走到6是15分;时针从5走到9是4时。",
+    "knowledge_points": [
+      "5的乘法口诀及应用",
+      "4的乘法口诀及应用",
+      "时，分的认识及换算",
+      "时，分，秒有关的计算"
+    ],
+    "source": "23-24二年级上·新疆乌鲁木齐·期末"
+  },
+  {
+    "id": "45",
+    "unit": "第七单元认识时间",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "钟面上，时针指向3和4之间，分针指向6，此时钟面上的时间是( ),再过一刻是( )。",
+    "options": [],
+    "answer": "3:30;3:45",
+    "solution": "【分析】时针指向3和4之间，所以是3时，分针指向6，钟面所显示的时刻是3:30。一刻是15分钟，据此用现在的时刻+15分钟，即可得出答案.\n【详解】钟面上，时针指向3和4之间，分针指向6，此时钟面上的时间是3:30.3:30+15=3:45，所以再过一刻是3:45。",
+    "knowledge_points": [
+      "半点时间与钟面指针的位置",
+      "时，分，秒时间的推算"
+    ],
+    "source": "24-25二年级下·贵州铜仁·期末"
+  },
+  {
+    "id": "46",
+    "unit": "第七单元认识时间",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "分针从3走到7，经过了( )分钟，时针从12走到2，经过了( )小时。",
+    "options": [],
+    "answer": "20;2",
+    "solution": "【分析】钟面上长针是分针，短针是时针，有12个大格，分针走1大格是5分钟，时针走1大格是1小时，由此先计算出分针和时针经过了几个大格，再计算出经过的时间即可.\n【详解】7 - 3 = 4(个),分针走了4个大格,4×5 = 20(分钟);时针从12走到2，走了2个大格,2×1 = 2(小时)。分针从3走到7，经过了20分钟，时针从12走到2，经过了2小时。",
+    "knowledge_points": [
+      "时，分，秒有关的计算"
+    ],
+    "source": "23-24二年级下·云南曲靖·期末"
+  },
+  {
+    "id": "47",
+    "unit": "第七单元认识时间",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "笑笑早上8:20到校，中午11:20放学回到家，经过了( )时。",
+    "options": [],
+    "answer": "3",
+    "solution": "【分析】根据经过时间=结束时间-开始时间，计算即可.\n【详解】8:20即8时20分;11:20即11时20分;11时20分-8时20分=3时。笑笑早上8:20到校，中午11:20放学回到家，经过了3时。",
+    "knowledge_points": [
+      "时，分，秒有关的计算"
+    ],
+    "source": "23-24二年级下·广东韶关·期末"
+  },
+  {
+    "id": "48",
+    "unit": "第七单元认识时间",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "200米赛跑中，小红用时1分50秒，小英用时100秒，小云用时103秒，三人中( )跑得最快,( )跑得最慢。",
+    "options": [],
+    "answer": "小英;小红",
+    "solution": "【分析】由题意可知：把三个人用的时间先统一单位\"秒\"，再比较大小，谁用的时间少谁跑得最快，谁用的时间多谁跑得最慢.\n【详解】小红:1分50秒=60秒+50秒=110秒;小英:100秒;小云:103秒。110 > 103 > 100，三人中小英跑得最快，小红跑得最慢。",
+    "knowledge_points": [
+      "时，分的认识及换算",
+      "时间快慢的比较"
+    ],
+    "source": "23-24二年级下·重庆潼南·期末"
+  },
+  {
+    "id": "49",
+    "unit": "第七单元认识时间",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "1米-15厘米=( )厘米;1小时=( )分;45厘米+8厘米=( )厘米;6米+49米=( )米。",
+    "options": [],
+    "answer": "85;60;53;55",
+    "solution": "【分析】单位相同的直接相加减，单位不同的根据1米=100厘米,1小时=60分统一单位再计算即可.\n【详解】1米-15厘米=100厘米-15厘米=85厘米;1小时=60分;45厘米+8厘米=53厘米;6米+49米=55米。",
+    "knowledge_points": [
+      "时，分的认识及换算",
+      "厘米和米之间的进率与换算"
+    ],
+    "source": "23-24二年级下·湖北黄冈·期末"
+  },
+  {
+    "id": "50",
+    "unit": "第七单元认识时间",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "如图，当分针从12旋转到如图这个位置时，至少经过了( )分.\n\n![](images/a499d578b7ad7ad1b7fb28366f147360e83e46e1478d305853d44d67b319238a.jpg)",
+    "options": [],
+    "answer": "45",
+    "solution": "【分析】钟面上较短的针是时针，较长的针是分针。分针走1小格是1分，走1大格是5分。分针从12旋转到9，至少需要走9大格，用9乘5即可求解.\n【详解】9×5=45(分),如图，当分针从12旋转到如图这个位置时，至少经过了45分。",
+    "knowledge_points": [
+      "9的乘法口诀及应用",
+      "一般时间与钟面指针的位置"
+    ],
+    "source": "24-25二年级下·浙江杭州·期中"
+  },
+  {
+    "id": "51",
+    "unit": "第七单元认识时间",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "钟面上有( )大格,( )个小格，时针走一大格是( )小时，分针走一小格是( )分，走一大格是( )分。时针走一大格，分针正好走( )圈。分针走一圈正好是( )小时。",
+    "options": [],
+    "answer": "12;60;1;1;5;1;1",
+    "solution": "【分析】钟面上长针是分针，短针是时针，有12个大格，每个大格里有5个小格，也就是一共有60个小格。分针走1小格是1分钟，走1大格是5分钟;时针走1大格是1小时,1小时=60分，也就是时针走1大格，分针要走60个小格，也就是一圈.\n【详解】钟面上有12大格,60个小格，时针走一大格是1小时，分针走一小格是1分，走一大格是5分。时针走一大格，分针正好走1圈。分针走一圈正好是1小时。",
+    "knowledge_points": [
+      "时，分的认识及换算"
+    ],
+    "source": "24-25二年级下·河南许昌·开学考试"
+  },
+  {
+    "id": "52",
+    "unit": "第七单元认识时间",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "在括号里填上\">\"\"<\"或\"=\"。32 + 46( )70;76 - 47( )77 - 47;30分( )半小时;4×4( )4 + 4;56厘米( )1米 - 44厘米;8时( )90分。",
+    "options": [],
+    "answer": ">;<;=;>;=;>",
+    "solution": "【分析】根据题意，依次计算出各算式的结果再比较大小。长度单位的题目根据1米=100厘米换算单位再计算比较;时间单位的题目根据1时=60分换算单位再比较.\n【详解】32 + 46 = 78,78 > 70;76 - 47 = 29,77 - 47 = 30,29 < 30;30分 = 半小时;4×4 = 16,4 + 4 = 8,16 > 8;1米 = 100厘米,100厘米 - 44厘米 = 56厘米，所以56厘米 = 1米 - 44厘米;8时 = 8×60 = 480分,480 > 90分，故8时 > 90分。",
+    "knowledge_points": [
+      "两位数与两位数的退位减法",
+      "4的乘法口诀及应用",
+      "时，分的认识及换算",
+      "厘米和米之间的进率与换算"
+    ],
+    "source": "24-25二年级上·河南信阳·期末"
+  },
+  {
+    "id": "53",
+    "unit": "第七单元认识时间",
+    "question_type": "填空题",
+    "difficulty": 0.94,
+    "question": "( )时 = 60分;1米 = ( )厘米;( )刻 = 15分。",
+    "options": [],
+    "answer": "1;100;1",
+    "solution": "【分析】60分钟就是1个小时,100厘米就是1米长,15分钟就是一刻，据此填空.\n【详解】1时 = 60分;1米 = 100厘米;1刻 = 15分。",
+    "knowledge_points": [
+      "时，分的认识及换算",
+      "厘米和米之间的进率与换算"
+    ],
+    "source": "24-25二年级上·河南信阳·期末"
+  },
+  {
+    "id": "54",
+    "unit": "第七单元认识时间",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "在( )里填上\">\"\"<\"或\"=\"。14 + 20( )41 + 20;60 + 19( )9×6;1米( )37厘米 + 63厘米;5 + 5( )5×5;4×6 - 5( )3×6 + 6;1小时( )100分。",
+    "options": [],
+    "answer": "<;>;=;<;<;<",
+    "solution": "【分析】整数的大小比较时，位数多的数大;位数相同，从高位开始比较。含有算式的可以先算出结果;1米=100厘米,1时=60分，单位不统一先统一再比.\n【详解】14 + 20 = 34,41 + 20 = 61，所以34 < 61;60 + 19 = 79,9×6 = 54，所以79 > 54;37厘米 + 63厘米 = 100厘米 = 1米，所以1米 = 37厘米 + 63厘米;5 + 5 = 10,5×5 = 25，所以10 < 25;4×6 - 5 = 24 - 5 = 19,3×6 + 6 = 18 + 6 = 24，所以19 < 24;1小时 = 60分 < 100分。",
+    "knowledge_points": [
+      "100以内数的比大小",
+      "5的乘法口诀及应用",
+      "9的乘法口诀及应用",
+      "时，分的认识及换算"
+    ],
+    "source": "24-25二年级上·浙江嘉兴·期末"
+  },
+  {
+    "id": "55",
+    "unit": "第七单元认识时间",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "钟面上，分针从5走到10，走了( )分钟。时针从12开始绕了一圈又走回12，走了( )时。",
+    "options": [],
+    "answer": "25;12",
+    "solution": "【分析】钟面上长针是分针，短针是时针，有12个大格，分针走1大格是5分钟，时针走1大格是1小时。先计算走了几个大格，再换算成时间.\n【详解】分针从5走到10，走了5个大格,5×5=25分钟;时针绕一圈走了12个大格，是12小时。",
+    "knowledge_points": [
+      "时，分，秒有关的计算"
+    ],
+    "source": "24-25二年级上·浙江嘉兴·期末"
+  },
+  {
+    "id": "56",
+    "unit": "第七单元认识时间",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "分针从12走到6，走了( )分;时针从6走到10，走了( )时。",
+    "options": [],
+    "answer": "30;4",
+    "solution": "【分析】分针每走两个相邻数字之间为5分钟，分针从12走到6，经过6个间隔，每个间隔5分钟，因此总时间为6×5=30分;时针每走一个数字代表1小时，时针从6走到10，经过4个数字，因此总时间为4时.\n【详解】分针从12走到6，走了30分;时针从6走到10，走了4时。",
+    "knowledge_points": [
+      "时，分，秒有关的计算"
+    ],
+    "source": "24-25二年级上·河南南阳·期末"
+  },
+  {
+    "id": "57",
+    "unit": "第七单元认识时间",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "时针从2走到7，走了( )时。分针从12走到5，走了( )分。",
+    "options": [],
+    "answer": "5;25",
+    "solution": "【分析】钟面上长针是分针，短针是时针，有12个大格，分针走1大格是5分钟，时针走1大格是1小时，由此先计算出走了几个大格，再用乘法计算出经过的时间即可.\n【详解】时针从2走到7，走了5个大格,5×1=5时;分针从12走到5，走了5个大格,5×5=25分。",
+    "knowledge_points": [
+      "5的乘法口诀及应用",
+      "时，分的认识及换算"
+    ],
+    "source": "24-25二年级上·贵州黔南·期末"
+  },
+  {
+    "id": "58",
+    "unit": "第七单元认识时间",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "星期六，露露8:00开始吃早点，然后和外婆一起去公园,11:00离开公园，她们可能在( )到的公园。",
+    "options": [],
+    "answer": "9:00",
+    "solution": "【分析】由题意可知，星期六，露露8:00开始吃早点，然后和外婆一起去公园,11:00离开公园，问题是她们可能什么时候到公园，只要时间在8:00与11:00之间，就是符合题意的.\n【详解】例如9:00在8:00与11:00之间，所以她们可能在9:00到的公园。",
+    "knowledge_points": [
+      "时，分，秒时间的推算"
+    ],
+    "source": "24-25二年级上·河南三门峡·期末"
+  },
+  {
+    "id": "59",
+    "unit": "第七单元认识时间",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "在括号里填上\">\"\"<\"或\"=\"。34( )17 + 18;40 - 25( )16;5×5( )3×8;2时( )60分;30厘米( )3米;40厘米 + 60厘米( )1米。",
+    "options": [],
+    "answer": "<;<;>;>;<;=",
+    "solution": "【分析】先计算出各算式的答案然后再比较大小。单位不统一时，根据1时=60分,1米=100厘米统一单位再比较.\n【详解】17 + 18 = 35,34 < 35;40 - 25 = 15 < 16;5×5 = 25 > 24 = 3×8;2时 = 120分 > 60分;3米 = 300厘米 > 30厘米;40厘米 + 60厘米 = 100厘米 = 1米。",
+    "knowledge_points": [
+      "两位数与两位数的进位加法",
+      "8的乘法口诀及应用",
+      "时，分的认识及换算",
+      "厘米和米之间的进率与换算"
+    ],
+    "source": "24-25二年级上·河南三门峡·期末"
+  },
+  {
+    "id": "60",
+    "unit": "第七单元认识时间",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "钟面上，时针从\"12\"走到\"7\"，走了( )时;分针从\"2\"走到\"9\"，走了( )分。",
+    "options": [],
+    "answer": "7;35",
+    "solution": "【分析】时针从\"12\"走到\"7\"，每个数字代表1小时，共经过7个数字，因此走了7小时;分针从\"2\"走到\"9\"，每个数字代表5分钟，共经过7个数字，因此走了7×5=35分钟.\n【详解】钟面上，时针从\"12\"走到\"7\"，走了7时;分针从\"2\"走到\"9\"，走了35分。",
+    "knowledge_points": [
+      "时，分，秒有关的计算"
+    ],
+    "source": "24-25二年级上·浙江台州·期末"
+  },
+  {
+    "id": "61",
+    "unit": "第七单元认识时间",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "时针从12走到4走了( )小时，分针从12走到4走了( )分钟。",
+    "options": [],
+    "answer": "4;20",
+    "solution": "【分析】时针部分：时针每走一个数字代表1小时，从12走到4，共经过4个数字间隔，因此走了4小时。分针部分：分针每走一个数字代表5分钟，从12走到4，经过4个数字间隔，因此走了4×5=20分钟.\n【详解】时针从12走到4走了4小时;分针从12走到4走了20分钟。",
+    "knowledge_points": [
+      "时，分，秒有关的计算"
+    ],
+    "source": "24-25二年级上·浙江温州·期末"
+  },
+  {
+    "id": "62",
+    "unit": "第七单元认识时间",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "在括号里填上\">\"\"<\"或\"=\"。33 + 17( )64 - 15;7×8( )6×8 + 8;5 + 5( )5×5;1时( )60分。",
+    "options": [],
+    "answer": ">;=;<;=",
+    "solution": "【分析】先计算出每一个算式的得数或统一单位，然后比较大小即可。1时=60分.\n【详解】33 + 17 = 50,64 - 15 = 49，所以50 > 49;7×8 = 56,6×8 + 8 = 48 + 8 = 56，所以相等;5 + 5 = 10 < 25 = 5×5;1时 = 60分。",
+    "knowledge_points": [
+      "100以内数的比大小",
+      "8的乘法口诀及应用",
+      "时，分的认识及换算",
+      "表内乘加，乘减"
+    ],
+    "source": "24-25二年级上·浙江温州·期末"
+  },
+  {
+    "id": "63",
+    "unit": "第七单元认识时间",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "填上合适的单位：学校里课间休息时间为10( ),小明身高125( )。",
+    "options": [],
+    "answer": "分钟或min;厘米或cm",
+    "solution": "【分析】1节课是45分钟，所以计量课间休息的时间用\"分钟\"作单位比较合适;1厘米大约是1个指甲盖的宽度，所以计量小明的身高用\"厘米\"作单位比较合适.\n【详解】学校里课间休息时间为10分钟，小明身高125厘米。",
+    "knowledge_points": [
+      "时间单位的选择",
+      "长度单位的选择"
+    ],
+    "source": "24-25二年级上·云南保山·期末"
+  },
+  {
+    "id": "64",
+    "unit": "第七单元认识时间",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "在括号里填上\">\"\"<\"或\"=\"。4×9( )6×7;3×6( )2×9;56 + 7( )8×7;2时( )150分;1米( )95厘米;86 - 7 - 23( )86 -(7 + 23)。",
+    "options": [],
+    "answer": "<;=;>;<;>;=",
+    "solution": "【分析】先计算出各算式的答案，然后比较大小即可。先将单位换算统一然后再比较大小,1时=60分,1米=100厘米.\n【详解】4×9 = 36 < 42 = 6×7;3×6 = 18 = 2×9;56 + 7 = 63 > 56 = 8×7;2时 = 120分 < 150分;1米 = 100厘米 > 95厘米;86 - 7 - 23 = 79 - 23 = 56,86 - (7 + 23) = 86 - 30 = 56，相等。",
+    "knowledge_points": [
+      "100以内数的加减混合运算",
+      "9的乘法口诀及应用",
+      "时，分的认识及换算"
+    ],
+    "source": "24-25二年级上·湖北武汉·期末"
+  },
+  {
+    "id": "65",
+    "unit": "第七单元认识时间",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "钟面上，分针从12走到7，走了( )分，时针从3走到10，走了( )时。",
+    "options": [],
+    "answer": "35;7",
+    "solution": "【分析】钟面上被平均分成12个大格,60个小格，时针走1大格是1时，分针走1大格是5分钟。分针从12走到7，走了7个大格，是7×5分;时针从3走到10，走了10 - 3 = 7个大格，是7×1时.\n【详解】7×5 = 35分;7×1 = 7时。所以分针从12走到7，走了35分，时针从3走到10，走了7时。",
+    "knowledge_points": [
+      "7的乘法口诀及应用",
+      "时，分的认识及换算",
+      "时，分，秒有关的计算"
+    ],
+    "source": "24-25二年级上·湖北武汉·期末"
+  },
+  {
+    "id": "66",
+    "unit": "第七单元认识时间",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "学校组织春游，路上用了45分钟,9:00到达目的地，队伍最晚是( )时( )分出发。",
+    "options": [],
+    "answer": "8;15",
+    "solution": "【分析】根据结束时间-经过时间=开始时间，计算即可.\n【详解】9:00是9时。9时-45分=8时15分。学校组织春游，路上用了45分钟,9:00到达目的地，队伍最晚是8时15分出发。",
+    "knowledge_points": [
+      "时，分，秒时间的推算"
+    ],
+    "source": "24-25二年级上·四川乐山·期末"
+  },
+  {
+    "id": "67",
+    "unit": "第七单元认识时间",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "小红晚上9点睡觉，爸爸比她晚睡1小时，爸爸睡觉的时间是( )点。",
+    "options": [],
+    "answer": "10",
+    "solution": "【分析】结束时间=开始时间+经过时间，用小红睡觉的时间加上爸爸比她晚睡的1小时即可.\n【详解】9时+1时=10时。小红晚上9点睡觉，爸爸比她晚睡1小时，爸爸睡觉的时间是10点。",
+    "knowledge_points": [
+      "时，分，秒时间的推算"
+    ],
+    "source": "24-25一年级上·河北沧州·期末"
+  },
+  {
+    "id": "68",
+    "unit": "第七单元认识时间",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "在( )里填上\">\"\"<\"或\"=\"。1时( )100分;2米( )20厘米;△ + △( )△*3 - △。",
+    "options": [],
+    "answer": "<;>;=",
+    "solution": "【分析】1时=60分,1米=100厘米，统一单位后进行比较。第三题根据乘法的意义解答,△*3表示3个△的和，减去1个△就是2个△的和，可以列式为△ + △.\n【详解】1时 = 60分，所以1时 < 100分;2米 = 200厘米 > 20厘米，所以2米 > 20厘米;△*3 - △ = 2*△,△ + △ = 2*△,所以△ + △ = △*3 - △。",
+    "knowledge_points": [
+      "初步认识乘法意义",
+      "时，分的认识及换算",
+      "厘米和米之间的进率与换算"
+    ],
+    "source": "24-25二年级上·福建龙岩·期末"
+  },
+  {
+    "id": "69",
+    "unit": "第七单元认识时间",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "钟面上,9时整，时针和分针形成的角是( )角;2时整，时针和分针形成的角是( )角;5时整，时针和分针形成的角是( )角。",
+    "options": [],
+    "answer": "直;锐;钝",
+    "solution": "【分析】在三角板上，最大角就是直角，锐角比直角小，钝角比直角大。9时整，分针指向12，时针指向9，时针和分针形成的角是直角;2时整，分针指向12，时针指向2，时针和分针形成的角是锐角;5时整，分针指向12，时针指向5，时针和分针形成的角是钝角.\n【详解】钟面上,9时整，时针和分针形成的角是直角;2时整是锐角;5时整是钝角。",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征",
+      "整点时间与钟面指针的位置"
+    ],
+    "source": "24-25二年级上·浙江温州·期末"
+  },
+  {
+    "id": "70",
+    "unit": "第七单元认识时间",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "一节课的时间是40( );小学生每天要睡够10( );一本书的长度是18( )。",
+    "options": [],
+    "answer": "分钟或分或min;时或小时或h;厘米或cm",
+    "solution": "【分析】根据生活经验以及数据的大小，选择合适的计量单位来解决此题。表示较短的时间时，一般选择\"分钟\"作单位，如：一节课的时间是40分钟;表示较长的时间时，一般选择\"小时\"作单位，如小学生每天要睡够10小时;食指宽大约是1厘米，所以，计量一本书的长度用\"厘米\"作单位比较合适.\n【详解】一节课的时间是40分，小学生每天要睡够10小时;一本书的长度是18厘米。",
+    "knowledge_points": [
+      "时间单位的选择",
+      "长度单位的选择"
+    ],
+    "source": "24-25二年级上·四川乐山·期末"
+  },
+  {
+    "id": "71",
+    "unit": "第七单元认识时间",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "在括号里填上合适的单位。小刚早上7( )起床，洗漱15( )后，去吃一根约20( )长的油条，喝了一杯10( )高的牛奶杯装的牛奶，接着步行15( )到学校，看到学校的旗杆高约10( ),他开心地走进教室，准备开始一天的学习。",
+    "options": [],
+    "answer": "时;分或分钟或min;厘米或cm;厘米或cm;分或分钟或min;米或m",
+    "solution": "【分析】根据生活经验，对长度单位，时间单位和数据大小的认识可知：早上一般7时起床;计量比较短的时间，常用分(min)作单位，所以洗漱的时间，步行到学校的时间用分作单位比较合适;计量比较短的物体长度通常用厘米(cm)作单位，食指宽大约是1厘米，所以计量油条的长度，牛奶的高度用厘米作单位比较合适;计量较长的物体用米(m)作单位，二年级学生双臂展开的长度大约是1米，所以计量旗杆的高度用米作单位比较合适.\n【详解】小刚早上7时起床，洗漱15分后，去吃一根约20厘米长的油条，喝了一杯10厘米高的牛奶杯装的牛奶，接着步行15分到学校，看到学校的旗杆高约10米。",
+    "knowledge_points": [
+      "时间单位的选择",
+      "长度单位的选择"
+    ],
+    "source": "24-25二年级上·湖南株洲·期末"
+  },
+  {
+    "id": "72",
+    "unit": "第七单元认识时间",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "时针指在4和5之间，分针指着9，这时的时间是( ),过一刻是( )。",
+    "options": [],
+    "answer": "4时45分或4:45;5时或5:00",
+    "solution": "【分析】钟面上长针是分针，短针是时针。有12个大格，分针走1大格是5分钟，时针走1大格是1小时。一刻是15分钟，过一刻的时间=现在的时间+15分.\n【详解】分针指向9，是45分，时针在4和5之间，是4时，则表示的时间是4时45分，也可以写作4:45.4时45分+15分=5时，也可以写作5:00。",
+    "knowledge_points": [
+      "一般时间与钟面指针的位置",
+      "时，分，秒时间的推算"
+    ],
+    "source": "24-25二年级上·湖南湘西·期末"
+  },
+  {
+    "id": "73",
+    "unit": "第七单元认识时间",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "时针从12走到6，走了( )时;分针从12走到3，走了( )分。分针从12绕一圈走回到12，是( )分，也就是( )小时。",
+    "options": [],
+    "answer": "6;15;60;1",
+    "solution": "【分析】钟面上较短的针是时针，较长的针是分针。时针走一大格是1时;分针走1大格是5分。时针从12走到6，走了6大格;分针从12走到3，走了3大格.\n【详解】3×5 = 15(分),时针从12走到6，走了6时;分针从12走到3，走了15分。分针从12绕一圈走回到12，是60分，也就是1小时。",
+    "knowledge_points": [
+      "时，分的认识及换算"
+    ],
+    "source": "23-24二年级上·湖南长沙·期末"
+  },
+  {
+    "id": "74",
+    "unit": "第七单元认识时间",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "时针从4走到7，过了( )时。",
+    "options": [],
+    "answer": "3",
+    "solution": "【分析】钟面上较短的针是时针，较长的针是分针。时针走一大格是1时。时针从4走到7，经过的数字差就是经过的小时数.\n【详解】7-4=3(大格),时针从4走到7，过了3时。",
+    "knowledge_points": [
+      "时，分的认识及换算"
+    ],
+    "source": "24-25二年级上·湖南长沙·期末"
+  },
+  {
+    "id": "75",
+    "unit": "第七单元认识时间",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "钟面上，分针走1小格是( )分，时针走1大格是( )时;时针从4走到5，分针正好走了( )圈，也就是( )分。",
+    "options": [],
+    "answer": "1;1;1;60",
+    "solution": "【分析】根据钟面上分针，时针的走动规律解答.\n【详解】钟面上，分针走1小格是1分，时针走1大格是1时;时针从4走到5，刚好1小时，分针正好走了1圈，也就是60分。",
+    "knowledge_points": [
+      "时，分的认识及换算"
+    ],
+    "source": "24-25二年级上·河南郑州·期末"
+  },
+  {
+    "id": "76",
+    "unit": "第七单元认识时间",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "如图，钟面上的时间是( ),再过一刻是( ),分针这一刻钟走过的区域形成的角是( )角.\n\n![](images/f7d800883f5aaf252b558bf30a1717ef67a4a852985dc2f1734033a6b9eaee80.jpg)",
+    "options": [],
+    "answer": "4:15或4时15分;4:30或4时30分;直",
+    "solution": "【分析】钟面上长针是分针，短针是时针。有12个大格，分针走1大格是5分钟，时针走1大格是1小时。再过一刻，也就是再过15分，用现在的时间+15分计算即可;与书本，黑板的角相同大小的是直角.\n【详解】分针指向3，时针指向4和5之间，是4时15分，也写作4:15.4时15分+15分=4时30分，也写作4:30。分针这一刻钟走过的区域从3走到6，形成一个直角。",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征",
+      "一般时间与钟面指针的位置",
+      "时，分，秒时间的推算"
+    ],
+    "source": "24-25二年级上·河南郑州·期末"
+  },
+  {
+    "id": "77",
+    "unit": "第七单元认识时间",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "在括号里填上合适的单位。小景是二年级的小朋友，他的身高是120( ),他的房间长约5( )。周末他和同学步行到星光电影院，大约用时20( ),他们一起看了一场时长为2( )的电影。",
+    "options": [],
+    "answer": "厘米或cm;米或m;分钟或min或分;小时或时",
+    "solution": "【分析】结合经验及数据大小选择合适单位。计量较短的物体，用\"厘米\"作单位，食指的宽度约为1厘米，则计量小景的身高用\"厘米\"作单位;计量较长的物体，用\"米\"作单位，学生的双臂展开约为1米，则计量房间的长度用\"米\"作单位;计量步行时间用\"分钟\"作单位较合适;计量一场电影的时长用\"小时\"作单位较合适.\n【详解】小景的身高是120厘米，房间长约5米，步行到星光电影院大约用时20分钟，电影时长为2小时。",
+    "knowledge_points": [
+      "时间单位的选择",
+      "长度单位的选择"
+    ],
+    "source": "24-25二年级上·浙江杭州·期末"
+  },
+  {
+    "id": "78",
+    "unit": "第七单元认识时间",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "分针从3走到6，走了( )分;时针从6走到9，走了( )时。",
+    "options": [],
+    "answer": "15;3",
+    "solution": "【分析】分针走1大格就是5分，先用减法求出分针走了几大格，然后乘5求出几分。时针走1大格就是1时，先求出走了几大格，再乘1求出几时.\n【详解】6 - 3 = 3(大格),3×5 = 15(分);9 - 6 = 3(大格),3×1 = 3(时)。分针从3走到6，走了15分;时针从6走到9，走了3时。",
+    "knowledge_points": [
+      "8,9的加减法",
+      "5的乘法口诀及应用",
+      "3的乘法口诀及应用",
+      "时，分，秒有关的计算"
+    ],
+    "source": "24-25二年级上·江西南昌·期末"
+  },
+  {
+    "id": "79",
+    "unit": "第七单元认识时间",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "在括号里填上\">\"\"<\"或\"=\".\n17 + 18( )26;5×7 + 5( )6×7;4×8( )5×6;34 - 7( )3×9;100厘米( )98米;1时( )50分。",
+    "options": [],
+    "answer": ">;<;>;=;<;>",
+    "solution": "【分析】先计算出各算式的结果，再比较大小;100厘米=1米,1时=60分，统一单位后比较.\n【详解】17 + 18 = 35 > 26;5×7 + 5 = 40 < 42 = 6×7;4×8 = 32 > 30 = 5×6;34 - 7 = 27 = 3×9;100厘米 = 1米 < 98米;1时 = 60分 > 50分。",
+    "knowledge_points": [
+      "100以内数的比大小",
+      "9的乘法口诀及应用",
+      "乘加，乘减混合运算",
+      "时，分的认识及换算"
+    ],
+    "source": "24-25二年级上·湖北孝感·期末"
+  },
+  {
+    "id": "80",
+    "unit": "第七单元认识时间",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "看图填空.\n\n![](images/85061aea0c75e71496a41f7735aa4b90bfca22d5a6d41b576fe9da956a450d1e.jpg)\n![](images/fc01683e14e873b37e8fc54893e04858530052ba67b0badadae3b3fc6ffe65be.jpg)\n![](images/ca7bc1fb187ce0e5d9e1aa24e79e622bde276069bf49139b338d67c4362de3b2.jpg)\n![](images/f08584ff2147338d3528014676f712bab3e984349e23a29aeea9dd432b2b02c3.jpg)\n\n过5分是( );过10分是( );过一刻是( );过半小时是( )。",
+    "options": [],
+    "answer": "3时20分或3:20;10时40分或10:40;9时35分或9:35;10时35分或10:35",
+    "solution": "【分析】时针指向3过一点，分针指向3，是3时15分;时针指向10和11之间，分针指向6，是10时30分;时针指向9和10之间，分针指向4，是9时20分;时针指向10过一点，分针指向1，是10时5分。一刻是15分，半小时是30分，结束时间=开始时间+经过时间.\n【详解】3时15分+5分=3时20分;10时30分+10分=10时40分;9时20分+15分=9时35分;10时5分+30分=10时35分。",
+    "knowledge_points": [
+      "半点时间与钟面指针的位置",
+      "一般时间与钟面指针的位置",
+      "时，分，秒时间的推算"
+    ],
+    "source": "24-25二年级上·青海西宁·期末"
+  },
+  {
+    "id": "81",
+    "unit": "第七单元认识时间",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "填上合适的计量单位。小红每天睡9( );旗杆高大约15( );小明的身高大约是134( );鞋大约长20( )。",
+    "options": [],
+    "answer": "小时或时或h;米或m;厘米或cm;厘米或cm",
+    "solution": "【分析】表示较长的时间时，一般选择\"小时\"作单位;米尺长是1米，用\"米\"计量旗杆高比较合适;食指宽大约是1厘米，所以计量身高和鞋长用\"厘米\"作单位比较合适.\n【详解】小红每天睡9小时;旗杆高大约15米;小明身高约134厘米;鞋大约长20厘米。",
+    "knowledge_points": [
+      "时间单位的选择",
+      "长度单位的选择"
+    ],
+    "source": "24-25二年级上·湖北随州·期末"
+  },
+  {
+    "id": "82",
+    "unit": "第七单元认识时间",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "9时整，分针和时针形成的角是( )角。( )时或( )时整分针和时针在一条直线上。",
+    "options": [],
+    "answer": "直;12;6",
+    "solution": "【分析】9时整，分针指向12，时针指向9，形成的角是直角。12时整，分针和时针都指向12;6时整，分针指向12，时针指向6，这两种情况分针和时针在一条直线上.\n【详解】9时整，分针和时针形成的角是直角;12时或6时整，分针和时针在一条直线上。",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征",
+      "整点时间与钟面指针的位置"
+    ],
+    "source": "24-25二年级上·辽宁抚顺·期末"
+  },
+  {
+    "id": "83",
+    "unit": "第七单元认识时间",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "分针从2走到8，走了( )分，时针从4走到7，走了( )时。",
+    "options": [],
+    "answer": "30;3",
+    "solution": "【分析】钟面上较短针是时针，较长针是分针。分针每走1大格是5分，从2到8经过6个大格;时针每走1大格是1时，从4到7经过3个大格.\n【详解】8 - 2 = 6(大格),6×5 = 30分;7 - 4 = 3(时)。",
+    "knowledge_points": [
+      "一般时间与钟面指针的位置"
+    ],
+    "source": "24-25二年级上·河南驻马店·期末"
+  },
+  {
+    "id": "84",
+    "unit": "第七单元认识时间",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "( )米 = 200厘米;100分钟 = ( )小时( )分钟。",
+    "options": [],
+    "answer": "2;1;40",
+    "solution": "【分析】根据1米=100厘米,1小时=60分钟。2米=200厘米;100分钟=60分钟+40分钟=1小时40分钟.\n【详解】2米 = 200厘米;100分钟 = 1小时40分钟。",
+    "knowledge_points": [
+      "时，分的认识及换算",
+      "厘米和米之间的进率与换算"
+    ],
+    "source": "24-25二年级上·湖南娄底·期末"
+  },
+  {
+    "id": "85",
+    "unit": "第七单元认识时间",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "在( )里填上合适的单位名称。我是一名小学二年级学生，我的身高有135( ),我用的跳绳长大约2( )多，我睡的床宽约2( ),我每天坚持阅读1( )的课外书。",
+    "options": [],
+    "answer": "厘米或cm;米或m;米或m;时或小时或h",
+    "solution": "【分析】食指宽大约是1厘米，所以计量身高用\"厘米\";米尺长1米，所以计量跳绳长和床宽用\"米\";较长时间一般用\"小时\"作单位.\n【详解】身高135厘米，跳绳长约2米多，床宽约2米，每天阅读1小时课外书。",
+    "knowledge_points": [
+      "时间单位的选择",
+      "长度单位的选择"
+    ],
+    "source": "24-25二年级上·浙江台州·期末"
+  },
+  {
+    "id": "86",
+    "unit": "第七单元认识时间",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "在( )里填上合适的单位.\n(1)教学楼高15( ).\n(2)毛巾宽30( ).\n(3)学校课间休息时间为10( ).\n(4)教室的门高约2( )。",
+    "options": [],
+    "answer": "米或m;厘米或cm;分钟或分或min;米或m",
+    "solution": "【分析】大拇指的指甲长度大约1厘米，计量毛巾宽度用\"厘米\"合适;两臂展开约1米，计量教学楼和门的高度用\"米\"合适;课间休息用\"分钟\"计量合适.\n【详解】教学楼高15米;毛巾宽30厘米;课间休息时间为10分钟;教室门高约2米。",
+    "knowledge_points": [
+      "时间单位的选择",
+      "长度单位的选择"
+    ],
+    "source": "24-25二年级上·湖北黄冈·期末"
+  },
+  {
+    "id": "87",
+    "unit": "第七单元认识时间",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "时针从\"1\"走到\"3\"，经过了( )时;分针从\"2\"走到\"5\"，经过了( )分。",
+    "options": [],
+    "answer": "2;15",
+    "solution": "【分析】时针每走一个数字格代表1小时，从1到3经过2个数字格;分针每走一个数字格代表5分钟，从2到5经过3个数字格.\n【详解】3 - 1 = 2(时);3×5 = 15(分)。",
+    "knowledge_points": [
+      "时，分，秒有关的计算"
+    ],
+    "source": "24-25二年级上·四川广元·期末"
+  },
+  {
+    "id": "88",
+    "unit": "第七单元认识时间",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "在括号里填上合适的单位.\n一棵大树高8( );小东的身高是123( );课间休息10( );爸爸看球赛看了2( )。",
+    "options": [],
+    "answer": "米或m;厘米或cm;分钟或分或min;小时或时或h",
+    "solution": "【分析】二年级学生双臂展开约1米，计量大树高度用\"米\";食指宽约1厘米，计量身高和课间休息用\"厘米\"和\"分钟\"合适;看球赛用\"小时\"计量合适.\n【详解】一棵大树高8米;小东身高123厘米;课间休息10分钟;爸爸看球赛看了2小时。",
+    "knowledge_points": [
+      "时间单位的选择",
+      "长度单位的选择"
+    ],
+    "source": "24-25二年级上·江西赣州·期末"
+  },
+  {
+    "id": "89",
+    "unit": "第七单元认识时间",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "在日常生活中，我们常说的\"一刻\"是( )分钟，学校大课间休息的\"半小时\"是( )分钟。",
+    "options": [],
+    "answer": "15;30",
+    "solution": "【分析】1小时=60分钟,60的一半是30分钟，即半小时,30的一半是15分钟，即一刻.\n【详解】一刻是15分钟，半小时是30分钟。",
+    "knowledge_points": [
+      "时，分的认识及换算",
+      "时，分，秒有关的计算"
+    ],
+    "source": "24-25二年级上·湖北襄阳·期末"
+  },
+  {
+    "id": "90",
+    "unit": "第七单元认识时间",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "在括号里填上\">\"\"<\"或\"=\"。8 + 6( )8×6;7×3 + 7( )28;100分( )1时;5米( )59厘米。",
+    "options": [],
+    "answer": "<;=;>;>",
+    "solution": "【分析】先计算各算式结果，再比较大小。1时=60分,1米=100厘米.\n【详解】8 + 6 = 14 < 48 = 8×6;7×3 + 7 = 21 + 7 = 28 = 28;100分 > 60分 = 1时;5米 = 500厘米 > 59厘米。",
+    "knowledge_points": [
+      "7的乘法口诀及应用",
+      "8的乘法口诀及应用",
+      "时，分的认识及换算",
+      "长度单位换算"
+    ],
+    "source": "24-25二年级上·湖北黄石·期末"
+  },
+  {
+    "id": "91",
+    "unit": "第七单元认识时间",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "时针走一大格走了( )时;分针从3走到6，走了( )分。",
+    "options": [],
+    "answer": "1;15",
+    "solution": "【分析】时针走一大格是1时;分针走1大格是5分，从3到6走了3个大格.\n【详解】时针走一大格走了1时;3×5 = 15(分),分针从3走到6走了15分。",
+    "knowledge_points": [
+      "时，分，秒有关的计算"
+    ],
+    "source": "24-25二年级上·福建三明·期末"
+  },
+  {
+    "id": "92",
+    "unit": "第七单元认识时间",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "时针从3走到6，走了( )时，分针从11走到2，走了( )分。",
+    "options": [],
+    "answer": "3;15",
+    "solution": "【分析】时针走1大格就是1小时，分针走1大格就是5分。时针从3到6经过3个大格;分针从11到2也经过3个大格.\n【详解】时针从3走到6，走了3时;分针从11走到2，走了3×5=15分。",
+    "knowledge_points": [
+      "5的乘法口诀及应用",
+      "3的乘法口诀及应用",
+      "时，分，秒有关的计算"
+    ],
+    "source": "23-24二年级上·浙江杭州·期末"
+  },
+  {
+    "id": "93",
+    "unit": "第七单元认识时间",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "时钟有三个指针分别是：时针，分针，秒针。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】钟面上又粗又短的针是时针，又细又长的针是秒针，还有一个是分针，长度和粗细介于时针和秒针之间.\n【详解】时钟有三个指针分别是：时针，分针，秒针。说法正确，故答案为√。",
+    "knowledge_points": [
+      "时，分的认识及换算",
+      "秒的认识"
+    ],
+    "source": "24-25一年级下·湖南岳阳·期末"
+  },
+  {
+    "id": "94",
+    "unit": "第七单元认识时间",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "分针在钟面上转了6圈，时针转了3圈。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】分针转1圈是60分钟，即1小时，分针转6圈对应6小时。时针每12小时转1圈,6小时只转半圈.\n【详解】分针在钟面上转了6圈，时针转了半圈，而不是3圈。原题说法错误，故答案为*。",
+    "knowledge_points": [
+      "时，分的认识及换算"
+    ],
+    "source": "24-25二年级下·广东揭阳·期末"
+  },
+  {
+    "id": "95",
+    "unit": "第七单元认识时间",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "钟面上分针走一圈，时针走1大格。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】时针走1大格的时间是1小时，分针走一圈是60分钟，也就是1小时.\n【详解】1小时=60分钟，钟面上分针走一圈是60分钟，也就是1小时，此时时针走1大格。说法正确，故答案为√。",
+    "knowledge_points": [
+      "时，分的认识及换算"
+    ],
+    "source": "2024·湖北襄阳·小升初真题"
+  },
+  {
+    "id": "96",
+    "unit": "第七单元认识时间",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "在钟面上，时针走一小格时，分针刚好走一圈。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】时针走一大格是1时，分针走一圈也是1时;题目说\"时针走一小格\"，本应是\"走一大格\"才对应分针走一圈.\n【详解】在钟面上，时针走一大格时，分针刚好走一圈。原题说法错误，故答案为*。",
+    "knowledge_points": [
+      "一般时间与钟面指针的位置",
+      "时，分的认识及换算"
+    ],
+    "source": "24-25二年级上·河南信阳·期末"
+  },
+  {
+    "id": "97",
+    "unit": "第七单元认识时间",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "时与分之间的关系是1时=60分,30分也可以说成半小时。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】30加30得60，所以30是60的一半,30分是60分的一半.\n【详解】时与分之间的关系是1时=60分,30分也可以说成半小时。说法正确，故答案为√。",
+    "knowledge_points": [
+      "时，分的认识及换算"
+    ],
+    "source": "24-25二年级上·河南南阳·期末"
+  },
+  {
+    "id": "98",
+    "unit": "第七单元认识时间",
+    "question_type": "判断题",
+    "difficulty": 0.94,
+    "question": "天安门广场国旗的升降时间是根据北京的日出日落时间确定的。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】北京天安门广场每天的升旗和降旗时间是根据北京的日出日落时间确定的。早晨，当太阳的上部边缘与天安门广场所见地平线相平时，为升旗时间.\n【详解】天安门广场国旗的升降时间是根据北京的日出日落时间确定的。说法正确，故答案为√。",
+    "knowledge_points": [
+      "时，分的认识及换算"
+    ],
+    "source": "24-25二年级上·山东菏泽·期末"
+  },
+  {
+    "id": "99",
+    "unit": "第七单元认识时间",
+    "question_type": "判断题",
+    "difficulty": 0.65,
+    "question": "现在是![](images/21c84f2b03e0f134281c775a987dd1155461cf55fef9489d71bfcb1c1721a102.jpg),再过一刻，时针和分针就能形成一个直角。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】一刻就是15分。时针指向8和9之间，表示8时多，分针指向9，表示45分，即8:45。再过一刻是8:45+15=9:00，此时时针指向9，分针指向12，二者形成直角.\n【详解】8:45再过一刻是9:00,9时整时针和分针成直角。说法正确，故答案为√。",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征",
+      "整点时间与钟面指针的位置",
+      "一般时间与钟面指针的位置",
+      "时，分，秒时间的推算"
+    ],
+    "source": "24-25二年级上·浙江台州·期末"
+  },
+  {
+    "id": "100",
+    "unit": "第七单元认识时间",
+    "question_type": "作图题",
+    "difficulty": 0.65,
+    "question": "根据时间画钟表指针:7时整,3时30分。",
+    "options": [],
+    "answer": "见详解",
+    "solution": "【分析】钟面被平均分成12个大格，时针走一大格是1小时，分针走一大格是5分钟。7时整时，时针指向7，分针指向12;3时30分时，时针在3和4的正中间，分针指向6.\n【详解】7时整：时针指向7，分针指向12;3时30分：时针指向3和4之间的中点，分针指向6.\n![](images/fd8a624455de4db753b185ef188cb639f7233ff02e3e12891988d512632efd02.jpg)\n![](images/f970c592364acf30d5dfacf2707378a02abcf7d8d08f59e88f79f936f4acb790.jpg)",
+    "knowledge_points": [
+      "整点时间与钟面指针的位置",
+      "半点时间与钟面指针的位置"
+    ],
+    "source": "24-25二年级下·湖南岳阳·期中"
+  },
+  {
+    "id": "101",
+    "unit": "第七单元认识时间1",
+    "question_type": "选择题",
+    "difficulty": 0.94,
+    "question": "聪聪和爸爸8:30去踢球，然后去外婆家，他10:00还要去学钢琴。聪聪可能在什么时间去外婆家。( )",
+    "options": [
+      "A. ![](images/220200f41ad41e7ff326ffbace2123b710f5bb05e1afaf2b17a3026c72b31cd2.jpg)",
+      "B. ![](images/482391f234cdcf69e50e600f0456559748d23a89171149a78ac56249a872e960.jpg)",
+      "C. ![](images/fd2c64cf29e1c20c8deefb5a53ef2ca70178833f03a6866a1db90fba006aafff.jpg)"
+    ],
+    "answer": "B",
+    "solution": "【分析】聪聪去外婆家的时间是8:30到10:00之间，逐项分析。对于分针，走过的数字格数乘5就是经过的分钟数;对于时针，看它走过的数字格数就能知道经过的小时数;分针走一圈是60分钟即1小时，时针走一圈是12小时.\n【详解】A。时针走了10个数字格，是10:00，分针走了1个数字格,1×5=5分，合起来是10:05，不符合题意;B。时针走了9个数字格，是9:00，分针走了1个数字格,1×5=5分，合起来是9:05，符合题意;C。时针走了8个数字格，分针指向12，是8:00，不符合题意。故答案为:B",
+    "knowledge_points": [
+      "整点时间与钟面指针的位置",
+      "一般时间与钟面指针的位置",
+      "时，分，秒时间的推算"
+    ],
+    "source": "24-25二年级上·山东济宁·期末"
+  },
+  {
+    "id": "102",
+    "unit": "第七单元认识时间1",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "现在时间如下图，动画片已经播放一刻钟了，动画片是( )开始播放的.\n\n![](images/8bf3a4dcb085d5f14e6951e14ad6e2a6ae2d239a5abf49148c8956250236ecf2.jpg)",
+    "options": [
+      "A. 6:20",
+      "B. 6:40",
+      "C. 7:20"
+    ],
+    "answer": "B",
+    "solution": "【分析】先读出钟表上的时间，然后用钟表上的时间减去一刻钟(15分钟),求出结果，就是动画片开始播放的时间.\n【详解】钟面显示时间：时针快指向7，表示6时多，分针指向11，表示55分，合起来是6:55;6:55 - 15分 = 6:40，即动画片是6:40开始播放的。故答案为:B",
+    "knowledge_points": [
+      "一般时间与钟面指针的位置",
+      "时，分，秒时间的推算"
+    ],
+    "source": "24-25二年级上·四川南充·期末"
+  },
+  {
+    "id": "103",
+    "unit": "第七单元认识时间1",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "如果钟面上的时针和分针重合在一起，此时是( )。",
+    "options": [
+      "A. 6:00",
+      "B. 6:30",
+      "C. 12:00"
+    ],
+    "answer": "C",
+    "solution": "【分析】钟面上较短的针是时针，较长的针是分针。分针指向12，时针指向几就是几时;分针指向6，时针刚过几就是几时半.\n【详解】A。6:00时，时针指向6，分针指向12，没有重合;B。6:30时，时针在6和7之间，分针指向6，没有重合;C。12:00时，时针指向12，分针指向12，重合在一起。如果时针和分针重合在一起，此时是12:00。故答案为:C",
+    "knowledge_points": [
+      "整点时间与钟面指针的位置",
+      "半点时间与钟面指针的位置"
+    ],
+    "source": "24-25二年级上·福建三明·期末"
+  },
+  {
+    "id": "104",
+    "unit": "第七单元认识时间1",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "时针指向7和8之间，分针指向4，表示( )。",
+    "options": [
+      "A. 8时20分",
+      "B. 4时35分",
+      "C. 7时20分"
+    ],
+    "answer": "C",
+    "solution": "【分析】钟面上12个数字把钟面平均分成12个大格,60个小格，分针走一大格是5分，时针走一大格是1时。时针指向7和8之间，表示7时多，分针指向4，表示20分.\n【详解】由分析可知：时针指向7和8之间，分针指向4，表示7时20分。故答案为:C",
+    "knowledge_points": [
+      "一般时间与钟面指针的位置"
+    ],
+    "source": "23-24二年级上·浙江杭州·期末"
+  },
+  {
+    "id": "105",
+    "unit": "第七单元认识时间1",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "9时整，钟面上分针与时针所成较小的角是( )。",
+    "options": [
+      "A. 锐角",
+      "B. 直角",
+      "C. 钝角"
+    ],
+    "answer": "B",
+    "solution": "【分析】在直角三角板上，最大角就是直角，钝角比直角大，锐角比直角小。9时整，分针指向12，时针指向9，分针与时针所成较小的角是直角.\n【详解】9时整，钟面上分针与时针所成较小的角是直角。故答案为:B",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征",
+      "整点时间与钟面指针的位置"
+    ],
+    "source": "23-24二年级上·山东济宁·期末"
+  },
+  {
+    "id": "106",
+    "unit": "第七单元认识时间1",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "分针从12走到6，走了( )分。",
+    "options": [
+      "A. 6",
+      "B. 30",
+      "C. 60"
+    ],
+    "answer": "B",
+    "solution": "【分析】钟表上，短针是时针，长针是分针，时针走1大格是1小时，分针走1大格是5分钟。分针从12走到6走了6个大格，是6个5分钟.\n【详解】5×6=30(分),分针从12走到6走了30分。故答案为:B",
+    "knowledge_points": [
+      "整点时间与钟面指针的位置",
+      "时，分的认识及换算"
+    ],
+    "source": "24-25二年级上·江西抚州·期末"
+  },
+  {
+    "id": "107",
+    "unit": "第七单元认识时间1",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "钟面上时针在5和6之间，分针对着数字9，这时是( )。",
+    "options": [
+      "A. 6:15",
+      "B. 5:45",
+      "C. 6:45"
+    ],
+    "answer": "B",
+    "solution": "【分析】分针指向12，时针指向几就是几时;分针指向6，时针刚过几就是几时半。时针刚过几就是几时，分针指向第多少个小格就是多少分.\n【详解】时针在5和6之间表示5时多，分针指向9表示45分，这时是5:45。故答案为:B",
+    "knowledge_points": [
+      "一般时间与钟面指针的位置",
+      "时，分的认识及换算"
+    ],
+    "source": "24-25二年级上·河南南阳·期末"
+  },
+  {
+    "id": "108",
+    "unit": "第七单元认识时间1",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "分针和时针都指向12，这时是( )。",
+    "options": [
+      "A. 1时",
+      "B. 6时",
+      "C. 12时"
+    ],
+    "answer": "C",
+    "solution": "【分析】钟面上较短的针是时针，较长的针是分针。分针指向12，时针指向几就是几时.\n【详解】分针和时针都指向12，这时是12时。故答案为:C",
+    "knowledge_points": [
+      "整点时间与钟面指针的位置"
+    ],
+    "source": "24-25二年级上·内蒙古通辽·期末"
+  },
+  {
+    "id": "109",
+    "unit": "第七单元认识时间1",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "当钟面上时针和分针形成的夹角是直角时，时间可能是( )。",
+    "options": [
+      "A. 3:30",
+      "B. 9:00",
+      "C. 9:30"
+    ],
+    "answer": "B",
+    "solution": "【分析】在三角板上，最大角就是直角，锐角比直角小，钝角比直角大;先弄清时针和分针分别指向哪里，然后判断是什么角即可.\n【详解】A。3:30，时针指向3和4中间，分针指向6，夹角为锐角;B。9:00，时针指向9，分针指向12，夹角为直角;C。9:30，时针指向9和10中间，分针指向6，夹角为钝角。故答案为:B",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征",
+      "整点时间与钟面指针的位置",
+      "半点时间与钟面指针的位置"
+    ],
+    "source": "24-25二年级上·福建福州·期末"
+  },
+  {
+    "id": "110",
+    "unit": "第七单元认识时间1",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "![](images/581abb4c38a3cf4cc9d83149439c357f6b4c49f939598916fb0691f21e5498da.jpg)过10分是( )。",
+    "options": [
+      "A. 2:40",
+      "B. 2:50",
+      "C. 3:00"
+    ],
+    "answer": "B",
+    "solution": "【分析】时针指向2和3之间，表示2时多，分针指向8，表示40分，合起来就是2:40;然后用2:40加上10分即可.\n【详解】2:40 + 10分 = 2:50，即图示时间过10分是2:50。故答案为:B",
+    "knowledge_points": [
+      "一般时间与钟面指针的位置",
+      "时，分，秒时间的推算"
+    ],
+    "source": "24-25二年级上·甘肃天水·期末"
+  },
+  {
+    "id": "111",
+    "unit": "第七单元认识时间1",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "![](images/2026-03-01%20224630.jpg)小宇哪个时间在学琴。( )",
+    "options": [
+      "A. ![](images/b5e7ba6eb722faf2c63420f8ac8ee172b15de5b5bbc1edafcda8816a79c541d3.jpg)",
+      "B. ![](images/705b0c6c65ebbf25646670aa01422d5de67be280f3138f992be0a425698e6689.jpg)",
+      "C. ![](images/6c0b4b2a7f822f141edb614c3ed372db53d719141fa76c06f556bd5f55c1997c.jpg)"
+    ],
+    "answer": "A",
+    "solution": "【分析】需要学2小时钢琴，用开始时间加经过时间可以计算出结束时间，然后看给出的时刻是否在这个区间内.\n【详解】9:00 + 2小时 = 11:00，学钢琴时间在9:00到11:00之间。A显示的是10:00，在此区间内，符合;B显示1:30，不在区间内;C显示5:20，也不在区间内。故答案为:A",
+    "knowledge_points": [
+      "整点时间与钟面指针的位置",
+      "半点时间与钟面指针的位置",
+      "一般时间与钟面指针的位置",
+      "时，分，秒时间的推算"
+    ],
+    "source": "24-25二年级上·甘肃庆阳·期末"
+  },
+  {
+    "id": "112",
+    "unit": "第七单元认识时间1",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "聪聪和爸爸8:30去踢球，然后去外婆家，他10:00还要去学钢琴。聪聪可能在什么时间去外婆家。( )",
+    "options": [
+      "A. ![](images/0f991eb4d44821cf87b3370dd1778337a02ff8c24be4f882c536cb50469a7e53.jpg)",
+      "B. ![](images/5557d983937e2574668ffd1820749bb927c9fb1d905dd63e0e278d88ab7aa115.jpg)",
+      "C. ![](images/a422aee71a8dc8befe1e51d8abbf2c3e5fb99d0a645844d7128a0f80b8f022c9.jpg)"
+    ],
+    "answer": "B",
+    "solution": "【分析】聪聪去外婆家的时间是8:30到10:00之间。根据钟面读出三个时刻，判断是否在该区间内.\n【详解】A显示10:05，在10:00之后，不符合;B显示9:05，在8:30到10:00之间，符合;C显示8:00，在8:30之前，不符合。故答案为:B",
+    "knowledge_points": [
+      "整点时间与钟面指针的位置",
+      "一般时间与钟面指针的位置"
+    ],
+    "source": "24-25二年级上·山东济宁·期末"
+  },
+  {
+    "id": "113",
+    "unit": "第七单元认识时间1",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "明明每天坚持练完字后就读课外书。他4:30放学回到家后开始练字,5:20练完字,6:00吃晚饭。明明( )可能在读课外书。",
+    "options": [
+      "A. 4:50",
+      "B. 5:10",
+      "C. 5:45"
+    ],
+    "answer": "C",
+    "solution": "【分析】4:30-5:20在练字，练完字后到6:00这段时间在读课外书.\n【详解】A。4:50在练字时间段，不符合;B。5:10仍在练字时间段，不符合;C。5:45在5:20到6:00之间，可能在读课外书，符合。故答案为:C",
+    "knowledge_points": [
+      "时，分的认识及换算"
+    ],
+    "source": "24-25二年级上·广东汕头·期末"
+  },
+  {
+    "id": "114",
+    "unit": "第七单元认识时间1",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "童童可能在什么时间登山。( )\n\n![](images/2026-03-01%20224932.jpg)",
+    "options": [
+      "A. ![](images/c98bbe16a8fc0bfef78f91733cc4161d989581ddb3bc1ddd96f0e184a2a24cb2.jpg)",
+      "B. ![](images/a1a9aae88d1a58d9c7d662561e2c66c41f8ee8dd2055853880cea709b399affd.jpg)",
+      "C. ![](images/24e759e3086ae76508668fe735c14ee46ec530a8e55138439ed046c47ec1ed1c.jpg)"
+    ],
+    "answer": "C",
+    "solution": "【分析】题干给出童童登山的时间范围在9时到12时之间。根据钟面图像判断各选项时间是否在此区间内.\n【详解】A表示8:55，在9时之前，不符合;B表示2:00，在12时之后，不符合;C表示10:30，在9时到12时之间，符合。故答案为:C",
+    "knowledge_points": [
+      "整点时间与钟面指针的位置",
+      "半点时间与钟面指针的位置",
+      "一般时间与钟面指针的位置"
+    ],
+    "source": "24-25二年级上·河南开封·期末"
+  },
+  {
+    "id": "115",
+    "unit": "第七单元认识时间1",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "万平口景区是夏天旅游的好去处。聪聪和爸爸去万平口游玩，他们7:10吃了早餐，然后在沙滩上游玩到11:30，下面哪个时刻他们可能在沙滩上游玩。( )",
+    "options": [
+      "A. 7:05",
+      "B. 8:30",
+      "C. 12:00"
+    ],
+    "answer": "B",
+    "solution": "【分析】游玩时间应在7:10之后,11:30之前.\n【详解】A。7:05在吃早餐前，不符合;B。8:30在7:10到11:30之间，符合;C。12:00在离开沙滩之后，不符合。故答案为:B",
+    "knowledge_points": [
+      "半点时间与钟面指针的位置",
+      "一般时间与钟面指针的位置",
+      "时，分，秒时间的推算"
+    ],
+    "source": "24-25二年级上·山东日照·期末"
+  },
+  {
+    "id": "116",
+    "unit": "第七单元认识时间1",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "现在的时间是10:35,( )在和图中的钟上同一节体育课。",
+    "options": [
+      "A. ![](images/2026-03-01%20225436.jpg)",
+      "B. ![](images/2026-03-01%20225448.jpg)",
+      "C. ![](images/2026-03-01%20225554.jpg)"
+    ],
+    "answer": "A",
+    "solution": "【分析】根据各钟面上时针和分针的位置读出时间，与10:35进行比较，找出与10:35相同的即可.\n【详解】A钟面：时针指向10和11之间，分针指向7，表示10:35;B:9:10;C:9:40。只有A为10:35，与题意一致。故答案为:A",
+    "knowledge_points": [
+      "一般时间与钟面指针的位置"
+    ],
+    "source": "24-25二年级上·全国·期末"
+  },
+  {
+    "id": "117",
+    "unit": "第七单元认识时间1",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "妈妈说：\"我们早上8:00去超市，然后去姥姥家.\"笑笑说：\"我中午12:15还要去少年宫学下棋.\"下面图( )的时刻，笑笑可能在姥姥家。",
+    "options": [
+      "A. ![](images/19f13a88ff4e90d0f34d893b0dd81acc8031d8a0e5227f4db46c1aabaeaed975.jpg)",
+      "B. ![](images/e15365af979718c3fd0f7e69f3e65ea439d9ad2f49df1a7860a88cdcb0968fe1.jpg)",
+      "C. ![](images/ef3f04adcbe4ce55306aefa081b389a8e86c068fa60e258d15cf15032a3394af.jpg)"
+    ],
+    "answer": "B",
+    "solution": "【分析】笑笑在姥姥家的时间应在8:00之后,12:15之前。根据钟面读出各图时间并判断是否在该区间.\n【详解】A:7:55，在8:00之前;B:10:35，在8:00至12:15之间，符合;C:12:30，在12:15之后，不符合。故答案为:B",
+    "knowledge_points": [
+      "半点时间与钟面指针的位置",
+      "一般时间与钟面指针的位置"
+    ],
+    "source": "23-24二年级上·河北保定·期末"
+  },
+  {
+    "id": "118",
+    "unit": "第七单元认识时间1",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "9时30分，钟面上的时针和分针形成一个( )。",
+    "options": [
+      "A. 锐角",
+      "B. 直角",
+      "C. 钝角"
+    ],
+    "answer": "C",
+    "solution": "【分析】9时30分时，时针在9和10之间，分针指向6，二者形成的角大于直角，为钝角.\n【详解】9时30分，钟面上的时针和分针形成一个钝角。故答案为:C",
+    "knowledge_points": [
+      "角的初步认识及辨认",
+      "半点时间与钟面指针的位置"
+    ],
+    "source": "23-24二年级上·浙江绍兴·期末"
+  },
+  {
+    "id": "119",
+    "unit": "第七单元认识时间1",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面钟表上的时间再过一刻是( ).\n\n![](images/02f78036dc5a0827609bd1b97f267e67d5b8fad3dce89f62a4c44a5bf0f6b1b1.jpg)",
+    "options": [
+      "A. 7:40",
+      "B. 7:45",
+      "C. 8:00"
+    ],
+    "answer": "B",
+    "solution": "【分析】当分针指向6，时针过7，就是7:30。一刻就是15分钟，用7:30+15即可.\n【详解】7:30+15=7:45，所以再过一刻是7:45。故答案为:B",
+    "knowledge_points": [
+      "半点时间与钟面指针的位置",
+      "时，分，秒时间的推算"
+    ],
+    "source": "23-24二年级上·山东菏泽·期末"
+  },
+  {
+    "id": "120",
+    "unit": "第七单元认识时间1",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "龙龙上午8:50开始写作业，然后去打篮球,11:30回家吃饭。下面( )钟面上的时间，龙龙可能在打篮球。",
+    "options": [
+      "A. ![](images/81aae27074e0c987dce725fd1987b7fc8da88491e50f5c5a80a590f685025393.jpg)",
+      "B. ![](images/6f001129bdea3c4980aa5d2107c07becb073c7d793144b5738db7879439e2e99.jpg)",
+      "C. ![](images/301becdf8b9865d278a1d489bd1e2c7cb7225b786142bcea75cd7fc426120bf8.jpg)"
+    ],
+    "answer": "A",
+    "solution": "【分析】龙龙打篮球的时间在8:50到11:30之间，读出各钟面对应的时间进行判断.\n【详解】A表示9:40，在8:50到11:30之间，符合;B表示11:30，是吃饭时间，不符合;C表示7:05，在8:50之前，不符合。故答案为:A",
+    "knowledge_points": [
+      "半点时间与钟面指针的位置",
+      "一般时间与钟面指针的位置"
+    ],
+    "source": "23-24二年级上·河南郑州·期末"
+  },
+  {
+    "id": "121",
+    "unit": "第七单元认识时间1",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "我们生活中经常说到的时间30分，还可以说成是( )。",
+    "options": [
+      "A. 1小时",
+      "B. 30小时",
+      "C. 半小时"
+    ],
+    "answer": "C",
+    "solution": "【分析】1小时=60分,30分+30分=60分，所以30分是1小时的一半.\n【详解】30分是1小时的一半，也就是半小时。故答案为:C",
+    "knowledge_points": [
+      "时，分的认识及换算"
+    ],
+    "source": "23-24二年级上·重庆丰都·期末"
+  },
+  {
+    "id": "122",
+    "unit": "第七单元认识时间1",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "7:35到7:50，分针走了( )个大格。",
+    "options": [
+      "A. 1",
+      "B. 3",
+      "C. 15"
+    ],
+    "answer": "B",
+    "solution": "【分析】7:50-7:35=15分钟。钟面上分为12个大格，分针走一大格是5分钟,15分对应3个大格.\n【详解】分针走3个大格，每大格5分钟，共15分钟。故答案为:B",
+    "knowledge_points": [
+      "时，分，秒有关的计算"
+    ],
+    "source": "24-25二年级上·西藏那曲·期末"
+  },
+  {
+    "id": "123",
+    "unit": "第七单元认识时间1",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "一刻是( )分。",
+    "options": [
+      "A. 30",
+      "B. 5",
+      "C. 15"
+    ],
+    "answer": "C",
+    "solution": "【分析】30分也可以说成半小时;15分也可以说成一刻.\n【详解】一刻是15分。故答案为:C",
+    "knowledge_points": [
+      "时，分的认识及换算"
+    ],
+    "source": "24-25二年级上·西藏那曲·期末"
+  },
+  {
+    "id": "124",
+    "unit": "第七单元认识时间1",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "钟面上，分针从12旋转到3，经过的时间是( )。",
+    "options": [
+      "A. 3分",
+      "B. 3小时",
+      "C. 15分"
+    ],
+    "answer": "C",
+    "solution": "【分析】钟面上长针是分针，短针是时针。有12个大格，分针走1大格是5分钟。分针从12旋转到3走了3个大格.\n【详解】5×3=15(分),因此分针从12旋转到3经过的时间是15分。故答案为:C",
+    "knowledge_points": [
+      "时，分，秒有关的计算"
+    ],
+    "source": "23-24二年级下·四川德阳·期末"
+  },
+  {
+    "id": "125",
+    "unit": "第七单元认识时间1",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "第一节课在8时40分上课,9时20分下课，这节课上了( )。",
+    "options": [
+      "A. 半小时",
+      "B. 40分",
+      "C. 35分"
+    ],
+    "answer": "B",
+    "solution": "【分析】经过时间=结束时间-开始时间.\n【详解】9时20分-8时40分=40分，这节课上了40分。故答案为:B",
+    "knowledge_points": [
+      "时，分，秒有关的计算"
+    ],
+    "source": "23-24二年级上·四川德阳·期末"
+  },
+  {
+    "id": "126",
+    "unit": "第七单元认识时间1",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "星期六上午，妈妈8:00在家做早点,11:30回家做午饭，其余时间要到商店买衣服。妈妈可能在下面哪个时间到达商场。( )",
+    "options": [
+      "A. ![](images/657673c4d82be20b851d43a817793d7c177ce9927d7d124be235eff215a8272e.jpg)",
+      "B. ![](images/edd23e68e2770811f9e01db227f8bb87e3bee3e6e4ce3827829175d39a9acf80.jpg)",
+      "C. ![](images/84c3d7cc70f899c3f5505d87cfe093712c79f247c7261f3323e798d5ffcf319e.jpg)"
+    ],
+    "answer": "C",
+    "solution": "【分析】妈妈做早点需要一定时间,8:00开始做早点，做完后再去商场,11:30要回家做午饭。到达商场的时间应在做完早点之后,11:30之前.\n【详解】A表示7:10，妈妈还没做早点，不符合;B表示1:35，已过午饭时间，不符合;C表示9:15，可能到达商场，符合。故答案为:C",
+    "knowledge_points": [
+      "一般时间与钟面指针的位置"
+    ],
+    "source": "23-24二年级上·四川德阳·期末"
+  },
+  {
+    "id": "127",
+    "unit": "第七单元认识时间1",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "星期天，明明8:00吃早饭，接着练琴,9:30开始写作业,11:00和妈妈去公园玩。明明( )正在写作业。",
+    "options": [
+      "A. 8:30",
+      "B. 9:40",
+      "C. 11:05"
+    ],
+    "answer": "B",
+    "solution": "【分析】明明写作业的时间在9:30到11:00之间.\n【详解】A。8:30还没写作业;B。9:40在9:30到11:00之间，可能在写作业;C。11:05已去公园，不符合。故答案为:B",
+    "knowledge_points": [
+      "整点时间与钟面指针的位置",
+      "一般时间与钟面指针的位置"
+    ],
+    "source": "23-24二年级上·福建福州·期末"
+  },
+  {
+    "id": "128",
+    "unit": "第七单元认识时间1",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "聪聪9:00从家里出发，大约15分钟后到达滑雪场,12:00准时回家吃饭。聪聪可能在( )时间滑雪。",
+    "options": [
+      "A. ![](images/5aff251b0408bf129457c6c2af6d7f1b0fa150f84adcef16e049a31b06c1c070.jpg)",
+      "B. ![](images/d2c6966ebeaf52e2fffb08b669e64682142ea4be73664fdf35dbc20b60a79d7a.jpg)",
+      "C. ![](images/475cfbe2d1f2a27f702b59dd2b34ef1e0f9b62dcbf128b737628f2dfccfa9215.jpg)"
+    ],
+    "answer": "A",
+    "solution": "【分析】先求出到达滑雪场的时间:9:00 + 15分钟 = 9:15。滑雪时间在9:15到12:00之间.\n【详解】A:9:40，在9:15至12:00之间，符合;B:8:30，在出发前，不符合;C:12:25，在12:00之后，不符合。故答案为:A",
+    "knowledge_points": [
+      "一般时间与钟面指针的位置",
+      "时，分，秒有关的计算"
+    ],
+    "source": "23-24二年级上·福建三明·期末"
+  },
+  {
+    "id": "129",
+    "unit": "第七单元认识时间1",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "小红9:00开始写作业，然后整理房间,11:30再去奶奶家，她整理房间的时间可能是( )。",
+    "options": [
+      "A. ![](images/4cffed74b25f8600e6330593719229ac3676a58d81ddaed8d80db1810b798755.jpg)",
+      "B. ![](images/da0399ee01ee5f39f8cfffef8c57adaf5ddb3c58dda24dd659f9f62af360f9cb.jpg)",
+      "C. ![](images/19906a69d48aaf4aecd9684459c6e14b2863f86d4451f95d1681269aed15cb7a.jpg)"
+    ],
+    "answer": "B",
+    "solution": "【分析】整理房间的时间在9:00之后,11:30之前。A表示7:50，在开始写作业前;C表示11:50，已离家去奶奶家.\n【详解】B表示10:45，在9:00到11:30之间，符合题意。故答案为:B",
+    "knowledge_points": [
+      "一般时间与钟面指针的位置"
+    ],
+    "source": "23-24二年级上·河南安阳·期末"
+  },
+  {
+    "id": "130",
+    "unit": "第七单元认识时间1",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "钟面上的分针走两圈是( )。",
+    "options": [
+      "A. 24分",
+      "B. 2小时",
+      "C. 2分"
+    ],
+    "answer": "B",
+    "solution": "【分析】钟面上长针是分针，短针是时针，有12个大格，分针走1大格是5分钟，走1圈是1小时，走两圈是2小时.\n【详解】分针走两圈，表示经过2小时。故答案为:B",
+    "knowledge_points": [
+      "时，分，秒有关的计算"
+    ],
+    "source": "23-24二年级上·河南南阳·期末"
+  },
+  {
+    "id": "131",
+    "unit": "第七单元认识时间1",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "( )分 = 1小时;1米 - 60厘米 = ( )厘米;一刻 = ( )分。",
+    "options": [],
+    "answer": "60;40;15",
+    "solution": "【分析】1小时=60分;1米=100厘米;半小时=30分，一刻是半小时的一半即15分.\n【详解】60分 = 1小时;1米 - 60厘米 = 100厘米 - 60厘米 = 40厘米;一刻 = 15分。",
+    "knowledge_points": [
+      "时，分的认识及换算",
+      "厘米和米之间的进率与换算"
+    ],
+    "source": "24-25二年级上·四川广元·期末"
+  },
+  {
+    "id": "132",
+    "unit": "第七单元认识时间1",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "时针从3走到8走了( )时，分针从12走到3走了( )分。",
+    "options": [],
+    "answer": "5;15",
+    "solution": "【分析】时针走一大格是1小时，从3到8经过5个大格;分针走一大格是5分钟，从12到3经过3个大格.\n【详解】时针从3走到8走了5时;分针从12走到3走了3×5=15分。",
+    "knowledge_points": [
+      "8,9的加减法",
+      "5的乘法口诀及应用",
+      "时，分，秒有关的计算"
+    ],
+    "source": "24-25二年级上·四川南充·期末"
+  },
+  {
+    "id": "133",
+    "unit": "第七单元认识时间1",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "钟面上的时间是8:55，此时时针和分针的夹角是( )角，再过( )分就是9:30。",
+    "options": [],
+    "answer": "锐;35",
+    "solution": "【分析】8:55时，时针接近9，分针指向11，时针和分针的夹角比直角小，是锐角。求到9:30还要经过多长时间，用结束时间减开始时间.\n【详解】9:30 - 8:55 = 35(分),钟面上的时间是8:55，此时时针和分针的夹角是锐角，再过35分就是9:30。",
+    "knowledge_points": [
+      "一般时间与钟面指针的位置",
+      "直角，钝角，锐角的认识及特征",
+      "时，分，秒时间的推算"
+    ],
+    "source": "24-25二年级上·重庆奉节·期末"
+  },
+  {
+    "id": "134",
+    "unit": "第七单元认识时间1",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "在括号里填上\">\"\"<\"或\"=\".\n\n63 - 37( )5×5;8×3( )9×3 - 3;1时( )50分;24厘米 + 75厘米( )1米",
+    "options": [],
+    "answer": ">;=;>;<",
+    "solution": "【分析】有算式的，先计算出算式的结果再比较大小;单位不统一的，先根据1时=60分,1米=100厘米，统一单位，再比较大小。整数比较大小的方法：位数多的数就大;位数相同，先比较最高位上的数，最高位上大的，数就大，最高位相同的，就比较下一位，以此类推.\n【详解】63 - 37 = 26,5×5 = 25,26 > 25，所以63 - 37 > 5×5;8×3 = 24,9×3 - 3 = 24,24 = 24，所以8×3 = 9×3 - 3;1时 = 60分,60分 > 50分，所以1时 > 50分;24厘米 + 75厘米 = 99厘米,1米 = 100厘米,99厘米 < 100厘米，所以24厘米 + 75厘米 < 1米。",
+    "knowledge_points": [
+      "8的乘法口诀及应用",
+      "9的乘法口诀及应用",
+      "时，分的认识及换算",
+      "厘米和米之间的进率与换算"
+    ],
+    "source": "24-25二年级上·重庆奉节·期末"
+  },
+  {
+    "id": "135",
+    "unit": "第七单元认识时间1",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "在括号里填上合适的单位名称。玲玲是二(1)班的学生，她所在的教室长约8( ),在她桌上有一本长为26( )的数学书。一节课的时间是40( ),她一天在学校学习的时间大约为6( )。",
+    "options": [],
+    "answer": "米或m;厘米或cm;分或min;时或h",
+    "solution": "【分析】常用的时间单位有时，分，秒;常用的长度单位有米，分米，厘米等。(1)测量较长的物体，通常用\"米\"作单位，讲桌的长度大约是1米，所以计量教室的长用\"米\"作单位比较合适;(2)测量较短的物体，通常用\"厘米\"作单位，大拇指的宽度约1厘米，所以计量数学书的长用\"厘米\"作单位比较合适。(3)1分钟心跳大约80下,1分钟能写15遍名字，所以计量一节课的时间用\"分钟\"作单位比较合适;(4)一节课40分钟，所以计量一天在学校的时间，结合数据应该用\"时\"作单位比较合适.\n【详解】玲玲是二(1)班的学生，她所在的教室长约8米，在她桌上有一本长为26厘米的数学书。一节课的时间是40分，她一天在学校学习的时间大约为6时。",
+    "knowledge_points": [
+      "时间单位的选择",
+      "长度单位的选择"
+    ],
+    "source": "24-25二年级上·福建三明·期末"
+  },
+  {
+    "id": "136",
+    "unit": "第七单元认识时间1",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "小芳7:30从家出发，走一刻到达学校，小芳到达学校的时间是( )。",
+    "options": [],
+    "answer": "7:45或7时45分",
+    "solution": "【分析】钟表上有12大格,60小格，时针走1大格是1时，圈12小时，分针走1小格是1分,1大格是5分，一圈60分钟。7:30，时针位于7和8之间，即7时多，分针指向6,15分可以说成一刻钟，即分针走了15小格，分针指向9，此时是7:45.\n【详解】小芳7:30从家出发，走一刻到达学校，小芳到达学校的时间是7:45。",
+    "knowledge_points": [
+      "半点时间与钟面指针的位置",
+      "一般时间与钟面指针的位置",
+      "时，分，秒时间的推算"
+    ],
+    "source": "24-25二年级上·河南开封·期末"
+  },
+  {
+    "id": "137",
+    "unit": "第七单元认识时间1",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "在( )里填上合适的单位.\n\n一支粉笔长约8( );明明每天午休1( );小红跳绳100下用了1( );篮球场长28( )",
+    "options": [],
+    "answer": "厘米或cm;小时或h;分钟或分或min;米或m",
+    "solution": "【分析】大拇指的指甲长度大约1厘米，计量一支粉笔的长度用\"厘米\"作单位比较合适。做一顿家常饭的时间大约是1小时，计量午休的时间用\"小时\"作单位比较合适。削一个苹果的时间大约是1分钟，计量跳绳100下的时间用\"分钟\"作单位比较合适。小学生两臂伸开的长度大约1米，计量篮球场的长度用\"米\"作单位比较合适.\n【详解】一支粉笔长约8厘米;明明每天午休1小时;小红跳绳100下用了1分钟;篮球场长28米。",
+    "knowledge_points": [
+      "时间单位的选择",
+      "长度单位的选择"
+    ],
+    "source": "24-25二年级上·河南南阳·期末"
+  },
+  {
+    "id": "138",
+    "unit": "第七单元认识时间1",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "在括号填上合适的单位。丽丽早晨7( )起床，吃早餐用了20( )。体育课上，丽丽看到操场上旗杆高约13( ),操场上一条跑道的长是60( )。",
+    "options": [],
+    "answer": "时;分钟或分;米或m;米或m",
+    "solution": "【分析】常用的时间单位有时，分，秒;常用的长度单位有米，分米，厘米等。(1)根据常识，结合题目数据，丽丽早上起床的时间应该用\"时\"作单位比较合适;(2)1分钟心跳大约80下,1分钟能写15遍名字，所以计量吃早餐的时间用\"分钟\"作单位比较合适;(3)测量较长的物体，通常用\"米\"作单位，讲桌的长度大约是1米，所以计量操场上旗杆高用\"米\"作单位比较合适;(4)测量较长的物体，通常用\"米\"作单位，讲桌的长度大约是1米，所以计量操场上跑道长用\"米\"作单位比较合适.\n【详解】丽丽早晨7时起床，吃早餐用了20分钟。体育课上，丽丽看到操场上旗杆高约13米，操场上一条跑道的长是60米。",
+    "knowledge_points": [
+      "时间单位的选择",
+      "长度单位的选择"
+    ],
+    "source": "23-24二年级上·浙江·期末"
+  },
+  {
+    "id": "139",
+    "unit": "第七单元认识时间1",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "分针走一圈是( )分，时针从2走到6，走了( )时。",
+    "options": [],
+    "answer": "60;4",
+    "solution": "【分析】分针走一圈是60分，也就是1小时;时针走一大格是1小时。先算出时针走几大格，然后乘1求出积，就是时针走了几时.\n【详解】6 - 2 = 4(大格),1×4 = 4(时),即，分针走一圈是60分，时针从2走到6，走了4时。",
+    "knowledge_points": [
+      "时，分的认识及换算",
+      "时，分，秒有关的计算"
+    ],
+    "source": "24-25二年级上·福建福州·期末"
+  },
+  {
+    "id": "140",
+    "unit": "第七单元认识时间1",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "分针从3走到9，走了( )分;时针从3走到9，走了( )小时。",
+    "options": [],
+    "answer": "30;6",
+    "solution": "【分析】钟表上有12大格,60小格，时针走1大格是1时，圈12小时，分针走1小格是1分,1大格是5分，一圈60分。据此解答.\n【详解】根据分析：从3走到9，走了6大格，即9 - 3 = 6,6×5 = 30(分),6×1 = 6(时),分针从3走到9，走了30分;时针从3走到9，走了6小时。",
+    "knowledge_points": [
+      "6的乘法口诀及应用",
+      "时，分，秒有关的计算"
+    ],
+    "source": "24-25二年级上·山东日照·期末"
+  },
+  {
+    "id": "141",
+    "unit": "第七单元认识时间1",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "钟面上有( )个大格,( )个小格。时针从12走到5，走了( )时，分针从12走到5，走了( )分。",
+    "options": [],
+    "answer": "12;60;5;25",
+    "solution": "【分析】在钟面上，一周平均分成12个大格，一个大格又平均分成了5个小格，一共有60个小格;时针走一个大格是1小时，时针从12走到5，走了5大格，即走了5时;分针每走1小格是1分，则走一大格是5分，分针从12走到5，走了5大格，即走了25分.\n【详解】由分析可知：钟面上有12个大格,60个小格。时针从12走到5，走了5时，分针从12走到5，走了25分。",
+    "knowledge_points": [
+      "时，分的认识及换算"
+    ],
+    "source": "24-25二年级上·内蒙古通辽·期末"
+  },
+  {
+    "id": "142",
+    "unit": "第七单元认识时间1",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "时针从1走到3经过了( )时，分针从2走到5经过了( )分。时针从6走到7，分针刚好走了( )圈，也就是( )分。",
+    "options": [],
+    "answer": "2;15;1或一;60",
+    "solution": "【分析】钟面上共有12个大格,60个小格，时针走1大格是1小时，分针走一小格是1分钟，走一大格是5分钟，走一圈是1小时;时针从1走到3时针走了2大格是2小时;分针从2走到5走了3大格是15分;时针从6走到7，时针走了1大格是1小时，分针走一圈是1小时,1小时=60分;据此解答.\n【详解】根据分析:3 - 1 = 2(大格),2×1 = 2(时),5 - 2 = 3(大格),3×5 = 15(分),7 - 6 = 1(大格),1×1 = 1(时),所以时针从1走到3经过了2时，分针从2走到5经过了15分。时针从6走到7，分针刚好走了1圈，也就是60分。",
+    "knowledge_points": [
+      "5的乘法口诀及应用",
+      "2的乘法口诀及应用",
+      "时，分的认识及换算",
+      "时，分，秒有关的计算"
+    ],
+    "source": "24-25二年级上·河南南阳·期末"
+  },
+  {
+    "id": "143",
+    "unit": "第七单元认识时间1",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "陕坝到临河的公交车每隔10分钟发一班，这班车是8:55发车，下一班是( )发车。",
+    "options": [],
+    "answer": "9:05或9时5分",
+    "solution": "【分析】根据题意，这班车的发车时间+间隔的时间=下一班的发车时间.\n【详解】8:55即8时55分。8时55分+10分=9时5分，也写作9:05。陕坝到临河的公交车每隔10分钟发一班，这班车是8:55发车，下一班是9:05发车。",
+    "knowledge_points": [
+      "时，分，秒时间的推算"
+    ],
+    "source": "24-25二年级上·内蒙古巴彦淖尔·期末"
+  },
+  {
+    "id": "144",
+    "unit": "第七单元认识时间1",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "下边钟面上显示的时间是( ),再过5分钟是( );5:30时，分针指向数字( ).\n\n![](images/2026-03-01%20231248.jpg)",
+    "options": [],
+    "answer": "4:55或4时55分;5:00或5时;6",
+    "solution": "【分析】钟面上长针是分针，短针是时针，有12个大格，分针走1大格是5分钟，时针走1大格是1小时。求再过5分钟的时间，用现在的时间+5分钟，计算即可;分针指向6，时针过了几就是几时30分.\n【详解】分针指向11，时针接近5，是4时55分，也写作4:55;4时55分+5分=5时，也写作5:00;下边钟面上显示的时间是4:55，再过5分钟是5:00;5:30时，分针指向数字6。",
+    "knowledge_points": [
+      "半点时间与钟面指针的位置",
+      "一般时间与钟面指针的位置",
+      "时，分的认识及换算"
+    ],
+    "source": "24-25二年级上·山东济宁·期末"
+  },
+  {
+    "id": "145",
+    "unit": "第七单元认识时间1",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "团结杯雪地足球赛从上午9时15分开始，进行了35分钟，比赛结束时是( )时( )分。",
+    "options": [],
+    "answer": "9;50",
+    "solution": "【分析】开始时刻+经过时间=结束时刻，用9时15分加上35分钟即可求解.\n【详解】9时15分+35分钟=9时50分，比赛结束时是9时50分。",
+    "knowledge_points": [
+      "时，分，秒时间的推算"
+    ],
+    "source": "24-25二年级上·黑龙江哈尔滨·期末"
+  },
+  {
+    "id": "146",
+    "unit": "第七单元认识时间1",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "时针从12开始绕一圈又走回12，经过了( )时;分针从1走到12，经过了( )分。",
+    "options": [],
+    "answer": "12;55",
+    "solution": "【分析】钟面上较短的针是时针，较长的针是分针。时针走一大格是1时，走一圈是12时;分针走1小格是1分，走1大格是5分，从1走到12走了11个大格.\n【详解】5×11 = 55(分),时针从12开始绕一圈又走回12，经过了12时;分针从1走到12，经过了55分。",
+    "knowledge_points": [
+      "一般时间与钟面指针的位置",
+      "时，分，秒有关的计算"
+    ],
+    "source": "24-25二年级上·河北邯郸·期末"
+  },
+  {
+    "id": "147",
+    "unit": "第七单元认识时间1",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "1时36分 = ( )分;105分 = ( )时( )分",
+    "options": [],
+    "answer": "96;1;45",
+    "solution": "【分析】根据1时=60分，然后利用数的分与合完成填空即可。据此解答.\n【详解】(1)1时36分可分成:1时和36分,1时=60分,60分+36分=96分，所以1时36分=96分;(2)105分可分成:60分和45分,1时=60分，所以105分=1时45分。",
+    "knowledge_points": [
+      "时，分的认识及换算"
+    ],
+    "source": "24-25二年级上·河北邯郸·期末"
+  },
+  {
+    "id": "148",
+    "unit": "第七单元认识时间1",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "分针从12走到7，走了( )分。",
+    "options": [],
+    "answer": "35",
+    "solution": "【分析】钟面上长针是分针，短针是时针，有12个大格，分针走1大格是5分钟，时针走1大格是1小时，由此先计算出走了几个大格，再用乘法计算出走了多少分即可.\n【详解】分针从12走到7，走了7个大格。5×7=35(分),分针从12走到7，走了35分。",
+    "knowledge_points": [
+      "7的乘法口诀及应用",
+      "时，分，秒有关的计算"
+    ],
+    "source": "24-25二年级上·广东江门·期末"
+  },
+  {
+    "id": "149",
+    "unit": "第七单元认识时间1",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "在括号里填上\">\"\"<\"或\"=\".\n\n54 - 37( )3×9;4 + 4( )4×4;52 + 39( )53 + 38\n21 + 29( )40;1时( )100分;3×8 + 8( )5×8 - 8",
+    "options": [],
+    "answer": "<;<;=;>;<;=",
+    "solution": "【分析】先计算出每个算式的结果或先统一单位，然后比较大小即可。整数比较大小方法:①位数多的数大于位数少的数;②位数相同的，先比较最高位上的数，最高位上大的，数就大，最高位数相同的，就比较下一位，以此类推。1时=60分.\n【详解】54 - 37 = 17,3×9 = 27，故54 - 37 < 3×9;4 + 4 = 8,4×4 = 16，故4 + 4 < 4×4;52 + 39 = 91,53 + 38 = 91，故52 + 39 = 53 + 38;21 + 29 = 50，故21 + 29 > 40;1时 = 60分，故1时 < 100分;3×8 + 8 = 24 + 8 = 32,5×8 - 8 = 40 - 8 = 32，故3×8 + 8 = 5×8 - 8。",
+    "knowledge_points": [
+      "100以内数的比大小",
+      "两位数与两位数的进位加法",
+      "时，分的认识及换算",
+      "表内乘加，乘减"
+    ],
+    "source": "24-25二年级上·福建福州·期末"
+  },
+  {
+    "id": "150",
+    "unit": "第七单元认识时间1",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "下图钟面上的时刻是( ),最少再过( )分，时针和分针就成直角了.\n\n![](images/8a57cf7e84de4546f0b797b99578f4c8b4504a63d6dd0ad09aac46faeceec10a.jpg)",
+    "options": [],
+    "answer": "7:55;65",
+    "solution": "【分析】时针指向7和8之间,7时多，分针指向11，表示55分，合起来是7时55分;9时时，时针指向9，分针指向12;3时时，时针指向3，分针指向12，这两个时间时针和分针形成的角是直角;题目中求最少经过几分,9时经过时间最少;经过时间=结束时间-开始时间.\n【详解】由题意分析得:9:00 - 7:55 = 65(分),钟面上的时刻是7:55，最少再过65分，时针和分针就成直角了。",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征",
+      "整点时间与钟面指针的位置",
+      "一般时间与钟面指针的位置",
+      "时，分，秒有关的计算"
+    ],
+    "source": "23-24二年级上·浙江·期末"
+  },
+  {
+    "id": "151",
+    "unit": "第七单元认识时间1",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "如图，钟面上的时间是( ),这时分针和时针所成的角是( )角;再过半小时是( ),这时分针和时针所成的角是( )角.\n\n![](images/175b493d3432dd182443c76f849ded74df88658456bc17e0737dbf52223b7904.jpg)",
+    "options": [],
+    "answer": "9:25或9时25分;钝;9:55或9时55分;锐",
+    "solution": "【分析】钟表上有12大格,60小格，时针走1大格是1时，圈12小时，分针走1小格是1分,1大格是5分，一圈60分钟。30分也可以说成半小时。时针位于9和10之间，就是9时多，分针指向5，是25分，时间是9时25分;再过半小时即30分，分针指向11，是55分，时间就是9时55分;比直角小的是锐角，比直角大的是钝角.\n【详解】如图，钟面上的时间是9:25，这时分针和时针所成的角是钝角;再过半小时是9:55，这时分针和时针所成的角是锐角。",
+    "knowledge_points": [
+      "角的初步认识及辨认",
+      "一般时间与钟面指针的位置"
+    ],
+    "source": "24-25二年级上·河南开封·期末"
+  },
+  {
+    "id": "152",
+    "unit": "第七单元认识时间1",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "时针从12走到2，走了( )小时，分针从12走到2走了( )分钟。",
+    "options": [],
+    "answer": "2;10",
+    "solution": "【分析】钟面上较短的针是时针，较长的针是分针。时针走一大格是1时;分针走1小格是1分，走1大格是5分。用分针走的大格数乘5即可求出走了多少分钟.\n【详解】2×5 = 10(分钟),时针从12走到2，走了2小时，分针从12走到2走了10分钟。",
+    "knowledge_points": [
+      "一般时间与钟面指针的位置"
+    ],
+    "source": "24-25二年级上·吉林·期末"
+  },
+  {
+    "id": "153",
+    "unit": "第七单元认识时间1",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "观察钟面，回答问题。![](images/decd51c3f7d3833c59396b3e063a3b1fe92e744c34c63afa08d8f6b2e105aac4.jpg)时针从10走到2，走了( )时;分针从10走到2，走了( )分;分针从12绕一圈走回到12，是( )分，也就是( )。钟面现在的时间是( ),再过半小时是( )。",
+    "options": [],
+    "answer": "4;20;60;1小时;9:05;9:35",
+    "solution": "【分析】钟表上，短针是时针，长针是分针，时针走1大格是1小时，分针走1大格是5分钟，秒针走1大格是5秒钟。时针走1圈是12小时，分针走1圈是1小时，秒针走1圈是1分钟。则时针走1个数字(1大格)是1小时，从10走到2，走了4个数字，即4大格，是4小时;分针走一个数字(1大格)是5分钟，分针从10走到2，走了4个数字(即4大格),是4个5分钟，用乘法计算:4×5=20(分钟),即20分钟;分针从12开始绕了一圈又走回12，走12大格，即60分钟，也就是1小时;钟面上分针指向1，时针指向9，则表示的是9:05，求再过半个小时是多少。半个小时为30分钟，则结束时间=开始时间+经过时间.\n【详解】4×5 = 20(分钟),9:05 + 30分 = 9:35，则时针从10走到2，走了4时;分针从10走到2，走了20分;分针从12绕一圈走回到12，是60分，也就是1小时。钟面现在的时间是9:05，再过半小时是9:35。",
+    "knowledge_points": [
+      "一般时间与钟面指针的位置",
+      "时，分，秒有关的计算"
+    ],
+    "source": "23-24二年级上·四川德阳·期末"
+  },
+  {
+    "id": "154",
+    "unit": "第七单元认识时间1",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "小明每天中午休息半小时，也就是休息( )分钟。",
+    "options": [],
+    "answer": "30",
+    "solution": "【分析】1小时=60分,30分+30分=60分，所以30分是60分的一半，也就是一小时的一半，即30分也可以说成半小时.\n【详解】小明每天中午休息半小时，也就是休息30分钟。",
+    "knowledge_points": [
+      "时，分的认识及换算"
+    ],
+    "source": "24-25二年级上·吉林四平·期末"
+  },
+  {
+    "id": "155",
+    "unit": "第七单元认识时间1",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "3时，钟面上时针和分针形成的夹角是( )角，再过5分钟，时针和分针形成的夹角是( )角。",
+    "options": [],
+    "answer": "直;锐",
+    "solution": "【分析】角由一个顶点和两条边组成，和书本，黑板的角相同大小的是直角，比直角大的是钝角，比直角小的是锐角。钟面上长针是分针，短针是时针。有12个大格，分针走1大格是5分钟，时针走1大格是1小时。3时：分针指向12，时针指向3，组成的角是直角;再过5分钟，也就是分针指向1，时针刚过3，组成的角是锐角.\n【详解】由分析得:3时，钟面上时针和分针形成的夹角是直角，再过5分钟，时针和分针形成的夹角是锐角。",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征",
+      "整点时间与钟面指针的位置",
+      "一般时间与钟面指针的位置"
+    ],
+    "source": "23-24二年级上·浙江宁波·期末"
+  },
+  {
+    "id": "156",
+    "unit": "第七单元认识时间1",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "小玲早上8:30到校,11:00放学，她上午在校( )时( )分。",
+    "options": [],
+    "answer": "2;30",
+    "solution": "【分析】根据经过时间=结束时刻-开始时刻即可解答.\n【详解】11:00-8:30=2:30，则小玲早上8:30到校,11:00放学，她上午在校2时30分。",
+    "knowledge_points": [
+      "时，分，秒有关的计算"
+    ],
+    "source": "23-24二年级上·浙江宁波·期末"
+  },
+  {
+    "id": "157",
+    "unit": "第七单元认识时间1",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "时针从\"2\"走到\"6\"，走了( )时，分针从\"2\"走到\"6\"，走了( )分。",
+    "options": [],
+    "answer": "4;20",
+    "solution": "【分析】钟表上，短针是时针，长针是分针，时针走1大格是1小时，分针走1大格是5分钟。时针走1圈是12小时，分针走1圈是1小时。则时针走1个数字(1大格)是1小时，从2走到6，走了4个数字，即4大格，是4小时;分针走一个数字(1大格)是5分钟，分针从2走到6，走了4个数字(即4大格),是4个5分钟，用乘法计算:4×5=20(分钟),即20分钟.\n【详解】4×5=20(分),则时针从\"2\"走到\"6\"，走了4时，分针从\"2\"走到\"6\"，走了20分。",
+    "knowledge_points": [
+      "整点时间与钟面指针的位置",
+      "时，分的认识及换算"
+    ],
+    "source": "23-24二年级上·浙江宁波·期末"
+  },
+  {
+    "id": "158",
+    "unit": "第七单元认识时间1",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "下午第一节课的上课时间是2:50，王老师提前5分到教室做课前准备，王老师到教室的时间是下午( )。",
+    "options": [],
+    "answer": "2:45或2时45分",
+    "solution": "【分析】根据第一节上课时间是2:50，王老师提前5分到教室准备，老师下午到教室的时间是2时50分减去5分即可，据此解答.\n【详解】根据分析:2时50分-5分=2时45分;所以，王老师到教室的时间是下午2:45(或2时45分)。",
+    "knowledge_points": [
+      "时，分，秒有关的计算",
+      "时，分，秒时间的推算"
+    ],
+    "source": "23-24二年级上·河北保定·期末"
+  },
+  {
+    "id": "159",
+    "unit": "第七单元认识时间1",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "在( )里填上合适的单位名称.\n\n一节课的时间是40( );妈妈身高约1( )65( )\n一支水彩笔长约10( );一张试卷的长大约40( )",
+    "options": [],
+    "answer": "分钟或分或min;米或m;厘米或cm;厘米或cm;厘米或cm",
+    "solution": "【分析】根据情景，生活经验，以及对长度单位和数据大小的认识可知：计量一首歌用的时间用\"分钟\"作单位，则计量一节课的时间用\"分钟\"作单位;1米大约有成年人正常脚步两步长，所以计量妈妈身高用\"米\"作单位;1厘米大约是食指的指甲盖的长度，所以计量一支水彩笔的长度，一张试卷的长度用\"厘米\"作单位.\n【详解】一节课的时间是40分钟;妈妈身高约1米65厘米;一支水彩笔长约10厘米;一张试卷的长大约40厘米。",
+    "knowledge_points": [
+      "时间单位的选择",
+      "长度单位的选择"
+    ],
+    "source": "23-24二年级上·浙江宁波·期末"
+  },
+  {
+    "id": "160",
+    "unit": "第七单元认识时间1",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "在括号里填上\">\"\"<\"或\"=\".\n\n41( )18+22;45-7( )55-17;1时( )90分;65厘米+25厘米( )1米",
+    "options": [],
+    "answer": ">;=;<;<",
+    "solution": "【分析】比较数字的大小，首先要将需要计算的算式计算出来，其次要区分大小等于号，再进行数字大小的比较即可;需要进行单位换算的先进行换算再进行比较,1小时=60分,1米=100厘米.\n【详解】18+22=40,41>40，所以41>18+22;45-7=38,55-17=38，所以45-7=55-17;1时=60分,60分<90，所以1时<90分;1米=100厘米,65厘米+25厘米=90厘米，所以65厘米+25厘米<1米。",
+    "knowledge_points": [
+      "100以内数的比大小",
+      "两位数与两位数的退位减法",
+      "时，分的认识及换算",
+      "厘米和米之间的进率与换算"
+    ],
+    "source": "23-24二年级上·浙江绍兴·期末"
+  },
+  {
+    "id": "161",
+    "unit": "第七单元认识时间1",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "分针从12走到7，走了( )分，时针从5走到8走了( )时。",
+    "options": [],
+    "answer": "35;3",
+    "solution": "【分析】钟面上有12个大格，分针走一大格表示5分钟，时针走一大格表示1小时，据此数清楚走过多少大格，据此解答即可.\n【详解】12表示新的一圈开始，所以分针从12走到7，一共走了7大格。7×5=35(分),所以分针从12走到7，走了35分。8-5=3(格),时针从5走到8走了3大格，即走了3时。",
+    "knowledge_points": [
+      "时，分，秒有关的计算"
+    ],
+    "source": "23-24二年级上·山东菏泽·期末"
+  },
+  {
+    "id": "162",
+    "unit": "第七单元认识时间1",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "如图，现在的时间是( ),再过一刻，钟面上的时间是( ).\n\n![](images/82210de6ac886e5e6249dd69b25b064c35841797d9a132703241baebe20ca72b.jpg)",
+    "options": [],
+    "answer": "3时45分或3:45;4时或4:00",
+    "solution": "【分析】钟面上，时针走一大格表示1小时，分针走一小格表示1分钟，当时针指在两个数之间时，选较小的数作为小时数;一刻钟指的是15分钟。用现在的时间加上15分钟，即可求出一刻钟后的时间.\n【详解】3时45分+15分=4时，现在的时间是3时45分，再过一刻，钟面上的时间是4时。",
+    "knowledge_points": [
+      "一般时间与钟面指针的位置",
+      "时，分，秒时间的推算"
+    ],
+    "source": "23-24二年级上·福建福州·期末"
+  },
+  {
+    "id": "163",
+    "unit": "第七单元认识时间1",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "10时整，钟面上时针和分针所成的角是( )角;1时30分，钟面上时针和分针所成的角是( )角。",
+    "options": [],
+    "answer": "锐;钝",
+    "solution": "【分析】比三角尺中的直角小的角是锐角，比三角尺中的直角大的角是钝角，和三角尺中的直角相等的角是直角，据此解答.\n【详解】钟面上3时整和9时整时针和分针形成的角是直角,10时整，钟面上时针和分针所成的角是锐角;1时30分，钟面上时针和分针所成的角是钝角。",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征",
+      "整点时间与钟面指针的位置",
+      "一般时间与钟面指针的位置"
+    ],
+    "source": "23-24二年级上·浙江台州·期末"
+  },
+  {
+    "id": "164",
+    "unit": "第七单元认识时间1",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "在下面的括号里填上\">\"\"<\"或\"=\".\n\n7+7( )7×2;74-15( )53+8;25厘米( )2米5厘米\n9×4( )43-8;5×8+5( )8×6-8;50分钟( )半小时",
+    "options": [],
+    "answer": "=;<;<;>;>;>",
+    "solution": "【分析】先计算出每个算式的结果或先统一单位，然后比较大小即可。整数比较大小方法:①位数多的数大于位数少的数;②位数相同的，先比较最高位上的数，最高位上大的，数就大，最高位数相同的，就比较下一位，以此类推。1米=100厘米;半小时=30分钟.\n【详解】7+7=14,7×2=14，故,7+7=7×2;74-15=59,53+8=61，故,74-15<53+8;1米=100厘米,100厘米>25厘米，即1米>25厘米，故,25厘米<2米5厘米;9×4=36,43-8=35，故,9×4>43-8;5×8+5=40+5=45,8×6-8=40，故,5×8+5>8×6-8;半小时=30分钟，故,50分钟>半小时。",
+    "knowledge_points": [
+      "一位数与两位数的进位加法",
+      "7的乘法口诀及应用",
+      "时，分的认识及换算",
+      "表内乘加，乘减"
+    ],
+    "source": "23-24二年级上·浙江台州·期末"
+  },
+  {
+    "id": "165",
+    "unit": "第七单元认识时间1",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "分针从\"12\"走到\"3\"，走了( )分钟;时针从\"3\"走到\"6\"，走了( )小时。时针走一圈，走了( )小时。",
+    "options": [],
+    "answer": "15;3;12",
+    "solution": "【分析】对于分针，走过的数字格数乘5就是经过的分钟数;对于时针，看它走过的数字格数就能知道经过的小时数;同时要知道分针走一圈是60分钟即1小时，时针走一圈12小时.\n【详解】(1)分针从\"12\"走到\"3\"，走了3个数字格，每走一个数字格代表5分钟,3×5=15(分钟);(2)时针从\"3\"走到\"6\"，时针每走一个数字格就代表1小时,6-3=3(小时);(3)根据钟表的特征，时针走一圈，总共会经过12个数字格，每个数字格代表1小时，所以走了12小时。所以，分针从\"12\"走到\"3\"，走了15分钟;时针从\"3\"走到\"6\"，走了3小时。时针走一圈，走了12小时。",
+    "knowledge_points": [
+      "时，分的认识及换算"
+    ],
+    "source": "23-24二年级上·浙江台州·期末"
+  },
+  {
+    "id": "166",
+    "unit": "第七单元认识时间1",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "在括号里填上\">\"\"<\"或\"=\".\n\n11米( )10厘米;4×5( )9;3×9( )25;25+15( )50-20;8×3+3( )9×3;100分( )2时",
+    "options": [],
+    "answer": ">;>;>;>;=;<",
+    "solution": "【分析】整数的大小比较：比较数的大小，先看位数的多少，位数多的数就大;位数相同，从高位开始比较，高位上的数大则这个数大，高位上的数相同，就比较下一位。含有算式的，可以先计算出算式的结果，再比较大小;1米=100厘米,1时=60分，单位不统一时，先化成相同单位，再比较大小.\n【详解】10厘米<100厘米=1米，所以11米>10厘米;4×5=20，所以4×5>9;3×9=27，所以3×9>25;25+15=40,50-20=30，所以25+15>50-20;8×3+3=24+3=27,9×3=27，所以8×3+3=9×3;2时=60分+60分=120分，所以100分<2时。",
+    "knowledge_points": [
+      "100以内数的比大小",
+      "9的乘法口诀及应用",
+      "时，分的认识及换算",
+      "厘米和米之间的进率与换算"
+    ],
+    "source": "24-25二年级上·吉林四平·期末"
+  },
+  {
+    "id": "167",
+    "unit": "第七单元认识时间1",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "在括号里填上合适的单位名称.\n\n小轿车长约5( );一根黄瓜长21( );小学生睡眠9( );一节课的时间是40( );一座楼房高30( )",
+    "options": [],
+    "answer": "米或m;厘米或cm;小时或h或时;分或分钟或min;米或m",
+    "solution": "【分析】注意联系生活实际，计量单位和数据的大小，灵活的选择。小学生两臂伸开的长度大约1米，计量小轿车长度和楼房高度用\"米\"作单位比较合适。大拇指的指甲长度大约1厘米，计量黄瓜的长度用\"厘米\"作单位比较合适。削一个苹果的时间大约是1分，计量一节课的时间用\"分\"作单位比较合适。做一顿家常饭的时间大约是1小时，计量睡眠时间用\"小时\"作单位比较合适.\n【详解】小轿车长约5米;一根黄瓜长21厘米;小学生睡眠9小时;一节课的时间是40分;一座楼房高30米。",
+    "knowledge_points": [
+      "时间单位的选择",
+      "长度单位的选择"
+    ],
+    "source": "24-25二年级上·吉林四平·期末"
+  },
+  {
+    "id": "168",
+    "unit": "第七单元认识时间1",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "在括号里填上\">\"\"<\"或\"=\".\n\n22+45( )70;56-32( )57-32;60分( )1时\n4×4( )4+4;45厘米( )1米-56厘米;8时( )100分",
+    "options": [],
+    "answer": "<;<;=;>;>;>",
+    "solution": "【分析】先计算出每个算式的结果或先统一单位，然后比较大小即可。整数比较大小方法:①位数多的数大于位数少的数;②位数相同的，先比较最高位上的数，最高位上大的，数就大，最高位数相同的，就比较下一位，以此类推。1米=100厘米,1时=60分.\n【详解】22+45=67，故,22+45<70;56-32=24,57-32=25，故,56-32<57-32;1时=60分，即,60分=1时;4×4=16,4+4=8，故,4×4>4+4;1米=100厘米,100厘米-56厘米=44厘米，故,45厘米>1米-56厘米;1时=60分,100分=1时40分，故,8时>100分。",
+    "knowledge_points": [
+      "100以内数的比大小",
+      "4的乘法口诀及应用",
+      "时，分的认识及换算",
+      "厘米和米之间的进率与换算"
+    ],
+    "source": "23-24二年级上·河北保定·期末"
+  },
+  {
+    "id": "169",
+    "unit": "第七单元认识时间1",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "在括号里填上适当的单位。小红是二年级学生，身高1( )28( ),坐在长约6( )的教室里，用长约20( )的铅笔在写字。一节课的时间是40( ),小红一天在校的时间是6( )。",
+    "options": [],
+    "answer": "米或m;厘米或cm;米或m;厘米或cm;分或分钟或min;时或小时或h",
+    "solution": "【分析】根据生活经验，对长度单位，时间单位和数据大小的认识可知：计量较长的物体用米作单位，二年级学生双臂展开的长度大约是1米，所以计量教室的长度，用米作单位比较合适;计量比较短的物体的长度，通常用厘米作单位，食指的宽大约是1厘米，所以计量铅笔的长度用厘米作单位比较合适;小红的身高应写作1米28厘米;计量比较短的时间，常用分作单位，所以计量一节课的时间，用分作单位比较合适;计量比较长的时间，常用时作单位，所以计量一天在校的时间，用时作单位比较合适.\n【详解】小红是二年级学生，身高1米28厘米，坐在长约6米的教室里，用长约20厘米的铅笔在写字。一节课的时间是40分，小红一天在校的时间是6时。",
+    "knowledge_points": [
+      "时间单位的选择",
+      "长度单位的选择"
+    ],
+    "source": "23-24二年级上·河北保定·期末"
+  },
+  {
+    "id": "170",
+    "unit": "第七单元认识时间1",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "56厘米+44厘米=( )米;85分=( )时( )分",
+    "options": [],
+    "answer": "1;1;25",
+    "solution": "【分析】根据\"1米=100厘米,1时=60分\"及整数加减法的计算法则来解决此题.\n【详解】56厘米+44厘米=100厘米,100厘米=1米，即,56厘米+44厘米=1米;1时=60分,85分-60分=25分，故,85分=1时25分。",
+    "knowledge_points": [
+      "时，分的认识及换算",
+      "厘米和米之间的进率与换算"
+    ],
+    "source": "23-24二年级上·甘肃天水·期末"
+  },
+  {
+    "id": "171",
+    "unit": "第七单元认识时间1",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "在括号里填上大于，小于或等于号.\n\n63-25( )40;6×7( )40;1米-30厘米( )60厘米;3×9( )30;94-30( )65;40分钟( )半小时",
+    "options": [],
+    "answer": "<;>;>;<;<;>",
+    "solution": "【分析】整数的大小比较：比较数的大小，先看位数的多少，位数多的数就大;位数相同，从高位开始比较，高位上的数大则这个数大，高位上的数相同，就比较下一位。含有算式的，可以先计算出算式的结果，再比较大小;1小时=60分,1米=100厘米，单位不统一时，先化成相同单位，再比较大小.\n【详解】63-25=38，所以63-25<40;6×7=42，所以6×7>40;1米-30厘米=100厘米-30厘米=70厘米，所以1米-30厘米>60厘米;3×9=27，所以3×9<30;94-30=64，所以94-30<65;1小时=60分，半小时=30分钟，所以40分钟>半小时。",
+    "knowledge_points": [
+      "100以内数的比大小",
+      "两位数与两位数的退位减法",
+      "时，分的认识及换算",
+      "厘米和米之间的进率与换算"
+    ],
+    "source": "23-24二年级上·河南郑州·期末"
+  },
+  {
+    "id": "172",
+    "unit": "第七单元认识时间1",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "现在是4:00，再过一刻就是( ):( )。",
+    "options": [],
+    "answer": "4;15",
+    "solution": "【分析】1刻=15分，用开始时刻加经过时间即可求出结束时刻.\n【详解】1刻=15分,4:00+15分=4:15，现在是4:00，再过一刻就是4:15。",
+    "knowledge_points": [
+      "时，分，秒时间的推算"
+    ],
+    "source": "23-24二年级上·河南郑州·期末"
+  },
+  {
+    "id": "173",
+    "unit": "第七单元认识时间1",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "分针从3走到8是( )分，时针从2走到11是( )时。",
+    "options": [],
+    "answer": "25;9",
+    "solution": "【分析】钟面上较短的针是时针，较长的针是分针。时针走一大格是1时;分针走1小格是1分，走1大格是5分;秒针走1小格是1秒，走1大格是5秒。用分针走的大格数乘5即可求出走了多少分。时针走了多少大格就是多少时.\n【详解】8-3=5(大格),5×5=25(分),11-2=9(大格),分针从3走到8是25分，时针从2走到11是9时。",
+    "knowledge_points": [
+      "时，分的认识及换算",
+      "时，分，秒有关的计算"
+    ],
+    "source": "23-24二年级上·河南郑州·期末"
+  },
+  {
+    "id": "174",
+    "unit": "第七单元认识时间1",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "在括号里填上\">\"\"<\"\"=\"或者\"+\"\"-\"\"*\".\n\n4米( )40厘米;1时20分( )80分;8( )2=16;18( )6=12",
+    "options": [],
+    "answer": ">;=;*;-",
+    "solution": "【分析】比较数的大小时，位数多的数就大;位数相同比较最高位，最高位大的数就大;最高位相同比较下一位，直到比较出结果为止。第1题：根据1米=100厘米换算单位再比较;第2题：根据1时=60分换算单位再比较;第3题：根据乘法口诀二八十六解答;第4题:18减去6就是12.\n【详解】4米=400厘米;400厘米>40厘米，则4米>40厘米;1时20分=60分+20分=80分;8×2=16;18-6=12。",
+    "knowledge_points": [
+      "不退位减法(20以内)",
+      "8的乘法口诀及应用",
+      "时，分的认识及换算",
+      "厘米和米之间的进率与换算"
+    ],
+    "source": "24-25二年级上·西藏那曲·期末"
+  },
+  {
+    "id": "175",
+    "unit": "第七单元认识时间1",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "在括号里填上\"<\"\">\"\"=\"或\"+\"\"-\"\"*\".\n\n7+56( )64;36( )73-36;65( )9×7;68分钟( )1小时;22( )6=16;5( )9=45;0( )8=8;0( )5=0",
+    "options": [],
+    "answer": "<;<;>;>;-;*;+;*",
+    "solution": "【分析】有算式先算出算式的得数，再根据100以内整数比较大小，进行解答即可。1小时=60分钟，先将单位统一，再进行比较大小。根据整数加减法运算，乘法口诀结合题干要求进行解答即可.\n【详解】7+56=63,63<64，所以7+56<64.73-36=37,36<37，所以36<73-36.9×7=56,65>56，所以65>9×7.1小时=60分钟,68分钟>60分钟，所以68分钟>1小时。22-6=16，根据\"五九四十五\"可知:5×9=45,0+8=8,0乘任何数都等于0.0×5=0",
+    "knowledge_points": [
+      "100以内数的比大小",
+      "9的乘法口诀及应用",
+      "用7~9的乘法口诀求商",
+      "时，分的认识及换算"
+    ],
+    "source": "23-24二年级上·新疆昌吉·期末"
+  },
+  {
+    "id": "176",
+    "unit": "第七单元认识时间1",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "时针从10走到2走了( )时，分针从12走到3，走了( )分。",
+    "options": [],
+    "answer": "4;15",
+    "solution": "【分析】时针走一大格就是1小时，分针走一大格就是5分;先分别数一数时针和分针分别走了几大格，然后用乘法算一算，即可解决此题.\n【详解】时针从10走到11，走了1大格;从11走到12，走了1大格;从12走到1，走了1大格;从1走到2，走了1大格;一共走了4大格;1×4=4(时)。分针从12走到1，走了1大格;从1走到2，走了1大格;从2走到3，走了1大格;一共走了3大格;5×3=15(分)。即，时针从10走到2走了4时，分针从12走到3，走了15分。",
+    "knowledge_points": [
+      "5的乘法口诀及应用",
+      "4的乘法口诀及应用",
+      "时，分，秒有关的计算"
+    ],
+    "source": "24-25二年级上·西藏那曲·期末"
+  },
+  {
+    "id": "177",
+    "unit": "第七单元认识时间1",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "时针从12走到11，走了( )时;分针从7走到12，走了( )分;分针从6开始绕了一圈回到6，走了( )时。",
+    "options": [],
+    "answer": "11;25;1",
+    "solution": "【分析】时针走一大格是1时;分针走一大格是5分;分针走一圈就是60分，也就是1时。时针从12走到12是12大格，则，时针从12走到11就是11大格，也就是11时;分针从7走到12，走了12-7=5(大格),时间过去了5×5=25(分),即分针从7走到12，走了25分;分针从6开始绕了一圈回到6，也就是走了60分，即，走了1时.\n【详解】由题意分析得:12-7=5(大格),5×5=25(分),即时针从12走到11，走了11时;分针从7走到12，走了25分;分针从6开始绕了一圈回到6，走了1时。",
+    "knowledge_points": [
+      "时，分，秒有关的计算"
+    ],
+    "source": "23-24二年级上·甘肃天水·期末"
+  },
+  {
+    "id": "178",
+    "unit": "第七单元认识时间1",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "在括号里填上\"+\"\"-\"\"*\"或\">\"\"<\"\"=\".\n\n9( )5=45;52+32( )85;1+1( )1×1;1时( )59分\n60( )7=53;79( )95-20;34厘米+66厘米( )1米",
+    "options": [],
+    "answer": "*;<;>;>;-;>;=",
+    "solution": "【分析】根据乘法口诀计算，有算式的先计算出结果再比较大小，单位不统一的，先统一单位再比较大小.\n【详解】9×5=45;52+32=84,84<85，故52+32<85;1+1=2,1×1=1,2>1，故1+1>1×1;1时=60分,60分>59分，故1时>59分;60-7=53;95-20=75,79>75，故79>95-20;1米=100厘米,34厘米+66厘米=100厘米，故34厘米+66厘米=1米。",
+    "knowledge_points": [
+      "100以内数的比大小",
+      "9的乘法口诀及应用",
+      "时，分的认识及换算",
+      "厘米和米之间的进率与换算"
+    ],
+    "source": "23-24二年级上·福建福州·期末"
+  },
+  {
+    "id": "179",
+    "unit": "第七单元认识时间1",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "青青下午5:40开始做数学作业，做了20分钟，做完的时间是下午( )。",
+    "options": [],
+    "answer": "6:00",
+    "solution": "【分析】开始时刻+经过时间=结束时刻，据此计算.\n【详解】5:40+20分钟=6:00，青青下午5:40开始做数学作业，做了20分钟，做完的时间是下午6:00。",
+    "knowledge_points": [
+      "时，分，秒时间的推算"
+    ],
+    "source": "23-24二年级上·河南安阳·期末"
+  },
+  {
+    "id": "180",
+    "unit": "第七单元认识时间1",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "60分=( )时;一刻=( )",
+    "options": [],
+    "answer": "1;15分钟",
+    "solution": "【分析】根据时间单位之间的进率可知,1时=60分，一刻是15分钟，据此可解答.\n【详解】60分=1时;一刻=15分钟。",
+    "knowledge_points": [
+      "时，分的认识及换算"
+    ],
+    "source": "23-24二年级上·河南南阳·期末"
+  },
+  {
+    "id": "181",
+    "unit": "第七单元认识时间1",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "在括号里填上合适的长度单位.\n\n小刚的身高是128( ),早上从2( )长的床上起来，走路10分钟去学校。学校的教学楼高15( ),走进教室，小刚拿出长20( )的文具盒准备上课。",
+    "options": [],
+    "answer": "厘米或cm;米或m;米或m;厘米或cm",
+    "solution": "【分析】根据生活经验及结合给出的数据，来选择合适的长度单位。食指宽大约是1厘米，所以，计量小刚的身高和文具盒的长用\"厘米\"作单位比较合适;米尺的长度是1米，所以，计量床的长和教学楼的高用\"米\"作单位比较合适.\n【详解】由题意分析得：小刚的身高是128厘米，早上从2米长的床上起来，走路10分钟去学校。学校的教学楼高15米，走进教室，小刚拿出长20厘米的文具盒准备上课。",
+    "knowledge_points": [
+      "时，分的认识及换算",
+      "长度单位的选择"
+    ],
+    "source": "23-24二年级上·河南洛阳·期末"
+  },
+  {
+    "id": "182",
+    "unit": "第七单元认识时间1",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "分针从6走到12，走了( )分。时针从6走到12，走了( )时。",
+    "options": [],
+    "answer": "30;6",
+    "solution": "【分析】钟表上有12个大格,60个小格，每个大格中有5小格，分针走1小格是1分，走一大格是5分，时针走一大格是1时;分针从6走到12，即走了6大格，即6×5=30(分);时针从6走到12，走了6大格，即6时.\n【详解】分针从6走到12，走了30分。时针从6走到12，走了6时。",
+    "knowledge_points": [
+      "时，分的认识及换算"
+    ],
+    "source": "23-24二年级上·重庆秀山·期末"
+  },
+  {
+    "id": "183",
+    "unit": "第七单元认识时间1",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "在括号里填上合适的单位.\n\n一棵树高10( );数学书厚约1( );小学生睡眠时间应超过8( );一节课的时间是40( )",
+    "options": [],
+    "answer": "米或m;厘米或cm;时或h或小时;分或min或分钟",
+    "solution": "【分析】根据生活经验，对长度单位，时间单位和数据大小的认识可知：计量较长的物体用米作单位，二年级学生双臂展开的长度大约是1米，所以计量树的高度用米作单位比较合适;计量比较短的物体的长度，通常用厘米作单位，食指的宽大约是1厘米，所以计量数学书的厚度用厘米作单位比较合适;计量较长的时间常用时作单位，所以计量睡眠时间用时作单位比较合适;计量较短的时间常用分作单位，所以计量一节课的时间用分作单位比较合适.\n【详解】一棵树高10米;数学书厚约1厘米;小学生睡眠时间应超过8时;一节课的时间是40分。",
+    "knowledge_points": [
+      "时间单位的选择",
+      "长度单位的选择"
+    ],
+    "source": "23-24二年级上·浙江温州·期末"
+  },
+  {
+    "id": "184",
+    "unit": "第七单元认识时间1",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "分针从12走到8，一共走了( )分钟，再过( )分钟是1小时。",
+    "options": [],
+    "answer": "40;20",
+    "solution": "【分析】钟面上长针是分针，短针是时针。有12个大格，分针走1大格是5分钟，时针走1大格是1小时。分针从12走到8，走了8个大格，再用乘法计算出走了多少分钟即可。求再过几分钟是1小时，用1小时减去求出的分钟数即可，根据1时=60分换算单位后再计算.\n【详解】8×5=40(分钟),1时-40分=60分-40分=20分，分针从12走到8，一共走了40分钟，再过20分钟是1小时。",
+    "knowledge_points": [
+      "时，分的认识及换算",
+      "时，分，秒时间的推算"
+    ],
+    "source": "23-24二年级上·湖南湘西·期末"
+  },
+  {
+    "id": "185",
+    "unit": "第七单元认识时间1",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "分针从3走到9，走了( )大格，走了( )分。",
+    "options": [],
+    "answer": "6;30",
+    "solution": "【分析】时针走一大格是1时，分针走1小格是1分，走1大格是5分;从3走到9，走的格数=9-3=6，即走了6大格。则走了几分，用一格是5分乘走的格数.\n【详解】9-3=6(格),5×6=30(分),分针从3走到9，走了6大格，走了30分。",
+    "knowledge_points": [
+      "6的乘法口诀及应用",
+      "整点时间与钟面指针的位置",
+      "一般时间与钟面指针的位置",
+      "时，分的认识及换算"
+    ],
+    "source": "23-24二年级上·福建福州·期末"
+  },
+  {
+    "id": "186",
+    "unit": "第七单元认识时间1",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "分针从12走到8走了( )分，时针从12走到8走了( )时。",
+    "options": [],
+    "answer": "40;8",
+    "solution": "【分析】钟面上长针是分针，短针是时针。有12个大格，时针走1大格是1时，分针走1大格是5分。由此先计算出走了几个大格，再用乘法计算出走了多长时间即可.\n【详解】分针和时针从12走到8，都走了8个大格。分针:8×5=40(分);时针:8×1=8(时)。分针从12走到8走了40分，时针从12走到8走了8时。",
+    "knowledge_points": [
+      "8的乘法口诀及应用",
+      "时，分，秒时间的推算"
+    ],
+    "source": "2024二年级上·全国·专题练习"
+  },
+  {
+    "id": "187",
+    "unit": "第七单元认识时间1",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "在括号里填上\">\"\"<\"或\"=\".\n\n200分( )2时;1时40分( )100分;1时1刻( )90分",
+    "options": [],
+    "answer": ">;=;<",
+    "solution": "【分析】1时=60分,1刻=15分，据此将单位统一后再作比较.\n【详解】2时=60分+60分=120分钟,200>120，则200分>2时;1时40分=60分+40分=100分，则1时40分=100分;1时1刻=60分+15分=75分,75<90，则1时1刻<90分。",
+    "knowledge_points": [
+      "时，分的认识及换算"
+    ],
+    "source": "2024二年级上·全国·专题练习"
+  },
+  {
+    "id": "188",
+    "unit": "第七单元认识时间1",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "分针走1小格是( )分，分针走1大格是( )分，分针走一圈是( )分，也就是( )时，时针走1大格是( )时，时针走一圈是( )时。",
+    "options": [],
+    "answer": "1;5;60;1;1;12",
+    "solution": "【分析】根据钟面上12个数字把钟面分成12大格，每大格分5小格，共60小格，时针走1大格是1时，走一圈是12时，分针走1小格是1分，走1大格是5分，走一圈是60分。据此解答即可.\n【详解】分针走1小格是1分，分针走1大格是5分，分针走一圈是60分，也就是1时，时针走1大格是1时，时针走一圈是12时。",
+    "knowledge_points": [
+      "一般时间与钟面指针的位置",
+      "时，分的认识及换算"
+    ],
+    "source": "2024二年级上·全国·专题练习"
+  },
+  {
+    "id": "189",
+    "unit": "第七单元认识时间1",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "分针从2走到8，走了6分。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】分针走1大格是5分，求分针从2走到8，走了几分，先用减法求出走了几大格，然后乘上5，求出积，就是走了几分.\n【详解】8-2=6(大格),6×5=30(分),即，分针从2走到8，走了30分。原说法错误。故答案为: ×",
+    "knowledge_points": [
+      "6的乘法口诀及应用",
+      "时，分，秒有关的计算"
+    ],
+    "source": "24-25二年级上·重庆奉节·期末"
+  },
+  {
+    "id": "190",
+    "unit": "第七单元认识时间1",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "我们8时上课，小明7时55分到校，他迟到了。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】上课的时间晚于到校的时间则没有迟到，到校的时间晚于上课的时间则迟到了.\n【详解】我们8时上课，小明7时55分到校，上课的时间晚于小明到校的时间，他没有迟到。原题说法错误。故答案为: ×",
+    "knowledge_points": [
+      "时，分的认识及换算"
+    ],
+    "source": "24-25二年级上·河南南阳·期末"
+  },
+  {
+    "id": "191",
+    "unit": "第七单元认识时间1",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "小明写一个大字需要60分钟。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】心脏跳动一次的时间大约是1秒，计量写一个字的时间用\"秒\"作单位比较合适.\n【详解】小明写一个大字需要60秒。原题说法错误。故答案为: ×",
+    "knowledge_points": [
+      "时，分的认识及换算",
+      "秒的认识"
+    ],
+    "source": "24-25二年级上·内蒙古通辽·期末"
+  },
+  {
+    "id": "192",
+    "unit": "第七单元认识时间1",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "钟面上，分针从2走到5，走了3分。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】分针走一大格，表示走了5分;先用减法求出分针走了几个大格，然后乘5，求出积，即可解决.\n【详解】5-2=3(个),3×5=15(分),即，钟面上，分针从2走到5，走了15分。原题说法错误。故答案为: ×",
+    "knowledge_points": [
+      "5的乘法口诀及应用",
+      "时，分，秒有关的计算"
+    ],
+    "source": "24-25二年级上·甘肃天水·期末"
+  },
+  {
+    "id": "193",
+    "unit": "第七单元认识时间1",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "可以用来计量物体长度的单位是米，分。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】根据生活经验，对长度单位，时间单位和数据大小的认识可知：计量较长的物体用米作单位，二年级学生双臂展开的长度大约是1米;计量比较短的时间，常用分作单位，由此解答.\n【详解】米是用来计量物体长度的单位，分是用来计量时间的单位，原题说法错误。故答案为: ×",
+    "knowledge_points": [
+      "时，分的认识及换算",
+      "米的认识"
+    ],
+    "source": "24-25二年级上·内蒙古巴彦淖尔·期末"
+  },
+  {
+    "id": "194",
+    "unit": "第七单元认识时间1",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "小红说1刻钟就是30分钟。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】在时间的计量里,1刻钟表示的是15分钟，而不是30分钟。这是一个基本的时间换算常识。据此解答.\n【详解】根据分析可知：小红说1刻钟就是30分钟。说法错误。故答案为: ×",
+    "knowledge_points": [
+      "时，分的认识及换算"
+    ],
+    "source": "24-25二年级上·黑龙江·期末"
+  },
+  {
+    "id": "195",
+    "unit": "第七单元认识时间1",
+    "question_type": "判断题",
+    "difficulty": 0.94,
+    "question": "东东同学认为，\"时\"是用来计量长度的单位。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】联系生活实际，\"时，分，秒\"是用来计量时间单位的，\"厘米，米\"是用来计量长度单位的，据此解答.\n【详解】\"时\"是用来计量时间单位的。原题说法错误。故答案为: ×",
+    "knowledge_points": [
+      "时间单位的选择",
+      "长度单位的选择"
+    ],
+    "source": "23-24二年级上·重庆丰都·期末"
+  },
+  {
+    "id": "196",
+    "unit": "第七单元认识时间1",
+    "question_type": "判断题",
+    "difficulty": 0.65,
+    "question": "妈妈上午8时上班,12时下班，她上午工作了4小时。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】经过时间=结束时刻-开始时刻，用下班时间减上班时间即可求解.\n【详解】12时-8时=4(小时),妈妈上午8时上班,12时下班，她上午工作了4小时。原题说法正确。故答案为:√",
+    "knowledge_points": [
+      "时，分，秒时间的推算"
+    ],
+    "source": "23-24二年级上·四川广元·期末"
+  },
+  {
+    "id": "197",
+    "unit": "第七单元认识时间1",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "时针走一大格是1分。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】钟面上较短的针是时针，较长的针是分针。时针走一大格是1时;分针走1小格是1分，走1大格是5分;秒针走1小格是1秒，走1大格是5秒。时针刚过几就是几时;从12开始，分针指向第多少个小格就是多少分.\n【详解】时针走一大格是1时。原题说法错误。故答案为: ×",
+    "knowledge_points": [
+      "时，分的认识及换算"
+    ],
+    "source": "23-24二年级上·四川广元·期末"
+  },
+  {
+    "id": "198",
+    "unit": "第七单元认识时间1",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "当9:00和3:00时，时针和分针成直角。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】用三角尺的直角进行比较，和三角尺的直角重合则为直角，小于则为锐角，大于则为钝角.\n【详解】当9:00和3:00时，时针和分针成直角。原题说法正确。故答案为:√",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征",
+      "整点时间与钟面指针的位置"
+    ],
+    "source": "23-24二年级上·四川德阳·期末"
+  },
+  {
+    "id": "199",
+    "unit": "第七单元认识时间1",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "时针在7和8之间，分针指向6，是7:30。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】分针走1小格是1分，走一大格是5分;时针走过数字几就是几时。据此判断即可.\n【详解】时针在7和8之间，即时针走过7是7时;分针指向6，即分针走过6个大格,6×5=30(分)即30个小格就是30分;所以时针在7和8之间，分针指向6，是7:30，说法正确。故答案为:√",
+    "knowledge_points": [
+      "半点时间与钟面指针的位置"
+    ],
+    "source": "23-24二年级上·河南安阳·期末"
+  },
+  {
+    "id": "200",
+    "unit": "第七单元认识时间1",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "小明拼装一辆玩具赛车用了27分，小亮用了34分，小亮比小明快7分。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】根据题意可知：做同一件事情，用时越短则越快，可知谁比谁快，则比较两人用时长短。再求出小明和小亮相差的时间.\n【详解】27<34,34-27=7(分),则小明拼装一辆玩具赛车用了27分，小亮用了34分，小亮比小明慢7分，原题说法错误。故答案为: ×",
+    "knowledge_points": [
+      "两位数与两位数的退位减法",
+      "时间快慢的比较"
+    ],
+    "source": "23-24二年级上·河南南阳·期末"
+  },
+  {
+    "id": "201",
+    "unit": "第七单元 认识时间",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "红红8:30和爸爸一起去外婆家送水果，然后去图书馆借书,12:30开始午休。红红到达图书馆的时间可能是( )。",
+    "options": [
+      "A. 8:25",
+      "B. 10:30",
+      "C. 12:40"
+    ],
+    "answer": "B",
+    "solution": "【分析】根据题意,8:30红红和爸爸去外婆家送水果，然后去图书馆借书,12:30开始午休，也就是到图书馆的时间在8:30之后，在12:30之前，由此解答.\n【详解】A。8:25在8:30之前，红红和爸爸还没有出发去外婆家，不符合题意;B。10:30在8:30和12:30之间，符合题意;C。12:40在12:30之后，已经开始午休了，不符合题意。所以红红到达图书馆的时间可能是10:30。故答案为:B",
+    "knowledge_points": [
+      "时，分，秒时间的推算"
+    ],
+    "source": "23-24 二年级上·重庆秀山·期末"
+  },
+  {
+    "id": "202",
+    "unit": "第七单元 认识时间",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "下面的时刻，分针和时针形成的角不是直角的是( )。",
+    "options": [
+      "A. 3时",
+      "B. 3时30分",
+      "C. 9时"
+    ],
+    "answer": "B",
+    "solution": "【分析】分针指着12，时针指着几就是几时。分针指着6，时针在两个数之间。较小的那个数是几，就是几时30分。由题意得，可以先找出选项中的时刻的分针和时针所形成的角，然后找出不是直角的选项即可.\n【详解】A。![](images/04bb7a7c9ea6c14d484a59f0f9f2edd1c0a0061624d1458b6385077818289b30.jpg)由图可知,3时时，分针和时针形成的角是直角。B。![](images/2aca8c2ab591fca2491c03d019243a98344164c28296936a0ed99c652376dce3.jpg)由图可知,3时30分时，分针和时针形成的角不是直角。C。![](images/d87430f9ad75c229547e2d29be9ea91a67a459d1873676d8dfb1ea14d246197a.jpg)由图可知,9时时，分针和时针形成的角是直角。故答案为:B",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征",
+      "整点时间与钟面指针的位置",
+      "半点时间与钟面指针的位置"
+    ],
+    "source": "24-25 二年级上·福建厦门·期中"
+  },
+  {
+    "id": "203",
+    "unit": "第七单元 认识时间",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "下面说法正确的是( )。",
+    "options": [
+      "A. 笔算加减法时，要从个位算起。",
+      "B. 角的大小与角两边的长短有关。",
+      "C. 钟面上3时或6时整，时针和分针成直角。"
+    ],
+    "answer": "A",
+    "solution": "【分析】加法计算时，相同数位对齐，从个位加起，哪一位相加满十就向前一位进1。减法计算时，相同数位对齐，从个位减起，哪一位不够减就向前一位借1当十。角的大小与角的两条边张开的程度有关，而角的大小与边的长短没有关系。两边张开的越大，角就越大。钟面上较短的针是时针，较长的针是分针。分针指向12，时针指向几就是几时。三角尺上最大的角为直角.\n【详解】A。笔算加减法时，要从个位算起，原题说法正确。B。角的大小与角两边的长短无关，原题说法错误。C。钟面上3时整，时针和分针成直角;6时整，时针和分针不成直角。原题说法错误。故答案为:A",
+    "knowledge_points": [
+      "两位数与两位数的进位加法",
+      "直角，钝角，锐角的认识及特征",
+      "角的大小比较",
+      "整点时间与钟面指针的位置"
+    ],
+    "source": "24-25 二年级上·福建莆田·期中"
+  },
+  {
+    "id": "204",
+    "unit": "第七单元 认识时间",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "当钟面上的时刻是5时整时，时针和分针形成的夹角是( )。",
+    "options": [
+      "A. 锐角",
+      "B. 直角",
+      "C. 钝角"
+    ],
+    "answer": "C",
+    "solution": "【分析】5时整，时针指向5，分针指向12，形成的角可用三角尺进行测量，大于直角的角是钝角，小于直角的角是锐角，与三角尺中直角相等的是直角。据此即可解答。本题主要考查钟面上时针和分针所成角度的问题.\n【详解】据分析可知：当钟面上的时刻是5时整时，时针和分针形成的夹角是钝角。故答案为:C",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征",
+      "整点时间与钟面指针的位置"
+    ],
+    "source": "23-24 二年级上·河南濮阳·期中"
+  },
+  {
+    "id": "205",
+    "unit": "第七单元 认识时间",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "电子表显示6:05，表示( )。",
+    "options": [
+      "A. 6时50分",
+      "B. 6时零5分",
+      "C. 6时零5秒"
+    ],
+    "answer": "B",
+    "solution": "【分析】根据电子表显示时间的特点可知：\"：\"左边的数字表示几时，\"：\"右边的数字表示几分;所以显示6:05，表示6时零5分。据此选择.\n【详解】根据分析可知：电子表显示6:05，表示6时零5分。故答案为:B",
+    "knowledge_points": [
+      "时，分的认识及换算"
+    ],
+    "source": "23-24 三年级上·河北邢台·期中"
+  },
+  {
+    "id": "206",
+    "unit": "第七单元 认识时间",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "钟面上是整时的时候，分针和时针不能形成直角的是( )。",
+    "options": [
+      "A. 3时",
+      "B. 6时",
+      "C. 9时"
+    ],
+    "answer": "B",
+    "solution": "【分析】钟面上较短的针是时针，较长的针是分针。分针指向12，时针指向几就是几时。三角尺上最大的角为直角，用三角板的直角进行比较测量，比直角小的就是锐角，比直角大的就是钝角。据此解答.\n【详解】A。3时整，时针指向3，分针指向12，这个时刻分针和时针形成直角。B。6时整，时针指向6，分针指向12，这个时刻分针和时针不能形成直角。C。9时整，时针指向9，分针指向12，这个时刻分针和时针形成直角。分针和时针不能形成直角的是6时。故答案为:B",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征",
+      "整点时间与钟面指针的位置"
+    ],
+    "source": "22-23 二年级上·河南南阳·期中"
+  },
+  {
+    "id": "207",
+    "unit": "第七单元 认识时间",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "时针和分针形成的较小角是钝角的是( )。",
+    "options": [
+      "A. ![](images/c0f70f9e5f072f9b0fc7a34db82ba35b1a720fbc068a44ea6af90ca545e30b19.jpg)",
+      "B. ![](images/a34f01093b8b2852920dd7bc48f7b416e16034211cbd2e34231ff28300fec278.jpg)",
+      "C. ![](images/18412cbeb4791bb5dd087ff0d6c812d08288c4739e1c64711bd57e7a403c556f.jpg)"
+    ],
+    "answer": "A",
+    "solution": "【分析】钟面上较短的针是时针，较长的针是分针。三角尺上最大的角为直角，用三角板的直角进行比较测量，比直角小的就是锐角，比直角大的就是钝角.\n【详解】A。时针和分针形成的较小角是钝角;B。时针和分针形成的较小角是直角;C。时针和分针形成的较小角是锐角。故答案为:A",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征",
+      "整点时间与钟面指针的位置",
+      "一般时间与钟面指针的位置"
+    ],
+    "source": "22-23 二年级上·浙江·期中"
+  },
+  {
+    "id": "208",
+    "unit": "第七单元 认识时间",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "1个人唱一首歌用3分,6个人齐唱这首歌要用( )分。",
+    "options": [
+      "A. 3",
+      "B. 9",
+      "C. 18"
+    ],
+    "answer": "A",
+    "solution": "【分析】根据题意，一个人唱一首歌用3分，说明这首歌时长是3分，所以无论几个人唱，只要是一起唱，都是3分，由此解答.\n【详解】由分析可知,1个人唱一首歌用3分,6个人齐唱这首歌要用3分。故答案为:A",
+    "knowledge_points": [
+      "时，分的认识及换算"
+    ],
+    "source": "23-24 二年级下·河南驻马店·期末"
+  },
+  {
+    "id": "209",
+    "unit": "第七单元 认识时间",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "小明从家到学校要走15分钟，他每天要在7:40到校，他应该在什么时候从家出发，才能准时到校。正确的解答是( )。",
+    "options": [
+      "A. 7:45",
+      "B. 7:25",
+      "C. 7:15"
+    ],
+    "answer": "B",
+    "solution": "【分析】开始时刻=结束时刻-经过时间;据此解答即可.\n【详解】7:40-15分=7:25，所以他应该在7:25从家出发，才能准时到校。故答案为:B",
+    "knowledge_points": [
+      "时，分，秒时间的推算"
+    ],
+    "source": "18-19 二年级下·江苏·期末"
+  },
+  {
+    "id": "210",
+    "unit": "第七单元 认识时间",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "钟表上，时针在8和9之间，分针指向7，是( )。",
+    "options": [
+      "A. 8:07",
+      "B. 8:35",
+      "C. 9:07"
+    ],
+    "answer": "B",
+    "solution": "【分析】钟面上长针是分针，短针是时针。有12个大格，分针走1大格是5分钟，时针走1大格是1小时。时针在8和9之间是8时，分针指向7是35分，也就是8时35分，也写作8:35.\n【详解】由分析可知，钟表上，时针在8和9之间，分针指向7，是8:35。故答案为:B",
+    "knowledge_points": [
+      "一般时间与钟面指针的位置"
+    ],
+    "source": "23-24 二年级下·河北保定·期末"
+  },
+  {
+    "id": "211",
+    "unit": "第七单元 认识时间",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "如果时针走1大格，那么分针走( )大格。",
+    "options": [
+      "A. 12",
+      "B. 30",
+      "C. 60"
+    ],
+    "answer": "A",
+    "solution": "【分析】钟面上长针是分针，短针是时针。有12个大格，时针走1大格是1小时。分针走1大格是5分钟，走1圈是1小时，也就是走12个大格是1小时，由此解答.\n【详解】由分析可知，时针走1大格，那么分针走12大格。故答案为:A",
+    "knowledge_points": [
+      "时，分的认识及换算"
+    ],
+    "source": "23-24 二年级下·河北邢台·期末"
+  },
+  {
+    "id": "212",
+    "unit": "第七单元 认识时间",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "钟面上分针从12走到4，走了( )分钟。",
+    "options": [
+      "A. 15",
+      "B. 4",
+      "C. 20"
+    ],
+    "answer": "C",
+    "solution": "【分析】钟面上总共有60个小格,12个大格，每个大格里都有5个小格，分针走过多少小格就是多少分.\n【详解】分针从12走到4，一共走了4个大格,4×5=20(个),即走了20个小格;所以走了20分钟。故答案为:C",
+    "knowledge_points": [
+      "时，分，秒有关的计算"
+    ],
+    "source": "23-24 二年级下·甘肃平凉·期末"
+  },
+  {
+    "id": "213",
+    "unit": "第七单元 认识时间",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "播放1集动画片的时间是20分钟，播放( )集的时间是1小时。",
+    "options": [
+      "A. 1",
+      "B. 2",
+      "C. 3"
+    ],
+    "answer": "C",
+    "solution": "【分析】1时=60分钟，几个20分钟相加等于60分钟，动画片就播放几集。据此解答即可.\n【详解】1时=60分钟,20+20+20=60(分钟),3个20分钟相加等于60分钟，所以播放3集的时间是1小时。故答案为:C",
+    "knowledge_points": [
+      "整十数之间的加减法",
+      "100以内数的连加运算",
+      "时，分的认识及换算"
+    ],
+    "source": "22-23 二年级下·河南周口·期末"
+  },
+  {
+    "id": "214",
+    "unit": "第七单元 认识时间",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "时针指向4和5之间，分针指向9，这时是( )。",
+    "options": [
+      "A. 9:30",
+      "B. 9:25",
+      "C. 4:45"
+    ],
+    "answer": "C",
+    "solution": "【分析】钟面上有12个大格，分针走1大格是5分钟，时针走1大格是1小时。时针在4和5之间，是4时多，分针指向9，是5×9=45(分),此时时间是4时45分，也写作4:45，由此解答.\n【详解】由分析可知，时针指向4和5之间，分针指向9，这时是4:45。故答案为:C",
+    "knowledge_points": [
+      "一般时间与钟面指针的位置"
+    ],
+    "source": "22-23 二年级上·福建莆田·期末"
+  },
+  {
+    "id": "215",
+    "unit": "第七单元 认识时间",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "电影在下午3:45开始放映。下面( )个时间丁丁会在踢球.\n\n![](images/c70de6e63b132cb1f97aa85157e3c3971171006089d7803f18e331f6a2585635.jpg)",
+    "options": [
+      "A. 2:50",
+      "B. 1:35",
+      "C. 4:20"
+    ],
+    "answer": "A",
+    "solution": "【分析】时针指向1和2之间，表示1时多，分针指向7，表示35分，合起来就是1:35;也就是丁丁踢球的时间是在1:35之后，且在3:45之前;据此解决.\n【详解】A。2:50在1:35之后，且在3:45之前，符合题意;B。1:35正在写作业，不符合题意;C。4:20在3:45之后，不符合题意;即，电影在下午3:45开始放映。在2:50丁丁会在踢球。故答案为:A",
+    "knowledge_points": [
+      "一般时间与钟面指针的位置"
+    ],
+    "source": "23-24 二年级上·福建莆田·期末"
+  },
+  {
+    "id": "216",
+    "unit": "第七单元 认识时间",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "下面钟表显示的时间再过一刻是( ).\n\n![](images/ae8da7dd31a1361dba4c5337ebd0ccaf07529d124ee9e9c3c985025b5136cc97.jpg)",
+    "options": [
+      "A. 8时50分",
+      "B. 9时",
+      "C. 8时55分"
+    ],
+    "answer": "B",
+    "solution": "【分析】一刻是15分钟，先读出钟面上的时间，然后加上15分钟得出结论即可.\n【详解】8时45分+15分=9时，即钟表显示的时间再过一刻是9时。故答案为:B",
+    "knowledge_points": [
+      "一般时间与钟面指针的位置",
+      "时，分，秒时间的推算"
+    ],
+    "source": "23-24 二年级上·福建莆田·期末"
+  },
+  {
+    "id": "217",
+    "unit": "第七单元 认识时间",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面时间( ),分针和时针成直角。",
+    "options": [
+      "A. 3:15",
+      "B. 3:30",
+      "C. 5:00",
+      "D. 9:00"
+    ],
+    "answer": "D",
+    "solution": "【分析】据题意可知，本题考查对于分针和时针位置的认识，钟表中有12个时辰，且平均分布12格，每格代表5分钟，即可知选项中各个时间指向的位置，且钟表上下左右中间的对应时间分别是:12点,6点,3点,9点，当时针与分针形成直角(90°)时，时间分别为:3点整,9点整，根据题目选项，可得出答案。本题考查学生对于钟表指针位置的认识和角的判断.\n【详解】A。3:15时针指向3和4之间位置，分针指向3，形成锐角;B。3:30时针指向3和4的中间，分针指向6，形成锐角;C。5:00时针指向5，分针指向12，形成钝角;D。9:00时针指向9，分针指向12，形成直角。故答案为:D",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征",
+      "整点时间与钟面指针的位置"
+    ],
+    "source": "23-24 二年级上·福建莆田·期末"
+  },
+  {
+    "id": "218",
+    "unit": "第七单元 认识时间",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "下边的钟面时间是( ).\n\n![](images/4d732086ab4485f2ed248610b3dd225bf105f9a2c2240deb60316d09e0d3f6d8.jpg)",
+    "options": [
+      "A. 9时11分",
+      "B. 9时55分",
+      "C. 10时55分"
+    ],
+    "answer": "B",
+    "solution": "【分析】根据钟表的认识，当分针指向12时，时针指向几就是几时整;时针刚过几就是几时，分针指向多少分，就是几时多少分，据此解答即可.\n【详解】由图可知，时针指向9和10之间，分针指向55分，所以钟面时间是9时55分。故答案为:B",
+    "knowledge_points": [
+      "一般时间与钟面指针的位置"
+    ],
+    "source": "22-23 二年级上·福建莆田·期末"
+  },
+  {
+    "id": "219",
+    "unit": "第七单元 认识时间",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "时针走一圈，分针要走( )。",
+    "options": [
+      "A. 1圈",
+      "B. 10圈",
+      "C. 12圈"
+    ],
+    "answer": "C",
+    "solution": "【分析】钟面上有12大格60小格，时针走一大格是一小时，走一圈是12小时，分针走一大格是5分钟，走一圈是一小时;据此即可解答.\n【详解】钟面上时针走一圈，也就是走12小时，分针要走12圈。故答案为:C",
+    "knowledge_points": [
+      "时，分的认识及换算"
+    ],
+    "source": "23-24 二年级下·河南周口·期末"
+  },
+  {
+    "id": "220",
+    "unit": "第七单元 认识时间",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "5小时前是9:00，现在钟面上时针指向( )。",
+    "options": [
+      "A. 1",
+      "B. 2",
+      "C. 3"
+    ],
+    "answer": "B",
+    "solution": "【分析】根据题意，从9:00向后推5个小时即可。10:00,11:00,12:00,1:00,2:00，则现在的时间为2:00，钟面上时针指向2，分针指向12.\n【详解】5小时前是9:00，现在钟面上时针指向2。故答案为:B",
+    "knowledge_points": [
+      "整点时间与钟面指针的位置"
+    ],
+    "source": "23-24 二年级上·全国·课后作业"
+  },
+  {
+    "id": "221",
+    "unit": "第七单元 认识时间",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "2小时后是12:30，现在钟面上显示的时间是( )。",
+    "options": [
+      "A. 14:30",
+      "B. 10:30",
+      "C. 2:30"
+    ],
+    "answer": "B",
+    "solution": "【分析】要求12:30前2小时是多少，根据钟表知识可知:12:30前2小时是10:30，据此解答即可.\n【详解】据分析可知：现在钟面上显示的时间是10:30。故答案为:B",
+    "knowledge_points": [
+      "时，分，秒时间的推算"
+    ],
+    "source": "23-24 二年级上·全国·课后作业"
+  },
+  {
+    "id": "222",
+    "unit": "第七单元 认识时间",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "分针从12走到12，走了( )。",
+    "options": [
+      "A. 12分钟",
+      "B. 12小时",
+      "C. 60分钟"
+    ],
+    "answer": "C",
+    "solution": "【分析】分针走1小格是1分钟，走1大格是5分钟，走一圈是60分钟;分针从12走到12，刚好走了一圈，也就是走了60分钟;据此解决.\n【详解】由题意分析得：分针从12走到12，走了60分钟。故答案为:C",
+    "knowledge_points": [
+      "时，分的认识及换算"
+    ],
+    "source": "23-24 二年级上·全国·课后作业"
+  },
+  {
+    "id": "223",
+    "unit": "第七单元 认识时间",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "佳佳从晚上8:15开始读课外书,40分钟后睡觉，从读书到睡觉，钟面上分针走了( )大格。",
+    "options": [
+      "A. 3",
+      "B. 8",
+      "C. 11"
+    ],
+    "answer": "B",
+    "solution": "【分析】钟面上分针走一个大格是5分钟，根据五八四十可知,40分钟分针走了8个大格，据此得出结论即可.\n【详解】5×8=40(分),即钟面上分针走了8个大格。故答案为:B",
+    "knowledge_points": [
+      "时，分，秒有关的计算"
+    ],
+    "source": "23-24 二年级上·全国·课后作业"
+  },
+  {
+    "id": "224",
+    "unit": "第七单元 认识时间",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "小宇在规定时间内完成作业，写语文作业用去了规定时间的一半，写数学作业用去了剩下时间的一半，最后还有10分钟读英语，小宇完成全部作业要( )分钟。",
+    "options": [
+      "A. 20",
+      "B. 40",
+      "C. 60"
+    ],
+    "answer": "B",
+    "solution": "【分析】由题意分析可知，英语和数学用时一样长，都是10分钟，则小宇写完作业规定时间的一半是(10+10=20)分钟;则写完作业规定的时间是(20+20=40)分钟;据此解决.\n【详解】10+10=20(分钟),20+20=40(分钟),即，小宇完成全部作业要40分钟。故答案为:B",
+    "knowledge_points": [
+      "倒推问题",
+      "时，分的认识及换算"
+    ],
+    "source": "23-24 二年级上·全国·课后作业"
+  },
+  {
+    "id": "225",
+    "unit": "第七单元 认识时间",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "丽丽读完一首古诗需要20秒,3人齐读这首古诗需要( )秒。",
+    "options": [
+      "A. 20",
+      "B. 60",
+      "C. 1"
+    ],
+    "answer": "A",
+    "solution": "【分析】3人齐读这首古诗是同时进行的，所以,3人齐读这首古诗需要的时间与一个人读完一首古诗需要的时间是一样的;据此解决即可.\n【详解】由题意分析得：丽丽读完一首古诗需要20秒,3人齐读这首古诗需要20秒。故答案为:A",
+    "knowledge_points": [
+      "秒的认识"
+    ],
+    "source": "23-24 二年级上·全国·课后作业"
+  },
+  {
+    "id": "226",
+    "unit": "第七单元 认识时间",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "我们读一篇课文需要5( )。",
+    "options": [
+      "A. 时",
+      "B. 分",
+      "C. 厘米"
+    ],
+    "answer": "B",
+    "solution": "【分析】根据生活经验，对时间单位和数据大小的认识可知：表示比较长的时间，常用时作单位;表示比较短的时间，常用分作单位，读一篇课文需要的时间较短，用分作单位比较合适.\n【详解】A。5时的时间很长，不符合读一篇课文的时间;B。5分符合读一篇课文的时间;C。5厘米是表示长度的单位，不符合题意。所以读一篇课文需要5分。故答案为:B",
+    "knowledge_points": [
+      "时间单位的选择",
+      "厘米的认识"
+    ],
+    "source": "23-24 二年级上·全国·单元测试"
+  },
+  {
+    "id": "227",
+    "unit": "第七单元 认识时间",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "一分钟之内，小桃红不可能完成( )。",
+    "options": [
+      "A. 跳绳4次",
+      "B. 做口算题10道",
+      "C. 写一篇作文"
+    ],
+    "answer": "C",
+    "solution": "【分析】1分钟的时间比较短，根据生活经验判断，对时间单位和数据大小的认识。一分钟之内可以跳绳4次;一分钟之内可以做口算题10道;写一篇作文大约需要15~20分钟;据此选择即可。要注意联系生活实际，计量单位和数据的大小，进行解答.\n【详解】由分析可知，一分钟之内，小桃红不可能完成写一篇作文。故答案为:C",
+    "knowledge_points": [
+      "时，分的认识及换算",
+      "时间的估计"
+    ],
+    "source": "23-24 二年级上·全国·单元测试"
+  },
+  {
+    "id": "228",
+    "unit": "第七单元 认识时间",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "时针从1走到4，分针走了( )。",
+    "options": [
+      "A. 3大格",
+      "B. 3圈",
+      "C. 30圈"
+    ],
+    "answer": "B",
+    "solution": "【分析】钟面上长针是分针，短针是时针。有12个大格，时针走1大格是1小时，分针走1圈是1小时。由此计算出时针走了几小时，相对应的分针就走了几圈.\n【详解】时针从1走到4，走了3大格，也就是3小时，分针就走了3圈。故答案为:B",
+    "knowledge_points": [
+      "时，分的认识及换算"
+    ],
+    "source": "23-24 二年级上·全国·单元测试"
+  },
+  {
+    "id": "229",
+    "unit": "第七单元 认识时间",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "( )分是一刻钟。",
+    "options": [
+      "A. 5",
+      "B. 10",
+      "C. 15"
+    ],
+    "answer": "C",
+    "solution": "【分析】根据1小时分4刻钟,1刻钟为15分钟。据此解答。本题考查时间的计算，熟练掌握数量关系换算单位.\n【详解】由分析可知,15分是1刻钟。故答案为:C.",
+    "knowledge_points": [
+      "时，分的认识及换算"
+    ],
+    "source": "23-24 二年级上·全国·单元测试"
+  },
+  {
+    "id": "230",
+    "unit": "第七单元 认识时间",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "小石头收拾书包准备回家，大约用了( )。",
+    "options": [
+      "A. 3分",
+      "B. 30分",
+      "C. 3时"
+    ],
+    "answer": "A",
+    "solution": "【分析】削一个苹果的时间大约是1分钟，做一顿家常饭的时间大约是1小时。联系生活实际，计量单位和数据的大小，收拾书包一般只需要几分钟.\n【详解】A。3分钟较短，符合;B。对于收拾书包来说,30分钟太久，不符合;C。3小时将近一下午的工作时间，太久，不符合。小石头收拾书包准备回家，大约用了3分。故答案为:A",
+    "knowledge_points": [
+      "时，分的认识及换算"
+    ],
+    "source": "23-24 二年级上·全国·单元测试"
+  },
+  {
+    "id": "231",
+    "unit": "第七单元 认识时间",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "钟表上分针从2走到9，走了( )。",
+    "options": [
+      "A. 7时",
+      "B. 7分",
+      "C. 35分"
+    ],
+    "answer": "C",
+    "solution": "【分析】在钟面上，分成12个大格，一个大格又分成了5个小格，时针走一个大格是1小时;分针每走1小格是1分，走1大格是5分，据此解答。分针从数字\"2\"走到\"9\"，走了7个大格，是5×7=35(分).\n【详解】5×7=35(分),钟表上分针从2走到9，走了35分。故答案为:C",
+    "knowledge_points": [
+      "一般时间与钟面指针的位置",
+      "时，分，秒有关的计算"
+    ],
+    "source": "22-23 二年级下·河南商丘·期末"
+  },
+  {
+    "id": "232",
+    "unit": "第七单元 认识时间",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "从7时30分起，分针又走了15分，是( )。",
+    "options": [
+      "A. 7时45分",
+      "B. 7时15分",
+      "C. 7时35分"
+    ],
+    "answer": "A",
+    "solution": "【分析】根据结束时间=开始时间+经过时间;代入数据据此解决.\n【详解】7时30分+15分=7时45分，即，从7时30分起，分针又走了15分，是7时45分。故答案为:A",
+    "knowledge_points": [
+      "时，分，秒时间的推算"
+    ],
+    "source": "23-24 二年级下·湖南邵阳·期末"
+  },
+  {
+    "id": "233",
+    "unit": "第七单元 认识时间",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "佳佳每天下午放学后，从7点开始，先拍球20分钟，再练字10分钟，她再看( )故事书就正好是1小时。",
+    "options": [
+      "A. 20分钟",
+      "B. 30分钟",
+      "C. 70分钟"
+    ],
+    "answer": "B",
+    "solution": "【分析】用1时先减去拍球的时间，求出差，再减去练字的时间，求出差，即可解决。1小时=60分钟.\n【详解】1小时-20分钟=40分钟,40分钟-10分钟=30分钟，即，佳佳每天下午放学后，从7点开始，先拍球20分钟，再练字10分钟，她再看30分钟故事书就正好是1小时。故答案为:B",
+    "knowledge_points": [
+      "时，分，秒有关的计算"
+    ],
+    "source": "23-24 二年级下·河南新乡·期末"
+  },
+  {
+    "id": "234",
+    "unit": "第七单元 认识时间",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "淘气7:28出发去上学,7:52到校，路上用了( )分。",
+    "options": [
+      "A. 18",
+      "B. 24",
+      "C. 34"
+    ],
+    "answer": "B",
+    "solution": "【分析】根据\"经过时间=结束时间-开始时间\"来解决此题.\n【详解】7:52-7:28=24(分),即，淘气7:28出发去上学,7:52到校，路上用了24分。故答案为:B",
+    "knowledge_points": [
+      "时，分，秒有关的计算"
+    ],
+    "source": "23-24 二年级下·河南信阳·期末"
+  },
+  {
+    "id": "235",
+    "unit": "第七单元 认识时间",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "钟面上的时针走( )圈正好是一天。",
+    "options": [
+      "A. 1",
+      "B. 2",
+      "C. 12"
+    ],
+    "answer": "B",
+    "solution": "【分析】一天是24小时，钟面上的时针走1圈是12小时，走2圈正好是一天。据此解答即可.\n【详解】钟面上的时针走2圈正好是一天。故答案为:B",
+    "knowledge_points": [
+      "整点时间与钟面指针的位置",
+      "时，分的认识及换算"
+    ],
+    "source": "22-23 三年级下·黑龙江哈尔滨·期末"
+  },
+  {
+    "id": "236",
+    "unit": "第七单元 认识时间",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "分针从12旋转到如图中的位置，经过了( )分.\n\n![](images/2167f66978a6eb4daeb0a917aa28f29f646f71f8e4d0d96c7d9694b3afad14eb.jpg)",
+    "options": [
+      "A. 8",
+      "B. 40",
+      "C. 45"
+    ],
+    "answer": "B",
+    "solution": "【分析】已知钟面上有12个大格，分针每走一个大格表示5分钟，先算出12到8一共走了多少个大格，再根据乘法的意义，用分针所走的大格数量乘5，即可得出答案.\n【详解】从题干可知:12到8一共走了8个大格。8×5=40(分),所以经过了40分。故答案为:B",
+    "knowledge_points": [
+      "8的乘法口诀及应用",
+      "时，分，秒有关的计算"
+    ],
+    "source": "22-23 二年级下·湖北武汉·期中"
+  },
+  {
+    "id": "237",
+    "unit": "第七单元 认识时间",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "小明和小丽，小红三人做同样的10道数学题，小明用了8分钟，小丽用了10分钟，小红用了9分钟。( )做得最慢。",
+    "options": [
+      "A. 小明",
+      "B. 小丽",
+      "C. 小红"
+    ],
+    "answer": "B",
+    "solution": "【分析】做同样的10道数学题，用的时间越多，表示做得越慢;据此解决.\n【详解】8分钟<9分钟<10分钟，即，做同样的10道数学题，小丽用时最长，表示她做得最慢。故答案为:B",
+    "knowledge_points": [
+      "时间快慢的比较"
+    ],
+    "source": "22-23 二年级上·河南南阳·期末"
+  },
+  {
+    "id": "238",
+    "unit": "第七单元 认识时间",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "小红可能在( )去看木偶剧.\n\n![](images/2026-03-02%20005527.jpg)",
+    "options": [
+      "A. ![](images/571de12a90bcc4c6b36aa364d621d32b8d5888e93441391d7c87a4ee290ab93a.jpg)",
+      "B. ![](images/2143bf19fc04915b78105782dd337477d32e5af6561238a3956612e2142d7fc0.jpg)",
+      "C. ![](images/608d9ebe077b11fab95dbabe9d8c8956ac535dd6be79f1bd3e6ef6ec8bc3e50d.jpg)"
+    ],
+    "answer": "B",
+    "solution": "【分析】分针指向6，时针刚过几就是几时半。时针走一大格是1时;分针走1小格是1分，走1大格是5分;秒针走1小格是1秒，走1大格是5秒。时针刚过几就是几时，分针指向第多少个小格就是多少分，据此分析出各个选项钟面的时间。妈妈说8:30开始大扫除，然后去看木偶剧，小红12:30要去小丽家玩，所以看木偶剧的时间应该在完成大扫除之后和去小丽家玩之前，据此解答.\n【详解】A。钟面时间是8:35,5分钟不可能完成大扫除，所以该选项不符合题意;B。钟面时间是10:05，小红可能在这个时间去看木偶剧，该选项符合题意;C。钟面时间是12:30，此时小红要去小丽家玩，该选项不符合题意。故答案为:B",
+    "knowledge_points": [
+      "一般时间与钟面指针的位置",
+      "时，分，秒时间的推算"
+    ],
+    "source": "22-23 二年级上·河南南阳·期末"
+  },
+  {
+    "id": "239",
+    "unit": "第七单元 认识时间",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "小明6:50吃早饭，然后去找同学玩，他11:45回家。小明可能是在下面哪个时间和同学玩。( )",
+    "options": [
+      "A. 11:50",
+      "B. 10:49",
+      "C. 6:50"
+    ],
+    "answer": "B",
+    "solution": "【分析】小明在6:50过后一些时间到11:45这段时间之间和同学玩，找到这个时间段内的时间即可.\n【详解】A。11:50在11:45之后，不符合;B。10:49在6:50和11:45之间，符合;C。6:50还在吃早饭，不符合。小明可能是在10:49和同学玩。故答案为:B",
+    "knowledge_points": [
+      "时，分的认识及换算",
+      "时，分，秒时间的推算"
+    ],
+    "source": "22-23 二年级上·河北邢台·期末"
+  },
+  {
+    "id": "240",
+    "unit": "第七单元 认识时间",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "过一刻是( ).\n\n![](images/aeadf2c5d324b781079f54a5c7012e65b61bcf0530f5ead26e5f596ef53638ab.jpg)",
+    "options": [
+      "A. 8:15",
+      "B. 9:15",
+      "C. 9:45"
+    ],
+    "answer": "B",
+    "solution": "【分析】钟面上分针指向12，时针指向9，是9时。一刻是15分，过一刻的时间=现在的时间+15分，计算即可.\n【详解】9时+15分=9时15分，也写作9:15。过一刻是9:15。故答案为:B",
+    "knowledge_points": [
+      "整点时间与钟面指针的位置",
+      "时，分，秒时间的推算"
+    ],
+    "source": "22-23 二年级上·山东菏泽·期末"
+  },
+  {
+    "id": "241",
+    "unit": "第七单元 认识时间",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "实验小学12月31日下午1:30开始元旦表演,( )迟到了。",
+    "options": [
+      "A. ![](images/3ab9416cd82e454facd0457bbd1a99243f523899ff0c6078538320ad047b7fd7.jpg)",
+      "B. ![](images/a4521d1baed4be19d8f9c3d8d7b3846138b84dcb80a4577072b573ed3f2a84bf.jpg)",
+      "C. ![](images/e2c0c97b644465b10210bbcbee81022f38acc8591075ad26f24cdfe33be9d609.jpg)"
+    ],
+    "answer": "A",
+    "solution": "【分析】钟面上有12大格，分针走一大格表示5分钟，时针走一大格表示1小时，据此读出各个选项钟面的时刻，即可得出答案.\n【详解】A。时针指向1和2之间，表示1时，分针指向6和7之间，所以钟面所显示的时刻在1:30分之后，符合题意。B。时针指向1，分针指向3，所以钟面所显示的时刻是1:15，在1:30之前，不符合题意。C。时针指向1和2之间，表示1时，分针指向5，所以钟面所显示的时刻是1:25，在1:30之前，不符合题意。故答案为:A",
+    "knowledge_points": [
+      "一般时间与钟面指针的位置"
+    ],
+    "source": "22-23 二年级上·湖北省直辖县级单位·期末"
+  },
+  {
+    "id": "242",
+    "unit": "第七单元 认识时间",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "时针指在5和6之间，分针指着6，这时的时间是( )。",
+    "options": [
+      "A. 6:30",
+      "B. 6:00",
+      "C. 5:30"
+    ],
+    "answer": "C",
+    "solution": "【分析】钟面上长针是分针，短针是时针。有12个大格，分针走1大格是5分钟，时针走1大格是1小时。如图：时针在5和6之间是5时，分针指向6，是30分，即5时30分，也写作5:30.\n\n![](images/e9bf2f77700339789ef398eb67b1480861959e3280665e071c9a96e5ef714cd8.jpg)\n【详解】由分析可知，时针指在5和6之间，分针指着6，这时的时间是5:30。故答案为:C",
+    "knowledge_points": [
+      "半点时间与钟面指针的位置"
+    ],
+    "source": "23-24 二年级上·江西宜春·期末"
+  },
+  {
+    "id": "243",
+    "unit": "第七单元 认识时间",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "![](images/2026-03-02%20005932.jpg)\n小红和小明可能在下午( )去图书馆。",
+    "options": [
+      "A. 1:35",
+      "B. 2:30",
+      "C. 4:25",
+      "D. 4:30"
+    ],
+    "answer": "B",
+    "solution": "【分析】根据题意，他们去图书馆的时间在1:30至4:30之间，由此选择合适的即可.\n【详解】A。1:35：此时接近刚开始写作业的时间，这段时间不能完成作业，不符合题意;B。2:30：此时在1:30至4:30之间，而且距离写作业有一段时间，符合题意;C。4:25：此时接近小红要去外婆家吃饭的时间，不符合题意;D。4:30：此时为小红去外婆家吃饭的时间，不符合题意。小红和小明可能在下午2:30去图书馆。故答案为:B",
+    "knowledge_points": [
+      "时，分，秒时间的推算"
+    ],
+    "source": "23-24 二年级上·浙江台州·期末"
+  },
+  {
+    "id": "244",
+    "unit": "第七单元 认识时间",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "钟面上，时针和分针形成直角的是( )时和( )时,3:30的时候，时针与分针成( )角。",
+    "options": [],
+    "answer": "9;3;锐",
+    "solution": "【分析】角由一个顶点和两条边组成，和书本，黑板的角相同大小的是直角，比直角大的是钝角，比直角小的是锐角。钟面上长针是分针，短针是时针。分针指向12，时针指向几就是几时;分针指向6，时针过了几就是几时30分。图1：分针指向12，时针指向9，是9时，形成的是直角;图2：分针指向12，时针指向3，是3时，形成的是直角;图3：分针指向6，时针指向3和4中间，是3:30，形成的是锐角.\n\n![](images/7c94954477d2b38998bdd86df9901224f2bc98b2cc5e15f1f851da2dd1b16f2d.jpg)\n\n![](images/7614a939f38119c6622f7ab263ce35958662328ac9862060b53ebce20477e706.jpg)\n\n![](images/b46be866895ec6581f93a859d299e7a15dee6b8d417ca6ad1cd2bb0c2442c736.jpg)\n【详解】由分析可知，钟面上，时针和分针形成直角的是9时和3时,3:30的时候，时针与分针成锐角。",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征",
+      "整点时间与钟面指针的位置",
+      "半点时间与钟面指针的位置"
+    ],
+    "source": "24-25 二年级上·河北保定·期中"
+  },
+  {
+    "id": "245",
+    "unit": "第七单元 认识时间",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "如图:\n\n![](images/f38768fb4779c9a3e9ca083bb580c96ee82ebfc6aa54ba08928eb3d4e57929c9.jpg)\n\n钟面上的时针和分针组成较小的角是( )角，当钟面上显示5时整时，时针和分针组成较小的角是( )角。",
+    "options": [],
+    "answer": "直;钝",
+    "solution": "【分析】三角尺上最大的角为直角，用三角板的直角进行比较测量，比直角小的就是锐角，比直角大的就是钝角。钟面上较短的针是时针，较长的针是分针。分针指向12，时针指向几就是几时.\n【详解】![](images/b7acf547efcb418ca0c824e024483e6a21220603fc6adfaba58b36f841b83dae.jpg)钟面上的时针和分针组成较小的角是直角。当钟面上显示5时整时，如图:![](images/571d41e0802e1a88d2a4011ed7d271fabc5b07199c76b839e6a48b06884407c2.jpg),时针和分针组成较小的角是钝角。",
+    "knowledge_points": [
+      "角的初步认识及辨认",
+      "整点时间与钟面指针的位置"
+    ],
+    "source": "23-24 二年级上·贵州六盘水·期中"
+  },
+  {
+    "id": "246",
+    "unit": "第七单元 认识时间",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "在( )里填上合适的单位名称.\n\n(1)一节课时长40( ).\n(2)小红的身高125( )。",
+    "options": [],
+    "answer": "分钟或分或min;厘米或cm",
+    "solution": "【分析】根据生活经验以及数据的大小，选择合适的计量单位来解决此题。表示较长的时间时，一般选择\"小时\"作单位;表示较短的时间时，一般选择\"分钟\"作单位，如：一节课时长40分钟。食指宽大约是1厘米，所以，计量小红的身高用\"厘米\"作单位比较合适.\n【详解】(1)一节课时长40分钟。(2)小红的身高125厘米。",
+    "knowledge_points": [
+      "时间单位的选择",
+      "长度单位的选择"
+    ],
+    "source": "23-24 二年级下·贵州六盘水·期末"
+  },
+  {
+    "id": "247",
+    "unit": "第七单元 认识时间",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "钟面上9时整，时针和分针所成的角是( )度;8时整时针和分针成( )角。",
+    "options": [],
+    "answer": "90;钝",
+    "solution": "【分析】角由一个顶点和两条边组成。和书本，黑板的角相同大小的是直角，比直角大的是钝角，比直角小的是锐角。图1：分针指向12，时针指向9，是9时，组成的角是直角，直角是90度;图2：分针指向12，时针指向8，是8时，组成的角比直角大，是钝角.\n\n![](images/f124010e96e98a666e680aa1356668c047507586afc4fb7083d633ce285938dd.jpg)\n\n![](images/6a466f1a19b3b59c8a69587a55b3f900a87bd6983eaeb425a0a24b8bb5179c37.jpg)\n【详解】钟面上9时整，时针和分针所成的角是90度;8时整时针和分针成钝角。",
+    "knowledge_points": [
+      "角的分类及换算",
+      "整点时间与钟面指针的位置"
+    ],
+    "source": "23-24 二年级上·山东济南·期中"
+  },
+  {
+    "id": "248",
+    "unit": "第七单元 认识时间",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "如图钟面上的时刻是跳蚤市场开始的时间，跳蚤市场开始的时间是( ),这时时针和分针组成的角是( )角.\n\n![](images/b61dbabd1494dc25675ecc4ebd901b75ce308102fef853fd86d0615361202f8b.jpg)",
+    "options": [],
+    "answer": "9:00;直",
+    "solution": "【分析】钟表上，短针是时针，长针是分针，有12大格，分针走一大格是5分，时针走一大格是1时。当钟表上分针指向12，时针指向几，就是几时;判断这时时针和分针组成的角，可以用三角尺上的直角比一比;则大于直角的是钝角，小于直角的是锐角.\n【详解】跳蚤市场开始时间是9:00，这时时针和分针组成的角是直角。",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征",
+      "整点时间与钟面指针的位置"
+    ],
+    "source": "23-24 二年级上·河南信阳·期中"
+  },
+  {
+    "id": "249",
+    "unit": "第七单元 认识时间",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "9时整，时针和分针形成的角是( )角;5时整，时针和分针形成的角是( )角。",
+    "options": [],
+    "answer": "直;钝",
+    "solution": "【分析】比三角尺中的直角小的角是锐角，比三角尺中的直角大的角是钝角，和三角尺中的直角相等的角是直角，再结合题干要求的时针和分针的位置，即可得出答案.\n【详解】9时整，时针和分针形成的角是直角;5时整，时针和分针形成的角是钝角。",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征",
+      "整点时间与钟面指针的位置"
+    ],
+    "source": "23-24 二年级上·广东江门·期中"
+  },
+  {
+    "id": "250",
+    "unit": "第七单元 认识时间",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "钟面上3时整，时针和分针所成的角是( )角,9:30时，时针和分针所成的角是( )角。",
+    "options": [],
+    "answer": "直;钝",
+    "solution": "【分析】根据钟表的认识，当分针指向12时，时针指向几就是几时整;时针走一大格是1时;分针走1小格是1分，走1大格是5分。时针刚过几就是几时，分针指向第多少个小格就是多少分，据此得出相应的时间钟面上时针和分针的位置。根据直角的特征，可知长方形，正方形的4个角都是直角，要知道一个角是不是直角，用三角尺上的直角比较即可，比直角小的角叫做锐角，比直角大的角叫做钝角;据此根据直角，钝角和锐角的认识进行判断.\n【详解】钟面上3时整时，时针指向3，分针指向12，此时时针和分针所成的角是直角;9:30时，时针指向9和10的中间，分针指向6，此时时针和分针所成的角是钝角。",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征",
+      "整点时间与钟面指针的位置",
+      "一般时间与钟面指针的位置"
+    ],
+    "source": "20-21 四年级上·山东济宁·期末"
+  },
+  {
+    "id": "251",
+    "unit": "第七单元 认识时间",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "小明和妈妈上午7:55从家出发去奶奶家,9:10到达，她们路上用了( )分。",
+    "options": [],
+    "answer": "75",
+    "solution": "【分析】根据经过时间=结束时刻-开始时刻，用到达时间减出发时间，即可求出路上用的时间，注意1小时=60分.\n【详解】9:10-7:55=75(分),她们路上用了75分。",
+    "knowledge_points": [
+      "时，分，秒有关的计算"
+    ],
+    "source": "23-24 二年级下·河南驻马店·期末"
+  },
+  {
+    "id": "252",
+    "unit": "第七单元 认识时间",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "1时20分=( )分;2分=( )秒;105分=( )时( )分",
+    "options": [],
+    "answer": "80;120;1;45",
+    "solution": "【分析】根据1分=60秒,1小时=60分，结合题干要求进行解答即可.\n【详解】1时20分=80分;2分=120秒;105分=1小时45分。",
+    "knowledge_points": [
+      "时，分的认识及换算",
+      "时，分，秒之间的换算与比较"
+    ],
+    "source": "23-24 二年级下·河南商丘·期末"
+  },
+  {
+    "id": "253",
+    "unit": "第七单元 认识时间",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "9时零5分可以写作( );79分=( )时( )分。",
+    "options": [],
+    "answer": "9:05;1;19",
+    "solution": "【分析】9时零5分是文字表示时间法，另一种表示时间法是电子表表示法，时和分中间用\"：\"隔开，分钟不超过10的前面添0补位;换算单位时根据1时=60分解答.\n【详解】79分=60分+19分,9时零5分可以写作9:05;79分=1时19分。",
+    "knowledge_points": [
+      "时，分的认识及换算"
+    ],
+    "source": "23-24 二年级下·河北保定·期末"
+  },
+  {
+    "id": "254",
+    "unit": "第七单元 认识时间",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "9时30分也可以说( )点半;大约8时可以说快( )点了。",
+    "options": [],
+    "answer": "9;8",
+    "solution": "【分析】根据对时间的认识可知，几时30分，也可以说几点半。大约几时也可以说是快几点了，由此解答.\n【详解】9时30分也可以说9点半;大约8时可以说快8点了。",
+    "knowledge_points": [
+      "半点时间与钟面指针的位置",
+      "时，分的认识及换算"
+    ],
+    "source": "23-24 一年级下·河北保定·期末"
+  },
+  {
+    "id": "255",
+    "unit": "第七单元 认识时间",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "钟面上，时针从12开始走，走了半圈，经过了( )小时，分针从12开始走，走了半圈，经过了( )分钟。",
+    "options": [],
+    "answer": "6;30",
+    "solution": "【分析】钟面上长针是分针，短针是时针，有12个大格，分针走1大格是5分钟，时针走1大格是1小时，由此先计算出走了几个大格，再用乘法计算出走了多长时间即可.\n【详解】从12开始走半圈，也就是走了6个大格。时针:6×1=6(小时);分针:6×5=30(分钟)。钟面上，时针从12开始走，走了半圈，经过了6小时，分针从12开始走，走了半圈，经过了30分钟。",
+    "knowledge_points": [
+      "6的乘法口诀及应用",
+      "时，分，秒有关的计算"
+    ],
+    "source": "23-24 二年级下·河北保定·期末"
+  },
+  {
+    "id": "256",
+    "unit": "第七单元 认识时间",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "小明到公园游玩，他下午3:00到公园，玩了40分钟后离开公园，他离开公园的时间是下午( )。",
+    "options": [],
+    "answer": "3:40或3时40分",
+    "solution": "【分析】根据结束时刻=开始时刻+经过时间，用小明到公园的时间加上在公园游玩的时间，即可求出他离开公园的时间.\n【详解】3时+40分=3时40分，所以他离开公园的时间是下午3时40分。",
+    "knowledge_points": [
+      "时，分，秒时间的推算"
+    ],
+    "source": "23-24 二年级下·河南周口·期末"
+  },
+  {
+    "id": "257",
+    "unit": "第七单元 认识时间",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "做一道数学题，小红比小明多用10分钟，小军比小明少用5分钟，则( )做得最慢。",
+    "options": [],
+    "answer": "小红",
+    "solution": "【分析】做一道数学题，用的时间越多，表示做得越慢，用的时间越少，表示做得越快。小军比小明少用5分钟，也就是小明比小军多用5分钟;小红比小明多用10分钟，小明又比小军多用5分钟,10+5=15(分钟),所以小红比小军多用15分钟;所以小红做题用时最多，做得最慢，小军做题用时最少，做得最快;小明做题速度排在第二.\n【详解】由题意分析得：小红做题用时>小明做题用时>小军做题用时，则小红做题速度<小明做题速度<小军做题速度，所以，小红做得最慢。",
+    "knowledge_points": [
+      "时间快慢的比较"
+    ],
+    "source": "23-24 二年级下·贵州铜仁·期末"
+  },
+  {
+    "id": "258",
+    "unit": "第七单元 认识时间",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "时针从12走到5，走了( )小时;分针从12走到5，走了( )分钟，再加上( )分钟就是1小时。",
+    "options": [],
+    "answer": "5;25;35",
+    "solution": "【分析】钟面上长针是分针，短针是时针。有12个大格，分针走1大格是5分钟，时针走1大格是1小时。由此先计算出走了几大格，再用乘法计算出走了多长时间即可。1小时=60分，再减去走了的时间，结果就是需要再加上的时间.\n【详解】时针，分针从12走到5，走了5大格。1×5=5(小时);5×5=25(分钟);60-25=35(分钟)。时针从12走到5，走了5小时;分针从12走到5，走了25分钟，再加上35分钟就是1小时。",
+    "knowledge_points": [
+      "时，分的认识及换算"
+    ],
+    "source": "23-24 二年级上·全国·课后作业"
+  },
+  {
+    "id": "259",
+    "unit": "第七单元 认识时间",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "钟面上9时30分，时针与分针形成的角是( )角;3时30分，时针与分针形成的角是( )角。",
+    "options": [],
+    "answer": "钝;锐",
+    "solution": "【分析】和书本，黑板的角相同大小的是直角;比直角大的是钝角;比直角小的是锐角。半点时，分针指向6，时针过了几就是几时。图1为9时30分，形成的角比直角大，是钝角;图2是3时30分，形成的角比直角小，是锐角.\n\n![](images/84101b8b01dcbd2bd7431f44a43787d8b2ed97d8604682b556aa029643b4b94d.jpg)\n\n![](images/c68a8aa1aec78117041574ac7f989555925d626a12eca03f5c30bb1d55a2ecbf.jpg)\n【详解】钟面上9时30分，时针与分针形成的角是钝角;3时30分，时针与分针形成的角是锐角。",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征",
+      "半点时间与钟面指针的位置"
+    ],
+    "source": "23-24 二年级上·全国·课后作业"
+  },
+  {
+    "id": "260",
+    "unit": "第七单元 认识时间",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "时针在2和3之间，分针指向4，此时是( )时( )分;时针快指着10，分针指着11，此时是( )时( )分。",
+    "options": [],
+    "answer": "2;20;9;55",
+    "solution": "【分析】时针在2和3之间，表示2时多，分针指向4，表示20分，合起来就是2时20分;时针快指着10，表示9时多，分针指着11，表示55分，合起来就是9时55分;据此解决.\n【详解】由题意分析得：时针在2和3之间，分针指向4，此时是2时20分;时针快指着10，分针指着11，此时是9时55分。",
+    "knowledge_points": [
+      "一般时间与钟面指针的位置"
+    ],
+    "source": "23-24 二年级上·全国·课后作业"
+  },
+  {
+    "id": "261",
+    "unit": "第七单元 认识时间",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "欢欢，贝贝和琪琪三人比赛折千纸鹤，每人折5只，欢欢用了3分钟，贝贝比欢欢少用20秒，琪琪比贝贝多用了15秒。第一名是( ),最后一名是( )。",
+    "options": [],
+    "answer": "贝贝;欢欢",
+    "solution": "【分析】欢欢所用的时间减去20秒，求出的是贝贝所用的时间;贝贝所用的时间加上15秒，求出的是琪琪所用的时间;折同样数量的千纸鹤，用的时间越少，表示折得速度越快;反之速度越慢.\n【详解】3分钟-20秒=2分钟40秒;2分钟40秒+15秒=2分钟55秒;3分钟>2分钟55秒>2分钟40秒，即，第一名是贝贝，最后一名是欢欢。",
+    "knowledge_points": [
+      "时间快慢的比较",
+      "时，分，秒有关的计算"
+    ],
+    "source": "23-24 二年级上·全国·课后作业"
+  },
+  {
+    "id": "262",
+    "unit": "第七单元 认识时间",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "一节课40分，一场考试60分，一场考试比一节课多( )分。",
+    "options": [],
+    "answer": "20",
+    "solution": "【分析】根据题意可知：求一个数比另一个数多多少，用减法计算.\n【详解】60-40=20(分),所以一场考试比一节课多20分。",
+    "knowledge_points": [
+      "整十数之间的加减法",
+      "时，分，秒有关的计算"
+    ],
+    "source": "23-24 二年级上·全国·单元测试"
+  },
+  {
+    "id": "263",
+    "unit": "第七单元 认识时间",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "时针从12走到2，走了( )时;分针从2走到8，走了( )分。",
+    "options": [],
+    "answer": "2;30",
+    "solution": "【分析】钟面12个数字把钟面平均分成12份，即12大格，时针走1大格就是1小时，分针走1大格是5分钟，走几大格就是几个5分钟;据此解答.\n【详解】8-2=6(大格),6×5=30(分)。则时针从12走到2，走了2时;分针从2走到8，走了30分。",
+    "knowledge_points": [
+      "6的乘法口诀及应用",
+      "时，分的认识及换算",
+      "时，分，秒有关的计算"
+    ],
+    "source": "23-24 二年级上·全国·单元测试"
+  },
+  {
+    "id": "264",
+    "unit": "第七单元 认识时间",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "在括号里填上\">\"\"<\"或\"=\".\n\n1时20分( )82分;2时( )2时10分;55分( )1时-10分;3时( )2时+60分;1时25分( )96分;18分+25分( )1时-20分",
+    "options": [],
+    "answer": "<;<;>;=;<;>",
+    "solution": "【分析】整数的大小比较：比较数的大小，先看数位的多少，数位多的数就大;数位相同，从高位开始比较，高位上的数大则这个数大，高位上的数相同，就比较下一位。含有算式的大小比较，可以先计算出每个算式的结果，再比较大小;1时=60分，单位不统一时，先化成相同单位，再比较大小.\n【详解】1时20分=60分+20分=80分，所以1时20分<82分;2时<2时10分;1时-10分=60分-10分=50分，所以55分>1时-10分;2时+60分=2时+1时=3时，所以3时=2时+60分;1时25分=60分+25分=85分，所以1时25分<96分;18分+25分=43分,1时-20分=60分-20分=40分，所以18分+25分>1时-20分。",
+    "knowledge_points": [
+      "100以内数的比大小",
+      "时，分，秒之间的换算与比较"
+    ],
+    "source": "23-24 二年级上·全国·单元测试"
+  },
+  {
+    "id": "265",
+    "unit": "第七单元 认识时间",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "时针从3走到6，走了( )时;10:45再过15分是( )。",
+    "options": [],
+    "answer": "3;11:00",
+    "solution": "【分析】钟面上长针是分针，短针是时针，有12个大格，分针走1大格是5分钟，时针走1大格是1小时，由此计算出走了几大格即可;结束时间=开始时间+经过时间，由此解答.\n【详解】10:45+15分=11:00，时针从3走到6，走了3大格。走了3时,10:45再过15分是11:00。",
+    "knowledge_points": [
+      "时，分，秒有关的计算",
+      "时，分，秒时间的推算"
+    ],
+    "source": "23-24 二年级上·全国·单元测试"
+  },
+  {
+    "id": "266",
+    "unit": "第七单元 认识时间",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "钟面上时针和分针都指向12，这时的时刻是( )时;钟面上时针和分针连成一条直线，分针指向12，这时的时刻是( )时。",
+    "options": [],
+    "answer": "12;6",
+    "solution": "【分析】钟面上长针是分针，短针是时针。分针指向12，时针指向几就是几时。图1：分针和时针都指向12，是12时;图2：分针指向12，时针和分针成一条直线，时针指向6，是6时.\n\n![](images/1c4e3fc8e9d53ee37441828ea5926f1e8e921a0f97dbbeebcd5b693936539c17.jpg)\n【详解】钟面上时针和分针都指向12，这时的时刻是12时;钟面上时针和分针连成一条直线，分针指向12，这时的时刻是6时。",
+    "knowledge_points": [
+      "整点时间与钟面指针的位置"
+    ],
+    "source": "23-24 二年级上·全国·单元测试"
+  },
+  {
+    "id": "267",
+    "unit": "第七单元 认识时间",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "时针转1圈，分针转( )圈。",
+    "options": [],
+    "answer": "12",
+    "solution": "【分析】时针走1大格是1小时，分针走1圈是1小时。所以时针走1大格，分针转1圈。据此分析.\n【详解】时针转1圈，走了12个大格，一共是12小时，那么分针就应该转12圈。故时针转1圈，分针转12圈。",
+    "knowledge_points": [
+      "时，分的认识及换算"
+    ],
+    "source": "23-24 三年级下·湖北荆门·期末"
+  },
+  {
+    "id": "268",
+    "unit": "第七单元 认识时间",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "钟面上一共有( )大格，时针走一大格是( )时。分针走1小格是( )分。",
+    "options": [],
+    "answer": "12;1;1",
+    "solution": "【分析】在钟面上，共有12个大格，每个大格分成5个小格，共有60个小格，时针走1大格是1时;分针走1小格是1分，走1大格是5分，走一圈是60分;据此进行解答.\n【详解】由分析可得，钟面上一共有12大格，时针走1大格是1时，分针走1小格是1分。",
+    "knowledge_points": [
+      "整点时间与钟面指针的位置",
+      "半点时间与钟面指针的位置",
+      "一般时间与钟面指针的位置"
+    ],
+    "source": "22-23 二年级上·湖北省直辖县级单位·期末"
+  },
+  {
+    "id": "269",
+    "unit": "第七单元 认识时间",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "时钟上的时刻为( ),再过15分钟是( ).\n\n![](images/c4015c3e56ef2de8cd8c0d3c215a133f559d56f8bc0f41c8025e2eae42abc462.jpg)",
+    "options": [],
+    "answer": "7:15或7时15分;7:30或7时30分",
+    "solution": "【分析】时针指向7和8之间，表示7时多，分针指向3，表示15分，合起来表示7时15分;结束时刻=开始时刻+经过时间;据此解决.\n【详解】7时15分+15分=7时30分，时钟上的时刻为7时15分，再过15分钟是7时30分。",
+    "knowledge_points": [
+      "一般时间与钟面指针的位置",
+      "时，分，秒时间的推算"
+    ],
+    "source": "23-24 二年级上·浙江温州·期末"
+  },
+  {
+    "id": "270",
+    "unit": "第七单元 认识时间",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "分针从\"12\"走到\"3\"，经过了( )分;时针从\"3\"走到\"12\"，经过了( )小时。",
+    "options": [],
+    "answer": "15;9",
+    "solution": "【分析】时针走一大格是1时;分针走1小格是1分，走1大格是5分;秒针走1小格是1秒，走1大格是5秒。分针从\"12\"走到\"3\"，走了3大格，数三次5即可，是15分。时针从\"3\"走到\"12\"，走了9个大格，是9小时.\n【详解】分针从\"12\"走到\"3\"，经过了15分;时针从\"3\"走到\"12\"，经过了9小时。",
+    "knowledge_points": [
+      "一般时间与钟面指针的位置",
+      "时，分，秒有关的计算"
+    ],
+    "source": "23-24 二年级上·江西宜春·期末"
+  },
+  {
+    "id": "271",
+    "unit": "第七单元 认识时间",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "一刻钟也可以说成30分钟。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】一小时是60分钟,30分钟可以说是半小时，而一刻钟为15分钟，由此解答.\n【详解】一刻钟也可以说成15分钟。原题说法错误。故答案为: ×",
+    "knowledge_points": [
+      "时，分的认识及换算"
+    ],
+    "source": "22-23 二年级上·河南南阳·期中"
+  },
+  {
+    "id": "272",
+    "unit": "第七单元 认识时间",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "一家小饭店的营业时间为下午5:30到晚上9:00，那么，这家饭店营业了11小时30分。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】根据题意可知：求这家饭店营业了多久，用晚上结束的时间减去营业开始的时间.\n【详解】9:00-5:30=3:30，则这家饭店营业了3小时30分钟。故答案为: ×",
+    "knowledge_points": [
+      "时，分，秒有关的计算"
+    ],
+    "source": "23-24 二年级下·河北邢台·期末"
+  },
+  {
+    "id": "273",
+    "unit": "第七单元 认识时间",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "1小时刚好是60分钟。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】根据小时和分钟之间的进率,1时=60分解答即可.\n【详解】1时=60分，所以1小时刚好是60分钟。故答案为:√",
+    "knowledge_points": [
+      "时，分的认识及换算"
+    ],
+    "source": "22-23 二年级上·福建莆田·期末"
+  },
+  {
+    "id": "274",
+    "unit": "第七单元 认识时间",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "时针在1和2之间，分针指着4，时间是2:40。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】时针在1和2之间，表示1时多，分针指着4，表示20分，合起来表示的时间是1:20.\n【详解】由题意分析得：时针在1和2之间，分针指着4，时间是1:20。故答案为: ×",
+    "knowledge_points": [
+      "一般时间与钟面指针的位置"
+    ],
+    "source": "23-24 二年级下·河南周口·期末"
+  },
+  {
+    "id": "275",
+    "unit": "第七单元 认识时间",
+    "question_type": "判断题",
+    "difficulty": 0.65,
+    "question": "小军做100道计算题只用了1秒钟。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】1秒钟可以读一道计算题，据此得出结论即可.\n【详解】根据分析知:1秒钟不能做100道计算题。故答案为: ×",
+    "knowledge_points": [
+      "秒的认识"
+    ],
+    "source": "23-24 二年级下·河南周口·期末"
+  },
+  {
+    "id": "276",
+    "unit": "第七单元 认识时间",
+    "question_type": "判断题",
+    "difficulty": 0.65,
+    "question": "果果跑50米用了11秒，甜甜想赢他最多只能用12秒。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】跑相同的距离用的时间越短跑的越快，据此可知，甜甜要想赢果果，甜甜需要的时间应小于11秒，最多是10秒.\n【详解】果果跑50米用了11秒，甜甜用12秒不能赢果果，甜甜想赢他最多只能用10秒。原题说法错误。故答案为: ×",
+    "knowledge_points": [
+      "时间快慢的比较"
+    ],
+    "source": "23-24 二年级上·全国·课后作业"
+  },
+  {
+    "id": "277",
+    "unit": "第七单元 认识时间",
+    "question_type": "判断题",
+    "difficulty": 0.65,
+    "question": "100秒比2分钟时间长。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】1分钟=60秒，算出2分钟有多少秒，然后和100秒作比较即可求解.\n【详解】1分钟=60秒,2分钟=60秒+60秒=120秒,100秒<120秒，所以100秒比2分钟时间短，原题说法错误。故答案为: ×",
+    "knowledge_points": [
+      "时，分，秒之间的换算与比较"
+    ],
+    "source": "23-24 二年级上·全国·课后作业"
+  },
+  {
+    "id": "278",
+    "unit": "第七单元 认识时间",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "奇奇做完10道口算题用了10分钟。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】根据生活经验以及时间单位，数据的大小，对此题的时间进行估计即可。做1道口算题大概用1秒，那么，做完10道口算题大约用10秒.\n【详解】由题意分析得：奇奇做完10道口算题用了10秒;原说法错误。故答案为: ×",
+    "knowledge_points": [
+      "时间的估计",
+      "时间单位的选择"
+    ],
+    "source": "23-24 二年级上·全国·课后作业"
+  },
+  {
+    "id": "279",
+    "unit": "第七单元 认识时间",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "时针在8和9之间，分针指着8，这时的时间是8:40。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】钟面上长针是分针，短针是时针。有12个大格，分针走1大格是5分钟，时针走1大格是1小时。时针在8和9之间，是8时，分针指向8，是40分，也就是8时40分，也写作8:40.\n【详解】由分析可知，时针在8和9之间，分针指着8，这时的时间是8:40。原题说法正确。故答案为:√",
+    "knowledge_points": [
+      "一般时间与钟面指针的位置"
+    ],
+    "source": "23-24 二年级上·全国·单元测试"
+  },
+  {
+    "id": "280",
+    "unit": "第七单元 认识时间",
+    "question_type": "判断题",
+    "difficulty": 0.65,
+    "question": "下午3时，时针和分针组成的角是直角。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】当一条直线和另一条横的直线交成的邻角彼此相等时，这些角的每一个被叫做直角，三角尺上最大的角为直角。分针指向12，时针指向几就是几时;下午3时，分针指向12，时针指向3，这时时针和分针组成的角是直角.\n【详解】下午3时，时针和分针组成的角是直角。原题说法正确。故答案为:√",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征",
+      "整点时间与钟面指针的位置"
+    ],
+    "source": "23-24 二年级上·全国·单元测试"
+  },
+  {
+    "id": "281",
+    "unit": "第七单元 认识时间",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "小桃红吃饭用了20分，写作业用40分，一共用了1时。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】根据题意，吃饭的时间+写作业的时间=一共用的时间，计算出结果再根据1时=60分换算即可.\n【详解】20分+40分=60分=1时，小桃红吃饭用了20分，写作业用40分，一共用了1时。原题说法正确。故答案为:√",
+    "knowledge_points": [
+      "时，分的认识及换算",
+      "时，分，秒有关的计算"
+    ],
+    "source": "23-24 二年级上·全国·单元测试"
+  },
+  {
+    "id": "282",
+    "unit": "第七单元 认识时间",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "2时-60分=1时。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】根据1时=60分，换算计算即可.\n【详解】2时-60分=2时-1时=1时，原题计算正确。故答案为:√",
+    "knowledge_points": [
+      "时，分的认识及换算"
+    ],
+    "source": "23-24 二年级上·全国·单元测试"
+  },
+  {
+    "id": "283",
+    "unit": "第七单元 认识时间",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "一节课是40分钟，再上10分钟就是1小时。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】先用一节课的时间加上10分钟，计算出总时间，再与1小时比较即可.\n【详解】40分+10分=50分;1时=60分。50分不等于1小时。所以原题说法错误。故答案为: ×",
+    "knowledge_points": [
+      "时，分的认识及换算"
+    ],
+    "source": "23-24 二年级下·广东·期末"
+  },
+  {
+    "id": "284",
+    "unit": "第七单元 认识时间",
+    "question_type": "判断题",
+    "difficulty": 0.65,
+    "question": "100米赛跑中，小刚用了13秒，小红用了14秒，小红比小刚快一些。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】跑步比赛中，用时短的速度快.\n【详解】小刚:13秒，小红:14秒,13秒<14秒，所以小刚比小红快一些。故答案为: ×",
+    "knowledge_points": [
+      "时间快慢的比较"
+    ],
+    "source": "23-24 二年级下·山东·期末"
+  },
+  {
+    "id": "285",
+    "unit": "第七单元 认识时间",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "钟表上分针从12旋转到2，所经过的时间是10分。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】钟面上分针走一小格是1分，走一大格是5分。分针从12走到2，走了2个大格，经过的时间就是2×5分，据此解答.\n【详解】2×5=10(分),钟表上分针从12旋转到2，所经过的时间是10分。此说法正确。故答案为:√",
+    "knowledge_points": [
+      "一般时间与钟面指针的位置",
+      "时，分，秒有关的计算"
+    ],
+    "source": "23-24 二年级下·河北保定·期末"
+  },
+  {
+    "id": "286",
+    "unit": "第七单元 认识时间",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "一场足球赛9:40开始，经过50分钟结束，结束的时间是10:20。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】根据结束时刻=开始时间+经过时间，计算出结束的时间，即可判断.\n【详解】9:40+50分钟=10:30，所以一场足球赛9:40开始，经过50分钟结束，结束的时间是10:30，原题说法错误。故答案为: ×",
+    "knowledge_points": [
+      "时，分，秒时间的推算"
+    ],
+    "source": "23-24 二年级下·河南周口·期末"
+  },
+  {
+    "id": "287",
+    "unit": "第七单元 认识时间",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "![](images/ec86c628d2d5bf2c991ba24ca2edb1eb74d61d2e72664cd5546da2682edab1e3.jpg),此时是1时。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】时针指向12过一点，表示12时多，分针指向1，表示5分，合起来就是12时5分;据此解决.\n【详解】由题意分析得:![](images/d673aa41d2e11ae6010ac707c27d9a0fd17c8be4419c255c2c786d115252ce44.jpg),此时是12时5分，所以原题说法是错误的。故答案为: ×",
+    "knowledge_points": [
+      "一般时间与钟面指针的位置"
+    ],
+    "source": "22-23 一年级下·河南周口·期末"
+  },
+  {
+    "id": "288",
+    "unit": "第七单元 认识时间",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "妈妈每天工作8分。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】1秒差不多是眨一下眼的时长，而1分钟=60秒,1小时=60分，根据对1秒,1分,1小时实际有多长的认识，结合生活实际以及数值的大小，计量妈妈每天的工作时间，用\"时\"作计量单位.\n【详解】妈妈每天工作应该是8小时，原题说法错误。故答案为: ×",
+    "knowledge_points": [
+      "时，分的认识及换算",
+      "秒的认识",
+      "时间单位的选择"
+    ],
+    "source": "22-23 二年级上·湖北省直辖县级单位·期末"
+  },
+  {
+    "id": "289",
+    "unit": "第七单元 认识时间",
+    "question_type": "解答题",
+    "difficulty": 0.65,
+    "question": "文文上午7:30上学，中午11:30放学，下午2:00上学,5:30放学，文文全天在校多少时间。",
+    "options": [],
+    "answer": "7小时30分",
+    "solution": "【分析】首先根据经过的时间=放学的时刻-到校的时刻，分别求出文文上午，下午在校的时间各是多少，然后把它们求和，求出他一天的在校时间即可.\n【详解】11:30-7:30=4小时,5:30-2:00=3小时30分,4小时+3小时30分=7小时30分，答：文文全天在校7小时30分。",
+    "knowledge_points": [
+      "时，分，秒有关的计算"
+    ],
+    "source": "22-23 二年级下·河南周口·期末"
+  },
+  {
+    "id": "290",
+    "unit": "第七单元 认识时间",
+    "question_type": "解答题",
+    "difficulty": 0.85,
+    "question": "婷婷每天从家到学校要走8分钟，中午回家吃饭，下午再上学。那么她每天花在路上的时间是多少分钟。",
+    "options": [],
+    "answer": "32分钟",
+    "solution": "【分析】根据题意可知，婷婷每天要从家到学校往返2次，也就是走4次同样的路程，婷婷每次从家到学校要走8分钟,4次要走的时间也就是4个8分钟，用每次走的时间×次数=一共需要的时间.\n【详解】8×4=32(分钟),答：她每天花在路上的时间是32分钟。",
+    "knowledge_points": [
+      "8的乘法口诀及应用",
+      "时，分的认识及换算"
+    ],
+    "source": "23-24 二年级上·全国·课后作业"
+  },
+  {
+    "id": "291",
+    "unit": "第七单元 认识时间",
+    "question_type": "解答题",
+    "difficulty": 0.65,
+    "question": "公交车每天上午6时30分开始发车，每隔15分钟发一辆。那么8时发出的是第几辆车。",
+    "options": [],
+    "answer": "第七辆",
+    "solution": "【分析】由题意可推出上午6时30分开始发出第一辆车;上午6时45分发出第二辆车;上午7时发出第三辆车;上午7时15分发出第四辆车;上午7时30分发出第五辆车;上午7时45分发出第六辆车;上午8时发出第七辆车.\n【详解】第二辆：上午6时30分+15分=上午6时45分，第三辆：上午6时45分+15分=上午7时，第四辆：上午7时+15分=上午7时15分，第五辆：上午7时15分+15分=上午7时30分，第六辆：上午7时30分+15分=上午7时45分，第七辆：上午7时45分+15分=上午8时，答：上午8时发出的是第七辆车。",
+    "knowledge_points": [
+      "时，分，秒时间的推算"
+    ],
+    "source": "23-24 二年级上·全国·课后作业"
+  },
+  {
+    "id": "292",
+    "unit": "第七单元 认识时间",
+    "question_type": "解答题",
+    "difficulty": 0.65,
+    "question": "在100米短跑比赛中，张丽比王成多用6秒，李亮比王成少用2秒，跑得最快的人比跑得最慢的人少用几秒。",
+    "options": [],
+    "answer": "8秒",
+    "solution": "【分析】在100米短跑比赛中，用的时间少跑得就快;反之，用的时间长跑得就慢。李亮比王成少用2秒，而张丽比王成多用6秒，也就是王成又比张丽少用6秒;所以李亮最快，张丽最慢，且李亮比张丽少用(2+6)秒;据此解决.\n【详解】2+6=8(秒),答：跑得最快的人比跑得最慢的人少用8秒。",
+    "knowledge_points": [
+      "时间快慢的比较",
+      "时，分，秒有关的计算"
+    ],
+    "source": "23-24 二年级上·全国·课后作业"
+  },
+  {
+    "id": "293",
+    "unit": "第七单元 认识时间",
+    "question_type": "解答题",
+    "difficulty": 0.65,
+    "question": "小区电梯上升一层要3秒，亮亮家住在六楼，他从一楼乘坐电梯，经过多少秒可以到达他家。(电梯中途不停)",
+    "options": [],
+    "answer": "15秒",
+    "solution": "【分析】从1楼到6楼需要上升5层，上升一层需要的时间×上升的层数=经过的时间，据此列式解答即可.\n【详解】6-1=5(层),3×5=15(秒),答：经过15秒可以到达他家。",
+    "knowledge_points": [
+      "时，分，秒有关的计算"
+    ],
+    "source": "23-24 二年级上·全国·课后作业"
+  },
+  {
+    "id": "294",
+    "unit": "第七单元 认识时间",
+    "question_type": "解答题",
+    "difficulty": 0.65,
+    "question": "姥爷家有一个老座钟，每到整点都要敲钟，几点敲几下，另外每半点时还要敲一下，这座钟从上午8点到下午1点半一共敲了多少下。",
+    "options": [],
+    "answer": "57下",
+    "solution": "【分析】由题意得，上午8点,9点,10点,11点，中午12点和下午1点这座钟分别敲8下,9下,10下,11下,12下和1下。除了整点敲钟外，这座钟在上午8点半,9点半,10点半,11点半，中午12点半和下午1点半都会敲1下，一共敲6下。求这座钟从上午8点到下午1点半一共敲了多少下，直接把它们加起来即可.\n【详解】8+9+10+11+12+1+6=57(下),答：这座钟从上午8点到下午1点半一共敲了57下。",
+    "knowledge_points": [
+      "100以内数的连加运算",
+      "时，分的认识及换算"
+    ],
+    "source": "23-24 三年级上·全国·课后作业"
+  },
+  {
+    "id": "295",
+    "unit": "第七单元 认识时间",
+    "question_type": "解答题",
+    "difficulty": 0.65,
+    "question": "爸爸坐火车出差，请问爸爸坐了多长时间火车。\n\n![](images/ce587b250b95b27efa979e399d0120c32d99891282c210c0dd1a544f78c5c7ed.jpg)\n\n![](images/66f0865a6a82869c642c2cd016d11b3d35838c0974fa2d853e36b67c1305f01a.jpg)",
+    "options": [],
+    "answer": "15小时",
+    "solution": "【分析】爸爸坐火车的时间可以分为两段,1月1日时针从7走到12经过12-7=5(小时),1月2日时针从12走到10经过10小时，因此爸爸坐火车的时间一共是5+10=15(小时),据此解答即可.\n【详解】12-7=5(小时),5+10=15(小时),答：爸爸坐了15小时火车。",
+    "knowledge_points": [
+      "时，分，秒有关的计算"
+    ],
+    "source": "23-24 三年级上·全国·课后作业"
+  },
+  {
+    "id": "296",
+    "unit": "第七单元 认识时间",
+    "question_type": "解答题",
+    "difficulty": 0.65,
+    "question": "星期天，小雅去少年宫学习画画，开始上课时，钟面时针指向9，分针指向12，下课时，时针在11到12之间，分针指向6，小雅一共学习了多长时间。",
+    "options": [],
+    "answer": "2小时30分",
+    "solution": "【分析】根据题意可知,9时开始上课,11时30分下课。用结束的时刻减去开始的时刻即可求出一共学习了多长时间.\n【详解】11时30分-9时=2小时30分，答：小雅一共学习了2小时30分。",
+    "knowledge_points": [
+      "整点时间与钟面指针的位置",
+      "半点时间与钟面指针的位置",
+      "时，分，秒有关的计算"
+    ],
+    "source": "23-24 二年级上·全国·课后作业"
+  },
+  {
+    "id": "297",
+    "unit": "第七单元 认识时间",
+    "question_type": "解答题",
+    "difficulty": 0.65,
+    "question": "李伯伯要将一根6米长的木料平均锯成6段，每锯一次需要4分钟，他从下午3:40开始锯，要到什么时候才能锯完。",
+    "options": [],
+    "answer": "下午4:00",
+    "solution": "【分析】锯一次分成2段，锯两次分成3段，锯三次分成4段，锯四次分成5段，锯五次分成6段，也就是一根木料锯成6段，需要锯5次;每锯一次需要4分钟，先用乘法求出锯5次需要多少分钟;然后根据\"结束时间=开始时间+经过时间\"来求出锯完时间即可.\n【详解】6-1=5(次),4×5=20(分钟),3:40+20分钟=4:00，答：要到下午4:00才能锯完。",
+    "knowledge_points": [
+      "时，分，秒有关的计算",
+      "时，分，秒时间的推算",
+      "植树问题(两端都不栽)"
+    ],
+    "source": "23-24 二年级上·全国·课后作业"
+  },
+  {
+    "id": "298",
+    "unit": "第七单元 认识时间",
+    "question_type": "解答题",
+    "difficulty": 0.65,
+    "question": "下午小丁放学回家，他从镜子里看到钟面上的时间是5:45,25分钟后小丁练完钢琴，这时钟面上的正确的时间是几时几分。",
+    "options": [],
+    "answer": "6时40分",
+    "solution": "【分析】镜面时间问题要掌握镜子中的时间与实际时间刚好是左右相反的。5时多，镜子里时针在\"5\"和\"6\"之间，实际在\"6\"和\"7\"之间，表示6时多;45分，镜子里分针指向\"9\"，实际分针指向\"3\"，表示15分，所以小丁放学正确时间为6时15分;然后根据\"结束时间=开始时间+经过时间\"来求出这时钟面上的正确的时间.\n【详解】从镜子里看到钟面上的时间是5:45，实际时间是6:15;6时15分+25分钟=6时40分，答：这时钟面上的正确的时间是6时40分。",
+    "knowledge_points": [
+      "镜面对称",
+      "一般时间与钟面指针的位置",
+      "时，分，秒时间的推算"
+    ],
+    "source": "23-24 二年级上·全国·课后作业"
+  },
+  {
+    "id": "299",
+    "unit": "第七单元 认识时间",
+    "question_type": "解答题",
+    "difficulty": 0.85,
+    "question": "学校每天早上8时35分上第一节课,9时15分第一节课下课，一节课是多长时间。",
+    "options": [],
+    "answer": "40分钟",
+    "solution": "【分析】经过时间=结束时刻-开始时刻;用下课时刻减去上课时刻，求出一节课的时长。据此解决.\n【详解】9时15分-8时35分=40(分钟),答：一节课是40分钟。",
+    "knowledge_points": [
+      "时，分，秒有关的计算"
+    ],
+    "source": "23-24 二年级上·全国·课后作业"
+  },
+  {
+    "id": "300",
+    "unit": "第七单元 认识时间",
+    "question_type": "解答题",
+    "difficulty": 0.85,
+    "question": "小明从家到学校用30分钟，要求8:30到校，小明最迟什么时候从家出发才能不迟到。",
+    "options": [],
+    "answer": "8时",
+    "solution": "【分析】根据题意可知，用到校的时间-小明路上的时间=小明最迟从家出发的时间.\n【详解】8时30分-30分=8时，答：小明最迟8时从家出发才能不迟到。",
+    "knowledge_points": [
+      "时，分，秒时间的推算"
+    ],
+    "source": "22-23 二年级下·湖南邵阳·期中"
+  },
+  {
+    "id": "301",
+    "unit": "第七单元 认识时间",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "分针从3走到9，下列说法正确的是( )。",
+    "options": [
+      "A. 走了30分",
+      "B. 走了6时",
+      "C. 走了35分"
+    ],
+    "answer": "A",
+    "solution": "【分析】钟面上长针是分针，短针是时针，共12个大格，分针走1大格是5分钟，时针走1大格是1小时。由此计算出分针从3走到9走了几个大格，再和5相乘即可求出走了多长时间.\n【详解】分针从3走到9，走了9-3=6(大格);6×5=30(分),分针从3走到9，走了30分。故答案为:A",
+    "knowledge_points": [
+      "时，分，秒有关的计算"
+    ],
+    "source": "23-24 二年级上·甘肃庆阳·期末"
+  },
+  {
+    "id": "302",
+    "unit": "第七单元 认识时间",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "妈妈9:00吃完早餐，休息一会儿后，再去商场买衣服。妈妈去商场的时间可能是( )。",
+    "options": [
+      "A. ![](images/285c5f4ab04795101e83ab63bf1eeaaa8c6e1fe04a17aade8da0fb3e57fb8276.jpg)",
+      "B. ![](images/51e3b57798e6448be645f49e6d44bec8e77e461611819cf70fdb10f0eae1ec76.jpg)",
+      "C. ![](images/16893c23ce080c24c3131fe3ddf027c367cabaffe75a6a56e3781a9ac71fcba4.jpg)"
+    ],
+    "answer": "C",
+    "solution": "【分析】妈妈9:00吃完早餐，休息一会儿后，再去商场买衣服。妈妈去商场的时间是在9:00以后。先读出每个钟表上的时间，再找出符合要求的即可.\n【详解】A。分针指向1，表示5分，时针指向6过一点，表示6时多，合起来就是6时5分，不符合题意;B。分针指向5，表示25分，时针指向2和3之间，表示2时多，合起来就是2时25分，不符合题意;C。分针指向11，表示55分，时针快指向10，表示9时多，合起来就是9时55分，符合题意;妈妈去商场的时间可能是9时55分。故答案为:C",
+    "knowledge_points": [
+      "一般时间与钟面指针的位置"
+    ],
+    "source": "23-24 二年级上·山东临沂·期末"
+  },
+  {
+    "id": "303",
+    "unit": "第七单元 认识时间",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "下列说法中正确的是( )。",
+    "options": [
+      "A. 9时30分时，钟面的时针与分针成直角",
+      "B. 角的两边越长，角就越大",
+      "C. 角有一个顶点两条边"
+    ],
+    "answer": "C",
+    "solution": "【分析】分针指向6，时针刚过几就是几时半。当一条直线和另一条横的直线交成的邻角彼此相等时，这些角的每一个被叫做直角。角的大小与角的两条边张开的程度有关，而角的大小与边的长短没有关系。两边张开的越大，角就越大。角有两条边和一个公共端点，这两条边叫做角的边，它们的公共端点叫做角的顶点。据此解答.\n【详解】A。9时30分，钟面的时针与分针成钝角，原题说法错误;B。角的两条边的长度和角的大小没有关系，原题说法错误;C。角有一个顶点两条边，原题说法正确。故答案为:C",
+    "knowledge_points": [
+      "角的初步认识及辨认",
+      "角的大小比较",
+      "半点时间与钟面指针的位置"
+    ],
+    "source": "23-24 二年级上·浙江温州·期末"
+  },
+  {
+    "id": "304",
+    "unit": "第七单元 认识时间",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "星期六上午9时，小明开始做口算题,5分钟后完成，小明完成口算时，钟面上时针和分针形成的夹角是( )。",
+    "options": [
+      "A. 锐角",
+      "B. 直角",
+      "C. 钝角"
+    ],
+    "answer": "C",
+    "solution": "【分析】9时，时针指向9，分针指向12，这时两针之间的夹角是直角,5分钟后，分针指向1，时针刚刚超过9一点，所以两针之间的夹角是钝角.\n【详解】9时5分，钟面上时针和分针形成的夹角是钝角。故答案为:C",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征",
+      "一般时间与钟面指针的位置"
+    ],
+    "source": "23-24 二年级上·浙江嘉兴·期末"
+  },
+  {
+    "id": "305",
+    "unit": "第七单元 认识时间",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "钟面上的时间是( ).\n\n![](images/63b9edfd69301e3db5d943374e2c2bd46c826c6a95a12f20eb2c84672d5f9e57.jpg)",
+    "options": [
+      "A. 7时45分",
+      "B. 4时35分",
+      "C. 8时15分"
+    ],
+    "answer": "B",
+    "solution": "【分析】钟面上有12个大格，时针走一大格是1时，分针走一大格是5分，时针在4和5之间表示的是4时多，分针指着7，表示7×5=35分，据此解答.\n【详解】根据分析：题图的时间是4时35分。故答案为:B",
+    "knowledge_points": [
+      "一般时间与钟面指针的位置"
+    ],
+    "source": "23-24 二年级上·浙江温州·期末"
+  },
+  {
+    "id": "306",
+    "unit": "第七单元 认识时间",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "下面的时刻中，同学们正在\"大课间\"的是( ).\n\n![](images/cb4dff59bdde4153926787dac2fff08d774d9f179b2edb00a4e35c798df39213.jpg)",
+    "options": [
+      "A. 3:10",
+      "B. 4:20",
+      "C. 3:50"
+    ],
+    "answer": "C",
+    "solution": "【分析】用现在的时间加上10分钟就是大课间开始的时间，用大课间开始的时间加30分钟就是大课间结束的时间.\n【详解】3:20+10分钟=3:30,3:30+30分钟=4:00，大课间的时间是3:30到4:00。A。3:10在3:30之前，不符合;B。4:20在4:00之后，不符合;C。3:50在3:30到4:00之间，符合。故答案为:C",
+    "knowledge_points": [
+      "时，分，秒时间的推算"
+    ],
+    "source": "23-24 二年级上·浙江温州·期末"
+  },
+  {
+    "id": "307",
+    "unit": "第七单元 认识时间",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "想一想妈妈可能在如图哪个时间去超市买菜。( )\n\n![](images/2026-03-02%20013522.jpg)",
+    "options": [
+      "A. ![](images/5753d8f2c6b2cb23ab25e115bc9dbc4954a7935425b56272566160f431f05da1.jpg)",
+      "B. ![](images/63755d7233b0c41000f88c621ff5abb2ce1cc314eac9806a445d173d125aba02.jpg)",
+      "C. ![](images/3de75811b625e63230e2d08f93041116f1e0f1832c01d0d6923ce22648885a6e.jpg)"
+    ],
+    "answer": "B",
+    "solution": "【分析】根据题意，妈妈去超市买菜的时间在8:40至12:20之间，由此找到合适的即可.\n【详解】A。分针指向7，时针指向8和9之间，是8:35，在大扫除之前，不符合题意;B。分针指向1，时针指向10，是10:05，在8:40至12:20之间，符合题意;C。分针指向6，时针指向12和1之间，是12:30，在吃午饭之后，不符合题意。所以妈妈可能在10:05去超市买菜。故答案为:B",
+    "knowledge_points": [
+      "一般时间与钟面指针的位置"
+    ],
+    "source": "23-24 二年级上·河南焦作·期末"
+  },
+  {
+    "id": "308",
+    "unit": "第七单元 认识时间",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "一刻前是( ).\n\n![](images/91909ca85a5ee93cefaac428a4dd93097f113546b52bcfac7b8309791a572fe1.jpg)",
+    "options": [
+      "A. 9:15",
+      "B. 8:30",
+      "C. 8:45"
+    ],
+    "answer": "C",
+    "solution": "【分析】钟面上长针是分针，短针是时针。分针走1大格是5分钟，时针走1大格是1小时。题中钟面分针指向12，时针指向9，是9时。一刻是15分，一刻前的时间=现在的时间-15分，计算即可.\n【详解】9时-15分=8时45分，也写作8:45。一刻前是8:45。故答案为:C",
+    "knowledge_points": [
+      "整点时间与钟面指针的位置",
+      "时，分，秒时间的推算"
+    ],
+    "source": "23-24 二年级上·山东菏泽·期末"
+  },
+  {
+    "id": "309",
+    "unit": "第七单元 认识时间",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "典典周六上午9:00看完课外书，然后和朋友一起打篮球,12:00吃午饭，典典可能在( )和朋友一起打篮球。",
+    "options": [
+      "A. 8:50",
+      "B. 10:30",
+      "C. 12:10"
+    ],
+    "answer": "B",
+    "solution": "【分析】根据题意，典典和朋友打篮球的时间应在9:00到12:00之间，由此选择合适的即可.\n【详解】A。8:50在典典看完课外书之前，不符合题意;B。10:30在9:00和12:00之间，符合题意;C。12:10在吃午饭时间之后，不符合题意。典典可能在10:30和朋友一起打篮球。故答案为:B",
+    "knowledge_points": [
+      "时，分，秒时间的推算"
+    ],
+    "source": "23-24 二年级上·湖南怀化·期末"
+  },
+  {
+    "id": "310",
+    "unit": "第七单元 认识时间",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "分针从12走到6，走了( )分。",
+    "options": [
+      "A. 6",
+      "B. 30",
+      "C. 12"
+    ],
+    "answer": "B",
+    "solution": "【分析】时针走一大格是1时;分针走1小格是1分，走1大格是5分;秒针走1小格是1秒，走1大格是5秒。分针从12走到6，走了6大格，用6乘5即可求解.\n【详解】6×5=30(分),分针从12走到6，走了30分。故答案为:B",
+    "knowledge_points": [
+      "时，分的认识及换算"
+    ],
+    "source": "18-19 二年级上·全国·期末"
+  },
+  {
+    "id": "311",
+    "unit": "第七单元 认识时间",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "小军8:30开始做作业，然后去找小明玩,11:30回家吃午饭。小军去找小明玩出发的时间可能是( )。",
+    "options": [
+      "A. ![](images/c727be5f01cd41ee498e058c38978933d00a98baf3af8192dc213d754806ce80.jpg)",
+      "B. ![](images/ec2c523233cc0ba7fce237b81baea2fb0cc6960a53c0c411dcfb7ac85d75aef6.jpg)",
+      "C. ![](images/8337ce0d74d03d9ebee19e1e303ae93ef2404b862e5ba0d7a2987752e202b9b0.jpg)"
+    ],
+    "answer": "B",
+    "solution": "【分析】根据题意，小军找小明玩出发的时间应该在8:30至11:30之间，由此找到合适的即可.\n【详解】A。分针指向10，时针接近12，是11:50，超过了吃午饭的时间，不符合题意;B。分针指向2，时针指向10多一点儿，是10:10，在8:30至11:30之间，符合题意;C。分针指向4，时针指向8和9之间，是8:20，在写作业时间之前，不符合题意。小军去找小明玩出发的时间可能是10:10。故答案为:B",
+    "knowledge_points": [
+      "一般时间与钟面指针的位置",
+      "时，分，秒时间的推算"
+    ],
+    "source": "23-24 二年级上·湖南张家界·期末"
+  },
+  {
+    "id": "312",
+    "unit": "第七单元 认识时间",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "分针从3走到11，走过了( )分。",
+    "options": [
+      "A. 8",
+      "B. 40",
+      "C. 35"
+    ],
+    "answer": "B",
+    "solution": "【分析】钟面上有12个大格，分针走1大格是5分钟，由此计算出走了多少个大格，再用乘法计算出走了多少分即可.\n【详解】分针从3走到11，走了11-3=8(大格);8×5=40(分),走过了40分。故答案为:B",
+    "knowledge_points": [
+      "8的乘法口诀及应用",
+      "时，分，秒有关的计算"
+    ],
+    "source": "23-24 二年级上·江西新余·期末"
+  },
+  {
+    "id": "313",
+    "unit": "第七单元 认识时间",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面的时间读得对的钟表是( )。",
+    "options": [
+      "A. ![](images/e291009c92db8ece986fe3d3c699df65d59f88c52bea5b3735d0f2a1dd145cb6.jpg) 7时半",
+      "B. ![](images/0a8dea7c4f7367a7a4f9eb229a305a26f328077e234600960259e0068cc8d5fa.jpg) 6时半",
+      "C. ![](images/d4499b8246846001571fa650f0f35378b617a03775dfc07b80848da7354ab717.jpg) 6时刚过"
+    ],
+    "answer": "A",
+    "solution": "【分析】钟面上长针是分针，短针是时针。分针走1大格是5分钟，时针走1大格是1小时。由此读出每个钟表的时间选择即可.\n【详解】A。分针指向6，时针过了7，在7和8之间，是7时半;B。分针指向6，时针过了5，在5和6之间，是5时半;C。分针指向6，时针过了12，在12和1之间，是12时半。故答案为:A",
+    "knowledge_points": [
+      "半点时间与钟面指针的位置"
+    ],
+    "source": "23-24 一年级上·湖北襄阳·期末"
+  },
+  {
+    "id": "314",
+    "unit": "第七单元 认识时间",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "下面是星星周六的活动时间安排表.\n\n<table><tr><td>时间</td><td>上午8:00~9:00</td><td>上午9:00~9:40</td><td>中午12:00</td></tr><tr><td>活动</td><td>看书</td><td>运动</td><td>吃午饭</td></tr></table>\n\n星星运动完准备去超市购物。星星在超市购物的时间可能是( )。",
+    "options": [
+      "A. ![](images/d99edfea5812f38e86ae6cf844f086bacc0a16f19fe54fa14186a85db52165d2.jpg)",
+      "B. ![](images/0272ad67c28a3179c25b2b080bbfbb52c682630f484805b69042845da0f07741.jpg)",
+      "C. ![](images/cc7a02a18004347a183dbd4e076371708f7e51b76932e0c1a715adc53229f92c.jpg)"
+    ],
+    "answer": "B",
+    "solution": "【分析】根据题意，运动的时间是上午9:00~9:40，吃午饭时间是中午12:00，运动完准备去超市购物。所以去超市的时间应该在9:40~12:00之间，由此逐项判断.\n【详解】A。是9:30，这时在运动，不符合题意;B。是10:15，在9:40~12:00之间，符合题意;C。是12:25，是吃过午饭之后，不符合题意。故答案为:B",
+    "knowledge_points": [
+      "一般时间与钟面指针的位置",
+      "时，分，秒时间的推算"
+    ],
+    "source": "23-24 二年级上·浙江台州·期末"
+  },
+  {
+    "id": "315",
+    "unit": "第七单元 认识时间",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "电影开始播放的时间是上午10时，明明和妈妈到电影院的时间如图，明明和妈妈迟到了吗。( )\n\n![](images/73da539e20d42f363b1b473722da4af5f19d8fcf052ebea06b0b991e86aea78d.jpg)",
+    "options": [
+      "A. 迟到了",
+      "B. 没迟到",
+      "C. 不能确定"
+    ],
+    "answer": "A",
+    "solution": "【分析】根据钟表上时间的认识，分针指12，时针指几就是几时;分针刚过12，时针过几，就是几时刚过;由此得出钟面上时间，再与开始时间比较即可解答.\n【详解】由题可知：电影开始播放的时间是上午10时，钟面的时间是10时刚过，所以明明和妈妈迟到了。故答案为:A",
+    "knowledge_points": [
+      "整点时间与钟面指针的位置",
+      "时，分，秒时间的推算"
+    ],
+    "source": "23-24 一年级上·重庆大渡口·期末"
+  },
+  {
+    "id": "316",
+    "unit": "第七单元 认识时间",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "下面钟表显示的时间再过10分是( ).\n\n![](images/e0b8564e16689031647bafa27dca8cb1d26ad8be98f1816c667b46ba9470cf0d.jpg)",
+    "options": [
+      "A. 9时50分",
+      "B. 8时55分",
+      "C. 8时35分"
+    ],
+    "answer": "B",
+    "solution": "【分析】时针走一大格是1时;分针走1小格是1分，走1大格是5分;秒针走1小格是1秒，走1大格是5秒。时针刚过几就是几时，分针指向第多少个小格就是多少分。钟表显示的是8时45分，再加10分即可求解.\n【详解】8时45分+10分=8时55分，钟表显示的时间再过10分是8时55分。故答案为:B",
+    "knowledge_points": [
+      "一般时间与钟面指针的位置",
+      "时，分，秒时间的推算"
+    ],
+    "source": "23-24 二年级上·山东济南·期末"
+  },
+  {
+    "id": "317",
+    "unit": "第七单元 认识时间",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "玲玲和妈妈周六早上8:05出门去超市，去的路上花了10分钟，买东西用了35分钟，回来的路上花了10分钟。她们到家的时间是( )。",
+    "options": [
+      "A. 8:60",
+      "B. 9:00",
+      "C. 9:05"
+    ],
+    "answer": "B",
+    "solution": "【分析】出门的时间加上路上来回的时间，加上买东西的时间就是到家的时间，注意如果分钟数满60分钟要往前进一小时。本题考查了时间的计算问题.\n【详解】8:05+10分+35分+10分=9:00，她们到家的时间是9:00。故答案为:B",
+    "knowledge_points": [
+      "时，分，秒时间的推算"
+    ],
+    "source": "23-24 二年级上·湖北武汉·期末"
+  },
+  {
+    "id": "318",
+    "unit": "第七单元 认识时间",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "如图中钟面上所示的时间，再过一刻是( ).\n\n![](images/39e4b310958d009c75940ca4d30ef715c68635765d2991aaf10e399409156182.jpg)",
+    "options": [
+      "A. 10:45",
+      "B. 9:45",
+      "C. 9:15"
+    ],
+    "answer": "B",
+    "solution": "【分析】钟面上有12大格。分针走1大格是5分钟，时针走1大格是1小时。分针指向6，时针指向9和10之间，是9时30分。结束的时刻=开始的时刻+经过的时间，由此计算即可.\n【详解】一刻是15分;9时30分+15分=9时45分，钟面上所示的时间，再过一刻是9时45分，也写作9:45。故答案为:B",
+    "knowledge_points": [
+      "半点时间与钟面指针的位置",
+      "时，分，秒时间的推算"
+    ],
+    "source": "23-24 二年级上·山西忻州·期末"
+  },
+  {
+    "id": "319",
+    "unit": "第七单元 认识时间",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "丹丹可能在( )去超市购物.\n\n![](images/2026-03-02%20143951.jpg)",
+    "options": [
+      "A. ![](images/11761e5cf305619df08a25f3d8474557c0701569be0a6ea86cc486da4e1793d6.jpg)",
+      "B. ![](images/d9ccf54172e5681240f7359a75d3e74dc9df2720498935685b56a06249530a23.jpg)",
+      "C. ![](images/a797e1d5d143f4f62f47bbd35ac89ae10ec43694587ab55bfbb94fd09de71999.jpg)"
+    ],
+    "answer": "B",
+    "solution": "【分析】先读出钟表上的时间，再找出时间是在9:00之后,11:30之前的，就是丹丹去超市的时间.\n【详解】A。此刻是8:25，在9:00之前，不符合题意;B。此刻是10:30，在9:00之后,11:30之前，符合题意;C。此刻是11:40，在11:30之后，不符合题意;即，丹丹可能在10:30去超市购物。故答案为:B",
+    "knowledge_points": [
+      "半点时间与钟面指针的位置",
+      "一般时间与钟面指针的位置"
+    ],
+    "source": "23-24 二年级上·四川南充·期末"
+  },
+  {
+    "id": "320",
+    "unit": "第七单元 认识时间",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "2024年建发厦门马拉松赛将于2024年1月7日在我市思明区举行，有三名运动员同组参加跑步比赛，下面钟面上显示的是他们到达终点的时间,( )跑得最快.\n\n![](images/d14cdf71852cc1aa8e3dab5d6059d055c7bbd5cb88f64eb2c26b538dd2cd4aae.jpg)",
+    "options": [
+      "A. 培培",
+      "B. 优优",
+      "C. 聪聪"
+    ],
+    "answer": "A",
+    "solution": "【分析】跑步比赛是同时出发的，到达终点的时间越早，表示跑得越快。先读出时间，再比较一下，即可解决.\n【详解】A。![](images/c410318513a0192a1a5912ee89199395cf8b95d4c079c2337819ef168a698828.jpg),时针快指向10，表示9时多，分针指向11，表示55分，合起来就是9时55分;B。![](images/a6b04c104fc77092650cd078fa3b5f65e8be70eabef59aa8b58e81a1a8627ac2.jpg),时针指向10，分针指向12，表示10时;C。![](images/6f63c63a918616bad6c8f0663929af4904450d0221d8e7a22aa9485e18c3a1a2.jpg),时针指向10多一些，表示10时多，分针指向1，表示5分，合起来就是10时5分;9时55分早于10时,10时又早于10时5分。故，培培跑得最快。故答案为:A",
+    "knowledge_points": [
+      "整点时间与钟面指针的位置",
+      "一般时间与钟面指针的位置",
+      "时间快慢的比较"
+    ],
+    "source": "23-24 二年级上·福建厦门·期末"
+  },
+  {
+    "id": "321",
+    "unit": "第七单元 认识时间",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "红红8:30开始大扫除，然后去摘草莓,11:30要去琳琳家玩。红红可能在下面( )时间去摘草莓。",
+    "options": [
+      "A. ![](images/0d45e268c5b38f3ca5ba61456dcddc823fda6a6d21a3e085d623e963aefd2413.jpg)",
+      "B. ![](images/2a1b6ff9cae8378779b712f9e2e68ba2fe9bc4d4392ffce4fb0b7d0a7a99fe58.jpg)",
+      "C. ![](images/fd4b7667827ed6c60467b7829160a784799237385c2c89ed38069eb1e7fe5d73.jpg)"
+    ],
+    "answer": "B",
+    "solution": "【分析】根据题意可知，红红可能去摘草莓的时间在8:30~11:30之间，分析各钟面的时间，找到符合题意的即可.\n【详解】A。分针指向7，时针指向8和9之间，是8时35分，这段时间大扫除一般不能完成，不符合题意;B。分针指向1，时针指向10多一点儿，是10时5分，符合题意;C。分针指向6，时针指向11和12之间，是11时30分，不符合题意。红红可能在10时5分去摘草莓。故答案为:B",
+    "knowledge_points": [
+      "半点时间与钟面指针的位置",
+      "一般时间与钟面指针的位置"
+    ],
+    "source": "23-24 二年级上·福建厦门·期末"
+  },
+  {
+    "id": "322",
+    "unit": "第七单元 认识时间",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "时针指在4和5之间，分针指着7，这时的时间是( )。",
+    "options": [
+      "A. 4:07",
+      "B. 4:35",
+      "C. 5:35"
+    ],
+    "answer": "B",
+    "solution": "【分析】钟面上有12个大格，分针走1大格是5分钟，时针走1大格是1小时。时针在4和5之间，是4时。分针指向7，是5×7=35(分),此时时间是4时35分，也写作4:35，由此解答.\n【详解】由分析可知，时针指在4和5之间，分针指着7，这时的时间是4:35。故答案为:B",
+    "knowledge_points": [
+      "一般时间与钟面指针的位置"
+    ],
+    "source": "23-24 二年级上·福建厦门·期末"
+  },
+  {
+    "id": "323",
+    "unit": "第七单元 认识时间",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "小马老师7:30开车从家出发，大约9:00就可以到达目的地了。小马老师可能在路上的时间是( )。",
+    "options": [
+      "A. 7:25",
+      "B. 8:30",
+      "C. 9:30"
+    ],
+    "answer": "B",
+    "solution": "【分析】小马老师可能在路上的时间是7:30到9:00之间，找出符合的即可.\n【详解】A。7:25在7:30之前，不符合;B。8:30在7:30到9:00之间，符合;C。9:30在9:00之后，不符合。小马老师可能在路上的时间是8:30。故答案为:B",
+    "knowledge_points": [
+      "时，分的认识及换算"
+    ],
+    "source": "23-24 二年级上·广东东莞·期末"
+  },
+  {
+    "id": "324",
+    "unit": "第七单元 认识时间",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "分针从5走到8，走了( )。",
+    "options": [
+      "A. 3时",
+      "B. 30分",
+      "C. 一刻"
+    ],
+    "answer": "C",
+    "solution": "【分析】钟面上有12个大格，分针走1大格是5分钟。先计算出走了几大格，再用乘法计算出走了多长时间即可.\n【详解】分针从5走到8，走了8-5=3(大格);5×3=15(分钟),15分钟=1刻钟，分针从5走到8，走了一刻。故答案为:C",
+    "knowledge_points": [
+      "时，分，秒有关的计算"
+    ],
+    "source": "23-24 二年级上·河南南阳·期末"
+  },
+  {
+    "id": "325",
+    "unit": "第七单元 认识时间",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "亮亮可能在哪个时间去公园玩。( )\n\n![](images/2026-03-02%20144441.jpg)",
+    "options": [
+      "A. ![](images/18b18bf55652e8cdc462e94511af6623e79bb20e1882db43db831c39d37023f3.jpg)",
+      "B. ![](images/742892c71c581016dedba17cece0071269783f39630cdae9567f984912eb7ca5.jpg)",
+      "C. ![](images/f8db53cfdcba3a23185f2112a2bcbf31db9a4246b7e373f9d812a601d8387f82.jpg)"
+    ],
+    "answer": "B",
+    "solution": "【分析】亮亮应该在8:00到10:30之间去公园玩，选择符合的时间即可。分针指向6，时针刚过几就是几时半。时针走一大格是1时;分针走1小格是1分，走1大格是5分;秒针走1小格是1秒，走1大格是5秒。时针刚过几就是几时，分针指向第多少个小格就是多少分.\n【详解】A。钟面显示为11:05，在10:30之后，不符合;B。钟面显示为8:30，在8:00到10:30之间，符合;C。钟面显示为7:55，在8:00之前，不符合。故答案为:B",
+    "knowledge_points": [
+      "半点时间与钟面指针的位置",
+      "一般时间与钟面指针的位置",
+      "时，分，秒时间的推算"
+    ],
+    "source": "23-24 二年级上·河南南阳·期末"
+  },
+  {
+    "id": "326",
+    "unit": "第七单元 认识时间",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "小文8:00开始写作业，写完作业去踢球，然后要在11:00以前去奶奶家。下面时间他可能在踢球的是( )。",
+    "options": [
+      "A. ![](images/602d6316002afc77ba711ae360e00ab4978613b19e4d98ae17a1f6a35619bf72.jpg)",
+      "B. ![](images/56308f32f18573ac74672ead07de07d0054243cfd0a6467ef803c28d18cdc73c.jpg)",
+      "C. ![](images/f67b6156f0bad7986dcd1584087a130ab7cf42db456db87cb0e12ee8a29572e0.jpg)"
+    ],
+    "answer": "A",
+    "solution": "【分析】小文踢球的时间应该在8:00到11:00之间，找出符合的时间即可。分针指向6，时针刚过几就是几时半。时针走一大格是1时;分针走1小格是1分，走1大格是5分;秒针走1小格是1秒，走1大格是5秒。时针刚过几就是几时，分针指向第多少个小格就是多少分.\n【详解】A。钟面显示10:10，在8:00到11:00之间，符合;B。钟面显示11:30，在11:00之后，不符合;C。钟面显示7:50，在8:00之前，不符合。故答案为:A",
+    "knowledge_points": [
+      "半点时间与钟面指针的位置",
+      "一般时间与钟面指针的位置"
+    ],
+    "source": "23-24 二年级上·湖南株洲·期末"
+  },
+  {
+    "id": "327",
+    "unit": "第七单元 认识时间",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "下面( )时间，钟面的时针和分针成直角。",
+    "options": [
+      "A. 6时",
+      "B. 9时",
+      "C. 12时"
+    ],
+    "answer": "B",
+    "solution": "【分析】当一条直线和另一条横的直线交成的邻角彼此相等时，这些角的每一个被叫做直角.\n【详解】A。6时分针指向12，时针指向6，时针和分针在一条直线上，不成直角;B。9时分针指向12，时针指向9，时针和分针成直角;C。12时时针和分针重合，都指向12，不成直角。9时，钟面的时针和分针成直角。故答案为:B",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征",
+      "整点时间与钟面指针的位置"
+    ],
+    "source": "23-24 二年级上·浙江嘉兴·期末"
+  },
+  {
+    "id": "328",
+    "unit": "第七单元 认识时间",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "小亮开始读书的时间如图所示，他半小时后上床睡觉，睡觉时间是( ).\n\n![](images/82dafc8ef5278116514d08011d2473f59cf7301ad312169556e47f2e8328ae19.jpg)",
+    "options": [
+      "A. 8:45",
+      "B. 9:06",
+      "C. 9:30"
+    ],
+    "answer": "C",
+    "solution": "【分析】分针指向12，时针指向几就是几时。钟表所示时间是9时，半小时是30分，用9时加30分即可求解.\n【详解】半小时=30分,9时+30分=9时30分，睡觉时间是9:30。故答案为:C",
+    "knowledge_points": [
+      "整点时间与钟面指针的位置",
+      "时，分，秒时间的推算"
+    ],
+    "source": "23-24 二年级上·贵州铜仁·期末"
+  },
+  {
+    "id": "329",
+    "unit": "第七单元 认识时间",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "小兔子去拔萝卜的时间可能是( ).\n\n![](images/4cbec5b350cd0f117f1d10a4aa5f887185197c11d79a73eca444c518aa77c174.jpg)",
+    "options": [
+      "A. ![](images/1beb74839836a4118de3fc64692fbb7166f6b00831aaef9abe5649512990f4b7.jpg)",
+      "B. ![](images/e30219b52e192e41b44204624a0b8945bee38cc40ead1782cbb9605a8e4c4924.jpg)",
+      "C. ![](images/be5efabb30d98eb4eb625855c10c91864ed1ab63a3dd45416eda09123e412685.jpg)"
+    ],
+    "answer": "B",
+    "solution": "【分析】由题可知，小兔子去拔萝卜的时间在8:05到11:05之间，据此选择.\n【详解】A。钟面显示的时间是7:05，在8:05之前，不符合;B。钟面显示的时间是9:30，在8:05到11:05之间，符合;C。钟面显示的时间是11:30，在11:05之后，不符合。故答案为:B",
+    "knowledge_points": [
+      "半点时间与钟面指针的位置",
+      "一般时间与钟面指针的位置"
+    ],
+    "source": "23-24 二年级上·湖北黄石·期末"
+  },
+  {
+    "id": "330",
+    "unit": "第七单元 认识时间",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "小丽晚上7时半有一节钢琴课，她计划下午5:00开始写作业，写完作业去钢琴教室。小丽在去钢琴教室的路上的时间可能是( )。",
+    "options": [
+      "A. ![](images/152e2dc214ccd9c513954c4149b74f58f0d008daa5b893f1a9c74211747c3d7c.jpg)",
+      "B. ![](images/3082a49b3fa707d5c6d27111b276f3deb8c3086b0fa28b1a02cd807b04b79db7.jpg)",
+      "C. ![](images/1880ab584837110c805c38db0c47b7e404481e628ad43b99e252a1baf0b96d5a.jpg)"
+    ],
+    "answer": "B",
+    "solution": "【分析】根据题意，路上的时间应该在5:00至7:30之间，找出选项中在这一时间段内的即可.\n【详解】A。分针指向12，时针指向8，是8时，不符合题意;B。分针指向10，时针接近7，是6时50分，符合题意;C。分针指向6，时针指向10和11之间，是10时30分，不符合题意。小丽在去钢琴教室的路上的时间可能是6时50分。故答案为:B",
+    "knowledge_points": [
+      "整点时间与钟面指针的位置",
+      "半点时间与钟面指针的位置",
+      "一般时间与钟面指针的位置"
+    ],
+    "source": "23-24 二年级上·广东江门·期末"
+  },
+  {
+    "id": "331",
+    "unit": "第七单元 认识时间",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "第五个节目可能在( )演出.\n\n![](images/2026-03-02%20144856.jpg)",
+    "options": [
+      "A. ![](images/ee507bb5dce2e888ecdc8737771469dcb94d4952416d3cac4c716e2ef7f6b30c.jpg)",
+      "B. ![](images/d1a73f43bd036a259282efc9d549c634759e83d8aa633428acb8dd1b7aa3fee2.jpg)",
+      "C. ![](images/84b7d3df49a406496be814b514958ab64bfe1620d6689ab9e977c14f6d9f6924.jpg)"
+    ],
+    "answer": "A",
+    "solution": "【分析】根据题意，第五个节目时间在8:30至9:40之间。钟面上长针是分针，短针是时针。分针走1大格是5分钟，时针走1大格是1小时，由此分析各选项的时间，找到符合题意的即可.\n【详解】A。分针指向12，时针指向9，是9时，在8:30至9:40之间，符合题意;B。分针指向5，时针指向8和9之间，是8时25分，不在8:30至9:40之间，不符合题意;C。分针指向3，时针指向10多一点儿，是10时15分，不在8:30至9:40之间，不符合题意。所以第五个节目可能在9时演出。故答案为:A",
+    "knowledge_points": [
+      "整点时间与钟面指针的位置",
+      "一般时间与钟面指针的位置"
+    ],
+    "source": "23-24 二年级上·河南漯河·期末"
+  },
+  {
+    "id": "332",
+    "unit": "第七单元 认识时间",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "毛毛周日上午9:00开始写作业，然后去上书法课,12:00回家吃饭。毛毛上书法课的时间可能是( ).\n\n![](images/b2ecb2243137f339c03aad32c627afba8d777f64f5d2ed32aba23e9e0eceb039.jpg)",
+    "options": [
+      "A. ![](images/b2ecb2243137f339c03aad32c627afba8d777f64f5d2ed32aba23e9e0eceb039.jpg)",
+      "B. ![](images/cd912ffb312333c23d3997babedbe003b164d32d7a8d36dbb88c53b1f2bc97a0.jpg)",
+      "C. ![](images/fef9727f17d154e2e6b574fb5f3b0c95a75ad37b8937de2b5a9ce4dc4a66b1bd.jpg)"
+    ],
+    "answer": "B",
+    "solution": "【分析】先读出每个钟表上的时间，再找出在9:00之后,12:00之前的时间，就可能是毛毛上书法课的时间.\n【详解】A。此时是9:00，不在9:00之后，不符合题意;B。此时是10:30，在9:00之后,12:00之前，符合题意;C。此时是12:15，在12:00之后，不符合题意;即，毛毛上书法课的时间可能是10:30。故答案为:B",
+    "knowledge_points": [
+      "整点时间与钟面指针的位置",
+      "半点时间与钟面指针的位置",
+      "一般时间与钟面指针的位置"
+    ],
+    "source": "23-24 二年级上·福建三明·期末"
+  },
+  {
+    "id": "333",
+    "unit": "第七单元 认识时间",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "![](images/3e9ad601c9462c21c56b9c3e7ab26b87dae4e725172923dec82fe5f763f104b2.jpg)过一刻钟后是( )。",
+    "options": [
+      "A. 1:50",
+      "B. 1:35",
+      "C. 2:20"
+    ],
+    "answer": "B",
+    "solution": "【分析】利用结束时间=开始时间+经过时间，即可求出过一刻钟后的时间.\n【详解】通过观察钟面可知开始时间是1:20，加上15分(一刻钟是15分)是1:35。所以过一刻钟后是1:35。故答案为:B",
+    "knowledge_points": [
+      "时，分，秒时间的推算"
+    ],
+    "source": "23-24 二年级上·山东菏泽·期末"
+  },
+  {
+    "id": "334",
+    "unit": "第七单元 认识时间",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "豆豆周六下午2:00开始写作业，做完作业后看动画片，下午6:00开始吃晚饭，豆豆可能在( )看动画片。",
+    "options": [
+      "A. 下午1:30",
+      "B. 下午5:00",
+      "C. 下午6:20"
+    ],
+    "answer": "B",
+    "solution": "【分析】由题意可知：豆豆看动画片的时间是在下午2:00之后，下午6:00之前;据此解决.\n【详解】A。下午1:30是在下午2:00之前，不符合题意;B。下午5:00是在下午2:00之后，下午6:00之前，符合题意;C。下午6:20是在下午6:00之后，不符合题意;即，豆豆可能在下午5:00看动画片。故答案为:B",
+    "knowledge_points": [
+      "时，分的认识及换算"
+    ],
+    "source": "23-24 二年级上·陕西安康·期末"
+  },
+  {
+    "id": "335",
+    "unit": "第七单元 认识时间",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "课间休息的时间是10( )。",
+    "options": [
+      "A. 时",
+      "B. 米",
+      "C. 分"
+    ],
+    "answer": "C",
+    "solution": "【分析】根据实际情况可知，课间休息时间一般都是10分.\n【详解】由题意分析得：课间休息的时间是10分。故答案为:C",
+    "knowledge_points": [
+      "时间单位的选择"
+    ],
+    "source": "23-24 二年级上·陕西安康·期末"
+  },
+  {
+    "id": "336",
+    "unit": "第七单元 认识时间",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "月月星期六上午9:00开始写作业，然后看动画片,12:00吃午饭。月月可能在( )看动画片。",
+    "options": [
+      "A. 8:30",
+      "B. 10:00",
+      "C. 12:30"
+    ],
+    "answer": "B",
+    "solution": "【分析】由题意可知，月月看动画片的时间是在9:00之后，且在12:00之前这段时间;据此解决.\n【详解】A。8:30是在9:00之前，不符合题意;B。10:00是在9:00之后，且在12:00之前，符合题意;C。12:30是在12:00之后，不符合题意;即，月月可能在10:00看动画片。故答案为:B",
+    "knowledge_points": [
+      "时，分的认识及换算"
+    ],
+    "source": "23-24 二年级上·广东河源·期末"
+  },
+  {
+    "id": "337",
+    "unit": "第七单元 认识时间",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "英英和妈妈8:35开始打扫卫生，然后去超市，再在11:00去奶奶家。英英可能在( )去超市。",
+    "options": [
+      "A. ![](images/05710a15f1aa007d70a9ca3799237dfa60cae7ae24a3da63008fced4dc584683.jpg)",
+      "B. ![](images/ee631872c51c8a9cd58dedbf37e70fdf11d7602b29ca0374e54ca4d3c410ad4a.jpg)",
+      "C. ![](images/9443666a73935ab7f7026e5c520a45ca68319127d9348fbcf8481b933e8c578d.jpg)"
+    ],
+    "answer": "B",
+    "solution": "【分析】英英和妈妈8:35开始打扫卫生，然后去超市，再在11:00去奶奶家。说明英英是在8:35和11:00之间去的超市，据此先读出各个钟面上的时刻是多少，再进行判断即可.\n【详解】A。钟面所显示的时刻是8:30，这是英英和妈妈还没开始打扫卫生，不符合题意;B。钟面所显示的时刻是10:05，在8:35和11:00之间，符合题意;C。钟面所显示的时刻是1:30，在11:00之后，不符合题意。故答案为:B.",
+    "knowledge_points": [
+      "半点时间与钟面指针的位置",
+      "一般时间与钟面指针的位置"
+    ],
+    "source": "23-24 一年级上·四川乐山·期末"
+  },
+  {
+    "id": "338",
+    "unit": "第七单元 认识时间",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "钟面上的分针从12走到5，走了( )分。",
+    "options": [
+      "A. 5",
+      "B. 25",
+      "C. 35"
+    ],
+    "answer": "B",
+    "solution": "【分析】钟面上分针走一个数字格是5分，从12到5走过了5个数字格,5×5=25(分),据此得出结论即可.\n【详解】5×5=25(分),即走了25分。故答案为:B",
+    "knowledge_points": [
+      "5的乘法口诀及应用",
+      "一般时间与钟面指针的位置",
+      "时，分的认识及换算"
+    ],
+    "source": "23-24 二年级上·四川广元·期末"
+  },
+  {
+    "id": "339",
+    "unit": "第七单元 认识时间",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "![](images/655a5357f8fa2ea3a6a0cdf1822f7a43af81c538c7423f27600d214876a5659e.jpg)括号里填( )。",
+    "options": [
+      "A. 5",
+      "B. 15",
+      "C. 10"
+    ],
+    "answer": "B",
+    "solution": "【分析】先读出钟表上的时间，再用减法求出经过时间。经过时间=结束时间-开始时间.\n【详解】![](images/46f42d7f21ea916ac6ad1bdff6a199f9b4a81f1bc6fbbb9661db4cab72c5efee.jpg)时针指向10和11之间，表示10时多，分针指向2，表示10分，合起来就是10时10分;![](images/c927f02c33ad1b131420250f762f90e6a90776b9b4dcbe51cdd4dd2f49374de6.jpg)时针指向10和11之间，表示10时多，分针指向5，表示25分，合起来就是10时25分;10时25分-10时10分=15分，故，括号里填15。故答案为:B",
+    "knowledge_points": [
+      "一般时间与钟面指针的位置",
+      "时，分，秒有关的计算"
+    ],
+    "source": "23-24 二年级上·山东菏泽·期末"
+  },
+  {
+    "id": "340",
+    "unit": "第七单元 认识时间",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "6:00过半小时是( )。",
+    "options": [
+      "A. 6:05",
+      "B. 6:50",
+      "C. 6:30"
+    ],
+    "answer": "C",
+    "solution": "【分析】半小时就是30分。根据结束时间=开始时间+经过时间，即可解答.\n【详解】6:00+30分=6:30，即,6:00过半小时是6:30。故答案为:C",
+    "knowledge_points": [
+      "时，分，秒时间的推算"
+    ],
+    "source": "23-24 二年级上·湖南岳阳·期末"
+  },
+  {
+    "id": "341",
+    "unit": "第七单元 认识时间",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "军军在下面哪个时间可能在回家吃饭路上。( )\n\n![](images/2026-03-02%20145606.jpg)",
+    "options": [
+      "A. ![](images/6ee9bbfd5e779980cf3db606b0ef164fd9ae1dfdc54031322bfbb3759608d2bb.jpg)",
+      "B. ![](images/f52bfc1c1828d6ab7db5ef357b816ef7bec7745d266da9e5d6170b03bd1e2c5f.jpg)",
+      "C. ![](images/9025ed066b4e7a049096853aceab67b12682e8163f5ca449f7cfff0ff4356c63.jpg)"
+    ],
+    "answer": "A",
+    "solution": "【分析】军军回家吃饭路上的时间是在9:05之后,12:00之前;据此解决此题。先读出时间，再找出符合要求的时间.\n【详解】A。此时是10:25，这时间是在9:05之后,12:00之前，符合题意。B。此时是5:30，这时间是在9:05之前，不符合题意。C。此时是12:05，这时间是在12:00之后，不符合题意。故，军军回家吃饭路上的时间可能是10:25。故答案为:A",
+    "knowledge_points": [
+      "半点时间与钟面指针的位置",
+      "一般时间与钟面指针的位置"
+    ],
+    "source": "23-24 二年级上·湖南岳阳·期末"
+  },
+  {
+    "id": "342",
+    "unit": "第七单元 认识时间",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "12时50分，时针与分针形成的角是( )。",
+    "options": [
+      "A. 锐角",
+      "B. 直角",
+      "C. 钝角"
+    ],
+    "answer": "A",
+    "solution": "【分析】在三角板上，最大角就是直角;钝角比直角大;锐角比直角小。12时50分，分针指向10，时针快指向1，时针与分针形成的角是锐角.\n【详解】由题意分析得:12时50分，时针与分针形成的角是锐角。故答案为:A",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征",
+      "一般时间与钟面指针的位置"
+    ],
+    "source": "23-24 二年级上·湖南岳阳·期末"
+  },
+  {
+    "id": "343",
+    "unit": "第七单元 认识时间",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "周六红红做完作业去公园玩，但11:00前要回家吃午饭。她从8:30开始做作业，那么她可能在公园玩的时间是( )。",
+    "options": [
+      "A. ![](images/b99d51329caec845550caeb8be76b0d5e5eb60b5bfaaa505a1311b9277707469.jpg)",
+      "B. ![](images/6447fe3760b6b1ed451a0c563e41fdecfdeb2c2224b3f780bc62243cc412a0e1.jpg)",
+      "C. ![](images/ba3e4672b2e544cd9a5273d4f098828100046a15ddfb5d9a79eb2c250a57833e.jpg)"
+    ],
+    "answer": "B",
+    "solution": "【分析】先读出钟表上的时间，再找出在8:30之后,11:00之前的时间，就是红红可能在公园玩的时间.\n【详解】A。此时是11:05，这时间是在11:00之后，不符合题意;B。此时是9:55，这时间是在8:30之后,11:00之前，符合题意;C。此时是7:35，这时间是在8:30之前，不符合题意。故，红红可能在公园玩的时间是9:55。故答案为:B",
+    "knowledge_points": [
+      "一般时间与钟面指针的位置"
+    ],
+    "source": "23-24 二年级上·浙江宁波·期末"
+  },
+  {
+    "id": "344",
+    "unit": "第七单元 认识时间",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "分针从6走到9，走了( )分。",
+    "options": [
+      "A. 6",
+      "B. 15",
+      "C. 30"
+    ],
+    "answer": "B",
+    "solution": "【分析】分针走1大格是5分钟，先用减法求出分针走了几大格，再用乘法求出分针走了几分钟.\n【详解】9-6=3(大格),5×3=15(分),故，分针从6走到9，走了15分。故答案为:B",
+    "knowledge_points": [
+      "时，分，秒有关的计算"
+    ],
+    "source": "23-24 二年级上·山东日照·期末"
+  },
+  {
+    "id": "345",
+    "unit": "第七单元 认识时间",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "钟表显示的时间再过10分是( ).\n\n![](images/0c07b5f94a1627a5ebcb6d30ed094ae9c27a2c6ac95d598882e9e3c01c91a269.jpg)",
+    "options": [
+      "A. 12时10分",
+      "B. 12时16分",
+      "C. 12时40分"
+    ],
+    "answer": "C",
+    "solution": "【分析】首先要认出此时钟表上的时间，钟表上时针在12和1之间表示12时，分针指向6，表示30分，则钟表显示的时间是12时30分。再过10分就是分针再走2大格，指向8，就是12时40分.\n【详解】由分析可得：此时钟表的时间是12时30分，再过10分是12时40分。故答案为:C",
+    "knowledge_points": [
+      "一般时间与钟面指针的位置"
+    ],
+    "source": "22-23 二年级上·广东广州·期末"
+  },
+  {
+    "id": "346",
+    "unit": "第七单元 认识时间",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "小红可能在什么时间去超市购物。( )\n妈妈：\"小红，我们8:30开始大扫除，然后去超市购物.\"\n小红：\"妈妈，我11:30要去小明家玩.\"",
+    "options": [
+      "A. ![](images/31a1f659a6468386d4ee3955aca9ab24a0ec3337bcd6e039852968db6ec9c72c.jpg)",
+      "B. ![](images/c2eb0b8d963af839aa9555e24fa5618a0b6792eb91ee6dba2c10c59488827d42.jpg)",
+      "C. ![](images/62dd42e4c7c45369c74461e5cc032af3620b0221d5b4e80d5dbb65f815bf2635.jpg)"
+    ],
+    "answer": "B",
+    "solution": "【分析】钟面上长针是分针，短针是时针。分针走1大格是5分钟，时针走1大格是1小时，分针指向12时，时针指向几就是几时。分针指向6，时针在两个数中间，较小的数是几，就表示几时30分。A。时针指向8和9之间，分针指向7，是8:35;B。时针指向10，分针指向1，是10:05;C。时针指向11和12之间，分针指向6，是11:30。小红8:30开始大扫除，然后去超市购物,11:30去小明家玩，则小红购物的时间是在8:30以后和11:30之间.\n【详解】由分析可得:A。8:35，小红8:30开始大扫除，则8:35还在打扫除，不符合题意;B。10:05，在8:30开始大扫除以后在11:30之前，符合题意;C。11:30，小红去小明家的时间，不符合题意。故答案为:B",
+    "knowledge_points": [
+      "半点时间与钟面指针的位置",
+      "一般时间与钟面指针的位置"
+    ],
+    "source": "22-23 二年级上·广东广州·期末"
+  },
+  {
+    "id": "347",
+    "unit": "第七单元 认识时间",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "周六的上午，王叔叔打算7:00开始晨练，然后去图书馆看书,11:30回家吃饭。他可能在( )去图书馆。",
+    "options": [
+      "A. ![](images/c5c33bd7fc1731bce3d15f8220ce5880b35288bcae4d5965eb06ab487929a6ad.jpg)",
+      "B. ![](images/1505215843f1c7ae5b5864216506c9ee4882f7bb80c6f3bdcf54efb037ca1bfa.jpg)",
+      "C. ![](images/72678331d10a746e33db52771bf980648ccfd7caf3cffc3ba891f9c31f58958a.jpg)"
+    ],
+    "answer": "B",
+    "solution": "【分析】先读出每个钟表上的时间，再找出时间是在7:00以后,11:30之前的时间，就是王叔叔可能在图书馆的时间.\n【详解】A。此时是6:15，这时间是在7:00之前，不符合题意;B。此时是9:40，这时间是在7:00以后,11:30之前，符合题意;C。此时是1:55，这时间是在7:00之前，不符合题意;即，周六的上午，王叔叔打算7:00开始晨练，然后去图书馆看书,11:30回家吃饭。他可能在9:40去图书馆。故答案为:B",
+    "knowledge_points": [
+      "一般时间与钟面指针的位置"
+    ],
+    "source": "23-24 二年级上·湖南长沙·期末"
+  },
+  {
+    "id": "348",
+    "unit": "第七单元 认识时间",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "根据对话，他们踢球的时间可能是( ).\n\n![](images/2026-03-02%20150246.jpg)",
+    "options": [
+      "A. ![](images/d7ed3b6e9233b39b0decfa8cfa7e962bc45b9b82ceddaa776a5d1a6fc7771075.jpg)",
+      "B. ![](images/64a1cf0c72398747d902f802262a8739abe53b8c044fa9d52778537187f2390b.jpg)",
+      "C. ![](images/d2957305ec15a1560a34839d129afa4bb98bc024b4bb89db813272d766549079.jpg)"
+    ],
+    "answer": "C",
+    "solution": "【分析】根据题中他们是要先去图书馆然后再去踢球，最后去少年宫，而他们的时间安排是从2:20开始,5:30要去少年宫，可以断定出去踢球的时间在2:20和5:30之间，然后依次分析出每个钟表代表的时间即可.\n【详解】由分析可得，他们去踢球的时间在2:20和5:30之间，观察下面的钟表，选出时间合适的时间即可。A。时针走过2，分针从12起走了15小格，就是2时15分，时间点不在2:20和5:30之间;B。时针走过5，分针从12起走了40个小格，就是5时40分，时间点不在2:20和5:30之间;C。时针走过3，分针从12起走了20个小格，就是3时20分，时间点在2:20和5:30之间。故答案为:C",
+    "knowledge_points": [
+      "一般时间与钟面指针的位置"
+    ],
+    "source": "23-24 二年级上·宁夏固原·期末"
+  },
+  {
+    "id": "349",
+    "unit": "第七单元 认识时间",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "时针走过数字2，分针从12起走了15个小格是( )。",
+    "options": [
+      "A. 2:15",
+      "B. 12:15",
+      "C. 3:15"
+    ],
+    "answer": "A",
+    "solution": "【分析】钟面上长针是分针，短针是时针，分针走1小格是1分钟，分针走1大格是5分钟，时针走1大格是1小时.\n【详解】由分析可得：时针走过数字2，分针从12起走了15个小格是2:15。故答案为:A",
+    "knowledge_points": [
+      "一般时间与钟面指针的位置"
+    ],
+    "source": "23-24 二年级上·河北廊坊·期末"
+  },
+  {
+    "id": "350",
+    "unit": "第七单元 认识时间",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "时针从\"3\"走到\"6\"，走了( )时，分针从\"3\"走到\"6\"，走了( )分。",
+    "options": [],
+    "answer": "3;15",
+    "solution": "【分析】钟面上有12个大格，时针走1大格是1时，分针走1大格是5分。由此根据从\"3\"走到\"6\"经过的格数确定走的小时数或分数即可.\n【详解】从\"3\"走到\"6\"，经过了6-3=3(格),分针:5×3=15(分);时针:1×3=3(时)。时针从\"3\"走到\"6\"，走了3时，分针从\"3\"走到\"6\"，走了15分。",
+    "knowledge_points": [
+      "时，分，秒有关的计算"
+    ],
+    "source": "23-24 二年级上·浙江嘉兴·期末"
+  },
+  {
+    "id": "351",
+    "unit": "第七单元 认识时间",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "在括号填上合适的单位名称.\n\n一本数学书厚约1( );长颈鹿高约3( )\n小学生每天在校时间是6( );一节课的时间是40( )",
+    "options": [],
+    "answer": "厘米或cm;米或m;小时或h;分钟或min",
+    "solution": "【分析】根据实际生活经验以及题干中的具体数据来进行填空，长度单位从厘米和米中选择，时间单位从分钟和小时里选择，据此解答.\n【详解】填空如下：一本数学书厚约1厘米;长颈鹿高约3米;小学生每天在校时间是6小时;一节课的时间是40分钟。",
+    "knowledge_points": [
+      "时间单位的选择",
+      "长度单位的选择"
+    ],
+    "source": "23-24 二年级上·浙江杭州·期末"
+  },
+  {
+    "id": "352",
+    "unit": "第七单元 认识时间",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "如下图，钟面的时间是( ),时针和分针形成的角是( )角，再过15分钟，时针和分针形成的是( )角.\n\n![](images/14da0d06c47a9a9d4bdd07708eca64f6f215b04dcd21361d292389368e615602.jpg)",
+    "options": [],
+    "answer": "8时45分;锐;直",
+    "solution": "【分析】分针指向12，时针指向几就是几时。时针走一大格是1时;分针走1小格是1分，走1大格是5分;秒针走1小格是1秒，走1大格是5秒。时针刚过几就是几时，分针指向第多少个小格就是多少分。图中表示的是8时45分，再过15分是9时,9时时针指向9，分针指向12，时针和分针形成的是直角.\n【详解】8时45分+15分=9时，钟面的时间是8时45分，时针和分针形成的角是锐角，再过15分钟，时针和分针形成的是直角。",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征",
+      "整点时间与钟面指针的位置",
+      "一般时间与钟面指针的位置",
+      "时，分，秒时间的推算"
+    ],
+    "source": "23-24 二年级上·浙江温州·期末"
+  },
+  {
+    "id": "353",
+    "unit": "第七单元 认识时间",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "钟表上分针走1大格是( )分，分针走一圈就是( )分。时针走1大格是1时，当分针走一圈，时针刚好走1大格，是( )分。如图钟表显示的时间是( ):( ).\n\n![](images/94bbb56d3718217da7dbb4d25798e9186635bf41f68112a900b094e8ff309d72.jpg)",
+    "options": [],
+    "answer": "5;60;60;8;35",
+    "solution": "【分析】分针走一小格是1分，一大格里有5个小格，一圈是60个小格。分针走一圈是60分钟，时针跟着走一大格是1小时。分针指向7代表35分，时针在8和9之间是过了8时，据此解答.\n【详解】1大格里有5小格，是5分钟，一圈是60个小格，是60分钟。时针走1时是1大格，是60分。钟面上是8:35。",
+    "knowledge_points": [
+      "一般时间与钟面指针的位置",
+      "时，分的认识及换算"
+    ],
+    "source": "23-24 二年级上·河南焦作·期末"
+  },
+  {
+    "id": "354",
+    "unit": "第七单元 认识时间",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "猜一猜，小哲和小琪说的分别是( )时和( )时.\n\n![](images/2026-03-02%20150535.jpg)",
+    "options": [],
+    "answer": "12;6",
+    "solution": "【分析】分针指向12，时针指向几就是几时;当时针和分针重叠的时候应该是12时;当时针和分针在两端成一条直的线段时应该是6时.\n【详解】由分析可知：小哲和小琪说的分别是12时和6时。",
+    "knowledge_points": [
+      "整点时间与钟面指针的位置"
+    ],
+    "source": "23-24 二年级下·江苏·课后作业"
+  },
+  {
+    "id": "355",
+    "unit": "第七单元 认识时间",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "中央电视台晚上播放《新闻联播》通常用时( )分钟，再加上( )分钟是1小时。",
+    "options": [],
+    "answer": "30;30",
+    "solution": "【分析】新闻是述说重点，比较简洁，一般是30分钟。1小时=60分，用60分减去30分即可求出需要加的时间.\n【详解】1小时=60分,60分-30分=30分，中央电视台晚上播放《新闻联播》通常用时30分钟，再加上30分钟是1小时。",
+    "knowledge_points": [
+      "时，分的认识及换算",
+      "时，分，秒时间的推算"
+    ],
+    "source": "23-24 二年级下·江苏·课后作业"
+  },
+  {
+    "id": "356",
+    "unit": "第七单元 认识时间",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "朝阳小学在全国爱眼日当天举行了\"爱护眼睛，守住光明\"的主题活动。活动在当天上午10:00准时开始，这时钟面上的分针指向( ),12:40活动结束，这时钟面上的分针指向( )。",
+    "options": [],
+    "answer": "12;8",
+    "solution": "【分析】钟面上有12个大格，分针走1大格是5分钟，时针走1大格是1小时。整点时，分针指向12，时针指向几就是几时;10:00时，分针指向12，时针指向10;12:40时，分针指向几，即几个5是40，根据乘法口诀解答即可.\n【详解】根据乘法口诀五八四十可知,5×8=40(分钟)也就是走了8个大格。活动在当天上午10:00准时开始，这时钟面上的分针指向12,12:40活动结束，这时钟面上的分针指向8。",
+    "knowledge_points": [
+      "整点时间与钟面指针的位置",
+      "一般时间与钟面指针的位置"
+    ],
+    "source": "23-24 二年级上·湖南怀化·期末"
+  },
+  {
+    "id": "357",
+    "unit": "第七单元 认识时间",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "分针从2走到9，走了( )分。",
+    "options": [],
+    "answer": "35",
+    "solution": "【分析】钟面上有12个大格，分针走1大格是5分钟，时针走1大格是1小时。由此计算出走了几个大格，再用乘法计算出走了多少分即可.\n【详解】分针从2走到9，走了9-2=7(大格);5×7=35(分);分针从2走到9，走了35分。",
+    "knowledge_points": [
+      "7的乘法口诀及应用",
+      "时，分，秒有关的计算"
+    ],
+    "source": "23-24 二年级上·山东济宁·期末"
+  },
+  {
+    "id": "358",
+    "unit": "第七单元 认识时间",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "在括号里填上适当的单位名称。李老师的身高约1( )62( )。一节课的时间是40( )。",
+    "options": [],
+    "answer": "米或m;厘米或cm;分钟或min",
+    "solution": "【分析】根据生活经验，对长度单位，时间单位和数据大小的认识可知：测量较长的物体用米作单位，二年级学生双臂展开的长度大约是1米;量比较短的物体的长度，通常用厘米作单位，食指的宽大约是1厘米。所以身高写作1米62厘米比较合适;表示比较长的时间一般用时作单位，表示比较短的时间一般用分钟作单位。一节课的时间用分钟作单位比较合适.\n【详解】李老师的身高约1米62厘米。一节课的时间是40分钟。",
+    "knowledge_points": [
+      "时间单位的选择",
+      "长度单位的选择"
+    ],
+    "source": "23-24 二年级上·福建厦门·期末"
+  },
+  {
+    "id": "359",
+    "unit": "第七单元 认识时间",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "在括号里填上合适的单位名称.\n\n爸爸的身高是1( )80( );一辆汽车1( )大约行驶60千米;课间休息时间是10( )。",
+    "options": [],
+    "answer": "米或m;厘米或cm;小时或时或h;分钟或分或min",
+    "solution": "【分析】一般情况下，大家的大拇指的指甲长度就是1厘米左右。1米大约有成年人正常脚步两步长。汽车每小时跑的路程是按千米计的。课间休息时间用来上厕所，喝水等，一般10分钟左右.\n【详解】爸爸的身高是1米80厘米;一辆汽车1小时大约行驶60千米;课间休息时间是10分钟。",
+    "knowledge_points": [
+      "时间单位的选择",
+      "长度单位的选择"
+    ],
+    "source": "23-24 二年级上·广东东莞·期末"
+  },
+  {
+    "id": "360",
+    "unit": "第七单元 认识时间",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "1个人吃1个苹果要用3分钟，照这样,5个人吃5个苹果需要( )分钟。",
+    "options": [],
+    "answer": "3",
+    "solution": "【分析】5个人吃5个苹果，可以同时吃，所以还是吃3分钟.\n【详解】1个人吃1个苹果要用3分钟，照这样,5个人吃5个苹果需要3分钟。",
+    "knowledge_points": [
+      "时，分的认识及换算"
+    ],
+    "source": "23-24 二年级上·贵州铜仁·期末"
+  },
+  {
+    "id": "361",
+    "unit": "第七单元 认识时间",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "![](images/22702aa9ae8d281f13c392c119e3ec169307615169e04f28de1af49fe9b0b488.jpg)钟面上的时间是( ),过半小时是( )。钟面上的时间是( ),过一刻是( )。",
+    "options": [],
+    "answer": "3时15分或3:15;3时45分或3:45;4时45分或4:45;5时或5:00",
+    "solution": "【分析】钟面上有12个大格。分针走1大格是5分钟，时针走1大格是1小时。第1个钟面上分针指向3，时针指向3和4之间，是3时15分。半小时是30分，过半小时的时间用现在的时间+30分计算;第2个钟面上分针指向9，时针接近5，是4时45分，一刻是15分，再过一刻用现在的时间+15分计算.\n【详解】3时15分+30分=3时45分,4时45分+15分=5时，钟面上的时间是3时15分，过半小时是3时45分。钟面上的时间是4时45分，过一刻是5时。",
+    "knowledge_points": [
+      "一般时间与钟面指针的位置",
+      "时，分，秒时间的推算"
+    ],
+    "source": "23-24 二年级上·四川南充·期末"
+  },
+  {
+    "id": "362",
+    "unit": "第七单元 认识时间",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "分针从12走到5，走了( )分，分针从3走到8，走了( )分。时针从12走到6，走了( )时.\n\n![](images/65f01f6ab2548c173ea3f32c619b1f2a2e7be19b3f4c6b3a013bc6355245030a.jpg)",
+    "options": [],
+    "answer": "25;25;6",
+    "solution": "【分析】分针走一大格是5分钟，数一数走了几个大格再乘5就是多少分钟。时针走一大格是1小时，走几个大格就是几小时。本题考查了分钟和小时的运算问题.\n【详解】分针从12到5，走了5个大格，分针从3到8走了5个大格，时针从12到6走了6个大格。5×5=25(分),5×5=25(分),1×6=6(小时),故填空为：分针从12走到5，走了25分，分针从3走到8，走了25分。时针从12走到6，走了6时。",
+    "knowledge_points": [
+      "时，分，秒有关的计算"
+    ],
+    "source": "23-24 二年级上·四川南充·期末"
+  },
+  {
+    "id": "363",
+    "unit": "第七单元 认识时间",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "钟面上9:30的时候，时针与分针形成的角是( )角,9:55的时候，时针与分针形成的角是( )角。",
+    "options": [],
+    "answer": "钝;锐",
+    "solution": "【分析】先判断钟面上某一时刻时针和分针指向的位置，然后判断是什么角。用三角板的直角进行比较测量，比直角小的就是锐角，比直角大的就是钝角.\n【详解】钟面上9:30的时候，时针在9与10之间，分针指向6，时针与分针形成的角是钝角;9:55的时候，时针在9与10之间，分针指向11，时针与分针形成的角是锐角。",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征",
+      "半点时间与钟面指针的位置",
+      "一般时间与钟面指针的位置"
+    ],
+    "source": "23-24 二年级上·浙江·期末"
+  },
+  {
+    "id": "364",
+    "unit": "第七单元 认识时间",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "时针指向8和9之间，分针指向7后边3个格，现在时间是( )。",
+    "options": [],
+    "answer": "8:38或8时38分",
+    "solution": "【分析】时针指向8和9之间，是8时;分针指向7后边3个格，用7乘5再加3就是分钟数.\n【详解】7×5+3=35+3=38(分),现在时间是8:38。",
+    "knowledge_points": [
+      "一般时间与钟面指针的位置",
+      "表内乘加，乘减"
+    ],
+    "source": "23-24 二年级上·山东济宁·期末"
+  },
+  {
+    "id": "365",
+    "unit": "第七单元 认识时间",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "分针从\"12\"走到\"5\"，走了( )分钟;时针从\"4\"走到\"9\"，走了( )小时。",
+    "options": [],
+    "answer": "25;5",
+    "solution": "【分析】时针走一大格是1时;分针走1小格是1分，走1大格是5分;秒针走1小格是1秒，走1大格是5秒。分针从\"12\"走到\"5\"，走了5大格;时针从\"4\"走到\"9\"，走了5大格.\n【详解】分针从\"12\"走到\"5\"，走了25分钟;时针从\"4\"走到\"9\"，走了5小时。",
+    "knowledge_points": [
+      "时，分的认识及换算"
+    ],
+    "source": "23-24 二年级上·河南南阳·期末"
+  },
+  {
+    "id": "366",
+    "unit": "第七单元 认识时间",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "时针从数字\"3\"到数字\"8\"走了( ),分针从数字\"2\"到数字\"9\"走了( )。",
+    "options": [],
+    "answer": "5小时或5h;35分钟或35min",
+    "solution": "【分析】钟面上有12个大格。分针走1大格是5分钟，时针走1大格是1小时。由此计算.\n【详解】时针从数字\"3\"到数字\"8\"走了8-3=5(大格);5×1=5(小时);分针从数字\"2\"到数字\"9\"走了9-2=7(大格);7×5=35(分钟)。时针从数字\"3\"到数字\"8\"走了5小时，分针从数字\"2\"到数字\"9\"走了35分钟。",
+    "knowledge_points": [
+      "时，分，秒有关的计算"
+    ],
+    "source": "23-24 二年级上·湖南株洲·期末"
+  },
+  {
+    "id": "367",
+    "unit": "第七单元 认识时间",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "时针从\"6\"走到\"9\"，经过了( )小时，分针从\"6\"走到\"9\"，经过了( )分钟。分针走一大格是( )分。",
+    "options": [],
+    "answer": "3;15;5",
+    "solution": "【分析】钟面上共12个大格。分针走1大格是5分钟，时针走1大格是1小时。从\"6\"走到\"9\"，走了9-6=3(大格),由此解答.\n【详解】时针:3×1=3(小时);分针:3×5=15(分钟)。时针从\"6\"走到\"9\"，经过了3小时，分针从\"6\"走到\"9\"，经过了15分钟。分针走一大格是5分。",
+    "knowledge_points": [
+      "时，分，秒有关的计算"
+    ],
+    "source": "23-24 二年级上·浙江台州·期末"
+  },
+  {
+    "id": "368",
+    "unit": "第七单元 认识时间",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "时针从2走到7，走了( )时。分针从2走到7，走了( )分。",
+    "options": [],
+    "answer": "5;25",
+    "solution": "【分析】时针走1个数字(1大格)是1时，从2走到7，走了7-2=5(大格),是5时;分针走1个数字(1大格)是5分，从2走到7，走了7-2=5(大格),是5个5分，即25分.\n【详解】时针从2走到7,7-2=5(大格),5×1=5(时);分针从2走到7,7-2=5(大格),5×5=25(分)。时针从2走到7，走了5时。分针从2走到7，走了25分。",
+    "knowledge_points": [
+      "5的乘法口诀及应用",
+      "时，分，秒有关的计算"
+    ],
+    "source": "23-24 二年级上·浙江嘉兴·期末"
+  },
+  {
+    "id": "369",
+    "unit": "第七单元 认识时间",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "分针从2走到4走了( )分，时针从2走到4走了( )小时。",
+    "options": [],
+    "answer": "10;2",
+    "solution": "【分析】时针走一大格是1时;分针走1小格是1分，走1大格是5分;秒针走1小格是1秒，走1大格是5秒.\n【详解】4-2=2(大格),2×5=10(分),分针从2走到4走了10分，时针从2走到4走了2小时。",
+    "knowledge_points": [
+      "时，分的认识及换算"
+    ],
+    "source": "23-24 二年级上·贵州铜仁·期末"
+  },
+  {
+    "id": "370",
+    "unit": "第七单元 认识时间",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "现在是10时40分，过一刻是( ),过半小时是( )。",
+    "options": [],
+    "answer": "10时55分或10:55;11时10分或11:10",
+    "solution": "【分析】一刻是15分,10时40分过15分钟是10时55分，半小时是30分,10时40分过30分是10时70分，满60分是1时，即10时40分过30分是11时10分，据此得出结论即可.\n【详解】10时40分+15分=10时55分,10时40分+30分=10时70分=11时10分，故现在是10时40分，过一刻是10时55分或10:55，过半小时是11时10分或11:10。",
+    "knowledge_points": [
+      "时，分，秒时间的推算"
+    ],
+    "source": "23-24 二年级上·河南南阳·期末"
+  },
+  {
+    "id": "371",
+    "unit": "第七单元 认识时间",
+    "question_type": "填空题",
+    "difficulty": 0.94,
+    "question": "在( )里填上合适的单位.\n\n星期六早上，小明从长2( )的床上起来，拿起长15( )的牙刷刷牙，吃早餐用了15( ),写作业用了1( )。",
+    "options": [],
+    "answer": "米或m;厘米或cm;分或min或分钟;时或小时或h",
+    "solution": "【分析】床比成年人长一点，一般是2米左右;牙刷比手掌长一点，一般就十多厘米;吃早餐较快，十几分钟即可;写作业一般是1小时左右.\n【详解】星期六早上，小明从长2米的床上起来，拿起长15厘米的牙刷刷牙，吃早餐用了15分钟，写作业用了1小时。",
+    "knowledge_points": [
+      "时间单位的选择",
+      "长度单位的选择"
+    ],
+    "source": "23-24 二年级上·湖南株洲·期末"
+  },
+  {
+    "id": "372",
+    "unit": "第七单元 认识时间",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "分针走一圈是( )分;时针从\"3\"走到\"8\"，走了( )小时。",
+    "options": [],
+    "answer": "60;5",
+    "solution": "【分析】钟面上共12个大格，分针走1大格是5分钟，时针走1大格是1小时。分针走1圈是1小时，也就是60分钟.\n【详解】8-3=5(小时),分针走一圈是60分;时针从\"3\"走到\"8\"，走了5小时。",
+    "knowledge_points": [
+      "时，分的认识及换算"
+    ],
+    "source": "23-24 二年级上·广东江门·期末"
+  },
+  {
+    "id": "373",
+    "unit": "第七单元 认识时间",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "在钟表上，分针从12走到5，走了( )分钟;时针从12开始绕了一圈又回到12，走了( )小时。",
+    "options": [],
+    "answer": "25;12",
+    "solution": "【分析】分针走1大格是5分钟，时针走1大格是1小时。先找出分针和时针各走了几大格，然后用乘法算出各走过的时间.\n【详解】分针从12走到5，走了5大格;5×5=25(分钟),时针从12开始绕了一圈又回到12，走了12大格;1×12=12(小时),故，在钟表上，分针从12走到5，走了25分钟;时针从12开始绕了一圈又回到12，走了12小时。",
+    "knowledge_points": [
+      "时，分的认识及换算",
+      "时，分，秒有关的计算"
+    ],
+    "source": "23-24 二年级上·山东济宁·期末"
+  },
+  {
+    "id": "374",
+    "unit": "第七单元 认识时间",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "钟面上分针走1小格是( )分，走1大格是( )分。时针走1大格是( )时.\n\n![](images/31aaca7466dc544ee8805788a272c68c303fc58da8212b32136635bc4db2af82.jpg)",
+    "options": [],
+    "answer": "1;5;1",
+    "solution": "【分析】钟面上有12大格,1个大格里面有5个小格，一共有60个小格，分针走1小格表示1分钟，走1大格是5分钟。时针走1大格是1小时。据此解答即可.\n【详解】据分析可知：钟面上分针走1小格是1分，走1大格是5分。时针走1大格是1时。",
+    "knowledge_points": [
+      "时，分的认识及换算"
+    ],
+    "source": "23-24 二年级上·河北邯郸·期末"
+  },
+  {
+    "id": "375",
+    "unit": "第七单元 认识时间",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "下图钟面上的时间是( ),再过25分钟是( ).\n\n![](images/ad52c013f2cdb7b1f059f5b7ac6ee7d227055d959dac0afebaec64c813227fec.jpg)",
+    "options": [],
+    "answer": "2:20;2:45",
+    "solution": "【分析】时针走一大格是1时;分针走1小格是1分，走1大格是5分;秒针走1小格是1秒，走1大格是5秒。时针刚过几就是几时，分针指向第多少个小格就是多少分。钟面上表示的时间是2:20，加25分钟即可求出再过25分钟的时间.\n【详解】钟面上的时间是2:20.2:20+25分=2:45，再过25分钟是2:45。",
+    "knowledge_points": [
+      "一般时间与钟面指针的位置",
+      "时，分，秒时间的推算"
+    ],
+    "source": "23-24 二年级上·湖北黄石·期末"
+  },
+  {
+    "id": "376",
+    "unit": "第七单元 认识时间",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "钟面上，分针从6走到12，走了( )分;时针从3开始绕了一圈走到4，走了( )小时。",
+    "options": [],
+    "answer": "30;13",
+    "solution": "【分析】分针走1大格是5分钟;时针走1大格是1小时;先找出分针和时针分别走了几大格，再用乘法算出经过时间.\n【详解】12-6=6(大格),6×5=30(分),时针从3开始绕了一圈走到3，时针就是走12大格，再走到4，时针就是走13大格;13×1=13(小时),故，钟面上，分针从6走到12，走了30分;时针从3开始绕了一圈走到4，走了13小时。",
+    "knowledge_points": [
+      "时，分，秒有关的计算"
+    ],
+    "source": "23-24 二年级上·陕西安康·期末"
+  },
+  {
+    "id": "377",
+    "unit": "第七单元 认识时间",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "①![](images/f1794b31eae8082d1da7251aa27f77c607e306a22e4052abbceab88c39f1f626.jpg)过10分是( ).\n②![](images/fc7bba4866a6d578c097451641be3d15e3002135f320ed15ef18a66a0517babe.jpg)过一刻是( ).\n③![](images/1f3c337048b27b26522ac50c26db594547bdb9b40d8002efb5f0411663000ad9.jpg)过半小时是( )。",
+    "options": [],
+    "answer": "1时45分或1:45;8时或8:00;4时30分或4:30",
+    "solution": "【分析】时针指向1和2之间，表示1时多，分针指向7，表示35分，合起来就是1时35分;时针指向7和8之间，表示7时多，分针指向9，表示45分，合起来就是7时45分;时针指向4，分针指向12，表示4时;结束时间=开始时间+经过时间;半小时就是30分;一刻就是15分.\n【详解】由题意分析得:1时35分+10分=1时45分,7时45分+15分=8时,4时+30分=4时30分。故,①过10分是1时45分。②过一刻是8时。③过半小时是4时30分。",
+    "knowledge_points": [
+      "整点时间与钟面指针的位置",
+      "一般时间与钟面指针的位置",
+      "时，分，秒时间的推算"
+    ],
+    "source": "23-24 二年级上·青海果洛·期末"
+  },
+  {
+    "id": "378",
+    "unit": "第七单元 认识时间",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "下图钟面上时刻是( ),至少再过( )分钟，时针和分针形成的角是直角.\n\n![](images/3a0ef0e0468bce234e84587bc2f6a4eb21f9734ecd25ef4c74e2cffc158df699.jpg)",
+    "options": [],
+    "answer": "8:55或8时55分;5",
+    "solution": "【分析】时针指向8和9之间,8时多，分针指向11，表示55分，合起来就是8:55.9时时，时针指向9，分针指向12，时针和分针形成的角是直角。经过时间=结束时间-开始时间.\n【详解】由题意分析得:9:00-8:55=5(分钟),故，钟面上时刻是8:55，至少再过5分钟，时针和分针形成的角是直角。",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征",
+      "整点时间与钟面指针的位置",
+      "一般时间与钟面指针的位置",
+      "时，分，秒有关的计算"
+    ],
+    "source": "23-24 一年级上·四川乐山·期末"
+  },
+  {
+    "id": "379",
+    "unit": "第七单元 认识时间",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "分针从12走到5，经过了( )分;时针从12走到5，经过了( )时。",
+    "options": [],
+    "answer": "25;5",
+    "solution": "【分析】分针走1大格就是5分;时针走1大格就是1小时;先分别找出分针和时针分别走了多少大格，再用乘法求出经过时间即可.\n【详解】分针从12走到5，走了5大格;5×5=25(分),1×5=5(时),故，分针从12走到5，经过了25分;时针从12走到5，经过了5时。",
+    "knowledge_points": [
+      "时，分，秒有关的计算"
+    ],
+    "source": "23-24 一年级上·四川乐山·期末"
+  },
+  {
+    "id": "380",
+    "unit": "第七单元 认识时间",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "钟面上的时针从数字4走到数字5，走了( )分钟。",
+    "options": [],
+    "answer": "60",
+    "solution": "【分析】根据钟表与时间的认识，钟面被12个数平均分成12大格,1大格又分5小格，时针走1大格是1小时，分针走1大格是5分,1小时=60分钟，据此解答即可.\n【详解】钟面上的时针从数字4走到数字5，也就是走了1大格，走了1小时，也就是60分钟。",
+    "knowledge_points": [
+      "整点时间与钟面指针的位置",
+      "时，分的认识及换算"
+    ],
+    "source": "23-24 二年级上·江西吉安·期末"
+  },
+  {
+    "id": "381",
+    "unit": "第七单元 认识时间",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "( )米=300厘米 1时20分=( )分",
+    "options": [],
+    "answer": "3;80",
+    "solution": "【分析】长度单位根据1米=100厘米进行换算;时间单位根据1时=60分进行换算，由此解答.\n【详解】1米=100厘米,3米=300厘米;1时=60分,1时20分=60分+20分=80分。",
+    "knowledge_points": [
+      "时，分的认识及换算",
+      "厘米和米之间的进率与换算"
+    ],
+    "source": "23-24 二年级上·江西吉安·期末"
+  },
+  {
+    "id": "382",
+    "unit": "第七单元 认识时间",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "分针从12走到4，走了( )分;时针从12开始绕一圈又走回12，走了( )时。",
+    "options": [],
+    "answer": "20;12",
+    "solution": "【分析】先算出分针和时针分别走了几大格，再用乘法求出相应的经过时间。分针走1大格是5分钟;时针走1大格是1时.\n【详解】分针从12走到4，走了4大格;4×5=20(分),时针从12开始绕一圈又走回12，走了12大格;12×1=12(时),分针从12走到4，走了20分;时针从12开始绕一圈又走回12，走了12时。",
+    "knowledge_points": [
+      "时，分，秒有关的计算"
+    ],
+    "source": "23-24 二年级上·湖南岳阳·期末"
+  },
+  {
+    "id": "383",
+    "unit": "第七单元 认识时间",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "黑板的长大约是4( ),一节课的时间是40( ),故事书宽15( )。",
+    "options": [],
+    "answer": "米或m;分钟或min;厘米或cm",
+    "solution": "【分析】根据实际情况及给出的数据，选择合适的长度单位或时间单位即可。要表示较长的物体长度时，一般选择米做单位;要表示较短的物体长度时，一般选择厘米做单位。一节课的时间一般是40分钟.\n【详解】由题意分析得：黑板的长大约是4米，一节课的时间是40分钟，故事书宽15厘米。",
+    "knowledge_points": [
+      "时间单位的选择",
+      "长度单位的选择"
+    ],
+    "source": "23-24 二年级上·湖南岳阳·期末"
+  },
+  {
+    "id": "384",
+    "unit": "第七单元 认识时间",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "时针从\"1\"走到\"3\"，走过的时间是( )小时;分针从\"1\"走到\"3\"，走过的时间是( )分。",
+    "options": [],
+    "answer": "2;10",
+    "solution": "【分析】时针走1个大格是1小时，先计算出从\"1\"走到\"3\"走过了几个大格，也就是几小时;分针走1个大格是5分，先计算出从\"1\"走到\"3\"走过了几个大格，也就是5*几分，据此解答即可.\n【详解】3-1=2(个),3-1=2(个),5×2=10(分),时针从\"1\"走到\"3\"，走过了2个大格，走过的时间是2小时;分针从\"1\"走到\"3\"，走过了2个大格，走过的时间是10分。",
+    "knowledge_points": [
+      "时，分，秒有关的计算"
+    ],
+    "source": "23-24 二年级上·浙江温州·期末"
+  },
+  {
+    "id": "385",
+    "unit": "第七单元 认识时间",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "1时=( )分;180分=( )时;90分=( )时( )分",
+    "options": [],
+    "answer": "60;3;1;30",
+    "solution": "【分析】根据1时=60分进行换算;根据60分=1时,180分里有3个60分，即3时;根据60分=1时,90分可以分为60分和30分，所以90分=1时30分.\n【详解】1时=60分;180分=3时;90分=1时30分。",
+    "knowledge_points": [
+      "时，分的认识及换算"
+    ],
+    "source": "23-24 二年级上·山东日照·期末"
+  },
+  {
+    "id": "386",
+    "unit": "第七单元 认识时间",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "现在的时间是![](images/99a802923717bec5ce4ac8f35ff1be76b4cbee77289b63c68b4880234dce2f93.jpg),再过一刻的时间是5时。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】钟面上有12个大格，分针走1大格是5分钟，时针走1大格是1小时。图中分针指向9，时针接近5，是4时45分，一刻是15分。再过一刻的时间，用现在的时间+15分计算.\n\n![](images/aac47f42e914557194d72930284126a9f0d384126fb4e143310b75c0cc4aaa39.jpg)\n【详解】4时45分+15分=4时60分;60分=1时，则4时60分=5时。现在的时间再过一刻的时间是5时。原题说法正确。故答案为:√",
+    "knowledge_points": [
+      "一般时间与钟面指针的位置",
+      "时，分的认识及换算",
+      "时，分，秒时间的推算"
+    ],
+    "source": "23-24 二年级上·湖南怀化·期末"
+  },
+  {
+    "id": "387",
+    "unit": "第七单元 认识时间",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "钟面上的时针指在7和8之间，分针指向5，此时是7时5分。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】钟面上有12个大格，分针走1大格是5分钟，时针走1大格是1小时。时针在7和8之间，是7时，分针指向5，是5×5=25(分),此时是7时25分，由此解答.\n【详解】由分析可知，钟面上的时针指在7和8之间，分针指向5，此时是7时25分，原题说法错误。故答案为: ×",
+    "knowledge_points": [
+      "一般时间与钟面指针的位置"
+    ],
+    "source": "23-24 二年级上·湖南张家界·期末"
+  },
+  {
+    "id": "388",
+    "unit": "第七单元 认识时间",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "我从家到学校走了8小时。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】根据生活经验，对时间单位和数据大小的认识可知：表示比较长的时间一般用小时作单位;表示比较短的时间一般用分钟作单位。从家到学校走的时间一般比较短，用分钟作单位比较合适.\n【详解】由分析可知，我从家到学校走了8分钟。原题说法错误。故答案为: ×",
+    "knowledge_points": [
+      "时间单位的选择"
+    ],
+    "source": "23-24 二年级上·山东济南·期末"
+  },
+  {
+    "id": "389",
+    "unit": "第七单元 认识时间",
+    "question_type": "判断题",
+    "difficulty": 0.65,
+    "question": "6时整，钟面上时针和分针组成的角正好是直角。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】当一条直线和另一条横的直线交成的邻角彼此相等时，这些角的每一个被叫做直角。6时整，分针指向12，时针指向6，时针和分针在一条直线上，因此不是直角.\n【详解】由分析可知:6时整，钟面上时针和分针组成的角不是直角。原题说法错误。故答案为: ×",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征",
+      "整点时间与钟面指针的位置"
+    ],
+    "source": "23-24 二年级上·山东济南·期末"
+  },
+  {
+    "id": "390",
+    "unit": "第七单元 认识时间",
+    "question_type": "判断题",
+    "difficulty": 0.65,
+    "question": "时针走1大格，分针走60小格，所以1时=60分。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】分针走一圈，时针跟着走1大格，时针走1大格是小时，分针走一圈是1小时,1小格是1分钟，分针走一圈是60个小格，就是60分钟，据此解答.\n【详解】分针走一圈，走了60个小格也就是60分钟，时针走一大格，代表1小时，此说法正确。故答案为:√",
+    "knowledge_points": [
+      "时，分的认识及换算"
+    ],
+    "source": "23-24 二年级上·湖北武汉·期末"
+  },
+  {
+    "id": "391",
+    "unit": "第七单元 认识时间",
+    "question_type": "判断题",
+    "difficulty": 0.65,
+    "question": "分针从4走到10，走了35分。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】分针走1大格是5分钟，从4到10走了6个大格，用乘法计算即可.\n【详解】10-4=6,6×5=30(分钟),此说法错误。故答案为: ×",
+    "knowledge_points": [
+      "6的乘法口诀及应用",
+      "时，分，秒有关的计算"
+    ],
+    "source": "23-24 二年级上·湖北武汉·期末"
+  },
+  {
+    "id": "392",
+    "unit": "第七单元 认识时间",
+    "question_type": "判断题",
+    "difficulty": 0.94,
+    "question": "分针从12绕一圈走回到12，是1时。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】时针走一大格是1时;分针走1小格是1分，走1大格是5分，走一圈是60分，也就是1时.\n【详解】分针从12绕一圈走回到12，是1时。原题说法正确。故答案为:√",
+    "knowledge_points": [
+      "时，分的认识及换算"
+    ],
+    "source": "23-24 二年级上·广东东莞·期末"
+  },
+  {
+    "id": "393",
+    "unit": "第七单元 认识时间",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "分针走一圈，经过的时间是1小时。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】钟面上有12个大格。分针走1大格是5分钟，时针走1大格是1小时。分针走1圈是1小时，时针走1圈是12小时，由此解答.\n【详解】由分析可知，分针走一圈，经过的时间是1小时。原题说法正确。故答案为:√",
+    "knowledge_points": [
+      "时，分，秒有关的计算"
+    ],
+    "source": "23-24 二年级上·河南南阳·期末"
+  },
+  {
+    "id": "394",
+    "unit": "第七单元 认识时间",
+    "question_type": "判断题",
+    "difficulty": 0.65,
+    "question": "钟面上5时整，时针和分针成钝角。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】钟面上5时整，分针指向12，时针指向5，所成的角比直角大，是钝角.\n【详解】钟面上5时整，时针和分针成钝角。原题说法正确。故答案为:√",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征",
+      "整点时间与钟面指针的位置"
+    ],
+    "source": "19-20 四年级上·湖北孝感·期中"
+  },
+  {
+    "id": "395",
+    "unit": "第七单元 认识时间",
+    "question_type": "判断题",
+    "difficulty": 0.94,
+    "question": "时针走一大格是1小时，分针走一圈也是1小时。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】时针走一大格是1时;分针走1小格是1分，走1大格是5分，走一圈是1小时.\n【详解】时针走一大格是1小时，分针走一圈也是1小时。原题说法正确。故答案为:√",
+    "knowledge_points": [
+      "时，分的认识及换算"
+    ],
+    "source": "23-24 二年级上·河南南阳·期末"
+  },
+  {
+    "id": "396",
+    "unit": "第七单元 认识时间",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "欢欢唱一首儿歌用2秒。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】根据生活经验以及对时间单位和数据大小的认识，秒表示的时间极短，一般说几个字的时间就需要1秒;1分钟=60秒，所以分钟表示的时间比较长。从日常生活经验可知：一首儿歌的时间一般是2分钟.\n【详解】据分析可知：欢欢唱一首儿歌用2分钟。原题说法不正确。故答案为: ×",
+    "knowledge_points": [
+      "时，分的认识及换算",
+      "秒的认识"
+    ],
+    "source": "23-24 二年级上·河北邯郸·期末"
+  },
+  {
+    "id": "397",
+    "unit": "第七单元 认识时间",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "![](images/e6f8fe1b900e34caeb5a16d699f1719d507981d951e4efaf09c2028750c5ee75.jpg)这个钟面上的时刻是7时30分。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】时针指向7和8之间，表示7时多，分针指向6，表示30分，合起来就是7时30分.\n【详解】由题意分析得：这个钟面上的时刻是7时30分，此说法正确。故答案为:√",
+    "knowledge_points": [
+      "半点时间与钟面指针的位置"
+    ],
+    "source": "23-24 二年级上·甘肃天水·期末"
+  },
+  {
+    "id": "398",
+    "unit": "第七单元 认识时间",
+    "question_type": "判断题",
+    "difficulty": 0.65,
+    "question": "分针走一个小格与时针走一个小格的时间是一样的。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】钟面上有12个数字,12个大格，时针走一小格是12分，分针每走一个小格是1分钟，秒针每走一个小格是1秒.\n【详解】分针走一个小格是1分钟，时针走一个小格是12分，所以时间不一样。原题说法错误。故答案为: ×",
+    "knowledge_points": [
+      "时，分的认识及换算",
+      "秒的认识"
+    ],
+    "source": "23-24 二年级上·陕西延安·期末"
+  },
+  {
+    "id": "399",
+    "unit": "第七单元 认识时间",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "时针从12走到3，走了3时。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】时针走1大格就是1小时，故，时针走几大格就是几小时.\n【详解】由题意分析得：时针从12走到3，走了3大格，所以时针走了3时;原题说法正确。故答案为:√",
+    "knowledge_points": [
+      "时，分，秒有关的计算"
+    ],
+    "source": "23-24 二年级上·青海果洛·期末"
+  },
+  {
+    "id": "400",
+    "unit": "第七单元 认识时间",
+    "question_type": "计算题",
+    "difficulty": 0.85,
+    "question": "直接写出得数.\n\n9×8=( );7×6=( );26+48=( );42-17=( );8×9-8=( );7×6+28=( );51-20+64=( );68=( )-8;43+17=( )-12;45分+一刻=( )时",
+    "options": [],
+    "answer": "72;42;74;25;64;70;95;76;72;1",
+    "solution": "【分析】本题包含乘法口诀，两位数加减法，加减混合运算，乘减乘加，求未知数以及时间单位的换算。计算时，乘法直接应用口诀;加减法要注意进位和退位;乘减乘加要先算乘法再算加减法;加减混合运算按从左到右的顺序计算;求未知数可以利用加减法各部分之间的关系;时间单位换算要明确1时=60分,1刻=15分.\n【详解】9×8=72(口诀\"八九七十二\");7×6=42(口诀\"六七四十二\");26+48=74(个位6+8=14，向十位进1，十位2+4+1=7，得74);42-17=25(个位2减7不够，向十位借1,12-7=5，十位4借1剩3,3-1=2，得25);8×9-8=72-8=64(先算乘法8×9=72，再算减法72-8=64);7×6+28=42+28=70(先算乘法7×6=42，再算加法42+28=70);51-20+64=31+64=95(先算51-20=31，再算31+64=95);求68=( )-8，即被减数=差+减数,68+8=76，所以括号里填76;求43+17=( )-12，左边43+17=60，即60=( )-12，所以被减数=60+12=72，括号里填72;45分+一刻=45分+15分=60分=1时。",
+    "knowledge_points": [
+      "两位数与两位数的进位加法",
+      "100以内数的加减混合运算",
+      "时，分的认识及换算",
+      "表内乘加，乘减"
+    ],
+    "source": "23-24 二年级上·福建厦门·期末"
+  },
+  {
+    "id": "401",
+    "unit": "第七单元 认识时间",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "7时5分也可以表示为( )。",
+    "options": [
+      "A. 7:5",
+      "B. 7:50",
+      "C. 7:05"
+    ],
+    "answer": "C",
+    "solution": "【分析】我们要分别对每个选项的答案进行分析，依次写出每个选项所表示的内容，据此来解答.\n【详解】A。书写不规范，不表示时间;B。表示的时间是7时50分;C。表示的时间是7时5分，与题目一致。故答案为:C",
+    "knowledge_points": [
+      "一般时间与钟面指针的位置"
+    ],
+    "source": "23-24 二年级上·湖北襄阳·期末"
+  },
+  {
+    "id": "402",
+    "unit": "第七单元 认识时间",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "一节课的时间是40( )。",
+    "options": [
+      "A. 米",
+      "B. 分钟",
+      "C. 元"
+    ],
+    "answer": "B",
+    "solution": "【分析】根据实际情况来选择时间单位即可。时间单位有：时(小时),分(分钟),秒。米是长度单位;元是人民币的单位.\n【详解】结合实际分析得：一节课的时间是40分钟。故答案为:B",
+    "knowledge_points": [
+      "时，分的认识及换算",
+      "时间单位的选择",
+      "元，角，分的认识及换算"
+    ],
+    "source": "18-19 二年级下·浙江·课后作业"
+  },
+  {
+    "id": "403",
+    "unit": "第七单元 认识时间",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "小青8:15开始练习小提琴，然后去放风筝。11:30要去奶奶家，那小青可能在什么时间去放风筝。( )",
+    "options": [
+      "A. ![](images/ef0c82aece7fb0f7e5d5249924da521c1ff54c0668c8993445ce16e258209e59.jpg)",
+      "B. ![](images/83ed4b03c06db64f0770a2129d67a2a3e4dacf0ccd79d8a36bcf6b6f82367987.jpg)",
+      "C. ![](images/bb3446c1323df25cbaf05a811ec01fcf66f09bbed65bacf86d5671ac258395bb.jpg)"
+    ],
+    "answer": "B",
+    "solution": "【分析】小青放风筝的时间是在8:15之后，且在11:30以前;据此解决此题.\n【详解】A。此时是8:10,8:10在8:15之前，不符合题意;B。此时是10:10,10:10在8:15之后，且在11:30以前，符合题意;C。此时是11:45,11:45在11:30之后，不符合题意。故，小青可能在10:10去放风筝。故答案为:B",
+    "knowledge_points": [
+      "一般时间与钟面指针的位置"
+    ],
+    "source": "23-24 二年级上·广东江门·期末"
+  },
+  {
+    "id": "404",
+    "unit": "第七单元 认识时间",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "小红和小丽上午9:30在超市相遇。小红对小丽说：\"我们下午3点去踢球吧.\"小丽说：\"行，但我要先去书店买书.\"小丽最有可能买书的时间是( )。",
+    "options": [
+      "A. 上午9:10",
+      "B. 中午12:50",
+      "C. 下午3:10"
+    ],
+    "answer": "B",
+    "solution": "【分析】由题可知：小丽买书的时间在9:30到下午3点之间即可.\n【详解】A。上午9:10在上午9:30之前，不可能;B。中午12:50在上午9:30到下午3点之间，可能;C。下午3:10在下午3点之后，不可能。小丽最有可能买书的时间是中午12:50。故答案为:B",
+    "knowledge_points": [
+      "时，分，秒时间的推算"
+    ],
+    "source": "19-20 二年级上·天津·期末"
+  },
+  {
+    "id": "405",
+    "unit": "第七单元 认识时间",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "周日，芳芳7:30开始吃早饭，然后和爸爸一起去海滨公园玩,11:30回家吃午饭，芳芳和爸爸可能在( )到达海滨公园门口准备游玩。",
+    "options": [
+      "A. 12:00",
+      "B. 9:00",
+      "C. 7:30"
+    ],
+    "answer": "B",
+    "solution": "【分析】结合题意可知，芳芳和爸爸一起去海滨公园玩的时间是在7:30之后,11:30之前;据此解决.\n【详解】由题意分析得:A。12:00在11:30之后，故，芳芳和爸爸不可能在12:00到达海滨公园门口准备游玩。B。9:00在7:30之后,11:30之前，故，芳芳和爸爸可能在9:00到达海滨公园门口准备游玩。C。7:30他们开始吃早饭，故，芳芳和爸爸不可能在7:30到达海滨公园门口准备游玩。故答案为:B",
+    "knowledge_points": [
+      "时，分，秒时间的推算"
+    ],
+    "source": "22-23 二年级上·山东临沂·期末"
+  },
+  {
+    "id": "406",
+    "unit": "第七单元 认识时间",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面哪个钟表所表示的时间是错误的。( )",
+    "options": [
+      "A. ![](images/c9ee96b982af29acc2268391d76c4ba99d55871855d7b720a2537c705a0301dc.jpg)",
+      "B. ![](images/58be3a15df54154904efc22dd9e1b7101b91fca293bceef6b8b708e983eee194.jpg)",
+      "C. ![](images/678969b6d4bda4773943eb894f61fb8d2f41dfac577f4e2f2932a5bb5deab775.jpg)"
+    ],
+    "answer": "A",
+    "solution": "【分析】根据钟表上时针和分针之间的关系判断是否正确。整点时，分针指向12;几时半时，分针指向6，时针指向两数的中间等.\n【详解】A。若要表示11:30，时针要指向11和12的中间;若要表示12:30，时针要指向12和1的中间;所以此钟表所表示的时间是错误的;B。此钟表所表示的时间是正确的;C。此钟表所表示的时间是正确的。故答案为:A",
+    "knowledge_points": [
+      "半点时间与钟面指针的位置",
+      "一般时间与钟面指针的位置"
+    ],
+    "source": "22-23 二年级上·云南昭通·期末"
+  },
+  {
+    "id": "407",
+    "unit": "第七单元 认识时间",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "时针从一个数字走到下一个数字时，分针正好走过的时长是( )。",
+    "options": [
+      "A. 5分",
+      "B. 1分",
+      "C. 60分"
+    ],
+    "answer": "C",
+    "solution": "【分析】时针从一个数字走到下一个数字时，时间过了一个小时，则分针也走过一个小时即60分，据此解答即可.\n【详解】由分析知：分针正好走过的时长是60分。故答案为:C",
+    "knowledge_points": [
+      "时，分的认识及换算"
+    ],
+    "source": "22-23 二年级上·浙江温州·期末"
+  },
+  {
+    "id": "408",
+    "unit": "第七单元 认识时间",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "星期六，妈妈7:30在家吃早餐，准备10:00逛商场，去商场之前要去超市买东西，妈妈去超市买东西最合理的时间是( )。",
+    "options": [
+      "A. 7:35",
+      "B. 8:20",
+      "C. 10:10"
+    ],
+    "answer": "B",
+    "solution": "【分析】根据题意,7:30吃早餐，吃早餐时需要一定的时间,10:00要去商场，在去商场之前要去超市，说明去超市的时间要在吃完早餐到10:00之间，选择合理的即可.\n【详解】A。7:35，距离吃早餐的时间较短,5分钟的时间吃早餐不合理;B。8:20，这段时间足够吃早餐，也在去商场的时间之前，符合题意;C。10:10，比去商场的时间要晚，不符合题意。妈妈去超市买东西最合理的时间是8:20。故答案为:B",
+    "knowledge_points": [
+      "时，分，秒时间的推算"
+    ],
+    "source": "22-23 二年级上·贵州铜仁·期末"
+  },
+  {
+    "id": "409",
+    "unit": "第七单元 认识时间",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面可以用来计量物体长度的单位是( )。",
+    "options": [
+      "A. 米",
+      "B. 分",
+      "C. 时"
+    ],
+    "answer": "A",
+    "solution": "【分析】米和厘米是长度单位，可以用来计量物体长度。时和分是时间单位，可以用来计量时间的多少.\n【详解】由题意分析得：可以用来计量物体长度的单位是米。故答案为:A",
+    "knowledge_points": [
+      "时，分的认识及换算",
+      "厘米的认识",
+      "米的认识",
+      "长度单位的选择"
+    ],
+    "source": "22-23 二年级上·福建三明·期末"
+  },
+  {
+    "id": "410",
+    "unit": "第七单元 认识时间",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "50米赛跑，明明跑了15秒，红红跑了14秒，军军跑了13秒,( )最快。",
+    "options": [
+      "A. 明明",
+      "B. 红红",
+      "C. 军军"
+    ],
+    "answer": "C",
+    "solution": "【分析】根据经验可知：时间短的，则跑的最快，然后根据20以内数比较大小，找到数字最小的即可.\n【详解】15>14>13，则军军跑的最快。故答案为:C",
+    "knowledge_points": [
+      "时间快慢的比较"
+    ],
+    "source": "22-23 二年级上·四川乐山·期末"
+  },
+  {
+    "id": "411",
+    "unit": "第七单元 认识时间",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "分针从1走到5，走了( )分。",
+    "options": [
+      "A. 4",
+      "B. 5",
+      "C. 20"
+    ],
+    "answer": "C",
+    "solution": "【分析】分针每走1大格就是5分钟，先算出分针走了几大格，再用乘法求出一共走了几分钟.\n【详解】5-1=4(大格),5×4=20(分),即，分针从1走到5，走了20分。故答案为:C",
+    "knowledge_points": [
+      "5以内数的减法",
+      "5的乘法口诀及应用",
+      "时，分，秒有关的计算"
+    ],
+    "source": "22-23 二年级上·山东临沂·期末"
+  },
+  {
+    "id": "412",
+    "unit": "第七单元 认识时间",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "![](images/993792190325814dd36fe4d07dac0dfe04a92377218c17717614ed407bb9e9cf.jpg),下面的时间中，小明一家一定在高铁上的是( )。",
+    "options": [
+      "A. ![](images/ed74ba8eb04ed14d450b6db2488716db959de5c284d3b6dbf2fd763f8193dde9.jpg)",
+      "B. ![](images/5c14fd8728a26dc75e736b9183eb3eade476212bf66e7c5d93a7d415a0490dc1.jpg)",
+      "C. ![](images/20b2baf4665fd3070737117091a8ba357f776276331c338c291d0e5c50a8701b.jpg)"
+    ],
+    "answer": "C",
+    "solution": "【分析】从题干可知：小明家12:15在吃饭，下午2:30就能到达上海，所以小明家在高铁上的时间是12:15之后,2:30之前，据此解答即可.\n【详解】A。钟面上所显示的时刻是10:45，不符合题意。B。钟面所显示的时刻是2:40，不符合题意。C。钟面所显示的时刻是1:30，符合题意。故答案为:C",
+    "knowledge_points": [
+      "一般时间与钟面指针的位置"
+    ],
+    "source": "21-22 二年级上·浙江湖州·期末"
+  },
+  {
+    "id": "413",
+    "unit": "第七单元 认识时间",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "芳芳起床的时间是8:00，妈妈比她早起1个小时，妈妈( )起床。",
+    "options": [
+      "A. 7:00",
+      "B. 8:00",
+      "C. 9:00",
+      "D. 8:01"
+    ],
+    "answer": "A",
+    "solution": "【分析】妈妈的起床时间=芳芳的起床时间-1小时.\n【详解】由题意分析得:8-1=7(时),即，妈妈7:00起床。故答案为:A",
+    "knowledge_points": [
+      "时，分，秒时间的推算"
+    ],
+    "source": "21-22 一年级上·浙江·期末"
+  },
+  {
+    "id": "414",
+    "unit": "第七单元 认识时间",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "( )时整，钟面上的时针与分针所夹的角是直角。",
+    "options": [
+      "A. 3",
+      "B. 12",
+      "C. 6"
+    ],
+    "answer": "A",
+    "solution": "【分析】根据钟面上每两个大格之间是30度，据此回答。主要考查了角的认识及认识钟面，要熟练掌握.\n【详解】直角是90度,A。3,3点整时，从12到3走了3个大格也就是90度，是直角，故符合题意;B。12,12点整时，分针从12走一圈到12走了12个大格，也就是走了360度，故不符合题意;C。6,6点整时，从12到6走了6个大格也就是180度，故不符合题意。故答案为:A",
+    "knowledge_points": [
+      "角的初步认识及辨认",
+      "直角，钝角，锐角的认识及特征",
+      "整点时间与钟面指针的位置"
+    ],
+    "source": "21-22 二年级上·江西鹰潭·期末"
+  },
+  {
+    "id": "415",
+    "unit": "第七单元 认识时间",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下图是小明出发去图书馆的时间，到图书馆的时间可能是( ).\n\n![](images/a6fdc5618995ff3e117c007343559043fd44da199f550fe470b3d0cb0d4c1ca1.jpg)",
+    "options": [
+      "A. 10:00",
+      "B. 10:50",
+      "C. 10:30"
+    ],
+    "answer": "B",
+    "solution": "【分析】由题意可知，图中的钟面上，分针指向6，时针指向\"10\"和\"11\"之间，所以出发的时间是10:30，到图书馆可能还需要一段时间，有可能是10:50到的图书馆，据此解答即可。熟练掌握认识时间是解决此题的关键.\n【详解】由分析可得：小明出发去图书馆的时间是10:30，到图书馆的时间可能是10:50。故答案为:B",
+    "knowledge_points": [
+      "时，分，秒时间的推算"
+    ],
+    "source": "22-23 二年级上·全国·随堂练习"
+  },
+  {
+    "id": "416",
+    "unit": "第七单元 认识时间",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "晓晓跑步的时间可能是( ).\n\n![](images/4148b84672a36203a893978c75b80d5111c3b2bf13272d5ec5d7bcc917335bd2.jpg)",
+    "options": [
+      "A. ![](images/b7e6d935ab45ad929c1480e3bb717be7d2730a8695f776db3cb1ec7ce1d665d0.jpg)",
+      "B. ![](images/4c470e560f8b62b79e6b9308303890a86586275051b5488226eea7943a8ce424.jpg)",
+      "C. ![](images/5891065a9e77768d82f9b27ea84b0af792268e66da8d78f495a5807be2f3eced.jpg)"
+    ],
+    "answer": "C",
+    "solution": "【分析】由题意可知，题干中的钟面上分针指向12，时针指向3，所以他们画画的时间是3:00，画完画再去跑步，说明跑步的时间比3:00还要迟，据此解答即可。熟练掌握认识时间是解决此题的关键.\n【详解】A。钟面上的分针指向5，时针指向\"1\"和\"2\"之间，是1:25;B。钟面上的分针指向12，时针指向2，是2:00;C。钟面上的分针指向6，时针指向\"4\"和\"5\"之间，是4:30。因此晓晓跑步的时间可能是4:30。故答案为:C",
+    "knowledge_points": [
+      "时，分，秒时间的推算"
+    ],
+    "source": "22-23 二年级上·全国·随堂练习"
+  },
+  {
+    "id": "417",
+    "unit": "第七单元 认识时间",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面的事件中，最有可能在1分钟内完成的是( )。",
+    "options": [
+      "A. 上一节数学课",
+      "B. 跑1千米",
+      "C. 计算18道口算题"
+    ],
+    "answer": "C",
+    "solution": "【分析】根据对1分钟时间实际有多长的认识，结合生活实际即可进行选择，即可解题。此题考查根据情景选择合适的计量单位，要注意联系生活实际，计量单位和数据的大小，灵活地选择.\n【详解】A。上一节数学课大约是40分钟，不符合题意;B。跑一千米需要约5分钟，不符合题意;C。计算18道口算题大约1分钟，符合题意。故答案为:C",
+    "knowledge_points": [
+      "时，分的认识及换算"
+    ],
+    "source": "22-23 三年级上·吉林·期末"
+  },
+  {
+    "id": "418",
+    "unit": "第七单元 认识时间",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "周六，小明7:30开始吃早餐，然后和爸爸一起去公园玩,11:30要回家吃午饭。小明和爸爸可能在( )的时候到公园门口准备游玩。",
+    "options": [
+      "A. 7:30",
+      "B. 8:30",
+      "C. 11:35"
+    ],
+    "answer": "B",
+    "solution": "【分析】由题意可知，周六，小明7:30开始吃早餐，然后和爸爸一起去公园玩,11:30要回家吃午饭，问题是小明和爸爸可能在什么时候到公园门口准备游玩，那么游玩的时间只要在7:30与11:30之间，就是符合题意的，通过观察，只有8:30在这两个时间点之间，据此解答即可。熟练掌握时间的推算是解决此题的关键.\n【详解】由分析可得：周六，小明7:30开始吃早餐，然后和爸爸一起去公园玩,11:30要回家吃午饭。小明和爸爸可能在(8:30)的时候到公园门口准备游玩。故答案为:B",
+    "knowledge_points": [
+      "时，分，秒时间的推算"
+    ],
+    "source": "22-23 二年级上·湖北黄石·期末"
+  },
+  {
+    "id": "419",
+    "unit": "第七单元 认识时间",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "一集电视剧大约需35( )。",
+    "options": [
+      "A. 时",
+      "B. 分",
+      "C. 无法确定"
+    ],
+    "answer": "B",
+    "solution": "【分析】根据所给数据和生活常识，计量一集电视剧的时间长短应该用\"分\"作单位。本题考查对时间单位的认识，要结合实际情况解题.\n【详解】由分析可知：一集电视剧大约需35分。故答案为:B",
+    "knowledge_points": [
+      "时，分的认识及换算",
+      "时间单位的选择"
+    ],
+    "source": "22-23 二年级上·河南南阳·期末"
+  },
+  {
+    "id": "420",
+    "unit": "第七单元 认识时间",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "下面读法错误的是( )。",
+    "options": [
+      "A. ![](images/f8dabc3f34f37ab1ab7541a84d99d8db2ce313a9abe3c12dbb6c6ec9cca2869f.jpg) 2时35分",
+      "B. ![](images/e0157dcf53519555a9b65dee139fcd02837097e905fef7d6cd33c741a4b74027.jpg) 9时50分",
+      "C. ![](images/4462893f458e3b90dc0c3060b7a621f40f56c9d3c8de351139697344f4eb7eb8.jpg) 6时差5分"
+    ],
+    "answer": "B",
+    "solution": "【分析】根据钟面上时针和分针的位置，即可得出钟面显示的时刻。本题考查学生对认识时钟的掌握和运用.\n【详解】A。时针指向2和3之间，分针指向7，此时在钟表上是2时35分，故本选项说法正确;B。时针指向8和9之间，分针指向10，此时在钟表上是8时50分，不是9时50分，故本选项说法错误;C。时针指向5和6之间，分针指向11，此时在钟表上是5时55分，故原题说法正确。故答案为:B",
+    "knowledge_points": [
+      "一般时间与钟面指针的位置"
+    ],
+    "source": "22-23 二年级上·全国·单元测试"
+  },
+  {
+    "id": "421",
+    "unit": "第七单元 认识时间",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "下面可以用来计量物体长度的单位是( )。",
+    "options": [
+      "A. 米",
+      "B. 角",
+      "C. 时"
+    ],
+    "answer": "A",
+    "solution": "【分析】米是计量物体长度的，角是计量货币的，时是用来计量时间的。熟练掌握对计量单位的认识是解题关键.\n【详解】题目中可以用来计量物体长度的单位是米。故答案为:A",
+    "knowledge_points": [
+      "长度单位的选择"
+    ],
+    "source": "20-21 二年级上·广东江门·期末"
+  },
+  {
+    "id": "422",
+    "unit": "第七单元 认识时间",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "玲玲和妈妈周日早上8:05出门去超市购物，去的路上用了10分钟，买东西用了40分钟，回来的路上又用了10分钟。她们到家的时刻是( )。",
+    "options": [
+      "A. 8:55",
+      "B. 8:65",
+      "C. 9:05",
+      "D. 9:15"
+    ],
+    "answer": "C",
+    "solution": "【分析】先计算一共花的时间，再用出门时间加一共花的时间即可求解。开始时间+经过时间=结束时间.\n【详解】10+40+10=60(分钟),8时5分+60分=9时5分，所以她们到家的时刻是9:05。故答案为:C",
+    "knowledge_points": [
+      "时，分，秒时间的推算"
+    ],
+    "source": "20-21 二年级上·天津红桥·期末"
+  },
+  {
+    "id": "423",
+    "unit": "第七单元 认识时间",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "星期天，小明9:00吃完早饭先做完作业,10:30再去打篮球，他做完作业的时间可能是( )。",
+    "options": [
+      "A. 8:30",
+      "B. 10:15",
+      "C. 11:00"
+    ],
+    "answer": "B",
+    "solution": "【分析】小明9:00吃完早饭先做完作业,10:30再去打篮球，他做完作业的时间在9:00后,10:30前，据此解答。本题考查时间的推算，让学生能够熟练掌握知识点.\n【详解】A。8:30在9:00前，不符题意;B。10:15在9:00后,10:30前，符合题意;C。11:00在10:30后，不符题意。故答案为:B",
+    "knowledge_points": [
+      "时，分，秒时间的推算"
+    ],
+    "source": "20-21 二年级上·四川乐山·期末"
+  },
+  {
+    "id": "424",
+    "unit": "第七单元 认识时间",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "![](images/c282e124d7905f064accccb6184c8dff040de01ab0a181bb63e9ca91ccf84399.jpg)过半小时是( )。",
+    "options": [
+      "A. 12:30",
+      "B. 3:30",
+      "C. 4:00"
+    ],
+    "answer": "B",
+    "solution": "【分析】钟面上的时间是3时，用3时加30分即可。熟练掌握时间的计算方法是解题关键.\n【详解】3时+30分=3时30分，所以过半小时是3:30。故答案为:B",
+    "knowledge_points": [
+      "时，分，秒时间的推算"
+    ],
+    "source": "21-22 二年级上·广西玉林·期末"
+  },
+  {
+    "id": "425",
+    "unit": "第七单元 认识时间",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "现在是6时30分，再过一刻钟是( )。",
+    "options": [
+      "A. 6时35分",
+      "B. 7时",
+      "C. 6时45分"
+    ],
+    "answer": "C",
+    "solution": "【分析】一刻是15分钟，用6时30分加15分钟即可。开始时间+经过时间=结束时间.\n【详解】6时30分+15分=6时45分，再过一刻钟是6时45分。故答案为:C",
+    "knowledge_points": [
+      "时，分，秒时间的推算"
+    ],
+    "source": "20-21 二年级上·江西赣州·期末"
+  },
+  {
+    "id": "426",
+    "unit": "第七单元 认识时间",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "小丽6:30起床，吃完早饭,7:25从家出发去学校，小丽可能在( )开始吃早饭。",
+    "options": [
+      "A. 7:00",
+      "B. 6:15",
+      "C. 8:35"
+    ],
+    "answer": "A",
+    "solution": "【分析】小丽6:30起床,7:25从家出发去学校，小丽吃早饭一定在6:30之后,7:25之前，可以用排除法排除，即可得出答案。解题关键要明确吃早饭一定在6:30之后,7:25之前.\n【详解】A。7:00在6:30之后,7:25之前。B。6:15在6:30之前。C。8:35在7:25之后。小丽6:30起床，吃完早饭后,7:25从家出发去学校，小丽可能在7:00开始吃早饭。故答案为:A",
+    "knowledge_points": [
+      "时，分，秒时间的推算"
+    ],
+    "source": "21-22 二年级上·浙江绍兴·期末"
+  },
+  {
+    "id": "427",
+    "unit": "第七单元 认识时间",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "2时55分也可以说是( )。",
+    "options": [
+      "A. 2时差5分",
+      "B. 3时差5分",
+      "C. 3时过5分"
+    ],
+    "answer": "B",
+    "solution": "【分析】2时55分，还不到3时，还差5分就是3时，据此解答即可。熟悉钟面的知识，是解答此题的关键.\n【详解】2时55分也可以说是3时差5分。故答案为:B",
+    "knowledge_points": [
+      "时，分，秒时间的推算"
+    ],
+    "source": "20-21 二年级下·重庆黔江·期末"
+  },
+  {
+    "id": "428",
+    "unit": "第七单元 认识时间",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "一节课40( )。",
+    "options": [
+      "A. 米",
+      "B. 分",
+      "C. 时"
+    ],
+    "answer": "B",
+    "solution": "【分析】根据生活经验，对时间单位和数据的大小，可知计量一节课的时间用\"分\"作单位。此题考查根据情景选择合适的计量单位，要注意联系生活实际，计量单位和数据的大小，灵活的选择.\n【详解】一节课40分。故答案为:B",
+    "knowledge_points": [
+      "时，分的认识及换算",
+      "时间单位的选择",
+      "米的认识"
+    ],
+    "source": "20-21 二年级下·江西赣州·期末"
+  },
+  {
+    "id": "429",
+    "unit": "第七单元 认识时间",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "分针走1大格是( )分。",
+    "options": [
+      "A. 1",
+      "B. 5",
+      "C. 60"
+    ],
+    "answer": "B",
+    "solution": "【分析】钟面上，一共有12个大格和60个小格，分针走大格，就代表5分，分针走一小格，表示1分，走一圈就是60分。根据钟面的知识，解答此题即可.\n【详解】由分析可知：分针走1大格是5分。故答案为:B",
+    "knowledge_points": [
+      "一般时间与钟面指针的位置",
+      "时，分的认识及换算"
+    ],
+    "source": "20-21 二年级下·福建南平·期末"
+  },
+  {
+    "id": "430",
+    "unit": "第七单元 认识时间",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "下面是选手参加50米游泳比赛成绩,( )游得最快.\n\n<table><tr><td>李强</td><td>王兵</td><td>张明明</td></tr><tr><td>34秒</td><td>32秒</td><td>35秒</td></tr></table>",
+    "options": [
+      "A. 李强",
+      "B. 王兵",
+      "C. 张明明"
+    ],
+    "answer": "B",
+    "solution": "【分析】游泳比赛中，用时最少的就是游得最快的，比较一下他们的时间即可求解。解答此题需要熟练掌握100以内数的大小关系.\n【详解】32<34<35，所以王兵游得最快。故答案为:B",
+    "knowledge_points": [
+      "100以内数的比大小",
+      "时间快慢的比较"
+    ],
+    "source": "21-22 二年级下·广东韶关·期末"
+  },
+  {
+    "id": "431",
+    "unit": "第七单元 认识时间",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "时针在5和6之间，分针指着5，是( )。",
+    "options": [
+      "A. 5:25",
+      "B. 5:50",
+      "C. 6:25"
+    ],
+    "answer": "A",
+    "solution": "【分析】时针在5和6之间，应该是5时，分针指着5，用5乘5即是它的分钟数。熟练掌握一般时间与钟面指针的位置关系是解题关键.\n【详解】5×5=25(分),所以是5时25分，即5:25。故答案为:A",
+    "knowledge_points": [
+      "一般时间与钟面指针的位置"
+    ],
+    "source": "20-21 二年级下·河南信阳·期末"
+  },
+  {
+    "id": "432",
+    "unit": "第七单元 认识时间",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "小佳7:30吃早餐，然后去图书城看书,9:50学钢琴。小佳在图书城看书的时间可能是( )。",
+    "options": [
+      "A. ![](images/51a860cc05f8a1ef35ec6c1aa325087cfabe0389a18453f1073012cca826353d.jpg)",
+      "B. ![](images/3ca26bd712f7e51a16046d0a2ac64f28cc8042177452bb753b2c47eeffdf4841.jpg)",
+      "C. ![](images/b98e3f82b647e16b844a41f2c2e09e1e0a233fbef26d3d2a538034239dc6970f.jpg)"
+    ],
+    "answer": "C",
+    "solution": "【分析】由题意可知，小佳在图书城看书的时刻在7:30至9:50之间，分别读出选项中三个钟面所显示的时刻，找出符合要求的答案即可。此题主要考查认识钟面指针及时间读法以及日期和时间的推算.\n【详解】A。钟面所显示的时刻是7:10，早于小佳吃饭的时间，不符合要求;B。钟面所显示的时刻是10:00，晚于9:50，这应该是小佳还在学钢琴的时间;C。钟面所显示的时刻是9:10，介于7:30至9:50之间，这应该是小佳在图书城看书的时间。故答案为:C",
+    "knowledge_points": [
+      "整点时间与钟面指针的位置",
+      "一般时间与钟面指针的位置",
+      "时，分，秒时间的推算"
+    ],
+    "source": "21-22 二年级上·湖北孝感·期末"
+  },
+  {
+    "id": "433",
+    "unit": "第七单元 认识时间",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "一刻钟前的时刻是( ).\n\n![](images/f3ae070849e3f642cfc28d780d09abd565bbdc15033b76d038a6feffb7a92547.jpg)",
+    "options": [
+      "A. 7:50",
+      "B. 8:20",
+      "C. 2:20"
+    ],
+    "answer": "A",
+    "solution": "【分析】一刻钟前的时刻，则开始时刻=结束时刻-经过的时间，一刻钟是15分钟，即8时5分-15分即可求解。本题主要考查经过的时间计算，同时要清楚一刻钟是15分钟.\n【详解】由分析可知:8时5分-15分=7时50分，即7时50分=7:50，所以一刻钟前的时刻是7:50。故答案为:A",
+    "knowledge_points": [
+      "一般时间与钟面指针的位置",
+      "时，分，秒有关的计算"
+    ],
+    "source": "21-22 二年级上·河北承德·期末"
+  },
+  {
+    "id": "434",
+    "unit": "第七单元 认识时间",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "![](images/59d3dad3bedb6fe1d19c2b84435f4c081f04773aa80e004b2016b510b985f908.jpg)钟面上的时间是( )。",
+    "options": [
+      "A. 5:55",
+      "B. 7:55",
+      "C. 6:55"
+    ],
+    "answer": "C",
+    "solution": "【分析】观察钟面，时针接近7，分针指向11，表示6时55分。结合选项，正确读出钟面时间即可.\n【详解】钟面上时针接近7，分针指向11，表示6时55分。故答案为:C",
+    "knowledge_points": [
+      "一般时间与钟面指针的位置",
+      "时，分，秒时间的推算"
+    ],
+    "source": "21-22 二年级上·山东菏泽·期末"
+  },
+  {
+    "id": "435",
+    "unit": "第七单元 认识时间",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "学校一节课的时间是( )。",
+    "options": [
+      "A. 4分钟",
+      "B. 40分钟",
+      "C. 4小时"
+    ],
+    "answer": "B",
+    "solution": "【分析】根据生活实际可知，学校一节课的时间小于1小时，也就是小于60分钟，再结合实际数据进行选择即可。此题考查的是对时间的估测，应熟练掌握对时间单位的认识.\n【详解】根据实际可知，学校一节课的时间是40分钟。故答案为:B",
+    "knowledge_points": [
+      "时间的估计"
+    ],
+    "source": "21-22 二年级上·山东菏泽·期末"
+  },
+  {
+    "id": "436",
+    "unit": "第七单元 认识时间",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "3时45分再过10分钟后是( )。",
+    "options": [
+      "A. 3时35分",
+      "B. 3时55分",
+      "C. 4时45分"
+    ],
+    "answer": "B",
+    "solution": "【分析】本题考查时间的推算。已知开始时间是3时45分，求再过10分钟后的时间，直接用开始时间加上经过的时间即可。计算时要注意满60分向时进1.\n【详解】3时45分+10分=3时55分。故答案为:B",
+    "knowledge_points": [
+      "时，分，秒时间的推算"
+    ],
+    "source": "20-21 二年级上·河南洛阳·期末"
+  },
+  {
+    "id": "437",
+    "unit": "第七单元 认识时间",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "时针从12走到3，走了( )时，分针从12走到3，走了( )分。",
+    "options": [],
+    "answer": "3;15",
+    "solution": "【分析】时针走一大格，就是1小时;分针走一大格，就是5分钟。先找出时针和分针各走了几大格，再用乘法求出走过的时间即可.\n【详解】时针从12走到3，走了3大格;1×3=3(时),分针从12走到3，走了3大格;5×3=15(分),故，时针从12走到3，走了3时，分针从12走到3，走了15分。",
+    "knowledge_points": [
+      "时，分，秒有关的计算"
+    ],
+    "source": "23-24 二年级上·新疆喀什·期末"
+  },
+  {
+    "id": "438",
+    "unit": "第七单元 认识时间",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "下图钟面上的时间是10时45分，再过( )分是11时.\n\n![](images/4b628b27daf7d540e56e0e38f1744ebc1e733897049283ef86523c48628efac5.jpg)",
+    "options": [],
+    "answer": "15",
+    "solution": "【分析】用结束时间减去开始时间即可得到经过时间，据此计算.\n【详解】11时-10时45分=15分钟，钟面上的时间是10时45分，再过15分是11时。",
+    "knowledge_points": [
+      "时，分，秒有关的计算"
+    ],
+    "source": "19-20 二年级上·天津·期末"
+  },
+  {
+    "id": "439",
+    "unit": "第七单元 认识时间",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "钟面上有( )大格，每个大格里有( )小格，一共有( )小格。",
+    "options": [],
+    "answer": "12;5;60",
+    "solution": "【分析】钟面上有12大格，每个大格里有5小格，据此求一共有多少小格.\n【详解】由实际分析得：钟面上有12大格，每个大格里有5小格，一共有60小格。如下图.\n\n![](images/62edb123fb1f77448adea43697e8fb4a88eeaa5241f3b0e30c12ac2ea87ca546.jpg)",
+    "knowledge_points": [
+      "时，分的认识及换算",
+      "秒的认识"
+    ],
+    "source": "23-24 二年级上·新疆乌鲁木齐·期末"
+  },
+  {
+    "id": "440",
+    "unit": "第七单元 认识时间",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "时针从12走到3，走了( )时。",
+    "options": [],
+    "answer": "3",
+    "solution": "【分析】钟面上长针是分针，短针是时针。时针走1大格是1小时，由此解答.\n【详解】时针从12走到3，走了3大格,3×1=3(时)走了3时。",
+    "knowledge_points": [
+      "3的乘法口诀及应用",
+      "时，分，秒有关的计算"
+    ],
+    "source": "23-24 二年级上·新疆乌鲁木齐·期末"
+  },
+  {
+    "id": "441",
+    "unit": "第七单元 认识时间",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "时针从12走到5是经过了( )时，分针从12走到7是经过了( )分。",
+    "options": [],
+    "answer": "5;35",
+    "solution": "【分析】时针走1大格表示走过1小时，分针走1大格表示走过5分钟。先找出时针和分针分别走了几大格，再用乘法求出结果即可.\n【详解】时针从12走到5，时针走了5大格,1×5=5(时);分针从12走到7，分针走了7大格,5×7=35(分)。故，时针从12走到5是经过了5时，分针从12走到7是经过了35分。",
+    "knowledge_points": [
+      "时，分，秒有关的计算"
+    ],
+    "source": "23-24 二年级上·广东汕头·期末"
+  },
+  {
+    "id": "442",
+    "unit": "第七单元 认识时间",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "时针从12走到6，走了( )时;分针从3走到10，走了( )分。钟面上3:00时时针和分针成( )角。",
+    "options": [],
+    "answer": "6;35;直",
+    "solution": "【分析】分针走一个大格是5分钟，秒针走一个大格是5秒，时针走一个大格是1小时，据此解答即可.\n【详解】时针从12走到6，走了6时;10-3=7(格),7×5=35(分),分针从3走到10，走了35分。钟面上3:00时时针和分针成直角。",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征",
+      "时，分，秒有关的计算"
+    ],
+    "source": "23-24 二年级上·黑龙江鸡西·期末"
+  },
+  {
+    "id": "443",
+    "unit": "第七单元 认识时间",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "钟面上，分针从2走到5，走了( )分;时针从2走到5，走了( )时。",
+    "options": [],
+    "answer": "15;3",
+    "solution": "【分析】钟面上短针是时针，长针是分针。分针走1大格是5分钟。时针走1大格是1小时，由此解答.\n【详解】从2走到5，走了3格，即5×3=15(分);1×3=3(时)。钟面上，分针从2走到5，走了15分;时针从2走到5，走了3时。",
+    "knowledge_points": [
+      "5的乘法口诀及应用",
+      "3的乘法口诀及应用",
+      "时，分，秒有关的计算"
+    ],
+    "source": "22-23 二年级上·广东佛山·期末"
+  },
+  {
+    "id": "444",
+    "unit": "第七单元 认识时间",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "分针从1走到5，走了( )分;时针从1走到5，走了( )时。",
+    "options": [],
+    "answer": "20;4",
+    "solution": "【分析】分针每走1大格，就是5分;时针每走1大格，就是1小时;先分别求出分针和时针走了几大格，再用乘法求出相应的经过时间.\n【详解】5-1=4(大格),5×4=20(分),1×4=4(时),故，分针从1走到5，走了20分;时针从1走到5，走了4时。",
+    "knowledge_points": [
+      "时，分，秒有关的计算"
+    ],
+    "source": "22-23 二年级上·山东临沂·期末"
+  },
+  {
+    "id": "445",
+    "unit": "第七单元 认识时间",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "钟面上，时针从12走到8经过了( )小时，分针从12走到8经过了( )分钟。",
+    "options": [],
+    "answer": "8;40",
+    "solution": "【分析】钟面上长针是分针，短针是时针。分针走1大格是5分钟，时针走1大格是1小时，由此解答.\n【详解】从12走到8，时针走了1×8=8(小时);分针走了5×8=40(分钟),钟面上，时针从12走到8经过了8小时，分针从12走到8经过了40分钟。",
+    "knowledge_points": [
+      "8的乘法口诀及应用",
+      "时，分，秒有关的计算"
+    ],
+    "source": "22-23 二年级上·浙江杭州·期末"
+  },
+  {
+    "id": "446",
+    "unit": "第七单元 认识时间",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "如图,![](images/a0ed62f6f720d790623bb9747cf7cf511f2e5e5189b28ac2abde6d385199f627.jpg),钟面上显示的是( )时( )分，分针和时针组成( )角，再过一刻钟是( )。",
+    "options": [],
+    "answer": "6;5;钝;6:20或6时20分",
+    "solution": "【分析】时针指向6多一点，分针指向1，表示6时5分。在三角板上，最大角是直角;钝角比直角大;锐角比直角小。一刻钟是15分钟，结束时间=开始时间+经过时间。据此解决此题.\n【详解】由题意分析得:6时5分+15分=6时20分，故，钟面上显示的是6时5分，分针和时针组成钝角，再过一刻钟是6时20分。",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征",
+      "一般时间与钟面指针的位置",
+      "时，分，秒时间的推算"
+    ],
+    "source": "22-23 二年级上·重庆巫溪·期末"
+  },
+  {
+    "id": "447",
+    "unit": "第七单元 认识时间",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "在括号里填上\">\"\"<\"或\"=\".\n\n70( )34+40;3米( )30厘米;3+3( )3×3;60分( )1小时",
+    "options": [],
+    "answer": "<;>;<;=",
+    "solution": "【分析】将算式计算出结果再比较大小。比较大小时，数位多的数就大，数位相同比较最高位，最高位大的数就大，最高位相同则比较下一位，直到比较出结果为止。长度和时间的先统一单位再进行比较.\n【详解】34+40=74;70<74，则70<34+40;3米>1米;1米=100厘米;100厘米>30厘米，则3米>30厘米;3+3=6;3×3=9;6<9，则3+3<3×3;60分=1小时。",
+    "knowledge_points": [
+      "100以内数的比大小",
+      "3的乘法口诀及应用",
+      "时，分的认识及换算",
+      "厘米和米之间的进率与换算"
+    ],
+    "source": "22-23 二年级上·河南南阳·期末"
+  },
+  {
+    "id": "448",
+    "unit": "第七单元 认识时间",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "在括号里填入\">\"\"<\"或\"=\".\n\n44( )79-33;3×4( )4+4+4;60厘米( )6米;65分钟( )1小时",
+    "options": [],
+    "answer": "<;=;<;>",
+    "solution": "【分析】依次计算出各算式的结果再比较大小。比较大小时，数位多的数就大;数位相同比较最高位，最高位大的数就大;最高位相同比较下一位，直到比较出结果为止。长度和时间的先统一单位再比较.\n【详解】79-33=46;44<46，则44<79-33;3×4=12;4+4+4=12;12=12，则3×4=4+4+4;60厘米<100厘米;100厘米=1米;1米<6米，则60厘米<6米;1小时=60分钟;65分钟>60分钟，则65分钟>1小时。",
+    "knowledge_points": [
+      "100以内数的比大小",
+      "4的乘法口诀及应用",
+      "时，分的认识及换算",
+      "厘米和米之间的进率与换算"
+    ],
+    "source": "22-23 二年级上·四川乐山·期末"
+  },
+  {
+    "id": "449",
+    "unit": "第七单元 认识时间",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "在下面的括号里填上合适的单位名称.\n\n篮球场长28( ).\n一节数学课上了40( )。",
+    "options": [],
+    "answer": "米或m;分钟或分或min",
+    "solution": "【分析】幼儿园大班小朋友的身高大概是1米，测量较长的物体长度时通常用米做单位，根据生活经验并结合实际数据可知，计量一节数学课的时间以分为单位，据此得出结论即可.\n【详解】根据分析知：篮球场长28米。一节数学课上了40分钟。",
+    "knowledge_points": [
+      "时间单位的选择",
+      "长度单位的选择"
+    ],
+    "source": "22-23 二年级上·福建福州·期末"
+  },
+  {
+    "id": "450",
+    "unit": "第七单元 认识时间",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "用合适的单位填空。上午8( ),小红到达学校。第一节是语文课，同学们读了一篇课文，用了5( )。体育课上，小红看到操场上旗杆的高约13( ),操场一条边的长是60( ),她跳远的成绩是1( )20( )。",
+    "options": [],
+    "answer": "时;分钟或min;米或m;米或m;米或m;厘米或cm",
+    "solution": "【分析】根据生活情境及数据的大小，填合适的单位即可。到校时间一般为8时;读一篇文章的时间较短，一般为5分钟;旗杆的高度较高，用米作单位;操场的长度较长，用米作单位;跳远的长度一般写作1米20厘米。由此填写.\n【详解】上午8时，小红到达学校。第一节是语文课，同学们读了一篇课文，用了5分钟。体育课上，小红看到操场上旗杆的高约13米，操场一条边的长是60米，她跳远的成绩是1米20厘米。",
+    "knowledge_points": [
+      "时间单位的选择",
+      "长度单位的选择"
+    ],
+    "source": "22-23 二年级上·河南信阳·期末"
+  },
+  {
+    "id": "451",
+    "unit": "第七单元 认识时间",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "下图钟面上显示的时间是( ),再过10分钟是( ).\n\n![](images/6bed2c4168973cfbe6adbf9078ed0b286c71827485f44056fca9ec13f9a02f74.jpg)",
+    "options": [],
+    "answer": "5:50或5时50分;6:00或6时",
+    "solution": "【分析】时针快指向6，表示5时多，分针指向10，表示50分;合起来就是5时50分。结束时间=开始时间+经过时间.\n【详解】由题意分析得:5时50分+10分=6时，故，钟面上显示的时间是5时50分，再过10分钟是6时。",
+    "knowledge_points": [
+      "一般时间与钟面指针的位置",
+      "时，分，秒时间的推算"
+    ],
+    "source": "21-22 二年级上·浙江湖州·期末"
+  },
+  {
+    "id": "452",
+    "unit": "第七单元 认识时间",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "![](images/72ae768c34f82c5e024facc69b675ee3d9fe5868ff5c05c879b7c4e45c35f3de.jpg)如图，钟面上的时间是( ),过10分钟后是( )。",
+    "options": [],
+    "answer": "1:05或1时5分;1:15或1时15分",
+    "solution": "【分析】根据时针走1大格是1小时，分针走1大格是5分钟即可解答。时针和分针指向1，是1个5分钟，是1:05，即可解答。加上10分钟，即可求出过10分后的时间.\n【详解】5+10=15(分),所以钟面上的时间是1:05(或1时5分),过10分钟后是1:15(或1时15分)。",
+    "knowledge_points": [
+      "一般时间与钟面指针的位置",
+      "时，分，秒时间的推算"
+    ],
+    "source": "22-23 二年级上·宁夏固原·期末"
+  },
+  {
+    "id": "453",
+    "unit": "第七单元 认识时间",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "一刻=( )分;30分+30分=( )时",
+    "options": [],
+    "answer": "15;1",
+    "solution": "【分析】一刻就是15分钟,1时=60分，据此解答.\n【详解】一刻=15分;30分+30分=60分=1时。",
+    "knowledge_points": [
+      "时，分的认识及换算"
+    ],
+    "source": "22-23 二年级上·湖南张家界·期末"
+  },
+  {
+    "id": "454",
+    "unit": "第七单元 认识时间",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "时针从一个数字走到下一个数字是( )小时，分针走一个大格是( )分钟。",
+    "options": [],
+    "answer": "1;5",
+    "solution": "【分析】时针走1大格是1小时，分针走1大格是5分钟.\n【详解】时针从一个数字走到下一个数字是(1)小时，分针走一个大格是(5)分钟。如：时针从8点走到9点,8点到9点为一个小时，分针走一大格为5分钟。",
+    "knowledge_points": [
+      "一般时间与钟面指针的位置",
+      "时，分的认识及换算"
+    ],
+    "source": "19-20 三年级上·海南省直辖县级单位·期中"
+  },
+  {
+    "id": "455",
+    "unit": "第七单元 认识时间",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "夏天午睡大约用1( ),脉搏跳10次大约用8( )。",
+    "options": [],
+    "answer": "时或h;秒或s",
+    "solution": "【分析】午睡的时间较短，一般是1小时左右;脉搏跳动的时间一般用秒计算。熟练掌握对时，分，秒的认识是解题关键.\n【详解】夏天午睡大约用1时，脉搏跳10次大约用8秒。",
+    "knowledge_points": [
+      "时，分的认识及换算",
+      "秒的认识"
+    ],
+    "source": "22-23 二年级下·贵州毕节·期末"
+  },
+  {
+    "id": "456",
+    "unit": "第七单元 认识时间",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "钟面上有( )个小格，分针走1小格是( )分。走5小格是( )分。走60小格(一圈)是( )分。",
+    "options": [],
+    "answer": "60;1;5;60",
+    "solution": "【分析】在钟面上，一周平均分成12个大格，一个大格又平均分成5个小格，所以钟面上有60个小格，分针每过一小格是1分，时针过一个大格是1小时，分针走1圈，是60分，据此解答即可。熟练掌握钟表的认识是解决此题的关键.\n【详解】钟面上有(60)个小格，分针走1小格是(1)分。走5小格是(5)分。走60小格(一圈)是(60)分。",
+    "knowledge_points": [
+      "整点时间与钟面指针的位置",
+      "时，分的认识及换算"
+    ],
+    "source": "22-23 二年级上·全国·随堂练习"
+  },
+  {
+    "id": "457",
+    "unit": "第七单元 认识时间",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "钟面上有( )个大格，时针走1大格是( )时。走5大格是( )时。走12大格是( )时。",
+    "options": [],
+    "answer": "12;1;5;12",
+    "solution": "【分析】在钟面上，平均分成12个大格，一个大格又平均分成了5个小格，一共有60个小格，秒针每过一小格是1秒，分针每过1小格是1分，则走1大格是5分，时针过一个大格是1小时;据此解答即可。题主要考查了学生对钟表的认识，要熟练掌握.\n【详解】钟面上有(12)个大格，时针走1大格是(1)时。走5大格是(5)时。走12大格是(12)时。",
+    "knowledge_points": [
+      "整点时间与钟面指针的位置",
+      "时，分的认识及换算"
+    ],
+    "source": "22-23 二年级上·全国·随堂练习"
+  },
+  {
+    "id": "458",
+    "unit": "第七单元 认识时间",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "时针从\"1\"走到\"6\"，走了( )小时;分针从\"1\"走到\"6\"走了( )分钟。",
+    "options": [],
+    "answer": "5;25",
+    "solution": "【分析】时针走1大格为1小时，从1走到6，走了5大格，走了1×5=5(小时)。分针走1大格为5分钟，从1走到6，走了5大格，走了5×5=25(分钟)。本题主要考查对钟表的认识，要熟练掌握.\n【详解】时针从\"1\"走到\"6\"，走了5小时;分针从\"1\"走到\"6\"走了25分钟。",
+    "knowledge_points": [
+      "5的乘法口诀及应用",
+      "时，分的认识及换算"
+    ],
+    "source": "22-23 二年级上·湖北黄石·期末"
+  },
+  {
+    "id": "459",
+    "unit": "第七单元 认识时间",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "1时等于( )分,30分也可以说成( )。",
+    "options": [],
+    "answer": "60;半小时",
+    "solution": "【分析】由题意可知，钟面上一共有12个大格,60个小格，每个大格有5个小格。时针走1大格是1小时，分针走1小格是1分钟，走1大格是5分钟;时针走1大格，分针要走1整圈，所以1时=60分,30分也就是1小时的一半，也被称为半小时，据此解答即可。熟练掌握时与分的单位换算是解决此题的关键.\n【详解】由分析可得:1时等于(60)分,30分也可以说成(半小时)。",
+    "knowledge_points": [
+      "时，分的认识及换算"
+    ],
+    "source": "22-23 二年级上·河南南阳·期末"
+  },
+  {
+    "id": "460",
+    "unit": "第七单元 认识时间",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "1米=( )厘米;( )时=60分。",
+    "options": [],
+    "answer": "100;1",
+    "solution": "【分析】根据长度单位和时间单位的进率，即1米=100厘米,1时等于60分，进行解答。本题考查学生对长度单位和时间单位换算的掌握和运用.\n【详解】1米=100厘米;1时=60分。",
+    "knowledge_points": [
+      "时，分的认识及换算",
+      "厘米和米之间的进率与换算"
+    ],
+    "source": "21-22 二年级上·山东济宁·期末"
+  },
+  {
+    "id": "461",
+    "unit": "第七单元 认识时间",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "分针从1走到5，走了( )分，时针从6走到9，走了( )时。",
+    "options": [],
+    "answer": "20;3",
+    "solution": "【分析】钟面上分12大格，每大格分5小格，共分60小格。分针走1大格经过的时间是5分钟，分针从1走到5，走了4个5分钟;时针走1大格是1小时，时针从6走到9，走了3个1小时;用乘法即可解答。此题主要是考查钟表的认识及时间的推算。要熟练掌握基础知识.\n【详解】5×4=20(分),1×3=3(时),分针从1走到5，走了20分，时针从6走到9，走了3时。",
+    "knowledge_points": [
+      "时，分，秒有关的计算"
+    ],
+    "source": "20-21 二年级上·广东江门·期末"
+  },
+  {
+    "id": "462",
+    "unit": "第七单元 认识时间",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "在下面括号里填上\">\"\"<\"或\"=\".\n\n98厘米( )1米;60分( )1时;3×6( )6+6+5",
+    "options": [],
+    "answer": "<;=;>",
+    "solution": "【分析】(1)根据1米=100厘米，将单位换算后进行比较;(2)根据1时=60分进行比较;(3)先算出两个算式的结果，再进行比较。本题主要考查数量的比较大小，单位不同时先将单位换算统一后比较，算式比较先算出计算结果，再进行比较.\n【详解】1米=100厘米,98厘米<1米;60分=1时;3×6=18,6+6+5=17,3×6>6+6+5。",
+    "knowledge_points": [
+      "100以内数的比大小",
+      "6的乘法口诀及应用",
+      "时，分的认识及换算",
+      "厘米和米之间的进率与换算"
+    ],
+    "source": "20-21 二年级上·四川乐山·期末"
+  },
+  {
+    "id": "463",
+    "unit": "第七单元 认识时间",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "时针从5走到11，走了( )时，分针从3走到9，走了( )分。",
+    "options": [],
+    "answer": "6;30",
+    "solution": "【分析】时针走一大格是1时，分针走一大格是5分。熟练掌握对钟面的认识是解题关键.\n【详解】时针从5走到11，走了6大格，就是6时;分针从3走到9，走了6大格，是30分。",
+    "knowledge_points": [
+      "时，分的认识及换算"
+    ],
+    "source": "20-21 二年级上·海南省直辖县级单位·期末"
+  },
+  {
+    "id": "464",
+    "unit": "第七单元 认识时间",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "钟面上分针从12走到3，走了( )分，时针从12走到3，走( )时。",
+    "options": [],
+    "answer": "15;3",
+    "solution": "【分析】时针走一大格是1小时，分针走一大格是5分钟，据此解答即可。根据钟面的知识解答此题即可.\n【详解】钟面上分针从12走到3，走了3大格,3×5=15(分),所以走了15分。时针从12走到3，走了3大格,3×1=3(时),所以走了3时。",
+    "knowledge_points": [
+      "时，分，秒有关的计算"
+    ],
+    "source": "20-21 二年级上·湖北十堰·期末"
+  },
+  {
+    "id": "465",
+    "unit": "第七单元 认识时间",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "1米=( )厘米;( )时=60分;300厘米=( )米",
+    "options": [],
+    "answer": "100;1;3",
+    "solution": "【分析】根据1米=100厘米,1小时=60分，据此进行单位换算即可。本题考查学生对长度单位，时间单位换算的掌握和运用.\n【详解】由分析得:1米=100厘米,1小时=60分,300厘米=3米。",
+    "knowledge_points": [
+      "时，分的认识及换算",
+      "厘米和米之间的进率与换算"
+    ],
+    "source": "21-22 二年级上·浙江绍兴·期末"
+  },
+  {
+    "id": "466",
+    "unit": "第七单元 认识时间",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "一个小朋友唱一首歌要用5分钟，全班40个小朋友一起唱这首歌要用( )分钟。",
+    "options": [],
+    "answer": "5",
+    "solution": "【分析】全班40个小朋友一起唱这首歌要用的时间，与一个小朋友唱一首歌要用的时间相同，依此填空。唱一首歌的时间，与唱歌的人数没有关系.\n【详解】根据分析可知，一个小朋友唱一首歌要用5分钟，全班40个小朋友一起唱这首歌要用5分钟。",
+    "knowledge_points": [
+      "时，分的认识及换算"
+    ],
+    "source": "20-21 四年级上·海南省直辖县级单位·期末"
+  },
+  {
+    "id": "467",
+    "unit": "第七单元 认识时间",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "填上合适的单位名称.\n\n小明上午在学校里的时间大约是3( );一棵大树高约10( );冬冬吃饭大约需要25( );王老师身高1( )62( )",
+    "options": [],
+    "answer": "小时;米或m;分钟;米或m;厘米或cm",
+    "solution": "【分析】根据生活经验以及数据的大小，选择合适的计量单位，即可解答。此题考查根据情景选择合适的计量单位，要注意联系生活实际，计量单位和数据的大小，灵活地选择.\n【详解】小明上午在学校里的时间大约是3小时，一棵大树高约10米(或m),冬冬吃饭大约需要25分钟，王老师的身高1米(或m)62厘米(或cm)。",
+    "knowledge_points": [
+      "时，分的认识及换算",
+      "厘米的认识",
+      "米的认识",
+      "长度单位的选择"
+    ],
+    "source": "20-21 二年级下·江西赣州·期末"
+  },
+  {
+    "id": "468",
+    "unit": "第七单元 认识时间",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "如表是三位同学折60只纸鹤所需要的时间。( )折得最快,( )折得最慢.\n\n<table><tr><td>小米</td><td>小雪</td><td>东东</td></tr><tr><td>43</td><td>1时2</td><td>58</td></tr><tr><td>分</td><td>分</td><td>分</td></tr></table>",
+    "options": [],
+    "answer": "小米;小雪",
+    "solution": "【分析】时间越短，速度越快;时间越长，速度越慢，据此解答即可。熟练掌握时间单位的换算，是解答此题的关键.\n【详解】1时=60分，所以1时2分=62分,62分>58分>43分，所以小米折得最快，小雪折得最慢。",
+    "knowledge_points": [
+      "时，分的认识及换算"
+    ],
+    "source": "21-22 二年级下·河南周口·期末"
+  },
+  {
+    "id": "469",
+    "unit": "第七单元 认识时间",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "如果现在是\n\n![](images/ddafa1d567a3de50cfe96312389d59f4e4319bf59871509cb79cd1345f7263d0.jpg)\n\n再过( )分是11时;如果现在是下午2:40，再过一刻是下午( )时( )分。",
+    "options": [],
+    "answer": "15;2;55",
+    "solution": "【分析】钟面上的时间是10时45分，用11时减去10时45分即可;一刻是15分，用2时40分加上15分即可。熟练掌握时间的计算方法是解题关键.\n【详解】11时-10时45分=15分，所以再过15分是11时。2:40即2时40分,2时40分+15分=2时55分，所以再过一刻是下午2时55分。",
+    "knowledge_points": [
+      "一般时间与钟面指针的位置",
+      "时，分，秒时间的推算"
+    ],
+    "source": "20-21 二年级下·河南信阳·期末"
+  },
+  {
+    "id": "470",
+    "unit": "第七单元 认识时间",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "六点半记作( )或( )时( )分。",
+    "options": [],
+    "answer": "6:30;6;30",
+    "solution": "【分析】读写时间时，可以采用几时几分的形式，也可以采用数字的形式。例如:4:05读作:4时5分;4:45读作:4时45分;因为30分可以说成半小时，所以六点半可以写作:6:30;读作:6时半或6时30分。正确读写钟面上的时间--几时几分，懂得半时有两种读法，是解题关键.\n【详解】由分析得：六点半记作6:30或6时30分。",
+    "knowledge_points": [
+      "半点时间与钟面指针的位置"
+    ],
+    "source": "22-23 二年级上·全国·课后作业"
+  },
+  {
+    "id": "471",
+    "unit": "第七单元 认识时间",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "分针刚过12，时针指向8，这时是( )时刚过一点。",
+    "options": [],
+    "answer": "8",
+    "solution": "【分析】已知时针指向8，说明是8时，又知道分针刚过12，说明是8时，但刚过一点，所以是8时刚过一点。本题考查了一般时间与钟面指针的位置等知识内容.\n【详解】根据分析，分针刚过12，时针指向8，这时是8时刚过一点。",
+    "knowledge_points": [
+      "一般时间与钟面指针的位置"
+    ],
+    "source": "20-21 一年级下·江西抚州·单元测试"
+  },
+  {
+    "id": "472",
+    "unit": "第七单元 认识时间",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "笑笑早上7:00起床，她用30分钟洗漱和吃饭，那么她( )就可以去上学了。",
+    "options": [],
+    "answer": "7:30",
+    "solution": "【分析】本题考查时间的推算。已知笑笑起床时间是7:00，经过30分钟洗漱和吃饭，求她可以去上学的时间，直接用起床时间加上经过的时间即可。计算时注意分钟满60向时进1，本题30分加0分仍为30分，时不变.\n【详解】7:00+30分=7:30。故答案为:7:30",
+    "knowledge_points": [
+      "时，分，秒时间的推算"
+    ],
+    "source": "18-19 一年级上·河南商丘·期末"
+  },
+  {
+    "id": "473",
+    "unit": "第七单元 认识时间",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "分针从4走到11，走了( )分;时针从4走到11，走了( )时。",
+    "options": [],
+    "answer": "35;7",
+    "solution": "【分析】本题考查钟面上时针和分针行走经过的时间。分针走一大格是5分钟，时针走一大格是1小时。分别数出分针和时针从4走到11经过的大格数，再乘每大格对应的时间即可.\n【详解】分针从4走到11，走了11-4=7(大格),7×5=35(分);时针从4走到11，走了11-4=7(大格),7×1=7(时)。故答案为:35;7",
+    "knowledge_points": [
+      "时，分，秒有关的计算"
+    ],
+    "source": "21-22 二年级上·湖北孝感·期末"
+  },
+  {
+    "id": "474",
+    "unit": "第七单元 认识时间",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "上一节课需要40分钟，如果第二节课从上午9:05开始，那么下课的时间是上午( )时( )分。",
+    "options": [],
+    "answer": "9;45",
+    "solution": "【分析】本题考查时间的推算。已知一节课需要40分钟，从上午9:05开始上课，求下课时间，直接用开始时间加上经过的时间即可。计算时要注意分钟相加满60向时进1.\n【详解】9:05+40分=9:45。故答案为:9;45",
+    "knowledge_points": [
+      "时，分，秒时间的推算"
+    ],
+    "source": "21-22 二年级上·湖南怀化·期末"
+  },
+  {
+    "id": "475",
+    "unit": "第七单元 认识时间",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "时针走过7，分针从12开始走了10大格，就是( )。",
+    "options": [],
+    "answer": "7时50分",
+    "solution": "【分析】本题考查钟面上时间的认识。时针走过7，表示此时是7时多;分针从12开始走了10大格，分针每走一大格是5分钟,10大格就是10×5=50分。合起来就是7时50分.\n【详解】时针走过7，是7时多;分针走了10大格，是10×5=50(分);所以此时是7时50分。故答案为:7时50分",
+    "knowledge_points": [
+      "时，分，秒时间的推算"
+    ],
+    "source": "21-22 二年级上·福建莆田·期末"
+  },
+  {
+    "id": "476",
+    "unit": "第七单元 认识时间",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "下图钟面上的时间是( ),也可以表示成( ),过20分钟是( ).\n\n![](images/22ff99b7502832a26de5a4ff9e7d0edf44974cb91d1e68a10fa932ab19a761d5.jpg)",
+    "options": [],
+    "answer": "7时30分;7:30;7时50分",
+    "solution": "【分析】观察钟面，时针指向7和8的中间，分针指向6，表示7时30分。也可以表示成7:30。再过20分钟，用当前时间加上20分钟即可,7时30分+20分=7时50分.\n【详解】钟面时间为7时30分，也可以表示成7:30;过20分钟后是7时50分。故答案为:7时30分;7:30;7时50分",
+    "knowledge_points": [
+      "半点时间与钟面指针的位置",
+      "时，分，秒时间的推算"
+    ],
+    "source": "21-22 二年级上·贵州黔西·期末"
+  },
+  {
+    "id": "477",
+    "unit": "第七单元 认识时间",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "在括号里填上\"<\"\">\"或\"=\".\n\n9+56( )64;9×7( )65;1小时5分钟( )65分钟",
+    "options": [],
+    "answer": ">;<;=",
+    "solution": "【分析】本题考查数的大小比较以及时间单位的换算。先计算出左边算式的结果或统一单位，再进行比较.\n【详解】9+56=65,65>64，所以9+56>64;9×7=63,63<65，所以9×7<65;1小时=60分,1小时5分钟=60分+5分=65分,65分=65分，所以1小时5分钟=65分钟。故答案为:>;<;=",
+    "knowledge_points": [
+      "100以内数的比大小",
+      "一位数与两位数的进位加法",
+      "9的乘法口诀及应用",
+      "时，分的认识及换算"
+    ],
+    "source": "21-22 二年级上·贵州黔西·期末"
+  },
+  {
+    "id": "478",
+    "unit": "第七单元 认识时间",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "时针从\"12\"走到\"3\"走了( )小时，分针从\"12\"走到\"3\"，走了( )分钟。",
+    "options": [],
+    "answer": "3;15",
+    "solution": "【分析】本题考查钟面上时针和分针行走经过的时间。时针走一大格是1小时，分针走一大格是5分钟。分别数出时针和分针从12走到3经过的大格数，再乘每大格对应的时间即可.\n【详解】时针从12走到3，走了3大格,3×1=3(小时);分针从12走到3，走了3大格,3×5=15(分钟)。故答案为:3;15",
+    "knowledge_points": [
+      "5的乘法口诀及应用",
+      "3的乘法口诀及应用",
+      "时，分的认识及换算"
+    ],
+    "source": "21-22 二年级上·山西吕梁·期末"
+  },
+  {
+    "id": "479",
+    "unit": "第七单元 认识时间",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "在括号里填上\">\"\"<\"或\"=\".\n\n7×6( )48;30厘米( )2米\n5×7( )7×4+5;半小时( )50分",
+    "options": [],
+    "answer": "<;<;>;<",
+    "solution": "【分析】本题考查数的大小比较，长度单位换算以及时间单位换算。先计算出左边算式的结果或统一单位，再进行比较.\n【详解】7×6=42,42<48，所以7×6<48;2米=200厘米,30厘米<200厘米，所以30厘米<2米;5×7=35,7×4+5=28+5=33,35>33，所以5×7>7×4+5;半小时=30分,30分<50分，所以半小时<50分。故答案为:<;<;>;<",
+    "knowledge_points": [
+      "7的乘法口诀及应用",
+      "时，分的认识及换算",
+      "厘米和米之间的进率与换算",
+      "表内乘加，乘减"
+    ],
+    "source": "21-22 二年级上·山东菏泽·期末"
+  },
+  {
+    "id": "480",
+    "unit": "第七单元 认识时间",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "2时45分再过15分是3时整。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】2时45分+15分，先计算45分+15分=60分=1时，再算2时+1时=3时。由此解答.\n【详解】由分析可知,2时45分再过15分是3时整。原题说法正确。故答案为:√",
+    "knowledge_points": [
+      "时，分的认识及换算",
+      "时，分，秒有关的计算"
+    ],
+    "source": "23-24 二年级上·甘肃平凉·期末"
+  },
+  {
+    "id": "481",
+    "unit": "第七单元 认识时间",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "分针走1大格是1分钟，时针走一大格是1小时。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】钟面上有60小格,12大格(如下图);分针每走1小格就是1分钟，走1大格就是5分钟;时针走1大格是1小时.\n【详解】由题意分析得:![](images/ea15112c7b70f7d6b887f5b10ef2891539af9a88ba828131bcd1b7111565d0cb.jpg)分针走1大格是5分钟，时针走一大格是1小时;所以原题说法错误。故答案为: ×",
+    "knowledge_points": [
+      "时，分的认识及换算"
+    ],
+    "source": "22-23 二年级上·山东临沂·期末"
+  },
+  {
+    "id": "482",
+    "unit": "第七单元 认识时间",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "分针指着12，时针指着8，就是8时。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】分针指着12，时针指着几，就是几时.\n【详解】分针指着12，时针指着8，就是8时。原题说法正确。故答案为:√",
+    "knowledge_points": [
+      "整点时间与钟面指针的位置"
+    ],
+    "source": "22-23 二年级上·河南南阳·期末"
+  },
+  {
+    "id": "483",
+    "unit": "第七单元 认识时间",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "钟面上3时和6时整，分针和时针形成的角是直角。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】像长方形和正方形上的角一样的是直角，据此得出结论即可.\n【详解】钟面上3时整，分针和时针形成的角和长方形上的角一样是直角。6时整，分针和时针形成的角是平角。故答案为: ×",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征",
+      "整点时间与钟面指针的位置"
+    ],
+    "source": "23-24 二年级上·广东江门·期中"
+  },
+  {
+    "id": "484",
+    "unit": "第七单元 认识时间",
+    "question_type": "判断题",
+    "difficulty": 0.65,
+    "question": "因为1时=60分，所以分针走一圈，时针走一大格就是1时。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】根据时针走1大格是1小时，分针走1大格是5分钟即可解答。本题主要考查时针走1大格是1小时，分针走1大格是5分钟.\n【详解】因为1时=60分，所以分针走一圈刚好是60分，此时时针走一大格就是1时;原题说法正确。故答案为:√",
+    "knowledge_points": [
+      "时，分的认识及换算"
+    ],
+    "source": "23-24 三年级·全国·假期作业"
+  },
+  {
+    "id": "485",
+    "unit": "第七单元 认识时间",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "时针从12开始绕一大圈又走回12，走了60分。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】时针走一圈是12小时，分针走一圈是60分。熟练掌握对时，分的认识是解题关键.\n【详解】时针从12开始绕一大圈又走回12，走了12小时，也就是12个60分。原题说法错误。故答案为: ×",
+    "knowledge_points": [
+      "时，分的认识及换算"
+    ],
+    "source": "20-21 二年级上·湖南岳阳·期末"
+  },
+  {
+    "id": "486",
+    "unit": "第七单元 认识时间",
+    "question_type": "判断题",
+    "difficulty": 0.65,
+    "question": "儿童每天需要的睡眠时间是10分。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】根据生活经验以及数据的大小，选择合适的计量单位，即可解答。此题考查根据情景选择合适的计量单位，要注意联系生活实际，计量单位和数据的大小，灵活的选择.\n【详解】儿童每天需要的睡眠时间是10小时。原题说法错误。故答案为: ×",
+    "knowledge_points": [
+      "时间单位的选择"
+    ],
+    "source": "20-21 二年级下·重庆黔江·期末"
+  },
+  {
+    "id": "487",
+    "unit": "第七单元 认识时间",
+    "question_type": "判断题",
+    "difficulty": 0.65,
+    "question": "分针从\"3\"走到\"6\"，走了15分钟。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】分针从\"3\"走到\"6\"，走了3大格，分针走一大格表示经过5分钟，据此解答。此题考查了钟表和时间的认识，要熟练掌握.\n【详解】6-3=3(格),3×5=15(分钟),所以，分针从\"3\"走到\"6\"，走了15分钟。原题说法正确。故答案为:√",
+    "knowledge_points": [
+      "时，分，秒有关的计算"
+    ],
+    "source": "20-21 二年级下·重庆黔江·期末"
+  },
+  {
+    "id": "488",
+    "unit": "第七单元 认识时间",
+    "question_type": "判断题",
+    "difficulty": 0.65,
+    "question": "时针走1大格的时间是1分。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】在钟表上，时针走1大格的时间是1小时，分针走1大格的时间是5分钟，据此解答即可。本题考查的是对钟表的认识，时针与分针走1大格所经过的时间是解题的关键.\n【详解】时针走1大格的时间是1小时，故说法不正确。故答案为: ×",
+    "knowledge_points": [
+      "时，分的认识及换算"
+    ],
+    "source": "20-21 二年级下·江西赣州·期末"
+  },
+  {
+    "id": "489",
+    "unit": "第七单元 认识时间",
+    "question_type": "判断题",
+    "difficulty": 0.65,
+    "question": "分针从2走到6，经过了4分。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】分针每走过1大格是5分钟，从2走到6是4大格，据此解答即可。本题主要考查了对钟表的认识，解题的关键是理解分针每走过1大格是5分钟.\n【详解】5+5+5+5=10+5+5=15+5=20(分),所以分针从2走到6，经过了20分。故答案为: ×",
+    "knowledge_points": [
+      "时，分，秒有关的计算"
+    ],
+    "source": "21-22 二年级下·四川自贡·期末"
+  },
+  {
+    "id": "490",
+    "unit": "第七单元 认识时间",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "分针走一大圈，时针刚好走一大格，即1时。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】分针走一圈是1时，时针走一大格是1时，据此判断。熟练掌握时间与钟面指针的位置关系是解题关键.\n【详解】分针走一大圈，时针刚好走一大格，即1时，原题说法正确。故答案为:√",
+    "knowledge_points": [
+      "一般时间与钟面指针的位置",
+      "时，分的认识及换算"
+    ],
+    "source": "22-23 二年级上·全国·期末"
+  },
+  {
+    "id": "491",
+    "unit": "第七单元 认识时间",
+    "question_type": "判断题",
+    "difficulty": 0.65,
+    "question": "时针走一大格是1时，分针走一大格是5分。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】时针走一大格是1小时，分针走一大格是5分，据此判断.\n【详解】如图:\n\n![](images/5680f5581064fafa5d63b023b991a82607eb2d74f2fbd433eb7ef7c835314ad7.jpg)\n\n时针走一大格是1小时，分针走一大格是5分。原说法正确。故答案为:√",
+    "knowledge_points": [
+      "时，分的认识及换算"
+    ],
+    "source": "21-22 二年级下·河南鹤壁·期末"
+  },
+  {
+    "id": "492",
+    "unit": "第七单元 认识时间",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "分针从12走到6，经过了30分。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】分针每走一大格是5分，分针从12走到6走了6个大格，就是6个5分，据此解答。本题是考查钟表的认识，属于基础知识.\n【详解】5×6=30(分),所以经过了30分。故答案为:√",
+    "knowledge_points": [
+      "时，分的认识及换算",
+      "时，分，秒有关的计算"
+    ],
+    "source": "21-22 二年级下·河南周口·期末"
+  },
+  {
+    "id": "493",
+    "unit": "第七单元 认识时间",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "4时半就是4:30。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】4时半就是4时30分，也就是:4:30;据此解题即可。正确理解半点的意义，是解答此题的关键.\n【详解】根据分析可知:4时半就是4:30，是正确的。故答案为:√",
+    "knowledge_points": [
+      "半点时间与钟面指针的位置"
+    ],
+    "source": "22-23 二年级上·全国·期末"
+  },
+  {
+    "id": "494",
+    "unit": "第七单元 认识时间",
+    "question_type": "判断题",
+    "difficulty": 0.65,
+    "question": "下图钟面上的时刻是6:00。( )\n\n![](images/ed379382ab8681877f926983bd0cb29ba79e58eb3a67d0b02a599346775e022c.jpg)",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】根据钟面时针与分针的位置可以判断出时间。掌握整点，半点时间钟面时针与分针的位置关系是解题的关键.\n【详解】钟面上时针指向2和3的中间，分针指向6，是2:30;6:00的时候，时针指向6，分针指向12，题干说法错误。故答案为: ×",
+    "knowledge_points": [
+      "整点时间与钟面指针的位置",
+      "半点时间与钟面指针的位置"
+    ],
+    "source": "22-23 一年级上·全国·期末"
+  },
+  {
+    "id": "495",
+    "unit": "第七单元 认识时间",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "时针从12走到2是2分。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】根据时针走一大格代表的时间作出判断即可。解答本题需要熟练掌握整点时间与钟面指针的位置关系.\n【详解】时针走一大格代表1小时，从12走到2走了两大格，所以是2小时。故答案为: ×",
+    "knowledge_points": [
+      "时，分的认识及换算"
+    ],
+    "source": "21-22 二年级下·贵州铜仁·期末"
+  },
+  {
+    "id": "496",
+    "unit": "第七单元 认识时间",
+    "question_type": "判断题",
+    "difficulty": 0.65,
+    "question": "时针从5开始绕了一圈又走回到5，走了60分。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】在钟面上，共有12个大格，每个大格分成5个小格，共有60个小格，时针走1大格是1时;分针走1小格是1分，走1大格是5分，走一圈是60分，据此进行解答。此题考查在钟面上时针，分针的运行规律.\n【详解】由分析可得：时针从5开始绕了一圈又走回5，走了12时，所以原题说法错误。故答案为: ×",
+    "knowledge_points": [
+      "时，分，秒有关的计算"
+    ],
+    "source": "21-22 二年级上·湖北孝感·期末"
+  },
+  {
+    "id": "497",
+    "unit": "第七单元 认识时间",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "分针从12走到7与分针从7走到12所用的时间相同。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】分针走一大格是五分钟，按顺时针方向分别数一下从12走到7需要走几大格以及从7走到12需要走几大格，计算出所需要的时间进行判断即可。本题重点考查对分针的认识以及简单的经过时间的计算，注意数格时一定要按照顺时针方向.\n【详解】分针从12走到7需要走7大格,5×7=35(分),分针从7走到12需要走5大格,5×5=25(分),所以分针从12走到7与分针从7走到12所用的时间不相同，原题说法错误。故答案为: ×",
+    "knowledge_points": [
+      "时，分的认识及换算",
+      "时，分，秒有关的计算"
+    ],
+    "source": "21-22 二年级上·湖南怀化·期末"
+  },
+  {
+    "id": "498",
+    "unit": "第七单元 认识时间",
+    "question_type": "判断题",
+    "difficulty": 0.65,
+    "question": "钟面上分针走2圈，时针正好走2个大格。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】根据钟表的认识，可知钟面被平均分成60个小格，分针走1小格是1分钟;钟面被平均分成12个大格，时针走1个大格是1个小时;1小时=60分钟，所以分针走1圈，时针走了1个大格，分针走2圈，时针走2个大格。本题主要考查了钟面的认识，要熟练掌握.\n【详解】钟面上分针走2圈，时针正好走2个大格。原题干说法正确。故答案为:√",
+    "knowledge_points": [
+      "时，分的认识及换算"
+    ],
+    "source": "21-22 二年级上·河北承德·期末"
+  },
+  {
+    "id": "499",
+    "unit": "第七单元 认识时间",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "分针走1小格的时间是1分。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】本题考查钟面上分针走动与时间的关系。在钟面上，分针每走一小格代表的时间是1分钟，这是基本的时间单位认识.\n【详解】分针走1小格的时间是1分，原题说法正确。故答案为:√",
+    "knowledge_points": [
+      "时，分的认识及换算"
+    ],
+    "source": "19-20 二年级上·广东肇庆·期末"
+  },
+  {
+    "id": "500",
+    "unit": "第七单元 认识时间",
+    "question_type": "解答题",
+    "difficulty": 0.85,
+    "question": "丁丁每分钟能做9道口算题，他从8:25做到8:30，总共做了多少道口算题。",
+    "options": [],
+    "answer": "45道",
+    "solution": "【分析】根据题意可知：求他从8:25做到8:30，总共做了多少道口算题。需要算出8:25到8:30是几分钟，用结束的时间减去开始的时间即可，然后求总共做了多少道口算题。用每分钟做的数量乘分钟数即可.\n【详解】8:30-8:25=5(分),9×5=45(道),答：总共做了45道口算题。",
+    "knowledge_points": [
+      "9的乘法口诀及应用",
+      "时，分，秒有关的计算"
+    ],
+    "source": "22-23 二年级上·浙江杭州·期末"
+  }
+]
diff --git "a/\344\272\214\345\271\264\347\272\247\351\242\230\351\233\206/\344\272\214\345\271\264\347\272\247\344\270\212/\344\272\214\345\271\264\347\272\247\344\270\212\347\254\254\344\270\211\345\215\225\345\205\203\350\247\222\347\232\204\345\210\235\346\255\245\350\256\244\350\257\206.json" "b/\344\272\214\345\271\264\347\272\247\351\242\230\351\233\206/\344\272\214\345\271\264\347\272\247\344\270\212/\344\272\214\345\271\264\347\272\247\344\270\212\347\254\254\344\270\211\345\215\225\345\205\203\350\247\222\347\232\204\345\210\235\346\255\245\350\256\244\350\257\206.json"
new file mode 100644
index 0000000000000000000000000000000000000000..14e8f464fe4401e02d884987fa1e18d6fc8ab9cf
--- /dev/null
+++ "b/\344\272\214\345\271\264\347\272\247\351\242\230\351\233\206/\344\272\214\345\271\264\347\272\247\344\270\212/\344\272\214\345\271\264\347\272\247\344\270\212\347\254\254\344\270\211\345\215\225\345\205\203\350\247\222\347\232\204\345\210\235\346\255\245\350\256\244\350\257\206.json"
@@ -0,0 +1,8184 @@
+[
+  {
+    "id": "1",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.94,
+    "question": "如图，由外到内，这些直角( ).\n\n![](images/070816be372937a1a7df8d1351f4123f786687a9c6cffee6d9818f0b505336b7.jpg)",
+    "options": [
+      "A. 越来越小",
+      "B. 越来越大",
+      "C. 一样大"
+    ],
+    "answer": "C",
+    "solution": "【分析】和书本，黑板的角相同大小的是直角。角的大小和其两边的长度无关.\n【详解】由分析可得：如图，由外到内，这些直角(一样大)。故答案为:C",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "24-25 二年级上·福建厦门·期中"
+  },
+  {
+    "id": "2",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "如果把角的两条边延长，那么这个角的大小( )。",
+    "options": [
+      "A. 不变",
+      "B. 变大",
+      "C. 变小"
+    ],
+    "answer": "A",
+    "solution": "【分析】角是由一个公共端点的两条射线组成的图形，角的大小取决于两条射线张开的程度，与边的长短无关.\n【详解】由分析可知，把角的两边延长，两条射线的张开程度并没有改变，所以角的大小不变。如图:![](images/926c18c69f784f03c20cd7089f091f2b48e609184750fa322f3b562c92ea1955.jpg)故答案为:A",
+    "knowledge_points": [
+      "角的初步认识及辨认"
+    ],
+    "source": "24-25 二年级上·广西河池·期中"
+  },
+  {
+    "id": "3",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.94,
+    "question": "有一个角，被遮住了一部分(如下图),这个角是( ).\n\n![](images/edfcde8ee133dd085d02263bf854dfcaa7d4ab3d6cb8c98e113313ab98ad8bd9.jpg)",
+    "options": [
+      "A. 直角",
+      "B. 钝角",
+      "C. 锐角",
+      "D. 都有可能"
+    ],
+    "answer": "B",
+    "solution": "【分析】和书本，黑板的角相同大小的是直角，比直角大的是钝角，比直角小的是锐角。延长这个角的两条边使相交即可找到角的顶点，把角补充完整后再拿直角三角尺的直角比一比，这个角比直角大，是钝角.\n【详解】由分析可得：被遮住的这个角比直角大，是钝角。故答案为:B",
+    "knowledge_points": [
+      "角的初步认识及辨认",
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "24-25 二年级上·四川成都·期中"
+  },
+  {
+    "id": "4",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面图形中,( )是长方形。",
+    "options": [
+      "A. 四条边都相等的图形",
+      "B. 对边相等，四个角都是直角的图形",
+      "C. 三条边围成的图形"
+    ],
+    "answer": "B",
+    "solution": "【分析】长方形是长长方方的，由4 条边围成，且对边一样长,4 个角都是直角。正方形是正正方方的，由4 条边围成，且4 条边都一样长。三角形是由3 条线段首尾依次连接而成的封闭图形.\n【详解】由分析可得:A。四条边都相等的图形是正方形。B。对边相等，四个角都是直角的图形，是长方形。 C。三条边围成的图形是三角形。故答案为:B",
+    "knowledge_points": [
+      "长方形，正方形，三角形和圆的初步认识"
+    ],
+    "source": "25-26 二年级上·黑龙江佳木斯·开学考试"
+  },
+  {
+    "id": "5",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "如图是拉筋斜踏板，要使坡度变大，就需要让∠1变大，下面说法正确的是( ).\n\n![](images/bc7baf1b4dc260ee94900d2535daee424dcee9c1ef5e5fbe21bb925f1ed59a1e.jpg)\n\n![](images/875610fb5dde34332cb2f96d4f318a9199c562865db75404664e5e9399eebb01.jpg)",
+    "options": [
+      "A. 增加OC的长度",
+      "B. 增加OB的长度",
+      "C. 将点D移到点E,∠1变大",
+      "D. 将点D移到点G,∠1变大"
+    ],
+    "answer": "C",
+    "solution": "【分析】角的大小与角叉开的大小有关，与边的长短无关，据此解答.\n【详解】A。增加OC的长度，是延长边，不会让∠1变大，不符合题意;B。增加OB的长度，是延长边，不会让∠1变大，不符合题意;C。将点D移到点E,AD长度一定，所以OC和OB开口变大,∠1变大，符合题意;D。将点D移到点G,AD长度一定，所以OC和OB开口变小,∠1变小，不符合题意。故答案为:C",
+    "knowledge_points": [
+      "角的初步认识及辨认"
+    ],
+    "source": "24-25 六年级下·河北承德·期末"
+  },
+  {
+    "id": "6",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "平行四边形的四个角都不是( )。",
+    "options": [
+      "A. 锐角",
+      "B. 直角",
+      "C. 钝角"
+    ],
+    "answer": "B",
+    "solution": "【分析】三角尺上最大的角是直角，比直角大的角是钝角，比直角小的角是锐角。平行四边形有4条直直的边，对边相等，有2条同方向的斜边，它的角不像长方形，正方形那样方方正正的(直角),它的角有的会\"张得大一点\"(钝角),有的会\"张得小一点\"(锐角).\n【详解】由分析可知：平行四边形的四个角有的是钝角，有的是锐角，但没有直角。故答案为:B",
+    "knowledge_points": [
+      "平行四边形的初步认识",
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "24-25 二年级下·天津静海·期末"
+  },
+  {
+    "id": "7",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "红领巾有3 个角，其中有( )个钝角和( )个锐角。",
+    "options": [
+      "A. 1;2",
+      "B. 2;3",
+      "C. 3;1"
+    ],
+    "answer": "A",
+    "solution": "【分析】三角尺上最大的角是直角，比直角小的角是锐角，比直角大的角是钝角。用三角尺上的直角去对比红领巾的3个角，即可知有几个钝角和有几个锐角.\n【详解】由分析可知：红领巾有3 个角，其中有一个角比直角大，有两个角比直角小。所以红领巾的3 个角中，有1 个钝角和2 个锐角。故答案为:A",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "24-25 二年级下·天津静海·期末"
+  },
+  {
+    "id": "8",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "图中有( )个锐角.\n\n![](images/2a85bb07e83304edfb52f7cebdeb75d66abb6b7ca55aec4db2575204ffa5e924.jpg)",
+    "options": [
+      "A. 4",
+      "B. 3",
+      "C. 6"
+    ],
+    "answer": "A",
+    "solution": "【分析】据题意，锐角是小于直角的角，可用三角尺对照题目中的三角形，进行测量，即可得出答案.\n【详解】![](images/765c716fdaf0be8eb93165a5816b145a67c751157a7fba25f7ccf1b729b38f56.jpg)数一数一共有 4 个锐角。故答案为:A",
+    "knowledge_points": [
+      "角的初步认识及辨认",
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "23-24 二年级下·湖北黄冈·期末"
+  },
+  {
+    "id": "9",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面图形中，对边相等没有直角的是( )。",
+    "options": [
+      "A. ![](images/2026-02-19%20225602.jpg)",
+      "B. ![](images/2026-02-19%20225617.jpg)",
+      "C. ![](images/2026-02-19%20225646.jpg)"
+    ],
+    "answer": "C",
+    "solution": "【分析】由一个点引出两条直直的线所组成的图形是角，和书本，黑板的角相同大小的是直角，由此解答.\n【详解】A。长方形对边相等，有 4 个直角，不符合题意;B。正方形每条边都相等，有 4 个直角，不符合题意;C。平行四边形对边相等，没有直角，符合题意。则对边相等没有直角的是平行四边形。故答案为:C",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "23-24 二年级下·重庆潼南·期末"
+  },
+  {
+    "id": "10",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "用锐角和直角一定可以拼出( )。",
+    "options": [
+      "A. 锐角",
+      "B. 直角",
+      "C. 钝角"
+    ],
+    "answer": "C",
+    "solution": "【分析】角由一个顶点和两条边组成，和书本，黑板的角相同大小的是直角，比直角大的是钝角，比直角小的是锐角。由此解答.\n【详解】如图：直角不管和多大的锐角拼在一起，拼成的角都比直角大，也就是用锐角和直角一定可以拼出钝角。![](images/0fcc4c9fcac657ecc87a11cf60c6a99ab599715782b4a8480a7a762305815582.jpg)故答案为:C",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "24-25 二年级上·河南三门峡·期末"
+  },
+  {
+    "id": "11",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下列事件中，不符合生活实际的是( )。",
+    "options": [
+      "A. 居民楼每一层的高度普遍是 2 米",
+      "B. 一天的高峰期小刘卖了 98 根雪糕",
+      "C. 一个长方形桌面共有 4 个直角",
+      "D. 小华的教室长度为 90 厘米"
+    ],
+    "answer": "D",
+    "solution": "【分析】根据情景选择合适的计量单位，根据生活经验，对每种单位和数据大小的认识，即可做出选择。计量较短的物体，用\"厘米\"作单位，食指的宽度约为1 厘米。计量较长的物体，用\"米\"作单位，学生的双臂展开约为 1米。则计量楼房层高，房间的长度用\"米\"作单位。长方形有 4 条边对边相等,4 个直角且都是直角.\n【详解】居民楼每一层的高度普遍是 2 米，符合生活实际;一天的高峰期小刘卖了 98 根雪糕，符合生活实际;一个长方形桌面共有4 个直角，符合生活实际;小华的教室长度为90 厘米，不符合生活实际。故答案为:D",
+    "knowledge_points": [
+      "长方形，正方形，三角形和圆的初步认识",
+      "厘米的认识",
+      "米的认识",
+      "长度单位的选择"
+    ],
+    "source": "24-25 二年级上·浙江温州·期末"
+  },
+  {
+    "id": "12",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "用( )一定能拼成一个钝角。",
+    "options": [
+      "A. 一个钝角和一个锐角",
+      "B. 两个锐角",
+      "C. 一个直角和一个锐角",
+      "D. 两个直角"
+    ],
+    "answer": "C",
+    "solution": "【分析】大于直角的是钝角，小于直角的是锐角。一个直角和一个锐角拼成的角一定大于直角，据此解答.\n【详解】A。一个钝角和一个锐角可能拼成钝角，也可能是平角。B。两个锐角可以拼成锐角，直角或钝角。C。一个直角和一个锐角可以拼成一个钝角。D。两个直角一定拼成的角比钝角大。故答案:C",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "24-25 二年级上·浙江温州·期末"
+  },
+  {
+    "id": "13",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "从下面这些字母中找角，有( )个字母能找到角.\n\nA C E O N Q T",
+    "options": [
+      "A. 3",
+      "B. 4",
+      "C. 5"
+    ],
+    "answer": "B",
+    "solution": "【分析】由一个点引出两条直直的线所组成的图形是角。角有两条边和一个公共端点，这两条边叫做角的边，它们的公共端点叫做角的顶点.\n【详解】能找到角的字母有 A,E,N,T,共 4 个。故答案为:B",
+    "knowledge_points": [
+      "角的初步认识及辨认"
+    ],
+    "source": "24-25 二年级上·湖北荆州·期末"
+  },
+  {
+    "id": "14",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "如图，从顶点 O 引出了 5 条射线，一共有( )个角.\n\n![](images/3950b424b33e0482c3ffb5a9d5508553812207259ddd9db83fe5a9194f006511.jpg)",
+    "options": [
+      "A. 5",
+      "B. 10",
+      "C. 15",
+      "D. 20"
+    ],
+    "answer": "B",
+    "solution": "【分析】角的定义为：由一点引出的两条射线所组成的图形叫做角。我们可以按照一定的顺序去数这个图形中的角，避免遗漏和重复;据此解答.\n【详解】我们可以看到图中有4 个单角，相邻的两个单角组成一稍微大的角，一共有3 个，相邻的三个单角组成一个更大的角，一共有 2 个，最后还有 1 个,4 个单角组成的最大角，列式为: 4 + 3 + 2 + 1 = 10(个);从顶点 O 引出了 5 条射线，一共有 10 个角。故答案为:B",
+    "knowledge_points": [
+      "角的初步认识及辨认",
+      "数图形(数角)"
+    ],
+    "source": "24-25 二年级上·浙江温州·期末"
+  },
+  {
+    "id": "15",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "数一数，下图中共有( )个角.\n\n![](images/398c18d1d76431b3755241bcb0b767bb3180de4487d7d6de04d3f49504b9003c.jpg)",
+    "options": [
+      "A. 10",
+      "B. 5",
+      "C. 4"
+    ],
+    "answer": "A",
+    "solution": "【分析】根据角的概念，边是两条射线，顶点是这两条射线的公共端点，据此解答即可.\n【详解】![](images/1f20a9e6ef1f54cdc7f3d7f72d6b5a2dd4251ffe4b75a37712964033108ddbb4.jpg)从图上可得：一共有10 个角。故答案为:A",
+    "knowledge_points": [
+      "角的初步认识及辨认"
+    ],
+    "source": "24-25 二年级上·云南保山·期末"
+  },
+  {
+    "id": "16",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面用三角板拼出的角，最大的是( )。",
+    "options": [
+      "A. ![](images/c3008b0b7e9f465a9a55e77991a86e6e586ca4f793bb8c21aea7e63639072063.jpg)",
+      "B. ![](images/827175a8ad93825479262e408f2ee45b2a07227357aae5deebaa36d0fb193aee.jpg)",
+      "C. ![](images/6ce435a26a8b9465038dbdb0216b5463cd5dcbefca2c00da4526bab7074b8b6c.jpg)"
+    ],
+    "answer": "A",
+    "solution": "【分析】用三角尺中的直角进行比较，大于直角的是钝角小于直角的是锐角，则锐角 < 直角 < 钝角.\n【详解】A。直角和锐角拼在一起，则大于直角，是钝角。B。两个最大的锐角拼在一起用三角尺的直角比较大于直角是钝角。C。用三角尺的直角比较小于直角，则是锐角。由此可知,C 最小是锐角，则比较AB,AB 中有一个角是相同的，其中A 中的一个角是直角，大于B 中的锐角，则A 中两个角拼在一起组成的钝角大于B 中两角拼成的钝角。故答案为:A",
+    "knowledge_points": [
+      "角的初步认识及辨认",
+      "直角，钝角，锐角的认识及特征",
+      "角的大小比较"
+    ],
+    "source": "24-25 二年级上·湖北武汉·期末"
+  },
+  {
+    "id": "17",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "图中用一副三角尺拼出的是一个( ).\n\n![](images/bdee33970baa27d0c41f5eab90707f409d108972512e781496bb3fd2911600f4.jpg)",
+    "options": [
+      "A. 锐角",
+      "B. 直角",
+      "C. 钝角"
+    ],
+    "answer": "C",
+    "solution": "【分析】在三角板上，最大的角就是直角，而钝角比直角大，锐角比直角小;据此判断一个角是什么角。图中用一副三角尺拼出的角比直角大，是一个钝角.\n【详解】由题意分析得：图中用一副三角尺拼出的是一个钝角。故答案为:C",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征",
+      "用同样的图形拼接"
+    ],
+    "source": "24-25 二年级上·湖北随州·期末"
+  },
+  {
+    "id": "18",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "妈妈解锁手机的图案密码中有3 个锐角和2 个直角，妈妈的解锁密码可能是图案( )。",
+    "options": [
+      "A. ![](images/424c4a3d7061ab15c11faf022f491724a763f274d03807366c6b7f111554c5b0.jpg)",
+      "B. ![](images/d23dc0a78982b4cd5e7ccd64b692c606edd176ec2ac18a0e45d462c12cdf58c5.jpg)",
+      "C. ![](images/e31c1ebdfa75ed0d77e1d3795bad1bd14ed70cd92a46f256fb84a843fe309348.jpg)"
+    ],
+    "answer": "C",
+    "solution": "【分析】角是由1个顶点引出两条直直的线组成的图形，在三角板上，最大的角就是直角，比直角大的角是钝角，比直角小的角是锐角;用三角板上的直角比一比就可以找到几个直角，几个锐角和几个钝角;逐项分析各个选项中各种角的数量，即可解答.\n【详解】A。解锁图案中有 2 个锐角，答案不正确;B。解锁图案中有1 个锐角,1 个钝角和3 个直角，答案不正确;C。解锁图案中有 3 个锐角和 2 个直角，答案正确。故答案为:C",
+    "knowledge_points": [
+      "角的初步认识及辨认",
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "24-25 二年级上·河北保定·期末"
+  },
+  {
+    "id": "19",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "下边的三个图形中，角最多的是( )。",
+    "options": [
+      "A. ![](images/2026-02-19%20230421.jpg)",
+      "B. ![](images/2026-02-19%20230446.jpg)",
+      "C. ![](images/2026-02-19%20230502.jpg)"
+    ],
+    "answer": "C",
+    "solution": "【分析】由一个点引出两条直直的线所组成的图形是角。角有两条边和一个公共端点，这两条边叫做角的边，它们的公共端点叫做角的顶点。数一数每个图形有多少个角，然后比较即可求解.\n【详解】A。4 个角;B。3 个角;C。7 个角。3 < 4 < 7，角最多的是C。故答案为:C",
+    "knowledge_points": [
+      "角的初步认识及辨认",
+      "数图形(数角)"
+    ],
+    "source": "24-25 二年级上·湖南长沙·期末"
+  },
+  {
+    "id": "20",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "圈出的正方体的这个点是( )个直角的顶点.\n\n![](images/fe4055d125cd60a32e91b97a25ce9b573545034b6315a04f4e0cca7c00b81e80.jpg)",
+    "options": [
+      "A. 2",
+      "B. 3",
+      "C. 4"
+    ],
+    "answer": "B",
+    "solution": "【分析】由一个点引出两条直直的线所组成的图形是角，这个点是角的顶点，两条直直的线是角的边。和书本，黑板的角相同大小的是直角。正方体的6 个面都是正方形，正方形的 4 个角都是直角，圈出的这个点是几个角的顶点，就是几个直角的顶点.\n【详解】由图可知，圈出的正方体的这个点是3个角的顶点,3 个角都是直角，也就是3 个直角的顶点。故答案为:B",
+    "knowledge_points": [
+      "角的初步认识及辨认",
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "24-25 二年级上·湖南株洲·期末"
+  },
+  {
+    "id": "21",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "一个长方形剪去一个角后，最多还剩( )个角。",
+    "options": [
+      "A. 5",
+      "B. 4",
+      "C. 3"
+    ],
+    "answer": "A",
+    "solution": "【分析】角由一个顶点和两条边组成。一个长方形，剪去一个角，可以沿着两个相对的角剪;也可以从一个角剪到不相邻的边上的任意一点;也可以在相邻的边上任取一点剪，由此得出剩下的角的数量，再比较大小即可.\n【详解】A。![](images/d9d36860a53f342a27615d01e26e0b42a0a2b3cedb46164d90877771e5b0f386.jpg),剩 5 个角;B。![](images/7c20039991939713140466232f01dd2ab21c88ee40c1286a89445703e37c88c9.jpg),剩 4 个角;C。![](images/773ba4da1be1aaa1fb43b6074f90cd26a6cc07baf57f24e733d99ec4c15cb363.jpg),剩3 个角。5 > 4 > 3，则一个长方形剪去一个角后，最多还剩5 个角。故答案为:A",
+    "knowledge_points": [
+      "角的初步认识及辨认",
+      "平面图形的分割"
+    ],
+    "source": "24-25 二年级上·安徽黄山·期末"
+  },
+  {
+    "id": "22",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "比较下面三个角，说法正确的是( ).\n\n![](images/07f23e855f2dc4be9e9da79dfbdc5223e45db905efe97ac014e1fc397c971a8b.jpg)",
+    "options": [
+      "A. 三个角一样大",
+      "B. 左边的角最大",
+      "C. 中间的角最大"
+    ],
+    "answer": "B",
+    "solution": "【分析】三角尺上最大的角为直角，用三角板的直角进行比较测量，比直角小的就是锐角，比直角大的就是钝角，所以钝角 > 直角 > 锐角.\n【详解】左边是钝角，中间是直角，右边是锐角。钝角 > 直角 > 锐角，所以左边的角最大。故答案为:B",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征",
+      "角的大小比较"
+    ],
+    "source": "24-25 二年级上·湖北孝感·期末"
+  },
+  {
+    "id": "23",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "下面各角中，是直角的是( )。",
+    "options": [
+      "A. ![](images/4148b524f275f960cb4eea29126e3f47bb5dee83c2d5d18a2294df0a3bb4a314.jpg)",
+      "B. ![](images/aebf4d95e726c4d73509c824fb0fdf8e8b0939f5fc4c986eeb6f906feee15ed5.jpg)",
+      "C. ![](images/3b757e32feaa3fad0c1191c6342e7114475e2ba3329376682b6535b54c6f3c82.jpg)"
+    ],
+    "answer": "A",
+    "solution": "【分析】角是由1个顶点和2条边组成;用三角尺上的直角比一比和三角尺直角相同的角是直角，比三角尺直角大的角是钝角，比三角尺直角小的角是锐角，据此解答.\n【详解】用三角尺的直角比一比可得:A。是直角;B。是锐角;C。是钝角。故答案为:A",
+    "knowledge_points": [
+      "角的初步认识及辨认",
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "24-25 二年级上·陕西延安·期末"
+  },
+  {
+    "id": "24",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "如图,![](images/8ecb96b94026802084209c1bbb835561fd79bcf38d9393b6970a59231f8a3431.jpg)有( )个直角。",
+    "options": [
+      "A. 5",
+      "B. 6",
+      "C. 7"
+    ],
+    "answer": "A",
+    "solution": "【分析】从一点引出两条射线所形成的图形叫做角。和书本，黑板的角相同大小的是直角;根据直角特征数出个数即可.\n【详解】数出该图有 5 个直角。故答案为:A",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "24-25 二年级上·广西贵港·期末"
+  },
+  {
+    "id": "25",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "下面关于角的说法( )是正确的。",
+    "options": [
+      "A. 一个三角形不可能有 3 个锐角",
+      "B. 一副三角尺有一个钝角",
+      "C. 一个直角和一个锐角可以拼成一个钝角"
+    ],
+    "answer": "C",
+    "solution": "【分析】三角尺上最大的角为直角，用三角板的直角进行比较测量，比直角小的就是锐角，比直角大的就是钝角。据此逐项分析.\n【详解】A。如图![](images/2026-02-19%20231150.jpg)三角形中有3个锐角，原题说法错误。B。三角尺上最大的角为直角，没有钝角，原题说法错误。C。比直角大的就是钝角,![](images/2026-02-19%20231209.jpg)图中由一个直角和个锐角拼成了一个钝角，原题说法正确。关于角的说法正确的是：一个直角和一个锐角可以拼成一个钝角。故答案为:C",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "24-25 二年级上·湖南娄底·期末"
+  },
+  {
+    "id": "26",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面拼成的3 个角中，最大的是( )。",
+    "options": [
+      "A. ![](images/915477680675f63e2ae8771c3f6f51365eee7ba4caba2282d91b576be96989e1.jpg)",
+      "B. ![](images/63759422cac3e30d2d85293d08870569a6959b27d56d3240c774020b5d5afe73.jpg)",
+      "C. ![](images/60bc24cba3b9f09476ed961c52bc761a8da40f885af0822e1ea0f3469c24d1ee.jpg)"
+    ],
+    "answer": "B",
+    "solution": "【分析】用三角尺上的直角量一量，比一比分别看看它们和直角的关系，和直角一样大的是直角，比直角大的是钝角，比直角小的是锐角，据此解答.\n【详解】A。和直角一样大，是直角;B。比直角大，是钝角;C。比直角小，是锐角。故答案为:B",
+    "knowledge_points": [
+      "角的初步认识及辨认",
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "24-25 二年级上·湖北黄石·期末"
+  },
+  {
+    "id": "27",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "下列图形中一个角都没有的是( )。",
+    "options": [
+      "A. ![](images/2026-02-19%20231425.jpg)",
+      "B. ![](images/2026-02-19%20231516.jpg)",
+      "C. ![](images/2026-02-19%20231536.jpg)"
+    ],
+    "answer": "B",
+    "solution": "【分析】从一点引出两条射线所形成的图形叫做角。和书本，黑板的角相同大小的是直角，比直角大的是钝角，比直角小的是锐角.\n【详解】A。图形有6个角;B。图形有 0 个角;C。图形有2 个角;所以一个角都没有的是第二个图形。故答案为:B",
+    "knowledge_points": [
+      "角的初步认识及辨认"
+    ],
+    "source": "24-25 二年级上·福建三明·期末"
+  },
+  {
+    "id": "28",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面物品表面有角的是( )",
+    "options": [
+      "A. ![](images/4411e90df27d7f4514ed411bce5d4b4750e8a34d03b32626e449d0ee95bf8f85.jpg)",
+      "B. ![](images/dfc244dec798a05ec5ddc74f7e5cc90857a5240cd6fa87f58a99822f3da75b0c.jpg)",
+      "C. ![](images/1a03543d7cb9c39af50b26f6377c391371c31262aa555ca6a48cb42a3aebfd2b.jpg)"
+    ],
+    "answer": "B",
+    "solution": "【分析】角是由1 个点引出两条直直的线所组成的图形;据此判断物品表面是否有角即可.\n【详解】A。杯子的表面没有直直的线，故杯子的表面没有角;B。语文书的上面就有4 个角;故语文书表面有角;C。球的表面没有直直的线，故球的表面没有角;即，物品表面有角的是语文书。故答案为:B",
+    "knowledge_points": [
+      "角的初步认识及辨认"
+    ],
+    "source": "24-25 二年级上·内蒙古通辽·期末"
+  },
+  {
+    "id": "29",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面各图形中( )是角。",
+    "options": [
+      "A. ![](images/a8f9ae5a60fcc34622be061df62cbd76c8ad85db294cb34c89a61ab2e5f17639.jpg)",
+      "B. ![](images/ccc177ca3298d14798fff091c1f4c019a3d8ea290ad5d26a5475c4dac1f313f3.jpg)",
+      "C. ![](images/6770187a774fa182fba62366ce640652097af9897eb570cd7bcd00c6c535999a.jpg)"
+    ],
+    "answer": "B",
+    "solution": "【分析】角是由1个点引出两条直直的线所组成的图形;据此选择即可.\n【详解】A。 图不是角;B. 此图是角;C。此图不是角。故答案为:B",
+    "knowledge_points": [
+      "角的初步认识及辨认"
+    ],
+    "source": "24-25 二年级上·内蒙古巴彦淖尔·期末"
+  },
+  {
+    "id": "30",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "从一张三角形纸上剪下一个角，剩下的部分不可能有( )个角。",
+    "options": [
+      "A. 2",
+      "B. 3",
+      "C. 4"
+    ],
+    "answer": "A",
+    "solution": "【分析】由一个点引出两条直直的线所组成的图形是角。角有两条边和一个公共端点，这两条边叫做角的边，它们的公共端点叫做角的顶点。动手操作一下即可求解.\n【详解】![](images/7c20e2bcdd25ba527856dd714f6d7628643dbe1e8032f6cbfb6fc9c99ccd445d.jpg),![](images/c3eb62bad9d58c7d7dff6b8d8eb696247e4d76b6c06e6db3115b9880e1b84d9d.jpg),由图可知，从一张三角形纸上剪下一个角，剩下的部分可能有 3 个或 4 个角，不可能有 2 个角。故答案为:A",
+    "knowledge_points": [
+      "角的初步认识及辨认",
+      "平面图形的分割"
+    ],
+    "source": "24-25 二年级上·黑龙江哈尔滨·期末"
+  },
+  {
+    "id": "31",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "用放大镜看一个角，看到角的大小( )。",
+    "options": [
+      "A. 变大",
+      "B. 不变",
+      "C. 变小"
+    ],
+    "answer": "B",
+    "solution": "【分析】根据题意可知：角的大小和两边的长度无关，和两边叉开的大小有关。则放大镜看一个角放大了角的两边边长，两边叉开的大小没有改变.\n【详解】则放大镜看一个角放大了角的两边边长，两边叉开的大小没有改变。则看到的角是不变的。故答案为:B",
+    "knowledge_points": [
+      "角的初步认识及辨认"
+    ],
+    "source": "18-19 二年级上·全国·单元测试"
+  },
+  {
+    "id": "32",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面角中,( )最大。",
+    "options": [
+      "A. 钝角",
+      "B. 直角",
+      "C. 锐角"
+    ],
+    "answer": "A",
+    "solution": "【分析】三角尺上最大的角为直角，用三角板的直角进行比较测量，比直角小的就是锐角，比直角大的就是钝角，据此解答.\n【详解】锐角 < 直角 < 钝角，钝角最大。故答案为:A",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征",
+      "角的大小比较"
+    ],
+    "source": "24-25 二年级上·河南周口·期末"
+  },
+  {
+    "id": "33",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下列图形中，有两个直角的是( )。",
+    "options": [
+      "A. ![](images/69eb3d37da84fbeb7e187c4b6471f88703616ff9bafeb886973acf46b93e06ed.jpg)",
+      "B. ![](images/03f3dc1837a2e2ac847aaaa43150e9b9f57e4da331e59485f4d9b89fb6a7fb42.jpg)",
+      "C. ![](images/67fb7e47edac5c06d3ec3ace1e0f4bc963504465c5cdeda0e1ca38e25fcb8d06.jpg)",
+      "D. ![](images/3505ceb6ccdd96607471361d74a12e2917b3d90e652cde6c9c62b05461693d11.jpg)"
+    ],
+    "answer": "B",
+    "solution": "【分析】用三角尺的直角进行比对，和直角重合的是直角，大于直角的是钝角，小于直角的是锐角.\n【详解】A。4 个直角，不符合题意;B。2 个直角，符合题意。C。1 个直角，不符合题意。D。1 个直角，不符合题意。故答案为:B",
+    "knowledge_points": [
+      "角的初步认识及辨认",
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "23-24 二年级上·浙江宁波·期末"
+  },
+  {
+    "id": "34",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "下面用三角尺拼成的角中,( )是钝角。",
+    "options": [
+      "A. ![](images/42705add7f0d161eb4dbc35e2dc83d359057aff45fe02092ff24262a0b21e966.jpg)",
+      "B. ![](images/f15dc5554a484acabf32b2af0adee80aa397802a56f25ee4963eaecfc1bb88fb.jpg)",
+      "C. ![](images/e550570e4a9a7aeb000eee7ffd364b4f5ef960c32ea8ec0c748bffd44f8ecc00.jpg)"
+    ],
+    "answer": "B",
+    "solution": "【分析】![](images/606ec3bdf37d5976079e34e15378e4e7e5c0b5deec53aef0d785b8417ec43175.jpg),像这样的角都是直角，锐角比直角小，钝角比直角大，据此选择.\n【详解】A。是直角，不符合题意。B。是钝角，符合题意。C。是锐角，不符合题意。用三角尺拼成的角中,B是钝角。故答案为:B",
+    "knowledge_points": [
+      "角的初步认识及辨认"
+    ],
+    "source": "23-24 二年级上·河北石家庄·期末"
+  },
+  {
+    "id": "35",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "下面的说法中，错误的是( )。",
+    "options": [
+      "A. 用一副三角尺能拼出一个直角",
+      "B. 角的大小和两条边的长短无关",
+      "C. 线段是直的，有两个端点，可以量出长度"
+    ],
+    "answer": "A",
+    "solution": "【分析】三角板上最大的角就是直角，比直角小的角是锐角，比直角大的角是钝角。每个三角尺中，都有一个直角和两个锐角，可以拼成的角如下:![](images/71f048013b05e89fb066f21900a52f7ad0ff44fc5697d9e3c96574e239d95b70.jpg),由图可知，用一副三角尺只能拼成钝角和锐角，不能拼成直角。角的大小跟两边叉开的大小有关，与两边的长短无关。线段是一条直直的线，有限长，有两个端点，可以测量，据此判断即可.\n【详解】A。用一副三角尺不能拼出一个直角，原说法错误;B。角的大小和两条边的长短无关，说法正确;C。线段是直的，有两个端点，可以量出长度，说法正确。故答案为:A",
+    "knowledge_points": [
+      "线段的初步认识",
+      "角的初步认识及辨认",
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "23-24 二年级上·浙江台州·期末"
+  },
+  {
+    "id": "36",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "红领巾里最大的角是( )。",
+    "options": [
+      "A. 钝角",
+      "B. 锐角",
+      "C. 直角"
+    ],
+    "answer": "A",
+    "solution": "【分析】比三角尺中的直角小的角是锐角，比三角尺中的直角大的角是钝角，和三角尺中的直角相等的角是直角，据此解答.\n【详解】根据生活经验可知：红领巾里最大的角是钝角。故答案为:A",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "24-25 二年级上·西藏那曲·期末"
+  },
+  {
+    "id": "37",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "数一数，下面图形中一共有( )个角.\n\n![](images/97ab63e52443f696313a93ebb0967e84c4883f2940248cebbc888dcd00da15df.jpg)",
+    "options": [
+      "A. 3",
+      "B. 6",
+      "C. 4"
+    ],
+    "answer": "B",
+    "solution": "【分析】角的定义为：由一点引出的两条射线所组成的图形叫做角。我们可以按照一定的顺序去数这个图形中的角，避免遗漏和重复。据此解答.\n【详解】我们可以看到图中有3 个单角，相邻的两个单角组成一稍微大的角，这里一共有2 个,3 个单角组成的大角，这里只有 1 个;共: 3 + 2 + 1 = 6(个)故答案为:B",
+    "knowledge_points": [
+      "角的初步认识及辨认",
+      "数图形(数角)"
+    ],
+    "source": "19-20 二年级上·四川宜宾·期末"
+  },
+  {
+    "id": "38",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "演出结束时，表演者要对观众行鞠躬礼致谢。下面四个小朋友行鞠躬礼形成的角中，最大的是( ),最小的是( )。(填序号)\n\n![](images/21520dde2e5c1cd3e744f8767e173939a185d15dd2fe6a35d4203d977fb8d5f9.jpg)\n\n![](images/d10a986eec2b157173985cf998b2fb8583c0f53ac2920943af49b8f44b0de461.jpg)\n\n![](images/41f1bb5f38a948ec743f5cbcc9a832f8ed2dff5a480309d78cf39d5092af9053.jpg)\n\n![](images/2c298dee98c26ddf4a15d4326d6aa2f67941080c712851216f39b09b45b22b94.jpg)",
+    "options": [],
+    "answer": "④;②",
+    "solution": "【分析】在三角板上，最大的角就是直角，比直角大的角是钝角，比直角小的角是锐角;用三角板上的直角比一比就可以找到直角，锐角和钝角;通过观察和测量,①③④都比直角大，都是钝角;②是直角，故②是最小的角;比较 ①③④,谁比直角大的多，谁就是最大的角;【详解】由分析可得:①比直角大了些;不符合题意;③比直角大了一点;不符合题意;④比直角大的多;符合题意;演出结束时，表演者要对观众行鞠躬礼致谢。下面四个小朋友行鞠躬礼形成的角中，最大的是④ ,最小的是②。",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "24-25 二年级下·天津河西·期末"
+  },
+  {
+    "id": "39",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "正方形有( )条边，每个角都是( )角。",
+    "options": [],
+    "answer": "4;直",
+    "solution": "【分析】由一个顶点引出两条直直的线所组成的图形是角，和黑板，书本的角相同大小的是直角。如图为正方形，有4条边，有4 个直角.\n![](images/60a8f01ee7e2aeb90db3db1cb46a23f3ba0e9167b9706ef0a2011e7b90ed633e.jpg)\n【详解】由分析得：正方形有4 条边，每个角都是直角。",
+    "knowledge_points": [
+      "正方形的概念及特点",
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "24-25 一年级下·湖南湘潭·期中"
+  },
+  {
+    "id": "40",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "红领巾上有( )个角，分别是( )个锐角和( )个钝角。",
+    "options": [],
+    "answer": "3;2;1",
+    "solution": "【分析】角是由一个顶点引出两条直直的线组成的图形;三角尺上最大的角是直角，比直角小的角是锐角，比直角大的角是钝角。通过观察红领巾![](images/c9f548a2be5a55f236ba4b5d27f89f720e2dea78ff710c991c8cf9323ecc9812.jpg),可知红领巾上有3个角;通过用三角尺上的直角对比，可知红领巾上有 2 个锐角和1 个钝角.\n【详解】由分析可知：红领巾上有3 个角，分别是2 个锐角和1 个钝角。",
+    "knowledge_points": [
+      "角的初步认识及辨认",
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "24-25 二年级上·福建龙岩·期末"
+  },
+  {
+    "id": "41",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "图中有( )条线段，有( )个钝角.\n\n![](images/89e3f3277f0daf16b0147d4048d12d522612a81727bfa072edd76b48e4e3de01.jpg)",
+    "options": [],
+    "answer": "5;2",
+    "solution": "【分析】线段是一条直直的线，有限长，有两个端点，可以测量。据此数一数即可，数的时候要做到不重复。用三角板的直角进行比较测量，比直角小的就是锐角，比直角大的就是钝角.\n【详解】由分析可得：图中有 5 条线段，有 2 个钝角。",
+    "knowledge_points": [
+      "线段，直线，射线的认识及特征",
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "24-25 二年级上·湖北武汉·期末"
+  },
+  {
+    "id": "42",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "下图中有( )条线段，有( )个角，其中有( )个直角,( )个锐角,( )个钝角.\n\n![](images/6352e4e4acf380acd69deecea74f069f5945e3b2e8c00331335f2bb8eb684019.jpg)",
+    "options": [],
+    "answer": "5;8;2;5;1",
+    "solution": "【分析】线段有两个端点，中间是直直的线，长度可测量;比三角尺中的直角小的角是锐角，比三角尺中的直角大的角是钝角，和三角尺中的直角相等的角是直角;据此解答.\n【详解】从图上可得：有5 条线段，有8 个角，其中有2 个直角,5 个锐角,1 个钝角。",
+    "knowledge_points": [
+      "线段的初步认识",
+      "角的初步认识及辨认",
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "24-25 二年级上·贵州铜仁·期末"
+  },
+  {
+    "id": "43",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "下图中一共有( )条线段，一共有( )个角，其中有( )个锐角和( )个直角.\n\n![](images/9a3b267a2639462727521b611da7c31fc3dc34bebe96929a4887a2ff25ebca95.jpg)",
+    "options": [],
+    "answer": "6;9;2;4",
+    "solution": "【分析】线段是一条直直的线，且有两个端点;角是由一个点引出来两条直直的线所组成的图形;在三角板上，最大角就是直角，而锐角比直角小，钝角比直角大;根据图形的特征分别数一数各有多少，即可解决.\n【详解】由题意分析得：下图中一共有6 条线段，一共有9 个角，其中有2 个锐角和4 个直角。",
+    "knowledge_points": [
+      "线段的初步认识",
+      "直角，钝角，锐角的认识及特征",
+      "数图形(线段，直线，射线)",
+      "数图形(数角)"
+    ],
+    "source": "24-25 二年级上·福建龙岩·期末"
+  },
+  {
+    "id": "44",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "下图中，有( )条线段，有( )个钝角.\n\n![](images/cbf3e87d1f324590b142342d18866c6a92fcd2c948834fa84a584387784f0009.jpg)",
+    "options": [],
+    "answer": "5;2",
+    "solution": "【分析】黑板的边，桌子的边和书的边都可以看作线段，线段是直的，可以量出长度，有两个端点，数一数可知图中有多少线段填空即可;角是由1 个顶点引出两条直直的线组成的图形，在三角板上，最大的角就是直角，比直角大的角是钝角，比直角小的角是锐角;用三角板上的直角比一比就可以找到几个钝角，数一数填空即可;【详解】数一数可知：图中，有 5 条线段，有 2 个钝角。",
+    "knowledge_points": [
+      "线段的初步认识",
+      "角的初步认识及辨认",
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "24-25 二年级上·四川乐山·期末"
+  },
+  {
+    "id": "45",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "红领巾上有( )个角，其中最大的角是( )角。",
+    "options": [],
+    "answer": "3;钝",
+    "solution": "【分析】角由一个顶点和两条边组成，和书本，黑板的角相同大小的是直角，比直角大的是钝角，比直角小的是锐角，三角尺上最大的角是直角，由此解答.\n【详解】如图：红领巾上有 3 个角，其中最大的角是钝角.\n![](images/36e0669e7a4b33b3f2d113d49fe5b83f7ca92eac2b2398f554c19d144d2ae7a8.jpg)",
+    "knowledge_points": [
+      "角的初步认识及辨认",
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "24-25 二年级上·安徽黄山·期末"
+  },
+  {
+    "id": "46",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "平行四边形对角( ),对边( )。",
+    "options": [],
+    "answer": "相等;相等",
+    "solution": "【分析】平行四边形有 4 条直直的边，对边相等，对角相等，有 2 条同方向的斜边.\n【详解】平行四边形对角相等，对边相等。",
+    "knowledge_points": [
+      "平行四边形的初步认识",
+      "角的初步认识及辨认",
+      "角的大小比较"
+    ],
+    "source": "23-24 二年级下·广东汕头·期中"
+  },
+  {
+    "id": "47",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "下面用三角尺拼成的角中，是钝角的有( )个.\n\n![](images/29543b4ea2c163ce0134c0a0035cbb5d9c9718b6044204afa7c3778902b14d7e.jpg)\n①\n![](images/4d5302665722de8d3343049305d6650a53064f49929a9553475b74f9115c5afa.jpg)\n②\n![](images/18017b7584213d49cedf6de5e17cba10ee1eada33cb9f72b36574207c63ec303.jpg)\n③\n![](images/5559d969fa64397667ff29b14e9e701ef7bf9c27da3a6a25452ce3d865ed4dad.jpg)\n④",
+    "options": [],
+    "answer": "2",
+    "solution": "【分析】角是由1个顶点引出两条直直的线组成的图形，在三角板上，最大的角就是直角，比直角大的角是钝角，比直角小的角是锐角;用三角板上的直角比一比就可以找到有几个钝角;【详解】用三角板上的直角比一比可知:①是钝角;②是直角;③是钝角;④是锐角。三角尺拼成的角中，是钝角的有2个。",
+    "knowledge_points": [
+      "角的初步认识及辨认",
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "24-25 二年级上·江西鹰潭·期末"
+  },
+  {
+    "id": "48",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "如图中，一共有( )条线段和( )个角。其中,( )个直角,( )个锐角,( )个钝角.\n\n![](images/1fe0d1df04a5918a45e1d227cb22c959b65345b93d9b1a40706a14ffced2bbec.jpg)",
+    "options": [],
+    "answer": "5;8;1;5;2",
+    "solution": "【分析】黑板的边，桌子的边，书的边像这样有两个端点，中间是直直的线，都可以看作线段，数一数填空即可;角是由1 个顶点引出两条直直的线组成的图形，在三角板上，最大的角就是直角，比直角大的角是钝角，比直角小的角是锐角;用三角板上的直角比一比就可以找到几个直角，几个锐角和几个钝角;【详解】如图中，一共有5 条线段和8 个角。其中,1 个直角,5 个锐角,2 个钝角。",
+    "knowledge_points": [
+      "线段的初步认识",
+      "角的初步认识及辨认",
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "24-25 二年级上·浙江杭州·期末"
+  },
+  {
+    "id": "49",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "![](images/7ce4bd82a141553031a415ce138cd39534bdc83b08f7f33e9881afa5acda742d.jpg),左图中有( )条线段，有( )个角，其中有( )个钝角。",
+    "options": [],
+    "answer": "4;4;2",
+    "solution": "【分析】线段两端都有端点，不可延长，两个端点间的线条是直的。由一个点引出两条直直的线所组成的图形是角。角有两条边和一个公共端点，这两条边叫做角的边，它们的公共端点叫做角的顶点。三角尺上最大的角为直角，用三角板的直角进行比较测量，比直角小的就是锐角，比直角大的就是钝角.\n【详解】图中有 4 条线段，有 4 个角，其中有 2 个钝角。",
+    "knowledge_points": [
+      "线段的初步认识",
+      "角的初步认识及辨认",
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "24-25 二年级上·山东济宁·期末"
+  },
+  {
+    "id": "50",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "图中有( )条线段，有( )个直角，有( )个锐角，有( )个钝角.\n\n![](images/a94c03d53a1a260a093f5c1fbaaa7085a221e5c934efec58b8784724ddd3c9bc.jpg)",
+    "options": [],
+    "answer": "4;1;2;1",
+    "solution": "【分析】线段是一条直直的线，且有2 个端点。角是由一个点引出两条直直的线所组成的图形。在三角板上，最大的角就是直角，钝角比直角大，锐角比直角小，用三角板上的直角比一比;据此解决此题.\n【详解】由题意分析得：图中有 4 条线段，有 1 个直角，有 2 个锐角，有 1 个钝角。",
+    "knowledge_points": [
+      "线段，直线，射线的认识及特征",
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "24-25 二年级上·浙江台州·期末"
+  },
+  {
+    "id": "51",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "一个三角板上有( )个锐角,( )个直角。",
+    "options": [],
+    "answer": "2;1",
+    "solution": "【分析】观察三角板，可以发现一个三角板上有3 个角,2 个锐角,1 个直角.\n【详解】一个三角板上有2 个锐角,1 个直角。",
+    "knowledge_points": [
+      "角的初步认识及辨认",
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "23-24 二年级上·山东济宁·期末"
+  },
+  {
+    "id": "52",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "下图中有( )条线段,( )个角,( )个直角.\n\n![](images/bfac8c359d99e8c0a48eee59111936baa9e51758af0ccbc0d6d76f684568efc2.jpg)",
+    "options": [],
+    "answer": "5;8;1",
+    "solution": "【分析】线段两端都有端点，不可延长，两个端点间的线条是直的。由一个点引出两条直直的线所组成的图形是角。角有两条边和一个公共端点，这两条边叫做角的边，它们的公共端点叫做角的顶点。三角尺上最大的角为直角，用三角板的直角进行比较测量，比直角小的就是锐角，比直角大的就是钝角.\n【详解】该图中有 5 条线段,8 个角,1 个直角。",
+    "knowledge_points": [
+      "线段的初步认识",
+      "角的初步认识及辨认",
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "24-25 二年级上·湖北黄冈·期末"
+  },
+  {
+    "id": "53",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "下图中有( )条线段，有( )个锐角，有( )个直角，有( )个钝角.\n\n![](images/ee2c5aa56a768c3d8140a0769fcd5e1a15c613b340a9f8b8545536d44ef229e3.jpg)",
+    "options": [],
+    "answer": "6;2;5;2",
+    "solution": "【分析】线段有两个端点，而两个端点间的距离就是这条线段的长度。比三角尺中的直角小的角是锐角，比三角尺中的直角大的角是钝角，和三角尺中的直角相等的角是直角，据此解答.\n【详解】下图中有6 条线段，有2 个锐角，有5 个直角，有2 个钝角。![](images/4ab78091972ac9205162dd34ce4c41eb4cec606e762d33fcdb685789f3351236.jpg)",
+    "knowledge_points": [
+      "线段的初步认识",
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "24-25 二年级上·四川南充·期末"
+  },
+  {
+    "id": "54",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "如下图，有( )个直角,( )个钝角.\n\n![](images/0d39b0082f6fb0b0f076cd26bc36323efc14889cfdfc1d732f4b59d2d22a2b39.jpg)",
+    "options": [],
+    "answer": "11;2",
+    "solution": "【分析】在三角板上，最大角就是直角，钝角比直角大，锐角比直角小;据此数一数各有几个即可。如图 1，有 11 个直角;如图 2，有 2 个钝角。![](images/6c1a5485e193edcf13d3a0c9272f271615bfcf8d1553b2f2fe109e241681da50.jpg)(图 1),![](images/0cb73ffe2171946179f185743c4e3188827198daddd99bdecd9ca918c84bd30e.jpg)(图 2)\n【详解】由题意分析得：该图有 11 个直角,2 个钝角。",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征",
+      "数图形(数角)"
+    ],
+    "source": "24-25 二年级上·江西抚州·期末"
+  },
+  {
+    "id": "55",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "下图中有( )条线段,( )个锐角,( )个直角.\n\n![](images/b527b4b096f2dd5ffcc86f0ea7a40cc661bd708473c309c5d1417e5bed0fcb8b.jpg)",
+    "options": [],
+    "answer": "6;4;5",
+    "solution": "【分析】线段是一条直直的线，且有两个端点;角是由一个点引出两条直直的线所组成的图形。三角板上最大的角是直角，比直角小的是锐角。由此分别数出线段的条数，锐角和直角的个数.\n【详解】由分析可知：下图中有 6 条线段,4 个锐角,5 个直角。",
+    "knowledge_points": [
+      "线段的初步认识",
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "23-24 二年级上·浙江·期末"
+  },
+  {
+    "id": "56",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "下边图形中有( )条线段，有( )个角，有( )个直角.\n\n![](images/499a3401ae3bc4182ba66cfffa51141438a380db8be95754d1d6a91b6bb3cd5d.jpg)",
+    "options": [],
+    "answer": "3;3;1",
+    "solution": "【分析】线段两端都有端点，不可延长，两个端点间的线条是直的。由一个点引出两条直直的线所组成的图形是角。角有两条边和一个公共端点，这两条边叫做角的边，它们的公共端点叫做角的顶点。三角尺上最大的角为直角，用三角板的直角进行比较测量，比直角小的就是锐角，比直角大的就是钝角.\n【详解】下边图形中有 3 条线段，有 3 个角，有 1 个直角。",
+    "knowledge_points": [
+      "线段的初步认识",
+      "角的初步认识及辨认",
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "24-25 二年级上·吉林·期末"
+  },
+  {
+    "id": "57",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "用直角和锐角拼出的角一定是( )。",
+    "options": [],
+    "answer": "钝角",
+    "solution": "【分析】大于直角的角是钝角，小于直角的角是锐角。直角和锐角拼成的角一定大于直角则是钝角.\n【详解】由分析可得：用直角和锐角拼出的角一定是钝角。",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "24-25 二年级上·山东日照·期末"
+  },
+  {
+    "id": "58",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "下图中有( )条线段,( )个直角,( )个锐角,( )个钝角.\n\n![](images/1a109b79c3cfaa66915c70f97a61791affe2ef9c4419395cf7c10e96b7c9660a.jpg)",
+    "options": [],
+    "answer": "5;2;5;1",
+    "solution": "【分析】直线上任意两点之间的一段叫做线段。线段是直的，可以量出长度，一条线段有两个端点。![](images/2026-02-19%20234146.jpg)这样的角是直角,![](images/2026-02-19%20234203.jpg)锐角比直角小,![](images/2026-02-19%20234220.jpg)钝角比直角大。据此解答.\n【详解】根据分析，图中有 5 条线段,2 个直角,5 个锐角,1 个钝角。",
+    "knowledge_points": [
+      "线段的初步认识",
+      "角的初步认识及辨认",
+      "数图形(线段，直线，射线)",
+      "数图形(数角)"
+    ],
+    "source": "24-25 二年级上·河南南阳·期末"
+  },
+  {
+    "id": "59",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "图中有( )条线段。有( )个角，其中有( )个直角。",
+    "options": [],
+    "answer": "5;8;4",
+    "solution": "【分析】线段是有两个端点，且中间是一条直线，有限长，可测量。角由一个顶点，两条边组成;用三角尺的直角比较，和三角尺直角重合的是直角，大于直角的角是钝角，小于直角的角是锐角.\n【详解】图中有5 条线段。有8 个角，其中有4 个直角。",
+    "knowledge_points": [
+      "线段，直线，射线的认识及特征",
+      "角的初步认识及辨认",
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "24-25 二年级上·内蒙古通辽·期末"
+  },
+  {
+    "id": "60",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "图中，共有( )个直角,( )个锐角和( )个钝角.\n\n![](images/9791584598b899ed6c2d3bf83c236e9e2afe8ad314324e713d7ea3be91e2f16a.jpg)",
+    "options": [],
+    "answer": "1;1;2",
+    "solution": "【分析】用三角尺上直角比一比，找出跟直角一样大的有几个，填有几个直角，比直角小的有几个，填有几个锐角，比直角大的有几个，填几个钝角，据此解答.\n【详解】由图可知：一共有1 个直角,1 个锐角和2 个钝角。",
+    "knowledge_points": [
+      "角的初步认识及辨认",
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "24-25 二年级上·甘肃天水·期末"
+  },
+  {
+    "id": "61",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "图中有( )个直角,( )个锐角,( )个钝角.\n\n![](images/397858be0e8e50e7066f3af7d0657d0d6dc8f640e5c2871bb235a7b0e400e194.jpg)",
+    "options": [],
+    "answer": "2;1;2",
+    "solution": "【分析】角由一个顶点和两条边组成，和书本，黑板的角相同大小的是直角，比直角大的是钝角，比直角小的是锐角，三角尺中最大的角是直角，可由此比较解答.\n【详解】图中有 2 个直角,1 个锐角,2 个钝角。![](images/e81ed199070d3d5215b1f8648619fbde66d81d876144d9caf849a41e93eaa807.jpg),直角;![](images/03db7ec05aa39ca7adbfa20d566ed565471de7c9c7f46322b4bc69aaa36ba8c1.jpg),锐角;![](images/c31621c25083d7df26dd02aaadb82cf20cc70d0e46ce7f91344b06f53bb9533a.jpg),钝角。",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "24-25 二年级上·内蒙古巴彦淖尔·期末"
+  },
+  {
+    "id": "62",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "下图中有( )条线段，有( )个锐角，有( )个直角，有( )个钝角.\n\n![](images/04b8cffaf249dad7ddd11117a5778594dcb714e536f82bc4552dfe4f8adec178.jpg)",
+    "options": [],
+    "answer": "5;5;2;1",
+    "solution": "【分析】线段有2 个端点，中间是直直的线，长度可测量;角有一个顶点和两条边组成，和书本，黑板的角相同大小的是直角，比直角大的是钝角，比直角小的是锐角，三角尺上最大的角是直角，可由此比较解答.\n【详解】图中有5 条线段，有5 个锐角，有2 个直角，有1 个钝角。![](images/2026-02-19%20234345.jpg)",
+    "knowledge_points": [
+      "线段的初步认识",
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "24-25 二年级上·甘肃庆阳·期末"
+  },
+  {
+    "id": "63",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "![](images/4044c5a14b58d39fa62aa1e7f4eb711201162617d6e4373177d91022afb360b5.jpg),图中一共有( )条线段，有( )个锐角，有( )个直角,( )个钝角。",
+    "options": [],
+    "answer": "6;4;4;1",
+    "solution": "【分析】线段有两个端点，中间是直直的线，长度可测量。角由一个顶点和两条边组成，和书本，黑板的角相同大小的是直角，比直角大的是钝角，比直角小的是锐角，由此解答.\n【详解】图中一共有6 条线段，有4 个锐角，有4 个直角,1 个钝角.\n![](images/2026-02-19%20234701.jpg)",
+    "knowledge_points": [
+      "线段的初步认识",
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "24-25 二年级上·山东济宁·期末"
+  },
+  {
+    "id": "64",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "数一数下图中各有几个角.\n\n![](images/0ef876954e832af6f49be9ca9d6b3fd563d824a95723bf0d738f3224517a23b4.jpg)\n\n图中有( )个直角，有( )个锐角，有( )个钝角。",
+    "options": [],
+    "answer": "3;4;1",
+    "solution": "【分析】三角尺上最大的角为直角，用三角板的直角进行比较测量，比直角小的就是锐角，比直角大的就是钝角.\n【详解】图中有 3 个直角，有 4 个锐角，有 1 个钝角。",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "24-25 二年级上·河南周口·期末"
+  },
+  {
+    "id": "65",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "数一数下图中各有几个角.\n\n![](images/65de391e3e320f153949ad24e6665dd591e255a6636bf5c83ff4a543a5920e70.jpg)\n\n图中有( )个直角，有( )个锐角，有( )个钝角。",
+    "options": [],
+    "answer": "2;4;1",
+    "solution": "【分析】三角尺上最大的角为直角，用三角板的直角进行比较测量，比直角小的就是锐角，比直角大的就是钝角.\n【详解】图中有 2 个直角，有 4 个锐角，有 1 个钝角。",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "24-25 二年级上·河南周口·期末"
+  },
+  {
+    "id": "66",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "图形![](images/2026-02-19%20235953.jpg)中有( )个角，其中有( )个直角。",
+    "options": [],
+    "answer": "5;3",
+    "solution": "【分析】角由一个顶点，两条边组成的图形;用三角尺上的直角进行比较，和三角尺的直角重合则是直角，大于直角的是钝角，小于直角的是锐角.\n【详解】由分析可得：图形中有 5 个角，其中有 3 个直角。",
+    "knowledge_points": [
+      "角的初步认识及辨认",
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "23-24 二年级上·浙江宁波·期末"
+  },
+  {
+    "id": "67",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "一个三角尺上有( )个锐角，三角尺上最大的那个角是( )角，红领巾上最大的那个角是( )角。",
+    "options": [],
+    "answer": "2;直;钝",
+    "solution": "【分析】三角尺上最大的角为直角，用三角板的直角进行比较测量，比直角小的就是锐角，比直角大的就是钝角.\n【详解】一个三角尺上有2 个锐角，三角尺上最大的那个角是直角，红领巾上最大的那个角是钝角。三角尺如图:![](images/cb2690d8542dd70bf385466c92b1362f7406640448cd59dc0b9f3fd27dfc49fd.jpg);红领巾如图:![](images/1de03ba861d1993f4383f4bc051b72c99b9e1e62d05ddffa83c327b931951a2a.jpg)",
+    "knowledge_points": [
+      "角的初步认识及辨认",
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "23-24 二年级上·河南安阳·期末"
+  },
+  {
+    "id": "68",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "下图中有( )个角，其中有( )个锐角和( )个钝角.\n\n![](images/e703776c3cd4f1e0cdeda0c0ab8e281eb11070b92bcf3d7764645f857d6829ef.jpg)",
+    "options": [],
+    "answer": "4;2;2",
+    "solution": "【分析】根据题意可知：角由一个顶点，两条边组成。用三角尺的直角进行比较，大于直角的角是钝角，小于直角的角是锐角.\n【详解】图中有4 个角，其中有2 个锐角和2 个钝角。",
+    "knowledge_points": [
+      "角的初步认识及辨认",
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "24-25 二年级上·新疆乌鲁木齐·期中"
+  },
+  {
+    "id": "69",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "一副三角板上有( )个角，其中( )个是直角。",
+    "options": [],
+    "answer": "6;2",
+    "solution": "【分析】根据生活经验可知，一副三角板里有2 个三角板，每个三角板上都有3 个角，每个三角板内都有1 个直角，据此解答即可.\n【详解】3+3=6(个),1+1=2(个),所以一副三角板上有 6 个角，其中 2 个是直角。",
+    "knowledge_points": [
+      "角的初步认识及辨认",
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "23-24 二年级上·江西赣州·期末"
+  },
+  {
+    "id": "70",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "下图中有( )个直角,( )个锐角,( )个钝角.\n\n![](images/33899b0cb8dcce6395a3e5d3a46e1488b9d099c0eb512fa5e25d3e84ba5fb919.jpg)",
+    "options": [],
+    "answer": "2;2;3",
+    "solution": "【分析】像长方形的四个角一样直直的角是直角，比直角大的角是钝角，比直角小的角是锐角，据此得出结论即可.\n【详解】根据分析知：图中有2 个直角,2 个锐角,3 个钝角。",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "23-24 二年级上·福建福州·期末"
+  },
+  {
+    "id": "71",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "下图中有( )个角，都是( )角.\n\n![](images/f26958e9184bf7d5d89526a19839c4d5310ad7653b61f198f5578bbcd02625ad.jpg)",
+    "options": [],
+    "answer": "2;直",
+    "solution": "【分析】从一点引出两条射线所形成的图形叫做角，角有 1 个顶点,2 条边;和书本的角相同的是直角,![](images/2026-02-20%20000228.jpg)像这样的角都是直角.\n【详解】由分析可知：图中有 2 个角，都是直角。",
+    "knowledge_points": [
+      "角的初步认识及辨认"
+    ],
+    "source": "23-24 二年级上·河北保定·期末"
+  },
+  {
+    "id": "72",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "用三角板上的角比比看：下面各题左右两个角，哪个角大。哪个角小。(填写\">\"\"<\"或\"=\")\n\n![](images/3c42b3fa42b11147e4fe7d774db8248d7ab47dbcf48ceb03ab9fdd58b90cd64f.jpg)",
+    "options": [],
+    "answer": ">;=",
+    "solution": "【分析】角由一个顶点和两条边组成。三角尺上最大的角是直角，比直角大的是钝角，比直角小的是锐角。角的两条边开叉越大角越大，开叉越小角越小。由此比较即可.\n【详解】第1 组：都是锐角，左边的角开叉大，右边的角开叉小;第 2 组：两个角都是直角，一样大。",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征",
+      "角的大小比较"
+    ],
+    "source": "23-24 二年级上·河北保定·期末"
+  },
+  {
+    "id": "73",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "下图中有( )条线段,( )个直角,( )个锐角,( )个钝角.\n\n![](images/a30579c2c5d5dd3038bb09705699df102c8f60a7e04bdde1fc5bbac6533a10d0.jpg)",
+    "options": [],
+    "answer": "4;2;1;1",
+    "solution": "【分析】线段有两个端点，中间是直直的线，长度可测量。角由一个顶点和两条边组成，和书本，黑板的角相同大小的是直角，比直角大的是钝角，比直角小的是锐角，由此解答.\n【详解】下图中有 4 条线段,2 个直角,1 个锐角,1 个钝角.\n![](images/9083fce252d8060a99ef2a7611584674ac6db6bc2f7130f3e2d596f27506511b.jpg)",
+    "knowledge_points": [
+      "线段的初步认识",
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "23-24 二年级上·河北保定·期末"
+  },
+  {
+    "id": "74",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "图中( )条线段，有( )个直角，比直角小的角有( )个.\n\n![](images/0bb6863d541b28ba463ceedb8688b781306b3006fb3c4fb128c1b2573437c880.jpg)",
+    "options": [],
+    "answer": "5;2;3",
+    "solution": "【分析】线段有两个端点，且两个端点之间的直线距离就是这条线段的长度。比三角尺中的直角小的角是锐角，比三角尺中的直角大的角是钝角，和三角尺中的直角相等的角是直角，据此解答.\n【详解】从图上可得：有5 条线段，有2 个直角，比直角小的角有 3 个.\n![](images/3c7751eda569678d45e3dc8eff55786b1b011efa09108a58fbd257f3a315aac3.jpg)",
+    "knowledge_points": [
+      "角的初步认识及辨认",
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "23-24 二年级上·山东菏泽·期末"
+  },
+  {
+    "id": "75",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "在我们学过的角中，最( )的角是锐角，最( )的角是钝角。",
+    "options": [],
+    "answer": "小;大",
+    "solution": "【分析】角由一个顶点和两条边组成，和书本，黑板的角相同大小的是直角，比直角大的是钝角，比直角小的是锐角，由此解答.\n【详解】由分析可知：锐角 < 直角 < 钝角，在我们学过的角中，最小的角是锐角，最大的角是钝角。",
+    "knowledge_points": [
+      "角的初步认识及辨认",
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "23-24 二年级上·重庆丰都·期末"
+  },
+  {
+    "id": "76",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "图中一共有( )个角，其中直角有( )个，钝角有( )个.\n\n![](images/ac8f4b3ae41182a73a8fc7ea0be9a9ac7bc1a227533c83bece821cb38b51bb5c.jpg)",
+    "options": [],
+    "answer": "8;4;2",
+    "solution": "【分析】一个角有1 个顶点和2 条边，据此数一数即可知图中一共有几个角;用三角尺上的直角比一比和三角尺直角相同的角是直角，比三角尺直角大的角是钝角，比三角尺直角小的角是锐角，据此用三角尺上的直角比一比即可知有几个直角，几个钝角.\n【详解】根据角的特点，通过数一数可知图中一共有8 个角;用三角尺上的直角比一比可知有 4 个直角,2 个钝角。所以，图中一共有8 个角，其中4 个直角,2 个钝角。",
+    "knowledge_points": [
+      "角的初步认识及辨认",
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "23-24 二年级上·浙江台州·期末"
+  },
+  {
+    "id": "77",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "下图中共有( )条线段，有( )个锐角.\n\n![](images/f5666e75bf8cfb07263222ccc689854d90e6090cbff678efcc916f0b2221f6da.jpg)",
+    "options": [],
+    "answer": "5;4",
+    "solution": "【分析】根据线段的概念数出图中的线段条数即可;线段有两个端点，有限长，可测量。角是由一个公共点，两条边围成的图形。用三角尺的直角进行比较，小于直角的是锐角，据此数一数.\n【详解】由分析可得：图中共有 5 条线段，有 4 个锐角。",
+    "knowledge_points": [
+      "线段，直线，射线的认识及特征",
+      "直角，钝角，锐角的认识及特征",
+      "数图形(数角)"
+    ],
+    "source": "23-24 二年级上·福建三明·期末"
+  },
+  {
+    "id": "78",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "三个锐角拼起来一定是钝角。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】比三角尺中的直角小的角是锐角，比三角尺中的直角大的角是钝角，和三角尺中的直角相等的角是直角，据此解答.\n【详解】据分析可知：三个锐角拼起来可能是锐角，可能是直角，也可能是钝角。所以原题说法错误。故答案为: ×",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "24-25 二年级下·贵州铜仁·期末"
+  },
+  {
+    "id": "79",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "9 时整，时针和分针形成的角是直角。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】钟面上，长针是分针，短针是时针，有12 个大格，分针指向12，时针指向几就是几时。由一个点引出两条直直的线所组成的图形是角，和书本，黑板的角相同大小的是直角，由此解答.\n【详解】由分析得:![](images/053ec9fe8f793e3ee522f9cf233a669c738442f846868ae5d651e10d3224fcba.jpg),9 时整，分针指向12，时针指向9，时针和分针形成的角是直角，原题说法正确。故答案为:√",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征",
+      "整点时间与钟面指针的位置"
+    ],
+    "source": "24-25 二年级下·云南曲靖·期末"
+  },
+  {
+    "id": "80",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "判断题",
+    "difficulty": 0.65,
+    "question": "长方形和正方形的四个角都是直角( )。",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】将长方形和正方形的四个角和直角三角板上的直角作比较，无论是长方形还是正方形的四个角都和直角三角板上的直角相同，则长方形和正方形的四个角都是直角，由此进行判断即可.\n【详解】根据分析可得：长方形和正方形的四个角都是直角，原说法正确。故答案为:√",
+    "knowledge_points": [
+      "长方形，正方形，三角形和圆的初步认识",
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "24-25 一年级下·黑龙江佳木斯·期末"
+  },
+  {
+    "id": "81",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "角的大小就看画出角的两边的长短。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】角的大小与角的两条边张开的程度有关，而角的大小与边的长短没有关系。两边张开的越大，角就越大.\n【详解】角的大小与两条边的长短没有关系。原题说法错误。故答案为: ×",
+    "knowledge_points": [
+      "角的大小比较"
+    ],
+    "source": "24-25 二年级上·山东菏泽·期末"
+  },
+  {
+    "id": "82",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "一个角放在10倍的放大镜下看，这个角就增大了10倍。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】角的大小与角的两条边张开的程度有关，而角的大小与边的长短没有关系。两边张开的越大，角就越大.\n【详解】一个角放在10倍的放大镜下看，这个角的边变长了，角的大小不变。原题说法错误。故答案为: ×",
+    "knowledge_points": [
+      "角的初步认识及辨认"
+    ],
+    "source": "23-24 二年级下·广东汕头·期中"
+  },
+  {
+    "id": "83",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "所有的直角大小都是一样的。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】角由一个顶点和两条边组成，三角尺上最大的角是直角，角的大小与两条边张开的大小有关，与边的长短无关。如图，这些都是直角。由此解答.\n![](images/c37595f95831b46615f3209bc0dd97b0165cb68de7fa563643c2651336086b25.jpg)\n【详解】由分析可得：所有的直角大小都是一样的。原题说法正确。故答案为:√",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "23-24 二年级下·广东汕尾·期中"
+  },
+  {
+    "id": "84",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "判断题",
+    "difficulty": 0.65,
+    "question": "![](images/0dd6e1a7b640ebb31917da6cea2e58620d577fb092260fc0f7c6da76262d18f5.jpg),左图剪去一个角，还剩 3 个角。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】如下图可知：原图形是长方形，剪去一个角后，剩下的图形可能还剩3 个角,4 个角或5 个角;据此解决.\n![](images/36762e301e53ff1128b960672c34c0ca9967991c6418e823a7851b9c38acdddd.jpg)\n![](images/a7788cc8bf4a0beef44761ee1f8e97c8f67d62c652f767ee2999efb789c98a1c.jpg)\n![](images/344de54e480cb51a4b6512e0e9f075d6805394bc484dc0963b013601774e75a1.jpg)\n【详解】由题意分析得：左图剪去一个角，可能还剩3 个角,4 个角或 5 个角，原题说法错误。故答案为: ×",
+    "knowledge_points": [
+      "角的初步认识及辨认",
+      "平面图形的分割"
+    ],
+    "source": "24-25 二年级上·浙江台州·期末"
+  },
+  {
+    "id": "85",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "如果把一个角的两条边延长，这个角就变大了。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】角的大小与边的长短无关，与角两边的张口有关，两边的张口越大，角就越大，反之越小，据此判断即可.\n【详解】由分析可知：如果把一个角的两条边延长，这个角的大小不变，原题说法错误。故答案为: ×",
+    "knowledge_points": [
+      "角的初步认识及辨认"
+    ],
+    "source": "23-24 二年级上·浙江杭州·期末"
+  },
+  {
+    "id": "86",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "角的两边张开得大，角就大。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】角的大小与角的两条边张开的程度有关，而角的大小与边的长短没有关系。两边张开的越大，角就越大.\n【详解】角的两边张开得大，角就大。原题说法正确。故答案为:√",
+    "knowledge_points": [
+      "角的大小比较"
+    ],
+    "source": "24-25 二年级上·内蒙古通辽·期末"
+  },
+  {
+    "id": "87",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "教室门上的直角比数学书上的直角大。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】角由一个顶点和两条边组成，和书本，黑板的角相同大小的是直角。角的大小和边的长短无关，只和两条边开叉的大小有关，两条边开叉越大角越大;两条边开叉越小角越小，由此解答.\n【详解】教室门上的直角和数学书上的直角，都是直角，所有的直角都一样大，原题说法错误。故答案为: ×",
+    "knowledge_points": [
+      "角的初步认识及辨认",
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "24-25 二年级上·甘肃庆阳·期末"
+  },
+  {
+    "id": "88",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "判断题",
+    "difficulty": 0.94,
+    "question": "三角板上的三个角中，最大的一个角是钝角。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】三角尺上最大的角为直角，用三角板的直角进行比较测量，比直角小的就是锐角，比直角大的就是钝角。三角板如图:![](images/f615dd44c6fc1d658a2c13740f370c47a6ad9d1c5b452660c508696aa2a9da9a.jpg)\n【详解】三角板上的三个角中，最大的一个角是直角。原题说法错误。故答案为: ×",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "24-25 二年级上·河南·期末"
+  },
+  {
+    "id": "89",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "判断题",
+    "difficulty": 0.65,
+    "question": "把4 个角拼在一起就有 8 个角。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】角与角之间拼组的数量不是直接的加减问题，可以举例说明.\n【详解】![](images/bf0e0b1cf3365a48e79dce485c60bfd146b93b2fa7eefa3fd9879fcd0d1025f1.jpg),上图中是4 个角拼在一起的，组成的角有4+3+2+1=10(个)。原题说法错误。故答案为: ×",
+    "knowledge_points": [
+      "角的初步认识及辨认",
+      "数图形(数角)"
+    ],
+    "source": "24-25 二年级上·河南周口·期末"
+  },
+  {
+    "id": "90",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "角的开口越大，角就越小。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】角的含义：由一点引出两条直直的线所组成的图形叫做角;角的大小与角的两边的长短无关，只与角的开口大小有关。角的开口越大，角就越大，反之，角的开口越小，角就越小.\n【详解】由题意分析得：角的开口越大，角就越大。原题说法错误。故答案为: ×",
+    "knowledge_points": [
+      "角的初步认识及辨认"
+    ],
+    "source": "23-24 二年级上·河北保定·期末"
+  },
+  {
+    "id": "91",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "小马虎认为黑板上的直角和作业本上的直角同样大。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】角由一个顶点和两条边组成。角的大小与边的长短无关，只和两条边开叉的大小有关，两条边开叉越大角越大;两条边开叉越小角越小。三角尺上最大的角是直角，由此解答.\n【详解】黑板上的直角和作业本上的直角都是直角，所有的直角都一样大。所以原题说法正确。故答案为:√",
+    "knowledge_points": [
+      "角的初步认识及辨认",
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "23-24 二年级上·重庆丰都·期末"
+  },
+  {
+    "id": "92",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "判断题",
+    "difficulty": 0.65,
+    "question": "一个长方形桌面，锯掉一个角，只剩下 3 个角。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】一个长方形桌面，锯掉一个角，可能还剩下 3 个角，也可能剩下4 个角，还可能剩下5 个角(如下图)![](images/0fe7d12349276556344ed4dc45fd8b996b5745488a1cbf32d57c2cf513f4f7c4.jpg)\n【详解】由题意分析得：一个长方形桌面，锯掉一个角，可能剩下 3 个角,4 个角或 5 个角;原题说法错误。故答案为: ×",
+    "knowledge_points": [
+      "长方形的概念及特点",
+      "角的初步认识及辨认",
+      "平面图形的分割"
+    ],
+    "source": "23-24 二年级上·新疆昌吉·期末"
+  },
+  {
+    "id": "93",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "所有的锐角都比直角小，所有的直角都比钝角小。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】角由一个顶点和两条边组成。三角尺上最大的角是直角，钝角比直角大，比直角小的是锐角，也就是锐角 < 直角 < 钝角，由此解答.\n【详解】由题意分析得：所有的锐角都比直角小，所有的直角都比钝角小。原题说法正确。故答案为:√",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "23-24 二年级上·甘肃天水·期末"
+  },
+  {
+    "id": "94",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "三角尺中有三个角，其中最大的是直角。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】角由一个顶点和两条边组成，和书本，黑板的角相同大小的是直角，比直角大的是钝角，比直角小的是锐角。由此解答.\n【详解】如图为三角尺，有 1 个直角和 2 个锐角。直角 > 锐角。![](images/437ac2c4174ae334174cc68958c73f2e86c037aeee25f8d3f722aa211af2d50f.jpg),则三角尺中有三个角，其中最大的是直角。原题说法正确。故答案为:√",
+    "knowledge_points": [
+      "角的初步认识及辨认",
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "19-20 四年级上·全国·课后作业"
+  },
+  {
+    "id": "95",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "作图题",
+    "difficulty": 0.85,
+    "question": "请你画一个钝角，并把它分成一个直角和一个锐角。",
+    "options": [],
+    "answer": "见详解",
+    "solution": "【分析】角由一个顶点和两条边组成，和书本，黑板的角相同大小的是直角，比直角大的是钝角，比直角小的是锐角，三角尺上最大的角是直角，可由此作图.\n【详解】由分析作图如下:\n\n![](images/7ed77f9e415850a0baa6d9ed439c678bab645bb907e9d1c06b20400ae033566a.jpg)\n\n(画法不唯一)",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "17-18 四年级上·四川·课后作业"
+  },
+  {
+    "id": "96",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "作图题",
+    "difficulty": 0.65,
+    "question": "画一条比 8 厘米短 2 厘米的线段，并以这条线段为角的一边，画一个钝角。",
+    "options": [],
+    "answer": "见详解",
+    "solution": "【分析】线段有两个端点，中间是直直的线。线段的画法：先点一个点，然后用直尺的0 刻度线对准这个点，接着找出要画的线段的刻度，并点上一个点，最后沿着直尺把这两个点连起来，即可画出线段，要将长度标注出来。比8 厘米短 2 厘米，用 8 厘米-2 厘米计算。角由一个顶点和两条边组成，和书本，黑板的角相同大小的是直角，三角尺上最大的角是直角，比直角大的是钝角，由此解答.\n【详解】8 - 2 = 6(厘米),画 6 厘米长的线段.\n\n![](images/e3a4c10e7d03f48ce4f2fbc23387807b29a37c2bb9b1a7cfef9687fe575622b4.jpg)\n\n(画法不唯一)",
+    "knowledge_points": [
+      "用直尺画线段",
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "24-25 二年级上·安徽黄山·期末"
+  },
+  {
+    "id": "97",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "作图题",
+    "difficulty": 0.65,
+    "question": "(1)下面的图形里原有( )个角，有( )个直角.\n\n(2)在图形里加画一条线段，使它增加 3 个直角.\n\n![](images/3e409e332876330d0840fbaa84bf1893c18250e3e942ba38ab6602bcbdf9486e.jpg)",
+    "options": [],
+    "answer": "4;2;见详解",
+    "solution": "【分析】(1)角是由 1 个顶点引出两条直直的线组成的图形;在三角板上，最大角就是直角。(2)在图形的右边上取一个点，使得这个点到右边下端点的长度等于左边的长度，然后把这点与左边的上端点连起来，就可以使图形增加3 个直角.\n【详解】由题意分析得:(1)下面的图形里原有 4 个角，有 2 个直角。(2)在图形里加画一条线段，使它增加 3 个直角，如下图.\n![](images/16683d9db1a16da01b6a23d607550ed3f0ce52a9a26262fb5efdcfcbd23feffb.jpg)",
+    "knowledge_points": [
+      "角的初步认识及辨认",
+      "直角，钝角，锐角的认识及特征",
+      "平面图形的分割"
+    ],
+    "source": "24-25 二年级上·辽宁抚顺·期末"
+  },
+  {
+    "id": "98",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "解答题",
+    "difficulty": 0.65,
+    "question": "下图中有( )条线段,( )个角，在图形里加画一条线段，使它增加4 个直角.\n\n![](images/aecf20f7b4841d742cb5ea182c9dd433d43229227efb9cd62256d8b560a4d41e.jpg)",
+    "options": [],
+    "answer": "4;4;作图见详解",
+    "solution": "【分析】线段是直直的，有两个端点;角是由一个顶点两条边围成的图形，像长方形的四个角一样直直的角是直角，据此得出结论即可.\n【详解】根据分析知：图中有4 条线段,4 个角，使它增加4 个直角，作图如下:\n\n![](images/71ecf5a9dac64f2042498d524f85d5b13488744a0fe877ad1e6f76e6b4a5fe0c.jpg)",
+    "knowledge_points": [
+      "线段，直线，射线的认识及特征",
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "24-25 二年级上·湖北随州·期末"
+  },
+  {
+    "id": "99",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "解答题",
+    "difficulty": 0.65,
+    "question": "如图中有( )个直角，有( )个锐角，还有( )个钝角。请你在下图形中加画一条线段，使它增加3 个直角.\n\n![](images/ef18bc41e62a391bce4067fe7aa92dd9e811f6ce71f37334765514e64905c364.jpg)",
+    "options": [],
+    "answer": "0;2;2;见详解",
+    "solution": "【分析】三角尺上最大的角为直角，用三角板的直角进行比较测量，比直角小的就是锐角，比直角大的就是钝角。过上面两个顶点画直角可以满足要求.\n【详解】原来的图中有0 个直角，有2 个锐角，还有2 个钝角。在图形中加画一条线段，使它增加3 个直角:\n![](images/068ad09855c7ad0e618562dcf0a0f4aa9882d6e2217a85922fbbf878e4ebe1b8.jpg)",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征",
+      "平面图形的分割"
+    ],
+    "source": "24-25 二年级上·黑龙江哈尔滨·期末"
+  },
+  {
+    "id": "100",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "解答题",
+    "difficulty": 0.65,
+    "question": "图中有( )个直角，请借助三角尺量一量，并做好直角标记.\n\n![](images/7c7e8d195f1ab667567f60f7560203f797a94934d56fbf0e77951ff88bc1737f.jpg)",
+    "options": [],
+    "answer": "3;图见详解",
+    "solution": "【分析】比三角尺上的直角小的角是锐角，和三角尺上的直角同样大的角是直角，比三角尺上的直角大的角是钝角;在三角尺上，最大角就是直角;据此借助三角尺的直角量量，并做好直角标记即可.\n【详解】图中有 3 个直角。如下图所示:\n![](images/d38dd677d7ef9df310aef02efa3fdafd3a00dad198a202f945fa4a94748dc877.jpg)",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "23-24 三年级上·北京顺义·期末"
+  },
+  {
+    "id": "101",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面的四个角中,( )是钝角。",
+    "options": [
+      "A. ![](images/bb8c5f43474de745ea36dbda99bbd9f8624c5ccf7eef787a8a762172ed306753.jpg)",
+      "B. ![](images/98fa0433644e5b66571bccdf30d632b09f3d13c257c0652610477198ec23702e.jpg)",
+      "C. ![](images/d153fe53deac2a52061ee900578e9d81868d8d571ddb0367cf90b1b751264805.jpg)",
+      "D. ![](images/66df1826e009442db1c8846e1431325ff2a0769e90fe0cdd2ff937e2989d4cad.jpg)"
+    ],
+    "answer": "B",
+    "solution": "【分析】锐角比直角小，钝角比直角大。据此解答.\n【详解】A。这个角是锐角。不满足题意。B。这个角是钝角。满足题意。C。这个角是直角。不满足题意。D。这个角是锐角。不满足题意。故答案为:B",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "23-24 三年级上·北京平谷·期末"
+  },
+  {
+    "id": "102",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下列关于角的描述，正确的是( )。",
+    "options": [
+      "A. 每个三角尺上都有三个锐角",
+      "B. 黑板上的直角比三角尺的直角大",
+      "C. 所有的锐角都比钝角小"
+    ],
+    "answer": "C",
+    "solution": "【分析】角由一个顶点和两条边组成，和书本，黑板的角相同大小的是直角，比直角大的是钝角，比直角小的是锐角。三角尺上最大的角是直角，由此解答.\n【详解】A。![](images/1c9dff13852aac2ea6740801f75bc6c74039656cff22ecba65785b89718e551e.jpg)如图为三角尺，每个三角尺上都有两个锐角，原说法错误;B。黑板上的直角和三角尺上的直角，都是直角，所有的直角都一样大，原说法错误;C。钝角 > 直角 > 锐角，所有的锐角都比钝角小，原说法正确。所以正确的是所有的锐角都比钝角小。故答案为:C",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "23-24 二年级上·福建福州·期末"
+  },
+  {
+    "id": "103",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面用三角尺拼出来的角是锐角的是( )。",
+    "options": [
+      "A. ![](images/6cff40aa0c6245ed45f80381eef62519a002b5939fed3a26abb75bf16c93d594.jpg)",
+      "B. ![](images/8473668eb3bd3989e50f0014f9a827e0e348bfb075616ae1bec2a907f04b925b.jpg)",
+      "C. ![](images/85fc88cbd92a150b4d3502043bbcd48184fd9609e56299df2e4df6ac8176ca00.jpg)"
+    ],
+    "answer": "C",
+    "solution": "【分析】角由一个顶点和两条边组成，和书本，黑板的角相同大小的是直角;比直角大的是钝角;比直角小的是锐角。三角尺上最大的角是直角，可由此比较解答.\n【详解】A。由两个锐角拼成的钝角，不符合题意;B。由两个锐角拼成的钝角，不符合题意;C。由两个锐角拼成的锐角，符合题意。C 拼出来的角是锐角。故答案为:C",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "23-24 二年级上·福建三明·期末"
+  },
+  {
+    "id": "104",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面灯笼杆和灯笼绳形成的三个角中，最大的是( )。",
+    "options": [
+      "A. ![](images/ae21101ffb1b37906342842c834c9d135000289da30691d28eedb65031b462ae.jpg)",
+      "B. ![](images/d3b79bc8f374374a9b6fef2d3277cf7408db6ffa76189ca2005523b6050d9785.jpg)",
+      "C. ![](images/96a1c7e94825d8c3223f3e6788f040196dad0d0e576e8f26887a3146bbfe2b1f.jpg)"
+    ],
+    "answer": "C",
+    "solution": "【分析】根据题意可知：用三角尺的直角进行比对即可。和直角重合的就是直角，大于直角的是钝角，小于直角的是锐角。即锐角 < 直角 < 钝角，钝角最大.\n【详解】A。和直角重合，是直角，则不符合题意;B。小于直角为锐角，则不符合题意;C。大于直角为钝角，则符合题意。故答案为:C",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "23-24 二年级上·河南安阳·期末"
+  },
+  {
+    "id": "105",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下列说法正确的是( )。",
+    "options": [
+      "A. 角的两边越长，角越大",
+      "B. 所有直角都一样大",
+      "C. 所有锐角都一样大"
+    ],
+    "answer": "B",
+    "solution": "【分析】角由一个顶点和两条边组成，和书本，黑板的角相同大小的是直角;比直角小的是锐角。角大小和边的长短无关，只和两条边开叉的大小有关，两条边开叉越大角越大;两条边开叉越小角越小，由此解答.\n【详解】A。角的两边和角的大小无关，原说法错误;B。所有的直角都一样大，原说法正确;C。比直角小的角是锐角，锐角有很多种，原说法错误。所以说法正确的是所有直角都一样大。故答案为:B",
+    "knowledge_points": [
+      "角的初步认识及辨认",
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "23-24 二年级上·河南安阳·期末"
+  },
+  {
+    "id": "106",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "一个角，如果它的两边都加长 3 厘米，那么这个角( )。",
+    "options": [
+      "A. 变大",
+      "B. 变小",
+      "C. 不变"
+    ],
+    "answer": "C",
+    "solution": "【分析】角由一个顶点和两条边组成。角的大小和边的长短无关，只和两边开叉的大小有关，两边开叉越大角越大;两边开叉越小角越小，由此解答.\n【详解】由分析可知，一个角，如果它的两边都加长3 厘米，那么这个角不变。故答案为:C",
+    "knowledge_points": [
+      "角的初步认识及辨认"
+    ],
+    "source": "24-25 二年级上·河南南阳·期中"
+  },
+  {
+    "id": "107",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面的图形,( )是角。",
+    "options": [
+      "A. ![](images/9c2f0fe71ddc874c27ce26466058fca229fa9bc3ae806c983aa7e37a897a6065.jpg)",
+      "B. ![](images/6236e5cf54ec6f18366e16129aafc03688557aae7eac98baa72ca95ec7709e29.jpg)",
+      "C. ![](images/34e941459e2f0f7bc19ba0199cfa2343d3423d9b1a29e2e7be218fe83eb38626.jpg)"
+    ],
+    "answer": "C",
+    "solution": "【分析】由一个点引出两条直直的线所组成的图形是角，这个公共端点是角的顶点，两条直直的线是角的边，由此解答.\n【详解】A。没有公共端点，不是角;B。不是两条直直的边，不是角。C。有公共端点，是两条直直的边，是角;所以C是角。故答案为:C",
+    "knowledge_points": [
+      "角的初步认识及辨认"
+    ],
+    "source": "23-24 二年级上·重庆永川·期末"
+  },
+  {
+    "id": "108",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "一个三角形内最多有( )个直角，至少有( )个锐角。",
+    "options": [
+      "A. 1;2",
+      "B. 3;2",
+      "C. 2;2"
+    ],
+    "answer": "A",
+    "solution": "【分析】在三角板上，最大角就是直角，锐角比直角小，钝角比直角大。一个三角形内最多有1 个直角，至少有2 个锐角，如图![](images/29fad14c459a91d206873cdabc8540f19a4f76fb49dbdf981c38d5c1f70dd118.jpg)一个三角形内最多有3 个锐角，如图![](images/e84cf40d9df82e3d7cd890a1fa97c98338d1325cfd8805ba783aa10d9ccdf85f.jpg)\n【详解】由题意分析得：一个三角形内最多有 1 个直角，至少有 2 个锐角。故答案为:A",
+    "knowledge_points": [
+      "长方形，正方形，三角形和圆的初步认识",
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "23-24 二年级上·云南红河·期末"
+  },
+  {
+    "id": "109",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面图形中,( )没有角。",
+    "options": [
+      "A. ![](images/cf2bcfd295b1858f20db960bd4e821e40481c7003a0ecf7cce2318cec7c9a8f8.jpg)",
+      "B. ![](images/875aa027982183e50b581ea0b7dd003c18586c063c7c35c4c5f4c9fe5e409c1b.jpg)",
+      "C. ![](images/9b4ebeb8137751b0877216ce314389aa1bad41027d77ef5f1817c8771eb10f3e.jpg)"
+    ],
+    "answer": "A",
+    "solution": "【分析】由一个点引出两条直直的线所组成的图形是角，这个点是角的顶点，两条直直的线是角的边，由此解答.\n【详解】A。没有顶点，没有直直的边，没有角;B。有3 个角;C。有 2 个角。A没有角。故答案为:A",
+    "knowledge_points": [
+      "角的初步认识及辨认"
+    ],
+    "source": "24-25 二年级上·河南漯河·期中"
+  },
+  {
+    "id": "110",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "下列说法错误的是( )。",
+    "options": [
+      "A. 锐角 < 直角 < 钝角",
+      "B. 任何一个角都有两条边和一个顶点",
+      "C. 用放大镜看角，这个角就变大了"
+    ],
+    "answer": "C",
+    "solution": "【分析】看选项，逐项分析。在三角板上，最大角就是直角，锐角比直角小，钝角比直角大;钝角 > 直角 > 锐角。角是由1 个点引出两条直直的线所组成的图形，这个点是顶点，两条直直的线是角的两边。用放大镜看角，角的两边长度会变，但是两边之间的夹角大小没变，所以这个角度不变.\n【详解】A。锐角 < 直角 < 钝角，原说法正确。B。任何一个角都有两条边和一个顶点，原说法正确。C。用放大镜看角，这个角的大小不变，原说法错误。故答案为:C",
+    "knowledge_points": [
+      "角的初步认识及辨认",
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "24-25 二年级上·河南周口·期中"
+  },
+  {
+    "id": "111",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "下列图形中不是直角的是( )。",
+    "options": [
+      "A. ![](images/831cfbc7def307ff0b17e2d1bf115f18e32896935b75dfdfa0b6d6507f30743e.jpg)",
+      "B. ![](images/8aa6021e007aaa41416adf54c3dc45d609a94daa3c119a0b5938d07e4c973148.jpg)",
+      "C. ![](images/2026-02-20%20010107.jpg)"
+    ],
+    "answer": "B",
+    "solution": "【分析】和书本，黑板的角相同大小的是直角，比直角大的是钝角，比直角小的是锐角，三角尺中最大的角是直角，可由此比较解答.\n【详解】根据分析:A。是直角;B。比直角大，是钝角;C。是直角;所以不是直角的是B。故答案为:B",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "24-25 二年级上·山东青岛·期中"
+  },
+  {
+    "id": "112",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "下面图( )拼出的角是钝角。",
+    "options": [
+      "A. ![](images/5936fe13e48e9e6311ba5f59ee51e7b39d80ffe2f0fa80adf759e3404f663e60.jpg)",
+      "B. ![](images/59f2bff62e80c5a9bf4ba4043de2a01cb71d4aa6f78f581e4ada608c631323ef.jpg)",
+      "C. ![](images/c9705e8b1fe8c86c9e11f27573504c9cc6d6ec1ffab00094f4568bb9e2434892.jpg)"
+    ],
+    "answer": "C",
+    "solution": "【分析】![](images/2026-02-20%20010530.jpg)像这样的图形都是直角，每个三角尺上都有一个直角，要知道一个角是不是直角可以用三角尺上的直角比比。像这样的图形都是锐角，锐角比直角小，像这样的图形都是钝角，钝角比直角大。据此解答.\n【详解】A。拼出的是锐角，不符合题意;B。拼出的是直角，不符合题意;C。拼出的是钝角，符合题意。故答案为:C",
+    "knowledge_points": [
+      "角的初步认识及辨认",
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "24-25 二年级上·广东汕头·期中"
+  },
+  {
+    "id": "113",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面用三角尺拼成的角中,( )是锐角。",
+    "options": [
+      "A. ![](images/5900466a9f2e1152b233b7a1b23eb8c9c6b3d430eb4da757cdb3884d315afb6e.jpg)",
+      "B. ![](images/b2cd95d33a69c84f55628c9394a200936a104f98ab72959300b2c23660388887.jpg)",
+      "C. ![](images/7600d5f15b9f6d4a14ececcd81d55a8f2fccacef31a590c7e1f1a905e649f017.jpg)"
+    ],
+    "answer": "B",
+    "solution": "【分析】三角板中有一个直角，两个锐角，用三角尺的直角进行比较，和直角重合则是直角，大于直角的是钝角，小于直角的是锐角.\n【详解】A。用三角尺的直角比较，拼在一起的角大于直角，是钝角，故不符合题意。B。两个最小的锐角拼在一起，用三角尺的直角对比，小于直角，则是锐角，符合题意。C。直角和锐角拼在一起的角大于直角，是钝角，不符合题意。故答案为:B",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "24-25 二年级上·广西南宁·期中"
+  },
+  {
+    "id": "114",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "下面的说法正确的是( )。",
+    "options": [
+      "A. ![](images/9ab58b130bd40dc973054463c0068fca9f09420301390008cffea74fe538ea45.jpg)有 6 个角",
+      "B. ![](images/9d338bb3fdcaa77b6b276e272988e4204bc9c01d27565e55d76e71d6691be611.jpg)有 4 个角",
+      "C. ![](images/bfeca83e73b019010b31933b4103f518a9f52eb0df019bbbb7273542d31a2dc8.jpg)有 2 个角"
+    ],
+    "answer": "A",
+    "solution": "【分析】角是由一个点引出两条直直的线所组成的图形，根据角的特征判断选择即可.\n【详解】A。有 6 个角，选项中说法正确，符合题意;B. 不存在由一个点引出两条直直的线所组成的图形，图中没有角，选项中说法错误，不符合题意;C。有 3 个角，选项中说法错误，不符合题意。故答案为:A",
+    "knowledge_points": [
+      "角的初步认识及辨认",
+      "数图形(数角)"
+    ],
+    "source": "23-24 二年级上·重庆秀山·期末"
+  },
+  {
+    "id": "115",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面的说法正确的是( )。",
+    "options": [
+      "A. ○有 6 个角",
+      "B. □有 4 个角",
+      "C. ![](images/2026-02-20%20011234.jpg)有 2 个角"
+    ],
+    "answer": "B",
+    "solution": "【分析】已知角是由一个顶点向不同方向画出的两条直线组成的，根据角的特点和选项中给出的图形即可得出答案.\n【详解】A。圆形是没有角的，原题说法错误。B。正方形有4 个角，原题说法正确。C。直线没有角，原题说法错误。故答案为:B",
+    "knowledge_points": [
+      "正方形的概念及特点",
+      "圆的概念及特点",
+      "角的初步认识及辨认"
+    ],
+    "source": "23-24 二年级上·重庆秀山·期末"
+  },
+  {
+    "id": "116",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下图中,( )是角。",
+    "options": [
+      "A. ![](images/e2ed71339a7949f93372f77dd286ad9c528a3dae4c8270ecb154007a262407a6.jpg)",
+      "B. ![](images/a942062abacb88836dc53228bbb28a5d69e2b623453d0fc609c0de728de4b370.jpg)",
+      "C. ![](images/934fc15256b2c81fc8a223d70f94a0b07076de77479d5d1c6b5cb4284cfbc69e.jpg)"
+    ],
+    "answer": "B",
+    "solution": "【分析】由一个点引出两条直直的线所组成的图形是角，这个公共的端点是角的顶点，两条直直的线是角的边，由此解答.\n【详解】A。没有公共端点，不是角;B。是角;C。不是两条直直的边，不是角。B是角。故答案为:B",
+    "knowledge_points": [
+      "角的初步认识及辨认"
+    ],
+    "source": "23-24 二年级上·浙江温州·期末"
+  },
+  {
+    "id": "117",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.94,
+    "question": "一副(两个)三角板上有( )个直角。",
+    "options": [
+      "A. 1",
+      "B. 2",
+      "C. 3"
+    ],
+    "answer": "B",
+    "solution": "【分析】一个三角尺中有1 个直角,2 个锐角，则题干中说的一副则有 2 个三角尺，则直角有 2 个.\n【详解】由分析可得：一副(两个)三角板上有2 个直角。故答案为:B",
+    "knowledge_points": [
+      "角的初步认识及辨认",
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "24-25 二年级上·河北沧州·期中"
+  },
+  {
+    "id": "118",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面图形中,( )是角。",
+    "options": [
+      "A. ![](images/2026-02-20%20011828.jpg)",
+      "B. ![](images/2026-02-20%20011849.jpg)",
+      "C. ![](images/2026-02-20%20011905.jpg)"
+    ],
+    "answer": "B",
+    "solution": "【分析】从一点引出两条射线所形成的图形叫做角。这一点是角的顶点，两条射线是角的边。据此解决即可.\n【详解】A。两条边不是直直的线，这不是角;B。这是角;C。没有顶点，这不是角。故答案为:B",
+    "knowledge_points": [
+      "角的初步认识及辨认"
+    ],
+    "source": "24-25 二年级上·河北沧州·期中"
+  },
+  {
+    "id": "119",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "用放大镜看一个直角，看到的结果( )。",
+    "options": [
+      "A. 还是直角",
+      "B. 会变大成钝角",
+      "C. 会变小成锐角"
+    ],
+    "answer": "A",
+    "solution": "【分析】角由一个顶点和两条边组成，和书本，黑板的角相同大小的是直角。角的大小和边的长短无关，只和两边开叉的大小有关，两边开叉越大角越大;两边开叉越小角越小，由此解答.\n【详解】用放大镜看一个直角，角的两条边变长了，角的大小不变，看到的结果还是直角。故答案为:A",
+    "knowledge_points": [
+      "角的初步认识及辨认",
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "24-25 二年级上·山东济南·期中"
+  },
+  {
+    "id": "120",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "图中有( )个角.\n\n![](images/1c7a7c0ec879cf8d1e2f1ca07aab7add9c91560fa05c5a0d5f92ffd038e26ff3.jpg)",
+    "options": [
+      "A. 3",
+      "B. 2",
+      "C. 4"
+    ],
+    "answer": "A",
+    "solution": "【分析】由一个点引出两条直直的线所组成的图形是角，这个点是角的顶点，两条直直的线是角的边，由此数出角的数量即可.\n【详解】图中有3 个角。![](images/29bfb10d23804e65c76ef4df15b58498eed867a11a1afe8301a1b230297025ba.jpg)故答案为:A",
+    "knowledge_points": [
+      "角的初步认识及辨认"
+    ],
+    "source": "24-25 二年级上·河南三门峡·期中"
+  },
+  {
+    "id": "121",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "将( )拼在一起，一定可以拼出一个钝角。",
+    "options": [
+      "A. 2 个直角",
+      "B. 2 个锐角",
+      "C. 1 个直角和1 个锐角"
+    ],
+    "answer": "C",
+    "solution": "【分析】三角尺上最大的角为直角，用三角板的直角进行比较测量，比直角小的就是锐角，比直角大的就是钝角，一个直角和一个锐角拼成的角一定比直角大，据此解答即可.\n【详解】A。2 个直角，拼成的角比钝角大;B。2 个锐角可能拼成一个锐角，也可能拼成一个直角，也可能拼成一个钝角;C。1 个直角和 1 个锐角一定能拼成一个钝角。所以 1 个直角和 1 个锐角，一定能拼成一个钝角。故答案为:C",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "24-25 二年级上·河北唐山·期中"
+  },
+  {
+    "id": "122",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面说法正确的是( )。",
+    "options": [
+      "A. 角的两条边越长，角越大",
+      "B. 在放大镜下看角，角变大了",
+      "C. 角的两条边张开得越大，角越大"
+    ],
+    "answer": "C",
+    "solution": "【分析】角由一个顶点和两条边组成。角的大小和边的长短无关，只和两边开叉的大小有关，两条边开叉越大角越大;两条边开叉越小角越小，由此解答.\n【详解】A。角的两条边的长度和角的大小无关，原说法错误;B。在放大镜下看角，角的边变长了，角的大小不变，原说法错误;C。角的两条边张开得越大，角越大，原说法正确。所以说法正确的是角的两条边张开得越大，角越大。故答案为:C",
+    "knowledge_points": [
+      "角的初步认识及辨认"
+    ],
+    "source": "24-25 二年级上·河北唐山·期中"
+  },
+  {
+    "id": "123",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "![](images/d9212e67dc089149a97fa78c4e9dad0c65a3947d209bbd10e1c41c171a2d7d58.jpg)左图沿图中虚线剪去下面一个角后，还剩( )个角。",
+    "options": [
+      "A. 1",
+      "B. 3",
+      "C. 4"
+    ],
+    "answer": "B",
+    "solution": "【分析】由一个点引出两条直直的线所组成的图形是角，这个点是角的顶点，两条直直的线是角的边。由此数出剩下的角的数量即可.\n【详解】![](images/2026-02-20%20012133.jpg)左图沿图中虚线剪去下面一个角后，还剩 3 个角。故答案为:B",
+    "knowledge_points": [
+      "角的初步认识及辨认"
+    ],
+    "source": "24-25 二年级上·福建厦门·期中"
+  },
+  {
+    "id": "124",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "一个直角和一个锐角可以拼成( )。",
+    "options": [
+      "A. 锐角",
+      "B. 直角",
+      "C. 钝角"
+    ],
+    "answer": "C",
+    "solution": "【分析】角由一个顶点和两条边组成。和书本，黑板的角相同大小的是直角，比直角大的是钝角，比直角小的是锐角，由此解答.\n【详解】如图：一个直角和一个锐角可以拼成钝角。![](images/2026-02-20%20012218.jpg)故答案为:C",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "24-25 二年级上·福建厦门·期中"
+  },
+  {
+    "id": "125",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面说法中，正确的是( )。",
+    "options": [
+      "A. 操场跑一圈，约200 厘米",
+      "B. 角的边越长，这个角就越大",
+      "C. 方桌上的直角和三角尺上的直角一样大"
+    ],
+    "answer": "C",
+    "solution": "【分析】根据生活经验，对长度单位和数据大小的认识可知：计量较长的物体用\"米\"作单位，二年级学生双臂展开的长度大约是1米，计量比较短的物体长度，通常用\"厘米\"作单位，食指的宽大约是1厘米，所以计量操场的长度用\"米\"作单位比较合适;角由一个点和两条边组成。角的大小和边的长短无关，只和两边开叉的大小有关，两边开叉越大角越大，两边开叉越小角越小，由此解答.\n【详解】A。操场跑一圈，约200米，原说法错误;B。角的边长和角的大小无关，原说法错误;C。方桌上的直角和三角尺上的直角都是直角，两个角的边开叉的大小相同，即所有的直角都一样大，原说法正确。故答案为:C",
+    "knowledge_points": [
+      "角的初步认识及辨认",
+      "直角，钝角，锐角的认识及特征",
+      "角的大小比较",
+      "长度单位的选择"
+    ],
+    "source": "24-25 二年级上·福建三明·期中"
+  },
+  {
+    "id": "126",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "下面用三角尺拼成的三个角中，最大的角是( )。",
+    "options": [
+      "A. ![](images/46b7e616cd24705204ea2e7009530524b156b1cf054b97289faa2f447cb3aa9f.jpg)",
+      "B. ![](images/69ace44eac29c6f8010f86ccf882ffe36aa936a669c32ba90cfc1c8d914df1c3.jpg)",
+      "C. ![](images/8501ab9a4b6e366fc9a2af2b67489a314fbe62c50cfceeaa961897ae6390e979.jpg)"
+    ],
+    "answer": "A",
+    "solution": "【分析】角由一个顶点和两条边组成，和书本，黑板的角相同大小的是直角，比直角大的是钝角，比直角小的是锐角。三角尺上最大的角是直角，可由此解答.\n【详解】A。是由一个直角和一个锐角拼成的钝角;B。是由两个锐角拼成的直角;C。是由两个锐角拼成的钝角。钝角 > 直角。A和C中都有一个相同的锐角，比较另一个角即可。A中另一个角是直角,C 中另一个角是锐角，直角 > 锐角。所以组成的角中最大的角是A。故答案为:A",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征",
+      "角的大小比较"
+    ],
+    "source": "24-25 二年级上·福建三明·期中"
+  },
+  {
+    "id": "127",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "关于下图两个角，说法正确的是( ).\n\n![](images/7ad2e10287f0f424221a37a8755eca29975c04f2b40c796de1ade281cbf973d9.jpg)\n\n![](images/48ca34f730ae6397a715f3906803ed19a101a30f011c495ac423dc39ecd6e9e4.jpg)",
+    "options": [
+      "A. 角 B > 角 A,因为角 B 的边比较长",
+      "B. 角 A < 角 B,因为角 A 的边比较短",
+      "C. 角 A = 角 B,因为直角都一样大，与边的长短无关",
+      "D. 角 A 和角 B 无法比较"
+    ],
+    "answer": "C",
+    "solution": "【分析】角由一个顶点和两条边组成，角的大小和边的长短无关，只和两边开叉的大小有关，两边开叉越大角越大;两边开叉越小角越小，三角尺上最大的角是直角，可由此比较解答.\n【详解】由分析比较可知：角 A 和角 B 都是直角，所有的直角一样大。所以说法正确的是角 A = 角 B,因为直角都一样大，与边的长短无关。故答案为:C",
+    "knowledge_points": [
+      "角的初步认识及辨认",
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "24-25 二年级上·福建龙岩·期中"
+  },
+  {
+    "id": "128",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面拼成的角中,( )是锐角。",
+    "options": [
+      "A. ![](images/42bbdd4affc2dcb837c2671d0f052a4f57ccce647317533b4a9e9113328d29c3.jpg)",
+      "B. ![](images/2190c0896b018b2b5375af5c09c8a2d51ddea5307e540854658935ed681eee86.jpg)",
+      "C. ![](images/80d6aebdf02674fff99676737907104a9c301bf28ae582e9562d889119d15259.jpg)"
+    ],
+    "answer": "B",
+    "solution": "【分析】角由一个顶点和两条边组成，和书本，黑板的角相同大小的是直角，比直角小的是锐角，比直角大的是钝角，三角尺上最大的角是直角，由此解答.\n【详解】A。这个角是由一个直角和一个锐角拼成的钝角;B。这个角是由两个锐角拼成的锐角;C。这个角是由两个锐角拼成的直角。所以B是锐角。故答案为:B",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "24-25 二年级上·河南南阳·期中"
+  },
+  {
+    "id": "129",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "在![](images/2026-02-20%20012631.jpg)中一共有( )个角。",
+    "options": [
+      "A. 3",
+      "B. 4",
+      "C. 6"
+    ],
+    "answer": "C",
+    "solution": "【分析】根据题意，图中单独的角有3个，由两个单独的角组成的角有2个，由三个单独的角组成的角有1个，则一共有 3 + 2 + 1 = 6 个角.\n【详解】由分析可知，图中一共有 6 个角。故答案为:C",
+    "knowledge_points": [
+      "角的初步认识及辨认",
+      "数图形(数角)"
+    ],
+    "source": "24-25 二年级上·湖北武汉·期中"
+  },
+  {
+    "id": "130",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "下面拼成的3 个角，最大的是( )。",
+    "options": [
+      "A. ![](images/f278cfccfbdbad94052e842420dde2004042695d9b1b137b5e726be2efa66378.jpg)",
+      "B. ![](images/0cd1f144dbfae2ae9096dc6aebd7fee7545be8359e5e727ed65f207bd2ce35c2.jpg)",
+      "C. ![](images/0f071ed399f2ec1d263c858b2bfc5311535f960c1d9dcc309919d7a71e31bcd6.jpg)"
+    ],
+    "answer": "A",
+    "solution": "【分析】角由一个顶点和两条边组成，和书本，黑板的角相同大小的是直角，比直角大的是钝角，比直角小的是锐角。也就是锐角 < 直角 < 钝角，三角板中最大的角是直角，角的大小和两边开叉大小有关，两边开叉越大角越大，由此解答.\n【详解】A。是由一个最大的锐角和一个直角拼成的钝角;B。是由两个锐角拼成的锐角，还有一个直角和较大的锐角拼成的钝角;C。是由两个锐角拼成的锐角，还有一个直角和较大的锐角拼成的钝角;钝角 > 锐角。都有直角的，比较另一个锐角即可,A中的锐角开叉比其它的锐角开叉大，也就是 A 拼成的角最大。故答案为:A",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征",
+      "角的大小比较"
+    ],
+    "source": "24-25 二年级上·河南南阳·期中"
+  },
+  {
+    "id": "131",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面图形中，哪个不是角。( )",
+    "options": [
+      "A. ![](images/119a3bbd2e4d7c76f270c01ab0916c822fa044942df3ef824a4fd44d59849a76.jpg)",
+      "B. ![](images/b7130698d0e677be990362ebfb771a0819d9460c013ab3fa54dea9af5c6f6ebe.jpg)",
+      "C. ![](images/babd01986899e34db34b1371da133c9d9ecedf926b35f95f9a7af41544d172ea.jpg)"
+    ],
+    "answer": "B",
+    "solution": "【分析】由一个点引出两条直直的线所组成的图形是角，这个点是角的顶点，两条直直的线是角的边，由此解答.\n【详解】A。是角;B。没有两条直直的边，不是角;C。是角。所以不是角的是B。故答案为:B",
+    "knowledge_points": [
+      "角的初步认识及辨认"
+    ],
+    "source": "24-25 二年级上·广西玉林·期中"
+  },
+  {
+    "id": "132",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "每个三角板有( )个锐角。",
+    "options": [
+      "A. 1",
+      "B. 2",
+      "C. 4"
+    ],
+    "answer": "B",
+    "solution": "【分析】角由一个顶点和两条边组成，和书本，黑板的角相同大小的是直角，比直角小的是锐角，如图为三角板，红线标注的均为锐角.\n![](images/2bb56d2df4a3d1d670fff44b05e2866c4782ad33228c0b7d32920e25b3a71e8b.jpg)\n【详解】由分析可知，每个三角板有2 个锐角。故答案为:B",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "24-25 二年级上·山东济南·期中"
+  },
+  {
+    "id": "133",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "用两把不同的三角尺，一定不能拼成的角是( )。",
+    "options": [
+      "A. 直角",
+      "B. 钝角",
+      "C. 锐角"
+    ],
+    "answer": "A",
+    "solution": "【分析】角由一个顶点和两条边组成，和书本，黑板的角相同大小的是直角，比直角大的是钝角，比直角小的是锐角，三角尺上最大的角是直角，由此可作图拼出角进行选择.\n【详解】A。不能拼出直角;B。![](images/68add3b7a8e9a99d8749eaa42b8d892011ca8e1c09d9dbfd4964e8ae19bc18e1.jpg)可以拼出钝角;C。![](images/6979b0c6d4406657d17fec83a1f87cc4bfa779e8d7309892aead5e1241620d41.jpg)可以拼出锐角。所以用两把不同的三角尺，一定不能拼成的角是直角。故答案为:A",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "24-25 二年级上·河南郑州·期中"
+  },
+  {
+    "id": "134",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "用三角尺拼角，拼出了锐角的是( )。",
+    "options": [
+      "A. ![](images/b1c6bec565d0f09a67db1151319fb6899464e0fa9306fea54bd7c5eaf6b2e0df.jpg)",
+      "B. ![](images/1f22760060492f0986528d10bdc0e382a18697632dd3f0b458d6a336fd8afb8d.jpg)",
+      "C. ![](images/1ef89a614ae7ad3c20b8f87ae6e77885c8d35acbfc13ed61f8f82bde03797a8f.jpg)"
+    ],
+    "answer": "B",
+    "solution": "【分析】角由一个顶点和两条边组成，和书本，黑板的角相同大小的是直角，比直角大的是钝角，比直角小的是锐角。三角尺中最大的角是直角，由此解答.\n【详解】A。这个角是由两个锐角拼成的钝角;B。这个角是由两个锐角拼成的锐角;C。这个角是由一个直角和一个锐角拼成的钝角。所以拼成了锐角的是B。故答案为:B",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "24-25 二年级上·山东菏泽·期中"
+  },
+  {
+    "id": "135",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面图( )中拼成的角是锐角。",
+    "options": [
+      "A. ![](images/3326c30af9f102c1cf617fb8405500ec120f59348d011bb489f901a775cefd6c.jpg)",
+      "B. ![](images/ad7a31dd021356b2e8cc93a86df722005db06cc5b065a09780eed1243cc082c6.jpg)",
+      "C. ![](images/2b650eb701cd9748a91d8f7753e3efda967b4bf82a4d398ca6dc16329e6df019.jpg)"
+    ],
+    "answer": "B",
+    "solution": "【分析】比直角小的角是锐角，比直角大的角是钝角，用三角板的直角去比较，即可知拼成的角是不是锐角.\n【详解】A。用直角三角板的直角比较，比三角板的直角大，是钝角，不符合题意。B。用直角三角板的直角比较，比直角小，是锐角，符合题意。C。用直角三角板的直角比较，和直角一样大，是直角，不符合题意。故答案为:B",
+    "knowledge_points": [
+      "角的初步认识及辨认",
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "24-25 二年级上·湖北孝感·期中"
+  },
+  {
+    "id": "136",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下图有几个角( ).\n\n![](images/1aaa3c8e3dd5ba1f944f41d80bf9f9ac6fb3e07565d0760b0f3c3218770fba60.jpg)",
+    "options": [
+      "A. 6",
+      "B. 7",
+      "C. 8"
+    ],
+    "answer": "C",
+    "solution": "【分析】角是由一个顶点和从顶点画出的两条直线组成的，根据对角的认识，从给出的图片中找一找，图片是两个三角形组成的，两个三角形内各有3 个角，两个三角形相对接的地方，也有由顶点和直线组成的角，两边各有一个，即可得出一共有几个角。考查学生对角的认识和观察能力.\n【详解】![](images/1c512dca15f9d8a5f3fc051a0b89cc4b2bb45cefd959ff3d29c9126fe54fe46a.jpg)数一数图片中角的个数为8 个。故答案为:C",
+    "knowledge_points": [
+      "角的初步认识及辨认"
+    ],
+    "source": "24-25 二年级上·河南南阳·期中"
+  },
+  {
+    "id": "137",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "![](images/459f3c332aeb785655c70dde0750e7acf8bc83efbfc0cf71930d687246a764a8.jpg)\n这个图形中有( )个钝角。",
+    "options": [
+      "A. 2",
+      "B. 3",
+      "C. 4"
+    ],
+    "answer": "A",
+    "solution": "【分析】角由一个顶点和两条边组成。三角板中最大的角是直角，比直角小的是锐角，比直角大的是钝角.\n【详解】由分析可得：这个图形中有 2 个钝角。故答案为:A",
+    "knowledge_points": [
+      "角的初步认识及辨认",
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "24-25 二年级上·河北保定·期中"
+  },
+  {
+    "id": "138",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "一个三角板上有( )个角。",
+    "options": [
+      "A. 1",
+      "B. 2",
+      "C. 3"
+    ],
+    "answer": "C",
+    "solution": "【分析】由一个点引出两条直直的线所组成的图形是角。角有两条边和一个公共端点，这两条边叫做角的边，它们的公共端点叫做角的顶点.\n【详解】三角板如图:![](images/98824e5a116888fc65cf1028922e3fdddb9e28914009df0b231372298273c1db.jpg)一个三角板上有 3 个角。故答案为:C",
+    "knowledge_points": [
+      "角的初步认识及辨认"
+    ],
+    "source": "24-25 二年级上·河北保定·期中"
+  },
+  {
+    "id": "139",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "人民广场上有 9 根整齐排列的柱子，明明在柱子间走动，她行走的路线中仅有 1 个直角和 2 个锐角。明明行走的路线可能是( )。",
+    "options": [
+      "A. ![](images/dc6e8329ab54d78c8916006a08d07fbc4a24837349db8e72a5505f419c44c4ca.jpg)",
+      "B. ![](images/6f35333508b0c8a2458511debe21079764ce27b7749c186a9d2a3dab9f468948.jpg)",
+      "C. ![](images/d50449a76be16aea668e1f59c42c6c19872439b984ccc8c073e0ece6d4c87c62.jpg)"
+    ],
+    "answer": "B",
+    "solution": "【分析】三角尺上最大的角为直角，用三角板的直角进行比较测量，比直角小的就是锐角，比直角大的就是钝角.\n【详解】A。没有锐角，不符合;B。只有1 个直角和2 个锐角，符合;C。有3 个直角，不符合。明明行走的路线可能是B。故答案为:B",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "24-25 二年级上·福建福州·期中"
+  },
+  {
+    "id": "140",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "角两边之间的张口越大，这个角就( )。",
+    "options": [
+      "A. 越大",
+      "B. 越小",
+      "C. 不变"
+    ],
+    "answer": "A",
+    "solution": "【分析】角的大小和两边叉开的大小有关，叉开的越大，则角越大，叉开的越小则角越小.\n【详解】由分析可得：角两边之间的张口越大，这个角就越大。故答案为:A",
+    "knowledge_points": [
+      "角的初步认识及辨认"
+    ],
+    "source": "24-25 二年级上·湖南怀化·期中"
+  },
+  {
+    "id": "141",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下列各图中，角的个数最多的是( )。",
+    "options": [
+      "A. ![](images/d7d8d28cd22415047e679a49f2f97abb92c4a28224a27617ce6d42dbf15d4577.jpg)",
+      "B. ![](images/0e0bd0c183adac40cdcb6070183d9784dca7dde8d7e84b25d92d7d878b78e095.jpg)",
+      "C. ![](images/6d8c598f1273db09ecd83fe8667e31c14fea2f4b3303ccf4681222fb994073a0.jpg)"
+    ],
+    "answer": "A",
+    "solution": "【分析】角是由一个点引出两条直直的线所组成的图形;在三角板上最大角就是直角，锐角比直角小，钝角比直角大;据此数一数每个图形各有几个角，即可解决.\n【详解】A。五角星内有 5 个锐角，外有 5 个钝角，一共有 10 个角;B。此题有3 个基本角，由2 个基本角组成的角有2 个，由3 个基本角组成的角有1 个,1 + 2 + 3 = 6(个),共有 6 个角;C。五边形内有5 个角;10 > 6 > 5，即角的个数最多的是A。故答案为:A",
+    "knowledge_points": [
+      "角的初步认识及辨认",
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "24-25 二年级上·福建泉州·期中"
+  },
+  {
+    "id": "142",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "下面拼出的角不是直角的是( )。",
+    "options": [
+      "A. ![](images/80bf387d8cbcdab6028902f9381e71ece2a751524ab8e5f964c7dfab766b72e2.jpg)",
+      "B. ![](images/9d758c51820850f87b412445815347b43a7647c8dceb0f10e889fcbea67576ee.jpg)",
+      "C. ![](images/014588b770001c2a9649ec339a48e357df75c842d4e721baed03c0e8b186aa9f.jpg)"
+    ],
+    "answer": "B",
+    "solution": "【分析】三角尺上最大的角为直角，用三角板的直角进行比较测量，比直角小的就是锐角，比直角大的就是钝角.\n【详解】A。拼出的是直角;B。一个直角和一个锐角拼成的，是钝角;C。拼成的是直角。拼出的角不是直角的是B。故答案为:B",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征",
+      "平面图形的拼接"
+    ],
+    "source": "24-25 二年级上·福建三明·期中"
+  },
+  {
+    "id": "143",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面图中( )是钝角。",
+    "options": [
+      "A. ![](images/fb7a6f023bfa0281e9a91cc8250768c4aecd70dd3f4894a0271ac1e827050e28.jpg)",
+      "B. ![](images/782efee4b18d038580eb18d8909e37894507ba7b12df4c3f616a6787d623a223.jpg)",
+      "C. ![](images/db6ca612cbf1874da3b2a7a031a26a985319d467f3c48e16d90823715bcdbc5e.jpg)"
+    ],
+    "answer": "C",
+    "solution": "【分析】在三角板上，最大角就是直角，锐角比直角小，钝角比直角大;据此解决.\n【详解】A。这是锐角;B。这是直角;C。这是钝角;故答案为:C",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "24-25 二年级上·山东济南·期中"
+  },
+  {
+    "id": "144",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "下面用三角尺拼成的角中,( )是钝角。",
+    "options": [
+      "A. ![](images/c4974cf5ac61aa11cef15933bc2066866b678b57959f9a557b111396cb3849e9.jpg)",
+      "B. ![](images/7e75cce3290e51ac4014b9efc42b3620dc73e1fe4edb44ab58998b18722647e8.jpg)",
+      "C. ![](images/313e5ecc38ece0ab98e1a30507dcaceb02c86c2c62fff609fb05e3329e06adbb.jpg)",
+      "D. ![](images/458ad3719246222e0c6a074def33801efcf75c6912ed6087c6482f5fd8832b21.jpg)"
+    ],
+    "answer": "A",
+    "solution": "【分析】三角板上最大的角就是直角，比直角小的角是锐角，比直角大的角是钝角。据此用三角板上的直角与选项中拼成的角比较即可.\n【详解】A。拼成的角比三角板上的直角大，是钝角;B。拼成的角等于三角板上的直角，是直角;C。拼成的角小于三角板上的直角，是锐角;D。拼成的角小于三角板上的直角，是锐角。所以A是钝角。故答案为:A",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "24-25 二年级上·福建龙岩·期中"
+  },
+  {
+    "id": "145",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "关于角的说法，下面正确的是( )。",
+    "options": [
+      "A. 钝角 > 直角 > 锐角",
+      "B. 角的大小跟两边张开的大小无关",
+      "C. 两个锐角拼出的角一定是锐角",
+      "D. ![](images/590648a391e7e7474dc10267e6e23c377a4807ac238905c21dd9f0801edb21d3.jpg)左图是一个角"
+    ],
+    "answer": "A",
+    "solution": "【分析】大于直角的是钝角，小于直角的是锐角;角的大小和两边叉开的大小有关和两边的长度无关;两个锐角可拼出一个直角，或钝角或锐角;从一点引出两条射线所形成的图形叫做角.\n【详解】A。钝角 > 直角 > 锐角，大于直角的是钝角，小于直角的是锐角，符合题意。B。角的大小跟两边张开的大小无关，角的大小和张开大小有关，和长度无关，不符合题意。C。两个锐角拼出的角一定是锐角，两个锐角拼出的角可能是锐角，钝角和直角，不符合题意。D。该图不是一个角，不符合题意。故答案为:A",
+    "knowledge_points": [
+      "角的初步认识及辨认",
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "24-25 二年级上·福建龙岩·期中"
+  },
+  {
+    "id": "146",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "把一个直角的两条边延长，这个直角的大小( )。",
+    "options": [
+      "A. 变大",
+      "B. 变小",
+      "C. 不变",
+      "D. 无法确定"
+    ],
+    "answer": "C",
+    "solution": "【分析】角的大小只跟两边叉开的大小有关，与两边的长短无关。据此解答即可.\n【详解】由分析可得，把一个直角的两条边延长，这个直角的大小不变。故答案为:C",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征",
+      "角的大小比较"
+    ],
+    "source": "24-25 二年级上·福建龙岩·期中"
+  },
+  {
+    "id": "147",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "下面( )时整，分针和时针组成的角最小。",
+    "options": [
+      "A. 1",
+      "B. 3",
+      "C. 8",
+      "D. 9"
+    ],
+    "answer": "A",
+    "solution": "【分析】分针指向12，时针指向几就是几时，据此用钟表表示出各选项的时间。三角板上最大的角就是直角，比直角小的角是锐角，比直角大的角是钝角。据此用三角板上的最大角判断各钟表时针和分针所成的角的类型，再根据钝角 > 直角 > 锐角比较大小即可.\n【详解】A。![](images/3446ac7e1af6b6f99f19b58e9849b054672194a031a823104d26e454e428c38b.jpg)分针和时针组成的角是锐角;B。![](images/41bdb8c5c98ad4190b0752e98a8e5885bcb03900033003c4ecb501b3d70ea8ca.jpg)分针和时针组成的角是直角;C。![](images/9e5a03a0163cd68e1ec5c23c268987dfc9262f737cedf9154fd6ff108c366754.jpg)分针和时针组成的角是钝角;D。![](images/9b67ba3b79144a1d638f21998ace3f6c8408c96ac0367e98650c219ea8d5d80f.jpg)分针和时针组成的角是直角。锐角最小,1 时整，分针和时针组成的角最小。故答案为:A",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征",
+      "角的大小比较",
+      "整点时间与钟面指针的位置"
+    ],
+    "source": "24-25 二年级上·福建龙岩·期中"
+  },
+  {
+    "id": "148",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下图中,( )遮住的角是钝角。",
+    "options": [
+      "A. ![](images/6b867c4cbbe884d5abef497683f6a6af073a6064d5f60b6e5b5677f349a27ed0.jpg)",
+      "B. ![](images/875d216dac1d33c8ea1bda531ebbf742839d4079235c0bca91a972612cb78e02.jpg)",
+      "C. ![](images/c26a75fc965c54cbd75db3332081baa4a7ceab0f9099e58b69f995b6c72f5b30.jpg)"
+    ],
+    "answer": "A",
+    "solution": "【分析】由一个点引出两条直直的线所组成的图形是角，这个点是角的顶点，两条直直的线是角的边。三角板上最大的角是直角，比直角大的是钝角，比直角小的是锐角。由此延长各角的边至顶点处，判断是什么角即可.\n【详解】A。是钝角;B。是直角;C。是锐角。A遮住的角是钝角。故答案为:A",
+    "knowledge_points": [
+      "角的初步认识及辨认",
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "24-25 二年级上·湖南衡阳·期中"
+  },
+  {
+    "id": "149",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "![](images/8fcacac6e771504aaf49d4389e76780ce732708a963d9b39d8a028a7841d6035.jpg)\n左图中有( )个角。",
+    "options": [
+      "A. 6",
+      "B. 7",
+      "C. 8"
+    ],
+    "answer": "C",
+    "solution": "【分析】由一个点引出两条直直的线所组成的图形是角。据此数一数。两个三角形中共 6 个角，由两个小角组成的角有2个，合起来是8个.\n【详解】该图中有 8 个角。故答案为:C",
+    "knowledge_points": [
+      "长方形，正方形，三角形和圆的初步认识",
+      "角的初步认识及辨认"
+    ],
+    "source": "19-20 二年级上·全国·期中"
+  },
+  {
+    "id": "150",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面图形中，是直角的是( )。",
+    "options": [
+      "A. ![](images/c2b83217fd01fa0cd274aec888017559d51f6dbc95ae30908258072833afcac0.jpg)",
+      "B. ![](images/80f1b96f72c368dd4acc27099f14b9d10d7f61a1a89c2bd95d51661da35c6848.jpg)",
+      "C. ![](images/ed704d9a6ce1fa1e78b8ea6e2628233393a4222e300c33bed011071edb6dbd8e.jpg)"
+    ],
+    "answer": "B",
+    "solution": "【分析】三角尺上最大的角为直角，用三角板的直角进行比较测量，比直角小的就是锐角，比直角大的就是钝角，据此解答.\n【详解】A。是锐角;B。是直角;C。是钝角。是直角的是B。故答案为:B",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "24-25 二年级上·内蒙古通辽·期中"
+  },
+  {
+    "id": "151",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面的四个角，哪个角最大。( )",
+    "options": [
+      "A. ![](images/db3bf8881a5f5bc1850920a70fcfbf1c32fdf49bbf00298b8379b8389e0d8355.jpg)",
+      "B. ![](images/a87120c4ee0efeeff02441c0641cbf73afe6bfde848510b27fe8c4a30ee51d40.jpg)",
+      "C. ![](images/62335cdab5fa33a8f4f669cafc73d612cf340543f2cb19cb1196d9106d2d4f48.jpg)",
+      "D. ![](images/2026-02-20%20015054.jpg)"
+    ],
+    "answer": "D",
+    "solution": "【分析】角由一个顶点和两条边组成。和书本，黑板的角相同大小的是直角，比直角大的是钝角，比直角小的是锐角，也就是钝角 > 直角 > 锐角，三角板上最大的角是直角，可由此比较解答.\n【详解】A。是锐角;B。是直角;C。是直角;D。是钝角。钝角最大，也就是D最大。故答案为:D",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征",
+      "角的大小比较"
+    ],
+    "source": "24-25 二年级上·广东东莞·期中"
+  },
+  {
+    "id": "152",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "直角三角尺上有( )个角，其中有( )个直角。",
+    "options": [],
+    "answer": "3;1",
+    "solution": "【分析】角由一个顶点和两条边组成，和书本，黑板的角相同大小的是直角。如图为直角三角尺，每个三角尺上都有 3 个角，都有 1 个直角。![](images/c34490a6d219fe6942fb73cb464a6ae68eae1b5223523838e2e9ab3344f1385c.jpg)\n【详解】直角三角尺上有 3 个角，其中有 1 个直角。",
+    "knowledge_points": [
+      "角的初步认识及辨认",
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "24-25 二年级上·广西玉林·期中"
+  },
+  {
+    "id": "153",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "数一数，填一填.\n\n![](images/1f6c2d22a913a1c680818632bec9428aa2698c86a7bee11a6dd076f18f53ce42.jpg)\n①\n![](images/12ef16156e15bca08e51741ffbeb86e8439cd31fcdbca4d2445500108fb4778a.jpg)\n②\n![](images/0b557d7bde404225985437cc8fd90ef2b426fceca8408db2693e55fea0bee4b7.jpg)\n③\n( )个直角;( )个角;( )个角。",
+    "options": [],
+    "answer": "2;7;5",
+    "solution": "【分析】角由一个顶点和两条边组成。和书本，黑板的角相同大小的是直角，由此数出角的数量即可.\n【详解】①2 个直角;②7 个角;③5 个角。",
+    "knowledge_points": [
+      "角的初步认识及辨认",
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "24-25 二年级上·湖南怀化·期中"
+  },
+  {
+    "id": "154",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "图中有( )个钝角,( )条线段.\n\n![](images/468fbdacb6f28232b1989985aef80b72565b323f7381142a39b588fab3210192.jpg)",
+    "options": [],
+    "answer": "2;6",
+    "solution": "【分析】角由一个顶点和两条边组成，和书本，黑板的角相同大小的是直角，比直角大的是钝角。三角尺上最大的角是直角，可由此比较解答。线段有两个端点，中间是直直的线，长度可测量，由此解答.\n【详解】图中有2 个钝角,6 条线段.\n![](images/741e48b40528f17acf6d2f0ed001e0006937b2baad40b3bba3d2357d2b27b7b7.jpg)",
+    "knowledge_points": [
+      "线段的初步认识",
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "24-25 二年级上·河南南阳·期中"
+  },
+  {
+    "id": "155",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "图中有( )条线段，有( )个直角.\n\n![](images/4132c187df16bbdb99053e5ec7de8328a825970ebb1651622f1753a764a6e5ad.jpg)",
+    "options": [],
+    "answer": "6;5",
+    "solution": "【分析】线段有两个端点，中间是直直的线，长度可测量;角由一个顶点和两条边组成，和书本，黑板的角相同大小的是直角，三角尺上最大的角是直角，可由此比较解答.\n【详解】图中有 6 条线段，有 5 个直角.\n![](images/aa05037aed29845425831db80d7b709ed52215909dbf84734235be6d82887645.jpg)",
+    "knowledge_points": [
+      "线段的初步认识",
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "23-24 二年级上·重庆永川·期末"
+  },
+  {
+    "id": "156",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "图中，有( )条线段，有( )个锐角，有( )个直角，有( )个钝角.\n\n![](images/c0c76e4aa8432a900f36f5119f2cca2496855930debf6fe98ae838c2cc836c6b.jpg)",
+    "options": [],
+    "answer": "4;1;2;1",
+    "solution": "【分析】![](images/2026-02-20%20015920.jpg)像这样的都是线段，线段是直的，有两个端点，可以量出长度;每个三角尺上都有一个直角![](images/2026-02-20%20015954.jpg)要知道一个角是不是直角，可以用三角尺上的直角比一比，比直角小的就是锐角，比直角大的就是钝角，据此解答.\n【详解】根据分析：图中，有4 条线段，有1 个锐角，有2 个直角，有1 个钝角。",
+    "knowledge_points": [
+      "线段的初步认识",
+      "角的初步认识及辨认"
+    ],
+    "source": "24-25 二年级上·重庆·期中"
+  },
+  {
+    "id": "157",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "图中一共有( )条线段,( )个角。其中有( )个锐角,( )个钝角.\n\n![](images/7b7fe8544ba9677bd0063fe817e5e67a1a916ffdbf1bd24d5b536d2fe5bb8b5d.jpg)",
+    "options": [],
+    "answer": "5;8;5;2",
+    "solution": "【分析】线段有 2 个端点，中间是直直的线，长度可测量，由此数出线段的数量;角由一个顶点和两条边组成，和书本，黑板的角相同大小的是直角，比直角小的是锐角，比直角大的是钝角，三角尺上最大的角是直角，可由此比较解答.\n【详解】图中一共有 5 条线段,8 个角。其中有 5 个锐角,2 个钝角.\n![](images/2026-02-20%20020258.jpg)",
+    "knowledge_points": [
+      "线段的初步认识",
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "24-25 二年级上·山东临沂·期中"
+  },
+  {
+    "id": "158",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "数一数.\n![](images/9a79e806e28d93f028274dce192b662b22ccff5c72b8c2ce1f7f6332cc716dee.jpg)\n( )条线段,( )个角.\n![](images/fe5f2a138f1ce3d6510b262456357d899897c038db49b33fb7e5ff2db6bf2961.jpg)\n( )条线段,( )个角。",
+    "options": [],
+    "answer": "5;5;7;10",
+    "solution": "【分析】线段是直的，有两个端点，有限长，可以测量长度;角有两条边和一个顶点，根据线段和角的特征数一数即可.\n【详解】根据线段和角的特征数一数可知：有5 条线段,5 个角。有7 条线段,10 个角。",
+    "knowledge_points": [
+      "线段的初步认识",
+      "角的初步认识及辨认"
+    ],
+    "source": "24-25 二年级上·广东汕头·期中"
+  },
+  {
+    "id": "159",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "数一数，下面这些数字中各有几个直角。\n![](images/2026-02-20%20020718.jpg)\n( )个;( )个;( )个;( )个",
+    "options": [],
+    "answer": "6;3;4;4",
+    "solution": "【分析】角由一个顶点和两条边组成，和书本，黑板的角相同大小的是直角，三角尺上最大的角是直角，可由此比较解答.\n【详解】由分析得:![](images/2026-02-20%20020746.jpg)分别有6 个,3 个,4 个,4 个直角。",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "24-25 二年级上·广西南宁·期中"
+  },
+  {
+    "id": "160",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "图中有( )个锐角,( )个直角,( )个钝角.\n\n![](images/9f2fba83aa755fef7be55ceac1e9d20c4124496e013c965403371f5a6a307c8f.jpg)",
+    "options": [],
+    "answer": "1;2;1",
+    "solution": "【分析】依据角的概念：有公共端点的两条射线所围成的图形叫做角;然后用三角尺的直角进行比较，和三角尺的直角重合的是直角，大于直角的角是钝角，小于直角的是锐角.\n【详解】由分析可得：有1 个锐角,2 个直角,1 个钝角。",
+    "knowledge_points": [
+      "角的初步认识及辨认",
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "23-24 二年级上·重庆秀山·期末"
+  },
+  {
+    "id": "161",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "图中有( )条线段，有( )个直角,( )个锐角.\n\n![](images/422ea5cc1bee57295d9953ab1667bbc5eb0a8be2bb23b508362af70b8fe52668.jpg)",
+    "options": [],
+    "answer": "5;2;1",
+    "solution": "【分析】线段：有两个端点，中间是一条直直的线，有限长，可测量。依据角的概念：有公共端点的两条射线所围成的图形叫做角。用三角尺的直角进行比较，和三角尺的直角重合的是直角，大于直角的角是钝角，小于直角的是锐角.\n【详解】由分析可得：有 5 条线段，有 2 个直角,1 个锐角。",
+    "knowledge_points": [
+      "线段的初步认识",
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "23-24 二年级上·浙江温州·期末"
+  },
+  {
+    "id": "162",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "下图中一共有( )个角，其中( )个直角,( )个锐角,( )个钝角.\n\n![](images/c0fd3c4f0ef40c897451ac91c372b192942aa046e34a7e8bbb3dc0bdebd45799.jpg)",
+    "options": [],
+    "answer": "4;2;1;1",
+    "solution": "【分析】依据角的概念：有公共端点的两条射线所围成的图形叫做角，即可数清图中角的数量;然后用三角尺的直角进行比较，和三角尺的直角重合的是直角，大于直角的角是钝角，小于直角的是锐角.\n【详解】由分析可得：一共有4 个角，其中2 个直角,1 个锐角,1 个钝角。",
+    "knowledge_points": [
+      "角的初步认识及辨认",
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "24-25 二年级上·河北沧州·期中"
+  },
+  {
+    "id": "163",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "数一数，下面图形中各有几条线段，几个角。\n\n![](images/b43825b0debc1e9fbab92fa9134d178d2ed2db5103414f2d2157a607091940ea.jpg)\n\n线段:( )条;线段:( )条;线段:( )条\n角:( )个;角:( )个;角:( )个",
+    "options": [],
+    "answer": "4;6;2;4;6;1",
+    "solution": "【分析】线段是直的，有两个端点，有限长，可以测量长度;角有两条边和一个公共端点。根据线段和角的特征数数即可.\n【详解】由分析数一数可知：线段:4 条，角:4 个;线段:6 条，角:6 个;线段:2 条，角:1 个。",
+    "knowledge_points": [
+      "线段的初步认识",
+      "角的初步认识及辨认"
+    ],
+    "source": "24-25 二年级上·河南三门峡·期中"
+  },
+  {
+    "id": "164",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "下边的图形中共有( )个角.\n\n![](images/a7733e76d6802e4409921cd546d2a8f8aad66b78b439019361f68c8f15481842.jpg)",
+    "options": [],
+    "answer": "6",
+    "solution": "【分析】对于由多条射线从一个公共端点出发组成的图形，每两条射线都可以组成一个角，所以要找出所有不同的两条射线的组合情况，就能确定角的个数。通过依次累加的方式来计算角的个数。图中共有4 条射线，先选第一条射线，它可和另外3 条射线组成3 个角;选第二条射线，它可和除第一条射线外的2 条射线组成2 个角，以此类推，选第三条射线，它可和除第一条第二条射线外的1 条射线组成1 个角，最后一条线，无法再与其它线组成角，故角的总数为:3 + 2 + 1 = 6(个)。由此判断即可.\n【详解】根据分析可知:3 + 2 + 1 = 6(个),该图形中共有 6 个角。",
+    "knowledge_points": [
+      "角的初步认识及辨认"
+    ],
+    "source": "24-25 二年级上·福建厦门·期中"
+  },
+  {
+    "id": "165",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "图中一共有( )条线段，有( )个锐角,( )个直角.\n\n![](images/42469bd807371b9885b6ffb13def797492edb120b5488600cde2d0071e0d4770.jpg)",
+    "options": [],
+    "answer": "5;4;4",
+    "solution": "【分析】线段有两个端点，中间是直直的线，长度可测量。角有一个顶点和两条边组成，和书本，黑板的角相同大小的是直角，比直角小的是锐角，由此解答.\n【详解】图中一共有 5 条线段，有 4 个锐角,4 个直角。",
+    "knowledge_points": [
+      "线段的初步认识",
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "24-25 二年级上·福建三明·期中"
+  },
+  {
+    "id": "166",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "数一数，下列图形中各有几个角。\n![](images/2026-02-20%20230239.jpg)\n( )个;( )个;( )个;( )个;( )个",
+    "options": [],
+    "answer": "3;4;6;5;0",
+    "solution": "【分析】根据角的定义，角是由一个顶点和两条直直的边组成的，如图：据此解答.\n【详解】根据分析:3 个;4 个;6 个;5 个;0 个。",
+    "knowledge_points": [
+      "角的初步认识及辨认"
+    ],
+    "source": "24-25 二年级上·福建福州·期中"
+  },
+  {
+    "id": "167",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "每把三角尺上有( )个钝角,( )个直角,( )个锐角。锐角比直角( ),钝角比直角( ),钝角比锐角( )。(填\"大\"或\"小\")",
+    "options": [],
+    "answer": "0;1;2;小;大;大",
+    "solution": "【分析】根据题意，三角尺上最大的角是直角，比直角大的角是钝角，比直角小的角是锐角，锐角 < 直角 < 钝角，据此解答.\n【详解】如图:![](images/5beaf8ca017a8b4322c35f3179be134e98fb0fb4f902743f60ab6bd36510a1c1.jpg)每把三角尺上有0 个钝角,1 个直角,2 个锐角。锐角比直角小，钝角比直角大，钝角比锐角大。",
+    "knowledge_points": [
+      "角的初步认识及辨认",
+      "直角，钝角，锐角的认识及特征",
+      "角的大小比较"
+    ],
+    "source": "24-25 二年级上·福建福州·期中"
+  },
+  {
+    "id": "168",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "![](images/13f0c5c2a4f220abf2b977415fe5066ad393409ccb12bc85ca68f9b203f2f227.jpg)\n左图有( )条线段,( )个锐角,( )个直角,( )个钝角。",
+    "options": [],
+    "answer": "5;1;2;2",
+    "solution": "【分析】线段有两个端点，中间是直直的线，长度可测量;角由一个顶点和两条边组成，和书本，黑板的角相同大小的是直角，比直角小的是锐角，比直角大的是钝角.\n【详解】该图有 5 条线段,1 个锐角,2 个直角,2 个钝角。",
+    "knowledge_points": [
+      "线段的初步认识",
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "24-25 二年级上·河南南阳·期中"
+  },
+  {
+    "id": "169",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "下面的图形中各有几个角。\n\n![](images/2026-02-20%20230726.jpg)\n\n( )个角;( )个锐角;( )个直角;( )个角",
+    "options": [],
+    "answer": "4;5;2;5",
+    "solution": "【分析】角由一个顶点和两条边组成。三角板上最大的角是直角，比直角大的是钝角，比直角小的是锐角。如图，数出角的数量即可.\n【详解】由分析填写如下:![](images/2026-02-20%20231122.jpg)",
+    "knowledge_points": [
+      "角的初步认识及辨认",
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "24-25 二年级上·河南南阳·期中"
+  },
+  {
+    "id": "170",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "![](images/2026-02-20%20231230.jpg)图中有( )个锐角，有( )个直角。",
+    "options": [],
+    "answer": "3;3",
+    "solution": "【分析】角由一个顶点和两条边组成，和书本，黑板的角相同大小的是直角，比直角小的是锐角，由此数出角的数量即可.\n【详解】![](images/18a9872e897d63a9774f20d56093506b68dec09ffd094ed0a1c5bbc6bf025df8.jpg)锐角\n![](images/e3f8deb70724bbc050c18987608d9bcb88ab9474420466150895418309182875.jpg)直角。图中有3 个锐角，有3 个直角。",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "24-25 二年级上·山东日照·期中"
+  },
+  {
+    "id": "171",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "如图，图中有( )个锐角,( )个直角,( )个钝角.\n\n![](images/422f61b17dc852f0da72d9889fda2dac798355cfc8cdf8515c15259ad9c27c5f.jpg)",
+    "options": [],
+    "answer": "2;2;1",
+    "solution": "【分析】像![](images/2026-02-20%20231353.jpg)这样的角都是直角，像![](images/2026-02-20%20231411.jpg)这样比直角小的是锐角，像![](images/2026-02-20%20231445.jpg)这样比直角大的是钝角。由此解答.\n【详解】图中有 2 个锐角,2 个直角,1 个钝角。",
+    "knowledge_points": [
+      "角的初步认识及辨认"
+    ],
+    "source": "24-25 二年级上·山东青岛·期中"
+  },
+  {
+    "id": "172",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "下图由( )条线段围成，图中有( )个锐角.\n\n![](images/bd06857be9adfeb574ef9094d377a3735af43c3051ad8dbffbd8711c38b83dee.jpg)",
+    "options": [],
+    "answer": "3;2",
+    "solution": "【分析】线段有两个端点，中间是直直的线，长度可测量;角由一个顶点和两条边组成，和书本，黑板的角相同大小的是直角，比直角大的是钝角，比直角小的是锐角。由此数出线段和锐角的数量即可.\n![](images/94f59d10a43646a07071fa74bbfec29f6993f278b24dc7bdfec915e68050bd30.jpg)\n【详解】该图由 3 条线段围成，图中有 2 个锐角。",
+    "knowledge_points": [
+      "线段的初步认识",
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "24-25 二年级上·山东菏泽·期中"
+  },
+  {
+    "id": "173",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "如图中，有( )个锐角，有( )个直角，有( )个钝角.\n\n![](images/a5d9386bf83b818717f67f704d80f3c7e52d00bfb4a36cb0afc407d3b44fd13c.jpg)",
+    "options": [],
+    "answer": "2;2;1",
+    "solution": "【分析】角由一个顶点和两条边组成。和书本，黑板的角相同大小的是直角，比直角大的是钝角，比直角小的是锐角。红色线是锐角，蓝色线是直角，绿色线是钝角，由此解答.\n![](images/543612842c16c9fb689361676d2c353c2aab209327aebbb1c2ecc7a67b889821.jpg)\n【详解】该图中，有 2 个锐角，有 2 个直角，有 1 个钝角。",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "24-25 二年级上·云南文山·期中"
+  },
+  {
+    "id": "174",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "下面是用三角板拼成的角，分别是什么角。\n\n![](images/1a5eb4d5f25e3c477a40b8caa4a462c7cbe35a0c8b2fa5542df001a96e0e603f.jpg)\n![](images/80a3b605b8d90bcb70d711734ad8dfa207f50c52fda47ca3e931b5dd3a47cd6e.jpg)\n![](images/896ac39e29ea518a8df2c486a37aa258447a4be393537bc2601441ed432bfb6e.jpg)\n![](images/c1f4bc1863e212034ba068cd831eb91e31b3210789ef48b04cb03d1c2278344c.jpg)\n\n( )角;( )角;( )角;( )角",
+    "options": [],
+    "answer": "钝;锐;钝;直",
+    "solution": "【分析】角由一个顶点和两条边组成。和书本，黑板的角相同大小的是直角，比直角小的是锐角，比直角大的是钝角。三角板上最大的角是直角，可由此比较解答.\n【详解】图 1：是由一个直角和一个锐角拼成的钝角;图 2：是由两个锐角拼成的锐角;图 3：是由一个直角和一个锐角拼成的钝角;图 4：是由两个锐角拼成的直角。",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "24-25 二年级上·河北保定·期中"
+  },
+  {
+    "id": "175",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "一个角有( )个顶点,( )条边组成。角的两条边的张口越大，角越( )。",
+    "options": [],
+    "answer": "1;2;大",
+    "solution": "【分析】由一个点引出两条直直的线所组成的图形是角。角有两条边和一个公共端点，这两条边叫做角的边，它们的公共端点叫做角的顶点。角的大小与角的两条边张开的程度有关，而角的大小与边的长短没有关系。两边张开的越大，角就越大.\n【详解】一个角有1 个顶点,2 条边组成。角的两条边的张口越大，角越大。",
+    "knowledge_points": [
+      "角的初步认识及辨认",
+      "角的大小比较"
+    ],
+    "source": "24-25 二年级上·河北保定·期中"
+  },
+  {
+    "id": "176",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "红领巾上有( )个角，其中( )个锐角,( )个直角,( )个钝角。",
+    "options": [],
+    "answer": "3;2;0;1",
+    "solution": "【分析】在三角板上，最大角就是直角，钝角比直角大，锐角比直角小。如下图，红领巾上面2 个角是锐角，下面这个角是钝角，没有直角.\n![](images/6213d72f30dd0573daae5cf52e1f6e63d1a8e654ceae61378fd122b97d728446.jpg)\n【详解】由题意分析得：红领巾上有3 个角，其中2 个锐角,0 个直角,1 个钝角。",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "2024 二年级上·全国·专题练习"
+  },
+  {
+    "id": "177",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "下图中有( )条线段，共有( )个角，其中锐角有( )个，直角有( )个，钝角有( )个.\n\n![](images/35af5ec6f626df33667138d6c8bcb3a31c5a4f0e764af66b610dfb8e324642f7.jpg)",
+    "options": [],
+    "answer": "7;8;3;3;2",
+    "solution": "【分析】线段是一条直直的线，并且有两个端点;平行四边形的四条边就是4 条线段，平行四边形内有1 条线段，这条线段又把下边分成了2 条线段，所以图中一共有7 条线段。角是由一个点引出两条直直的线所组成的图形;在三角板上，最大角就是直角，锐角比直角小，钝角比直角大。平行四边形本身就有4 个角(2 个锐角和2 个钝角),平行四边形内的这条线段使得图中又多了4 个角(1 个锐角和3 个直角),一共有 8 个角，其中锐角有 3 个，直角有 3 个，钝角有 2 个.\n【详解】由题意分析得：该图中有7 条线段，共有8 个角，其中锐角有3 个，直角有 3 个，钝角有2 个。",
+    "knowledge_points": [
+      "线段的初步认识",
+      "角的初步认识及辨认",
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "24-25 二年级上·福建泉州·期中"
+  },
+  {
+    "id": "178",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "![](images/52b24d84fe07d8de32e90169e3b6649d0362b0bef4f0864ea9d2f64e7648d924.jpg)① 是( )角,②是( )角,③是( )角。",
+    "options": [],
+    "answer": "直;锐;钝",
+    "solution": "【分析】角有一个顶点，两条边;每个三角尺上都有一个直角，要知道一个角是不是直角，可以用三角尺上的直角比一比，锐角比直角小，钝角比直角大,\n![](images/366ca9f1e0a09fd805686157c937d17f8378cde2b42a893447856f9052a5bd0d.jpg)据此解答.\n【详解】①是直角,②是锐角,③是钝角。",
+    "knowledge_points": [
+      "角的初步认识及辨认"
+    ],
+    "source": "24-25 二年级上·山东济南·期中"
+  },
+  {
+    "id": "179",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "图中有( )个直角,( )个锐角,( )个钝角.\n\n![](images/4a0128163ae86552210d1493002dcc4e0d6772e83213403794284734cb580898.jpg)",
+    "options": [],
+    "answer": "2;1;1",
+    "solution": "【分析】角由一个顶点和两条边组成。和书本，黑板的角相同大小的是直角，比直角大的是钝角，比直角小的是锐角。三角板中最大的角是直角，可由此比较解答.\n【详解】红色线是直角;绿色线是锐角;蓝色线是钝角.\n![](images/7535500a080cff5c65e5d55ff191dd91f11d3966bd9ed55608511c32816000d2.jpg)\n图中有 2 个直角,1 个锐角,1 个钝角。",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "24-25 二年级上·湖北十堰·期中"
+  },
+  {
+    "id": "180",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "下图中，角 6 和角 1可以拼出一个( )角。角 1 和角 2 可以拼成一个( )角.\n\n![](images/59805cff66faa0f1d1428b3e48e3861c27923e7713be2ac36ba2613ae4fdfd0e.jpg)\n![](images/1ea31cedb5dc449e27dea50cb97289c1644e9f2b37b415662126b2020da91f9a.jpg)",
+    "options": [],
+    "answer": "钝;锐",
+    "solution": "【分析】根据角的初步认识，用三角尺的直角进行比较，小于直角的角是锐角，大于直角的角是钝角，根据图片可知：角 6 是直角，角 1 是锐角，直角和锐角的和大于直角，则是钝角;角 1 和角 2 的和小于直角，是锐角，两锐角和小于直角，则是锐角.\n【详解】由分析可得：角 6 和角 1 可以拼出一个钝角。角 1 和角 2 可以拼成一个锐角。",
+    "knowledge_points": [
+      "角的初步认识及辨认",
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "24-25 二年级上·山东济南·期中"
+  },
+  {
+    "id": "181",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "填序号。下图直角有( ),锐角有( ),钝角有( ).\n![](images/2026-02-20%20232304.jpg)",
+    "options": [],
+    "answer": "①;②,⑤;③,④",
+    "solution": "【分析】三角板上最大的角就是直角，比直角小的角是锐角，比直角大的角是钝角。对照三角板上直角的大小判断图中角的类型即可.\n【详解】通过对照三角板上的直角可得，直角有:①;锐角有:②,⑤;钝角有:③,④。",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "24-25 二年级上·吉林四平·期中"
+  },
+  {
+    "id": "182",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "图中共有( )个角，其中有( )个直角。",
+    "options": [],
+    "answer": "3;1",
+    "solution": "【分析】角是由一个点引出两条直直的线所组成图形;而在三角板上，最大角就是直角;据此解决此题.\n【详解】由题意分析得：图中共有 3 个角，其中有 1 个直角。",
+    "knowledge_points": [
+      "角的初步认识及辨认",
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "24-25 二年级上·吉林白城·期中"
+  },
+  {
+    "id": "183",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "下图中一共有( )个锐角,( )个钝角,( )个直角.\n\n![](images/1d3d3f44426f4117e54c42a9ca9e3744b8ab4b125218e392e5ade593e03f8fb4.jpg)",
+    "options": [],
+    "answer": "5;1;1",
+    "solution": "【分析】三角尺上最大的角为直角，用三角板的直角进行比较测量，比直角小的就是锐角，比直角大的就是钝角。据此数一数.\n【详解】该图中一共有5 个锐角,1 个钝角,1 个直角。",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "24-25 二年级上·河南南阳·期中"
+  },
+  {
+    "id": "184",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "一张长方形纸片有( )个角，其中有( )个直角。一条红领巾有( )个角，其中最大的角是( )角。",
+    "options": [],
+    "answer": "4;4;3;钝",
+    "solution": "【分析】由题意可知：角是从一个顶点引出的两条直直的线;通常通过观察实物(如三角板，课本，黑板面等)来认识直角。大于直角的是钝角，小于直角是锐角。长方形有4 条边，分别对边相等,4 个角且都是直角.\n【详解】由分析可得：一张长方形纸片有4 个角，其中有4 个直角。一条红领巾有3 个角，其中最大的角是钝角。",
+    "knowledge_points": [
+      "长方形的概念及特点",
+      "角的初步认识及辨认",
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "24-25 二年级上·福建福州·期中"
+  },
+  {
+    "id": "185",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "直角肯定比锐角大，比钝角小。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】比直角小的角是锐角，比直角大的角是钝角.\n【详解】由分析可得：直角肯定比锐角大，比钝角小，原题说法正确。故答案为:√",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征",
+      "角的大小比较"
+    ],
+    "source": "24-25 二年级上·新疆乌鲁木齐·期中"
+  },
+  {
+    "id": "186",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "用放大镜看一个角，看到的角度数一定变大了。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】角的度数的大小，只与两边叉开的大小有关，所以用放大镜看角，只是角的长度变大了，这个角的度数不会发生变化，据此即可解答.\n【详解】由分析知：在放大镜下看一个角，角的大小不变;故原题说法错误;故答案为: ×",
+    "knowledge_points": [
+      "角的初步认识及辨认",
+      "角的大小比较"
+    ],
+    "source": "24-25 二年级上·河南南阳·期中"
+  },
+  {
+    "id": "187",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "三角板上的直角和长方形上的直角是不一样大的。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】从一点引出两条射线所形成的图形叫做角，角是由一个顶点和两条边组成的。和书本，黑板的角相同大小的是直角，直角都是一样大的.\n【详解】三角板上的直角和长方形上的直角是一样大的。原题说法错误。故答案为: ×",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "23-24 二年级上·云南红河·期末"
+  },
+  {
+    "id": "188",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "用放大镜看一个直角，这个直角就会变大，最终成为钝角。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】角由一个顶点和两条边组成，和书本，黑板的角相同大小的是直角，比直角大的是钝角，比直角小的是锐角。角的大小和边的长短无关，只和两边开叉的大小有关，两边开叉越大角越大;两边开叉越小角越小，由此解答.\n【详解】由分析可知，用放大镜看一个直角，这个直角的两条边会变长，角的大小不会变，还是直角。原题说法错误。故答案为: ×",
+    "knowledge_points": [
+      "角的初步认识及辨认",
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "24-25 二年级上·山东临沂·期中"
+  },
+  {
+    "id": "189",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "判断题",
+    "difficulty": 0.65,
+    "question": "所有的直角都是一样大。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】角的大小与两条边张开的大小有关，与边的长短无关。如图，这些都是直角.\n![](images/d4b224bc5374f5b0d0aa7c0a6d590667939c707b7955b7f2d53d96b0dd38b5f7.jpg)\n【详解】由分析可得：所有的直角都是一样大。原题说法正确。故答案为:√",
+    "knowledge_points": [
+      "角的初步认识及辨认",
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "23-24 二年级上·广东汕头·期中"
+  },
+  {
+    "id": "190",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "判断题",
+    "difficulty": 0.65,
+    "question": "每个三角尺上都有两个锐角。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】根据对角的认识可知,![](images/2026-02-20%20232829.jpg)是直角，和书本，课桌的角相等大小的是直角，比直角小的是锐角![](images/2026-02-20%20232850.jpg),比直角大的是钝角![](images/2026-02-20%20232924.jpg)。如图:![](images/2026-02-20%20232954.jpg)三角尺上都有1个直角,2个锐角。由此解答.\n【详解】由分析可得：每个三角尺上都有两个锐角。原题说法正确。故答案为:√",
+    "knowledge_points": [
+      "角的初步认识及辨认",
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "24-25 二年级上·西藏拉萨·期中"
+  },
+  {
+    "id": "191",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "把一个角放到放大镜下观察，角变大了。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】角由一个顶点和两条边组成，角的大小和边的长短无关，只和两条边开叉的大小有关。两条边开叉越大角越大;两条边开叉越小角越小，由此解答.\n【详解】把一个角放到放大镜下观察，角的边变长了，两条边开叉的大小不变，角的大小不变，原题说法错误。故答案为: ×",
+    "knowledge_points": [
+      "角的初步认识及辨认"
+    ],
+    "source": "23-24 二年级上·湖南·期末"
+  },
+  {
+    "id": "192",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "如图中有2 个锐角。( )\n\n![](images/74df26f8a1fbc46f8394387de912a774ecffc19bbef9e4d2cbae058b6ca7853e.jpg)",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】角由一个顶点和两条边组成，和书本，黑板的角相同大小的是直角，比直角大的是钝角，比直角小的是锐角，由此解答.\n【详解】图中有 1 个锐角，原题说法错误。![](images/059f3cc32d1b36129a63e3ca3165a962ff53e1cd81237fd26ed9bd707a71db54.jpg)故答案为: ×",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "24-25 二年级上·河南周口·期中"
+  },
+  {
+    "id": "193",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "判断题",
+    "difficulty": 0.65,
+    "question": "用一副三角尺中的两个锐角一定能拼成一个直角。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】角由一个顶点和两条边组成，和书本，黑板的角相同大小的是直角，比直角大的是钝角，比直角小的是锐角。三角尺中最大的角是直角，由此可作图拼出角判断即可.\n【详解】如图为一副三角尺中的两个锐角拼成的角，图1拼成了钝角;图2拼成了锐角;不能拼成直角。原题说法错误.\n![](images/8ce4b5ae861d86a9ea73be7166f108fff064664260955162407a991a5724df76.jpg)\n![](images/3f27d13668025aadedf1f361f5db388c35392ffd3942b6f33f8f6215621283ba.jpg)故答案为: ×",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "24-25 二年级上·河南三门峡·期中"
+  },
+  {
+    "id": "194",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "数学书上的直角比白板上的直角小。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】角由一个顶点和两条边组成。角的大小只和两条边开叉的大小有关。两边开叉越大角越大;两边开叉越小角越小，由此解答.\n【详解】由分析可知，数学书上的直角和白板上的直角，都是直角，一样大。原题说法错误。故答案为: ×",
+    "knowledge_points": [
+      "角的初步认识及辨认",
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "24-25 二年级上·广西玉林·期中"
+  },
+  {
+    "id": "195",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "钟表上 3 时整，时针和分针的夹角是一个直角。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】角由一个顶点和两条边组成。和书本，黑板的角相同大小的是直角。钟面上长针是分针，短针是时针，分针指向12，时针指向几就是几时，由此可作图判断.\n【详解】如图为3 时整，时针和分针的夹角是一个直角，原题说法正确。![](images/3ea56f58a972dabb53ad98a32c6d729488f569125f3586a7cf00f26ede5f7aab.jpg)故答案为:√",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征",
+      "整点时间与钟面指针的位置"
+    ],
+    "source": "24-25 二年级上·河北保定·期中"
+  },
+  {
+    "id": "196",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "用一副三角尺中的锐角拼成的角一定是钝角。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】一副三角尺中的角有 30°,60°,45°,90°,大于直角90°的是钝角，小于直角的是锐角。则把30°的角和45°的角拼在一起是75°的角。75° < 90°,这是锐角，不是钝角，据此解答即可.\n【详解】由分析可得：用一副三角尺中的锐角拼成的角不一定是钝角。原题说法错误。故答案为: ×",
+    "knowledge_points": [
+      "角的初步认识及辨认",
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "24-25 二年级上·山东济宁·期中"
+  },
+  {
+    "id": "197",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "角的边画的越长，这个角就越大。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】由一个点引出两条直直的线所组成的图形是角，这个点是角的顶点，两条直直的线是角的边。角的大小和两边的长短无关，只和两条边开叉的大小有关，两条边开叉越大，角越大;两条边开叉越小，角越小，由此解答.\n【详解】由分析可知，角的边画的长短和角的大小无关，原题说法错误。故答案为: ×",
+    "knowledge_points": [
+      "角的初步认识及辨认"
+    ],
+    "source": "24-25 二年级上·山东临沂·期中"
+  },
+  {
+    "id": "198",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "判断题",
+    "difficulty": 0.65,
+    "question": "所有的三角形都有一个直角。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】在三角板上，最大角就是直角，锐角比直角小，钝角比直角大。所有的三角形都有三个角，三个角可能都是锐角(如图1);也可能有一个直角和两个锐角(如图2);还可能有一个钝角和两个锐角(如图3);据此解决此题.\n![](images/5d33462ac150c1bc4d223e95b34034c5c0c81e5bba0bae0e4cd746277056dfdc.jpg)图1\n![](images/5e0fcb6a4bf54a0cbfe18325faf5edc45a7ab97ff0e7e4bd7bcbe65b67872721.jpg)图2\n![](images/c22b35a6f71e2deb2e1afc2192a09a2d360ff84878ed7ade8e68289b0ebb0f22.jpg)图3\n【详解】由题意分析得：所有的三角形不一定都有一个直角，有可能都是锐角，也有可能有一个钝角;原题说法错误。故答案为: ×",
+    "knowledge_points": [
+      "长方形，正方形，三角形和圆的初步认识",
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "2024 二年级上·全国·专题练习"
+  },
+  {
+    "id": "199",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "一个顶点和两条边都可以组成一个角。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】角有两条直直的边和一个公共端点，这两条直直的边叫做角的边，它们的公共端点叫做角的顶点，据此解答即可.\n【详解】由分析可得，只有两条边连在一个公共顶点上形成的图形才是角，原题说法错误。故答案为: ×",
+    "knowledge_points": [
+      "角的初步认识及辨认"
+    ],
+    "source": "24-25 二年级上·河南南阳·期中"
+  },
+  {
+    "id": "200",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "判断题",
+    "difficulty": 0.65,
+    "question": "直角都比锐角大，也比钝角大。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】从一点引出两条射线所形成的图形叫做角。和书本，黑板的角相同大小的是直角，比直角大的是钝角，比直角小的是锐角，由此解答.\n【详解】钝角比直角大，直角比锐角大。原题表述错误。故答案为: ×",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "24-25 二年级上·山东济宁·期中"
+  },
+  {
+    "id": "201",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下列说法中,( )说得正确.\n小青说：\"角的两条边越长，这个角就越大.\"\n亮亮说：\"老师的三角尺上的直角比同学们三角尺上的直角大.\"\n文文说：\"角的两条边张开得越大，角就越大，角的两条边张开得越小，角就越小.\"",
+    "options": [
+      "A. 小青",
+      "B. 亮亮",
+      "C. 文文"
+    ],
+    "answer": "C",
+    "solution": "【分析】角由一个顶点和两条边组成。和书本，黑板的角相同大小的是直角。角的大小和边的长短无关，只和两条边开叉的大小有关，两边开叉越大角越大;两边开叉越小角越小，由此分析选择.\n【详解】A。角的两条边的长短和角的大小无关，原说法错误;B。老师三角尺上的直角和同学们三角尺上的直角，都是直角，同样大，原说法错误;C。角的两条边张开得越大，角就越大，角的两条边张开得越小，角就越小。原说法正确。所以文文说得正确。故答案为:C",
+    "knowledge_points": [
+      "角的初步认识及辨认",
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "24-25 二年级上·福建福州·期中"
+  },
+  {
+    "id": "202",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面用一副三角尺拼成的角中，最小的是( )。",
+    "options": [
+      "A. ![](images/640d01baa5276adbd69214306fb7f0829c8dd6385727e0927a74ae25620e93de.jpg)",
+      "B. ![](images/d2994df7f33e72dbc7a405f2ce6cb86aee06d23c1fbb2593e2e5ddb9bc2ae43f.jpg)",
+      "C. ![](images/8610ed6b855a47f93890f72cf8676416aea570a39744a651c1f1522c25e5627a.jpg)"
+    ],
+    "answer": "C",
+    "solution": "【分析】在三角板上，最大的角是直角，钝角比直角大，锐角比直角小。可分别将拼成的角和三角板中的直角进行比较，钝角 > 直角 > 锐角。由此解答.\n【详解】A。拼成的角是钝角;B。拼成的角是钝角;C。拼成的角是锐角。钝角 > 锐角，所以最小的是C。故答案为:C",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征",
+      "角的大小比较"
+    ],
+    "source": "24-25 二年级上·宁夏银川·期中"
+  },
+  {
+    "id": "203",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面( )是角。",
+    "options": [
+      "A. ![](images/fb1f1521dea2a23369045ec870b094dfb3fbcedbf667b856ffc2685d207469f6.jpg)",
+      "B. ![](images/da33e28fd4e18e98accba567615ba0fa59246fd765d073f20e05928dcb83013a.jpg)",
+      "C. ![](images/47eb7df5c62148837d40fa625f27472a2b591aeb1a4c6837c0757abd918209aa.jpg)"
+    ],
+    "answer": "B",
+    "solution": "【分析】角是由两条边和一个顶点组成的，结合题意分析解答即可.\n【详解】据分析可知:A,C并不是角，而B是角。故答案为:B",
+    "knowledge_points": [
+      "角的初步认识及辨认"
+    ],
+    "source": "24-25 二年级上·宁夏银川·期中"
+  },
+  {
+    "id": "204",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "数一数，下面图形中一共有( )个角.\n\n![](images/17e53564bbbf63a3b345c9f7ffa193fb3f9ae16d2876286d4aaf1212bdd116f9.jpg)",
+    "options": [
+      "A. 4",
+      "B. 5",
+      "C. 6"
+    ],
+    "answer": "C",
+    "solution": "【分析】由一个点引出两条直直的线所组成的图形是角，这个点是角的顶点，两条直直的线是角的边，由此解答.\n【详解】下面图形中一共有 6 个角。![](images/73aefadd8ab0d02479e90e31c1439df359d8ed39c35ebd03bc31e8856faacf46.jpg)故答案为:C",
+    "knowledge_points": [
+      "角的初步认识及辨认"
+    ],
+    "source": "24-25 二年级上·河北沧州·期中"
+  },
+  {
+    "id": "205",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下图中，角比直角大的是( )。",
+    "options": [
+      "A. ![](images/11343582e1265a0a77d1004bf52874db6d8473d582a52d6e1788d28baa692c66.jpg)",
+      "B. ![](images/d43e81095c9c421b63cc90ba23548fce8db2c9f665ee5176452ee319cee1b2c1.jpg)",
+      "C. ![](images/0789a376653811425e8ef73927219a113c88dcf97171cf5af921f4006ef083eb.jpg)"
+    ],
+    "answer": "C",
+    "solution": "【分析】角由一个顶点和两条边组成。和书本，黑板的角相同大小的是直角，比直角大的是钝角，比直角小的是锐角，三角板上最大的角是直角，可由此比较解答.\n【详解】A。组成的角是直角，不符合题意;B。组成的角是锐角，比直角小，不符合题意;C。组成的角是钝角，比直角大，符合题意。图中角比直角大的是C。故答案为:C",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "24-25 二年级上·湖北十堰·期中"
+  },
+  {
+    "id": "206",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "在直角，锐角和钝角中，最小的角是( )。",
+    "options": [
+      "A. 钝角",
+      "B. 直角",
+      "C. 锐角"
+    ],
+    "answer": "C",
+    "solution": "【分析】三角尺上最大的角为直角，用三角板的直角进行比较测量，比直角小的就是锐角，比直角大的就是钝角。所以钝角 > 直角 > 锐角.\n【详解】钝角 > 直角 > 锐角，在直角，锐角和钝角中，最小的角是锐角。故答案为:C",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征",
+      "角的大小比较"
+    ],
+    "source": "24-25 二年级上·河北保定·期中"
+  },
+  {
+    "id": "207",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "下图中有( )个角.\n\n![](images/27c29075b58ca6b17170f2be65189c2ba4a697cd4509a9d8857b1eb2a30a67ad.jpg)",
+    "options": [
+      "A. 3",
+      "B. 4",
+      "C. 6"
+    ],
+    "answer": "C",
+    "solution": "【分析】角有两条直直的边和一个公共端点，这两条直直的边叫做角的边，它们的公共端点叫做角的顶点。图中单个的角有 3 个，由 2 个单个的角组成的角有 2 个，由3 个单个的角组成的大角有 1 个，用加法求出总数即可.\n【详解】3 + 2 + 1 = 6(个),所以图中有6 个角。故答案为:C",
+    "knowledge_points": [
+      "角的初步认识及辨认",
+      "数图形(数角)"
+    ],
+    "source": "24-25 二年级上·福建福州·期中"
+  },
+  {
+    "id": "208",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "我们的手能比画出各种角，下面图( )中比画的角最大。",
+    "options": [
+      "A. ![](images/a4607dc96bc37d8e9a47787d3f6905a3a5abfcb678a082547cf02cd6280b87e8.jpg)",
+      "B. ![](images/887cd1ca57d4355b3a303d7ead588e07010c57b2341c2443c4ae9b3e4e32f1a2.jpg)",
+      "C. ![](images/b5be96a0a623bbe83bf386f64691fe836ae55cec87533784a537dcd01633632c.jpg)"
+    ],
+    "answer": "C",
+    "solution": "【分析】角的大小与角的两条边张开的程度有关，而角的大小与边的长短没有关系。两边张开的越大，角就越大。三角尺上最大的角为直角，用三角板的直角进行比较测量，比直角小的就是锐角，比直角大的就是钝角。钝角 > 直角 > 锐角，据此比较.\n【详解】A。比画的是锐角;B。比画的是直角;C。比画的是钝角。钝角 > 直角 > 锐角，比画的角最大。故答案为:C",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征",
+      "角的大小比较"
+    ],
+    "source": "24-25 二年级上·陕西汉中·期中"
+  },
+  {
+    "id": "209",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "![](images/4306abf0a97d0a64d7caadb8f8544c8385b326811004d0f323d4fac014459ebe.jpg)中有( )个直角。",
+    "options": [
+      "A. 5",
+      "B. 6",
+      "C. 7"
+    ],
+    "answer": "B",
+    "solution": "【分析】角由一个顶点和两条边组成。和书本，黑板的角相同大小的是直角。三角板中最大的角是直角，由此可用三角板的直角比较解答.\n【详解】由分析作图如下:![](images/5c5cb97ba962666cad2fe0a323cbf8e8f06760e4f5d9ea48c208afba31c123f7.jpg)有6 个直角。故答案为:B",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "24-25 二年级上·广东东莞·期中"
+  },
+  {
+    "id": "210",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "8 时整，时针和分针所形成的较小的角是( )。",
+    "options": [
+      "A. 锐角",
+      "B. 直角",
+      "C. 钝角",
+      "D. 无法确定"
+    ],
+    "answer": "C",
+    "solution": "【分析】先确定分针和时针分别指向哪个数，再根据\"在三角板上，最大角就是直角，锐角比直角小，钝角比直角大\"来判断是什么角即可.\n【详解】如图,8 时整，时针指着8，分针指着12，此时时针和分针形成的角比直角大，是钝角;![](images/163aec29d1075a9bc2dc3778c54165b93a92eec458be723c616ced934d7046bf.jpg)故答案为:C",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征",
+      "整点时间与钟面指针的位置"
+    ],
+    "source": "24-25 二年级上·江西宜春·期中"
+  },
+  {
+    "id": "211",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "数学书上的直角和三角尺上的直角相比,( )。",
+    "options": [
+      "A. 数学书上的直角大",
+      "B. 一样大",
+      "C. 三角尺上的直角大"
+    ],
+    "answer": "B",
+    "solution": "【分析】角由一个顶点和两条边组成，角的大小和边的长短无关，只和两条边开叉的大小有关，叉开得越大角越大;叉开得越小角越小.\n【详解】由分析可知，数学书上的直角和三角尺上的直角，都是直角，一样大。故答案为:B",
+    "knowledge_points": [
+      "角的初步认识及辨认",
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "24-25 二年级上·陕西安康·期中"
+  },
+  {
+    "id": "212",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "用 10 倍的放大镜去看一个角，看到的角( )。",
+    "options": [
+      "A. 变大",
+      "B. 不变",
+      "C. 变小"
+    ],
+    "answer": "B",
+    "solution": "【分析】角的大小跟两边叉开的大小有关，与两边的长短无关。据此解答.\n【详解】用10 倍的放大镜去看一个角，只改变角两边的长度，没有改变角两边叉开的大小，则角的大小不变。故答案为:B",
+    "knowledge_points": [
+      "角的初步认识及辨认",
+      "角的大小比较"
+    ],
+    "source": "24-25 二年级上·广东汕头·期中"
+  },
+  {
+    "id": "213",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面的图形中，是锐角的是( )。",
+    "options": [
+      "A. ![](images/2026-02-22%20134553.jpg)",
+      "B. ![](images/2026-02-22%20134622.jpg)",
+      "C. ![](images/9e70d894986466dae219ef6c2715b7d9c34f1a104789d56884405c0f227f07a6.jpg)"
+    ],
+    "answer": "A",
+    "solution": "【分析】三角尺上最大的角为直角，用三角板的直角进行比较测量，比直角小的就是锐角，比直角大的就是钝角。据此解答.\n【详解】A。是锐角;B。是钝角;C。是直角。是锐角的是A。故答案为:A",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "24-25 二年级上·云南红河·期中"
+  },
+  {
+    "id": "214",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "如图，长方形被剪去一刀，还剩下( )个直角.\n\n![](images/a92c596594e856321b01118728cf3418e3555f8eb7d45604aaf40b5ed27e7d96.jpg)",
+    "options": [
+      "A. 3",
+      "B. 4",
+      "C. 5"
+    ],
+    "answer": "A",
+    "solution": "【分析】角有两条直直的边和一个公共端点，这两条直直的边叫做角的边，它们的公共端点叫做角的顶点;三角板上最大的角就是直角，据此数出长方形被剪去一刀后剩下直角的数量即可.\n【详解】如下图：长方形被剪去一刀，还剩下 3 个直角。故答案为:A",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "24-25 二年级上·吉林四平·期中"
+  },
+  {
+    "id": "215",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面图形中有两个直角的是( )。",
+    "options": [
+      "A. ![](images/7f8f2e640294ee471a5183b3b44a4531754fd886b321fc0879fe3ec2f6c1beb9.jpg)",
+      "B. ![](images/68f143c452939685539d76e97d9ce5ed5e94a1ca9ccca06c70a77f7896b2118b.jpg)",
+      "C. ![](images/fd6590288ffa486b95e0f1549ed92a60597fcd9f1f32f4507f0a6a60f0eb5681.jpg)",
+      "D. ![](images/2a424fd3ce1426598ca98df5053d9380c3f56f36a3c66a09daca5187e2922831.jpg)"
+    ],
+    "answer": "B",
+    "solution": "【分析】角由一个顶点和两条边组成，和书本，黑板的角相同大小的是直角，三角板上最大的角是直角，由此比较解答.\n【详解】A。有 4 个直角，不符合题意;B。有2 个直角，符合题意;C。不是角，不符合题意;D。没有直角，不符合题意;有两个直角的图形是B。故答案为:B",
+    "knowledge_points": [
+      "角的初步认识及辨认"
+    ],
+    "source": "24-25 二年级上·广东江门·期中"
+  },
+  {
+    "id": "216",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面钟面上的角,( )是钝角。",
+    "options": [
+      "A. ![](images/e424f3e757f0064d7df92ba4946926fc5988a5fae6e7138d9fa832745e0ac3f5.jpg)",
+      "B. ![](images/36f1df28878dfa649b1ef0f501fcc9de84d9c93a8a06fe7545f8347e20403e94.jpg)",
+      "C. ![](images/e83fa99302437f472373bb09423aca9573efcffbcf72f40d0bc2dbbaef5de24b.jpg)"
+    ],
+    "answer": "A",
+    "solution": "【分析】角由一个顶点和两条边组成。和书本，黑板的角相同大小的是直角;比直角大的是钝角;比直角小的是锐角。三角板上最大的角是直角，由此可用三角板的直角比较解答.\n【详解】A。是钝角，符合题意;B。是锐角，不符合题意;C。是锐角，不符合题意。A是钝角。故答案为:A",
+    "knowledge_points": [
+      "角的初步认识及辨认",
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "22-23 二年级上·浙江绍兴·期中"
+  },
+  {
+    "id": "217",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "下面用三角尺拼成的角中，拼成钝角的是( )。",
+    "options": [
+      "A. ![](images/7765db8a1ea5221e68cbb3ef4e533b40e5ffd07c6d9401e6815ab8b2d9198ad5.jpg)",
+      "B. ![](images/b663ce839746e26a53ba2c83cef47552940a09e94dff447d7e1542e5f1ffafc9.jpg)",
+      "C. ![](images/dd09901a27337d643936eacc7dfa137b223db8f1fba1868739ab4339929f9b7e.jpg)"
+    ],
+    "answer": "C",
+    "solution": "【分析】角由一个顶点和两条边组成，和书本，黑板的角相同大小的是直角;比直角大的是钝角;比直角小的是锐角。三角尺上最大的角是直角，由此解答.\n【详解】A。图形是由两个锐角拼成的锐角，不符合题意;B。图形是由两个锐角拼成的直角，不符合题意;C。图形是由一个直角和一个锐角拼成的钝角，符合题意。拼成钝角的是C。故答案为:C",
+    "knowledge_points": [
+      "角的初步认识及辨认",
+      "平面图形的拼接"
+    ],
+    "source": "23-24 二年级上·广东珠海·期中"
+  },
+  {
+    "id": "218",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "![](images/2026-02-22%20135717.jpg)数一数，左图有( )个角。",
+    "options": [
+      "A. 1",
+      "B. 2",
+      "C. 3"
+    ],
+    "answer": "A",
+    "solution": "【分析】由一个点引出两条直直的线所组成的图形是角，这个点是角的顶点，两条直直的线是角的边，由此解答.\n【详解】![](images/5c931a0ffe20f0c528cba3e222ec5f622ef41825b0b7cff476e706db34fdc959.jpg)左图有1 个角。故答案为:A",
+    "knowledge_points": [
+      "角的初步认识及辨认"
+    ],
+    "source": "23-24 二年级上·广东珠海·期中"
+  },
+  {
+    "id": "219",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面角中,( )是锐角。",
+    "options": [
+      "A. ![](images/2026-02-22%20135844.jpg)",
+      "B. ![](images/2026-02-22%20135921.jpg)",
+      "C. ![](images/2026-02-22%20135946.jpg)"
+    ],
+    "answer": "A",
+    "solution": "【分析】角由一个顶点和两条边组成。和书本，黑板的角相同大小的是直角，比直角大的是钝角，比直角小的是锐角，三角板上最大的角是直角，可以用三角板的直角比较解答.\n【详解】A。是锐角;B。是直角;C。是钝角。A是锐角。故答案为:A",
+    "knowledge_points": [
+      "角的初步认识及辨认"
+    ],
+    "source": "24-25 二年级上·吉林白城·期中"
+  },
+  {
+    "id": "220",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面物体表面有角的是( )。",
+    "options": [
+      "A. ![](images/883be6692de43e5671f3eb4f7fe3d57883a2fe17027acddfaaed18c8c5ce8d11.jpg)",
+      "B. ![](images/1b4f69c29c948bc2e63d8f28df12770da065054b7dfbab73fcf7e359ff3fd864.jpg)",
+      "C. ![](images/7f0216bcce2b1c37b60584ab4069cdf6287f2cde4b9365952ee248010f564812.jpg)"
+    ],
+    "answer": "C",
+    "solution": "【分析】角有两条直直的边和一个公共端点，这两条直直的边叫做角的边，它们的公共端点叫做角的顶点;据此逐项分析即可.\n【详解】A。是一个光滑的球体，表面没有角;B。上下面是圆，侧面是一个曲面，表面没有角;C。表面有直直的边和公共顶点，有角。故答案为:C",
+    "knowledge_points": [
+      "角的初步认识及辨认"
+    ],
+    "source": "24-25 二年级上·甘肃陇南·期中"
+  },
+  {
+    "id": "221",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "两条交叉在一起的直线，最多会形成( )个直角。",
+    "options": [
+      "A. 4",
+      "B. 3",
+      "C. 2"
+    ],
+    "answer": "A",
+    "solution": "【分析】角由一个顶点和两条边组成，和书本，黑板的角相同大小的是直角。三角板上最大的角是直角。要想两条交叉在一起的直线，形成的直角最多，则两条线呈如图的关系，数出直角的数量即可.\n![](images/a8988ba54cca54d786f11a53d49bb1b03bedc920177328026b6df2502fcc5f9a.jpg)\n【详解】两条交叉在一起的直线，最多会形成4 个直角。故答案为:A",
+    "knowledge_points": [
+      "角的初步认识及辨认",
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "23-24 二年级上·甘肃武威·期中"
+  },
+  {
+    "id": "222",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下图中一共有( )个直角.\n\n![](images/e5986f2a49a52273b98836d417a67d354b4ce8a68d9f80bae0b7ab8cff2de5e8.jpg)",
+    "options": [
+      "A. 4",
+      "B. 2",
+      "C. 1"
+    ],
+    "answer": "B",
+    "solution": "【分析】角由一个顶点和两条边组成。和书本，黑板的角相同大小的是直角，由此解答.\n【详解】![](images/e14422c8a5d92cdf7b1c0e4f9a6ac65453962a6c8634770e4400f5087900a05f.jpg)图中一共有2 个直角。故答案为:B",
+    "knowledge_points": [
+      "角的初步认识及辨认"
+    ],
+    "source": "24-25 二年级上·河北·期中"
+  },
+  {
+    "id": "223",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下图中有( )个是直角.\n\n![](images/ded6b7ba74265a98e0e3ab4cc78c57d44e1f6c077b73027f5372b5c94fb33b27.jpg)",
+    "options": [
+      "A. 2",
+      "B. 3",
+      "C. 4",
+      "D. 6"
+    ],
+    "answer": "B",
+    "solution": "【分析】角由一个顶点和两条边组成，和书本，黑板的角相同大小的是直角，三角尺中最大的角是直角，由此可用三角尺比较解答.\n【详解】![](images/8fedcb78f6fb9e573a3c0c68c55bbb44c439bd1f5084041ee2c74b49fd4814e8.jpg)图中有3 个是直角。故答案为:B",
+    "knowledge_points": [
+      "角的初步认识及辨认"
+    ],
+    "source": "24-25 二年级上·福建莆田·期中"
+  },
+  {
+    "id": "224",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下图中不是角的有( )个.\n\n![](images/2950084c45d483d6d4d11fe387731ba5d5dea95b78b492dfafbdbb878240ce48.jpg)\n①\n![](images/00801d917c89fc2b971e82b90ca63db30e5d767ef7819ad0e3dbcefe6dde24c8.jpg)\n②\n![](images/591b142b4c65cdf0036c180cc21a2f582e54d8137cacf4fd77e728c5d3051e03.jpg)\n③\n![](images/80cb930e3dca572a8f6c6268fcc62235754768d24cf6ceed6fa16afb4370dcb1.jpg)\n④",
+    "options": [
+      "A. 1",
+      "B. 2",
+      "C. 3",
+      "D. 4"
+    ],
+    "answer": "A",
+    "solution": "【分析】由一个点引出两条直直的线所组成的图形是角，这个点是角的顶点，两条直直的线是角的边，由此解答.\n【详解】由分析可知:①是;②不是;③是;④是。图中不是角的有1 个。故答案为:A",
+    "knowledge_points": [
+      "角的初步认识及辨认"
+    ],
+    "source": "24-25 二年级上·福建莆田·期中"
+  },
+  {
+    "id": "225",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "爸爸的手机锁屏密码是一种图形密码，图案里有 1 个直角和 2 个锐角，爸爸设置的手机密码是( )。",
+    "options": [
+      "A. ![](images/28f1ae3f34d6caf0fe01afa3fc5a758c1d456320d1fdeb22496b658c32be4128.jpg)",
+      "B. ![](images/7959e646a1c1b17984b25f89d28d4034cc1192c99c2de2bf5e20fdbea6aceacc.jpg)",
+      "C. ![](images/794c3a1526748669ad1073f92eb6e1233c4e59a453febb456666830960dad131.jpg)"
+    ],
+    "answer": "B",
+    "solution": "【分析】角由一个顶点和两条边组成。和书本，黑板的角相同大小的是直角，比直角大的是钝角，比直角小的是锐角，由此解答.\n【详解】锐角用红色线表示;直角用蓝色线表示;钝角用绿色线表示。A。有 1 个直角和 2 个钝角，不符合题意;B。有 1 个直角和 2 个锐角，符合题意;C。有2 个锐角，不符合题意。爸爸设置的手机密码是B。故答案为:B",
+    "knowledge_points": [
+      "角的初步认识及辨认",
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "24-25 二年级上·福建莆田·期中"
+  },
+  {
+    "id": "226",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下图中的 3 个角( ).\n\n![](images/b16d7aea4b406b19732b16a13afb57e3a047edd34fbc9f8a16dc9582f16d3a09.jpg)",
+    "options": [
+      "A. 第3 个最大",
+      "B. 第1 个最小",
+      "C. 3 个一样大"
+    ],
+    "answer": "C",
+    "solution": "【分析】角由一个顶点和两条边组成。三角板上最大的角是直角，比直角大的是钝角，比直角小的是锐角。角的大小和边的长短无关，只和两条边开叉的大小有关，叉开得越大角越大，叉开得越小角越小，由此解答.\n【详解】由分析可知，题中3 个角都是直角，所有的直角都同样大。所以 3 个角一样大。故答案为:C",
+    "knowledge_points": [
+      "角的初步认识及辨认"
+    ],
+    "source": "24-25 二年级上·福建莆田·期中"
+  },
+  {
+    "id": "227",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "图中有( )个角.\n\n![](images/4c311fbdc6442dce30829559521e1ac91a5297d8ffbfb5a94a6f7a142871875a.jpg)",
+    "options": [
+      "A. 4",
+      "B. 5",
+      "C. 6"
+    ],
+    "answer": "B",
+    "solution": "【分析】角是从顶点分别画两条射线。然后数一数.\n【详解】根据对角的认识可知：图中有5 个角。故答案为:B",
+    "knowledge_points": [
+      "角的初步认识及辨认"
+    ],
+    "source": "23-24 二年级上·浙江温州·期中"
+  },
+  {
+    "id": "228",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "黑板上的直角与三角尺上的直角比较,( )。",
+    "options": [
+      "A. 黑板上的直角大",
+      "B. 三角尺上的直角大",
+      "C. 一样大"
+    ],
+    "answer": "C",
+    "solution": "【分析】三角尺上最大的角就是直角，比直角小的角是锐角，比直角大的角是钝角。角的大小只跟两边叉开的大小有关，与两边的长短无关。据此解答即可.\n【详解】由分析可得，黑板上的直角与三角尺上的直角相比较，只是边更长，两边叉开的大小一样，所以是一样大。故答案为:C",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征",
+      "角的大小比较"
+    ],
+    "source": "23-24 二年级上·浙江温州·期中"
+  },
+  {
+    "id": "229",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "在下面三个图形中，有 2 个直角的是( )。",
+    "options": [
+      "A. ![](images/0a028b7b2ff1045e620b346d3bb5ac55792e44ddeb13651bfdc3488a6b329216.jpg)",
+      "B. ![](images/7a3a5a3716399af44caa40bba9124c9ce4944be9f9a64089e0937c16a586b2a7.jpg)",
+      "C. ![](images/a46be8ca9183f7b76e1ab1847de7085507f0a9e526ae18f217d9fa304c76079a.jpg)"
+    ],
+    "answer": "C",
+    "solution": "【分析】三角板上最大的角就是直角，比直角小的角是锐角，比直角大的角是钝角。据此解答即可.\n【详解】A。有 4 个直角，不符合题意;B。一个直角都没有，不符合题意;C。有 2 个直角，符合题意。故答案为:C",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "23-24 二年级上·浙江温州·期中"
+  },
+  {
+    "id": "230",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面图形中，不是角的是( )。",
+    "options": [
+      "A. ![](images/dddd6d91acd4fe4fbd4d9e5deb42ad2ad3ffb037c39228f6b07bed8c57afce61.jpg)",
+      "B. ![](images/bcf4eb9d23010a2ba1ca8e18995e6ca1cf8760a76ce80a2b31256b09040c9960.jpg)",
+      "C. ![](images/252f2bb6db5f789724921cb83a1c345b960ebdb7fb3d51adedc60a83980a1724.jpg)"
+    ],
+    "answer": "C",
+    "solution": "【分析】由一个点引出两条直直的线所组成的图形是角，这个点是角的顶点，两条直直的线是角的边。由此解答.\n【详解】A。是角;B。是角;C。不是角。所以不是角的是C。故答案为:C",
+    "knowledge_points": [
+      "角的初步认识及辨认"
+    ],
+    "source": "23-24 二年级上·湖北孝感·期中"
+  },
+  {
+    "id": "231",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "图中有( )个直角.\n\n![](images/95c67931ab6981b6838d0bf9dbf4ab1eaf1649904f5eae8140ddb8e7680afcf5.jpg)",
+    "options": [
+      "A. 3",
+      "B. 5",
+      "C. 6"
+    ],
+    "answer": "C",
+    "solution": "【分析】三角尺上最大的角为直角，据此比一比，数一数.\n【详解】正方形中有4 个直角，每个三角形中有1 个直角，则图中有 6 个直角。故答案为:C",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "22-23 二年级上·河南南阳·期中"
+  },
+  {
+    "id": "232",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下图中有( )个直角.\n\n![](images/67812cc5438a6e0b4257786e25c964e65648771ca1bb45e83abe7c074a224bff.jpg)",
+    "options": [
+      "A. 1",
+      "B. 2",
+      "C. 4"
+    ],
+    "answer": "B",
+    "solution": "【分析】三角板上最大的角就是直角，比直角小的角是锐角，比直角大的角是钝角。据此解答即可.\n【详解】如下图:![](images/2ad2360cd049499bdadef58d47e04533e9649484453c7d50578deb73ad342c30.jpg)所以图中一共有2 个直角。故答案为:B",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "23-24 二年级上·河南周口·期中"
+  },
+  {
+    "id": "233",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面各图中，是直角的是( )。",
+    "options": [
+      "A. ![](images/84a27ef925894e3267c02abde3cef654f59df6814228e7085b37896b648cf880.jpg)",
+      "B. ![](images/6d0af456608fbe8bbe70b9aaa9822cc71816927ebcdf0c13169bcbb29fc91451.jpg)",
+      "C. ![](images/a5366663a8256d2f8fdb34de1658ae8a00935a782b684d60e979188a8705f655.jpg)"
+    ],
+    "answer": "B",
+    "solution": "【分析】三角尺上最大的角为直角，用三角板的直角进行比较测量，比直角小的就是锐角，比直角大的就是钝角.\n【详解】A。是锐角;B。是直角;C。是钝角。是直角的是B。故答案为:B",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "23-24 二年级上·新疆巴音郭楞·期中"
+  },
+  {
+    "id": "234",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "黑板上的直角与课本封面上的直角相比较( )。",
+    "options": [
+      "A. 黑板上的直角大",
+      "B. 课本封面上的直角小",
+      "C. 一样大"
+    ],
+    "answer": "C",
+    "solution": "【分析】三角板上最大的角就是直角，比直角小的角是锐角，比直角大的角是钝角。角的大小只跟两边叉开的大小有关，与两边的长短无关。据此解答即可.\n【详解】由分析可得，黑板上的直角与课本封面上的直角相比较，只是边更长，两边叉开的大小一样，所以是一样大。故答案为:C",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征",
+      "角的大小比较"
+    ],
+    "source": "19-20 二年级上·福建厦门·期中"
+  },
+  {
+    "id": "235",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "如图中有( )条线段,( )个角.\n\n![](images/6e16095d0d25df8233a042b29d0d0161c947e0cc13836e1fca4942cd7bbf81fe.jpg)",
+    "options": [
+      "A. 2;2",
+      "B. 3;2",
+      "C. 4;2"
+    ],
+    "answer": "B",
+    "solution": "【分析】线段是一条直直的线，且有2 个端点;角是由1 个点引出两条直直的线所组成的图形;据此解决即可.\n【详解】由题意分析得：如图中有3 条线段,2 个角。故答案为:B",
+    "knowledge_points": [
+      "线段，直线，射线的认识及特征",
+      "角的初步认识及辨认"
+    ],
+    "source": "23-24二年级上·福建漳州·期中"
+  },
+  {
+    "id": "236",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "下面用一副三角尺拼成的角中，是锐角的是( )。",
+    "options": [
+      "A. ![](images/75913343fef1ec62c571d1797a6c15852aee7fe5117bcc8d728b6fb637ee322c.jpg)",
+      "B. ![](images/947d5576ee4db1af2d743f8878f117d6a032e3d9b6851a30fa60d3f8a067b6b1.jpg)",
+      "C. ![](images/d4e905be9cd4712d090579460e66a76f66911c0b29ea77cb423299082b819ec5.jpg)"
+    ],
+    "answer": "A",
+    "solution": "【分析】三角板上最大的角就是直角，比直角小的角是锐角，比直角大的角是钝角。对照三角板上直角的大小判断各选项中拼成的角的类型即可.\n【详解】A。拼成的角比直角小，是锐角;B。拼成的角比直角大，是钝角;C。拼成的角比直角大，是钝角。故答案为:A",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "23-24 二年级上·浙江温州·期中"
+  },
+  {
+    "id": "237",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "下列说法正确的是( )。",
+    "options": [
+      "A. 黑板上的直角比数学书上的直角大",
+      "B. 笔算加减法时，从十位算起",
+      "C. 一副三角尺可以拼出锐角或钝角"
+    ],
+    "answer": "C",
+    "solution": "【分析】角的大小跟两边叉开的大小有关，与两边的长短无关;笔算加减法时，要把相同数位对齐，从个位算起;每个三角尺中，都有一个直角和两个锐角，将两个三角尺最小的角拼在一起可组成一个锐角，将三角尺中的一个直角和另一个三角尺中的锐角拼在一起可组成一个钝角，据此逐项分析即可.\n【详解】A。黑板上的直角和数学书上的直角一样大，只是边更长，原说法错误;B。笔算加减法时，从个位算起，原说法错误;C。一副三角尺可以拼出锐角或钝角，说法正确。故答案为:C",
+    "knowledge_points": [
+      "两位数与两位数的进位加法",
+      "两位数与两位数的退位减法",
+      "直角，钝角，锐角的认识及特征",
+      "角的大小比较"
+    ],
+    "source": "22-23 二年级上·浙江温州·期中"
+  },
+  {
+    "id": "238",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下边的图形有( )个角.\n\n![](images/ac1621dd68cc21c896e36ab46b9f61bd385c2e1756b8d832283bd466c062f23c.jpg)",
+    "options": [
+      "A. 4",
+      "B. 6",
+      "C. 8"
+    ],
+    "answer": "C",
+    "solution": "【分析】由一个点引出两条直直的线所组成的图形是角。由此数出角的数量即可.\n【详解】![](images/171ac44abd5ff5d5e0ad7078abafc26d584a5373e1d4ed8e249b2ed53d357914.jpg)图中有8 个角。故答案为:C",
+    "knowledge_points": [
+      "角的初步认识及辨认"
+    ],
+    "source": "22-23 二年级上·浙江温州·期中"
+  },
+  {
+    "id": "239",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "图中有( )个角.\n\n![](images/43fc210bef2eb7699c527e9a30d0103db4118365dc5aabeb9f5f93a375eae6ec.jpg)",
+    "options": [
+      "A. 6",
+      "B. 8",
+      "C. 9"
+    ],
+    "answer": "A",
+    "solution": "【分析】角有两条直直的边和一个公共端点，这两条直直的边叫做角的边，它们的公共端点叫做角的顶点，由此数出图中角的数量即可.\n【详解】根据对角的认识，数出图中一共有6 个角。故答案为:A",
+    "knowledge_points": [
+      "角的初步认识及辨认"
+    ],
+    "source": "23-24 二年级上·山东菏泽·期中"
+  },
+  {
+    "id": "240",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下列图形中,( )是钝角。",
+    "options": [
+      "A. ![](images/e998bef55b222116a2081d7959e7817969e1acfbeb5b0dc911af06ef896b6f8f.jpg)",
+      "B. ![](images/ebbc9f527c2a420199a59b433ca283141daf5e9f26c3c7b3038c02d83340d6db.jpg)",
+      "C. ![](images/ca9ff5375b697dbcbaa0e6c3d60d1c1f76b7e0b1195735423c10af5f57686198.jpg)"
+    ],
+    "answer": "A",
+    "solution": "【分析】三角板上最大的角就是直角，比直角小的角是锐角，比直角大的角是钝角。对照三角板上直角的大小判断即可.\n【详解】A。比直角开口大，是钝角;B。是直角;C。比直角开口小，是锐角。故答案为:A",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "23-24 二年级上·山东菏泽·期中"
+  },
+  {
+    "id": "241",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "如图中,( )是角。",
+    "options": [
+      "A. ![](images/2026-02-22%20142039.jpg)",
+      "B. ![](images/f82919b072c2033035f8f7b8c8f0067b8774ff3bb8d7167710e36db0a6476e91.jpg)"
+    ],
+    "answer": "B",
+    "solution": "【分析】角有两条直直的边和一个公共端点，这两条直直的边叫做角的边，它们的公共端点叫做角的顶点，据此解答即可.\n【详解】A。只有一条直直的边，不是角;B。有两条直直的边和一个公共端点，是角。故答案为:B",
+    "knowledge_points": [
+      "角的初步认识及辨认"
+    ],
+    "source": "23-24 二年级上·河北邢台·期中"
+  },
+  {
+    "id": "242",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "下面( )拼成的角是钝角。",
+    "options": [
+      "A. ![](images/a2aec254effecd6c284106a90de4a90c8d19ff9fc5ade841b5844b0dbcb644c6.jpg)",
+      "B. ![](images/ef6deac5e24d0dbe8a81d77b5d71cfdb5575ac463e4973fca3b31aedd90f9c02.jpg)",
+      "C. ![](images/4fd702f85fa68c41713cd3cddd1cd6844755f86a67cadc4c3a1f75dd597111a7.jpg)"
+    ],
+    "answer": "A",
+    "solution": "【分析】比直角小的角是锐角，比直角大的角是钝角，用三角板的直角去比较，即可知拼成的角是不是钝角.\n【详解】A。拼成的角比三角板的直角大，是钝角，符合题意;B。拼成的角等于三角板的直角，是直角，不符合题意;C。拼成的角比三角板的直角小，是锐角，不符合题意。故答案为:A",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征",
+      "平面图形的拼接"
+    ],
+    "source": "23-24 二年级上·河南漯河·期中"
+  },
+  {
+    "id": "243",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "一个![](images/ba5cd09a5beb8abcbdc1e13d1b8fd50fe3e7a79c174b4c902a05c4eb496c56f8.jpg)有( )个角，每个角都是( )角。",
+    "options": [],
+    "answer": "5;钝",
+    "solution": "【分析】角由一个顶点和两条边组成。和书本，黑板的角相同大小的是直角，比直角大的是钝角，比直角小的是锐角。三角板上最大的角是直角，可由此比较解答.\n【详解】该图形有 5 个角，每个角都是钝角。",
+    "knowledge_points": [
+      "角的初步认识及辨认",
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "24-25二年级上·山东济宁·期中"
+  },
+  {
+    "id": "244",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "教室的黑板表面有( )个角，它们都是( )角。你的一个三角尺上有( )个角，其中有( )个直角。",
+    "options": [],
+    "answer": "4;直;3;1",
+    "solution": "【分析】角有两条直直的边和一个公共端点，这两条直直的边叫做角的边，它们的公共端点叫做角的顶点;三角板上最大的角就是直角，比直角小的角是锐角，比直角大的角是钝角，据此解答即可.\n【详解】如下图:![](images/bb9b4ee35066091c4ec4119b6e7c5870bff06f350671e136f952a0b65b55fd37.jpg)教室的黑板表面有 4 个角，它们都是直角。如下图:![](images/70633a7b976d642e451a4ba12766acccfd6a9f53f59222f7f65754298e62c1d8.jpg)一个三角尺上有 3 个角，其中有 1 个直角。",
+    "knowledge_points": [
+      "角的初步认识及辨认",
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "23-24 二年级上·河南南阳·期中"
+  },
+  {
+    "id": "245",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "下面用三角尺拼成的分别是什么角。填一填.\n\n![](images/82a2ad14972f8bfaf1ae3eccda5f7770690ee6f8ebb7361dd0eee4dbbe6698be.jpg)\n\n( )角;( )角;( )角;( )角",
+    "options": [],
+    "answer": "锐;钝;锐;直",
+    "solution": "【分析】可以利用直角尺根据给出的图片拼一拼，并用直角尺中的直角与图片中的角进行对比，大于直角的是钝角，小于直角的是锐角，据此可得出答案。考查学生对角的认识和直角尺的使用.\n【详解】![](images/85947214ebacb93fb78538b6fe62d5897ee04188e311fa866fdb0c9595f1afdb.jpg)",
+    "knowledge_points": [
+      "角的初步认识及辨认",
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "24-25 二年级上·福建福州·期中"
+  },
+  {
+    "id": "246",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "一个三角尺中有( )个角，最大的角是( )角。红领巾中最大的角是( )角，其余的两个角都是( )角。",
+    "options": [],
+    "answer": "3;直;钝;锐",
+    "solution": "【分析】三角板上最大的角就是直角，比直角小的角是锐角，比直角大的角是钝角。如下图:![](images/01533cfed8318ee792d8603769766487afbcf0b6d8e5ca5b102b2c154850f553.jpg)每一个三角板上都有 1 个直角和 2 个锐角;根据生活常识可知，红领巾上有3 个角，最大的角比直角大，所以最大角是钝角，另外两个是锐角.\n【详解】由分析可得，一个三角尺中有3 个角，最大的角是直角。红领巾中最大的角是钝角，其余的两个角都是锐角。",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "23-24 二年级上·河南三门峡·期中"
+  },
+  {
+    "id": "247",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "如图中，一共有( )个角，其中有( )个钝角，有( )个锐角.\n\n![](images/3bdf271997fb56703866586f554279efa36b0edf0d9b4e2973e968f00c5fef62.jpg)",
+    "options": [],
+    "answer": "4;2;2",
+    "solution": "【分析】角由一个顶点两条边组成，像长方形上直直的角是直角，比直角大的角是钝角，比直角小的角是锐角，据此得出结论即可.\n【详解】根据分析知：图中，一共有 4 个角，其中有 2 个钝角，有 2 个锐角。",
+    "knowledge_points": [
+      "角的初步认识及辨认",
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "22-23 二年级上·广西贵港·期中"
+  },
+  {
+    "id": "248",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "一个三角尺上最少有( )个锐角。",
+    "options": [],
+    "answer": "2",
+    "solution": "【分析】根据对角的认识可知，和书本，课桌的角相等大小的是直角，比直角小的是锐角，比直角大的是钝角。如图：每个三角尺上都有1个直角,2个锐角。由此解答。![](images/fa5000a1a8d7d2e7fde239159c73fb0c69f6f76c66d29b3d953f8684c748fcbf.jpg)\n【详解】由分析可得，一个三角尺上最少有 2 个锐角。",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "23-24 二年级上·河北邯郸·期中"
+  },
+  {
+    "id": "249",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "数一数，图中各有几个角。\n\n![](images/2026-02-22%20154552.jpg)\n\n( )个;( )个;( )个",
+    "options": [],
+    "answer": "3;4;5",
+    "solution": "【分析】角有两条边和一个公共端点，这两条边叫做角的边，它们的公共端点叫做角的顶点，据此数数即可.\n【详解】如图:\n![](images/0dc538cb6548a9330d3280dc027238bafefb6a67dc1567724d72475debf5944b.jpg)\n![](images/f0e5d4ad6692731a60354018f0788156aaba14a860d22d5869f32f49874e0b23.jpg)\n![](images/7c711dd1fb27fee4023bf589c2772c91a6958e544e3c75e4d7b992fa3febbf0b.jpg)",
+    "knowledge_points": [
+      "角的初步认识及辨认"
+    ],
+    "source": "23-24二年级上·河南周口·期中"
+  },
+  {
+    "id": "250",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "下图中,( )号不是角:( )号是直角.\n\n![](images/e5eeb5c62cce1f70aaa0de0fa7a647089f254b4cb40cf2e6ae47514ef7b5a6d5.jpg)\n![](images/ca772423ddf2468fcb7e11ccd2ed000143a6c4b4986dda2af7d46081f8af3c6e.jpg)\n![](images/55e45e52768b0a28b6f22403fdeb7d04a5f11922edc638d5e6c6033ed2bab1c9.jpg)\n![](images/d0b6ad7e50c55d5a96c13a798cffc299a553103ec58f2f41e1f44822959101fc.jpg)",
+    "options": [],
+    "answer": "④;②",
+    "solution": "【分析】从一点引出两条射线组成的图形叫做角;直角可以用三角尺的直角进行比对，小于直角的是锐角，大于直角的是钝角.\n【详解】④号不是角，因为④号有一条边是弯曲的;①,② ,③是角，其中②是直角。则图中④号不是角;②号是直角。",
+    "knowledge_points": [
+      "角的初步认识及辨认",
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "23-24 二年级上·福建福州·期中"
+  },
+  {
+    "id": "251",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "一个三角尺上有( )个角，其中有 1 个( )角。",
+    "options": [],
+    "answer": "3;直",
+    "solution": "【分析】角由一个顶点和两条边组成。和书本，黑板的角相同大小的是直角，比直角小的是锐角，比直角大的是钝角，由此解答.\n【详解】如图为三角尺，一个三角尺上有3 个角，其中有1 个直角.\n![](images/21b93b246863172c390ecc5d777ed778cdcc5e7488cfc47ec6192914222566dc.jpg)",
+    "knowledge_points": [
+      "角的初步认识及辨认"
+    ],
+    "source": "23-24 二年级上·山东济宁·期中"
+  },
+  {
+    "id": "252",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "图中有( )个角，有( )个直角.\n\n![](images/4a02adb9111c97dd65344e6294074a48c363a1abd062f27e9840459a67b2d3d8.jpg)",
+    "options": [],
+    "answer": "8;3",
+    "solution": "【分析】角由一个顶点和两条边组成，和书本，黑板的角相同大小的是直角，由此解答.\n【详解】![](images/6befea9f63d5055f51c69a81d8335c844d3ee16e6a87d6be285c188d543785eb.jpg)图中有8 个角，有3 个直角。",
+    "knowledge_points": [
+      "角的初步认识及辨认"
+    ],
+    "source": "23-24 二年级上·浙江杭州·期中"
+  },
+  {
+    "id": "253",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "如图中，共有( )个直角,( )个锐角和( )个钝角.\n\n![](images/69d475f6a34d4d6ce74ed7469618b1a7d6ac9811f2c6f8addb2d282c04b4b6e7.jpg)",
+    "options": [],
+    "answer": "2;1;1",
+    "solution": "【分析】三角板上最大的角就是直角，比直角小的角是锐角，比直角大的角是钝角。对照三角板上直角的大小判断图形中直角，锐角和钝角的个数即可.\n【详解】图中，数出共有 2 个直角,1 个锐角和 1 个钝角。",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "23-24 二年级上·甘肃庆阳·期中"
+  },
+  {
+    "id": "254",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "下面图形中，有( )条线段,( )个角，其中有( )个锐角.\n\n![](images/f5d046ee6eb3a75da3f85e1eb87148d45a0ee2b5658427a878d3138c0b3dd348.jpg)",
+    "options": [],
+    "answer": "8;7;3",
+    "solution": "【分析】线段是一条直直的线，有限长，有两个端点，可以测量;角有两条直直的边和一个公共端点，这两条直直的边叫做角的边，它们的公共端点叫做角的顶点;三角板上最大的角就是直角，比直角小的角是锐角，比直角大的角是钝角。据此数出图中线段，角，锐角的数量即可.\n【详解】由图可知，单条的线段有6 条，由2 条单条的线段组成的线段有 2 条，所以一共有 6 + 2 = 8(条);数出一共有 7 个角，其中锐角有 3 个。",
+    "knowledge_points": [
+      "线段的初步认识",
+      "直角，钝角，锐角的认识及特征",
+      "数图形(线段，直线，射线)",
+      "数图形(数角)"
+    ],
+    "source": "24-25 二年级上·福建福州·期中"
+  },
+  {
+    "id": "255",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "下图是由( )条线段组成的;其中有( )个直角,( )个钝角.\n\n![](images/00ffa8c2b273f316fb75125c4199fd07ca18788fefee173f50734d728d487b97.jpg)",
+    "options": [],
+    "answer": "5;2;2",
+    "solution": "【分析】线段是一条直直的线，有限长，有两个端点，可以测量;角有两条直直的边和一个公共端点，这两条直直的边叫做角的边，它们的公共端点叫做角的顶点;三角板上最大的角就是直角，比直角小的角是锐角，比直角大的角是钝角。据此数出图中线段，直角，钝角的数量即可.\n【详解】如下图:![](images/5e96229c56660c53217d70dbdc5572aee00eb14624cc04e0016431d922ee619a.jpg)是由 5 条线段组成的;其中有 2 个直角,2 个钝角。",
+    "knowledge_points": [
+      "线段的初步认识",
+      "直角，钝角，锐角的认识及特征",
+      "数图形(线段，直线，射线)",
+      "数图形(数角)"
+    ],
+    "source": "24-25 二年级上·陕西汉中·期中"
+  },
+  {
+    "id": "256",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "一个角是由( )个顶点和( )条边组成的。数学课本的封面有( )个直角。",
+    "options": [],
+    "answer": "1;2;4",
+    "solution": "【分析】由题意可知：角是从一个顶点分别画两条直直的线;结合生活经验，用三角板的直角比一比，比直角小的是锐角，比直角大的是钝角。和直角重合是直角.\n【详解】一个角是由1 个顶点和2 条边组成的。数学课本的封面有4 个直角。",
+    "knowledge_points": [
+      "角的初步认识及辨认",
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "24-25 二年级上·青海果洛·期中"
+  },
+  {
+    "id": "257",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "如下图中，有( )条线段,( )个锐角,( )个钝角,( )个直角.\n\n![](images/b067f576dc647799e88c6e6060b023f3aab16cf37ce8397afb9ec3091ab1ca6e.jpg)",
+    "options": [],
+    "answer": "5;1;2;2",
+    "solution": "【分析】线段是一条直直的线，有限长，有两个端点，可以测量，据此数出图中线段的数量;三角板上最大的角就是直角，比直角小的角是锐角，比直角大的角是钝角。据此数出图中锐角，钝角和直角的数量.\n【详解】下图中，有 5 条线段,1 个锐角,2 个钝角,2 个直角。![](images/0008e4751e1e124028d1e7cee2ef6c91d0e8b8bfd9807914db636077b7d86f92.jpg)",
+    "knowledge_points": [
+      "线段的初步认识",
+      "直角，钝角，锐角的认识及特征",
+      "数图形(线段，直线，射线)"
+    ],
+    "source": "24-25 二年级上·山东济南·期中"
+  },
+  {
+    "id": "258",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "![](images/2026-02-22%20155054.jpg)左图中共有( )个角，其中( )个钝角,( )个锐角。",
+    "options": [],
+    "answer": "4;1;2",
+    "solution": "【分析】角有两条直直的边和一个公共端点，这两条直直的边叫做角的边，它们的公共端点叫做角的顶点，据此数出图中角的数量;三角板上最大的角就是直角，比直角小的角是锐角，比直角大的角是钝角。据此数出图中钝角和锐角的数量.\n【详解】如下图:![](images/70704a4bbd737ea56a1a14f544f1c0bb7d1acef9a609725081f92b324988f631.jpg)所以图中共有 4 个角，其中 1 个钝角,2 个锐角。",
+    "knowledge_points": [
+      "角的初步认识及辨认",
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "24-25 二年级上·河北廊坊·期中"
+  },
+  {
+    "id": "259",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "![](images/9d3ef521d85fab4a649df48d22790a7b3d9ce201fa4bcbc9014362bddf3b4668.jpg)图中有( )条线段，共有( )个角,( )个直角,( )个钝角。",
+    "options": [],
+    "answer": "5;5;3;2",
+    "solution": "【分析】线段有 2 个端点;角是从顶点分别画两条射线;用三角尺的直角与其它角逐个比较，三角尺的直角与之重合是直角，若大于直角是钝角，则小于直角是锐角，据此即可.\n【详解】由分析可得：图中有5 条线段，共有5 个角,3 个直角,2 个钝角。",
+    "knowledge_points": [
+      "线段的初步认识",
+      "线段，直线，射线的认识及特征",
+      "角的初步认识及辨认",
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "24-25 二年级上·云南红河·期中"
+  },
+  {
+    "id": "260",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "五角星有( )个锐角。",
+    "options": [],
+    "answer": "5",
+    "solution": "【分析】角由一个顶点和两条边组成，和书本，黑板的角同样大小的是直角，比直角大的是钝角，比直角小的是锐角，如图为五角星，数出锐角的数量即可。![](images/eb6c684468ce3dcd6597d07573eae7447d322e4314328851f651f732790ed380.jpg)\n【详解】由分析可知：五角星有5 个锐角。",
+    "knowledge_points": [
+      "角的初步认识及辨认"
+    ],
+    "source": "23-24 二年级上·甘肃武威·期中"
+  },
+  {
+    "id": "261",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "三角尺上每一个角都有( )个顶点和( )条边;每条红领巾都有( )个角，其中最大的角是( )角，最小的角是( )角。",
+    "options": [],
+    "answer": "一或1;两或2;3;钝;锐",
+    "solution": "【分析】由一个点引出两条直直的线所形成的图形是角，这个点是角的顶点，两条直直的线是角的边。三角板上最大的角是直角，比直角大的是钝角，比直角小的是锐角。由此解答.\n【详解】三角尺上每一个角都有一个顶点和两条边;每条红领巾都有3 个角，其中最大的角是钝角，最小的角是锐角。![](images/9c8730c790d2d68a0104f0fb812efb43a3042b965c0ee702d944386b6c366464.jpg)",
+    "knowledge_points": [
+      "角的初步认识及辨认",
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "24-25 二年级上·福建莆田·期中"
+  },
+  {
+    "id": "262",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "下图是一副三角板拼成的图形，图中有( )个锐角,( )个直角,( )个钝角.\n\n![](images/6e83ca4ad1ee84de30e8c4c770c816da4c6492df72cb04cf88ea0533e20840b7.jpg)",
+    "options": [],
+    "answer": "5;2;1",
+    "solution": "【分析】角由一个顶点和两条边组成。三角板中最大的角是直角，比直角小的是锐角，比直角大的是钝角。红色线是锐角，绿色线是直角，蓝色线是钝角。![](images/a283e29f917c40a795f5b9f19b4cf5cd634917a5792aa938c7f39a3a90d0d9bf.jpg)\n【详解】该图是一副三角板拼成的图形，图中有5 个锐角,2 个直角,1 个钝角。",
+    "knowledge_points": [
+      "角的初步认识及辨认"
+    ],
+    "source": "23-24 二年级上·河南南阳·期中"
+  },
+  {
+    "id": "263",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "钟面上( )时和( )时整，时针和分针所成的角是直角;5 时整，时针和分针所成的角是( )角;10 时整，时针和分针所成的角是( )角。",
+    "options": [],
+    "answer": "3;9;钝;锐",
+    "solution": "【分析】角由一个顶点和两条边组成，和书本，黑板的角相同大小的是直角，比直角大的是钝角，比直角小的是锐角。钟面上长针是分针，短针是时针。分针指向 12，时针指向 3，是 3 时，形成的角是直角;分针指向 12，时针指向 9，是 9 时，形成的角是直角;分针指向 12，时针指向 5，是 5 时，形成的角是钝角;分针指向12，时针指向10，是10 时，形成的角是锐角.\n![](images/af141fd5256e0059566713af567cea76cf56899cd5e3e9eb8dee235c06edf663.jpg)\n![](images/c386a8268a3288b425e5a210d7f7961c0b1d6b53f4d425cfdc5b151fb1bae2ad.jpg)\n![](images/88144b97d4f9d1170ca19ad232f7c27f1d9614e2485ea62ca9c220cde21a296c.jpg)\n![](images/1ebad8f2b320d4f5af7e51a4f463f38c334713c7577efe071c618bd80eb2ed38.jpg)\n【详解】钟面上3 时和9 时整，时针和分针所成的角是直角;5 时整，时针和分针所成的角是钝角;10 时整，时针和分针所成的角是锐角。",
+    "knowledge_points": [
+      "角的初步认识及辨认",
+      "整点时间与钟面指针的位置"
+    ],
+    "source": "23-24 二年级上·甘肃武威·期中"
+  },
+  {
+    "id": "264",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "晚上9 时，钟面上时针和分针所形成的角是( )角。",
+    "options": [],
+    "answer": "直",
+    "solution": "【分析】角由一个顶点和两条边组成，和书本，黑板的角相同大小的是直角，比直角大的是钝角，比直角小的是锐角。钟面上长针是分针，短针是时针。如图，分针指向12，时针指向 9，是 9 时，形成的角是直角。![](images/7261df5166d77a85530d66d3fd9fbb40063aa80c0b8a1cfe401ea9d84de41ae3.jpg)\n【详解】晚上 9 时，钟面上时针和分针所形成的角是直角。",
+    "knowledge_points": [
+      "角的初步认识及辨认",
+      "整点时间与钟面指针的位置"
+    ],
+    "source": "23-24 二年级上·吉林四平·期中"
+  },
+  {
+    "id": "265",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "下图三角尺上，角1 比角4( ),角2 比角4( ),角3 比角4( )。(填\"大\"或\"小\")\n\n![](images/6a7f292e13dbbe3ce4f32988801c5aeb581da201b2f3507e3c834096a6c56a00.jpg)",
+    "options": [],
+    "answer": "大;小;大",
+    "solution": "【分析】角的大小只跟两边叉开的大小有关，与两边的长短无关，角的开口越大，角就越大，开口越小，角就越小。据此解答即可.\n【详解】由图可知，角1 的开口比角4 的开口大，所以角1 比角4 大，角2 的开口比角4 的开口小，所以角2 比角4 小，角3 的开口比角4 的开口大，所以角3 比角4 大。",
+    "knowledge_points": [
+      "角的大小比较"
+    ],
+    "source": "24-25 二年级上·河北·期中"
+  },
+  {
+    "id": "266",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "![](images/06d7c7d3f6fb4d9e6875e611365a201b08a8bc14514ad5aab481223604572873.jpg)\n![](images/37fc4fb1224f49769a26525a411ac58a0a63943eff57a87c45d0e4c0eedefd56.jpg)\n![](images/10f0d5ea2ba879bd3ce485c8ae87126f35288de263297f953ab516863118aa9f.jpg)\n![](images/126eeeeba00a084a436c1261d2567473baf8ab026d9edc2abc97ac4c04e89ac7.jpg)\n(1)上面的图形中，最大的角是( ),最小的角是( ),直角是( ).\n(2)比直角小的角有( ),它们都是( )角;比直角大的角有( ),它是( )角.\n(3)想将④号角变得更大些，可将它的两条边( )些。(填\"张开\"或\"收拢\")",
+    "options": [],
+    "answer": "④;③;②;①,③;锐;④;钝;张开",
+    "solution": "【分析】角由一个顶点和两条边组成。三角尺中最大的角是直角，比直角大的是钝角，比直角小的是锐角。角的大小只和两条边开叉的大小有关，叉开得越大角越大;叉开得越小角越小。(1)①③是锐角,②是直角,④是钝角。角的大小排列为④ > ② > ① > ③。(2)比直角小的是①③;比直角大的是④;(3)要想角变大，也就是把两边叉开得更大些，把边张开些即可.\n【详解】(1)上面的图形中，最大的角是④,最小的角是③,直角是②。(2)比直角小的角有①,③,它们都是锐角;比直角大的角有④,它是钝角。(3)想将④号角变得更大些，可将它的两条边张开些。",
+    "knowledge_points": [
+      "角的初步认识及辨认",
+      "角的大小比较"
+    ],
+    "source": "24-25 二年级上·福建莆田·期中"
+  },
+  {
+    "id": "267",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "填一填。(填序号)\n\n![](images/76819ed26afd24e39447b13ec4aa78ade3c80a8a836c52b3f0d847551c425ef4.jpg)\n\n(1)锐角:( )。 (2)直角:( )。 (3)钝角:( )。",
+    "options": [],
+    "answer": "②,⑤,⑥;①,⑦,⑧;③,④",
+    "solution": "【分析】根据图片可知：用三角尺的直角进行比较，和直角重合的是直角，大于直角的是钝角，小于直角的是锐角.\n【详解】(1)锐角:②,⑤,⑥;(2)直角:①,⑦,⑧;(3)钝角:③,④。",
+    "knowledge_points": [
+      "角的初步认识及辨认",
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "24-25 二年级上·甘肃兰州·期中"
+  },
+  {
+    "id": "268",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "将一个长方形上下对折后，再左右对折，形成的两条折痕交叉处有( )个直角。",
+    "options": [],
+    "answer": "4",
+    "solution": "【分析】长方形是长长方方的，有4条直直的边，对边相等。角由一个顶点和两条边组成，和书本，黑板的角相同大小的是直角，由此解答.\n【详解】如图：将一个长方形上下对折后，再左右对折，形成的两条折痕交叉处有4个直角.\n![](images/963b22bbf1303d2856cee4bd9c4e47ad629efa7373ae6255061360df23aa37c5.jpg)",
+    "knowledge_points": [
+      "角的初步认识及辨认"
+    ],
+    "source": "24-25二年级上·福建莆田·期中"
+  },
+  {
+    "id": "269",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "下图中有( )个直角.\n\n![](images/be46d2499f84b655cfd1ce414e54bfcad04b348ac0fe1a01cf33310a4de9712e.jpg)",
+    "options": [],
+    "answer": "3",
+    "solution": "【分析】三角板上最大的角就是直角，比直角小的角是锐角，比直角大的角是钝角。据此数出图形中直角的数量即可.\n【详解】如下图:![](images/c3d448a388c1a0130ca2107d40b78f058143011c4d828f25539f0040fbdb8c2b.jpg)图中有3个直角。",
+    "knowledge_points": [
+      "角的初步认识及辨认",
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "24-25 二年级上·福建莆田·期中"
+  },
+  {
+    "id": "270",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "![](images/1136a54ab1e295b279b5ac9007d2dccc8aea2d83b3ce6cb2d43efe0a98a2a441.jpg)\n\n(1)上边的图形是由( )条线段围成的.\n(2)这个图形里有( )个角;其中有( )个锐角,( )个直角,( )个钝角。",
+    "options": [],
+    "answer": "5;8;4;2;2",
+    "solution": "【分析】(1)线段有两个端点，中间是直直的线，长度可测量，如图数出线段的数量即可;![](images/fa0cceafc0d1ba5aff1848deaf86ac10588c134c3afe0fbbe24b8a774966def5.jpg)(2)角由一个顶点和两条边组成。三角板中最大的角是直角;比直角大的是钝角;比直角小的是锐角。如图，红色线是锐角，蓝色线是直角;绿色线是钝角。![](images/5accf23dc57a9b9cdff8e02ac2c000610d258217dc6756313560459dc3865e97.jpg)\n【详解】(1)上边的图形是由 5 条线段围成的。(2)这个图形里有8 个角;其中有4 个锐角,2 个直角,2 个钝角。",
+    "knowledge_points": [
+      "线段的初步认识",
+      "角的初步认识及辨认"
+    ],
+    "source": "24-25 二年级上·福建莆田·期中"
+  },
+  {
+    "id": "271",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "图中有( )条线段，有( )个角，有( )个锐角，有( )个钝角.\n\n![](images/094cd144ae5bbd7648a57bc502aae00142bab62d21931718a7cf99725a768188.jpg)",
+    "options": [],
+    "answer": "5;8;5;2",
+    "solution": "【分析】线段两端都有端点，不可延长，两个端点间的线条是直的。由一个点引出两条直直的线所组成的图形是角。三角尺上最大的角为直角，用三角板的直角进行比较测量，比直角小的就是锐角，比直角大的就是钝角.\n【详解】图中有 5 条线段，有 8 个角，有 5 个锐角，有 2 个钝角。",
+    "knowledge_points": [
+      "线段的初步认识",
+      "角的初步认识及辨认",
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "24-25 二年级上·福建莆田·期中"
+  },
+  {
+    "id": "272",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "一个角有( )个顶点和( )条边。一条红领巾上最大的角是( )角。",
+    "options": [],
+    "answer": "一或1;两或2;钝",
+    "solution": "【分析】由一个点引出两条直直的线所形成的图形是角，这个点是角的顶点，两条直直的线是角的边。三角板上最大的角是直角，比直角大的是钝角，比直角小的是锐角。如图为红领巾，最大的角是钝角.\n![](images/fdf22dd840229d9b5f72352949fa3300841d2a6d49a81e28c62c4cfa706eb21a.jpg)\n【详解】一个角有一个顶点和两条边。一条红领巾上最大的角是钝角。",
+    "knowledge_points": [
+      "角的初步认识及辨认",
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "24-25 二年级上·福建莆田·期中"
+  },
+  {
+    "id": "273",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "![](images/ef17af5a73af5a0d8529d5d4bfadc3b3b95a24c7d463445b37973684b9b5caf3.jpg)\n( )个角\n![](images/dbc8f533861ac287b94d659c6dfbe24b190222939a7774260a917ed6d7caf8ef.jpg)\n( )条线段",
+    "options": [],
+    "answer": "6;6",
+    "solution": "【分析】(1)角是从顶点分别画两条射线;根据图片可知：从上到下数：一共有3 个较小的角，上面2 个较小的角组成1 个较大的角，下面两较小的角组成1 个较大的角,3 个较小的角组成一个大的角。分别把这几个角相加求出共有的即可。(2)线段有两个端点，有限长，两点之间可以作一条线段。根据图片可知：从前往后数：一共有3 条短的线段，前两条组成一条较长的线段，后面两条短的组成1 条较长的线段,3 条短线段组成一条长线段。分别把这几条相加求出共有的即可.\n【详解】(1)3 + 1 + 1 + 1 = 4 + 1 + 1 = 5 + 1 = 6(个);(2)3 + 1 + 1 + 1 = 4 + 1 + 1 = 5 + 1 = 6(条)。",
+    "knowledge_points": [
+      "线段的初步认识",
+      "线段，直线，射线的认识及特征",
+      "角的初步认识及辨认"
+    ],
+    "source": "23-24 二年级上·浙江温州·期中"
+  },
+  {
+    "id": "274",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "图中共有( )条线段,( )个锐角,( )个直角,( )个钝角.\n\n![](images/c4d2ba8ec1b40ae058f8d304e51f98c55a6e3e3d94aa96312553f1ba32adafa0.jpg)",
+    "options": [],
+    "answer": "6;2;2;2",
+    "solution": "【分析】线段有两个端点，中间是直直的线，长度可测量。角由一个顶点和两条边组成，和书本，黑板同样大小的角是直角，比直角大的是钝角，比直角小的是锐角。红色线是锐角，蓝色线是钝角，绿色线是直角.\n![](images/6c4eed3b92766bdffe9fc221c596052f403c2e242fa919e35f21838a35d028cb.jpg)\n【详解】图中共有6 条线段,2 个锐角,2 个直角,2 个钝角。",
+    "knowledge_points": [
+      "线段的初步认识",
+      "角的初步认识及辨认"
+    ],
+    "source": "23-24 二年级上·湖北孝感·期中"
+  },
+  {
+    "id": "275",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "填\"大\"\"小\"，锐角比直角( ),钝角比直角( )。",
+    "options": [],
+    "answer": "小;大",
+    "solution": "【分析】三角板上最大的角就是直角，比直角小的角是锐角，比直角大的角是钝角。如下图:\n![](images/c014c9bcdd21a4487acf66d1618c605616944b5841b68f058b492af619cb1f5e.jpg)\n![](images/81f4b94585908b4cb2534514925f9e9e34ce7d26f38996f2db3058f0cf04c62c.jpg)\n![](images/53eee3ca9be4adcd6ca89d993374518e78cf2c5fb67695f67d45ada83447f2ce.jpg)\n【详解】由分析可得，锐角比直角小，钝角比直角大。",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征",
+      "角的大小比较"
+    ],
+    "source": "23-24 二年级上·江西九江·期中"
+  },
+  {
+    "id": "276",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "下图中有( )个角，其中有( )个是直角.\n\n![](images/011b882542579cebc915f78640352d64e3e63e4714f96e821af45e29516c8359.jpg)",
+    "options": [],
+    "answer": "5;2",
+    "solution": "【分析】角有两条直直的边和一个公共端点，这两条直直的边叫做角的边，它们的公共端点叫做角的顶点;三角板上最大的角就是直角，比直角小的角是锐角，比直角大的角是钝角。据此解答即可.\n【详解】如下图:![](images/743c60348557207f17545c96d33a6f600c8c43f6bc2975d05874b3b2be9c6ea4.jpg)数出一共有5 个角，其中有2 个是直角。",
+    "knowledge_points": [
+      "角的初步认识及辨认",
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "23-24 二年级上·山东济宁·期中"
+  },
+  {
+    "id": "277",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "下面图形中各有几个角。\n\n![](images/9db4e4a256a9be92bcb70e16c5172e6ceb71cf5d8c96cac22d2b16a2b2da452b.jpg)\n①\n![](images/759e93c44b35b09b3d0793d04729c2800c1268f595f1d6c731242d57265960d9.jpg)\n②\n![](images/ec97b7ed7b615e6523d1e23ab1dedb7a047c8bc5a97b1f2f75b6c7831ecca56c.jpg)\n③\n\n( )个;( )个;( )个",
+    "options": [],
+    "answer": "4;6;5",
+    "solution": "【分析】角是由1 个点引出2 条直直的线所组成的图形;据此数一数，即可解决.\n【详解】由题意分析得:①有4 个;②有6 个;③有5 个。",
+    "knowledge_points": [
+      "角的初步认识及辨认"
+    ],
+    "source": "23-24 二年级上·河南周口·期中"
+  },
+  {
+    "id": "278",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "![](images/19b5adfaf758283a4cee40489ddd913524ba3d149a4e35980e81eb053428269c.jpg)如图中有( )条线段，有( )个锐角，有( )个直角,( )个钝角。",
+    "options": [],
+    "answer": "6;2;5;1",
+    "solution": "【分析】线段有两个端点，两个端点间的线条是直的，不可延长，可以测量;直角等于90度，锐角小于直角，钝角大于直角，利用三角板的直角比划测量.\n【详解】如图中有6 条线段，有2 个锐角，有5 个直角,1 个钝角。",
+    "knowledge_points": [
+      "线段的初步认识",
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "23-24 二年级上·湖北孝感·期中"
+  },
+  {
+    "id": "279",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "如图，图形中有( )条线段,( )个角.\n\n![](images/3d79d4405cfb7a9a9e5c3a185afaced1c5ba7f6dabe6832423a322b2d69431af.jpg)",
+    "options": [],
+    "answer": "3;3",
+    "solution": "【分析】线段有2 个端点，且是一条直直的线;角是由一个顶点引出两条直直的线所组成的图形;据此解决.\n【详解】由题意分析得：如图，图形中有3 条线段,3 个角。![](images/1cf2f6d703ae56997cc057f09b037499cfb6ea4b70fb29e6a719fe5530e8aed2.jpg)",
+    "knowledge_points": [
+      "线段，直线，射线的认识及特征",
+      "角的初步认识及辨认"
+    ],
+    "source": "23-24 二年级上·山东菏泽·期中"
+  },
+  {
+    "id": "280",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "一个角是由( )个顶点和( )条边组成。一张圆形纸，先上下对折再左右对折，展开后的折痕组成( )个直角。",
+    "options": [],
+    "answer": "一或1;两或2;4",
+    "solution": "【分析】由一个点引出两条直直的线所形成的图形是角，这个点是角的顶点，两条直直的线是角的边。和书本，黑板的角相同大小的是直角。圆没有直直的边，如图，圆对折展开后有4 个直角。![](images/6584aa107cfbd5e2dfb8ccd79047cbbd7b7eda6dc57b2cae6efc0f5e3bb3f535.jpg)\n【详解】一个角是由一个顶点和两条边组成。一张圆形纸，先上下对折再左右对折，展开后的折痕组成 4 个直角。",
+    "knowledge_points": [
+      "角的初步认识及辨认"
+    ],
+    "source": "23-24 二年级上·河南漯河·期中"
+  },
+  {
+    "id": "281",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "一条红领巾有( )个角，其中两个角是( )角，一个角是( )角。",
+    "options": [],
+    "answer": "3或三;锐;钝",
+    "solution": "【分析】角由一个顶点和两条边组成，和书本，黑板的角相同大小的是直角，比直角大的是钝角，比直角小的是锐角，由此解答.\n【详解】如图：一条红领巾有3 个角，其中两个角是锐角，一个角是钝角。![](images/ab8368cd1b74a68809c781af0ec3774b6b02994bf0e38311852ca87a8e27c38e.jpg)",
+    "knowledge_points": [
+      "角的初步认识及辨认"
+    ],
+    "source": "23-24 二年级上·湖北荆州·期中"
+  },
+  {
+    "id": "282",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "图中共有( )条线段,( )个角.\n\n![](images/c9d0dedcecd8918925923b81e6c72c69665045d3a91e297918532d2e9fb3eb2d.jpg)",
+    "options": [],
+    "answer": "2;1",
+    "solution": "【分析】线段有两个端点，中间是直直的线，长度可测量;角由一个顶点和两条边组成，由此数出角和线段的数量即可.\n【详解】图中共有 2 条线段,1 个角.\n![](images/9641e5c668b7d01c3630f4c8ca54311f36699da96a5e201547bb4cc4ea98bcc9.jpg)",
+    "knowledge_points": [
+      "线段的初步认识",
+      "角的初步认识及辨认"
+    ],
+    "source": "23-24 二年级上·浙江温州·期中"
+  },
+  {
+    "id": "283",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "钟面上,9:00时，时针与分针形成的角是( )角;4:00 时，时针与分针形成的角是( )角。",
+    "options": [],
+    "answer": "直;钝",
+    "solution": "【分析】三角板上最大的角就是直角，比直角小的角是锐角，比直角大的角是钝角。分针指向12，时针指向几就是几时。据此解答即可.\n【详解】9:00 时，分针指向 12，时针指向 9，如下图:\n![](images/b59e1db97e62168bdd312c7e254ce2b892250644d02490436d07615f04e1e2d5.jpg)\n时针与分针形成的角是直角;4:00 时，分针指向 12，时针指向 4，如下图:\n![](images/55fba0e06926c334647ffc03758dcbc6fbb226cf0ae6d3b441ce4c7b7bf016b5.jpg)\n时针与分针形成的角是钝角。",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征",
+      "整点时间与钟面指针的位置"
+    ],
+    "source": "23-24 二年级上·浙江温州·期中"
+  },
+  {
+    "id": "284",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "角是由( )个顶点,2 条( )组成的。",
+    "options": [],
+    "answer": "1;边",
+    "solution": "【分析】根据角的概念和画法，先画一个点，将这个点作为顶点，用尺子分别向两个方向画两条直线，组成的就是角，据此可以得出答案。考查对角的认识.\n【详解】角是由 1 个顶点,2 条边组成的。",
+    "knowledge_points": [
+      "角的初步认识及辨认",
+      "角的概念及表示方法"
+    ],
+    "source": "22-23 二年级上·浙江温州·期中"
+  },
+  {
+    "id": "285",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "![](images/5fa8f375dd5e6138288a256334cdc9623b360a2b26b3a340e72554304f166b2a.jpg)图中有( )个角，其中有( )个锐角,( )个钝角,( )个直角。",
+    "options": [],
+    "answer": "8;5;1;2",
+    "solution": "【分析】角由一个顶点和两条边组成。和书本，黑板的角相同大小的是直角，比直角小的是锐角，比直角大的是钝角，由此作图如下：红线是锐角，蓝线是钝角;绿线是直角.\n![](images/38274aa196bc5de1b3c585f76c98679212dd4468d776a14116f6ac52f6044af1.jpg)\n【详解】图中有8 个角，其中有5 个锐角,1 个钝角,2 个直角。",
+    "knowledge_points": [
+      "角的初步认识及辨认"
+    ],
+    "source": "22-23 二年级上·浙江杭州·期末"
+  },
+  {
+    "id": "286",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "判断题",
+    "difficulty": 0.65,
+    "question": "把一个正方形剪下一个角，还剩下 5 个角。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】四条边都相等，方方正正的四边形是正方形。动手剪一剪，如下图:\n![](images/1f879be1ff194427ec322746f34eb2f318f475b0454d5a9a429f36d510bfc574.jpg)\n【详解】把一个正方形剪下一个角，还剩下5 个角或者3 个角。原题说法错误。故答案为: ×",
+    "knowledge_points": [
+      "正方形的概念及特点",
+      "角的初步认识及辨认",
+      "平面图形的分割"
+    ],
+    "source": "24-25 二年级上·内蒙古通辽·期中"
+  },
+  {
+    "id": "287",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "钟面上3时整，时针和分针成钝角。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】角由一个顶点和两条边组成。和书本，黑板的角相同大小的是直角，比直角大的是钝角，比直角小的是锐角。钟面上长针是分针，短针是时针，如图，分针指向12，时针指向3，是3 时，组成的角是直角.\n![](images/c855bfe7bf146cdd62dcf860b2f24f2f962433395452753b078296c8b655470a.jpg)\n【详解】由分析可知，钟面上3 时整，时针和分针成直角。原题说法错误。故答案为: ×",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征",
+      "整点时间与钟面指针的位置"
+    ],
+    "source": "24-25 二年级上·湖北襄阳·期中"
+  },
+  {
+    "id": "288",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "判断题",
+    "difficulty": 0.65,
+    "question": "下图中只有 2 个角。( )\n\n![](images/deb8c3e51669e885d796350129e8cd933a85a4e5f482e21fe2ff2147ea54c1d3.jpg)",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】角有两条直直的边和一个公共端点，这两条直直的边叫做角的边，它们的公共端点叫做角的顶点，据此数出图中角的数量即可.\n【详解】如下图:\n![](images/767bef5d64df3c6057f1287f5055d5faa9de70cfd2c390dbf2777b5532e41283.jpg)\n所以图中一共有3 个角，原题说法错误。故答案为: ×",
+    "knowledge_points": [
+      "角的初步认识及辨认",
+      "数图形(数角)"
+    ],
+    "source": "24-25 二年级上·河北廊坊·期中"
+  },
+  {
+    "id": "289",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "判断题",
+    "difficulty": 0.65,
+    "question": "![](images/493706324c798605555fd74f792691b4fece6e4e3b8855264b9bbcb4ec69476c.jpg)\n\n左图中有2 个直角,4 个锐角。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】三角尺上最大的角为直角，用三角板的直角进行比较测量，比直角小的就是锐角，比直角大的就是钝角。据此数一数.\n【详解】左图中有4 个直角,4 个锐角。原题说法错误。故答案为: ×",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "24-25 二年级上·云南红河·期中"
+  },
+  {
+    "id": "290",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "角的大小与两边张开的大小有关，开口越大，角越大。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】角的大小与角的两条边张开的程度有关，而角的大小与边的长短没有关系。两边张开的越大，角就越大.\n【详解】角的大小与两边张开的大小有关，开口越大，角越大。原题说法正确。故答案为:√",
+    "knowledge_points": [
+      "角的大小比较"
+    ],
+    "source": "17-18 四年级上·吉林·期中"
+  },
+  {
+    "id": "291",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "一点和两条线就可以组成一个角。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】由一个点引出两条直直的线所组成的图形是角，这个点是两条线的公共点，是角的顶点，两条直直的线是角的边，由此解答.\n【详解】由分析可知，若两条线没有公共点，就不能形成一个角。原题说法错误。故答案为: ×",
+    "knowledge_points": [
+      "角的初步认识及辨认"
+    ],
+    "source": "24-25 二年级上·陕西西安·期中"
+  },
+  {
+    "id": "292",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "放大镜能放大字，所以也能放大角的度数。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】角由一个顶点和两条边组成，角的大小与边的长短无关，只和两边开叉的大小有关。叉开得越大角越大，叉开得越小角越小，由此解答.\n【详解】由分析可知，放大镜能放大字，能放大角两边的长短，但是不会放大角的度数，原题说法错误。故答案为: ×",
+    "knowledge_points": [
+      "角的初步认识及辨认"
+    ],
+    "source": "23-24 二年级上·广东珠海·期中"
+  },
+  {
+    "id": "293",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "国旗上的直角与粉笔盒上的直角一样大。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】角的大小只跟两边叉开的大小有关，与两边的长短无关。据此解答即可.\n【详解】由分析可得，国旗上的直角与粉笔盒上的直角相比较，只是边更长，两边叉开的大小一样，所以是一样大。原题说法正确。故答案为:√",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征",
+      "角的大小比较"
+    ],
+    "source": "23-24 二年级上·广东珠海·期中"
+  },
+  {
+    "id": "294",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "![](images/2026-02-22%20161230.jpg)(图1)和![](images/2026-02-22%20161255.jpg)(图2)都是角。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】根据角的特点，两条边是两条笔直的线，据此判断画出的图形即可.\n【详解】据分析可知：图1是角，图2不是角。原题说法错误。故答案为: ×",
+    "knowledge_points": [
+      "角的初步认识及辨认"
+    ],
+    "source": "24-25 二年级上·吉林白城·期中"
+  },
+  {
+    "id": "295",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "老师用的大三角板上的直角和同学们用的小三角板上的直角一样大。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】角由一个顶点和两条边组成，角的大小和边的长短无关，只和两条边开叉的大小有关，叉开得越大，角越大，叉开得越小，角越小，由此解答.\n【详解】由分析可知：老师用的大三角板上的直角和同学们用的小三角板上的直角，都是直角，所有的直角一样大，原题说法正确。故答案为:√",
+    "knowledge_points": [
+      "角的初步认识及辨认"
+    ],
+    "source": "23-24 二年级上·甘肃武威·期中"
+  },
+  {
+    "id": "296",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "判断题",
+    "difficulty": 0.65,
+    "question": "用一副三角尺拼不出直角。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】三角板上最大的角就是直角，比直角小的角是锐角，比直角大的角是钝角。每个三角尺中，都有一个直角和两个锐角，可以拼成的角如下:\n![](images/2f386044ed8c9e8583e649554b1a8f442670a8560a69e417a06201f20b95be78.jpg)\n由图可知，用一副三角尺只能拼成钝角和锐角，不能拼成直角，据此判断即可.\n【详解】由分析可得，用一副三角尺拼不出直角。原题说法正确。故答案为:√",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "23-24 二年级上·江西九江·期中"
+  },
+  {
+    "id": "297",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "判断题",
+    "difficulty": 0.65,
+    "question": "下图中有 3 个角。( )\n\n![](images/a01e3de7fe8e50e881b561b24ff99b002c5ecbfdac7c53ce530e7749f99174cb.jpg)",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】角有两条直直的边和一个公共端点，这两条直直的边叫做角的边，它们的公共端点叫做角的顶点，据此数出图中角的数量即可.\n【详解】根据对角的认识可知，数出单个的角有 2 个，由 2 个单个的角组成的大角有1 个，所以一共有 1 + 2 = 3(个),原题说法正确。故答案为:√",
+    "knowledge_points": [
+      "角的初步认识及辨认"
+    ],
+    "source": "23-24 二年级上·河南周口·期中"
+  },
+  {
+    "id": "298",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "判断题",
+    "difficulty": 0.65,
+    "question": "用两幅三角尺拼出来的角，可能是锐角，也可能是直角。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】在三角板上，最大角就是直角，其余的两个角是锐角;锐角比直角小，而钝角比直角大。用两幅三角尺拼出来的角，可能是锐角，也可能是直角，还可能是钝角，如下图.\n![](images/6ad50b142a1dcf14c5f46a35a1e3ac1ae40b113522e2d95ba9bc2be8fc1413f6.jpg)\n拼出的是锐角\n![](images/e71775e2b9a5ef16d292a31b392f57b830e4b119ddcff0feccde7c14b7544801.jpg)\n拼出的是直角\n![](images/decdd55da81e38950f477bb267a18c1ea5c7d30dba6cf8d256f0f4b487c0e278.jpg)\n拼出的是钝角\n【详解】由题意分析得：用两幅三角尺拼出来的角，可能是锐角，也可能是直角;此说法正确。故答案为:√",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征",
+      "平面图形的拼接"
+    ],
+    "source": "23-24 二年级上·山东菏泽·期中"
+  },
+  {
+    "id": "299",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "判断题",
+    "difficulty": 0.65,
+    "question": "一张长方形的纸，剪去一个角，还剩三个角。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】一张长方形的纸，剪去 1 个角以后，还剩几个角，有三种剪法。如下图：剪法一:![](images/2026-02-22%20161558.jpg),还剩 5 个角;剪法二:![](images/2026-02-22%20161617.jpg),还剩 4 个角;剪法三:![](images/2026-02-22%20161641.jpg)还剩 3 个角，据此解答即可.\n【详解】由分析可得，一张长方形的纸，剪去一个角，不一定还剩三个角。原题说法错误。故答案为: ×",
+    "knowledge_points": [
+      "角的初步认识及辨认",
+      "平面图形的分割"
+    ],
+    "source": "23-24 二年级上·山东菏泽·期中"
+  },
+  {
+    "id": "300",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "解答题",
+    "difficulty": 0.65,
+    "question": "下面的图中有( )个锐角,( )个直角,( )个钝角。请在图中画一条直线使它增加4 个直角.\n\n![](images/ce52556f748fcc6372b64b61d380601c5181b01573614ef737cd0b7871140841.jpg)",
+    "options": [],
+    "answer": "0;2;3;画线见详解",
+    "solution": "【分析】在三角板上，最大角就是直角，锐角比直角小，钝角比直角大，据此判断一个角是什么角。先在上边取一个点(不取两端端点),然后在下边也同样取一个点，使得这个点到左端点的长度与上边取的点到左端点的长度一样长，然后把这两个点连起来，就可以使图形增加4 个直角.\n【详解】由题意分析得：图中原有0 个锐角,2 个直角,3 个钝角。在图中画一条直线使它增加4 个直角，如下:\n![](images/7bb467866de4e4015885b6f44479e27450749b4f00426f3db6e69d2ae45b081f.jpg)",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "23-24 二年级上·江西赣州·期中"
+  },
+  {
+    "id": "301",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "图中有( )个角.\n\n![](images/12349f61d6868b8566a097bba85bdb9989e34c4f8097a781a23ca7fbe1b2ab72.jpg)",
+    "options": [
+      "A. 4",
+      "B. 7",
+      "C. 8"
+    ],
+    "answer": "B",
+    "solution": "【分析】由一个点引出两条直直的线所组成的图形是角。作图如下，数出角的数量即可.\n![](images/8047d2516f1cbba1f79c290c0448eb2da862955ac0ab0c5b0c9672da3192625b.jpg)\n【详解】由分析可知，图中有7 个角。故答案为:B",
+    "knowledge_points": [
+      "角的初步认识及辨认"
+    ],
+    "source": "23-24 二年级上·河南周口·期中"
+  },
+  {
+    "id": "302",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "下面有 2 个钝角的图形是( )。",
+    "options": [
+      "A. ![](images/04ecc791d707c0a09d1a5d0eee8e8205c4cd36cd7c0a524483fbf88892d5c983.jpg)",
+      "B. ![](images/3a7e1965bb46814980272b54629d6c8b68456ed4d00e373a927f8f1cb373cdd5.jpg)",
+      "C. ![](images/61fdac16a922e903a59cb7dc4c5e56ebda034df592bd6e57166033a00608ae08.jpg)",
+      "D. ![](images/8636bf1d4727c3c3011f8d014b47dbd46a3619b42f6d7ce92227eb0bae36b378.jpg)"
+    ],
+    "answer": "C",
+    "solution": "【分析】三角尺上最大的角为直角，用三角板的直角进行比较测量，比直角小的就是锐角，比直角大的就是钝角。据此解答.\n【详解】A。四个都是直角;B。1 个钝角,2 个锐角;C。2 个钝角,2 个锐角;D。1 个直角,2 个锐角。有 2 个钝角的图形是C。故答案为:C",
+    "knowledge_points": [
+      "长方形，正方形，三角形和圆的初步认识",
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "23-24 二年级上·福建龙岩·期中"
+  },
+  {
+    "id": "303",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面拼成的角中，最小的是( )。",
+    "options": [
+      "A. ![](images/b558e2c12c6754f24d8eb26dbe8989e7fbb79acaa17adb360bda068f1b8f1977.jpg)",
+      "B. ![](images/dc46e054ecbf9fcd3386a74285340cfde7dc9f23db4697da35d769bea0edebb9.jpg)",
+      "C. ![](images/a400c603b262d957c1a823279657a0d2a245a6c563b51f96c18232ed520850d5.jpg)",
+      "D. ![](images/bc2dd01520fefa20090d92f33db80a2971729b865e4a7f73e9a002cf586ded51.jpg)"
+    ],
+    "answer": "A",
+    "solution": "【分析】根据开口越大角越大的原理，可以观察选项中的角。小于直角的角是锐角，大于直角的角是钝角，据此解答。考查对角的认识和三角尺中角的大小的判断.\n【详解】A。是锐角;B。是钝角;C。是钝角;D。是直角;最小的是A。故答案为:A",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征",
+      "角的大小比较"
+    ],
+    "source": "23-24 二年级上·福建龙岩·期中"
+  },
+  {
+    "id": "304",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "下面拼成的3 个角中最大的是( )。",
+    "options": [
+      "A. ![](images/c24138efee277c2da6d0452ec9a1d976676bb91800865dcde13545e5bc8c9bdf.jpg)",
+      "B. ![](images/24b5f9499257f23d8fe7a420001cc8aa73de5fa8d2f9af75c9c4da861bbaa2cf.jpg)",
+      "C. ![](images/b98ebe02a4ac964d3ba78e76e24e50dcabb36ab3dc5c358ff44973adde205335.jpg)"
+    ],
+    "answer": "A",
+    "solution": "【分析】角由一个顶点和两条边组成。三角尺上最大的角是直角，比直角小的是锐角，比直角大的是钝角，由此解答.\n【详解】A。这个角是由一个直角和一个锐角拼成的，是钝角;B。这个角是由两个锐角拼成的，是锐角;C。这个角是由两个锐角拼成的，是钝角;钝角 > 锐角,A 和 C 中都有相同的一个锐角，比较另一个角即可。A 中另一个角是直角,C 中另一个角是锐角，直角 > 锐角，则A的角最大。拼成的 3 个角中最大的是A。故答案为:A",
+    "knowledge_points": [
+      "角的初步认识及辨认",
+      "角的大小比较"
+    ],
+    "source": "23-24 二年级上·湖北荆州·期中"
+  },
+  {
+    "id": "305",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下图中有( )个钝角.\n\n![](images/72f5331f78d77850302d111fb02fc6cab7057c6c790b92258618df28520c610a.jpg)",
+    "options": [
+      "A. 1",
+      "B. 2",
+      "C. 3"
+    ],
+    "answer": "B",
+    "solution": "【分析】角由一个顶点和两条边组成。三角板中最大的角是直角，比直角大的是钝角，由此可作图数出钝角的数量.\n【详解】由分析作图如下:![](images/8e68f3b54406a0275399a186137fd79dca5c14698a2e825f40b61f2bb5447db4.jpg)图中有 2 个钝角。故答案为:B",
+    "knowledge_points": [
+      "角的初步认识及辨认"
+    ],
+    "source": "23-24 二年级上·湖北荆州·期中"
+  },
+  {
+    "id": "306",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下图中不是角的是( )。",
+    "options": [
+      "A. ![](images/5a20d923a3538cbf297635b2e90d8396e61a17b43e546e27864e2058592fbeb1.jpg)",
+      "B. ![](images/c5b2fd55248306da7a576db0d4e389e18065aa0860277d58dd2d25eaf02e8b9c.jpg)",
+      "C. ![](images/dc7335663ab6d68a08552dd50894cce7462ba397aa8c2976b4a42ab34437fb8c.jpg)"
+    ],
+    "answer": "C",
+    "solution": "【分析】角有两条直直的边和一个公共端点，这两条直直的边叫做角的边，它们的公共端点叫做角的顶点，据此解答即可.\n【详解】A。有两条直直的边和一个公共端点，是角;B。有两条直直的边和一个公共端点，是角;C。没有两条直直的边，不是角。故答案为:C",
+    "knowledge_points": [
+      "角的初步认识及辨认"
+    ],
+    "source": "23-24 二年级上·山东日照·期中"
+  },
+  {
+    "id": "307",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下图中，有( )个直角.\n\n![](images/cb788b64c563e2235994152d8737001ce7ca58cd71c1ee3a07834ef187f55a52.jpg)",
+    "options": [
+      "A. 10",
+      "B. 11",
+      "C. 12"
+    ],
+    "answer": "C",
+    "solution": "【分析】三角板上最大的角就是直角，比直角小的角是锐角，比直角大的角是钝角。对照三角板上直角的大小判断图形中直角的个数即可.\n【详解】如下图:![](images/fc074e72eb24ce8cf89b0ac75037440805b77b97119df0afa2c067d1a75f7ca9.jpg)一共有12 个直角。故答案为:C",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "23-24 二年级上·山东日照·期中"
+  },
+  {
+    "id": "308",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面说法正确的是( )。",
+    "options": [
+      "A. 角的两条边越长，角就越大",
+      "B. 黑板上的直角和数学书上的直角一样大",
+      "C. 如图中,![](images/16aafa8b6d6d839ee4f74d5346508afd58eaab0533ee363a242b4f5d1f2fc4d6.jpg)两个三角尺拼成的角是锐角"
+    ],
+    "answer": "B",
+    "solution": "【分析】角的大小与角的两条边长度无关，和两边叉开的大小有关。直角大小都是相等的。大于直角的角是钝角，小于直角的是锐角.\n【详解】A。角的两条边越长，角就越大。角的大小与角的两条边长度无关，和两边叉开的大小有关。则不符合题意;B。黑板的直角和数学书上的直角都是一样大，符合题意;C。三角尺拼成的角是由直角和锐角拼成，大于直角，为钝角，则不符合题意。故答案为:B",
+    "knowledge_points": [
+      "角的初步认识及辨认",
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "23-24 二年级上·河南焦作·期中"
+  },
+  {
+    "id": "309",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "下面( )两个三角板拼成的是锐角。",
+    "options": [
+      "A. ![](images/43f4fda63aec7073552a85b58cf09951ae4be6f183e474b40eed4864046542b4.jpg)",
+      "B. ![](images/e6683f86251e86f40b2d7fb096b07e9bedc7c983612583abce98f1f669d3f8db.jpg)",
+      "C. ![](images/ca41cef69d0392b730434058cdf0f8b5515e53baf69b88d1fb98c320646aea5d.jpg)"
+    ],
+    "answer": "B",
+    "solution": "【分析】三角尺上最大的角为直角，用三角板的直角进行比较测量，比直角小的就是锐角，比直角大的就是钝角.\n【详解】A。一个锐角和一个直角组成，拼成的是钝角;B。两个锐角组成，其中一个是三角板中最小的锐角，拼成的是锐角;C。一个锐角和一个直角组成，拼成的是钝角。B拼成的是锐角。故答案为:B",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征",
+      "平面图形的拼接"
+    ],
+    "source": "23-24 二年级上·山东临沂·期中"
+  },
+  {
+    "id": "310",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "用一副三角尺拼出了以下三个角，其中( )是锐角。",
+    "options": [
+      "A. ![](images/9f1cd0e58efb54ebf91fcf114dce204526cc7d2fefc8e4f9a2149f9e142fbf3c.jpg)",
+      "B. ![](images/4d9140b5777af4a1fa914e34db2b4267906a076b026472919e6749aeab51ff7f.jpg)",
+      "C. ![](images/91e5f49cd73f98d4e1627f37106447e7f77e5674eea20a885f2d0d6cf62af6e8.jpg)"
+    ],
+    "answer": "B",
+    "solution": "【分析】三角尺上最大的角为直角，用三角板的直角进行比较测量，比直角小的就是锐角，比直角大的就是钝角。据此解答.\n【详解】A。一个直角和一个锐角组成，组成的角比三角尺上的直角大，组成的是钝角;B。两个锐角组成，其中一个锐角是三角板中最小的锐角，组成的角比三角尺上的直角小，组成的是锐角;C。一个直角和一个锐角组成，组成的角比三角尺上的直角大，组成的是钝角。B是锐角。故答案为:B",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "23-24 二年级上·河南驻马店·期中"
+  },
+  {
+    "id": "311",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "两个三角尺拼出的角是( ).\n\n![](images/089b23f49cc58bc5d76eac243d1b672e91d231e19369fab158699d97ce779e88.jpg)",
+    "options": [
+      "A. 直角",
+      "B. 钝角",
+      "C. 锐角"
+    ],
+    "answer": "B",
+    "solution": "【分析】角由一个顶点和两条边组成，和书本，黑板的角相同大小的是直角;比直角大的是钝角;比直角小的是锐角，由此解答.\n【详解】图形是由一个锐角和一个直角拼成的，比直角大，是钝角。故答案为:B",
+    "knowledge_points": [
+      "角的初步认识及辨认"
+    ],
+    "source": "23-24 二年级上·河北邢台·期中"
+  },
+  {
+    "id": "312",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "下面说法正确的有( )句.\n①钟表上显示 3 时，时针和分针成一直角.\n②最小两位数和最大的两位数相差 90.\n③铅笔的左端对准尺子上的刻度3，右端对准刻度10，那么铅笔长 7 厘米.\n④把一个直角两条边剪去一半，这个角变小了。",
+    "options": [
+      "A. 0",
+      "B. 1",
+      "C. 2",
+      "D. 3"
+    ],
+    "answer": "C",
+    "solution": "【分析】①角由一个顶点和两条边组成，和书本，黑板同样大小的角是直角，钟面上分针指向12，时针指向几就是几时。如图分针指向12，时针指向3，是3 时，形成的角是直角;![](images/98d10ee0285da898d877676d8b9b4c2f205d8391d94303fbef0356aaa77d9b6e.jpg)②最小的两位数是10，最大的两位数是99，求相差多少，用减法计算;③测量物体长度时，将物体的左侧与直尺的0 刻度线对齐，物体与直尺放平，不要倾斜，物体右侧与直尺所对应的刻度就是物体的长度;若物体的左侧未与直尺的0 刻度线对齐，则用测量结束的刻度-测量开始的刻度 = 物体的长度;④角的大小与边的长短无关，只和两条边开叉的大小有关.\n【详解】①钟表上显示 3 时，时针和分针成一直角。原说法正确;②99 - 10 = 89，最小两位数和最大的两位数相差89，原说法错误。③10 - 3 = 7(厘米),铅笔的左端对准尺子上的刻度 3，右端对准刻度 10，那么铅笔长7 厘米。原说法正确。④把一个直角两条边剪去一半，这个角不变。原说法错误。说法正确的有2 句。故答案为:C",
+    "knowledge_points": [
+      "长度的测量方法",
+      "两位数与整十数的减法",
+      "角的初步认识及辨认",
+      "整点时间与钟面指针的位置"
+    ],
+    "source": "23-24 二年级上·福建厦门·期中"
+  },
+  {
+    "id": "313",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "用三角尺上的一个直角和一个锐角拼出的角是( )。",
+    "options": [
+      "A. 锐角",
+      "B. 直角",
+      "C. 钝角",
+      "D. 不确定"
+    ],
+    "answer": "C",
+    "solution": "【分析】在三角板上最大的角是直角，钝角比直角大，锐角比直角小(如下图);由此用三角尺上的直角和锐角拼拼选择即可。![](images/2026-02-22%20170456.jpg)\n【详解】如图为三角尺上的一个直角和一个锐角拼成的角，比直角大。![](images/2026-02-22%20170521.jpg)所以用三角尺上的一个直角和一个锐角拼出的角是钝角。故答案为:C",
+    "knowledge_points": [
+      "角的初步认识及辨认"
+    ],
+    "source": "23-24 二年级上·福建厦门·期中"
+  },
+  {
+    "id": "314",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面说法正确的是( )。",
+    "options": [
+      "A. 三角尺上的直角比数学书上的直角大",
+      "B. 角的大小与两条边张开的大小有关",
+      "C. 角的两条边越长，角就越大"
+    ],
+    "answer": "B",
+    "solution": "【分析】所有的直角都是一样大，与三角板上的直角相同，角的大小与边的长短没有关系，与角的两边的张开大小有关，据此即可得出答案。本题考查了学生对于角的初步认识，及影响角的大小的因素.\n【详解】A。直角都是一样大的，原题说法错误;B。角的大小与两条边张开的大小有关，原题说法正确;C。角的大小与两条边长短无关，与两条边张开的大小有关，原题说法错误。故答案为:B",
+    "knowledge_points": [
+      "角的初步认识及辨认",
+      "直角，钝角，锐角的认识及特征",
+      "角的大小比较"
+    ],
+    "source": "23-24 二年级上·河南信阳·期中"
+  },
+  {
+    "id": "315",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面说法正确的是( )。",
+    "options": [
+      "A. 图中共有 2 个角![](images/2026-02-22%20170926.jpg)",
+      "B. 3 个 6 相加写成乘法算式是6×3",
+      "C. 90 厘米长的线段比1 米长的线段长"
+    ],
+    "answer": "B",
+    "solution": "【分析】根据给出的角的图片数一数就可知道共有几个角;通过加法与乘法之间的相互转换;先进行单位的换算,1 米 = 100 厘米，再进行比较.\n【详解】A。数一数图片中的角有两个小角，两个小角可以组成一个大角，所以图片中有3 个角，说法错误;B。6 + 6 + 6，三个6 相加，可用乘法进行计算，列式为6×3或3×6，说法正确;C。1 米 = 100 厘米,90 厘米与100 厘米进行比较，可知90 厘米比100 厘米短，也就是90 厘米长的线段比1 米长的线段短，说法错误。故答案为:B",
+    "knowledge_points": [
+      "同数连加的应用",
+      "角的初步认识及辨认",
+      "厘米和米之间的进率与换算"
+    ],
+    "source": "23-24 二年级上·河北邢台·期中"
+  },
+  {
+    "id": "316",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "下边的图形一共有( )个角.\n\n![](images/a33f60b721a6e24f9e38d46b2c863f57f20abc212fc2a22782c37baca63c1e6d.jpg)",
+    "options": [
+      "A. 5",
+      "B. 4",
+      "C. 3"
+    ],
+    "answer": "C",
+    "solution": "【分析】角是由一个顶点和两条直直的边组成，据此得出结论即可.\n【详解】根据分析知：图中有3 个角。故答案为:C",
+    "knowledge_points": [
+      "角的初步认识及辨认"
+    ],
+    "source": "23-24 二年级上·广东东莞·期中"
+  },
+  {
+    "id": "317",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "如图，钟面上时针与分针所组成的角是( ).\n\n![](images/0b898f3cbec74e99e71d69d81a278adcc8815f2463d3436adfa48cc91ebbc0a4.jpg)",
+    "options": [
+      "A. 直角",
+      "B. 锐角",
+      "C. 钝角"
+    ],
+    "answer": "C",
+    "solution": "【分析】角由一个顶点和两条边组成。和书本，黑板的角相同大小的是直角;比直角小的是锐角;比直角大的是钝角，可以用三角尺上的直角比较解答.\n【详解】由分析可知，钟面上时针与分针所组成的角比直角大，是钝角。故答案为:C",
+    "knowledge_points": [
+      "角的初步认识及辨认"
+    ],
+    "source": "23-24 二年级上·河南南阳·期中"
+  },
+  {
+    "id": "318",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "![](images/abebd090571f4f4d111436f15cda9ed753f04c7519af38a67063519cbec6777b.jpg)这个钟面上时针和分针组成的角是( )。",
+    "options": [
+      "A. 锐角",
+      "B. 直角",
+      "C. 钝角"
+    ],
+    "answer": "B",
+    "solution": "【分析】三角板上最大的角就是直角，比直角小的角是锐角，比直角大的角是钝角。据此解答即可.\n【详解】用三角板的直角对照可得,![](images/f28bba74039f15b5b6a4011386ca30544f4c9d2857fbcec45e8a6351b10c8cd6.jpg)这个钟面上时针和分针组成的角是直角。故答案为:B",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "22-23 二年级上·广西贵港·期中"
+  },
+  {
+    "id": "319",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "![](images/86c7b0e1e32ce28bd3224bf9911962a4f9ec7892b6a713079544b73cfbd6508d.jpg)左图沿图中虚线剪去一个角后，还剩( )个角。",
+    "options": [
+      "A. 5",
+      "B. 4",
+      "C. 3"
+    ],
+    "answer": "B",
+    "solution": "【分析】从一点引出两条直直的线所组成的图形叫角，这点是角的顶点，两条直直的线是角的边。根据角的特征数出如下图剩下图形的角的个数即可.\n【详解】由分析可知:![](images/8b33eef5e11b7b4c14c984febfaf52d300bee475124f72df43d020a1af603668.jpg)左图沿图中虚线剪去一个角后，还剩4 个角。故答案为:B",
+    "knowledge_points": [
+      "角的初步认识及辨认",
+      "数图形(数角)"
+    ],
+    "source": "20-21 二年级上·全国·期中"
+  },
+  {
+    "id": "320",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "数学书的封面上有( )个直角。",
+    "options": [
+      "A. 2",
+      "B. 4",
+      "C. 3"
+    ],
+    "answer": "B",
+    "solution": "【分析】三角板上最大的角就是直角，比直角小的角是锐角，比直角大的角是钝角。对照三角板上直角的大小判断数学书封面上直角的个数即可.\n【详解】数学书的封面如下:![](images/6662d4832f1879c9aa24726cc292cb92d9e56b837578b3b1cc86f82fe8fecaae.jpg)一共有4 个直角。故答案为:B",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "23-24 二年级上·河北邯郸·期中"
+  },
+  {
+    "id": "321",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "![](images/1168213de2b6c02ca498fdc64a57ed23718cd6fa5b6602b418679270d65fa96f.jpg)左图中一共有( )个角。",
+    "options": [
+      "A. 6",
+      "B. 7",
+      "C. 8"
+    ],
+    "answer": "B",
+    "solution": "【分析】角有两条直直的边，有一个公共端点，这两条直直的边叫做角的边，它们的公共端点叫做角的顶点，则两个小三角形各有3 个角,2 个小三角形合成一个大的三角形多出来 1 个角，加起来即可.\n【详解】由分析可得:3 + 3 + 1 = 7(个),故答案为:B",
+    "knowledge_points": [
+      "角的初步认识及辨认"
+    ],
+    "source": "23-24 二年级上·山西忻州·期中"
+  },
+  {
+    "id": "322",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "两个锐角拼在一起，可以拼成( )。",
+    "options": [
+      "A. 只能是直角或钝角",
+      "B. 只能是钝角",
+      "C. 锐角，直角或钝角"
+    ],
+    "answer": "C",
+    "solution": "【分析】比三角尺中的直角小的角是锐角，比三角尺中的直角大的角是钝角，和三角尺中的直角相等的角是直角，据此解答.\n【详解】用一副三角形进行拼凑可知：两个锐角拼在一起可以拼成锐角，直角或钝角。故答案为:C",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "23-24 二年级上·甘肃庆阳·期中"
+  },
+  {
+    "id": "323",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下图钟面上的时针和分针组成的角是( ).\n\n![](images/58c63b659d126a164e5cd7c32c31eed3342397c62d89ed61c92e44cddc1df2f4.jpg)",
+    "options": [
+      "A. 直角",
+      "B. 锐角",
+      "C. 钝角"
+    ],
+    "answer": "C",
+    "solution": "【分析】用三角尺的直角测量分针和时针张开的角度，能重合的就是直角，比直角大的就是钝角，比直角小的就是锐角，据此解答.\n【详解】由分析可知：图中钟面上的时针和分针组成的角比直角大，是钝角;![](images/eeb6d38b03efdcc31307ea80b0a2b1cce9d50121b46e045d8077357356c9cd22.jpg)故答案为:C",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "23-24 二年级上·甘肃庆阳·期中"
+  },
+  {
+    "id": "324",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面的图形中，图( )是钝角。",
+    "options": [
+      "A. ![](images/4333341bf72d3092b3518924144d1a9e1bec86ef63fda8540bd3d925b279a421.jpg)",
+      "B. ![](images/6dd53e8603ddf4a74877311d16b76590ad2b5c17945f2c19a20862dda2aa5d59.jpg)",
+      "C. ![](images/88d55013985700473984ee964c2e9f7887db8fb35981a69256bdea19e6452554.jpg)"
+    ],
+    "answer": "A",
+    "solution": "【分析】三角板上最大的角就是直角，比直角小的角是锐角，比直角大的角是钝角，据此解答即可.\n【详解】A。是钝角，符合题意;B。是直角，不符合题意;C。是锐角，不符合题意。故答案为:A",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "23-24 二年级上·广西贵港·期中"
+  },
+  {
+    "id": "325",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下列说法中，错误的是( )。",
+    "options": [
+      "A. 角的两边越长，角越大",
+      "B. 角的大小与开口大小有关",
+      "C. 角的大小与两边长短无关"
+    ],
+    "answer": "A",
+    "solution": "【分析】角的大小与角两边的长度无关，与角张开的角度有关。据此解答即可.\n【详解】A。角的两边越长，角不一定越大，原说法错误;B。角的大小与开口大小有关，开口越大，角越大，开口越小，角越小，说法正确;C。角的大小与两边长短无关，说法正确。故答案为:A",
+    "knowledge_points": [
+      "角的大小比较"
+    ],
+    "source": "23-24 二年级上·广东江门·期中"
+  },
+  {
+    "id": "326",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "用三角板拼角，拼成的角是钝角的是( )。",
+    "options": [
+      "A. ![](images/95ce8ec9216383fccc6623a5c7e6e8bd4abf15285dbf36d0065142961cd4d9e9.jpg)",
+      "B. ![](images/4196ec688ee172a51d5446bd1ab0f0f8954dd516e2f75df21677d9c90a6f819b.jpg)",
+      "C. ![](images/1245d58b39e5f75b59b65f293711c9769612026a310acdd997d4a421e7018d0a.jpg)"
+    ],
+    "answer": "B",
+    "solution": "【分析】三角尺上最大的角为直角，用三角板的直角进行比较测量，比直角小的就是锐角，比直角大的就是钝角。据此量一量并解答.\n【详解】A。组成的是直角;B。组成的是钝角;C。组成的是锐角。拼成的角是钝角的是B。故答案为:B",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征",
+      "用三角尺画角"
+    ],
+    "source": "23-24 二年级上·福建漳州·期中"
+  },
+  {
+    "id": "327",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面图形中，哪个选项是直角( )。",
+    "options": [
+      "A. ![](images/59c88117681b3577f727f25116a09403a539aa2f4ee2f3c03e30526dac3baea6.jpg)",
+      "B. ![](images/6659b14788833065f4e2e34be916859cd63320c8abe5b8d56e1417600bf70c10.jpg)",
+      "C. ![](images/77bfafd9f2a47bd2a9bf47d58ef5b4d1b659e86e86017336961a5485170da2c5.jpg)"
+    ],
+    "answer": "A",
+    "solution": "【分析】据题意可知，判断哪个角是直角，直角的度数是90°,用三角尺中的直角挨个进行测量，即可判断出直角。考查学生对于角的认识和判断.\n【详解】A。测量可以得出与直角尺的直角重合，是直角;B。测量可以得出大于直角尺中的直角，是钝角;C。测量可以得出小于直角尺中的直角，是锐角。故答案为:A",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "23-24 二年级上·福建漳州·期中"
+  },
+  {
+    "id": "328",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "下面的图形中，有( )个角.\n\n![](images/6ce7675f1c75ff800ac77c1494776b6d6699203de2f0eebfab17de777ab996b0.jpg)",
+    "options": [
+      "A. 3",
+      "B. 2",
+      "C. 1"
+    ],
+    "answer": "A",
+    "solution": "【分析】角有两条边和一个公共端点，这两条边叫做角的边，它们的公共端点叫做角的顶点。有 2 个小角,1 个由两个小角组成的大角，一共 3 个.\n【详解】下面的图形中，有 3 个角。故答案为:A",
+    "knowledge_points": [
+      "角的初步认识及辨认"
+    ],
+    "source": "23-24 二年级上·陕西安康·期中"
+  },
+  {
+    "id": "329",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面( )比直角小。",
+    "options": [
+      "A. ![](images/2026-02-23%20221852.jpg)",
+      "B. ![](images/2026-02-23%20221914.jpg)",
+      "C. ![](images/2026-02-23%20221939.jpg)"
+    ],
+    "answer": "A",
+    "solution": "【分析】三角板上最大的角就是直角，比直角小的角是锐角，比直角大的角是钝角。用三角板上的直角对照各选项的角比较大小即可.\n【详解】A。是锐角，比直角小;B。是直角;C。是钝角，比直角大。故答案为:A",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征",
+      "角的大小比较"
+    ],
+    "source": "23-24 二年级上·江西宜春·期中"
+  },
+  {
+    "id": "330",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "这个图中共有( )个钝角.\n\n![](images/a938ff2ed25987f15f62bf56455592cb96635bfdbdd2fcd77c04951e3890943e.jpg)",
+    "options": [
+      "A. 2",
+      "B. 4",
+      "C. 5"
+    ],
+    "answer": "A",
+    "solution": "【分析】角由一个顶点和两条边组成，和书本，黑板的角相同大小的角是直角，比直角大的是钝角，由此数出钝角的数量即可.\n【详解】由分析作图如下:![](images/d844348bfe43091db95746b0b927fd71ec8da32850348364532d19c50782b745.jpg)图中共有2 个钝角。故答案为:A",
+    "knowledge_points": [
+      "角的初步认识及辨认"
+    ],
+    "source": "22-23 二年级上·山东菏泽·期中"
+  },
+  {
+    "id": "331",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下图中，是直角的是( )。",
+    "options": [
+      "A. ![](images/fa0507b2c6c0dbe52349e3e8684d84bdf53c683d5ce0d1a6336b2bf22086f2a8.jpg)",
+      "B. ![](images/74571304ef891e08c46c2a057f1269782d04c7442b72aefe69bab397279200ce.jpg)",
+      "C. ![](images/0c2bf32f623ed9a4b1b5c7be19b1eaf4bbb9b84624755890bbd6f2c03f0bf78d.jpg)"
+    ],
+    "answer": "B",
+    "solution": "【分析】角由一个顶点和两条边组成。和书本，黑板的角相同大小的是直角，比直角大的是钝角，比直角小的是锐角。可以用三角板上的直角比较解答.\n【详解】A。是锐角;B。是直角;C。是钝角。B是直角。故答案为:B",
+    "knowledge_points": [
+      "角的初步认识及辨认"
+    ],
+    "source": "23-24 二年级上·新疆和田·期中"
+  },
+  {
+    "id": "332",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "下面拼成的3 个角，最大的是( )。",
+    "options": [
+      "A. ![](images/36e4b31c83b5293bdfc919dab53d843746da4b907d2a9334a8fff46069d9ab87.jpg)",
+      "B. ![](images/4e20bfb397ec75e154c259fa1e678dd62990e8bb2e6c05313288bca840b2f98c.jpg)",
+      "C. ![](images/f7014cec2cfe1f6470e9743db407121d2e6194d7eec16b161379ed3d0d616f1f.jpg)"
+    ],
+    "answer": "C",
+    "solution": "【分析】角由一个顶点和两条边组成。和书本，黑板的角相同大小的是直角，比直角大的是钝角，比直角小的是锐角。钝角 > 直角 > 锐角，由此比较拼成的角大小即可.\n【详解】A。此图中的角是由两个锐角拼成的直角;B。此图中的角是由两个锐角拼成的锐角;C。此图中的角是由一个直角和一个锐角拼成的钝角;拼成的 3 个角中，最大的是钝角，也就是C。故答案为:C",
+    "knowledge_points": [
+      "角的初步认识及辨认",
+      "角的大小比较"
+    ],
+    "source": "23-24 二年级上·湖南常德·期中"
+  },
+  {
+    "id": "333",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "如图中有( )个直角.\n\n![](images/62d8c5f4c8608ddb85c71eae5bfd2389dd172406760421b3ed5796c76bff5034.jpg)",
+    "options": [
+      "A. 2",
+      "B. 4",
+      "C. 6"
+    ],
+    "answer": "C",
+    "solution": "【分析】三角尺上最大的角为直角。左边正方形里面有4 个直角，右边部分有2 个直角，然后相加即可.\n【详解】4 + 2 = 6(个),图中有 6 个直角。故答案为:C",
+    "knowledge_points": [
+      "正方形的概念及特点",
+      "角的初步认识及辨认",
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "23-24 二年级上·河南周口·期中"
+  },
+  {
+    "id": "334",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "角的大小与( )有关。",
+    "options": [
+      "A. 两边的长短",
+      "B. 两条边张开的大小",
+      "C. 无法确定"
+    ],
+    "answer": "B",
+    "solution": "【分析】角的大小与两边的长短无关，只有两边张开的大小有关，张开的越大，角越大，张开的越小，角越小.\n【详解】由分析可得：角的大小与两条边张开的大小有关。故答案为:B",
+    "knowledge_points": [
+      "角的初步认识及辨认",
+      "角的概念及表示方法"
+    ],
+    "source": "20-21 四年级上·河北承德·期中"
+  },
+  {
+    "id": "335",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "如图角中，最大的是( )。",
+    "options": [
+      "A. ![](images/69bed8f2299cd9ee29ae2b9fde672702d8fe86a93e95a72cfc4edf482f361e2c.jpg)",
+      "B. ![](images/2026-02-23%20222212.jpg)",
+      "C. ![](images/2026-02-23%20222222.jpg)"
+    ],
+    "answer": "C",
+    "solution": "【分析】在三角板上，最大角就是直角，锐角比直角小，钝角比直角大;即，钝角 > 直角 > 锐角;据此解决即可.\n【详解】A。这是锐角;B。这是直角;C。这是钝角;钝角 > 直角 > 锐角，所以，最大的角是C。故答案为:C",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征",
+      "角的大小比较"
+    ],
+    "source": "19-20 二年级上·全国·单元测试"
+  },
+  {
+    "id": "336",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "把直角，锐角，钝角按一定的顺序排列起来，正确的是( )。",
+    "options": [
+      "A. 锐角 < 直角 < 钝角",
+      "B. 锐角 > 钝角 > 直角",
+      "C. 钝角 < 直角 < 锐角"
+    ],
+    "answer": "A",
+    "solution": "【分析】根据小于直角的是锐角，大于直角的是钝角，直角，锐角，钝角中，钝角最大，锐角最小。据此选择即可.\n【详解】由分析可得：锐角 < 直角 < 钝角。故答案为:A",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "23-24 二年级上·福建福州·期中"
+  },
+  {
+    "id": "337",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "如图中角有( )个.\n\n![](images/2026-02-23%20222518.jpg)",
+    "options": [
+      "A. 2 个",
+      "B. 3 个",
+      "C. 4 个"
+    ],
+    "answer": "B",
+    "solution": "【分析】角是由一个顶点和两条边组成的图形。两条边都是直直的线，由此解答.\n【详解】![](images/2026-02-23%20222545.jpg)图中角有3 个。故答案为:B",
+    "knowledge_points": [
+      "角的初步认识及辨认"
+    ],
+    "source": "23-24 二年级上·甘肃临夏·期中"
+  },
+  {
+    "id": "338",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下图中有( )个锐角.\n\n![](images/823f8c7eb067e9b5037dd18d3e490b9ae0801a182c65e547c6f504383dff4e15.jpg)",
+    "options": [
+      "A. 5",
+      "B. 3",
+      "C. 6"
+    ],
+    "answer": "A",
+    "solution": "【分析】角由一个顶点和两条边组成，和书本，黑板的角相同大小的是直角，比直角小的是锐角，由此解答.\n【详解】由分析作图如下:![](images/d021ffad6d2fbd405f1151dcdabc07d294506a7bb0a3b8634cace86b134663fa.jpg)图中一共有 5 个锐角。故答案为:A",
+    "knowledge_points": [
+      "角的初步认识及辨认"
+    ],
+    "source": "23-24 二年级上·浙江杭州·期中"
+  },
+  {
+    "id": "339",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面的图形中,( )不是角。",
+    "options": [
+      "A. ![](images/2bc52208cbe5a6aa4933c08d7a45804b4fa0ddc69507a1f783371e9d03aaa72a.jpg)",
+      "B. ![](images/9deff85a7fb1e88407015be511ddd26ee02230cc73ed29b6750281ea8ca53a96.jpg)",
+      "C. ![](images/323b96ab4c3da2c3c433312514bf06798671e22539cd452b0be044faa14f3ed0.jpg)"
+    ],
+    "answer": "C",
+    "solution": "【分析】角由一个顶点和两条边组成，两条边都是直直的线，由此解答.\n【详解】A。是角;B。是角;C。不是角。C不是角。故答案为:C",
+    "knowledge_points": [
+      "角的初步认识及辨认"
+    ],
+    "source": "23-24 二年级上·广西百色·期中"
+  },
+  {
+    "id": "340",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "下面角中，最小的是( )。",
+    "options": [
+      "A. ![](images/2026-02-23%20223152.jpg)",
+      "B. ![](images/2026-02-23%20223211.jpg)",
+      "C. ![](images/2026-02-23%20223227.jpg)"
+    ],
+    "answer": "C",
+    "solution": "【分析】三角板上最大的角就是直角，利用三角板的直角为标准，锐角小于直角，钝角大于直角，据此比较解答即可.\n【详解】A。图中的角是钝角，比直角大;B。图中的角是直角;C。图中的角是锐角，比直角小。下面角中，最小的是C。故答案为:C",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征",
+      "角的大小比较"
+    ],
+    "source": "23-24 二年级上·甘肃庆阳·期中"
+  },
+  {
+    "id": "341",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "如果把角的两边延长，这个角( )。",
+    "options": [
+      "A. 变大",
+      "B. 变小",
+      "C. 不能确定",
+      "D. 大小不变"
+    ],
+    "answer": "D",
+    "solution": "【分析】角的大小与两条边的长短无关;与角两条边叉开的大小有关，两边叉开的越大，角就越大;两边叉开的越小，角就越小;据此解决.\n【详解】角的大小与两条边的长短无关，如果把角的两边延长，这个角不变。故答案为:D",
+    "knowledge_points": [
+      "角的初步认识及辨认"
+    ],
+    "source": "23-24 二年级上·湖北省直辖县级单位·期中"
+  },
+  {
+    "id": "342",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "下列说法不正确的是( )。",
+    "options": [
+      "A. 一根旗杆高 13 厘米。",
+      "B. 在口算加减法时，有小括号的先算小括号。",
+      "C. 三角尺上的直角和黑板上的直角一样大。"
+    ],
+    "answer": "A",
+    "solution": "【分析】A。1 厘米大约是指甲盖的宽度，二年级学生双臂展开的长度大约是 1 米，所以计量一根旗杆的高度用\"米\"作单位比较合适;B。在口算加减法时，有小括号要先算括号里面的，再算括号外面的，没有小括号按照从左到右的顺序计算即可;C。三角板上直直的角是直角，角的大小与边的长短无关，只与两边叉开的大小有关。据此逐项分析即可.\n【详解】A。一根旗杆高 13 米;原说法错误;B。在口算加减法时，有小括号的先算小括号，说法正确;C。三角尺上的直角和黑板上的直角一样大，说法正确。故答案为:A",
+    "knowledge_points": [
+      "带有小括号的混合运算",
+      "直角，钝角，锐角的认识及特征",
+      "厘米的认识",
+      "米的认识"
+    ],
+    "source": "23-24 二年级上·浙江温州·期中"
+  },
+  {
+    "id": "343",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "一副三角尺可以拼出( )角。",
+    "options": [
+      "A. 锐角",
+      "B. 钝角",
+      "C. 锐角或钝角"
+    ],
+    "answer": "C",
+    "solution": "【分析】一副三角尺里有锐角和直角，用锐角和直角可以拼出钝角，用锐角和锐角拼成锐角，据此求解.\n【详解】一副三角尺可以拼出锐角或钝角。故答案为:C",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征",
+      "用三角尺画角"
+    ],
+    "source": "23-24 二年级上·浙江温州·期中"
+  },
+  {
+    "id": "344",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面的时刻，分针和时针形成的角是直角的是( )。",
+    "options": [
+      "A. 4 时",
+      "B. 3 时",
+      "C. 7 时"
+    ],
+    "answer": "B",
+    "solution": "【分析】在三角板上，最大角就是直角;钝角比直角大，锐角比直角小。3 时，分针指向12，时针指向3，分针与时针所成的角是直角;9 时，分针指向12，时针指向9，分针与时针所成的角是直角.\n【详解】A。4 时，分针指向12，时针指向4，分针与时针所成的角是钝角;B。3 时，分针指向12，时针指向3，分针与时针所成的角是直角;C。7 时，分针指向12，时针指向7，分针与时针所成的角是钝角;即，分针和时针形成的角是直角的是3 时。故答案为:B",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征",
+      "整点时间与钟面指针的位置"
+    ],
+    "source": "23-24 二年级上·贵州铜仁·期中"
+  },
+  {
+    "id": "345",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "3 时整，钟面上的分针与时针所成的角是( )角。",
+    "options": [],
+    "answer": "直",
+    "solution": "【分析】角由一个顶点和两条边组成。和书本，黑板的角相同大小的是直角，比直角小的是锐角，比直角大的是钝角。分针指向12，时针指向3 是3 时，如图，组成的角是直角。![](images/fe5147b042ce519e0071bec30b84ba2f15334624a49fd4ac1dee8d0825cc5a20.jpg)\n【详解】3 时整，钟面上的分针与时针所成的角是直角。",
+    "knowledge_points": [
+      "角的初步认识及辨认",
+      "整点时间与钟面指针的位置"
+    ],
+    "source": "23-24 二年级上·江西宜春·期中"
+  },
+  {
+    "id": "346",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "比直角小的角叫( ),比直角大的角叫( )。",
+    "options": [],
+    "answer": "锐角;钝角",
+    "solution": "【详解】角由一个顶点和两条边组成。如图：和书本，黑板的角相同大小的是直角，比直角小的角叫锐角，比直角大的角叫钝角。![](images/2026-02-23%20223703.jpg)",
+    "knowledge_points": [
+      "角的初步认识及辨认"
+    ],
+    "source": "16-17 二年级下·四川·课后作业"
+  },
+  {
+    "id": "347",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "![](images/2026-02-23%20223748.jpg)这个指示牌是由( )条线段围成的。这个指示牌上，直角有( )个，锐角有( )个，钝角有( )个。",
+    "options": [],
+    "answer": "5;2;1;2",
+    "solution": "【分析】线段有2 个端点，中间有直直的线，长度可测量。角由一个顶点和两条边组成，和书本，黑板的角相同大小的是直角，比直角大的是钝角，比直角小的是锐角，由此解答.\n【详解】![](images/5a9eaac4e7bba4a7a0b358a43e3583549ef387f3d97a161fa9780179c30f5fcc.jpg)红色线是直角，绿色线是锐角，蓝色线是钝角。这个指示牌是由 5 条线段围成的。这个指示牌上，直角有 2 个，锐角有 1 个，钝角有 2 个。",
+    "knowledge_points": [
+      "线段的初步认识",
+      "角的初步认识及辨认"
+    ],
+    "source": "23-24 二年级上·福建龙岩·期中"
+  },
+  {
+    "id": "348",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "在我们学过的角中，比直角大的角叫( )角，比直角小的角叫( )角。",
+    "options": [],
+    "answer": "钝;锐",
+    "solution": "【详解】根据对角的认识可知，在我们学过的角中，和书本，黑板相同大小的是直角，比直角大的角叫钝角，比直角小的角叫锐角。![](images/2026-02-23%20224430.jpg)",
+    "knowledge_points": [
+      "角的初步认识及辨认",
+      "角的大小比较"
+    ],
+    "source": "23-24 二年级上·山东临沂·期中"
+  },
+  {
+    "id": "349",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "1 时整，时针和分针组成的角是( )角;9 时整，时针和分针组成的角是( )角;4 时整，时针和分针组成的角是( )角。",
+    "options": [],
+    "answer": "锐;直;钝",
+    "solution": "【分析】钟面上长针是分针，短针是时针，分针指向12，时针指向几就是几时。角由一个顶点和两条边组成，和书本，黑板的角相同大小的是直角，比直角大的是钝角，比直角小的是锐角，由此解答.\n【详解】1 时整，时针和分针组成的角是锐角;9 时整，时针和分针组成的角是直角;4 时整，时针和分针组成的角是钝角.\n![](images/c9dba162beeb47655ff9980e37492cecdd5f476bd58ea1683caa85d89cf554bf.jpg)\n![](images/ea0ebf5e0ff80bf9ef98172db868a20148519994eb7ec46dc99450600f2a7e59.jpg)\n![](images/8dd925a4f1f2d32214ac8d327fc434eb2c040a61340f7afbda637f6889a1acb9.jpg)",
+    "knowledge_points": [
+      "角的初步认识及辨认",
+      "整点时间与钟面指针的位置"
+    ],
+    "source": "23-24 二年级上·湖北荆州·期中"
+  },
+  {
+    "id": "350",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "三角尺上的直角和数学书封面上的直角( )。",
+    "options": [],
+    "answer": "一样大",
+    "solution": "【分析】角由一个顶点和两条边组成。角的大小与角的两边张开的程度有关，和边的长短无关，两边张开的越大，角就越大，由此解答.\n【详解】三角尺上的直角和数学书封面上的直角都是直角，一样大。",
+    "knowledge_points": [
+      "角的初步认识及辨认",
+      "角的大小比较"
+    ],
+    "source": "23-24 二年级上·湖北荆州·期中"
+  },
+  {
+    "id": "351",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "数学课本封面上有( )个角，其中锐角有( )个，直角有( )个。",
+    "options": [],
+    "answer": "4;0;4",
+    "solution": "【分析】角由一个顶点和两条边组成。三角尺上最大的角是直角，比直角小的是锐角，比直角大的是钝角，由此解答.\n【详解】数学课本封面上有 4 个角，其中锐角有 0 个，直角有 4 个。",
+    "knowledge_points": [
+      "角的初步认识及辨认"
+    ],
+    "source": "23-24 二年级上·山东济南·期中"
+  },
+  {
+    "id": "352",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "图形![](images/2026-02-23%20224248.jpg)中有( )条线段,( )个锐角,( )个直角,( )个钝角。",
+    "options": [],
+    "answer": "6;4;4;1",
+    "solution": "【分析】线段有2 个端点，用三角尺的直角与其它角逐个比较，若大于直角是钝角，则小于直角是锐角，三角尺的直角与之重合是直角，据此即可.\n【详解】该图形中有 6 条线段,4 个锐角,4 个直角,1 个钝角。",
+    "knowledge_points": [
+      "线段的初步认识",
+      "线段，直线，射线的认识及特征",
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "23-24 二年级上·山东菏泽·期中"
+  },
+  {
+    "id": "353",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "直角比锐角( ),锐角比钝角( )。",
+    "options": [],
+    "answer": "大;小",
+    "solution": "【分析】三角板上最大的角就是直角，比直角小的角是锐角，比直角大的角是钝角，角的开口越大角就越大，据此解答即可.\n【详解】如下图:![](images/2026-02-23%20224430.jpg)所以直角比锐角大，锐角比钝角小。",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征",
+      "角的大小比较"
+    ],
+    "source": "23-24 二年级上·山东济宁·期中"
+  },
+  {
+    "id": "354",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "当时针和分针所组成的角是直角时，可能是( )时或( )时。",
+    "options": [],
+    "answer": "3;9",
+    "solution": "【分析】角由一个顶点和两条边组成。和书本，黑板的角相同大小的是直角。钟面上长针是分针，短针是时针，分针指向12，时针指向几就是几时。当分针指向12，时针指向3 或9 时，组成的角是直角.\n【详解】当时针和分针所组成的角是直角时，可能是3 时或9 时。",
+    "knowledge_points": [
+      "角的初步认识及辨认",
+      "整点时间与钟面指针的位置"
+    ],
+    "source": "23-24 二年级上·河南驻马店·期中"
+  },
+  {
+    "id": "355",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "下面的字母中各藏着几个相应的角。数一数，填一填.\n![](images/2026-02-23%20224623.jpg)\n\n( )个直角;( )个锐角;( )个锐角和( )个钝角",
+    "options": [],
+    "answer": "4;2;3;2",
+    "solution": "【分析】角由一个顶点和两条边组成。和书本，黑板的角相同大小的是直角;比直角大的是钝角;比直角小的是锐角，由此作图如下，数出角的数量即可。![](images/2026-02-23%20224651.jpg)(图 3 红线是锐角，蓝线是钝角)\n【详解】由分析得:![](images/2026-02-23%20224717.jpg)4 个直角;2 个锐角;3 个锐角和2 个钝角。",
+    "knowledge_points": [
+      "角的初步认识及辨认"
+    ],
+    "source": "23-24 二年级上·河北邢台·期中"
+  },
+  {
+    "id": "356",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "如图，图中一共有( )条线段，有( )个直角，有( )个钝角.\n\n![](images/0e50ee66c781953e38448f1faefba5f815de9849767649cc186f75922c80f6b3.jpg)",
+    "options": [],
+    "answer": "6;4;3",
+    "solution": "【分析】线段是一条直直的线且有2 个端点;在三角板上，最大角就是直角，钝角比直角大，锐角比直角小。图中共有6 条线段;下面正方形中有4 个直角;上面一个钝角，左，右两边合在一起的两个角分别组成两个钝角，共3 个钝角.\n【详解】由题意分析得：图中一共有6 条线段，有4 个直角，有3 个钝角。",
+    "knowledge_points": [
+      "线段的初步认识",
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "23-24 二年级上·湖北省直辖县级单位·期中"
+  },
+  {
+    "id": "357",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "图中一共有( )条线段，有( )个锐角，有( )个直角,( )个钝角.\n\n![](images/a877de48faf4a6358e372fb9289727d38b819cf64d9d190f2007e47f8f072a1c.jpg)",
+    "options": [],
+    "answer": "7;3;3;2",
+    "solution": "【分析】线段有2 个端点，且是一条直直的线;在三角板上，最大的角就是直角，锐角比直角小，钝角比直角大;据此找出不同角的个数.\n【详解】由题意分析得：图中一共有7 条线段，有3 个锐角，有3 个直角,2 个钝角。",
+    "knowledge_points": [
+      "线段，直线，射线的认识及特征",
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "23-24 二年级上·江西赣州·期中"
+  },
+  {
+    "id": "358",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "小强用在跳蚤市场买到的两个三角尺拼成了一个角(如图),他拼成的是( )角.\n\n![](images/8507d41e5c2bfb01303f82cc0f86840d09e8536a4b2e455fa2a15dda552962ca.jpg)",
+    "options": [],
+    "answer": "钝",
+    "solution": "【分析】一副三角尺中的角分别是2 个锐角，和一个直角，大于直角的是钝角，小于直角的是锐角，用它们最大的两个锐角进行拼组，大于直角，则为钝角.\n【详解】小强用在跳蚤市场买到的两个三角尺拼成了一个角，他拼成的是钝角。",
+    "knowledge_points": [
+      "角的初步认识及辨认",
+      "直角，钝角，锐角的认识及特征",
+      "用三角尺画角",
+      "平面图形的拼接"
+    ],
+    "source": "23-24 二年级上·河南信阳·期中"
+  },
+  {
+    "id": "359",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "三角形有( )条边，一个三角形最多有( )个钝角。",
+    "options": [],
+    "answer": "3;1",
+    "solution": "【分析】由三条边围成的图形是三角形，像长方形上的直直的角是直角，大于直角的角是钝角，一个三角形最多有1 个钝角，据此得出结论即可.\n【详解】根据分析知：三角形有3 条边，一个三角形最多有1 个钝角。",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征",
+      "三角形的概念及表示方法"
+    ],
+    "source": "23-24 二年级上·广东江门·期中"
+  },
+  {
+    "id": "360",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "下图中，锐角有( )个，直角有( )个，钝角有( )个.\n\n![](images/a87cd580e9fd69994e82fd86e18e0ad89dd7ad8bf0f905b6a02ac765d08e5f00.jpg)",
+    "options": [],
+    "answer": "5;2;1",
+    "solution": "【分析】根据对锐角，钝角和直角的认识，从图中找到比直角小的角即为锐角，比直角大的角即为钝角.\n【详解】根据分析可知，图中两个三角形各有 2 个锐角，右下角两个小的锐角可以组成一个稍大的锐角，一共有2 + 2 + 1 = 5(个),左下角有 1 个直角，左上角的两个锐角也可以组成 1 个直角，一共有 1 + 1 = 2(个);右上角有1 个钝角;所以图中锐角有5 个，直角有2 个，钝角有1 个。",
+    "knowledge_points": [
+      "角的初步认识及辨认"
+    ],
+    "source": "22-23 二年级上·浙江·期中"
+  },
+  {
+    "id": "361",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "我们教室里的( )的四个角都是直角，我们所戴的红领巾有( )个锐角和一个( )角。",
+    "options": [],
+    "answer": "黑板;2;钝",
+    "solution": "【分析】每个三角尺上都有一个直角，要知道一个角是不是直角，可以用三角尺上的直角比一比;小于直角的是锐角，大于直角的是钝角再结合生活经验，即可解答.\n【详解】我们教室里的黑板的四个角都是直角，我们所戴的红领巾有2 个锐角和一个钝角。",
+    "knowledge_points": [
+      "角的初步认识及辨认"
+    ],
+    "source": "23-24 二年级上·河北邢台·期中"
+  },
+  {
+    "id": "362",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "数一数，下面的图形各有几个角。\n\n![](images/4dc35baed0f0f4f730a5cf151894d9eb074183434bd9a04a0b6a9f54020c6244.jpg)\n①\n![](images/bf4fb96a2adcf974fd8083d9656bdfd1a24748c92d8382f2823a4e3647166183.jpg)\n②\n![](images/19458193917a6e8b9de2c9141524d61b04a599e7aac3555afcdbf14d03bb76b1.jpg)\n③\n( )个角;( )个角;( )个角",
+    "options": [],
+    "answer": "3;5;4",
+    "solution": "【分析】角由一个顶点和两条边组成，由此作图如下，数出角的数量即可。![](images/2026-02-23%20225748.jpg)\n【详解】由分析填写如下:①有3 个角;②有5 个角;③有4 个角。",
+    "knowledge_points": [
+      "角的初步认识及辨认"
+    ],
+    "source": "23-24 二年级上·江西宜春·期中"
+  },
+  {
+    "id": "363",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "如图中，有( )个锐角,( )个直角.\n\n![](images/80606d97ffd145cb13b1d6ab998bc7945a20cb63f0b98a83084bafd51622174a.jpg)",
+    "options": [],
+    "answer": "4;3",
+    "solution": "【分析】三角板上最大的角就是直角，比直角小的是锐角。由此依次数出锐角和直角的个数即可.\n【详解】数出图中有4 个锐角,3 个直角。",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "23-24 二年级上·河南周口·期中"
+  },
+  {
+    "id": "364",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "一把三角板上有( )个角，其中( )个是直角。",
+    "options": [],
+    "answer": "3;1",
+    "solution": "【分析】一把三角板上有 3 个角，其中 1 个是直角，其余两个是锐角.\n【详解】一把三角板上有 3 个角，其中 1 个是直角。",
+    "knowledge_points": [
+      "角的初步认识及辨认",
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "23-24 二年级上·河南周口·期中"
+  },
+  {
+    "id": "365",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "如图形中各有几个直角。\n\n![](images/707cfa0620e6bbf1ceae226d3713d27d0067d51286a17aa0af888a64e4adf7f3.jpg)\n①\n![](images/1691f9331825122dab5b8366ead966f23b3c3dcea17ab9bbaaf7cd95e4828fc5.jpg)\n②\n![](images/01f0c032702e8647d88bc2fb634659dfee08c44ab5a4033a4dd6468589e00473.jpg)\n③\n( )个;( )个;( )个",
+    "options": [],
+    "answer": "2;1;4",
+    "solution": "【分析】角由一个顶点和两条边组成。和书本，黑板的角相同大小的是直角，如图，数出直角的数量即可.\n![](images/2026-02-23%20230206.jpg)\n【详解】由分析得:①有2 个;②有1 个;③有4 个。",
+    "knowledge_points": [
+      "角的初步认识及辨认"
+    ],
+    "source": "23-24 二年级上·山东临沂·期中"
+  },
+  {
+    "id": "366",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "下图中线段有( )条，角有( )个.\n\n![](images/54920e5cfc2a7ab4cba3143a606c3b422110eed2e41ff821f2f82bad2a17a4ae.jpg)",
+    "options": [],
+    "answer": "3;2",
+    "solution": "【分析】线段有两个端点，中间是直直的线，长度可测量;由一个点引出两条直直的线所组成的图形是角，由此解答.\n【详解】由分析得：下图中线段有 3 条，角有 2 个。",
+    "knowledge_points": [
+      "线段的初步认识",
+      "角的初步认识及辨认"
+    ],
+    "source": "22-23 二年级上·浙江·期中"
+  },
+  {
+    "id": "367",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "下图中有( )条线段;( )个钝角.\n\n![](images/cac08d74bb806eda4f43b79171394d362bca43555d0774fdd772cf75de6fa843.jpg)",
+    "options": [],
+    "answer": "4;2",
+    "solution": "【分析】线段有两个端点，中间有直直的线，长度可测量;角由一个顶点和两条边组成，和书本，黑板的角相同大小的是直角，比直角大的是钝角。由此解答.\n【详解】由分析作图如下：图中有4 条线段;2 个钝角.\n![](images/06cff19f34970c44181d9b2277211003fa5c12ec91bd34203bd8c753cec08291.jpg)",
+    "knowledge_points": [
+      "线段的初步认识",
+      "角的初步认识及辨认"
+    ],
+    "source": "23-24 二年级上·河南郑州·期中"
+  },
+  {
+    "id": "368",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "图中的图形中有( )条线段，有( )个锐角，有( )个直角，有( )个钝角.\n\n![](images/f0c8452f2afb78f63514b365135c73e9cea7bafa811154158f1df7d573a1a314.jpg)",
+    "options": [],
+    "answer": "5;1;2;2",
+    "solution": "【分析】线段是直直的，有两个端点。从一点引出两条射线组成的图形叫做角。角有一个顶点，两条边，然后用三角尺的直角进行对比数出的角，小于直角的是锐角，大于直角的是钝角.\n【详解】图中的图形中有5 条线段，有1 个锐角，有2 个直角，有2 个钝角。",
+    "knowledge_points": [
+      "线段的初步认识",
+      "线段，直线，射线的认识及特征",
+      "角的初步认识及辨认",
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "20-21 二年级上·辽宁盘锦·期中"
+  },
+  {
+    "id": "369",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "在直角，锐角，钝角中，直角比( )大，比( )小。",
+    "options": [],
+    "answer": "锐角;钝角",
+    "solution": "【分析】比三角尺中的直角小的角是锐角，比三角尺中的直角大的角是钝角，和三角尺中的直角相等的角是直角，据此解答.\n【详解】在直角，锐角，钝角中，直角比锐角大，比钝角小。",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "23-24 二年级上·甘肃武威·期中"
+  },
+  {
+    "id": "370",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "用两把不同的三角尺可以拼出( )角或( )角。",
+    "options": [],
+    "answer": "锐;钝",
+    "solution": "【详解】三角板上最大的角就是直角，每个三角尺中，都有一个直角和两个锐角;比直角小的角是锐角，比直角大的角是钝角。由此可知，将三角尺中的一个直角和另一个三角尺中的锐角拼在一起可组成一个钝角，将三角尺中的最小的锐角和另一个三角尺中的最小的锐角拼在一起可组成一个更大的锐角;综上可知：用两把不同的三角尺可以拼出锐角或钝角。",
+    "knowledge_points": [
+      "角的初步认识及辨认"
+    ],
+    "source": "23-24 二年级上·浙江杭州·期中"
+  },
+  {
+    "id": "371",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "数学书的封面有( )个直角。",
+    "options": [],
+    "answer": "4",
+    "solution": "【分析】从一点引出两条射线组成的图形叫做角。角有一个顶点，两条边，据此数出角的数量，然后用三角尺的直角进行对比数出的角，小于直角的是锐角，大于直角的是钝角.\n【详解】数学书的封面有 4 个直角。",
+    "knowledge_points": [
+      "角的初步认识及辨认",
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "23-24 二年级上·浙江杭州·期中"
+  },
+  {
+    "id": "372",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "锐角比直角( )(选填：大，小);锐角和直角拼出的角是( )角(选填：锐角，直角，钝角);角有( )个顶点,( )条边。",
+    "options": [],
+    "answer": "小;钝;1;2",
+    "solution": "【分析】在三角板上最大的角是直角，钝角比直角大，锐角比直角小(如下图);一个直角和一个锐角一定拼成一个钝角。角是由一个点和两条直直的线所组成的图形，这个点就是角的顶点，两条线就是角的两条边.\n![](images/30dffc8eaf2e3b4fe7af9318cfe90348ac0ef17f4885f12fdc2a12c90780df34.jpg)\n![](images/299dc4a0403d0dfdc66bedaeaf25eb781b1e8311ebb3cd7814392a769848ff29.jpg)\n![](images/57497184a0992ee5f40eb9222d16b0a02acc32e128cee8551538736388647ed9.jpg)\n【详解】由题意分析得：锐角比直角小;锐角和直角拼出的角是钝角;角有 1 个顶点,2 条边。",
+    "knowledge_points": [
+      "角的初步认识及辨认",
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "23-24 二年级上·云南玉溪·期中"
+  },
+  {
+    "id": "373",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "红领巾是少先队员的标志，是少先队组织的重要象征。 ![](images/2026-02-23%20230508.jpg)中最大的角是( )角，另外两个角是( )角。",
+    "options": [],
+    "answer": "钝;锐",
+    "solution": "【分析】三角尺上最大的角为直角，用三角板的直角进行比较测量，比直角小的就是锐角，比直角大的就是钝角。据此解答.\n【详解】 红领巾中最大的角是钝角，另外两个角是锐角。",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "23-24 二年级上·贵州六盘水·期中"
+  },
+  {
+    "id": "374",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "图中有( )个直角，有( )个锐角，有( )个钝角.\n\n![](images/1cf8f88472a687f7b8fb60527df1a77cb38549a81eab8c012964d7195bff7c6c.jpg)",
+    "options": [],
+    "answer": "3;3;2",
+    "solution": "【分析】角由一个顶点和两条边组成，和书本，黑板的角相同大小的是直角;比直角大的是钝角;比直角小的是锐角，由此解答.\n【详解】由分析作图如下：红线为直角;蓝线为锐角;绿线为钝角。![](images/d86197e6fc670bd2dbe465858a3ab541dd53599f34b4b3ecbd361129bcc75341.jpg)图中有3 个直角，有3 个锐角，有2 个钝角。",
+    "knowledge_points": [
+      "角的初步认识及辨认"
+    ],
+    "source": "23-24 二年级上·山东济宁·期中"
+  },
+  {
+    "id": "375",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "教室的黑板表面有( )个角，都是( )。",
+    "options": [],
+    "answer": "4;直角",
+    "solution": "【分析】三角尺上最大的角为直角，用三角板的直角进行比较测量，比直角小的就是锐角，比直角大的就是钝角。据此比一比，数一数.\n【详解】教室的黑板表面有 4 个角，都是直角。",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "23-24 二年级上·广东汕头·期中"
+  },
+  {
+    "id": "376",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "数一数.\n![](images/2026-02-23%20230657.jpg)\n\n( )个角;( )个直角;( )个角",
+    "options": [],
+    "answer": "3;8;8",
+    "solution": "【分析】从一点引出两条射线组成的图形叫做角，这个点叫做顶点。用三角尺的直角进行比较，大于直角的是钝角，小于直角的是锐角。长方形的四个角都是直角。图 1:1 个大角，又分成了 2 个小角，共有 3 个角;图 2：小长方形有 4 个直角，较大长方形有 4 个直角，共 8 个直角。图 3：两个三角形各有3 个角，两个三角形拼在一起，又增加 2 个角。共有 3 + 3 + 2 = 8(个)角.\n【详解】由分析可得:3 个角;8 个直角;8 个角。",
+    "knowledge_points": [
+      "长方形的概念及特点",
+      "角的初步认识及辨认",
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "23-24 二年级上·广东佛山·期中"
+  },
+  {
+    "id": "377",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "图中共有( )个角，其中钝角有( )个.\n\n![](images/16b1d503880796971c5e58f099e9fb3b4b9af739373eab07390907c40603ca0f.jpg)",
+    "options": [],
+    "answer": "4;2",
+    "solution": "【分析】从一点引出两条射线组成的图形叫做角，这个点叫做顶点，用三角尺的直角进行比较，大于直角的是钝角.\n【详解】图中共有4 个角，其中钝角有2 个。",
+    "knowledge_points": [
+      "角的初步认识及辨认",
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "23-24 二年级上·浙江温州·期中"
+  },
+  {
+    "id": "378",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "角的大小和角的两边的长短无关。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】角的大小与两边的长短无关，只有边叉开的大小有关，叉开得越大，角越大，叉开得越小，角越小。据此举例解答.\n【详解】例如用放大镜看角，只改变角两边的长度，没有改变角两边叉开的大小，则角的大小不变。原题说法正确。故答案为:√",
+    "knowledge_points": [
+      "角的大小比较"
+    ],
+    "source": "23-24 二年级上·河南三门峡·期中"
+  },
+  {
+    "id": "379",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "把角的两条边都减少 3 厘米，这个角的大小不变。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】角由一个顶点和两条边组成，角的大小和边的长短无关，只和边张开的大小有关，两边张开的越大，角越大;两边张开的越小，角越小.\n【详解】由分析可知，把角的两条边都减少3 厘米，这个角的大小不变。原题说法正确。故答案为:√",
+    "knowledge_points": [
+      "角的初步认识及辨认",
+      "角的大小比较"
+    ],
+    "source": "23-24 二年级上·山东临沂·期中"
+  },
+  {
+    "id": "380",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "直角三角尺中最大的角是钝角。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】如下图:![](images/7610891db0f8173402c0fb59573bb223d420d76282115e08db9058392554619b.jpg)三角板上最大的角就是直角，比直角小的角是锐角，比直角大的角是钝角，据此解答即可.\n【详解】由分析可得，直角三角尺中最大的角是直角。原题说法错误。故答案为: ×",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "23-24 二年级上·山东济南·期中"
+  },
+  {
+    "id": "381",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "判断题",
+    "difficulty": 0.65,
+    "question": "图中有3 个角。( )\n\n![](images/9d90ee372b60374508008e845b70ad2565f5b73a1826534494a8744c9a6e0b64.jpg)",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】角有两条直直的边和一个公共端点，这两条直直的边叫做角的边，它们的公共端点叫做角的顶点，由此数出图中角的数量即可.\n【详解】如上图，单个的角有2 个，由2 个单个的角组成的大角有 1 个，一共有 1 + 2 = 3(个),即图中有 3 个角，原题说法正确。故答案为:√",
+    "knowledge_points": [
+      "角的初步认识及辨认"
+    ],
+    "source": "23-24 二年级上·山东菏泽·期中"
+  },
+  {
+    "id": "382",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "锐角都比直角小。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】根据大于直角的是钝角，小于直角的是锐角即可判断.\n【详解】锐角都比直角小，原题说法正确。故答案为:√",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "18-19 二年级下·江苏·期末"
+  },
+  {
+    "id": "383",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "数学书封面上的直角与教室门上的直角一样大。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】角的大小与角的两条边张开的程度有关，而角的大小与边的长短没有关系。两边张开的越大，角就越大.\n【详解】数学书封面上的直角与教室门上的直角一样大。原题说法正确。故答案为:√",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征",
+      "角的大小比较"
+    ],
+    "source": "23-24 二年级上·河北邢台·期中"
+  },
+  {
+    "id": "384",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "判断题",
+    "difficulty": 0.65,
+    "question": "小乐认为用两个锐角只能拼成一个钝角。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】三角板上最大的角就是直角，比直角小的角是锐角，比直角大的角是钝角，据此动手拼一拼即可.\n【详解】作图如下:![](images/334e1e97966dafc9f5a6155a3e19218250814cea64e342260df59b7c68911213.jpg)由图可知，两个锐角可以拼成一个锐角，一个钝角或者一个直角，原题说法错误。故答案为: ×",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "23-24 二年级上·河南驻马店·期中"
+  },
+  {
+    "id": "385",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "凳子的面有4 个角。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】凳子的面是一个长方形或正方形时，有四个角，且 4 个角都是直角，但如果凳子的面是圆形则没有角，题干没有说明凳子的面是什么形状，据此可解答.\n【详解】据分析可得，凳子的面可能是4 个角，也可能没有角。故答案为: ×",
+    "knowledge_points": [
+      "角的初步认识及辨认"
+    ],
+    "source": "23-24 二年级上·河南南阳·期中"
+  },
+  {
+    "id": "386",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "判断题",
+    "difficulty": 0.65,
+    "question": "一个角的两条边张口越大，这个角就越大。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】角由一个顶点两条边组成，两条边张口越大角就越大，据此得出结论即可.\n【详解】根据分析知：一个角的两条边张口越大，这个角就越大。说法正确。故答案为:√",
+    "knowledge_points": [
+      "角的初步认识及辨认"
+    ],
+    "source": "22-23 二年级上·广西贵港·期中"
+  },
+  {
+    "id": "387",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "用一个直角和一个锐角拼成的角一定是钝角。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】比三角尺中的直角小的角是锐角，比三角尺中的直角大的角是钝角，和三角尺中的直角相等的角是直角，据此解答.\n【详解】据分析可知：一个直角和一个锐角拼成的角一定是钝角。原题说法正确。故答案为:√",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "23-24 二年级上·山西忻州·期中"
+  },
+  {
+    "id": "388",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "这些都是角。( )\n\n![](images/c3f3e187e613087c69afa7bbca41df28c7feeea5dec91d5675519c46abe61817.jpg)",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】角有两条直直的边和一个公共端点，这两条直直的边叫做角的边，它们的公共端点叫做角的顶点，据此解答即可.\n【详解】第一个图和第二个图是角，第三个图没有两条直直的边，不是角，原题说法错误。故答案为: ×",
+    "knowledge_points": [
+      "角的初步认识及辨认"
+    ],
+    "source": "23-24 二年级上·甘肃庆阳·期中"
+  },
+  {
+    "id": "389",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "在黑板上画的直角要比在练习本上画的直角大。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】三角板上最大的角就是直角，角的大小与角两边的长度无关，与角张开的角度有关。据此解答即可.\n【详解】在黑板上画的直角和在练习本上画的直角都是直角，一样大，原题说法错误。故答案为: ×",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征",
+      "角的大小比较"
+    ],
+    "source": "23-24 二年级上·陕西·期中"
+  },
+  {
+    "id": "390",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "一个角有 1 个顶点,2 条边。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】角有两条直直的边和一个公共端点，这两条直直的边叫做角的边，它们的公共端点叫做角的顶点，据此判断即可.\n【详解】一个角有 1 个顶点,2 条边。原题说法正确。故答案为:√",
+    "knowledge_points": [
+      "角的初步认识及辨认"
+    ],
+    "source": "23-24 二年级上·黑龙江哈尔滨·期中"
+  },
+  {
+    "id": "391",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "判断题",
+    "difficulty": 0.65,
+    "question": "下图中有 2 个角。( )\n\n![](images/99b65ccbff65f71588509c5453ede0f1b119591b44fe5b22a10b2624220b85d6.jpg)",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】角有两条直直的边和一个公共端点，这两条直直的边叫做角的边，它们的公共端点叫做角的顶点，由此数出图中角的数量即可.\n【详解】由图可知，单个的角有2 个，由2 个单个的角组成的大角有1 个，所以一共有 2 + 1 = 3(个),原题说法错误。故答案为: ×",
+    "knowledge_points": [
+      "数一数",
+      "角的初步认识及辨认"
+    ],
+    "source": "16-17 四年级·全国·课后作业"
+  },
+  {
+    "id": "392",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "一副三角尺上共有4 个锐角，但没有钝角。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】角由一个顶点和两条边组成。和书本，黑板同样大小的角是直角;比直角大的是钝角;比直角小的是锐角，由此解答.\n【详解】如图为一副三角尺，共有4 个锐角,2 个直角，没有钝角。原题说法正确。![](images/24ea7f16bc033ebe5757c1fbd64494ad1e75384063d212ca58867ed90df68d59.jpg)故答案为:√",
+    "knowledge_points": [
+      "角的初步认识及辨认",
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "23-24 二年级上·山东菏泽·期中"
+  },
+  {
+    "id": "393",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "锐角 > 直角 > 钝角。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】三角尺上最大的角为直角，用三角板的直角进行比较测量，比直角小的就是锐角，比直角大的就是钝角。锐角 < 直角 < 钝角，据此解答.\n【详解】锐角 < 直角 < 钝角，原题说法错误。故答案为: ×",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征",
+      "角的大小比较"
+    ],
+    "source": "23-24 二年级上·山东菏泽·期中"
+  },
+  {
+    "id": "394",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "判断题",
+    "difficulty": 0.65,
+    "question": "一个点和两条边一定能组成一个角。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】从一个点引出两条直直的线所组成的图形是角，这个点是角的顶点，两条直直的线是角的边，由此解答.\n【详解】如图1 是角;图2 不是角。所以一个点和两条边不一定能组成一个角，原题说法错误。![](images/053c5b518f37210e3bff8ef3ea380b60daa3047d7b5e9bee680bfd87f0ffb238.jpg)![](images/50bf8937079d5ea2a6e533f40b0b67d7e0aa55f5fb1549f71824193d396676bc.jpg)故答案为: ×",
+    "knowledge_points": [
+      "角的初步认识及辨认"
+    ],
+    "source": "23-24 二年级上·重庆涪陵·期中"
+  },
+  {
+    "id": "395",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "用一副三角板不能拼出锐角来。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】一个三角板上有两个锐角和一个直角，锐角是小于直角的角，用三角板上的角可以拼成锐角或钝角。如图拼起来![](images/20f3e167b85a4513d96352d4c78efc552ae2f848ca991d7188ea7d9bdcc2b3d6.jpg)这个角是一个锐角，据此判断.\n【详解】根据分析，用一副三角板可以拼成锐角，原题说法错误。故答案为: ×",
+    "knowledge_points": [
+      "角的初步认识及辨认",
+      "直角，钝角，锐角的认识及特征",
+      "用三角尺画角",
+      "平面图形的拼接"
+    ],
+    "source": "23-24 二年级上·河北保定·期中"
+  },
+  {
+    "id": "396",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "锐角比钝角小，比直角小。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】角由一个顶点和两条边组成，和书本，黑板上的角同样大小的角是直角，比直角大的是钝角，比直角小的是锐角，由此解答.\n【详解】由分析可知：锐角 < 直角 < 钝角，锐角比钝角小，比直角小。原题说法正确。故答案为:√",
+    "knowledge_points": [
+      "角的初步认识及辨认",
+      "角的大小比较"
+    ],
+    "source": "23-24 二年级上·甘肃临夏·期中"
+  },
+  {
+    "id": "397",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "判断题",
+    "difficulty": 0.65,
+    "question": "三角板上的直角和黑板上的直角一样大。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】在三角板上，最大角就是直角，所有的直角都一样大;角的大小与边的长短无关，与两边叉开的大小有关;据此判断即可.\n【详解】由题意分析得：黑板面上的直角和三角板上的直角一样大;此说法正确。故答案为:√",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "23-24 二年级上·甘肃庆阳·期中"
+  },
+  {
+    "id": "398",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "判断题",
+    "difficulty": 0.65,
+    "question": "把一个角放在放大镜下观察，这个角不会变大。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】角的大小与两条边的长短无关;与角两条边叉开的大小有关，两边叉开的越大，角就越大;两边叉开的越小，角就越小;据此解决。故，在放大镜下看一个角，只是角的边放大了，但角的大小并不会改变.\n【详解】由题意分析得：把一个角放在放大镜下观察，这个角不会变大;原题干说法正确。故答案为:√",
+    "knowledge_points": [
+      "角的初步认识及辨认"
+    ],
+    "source": "23-24 二年级上·湖北省直辖县级单位·期中"
+  },
+  {
+    "id": "399",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "将一个角的两边加长，角就变大了。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】角的大小与角两边的长短无关;与角两边张口的大小有关，角两边张口越大，角就越大，反之就越小;据此判断即可.\n【详解】由题意分析得：将一个角的两边加长，角大小不变。原题说法错误。故答案为: ×",
+    "knowledge_points": [
+      "角的初步认识及辨认"
+    ],
+    "source": "23-24 二年级上·云南玉溪·期中"
+  },
+  {
+    "id": "400",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "解答题",
+    "difficulty": 0.65,
+    "question": "一张正方形的纸，剪去一个角，还剩几个角。\n\n![](images/fa5bd333490b4c64596307b0b4b8c471e3845784d2bc6e5018001a403948632b.jpg)",
+    "options": [],
+    "answer": "3个或4个或5个",
+    "solution": "【分析】四条边都相等，四个角都相等的四边形是正方形，画图解答.\n【详解】如图:\n![](images/cfd8969bb14b1c49ab476aa6375118d7aa6159cbd55b1e33879b51c35fe66eae.jpg)\n答：还剩 3 个或 4 个或 5 个角。",
+    "knowledge_points": [
+      "正方形的概念及特点",
+      "角的初步认识及辨认",
+      "平面图形的分割"
+    ],
+    "source": "23-24 二年级上·山东菏泽·期中"
+  },
+  {
+    "id": "401",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下图中( )不是角.\n\n![](images/9d7aee7e4eab18ea1ecb890213f2a8b741e4fdb3328bef2b3d2539a3c749c667.jpg)",
+    "options": [
+      "A. ",
+      "B. ",
+      "C. "
+    ],
+    "answer": "B",
+    "solution": "【分析】角由一个顶点两条边组成，两条边都是直直的线，由此解答.\n【详解】A。有一个顶点两条边，是角;B。不是两条边和一个顶点，不是角;C。有一个顶点两条边，是角;所以B不是角。故答案为:B",
+    "knowledge_points": [
+      "角的初步认识及辨认"
+    ],
+    "source": "23-24 二年级上·河北邢台·期中"
+  },
+  {
+    "id": "402",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面的四边形中，相邻的两条边相等且有直角的是( )。",
+    "options": [
+      "A. 长方形",
+      "B. 平行四边形",
+      "C. 正方形"
+    ],
+    "answer": "C",
+    "solution": "【分析】根据正方形，长方形，平行四边形的特征进行解答.\n【详解】A。长方形，两组对边相等，四个角都是直角，不符合题意。B。平行四边形，对边平行且相等，四个角都不是直角，不符合题意。C。正方形，四条边都相等，四个角都是直角，符合题意。故答案为:C",
+    "knowledge_points": [
+      "长方形，正方形，三角形和圆的初步认识",
+      "平行四边形的初步认识",
+      "角的初步认识及辨认"
+    ],
+    "source": "23-24 二年级下·河北唐山·期末"
+  },
+  {
+    "id": "403",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "下面( )不是角。",
+    "options": [
+      "A. ![](images/737963fcb5769b0d76cbc41e53063e55689bbd568abdc104fb4cea1b11c430da.jpg)",
+      "B. ![](images/522c1f1c20bd370bca3fb16707a02f23deac3a8dbb48cace319a43bfaf2b4a30.jpg)",
+      "C. ![](images/05d30f3ef255f14867272c88e4e98d8d70b6f0ebe276ca74e6d2ab2c68ffe8fe.jpg)"
+    ],
+    "answer": "A",
+    "solution": "【分析】角有一个顶点两条边组成，两条边都是直直的线，据此得出结论即可.\n【详解】根据分析知：图形A不是角。故答案为:A",
+    "knowledge_points": [
+      "角的初步认识及辨认"
+    ],
+    "source": "23-24 二年级上·福建莆田·期末"
+  },
+  {
+    "id": "404",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面说法正确的是( )。",
+    "options": [
+      "A. 黑板上的直角比尺子上的直角大。",
+      "B. 角的两边越长，角越大。",
+      "C. 七巧板中三角板的两个锐角大小相等。"
+    ],
+    "answer": "C",
+    "solution": "【分析】根据角的意义，从一点引出两条射线组成的图形叫做角，因为角的两边是两条射线，射线可以向一方无限延长，所以角的大小与角的两条边的长短没有关系，与两边叉开的大小有关，据此判断.\n【详解】A。黑板上的直角比尺子上的直角大，直角都是一样大，此说法是错误的;B。角的两边越长，这个角就越大，角的大小与边长没有关系，此说法是错误的;C。七巧板中三角板的两个锐角大小相等，此说法正确。故答案为:C",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征",
+      "角的大小比较",
+      "用七巧板拼图形"
+    ],
+    "source": "23-24 二年级上·福建莆田·期中"
+  },
+  {
+    "id": "405",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "( )是锐角。",
+    "options": [
+      "A. ![](images/22c8d172726920f4c211f971b16db7722b4c9f93493e0ab882b2ecdb7145fbc7.jpg)",
+      "B. ![](images/69366ccd244d80e1d1c032bcd8dd2d29ec42ed1af767f06acfdf31b1336f652c.jpg)",
+      "C. ![](images/12d6b12976c9a850692d0cbffe25fd969db8478590d522796cedbc4224505ef6.jpg)"
+    ],
+    "answer": "B",
+    "solution": "【分析】比三角尺中的直角小的角是锐角，比三角尺中的直角大的角是钝角，和三角尺中的直角相等的角是直角，据此解答.\n【详解】A。是一个钝角;B。是一个锐角;C。是一个直角。故答案为:B",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "22-23 二年级上·福建莆田·期中"
+  },
+  {
+    "id": "406",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "两根小棒摆成的图形，最多有( )个直角。",
+    "options": [
+      "A. 2",
+      "B. 4",
+      "C. 8"
+    ],
+    "answer": "B",
+    "solution": "【分析】从一点引出两条射线所形成的图形叫做角。和书本，黑板的角相同大小的是直角。若要摆成的图形中直角最多，可如图摆放，数出直角的数量即可.\n![](images/31199d8e5de636874aff7a0597cb9accbdaf37887f665964c85944879482203e.jpg)\n【详解】由分析可知，两根小棒摆成的图形，最多有4 个直角。故答案为:B",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "23-24 二年级上·全国·课后作业"
+  },
+  {
+    "id": "407",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "把一张正方形纸对折一次，再沿着不同方向对折第二次，展开后，折痕及原来的正方形一共最多组成( )个直角。",
+    "options": [
+      "A. 16",
+      "B. 8",
+      "C. 4"
+    ],
+    "answer": "A",
+    "solution": "【分析】和书本，黑板同样大小的角是直角。如图将正方形对折一次，形成一个折痕;再沿着不同方向对折一次，形成第二个折痕。数一数可知，一共有16 个直角.\n![](images/b346bd20c57a69f41e40a7b0636ec3e018c32b3bf0cff8920eaafdb0e2f9b53d.jpg)\n【详解】由分析可知，把一张正方形纸对折一次，再沿着不同方向对折第二次，展开后，折痕及原来的正方形一共最多组成16 个直角。故答案为:A",
+    "knowledge_points": [
+      "图形的折叠问题",
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "23-24 二年级上·全国·课后作业"
+  },
+  {
+    "id": "408",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "用两块三角尺拼成的角是锐角的是( )。",
+    "options": [
+      "A. ![](images/2a6a77542f4bce6e2cd7d64895a7a3cf633b35cccb2bf3cbd43f2a5a496747f9.jpg)",
+      "B. ![](images/757cb311599d17f3e3bef900025959db8762dd6e35f29e802d2c8b41e077bcd2.jpg)",
+      "C. ![](images/eec90400a58ba25bb6d496da193d437f4ccabe932825196cb759a74a7dcffc35.jpg)"
+    ],
+    "answer": "B",
+    "solution": "【分析】从一点引出两条直直的线所形成的图形叫做角。和书本，黑板的角同样大小的是直角;比直角小的是锐角;比直角大的是钝角，由此选择.\n【详解】A。拼成的角比直角大，是钝角;B。拼成的角比直角小，是锐角;C。拼成的角比直角大，是钝角。用两块三角尺拼成的角是锐角的是B。故答案为:B",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征",
+      "用三角尺画角"
+    ],
+    "source": "23-24 二年级上·全国·课后作业"
+  },
+  {
+    "id": "409",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "把一个角用放大镜看，这个角( )。",
+    "options": [
+      "A. 变大了",
+      "B. 变小了",
+      "C. 不变"
+    ],
+    "answer": "C",
+    "solution": "【分析】角的大小只与角两边张开的大小有关。把一个角用放大镜看，放大的是角的两条边，不改变角的形状，根据角的大小与边长无关可知角的度数不会改变，据此解答即可.\n【详解】把一个角用放大镜看，这个角不变;故答案为:C",
+    "knowledge_points": [
+      "角的初步认识及辨认"
+    ],
+    "source": "23-24 二年级上·全国·课后作业"
+  },
+  {
+    "id": "410",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "下面图形中，有 2 个钝角的是( )。",
+    "options": [
+      "A. ![](images/7adf805b3522c72d881686c3a42e2b24bd61f2afd62a56a18cdd61f4d3d6fa14.jpg)",
+      "B. ![](images/aea919f753c6f3349477d48b9574a481d74324e9bb456ff1f38194152e89e86d.jpg)",
+      "C. ![](images/e13196586f28eb59d7debd69fa866fe714f13888f9dc21d82bbad4fe09230c80.jpg)"
+    ],
+    "answer": "B",
+    "solution": "【分析】长方形上的四个直直的角都是直角，比直角大的角是钝角，比直角小的角是锐角，据此得出结论即可.\n【详解】A。选项图形中有3 个锐角，没有钝角，不符合题意;B。选项图形中有 2 个锐角,2 个钝角，符合题意;C。选项图形中有 4 个直角，没有钝角，不符合题意;故答案为:B",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "23-24 二年级上·全国·单元测试"
+  },
+  {
+    "id": "411",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "下图中有( )个角.\n\n![](images/4d9f43d822b18a7e0592e5c6b30d9d65aed442fa5964ebd248a8e3e4b57dc0d7.jpg)",
+    "options": [
+      "A. 7",
+      "B. 8",
+      "C. 9"
+    ],
+    "answer": "B",
+    "solution": "【分析】正方形上有 4 个直角，中间的对角线又把两个直角分成4 个锐角，共8 个角，据此得出结论即可.\n【详解】根据分析知：图中共有8 个角。故答案为:B",
+    "knowledge_points": [
+      "角的初步认识及辨认"
+    ],
+    "source": "23-24 二年级上·全国·单元测试"
+  },
+  {
+    "id": "412",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下图中有( )个锐角.\n\n![](images/cc7106660ec1540cd0febb6000b8791369ca74a681c7fc2da7c7497d1a19fb86.jpg)",
+    "options": [
+      "A. 3",
+      "B. 2",
+      "C. 1"
+    ],
+    "answer": "C",
+    "solution": "【分析】从一点引出两条射线所形成的图形叫做角。和书本，黑板的角相同大小的是直角，比直角大的是钝角，比直角小的是锐角，由此数出锐角的数量即可.\n【详解】由分析作图如下：图中有 1 个锐角。![](images/c7e06a5d4e5497cc8304ba76a373beb634023430c175d0ebb70413ef62a8e2bf.jpg)故答案为:C",
+    "knowledge_points": [
+      "角的初步认识及辨认",
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "23-24二年级上·全国·单元测试"
+  },
+  {
+    "id": "413",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "下面物体中表面有角的是( )。",
+    "options": [
+      "A. ![](images/5f57385bb04cb7d7f2c76436ab1b7d1dd77d1cb2d179174bdfe528c53b20c0e4.jpg)",
+      "B. ![](images/16f833fd79ce152e1ef4c3ca5325c7c2bc3a934d550ecec70960dee4a748530e.jpg)",
+      "C. ![](images/1749374d8c02db33496e810a8dd159f962162c0ed8ba6e037d8dd9fcbb212770.jpg)"
+    ],
+    "answer": "C",
+    "solution": "【分析】根据角的特征，角有一个顶点，两条边;角有大小，角的张口越大，角越大。据此解答。本题考查角的认识及特征.\n【详解】由分析可知A。是个球体，没有角;B。是圆柱体，没有角;C。有一个顶点，两条边，所以表面有角。故答案为:C.",
+    "knowledge_points": [
+      "角的初步认识及辨认"
+    ],
+    "source": "23-24二年级上·全国·单元测试"
+  },
+  {
+    "id": "414",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "在放大镜下看一个直角，这个直角( )。",
+    "options": [
+      "A. 还是直角",
+      "B. 变成钝角",
+      "C. 变成锐角"
+    ],
+    "answer": "A",
+    "solution": "【分析】角的大小与边的长短无关，与角两边叉开的大小有关，角两边叉开越大，角就越大，反之就越小.\n【详解】由题意分析得：在放大镜下看一个直角，放大的是直角的边长，故，角的大小没有变，这个直角还是直角。故答案为:A",
+    "knowledge_points": [
+      "角的初步认识及辨认",
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "23-24二年级下·贵州毕节·期末"
+  },
+  {
+    "id": "415",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面三个图形,( )中没有直角。",
+    "options": [
+      "A. ![](images/a0c696ebc6e097c195ba20e9eea91d509213159496d32378e160109e9340a24f.jpg)",
+      "B. ![](images/7ab651e80959c4639d661e56976a570ea343dc36a5316ad94e66e707b310b917.jpg)",
+      "C. ![](images/5644b58656ef43380477be763805608d77ddfe4cd7a7347691066eebf8199ede.jpg)"
+    ],
+    "answer": "B",
+    "solution": "【分析】从一点引出两条射线所形成的图形叫做角。和书本，黑板的角相同大小的是直角，由此选择.\n【详解】A。有 4 个直角;B。没有直角;C。有1 个直角。故答案为:B",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "23-24 二年级下·陕西西安·期末"
+  },
+  {
+    "id": "416",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "如图中一共有( )个角.\n\n![](images/eb5f9989316b20862c4d02a3301dfb503e2cad17a7acdd6f9363d66c05409aeb.jpg)",
+    "options": [
+      "A. 6",
+      "B. 8",
+      "C. 10"
+    ],
+    "answer": "B",
+    "solution": "【分析】根据角的认识，角由一个顶点和两条边组成，由此数出.\n![](images/a0e70c7b1f2fe296a8fac8daeab4901b06f12f2c2635bc843fe77682d5acb194.jpg)\n【详解】由分析可知：图中一共有8 个角。故答案为:B",
+    "knowledge_points": [
+      "角的初步认识及辨认"
+    ],
+    "source": "23-24 二年级下·河南新乡·期末"
+  },
+  {
+    "id": "417",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下图中有( )个角.\n\n![](images/a5916b0d82f7ae1889de63f4047d1033fdd7ff77a45069877bd52f50eb4f0a0d.jpg)",
+    "options": [
+      "A. 2",
+      "B. 3",
+      "C. 4"
+    ],
+    "answer": "B",
+    "solution": "【分析】角有两条直直的边和一个公共端点，这两条直直的边叫做角的边，它们的公共端点叫做角的顶点，由此数出图中角的数量即可.\n【详解】![](images/c22d19cb126a44d83623b25dc89048a6389105f9e17336af34d504abf88febb3.jpg)2 + 1 = 3(个),由图可知，图中有2 个小角和1 个大角，所以一共有3 个角。故答案为:B",
+    "knowledge_points": [
+      "角的初步认识及辨认"
+    ],
+    "source": "22-23 二年级上·湖北省直辖县级单位·期末"
+  },
+  {
+    "id": "418",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下列图形中,( )不是角。",
+    "options": [
+      "A. ![](images/06fa04070859b04fd3260392c762705e799f8ab642f02d9e218a906aba5ba71f.jpg)",
+      "B. ![](images/b5ba030d71c6a124ffd92a7ff23279d7e0a1d28d9c3a6beac94e32c8bbae7583.jpg)",
+      "C. ![](images/d4d3036b245fe112584758bb9b8ee48ba1a8c9c90ae10d29371e3ebc8e08bbec.jpg)"
+    ],
+    "answer": "B",
+    "solution": "【分析】角有两条直直的边和一个公共端点，这两条直直的边叫做角的边，它们的公共端点叫做角的顶点，据此判断即可.\n【详解】A。符合角的概念;B。没有公共端点，不符合角的概念;C。符合角的概念。所以只有B不是角。故答案为:B",
+    "knowledge_points": [
+      "角的初步认识及辨认"
+    ],
+    "source": "22-23二年级上·湖北省直辖县级单位·期末"
+  },
+  {
+    "id": "419",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下列( )不是长方形和正方形的共同特征。",
+    "options": [
+      "A. 四个角都是直角",
+      "B. 四条边都相等",
+      "C. 对边相等"
+    ],
+    "answer": "B",
+    "solution": "【分析】从一点引出两条射线所形成的图形叫做角。和书本相等大小的是直角。长方形是四个角相等的四边形;四条边都相等，四个角都相等的四边形是正方形，据此解答.\n【详解】A。长方形和正方形的四个角都是直角;B。长方形和正方形的四条边并不是一定相等;C。长方形和正方形的对边都相等。不是长方形和正方形的共同特征的是：四条边都相等。故答案为:B",
+    "knowledge_points": [
+      "长方形，正方形，三角形和圆的初步认识",
+      "角的初步认识及辨认"
+    ],
+    "source": "23-24 二年级下·河南周口·期中"
+  },
+  {
+    "id": "420",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面图形中,( )没有直角。",
+    "options": [
+      "A. ![](images/1b1f80cb3cfd5fdcfa4340609fda3adcac8b5c8bd7ae3450e38f8dc7d3c7a449.jpg)",
+      "B. ![](images/48daa55b30f7fc16897b338ad811653d116b112ada14e8b041b0f53c4e29b671.jpg)",
+      "C. ![](images/d507af2621025b9aeee1ca7ac4107be461e396a1368abceb84fc821f81743e5d.jpg)"
+    ],
+    "answer": "A",
+    "solution": "【分析】从一点引出两条射线所形成的图形叫做角。和书本，黑板的角相等大小的是直角，由此解答.\n【详解】A。没有直角;B。有 4 个直角;C。有4 个直角。A没有直角。故答案为:A",
+    "knowledge_points": [
+      "角的初步认识及辨认"
+    ],
+    "source": "22-23二年级上·河南南阳·期中"
+  },
+  {
+    "id": "421",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "在钟面上,2 点时分针与时针所夹的角是( )。",
+    "options": [
+      "A. 锐角",
+      "B. 直角",
+      "C. 钝角"
+    ],
+    "answer": "A",
+    "solution": "【分析】在三角板上，最大角就是直角，锐角比直角小，钝角比直角大。在钟面上,2 点时，分针指向 12，时针指向 2，分针与时针所夹的角是锐角.\n【详解】由题意分析得：在钟面上,2 点时分针与时针所夹的角是锐角。故答案为:A",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征",
+      "整点时间与钟面指针的位置"
+    ],
+    "source": "22-23 二年级上·河南南阳·期末"
+  },
+  {
+    "id": "422",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "下面四个图形中哪个是钝角。( )",
+    "options": [
+      "A. ![](images/2026-02-24%20092704.jpg)",
+      "B. ![](images/2026-02-24%20092728.jpg)",
+      "C. ![](images/2026-02-24%20092743.jpg)",
+      "D. ![](images/2026-02-24%20092801.jpg)"
+    ],
+    "answer": "C",
+    "solution": "【分析】像长方形的四个角一样的直直的角是直角，比直角大的是钝角，比直角小的是锐角，据此得出结论即可.\n【详解】A。选项是锐角，不符合题意;B。选项不是角，不符合题意;C。选项是钝角，符合题意;D。选项是直角，不符合题意;故答案为:C",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "22-23 二年级上·山东济南·期末"
+  },
+  {
+    "id": "423",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下图中，有三个直角的是( )。",
+    "options": [
+      "A. ![](images/a1e54c32ece6d9dd40552782a88d78fb820699249d6652ba3c046d87508c447e.jpg)",
+      "B. ![](images/287dc15191384aae53ab6ec1937e4be8a2a52b9c64f6ef0b113a5b86e250d9ad.jpg)",
+      "C. ![](images/112661f2e16e2553e8a0e3b9b934e47f46e568cb0930ed25b403b9be6c39fe07.jpg)"
+    ],
+    "answer": "C",
+    "solution": "【分析】根据对直角的认识，比三角尺中直角小的角是锐角，比三角尺中直角大的角是钝角，和三角尺中直角相等的角是直角，据此解答.\n【详解】A。有2 个直角;B。有 5 个直角;C。有 3 个直角。符合题意的是C。故答案为:C",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "22-23二年级上·山东菏泽·期中"
+  },
+  {
+    "id": "424",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下图中，钝角有( )个.\n\n![](images/d744632142a907b15163f28aed96f0844335a89fc8c5ba1f2f22b6fca893f0ca.jpg)",
+    "options": [
+      "A. 4",
+      "B. 3",
+      "C. 2"
+    ],
+    "answer": "A",
+    "solution": "【分析】根据题图，把各角和三角尺中的直角比较，比三角尺中直角小的角是锐角，比三角尺中直角大的角是钝角，和三角尺中直角相等的角是直角，据此解答.\n【详解】根据分析，我们可以把钝角画出来,![](images/7a641c0cd4cd6dc9bd8c3a0de7c5890b263aa4ed3f8a35375f132b55c9091d6f.jpg)一共有 4 个钝角。故答案为:A",
+    "knowledge_points": [
+      "角的初步认识及辨认",
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "22-23 二年级上·河南南阳·期中"
+  },
+  {
+    "id": "425",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "三角尺上的 3 个角中，有( )个角是直角。",
+    "options": [
+      "A. 1",
+      "B. 2",
+      "C. 3"
+    ],
+    "answer": "A",
+    "solution": "【分析】根据生活经验可知：三角尺上有1 个直角。据此解答即可.\n【详解】据分析可知：三角尺上的3 个角中，有1 个角是直角。故答案为:A",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "22-23 二年级上·河北邢台·期中"
+  },
+  {
+    "id": "426",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "用三角板上的一个直角和一个锐角拼在一起，拼成的角是( )。",
+    "options": [
+      "A. 锐角",
+      "B. 直角",
+      "C. 钝角"
+    ],
+    "answer": "C",
+    "solution": "【分析】在三角板上，最大角就是直角，钝角比直角大，锐角比直角小;用三角板上的一个直角和一个锐角拼在一起，拼成的角是钝角。(如下图)\n![](images/d9ebfaec465f3fec5bf49495f2db2e4512be24844c85aa9f85e2a6339daea121.jpg)\n【详解】由题意分析得：用三角板上的一个直角和一个锐角拼在一起，拼成的角是钝角。故答案为:C",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征",
+      "平面图形的拼接"
+    ],
+    "source": "22-23 二年级上·湖北恩施·期中"
+  },
+  {
+    "id": "427",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "如图中加一条线段，最多能增加( )个直角.\n\n![](images/f1e836644ef2249d2c7150465990fff1bba60b395f4935d1af56f2f8c3fda334.jpg)",
+    "options": [
+      "A. 4",
+      "B. 5",
+      "C. 6"
+    ],
+    "answer": "C",
+    "solution": "【分析】当一条直线和另一条横的直线交成的邻角彼此相等时，这些角的每一个被叫做直角。连接长方形的左边的宽的中间点与三角形的右侧的顶点即可得最多的直角.\n【详解】由分析可得:![](images/5eef72f66d659a2ef7566d402779dc6f696dfa01b8568e94fcf33c11f9907797.jpg)这样画可以增加 6 个直角。故答案为:C",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "22-23 二年级上·山东菏泽·期末"
+  },
+  {
+    "id": "428",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面图形中，是线段的是( )。",
+    "options": [
+      "A. ![](images/d0eedae646eb345f0c6e497ed2aa87d34c1a4b0d2d10cd4fe78e60fee1871bc6.jpg)",
+      "B. ![](images/1fcf2463f153a3bb7d266299c5a4c6664884ac7c0fca0331224a078af5bbfa7b.jpg)",
+      "C. ![](images/2026-02-24%20093224.jpg)"
+    ],
+    "answer": "B",
+    "solution": "【分析】线段有 2 个端点，且是一条直直的线.\n【详解】由分析可得:A。是弯曲的线，不符合题意;B。有 2 个端点且是一条直直的线，符合题意;C。是直线没有端点，不符合题意。故答案为:B",
+    "knowledge_points": [
+      "线段的初步认识"
+    ],
+    "source": "22-23 二年级上·山东济南·期末"
+  },
+  {
+    "id": "429",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下图中,( )是角。",
+    "options": [
+      "A. ![](images/cba2c8858a5fda19c7da5fe973e3a2eb5d71ea1d39310e544ac45d955e71931d.jpg)",
+      "B. ![](images/45d577a7b95c9cf3dd58e19d5923c03a3b3d5e67279a2f2c31637956c76c30fb.jpg)",
+      "C. ![](images/d3228c77f3d097bd86cb01e15c5c5272def84dbfef0adc281f0cd12bc8a8d951.jpg)"
+    ],
+    "answer": "B",
+    "solution": "【分析】从一点引出两条射线所形成的图形叫做角。由此解答.\n【详解】A。不是角;B。是角;C。不是角。B是角。故答案为:B",
+    "knowledge_points": [
+      "角的初步认识及辨认"
+    ],
+    "source": "23-24 二年级上·江西宜春·期末"
+  },
+  {
+    "id": "430",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "下面拼成的 3 个角中，最大的是( )。",
+    "options": [
+      "A. ![](images/687b4c2eba45d436db21ea259e13d500582c7208c7face4ac4eadd3ee76419d2.jpg)",
+      "B. ![](images/9a29728eb59f654568852b1dccd9502713974ca1c3ae5f1110fd6bd994f3e7fa.jpg)",
+      "C. ![](images/74101ff2ebbafd5317ff2cb368f0eeb46413e89a06ed34501d1694054f776f04.jpg)"
+    ],
+    "answer": "A",
+    "solution": "【分析】用三角板的直角进行比较测量，比直角小的就是锐角，比直角大的就是钝角。据此解答.\n【详解】A。此图中的角由一个直角和三角板中中等大小的锐角组成;B。此图中的角由一个直角和三角板中较小的锐角组成;C。此图中的角是一个直角。拼成的3 个角中，最大的是A。故答案为:A",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征",
+      "角的大小比较"
+    ],
+    "source": "23-24 二年级上·甘肃庆阳·期末"
+  },
+  {
+    "id": "431",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "![](images/db5093a6bb20e87c5f45acb5fef78b23ed6bcd27169f4cd486f08bc42f69be88.jpg)左边的图形剪去一个角后，还剩下( )角。",
+    "options": [
+      "A. 3 个",
+      "B. 4 个",
+      "C. 5 个"
+    ],
+    "answer": "C",
+    "solution": "【分析】从一点引出两条射线所形成的图形叫做角。由此数出剪后图形角的数量即可.\n【详解】作图如下:![](images/65d147a8fbec549e4bb2ca235e94121d734e8d8c1c687e86bf617ae1159c69e2.jpg)数一数可知，还剩下5 个角。故答案为:C",
+    "knowledge_points": [
+      "角的初步认识及辨认"
+    ],
+    "source": "23-24二年级上·甘肃庆阳·期末"
+  },
+  {
+    "id": "432",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下图中比直角小的角是( )。",
+    "options": [
+      "A. ![](images/d7b619ca9f61ef109a1429da47e459802a79f480fbb0c653c2b77fcff31ac279.jpg)",
+      "B. ![](images/94a7658d931fd760229775c30f399b7b4e1bcb8e11ba185fb7e86a4a5cb54f2b.jpg)",
+      "C. ![](images/1f85be8c4eedccaa5b871b7b244d13683436fb617273859ec35f3319380c7066.jpg)"
+    ],
+    "answer": "A",
+    "solution": "【分析】在三角板上，最大角就是直角，锐角比直角小，钝角比直角大.\n【详解】A。这是锐角，比直角小;B。这是直角;C。这是钝角，比直角大;即,A是比直角小的角。故答案为:A",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "23-24二年级上·新疆塔城·期末"
+  },
+  {
+    "id": "433",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "角的大小和两条边的长短( )。",
+    "options": [
+      "A. 有关",
+      "B. 无关",
+      "C. 不能确定"
+    ],
+    "answer": "B",
+    "solution": "【分析】从一点引出两条射线所形成的图形叫做角。角的大小与两边的长短无关，只与边叉开的大小有关，叉开得越大，角越大，叉开得越小，角越小。由此解答.\n【详解】由分析可知，角的大小与两条边的长短无关。故答案为:B",
+    "knowledge_points": [
+      "角的初步认识及辨认"
+    ],
+    "source": "20-21二年级上·广西南宁·期中"
+  },
+  {
+    "id": "434",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "一张长方形纸有四个角，用剪刀沿直线剪去一个角后，还剩( )个角。",
+    "options": [
+      "A. 3",
+      "B. 4",
+      "C. 5",
+      "D. 3 个,4 个,5 个都有可能"
+    ],
+    "answer": "D",
+    "solution": "【分析】从一点引出两条射线所形成的图形叫做角。本题可分三种情况。直线不过顶点时，剪完还剩5 个角;直线过一个顶点时，剪完还剩4 个角;直线过两个顶点时，剪完还剩3 个角。由此解答.\n![](images/4c884475676dc237e8976120b3f01072c3f2e0fd7eefc85e2ab65415fe5514e5.jpg)\n【详解】由分析可知，一张长方形纸有四个角，用剪刀沿直线剪去一个角后，可能还剩 3 个,4 个或 5 个角。故答案为:D",
+    "knowledge_points": [
+      "角的初步认识及辨认",
+      "平面图形的分割"
+    ],
+    "source": "23-24 二年级上·广东佛山·期末"
+  },
+  {
+    "id": "435",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面用三角尺拼成的角中，最大的是( )。",
+    "options": [
+      "A. ![](images/ea22dba0dd634f8c121a3e6993dc0253961d7eba2ab35020035d2ab4f494a6a8.jpg)",
+      "B. ![](images/dfab25d23d9a72f8607e81a4404506499b5c2b0cbd137c3f911a7887a108592b.jpg)",
+      "C. ![](images/e94a18e8ff15252ec2c8e7ca2efab8f19aa1f6182cb54360660cd0684f7a0abb.jpg)"
+    ],
+    "answer": "B",
+    "solution": "【分析】在三角尺上，最大的角是直角。钝角比直角大，锐角比直角小。钝角>直角>锐角。由此解答.\n【详解】A。拼成的角是直角;B。拼成的角是钝角;C。拼成的角是锐角。拼成的角中最大的是B。故答案为:B",
+    "knowledge_points": [
+      "角的初步认识及辨认",
+      "平面图形的拼接"
+    ],
+    "source": "23-24 二年级上·重庆大渡口·期末"
+  },
+  {
+    "id": "436",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "一个三角尺上有( )个角，其中最大的那个角是( )角。要判断一个角是不是直角，可以用三角尺上的( )来比一比。",
+    "options": [],
+    "answer": "3;直;直角",
+    "solution": "【分析】角有两条边和一个公共端点，这两条边叫做角的边，它们的公共端点叫做角的顶点。三角尺上最大的角为直角。如图:\n![](images/a2b45a9cf8c7b12c8ce3b6dc76aa50cfb2eedce87c7d23f59a3eaf973a631126.jpg)\n![](images/cc87f92cd1bd7f32cd35a265189cf7d0198255d0843a3b79e12f3d1eab9c38e5.jpg)\n【详解】一个三角尺上有3 个角，其中最大的那个角是直角。要判断一个角是不是直角，可以用三角尺上的直角来比一比。",
+    "knowledge_points": [
+      "角的初步认识及辨认",
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "23-24 二年级上·河南郑州·期中"
+  },
+  {
+    "id": "437",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "我们常用的三角尺上，每个三角尺有 1 个( )角，有( )个锐角。",
+    "options": [],
+    "answer": "直;2",
+    "solution": "【分析】角由一个顶点和两条边组成。和书本，黑板的角相同大小的是直角，比直角小的是锐角，比直角大的是钝角，由此解答.\n【详解】如图为三角尺，每个三角尺有1 个直角，有2 个锐角.\n![](images/3e0945433549fe00bf76979a7b2bbea6f66cc2831786c74d4de434f6ee881687.jpg)",
+    "knowledge_points": [
+      "角的初步认识及辨认"
+    ],
+    "source": "23-24 二年级上·云南文山·期中"
+  },
+  {
+    "id": "438",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "一个正方形有( )个角，都是( )角。",
+    "options": [],
+    "answer": "4;直",
+    "solution": "【分析】角由一个顶点和两条边组成。和书本，黑板的角相同大小的是直角。如图为正方形，有 4 个直角.\n![](images/183e5764dfa1743ff567674e48a803160e2cf58d67bf0fc1357825cd773f32b4.jpg)\n【详解】由分析可知，一个正方形有4 个角，都是直角。",
+    "knowledge_points": [
+      "角的初步认识及辨认"
+    ],
+    "source": "19-20 二年级下·江苏徐州·阶段练习"
+  },
+  {
+    "id": "439",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "数一数.\n\n![](images/5b45a88b3b2a4fc1b559cceb288ff895a70e8d52aef6c76b821e7f6311cc1a31.jpg)\n\n![](images/1fe829bebd845ebb64a3336d2dfacee47bb62495bd6f95c332d348185a3155f1.jpg)\n\n有( )个角;有( )个平行四边形",
+    "options": [],
+    "answer": "6;9",
+    "solution": "【分析】角有一个顶点和两条边;平行四边形有4 条直直的边，对边相等，有2 条同方向的斜边，由此数出数量即可.\n【详解】图1：单独的小角有3 个;2 个小角组成的大角有2 个;3 个小角组成的大角有 1 个，一共有 6 个角;图2：单独的小平行四边形有4 个;2 个小平行四边形组成的大平行四边形有 4 个;4 个小平行四边形组成的大平行四边形有 1 个，一共有 9 个平行四边形。图1有6 个角;图2有9 个平行四边形。",
+    "knowledge_points": [
+      "平行四边形的初步认识",
+      "角的初步认识及辨认"
+    ],
+    "source": "23-24 二年级下·河南驻马店·期末"
+  },
+  {
+    "id": "440",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "钟面上 1 时整，分针和时针成( )角,9 时整，分针和时针成( )角,7 时整，分针和时针成( )角。",
+    "options": [],
+    "answer": "锐;直;钝",
+    "solution": "【分析】根据钟表的认识，当分针指向 12 时，时针指向几就是几时整;据此得出相应的时间钟面上时针和分针的位置;根据直角的特征，可知长方形，正方形的4 个角都是直角，要知道一个角是不是直角，用三角尺上的直角比较即可，比直角小的角叫做锐角，比直角大的角叫做钝角;据此根据直角，钝角和锐角的认识进行判断.\n【详解】1 时整，分针指向 12，时针指向 1，此时分针和时针成锐角;9 时整，分针指向12，时针指向9，此时分针和时针成直角;7 时整，分针指向 12，时针指向 7，此时分针和时针成钝角。",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征",
+      "整点时间与钟面指针的位置"
+    ],
+    "source": "23-24 二年级下·河南周口·期末"
+  },
+  {
+    "id": "441",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "长方形和正方形都有( )条边，都有( )个( )角。",
+    "options": [],
+    "answer": "4;4;直",
+    "solution": "【分析】根据长方形，正方形的特征即可解答。正方形的特征是四条边都相等，四个角都是直角。长方形的特征是两组对边相等，四个角都是直角.\n【详解】长方形和正方形都有4 条边，都有4 个直角。",
+    "knowledge_points": [
+      "长方形的概念及特点",
+      "正方形的概念及特点",
+      "角的初步认识及辨认"
+    ],
+    "source": "23-24 二年级下·河北唐山·期末"
+  },
+  {
+    "id": "442",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "填序号，下图直角有( ),锐角有( ),钝角有( ).\n\n![](images/2026-02-24%20094549.jpg)",
+    "options": [],
+    "answer": "①;②⑤;③④",
+    "solution": "【分析】比三角尺中的直角小的角是锐角，比三角尺中的直角大的角是钝角，和三角尺中的直角相等的角是直角，据此解答.\n【详解】据分析可知：直角有①,锐角有②⑤,钝角有③④。",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "23-24 二年级下·河南商丘·期末"
+  },
+  {
+    "id": "443",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "下图中有( )个锐角,( )个钝角.\n\n![](images/cb43530278daeaeb7bd38bddd7eec87c652b08ff70af4bf7a8507fde553d7fdf.jpg)",
+    "options": [],
+    "answer": "4;4",
+    "solution": "【分析】比三角尺中的直角小的角是锐角，比三角尺中的直角大的角是钝角，和三角尺中的直角相等的角是直角，据此解答.\n【详解】根据对角的初步认识可知：图中有4 个锐角,4 个钝角。",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "22-23 二年级上·福建莆田·期末"
+  },
+  {
+    "id": "444",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "下图中，有( )条线段，有( )个锐角，有( )个钝角.\n\n![](images/c255e24001c13bdf73850b9c369fef864ba30af979b18510bbdd475cf9c5a209.jpg)",
+    "options": [],
+    "answer": "5;5;1",
+    "solution": "【分析】线段有两个端点，且是一条直直的线;在三角板上，最大角就是直角，钝角比直角大，锐角比直角小;据此解决此题.\n【详解】由题意分析得：该图中，有 5 条线段，有 5 个锐角，有 1 个钝角。",
+    "knowledge_points": [
+      "线段，直线，射线的认识及特征",
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "23-24 二年级上·福建莆田·期末"
+  },
+  {
+    "id": "445",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "下图中有( )个直角,( )个锐角.\n\n![](images/d3d12c3db3b5a7e28dfb2c1ead08eb8ebbb780298cce4cb828fd158c4bb0bd6c.jpg)",
+    "options": [],
+    "answer": "4;2",
+    "solution": "【分析】三角板上直直的角是直角，比直角大的角是钝角，比直角小的角是锐角，据此得出结论即可.\n【详解】根据分析知：图中有 4 个直角,2 个锐角。",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "22-23 二年级上·福建莆田·期末"
+  },
+  {
+    "id": "446",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "图中有( )个角，有( )个锐角，有( )个钝角.\n\n![](images/6d4064e47e38d2599e61d6106963416fe9ad8ce1f524e5b8b18d0ff23e8da090.jpg)",
+    "options": [],
+    "answer": "7;6;1",
+    "solution": "【分析】有一个顶点两条边组成的图形是角，三角板上直直的角是直角，比直角大的角是钝角，比直角小的角是锐角。据此得出结论即可。注意不要漏数两个角拼在一起的角.\n【详解】根据分析知：图中有7 个角，有6 个锐角，有1 个钝角。",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "23-24 二年级上·福建莆田·期末"
+  },
+  {
+    "id": "447",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "在红领巾的三个角中，有一个较大的角是( )角，另外两个角都是( )角。",
+    "options": [],
+    "answer": "钝;锐",
+    "solution": "【分析】用三角尺的直角进行对比，大于直角的是钝角，小于直角的是锐角.\n【详解】由分析可得：在红领巾的三个角中，有一个较大的角是钝角，另外两个角都是锐角。",
+    "knowledge_points": [
+      "角的初步认识及辨认",
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "23-24 二年级下·河南周口·期末"
+  },
+  {
+    "id": "448",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.94,
+    "question": "![](images/9ae3a331ec16a7e4525ee42c6c7cc983a0413a62c1101d146c7002f546f07faf.jpg)左图中有( )个角，其中有( )个锐角。",
+    "options": [],
+    "answer": "4;2",
+    "solution": "【分析】据题意可知，角是由一个顶点和两条边组成的;用三角尺中的直角测量，比直角小的为锐角，即可知左图中角的对应数量;据此解答。考查学生对于图形中角的认识和角的区分.\n【详解】根据分析：图中共有4 个角;左下角和右下角的角比直角小，所以其中有2 个是锐角。",
+    "knowledge_points": [
+      "角的初步认识及辨认",
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "23-24 二年级上·福建莆田·期末"
+  },
+  {
+    "id": "449",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "图中，有( )个锐角,( )个直角和( )个钝角.\n\n![](images/8694aecdc38bb4ddb9eecfa9da4dd1f4fe0bde73e9e2eb0046e97ac1b2b425fb.jpg)",
+    "options": [],
+    "answer": "10;4;2",
+    "solution": "【分析】比三角尺中的直角小的角是锐角，比三角尺中的直角大的角是钝角，和三角尺中的直角相等的角是直角，据此解答.\n【详解】图中有10 个锐角,4 个直角,2 个钝角。",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "23-24 二年级下·湖南邵阳·期末"
+  },
+  {
+    "id": "450",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "钟面上 5 时整，时针和分针形成的角是( )角;( )时整和( )时整，钟面上时针和分针形成的角是直角。",
+    "options": [],
+    "answer": "钝;3;9",
+    "solution": "【分析】和书本，黑板的角相同大小的是直角;比直角大的是钝角;比直角小的是锐角。5 时整，如图1，分针指向12，时针指向5，形成的角是钝角;要形成直角，分针指向12，时针可指向 3 或 9，图 2 是 3 时，图 3 是 9 时.\n![](images/1e2a99761b5ea7a36dbb1f8510b61a6be09b0a52fcc96823bac4ef8e1d2f5f56.jpg)\n![](images/cf181be7285990b4fea59478458c44a08b20bc07d83553167412c61f428aa713.jpg)\n![](images/261b317aa541897450d9acefd26c24e18bd217719ad794cb1c5c89476d143153.jpg)\n【详解】钟面上5 时整，时针和分针形成的角是钝角;3 时整和9 时整，钟面上时针和分针形成的角是直角。",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征",
+      "整点时间与钟面指针的位置"
+    ],
+    "source": "23-24 二年级上·全国·课后作业"
+  },
+  {
+    "id": "451",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "( )个直角,( )个锐角,( )个钝角.\n\n![](images/3fba37dd4d9707f11281d59f829fbd46b8253e43cbb4356f77481199de2ea1f3.jpg)",
+    "options": [],
+    "answer": "5;6;2",
+    "solution": "【分析】直角是一种特殊的角，每副三角尺上都有一个直角，直角的一条边是水平的，另一条边是竖直的;锐角比直角小;钝角比直角大。据此解答.\n【详解】由分析可得:5 个直角,6 个锐角,2 个钝角。",
+    "knowledge_points": [
+      "角的初步认识及辨认",
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "23-24 二年级上·全国·课后作业"
+  },
+  {
+    "id": "452",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "( )个直角,( )个锐角,( )个钝角.\n\n![](images/13549f1bc1a439ffb41a9fa3aa3b3124a87f939064cae0a6377255f04ef57b92.jpg)",
+    "options": [],
+    "answer": "2;5;1",
+    "solution": "【分析】从一点引出两条射线所形成的图形叫做角。和书本，黑板的角相同大小的是直角，比直角大的是钝角，比直角小的是锐角，由此解答.\n【详解】由分析作图如下：黑色线为直角;橙色线为锐角;蓝色线为钝角。![](images/7c52d5029a22d3dceea34a639e537a44559ae580d7292981e3eaf2564a36681a.jpg)2 个直角,5 个锐角,1 个钝角。",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "23-24 二年级上·全国·课后作业"
+  },
+  {
+    "id": "453",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "一个角有( )个顶点,( )条边。角两边的张口越小，角就越( )。",
+    "options": [],
+    "answer": "1;2;小",
+    "solution": "【分析】角有一个顶点，两条边。角的大小与两边张口的大小有关，张口越小，角就越小.\n【详解】一个角有 1 个顶点,2 条边。角两边的张口越小，角就越小。例如:\n![](images/a123e07971382867eddb027265693bd33ffa307309e31d1a696d67c32ccad0cf.jpg)\n![](images/29eef248e68bf85b20967cd176c940352aa488a8dd505d7b34664ac659e78420.jpg)\n![](images/189bd85e134ec9390c4b1c4dae829da972bfe716183974e44baeea2e0f15fdec.jpg)",
+    "knowledge_points": [
+      "角的初步认识及辨认"
+    ],
+    "source": "23-24 二年级上·全国·课后作业"
+  },
+  {
+    "id": "454",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "从一个钝角里去掉一个直角，剩下的角一定是( )角;两个锐角拼在一起可能得到一个( )角,( )角或( )角。",
+    "options": [],
+    "answer": "锐;锐;钝;直",
+    "solution": "【分析】和书本，黑板的角同样大小的是直角，比直角大的是钝角，比直角小的是锐角。一个锐角和一个直角拼起来是一个钝角，所以钝角去掉直角后，剩下的是锐角。图1：两个锐角拼起来的角是锐角;图2：两个锐角拼起来的角是钝角;图3：两个锐角拼起来的角是直角.\n![](images/22e945954f36ab3e35e388845da55c24c2704134343bec0b8dd40451a97ef12e.jpg)\n【详解】从一个钝角里去掉一个直角，剩下的角一定是锐角;两个锐角拼在一起可能得到一个锐角，钝角或直角。",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "23-24 二年级上·全国·课后作业"
+  },
+  {
+    "id": "455",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "下面图形中各有几个直角。\n\n![](images/459a58f76dc997cd8482bf4a55f596ac5ce9e62d9693558c0e7fd0a2aff5b930.jpg)\n①\n![](images/fd2d5b33cb7686b87b759491bcdbf7c18ea6e85efb0990cf97fe7f1f7dd1ddfc.jpg)\n②\n![](images/415616947a19dbf82176a22c65c3107e3eed95302d0944e0dbe47d25f2e3c940.jpg)\n③\n( )个;( )个;( )个",
+    "options": [],
+    "answer": "2;3;4",
+    "solution": "【分析】从一点引出两条射线所形成的图形叫做角。和书本，黑板的角相同大小的是直角，由此作图如下，数出直角的数量即可.\n![](images/2026-02-24%20180348.jpg)\n【详解】由分析填写如下:①有2 个;②有3 个;③有4 个。",
+    "knowledge_points": [
+      "角的初步认识及辨认",
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "23-24 二年级上·全国·单元测试"
+  },
+  {
+    "id": "456",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "图中有( )个直角,( )个钝角,( )个锐角.\n\n![](images/40307824277ca1576e5bc5a07b2ff3a4f63db70a4e8b7e723610a64899e1a20e.jpg)",
+    "options": [],
+    "answer": "4;2;2",
+    "solution": "【分析】直角三角尺上最大的那个角就是直角，用三角尺的直角进行对比，大于直角的是钝角，小于直角的是锐角;据此数出各个角的数量.\n【详解】图中有4 个直角,2 个钝角,2 个锐角。",
+    "knowledge_points": [
+      "角的初步认识及辨认",
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "23-24 二年级上·全国·单元测试"
+  },
+  {
+    "id": "457",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "数一数，下图中各有几个角。\n\n![](images/7e6127b8489076a3ffb6fd5a5ef292efe8aaaa7270cb90bcadac7bdfee3b4212.jpg)\n( )个\n![](images/d82ffe20bb57dddaeef6a1b286be54ab8e185827544fc7a0df8c2e31045dd70b.jpg)\n( )个",
+    "options": [],
+    "answer": "7;6",
+    "solution": "【分析】角有两条边和一个公共端点，这两条边叫做角的边，它们的公共端点叫做角的顶点。![](images/95977f271716744b63a5c248af2df5e46dce646cd3cff8567d4b1add94563a55.jpg)数一数，有 7 个。单独的小角有3 个，两个小角组成的角有2 个,3 个小角组成的角有 1 个，相加即可.\n【详解】图1有7 个;3 + 2 + 1 = 6(个),图2有6 个。",
+    "knowledge_points": [
+      "角的初步认识及辨认"
+    ],
+    "source": "23-24 二年级上·全国·单元测试"
+  },
+  {
+    "id": "458",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "数学课本的封面上有( )个角，都是( )角。",
+    "options": [],
+    "answer": "4;直",
+    "solution": "【分析】根据角的概念和直角的特征数出数学书封面角的数量和类型即可.\n【详解】数学课本的封面上有 4 个角，都是直角。",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "17-18二年级上·全国·单元测试"
+  },
+  {
+    "id": "459",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "3 时整，钟面上时针和分针组成的角是( )。",
+    "options": [],
+    "answer": "直角",
+    "solution": "【分析】3 时整分针指在12，时针指在3，根据直角，锐角，钝角的特点观察分针和时针所夹的角即可.\n【详解】3 时整，钟面上时针和分针组成的角是直角。",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "20-21四年级上·山东临沂·期末"
+  },
+  {
+    "id": "460",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "要知道一个角是不是直角，可以用三角板上的( )比一比,( )角比直角大,( )角比直角小。",
+    "options": [],
+    "answer": "直角;钝;锐",
+    "solution": "【分析】三角板上直直的角是直角，判断一个角是不是直角可以用三角板上的直角比一比，比直角大的角是钝角，比直角小的角是锐角，据此得出结论即可.\n【详解】要知道一个角是不是直角，可以用三角板上的直角比一比，钝角比直角大，锐角比直角小。",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "23-24二年级上·全国·单元测试"
+  },
+  {
+    "id": "461",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "钟面上( )时整和( )时整，时针和分针形成的角是直角。",
+    "options": [],
+    "answer": "3;9",
+    "solution": "【分析】在三角板上，最大角就是直角;据此判断一个角是不是直角即可。3 时整，时针指向3，分针指向12，时针和分针形成的角是直角;9 时整，时针指向9，分针指向12，时针和分针形成的角是直角;据此解决.\n【详解】由题意分析得：钟面上3 时整和9 时整，时针和分针形成的角是直角。",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征",
+      "整点时间与钟面指针的位置"
+    ],
+    "source": "22-23 二年级上·江西赣州·阶段练习"
+  },
+  {
+    "id": "462",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "下图中，有( )个锐角,( )个直角,( )个钝角.\n\n![](images/9ce9c360558e135705734b5d0a6876bcf9e8859d9f67775f1755ca0907c83c4e.jpg)",
+    "options": [],
+    "answer": "3;3;2",
+    "solution": "【分析】在三角板上，最大角就是直角，锐角比直角小;钝角比直角大;据此解决.\n【详解】图中，有 3 个锐角,3 个直角,2 个钝角。",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "23-24 二年级下·湖南邵阳·期末"
+  },
+  {
+    "id": "463",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "下面图形中，有( )个直角,( )个钝角.\n\n![](images/4696d0ffe8210af6820570cc3665228fcc94cb107a59ffb60a889177004808ee.jpg)",
+    "options": [],
+    "answer": "11;2",
+    "solution": "【分析】像正方形的四个角一样直直的角是直角，比直角大的角是钝角，据此得出结论即可.\n【详解】根据分析知：图中，有 11 个直角,2 个钝角。",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "22-23 二年级上·河南南阳·期末"
+  },
+  {
+    "id": "464",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "魔方的每个面都是( )形，黑板是( )形，它们都有( )条边,( )个角，每个角都是( )角。",
+    "options": [],
+    "answer": "正方;长方;4;4;直",
+    "solution": "【分析】长方形是四个角相等的四边形;四条边都相等，四个角都相等的四边形是正方形;圆是由一条曲线组成的圈，圆圆的;三角形是由同一平面内不在同一直线上的三条线段\"首尾\"顺次连接所组成的封闭图形。平行四边形两组相对的边分别平行。据此解答.\n【详解】魔方的每个面都是正方形，黑板是长方形，它们都有4 条边,4 个角，每个角都是直角。",
+    "knowledge_points": [
+      "长方形，正方形，三角形和圆的初步认识",
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "23-24二年级下·河南周口·期中"
+  },
+  {
+    "id": "465",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "数一数，下图中一共有几个角。\n\n![](images/16b901a805a8bbfc804ca618fdedbd3defcf69bec88aa7a719e682d86a983da0.jpg)\n①\n![](images/c9f45480f914cf8150ad834024c9f870ac31888e44b7a92193db03cbed70ecde.jpg)\n②\n![](images/41e198629217dbb791fe7b412072c14db06ab459f7ef35f0aa995285dac5f2ce.jpg)\n③\n( )个角;( )个角;( )个角",
+    "options": [],
+    "answer": "3;5;4",
+    "solution": "【分析】角是由1 个顶点引出两条直直的线所组成的图形;角有两条边和一个公共端点，这两条边叫做角的边，它们的公共端点叫做角的顶点。据此数一数各有几个角即可.\n【详解】由题意分析得:①有3 个角;②有5 个角;③有4 个角。",
+    "knowledge_points": [
+      "角的初步认识及辨认"
+    ],
+    "source": "22-23 二年级上·河南南阳·期中"
+  },
+  {
+    "id": "466",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "你佩戴的红领巾上有( )个角，分别是两个( )角和一个( )角。",
+    "options": [],
+    "answer": "3;锐;钝",
+    "solution": "【分析】当一条直线和另一条横的直线交成的邻角彼此相等时，这些角的每一个被叫做直角，大于直角的是钝角，小于直角的是锐角.\n【详解】红领巾上有 3 个角，分别是两个锐角和一个钝角。",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "19-20 二年级上·全国·单元测试"
+  },
+  {
+    "id": "467",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "教室的黑板有( )个角，它们都是( )角。",
+    "options": [],
+    "answer": "4;直",
+    "solution": "【分析】角是由一个顶点引出两条直直的线所组成的图形;在三角板上，最大角就是直角;据此解决.\n【详解】由题意分析得：教室的黑板有4 个角，它们都是直角。",
+    "knowledge_points": [
+      "角的初步认识及辨认",
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "19-20 二年级上·全国·期中"
+  },
+  {
+    "id": "468",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "下图中有( )条线段,( )个直角,( )个锐角,( )个钝角.\n\n![](images/d925171035b7a072db5ff7c1cd868a9662b4245f3708160f0c4e365525c6067b.jpg)",
+    "options": [],
+    "answer": "6;4;2;3",
+    "solution": "【分析】线段是一条直直的线，且有2 个端点;在三角板上，最大角就是直角;锐角比直角小;钝角比直角大;据此解决.\n【详解】由题意分析得：图中有6 条线段,4 个直角,2 个锐角,3 个钝角。",
+    "knowledge_points": [
+      "线段的初步认识",
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "22-23 二年级上·河北邢台·期中"
+  },
+  {
+    "id": "469",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "数一数，下图中各有几个角。\n\n![](images/d1dcbde890bb48feb2802c006ba7e00e533c8524ab228a9f791f702297dd1523.jpg)\n①\n![](images/ddc5d09f2aa549f4c3bd766e9a0e7ef9c050d3aea8b2afb8f96641b5432766ae.jpg)\n②\n![](images/dcf599a3007b5326809f84142523912952ea55d993dc0a5bef42c1ec3f36ab49.jpg)\n③\n( )个;( )个;( )个",
+    "options": [],
+    "answer": "3;4;6",
+    "solution": "【分析】由一个顶点引出两条直直的线组成的图形叫做角;据此数一数每个图形有几个角即可.\n【详解】由题意分析得:①有3 个;②有4 个;③有6 个。",
+    "knowledge_points": [
+      "角的初步认识及辨认"
+    ],
+    "source": "22-23 二年级上·湖北恩施·期中"
+  },
+  {
+    "id": "470",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "下面的图形是由( )条线段围成的，共有( )个角，其中有( )个直角,( )个钝角,( )个锐角.\n\n![](images/0f969a8af00a9077f191c3767be798b105efa83abdea1c223fc0584e5ca29e11.jpg)",
+    "options": [],
+    "answer": "4;4;2;1;1",
+    "solution": "【分析】线段是直直的，有两个端点，据此数一数即可知道图形由几条线段围成的;角是由一个顶点和两条边组成的，据此数一数即可知道图形共有几个角;比直角大的角是钝角，比直角小的角是锐角，用三角板上的直角比一比即可知有几个直角，几个钝角，几个锐角.\n【详解】由分析可知：题中的图形是由4 条线段围成的，共有4 个角，其中有2 个直角,1 个钝角,1 个锐角。",
+    "knowledge_points": [
+      "线段的初步认识",
+      "角的初步认识及辨认",
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "22-23 二年级上·山东济宁·期末"
+  },
+  {
+    "id": "471",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "图中,( )条线段,( )个钝角,( )个直角.\n\n![](images/7239787a0525da0fd4ae5be25a1fa5dd4a7520a34833dbf6be8aee637b438449.jpg)",
+    "options": [],
+    "answer": "10;2;6",
+    "solution": "【分析】线段是直的，有两个端点，可测量;从一点引出两条射线所形成的图形叫做角，和书本同样大小的角是直角，比直角大的是钝角，由此数出数量即可.\n【详解】由分析作图如下:\n![](images/18ab47741e5c0ad1d24141fc2455e81e08aea23f78f1336812325adf231c9740.jpg)\n图中,10 条线段,2 个钝角,6 个直角。",
+    "knowledge_points": [
+      "线段的初步认识",
+      "角的初步认识及辨认"
+    ],
+    "source": "22-23 二年级上·山东菏泽·期末"
+  },
+  {
+    "id": "472",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "数一数，填一填.\n\n![](images/1807e92cd00f5dc4f6d61a03aff9c609ee4798214673c19584012a9f25c7b538.jpg)\n( )条线段;( )个角\n![](images/5ae0b6ef5fff2d2924538bdb9b2a03eeccbc0f383402e7c75f26d7d9196bf274.jpg)\n( )条射线;( )个角",
+    "options": [],
+    "answer": "4;3;4;6",
+    "solution": "【分析】线段：由 2 个端点，且是一条笔直的线;射线：由 1 个点引出一条笔直的线;角是由 1 个顶点引出两条射线所组成的图形。根据线段，角和射线的特征，分别数一数各有多少;据此解决。图2中基本角有 3 个，由 2 个基本角组成的角有2 个，由3 个基本角组成的角有1 个，然后加起来，求出和，就是此图角的总数量.\n【详解】图1有4 条线段,3 个角;图2有4 条射线,3 + 2 + 1 = 6(个),有6 个角。",
+    "knowledge_points": [
+      "线段，直线，射线的认识及特征",
+      "角的初步认识及辨认"
+    ],
+    "source": "22-23 二年级上·湖北省直辖县级单位·期末"
+  },
+  {
+    "id": "473",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "下图中有( )个角，其中有( )个直角，有( )个锐角，有( )个钝角.\n\n![](images/8dacfca07b383fc9d5a9ffd276fb56ddddc21695bac453e5d3decf7ad3532220.jpg)",
+    "options": [],
+    "answer": "6;1;3;2",
+    "solution": "【分析】从一点引出两条射线所形成的图形叫做角。和书本同样大小的是直角，比直角大的是钝角，比直角小的是锐角，由此数出数量即可.\n【详解】由分析作图如下：绿色线为直角;红色线为锐角;蓝色线为钝角。![](images/d0add4f3bac7c8af72741bff7039dd48b61653fa0f804c727f2d062c92aa3364.jpg)图中有 6 个角，其中有 1 个直角，有 3 个锐角，有 2 个钝角。",
+    "knowledge_points": [
+      "角的初步认识及辨认"
+    ],
+    "source": "23-24 二年级上·浙江台州·期末"
+  },
+  {
+    "id": "474",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "正方形四条边都( ),四个角都是( )。",
+    "options": [],
+    "answer": "相等;直角",
+    "solution": "【分析】四条边都相等，四个角都相等的四边形是正方形，据此解答.\n【详解】正方形四条边都相等，四个角都是直角。如图:![](images/9a33ea08f9466e3dc83c680fecb62b05b5b9042c526b584c308b18646a39b3ae.jpg)",
+    "knowledge_points": [
+      "正方形的概念及特点"
+    ],
+    "source": "22-23 二年级下·广西贵港·期中"
+  },
+  {
+    "id": "475",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "如图中有( )条线段，有( )个直角.\n\n![](images/eb57ca977792ba90a40a7767c1bb8909868f73311496deb09018822e57ebc9d3.jpg)",
+    "options": [],
+    "answer": "5;2",
+    "solution": "【分析】从一点引出两条射线所形成的图形叫做角。和书本同样大小的角是直角。线段是直的，有两个端点，可测量。由此解答.\n【详解】由分析可知，图中有 5 条线段，有 2 个直角。",
+    "knowledge_points": [
+      "线段的初步认识",
+      "角的初步认识及辨认"
+    ],
+    "source": "23-24二年级上·山东济南·期末"
+  },
+  {
+    "id": "476",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "一个直角和一个锐角拼出的角是( )角。",
+    "options": [],
+    "answer": "钝",
+    "solution": "【分析】在三角板上，最大角就是直角，锐角比直角小，钝角比直角大。一个直角和一个锐角拼出的角是钝角;如下图。![](images/1d66dfead5402e25fb48058b202a21a3a04df34d3be1bd720ca27a2111c31ce9.jpg)\n【详解】由题意分析得：一个直角和一个锐角拼出的角是钝角。",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "23-24 二年级上·河南周口·期末"
+  },
+  {
+    "id": "477",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "下图中有( )条线段，一共有( )个角，有( )个直角.\n\n![](images/8db602773d5f4e39af997fc8174f856387e506f98188515caf9b9f9ea70d590b.jpg)",
+    "options": [],
+    "answer": "3;2;2",
+    "solution": "【分析】线段是直的，有两个端点，可测量，由此数出数量即可;从一点引出两条射线所形成的图形叫做角。和书本同样大小的角是直角，由此解答.\n【详解】由分析可知：下图中有3 条线段，一共有2 个角，有2 个直角。",
+    "knowledge_points": [
+      "线段的初步认识",
+      "角的初步认识及辨认"
+    ],
+    "source": "23-24 二年级上·甘肃庆阳·期末"
+  },
+  {
+    "id": "478",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "图中有( )条线段，有( )个锐角.\n\n![](images/4a5c8dc9d980edb97e9dbccfdfd54745437737b4d5f6acd9f22a52890a9fe26c.jpg)",
+    "options": [],
+    "answer": "4;2",
+    "solution": "【分析】从一点引出两条射线所形成的图形叫做角。和书本同样大小的是直角，比直角小的是锐角，由此数出锐角的数量即可;线段是直的，有两个端点，可测量，由此数出线段的数量即可.\n【详解】由分析作图如下：图中有 4 条线段，有 2 个锐角.\n![](images/f41e721257524ab6f682df61d9125802e53f22611ef556c53e2e176f1aba0cb0.jpg)",
+    "knowledge_points": [
+      "线段的初步认识",
+      "角的初步认识及辨认"
+    ],
+    "source": "23-24 二年级上·甘肃庆阳·期末"
+  },
+  {
+    "id": "479",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "图中有( )个直角，有( )条线段.\n\n![](images/5bdf22cdac35e7fb02d5c1dc804231527bab03a13722f7f8c17ac1ce2ca5d218.jpg)",
+    "options": [],
+    "answer": "4;6",
+    "solution": "【分析】和三角尺中的直角相等的角是直角，据此解答。线段有两个端点，且两个端点之间的距离就是这条线段的长度。图形两个顶点之间的线就是线段，据此解答即可.\n【详解】图中有4 个直角，有6 条线段。",
+    "knowledge_points": [
+      "线段，直线，射线的认识及特征",
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "23-24 二年级上·山东临沂·期末"
+  },
+  {
+    "id": "480",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "下图中有( )条线段，有( )个角，其中有( )个是钝角.\n\n![](images/1fbb518cd18509c9df88ef8b7cd860ebb211a1f9b345366c717606f57f6e6ad9.jpg)",
+    "options": [],
+    "answer": "4;4;1",
+    "solution": "【分析】线段是直直的两端都有端点，不可延长。角是由两条有公共端点的射线组成的几何对象。长方形上的直直的角是直角，比直角大的角叫做钝角.\n【详解】根据分析知：图中有 4 条线段，有 4 个角，其中有 1 个是钝角。",
+    "knowledge_points": [
+      "线段，直线，射线的认识及特征",
+      "角的初步认识及辨认",
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "23-24 二年级上·新疆塔城·期末"
+  },
+  {
+    "id": "481",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "下图中有( )条线段，有( )个角，其中直角有( )个，锐角有( )个，钝角有( )个.\n\n![](images/b8b3531b902adfc71d8e27582e30c566ff94bfa950b428ae47bdd64266b0f1fc.jpg)",
+    "options": [],
+    "answer": "5;5;3;0;2",
+    "solution": "【分析】线段是直直的，有两个端点，由5 条线段围成的封闭图形是五边形;角有一个端点，两条边组成，五边形有5 个角，用三角尺的直角测量是不是直角，比直角大的是钝角，比直角小的是锐角，据此解答.\n【详解】填空如下：图中有5 条线段，有5 个角，其中直角有3 个，锐角有0 个，钝角有2 个。",
+    "knowledge_points": [
+      "线段，直线，射线的认识及特征",
+      "角的初步认识及辨认",
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "23-24 二年级上·浙江杭州·期末"
+  },
+  {
+    "id": "482",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "如图中有( )条线段，有( )个角，其中有( )个直角.\n\n![](images/347e421280b19289ad98c425550aa7afcb742152d1c202389711f5e53b4bbeea.jpg)",
+    "options": [],
+    "answer": "4;4;2",
+    "solution": "【分析】线段两端都有端点，不可延长，两个端点间的线条是直的。角有两条边和一个公共端点，这两条边叫做角的边，它们的公共端点叫做角的顶点。当一条直线和另一条横的直线交成的邻角彼此相等时，这些角的每一个被叫做直角.\n【详解】图中有 4 条线段，有 4 个角，其中有 2 个直角。",
+    "knowledge_points": [
+      "线段的初步认识",
+      "角的初步认识及辨认",
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "23-24二年级上·河南焦作·期末"
+  },
+  {
+    "id": "483",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "下图中，有( )条线段,( )个角,( )个直角.\n\n![](images/3eb77bbad5b5e99a7a8dee5be4c43c1ed10df7ed42e4e64f14c4bc045c07cf6b.jpg)",
+    "options": [],
+    "answer": "6;9;3",
+    "solution": "【分析】线段是直的，有两个端点，可测量。由此数出线段的数量即可;从一点引出两条射线所形成的图形叫做角。和书本同样大小的角是直角，由此数出数量即可.\n【详解】由分析作图如下:![](images/4d869830f4dbf06313549d2185091ee45759aabb72718e1d716f1bc950a5d885.jpg)图中，有 6 条线段,9 个角,3 个直角。",
+    "knowledge_points": [
+      "线段的初步认识",
+      "角的初步认识及辨认"
+    ],
+    "source": "23-24 二年级上·山东菏泽·期末"
+  },
+  {
+    "id": "484",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "![](images/af91105127a922b4787724d4da9729afcadc576aadac679ba8fa9d09210dc4ba.jpg)左图用一副三角板拼成的角有( )个锐角,( )个直角,( )个钝角。",
+    "options": [],
+    "answer": "5;2;1",
+    "solution": "【分析】当一条直线和另一条横的直线交成的邻角彼此相等时，这些角的每一个被叫做直角，大于直角的是钝角，小于直角的是锐角.\n【详解】图中用一副三角板拼成的角有5 个锐角,2 个直角,1 个钝角。",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "23-24 二年级上·湖北省直辖县级单位·期末"
+  },
+  {
+    "id": "485",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "下图中有( )条线段,( )个锐角,( )个直角,( )个钝角.\n\n![](images/19ca173b595e508a63b9670907fb05a380f7af2a45aaf5cc00ccf487e0493ec2.jpg)",
+    "options": [],
+    "answer": "9;4;6;3",
+    "solution": "【分析】线段是一条直直的线，且有2 个端点;角是由一个点引出两条直直的线所组成的图形。在三角板上，最大角就是直角，钝角比直角大，锐角比直角小。据此得出结论即可。熟练掌握线段和角的初步认识是解决此题的关键.\n【详解】根据分析知：图中有 9 条线段,4 个锐角,6 个直角,3 个钝角。",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "23-24 二年级上·湖南张家界·期末"
+  },
+  {
+    "id": "486",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "![](images/86327923cfb437f7eae5a82f631b06c5d21737e79bd1e9c7992062fa7bea9814.jpg)左图中，有( )条线段，有( )个角，其中有( )个直角。",
+    "options": [],
+    "answer": "7;8;5",
+    "solution": "【分析】线段是直的，有两个端点，可测量。从一点引出两条射线所形成的图形叫做角。和书本同样大小的角是直角，由此解答.\n【详解】该图中，有 7 条线段，有 8 个角，其中有5 个直角。",
+    "knowledge_points": [
+      "线段的初步认识",
+      "角的初步认识及辨认"
+    ],
+    "source": "23-24 二年级上·山东济宁·期末"
+  },
+  {
+    "id": "487",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "判断题",
+    "difficulty": 0.65,
+    "question": "用一个直角和一个锐角一定能拼成一个钝角。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】三角尺上最大的角为直角，用三角板的直角进行比较测量，比直角小的就是锐角，比直角大的就是钝角。一个直角和一个锐角拼成的角一定比直角大，据此作图解答.\n【详解】如图:![](images/5f2f08cb081f45f3002e80d0a99dcd7d745162c8a79192f822b91aaf7f8f8522.jpg)用一个直角和一个锐角一定能拼成一个钝角。原题说法正确。故答案为:√",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "20-21 二年级上·内蒙古巴彦淖尔·期中"
+  },
+  {
+    "id": "488",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "正方形，平行四边形都有四条边，四个直角。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】根据正方形，平行四边形的特征来解决即可。正方形是正正方方的，由4 条边围成，且4 条边都一样长，且4 个角都是直角;平行四边形是由4 条边围成，且对边一样长，一组对边向同一个方向倾斜，有4 个角，一般都不是直角.\n【详解】由题意分析得：正方形，平行四边形都有四条边，四个直角;此说法错误。故答案为: ×",
+    "knowledge_points": [
+      "平行四边形的概念及特点",
+      "正方形的概念及特点"
+    ],
+    "source": "23-24 二年级下·河北邯郸·期末"
+  },
+  {
+    "id": "489",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "把长方形纸片剪去一个最大的正方形后，剩下的纸片四个角都是直角。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】长方形和正方形都有四条边，四个角都是直角，根据长方形和正方形的图形特征进行解答即可.\n【详解】把长方形纸片剪去一个最大的正方形后，即以这个长方形较短的边为正方形的边长画的正方形最大，剩下的纸片为长方形，所以剩下的纸片四个角都是直角，原题说法正确。故答案为:√",
+    "knowledge_points": [
+      "长方形，正方形，三角形和圆的初步认识",
+      "直角，钝角，锐角的认识及特征",
+      "平面图形的分割"
+    ],
+    "source": "23-24 二年级下·河南周口·期末"
+  },
+  {
+    "id": "490",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "判断题",
+    "difficulty": 0.65,
+    "question": "一个三角形，用剪刀剪去一个角后，可能还有三个角。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】一个三角形，用剪刀剪去一个角有以下两种情况，如图:![](images/ccd8a6589f67cdd8217021f00435ef85f0bf5b02461fe0866d7710692dfef563.jpg)![](images/66eff920675606ffc1ca162b0f0dc191c9fc81e17e8ea350baf597251e146e19.jpg)所以剩下的角还有三个或四个，据此解答即可.\n【详解】一个三角形，用剪刀剪去一个角后，可能还有三个角或四个角，原题说法正确;故答案为:√",
+    "knowledge_points": [
+      "长方形，正方形，三角形和圆的初步认识",
+      "角的初步认识及辨认"
+    ],
+    "source": "23-24二年级上·全国·课后作业"
+  },
+  {
+    "id": "491",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "在三角尺中，最大的角一定是直角。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】和书本，黑板的角相同大小的是直角，比直角大的是钝角，比直角小的是锐角。如图为三角尺，红色线的角是直角，黑色线的角都比直角小，是锐角，也就是直角最大.\n![](images/ea03f3c0bdff62a43dbeb6e29f995888ef75170e998756a4cb4da4b263c4b534.jpg)\n【详解】由分析可知，在三角尺中，最大的角一定是直角。原题说法正确。故答案为:√",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "23-24二年级上·全国·课后作业"
+  },
+  {
+    "id": "492",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "一副三角尺中有 2 个直角,4 个钝角。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】从一点引出两条射线所形成的图形叫做角。和书本，黑板的角相同大小的是直角，比直角大的是钝角，比直角小的是锐角，由此解答.\n【详解】如图为一副三角尺，其中有2 个直角,4 个锐角，原题说法错误。![](images/9b9752406150637041595e6acc32d6279c3d315914bfd7421018b997116c2aa2.jpg)故答案为: ×",
+    "knowledge_points": [
+      "角的初步认识及辨认",
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "23-24 二年级上·全国·单元测试"
+  },
+  {
+    "id": "493",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "判断题",
+    "difficulty": 0.65,
+    "question": "所有的角中，直角最大。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】钝角比直角大，据此得出结论即可.\n【详解】根据分析知：所有的角中，直角最大，此说法错误。故答案为: ×",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "18-19 二年级上·全国·单元测试"
+  },
+  {
+    "id": "494",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "判断题",
+    "difficulty": 0.65,
+    "question": "一个直角和一个锐角可以拼成一个钝角。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】从一点引出两条射线所形成的图形叫做角。和书本，黑板的角相同大小的是直角，比直角大的是钝角，比直角小的是锐角，由此解答.\n【详解】如图:![](images/0c0efcaab60bc0cadd26ecb14dda2fd8795b3e7a47399095aab755617a94c4e7.jpg)所以一个直角和一个锐角可以拼成一个钝角;故答案为:√",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "20-21 二年级上·广西南宁·期中"
+  },
+  {
+    "id": "495",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "判断题",
+    "difficulty": 0.65,
+    "question": "用纸折角，折出的角的大小与这张纸的大小有关。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】角的大小与两条边的长短无关，与两条边叉开的大小有关，叉开的越大，角就越大;叉开的越小，角就越小。本题考查了角的大小影响的因素.\n【详解】用纸折角，折出的角的大小与这张纸的大小无关，角的大小与角两条边的长短无关，原题干说法错误。故答案为: ×",
+    "knowledge_points": [
+      "角的初步认识及辨认"
+    ],
+    "source": "23-24 二年级下·广东韶关·期末"
+  },
+  {
+    "id": "496",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "角的大小与角两边的长度无关。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】角的特点有：角的大小与边的长短无关，与角的叉开大小有关，叉开的越大，角越大。由此解答.\n【详解】由分析可知：角的大小与角两边的长度无关，原题说法正确。故答案为:√",
+    "knowledge_points": [
+      "角的初步认识及辨认"
+    ],
+    "source": "23-24 二年级下·河南新乡·期末"
+  },
+  {
+    "id": "497",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "判断题",
+    "difficulty": 0.65,
+    "question": "![](images/dc5be7fd2732dac6d7c515c37350954027831669064cfd1f0d8998c4439d8f90.jpg)有8 个角。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】角有两条直直的边和一个公共端点，这两条直直的边叫做角的边，它们的公共端点叫做角的顶点，据此数出该图一共有多少个角即可.\n【详解】![](images/f467424c22c58e052f3c9a027cb0d0184ab2ca2b5160413de271baa0401090ae.jpg)数出该图一共有8 个角，原题说法正确。故答案为:√",
+    "knowledge_points": [
+      "角的初步认识及辨认"
+    ],
+    "source": "22-23二年级上·山西长治·期中"
+  },
+  {
+    "id": "498",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "判断题",
+    "difficulty": 0.65,
+    "question": "一个三角板有一个直角，两个锐角。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】一副三角板的六个角共有4 个度数，分别是30°,45°,60°,90°,每个三角板都是由一个直角和两个锐角组成的，据此解答.\n【详解】一个三角板是由一个直角和两个锐角组成的，此说法正确。故答案为:√",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "23-24二年级上·江西宜春·期末"
+  },
+  {
+    "id": "499",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "用一副三角尺可以拼出一个钝角。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】两个三角尺分别是由一个直角和两个锐角组成，拼成的钝角比直角大即可，据此解答.\n【详解】钝角比直角大，用一个直角和一个锐角即可拼成钝角，此说法正确。故答案为:√",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "23-24 二年级上·江西宜春·期末"
+  },
+  {
+    "id": "500",
+    "unit": "第三单元 角的初步认识",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "数学书封面的直角比三角尺上的直角大。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】从一点引出两条射线所形成的图形叫做角。角的大小与两边的长短无关，只与边叉开的大小有关，叉开得越大，角越大，叉开得越小，角越小。由此解答.\n【详解】由分析可知，数学书封面的直角和三角尺上的直角一样大。原题说法错误。故答案为: ×",
+    "knowledge_points": [
+      "角的初步认识及辨认"
+    ],
+    "source": "18-19二年级上·全国·期中"
+  }
+]
diff --git "a/\344\272\214\345\271\264\347\272\247\351\242\230\351\233\206/\344\272\214\345\271\264\347\272\247\344\270\212/\344\272\214\345\271\264\347\272\247\344\270\212\347\254\254\344\272\214\345\215\225\345\205\203100\344\273\245\345\206\205\345\212\240\346\263\225\345\222\214\345\207\217\346\263\225(\344\272\214).json" "b/\344\272\214\345\271\264\347\272\247\351\242\230\351\233\206/\344\272\214\345\271\264\347\272\247\344\270\212/\344\272\214\345\271\264\347\272\247\344\270\212\347\254\254\344\272\214\345\215\225\345\205\203100\344\273\245\345\206\205\345\212\240\346\263\225\345\222\214\345\207\217\346\263\225(\344\272\214).json"
new file mode 100644
index 0000000000000000000000000000000000000000..a187cf8d9219f611d8fb79d659af5c5867021e22
--- /dev/null
+++ "b/\344\272\214\345\271\264\347\272\247\351\242\230\351\233\206/\344\272\214\345\271\264\347\272\247\344\270\212/\344\272\214\345\271\264\347\272\247\344\270\212\347\254\254\344\272\214\345\215\225\345\205\203100\344\273\245\345\206\205\345\212\240\346\263\225\345\222\214\345\207\217\346\263\225(\344\272\214).json"
@@ -0,0 +1,7470 @@
+[
+  {
+    "id": "1",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "红红在做一道加法算式时，把其中一个加数 34 看成了 43，结果是 75，正确的结果是( )。",
+    "options": [
+      "A. 66",
+      "B. 75",
+      "C. 84"
+    ],
+    "answer": "A",
+    "solution": "【分析】在做一道加法算式时，把其中一个加数 34 看成了43，所以和会增加 43 - 34 = 9，和增加了9得到错误的结果75，所以用 75 减 9 可算出正确的结果.\n【详解】43 - 34 = 9,75 - 9 = 66，正确的结果是 66。故答案为:A",
+    "knowledge_points": [
+      "两位数与两位数的退位减法",
+      "错中求解问题(加减法)"
+    ],
+    "source": "24-25三年级上·湖北·期中"
+  },
+  {
+    "id": "2",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "红红做一道减法题，把减数 43 看成了 34，算出的与正确的差相比较( )。",
+    "options": [
+      "A. 多 9",
+      "B. 少 9",
+      "C. 多 11"
+    ],
+    "answer": "A",
+    "solution": "【分析】在计算减法时，如果把减数看多了，算出的差会比正确结果小;如果把减数看少了，算出的差会比正确结果大。减数看少了几，算出的差就比正确的差多几。据此解答.\n【详解】由分析知:43 - 34 = 9，红红做一道减法题，把减数 43 看成了 34，算出的与正确的差相比较多 9。故答案为:A",
+    "knowledge_points": [
+      "两位数与两位数的退位减法"
+    ],
+    "source": "24-25 三年级上·四川南充·期中"
+  },
+  {
+    "id": "3",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "选择题",
+    "difficulty": 0.94,
+    "question": "水果店有苹果75箱，第一天卖出24箱，第二天卖出36箱，还剩多少箱。下面列式，错误的是( )。",
+    "options": [
+      "A. 75 - 24 - 36",
+      "B. 75 - 24 + 36",
+      "C. 75 - (24 + 36)"
+    ],
+    "answer": "B",
+    "solution": "【分析】根据题意可知：求还剩多少箱，用水果店有的数量减去第一天卖的数量再减去第二天卖出的数量即可;或者先求出第一天和第二天一共卖出的数量，然后用水果店有的数量减去第一天和第二天一共卖出的数量即可。因题意要求是选择错误选项，则据此进行选择即可.\n【详解】A。75 - 24 - 36表示的是水果店有的数量减去第一天卖的数量再减去第二天卖出的数量为剩余的数量，表述正确，不符合题意;B。75 - 24 + 36表示的是水果店有的数量减去第一天卖的数量再加上第二天卖出的，题干未给出相对应的问题，则符合题意;C。75 - (24 + 36)表示先求出第一天和第二天一共卖出的数量，然后用水果店有的数量减去第一天和第二天一共卖出的数量即可还剩的数量，表述正确，不符合题意。故答案为:B",
+    "knowledge_points": [
+      "100以内数的连减运算",
+      "带有小括号的混合运算",
+      "100以内数的加减混合运算"
+    ],
+    "source": "24-25二年级上·广东东莞·期中"
+  },
+  {
+    "id": "4",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "同学们排队做操，小明前面有11名同学，后面有16名同学，这一列一共有( )名同学。",
+    "options": [
+      "A. 27",
+      "B. 28",
+      "C. 29"
+    ],
+    "answer": "B",
+    "solution": "【分析】将小明前面和后面的同学数量相加，再加上小明这个人，即可得出这一列一共有多少名同学.\n【详解】11 + 16 + 1 = 27 + 1 = 28(名),所以这一列一共有28名同学。故答案为:B",
+    "knowledge_points": [
+      "100以内数的连加运算"
+    ],
+    "source": "22-23二年级下·新疆乌鲁木齐·期中"
+  },
+  {
+    "id": "5",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "小明有30元，买书花了15元，买玩具花了10元。求还剩多少钱。下面列式错误的是( )。",
+    "options": [
+      "A. 30 - 15 + 10",
+      "B. 30 - 15 - 10",
+      "C. 30 - (15 + 10)"
+    ],
+    "answer": "A",
+    "solution": "【分析】根据题意，结合题目已知条件和问题，逐项分析各个选项，找出错误的算式即可解答.\n【详解】A。小明的钱数减去买书花的钱数，再加上买玩具花的钱数，算式没有意义，不能求出还剩下多少钱，算式错误;B。小明的钱数减去买书花的钱数，再减去买玩具花的钱数，等于还剩下多少钱，算式正确;C。买书的钱数加上买玩具花的钱数，等于一共花了多少钱，再用小明的钱数减去一共花的钱数，等于还剩下多少钱，算式正确。故答案为:A",
+    "knowledge_points": [
+      "100 以内数的连减运算",
+      "100 以内数的加减混合运算"
+    ],
+    "source": "24-25二年级下·湖南长沙·期中"
+  },
+  {
+    "id": "6",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "在计算 39 + 25 时，聪聪，明明和乐乐分别用了以下方法，你认为错误的是( )。",
+    "options": [
+      "A. 明明：先算 30 + 20 = 50  ,再算 5 + 9 = 14，最后算 50 + 14 = 64  ",
+      "B. 聪聪：先算 9 + 5 = 14，再算 3 + 2 = 5，所以等于54  ",
+      "C. 乐乐：先算 39 + 1 = 40，再算 40 + 24 = 64"
+    ],
+    "answer": "B",
+    "solution": "【分析】分析明明的方法：明明把39拆分成 30 + 9，把 25拆分成 20 + 5 。先计算整十数相加: 30 + 20 = 50  ,这是将两个数的十位数字所代表的数值相加。再计算个位数字相加:5 + 9 = 14，即把两个数个位上的数字相加。最后将两部分结果相加:50 + 14 = 64，这种方法符合两位数加两位数的口算思路，是正确的。分析聪聪的方法：聪聪先算 9 + 5  = 14，这一步计算两个数个位上的数字之和，是正确的。但是再算 3 + 2 = 5 时出现错误，这里的3和2分别是39和25的十位数字，在计算十位数字之和时，因为3表示3个十,2表示2个十，所以应该计算 30 + 20 = 50  ,而不是 3 + 2 = 5 。正确的计算应该是50+ 14 = 64，而不是 54，所以聪聪的方法错误。分析乐乐的方法：乐乐采用凑整法，先算 39 + 1 = 40，再算 40 + 24 = 64，这种凑整的方法在加法计算中经常使用，是正确的.\n【详解】A。明明的方法：把39拆分成 30 + 9，把25拆分成 20 + 5 。先算 30 + 20 = 50  ,再算 5 + 9 = 14，最后算50 + 14 = 64，这种方法是正确的，符合两位数加两位数的口算方法。B。聪聪的方法：先算 9 + 5 = 14，再算 3 + 2 = 5 时出现错误，这里的3和2分别是39和25的十位数字，在计算十位数字之和时，因为3表示3个十,2表示2个十，所以应该是30+ 20 = 50，而不是 3 + 2 = 5，最后结果应该是 50 + 14 = 64，所以聪聪的方法错误。C。乐乐的方法：采用凑整法，先算 39 + 1 = 40，把39凑成了整十数 40。因为加了 1，所以后面要再加上 25 - 1 = 24，即 40 + 24 = 64，这种方法是正确的。故答案为:B",
+    "knowledge_points": [
+      "两位数与两位数的进位加法"
+    ],
+    "source": "24-25 三年级上·河南郑州·期末"
+  },
+  {
+    "id": "7",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "一根彩带长 100 米。第一次用去38米，第二次用去20米，剩下的彩带比原来短了( )米。",
+    "options": [
+      "A. 42",
+      "B. 58",
+      "C. 62"
+    ],
+    "answer": "B",
+    "solution": "【分析】根据题意，剩下的彩带比原来短的长度，也就是共用去的长度，用加法计算，即第一次用去的长度 + 第二次用去的长度 = 一共用去的长度.\n【详解】38 + 20 = 58(米),剩下的彩带比原来短了58米。故答案为:B",
+    "knowledge_points": [
+      "两位数与整十数的加法"
+    ],
+    "source": "24-25 二年级上·浙江嘉兴·期末"
+  },
+  {
+    "id": "8",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "夏天往往是从一块西瓜开始的。果农张叔叔拉了一车西瓜，卖了65个后，还剩下12个没有卖，这车西瓜一共有( )个。",
+    "options": [
+      "A. 53",
+      "B. 77",
+      "C. 86"
+    ],
+    "answer": "B",
+    "solution": "【分析】将卖了的个数和没有卖的个数相加即可求出这车西瓜一共有多少个.\n【详解】65 + 12 = 77(个),这车西瓜一共有77个。故答案为:B",
+    "knowledge_points": [
+      "两位数与两位数的不进位加法"
+    ],
+    "source": "24-25 二年级上·河南南阳·期末"
+  },
+  {
+    "id": "9",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "一根长70米的绳子，第一次剪去28米，第二次剪去15米，这根绳子一共剪去了多少米。列式正确的是( )。",
+    "options": [
+      "A. 70 - 28 - 15",
+      "B. 70 - 28 + 15",
+      "C. 28 + 15"
+    ],
+    "answer": "C",
+    "solution": "【分析】根据题意可知：求这根绳子一共剪去了多少米。用第一次剪去的长度加上第二次剪去的长度即可.\n【详解】28 + 15 = 43(米),这根绳子一共剪去43米。列式正确的是 28 + 15。故答案为:C",
+    "knowledge_points": [
+      "两位数与两位数的进位加法"
+    ],
+    "source": "24-25二年级上·贵州黔南·期末"
+  },
+  {
+    "id": "10",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "一共有50元钱，第一次用掉了 16 元，第二次用掉了 20 元。算式\"16 + 20 = 36(元)\"解决的问题是( )。",
+    "options": [
+      "A. 还剩下多少元。",
+      "B. 两次一共用掉多少元。",
+      "C. 原来有多少元。",
+      "D. 第二次比第一次多用掉多少元。"
+    ],
+    "answer": "B",
+    "solution": "【分析】根据题意,16是第一次用掉的钱数,20是第二次用掉的钱数，加法表示求两次一共用掉的钱数，由此解答.\n【详解】A。还剩下多少元。列式应为 50 - 16 - 20 = 14(元),不符合题意;B。两次一共用掉多少元。列式为 16 + 20 = 36(元),符合题意;C。原来有 50 元钱，不需要计算，不符合题意;D。第二次比第一次多用掉多少元。列式应为 20 - 16 = 4(元),不符合题意。所以算式\"16 + 20 = 36(元)\"解决的问题是两次一共用掉多少元。故答案为:B",
+    "knowledge_points": [
+      "100 以内数的连减运算",
+      "\"提问题\" \"填条件\"问题",
+      "两位数与两位数的退位减法",
+      "两位数与整十数的加法"
+    ],
+    "source": "24-25二年级上·福建福州·期末"
+  },
+  {
+    "id": "11",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "一根电线长 100 米，用去了 70 米，剩下的比用去的短( )米。",
+    "options": [
+      "A. 30",
+      "B. 40",
+      "C. 50"
+    ],
+    "answer": "B",
+    "solution": "【分析】根据题意，用去的长度减去剩下的长度，可求出剩下的比用去的短多少米，其中剩下的长度用原来的长度减去用去的长度计算.\n【详解】70 -(100 - 70)= 70 - 30 = 40(米),剩下的比用去的短40米。故答案为:B",
+    "knowledge_points": [
+      "带有小括号的混合运算"
+    ],
+    "source": "24-25 二年级上·河南三门峡·期末"
+  },
+  {
+    "id": "12",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "如果把算式78 - 16 - 2 变成 78 - (16 - 2),计算结果和原式相比( )。",
+    "options": [
+      "A. 大 4",
+      "B. 小 4",
+      "C. 不变"
+    ],
+    "answer": "A",
+    "solution": "【分析】先按照整数混合运算的运算顺序求出两个算式的结果，然后比较一下结果并相减，求出差，即可解决。只有加减法的混合运算，从左往右计算;含有小括号的混合运算，先算小括号里面的，再算小括号外面的.\n【详解】78 - 16 - 2 = 62 - 2  = 60;78 - (16 - 2)  = 78 - 14  = 64,64 > 60,64 - 60 = 4，即，如果把算式 78 - 16 - 2 变成 78 - (16 - 2),计算结果和原式相比大 4。故答案为:A",
+    "knowledge_points": [
+      "100以内数的比大小",
+      "100以内数的连减运算",
+      "带有小括号的混合运算"
+    ],
+    "source": "24-25二年级上·河南南阳·期末"
+  },
+  {
+    "id": "13",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "2024年巴黎奥运会上，中国队共获得44枚金牌，银牌比金牌少17枚。算式\"44 - 17\"解决的问题是( )。",
+    "options": [
+      "A. 金牌有几枚",
+      "B. 银牌有几枚",
+      "C. 金牌数比银牌数少几枚",
+      "D. 一共获得几枚金牌和银牌"
+    ],
+    "answer": "B",
+    "solution": "【分析】算式\"44 - 17\"表示用金牌的数量减去银牌比金牌少的数量，求的是银牌的数量.\n【详解】A。已知金牌有 44 枚，不符合。B。求的是银牌的数量，符合。C。银牌比金牌少，不符合。D。求的是银牌的数量，不符合。2024年巴黎奥运会上，中国队共获得44枚金牌，银牌比金牌少17枚。算式\"44 - 17\"解决的问题是：银牌有几枚。故答案为:B",
+    "knowledge_points": [
+      "\"提问题\"\"填条件\"问题",
+      "两位数与两位数的退位减法"
+    ],
+    "source": "24-25二年级上·福建龙岩·期末"
+  },
+  {
+    "id": "14",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "下面算式中,( )的得数大于 50。",
+    "options": [
+      "A. 89 - 49",
+      "B. 20 + 36",
+      "C. 70 - 21"
+    ],
+    "answer": "B",
+    "solution": "【分析】整数的大小比较：比较数的大小，先看位数的多少，位数多的数就大;位数相同，从高位开始比较，高位上的数大则这个数大，高位上的数相同，就比较下一位。算出各算式的结果，然后作比较.\n【详解】A。89 - 49 = 40 , 40 < 50;B。20 + 36 = 56 ,56 > 50;C. 70 - 21 = 49 , 49 < 50.20 + 36 的得数大于 50。故答案为:B",
+    "knowledge_points": [
+      "100以内数的比大小",
+      "两位数与两位数的退位减法",
+      "两位数与两位数的不退位减法",
+      "两位数与整十数的加法"
+    ],
+    "source": "24-25 二年级上·广东云浮·期末"
+  },
+  {
+    "id": "15",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "二(3)班一共有 24 人参加了写字社团，有 21 人参加了美术社团，其中有 8 人两个社团都参加，还有 5 人一项活动也没有参加，二(3)一共有( )人。",
+    "options": [
+      "A. 45",
+      "B. 44",
+      "C. 42",
+      "D. 50"
+    ],
+    "answer": "C",
+    "solution": "【分析】根据题意可知，参加写字社团的人数加上参加美术社团的人数，减去两项社团都参加的人数，等于至少参加一个社团的人数，再加上一项也没有参加的人数，等于这个班的总人数，据此解答.\n【详解】根据分析可得:24 + 21 - 8 = 45 - 8 = 37(人),37 + 5 = 42(人),所以，二(3)一共有42人。故答案为:C",
+    "knowledge_points": [
+      "一位数与两位数的进位加法",
+      "100以内数的加减混合运算",
+      "集合问题"
+    ],
+    "source": "24-25 二年级上·浙江温州·期末"
+  },
+  {
+    "id": "16",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "上学期二年级的男生人数比女生多 28 人，这学期转来了 4 名男生和 6 名女生，现在二年级男生人数比女生多( )人。",
+    "options": [
+      "A. 24",
+      "B. 26",
+      "C. 30",
+      "D. 34"
+    ],
+    "answer": "B",
+    "solution": "【分析】根据题意，先用6减4求出转来的男生比女生少几名，再用28减转来的男生比女生少的人数，等于现在二年级男生比女生多多少人，即可解答此题.\n【详解】根据分析可得:28 - (6 - 4)= 28 - 2 = 26(人),所以，现在二年级男生人数比女生多26人。故答案为:B",
+    "knowledge_points": [
+      "100以内数的连减运算"
+    ],
+    "source": "24-25 二年级上·浙江温州·期末"
+  },
+  {
+    "id": "17",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "李老师与平平的年龄和是43岁,3年后李老师和平平的年龄和是( )岁。",
+    "options": [
+      "A. 46",
+      "B. 49",
+      "C. 40",
+      "D. 37"
+    ],
+    "answer": "B",
+    "solution": "【分析】依据题意可知,3年后李老师增加3岁，平平增加3岁，所以3年后两人的年龄和等于现在两人的年龄和加3，再加3岁，由此解答本题.\n【详解】根据分析可得 43 + 3 + 3 = 49(岁),所以3年后李老师和平平的年龄和是49岁。故答案为:B",
+    "knowledge_points": [
+      "100以内数的连加运算"
+    ],
+    "source": "24-25 二年级上·浙江温州·期末"
+  },
+  {
+    "id": "18",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "一楼一共有9个房间，用9把钥匙打开9个房间的门，每把钥匙只能打开其中的一扇门，最多( )次才能确保门能打开。",
+    "options": [
+      "A. 36",
+      "B. 45",
+      "C. 9",
+      "D. 27"
+    ],
+    "answer": "B",
+    "solution": "【分析】第一把钥匙最多要试9次就能确保把门打开;第二把钥匙最多要试8次就能确保把门打开;第三把钥匙最多要试7次就能确保把门打开;以此类推，直到最后1把钥匙要试1次就能确保把门打开;据此解答即可.\n【详解】根据分析可得:9 + 8 + 7 + 6 + 5 + 4 + 3 + 2 + 1 = 45(次),所以，最多要试 45 次才能确保门能打开。故答案为:B",
+    "knowledge_points": [
+      "100 以内数的连加运算"
+    ],
+    "source": "24-25二年级上·浙江温州·期末"
+  },
+  {
+    "id": "19",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "贝贝在计算两位数加两位数时，个位上算 6 + 7  =  13，十位上算 3 + 2 + 1 = 6，贝贝计算的这道题是( )。",
+    "options": [
+      "A. ①和②",
+      "B. ③和④",
+      "C. ①和③",
+      "D. ②和 ④"
+    ],
+    "answer": "B",
+    "solution": "【分析】两位数与两位数的加法计算时，相同数位对齐，从个位算起，若相加满十，则向十位进1。题中个位算6 + 7= 13，也就是两个加数的个位分别是6和7，满十向十位进1;十位上算 3 + 2 + 1 = 6，其中 1 是个位进的位，也就是两个数的十位分别是 3 和 2，由此解答.\n【详解】① 37 - 36 是减法算式，不符合题意;②33 + 67 个位分别是3和7，十位分别是3和6，不符合题意;③36 + 27 个位分别是 6 和 7，十位分别是 3 和 2，符合题意;④26 + 37 个位分别是6和7，十位分别是2和3，符合题意。所以贝贝计算的这道题是③和 ④。故答案为:B",
+    "knowledge_points": [
+      "两位数与两位数的不退位减法",
+      "两位数与两位数的进位加法"
+    ],
+    "source": "24-25二年级上·福建龙岩·期末"
+  },
+  {
+    "id": "20",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "34 + 5□,要使和的十位数字是9,□里有( )种填法。",
+    "options": [
+      "A. 4",
+      "B. 5",
+      "C. 6"
+    ],
+    "answer": "A",
+    "solution": "【分析】两位数与两位数的加法计算时，相同数位对齐，从个位算起，个位相加满十，向十位进1。要使和的十位是9，则十位为 3 + 5 + 1 = 9，即个位相加的和要大于或等于10，由此解答.\n【详解】由分析可知: 4 + □大于或等于 10.4 + □ = 10 时, 10 - 4 = 6。也就是□里可以填的数大于或等于 6，即可以填写6,7,8,9，共4种填法。故答案为:A",
+    "knowledge_points": [
+      "两位数与两位数的进位加法"
+    ],
+    "source": "24-25 二年级上·浙江嘉兴·期末"
+  },
+  {
+    "id": "21",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "一根绳子长 100 米，第一次剪去28米，第二次剪去54米。算式\"100 - (28 + 54)\"解决的问题是( )。",
+    "options": [
+      "A. 第一次剪去后剩下多少米。  ",
+      "B. 两次一共剪去多少米。",
+      "C. 剪去两次后还剩多少米。"
+    ],
+    "answer": "C",
+    "solution": "【分析】由题意可知一根绳子长 100 米，第一次剪去 28 米，第二次剪去54米。算式\"100 - (28 + 54)\"解决的问题是减去两次后还剩多少米，因为 28 + 54 求的是两次剪去的长度之和，用绳子的总长度减去两次剪去的长度之和，计算的就是剪去两次后还剩多少米.\n【详解】由分析得:100 - (28 + 54) = 100 - 82 = 18(米),一根绳子长 100 米，第一次剪去 28 米，第二次剪去 54 米;算式\"100 - (28 + 54)\"解决的问题是减去两次后还剩多少米。故答案为:C",
+    "knowledge_points": [
+      "带有小括号的混合运算",
+      "\"提问题\"\"填条件\"问题"
+    ],
+    "source": "24-25 二年级上·湖北武汉·期末"
+  },
+  {
+    "id": "22",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "小军拍球拍了 21 下，比小丽拍的少 15 下，两人一共拍了( )下。",
+    "options": [],
+    "answer": "57",
+    "solution": "【分析】小军拍球拍了 21 下，比小丽拍的少 15 下，用 21加上15可算出小丽拍了多少下，再加上小军拍的可算出两人一共拍了多少下.\n【详解】21 + 15 + 21 = 36 + 21 = 57(下),所以两人一共拍了 57 下。",
+    "knowledge_points": [
+      "两位数与两位数的不进位加法",
+      "100以内数的连加运算"
+    ],
+    "source": "2025 三年级上·全国·专题练习"
+  },
+  {
+    "id": "23",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "一张桌子 48 元，一把椅子 22 元，买一套桌椅需要( )元。",
+    "options": [],
+    "answer": "70",
+    "solution": "【分析】用一张桌子加上一把椅子的钱则是买一套桌椅需要的钱.\n【详解】 48 + 22 = 70 (元),所以买一套桌椅需要70元。",
+    "knowledge_points": [
+      "两，三位数的一次进位加法"
+    ],
+    "source": "25-26 三年级上·广东韶关·期中"
+  },
+  {
+    "id": "24",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "与168相加时会产生进位的三位数有( )个。",
+    "options": [],
+    "answer": "836",
+    "solution": "【分析】本题可先求出所有三位数的个数，再求出与168相加不产生进位的三位数的个数，最后用所有三位数的个数减去不产生进位的三位数的个数，即可得到与168相加时会产生进位的三位数的个数.\n【详解】步骤一：计算所有三位数的个数三位数的范围是100到999，所以所有三位数的个数为999 - 100 + 1 = 900(个)。步骤二：计算与168相加不产生进位的三位数的个数设三位数为 ABC(A 为百位数字,B 为十位数字,C 为个位数字) 。个位数字 C 的取值：与 8 相加不进位，则(C + 8) < 10，即 C < 2，所以 C 可以取 0,1 共 2 种可能。十位数字 B 的取值：与 6 相加不进位，则(B + 6) < 10，即 B < 4，所以B可以取0,1,2,3共4种可能。百位数字A的取值：与1相加不进位，则(A + 1) < 10，又因为 A 是三位数的百位数字，所以( A > 0 ),即 A 可以取 1,2,3,4,5,6,7,8 共 8 种可能。根据排列组合的乘法原理，与168相加不产生进位的三位数的个数为:8×4×2 = 64(个)。步骤三：计算与168相加时会产生进位的三位数的个数用所有三位数的个数减去与168相加不产生进位的三位数的个数，可得与168相加时会产生进位的三位数的个数为900 - 64  =  836个。综上，与 168 相加时会产生进位的三位数有 836 个。",
+    "knowledge_points": [
+      "两，三位数的连续进位加法"
+    ],
+    "source": "2025四年级·福建泉州·竞赛"
+  },
+  {
+    "id": "25",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "小明的储蓄罐里有28元，他买了一个15元的文具盒，又存了12元，现在储蓄罐里有( )元。",
+    "options": [],
+    "answer": "25",
+    "solution": "【分析】由题意得，小明的储蓄罐里有28元，他买了一个15元的文具盒，可以先用28减去15算出小明还剩多少元。他又存了12元，直接用前面的得数加上12即可算出现在储蓄罐里有多少元.\n【详解】28 - 15 + 12 = 13 + 12 = 25(元),故现在储蓄罐里有 25 元。",
+    "knowledge_points": [
+      "100以内数的加减混合运算"
+    ],
+    "source": "24-25 三年级下·黑龙江佳木斯·期末"
+  },
+  {
+    "id": "26",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "在括号里填上合适的数.\n46 + ( ) = 59;25 + 37 = ( );91 - 29 = ( )\n56 + 7 = ( );12 - ( ) = 5;( ) + 40 = 76\n72 + (13 - 7) = ( );( ) - 70 = 5;86 - 20 = ( );20 + (17 - 8) = ( )",
+    "options": [],
+    "answer": "13;62;62;63;7;36;78;75;66;29",
+    "solution": "【分析】根据一个加数 = 和 - 另一个加数，加数 + 加数 = 和，被减数 - 减数 = 差，减数 = 被减数 - 差，被减数 = 减数 + 差，即可解答;在有括号的算式里，要先算括号里面的，再算括号外面的.\n【详解】59 - 46 = 13，故 46 + 13 = 59;25 + 37 = 62;91 - 29 = 62;56 + 7 = 63;12 - 5 = 7，故 12 - 7 = 5;76 - 40 = 36，故 36 + 40 = 76;13 - 7 = 6,72 + 6 = 78，故 72 + (13 - 7) = 78;70 + 5 = 75，故 75 - 70 = 5;86 - 20 = 66;17 - 8 = 9,20 + 9 = 29，故 20 + (17 - 8) = 29。",
+    "knowledge_points": [
+      "两位数与整十数的减法",
+      "两位数与两位数的退位减法",
+      "十几减 5~2 的退位减法",
+      "两位数与两位数的进位加法"
+    ],
+    "source": "24-25 一年级下·湖南株洲·期末"
+  },
+  {
+    "id": "27",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "王奶奶家养了 35 只母鸡，比公鸡少 16 只，王奶奶家一共养了( )只鸡。",
+    "options": [],
+    "answer": "86",
+    "solution": "【分析】由题意可知，母鸡比公鸡少，也就是公鸡比母鸡多，用母鸡的数量加上母鸡比公鸡少的数量，求出和，就是公鸡的数，再加上母鸡的数量，就是一共养了的鸡数量.\n【详解】35 + 16 + 35 = 51 + 35 = 86(只),即，王奶奶家养了 35 只母鸡，比公鸡少 16 只，王奶奶家一共养了 86 只鸡。",
+    "knowledge_points": [
+      "100以内数的连加运算"
+    ],
+    "source": "23-24二年级上·新疆乌鲁木齐·期末"
+  },
+  {
+    "id": "28",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "如果 36 + 4□ 的和的十位上是 7，那么□里一共有( )种填法。",
+    "options": [],
+    "answer": "4",
+    "solution": "【分析】和的十位上是 7，说明个位上的数相加不满十，找出与 6 相加，小于 10 的数，即可解答.\n【详解】6 + 0 = 6,6 + 1 = 7,6 + 2 = 8,6 + 3 = 9，所以 □ 里面能填的数有0,1,2,3，一共有4种填法。",
+    "knowledge_points": [
+      "两位数与两位数的不进位加法"
+    ],
+    "source": "24-25 二年级下·贵州铜仁·期末"
+  },
+  {
+    "id": "29",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "一班同学捡了24节废旧电池，二班比一班多捡了 8 节，二班捡了( )节废旧电池，两个班一共捡了( )节废旧电池。",
+    "options": [],
+    "answer": "32;56",
+    "solution": "【分析】因为二班比一班多捡了8节，根据加法的意义，用24 + 8 即可得出二班捡了多少节废电池。再将两个班捡的废电池数量相加，据此即可得出两个班一共捡了多少节废电池.\n【详解】24 + 8 = 32(节),所以二班捡了 32 节废电池。24 + 32 = 56 (节),所以两个班一共捡了 56 节废电池。",
+    "knowledge_points": [
+      "两位数与两位数的不进位加法",
+      "一位数与两位数的进位加法"
+    ],
+    "source": "23-24二年级下·湖南常德·期中"
+  },
+  {
+    "id": "30",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "( )比36多54,81 比 27 多( )。",
+    "options": [],
+    "answer": "90;54",
+    "solution": "【分析】求比一个数多几的数是多少，用这个数 + 多的数计算;求一个数比另一个数多几，用这个数 - 另一个数计算.\n【详解】36 + 54 = 90,81 - 27 = 54,90 比 36 多 54,81 比 27 多 54。",
+    "knowledge_points": [
+      "两位数与两位数的退位减法",
+      "两位数与两位数的进位加法"
+    ],
+    "source": "23-24二年级下·云南曲靖·期末"
+  },
+  {
+    "id": "31",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "从 56 里减去 40，再加上 18，结果是( )。",
+    "options": [],
+    "answer": "34",
+    "solution": "【分析】根据题意，先计算出56减去40的差，再用这个差和18相加，求出和即可.\n【详解】56 - 40 + 18 = 16 + 18 = 34，从 56 里减去 40，再加上 18，结果是 34。",
+    "knowledge_points": [
+      "100以内数的加减混合运算"
+    ],
+    "source": "24-25 二年级下·湖南湘潭·期中"
+  },
+  {
+    "id": "32",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "希望小学有24名女教师，男教师比女教师少 6 名，希望小学一共有( )名教师。",
+    "options": [],
+    "answer": "42",
+    "solution": "【分析】根据题意，先用女教师的人数减去男教师比女教师少的人数，计算出男教师的人数，再和女教师的人数相加，就是教师的总人数.\n【详解】24 - 6 + 24 = 42(名),希望小学有24名女教师，男教师比女教师少6名，希望小学一共有 42 名教师。",
+    "knowledge_points": [
+      "100以内数的加减混合运算"
+    ],
+    "source": "24-25二年级下·福建龙岩·期中"
+  },
+  {
+    "id": "33",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "两位老师带领学生参观海洋公园，男生有38人，女生有49人，老师和学生一共要买( )张门票。",
+    "options": [],
+    "answer": "89",
+    "solution": "【分析】用男生的人数加上女生的人数再加上两位老师，即可求出一共需要买的门票数量.\n【详解】38 + 49 + 2 = 89(张),两位老师带领学生参观海洋公园，男生有38人，女生有49人，老师和学生一共要买89张门票。",
+    "knowledge_points": [
+      "100 以内数的连加运算"
+    ],
+    "source": "24-25 二年级上·湖北荆州·期末"
+  },
+  {
+    "id": "34",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "笔算 37 + 25 时，个位上( )加( )得( ),向( )位进 1，个位写( )。",
+    "options": [],
+    "answer": "7;5;12;十;2",
+    "solution": "【分析】两位数与两位数的加法计算时，相同数位对齐，从个位算起，若个位相加满十，则向十位进 1，由此解答.\n【详解】笔算 37 + 25 时，个位上 7 加 5 得 12，向十位进 1，个位写 2。",
+    "knowledge_points": [
+      "两位数与两位数的进位加法"
+    ],
+    "source": "24-25二年级上·贵州黔南·期末"
+  },
+  {
+    "id": "35",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "算式\"54 - □\"是一道退位减法题，那么 □ 里最小可以填( )。",
+    "options": [],
+    "answer": "5",
+    "solution": "【分析】根据题意可知：两位数与一位数的减法计算时，一位数要与两位数的个位对齐，从个位算起，若个位不够减，则从十位退1作十进行计算。要想算式为退位减法，也就是被减数的个位要比减数的个位小，即 4 < □ ,则 □ 最小是比 4 大 1 的数，由此解答.\n【详解】 4 + 1 = 5，则算式\"54 - □\"是一道退位减法题，那么 □ 里最小可以填5。",
+    "knowledge_points": [
+      "一位数与两位数的退位减法"
+    ],
+    "source": "24-25二年级上·福建福州·期末"
+  },
+  {
+    "id": "36",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "比 38 多 12 的数是( );比 54 少 27 的数是( )。",
+    "options": [],
+    "answer": "50;27",
+    "solution": "【分析】求比一个数多几的数，用加法计算。求比一个数少几的数，用减法计算.\n【详解】 38 + 12 = 50,54 - 27 = 27，则比 38 多 12 的数是 50;比 54 少 27 的数是 27。",
+    "knowledge_points": [
+      "两位数与两位数的退位减法",
+      "两位数与两位数的进位加法"
+    ],
+    "source": "24-25 二年级上·河南三门峡·期末"
+  },
+  {
+    "id": "37",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "( )比 71 少29,83 比( )多 24。",
+    "options": [],
+    "answer": "42;59",
+    "solution": "【分析】求比一个数少几的数是多少，用这个数 - 少的数计算;已知一个数比另一个数多几，求另一个数，用这个数 - 多的数计算.\n【详解】71 - 29 = 42,83 - 24 = 59,42 比 71 少 29,83 比 59 多 24。",
+    "knowledge_points": [
+      "两位数与两位数的退位减法"
+    ],
+    "source": "24-25 二年级上·湖北黄冈·期末"
+  },
+  {
+    "id": "38",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "奶奶带了100元钱，买了一瓶油29元，一袋米51元，一共用去( )元，还剩下( )元。",
+    "options": [],
+    "answer": "80;20",
+    "solution": "【分析】用一瓶油的价钱加一袋米的价钱即可求出一共用去多少钱，用奶奶带的钱数减去一共用的钱数即可求出还剩下多少元.\n【详解】29 + 51 = 80(元),100 - 80 = 20 (元),一共用去80元，还剩下20元。",
+    "knowledge_points": [
+      "整十数之间的加减法",
+      "两位数与两位数的进位加法"
+    ],
+    "source": "24-25二年级上·安徽黄山·期末"
+  },
+  {
+    "id": "39",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "比 68 多 12 的数是( ),( )比 35 少 15。",
+    "options": [],
+    "answer": "80;20",
+    "solution": "【分析】要求比68多12的数是多少，根据加法的意义，用 68 + 12 进行解答即可;要求比 35 少 15 的数是多少，根据减法的意义，用 35 - 15 进行解答即可.\n【详解】68 + 12 = 80，所以比 68 多 12 的数是 80;35 - 15 = 20，所以 20 比 35 少 15。",
+    "knowledge_points": [
+      "两位数与两位数的不退位减法",
+      "两位数与两位数的进位加法"
+    ],
+    "source": "24-25 二年级上·云南保山·期末"
+  },
+  {
+    "id": "40",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "比 58 多 15 的数是( ),( )比 60 少 33。",
+    "options": [],
+    "answer": "73;27",
+    "solution": "【分析】求比一个数多几的数，用加法计算。求比一个数少几的数，用减法计算.\n【详解】58 + 15 = 73,60 - 33 = 27，则比58多15的数是73,27比60少33。",
+    "knowledge_points": [
+      "两位数与两位数的退位减法",
+      "两位数与两位数的进位加法"
+    ],
+    "source": "24-25 二年级上·河南信阳·期末"
+  },
+  {
+    "id": "41",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "两位老师，带领学生参观博物馆，其中有男学生 28 人，女学生 22 人，要买( )张票。",
+    "options": [],
+    "answer": "52",
+    "solution": "【分析】教师的数量加上男学生的数量，再加上女学生的数量，等于一共多少个人去参观博物馆，就是购买门票的数量，据此解答.\n【详解】2 + 28 + 22 = 52(张),所以，需要买52张票。",
+    "knowledge_points": [
+      "100以内数的连加运算"
+    ],
+    "source": "24-25二年级上·四川乐山·期末"
+  },
+  {
+    "id": "42",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "比 36 大 18 的数是( );36 比 51 少( )。",
+    "options": [],
+    "answer": "54;15",
+    "solution": "【分析】求比一个数大多少的数用加法计算。求一个数比另一个数少多少，用减法计算.\n【详解】36 + 18 = 54,51 - 36 = 15，比 36 大 18 的数是 54;36 比 51 少 15。",
+    "knowledge_points": [
+      "两位数与两位数的退位减法",
+      "两位数与两位数的进位加法"
+    ],
+    "source": "24-25 二年级上·河南南阳·期末"
+  },
+  {
+    "id": "43",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "比 46 多 35 的数是( ),34 比( )多 19。",
+    "options": [],
+    "answer": "81;15",
+    "solution": "【分析】求比一个数多几的数是多少，用这个数 + 多的数计算;已知一个数比另一个数多几，求另一个数，用这个数 - 多的数计算.\n【详解】46 + 35 = 81;34 - 19 = 15，比 46 多 35 的数是 81,34 比 15 多 19。",
+    "knowledge_points": [
+      "两位数与两位数的退位减法",
+      "两位数与两位数的进位加法"
+    ],
+    "source": "24-25 二年级上·贵州黔南·期末"
+  },
+  {
+    "id": "44",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "比 60 少 12 的数是( )。一个加数是 54，另一个加数是 18，和是( )。",
+    "options": [],
+    "answer": "48;72",
+    "solution": "【分析】求比一个数少几的数用减法计算。根据加数 + 加数 = 和，列式计算.\n【详解】 60 - 12 = 48;54 + 18 = 72 则比 60 少 12 的数是 48。一个加数是 54，另一个加数是18，和是 72。",
+    "knowledge_points": [
+      "两位数与两位数的退位减法",
+      "两位数与两位数的进位加法"
+    ],
+    "source": "24-25 二年级上·湖北武汉·期末"
+  },
+  {
+    "id": "45",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "一个数加上 24，再减去 18，结果比原数大。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】根据题意，一个数先加24，再减18，相当于这个数增加了 24 - 18 = 6。无论原数是多少，增加6后的结果一定比原数大.\n【详解】由分析知:24 - 18 = 6，一个数加上 24，再减去 18，结果比原数大。故答案为:√",
+    "knowledge_points": [
+      "两位数与两位数的退位减法"
+    ],
+    "source": "25-26 三年级上·甘肃·阶段练习"
+  },
+  {
+    "id": "46",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "判断题",
+    "difficulty": 0.65,
+    "question": "一个数减去35，再加上 28，结果比原数小。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】一个数先减去 35，会让原来的数变小，再加上28，会让数变大一点，可以通过比较\"减去的\"和\"加上的\"哪个更多，从而判断最终结果是变大还是变小.\n【详解】 35 > 28，且 35 - 28 = 7，\"减去 35\"比\"加上 28\"多减了7，所以最后结果一定比原数小。原题说法正确。故答案为:√",
+    "knowledge_points": [
+      "100 以内数的加减混合运算"
+    ],
+    "source": "25-26 三年级上·甘肃天水·阶段练习"
+  },
+  {
+    "id": "47",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "判断题",
+    "difficulty": 0.65,
+    "question": "36 - 27 + 3 = 36 - 30 = 6 。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】根据加减混合运算的顺序，应从左往右依次计算，先计算减法，再算加法。原题改变了运算顺序，导致结果错误。以此判断即可.\n【详解】根据分析可知:36 - 27 + 3 = 9 + 3 = 12，原题计算错误。故答案为: ×",
+    "knowledge_points": [
+      "100以内数的加减混合运算"
+    ],
+    "source": "25-26 三年级上·全国·单元测试"
+  },
+  {
+    "id": "48",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "算式 64 - 15 + 27 与64 - (15 + 27)的计算结果相同。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】只有加减法的四则运算，按照从左到右的顺序计算，有括号的，要先算括号里面的，再算括号外面的。64 - 15 + 27 按照从左到右的顺序计算;64 - (15 + 27)先算括号里面的加法，再算括号外面的减法，分别计算出结果，即可知结果是否相同，据此解答.\n【详解】64 - 15 + 27 = 49 + 27 = 76,64 - (15 + 27) = 64 - 42 = 22,76 > 22，算式 64 - 15 + 27 与 64 - (15 + 27)的计算结果不相同，原题说法错误。故答案为: ×",
+    "knowledge_points": [
+      "带有小括号的混合运算",
+      "100以内数的加减混合运算"
+    ],
+    "source": "24-25 二年级下·陕西延安·期中"
+  },
+  {
+    "id": "49",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "判断题",
+    "difficulty": 0.65,
+    "question": "68-(35-23)与 68 - 35 + 23的运算顺序不同，但结果相同。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】只有加减法的混合运算，从左往右计算，若有括号，则先算括号里面的，再算括号外面的，由此计算出结果即可解答.\n【详解】68 - (35 - 23)先算括号里的减法，再算括号外的减法;68 - 35 + 23 从左往右计算。68 - (35 - 23)= 68 - 12 = 56,68 - 35 + 23 = 33 + 23 =56，即 68 - (35 - 23)与 68 - 35 + 23 的运算顺序不同，但结果相同，原题说法正确。故答案为:√",
+    "knowledge_points": [
+      "有括号的运算顺序",
+      "带有小括号的混合运算",
+      "100 以内数的加减混合运算",
+      "无括号的运算顺序"
+    ],
+    "source": "24-25 二年级上·贵州黔南·期末"
+  },
+  {
+    "id": "50",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "计算题",
+    "difficulty": 0.65,
+    "question": "看图列式并计算.\n\n![](images/9a84af66ed5fa73ee38e62afa8e41a0c41ba75559e492cad5d714645f945ec1d.jpg)",
+    "options": [],
+    "answer": "38 朵",
+    "solution": "【分析】由红花有20朵，蓝花比红花多8朵，先求出蓝花朵数，再根据黄花比蓝花多10朵，再加10朵即为黄花朵数，据此解答.\n【详解】20 + 8 + 10 = 38(朵),黄花 38 朵。",
+    "knowledge_points": [
+      "图文问题",
+      "两，三位数的连加运算"
+    ],
+    "source": "25-26三年级上·陕西延安·阶段练习"
+  },
+  {
+    "id": "51",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "计算题",
+    "difficulty": 0.85,
+    "question": "根据线段图列式计算.\n\n![](images/934f813d2698284ab58910344a78ea2993b5dc8958926eac7a83a39750b0f701.jpg)",
+    "options": [],
+    "answer": "55 人",
+    "solution": "【分析】用23加上9，求出女生的人数，再用女生的人数加上男生的人数，求出一共的人数.\n【详解】23 + 9 + 23 = 32 + 23 = 55(人),所以一共有 55 人。",
+    "knowledge_points": [
+      "图文问题",
+      "100 以内数的连加运算"
+    ],
+    "source": "24-25 三年级下·福建莆田·期中"
+  },
+  {
+    "id": "52",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "计算题",
+    "difficulty": 0.65,
+    "question": "41与25的和减去18，差是多少。",
+    "options": [],
+    "answer": "48",
+    "solution": "【分析】先求 41 与 25 的和，再用所得的和减去 18，据此解答.\n【详解】41 + 25 - 18 = 66 - 18 = 48,41与25的和减去18，差是 48。",
+    "knowledge_points": [
+      "100以内数的加减混合运算"
+    ],
+    "source": "22-23二年级下·新疆乌鲁木齐·期中"
+  },
+  {
+    "id": "53",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "计算题",
+    "difficulty": 0.65,
+    "question": "计算下列各题.\n83 - 3 + 7;40 + 22 - 5;97 - (8 + 7)\n91 - 40 - 40;51 +(92 - 80);78 + 9 - 50",
+    "options": [],
+    "answer": "87;57;82;11;63;37",
+    "solution": "【分析】混合运算的运算顺序：如果只有加减法或只有乘除法，按照从左到右的顺序计算;如果既有加减法又有乘除法，要先算乘除法，再算加减法;如果有括号，要先算括号里面的，再算括号外面的。97 - (8 + 7)先算括号里面的加法，再算括号外面的减法;51 + (92 - 80)先算括号里面的减法，再算括号外面的加法;其它题都按照从左往右的顺序计算即可.\n【详解】83 - 3 + 7 = 80 + 7 = 87;40 + 22 - 5 = 62 - 5 = 57;97 - (8 + 7) = 97 - 15 = 82;91 - 40 - 40 = 51 - 40 = 11;51 + (92 - 80) = 51 + 12 = 63;78 + 9 - 50 = 87 - 50 = 37",
+    "knowledge_points": [
+      "100以内数的连减运算",
+      "带有小括号的混合运算",
+      "100 以内数的加减混合运算"
+    ],
+    "source": "24-25 一年级下·广东广州·期末"
+  },
+  {
+    "id": "54",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "计算题",
+    "difficulty": 0.65,
+    "question": "63 减去 42 与 8 的和，差是多少。",
+    "options": [],
+    "answer": "13",
+    "solution": "【分析】根据题意，先计算出 42 与 8 的和，列式计算 42 + 8 = 50 ,63再减去50，列式计算 63 - 50 = 13。列综合算式时，因为要先算 42 + 8，所以要把 42 + 8 带上小括号，即63 -(42 + 8).\n【详解】63 -(42 + 8)= 63 - 50 = 13",
+    "knowledge_points": [
+      "带有小括号的混合运算"
+    ],
+    "source": "24-25 一年级上·江西吉安·期末"
+  },
+  {
+    "id": "55",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "计算题",
+    "difficulty": 0.85,
+    "question": "竖式计算.\n19 + 27 + 45 =( );98 - 49 - 37 =( );100 - 56 + 35 =( )",
+    "options": [],
+    "answer": "91;12;79",
+    "solution": "【分析】加法：相同数位对齐，计算从个位算起，若和超过10，则向前进1。减法：相同数位对齐，计算从个位算起，若不够减，则向前一位借 1 当 10。根据整数混合运算可知：同级运算，按照从左往右的顺序依次计算即可.\n【详解】19 + 27 + 45 = 91;98 - 49 - 37 = 12;100 - 56 + 35 = 79\n![](images/2026-02-06%20214714.jpg)",
+    "knowledge_points": [
+      "100 以内数的连减运算",
+      "100 以内数的加减混合运算",
+      "100 以内数的连加运算"
+    ],
+    "source": "24-25 二年级下·广东梅州·开学考试"
+  },
+  {
+    "id": "56",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "计算题",
+    "difficulty": 0.65,
+    "question": "用竖式计算.\n47 + 25 =( );61 - 18 =( );75 - 46 + 31 =( )",
+    "options": [],
+    "answer": "72;43;60",
+    "solution": "【分析】本题根据竖式计算的法则来解答即可。加法：相同数位对齐，从个位算起，哪一位相加满十，向前一位进 1。减法：相同数位对齐，从个位算起，哪一位不够减，从前一位退 1 作十计算。第 1,2 题直接计算;第 3 题从左往右计算.\n【详解】47 + 25 = 72;61 - 18 = 43;75 - 46 + 31 = 60\n![](images/2026-02-06%20215002.jpg)",
+    "knowledge_points": [
+      "100以内数的加减混合运算",
+      "两位数与两位数的退位减法",
+      "两位数与两位数的进位加法"
+    ],
+    "source": "24-25 二年级上·湖北荆州·期末"
+  },
+  {
+    "id": "57",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "计算题",
+    "difficulty": 0.65,
+    "question": "列竖式计算.\n51 - 36 =( );29 + 43 =( );90 - 27 =( )\n56 + 26 - 28 =( );27 + 35 + 34 =( );63 - (15 + 43) =( )",
+    "options": [],
+    "answer": "15;72;63;54;96;5",
+    "solution": "【分析】本题根据竖式计算的法则来解答即可。加法：相同数位对齐，从个位算起，哪一位相加满十，向前一位进 1。减法：相同数位对齐，从个位算起，哪一位不够减，从前一位退1作十计算。第一行：直接计算;第二行：第1,2题从左往右计算;第3题先算加法，再算减法.\n【详解】51 - 36 = 15;29 + 43 = 72;90 - 27 = 63\n![](images/2026-02-06%20215337.jpg)\n56 + 26 - 28 = 54;27 + 35 + 34 = 96;63 - (15 + 43) = 5\n![](images/2026-02-06%20215431.jpg)",
+    "knowledge_points": [
+      "带有小括号的混合运算",
+      "100以内数的加减混合运算",
+      "两位数与两位数的退位减法",
+      "两位数与两位数的进位加法"
+    ],
+    "source": "24-25 二年级上·浙江台州·期末"
+  },
+  {
+    "id": "58",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "计算题",
+    "difficulty": 0.65,
+    "question": "竖式计算.\n①72 - 22 =( ) ②36 + 64 =( ) ③87 - 39 =( )\n④78 - 6 - 57 =( ) ⑤89 - (49 + 20) =( ) ⑥51 + 25 + 18 =( )",
+    "options": [],
+    "answer": "50;100;48;15;20;94",
+    "solution": "【分析】加法竖式计算时，相同数位对齐，从个位加起，哪一位相加满十就向前一位进1。减法竖式计算时，相同数位对齐，从个位减起，哪一位不够减就向前一位借1当十，和本位上的数合并在一起，再减。整数混合运算中，同级运算时，从左到右依次计算;有括号时，先算括号里面的，再算括号外面的.\n【详解】①72 - 22 = 50,②36 + 64 = 100,③87 - 39 = 48\n![](images/2026-02-06%20220101.jpg)\n④78 - 6 - 57 = 15,⑤89 - (49 + 20) = 20,⑥51 + 25 + 18 = 94\n![](images/2026-02-06%20220123.jpg)",
+    "knowledge_points": [
+      "100以内数的连减运算",
+      "带有小括号的混合运算",
+      "两位数与两位数的退位减法",
+      "两位数与两位数的进位加法"
+    ],
+    "source": "24-25 二年级上·福建龙岩·期末"
+  },
+  {
+    "id": "59",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "计算题",
+    "difficulty": 0.85,
+    "question": "列竖式计算.\n83 - 54 =( );37 + 43 =( );61 - 37 + 29 =( );100 - (35 + 17) =( )",
+    "options": [],
+    "answer": "29;80;53;48",
+    "solution": "【分析】加法竖式计算时，相同数位对齐，从个位加起，哪一位相加满十就向前一位进 1。减法竖式计算时，相同数位对齐，从个位减起，哪一位不够减就向前一位借1当十，和本位上的数合并在一起，再减。整数混合运算中，同级运算时，从左到右依次计算;有括号时，先算括号里面的，再算括号外面的.\n【详解】83 - 54 = 29;37 + 43 = 80\n![](images/2026-02-06%20221509.jpg)\n61 - 37 + 29 = 53;100 - (35 + 17) = 48\n![](images/2026-02-06%20221523.jpg)",
+    "knowledge_points": [
+      "100以内数的加减混合运算",
+      "两位数与两位数的退位减法",
+      "两位数与两位数的进位加法"
+    ],
+    "source": "24-25 二年级上·福建龙岩·期末"
+  },
+  {
+    "id": "60",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "计算题",
+    "difficulty": 0.85,
+    "question": "竖式计算.\n26 + 35 + 14 =( );70 - 27 - 16 =( );95 - 56 + 34 =( )\n23 + (30 - 18) =( );68 - (81 - 69) =( );80 - (43 + 19) =( )",
+    "options": [],
+    "answer": "75;27;73;35;56;18",
+    "solution": "【分析】加法竖式计算时，相同数位对齐，从个位加起，哪一位相加满十就向前一位进 1。减法竖式计算时，相同数位对齐，从个位减起，哪一位不够减就向前一位借1当十，和本位上的数合并在一起，再减。整数混合运算中，同级运算时，从左到右依次计算;有括号时，先算括号里面的，再算括号外面的.\n【详解】26 + 35 + 14 = 75;70 - 27 - 16 = 27;95 - 56 + 34 = 73\n![](images/2026-02-06%20222217.jpg)\n23 + (30 - 18) = 35;68 - (81 - 69) = 56;80 - (43 + 19) = 18\n![](images/2026-02-06%20222241.jpg)",
+    "knowledge_points": [
+      "100以内数的连减运算",
+      "带有小括号的混合运算",
+      "100以内数的加减混合运算",
+      "100以内数的连加运算"
+    ],
+    "source": "24-25 二年级上·山东菏泽·期末"
+  },
+  {
+    "id": "61",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.65,
+    "question": "全运会特许商品店有\"喜洋洋\"毛绒玩具34个，\"乐融融\"比\"喜洋洋\"少6个.\"乐融融\"有多少个。\"喜洋洋\"和\"乐融融\"一共有多少个。",
+    "options": [],
+    "answer": "28 个;62 个",
+    "solution": "【分析】由题意得，\"喜洋洋\"毛绒玩具 34 个，\"乐融融\"比\"喜洋洋\"少6个，直接用34减去6可以算出\"乐融融\"有多少个。然后再加上 34 个即可算出\"喜洋洋\"和\"乐融融\"一共有多少个.\n【详解】34 - 6 = 28(个),28 + 34 = 62(个),答：\"乐融融\"有 28 个，\"喜洋洋\"和\"乐融融\"一共有 62 个。",
+    "knowledge_points": [
+      "一位数与两位数的退位减法",
+      "两位数与两位数的进位加法"
+    ],
+    "source": "25-26 三年级上·广东广州·月考"
+  },
+  {
+    "id": "62",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.94,
+    "question": "张爷爷收了 90 个西瓜，第一车运走了26个，第二车运走了28个，还剩多少个西瓜。",
+    "options": [],
+    "answer": "36 个",
+    "solution": "【分析】根据题意可知：用张爷爷收的数量连续减去第一车运走的数量和第二车运走的数量即可.\n【详解】90 - 26 - 28 = 64 - 28 = 36(个),答：还剩36个西瓜。",
+    "knowledge_points": [
+      "100 以内数的连减运算"
+    ],
+    "source": "25-26 二年级上·全国·课后作业"
+  },
+  {
+    "id": "63",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.85,
+    "question": "一捆绳子长 100 米，先用去 30 米，又用去 28 米。这捆绳子还剩下多少米。",
+    "options": [],
+    "answer": "42 米",
+    "solution": "【分析】用绳子总长度减去第一次用去的，再减去第二次用去的，即可求出剩下的长度.\n【详解】100 - 30 - 28 = 70 - 28 = 42(米),答：这捆绳子还剩下42米。",
+    "knowledge_points": [
+      "100以内数的连减运算"
+    ],
+    "source": "25-26 三年级上·贵州黔西·阶段练习"
+  },
+  {
+    "id": "64",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.65,
+    "question": "木雕是我国的非遗传统手工艺术品。张叔叔做了 92 个木雕，第一周卖出36 个，第二周卖出 45 个，还剩多少个木雕没有卖出。",
+    "options": [],
+    "answer": "11 个",
+    "solution": "【分析】用木雕的总数量减去第一周卖出的，再减去第二周卖出的求出剩下的数量.\n【详解】92 - 36 - 45 = 56 - 45 = 11(个),答：还剩11个木雕没有卖出。",
+    "knowledge_points": [
+      "100以内数的连减运算"
+    ],
+    "source": "25-26三年级上·陕西延安·阶段练习"
+  },
+  {
+    "id": "65",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.85,
+    "question": "校园运动会开始啦!在1分钟踢毽子比赛中，同同踢了64下，比梦梦多踢了28下.\n(1)梦梦踢了多少下。 \n(2)两人一共踢了多少下。",
+    "options": [],
+    "answer": "36 下;100 下",
+    "solution": "【分析】(1)根据题意可知，用同同踢的毽子个数减去 28即可求出梦梦踢的毽子个数;(2)将同同和梦梦踢的毽子个数相加即可.\n【详解】(1)64 - 28 = 36(下),答：梦梦踢了 36 下。(2)64 + 36 = 100(下),答：两人一共踢了100下。",
+    "knowledge_points": [
+      "两位数与两位数的退位减法",
+      "两位数与两位数的进位加法"
+    ],
+    "source": "24-25三年级上·陕西渭南·期中"
+  },
+  {
+    "id": "66",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.65,
+    "question": "停车场原来有汽车54辆，开走25辆，又开来32辆，现在停车场有多少辆汽车。",
+    "options": [],
+    "answer": "61 辆",
+    "solution": "【分析】根据题干，停车场原来有汽车54辆，开走25辆，那就是用原来的辆数减去开走的辆数，即:54 - 25;又开来 32 辆，也就是再加 32 辆，依次计算即可.\n【详解】54 - 25 + 32 = 61(辆),答：现在停车场有61辆汽车。",
+    "knowledge_points": [
+      "100以内数的加减混合运算"
+    ],
+    "source": "24-25 二年级上·新疆克孜勒苏·期中"
+  },
+  {
+    "id": "67",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.85,
+    "question": "小敏今年 11 岁，她爷爷今年 65 岁，再过 8 年，小敏和她爷爷共有多少岁。",
+    "options": [],
+    "answer": "92 岁",
+    "solution": "【分析】再过8年，小敏年龄增加8年，爷爷的年龄也增加8年，因此再过8年，小敏和她爷爷的年龄和是今年小敏的年龄加爷爷的年龄再加两个 8 年.\n【详解】由分析可得:11 + 8 + 65 + 8 = 19 + 65 + 8 = 84 + 8 = 92(岁),答：小敏和她爷爷共有92岁。",
+    "knowledge_points": [
+      "100以内数的连加运算",
+      "年龄问题"
+    ],
+    "source": "25-26 三年级上·湖南永州·阶段练习"
+  },
+  {
+    "id": "68",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.65,
+    "question": "一场篮球赛分为上半场和下半场，两个班下半场得分同样多。上半场二(2)班得了多少分。\n<table><tr><td>班级</td><td>总分</td><td>上半场</td><td>下半场</td></tr><tr><td>二(1)班</td><td>46分</td><td>25分</td><td>同样多</td></tr><tr><td>二(2)班</td><td>40分</td><td>。分</td><td>同样多</td></tr></table>",
+    "options": [],
+    "answer": "19 分",
+    "solution": "【分析】根据表格分析，二(1)班和二(2)班的总分是由上半场的分和下半场的分相加得到，用二(1)班的总分减去二(1)班上半场的分，得到二(1)班下半场的分，二(2)班下半场的分与二(1)班下半场的分相同，即用二(2)班总分减去下半场的分，即可得到二(2)班上半场的分.\n【详解】46 - 25 = 21(分),40 - 21 = 19(分),答：上半场二(2)班得了19分。",
+    "knowledge_points": [
+      "两位数与两位数的退位减法",
+      "两位数与两位数的不退位减法"
+    ],
+    "source": "24-25 二年级下·福建莆田·期中"
+  },
+  {
+    "id": "69",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.85,
+    "question": "刘老师要批改82篇作文，第一天批改了32篇，第二天批改的比第一天多3篇，还有多少篇没有批改。",
+    "options": [],
+    "answer": "15篇",
+    "solution": "【分析】根据题意，第二天批改的比第一天多3篇，先用第一天批改的篇数加上3，求出第二天批改了多少篇，用要批改的总篇数减去第一天和第二天批改的篇数之和，即可求出还有多少篇没有批改。据此即可解答.\n【详解】82 - (32 + 32 + 3) = 82 - 67 = 15(篇),答：还有 15 篇没有批改。",
+    "knowledge_points": [
+      "100以内数的连减运算",
+      "两位数与两位数的退位减法"
+    ],
+    "source": "24-25四年级下·天津河北·期末"
+  },
+  {
+    "id": "70",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.65,
+    "question": "便民小吃店做了91个饼，上午卖出了 46 个，下午卖出了 39 个，还剩多少个饼。",
+    "options": [],
+    "answer": "6 个",
+    "solution": "【分析】用便民小吃店做饼的总个数减去上午卖出的个数，再减去下午卖出的个数，即可求出还剩多少个饼.\n【详解】91 - 46 - 39 = 45 - 39 = 6(个),答：还剩6个饼。",
+    "knowledge_points": [
+      "100 以内数的连减运算"
+    ],
+    "source": "24-25二年级下·云南红河·期末"
+  },
+  {
+    "id": "71",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.65,
+    "question": "王叔叔和李叔叔都是外卖骑手。李叔叔上午接了16单，下午李叔叔接的单和王叔叔一样多，下面是他们今天一天的接单量。问：王叔叔上午接了多少单。\n<table><tr><td>王叔叔</td><td>李叔叔</td></tr><tr><td>42单</td><td>48单</td></tr></table>",
+    "options": [],
+    "answer": "10 单",
+    "solution": "【分析】先用李叔叔一天的接单量减去李叔叔上午的接单量，算出李叔叔下午的接单量，同时也是王叔叔下午的接单量;再用王叔叔一天的接单量减去王叔叔下午的接单量，即可求出王叔叔上午接了多少单.\n【详解】48 - 16 = 32(单),42 - 32 = 10(单),答：王叔叔上午接了10单。",
+    "knowledge_points": [
+      "两位数与两位数的不退位减法"
+    ],
+    "source": "24-25 二年级下·云南红河·期末"
+  },
+  {
+    "id": "72",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.65,
+    "question": "垃圾分类：三(1)班收集了 35 千克可回收垃圾，三(2)班收集的垃圾比三(1)班少 8 千克。两个班一共收集了多少千克可回收垃圾。",
+    "options": [],
+    "answer": "62 千克",
+    "solution": "【分析】由题意得，三(1)班收集了35千克可回收垃圾，三(2)班收集的垃圾比三(1)班少 8 千克，可以先用 35减去8算出三(2)班收集了多少千克垃圾。然后再加上三(1)班收集的垃圾质量即可算出两个班一共收集了多少千克可回收垃圾.\n【详解】35 - 8 + 35 = 27 + 35 = 62(千克),答：两个班一共收集了 62 千克可回收垃圾。",
+    "knowledge_points": [
+      "100 以内数的加减混合运算"
+    ],
+    "source": "24-25 三年级下·湖北武汉·期末"
+  },
+  {
+    "id": "73",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.65,
+    "question": "一捆丝绳长100米，一班先用去20米，又用去38米。二班需要40米，剩下的丝绳够吗。",
+    "options": [],
+    "answer": "够",
+    "solution": "【分析】先用一捆丝绳的长度分别减去一班两次用去的长度，求出剩下的长度，再用剩下的长度和二班需要用的长度作比较，即可解答.\n【详解】100 - 20 - 38 = 80 - 38 = 42(米),42 > 40，答：剩下的丝绳够。",
+    "knowledge_points": [
+      "100以内数的比大小",
+      "100以内数的连减运算"
+    ],
+    "source": "23-24二年级上·新疆乌鲁木齐·期末"
+  },
+  {
+    "id": "74",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.85,
+    "question": "水果店运来 56 箱苹果，上午卖出 18 箱，下午卖出 24 箱，还剩多少箱。",
+    "options": [],
+    "answer": "14 箱",
+    "solution": "【分析】要求水果店还剩多少箱苹果，根据减法的意义，用运来的苹果数量减去上午和下午卖出的苹果数量，即可得出答案.\n【详解】56 - 18 - 24 = 38 - 24 = 14(箱),答：还剩14箱。",
+    "knowledge_points": [
+      "100 以内数的连减运算"
+    ],
+    "source": "24-25 二年级下·山东济宁·期末"
+  },
+  {
+    "id": "75",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.65,
+    "question": "工人要挖一条排水沟，上午挖了57米，比下午多挖了18米，全天一共挖了多少米排水沟。",
+    "options": [],
+    "answer": "96 米",
+    "solution": "【分析】用上午挖的长度减上午比下午多挖的长度算出下午挖的长度，然后将下午挖的长度和上午挖的长度相加即可.\n【详解】57 - 18 = 39(米),57 + 39 = 96(米),答：全天一共挖了 96 米排水沟。",
+    "knowledge_points": [
+      "两位数与两位数的退位减法",
+      "两位数与两位数的进位加法"
+    ],
+    "source": "23-24二年级下·云南曲靖·期末"
+  },
+  {
+    "id": "76",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.65,
+    "question": "一件儿童上衣 68 元，一条长裤比上衣便宜 15 元，一条裙子又比长裤贵2元。这条裙子多少元。",
+    "options": [],
+    "answer": "55 元",
+    "solution": "【分析】用上衣的价钱减去 15 元，就是长裤的价钱;再用长裤的价钱加上2元，就是裙子的价钱.\n【详解】68 - 15 + 2 = 53 + 2 = 55(元),答：这条裙子 55 元。",
+    "knowledge_points": [
+      "100以内数的加减混合运算"
+    ],
+    "source": "24-25 四年级下·海南省直辖县级单位·期中"
+  },
+  {
+    "id": "77",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.85,
+    "question": "明明今年 8 岁，妈妈今年 32 岁。明明 15 岁时，妈妈多少岁。",
+    "options": [],
+    "answer": "39 岁",
+    "solution": "【分析】根据减法的意义，用32 - 8先求出妈妈和明明的年龄差，当明明15岁时，妈妈和他的年龄差不变，用年龄差加上明明的年龄就可求出妈妈的年龄，据此列式解答即可.\n【详解】32 - 8 + 15 = 24 + 15 = 39(岁),答：妈妈39岁。",
+    "knowledge_points": [
+      "100 以内数的加减混合运算",
+      "年龄问题"
+    ],
+    "source": "24-25二年级下·贵州铜仁·期末"
+  },
+  {
+    "id": "78",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.85,
+    "question": "为了清除空气污染，沿河县某小学二年级和三年级的同学参加课外植树活动，二年级同学栽了38棵，三年级同学栽了53棵，两个年级一共栽了多少棵树。",
+    "options": [],
+    "answer": "91 棵",
+    "solution": "【分析】根据题意可知：用二年级栽的数量加上三年级栽的数量即可求出两个年级一共栽的数量.\n【详解】38 + 53 = 91(棵),答：两个年级一共栽了91棵树。",
+    "knowledge_points": [
+      "两位数与两位数的进位加法"
+    ],
+    "source": "24-25二年级下·贵州铜仁·期末"
+  },
+  {
+    "id": "79",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.65,
+    "question": "一辆公交车上有34名乘客，到站后下车18人，上车15人。现在公交车上有多少人。",
+    "options": [],
+    "answer": "31 人",
+    "solution": "【分析】用公交车上原有乘客人数减去下车的人数，再加上上车的人数，即可求出现在公交车上有多少人.\n【详解】34 - 18 + 15 = 16 + 15 = 31(人),答：现在公交车上有31人。",
+    "knowledge_points": [
+      "100以内数的加减混合运算"
+    ],
+    "source": "23-24 二年级下·内蒙古鄂尔多斯·期中"
+  },
+  {
+    "id": "80",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.65,
+    "question": "一个书包 48 元，一个文具盒比书包便宜 22 元，买这两样物品一共要多少钱。",
+    "options": [],
+    "answer": "74 元",
+    "solution": "【分析】用书包的价钱减22算出一个文具盒的价钱，然后将两样物品的价钱相加即可求解.\n【详解】48 - 22 = 26(元),48 + 26 = 74(元),答：买这两样物品一共要 74 元钱。",
+    "knowledge_points": [
+      "两位数与两位数的不退位减法",
+      "两位数与两位数的进位加法"
+    ],
+    "source": "24-25 一年级下·湖南岳阳·期中"
+  },
+  {
+    "id": "81",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.65,
+    "question": "二年级1班的明明和爸爸，妈妈一起去公园玩。成人票每张25元，儿童票每张 8 元，一共要花多少钱。",
+    "options": [],
+    "answer": "58 元",
+    "solution": "【分析】根据加法的意义，用加法求出两张成人票的钱数也就是爸爸和妈妈要花费的钱数，再加上一张儿童票的价钱也就是明明要花费的钱数，即可求出要花费的总钱数，据此解答即可.\n【详解】25 + 25 + 8 = 50 + 8 = 58(元),答：一共要花 58 元。",
+    "knowledge_points": [
+      "100 以内数的连加运算"
+    ],
+    "source": "23-24二年级下·重庆大渡口·期末"
+  },
+  {
+    "id": "82",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.85,
+    "question": "某超市原有 60 袋大米，先卖出34袋，又买进了27袋。现在超市有多少袋大米。",
+    "options": [],
+    "answer": "53 袋",
+    "solution": "【分析】用超市原有的大米袋数减去卖出的袋数，再加上买进的袋数，即可求出现在超市有多少袋大米.\n【详解】60 - 34 + 27 = 26 + 27 = 53(袋),答：现在超市有53袋大米。",
+    "knowledge_points": [
+      "100以内数的加减混合运算"
+    ],
+    "source": "24-25二年级下·福建龙岩·期中"
+  },
+  {
+    "id": "83",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.85,
+    "question": "书店一共进了80本《十万个为什么》,上周卖了25本，这周卖了38本，还剩多少本。",
+    "options": [],
+    "answer": "17 本",
+    "solution": "【分析】根据减法的意义，书店进《十万个为什么》的总数量 - 上周卖的数量 - 这周卖的数量 = 还剩的数量.\n【详解】80 - 25 - 38 = 17(本),答：还剩17本。",
+    "knowledge_points": [
+      "100以内数的连减运算"
+    ],
+    "source": "24-25二年级下·新疆喀什·期中"
+  },
+  {
+    "id": "84",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.85,
+    "question": "二(3)班王老师带了60瓶矿泉水，上午喝掉25瓶，下午喝掉了30瓶，还剩下多少瓶。",
+    "options": [],
+    "answer": "5 瓶",
+    "solution": "【分析】用王老师带的总瓶数减上午喝掉的瓶数，再减下午喝掉的瓶数即可求出还剩多少瓶.\n【详解】60 - 25 - 30 = 35 - 30 = 5 (瓶) ,答：还剩下5瓶。",
+    "knowledge_points": [
+      "100以内数的连减运算"
+    ],
+    "source": "24-25二年级下·山东济宁·期中"
+  },
+  {
+    "id": "85",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.85,
+    "question": "二(3)班有 54 人，每人参加一项体育活动。17人参加跳绳,15人参加羽毛球，其余的参加篮球。参加篮球的有多少人。",
+    "options": [],
+    "answer": "22 人",
+    "solution": "【分析】根据减法的意义，二(3)班的总人数 - 参加跳绳的人数 - 参加羽毛球的人数 = 参加篮球的人数.\n【详解】54 - 17 - 15 = 22(人),答：参加篮球的有22人。",
+    "knowledge_points": [
+      "100以内数的连减运算"
+    ],
+    "source": "24-25 二年级下·贵州铜仁·期中"
+  },
+  {
+    "id": "86",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.85,
+    "question": "商店原来有 55 千克的芒果，运来 35 千克，后来又卖出了 46 千克，还剩多少千克。",
+    "options": [],
+    "answer": "44 千克",
+    "solution": "【分析】根据题意，商店原有芒果的重量 + 运来的重量 - 卖出的重量 = 还剩的重量.\n【详解】55 + 35 - 46 = 90 - 46 = 44 (千克) ,答：还剩44千克。",
+    "knowledge_points": [
+      "100以内数的加减混合运算"
+    ],
+    "source": "24-25 二年级下·广东云浮·期中"
+  },
+  {
+    "id": "87",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.65,
+    "question": "欣欣水果店原来有85箱苹果，上午卖出16箱，下午卖出32箱。欣欣水果店还剩多少箱苹果。",
+    "options": [],
+    "answer": "37 箱",
+    "solution": "【分析】根据题意，欣欣水果店还剩苹果的箱数 = 欣欣水果店原来有苹果的箱数 - 上午卖出苹果的箱数 - 下午卖出苹果的箱数.\n【详解】85 - 16 - 32 = 37(箱),答：欣欣水果店还剩 37 箱苹果。",
+    "knowledge_points": [
+      "100 以内数的连减运算"
+    ],
+    "source": "24-25 二年级下·广东汕头·期中"
+  },
+  {
+    "id": "88",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.65,
+    "question": "班级图书角原来有60本图书，借出去 37 本，又还回来 24 本，现在图书角有多少本图书。",
+    "options": [],
+    "answer": "47 本",
+    "solution": "【分析】用原来的图书数量减去借出去的图书数量，再加上还回来的图书数量，即可求出现在的图书数量.\n【详解】60 - 37 + 24 = 23 + 24 = 47(本),答：现在图书角有47本图书。",
+    "knowledge_points": [
+      "100以内数的加减混合运算"
+    ],
+    "source": "24-25二年级下·广东东莞·期中"
+  },
+  {
+    "id": "89",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.65,
+    "question": "学校话剧社有23名男生和 15 名女生，其中 17 人参加了舞台剧表演，话剧社还剩几人。",
+    "options": [],
+    "answer": "21 人",
+    "solution": "【分析】用男生人数加女生人数算出总人数，然后减去参加了舞台剧表演的人数即可求解.\n【详解】23 + 15 - 17 = 21(人),答：话剧社还剩21人。",
+    "knowledge_points": [
+      "100 以内数的加减混合运算"
+    ],
+    "source": "24-25二年级下·浙江杭州·期中"
+  },
+  {
+    "id": "90",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.85,
+    "question": "跳绳比赛：小红第一次跳了 32 下，第二次比第一次多跳 9 下，两次一共跳了多少下。",
+    "options": [],
+    "answer": "73 下",
+    "solution": "【分析】根据题意可知，小红第一次跳的下数加上第二次比第一次多跳的下数，等于小红第二次跳的下数，第一次和第二次的下数相加，等于两次一共跳了多少下，据此解答.\n【详解】根据分析可得:32 + 9 = 41(下),32 + 41 = 73(下),答：两次一共跳了73下。",
+    "knowledge_points": [
+      "两位数与两位数的不退位加法",
+      "一位数与两位数的进位加法"
+    ],
+    "source": "24-25二年级下·湖南岳阳·期中"
+  },
+  {
+    "id": "91",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.65,
+    "question": "李老师要批改作文，第一天和第二天各批改了 25 篇，第三天和第四天共批了 40 篇。四天一共批改多少篇。",
+    "options": [],
+    "answer": "90 篇",
+    "solution": "【分析】根据题意，已知第一天和第二天各批改了 25 篇，即为第一天批改了25篇，第二天也批改了25篇，用25加上25，就是前两天共批改的篇数，再加上第三天和第四天共批了 40 篇，就是四天一共批改的篇数;列式计算即可.\n【详解】根据分析可知:25 + 25 + 40 = 50 + 40 = 90(篇),答：四天一共批改 90 篇。",
+    "knowledge_points": [
+      "100 以内数的连加运算"
+    ],
+    "source": "23-24 三年级下·安徽马鞍山·期末"
+  },
+  {
+    "id": "92",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.65,
+    "question": "水果店原有苹果 45 千克，上午老板进货买入 26 千克，下午卖出 58 千克，现在店里有多少千克苹果。",
+    "options": [],
+    "answer": "13 千克",
+    "solution": "【分析】用原有的苹果千克数加上买入的千克数减去卖出的千克数即可求出现在有多少千克苹果.\n【详解】45 + 26 - 58 = 13(千克),答：现在店里有 13 千克苹果。",
+    "knowledge_points": [
+      "100 以内数的加减混合运算"
+    ],
+    "source": "24-25 二年级上·浙江嘉兴·期末"
+  },
+  {
+    "id": "93",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.65,
+    "question": "一筐苹果连筐重32千克，卖出一半苹果后，这时连筐重17千克，这筐苹果原来重多少千克。筐重多少千克。",
+    "options": [],
+    "answer": "30 千克;2 千克",
+    "solution": "【分析】根据题意可知，一筐苹果连筐的重量减去卖出一半后连筐的重量，等于这筐苹果一半的重量，半筐苹果的重量加上半筐苹果的重量，等于这筐苹果原来的重量;一筐苹果连筐的总重量减去这筐苹果原来的重量，等于筐子的重量，据此解答.\n【详解】根据分析可得:32 - 17 = 15(千克),15 + 15 = 30(千克),32 - 30 = 2(千克),答：这筐苹果原来重 30 千克;筐重 2 千克。",
+    "knowledge_points": [
+      "两位数与整十数的减法",
+      "两位数与两位数的退位减法",
+      "两位数与两位数的进位加法"
+    ],
+    "source": "24-25二年级上·湖北黄冈·期末"
+  },
+  {
+    "id": "94",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.65,
+    "question": "二(1)班有 33 人参加学校运动会，二(2)班参加的人数比二(1)班多8人。两个班一共有多少人参加。",
+    "options": [],
+    "answer": "74 人",
+    "solution": "【分析】根据题意，先用二(1)班参加运动会的人数和二(2)班比二(1)班多的人数相加，计算出二(2)班参加运动会的人数，再和二(1)班参加的人数相加，就是两个班参加运动会的总人数.\n【详解】33 + 8 + 33 = 74(人),答：两个班一共有 74 人参加。",
+    "knowledge_points": [
+      "100 以内数的连加运算"
+    ],
+    "source": "24-25 二年级上·贵州黔南·期末"
+  },
+  {
+    "id": "95",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.85,
+    "question": "美美和丽丽一起看一本书，美美看了 35 页，美美比丽丽少看了 16 页，丽丽看了多少页。",
+    "options": [],
+    "answer": "51 页",
+    "solution": "【分析】根据题意可知：一个数比另一个数少几，求另一个数，用一个数加上少的数即可.\n【详解】35 + 16 = 51(页),答：丽丽看了 51 页。",
+    "knowledge_points": [
+      "两位数与两位数的进位加法"
+    ],
+    "source": "24-25 二年级上·福建福州·期末"
+  },
+  {
+    "id": "96",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.65,
+    "question": "学校图书室有 100 本故事书，二(1)班借走了 20 本，二(2)班借走了 37 本，二(6)班想借 45 本，剩下的故事书够吗。",
+    "options": [],
+    "answer": "不够",
+    "solution": "【分析】根据题意，先用故事书的总数量 - 二(1)班借走的数量 - 二(2)班借走的数量 = 剩下的数量，再和二(6)班想借的数量比较大小，剩下的数量大于或等于二(6)班想借的数量够，小于则不够.\n【详解】100 - 20 - 37 = 43(本),43 < 45，答：剩下的故事书不够。",
+    "knowledge_points": [
+      "100以内数的比大小",
+      "100以内数的连减运算"
+    ],
+    "source": "24-25 二年级上·湖北黄冈·期末"
+  },
+  {
+    "id": "97",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.85,
+    "question": "幸福小学秋期运动会期间，二(1)班上交 43 篇广播稿，二(2)班上交 32 篇广播稿，其中有 48 篇广播稿被选出进行了广播，没有进行广播的有多少篇。",
+    "options": [],
+    "answer": "27 篇",
+    "solution": "【分析】根据题意可知，二(1)班上交广播稿的数量加上二(2)班上交广播稿的数量，减去被选中广播稿的数量，等于没有进行广播的数量，据此解答.\n【详解】根据分析可得:43 + 32 - 48 = 27(篇),答：没有进行广播的有 27 篇。",
+    "knowledge_points": [
+      "100 以内数的加减混合运算"
+    ],
+    "source": "24-25 二年级上·河南南阳·期末"
+  },
+  {
+    "id": "98",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.85,
+    "question": "一辆公交车上原来有 40 人，到达人民医院站时，有 15 人下车，又有 17 人上车。现在车上有多少人。",
+    "options": [],
+    "answer": "42 人",
+    "solution": "【分析】根据题意可知，用原来的人数减去下车的人数，再加上上车的人数，即可求出现在车上有多少人，据此解答.\n【详解】根据分析可得:40 - 15 + 17 = 42(人),答：车上现在有42人。",
+    "knowledge_points": [
+      "100 以内数的加减混合运算"
+    ],
+    "source": "24-25 二年级上·浙江台州·期末"
+  },
+  {
+    "id": "99",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.65,
+    "question": "三个小朋友比赛踢毽子。芳芳说\"我踢的是你们两个踢的数量之和.\"阳阳说\"我比芳芳少踢 37 个.\"媛媛说\"我比芳芳少踢 28 个.\"你知道芳芳踢了多少个吗。",
+    "options": [],
+    "answer": "65 个",
+    "solution": "【分析】根据题意可知，阳阳比芳芳少踢的数量就是媛媛踢的数量;媛媛比芳芳少踢的数量就是阳阳踢的数量，则阳阳踢的数量 + 媛媛踢的数量 = 芳芳踢的数量.\n【详解】37 + 28 = 65(个),答：芳芳踢了65个。",
+    "knowledge_points": [
+      "两位数与两位数的进位加法"
+    ],
+    "source": "24-25 二年级上·河南信阳·期末"
+  },
+  {
+    "id": "100",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.65,
+    "question": "停车场原来有65辆车，开走19辆后，又开来了38辆。停车场现在有多少辆车。",
+    "options": [],
+    "answer": "84 辆",
+    "solution": "【分析】根据题意，开走的数量要减去，又开来的数量要加上，即原来的数量 - 开走的数量 + 又开来的数量 = 现在的数量.\n【详解】65 - 19 + 38 = 84(辆),答：停车场现在有84辆车。",
+    "knowledge_points": [
+      "100以内数的加减混合运算"
+    ],
+    "source": "24-25二年级上·贵州黔南·期末"
+  },
+  {
+    "id": "101",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "周老师今年 42 岁，小璐 9 岁，十年后，周老师比小璐大( )岁。",
+    "options": [
+      "A. 33",
+      "B. 23",
+      "C. 43"
+    ],
+    "answer": "A",
+    "solution": "【分析】根据年龄差不变可知，今年周老师比小璐大几岁，十年后周老师还是比小璐大几岁，则用今年周老师的年龄 - 小璐的年龄，计算即可.\n【详解】42 - 9 = 33(岁),周老师今年 42 岁，小璐 9 岁，十年后，周老师比小璐大 33 岁。故答案为:A",
+    "knowledge_points": [
+      "一位数与两位数的退位减法"
+    ],
+    "source": "24-25 二年级上·湖北黄冈·期末"
+  },
+  {
+    "id": "102",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "25 与 16 的差加上 56 得多少。正确列式为( )",
+    "options": [
+      "A. 56 - 25 - 16",
+      "B. 56 - 25 + 16",
+      "C. 25 - 16 + 56"
+    ],
+    "answer": "C",
+    "solution": "【分析】因为是用差加上 56，所以先求差，求差用减法计算，用 25 减去 16 再加上 56 即可.\n【详解】25 与 16 的差加上 56 得多少。正确列式为 25 - 16 + 56。故答案为:C",
+    "knowledge_points": [
+      "100以内数的加减混合运算"
+    ],
+    "source": "24-25 二年级上·山东菏泽·期末"
+  },
+  {
+    "id": "103",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "选择题",
+    "difficulty": 0.4,
+    "question": "工厂里 98 个零件中有 21 个次品，要保证取出的零件中至少有一个合格品，则至少应该取出( )个零件。",
+    "options": [
+      "A. 21",
+      "B. 22",
+      "C. 77",
+      "D. 78"
+    ],
+    "answer": "B",
+    "solution": "【分析】98个零件中有21个次品，那么合格的零件有 98 - 21 = 77(个);考虑最差情况，取出的前 21 个，全是不合格的零件，此时，再从剩下的77个合格品中任取1个，就一定能保证取出的零件中至少有1个合格品，据此解答即可。本题需要从最不利的方面考虑，将所有次品全部拿出来，然后再拿出来的就是合格品了.\n【详解】根据分析可得:21 + 1 = 22(个),所以，至少应该取出22个零件。故答案为:B",
+    "knowledge_points": [
+      "两位数与一位数的加法(不进位)",
+      "两位数与两位数的不退位减法",
+      "最不利原则"
+    ],
+    "source": "24-25 二年级上·浙江温州·期末"
+  },
+  {
+    "id": "104",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "如图，根据数轴计算 A - B = ( ).\n\n![](images/687affc7a4f6c2081111dc233a26911c13318eeb8af6f7671d81c6737291d0c5.jpg)",
+    "options": [
+      "A. 53",
+      "B. 45",
+      "C. 37",
+      "D. 29"
+    ],
+    "answer": "C",
+    "solution": "【分析】根据图示可知，数轴上A与B的差即是45与8的差，用 45 减去 8 即可解答.\n【详解】根据分析可得:45 - 8 = 37，所以，根据数轴计算 A - B = 37。故答案为:C",
+    "knowledge_points": [
+      "一位数与两位数的退位减法"
+    ],
+    "source": "24-25 二年级上·浙江温州·期末"
+  },
+  {
+    "id": "105",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "下面算式有些数字看不清了，其中得数一定大于 40 的是( )。",
+    "options": [
+      "A. 19 + 1★",
+      "B. 30 + ★9",
+      "C. 50 - ★8"
+    ],
+    "answer": "B",
+    "solution": "【分析】根据题意，得数一定大于40，也就是得数为大于40的数。对于选项中的算式，减法算式的减数要填最大的数来计算，得出的结果才最小;加法算式中，加数要填最小的数，得出的结果才最小。由此解答.\n【详解】A。19 + 1★,当★是 0 时, 19 + 10 = 29 , 29 < 40，不符合题意;B。30 + ★9，当★是 1 时, 30 + 19 = 49 , 49 > 40，符合题意;C. 50 - ★8,★最大能填 4, 50 - 48 = 2 , 2 < 40，不符合题意。故答案为:B",
+    "knowledge_points": [
+      "两位数与整十数的减法",
+      "两位数与两位数的退位减法"
+    ],
+    "source": "24-25 二年级上·浙江温州·期末"
+  },
+  {
+    "id": "106",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面的算式中，列竖式计算\"3\"与\"4\"能直接相加的是( )。",
+    "options": [
+      "A. 32 + 24",
+      "B. 15 + 34",
+      "C. 42 + 35"
+    ],
+    "answer": "C",
+    "solution": "【分析】计算整数加法时，相同数位上的数可以直接相加，不同数位上的数不能直接相加，逐项分析找出正确答案即可.\n【详解】A。32 + 24,3 在十位上,4 在个位上，不能直接相加;B。15 + 34,3在十位上,4在个位上，并且在同一个数里，不能直接相加;C。42 + 35,4在十位上,3在十位上，并且不在同一个数里，可以直接相加。故答案为:C",
+    "knowledge_points": [
+      "两位数与两位数的不退位加法"
+    ],
+    "source": "24-25二年级上·湖南株洲·期末"
+  },
+  {
+    "id": "107",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "一根彩带长 50 米，第一次用去了18米，第二次用去了13米，剩下的彩带比原来短了( )米。",
+    "options": [
+      "A. 19",
+      "B. 31",
+      "C. 5"
+    ],
+    "answer": "B",
+    "solution": "【分析】根据题意，剩下的彩带比原来短的长度是两次用去的长度和，用第一次用去的长度加上第二次用去的长度，计算即可.\n【详解】18 + 13 = 31(米),剩下的彩带比原来短了 31 米。故答案为:B",
+    "knowledge_points": [
+      "两位数与两位数的进位加法"
+    ],
+    "source": "24-25 二年级上·湖南湘西·期末"
+  },
+  {
+    "id": "108",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "\"水果店运来 64 个西瓜，上午卖了 37 个，下午卖了 23 个，还剩多少个西瓜。\"正确的算式是( )。",
+    "options": [
+      "A. 64 - (37 - 23)",
+      "B. 64 - 23 - 37",
+      "C. 64 - 23 + 37"
+    ],
+    "answer": "B",
+    "solution": "【分析】用运来西瓜的总数量依次减去上午卖了的数量和下午卖了的数量，求出差，就是还剩的数量。选项中 64 - 23 - 37 也表示从总数里减去下午和上午卖出的数量，据此解决即可.\n【详解】由题意分析得：\"水果店运来 64 个西瓜，上午卖了 37 个，下午卖了 23 个，还剩多少个西瓜。\"正确的算式是(64 - 23 - 37)。故答案为:B",
+    "knowledge_points": [
+      "100 以内数的连减运算"
+    ],
+    "source": "23-24 二年级上·湖南长沙·期末"
+  },
+  {
+    "id": "109",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "下面的算式中,( )的得数比 50 大。",
+    "options": [
+      "A. 26 + 14",
+      "B. 83 - 38",
+      "C. 37 + 16"
+    ],
+    "answer": "C",
+    "solution": "【分析】由题意得，先分别计算出每个算式的结果，然后再与50比较即可.\n【详解】A。26 + 14 = 40 ,40 < 50。B。83 - 38 = 45 ,45 < 50。C。37 + 16 = 53 ,53 > 50。所以算式 37 + 16 的得数比50大。故答案为:C",
+    "knowledge_points": [
+      "两位数与两位数的退位减法",
+      "两位数与两位数的进位加法"
+    ],
+    "source": "24-25 三年级上·天津北辰·期末"
+  },
+  {
+    "id": "110",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "选择题",
+    "difficulty": 0.94,
+    "question": "一本故事书有50页，上周读21页，这周读( )页，还剩6页。",
+    "options": [
+      "A. 27 页",
+      "B. 23 页",
+      "C. 29 页"
+    ],
+    "answer": "B",
+    "solution": "【分析】故事书的总页数减去上周读的页数，再减去还剩下的页数，等于这周读的页数，据此解答.\n【详解】根据分析可得:50 - 21 - 6 = 23(页),这周读了 23 页。故答案为:B",
+    "knowledge_points": [
+      "100 以内数的连减运算"
+    ],
+    "source": "24-25二年级上·山东济宁·期末"
+  },
+  {
+    "id": "111",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "冬至这天小语家包饺子。爸爸包了29个饺子，妈妈包了35个饺子，小语包了12个饺子，他们一共包了( )个饺子。",
+    "options": [
+      "A. 52",
+      "B. 66",
+      "C. 76"
+    ],
+    "answer": "C",
+    "solution": "【分析】求一共包了多少个饺子，根据加法的意义，将他们三人包的数量相加即可.\n【详解】根据分析可得:29 + 35 + 12 = 76(个),因此，他们一共包了76个饺子。故答案为:C",
+    "knowledge_points": [
+      "100以内数的连加运算"
+    ],
+    "source": "24-25二年级上·陕西延安·期末"
+  },
+  {
+    "id": "112",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "一本书有 95 页，小红第一天看了 27 页，第二天看了 34 页。还剩多少页没看。小红想先求两天一共看了多少页，再求还剩多少页没看。她列出的算式是( )。",
+    "options": [
+      "A. 95 - (27 + 34)",
+      "B. 95 - 27 - 34",
+      "C. 95 - 27 + 34"
+    ],
+    "answer": "A",
+    "solution": "【分析】求出两天一共看多少页，用加法计算，即第一天看的页数加上第二天看的页数;求还剩下多少页，用减法计算，即书的总页数减去两天看的页数，可以算出来还剩多少页。根据分析选择正确答案即可.\n【详解】A。括号里算出来两天看的页数，再用总页数减去两天看的页数，即可求出还剩下多少页，符合题意先算两天看的页数，再算还剩下的页数，答案正确;B。总页数减去第一天看的页数，再减去第二天看的页数，等于还剩下多少页;先算出来第一天看完后还剩下多少页，不符合题目要求先算两天一共看多少页，答案不正确;C。总页数减去第一天看的页数，再加上第二天看的页数，算式没有意义，答案不正确。故答案为:A",
+    "knowledge_points": [
+      "带有小括号的混合运算",
+      "100以内数的加减混合运算"
+    ],
+    "source": "24-25 二年级上·湖北黄石·期末"
+  },
+  {
+    "id": "113",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "长汀是国家历史文化名城，世界客家首府。长汀古城店头街一家文创店上午卖出 26 个冰箱贴，下午卖出的冰箱贴比上午多 14 个，今天一共卖出多少个冰箱贴。要解决这个问题，必须先求出的中间问题是( )。",
+    "options": [
+      "A. 下午卖出多少个冰箱贴",
+      "B. 上午卖出多少个冰箱贴",
+      "C. 今天一共卖出多少个冰箱贴",
+      "D. 还剩多少个冰箱贴"
+    ],
+    "answer": "A",
+    "solution": "【分析】把上午卖出的冰箱贴与下午卖出的冰箱贴加起来，求出和，就是今天一共卖出多少个冰箱贴，而\"下午卖出的冰箱贴数量\"题中并没有直接告知是多少，所以，要求今天一共卖出多少个冰箱贴，必须先求出的中间问题是：下午卖出多少个冰箱贴.\n【详解】由题意分析得：长汀是国家历史文化名城，世界客家首府。长汀古城店头街一家文创店上午卖出 26 个冰箱贴，下午卖出的冰箱贴比上午多14个，今天一共卖出多少个冰箱贴。要解决这个问题，必须先求出的中间问题是：下午卖出多少个冰箱贴。故答案为:A",
+    "knowledge_points": [
+      "两位数与两位数的进位加法"
+    ],
+    "source": "24-25二年级上·福建龙岩·期末"
+  },
+  {
+    "id": "114",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "74 - 2□,要使差的十位上的数字是 4,□里可以填( )。",
+    "options": [
+      "A. 0~4",
+      "B. 5~9",
+      "C. 0~9"
+    ],
+    "answer": "B",
+    "solution": "【分析】两位数与两位数的减法计算时，相同数位对齐，从个位开始算起，若不够减从十位退1作十计算。要使差的十位上的数字是4，也就是 7 - 2 - 1 = 4，从十位退了1，则方框里可以填的数一定大于4，由此解答.\n【详解】由分析可知，比 4 大的数有 5,6,7,8,9。所以 □ 里可以填 5~9。故答案为:B",
+    "knowledge_points": [
+      "两位数与两位数的退位减法"
+    ],
+    "source": "24-25 二年级上·四川乐山·期末"
+  },
+  {
+    "id": "115",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "爸爸今年 39 岁，小明今年11岁，爸爸比小明大( )岁。",
+    "options": [
+      "A. 50",
+      "B. 18",
+      "C. 28"
+    ],
+    "answer": "C",
+    "solution": "【分析】用爸爸今年的岁数减小明今年的岁数即可求解.\n【详解】39 - 11 = 28(岁),爸爸比小明大28岁。故答案为:C",
+    "knowledge_points": [
+      "两位数与两位数的不退位减法"
+    ],
+    "source": "20-21 二年级上·湖南长沙·期末"
+  },
+  {
+    "id": "116",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "计算60 - 37时，从十位退1后，个位要算( )。",
+    "options": [
+      "A. 0 - 7",
+      "B. 10 - 7",
+      "C. 60 - 7"
+    ],
+    "answer": "B",
+    "solution": "【分析】两位数与两位数的减法计算时，相同数位对齐，从个位算起，个位若不够减，则从十位退1作十进行计算，由此解答.\n【详解】计算60 - 37时，从十位退1后，个位的0和十位退的\"1\"合在一起是 10，也就是个位要算 10 - 7。故答案为:B",
+    "knowledge_points": [
+      "两位数与两位数的退位减法"
+    ],
+    "source": "24-25二年级上·河南郑州·期末"
+  },
+  {
+    "id": "117",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "算式\"34 - 1□\"的差的十位上是 1，那么□里可以填( )。",
+    "options": [
+      "A. 0~9",
+      "B. 0~4",
+      "C. 5~9"
+    ],
+    "answer": "C",
+    "solution": "【分析】两位数与两位数的减法计算时，相同数位对齐，从个位算起，个位若不够减，则从十位退 1 作十计算。要想差的十位上是 1，也就是 3 - 1 - 1 = 1，从十位退了 1，即个位上的 4 不够减 □ ,则 4 小于 □,由此解答.\n【详解】由分析可知, 4 < □,比 4 大的数有5,6,7,8,9。□ 里可以填 5~9。故答案为:C",
+    "knowledge_points": [
+      "两位数与两位数的退位减法"
+    ],
+    "source": "24-25二年级上·浙江杭州·期末"
+  },
+  {
+    "id": "118",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "乐乐如果再长高 18 厘米，正好是 1 米，乐乐现在的身高是( )厘米。",
+    "options": [
+      "A. 72",
+      "B. 82",
+      "C. 92"
+    ],
+    "answer": "B",
+    "solution": "【分析】先将 1 米换算成厘米作单位,1 米 = 100 厘米，然后用 100 厘米减去乐乐再长高的厘米数即可求解.\n【详解】1 米 = 100 厘米,100 - 18 = 82(厘米),乐乐现在的身高是82厘米。故答案为:B",
+    "knowledge_points": [
+      "厘米和米之间的进率与换算",
+      "两，三位数的连续退位减法"
+    ],
+    "source": "24-25 二年级上·河南商丘·期末"
+  },
+  {
+    "id": "119",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "李老师买了一本书，付了三张 5 元的，一张 10 元的，这本书的价钱是( )元。",
+    "options": [
+      "A. 15",
+      "B. 10",
+      "C. 25"
+    ],
+    "answer": "C",
+    "solution": "【分析】将付的所有钱相加即可求出这本书的价钱。都是元作单位，直接将数字相加.\n【详解】5 + 5 + 5 + 10 = 25(元),这本书的价钱是25元。故答案为:C",
+    "knowledge_points": [
+      "十元以上人民币的认识与计算",
+      "100 以内数的连加运算"
+    ],
+    "source": "24-25 二年级上·湖北孝感·期末"
+  },
+  {
+    "id": "120",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "学校买来 80 个气球，一年级领走了28个，二年级领走了43个。还剩( )个。",
+    "options": [
+      "A. 71",
+      "B. 9",
+      "C. 61"
+    ],
+    "answer": "B",
+    "solution": "【分析】用学校买来气球的总数减去一年级领走的个数，再减去二年级领走的个数，即可计算出还剩多少个.\n【详解】80 - 28 - 43 = 9(个),还剩9个气球。故答案为:B",
+    "knowledge_points": [
+      "100 以内数的连减运算",
+      "两位数与两位数的退位减法"
+    ],
+    "source": "24-25 二年级上·青海西宁·期末"
+  },
+  {
+    "id": "121",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "端午节，学校举行了丰富多彩的实践活动，\"做香囊\"，\"包粽子\"等，下面是一，二年级参加活动的人数情况(每人只参加一个项目),二年级至少要有( )人参加，总人数才能超过一年级.\n<table><tr><td>年级</td><td>做香囊</td><td>包粽子</td></tr><tr><td>一年级</td><td>27人</td><td>18人</td></tr><tr><td>二年级</td><td>36人</td><td></td></tr></table>",
+    "options": [
+      "A. 9",
+      "B. 45",
+      "C. 10"
+    ],
+    "answer": "C",
+    "solution": "【分析】先算出一年级的总人数，再用一年级的总人数减去二年级做香囊的人数，因为二年级的总人数要超过一年级总人数，所以再加1即可.\n【详解】27 + 18 = 45(人),45 - 36 = 9(人),9 + 1 = 10(人),二年级至少要有 10 人参加，总人数才能超过一年级。故答案为:C",
+    "knowledge_points": [
+      "两位数与两位数的退位减法",
+      "两位数与两位数的进位加法"
+    ],
+    "source": "24-25二年级上·河南驻马店·期末"
+  },
+  {
+    "id": "122",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "小红有 48 元钱，给弟弟 10 元后，两人的钱数就同样多，原来弟弟有( )元。",
+    "options": [],
+    "answer": "28",
+    "solution": "【分析】小红给弟弟10元后，两人的钱数同样多，说明小红比弟弟多2个10元即20元，用小红的钱数减去小红比弟弟多的钱数，等于原来弟弟有多少元，据此解答.\n【详解】根据分析可得:10 + 10 = 20(元),48 - 20 = 28(元),所以原来弟弟有 28 元。",
+    "knowledge_points": [
+      "和差倍问题",
+      "两位数与两位数的不退位减法",
+      "整十数之间的加减法"
+    ],
+    "source": "24-25 二年级上·四川乐山·期末"
+  },
+  {
+    "id": "123",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "比 56 多 15 的数是( ),比 84 少( )的数是 39。",
+    "options": [],
+    "answer": "71;45",
+    "solution": "【分析】求比56多15的数是多少，用加法计算;用84减去 39 即可求出比 84 少几的数是 39，据此解答.\n【详解】根据分析可得:56 + 15 = 71,84 - 39 = 45，比56多15的数是71，比84少45的数是 39。",
+    "knowledge_points": [
+      "两位数与两位数的退位减法",
+      "两位数与两位数的进位加法"
+    ],
+    "source": "24-25 二年级上·四川乐山·期末"
+  },
+  {
+    "id": "124",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "明明做一道减法题，把减数 24 抄错成了 42，算得差是 30，正确的差是( )。",
+    "options": [],
+    "answer": "48",
+    "solution": "【分析】根据题意，先用错误的减数和错误的差相加，求出被减数，再用被减数减去正确的减数，即可得出正确的差.\n【详解】被减数:42 + 30 = 72，正确的差:72 - 24 = 48，明明做一道减法题，把减数24抄错成了42，算得差是30，正确的差是 48。",
+    "knowledge_points": [
+      "两位数与两位数的退位减法",
+      "两位数与整十数的加法"
+    ],
+    "source": "24-25 二年级上·福建龙岩·期末"
+  },
+  {
+    "id": "125",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "比 37 多 18 的数是( ),( )比 72 少 15。",
+    "options": [],
+    "answer": "55;57",
+    "solution": "【分析】求比一个数多几的数是多少，用这个数 + 多的数计算;求比一个数少几的数是多少，用这个数 - 少的数计算.\n【详解】37 + 18 = 55;72 - 15 = 57，比 37 多 18 的数是 55,57 比 72 少 15。",
+    "knowledge_points": [
+      "两位数与两位数的退位减法",
+      "两位数与两位数的进位加法"
+    ],
+    "source": "24-25 二年级上·浙江台州·期末"
+  },
+  {
+    "id": "126",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "李贺今年 13 岁，比爸爸小 28 岁，妈妈比爸爸小 2 岁，妈妈今年( )岁。",
+    "options": [],
+    "answer": "39",
+    "solution": "【分析】用李贺今年的岁数加28算出爸爸的岁数，再用爸爸的岁数减2即可求出妈妈的岁数.\n【详解】13 + 28 - 2 = 39(岁),妈妈今年39岁。",
+    "knowledge_points": [
+      "100以内数的加减混合运算"
+    ],
+    "source": "24-25 二年级上·山东菏泽·期末"
+  },
+  {
+    "id": "127",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "歌唱比赛中，小红获得 55 个赞，小林和小红相差 18 个赞，小林最多获得( )个赞，最少获得( )个赞。",
+    "options": [],
+    "answer": "73;37",
+    "solution": "【分析】根据题意，小林和小红相差18个赞，小林可能比小红得到的赞多，也可能比小红得到的赞少。则用小红得到赞的数量 + 18 = 小林最多得到赞的数量;用小红得到赞的数量 - 18 = 小林最少得到赞的数量.\n【详解】55 + 18 = 73(个);55 - 18 = 37(个),歌唱比赛中，小红获得 55 个赞，小林和小红相差 18 个赞，小林最多获得 73 个赞，最少获得 37 个赞。",
+    "knowledge_points": [
+      "两位数与两位数的退位减法",
+      "两位数与两位数的进位加法"
+    ],
+    "source": "24-25 二年级上·湖南株洲·期末"
+  },
+  {
+    "id": "128",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "把 25,27,29,31 这四个数填入下面的( ).\n( ) + ( ) - ( ) = ( )。",
+    "options": [],
+    "answer": "27;29;25;31",
+    "solution": "【分析】整数混合运算中，同级运算时，从左到右依次计算，据此试填.\n【详解】27 + 29 - 25 = 31。(答案不唯一)",
+    "knowledge_points": [
+      "100以内数的加减混合运算"
+    ],
+    "source": "20-21 二年级上·湖南长沙·期末"
+  },
+  {
+    "id": "129",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "一根筷子长 25 厘米,( )根这样的筷子接起来是1米。",
+    "options": [],
+    "answer": "4",
+    "solution": "【分析】1 米 = 100 厘米，多少个 25 厘米相加得 100 厘米就需要多少根这样的筷子接起来.\n【详解】1 米 = 100 厘米,25 + 25 + 25 + 25 = 100(厘米),4根这样的筷子接起来是1米。",
+    "knowledge_points": [
+      "厘米和米之间的进率与换算",
+      "100 以内数的连加运算"
+    ],
+    "source": "20-21 二年级上·湖南长沙·期末"
+  },
+  {
+    "id": "130",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "计算61 - 25时，我是这样想的：个位上 1 减 5 不够减，从( )位退 1 后，个位要算( )减 5 得( ),所以 61 - 25 = ( )。",
+    "options": [],
+    "answer": "十;11;6;36",
+    "solution": "【分析】减法竖式计算时，相同数位对齐，从个位减起，哪一位不够减就向前一位借1当十，和本位上的数合在一起，再减.\n【详解】计算 61 - 25 时，我是这样想的：个位上 1 减 5 不够减，从十位退 1 后，个位要算 11 减 5 得 6，所以 61 - 25 = 36。",
+    "knowledge_points": [
+      "两位数与两位数的退位减法"
+    ],
+    "source": "23-24二年级上·湖南长沙·期末"
+  },
+  {
+    "id": "131",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "25 厘米 + 75 厘米 = ( )米。",
+    "options": [],
+    "answer": "1",
+    "solution": "【分析】单位相同的直接将数字相加减，然后根据100厘米= 1 米进行换算.\n【详解】25厘米 + 75厘米 = 100 厘米,100 厘米 = 1 米，所以25厘米 + 75厘米 = 1 米。",
+    "knowledge_points": [
+      "厘米和米之间的进率与换算",
+      "两位数与两位数的进位加法"
+    ],
+    "source": "24-25 二年级上·湖南长沙·期末"
+  },
+  {
+    "id": "132",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "90 比 72 多( );比 29 多 54 的数是( )。",
+    "options": [],
+    "answer": "18;83",
+    "solution": "【分析】求一个数比另一个数多多少，用这个数 - 另一个数计算;求比一个数多几的数是多少，用这个数 + 多的数计算.\n【详解】90 - 72 = 18;29 + 54 = 83,90 比 72 多 18;比 29 多 54 的数是 83。",
+    "knowledge_points": [
+      "两位数与两位数的退位减法",
+      "两位数与两位数的进位加法"
+    ],
+    "source": "24-25 二年级上·湖南长沙·期末"
+  },
+  {
+    "id": "133",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "比 72 多 18 的数是( )。",
+    "options": [],
+    "answer": "90",
+    "solution": "【分析】求比一个数多几的数是多少，用加法列式解决.\n【详解】72 + 18 = 90，即，比 72 多 18 的数是 90。",
+    "knowledge_points": [
+      "两位数与两位数的进位加法"
+    ],
+    "source": "24-25 二年级上·湖南湘西·期末"
+  },
+  {
+    "id": "134",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "68 比( )少 12;73 比 65 多( )。",
+    "options": [],
+    "answer": "80;8",
+    "solution": "【分析】用68加12即可算出68比哪个数少12。求一个数比另一个数多多少用减法计算.\n【详解】68 + 12 = 80,73 - 65 = 8,68 比 80 少 12;73 比 65 多 8。",
+    "knowledge_points": [
+      "两位数与两位数的退位减法",
+      "两位数与两位数的进位加法"
+    ],
+    "source": "20-21 二年级上·湖南长沙·期末"
+  },
+  {
+    "id": "135",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "67 + 2□ 是一道进位加法题,□ 里最小填( )。8□ - 32，差的十位上是 4,□ 里最大填( )。",
+    "options": [],
+    "answer": "3;1",
+    "solution": "【分析】加法计算时，相同数位对齐，从个位加起，哪一位相加满十就向前一位进 1。减法计算时，相同数位对齐，从个位减起，哪一位不够减就向前一位借 1 当十，和本位上的数合并在一起，再减。67 + 2□ 是一道进位加法题,7加 □ 里的数最小是10,7加3 得 10，所以最小填 3.8减3得5,8□ - 32，差的十位上是4，所以有退位，方框里的数小于2，用2减1即可求解.\n【详解】7 + 3 = 10,2 - 1 = 1，由分析可得,67 + 2□ 是一道进位加法题,□里最小填3.8□ - 32，差的十位上是 4,□里最大填 1。",
+    "knowledge_points": [
+      "两位数与两位数的退位减法",
+      "两位数与两位数的进位加法"
+    ],
+    "source": "24-25二年级上·湖南株洲·期末"
+  },
+  {
+    "id": "136",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "小马虎在做一道减法题时，把减数35看成了53，这样算得的差是28，正确的差是( )。",
+    "options": [],
+    "answer": "46",
+    "solution": "【分析】根据题意，先用错误的减数和错误的差相加，求出被减数，再用被减数减去正确的减数，即可计算出正确的差.\n【详解】被减数:53 + 28 = 81，正确的差:81 - 35 = 46，小马虎在做一道减法题时，把减数 35 看成了 53，这样算得的差是 28，正确的差是 46。",
+    "knowledge_points": [
+      "两位数与两位数的退位减法",
+      "两位数与两位数的进位加法",
+      "错中求解问题(加减法)"
+    ],
+    "source": "24-25 二年级上·安徽黄山·期末"
+  },
+  {
+    "id": "137",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "比53少8的数是( );( )比70少24。",
+    "options": [],
+    "answer": "45;46",
+    "solution": "【分析】求比一个数少几的数是多少，用这个数 - 少的数计算，由此解答.\n【详解】53 - 8 = 45,70 - 24 = 46，比 53 少 8 的数是 45;46 比 70 少 24。",
+    "knowledge_points": [
+      "一位数与两位数的退位减法",
+      "两位数与两位数的退位减法"
+    ],
+    "source": "24-25 二年级上·安徽黄山·期末"
+  },
+  {
+    "id": "138",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "比 56 多 39 的数是( ),比 85 少( )的数是 58。",
+    "options": [],
+    "answer": "95;27",
+    "solution": "【分析】求比一个数多多少的数用加法计算。用 85 减 58 即可求出比 85 少多少的数是 58.\n【详解】56 + 39 = 95,85 - 58 = 27，比56多39的数是95，比85少27的数是 58。",
+    "knowledge_points": [
+      "两位数与两位数的退位减法",
+      "两位数与两位数的进位加法"
+    ],
+    "source": "24-25 二年级上·湖南湘西·期末"
+  },
+  {
+    "id": "139",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "38 比 29 多( ),比 40 少 8 的数是( )。",
+    "options": [],
+    "answer": "9;32",
+    "solution": "【分析】求一个数比另一个数多多少，用减法列式解决;求比一个数少几的数是多少，用减法列式解决.\n【详解】38 - 29 = 9,40 - 8 = 32，即,38 比 29 多 9，比 40 少 8 的数是 32。",
+    "knowledge_points": [
+      "一位数与两位数的退位减法",
+      "两位数与两位数的退位减法"
+    ],
+    "source": "24-25 二年级上·江西南昌·期末"
+  },
+  {
+    "id": "140",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "妈妈带了 2 张 50 元钱去买大米和食用油，买大米用去32元，买食用油用去58元，应找回( )元钱。",
+    "options": [],
+    "answer": "10",
+    "solution": "【分析】先算出妈妈一共带了多少钱，将2张50元相加。再用妈妈一共带的钱数减去买大米用去的钱数，再减去买食用油用去的钱数即可求出应找回多少钱.\n【详解】50 + 50 = 100(元),100 - 32 - 58 = 10(元),应找回 10 元钱。",
+    "knowledge_points": [
+      "100 以内数的连减运算",
+      "十元以上人民币的认识与计算"
+    ],
+    "source": "24-25 二年级上·湖北孝感·期末"
+  },
+  {
+    "id": "141",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "学校艺术节上，二年级有54人表演节目，一年级表演节目的学生人数比二年级的少 16 人，艺术节上一年级和二年级表演节目的一共有( )人。",
+    "options": [],
+    "answer": "92",
+    "solution": "【分析】用二年级的人数减一年级比二年级少的人数即可求出一年级的人数，然后将两个年级的人数相加即可求出共有多少人.\n【详解】54 - 16 = 38(人),54 + 38 = 92(人),艺术节上一年级和二年级表演节目的一共有 92 人。",
+    "knowledge_points": [
+      "两位数与两位数的退位减法",
+      "两位数与两位数的进位加法"
+    ],
+    "source": "24-25二年级上·陕西延安·期末"
+  },
+  {
+    "id": "142",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "比 79 大 16 的数是( ),比 53 小 28 的数是( )。",
+    "options": [],
+    "answer": "95;25",
+    "solution": "【分析】求比一个数大几的数是多少，用加法计算;求比一个数小几的数是多少，用减法计算，据此解答即可.\n【详解】79 + 16 = 95,53 - 28 = 25，比 79 大 16 的数是 95，比 53 小 28 的数是 25。",
+    "knowledge_points": [
+      "两位数与两位数的退位减法",
+      "两位数与两位数的进位加法"
+    ],
+    "source": "24-25 二年级上·山东济宁·期末"
+  },
+  {
+    "id": "143",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "二(1)班开展\"争做环保小卫士\"活动，第一小队收集了38节废电池，第二小队收集废电池的节数比第一小队多 8 节。第二小队收集了( )节废电池，这两个小队一共收集了( )节废电池。",
+    "options": [],
+    "answer": "46;84",
+    "solution": "【分析】先用第一小队收集的废电池节数加上8节，求出第二小队收集的废电池节数;再将两个小队收集的废电池节数相加，即可求出两队一共收集的废电池节数.\n【详解】38 + 8 = 46(节),38 + 46 = 84(节),第二小队收集了46节废电池，这两个小队一共收集了84节废电池。",
+    "knowledge_points": [
+      "一位数与两位数的进位加法",
+      "两位数与两位数的进位加法"
+    ],
+    "source": "24-25 二年级上·青海西宁·期末"
+  },
+  {
+    "id": "144",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "比 55 多 14 的数是( ),比 51 少 28 的数是( )。",
+    "options": [],
+    "answer": "69;23",
+    "solution": "【分析】求比一个数多几的数是多少，用加法计算，求比一个数少几的数是多少，用减法计算，据此解答.\n【详解】55 + 14 = 69,51 - 28 = 23，比55多14的数是69，比51少28的数是 23。",
+    "knowledge_points": [
+      "两位数与两位数的不退位加法",
+      "两位数与两位数的退位减法"
+    ],
+    "source": "24-25 二年级上·辽宁抚顺·期末"
+  },
+  {
+    "id": "145",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "小红身高 96 厘米，她再长高( )厘米就是 1 米。",
+    "options": [],
+    "answer": "4",
+    "solution": "【分析】用 1 米(1 米 = 100 厘米)减去小红的身高，求出差，即可解决.\n【详解】1 米 = 100 厘米,100 - 96 = 4(厘米),即，小红身高 96 厘米，她再长高 4 厘米就是 1 米。",
+    "knowledge_points": [
+      "厘米和米之间的进率与换算",
+      "两位数与两位数的退位减法"
+    ],
+    "source": "24-25 二年级上·湖北随州·期末"
+  },
+  {
+    "id": "146",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "90 比 56 多( ),比 72 少 12 的数是( )。",
+    "options": [],
+    "answer": "34;60",
+    "solution": "【分析】根据题意，求一个数比另一个数多多少，用减法计算;求比一个数少几的数是多少，用减法计算，据此解答.\n【详解】根据题意可得:90 - 56 = 34,72 - 12 = 60，所以,90 比 56 多 34，比 72 少 12 的数是 60。",
+    "knowledge_points": [
+      "两位数与两位数的不退位减法",
+      "两位数与两位数的退位减法"
+    ],
+    "source": "24-25 二年级上·湖南娄底·期末"
+  },
+  {
+    "id": "147",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "2024 年的巴黎奥运会中，中国获得40枚金牌，获得的铜牌比金牌少16枚，铜牌有( )枚，银牌比铜牌多 3 枚，银牌有( )枚。",
+    "options": [],
+    "answer": "24;27",
+    "solution": "【分析】用金牌的数量减去16即可得到铜牌的数量;用铜牌的数量加上3即可得到银牌的数量.\n【详解】40 - 16 = 24(枚),24 + 3 = 27(枚),所以 2024 年的巴黎奥运会中，中国获得 40 枚金牌，获得的铜牌比金牌少 16 枚，铜牌有 24 枚，银牌比铜牌多 3 枚，银牌有 27 枚。",
+    "knowledge_points": [
+      "两位数与一位数的加法(不进位)",
+      "两位数与两位数的退位减法"
+    ],
+    "source": "24-25 二年级上·浙江台州·期末"
+  },
+  {
+    "id": "148",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "小亮计划三天写 100 个生字，第一天写了39个，第二天写了53个，小亮第三天要写( )个生字。",
+    "options": [],
+    "answer": "8",
+    "solution": "【分析】用一共要写的个数减第一天写的个数，再减第二天写的个数即可求出第三天需要写的个数.\n【详解】100 - 39 - 53 = 8(个),小亮第三天要写8个生字。",
+    "knowledge_points": [
+      "100 以内数的连减运算"
+    ],
+    "source": "24-25 二年级上·湖北黄冈·期末"
+  },
+  {
+    "id": "149",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "48 比 16 多( ),比 80 少 63 的数是( )。",
+    "options": [],
+    "answer": "32;17",
+    "solution": "【分析】求一个数比另一个数多多少用减法计算。求比一个数少多少的数用减法计算.\n【详解】48 - 16 = 32,80 - 63 = 17,48 比 16 多 32，比 80 少 63 的数是 17。",
+    "knowledge_points": [
+      "两位数与两位数的不退位减法",
+      "两位数与两位数的退位减法"
+    ],
+    "source": "24-25 二年级上·湖北黄冈·期末"
+  },
+  {
+    "id": "150",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "95 比 47 多( ),( )比 53 多 26。",
+    "options": [],
+    "answer": "48;79",
+    "solution": "【分析】95 比 47 多几，要用 95 减去 47;一个数比 53 多26，则这个数是用53加26求得.\n【详解】95 - 47 = 48,53 + 26 = 79,95 比 47 多 48,79 比 53 多 26。",
+    "knowledge_points": [
+      "两位数与两位数的不退位加法",
+      "两位数与两位数的退位减法"
+    ],
+    "source": "24-25 三年级上·湖北黄冈·期末"
+  },
+  {
+    "id": "151",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "比 58 多 27 的数是( ),95 比( )多 19。",
+    "options": [],
+    "answer": "85;76",
+    "solution": "【分析】求比一个数多几的数是多少，用加法计算;已知一个数比另一个数多多少，求另一个数是多少，用减法即可解决.\n【详解】根据分析可得:58 + 27 = 85;95 - 19 = 76，所以，比58多27的数是85,95比76多 19。",
+    "knowledge_points": [
+      "两位数与两位数的退位减法",
+      "两位数与两位数的进位加法"
+    ],
+    "source": "24-25 二年级上·四川南充·期末"
+  },
+  {
+    "id": "152",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "一个三层的书柜里有 98 本书，其中上层有 38 本，中层有 26 本。下层有( )本图书。",
+    "options": [],
+    "answer": "34",
+    "solution": "【分析】用书柜图书的总本数先减去上层的本数，求出差，再减去中层的本数，求出差，就是下层的本数.\n【详解】98 - 38 - 26 = 60 - 26 = 34(本),即，一个三层的书柜里有 98 本书，其中上层有 38 本，中层有 26 本。下层有 34 本图书。",
+    "knowledge_points": [
+      "100 以内数的连减运算"
+    ],
+    "source": "24-25 二年级上·重庆奉节·期末"
+  },
+  {
+    "id": "153",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "比 26 多 18 的数是( ),( )比 56 少 19。",
+    "options": [],
+    "answer": "44;37",
+    "solution": "【分析】求比一个数多几的数是多少，用加法列式解决;求比一个数少几的数是多少，用减法列式解决.\n【详解】26 + 18 = 44,56 - 19 = 37，即，比 26 多 18 的数是 44,37 比 56 少 19。",
+    "knowledge_points": [
+      "两位数与两位数的退位减法",
+      "两位数与两位数的进位加法"
+    ],
+    "source": "24-25 二年级上·重庆奉节·期末"
+  },
+  {
+    "id": "154",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "要使 7□ - 24，差的十位上的数为 4，那么□里有( )种不同的填法。",
+    "options": [],
+    "answer": "4",
+    "solution": "【分析】整数减法计算法则：相同数位对齐，从个位减起，哪一位上的数不够减，要从前一位退1当十再继续减。据此解答.\n【详解】7□ - 24,7 - 2 = 5，若个位不向十位借1，则差的十位上的数就是 5;故，要使差的十位上的数为4，则个位上的□应不够减4，要从十位借 1;所以,□里的数要小于 4，小于 4 的数有:3,2,1,0;即，要使7□ - 24，差的十位上的数为4，那么□里有4种不同的填法。",
+    "knowledge_points": [
+      "两位数与两位数的退位减法"
+    ],
+    "source": "23-24 二年级上·浙江杭州·期末"
+  },
+  {
+    "id": "155",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "64 比( )多 8,( )比 56 少 19。",
+    "options": [],
+    "answer": "56;37",
+    "solution": "【分析】已知一个数比另一个数多多少，求另一个数是多少，用减法列式解决;求比一个数少几的数是多少，用减法列式解决;据此解决.\n【详解】64 - 8 = 56,56 - 19 = 37，即,64 比 56 多 8,37 比 56 少 19。",
+    "knowledge_points": [
+      "一位数与两位数的退位减法",
+      "两位数与两位数的退位减法"
+    ],
+    "source": "23-24 二年级上·浙江杭州·期末"
+  },
+  {
+    "id": "156",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "46 - 23 + 12 与 46 - (23 + 12)的计算结果相同。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】100以内加减法及连加，连减和加减混合计算，按照从左往右的顺序进行计算，数位要对齐，从个位算起，加法时，满十向前一位进一;减法时，如果不够减要向前位借一当十，加上原来的数再减;有括号先算括号里面，再算括号外边，算出两个算式的结果后即可解答.\n【详解】第一个算式:46 - 23 + 12 = 23 + 12 = 35;第二个算式:46 - (23 + 12) = 46 - 35 = 11.46 - 23 + 12 与 46 - (23 + 12)的计算结果不相同;原说法错误。故答案为: ×",
+    "knowledge_points": [
+      "100以内数的加减混合运算"
+    ],
+    "source": "24-25 二年级上·河南三门峡·期末"
+  },
+  {
+    "id": "157",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "判断题",
+    "difficulty": 0.65,
+    "question": "小军在做一道减法题时，把被减数64看成了46，这样算出的差是28，正确的差是 46。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】根据题意，先用错误的被减数减去错误的差，计算出减数，再用正确的被减数减去减数即可解答.\n【详解】减数:46 - 28 = 18，正确的差:64 - 18 = 46，小军在做一道减法题时，把被减数64看成了46，这样算出的差是28，正确的差是46。原题说法正确。故答案为:√",
+    "knowledge_points": [
+      "两位数与两位数的退位减法",
+      "错中求解问题(加减法)"
+    ],
+    "source": "24-25 二年级上·湖南湘西·期末"
+  },
+  {
+    "id": "158",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "7 + 16 + 14 + 2 = 39。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】整数混合运算中，同级运算时，从左到右依次计算，算出结果即可判断对错.\n【详解】7 + 16 + 14 + 2 = 39，原题说法正确。故答案为:√",
+    "knowledge_points": [
+      "100 以内数的连加运算"
+    ],
+    "source": "23-24 二年级下·广东汕头·期中"
+  },
+  {
+    "id": "159",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "计算 75 + (25 - 17)时，先算加法，再算减法。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】整数混合运算中，同级运算时，从左到右依次计算;有括号时，先算括号里面的，再算括号外面的.\n【详解】75 + (25 - 17) = 75 + 8 = 83，计算 75 + (25 - 17)时，先算减法，再算加法。原题说法错误。故答案为: ×",
+    "knowledge_points": [
+      "带有小括号的混合运算"
+    ],
+    "source": "24-25 二年级上·山东济宁·期末"
+  },
+  {
+    "id": "160",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "46 与 25 的和是 61，差是 11。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】求两个数的和是多少，用加法计算;求两个数的差是多少，用减法计算.\n【详解】46 + 25 = 71,46 - 25 = 21，两个数的和是 71，两个数的差是 21，所以原题干说法错误。故答案为: ×",
+    "knowledge_points": [
+      "两位数与两位数的不退位减法",
+      "两位数与两位数的进位加法"
+    ],
+    "source": "24-25 二年级上·青海西宁·期末"
+  },
+  {
+    "id": "161",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "计算72 - (36 - 15)时，应先算括号里面的减法。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】只有加减法的混合运算，从左往右计算，若有括号，则先算括号里面的，再算括号外面的，据此解答.\n【详解】计算72 - (36 - 15)时，应先算括号里面的减法，原说法正确。故答案为:√",
+    "knowledge_points": [
+      "带有小括号的混合运算"
+    ],
+    "source": "24-25 二年级上·辽宁抚顺·期末"
+  },
+  {
+    "id": "162",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "45 比 33 多几。可以这样列式:45 + 33 = 78。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】求一个数比另一个数多多少，用减法列式解决.\n【详解】由题意分析得:45 比 33 多几。可以这样列式:45 - 33 = 12;原题做法错误。故答案为: ×",
+    "knowledge_points": [
+      "两位数与两位数的退位减法"
+    ],
+    "source": "24-25 二年级上·辽宁抚顺·期末"
+  },
+  {
+    "id": "163",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "判断题",
+    "difficulty": 0.65,
+    "question": "浩浩今年 8 岁。爸爸 5 年后 43 岁，爸爸比浩浩大 35 岁。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】根据题意分析，爸爸5年后43岁，浩浩今年8岁，则浩浩5年后是 8 + 5 = 13(岁),用5年后爸爸的年龄减去5年后浩浩的年龄，即可得到爸爸比浩浩大的岁数.\n【详解】8 + 5 = 13(岁),43 - 13 = 30(岁),所以爸爸比浩浩大 30 岁。故答案为: ×",
+    "knowledge_points": [
+      "8加几的进位加法",
+      "两位数与两位数的不退位减法",
+      "年龄问题"
+    ],
+    "source": "24-25 二年级上·四川广元·期末"
+  },
+  {
+    "id": "164",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.65,
+    "question": "一本故事书有 65 页，小红第 1 天看了 18 页，接下来的 4 天，小红共看了 24 页。小红还有多少页没有看。",
+    "options": [],
+    "answer": "23 页",
+    "solution": "【分析】小红第1天看的页数加上接下来4天看的页数，等于小红看的页数;用故事书的总页数减去看的页数，等于小红还有多少页没有看，据此解答即可.\n【详解】18 + 24 = 42(页),65 - 42 = 23(页),答：小红还有 23 页没有看。",
+    "knowledge_points": [
+      "两位数与两位数的不退位减法",
+      "两位数与两位数的进位加法"
+    ],
+    "source": "24-25 二年级上·四川乐山·期末"
+  },
+  {
+    "id": "165",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.85,
+    "question": "第 33 届夏季奥运会于 2024 年 7 月 26 日在巴黎开幕，中国体育代表团在本届奥运会收获满满，成绩斐然，获得金牌40枚，银牌比金牌少13枚，铜牌24枚。获得金牌和银牌一共多少枚。",
+    "options": [],
+    "answer": "67 枚",
+    "solution": "【分析】先用金牌的数量减去13枚，求出差，就是银牌的数量，然后加上金牌的数量，求出和，就是获得金牌和银牌一共多少枚.\n【详解】40 - 13 + 40 = 27 + 40 = 67(枚),答：获得金牌和银牌一共 67 枚。",
+    "knowledge_points": [
+      "100 以内数的加减混合运算"
+    ],
+    "source": "24-25 二年级上·福建龙岩·期末"
+  },
+  {
+    "id": "166",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.85,
+    "question": "共享单车低碳出行，育才路站点停放40辆共享单车，早上骑走15辆，中午又骑走 23 辆，现在还有多少辆共享单车。",
+    "options": [],
+    "answer": "2 辆",
+    "solution": "【分析】用共享单车原来站点停放的数量减去早上骑走的数量，求出差，再减去中午又骑走的数量，求出差，就是现在还有的数量.\n【详解】40 - 15 - 23 = 25 - 23 = 2(辆),答：现在还有2辆共享单车。",
+    "knowledge_points": [
+      "100以内数的连减运算"
+    ],
+    "source": "24-25 二年级上·河南南阳·期末"
+  },
+  {
+    "id": "167",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.65,
+    "question": "海洋馆里有 13 条黄金神仙鱼，花面神仙鱼比黄金神仙鱼多 9 条，透红小丑鱼比黄金神仙鱼少8条。花面神仙鱼有多少条。两种神仙鱼共有多少条。",
+    "options": [],
+    "answer": "22 条;35 条",
+    "solution": "【分析】用黄金神仙鱼的条数加9条即可求出花面神仙鱼的条数。将黄金神仙鱼的条数和花面神仙鱼的条数相加即可.\n【详解】13 + 9 = 22(条),13 + 22 = 35(条),答：花面神仙鱼有22条;两种神仙鱼共有35条。",
+    "knowledge_points": [
+      "两位数与两位数的不退位加法",
+      "一位数与两位数的进位加法"
+    ],
+    "source": "24-25 二年级上·福建龙岩·期末"
+  },
+  {
+    "id": "168",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.65,
+    "question": "龙崆洞坐落于龙岩市新罗区雁石镇，流水淙淙，景色秀丽，风物宜人，有着丰富的山林景观和复杂独特的喀斯特地貌。一张成人票 60 元，一张儿童票比一张成人票便宜 27 元。一张儿童票多少钱。",
+    "options": [],
+    "answer": "33 元",
+    "solution": "【分析】用一张成人票的价钱减一张儿童票比一张成人票便宜的钱数，即可求出一张儿童票多少钱.\n【详解】60 - 27 = 33(元),答：一张儿童票33元钱。",
+    "knowledge_points": [
+      "两位数与两位数的退位减法"
+    ],
+    "source": "24-25 二年级上·福建龙岩·期末"
+  },
+  {
+    "id": "169",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.65,
+    "question": "学校有白粉笔 73 盒，彩色粉笔22盒，用去67盒，还剩多少盒。",
+    "options": [],
+    "answer": "28 盒",
+    "solution": "【分析】根据题意，首先，要知道学校粉笔的总数，这需要将白粉笔的数量和彩色粉笔的数量相加。已知白粉笔有73盒，彩色粉笔有22盒，那么粉笔的总数就是白粉笔数量与彩色粉笔数量之和，即 73 + 22 盒。然后，根据用去了67盒，要求剩下的盒数，就用粉笔的总数减去用去的盒数，由此解答.\n【详解】73 + 22 - 67 = 95 - 67 = 28(盒),答：还剩 28 盒。",
+    "knowledge_points": [
+      "100 以内数的加减混合运算"
+    ],
+    "source": "24-25 二年级上·山东菏泽·期末"
+  },
+  {
+    "id": "170",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.65,
+    "question": "某购物平台\"6·18\"举行生活用品促销活动，所有生活用品\"满 99 元减 25 元，包邮\"。果果对妈妈说：\"妈妈，您只要花74元就可以买到下面三种生活用品啦.\"你觉得果果说的有道理吗。为什么。\n![](images/2026-02-07%20121233.jpg)",
+    "options": [],
+    "answer": "有道理;原因见详解",
+    "solution": "【分析】本题涉及到价格的计算以及促销活动规则的应用。首先用加法计算出三种生活用品的总价，然后根据\"满 99元减25元\"的促销规则，判断总价是否满足满减条件，若满足则用减法计算出实际需要支付的价钱，最后与果果所说的 74 元进行比较，判断果果说的是否有道理即可.\n【详解】46 + 23 + 30 = 69 + 30 = 99(元),99 - 25 = 74(元),答：果果说的有道理。",
+    "knowledge_points": [
+      "两位数与两位数的不退位减法",
+      "促销问题",
+      "100以内数的连加运算"
+    ],
+    "source": "24-25二年级上·福建龙岩·期末"
+  },
+  {
+    "id": "171",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.85,
+    "question": "小云读一本 72 页的故事书,3 天读了 24 页。照这样读，剩下的几天读完。",
+    "options": [],
+    "answer": "6 天",
+    "solution": "【分析】先用3天读的总页数/3计算出平均每天读的页数，总页数 - 读了的页数 = 还剩的页数，然后再除以每天读的页数，就是读完剩下需要的天数.\n【详解】72 - 24 = 48(页),24÷3 = 8(页),48÷8 = 6(天),答：剩下的6天读完。",
+    "knowledge_points": [
+      "单归一问题",
+      "两位数与两位数的退位减法"
+    ],
+    "source": "23-24 三年级下·甘肃平凉·开学考试"
+  },
+  {
+    "id": "172",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.65,
+    "question": "小红和小军一共跳了多少下。\n\n![](images/4cb8871bb14a25b05b25a83ad0ff9bfc5a408bf86dd8c235b6561fd35486be7d.jpg)",
+    "options": [],
+    "answer": "68 下",
+    "solution": "【分析】用小军跳的数量加小红比小军多跳的数量可以算出小红跳的数量，然后将两人跳的数量相加即可求解.\n【详解】25 + 18 + 25 = 68(下),答：小红和小军一共跳了 68 下。",
+    "knowledge_points": [
+      "图文问题",
+      "100 以内数的连加运算"
+    ],
+    "source": "20-21 二年级上·湖南长沙·期末"
+  },
+  {
+    "id": "173",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.65,
+    "question": "二(1)班有男生 15 人，比女生少8人，二(1)班共有多少人。",
+    "options": [],
+    "answer": "38 人",
+    "solution": "【分析】用男生人数加男生比女生少的人数算出女生人数，然后将男生人数和女生人数相加即可求出二(1)班共有多少人.\n【详解】15 + 8 + 15 = 38(人),答：二(1)班共有 38 人。",
+    "knowledge_points": [
+      "100 以内数的连加运算"
+    ],
+    "source": "24-25 二年级上·湖南湘西·期末"
+  },
+  {
+    "id": "174",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.85,
+    "question": "儿子今年 11 岁，爸爸今年 34 岁。10 年后爸爸比儿子大多少岁。",
+    "options": [],
+    "answer": "23 岁",
+    "solution": "【分析】爸爸今年的年龄减去儿子今年的年龄，等于爸爸今年比儿子大多少岁，因为他们的年龄差始终不变，所以爸爸今年比儿子大多少岁，和10年后爸爸比儿子大多少岁一样，据此解答.\n【详解】根据分析可得:34 - 11 = 23(岁),答:10 年后爸爸比儿子大 23 岁。",
+    "knowledge_points": [
+      "两位数与两位数的不退位减法"
+    ],
+    "source": "24-25 二年级上·安徽黄山·期末"
+  },
+  {
+    "id": "175",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.65,
+    "question": "水果店里运来一批水果，上午卖出 18 筐，下午卖出 14 筐，店里还剩下 12 筐，请问一共运来多少筐水果。",
+    "options": [],
+    "answer": "44 筐",
+    "solution": "【分析】用上午卖出的筐数加下午卖出的筐数再加上还剩下的筐数即可求出一共运来多少筐水果.\n【详解】18 + 14 + 12 = 44(筐),答：一共运来 44 筐水果。",
+    "knowledge_points": [
+      "100 以内数的连加运算"
+    ],
+    "source": "23-24 二年级下·广东汕头·期中"
+  },
+  {
+    "id": "176",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.65,
+    "question": "三(1)班里有男生11人，女生16人，后来又转来14人，请问班上一共有多少人。",
+    "options": [],
+    "answer": "41 人",
+    "solution": "【分析】用男生人数加女生人数再加上又转来的人数即可求出班上一共有多少人.\n【详解】11 + 16 + 14 = 41(人),答：班上一共有41人。",
+    "knowledge_points": [
+      "100 以内数的连加运算"
+    ],
+    "source": "23-24二年级下·广东汕头·期中"
+  },
+  {
+    "id": "177",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.85,
+    "question": "小敏有4个苹果，妈妈给她5个，爸爸又给她11个，请问她现在有多少个苹果。",
+    "options": [],
+    "answer": "20 个",
+    "solution": "【分析】求小敏现在苹果的数量，用加法计算，即小敏原有苹果的数量 + 妈妈给她的数量 + 爸爸又给她的数量 = 现在的数量.\n【详解】4 + 5 + 11 = 20(个),答：她现在有 20 个苹果。",
+    "knowledge_points": [
+      "100以内数的连加运算"
+    ],
+    "source": "23-24二年级下·广东汕头·期中"
+  },
+  {
+    "id": "178",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.85,
+    "question": "动物园里有 14 只猴子，猴子比老虎多 3 只，这两种动物一共有多少只。",
+    "options": [],
+    "answer": "25 只",
+    "solution": "【分析】猴子比老虎多3只，也就是老虎比猴子少3只，故，先用猴子的数量减去3只，求出差，就是老虎的数量，然后加上猴子的数量，求出和，即可解决.\n【详解】14 - 3 + 14 = 11 + 14 = 25(只),答：这两种动物一共有25只。",
+    "knowledge_points": [
+      "100以内数的加减混合运算"
+    ],
+    "source": "23-24 二年级上·湖南长沙·期末"
+  },
+  {
+    "id": "179",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.65,
+    "question": "电器市场原来有 48 台冰箱，卖出 39 台后，又运进了 31 台。现在有冰箱多少台。",
+    "options": [],
+    "answer": "40 台",
+    "solution": "【分析】用原来的数量减去卖出的数量，再加上又运进的数量即可求出现在有冰箱多少台.\n【详解】48 - 39 + 31 = 40(台),答：现在有冰箱40台。",
+    "knowledge_points": [
+      "100以内数的加减混合运算"
+    ],
+    "source": "23-24 二年级上·湖南长沙·期末"
+  },
+  {
+    "id": "180",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.65,
+    "question": "布置教室需要60朵红花，还要做多少朵红花。\n\n![](images/5767c76823f3d161d8cd2aa973c4b2d8ec619c7cf95e417e1c164fe82bd91f9c.jpg)",
+    "options": [],
+    "answer": "16 朵",
+    "solution": "【分析】男孩和女孩做的同样多，所以男孩也做了 22 朵，用一共需要做的朵数依次减去两个小朋友已经做了的朵数即可.\n【详解】60 - 22 - 22 = 16(朵),答：还要做16朵红花。",
+    "knowledge_points": [
+      "图文问题",
+      "100以内数的连减运算"
+    ],
+    "source": "24-25二年级上·湖南长沙·期末"
+  },
+  {
+    "id": "181",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.65,
+    "question": "奶奶家原来养了 26 只鸡，后来又买了37只鸭和35只鸡，奶奶家养的鸡比鸭多多少只。",
+    "options": [],
+    "answer": "24 只",
+    "solution": "【分析】用鸡原来的数量加上又买来鸡的数量算出鸡的总数，然后减去鸭的数量即可求解.\n【详解】26 + 35 - 37 = 24(只),答：奶奶家养的鸡比鸭多24只。",
+    "knowledge_points": [
+      "100以内数的加减混合运算"
+    ],
+    "source": "20-21 二年级上·湖南长沙·期末"
+  },
+  {
+    "id": "182",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.85,
+    "question": "同学们要种 93 棵树，已经种了 29 棵，还要种多少棵。",
+    "options": [],
+    "answer": "64 棵",
+    "solution": "【分析】根据减法的意义，要种的数量 - 已经种了的数量 = 还要种的数量.\n【详解】93 - 29 = 64(棵),答：还要种64棵。",
+    "knowledge_points": [
+      "两位数与两位数的退位减法"
+    ],
+    "source": "23-24 二年级下·广东汕尾·期中"
+  },
+  {
+    "id": "183",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.85,
+    "question": "二年级有90名学生参加研学活动，有28人去革命纪念馆，有35人去历史博物馆，剩下的人去城市规划展示馆。有多少名学生去参观城市规划展示馆。",
+    "options": [],
+    "answer": "27 名",
+    "solution": "【分析】根据题意可知：用二年级的总人数减去去革命纪念馆的，再减去去历史博物馆的人数即可.\n【详解】90 - 28 - 35 = 62 - 35 = 27(名),答：有 27 名学生去参观城市规划展示馆。",
+    "knowledge_points": [
+      "100 以内数的连减运算"
+    ],
+    "source": "24-25二年级上·浙江杭州·期末"
+  },
+  {
+    "id": "184",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.85,
+    "question": "奇奇上个月得到的零花钱如下.\n<table><tr><td>爷爷</td><td>妈妈</td><td>爸爸</td></tr><tr><td>35元</td><td>25元</td><td>30元</td></tr></table>\n(1)奇奇一共有多少零花钱。 \n(2)奇奇买了一个书包花了 36 元，又买了一个文具盒花了18 元，还剩多少元。",
+    "options": [],
+    "answer": "90 元;36 元",
+    "solution": "【分析】(1)用加法把爷爷，妈妈和爸爸给的零花钱加起来，求出和，就是奇奇一共有多少零花钱。(2)用奇奇一共的零花钱先减去买一个书包花的钱数，求出差，再减去买一个文具盒花的钱数，求出差，就是还剩多少元.\n【详解】(1)35 + 25 + 30 = 60 + 30 = 90(元),答：奇奇一共有90元的零花钱。(2)90 - 36 - 18 = 54 - 18 = 36(元),答：还剩 36 元。",
+    "knowledge_points": [
+      "100以内数的连减运算",
+      "100以内数的连加运算"
+    ],
+    "source": "24-25 二年级上·江西南昌·期末"
+  },
+  {
+    "id": "185",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.85,
+    "question": "今年，妈妈给小丽买了18本故事书，买的科技书比故事书多6本，妈妈给小丽买了多少本科技书。科技书和故事书一共买了多少本。",
+    "options": [],
+    "answer": "24 本;42 本",
+    "solution": "【分析】用故事书的数量加上6本，求出和，就是科技书的数量;然后把科技书与故事书的数量加起来，求出和，就是一共的数量.\n【详解】18 + 6 = 24(本),24 + 18 = 42(本),答：妈妈给小丽买了24本科技书;科技书和故事书一共买了 42 本。",
+    "knowledge_points": [
+      "一位数与两位数的进位加法",
+      "两位数与两位数的进位加法"
+    ],
+    "source": "24-25 二年级上·河南郑州·期末"
+  },
+  {
+    "id": "186",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.85,
+    "question": "新年到了，小朋友们准备剪一些窗花装饰教室。男生剪了 25 个窗花，女生比男生多剪16个，女生剪了多少个窗花。他们一共剪了多少个窗花。",
+    "options": [],
+    "answer": "41 个;66 个",
+    "solution": "【分析】根据题意可知：求比一个数多几的数可用加法计算，则求女生剪的数量，用男生剪的数量加上女生比男生多剪的数量即可，然后求他们一共剪的数量，用男生剪的数量加女生剪的数量即可.\n【详解】25 + 16 = 41(个),25 + 41 = 66(个),答：女生剪了41个窗花，他们一共剪了66个窗花。",
+    "knowledge_points": [
+      "两位数与两位数的不退位加法",
+      "两位数与两位数的进位加法"
+    ],
+    "source": "24-25 二年级上·浙江杭州·期末"
+  },
+  {
+    "id": "187",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.85,
+    "question": "春节送\"福\"。爷爷写了 50 张\"福\"字，送出去了 28 张，又写了 16 张。现在还有多少张。",
+    "options": [],
+    "answer": "38 张",
+    "solution": "【分析】用爷爷先写的\"福\"字张数减去送出去的张数，再加上又写的张数，即可求出现有的张数，据此解答.\n【详解】50 - 28 + 16 = 22 + 16 = 38(张),答：现在还有 38 张。",
+    "knowledge_points": [
+      "100 以内数的加减混合运算"
+    ],
+    "source": "24-25二年级上·青海西宁·期末"
+  },
+  {
+    "id": "188",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.65,
+    "question": "二年级有48人参加学校趣味运动会，一年级参加的人数比二年级少 12 人。两个年级一共有多少人参加学校趣味运动会。",
+    "options": [],
+    "answer": "84 人",
+    "solution": "【分析】由题可知：二年级有48人参加运动会，一年级参加的人数比二年级少12人，先求出一年级有多少人参加，根据减法的意义，用减法计算。再将一年级和二年级的人数相加，即可得出两个年级一共有多少人参加.\n【详解】48 - 12 + 48 = 36 + 48 = 84(人),答：两个年级一共有 84 人参加学校趣味运动会。",
+    "knowledge_points": [
+      "100 以内数的加减混合运算"
+    ],
+    "source": "24-25二年级上·河南商丘·期末"
+  },
+  {
+    "id": "189",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.65,
+    "question": "红光小学最近购进100个机器人模型，分给一年级26个，二年级37个。三年级需要36个，剩下的够吗。为什么。",
+    "options": [],
+    "answer": "够;因为剩下个数比三年级需要的个数多",
+    "solution": "【分析】用购进的机器人模型数量减去分给一年级的数量，再减去分给二年级的数量，求出还剩的数量。用还剩的数量和三年级需要的数量作比较即可求解。剩余的数量小于需要的数量则不够，反之就够.\n【详解】100 - 26 - 37 = 37(个),37 > 36，够，因为剩下个数比三年级需要的个数多。答：剩下的够;因为剩下个数比三年级需要的个数多。",
+    "knowledge_points": [
+      "100 以内数的比大小",
+      "100 以内数的连减运算"
+    ],
+    "source": "24-25 二年级上·湖北孝感·期末"
+  },
+  {
+    "id": "190",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.85,
+    "question": "农场养了 46 只白兔子，养的灰兔子的只数比白兔子多 8 只.\n(1)农场养了多少只灰兔子。 \n(2)农场一共养了多少只兔子。",
+    "options": [],
+    "answer": "54 只;100 只",
+    "solution": "【分析】(1)用白兔子的只数加上灰兔子比白兔子多的只数，求出和，就是灰兔子的只数。(2)求一共养了多少只兔子，就是求两个数的和，用加法列式解决.\n【详解】(1)46 + 8 = 54(只),答：农场养了 54 只灰兔子。(2)46 + 54 = 100(只),答：农场一共养了 100 只兔子。",
+    "knowledge_points": [
+      "一位数与两位数的进位加法",
+      "两位数与两位数的进位加法"
+    ],
+    "source": "24-25 二年级上·河南郑州·期末"
+  },
+  {
+    "id": "191",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.65,
+    "question": "希望小学合唱团有42名男生，女生比男生少 8 人，合唱团一共有多少人。",
+    "options": [],
+    "answer": "76 人",
+    "solution": "【分析】用男生人数减女生比男生少的人数可以算出女生人数，然后将男生人数和女生人数相加即可求解.\n【详解】42 - 8 = 34(人),42 + 34 = 76(人),答：合唱团一共有76人。",
+    "knowledge_points": [
+      "一位数与两位数的退位减法",
+      "两位数与两位数的不退位加法"
+    ],
+    "source": "24-25 二年级上·山东济宁·期末"
+  },
+  {
+    "id": "192",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.65,
+    "question": "周末小明一家人到兴义市国家 AAAA 级风景区万峰林游玩。乘坐旅游观光车时，车上原来有56人，到南山站，下去22人，又上来了29人。现在车上有多少人。",
+    "options": [],
+    "answer": "63 人",
+    "solution": "【分析】根据题意可知，用车上原来的乘客数量 - 下车的人数 + 又上来的人数 = 车上现在的总人数，据此列式解答.\n【详解】56 - 22 + 29 = 34 + 29 = 63(人),答：现在车上有63人。",
+    "knowledge_points": [
+      "100 以内数的加减混合运算"
+    ],
+    "source": "24-25 二年级上·贵州黔西·期末"
+  },
+  {
+    "id": "193",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.65,
+    "question": "清明节，雨纷纷，先人墓前去祭扫。清明节，希望小学学生前往烈士陵园祭扫，学校分两辆车把学生送往烈士陵园。第一辆车有学生37人，第二辆车比第一辆车多15名学生，一共有多少名学生去烈士陵园祭扫。",
+    "options": [],
+    "answer": "89 名",
+    "solution": "【分析】用第一辆车的人数加第二辆车比第一辆车多的人数即可算出第二辆车的人数，最后将两辆车的人数相加即可求解.\n【详解】37 + 15 + 37 = 89(名),答：一共有 89 名学生去烈士陵园祭扫。",
+    "knowledge_points": [
+      "100以内数的连加运算"
+    ],
+    "source": "24-25二年级上·河南驻马店·期末"
+  },
+  {
+    "id": "194",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.85,
+    "question": "停车场原来停了45辆车，开走了 16 辆，又开来 28 辆。现在停了多少辆。",
+    "options": [],
+    "answer": "57 辆",
+    "solution": "【分析】原来停车的数量减去开走的数量，再加上开来的数量，等于现在停了多少辆，据此解答.\n【详解】根据分析可得:45 - 16 + 28 = 57(辆),答：现在停了57辆。",
+    "knowledge_points": [
+      "100以内数的加减混合运算"
+    ],
+    "source": "24-25二年级上·湖南娄底·期末"
+  },
+  {
+    "id": "195",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.65,
+    "question": "停车场原来有97辆车，开走了45辆，又开来了36辆，停车场现在有多少辆车。",
+    "options": [],
+    "answer": "88 辆",
+    "solution": "【分析】停车场原有车辆数减去开走的车辆数，再加上开来的车辆数，即可得到现在的车辆数.\n【详解】97 - 45 + 36 = 52 + 36 = 88(辆),答：停车场现在有 88 辆车。",
+    "knowledge_points": [
+      "100以内数的加减混合运算"
+    ],
+    "source": "24-25二年级上·四川广元·期末"
+  },
+  {
+    "id": "196",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.65,
+    "question": "公交车上原来有75人，到站后，下车 26 人，上车 14 人，现在车上有多少人。",
+    "options": [],
+    "answer": "63 人",
+    "solution": "【分析】先用公交车上原有的人数减去下车的人数，再加上上车的人数，即可求出现在车上有多少人.\n【详解】75 - 26 + 14 = 63(人),答：现在车上有 63 人。",
+    "knowledge_points": [
+      "两位数与两位数的退位减法",
+      "100以内数的加减混合运算",
+      "两位数与两位数的进位加法"
+    ],
+    "source": "24-25二年级上·广西贵港·期末"
+  },
+  {
+    "id": "197",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.85,
+    "question": "学校合唱队有 23 名女生，男生比女生多 4 人。合唱队一共有多少人。",
+    "options": [],
+    "answer": "50 人",
+    "solution": "【分析】先求出合唱队男生有多少人，用女生的人数加4即可;再用男生人数加上女生人数，求出一共有多少人，据此解答.\n【详解】根据分析可得:23 + 4 + 23 = 50(人),答：合唱队一共有50人。",
+    "knowledge_points": [
+      "100以内数的连加运算"
+    ],
+    "source": "24-25 二年级上·湖北黄石·期末"
+  },
+  {
+    "id": "198",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.65,
+    "question": "一根绳子长 90 厘米，第一次用去了 35 厘米，第二次用去 27 厘米，一共用去了多少厘米。",
+    "options": [],
+    "answer": "62 厘米",
+    "solution": "【分析】把两次用去的绳子长度加起来，求出和，就是共用去的长度.\n【详解】35 + 27 = 62(厘米),答：一共用去了62厘米。",
+    "knowledge_points": [
+      "两位数与两位数的进位加法"
+    ],
+    "source": "23-24 二年级上·浙江杭州·期末"
+  },
+  {
+    "id": "199",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.65,
+    "question": "\"孤舟蓑笠翁，独钓寒江雪\"描绘了一幅冬季的景象。老师将二(1)班同学分为3组，以小组为单位制作诗中的斗笠。第一小组做了17个斗笠，第二小组比第一小组多做9个，第三小组比第一小组少做8个.\n(1)第二小组做了多少个斗笠。第一和第二小组一共制作了多少个斗笠。\n(2)你还能提出其他数学问题并解答吗。",
+    "options": [],
+    "answer": "26 个;43 个;第三小组做了多少个斗笠。9 个(答案不唯一)",
+    "solution": "【分析】(1)根据题意可知：可根据求比一个数多几的数，用加法计算，用第一小组做的数量加上第二小组比第一小组多做的数量即可求出第二小组做的数量;然后用第一小组做的数量加上第二小组做的数量即可求出第一和第二小组一共制作的数量。(2)根据题意提出问题合理即可;例如第三小组做了多少个斗笠。可根据求比一个数少几的数，用减法计算，用第一小组做的数量减去第三小组比第一小组少做的数量即可.\n【详解】(1)17 + 9 = 26(个),17 + 26 = 43(个),答：第二小组做了26个斗笠。第一和第二小组一共制作了43个斗笠。(2)第三小组做了多少个斗笠。17 - 8 = 9(个),答：第三小组做了 9 个斗笠。(答案不唯一)",
+    "knowledge_points": [
+      "十几减8的退位减法",
+      "一位数与两位数的进位加法",
+      "\"提问题\"\"填条件\"问题",
+      "两位数与两位数的进位加法"
+    ],
+    "source": "24-25二年级上·山东日照·期末"
+  },
+  {
+    "id": "200",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.65,
+    "question": "今年的 11 月 9 日是全国第33个消防宣传日。红旗小学举办的\"消防安全，人人有责\"主题活动。一年级选送了18人参加消防知识竞赛，二年级比一年级多选送6人。两个年级参加知识竞赛的共有多少人。",
+    "options": [],
+    "answer": "42 人",
+    "solution": "【分析】用一年级选送的人数加多选送的人数，求出二年级选送的人数，然后用二年级选送的人数加一年级选送的人数即可求解.\n【详解】18 + 6 + 18 = 42(人),答：两个年级参加知识竞赛的共有42人。",
+    "knowledge_points": [
+      "100 以内数的连加运算"
+    ],
+    "source": "24-25 二年级上·吉林·期末"
+  },
+  {
+    "id": "201",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "下面的小棒图表示的算式是( ).\n\n![](images/f88dcb48e1cb167bc8a8e26b13e188c0a3a71cd2d4afaed800f969c4a5f65ce4.jpg)",
+    "options": [
+      "A. 31 + 28 = 59",
+      "B. 31 - 28 = 3",
+      "C. 31 - 8 = 23"
+    ],
+    "answer": "B",
+    "solution": "【分析】![](images/ccaa673fc346ed76218466c486d0f75ccf78247b18fe0028f82087f041379407.jpg),表示31根小棒,![](images/21f8259fcd20f3feebef642ec8b9e32211964c240d08b15953ea638ca57f079b.jpg),表示圈走了 28 根小棒，表示 31 减 28.\n【详解】小棒图表示的算式是 31 - 28 = 3。故答案为:B",
+    "knowledge_points": [
+      "两位数与两位数的退位减法"
+    ],
+    "source": "24-25二年级上·湖北黄石·期末"
+  },
+  {
+    "id": "202",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "下面的小棒图表示的算式是( ).\n\n![](images/98c847cf3a168e86c8f1686accd27f517309e198d60db82f20d93a425a4bea9f.jpg)",
+    "options": [
+      "A. 31 + 28 = 59",
+      "B. 31 - 8 = 23",
+      "C. 31 - 28 = 3"
+    ],
+    "answer": "C",
+    "solution": "【分析】据图分析，原有31根小棒，圈出28根，圈出代表减去的意思，还剩3根小棒，即用 31 - 28 = 3.\n【详解】小棒图表示的算式是: 31 - 28 = 3。故答案为:C",
+    "knowledge_points": [
+      "两位数与两位数的退位减法"
+    ],
+    "source": "24-25 二年级上·福建三明·期末"
+  },
+  {
+    "id": "203",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "体育室有 80 个足球，一年级借走 25 个，二年级借走 28 个，体育室还剩多少个足球。明明先算两个年级一共借走多少个。再算还剩多少个。他列的算式是( )。",
+    "options": [
+      "A. 80 - 25 - 28",
+      "B. 80 - (25 + 28)",
+      "C. 80 - 25 + 28"
+    ],
+    "answer": "B",
+    "solution": "【分析】由题可知，体育室有80个足球，一年级借走25个，二年级借走28个，用一年级借走的个数加上二年级借走的个数，求出和就是两个年级一共借走多少个，列式为 25 + 28;然后用总的个数减去一年级和二年级一共借走的个数，求出差就是还剩多少个，列式为 80 - (25 + 28).\n【详解】由分析可知：体育室有80个足球，一年级借走25个，二年级借走28个，体育室还剩多少个足球。明明先算两个年级一共借走多少个。再算还剩多少个。他列的算式是 80 - (25 + 28)。故答案为:B",
+    "knowledge_points": [
+      "带有小括号的混合运算"
+    ],
+    "source": "24-25 二年级上·江西抚州·期末"
+  },
+  {
+    "id": "204",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "如果 ☆ - 27 = 36，则 ☆ = ( )。",
+    "options": [
+      "A. 11",
+      "B. 9",
+      "C. 63"
+    ],
+    "answer": "C",
+    "solution": "【分析】根据被减数 - 减数 = 差，可得被减数 = 减数 + 差，因此要想算出☆等于多少，只需要把27和36相加即可.\n【详解】 27 + 36 = 63，因此,☆等于 63;故答案为:C",
+    "knowledge_points": [
+      "两位数与两位数的进位加法",
+      "两位数与两位数的退位减法"
+    ],
+    "source": "24-25 三年级上·广东广州·期末"
+  },
+  {
+    "id": "205",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "冬冬有80元，买书用去了 42 元，买本子又用去 16 元，则 42 + 16 表示( )。",
+    "options": [
+      "A. 冬冬还剩下多少钱",
+      "B. 冬冬买书比买本子多用多少钱",
+      "C. 冬冬买书和买本子一共用去多少钱"
+    ],
+    "answer": "C",
+    "solution": "【分析】A。求冬冬还剩下多少钱，用冬冬有的钱减去买书花的钱再减去买本子花的钱;B。求冬冬买书比买本子多用多少钱，用冬冬买书的钱减去买本子的钱;C。求冬冬买书和买本子一共用去多少钱，用冬冬买书的花的钱加上买本子花的钱.\n【详解】由分析可知:A。求冬冬还剩下多少钱，列式为 80 - 42 - 16，不符合题意;B。求冬冬买书比买本子多用多少钱，列式为 42 - 16，不符合题意;C。求冬冬买书和买本子一共用去多少钱，列式为 42 + 16，符合题意。故答案为:C",
+    "knowledge_points": [
+      "100 以内数的连减运算",
+      "两位数与两位数的退位减法",
+      "两位数与两位数的不退位加法"
+    ],
+    "source": "24-25二年级上·福建福州·期末"
+  },
+  {
+    "id": "206",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "下图表示的是一道减法算式的计算过程，这道算式是( ).\n\n![](images/06361fec77d1a218977225f08a4168596f01e9303c17921101c829c744d8256b.jpg)",
+    "options": [
+      "A. 26 - 9",
+      "B. 26 - 19",
+      "C. 36 - 19"
+    ],
+    "answer": "C",
+    "solution": "【分析】上图,3捆小棒表示30,6根小棒表示6，合起来表示 36;下图，圈出来 1 捆小棒和 9 根小棒，也就是圈出了 19 根小棒，表示从 36 里面减去 19;所以，图中表示的减法算式是 36 - 19;据此解决.\n【详解】由题意分析得：该图表示的是一道减法算式的计算过程，这道算式是36 - 19。故答案为:C",
+    "knowledge_points": [
+      "两位数与两位数的退位减法"
+    ],
+    "source": "24-25 二年级上·福建福州·期末"
+  },
+  {
+    "id": "207",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "小明有 50 元，买漫画书用了17元，他还剩多少钱。( )",
+    "options": [
+      "A. 13 元",
+      "B. 23 元",
+      "C. 33 元"
+    ],
+    "answer": "C",
+    "solution": "【分析】要求小明还剩多少钱，根据减法的意义，用小明有的钱减去买漫画书的钱，即可得出答案.\n【详解】 50 - 17 = 33(元),所以他还剩 33 元。故答案为:C",
+    "knowledge_points": [
+      "两位数与两位数的退位减法"
+    ],
+    "source": "24-25二年级上·广东江门·期末"
+  },
+  {
+    "id": "208",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "用竖式计算\"45 - 28\"时，个位上的5减8不够减，从十位退1，个位上要算( )减 8。",
+    "options": [
+      "A. 10",
+      "B. 15",
+      "C. 18"
+    ],
+    "answer": "B",
+    "solution": "【分析】整数减法列竖式计算，相同数位要对齐，从个位算起，哪一位不够减时，要向前一位借一当十再减。据此解决.\n【详解】由题意分析得:![](images/2026-02-07%20130718.jpg),即，用竖式计算\"45 - 28\"时，个位上的5减8不够减，从十位退 1，个位上要算 15 减 8。故答案为:B",
+    "knowledge_points": [
+      "两位数与两位数的退位减法"
+    ],
+    "source": "24-25 二年级上·广东江门·期末"
+  },
+  {
+    "id": "209",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "乐乐参加百米赛跑，再跑19米就到终点了，他跑过的距离比没跑的长( )米。",
+    "options": [
+      "A. 19",
+      "B. 62",
+      "C. 81"
+    ],
+    "answer": "B",
+    "solution": "【分析】根据题意，百米跑也就是要跑的总长度是100米，则用要跑的总长度 - 没跑的长度 = 已经跑过的长度;已经跑过了的长度 - 没跑的长度 = 跑过的比没跑的长的米数.\n【详解】跑过的距离:100 - 19 = 81(米),81 - 19 = 62(米),他跑过的距离比没跑的长62米。故答案为:B",
+    "knowledge_points": [
+      "两位数与两位数的退位减法"
+    ],
+    "source": "24-25 二年级上·河北保定·期末"
+  },
+  {
+    "id": "210",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "29与47的和是( )。",
+    "options": [
+      "A. 66",
+      "B. 76",
+      "C. 86"
+    ],
+    "answer": "B",
+    "solution": "【分析】求两个数的和是多少，用加法列式解决。整数加法计算时，相同数位对齐，从低位加起，哪一位上的数相加满十，就向前一位进一.\n【详解】29 + 47 = 76，即,29与47的和是 76。故答案为:B",
+    "knowledge_points": [
+      "两位数与两位数的进位加法"
+    ],
+    "source": "24-25二年级上·甘肃天水·期末"
+  },
+  {
+    "id": "211",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "要使25 + 3□ 的和是六十多, □ 里应填( )。",
+    "options": [
+      "A. 比 5 小的数",
+      "B. 比 5 大的数",
+      "C. 5"
+    ],
+    "answer": "B",
+    "solution": "【分析】根据题意，十位上数字的和是 2 + 3 = 5，要使得数是六十多，个位上数字的和必须大于10，向前一位进一,5 + □ > 10,10 - 5 = 5，即比 5 大的数.\n【详解】要使25 + 3□ 的和是六十多,□里应填比5大的数。故答案为:B",
+    "knowledge_points": [
+      "两位数与两位数的进位加法"
+    ],
+    "source": "24-25二年级上·河南开封·期末"
+  },
+  {
+    "id": "212",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "一个数减去 18，再加上 18，结果是 76，这个数是( )。",
+    "options": [
+      "A. 36",
+      "B. 0",
+      "C. 76"
+    ],
+    "answer": "C",
+    "solution": "【分析】一个数先减去几，再加上刚才减去的数，等于没加没减，还是原数，据此解答.\n【详解】根据分析可得：一个数减去 18，再加上 18，结果是 76，那么这个数是 76。故答案为:C",
+    "knowledge_points": [
+      "100以内数的加减混合运算"
+    ],
+    "source": "24-25 二年级上·河北邯郸·期末"
+  },
+  {
+    "id": "213",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "花坛里本来有 68 盆向日葵，搬走 42 盆后，又搬过来 11 盆，现在花坛里还有( )盆向日葵。",
+    "options": [
+      "A. 27",
+      "B. 37",
+      "C. 47"
+    ],
+    "answer": "B",
+    "solution": "【分析】用花坛里原来的向日葵数量先减去搬走的数量，求出差，再加上又搬来的数量，求出和，即可解决.\n【详解】68 - 42 + 11 = 26 + 11 = 37(盆),即，花坛里本来有68盆向日葵，搬走 42 盆后，又搬过来 11 盆，现在花坛里还有37盆向日葵。故答案为:B",
+    "knowledge_points": [
+      "100以内数的加减混合运算"
+    ],
+    "source": "24-25 二年级上·全国·期末"
+  },
+  {
+    "id": "214",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "小红有 21 本故事书，小兰有39本故事书，小兰给小红( )本故事书，两人的故事书就同样多了。",
+    "options": [
+      "A. 18",
+      "B. 9",
+      "C. 6",
+      "D. 4"
+    ],
+    "answer": "B",
+    "solution": "【分析】根据题意可知：先求出小兰比小红多的数量，用小兰的数量减去小红的数量即可，然后把多出的数量分成相等的两部分，把其中一部分分给小红则两人一样多.\n【详解】39 - 21 = 18(本),18 = 9 + 9，则小兰给小红 9 本故事书，两人的故事书就同样多了。故答案为:B",
+    "knowledge_points": [
+      "两位数与两位数的不退位减法",
+      "9加几的进位加法"
+    ],
+    "source": "23-24 二年级上·浙江宁波·期末"
+  },
+  {
+    "id": "215",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "计算 75 - (17 + 22)时，应先算( )。",
+    "options": [
+      "A. 17 + 22",
+      "B. 75 - 17",
+      "C. 75 + 22"
+    ],
+    "answer": "A",
+    "solution": "【分析】含有小括号的混合运算，要先算小括号里面的，再算小括号外面的.\n【详解】由题意分析得:75 - (17 + 22) = 75 - 39 = 36，计算 75 -(17 + 22)时，应先算 17 + 22。故答案为:A",
+    "knowledge_points": [
+      "带有小括号的混合运算"
+    ],
+    "source": "23-24 二年级上·河北保定·期末"
+  },
+  {
+    "id": "216",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "有一条 50 米长的彩带，第一次用去 14 米，第二次用去 24 米，还剩下( )米。",
+    "options": [
+      "A. 38",
+      "B. 12",
+      "C. 36"
+    ],
+    "answer": "B",
+    "solution": "【分析】根据题意，用总的彩带长度减去第一次用去的长度，再减去第二次用去的长度，即可求出还剩下多少米，据此解答.\n【详解】50 - 14 - 24 = 36 - 24 = 12(米),还剩下 12 米。故答案为:B",
+    "knowledge_points": [
+      "100以内数的连减运算"
+    ],
+    "source": "23-24 二年级上·浙江绍兴·期末"
+  },
+  {
+    "id": "217",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "68 比 12 多( ),比 60 少 36 的数是( )。",
+    "options": [],
+    "answer": "56;24",
+    "solution": "【分析】求 68 比 12 多多少，用减法计算，即 68 - 12;求比 60 少 36 的数是多少，用减法计算，即 60 - 36;据此解答.\n【详解】68 - 12 = 56,60 - 36 = 24.68 比 12 多 56，比 60 少 36 的数是 24。",
+    "knowledge_points": [
+      "两位数与两位数的不退位减法",
+      "两位数与两位数的退位减法"
+    ],
+    "source": "24-25 二年级上·江西赣州·期末"
+  },
+  {
+    "id": "218",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "24 比 56 少( ),比 15 多 77 的数是( )。",
+    "options": [],
+    "answer": "32;92",
+    "solution": "【分析】求一个数比另一个数多多少，用减法列式解决;求比一个数多多少的数是多少，用加法列式解决.\n【详解】 56 - 24 = 32,15 + 77 = 92，即,24 比 56 少 32，比 15 多 77 的数是 92。",
+    "knowledge_points": [
+      "两位数与两位数的不退位减法",
+      "两位数与两位数的进位加法"
+    ],
+    "source": "24-25 二年级上·河南南阳·期末"
+  },
+  {
+    "id": "219",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "比 45 多 37 的数是( ),( )比 28 少 19。",
+    "options": [],
+    "answer": "82;9",
+    "solution": "【分析】求比一个数多几的数是多少，用加法计算，用这个数 + 多的数计算;求比一个数少几的数是多少，用减法计算，用这个数 - 少的数.\n【详解】 45 + 37 = 82,28 - 19 = 9，比 45 多 37 的数是 82,9 比 28 少 19。",
+    "knowledge_points": [
+      "两位数与两位数的进位加法",
+      "两位数与两位数的退位减法"
+    ],
+    "source": "23-24 二年级上·浙江·期末"
+  },
+  {
+    "id": "220",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "( )比 25 多26;73 比 20 多( )。",
+    "options": [],
+    "answer": "51;53",
+    "solution": "【分析】求比一个数多多少的数用加法计算。求一个数比另一个数多多少用减法计算.\n【详解】25 + 26 = 51,73 - 20 = 53,51 比 25 多 26;73 比 20 多 53。",
+    "knowledge_points": [
+      "两位数与两位数的进位加法",
+      "两位数与整十数的减法"
+    ],
+    "source": "24-25 二年级上·内蒙古通辽·期末"
+  },
+  {
+    "id": "221",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "公交车上原来有 45 人，到站后，下车 19 人，又上车 26 人，公交车上现在有( )人。",
+    "options": [],
+    "answer": "52",
+    "solution": "【分析】用公交车上原来的人数减去下车的人数，求出差，再加上又上车的人数，求出和，即可解决.\n【详解】45 - 19 + 26 = 26 + 26 = 52(人),即，公交车上原来有45人，到站后，下车19人，又上车26人，公交车上现在有 52 人。",
+    "knowledge_points": [
+      "100以内数的加减混合运算"
+    ],
+    "source": "24-25 二年级上·河北保定·期末"
+  },
+  {
+    "id": "222",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "学校艺术节上，二年级有36人表演节目，三年级表演节目的人数比二年级多 19 人，三年级有( )人表演节目，二年级和三年级一共有( )人表演节目。",
+    "options": [],
+    "answer": "55;91",
+    "solution": "【分析】用二年级表演节目的人数加上 19 人，求出和，就是三年级的表演节目人数;二年级表演节目的人数与三年级表演节目的人数加起来，求出和，就是一共的表演节目人数.\n【详解】36 + 19 = 55(人),36 + 55 = 91(人),即，三年级有 55 人表演节目，二年级和三年级一共有 91 人表演节目。",
+    "knowledge_points": [
+      "两位数与两位数的进位加法"
+    ],
+    "source": "24-25 二年级上·甘肃天水·期末"
+  },
+  {
+    "id": "223",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "17 比 65 少( );( )比 80 多 17。",
+    "options": [],
+    "answer": "48;97",
+    "solution": "【分析】求 17 比 65 少多少，用减法列式计算;求比 80 多17 的数是多少，用加法列式计算.\n【详解】65 - 17 = 48,80 + 17 = 97.17 比 65 少 48;97 比 80 多 17。",
+    "knowledge_points": [
+      "两位数与两位数的退位减法",
+      "两位数与两位数的不退位加法"
+    ],
+    "source": "24-25 二年级上·广东汕头·期末"
+  },
+  {
+    "id": "224",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "填上合适的数.\n34 米 + 18 米 =( )米;3 米 - 100 厘米 =( )米",
+    "options": [],
+    "answer": "52;2",
+    "solution": "【分析】34米和18米，两个单位一样可以直接相加;3米和100厘米，单位不一样，需要单位变一样后再计算,1米 = 100 厘米，先把 100 厘米变成 1 米，单位一样后再减，据此解答.\n【详解】根据分析可得:(1)34 米 + 18 米 = 52 米;(2)1米 = 100 厘米,3米 - 100厘米 = 3 米 - 1米 = 2 米。",
+    "knowledge_points": [
+      "两位数与两位数的进位加法",
+      "厘米和米之间的进率与换算"
+    ],
+    "source": "24-25二年级上·河南开封·期末"
+  },
+  {
+    "id": "225",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "比 35 多 18 的数是( ),( )比 56 少 20。",
+    "options": [],
+    "answer": "53;36",
+    "solution": "【分析】求比 35 多 18 的数是多少，用加法列式计算，求比56 少 20 的数是多少，用减法列式计算.\n【详解】35 + 18 = 53,56 - 20 = 36，比 35 多 18 的数是 53,36 比 56 少 20。",
+    "knowledge_points": [
+      "两位数与两位数的进位加法",
+      "两位数与整十数的减法"
+    ],
+    "source": "24-25 二年级上·河北邯郸·期末"
+  },
+  {
+    "id": "226",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "比 32 多 18 的数是( ),比 60 少 26 的数是( )。",
+    "options": [],
+    "answer": "50;34",
+    "solution": "【分析】求比一个数多几的数是多少，用加法列式解决;求比一个数少几的数是多少，用减法列式解决.\n【详解】32 + 18 = 50,60 - 26 = 34，即，比 32 多 18 的数是 50，比 60 少 26 的数是 34。",
+    "knowledge_points": [
+      "两位数与两位数的进位加法",
+      "两位数与两位数的退位减法"
+    ],
+    "source": "24-25 二年级上·广东江门·期末"
+  },
+  {
+    "id": "227",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "65 + 18 = □3 , □ 里应填( )。",
+    "options": [],
+    "answer": "8",
+    "solution": "【分析】算出65加18的和，根据得数即可完成填空，据此解答.\n【详解】65 + 18 = 83，所以 □ 里应填8。",
+    "knowledge_points": [
+      "两位数与两位数的进位加法"
+    ],
+    "source": "24-25 二年级上·甘肃天水·期末"
+  },
+  {
+    "id": "228",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "76 比 67 大( ),比最大的两位数少 45 的数是( )。",
+    "options": [],
+    "answer": "9;54",
+    "solution": "【分析】求一个数比另一个数大几，用这个数 - 另一个数计算;求比一个数少几的数是多少，用这个数 - 少的数计算;最大的两位数是 99，由此解答.\n【详解】76 - 67 = 9;99 - 45 = 54,76 比 67 大 9，比最大的两位数少 45 的数是 54。",
+    "knowledge_points": [
+      "两位数与两位数的不退位减法",
+      "两位数与两位数的退位减法"
+    ],
+    "source": "24-25 二年级上·甘肃庆阳·期末"
+  },
+  {
+    "id": "229",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "比 24 多 36 的数是( ),比 62 少 28 的数是( )。",
+    "options": [],
+    "answer": "60;34",
+    "solution": "【分析】求比一个数多几的数是多少，用加法计算;求比一个数少几的数是多少，用减法计算，据此解答.\n【详解】根据分析可得:24 + 36 = 60;62 - 28 = 34，比 24 多 36 的数是 60，比 62 少 28 的数是 34。",
+    "knowledge_points": [
+      "两位数与两位数的进位加法",
+      "两位数与两位数的退位减法"
+    ],
+    "source": "24-25 二年级上·黑龙江哈尔滨·期末"
+  },
+  {
+    "id": "230",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "比 37 大 10 的数是( );38 比 70 少( )。",
+    "options": [],
+    "answer": "47;32",
+    "solution": "【分析】根据求比一个数大的几数，用加法计算;根据求一个数比另一个数少几，用减法计算.\n【详解】37 + 10 = 47,70 - 38 = 32，则比 37 大 10 的数是 47;38 比 70 少 32。",
+    "knowledge_points": [
+      "两位数与整十数的加法",
+      "两位数与两位数的退位减法"
+    ],
+    "source": "24-25 二年级上·山东日照·期末"
+  },
+  {
+    "id": "231",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "有51块巧克力，至少拿走( )块后，正好平均分给 8 个人。",
+    "options": [],
+    "answer": "3",
+    "solution": "【分析】用总块数依次减去 8 块，减到不能减为止，最后剩下几块则至少拿走几块.\n【详解】51 - 8 - 8 - 8 - 8 - 8 - 8 = 3(块),有 51 块巧克力，至少拿走 3 块后，正好平均分给 8 个人。",
+    "knowledge_points": [
+      "100 以内数的连减运算"
+    ],
+    "source": "24-25二年级上·河南周口·期末"
+  },
+  {
+    "id": "232",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "40 米 - 18 米 =( )米;2 米 - 100 厘米 =( )米;35 厘米 - 28 厘米 =( )厘米;30 厘米 + 70 厘米 =( )米",
+    "options": [],
+    "answer": "22;1;7;1",
+    "solution": "【分析】同单位的直接相加减，不同单位的根据1米 = 100 厘米统一单位再计算.\n【详解】40 米 - 18 米 = 22 米;2 米 - 100 厘米 = 2 米 - 1 米 = 1 米;35 厘米 - 28 厘米 = 7 厘米;30厘米 + 70厘米 = 100 厘米 = 1 米。",
+    "knowledge_points": [
+      "两位数与两位数的退位减法",
+      "厘米和米之间的进率与换算"
+    ],
+    "source": "24-25 二年级上·河北保定·期末"
+  },
+  {
+    "id": "233",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "一所学校组织寒假研学活动，有 85 名同学报名。报名参观科技馆的有 26 名同学，报名去查干湖徒步的有 35 名同学，其他同学报名\"探索渔猎文化\"。报名\"探索渔猎文化\"的同学有( )名。",
+    "options": [],
+    "answer": "24",
+    "solution": "【分析】根据题意可知，用报名的总人数依次减去报名参观科技馆的人数和报名去查干湖徒步的人数，即可求出报名\"探索渔猎文化\"的人数.\n【详解】85 - 26 - 35 = 59 - 35 = 24(名),则报名\"探索渔猎文化\"的同学有 24 名。",
+    "knowledge_points": [
+      "100以内数的连减运算"
+    ],
+    "source": "24-25 三年级上·吉林松原·期末"
+  },
+  {
+    "id": "234",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "乐乐有 16 张画片，娜娜有 25 张画片，乐乐比娜娜少( )张，两人一共有( )张画片。",
+    "options": [],
+    "answer": "9;41",
+    "solution": "【分析】求一个数比另一个数少几，用另一个数 - 这个数计算，即娜娜画片的数量 - 乐乐画片的数量 = 乐乐比娜娜少的数量;求两人一共有多少张，用加法计算，即乐乐画片的数量 + 娜娜画片的数量 = 两人一共的数量.\n【详解】25 - 16 = 9(张),16 + 25 = 41(张),乐乐有 16 张画片，娜娜有 25 张画片，乐乐比娜娜少 9 张，两人一共有41张画片。",
+    "knowledge_points": [
+      "两位数与两位数的进位加法",
+      "两位数与两位数的退位减法"
+    ],
+    "source": "23-24 二年级上·河北保定·期末"
+  },
+  {
+    "id": "235",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "比 52 多 18 的数是( );比 63 少 30 的数是( )。",
+    "options": [],
+    "answer": "70;33",
+    "solution": "【分析】根据求比一个数多几的数，用加法计算;求比一个数少几的数，用减法计算.\n【详解】52 + 18 = 70,63 - 30 = 33，则比52多18的数是 70;比63少30的数是 33。",
+    "knowledge_points": [
+      "两位数与两位数的进位加法",
+      "两位数与整十数的减法"
+    ],
+    "source": "24-25 二年级上·吉林四平·期末"
+  },
+  {
+    "id": "236",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "小丽的身高是 88 厘米，小明身高 1 米，小丽比小明矮( )厘米。",
+    "options": [],
+    "answer": "12",
+    "solution": "【分析】根据减法的意义，小明的身高 - 小丽的身高 = 小丽比小明矮的高度，根据1米 = 100 厘米换算单位再计算.\n【详解】1 米 = 100 厘米,100 - 88 = 12(厘米),小丽的身高是 88 厘米，小明身高 1 米，小丽比小明矮 12 厘米。",
+    "knowledge_points": [
+      "两位数与两位数的退位减法",
+      "厘米和米之间的进率与换算"
+    ],
+    "source": "24-25 二年级上·吉林四平·期末"
+  },
+  {
+    "id": "237",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "比 38 多 15 的数是( );48 比( )少 27。",
+    "options": [],
+    "answer": "53;75",
+    "solution": "【分析】根据题意，求比 38 多 15 的数是多少，求 48 比几少 27，用加法列式计算.\n【详解】38 + 15 = 53,48 + 27 = 75，比 38 多 15 的数是 53;48 比 75 少 27。",
+    "knowledge_points": [
+      "两位数与两位数的进位加法"
+    ],
+    "source": "23-24 二年级上·浙江宁波·期末"
+  },
+  {
+    "id": "238",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "比 38 多 27 的数是( ),比 42 少 15 的数是( )。",
+    "options": [],
+    "answer": "65;27",
+    "solution": "【分析】求比一个数多多少的数用加法计算;求比一个数少多少的数用减法计算.\n【详解】38 + 27 = 65,42 - 15 = 27，比 38 多 27 的数是 65，比 42 少 15 的数是 27。",
+    "knowledge_points": [
+      "两位数与两位数的进位加法",
+      "两位数与两位数的退位减法"
+    ],
+    "source": "23-24 二年级上·河北保定·期末"
+  },
+  {
+    "id": "239",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "三名老师带领学生去参加\"海洋\"主题的研学活动，男学生 38 人，女学生 24 人，一共要买( )张门票。",
+    "options": [],
+    "answer": "65",
+    "solution": "【分析】用老师人数加男学生人数，再加女学生人数即可求解.\n【详解】3 + 38 + 24 = 65(张),一共要买65张门票。",
+    "knowledge_points": [
+      "100以内数的连加运算"
+    ],
+    "source": "23-24二年级上·河北保定·期末"
+  },
+  {
+    "id": "240",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "比 39 多 26 的数是( );比 85 少 18 的数是( )。",
+    "options": [],
+    "answer": "65;67",
+    "solution": "【分析】求比一个数多几的数是多少，用这个数 + 多的数计算;求比一个数少几的数是多少，用这个数 - 少的数计算.\n【详解】39 + 26 = 65;85 - 18 = 67，比 39 多 26 的数是 65;比 85 少 18 的数是 67。",
+    "knowledge_points": [
+      "两位数与两位数的进位加法",
+      "两位数与两位数的退位减法"
+    ],
+    "source": "23-24 二年级上·河北保定·期末"
+  },
+  {
+    "id": "241",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "比 53 小 9 的数是( );比 86 大 7 的数是( )。",
+    "options": [],
+    "answer": "44;93",
+    "solution": "【分析】求比 53 小 9 的数是多少，用减法列式计算;求比86 大 7 的数是多少，用加法列式计算.\n【详解】53 - 9 = 44,86 + 7 = 93，比 53 小 9 的数是 44;比 86 大 7 的数是 93。",
+    "knowledge_points": [
+      "一位数与两位数的退位减法",
+      "一位数与两位数的进位加法"
+    ],
+    "source": "23-24 二年级上·浙江绍兴·期末"
+  },
+  {
+    "id": "242",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "35 比( )多 11.26与 48 相差( )。比 42 多 16 的数是( )。",
+    "options": [],
+    "answer": "24;22;58",
+    "solution": "【分析】已知一个数比另一个数多几，求另一个数是多少，用减法列式解决;求两个数的差是多少，用减法列式解决;求比一个数多几的数是多少，用加法列式解决.\n【详解】35 - 11 = 24,48 - 26 = 22,42 + 16 = 58，即 35 比 24 多 11.26 与 48 相差 22。比 42 多 16 的数是 58。",
+    "knowledge_points": [
+      "两位数与两位数的不退位减法",
+      "两位数与两位数的不进位加法"
+    ],
+    "source": "23-24 二年级上·福建福州·期末"
+  },
+  {
+    "id": "243",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "计算 53 - 14 时，个位不够减，从十位退 1 后，个位要算成( ),十位要算成( )减( )。",
+    "options": [],
+    "answer": "13减4;4;1",
+    "solution": "【分析】笔算两位数减法：相同数位对齐，计算从个位算起，若不够减，则向十位借1当10再减.\n【详解】计算53 - 14时，个位不够减，从十位退1后，个位要算成13减4，十位要算成4减1。",
+    "knowledge_points": [
+      "两位数与两位数的退位减法"
+    ],
+    "source": "23-24 二年级上·山东菏泽·期末"
+  },
+  {
+    "id": "244",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "一个杯子 9 元，买 10 个这样的杯子一共需要( )元。",
+    "options": [],
+    "answer": "90",
+    "solution": "【分析】将10个杯子的价钱相加即可求出买10个这样的杯子一共需要多少元.\n【详解】9 + 9 + 9 + 9 + 9 + 9 + 9 + 9 + 9 + 9 = 90(元),买10个这样的杯子一共需要90元。",
+    "knowledge_points": [
+      "100以内数的连加运算"
+    ],
+    "source": "23-24 二年级上·重庆丰都·期末"
+  },
+  {
+    "id": "245",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "比 68 少 12 的数是( ),比( )多 16 的数是 53。",
+    "options": [],
+    "answer": "56;37",
+    "solution": "【分析】求比一个数少几的数是多少，用这个数 - 少的数计算;比一个数多几的数是另一个数，求这个数，用另一个数 - 多的数计算.\n【详解】68 - 12 = 56;53 - 16 = 37，比 68 少 12 的数是 56，比 37 多 16 的数是 53。",
+    "knowledge_points": [
+      "两位数与两位数的不退位减法",
+      "两位数与两位数的退位减法"
+    ],
+    "source": "23-24 二年级上·河北保定·期末"
+  },
+  {
+    "id": "246",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "41 与 26 的和是( );95 与 47 的差是( )。",
+    "options": [],
+    "answer": "67;48",
+    "solution": "【分析】求 41 与 26 的和，用 41 + 26 计算;求 95 与 47 的差，用95 - 47计算.\n【详解】41 + 26 = 67;95 - 47 = 48,41 与 26 的和是 67;95 与 47 的差是 48。",
+    "knowledge_points": [
+      "两位数与两位数的退位减法",
+      "两位数与两位数的不退位加法"
+    ],
+    "source": "23-24 二年级上·河北保定·期末"
+  },
+  {
+    "id": "247",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "四十几加四十几的得数不可能的是九十几。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】四十几加四十几的得数，最小是 41 + 41 = 82，最大是 49 + 49 = 98，所以得数可能是八十几或九十几，据此解答.\n【详解】根据分析可得：四十几加四十几的得数可能是八十几或九十几;所以原说法错误。故答案为: ×",
+    "knowledge_points": [
+      "两位数与两位数的进位加法",
+      "两位数与两位数的不退位加法"
+    ],
+    "source": "24-25 二年级上·湖北黄石·期末"
+  },
+  {
+    "id": "248",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "计算 40 - (20 - 12)时，要先算 20 - 12。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】根据整数加减法的计算法则可知，只有加减的混合运算，从左往右的顺序进行计算;若有括号，先算括号里面的，再算括号外面的;据此解答.\n【详解】由分析可得:40 - (20 - 12)= 40 - 8 = 32，计算40 - (20 - 12)时，要先算20 - 12。故答案为:√",
+    "knowledge_points": [
+      "100 以内数的加减混合运算"
+    ],
+    "source": "24-25 二年级上·广东江门·期末"
+  },
+  {
+    "id": "249",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "65 比 29 多 46。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】求一个数比另一个数多多少，用减法列式解决。整数减法计算时，相同数位对齐，从低位减起，哪一位上的数不够减，就从它的前一位退一作十，和本位上的数合并在一起，再减.\n【详解】65 - 29 = 36，即,65 比 29 多 36;原说法错误。故答案为: ×",
+    "knowledge_points": [
+      "两位数与两位数的退位减法"
+    ],
+    "source": "24-25 二年级上·甘肃天水·期末"
+  },
+  {
+    "id": "250",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "计算 72 - (36 + 15)时，应先算减法。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】只有加减法的混合运算，从左往右计算;若有括号，则先算括号里面的，再算括号外面的.\n【详解】计算 72 - (36 + 15)时，应先算 36 + 15，即先算加法，原题说法错误。故答案为: ×",
+    "knowledge_points": [
+      "有括号的运算顺序"
+    ],
+    "source": "24-25 二年级上·内蒙古巴彦淖尔·期末"
+  },
+  {
+    "id": "251",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "判断题",
+    "difficulty": 0.65,
+    "question": "如果 56 - 2□ 是一道退位减法算式，那么□里最小填 7。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】两位数与两位数的减法计算时，相同数位对齐，从个位算起，若个位不够减，则从十位退1作十进行计算。要想算式为退位减法，也就是被减数的个位要比减数的个位小，即6<□,则□最小是比6大1的数，由此解答.\n【详解】6 + 1 = 7，如果56 - 2□是一道退位减法算式，那么□里最小填7。原题说法正确。故答案为:√",
+    "knowledge_points": [
+      "两位数与两位数的退位减法"
+    ],
+    "source": "24-25 二年级上·甘肃庆阳·期末"
+  },
+  {
+    "id": "252",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "判断题",
+    "difficulty": 0.65,
+    "question": "62 - 18 - 9 和 62 - (18 - 9)的计算顺序不一样，结果也不一样。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】加减法混合运算中，没有括号的，从左到右依次计算;有括号的，先算括号里面的，再算括号外面的。据此解答.\n【详解】62 - 18 - 9 = 44 - 9 = 35;62 -(18 - 9)= 62 - 9 = 53,62 - 18 - 9和62 -(18 - 9)的计算顺序不一样，结果也不一样。原题说法正确。故答案为:√",
+    "knowledge_points": [
+      "100 以内数的加减混合运算",
+      "带有小括号的混合运算"
+    ],
+    "source": "24-25 二年级上·广东汕头·期末"
+  },
+  {
+    "id": "253",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "最大的两位数与最小的两位数相差 90。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】根据题意可知：最大的两位数是99，最小的两位数是10，求相差多少。把两者相减即可.\n【详解】99 - 10 = 89，则最大的两位数与最小的两位数相差89;原题说法错误。故答案为: ×",
+    "knowledge_points": [
+      "两位数与两位数的不退位减法"
+    ],
+    "source": "24-25 二年级上·河北·期末"
+  },
+  {
+    "id": "254",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "苹果有 32 个，梨比苹果多 9 个，苹果和梨一共有 41 个。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】先求出梨的数量，苹果的数量加9即可，然后再算出苹果和梨的总数量，判断题目是否正确.\n【详解】32 + 9 + 32 = 41 + 32 = 73(个),所以，苹果和梨一共有73个，原说法错误。故答案为: ×",
+    "knowledge_points": [
+      "100以内数的连加运算",
+      "两位数与两位数的不进位加法",
+      "一位数与两位数的进位加法"
+    ],
+    "source": "23-24 二年级上·河北保定·期末"
+  },
+  {
+    "id": "255",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "计算题",
+    "difficulty": 0.65,
+    "question": "看图列式.\n\n![](images/5311b8494db3644ba75d17ca35ded3d710f502e7c43ccfb03a90c090a93fa4f7.jpg)\n□ ○ □ = □(个)",
+    "options": [],
+    "answer": "56 + 24 = 80",
+    "solution": "【分析】足球有56个，篮球比足球多24个，求篮球的数量，用足球的数量 + 篮球比足球多的数量 = 篮球的数量，由此解答.\n【详解】56 + 24 = 80(个),篮球有80个。",
+    "knowledge_points": [
+      "两位数与两位数的进位加法",
+      "图文问题"
+    ],
+    "source": "23-24 二年级上·江西抚州·期末"
+  },
+  {
+    "id": "256",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "计算题",
+    "difficulty": 0.85,
+    "question": "列算式.\n\n![](images/bbbb41b2ae5df2d947e92f1f609b139564a5d38efdf51b4e7db772599ed0106c.jpg)\n□ ○ □ = □(个)",
+    "options": [],
+    "answer": "36 + 27 = 63",
+    "solution": "【分析】将左右两边的个数相加即可求出一共有多少个.\n【详解】36 + 27 = 63(个),一共有 63 个水果。",
+    "knowledge_points": [
+      "两位数与两位数的进位加法",
+      "图文问题"
+    ],
+    "source": "24-25 二年级上·全国·假期作业"
+  },
+  {
+    "id": "257",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "计算题",
+    "difficulty": 0.85,
+    "question": "看图列式.\n\n![](images/378ff7308bbb24fe97ed90bd2842aa21e9cc84b73bca4100d17a5328b8cef2fb.jpg)\n□ ○ □ = □(个)",
+    "options": [],
+    "answer": "74 - 28 = 46",
+    "solution": "【分析】用总数减右边的个数即可求出左边有多少个.\n【详解】74 - 28 = 46(个)",
+    "knowledge_points": [
+      "两位数与两位数的退位减法",
+      "图文问题"
+    ],
+    "source": "24-25 二年级上·全国·假期作业"
+  },
+  {
+    "id": "258",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "计算题",
+    "difficulty": 0.85,
+    "question": "看图列出算式.\n\n![](images/d63d97408ddf9610161a3c02b35c3d74ff857730df4d5bb996e27a54c52477c4.jpg)\n□ ○ □ = □( )",
+    "options": [],
+    "answer": "70 - 45 = 25(个)",
+    "solution": "【分析】苹果有70个，梨的数量比苹果少45个，则，用苹果的数量减去45个，求出差，就是梨的数量.\n【详解】由题意分析得:70 - 45 = 25(个),梨有 25 个。",
+    "knowledge_points": [
+      "两位数与两位数的退位减法",
+      "图文问题"
+    ],
+    "source": "24-25 二年级上·全国·假期作业"
+  },
+  {
+    "id": "259",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "计算题",
+    "difficulty": 0.85,
+    "question": "看图列式计算.\n\n![](images/2d1ac5ed826c0786a71832d08be9ff49f44ab4c75a3061a7e8b5b5a5597d9424.jpg)\n□ ○ □ = □( )",
+    "options": [],
+    "answer": "65 - 29 = 36(只)",
+    "solution": "【分析】鸡有65只，鸭的数量比鸡的数量少29只，则用鸡的数量减去29，求出差，就是鸭的数量.\n【详解】由题意分析得:65 - 29 = 36(只),鸭有 36 只。",
+    "knowledge_points": [
+      "两位数与两位数的退位减法",
+      "图文问题"
+    ],
+    "source": "24-25 二年级上·全国·假期作业"
+  },
+  {
+    "id": "260",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.65,
+    "question": "冬至是\"二十四节气\"之一，在我国传统习俗中，冬至一定要吃饺子。琳琳家冬至也吃饺子，奶奶包了54个饺子，妈妈比奶奶少包了 18 个饺子.\n(1)妈妈包了多少个饺子。 \n(2)妈妈和奶奶一共包了多少个饺子。",
+    "options": [],
+    "answer": "36 个;90 个",
+    "solution": "【分析】(1)妈妈包饺子的数量 = 奶奶包饺子的数量 - 妈妈比奶奶少包的数量;(2)一共包的数量 = 奶奶包饺子的数量 + 妈妈包饺子的数量，据此解答.\n【详解】(1)54 - 18 = 36(个),答：妈妈包了36个饺子。(2)54 + 36 = 90(个),答：妈妈和奶奶一共包了90个饺子。",
+    "knowledge_points": [
+      "两位数与两位数的进位加法",
+      "两位数与两位数的退位减法"
+    ],
+    "source": "24-25二年级上·四川广元·期末"
+  },
+  {
+    "id": "261",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.85,
+    "question": "小强家的网店今天上午接到 55 份订单，下午比上午少接到 18 份订单。小强家的网店今天一共接到多少份订单。",
+    "options": [],
+    "answer": "92 份",
+    "solution": "【分析】先用上午的订单数量减去18份，求出差，就是下午的订单数量，再加上上午的订单数量，求出和，即可解决.\n【详解】55 - 18 + 55 = 37 + 55 = 92(份),答：小强家的网店今天一共接到 92 份订单。",
+    "knowledge_points": [
+      "100 以内数的加减混合运算"
+    ],
+    "source": "24-25 二年级上·四川南充·期末"
+  },
+  {
+    "id": "262",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.65,
+    "question": "工人叔叔修一条路，上午修了 38 米，下午修了 24 米，还剩 32 米没修，这天一共修了多少米。",
+    "options": [],
+    "answer": "62 米",
+    "solution": "【分析】求一共修了多少米，用加法计算，即上午修的米数 + 下午修的米数 = 一共修的米数.\n【详解】38 + 24 = 62(米),答：这天一共修了62米。",
+    "knowledge_points": [
+      "两位数与两位数的进位加法"
+    ],
+    "source": "23-24 二年级上·河北保定·期末"
+  },
+  {
+    "id": "263",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.65,
+    "question": "果园原来有48棵苹果树,27棵梨树，农民伯伯又栽了19棵果树。现在果园一共有多少棵果树。",
+    "options": [],
+    "answer": "94 棵",
+    "solution": "【分析】根据题意，先用苹果树的数量和梨树的数量相加，计算出原来有多少棵果树，再加上又栽的果树数量，就是果树的总数量.\n【详解】48 + 27 + 19 = 94(棵),答：现在果园一共有 94 棵果树。",
+    "knowledge_points": [
+      "100以内数的连加运算"
+    ],
+    "source": "24-25 二年级上·广东江门·期末"
+  },
+  {
+    "id": "264",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.85,
+    "question": "学校组织二年级学生去看电影，二(1)班有48人，二(2)班有47人，这两个班一共有多少人。",
+    "options": [],
+    "answer": "95 人",
+    "solution": "【分析】求两个班一共有多少人，就是求两个数的和，用加法列式解决.\n【详解】48 + 47 = 95(人),答：这两个班一共有 95 人。",
+    "knowledge_points": [
+      "两位数与两位数的进位加法"
+    ],
+    "source": "24-25 二年级上·广东江门·期末"
+  },
+  {
+    "id": "265",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.85,
+    "question": "车上原来有 86 人，下来 24 人，又上去了 19 人，现在车上有多少人。\n\n![](images/73fb9078854b99ca1f6fa88be717801e69cd5b43973bab789cbd25407c9365e8.jpg)",
+    "options": [],
+    "answer": "81 人",
+    "solution": "【分析】先用车上原来的人数减去下车的人数，求出差，再加上又上车的人数，求出和，就是现在车上的人数.\n【详解】86 - 24 + 19 = 62 + 19 = 81(人),答：现在车上有81人。",
+    "knowledge_points": [
+      "100以内数的加减混合运算"
+    ],
+    "source": "23-24 二年级上·山东济宁·期末"
+  },
+  {
+    "id": "266",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.85,
+    "question": "聪聪有38张明信片，明明比聪聪少 15 张，明明有多少张明信片。他们一共有多少张明信片。",
+    "options": [],
+    "answer": "23 张;61 张",
+    "solution": "【分析】求比一个数少几的数是多少，用减法计算，即聪聪明信片的数量 - 明明比聪聪少的数量 = 明明明信片的数量，再和聪聪明信片的数量相加，就是两人明信片一共的数量.\n【详解】根据分析可得：明明明信片的数量:38 - 15 = 23(张),两人明信片的数量:23 + 38 = 61(张),答：明明有23张明信片，他们一共有61张明信片。",
+    "knowledge_points": [
+      "两位数与两位数的不退位减法",
+      "两位数与两位数的进位加法"
+    ],
+    "source": "24-25二年级上·广东江门·期末"
+  },
+  {
+    "id": "267",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.85,
+    "question": "小冬跳了多少下。\n![](images/2026-02-08%20153416.jpg)",
+    "options": [],
+    "answer": "87 下",
+    "solution": "【分析】根据题意可知：可根据求比一个数多几的数，用加法计算.\n【详解】72 + 15 = 87(下),答：小冬跳了87下。",
+    "knowledge_points": [
+      "两位数与两位数的不退位加法"
+    ],
+    "source": "24-25 二年级上·江西抚州·期末"
+  },
+  {
+    "id": "268",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.65,
+    "question": "学校体育教室原来有43个足球，被同学们借走14个后，又还回来8个，现在体育教室里有多少个足球。",
+    "options": [],
+    "answer": "37 个",
+    "solution": "【分析】用体育教室原有的足球个数减去借走的个数，再加上还回来的个数，即可求出现在体育教室有多少个足球.\n【详解】43 - 14 + 8 = 29 + 8 = 37(个),答：现在体育教室里有37个足球。",
+    "knowledge_points": [
+      "100以内数的加减混合运算"
+    ],
+    "source": "24-25二年级上·福建福州·期末"
+  },
+  {
+    "id": "269",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.65,
+    "question": "丰都新县城龙河东新修了100多栋高层建筑，很多小区都是全新的楼房。已知某小区1号楼有 38 米,2号楼比1号楼高13米,3号楼比2号楼低5米，请你帮忙算一算.\n![](images/d1a166dbd1258649ec08542eef7dcb9824dbf9fb9a016e93f7743ccacfde0542.jpg)\n□ ○ □ ○ □ = □( )",
+    "options": [],
+    "answer": "38 + 13 - 5 = 46(米)",
+    "solution": "【分析】用1号楼的高度加2号楼比1号楼高的部分即可求出2号楼的高度，用2号楼的高度减去3号楼比2号楼低的部分即可求出3号楼的高度.\n【详解】38 + 13 - 5 = 46(米),答:3号楼有46米。",
+    "knowledge_points": [
+      "100以内数的加减混合运算"
+    ],
+    "source": "23-24二年级上·重庆丰都·期末"
+  },
+  {
+    "id": "270",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.65,
+    "question": "丰都县今年风调雨顺，王叔叔家的水果丰收了。他统计了一下，他家今年收获了 81 箱无核梨,36 箱柿子。请你帮忙算一算，无核梨比糖梨多收了多少箱。\n\n![](images/b1850feab3d8ee36451c6b2e71cd7776594089e56c0ec77aeabd184d0aa3c71a.jpg)\n\n□ ○ □ = □( )",
+    "options": [],
+    "answer": "81 - 42 = 39(箱)",
+    "solution": "【分析】用无核梨的箱数减糖梨的箱数即可求出无核梨比糖梨多收了多少箱.\n【详解】81 - 42 = 39(箱),答：无核梨比糖梨多收了39箱。",
+    "knowledge_points": [
+      "两位数与两位数的退位减法",
+      "图文问题"
+    ],
+    "source": "23-24 二年级上·重庆丰都·期末"
+  },
+  {
+    "id": "271",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.85,
+    "question": "课间活动时，操场上跳绳的有48人，跑步的有39人，参加这两项活动的共有多少人。其中女生有30人，男生有多少人。",
+    "options": [],
+    "answer": "87 人;57 人",
+    "solution": "【分析】根据题意可知：求一共参加这两项活动有多少人。用参加跳绳的人数加上跑步的人数即可;求男生的人数，用共参加的人数减去女生的人数即可.\n【详解】48 + 39 = 87(人),87 - 30 = 57(人),答：参加这两项活动的共有 87 人，男生有 57 人。",
+    "knowledge_points": [
+      "两位数与两位数的进位加法",
+      "两位数与整十数的减法"
+    ],
+    "source": "24-25二年级上·黑龙江哈尔滨·期末"
+  },
+  {
+    "id": "272",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.85,
+    "question": "\"十月一，冬至到，家家户户吃水饺\"。冬至这天，思思包了16个饺子，比妈妈少包27个。他们一共包了几个饺子。",
+    "options": [],
+    "answer": "59 个",
+    "solution": "【分析】根据题意可知先求出妈妈包的数量，用思思包的数量加上比妈妈少的数量，然后再加上思思包的数量即可.\n【详解】16 + 27 + 16 = 43 + 16 = 59(个),答：他们一共包了 59 个饺子。",
+    "knowledge_points": [
+      "100 以内数的连加运算"
+    ],
+    "source": "24-25 二年级上·山东日照·期末"
+  },
+  {
+    "id": "273",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.85,
+    "question": "菜市场原来有 83 个冬瓜，运走了35个，现在有多少个冬瓜。",
+    "options": [],
+    "answer": "48 个",
+    "solution": "【分析】用原来的冬瓜数量减去运走的数量，求出差，就是现在还有的数量.\n【详解】83 - 35 = 48(个),答：现在有48个冬瓜。",
+    "knowledge_points": [
+      "两位数与两位数的退位减法"
+    ],
+    "source": "24-25 二年级上·河南南阳·期末"
+  },
+  {
+    "id": "274",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.85,
+    "question": "公共汽车上原来有40位乘客，到达商业城站下了 25 人，又上来了 16 人。现在公共汽车上有多少人。",
+    "options": [],
+    "answer": "31 人",
+    "solution": "【分析】公共汽车上原有的人数减去下车的人数，再加上上车的人数，就能算出来现在有几人，即可解答.\n【详解】根据分析可得:40 - 25 + 16 = 31(人),答：现在公共汽车上有 31 人。",
+    "knowledge_points": [
+      "100 以内数的加减混合运算"
+    ],
+    "source": "24-25 二年级上·广东江门·期末"
+  },
+  {
+    "id": "275",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.85,
+    "question": "小红有16颗糖，小林比她少 7 颗，两人一共有几颗糖。",
+    "options": [],
+    "answer": "25 颗",
+    "solution": "【分析】求比一个数少几的数是多少，用减法计算，即小红的糖的数量 - 小林比她少的数量 = 小林的糖的数量，再加上小红的糖的数量，就是两人一共的糖的数量，据此解答即可.\n【详解】16 - 7 + 16 = 9 + 16 = 25(颗),答：两人一共有25颗糖。",
+    "knowledge_points": [
+      "100以内数的加减混合运算"
+    ],
+    "source": "23-24二年级上·浙江·期末"
+  },
+  {
+    "id": "276",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.85,
+    "question": "同学们栽树。一班栽了25棵，二班栽了27棵，三班栽了34棵。这三个班一共栽了多少棵树。",
+    "options": [],
+    "answer": "86 棵",
+    "solution": "【分析】一班栽的棵数加上二班栽的棵数，再加上三班栽的棵数，即可算出一共栽了多少棵，据此解答.\n【详解】25 + 27 + 34 = 52 + 34 = 86(棵),答：这三个班一共栽了86棵树。",
+    "knowledge_points": [
+      "100 以内数的连加运算"
+    ],
+    "source": "24-25二年级上·甘肃天水·期末"
+  },
+  {
+    "id": "277",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.65,
+    "question": "金秋十月，硕果累累。一辆小货车一次最多能装50箱，这些苹果和梨能一次运走吗。\n\n![](images/4547860aeaee258a2208306fb76dcbfdd010de074c291e69fe195c199e42d4fe.jpg) 29箱\n\n![](images/861eac1cccfbe0a0b00d3f680ebf5b0f770cde55cb2645306728fda95e29d6f2.jpg) 27箱",
+    "options": [],
+    "answer": "不能",
+    "solution": "【分析】用加法算出苹果和梨一共的箱数，然后和50箱作比较，大于 50 箱则不能一次运走，反之则能.\n【详解】29 + 27 = 56(箱),56 > 50，不能。答：这些苹果和梨不能一次运走。",
+    "knowledge_points": [
+      "两位数与两位数的进位加法",
+      "图文问题"
+    ],
+    "source": "24-25二年级上·内蒙古通辽·期末"
+  },
+  {
+    "id": "278",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.65,
+    "question": "食堂原有 45 棵白菜，吃了 37 棵后，又买来 28 棵。食堂现在有多少棵白菜。",
+    "options": [],
+    "answer": "36 棵",
+    "solution": "【分析】用原有的数量减去吃了的数量，再加上又买来的数量即可求解.\n【详解】45 - 37 + 28 = 36(棵),答：食堂现在有36棵白菜。",
+    "knowledge_points": [
+      "100以内数的加减混合运算"
+    ],
+    "source": "24-25 二年级上·甘肃天水·期末"
+  },
+  {
+    "id": "279",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.65,
+    "question": "超市原来有44个皮球，卖掉了26个皮球后，又进货了37个皮球，现在超市有多少个皮球。",
+    "options": [],
+    "answer": "55 个",
+    "solution": "【分析】根据题意，卖掉的数量要减去，又进货的数量要加上，即原来的数量 - 卖掉的数量 + 又进货的数量 = 现在的数量.\n【详解】44 - 26 + 37 = 55(个),答：现在超市有55个皮球。",
+    "knowledge_points": [
+      "100以内数的加减混合运算"
+    ],
+    "source": "24-25二年级上·内蒙古巴彦淖尔·期末"
+  },
+  {
+    "id": "280",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.65,
+    "question": "还剩多少本。\n\n![](images/57214ef5520f1959b28993c225e7de1a4e643e4cabb384afda818f4cff82140e.jpg)\n\n![](images/fed6cac01e833cb6b78fe05a3973ddde15b7e1ee7fc637b03853f7714aa276d4.jpg)\n\n![](images/b40841b9f0265d81b7081ae25dfe0639e11b646db91f60ec7233b4eae263a277.jpg)\n\n![](images/b3067160a9dee68057a682fc26a57a4a899fa57d97193d77929fd0b5c8e48299.jpg)",
+    "options": [],
+    "answer": "36 本",
+    "solution": "【分析】用书架上原来一共的本数减去二(1)班借走的本数，再减二(2)班借走的本数即可求出还剩多少本.\n【详解】78 - 18 - 24 = 36(本),答：还剩 36 本。",
+    "knowledge_points": [
+      "100以内数的连减运算",
+      "图文问题"
+    ],
+    "source": "24-25 二年级上·广东汕头·期末"
+  },
+  {
+    "id": "281",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.85,
+    "question": "2024 年 12 月 4 日是我国第十一个国家宪法日。为了普及宪法知识，某校特意买来一些宪法相关书籍，分给每个年级供学生们阅读，二年级分到了28本，三年级分到的比二年级多14本，三年级分到了多少本。二年级和三年级一共分到了多少本。",
+    "options": [],
+    "answer": "42 本;70 本",
+    "solution": "【分析】根据题意可知：可根据求比一个数多几的数，用加法计算即可求出三年级分的数量，然后把二年级分的数量和三年级分的数量相加即可求出二年级和三年级一共分到的数量.\n【详解】28 + 14 = 42(本),28 + 42 = 70(本),答：三年级分到了 42 本，二年级和三年级一共分到了 70 本。",
+    "knowledge_points": [
+      "两位数与两位数的进位加法"
+    ],
+    "source": "24-25 二年级上·陕西西安·期末"
+  },
+  {
+    "id": "282",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.65,
+    "question": "一条裤子36元，比一件上衣便宜15元。一件上衣多少钱。买一件上衣和一条裤子一共需要多少钱。",
+    "options": [],
+    "answer": "51 元;87 元",
+    "solution": "【分析】根据题意，用裤子的价格加上15，即可求出一件上衣多少钱;把一件上衣的价格和一条裤子的价格相加，即可求出买一件上衣和一条裤子一共多少钱.\n【详解】36 + 15 = 51(元),51 + 36 = 87(元),答：一件上衣 51 元，买一件上衣和一条裤子一共需要 87 元。",
+    "knowledge_points": [
+      "两位数与两位数的进位加法",
+      "两位数与两位数的不进位加法"
+    ],
+    "source": "24-25二年级上·河北邯郸·期末"
+  },
+  {
+    "id": "283",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.65,
+    "question": "爱科学博物馆有 90个机器人模型，送给星星小学26个，博爱小学27个。博物馆的机器人模型少了多少个。实验小学需要36个，剩下的够吗。",
+    "options": [],
+    "answer": "53 个;够",
+    "solution": "【分析】根据题意，把送给星星小学的数量和送给博爱小学的数量相加，即可求出博物馆机器人模型少的数量;用博物馆机器人模型总的数量减去博物馆少的数量，即可求出博物馆剩下的数量，再与实验小学需要的数量进行比较即可.\n【详解】26 + 27 = 53(个),90 - 53 = 37(个),37 > 36 或 36 < 37，答：博物馆机器人少了 53 个;实验小学需要 36 个，剩下的够。",
+    "knowledge_points": [
+      "100以内数的比大小",
+      "两位数与两位数的进位加法",
+      "两位数与两位数的退位减法"
+    ],
+    "source": "24-25 二年级上·山东临沂·期末"
+  },
+  {
+    "id": "284",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.85,
+    "question": "二年级学生要做 98 朵花送给幼儿园的小朋友，男生做了 39 朵花，女生做了 42 朵花，还差多少朵。",
+    "options": [],
+    "answer": "17 朵",
+    "solution": "【分析】用一共要做的花数量先减去男生做的数量，求出差，再减去女生做的数量，求出差，即可解决.\n【详解】98 - 39 - 42 = 59 - 42 = 17(朵),答：还差17朵。",
+    "knowledge_points": [
+      "100 以内数的连减运算"
+    ],
+    "source": "24-25 二年级上·河北保定·期末"
+  },
+  {
+    "id": "285",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.65,
+    "question": "抖音直播购物越来越受欢迎，张阿姨的抖音直播间也订单不断。张阿姨昨天上午接到36份订单，下午比上午多接了18份订单，下午接了多少份订单。张阿姨昨天一共接了多少份订单。",
+    "options": [],
+    "answer": "54 份;90 份",
+    "solution": "【分析】求比一个数多几的数是多少，用加法列式计算;故，用上午的订单数量加下午比上午多接的数量，求出和，就是下午接的订单数量。求两个数的和是多少，用加法列式计算;故，把上午的订单数量与下午的数量加起来，求出和，就是一共接了的订单数量.\n【详解】36 + 18 = 54(份),36 + 54 = 90(份),答：下午接了 54 份订单;张阿姨昨天一共接了 90 份订单。",
+    "knowledge_points": [
+      "两位数与两位数的进位加法"
+    ],
+    "source": "24-25 二年级上·甘肃庆阳·期末"
+  },
+  {
+    "id": "286",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.65,
+    "question": "妈妈包了 90 个饺子，还剩多少个。\n\n![](images/eadd812da7b8ec181eeda088efd7523f6948d27c3df26c3b7e10e93ad3dfdcc6.jpg)",
+    "options": [],
+    "answer": "50 个",
+    "solution": "【分析】求还剩多少个，用减法计算，即饺子的总数量 - 小女孩吃的数量 - 小男孩吃的数量 = 还剩的数量.\n【详解】90 - 18 - 22 = 50(个),答：还剩 50 个。",
+    "knowledge_points": [
+      "100以内数的连减运算"
+    ],
+    "source": "24-25 二年级上·甘肃庆阳·期末"
+  },
+  {
+    "id": "287",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.85,
+    "question": "下雪了，小明堆了两个雪人，一个雪人的高度是 45 厘米，另一个雪人比它高18 厘米，另一个雪人的高度是多少厘米。\n\n![](images/80df53cb283c5ebbb097f9b93154affa0a40a098381eabbfcad5e4f576bc024e.jpg)",
+    "options": [],
+    "answer": "63 厘米",
+    "solution": "【分析】根据题意可知：可根据求比一个数多几的数，用加法计算，用一个雪人的高度加上一个雪人比它高的高度即可.\n【详解】45 + 18 = 63(厘米),答：另一个雪人的高度是 63 厘米。",
+    "knowledge_points": [
+      "两位数与两位数的进位加法"
+    ],
+    "source": "24-25二年级上·山东日照·期末"
+  },
+  {
+    "id": "288",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.85,
+    "question": "我国发射的神舟七号飞船运载 3 名航天员绕地球飞行了 45 圈，神舟六号比它多飞了 31 圈，神舟六号绕地球飞行了多少圈。",
+    "options": [],
+    "answer": "76 圈",
+    "solution": "【分析】求比一个数多几的数是多少，用这个数 + 多的数计算，即神舟七号飞船绕地球飞行的圈数 + 神舟六号比它多飞的圈数 = 神舟六号绕地球飞行的圈数.\n【详解】45 + 31 = 76(圈),答：神舟六号绕地球飞行了 76 圈。",
+    "knowledge_points": [
+      "两位数与两位数的不进位加法"
+    ],
+    "source": "24-25 二年级上·广东江门·期末"
+  },
+  {
+    "id": "289",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.65,
+    "question": "茜茜拿 50 元买礼物，找回了29元。买这份礼物花了多少元钱。",
+    "options": [],
+    "answer": "21 元",
+    "solution": "【分析】根据减法的意义，茜茜拿的钱数 - 找回的钱数 = 买礼物花的钱数.\n【详解】50 - 29 = 21(元),答：买这份礼物花了21元钱。",
+    "knowledge_points": [
+      "两位数与两位数的退位减法",
+      "经济问题"
+    ],
+    "source": "24-25 二年级上·河北保定·期末"
+  },
+  {
+    "id": "290",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.65,
+    "question": "二(1)班图书角有科技书54本，借走了16本，后来又买回来30本。现在图书角有科技书多少本。",
+    "options": [],
+    "answer": "68 本",
+    "solution": "【分析】根据题意，借走的数量要减去，又买回来的数量要加上，则现在的数量 = 原有的数量 - 借走的数量 + 又买回来的数量.\n【详解】54 - 16 + 30 = 68(本),答：现在图书角有科技书 68 本。",
+    "knowledge_points": [
+      "100以内数的加减混合运算"
+    ],
+    "source": "24-25 二年级上·河北保定·期末"
+  },
+  {
+    "id": "291",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.85,
+    "question": "王老师买来两本书，一本故事书 38 元，另一本科技书比故事书贵 12 元.\n(1)科技书要多少元。(2)两本书共要多少元。",
+    "options": [],
+    "answer": "50 元;88 元",
+    "solution": "【分析】(1)根据题意可知：求比一个数多几的数，用加法计算，用故事书的价格加上科技书比故事书贵的价格，即可求出科技书要几元。(2)由(1)求出科技书的钱数加上故事书的钱数，即可求出两本书共要的钱数.\n【详解】(1)38 + 12 = 50(元),答：科技书要 50 元。(2)50 + 38 = 88(元),答：两本书共要88元。",
+    "knowledge_points": [
+      "两位数与整十数的加法",
+      "两位数与两位数的进位加法"
+    ],
+    "source": "23-24二年级上·浙江宁波·期末"
+  },
+  {
+    "id": "292",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.65,
+    "question": "学校合唱队有女生32人，比男生多 9 人，合唱队一共有学生多少人。",
+    "options": [],
+    "answer": "55 人",
+    "solution": "【分析】根据题意，已知一个数比另一个数多几，求另一个数，用减法计算，故先用女生人数减去9人，求出差，就是男生人数，然后加上女生人数，求出和，就是一共的人数.\n【详解】32 - 9 + 32 = 23 + 32 = 55(人),答：合唱队一共有学生 55 人。",
+    "knowledge_points": [
+      "100以内数的加减混合运算"
+    ],
+    "source": "23-24二年级上·河北保定·期末"
+  },
+  {
+    "id": "293",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.85,
+    "question": "一个书包 36 元，丽丽有 50 元，买了一个书包后还剩多少元。",
+    "options": [],
+    "answer": "14 元",
+    "solution": "【分析】用丽丽的钱数减去一个书包的价钱即可求出买了一个书包后还剩多少元.\n【详解】50 - 36 = 14(元),答：买了一个书包后还剩14元。",
+    "knowledge_points": [
+      "两位数与两位数的退位减法"
+    ],
+    "source": "23-24 二年级上·河北保定·期末"
+  },
+  {
+    "id": "294",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.85,
+    "question": "车上有 42 人，到站下车18人，又上车12人，现在车上有多少人。",
+    "options": [],
+    "answer": "36 人",
+    "solution": "【分析】先用车上原有的人数减去到站下车的人数，求出差，再加上又上车的人数，求出和，即可解决.\n【详解】42 - 18 + 12 = 24 + 12 = 36(人),答：现在车上有36人。",
+    "knowledge_points": [
+      "100以内数的加减混合运算"
+    ],
+    "source": "23-24 二年级上·浙江绍兴·期末"
+  },
+  {
+    "id": "295",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.65,
+    "question": "李奶奶家有鸭蛋 25 个，鸡蛋比鸭蛋多8个，鹅蛋比鸭蛋少12个。李奶奶家有鸡蛋多少个。鹅蛋有多少个。",
+    "options": [],
+    "answer": "33 个;13 个",
+    "solution": "【分析】已知鸭蛋有25个，鸡蛋比鸭蛋多8个，可用加法计算，鸭蛋加上鸡蛋比它多的8个，即可得出鸡蛋的数量;已知鹅蛋比鸭蛋少12个，可用减法计算，鸭蛋减去鹅蛋比它少的12个，即可得出鹅蛋的数量.\n【详解】25 + 8 = 33(个),25 - 12 = 13(个),答：李奶奶家有鸡蛋 33 个;鹅蛋有 13 个。",
+    "knowledge_points": [
+      "两位数与两位数的不退位减法",
+      "一位数与两位数的进位加法"
+    ],
+    "source": "23-24 二年级上·河南安阳·期末"
+  },
+  {
+    "id": "296",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.65,
+    "question": "育才小学有 32 名男教师,41 名女教师，一共有多少名教师。蓝天小学共有 42 名教师，比育才小学少多少名。",
+    "options": [],
+    "answer": "73 名;31 名",
+    "solution": "【分析】根据题意，用育才小学男教师的人数加上女教师的人数即可求出一共有多少名教师。用育才小学的总人数减去蓝天小学的总人数，即可求出蓝天小学比育才小学少多少名，据此解答.\n【详解】32 + 41 = 73(名),73 - 42 = 31(名),答：育才小学一共有73名教师，蓝天小学比育才小学少31名。",
+    "knowledge_points": [
+      "两位数与两位数的不退位减法",
+      "两位数与两位数的不进位加法"
+    ],
+    "source": "23-24 二年级上·山东菏泽·期末"
+  },
+  {
+    "id": "297",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.65,
+    "question": "在跳绳比赛中，小芳每分钟可以跳85个，小红每分钟比小芳少跳17个，小红每分钟跳多少个。",
+    "options": [],
+    "answer": "68 个",
+    "solution": "【分析】用小芳每分钟可以跳的个数减小红每分钟比小芳少跳的个数，即可求出小红每分钟跳多少个.\n【详解】85 - 17 = 68(个),答：小红每分钟跳 68 个。",
+    "knowledge_points": [
+      "两位数与两位数的退位减法"
+    ],
+    "source": "23-24 二年级上·河南郑州·期末"
+  },
+  {
+    "id": "298",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.65,
+    "question": "国庆假期第一天，天健湖公园迎来文旅小热潮。停车场原来有汽车64辆，开走了25辆，又开来32辆，现在停车场里有多少辆汽车。",
+    "options": [],
+    "answer": "71 辆",
+    "solution": "【分析】根据题意，开走的数量要减去，又开来的数量要加上，即原来的数量 - 开走的数量 + 又开来的数量 = 现在的数量.\n【详解】64 - 25 + 32 = 71(辆),答：现在停车场里有71辆汽车。",
+    "knowledge_points": [
+      "100以内数的加减混合运算"
+    ],
+    "source": "24-25 二年级上·河南南阳·期中"
+  },
+  {
+    "id": "299",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.85,
+    "question": "李阿姨在网上开了一个文具店，今天销售情况如下:\n\n铅笔 圆珠笔 毛笔\n35支 比铅笔多16支 比圆珠笔少22支\n\n(1)圆珠笔卖了多少支。\n(2)再提一个数学问题并解答。",
+    "options": [],
+    "answer": "51 支;毛笔卖了多少支。29 支(答案不唯一)",
+    "solution": "【分析】求比一个数多几的数是多少，用加法列式计算;求比一个数少几的数是多少，用减法列式计算。(1)铅笔有35支，用铅笔的数量加上16支，求出和，就是圆珠笔的数量。(2)根据已知条件提出数学问题，合理即可，但答案不唯一.\n【详解】(1)35 + 16 = 51(支),答：圆珠笔卖了51支。(2)毛笔卖了多少支。51 - 22 = 29(支),答：毛笔卖了29支。(答案不唯一)",
+    "knowledge_points": [
+      "两位数与两位数的进位加法",
+      "\"提问题\"\"填条件\"问题",
+      "两位数与两位数的退位减法"
+    ],
+    "source": "23-24 二年级上·河北保定·期末"
+  },
+  {
+    "id": "300",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.65,
+    "question": "小伟有 41 本故事书，小贝比小伟少 16 本，他们两人一共有多少本故事书。",
+    "options": [],
+    "answer": "66 本",
+    "solution": "【分析】求比一个数少几的数是多少，用这个数 - 少的数计算，即小伟故事书的数量 - 小贝比小伟少的数量 = 小贝故事书的数量，再加上小伟故事书的数量就是两人故事书的总数量.\n【详解】41 - 16 + 41 = 66(本),答：他们两人一共有 66 本故事书。",
+    "knowledge_points": [
+      "100以内数的加减混合运算"
+    ],
+    "source": "23-24 二年级上·广东韶关·期末"
+  },
+  {
+    "id": "301",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "选择题",
+    "difficulty": 0.5,
+    "question": "计算 40 - (15 - 2)时，先算( )。",
+    "options": [
+      "15 - 2",
+      "40 - 15",
+      "40 - 2"
+    ],
+    "answer": "A",
+    "solution": "【分析】只有加减法的混合运算，从左往右计算;若有括号，则先算括号里面的，再算括号外面的.\n【详解】由分析可知:40 -(15 - 2)= 40 - 13 = 27，计算40 -(15 - 2)时，先算15 - 2。故答案为:A",
+    "knowledge_points": [],
+    "source": ""
+  },
+  {
+    "id": "302",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "选择题",
+    "difficulty": 0.5,
+    "question": "下面算式中,( )的结果大于 70。",
+    "options": [
+      "98 - 29",
+      "98 - 15",
+      "48 + 19"
+    ],
+    "answer": "B",
+    "solution": "【分析】根据整数加减法的计算法则，依次计算出各算式的结果再和70比较大小。比较时，位数多的数就大;位数相同比较最高位，最高位大的数就大;最高位相同比较下一位，直到比较出结果为止.\n【详解】A。98 - 29 = 69;69 < 70，不符合题意;B。98 - 15 = 83;83 > 70，符合题意;C。48 + 19 = 67;67 < 70，不符合题意。所以98 - 15的结果大于 70。故答案为:B",
+    "knowledge_points": [],
+    "source": ""
+  },
+  {
+    "id": "303",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "选择题",
+    "difficulty": 0.5,
+    "question": "慧慧是个节俭的好孩子，这学期她存了43 元零花钱，玲玲存的比她少19 元，玲玲存了( )元。学校搞\"爱心捐款\"活动时，她们把自己存的钱都捐出去了，她俩一共捐了( )元。",
+    "options": [
+      "24,67",
+      "24,62",
+      "62,81"
+    ],
+    "answer": "A",
+    "solution": "【分析】已知慧慧存了 43 元，玲玲比她少 19 元，可用慧慧的钱数减去少的 19 元，即可得出玲玲存了多少钱;再把两个人的钱数相加即可得出她俩一共捐了多少钱.\n【详解】43 - 19 = 24(元),所以玲玲存了 24 元。43 + 24 = 67(元),她们俩一共捐了67 元。故答案为:A",
+    "knowledge_points": [],
+    "source": ""
+  },
+  {
+    "id": "304",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "选择题",
+    "difficulty": 0.5,
+    "question": "下面的算式中，先算加法，再算减法的是( )。",
+    "options": [
+      "85 - 36 + 24",
+      "45 +(52 - 28)",
+      "72 + 25 - 24"
+    ],
+    "answer": "C",
+    "solution": "【分析】根据整数加减法混合运算法则：有小括号的运算，先算小括号内的算式，再算括号外的计算，没有括号则按照从左往右的顺序依次计算即可。计算时要注意相同数位对齐，加法则从个位开始计算，满十则向前一位进 1;减法则从个位开始计算，当不够减时，则向高位借 1 当十，再进行计算.\n【详解】A。85 - 36 + 24，先算减法，再算加法;B。45 +(52 - 28),先算减法，再算加法;C。72 + 25 - 24，先算加法，再算减法。故答案为:C",
+    "knowledge_points": [],
+    "source": ""
+  },
+  {
+    "id": "305",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "选择题",
+    "difficulty": 0.5,
+    "question": "小明有 40 元钱，买故事书花了 28 元，还剩( )元。",
+    "options": [
+      "12",
+      "22",
+      "28"
+    ],
+    "answer": "A",
+    "solution": "【分析】求还剩多少元，用减法计算，即小明的钱数 - 买故事书花的钱数 = 还剩的钱数.\n【详解】40 - 28 = 12(元),还剩12元。故答案为:A",
+    "knowledge_points": [],
+    "source": ""
+  },
+  {
+    "id": "306",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "选择题",
+    "difficulty": 0.5,
+    "question": "小明有50 元钱，买故事书花了31 元，他还剩( )元。",
+    "options": [
+      "30",
+      "19",
+      "20"
+    ],
+    "answer": "B",
+    "solution": "【分析】用原有的钱减去买故事书花了的钱，求出差，就是还剩的钱.\n【详解】50 - 31 = 19(元),即，小明有 50 元钱，买故事书花了 31 元，他还剩 19 元。故答案为:B",
+    "knowledge_points": [],
+    "source": ""
+  },
+  {
+    "id": "307",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "选择题",
+    "difficulty": 0.5,
+    "question": "计算\"55 - 3□\"时,□里填( )时要退位。",
+    "options": [
+      "6,7,8 或 9",
+      "5",
+      "0,1,2,3 或 4"
+    ],
+    "answer": "A",
+    "solution": "【分析】当减数的个位数大于被减数的个位数时，个位上的数相减时要退位;则，当□ > 5，计算\"55 - 3□\"时要退位;据此解决.\n【详解】由题意分析得：大于 5 的数有:6,7,8,9;即，计算\"55 - 3□\",□里填(6,7,8或9)时要退位。故答案为:A",
+    "knowledge_points": [],
+    "source": ""
+  },
+  {
+    "id": "308",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "选择题",
+    "difficulty": 0.5,
+    "question": "哥哥有35本故事书，送给妹妹5本后，两人故事书的本数就一样多了，妹妹原来有( )本故事书。",
+    "options": [
+      "30",
+      "25",
+      "20"
+    ],
+    "answer": "B",
+    "solution": "【分析】根据题意可知，哥哥有 35 本故事书，送给妹妹 5 本后，这时哥哥还有(35 - 5)本;因为两人故事书的本数一样多，那么这时妹妹也有(35 - 5)本，再减去哥哥给的5本，就是妹妹原来的本数.\n【详解】35 - 5 - 5 = 30 - 5 = 25(本),则哥哥有35本故事书，送给妹妹5本后，两人故事书的本数就一样多了，妹妹原来有25本故事书。故答案为:B",
+    "knowledge_points": [],
+    "source": ""
+  },
+  {
+    "id": "309",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "选择题",
+    "difficulty": 0.5,
+    "question": "一根长60米的绳子，第一次剪去31米，第二次剪去26米，这根绳子比原来短了多少米。列式是( )。",
+    "options": [
+      "60 - 31 - 26",
+      "60 - 31 + 26",
+      "31 + 26"
+    ],
+    "answer": "C",
+    "solution": "【分析】已知第一次剪去 31 米，第二次剪去 26 米，求这根绳子比原来短了多少米，把两次剪去的长度相加即可得出答案.\n【详解】据分析可得:31 + 26，即可算出比原来短了多少米。故答案为:C",
+    "knowledge_points": [],
+    "source": ""
+  },
+  {
+    "id": "310",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "选择题",
+    "difficulty": 0.5,
+    "question": "一个笔袋15 元，一支钢笔8 元，小明付了50 元，找回( )元。",
+    "options": [
+      "35",
+      "23",
+      "27"
+    ],
+    "answer": "C",
+    "solution": "【分析】已知一个笔袋15 元，一支钢笔8 元，相加即可得出一共花了多少钱，再用50 元减去花的金额即可.\n【详解】15 + 8 = 23(元),50 - 23 = 27(元),一共花了 23 元，找回了 27 元。故答案为:C",
+    "knowledge_points": [],
+    "source": ""
+  },
+  {
+    "id": "311",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "选择题",
+    "difficulty": 0.5,
+    "question": "下面三个算式，得数一定大于 60 的是( )。",
+    "options": [
+      "25 + 36 - 5",
+      "54 + 12 + 2",
+      "81 - 16 - 15"
+    ],
+    "answer": "B",
+    "solution": "【分析】将选项中的算式计算出结果，再与 60 进行比较，计算时按照相同数位对齐，从个位算起。加法时，满十进一;减法时，哪一位上不够减，向前一位借一当十，从左向右依次进行计算.\n【详解】A。25 + 36 - 5 = 56,56 小于60，不符合题意;B。54 + 12 + 2 = 68,68 大于60，符合题意;C。81 - 16 - 15 = 50,50 小于60，不符合题意。故答案为:B",
+    "knowledge_points": [],
+    "source": ""
+  },
+  {
+    "id": "312",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "选择题",
+    "difficulty": 0.5,
+    "question": "河里原来有32只鸭子，游走了15只，又游来了9只。河里现在的鸭子数与原来的鸭子数相比,( )。",
+    "options": [
+      "与原来同样多",
+      "比原来多了",
+      "比原来少了"
+    ],
+    "answer": "C",
+    "solution": "【分析】根据题意，游走的数量要减去，又游来的数量要加上，则原来的数量 - 游走的数量 + 又游来的数量 = 现在的数量，再和原来的数量比较大小。现在的数量小于原来的数量就是比原来少了;现在的数量等于原来的数量就是与原来同样多;现在的数量大于原来的数量就是比原来多了。比较时，位数多的数就大;位数相同比较最高位，最高位大的数就大;最高位相同比较下一位，直到比较出结果为止.\n【详解】32 - 15 + 9 = 26(只),26 < 32，河里现在的鸭子数与原来的鸭子数相比，比原来少了。故答案为:C",
+    "knowledge_points": [],
+    "source": ""
+  },
+  {
+    "id": "313",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "选择题",
+    "difficulty": 0.5,
+    "question": "下面算式中得数最接近 50 的是( )。",
+    "options": [
+      "10 + 39",
+      "74 - 17",
+      "51 - 8"
+    ],
+    "answer": "A",
+    "solution": "【分析】根据题意，依次计算出各算式的结果，再和 50 作差，比较差的大小，差越小越接近 50.\n【详解】A。10 + 39 = 49;50 - 49 = 1;B。74 - 17 = 57;57 - 50 = 7;C。51 - 8 = 43;50 - 43 = 7;7 = 7 > 1，则得数最接近50 的是 10 + 39。故答案为:A",
+    "knowledge_points": [],
+    "source": ""
+  },
+  {
+    "id": "314",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "选择题",
+    "difficulty": 0.5,
+    "question": "一根竹竿插入水中，水面以上部分是54 厘米，水面以下部分是46 厘米，这根竹竿长( )。",
+    "options": [
+      "90 厘米",
+      "1 米",
+      "100 米"
+    ],
+    "answer": "B",
+    "solution": "【分析】根据加法的意义，水面以上部分的长度 + 水面以下部分的长度 = 竹竿的总长度，根据1 米 = 100 厘米换算单位即可.\n【详解】54 + 46 = 100(厘米),100 厘米 = 1 米，这根竹竿长1 米。故答案为:B",
+    "knowledge_points": [],
+    "source": ""
+  },
+  {
+    "id": "315",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "填空题",
+    "difficulty": 0.5,
+    "question": "直尺上从刻度 3 到刻度 9 是( )厘米。被减数是 57，减数是 34，差是( )。",
+    "options": [],
+    "answer": "6;23",
+    "solution": "【分析】尺子测量物体时应将0 刻度移动到被测物体的边缘，将直尺与被测物体重合，再观察被测物体另一端的刻度即可。当0刻度与被测物体的边缘不对齐时，用末端的刻度值减去开始的刻度值即可。根据被减数 - 减数 = 差即可解答.\n【详解】9 - 3 = 6(厘米),57 - 34 = 23。",
+    "knowledge_points": [],
+    "source": ""
+  },
+  {
+    "id": "316",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "填空题",
+    "difficulty": 0.5,
+    "question": "比 80 大 15 的数是( ),15 比 80 少( )。",
+    "options": [],
+    "answer": "95;65",
+    "solution": "【分析】求比 80 大 15 的数是多少，用加法列式计算;求 15 比 80 少多少，用减法列式计算.\n【详解】80 + 15 = 95,80 - 15 = 65，比 80 大 15 的数是 95,15 比 80 少 65。",
+    "knowledge_points": [],
+    "source": ""
+  },
+  {
+    "id": "317",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "填空题",
+    "difficulty": 0.5,
+    "question": "我们在口算 25 + 12 时，先想 20 +( )=( ),再想( )+ 2 =( ),最后想( )+( )=( )。",
+    "options": [],
+    "answer": "10;30;5;7;30;7;37",
+    "solution": "【分析】加法计算时，相同数位对齐，从个位加起，个位和个位相加，十位和十位相加，最后将两个得数相加即可.\n【详解】我们在口算 25 + 12 时，先想 20 + 10 = 30，再想 5 + 2 = 7，最后想 30 + 7 = 37。",
+    "knowledge_points": [],
+    "source": ""
+  },
+  {
+    "id": "318",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "填空题",
+    "difficulty": 0.5,
+    "question": "一本书共有 98 页，明明第一天读了 26 页，第二天读了 19 页，第三天从第( )页开始读。",
+    "options": [],
+    "answer": "46",
+    "solution": "【分析】这是一个关于加法运算的问题。我们要把前两天读的页数加起来，再加上1 页，就是第三天开始读的页数，这本书一共有 98 页，是干扰性的题干，不用即可，据此解答.\n【详解】根据分析可列式:26 + 19 + 1 = 45 + 1 = 46(页),所以，第三天从第46 页开始读。",
+    "knowledge_points": [],
+    "source": ""
+  },
+  {
+    "id": "319",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "填空题",
+    "difficulty": 0.5,
+    "question": "比 74 少 17 的数是( ),比 45 多 38 的数是( )。",
+    "options": [],
+    "answer": "57;83",
+    "solution": "【分析】求比一个数少几的数是多少，用减法列式计算;求比一个数多几的数是多少，用加法列式计算;据此解决.\n【详解】由题意分析得:74 - 17 = 57,45 + 38 = 83，即，比 74 少 17 的数是 57，比 45 多 38 的数是 83。",
+    "knowledge_points": [],
+    "source": ""
+  },
+  {
+    "id": "320",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "填空题",
+    "difficulty": 0.5,
+    "question": "比 59 多 37 的数是( ),比 72 少 39 的数是( )。",
+    "options": [],
+    "answer": "96;33",
+    "solution": "【分析】求比一个数多几的数是多少，用这个数 + 多的数计算;求比一个数少几的数是多少，用这个数 - 少的数计算.\n【详解】59 + 37 = 96;72 - 39 = 33，比59多37的数是96，比72少39的数是33。",
+    "knowledge_points": [],
+    "source": ""
+  },
+  {
+    "id": "321",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "填空题",
+    "difficulty": 0.5,
+    "question": "比 47 多 28 的数是( ),比 92 少 56 的数是( )。",
+    "options": [],
+    "answer": "75;36",
+    "solution": "【分析】求比一个数多几的数是多少，用这个数 + 多的数计算;求比一个数少几的数是多少，用这个数 - 少的数计算.\n【详解】47 + 28 = 75;92 - 56 = 36，比 47 多 28 的数是 75，比 92 少 56 的数是 36。",
+    "knowledge_points": [],
+    "source": ""
+  },
+  {
+    "id": "322",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "填空题",
+    "difficulty": 0.5,
+    "question": "计算 76 -(37 + 17),先算( )法，再算( )法，结果是( )。",
+    "options": [],
+    "answer": "加;减;22",
+    "solution": "【分析】只有加减法的混合运算，从左往右计算，若有括号，则先算括号里面的，再算括号外面的，由此解答.\n【详解】![](images/2026-02-11%20232523.jpg)\n\n计算 76 - (37 + 17),先算加法，再算减法，结果是 22。",
+    "knowledge_points": [],
+    "source": ""
+  },
+  {
+    "id": "323",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "填空题",
+    "difficulty": 0.5,
+    "question": "比 52 多 18 的数是( );( )比 63 少 24。",
+    "options": [],
+    "answer": "70;39",
+    "solution": "【分析】求比一个数多几的数是多少，用这个数 + 多的数计算;求比一个数少几的数是多少，用这个数 - 少的数计算.\n【详解】52 + 18 = 70;63 - 24 = 39，比 52 多 18 的数是 70;39 比 63 少 24。",
+    "knowledge_points": [],
+    "source": ""
+  },
+  {
+    "id": "324",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "填空题",
+    "difficulty": 0.5,
+    "question": "80 厘米 - 45 厘米 =( )厘米;1 米 - 38 厘米 =( )厘米",
+    "options": [],
+    "answer": "35;62",
+    "solution": "【分析】根据1 米 = 100 厘米将单位换算统一，然后计算.\n【详解】80 厘米 - 45 厘米 = 35 厘米。1 米 = 100 厘米，则1 米 - 38 厘米 = 100 厘米 - 38 厘米 = 62 厘米。",
+    "knowledge_points": [],
+    "source": ""
+  },
+  {
+    "id": "325",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "填空题",
+    "difficulty": 0.5,
+    "question": "在括号里填上\">\"\"<\"或\"=\".\n\n24 + 47( )72;72 - 26( )50 - 4;2 米( )20 厘米\n\n28( )80 - 62;68 + 18( )90 - 23;40 厘米( )1 米 - 70 厘米",
+    "options": [],
+    "answer": "<;=;>;>;>;>",
+    "solution": "【分析】根据整数加减法的计算法则，依次计算出各算式的结果再比较大小。比较时，位数多的数就大;位数相同比较最高位，最高位大的数就大;最高位相同比较下一位，直到比较出结果为止。长度单位的题目根据 1 米 = 100 厘米统一单位再比较.\n【详解】24 + 47 = 71,71 < 72，则 24 + 47 < 72;72 - 26 = 46,50 - 4 = 46,46 = 46，则 72 - 26 = 50 - 4;1 米 = 100 厘米,2 米 = 200 厘米,200 厘米 > 20 厘米，则2 米 > 20 厘米;80 - 62 = 18,28 > 18，则 28 > 80 - 62;68 + 18 = 86,90 - 23 = 67,86 > 67，则 68 + 18 > 90 - 23;1 米 - 70 厘米 = 100 厘米 - 70 厘米 = 30 厘米,40 厘米 > 30 厘米，则40 厘米 > 1 米 - 70 厘米。",
+    "knowledge_points": [],
+    "source": ""
+  },
+  {
+    "id": "326",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "填空题",
+    "difficulty": 0.5,
+    "question": "比 36 多 16 的数是( ),( )比 45 少 18。",
+    "options": [],
+    "answer": "52;27",
+    "solution": "【分析】求比一个数多几的数是多少，用这个数 + 多的数计算;求比一个数少几的数是多少，用这个数 - 少的数计算.\n【详解】36 + 16 = 52;45 - 18 = 27，比 36 多 16 的数是 52,27 比 45 少 18。",
+    "knowledge_points": [],
+    "source": ""
+  },
+  {
+    "id": "327",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "填空题",
+    "difficulty": 0.5,
+    "question": "一根绳子原来长 80 米，第一次用去 16 米，第二次用去 24 米，两次一共用去( )米，还剩( )米。",
+    "options": [],
+    "answer": "40;40",
+    "solution": "【分析】据题意，第一次用去16 米，第二次用去24 米，相加即可得出两次一共用去多少米;用总的米数减去用去的米数即可得出还剩多少米.\n【详解】16 + 24 = 40(米),80 - 40 = 40(米),一根绳子原来长 80 米，第一次用去 16 米，第二次用去 24 米，两次一共用去40米，还剩40米。",
+    "knowledge_points": [],
+    "source": ""
+  },
+  {
+    "id": "328",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "填空题",
+    "difficulty": 0.5,
+    "question": "计算 75 - (16 + 5)时，应先算( )法，再算( )法，结果是( )。",
+    "options": [],
+    "answer": "加;减;54",
+    "solution": "【分析】有小括号的加减混合运算，应先算括号里面的，再算括号外面的，据此解答.\n【详解】75 -(16 + 5)= 75 - 21 = 54，计算75 -(16 + 5)时，应先算加法，再算减法，结果是54。",
+    "knowledge_points": [],
+    "source": ""
+  },
+  {
+    "id": "329",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "填空题",
+    "difficulty": 0.5,
+    "question": "48 比 9 大( ),56 比 74 小( )。",
+    "options": [],
+    "answer": "39;18",
+    "solution": "【分析】根据题意可知：求一个数比一个数大几，用减法计算即可。求一个数比一个数少几，用减法计算即可.\n【详解】48 - 9 = 39,74 - 56 = 18，则 48 比 9 大 39,56 比 74 小 18。",
+    "knowledge_points": [],
+    "source": ""
+  },
+  {
+    "id": "330",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "填空题",
+    "difficulty": 0.5,
+    "question": "买一个书包要38 元，一个水杯要29 元，买这两样东西要( )元。付出100 元，应找回( )元。",
+    "options": [],
+    "answer": "67;33",
+    "solution": "【分析】将两样东西的价钱相加，即可求出买这两样东西要多少元。用100 元减去买这两样东西要的钱数，即可求出应找回多少元.\n【详解】38 + 29 = 67(元),100 - 67 = 33(元),买这两样东西要67 元。付出100 元，应找回33 元。",
+    "knowledge_points": [],
+    "source": ""
+  },
+  {
+    "id": "331",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "填空题",
+    "difficulty": 0.5,
+    "question": "二年级组织跳绳比赛，闹闹跳了98 个，欢欢跳的比闹闹少14 个，菲菲跳的比欢欢多6 个，菲菲跳了( )个。",
+    "options": [],
+    "answer": "90",
+    "solution": "【分析】根据题意，用闹闹跳的数量减去 14 即可求出欢欢跳的数量，欢欢跳的数量加 6 即可求出菲菲跳了多少个，列式计算.\n【详解】98 - 14 + 6 = 84 + 6 = 90(个),二年级组织跳绳比赛，闹闹跳了 98 个，欢欢跳的比闹闹少 14 个，菲菲跳的比欢欢多 6 个，菲菲跳了 90 个。",
+    "knowledge_points": [],
+    "source": ""
+  },
+  {
+    "id": "332",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "填空题",
+    "difficulty": 0.5,
+    "question": "比 37 多 26 的数是( ),比 80 少 9 的数是( )。",
+    "options": [],
+    "answer": "63;71",
+    "solution": "【分析】求比一个数多几的数是多少，用这个数 + 多的数计算;求比一个数少几的数是多少，用这个数 - 少的数计算.\n【详解】37 + 26 = 63;80 - 9 = 71，比 37 多 26 的数是 63，比 80 少 9 的数是 71。",
+    "knowledge_points": [],
+    "source": ""
+  },
+  {
+    "id": "333",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "填空题",
+    "difficulty": 0.5,
+    "question": "比 28 多 12 的数是( ),46 比( )少 23。",
+    "options": [],
+    "answer": "40;69",
+    "solution": "【分析】求比一个数多几的数是多少，用这个数 + 多的数计算;已知一个数比另一个数少几，求另一个数，用这个数 + 少的数计算.\n【详解】28 + 12 = 40,46 + 23 = 69，比 28 多 12 的数是 40,46 比 69 少 23。",
+    "knowledge_points": [],
+    "source": ""
+  },
+  {
+    "id": "334",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "填空题",
+    "difficulty": 0.5,
+    "question": "7□ - 4□ 的差最大是( );7□ - 4□ 的差最小是( )。",
+    "options": [],
+    "answer": "39;21",
+    "solution": "【分析】要使7□ - 4□ 的差最大，那么被减数要尽可能大，减数要尽可能小。被减数是7□,要使其最大，个位上的数字应取最大的一位数 9，所以被减数为 79。减数是4□,要使其最小，个位上的数字应取最小的一位数 0，所以减数为 40。根据\"被减数 - 减数 = 差\"求出差即可。要使7□ - 4□ 的差最小，那么被减数要尽可能小，减数要尽可能大。被减数是7□,要使其最小，个位上的数字应取最小的一位数 0，所以被减数为 70。减数是4□,要使其最大，个位上的数字应取最大的一位数 9，所以减数为 49。根据\"被减数 - 减数 = 差\"求出差即可.\n【详解】79 - 40 = 39,70 - 49 = 21,7□ - 4□ 的差最大是39;7□ - 4□ 的差最小是21。",
+    "knowledge_points": [],
+    "source": ""
+  },
+  {
+    "id": "335",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "填空题",
+    "difficulty": 0.5,
+    "question": "公交车上原来有 21 人，中途下车了 12 人，又上车了 15 人，现在车上有( )人。",
+    "options": [],
+    "answer": "24",
+    "solution": "【分析】根据题意，下车的人数要减去，上车的人数要加上，即原有的人数 - 下车的人数 + 又上车的人数 = 现在的人数.\n【详解】21 - 12 + 15 = 24(人),公交车上原来有 21 人，中途下车了 12 人，又上车了 15 人，现在车上有 24 人。",
+    "knowledge_points": [],
+    "source": ""
+  },
+  {
+    "id": "336",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "填空题",
+    "difficulty": 0.5,
+    "question": "一根电线用去 38 米，还有 44 米。这根电线原来长( )米。",
+    "options": [],
+    "answer": "82",
+    "solution": "【分析】求电线原来的长度，用加法计算，即用去的长度 + 还有的长度 = 原来的长度.\n【详解】38 + 44 = 82(米),一根电线用去38 米，还有44 米。这根电线原来长82米。",
+    "knowledge_points": [],
+    "source": ""
+  },
+  {
+    "id": "337",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "填空题",
+    "difficulty": 0.5,
+    "question": "一个水瓶25 元，小明有19 元，他还差( )元才可以买一个水瓶。",
+    "options": [],
+    "answer": "6",
+    "solution": "【分析】根据减法的意义，水瓶的价钱 - 小明有的钱数 = 要买一个水瓶小明还差的钱数。代入数据即可得解.\n【详解】25 - 19 = 6(元),一个水瓶25 元，小明有19 元，他还差6元才可以买一个水瓶。",
+    "knowledge_points": [],
+    "source": ""
+  },
+  {
+    "id": "338",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "填空题",
+    "difficulty": 0.5,
+    "question": "宁宁做一道减法题时，将减数 34 看成了 43，求出的差是 18，正确的差应该是( )。",
+    "options": [],
+    "answer": "27",
+    "solution": "【分析】差 + 减数 = 被减数，用18 加43 算出正确的被减数，然后用正确的被减数减去正确的减数，即可得到正确的差.\n【详解】18 + 43 = 61,61 - 34 = 27，正确的差应该是 27。",
+    "knowledge_points": [],
+    "source": ""
+  },
+  {
+    "id": "339",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "填空题",
+    "difficulty": 0.5,
+    "question": "安安有64 元钱，果果有50 元钱，安安比果果多( )元钱;安安给果果( )元钱后，两人的钱就同样多。",
+    "options": [],
+    "answer": "14;7",
+    "solution": "【分析】已知安安有64 元，果果有50 元，用安安的钱数减去果果的钱数，即可得出安安比果果多几元;根据安安比果果多的钱数，分成相同的两部分，分别分给安安和果果即可.\n【详解】64 - 50 = 14(元);14 平均分成 7 和 7。安安有64 元钱，果果有50 元钱，安安比果果多14 元钱，安安给果果7 元钱后，两人的钱就同样多。",
+    "knowledge_points": [],
+    "source": ""
+  },
+  {
+    "id": "340",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "填空题",
+    "difficulty": 0.5,
+    "question": "比 37 多 18 的数是( );( )比 72 少 25。",
+    "options": [],
+    "answer": "55;47",
+    "solution": "【分析】求比一个数多几的数是多少，用这个数 + 多的数计算;求比一个数少几的数是多少，用这个数 - 少的数计算.\n【详解】37 + 18 = 55,72 - 25 = 47，比 37 多 18 的数是 55;47 比 72 少 25。",
+    "knowledge_points": [],
+    "source": ""
+  },
+  {
+    "id": "341",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "填空题",
+    "difficulty": 0.5,
+    "question": "比 24 多 58 的数是( ),60 比 29 多( ),( )比 35 少 17。",
+    "options": [],
+    "answer": "82;31;18",
+    "solution": "【分析】根据题意，比 24 多 58 的数是多少，用加法计算,60 比 29 多多少，用减法计算，几比35 少17，用减法计算，据此解答.\n【详解】根据分析:24 + 58 = 82,60 - 29 = 31,35 - 17 = 18，比 24 多 58 的数是 82,60 比 29 多 31,18 比 35 少 17。",
+    "knowledge_points": [],
+    "source": ""
+  },
+  {
+    "id": "342",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "填空题",
+    "difficulty": 0.5,
+    "question": "比 78 多 14 的数是( ),16 比 53 少( )。",
+    "options": [],
+    "answer": "92;37",
+    "solution": "【分析】求比一个数多多少的数用加法计算;求一个数比另一个数少多少用减法计算.\n【详解】78 + 14 = 92,53 - 16 = 37，比 78 多 14 的数是 92,16 比 53 少 37。",
+    "knowledge_points": [],
+    "source": ""
+  },
+  {
+    "id": "343",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "填空题",
+    "difficulty": 0.5,
+    "question": "计算 82 - 43 + 25时，应先算( )法，再算( )法，结果为( )。",
+    "options": [],
+    "answer": "减;加;64",
+    "solution": "【分析】加减法混合运算的计算顺序是从左向右依次计算.\n【详解】82 - 43 + 25 = 39 + 25 = 64，计算 82 - 43 + 25 时，应先算减法，再算加法，结果为64。",
+    "knowledge_points": [],
+    "source": ""
+  },
+  {
+    "id": "344",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "填空题",
+    "difficulty": 0.5,
+    "question": "比 35 多 47 的数是( ),( )比 54 少 18。",
+    "options": [],
+    "answer": "82;36",
+    "solution": "【分析】根据题意可知：求比一个数多几的数，用加法计算;求比一个数少几的数，用减法计算.\n【详解】35 + 47 = 82;54 - 18 = 36，则比 35 多 47 的数是 82,36 比 54 少 18。",
+    "knowledge_points": [],
+    "source": ""
+  },
+  {
+    "id": "345",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "填空题",
+    "difficulty": 0.5,
+    "question": "24 米 + 8 米 =( )米;1 米 - 20 厘米 =( )厘米",
+    "options": [],
+    "answer": "32;80",
+    "solution": "【分析】根据1 米 = 100 厘米将单位换算统一，然后再计算.\n【详解】24 米 + 8 米 = 32 米,1米 - 20厘米 = 100 厘米 - 20厘米 = 80 厘米。",
+    "knowledge_points": [],
+    "source": ""
+  },
+  {
+    "id": "346",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "填空题",
+    "difficulty": 0.5,
+    "question": "今年爷爷 65 岁，爸爸 38 岁,5 年前爷爷比爸爸大( )岁。",
+    "options": [],
+    "answer": "27",
+    "solution": "【分析】根据年龄差不变可知，今年爷爷比爸爸大几岁,5 年前爷爷比爸爸还是大几岁，则用爷爷今年的年龄 - 爸爸今年的年龄 = 爷爷比爸爸大的岁数.\n【详解】65 - 38 = 27(岁),5 年前爷爷比爸爸大27岁。",
+    "knowledge_points": [],
+    "source": ""
+  },
+  {
+    "id": "347",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "填空题",
+    "difficulty": 0.5,
+    "question": "( )比 48 多 15，比 70 少 18 的数是( )。",
+    "options": [],
+    "answer": "63;52",
+    "solution": "【分析】求比 48 多 15 的数，用加法计算;求比 70 少 18 的数是多少，用减法计算.\n【详解】48 + 15 = 63,70 - 18 = 52,63 比 48 多 15，比 70 少 18 的数是 52。",
+    "knowledge_points": [],
+    "source": ""
+  },
+  {
+    "id": "348",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "填空题",
+    "difficulty": 0.5,
+    "question": "比 76 少 40 的数是( ),( )比 16 多 18。",
+    "options": [],
+    "answer": "36;34",
+    "solution": "【分析】据题意，比 76 少 40 的数，用减法计算，即 76 减 40 即可得出答案，比 16 多 18 的数，可用加法计算，即16 加18 即可得出答案.\n【详解】76 - 40 = 36;16 + 18 = 34，比76少40的数是36,34比16多18。",
+    "knowledge_points": [],
+    "source": ""
+  },
+  {
+    "id": "349",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "判断题",
+    "difficulty": 0.5,
+    "question": "88 比 99 少 10。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】求一个数比另一个数少几，用另一个数 - 这个数计算.\n【详解】99 - 88 = 11,88 比99 少11。原题说法错误。故答案为: ×",
+    "knowledge_points": [],
+    "source": ""
+  },
+  {
+    "id": "350",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "判断题",
+    "difficulty": 0.5,
+    "question": "我们在进行竖式计算时，要注意相同数位对齐。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】本题根据竖式计算的法则来解答即可。加法：相同数位对齐，从个位算起，哪一位相加满十，向前一位进1。减法：相同数位对齐，从个位算起，哪一位不够减，从前一位退1 作十计算。由此解答.\n【详解】由分析可知，我们在进行竖式计算时，要注意相同数位对齐。原题说法正确。例如:25 + 27 = 52;50 - 28 = 22\n![](images/2026-02-13%20203422.jpg)\n故答案为:√",
+    "knowledge_points": [],
+    "source": ""
+  },
+  {
+    "id": "351",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "判断题",
+    "difficulty": 0.5,
+    "question": "34 - 2 - 11 和 34 -(2 + 11)的计算结果和计算顺序都相同。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】整数混合运算法则：有小括号的先算小括号中的，再算括号外的;同级运算的，按照从左到右的顺序依次计算。计算出各算式的答案，然后进行比较即可.\n【详解】34 - 2 - 11 = 32 - 11 = 21;34 - (2 + 11) = 34 - 13 = 21;21 = 21，则 34 - 2 - 11 和 34 -(2 + 11)的计算结果相同，计算顺序不相同，则原题说法错误。故答案为: ×",
+    "knowledge_points": [],
+    "source": ""
+  },
+  {
+    "id": "352",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "判断题",
+    "difficulty": 0.5,
+    "question": "在算式 70 - 60 - 6 中，可以先算 60 - 6。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】没有小括号的加减混合运算，按从左向右顺序依次计算。70 - 60 - 6中，从左向右依次计算，即先算 70 - 60 = 10，再算 10 - 6 = 4.\n【详解】由分析可得：在算式70 - 60 - 6 中，可以先算 70 - 60。原题说法错误。故答案为: ×",
+    "knowledge_points": [],
+    "source": ""
+  },
+  {
+    "id": "353",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "计算题",
+    "difficulty": 0.5,
+    "question": "38 减去19，再加上38，和是多少。",
+    "options": [],
+    "answer": "38 - 19 + 38 = 57",
+    "solution": "【分析】根据题意，先用减法计算出 38 减去 19 的差，再用这个差加上 38，计算出它们的和即可.\n【详解】38 - 19 + 38 = 57,38 减去 19，再加上 38，和是 57。",
+    "knowledge_points": [],
+    "source": ""
+  },
+  {
+    "id": "354",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "计算题",
+    "difficulty": 0.5,
+    "question": "看图列算式.\n\n![](images/8a8075ac97b1d15d67ce15acade49ae15fa36b2f906280af88f5cd08481d3328.jpg)\n\n□ ○ □ = □(个)",
+    "options": [],
+    "answer": "36 + 45 = 81",
+    "solution": "【分析】左边筐里有36 个，右边筐里有45 个，求一共有多少个，用加法计算，即左边筐里的数量 + 右边筐里的数量 = 总数量.\n【详解】36 + 45 = 81(个),一共有81 个。",
+    "knowledge_points": [],
+    "source": ""
+  },
+  {
+    "id": "355",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "计算题",
+    "difficulty": 0.5,
+    "question": "看图列式.\n\n![](images/a9d6db66e5105278d4e69d558f5ca609a3914e4ae1d567b9ae76284785d016f8.jpg)\n\n□ ○ □ ○ □ = □(元)",
+    "options": [],
+    "answer": "43 - 15 + 43 = 71",
+    "solution": "【分析】由题可知，一双鞋43 元，一副手套比一双鞋少15 元，求一双鞋和一副手套一共多少元。先用一双鞋的钱数减去一副手套比一双鞋少的钱数，求出一副手套多少钱，再和一双鞋的钱数相加，就是总钱数.\n【详解】43 - 15 + 43 = 71(元),一双鞋和一副手套一共71元。",
+    "knowledge_points": [],
+    "source": ""
+  },
+  {
+    "id": "356",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "计算题",
+    "difficulty": 0.5,
+    "question": "看图列式计算.\n\n![](images/95a435908414526febe5a0593791eb2bc2b8af5a6734b61d720a8d93ba92df59.jpg)\n\n□ ○ □ ○ □ = □(元)",
+    "options": [],
+    "answer": "28 + 36 + 34 = 98",
+    "solution": "【分析】根据图片可知：求一共多少钱。用裤子的钱数加裙子的钱数再加鞋子的钱数即可.\n【详解】28 + 36 + 34 = 64 + 34 = 98(元)",
+    "knowledge_points": [],
+    "source": ""
+  },
+  {
+    "id": "357",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "计算题",
+    "difficulty": 0.5,
+    "question": "看图列式计算.\n\n![](images/967f7f8fe921db6442f70f469aac62e55dd6a69bd9eb517ab7cf271c49f094b9.jpg)\n\n□ ○ □ = □(元)",
+    "options": [],
+    "answer": "38 + 16 = 54",
+    "solution": "【分析】一个书包38 元，一本书16 元，求一共多少元，用加法计算，即书包的钱数 + 书的钱数 = 总钱数.\n【详解】38 + 16 = 54(元),一共54元。",
+    "knowledge_points": [],
+    "source": ""
+  },
+  {
+    "id": "358",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "计算题",
+    "difficulty": 0.5,
+    "question": "看图列式计算.\n\n![](images/3a6c66a5de9d3fb294ca6e715beef43cb67edf5345484c8934fe340d961beb92.jpg)\n\n□ ○ □ = □(个)",
+    "options": [],
+    "answer": "52 - 16 = 36",
+    "solution": "【分析】一共有52 个苹果，右边有16 个，求左边筐里有多少个，用减法计算，即总数量 - 右边的数量 = 左边筐里的数量.\n【详解】52 - 16 = 36(个),左边筐里有36个。",
+    "knowledge_points": [],
+    "source": ""
+  },
+  {
+    "id": "359",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.5,
+    "question": "二年级参加舞蹈社团的同学有34 人，比绘画社团的同学多15 人，二年级参加社团活动的同学一共有多少人。",
+    "options": [],
+    "answer": "53 人",
+    "solution": "【分析】用舞蹈社团的人数减去15 人，求出差，就是绘画社团的人数，再加上舞蹈社团人数，求出和，即可解决.\n【详解】34 - 15 + 34 = 19 + 34 = 53(人),答：二年级参加社团活动的同学一共有53人。",
+    "knowledge_points": [],
+    "source": ""
+  },
+  {
+    "id": "360",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.5,
+    "question": "二(1)班图书角有73本书，借出45本书，还回19本书，图书角现在有多少本书。",
+    "options": [],
+    "answer": "47 本",
+    "solution": "【分析】根据加，减法的意义，用图书角原有的书的本数减去借出的书的本数，再加上还回的书的本数即可求出图书角现在有的书的本数，据此解答即可.\n【详解】73 - 45 + 19 = 28 + 19 = 47(本),答：图书角现在有47本书。",
+    "knowledge_points": [],
+    "source": ""
+  },
+  {
+    "id": "361",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.5,
+    "question": "一根绳子长80米，第一次用去41米，第二次用去的比第一次少13米，第二次用去多少米。",
+    "options": [],
+    "answer": "28 米",
+    "solution": "【分析】根据减法的意义，用第一次用去的长度减去第二次比第一次少用去的长度，即可求出第二次用去的长度，据此解答即可.\n【详解】41 - 13 = 28(米),答：第二次用去28米。",
+    "knowledge_points": [],
+    "source": ""
+  },
+  {
+    "id": "362",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.5,
+    "question": "卓玛今年 17 岁，爸爸今年 45 岁，过 10 年后，爸爸比卓玛大多少岁。",
+    "options": [],
+    "answer": "28 岁",
+    "solution": "【分析】两个人的年龄差是不变的，用爸爸今年的年龄减去卓玛今年的年龄，求出差，就是过10 年后，爸爸比卓玛大多少岁.\n【详解】45 - 17 = 28(岁),答：爸爸比卓玛大28岁。",
+    "knowledge_points": [],
+    "source": ""
+  },
+  {
+    "id": "363",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.5,
+    "question": "二(1)班有 27 幅画，二(2)班有 36 幅画，将这些画贴在走廊里，已经贴了 45 幅，还没贴的有多少幅。",
+    "options": [],
+    "answer": "18 幅",
+    "solution": "【分析】将1 班和2 班的画的数量相加，先求出需要贴的画一共有多少幅，再减去已经贴了的45 幅，即可得出还有多少幅没贴.\n【详解】27 + 36 - 45 = 63 - 45 = 18(幅),答：还没贴的有18幅。",
+    "knowledge_points": [],
+    "source": ""
+  },
+  {
+    "id": "364",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.5,
+    "question": "阅览室里上午有75 人，中午走了36 人，下午又来了27 人，阅览室里下午有多少人。",
+    "options": [],
+    "answer": "66 人",
+    "solution": "【分析】用上午的人数减中午走的人数，再加下午又来了的人数即可求出阅览室里下午有多少人.\n【详解】75 - 36 + 27 = 66(人),答：阅览室里下午有66人。",
+    "knowledge_points": [],
+    "source": ""
+  },
+  {
+    "id": "365",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.5,
+    "question": "![](images/58c5f37575af0265cbb2cf4860a6efb95e4439ad21e51f6509aecd8016aa7d80.jpg) 篮球35元\n\n![](images/c33d84a18f7b184001be3e030fbc9758c41950ceae6ea6dc7274de0706c4a517.jpg) 足球29元\n\n![](images/6b1f29ed823ba04b3c268f60edc8aad29b063b5a70ad8146d8826928367d0ef9.jpg) 排球48元\n\n(1)小明拿 100 元买了两种球，最多剩下多少元。\n(2)请你再提出一个数学问题，并尝试解答。",
+    "options": [],
+    "answer": "36 元;足球和排球各买一个一共需要多少钱。77 元(答案不唯一)",
+    "solution": "【分析】(1)先找出价钱最少的两种球，然后用100 元减去这两种球的价钱，求出差，就是最多剩下的钱。(2)根据已知条件提出，合理即可，答案不唯一.\n【详解】(1)48 > 35 > 29,100 - 35 - 29 = 65 - 29 = 36(元),答：最多剩下36元。(2)足球和排球各买一个，一共需要多少钱。29 + 48 = 77(元),答：一共需要77元钱。(答案不唯一)",
+    "knowledge_points": [],
+    "source": ""
+  },
+  {
+    "id": "366",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.5,
+    "question": "冬季运动会上，二年级一班3个同学拍球个数统计如下.\n\n<table><tr><td>姓名</td><td>第一次</td><td>第二次</td><td>第三次</td><td>总数</td></tr><tr><td>冬冬</td><td>25个</td><td>29个</td><td>。</td><td>81个</td></tr><tr><td>宁宁</td><td>25个</td><td>25个</td><td>33个</td><td>。</td></tr><tr><td>兰兰</td><td>26个</td><td>27个</td><td>。</td><td>。</td></tr></table>\n\n(1)冬冬第三次拍了多少个。\n(2)宁宁三次一共拍了多少个。\n(3)兰兰拍球的总数排第二(不考虑并列第二的情况),她拍球的总数是多少个。第三次拍了多少个。",
+    "options": [],
+    "answer": "27 个;83 个;82 个;29 个",
+    "solution": "【分析】(1)用总数减去第一次拍的个数，再减去第二次拍的个数即可求解。(2)将宁宁三次拍的数量相加即可求出宁宁三次一共拍了多少个。(3)兰兰拍的数量大于冬冬拍的数量，并且小于宁宁拍的数量，据此比较即可求出兰兰拍球的总数。用兰兰拍的总数减去兰兰第一次和第二次拍的个数即可求出兰兰第三次拍了多少个.\n【详解】(1)81 - 25 - 29 = 27(个),答：冬冬第三次拍了27个。(2)25 + 25 + 33 = 83(个),答：宁宁三次一共拍了83个。(3)81 < 82 < 83,82 - 26 - 27 = 29(个),答：兰兰拍球的总数是82个;第三次拍了29个。",
+    "knowledge_points": [],
+    "source": ""
+  },
+  {
+    "id": "367",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.5,
+    "question": "小华，小兰和小丽三人跳绳。小华跳了64 下，小兰比小华少跳6 下，小丽比小华多跳12 下.\n\n(1)小兰跳了多少下。\n(2)小丽跳了多少下。",
+    "options": [],
+    "answer": "58 下;76 下",
+    "solution": "【分析】(1)求比一个数少几的数是多少，用这个数 - 少的数计算，即小华跳的数量 - 小兰比小华少跳的数量 = 小兰跳的数量;(2)求比一个数多几的数是多少，用这个数 + 多的数计算，即小华跳的数量 + 小丽比小华多跳的数量 = 小丽跳的数量.\n【详解】(1)64 - 6 = 58(下),答：小兰跳了58下。(2)64 + 12 = 76(下),答：小丽跳了76下。",
+    "knowledge_points": [],
+    "source": ""
+  },
+  {
+    "id": "368",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.5,
+    "question": "乐乐写了45个毛笔字，毛毛和他写得一样多，两人一共写了多少个毛笔字。",
+    "options": [],
+    "answer": "90 个",
+    "solution": "【分析】根据题意可知，毛毛写毛笔字的数量和乐乐一样多，也是45 个，求两人一共写了多少个，用加法计算，即乐乐写的数量 + 毛毛写的数量 = 一共写的数量.\n【详解】45 + 45 = 90(个),答：两人一共写了90个毛笔字。",
+    "knowledge_points": [],
+    "source": ""
+  },
+  {
+    "id": "369",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.5,
+    "question": "一本《神话故事》,明明已经看了 34 页，还没看的比已经看的少 5 页，明明还剩多少页没看。这本《神话故事》一共有多少页。",
+    "options": [],
+    "answer": "29 页;63 页",
+    "solution": "【分析】还没看的比已经看的少 5 页，用已经看的页数减 5 即可求出还剩多少页没看。用已经看的页数加还没看的页数即可求出一共多少页.\n【详解】34 - 5 = 29(页),34 + 29 = 63(页),答：明明还剩29页没看。这本《神话故事》一共63页。",
+    "knowledge_points": [],
+    "source": ""
+  },
+  {
+    "id": "370",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.5,
+    "question": "二(3)班男生有 31 人，女生比男生少 14 人。二(3)班女生有多少人。一共有多少人。",
+    "options": [],
+    "answer": "17 人;48 人",
+    "solution": "【分析】求比一个数少几的数是多少，用这个数 - 少的数计算，即男生的人数 - 女生比男生少的人数 = 女生的人数;求一共有多少人，用加法计算，即男生的人数 + 女生的人数 = 一共的人数.\n【详解】31 - 14 = 17(人),31 + 17 = 48(人),答：二(3)班女生有17人，一共有48人。",
+    "knowledge_points": [],
+    "source": ""
+  },
+  {
+    "id": "371",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.5,
+    "question": "融百电器商场中的家电专柜原来有70 台电视机，卖出38 台后，又运来45 台。商场现在有多少台电视机。",
+    "options": [],
+    "answer": "77 台",
+    "solution": "【分析】根据题意可知：求现在有多少台电视机。用原有的数量减去卖出的数量再加上运来的数量即可.\n【详解】70 - 38 + 45 = 32 + 45 = 77(台),答：商场现在有77台电视机。",
+    "knowledge_points": [],
+    "source": ""
+  },
+  {
+    "id": "372",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.5,
+    "question": "向阳村原来有39 台电冰箱，今年新买入的比原来的少11 台，现在向阳村一共有电冰箱多少台。",
+    "options": [],
+    "answer": "67 台",
+    "solution": "【分析】根据题意，用原来电冰箱的数量减去11 即可求出今年新买入的数量，再加上原来的数量，即可求出现在一共有多少台电冰箱。据此解答.\n【详解】39 - 11 + 39 = 28 + 39 = 67(台),答：现在向阳村一共有电冰箱67台。",
+    "knowledge_points": [],
+    "source": ""
+  },
+  {
+    "id": "373",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.5,
+    "question": "元旦学校要装饰校园，二年级要贴34 幅画，三年级比二年级多贴18 幅画。三年级要贴多少幅画。两个年级一共要贴多少幅画。",
+    "options": [],
+    "answer": "52 幅;86 幅",
+    "solution": "【分析】求比一个数多几的数是多少，用这个数 + 多的数计算，即二年级要贴的数量 + 三年级比二年级多贴的数量 = 三年级要贴的数量;求两个年级一共要贴的数量，用加法计算，即二年级要贴的数量 + 三年级要贴的数量 = 两个年级一共要贴的数量.\n【详解】34 + 18 = 52(幅),34 + 52 = 86(幅),答：三年级要贴52幅画，两个年级一共要贴86幅画。",
+    "knowledge_points": [],
+    "source": ""
+  },
+  {
+    "id": "374",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.5,
+    "question": "公交车上原来有56 人，到南山站，下去22 人，又上来了29 人。现在车上有多少人。",
+    "options": [],
+    "answer": "63 人",
+    "solution": "【分析】根据题意可知：求现在车上有多少人。用原有的人数减去下去的人数再加上上来的人数.\n【详解】56 - 22 + 29 = 34 + 29 = 63(人),答：现在车上有63人。",
+    "knowledge_points": [],
+    "source": ""
+  },
+  {
+    "id": "375",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.5,
+    "question": "哥哥买一个书包58元，弟弟买一双球鞋比哥哥的书包便宜17元。两人一共花了多少元。",
+    "options": [],
+    "answer": "99 元",
+    "solution": "【分析】根据求比一个数少几的数，用减法计算。用书包的钱数减去弟弟买一双球鞋比哥哥的书包便宜的钱数，即可求出球鞋的钱数。然后再加上书包的钱数即可求出一共花的钱数.\n【详解】58 - 17 + 58 = 41 + 58 = 99(元),答：两人一共花了99元。",
+    "knowledge_points": [],
+    "source": ""
+  },
+  {
+    "id": "376",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.5,
+    "question": "一捆电线，一年级用去27米，二年级用去37米，还剩下23米。这捆电线原来有多少米。",
+    "options": [],
+    "answer": "87 米",
+    "solution": "【分析】根据加法的意义，一年级用去的长度 + 二年级用去的长度 + 剩下的长度 = 原来的长度，由此解答.\n【详解】27 + 37 + 23 = 87(米),答：这捆电线原来有87米。",
+    "knowledge_points": [],
+    "source": ""
+  },
+  {
+    "id": "377",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.5,
+    "question": "一本故事书共96 页，小光第一天看了29 页，第二天看了26 页.\n\n(1)两天一共看了多少页。(2)还剩多少页没看。",
+    "options": [],
+    "answer": "55 页;41 页",
+    "solution": "【分析】(1)求两天一共看了几页，用加法计算，即第一天看的页数 + 第二天看的页数=两天一共看的页数;(2)求还剩多少页没看，用减法计算，即总页数 - 两天一共看的页数 = 剩下没看的页数.\n【详解】(1)29 + 26 = 55(页),答：两天一共看了55页。(2)96 - 55 = 41(页),答：还剩41页没看。",
+    "knowledge_points": [],
+    "source": ""
+  },
+  {
+    "id": "378",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.5,
+    "question": "一个文具盒18 元，比书包便宜36 元，买这两样物体一共需要多少元。",
+    "options": [],
+    "answer": "72 元",
+    "solution": "【分析】已知一个文具盒是 18 元，比书包便宜 36 元，书包的价格就等于文具盒加上 36 元，得出的金额再加上一个文具盒的价格就是两样物体一共多少元.\n【详解】18 + 36 + 18 = 54 + 18 = 72(元),答：买这两样物品一共需要72元。",
+    "knowledge_points": [],
+    "source": ""
+  },
+  {
+    "id": "379",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.5,
+    "question": "一根电线长1 米，第一次用去27 厘米，第二次用去35 厘米，还剩下多少厘米。",
+    "options": [],
+    "answer": "38 厘米",
+    "solution": "【分析】先把1 米换算成100 厘米，然后用100 厘米先减去第一次用去的长度，求出差，再减去第二次用去的长度，求出差，即可解决.\n【详解】1 米 = 100 厘米,100 - 27 - 35 = 73 - 35 = 38(厘米),答：还剩下38厘米。",
+    "knowledge_points": [],
+    "source": ""
+  },
+  {
+    "id": "380",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.5,
+    "question": "纸艺社团有35 人，足球社团比篮球社团多8 人，篮球社团比纸艺社团少17 人，篮球社团有多少人。足球社团有多少人。",
+    "options": [],
+    "answer": "18 人;26 人",
+    "solution": "【分析】根据求比一个数少几的数，用减法计算。用纸艺社团的人数减去17人，求出篮球社团的人数。求比一个数多几的数，用加法计算。用篮球社团的人数加上8 人，求出足球社团的人数.\n【详解】35 - 17 = 18(人),18 + 8 = 26(人),答：篮球社团有18人，足球社团有26人。",
+    "knowledge_points": [],
+    "source": ""
+  },
+  {
+    "id": "381",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.5,
+    "question": "买这 3 个水壶,100 元够吗。\n\n![](images/f7af3647b4fd29717f87876753735bd5671f199ba389aca88c41223a5363917d.jpg)",
+    "options": [],
+    "answer": "够",
+    "solution": "【分析】根据题意，先用加法计算出这3 个水壶一共需要多少元，再和100 元比较大小，需要的钱数大于 100 元不够，小于或等于 100 元够.\n【详解】28 + 25 + 33 = 86(元),86 < 100，答：买这3个水壶,100元够。",
+    "knowledge_points": [],
+    "source": ""
+  },
+  {
+    "id": "382",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.5,
+    "question": "玩具店五周年庆，全场满80 元减10 元.\n![](images/2026-02-13%20210451.jpg)\n(1)买一辆小汽车和一个变形金刚，要花多少钱。\n(2)小东想买一架小飞机和一个布娃娃，还差5元，小东有多少钱。\n(3)你还能提出其他数学问题并解答吗。",
+    "options": [],
+    "answer": "72 元;55 元;小飞机比布娃娃贵多少元。2 元(答案不唯一)",
+    "solution": "【分析】(1)根据加法的意义，一辆小汽车的钱数 + 一个变形金刚的钱数 = 一共要花的钱数，再和 80 比较大小，若大于或等于 80 元，则再减 10 元是实际要花的钱数;(2)根据题意，先用加法计算出一架小飞机和一个布娃娃一共需要多少钱，再减去小东还差的钱数，就是小东有的钱数;(3)提出的问题符合题意即可，可提出小飞机比布娃娃贵多少元。用减法计算.\n【详解】(1)35 + 47 = 82(元),82 > 80,82 - 10 = 72(元),答：要花72元钱。(2)31 + 29 - 5 = 55(元),答：小东有55元钱。(3)小飞机比布娃娃贵多少元。(答案不唯一),31 - 29 = 2(元),答：小飞机比布娃娃贵2元。",
+    "knowledge_points": [],
+    "source": ""
+  },
+  {
+    "id": "383",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.5,
+    "question": "港珠澳大桥是世界上最长的跨海大桥，行驶在大桥上的双层巴士上层有53 个座位，下层比上层少 29 个座位.\n\n![](images/5db17c614c8da221d59eabefed964fbeae2ff6eaf13e6745504ba8699fb00098.jpg)\n\n(1)下层有多少个座位。\n(2)双层巴士一共有多少个座位。",
+    "options": [],
+    "answer": "24 个;77 个",
+    "solution": "【分析】(1)由题意得，双层巴士上层有 53 个座位，下层比上层少 29 个座位，那么直接用53减去29即可算出下层有多少个座位。(2)由(1)可得下层有多少个座位，求双层巴士一共有多少个座位，用加法计算.\n【详解】53 - 29 = 24(个),(1)答：下层有24个座位。53 + 24 = 77(个),(2)答：一共有77个座位。",
+    "knowledge_points": [],
+    "source": ""
+  },
+  {
+    "id": "384",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.5,
+    "question": "他们两人一共摘了多少个苹果。\n\n![](images/89a6807b899b738deb467f3ef708bf1bd61a20bb08b39a79cca38816ad4e550a.jpg)",
+    "options": [],
+    "answer": "40 个",
+    "solution": "【分析】先用女孩摘的苹果数量加上男孩比女孩多摘的数量，求出和，表示男孩摘的苹果数量，然后加上女孩摘的苹果数量，求出和，即可解决.\n【详解】17 + 6 + 17 = 23 + 17 = 40(个),答：他们两人一共摘了40个苹果。",
+    "knowledge_points": [],
+    "source": ""
+  },
+  {
+    "id": "385",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.5,
+    "question": "花金鱼有47 条，红金鱼有36 条，黑金鱼有14 条，共有金鱼多少条。红金鱼比黑金鱼多多少条。",
+    "options": [],
+    "answer": "97 条;22 条",
+    "solution": "【分析】求一共有多少条，用加法计算，即花金鱼的数量 + 红金鱼的数量 + 黑金鱼的数量=一共的数量;求红金鱼比黑金鱼多几条，用减法计算，即红金鱼的数量 - 黑金鱼的数量 = 红金鱼比黑金鱼多的数量.\n【详解】47 + 36 + 14 = 97(条),36 - 14 = 22(条),答：共有金鱼97条，红金鱼比黑金鱼多22条。",
+    "knowledge_points": [],
+    "source": ""
+  },
+  {
+    "id": "386",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.5,
+    "question": "教育大楼高38米，文化大楼比教育大楼低6米，文化大楼高多少米。",
+    "options": [],
+    "answer": "32 米",
+    "solution": "【分析】因为文化大楼比教育大楼低6 米，根据减法的意义，用38 - 6 即可得出文化大楼的高度.\n【详解】38 - 6 = 32(米),答：文化大楼高32米。",
+    "knowledge_points": [],
+    "source": ""
+  },
+  {
+    "id": "387",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.5,
+    "question": "下表为2024 年多哈世界游泳锦标赛中国队与美国队的奖牌数，中国比美国多多少块奖牌。\n\n队别 中国队 美国队\n奖牌数 3118",
+    "options": [],
+    "answer": "13 块",
+    "solution": "【分析】根据题意可知：求中国比美国多多少块奖牌。用中国队的数量减去美国队的数量即可.\n【详解】31 - 18 = 13(块),答：中国比美国多13块奖牌。",
+    "knowledge_points": [],
+    "source": ""
+  },
+  {
+    "id": "388",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.5,
+    "question": "公交车上原来有 48 人，现在有多少人。\n\n![](images/a074cfaaac7d4676e61bbd98f4a0681d4a466787c3b19759e5aa9fe5fd936632.jpg)",
+    "options": [],
+    "answer": "53 人",
+    "solution": "【分析】据题意，公交车上原来有48 人，下车了12 人，可用减法计算，又上车了17 人，可用加法计算，所以用原来的人数减去下车的人数再加上上车的人数即可得出现在的人数.\n【详解】48 - 12 + 17 = 36 + 17 = 53(人),答：公交车上现在有53人。",
+    "knowledge_points": [],
+    "source": ""
+  },
+  {
+    "id": "389",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.5,
+    "question": "星星小学有女教师54名，男教师比女教师少20名。男教师有多少名。星星小学一共有多少名教师。",
+    "options": [],
+    "answer": "34 名;88 名",
+    "solution": "【分析】根据题意可知，男教师比女教师少20 名，用女教师的人数减去20 即可得到男教师的人数;求出的男教师人数再加上女教师的人数，即可求得星星学校一共有多少名教师.\n【详解】54 - 20 = 34(名),34 + 54 = 88(名),答：男教师有34名，星星小学一共有88名教师。",
+    "knowledge_points": [],
+    "source": ""
+  },
+  {
+    "id": "390",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.5,
+    "question": "希望小学有男教师 25 人，女教师比男教师多 19 人.\n\n(1)女教师有多少人。\n(2)希望小学一共有教师多少人。",
+    "options": [],
+    "answer": "44 人;69 人",
+    "solution": "【分析】(1)根据题意可知：求女教师的人数。可根据求比一个数多几的数，用加法计算;(2)根据题意可知：求一共有的人数。用男教师的人数加女教师的人数即可.\n【详解】(1)25 + 19 = 44(人),答：女教师有44人。(2)25 + 44 = 69(人),答：希望小学一共有教师69人。",
+    "knowledge_points": [],
+    "source": ""
+  },
+  {
+    "id": "391",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.5,
+    "question": "桌子上有35 个梨子，二(1)班有男生18 人，女生19 人，如果一人分一个梨子，够吗。不够的话，差几个。",
+    "options": [],
+    "answer": "不够;2 个",
+    "solution": "【分析】已知，班内男生 18 人，女生 19 人，相加得出班内的总人数，再与 35 个梨子进行比较即可.\n【详解】18 + 19 = 37(人),37 > 35，所以不够,37 - 35 = 2(个),答：一共有37人，一人分一个梨子不够，还差2个。",
+    "knowledge_points": [],
+    "source": ""
+  },
+  {
+    "id": "392",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.5,
+    "question": "乐乐有100 元钱，买篮球用去38 元，买乒乓拍用去45 元。乐乐还剩多少钱。",
+    "options": [],
+    "answer": "17 元",
+    "solution": "【分析】用乐乐的总钱数减去买篮球用去的钱数，再减买乒乓拍用去的钱数即可求出乐乐还剩多少钱.\n【详解】100 - 38 - 45 = 17(元),答：乐乐还剩17元。",
+    "knowledge_points": [],
+    "source": ""
+  },
+  {
+    "id": "393",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.5,
+    "question": "公共汽车上原有42人，到站后下车29人，上车18人。现在车上有多少人。",
+    "options": [],
+    "answer": "31 人",
+    "solution": "【分析】根据题意，用车上原有的人数减去到站后下车的人数再加上上车的人数，即可求出现在车上有多少人。据此解答.\n【详解】42 - 29 + 18 = 13 + 18 = 31(人),答：现在车上有31人。",
+    "knowledge_points": [],
+    "source": ""
+  },
+  {
+    "id": "394",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.5,
+    "question": "学校\"小新星\"合唱团原来有54 人，今年有25 人毕业，又新增27 人。合唱团现在有多少人。",
+    "options": [],
+    "answer": "56 人",
+    "solution": "【分析】已知合唱团原有54 人，毕业了25 人，可用总数减去毕业的人数得出剩余的人数，又新增了27 人，用剩余人数加新增人数即可得出现在的总人数.\n【详解】54 - 25 + 27 = 29 + 27 = 56(人),答：合唱团现在有56人。",
+    "knowledge_points": [],
+    "source": ""
+  },
+  {
+    "id": "395",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.5,
+    "question": "二年级一班有 22 名男生,19 名女生，二年级二班比二年级一班少 3 名学生，二年级二班有多少名学生。",
+    "options": [],
+    "answer": "38 名",
+    "solution": "【分析】根据题意可知：先求出一班一共有多少人。用男生的人数加女生的人数即可，然后根据求比一个数少几的数，用减法计算。用一班的人数减去二班比一班少的人数即可.\n【详解】22 + 19 = 41(名),41 - 3 = 38(名),答：二年级二班有38名学生。",
+    "knowledge_points": [],
+    "source": ""
+  },
+  {
+    "id": "396",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.5,
+    "question": "赵叔叔的奶茶店周六上午接到 28 份美团订单，下午比上午多接到 53 份，晚上比下午少 19 份订单。赵叔叔的奶茶店晚上接到多少份订单。",
+    "options": [],
+    "answer": "62 份",
+    "solution": "【分析】求比一个数多几的数是多少，用这个数 + 多的数计算;求比一个数少几的数是多少，用这个数 - 少的数计算。即用上午接到的数量加上下午比上午多接到的数量，计算出下午接到多少份，再用下午接到的数量减去晚上比下午少接到的数量，就是晚上接到的数量.\n【详解】28 + 53 - 19 = 62(份),答：赵叔叔的奶茶店晚上接到62份订单。",
+    "knowledge_points": [],
+    "source": ""
+  },
+  {
+    "id": "397",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.5,
+    "question": "水果店卖了14 箱橘子，还剩下36 箱橘子。商店里原来一共有多少箱橘子。又运来42箱苹果，橘子和苹果现在一共多少箱。",
+    "options": [],
+    "answer": "50 箱;78 箱",
+    "solution": "【分析】求原来橘子的箱数，用加法计算，即卖了的箱数 + 还剩的箱数 = 原来的箱数;求现在橘子和苹果的总箱数，用加法计算，即剩下橘子的箱数 + 运来苹果的箱数 = 现在橘子和苹果一共的箱数.\n【详解】14 + 36 = 50(箱),36 + 42 = 78(箱),答：商店里原来一共有50箱橘子，橘子和苹果现在一共78箱。",
+    "knowledge_points": [],
+    "source": ""
+  },
+  {
+    "id": "398",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.5,
+    "question": "猴妈妈提了一篮花生，第一只猴子拿走了30 个，第二只猴子拿走了28 个，第三只猴子拿走的和第一只同样多。这时，篮子里没有花生了。猴妈妈篮子里原来有多少个花生。",
+    "options": [],
+    "answer": "88 个",
+    "solution": "【分析】根据题意分析，第三只猴子拿走的和第一只同样多，则第三只猴子也拿走了30 个，将这三只猴子拿的花生的数量加起来，即可得到猴妈妈篮子里原有的花生的数量.\n【详解】30 + 28 + 30 = 58 + 30 = 88(个),答：猴妈妈篮子里原来有88个花生。",
+    "knowledge_points": [],
+    "source": ""
+  },
+  {
+    "id": "399",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.5,
+    "question": "妈妈带了100 元钱去超市，买水果花了28 元，买牛肉花了41 元，买东西一共花了多少钱。",
+    "options": [],
+    "answer": "69 元",
+    "solution": "【分析】已知妈妈买水果花了 28 元，买牛肉花了 41 元，两种物品的钱数相加即可得出共花了多少钱.\n【详解】28 + 41 = 69(元),答：买东西一共花了69元。",
+    "knowledge_points": [],
+    "source": ""
+  },
+  {
+    "id": "400",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.5,
+    "question": "华华有28 张卡片，兰兰比华华多12 张卡片，他们一共有多少张卡片。",
+    "options": [],
+    "answer": "68 张",
+    "solution": "【分析】求比一个数多几的数是多少，用这个数 + 多的数计算，即华华卡片的数量 + 兰兰比华华多的数量 = 兰兰卡片的数量，再和华华卡片的数量相加，就是他们一共的卡片数量.\n【详解】28 + 12 + 28 = 68(张),答：他们一共有68张卡片。",
+    "knowledge_points": [],
+    "source": ""
+  },
+  {
+    "id": "401",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "小红有 21 枚邮票，小兰有 39 枚邮票。小兰给小红( )枚邮票，两人的邮票数量就一样多了。",
+    "options": [
+      "18",
+      "9",
+      "30"
+    ],
+    "answer": "B",
+    "solution": "【分析】先用小兰的邮票数量减去小红的邮票数量，求出差，再把差平均分成2份，把其中的1份给小红，两人的邮票数量就一样多了.\n【详解】39 - 21 = 18(枚),18 = 9 + 9，即,18枚邮票平均分成2份，每份是9枚;即，小红有21枚邮票，小兰有39枚邮票。小兰给小红9枚邮票，两人的邮票数量就一样多了。故答案为:B",
+    "knowledge_points": [
+      "9加几的进位加法",
+      "两位数与两位数的不退位减法"
+    ],
+    "source": "23-24 二年级上·河南南阳·期末"
+  },
+  {
+    "id": "402",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "下列算式中，得数最大的是( )。",
+    "options": [
+      "38+45",
+      "26+34",
+      "52+39"
+    ],
+    "answer": "C",
+    "solution": "【分析】根据整数加减法的计算法则，依次计算出各算式的结果再比较大小，比较时，位数多的数就大;位数相同比较最高位，最高位大的数就大;最高位相同比较下一位，直到比较出结果为止.\n【详解】A。38 + 45 = 83;B。26 + 34 = 60;C。52 + 39 = 91;91 > 83 > 60，得数最大的是 52 + 39。故答案为:C",
+    "knowledge_points": [
+      "100以内数的比大小",
+      "两位数与两位数的进位加法"
+    ],
+    "source": "24-25二年级上·河南南阳·期中"
+  },
+  {
+    "id": "403",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "50 - 19 + 28 应该先算( )。",
+    "options": [
+      "50 - 19",
+      "19 + 28",
+      "50 - 28"
+    ],
+    "answer": "A",
+    "solution": "【分析】只有加减法的混合运算，要从左往右计算，由此解答.\n【详解】50 - 19 + 28应该先算减法，再算加法，也就是先算 50 - 19。故答案为:A",
+    "knowledge_points": [
+      "无括号的运算顺序",
+      "100以内数的加减混合运算"
+    ],
+    "source": "24-25二年级上·河南漯河·期中"
+  },
+  {
+    "id": "404",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "王阿姨 17 年后是( )岁.\n\n![](images/2026-02-13%20220037.jpg)",
+    "options": [
+      "54",
+      "43",
+      "37"
+    ],
+    "answer": "A",
+    "solution": "【分析】根据题意，先用王阿姨11年前的年龄加上11岁，即可求出王阿姨今年的年龄。再用王阿姨今年的年龄加上17岁，就是17年后的王阿姨的年龄.\n【详解】26 + 11 + 17 = 54(岁),王阿姨 17 年后是 54 岁。故答案为:A",
+    "knowledge_points": [
+      "图文问题",
+      "100以内数的连加运算"
+    ],
+    "source": "24-25 二年级上·河南周口·期中"
+  },
+  {
+    "id": "405",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "闹闹比笑笑多摘了13个桃子。他俩一共摘了( )个.\n\n![](images/d324777e721bdad4247d94e93d2ac86e4180cd95218961809e1f0d10fae281f7.jpg)\n\n![](images/a65cb2cc32e277e9e1d8e1adfd06cd5221b518cd8c62eef873b538727036490b.jpg)",
+    "options": [
+      "35",
+      "61",
+      "83"
+    ],
+    "answer": "C",
+    "solution": "【分析】根据题意，用闹闹摘的数量减去13即可求出笑笑摘的数量，把闹闹和笑笑摘的数量相加即可求出他俩一共摘了多少，据此解答.\n【详解】48 - 13 + 48 = 35 + 48 = 83(个),他俩一共摘了83个。故答案为:C",
+    "knowledge_points": [
+      "100以内数的加减混合运算"
+    ],
+    "source": "24-25二年级上·河南周口·期中"
+  },
+  {
+    "id": "406",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "小思笔算 35 + 24，第二步计算的是( )。",
+    "options": [
+      "5 个一加 2 个一",
+      "3 个十加 2 个十",
+      "3 个十加 4 个十"
+    ],
+    "answer": "B",
+    "solution": "【分析】两位数与两位数的加法计算时，相同数位对齐，从个位算起，个位相加满十向十位进1，由此解答.\n【详解】![](images/2026-02-13%20220330.jpg)\n小思笔算35 + 24，第一步计算的是5个一加4个一;第二步计算的是3个十加2个十。故答案为:B",
+    "knowledge_points": [
+      "两位数与两位数的不进位加法"
+    ],
+    "source": "24-25 二年级上·广西南宁·期中"
+  },
+  {
+    "id": "407",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "数学课上，东东在口算一道两位数减两位数的算式时，他先算 92 - 30 = 62，再算 62 - 5 = 57，他口算的算式是( )。",
+    "options": [
+      "92 - 65",
+      "92 - 62",
+      "92 - 35"
+    ],
+    "answer": "C",
+    "solution": "【分析】根据两位数减两位数的口算方法，可以把减数看作整十数和一位数，先用被减数减整十数，再减一位数;根据题意，先算92减30得62，再算62减5得57，可知把减数看作了30和5分别相减，即减数是30和5的和35，所以口算的算式是92 - 35;据此解答.\n【详解】根据分析可知：数学课上，东东在口算一道两位数减两位数的算式时，他先算 92 - 30 = 62，再算 62 - 5 = 57，他口算的算式是92 - 35。故答案为:C",
+    "knowledge_points": [
+      "两位数与两位数的加减法口算"
+    ],
+    "source": "24-25三年级上·青海果洛·期中"
+  },
+  {
+    "id": "408",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "一根电线长 82 米，第一次用去 34 米，第二次用去 42 米。第二次比第一次多用( )米。",
+    "options": [
+      "6",
+      "76",
+      "8"
+    ],
+    "answer": "C",
+    "solution": "【分析】根据题意可知，要求第二次比第一次多用多少米，用第二次用的长度减去第一次用的长度即可.\n【详解】42 - 34 = 8(米),第二次比第一次多用8米。故答案为:C",
+    "knowledge_points": [
+      "两位数与两位数的退位减法"
+    ],
+    "source": "23-24 二年级上·重庆秀山·期末"
+  },
+  {
+    "id": "409",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "笔算60 - 42时，从十位退 1 后，个位要算( )减 2。",
+    "options": [
+      "8",
+      "10",
+      "12"
+    ],
+    "answer": "B",
+    "solution": "【分析】根据减法计算时，哪一位上不够减，向前一位借一当十，所以十位退 1，个位当 10，计算时是 10 减 2.\n【详解】60 - 42 = 18,0 减 2 不够减，向 6 借 1 当 10，就是10 - 2。故答案为:B",
+    "knowledge_points": [
+      "两位数与两位数的退位减法"
+    ],
+    "source": "24-25二年级上·广西玉林·期中"
+  },
+  {
+    "id": "410",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "要使 36 + 12 + □ < 56,□里最大可以填( )。",
+    "options": [
+      "7",
+      "8",
+      "6"
+    ],
+    "answer": "A",
+    "solution": "【分析】根据题意，先计算出左侧算式等于56时，应填的数是多少，要想方框里填的数最大，则最大是比求出来的数小1的数，由此用求出的数 - 1计算即可.\n【详解】36 + 12 + □ = 56，则56 - 36 - 12 = 8，当36 + 12 + □ < 56时,□里最大可以填8 - 1 = 7。故答案为:A",
+    "knowledge_points": [
+      "100以内数的比大小",
+      "100以内数的连减运算",
+      "100以内数的连加运算"
+    ],
+    "source": "24-25 二年级上·河南商丘·期中"
+  },
+  {
+    "id": "411",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "下面算式的得数比50 大的是( )。",
+    "options": [
+      "52 - 28 + 24",
+      "15 + 27 + 26",
+      "19 + 3 + 28"
+    ],
+    "answer": "B",
+    "solution": "【分析】根据题意，依次计算出各算式的结果再和50比较大小。比较时，位数多的数就大;位数相同比较最高位，最高位大的数就大;最高位相同比较下一位，直到比较出结果为止。只有加减法的混合运算，从左往右计算.\n【详解】A。52 - 28 + 24 = 48;48 < 50，不符合题意;B。15 + 27 + 26 = 68;68 > 50，符合题意;C。19 + 3 + 28 = 50;50 = 50，不符合题意。得数比50大的是15 + 27 + 26。故答案为:B",
+    "knowledge_points": [
+      "100以内数的比大小",
+      "100以内数的连加运算",
+      "100 以内数的加减混合运算"
+    ],
+    "source": "24-25 二年级上·河南商丘·期中"
+  },
+  {
+    "id": "412",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "64 - 2□,要使差的十位上的数字是 3,□里可以填( )。",
+    "options": [
+      "3",
+      "4",
+      "5"
+    ],
+    "answer": "C",
+    "solution": "【分析】两位数与两位数的减法计算时，相同数位对齐，从个位算起，个位若不够减，则从十位退1作十计算。要使差的十位上是3，也就是 6 - 2 - 1 = 3，从十位退了1，也就是个位上 4 不够减 □,即 4 小于 □,由此解答.\n【详解】A。4 > 3，不符合题意;B。4 = 4，不符合题意;C。4 < 5，符合题意。□ 里可以填5。故答案为:C",
+    "knowledge_points": [
+      "两位数与两位数的不退位减法",
+      "两位数与两位数的退位减法"
+    ],
+    "source": "24-25 二年级上·山东济南·期中"
+  },
+  {
+    "id": "413",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "笔算加减法，要把( )对齐。",
+    "options": [
+      "相同数位",
+      "数位",
+      "个位十位"
+    ],
+    "answer": "A",
+    "solution": "【分析】本题根据竖式计算的法则来解答即可。加法：相同数位对齐，从个位算起，哪一位相加满十，向前一位进 1。减法：相同数位对齐，从个位算起，哪一位不够减，从前位退 1 作十计算。由此解答.\n【详解】由分析可知：笔算加减法时，要把相同数位对齐。例如:24 + 28 = 52;50 - 26 = 24.\n![](images/2026-02-13%20221145.jpg)\n故答案为:A",
+    "knowledge_points": [
+      "两位数与两位数的退位减法",
+      "两位数与两位数的进位加法"
+    ],
+    "source": "24-25 二年级上·河南三门峡·期中"
+  },
+  {
+    "id": "414",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "姐姐有53本故事书，比弟弟少19本，弟弟有( )本故事书。",
+    "options": [
+      "34",
+      "62",
+      "72",
+      "82"
+    ],
+    "answer": "C",
+    "solution": "【分析】姐姐有53本故事书，比弟弟少19本，那么弟弟就比姐姐多 19 本书，直接用 53 加上 19 即可算出弟弟有多少本故事书.\n【详解】53 + 19 = 72(本),即弟弟有 72 本故事书。故答案为:C",
+    "knowledge_points": [
+      "两位数与两位数的进位加法"
+    ],
+    "source": "24-25三年级上·重庆·期中"
+  },
+  {
+    "id": "415",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "一捆铁丝长100米，第一次用了35米，第二次用了45米，一共用了多少米。列式为( )。",
+    "options": [
+      "100 - 35 + 45 ",
+      "35 + 45",
+      "100 -(35 + 45)"
+    ],
+    "answer": "B",
+    "solution": "【分析】根据题意，第一次用去的长度加上第二次用去的长度，就是一共用了多少米.\n【详解】第一次用了 35 米，第二次用了 45 米，一共用了多少米。35 + 45 = 80(米),一共用了 80 米。选项 A 不符合题意，选项 C 是求还剩多少米。故答案为:B",
+    "knowledge_points": [
+      "两位数与两位数的进位加法"
+    ],
+    "source": "24-25三年级上·河南信阳·期中"
+  },
+  {
+    "id": "416",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "小明，小红，小军一起去摘草莓。三个人一共摘了 74 个，小明和小军一共摘了 52 个，小红摘了( )个。",
+    "options": [
+      "22",
+      "24",
+      "26"
+    ],
+    "answer": "A",
+    "solution": "【分析】根据减法的意义，三个人摘的总数量 - 小明和小军一共摘的数量 = 小红摘的数量.\n【详解】74 - 52 = 22(个),小红摘了22个。故答案为:A",
+    "knowledge_points": [
+      "两位数与两位数的不退位减法"
+    ],
+    "source": "24-25 二年级上·广东韶关·期中"
+  },
+  {
+    "id": "417",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "有 50 千克水果，第一天卖出26千克，第二天卖出17千克。算式\"26 + 17 = 43(千克)\"解决的问题是( )。",
+    "options": [
+      "还剩下多少千克水果",
+      "两天一共卖出多少千克水果",
+      "第二天比第一天少卖出多少千克水果"
+    ],
+    "answer": "B",
+    "solution": "【分析】根据题意，有50千克水果，第一天卖出26千克，第二天卖出17千克。算式\"26 + 17 = 43(千克)\"中26表示第一天卖出的数量,17表示第二天卖出的数量，两者相加表示两天一共卖出的数量，据此解答.\n【详解】根据分析：有50千克水果，第一天卖出26千克，第二天卖出17千克。算式\"26 + 17 = 43(千克)\"解决的问题是两天一共卖出多少千克水果。故答案为:B",
+    "knowledge_points": [
+      "\"提问题\"\"填条件\"问题",
+      "两位数与两位数的进位加法"
+    ],
+    "source": "24-25 二年级上·河北唐山·期中"
+  },
+  {
+    "id": "418",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "欢欢有32枚纪念币，乐乐和欢欢相差 18 枚，乐乐( )枚。",
+    "options": [
+      "14",
+      "50",
+      "50 或 14"
+    ],
+    "answer": "C",
+    "solution": "【分析】根据题意，欢欢有32枚纪念币，乐乐和欢欢相差18，说明欢欢有可能比乐乐多18枚，用减法计算可以求出乐乐的数量，也有可能欢欢比乐乐少18枚，用加法计算可以求出乐乐的数量，据此解答.\n【详解】根据分析：当欢欢比乐乐多18枚时，乐乐的数量:32 - 18 = 14(枚),当欢欢比乐乐少 18 枚时，乐乐的数量:32 + 18 = 50(枚),所以乐乐可能有14枚或者有50枚。故答案为:C",
+    "knowledge_points": [
+      "两位数与两位数的退位减法",
+      "两位数与两位数的进位加法"
+    ],
+    "source": "24-25二年级上·河北唐山·期中"
+  },
+  {
+    "id": "419",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面算式中，计算结果最接近 70 的是( )。",
+    "options": [
+      "37 + 29",
+      "28 + 27",
+      "96 - 13"
+    ],
+    "answer": "A",
+    "solution": "【分析】根据题意，分别计算出各个算式的结果，再求出与70的差，比较差的大小，差最小的最接近70。据此解答.\n【详解】A。37 + 29 = 66,70 - 66 = 4;B。28 + 27 = 55,70 - 55 = 15;C。96 - 13 = 83,83 - 70 = 13;4 < 13 < 15，所以37 + 29的结果最接近70。故答案为:A",
+    "knowledge_points": [
+      "两位数与两位数的不退位减法",
+      "两位数与两位数的进位加法"
+    ],
+    "source": "24-25二年级上·福建厦门·期中"
+  },
+  {
+    "id": "420",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "玲玲想买以下这两件衣服，带( )元就够了.\n\n![](images/1e71aee8590538c314a4ac0ff0b01056b2b2117943503f88d0db477403211f96.jpg)\n\n![](images/abad8d19e925040d0884a1dff4c8dc58950ad16fd2bc37d83a7b9e8304d414bd.jpg)",
+    "options": [
+      "60 元",
+      "70 元",
+      "80 元"
+    ],
+    "answer": "B",
+    "solution": "【分析】由题意得，一件裙子37元，一件衣服32元，可以先用加法算出一共需要多少钱，然后结合选项找出玲玲需要带的最少的钱数即可.\n【详解】37 + 32 = 69(元),A。69 > 60，不满足题意。B。70 > 69，满足题意。C。80 > 69，满足题意。80 > 70，所以玲玲需要70元就够了。故答案为:B",
+    "knowledge_points": [
+      "两位数与两位数的不进位加法"
+    ],
+    "source": "24-25二年级上·福建厦门·期中"
+  },
+  {
+    "id": "421",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "与 83 - 42 - 18 计算结果相同的是( )。",
+    "options": [
+      "83 - (42 - 18)",
+      "83 - 42 + 18",
+      "83 - (42 + 18)"
+    ],
+    "answer": "C",
+    "solution": "【分析】先计算出各算式的答案，然后再比较大小即可。根据整数混合运算可知：同级运算，按照从左往右的顺序依次计算即可。有小括号的，先算小括号中的，再算小括号外面的.\n【详解】83 - 42 - 18 = 41 - 18 = 23。A。83 - (42 - 18) = 83 - 24 = 59,59 > 23，则不符合题意。B。83 - 42 + 18 = 41 + 18 = 59,59 > 23，则不符合题意。C。83 - (42 + 18) = 83 - 60 = 23,23 = 23，则符合题意。故答案为:C",
+    "knowledge_points": [
+      "100以内数的加减混合运算"
+    ],
+    "source": "24-25 二年级上·福建三明·期中"
+  },
+  {
+    "id": "422",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "如图，下面说法错误的是( ).\n\n![](images/0d3b4a4cf4123aca47283864be61ab553e8a9dded26a82b95d6695738f817953.jpg)",
+    "options": [
+      "一班有14本书",
+      "二班比一班少5本",
+      "![](images/2026-02-13%20224929.jpg)表示要求二班有几本",
+      "可以列式为:9 + 5 = 14(本)"
+    ],
+    "answer": "D",
+    "solution": "【分析】由图可知，一班有14本，二班比一班少5本,。处表示二班的数量，一班的数量 - 二班比一班少的数量 = 二班的数量.\n【详解】A。一班有14本书，说法正确;B。二班比一班少5本，说法正确;C。表示要求二班有几本，说法正确;D。可以列式为14 - 5 = 9(本),原说法错误。所以说法错误的是可以列式为:9 + 5 = 14(本)。故答案为:D",
+    "knowledge_points": [
+      "9 加几的进位加法",
+      "十几减 5~2 的退位减法",
+      "图文问题"
+    ],
+    "source": "24-25 二年级上·福建龙岩·期中"
+  },
+  {
+    "id": "423",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下图圈起来的部分表示的是( ).\n\n![](images/a28bcb420cb3340afb286974bba07726748a0b94aab162897e4b87f3baa44094.jpg)",
+    "options": [
+      "4个十加2个一",
+      "4 个一加 2 个十",
+      "4 个十加2个十",
+      "4个一加2个一"
+    ],
+    "answer": "D",
+    "solution": "【分析】圈起来的部分上面有4根小棒，表示4个一，下面有 2 根小棒，表示 2 个一，合起来就表示 4 个一加 2 个一;据此解决.\n【详解】由题意分析得：该图圈起来的部分表示的是:4个一加2个一。故答案为:D",
+    "knowledge_points": [
+      "两位数与两位数的不进位加法"
+    ],
+    "source": "24-25二年级上·福建龙岩·期中"
+  },
+  {
+    "id": "424",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面几组物品中，价格和最接近 60 元的是( ).\n\n![](images/2026-02-13%20230142.jpg)",
+    "options": [
+      "钢笔和笔袋",
+      "篮球和笔袋",
+      "钢笔和篮球"
+    ],
+    "answer": "B",
+    "solution": "【分析】可逐项计算出钢笔和笔袋，篮球和笔袋，钢笔和篮球的价格之和，再与60分别作差，看哪个选项的差最小，即是所求.\n【详解】A。钢笔和笔袋,15 + 12 = 27(元),60 - 27 = 33(元);B。篮球和笔袋,47 + 12 = 59(元),60 - 59 = 1(元);C。钢笔和篮球,15 + 47 = 62(元),62 - 60 = 2(元),1 < 2 < 33，即篮球和笔袋的价格接近60元。故答案为:B",
+    "knowledge_points": [
+      "两位数与两位数的不进位加法",
+      "两位数与两位数的不退位减法",
+      "两位数与两位数的退位减法",
+      "两位数与两位数的进位加法"
+    ],
+    "source": "24-25 二年级上·福建福州·期中"
+  },
+  {
+    "id": "425",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "74 - 3□,要使差的十位上的数字是 3,□里可以填( )。",
+    "options": [
+      "0 至 4",
+      "5 至 9",
+      "0 至 9"
+    ],
+    "answer": "B",
+    "solution": "【分析】两位数与两位数的减法计算时，相同数位对齐，从个位算起，个位若不够减，则从十位退1作十计算。要想差的十位上是 3，也就是 7 - 3 - 1 = 3，从十位退了 1，也就是个位上 4 不够减 □,即 4 小于 □,由此解答.\n【详解】由分析可知,4 < □,比4大的数有:5,6,7,8,9. □ 里可以填5至 9。故答案为:B",
+    "knowledge_points": [
+      "两位数与两位数的退位减法"
+    ],
+    "source": "24-25二年级上·河南南阳·期中"
+  },
+  {
+    "id": "426",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "有一本故事书，亮亮第一天看了32页，第二天看的比第一天多16页，第二天看了( )页。",
+    "options": [
+      "17",
+      "48",
+      "79"
+    ],
+    "answer": "B",
+    "solution": "【分析】根据题意可知，第二天比第一天多16页，即是比32页多16页，用加法列式计算.\n【详解】32 + 16 = 48(页),亮亮第一天看了32页，第二天看的比第一天多16页，第二天看了48页。故答案为:B",
+    "knowledge_points": [
+      "两位数与两位数的不进位加法"
+    ],
+    "source": "24-25 二年级上·湖北武汉·期中"
+  },
+  {
+    "id": "427",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "如果算式\"54 + 3□\"是一道进位加法题,□里最小可以填( );如果算式\"71 - 4□\"是一道退位减法题,□里最小可以填( )。",
+    "options": [],
+    "answer": "6;2",
+    "solution": "【分析】本题根据竖式计算的法则来解答即可。加法：相同数位对齐，从个位算起，哪一位相加满十，向前一位进 1。减法：相同数位对齐，从个位算起，哪一位不够减，从前一位退1作十计算。由此解答.\n【详解】54 + 3□若是进位加法，也就是个位的和要大于或等于 10，最小和为 10，即 4 + □ = 10,10 - 4 = 6,□ = 6;71 - 4□若为退位减法，也就是个位□要大于1，最小是比1大 1 的数，即 1 + 1 = 2。如果算式\"54 + 3□\"是一道进位加法题,□里最小可以填6;如果算式\"71 - 4□\"是一道退位减法题,□里最小可以填2。",
+    "knowledge_points": [
+      "两位数与两位数的退位减法",
+      "两位数与两位数的进位加法"
+    ],
+    "source": "24-25二年级上·河南南阳·期中"
+  },
+  {
+    "id": "428",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "小宇在做一道减法题时，把被减数75看成了57，这样算得结果是28，则正确的结果是( )。",
+    "options": [],
+    "answer": "46",
+    "solution": "【分析】据题意，看错后的被减数是57，差是28，用被减数减差即可得出减数，再用正确的75减去减数即可得出正确结果.\n【详解】据分析可得:57 - 28 = 29,75 - 29 = 46，小宇在做一道减法题时，把被减数75看成了57，这样算得结果是28，则正确的结果是46。",
+    "knowledge_points": [
+      "两位数与两位数的退位减法",
+      "错中求解问题(加减法)"
+    ],
+    "source": "24-25二年级上·河南南阳·期中"
+  },
+  {
+    "id": "429",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "比 37 多 25 的数是( );70 比( )少 19。",
+    "options": [],
+    "answer": "62;89",
+    "solution": "【分析】求比一个数多几的数是多少，用这个数 + 多的数计算;已知一个数比另一个数少几，求另一个数，用这个数 + 少的数计算.\n【详解】37 + 25 = 62;70 + 19 = 89，比37多25的数是62;70比89少19。",
+    "knowledge_points": [
+      "两位数与整十数的加法",
+      "两位数与两位数的进位加法"
+    ],
+    "source": "24-25 二年级上·河南南阳·期中"
+  },
+  {
+    "id": "430",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "一个书包 23 元，一个文具盒比一个书包便宜 9 元，一个文具盒( )元。",
+    "options": [],
+    "answer": "14",
+    "solution": "【分析】求比一个数少几的数是多少，用这个数 - 少的数计算，即书包的价格 - 文具盒比书包便宜的价格 = 文具盒的价格.\n【详解】23 - 9 = 14(元),一个书包23元，一个文具盒比一个书包便宜9元，一个文具盒14元。",
+    "knowledge_points": [
+      "一位数与两位数的退位减法"
+    ],
+    "source": "24-25 二年级上·河南漯河·期中"
+  },
+  {
+    "id": "431",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "书店为回馈新老顾客，特举行优惠促销活动。小可买了一本48元的漫画书和一本 16 元的童话故事书，一共需付( )元。小可带了100元，售货员阿姨应找回( )元.\n\n![](images/1f2b0f5defe58e7c2ee0529dc5d56ec93ab93b52e0ad629e2ed1616bbfec9615.jpg)",
+    "options": [],
+    "answer": "54;46",
+    "solution": "【分析】根据题意，把一本漫画书和一本童话故事书的价格相加即可求出两本书的价格，两本书的价格满50元可以减10元，用两本书的价格减去10即一共需要付的钱数;用带的钱数减去一共需要付的钱数即可求出售货员阿姨应找回多少元，据此解答.\n【详解】48 + 16 = 64(元),64 > 50,64 - 10 = 54(元),即一共需要付54元。100 - 54 = 46(元),应找回46元。书店为回馈新老顾客，特举行优惠促销活动。小可买了一本48元的漫画书和一本16元的童话故事书，一共需付54元。小可带了100元，售货员阿姨应找回46元。",
+    "knowledge_points": [
+      "经济问题",
+      "促销问题",
+      "两位数与两位数的退位减法",
+      "两位数与整十数的减法",
+      "两位数与两位数的进位加法"
+    ],
+    "source": "24-25 二年级上·河南周口·期中"
+  },
+  {
+    "id": "432",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "74 比 39 多( ),24 比( )多 14。",
+    "options": [],
+    "answer": "35;10",
+    "solution": "【分析】求一个数比另一个数多多少(或者少多少),用大的数减去小的数。求74比39多多少，用74 - 39;求24比几多14用24 - 14，由此解答.\n【详解】74 - 39 = 35,24 - 14 = 10，所以74比39多35,24比10多14。",
+    "knowledge_points": [
+      "两位数与两位数的不退位减法",
+      "两位数与两位数的退位减法"
+    ],
+    "source": "23-24 二年级上·福建福州·期末"
+  },
+  {
+    "id": "433",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "计算 75 - 43 + 19 时，先算( )法，再算( )法，结果是( )。",
+    "options": [],
+    "answer": "减;加;51",
+    "solution": "【分析】只有加减法的混合运算，要从左往右计算，由此解答.\n【详解】75 - 43 + 19 = 32 + 19 = 51，计算 75 - 43 + 19 时，先算减法，再算加法，结果是51。",
+    "knowledge_points": [
+      "100以内数的加减混合运算"
+    ],
+    "source": "24-25 二年级上·广东韶关·期中"
+  },
+  {
+    "id": "434",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "计算 90 - (42 + 19)时，应先算( )法，再算( )法，结果是( )。",
+    "options": [],
+    "answer": "加;减;29",
+    "solution": "【分析】只有加减法的混合运算，要从左往右计算;若有括号，则先算括号里面的，再算括号外面的，由此解答.\n【详解】90 - (42 + 19)= 90 - 61 = 29，计算90 - (42 + 19)时，应先算加法，再算减法，结果是29。",
+    "knowledge_points": [
+      "带有小括号的混合运算",
+      "有括号的运算顺序"
+    ],
+    "source": "24-25 二年级上·广东汕头·期中"
+  },
+  {
+    "id": "435",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "25 + 4□ > 70,□里最小填( )。",
+    "options": [],
+    "answer": "6",
+    "solution": "【分析】根据题意可知，要使25 + 4□ > 70,4□ > 70 - 25，利用70减去25求出差，再利用差加1即可求出4□里的数.\n【详解】70 - 25 = 45,45 + 1 = 46,25 + 46 > 70，则□里最小填6。",
+    "knowledge_points": [
+      "两位数与两位数的退位减法",
+      "一位数与两位数的进位加法"
+    ],
+    "source": "24-25 三年级上·福建厦门·期中"
+  },
+  {
+    "id": "436",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "有一根75厘米长的绳子，第一次剪去27厘米，第二次剪去19厘米。第一次比第二次多剪去( )厘米，剪完两次后还剩下( )厘米。",
+    "options": [],
+    "answer": "8;29",
+    "solution": "【分析】根据减法的意义，第一次剪去的长度 - 第二次剪去的长度 = 第一次比第二次多剪去的长度;总长度 - 第一次剪去的长度 - 第二次剪去的长度 = 还剩下的长度.\n【详解】27 - 19 = 8(厘米),75 - 27 - 19 = 29(厘米),有一根75厘米长的绳子，第一次剪去27厘米，第二次剪去19厘米。第一次比第二次多剪去8厘米，剪完两次后还剩下29厘米。",
+    "knowledge_points": [
+      "100以内数的连减运算",
+      "两位数与两位数的退位减法"
+    ],
+    "source": "24-25二年级上·福建三明·期中"
+  },
+  {
+    "id": "437",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "比 25 多 32 的数是( ),( )比 78 少 46。",
+    "options": [],
+    "answer": "57;32",
+    "solution": "【分析】求比25多32的数是多少，用加法计算;一个数比78少46，求这个数，直接用78减去46即可解答.\n【详解】25 + 32 = 57,78 - 46 = 32，比25多32的数是57,32比78少46。",
+    "knowledge_points": [
+      "两位数与两位数的不进位加法",
+      "两位数与两位数的不退位减法"
+    ],
+    "source": "24-25 二年级上·福建厦门·期中"
+  },
+  {
+    "id": "438",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "要在计数器上用珠子表示 25 与 35 的和，需要( )颗珠子。",
+    "options": [],
+    "answer": "6",
+    "solution": "【分析】根据题意，先计算出25与35的和，再数出和的各个数位上的数字之和即可.\n【详解】25 + 35 = 60,6 + 0 = 6(颗),要在计数器上用珠子表示25与35的和，需要6颗珠子。",
+    "knowledge_points": [
+      "两位数与两位数的进位加法"
+    ],
+    "source": "24-25三年级上·河南信阳·期中"
+  },
+  {
+    "id": "439",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "43 比 18 多( ),17 比 36 少( ),比 30 多 12 的数是( )。",
+    "options": [],
+    "answer": "25;19;42",
+    "solution": "【分析】求一个数比另一个数多几，用这个数 - 另一个数计算;求一个数比另一个数少几，用另一个数 - 这个数计算;求比一个数多几的数是多少，用这个数 + 多的数计算.\n【详解】43 - 18 = 25;36 - 17 = 19;30 + 12 = 42,43 比 18 多 25,17 比 36 少 19，比 30 多 12 的数是 42。",
+    "knowledge_points": [
+      "两位数与两位数的退位减法",
+      "两位数与整十数的加法"
+    ],
+    "source": "24-25 二年级上·山东临沂·期中"
+  },
+  {
+    "id": "440",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "二年级参加篮球社团的有 18 人，参加乒乓球社团的人数比篮球社团的多 9 人。参加乒乓球社团的有( )人，参加篮球社团和乒乓球社团的一共有( )人。",
+    "options": [],
+    "answer": "27;45",
+    "solution": "【分析】因为参加乒乓球社团的人数比篮球社团的多9人，根据加法的意义，用18 + 9先求出乒乓球社团的人数，再将两个社团的人数相加，即可得出答案.\n【详解】18 + 9 = 27(人),参加乒乓球社团的有27人。18 + 27 = 45(人),参加篮球社团和乒乓球社团的一共有45人。",
+    "knowledge_points": [
+      "一位数与两位数的进位加法",
+      "两位数与两位数的进位加法"
+    ],
+    "source": "24-25 二年级上·河南商丘·期中"
+  },
+  {
+    "id": "441",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "计算 65 - 27 + 19 时，要先算( )法，再算( )法，结果是( )。",
+    "options": [],
+    "answer": "减;加;57",
+    "solution": "【分析】只有加减法的混合运算，要从左往右计算，由此解答.\n【详解】![](images/2026-02-13%20231203.jpg)\n\n计算 65 - 27 + 19 时，要先算减法，再算加法，结果是 57。",
+    "knowledge_points": [
+      "无括号的运算顺序",
+      "100以内数的加减混合运算"
+    ],
+    "source": "24-25 二年级上·河南商丘·期中"
+  },
+  {
+    "id": "442",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "比 72 少 15 的数是( );( )比 36 多 15。",
+    "options": [],
+    "answer": "57;51",
+    "solution": "【分析】求比一个数少几的数，用减法计算;求比一个数多几的数，用加法计算.\n【详解】72 - 15 = 57,36 + 15 = 51，则比 72 少 15 的数是 57;51 比 36 多 15。",
+    "knowledge_points": [
+      "两位数与两位数的退位减法",
+      "两位数与两位数的进位加法"
+    ],
+    "source": "24-25 二年级上·河南周口·期中"
+  },
+  {
+    "id": "443",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "二(2)班有男生 27 人，女生 16 人，男生比女生多( )人。",
+    "options": [],
+    "answer": "11",
+    "solution": "【分析】求一个数比另一个数多多少，用这个数 - 另一个数计算，即男生的人数 - 女生的人数 = 男生比女生多的人数.\n【详解】27 - 16 = 11(人),二(2)班有男生27人，女生16人，男生比女生多11人。",
+    "knowledge_points": [
+      "两位数与两位数的不退位减法"
+    ],
+    "source": "24-25 二年级上·山东济南·期中"
+  },
+  {
+    "id": "444",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "( )米 = 100 厘米;2 米 = ( )厘米;1 米 - 81 厘米 = ( )厘米;9 米 - 8 米 = ( )厘米",
+    "options": [],
+    "answer": "1;200;19;100",
+    "solution": "【分析】同单位的直接相加减，不同单位的根据1米 = 100 厘米换算单位即可。第1题:100个1厘米是100厘米，也是1米;第 2 题:2 米是 2 个 1 米，也就是 2 个 100 厘米，是 200 厘米;第 3 题：将 1 米换算为 100 厘米再计算;第4题：计算出结果再换算即可.\n【详解】1米 = 100 厘米;2 米 = 200 厘米;1米 - 81厘米 = 100 厘米 - 81厘米 = 19 厘米;9 米 - 8 米 = 1 米 = 100 厘米",
+    "knowledge_points": [
+      "厘米和米之间的进率与换算",
+      "两，三位数的连续退位减法"
+    ],
+    "source": "24-25 二年级上·河南三门峡·期中"
+  },
+  {
+    "id": "445",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "( )比 35 多28,75 比 29 多( )。",
+    "options": [],
+    "answer": "63;46",
+    "solution": "【分析】求比35多28的数是多少，用加法计算;求75比29 多多少，用减法计算.\n【详解】 35 + 28 = 63,75 - 29 = 46,63 比 35 多 28,75 比 29 多 46。",
+    "knowledge_points": [
+      "两位数与两位数的退位减法",
+      "两位数与两位数的进位加法"
+    ],
+    "source": "24-25 二年级上·湖北武汉·期中"
+  },
+  {
+    "id": "446",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "比 57 多 16 的数是( );91 比 26 多( )。",
+    "options": [],
+    "answer": "73;65",
+    "solution": "【分析】求比一个数多几的数是多少，用这个数 + 多的数计算;求一个数比另一个数多几，用这个数 - 另一个数计算.\n【详解】 57 + 16 = 73;91 - 26 = 65，比 57 多 16 的数是 73;91 比 26 多 65。",
+    "knowledge_points": [
+      "两位数与两位数的退位减法",
+      "两位数与两位数的进位加法"
+    ],
+    "source": "24-25 二年级上·河南南阳·期中"
+  },
+  {
+    "id": "447",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "1 米 = ( )厘米;58 厘米 + 22 厘米 = ( )厘米;95 厘米 - 70 厘米 = ( )厘米",
+    "options": [],
+    "answer": "100;80;25",
+    "solution": "【分析】同单位的直接相加减，不同单位的根据1米 = 100 厘米换算单位即可.\n【详解】1 米 = 100 厘米;58 厘米 + 22 厘米 = 80 厘米;95 厘米 - 70厘米 = 25 厘米",
+    "knowledge_points": [
+      "厘米和米之间的进率与换算",
+      "两位数与两位数的进位加法"
+    ],
+    "source": "24-25 二年级上·山东青岛·期中"
+  },
+  {
+    "id": "448",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "45 厘米 + 6 厘米 = ( )厘米;30 厘米 + 70 厘米 = ( )厘米",
+    "options": [],
+    "answer": "51;100",
+    "solution": "【分析】由于前后的单位相同，根据加法的计算方法，直接相加即可.\n【详解】45 厘米 + 6 厘米 = 51 厘米;30 厘米 + 70 厘米 = 100 厘米",
+    "knowledge_points": [
+      "一位数与两位数的进位加法",
+      "厘米的认识",
+      "整十数之间的加减法"
+    ],
+    "source": "24-25 二年级上·山东济宁·期中"
+  },
+  {
+    "id": "449",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "45 比 72 少( );72 比( )多 19。",
+    "options": [],
+    "answer": "27;53",
+    "solution": "【分析】求一个数比另一个数少多少，用另一个数 - 这个数计算;已知一个数比另一个数多几，求另一个数，用这个数 - 多的数计算.\n【详解】72 - 45 = 27;72 - 19 = 53,45比72少27;72比53多19。",
+    "knowledge_points": [
+      "两位数与两位数的退位减法"
+    ],
+    "source": "24-25 二年级上·山东济南·期中"
+  },
+  {
+    "id": "450",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "芳芳收集了 36 片叶子，给丽丽6片后，芳芳和丽丽的叶子数量就一样多了，丽丽原来收集了( )片叶子。",
+    "options": [],
+    "answer": "24",
+    "solution": "【分析】根据题意，先用芳芳原有的叶子数量 - 给丽丽的数量，求出芳芳现在有多少片叶子，也就是丽丽现在有多少片叶子，再减去芳芳给丽丽的数量，就是丽丽原来的数量.\n【详解】36 - 6 - 6 = 24(片),芳芳收集了36片叶子，给丽丽6片后，芳芳和丽丽的叶子数量就一样多了，丽丽原来收集了24片叶子。",
+    "knowledge_points": [
+      "100 以内数的连减运算"
+    ],
+    "source": "24-25 二年级上·河南郑州·期中"
+  },
+  {
+    "id": "451",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "海王星有 14 颗已知卫星，天王星比海王星多13颗已知卫星，比木星少65颗已知卫星，木星有( )颗已知卫星。",
+    "options": [],
+    "answer": "92",
+    "solution": "【分析】用海王星有的颗数加天王星比海王星多的颗数可以算出天王星有的颗数，然后用天王星有的颗数加天王星比木星少的颗数即可求出木星有多少颗已知卫星.\n【详解】14 + 13 = 27(颗),27 + 65 = 92(颗),木星有92颗已知卫星。",
+    "knowledge_points": [
+      "两位数与两位数的不进位加法",
+      "两位数与两位数的进位加法"
+    ],
+    "source": "24-25 二年级上·河南郑州·期中"
+  },
+  {
+    "id": "452",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "94 - 24 的差个位上的数字是( );88 - 72 的差十位上的数字是( )。",
+    "options": [],
+    "answer": "0;1",
+    "solution": "【分析】两位数与两位数的不退位减法计算时，从个位算起，个位数字减个位数字，十位数字减十位数字。94 减 24个位都是4，相减后个位上的数字是0，十位相减是:9 - 2 = 7，所以94 - 24 = 70;88 减 72 个位是:8 - 2 = 6，十位是:8 - 7 = 1，所以88 - 72 = 16.\n【详解】根据分析可知,94 - 24的差个位上的数字是0;88 - 72的差十位上的数字是1。",
+    "knowledge_points": [
+      "两位数与两位数的不退位减法",
+      "100以内数的组成"
+    ],
+    "source": "24-25 二年级上·广西玉林·期中"
+  },
+  {
+    "id": "453",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "小红身高90厘米，王磊身高98厘米，王磊比小红高( )厘米，王磊还要再长( )厘米，他的身高就是1米。",
+    "options": [],
+    "answer": "8;2",
+    "solution": "【分析】根据减法的意义，王磊的身高 - 小红的身高 = 王磊比小红高的高度;1米 - 王磊的身高 = 到1米时，王磊还要再长的高度。根据1米 = 100 厘米换算单位再计算.\n【详解】98 - 90 = 8(厘米),1 米 - 98 厘米 = 100 厘米 - 98 厘米 = 2 厘米，小红身高 90 厘米，王磊身高 98 厘米，王磊比小红高 8 厘米，王磊还要再长2厘米，他的身高就是1米。",
+    "knowledge_points": [
+      "厘米和米之间的进率与换算",
+      "两位数与两位数的退位减法"
+    ],
+    "source": "24-25二年级上·广西玉林·期中"
+  },
+  {
+    "id": "454",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "填\" > \" \" < \"或\"=\".\n\n1 米( )90 厘米;43( )60 - 37\n\n70 厘米 + 30 厘米( )2 米;27 + 25( )74 - 26",
+    "options": [],
+    "answer": ">;>;<;>",
+    "solution": "【分析】单位不统一的先转换成统一单位再比较大小,1米 = 100 厘米，有算式的要算出算式的结果再进行比较大小，据此解答.\n【详解】1 米 = 100 厘米,100 厘米 > 90 厘米，故1米 > 90厘米;60 - 37 = 23,43 > 23，故43 > 60 - 37;70 厘米 + 30 厘米 = 100 厘米 = 1 米,1 米 < 2 米，故70厘米 + 30厘米 < 2米;27 + 25 = 52,74 - 26 = 48,52 > 48，故27 + 25 > 74 - 26。",
+    "knowledge_points": [
+      "厘米和米之间的进率与换算",
+      "100以内数的比大小",
+      "两位数与两位数的退位减法",
+      "两位数与两位数的进位加法"
+    ],
+    "source": "24-25 二年级上·山东日照·期中"
+  },
+  {
+    "id": "455",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "64 比 91 少( ),( )比 18 多 52。",
+    "options": [],
+    "answer": "27;70",
+    "solution": "【分析】根据求一个数比另一个数少多少用减法计算，用大数减小数即可求出少的数;求比一个数多多少是多少的数用加法计算，用小数加多出的数即可求出大数。据此解答.\n【详解】91 - 64 = 27,52 + 18 = 70,64 比 91 少 27,70 比 18 多 52。",
+    "knowledge_points": [
+      "两位数与两位数的退位减法",
+      "两位数与两位数的进位加法"
+    ],
+    "source": "24-25 二年级上·山东日照·期中"
+  },
+  {
+    "id": "456",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "计算 23 + (60 - 29)时，应先算( )法，再算( )法，结果得( )。",
+    "options": [],
+    "answer": "减;加;54",
+    "solution": "【分析】只有加减法的混合运算，从左往右计算;若有括号，则先算括号里面的，再算括号外面的，由此解答.\n【详解】23 + (60 - 29)= 23 + 31 = 54，计算 23 + (60 - 29)时，应先算减法，再算加法，结果得54。",
+    "knowledge_points": [
+      "带有小括号的混合运算",
+      "100以内数的加减混合运算"
+    ],
+    "source": "24-25 二年级上·山东日照·期中"
+  },
+  {
+    "id": "457",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "把 26,27,28,29填入括号中，使算式成立:( ) + ( ) - ( ) = ( )。",
+    "options": [],
+    "answer": "26;29;27;28",
+    "solution": "【分析】根据 26 + 29 = 27 + 28 可以有8种填法:26 + 29 - 27 = 28,26 + 29 - 28 = 27,29 + 26 - 27 = 28,29 + 26 - 28 = 27,27 + 28 - 26 = 29,27 + 28 - 29 = 26,28 + 27 - 29 = 26,28 + 27 - 26 = 29，任选一个填入即可.\n【详解】把26,27,28,29填入括号中，使算式成立:26 + 29 - 27 = 28。(答案不唯一)",
+    "knowledge_points": [
+      "两位数与两位数的进位加法",
+      "100以内数的加减混合运算"
+    ],
+    "source": "24-25 二年级上·湖北孝感·期中"
+  },
+  {
+    "id": "458",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "计算 48 - 2□ 时，当□中填( )时需要退位;算式 4○ + 2☆ = 72，那么○ + ☆ = ( )。",
+    "options": [],
+    "answer": "9;12",
+    "solution": "【分析】减法计算时，相同数位对齐，从个位减起，哪一位不够减就向前一位借1当十。加法计算时，相同数位对齐，从个位加起，哪一位相加满十就向前一位进 1。需要退位，则方框里的数应该比8大。十位上的4和2相加得6，说明有进位，则○ + ☆的得数是12.\n【详解】计算48 - 2□时，当□中填9时需要退位;算式4○ + 2☆ = 72，那么○ + ☆ = 12。",
+    "knowledge_points": [
+      "两位数与两位数的退位减法",
+      "两位数与两位数的进位加法"
+    ],
+    "source": "24-25 二年级上·湖北孝感·期中"
+  },
+  {
+    "id": "459",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "在括号里填上\" > \" \" < \"或\" = \".\n\n46 + 38( )100;61 - 21 - 6( )61 - (21 - 6);9 米( )90 厘米\n86 - 17( )60;4 + 4 - 4( )4×2;30 厘米( )1 米 - 70厘米",
+    "options": [],
+    "answer": "<;<;>;>;<;=",
+    "solution": "【分析】据题意，是对数字之间的大小比较，首先要将需要计算的算式计算出结果，再进行结果的比较。计算时，相同数位对齐，加法时，满十进一;减法时，哪一位上不够减，向前一位借一当十，有括号的先计算括号里面的，依次进行计算即可;长度单位的比较时，需要进行单位的换算 1 米 = 100 厘米，换算完成后再进行计算。考查学生两位数的加减计算和长度单位之间的换算和计算.\n【详解】46 + 38 = 84,84 < 100，所以46 + 38 < 100;61 - 21 - 6 = 34,61 - (21 - 6)= 46,34 < 46，所以61 - 21 - 6 < 61 - (21 - 6);9 米 = 900 厘米,900 厘米 > 90 厘米，所以9米 > 90厘米;86 - 17 = 69,69 > 60，所以86 - 17 > 60;4 + 4 - 4 = 4,4×2 = 8,4 < 8，所以4 + 4 - 4 < 4×2;1 米 = 100 厘米,100厘米 - 70厘米 = 30 厘米，所以30厘米 = 1 米 - 70 厘米。",
+    "knowledge_points": [
+      "厘米和米之间的进率与换算",
+      "两位数与两位数的退位减法",
+      "带有小括号的混合运算",
+      "两位数与两位数的进位加法"
+    ],
+    "source": "24-25 二年级上·湖北孝感·期中"
+  },
+  {
+    "id": "460",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "( )比 39 多25,47 比( )少 24。",
+    "options": [],
+    "answer": "64;71",
+    "solution": "【分析】求比一个数多几的数是多少，用加法计算，求比39多25的数是多少，相加即可得出答案;求一个数比几少多少，用加法计算，求 47 比几少 24，相加即可得出答案.\n【详解】 39 + 25 = 64,47 + 24 = 71,64 比 39 多 25,47 比 71 少 24。",
+    "knowledge_points": [
+      "两位数与两位数的进位加法"
+    ],
+    "source": "24-25 二年级上·河北保定·期中"
+  },
+  {
+    "id": "461",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "买一杯5元6角的饮料，付了 10 元，应找回( )元( )角。",
+    "options": [],
+    "answer": "4;4",
+    "solution": "【分析】据题意，人民币1元 = 10角，可先用10元减去5元，再用5元减6角，可将元转换为角，再计算，即可得出答案。考查学生人民币的换算和计算.\n【详解】10 元 - 5 元 6 角 = 4 元 4 角。买一杯5元6角的饮料，付了10元，应找回4元4角。",
+    "knowledge_points": [
+      "元，角，分的认识及换算",
+      "十元以下人民币的认识与计算"
+    ],
+    "source": "24-25二年级上·广东韶关·期中"
+  },
+  {
+    "id": "462",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "妈妈今年给小红买了12本故事书。买的科技书比故事书多6本。妈妈给小红买了( )本科技书，两种书一共买了( )本。",
+    "options": [],
+    "answer": "18;30",
+    "solution": "【分析】求比一个数多几的数是多少，用这个数 + 多的数计算，即买故事书的数量 + 买科技书比故事书多的数量 = 买科技书的数量;求一共买了多少本，用加法计算，即买故事书的数量 + 买科技书的数量 = 买的总数量.\n【详解】 12 + 6 = 18(本),12 + 18 = 30(本),妈妈今年给小红买了12本故事书。买的科技书比故事书多6 本。妈妈给小红买了 18 本科技书，两种书一共买了 30 本。",
+    "knowledge_points": [
+      "不进位加法(20以内)",
+      "两位数与两位数的进位加法"
+    ],
+    "source": "24-25 二年级上·河北唐山·期中"
+  },
+  {
+    "id": "463",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "如图，交换( )和( )两个球，可以使天平两边三个数的和相等.\n\n![](images/787d7013480cb31bbba6028b0255dcc03e90586ef517797523d97ecffc561e08.jpg)",
+    "options": [],
+    "answer": "5;9",
+    "solution": "【分析】观察，两边都有32，所以只需在另外4个球里面交换即可。让最大的数和最小的数在一起，中间的两个数在一起，将5和9交换，即可使14和5在一起,10和9在一起.\n【详解】 5 < 9 < 10 < 14,32 + 10 + 9 = 51,32 + 5 + 14 = 51，交换5和9两个球，可以使天平两边三个数的和相等。",
+    "knowledge_points": [
+      "20 以内数的比大小",
+      "100 以内数的连加运算"
+    ],
+    "source": "24-25 二年级上·福建福州·期中"
+  },
+  {
+    "id": "464",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "二(2)班有 23 名女生,16 名男生去看电影,40 个座位够坐吗。",
+    "options": [],
+    "answer": "够",
+    "solution": "【分析】根据题意可知：用女生的人数加男生的人数求出共有的人数，然后和40比较，大于40则不够，小于等于40 则够.\n【详解】 23 + 16 = 39(人),39 < 40，答:40 个座位够坐。",
+    "knowledge_points": [
+      "两位数与两位数的不进位加法",
+      "100以内数的比大小"
+    ],
+    "source": "24-25 二年级上·湖北武汉·期中"
+  },
+  {
+    "id": "465",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "二年级 3 班共有 45 人，课后服务时参加跳绳和踢足球两项户外活动，参加跳绳的有 18 人，参加踢足球的有 16 人，全班还剩( )人没有参加户外活动。",
+    "options": [],
+    "answer": "11",
+    "solution": "【分析】根据减法的意义，总人数 - 参加跳绳的人数 - 参加踢足球的人数 = 没有参加户外活动的人数.\n【详解】45 - 18 - 16 = 11(人),全班还剩11人没有参加户外活动。",
+    "knowledge_points": [
+      "100 以内数的连减运算"
+    ],
+    "source": "24-25 二年级上·河北保定·期中"
+  },
+  {
+    "id": "466",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "36 比 63 少( ),75 比 25 多( )。",
+    "options": [],
+    "answer": "27;50",
+    "solution": "【分析】求一个数比另一个数少多少，用另一个数 - 这个数计算;求一个数比另一个数多多少，用这个数 - 另一个数计算.\n【详解】63 - 36 = 27;75 - 25 = 50,36比63少27,75比25多50。",
+    "knowledge_points": [
+      "两位数与两位数的不退位减法",
+      "两位数与两位数的退位减法"
+    ],
+    "source": "24-25 二年级上·河南南阳·期中"
+  },
+  {
+    "id": "467",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "计算两位数的加减法要从个位开始算。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】本题根据竖式计算的法则来解答即可。加法：相同数位对齐，从个位算起，个位相加满十，向十位进 1。减法：相同数位对齐，从个位算起，个位不够减，从十位退1作十计算。由此解答.\n【详解】计算两位数的加减法要从个位开始算。原题说法正确。例:24 + 28 = 52;50 - 22 = 28\n![](images/2026-02-15%20155011.jpg)\n故答案为:√",
+    "knowledge_points": [
+      "两位数与两位数的退位减法",
+      "两位数与两位数的进位加法"
+    ],
+    "source": "24-25 二年级上·河南漯河·期中"
+  },
+  {
+    "id": "468",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "判断题",
+    "difficulty": 0.65,
+    "question": "比58多22的数是70。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】求比一个数多几的数是多少，用这个数 + 多的数计算，由此解答.\n【详解】58 + 22 = 80，比58多22的数是80。原题说法错误。故答案为: ×",
+    "knowledge_points": [
+      "两位数与两位数的进位加法"
+    ],
+    "source": "24-25二年级上·广东汕头·期中"
+  },
+  {
+    "id": "469",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "计算退位减法时，十位上退 1 后，计算十位时要先减去 1 再计算。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】整数减法计算法则：相同数位对齐，从低位减起，哪一位上的数不够减，就从它的前一位退一作十，和本位上的数合并在一起，再减。据此解答即可.\n【详解】根据分析可知，计算退位减法时，十位上退1后，计算十位时要先减去 1 再计算。例如:![](images/2026-02-15%20155157.jpg) ,个位上的 5 不够减，从十位上的 7 退一作十，和本位上的5合并在一起减去7;十位上此时是 7 - 1 = 6，用十位上的6再减去2即可;原说法正确。故答案为:√",
+    "knowledge_points": [
+      "两位数与两位数的退位减法"
+    ],
+    "source": "24-25二年级上·广西玉林·期中"
+  },
+  {
+    "id": "470",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.65,
+    "question": "元旦节，超市里搞满60元就优惠10元的促销活动，妈妈买一袋大米45元，买一袋面粉 17 元，妈妈需要付多少元。",
+    "options": [],
+    "answer": "52 元",
+    "solution": "【分析】根据题意，先用加法计算出一袋大米和一袋面粉共多少元，再和60比较大小，若大于或等于60元，则再减10元是实际要付的钱数.\n【详解】45 + 17 = 62(元),62 > 60,62 - 10 = 52(元),答：妈妈需要付52元。",
+    "knowledge_points": [
+      "100以内数的比大小",
+      "促销问题",
+      "两位数与整十数的减法",
+      "两位数与两位数的进位加法"
+    ],
+    "source": "23-24二年级上·重庆永川·期末"
+  },
+  {
+    "id": "471",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.85,
+    "question": "河里有53只鸭子，鹅的只数比鸭子少26只，鹅有多少只。鸭子和鹅一共有多少只。",
+    "options": [],
+    "answer": "27 只;80 只",
+    "solution": "【分析】已知河里有53只鸭子，鹅比鸭子少26只，用鸭子的数量减26即可得出鹅的数量，将鸭子的数量和鹅的数量相加即可得出一共有多少只.\n【详解】53 - 26 = 27(只),53 + 27 = 80(只),答：鹅有27只，鸭子和鹅一共有80只。",
+    "knowledge_points": [
+      "两位数与两位数的退位减法",
+      "两位数与两位数的进位加法"
+    ],
+    "source": "24-25二年级上·河南驻马店·期中"
+  },
+  {
+    "id": "472",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.65,
+    "question": "学校舞蹈队有女生 25 人，男生17人，一共有多少人。合唱队共有35人，比舞蹈队少多少人。",
+    "options": [],
+    "answer": "42 人;7 人",
+    "solution": "【分析】求一共有多少人，用加法计算，即女生的人数 + 男生的人数 = 总人数;求一个数比另一个数少几，用另一个数 - 这个数计算，即舞蹈队的人数 - 合唱队的人数 = 合唱队比舞蹈队少的人数.\n【详解】25 + 17 = 42(人),答：一共有42人。42 - 35 = 7(人),答：合唱队比舞蹈队少7人。",
+    "knowledge_points": [
+      "两位数与两位数的退位减法",
+      "两位数与两位数的进位加法"
+    ],
+    "source": "24-25 二年级上·重庆·期中"
+  },
+  {
+    "id": "473",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.65,
+    "question": "白云超市进行十周年店庆大酬宾活动.\n\n![](images/2026-02-15%20155715.jpg)\n\n(1)两种杯子，妈妈各买一盒，一共花了多少元。\n(2)妈妈想买一个书包和一把雨伞，实际要付多少元。",
+    "options": [],
+    "answer": "55 元;77 元",
+    "solution": "【分析】(1)根据题意，先用加法计算出两种杯子的总价钱，若大于或等于60元，则再减5元是实际要付的钱数;若大于或等于80元，则再减8元是实际要付的钱数。(2)根据题意，先用加法计算出一个书包和一把雨伞的总价钱，若大于或等于60元，则再减5元是实际要付的钱数;若大于或等于80元，则再减8元是实际要付的钱数.\n【详解】(1)36 + 24 = 60(元),60 = 60,60 - 5 = 55(元),答：一共花了55元。(2)58 + 27 = 85(元),85 > 80,85 - 8 = 77(元),答：实际要付77元。",
+    "knowledge_points": [
+      "一位数与两位数的退位减法",
+      "100以内数的比大小",
+      "图文问题",
+      "两位数与两位数的进位加法"
+    ],
+    "source": "24-25 二年级上·山东临沂·期中"
+  },
+  {
+    "id": "474",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.65,
+    "question": "网上购物狂欢节，满 88 元减 12 元。妈妈要买如图的两件衣服，需要付多少元。\n\n![](images/2026-02-15%20160008.jpg)",
+    "options": [],
+    "answer": "84 元",
+    "solution": "【分析】根据题意，先用加法计算出两件衣服一共需要多少钱，再和88比较大小，若大于或等于88元需要再减12元是要付的钱数.\n【详解】54 + 42 = 96(元),96 > 88,96 - 12 = 84(元),答：需要付84元。",
+    "knowledge_points": [
+      "两位数与两位数的不进位加法",
+      "两位数与两位数的不退位减法",
+      "100以内数的比大小",
+      "图文问题"
+    ],
+    "source": "24-25 二年级上·广东韶关·期中"
+  },
+  {
+    "id": "475",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.65,
+    "question": "两个班一共有多少人。如果每人发一顶帽子，还差多少顶帽子。\n\n![](images/d88325a6e3f03e28536b471fa7e0e83499f08326885cd4d975d821f1433422bc.jpg)",
+    "options": [],
+    "answer": "73 人;13 顶",
+    "solution": "【分析】求一共有多少人，用加法计算，即一个班的人数 + 另一个班的人数 = 总人数;共有多少人就需要多少顶帽子，则用需要的帽子数量 - 已经有的帽子数量 = 还差的帽子数量.\n【详解】37 + 36 = 73(人),73 - 60 = 13(顶),答：两个班一共有73人;还差13顶帽子。",
+    "knowledge_points": [
+      "图文问题",
+      "两位数与整十数的减法",
+      "两位数与两位数的进位加法"
+    ],
+    "source": "24-25二年级上·广东汕头·期中"
+  },
+  {
+    "id": "476",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.65,
+    "question": "公共汽车上原来有64 人。到一个站台后，下去 26 人，上来 19 人。现在公共汽车上有多少人。",
+    "options": [],
+    "answer": "57 人",
+    "solution": "【分析】根据题意，下去的人数要减去，上来的人数要加上，则现在的人数 = 原来的人数 - 下去的人数 + 上来的人数，由此解答.\n【详解】64 - 26 + 19 = 57(人),答：现在公共汽车上有57人。",
+    "knowledge_points": [
+      "100 以内数的加减混合运算"
+    ],
+    "source": "24-25 二年级上·广西南宁·期中"
+  },
+  {
+    "id": "477",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.65,
+    "question": "英才小学开展\"变废为宝\"主题活动。二(1)班同学用废弃塑料瓶制作了 52件手工艺品，比二(2)班多 16 件，二(2)班制作了多少件。两个班一共制作了多少件。",
+    "options": [],
+    "answer": "36 件;88 件",
+    "solution": "【分析】已知一个数比另一个数多几，求另一个数，用这个数 - 多的数计算，即用二(1)班制作的数量减去二(1)班比二(2)班多制作的数量，就是二(2)班制作的数量;求两个班一共制作了多少件，用加法计算，即用二(1)班制作的数量加上二(2)班制作的数量，就是两个班一共制作的数量.\n【详解】52 - 16 = 36(件),52 + 36 = 88(件),答：二(2)班制作了36件，两个班一共制作了88件。",
+    "knowledge_points": [
+      "两位数与两位数的不进位加法",
+      "两位数与两位数的退位减法"
+    ],
+    "source": "24-25 二年级上·福建三明·期中"
+  },
+  {
+    "id": "478",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.65,
+    "question": "秋天到了王伯伯果园共收了 65 箱苹果，昨天卖了 17 箱，今天卖了 25 箱，还剩下多少箱苹果没卖。",
+    "options": [],
+    "answer": "23 箱",
+    "solution": "【分析】根据减法的意义，收苹果的总箱数 - 昨天卖了的箱数 - 今天卖了的箱数 = 还剩的箱数，把数据代入计算即可解答.\n【详解】65 - 17 - 25 = 23(箱),答：还剩下23箱苹果没卖。",
+    "knowledge_points": [
+      "100以内数的连减运算"
+    ],
+    "source": "24-25 二年级上·山东济宁·期中"
+  },
+  {
+    "id": "479",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.65,
+    "question": "小梅在计算 37 加一个一位数时，把这个一位数加到37的十位上了，结果得到87。正确的结果是多少。",
+    "options": [],
+    "answer": "42",
+    "solution": "【分析】根据题意，用错误的和减去37，求出错误的加数。正确的加数是一位数，也就是错误加数十位上的数，再和37相加就是正确的得数.\n【详解】87 - 37 = 50,37 + 5 = 42，答：正确的结果是42。",
+    "knowledge_points": [
+      "两位数与两位数的不退位减法",
+      "一位数与两位数的进位加法"
+    ],
+    "source": "24-25 二年级上·福建福州·期中"
+  },
+  {
+    "id": "480",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.65,
+    "question": "迎国庆，学校准备了一些花装点校园。菊花有 75 盆，月季花比菊花少 8 盆。月季花有多少盆。",
+    "options": [],
+    "answer": "67 盆",
+    "solution": "【分析】根据题意，菊花有75盆，月季花比菊花少8盆。用菊花的数量减去8盆，即可求出月季花有多少盆。用减法列式计算.\n【详解】75 - 8 = 67(盆),答：月季花有67盆。",
+    "knowledge_points": [
+      "一位数与两位数的退位减法"
+    ],
+    "source": "24-25 二年级上·河南南阳·期中"
+  },
+  {
+    "id": "481",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.85,
+    "question": "3月12日植树节到了，二年级同学要植 90 棵树，第一天植了 34 棵树，第二天植了29棵树，还剩多少棵树没植完。",
+    "options": [],
+    "answer": "27 棵",
+    "solution": "【分析】用一共要植树的棵数减去第一天的植树棵数，求出差，再减去第二天的植树棵数，求出差，即可解决.\n【详解】90 - 34 - 29 = 56 - 29 = 27(棵),答：还剩27棵树没植完。",
+    "knowledge_points": [
+      "100 以内数的连减运算"
+    ],
+    "source": "23-24二年级上·湖南湘西·期末"
+  },
+  {
+    "id": "482",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.85,
+    "question": "图书角有 48 本书，借出 37 本，还回 19 本，现在图书角有多少本书。",
+    "options": [],
+    "answer": "30 本",
+    "solution": "【分析】根据题意可知：求现在图书角有多少本书。用原有的数量减去借出的数量，再加上还回的数量即可.\n【详解】48 - 37 + 19 = 11+19 = 30(本),答：现在图书角有30本书。",
+    "knowledge_points": [
+      "100以内数的加减混合运算"
+    ],
+    "source": "24-25 二年级上·河北沧州·期中"
+  },
+  {
+    "id": "483",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.65,
+    "question": "小明有 36 本故事书，小东的故事书比小明多 15 本，小东有多少本故事书。",
+    "options": [],
+    "answer": "51 本",
+    "solution": "【分析】求比一个数多几的数是多少，用这个数 + 多的数计算，即小明故事书的数量 + 小东比小明多的数量 = 小东故事书的数量.\n【详解】36 + 15 = 51(本),答：小东有51本故事书。",
+    "knowledge_points": [
+      "两位数与两位数的进位加法"
+    ],
+    "source": "23-24 二年级上·重庆璧山·期末"
+  },
+  {
+    "id": "484",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.85,
+    "question": "红星小学二(4)班原来有 42 人，新学期转来了 4 人，转走了 6 人，现在二(4)班有学生多少人。",
+    "options": [],
+    "answer": "40 人",
+    "solution": "【分析】已知班内原来有42人，转来了4人，又转走了6人，转来的可用加法计算，转走的可用减法计算，即原有人数加上转来的减去转走的，即可得出现有的人数.\n【详解】42 + 4 - 6 = 46 - 6 = 40(人),答：现在二(4)班有学生40人。",
+    "knowledge_points": [
+      "100以内数的加减混合运算"
+    ],
+    "source": "24-25二年级上·广西玉林·期中"
+  },
+  {
+    "id": "485",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.85,
+    "question": "一班有36人参加校运动会，二班比一班多9人参加，二班有多少人参加校运动会。一班和二班一共有多少人参加校运动会。",
+    "options": [],
+    "answer": "45 人;81 人",
+    "solution": "【分析】根据题意可知：求比一个数多几的数，用加法计算，可求出二班的人数，然后再加上一班的人数即可求出一班和二班一共有多少人参加校运动会.\n【详解】36 + 9 = 45(人),45 + 36 = 81(人),答：二班有45人参加校运动会，一班和二班一共有81人参加校运动会。",
+    "knowledge_points": [
+      "一位数与两位数的进位加法",
+      "两位数与两位数的进位加法"
+    ],
+    "source": "24-25二年级上·湖北武汉·期中"
+  },
+  {
+    "id": "486",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.85,
+    "question": "一根1米长的绳子，第一次用去了30厘米，第二次用去了40厘米，这根绳子还剩多少厘米。",
+    "options": [],
+    "answer": "30 厘米",
+    "solution": "【分析】根据题意可知：求还剩多少厘米，用原有的长度减去第一次用去的长度再减去第二次用去的长度即可。然后根据1米 = 100 厘米将单位换算统一再计算.\n【详解】1米 = 100 厘米,100 - 30 - 40 = 70 - 40 = 30(厘米),答：这根绳子还剩30厘米。",
+    "knowledge_points": [
+      "厘米和米之间的进率与换算",
+      "100 以内数的连减运算"
+    ],
+    "source": "24-25二年级上·湖北武汉·期中"
+  },
+  {
+    "id": "487",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.65,
+    "question": "一本书92页，彤彤第一天看了29页，第二天看了34页，两天一共看了多少页。还剩多少页没看。",
+    "options": [],
+    "answer": "63 页;29 页",
+    "solution": "【分析】求两天一共看了多少页，用加法计算，即第一天看的页数 + 第二天看的页数 = 两天一共看的页数;求还剩多少页没看，用减法计算，即书的总页数 - 两天看了的页数 = 剩下没看的页数.\n【详解】29 + 34 = 63(页),92 - 63 = 29(页),答：两天一共看了63页，还剩29页没看。",
+    "knowledge_points": [
+      "两位数与两位数的退位减法",
+      "两位数与两位数的进位加法"
+    ],
+    "source": "24-25二年级上·河南三门峡·期中"
+  },
+  {
+    "id": "488",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.65,
+    "question": "桃林小学二(三)班有男生 32 人，女生比男生少 8 人，女生有多少人。全班有多少人。",
+    "options": [],
+    "answer": "24 人;56 人",
+    "solution": "【分析】求比一个数少几的数是多少，用减法计算，即男生的人数 - 女生比男生少的人数 = 女生的人数;求全班有多少人，用加法计算，即男生的人数 + 女生的人数 = 全班的人数.\n【详解】32 - 8 = 24(人),32 + 24 = 56(人),答：女生有24人，全班有56人。",
+    "knowledge_points": [
+      "一位数与两位数的退位减法",
+      "两位数与两位数的不进位加法"
+    ],
+    "source": "24-25二年级上·河南三门峡·期中"
+  },
+  {
+    "id": "489",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.65,
+    "question": "为了绿化环境，同学们去郊区植树，二年级(5)班植树42棵，二年级(6)班比二年级(5)班少植树14棵.\n\n(1)二年级(6)班植树多少棵。\n(2)两个班一共植树多少棵。",
+    "options": [],
+    "answer": "28 棵;70 棵",
+    "solution": "【分析】(1)根据题意，二年级(6)班比二年级(5)班少植树14棵。即比42棵少14棵，用减法计算。(2)求一共的棵数，将二年级(5)班和二年级(6)班棵数相加即可解答.\n【详解】(1)42 - 14 = 28(棵),答：二年级(6)班植树28棵。(2)42 + 28 = 70(棵),答：两个班一共植树70棵。",
+    "knowledge_points": [
+      "两位数与两位数的退位减法",
+      "两位数与两位数的进位加法"
+    ],
+    "source": "24-25 二年级上·山东菏泽·期中"
+  },
+  {
+    "id": "490",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.65,
+    "question": "小红有36个气球，比小华多 17 个。他们俩一共有多少个气球。",
+    "options": [],
+    "answer": "55 个",
+    "solution": "【分析】根据题意，小红有36个气球，比小华多17个。则小华比小红少17个，即比36少17个，用减法计算求出小华的数量，再加上小红的数量，即可求出一共的气球数量.\n【详解】36 - 17 + 36 = 19 + 36 = 55(个),答：他们俩一共有55个气球。",
+    "knowledge_points": [
+      "100 以内数的加减混合运算"
+    ],
+    "source": "24-25 二年级上·江西宜春·期中"
+  },
+  {
+    "id": "491",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.85,
+    "question": "同学们去郊游，二(1)班去了 19 人，二(2)班去了 18 人，二(3)班去了20 人，一共去了多少人。",
+    "options": [],
+    "answer": "57 人",
+    "solution": "【分析】求一共去了多少人，用加法计算，即二(1)班去的人数 + 二(2)班去的人数 + 二(3)班去的人数 = 去的总人数.\n【详解】19 + 18 + 20 = 57(人),答：一共去了57人。",
+    "knowledge_points": [
+      "100以内数的连加运算"
+    ],
+    "source": "24-25 二年级上·山东济南·期中"
+  },
+  {
+    "id": "492",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.65,
+    "question": "美术兴趣小组女生有25人，男生比女生少6人。男生有多少人。美术兴趣小组一共有多少人。",
+    "options": [],
+    "answer": "19 人;44 人",
+    "solution": "【分析】求比一个数少几的数是多少，用减法计算，即女生的人数 - 男生比女生少的人数 = 男生的人数;求一共有多少人，用加法计算，即女生的人数 + 男生的人数 = 总人数.\n【详解】25 - 6 = 19(人),25 + 19 = 44(人),答：男生有19人，美术兴趣小组一共有44人。",
+    "knowledge_points": [
+      "一位数与两位数的退位减法",
+      "两位数与两位数的进位加法"
+    ],
+    "source": "24-25 二年级上·广西玉林·期中"
+  },
+  {
+    "id": "493",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.85,
+    "question": "一捆丝绳长 100 米。一班先用去 20 米，又用去 38 米，这根丝绳比原来短了多少米。二班需要 40 米，剩下的丝绳够吗。",
+    "options": [],
+    "answer": "58 米;够",
+    "solution": "【分析】根据题意可知：求比原来短的米数，即求用去的米数，用一班先用去的米数加上又用去的米数即可;然后用总长度减去一班用去的长度求出剩下的米数，再和二班需要用的长度进行比较，大于或者等于二班需要的长度则够，小于则不够.\n【详解】20 + 38 = 58(米),100 - 58 = 42(米),42 > 40，答：这根丝绳比原来短了58米，二班需要40米，剩下的丝绳够。",
+    "knowledge_points": [
+      "两位数与两位数的退位减法",
+      "两位数与整十数的加法"
+    ],
+    "source": "24-25 二年级上·湖北孝感·期中"
+  },
+  {
+    "id": "494",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.65,
+    "question": "同学们在踢毽子，男生有 26 名，女生有 19 名.\n\n(1)踢毽子的一共有多少名同学。\n(2)男生比女生多多少名。",
+    "options": [],
+    "answer": "45 名;7 名",
+    "solution": "【分析】(1)求一共有多少名同学，用加法计算，即男生的人数 + 女生的人数 = 总人数;(2)求男生比女生多几名，用减法计算，即男生的人数 - 女生的人数 = 男生比女生多的人数.\n【详解】(1)26 + 19 = 45(名),答：踢毽子的一共有45名同学。(2)26 - 19 = 7(名),答：男生比女生多7名。",
+    "knowledge_points": [
+      "两位数与两位数的退位减法",
+      "两位数与两位数的进位加法"
+    ],
+    "source": "24-25 二年级上·河北保定·期中"
+  },
+  {
+    "id": "495",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.85,
+    "question": "为了绿化环境，同学们去郊区植树。二(1)班植树 45 棵，二(2)班比(1)班少植树17棵。二(2)班植树多少棵。两个班一共植树多少棵。\n\n![](images/9248c9685ad0352c2a615be2eb193febeeb988db4acf1e8ea9a17a443620d202.jpg)",
+    "options": [],
+    "answer": "28 棵;73 棵",
+    "solution": "【分析】求二(2)班植树多少棵，用二(1)班植树的数量减去二(2)班比(1)班少植树的数量，即可求出二(2)班植树的数量;把两个班植树的数量相加，即是一共植树的数量.\n【详解】二(2)班:45 - 17 = 28(棵),一共:28 + 45 = 73(棵),答：二(2)班植树28棵，两个班一共植树73棵。",
+    "knowledge_points": [
+      "两位数与两位数的退位减法",
+      "两位数与两位数的进位加法"
+    ],
+    "source": "24-25 二年级上·江西九江·期中"
+  },
+  {
+    "id": "496",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.65,
+    "question": "某电器商店原有 85台电视机，双十一当天，上午卖出 39 台，下午卖出 36 台，还剩下多少台电视机。(用两种方法计算)",
+    "options": [],
+    "answer": "10 台",
+    "solution": "【分析】求还剩多少台，可以用总数量减去上午卖出的数量，再减去下午卖出的数量，就是还剩的数量;也可以先用加法计算出上午和下午一共卖出的数量，再用总数量减去一共卖出的数量，就是还剩的数量.\n【详解】方法一:85 - 39 - 36 = 46 - 36 = 10(台);方法二:85 - (39 + 36) = 85 - 75 = 10(台),答：还剩下10台电视机。",
+    "knowledge_points": [
+      "100 以内数的连减运算",
+      "带有小括号的混合运算"
+    ],
+    "source": "24-25 二年级上·广东韶关·期中"
+  },
+  {
+    "id": "497",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.65,
+    "question": "在 2024 年巴黎奥运会中，中国代表团获得金牌数第一的好成绩.\n\n金牌 银牌 铜牌\n比银牌数多17枚 27枚 31枚\n\n(1)中国代表团得了几枚金牌。\n(2)中国代表团获得的金牌和银牌一共有几枚。\n(3)你还能提出什么数学问题。",
+    "options": [],
+    "answer": "44 枚;71 枚;中国代表团获得的银牌和铜牌一共有几枚。58 枚(答案不唯一)",
+    "solution": "【分析】(1)已知一个数比另一个数多多少，求一个数是几，用加法列式解决;(2)把金牌的数量与银牌的数量加起来，求出和，即可解决此题;(3)根据已知条件提出数学问题，合理即可.\n【详解】(1)27 + 17 = 44(枚),答：中国代表团得了44枚金牌。(2)44 + 27 = 71(枚),答：中国代表团获得的金牌和银牌一共有71枚。(3)中国代表团获得的银牌和铜牌一共有几枚。27 + 31 = 58(枚),答：中国代表团获得的银牌和铜牌一共有58枚。(答案不唯一)",
+    "knowledge_points": [
+      "两位数与两位数的不进位加法",
+      "\"提问题\"\"填条件\"问题",
+      "两位数与两位数的进位加法"
+    ],
+    "source": "24-25 二年级上·福建龙岩·期中"
+  },
+  {
+    "id": "498",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.85,
+    "question": "二(1)班同学订了36 份《趣味数学》,比《故事大王》少 16 份。二(1)班订了多少份《故事大王》。",
+    "options": [],
+    "answer": "52 份",
+    "solution": "【分析】已知一个数和一个数比另一个数少多少，求另一个数是几，用加法列式解决.\n【详解】36 + 16 = 52(份),答：二(1)班订了52份《故事大王》。",
+    "knowledge_points": [
+      "两位数与两位数的进位加法"
+    ],
+    "source": "24-25二年级上·福建福州·期中"
+  },
+  {
+    "id": "499",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.65,
+    "question": "为了庆祝国庆，外国语小学的孩子们用100厘米长的彩带做一些有趣的创意手工。做头花用去27厘米，做中国结用去43厘米，一共用去了多少厘米。还剩下多少厘米。",
+    "options": [],
+    "answer": "70 厘米;30 厘米",
+    "solution": "【分析】求一共用去了多少厘米，用加法计算，即做头花用的长度 + 做中国结用的长度 = 一共用去的长度;求还剩下多少厘米，用减法计算，即总长度 - 一共用去的长度 = 还剩下的长度.\n【详解】27 + 43 = 70(厘米),100 - 70 = 30(厘米),答：一共用去了70厘米，还剩下30厘米。",
+    "knowledge_points": [
+      "整十数之间的加减法",
+      "两位数与两位数的进位加法"
+    ],
+    "source": "24-25二年级上·河南南阳·期中"
+  },
+  {
+    "id": "500",
+    "unit": "第二单元100以内加法和减法(二)",
+    "question_type": "解答题",
+    "difficulty": 0.65,
+    "question": "上午，聪聪在开元寺大街的书摊上买了36元一本的《故事大王》和48元一本的《未来科技》,聪聪买下这两本书共花了多少钱。\n\n□ ○ □ = □(元)",
+    "options": [],
+    "answer": "84 元",
+    "solution": "【分析】求一共花了多少钱，用加法计算，即《故事大王》的钱数 + 《未来科技》的钱数 = 两本书一共花的钱数.\n【详解】36 + 48 = 84(元),答：聪聪买下这两本书共花了84元钱。",
+    "knowledge_points": [
+      "两位数与两位数的进位加法"
+    ],
+    "source": "24-25二年级上·河北保定·期中"
+  }
+]
diff --git "a/\344\272\214\345\271\264\347\272\247\351\242\230\351\233\206/\344\272\214\345\271\264\347\272\247\344\270\212/\344\272\214\345\271\264\347\272\247\344\270\212\347\254\254\344\272\224\345\215\225\345\205\203\350\247\202\345\257\237\347\211\251\344\275\223.json" "b/\344\272\214\345\271\264\347\272\247\351\242\230\351\233\206/\344\272\214\345\271\264\347\272\247\344\270\212/\344\272\214\345\271\264\347\272\247\344\270\212\347\254\254\344\272\224\345\215\225\345\205\203\350\247\202\345\257\237\347\211\251\344\275\223.json"
new file mode 100644
index 0000000000000000000000000000000000000000..567c285bd4ec40f6b74a7b728d1f606ba3e9d5bd
--- /dev/null
+++ "b/\344\272\214\345\271\264\347\272\247\351\242\230\351\233\206/\344\272\214\345\271\264\347\272\247\344\270\212/\344\272\214\345\271\264\347\272\247\344\270\212\347\254\254\344\272\224\345\215\225\345\205\203\350\247\202\345\257\237\347\211\251\344\275\223.json"
@@ -0,0 +1,5052 @@
+[
+  {
+    "id": "1",
+    "unit": "第五单元 观察物体",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "无论从哪个位置观察，看到的图都相同的是( )。",
+    "options": [
+      "A. ![](images/c2113b11701344df9db21cb9c56f1a1ac9d2587e65b0583c944621df3ee4ca75.jpg)",
+      "B. ![](images/43c0faa130ddba6e5f1123ea37a359034f1219aaad342f1d06a948817692e6cb.jpg)",
+      "C. ![](images/ccdaa5cbe9a303583ffa6925fe246da8e04d36fbe255dad39b308cbb0289930a.jpg)",
+      "D. ![](images/8b00d4e2ab6592792259b927174986232aaf254bed42f36fa5278693dc9ef160.jpg)"
+    ],
+    "answer": "C",
+    "solution": "【分析】观察A,从正面和上面看到的形状是长方形，而从侧面看到的是正方形，也就是从正面和侧面看到的形状是不相同的(或从侧面和上面看到的形状是不相同的);观察B,从正面和侧面看到的形状是长方形，而从上面看到的是圆形，也就是从正面和上面看到的形状是不相同的(或从侧面和上面看到的形状是不相同的);观察C,无论从哪个位置看到的都是圆;观察D,从侧面和上面看到的形状是长方形，而从正面看到的是正方形，也就是从正面和侧面看到的形状是不相同的(或从正面和上面看到的形状是不相同的).\n【详解】由分析可知：无论从哪个位置观察，看到的图都相同的是C。故答案为:C",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "25-26 三年级上·辽宁鞍山·阶段练习"
+  },
+  {
+    "id": "2",
+    "unit": "第五单元 观察物体",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "下图中从右面看到的是( ).\n\n![](images/d4e3f7f17d7b7efc169410e13534551b8fe785caa4d9a14d83baa17d78636689.jpg)",
+    "options": [
+      "A. ![](images/6dfa66d17fa7529b2d5478fbc1421fce6418993862fc870f422c457e7d4a5b32.jpg)",
+      "B. ![](images/921e65e62217bfd8a3345173afa41a9dc79468b86a172ae640a98f3890668244.jpg)",
+      "C. ![](images/a0caf250c17f22364c7cc160f062a1b2e3901e7cecd33ac420e0ffc37ff0cc2b.jpg)"
+    ],
+    "answer": "A",
+    "solution": "【分析】由图示可知，图中从右面看到的是车尾，从左面看到的是车头，从前面看到的是车身;据此解决.\n【详解】A。 这是从右面看到的;B。这是从左面看到的;C。这是从前面看到的。故答案为:A",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "23-24 二年级上·新疆乌鲁木齐·期末"
+  },
+  {
+    "id": "3",
+    "unit": "第五单元 观察物体",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "观察一个长方体，最多可以看到( )个相同的正方形。",
+    "options": [
+      "A. 1",
+      "B. 2",
+      "C. 3",
+      "D. 4"
+    ],
+    "answer": "B",
+    "solution": "【分析】长方体有6 个面，有三组相对的面完全相同，一般情况下六个面都是长方形，特殊情况时有两个面是正方形，其他四个面都是长方形，并且这四个面完全相同.\n【详解】据分析一个长方体，最多可以看到2 个相同的正方形。故答案为:B",
+    "knowledge_points": [
+      "长方体的认识及特征"
+    ],
+    "source": "24-25 二年级上·浙江温州·期末"
+  },
+  {
+    "id": "4",
+    "unit": "第五单元 观察物体",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "看到的立体图形的一个面是圆形，这个立体图形是我们学过的，它可能是( )。",
+    "options": [
+      "A. 正方体",
+      "B. 圆柱",
+      "C. 长方形"
+    ],
+    "answer": "B",
+    "solution": "【分析】长方体是长长方方的，有六个平平的面(特殊情况下有两个面是正方形);正方体是方方正正的，六个面都是正方形;圆柱上下是平平的面，且上下一样粗，上下面是圆形;长方形是平面图形。由此选择即可.\n【详解】A。正方体看到的面是正方形，不符合题意;B。圆柱从上面或下面看是圆形，符合题意;C。长方形是平面图形，不符合题意。所以它可能是圆柱。故答案为:B",
+    "knowledge_points": [
+      "长方形，正方形，三角形和圆的初步认识",
+      "从不同位置观察单个物体",
+      "平面图形与立体图形的对应",
+      "立体图形的认识及分类"
+    ],
+    "source": "24-25 二年级上·福建龙岩·期末"
+  },
+  {
+    "id": "5",
+    "unit": "第五单元 观察物体",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "看到的立体图形的一个面是正方形，这个立体图形不可能是( )。",
+    "options": [
+      "A. ![](images/43dff8b52a7f767f2d26612f6774851fcdd537f3a25bb08cddcf45ebd0886221.jpg)",
+      "B. ![](images/c60c1cabf5f39e8657e34e46619b8124d87c7982cc8f49a000dead7216aa395a.jpg)",
+      "C. ![](images/a2420217c4b14c99c798048b037ca946e1a03dbc641c71e1fcdfedcd6ffe5e6a.jpg)"
+    ],
+    "answer": "C",
+    "solution": "【分析】长方体可能有正方形的面;圆柱从侧面看可能是正方形;球从任何方向看都是圆形.\n【详解】A。长方体可能有正方形的面，也就可能会看到正方形;B。圆柱从侧面看可能是正方形;C。球从任何方向看都是圆形。所以这个立体图形不可能是球。故答案为:C",
+    "knowledge_points": [
+      "从不同位置观察单个物体",
+      "立体图形的认识及分类"
+    ],
+    "source": "20-21 二年级上·湖南长沙·期末"
+  },
+  {
+    "id": "6",
+    "unit": "第五单元 观察物体",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面( )图是小丽看到的.\n\n![](images/6f1158f90d62b09052ad1e37e88103a7e847e1a485fe488222e83c4c8d61b105.jpg)",
+    "options": [
+      "A. ![](images/41a88f9a42a6fd4f0b9c936e7ac4c7cd0d219acc0c9f4dea8c647e2fa7deae16.jpg)",
+      "B. ![](images/b45888b4eb73588c3853b4cb91e6c16393d245c4c5334f57a98d427dfccc2456.jpg)",
+      "C. ![](images/1f1ca32767d10230918b8b3e3622061ebce8d0ba962f1288499aced2e270a950.jpg)"
+    ],
+    "answer": "B",
+    "solution": "【分析】小丽在玩具的后面，看到的是背面，看不到脸，据此解答.\n【详解】A。是正面看到的，不符合;B。是后面看到的，符合;C。是侧面看到的，不符合。故答案为:B",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "23-24 二年级上·湖南长沙·期末"
+  },
+  {
+    "id": "7",
+    "unit": "第五单元 观察物体",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "○ 是小明看到的立体图形的一面。这个立体图形可能是( )。",
+    "options": [
+      "A. 圆柱",
+      "B. 长方体",
+      "C. 正方体"
+    ],
+    "answer": "A",
+    "solution": "【分析】长方体，正方体的面都不是圆;圆柱的上下面是圆.\n【详解】A。圆柱上下面是圆，有可能;B。长方体各个面中都没有圆，不可能;C。正方体各个面中都没有圆，不可能。这个立体图形可能是圆柱。故答案为:A",
+    "knowledge_points": [
+      "从不同位置观察单个物体",
+      "立体图形的认识及分类"
+    ],
+    "source": "24-25 二年级上·湖北黄冈·期末"
+  },
+  {
+    "id": "8",
+    "unit": "第五单元 观察物体",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "扎马尾的女孩看到的图是( ).\n\n![](images/a18961106b3d659d1af4bfddd96bd45287225693e1cf4f6b93350481df2ccdd3.jpg)",
+    "options": [
+      "A. ![](images/cd9761ea85593abac72874141f56c64204e7ae29afdfc121b53d7ec9f3c6a0c7.jpg)",
+      "B. ![](images/441e9cf4341dcbf3dd84342c57ebe89028a06305f68eaa542c3fab49cde7e7ee.jpg)",
+      "C. ![](images/16d6e267f6954088673993845f5dd7951c8c5f6b90496cea66353c9e0ecec850.jpg)"
+    ],
+    "answer": "C",
+    "solution": "【分析】女孩看到熊猫的正面，右边男孩看到后面，中间男孩看到侧面，据此选出女孩看到的图.\n【详解】A。是中间男孩看到的;B。是右边男孩看到的;C。是女孩看到的。故答案为:C",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "24-25 二年级上·四川广元·期末"
+  },
+  {
+    "id": "9",
+    "unit": "第五单元 观察物体",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面第( )组，从上面看到的是 ○□。",
+    "options": [
+      "A. ![](images/2026-02-26%20004854.jpg)",
+      "B. ![](images/2026-02-26%20004906.jpg)",
+      "C. ![](images/2026-02-26%20004915.jpg)"
+    ],
+    "answer": "C",
+    "solution": "【分析】根据正方体，圆柱，球的特征，判断各组从上面看到的形状.\n【详解】A。从上面看到![](images/2026-02-26%20005317.jpg);B。从上面看到![](images/2026-02-26%20005340.jpg);C。从上面看到 ○□。故答案为:C",
+    "knowledge_points": [
+      "立体图形的认识及分类"
+    ],
+    "source": "24-25 二年级上·湖北黄石·期末"
+  },
+  {
+    "id": "10",
+    "unit": "第五单元 观察物体",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面哪幅图是小方看到的( ).\n\n![](images/249ed370c7120947cd924692e00556508897c0ac04e5f1fe2e55bea6f6dd646c.jpg)",
+    "options": [
+      "A. ![](images/df5c3d1887da6cafe404c3dbe8d806db16605b41b848c4d64d6c3976e5a86270.jpg)",
+      "B. ![](images/53460c2fb5bc5d7a1577837c683af1677202736e1dfd1728286a439090786718.jpg)",
+      "C. ![](images/945de998dcdf225313b03e67b241a065f91dd41bc60342f6cc20e5c27ddea9df.jpg)"
+    ],
+    "answer": "B",
+    "solution": "【分析】小林看到壶嘴朝右，小方看到壶嘴朝左，小民看到手柄，据此判断.\n【详解】据分析可知：小方看到的是B。故答案为:B",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "24-25 二年级上·贵州铜仁·期末"
+  },
+  {
+    "id": "11",
+    "unit": "第五单元 观察物体",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "从正面看一个立体图形，看到的面是一个长方形，这个立体图形是( )。",
+    "options": [
+      "A. 长方体",
+      "B. 圆柱",
+      "C. 长方体或圆柱"
+    ],
+    "answer": "C",
+    "solution": "【分析】长方体和圆柱从正面看都是长方形;正方体正面是正方形;球正面是圆.\n【详解】长方体从正面看是一个长方形;圆柱从正面看是一个长方形;因此可能是长方体或圆柱。故答案为:C",
+    "knowledge_points": [
+      "从不同位置观察单个物体",
+      "立体图形的认识及分类"
+    ],
+    "source": "24-25 二年级上·贵州铜仁·期末"
+  },
+  {
+    "id": "12",
+    "unit": "第五单元 观察物体",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下图中，小丽看到的动车模型是( ).\n\n![](images/2026-02-26%20005820.jpg)",
+    "options": [
+      "A. ①",
+      "B. ②",
+      "C. ③",
+      "D. ④"
+    ],
+    "answer": "C",
+    "solution": "【分析】小丽站在动车模型的正前面，只能看到车头，看不到侧面车窗.\n【详解】③是正前面看到的，只能看到车头。故答案为:C",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "24-25 二年级上·福建龙岩·期末"
+  },
+  {
+    "id": "13",
+    "unit": "第五单元 观察物体",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "从下面第( )个图形上看不到圆。",
+    "options": [
+      "A. ![](images/a41993c98617417c5013cbdbea54770513e9697713ca6167cda2c9fc35516508.jpg)",
+      "B. ![](images/0397ff20ae6832e76600658e200ec5211ef611a5858a19c56a3fb11978e3440b.jpg)",
+      "C. ![](images/33ee742071173b70154e7eb16b80599b3892e05e1f60350831f7a26a9d5f7004.jpg)"
+    ],
+    "answer": "C",
+    "solution": "【分析】圆柱从上面能看到圆;球从各方向都看到圆;长方体各面都不是圆.\n【详解】长方体不论从哪个方向都不会看到圆形。故答案为:C",
+    "knowledge_points": [
+      "从不同位置观察单个物体",
+      "立体图形的认识及分类"
+    ],
+    "source": "24-25 二年级上·四川乐山·期末"
+  },
+  {
+    "id": "14",
+    "unit": "第五单元 观察物体",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "小红看到的形状是( ).\n\n![](images/2026-02-26%20010118.jpg)",
+    "options": [
+      "A. ![](images/02f52c6c6eea69c45fbe5f5e1f421bb46d08642257bd27e082df2be57f80cfc5.jpg)",
+      "B. ![](images/bc17ed2da6d2e5a14699ed49ba5a70ed679f5c86a7eabda3b4032a7ce1a6571b.jpg)",
+      "C. ![](images/82dc40fcc1f7f0ee2544b73a695a80bf82840f6acd78ebb2ba2107b84c6f959d.jpg)"
+    ],
+    "answer": "B",
+    "solution": "【分析】一个物体从不同方向看，看到的形状可能会不同，判断各选项对应的观察方向.\n【详解】A。从正面看到;B。从侧面看到(小红看到的);C。从上面看到。故答案为:B",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "24-25 二年级上·湖南长沙·期末"
+  },
+  {
+    "id": "15",
+    "unit": "第五单元 观察物体",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "小明从某个方向看立体图形，看到的是圆形，它不可能是( )。",
+    "options": [
+      "A. ![](images/3af3535167c97921e6201a999fccde6cc9c0b4a1a9c9014cf284f033a9d3a74f.jpg)",
+      "B. ![](images/474a0c15c06235da658178b6394e026ef6cf6fa55409ff4bfae1438933c68fc0.jpg)",
+      "C. ![](images/6ef6b0e8b4976b286aa56003df310d7715b61f6ce1970020ec27d012d24fa136.jpg)"
+    ],
+    "answer": "B",
+    "solution": "【分析】圆柱从上面可能看到圆;球从各方向都是圆;长方体各面都不是圆.\n【详解】长方体不论从哪个方向都不会看到圆形，所以不可能是长方体。故答案为:B",
+    "knowledge_points": [
+      "从不同位置观察单个物体",
+      "立体图形的认识及分类"
+    ],
+    "source": "24-25 二年级上·湖南湘西·期末"
+  },
+  {
+    "id": "16",
+    "unit": "第五单元 观察物体",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "从正面观察下面的立体图形，看到![](images/2026-02-26%20120353.jpg)的是( )。",
+    "options": [
+      "A. ![](images/9e953a10477b585a7dc4d08ae657b04bd726f8ea6a8e56eaa1edc899c4ba633b.jpg)",
+      "B. ![](images/a1869f1b7e9cc3f3e63a729da695d32ba2a66936877e4357b3c7bdc1565f3dc6.jpg)",
+      "C. ![](images/93aef85ea6bc144846906d77ded7da60a3e2dd7929dfdddfc18d86e9b2f66502.jpg)"
+    ],
+    "answer": "B",
+    "solution": "【分析】正面是正对图形进行观察，逐项分析各图从正面看到的图形.\n【详解】A。从正面看到的是![](images/2026-02-26%20120510.jpg),不符;B。从正面看到的是![](images/2026-02-26%20120524.jpg),符合;C。从正面看到的是![](images/2026-02-26%20120624.jpg),不符。故答案为:B",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "24-25 二年级上·河南郑州·期末"
+  },
+  {
+    "id": "17",
+    "unit": "第五单元 观察物体",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "刺猬看到的是( ).\n\n![](images/2026-02-26%20121043.jpg)",
+    "options": [
+      "A. ![](images/81b93b8b2eef79b76f1d28211687f6ac356bc525123d0dd3420c4f77c1a606ba.jpg)",
+      "B. ![](images/257908165146921b8d0fdeede3f6568691ab370abce14df4a6fe9b745bcb1c6f.jpg)",
+      "C. ![](images/c02f43756604ff788cb97b776748f150edb0dd7e26196c032fdad087301ca2e4.jpg)"
+    ],
+    "answer": "C",
+    "solution": "【分析】结合长方体，正方体，圆柱的特点，判断刺猬观察到的平面图.\n【详解】A。是从正面看到的;B。是从左面看到的;C。是刺猬看到的。故答案为:C",
+    "knowledge_points": [
+      "从不同位置观察两个物体的相互关系"
+    ],
+    "source": "24-25 二年级上·浙江杭州·期末"
+  },
+  {
+    "id": "18",
+    "unit": "第五单元 观察物体",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "如图所示，小明观察到的图形是( ).\n\n![](images/96d00c3816384b65143b913e813c3f496c956adead829d3fbfd89447209fd658.jpg)",
+    "options": [
+      "A. ![](images/02595126deb4743d3bb9dd102063b719bf8190415bbc8f70b9973ed14aecc525.jpg)",
+      "B. ![](images/3d151f18757e30f3b0dd0cf736d1996f3308cfa55de7b010232f884f5a835636.jpg)",
+      "C. ![](images/03fb067e9a2e387f1d62400116a4b22ce1c7774d5f4916c02b59ea22ad865863.jpg)"
+    ],
+    "answer": "A",
+    "solution": "【分析】小明看到的是飞机的机头;小刚看到机尾;侧面机头朝左/朝右分别对应不同观察者.\n【详解】A 对应小明观察到的图形。故答案为:A",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "24-25 二年级上·河南郑州·期末"
+  },
+  {
+    "id": "19",
+    "unit": "第五单元 观察物体",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "从下面( )图形上看不到长方形。",
+    "options": [
+      "A. ![](images/ea39df96d25d93f382ac339ea1fa1b3b49d3948e7d3fcca86aa1833d24e10733.jpg)",
+      "B. ![](images/98f8bf08bd74ac8f2538cba15d661aa8bb63f63143a52e7418bc4e701db73dde.jpg)",
+      "C. ![](images/d2b169daa552e6c4432fa24eadec996abdaa0c4486c818f3972d14d56e25d38a.jpg)"
+    ],
+    "answer": "C",
+    "solution": "【分析】圆柱从前面或侧面看能看到长方形;长方体从前面或上面看能看到长方形;球从任何方向看都是圆形.\n【详解】球看不到长方形，所以选 C。故答案为:C",
+    "knowledge_points": [
+      "长方形，正方形，三角形和圆的初步认识",
+      "从不同位置观察单个物体",
+      "立体图形的认识及分类"
+    ],
+    "source": "24-25 二年级上·辽宁抚顺·期末"
+  },
+  {
+    "id": "20",
+    "unit": "第五单元 观察物体",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "小女孩看到的是( ).\n\n![](images/c0b6ef37f0e48a56776df0b52c2169bf013f2e28dd5db657e7f0d4d9bc0811e3.jpg)",
+    "options": [
+      "A. ![](images/6649b00c49112c90be4722637ff33876b9064b273c67fadae5f24e4b19c2a0e7.jpg)",
+      "B. ![](images/3caa46f8196e541e7c342af59db0f1d38bc65d145d7954ebec69b617e59aaabe.jpg)",
+      "C. ![](images/1021903ba2cbf0e413387f81f870c80b982c2a6558226baf9e103c89b5035b85.jpg)"
+    ],
+    "answer": "B",
+    "solution": "【分析】小女孩从右边看，白色面在下面且在她左边，白色面上方与右边都有黑色面.\n【详解】符合的是 B。故答案为:B",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "24-25 二年级上·浙江台州·期末"
+  },
+  {
+    "id": "21",
+    "unit": "第五单元 观察物体",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下列图形中，从上面看是正方形的是( )。",
+    "options": [
+      "A. ![](images/13584fa662c703c6b91259dda5695f94c31fef9b9be7442eb54f8a89c0e18bf2.jpg)",
+      "B. ![](images/7d58b1f2b63e164de655b85d0f421b627c6ad1ead3bf43fbfb0ee49b1ce3d134.jpg)",
+      "C. ![](images/601e4feffd6b050e7f602552236e0d5387e2315484ab55d769f7b75a968b6749.jpg)"
+    ],
+    "answer": "A",
+    "solution": "【分析】分别从上面观察三组小正方体的摆放，判断上视图.\n【详解】A 从上面看是一个正方形;B,C 不符合。故答案为:A",
+    "knowledge_points": [
+      "物体三视图的认识"
+    ],
+    "source": "24-25 二年级上·湖北黄冈·期末"
+  },
+  {
+    "id": "22",
+    "unit": "第五单元 观察物体",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "![](images/5ab0a9ee904d3613903dff0d3852183a50d82d1875e5992529f927dd32540f00.jpg)和![](images/2d02f62c1a3a74c7065dcc35501bef9fb1d0b437ed0b629e6d2331fd64e7fef6.jpg)从( )看，形状是完全相同的。",
+    "options": [
+      "A. 右面",
+      "B. 前面",
+      "C. 上面"
+    ],
+    "answer": "A",
+    "solution": "【分析】分别从右面，前面，上面观察两个图形，比较得到的形状是否相同.\n【详解】从右面看两个图形形状完全相同;从前面，上面看不相同。故答案为:A",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "24-25 二年级上·福建三明·期末"
+  },
+  {
+    "id": "23",
+    "unit": "第五单元 观察物体",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "小玲观察立体图形时看到一个正方形，这个立体图形不可能( )。",
+    "options": [
+      "A. 长方体",
+      "B. 圆柱体",
+      "C. 球"
+    ],
+    "answer": "C",
+    "solution": "【分析】长方体可能有正方形的面;圆柱从侧面看可能是正方形;球从任何方向看都是圆形.\n【详解】看到正方形不可能是球。故答案为:C",
+    "knowledge_points": [
+      "从不同位置观察单个物体",
+      "立体图形的认识及分类"
+    ],
+    "source": "24-25 二年级上·河南南阳·期末"
+  },
+  {
+    "id": "24",
+    "unit": "第五单元 观察物体",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "第( )幅图，从箭头的方向看都是 3 个小正方形。",
+    "options": [
+      "A. ![](images/2026-02-26%20122237.jpg)",
+      "B. ![](images/2026-02-26%20122254.jpg)",
+      "C. ![](images/dbe611d4dabdd3e6522389fff3bc4cb608d5249d274d96044a28481a7439fbe5.jpg)"
+    ],
+    "answer": "C",
+    "solution": "【分析】从箭头方向观察，判断看到的小正方形个数.\n【详解】只有 C 从上面和右面看都是 3 个小正方形。故答案为:C",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "23-24 二年级上·浙江·期末"
+  },
+  {
+    "id": "25",
+    "unit": "第五单元 观察物体",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "小鸭子看到的图形是( ).\n\n![](images/2026-02-26%20122652.jpg)",
+    "options": [
+      "A. ![](images/ecb7670349fd669e6bbcde8197ea15c5becd134fde9d3c23d0830f884fb6d886.jpg)",
+      "B. ![](images/1bb95ccf221b5e52fb7488b4d855f3a0ffedb471ba7efa9046a2c3190f7eac36.jpg)",
+      "C. ![](images/ef0c0c450bbe0f7dffc36d516168b16ae24bb22c75b3bed5c79f7690f685ec06.jpg)"
+    ],
+    "answer": "B",
+    "solution": "【分析】猴子看到壶嘴在左手柄在右;小鸭看到只能看到手柄和壶肚;蝴蝶看到圆形部分更多.\n【详解】对应小鸭看到的是 B。故答案为:B",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "24-25 二年级上·甘肃庆阳·期末"
+  },
+  {
+    "id": "26",
+    "unit": "第五单元 观察物体",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "![](images/2026-02-26%20122742.jpg)从上面看到的是( )。",
+    "options": [
+      "A. ![](images/0cbbd5414336c277bb8d01b28099a5548b70c2a612f19c98984d3950a3417e40.jpg)",
+      "B. ![](images/5dcc7bc5a6a0680db78f398bf6a53ab5dd501750093b581fede9667d50acb2d3.jpg)",
+      "C. ![](images/a58270a809830f50c2417bc223a9397c341d12c1957a2c8cdd237b3afc1bfa31.jpg)"
+    ],
+    "answer": "A",
+    "solution": "【分析】从上面看能看见一个长方形和一个正方形，长方形在左边.\n【详解】从上面看到的是 A。故答案为:A",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "24-25 二年级上·广东汕头·期末"
+  },
+  {
+    "id": "27",
+    "unit": "第五单元 观察物体",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "下图从后面观察这个物体，看到的是( ).\n\n![](images/4cadbd4f0da7c23ca6c34aab13cc8c78056d1160c9b82f885967bbba0184694f.jpg)",
+    "options": [
+      "A. ![](images/4a8ca9e0b10ddcee5f47c60dd05272f7efa216048e8834807dd6ea82e00a7244.jpg)",
+      "B. ![](images/f05a2eba40865cea5ab502eefb91a4cf417c13c76f03c6ec57a9653954629618.jpg)",
+      "C. ![](images/1d595231303af3f84d8de10d19489b28949f387342444b3cff8d7ea491d88c17.jpg)"
+    ],
+    "answer": "B",
+    "solution": "【分析】从后面看，上下两个正方体和右胳膊相对，一个正方体和左胳膊相对.\n【详解】从后面观察看到的是 B。故答案为:B",
+    "knowledge_points": [
+      "物体三视图的认识"
+    ],
+    "source": "24-25 二年级上·河南开封·期末"
+  },
+  {
+    "id": "28",
+    "unit": "第五单元 观察物体",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "![](images/2026-02-26%20123039.jpg)这张照片是( )号摄影师拍摄的.\n\n![](images/86a3ce5420d9de0beff83f91d6746595fbdb4a3757d97d3629bc48a193dc8924.jpg)",
+    "options": [
+      "A. ①",
+      "B. ②",
+      "C. ③"
+    ],
+    "answer": "A",
+    "solution": "【分析】①拍到猴子背面;②拍到侧面(猴子左手边);③拍到正面.\n【详解】这张照片是①号摄影师拍摄的。故答案为:A",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "24-25 二年级上·全国·期末"
+  },
+  {
+    "id": "29",
+    "unit": "第五单元 观察物体",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下列三种物体，从正面看是圆形的是( )。",
+    "options": [
+      "A. ![](images/946b95a5dfac582816b720b256ba51138b0c158e17bc8391425d2e08fc06b305.jpg)",
+      "B. ![](images/ff460fee48e45cc25be15556994c5eff28975ceabdcc4fde882b81b79e871971.jpg)",
+      "C. ![](images/28e0ef34452517cfb31beaf8953f6858a936c2bc4eaa783b4e80e65eb1c75656.jpg)"
+    ],
+    "answer": "B",
+    "solution": "【分析】逐项判断三种物体从正面看到的形状.\n【详解】A 从正面看是正方形;B 从正面看是圆形;C 从正面看是近似长方形。故答案为:B",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "24-25 二年级上·全国·期末"
+  },
+  {
+    "id": "30",
+    "unit": "第五单元 观察物体",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "小鸟看到的数字是( ).\n\n![](images/a74f4d3e3279d6cf8a7ae3d1150dd8022056c36956b64f2bde658efd8b2a0746.jpg)\n\n![](images/7f96d6d9ba4718ec0603c0ddfd6acd6b20f831af110087073ace50f20dda4dbf.jpg)",
+    "options": [
+      "A. 1",
+      "B. 2",
+      "C. 3"
+    ],
+    "answer": "B",
+    "solution": "【分析】从上面看到的是数字2，从前面看到的是数字1，从右面看到的是数字3.\n【详解】小鸟从上面看，看到的数字是 2。故答案为:B",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "24-25 二年级上·全国·期末"
+  },
+  {
+    "id": "31",
+    "unit": "第五单元 观察物体",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "![](images/c2ba28387dba58a703571606f877bb6171e6d882001042b9e6720e474d2395e6.jpg)观察左面的图形，从前面看到的是( )。",
+    "options": [
+      "A. ![](images/4ef2bd7c1234e99ce6570bce9d1ba2fbbed0f01a929a8e9661829036194858ee.jpg)",
+      "B. ![](images/d2c4d1cd7dfb03b40c75166c00f771db086ab11fe6081a2ec78b30fe5e6a30d7.jpg)",
+      "C. ![](images/284d5e40d81ab2aed06e967de68c7f46488e0849b62856112bf3741735c0449d.jpg)"
+    ],
+    "answer": "B",
+    "solution": "【分析】从前面看有两行：下层一行 2 个正方形，上层 1 个靠左.\n【详解】从前面看到的是 B。故答案为:B",
+    "knowledge_points": [
+      "物体三视图的认识"
+    ],
+    "source": "24-25 二年级上·吉林四平·期末"
+  },
+  {
+    "id": "32",
+    "unit": "第五单元 观察物体",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "如下图，小猫看到的是( ).\n\n![](images/aab2db9c0914bd80e2ee0165c463dca0c4789ca5295f08f777bbb2b0d7938c83.jpg)",
+    "options": [
+      "A. ![](images/781bc5a022ff2935892481b26bfbf302cf6d258e391ead23dacdb863eb7ba156.jpg)",
+      "B. ![](images/4a544c28f477595f3deabea445528b4968e8864566bddd3a2c9a798a9b5a57bc.jpg)",
+      "C. ![](images/38e53521b7e9e5bf8cea82242b87415d79a1b96dc78dad2cc423cbd6e4cec0bb.jpg)"
+    ],
+    "answer": "B",
+    "solution": "【分析】小猫看到的是烟囱在左，有长方形小窗户的一面.\n【详解】符合的是 B。故答案为:B",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "23-24 二年级上·河北保定·期末"
+  },
+  {
+    "id": "33",
+    "unit": "第五单元 观察物体",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "如图，小男孩看到的是( ).\n\n![](images/4ef691859eb58cf2e566d6e67b041ccdfa2ee9e33c9424a96c82c308bd111c7a.jpg)",
+    "options": [
+      "A. ![](images/6e9c73ebac8bc4bcbb1bbef55b3e0520365303e37d44fd0087f88e95b1817faa.jpg)",
+      "B. ![](images/01b328559ed6e614686a3e3f5897b7f3c02779ccaba0bc659f0c15b49cb09773.jpg)",
+      "C. ![](images/bb5205e2334b4f4b6ab9d004e78700b4c70b686b1f29481ef248f56caa7a92e8.jpg)"
+    ],
+    "answer": "A",
+    "solution": "【分析】小男孩站在房子的前面，看到的是房子的正面.\n【详解】房子正面能看见门和窗户，只有 A 符合。故答案为:A",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "23-24 二年级上·浙江绍兴·期末"
+  },
+  {
+    "id": "34",
+    "unit": "第五单元 观察物体",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "明明观察一个长方体，他看到的形状不可能是( )。",
+    "options": [
+      "A. 正方形",
+      "B. 长方形",
+      "C. 圆"
+    ],
+    "answer": "C",
+    "solution": "【分析】长方体有 6 个平平的面，看到的形状可能是长方形;特殊情况下也可能看到正方形，但不可能看到圆.\n【详解】A。特殊情况下能看到正方形;B。可能看到长方形;C。不可能看到圆。故答案为:C",
+    "knowledge_points": [
+      "从不同位置观察单个物体",
+      "立体图形的认识及分类"
+    ],
+    "source": "23-24 二年级上·河北石家庄·期末"
+  },
+  {
+    "id": "35",
+    "unit": "第五单元 观察物体",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面( )图是小欣看到的.\n\n![](images/b8e5cc1719607732a8a6e54ea61ffa1e280419b3059634e9042e420b9064cf33.jpg)",
+    "options": [
+      "A. ![](images/1b674bf2d1c1d2121073178a905ede20ce8d6a9386c031a4615dfd7e9d85af82.jpg)",
+      "B. ![](images/248f79e4d6a82b4f661d993b1a450785ba36a34f09cca3352a83ed7d13789c39.jpg)",
+      "C. ![](images/817c17939d7275038aa9a5e8a662f0b3ab5ce7398810fef19a999de2fcc1446d.jpg)"
+    ],
+    "answer": "A",
+    "solution": "【分析】小欣看到的是灭火器的管子在左边，罐子在右边.\n【详解】符合小欣看到的是 A。故答案为:A",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "23-24 二年级上·河南郑州·期末"
+  },
+  {
+    "id": "36",
+    "unit": "第五单元 观察物体",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "观察下面的物体，从上面看到的是( ).\n\n![](images/2026-02-26%20124624.jpg)",
+    "options": [
+      "A. ![](images/2026-02-26%20124637.jpg)",
+      "B. ![](images/2026-02-26%20124651.jpg)",
+      "C. ![](images/2026-02-26%20124724.jpg)"
+    ],
+    "answer": "A",
+    "solution": "【分析】圆柱的上面是圆，正方体的上面是正方形，圆柱在左边，正方体在右边，所以从上面看到左边圆形，右边正方形.\n【详解】从上面看到的是 A。故答案为:A",
+    "knowledge_points": [
+      "从不同位置观察两个物体的相互关系"
+    ],
+    "source": "23-24 二年级上·河南郑州·期末"
+  },
+  {
+    "id": "37",
+    "unit": "第五单元 观察物体",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "观察下面的立体图形,( )不能看到一个面是长方形。",
+    "options": [
+      "A. ![](images/04ea0f894bc0bfd2cdea255909b842d8d1eb5c2b4d910496541694450b527578.jpg)",
+      "B. ![](images/961078d0980a7f25864262d0955f04a0af21d0a982bb870c824d973324575687.jpg)",
+      "C. ![](images/8081795b8614eaa9023c8b53d15be08c5eb0adfc7b0b5b85ea095c4879e60c15.jpg)"
+    ],
+    "answer": "C",
+    "solution": "【分析】长方体，圆柱从某些方向能看到长方形;球从任何方向看到的都是圆.\n【详解】C 是球，看不到长方形面。故答案为:C",
+    "knowledge_points": [
+      "长方形，正方形，三角形和圆的初步认识",
+      "从不同位置观察单个物体",
+      "立体图形的认识及分类"
+    ],
+    "source": "23-24 二年级上·浙江台州·期末"
+  },
+  {
+    "id": "38",
+    "unit": "第五单元 观察物体",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "从②看到的图形是( ).\n\n![](images/4d053d477fcb673b838b68f06fbe6cccfe21cda2ad6da88cc1b18c520829c61f.jpg)",
+    "options": [
+      "A. ![](images/f07c1ae3010cb6984498a06e0c7d43bc297bcfbd94d90e57dbd54c62472d8323.jpg)",
+      "B. ![](images/0abb1008f0026182995f5b5148f34637b58ba9153a1a4f1e91ffcb378b35f232.jpg)",
+      "C. ![](images/974ec61364482ab5250ab4e89972f1d01a22b29ef00741b3f79fb991e932fc14.jpg)"
+    ],
+    "answer": "C",
+    "solution": "【分析】根据小女孩观察物体的位置(②),判断看到的形状.\n【详解】从②看到的是 C。故答案为:C",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "23-24 二年级上·江西抚州·期末"
+  },
+  {
+    "id": "39",
+    "unit": "第五单元 观察物体",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "从上面看是( ).\n\n![](images/5cce76f2aca9cec77fa661e615174f4bb7c5bb2e7bc81c791ee0dda114b7a1af.jpg)",
+    "options": [
+      "A. ![](images/828cb23d9fc343b97ed15ce4b191046876c3adc34f37efade89b6581d1e5238b.jpg)",
+      "B. ![](images/1faba5429a54632687471238f68566e362862f7f880283a93c93fa0d5a54ff1c.jpg)",
+      "C. ![](images/1446690f3ca66d9318f5022d5bdf0b01f6e12400e603a024e527f8ebac8c498e.jpg)"
+    ],
+    "answer": "C",
+    "solution": "【分析】一个物体从不同方向看，看到的形状可能会不同，判断哪个是从上面看到的.\n【详解】从上面看到的是 C。故答案为:C",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "23-24 二年级上·四川德阳·期末"
+  },
+  {
+    "id": "40",
+    "unit": "第五单元 观察物体",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "图中的小强看到的是图( ).\n\n![](images/07c1b0cf032c4f62f99dd402eedce047384d9b9d1e6653d744941cecd703e9f6.jpg)",
+    "options": [
+      "A. ![](images/a8fcb2536dcd107cd45412862866f908e934481b032bff484ef5b0cd283bfb67.jpg)",
+      "B. ![](images/504475441f7398d76a4671ddbd265ad225f05f452248acf8271325deff1e63a0.jpg)",
+      "C. ![](images/cfdd7b360bdef9470b5ec64b7c80b5735fe7d5b4f20d289ea7b31ca38389990b.jpg)"
+    ],
+    "answer": "C",
+    "solution": "【分析】小强在布偶的正面，所以他看到的是布偶的正面.\n【详解】对应的是 C。故答案为:C",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "24-25 三年级上·北京海淀·期中"
+  },
+  {
+    "id": "41",
+    "unit": "第五单元 观察物体",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "机灵狗站在 4 个不同的位置观察图一的两个物体，它站在( )位置看到的是图二.\n\n![](images/132e31b432f199f2f8268920440c7e9e3b1dc5e1cf6901bb94ee89c659644d77.jpg)\n图一\n\n![](images/3807753a27475103a3e77e6cf1a6485de570287cb3c67e35cb008265d41b4feb.jpg)\n图二",
+    "options": [
+      "A. ①",
+      "B. ②",
+      "C. ③",
+      "D. ④"
+    ],
+    "answer": "A",
+    "solution": "【分析】①看到右边是长方体，左边是圆柱;②长方体在前遮挡圆柱;③左边是长方体右边圆柱;④圆柱在前遮挡长方体.\n【详解】图二对应①位置。故答案为:A",
+    "knowledge_points": [
+      "从不同位置观察两个物体的相互关系"
+    ],
+    "source": "23-24 三年级上·北京西城·期末"
+  },
+  {
+    "id": "42",
+    "unit": "第五单元 观察物体",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "笑笑从窗外看到的情景会是下面哪幅图。( )\n\n![](images/a87563c6d425d01d23b1438e1cef7673ead23e4f39fbe1844da804595de1768d.jpg)",
+    "options": [
+      "A. ![](images/53569a46385c85b76af17c7acd52d823eccde88ac2d5e13853a08d0ecdc84d2f.jpg)",
+      "B. ![](images/65c302dc26467da75ed8820d4e1012e554fe564205ea1285975ba9d181907d00.jpg)",
+      "C. ![](images/042162a7d0a3e1210b4a9a290e9c4e26e8b30192b628a9a7d561881b3e152d28.jpg)"
+    ],
+    "answer": "A",
+    "solution": "【分析】笑笑与我们方向相反：我们看到小熊正面且在桌左边;笑笑看到小熊背面且在桌右边.\n【详解】符合的是 A。故答案为:A",
+    "knowledge_points": [
+      "从不同位置观察两个物体的相互关系"
+    ],
+    "source": "23-24 三年级上·吉林四平·期末"
+  },
+  {
+    "id": "43",
+    "unit": "第五单元 观察物体",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "大庆看到的是( ).\n\n![](images/e61f33926e38fff449a8c382ec515488418b8417e8ff06719cc1788a32974161.jpg)",
+    "options": [
+      "A. 左边是盒子，右边是西瓜",
+      "B. ![](images/b4d090479fd6971b0c94b1e89227443cde345f528da36a9cf5ed6205d10a1b92.jpg)",
+      "C. 左边是西瓜，右边是盒子"
+    ],
+    "answer": "A",
+    "solution": "【分析】大庆看到的是左边是盒子，右边是西瓜.\n【详解】与此对应的是 A。故答案为:A",
+    "knowledge_points": [
+      "从不同位置观察两个物体的相互关系"
+    ],
+    "source": "23-24 三年级上·吉林四平·期末"
+  },
+  {
+    "id": "44",
+    "unit": "第五单元 观察物体",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "从下面( )图形上看不到正方形。",
+    "options": [
+      "A. ![](images/84f2751f2b22ac314343e45bc087b1761875654437cb18fcf01427fad5d7df8f.jpg)",
+      "B. ![](images/f8933f5ba904e1d6b57149c7ca70e70759b922aa348d6ec8dd493041d6ccb3e8.jpg)",
+      "C. ![](images/ceef99dc76620981f87020871da2787a811439f30a8c31fcb5e29f8cdf6b00bd.jpg)",
+      "D. ![](images/b50ea4ab04c56af4308ff9db4b58393c3fc47eb969c151b2959ba5c8ace29c62.jpg)"
+    ],
+    "answer": "D",
+    "solution": "【分析】逐项判断各物体从不同方向能看到哪些平面图形.\n【详解】A 能看到长方形和正方形;B 能看到正方形;C 能看到圆和正方形;D 只能看到圆，看不到正方形。故答案为:D",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "23-24 二年级上·浙江绍兴·期末"
+  },
+  {
+    "id": "45",
+    "unit": "第五单元 观察物体",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "![](images/2eba480de9ad413e8e5fc15a0dcf759637806cf1557838e0041bee6565e37c00.jpg)左图从上面看到的图形是( )。",
+    "options": [
+      "A. ![](images/efd541c7e72bdb74167d36b9a9f9f191ba95da2f001371d2492f41353f006d08.jpg)",
+      "B. ![](images/8bbbc7191a37201617492c22684af44761040d0aeed94e8e0feafa5070006a38.jpg)",
+      "C. ![](images/3dee8ce76e2f9ed57255178885d3c82d997294449cd2c85ac190bf6628051f91.jpg)"
+    ],
+    "answer": "C",
+    "solution": "【分析】从上面看中间是一个正方形，正方形两边各一个长方形.\n【详解】对应的是 C。故答案为:C",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "23-24 二年级上·浙江杭州·期末"
+  },
+  {
+    "id": "46",
+    "unit": "第五单元 观察物体",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "女孩看到的是( )。",
+    "options": [
+      "A. ![](images/7c0618a4151a758ec23b62060429ae56ddb9dcdaa046f502fa3e202e7026fb71.jpg)",
+      "B. ![](images/2c5c2f74cd4f8f3764ae202d6c420e48634f48fbd6124e626d1c42356426adcf.jpg)",
+      "C. ![](images/17bf4b2cc275e2df58dfd397f3cbf94d770d1141d4c5b202e768fec647c69bb8.jpg)"
+    ],
+    "answer": "A",
+    "solution": "【分析】小女孩站在左侧，是从左面看的;从左面看前边是大长方形，后边两侧是两个小长方形.\n【详解】A 是从左面看到的。故答案为:A",
+    "knowledge_points": [
+      "从不同位置观察两个物体的相互关系"
+    ],
+    "source": "23-24 二年级上·福建三明·期末"
+  },
+  {
+    "id": "47",
+    "unit": "第五单元 观察物体",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "玲玲看到的立体图形的一个面是圆，这个立体图形是( )。",
+    "options": [
+      "A. 长方体",
+      "B. 正方体",
+      "C. 圆柱，也可能是球"
+    ],
+    "answer": "C",
+    "solution": "【分析】长方体，正方体没有圆形的面;圆柱上下是圆;球从任何方向看都是圆.\n【详解】可能是圆柱，也可能是球。故答案为:C",
+    "knowledge_points": [
+      "从不同位置观察单个物体",
+      "立体图形的认识及分类"
+    ],
+    "source": "23-24 二年级上·河南安阳·期末"
+  },
+  {
+    "id": "48",
+    "unit": "第五单元 观察物体",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "下面( )图是小红看到的.\n\n![](images/75fc77007d0ad09efeefc6248268c1a0ce936bcb0852fae9a6bfc8ef41008516.jpg)",
+    "options": [
+      "A. ![](images/f046cd79a4a8b813338b5a63e81da1ec78268ff75c9d64e230c8796d160bfde3.jpg)",
+      "B. ![](images/bbeb520bd6c9e83e468a82525713f3a139d7bed7309b873dd68e91b597fbb337.jpg)",
+      "C. ![](images/f237029d965d05805ea84e46070113cd78e499cbc097155b3000a0329aec1d79.jpg)"
+    ],
+    "answer": "A",
+    "solution": "【分析】小红看到的是车头的一面.\n【详解】对应的是 A。故答案为:A",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "23-24 二年级上·重庆永川·期末"
+  },
+  {
+    "id": "49",
+    "unit": "第五单元 观察物体",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "如图，乐乐看到的是( ),小明看到的是( ).\n\n![](images/77fb2f73d27b60171a2e58f91cc4e237d5151f65d765c747173a874b591f8f12.jpg)",
+    "options": [
+      "A. ①②",
+      "B. ②①",
+      "C. ①③"
+    ],
+    "answer": "B",
+    "solution": "【分析】乐乐看到的是球在圆柱体前;小明看到的是球在右边，圆柱体在左边.\n【详解】乐乐看到②,小明看到①,因此选\"②①\"。故答案为:B",
+    "knowledge_points": [
+      "从不同位置观察两个物体的相互关系"
+    ],
+    "source": "24-25 三年级上·河南商丘·期中"
+  },
+  {
+    "id": "50",
+    "unit": "第五单元 观察物体",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "看到立体图形的一个面是正方形，那么这个立体图形不可能是( )。",
+    "options": [
+      "A. 圆柱",
+      "B. 长方体",
+      "C. 球"
+    ],
+    "answer": "C",
+    "solution": "【分析】圆柱从侧面看可能是正方形;长方体可能有正方形的面;球从任何方向看都是圆形.\n【详解】不可能是球。故答案为:C",
+    "knowledge_points": [
+      "从不同位置观察单个物体",
+      "立体图形的认识及分类"
+    ],
+    "source": "23-24 二年级上·浙江温州·期末"
+  },
+  {
+    "id": "51",
+    "unit": "第五单元 观察物体",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "如图，鸭子看见的是( ).\n\n![](images/039965435a21368d4433b8dff9c21465dd1d76a2e7214d538006cb9eae15d316.jpg)",
+    "options": [
+      "A. ![](images/8102cce803e62c886d07e5a67653e9578c5b9b5b298ab4998e56919bb9b8abbe.jpg)",
+      "B. ![](images/d5a8a68b8f1f4b365b878972a9dc4d886b9c293e4de0b72e66032e1b79178572.jpg)",
+      "C. ![](images/13c3164b2667a97ebcf9851d4546b8fb3daae6ffb3b5dbfa34adecb0fe893f02.jpg)"
+    ],
+    "answer": "B",
+    "solution": "【分析】鸭子面向杯柄，看到的是杯柄的一面.\n【详解】对应的是 B。故答案为:B",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "23-24 二年级上·重庆璧山·期末"
+  },
+  {
+    "id": "52",
+    "unit": "第五单元 观察物体",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下图中，小女孩看到的是( )。",
+    "options": [
+      "A. ![](images/629379115a843f0f2325bc6b8ad55cc965fd5da5b4b530ed553e753fc9f1eced.jpg)",
+      "B. ![](images/6ddbd162478c4e931222f92f77504acd88c95040e34077ea23bbdc66eaab11fd.jpg)",
+      "C. ![](images/5ab2d6cc287790f4199c333b0264747294e661e137b04057a2eec83e23111ccb.jpg)"
+    ],
+    "answer": "B",
+    "solution": "【分析】站在观察者角度，从不同方向观察小汽车，将看到的形状与选项比较.\n【详解】小女孩站在小汽车后面，看到车尾，对应 B。故答案为:B",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "24-25 二年级上·河北廊坊·期中"
+  },
+  {
+    "id": "53",
+    "unit": "第五单元 观察物体",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "如图中，小兔子看到的是( ).\n\n![](images/4dd6919cd62e9702631a4567f547063b231367c18eaa04a47ac21ad93952fe84.jpg)",
+    "options": [
+      "A. ![](images/8c65686b4e8cceb1c3e15b21d3dd45c64a530aa83019ac8fc93ee6fb0b6e0f1e.jpg)",
+      "B. ![](images/296601d82a9330f04fd89157e44899bad0460f754c84c42ba53d1f8a9a940f95.jpg)",
+      "C. ![](images/3ae4715ae6d05017eb9b87f330d49874a7e95193a178e804e28cce1f02f695b7.jpg)"
+    ],
+    "answer": "C",
+    "solution": "【分析】兔子在猴子的后面，看到的是猴子的后背.\n【详解】A 是前面;B 是侧面;C 是后背。故答案为:C",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "23-24 二年级上·河北邢台·期中"
+  },
+  {
+    "id": "54",
+    "unit": "第五单元 观察物体",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "下边图片是( )看到的.\n\n![](images/f4eec7aa6ba13fb96f2cb501e080cf290c68b137770d56a2bbadd6f62f7fe07d.jpg)\n\n![](images/dfd9c844391dcff1a48751e4d1ad2491bea6f330894b977bb7191d21739a440c.jpg)",
+    "options": [
+      "A. 小刺猬",
+      "B. 小鸭",
+      "C. 长颈鹿"
+    ],
+    "answer": "C",
+    "solution": "【分析】小刺猬看到椅子背面;小鸭看到侧面;长颈鹿看到正面.\n【详解】图片为椅子的正面，是长颈鹿看到的。故答案为:C",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "22-23 二年级上·福建莆田·期末"
+  },
+  {
+    "id": "55",
+    "unit": "第五单元 观察物体",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "长方体从前面和后面看到的图形( )。",
+    "options": [
+      "A. 一定相同",
+      "B. 可能相同",
+      "C. 一定不同"
+    ],
+    "answer": "A",
+    "solution": "【分析】长方体相对的面完全一样，前面和后面是相对的面，所以看到的图形相同.\n【详解】长方体从前面和后面看到的图形一定相同。故答案为:A",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "23-24 二年级上·全国·单元测试"
+  },
+  {
+    "id": "56",
+    "unit": "第五单元 观察物体",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "拿走了( )个小方块.\n\n![](images/16c2194a9f3acb8174c8548e72d7552a6c5d4dad6ad575ea1a66cc5199df4a21.jpg)",
+    "options": [
+      "A. 5",
+      "B. 6",
+      "C. 7"
+    ],
+    "answer": "C",
+    "solution": "【分析】数一数可知，上面一层原来有 9 个，现在还剩 2 个，拿走了 9 - 2 = 7 个.\n【详解】9 - 2 = 7(个),故答案为:C",
+    "knowledge_points": [
+      "立体图形的认识",
+      "数一数"
+    ],
+    "source": "22-23 三年级下·湖北武汉·期末"
+  },
+  {
+    "id": "57",
+    "unit": "第五单元 观察物体",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面( )号图片是小东看到的.\n\n![](images/c3b8feef732827d3e5fb9cfa091f0d67d9a964438ec55542e85779d0cb050905.jpg)",
+    "options": [
+      "A. ![](images/b145a0128d63518e0e8a4bdcd738bac19517ccc482d93b84edcc9e874b733a8b.jpg)",
+      "B. ![](images/a752729b79af6c996784fb727956801d42bef8b6aab696fe10ff9e1c06683c26.jpg)",
+      "C. ![](images/7e733f3f106346cdb6e1ca753aeb68a3876b958fd6e372bdacdfbc65c9cdcec0.jpg)"
+    ],
+    "answer": "C",
+    "solution": "【分析】小东看到的是有门和窗户的一面.\n【详解】对应的是 C。故答案为:C",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "23-24 一年级下·天津河西·期末"
+  },
+  {
+    "id": "58",
+    "unit": "第五单元 观察物体",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "在括号里填上合适的序号。喜羊羊和美羊羊观察同一个立体图形。喜羊羊说：\"我看到的是长方形.\"美羊羊说：\"我看到的正方形.\"根据上面的对话可以猜出，它们观察的是( ).\n\n![](images/728d483f3aa66e44d2f23158cef74ea190f0b52af3138fa9a8fbe2c8c1d7f2be.jpg)\n\n![](images/647ca9367dda3aeaa75e3b917befe76b197aa0d55424aa2df294dfa7ebca53df.jpg)\n\n![](images/11b7c936d1d46b2b8956767d8a957dab1af9540f9f738e01f887a4499ecb7f42.jpg)",
+    "options": [],
+    "answer": "②",
+    "solution": "【分析】①每个面都是正方形;②有的面是正方形，有的面是长方形;③上面看是圆形，正面或侧面看是长方形.\n【详解】①不符合喜羊羊;②符合两人观察;③不符合美羊羊。故选②。",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "25-26 三年级上·广东汕头·阶段练习"
+  },
+  {
+    "id": "59",
+    "unit": "第五单元 观察物体",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "观察圆柱![](images/177398587e75ff5188028b6d7f52e3c829dd86ea95d7264bfc467559368cce36.jpg)时，从左面看到的是( )形，从正面看到是( )形，从上面看到的是( )形。",
+    "options": [],
+    "answer": "长方;长方;圆",
+    "solution": "【分析】圆柱从正面或侧面看是长方形，从上面看是圆形.\n【详解】从左面看是长方形;从正面看是长方形;从上面看是圆形。",
+    "knowledge_points": [
+      "物体三视图的认识"
+    ],
+    "source": "25-26 三年级上·广东汕头·阶段练习"
+  },
+  {
+    "id": "60",
+    "unit": "第五单元 观察物体",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "小光看到了( )个点子.\n\n![](images/16e12f2ecaa5e91ab9ca514132bdd57fd9e49f100e37a4493eab16ee797da386.jpg)\n![](images/423fd67f1724170f2ce90bcb4f9d7c42ba44047621ab7fa8a75c62f5ec1a1e3e.jpg)",
+    "options": [],
+    "answer": "5",
+    "solution": "【分析】小光站在正方体的右侧，看到的这一面有 5 个点.\n【详解】小光看到了 5 个点子。",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "24-25 一年级下·广东揭阳·期中"
+  },
+  {
+    "id": "61",
+    "unit": "第五单元 观察物体",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "右图是从( )面看到圆柱的形状.\n\n![](images/744d81c7f39e37e413c682a377b42f5f4b5068aa650e474a4aa884951cd139fb.jpg)\n\n![](images/65e65262781eb958df1b7d1ab8e8bc0481d5d568cf73fedf727756fb1e70ea5d.jpg)",
+    "options": [],
+    "answer": "正面或侧",
+    "solution": "【分析】圆柱从正面或侧面看是长方形，从上面或下面看是圆形.\n【详解】题图所示形状为长方形，所以是从正面或侧面看到的。",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "24-25 五年级下·湖南岳阳·期中"
+  },
+  {
+    "id": "62",
+    "unit": "第五单元 观察物体",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "看到我们学过的立体图形的一个面是圆，它可能是( )或( )。",
+    "options": [],
+    "answer": "球;圆柱",
+    "solution": "【分析】学过的立体图形中，圆柱的上下两个面是圆形，球从任何方向看都是圆形.\n【详解】它可能是球或圆柱。",
+    "knowledge_points": [
+      "从不同位置观察单个物体",
+      "立体图形的认识及分类"
+    ],
+    "source": "23-24 二年级上·湖南长沙·期末"
+  },
+  {
+    "id": "63",
+    "unit": "第五单元 观察物体",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "小蚂蚁看到的是图( ),小羊看到的是图( )。",
+    "options": [],
+    "answer": "③;①",
+    "solution": "【分析】小羊看到有门，说明在房屋前面;小蚂蚁看到中间有窗户，对应图③.\n【详解】小蚂蚁看到③,小羊看到①。",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "24-25 二年级上·河南周口·期末"
+  },
+  {
+    "id": "64",
+    "unit": "第五单元 观察物体",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "看一看下面的照片，从前面拍到的填\"前面\"，从后面拍到的填\"后面\"，从侧面拍到的填\"侧面\".\n\n![](images/a0962e41c947c49294d4116879e0899aba4e69443d94089526cba087a739dd24.jpg)\n\n![](images/151aa30fcf6c52e83a52fe092cda3627bc3f6afec1ae561ecabf7290d9582b75.jpg)\n\n![](images/57d9f61f9c70f2036dddf91862d1e4b958b4cb844b50aa30f88766012dd350ec.jpg)\n\n![](images/42523106e3c2cb490be91a9e028b38aee081cebd5e8a680b7560fc5185fba310.jpg)\n\n( )面;( )面;( )面;( )面",
+    "options": [],
+    "answer": "前;侧;侧;后",
+    "solution": "【分析】从前面拍到能看到头部;从后面拍到能看到尾部;从侧面拍到能看到身体侧面.\n【详解】依次为：前面;侧面;侧面;后面。",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "24-25 二年级上·河南周口·期末"
+  },
+  {
+    "id": "65",
+    "unit": "第五单元 观察物体",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "仔细观察，按要求填空.\n\n(1)从正面看是(图形)的有( ).\n(2)从侧面看是(图形)的有( ).\n(3)从上面看是(图形)的有( )。",
+    "options": [],
+    "answer": "④⑤;③④;②⑤",
+    "solution": "【分析】从不同方向观察同一个物体，看到的形状可能不同，逐个判断即可.\n【详解】(1)④⑤;(2)③④;(3)②⑤。",
+    "knowledge_points": [
+      "从不同位置观察单个物体",
+      "物体三视图的认识"
+    ],
+    "source": "23-24 二年级上·浙江宁波·期末"
+  },
+  {
+    "id": "66",
+    "unit": "第五单元 观察物体",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "在下图中,( )看到的是(图1),( )看到的是(图2),( )看到的是(图3).\n\n![](images/c28e391f4fca32f6714fe191ea7fac65c075dcee97b2d2e4e745cb2e44f0d62d.jpg)",
+    "options": [],
+    "answer": "豆豆;芳芳;小鸟",
+    "solution": "【分析】豆豆看到的是上边 1 个正方形，下边 2 个正方形且左下分成 4 个小正方形;芳芳看到上边 1 个，下边 1 个且上边有斜线;小鸟看到横向排列的 2 个正方形.\n【详解】豆豆;芳芳;小鸟。",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "23-24 二年级上·河北保定·期末"
+  },
+  {
+    "id": "67",
+    "unit": "第五单元 观察物体",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "如图中，笑笑看到的是图( ),淘气看到的是图( ).\n\n![](images/45ca10a5cf733ed151aeaeb600e9873c9610255c9d7a111da352cd3bab00a369.jpg)\n\n![](images/ad55a96cc4009e052fe593af439a6ca6fee9c3f4eddaf962a9c3790f64ad30b5.jpg)\n①\n\n![](images/677af13333f08d73a819c2d70e47fb71ff2e7d18a71019870b060887459cb5dc.jpg)\n②\n\n![](images/41f13483c8f168423a709abd99e35b9651daaed8f3551e025a63e324c520e2a4.jpg)\n③",
+    "options": [],
+    "answer": "①;③",
+    "solution": "【分析】笑笑看到上面有 3 个圆;淘气看到底面有 2 个圆.\n【详解】笑笑看到①;淘气看到③。",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "24-25 三年级上·河南商丘·期中"
+  },
+  {
+    "id": "68",
+    "unit": "第五单元 观察物体",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "把长方体放在桌面上，站在不同的位置上观察，每次最多可以看到( )个面。",
+    "options": [],
+    "answer": "3",
+    "solution": "【分析】从长方体的顶点处观察，最多能同时看到相邻的 3 个面.\n【详解】每次最多可以看到 3 个面。",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "23-24 三年级上·北京西城·期末"
+  },
+  {
+    "id": "69",
+    "unit": "第五单元 观察物体",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "他们观察的是什么立体图形。在正确答案下面的括号里画\"√\".\n\n![](images/c85b483e1c380decbe259bba7a30ff4d8a74cc4d1714101be1443e6b2d73293e.jpg)",
+    "options": [],
+    "answer": "圆柱",
+    "solution": "【分析】从侧面看是长方形，从上面看是长方形，从前后面看是圆，所以是圆柱.\n【详解】应选圆柱。",
+    "knowledge_points": [
+      "从不同位置观察单个物体",
+      "立体图形的认识及分类"
+    ],
+    "source": "2024 二年级上·全国·专题练习"
+  },
+  {
+    "id": "70",
+    "unit": "第五单元 观察物体",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "填一填.\n\n小狗看到的是图( ),小猴看到的是图( ),小猫看到的是图( ),小鸟看到的是图( )。",
+    "options": [],
+    "answer": "④;②;①;③",
+    "solution": "【分析】小狗看到的是房子的侧面且烟囱靠左;小猴看到房子正面有门有窗;小猫看到侧面且烟囱靠右;小鸟看到房顶.\n【详解】小狗看到④,小猴看到②,小猫看到①,小鸟看到③。",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "2024 二年级上·全国·专题练习"
+  },
+  {
+    "id": "71",
+    "unit": "第五单元 观察物体",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "桌子上放了两个立体图形，下图分别是站在哪个位置看到的，将序号填在相应的图片下面.\n\n![](images/0b5aefed387488e39da700337c46f95bc2027e8a89b4add79d2f62bff90d6201.jpg)\n\n![](images/958eac7310767880eccf63f2303220a32b4bf26cd09211540cf7ce862c397948.jpg)\n\n( );( );( );( )",
+    "options": [],
+    "answer": "②;③;①;④",
+    "solution": "【分析】从左面看只见大长方形;从前面看左大右小;从右面看前小后大的一半;从后面看左小右大.\n【详解】依次对应:②;③;①;④。",
+    "knowledge_points": [
+      "从不同位置观察两个物体的相互关系"
+    ],
+    "source": "24-25 六年级上·甘肃陇南·期中"
+  },
+  {
+    "id": "72",
+    "unit": "第五单元 观察物体",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "![](images/5086250e56630cb485584c5d1ef8fd7c06ab1e277bbd90de65ee5f2b40f8ee6f.jpg)\n\n(1)如图，从它的前面，侧面和上面观察，看到的都是( )形.\n(2)从它的( )面看到的是数字2，从它的侧面看到的是数字( ),从它的( )面看到的数字 3。",
+    "options": [],
+    "answer": "正方;上;6;前",
+    "solution": "【分析】该物体是正方体，各个面都是正方形;从上面看到数字2，从侧面看到数字6，从前面看到数字3.\n【详解】(1)正方形;(2)上面;6;前面。",
+    "knowledge_points": [
+      "立体图形的认识",
+      "从不同位置观察单个物体"
+    ],
+    "source": "24-25 二年级上·河北廊坊·期中"
+  },
+  {
+    "id": "73",
+    "unit": "第五单元 观察物体",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "观察如图的长方体，从前面看到的是( )形.\n\n![](images/220ae903f4cb34758652de9a689714ca6fcf49b78f88d24b020fe8c9218463b5.jpg)",
+    "options": [],
+    "answer": "长方",
+    "solution": "【分析】长方体从前面看到的面是长方形.\n【详解】从前面看到的是长方形。",
+    "knowledge_points": [
+      "长方形，正方形，三角形和圆的初步认识",
+      "从不同位置观察单个物体"
+    ],
+    "source": "23-24 二年级上·河北邢台·期中"
+  },
+  {
+    "id": "74",
+    "unit": "第五单元 观察物体",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "把符合要求的图形序号填在下面的括号里.\n\n![](images/2cabcb84a8dcbd5d9a5402de0a6039e2c63981ae6add55b50102b592ebd925bd.jpg)\n①\n![](images/b1e21a88a3d92fedf6946b727a62f21c7f06891d5eb2b24ee991614145793bca.jpg)\n②\n![](images/9f80dfe526b359d9e1241a47861900823cc2f5f6b95c8008168097b5ad03027a.jpg)\n③\n![](images/69bf209d4b31c2f5f1cdb7bd2fa9a06d8a20a055f1372f36c6d438cf0a8b5d33.jpg)\n④\n\n(1)从上面看是圆形的有( ).\n(2)从正面看是长方形的有( ).\n(3)从正面和上面看都是正方形的有( ).\n(4)从正面和上面看都是圆形的有( ).\n(5)从正面和上面看到的图形是一样的有( ).\n(6)从正面和左面看到的图形一样的有( )。",
+    "options": [],
+    "answer": "②,④;②,③;①;④;①,④;①,②,④",
+    "solution": "【分析】正方体从上面，正面，左面看都是正方形;圆柱上面看圆，正面和左面看长方形;长方体从上面，正面，左面看都是长方形;球从任何方向看都是圆.\n【详解】(1)②④;(2)②③;(3)①;(4)④;(5)①④;(6)①②④。",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "23-24 二年级上·全国·单元测试"
+  },
+  {
+    "id": "75",
+    "unit": "第五单元 观察物体",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "从正面看，是图( )。从左侧看，是图( )。从上面看，是图( ).\n\n![](images/55b1a38dfda43185d638105dfcab039af4120879434530972b8d6739f52a41e1.jpg)\n![](images/7425bb1acb64500c767be86ad0f4805f65d793faaf413e450c353f738dbee5e4.jpg)\n①\n![](images/0ae8d569c7a4e6dadda6cc7b1db9fc5cfe76e8098b82220f30fd66f1ffd48ae1.jpg)\n②\n![](images/acc553f31853d92f37804d7103ffe84b535ce7e0ffab9200b8ef7ec8e9874f24.jpg)\n③",
+    "options": [],
+    "answer": "②;①;③",
+    "solution": "【分析】从正面看：下层 3 个，上层 1 个在最左端;从左侧看：两层各 1 个;从上面看：一排 3 个.\n【详解】从正面看是②;从左侧看是①;从上面看是③。",
+    "knowledge_points": [
+      "物体三视图的认识"
+    ],
+    "source": "23-24 二年级上·全国·课后作业"
+  },
+  {
+    "id": "76",
+    "unit": "第五单元 观察物体",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "选一选，把序号填在括号里.\n\n(1)小洁从某一个方向看上面的物体，看到的是(给出的图形),她可能看的是( ).\n(2)小霞从某一个方向看上面的物体，看到的是(给出的图形),她可能看的是( )。",
+    "options": [],
+    "answer": "①;②或③",
+    "solution": "【分析】(1)只有①能看到题目给出的图形;(2)②从正面或上面能看到,③从上面能看到,①不能看到.\n【详解】(1)①;(2)②或③。",
+    "knowledge_points": [
+      "从不同位置观察单个物体",
+      "从不同位置观察两个物体的相互关系"
+    ],
+    "source": "23-24 二年级上·全国·课后作业"
+  },
+  {
+    "id": "77",
+    "unit": "第五单元 观察物体",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "选一选，把序号填在括号里.\n\n(1)从上面看是(给出的图形)的有( ).\n(2)从正面看是(给出的图形)的有( ).\n(3)从侧面看是(给出的图形)的有( )。",
+    "options": [],
+    "answer": "①,②,④,⑤;①,⑥;②,④,⑤",
+    "solution": "【分析】逐个判断每个物体从上面，正面，侧面看到的形状.\n【详解】(1)①②④⑤;(2)①⑥;(3)②④⑤。",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "23-24 二年级上·全国·课后作业"
+  },
+  {
+    "id": "78",
+    "unit": "第五单元 观察物体",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "对照下图，将合适的序号填入括号里.\n\n从正面看到的是( );从背面看到的是( );从上面看到的是( );从侧面看到的是( )。",
+    "options": [],
+    "answer": "①;④;③;②",
+    "solution": "【分析】从正面/背面/上面/侧面观察，分别对应题目给出的四个平面图.\n【详解】从正面是①;从背面是④;从上面是③;从侧面是②。",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "23-24 二年级上·全国·课后作业"
+  },
+  {
+    "id": "79",
+    "unit": "第五单元 观察物体",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "下面的图形分别是谁看到的。\n\n![](images/786bf3d50fe16d7719154131f9fa7b02287c629202afe987f40cedd16ba51598.jpg)\n\n![](images/d9901c7b793e8254b29fc7fd133223e40c431c1664e2b7d0306f7b10f75c4f9b.jpg)\n\n小强看到的是图( );小华看到的是图( );小力看到的是图( );小红看到的是图( )。",
+    "options": [],
+    "answer": "②;①;③;④",
+    "solution": "【分析】小华看到把手在左，壶嘴在右;小强看到把手在右，壶嘴在左;小红把手正对自己;小力壶嘴正对自己.\n【详解】小强②;小华①;小力③;小红④。",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "23-24 二年级上·全国·课后作业"
+  },
+  {
+    "id": "80",
+    "unit": "第五单元 观察物体",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "爸爸给林苗买了一个生日礼物，包装盒是个长方体。她想用手机给包装盒拍张照，发现拍照时一次最多只能拍到( )个面。",
+    "options": [],
+    "answer": "3",
+    "solution": "【分析】从一个方向观察长方体，最多能同时看到相邻的 3 个面.\n【详解】一次最多只能拍到 3 个面。",
+    "knowledge_points": [
+      "长方体的认识及特征",
+      "立体图形的认识",
+      "从不同位置观察单个物体"
+    ],
+    "source": "23-24 二年级上·全国·单元测试"
+  },
+  {
+    "id": "81",
+    "unit": "第五单元 观察物体",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "看图填空.\n\n![](images/0fcf12e22813ef9effb21313b6fdf6ee5cef537cd3efa7a047b68e681438b43e.jpg)\n\n![](images/97345049bdf7b7dc96464520dc88be20079983faaee93fdac0d7161bca56611d.jpg)\n\n(1)( )能看到小狗的眼睛，鼻子和耳朵，但看不见它的尾巴.\n(2)( )能看到小狗的一只耳朵，一只眼睛和尾巴.\n(3)( )能看到小狗的尾巴，但看不见它的眼睛和鼻子。",
+    "options": [],
+    "answer": "小石头;小明;小桃红",
+    "solution": "【分析】正面能看到眼睛鼻子耳朵;侧面能看到一只眼睛一只耳朵和尾巴;后面只能看到尾巴.\n【详解】(1)小石头;(2)小明;(3)小桃红。",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "23-24 二年级上·全国·单元测试"
+  },
+  {
+    "id": "82",
+    "unit": "第五单元 观察物体",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "下面四幅图分别是小女孩在几号位置观察到的。填一填.\n\n![](images/4a0f4774835ffccf148e235b5319848baaad5d4be891c52a89c75ed6f86db63d.jpg)\n\n![](images/d0b4b4ccb0204794947f9b6b33a0008e5d9b116a183df03a14460fcfd8e31e51.jpg)\n\n( );( );( );( )",
+    "options": [],
+    "answer": "1;3;4;2",
+    "solution": "【分析】1 号看到背面;2 号看到脸朝左的侧面;3 号看到正面;4 号看到脸朝右的侧面.\n【详解】依次填:1;3;4;2。",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "23-24 一年级下·山西晋城·期末"
+  },
+  {
+    "id": "83",
+    "unit": "第五单元 观察物体",
+    "question_type": "判断题",
+    "difficulty": 0.65,
+    "question": "![](images/7d61b252c99cde03d0a19f6740b5390b1de1022db5ae6628a1963bb416173083.jpg)\n这个小女孩看到的是(题图所示)。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】小女孩看到的是左边水壶壶嘴朝右，右边是水杯;题图中壶嘴朝左，所以不正确.\n【详解】原题错误。故答案为: ×",
+    "knowledge_points": [
+      "从不同位置观察两个物体的相互关系"
+    ],
+    "source": "25-26 三年级上·陕西安康·阶段练习"
+  },
+  {
+    "id": "84",
+    "unit": "第五单元 观察物体",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "小明从上面看到的是正方形，这个物体一定是正方体。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】仅从上面看到正方形不能确定一定是正方体，长方体也可能有正方形的面.\n【详解】该说法错误。故答案为: ×",
+    "knowledge_points": [
+      "从不同位置观察单个物体",
+      "立体图形的认识及分类"
+    ],
+    "source": "25-26 三年级上·甘肃天水·阶段练习"
+  },
+  {
+    "id": "85",
+    "unit": "第五单元 观察物体",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "从不同的方向观察同一个物体，看到的形状一定不同。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】例如球从任何方向看到的图形都是圆，所以可能相同.\n【详解】该说法错误。故答案为: ×",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "24-25 一年级下·湖南岳阳·期中"
+  },
+  {
+    "id": "86",
+    "unit": "第五单元 观察物体",
+    "question_type": "判断题",
+    "difficulty": 0.65,
+    "question": "一个足球平放桌面上，从上面，前面，左面看到的形状都是相同的。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】足球是球体，各方向看到的平面图形都是圆形.\n【详解】该说法正确。故答案为:√",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "24-25 四年级下·广东汕头·期中"
+  },
+  {
+    "id": "87",
+    "unit": "第五单元 观察物体",
+    "question_type": "判断题",
+    "difficulty": 0.65,
+    "question": "两个同学从不同角度观察同一个长方体，看到的形状可能是一样的，也可能是不一样的。( )\n\n![](images/e2facf2340b105c13fecd3ccb196ea447362bd4a429a5965897aeaf5e9be8d9f.jpg)",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】长方体从不同方向可能看到相同形状(如正面与左面相同),也可能不同(如正面与上面不同).\n【详解】该说法正确。故答案为:√",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "24-25 二年级上·河南南阳·期末"
+  },
+  {
+    "id": "88",
+    "unit": "第五单元 观察物体",
+    "question_type": "判断题",
+    "difficulty": 0.65,
+    "question": "圆柱不管从左面看还是上面看，看到的都是圆形。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】圆柱从上面看是圆形，从左面看是长方形.\n【详解】该说法错误。故答案为: ×",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "24-25 二年级上·湖南娄底·期末"
+  },
+  {
+    "id": "89",
+    "unit": "第五单元 观察物体",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "从不同位置观察同一立体图形，看到的形状可能相同，也可能不同。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】一般物体从不同位置看到形状不同;但球，正方体等从不同位置可能看到相同形状.\n【详解】该说法正确。故答案为:√",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "24-25 二年级上·甘肃·期末"
+  },
+  {
+    "id": "90",
+    "unit": "第五单元 观察物体",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "一个立体图形，从某个方向看到的是正方形，这个立体图形一定是正方体。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】从某个方向看到正方形，可能是正方体，也可能是有正方形面的长方体等.\n【详解】该说法错误。故答案为: ×",
+    "knowledge_points": [
+      "长方体的认识及特征",
+      "正方体的特征",
+      "从不同位置观察单个物体"
+    ],
+    "source": "24-25 二年级上·广东汕头·期末"
+  },
+  {
+    "id": "91",
+    "unit": "第五单元 观察物体",
+    "question_type": "判断题",
+    "difficulty": 0.65,
+    "question": "所有的长方体无论从哪个方向观察都是长方形。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】若长方体的长和宽相等，从上面看到可能是正方形，不一定都是长方形.\n【详解】该说法错误。故答案为: ×",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "24-25 二年级上·河北秦皇岛·期末"
+  },
+  {
+    "id": "92",
+    "unit": "第五单元 观察物体",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "一个物体从不同位置观察到的图形都一样。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】一般物体从不同位置观察形状不一样;也可能出现一样(如球，正方体),所以不能说都一样.\n【详解】该说法错误。故答案为: ×",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "23-24 二年级上·河北保定·期末"
+  },
+  {
+    "id": "93",
+    "unit": "第五单元 观察物体",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "从不同的角度观察同一物体，看到的形状一定不一样。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】球体，正方体等从不同角度看到的形状可能相同.\n【详解】该说法错误。故答案为: ×",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "23-24 二年级上·河南南阳·期末"
+  },
+  {
+    "id": "94",
+    "unit": "第五单元 观察物体",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "从不同的位置观察同一个物体，所看到的形状可能是相同的。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】例如正方体从不同位置看到的形状都是正方形.\n【详解】该说法正确。故答案为:√",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "24-25 四年级上·湖南邵阳·期中"
+  },
+  {
+    "id": "95",
+    "unit": "第五单元 观察物体",
+    "question_type": "判断题",
+    "difficulty": 0.65,
+    "question": "小丽给亮亮拍照，如图，则小丽是站在亮亮左面拍的照。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】照片中亮亮脸朝右，说明站在亮亮的右面拍的照.\n【详解】原题错误。故答案为: ×",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "24-25 二年级上·河北廊坊·期中"
+  },
+  {
+    "id": "96",
+    "unit": "第五单元 观察物体",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "我们只观察物体的一面，不能判断物体的形状。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】只看一面信息不足，通常需要从前面，上面，侧面等多个方向观察.\n【详解】该说法正确。故答案为:√",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "20-21 二年级上·河北张家口·期末"
+  },
+  {
+    "id": "97",
+    "unit": "第五单元 观察物体",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "任何一个物体从不同方向看到的形状一定是不同的。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】球从不同方向看到的形状相同(都是圆),所以不一定不同.\n【详解】该说法错误。故答案为: ×",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "23-24 二年级上·全国·单元测试"
+  },
+  {
+    "id": "98",
+    "unit": "第五单元 观察物体",
+    "question_type": "连线题",
+    "difficulty": 0.65,
+    "question": "下面的图形是谁看到的。连一连.\n\n![](images/523a1de8a7cf882cf2894c906513cbc5d4f0fda84031d8a5412809b9b40cfa4b.jpg)\n\n![](images/3fdef94a90fd60332e46bb3645b690f7c55a18d5f0cf3275e947a25c3d1b20ee.jpg)\n\n![](images/bfd698356a00ec85364e970f5839b49ffbce460e922b705f2e109d27c393ea92.jpg)\n\n![](images/6142fa52adb66ae4047570e4e7e263001e89a6ae69bb8f9d957841402629ac24.jpg)",
+    "options": [],
+    "answer": "见题图",
+    "solution": "【分析】根据三位同学观察到的平面图形特征进行连线.\n【详解】![](images/761c59e4cd1e22782da62f2b2bf18053680ad4f937e93d218cc34e31fbe825ae.jpg)",
+    "knowledge_points": [
+      "从不同位置观察两个物体的相互关系"
+    ],
+    "source": "23-24 二年级上·浙江绍兴·期末"
+  },
+  {
+    "id": "99",
+    "unit": "第五单元 观察物体",
+    "question_type": "连线题",
+    "difficulty": 0.85,
+    "question": "他们拍的照片分别是哪一张。连一连.\n\n![](images/10636ec5103303aa5dd3ba9177809e94da08ce245e97d0b8d5a42163e399ce6d.jpg)",
+    "options": [],
+    "answer": "见题图",
+    "solution": "【分析】贝贝拍到小猪正面;欢欢拍到尾巴;迎迎拍到头朝右侧面;京京拍到头朝左侧面.\n【详解】![](images/9e06b45bccc665b85a9526fc0107e40a0d3e90d39cd1be4aed2342aaa5b01dbc.jpg)",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "23-24 二年级上·浙江温州·期末"
+  },
+  {
+    "id": "100",
+    "unit": "第五单元 观察物体",
+    "question_type": "连线题",
+    "difficulty": 0.65,
+    "question": "下面的图形分别是谁看到的。连一连.\n\n![](images/bf8a56546d2cde3091b1978f987d403ad996d34d7c5b61312367acbb6c55be2f.jpg)",
+    "options": [],
+    "answer": "见题图",
+    "solution": "【分析】根据壶嘴，把手方向以及杯子相对位置判断各图对应的观察者.\n【详解】![](images/91f63b866cd73ced50307b2e90277107f7459b7b6f2715f8c0a153d6f6278c25.jpg)",
+    "knowledge_points": [
+      "从不同位置观察两个物体的相互关系"
+    ],
+    "source": "23-24 二年级上·浙江绍兴·期末"
+  },
+  {
+    "id": "101",
+    "unit": "第五单元 观察物体1",
+    "question_type": "选择题",
+    "difficulty": 0.94,
+    "question": "观察下边的图形，从上面看到的是( ).\n\n![](images/3c13dd4d8aed21c5ae32e5a613e52389d0af956d47f3a0223feab78e4b5246ed.jpg)",
+    "options": [
+      "A. ![](images/aace71b803adb3cd7590f63265a27731e805b454237411a5b6819f497fff6451.jpg)",
+      "B. ![](images/d6fcb0592c9c8e899c744320f7f8129c5ae2770d63812d6e5d928ee4c6b0b5a0.jpg)",
+      "C. ![](images/565092986c3c2316265476a6619844653b1575d03f99f7375d649e2e587aaab0.jpg)"
+    ],
+    "answer": "B",
+    "solution": "【分析】从上面观察该几何体，看到的是一层横向摆放的 2 个小正方形.\n【详解】从上面看到的图形是选项 B。故答案为:B",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "22-23 二年级上·湖南株洲·期末"
+  },
+  {
+    "id": "102",
+    "unit": "第五单元 观察物体1",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "从前面看立体图形( ),看到的不是长方形。",
+    "options": [
+      "A. ![](images/e38eb98298e08ea69e77cfac5a2f4d0edc8feb4edd4338fb73469cb5687deffe.jpg)",
+      "B. ![](images/58b1228519df6f3071d09c0bd1876dd6b69b93fdda1f2ebbbc9e3e63ff75db46.jpg)",
+      "C. ![](images/fa419a8f8e927b66cdaa5d9e2e12e20798a9f1960028b7e47eae6b72771c2001.jpg)"
+    ],
+    "answer": "C",
+    "solution": "【分析】圆柱从前面看是长方形，长方体从前面看是长方形，球从前面看是圆形.\n【详解】只有从球的前面看到的不是长方形。故答案为:C",
+    "knowledge_points": [
+      "立体图形的认识",
+      "长方形，正方形，三角形和圆的初步认识",
+      "从不同位置观察单个物体"
+    ],
+    "source": "22-23 二年级上·河南南阳·期末"
+  },
+  {
+    "id": "103",
+    "unit": "第五单元 观察物体1",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "从正面看到形状是 ![](images/10b3548074fd657f9303dddc5077a97860bd5b3a36d75fec820b53fe961b6739.jpg) 的图形是( )。",
+    "options": [
+      "A. ![](images/8f3a4b25c406b19be28c9fdac863ef251a66cabf278677c66e8e08864aeebcec.jpg)",
+      "B. ![](images/ad0d789ab5b2d70132fed5c69e2360c5d6def34bd4c0a65413695cdfc73c6f63.jpg)",
+      "C. ![](images/c89c306b0fa3937c9cb35ccf522484cf672553dcf81cb53e7d4522349366a9ca.jpg)"
+    ],
+    "answer": "B",
+    "solution": "【分析】逐项观察三个立体图形从正面看到的平面图形，与给定形状比较.\n【详解】只有选项 B 从正面看到的形状与题中给出的形状一致。故答案为:B",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "22-23 二年级上·河北邢台·期末"
+  },
+  {
+    "id": "104",
+    "unit": "第五单元 观察物体1",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "站在 ![](images/2026-03-03%20112047.jpg) 的侧面，看到的是图( )。",
+    "options": [
+      "A. ![](images/0aac0ed52b606aade33899e0193f70aa24fdf07c90125ec2b75f7980a9d2052d.jpg)",
+      "B. ![](images/31818d6bc51bc7eb22587520afa756f3bc0e232da8d681d2ac5564ca5d8e7dd2.jpg)",
+      "C. ![](images/f4debe3f9142872a3fa621ba8c16446cfb9203e58f93c98650fb287d3c4cb1ff.jpg)"
+    ],
+    "answer": "B",
+    "solution": "【分析】从侧面观察该物体，能看到其侧面轮廓，对应选项 B.\n【详解】A 为前面,C 为后面,B 为侧面。故答案为:B",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "23-24 一年级下·河南商丘·期中"
+  },
+  {
+    "id": "105",
+    "unit": "第五单元 观察物体1",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下图中，小鸟看到的是( )图.\n\n![](images/2026-03-03%20112306.jpg)",
+    "options": [
+      "A. ![](images/6728c5f7c661a00efa87b204088d67c7289b2f135778e9bfce01d6f8d1e53fd3.jpg)",
+      "B. ![](images/beaf41701ed6de217563bdee5633e8531edbc27648d89647914e33a8c8fc9ecf.jpg)",
+      "C. ![](images/068cd3659f6c3e772f3bc19552c3b5f486ea2ad6c22747adc95f3be8e49e43e1.jpg)",
+      "D. ![](images/04d2414a35463ff98f79052972a482b410bc149b08dc20f4ce7eab3b62c7230f.jpg)"
+    ],
+    "answer": "D",
+    "solution": "【分析】小鸟从正上方看，能看到 8 个小方块连成一排的形状.\n【详解】与此对应的是 D。故答案为:D",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "23-24 二年级上·浙江台州·期末"
+  },
+  {
+    "id": "106",
+    "unit": "第五单元 观察物体1",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "从上面看是 ![](images/2026-03-03%20112434.jpg) 的立体图形是( )。",
+    "options": [
+      "A. ![](images/8845cbb9b54b68f35b6a5e36c3ca687ed38c9c117359d3213fc7b7cfb32963aa.jpg)",
+      "B. ![](images/f650dec2013f353ff042f24696882fc28c127457b5535075f393cd0d93bd4f9a.jpg)",
+      "C. ![](images/e5a6abc6031cb38777af3adf54b1eaee5bb17c79eef857d3e55527055bcf5d5b.jpg)"
+    ],
+    "answer": "C",
+    "solution": "【分析】从上面观察，题图对应的是一行 3 个小正方形的形状，对应选项 C 的上视图.\n【详解】从上面看得到题中给定的平面图形的是 C。故答案为:C",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "23-24 二年级上·河南周口·期末"
+  },
+  {
+    "id": "107",
+    "unit": "第五单元 观察物体1",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "从正面观察 ![](images/2026-03-03%20112705.jpg) 看到的是图( ),从上面看到的是图( ).\n\n![](images/9db21eb290aba5dbeea011b24ffd90c65255a0bd54d266a878c1014084f60288.jpg)\n\n![](images/d423606dfda5b9e0ac9a4088791a5759a104411db96283264dcbd0308bc3b1ca.jpg)\n\n![](images/c3eb11610d5eafc1908fc6de51c83d6cc09515336abe2e9287b9e666eb25ad19.jpg)",
+    "options": [
+      "A. ③①",
+      "B. ①③",
+      "C. ②①"
+    ],
+    "answer": "A",
+    "solution": "【分析】从正面能看到门，窗和烟囱，对应图③;从上面能看到房顶和烟囱口，对应图①.\n【详解】正面是③,上面是①,对应\"③①\"。故答案为:A",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "23-24 二年级上·甘肃庆阳·期末"
+  },
+  {
+    "id": "108",
+    "unit": "第五单元 观察物体1",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "如图，小鸟从上面看到积木的形状是( ).\n\n![](images/40bf51b1951dca89d70aa73224d33e6d9ebe861671fdc2b040ac233ca0744b8d.jpg)",
+    "options": [
+      "A. ![](images/d6134f0a9e1058d719666f35335804226beb858cd84cd8992b7ffbebfbef0bf9.jpg)",
+      "B. ![](images/0798b75cd8f36c25018aa6d1623521fed70d7e63f51627ebdf50fa2158c0df56.jpg)",
+      "C. ![](images/82143f25f08ec60ca03a720e6b5b31db572456edcb29becadf86974342efe55e.jpg)"
+    ],
+    "answer": "A",
+    "solution": "【分析】从上面看该积木是一列 3 个小正方形，对应选项 A.\n【详解】小鸟从上面看到的形状是 A。故答案为:A",
+    "knowledge_points": [
+      "物体三视图的认识"
+    ],
+    "source": "23-24 二年级上·浙江温州·期末"
+  },
+  {
+    "id": "109",
+    "unit": "第五单元 观察物体1",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "优优看到的是图( ).\n\n![](images/f4bef442c5be3da8272bf34f9b893cb13f711c7b0941077d2630e02cc3269dbb.jpg)",
+    "options": [
+      "A. ![](images/3e589d702205faa902bb77dd7fee3190c55fc8ce16755b52a9033e9084ecf261.jpg)",
+      "B. ![](images/e33d28285fa3b84c17673bd27baf7fcff7f00e59f09fb130ba5547bf2e141761.jpg)",
+      "C. ![](images/96fdad59e4686faf7f5723bbc0b9d7f070ddc181372ab6c3e41842bf2bb12b16.jpg)"
+    ],
+    "answer": "B",
+    "solution": "【分析】优优面对柜子较窄的一侧，看到的是柜子的窄侧面，对应 B.\n【详解】优优看到的是 B。故答案为:B",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "23-24 二年级上·山东菏泽·期末"
+  },
+  {
+    "id": "110",
+    "unit": "第五单元 观察物体1",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "下面这个模型，从上面看到的是( ).\n\n![](images/c58e9fbfc7389c4dd5b26e4258d75e815cabea487da68c00170b9634bbad8b10.jpg)",
+    "options": [
+      "A. ![](images/222917bcf8166628b3296b3ab23e430c081d5fe836eb1b733c5962f3b24c641a.jpg)",
+      "B. ![](images/c9e9e3ee83b167ff932cefb8bf51f406b184cc43fe139b8ce7adb2ca7b85509a.jpg)",
+      "C. ![](images/6f13d03b0c5ec7c03c5f449bb0a178c270bf06a293a1ab2e3dd8cd7608ff792a.jpg)"
+    ],
+    "answer": "A",
+    "solution": "【分析】从上面看，看到下层 7 个小正方形三行排列：上 3，中 2，下 2，对应 A.\n【详解】从上面看到的是 A。故答案为:A",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "23-24 二年级上·广东佛山·期末"
+  },
+  {
+    "id": "111",
+    "unit": "第五单元 观察物体1",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面的图形( )是 ![](images/6e722832e7d081bfa966c5241e038e94a1947ae7af996b5e84e49b453679c205.jpg) 的右面。",
+    "options": [
+      "A. ![](images/098b813c8452c87a918183d02db4860056e666e60afbd1df86fa4c5681cd3ebe.jpg)",
+      "B. ![](images/5bceacd3e18b5653b61337d88ad3e5a7e38998a4128e936461f0a4fe3a247836.jpg)",
+      "C. ![](images/bcf5c43a6eebd4e046b3c896bf728cd7c2f9f7110dbb313d86461a6ac34f56ae.jpg)"
+    ],
+    "answer": "B",
+    "solution": "【分析】长方体的前后，左右，上下各面对应不同形状;题中右面是与左面相对的那一面.\n【详解】B 对应长方体的右面。故答案为:B",
+    "knowledge_points": [
+      "长方体的认识及特征",
+      "长方形，正方形，三角形和圆的初步认识",
+      "从不同位置观察单个物体"
+    ],
+    "source": "23-24 一年级下·全国·课后作业"
+  },
+  {
+    "id": "112",
+    "unit": "第五单元 观察物体1",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "当当过生日时，爸爸给他定做的生日蛋糕如下图，从上面看到的是( ).\n\n![](images/e9e9d52cbaa0c433b32f5284baf3b98a4011bc8e3831f20de0e252c3950a0ead.jpg)",
+    "options": [
+      "A. ![](images/826c9d123482836339d068349254cca65bbc51f2a27ac6d3702c2ec95e6eed99.jpg)",
+      "B. ![](images/3d03d30dc0c7b44e146813a3db229c01e0687cab03994499f36d7dc001d9951f.jpg)",
+      "C. ![](images/0175588519b8bfd6a89964e97a3199995d43eec2afe5f101f764cba4da83a468.jpg)"
+    ],
+    "answer": "A",
+    "solution": "【分析】蛋糕是三层大小不同的圆柱，从上面能看到 3 个大小不同的同心圆.\n【详解】与此对应的是 A。故答案为:A",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "23-24 二年级上·湖南怀化·期末"
+  },
+  {
+    "id": "113",
+    "unit": "第五单元 观察物体1",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "仔细观察，小狗看到的是( ).\n\n![](images/c3285eb5dd911b84f0c5073aeb9fb935b0d118562d6fc00b2d686203f2ed02ce.jpg)",
+    "options": [
+      "A. ![](images/7ae556a3d98ffa434351605fee65f685197af902e9dacc5cce8062ded97cb4c1.jpg)",
+      "B. ![](images/b5aa379c0a6a5271497609020895d52337eb6ca98cbd5df90bd325c8a53ad302.jpg)",
+      "C. ![](images/e5dfa9bab570a296862154075c328c77b7b848d63f5d94462374fb2994894b78.jpg)"
+    ],
+    "answer": "B",
+    "solution": "【分析】小猴在前面，小鸟在上方，小狗在侧面;侧面图对应 B.\n【详解】小狗看到的是 B。故答案为:B",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "23-24 二年级上·江西新余·期末"
+  },
+  {
+    "id": "114",
+    "unit": "第五单元 观察物体1",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "小兰从上面看到的是( ).\n\n![](images/59cc471336cd464d8d50696366cd4bb413e5058ffd7889387718538f7b6459ee.jpg)",
+    "options": [
+      "A. ![](images/2026-03-03%20113235.jpg)",
+      "B. ![](images/2026-03-03%20113244.jpg)",
+      "C. ![](images/b3e9111c471ae209791d21f58a763400b4bae3354f1811eb1265389f8f6cbbb3.jpg)"
+    ],
+    "answer": "B",
+    "solution": "【分析】从上面看只能看到桌面的轮廓和桌腿位置对应的形状，选项 B 与之对应.\n【详解】小兰从上面看到的是 B。故答案为:B",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "23-24 二年级上·安徽芜湖·期末"
+  },
+  {
+    "id": "115",
+    "unit": "第五单元 观察物体1",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "明明拍的是下面( )幅照片.\n\n![](images/5c64c0dac6fe783be42718cd2911112a68f76c6ee76bb02a2932bbb598dd6818.jpg)",
+    "options": [
+      "A. ![](images/6af7c43c33c2ca993a549a9ca83db7ffd0792d00e71e7ab80b4985e6ad1b6660.jpg)",
+      "B. ![](images/e644762418ad2f9ddfed8fe8f57d0d22c3be53397375a4e364261ac7126c72c8.jpg)",
+      "C. ![](images/7f5aea5a737fc23e8e2fd360fab7aed3d5726d87e0e0db2d86247aff02100e66.jpg)"
+    ],
+    "answer": "B",
+    "solution": "【分析】明明在小猫正前方拍照，能看到小猫正脸，对应 B.\n【详解】明明拍的是 B。故答案为:B",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "23-24 二年级上·浙江台州·期末"
+  },
+  {
+    "id": "116",
+    "unit": "第五单元 观察物体1",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "如图，小林看到的茶壶的样子是( ).\n\n![](images/d50f89204e50526e9175a05c3ed738dd4234c04db64bc84752fa5d72c64592d4.jpg)",
+    "options": [
+      "A. ![](images/42ff1f56770e1726f8ae9c82240368a5a5712385da242cf62264d19cb973d9ba.jpg)",
+      "B. ![](images/343713052f4a788cbcee475d9453e975c3b4c11d7a9aa049f2ad18a7aa6e4627.jpg)",
+      "C. ![](images/527a2950217663ce25f6ddc475ec6730854f3a0accb81bc77cadf983817fb377.jpg)"
+    ],
+    "answer": "A",
+    "solution": "【分析】小林在茶壶右侧，看到壶嘴朝右，把手朝左，对应 A.\n【详解】小林看到的是 A。故答案为:A",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "23-24 二年级上·浙江温州·期末"
+  },
+  {
+    "id": "117",
+    "unit": "第五单元 观察物体1",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "从上面看这两个物体 ![](images/2026-03-03%20113404.jpg) 和 ![](images/9e0430354d650b382f3011debfb8fda4aa15f20693a43d282531903ce4137adc.jpg),看到的都是( )。",
+    "options": [
+      "A. ![](images/f8db85b4f5a1bb312b4f27b22cce85add2dafe8a279311f0b6939af9029d4c4f.jpg)",
+      "B. ![](images/ad1ed69da009d1f0d0d5f7801bbea37d311a27ac15ec53ab3c5da72dc4ac5244.jpg)",
+      "C. ![](images/3b78e13016302b2615b2ce5d16fff9bf5995f9af305a11aeff5366734fe18c9d.jpg)"
+    ],
+    "answer": "A",
+    "solution": "【分析】从上面看两个物体都呈现 2 个小正方形一排的形状，对应 A.\n【详解】从上面看到的都是 A。故答案为:A",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "23-24 二年级上·山东济南·期末"
+  },
+  {
+    "id": "118",
+    "unit": "第五单元 观察物体1",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "女孩看到的图形是( ).\n\n![](images/116c1917fd992ccc334d9ecdff915d71da265c114de0bd65498353d24660fc6e.jpg)",
+    "options": [
+      "A. ![](images/12af808197be5b519023e9c15e15bd1d6fe1c40b70e31bde8e3a7f9b970b4222.jpg)",
+      "B. ![](images/84c077716ac72b4023609bf0575ace9f6f73647466fb1530a8d2fdf6381bff3a.jpg)",
+      "C. ![](images/4da8c1f835ecfa0629b2c7e50b32a0ded0a86b03d8addf835c7082c8fbcc0a8d.jpg)"
+    ],
+    "answer": "B",
+    "solution": "【分析】女孩在侧面，看到上下两个正方形竖直排列的形状.\n【详解】对应选项 B。故答案为:B",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "23-24 二年级上·湖北武汉·期末"
+  },
+  {
+    "id": "119",
+    "unit": "第五单元 观察物体1",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "根据图，下面哪幅图是小军看到的。( )\n\n![](images/53a9ec3ea76a4d301b62724badaf5cb532ba2f488c26ac47c34c1c198f50a692.jpg)",
+    "options": [
+      "A. ![](images/51daa87085686fa493b114e3699656b8c6d2999e18464cfdeeb7353b95d0f695.jpg)",
+      "B. ![](images/bd8a5175aa4abf56cf5baf82012893bfd03c244b24b9cdb603c002a4d4684f59.jpg)",
+      "C. ![](images/f9e6b2ff116a9fd9389595b30a86e8d675596f8b33e8b2410707e5928f2585ab.jpg)"
+    ],
+    "answer": "C",
+    "solution": "【分析】小军在侧面，看到人物脸朝右的侧面图.\n【详解】对应 C。故答案为:C",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "23-24 二年级上·贵州铜仁·期末"
+  },
+  {
+    "id": "120",
+    "unit": "第五单元 观察物体1",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "仔细观察下图,![](images/931502fbb9743952ad74c4877fda3c9140bea5d9011f42ad543c0a9279dfb58f.jpg) 是从( )方向看的.\n\n![](images/3c18ebbd87c30d4e0d3f959ef2d6c8ea127961b535e38cd74df2a4f66547557f.jpg)",
+    "options": [
+      "A. 正面",
+      "B. 左面",
+      "C. 上面",
+      "D. 右面"
+    ],
+    "answer": "D",
+    "solution": "【分析】从右面观察该立体，得到的平面图形与题中给出的相同.\n【详解】所以是从右面看的。故答案为:D",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "23-24 二年级上·浙江·期末"
+  },
+  {
+    "id": "121",
+    "unit": "第五单元 观察物体1",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面的圆柱从左面看到的是( ).\n\n![](images/9486d7a63aa3dfd3544fd3b199b63d0052d1fb21b6c23d8f491b65c1db9721b5.jpg)",
+    "options": [
+      "A. 圆形",
+      "B. 长方形",
+      "C. 正方形"
+    ],
+    "answer": "B",
+    "solution": "【分析】圆柱从上面看是圆，从前后左右看都是长方形.\n【详解】从左面看到的是长方形。故答案为:B",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "23-24 二年级上·河南南阳·期末"
+  },
+  {
+    "id": "122",
+    "unit": "第五单元 观察物体1",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "小华从某个方向看一个立体图形，看到的是圆，它不可能是( )。",
+    "options": [
+      "A. ![](images/3c087c5b7adb5e528fcd6e3a94b2fcc2642243981203fe03801a3cd929b1e596.jpg)",
+      "B. ![](images/61156c16e78c6f3323509a9d62c7fecd33f210b8526279f64f7aedeeb4168b7c.jpg)",
+      "C. ![](images/458aee6f19335627ff599b29d4335ca41a6efa6cf2262f74c2bf455d50d87fca.jpg)"
+    ],
+    "answer": "B",
+    "solution": "【分析】圆柱从上面可以看到圆;球从任何方向看到都是圆;长方体从任何方向都看不到圆.\n【详解】所以不可能是长方体。故答案为:B",
+    "knowledge_points": [
+      "从不同位置观察单个物体",
+      "物体三视图的认识"
+    ],
+    "source": "23-24 二年级上·江西赣州·期末"
+  },
+  {
+    "id": "123",
+    "unit": "第五单元 观察物体1",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面的图( )是小红看到的.\n\n![](images/89149950d2b21abdb9112dba62b1b548b0de19ac5d02c3d58efdc283e38b807a.jpg)",
+    "options": [
+      "A. ![](images/eac6caf4a75fbfc9a8fd170ecbc6f21825dd4ea1041324b24f30989d0432fe4a.jpg)",
+      "B. ![](images/ce54fa27fd2820e139cc183121176d2de079b8f10fd7393fd24ee79184d040b4.jpg)",
+      "C. ![](images/21218e82577ca4642290b120127b9261fcf0a32f5a16659db4c17b1fbb9ef0ae.jpg)"
+    ],
+    "answer": "B",
+    "solution": "【分析】小红看到的是壶嘴在右，把手在左的侧面图.\n【详解】对应 B。故答案为:B",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "23-24 二年级上·江西赣州·期末"
+  },
+  {
+    "id": "124",
+    "unit": "第五单元 观察物体1",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "小猫看到的是哪个图形。( )\n\n![](images/2026-03-03%20145102.jpg)",
+    "options": [
+      "A. ![](images/f2447e52d859d9a9e1f48c9dbdb5648c60e2c69e967c77ce2e3b879eb596a88a.jpg)",
+      "B. ![](images/8a44d9efb88525a0b0c4e1cfe417872e2b1647c0a08a082647fb70523e06ef50.jpg)",
+      "C. ![](images/2026-03-03%20144957.jpg)"
+    ],
+    "answer": "A",
+    "solution": "【分析】小猫在物体左边，看到的是一个正方形侧面，对应 A.\n【详解】A 为左侧视图。故答案为:A",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "23-24 二年级上·河南信阳·期末"
+  },
+  {
+    "id": "125",
+    "unit": "第五单元 观察物体1",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "从一个立体图形的一个面看的是圆形，这个立体图形是( )。",
+    "options": [
+      "A. 圆柱体",
+      "B. 正方体",
+      "C. 长方体"
+    ],
+    "answer": "A",
+    "solution": "【分析】圆柱从上下看是圆;正方体和长方体的面是正方形或长方形.\n【详解】所以该立体图形是圆柱体。故答案为:A",
+    "knowledge_points": [
+      "立体图形的认识",
+      "从不同位置观察单个物体"
+    ],
+    "source": "23-24 二年级上·山东临沂·期末"
+  },
+  {
+    "id": "126",
+    "unit": "第五单元 观察物体1",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "一个立体图形，从某个角度看到的图形是正方形，这个立体图形不可能是( )。",
+    "options": [
+      "A. 长方体",
+      "B. 圆柱",
+      "C. 球"
+    ],
+    "answer": "C",
+    "solution": "【分析】长方体可以有正方形面;圆柱从侧面在特殊情况下也可看到正方形;球从任何方向看都是圆形.\n【详解】因此不可能是球。故答案为:C",
+    "knowledge_points": [
+      "长方体的认识及特征",
+      "圆柱的认识及特征",
+      "长方形，正方形，三角形和圆的初步认识",
+      "从不同位置观察单个物体"
+    ],
+    "source": "23-24 一年级上·四川乐山·期末"
+  },
+  {
+    "id": "127",
+    "unit": "第五单元 观察物体1",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "仔细观察下图，从右面看到的是( ).\n\n![](images/6fc0c333f46e22936780fa33e8bfdb0f51945057dfbe965fa40334c75cba7896.jpg)",
+    "options": [
+      "A. ![](images/e85a0ee79023aeccfb2a932ae42837e16e4f611a27175063bb848dc74deda7a8.jpg)",
+      "B. ![](images/9979bed91e2d0c2ebccb0d7a7700a46ebd00d297720ab73b5a9713cf259c291c.jpg)",
+      "C. ![](images/3797a5b70fb131c4d3c6aea1feb51a1540539d3a9f6345882cf9bba4f1714f40.jpg)"
+    ],
+    "answer": "B",
+    "solution": "【分析】从右面看是两个上下相邻的正方形，对应 B.\n【详解】从右面看到的是 B。故答案为:B",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "23-24 二年级上·四川广元·期末"
+  },
+  {
+    "id": "128",
+    "unit": "第五单元 观察物体1",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "观察下面的立体图形，从①位置看到的形状是( ).\n\n![](images/984f357174bab2931dda291236a3a33b7cc006a6ae6ddabe6b99f03c84827542.jpg)",
+    "options": [
+      "A. ![](images/a6313e46d2856bd85f37166586153dc1a293016bf8839be17617307f45064450.jpg)",
+      "B. ![](images/2026-03-03%20145523.jpg)",
+      "C. ![](images/2026-03-03%20145536.jpg)"
+    ],
+    "answer": "A",
+    "solution": "【分析】从①(左侧)看，圆柱被正方体完全遮挡，只能看到正方体的一个正方形面.\n【详解】形状是正方形，对应 A。故答案为:A",
+    "knowledge_points": [
+      "从不同位置观察两个物体的相互关系"
+    ],
+    "source": "22-23 二年级上·河南南阳·阶段练习"
+  },
+  {
+    "id": "129",
+    "unit": "第五单元 观察物体1",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "一个图形，站在它的前面看，看到的是( )。",
+    "options": [
+      "A. ![](images/91e21f9deb591e466686e672b8a9a6590e8449b1cdc095ba754fcbc6fcd4f9f5.jpg)",
+      "B. ![](images/ba368f381113794662e1b0ac7cdd486e4490083e82d78db84208851f4fbf9d73.jpg)",
+      "C. ![](images/7001b848fbb5608a01e1fc7811f7907e7b540c56136aafc54bc9964a27061137.jpg)"
+    ],
+    "answer": "C",
+    "solution": "【分析】该图形是圆柱体，站在前面看到的是其侧面长方形.\n【详解】所以应选 C。故答案为:C",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "23-24 二年级上·浙江宁波·期末"
+  },
+  {
+    "id": "130",
+    "unit": "第五单元 观察物体1",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "欢欢，乐乐，明明三个好朋友一起观察物体，图2 的样子是( )看到的.\n\n![](images/8949783011fb541249b5627b17ef3b2a0b099b47fac7769c01a633384c2aadfc.jpg)\n\n![](images/969db0281cc1a3f94a83d6c60a12d5307128b3a43a60b6530e8b8fafbeb9e008.jpg)\n图2",
+    "options": [
+      "A. 乐乐",
+      "B. 欢欢",
+      "C. 明明"
+    ],
+    "answer": "A",
+    "solution": "【分析】明明看到杯子在左，壶在右;乐乐看到杯子在前，壶在后;欢欢只看到壶把.\n【详解】图 2 中杯子在前，壶在后，是乐乐看到的。故答案为:A",
+    "knowledge_points": [
+      "从不同位置观察两个物体的相互关系"
+    ],
+    "source": "23-24 二年级上·浙江温州·期末"
+  },
+  {
+    "id": "131",
+    "unit": "第五单元 观察物体1",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "观察下面 4 个物体，可以看到长方形的物体有( )个.\n\n![](images/1e6ef0e29b3c386416d4139cd5fa9862417444ad09bca48b83e3d1d3f786cb4d.jpg)",
+    "options": [
+      "A. 1",
+      "B. 2",
+      "C. 3"
+    ],
+    "answer": "C",
+    "solution": "【分析】长方体从多方向能看到长方形;圆柱从侧面能看到长方形;第三，第四个立体也能从某些方向看到长方形.\n【详解】4 个物体中有 3 个可以看到长方形。故答案为:C",
+    "knowledge_points": [
+      "长方形，正方形，三角形和圆的初步认识",
+      "从不同位置观察单个物体"
+    ],
+    "source": "23-24 二年级上·湖南株洲·期末"
+  },
+  {
+    "id": "132",
+    "unit": "第五单元 观察物体1",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "如图的图形，从各个方向看到都一样的是( ).\n\n![](images/688082637eb07a14fa5ad60d397d5b9b17b154490d5ab5b87ea76c191ccbd4eb.jpg)\n\n![](images/dacc568572e7c98fbf62519bbb0dcda66d8ac84d177d9db88d7b340dc398b39f.jpg)\n\n![](images/2026-03-03%20145855.jpg)",
+    "options": [
+      "A. 第一个",
+      "B. 第二个",
+      "C. 第三个"
+    ],
+    "answer": "C",
+    "solution": "【分析】只有球从各个方向看都是圆，而长方体和圆柱从不同方向看形状不同.\n【详解】第三个是球，符合条件。故答案为:C",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "23-24 二年级上·广东广州·期末"
+  },
+  {
+    "id": "133",
+    "unit": "第五单元 观察物体1",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "如图:![](images/2820b40a7cb6792e42f79f07ea01ead8fb69283c9c8f2c849eea5c7dce3f2f41.jpg),从前面看到的形状是( )。",
+    "options": [
+      "A. ![](images/82b085842c42a79c5f594bba085ba1fd8185203a64c30562c28de6c9b26b4fc1.jpg)",
+      "B. ![](images/1084156e55d43c4a3a96ec9b6550dad6a7cf804c78a2a19a07812f625feb6e85.jpg)",
+      "C. ![](images/ec7cb6a8ccbd71f4eff538f1689d9ed42e24006bf5259c2cac578490cf630c50.jpg)"
+    ],
+    "answer": "C",
+    "solution": "【分析】从前面看是 3 个正方形：下面并排 2 个，上面靠右 1 个.\n【详解】对应选项 C。故答案为:C",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "23-24 二年级上·内蒙古鄂尔多斯·期末"
+  },
+  {
+    "id": "134",
+    "unit": "第五单元 观察物体1",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "![](images/220ad06cab2477214bfbed5d61d6c0803c89eaec75024bba586fa835762bb4bf.jpg)从右面看到的是( )。",
+    "options": [
+      "A. ![](images/2026-03-03%20150052.jpg)",
+      "B. ![](images/2026-03-03%20150104.jpg)",
+      "C. ![](images/2026-03-03%20150116.jpg)",
+      "D. ![](images/2026-03-03%20150135.jpg)"
+    ],
+    "answer": "A",
+    "solution": "【分析】从右面看到的是两个正方形，并且是上下相邻的，即A.\n【详解】由题意分析得：从右面看到的是A。故答案为:A",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "22-23二年级上·浙江嘉兴·期末"
+  },
+  {
+    "id": "135",
+    "unit": "第五单元 观察物体1",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "看到立体图形的一个面是正方形，这个立体图形是( )。",
+    "options": [
+      "A. 长方体",
+      "B. 正方体",
+      "C. 长方体或正方体"
+    ],
+    "answer": "C",
+    "solution": "【分析】长方体是长长方方的，有6个面，特殊情况下有2个面是正方形;正方体是方方正正的,6个面是完全相同的正方形。由此分析选择即可.\n【详解】特殊的长方体如果看到的是相对的2个面，是正方形;一般的长方体看到的是长方形;正方体看到的每个面都是正方形。所以看到立体图形的一个面是正方形，这个立方图形是长方体或正方体。故答案为:C",
+    "knowledge_points": [
+      "立体图形的认识",
+      "从不同位置观察单个物体"
+    ],
+    "source": "22-23二年级上·山东临沂·期末"
+  },
+  {
+    "id": "136",
+    "unit": "第五单元 观察物体1",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "小兔看到的是( ).\n\n![](images/1978bfb029140a432847c17e38473a61c1ab7224bc0e4950ce5cd6498cbafcf2.jpg)",
+    "options": [
+      "A. ![](images/90dcb7e41aca2fa34c1a274d28132abc7dce8bd761ef305edb7df025d16211b5.jpg)",
+      "B. ![](images/e0a2a9705aaf1218bd548083baf8f9ab46e008d312290282e171a32d3f7cc3a5.jpg)",
+      "C. ![](images/0e921d90ab9c43891745ef018f85ca397f2013f7361aee54e1b1c6901e0f0786.jpg)",
+      "D. ![](images/b26d5308fdd6ae23741653f9eab969ff3398e0e2fa16a117e26a5c25cac4d807.jpg)"
+    ],
+    "answer": "C",
+    "solution": "【分析】小兔看到的是小杯子在前面，大杯子再后面，且是并排在一起.\n【详解】由题意分析得：小兔看到的是C。故答案为:C",
+    "knowledge_points": [
+      "从不同位置观察两个物体的相互关系"
+    ],
+    "source": "22-23二年级上·福建龙岩·期末"
+  },
+  {
+    "id": "137",
+    "unit": "第五单元 观察物体1",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "看到的立体图形的一个面是长方形，这个立体图形是下面的( )。",
+    "options": [
+      "A. ![](images/9944f94a3180bd119c63b07a3945e2bacbe8f4035ef2d34cb67afe211b432dde.jpg)",
+      "B. ![](images/c15d49249a9789452a6ea565f0dd6ef9d7676f8f04705e99035cc90927502726.jpg)",
+      "C. ![](images/3a72a32d2e825d1d7b6ae528af7aa16f64c876076f4c3438fdb6555e267b27da.jpg)"
+    ],
+    "answer": "A",
+    "solution": "【分析】球：由1个曲面围成。长方体的任意一个面的对面都与它完全相同(特殊情况下有四个面相同)。正方体的六个面都是一样的，四四方方的。据此解答.\n【详解】A。从前面看到的是一个长方形;B。从各个方向看到的都是圆;C。从前后左右上下看到的都是正方形。看到的立体图形的一个面是长方形，这个立体图形是A。故答案为:A",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "22-23二年级上·河南信阳·期末"
+  },
+  {
+    "id": "138",
+    "unit": "第五单元 观察物体1",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "下图中小林看到的茶壶的样子是( ).\n\n![](images/7b877bb4a3f7a531762a76f718b2a31ede47314802356ac92100641534311ea9.jpg)",
+    "options": [
+      "A. ![](images/0299ef655aab3986f7b24c0d40d12e38db936c1e5f0d551a5710cabf54fe146f.jpg)",
+      "B. ![](images/816af07eb33bbd20a1d70b299d067b1b458e106bbc58a7369caae933f8bc7c1c.jpg)",
+      "C. ![](images/12696a35c43600142a9c0739f85a95f8306a52b6ee09ac45f40f5acc5c727bb1.jpg)"
+    ],
+    "answer": "A",
+    "solution": "【分析】小林在右边，看到壶身，并且中间有把手，据此解答.\n【详解】由分析可得：图中小林看到的茶壶的样子是A。故答案为:A",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "21-22二年级上·浙江湖州·期末"
+  },
+  {
+    "id": "139",
+    "unit": "第五单元 观察物体1",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "俯视下边的图形，你观察到的图形是( ).\n\n![](images/ce7a6bbd05eb0138d8cb0c3edb882d246a0d0dd83e068b87852bbaad692d1d65.jpg)",
+    "options": [
+      "A. ![](images/19e49fc3c4e1034c5f8511a91f0dd660e496b9dccc2daa76386db1a4c5960e61.jpg)",
+      "B. ![](images/e840de4f459bf845dd8a5a4c9f8cc43b3e2421f7ae65b8e6b50ee7fc00954d3b.jpg)",
+      "C. ![](images/49ac6757562b2fbed2c2fbd843a09d9064a1e14a988da264116c01635b4aa5dc.jpg)"
+    ],
+    "answer": "C",
+    "solution": "【分析】俯视这个图形，能看到左边是一个圆，右边是个正方形.\n【详解】俯视这个图形，观察到的图形是C。故答案为:C",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "22-23二年级上·湖南张家界·期末"
+  },
+  {
+    "id": "140",
+    "unit": "第五单元 观察物体1",
+    "question_type": "选择题",
+    "difficulty": 0.94,
+    "question": "从圆柱的正面看到的图形是( ).\n\n![](images/d40f82d2d20155e0f5f91de01709d3e1107d179fc54daf24f9f091fc0e9b41f6.jpg)",
+    "options": [
+      "A. ![](images/6a21861f59ffedc582c1209e92570986ed197eb841ce51925c5a774d1aab65d9.jpg)",
+      "B. ![](images/c7a5c3bee06eb6209f04a6a06c469350433b3c4000355adf656cec66f075eca3.jpg)",
+      "C. ![](images/129a826194369f86cd84a518b5c5ed6f6efe667837bf266e09a49b62b892d5db.jpg)"
+    ],
+    "answer": "A",
+    "solution": "【分析】从正面看能看到圆柱是一个长方形;据此求解即可.\n【详解】从圆柱的正面看到的图形是长方形。故答案为:A",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "22-23二年级上·河南周口·期末"
+  },
+  {
+    "id": "141",
+    "unit": "第五单元 观察物体1",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "下面( )幅图是淘气看到的.\n\n![](images/3d148c93829d1417ccca10df0b5aad4dd7370b5776a13c6aaa0359aa02c1bcc1.jpg)",
+    "options": [
+      "A. ![](images/a23cb530bcb3d03fcda07c89e6a56a784f188293e658c93d131b0c66f7d97851.jpg)",
+      "B. ![](images/581d58d42c5ae16fe1c6146d36e9a8972946203dbbec5768a45b3d210b391e71.jpg)",
+      "C. ![](images/1453e9bc07e61a41d6f79ed27e256f6adad8fcd98d5983b00e3523e353607390.jpg)"
+    ],
+    "answer": "B",
+    "solution": "【分析】观察图形：淘气站在灯具的下面，从下往上看，看到的图形是第二个图形。本题考查从不同的方向观察物体，培养学生的空间想象力和抽象思维能力.\n【详解】A。是淘气从前面看到的图形;B。是淘气从下往上看到的图形;C。是淘气从上往下看到的图形。因为淘气站在灯具的下面，他能看到的图形是从下往上看，所以是B图形。故答案为:B",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "23-24三年级上·广东梅州·期中"
+  },
+  {
+    "id": "142",
+    "unit": "第五单元 观察物体1",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "观察![](images/2026-03-03%20150623.jpg),从( )看到的图形是![](images/2026-03-03%20150633.jpg)。",
+    "options": [
+      "A. 前面",
+      "B. 侧面",
+      "C. 上面"
+    ],
+    "answer": "C",
+    "solution": "【分析】观察图片可知，这是一个圆柱，圆柱是有一个曲面和2个圆组成的，从上面看可以看出是一个圆形。主要考查了从不同位置观察物体，要熟练掌握.\n【详解】根据题意，观察图片，从上面看是一个圆形。故答案为:C",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "22-23二年级上·河北保定·期中"
+  },
+  {
+    "id": "143",
+    "unit": "第五单元 观察物体1",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "如图，美美在门外看到妈妈在扫地，她看到的是( ).\n\n![](images/30984364692f6ed57a3dd18d30cf733598608e85d2baea4507e4da68102af0c7.jpg)",
+    "options": [
+      "A. ![](images/c33ace0a591c4a84ab3efc6260b6a69da38a8bcac92b85e19994f90f05e9c491.jpg)",
+      "B. ![](images/f4203ea78a3f852f6b9f35008a6bb1a223f5d8960c015f0ac4b6a937d093ce09.jpg)",
+      "C. ![](images/844d85d89fadcb1561a6033123bc7497974590332a51901333ea768224cb6061.jpg)"
+    ],
+    "answer": "B",
+    "solution": "【分析】根据图示可知，美美在门外看到妈妈在扫地，她看到的是妈妈的背影，据此解答即可.\n【详解】美美在门外看到妈妈在扫地，她看到的是![](images/955dbaa825421f6937903023f7303342448aa4993adc5511bccdcddd12238f80.jpg)。故答案为:B",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "22-23三年级上·河南驻马店·期中"
+  },
+  {
+    "id": "144",
+    "unit": "第五单元 观察物体1",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "如图，从( )看到的图形一样.\n\n![](images/87fd011101f77c99245e7c54669af18913581b06db4ec31f0ab46d16c84ed74a.jpg)",
+    "options": [
+      "A. 前面和右面",
+      "B. 前面和上面",
+      "C. 前面和左面",
+      "D. 右面和上面"
+    ],
+    "answer": "C",
+    "solution": "【分析】根据题意，图中的图形从前面和左面看到的都是2行，下行2个小正方形，上行1个小正方形居左，据此解答即可。本题是考查作简单图形的三视图，能正确辨认从正面，上面，左面(或右面)观察到的简单几何体的平面图形.\n【详解】图中的图形从前面和左面看到的都是2行，下行2个小正方形，上行1个小正方形居左。故答案为:C",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "22-23四年级上·福建宁德·期中"
+  },
+  {
+    "id": "145",
+    "unit": "第五单元 观察物体1",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "站在不同位置观察下面这个正方体，看到的( ).\n\n![](images/f0994c509b5baa004906d4833972304ea04d6b83cf21198639f13af045348f9f.jpg)",
+    "options": [
+      "A. 都一样",
+      "B. 都不一样",
+      "C. 可能一样",
+      "D. 无法确定"
+    ],
+    "answer": "B",
+    "solution": "【分析】由题意可知，这个正方体有6个面，其中能看见的有3个面，正方体的前面有3个点，正方体的右面有6个点，正方体的上面有5个点，所以站在不同的位置观察这个正方体，看到的点数都是不一样的，据此解答即可。本题考查的是从不同位置观察同一物体，熟练掌握这一知识点是关键.\n【详解】由分析可得：站在不同的位置观察这个正方体，看到的点数都是不一样的。故答案为:B",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "23-24二年级上·全国·课后作业"
+  },
+  {
+    "id": "146",
+    "unit": "第五单元 观察物体1",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "一个正方体的木块，每个面分别写着A,B,C,D,E,F,从不同方向观察结果如图，以下结论正确的是( ).\n\n![](images/b044f73caae4c5c300bfa545e69d10251684dc9b47f55faa18e7709bea401309.jpg)\n\n![](images/f704364557f955780282a04e5beb2ab8778e3bd0d8807b7d03c529e4b50a4a72.jpg)\n\n![](images/db4c5d8ba0fb51a54f7c3f1e1b796cfb658abc679f4eed73a993308bab0945b7.jpg)",
+    "options": [
+      "A. C与D相对",
+      "B. A与E相对",
+      "C. B与F相对",
+      "D. E与F相对"
+    ],
+    "answer": "A",
+    "solution": "【分析】从图中可知与C相邻的是E,F,B,A,可判断出C与D相对;与E相邻的是F,C,A,可知与E相对的可能为B和D,而D与C相对，所以和E相对的是B,剩下的是A和F相对。由此选择即可。本题主要考查了正方体相对两个面上的文字，根据相邻面的字母判断出相对面是解题的关键.\n【详解】A.C与D相对：说法正确;B.A与E相对：说法错误;C.B与F相对：说法错误;D.E与F相对：说法错误。结论正确的是C与D相对。故答案为:A",
+    "knowledge_points": [
+      "推理问题",
+      "从不同位置观察单个物体"
+    ],
+    "source": "23-24二年级上·全国·课后作业"
+  },
+  {
+    "id": "147",
+    "unit": "第五单元 观察物体1",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "旗杆在( )时影子最短。",
+    "options": [
+      "A. 早晨",
+      "B. 中午",
+      "C. 傍晚",
+      "D. 无法确定"
+    ],
+    "answer": "B",
+    "solution": "【分析】一天中，阳光下物体的影子会随着太阳位置的高低和方向的改变而改变。太阳位置最高时，物体的影子最短，太阳位置最低时，物体的影子最长。中午的时候太阳的位置最高，影子最短，依此选择。本题主要考查从不同方向观察物体，关键掌握影子变化的规律.\n【详解】由分析可知，旗杆在中午时影子最短。故答案为:B",
+    "knowledge_points": [
+      "观察的范围(视野与盲区)"
+    ],
+    "source": "23-24二年级上·全国·课后作业"
+  },
+  {
+    "id": "148",
+    "unit": "第五单元 观察物体1",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "从①号位置(见下图)拍摄到的图是( ).\n\n![](images/a29a822bd110f512b0b4f81ef902627fddf6f643be6e5147be981f74717dba9d.jpg)",
+    "options": [
+      "A. ![](images/e113dbc9396623ff9ba47c71213d7100962226a70b3d44c36e852fb9a5d0d547.jpg)",
+      "B. ![](images/d9b2ea7b930fd182865931837ffb01103f94c1144001f0422d64be313f25fdef.jpg)",
+      "C. ![](images/15ec61ed5df49b42c7b918a971c1824fc2fa414dd2802da7bc105228574da6b0.jpg)",
+      "D. ![](images/aa7147e64fe93d5e127e6f4c2d46cbda34b3cda197836c7b98149b5e9bbc895d.jpg)"
+    ],
+    "answer": "C",
+    "solution": "【分析】从①号位置观察，也就是从物体的左边观察，小正方体在前，长方体在后，正方体遮挡不住长方体，长方体漏出一部分，看到的是两个正方形上下堆叠在一起，据此选择即可。本题考查了从不同方向观察物体，要考虑两个物体的相对位置关系.\n【详解】根据分析可得，从①号位置拍摄到的图是C。故答案为:C",
+    "knowledge_points": [
+      "从不同位置观察两个物体的相互关系",
+      "判断照片的拍摄位置"
+    ],
+    "source": "23-24二年级上·全国·课后作业"
+  },
+  {
+    "id": "149",
+    "unit": "第五单元 观察物体1",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "从上面观察，看到的图是( )。",
+    "options": [
+      "A. ![](images/3337d9d14d4c033eae04b6b7e2c6f5bc51e76c93153bf51a0119981c823416d5.jpg)",
+      "B. ![](images/978fe88ea36c5023b14ea0dcfeb18c5c2ed7c3e6dd58c8b0ebb17923efd2cf41.jpg)",
+      "C. ![](images/c7649b24ee186d21e13364401b9ead99f2e9ab2dca770c15d7b1f66e49de829a.jpg)"
+    ],
+    "answer": "B",
+    "solution": "【分析】从上面观察这两个图形，看到两个圆形。从正面观察，看到左边是1个圆形，右边是一个长方形。从右面看到1个长方形，圆形被长方形遮挡住了。本题考查了从不同的方向观察物体，需要学生有较强的空间想象和推理能力.\n【详解】A。从正面看到;B。从上面看到;C。从右面看到。故答案为:B",
+    "knowledge_points": [
+      "从不同位置观察两个物体的相互关系"
+    ],
+    "source": "20-21三年级上·辽宁·期中"
+  },
+  {
+    "id": "150",
+    "unit": "第五单元 观察物体1",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面图( )是小明看到的.\n\n![](images/07434f57fae0f0cc51ad960c1b4e4d30aac144d07fc997cdc70c2c7e250414c8.jpg)",
+    "options": [
+      "A. ![](images/8a734d22ea2cd015d5e214419c46caf362a66cb3e463794d913fe5a1a502a7f8.jpg)",
+      "B. ![](images/3f4ef563812e203c226675f1544a95ebda5d2691077cdece251999b03565e840.jpg)",
+      "C. ![](images/1fb7b5520e91b6da4901924dc13123efcfcdea198ca3f74343877530cebfafb0.jpg)"
+    ],
+    "answer": "B",
+    "solution": "【分析】由题意可知，小明站在茶壶的侧面，看到的茶壶把在他的右边，看到的茶壶嘴在他的左边，据此解答即可熟练掌握从不同位置观察同一物体是解决此题的关键.\n【详解】由分析可得：第二幅图是小明看到的。故答案为:B",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "22-23二年级上·湖北黄石·期末"
+  },
+  {
+    "id": "151",
+    "unit": "第五单元 观察物体1",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面是小明一次立定跳远的照片，按拍摄时间的先后顺序排列正确的是().\n\n![](images/ea3ff84554167c8cef325cf54789a80ac457d63ffd46663387dd4dfb6e41a847.jpg)\n\n![](images/579759f1a37a923fd185915d3575cfa15e39e219e481a3c61dfd672421597748.jpg)\n\n![](images/7eb6a8d425f97d526db3f5152c492e02644312bc4267e6ca5c6b0764820e9e64.jpg)",
+    "options": [
+      "A. ①②③",
+      "B. ①③②",
+      "C. ②③①"
+    ],
+    "answer": "C",
+    "solution": "【分析】立定跳远先准备起跳，接下去在空中跳跃，最后落地，据此解答即可。本题的解答关键是要明确立定跳远的步骤.\n【详解】下面是小明一次立定跳远的照片，按拍摄时间的先后顺序排列正确的是②③①。故答案为:C",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "22-23二年级上·贵州铜仁·期末"
+  },
+  {
+    "id": "152",
+    "unit": "第五单元 观察物体1",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "观察下图，看到一个面是正方形，这个立体图形可能是().\n\n![](images/25a441621abe44997084d7b443a8f134f98db1527078b70faf81d2f4d8020d75.jpg)",
+    "options": [
+      "A. 长方体",
+      "B. 正方体",
+      "C. 以上答案都对"
+    ],
+    "answer": "C",
+    "solution": "【分析】长方体有6个面，有三组相对的面完全相同，一般情况下六个面都是长方形，特殊情况时有两个面是正方形，其它四个面都是长方形;正方体有6个面,6个面都是正方形，据此解答。此题考查了对长方体，正方体的特征的掌握，结合题意解答即可.\n【详解】根据题干分析可得，看到的立体图形的一个面是正方形，这个立体图形可能是正方体，也可能是长方体。故答案为:C",
+    "knowledge_points": [
+      "长方体的认识及特征",
+      "正方体的特征"
+    ],
+    "source": "21-22二年级下·贵州铜仁·期末"
+  },
+  {
+    "id": "153",
+    "unit": "第五单元 观察物体1",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下图中，鸟从上面往下看到().\n\n![](images/b3a7292d1afb8e05e3795b4f1ff8ac0f376307dd4d9a0bbb3ec5a9058cc3444f.jpg)",
+    "options": [
+      "A. ![](images/7c669f2263c5245e1f76fdd7e88845b32a92f8f569d5a8fe250d71bc6f56a477.jpg)",
+      "B. ![](images/3fca3e7651b24b87596c33eaf164cadf39bfb914d7c21c1201ef16bb65d5d099.jpg)",
+      "C. ![](images/2026-03-03%20150933.jpg)"
+    ],
+    "answer": "B",
+    "solution": "【分析】根据图意，鸟从上面往下看到的是最上面的一行小正方形即B,由此解答。此题考查了从不同方向观察物体和几何体，注意培养学生的空间想象力和抽象思维能力.\n【详解】由分析可知：鸟从上面往下看到的是B。故答案为:B",
+    "knowledge_points": [
+      "物体三视图的认识"
+    ],
+    "source": "22-23二年级上·全国·期末"
+  },
+  {
+    "id": "154",
+    "unit": "第五单元 观察物体1",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "丁丁用4个同样的小正方体搭成了一个立体图形，从前面看是\n\n![](images/fb74870c07569eae9ccfed16ca5081f6692fd58e7043d6f2a324e6bd3bd5b747.jpg)\n\n能是怎么搭的。( )。",
+    "options": [
+      "A. ![](images/373e0b2d6781056d2f3618ea0181ea3ad553a3699dcdfd9889d3c094ae8ab75d.jpg)",
+      "B. ![](images/21a9a2e8c0be1eeafb5ec9a5b6051ba6b27f7a8446b98fae619bdd682a9864c6.jpg)",
+      "C. ![](images/c98cc1d8982d0533eddf202e8e9f07b58049d07905f060bba36539504a760462.jpg)"
+    ],
+    "answer": "C",
+    "solution": "【分析】本题考查从不同位置观察立体图形，核心是判断用 4 个同样的小正方体搭成的立体图形，从前面看是否符合给定的视图。已知条件：用 4 个同样的小正方体搭成，且从前面看的形状为底层 2 个小正方形，上层 1 个小正方形在左侧。需要逐一分析每个选项的小正方体数量和正视图形状.\n【详解】选项 A:由 3 个小正方体组成，不满足\"4 个小正方体\"的条件，排除。选项 B:从前面看，底层有 3 个小正方形，上层有 1 个小正方形在中间，与题目要求的视图不符，排除。选项 C:由 4 个小正方体组成，从前面看，底层有 2 个小正方形，上层有 1 个小正方形在左侧，与题目要求的视图完全一致，符合条件。所以，正确答案是C。",
+    "knowledge_points": [
+      "立体图形的切拼",
+      "从不同位置观察单个物体"
+    ],
+    "source": "21-22二年级上·湖北襄阳·期末"
+  },
+  {
+    "id": "155",
+    "unit": "第五单元 观察物体1",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "小明从某一方向观察到的立体图形的一个面是○,这个立体图形可能是( )。",
+    "options": [
+      "A. 正方体",
+      "B. 圆柱",
+      "C. 长方体"
+    ],
+    "answer": "B",
+    "solution": "【分析】本题考查从不同方向观察立体图形。观察到的面是圆形，说明这个立体图形有可能某个面是圆形。正方体的每个面都是正方形，不可能看到圆;圆柱从侧面看是长方形，但从上面或下面看是圆形;长方体的每个面都是长方形或正方形，不可能看到圆。因此，这个立体图形可能是圆柱。 \n【详解】正方体的面都是正方形，不可能看到圆;圆柱从上面或下面看是圆形;长方体的面都是长方形或正方形，不可能看到圆。所以这个立体图形可能是圆柱。故答案为:B",
+    "knowledge_points": [
+      "立体图形的认识",
+      "从不同位置观察单个物体"
+    ],
+    "source": "21-22二年级上·湖北孝感·期末"
+  },
+  {
+    "id": "156",
+    "unit": "第五单元 观察物体1",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "图中，小猫看到的形状是( ).\n\n![](images/9d3fe8ff94b9274aaad73307199f2560f4ca2f915c15bcfe027c1b27882a49a6.jpg)",
+    "options": [
+      "A. ![](images/642c13f5c7f0c54ac9d328477ec62f6efe54c362bc632d0c29d456123bf170cc.jpg)",
+      "B. ![](images/faa83e84fab9d29a09ad6bc8a481a3ef1dd55e0298f62779da41725d198dc32f.jpg)",
+      "C. ![](images/5296f6df7952eb186c2922795c4bcf09135c590a71b44d6d05835e87f68f4b60.jpg)",
+      "D. ![](images/6f4417655ab70590e55fb4f07f9cc3692eba3c64cae84dd0a4ec6e9abadc852f.jpg)"
+    ],
+    "answer": "A",
+    "solution": "【分析】本题考查从不同位置观察物体。小猫在物体的侧面观察，看到的形状应与物体的侧面形状一致。根据常见的图形组合，需要判断小猫从侧面看到的是哪个选项的图形。 \n【详解】小猫从侧面观察物体，看到的形状应该是物体侧面的轮廓。根据图中物体的摆放位置，小猫看到的形状与选项A相符。故答案为:A",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "21-22二年级上·山西吕梁·期末"
+  },
+  {
+    "id": "157",
+    "unit": "第五单元 观察物体1",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "○是从\n\n![](images/55311e048ec94a19538b9c287410c8d41353c81c759de7ce3f785d12c8357c00.jpg)\n\n的( )看到的。",
+    "options": [
+      "A. 上面",
+      "B. 正面",
+      "C. 左面"
+    ],
+    "answer": "C",
+    "solution": "【分析】图中物体是一个圆柱体，在判断物体的形状是从哪个位置观察到的时，应站在观察者的角度，从不同方向观察所给的物体，将观察到的形状与所给的形状相比较，再作出判断.\n【详解】A。这个圆柱体从上面看到的是一个圆形;B。这个圆柱体从正面看到的是一个长方形;C。这个圆柱体从左面看到的是一个长方形。故答案为:A",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "21-22二年级上·河南漯河·期末"
+  },
+  {
+    "id": "158",
+    "unit": "第五单元 观察物体1",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "![](images/2026-03-03%20192813.jpg)是从( )立体图形上面看到的形状。",
+    "options": [
+      "A. ![](images/81d8331b8244ebe9501afd03499f8124784ba7d12e4d12505588658a88e01b6a.jpg)",
+      "B. ![](images/167499439ea16483d0c03cc747b22ec0b8e4638538552ba2671de1f08b3d3226.jpg)",
+      "C. ![](images/ea39de7e251ec917f9d92fab1798f61305d087ca72598ee1127d26063ff19a85.jpg)"
+    ],
+    "answer": "C",
+    "solution": "【分析】本题考查从上面观察立体图形。从上面看到的形状是图形中给出的平面图，需要判断这个平面图对应哪个立体图形的上面视图。根据常见的立体图形的上面视图特征进行分析.\n【详解】从上面看到的形状是圆形，说明这个立体图形的上面是圆形。圆柱从上面看是圆形，长方体从上面看是长方形。根据选项,C 选项是圆柱，从上面看是圆形。故答案为:C",
+    "knowledge_points": [
+      "物体三视图的认识"
+    ],
+    "source": "21-22二年级上·青海西宁·期末"
+  },
+  {
+    "id": "159",
+    "unit": "第五单元 观察物体1",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "无论从哪个位置看，看到的形状都一样的是图( )。",
+    "options": [
+      "A. ![](images/158e6e9d2290ac71528c3b44418f38a4946d39fc31b099afbb20efd9ad83db1f.jpg)",
+      "B. ![](images/23d7f8f186e69b654624bff1132535a0039ed28a4699092178610d1767ea9220.jpg)",
+      "C. ![](images/20f156f78d41ab03764226d53f98adf995bc8ed031f26d5e0143616389f010a7.jpg)"
+    ],
+    "answer": "C",
+    "solution": "【分析】找到从物体各个面看得到的图形，即可进行判断。注意球体是一个特殊的几何体，无论从哪个角度观察得到的图形都是圆形.\n【详解】由分析可得：因为球体无论从哪个角度观察，看到的平面图形都是圆形。故答案为:C",
+    "knowledge_points": [
+      "立体图形的认识",
+      "从不同位置观察单个物体"
+    ],
+    "source": "21-22二年级上·青海西宁·期末"
+  },
+  {
+    "id": "160",
+    "unit": "第五单元 观察物体1",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "从不同角度观察下面3个物体，可以看到长方形的物体有( )个.\n\n![](images/2bf91e79476cf9798b8e4a5dfe7ffaddb0be0ef9ee0e4245fa2e8514f4c87943.jpg)\n\n![](images/6ffde19d2034190f2f26c5e008e14b545d9d83498d586a2bf1f6c224d8b68adb.jpg)\n\n![](images/2f9a3bf22e7a67195904711dcd1cada65c7df88cc727c8ce4906a0d122b5e56c.jpg)",
+    "options": [
+      "A. 1",
+      "B. 2",
+      "C. 3"
+    ],
+    "answer": "C",
+    "solution": "【分析】从前，后或上，左，右面观察长方体可以看到长方形，从侧面观察圆柱可以看到长方形，从上，左，右面观察第三个图形可以看到长方形.\n【详解】由分析可知：从不同角度观察下面3个物体，都可以看到长方形。故答案为:C",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "20-21二年级上·广西百色·期末"
+  },
+  {
+    "id": "161",
+    "unit": "第五单元 观察物体1",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "芳芳看到的茶杯是什么样子的。( ).\n\n![](images/2026-03-03%20193049.jpg)\n\n![](images/e8c681a2f9e831fe8e8f606a0b00bc857d33fa29b2ea21a53e25c1ada098c59b.jpg)",
+    "options": [
+      "A. ![](images/6c161271704ef067f228d9c0cb0878e4c363d90c473cf1e6e1d48adc94c0289b.jpg)",
+      "B. ![](images/6df979bc66396691aae9c0fa50d4661c3ae25217a672cd204d018d325c6f4259.jpg)",
+      "C. ![](images/b1b4b92fea79aebb7dec178eef9cc946d307d84ac5446f30bf4987cb7d0b5b3c.jpg)"
+    ],
+    "answer": "B",
+    "solution": "【分析】根据芳芳观察茶杯的方向可知：芳芳从正面看这个茶杯，左手边是把手，右手边是壶嘴，据此选择即可。掌握从不同方向观察到物体的特征是解答本题的关键.\n【详解】由分析可知：芳芳看到的茶杯是B。故答案为:B",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "21-22二年级上·广西钦州·期末"
+  },
+  {
+    "id": "162",
+    "unit": "第五单元 观察物体1",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "观察下面图形，看不到长方形的是( )。",
+    "options": [
+      "A. ![](images/5d080672211bc0bae869877cac1b5c835590fe5d2014fc8f03d98387765b335e.jpg)",
+      "B. ![](images/5f0dcf30f4abf39e925d5ba6c9642e64c2951f7b150768519b83fae4febb893e.jpg)",
+      "C. ![](images/1d9fc0729016ee7fd5313cc0d7646375549e3151fb9515edb6d0acd9914b10bb.jpg)"
+    ],
+    "answer": "B",
+    "solution": "【分析】本题考查从不同位置观察立体图形，核心是判断哪个立体图形在观察时看不到长方形。需要逐一分析每个选项的立体图形特征.\n【详解】选项 A:长方体有 6 个面，其中至少有 4 个面是长方形，所以从不同方向观察时，一定能看到长方形。选项 B:球无论从哪个方向观察，看到的都是圆形，看不到长方形，符合题目要求。选项 C:圆柱的侧面是曲面，当从正面或侧面观察时，看到的是长方形。所以，正确答案是B。",
+    "knowledge_points": [
+      "长方形的概念及特点",
+      "从不同位置观察单个物体"
+    ],
+    "source": "20-21二年级上·湖北襄阳·期末"
+  },
+  {
+    "id": "163",
+    "unit": "第五单元 观察物体1",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "![](images/2038a22da5ed5cc2240849691336baf3a461a4928b88fb5294687da17b04c024.jpg)从正面看到的是图( ),从右面看到的是图( ),从上面看到的是图( ).\n\n①\n\n![](images/0024cd12ae9243dc3ba9d0232270bc188d435d5b1b1337696f3b8053b59dc150.jpg)\n\n②\n\n![](images/28837b75ee47cca0e7d18fd6960717a073f4d322e44ca805c2a7850b80c81e55.jpg)\n\n③\n\n![](images/848982f5600ecf17eff5655b26e7f56843caaf25246710309afef6d49ba2ed8a.jpg)\n\n④\n\n![](images/9b6945fefbb21be2656176c0cdfa0010a73afe7676f28818bad5072927752ed8.jpg)",
+    "options": [
+      "A. ①③②",
+      "B. ②③④",
+      "C. ①③④"
+    ],
+    "answer": "A",
+    "solution": "【分析】本题考查物体三视图的认识，核心是分别确定给定立体图形从正面，右面，上面观察到的形状，再匹配对应序号并选择正确选项。需要结合立体图形的结构，逐一分析不同视角的视图特征.\n【详解】首先分析立体图形的结构：该立体图形底层有 3 个小正方体横向排列，上层有 1 个小正方体在最左侧的小正方体上方。从正面看：底层能看到 3 个横向排列的小正方形，上层能看到 1 个小正方形在最左侧，对应图①。从右面看：只能看到上下 2 个叠放的小正方形，对应图③。 从上面看：只能看到 3 个横向排列的小正方形，对应图②。因此从正面，右面，上面看到的图形依次是①,③,②,对应选项 A。所以，正确答案是 A.",
+    "knowledge_points": [
+      "物体三视图的认识"
+    ],
+    "source": "20-21二年级上·江西吉安·期末"
+  },
+  {
+    "id": "164",
+    "unit": "第五单元 观察物体1",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "从正面看是![](images/2026-03-03%20193405.jpg)的是( )。",
+    "options": [
+      "A. ![](images/3067d022df3e6e6f10e156daa36081c7681d76299106fc11b2bca74ba4b1434b.jpg)",
+      "B. ![](images/742f81f8b536b498c2d4f15f53de639f27e621407c71741739b487c8ce4388c8.jpg)",
+      "C. ![](images/6886e489958f274c476f34e8bec8a6cd90c0c060ae6e2ec562018f924d528054.jpg)"
+    ],
+    "answer": "C",
+    "solution": "【分析】本题考查物体三视图的认识，核心是判断哪个立体图形从正面观察时，呈现出三个横向排列的小正方形的形状，需要逐一分析每个选项的正视图特征.\n【详解】 选项 A:从正面看，呈现的是三个纵向叠放的小正方形，与题目要求的视图不符，排除。选项 B:从正面看，底层有两个横向排列的小正方形，上层有一个小正方形在右侧，与题目要求的视图不符，排除。选项 C:从正面看，呈现的是三个横向排列的小正方形，与题目要求的视图完全一致，符合条件。所以，正确答案是 C.",
+    "knowledge_points": [
+      "物体三视图的认识"
+    ],
+    "source": "21-22二年级上·江西鹰潭·期末"
+  },
+  {
+    "id": "165",
+    "unit": "第五单元 观察物体1",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "小明看到的立体图形的一个面是正方形，这个立体图形( )。",
+    "options": [
+      "A. 一定是正方体",
+      "B. 一定是长方体",
+      "C. 可能是正方体，也可能是长方体"
+    ],
+    "answer": "C",
+    "solution": "【分析】本题考查从不同方向观察立体图形。看到一个面是正方形，说明这个立体图形有可能某个面是正方形。正方体的每个面都是正方形，所以可能是正方体;长方体也可能有正方形面(如特殊的长方体，有两个相对的面是正方形),所以也可能是长方体。因此，这个立体图形可能是正方体，也可能是长方体。 \n【详解】正方体的每个面都是正方形，所以可能是正方体;长方体也可能有正方形面(例如有两个相对的面是正方形的长方体),所以也可能是长方体。因此，这个立体图形可能是正方体，也可能是长方体。故答案为:C",
+    "knowledge_points": [
+      "立体图形的认识",
+      "从不同位置观察单个物体"
+    ],
+    "source": "20-21二年级上·辽宁抚顺·期末"
+  },
+  {
+    "id": "166",
+    "unit": "第五单元 观察物体1",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "观察下面的茶壶，写出下面4幅图分别是从哪个方向看到的.\n\n![](images/42941ecb2229ae4e3ee4ed1b8184b5298e185dcb74da654ebdfb57d46c16da87.jpg)\n\n( )面;( )面;( )面;( )面",
+    "options": [],
+    "answer": "右;前;左;后",
+    "solution": "【分析】第一图形是从右面看到的，第二个图形是从前面看到的，第三个图形是从左面看到的，第四个图形是从后面看到的，据此解答即可.\n【详解】![](images/8aff19241940f629b495e81ae43ce785b89825186b9b0ef9a9d3958f8fe32a43.jpg)\n![](images/7630dd6ebccc5761b841ff6912ee91ae1df3170a13325db5ae8e2a15d5467c21.jpg)\n\n右面\n\n![](images/af7d257a0e64a852b509ad3a623d60fb187b34b078de41cb5dd113cc75bb76ea.jpg)\n\n前面\n\n![](images/cb584b2b6c7465950ff5ab0517e00a83d63c5162fe0739185999e36f49af96b0.jpg)\n\n左面\n\n![](images/d6446ff20c090cf37d4f3d5503547407878ed16ca9e334f58568776ad408908d.jpg)\n\n后面",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "23-24四年级下·河北唐山·期中"
+  },
+  {
+    "id": "167",
+    "unit": "第五单元 观察物体1",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "从上面看是圆形，从前面和左边看是长方形，这个物体是( ),从哪个方向看都是圆形，这个物体是( )。",
+    "options": [],
+    "answer": "圆柱;球",
+    "solution": "【分析】![](images/36bd09c8e7f8cd743d197e5c2b86961c15ba8c35effeb309b524cdbbe848f7b0.jpg)\n\n长方体\n\n![](images/89967290f3d267b7459c5b0e1e1060f630d4b7fdd3ad4764a09a601b506de651.jpg)\n\n正方体\n\n![](images/98ddc3ec42f4a13c82836878498e9cac4d3d5d92f991e3b9b1ab8f08089e61e7.jpg)\n\n圆柱\n\n![](images/55bb50ea32bb9b3a552d6ee41cea2b17283fbbf8b45399d331d991ff964f556b.jpg)\n\n球\n观察上图可知：圆柱从上面看是圆形，从前后左右看都是长方形。球从哪个方向看都是圆形.\n【详解】从上面看是圆形，从前面和左边看是长方形，这个物体是圆柱，从哪个方向看都是圆形，这个物体是球。",
+    "knowledge_points": [
+      "物体三视图的认识"
+    ],
+    "source": "23-24二年级上·山东济宁·期末"
+  },
+  {
+    "id": "168",
+    "unit": "第五单元 观察物体1",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "观察立体图形时，乐乐看到了一个正方形，这个立体图形可能是( ),也可能是( )。",
+    "options": [],
+    "answer": "正方体;长方体",
+    "solution": "【分析】![](images/7603a01f0646d15984d9353da171ee074cd6f8ec4fca1bff1d6fa9f24218d5d1.jpg)\n\n由图片可知，观察正方体和长方体时可能看到正方形.\n【详解】观察立体图形时，乐乐看到了一个正方形，这个立体图形可能是正方体，也可能是长方体。",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "23-24二年级上·河南南阳·期末"
+  },
+  {
+    "id": "169",
+    "unit": "第五单元 观察物体1",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "从物体的哪面看到的，填一填.\n\n![](images/2ef142922037ab2fcb74a252e8e16bd0e28a1be28f1a654e67b765227b23313e.jpg)\n\n![](images/1e033906cc8c966a5f8f2a1321fc830dceee96d80e3275fffb24d7c8c6c8b8ad.jpg)\n\n![](images/027386a986ee8dda18c7e6240fe84e2cfdde18e55b365c5c61f1a96ec05e6e06.jpg)\n\n![](images/355cb84bb8be3b92995f237d37fd43da17f65688730f173006a39adccd55866d.jpg)\n\n( )面;( )面;( )面",
+    "options": [],
+    "answer": "上;右;前",
+    "solution": "【分析】观察立体图形可知，这个图形是由1个正方体和1个圆柱组成。从上面能看到1个正方形和1个长方形;从前面能看到1个正方形和1个圆;从右面看，圆柱把正方体挡住了，所以只能看到1个长方形。据此解答.\n【详解】根据分析可知:![](images/4f92462460c24d0823c90a0547f8a0d31a56832819188a0a492e7113a2c034c1.jpg)这是从上面看到的。![](images/8b9a098bbe556e5c778dcab743192686195aa5b8f0599dba90eb2be4d5f61f83.jpg)这是从右面看到的。![](images/437e86f75c06c7faa123585a170289b63228a744402bc8138567796c0daf6b95.jpg)这是从前面看到的。",
+    "knowledge_points": [
+      "从不同位置观察两个物体的相互关系"
+    ],
+    "source": "23-24二年级上·山东菏泽·期末"
+  },
+  {
+    "id": "170",
+    "unit": "第五单元 观察物体1",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "下面右边的三幅图分别是在哪个位置看到的。把相应的序号填在( )里.\n\n![](images/d4162a91209e44af735b59df36bc345b1ab354897daf5be16998f17c256ded5f.jpg)\n\n![](images/15b5b5cc803c1eb7b05c77115181ef112af6e7de14013ef5ac5eb609811a03f6.jpg)\n\n![](images/c65b6ce59172d71a7a5ecf517dfdcf69c2c307959ff2b95dca15e82c19087ba5.jpg)\n\n![](images/8533aa1c7c21cc50cb36d1a28ca5f63c8630c4ae8ce7a0dc9525d9c40e1714f9.jpg)\n\n( );( );( )",
+    "options": [],
+    "answer": "②;③;①",
+    "solution": "【分析】从①的位置看到两行小正方形，下面3个，上面1个，居中;从②的位置看到一行3个小正方形;从③的位置看到一列2个小正方形.\n【详解】②;③;①。",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "23-24二年级上·吉林四平·期末"
+  },
+  {
+    "id": "171",
+    "unit": "第五单元 观察物体1",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "一个立体图形不管从哪个方向看都是圆，这个立体图形是( )。",
+    "options": [],
+    "answer": "球",
+    "solution": "【分析】根据对立体图形的认识可知，球表面是曲面，从任何方向看都是圆形，由此解答.\n【详解】一个立体图形不管从哪个方向看都是圆，这个立体图形是球。",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "22-23二年级上·河南·阶段练习"
+  },
+  {
+    "id": "172",
+    "unit": "第五单元 观察物体1",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "下面图分别是谁看到的。把序号填在相应的括号里.\n\n![](images/d46765e163b3718863e636bd4c881a2a83600389ae64ace51a1ab1950c58b28c.jpg)\n\n![](images/8033f3af9e3c4dbf1d987704a88e1efba0ebb5636ddc13c805831422caefec20.jpg)\n\n![](images/0b975fec67353314cbfc45a43881608d77e91a106393fd1e4d9605bad1b0139b.jpg)\n\n![](images/d12aa8bbdb29d47b9f0c4a05235a40c3edf108e292a5a1ec4f0161232a48c06d.jpg)\n\n小狗看到的是图( )。小猴看到的是图( )。小猫看到的是图( )。",
+    "options": [],
+    "answer": "③;②;①",
+    "solution": "【分析】图中小猴站在房屋的前面，看到的是房屋有门的面;小猫站在侧面，看到的是有圆形窗户烟囱在右侧的面;小狗站在另一侧，看到的是有圆形窗户烟囱在左侧的一面。由此解答.\n【详解】\n\n![](images/157920ec054db1b386c1cef737188f8285a0f4048059e190dc4c3e64c1652c05.jpg)\n\n![](images/b0bbcef7b45197cd4117ff030e8033346afca0775ede33d4d5e1c00974e81b29.jpg)\n\n![](images/1c64cc95920280313f2dbea28c79fb278b7e3a4af42f17c7462c45386c836206.jpg)\n\n![](images/16948e60524bcc5c43a73dea1c170ea86eed1973d232ac3cf55e61543b6f2c7b.jpg)\n\n小狗看到的是图③。小猴看到的是图②。小猫看到的是图①。",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "22-23二年级上·四川乐山·期末"
+  },
+  {
+    "id": "173",
+    "unit": "第五单元 观察物体1",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "观察( )和( )时，从前面，侧面和上面所看到的形状都是相同的。",
+    "options": [],
+    "answer": "正方体;球体",
+    "solution": "【分析】根据题意可知：从前面，侧面和上面所看到的形状都是相同的，则说明该物体是有同样的图形组成的。由此可知是正方体，以及球体。主要考查了从不同位置观察单个物体，要熟练掌握.\n【详解】观察(正方体)和(球体)时，从前面，侧面和上面所看到的形状都是相同的。",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "22-23二年级上·河北保定·期中"
+  },
+  {
+    "id": "174",
+    "unit": "第五单元 观察物体1",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "![](images/2026-03-03%20194134.jpg)\n\n(1)( )从前面看到的形状相同,( )从前面看到的形状也相同.\n\n(2)①和⑤从( )面和( )面看到的形状一样。",
+    "options": [],
+    "answer": "②,③;⑤,⑥;上;右",
+    "solution": "【分析】根据从不同方向观察物体和几何体的方法，分别从前面，上面和左面观察各个图形，然后结合题意分析解答即可。此题考查了从不同方向观察物体和几何体，关键是确定观察方向.\n【详解】(1)②和③从前面看到的形状是相同的，都能看到一行3个正方形;⑤和⑥从前面看到的形状也相同，能看到4个正方形，分两层，上层1个，下层3个，左齐。(2)①和⑤从上面和右面看到的形状一样。从上面能看到4个正方形，分两层，上层3个，下层1个，右齐;从右面看到3个正方形，分两层，下层2个，上层1个，右齐。",
+    "knowledge_points": [
+      "物体三视图的认识"
+    ],
+    "source": "22-23四年级上·河南洛阳·期中"
+  },
+  {
+    "id": "175",
+    "unit": "第五单元 观察物体1",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "下面三幅图分别是谁看到的。把序号填在括号里.\n\n![](images/ff864af18b21245f7fecf8574e100d69fc21b0537d2ef2382087363ddf5e6c05.jpg)\n\n![](images/01359b81189e6110a28dd3b6bde94b336b7dd605b17c47d72d76958405f41a45.jpg)\n\n![](images/496f6e6467f97daaa03bf5808589b535c1032286166d59eafdf26caabed6aafa.jpg)\n\n![](images/b17febddb4aee48701893b8f4dd1d812834178017315faa1f08cfb273b64deee.jpg)\n\n( );( );( )",
+    "options": [],
+    "answer": "②;③;①",
+    "solution": "【分析】据图示,①看到的是电脑的前面，显示屏在左边，主机在右边。②看到的是电脑后面，显示屏在右边，主机在左边。③看到的是主机侧面，据此解答即可。本题考查了从不同位置观察两个物体的相互关系，需要学生有较强的空间想象和推理能力.\n【详解】②;③;①。",
+    "knowledge_points": [
+      "从不同位置观察两个物体的相互关系"
+    ],
+    "source": "22-23三年级上·河南驻马店·期中"
+  },
+  {
+    "id": "176",
+    "unit": "第五单元 观察物体1",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "从不同方向观察长方体，最多能看到()个相邻的面。",
+    "options": [],
+    "answer": "3",
+    "solution": "【分析】从不同方向观察长方体，当眼睛处于A点时，可以看到3个相邻的面;当眼睛处于B点时，可以看到1个面;当眼睛处于C点时，可以看到2个相邻的面;依此填空。本题考查从不同方向观察物体和几何体，培养学生观察能力和分析判断能力.\n\n![](images/74ec36ea7d402c4e56a29be86597f662c88d9c5296ff016612a9a0ba7f9e25e0.jpg)\n\n【详解】根据分析可知，从不同方向观察长方体，最多能看到3个相邻的面。",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "22-23三年级上·广东梅州·期末"
+  },
+  {
+    "id": "177",
+    "unit": "第五单元 观察物体1",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "看一看，填一填。(把字母填在括号里。)\n\n![](images/cf9d81d976778f46a43129cb329cea77b0e0d5ec3e95cce7aab5707c573bdf66.jpg)\n\n![](images/97a88af9020387d608bf5050a7a5f51d7dfb2fee9a86aa2beb1f057fa54f61b9.jpg)\n\n![](images/c4cb214ad55d00680625091e6e742dda2c9c2ee30420081d45209d8710e044a7.jpg)\n\n![](images/5eb610607e1b1dcaaac9456935fd7b012ac8dc6a954fcfd71535cf5142903d47.jpg)\n\n如图所示，娟娟看到的是图(),明明看到的是图(),亮亮看到的是图()。",
+    "options": [],
+    "answer": "B;A;C",
+    "solution": "【分析】亮亮站在汽车的侧面，看到汽车车头朝左;明明看到车头朝前;娟娟看到汽车的车尾，依此填空。本题是考查从不同方向观察物体，主要是培养学生的观察能力.\n【详解】根据分析可知，娟娟看到的是图B,明明看到的是图A,亮亮看到的是图C",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "21-22三年级上·辽宁沈阳·期末"
+  },
+  {
+    "id": "178",
+    "unit": "第五单元 观察物体1",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "观察立体图形时，小明看到了一个长方形，这个立体图形可能是(),也可能是()。",
+    "options": [],
+    "answer": "长方体;圆柱",
+    "solution": "【分析】由题意可知，长方体有6个面，每一个面都是长方形，也有2个对立面是正方形，其余4个面是长方形的特殊情况，小明在观察的立体图形中，看到了长方形，那么这个图形可能是长方体;圆柱是直直的，上面与下面是圆，如果从侧面观察，看到的就是一个长方形，那么小明看到的图形也有可能是圆柱，据此解答即可。熟练掌握立体图形的特征是解决此题的关键.\n【详解】由分析可得：观察立体图形时，小明看到了一个长方形，这个立体图形可能是(长方体),也可能是(圆柱)。",
+    "knowledge_points": [
+      "长方体的认识及特征",
+      "圆柱的认识及特征",
+      "从不同位置观察单个物体"
+    ],
+    "source": "22-23二年级上·湖北黄石·期末"
+  },
+  {
+    "id": "179",
+    "unit": "第五单元 观察物体1",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "站在一个位置上观察讲台，最多能看到讲台的()个面。",
+    "options": [],
+    "answer": "3",
+    "solution": "【分析】如下图，站在A的前面看时，只能看到1个面;站在B的前面看时，能看到2个面;从C的位置看时，能看到3个面，据此解答即可。此题考查了从不同方向观察单个物体，培养了学生的空间想象力和抽象思维能力.\n\n![](images/082c61e316d4e3679b392f47f05d77f8731d37f9cf7a5269539c9312adfc9ff4.jpg)\n\n【详解】根据分析可知，站在一个位置上观察讲台，最多能看到讲台的3个面。",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "21-22三年级上·浙江丽水·期末"
+  },
+  {
+    "id": "180",
+    "unit": "第五单元 观察物体1",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "小红看到的立体图形的一个面是长方形，这个立体图形是我们学过的，它可能是。",
+    "options": [],
+    "answer": "长方体或圆柱",
+    "solution": "【分析】长方体的特征：长方体有6个面，每个面都是长方形，也可能相对的两个面是正方形;圆柱的特征：从站立的圆柱前面看是长方形(有时也可能是正方形),据此解答。本题主要考查了从不同方向观察长方体和圆柱体，知道从不同方向观察分别看到的是什么样的图形是解本题的关键.\n【详解】小红看到的立体图形的一个面是长方形，这个立体图形是我们学过的，它可能是长方体或圆柱。",
+    "knowledge_points": [
+      "立体图形的认识"
+    ],
+    "source": "21-22二年级上·吉林四平·期末"
+  },
+  {
+    "id": "181",
+    "unit": "第五单元 观察物体1",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "一个物体，从正面和侧面看到的形状都是![](images/2026-03-03%20221121.jpg),这个物体最多要用()个小正方体拼成。",
+    "options": [],
+    "answer": "4",
+    "solution": "【分析】本题考查根据从不同方向观察到的形状还原立体图形。从正面和侧面看到的形状都是这个图形，表示从正面和侧面看都是2个小正方形上下排列(即一列两层)。那么这个立体图形至少需要2个小正方体(前后或左右错开),最多可以在前后或左右方向再增加小正方体，且不影响正面和侧面的视图。根据三视图推理，最多可以用4个小正方体拼成.\n【详解】从正面和侧面看到的都是上下2个正方形，说明这个立体图形从正面和侧面看都是2层，每层1个正方形。那么底层可以放前后两排各1个(共2个),上层也可以放前后两排各1个(共2个),这样从正面看时，前后排重叠，只能看到每层1个;从侧面看时，前后排也重叠，也只能看到每层1个。这样一共用了4个小正方体。如果只放2个(前后或左右错开),则只能看到每层1个，但数量少。所以最多用4个。故答案为:4",
+    "knowledge_points": [
+      "根据三视图确认几何体"
+    ],
+    "source": "21-22二年级上·山西阳泉·期末"
+  },
+  {
+    "id": "182",
+    "unit": "第五单元 观察物体1",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "看到的立体图形的某一个面是正方形，这个立体图形可能是我们学过的()。",
+    "options": [],
+    "answer": "正方体",
+    "solution": "【分析】本题考查从不同方向观察立体图形。看到一个面是正方形，说明这个立体图形有可能某个面是正方形。我们学过的立体图形中，正方体的每个面都是正方形;长方体也可能有正方形面(如特殊的长方体，有两个相对的面是正方形),但题目中问\"可能是我们学过的\"，通常答案填正方体，因为正方体是每个面都是正方形的典型立体图形，而长方体不一定是正方形面。 \n【详解】看到的立体图形的一个面是正方形，这个立体图形可能是我们学过的正方体(因为正方体的每个面都是正方形)。故答案为：正方体",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "20-21二年级上·内蒙古赤峰·期末"
+  },
+  {
+    "id": "183",
+    "unit": "第五单元 观察物体1",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "看到立体图形的一个面是长方形，这个立体图形一定是长方体。()",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】根据对立体图形的认识可知：长方体从不同方向看到的是长方形(有时也可以看到正方形);正方体从不同方向看到的都是正方形;圆柱从侧面看是长方形或正方形，从上下看是圆形;球表面是曲面，从任何方向看都是圆形。由此解答.\n【详解】由分析可知：看到立体图形的一个面是长方形，这个立体图形不一定是长方体。原题说法错误。故答案为: ×",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "23-24二年级上·山东菏泽·期末"
+  },
+  {
+    "id": "184",
+    "unit": "第五单元 观察物体1",
+    "question_type": "判断题",
+    "difficulty": 0.65,
+    "question": "观察一个立体图形，如果看到其中一个面是长方形，那么这个立体图形一定是长方体。()",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】\n![](images/dd408296c65a70f4ff28c6245661377a45a7a9894faf3fa88cdf9be8b59b9ad2.jpg)\n长方体\n![](images/5e670e03cd35d8df0c9c4b2a0a57380a0adad89f56c48bfbb5566cc66b129d77.jpg)\n正方体\n![](images/273fcc5bbca2de704a494eda3beee8f5ad3a9cb460c3f08543b969c0617de621.jpg)\n圆柱体\n![](images/ebae2ff26f2119fe27c081fefb24c12c3c67fadca8ea0a5c59f219bc0cb6bbd9.jpg)\n球\n如图，圆柱从侧面看可以看到长方形。据此解答.\n【详解】观察一个立体图形，如果看到其中一个面是长方形，那么这个立体图形可能是长方体，也可能是圆柱。原题说法错误。故答案为: ×",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "23-24二年级上·山东济南·期末"
+  },
+  {
+    "id": "185",
+    "unit": "第五单元 观察物体1",
+    "question_type": "判断题",
+    "difficulty": 0.94,
+    "question": "如果看到立体图形的一个面是圆，那么这个立体图形可能是球。()",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】球没有平面可以任意方向滚动，从各个方向看到的都是圆.\n【详解】如果看到立体图形的一个面是圆，那么这个立体图形可能是球。原题说法正确。故答案为:√",
+    "knowledge_points": [
+      "物体三视图的认识"
+    ],
+    "source": "23-24二年级上·湖北武汉·期末"
+  },
+  {
+    "id": "186",
+    "unit": "第五单元 观察物体1",
+    "question_type": "判断题",
+    "difficulty": 0.65,
+    "question": "从一个面观察到长方形的立体图形一定是长方体。()",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】长方体虽然从一个面观察，看到的是长方形(特殊长方形看到的可能是正方形),但从一个面观察到长方形的立体图形不一定是长方体。如下图，由11个相同小正方体组成的这个立体图形，从上面，侧面看到的都是长方形，但这个立体图形并不是长方体.\n\n![](images/cfac743b0b26737fcd1a993caa5ed30bc472b40c021d5a4dffaa926737cb6542.jpg)\n\n【详解】由题意分析得：这个由若干个小正方体搭成的立体图形，从上面，左面，右面看到的图形都是长方形，但它不是一个长方体。因此，从一个面观察到长方形的立体图形一定是长方体的说法错误。故答案为: ×",
+    "knowledge_points": [
+      "长方体的认识及特征",
+      "从不同位置观察单个物体"
+    ],
+    "source": "23-24二年级上·吉林松原·期末"
+  },
+  {
+    "id": "187",
+    "unit": "第五单元 观察物体1",
+    "question_type": "判断题",
+    "difficulty": 0.65,
+    "question": "小红看到的立体图形的一个面是正方形，这个立体图形一定是正方体。()",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】长方体有6个面，有三组相对的面完全相同，一般情况下六个面都是长方形，特殊情况时有两个面是正方形，其他四个面都是长方形;正方体有6个面,6个面都是正方形，据此判断.\n【详解】根据长方体和正方体的特征可知，一个立体图形，从一个面看到的是正方形，这个立体图形不一定是正方体，原题说法错误。故答案为: ×",
+    "knowledge_points": [
+      "长方体的认识及特征",
+      "正方体的特征"
+    ],
+    "source": "19-20二年级上·全国·期末"
+  },
+  {
+    "id": "188",
+    "unit": "第五单元 观察物体1",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "观察![](images/2026-03-03%20221542.jpg),从上面看到的图形是![](images/2026-03-03%20221554.jpg)。()",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】从上面看到的是3个正方形(上面并排2个，下面靠右1个),如图:![](images/2026-03-03%20221605.jpg).\n【详解】由题意分析得：观察该图，从上面看到的图形是![](images/2026-03-03%20221622.jpg);原题说法错误。故答案为: ×",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "23-24二年级上·河北廊坊·期末"
+  },
+  {
+    "id": "189",
+    "unit": "第五单元 观察物体1",
+    "question_type": "判断题",
+    "difficulty": 0.65,
+    "question": "小林观察一个学过的立体图形，他看到的立体图形的一个面是正方形这个立体图形一定是正方体。()",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】正方体:6个面都是正方形，且完全一样;故，从任意一个面看正方体，看到的都是正方形。长方体：一般的长方体6个面都是长方体，且相对的面一样;特殊的长方体有一组相对的面是正方形，另外4个面是长方形;故，从任意一个面看长方体，看到的可能是正方形，也可能是长方形。据此解决.\n【详解】由题意分析得：小林观察一个学过的立体图形，他看到的立体图形的一个面是正方形这个立体图形可能是正方体，也可能是长方体;故原题说法错误。故答案为: ×",
+    "knowledge_points": [
+      "长方体的认识及特征",
+      "正方体的特征",
+      "从不同位置观察单个物体"
+    ],
+    "source": "22-23二年级上·广东佛山·期末"
+  },
+  {
+    "id": "190",
+    "unit": "第五单元 观察物体1",
+    "question_type": "判断题",
+    "difficulty": 0.65,
+    "question": "从上面看![](images/2026-03-03%20221654.jpg)看到的形状是圆。()",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】圆柱的上下两个面都是圆，从上面看的形状是圆。据此得出结论.\n【详解】由分析知，原题结论正确。故答案为:√",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "22-23二年级上·河南信阳·期末"
+  },
+  {
+    "id": "191",
+    "unit": "第五单元 观察物体1",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "从任意一个方向观察一个长方体，看到的一定是长方形。()",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】如果这个长方体的长，宽，高各不相等，从任意一个方向观察，看到的一定是长方形。如果这个长方体的长，宽相等或长，高相等或宽，高相等，从任意一个方向观察，看到的是长方形或正方形，据此判断.\n【详解】由分析得：从任意一个方向观察一个长方体，看到的不一定是长方形，还有可能是正方形。故答案为: ×",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "23-24三年级上·河南商丘·期中"
+  },
+  {
+    "id": "192",
+    "unit": "第五单元 观察物体1",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "站在小明的后面拍照，拍不到他的两只眼睛。()",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】站在小明的后面，能看到他脑袋的后面，所以无法拍到他的两只眼睛。据此解答.\n【详解】根据分析，站在小明的后面拍照，拍不到他的两只眼睛。原题说法正确。故答案为:√",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "22-23二年级上·河南周口·期末"
+  },
+  {
+    "id": "193",
+    "unit": "第五单元 观察物体1",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "如图，明明看到的是\n\n![](images/b229a5aa7fa7e83873d838a3eb165a8059dcc500b701590ca6bdd075a2104ca5.jpg)\n\n。()\n![](images/2026-03-03%20221926.jpg)",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】根据图示，明明在车前面，看到的是车头;花花在车侧面，看到的是车身侧面;奇奇在车后，看到的是车尾;据此解答即可。本题考查了从不同方向观察物体知识，结合题意分析解答即可.\n【详解】由分析可知，明明在车前面，看到的是车头，所以原题说法错误;故答案为: ×",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "22-23三年级上·河南驻马店·期中"
+  },
+  {
+    "id": "194",
+    "unit": "第五单元 观察物体1",
+    "question_type": "判断题",
+    "difficulty": 0.65,
+    "question": "长方体不管从哪个方位来看都是长方形。()",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】长方体从不同方向看到的形状可能不全是长方形(有时两个相对的面是正方形),据此判断。本题是考查从不同方向观察物体和几何图形，是培养学生的观察能力.\n【详解】一个长方体不管从哪个方向观察，看到的可能都是长方形，但有时两个相对的面是正方形，所以原题说法错误。故答案为: ×",
+    "knowledge_points": [
+      "长方体的认识及特征",
+      "从不同位置观察单个物体"
+    ],
+    "source": "23-24二年级上·湖南怀化·期中"
+  },
+  {
+    "id": "195",
+    "unit": "第五单元 观察物体1",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "从上面和前面观察\n\n![](images/3bde369da5880e707148d94dcd2015d808f2f9fed3c4c8e2293df0304f4f7fec.jpg)\n\n,所看到的图形都是![](images/2026-03-03%20222014.jpg)。()",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】从上面看，看到的图形是![](images/2026-03-03%20222028.jpg);从前面看，看到的图形是![](images/2026-03-03%20222039.jpg)。由此判断即可。本题主要考查图形观察，培养学生的观察能力和空间想象能力.\n【详解】根据分析可知，从上面和前面观察，所看到的图形不同，原题说法错误。故答案为: ×",
+    "knowledge_points": [
+      "从不同位置观察单个物体",
+      "物体三视图的认识"
+    ],
+    "source": "23-24二年级上·全国·课后作业"
+  },
+  {
+    "id": "196",
+    "unit": "第五单元 观察物体1",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "小明看到立体图形的一个面是长方形，这个立体图形可能是圆柱。()",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】圆柱体从正面，侧面看都是长方形，从上面看是圆，据此解答。注意可能是和一定是的区别.\n【详解】小明看到立体图形的一个面是长方形，这个立体图形可能是圆柱。原题说法正确。故答案为:√",
+    "knowledge_points": [
+      "长方形的概念及特点",
+      "根据三视图确认几何体"
+    ],
+    "source": "20-21二年级上·湖南岳阳·期末"
+  },
+  {
+    "id": "197",
+    "unit": "第五单元 观察物体1",
+    "question_type": "判断题",
+    "difficulty": 0.65,
+    "question": "观察一个物体，无论从什么位置看，它都一定是一样的。()",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】从不同的方向观察物体，看到的形状可能相同，也可能不同，如：长方体或者正方体等图形;由此解答。本题考查观察物体的方法，注意学生空间想象力和抽象思维能力的培养.\n【详解】由分析可知：从不同的方向观察物体，看到的形状可能相同，也可能不同;故答案为: ×",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "22-23二年级上·全国·期末"
+  },
+  {
+    "id": "198",
+    "unit": "第五单元 观察物体1",
+    "question_type": "判断题",
+    "difficulty": 0.65,
+    "question": "从不同的位置观察玩具熊，所看到的形状是不相同的。()",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】根据玩具熊的特征进行判断即可。需要注意，并不是所有物体从不同位置观察到的形状都不同.\n【详解】玩具熊的每一面都不相同，所以从不同的位置观察玩具熊，所看到的形状是不相同的。故答案为:√",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "21-22一年级下·河南商丘·期末"
+  },
+  {
+    "id": "199",
+    "unit": "第五单元 观察物体1",
+    "question_type": "判断题",
+    "difficulty": 0.65,
+    "question": "看到立体图形的一个面是圆形，这个立体图形一定是球。()",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】本题考查从不同方向观察立体图形。看到一个面是圆形，说明这个立体图形有可能某个面是圆形。球体从任何方向看都是圆形，但圆柱从上面或下面看也是圆形，圆锥从下面看也是圆形。因此，看到圆形面不一定就是球，也可能是圆柱或圆锥等。 \n【详解】看到立体图形的一个面是圆形，这个立体图形可能是球，也可能是圆柱(从上面或下面看)或圆锥(从下面看)。所以原题说法错误。故答案为: ×",
+    "knowledge_points": [
+      "立体图形的认识",
+      "从不同位置观察单个物体"
+    ],
+    "source": "21-22二年级上·河北承德·期末"
+  },
+  {
+    "id": "200",
+    "unit": "第五单元 观察物体1",
+    "question_type": "解答题",
+    "difficulty": 0.85,
+    "question": "一个面是圆形，请猜一猜它可能是我们学过的哪个立体图形。",
+    "options": [],
+    "answer": "圆柱或球",
+    "solution": "【分析】如图：学过的立体图形中长方体和正方体的面是长方形或正方形。圆柱上下两个面是圆形，球从哪个面看都是圆形，由此解答。本题考查从不同方位观察物体.\n\n![](images/c19e215009eff99ba66c0a1d16b7cd17b0b30e4475f6cc87f9235bd1a1d61974.jpg)\n\n【详解】由分析可知，一个面是圆形的立体图形可能是圆柱或球。",
+    "knowledge_points": [
+      "立体图形的认识",
+      "从不同位置观察单个物体"
+    ],
+    "source": "22-23二年级上·全国·随堂练习"
+  },
+  {
+    "id": "201",
+    "unit": "第五单元 观察物体2",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "观察下面的两个长方形，从()看到的形状是相同的.\n\n![](images/8aa0bb5bf91978752d017540f1e9d1015a7b2ecacd2001e9fb09df72b1db0027.jpg)",
+    "options": [
+      "A. 侧面",
+      "B. 上面",
+      "C. 前面"
+    ],
+    "answer": "A",
+    "solution": "【分析】本题考查从不同方向观察物体。两个长方形，从不同方向观察，看到的形状可能相同也可能不同。需要分别从侧面，上面，前面观察，判断哪个方向看到的两个图形形状相同.\n【详解】从侧面看两个长方形，看到的都是长方形(或正方形，取决于长方形的摆放),形状相同;从上面看，可能看到不同的形状(如一个长方形横着，另一个竖着);从前面看，也可能不同。所以从侧面看到的形状是相同的。故答案为:A",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "19-20二年级上·广西·期中"
+  },
+  {
+    "id": "202",
+    "unit": "第五单元 观察物体2",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "下面的三个图形中,( )是从上面的看到的.\n\n![](images/d7dab2c9394bcba2ae8e565f8c23730d8f9feba051780e6b9a25d99830787bc7.jpg)",
+    "options": [
+      "A. ![](images/27b6c6841587344d2c8be17e779f2c8f98c0fdde40755743a29a197e4af34300.jpg)",
+      "B. ![](images/2026-03-03%20233934.jpg)",
+      "C. ![](images/d5cc6be4c79bd9fddb3ab56adce5e0dfafb48057f7f1f39163951c2c7a0b9b52.jpg)"
+    ],
+    "answer": "B",
+    "solution": "【分析】球无论从哪个方向观察，看到的形状都是圆，圆锥从侧面看到的形状是等腰三角形，从上面看到的形状是圆;长方体从正，上，侧面看到的都是长方形，只是长，宽不等。A是从左面看到的，只能看到圆与等腰三角形的三个角，长方体被挡住;B是从上面看到，球，圆锥都是圆，长方体是长方形;C是从正面看到的，球是圆，圆锥是等腰三角形，长方体是长方形，且互不遮挡;据此选择即可。本题主要考查从不同方向观察物体和几何图形，主要培养学生的观察能力.\n【详解】上面的三个图形中,B是从上面的看到的。故答案为:B",
+    "knowledge_points": [
+      "从不同位置观察两个物体的相互关系"
+    ],
+    "source": "20-21三年级上·内蒙古包头·期中"
+  },
+  {
+    "id": "203",
+    "unit": "第五单元 观察物体2",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "林林看到的是().\n\n![](images/2026-03-03%20234145.jpg)",
+    "options": [
+      "A. ![](images/a6b1bfa2e9a849d524d47d690bc9a6c245803dd9eb55b13993288195197bff16.jpg)",
+      "B. ![](images/2daf157ea96a456922a0122f79721d3e5f8eb95ca4fb568f3bd9e4ec155fc3d7.jpg)",
+      "C. ![](images/b696825cad41220eb14585b8e6dfede34ac6a494e0043fc7bffde828012e4d51.jpg)",
+      "D. ![](images/6e834dda244971066a06fcbac202f333df5a73b4f21271b5341061a7b892fb86.jpg)"
+    ],
+    "answer": "A",
+    "solution": "【分析】从前面看这个茶杯看到的图形是B,从后面看这个茶杯看到的图形是A,从左面看该茶杯看到的图形是![](images/b4c48eff3d658c82829f89d6e7ad9db150b0795b02fed1c8fdc6f62858500ad6.jpg),从右面看![](images/76a0f2a30b59002dd425fda611cf8033f2718c0f1a236cce8b0f4e53101bd154.jpg)看到的图形是![](images/2070d6036dd697ba9d190669e98faee6fe71bfb30a751a4fbd36d7b7f09a2b8a.jpg)。从不同的位置观察同一物体，所看到的物体的形状一般是不同的.\n【详解】A。是从后面看到的;B。是从前面看到的;C。是从右面看到的;D。是从左面看到的。林林站在后面，所以林林看到的是A。故答案为:A",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "20-21二年级上·四川广安·期末"
+  },
+  {
+    "id": "204",
+    "unit": "第五单元 观察物体2",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "从![](images/2026-03-03%20234455.jpg)右面看到的形状是()。",
+    "options": [
+      "A. ![](images/02ed93129e7932f16df096b0a24b4650e1a9baeffc98ceb11508e0a74dd5ebe2.jpg)",
+      "B. ![](images/0a56478ffe1ba43f966a6df77c187e76ddd2ffa3e267559ba36843a66330f37c.jpg)",
+      "C. ![](images/ca712b20b56dc4eb926b0ab3ef4c8d5d6cc610d6f92ad5fe6b70604a63d80e82.jpg)"
+    ],
+    "answer": "C",
+    "solution": "【分析】从不同方向观察物体，可以拿一个具体的实物，自己站在不同的方向实际看一下，也可以对照图片想象自己站在不同的方向，会看到什么样的图形。从右面看到的形状是:2行1列。据此解答。本题主要考查从不同方向观察物体和几何体，培养学生的空间观念.\n【详解】从右面看到的形状是:2行1列。故答案为:C",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "20-21二年级上·四川内江·期末"
+  },
+  {
+    "id": "205",
+    "unit": "第五单元 观察物体2",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "![](images/2026-03-03%20234627.jpg)\n女孩看到的图是()。",
+    "options": [
+      "A. ![](images/ef4e24f06a7886dff02310098f41a98d7be08615d51ba336362490d9ae9ab887.jpg)",
+      "B. ![](images/2e5b9228f00410ddb20a9687ed586db2ad5d590ea7cc503f10be3961566a90ae.jpg)",
+      "C. ![](images/fdef7b670d419c0b5503bd83082a8034fc59c496f13ad42ec9b26c00942bd029.jpg)"
+    ],
+    "answer": "B",
+    "solution": "【分析】本题考查从不同方向观察物体。图中通常有一个立体图形(如小动物或积木组合),从某个位置(如侧面，后面，上面)观察，看到的形状与选项中的图形进行匹配。需要根据观察者的位置判断看到的图形.\n【详解】根据图中观察者的位置，从该方向看到的图形应该是选项B中的形状。故答案为:B",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "19-20二年级上·湖南娄底·期末"
+  },
+  {
+    "id": "206",
+    "unit": "第五单元 观察物体2",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "从上面观察下图，所看到的图形是( ).\n\n![](images/e9767dab52a429dd1f322f976a9b715306e88d426b9da017e2771ed1dbb3eb8c.jpg)",
+    "options": [
+      "A. ![](images/62f762d9b650e05a26474453aac49dd5daa4bdf5df767bcb15af52c77c769148.jpg)",
+      "B. ![](images/c33ae66e1b39eb95aa5c0723b51405ad0757c8ce7edbd7f429a327051166dbd6.jpg)",
+      "C. ![](images/2026-03-03%20234834.jpg)"
+    ],
+    "answer": "A",
+    "solution": "【分析】根据图示可知，所给几何体左面的圆柱从上面看到的是长方形，右面的圆柱从上面看到的是圆;据此解答。本题主要从不同方向观察物体和几何图形，是培养学生的观察能力.\n【详解】从上面观察:![](images/6dbb175df60a0f1dfd1ed95130315d1efee07987ca50353b3bbafa0ed68f5281.jpg),所看到的图形是![](images/4c4b57430b95d62f48e4348dc4025dcef9beb6269a0f47504660ac9e80a93bec.jpg)。故答案为:A",
+    "knowledge_points": [
+      "从不同位置观察两个物体的相互关系"
+    ],
+    "source": "21-22三年级上·广东梅州·期末"
+  },
+  {
+    "id": "207",
+    "unit": "第五单元 观察物体2",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "从上面看,()看到的图形和另外两个不一样。",
+    "options": [
+      "A. ![](images/9f352152836165ad5a62a95076ed6b3362e5acad09e6c6e32d6ec69adf194ec7.jpg)",
+      "B. ![](images/fde0297c35bee138043578add57447d06e2b27474ea66c1d037ab7801389193e.jpg)",
+      "C. ![](images/bfa9b32f72c0f1814a6aeefbb614824917de10471cffc7d1723876aa71d89a6d.jpg)"
+    ],
+    "answer": "A",
+    "solution": "【分析】从上面看,A中的长方体看到的是正方形,B中的球体看到的是圆形,C中的圆柱体看到的是圆形,B和C从上面看，看到的均为圆形，因此A中的长方体看到的图形和另外两个不一样.\n【详解】A。从上面看，这个长方体看到的是正方形;B。从上面看，这个球体看到的是圆形;C。从上面看，这个圆柱体看到的是圆形，与B看到的图形一样。故答案为:A",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "21-22二年级上·河北张家口·期末"
+  },
+  {
+    "id": "208",
+    "unit": "第五单元 观察物体2",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "如图，小明从窗户外面看到的情景应该是().\n\n![](images/792a497a34b973bc85675ec309314d662405d59f08babcdea98c5419851dd546.jpg)",
+    "options": [
+      "A. ![](images/c57314ece1ce1aace33205ad4a23545c151da8b5b7b845192319471430c1ca6a.jpg)",
+      "B. ![](images/f8806aefc3aa814cc74a9bde2a77b7aefd9d6f30f45315b65450c86d7c022e34.jpg)",
+      "C. ![](images/da1f18d5cdea28484ec8fc0c6b47f26a2c6419abec240e1278c62ab0c1700c73.jpg)"
+    ],
+    "answer": "B",
+    "solution": "【分析】从小明的角度观察，是从后面看，小明只能看到小女孩的背影，排除A,并且小女孩在右侧，桌子在左侧，排除C,所以只有B符合题意;据此解答即可。本题主要考查观察物体，要站在小明的角度思考问题，观察图形.\n【详解】小明从窗户外面看到的情景应该是![](images/a2cb0f04dca134179bd32978b67968d76ddfdca9d4e9223950bd8fb2c8e21274.jpg)。故答案为:B",
+    "knowledge_points": [
+      "从不同位置观察两个物体的相互关系"
+    ],
+    "source": "21-22三年级上·山西晋城·期末"
+  },
+  {
+    "id": "209",
+    "unit": "第五单元 观察物体2",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面第()组图是小兔看到的.\n\n![](images/d95f5675a50f7d3887b47a6db089fe41ad73aceb3405bf46cbdffc3a3f26f634.jpg)",
+    "options": [
+      "A. ![](images/6947e677c55804e9bd4369bfdb4faa2638b08c196446325c009965916c5b37fe.jpg)",
+      "B. ![](images/3e01f68de69bcbf2b0f6aa66d14c8d9d1e00b537c9967dbf67ad9431d41d1ad1.jpg)",
+      "C. ![](images/d6ccf9b7139c308a562a0e7029d600a5050beec11ad19370683b3671562efd9a.jpg)"
+    ],
+    "answer": "B",
+    "solution": "【分析】本题考查从不同位置观察物体之间的相对位置关系。小兔在某个方向观察，看到的物体形状以及物体之间的遮挡关系会有所不同。需要根据小兔的位置判断哪个选项是它看到的画面.\n【详解】根据图中物体的摆放位置和小兔的观察方向，小兔看到的图形中，物体之间的前后，左右关系与选项B相符。故答案为:B",
+    "knowledge_points": [
+      "从不同位置观察两个物体的相互关系"
+    ],
+    "source": "21-22二年级上·福建泉州·期末"
+  },
+  {
+    "id": "210",
+    "unit": "第五单元 观察物体2",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "如图，小朋友看到杯子的形状是图().\n\n![](images/78d8e5ee9490b96b233776171ff469abb9a01d28e78bbd7978bafc33ff00ab54.jpg)",
+    "options": [
+      "A. ![](images/4d0f57aa8e20359b4dddfacc5ae9be00fc844c44de84f90b5ae0cf5b74c4d432.jpg)",
+      "B. ![](images/a107a3623cae8edece00f0f0f71554dea58f39de5f01f855f98a8a603bcd032e.jpg)",
+      "C. ![](images/67409bfabfe9fd6e44d1efa89d70b11d3d377f72ea8d065d9bdf3712a48b5211.jpg)"
+    ],
+    "answer": "C",
+    "solution": "【分析】本题考查从不同方向观察物体。小朋友观察杯子的位置不同，看到的杯子形状也不同。需要根据图中小朋友的观察角度，判断他看到的杯子形状与哪个选项相符.\n【详解】从图中小朋友的观察方向看，杯子呈现的形状与选项C中的图形一致。故答案为:C",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "21-22二年级上·山东临沂·期末"
+  },
+  {
+    "id": "211",
+    "unit": "第五单元 观察物体2",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "小宁站在小猴子的后面，他看到的是()。",
+    "options": [
+      "A. ![](images/ff6cba810e34fea5c4c9bc6863b48d4f3d7e48e1e314191ba5fc6e9bc99522e7.jpg)",
+      "B. ![](images/bb146bfae3460e0aec7764367c62223a8a6bcb78e0853f15d96f4a9953380786.jpg)",
+      "C. ![](images/6f0bcc228ebaa86708a6cbe1335b697a51b2a5f652962da9eb656a36ce29bc99.jpg)"
+    ],
+    "answer": "C",
+    "solution": "【分析】本题考查从不同方向观察物体。小宁站在小猴子的后面，他看到的是小猴子的背面。需要根据小猴子的朝向和位置，判断从后面看到的形状是哪个选项.\n【详解】从后面看小猴子，看到的是它的背部，与选项C中的图形一致。故答案为:C",
+    "knowledge_points": [
+      "从不同位置观察单个物体",
+      "前",
+      "后位置"
+    ],
+    "source": "21-22二年级上·河北张家口·期末"
+  },
+  {
+    "id": "212",
+    "unit": "第五单元 观察物体2",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "![](images/b8d173955a5619813d6c761bdaeeb2d5bb94f0df7e6bb218d3475b06dd88af8e.jpg)的上面是()形。",
+    "options": [
+      "A. ![](images/b5685fde9be6bf5ac95c24b6dc26dd386226e709724793a2c7fb088985d328e4.jpg)",
+      "B. ![](images/9ab124bcb1079a590502ae150624df631dc947e5454292a987b87f4776d21436.jpg)",
+      "C. ![](images/7a683654f0683a31ebb3bd5252cfbbec2a5d17e3ca78ba2167232c555f376abe.jpg)"
+    ],
+    "answer": "B",
+    "solution": "【分析】圆柱体的上面是一个圆形.\n【详解】A。是一个长方形，不合题意;B。是一个圆形，符合题意;C。是一个三角形，不合题意。故答案为:B",
+    "knowledge_points": [
+      "立体图形的认识"
+    ],
+    "source": "18-19一年级下·河南商丘·期末"
+  },
+  {
+    "id": "213",
+    "unit": "第五单元 观察物体2",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "![](images/c5b76a97ef8e6f7480b55354336186f7a57de9704261f9a8544f787daaa782eb.jpg)左图前面的面是()。",
+    "options": [
+      "A. 平行四边形",
+      "B. 长方形",
+      "C. 正方形"
+    ],
+    "answer": "B",
+    "solution": "【分析】本题考查从不同方向观察立体图形以及平面图形的认识。左图是一个长方体(或类似立体图形),它的前面是一个长方形(或正方形，但根据选项和常见题目，通常为长方形)。需要判断前面的面是什么形状.\n【详解】左图是一个长方体，它的前面是一个长方形。故答案为:B",
+    "knowledge_points": [
+      "长方形",
+      "正方形",
+      "三角形和圆的初步认识",
+      "从不同位置观察单个物体"
+    ],
+    "source": "21-22一年级下·全国·周测"
+  },
+  {
+    "id": "214",
+    "unit": "第五单元 观察物体2",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "小浩看到的是().\n\n![](images/38857927cbaf02da19539e8b93c490c513309bd6c801ec4bf1716bf11e19c80b.jpg)",
+    "options": [
+      "A. ![](images/efb8fb16c84a443ae4f86a86b094c9dbf0cde12b70dcd835bdaa217dad467cab.jpg)",
+      "B. ![](images/77bf7da68b8bf1114c7d49d7d7be2b6e6b72134f495701dcf093bd89c4a4b2d6.jpg)",
+      "C. ![](images/944a9356ef64ee6f96889466efff3d54561b547db97bad9b3bc749f0d90ae147.jpg)"
+    ],
+    "answer": "A",
+    "solution": "【分析】根据小浩坐的位置，小浩看到左边是水瓶，右边是水瓶的底部，一个圆形;据此进行选择即可。本题主要考查从不同方向观察物体，培养学生的空间想象能力.\n【详解】据分析可知：小浩看到的是A。故答案为:A",
+    "knowledge_points": [
+      "从不同位置观察两个物体的相互关系"
+    ],
+    "source": "21-22三年级上·河南鹤壁·期末"
+  },
+  {
+    "id": "215",
+    "unit": "第五单元 观察物体2",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "从上面观察这组物体，看到的形状是().\n\n![](images/0288b63bc87b70565668a18c4207ce88cccbc0de547a93338257ad6981cd41bb.jpg)",
+    "options": [
+      "A. ![](images/d00883893d9f84e936d7af45dafa23785daff465245c69ad663132f41ac173cd.jpg)",
+      "B. ![](images/d1f54a4fe824fc71803ccb93a78bd3bb5c22fe9e88694e93b6ce1ea76d6d4841.jpg)",
+      "C. ![](images/cf0031b0a28cd837c9efec0f5d6112091514726b890e0b012b084beede8aaf42.jpg)"
+    ],
+    "answer": "A",
+    "solution": "【分析】可逐项分析，判断每个图片分别是从哪个方向看到的，再做选择即可.\n【详解】A。![](images/cc7f4ea47de26a990404493561648aa06eda3269b02a9370e1c209ea24e21962.jpg)是从上面看到的;B。![](images/5a848e2d6ec430f6beb6e8853f573739befed956b61ca51ee52a6b45426b122f.jpg)不是从前，后，左，右4个方向看到的;C。![](images/aed6c51dfaba4de2a1fa12679f1d014c64db850b9c25cf7c6751c889f97f3e98.jpg)是从前面看到的。故答案为:A",
+    "knowledge_points": [
+      "从不同位置观察单个物体",
+      "物体三视图的认识"
+    ],
+    "source": "20-21二年级上·广东东莞·期末"
+  },
+  {
+    "id": "216",
+    "unit": "第五单元 观察物体2",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "小华看到的是().\n\n![](images/2026-03-03%20235456.jpg)",
+    "options": [
+      "A. ![](images/542a1ab1017168793f948ad849685d303e10f4fc20c4693f7f513e7e3fe84555.jpg)",
+      "B. ![](images/2d8718bf7fb7079c8d9f64cc29683c786fc43560aadc0a1da8b844bf51e25a00.jpg)",
+      "C. ![](images/7a09dd62be10630c833299b14b8e207f9ce714f7c749189cd60594810139be5b.jpg)"
+    ],
+    "answer": "B",
+    "solution": "【分析】根据题意可知，小丽看到的是![](images/e7b12153d53697fa3c0ade7e29cfe5b776ff0cc745cd5a724c15add7b1de8e5d.jpg);小华看到的是B;小东看到的是![](images/8ab037b0cc6c4b8a4d97aef9c55a9af9e3c4a0469952d266a23d5c9af011c807.jpg);据此解题即可。熟练掌握从不同方向观察同一个物体的方法，是解答此题的关键.\n【详解】A。小丽看到的是A;B。小华看到的是B;C。小东看到的是C。故答案为:B",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "19-20三年级上·河南商丘·期末"
+  },
+  {
+    "id": "217",
+    "unit": "第五单元 观察物体2",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "观察下图，小明看到的是图().\n\n![](images/7696cfc2f6bd752d53a1f1ee07494ec3d7158d20b42bcebc2ee707ccbd7a8719.jpg)",
+    "options": [
+      "A. ![](images/501ad64fec4e94e3c63747d43953f287a5b556d0e7aef9f8594d7a9acd44dff4.jpg)",
+      "B. ![](images/109588484b43e19955cd8918dd8154ac0b8d0a66dac36faa1d50b62542756df1.jpg)",
+      "C. ![](images/efc07234b37a5596c57fee266f9d3f5859271114fca28c9f11cb24109834b02a.jpg)"
+    ],
+    "answer": "A",
+    "solution": "【分析】根据图示，小明看到的是玩具猫的后面，小云看到的是玩具猫的右面，小丽看到的是玩具猫的左面，据此解答即可.\n【详解】观察下图，小明看到的是图![](images/4915aa88636af9d05bc72f821cd25f18130bfb80383e9068cacb807770460482.jpg)。故答案为:A",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "21-22二年级上·湖南怀化·单元测试"
+  },
+  {
+    "id": "218",
+    "unit": "第五单元 观察物体2",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "小明从左面看到![](images/2026-03-03%20235640.jpg)的物体是()。",
+    "options": [
+      "A. ![](images/f093609ffbc1d83993d467da70b1829d3e43bec4543196786eba21f7fe255b9c.jpg)",
+      "B. ![](images/b2d2dece13ba427c4538df43dcd4d8a35ed1472b7195f53f457498da7e016925.jpg)",
+      "C. ![](images/17c9cbe2229cf3f3a6e84a837107ffe7d0bdf211d6331003e7ea6414b84652c6.jpg)"
+    ],
+    "answer": "A",
+    "solution": "【分析】本题考查从不同方向观察立体图形。小明从左面看到的形状是□□,表示从左面看是上下两个小正方形(即一列两层)。需要判断哪个立体图形从左面看正好是上下两个正方形.\n【详解】从左面看到上下两个正方形，说明这个立体图形从左面看有两层，每层一个正方形。选项A的图形从左面看是上下两个正方形，符合题意;选项B和C从左面看可能是一个正方形或左右两个正方形，不符合。故答案为:A",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "21-22二年级上·湖南怀化·单元测试"
+  },
+  {
+    "id": "219",
+    "unit": "第五单元 观察物体2",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "一个立体图形，小杰看到它的一个面是圆的，它可能是()。",
+    "options": [
+      "A. 圆柱",
+      "B. 正方体",
+      "C. 长方体"
+    ],
+    "answer": "A",
+    "solution": "【分析】在以上的立体图形中，只有圆柱的两个底面是圆形的，正方体，长方体没有哪个面是圆形的，因此，小杰看到的可能是圆柱.\n【详解】结合圆柱，正方体，长方体的特征可知：小杰看到的可能是圆柱。故答案为:A",
+    "knowledge_points": [
+      "立体图形的认识",
+      "从不同位置观察单个物体"
+    ],
+    "source": "20-21二年级上·湖北黄冈·期末"
+  },
+  {
+    "id": "220",
+    "unit": "第五单元 观察物体2",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "观察物体![](images/2026-03-03%20235748.jpg),从右面看到的图形是()。",
+    "options": [
+      "A. ![](images/ce515d09dc9dc026918147a912eaf1b1bdd015ad257f67ea272ce8950cf1449d.jpg)",
+      "B. ![](images/1c76b3aa02dd5cf8b105ba7ddcd2c082fdf659dcdd0b62e0d3735b527bbe5531.jpg)",
+      "C. ![](images/0f4033d5c167ee0162e34f7bf939bde2ebfd435849d03d7ea4a9e8c3f69c6a06.jpg)"
+    ],
+    "answer": "C",
+    "solution": "【分析】可逐项分析，先判断每个图片分别是从哪个方向看到的，再做选择即可.\n【详解】A。是从前面看到的;B。是从左面看到的;C。是从右面看到的。故答案为:C",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "17-18二年级上·广西玉林·期末"
+  },
+  {
+    "id": "221",
+    "unit": "第五单元 观察物体2",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "小玉看到的图片是().\n\n![](images/2026-03-04%20000216.jpg)",
+    "options": [
+      "A. A",
+      "B. B",
+      "C. C",
+      "D. D"
+    ],
+    "answer": "D",
+    "solution": "【分析】可逐项分析，先判断每个图片分别是从哪个方向看到的，再做选择即可.\n【详解】A。![](images/40dfeadb0bb4fdf05ff6f882ed44c164ab375bc2dd70bbc03d11912706f00683.jpg)是小红看到的;B。![](images/e0f9d1ca3c9ba2d508b6a7c163d87d0645e250a145e6ede86c401a4ac536e49c.jpg)是小丽看到的;C。![](images/dda01d0299c7f1f7169688a4d0f80f7b5fc1ae1f3374e883770270699de692dc.jpg)是小芳看到的;D。![](images/17e697c2b3f538864d09c53f242d4471235d54bdd835b184bc8ef3b8266167a6.jpg)是小玉看到的。故答案为:D",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "21-22二年级上·黑龙江佳木斯·期末"
+  },
+  {
+    "id": "222",
+    "unit": "第五单元 观察物体2",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "如图:![](images/2026-03-04%20000216.jpg),从上面看到的形状是()。",
+    "options": [
+      "A. ![](images/f06b07a6b563bdb1a2a30a5d89d2f3c448e51892aa3681cd4f1743c46d128e46.jpg)",
+      "B. ![](images/bfa1c9d1fb1a1c2274a3100d5d1c9902be62b98257c33622465244e963f67cfd.jpg)",
+      "C. ![](images/582ab682d19ac89c74376ae925a0f2eb879c5e00f01848ed0779b2ee54ad3818.jpg)"
+    ],
+    "answer": "A",
+    "solution": "【分析】可结合图片逐项分析，先判断每个图片分别是从哪个方向看到的，再做选择即可.\n【详解】A。是从上面看到的;B。是从左面看到的;C。是从前面看到的。故答案为:A",
+    "knowledge_points": [
+      "物体三视图的认识"
+    ],
+    "source": "19-20二年级上·北京朝阳·期末"
+  },
+  {
+    "id": "223",
+    "unit": "第五单元 观察物体2",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面()图是小丽看到的.\n\n![](images/4674988ca3ef449843671f03551d04f1c5735ef2c8a0915cb5a9f2c7799092e1.jpg)",
+    "options": [
+      "A. ![](images/62dec81edfdffc9fa1492ef020fa1d8ff7ce6b7d74b5a9c2897c7ed3a29dff4c.jpg)",
+      "B. ![](images/e151d80cede69f80031f8781989dbbdff02210a49ea1aac0f7133eb9c0013481.jpg)",
+      "C. ![](images/febf38144ecb8ff8379d4b37456b99dba419bfc5cd3f3c15432d096ad2898eee.jpg)"
+    ],
+    "answer": "B",
+    "solution": "【分析】结合图示可知，小丽位于小猪的身后，则小丽看到的是小猪的后背.\n【详解】根据小丽，小猪的相对位置可知,![](images/309ec1820d5e9688e9cf69f391b6d52427e236d0adf6d0b9b20aca441f7e98b9.jpg)是小丽看到的。故答案为:B",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "19-20二年级上·江西抚州·期末"
+  },
+  {
+    "id": "224",
+    "unit": "第五单元 观察物体2",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "从不同方向观察()不会看到正方形。",
+    "options": [
+      "A. ![](images/467f4bf10fa9448e21cbc86e2eca88ae0b712044066910a0e3d11b58eecb2429.jpg)",
+      "B. ![](images/2d42c7dc5dcd076accbb717d7df81f0f495ef25890e3e6b3bdc9ac421eeeb92f.jpg)",
+      "C. ![](images/c627c9d644a35a51bfe0963e124f2b692fd9439945073e10f72c8d7a49dea559.jpg)"
+    ],
+    "answer": "C",
+    "solution": "【分析】本题考查从不同方向观察立体图形。需要判断哪个立体图形从任何方向观察都不会看到正方形。分析每个选项的立体图形从不同方向观察可能看到的形状.\n【详解】选项A是正方体，从任何方向看都是正方形，所以会看到正方形;选项B是长方体，可能从某个方向看到正方形(如果底面是正方形),也可能看到长方形;选项C是圆柱，从侧面看是长方形或圆形，从上面或下面看是圆形，不会看到正方形。所以从不同方向观察圆柱不会看到正方形。故答案为:C",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "21-22二年级上·吉林·期末"
+  },
+  {
+    "id": "225",
+    "unit": "第五单元 观察物体2",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "上面看![](images/2026-03-04%20000344.jpg),看到的图形是()。",
+    "options": [
+      "A. ![](images/6d0e3586db9013f1a04f712979ec5e51225297f882a13c50f9054dfbbeab9d49.jpg)",
+      "B. ![](images/2b1619e385f4154ce2a4cbfe51712665f01d5fba3b62a1447f4e3128b5e01f13.jpg)",
+      "C. ![](images/2ef37cf0cf348507d15c964e877e6bd2a91c114a19b8dd23ee33ae307b6c5a4d.jpg)"
+    ],
+    "answer": "A",
+    "solution": "【分析】圆柱上下是圆，且上下样粗，该图形是下面一个大的圆柱上面放了一个小圆柱;则可以从上面看到的是一个小圆在大圆中间，从左面和正面看是一个小长方形在大长方形上.\n【详解】由分析可得：上面看，看到的图形是A。故答案为:A",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "21-22二年级上·湖南怀化·期中"
+  },
+  {
+    "id": "226",
+    "unit": "第五单元 观察物体2",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "站在不同的位置看放在桌上的盒子，最多能看到()个面。",
+    "options": [
+      "A. 5",
+      "B. 4",
+      "C. 3"
+    ],
+    "answer": "C",
+    "solution": "【分析】站在不同方向观察一个物体或几何体，最少只能看到它的一个面，最多能看到它的三个面.\n【详解】如图:\n\n![](images/598d3a3c6d4f40344900c23436a5358105dfbbc90260a3f870413bad019a2ca3.jpg)\n站在不同的位置看放在桌上的盒子，最多能看到(3)个面。故答案为:C",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "20-21二年级上·湖南怀化·期中"
+  },
+  {
+    "id": "227",
+    "unit": "第五单元 观察物体2",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "明明观察桌子上摆的立体图形(如图所示),他从()看到的是![](images/5ebf8c9b37a5f6c91652173f2f59531fc6b34dfdf6194c0c140b09c9e6c8b167.jpg).\n\n![](images/97afa0cd839cbbb2e9d66351835dc547b9f14e8c3d28ec60efe6dc24e2477daf.jpg)",
+    "options": [
+      "A. 正面",
+      "B. 右面",
+      "C. 上面"
+    ],
+    "answer": "C",
+    "solution": "【分析】分别画出每个图形从正面，从右面，从上面观察到的形状，然后进行选择即可。此题考查的是从不同的位置观察单个物体，应熟练掌握.\n【详解】A。从正面看到的形状分别是:![](images/77f515ae6341dd373b95b63e6921ef29d0286a0929ba555e00ea33b882ccb67f.jpg);B。从右面看到的形状分别是:![](images/293d401a7047b60e7568a0b5ee36f3c9531633633d5a6cd6a2c87be9c371b8b8.jpg);C。从上面看到的形状分别是:![](images/5ebf8c9b37a5f6c91652173f2f59531fc6b34dfdf6194c0c140b09c9e6c8b167.jpg)。故答案为:C",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "20-21三年级上·河南郑州·期末"
+  },
+  {
+    "id": "228",
+    "unit": "第五单元 观察物体2",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "如图![](images/d9f88f37e28f3b0749fe289e967c5592e924ed4c89d5ba99cd001e6f6bb89161.jpg),上面看到的形状是()。",
+    "options": [
+      "A. ![](images/67e3077f5c18e2887b1ecb78749e3e609453fc0ed73fe0a22bc68b6dcaf37d08.jpg)",
+      "B. ![](images/571680b4bc6ab3351ac46313ebbb5c9844ed9e4dacaa584fe7a76a7e22834bd9.jpg)",
+      "C. ![](images/29fc4c4fe13a22a2ed00bc1ddfecb9e6ea8b8d426db8e1da1b9dd96e5cda98a7.jpg)"
+    ],
+    "answer": "A",
+    "solution": "【分析】本题考查从上面观察立体图形。图中是一个由小正方体搭成的立体图形，从上面看，看到的是小正方体从上往下投影的形状，即每个小正方体在水平面上的投影，需要根据立体图形的摆放判断上面看到的图形.\n【详解】从上面看，立体图形中每个小正方体的顶部都会显示为一个正方形，根据立体图形的排列，从上面看到的形状与选项A中的图形一致。故答案为:A",
+    "knowledge_points": [
+      "物体三视图的认识"
+    ],
+    "source": "19-20二年级上·北京西城·期末"
+  },
+  {
+    "id": "229",
+    "unit": "第五单元 观察物体2",
+    "question_type": "选择题",
+    "difficulty": 0.94,
+    "question": "笑笑和欢欢站在不同的位置观察![](images/97604420e6869d86dac149923fbe46764b0065e668ecb778c401aff5ebf01a54.jpg),他们看到的汽车的形状是()。",
+    "options": [
+      "A. 相同",
+      "B. 不同",
+      "C. 无法确定"
+    ],
+    "answer": "B",
+    "solution": "【分析】本题考查从不同方向观察物体。笑笑和欢欢站在不同的位置观察同一个物体，由于观察角度不同，他们看到的形状一般是不相同的.\n【详解】从不同的位置观察同一个物体，看到的形状通常是不同的。所以笑笑和欢欢看到的形状不同。故答案为:B",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "19-20一年级下·广西崇左·期中"
+  },
+  {
+    "id": "230",
+    "unit": "第五单元 观察物体2",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "下面是小明一次立定跳远的照片，按拍摄时间的先后顺序排列正确的是().\n\n![](images/b2292e68130b34a5078ce179faf6a5452bb8a3b09a4e2e0b92eaf04e2448fc61.jpg)\n\n![](images/d6524615e97adf352f9923031940e3c217a81ffa89a353d11d842f0ca9bbfd5f.jpg)\n\n![](images/d29645ef10878c4f030f66408f0d2377b8920375337b34010ceaef636455c29a.jpg)",
+    "options": [
+      "A. ①②③",
+      "B. ①③②",
+      "C. ②①③",
+      "D. ②③①"
+    ],
+    "answer": "D",
+    "solution": "【分析】根据题干分析可得，小明立定跳远先是起跳，然后空中跳跃，最后是落地;据此即可判断。本题考查观察物体的能力，要结合生活经验进行解答.\n【详解】观察图形可知：按照拍摄时间的先后顺序应该是②原地起跳;③空中跳跃;①落地，顺序是②③①;故答案选:D",
+    "knowledge_points": [
+      "观察的范围(视野与盲区)"
+    ],
+    "source": "20-21六年级下·浙江·期末"
+  },
+  {
+    "id": "231",
+    "unit": "第五单元 观察物体2",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "如图，看到![](images/c52113e2f9fd4a0e86829b6f8e1318dcd3e1695fdcc95310f21af3f94df1b67c.jpg)的是().\n\n![](images/cbce153b3a526199002bc14e5bc30bd41257dd89abf64c466e4119f59d6af5e9.jpg)",
+    "options": [
+      "A. 小玉",
+      "B. 小红",
+      "C. 小芳"
+    ],
+    "answer": "C",
+    "solution": "【分析】结合图示可知，看到的图片![](images/9f1fd9d6dfc5109ea98e2624f3a3fa80302c0bc8765b5b56facb6b216fe35737.jpg)是这头大象的后退和尾巴，只有站到大象身后的学生才能看得到.\n【详解】由分析得：看到![](images/3b1d2bda332fd693f37387a3d51f9c20d553a8ea620126bd3202738b0790b8cb.jpg)的是(小芳)。故答案为:C",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "20-21二年级上·云南昆明·期末"
+  },
+  {
+    "id": "232",
+    "unit": "第五单元 观察物体2",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "![](images/44e2b5940e781a8a2408e45704f4e7e7d530450a7016cc57dddd2d057c28192b.jpg)从前面看，看到的图形是什么。()",
+    "options": [
+      "A. ![](images/2026-03-04%20001058.jpg)",
+      "B. ![](images/2026-03-04%20001111.jpg)",
+      "C. ![](images/2026-03-04%20001129.jpg)"
+    ],
+    "answer": "C",
+    "solution": "【分析】可结合图示逐项分析，判断每个图片分别是从哪个方向看到的，再做选择即可.\n【详解】A。是从后面看到的;B。是从上面看到的;C。是从前面看到的。故答案为:C",
+    "knowledge_points": [
+      "物体三视图的认识"
+    ],
+    "source": "20-21二年级上·福建厦门·期末"
+  },
+  {
+    "id": "233",
+    "unit": "第五单元 观察物体2",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "王明看到立体图形的一个面是圆，这个立体图形不可能是()。",
+    "options": [
+      "A. ![](images/d523b0f16b0381bef2153c556fd2f58f45d9370ae47ff6ccbbfb35995d7df7ca.jpg)",
+      "B. ![](images/ec96c50853d3f169e86c04e9241d1b1a6a9c4db700061ea564cfdd42509bffce.jpg)",
+      "C. ![](images/e4685fa176c8058395a8b53dc23d361f4871e8dade0dd76f6e908c08f4b3f5f6.jpg)"
+    ],
+    "answer": "B",
+    "solution": "【分析】由题意，这个立体图形至少有一个面是圆形的，而题目中正方体无论哪个面都不是圆形的，因此这个立体图形不可能是正方体.\n【详解】由分析得：王明看到立体图形的一个面是圆，这个立体图形不可能是(正方体)。故答案为:B",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "20-21二年级上·山东临沂·期末"
+  },
+  {
+    "id": "234",
+    "unit": "第五单元 观察物体2",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "明明拍的照片是下面第( )幅图.\n\n![](images/2f5e6a2bd5e465c011c77102fbf36aa2a6fb159b3ac9ac40bbc3b47ca5a2171a.jpg)",
+    "options": [
+      "A. ![](images/eae769b9a8d00a748edb37de20054f6ea09bc502e64ddcdc47db86621d7c6078.jpg)",
+      "B. ![](images/9e02dd39dcb25d25d4eb914f7be992d28e49ba563ceecc8f9d82ad51fbc87162.jpg)",
+      "C. ![](images/46ce1f4909f78b12efd4c267a4633b0b0272b8dc3e3f484c132882c9318cb710.jpg)"
+    ],
+    "answer": "B",
+    "solution": "【分析】从图中分析可知，明明站在小企鹅的前面，看到的是小企鹅的正面.\n【详解】由分析可知，明明拍的照片是\n\n![](images/cb00c539e1166db8794f3b9fbe044f4dc92cb95e1a1c62c1be1c539bbb154f22.jpg)\n\n故答案为:B",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "235",
+    "unit": "第五单元 观察物体2",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "哪一幅图是小芳看到的。().\n\n![](images/831fd704bb6d9b4e92957ef2fc3d8997891a8af4e451e5979d0020686b547ee6.jpg)",
+    "options": [
+      "A. ![](images/9a4038fd553dbb4b2bab7707ec5e0bdae47aae29a15bec66394f4d61a5c6304c.jpg)",
+      "B. ![](images/df7dd6726e3dbbccfe37d61a38aa2e3cc787bd836c41b7b3f4f7a0adc1fa07c8.jpg)",
+      "C. ![](images/fb30af83295fef3f239056bc4b972558e2827c383a96baeadae174cbe8530635.jpg)"
+    ],
+    "answer": "B",
+    "solution": "【分析】如图所示，小芳站在熊猫的左侧，所以看到的是熊猫的左手.\n【详解】小芳看到的是\n\n![](images/6dea57c051e1fedf631173e5f3bb90a4ada72ee161c7d17ce025743e8e429167.jpg)\n\n故答案为:B",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "236",
+    "unit": "第五单元 观察物体2",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "下列图形中，不管从哪个角度观察都不可能看到圆形的是()。",
+    "options": [
+      "A. ![](images/b440012f762d279239408f92c0b105a95f975b6a673dbfbdd009ae280b58dea3.jpg)",
+      "B. ![](images/9a2ea2b869f146421d275c167db084fbf13e3d9915eb0f30a614b40d22bc27ac.jpg)",
+      "C. ![](images/d3cd6e5dcc8c1a67efb321697ca28a4ebe243ada21fedb0efbf031733d8b9a1f.jpg)"
+    ],
+    "answer": "B",
+    "solution": "【分析】A选项是圆柱体，圆柱从底面看可以看到圆形;B选项是一个长方体，长方体从任何方向看都是长方形(有时可以看到正方形),C选项是一个圆锥体，圆锥从上面看，可以看到圆形，据此解答即可.\n【详解】图形中，不管从哪个角度观察都不可能看到圆形的是B。故答案为:B",
+    "knowledge_points": [
+      "立体图形的认识",
+      "从不同位置观察单个物体"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "237",
+    "unit": "第五单元 观察物体2",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "小明看到立体图形的一个面是□,这个立体图形是我们学过的()。",
+    "options": [
+      "A. ![](images/c568a5112a724a793213dd3db6841861f6fa11722d595b028d02f9de311c753f.jpg)",
+      "B. ![](images/05f7b46acc7e920001c8500586a7ce876cac835a1d69368113f9579610f1dfea.jpg)",
+      "C. ![](images/789247849b99622ebf0e3403e07ea8fdeca98ee47f6f019fd24309b9bfb233fc.jpg)"
+    ],
+    "answer": "A",
+    "solution": "【分析】正方体从各个面看到的是正方形;圆柱从上下面看到的是圆，侧面看到的是长方形;圆锥从底面看到的是圆，侧面看到的是三角形，据此判断.\n【详解】A。从每个面看到的都是正方形，符合题意;B。从任何一个面看不到正方形，不符合题意;C。从任何一个面看不到正方形，不符合题意。故答案为:A",
+    "knowledge_points": [
+      "立体图形的认识",
+      "长方形，正方形，三角形和圆的初步认识",
+      "从不同位置观察单个物体"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "238",
+    "unit": "第五单元 观察物体2",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "![](images/e06e1cd967c7db2b91ffc6cb236441e8f6d4d5f01cbcdb09c525fc0935382679.jpg)\n\n是()看到的.\n\n![](images/8f8afa527aac1625fd38766956afbe956e5dc6212f2bdca8e7bc27d03861b367.jpg)",
+    "options": [
+      "A. 月月",
+      "B. 天天",
+      "C. 玲玲",
+      "D. 都不是"
+    ],
+    "answer": "B",
+    "solution": "【分析】观察这个冰箱可知，月月和玲玲都是从冰箱的侧面看的，不能看到冰箱门。而天天是从冰箱的正面看到，能看到冰箱门.\n![](images/68a280c82e05d56c13d2025a4eed3317008b48816e5c0bbcd968c303c6eaf4b2.jpg)\n中可以看到冰箱门，即这是天天看到的。本题考查了从不同的方向观察物体，需要学生有较强的空间想象和推理能力.\n【详解】根据分析可知,![](images/74dd20772c03f33302a587efe0579c9edc8d91753dab82bc15d47279b916c2f5.jpg)是天天看到的。故答案为:B.",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "239",
+    "unit": "第五单元 观察物体2",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "从正面观察![](images/2026-03-04%20001355.jpg)看到的形状是()。",
+    "options": [
+      "A. ![](images/fba8ac17898d58723cde659bb9ef6672f96096ce4b6ae22570fd236c4cd03419.jpg)",
+      "B. ![](images/e11234b1b9d587475ba445bbfe662826f33f0acbfdad8d67217df126881672da.jpg)",
+      "C. ![](images/6c913016e53eb86e886a1e6aca8fea79f8dbc60a08ea4d2d797cda79c7f62cad.jpg)"
+    ],
+    "answer": "C",
+    "solution": "【分析】从正面观察圆柱体，应该是正方形或长方形，结合图示可知，从正面观察这个圆柱体，看到的形状是长方形.\n【详解】由分析得：从正面观察，看到的形状是C。故答案为:C",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "240",
+    "unit": "第五单元 观察物体2",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "乌龟看到的是().\n\n![](images/f4540e2f8b9133e6e35c04f82346498e0581bd077b5ec72c0e82e377038630e2.jpg)",
+    "options": [
+      "A. ![](images/008cc9cce696d37eb4bb801715bef07f6a0d43dc5a8c908775f48178cf08caf4.jpg)",
+      "B. ![](images/790840911ae669a8a576ee2966cf025e16958299a5b0558a1ff6580f55e198cf.jpg)",
+      "C. ![](images/9ae7d5a2241160e1cbcaf24c9de1c10526d4a423d1c93dcf7e8120dd9fc4a394.jpg)"
+    ],
+    "answer": "A",
+    "solution": "【分析】可结合几个小动物相对于组合体的不同位置，对它们看到的形状有所判断，再做选择即可.\n【详解】A。小鸟位于组合体的正上方，看到的是C;B。小鸭位于组合体的左面，看到的是B;C。乌龟位于组合体的前面，看到的是A。故答案为:A",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "241",
+    "unit": "第五单元 观察物体2",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "从上面看是().\n\n![](images/a6f54d744007f38d726023d3dbd65a067d48fa93483ea22247de8da797493af0.jpg)",
+    "options": [
+      "A. ![](images/5370df5650f031d5700fc13d13d30df49f52f9dc1bfb60256dd480d22fc60b55.jpg)",
+      "B. ![](images/06fecdd38a016bc42c4aed1c52f680fc170d7b5c655ae9d131a32a6b180a9b46.jpg)",
+      "C. ![](images/9bd5573148c8a030ec73cfdf5beb4f1d17f5934303607bc011a3bed9a9cd91cf.jpg)"
+    ],
+    "answer": "C",
+    "solution": "【分析】本题考查从上面观察立体图形。图中是一个立体图形(可能是由小正方体搭成或单个立体图形),从上面看，看到的是这个立体图形的俯视图，即从上往下投影的形状.\n【详解】从上面观察这个立体图形，看到的形状与选项C中的图形一致。故答案为:C",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "242",
+    "unit": "第五单元 观察物体2",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下图从后边看，看到的形状是().\n\n![](images/4735cbb2898364bec1033758c56b7e05e66815cbd38911ecdc925dcf7930ee98.jpg)",
+    "options": [
+      "A. ![](images/0eb44bf7ce1e2c2b5b2c2149d168cdb0fa78a09558b7798448dd45f49aedd99d.jpg)",
+      "B. ![](images/428d36f437a3d424fd14803bbc449f65ed4dde84b404660ee44ca77df391d692.jpg)",
+      "C. ![](images/b196eabae0fe3b98d925df1a17d6137f7a0a73d80b597d508f3760424d6c1957.jpg)",
+      "D. ![](images/d49188548db037fef89486cde6db896df9b9ef9d67958d946f1e6567871f7962.jpg)"
+    ],
+    "answer": "D",
+    "solution": "【分析】本题考查从后面观察物体。从后边看，看到的是物体的背面，与从前面看看到的形状是左右相反的。需要根据图中物体的形状，判断从后面看到的图形是哪个选项.\n【详解】从后边观察这个物体，看到的形状与选项D中的图形一致。故答案为:D",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "243",
+    "unit": "第五单元 观察物体2",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "从不同角度观察到的物体形状()。",
+    "options": [
+      "A. 相同",
+      "B. 不一定相同",
+      "C. 一定不同"
+    ],
+    "answer": "B",
+    "solution": "【分析】本题考查从不同方向观察物体。从不同角度观察同一个物体，看到的形状可能相同，也可能不同，取决于物体的形状和观察角度。例如，观察球体从任何方向看都是圆形，形状相同;观察长方体从不同方向看可能看到不同的面。所以从不同角度观察到的物体形状不一定相同.\n【详解】从不同角度观察物体，看到的形状可能相同(如球体),也可能不同(如长方体),所以不一定相同。故答案为:B",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "244",
+    "unit": "第五单元 观察物体2",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "观察下面的物体，从前面看到的是().\n\n![](images/ce914037900f4ebfddc2ef8d02147d875c39a2a92ae6d36f0c5430a9c4a1a211.jpg)",
+    "options": [
+      "A. ![](images/2026-03-04%20001900.jpg)",
+      "B. ![](images/2026-03-04%20001910.jpg)",
+      "C. ![](images/0d5ea84e22a23cc9debcb7b0d84c0a91d9aa871aead390c8c8d0817e3851cd89.jpg)",
+      "D. ![](images/2026-03-04%20001928.jpg)"
+    ],
+    "answer": "D",
+    "solution": "【分析】逐个观察选项给出的图，是从哪个位置看到的，再进行选择;据此解答.\n【详解】根据分析:A。是从后面看到的;B。是从上面看到的;C。是从左侧面看到的;D。是从正面看到的。故答案为:D",
+    "knowledge_points": [
+      "从不同位置观察两个物体的相互关系"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "245",
+    "unit": "第五单元 观察物体2",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "小老鼠从上面观察下面四个物体,![](images/2026-03-04%20002040.jpg)是从()号物体看到的。",
+    "options": [
+      "A. ![](images/8ae204ab4ad26268f44d13dc74b228f2f5d83309c153475958d8c916b2481747.jpg)",
+      "B. ![](images/37e17479238dd34cb9ff349035197a0c6ae11a19bd0a036e7301e205d41416cc.jpg)",
+      "C. ![](images/6244ac4ecf5b6f8150aed997617e46697dc25305efe1045f58a47c48787b4034.jpg)",
+      "D. ![](images/9d12220d280eb241d22c0c536d92aadae26422774d3bdfceac8778a7a0571e34.jpg)"
+    ],
+    "answer": "B",
+    "solution": "【分析】本题考查从上面观察物体。小老鼠从上面观察四个物体，看到的形状是某个图形，需要判断这个图形是从几号物体看到的。根据图中物体的摆放和形状，从上往下看，每个物体的俯视图不同.\n【详解】从上面看到的形状与选项B中的图形一致，说明这个形状是从B号物体看到的。故答案为:B",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "246",
+    "unit": "第五单元 观察物体2",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下边的圆柱从左面看是().\n\n![](images/3c4f4142f1f68295da747f726e1d521327f94fb0a0ab5405739c5a35bff58db1.jpg)",
+    "options": [
+      "A. 圆形",
+      "B. 正方形",
+      "C. 长方形",
+      "D. 球"
+    ],
+    "answer": "C",
+    "solution": "【分析】本题考查从不同方向观察圆柱。圆柱从左面看(即从侧面看),看到的是一个长方形(或正方形，取决于圆柱的高度和底面直径的关系，但通常圆柱侧面看是长方形)。从上面或下面看才是圆形.\n【详解】圆柱从左面看，看到的是长方形。故答案为:C",
+    "knowledge_points": [
+      "正方形的概念及特点",
+      "从不同位置观察单个物体"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "247",
+    "unit": "第五单元 观察物体2",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "观察下图，小云看到的是图().\n\n![](images/96a959a28339d65e40602dac133bec12b0a6065d6f89030a579ea06f1b9a4361.jpg)",
+    "options": [
+      "A. ![](images/c871e20a0de967bc1639bb2ac9584cadbdccd6ff1ac32fda25291bf8c86bbf64.jpg)",
+      "B. ![](images/11bc7e40fb59933672a84d384ef2e9941d42f15f026092b9532e22821f1b1b71.jpg)",
+      "C. ![](images/3a5f7272c5490c926261955bf0d24c64ed7e8217fc24f53432e2b33e7f815b97.jpg)"
+    ],
+    "answer": "C",
+    "solution": "【分析】本题考查从不同方向观察物体。小云站在某个位置观察物体，她看到的形状取决于她的观察角度。需要根据图中物体的摆放和小云的位置，判断她看到的图形是哪个选项.\n【详解】根据小云的观察位置，她看到的形状与选项C中的图形一致。故答案为:C",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "248",
+    "unit": "第五单元 观察物体2",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "小红，小玉和小美给小胖拍照，照片()是小玉拍的.\n\n![](images/07afba9d12a169e8bf25cd2d58323248da2b156ab2b4c41f99237af8cf82c844.jpg)",
+    "options": [
+      "A. ![](images/ff25bdd255b67b18b4b744765aaf5ec60e194c1651a4aff16343e4b92557add0.jpg)",
+      "B. ![](images/5ac0876bea47b3fe35d209565f26d037c30166a494cfbb19d597e886c3492a19.jpg)",
+      "C. ![](images/6dc50f76e86794dafc9d2eb707cfcdbf96b88d5e97c708b63b201d4e7c065a4e.jpg)"
+    ],
+    "answer": "C",
+    "solution": "【分析】本题考查从不同方向观察物体。小红，小玉和小美站在不同的位置给小胖拍照，她们拍到的照片角度不同。小玉站在某个位置，她拍到的照片应该是从那个方向看到的形状.\n【详解】根据图中三人的位置，小玉拍到的照片与选项C中的图形一致。故答案为:C",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "249",
+    "unit": "第五单元 观察物体2",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "从不同方向观察下面立体图形，看到形状都一样的是()。",
+    "options": [
+      "A. ![](images/8ea39aa695e37451f1cf7b1cf36e4ddf9106299c4eb151736f120b20216d1a40.jpg)",
+      "B. ![](images/11ed301a628346872f4cb755860b972f08faba7f3e4f7fc1680efb44e379d15f.jpg)",
+      "C. ![](images/23190d6a50045c6aa590d825f2c300abdcff418b4647ee540f1c649409d3071f.jpg)"
+    ],
+    "answer": "B",
+    "solution": "【分析】从不同方向观察立体图形，一般是从上面或下面，左面或右面，前面或后面;有的物体看到的形状不同，有的看到的形状都一样，依次分析判断.\n【详解】A。从上面或下面看到的是正方形，从左面或右面看到的是长方形，从前面或后面看到的是长方形，看到的形状不完全相同;B。从任何方向看到的都是圆，看到的形状都一样;C。从上面或下面看到的是圆，从侧面看到的是长方形，看到的形状不完全相同。故答案为:B",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "250",
+    "unit": "第五单元 观察物体2",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "如图:\n\n![](images/0f8095505b7889d093584851d63e4ac72eda1d27e954fb3f5edb77b159ab5dcf.jpg)\n\n![](images/6b41089665cc2a9a5db300e2dbce5e2af4faa3f71ef590e5f0567036db5fbb9a.jpg)\n看到的是()。",
+    "options": [
+      "A. ![](images/ec7c313b200a6fec926c4641bc004cd26c1acff2728fdb7fb2cb407942b11fc9.jpg)",
+      "B. ![](images/c7420365cb3ac21d9f28c352af8d4015222acd17596269a692a32220e8fdb498.jpg)",
+      "C. ![](images/872616b67e8ca405ae29b18e441555fac76469f452afc9bb4ed3a5fed2baadc5.jpg)"
+    ],
+    "answer": "B",
+    "solution": "【分析】本题是从前面观察物体，根据物体前面的特征即可找出答案。此题考查了从不同方向观察物体和几何体的方法.\n【详解】解：从前面看：有把手图案，靠上方有一条线，所以B正确。故选:B.",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "251",
+    "unit": "第五单元 观察物体2",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "从上面观察下边的物体，看到的形状是().\n\n![](images/71ecd7bd56164a04224680f64237b848453883495c52840884061bf91ff66624.jpg)",
+    "options": [
+      "A. ![](images/853dfbbcc5a0ea3e17aee8b42f0394504e367265fddd8eb54c832905531ed9a7.jpg)",
+      "B. ![](images/c83ff2b69d906bab18a16bea75d4b6d5e5c59e8b6a1261f616b707da0000e2f2.jpg)",
+      "C. ![](images/2952add292ef3d4d4c13472d174afe391013746fd715a3318a3abcd8a1dce041.jpg)"
+    ],
+    "answer": "A",
+    "solution": "【分析】本题考查从上面观察由多个物体组成的图形。从上面看，看到的是每个物体在水平面上的投影，以及它们之间的相对位置关系。需要根据图中物体的摆放位置，判断从上面看到的形状.\n【详解】从上面观察图中的物体，看到的形状与选项A中的图形一致。故答案为:A",
+    "knowledge_points": [
+      "从不同位置观察两个物体的相互关系"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "252",
+    "unit": "第五单元 观察物体2",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "小白兔看到的图形是().\n\n![](images/ca386168606302ad966e1a008d0d0e3f1d3bc1520706afc500a554729f5e5b1a.jpg)",
+    "options": [
+      "A. ![](images/775919a39e82c139a1ee7a5fe9d03f296d6a5b96cc94ccfa0412ab90149a5adb.jpg)",
+      "B. ![](images/799b28e0e8ff311c2c0f57ddfcabec52a4918ad056119a51a6ac41ca6e26dac9.jpg)",
+      "C. ![](images/eeb6b5cad7767cf85a9c2520ac6a7427dc7ac38ad08f648a171764782930e5a3.jpg)"
+    ],
+    "answer": "C",
+    "solution": "【分析】观察图形可知，小白兔看到的图形中，树在右边，房子在左边。且烟囱远离树的一边，即靠左边。本题考查了从不同的方向观察物体，需要学生有较强的空间想象和推理能力.\n【详解】小白兔看到的图形是![](images/e4509b1bb69e56a6f9637fe89c30c511148e9e80ad37666d177d85d6eeedd8f1.jpg)。故答案为:C.",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "253",
+    "unit": "第五单元 观察物体2",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "如图，丽丽从门外看妈妈，看到的是图().\n\n![](images/5f3804ccfc6278fb52374b692da8dbfb6c8150b1b6f48ded93c7e8bd0cc2c9e9.jpg)",
+    "options": [
+      "A. ![](images/c07a38fec03a17f9b55cddabee0c5addaa45a513bdb7b00e05876cb6282204d0.jpg)",
+      "B. ![](images/944d1caf905b0d4b84a588dbe15ced31ab44b2a6242918e157b65b6f97318ec1.jpg)",
+      "C. ![](images/dcb9062167505a950e361ab185ac4ef20adec0f459e3ea7afa8accc0b12391c9.jpg)",
+      "D. ![](images/1f55e687eaa0678384956892ab6aec98b1340a98777b9889fba19794b009dae6.jpg)"
+    ],
+    "answer": "D",
+    "solution": "【分析】观察图形可知，丽丽从门外看妈妈，看到的是妈妈的背影。拖把头在妈妈的左脚边。本题考查了从不同的方向观察物体，需要学生有较强的空间想象和推理能力.\n【详解】丽丽从门外看妈妈，看到的是![](images/8fd350f8c9f4933bfe450c2a6d3db35e15f8d7349215f7290abc5072a4fb361f.jpg)。故答案为:D.",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "254",
+    "unit": "第五单元 观察物体2",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "![](images/2026-03-04%20002654.jpg)是()看到的.\n\n![](images/b58e5a2846ee3b39e16ac2430f8c7d027766118c1395774555289a984111459b.jpg)",
+    "options": [
+      "A. 小刺猬",
+      "B. 小鸭子",
+      "C. 长颈鹿"
+    ],
+    "answer": "A",
+    "solution": "【分析】本题考查从不同方向观察物体。图中给出了一个场景，几个小动物从不同方向观察同一个物体，某个小动物看到的形状如图所示，需要判断这个形状是哪个小动物看到的.\n【详解】根据图中各个小动物的位置和观察方向，这个形状是小刺猬看到的。故答案为:A",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "255",
+    "unit": "第五单元 观察物体2",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "看到的立体图形中有一个面是正方形，这个立体图形不可能是()。",
+    "options": [
+      "A. ![](images/5015f3986e3499881bed1f17fd15c15488179ea7955b668ad86751a2d37a20bd.jpg)",
+      "B. ![](images/e039a96cb56ff059637ee70bffa30461d95ef729e3e7f3c6effe652c36e4d702.jpg)",
+      "C. ![](images/1ffa186935b5dc7db8256c1748c6c215438c1bbd172330dcac5607bbeeaff4cf.jpg)",
+      "D. ![](images/28d15ab9589985b58b86086cb1b25721c13911a7b2eaffcf5d10933db3276ccb.jpg)"
+    ],
+    "answer": "D",
+    "solution": "【分析】本题考查从不同方向观察立体图形。看到的立体图形中有一个面是正方形，说明这个立体图形至少有一个面是正方形。需要判断哪个立体图形不可能有正方形面.\n【详解】选项A是正方体，每个面都是正方形;选项B和C都是长方体，可能有正方形面;选项D是球，没有任何面是正方形，所以不可能是球。故答案为:D",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "256",
+    "unit": "第五单元 观察物体2",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "![](images/76abb6db636863e43dc9f12abdda615eba098c23fdc0e006913aec564c19503e.jpg)从右面看到的是()。",
+    "options": [
+      "A. ![](images/136fdcbd4ee7ff8a71f55243cff39b9683267e791186e9fb2ffb9975c2f2cfda.jpg)",
+      "B. ![](images/89d9d3de90ec0c260e9bc20313864162d64dcbbf42832aff896edc29baf30bba.jpg)",
+      "C. ![](images/f2fdc6d2c8571c7f50053e454b82abd6e87e3863f9dd879acc2c8acad7835c0f.jpg)"
+    ],
+    "answer": "A",
+    "solution": "【分析】本题考查从右面观察立体图形。从右面看，看到的是物体右侧面的形状，与从左面看到的形状是左右相反的。需要根据图中物体的形状，判断从右面看到的图形是哪个选项.\n【详解】从右面观察图中的物体，看到的形状与选项A中的图形一致。故答案为:A",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "257",
+    "unit": "第五单元 观察物体2",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "下面的物体从右面看到的图形是().\n\n![](images/8f7ae9a88835af3c184b9b0ccf1e22ffe5bbcf3082a36f3e76ba6d689a2fe287.jpg)",
+    "options": [
+      "A. ![](images/cd939a1090a6bf61fe60aa3cfd7410a55963a4d14cb5d9a1713fd26b784856cc.jpg)",
+      "B. ![](images/715ad10fa40eaf75156dd90f1041fd007833ecc7e8eaa70d29faf8adb90a1b76.jpg)",
+      "C. ![](images/2fdc7c823c344c41448e4b124133a80e9f55fa42eb0d7e56275d3ee5f0b30b9d.jpg)"
+    ],
+    "answer": "A",
+    "solution": "【分析】假设自己是观察者，先按照题意站在不同方向看物体是什么形状。从图中可知这个物体是一栋房子。它的右下面有个长方形的门，屋顶上有烟囱。根据特征进行判断.\n【详解】在三个选项中,C是从上往下看到的图形;B是从前面看到的，烟囱在左上方，前面没有门。A是从右面看到的，有门而且烟囱在后上方。故答案为:A",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "258",
+    "unit": "第五单元 观察物体2",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "![](images/8dad90e24ad4fa7800f0f56621acfdf5b24dbf4aa7807264950b7242f4bbe183.jpg)从上面看到的图形是()。",
+    "options": [
+      "A. ![](images/869c647f18ba3ef8be885b21e3c1e2f8d134f63479486350047e238569b1c39b.jpg)",
+      "B. ![](images/ce7bfd9847b47998dfb0e37fe913b8c3272e029e0f9c541649e3359b9b60a70e.jpg)",
+      "C. ![](images/90194bd7949de9caf0564849e23c38837d8714a4a4d167c26db9ed1177285328.jpg)",
+      "D. ![](images/fcec4097384c9243df4f1ecd93adbd77807c21908ff79be23b5991f54d9214cf.jpg)"
+    ],
+    "answer": "D",
+    "solution": "【分析】本题考查从上面观察立体图形。从上面看，看到的是物体从上往下投影的形状，即每个小正方体在水平面上的投影，需要根据立体图形的摆放判断上面看到的图形.\n【详解】从上面观察图中的立体图形，看到的形状与选项D中的图形一致。故答案为:D",
+    "knowledge_points": [
+      "物体三视图的认识"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "259",
+    "unit": "第五单元 观察物体2",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "从不同的方向观察下面的立体图形，看到的形状都一样的是()。",
+    "options": [
+      "A. ![](images/6ec0c67b76c2e0902ab65c70c412c7a729d2aaa2247083c80f0ef4f30efbcb83.jpg)",
+      "B. ![](images/b35643b6735c6753babdba46d7e4f1f51277991062316be631d6225ea5914a07.jpg)",
+      "C. ![](images/6c61a81da2f99df36e3a8eda32d1ba2d75a43b934dd2f3d2930b11f78ecb9809.jpg)",
+      "D. ![](images/875794243f3c36948292a42204b3481de2afec7bcc3d7457e8aa56489cc1dad4.jpg)"
+    ],
+    "answer": "D",
+    "solution": "【分析】本题考查从不同方向观察立体图形。从不同的方向观察同一个立体图形，看到的形状可能相同，也可能不同。需要找出哪个立体图形从任何方向看，形状都一样.\n【详解】选项A是长方体，从不同方向看可能看到长方形或正方形，形状不同;选项B是圆柱，从侧面看是长方形，从上面或下面看是圆形，形状不同;选项C是圆锥，从侧面看是三角形，从下面看是圆形，形状不同;选项D是球，从任何方向看都是圆形，形状相同。所以从不同的方向观察球，看到的形状都一样。故答案为:D",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "260",
+    "unit": "第五单元 观察物体2",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "从不同的方向观察![](images/50148a8fe6019c34116f9bd434b5e12a7659344d0b801abe02333acb55807646.jpg),看到的形状不可能是()。",
+    "options": [
+      "A. ![](images/b5c7d9e248f07253c97733305b602d4bcb2ac1cf7ee870bfc619502a1acffcd0.jpg)",
+      "B. ![](images/2bc19f8927958af213429b3fb65f1f14780ed10fdee3f71a8766a9fd437c3b6c.jpg)",
+      "C. ![](images/cfba96a6d34b4c010e6282e75e01a6b414046fefcae3901fb7b72e7cfa391981.jpg)",
+      "D. ![](images/a9e7f26bd9c47acfaef4706a1feea90247b3deca5940cabf45dc118b0599dc7c.jpg)"
+    ],
+    "answer": "C",
+    "solution": "【分析】本题考查从不同方向观察立体图形。图中是一个长方体(或正方体),从不同的方向观察，可能看到长方形或正方形，但不可能看到圆形.\n【详解】长方体或正方体的每个面都是长方形或正方形，不可能有圆形。所以从不同方向观察，看到的形状不可能是圆形。故答案为:C",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "261",
+    "unit": "第五单元 观察物体2",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "从上面观察下图中的玩具车，看到的是().\n\n![](images/c0eee667c5cb2047d8a34ad597e1fce4b696bcdcac024535cdc4710b1ea4874e.jpg)",
+    "options": [
+      "A. ![](images/bcae0a7e124fef010e3f01cba3d82cdb1118ce70fc9e941bde9947a02527486a.jpg)",
+      "B. ![](images/c42d096096b019631fb548c249859a2c28116733df49d985c20ecdbe43323766.jpg)",
+      "C. ![](images/6bdb81b6aa2d9cb159c35d8a6ffc72a353890afec9be79625ea72b63254819bc.jpg)"
+    ],
+    "answer": "C",
+    "solution": "【分析】根据题图可知，从上面可以看到车的车顶，据此解答。本题考查观察物体，旨在考查学生的空间想象和推理能力.\n【详解】由分析可得：从上面看到的是C。故答案为:C",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "262",
+    "unit": "第五单元 观察物体2",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "仔细观察下图，从正面看到的图形是().\n\n![](images/38717e73dc64636b1a319f83ff5de26a2d765d3f12a5a3109152f1d1e0e8f3d6.jpg)",
+    "options": [
+      "A. ![](images/7c5d4ee18a50b196d826ab4e33bb730fe59aaca17eb17d517822284a3dc53be9.jpg)",
+      "B. ![](images/ffdd4b17d30209d2b35af6fd080b2a93de5277553d768ce78ae602d08fd045fd.jpg)",
+      "C. ![](images/1b103c9e4bb02d5807049662a965e2bb8852c8203768e2d44ead210e89842a3a.jpg)"
+    ],
+    "answer": "B",
+    "solution": "【分析】本题考查从正面观察立体图形。从正面看，看到的是物体正面的形状，即面对观察者的一面。需要根据图中物体的摆放，判断从正面看到的图形是哪个选项.\n【详解】从正面观察图中的物体，看到的形状与选项B中的图形一致。故答案为:B",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "263",
+    "unit": "第五单元 观察物体2",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "如图，图中乐乐看到的是().\n\n![](images/fb978390fde75935ef4e01dda8700362be2cfa0985c964ab6af1d6e8499adc15.jpg)",
+    "options": [
+      "A. ![](images/71914c42e23b45a86618102029be5b0384adcd0df761318260c2728f2c677a86.jpg)",
+      "B. ![](images/b57e7b421f44e4d4514d5f91f124576664059a7aab2e39d36be4814d8ffdeeb3.jpg)",
+      "C. ![](images/043530a557cd3475437e919417680fa096dc58b25daf0cc6e8eb75220b8c13a5.jpg)"
+    ],
+    "answer": "B",
+    "solution": "【分析】观察同一物体，从不同的位置观察物体，所看到的形状是不同的;但有特殊情况，如果这个物体是圆柱体，那么从正面，侧面看到的都是一个长方形，从上面看到的是一个圆形，球体不论从哪一个角度看到的形状都是圆形，据此可解。此题考查了从不同方向观察物体和几何体，锻炼了学生的空间想象力和抽象思维能力.\n【详解】观察物体从图中看到的，也就是乐乐从正面看到的是B。故答案为:B",
+    "knowledge_points": [
+      "从不同位置观察两个物体的相互关系"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "264",
+    "unit": "第五单元 观察物体2",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "如下图，从上面观察，所看到的图形是().\n\n![](images/f60da525a1686d3d9c1f8a3f80e15af454f0ad559776904b4dc6e8c68f497baf.jpg)",
+    "options": [
+      "A. ![](images/d7f67bbc261b04b3ee0322e199424f665153c63a329eafa386b2660c305549b7.jpg)",
+      "B. ![](images/622d706da423fd74ca701051dd2a3dfc0ecdc81f94f0f1cb83ac52d978955226.jpg)",
+      "C. ![](images/97e41146f306f43e0a5627b8e2fe442616c636092d01139b518a10d1e453e6a0.jpg)"
+    ],
+    "answer": "B",
+    "solution": "【分析】从上面观察几何体所看到的几何图形是它的俯视图，横着放的圆柱从上面看是长方形。据此解答。本题是一道三视图方面的题目，可以用\"排除法\"做题，更加简便.\n【详解】A。从上面看，不会看到右侧的圆形，所以错误;B。从上面看是长方形，本选项正确;C。从上面看也不会看到圆形，所以错误。故答案为:B.",
+    "knowledge_points": [
+      "物体三视图的认识"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "265",
+    "unit": "第五单元 观察物体2",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "观察1个粉笔盒，一次最多可以看到()个面。",
+    "options": [
+      "A. 二",
+      "B. 三",
+      "C. 四"
+    ],
+    "answer": "B",
+    "solution": "【分析】粉笔盒一般是一个长方体形状，从不同角度看到的面的个数是不同的，从一条棱可以看到2个面，从一个顶点可以看到3个面，据此解答即可。考查从不同方向观察物体。一个长方体或正方体一次最多看到3个面，最少可以看到1个面.\n【详解】由分析可知，观察1个粉笔盒，一次最多可以看到3个面。故答案为:B",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "266",
+    "unit": "第五单元 观察物体2",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "从不同的角度观察一个这样的纸巾盒，最多能看到()个面，最少能看到()个面.\n\n![](images/b1b7c2df16066c09d9372cbb1b4132fab4ae06b6fec57d8bda5dcb7ac958b9ef.jpg)",
+    "options": [],
+    "answer": "3;1",
+    "solution": "【分析】如下图所示，当站在A的前面看时，能看到3个面，站在B的前面看时，能看到2个面，从C的位置看时，能看到1个面，据此解答即可。此题考查了从不同方向观察物体和几何体，培养了学生的空间想象力和抽象思维能力.\n【详解】3>2>1，根据分析可知，从不同的角度观察一个这样的纸巾盒，最多能看到3个面，最少能看到1个面。",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "267",
+    "unit": "第五单元 观察物体2",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "下边的三张图片分别是在哪个位置看到的。请将序号填在括号里.\n\n![](images/f01ce941ca6914aa29c07c7dc6c017f3188f5a33e789c92d50d3b807fee01c53.jpg)\n\n![](images/5e67a2710a8a0f7c365d7f5022a66febb89bb9e500120caad85bc208bb8cfa08.jpg)\n\n![](images/79468d2d60fc5dd486abd67dbc24aaa41d470ba95b83dafe9928a33d7488f26f.jpg)\n\n![](images/f557f0110784aae993cf6f4e43f0aa4e44f4d3cf7c36c670f2286d696972cc7b.jpg)\n\n( );( );( )",
+    "options": [],
+    "answer": "③;②;①",
+    "solution": "【分析】本题考查从不同位置观察物体，并判断对应视图。图中给出了三个不同角度拍摄的图片，需要根据物体的形状特征和观察方向，判断每张图片分别是从哪个位置(①,②,③)看到的.\n【详解】从位置①看到的形状对应第三张图片;从位置②看到的形状对应第二张图片;从位置③看到的形状对应第一张图片。所以括号中依次填③,②,①。故答案为:③②①",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "268",
+    "unit": "第五单元 观察物体2",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "下面三幅图分别是谁看到的。填一填.\n![](images/2026-03-04%20003740.jpg)\n\n![](images/36795299796601da5984a88c3bef71ba0b03f3b4c8f33011c1c8972daa0786c2.jpg)\n\n![](images/0286d267ac4eebd3a1fb55d84351a6286ace89357f29e9db8a2367dd4b865df7.jpg)\n\n![](images/f82819b12ec1ed6bca41c9f089db043416302a943dc984f7451d962adcc60c82.jpg)\n\n( );( );( )",
+    "options": [],
+    "answer": "小玲;小刚;小红",
+    "solution": "【分析】根据图示，小玲看到的是壶的侧面，壶嘴朝右;小红看到的是壶嘴;小刚看到的是壶的侧面，壶嘴朝左，据此解答即可。本题是考查从不同方向观察物体和几何图形，关键是培养学生的观察能力.\n【详解】根据分析，作答如下:![](images/8dea4f9da749d61be2ad0f669fabaab2ab997fbc5abcccc9a7a1826e1d7c5f5c.jpg)",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "269",
+    "unit": "第五单元 观察物体2",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "站在不同的位置看文具盒，最多能看到()个面。",
+    "options": [],
+    "answer": "3",
+    "solution": "【分析】我们从文具盒的一个面观察，只能看是它1个面，从它的一条棱观察，能看到它的2个面，从它的一个顶点观察，能看到它的3个面，且最多能看到3个面，据此解答。本题是考查从不同方向观察物体的知识.\n【详解】根据分析可知，站在不同的位置看文具盒，最多能看到3个面。",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "270",
+    "unit": "第五单元 观察物体2",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "从不同角度观察魔方，每次最多可能看到()个面，最少可以看到()个面。",
+    "options": [],
+    "answer": "3;1",
+    "solution": "【分析】从不同角度看一个正方体，看到面的个数是不同的，从一个面看，只能看到1个面;从一条棱看，只能看到2个面;从一个顶点看，可以看到3个面;因此，从不同角度看一个正方体，最多能看到3个面，最少能看到1个面。此题考查了从不同方向观察问题和几何体，锻炼了学生的空间想象力和抽象思维能力.\n【详解】据分析可得：从不同角度观察魔方，每次最多可能看到3个面，最少可以看到1个面。",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "271",
+    "unit": "第五单元 观察物体2",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "站在不同的位置观察一个长方体物体，最多可以同时看到这个物体的()个面。",
+    "options": [],
+    "answer": "3",
+    "solution": "【分析】将长方体放在桌上进行观察，当眼睛处于长方体的顶点时，所看到的面最多，是3个面;当眼睛处于长方体的一面时，所见的面最少，就是1个面;依此填空。此题考查的是从不同面观察单个物体，应熟练掌握.\n【详解】根据分析可知：站在不同的位置观察一个长方体物体，最多可以同时看到这个物体的3个面。",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "272",
+    "unit": "第五单元 观察物体2",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "一个球无论从什么方向看到的都是一个()。",
+    "options": [],
+    "answer": "圆",
+    "solution": "【分析】根据球的特征，无论从哪个方向观察，看到的轮廓都是一样的，据此分析。从不同角度方向观察物体，常常得到不同的结果，特殊图形也可能得到相同的结果.\n【详解】一个球无论从什么方向看到的都是一个圆。",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "273",
+    "unit": "第五单元 观察物体2",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "小红看到一个立体图形的一个面是长方形，这个立体图形是我们学过的，可能是(),还可能是()。",
+    "options": [],
+    "answer": "圆柱;长方体",
+    "solution": "【分析】本题考查从不同方向观察立体图形。看到一个面是长方形，说明这个立体图形有可能某个面是长方形。我们学过的立体图形中，长方体的每个面可能是长方形;圆柱从侧面看也是长方形(或正方形);正方体的每个面都是正方形，不是长方形。所以可能是圆柱或长方体.\n【详解】看到一个面是长方形，这个立体图形可能是圆柱(从侧面看),也可能是长方体(从某个面看)。故答案为：圆柱;长方体",
+    "knowledge_points": [
+      "立体图形的认识"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "274",
+    "unit": "第五单元 观察物体2",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "![](images/2026-03-04%20004017.jpg)\n\n(1)从正面看是![](images/2026-03-04%20004058.jpg)的有().\n\n(2)从上面看是![](images/2026-03-04%20004110.jpg)的有().\n\n(3)从侧面看是![](images/2026-03-04%20004123.jpg)的有()。",
+    "options": [],
+    "answer": "①⑤;①②④;②④",
+    "solution": "【分析】(1)物体①从正面看是![](images/2026-03-04%20004207.jpg);物体②从正面看是![](images/041bc42ce7e61b60335d0615202c7f69fbde8eeb64dc096924d5ba828ec8df8d.jpg)\n体④从正面看是![](images/a73ca360b1d92e5c3016ebabd13f9535cfda5e363d2e004222865bc645b4339b.jpg);物体⑤从正面看是![](images/baae720dd2818922bd4b70693eb76a450b36281c2ec053306083d9a6f7ef2630.jpg)。(2)物体①从上面看是![](images/2026-03-04%20004244.jpg);物体②从上面看是![](images/2026-03-04%20004256.jpg);物体③从上面看是![](images/09b04465e8dd22ee96a4599ac3a487fba937c2d11784813051467b2ebccf3be5.jpg);物体④从上面看是![](images/2026-03-04%20004314.jpg);物体⑤从上面看是![](images/4861254929b9ce4069732cd12c745fc5f7b93fa36141e05c4d303c74a3596b9d.jpg)\n。(3)物体①从侧面看是![](images/2026-03-04%20004329.jpg);物体②从侧面看是![](images/2026-03-04%20004345.jpg)物体③从侧面看是![](images/76ca089e2c781d87230fc03d71cf40fc576d41507e28b9086a7873e054eef2c9.jpg);物体④从侧面看是![](images/2026-03-04%20004417.jpg)物体⑤从侧面看是![](images/39078d20b1aa5579abf0bee4720311b5ddf5c5fccc41981082ebf7fef85e8433.jpg)\n【详解】(1)①⑤。(2)①②④。 (3)②④。",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "275",
+    "unit": "第五单元 观察物体2",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "从不同的方位观察下面的物体，把相应的数字填在()内.\n\n![](images/a6b22495f2fecd7e92de75ecc56570b2e71c08edf304cd5fbbbe4f56525a6b2c.jpg)\n(1)\n\n![](images/6bab5d2b6fbdb2b81eb4521f0ad02b18af501b6227d265e4a02c605c3196b2aa.jpg)\n(2)\n\n(1)图(1)侧面写的是(),正面写的是(),上面写的是().\n(2)图(2)正面写的是(),上面写的是()。",
+    "options": [],
+    "answer": "2;3;5;2;1",
+    "solution": "【分析】观察图(1)的长方体的侧面写的是2，从正面看到的是3，从上面看到的是5。观察图(2)的圆柱正面写的是2，上面看到的是1，据此解答.\n【详解】(1)图(1)侧面写的是2，正面写的是3，上面写的是5。(2)图(2)正面写的是2，上面写的是1。",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "276",
+    "unit": "第五单元 观察物体2",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "站在不同的位置观察讲台，最少看到()个面，最多可以看到()个面。",
+    "options": [],
+    "answer": "1;3",
+    "solution": "【分析】站在不同的位置观察同一个物体，每次最多能看到3个面，最少能看到1个面，由此得出答案。此题考查了从不同方向观察物体，需要学生有较强的空间想象力和抽象思维能力.\n【详解】站在不同的位置观察讲台，最少看到1个面，最多可以看到3个面。",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "277",
+    "unit": "第五单元 观察物体2",
+    "question_type": "填空题",
+    "difficulty": 0.4,
+    "question": "有一个正方体，每个面上分别写着数字1至6，从三个不同的角度观察，数字\"3\"的对面是( ).\n\n![](images/b7065c4b5291722b42027a6892bd1fbe0b242774b0d27dcd3db26ccc7f6b8164.jpg)\n\n![](images/e461df2d1ecf0492335f4e3949bbd232f060558364a4665cf0c36f2058c3cd21.jpg)\n\n![](images/99ccbc3c638714e7396da4e0dad4e963cace22da601501af976862896a802291.jpg)",
+    "options": [],
+    "answer": "5",
+    "solution": "【分析】从第一幅图可知1和2,5相邻，第二幅图可知1和3,4相邻，剩下6和1相对;从第一幅图可知5和2,1相邻，第三幅图可知5和6,4相邻，剩下3和5相对;最后只剩4和2相对。本题考查学生从不同角度观察物体，关键是认识正方体每个面与4个面相邻，剩下一个面相对.\n【详解】由分析可知2和4相对,3和5相对,1和6相对。从三个不同的角度观察，数字\"3\"的对面是5。",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "278",
+    "unit": "第五单元 观察物体2",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "把粉笔盒放到桌面上，站在不同位置看，每次最多能看到()个面。",
+    "options": [],
+    "answer": "3",
+    "solution": "【分析】观察一个正方体或长方体，从它的一个面观察，只能看到一个面，从它一条棱观察，能看到它的相交于这条棱的两个面，从它的一个顶点观察，此时能看到它最多的面，能看到它的三个面。本题考查了从不同方向观察物体和几何体的相关知识点。主要是要培养学生的观察能力.\n【详解】站在不同的位置看粉笔盒，最多能看到3个面;故答案为:3",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "279",
+    "unit": "第五单元 观察物体2",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "一个球，从不同角度观察，所看到的形状都是()。",
+    "options": [],
+    "answer": "圆形",
+    "solution": "【分析】根据球的特点来分析。认识球的特征是解题关键，可以拿一个球状物体观察实验一下.\n【详解】球是圆的，它的每个方向都是圆形。",
+    "knowledge_points": [
+      "物体三视图的认识"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "280",
+    "unit": "第五单元 观察物体2",
+    "question_type": "判断题",
+    "difficulty": 0.65,
+    "question": "同一个物体，分别站在远处和近处看，看到的物体一样。()",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】一般地，看同一个物体，从远处看到的形状小，范围大，从近处看到的形状大，范围小，据此解答。本题考查了从不同距离观察物体，需要学生们全面考虑，认真判断.\n【详解】根据分析可知：看同一个物体，从远处看和近处看，看到的大小是不同的，所以原题干说法是错误的。故答案为: ×",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "281",
+    "unit": "第五单元 观察物体2",
+    "question_type": "判断题",
+    "difficulty": 0.65,
+    "question": "小红在看一个立体图形时，正面看到的是圆，那么这个物体一定是球。()",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】观察物体最少观察3个面才能确定物体的形状，因此从一个面观察不能确定物体的形状，据此判断。本题是考查从不同方向观察物体和几何图形，是培养学生的观察能力.\n【详解】小红在看一个立体图形时，正面看到的是圆，这个物体不一定是球，也可能是横着放的圆柱体，所以原题的说法错误。故答案为: ×",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "282",
+    "unit": "第五单元 观察物体2",
+    "question_type": "判断题",
+    "difficulty": 0.65,
+    "question": "在不同的位置观察同一个长方体，看到的一定都是长方形。()",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】本题考查从不同方向观察长方体。长方体有6个面，通常情况下每个面都是长方形，但特殊的长方体(有两个相对的面是正方形)可能会有正方形的面。因此，从不同位置观察长方体，看到的可能不都是长方形，也可能是正方形.\n【详解】特殊的长方体(如底面是正方形的长方体)可能有两个相对的面是正方形，所以从某些方向观察可能看到正方形。因此，在不同位置观察同一个长方体，看到的不一定都是长方形。原题说法错误。故答案为: ×",
+    "knowledge_points": [
+      "立体图形的认识",
+      "从不同位置观察单个物体"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "283",
+    "unit": "第五单元 观察物体2",
+    "question_type": "判断题",
+    "difficulty": 0.65,
+    "question": "一个粉笔盒放在桌子上，每次最多能看到1个面。()",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】先将粉笔盒画出来(如下图所示),我们如果站在正面和右侧面之间可以看到正面，右侧面，和上面，依此判断即可。此题考查的是从不同位置观察单个物体，应熟练掌握.\n\n![](images/c7fdbaa028c44320f6991a657a71e8bdd7d6f30b100aed6b54e846667784acf8.jpg)\n【详解】根据分析可知，一个粉笔盒放在桌子上，每次最多能看到3个面。故答案为: ×",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "284",
+    "unit": "第五单元 观察物体2",
+    "question_type": "判断题",
+    "difficulty": 0.65,
+    "question": "观察物体时，从不同的位置看到的图形一定不相同。()",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】对于一般的物体，从不同的位置观察物体，所看到的形状是不同的;但有特殊情况，如果这个物体是正方体，那么从正面，侧面和上面看到的都是一个正方形，即看到的形状一样;据此判断即可。解答此题的关键：根据题意，找出反例，进行分析，进而得出结论.\n【详解】解：由分析知;当这个物体是一个正方体或球体，那么从正面，侧面和上面看到的形状都一样。故答案为: ×。",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "285",
+    "unit": "第五单元 观察物体2",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "观察物体时，最多同时看到一个物体的三个面。()",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】我们可以把一个长方体放在桌子上进行观察，当眼睛在长方体的一个顶点时，能看到的面最多，最多只有3个面。此题考查了从不同方向观察物体和几何体，锻炼了学生的空间想象力和抽象思维能力.\n【详解】由题意知，观察物体时，最多同时看到一个物体的三个面。故答案为:√",
+    "knowledge_points": [
+      "长方体的认识及特征",
+      "从不同位置观察单个物体"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "286",
+    "unit": "第五单元 观察物体2",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "观察一个正方体，最多能看到2个面。()",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】一个正方体，将正方体放在桌上进行观察，当眼睛处于正方体的顶点时，所看到的面最多，是3个面，由此解答.\n【详解】由分析可知，观察一个正方体，最多能看到3个面。原题说法错误。故答案为: ×",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "287",
+    "unit": "第五单元 观察物体2",
+    "question_type": "判断题",
+    "difficulty": 0.65,
+    "question": "从不同的方向观察同一物体时，看到的图形可能不一样。()",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】列举实例说明即可。本题是考查从不同方向观察物体和几何图形，关键是培养学生的观察能力.\n【详解】圆柱从上面看到圆形，从前面看到长方形(或正方形),所以说从不同的方向观察同一物体时，看到的图形可能不一样。所以，原题说法正确。故答案为:√",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "288",
+    "unit": "第五单元 观察物体2",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "看到的立体图形的一个面是正方形，这个立体图形可能是正方体，也可能是长方体。()",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】本题考查从不同方向观察立体图形。看到一个面是正方形，说明这个立体图形有可能某个面是正方形。正方体的每个面都是正方形，所以可能是正方体;长方体也可能有正方形面(如特殊的长方体，有两个相对的面是正方形),所以也可能是长方体。因此，这个立体图形可能是正方体，也可能是长方体.\n【详解】看到的立体图形的一个面是正方形，这个立体图形可能是正方体，也可能是长方体(如底面是正方形的长方体)。原题说法正确。故答案为:√",
+    "knowledge_points": [
+      "根据三视图确认几何体"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "289",
+    "unit": "第五单元 观察物体2",
+    "question_type": "判断题",
+    "difficulty": 0.65,
+    "question": "从不同方向观察![](images/5f4eba5dceecb3db80730b8e29d356a0778844f6ad70408b44301344748b1d98.jpg),看到的形状不可能是正方形。()",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】从不同方向观察这个长方体，前面看到的是长方形，上面看到的是长方形，侧面可能看到正方形，据此判断.\n【详解】从不同方向观察这个长方体，看到的形状可能是正方形，原题说法错误。故答案为: ×",
+    "knowledge_points": [
+      "立体图形的认识",
+      "长方形，正方形，三角形和圆的初步认识",
+      "从不同位置观察单个物体"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "290",
+    "unit": "第五单元 观察物体2",
+    "question_type": "判断题",
+    "difficulty": 0.65,
+    "question": "从不同的位置观察同一立体图形看到的形状可能是不一样的，也可能是一样的。()",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】一般情况下，从不同的角度观察同一物体，看到的形状是不同的，但是对于规则对称的物体如球体和正方体等，从不同的角度看到的形状却是相同的。本题考查从不同的方向观察物体，需要学生有较强的空间想象和推理能力.\n【详解】根据分析可知，从不同的位置观察同一物体，看到的形状可能是不一样的，也有可能是一样的，原题说法正确。故答案为:√",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "291",
+    "unit": "第五单元 观察物体2",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "如图![](images/2c6222a915e84d5d0b6826e9e7874e313418374b19d95d19df0a4151b6863bab.jpg),从右边看到的形状是![](images/2026-03-04%20010211.jpg)。()",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】本题考查从右边观察物体。从右边看到的形状，需要根据图中物体的摆放位置判断。如果从右边看到的图形与题目中给出的图形一致，则说法正确.\n【详解】从右边观察图中的物体，看到的形状与题目中给出的图形一致。原题说法正确。故答案为:√",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "292",
+    "unit": "第五单元 观察物体2",
+    "question_type": "判断题",
+    "difficulty": 0.65,
+    "question": "观察一个物体要多从几个方向看看。()",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】本题考查观察物体的方法。从不同方向观察同一个物体，看到的形状可能不同，只有多从几个方向观察，才能更全面地了解物体的形状和特征.\n【详解】观察一个物体要多从几个方向看看，这样才能更全面地认识物体。原题说法正确。故答案为:√",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "293",
+    "unit": "第五单元 观察物体2",
+    "question_type": "判断题",
+    "difficulty": 0.65,
+    "question": "从不同的方向观察同一个长方体，看到的形状一样。()",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】运用举例法：假设这个长方体上下两个底面是正方形，从上面看到的图形是正方形，从侧面看到的图形是长方形.\n【详解】解：从不同的方向观察同一个长方体，看到的形状可能不一样，例如上下底面是正方形的长方体，所以原题说法错误。故答案为: ×",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "294",
+    "unit": "第五单元 观察物体2",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "观察一个长方体形状的物体，最多只能看到三个面。()",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】从长方体的一面观察，只能看到1个面;从长方体的一条棱观察，只能看到长方体的2个面;从长方体的一个顶点观察，只能看到长方体的3个面。即站在任意位置观察同一长方体最少能看到长方体的1个面，最多能看到长方体的3个面。此题主要考查长方体的特征，感受观察范围随观察点，观察角度的变化而变化.\n【详解】观察一个长方体形状的物体，最多只能看到三个面，所以判断正确。",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "295",
+    "unit": "第五单元 观察物体2",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "在同一方位，看一个物体最多可以看到四个面。()",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】在观察物体时，从同一个方位最多能看到三个面，可能是上面，前面，左面。据此解答即可\n【详解】在同一方位，看一个物体最多可以看到三个面。故答案为: ×",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "296",
+    "unit": "第五单元 观察物体2",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "贝贝站在不同的位置看到的乒乓球都是圆形。()",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】拿出一个乒乓球进行观察，就会发现各个角度看形状都是圆形，从而得解。本题考查了从不同的方向观察物体，需要学生有较强的空间想象和推理能力.\n【详解】根据分析可知，贝贝站在不同的位置看到的乒乓球都是圆形。故答案为:√。",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "297",
+    "unit": "第五单元 观察物体2",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "两个人拍同一景点，站在不同的位置所拍到的照片是不同的。()",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】本题考查从不同位置观察物体。两个人站在不同的位置拍摄同一个景点，由于观察角度不同，拍到的照片画面也会不同，包含的景物范围和相对位置会有差异.\n【详解】站在不同的位置拍摄同一景点，所拍到的照片通常是不同的。原题说法正确。故答案为:√",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "298",
+    "unit": "第五单元 观察物体2",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "从不同的方向观察立体图形，看到的形状是不同的。()",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】一般情况下，从不同方向观察立体图形看到的形状是不同的，但是个别图形如：正方体，球体在不同的方向观察的图形却是相同的，因此得解。此题考查了从不同方向观察物体和几何体，锻炼了学生的空间想象力和创新思维能力.\n【详解】解：一般情况下，从不同方向观察立体图形看到的形状是不同的，但是对于规则对称的图形如球体和正方体等，从不同方向看到的现状却是相同的。要求我们具体问题具体分析，故此说法是错误的;故答案为: ×。",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "299",
+    "unit": "第五单元 观察物体2",
+    "question_type": "判断题",
+    "difficulty": 0.65,
+    "question": "同一种景物，在不同位置拍摄出来的画面是不同的。()",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】本题考查从不同位置观察物体。同一种景物，从不同的位置拍摄，由于视角不同，画面中景物的形状，大小，相对位置都会发生变化，所以拍摄出来的画面是不同的.\n【详解】同一种景物，在不同位置拍摄出来的画面是不同的。原题说法正确。故答案为:√",
+    "knowledge_points": [
+      "从不同位置观察单个物体",
+      "判断照片的拍摄位置"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  },
+  {
+    "id": "300",
+    "unit": "第五单元 观察物体2",
+    "question_type": "解答题",
+    "difficulty": 0.65,
+    "question": "一只![](images/13e0e4e2cf6966310bc4d60c5ea3714e63974d0eb5407f46cdcc73692cb4b5ab.jpg)有4条腿,5只青蛙一共有多少条腿。",
+    "options": [],
+    "answer": "4×5=20(条)",
+    "solution": "【分析】本题考查乘法口诀的应用。一只青蛙有4条腿，求5只青蛙一共有多少条腿，就是求5个4相加的和，可以用乘法计算.\n【详解】4×5=20(条),答:5只青蛙一共有20条腿。故答案为:4×5=20(条)",
+    "knowledge_points": [
+      "4的乘法口诀及应用"
+    ],
+    "source": "25-26 一年级上·江西九江·期中"
+  }
+]
diff --git "a/\344\272\214\345\271\264\347\272\247\351\242\230\351\233\206/\344\272\214\345\271\264\347\272\247\344\270\212/\344\272\214\345\271\264\347\272\247\344\270\212\347\254\254\345\205\253\345\215\225\345\205\203\346\220\255\351\205\215.json" "b/\344\272\214\345\271\264\347\272\247\351\242\230\351\233\206/\344\272\214\345\271\264\347\272\247\344\270\212/\344\272\214\345\271\264\347\272\247\344\270\212\347\254\254\345\205\253\345\215\225\345\205\203\346\220\255\351\205\215.json"
new file mode 100644
index 0000000000000000000000000000000000000000..5db39abf7673c93b41faa52cc9ca52d40d80886d
--- /dev/null
+++ "b/\344\272\214\345\271\264\347\272\247\351\242\230\351\233\206/\344\272\214\345\271\264\347\272\247\344\270\212/\344\272\214\345\271\264\347\272\247\344\270\212\347\254\254\345\205\253\345\215\225\345\205\203\346\220\255\351\205\215.json"
@@ -0,0 +1,8591 @@
+[
+    {
+        "id":  "1",
+        "unit":  "搭配",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "用4,5,0,7四个数字一共可以组成()个没有重复数字的两位数.",
+        "options":  [
+                        "A. 6",
+                        "B. 9",
+                        "C. 18"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】根据题意可知,将7,5,4,0这四个数字组成两位数,十位上可能是7,5,4,0不可能在十位上,据此解答.\n【详解】十位上是7时,两位数有75,74,70;十位上是5时,两位数有57,54,50;十位上是4时,两位数有47,45,40.所以共可以组成9个没有重复数字的两位数.故答案为:B",
+        "knowledge_points":  [
+                                 "数字中的组合问题"
+                             ],
+        "source":  "2025三年级上·全国·专题练习"
+    },
+    {
+        "id":  "2",
+        "unit":  "搭配",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "一个荤菜和一个素菜搭配,有()种不同的搭配方法.(荤菜:羊肉,牛肉;素菜:白菜,土豆,茄子,黄瓜)",
+        "options":  [
+                        "A. 4",
+                        "B. 6",
+                        "C. 8"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】由题可知,每种荤菜都可以和4种素菜搭配,一共有2种荤菜,则总的搭配方法为2个4种,由此解答.\n【详解】由分析得:4×2=8(种),则一个荤菜和一个素菜搭配,有8种不同的搭配方法.故答案为:C",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "24-25二年级下·安徽淮南·期末"
+    },
+    {
+        "id":  "3",
+        "unit":  "搭配",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "某班要从4名男生和3名女生中各选出1人代表班级参加比赛,有()种不同的组队方案.",
+        "options":  [
+                        "A. 7",
+                        "B. 12",
+                        "C. 15"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】从4名男生中选1人有4种选择,再从3名女生中选1人有3种选择;则1名男生搭配1名女生有3种不同组队方案,所以4名男生有3×4=12种不同组队方案;据此解决.\n【详解】3×4=12(种),即,有12种不同的组队方案.故答案为:B",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "24-25二年级下·山东济南·期中"
+    },
+    {
+        "id":  "4",
+        "unit":  "搭配",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "用2,5,8三个数字可以组成()个不同的两位数.",
+        "options":  [
+                        "A. 3",
+                        "B. 6",
+                        "C. 9"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】组成两位数,用固定十位法,先把十位固定一个数,再写出个位的数,可以写出25,28,52,58,82,85这6个不同的两位数,据此解答.\n【详解】用2,5,8三个数字可以组成:25,28,52,58,82,85,一共组成6个不同的两位数.故答案为:B",
+        "knowledge_points":  [
+                                 "数字中的组合问题"
+                             ],
+        "source":  "24-25二年级下·黑龙江佳木斯·期末"
+    },
+    {
+        "id":  "5",
+        "unit":  "搭配",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "熊大,熊二和光头强一起拍照,可以拍()张不同的照片.",
+        "options":  [
+                        "A. 3",
+                        "B. 5",
+                        "C. 6"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】用列举法,一一列举所有可能的顺序,即可得出答案.\n【详解】第一种:熊大,熊二和光头强;第二种:熊大,光头强和熊二;第三种:熊二,熊大和光头强;第四种:熊二,光头强和熊大;第五种:光头强,熊大和熊二;第六种:光头强,熊二和熊大,所以可以拍出6张不同的照片.故答案为:C",
+        "knowledge_points":  [
+                                 "排列问题"
+                             ],
+        "source":  "24-25二年级下·河北保定·期末"
+    },
+    {
+        "id":  "6",
+        "unit":  "搭配",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "用1,3,2,8组成两位数(选取的数字不相同),一共有()种不同的数字.",
+        "options":  [
+                        "A. 12",
+                        "B. 10",
+                        "C. 9",
+                        "D. 6"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】十位上是1的两位数有:13,12,18;十位上是3的两位数有:31,32,38;十位上是2的两位数有:21,23,28;十位上是8的两位数有:81,83,82;每组有3个数,有这样的4组,每组的个数乘4组,等于共有多少种不同的数字;据此解答即可.\n【详解】根据分析可得:4×3=12(种),所以,一共有12种不同的数字.故答案为:A",
+        "knowledge_points":  [
+                                 "搭配问题",
+                                 "4的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·浙江温州·期末"
+    },
+    {
+        "id":  "7",
+        "unit":  "搭配",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "小光从1张10元,1张5元,1张2元,1张1元的人民币中拿走2张,他最多拿走()元钱.",
+        "options":  [
+                        "A. 7",
+                        "B. 3",
+                        "C. 15"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】根据题意,先比较四种钱的面值大小,把面值大的两个相加,就是最多能拿走的钱数.\n【详解】10元\u003e5元\u003e2元\u003e1元,10元+5元=15元,则他最多拿走15元钱.故答案为:C",
+        "knowledge_points":  [
+                                 "搭配问题",
+                                 "十元以上人民币的认识与计算"
+                             ],
+        "source":  "24-25二年级上·河南信阳·期末"
+    },
+    {
+        "id":  "8",
+        "unit":  "搭配",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "新年到了,3个好朋友互发短信拜年,一共要发()条短信.",
+        "options":  [
+                        "A. 3",
+                        "B. 4",
+                        "C. 6"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】3个好朋友互发短信拜年,假如这三个人是A,B,C,则A需要给B和C发,B需要给A和C发,C要给A和B发,每个人都发2条,共发3个2条短信,用乘法计算即可.\n【详解】3×2=6(条),则一共要发6条短信.故答案为:C",
+        "knowledge_points":  [
+                                 "搭配问题",
+                                 "3的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·湖北武汉·期末"
+    },
+    {
+        "id":  "9",
+        "unit":  "搭配",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "一件上衣配一条裤子,有()种穿法.\n\n![](images/4cf9b482eb0fc39538be8ad3d710e1f79b0ea964580e7f213617ec6add6cd76a.jpg)\n\n![](images/9f2d61b6bc63e49cb5805884fe8a4087ea812d28341061ce045aa8bfc422a666.jpg)\n\n![](images/3b8c0f7f897215190d1d3b4a29fbf78c4c64ce3639994046ed05fffcfeea2a72.jpg)\n\n![](images/6b64f508871bf1c4591876f38a7cce847a9d2e1c49e01c8c2d0a3c566c8fc3f2.jpg)",
+        "options":  [
+                        "A. 3",
+                        "B. 4",
+                        "C. 5"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】一件上衣配一条裤子,那么1件上衣搭配2条裤子可以搭配出2种穿法,2件上衣可以搭配出2×2种穿法;据此解答.\n【详解】2×2=4(种),所以,一件上衣配一条裤子,有4种不同的穿法.故答案为:B",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "24-25二年级上·河北保定·期末"
+    },
+    {
+        "id":  "10",
+        "unit":  "搭配",
+        "question_type":  "选择题",
+        "difficulty":  0.94,
+        "question":  "用2和1两个数字组成一个两位数,一共有()种搭配.",
+        "options":  [
+                        "A. 1",
+                        "B. 2",
+                        "C. 3",
+                        "D. 4"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】用2和1两个数字组成一个两位数,十位上是2,个位上是1的数是21,或十位上是1,个位上是2的数是12,一共有2种搭配,据此解答.\n【详解】用2和1两个数字组成一个两位数,一共有2种搭配.故答案为:B",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "24-25一年级上·浙江温州·期末"
+    },
+    {
+        "id":  "11",
+        "unit":  "搭配",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "学校开运动会,亮亮,明明,壮壮和强强参加接力赛,强强冲刺能力最强,老师把他定在第四位,那么这次接力赛一共有()种不同的排法.",
+        "options":  [
+                        "A. 4",
+                        "B. 5",
+                        "C. 6"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】根据题意可知,强强是第四位,剩下的三名同学进行排队,若亮亮排第一,(1)亮亮,明明,壮壮,强强;(2)亮亮,壮壮,明明,强强;共有2种排法.若明明排第一,(1)明明,亮亮,壮壮,强强;(2)明明,壮壮,亮亮,强强;共有2种排法.若壮壮排第一,(1)壮壮,亮亮,明明,强强;(2)壮壮,明明,亮亮,强强;共有2种排法.把上面的排法相加即可解答.\n【详解】根据分析可得:2+2+2=6(种),所以,这次接力赛一共有6种不同的排法.故答案为:C",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "24-25二年级上·河南南阳·期末"
+    },
+    {
+        "id":  "12",
+        "unit":  "搭配",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "从下面3张纸币中取纸币,有()种不同的钱数.\n\n![](images/471083c6ab3ba866e0aba8513b6516eee8362726439e771f72809bdae436e83a.jpg)\n\n![](images/1b99afc07112f12fd9754874806a51220db1d84c7deca71d08e60d5c29f83788.jpg)\n\n![](images/fb991c0159ac4d72f16ffd4f981926cc0669483eeefa8fe2d49085a905dca7c1.jpg)",
+        "options":  [
+                        "A. 3",
+                        "B. 6",
+                        "C. 7"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】分别列出各种可能,然后数一数.\n【详解】取一张:5元,10元,20元.取两张:5+10=15(元),10+20=30(元),5+20=25(元),取三张:5+10+20=35(元),有7种不同的钱数.故答案为:C",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "24-25二年级上·山东菏泽·期末"
+    },
+    {
+        "id":  "13",
+        "unit":  "搭配",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "从3只熊猫中选出2只送给友国,有()种不同的选法.",
+        "options":  [
+                        "A. 6",
+                        "B. 4",
+                        "C. 3"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】列出各种可能,然后数一数.可以选第一只和第二只,第一只和第三只,第二只和第三只,共三种选法.\n【详解】由分析可知,从3只熊猫中选出2只送给友国,有3种不同的选法.故答案为:C",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "24-25二年级上·湖南湘西·期末"
+    },
+    {
+        "id":  "14",
+        "unit":  "搭配",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "从2,4,6三个数字中任意选出两个求和,得数有()种可能.",
+        "options":  [
+                        "A. 2",
+                        "B. 3",
+                        "C. 6"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】根据题意,选取任意两个数求和,组成的加法算式有2+4,2+6,4+6,据此列举解答即可.\n【详解】从2,4,6三个数字中任意选出两个求和,有以下可能:2+4=6,2+6=8,4+6=10,所以,得数一共有3种可能.故答案为:B",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "24-25二年级上·湖北随州·期末"
+    },
+    {
+        "id":  "15",
+        "unit":  "搭配",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "4个人参加乒乓球比赛,每两个人之间都要比赛一场,一共要比赛()场.",
+        "options":  [
+                        "A. 6",
+                        "B. 8",
+                        "C. 5"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】可以列举的方法来解决此题.先假设参加乒乓球比赛的4个人分别是A,B,C,D,然后把所有的比赛场次一一列举出来即可.\n【详解】假设参加乒乓球比赛的4个人分别是A,B,C,D,比赛场次如下:A和B比赛一场,A和C比赛一场,A和D比赛一场;B和C比赛一场,B和D比赛一场;C和D比赛一场;即,4个人参加乒乓球比赛,每两个人之间都要比赛一场,共要比赛6场.故答案为:A",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "24-25二年级上·辽宁抚顺·期末"
+    },
+    {
+        "id":  "16",
+        "unit":  "搭配",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "暑假期间,旅行社推出\"亲子游\"路线.从厦门经福州到上海的交通方式如图,庆庆一家从厦门到上海的出行方案一共有()种.\n\n![](images/2026-03-02%20211720.jpg)",
+        "options":  [
+                        "A. 3",
+                        "B. 4",
+                        "C. 5",
+                        "D. 6"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】根据题意可知,从厦门到福州有2种交通方式出行,从福州到上海又有2种交通出行方式,根据乘法的意义,庆庆一家从厦门到上海的出行方案一共有2×2种,据此解答即可.\n【详解】2×2=4(种),即,庆庆一家从厦门到上海的出行方案一共有4种.故答案为:B",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "24-25二年级上·福建龙岩·期末"
+    },
+    {
+        "id":  "17",
+        "unit":  "搭配",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "龙龙正在装饰教室,他要将祖冲之,华罗庚和刘徽三位数学家的画像排成一行贴在教室的墙上.一共有()种贴法.",
+        "options":  [
+                        "A. 3",
+                        "B. 6",
+                        "C. 9"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】用列举的方法,把所有的可能性一一列举出来,然后数一数有几种贴法即可.\n【详解】祖冲之,华罗庚和刘徽三位数学家的画像排成行的贴法有:①祖冲之,华罗庚,刘徽;②祖冲之,刘徽,华罗庚;③华罗庚,祖冲之,刘徽;④华罗庚,刘徽,祖冲之;⑤刘徽,祖冲之,华罗庚;⑥刘徽,华罗庚,祖冲之;共有6种贴法.故答案为:B",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "24-25二年级上·福建福州·期末"
+    },
+    {
+        "id":  "18",
+        "unit":  "搭配",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "奇奇,亮亮和康康三人下棋,如果每两人下一盘棋,那么一共要下()盘.",
+        "options":  [
+                        "A. 3",
+                        "B. 5",
+                        "C. 6"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】用列举的方法,把所有的可能性一一列举出来,然后数一数,即可解决.\n【详解】由题意分析得:奇奇和亮亮下1盘,奇奇和康康下1盘;亮亮和康康下1盘;即,奇奇,亮亮和康康三人下棋,如果每两人下一盘棋,那么一共要下3盘.故答案为:A",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "24-25二年级上·甘肃天水·期末"
+    },
+    {
+        "id":  "19",
+        "unit":  "搭配",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "如右图,每次1件上衣,1条裤子,一共有()种穿法.\n\n![](images/3e12b3b5c6e8cddf69383af4f458630e68469031415ea8704f83bc9d13b6cf36.jpg)",
+        "options":  [
+                        "A. 3",
+                        "B. 4",
+                        "C. 5"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】根据题意,每件上衣都有2条裤子可以搭配,一共有2件上衣,则总的搭配方法也就是2个2种,由此解答.\n【详解】2×2=4(种),一共有4种穿法.故答案为:B",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "24-25二年级上·内蒙古巴彦淖尔·期末"
+    },
+    {
+        "id":  "20",
+        "unit":  "搭配",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "学校组织了体育,美术和舞蹈三个兴趣小组,小亮,明明和小青每人选一个兴趣小组,但不相同.有()种选法.",
+        "options":  [
+                        "A. 4种",
+                        "B. 5种",
+                        "C. 6种"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】小亮,明明和小青每人选一个兴趣小组,通过举例,依次写出各种不同选法,然后数一数即可求解.\n【详解】小亮选体育,明明选美术,小青选舞蹈;明明选体育,小亮选美术,小青选舞蹈;小青选体育,小亮选美术,明明选舞蹈;小青选体育,明明选美术,小亮选舞蹈;小青选美术,小亮选体育,明明选舞蹈;小青选美术,明明选体育,小亮选舞蹈,一共6种选法.故答案为:C",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "24-25二年级上·黑龙江哈尔滨·期末"
+    },
+    {
+        "id":  "21",
+        "unit":  "搭配",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "聪聪打算把买的3张不同的明信片,送给浩浩,乐乐各1张,一共有()种送法.",
+        "options":  [
+                        "A. 2",
+                        "B. 3",
+                        "C. 6"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】依次列出各种送法,数一数即可求解.\n【详解】浩浩得第一张,乐乐得第二张;乐乐得第一张,浩浩得第二张;浩浩得第二张,乐乐得第三张;乐乐得第二张,浩浩得第三张;浩浩得第一张,乐乐得第三张;乐乐得第一张,浩浩得第三张,一共有6种送法.故答案为:C",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "24-25二年级上·山东日照·期末"
+    },
+    {
+        "id":  "22",
+        "unit":  "搭配",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "从小红,小华,小丽3人中选2人参加演讲比赛,有()种不同的选法.",
+        "options":  [
+                        "A. 6",
+                        "B. 3",
+                        "C. 5"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】根据题意可知:选2人参加则可选择:小红小华,小红小丽,小华小丽,3种不同的选法.\n【详解】由分析可得:有(3)种不同的选法.故答案为:B",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "24-25二年级上·河北邯郸·期末"
+    },
+    {
+        "id":  "23",
+        "unit":  "搭配",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "每两个人拥抱一次,4个人一共要拥抱().",
+        "options":  [
+                        "A. 3次",
+                        "B. 4次",
+                        "C. 6次"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】根据题意,可以假设4个人分别是甲,乙,丙,丁,然后把所有的情况一一列举出来即可.\n【详解】4个人拥抱的情况分别为:甲和乙;甲和丙;甲和丁;乙和丙;乙和丁;丙和丁.每两个人拥抱一次,4个人一共要拥抱6次.故答案为:C",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "24-25二年级上·河北保定·期末"
+    },
+    {
+        "id":  "24",
+        "unit":  "搭配",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "阳阳,明明,东东三人一起去理发店理发,理发师只有一位,所以只能一个一个顺次理发,三个小朋友的理发顺序有()种.",
+        "options":  [
+                        "A. 3",
+                        "B. 6",
+                        "C. 5"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】根据题意,当第一个人是阳阳时,后面两个小朋友可以互换位置,有2种排列顺序;当第一个人是明明时,同样后面两个小朋友可以互换位置,也有2种排列顺序;当第一个人是东东时,后面两个小朋友也可以互换位置,也有2种排列顺序,由此解答.\n【详解】排列顺序可以为:阳阳,明明,东东;阳阳,东东,明明;明明,阳阳,东东;明明,东东,阳阳;东东,阳阳,明明;东东,明明,阳阳.三个小朋友的理发顺序有6种.故答案为:B",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "24-25二年级上·吉林·期末"
+    },
+    {
+        "id":  "25",
+        "unit":  "搭配",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "妈妈想买一件外套和一条裤子,她有()种选择.\n\n![](images/2026-03-02%20212147.jpg)",
+        "options":  [
+                        "A. 4",
+                        "B. 5",
+                        "C. 6"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】外套有2种选择,每件外套搭配一条裤子,又有3种可以选择,故,妈妈想买一件外套和一条裤子,她有2×3种选择.\n【详解】2×3=6(种),即,妈妈想买一件外套和一条裤子,她有6种选择.故答案为:C",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "24-25二年级上·全国·期末"
+    },
+    {
+        "id":  "26",
+        "unit":  "搭配",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "先任选下面的两朵花插在同一个花瓶里,剩下的花插在另一个花瓶里,共有()种不同的插法.\n\n![](images/2026-03-02%20212404.jpg)",
+        "options":  [
+                        "A. 4",
+                        "B. 5",
+                        "C. 6"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】根据题意分析,用1,2,3分别代表3朵花,用4,5分别代表2个花瓶.只要先将选出的2朵花插好,另外一朵花就直接插入另一个花瓶,所以直接插选出的2朵花即可,有124,125,134,135,234,235,总共是6种插法.\n【详解】根据搭配总共有6种不同的插法.故答案为:C",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "24-25二年级上·全国·期末"
+    },
+    {
+        "id":  "27",
+        "unit":  "搭配",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "5个人参加跳棋比赛,每2个人比赛一场,一共要进行()场比赛.",
+        "options":  [
+                        "A. 8",
+                        "B. 10",
+                        "C. 12"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】第一个人和另外4人进行4场;第二个人和剩下的3人进行3场;第三个人和剩下的2人进行2场;第四个人和剩下的1人进行1场,将这些场数加起来即可.\n【详解】4+3+2+1=10(场),一共要进行10场比赛.故答案为:B",
+        "knowledge_points":  [
+                                 "搭配问题",
+                                 "比赛问题"
+                             ],
+        "source":  "24-25二年级上·吉林四平·期末"
+    },
+    {
+        "id":  "28",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "从2,4,6中任选两个数字相加,和一共有()种情况.",
+        "options":  [
+
+                    ],
+        "answer":  "3",
+        "solution":  "【分析】用列举法,2可以和4,6组合,4可以和除了2之外的数字6组合,据此解答.\n【详解】2+4=6,2+6=8,4+6=10,从2,4,6中任选两个数字相加,和一共有3种情况.",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "2025三年级上·全国·专题练习"
+    },
+    {
+        "id":  "29",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "从0,2,7中任选两个数字,能组成()个不同的两位数,其中最小的是().",
+        "options":  [
+
+                    ],
+        "answer":  "4;20",
+        "solution":  "【分析】每个两位数的十位数和个位数不能一样,且十位不能为0,则可以组成72,70,27,20,再将这些数进行比较大小,找出最小的数即可.\n【详解】根据分析可知:从0,2,7中任选两个数字组成两位数,可以组成72,70,27,20这4个两位数;72\u003e70\u003e27\u003e20,故从0,2,7中任选两个数字,能组成4个不同的两位数,其中最小的是20.",
+        "knowledge_points":  [
+                                 "含0的组数问题"
+                             ],
+        "source":  "2025三年级上·全国·专题练习"
+    },
+    {
+        "id":  "30",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "用5,7和9组成两位数,每个两位数的十位数和个位数不能一样,分别是().",
+        "options":  [
+
+                    ],
+        "answer":  "57,59,75,79,95,97",
+        "solution":  "【分析】当十位是5时,个位可以是7或9,组成的数是57,59;当十位是7时,个位可以是5或9,组成的数是75,79;当十位是9时,个位可以是5或7,组成的数是95,97,据此解答.\n【详解】由分析可知:用5,7和9组成两位数,每个两位数的十位数和个位数不能一样,分别是57,59,75,79,95,97.",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "23-24二年级上·新疆乌鲁木齐·期末"
+    },
+    {
+        "id":  "31",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "用0,3,8这3个数能组成()个不同的两位数,其中最大的数是(),最小的数是(),它们相差().",
+        "options":  [
+
+                    ],
+        "answer":  "4;83;30;53",
+        "solution":  "【分析】先把用0,3,8这三张数字卡片组成不同的两位数一一列举出来,然后比较大小,即可找出最大的数和最小的数,并作差,即可解决.根据整数大小的比较,位数多的数大于位数少的数;位数相同的数,要从高位开始一级一级的往下比较.\n【详解】用0,3,8这三张数字卡片组成不同的两位数有:30,38,80,83,一共4个;30\u003c38\u003c80\u003c83;83-30=53,则用0,3,8这三张数字卡片组成4个不同的两位数,其中最大的数是83,最小的数是30,它们相差53.",
+        "knowledge_points":  [
+                                 "搭配问题",
+                                 "100以内数的比大小",
+                                 "100以内数的组成"
+                             ],
+        "source":  "24-25二年级下·贵州铜仁·期末"
+    },
+    {
+        "id":  "32",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "用3,2,4这3张数字卡片可以摆成()个不同的两位数,最大的两位数是(),最小的两位数是(),它们的和是(),差是().",
+        "options":  [
+
+                    ],
+        "answer":  "6;43;23;66;20",
+        "solution":  "【分析】根据题意可知,列出所有两位数:十位为2的有23,24;十位为3的有32,34;十位为4的有43,42,共有6个不同的两位数;再把这6个数从大到小排列为:43\u003e42\u003e34\u003e32\u003e24\u003e23,根据排序可知,最大的数是43,最小的数是23,再将43和23相加求出它们的和,相减求出它们的差,据此解答.\n【详解】根据分析可得:23,24,32,34,43,42数一数可知,可以摆成6个不同的两位数;从大到小排列为:43\u003e42\u003e34\u003e32\u003e24\u003e23,可知最大的数是43,最小的数是23;43+23=66,43-23=20,用3,2,4这3张数字卡片可以摆成6个不同的两位数,最大的两位数是43,最小的两位数是23,它们的和是66,差是20.",
+        "knowledge_points":  [
+                                 "搭配问题",
+                                 "100以内数的比大小",
+                                 "两位数与两位数的不进位加法",
+                                 "两位数与两位数的不退位减法"
+                             ],
+        "source":  "24-25二年级上·湖北荆州·期末"
+    },
+    {
+        "id":  "33",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "从2,5,9中任选两个数求积,得数可能是(),(),().",
+        "options":  [
+
+                    ],
+        "answer":  "10;18;45",
+        "solution":  "【分析】根据题意,任选两个数求积,可选择2和5相乘;2和9相乘;5和9相乘,计算出结果即可.\n【详解】2×5=10;2×9=18;5×9=45;从2,5,9中任选两个数求积,得数可能是10,18,45.",
+        "knowledge_points":  [
+                                 "搭配问题",
+                                 "5的乘法口诀及应用",
+                                 "9的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·浙江嘉兴·期末"
+    },
+    {
+        "id":  "34",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "用4,8,3组成两位数,每个两位数的十位数和个位数不能一样,能组成()个两位数.",
+        "options":  [
+
+                    ],
+        "answer":  "6",
+        "solution":  "【分析】根据题意可知,十位可以是4,8,3中的任意一个,个位从剩下的两个数字中选择,十位为4时,组成的数是48和43;十位为8时,组成的数是84和83;十位为3时,组成的数是34和38,共6种不同的两位数,据此解答.\n【详解】根据分析可得:用4,8,3组成两位数,每个两位数的十位数和个位数不能一样,能组成6个两位数.",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "24-25二年级上·浙江台州·期末"
+    },
+    {
+        "id":  "35",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "用1,7,9这三张数字卡片可以组成()个不同的两位数(十位与个位数字不能一样),其中最大的数是(),最小的数是().",
+        "options":  [
+
+                    ],
+        "answer":  "6;97;17",
+        "solution":  "【分析】先把用1,7,9三张数字卡片组成十位数字和个位数字不相同的两位数一一列举出来,然后比较大小,即可解决.两位数的比较大小,先比较十位上的数,十位上大的数就大,十位上相同的,就比较个位上的数,个位上大的数就大.\n【详解】由题意分析得:用1,7,9三张数字卡片组成十位数字和个位数字不相同的两位数有:17,19,71,79,91,97;97\u003e91\u003e79\u003e71\u003e19\u003e17;即,用1,7,9这三张数字卡片可以组成6个不同的两位数(十位与个位数字不能一样),其中最大的数是97,最小的数是17.",
+        "knowledge_points":  [
+                                 "搭配问题",
+                                 "100以内数的比大小"
+                             ],
+        "source":  "24-25二年级上·浙江温州·期末"
+    },
+    {
+        "id":  "36",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "六一儿童节到了,小飞,天天,阳阳互相发微信祝贺,他们一共发了()条微信;如果他们每两个人下一盘棋,一共下了()盘;他们站成一排照相,共有()种不同的站法.",
+        "options":  [
+
+                    ],
+        "answer":  "6;3;6",
+        "solution":  "【分析】3个人,每个人需要发2条,用3乘2即可求出一共发多少条.列举出下棋的每种情况,数一数.分别是小飞和天天,小飞和阳阳,天天和阳阳.列举出每种站法,小飞,天天,阳阳;小飞,阳阳,天天;天天,小飞,阳阳;天天,阳阳,小飞;阳阳,小飞,天天;阳阳,天天,小飞.\n【详解】六一儿童节到了,小飞,天天,阳阳互相发微信祝贺,他们一共发了6条微信;如果他们每两个人下一盘棋,共下了3盘;他们站成一排照相,共有6种不同的站法.",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "24-25二年级上·河南信阳·期末"
+    },
+    {
+        "id":  "37",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "用3,0,9组成两位数,每个两位数的十位数和个位数不能一样,能组成()个两位数,其中最大的是(),最小的是(),它们相差().",
+        "options":  [
+
+                    ],
+        "answer":  "4;93;30;63",
+        "solution":  "【分析】一个两位数,从右往左依次为个位,十位.组成两位数时,十位不能是0,由此写出数字,比较它们的大小,都是两位数,十位大的数就大;十位相同比较个位,个位大的数就大;最大的数-最小的数=它们相差的数.\n【详解】组成的两位数有:30,39,93,90.93\u003e90\u003e39\u003e30,93-30=63,用3,0,9组成两位数,每个两位数的十位数和个位数不能一样,能组成4个两位数,其中最大的是93,最小的是30,它们相差63.",
+        "knowledge_points":  [
+                                 "搭配问题",
+                                 "100以内数的比大小",
+                                 "两位数与整十数的减法"
+                             ],
+        "source":  "24-25二年级上·福建龙岩·期末"
+    },
+    {
+        "id":  "38",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "用1,4,8能组成()个不同的两位数,分别是().",
+        "options":  [
+
+                    ],
+        "answer":  "6;14,18,41,48,81,84",
+        "solution":  "【分析】十位上是1时,可以组成14,18;十位上是4时,可以组成41,48;十位上是8时,可以组成81,84.据此解答.\n【详解】用1,4,8能组成6个不同的两位数,分别是14,18,41,48,81,84.",
+        "knowledge_points":  [
+                                 "数字中的组合问题"
+                             ],
+        "source":  "24-25二年级上·湖北武汉·期末"
+    },
+    {
+        "id":  "39",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "用0,6和8组成两位数,每个两位数的十位数和个位数不能一样,可以组成()个不同的两位数,其中最大的数是(),最小的数是().",
+        "options":  [
+
+                    ],
+        "answer":  "4;86;60",
+        "solution":  "【分析】先把用0,6和8组成十位数和个位数不同的两位数一一列举出来,然后比较大小,即可解决.整数比较大小方法:①位数多的数大于位数少的数;②位数相同的,先比较最高位上的数,最高位上的数大则这个数大,最高位数相同的,就比较下一位,以此类推.\n【详解】由题意分析得:用0,6和8组成十位数和个位数不同的两位数有60,68,80,86;86\u003e80\u003e68\u003e60,即,用0,6和8组成两位数,每个两位数的十位数和个位数不能一样,可以组成4个不同的两位数,其中最大的数是86,最小的数是60.",
+        "knowledge_points":  [
+                                 "搭配问题",
+                                 "100以内数的比大小"
+                             ],
+        "source":  "24-25二年级上·四川乐山·期末"
+    },
+    {
+        "id":  "40",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "用红,黄,蓝三种颜色给两个同样的气球涂上不同的颜色,一共有()种涂色方法.",
+        "options":  [
+
+                    ],
+        "answer":  "3",
+        "solution":  "【分析】根据题意,给两个同样的气球涂不同的颜色,可将涂色的方法列举出来进行解答.\n【详解】涂色方法如下:①一个涂红色,另一个涂黄色;②一个涂红色,另一个涂蓝色;③一个涂黄色,另一个涂蓝色.即一共有3种涂色方法.",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "24-25二年级上·河南三门峡·期末"
+    },
+    {
+        "id":  "41",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "用2,0,6三张数字卡片可以摆出()个不同的两位数,其中最大的两位数是(),最小的两位数是().",
+        "options":  [
+
+                    ],
+        "answer":  "4;62;20",
+        "solution":  "【分析】按顺序,不重复,不遗漏的依次数出,0不能放在最高位;把2放在最高位可以组成的两位数有:20,26,把6放在最高位可以组成的两位数有:60,62;再比较四个两位数,找出最大的两位数和最小的两位数即可.\n【详解】根据分析可得:2+2=4(个),用2,0,6三张卡片可以摆出4个不同的两位数;62\u003e60\u003e26\u003e20,故最大的两位数是62,最小的两位数是20.",
+        "knowledge_points":  [
+                                 "搭配问题",
+                                 "100以内数的比大小"
+                             ],
+        "source":  "24-25二年级上·河南南阳·期末"
+    },
+    {
+        "id":  "42",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "用4,3,0这3个数能组成()个十位与个位不同的两位数.",
+        "options":  [
+
+                    ],
+        "answer":  "4",
+        "solution":  "【分析】采用列举法,把用4,3,0这3个数组成十位与个位不同的两位数一一列出来,然后数一数,即可解决.\n【详解】由题意分析得:用4,3,0这3个数组成十位与个位不同的两位数有:43,40,34,30,即,用4,3,0这3个数能组成4个十位与个位不同的两位数.",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "24-25二年级上·湖南湘西·期末"
+    },
+    {
+        "id":  "43",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "小丽,小花,小雨三个小朋友坐动车去旅游.动车上有A,B,C三个座位,他们有()种不同的坐法.\n\n![](images/2026-03-02%20213302.jpg)",
+        "options":  [
+
+                    ],
+        "answer":  "6",
+        "solution":  "【分析】根据题意,将三人的坐法一一列举出来,数出总数量即可.其中一个小朋友固定座位后,其余两个小朋友有两种坐法,由此解答.\n【详解】由分析得:小丽坐A,小花坐B,小雨坐C;小丽坐A,小雨坐B,小花坐C;小丽坐B,小花坐A,小雨坐C;小丽坐B,小雨坐A,小花坐C;小丽坐C,小花坐A,小雨坐B;小丽坐C,小花坐B,小雨坐A.小丽,小花,小雨三个小朋友坐动车去旅游.动车上有A,B,C三个座位,他们有6种不同的坐法.",
+        "knowledge_points":  [
+                                 "用列举法解决搭配问题"
+                             ],
+        "source":  "24-25二年级上·福建龙岩·期末"
+    },
+    {
+        "id":  "44",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "厨房有2种糕点,2种水果,要选1种糕点和1种水果搭配,共()种不同的搭配方法.",
+        "options":  [
+
+                    ],
+        "answer":  "4",
+        "solution":  "【分析】根据题意,1种糕点可以有2种水果进行搭配,共有2种糕点,则总的搭配方法是2个2种,由此解答.\n【详解】2×2=4(种),厨房有2种糕点,2种水果,要选1种糕点和1种水果搭配,共4种不同的搭配方法.",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "24-25二年级上·湖南株洲·期末"
+    },
+    {
+        "id":  "45",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "用3,4,5能组成()个没有重复数字的两位数,其中最大的数是(),最小的数是().",
+        "options":  [
+
+                    ],
+        "answer":  "6;54;34",
+        "solution":  "【分析】先把用3,4,5组成没有重复数字的两位数一一列举出来,然后比较大小,即可解决此题.\n【详解】由题意分析得:用3,4,5组成没有重复数字的两位数有:34,35,43,45,53,54,共有6个;34\u003c35\u003c43\u003c45\u003c53\u003c54,即,用3,4,5能组成6个没有重复数字的两位数,其中最大的数是54,最小的数是34.",
+        "knowledge_points":  [
+                                 "搭配问题",
+                                 "100以内数的比大小"
+                             ],
+        "source":  "23-24二年级上·湖南长沙·期末"
+    },
+    {
+        "id":  "46",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "有3个数15,8,9,任意选取其中2个数求和,得数有()种可能.",
+        "options":  [
+
+                    ],
+        "answer":  "3",
+        "solution":  "【分析】根据题意,选取任意两个数求和,可以选择15和8;15和9;8和9,计算出结果即可解答.\n【详解】15+8=23,15+9=24,8+9=17,有3个数15,8,9,任意选取其中2个数求和,得数有3种可能.",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "24-25二年级上·湖南株洲·期末"
+    },
+    {
+        "id":  "47",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "用6,2和7组成两位数,每个两位数的十位数和个位数不能一样,能组成()个不同的两位数,其中,最大的是(),最小的是(),它们的差是().",
+        "options":  [
+
+                    ],
+        "answer":  "6;76;26;50",
+        "solution":  "【分析】一个两位数,从右往左依次为个位,十位.组成两位数时,将其中一个数字写在十位,另外两个数字分别写在个位,由此写出组成的数.比较它们的大小,都是两位数,十位大的数就大;十位相同比较个位,个位大的数就大,由此找出最大的数和最小的数,相减即可求出它们的差.\n【详解】组成的数有:62,67,26,27,72,76.26\u003c27\u003c62\u003c67\u003c72\u003c76.76-26=50,用6,2和7组成两位数,每个两位数的十位数和个位数不能一样,能组成6个不同的两位数,其中,最大的是76,最小的是26,它们的差是50.",
+        "knowledge_points":  [
+                                 "100以内数的比大小",
+                                 "两位数与两位数的不退位减法",
+                                 "数字中的组合问题"
+                             ],
+        "source":  "24-25二年级上·安徽黄山·期末"
+    },
+    {
+        "id":  "48",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "二(1)班的图书角新增了3本图书,小红和小丽分别借阅其中一本,有()种不同的借法.",
+        "options":  [
+
+                    ],
+        "answer":  "6",
+        "solution":  "【分析】根据题意,假设3本图书为A,B,C.若小红借A,则小丽可以借B或C,有2种借法;若小红借B,则小丽可以借A或C,有2种借法;若小红借C,则小丽可以借A或B,有2种借法,由此解答.\n【详解】由分析得:2+2+2=6(种),二(1)班的图书角新增了3本图书,小红和小丽分别借阅其中一本,有6种不同的借法.",
+        "knowledge_points":  [
+                                 "用列举法解决搭配问题"
+                             ],
+        "source":  "24-25二年级上·湖南湘西·期末"
+    },
+    {
+        "id":  "49",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "3个小朋友每两人击掌一次,一共击掌()次.",
+        "options":  [
+
+                    ],
+        "answer":  "3",
+        "solution":  "【分析】根据题意,3个小朋友可以分别记为甲,乙,丙,由此写出所有的击掌可能性,数出次数即可.\n【详解】由分析得:甲和乙击掌;甲和丙击掌;乙和丙击掌.3个小朋友每两人击掌一次,一共击掌3次.",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "24-25二年级上·河南郑州·期末"
+    },
+    {
+        "id":  "50",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "用8,0,9能组成()个不同的两位数,其中最大的数比最小的数大().",
+        "options":  [
+
+                    ],
+        "answer":  "4;18",
+        "solution":  "【分析】0不能在最高位,先排十位,有2种排法;再排个位,有2种排法,再写出最大和最小的两位数,然后求出差即可.\n【详解】8,0,9可以组成的两位数有:80,89,90,98,共4个.98\u003e90\u003e89\u003e80,其中最大的数是98,最小的数是80,98-80=18,所以最大的数比最小的数大18.",
+        "knowledge_points":  [
+                                 "搭配问题",
+                                 "100以内数的比大小",
+                                 "100以内数的组成",
+                                 "两位数与整十数的减法"
+                             ],
+        "source":  "24-25二年级上·河南郑州·期末"
+    },
+    {
+        "id":  "51",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "用2,3,6三张数字卡片,可以组成()个两位数,其中最大的是(),最小的是(),它们相差().",
+        "options":  [
+
+                    ],
+        "answer":  "6;63;23;40",
+        "solution":  "【分析】用2,3,6三张数字卡片组数时,用其中一个数作为十位,另两个数分别作为个位,组成的数有:23,26,32,36,62,63,一共有6个不同的两位数;比较大小时,位数多的数就大,位数相同比较最高位,最高位大的数就大,最高位相同比较下一位,直到比较出大小为止,23\u003c26\u003c32\u003c36\u003c62\u003c63,把找出的最大的数和最小的数相减即可求出它们的差.\n【详解】63-23=40,用2,3,6三张数字卡片,可以组成6个两位数,其中最大的是63,最小的是23,它们相差40.",
+        "knowledge_points":  [
+                                 "搭配问题",
+                                 "100以内数的比大小",
+                                 "两位数与两位数的不退位减法"
+                             ],
+        "source":  "24-25二年级上·河南郑州·期末"
+    },
+    {
+        "id":  "52",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "用9,7,0可以写出()个十位和个位不同的两位数,其中最大的是(),最小的是().",
+        "options":  [
+
+                    ],
+        "answer":  "4;97;70",
+        "solution":  "【分析】用9,7,0三个数组数时,首位不能为0,用其中一个数作为十位,另两个数分别作为个位,组成的数有:97,90,79,70,一共有4个十位和个位不同的两位数;再把这几个比较大小.比较时,位数多的数就大,位数相同比较最高位,最高位大的数就大,最高位相同比较下一位,直到比较出大小为止,97\u003e90\u003e79\u003e70;据此解答.\n【详解】用9,7,0三个数字可以写出4个十位和个位不同的两位数,其中最大的是97,最小的是70.",
+        "knowledge_points":  [
+                                 "搭配问题",
+                                 "100以内数的比大小"
+                             ],
+        "source":  "24-25二年级上·山东济宁·期末"
+    },
+    {
+        "id":  "53",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "4个人站成一横排,小丽固定在第一位,有()种不同的站法.",
+        "options":  [
+
+                    ],
+        "answer":  "6",
+        "solution":  "【分析】有以下几种:小丽,A,B,C;小丽,A,C,B;小丽,B,A,C;小丽,B,C,A;小丽,C,A,B;小丽,C,B,A(共6种).\n【详解】4个人站成一横排,小丽固定在第一位,有6种不同的站法.",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "23-24二年级上·江西南昌·期末"
+    },
+    {
+        "id":  "54",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "用8,0,2可以组成()个不同的两位数,其中最大的两位数是().",
+        "options":  [
+
+                    ],
+        "answer":  "4;82",
+        "solution":  "【分析】先把用8,0,2组成不同的两位数一一列举出来,然后通过比较大小,找出最大的两位数即可.\n【详解】由题意分析得:用8,0,2组成不同的两位数有:80,82,20,28;82\u003e80\u003e28\u003e20,即,用8,0,2可以组成4个不同的两位数,其中最大的两位数是82.",
+        "knowledge_points":  [
+                                 "搭配问题",
+                                 "100以内数的比大小"
+                             ],
+        "source":  "24-25二年级上·江西南昌·期末"
+    },
+    {
+        "id":  "55",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "妈妈去买早餐,有3种主食(包子,油饼,油条),2种饮品(牛奶,豆浆),妈妈要买一种主食和一种饮品,有()种不同的买法.",
+        "options":  [
+
+                    ],
+        "answer":  "6",
+        "solution":  "【分析】每种主食都会配2种饮品与它搭配,共有3种主食,共有:2×3=6(种)不同的买法,列举出所有的买法即可.\n【详解】由题意分析得:第一种:包子和牛奶;第二种:包子和豆浆;第三种:油饼和牛奶;第四种:油饼和豆浆;第五种:油条和牛奶;第六种:油条和豆浆.妈妈去买早餐,有3种主食(包子,油饼,油条),2种饮品(牛奶,豆浆),妈妈要买一种主食和一种饮品,有6种不同的买法.",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "23-24二年级上·陕西延安·期末"
+    },
+    {
+        "id":  "56",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "明明,爸爸和爷爷下棋,如果每两人下一盘棋,一共要下()盘.",
+        "options":  [
+
+                    ],
+        "answer":  "3",
+        "solution":  "【分析】列出每种情况,然后数一数即可.\n【详解】分别是明明和爸爸,明明和爷爷,爸爸和爷爷,共要下3盘.",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "24-25二年级上·山东济宁·期末"
+    },
+    {
+        "id":  "57",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "用1,5,7组成两位数,每个两位数的十位数和个位数不能一样,能组成()个两位数,其中最大的数是(),最小的数是(),它们相差().",
+        "options":  [
+
+                    ],
+        "answer":  "6;75;15;60",
+        "solution":  "【分析】把用1,5,7组成十位数和个位数不一样的两位数一一列举出来,然后比较大小,找出其中最大与最小的两位数,再作差即可.\n【详解】用1,5,7组成十位数和个位数不一样的两位数有:15,17,51,57,71,75;15\u003c17\u003c51\u003c57\u003c71\u003c75,75-15=60,即,用1,5,7组成两位数,每个两位数的十位数和个位数不能一样,能组成6个两位数,其中最大的数是75,最小的数是15,它们相差60.",
+        "knowledge_points":  [
+                                 "搭配问题",
+                                 "100以内数的比大小",
+                                 "两位数与两位数的不退位减法"
+                             ],
+        "source":  "24-25二年级上·青海西宁·期末"
+    },
+    {
+        "id":  "58",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "用6,2,7三个数字,能组成()个不同的两位数.",
+        "options":  [
+
+                    ],
+        "answer":  "6",
+        "solution":  "【分析】用6,2,7三个数字组数时,用其中一个数作为十位,另两个数分别作为个位,组成的数有:62,67,26,27,76,72,一共有6个不同的两位数.\n【详解】根据分析可得:用6,2,7三个数字,能组成6个不同的两位数.",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "24-25二年级上·辽宁抚顺·期末"
+    },
+    {
+        "id":  "59",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "清明节学校举行\"红色故事我来讲\"活动.小文,欢欢,阳阳参加了此次活动.\n(1)比赛前,参赛队员每两人握一次手,以示友好.他们三人一共握了()次手.\n(2)他们三人都进入了前三名,三位同学互发一条短信进行祝贺,一共发了()条短信.\n(3)最终,欢欢获得第一名,他们三人站在一排合影,一共有()种站法.",
+        "options":  [
+
+                    ],
+        "answer":  "3;6;6",
+        "solution":  "【分析】(1)列举出每种可能并数一数即可.(2)每个人都要向另外两个人发一条短信,也就是每个人都要发2条,将每个人发的条数相加即可.(3)列举出每种站法并数一数即可.\n【详解】(1)分别是小文和欢欢,小文和阳阳,欢欢和阳阳握手,他们三人一共握了3次手.(2)2+2+2=6(条),一共发了6条短信.(3)从左到右分别可以是:小文,欢欢,阳阳,小文,阳阳,欢欢,欢欢,小文,阳阳,欢欢,阳阳,小文,阳阳,小文,欢欢,阳阳,欢欢,小文,一共有6种站法.",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "24-25二年级上·河南驻马店·期末"
+    },
+    {
+        "id":  "60",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "有1,3,5,7,9五个数,任意选其中两个数求积,最多可能有()个得数.",
+        "options":  [
+
+                    ],
+        "answer":  "10",
+        "solution":  "【分析】先固定一个数,再搭配另一个数求积,把不同的算式写出来,计算出结果,注意不能重复,即可解答.\n【详解】选定数字1,1和3相乘,1×3=3;1和5相乘,1×5=5;1和7相乘,1×7=7;1和9相乘,1×9=9,共有4个得数;选定数字3,3和5相乘,3×5=15;3和7相乘,3×7=21,3和9相乘,3×9=27,共有3个得数;选定数字5,5和7相乘,5×7=35;5和9相乘,5×9=45,共有2个得数;选定数字7,7和9相乘,7×9=63,共有1个得数;4+3+2+1=10(个),所以,最多可能有10个得数.",
+        "knowledge_points":  [
+                                 "搭配问题",
+                                 "5的乘法口诀及应用",
+                                 "7的乘法口诀及应用",
+                                 "9的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·四川广元·期末"
+    },
+    {
+        "id":  "61",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "用0,3,5可以组成()个十位和个位数字不同的两位数,把最大的数和最小的数合起来是().",
+        "options":  [
+
+                    ],
+        "answer":  "4;83",
+        "solution":  "【分析】先把用0,3,5组成十位和个位数字不同的两位数一一列举出来,然后把最大的数和最小的数加起来,求出和,即可解决此题.\n【详解】用0,3,5组成十位和个位数字不同的两位数有:30,35,50,53,30\u003c35\u003c50\u003c53,30+53=83,即,用0,3,5可以组成4个十位和个位数字不同的两位数,把最大的数和最小的数合起来是83.",
+        "knowledge_points":  [
+                                 "搭配问题",
+                                 "100以内数的比大小",
+                                 "100以内数的组成",
+                                 "两位数与整十数的加法"
+                             ],
+        "source":  "24-25二年级上·浙江台州·期末"
+    },
+    {
+        "id":  "62",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "从2,5,7三个数中任意选取其中的2个数求积,得数有()种可能.",
+        "options":  [
+
+                    ],
+        "answer":  "3",
+        "solution":  "【分析】乘法算式中两个乘数是口诀中的前两个数,积是口诀中的后一个数,写算式时两个乘数可互换位置.将每种可能列出来即可求解.\n【详解】2×5=10,5×7=35,2×7=14,得数有3种可能.",
+        "knowledge_points":  [
+                                 "搭配问题",
+                                 "5的乘法口诀及应用",
+                                 "7的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·湖北黄冈·期末"
+    },
+    {
+        "id":  "63",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "用(),(),()这3个数字中的两个数,可以组成52,58,25,28,85,82这6个两位数.",
+        "options":  [
+
+                    ],
+        "answer":  "2;5;8",
+        "solution":  "【分析】52,25,28,82这几个数字中含有共同的数字2;52,58,25,85这几个数字中含有共同数字5;58,28,85,82这几个数字中含有共同的数字8;25,28是用2开头组成的两位数,52,58是用5开头组成的两位数,85,82是用8开头组成的两位数;据此解答.\n【详解】根据分析可知:用2,5,8这3个数字中的两个数,可以组成52,58,25,28,85,82这6个两位数.",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "24-25二年级上·湖北襄阳·期末"
+    },
+    {
+        "id":  "64",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "从5,6,7这三个数中任意选取2个数求和,得数有()种可能,得数最大是(),得数最小是().",
+        "options":  [
+
+                    ],
+        "answer":  "3;13;11",
+        "solution":  "【分析】从三个数中任意取出两个数求和出现的可能性有:如果选出的数字是5和6,那么这两个数字的和是5+6=11,如果选出的数字是5和7,那么这两个数字的和是5+7=12,如果选出的数字是6和7,那么这两个数字的和是6+7=13,所以得数一共有3种可能.\n【详解】由题意分析得:5+6=11,5+7=12,6+7=13;11\u003c12\u003c13;从5,6,7这三个数中任意选取2个数求和,得数有3种可能,得数最大是13,得数最小是11.",
+        "knowledge_points":  [
+                                 "搭配问题",
+                                 "7,6加几的进位加法"
+                             ],
+        "source":  "24-25二年级上·湖北襄阳·期末"
+    },
+    {
+        "id":  "65",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "有3个声母卡片b,p,m,3个韵母卡片a,o,u,选择一个声母和一个韵母组成一个音节,一共有()种不同的选法.",
+        "options":  [
+
+                    ],
+        "answer":  "9",
+        "solution":  "【分析】根据题意可知,用每一个声母和所有的韵母进行一一搭配即可,那么根据乘法的意义,利用声母的个数乘韵母的个数即可解答.\n【详解】声母有3个,韵母有3个;3×3=9(种),一共有9种不同的选法.",
+        "knowledge_points":  [
+                                 "搭配问题",
+                                 "3的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·湖北黄石·期末"
+    },
+    {
+        "id":  "66",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "小华,小红和亮亮三个人相互握手,一共握()次.",
+        "options":  [
+
+                    ],
+        "answer":  "3",
+        "solution":  "【分析】用列举的方法,把所有可能性一一列举出来,然后数一数,即可知一共握几次手.\n【详解】由题意分析得:小华和小红握1次手,小华和亮亮握1次手,小红和亮亮握1次手.即小华,小红和亮亮三个人相互握手,一共握3次.",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "23-24二年级上·山东济宁·期末"
+    },
+    {
+        "id":  "67",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "用![](images/2026-03-02%20214324.jpg)这三张数字卡片能摆出()个不同的两位数,最大的数是(),最小的数是(),它们相差().",
+        "options":  [
+
+                    ],
+        "answer":  "4;86;60;26",
+        "solution":  "【分析】列举出每种可能并数一数,0不能放在最高位.然后将这些数据比较大小,整数的大小比较:比较数的大小,先看位数的多少,位数多的数就大;位数相同,从高位开始比较,高位上的数大则这个数大,高位上的数相同,就比较下一位.再用最大数减去最小数即可求出它们相差的数值.\n【详解】用这三张数字卡片能摆出的两位数有60,80,68,86,能摆出4个不同的两位数.86\u003e80\u003e68\u003e60,86-60=26,最大的数是86,最小的数是60,它们相差26.",
+        "knowledge_points":  [
+                                 "搭配问题",
+                                 "100以内数的比大小",
+                                 "100以内数的组成",
+                                 "两位数与整十数的减法"
+                             ],
+        "source":  "24-25二年级上·河南驻马店·期末"
+    },
+    {
+        "id":  "68",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "用3,6,9三张数字卡片能摆成()个不同的两位数;如果用0代替9,能摆成()个不同的两位数.",
+        "options":  [
+
+                    ],
+        "answer":  "6;4",
+        "solution":  "【分析】用3,6,9三张数字卡片组数时,用其中一个数作为十位,另两个数分别作为个位,组成的数有:36,39,63,69,93,96,一共有6个不同的两位数;如果用0代替9时,这时候只能用3和6作为十位,首位不能为0,则组成的数有:30,36,60,63,一共有4个不同的两位数.\n【详解】用3,6,9三张数字卡片组成的数有:36,39,63,69,93,96,一共有6个不同的两位数;如果用0代替9时,组成的数有:30,36,60,63,一共有4个不同的两位数.",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "24-25二年级上·四川广元·期末"
+    },
+    {
+        "id":  "69",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "用9,2,4三个数字能组成()个不同的两位数,其中最大的数是(),最小的数是().",
+        "options":  [
+
+                    ],
+        "answer":  "6;94;24",
+        "solution":  "【分析】用9,2,4三张数字卡片组数时,用其中一个数作为十位,另两个数分别作为个位,组成的数有:92,94,29,24,49,42,组成6个不同的两位数;比较数的大小,先看位数的多少,位数多的数就大;如果位数相同,从最高位开始比较,最高位上的数大则这个数就大,最高位相同,就比较下一位,以此类推.从小到大排序为:24\u003c29\u003c42\u003c49\u003c92\u003c94,根据排序完成填空即可.\n【详解】用9,2,4三个数字能组成6个不同的两位数,其中最大的数是94,最小的数是24.",
+        "knowledge_points":  [
+                                 "搭配问题",
+                                 "100以内数的比大小"
+                             ],
+        "source":  "24-25二年级上·江西赣州·期末"
+    },
+    {
+        "id":  "70",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "小丽,小美,小亮三个好朋友周末去公园玩耍,如果每两人都想合影留念,一共需要照()张合影.",
+        "options":  [
+
+                    ],
+        "answer":  "3",
+        "solution":  "【分析】可以用列举的方法把所有的合影结果一一列举出来,然后数一数有几种结果即可.\n【详解】由题意分析得:小丽,小美,小亮三人要合影留念,两人为一组合影留念,有以下几种结果:①小丽和小美,②小丽和小亮,③小美和小亮,一共3种结果.即,小丽,小美,小亮三个好朋友周末去公园玩耍,如果每两人都想合影留念,一共需要照3张合影.",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "24-25二年级上·重庆奉节·期末"
+    },
+    {
+        "id":  "71",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "用3,5,8三个数字组成个位和十位不同的两位数,能组成()个不同的两位数,其中最大的数比最小的数大().",
+        "options":  [
+
+                    ],
+        "answer":  "6;50",
+        "solution":  "【分析】列出各种可能,数一数即可.整数的大小比较:比较数的大小,先看位数的多少,位数多的数就大;位数相同,从高位开始比较,高位上的数大则这个数大,高位上的数相同,就比较下一位.比较一下,然后用最大的数减最小的数.\n【详解】用3,5,8三个数字组成个位和十位不同的两位数,有35,38,53,58,83,85.85\u003e83\u003e58\u003e53\u003e38\u003e35,85-35=50,用3,5,8三个数字组成个位和十位不同的两位数,能组成6个不同的两位数,其中最大的数比最小的数大50.",
+        "knowledge_points":  [
+                                 "搭配问题",
+                                 "100以内数的比大小",
+                                 "100以内数的组成",
+                                 "两位数与两位数的不退位减法"
+                             ],
+        "source":  "23-24二年级上·浙江杭州·期末"
+    },
+    {
+        "id":  "72",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "用2,0,9三个数字可以组成()个个位和十位上的数字不相同的两位数,其中最大的是(),最小的是().",
+        "options":  [
+
+                    ],
+        "answer":  "4;92;20",
+        "solution":  "【分析】先把用2,0,9三个数字组成的个位和十位上的数字不相同的两位数一一列举出来,然后比较大小,即可解决.\n【详解】用2,0,9三个数字组成的个位和十位上的数字不相同的两位数有:20,29,92,90;92\u003e90\u003e29\u003e20,即,用2,0,9三个数字可以组成4个个位和十位上的数字不相同的两位数,其中最大的是92,最小的是20.",
+        "knowledge_points":  [
+                                 "搭配问题",
+                                 "100以内数的比大小",
+                                 "100以内数的组成"
+                             ],
+        "source":  "23-24二年级上·浙江杭州·期末"
+    },
+    {
+        "id":  "73",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "用3,0,7组成两位数,一共可以组成()个十位与个位上数字不同的两位数,其中最大的是(),最小的是().",
+        "options":  [
+
+                    ],
+        "answer":  "4;73;30",
+        "solution":  "【分析】3和7可以作为十位数字,每个数字都可以作为个位数字,由此确定可以写出符合要求的两位数,并确定最大的和最小的.\n【详解】用3,0,7组成两位数,有30,37,73,70,共4个十位与个位上数字不同的两位数;73\u003e70\u003e37\u003e30,最大的是73,最小的是30;所以用3,0,7组成两位数,一共可以组成4个十位与个位上数字不同的两位数,其中最大的是73,最小的是30.",
+        "knowledge_points":  [
+                                 "搭配问题",
+                                 "100以内数的比大小"
+                             ],
+        "source":  "23-24二年级上·浙江·期末"
+    },
+    {
+        "id":  "74",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "新年临近,妈妈看中不同款式的3件上衣和2条裤子,如果她要买一件上衣和一条裤子,她有()种买法.",
+        "options":  [
+
+                    ],
+        "answer":  "6",
+        "solution":  "【分析】1条裤子可以配3件不同的上衣,有3种搭配方法;另一条裤子也同样有3种不同的搭配方法,3乘2即可求出所有的搭配种类.\n【详解】3×2=6(种),则她有6种买法.",
+        "knowledge_points":  [
+                                 "搭配问题",
+                                 "3的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·黑龙江哈尔滨·期末"
+    },
+    {
+        "id":  "75",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "从苹果,香蕉,梨三种水果中任意选出两种做水果拼盘,一共有()种选法.",
+        "options":  [
+
+                    ],
+        "answer":  "3",
+        "solution":  "【分析】通过列举的方法,把所有的选法都一一列举出来,然后数一数有几种选法即可解决.\n【详解】由题意分析得:从苹果,香蕉,梨三种水果中任意选出两种做水果拼盘,可以这样选:①苹果和香蕉;②苹果和梨;③香蕉和梨;一共有3种选法.",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "24-25二年级上·河北保定·期末"
+    },
+    {
+        "id":  "76",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "用9,6和4组成两位数,每个两位数的十位数和个位数不能一样,能组成()个两位数,组成的数中,最大的是().",
+        "options":  [
+
+                    ],
+        "answer":  "6;96",
+        "solution":  "【分析】用9,6和4组成的两位数一一列举出来(每个两位数的十位数和个位数不能一样),数一数有几个两位数,然后比较大小,即可解决.\n【详解】用9,6和4组成的两位数有(每个两位数的十位数和个位数不一样):96,94,69,64,49,46,一共有6个.96\u003e94\u003e69\u003e64\u003e49\u003e46;即,用9,6和4组成两位数,每个两位数的十位数和个位数不能一样,能组成6个两位数,组成的数中,最大的是96.",
+        "knowledge_points":  [
+                                 "搭配问题",
+                                 "100以内数的比大小"
+                             ],
+        "source":  "24-25二年级上·甘肃天水·期末"
+    },
+    {
+        "id":  "77",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "用3,4,5这三个数能组成()个十位与个位不同的两位数,其中最大的是(),最小的是().",
+        "options":  [
+
+                    ],
+        "answer":  "6;54;34",
+        "solution":  "【分析】依次列出各种情况,数一数即可.整数的大小比较:比较数的大小,先看位数的多少,位数多的数就大;位数相同,从高位开始比较,高位上的数大则这个数大,高位上的数相同,就比较下一位.\n【详解】可以组成34,35,43,45,53,54,共6个.54\u003e53\u003e45\u003e43\u003e35\u003e34,用3,4,5这三个数能组成6个十位与个位不同的两位数,其中最大的是54,最小的是34.",
+        "knowledge_points":  [
+                                 "搭配问题",
+                                 "100以内数的比大小",
+                                 "100以内数的组成"
+                             ],
+        "source":  "24-25二年级上·内蒙古通辽·期末"
+    },
+    {
+        "id":  "78",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "二(1)班在筹划校运动会接力赛方案时,决定让本班速度最快的小明跑最后一棒,其余三名同学乐乐,优优,轩轩跑其他三棒.一共有()种方案.",
+        "options":  [
+
+                    ],
+        "answer":  "6",
+        "solution":  "【分析】可采用列举的方法解答,一一列举出接力赛的所有可能组合情况;由于小明跑最后一棒是固定的,则只需对乐乐,优优,轩轩三人进行排列组合;先固定三人中的一人,然后将其余两人颠倒,找出所有的可能即可.\n【详解】小明是最后一棒,则乐乐,优优,轩轩顺序可能是:乐乐,优优,轩轩;乐乐,轩轩,优优;优优,乐乐,轩轩;优优,轩轩,乐乐;轩轩,乐乐,优优;轩轩,优优,乐乐;即,二(1)班在筹划校运动会接力赛方案时,决定让本班速度最快的小明跑最后一棒,其余三名同学乐乐,优优,轩轩跑其他三棒.一共有6种方案.",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "24-25二年级上·甘肃庆阳·期末"
+    },
+    {
+        "id":  "79",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "用1,5,7这三张数字卡片能摆出()个不同的两位数,其中最大的数是(),最小的数是(),它们相差().",
+        "options":  [
+
+                    ],
+        "answer":  "6;75;15;60",
+        "solution":  "【分析】用1,5,7组成的任意两位数有:15,17,51,57,71,75.然后比较这6个数,数位相同最高位上数大的就大,最高位相同比较个位,个位上大的数就大,15\u003c17\u003c51\u003c57\u003c71\u003c75.用最大的数减去最小的数即可求出两位数相差多少.据此解答.\n【详解】根据分析:75-15=60,用1,5,7这三张数字卡片能摆出6个不同的两位数,其中最大的数是75,最小的数是15,它们相差60.",
+        "knowledge_points":  [
+                                 "100以内数的比大小",
+                                 "两位数与两位数的不退位减法",
+                                 "数字中的组合问题"
+                             ],
+        "source":  "24-25二年级上·广东汕头·期末"
+    },
+    {
+        "id":  "80",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "从2,6,8这三个数字中任取两个求和,得数有()种可能,和最大是(),和最小是().",
+        "options":  [
+
+                    ],
+        "answer":  "3;14;8",
+        "solution":  "【分析】先确定第一个加数,然后选择第二个加数,可以是2和6,2和8,6和8,分别计算出它们的和,即可确定和有几种可能;再比较即可.\n【详解】2+6=8;2+8=10;6+8=14;14\u003e10\u003e8,从2,6,8这三个数字中任取两个求和,得数有3种可能,和最大是14,和最小是8.",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "24-25二年级上·陕西西安·期末"
+    },
+    {
+        "id":  "81",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "用数字卡片\"2\",\"7\",\"5\",可以摆出()个不同的两位数,其中最小的是(),最大的是().",
+        "options":  [
+
+                    ],
+        "answer":  "6;25;75",
+        "solution":  "【分析】一个两位数,从右往左依次为个位,十位.将其中一个数字写在十位,剩余的两个数字可分别写在个位,由此写出组成的数,再比较大小即可,都是两位数,十位大的数就大;十位相同比较个位,个位大的数就大.\n【详解】组成的数有:27,25,72,75,52,57.75\u003e72\u003e57\u003e52\u003e27\u003e25,用数字卡片\"2\",\"7\",\"5\",可以摆出6个不同的两位数,其中最小的是25,最大的是75.",
+        "knowledge_points":  [
+                                 "搭配问题",
+                                 "100以内数的比大小"
+                             ],
+        "source":  "24-25二年级上·广东江门·期末"
+    },
+    {
+        "id":  "82",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "三个好朋友见面,每两人拥抱一次,一共要拥抱()次.",
+        "options":  [
+
+                    ],
+        "answer":  "3",
+        "solution":  "【分析】第1个人要分别和另外2个人各拥抱1次,一共拥抱2次;除了第1个人,另外2个人还要拥抱1次,求出次数和即可,据此解答.\n【详解】2+1=3(次),三个好朋友见面,每两人拥抱一次,一共要拥抱3次.",
+        "knowledge_points":  [
+                                 "搭配问题",
+                                 "5以内数的加法"
+                             ],
+        "source":  "24-25二年级上·河南开封·期末"
+    },
+    {
+        "id":  "83",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "我国统一的急救电话是\"120\",用数字1,2,0能摆()个不同的两位数(个位数字和十位数字不一样),其中最大的两位数和最小的两位数相差().",
+        "options":  [
+
+                    ],
+        "answer":  "4;11",
+        "solution":  "【分析】用1,2,0组成的任意两位数十位不能是0,组成的两位数有:10,12,20,21.然后比较这四个数,数位相同最高位上数大的就大,最高位相同比较个位,个位上大的数就大,10\u003c12\u003c20\u003c21.用最大的数减去最小的数即可求出两位数相差多少.据此解答.\n【详解】根据分析:21-10=11,我国统一的急救电话是\"120\",用数字1,2,0能摆4个不同的两位数(个位数字和十位数字不一样),其中最大的两位数和最小的两位数相差11.",
+        "knowledge_points":  [
+                                 "搭配问题",
+                                 "两位数与整十数的减法"
+                             ],
+        "source":  "24-25二年级上·河南开封·期末"
+    },
+    {
+        "id":  "84",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "从5,3,0这三个数字中,任意选取2个组成一个两位数,有()种可能.",
+        "options":  [
+
+                    ],
+        "answer":  "4",
+        "solution":  "【分析】从5,3,0中选出两个数字组成一个两位数,它们分别是:53,50,35,30共4种不同的组法,据此解答.\n【详解】从5,3,0这三个数字中,任意选取2个组成一个两位数,有4种可能.",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "24-25二年级上·河北邯郸·期末"
+    },
+    {
+        "id":  "85",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "新年快到了,君君,王博,李路打算分别互赠一张新年贺卡,他们一共要送出()张贺卡.",
+        "options":  [
+
+                    ],
+        "answer":  "6",
+        "solution":  "【分析】一共有3人,每个人要送出去2张,用3乘2即可求解.\n【详解】3×2=6(张),他们一共要送出6张贺卡.",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "24-25二年级上·吉林·期末"
+    },
+    {
+        "id":  "86",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "用7,1,5三张数字卡片可以组成()个十位数字和个位数字不相同的两位数,其中最大的是(),最小的是().",
+        "options":  [
+
+                    ],
+        "answer":  "6;75;15",
+        "solution":  "【分析】先把用7,1,5三张数字卡片组成十位数字和个位数字不相同的两位数一一列举出来,然后比较大小,即可解决.\n【详解】由题意分析得:用7,1,5三张数字卡片组成十位数字和个位数字不相同的两位数有:71,75,17,15,57,51;75\u003e71\u003e57\u003e51\u003e17\u003e15;即,用7,1,5三张数字卡片可以组成6个十位数字和个位数字不相同的两位数,其中最大的是75,最小的是15.",
+        "knowledge_points":  [
+                                 "搭配问题",
+                                 "100以内数的比大小"
+                             ],
+        "source":  "23-24二年级上·河北保定·期末"
+    },
+    {
+        "id":  "87",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "小明有两件颜色不同的上衣和两条颜色不同的裤子,一件上衣配一条裤子,他可以有()种不同的穿法.",
+        "options":  [
+
+                    ],
+        "answer":  "4",
+        "solution":  "【分析】根据题意,1件上衣可以有2条裤子搭配,一共有2件上衣,则总的穿法也就是2个2种,由此解答.\n【详解】2×2=4(种),小明有两件颜色不同的上衣和两条颜色不同的裤子,一件上衣配一条裤子,他可以有4种不同的穿法.",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "23-24二年级上·河北保定·期末"
+    },
+    {
+        "id":  "88",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "用9,7,6三个数字组成两位数,每个两位数的十位数和个位数不能一样,能组成()个两位数,其中最大的两位数比最小的两位数多().如果从这三个数字中选取其中两个数求积,得数有()种可能.",
+        "options":  [
+
+                    ],
+        "answer":  "6;30;3",
+        "solution":  "【分析】一个两位数,从右往左依次为个位,十位.组成两位数时,将其中一个数字写在十位,另外两个数字分别写在个位,由此写出数字,数出数量.再比较这些数字的大小,将最大的数和最小的数相减即可求出差,比较时,都是两位数,十位大的数就大;十位相同比较个位,个位大的数就大;要选取两个数求积,可以选择9和7;9和6;6和7,由此解答.\n【详解】组成的两位数有:97,96,76,79,69,67;97\u003e96\u003e79\u003e76\u003e69\u003e67,97-67=30.9×7=63;9×6=54;7×6=42.用9,7,6三个数字组成两位数,每个两位数的十位数和个位数不能一样,能组成6个两位数,其中最大的两位数比最小的两位数多30.如果从这三个数字中选取其中两个数求积,得数有3种可能.",
+        "knowledge_points":  [
+                                 "搭配问题",
+                                 "100以内数的比大小",
+                                 "两位数与两位数的不退位减法",
+                                 "9的乘法口诀及应用"
+                             ],
+        "source":  "23-24二年级上·重庆秀山·期末"
+    },
+    {
+        "id":  "89",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "用0,3,5组成两位数,每个两位数的十位数和个位数不能一样,能组成()个不同的两位数,其中最大的数是(),最小的数是(),它们相差().",
+        "options":  [
+
+                    ],
+        "answer":  "4;53;30;23",
+        "solution":  "【分析】用0,3,5组成两位数,每个两位数的十位数和个位数不能一样,先确定十位上的数,再确定个位上的数,由此写出可以组成的两位数30,35,50,53,再将这些数比较大小,找出最大的数和最小的数即可.再将它们相减,即可求出它们之间相差的数.\n【详解】由分析可知:用0,3,5组成两位数,每个两位数的十位数和个位数不能一样,能组成的数有:30,35,50,53;53\u003e50\u003e35\u003e30;53-30=23,所以用0,3,5组成两位数,每个两位数的十位数和个位数不能一样,能组成4个不同的两位数,其中最大的数是53,最小的数是30,它们相差23.",
+        "knowledge_points":  [
+                                 "搭配问题",
+                                 "100以内数的比大小",
+                                 "两位数与整十数的减法"
+                             ],
+        "source":  "23-24二年级上·云南红河·期末"
+    },
+    {
+        "id":  "90",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "用7,3,5这三个数字组成()个没有重复数字的两位数,其中最大的是(),最小的是().",
+        "options":  [
+
+                    ],
+        "answer":  "6;75;35",
+        "solution":  "【分析】先把用7,3,5这三个数字组成没有重复数字的两位数一一列举出来,然后比较大小,找出最大的数和最小的数即可解决.\n【详解】用7,3,5这三个数字组成没有重复数字的两位数有:73,75,37,35,57,53,一共6个;75\u003e73\u003e57\u003e53\u003e37\u003e35,即,用7,3,5这三个数字组成6个没有重复数字的两位数,其中最大的是75,最小的是35.",
+        "knowledge_points":  [
+                                 "搭配问题",
+                                 "100以内数的比大小"
+                             ],
+        "source":  "23-24二年级上·山东菏泽·期末"
+    },
+    {
+        "id":  "91",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "如果从5,7,9这三张卡片中,任意抽取两张卡片并求积,得数有()种可能.",
+        "options":  [
+
+                    ],
+        "answer":  "3",
+        "solution":  "【分析】据题意,数字一共有3个,可以两两组合,列出可能出现的组合,数一数即可.\n【详解】5和7,5和9,7和9,一共有3种可能.如果从5,7,9这三张卡片中,任意抽取两张卡片并求积,得数有3种可能.",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "23-24二年级上·浙江杭州·期末"
+    },
+    {
+        "id":  "92",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "从9,8,5三个数中任意选取两个数组成两位数,有()种情况;从这三个数中任意取两个数求和,有()种情况.",
+        "options":  [
+
+                    ],
+        "answer":  "6或六;3或三",
+        "solution":  "【分析】从9,8,5三个数中任意选取两个数组成两位数,将所有情况列举出来并数一数;算出和有哪些情况,数一数即可求解.\n【详解】可以组成的两位数有98,95,89,85,59,58,共6个.9+8=17;8+5=13;9+5=14,从9,8,5三个数中任意选取两个数组成两位数,有6种情况;从这三个数中任意取两个数求和,有3种情况.",
+        "knowledge_points":  [
+                                 "搭配问题",
+                                 "9加几的进位加法"
+                             ],
+        "source":  "23-24二年级上·河南郑州·期末"
+    },
+    {
+        "id":  "93",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "用2,4,7这三个数字可以组成()个不同的两位数,从这三个数字中任选两个数相乘,有()种不同的乘积.",
+        "options":  [
+
+                    ],
+        "answer":  "6;3",
+        "solution":  "【分析】将组成的数字列举出来,数一数有几个.然后将这三个数字中任意两个相乘,数一数乘积有多少种情况.乘法算式中两个乘数是口诀中的前两个数,积是口诀中的后一个数,写算式时两个乘数可互换位置.\n【详解】用2,4,7这三个数字可以组成的不同两位数有:24,27,42,47,72,74.2×4=4×2=8,4×7=7×4=28,2×7=7×2=14,用2,4,7这三个数字可以组成6个不同的两位数,从这三个数字中任选两个数相乘,有3种不同的乘积.",
+        "knowledge_points":  [
+                                 "搭配问题",
+                                 "100以内数的组成",
+                                 "4的乘法口诀及应用",
+                                 "7的乘法口诀及应用"
+                             ],
+        "source":  "23-24二年级上·浙江台州·期末"
+    },
+    {
+        "id":  "94",
+        "unit":  "搭配",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "有三个同学,每两人握一次手,一共要握3次手.()",
+        "options":  [
+
+                    ],
+        "answer":  "√",
+        "solution":  "【分析】3个同学,每个同学需要和另两个同学握手,用乘法计算,即3×2,握手是相互的行为,再除以2去掉重复的次数,求出一共需要握手几次.\n【详解】3×2=6(次),6/2=3(次),有三个同学,每两人握一次手,一共要握3次手.故答案为:√",
+        "knowledge_points":  [
+                                 "搭配问题",
+                                 "3的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·江西赣州·期末"
+    },
+    {
+        "id":  "95",
+        "unit":  "搭配",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "用5,0,6三张数字卡片,能摆出6个不同的两位数.()",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】用5,0,6组成不同的两位数,由于0不能作首位,十位的选择有两种,分别是5,6;当十位是5时,可以组成50,56;当十位上是6时,可以组成60,65,一共有4个不同的两位数,据此解答.\n【详解】根据分析可得:用5,0,6三张数字卡片,能摆出4个不同的两位数.所以原题说法错误.故答案为: ×",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "24-25二年级上·湖北黄石·期末"
+    },
+    {
+        "id":  "96",
+        "unit":  "搭配",
+        "question_type":  "判断题",
+        "difficulty":  0.65,
+        "question":  "每两人拥抱一次,三人一共要拥抱6次.()",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】可以先假设出三个人分别是谁(如:甲,乙,丙),然后通过列举法,把所有的拥抱结果列举出来,即可知道一共要拥抱几次.\n【详解】假设这三个人分别是甲,乙,丙,每两人拥抱一次,有以下结果:甲乙拥抱1次,甲丙拥抱1次,乙丙拥抱1次,也就是每两人拥抱一次,三人一共要拥抱3次.原题说法错误.故答案为: ×",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "24-25二年级上·四川南充·期末"
+    },
+    {
+        "id":  "97",
+        "unit":  "搭配",
+        "question_type":  "判断题",
+        "difficulty":  0.65,
+        "question":  "有1元,5角,1角的硬币各一枚,一次取出两枚,一共可以取出4种不同的钱数.()",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】根据题意,任意取出两枚,可以是1元和5角,1元和1角,5角和1角,共三种情况,据此判断.\n【详解】根据分析,有1元,5角,1角的硬币各一枚,一次取出两枚,一共可以取出3种不同的钱数.原题说法错误.故答案为: ×",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "24-25二年级上·河南南阳·期末"
+    },
+    {
+        "id":  "98",
+        "unit":  "搭配",
+        "question_type":  "判断题",
+        "difficulty":  0.65,
+        "question":  "用2,3,0这三个数字可以组成6个不同的两位数.()",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】把2,3,0这三个数字组成不同的两位数一一列举出来,即可解决此题.\n【详解】用2,3,0这三个数字组成不同的两位数有23,20,32,30.即,用2,3,0这三个数字可以组成4个不同的两位数;原题说法错误.故答案为: ×",
+        "knowledge_points":  [
+                                 "搭配问题",
+                                 "100以内数的组成"
+                             ],
+        "source":  "24-25二年级上·内蒙古巴彦淖尔·期末"
+    },
+    {
+        "id":  "99",
+        "unit":  "搭配",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "老师买了三个不同的奖品,要奖励给3个小朋友,一人一个.有多少种分法?",
+        "options":  [
+
+                    ],
+        "answer":  "6种",
+        "solution":  "【分析】根据题意,有三个不同的奖品,要奖励给3个小朋友,可以将奖品分为A,B,C,小朋友为1,2,3,依次写出各种分法即可解答.\n【详解】由分析得:第1种:1得A,2得B,3得C;第2种:1得A,2得C,3得B;第3种:1得B,2得A,3得C;第4种:1得B,2得C,3得A;第5种:1得C,2得A,3得B;第6种:1得C,2得B,3得A.答:有6种分法.",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "25-26一年级上·全国·课后作业"
+    },
+    {
+        "id":  "100",
+        "unit":  "搭配",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "稻田捉鱼是万峰林景区内最受欢迎的儿童游玩项目.小明抓了43条鱼,爸爸抓的鱼比小明多29条,妈妈抓鱼比小明少18条.\n(1)爸爸抓了多少条鱼?\n(2)妈妈抓了多少条鱼?\n(3)抓鱼后,小明一家三口坐成一排拍照,有多少种坐法?",
+        "options":  [
+
+                    ],
+        "answer":  "72条;25条;6种",
+        "solution":  "【分析】(1)小明抓了43条鱼,爸爸抓的鱼比小明多29条,求爸爸抓的鱼,用小明抓的鱼加上爸爸比小明多的29条即可求出;(2)小明抓了43条鱼,妈妈抓鱼比小明少18条,求妈妈抓的鱼,用小明抓的鱼减妈妈比小明少的18条即可求出;(3)熟练掌握搭配问题的计算方法是解答此题的关键,具体坐法按左中右排列.第1种小明,爸爸,妈妈,第2种小明,妈妈,爸爸,第3种爸爸,小明,妈妈,第4种爸爸,妈妈,小明,第5种妈妈,小明,爸爸,第6种妈妈,爸爸,小明;或者根据每一个人坐在左边,都有2种坐法,坐在右边,中间同理,则3个人就有2×3种坐法.\n【详解】(1)爸爸抓了多少条鱼?43+29=72(条),答:爸爸抓了72条鱼.(2)妈妈抓了多少条鱼?43-18=25(条),答:妈妈抓了25条鱼.(3)抓鱼后,小明一家三口坐成一排拍照,有多少种坐法?2×3=6(种),答:一共有6种不同的坐法.",
+        "knowledge_points":  [
+                                 "搭配问题",
+                                 "两位数与两位数的进位加法",
+                                 "两位数与两位数的退位减法"
+                             ],
+        "source":  "24-25二年级上·贵州黔西·期末"
+    },
+    {
+        "id":  "101",
+        "unit":  "搭配",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "用5元,20元,50元的纸币各一张,可以组成()种不同的币值.",
+        "options":  [
+                        "A. 3",
+                        "B. 4",
+                        "C. 6",
+                        "D. 7"
+                    ],
+        "answer":  "D",
+        "solution":  "【分析】可以分别用1张,2张,3张纸币组成不同币值,分别列举出来,看看有多少种,选择正确答案即可.\n【详解】用一张时:可能出现3种不同的币值,分别是:5元,20元,50元;用两张时:可能出现3种不同的币值,分别是:25元,55元,70元;用三张时:只能出现1种币值:75元.综上可知:可以组成7种不同的币值.故答案为:D",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "23-24二年级上·浙江宁波·期末"
+    },
+    {
+        "id":  "102",
+        "unit":  "搭配",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "有红,黄,蓝三种颜色,选两种颜色给下边圆形上色.如果将这个圆上,下分别涂上不同的颜色,有()种涂法.\n\n![](images/37d729fd9dd3e560624e5a3739e0718df7eb807a5f269f7cd5d3eb03ed01f1ae.jpg)",
+        "options":  [
+                        "A. 8",
+                        "B. 6",
+                        "C. 4",
+                        "D. 2"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】根据题意可知:可以将不同的两种颜色搭配在一起,即可求出一共几种涂色.\n【详解】上部分先涂红色,则下部分可以涂黄,蓝色,共2种;上部分先涂黄色,则下部分可以涂红,蓝色,共2种;上部分先涂蓝色,则下部分可以涂红,黄色,共2种.2+2+2=6(种),则有红,黄,蓝三种颜色,选两种颜色给下边圆形上色.如果将这个圆上,下分别涂上不同的颜色,有6种涂法.故答案为:B",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "23-24二年级上·浙江宁波·期末"
+    },
+    {
+        "id":  "103",
+        "unit":  "搭配",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "用5,7,0能摆成()个不同的两位数.",
+        "options":  [
+                        "A. 2",
+                        "B. 4",
+                        "C. 6"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】列举出每种可能,数一数即可,0不能放在最前面.\n【详解】可以摆成57,50,75,70,共4个.用5,7,0能摆成4个不同的两位数.故答案为:B",
+        "knowledge_points":  [
+                                 "搭配问题",
+                                 "100以内数的组成"
+                             ],
+        "source":  "23-24二年级上·河南郑州·期末"
+    },
+    {
+        "id":  "104",
+        "unit":  "搭配",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "3个同学坐成一排合影,有()种坐法.",
+        "options":  [
+                        "A. 5",
+                        "B. 6",
+                        "C. 4"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】将每种坐法列举出来数一数即可.从左到右可以是第一位,第二位,第三位,第一位,第三位,第二位,第二位,第一位,第三位,第二位,第三位,第一位,第三位,第一位,第二位,第三位,第二位,第一位.\n【详解】3个同学坐成一排合影,有6种坐法.故答案为:B",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "23-24二年级上·重庆丰都·期末"
+    },
+    {
+        "id":  "105",
+        "unit":  "搭配",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "三个小朋友打羽毛球,每两个小朋友之间打一场比赛,一共比()场.",
+        "options":  [
+                        "A. 6",
+                        "B. 4",
+                        "C. 3"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】可以用列举的方法来解决此题;先假设三个小朋友分别是甲,乙,丙,然后把所有的可能性一一列举出来即可.\n【详解】由题意分析得:假设三个小朋友分别是甲,乙,丙,则比赛场次有以下:甲与乙打1场,甲与丙打1场,乙与丙打1场,一共比3场.故答案为:C",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "23-24二年级上·新疆昌吉·期末"
+    },
+    {
+        "id":  "106",
+        "unit":  "搭配",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "用1,2,0这三个数字能摆成()个十位和个位不同的两位数.",
+        "options":  [
+                        "A. 2",
+                        "B. 4",
+                        "C. 6",
+                        "D. 8"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】一个两位数,从右往左依次为个位,十位.组成两位数时,十位不能为0,十位分别写1或2,由此写出组成的数解答即可.\n【详解】组成的两位数有:12,10,21,20.用1,2,0这三个数字能摆成4个十位和个位不同的两位数.故答案为:B",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "23-24二年级上·浙江绍兴·期末"
+    },
+    {
+        "id":  "107",
+        "unit":  "搭配",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "从6,8,2这3个数中,任意选取其中2个数求和,得数有()种可能.",
+        "options":  [
+                        "A. 2",
+                        "B. 4",
+                        "C. 3"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】从6,8,2这3个数中,任意选取其中2个数求和,可能的情况有6+2=8,6+8=14,8+2=10,即得出有3种可能.\n【详解】6+2=2+6=8,6+8=8+6=14,8+2=2+8=10,即得出有3种可能.故答案为:C",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "23-24二年级上·福建莆田·期末"
+    },
+    {
+        "id":  "108",
+        "unit":  "搭配",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "用卡片3,5和0组成的两位数中,最大的数与最小的数的和是().",
+        "options":  [
+                        "A. 80",
+                        "B. 88",
+                        "C. 83"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】用卡片3,5和0组成的两位数有30,35,50,53,最大的是53,最小的是30,用加法计算出两数之和即可.\n【详解】30\u003c35\u003c50\u003c53,30+53=83,即最大的数与最小的数的和是83.故答案为:C",
+        "knowledge_points":  [
+                                 "搭配问题",
+                                 "数字中的组合问题"
+                             ],
+        "source":  "23-24二年级上·全国·课后作业"
+    },
+    {
+        "id":  "109",
+        "unit":  "搭配",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "早餐店的主食有烧饼和油条,饮品有牛奶和豆浆,宁宁的早点有()种不同的搭配方法.",
+        "options":  [
+                        "A. 3",
+                        "B. 4",
+                        "C. 5"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】烧饼搭配牛奶或豆浆是2种搭配方法,油条搭配牛奶或豆浆是2种搭配方法,共4种搭配方法,据此得出结论即可.\n【详解】2+2=4(种),即有4种不同的搭配方法.故答案为:B",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "23-24二年级上·全国·课后作业"
+    },
+    {
+        "id":  "110",
+        "unit":  "搭配",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "有4人,每两人通一次电话,共通()次电话.",
+        "options":  [
+                        "A. 1",
+                        "B. 3",
+                        "C. 6"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】假设4个人分别是甲,乙,丙,丁,甲要和乙,丙,丁三人通话共3次,乙和丙,丁两人通话2次,丙和丁通话1次,共通话3+2+1=6(次).\n【详解】3+2+1=5+1=6(次),即共通话6次.故答案为:C",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "23-24二年级上·全国·课后作业"
+    },
+    {
+        "id":  "111",
+        "unit":  "搭配",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "用5,7能摆成()个两位数.",
+        "options":  [
+                        "A. 2",
+                        "B. 3",
+                        "C. 4"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】用5,7摆成的两位数有57和75,一共有2个;据此解决.\n【详解】由题意分析得:用5,7能摆成2个两位数.故答案为:A",
+        "knowledge_points":  [
+                                 "100以内数的组成",
+                                 "数字中的组合问题"
+                             ],
+        "source":  "23-24二年级上·全国·课后作业"
+    },
+    {
+        "id":  "112",
+        "unit":  "搭配",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "三个朋友下棋,每两人下一局,一共要下().",
+        "options":  [
+                        "A. 2局",
+                        "B. 3局",
+                        "C. 4局"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】由题意知,三个朋友下棋,每两人下一局,列举出所有的可能即可.\n【详解】比如有A,B,C三人,A和B两人下一局,A和C两人下一局,B和C两人下一局,总共是三局.故答案为:B",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "23-24二年级上·全国·课后作业"
+    },
+    {
+        "id":  "113",
+        "unit":  "搭配",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "在一个长方体的正面和上面分别涂上红色,黄色,绿色3种颜色中的一种,一共有()种不同的涂法.",
+        "options":  [
+                        "A. 6",
+                        "B. 8",
+                        "C. 9"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】用列举的方法来解决此题.有以下涂法:①正面涂红色,上面涂红色;②正面涂红色,上面涂黄色;③正面涂红色,上面涂绿色;④正面涂黄色,上面涂红色;⑤正面涂黄色,上面涂黄色;⑥正面涂黄色,上面涂绿色;⑦正面涂绿色,上面涂红色;⑧正面涂绿色,上面涂黄色;⑨正面涂绿色,上面涂绿色;据此解决.\n【详解】3×3=9(种),即,在一个长方体的正面和上面分别涂上红色,黄色,绿色3种颜色中的一种,一共有9种不同的涂法.故答案为:C",
+        "knowledge_points":  [
+                                 "用列举法解决搭配问题"
+                             ],
+        "source":  "23-24二年级上·全国·单元测试"
+    },
+    {
+        "id":  "114",
+        "unit":  "搭配",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "从1元,5元,10元中任意选两张或三张,一共可以组成()种不同的钱数.",
+        "options":  [
+                        "A. 3",
+                        "B. 4",
+                        "C. 9"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】任选两张可以是1元+5元=6元,1元+10元=11元,5元+10元=15元,选三张1元+5元+10元=16元,据此得出结论即可.\n【详解】1元+5元=6元,1元+10元=11元,5元+10元=15元,1元+5元+10元=6元+10元=16元,即一共组成4种不同的钱数.故答案为:B",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "23-24二年级上·全国·单元测试"
+    },
+    {
+        "id":  "115",
+        "unit":  "搭配",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "早餐店的主食有烧饼,油条和包子.饮品有牛奶,豆浆和小米粥.宁宁想买一种主食和一种饮品,一共有()种不同的搭配方法.",
+        "options":  [
+                        "A. 4",
+                        "B. 6",
+                        "C. 9"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】根据题意,每种主食都可以搭配3种饮品,共3种主食,则总的搭配方法有3个3种,由此解答.\n【详解】3×3=9(种),一共有9种不同的搭配方法.故答案为:C",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "23-24二年级上·全国·单元测试"
+    },
+    {
+        "id":  "116",
+        "unit":  "搭配",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "小石头家的电话号码是46532 □ □,最后两个数字由0,8,9中的两个数组成,那么他家的电话号码有()种可能.",
+        "options":  [
+                        "A. 5",
+                        "B. 6",
+                        "C. 7"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】0,8,9中的两个数可能的组成有08,80,09,90,89,98,据此得出结论即可.\n【详解】根据分析知:他家的电话号码可能是:4653208,4653280,4653209,4653290,4653289,4653298,共有6种可能.故答案为:B",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "23-24二年级上·全国·单元测试"
+    },
+    {
+        "id":  "117",
+        "unit":  "搭配",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "同学们用红色,黄色,蓝色三种不同的气球装扮教室,至少用一种,最多用三种,一共有()种不同的搭配.",
+        "options":  [
+                        "A. 3",
+                        "B. 5",
+                        "C. 7"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】根据题意,用一种颜色时,可以选择红色一种,黄色一种,蓝色一种,共3种方法;选择两种颜色时,可选择红色和黄色,红色和蓝色,黄色和蓝色,共3种方法;选择三种颜色时,可选择红色,黄色和蓝色,共1种方法.\n【详解】3+3+1=7(种),一共有7种不同的搭配.故答案为:C",
+        "knowledge_points":  [
+                                 "用列举法解决搭配问题"
+                             ],
+        "source":  "23-24二年级上·全国·单元测试"
+    },
+    {
+        "id":  "118",
+        "unit":  "搭配",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "从3本不同的书中选2本送给小清,小聪各1本,一共有()种送法.",
+        "options":  [
+                        "A. 2",
+                        "B. 3",
+                        "C. 6"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】从三本书中选1本,送给小清有3种选择,再从剩下的2本书中选1本,送给小聪有2种选择,所以三本书中送给小清,小聪各1本共有3×2=6种选择.\n【详解】3×2=6(种),一共有6种送法.故答案为:C",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "22-23二年级上·河南南阳·期末"
+    },
+    {
+        "id":  "119",
+        "unit":  "搭配",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "有()种穿法.\n\n![](images/6defa02eed3f6d045369e4e8223ad961cd5f471cde852f60dd23120cb375a82f.jpg)",
+        "options":  [
+                        "A. 3",
+                        "B. 4",
+                        "C. 5"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】1件上衣可以有2种裤子搭配,则2件上衣就可以有(2×2=4)种裤子搭配,据此解决.\n【详解】由题意分析得:2×2=4(种),即有4种穿法.故答案为:B",
+        "knowledge_points":  [
+                                 "搭配问题",
+                                 "2的乘法口诀及应用"
+                             ],
+        "source":  "22-23二年级上·山东菏泽·期末"
+    },
+    {
+        "id":  "120",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "小芳有3件不同的上衣和2条颜色不同的裙子,一件上衣配一条裙子,她有()种不同的穿法.",
+        "options":  [
+
+                    ],
+        "answer":  "6",
+        "solution":  "【分析】根据题意,1件上衣可以有2条裙子搭配,一共有3件上衣,则总的穿法也就是3个2种,由此解答.\n【详解】2×3=6(种),小芳有3件不同的上衣和2条颜色不同的裙子,一件上衣配一条裙子,她有6种不同的穿法.",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "24-25二年级上·吉林四平·期末"
+    },
+    {
+        "id":  "121",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "1元,5角,1角三个硬币,任意两个可以组成()种不同的面值,其中最大的面值是().",
+        "options":  [
+
+                    ],
+        "answer":  "3;1元5角",
+        "solution":  "【分析】根据题意,可以将1元和5角组合;1元和1角组合;5角和1角组合.分别计算出总面值,再比较大小,选择出最大的面值即可.根据1元=10角换算单位再比较.\n【详解】1元+5角=1元5角;1元+1角=1元1角;5角+1角=6(角);1元5角=15角;1元1角=11角;15角\u003e11角\u003e6角,则1元5角\u003e1元1角\u003e6角.因此,这三个硬币任意两个可以组成3种不同的面值,其中最大的面值是1元5角.",
+        "knowledge_points":  [
+                                 "搭配问题",
+                                 "元,角,分的认识及换算",
+                                 "十元以下人民币的认识与计算"
+                             ],
+        "source":  "23-24二年级上·河北保定·期末"
+    },
+    {
+        "id":  "122",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "用红,黄,绿三种颜色给下图中的两个气球涂上不同的颜色,每个气球只涂一种颜色,一共有()种不同的涂色方法.\n\n![](images/f04388db4a91dc512a1d13be3a1efa4487e0995fbc6febc67da983b063c8115b.jpg)",
+        "options":  [
+
+                    ],
+        "answer":  "6",
+        "solution":  "【分析】把所有的涂色可能性一一列举出,然后数一数,即可解决.\n【详解】用红,黄,绿三种颜色给两个气球涂上不同的颜色,有以下可能性:①左边涂红色,右边涂黄色;②左边涂黄色,右边涂红色;③左边涂红色,右边涂绿色;④左边涂绿色,右边涂红色;⑤左边涂黄色,右边涂绿色;⑥左边涂绿色,右边涂黄色;即,一共有6种不同的涂色方法.",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "23-24二年级上·河北保定·期末"
+    },
+    {
+        "id":  "123",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "用5,3,0三张卡片一共能组成()个十位数和个位数不同的两位数,分别是().",
+        "options":  [
+
+                    ],
+        "answer":  "4;53,50,30,35",
+        "solution":  "【分析】根据给出的数字,可以用列举的方法,先将5放在十位,个位有两种可能,再将3放在十位,个位有两种可能,0不能在十位,所以有4种可能,再将组成的数写出来即可.\n【详解】用5,3,0三张卡片一共能组成4个十位数和个位数不同的两位数,分别是53,50,30,35.",
+        "knowledge_points":  [
+                                 "100以内数的组成",
+                                 "数字中的组合问题"
+                             ],
+        "source":  "23-24二年级上·河北石家庄·期末"
+    },
+    {
+        "id":  "124",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "用3,2,9三个数可以组成()个不同的两位数,其中最小的是().",
+        "options":  [
+
+                    ],
+        "answer":  "6;23",
+        "solution":  "【分析】先固定十位上的数,然后选择个位上的数,再把组成的数列举出来,算一算多少个,并选出最小的数即可.\n【详解】由题意分析得:用3,2,9三个数可以组成不同的两位数有:32,39,23,29,93,92,一共组成6个不同的两位数;23\u003c29\u003c32\u003c39\u003c92\u003c93,其中最小的是23.即,用3,2,9三个数可以组成6个不同的两位数,其中最小的是23.",
+        "knowledge_points":  [
+                                 "搭配问题",
+                                 "100以内数的比大小"
+                             ],
+        "source":  "23-24二年级上·甘肃天水·期末"
+    },
+    {
+        "id":  "125",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "用2,6,8三个数,这三个数中任意选取两个数求和,得数有()种可能.",
+        "options":  [
+
+                    ],
+        "answer":  "3",
+        "solution":  "【分析】从三个数中任意取出两个数求和出现的可能性有:如果选出的数字是2和6,那么这两个数字的和是2+6=8;如果选出的两个数字是2和8,这两个数字的和是2+8=10;选出的数字是6和8,那么这两个数字的和是6+8=14.所以得数一共有3种可能.\n【详解】由题意分析得:2+6=8,2+8=10,6+8=14;即,用2,6,8三个数,这三个数中任意选取两个数求和,得数有3种可能.",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "24-25二年级上·西藏那曲·期末"
+    },
+    {
+        "id":  "126",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "你能用2,0,4这三张数字卡片组成()个不同的两位数,其中最大的数是(),最小的数是(),它们相差().",
+        "options":  [
+
+                    ],
+        "answer":  "4;42;20;22",
+        "solution":  "【分析】先把用2,0,4这三张数字卡片组成不同的两位数一一列举出来,然后比较大小,即可找出最大的数和最小的数,并作差,即可解决.\n【详解】用2,0,4这三张数字卡片组成不同的两位数有:20,24,40,42,一共4个;20\u003c24\u003c40\u003c42;42-20=22,即,用2,0,4这三张数字卡片组成4个不同的两位数,其中最大的数是42,最小的数是20,它们相差22.",
+        "knowledge_points":  [
+                                 "搭配问题",
+                                 "100以内数的比大小",
+                                 "两位数与整十数的减法"
+                             ],
+        "source":  "23-24二年级上·新疆昌吉·期末"
+    },
+    {
+        "id":  "127",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "用8,6,5可以组成()个不同的两位数.",
+        "options":  [
+
+                    ],
+        "answer":  "6",
+        "solution":  "【分析】分别列出可以组成的各个数字:56,65,58,85,68,86,一共有6个.\n【详解】用8,6,5可以组成6个不同的两位数.",
+        "knowledge_points":  [
+                                 "搭配问题",
+                                 "100以内数的组成"
+                             ],
+        "source":  "23-24二年级上·四川广元·期末"
+    },
+    {
+        "id":  "128",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "请从4,5,9三个数中任意选择两个数求和,得数有()种.",
+        "options":  [
+
+                    ],
+        "answer":  "3",
+        "solution":  "【分析】将这三个数,两两相加,数出得数有几种可能.\n【详解】选取4,5的和为:4+5=9;选取4,9的和为:4+9=13;选取5,9的和为:5+9=14;结果有3种可能.则从4,5,9这三个数中任意选取其中的两个数求和,得数有3种可能.",
+        "knowledge_points":  [
+                                 "搭配问题",
+                                 "8,9的加减法",
+                                 "5~2加几的进位加法"
+                             ],
+        "source":  "23-24二年级上·四川德阳·期末"
+    },
+    {
+        "id":  "129",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "用\"读\",\"书\",\"好\"三个汉字排一排,一共有()种排法.",
+        "options":  [
+
+                    ],
+        "answer":  "6",
+        "solution":  "【分析】用\"读\",\"书\",\"好\"三个汉字排一排,可以排成读书好,读好书,好读书,好书读,书好读,书读好,一共有6种排法.据此得出结论即可.\n【详解】用\"读\",\"书\",\"好\"三个汉字排一排,一共有6种排法.",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "23-24二年级上·福建福州·期末"
+    },
+    {
+        "id":  "130",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "用3,4和8组成两位数,每个两位数的十位数字和个位数字不能一样,能组成()个两位数.其中最大的是(),最小的是().",
+        "options":  [
+
+                    ],
+        "answer":  "6;84;34",
+        "solution":  "【分析】用3,4和8组成两位数,每个两位数的十位数字和个位数字不能一样,先确定十位上的数,再确定个位上的数,由此写出可以组成的两位数有34,38,43,48,83,84,共有6个.再将这些数比较大小,找出最大的数和最小的数即可.两位数比较大小,先比较十位上的数字,十位上的数字大,这个数就大;十位上的数字相同,就比较个位上的数字,个位上的数字大,这个数就大.\n【详解】34\u003c38\u003c43\u003c48\u003c83\u003c84,最大的是84,最小的是34.用3,4和8组成两位数,每个两位数的十位数字和个位数字不能一样,能组成6个两位数.其中最大的是84,最小的是34.",
+        "knowledge_points":  [
+                                 "搭配问题",
+                                 "100以内数的比大小"
+                             ],
+        "source":  "23-24二年级上·福建福州·期末"
+    },
+    {
+        "id":  "131",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "用1,6,8组成两位数,十位数字和个位数字不能一样,能组成()个两位数.其中最大的是(),最小的是().",
+        "options":  [
+
+                    ],
+        "answer":  "6;86;16",
+        "solution":  "【分析】一个两位数,从右往左依次为个位,十位.要组成两位数时,将其中一个数写在十位,另外两个数分别写在个位,由此写出数字,数出个数即可.再比较它们的大小,比较时,都是两位数,十位大的数就大;十位相同比较个位,个位大的数就大.\n【详解】由分析可知,组成的两位数有:16,18,61,68,81,86.86\u003e81\u003e68\u003e61\u003e18\u003e16.用1,6,8组成两位数,十位数字和个位数字不能一样,能组成6个两位数.其中最大的是86,最小的是16.",
+        "knowledge_points":  [
+                                 "搭配问题",
+                                 "100以内数的比大小"
+                             ],
+        "source":  "23-24二年级上·湖南湘西·期末"
+    },
+    {
+        "id":  "132",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "用3,6,8能组成()个十位数字和个位数字不一样的两位数,其中最大的两位数是(),最小的两位数是().",
+        "options":  [
+
+                    ],
+        "answer":  "6;86;36",
+        "solution":  "【分析】每个数字都可以作为十位上的数字,先确定一个十位上的数字,个位上有两个数字可以选择,这样写出所有组成的两位数,然后把写出的数从大到小比较,即可求出最大的数和最小的数.\n【详解】由分析可得:组成的数有36,38,63,68,83,86,能组成6个;从大到小排列:86\u003e83\u003e68\u003e63\u003e38\u003e36.则用3,6,8能组成6个十位数字和个位数字不一样的两位数,其中最大的两位数是86,最小的两位数是36.",
+        "knowledge_points":  [
+                                 "100以内数的比大小",
+                                 "100以内数的组成",
+                                 "数字中的组合问题"
+                             ],
+        "source":  "23-24二年级上·重庆璧山·期末"
+    },
+    {
+        "id":  "133",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "从2,7,8这三个数中任意取其中2个数求和,得数有()种可能.",
+        "options":  [
+
+                    ],
+        "answer":  "3",
+        "solution":  "【分析】根据题意,任意取其中2个数求和,可以选择2和7,2和8,7和8,由此计算解答.\n【详解】2+7=9;2+8=10;7+8=15.从2,7,8这三个数中任意取其中2个数求和,得数有3种可能.",
+        "knowledge_points":  [
+                                 "搭配问题",
+                                 "8,9的加减法",
+                                 "10的加减法",
+                                 "7,6加几的进位加法"
+                             ],
+        "source":  "23-24二年级上·福建三明·期末"
+    },
+    {
+        "id":  "134",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "从4,6,0三个数字中选两个,每个两位数的十位数字和个位数字不能一样,可以组成()个不同的两位数.",
+        "options":  [
+
+                    ],
+        "answer":  "4",
+        "solution":  "【分析】一个两位数,从右往左依次为个位,十位.要组成两位数,十位不能为0,先确定十位上的数,再确定个位上的数,由此写出组成的数字,数出数量即可.\n【详解】组成的数字有:46,40,64,60.从4,6,0三个数字中选两个,每个两位数的十位数字和个位数字不能一样,可以组成4个不同的两位数.",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "23-24二年级上·河南安阳·期末"
+    },
+    {
+        "id":  "135",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "用3,5,8这三张数字卡片能组成()个不同的两位数.",
+        "options":  [
+
+                    ],
+        "answer":  "6",
+        "solution":  "【分析】把3,5,8这三张数字卡片组成不同的两位数一一列举出来,再数一数有几个,即可解决.\n【详解】由分析得:组成不同的两位数有:35,38,53,58,85,83;用3,5,8这三张数字卡片能组成6个不同的两位数.",
+        "knowledge_points":  [
+                                 "100以内数的组成",
+                                 "数字中的组合问题"
+                             ],
+        "source":  "23-24二年级上·重庆永川·期末"
+    },
+    {
+        "id":  "136",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "从3,6,8这三个数中任选两个数求和,一共有()种不同的结果.",
+        "options":  [
+
+                    ],
+        "answer":  "3",
+        "solution":  "【分析】3分别和6,8相加的和:3+6=9,3+8=11,有2种;6和8相加:6+8=14,有1种;然后把求出不同结果的数量相加即可求出一共有多少种,即2+1=3(种).\n【详解】由分析可得:从3,6,8这三个数中任选两个数求和,一共有3种不同的结果.",
+        "knowledge_points":  [
+                                 "搭配问题",
+                                 "7,6加几的进位加法",
+                                 "5~2加几的进位加法"
+                             ],
+        "source":  "2024二年级上·全国·专题练习"
+    },
+    {
+        "id":  "137",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "乐乐,强强,洋洋坐成一排合影,有()种坐法.",
+        "options":  [
+
+                    ],
+        "answer":  "6",
+        "solution":  "【分析】可以先排一个人,再排另外两个人,将3个人所有坐法列举出来,即可解答.乐乐,强强,洋洋;乐乐,洋洋,强强;强强,乐乐,洋洋;强强,洋洋,乐乐;洋洋,乐乐,强强;洋洋,强强,乐乐,共有6种坐法.\n【详解】乐乐,强强,洋洋坐成一排合影,有6种坐法.",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "23-24二年级下·河北唐山·期末"
+    },
+    {
+        "id":  "138",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "用2,0,6这三张数字卡片,能摆成()个不同的两位数,其中最小的两位数是().",
+        "options":  [
+
+                    ],
+        "answer":  "4;20",
+        "solution":  "【分析】用2,0,6这三张数字卡片组成不同的两位数,可以组成:20,26,62,60,共4个.4个数字进行比较即可得到最小的两位数.\n【详解】62\u003e60\u003e26\u003e20,用2,0,6这三张数字卡片,能摆成4个不同的两位数,其中最小的两位数是20.",
+        "knowledge_points":  [
+                                 "搭配问题",
+                                 "100以内数的比大小"
+                             ],
+        "source":  "23-24二年级下·贵州铜仁·期末"
+    },
+    {
+        "id":  "139",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "从6,8,9这3个数中,任意选取其中2个求和,得数有()种可能.",
+        "options":  [
+
+                    ],
+        "answer":  "3",
+        "solution":  "【分析】任意选取其中2个求和,相当于两两组合,据此列举即可.\n【详解】6+8=14;6+9=15;8+9=17,得数有3种可能.",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "22-23二年级上·福建莆田·期末"
+    },
+    {
+        "id":  "140",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "妈妈去买早餐,有3种主食(面包,油饼,油条),3种饮品(牛奶,豆浆,果汁),妈妈要选择一种主食和一种饮品,有()种不同的买法.",
+        "options":  [
+
+                    ],
+        "answer":  "9",
+        "solution":  "【分析】每种主食都会有3种饮料与它搭配,共有3种主食,所以共有(3×3=9)种不同的买法,列举出所有的买法即可.\n【详解】由题意分析得:①面包,牛奶;②面包,豆浆;③面包,果汁;④油饼,牛奶;⑤油饼,豆浆;⑥油饼,果汁;⑦油条,牛奶;⑧油条,豆浆;⑨油条,果汁.即,妈妈去买早餐,有3种主食(面包,油饼,油条),3种饮品(牛奶,豆浆,果汁),妈妈要选择一种主食和一种饮品,有9种不同的买法.",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "23-24二年级上·福建莆田·期末"
+    },
+    {
+        "id":  "141",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "小兔回家有()种走法.\n\n![](images/e6308bb1d2ffa3ccb9cf638a88bc7865a83c62bb51184dfc8c85ae14655da2d1.jpg)",
+        "options":  [
+
+                    ],
+        "answer":  "6",
+        "solution":  "【分析】小兔走到中间位置,有2种不同的走法,而中间位置到家又有3种不同走法,因此一共有3个2种不同的走法;据此解决.\n【详解】2×3=6(种),即小兔回家有6种走法.",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "23-24二年级上·全国·课后作业"
+    },
+    {
+        "id":  "142",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "用3,5,8这三张数字卡片能摆成()个不同的两位数,它们分别是().",
+        "options":  [
+
+                    ],
+        "answer":  "6;35,38,53,58,83,85",
+        "solution":  "【分析】用列举的方法把3,5,8这三张数字卡片组成的两位数一一列举出来,然后数一数一共有几个,即可解决.\n【详解】由题意分析得:用3,5,8这三张数字卡片摆成不同的两位数有:35,38,53,58,83,85,即,用3,5,8这三张数字卡片能摆成6个不同的两位数,它们分别是:35,38,53,58,83,85.",
+        "knowledge_points":  [
+                                 "搭配问题",
+                                 "数字中的组合问题"
+                             ],
+        "source":  "23-24二年级上·全国·课后作业"
+    },
+    {
+        "id":  "143",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "鹿,猴,兔三只小动物站成一队,一共有()种不同的站法.",
+        "options":  [
+
+                    ],
+        "answer":  "6",
+        "solution":  "【分析】鹿,猴,兔三只小动物站成一队,不同的站法有:①鹿,猴,兔,②鹿,兔,猴,③兔,鹿,猴,④兔,猴,鹿,⑤猴,兔,鹿,⑥猴,鹿,兔;一共有6种不同的站法.\n【详解】由题意分析得:三只小动物站成一队,一共有6种不同的站法.",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "23-24二年级上·全国·课后作业"
+    },
+    {
+        "id":  "144",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "用数字3,6,8可组成()个两位数,分别是().",
+        "options":  [
+
+                    ],
+        "answer":  "6;36,38,63,68,83,86",
+        "solution":  "【分析】十位数字是3时,个位数字可以是6也可以是8,即组成的两位数是36和38;十位数字是6时,个位数字可以是3也可以是8,即组成的两位数是63和68;十位数字是8时,个位数字可以是3也可以是6,即组成的两位数是83和86;一共6个;据此得出结论即可.\n【详解】用数字3,6,8可组成6个两位数,分别是36,38,63,68,83,86.",
+        "knowledge_points":  [
+                                 "数字中的排列问题"
+                             ],
+        "source":  "23-24二年级上·全国·课后作业"
+    },
+    {
+        "id":  "145",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "用数字1,2组成的两位数有()个,分别是().",
+        "options":  [
+
+                    ],
+        "answer":  "2;12,21",
+        "solution":  "【分析】用数字1,2组成的两位数,①把1放在十位数,2放在个位上,组成的数是12;②把2放在十位数,1放在个位上,组成的数是21;也就是用数字1,2组成的两位数有2个.\n【详解】由题意分析得:用数字1,2组成的两位数有2个,分别是12,21.",
+        "knowledge_points":  [
+                                 "100以内数的组成",
+                                 "数字中的组合问题"
+                             ],
+        "source":  "23-24二年级上·全国·课后作业"
+    },
+    {
+        "id":  "146",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "用数字2,0,5可组成()个两位数,分别是().",
+        "options":  [
+
+                    ],
+        "answer":  "4;20,25,50,52",
+        "solution":  "【分析】一个两位数的十位不能是0,十位数字是2时,个位数字是0或者5,组成的两位数是20和25;十位数字是5时,个位数字是0或者2,组成的两位数是50和52,一共能组成4个两位数,据此得出结论即可.\n【详解】用数字2,0,5可组成4个两位数,分别是20,25,50,52.",
+        "knowledge_points":  [
+                                 "含0的组数问题"
+                             ],
+        "source":  "23-24二年级上·全国·课后作业"
+    },
+    {
+        "id":  "147",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "四个小朋友需要互相握手,每两个小朋友握一次手,一共需要握()次手.",
+        "options":  [
+
+                    ],
+        "answer":  "6",
+        "solution":  "【分析】根据题意,每两个小朋友握一次手,4个小朋友分别标记为A,B,C,D.从A开始握,需要与B,C,D握手;B需要与C,D握手;C需要与D握手.将次数相加就是总次数.\n【详解】3+2+1=6(次),四个小朋友需要互相握手,每两个小朋友握一次手,一共需要握6次手.",
+        "knowledge_points":  [
+                                 "用列举法解决搭配问题"
+                             ],
+        "source":  "23-24二年级上·全国·单元测试"
+    },
+    {
+        "id":  "148",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在4,6,8三个数中任选两个数求和,得数有()种可能.",
+        "options":  [
+
+                    ],
+        "answer":  "3",
+        "solution":  "【分析】根据题意,可以选择4和6,4和8,6和8,计算出结果解答即可.\n【详解】4+6=10;4+8=12;6+8=14.在4,6,8三个数中任选两个数求和,得数有10,12,14,共3种可能.",
+        "knowledge_points":  [
+                                 "搭配问题",
+                                 "10的加减法",
+                                 "7,6加几的进位加法",
+                                 "5~2加几的进位加法"
+                             ],
+        "source":  "23-24二年级上·全国·单元测试"
+    },
+    {
+        "id":  "149",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "4个好朋友互相送礼物,一共送了()份.",
+        "options":  [
+
+                    ],
+        "answer":  "12",
+        "solution":  "【分析】4个好朋友互相送礼物,每个人都要为其他三个人准备礼物,因此每个人要送三次礼物,用人数乘每个人要送的次数,四个人一共送了十二次礼物,也就是十二份礼物.\n【详解】4×3=12(份),4个好朋友互相送礼物,一共送了12份.",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "23-24二年级上·全国·单元测试"
+    },
+    {
+        "id":  "150",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "田童有两件不同的上衣,两条不同的裙子,一件上衣搭配一条裙子,她有()种搭配方法.",
+        "options":  [
+
+                    ],
+        "answer":  "4",
+        "solution":  "【分析】根据题意,每件上衣可以搭配一条裙子,共两件上衣,总的搭配方法有2个2种,由此解答.\n【详解】2×2=4(种),田童有两件不同的上衣,两条不同的裙子,一件上衣搭配一条裙子,她有4种搭配方法.",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "23-24二年级上·全国·单元测试"
+    },
+    {
+        "id":  "151",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "用4,7,0可以组成()个个位数字和十位数字都不一样的两位数.",
+        "options":  [
+
+                    ],
+        "answer":  "4",
+        "solution":  "【分析】根据题意,用4,7,0可以组成的个位数字和十位数字都不一样的两位数有:40,47,70,74,一共4个.\n【详解】用4,7,0可以组成4个个位数字和十位数字都不一样的两位数.",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "23-24二年级上·全国·单元测试"
+    },
+    {
+        "id":  "152",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "用数字3,5,8组成的两位数,最大的是(),最小的是().",
+        "options":  [
+
+                    ],
+        "answer":  "85;35",
+        "solution":  "【分析】把用数字3,5,8组成的两位数都写出来,即有:35,38,53,58,83,85,比较大小.\n【详解】由题意分析得:85\u003e83\u003e58\u003e53\u003e38\u003e35.用数字3,5,8组成的两位数,最大的是85,最小的是35.",
+        "knowledge_points":  [
+                                 "搭配问题",
+                                 "100以内数的比大小"
+                             ],
+        "source":  "23-24二年级上·全国·单元测试"
+    },
+    {
+        "id":  "153",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "三名同学排成一排合影,有()种不同的排法.",
+        "options":  [
+
+                    ],
+        "answer":  "6",
+        "solution":  "【分析】把三名同学排成一排,依次列举每种可能,即可求得不同排法的数量.\n【详解】三名同学排成一排合影,一共有6种不同的排法.",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "23-24二年级上·全国·单元测试"
+    },
+    {
+        "id":  "154",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "用4,7,9可以写出()个两位数,其中最大的是(),最小的是().",
+        "options":  [
+
+                    ],
+        "answer":  "6;97;47",
+        "solution":  "【分析】把用4,7,9能写出的两位数都写出来,即有:47,49,74,79,94,97.然后比较大小,找出最小的和最大的即可.\n【详解】由题意分析得:用4,7,9可以写出6个两位数,其中最大的是97,最小的是47.",
+        "knowledge_points":  [
+                                 "搭配问题",
+                                 "100以内数的比大小"
+                             ],
+        "source":  "23-24二年级上·全国·单元测试"
+    },
+    {
+        "id":  "155",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "用2,4,7可以写出()个十位数字和个位数字不相同的两位数.",
+        "options":  [
+
+                    ],
+        "answer":  "6",
+        "solution":  "【分析】根据题意,把用2,4,7写出的两位数列出来即可求出它们的个数.\n【详解】由题意分析得:用2,4,7可以写出6个十位数字和个位数字不相同的两位数.",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "23-24二年级上·全国·单元测试"
+    },
+    {
+        "id":  "156",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "学校要从乒乓球,足球,篮球3个兴趣小组中选取两个参加比赛,共有()种不同的选法.",
+        "options":  [
+
+                    ],
+        "answer":  "3",
+        "solution":  "【分析】根据题意,可以把所有选法列举出来.乒乓球和足球,乒乓球和篮球,足球和篮球,一共3种选法.\n【详解】学校要从乒乓球,足球,篮球3个兴趣小组中选取两个参加比赛,共有3种不同的选法.",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "23-24二年级上·全国·单元测试"
+    },
+    {
+        "id":  "157",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "商店里有红,黄,蓝三种围巾,小芳和小明每人选一种颜色的围巾,且两人的颜色不同,一共有()种不同的颜色搭配.",
+        "options":  [
+
+                    ],
+        "answer":  "6",
+        "solution":  "【分析】小芳可以选择红,黄,蓝三种颜色;小明在小芳选择的颜色之外还有两种选择,因此每种小芳的选择对应两种小明的选择,共3×2=6种搭配.\n【详解】红黄,红蓝,黄红,黄蓝,蓝红,蓝黄,一共6种不同的颜色搭配.",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "23-24二年级上·全国·单元测试"
+    },
+    {
+        "id":  "158",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "用3,5,9这三个数字可以组成()个不同的两位数.",
+        "options":  [
+
+                    ],
+        "answer":  "6",
+        "solution":  "【分析】把3,5,9这三个数字组成的两位数列出来:35,39,53,59,93,95,一共6个.\n【详解】用3,5,9这三个数字可以组成6个不同的两位数.",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "23-24二年级上·全国·单元测试"
+    },
+    {
+        "id":  "159",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "有3个同学,每两个同学之间都要握手一次,一共需要握手()次.",
+        "options":  [
+
+                    ],
+        "answer":  "3",
+        "solution":  "【分析】把三个同学记作A,B,C.握手的组合有:A和B,A和C,B和C,一共3次.\n【详解】有3个同学,每两个同学之间都要握手一次,一共需要握手3次.",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "23-24二年级上·全国·单元测试"
+    },
+    {
+        "id":  "160",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "用1,3,7可以写出()个两位数,其中最大的两位数和最小的两位数相差().",
+        "options":  [
+
+                    ],
+        "answer":  "6;60",
+        "solution":  "【分析】用1,3,7写出的两位数有:13,17,31,37,71,73.最大的是73,最小的是13,它们的差为73-13=60.\n【详解】用1,3,7可以写出6个两位数,其中最大的两位数和最小的两位数相差60.",
+        "knowledge_points":  [
+                                 "搭配问题",
+                                 "100以内数的比大小"
+                             ],
+        "source":  "23-24二年级上·全国·单元测试"
+    },
+    {
+        "id":  "161",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "用数字2,5,8组成两位数,十位数字和个位数字不能一样,可以组成()个不同的两位数.",
+        "options":  [
+
+                    ],
+        "answer":  "6",
+        "solution":  "【分析】用2,5,8组成两位数,十位数字与个位数字不同的两位数有:25,28,52,58,82,85,共6个.\n【详解】用数字2,5,8组成两位数,十位数字和个位数字不能一样,可以组成6个不同的两位数.",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "23-24二年级上·全国·单元测试"
+    },
+    {
+        "id":  "162",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "4个同学一共要握()次手.",
+        "options":  [
+
+                    ],
+        "answer":  "6",
+        "solution":  "【分析】4个同学之间两两握手,组合有:1号和2号,1号和3号,1号和4号,2号和3号,2号和4号,3号和4号,共6次.\n【详解】4个同学一共要握6次手.",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "23-24二年级上·全国·单元测试"
+    },
+    {
+        "id":  "163",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "从3,5,9这三个数中任选两个求和,得数有()种不同的可能.",
+        "options":  [
+
+                    ],
+        "answer":  "3",
+        "solution":  "【分析】两两相加:3+5=8,3+9=12,5+9=14,共3种得数.\n【详解】从3,5,9这三个数中任选两个求和,得数有3种不同的可能.",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "23-24二年级上·全国·单元测试"
+    },
+    {
+        "id":  "164",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "用数字1,4,7组成的所有两位数中,最大的是(),最小的是().",
+        "options":  [
+
+                    ],
+        "answer":  "74;14",
+        "solution":  "【分析】用1,4,7组成的两位数有:14,17,41,47,71,74.比较大小可知最大和最小.\n【详解】由题意分析得:用数字1,4,7组成的所有两位数中,最大的是74,最小的是14.",
+        "knowledge_points":  [
+                                 "搭配问题",
+                                 "100以内数的比大小"
+                             ],
+        "source":  "23-24二年级上·全国·单元测试"
+    },
+    {
+        "id":  "165",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "5个同学每两人握一次手,共要握()次.",
+        "options":  [
+
+                    ],
+        "answer":  "10",
+        "solution":  "【分析】5个同学之间两两握手,可以理解为4+3+2+1=10.\n【详解】5个同学每两人握一次手,共要握10次.",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "23-24二年级上·全国·单元测试"
+    },
+    {
+        "id":  "166",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "用数字1,3,8可以写出()个两位数.",
+        "options":  [
+
+                    ],
+        "answer":  "6",
+        "solution":  "【分析】用1,3,8能写出的两位数有:13,18,31,38,81,83,共6个.\n【详解】用数字1,3,8可以写出6个两位数.",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "23-24二年级上·全国·单元测试"
+    },
+    {
+        "id":  "167",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "用2,6,8这三个数能组成()个不同的两位数.",
+        "options":  [
+
+                    ],
+        "answer":  "6",
+        "solution":  "【分析】用2,6,8能组成的不同两位数有:26,28,62,68,82,86,共6个.\n【详解】用2,6,8这三个数能组成6个不同的两位数.",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "23-24二年级上·全国·单元测试"
+    },
+    {
+        "id":  "168",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "小雨,小雪,小丽三个同学每两人拥抱一次,三个人一共要拥抱()次.",
+        "options":  [
+
+                    ],
+        "answer":  "3",
+        "solution":  "【分析】三人之间两两拥抱一次,组合为3对,一共3次.\n【详解】小雨,小雪,小丽三个同学每两人拥抱一次,三个人一共要拥抱3次.",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "23-24二年级上·全国·单元测试"
+    },
+    {
+        "id":  "169",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "用3,5,9可以写出()个不同的两位数.",
+        "options":  [
+
+                    ],
+        "answer":  "6",
+        "solution":  "【分析】用3,5,9写出的不同两位数有:35,39,53,59,93,95,共6个.\n【详解】用3,5,9可以写出6个不同的两位数.",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "23-24二年级上·全国·单元测试"
+    },
+    {
+        "id":  "170",
+        "unit":  "搭配",
+        "question_type":  "判断题",
+        "difficulty":  0.65,
+        "question":  "3个小朋友两个人跳一次舞,一共要跳3次.()",
+        "options":  [
+
+                    ],
+        "answer":  "√",
+        "solution":  "【分析】第一个人和第二个人跳一次,第二个人和第三个人跳一次,第一个人和第三个人跳一次,一共可以跳3次,据此解答.\n【详解】3个小朋友两个人跳一次舞,一共要跳3次.原题说法正确.故答案为:√",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "23-24二年级上·河南南阳·期末"
+    },
+    {
+        "id":  "171",
+        "unit":  "搭配",
+        "question_type":  "判断题",
+        "difficulty":  0.65,
+        "question":  "3个同学相见,每两个同学握一次手,一共要握3次.()",
+        "options":  [
+
+                    ],
+        "answer":  "√",
+        "solution":  "【分析】有3个同学(分别记作是甲,乙,丙),每两个同学握一次手,握手情况如下:甲与乙,甲与丙,乙与丙,由此解答.\n【详解】由分析可知,3个同学相见,每两个同学握一次手,共要握3次.原题说法正确.故答案为:√",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "23-24二年级上·重庆永川·期末"
+    },
+    {
+        "id":  "172",
+        "unit":  "搭配",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "甲,乙,丙3人每2人通一次电话,3人一共通了2次电话.()",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】甲,乙,丙3人每2人通一次电话,可以通过列举的方法来解决此题.\n【详解】由题意分析得:甲,乙,丙3人每2人通一次电话,甲乙通话1次,甲丙通话1次,乙丙通话1次,一共通3次电话;原说法错误.故答案为: ×",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "23-24二年级下·河北邯郸·期末"
+    },
+    {
+        "id":  "173",
+        "unit":  "搭配",
+        "question_type":  "判断题",
+        "difficulty":  0.65,
+        "question":  "用2,6和0组成两位数,每个两位数的十位数字和个位数字不能一样,可以组成6个两位数.()",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】先确定十位上的数字,再确定个位上的数字:当十位是2时,个位是6或0,有两种情况;当十位是6时,个位是2或0;据此列举即可.注意0不能放在最高位.\n【详解】用2,6和0组成两位数,每个两位数的十位数字和个位数字不能一样,可以组成的数有:26,20,62,60,可以组成4个两位数.原题说法错误.故答案为: ×",
+        "knowledge_points":  [
+                                 "搭配问题",
+                                 "100以内数的组成"
+                             ],
+        "source":  "22-23二年级上·福建莆田·期末"
+    },
+    {
+        "id":  "174",
+        "unit":  "搭配",
+        "question_type":  "判断题",
+        "difficulty":  0.65,
+        "question":  "有4件上衣,5条裤子,共有9种不同的穿法.()",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】当选择其中1件上衣时,裤子有5种不同的穿法,而上衣有4件,因此一共有4个5种不同的穿法;据此解决即可.\n【详解】4×5=20(种),即有4件上衣,5条裤子,共有20种不同的穿法;原说法错误.故答案为: ×",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "23-24二年级上·全国·课后作业"
+    },
+    {
+        "id":  "175",
+        "unit":  "搭配",
+        "question_type":  "判断题",
+        "difficulty":  0.65,
+        "question":  "把苹果,梨,香蕉各一个摆成一排,有6种不同的摆法.()",
+        "options":  [
+
+                    ],
+        "answer":  "√",
+        "solution":  "【分析】通过列举的方法来解决此题即可.\n【详解】把苹果,梨,香蕉各一个摆成一排,有以下摆法:①苹果,梨,香蕉,②苹果,香蕉,梨,③梨,苹果,香蕉,④梨,香蕉,苹果,⑤香蕉,梨,苹果,⑥香蕉,苹果,梨,一共有6种不同的摆法;原说法正确.故答案为:√",
+        "knowledge_points":  [
+                                 "排列问题"
+                             ],
+        "source":  "23-24二年级上·全国·课后作业"
+    },
+    {
+        "id":  "176",
+        "unit":  "搭配",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "用3和5组成两位数,只能组成一个两位数.()",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】用3和5组成两位数有35和53,一共组成两个两位数;据此解决.\n【详解】由题意分析得:用3和5组成两位数,能组成两个两位数;原说法错误.故答案为: ×",
+        "knowledge_points":  [
+                                 "100以内数的组成",
+                                 "数字中的组合问题"
+                             ],
+        "source":  "23-24二年级上·全国·课后作业"
+    },
+    {
+        "id":  "177",
+        "unit":  "搭配",
+        "question_type":  "判断题",
+        "difficulty":  0.65,
+        "question":  "用1,4和7可以组成6个不同的两位数.()",
+        "options":  [
+
+                    ],
+        "answer":  "√",
+        "solution":  "【分析】用1,4和7可以组成的两位数有14,41,17,71,47,74,据此得出结论即可.\n【详解】用1,4和7可以组成14,41,17,71,47,74,共6个不同的两位数,原题说法正确.故答案为:√",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "23-24二年级上·全国·单元测试"
+    },
+    {
+        "id":  "178",
+        "unit":  "搭配",
+        "question_type":  "判断题",
+        "difficulty":  0.65,
+        "question":  "小明,小红,小兰3个人排队,有6种不同的排法.()",
+        "options":  [
+
+                    ],
+        "answer":  "√",
+        "solution":  "【分析】根据题意,为了不重复,不遗漏,可以分别使小明,小红,小兰站在第一个位置,然后改变后两个人的顺序,结合上述分析用列举法将所有的排列方法写出来即可解答.\n【详解】由分析排列如下:小明,小红,小兰;小明,小兰,小红;小红,小明,小兰;小红,小兰,小明;小兰,小明,小红;小兰,小红,小明.小明,小红,小兰3个人排队,有6种不同的排法.原题说法正确.故答案为:√",
+        "knowledge_points":  [
+                                 "搭配问题",
+                                 "用列举法解决搭配问题"
+                             ],
+        "source":  "23-24二年级上·全国·单元测试"
+    },
+    {
+        "id":  "179",
+        "unit":  "搭配",
+        "question_type":  "判断题",
+        "difficulty":  0.65,
+        "question":  "小刚有3件上衣,2条裤子,一共有5种不同的穿法.()",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】根据题意知,有三件上衣,2条裤子,每件上衣都可以搭配2条裤子,有3件上衣就是有3个2相加,即2+2+2=3×2=6(种)不同的穿法.\n【详解】3×2=6(种),所以有6种不同的穿法,故答案为: ×",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "23-24二年级上·全国·单元测试"
+    },
+    {
+        "id":  "180",
+        "unit":  "搭配",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "用1,4,5能组成6个不同的两位数.()",
+        "options":  [
+
+                    ],
+        "answer":  "√",
+        "solution":  "【分析】一个两位数,从右往左依次为个位,十位.组成两位数时,可用其中一个数作为十位,另外两个数分别作为个位.组成的数有14,15,41,45,51,54,由此解答.\n【详解】由分析可知,用1,4,5能组成14,15,41,45,51,54,共6个不同的两位数.原题说法正确.故答案为:√",
+        "knowledge_points":  [
+                                 "100以内数的组成",
+                                 "数字中的组合问题"
+                             ],
+        "source":  "23-24二年级下·广东韶关·期中"
+    },
+    {
+        "id":  "181",
+        "unit":  "搭配",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "从1,2,3,4中任意选三个不同的数相加,可以得到多少个不同的和?",
+        "options":  [
+
+                    ],
+        "answer":  "4个",
+        "solution":  "【分析】根据题意,要选择三个不同的数相加求和,可以选择1,2,3相加;1,2,4相加;1,3,4相加;2,3,4相加,由此解答.\n【详解】1+2+3=6;1+2+4=7;1+3+4=8;2+3+4=9;得到的和有6,7,8,9.答:可以得到4个不同的和.",
+        "knowledge_points":  [
+                                 "搭配问题",
+                                 "连加,连减(10以内)"
+                             ],
+        "source":  "23-24二年级上·浙江温州·期末"
+    },
+    {
+        "id":  "182",
+        "unit":  "搭配",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "有三张面值分别为1元,5元,10元的人民币,从中选两张可以组成多少种不同的币值?",
+        "options":  [
+
+                    ],
+        "answer":  "3种",
+        "solution":  "【分析】从1元,5元,10元的人民币中选两张可以选1元和5元,1元和10元,5元和10元,即可以组成三种币值.\n【详解】1+5=6(元),1+10=11(元),5+10=15(元),答:可以组成3种不同的币值.",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "23-24二年级上·全国·课后作业"
+    },
+    {
+        "id":  "183",
+        "unit":  "搭配",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "从1,3,4,6,8,9这六个数中,任意选取两个数相乘,可以得到多少种不同的结果?",
+        "options":  [
+
+                    ],
+        "answer":  "14种",
+        "solution":  "【分析】本题可以采用列举法.从六个数中任意选取两个数,计算出乘积,再看看有多少不同的结果即可.解答本题的关键是要有序列举,做到不重复,不遗漏.\n【详解】1×3=3;1×4=4;1×6=6;1×8=8;1×9=9;3×4=12;3×6=18;3×8=24;3×9=27;4×6=24;4×8=32;4×9=36;6×8=48;6×9=54;8×9=72;3×8和4×6的结果相同,其余任意两组的乘积都不相等.5+4+3+2+1-1=14(种),答:可以得到14种不同的结果.",
+        "knowledge_points":  [
+                                 "搭配问题",
+                                 "6的乘法口诀及应用",
+                                 "8的乘法口诀及应用",
+                                 "9的乘法口诀及应用"
+                             ],
+        "source":  "23-24二年级上·全国·课后作业"
+    },
+    {
+        "id":  "184",
+        "unit":  "搭配",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "用1,2,3,4可组成多少个没有重复数字的三位数并且是双数?",
+        "options":  [
+
+                    ],
+        "answer":  "12个",
+        "solution":  "【分析】由题意知,需要组成没有重复数字的三位数并且是双数,那就可以确定个位是2或4,然后列举所有可能的组合,数出个数即可.\n【详解】个位为2时,三位数有:132,312,142,412,342,432,6个数;个位为4时,三位数有:124,214,134,314,234,324,6个数;能组成没有重复数字的三位数并且是双数有:6+6=12(个),答:用1,2,3,4可组成12个没有重复数字的三位数并且是双数.",
+        "knowledge_points":  [
+                                 "数字中的组合问题"
+                             ],
+        "source":  "23-24二年级上·全国·课后作业"
+    },
+    {
+        "id":  "185",
+        "unit":  "搭配",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "在两位整数中,十位数字小于个位数字的共有多少个?",
+        "options":  [
+
+                    ],
+        "answer":  "36个",
+        "solution":  "【分析】12,13,14,15,16,17,18,19,即,十位上是1,十位数字小于个位数字的共8个;23,24,25,26,27,28,29,即,十位上是2,十位数字小于个位数字的共7个;34,35,36,37,38,39,即,十位上是3,十位数字小于个位数字的共有6个;89,即,十位上是8,十位数字小于个位数字的有1个;十位上是9,十位数字小于个位数字的有0个;然后全部个数加起来,求出和,即可解决.\n【详解】8+7+6+5+4+3+2+1=36(个),答:十位数字小于个位数字的共有36个.",
+        "knowledge_points":  [
+                                 "100以内数的组成",
+                                 "数字中的组合问题"
+                             ],
+        "source":  "23-24二年级上·全国·课后作业"
+    },
+    {
+        "id":  "186",
+        "unit":  "搭配",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "数字和是6的两位数总共有多少个?",
+        "options":  [
+
+                    ],
+        "answer":  "6个",
+        "solution":  "【分析】因为6=1+5=2+4=3+3=6+0,所以组成这两位数的数字为1与5,2与4,3与3,6与0,即数字和为6的两位数为15,51,24,42,33,60,共6个.\n【详解】6=1+5=2+4=3+3=6+0.所以数字和为6的两位数为15,51,24,42,33,60,共6个.答:数字和是6的两位数总共有6个.",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "23-24二年级上·全国·课后作业"
+    },
+    {
+        "id":  "187",
+        "unit":  "搭配",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "由数字0,1,2,3组成三位数,可组成多少个没有重复数字的三位数?",
+        "options":  [
+
+                    ],
+        "answer":  "18个",
+        "solution":  "【分析】在确定由0,1,2,3组成的三位数的过程中,应该一位一位地去确定.要求组成的三位数中没有重复数字,百位上不能取0,有3种取法;由于百位从1,2,3中取走了一个,十位上要从0和剩下的两个数字中取出一个,有3种取法;由于百位和十位已各取走一个数字,个位上只能从剩下的两个数字中取出一个,有2种取法,故不同的取法有:3×3×2=18(个).\n【详解】3×3×2=9×2=18(个),答:可组成18个没有重复数字的三位数.",
+        "knowledge_points":  [
+                                 "搭配问题",
+                                 "表内连乘,连除运算",
+                                 "数字中的组合问题"
+                             ],
+        "source":  "23-24二年级上·全国·课后作业"
+    },
+    {
+        "id":  "188",
+        "unit":  "搭配",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "二(1)班的小平,小宁,小刚,小超四人排了一个小快板节目,准备参加\"六一\"演出.在演出过程中,队形不断变化(都站成一排).算一算他们在演出过程中,一共有多少种队形变化形式?",
+        "options":  [
+
+                    ],
+        "answer":  "24种",
+        "solution":  "【分析】我们假设小平站在排头,在小平右边有3个人,根据题意可知,这3个人在右边的三个位置上共有6种不同的站法,如下图:![](images/bc92cd3c187f0c5e9e456577da200eea66ef811aa57f3a6b971f7e9c25544764.jpg)同理,如果让小宁,小刚,小超分别站在排头,也各有6种不同的站法,共有4个6种.因为排头的人不同,所以每组6种站法是不会有重复情况出现的.因此,队形变化形式共有4×6=24(种).\n【详解】4×6=24(种),答:一共有24种队形变化形式.",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "23-24二年级上·全国·课后作业"
+    },
+    {
+        "id":  "189",
+        "unit":  "搭配",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "小明有3件上衣,如果每一件上衣与不同的裤子搭配,小明的衣服共有6种不同的穿法,小明有几条裤子呢?",
+        "options":  [
+
+                    ],
+        "answer":  "2条",
+        "solution":  "【分析】当小明只有1条裤子时,裤子就只有1种穿法,而上衣有3件,因此一共有1个3种不同的穿法,1×3=3(种),也就是共有3种不同的穿法;不符合题意.当小明有2条裤子时,裤子就有2种不同穿法,而上衣有3件,因此一共有2个3种不同的穿法,2×3=6(种),也就是共有6种不同的穿法;符合题意.解答题目时,可以这样列式计算,用6除以3,求出商即可.\n【详解】6/3=2(条),答:小明有2条裤子.",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "23-24二年级上·全国·课后作业"
+    },
+    {
+        "id":  "190",
+        "unit":  "搭配",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "在4,6,8这三个数中任意取两个不同的数求和,得数有几种可能?分别是多少?",
+        "options":  [
+
+                    ],
+        "answer":  "3种;10,12,14",
+        "solution":  "【分析】在4,6,8这三个数中任意取两个不同的数求和,有以下几种可能:①4+6,②4+8,③6+8;据此解决此题即可.\n【详解】4+6=10,4+8=12,6+8=14,答:得数有3种可能;分别是10,12,14.",
+        "knowledge_points":  [
+                                 "数字中的组合问题"
+                             ],
+        "source":  "23-24二年级上·全国·课后作业"
+    },
+    {
+        "id":  "191",
+        "unit":  "搭配",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "用4,8,5,9能摆成几个不同的两位数?按从小到大的顺序写出来.",
+        "options":  [
+
+                    ],
+        "answer":  "12个;45 \u003c 48 \u003c 49 \u003c 54 \u003c 58 \u003c 59 \u003c 84 \u003c 85 \u003c 89 \u003c 94 \u003c 95 \u003c 98",
+        "solution":  "【分析】先把用4,8,5,9摆成不同的两位数一一列举出来,然后比较一下大小,即可解决.整数比较大小方法:①位数多的数大于位数少的数;②位数相同的,先比较最高位上的数,最高位上大的,数就大,最高位数相同的,就比较下一位,以此类推.\n【详解】用4,8,5,9摆成不同的两位数有:48,45,49,84,85,89,54,58,59,94,98,95;即,用4,8,5,9能摆成12个不同的两位数.按从小到大的顺序排列是:45 \u003c 48 \u003c 49 \u003c 54 \u003c 58 \u003c 59 \u003c 84 \u003c 85 \u003c 89 \u003c 94 \u003c 95 \u003c 98.",
+        "knowledge_points":  [
+                                 "100以内数的比大小",
+                                 "数字中的排列问题"
+                             ],
+        "source":  "23-24二年级上·全国·课后作业"
+    },
+    {
+        "id":  "192",
+        "unit":  "搭配",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "现有1克,2克,4克砝码各一个,称东西时,砝码只能放在天平的一边,用这些砝码可以称出多少种不同的质量?",
+        "options":  [
+
+                    ],
+        "answer":  "7种",
+        "solution":  "【分析】可以从3个砝码中拿出1个,有3种拿法,即可称出3种不同的质量;如果从中拿出2个,有3种拿法,即1克+2克,1克+4克,2克+4克,可称出3种不同的质量;如果从中拿出3个,有1种拿法,即1克+2克+4克,因此一共可以称出7种不同的质量.\n【详解】由题意分析得:3+3+1=7(种),答:用这些砝码可以称出7种不同的质量.",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "23-24二年级上·全国·课后作业"
+    },
+    {
+        "id":  "193",
+        "unit":  "搭配",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "从甲地到乙地有两条路,从乙地到丙地有两条路,从甲地到乙地再到丙地有几种走法?\n\n![](images/cf958d31eb6da4194e88c9a358872d518db4abcb2899f0b793d276ac8fdf8e17.jpg)",
+        "options":  [
+
+                    ],
+        "answer":  "4种",
+        "solution":  "【分析】从甲地到乙地,当选择其中1条路时,则从乙地到丙地有2种不同的走法,而从甲地到乙地有2条路,因此,从甲地到乙地再到丙地一共有2个2种不同的走法;据此解决即可.\n【详解】2×2=4(种),答:从甲地到乙地再到丙地有4种走法.",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "23-24二年级上·全国·课后作业"
+    },
+    {
+        "id":  "194",
+        "unit":  "搭配",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "下面的3个数,任意选取2个数求积,得数有几种可能?分别是多少?\n\n2;5;7",
+        "options":  [
+
+                    ],
+        "answer":  "3种;10,14,35",
+        "solution":  "【分析】把2,5,7这三个数两两相乘,求出积,即可解决.\n【详解】2×5=10;2×7=14;5×7=35,答:2,5,7任意选取2个数求积,得数有3种可能;分别是10,14,35.",
+        "knowledge_points":  [
+                                 "搭配问题",
+                                 "5的乘法口诀及应用",
+                                 "7的乘法口诀及应用"
+                             ],
+        "source":  "23-24二年级上·全国·课后作业"
+    },
+    {
+        "id":  "195",
+        "unit":  "搭配",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "A,B,C,D,E五人每两人之间都要进行一场乒乓球比赛,一共要进行多少场比赛?",
+        "options":  [
+
+                    ],
+        "answer":  "10场",
+        "solution":  "【分析】A与B,C,D,E共要比赛4场;B与A已经比赛了,所以B与剩下的C,D,E还要比赛3场;C与剩下的D,E还要比赛2场;最后剩下D和E比赛1场,所以一共要进行比赛的场数是4+3+2+1=10(场).\n【详解】由题意分析得:4+3+2+1=10(场),答:一共要进行10场比赛.",
+        "knowledge_points":  [
+                                 "搭配问题",
+                                 "比赛问题"
+                             ],
+        "source":  "23-24二年级上·全国·课后作业"
+    },
+    {
+        "id":  "196",
+        "unit":  "搭配",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "从4名同学中选出2名参加作文竞赛,一共有几种不同的方案?",
+        "options":  [
+
+                    ],
+        "answer":  "6种",
+        "solution":  "【分析】根据题意,将4名同学编号为1号,2号,3号,4号.选择1号同学时,另一名同学可分别选择2号,3号,4号同学;选择2号同学时,另一名同学可分别选择3号,4号同学;选择3号同学时,另一名同学是4号同学.将所有方案相加就是总方案数.\n【详解】3+2+1=6(种),答:一共有6种不同的方案.",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "23-24二年级上·全国·单元测试"
+    },
+    {
+        "id":  "197",
+        "unit":  "搭配",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "一列火车从上海开往广州中途要经过5站,这列火车一共有几种不同的车票?",
+        "options":  [
+
+                    ],
+        "answer":  "21种",
+        "solution":  "【分析】根据题意中途经过5站,加上起点和终点,共7站.从第1站到其他各站有6种车票,从第2站到其他各站有5种车票,从第3站到其他各站有4种车票,从第4站到其他各站有3种车票;从第5站到其他各站有2种车票;从第6站到第7站有1种车票,由此相加即可.本题的关键点是要明确一共的站点数要算上起点和终点.\n【详解】6+5+4+3+2+1=21(种),答:这列火车一共有21种不同的车票.",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "23-24二年级上·全国·单元测试"
+    },
+    {
+        "id":  "198",
+        "unit":  "搭配",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "从5,3,2,0四个数中任意取出两个数组成一个两位数,共能组成几个不同的数?",
+        "options":  [
+
+                    ],
+        "answer":  "9个",
+        "solution":  "【分析】从5,3,2,0四张卡片中任意抽取两张组成一个两位数,十位上可以是5,3或2,由此写出可以组成的所有的两位数,从而解决问题.\n【详解】从5,3,2,0四个数中任意取出两个数组成一个两位数有:53,52,50;35,32,30;25,23,20,答:一共能组成9个不同的两位数.",
+        "knowledge_points":  [
+                                 "数字中的排列问题",
+                                 "含0的组数问题"
+                             ],
+        "source":  "23-24二年级上·全国·单元测试"
+    },
+    {
+        "id":  "199",
+        "unit":  "搭配",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "五个小朋友进行乒乓球比赛,每两个人之间比赛一次,一共要进行多少次比赛?",
+        "options":  [
+
+                    ],
+        "answer":  "10次",
+        "solution":  "【分析】第一个小朋友与其他4个小朋友比赛,有4次;第二个小朋友与剩下的3位小朋友比赛,有3次;第三个小朋友与剩下的2位小朋友比赛,有2次;第四个小朋友与剩下的1位小朋友比赛,有1次.所以总次数是4+3+2+1次比赛.\n【详解】4+3+2+1=10(次),答:一共要进行10次比赛.",
+        "knowledge_points":  [
+                                 "比赛问题"
+                             ],
+        "source":  "23-24二年级上·全国·单元测试"
+    },
+    {
+        "id":  "200",
+        "unit":  "搭配",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "小林有3双不同的袜子,还有3双不同的鞋,如果她要穿上鞋和袜子,有几种不同的穿法?",
+        "options":  [
+
+                    ],
+        "answer":  "9种",
+        "solution":  "【分析】根据题意可知:每一双不同的袜子,都可以与3双不同的鞋搭配,不同的袜子有3双,总的搭配种类用乘法计算.据此解答.\n【详解】3×3=9(种),答:有9种不同的穿法.",
+        "knowledge_points":  [
+                                 "搭配问题",
+                                 "3的乘法口诀及应用"
+                             ],
+        "source":  "22-23二年级上·河北保定·期末"
+    },
+    {
+        "id":  "201",
+        "unit":  "搭配",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "3名学生排成一排合影,有()种不同站法.",
+        "options":  [
+                        "A. 4",
+                        "B. 6",
+                        "C. 5",
+                        "D. 3"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】假设三名同学分别为A,B,C,则排列方法有ABC,ACB,BAC,BCA,CAB,CBA,共有6种不同站法.\n【详解】根据分析知,3名学生排成一排合影,有6种不同站法.故答案为:B",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "23-24二年级上·河南周口·期末"
+    },
+    {
+        "id":  "202",
+        "unit":  "搭配",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "小军有3件上衣和2条裤子,一件上衣配一条裤子,有()种不同穿法.",
+        "options":  [
+                        "A. 5",
+                        "B. 3",
+                        "C. 6"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】根据题意分析可知,一件上衣就可以与两条不同的裤子有两种搭配方法,所以3件上衣则就有:3×2种不同的穿法.\n【详解】3×2=6(种),每件上衣都有两种搭配方法,3件上衣就有6种搭配方法.故答案为:C",
+        "knowledge_points":  [
+                                 "搭配问题",
+                                 "3的乘法口诀及应用"
+                             ],
+        "source":  "23-24二年级上·甘肃庆阳·期末"
+    },
+    {
+        "id":  "203",
+        "unit":  "搭配",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "有红色,黄色,蓝色三种颜色的袜子,兰兰想买两种颜色的袜子,有()种买法.",
+        "options":  [
+                        "A. 4",
+                        "B. 3",
+                        "C. 6"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】用列举的方法把所有的可能性一一列举出来,然后数一数有几种买法即可.\n【详解】由题意分析得:有红色,黄色,蓝色三种颜色的袜子,买两种颜色的袜子的可能性有:①红色,黄色,②红色,蓝色,③黄色,蓝色;有3种买法.故答案为:B",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "23-24二年级上·山东临沂·期末"
+    },
+    {
+        "id":  "204",
+        "unit":  "搭配",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "妈妈有3件不同的衬衣,2条颜色不一样的裤子.妈妈一共有()种不同的搭配方法.",
+        "options":  [
+                        "A. 3",
+                        "B. 5",
+                        "C. 6"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】根据题意可知,每件衬衣都可以和2条裤子搭配,共3件衬衣,共2×3种搭配方法.\n【详解】2×3=6(种),妈妈一共有6种不同的搭配方法.故答案为:C",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "23-24二年级上·浙江杭州·期末"
+    },
+    {
+        "id":  "205",
+        "unit":  "搭配",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "亮亮从《格林童话》,《安徒生童话》,《自然科学》这3本书中选2本送人,一共有()种不同的选法.",
+        "options":  [
+                        "A. 2",
+                        "B. 6",
+                        "C. 3"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】根据题意,可有如下的选法:①《格林童话》,《安徒生童话》;②《格林童话》,《自然科学》;③《安徒生童话》,《自然科学》;共3种不同的选法.\n【详解】由分析可知,亮亮从《格林童话》,《安徒生童话》,《自然科学》这3本书中选2本送人,一共有3种不同的选法.故答案为:C",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "23-24二年级上·浙江嘉兴·期末"
+    },
+    {
+        "id":  "206",
+        "unit":  "搭配",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "有2件上衣和2条裤子,每次穿1件上衣,1条裤子,有()种穿法.\n\n![](images/4e56425239eaec827948e71937b84fd8249cbf2af7a8df7d5d04f5f0ebda9b5a.jpg)",
+        "options":  [
+                        "A. 4",
+                        "B. 6",
+                        "C. 2"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】上衣有2种穿法,裤子有2种穿法,用2乘2即可求解.\n【详解】2×2=4(种),有4种穿法.故答案为:A",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "23-24二年级上·河南焦作·期末"
+    },
+    {
+        "id":  "207",
+        "unit":  "搭配",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "用1,2,0能摆成()个不同的两位数.",
+        "options":  [
+                        "A. 2",
+                        "B. 4",
+                        "C. 6"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】组成两位数时,十位不能是0.用1和2分别作十位,能组成的两位数有:12,10,20,21,由此解答.\n【详解】由分析可知,用1,2,0能摆成4个不同的两位数.故答案为:B",
+        "knowledge_points":  [
+                                 "搭配问题",
+                                 "100以内数的组成"
+                             ],
+        "source":  "23-24二年级上·湖北省直辖县级单位·期末"
+    },
+    {
+        "id":  "208",
+        "unit":  "搭配",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "二年级举办垃圾分类知识竞答.二(1)班从2名男生和2名女生中各选1名男生和1名女生参加比赛,一共有()种选法.",
+        "options":  [
+                        "A. 7",
+                        "B. 5",
+                        "C. 4"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】根据题意,1名男生可以分别和2名女生组合,共2名男生,则有2×2种选法.\n【详解】2×2=4(种),一共有4种选法.故答案为:C",
+        "knowledge_points":  [
+                                 "搭配问题",
+                                 "2的乘法口诀及应用"
+                             ],
+        "source":  "23-24二年级上·湖南怀化·期末"
+    },
+    {
+        "id":  "209",
+        "unit":  "搭配",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "明明和花花坐一排,有()种坐法.",
+        "options":  [
+                        "A. 2",
+                        "B. 4",
+                        "C. 6"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】可以明明左边花花右边,也可以明明右边花花左边,共2种坐法.\n【详解】明明和花花坐一排,有2种坐法.故答案为:A",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "23-24二年级上·贵州遵义·期末"
+    },
+    {
+        "id":  "210",
+        "unit":  "搭配",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "贝贝和亮亮去王老师家做客,王老师拿出三袋不同的糖分给贝贝和亮亮,每人各分一袋,一共有()种不同的分法.",
+        "options":  [
+                        "A. 6",
+                        "B. 5",
+                        "C. 3"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】先确定一种糖给哪位小朋友,另一位小朋友就有2种分法,3种糖就有3个2种分法,即6种不同的分法.\n【详解】3×2=6(种),根据分析得出有6种不同的分法.故答案为:A",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "23-24二年级上·湖南张家界·期末"
+    },
+    {
+        "id":  "211",
+        "unit":  "搭配",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "有26人到公园划船,每条大船限坐6人,每条小船限坐4人,如果每条船都坐满,下面的租船方案可行的是().",
+        "options":  [
+                        "A. 租4条大船和1条小船",
+                        "B. 租2条大船和3条小船",
+                        "C. 租3条大船和2条小船"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】A方案租4条大船,即4×6=24人,租1条小船坐4人,24+4=28人,28-26=2人,小船少2人没有坐满;B方案租2条大船,即2×6=12人,租3条小船,即3×4=12人,租2条大船和3条小船坐12+12=24人,26-24=2人,还剩2人没有船坐;C方案租3条大船,即3×6=18人,租2条小船,即2×4=8人,18+8=26人,每条船都坐满.所以租船方案可行的是租3条大船和2条小船.\n【详解】有26人到公园划船,每条大船限坐6人,每条小船限坐4人,如果每条船都坐满,租船方案可行的是租3条大船和2条小船.故答案为:C",
+        "knowledge_points":  [
+                                 "搭配问题",
+                                 "租船问题"
+                             ],
+        "source":  "23-24三年级上·贵州黔西·期末"
+    },
+    {
+        "id":  "212",
+        "unit":  "搭配",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "从小朋友们手中拿的卡片中,任意选出2张组成两位数,能组成()个不同的两位数.\n\n![](images/f7227cb1284ced99a98998cc8beb1ab70368b8d679f031d2639641bd1d3bc90a.jpg)\n![](images/872632d6a41a8f7ec39f30bd5013e565c78b25a6aeb4b498d0c60646ff6d1acd.jpg)\n![](images/4fb3ffa6a0b706a21c027816dd7ed15fc228651ce18c81373a69e2027c70cd28.jpg)",
+        "options":  [
+                        "A. 3",
+                        "B. 4",
+                        "C. 6"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】组成两位数时,用其中一个数作为十位,另外两个数分别作为个位.由此组成的数有35,39,53,59,93,95.由此解答.\n【详解】由分析可知,从小朋友们手中拿的卡片中,任意选出2张组成两位数,能组成6个不同的两位数.故答案为:C",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "23-24二年级上·广东肇庆·期末"
+    },
+    {
+        "id":  "213",
+        "unit":  "搭配",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "3名同学坐成一排合影,有()种坐法.",
+        "options":  [
+                        "A. 4",
+                        "B. 6",
+                        "C. 8"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】根据题意,坐成一排时,可以先固定一个同学的位置,其余2名同学可互换位置,也就是有2种坐法.共3名同学,也就共有2×3=6(种)坐法.\n【详解】由分析可知,3名同学坐成一排合影,有6种坐法.故答案为:B",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "23-24二年级上·四川南充·期末"
+    },
+    {
+        "id":  "214",
+        "unit":  "搭配",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "小明有2件不同的上衣和3条不同的裤子,他可以有()种不同的穿法.",
+        "options":  [
+                        "A. 3",
+                        "B. 5",
+                        "C. 6"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】根据题意,每件上衣都可以搭配3条裤子,也就是3种不同的穿法.共有2件上衣,一共有3×2种方法.\n【详解】3×2=6(种),小明有2件不同的上衣和3条不同的裤子,他可以有6种不同的穿法.故答案为:C",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "23-24二年级上·新疆喀什·期末"
+    },
+    {
+        "id":  "215",
+        "unit":  "搭配",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "一种吃的搭配一种喝的,共有()种不同的搭配方法.\n\n![](images/269d3e27b86daee5a450faaac4d71e78424db14ecf1d52bd413734ea8ffc5a61.jpg)\n![](images/eb44fb864fc65711c58d6e5044829c74ae5fbe6da2b84b7321e0137c7c9eed37.jpg)\n![](images/895c67b25aabb5d9f97cf19bdc6f61290a5fe0ce7235645c5ae81ae3a588a564.jpg)\n![](images/433a63654d9aac929f6c4748b6f3b8b60fae0b657707a4d3c9cfcfa195e52575.jpg)",
+        "options":  [
+                        "A. 2",
+                        "B. 4",
+                        "C. 6"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】每种吃的可以搭配2种喝的,共有2种吃的,可以搭配2×2种,由此解答.\n【详解】2×2=4(种),一种吃的搭配一种喝的,共有4种不同的搭配方法.故答案为:B",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "23-24二年级上·浙江杭州·期末"
+    },
+    {
+        "id":  "216",
+        "unit":  "搭配",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "用2,6,0三个数字组成的两位数有()个.",
+        "options":  [
+                        "A. 2",
+                        "B. 4",
+                        "C. 6"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】组成两位数时,十位不能为0.因此可组成的数有26,20,60,62,由此解答.\n【详解】由分析可知,用2,6,0三个数字组成的两位数有4个.故答案为:B",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "23-24二年级上·贵州六盘水·期末"
+    },
+    {
+        "id":  "217",
+        "unit":  "搭配",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "用2,5,6这三张数字卡片可以组成()个不同的两位数.",
+        "options":  [
+                        "A. 3",
+                        "B. 4",
+                        "C. 5",
+                        "D. 6"
+                    ],
+        "answer":  "D",
+        "solution":  "【分析】用2,5,6组成两位数时,用其中一个数为十位,另外两个数分别为个位,可以组成的数有25,26,52,56,62,65,由此解答.\n【详解】由分析可知,用2,5,6这三张数字卡片可以组成6个不同的两位数.故答案为:D",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "23-24二年级上·浙江台州·期末"
+    },
+    {
+        "id":  "218",
+        "unit":  "搭配",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "从公园入口经过小桥到达动物园,一共有()条路可以走.\n\n![](images/9707de6591ea41979b2125e37fd0076086d52fb829191e823d79d5e015d8397c.jpg)",
+        "options":  [
+                        "A. 3",
+                        "B. 5",
+                        "C. 6"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】从公园入口到小桥有3条路可走,从小桥到动物园有2条路可走,用3乘2即可求解.\n【详解】3×2=6(条),从公园入口经过小桥到达动物园,一共有6条路可以走.故答案为:C",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "23-24二年级上·湖北襄阳·期末"
+    },
+    {
+        "id":  "219",
+        "unit":  "搭配",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "鹏鹏有两件上衣和两条裤子,一件上衣和一条裤子搭配,共有()种穿法.",
+        "options":  [
+                        "A. 3",
+                        "B. 5",
+                        "C. 4"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】一件上衣和一条裤子搭配,是1种穿法,则一件上衣和两条裤子分别搭配,有2种穿法;故两件上衣和两条裤子分别搭配,有(2×2)种穿法;据此解决.\n【详解】2×2=4(种),即鹏鹏有两件上衣和两条裤子,一件上衣和一条裤子搭配,共有4种穿法.故答案为:C",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "23-24二年级上·湖南怀化·期末"
+    },
+    {
+        "id":  "220",
+        "unit":  "搭配",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "甲,乙,丙三位保安排成一列去巡逻,一共有()种排法.",
+        "options":  [
+                        "A. 4",
+                        "B. 5",
+                        "C. 6"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】左边可以站3个人中的任意一个,3种站法;中间可以站剩下2个人中的任意一个,2种站法;这样右边就只有1种站法.用3乘2即可求解.\n【详解】3×2=6(种),甲,乙,丙三位保安排成一列去巡逻,一共有6种排法.故答案为:C",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "23-24二年级上·河南信阳·期末"
+    },
+    {
+        "id":  "221",
+        "unit":  "搭配",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "用0,1,7这三个数中的两个数组成两位数,最多能组成()个两位数.",
+        "options":  [
+                        "A. 6",
+                        "B. 5",
+                        "C. 4"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】三个不同的数字组成没有重复数字的两位数时:让每个数字(0除外)先作十位数字,然后其余两个数字依次和它组合.注意,不要遗漏,0不能放在两位数的十位上.\n【详解】1作十位可组成的两位数:10,17.7作十位可组成的两位数:70,71.最多能组成4个两位数.故答案为:C",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "23-24二年级上·山东菏泽·期末"
+    },
+    {
+        "id":  "222",
+        "unit":  "搭配",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "用2,3,5这三个数字能摆出()个不同的两位数.",
+        "options":  [
+                        "A. 2",
+                        "B. 4",
+                        "C. 6"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】用2,3,5这三个数字摆出的不同的两位数一一列举出来,再数一数有几个,即可解决.\n【详解】用2,3,5这三个数字摆出的不同的两位数有:23,25,32,35,52,53;即,用2,3,5这三个数字能摆出6个不同的两位数.故答案为:C",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "23-24二年级上·广东河源·期末"
+    },
+    {
+        "id":  "223",
+        "unit":  "搭配",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "用7,0,9可以组成()个不同的两位数.",
+        "options":  [
+                        "A. 3",
+                        "B. 4",
+                        "C. 6"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】运用列举法写出所有的可能,但是0不能写在首位;据此解答即可.\n【详解】用7,0,9可以组成不同的两位数有:70,79,97,90,一共有4个.故答案为:B",
+        "knowledge_points":  [
+                                 "搭配问题",
+                                 "100以内数的组成"
+                             ],
+        "source":  "23-24二年级上·广东广州·期末"
+    },
+    {
+        "id":  "224",
+        "unit":  "搭配",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "用6,0,1可以组成()个不同的两位数.",
+        "options":  [
+                        "A. 4",
+                        "B. 5",
+                        "C. 6"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】用6,0,1组成两位数时,十位不能为0.十位是6时,个位可以是0或1;十位是1时,个位可以是0或6.由此解答.\n【详解】由分析可知,组成的两位数有60,61,10,16.即用6,0,1可以组成4个不同的两位数.故答案为:A",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "23-24二年级上·湖南岳阳·期末"
+    },
+    {
+        "id":  "225",
+        "unit":  "搭配",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "3名同学一起合影,有()种站法.",
+        "options":  [
+                        "A. 4",
+                        "B. 5",
+                        "C. 6"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】先假设3名同学分别是甲,乙,丙,再把3人一起合影的不同站法一一列举出来,再数一数有几种站法即可.\n【详解】假设3名同学分别是甲,乙,丙,3人一起合影的不同站法有:甲乙丙,甲丙乙,乙甲丙,乙丙甲,丙甲乙,丙乙甲;也就是一共有6种站法.故答案为:C",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "23-24二年级上·湖南株洲·期末"
+    },
+    {
+        "id":  "226",
+        "unit":  "搭配",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "小强有3件不同的上衣,2条不同的裤子,每次上衣穿1件,裤子穿1条.他有()种不同的穿法.",
+        "options":  [
+                        "A. 8",
+                        "B. 6",
+                        "C. 5"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】上衣有3种选择方法,每一件上衣都可以搭配一条裤子,裤子有2种选择方法,求一共有多少种不同的穿法,用3×2即可.\n【详解】3×2=6(种),他有6种不同的穿法.故答案为:B",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "23-24二年级上·广东广州·期末"
+    },
+    {
+        "id":  "227",
+        "unit":  "搭配",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "从下边3个玩具中选2个,送给孙宁和陈灵,一共有()种送法.\n\n![](images/0f211954cd7e7caa68dee50c187fe637d5fb769d46eaf2caf0048b9e1eb42675.jpg)\n![](images/c027a6f67adb604eebbdbb246ab1ed76134dd59a27355957462546fe38473c83.jpg)\n![](images/f7d301cc9cd8cae277f633b74f68710b4ca401271a7c3e8bd8c10e07fceccc95.jpg)",
+        "options":  [
+                        "A. 3",
+                        "B. 6",
+                        "C. 8"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】先把所有的送法一一列举出来,然后数一数有几种不同的送法即可.\n【详解】①送魔方给孙宁,送玩具熊给陈灵;②送魔方给孙宁,送球给陈灵;③送玩具熊给孙宁,送魔方给陈灵;④送玩具熊给孙宁,送球给陈灵;⑤送球给孙宁,送魔方给陈灵;⑥送球给孙宁,送玩具熊给陈灵;即一共有6种送法.故答案为:B",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "23-24二年级上·宁夏固原·期末"
+    },
+    {
+        "id":  "228",
+        "unit":  "搭配",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "明明有3件不同的衬衣,2条颜色不一样的裙子,一共有()种穿法.",
+        "options":  [
+                        "A. 5",
+                        "B. 6",
+                        "C. 3"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】可以这样想:一件衬衣和2条裙子有两种搭配,那么3件衬衣和2条裙子就有3×2种搭配,据此解答.\n【详解】2×3=6(种),明明有3件不同的衬衣,2条颜色不一样的裙子,一共有6种穿法.故答案为:B",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "18-19二年级上·新疆阿克苏·期末"
+    },
+    {
+        "id":  "229",
+        "unit":  "搭配",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "三年级4个班进行拔河比赛,要求每两个班拔一次,三年级一共要拔河()场次.",
+        "options":  [
+                        "A. 4",
+                        "B. 6",
+                        "C. 8",
+                        "D. 12"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】因为有4个班进行比赛,先固定一个班,有3场;再固定第二个班,和剩下的班有2场;最后剩下两个班有1场,把场数相加即可.\n【详解】3+2+1=6(场),三年级4个班进行拔河比赛,要求每两个班拔一次,三年级共要拔河6场次.故答案为:B",
+        "knowledge_points":  [
+                                 "搭配问题",
+                                 "带有小括号的混合运算"
+                             ],
+        "source":  "23-24三年级上·湖南张家界·期末"
+    },
+    {
+        "id":  "230",
+        "unit":  "搭配",
+        "question_type":  "选择题",
+        "difficulty":  0.94,
+        "question":  "学校中午配餐提供4种主食,2种菜色,如果只选择一种主食和一种菜色搭配,则不同搭配方法有()种.",
+        "options":  [
+                        "A. 10",
+                        "B. 8",
+                        "C. 6",
+                        "D. 5"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】用主1,主2,主3,主4表示主食,用菜1,菜2表示菜色,可以进行如下搭配:每种主食都能搭配2种不同菜色.\n【详解】4×2=8(种),不同搭配方式有8种.故答案为:B",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "23-24六年级下·浙江杭州·开学考试"
+    },
+    {
+        "id":  "231",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "小东,小明,小芳三个人进行乒乓球单打比赛,每两个人之间都要比赛一场,一共要比()场.",
+        "options":  [
+
+                    ],
+        "answer":  "3",
+        "solution":  "【分析】每两个人之间比赛一场,把这三人的比赛场次一一列举出来,然后数一数共有几场,即可解决.\n【详解】小东,小明,小芳三个人进行乒乓球单打比赛,每两个人之间都要比赛一场,比赛场次如下:小东与小明比赛1场;小东与小芳比赛1场;小明与小芳比赛1场;一共要比3场.",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "23-24二年级上·浙江台州·期末"
+    },
+    {
+        "id":  "232",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "从3,8,7三个数中任意选取2个数求和,得数有()种可能.",
+        "options":  [
+
+                    ],
+        "answer":  "3",
+        "solution":  "【分析】从3,8,7三个数中任意选取2个数求和有3+8=8+3=11,3+7=7+3=10,8+7=7+8=15,即有3种结果.\n【详解】根据分析知:从3,8,7三个数中任意选取2个数求和,得数有3种可能.",
+        "knowledge_points":  [
+                                 "搭配问题",
+                                 "8加几的进位加法",
+                                 "7,6加几的进位加法"
+                             ],
+        "source":  "23-24二年级上·河南周口·期末"
+    },
+    {
+        "id":  "233",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "用3,6,9组成两位数,每个两位数的十位数字和个位数字不能一样,能组成()个两位数,其中最大的是(),最小的是().",
+        "options":  [
+
+                    ],
+        "answer":  "6;96;36",
+        "solution":  "【分析】把3,6,9组成的两位数一一列举出来(每个两位数的十位数字和个位数字不能一样),数一数有几个两位数,然后比较大小,即可解决.\n【详解】用3,6,9组成的两位数有(每个两位数的十位数字和个位数字不一样):36,63,39,93,69,96,一共有6个.96\u003e93\u003e69\u003e63\u003e39\u003e36;即,用3,6,9组成两位数,每个两位数的十位数字和个位数字不能一样,能组成6个两位数,其中最大的是96,最小的是36.",
+        "knowledge_points":  [
+                                 "搭配问题",
+                                 "100以内数的比大小"
+                             ],
+        "source":  "23-24二年级上·山东临沂·期末"
+    },
+    {
+        "id":  "234",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "用7,2,9能组成()个不同的两位数.其中最大的是(),最小的是(),它们的差是().",
+        "options":  [
+
+                    ],
+        "answer":  "6;97;27;70",
+        "solution":  "【分析】用7,2,9组成两位数时,其中一个数作为十位,另外两个数分别作为个位.可组成72,79,27,29,92,97这6个数.因为都是两位数,比较大小时,从十位比起.十位大的数就大;十位相同比较个位,个位大的数就大.由此找到最大的数和最小的数,再相减计算出差即可.\n【详解】97\u003e92\u003e79\u003e72\u003e29\u003e27,97-27=70,用7,2,9能组成6个不同的两位数.其中最大的是97,最小的是27,它们的差是70.",
+        "knowledge_points":  [
+                                 "搭配问题",
+                                 "100以内数的比大小",
+                                 "两位数与两位数的不退位减法"
+                             ],
+        "source":  "23-24二年级上·广东佛山·期末"
+    },
+    {
+        "id":  "235",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "用三张数字卡片1,2,3来组成两位数,能组成()个不同的两位数,其中最大的数是(),最小的数是().",
+        "options":  [
+
+                    ],
+        "answer":  "6;32;12",
+        "solution":  "【分析】用1,2,3三张数字卡片能组成十位数字是3的两位数有32,31;能组成十位数字是2的两位数有21,23;能组成十位数字是1的两位数有12,13;其中最大的是32,最小的是12,由此解答即可.\n【详解】用三张数字卡片1,2,3来组成两位数有:32,31,21,23,12,13;32\u003e31\u003e23\u003e21\u003e13\u003e12,用三张数字卡片1,2,3来组成两位数,能组成6个不同的两位数,其中最大的数是32,最小的数是12.",
+        "knowledge_points":  [
+                                 "搭配问题",
+                                 "100以内数的比大小"
+                             ],
+        "source":  "23-24二年级上·浙江温州·期末"
+    },
+    {
+        "id":  "236",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "有3个同学,每两个同学互相写1封信,一共需要写()封信,每两个同学互相握1次手,一共需要握()次.",
+        "options":  [
+
+                    ],
+        "answer":  "6;3",
+        "solution":  "【分析】根据题意,每个同学都可以给另外2个同学写信,共3个同学,需要写2×3=6(封);第1个同学可以和第2个,第3个同学握手;第2个同学可以和第3个同学握手,共握3次手.\n【详解】有3个同学,每两个同学互相写1封信,一共需要写6封信,每两个同学互相握1次手,一共需要握3次.",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "23-24二年级上·山东菏泽·期末"
+    },
+    {
+        "id":  "237",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "用6,2,3这三张卡片能组成()个两位数,分别是().",
+        "options":  [
+
+                    ],
+        "answer":  "6;63,62,32,36,23,26",
+        "solution":  "【分析】由题意可知,每个数字都可以与其他两个数字组合,每两个数字都可以组成两个不同的两位数,一共可以组成6个两位数,依次写出十位是6,2,3的两位数即可.\n【详解】用6,2,3这三张卡片能组成的数有63,62,32,36,23,26,共有6个两位数.",
+        "knowledge_points":  [
+                                 "搭配问题",
+                                 "100以内数的组成"
+                             ],
+        "source":  "23-24二年级上·广东广州·期末"
+    },
+    {
+        "id":  "238",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "用9,6,0三张数字卡片能摆()个不同的两位数,其中最大是(),最小是().",
+        "options":  [
+
+                    ],
+        "answer":  "4;96;60",
+        "solution":  "【分析】组成两位数时,十位不能为0,用9和6分别作为十位,其余两个数分别为个位,由此组成两位数即可.再比较它们的大小.都是两位数,十位大的数就大,十位相同比较个位,个位大的数就大.\n【详解】可以组成96,90,69,60这4个数.96\u003e90\u003e69\u003e60,用9,6,0三张数字卡片能摆4个不同的两位数,其中最大是96,最小是60.",
+        "knowledge_points":  [
+                                 "搭配问题",
+                                 "100以内数的比大小"
+                             ],
+        "source":  "23-24二年级上·山东济宁·期末"
+    },
+    {
+        "id":  "239",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "3个好朋友见面,相互握手,一共要握()次.",
+        "options":  [
+
+                    ],
+        "answer":  "3",
+        "solution":  "【分析】根据题意,第1个小朋友可以和第2个,第3个小朋友握手;第2个小朋友可以和第3个小朋友握手.由此解答.\n【详解】1+2=3(次),3个好朋友见面,相互握手,一共要握3次.",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "23-24二年级上·山东济宁·期末"
+    },
+    {
+        "id":  "240",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "汪老师,李老师,陈老师分别教音乐,美术,体育中的一门课程,并且所教课程各不相同,三位老师有()种不同的任教情况.",
+        "options":  [
+
+                    ],
+        "answer":  "6",
+        "solution":  "【分析】根据题意,先选定一位老师教其中一科,则其他老师有两种任教方法;共3位老师,就有2×3种方法.\n【详解】2×3=6(种),三位老师有6种不同的任教情况.",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "23-24二年级上·湖南怀化·期末"
+    },
+    {
+        "id":  "241",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "从4,7,9中任意选其中的两个数求积,得数有()种可能,其中最大的积与最小的积相差().",
+        "options":  [
+
+                    ],
+        "answer":  "3;35",
+        "solution":  "【分析】先固定一个数,再搭配另一个数求积,把不同的算式写出来,注意不能重复,再找出得数有几种可能,再用最大的积减去最小的积,据此解答.\n【详解】4×7=28;7×4=28;(结果一样,属于一种情况);4×9=36;9×4=36;(结果一样,属于一种情况);7×9=63;9×7=63;(结果一样,属于一种情况);所以得数有28,36,63三种情况,最大的是63,最小的是28,63-28=35.得数有3种可能,最大的积与最小的积相差35.",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "23-24二年级上·湖南张家界·期末"
+    },
+    {
+        "id":  "242",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "小红有两件上衣,两条裤子,如果她想配一套衣服,有()种配法.",
+        "options":  [
+
+                    ],
+        "answer":  "4",
+        "solution":  "【分析】根据题意,每件上衣都可以搭配两条裤子,共两件上衣,有2×2种搭法.\n【详解】2×2=4(种),小红有两件上衣,两条裤子,如果她想配一套衣服,有4种配法.",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "23-24二年级上·广东肇庆·期末"
+    },
+    {
+        "id":  "243",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "宁宁用三张不同的数字卡片组成了:15,18,51,58,81,85六个不同的两位数.这三张数字卡片上的数字分别是(),(),().",
+        "options":  [
+
+                    ],
+        "answer":  "1;5;8",
+        "solution":  "【分析】根据题意可知,每个两位数都由2个数字组成.15和51里有1和5;18和81里有1和8;58和85里有5和8.由此可知,这三个数字为1,5和8.\n【详解】由分析可知,宁宁用三张不同的数字卡片组成了:15,18,51,58,81,85六个不同的两位数.这三张数字卡片上的数字分别是1,5,8.",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "23-24二年级上·山西忻州·期末"
+    },
+    {
+        "id":  "244",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "用0,3,5这三个数字,共能组成()个不同的两位数.",
+        "options":  [
+
+                    ],
+        "answer":  "4",
+        "solution":  "【分析】组成两位数时,十位不能为0.用3和5分别作为十位,其余两个数分别作为个位,由此可组成的数字有30,35,50,53,由此解答.\n【详解】由分析可知,用0,3,5这三个数字,共能组成4个不同的两位数.",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "23-24二年级上·江西新余·期末"
+    },
+    {
+        "id":  "245",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "用2,4,7这三个数可以组成()个十位数字和个位数字不同的两位数.组成的最大的两位数是(),最小的两位数是(),它们的差是().",
+        "options":  [
+
+                    ],
+        "answer":  "6;74;24;50",
+        "solution":  "【分析】用2,4,7这三个数组成两位数时,用其中一个数作为十位,另外两个数分别作为个位.可以组成的数有24,27,42,47,72,74.比较大小时,都是两位数,十位上大的数就大;如果十位上的数相同,个位上大的数就大;求差用减法计算.\n【详解】74\u003e72\u003e47\u003e42\u003e27\u003e24,74-24=50,用2,4,7这三个数可以组成6个十位数字和个位数字不同的两位数.组成的最大的两位数是74,最小的两位数是24,它们的差是50.",
+        "knowledge_points":  [
+                                 "搭配问题",
+                                 "100以内数的比大小",
+                                 "两位数与两位数的不退位减法"
+                             ],
+        "source":  "23-24二年级上·浙江杭州·期末"
+    },
+    {
+        "id":  "246",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "用3,6,9三个数字卡片可以组成()个不同的两位数,其中最小的数是().",
+        "options":  [
+
+                    ],
+        "answer":  "6;36",
+        "solution":  "【分析】先固定十位上的数,再选择个位上的数,再把组成的数列举出来,算一算多少个,选出最小的数即可.本题考查了搭配问题.\n【详解】36,39,63,69,93,96,可以组成6个数,最小的是36.故填空为:可以组成6个不同的两位数,其中最小的数是36.",
+        "knowledge_points":  [
+                                 "搭配问题",
+                                 "100以内数的比大小",
+                                 "100以内数的组成"
+                             ],
+        "source":  "23-24二年级上·贵州铜仁·期末"
+    },
+    {
+        "id":  "247",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "用1,2,3,4,5,6,7,8,9组成两位数,一共能组成()个两位数.",
+        "options":  [
+
+                    ],
+        "answer":  "72",
+        "solution":  "【分析】组成两位数时,其中一个数为十位,其余几个数分别作为个位.每一个数字都可以与其他数字组成8个两位数,共9个数字,可以组成8×9=72(个)两位数.\n【详解】用1,2,3,4,5,6,7,8,9组成两位数,一共能组成72个两位数.",
+        "knowledge_points":  [
+                                 "搭配问题",
+                                 "9的乘法口诀及应用"
+                             ],
+        "source":  "23-24二年级上·山东济宁·期末"
+    },
+    {
+        "id":  "248",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "用3,5,7三张数字卡片可以组成()个不同的两位数;任意选两张数字卡片相乘,可以算出()个不同的积.",
+        "options":  [
+
+                    ],
+        "answer":  "6;3",
+        "solution":  "【分析】组成两位数时,用其中一个数为十位,另外两个数分别为个位.组成的数字有35,37,53,57,73,75.用两个数字相乘时,可用3和5相乘,3和7相乘,5和7相乘.由此解答.\n【详解】3×5=15;3×7=21;5×7=35,用3,5,7三张数字卡片可以组成6个不同的两位数;任意选两张数字卡片相乘,可以算出3个不同的积.",
+        "knowledge_points":  [
+                                 "搭配问题",
+                                 "5的乘法口诀及应用",
+                                 "7的乘法口诀及应用"
+                             ],
+        "source":  "23-24二年级上·浙江嘉兴·期末"
+    },
+    {
+        "id":  "249",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "用2,3,4能组成()个没有重复数字的两位数,其中最大的是(),最小的是().",
+        "options":  [
+
+                    ],
+        "answer":  "6;43;23",
+        "solution":  "【分析】用2,3,4能组成没有重复数字的两位数有:23,24,32,34,42,43,共6个;将它们比较大小即可求出最大的数和最小的数.\n【详解】用2,3,4能组成6个没有重复数字的两位数.23\u003c24\u003c32\u003c34\u003c42\u003c43,最大的是43,最小的是23.",
+        "knowledge_points":  [
+                                 "搭配问题",
+                                 "100以内数的比大小",
+                                 "100以内数的组成"
+                             ],
+        "source":  "23-24二年级上·贵州铜仁·期末"
+    },
+    {
+        "id":  "250",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "从1,2,3,4中,任意选取其中2个求和,得数有()个.",
+        "options":  [
+
+                    ],
+        "answer":  "5",
+        "solution":  "【分析】分别列出各种得数,数一数即可求解.\n【详解】1+2=3;1+3=4;1+4=5;2+3=5;2+4=6;3+4=7,有3,4,5,6,7,共5个得数.",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "23-24二年级上·山东济宁·期末"
+    },
+    {
+        "id":  "251",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "老师从笔记本,文具盒,钢笔三个礼品中选2样,送给小明和小芳各1样,共有()种送法.",
+        "options":  [
+
+                    ],
+        "answer":  "6",
+        "solution":  "【分析】可以送小明笔记本,文具盒,钢笔三个中的1个,这时有3种选法;然后给小芳送剩下的,这时有2种选法,用3乘2即可求解.\n【详解】3×2=6(种),共有6种送法.",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "23-24二年级上·湖南株洲·期末"
+    },
+    {
+        "id":  "252",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "快过年啦!3位好朋友约好见面时每两人拥抱1次,3人要拥抱()次;然后3人站成一排合影,共有()种不同的站法.",
+        "options":  [
+
+                    ],
+        "answer":  "3;6",
+        "solution":  "【分析】根据题意可知,拥抱时分别1和2为1次;1和3为1次;2和3为1次.合影时顺序可以为1,2,3;1,3,2;2,1,3;2,3,1;3,1,2;3,2,1,由此解答.\n【详解】由分析可知:快过年啦!3位好朋友约好见面时每两人拥抱1次,3人要拥抱3次;然后3人站成一排合影,共有6种不同的站法.",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "23-24二年级上·河南南阳·期末"
+    },
+    {
+        "id":  "253",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "用9,0,8三个数字组成两位数,每个两位数的个位数字和十位数字不能一样,可以组成()个不同的两位数.",
+        "options":  [
+
+                    ],
+        "answer":  "4",
+        "solution":  "【分析】先确定十位上的数,最高位上不能是0,所以十位有2种可能,则个位上有(3-1)种可能,用2乘2即可求解.\n【详解】3-1=2(个),2×2=4(个),可以组成4个不同的两位数.",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "23-24二年级上·江西赣州·期末"
+    },
+    {
+        "id":  "254",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "选用3,9,0中不同的两个数字能组成的两位数有().",
+        "options":  [
+
+                    ],
+        "answer":  "30,39,90,93",
+        "solution":  "【分析】从3,9,0中选两个数组成两位数,要组成两位数0只能放在个位上,3和9放在十位上,那么这个两位数是30和90,另外3和9个位和十位上都可以放,又可以组成的两位数是39和93.\n【详解】由以上分析可得,选用3,9,0中不同的两个数字能组成的两位数有30,39,90,93.",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "23-24二年级上·湖北襄阳·期末"
+    },
+    {
+        "id":  "255",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "有红黄蓝三面小旗,把它们排成一排,共有()种不同的排法.",
+        "options":  [
+
+                    ],
+        "answer":  "6",
+        "solution":  "【分析】用列举的方法,把不同的排列方法一一列举出来,然后数一数有几种即可.\n【详解】由题意分析得:红黄蓝三面小旗,把它们排成一排,不同的排法有:红黄蓝;红蓝黄;黄蓝红;黄红蓝;蓝红黄;蓝黄红;故,有红黄蓝三面小旗,把它们排成一排,共有6种不同的排法.",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "23-24二年级上·甘肃天水·期末"
+    },
+    {
+        "id":  "256",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "用5,0,9三个数字能摆成()个两位数,其中最大的两位数是(),最小的两位数是().",
+        "options":  [
+
+                    ],
+        "answer":  "4;95;50",
+        "solution":  "【分析】把5,0,9三个数字摆出的两位数一一列举出来,然后数一数即可知道有几个;再比较大小,即可解决.\n【详解】用5,0,9三个数字摆成的两位数有:50,90,59,95,一共4个;50\u003c59\u003c90\u003c95,故,用5,0,9三个数字能摆成4个两位数,其中最大的两位数是95,最小的两位数是50.",
+        "knowledge_points":  [
+                                 "搭配问题",
+                                 "100以内数的比大小"
+                             ],
+        "source":  "23-24二年级上·甘肃天水·期末"
+    },
+    {
+        "id":  "257",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "用数字2,0,8可以组成()个不同的两位数,其中组成最大的两位数是(),最小的两位数是().",
+        "options":  [
+
+                    ],
+        "answer":  "4;82;20",
+        "solution":  "【分析】根据题意,组成两位数时,十位上不能为0,组成的数字有20,28,80,82.再比较它们的大小即可找出最大的和最小的.因为都是两位数,先比较十位,十位大的数就大;十位相同比较个位,个位大的数就大.\n【详解】82\u003e80\u003e28\u003e20,用数字2,0,8可以组成4个不同的两位数,其中组成最大的两位数是82,最小的两位数是20.",
+        "knowledge_points":  [
+                                 "搭配问题",
+                                 "100以内数的比大小"
+                             ],
+        "source":  "23-24二年级上·湖北黄石·期末"
+    },
+    {
+        "id":  "258",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "苹苹生日那天,妈妈给她买了3件上衣和2条裙子,苹苹想试一试衣服怎样搭配最合适,每次上衣穿一件,裙子穿一条,她有()种不同的搭配方法.",
+        "options":  [
+
+                    ],
+        "answer":  "6",
+        "solution":  "【分析】根据题意可知,每1件上衣可以搭配2条裙子,共3件上衣,共有2×3种搭配方法.\n【详解】2×3=6(种),她有6种不同的搭配方法.",
+        "knowledge_points":  [
+                                 "搭配问题",
+                                 "3的乘法口诀及应用"
+                             ],
+        "source":  "22-23三年级下·全国·单元测试"
+    },
+    {
+        "id":  "259",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.4,
+        "question":  "3个小朋友互通一次电话,一共要通()次电话.",
+        "options":  [
+
+                    ],
+        "answer":  "3",
+        "solution":  "【分析】可以这样想:假设3个小朋友分别是:甲,乙,丙.甲需要和乙,丙通一次电话,乙需要和丙通一次电话,即甲乙,甲丙,乙丙,这样就能保证每两个人互通一次电话,并且不重复.在解决搭配问题时,一般先固定第一个,分别与后边搭配,看有几种搭配方式;再固定第二个,分别与后边搭配,看有几种搭配方式;依次类推,最后把所有的搭配方式加在一起即可,这样就能做到不重不漏.\n【详解】假设3个小朋友分别是:甲,乙,丙.共有甲乙,甲丙,乙丙三种搭配,即一共要通3次电话.",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "17-18二年级上·全国·单元测试"
+    },
+    {
+        "id":  "260",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "小丽和小明分别从苹果,香蕉和葡萄中选取一种水果,且两人选的水果不同,有()种选择方法.",
+        "options":  [
+
+                    ],
+        "answer":  "6",
+        "solution":  "【分析】小丽有3种选择,小明从剩下的2种水果中选一种,即可求出有几种选择方法.\n【详解】3×2=6(种),故,有6种选择方法.",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "23-24二年级上·吉林松原·期末"
+    },
+    {
+        "id":  "261",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "用数字卡片1,2,5能摆成()个不同的两位数.",
+        "options":  [
+
+                    ],
+        "answer":  "6",
+        "solution":  "【分析】三个不同的数字组成没有重复数字的两位数时:让每个数字(0除外)先作十位数,然后其余两个数字依次和它组合.注意,不要遗漏,0不能放在两位数的十位上.\n【详解】1作十位可组成的两位数:12,15.2作十位可组成的两位数:21,25.5作十位可组成的两位数:51,52.能摆成6个不同的两位数.",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "23-24二年级上·山东济宁·期末"
+    },
+    {
+        "id":  "262",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "用1,5,7可以组成()个不同的两位数,其中最大两位数是().",
+        "options":  [
+
+                    ],
+        "answer":  "6;75",
+        "solution":  "【分析】先把1,5,7组成的不同的两位数一一列举出来,再数一数即可知道有几个;然后比较大小,即可解决此题.\n【详解】用1,5,7组成的不同的两位数有:15,17,51,57,71,75,共6个;15\u003c17\u003c51\u003c57\u003c71\u003c75,故,用1,5,7可以组成6个不同的两位数,其中最大两位数是75.",
+        "knowledge_points":  [
+                                 "搭配问题",
+                                 "100以内数的比大小"
+                             ],
+        "source":  "23-24二年级上·湖南怀化·期末"
+    },
+    {
+        "id":  "263",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "用4,2和1组成两位数,每个两位数的十位数字和个位数字不能一样,能组成()个两位数,其中最大的是().",
+        "options":  [
+
+                    ],
+        "answer":  "6;42",
+        "solution":  "【分析】每个两位数的十位数字和个位数字不能一样,先确定十位上的数,再确定个位上的数,由此写出可以组成的数12,14,21,24,42,41,再将这些数进行比较大小,找出最大的数即可.\n【详解】用4,2和1组成的两位数有:12,14,21,24,41,42,共有6个;12\u003c14\u003c21\u003c24\u003c41\u003c42,最大的是42,所以用4,2和1组成两位数,每个两位数的十位数字和个位数字不能一样,能组成6个两位数,其中最大的是42.",
+        "knowledge_points":  [
+                                 "搭配问题",
+                                 "100以内数的比大小"
+                             ],
+        "source":  "23-24二年级上·青海果洛·期末"
+    },
+    {
+        "id":  "264",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "用7,0,2组成两位数,每个两位数的十位数字和个位数字不能一样,能组成()个不同的两位数.",
+        "options":  [
+
+                    ],
+        "answer":  "4",
+        "solution":  "【分析】利用枚举法,按十位数字分别是7和2列举即可.\n【详解】用7,0,2组成两位数,能组成4个不同的两位数,分别是:70,72,20,27.所以,能组成4个不同的两位数.",
+        "knowledge_points":  [
+                                 "搭配问题",
+                                 "100以内数的组成"
+                             ],
+        "source":  "23-24二年级上·山东临沂·期末"
+    },
+    {
+        "id":  "265",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "从语文,数学,英语3本书中选2本,分给丽丽,聪聪各1本,一共有()种不同的分法.",
+        "options":  [
+
+                    ],
+        "answer":  "6",
+        "solution":  "【分析】从三本书中选1本,送给丽丽有3种选择,再从剩下的2本书中选1本,送给聪聪有2种选择,根据乘法原理可得,共有3×2=6种选择.\n【详解】3×2=6(种),所以一共有6种.",
+        "knowledge_points":  [
+                                 "搭配问题",
+                                 "3的乘法口诀及应用"
+                             ],
+        "source":  "23-24二年级上·陕西延安·期末"
+    },
+    {
+        "id":  "266",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "有2元,5元,10元的人民币各一张,至少拿出2张,共能组成()种不同的币值.",
+        "options":  [
+
+                    ],
+        "answer":  "4",
+        "solution":  "【分析】用列举法一一列举出所有情况即可得出答案.\n【详解】取2张的情况:1张2元和1张5元,合起来的币值是2+5=7(元);1张2元和1张10元,合起来的币值是2+10=12(元);1张5元和1张10元,合起来的币值是5+10=15(元).取3张的情况:2+5+10=7+10=17(元),所以,一共能组成4种不同的币值.",
+        "knowledge_points":  [
+                                 "搭配问题",
+                                 "十元以上人民币的认识与计算"
+                             ],
+        "source":  "23-24二年级上·广东河源·期末"
+    },
+    {
+        "id":  "267",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "用0,3,5可以组成()个十位数字和个位数字不同的两位数,组成的这些两位数中最小的是().",
+        "options":  [
+
+                    ],
+        "answer":  "4;30",
+        "solution":  "【分析】把0,3,5组成的十位数字和个位数字不同的两位数列举出来,即可知道一共有几个;再比较大小,即可找出最小的数.\n【详解】用0,3,5组成的十位数字和个位数字不同的两位数有30,50,35,53,一共有4个;30\u003c35\u003c50\u003c53,故,用0,3,5可以组成4个十位数字和个位数字不同的两位数,组成的这些两位数中最小的是30.",
+        "knowledge_points":  [
+                                 "搭配问题",
+                                 "100以内数的比大小"
+                             ],
+        "source":  "23-24二年级上·广东河源·期末"
+    },
+    {
+        "id":  "268",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "从2,3,0三个数字中任选两个组成没有重复数字的两位数,能组成()个数,最大的数与最小的数的差是().",
+        "options":  [
+
+                    ],
+        "answer":  "4;12",
+        "solution":  "【分析】从2,3,0三个数字中任选两个组成没有重复数字的两位数,分别是20,23,30,32,一共4个,最大的是32,最小的是20,32-20=12,相差是12,据此得出结论即可.\n【详解】根据分析知:从2,3,0三个数字中任选两个组成没有重复数字的两位数,能组成4个数,32-20=12,故最大的数与最小的数的差是12.",
+        "knowledge_points":  [
+                                 "搭配问题",
+                                 "100以内数的比大小",
+                                 "100以内数的组成",
+                                 "两位数与整十数的减法"
+                             ],
+        "source":  "23-24二年级上·四川广元·期末"
+    },
+    {
+        "id":  "269",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "用2,4,6这三个数字组成两位数,每个两位数的个位数字和十位数字不同,能组成()个不同的两位数.其中,最大的两位数是().",
+        "options":  [
+
+                    ],
+        "answer":  "6;64",
+        "solution":  "【分析】用列举法一一列举出能组成的两位数分别是哪些,再进行比较大小,找出其中最大的两位数即可.\n【详解】用2,4,6这三个数字组成两位数,每个两位数的个位数字和十位数字不同,能组成的不同两位数有:24,26,42,46,62,64,一共有6个.24\u003c26\u003c42\u003c46\u003c62\u003c64,其中最大的两位数是64.",
+        "knowledge_points":  [
+                                 "搭配问题",
+                                 "100以内数的比大小",
+                                 "100以内数的组成"
+                             ],
+        "source":  "23-24二年级上·湖北随州·期末"
+    },
+    {
+        "id":  "270",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "从5,2,9三个数中任意选取两个数相乘,乘得的积有()种可能.其中最大的积比最小的积多().",
+        "options":  [
+
+                    ],
+        "answer":  "3;35",
+        "solution":  "【分析】通过列举的方法,把5,2,9三个数中任意选取两个数相乘,所有的可能性一一列举出来,然后比较大小,找出最大的积和最小的积,再作差,即可解决.\n【详解】从5,2,9三个数中任意选取两个数相乘,有以下可能:①5×2=10;②5×9=45;③2×9=18;45\u003e18\u003e10,45-10=35,故,从5,2,9三个数中任意选取两个数相乘,乘得的积有3种可能.其中最大的积比最小的积多35.",
+        "knowledge_points":  [
+                                 "搭配问题",
+                                 "100以内数的比大小",
+                                 "5的乘法口诀及应用",
+                                 "9的乘法口诀及应用"
+                             ],
+        "source":  "23-24二年级上·湖北荆州·期末"
+    },
+    {
+        "id":  "271",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "从3,8,9这三个数中选取2个数求和,得数有()种可能.",
+        "options":  [
+
+                    ],
+        "answer":  "3",
+        "solution":  "【分析】通过列举的方法,把所有的可能性一一列举出来,然后数一数,即可解决.\n【详解】由题意分析得:从3,8,9这三个数中选取2个数求和,可能性如下:①3+8=11;②3+9=12;③8+9=17,故,从3,8,9这三个数中选取2个数求和,得数有3种可能.",
+        "knowledge_points":  [
+                                 "搭配问题",
+                                 "9加几的进位加法",
+                                 "5~2加几的进位加法"
+                             ],
+        "source":  "23-24二年级上·新疆巴音郭楞·期末"
+    },
+    {
+        "id":  "272",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "用1,3,5三个数字能组成()个不同的两位数.",
+        "options":  [
+
+                    ],
+        "answer":  "6",
+        "solution":  "【分析】用列举法一一列举出组成的两位数,再进行解答.\n【详解】用1,3,5三个数字能组成的不同两位数有:13,15,31,35,51,53一共有6个.",
+        "knowledge_points":  [
+                                 "搭配问题",
+                                 "100以内数的组成"
+                             ],
+        "source":  "23-24二年级上·河北邯郸·期末"
+    },
+    {
+        "id":  "273",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "用3,0,5组成两位数,如果每个两位数中都没有重复数字,那么一共能组成()个两位数,最大的是().",
+        "options":  [
+
+                    ],
+        "answer":  "4;53",
+        "solution":  "【分析】先把3,0,5组成没有重复数字的两位数一一列举出来,再数一数,即可知道有几个,然后比较大小,找出最大的那个数即可.\n【详解】用3,0,5组成没有重复数字的两位数有:30,50,35,53;一共4个;30\u003c35\u003c50\u003c53,故,用3,0,5组成两位数,如果每个两位数中都没有重复数字,那么一共能组成4个两位数,最大的是53.",
+        "knowledge_points":  [
+                                 "搭配问题",
+                                 "100以内数的比大小",
+                                 "100以内数的组成"
+                             ],
+        "source":  "23-24二年级上·浙江宁波·期末"
+    },
+    {
+        "id":  "274",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "我和爸爸,妈妈坐成一排合影,有()种坐法.",
+        "options":  [
+
+                    ],
+        "answer":  "6",
+        "solution":  "【分析】把三人坐成一排合影的坐法一一列举出来,再数一数,即可解决.\n【详解】我和爸爸,妈妈坐成一排合影的坐法有:①我,爸爸,妈妈;②我,妈妈,爸爸;③爸爸,我,妈妈;④爸爸,妈妈,我;⑤妈妈,我,爸爸;⑥妈妈,爸爸,我;故,我和爸爸,妈妈坐成一排合影,有6种坐法.",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "23-24二年级上·湖南岳阳·期末"
+    },
+    {
+        "id":  "275",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "用卡片(1,2,3)组成两位数,每个两位数的十位数字和个位数字不能一样,能组成()个两位数,最大的是().",
+        "options":  [
+
+                    ],
+        "answer":  "6;32",
+        "solution":  "【分析】每个两位数的十位数字和个位数字不能一样,则可以组成12,13,21,23,31,32,再将这些数进行比较大小,找出最大的数即可.\n【详解】32\u003e31\u003e23\u003e21\u003e13\u003e12,用这些卡片组成十位数字和个位数字不一样的两位数,一共能组成6个两位数,最大的是32.",
+        "knowledge_points":  [
+                                 "搭配问题",
+                                 "100以内数的比大小"
+                             ],
+        "source":  "23-24二年级上·浙江温州·期末"
+    },
+    {
+        "id":  "276",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "用3,4,7这三张数字卡片组成两位数,能组成()个不同的两位数.",
+        "options":  [
+
+                    ],
+        "answer":  "6",
+        "solution":  "【分析】把3,4,7这三张数字卡片组成不同的两位数列举出来,再数一数有几个,即可解决.\n【详解】由题意分析得:用3,4,7这三张数字卡片组成不同的两位数有:34,37,43,47,73,74;故,用3,4,7这三张数字卡片组成两位数,能组成6个不同的两位数.",
+        "knowledge_points":  [
+                                 "搭配问题",
+                                 "100以内数的组成"
+                             ],
+        "source":  "23-24二年级上·河北廊坊·期末"
+    },
+    {
+        "id":  "277",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "用8,1,2组成两位数,每个两位数的十位数字和个位数字不能一样,可以组成()个不同的两位数,其中最大的两位数是().",
+        "options":  [
+
+                    ],
+        "answer":  "6;82",
+        "solution":  "【分析】先确定十位上的数,再确定个位上的数,由此写出用8,1,2可以组成的两位数,从而解决问题.\n【详解】用8,1,2组成两位数有81,82,18,12,28,21,一共有6个.82\u003e81\u003e28\u003e21\u003e18\u003e12,其中最大的两位数是82.",
+        "knowledge_points":  [
+                                 "搭配问题",
+                                 "100以内数的比大小",
+                                 "100以内数的组成"
+                             ],
+        "source":  "23-24二年级上·江西吉安·期末"
+    },
+    {
+        "id":  "278",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在3,4,5这三个数中任意选取两个数相乘,可以得到()个不同的乘积.",
+        "options":  [
+
+                    ],
+        "answer":  "3",
+        "solution":  "【分析】根据题意,可以选择3和4相乘,3和5相乘,4和5相乘,计算出结果解答即可.\n【详解】3×4=12;3×5=15;4×5=20,在3,4,5这三个数中任意选取两个数相乘,可以得到3个不同的乘积.",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "23-24二年级上·湖南长沙·期末"
+    },
+    {
+        "id":  "279",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "用3,0,6可以组成()个没有重复数字的两位数,其中最大的是(),最小的是().",
+        "options":  [
+
+                    ],
+        "answer":  "4;63;30",
+        "solution":  "【分析】先把3,0,6组成没有重复数字的两位数一一列举出来,再数一数即可知道一共有几个;最后比较大小,即可解决此题.\n【详解】用3,0,6组成没有重复数字的两位数有:30,60,36,63,一共有4个;63\u003e60\u003e36\u003e30,故,用3,0,6可以组成4个没有重复数字的两位数,其中最大的是63,最小的是30.",
+        "knowledge_points":  [
+                                 "搭配问题",
+                                 "100以内数的比大小"
+                             ],
+        "source":  "23-24二年级上·新疆喀什·期末"
+    },
+    {
+        "id":  "280",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "用4,5,1能组成()个个位数字和十位数字不同的两位数.",
+        "options":  [
+
+                    ],
+        "answer":  "6",
+        "solution":  "【分析】把4,5,1组成个位数字和十位数字不同的两位数一一列举出来,再数一数有几个即可解决.\n【详解】用4,5,1组成个位数字和十位数字不同的两位数有:45,41,54,51,14,15.故,用4,5,1能组成6个个位数字和十位数字不同的两位数.",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "23-24二年级上·湖北襄阳·期末"
+    },
+    {
+        "id":  "281",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "用1,2,4这三张卡片能组成()个两位数.",
+        "options":  [
+
+                    ],
+        "answer":  "6",
+        "solution":  "【分析】用1,2,4组成两位数时,用其中一个数作为十位,另外两个数分别作为个位.由此解答.\n【详解】由分析得:可组成的数有12,14,21,24,41,42.用1,2,4这三张卡片能组成6个两位数.",
+        "knowledge_points":  [
+                                 "搭配问题",
+                                 "100以内数的组成"
+                             ],
+        "source":  "23-24二年级上·甘肃平凉·期末"
+    },
+    {
+        "id":  "282",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "从7,8和9这三个数字中,任选两个数字求和,结果有()种可能.",
+        "options":  [
+
+                    ],
+        "answer":  "3",
+        "solution":  "【分析】任选两个数字求和时,可选择7和8;7和9;8和9.分别求和可知共有几种结果.\n【详解】7+8=15;7+9=16;8+9=17,从7,8和9这三个数字中,任选两个数字求和,结果有3种可能.",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "23-24二年级上·甘肃武威·期末"
+    },
+    {
+        "id":  "283",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.94,
+        "question":  "李老师从小华,小齐,小军3人中挑选两人参加跳绳比赛,有()种选法.",
+        "options":  [
+
+                    ],
+        "answer":  "3",
+        "solution":  "【分析】从小华,小齐,小军三人中选两人,是3选2的组合问题,写出所有的可能即可求解.\n【详解】从小华,小齐,小军三人中选两人,有以下的选择方法:小华,小齐;小齐,小军;小华,小军,所以一共有3种选法.",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "23-24二年级上·黑龙江鸡西·期末"
+    },
+    {
+        "id":  "284",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "用3,0,7三张卡片,可以摆出()个不同的两位数,其中最大的是(),最小的是(),它们相差().",
+        "options":  [
+
+                    ],
+        "answer":  "4;73;30;43",
+        "solution":  "【分析】用列举的方法,把3,0,7三张卡片摆出不同的两位数一一列举出来,然后比较这些数的大小,找出最大的数和最小的数,最后求出两数差,即可解决此题.\n【详解】用3,0,7三张卡片摆出不同的两位数有:30,70,37,73;73\u003e70\u003e37\u003e30;73-30=43,故,用3,0,7三张卡片,可以摆出4个不同的两位数,其中最大的是73,最小的是30,它们相差43.",
+        "knowledge_points":  [
+                                 "搭配问题",
+                                 "100以内数的比大小",
+                                 "100以内数的组成",
+                                 "两位数与整十数的减法"
+                             ],
+        "source":  "22-23二年级上·浙江嘉兴·期末"
+    },
+    {
+        "id":  "285",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "用7,5,9这三张数字卡片摆两位数,可以摆出()个不同的两位数,这些两位数中,最大的两位数是(),它比最小的三位数小().",
+        "options":  [
+
+                    ],
+        "answer":  "6;97;3",
+        "solution":  "【分析】用7,5,9组成两位数时,用一个数作为十位,另外两个数分别作为个位,组成的数有:75,79,57,59,95,97;比较大小时,都是两位数,则从十位开始比起,十位大的数就大;十位相同比较个位,直到比较出结果找到最大的两位数;求它比最小的三位数小多少,最小的三位数是100,用100减去组成的最大的两位数即可.\n【详解】97\u003e95\u003e79\u003e75\u003e59\u003e57;100-97=3,用7,5,9这三张数字卡片摆两位数,可以摆出6个不同的两位数,这些两位数中,最大的两位数是97,它比最小的三位数小3.",
+        "knowledge_points":  [
+                                 "搭配问题",
+                                 "100以内数的比大小",
+                                 "两位数与两位数的退位减法"
+                             ],
+        "source":  "22-23二年级上·浙江杭州·期末"
+    },
+    {
+        "id":  "286",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "用2,5,7组成两位数,每个两位数的个位数字和十位数字不能一样,能组成()个不同的两位数.",
+        "options":  [
+
+                    ],
+        "answer":  "6",
+        "solution":  "【分析】把2,5,7组成的两位数且个位数字和十位数字不一样的全部列举出来,然后数一数即可知道有几个不同的两位数.\n【详解】由题意分析得:2,5,7组成的两位数且个位数字和十位数字不一样的有:25,27,52,57,72,75;故,用2,5,7组成两位数,每个两位数的个位数字和十位数字不能一样,能组成6个不同的两位数.",
+        "knowledge_points":  [
+                                 "搭配问题",
+                                 "100以内数的组成"
+                             ],
+        "source":  "22-23二年级上·山东临沂·期末"
+    },
+    {
+        "id":  "287",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "从2,6,0这3个数中,任意选取其中两个数字求和,得数有()种可能,最大的和最小的相差().",
+        "options":  [
+
+                    ],
+        "answer":  "3;6",
+        "solution":  "【分析】先确定第一个加数,然后选择第二个加数,这样分别求出和,即可确定和有几种可能;然后用减法计算出最大的和与最小的和相差多少.\n【详解】2+6=8;2+0=2;6+0=6;8\u003e6\u003e2;8-2=6,故,得数有3种可能,最大的和最小的相差6.",
+        "knowledge_points":  [
+                                 "搭配问题",
+                                 "9以内数的比大小",
+                                 "有关0的加减法",
+                                 "8,9的加减法"
+                             ],
+        "source":  "22-23二年级上·重庆巫溪·期末"
+    },
+    {
+        "id":  "288",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "用0,3,6这三个数中的任意两个数求和,得数有()种可能,其中最大的和与最小的和相差().",
+        "options":  [
+
+                    ],
+        "answer":  "3;6",
+        "solution":  "【分析】先把0,3,6这三个数两两相加,求出和,然后数一数,即可知道得数有几种可能;接着比较大小,最后用最大的和减去最小的和,求出差,即可解决.\n【详解】0+3=3;0+6=6;3+6=9;3\u003c6\u003c9;9-3=6,故,用0,3,6这三个数中的任意两个数求和,得数有3种可能,其中最大的和与最小的和相差6.",
+        "knowledge_points":  [
+                                 "搭配问题",
+                                 "10以内数的比大小",
+                                 "有关0的加减法",
+                                 "8,9的减法"
+                             ],
+        "source":  "22-23二年级上·云南昭通·期末"
+    },
+    {
+        "id":  "289",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "用4,5和7组成两位数,每个两位数的十位数字和个位数字不能一样,能组成()个两位数,其中最大的两位数是().",
+        "options":  [
+
+                    ],
+        "answer":  "6;75",
+        "solution":  "【分析】用4,5和7组成两位数时,用其中一个数作为十位,另外两个数分别作为个位,组成的数有45;47;54;57;74;75;比较大小时,都是两位数,从十位比起,十位数字大的数就大,十位相同,比较个位,个位大的数就大,由此解答.\n【详解】组成的数有45;47;54;57;74;75;75\u003e74\u003e57\u003e54\u003e47\u003e45,用4,5和7组成两位数,每个两位数的十位数字和个位数字不能一样,能组成6个两位数,其中最大的两位数是75.",
+        "knowledge_points":  [
+                                 "搭配问题",
+                                 "100以内数的比大小"
+                             ],
+        "source":  "22-23二年级上·福建福州·期末"
+    },
+    {
+        "id":  "290",
+        "unit":  "搭配",
+        "question_type":  "判断题",
+        "difficulty":  0.65,
+        "question":  "用2,5,4三张数字卡可以组成6个十位数字和个位数字不同的两位数.()",
+        "options":  [
+
+                    ],
+        "answer":  "√",
+        "solution":  "【分析】用2,5,4三张数字卡组成的十位数字和个位数字不同的两位数有:25,24,52,54,42,45,共6个.\n【详解】用2,5,4三张数字卡可以组成6个十位数字和个位数字不同的两位数.原题说法正确.故答案为:√",
+        "knowledge_points":  [
+                                 "搭配问题",
+                                 "100以内数的组成"
+                             ],
+        "source":  "23-24二年级上·河南焦作·期末"
+    },
+    {
+        "id":  "291",
+        "unit":  "搭配",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "从4,7,9这3个数中,选取2个求和,得数有3种可能.()",
+        "options":  [
+
+                    ],
+        "answer":  "√",
+        "solution":  "【分析】根据题意,可以用4和7,4和9,7和9求和,由此解答.\n【详解】4+7=11;4+9=13;7+9=16,从4,7,9这3个数中,选取2个求和,得数有3种可能.原题说法正确.故答案为:√",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "23-24二年级上·湖南怀化·期末"
+    },
+    {
+        "id":  "292",
+        "unit":  "搭配",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "从3,4,5这3个数中,选取2个数求积,得数有3种可能.()",
+        "options":  [
+
+                    ],
+        "answer":  "√",
+        "solution":  "【分析】根据题意,选取2个数时,可以选择3,4;3,5和4,5,由此计算出结果判断即可.\n【详解】3×4=12;3×5=15;4×5=20,从3,4,5这3个数中,选取2个数求积,得数有3种可能.原题说法正确.故答案为:√",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "23-24二年级上·湖北武汉·期末"
+    },
+    {
+        "id":  "293",
+        "unit":  "搭配",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "每两个人互通一次电话,3人一共通了6次电话.()",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】根据题意,每两个人互通一次电话.可以是第1个人和第2个人互通电话;第1个人和第3个人互通电话;第2个人和第3个人互通电话.由此解答.\n【详解】由分析可知,每两个人互通一次电话,3人一共通了3次电话.原题说法错误.故答案为: ×",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "23-24二年级上·湖北武汉·期末"
+    },
+    {
+        "id":  "294",
+        "unit":  "搭配",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "小兰,小丽和小东三个好朋友见面了,他们每两人握一次手,一共要握3次手.()",
+        "options":  [
+
+                    ],
+        "answer":  "√",
+        "solution":  "【分析】可以用列举的方法来解决此题,小兰和小丽握手一次,小兰和小东握手一次,小丽和小东握手一次.\n【详解】由题意分析得:小兰和小丽握手一次,小兰和小东握手一次,小丽和小东握手一次;一共要握3次手.原说法正确.故答案为:√",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "23-24二年级上·四川南充·期末"
+    },
+    {
+        "id":  "295",
+        "unit":  "搭配",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "有3种奶糖,每两种装一袋,共有2种装法.()",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】假设它们为甲,乙,丙3种奶糖,可以甲,乙装一袋,可以乙,丙装一袋,可以甲,丙装一袋,共3种装法.\n【详解】有3种奶糖,每两种装一袋,共有3种装法.原题说法错误.故答案为: ×",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "23-24二年级上·河南南阳·期末"
+    },
+    {
+        "id":  "296",
+        "unit":  "搭配",
+        "question_type":  "判断题",
+        "difficulty":  0.65,
+        "question":  "小红和2名同学握手,每2个人握一次,一共要握6次.()",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】一共3名同学,分别是小红和甲同学握手,小红和乙同学握手,甲同学和乙同学握手,共3次.\n【详解】小红和2名同学握手,每2个人握一次,一共要握3次.原题说法错误.故答案为: ×",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "23-24二年级上·湖北黄石·期末"
+    },
+    {
+        "id":  "297",
+        "unit":  "搭配",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "4件上衣和3条裤子搭配成一套衣服,有7种搭配方法.()",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】根据题意,1条裤子搭配1件上衣,就有4种不同的搭配方法.有3条裤子,就有4×3种搭配方法.\n【详解】4×3=12(种),4件上衣和3条裤子搭配成一套衣服,有12种搭配方法.原题说法错误.故答案为: ×",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "21-22三年级下·全国·单元测试"
+    },
+    {
+        "id":  "298",
+        "unit":  "搭配",
+        "question_type":  "判断题",
+        "difficulty":  0.65,
+        "question":  "用2,0,7三个数字可组出4个不同的两位数.()",
+        "options":  [
+
+                    ],
+        "answer":  "√",
+        "solution":  "【分析】先把2,0,7三个数字组成不同的两位数一一列举出来,再数一数,即可解决.\n【详解】用2,0,7三个数字组成不同的两位数有:20,70,27,72;即,用2,0,7三个数字可组出4个不同的两位数;此说法正确.故答案为:√",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "23-24二年级上·陕西安康·期末"
+    },
+    {
+        "id":  "299",
+        "unit":  "搭配",
+        "question_type":  "判断题",
+        "difficulty":  0.65,
+        "question":  "三个好朋友握手,每两人握一次,要握3次手.()",
+        "options":  [
+
+                    ],
+        "answer":  "√",
+        "solution":  "【分析】假如三个好朋友分别为A,B,C,A和B握手一次,A和C握手一次,B和C握手一次,总共握手3次,据此得出结论即可.\n【详解】根据分析知,原题结论正确.故答案为:√",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "23-24二年级上·四川广元·期末"
+    },
+    {
+        "id":  "300",
+        "unit":  "搭配",
+        "question_type":  "判断题",
+        "difficulty":  0.65,
+        "question":  "三位羽毛球运动员进行比赛,每两个人比赛一场,共要进行6场比赛.()",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】可以这样想:假设三位羽毛球运动员分别是:甲,乙,丙.甲需要和乙,丙进行比赛,乙需要和丙进行比赛,即甲乙,甲丙,乙丙,这样就能保证每两个人比赛一场并且不重复.在解决搭配问题时,一般先固定第一个,分别与后边搭配,看有几种搭配方式;再固定第二个,分别与后边搭配,看有几种搭配方式;依次类推,最后把所有的搭配方式加在一起即可,这样就能做到不重不漏.\n【详解】假设三位羽毛球运动员分别是:甲,乙,丙.共有甲乙,甲丙,乙丙三种搭配,即共要进行3场比赛.故答案为: ×",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "23-24二年级上·青海果洛·期末"
+    },
+    {
+        "id":  "301",
+        "unit":  "搭配",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "从香蕉,苹果,草莓三种水果中任意选出两种做水果拼盘,一共有()种选法.",
+        "options":  [
+                        "A. 2",
+                        "B. 3",
+                        "C. 6"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】通过列举的方法,把所有的选法都一一列举出来,然后数一数有几种选法即可解决.\n【详解】从香蕉,苹果,草莓三种水果中任意选出两种做水果拼盘,可以这样选:香蕉和苹果;香蕉和草莓;苹果和草莓;一共有3种.故答案为:B",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "22-23二年级上·山东临沂·期末"
+    },
+    {
+        "id":  "302",
+        "unit":  "搭配",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "丽丽和爸爸到餐厅吃饭,餐厅菜谱如下:如果从素菜和荤菜中各选一种,共有()种搭配方法.\n\n![](images/2026-03-03%20002951.jpg)",
+        "options":  [
+                        "A. 2",
+                        "B. 4",
+                        "C. 6"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】酸辣土豆丝搭配宫保鸡丁,酸辣土豆丝搭配红烧排骨,番茄鸡蛋搭配宫保鸡丁,番茄鸡蛋搭配红烧排骨,共四种搭配,据此得出结论即可.\n【详解】由分析知:共有四种搭配方式.故答案为:B",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "22-23二年级上·河南信阳·期末"
+    },
+    {
+        "id":  "303",
+        "unit":  "搭配",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "用数字卡片![](images/2026-03-03%20003022.jpg)可以摆出()个不同的两位数.",
+        "options":  [
+                        "A. 3",
+                        "B. 4",
+                        "C. 6"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】把2,0,8组成的不同两位数一一列举出来(十位上不能是0),再数一数有几个;据此解决.\n【详解】由2,0,8组成的不同两位数有:20,80,28,82;即,可以摆出4个不同的两位数.故答案为:B",
+        "knowledge_points":  [
+                                 "搭配问题",
+                                 "100以内数的组成"
+                             ],
+        "source":  "22-23二年级上·宁夏固原·期末"
+    },
+    {
+        "id":  "304",
+        "unit":  "搭配",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "春节期间团团,圆圆,欢欢,乐乐四位小朋友每两个人之间只通一次电话,一共可以通()次电话.",
+        "options":  [
+                        "A. 4",
+                        "B. 6",
+                        "C. 12"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】如下图,把4位小朋友一字排开,先把每位小朋友与其他小朋友分别连上线,再数一数一共连了几条线,连了几条线,就要通几次电话.稍复杂的组合问题可以用图示连线的方法来解决.\n【详解】如图,3+2+1=6(次),所以一共可以通6次电话.故答案为:B",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "21-22六年级上·吉林松原·期末"
+    },
+    {
+        "id":  "305",
+        "unit":  "搭配",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "从下面的水果中任意选择两种,一共有()种不同的选法.\n\n![](images/c1e4a24154980e811027edc69f1ef2445042746aced1a85d83aa6bde624a000d.jpg)",
+        "options":  [
+                        "A. 4",
+                        "B. 6",
+                        "C. 8"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】由题意可知,从这些水果中任意选择两种,可以选择:樱桃+草莓,樱桃+香蕉,樱桃+葡萄,草莓+香蕉,草莓+葡萄,香蕉+葡萄,一共有6种选法,据此解答即可.\n【详解】由分析可得:樱桃+草莓,樱桃+香蕉,樱桃+葡萄,草莓+香蕉,草莓+葡萄,香蕉+葡萄,一共有6种选法.因此这些水果中任意选择两种,一共有6种不同的选法.故答案为:B",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "22-23二年级上·全国·课后作业"
+    },
+    {
+        "id":  "306",
+        "unit":  "搭配",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "小东有5件上衣,4条裤子,一共有()种不同的搭配方法.\n\n![](images/53c4a6acc327c5eff7538714b5a9f94b5a9761c4883da8cf25b9dbdfa188b78b.jpg)",
+        "options":  [
+                        "A. 5",
+                        "B. 4",
+                        "C. 20"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】由题意可知,每一件上衣与裤子有4种不同的搭配方法,则5件不同的上衣和4条不同的裤子的搭配方法有:4×5=20(种),据此解答即可.\n【详解】4×5=20(种),因此小东有5件上衣,4条裤子,一共有20种不同的搭配方法.故答案为:C",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "22-23二年级上·全国·课后作业"
+    },
+    {
+        "id":  "307",
+        "unit":  "搭配",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "在下面图形的任意两点之间画一条直线,还可以画()条直线.\n\n![](images/b6eee6a1197b76d071e198589b183e4a4d2438351616ab6dafc8f3e11c79d82d.jpg)",
+        "options":  [
+                        "A. 5",
+                        "B. 8",
+                        "C. 9"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】根据题意,可依次将A,B,C,D,E作为起点去连线.作图如下:得到了5条直线.每个起点连线都可得到两条直线,但是会有重复,要确保无重复无丢落.\n【详解】由分析可知,在题中图形的任意两点之间画一条直线,还可以画5条直线.故答案为:A",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "22-23二年级上·全国·课后作业"
+    },
+    {
+        "id":  "308",
+        "unit":  "搭配",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "先从下左图的牌中摸两张,再从下右图的牌中摸一张,摸出的三张牌共有()种可能的结果.\n\n![](images/80287aca0242b01c156713a2bcd959a3eaa888fbf258b3ba2407726c7ae94689.jpg)\n![](images/1d80824a8218c8e41de03a74ff7ef237956259787fd92bf7f5bce1319685cf92.jpg)",
+        "options":  [
+                        "A. 6",
+                        "B. 9",
+                        "C. 18"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】由题意可知,从左下图摸两张有2种摸法,从右下图摸一张有3种摸法,根据乘法原理可得:2×3=6(种),据此解答即可.\n【详解】2×3=6(种),因此先从下左图的牌中摸两张,再从下右图的牌中摸一张,摸出的三张牌共有6种可能的结果.故答案为:A",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "22-23二年级上·全国·课后作业"
+    },
+    {
+        "id":  "309",
+        "unit":  "搭配",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "有三张卡片,正反面都写有1个数字,第一张写0和1,第二张写2和3,第三张写4和5,从这三张卡片中取出两张,放在一起组成两位数,共可组成()个.",
+        "options":  [
+                        "A. 20",
+                        "B. 22",
+                        "C. 24"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】由题意可知,首先确定十位,0不可能是十位,所以十位上就有1,2,3,4或者5,共有5种可能;第二步断定个位,个位数字可以是剩余2张卡片中的任意一张的任意一面,所以共有2×2=4(种)可能;根据乘法原理,一共可以组成:5×4=20(种),据此解答即可.\n【详解】5×4=20(种),因此从这三张卡片中取出两张,放在一起组成两位数,共可组成20个.故答案为:A",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "23-24二年级上·全国·课后作业"
+    },
+    {
+        "id":  "310",
+        "unit":  "搭配",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "玲玲有2套不同颜色的衣服,如果搭配起来有()种不同的穿法.\n\n![](images/45aa415115d6a31f841105c4a17d10cb8eb0bd4a827d1857f5340e94e4b8a337.jpg)\n![](images/23a3e4201cc0c3de8111dbfa207c40e864f03401497435732dc3c90d61a9d4c7.jpg)\n![](images/9264f011489d92b046c2a352f98b9621cbe24fbbe60ca7cdd3807b4efa6c5fdb.jpg)\n![](images/07e195c88efa473b152096096c1c556f043c78b434b1c41a5ff4e58bc61c443f.jpg)",
+        "options":  [
+                        "A. 4",
+                        "B. 5",
+                        "C. 6"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】根据题意可知,玲玲有2套不同颜色的衣服,可以这样搭配:粉色短袖+粉色裙子,粉色短袖+白色裙子,白色短袖+粉色裙子,白色短袖+白色裙子,一共有4种搭配的方法.\n【详解】因此玲玲有2套不同颜色的衣服,如果搭配起来有4种不同的穿法.故答案为:A",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "23-24二年级上·全国·课后作业"
+    },
+    {
+        "id":  "311",
+        "unit":  "搭配",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "商场大促销,两件衣服99元,张阿姨从下面3件衣服中任意买两件,有()种不同的买法.\n\n![](images/28688fe0b01459a54ed4a2ff55e61c0b0a5df21f438d78fc6b3ac098b92b0222.jpg)",
+        "options":  [
+                        "A. 5",
+                        "B. 4",
+                        "C. 3"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】由题意可知,从三件衣服里面任意挑选两件,可以选第一件和第二件;也可以选第一件和第三件;也可以选第二件和第三件,一共有3种选法.\n【详解】商场大促销,两件衣服99元,张阿姨从下面3件衣服中任意买两件,有3种不同的买法.故答案为:C",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "22-23二年级上·湖北黄石·期末"
+    },
+    {
+        "id":  "312",
+        "unit":  "搭配",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "从5,8,10三个数中任意选出两个数求和,得数有()种可能.",
+        "options":  [
+                        "A. 1",
+                        "B. 6",
+                        "C. 3"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】求两个数的和有几种可能,就是求从这三个数中任选两数,可以有几种搭配方式.可以选5和8,5和10,8和10,共3种搭配方式.\n【详解】5+8=13,5+10=15,8+10=18,从5,8,10三个数中任意选出两个数求和,得数有3种可能.故答案为:C",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "22-23二年级上·河南郑州·期末"
+    },
+    {
+        "id":  "313",
+        "unit":  "搭配",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "用1,3,6组成两位数,每个两位数的十位数字和个位数字不同,能组成()个两位数.",
+        "options":  [
+                        "A. 3",
+                        "B. 6",
+                        "C. 12"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】根据题意可组成13,16,31,36,61,63,一共6个.情况不多时可以全部列举出来.\n【详解】用1,3,6组成两位数,每个两位数的十位数字和个位数字不同,能组成6个两位数.故答案为:B",
+        "knowledge_points":  [
+                                 "搭配问题",
+                                 "100以内数的组成"
+                             ],
+        "source":  "20-21二年级上·湖南岳阳·期末"
+    },
+    {
+        "id":  "314",
+        "unit":  "搭配",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "有3个数5,8,9,任意选取其中2个求和,得数有()种可能.",
+        "options":  [
+                        "A. 1",
+                        "B. 3",
+                        "C. 6"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】可以分别用5和8,5和9,8和9求和,一共有3种可能.\n【详解】有3个数5,8,9,任意选取其中2个求和,得数有3种可能.故答案为:B",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "20-21二年级上·广东江门·期末"
+    },
+    {
+        "id":  "315",
+        "unit":  "搭配",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "从小明,小华和小刚3个同学中选2人参加篮球队,有()种选法.",
+        "options":  [
+                        "A. 2",
+                        "B. 3",
+                        "C. 6"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】可以选小明和小华,小明和小刚或者小华和小刚,共3种选择.人数比较少的情况下可以将所有情况列出来.\n【详解】从小明,小华和小刚3个同学中选2人参加篮球队,有3种选法.故答案为:B",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "20-21二年级上·四川乐山·期末"
+    },
+    {
+        "id":  "316",
+        "unit":  "搭配",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "3个人拥抱,每两个人都要拥抱一次,一共要拥抱()次.",
+        "options":  [
+                        "A. 3次",
+                        "B. 4次",
+                        "C. 5次"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】根据题意,三个人每两个人都要拥抱一次,假设是ABC三个人,A需要与另外两个人拥抱,共拥抱两次,B与C拥抱一次,C已经与其他两个人拥抱过,由此可知共需要拥抱3次,据此解答.\n【详解】2+1=3(次),故答案为:A",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "20-21二年级上·海南省直辖县级单位·期末"
+    },
+    {
+        "id":  "317",
+        "unit":  "搭配",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "如图,兰兰从家出发,经过超市到学校,一共有()种走法.\n\n![](images/e76c585e12017881920fc0c95cf9436991080c3c26c3fe1ed48ee6c800f9a52f.jpg)",
+        "options":  [
+                        "A. 12",
+                        "B. 7",
+                        "C. 6"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】兰兰从家到超市有4种走法,从超市到学校有3种走法,用4乘3即可求解.\n【详解】4×3=12(种),一共有12种走法.故答案为:A",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "20-21二年级上·江西赣州·期末"
+    },
+    {
+        "id":  "318",
+        "unit":  "搭配",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "三个小朋友,每两人互送一张贺卡,一共要准备()张贺卡.",
+        "options":  [
+                        "A. 1",
+                        "B. 3",
+                        "C. 6"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】三人之间要两两互送贺卡,每人给其他两人准备贺卡,每人需要准备2张,用乘法计算三个人一共是多少张.此题需要注意,如:甲给乙与乙给甲的不是同一张,需要算2次.\n【详解】3×2=6(张),所以,一共要准备6张贺卡.故答案为:C",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "20-21二年级上·山东临沂·期末"
+    },
+    {
+        "id":  "319",
+        "unit":  "搭配",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "将下面的3个玩具分别送给小红,小明和小兰,一共有()种不同的送法.\n\n![](images/bd20c1dde3b00554e22407c0332d022839dba685a2a4a2ebcba4ef2110d8e2cb.jpg)",
+        "options":  [
+                        "A. 2",
+                        "B. 3",
+                        "C. 6"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】根据题意,3个玩具分别送三人,假如小红是第一个人,则有3种选择,小明就有2种选择,小兰有剩下一种选择,由此解答.\n【详解】3×2×1=6(种),所以一共有6种不同的送法.故答案为:C",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "22-23二年级上·全国·期末"
+    },
+    {
+        "id":  "320",
+        "unit":  "搭配",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "6个男生站成一排,每两个男生之间站一名女生,一共站()名女生.",
+        "options":  [
+                        "A. 5",
+                        "B. 3",
+                        "C. 2"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】根据题意,6个男生,每两个男生之间站一名女生,可通过画图,○表示男生,△表示女生,画出数出即可.\n【详解】○△○△○△○△○△○,由图可知:一共站5名女生.故答案为:A",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "20-21二年级下·河南信阳·期末"
+    },
+    {
+        "id":  "321",
+        "unit":  "搭配",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "小红,小丽,小刚三个同学排队,有()种排法.",
+        "options":  [
+                        "A. 3",
+                        "B. 4",
+                        "C. 6"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】三个同学排队,即把三个人按照不同的顺序进行排列,可以列举所有可能的排法,也可以用乘法原理计算:第一个位置有3种选择,第二个位置有2种选择,第三个位置有1种选择,所以一共有3×2×1=6种排法.\n【详解】三个同学排队,所有可能的排法为:小红,小丽,小刚;小红,小刚,小丽;小丽,小红,小刚;小丽,小刚,小红;小刚,小红,小丽;小刚,小丽,小红,共6种.故答案为:C",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "21-22二年级上·湖北襄阳·期末"
+    },
+    {
+        "id":  "322",
+        "unit":  "搭配",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "有3个数2,6,9,任意选取其中2个求和,得数有()种可能.",
+        "options":  [
+                        "A. 3",
+                        "B. 4",
+                        "C. 6"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】任意选取其中2个求和,即从3个数字2,6,9,任取2个数即可列举.列举时要按顺序列举,防止遗漏,特别要注意加数交换位置,和是不变的情况.\n【详解】2+6=8,2+9=11,6+9=15,所以,任意选取其中2个求和,得数有3种可能.故答案为:A",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "21-22二年级上·河北承德·期末"
+    },
+    {
+        "id":  "323",
+        "unit":  "搭配",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "3个好朋友握手,每两人握一次,要握()次手.",
+        "options":  [
+                        "A. 3次",
+                        "B. 6次",
+                        "C. 9次"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】3个好朋友见面,每两人握一次手,看作甲,乙,丙三个人列举即可.本题是典型的握手问题,如果人数比较少,可以用枚举法解答.\n【详解】3个好朋友看作甲,乙,丙,则甲乙握一次手,甲丙握一次手,乙丙握一次手,共需要握手3次.故答案为:A",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "21-22二年级上·河南漯河·期末"
+    },
+    {
+        "id":  "324",
+        "unit":  "搭配",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "妈妈想在如图的3件上衣和2条裤子中选一套,她一共有()种搭配方法.\n\n![](images/2026-03-03%20004649.jpg)",
+        "options":  [
+                        "A. 6",
+                        "B. 5",
+                        "C. 4",
+                        "D. 3"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】从3件上衣中选一件有3种选法,从2条裤子中选一件有2种选法,根据乘法原理,共有3×2种不同的搭配方法.\n【详解】3×2=6(种),所以共有6种搭配方法.故答案为:A",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "21-22二年级上·山西吕梁·期末"
+    },
+    {
+        "id":  "325",
+        "unit":  "搭配",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "下面说法正确的是().",
+        "options":  [
+                        "A. 一个三角形中一共有4个角.",
+                        "B. 3个好朋友见面互相拥抱一次,一共要拥抱6次.",
+                        "C. 8+8+8+6可以写成算式8×4-2.",
+                        "D. 3×6可以表示3个6相乘的积是多少."
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】逐项分析每个选项的正确性.\n【详解】A中一个三角形一共有3个角,不是4个角;B中3人每两人拥抱一次应为3次,不是6次;C中8+8+8+6=8×4-2,正确;D中\"3个6相乘\"应是6×6×6,3×6并非此意.故只有C正确.",
+        "knowledge_points":  [
+                                 "搭配问题",
+                                 "6的乘法口诀及应用",
+                                 "角的初步认识及辨认",
+                                 "表内乘加,乘减"
+                             ],
+        "source":  "21-22二年级上·福建莆田·期末"
+    },
+    {
+        "id":  "326",
+        "unit":  "搭配",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "3名女同学和2名男同学进行羽毛球单打比赛,如果每名女同学和每名男同学都打一局,一共要打()局.",
+        "options":  [
+                        "A. 5",
+                        "B. 8",
+                        "C. 6"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】可以分2个步骤进行:先从2个男生中选出1位男生有2种不同的选法,再从3个女生中选出1位女生有3种不同的选法,用乘法原理即可.\n【详解】2×3=6(局),所以一共要打6局.故答案为:C",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "21-22二年级上·甘肃陇南·期末"
+    },
+    {
+        "id":  "327",
+        "unit":  "搭配",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "用3,6,9组成两位数,要求每个两位数都没有重复数字,能组成()个不同的两位数.",
+        "options":  [
+                        "A. 4",
+                        "B. 6",
+                        "C. 8"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】当十位上的数是3时,可以组成2个两位数,十位上的数还可以是6或9,因此一共可以组成2×3个没有重复数字的两位数.\n【详解】2×3=6(个),用3,6,9组成两位数,每个两位数都没有重复数字,能组成6个不同的两位数.故答案为:B",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "20-21二年级上·云南玉溪·期末"
+    },
+    {
+        "id":  "328",
+        "unit":  "搭配",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "上衣和裤子搭配有()种穿法.\n\n![](images/a4254c83b625aae5e16305c7c99018cff47f9daf88295a92cc03ae11996ec4a9.jpg)\n![](images/b49dfe1c9a33619c4642e0f60acfcc9d781c036e13f09ffa5abbfa1addfd2bef.jpg)\n![](images/41dc06f14299912a92634f3a1cea6ea0400a31f39244bab84aabe3e85ebfb4f8.jpg)\n![](images/775e8c800cc7b17c178b27d5466df9674ab5ba1f7e829f4846b12d8996bd6dc4.jpg)",
+        "options":  [
+                        "A. 3",
+                        "B. 4",
+                        "C. 6"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】上衣有2件,裤子有2条,每件上衣都可以和两条裤子搭配,求一共有几种不同的穿法,可以用乘法计算:上衣件数×裤子条数.\n【详解】2×2=4(种),所以一共有4种不同的穿法.故答案为:B",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "20-21二年级上·宁夏·期末"
+    },
+    {
+        "id":  "329",
+        "unit":  "搭配",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "米莉有三件上衣,两条裤子,她一共有()种穿法.",
+        "options":  [
+                        "A. 3",
+                        "B. 5",
+                        "C. 6"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】先给三件上衣和两条裤子分别编号,然后两两搭配,把所有搭配方法一一列举出来,数一数即可.\n【详解】三件上衣分别为①,②,③;两条裤子分别为A,B.穿法有:①A,①B,②A,②B,③A,③B,共6种.故答案为:C",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "21-22二年级上·甘肃陇南·期末"
+    },
+    {
+        "id":  "330",
+        "unit":  "搭配",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "每两个人握1次手,4个人一共握()次手.",
+        "options":  [
+                        "A. 6",
+                        "B. 8",
+                        "C. 10"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】每两个人握1次手,第1个人要握3次,第2个人再握2次,第3个人再握1次,据此解答.\n【详解】3+2+1=6(次),所以4个人一共握6次手.故答案为:A",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "20-21二年级上·贵州安顺·期末"
+    },
+    {
+        "id":  "331",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "桌子上有一张5元,一张10元,一张20元的纸币,任意取两张纸币,可以组成()种不同的币值.",
+        "options":  [
+
+                    ],
+        "answer":  "3",
+        "solution":  "【分析】任意取两张去组合时,可以用5元和10元组合;5元和20元组合;10元和20元组合,有3种组合方式.\n【详解】5+10=15(元);5+20=25(元);10+20=30(元),任意取两张纸币,可以组成3种不同的币值.",
+        "knowledge_points":  [
+                                 "搭配问题",
+                                 "不进位加法(20以内)",
+                                 "整十数加减一位数",
+                                 "整十数之间的加减法"
+                             ],
+        "source":  "22-23二年级上·浙江杭州·期末"
+    },
+    {
+        "id":  "332",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "从0,6,8三个数中选取两个组成两位数,组成的两位数中最大的是().",
+        "options":  [
+
+                    ],
+        "answer":  "86",
+        "solution":  "【分析】先列举出用0,6,8三个数组成的所有的两位数,然后把这些数比较大小,找出最大数,即可解决.\n【详解】用0,6,8三个数组成的两位数有:60,80,68,86;60\u003c68\u003c80\u003c86.故,从0,6,8三个数中选取两个组成两位数,组成的两位数中最大的是86.",
+        "knowledge_points":  [
+                                 "搭配问题",
+                                 "100以内数的比大小",
+                                 "100以内数的组成"
+                             ],
+        "source":  "22-23二年级上·福建龙岩·期末"
+    },
+    {
+        "id":  "333",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "用6,8,9任意选取2个数求和,得数有()种可能.",
+        "options":  [
+
+                    ],
+        "answer":  "3",
+        "solution":  "【分析】从三个数中任意取出两个数求和出现的可能性有:如果选出的数字是6和8,和是14;如果是6和9,和是15;如果是8和9,和是17.所以得数一共有3种可能.\n【详解】6+8=14;6+9=15;8+9=17,用6,8,9任意选取2个数求和,得数有3种可能.",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "22-23二年级上·湖北随州·期末"
+    },
+    {
+        "id":  "334",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "用2,0和6能组成()个不同的两位数.",
+        "options":  [
+
+                    ],
+        "answer":  "4",
+        "solution":  "【分析】用2,0和6这三个数字组成不同的两位数,我们可以先确定十位上的数,再确定个位上的数,注意0不能在首位.当2在首位时,组成的两位数有20,26;当6在首位时,组成的两位数有60,62;所以一共可以组成4个不同的两位数.\n【详解】用2,0和6这三个数字组成的两位数分别是20,26,60,62,所以能组成4个不同的两位数.",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "22-23二年级上·贵州铜仁·期末"
+    },
+    {
+        "id":  "335",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "用4,7,3三张数字卡片可以组成()个十位数字和个位数字不同的两位数,分别是().",
+        "options":  [
+
+                    ],
+        "answer":  "6;47,43,74,73,34,37",
+        "solution":  "【分析】可以用列举的方法来解决.把4,7,3三张数字卡片组成不同的两位数一一列举出来,然后数一数;据此解决.\n【详解】由题意分析得:用4,7,3三张数字卡片组成不同的两位数有:47,43,74,73,34,37;即,用4,7,3三张数字卡片可以组成6个十位数字和个位数字不同的两位数,分别是47,43,74,73,34,37.",
+        "knowledge_points":  [
+                                 "搭配问题",
+                                 "100以内数的组成"
+                             ],
+        "source":  "22-23二年级上·河南焦作·期末"
+    },
+    {
+        "id":  "336",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "从3,6,9这3个数中,任意选取其中2个数求积,得数有()种可能,其中最大积为().",
+        "options":  [
+
+                    ],
+        "answer":  "3;54",
+        "solution":  "【分析】通过列举,先写出所有的乘法算式(从3,6,9这3个数中,任意选取其中2个数),再结合乘法口诀,求出积,然后比较大小,即可解决此题.\n【详解】3×6=18;6×9=54;3×9=27;54\u003e27\u003e18,故,从3,6,9这3个数中,任意选取其中2个数求积,得数有3种可能,其中最大积为54.",
+        "knowledge_points":  [
+                                 "搭配问题",
+                                 "100以内数的比大小",
+                                 "6的乘法口诀及应用",
+                                 "9的乘法口诀及应用"
+                             ],
+        "source":  "22-23二年级上·四川乐山·期末"
+    },
+    {
+        "id":  "337",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "用5,3,2能组成()个没有重复的数字的两位数,其中最大的是(),最小的数是().",
+        "options":  [
+
+                    ],
+        "answer":  "6;53;23",
+        "solution":  "【分析】用5,3,2组成两位数时,用其中一个数作为十位,另外两个数分别作为个位,组成的数有53;52;35;32;25;23.比较大小时,都是两位数,从十位比起,十位数字大的数就大,十位相同,比较个位,个位大的数就大,由此解答.\n【详解】53\u003e52\u003e35\u003e32\u003e25\u003e23,用5,3,2能组成6个没有重复的数字的两位数,其中最大的是53,最小的数是23.",
+        "knowledge_points":  [
+                                 "搭配问题",
+                                 "100以内数的比大小"
+                             ],
+        "source":  "22-23二年级上·山东临沂·期末"
+    },
+    {
+        "id":  "338",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "有三个数字3,4,9可以组成()个两位数.",
+        "options":  [
+
+                    ],
+        "answer":  "6",
+        "solution":  "【分析】用3,4,9组成的两位数,可以用其中一个数作为十位,另外两个数分别作为个位,组成的数有:34,39,43,49,93,94,由此解答.\n【详解】有三个数字3,4,9可以组成6个两位数.",
+        "knowledge_points":  [
+                                 "搭配问题",
+                                 "100以内数的组成"
+                             ],
+        "source":  "20-21二年级上·黑龙江鹤岗·期末"
+    },
+    {
+        "id":  "339",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "小刚有三条裤子,三件上衣,他有()种穿法.",
+        "options":  [
+
+                    ],
+        "answer":  "9",
+        "solution":  "【分析】1件上衣可以和3条裤子搭配,有3种搭配方法;那么3件上衣搭配3条裤子就有(3×3)种不同的搭配方法;据此解答即可.\n【详解】3×3=9(种),小刚有三条裤子,三件上衣,他有9种穿法.",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "22-23二年级上·湖南张家界·期末"
+    },
+    {
+        "id":  "340",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "中国最小的铁路只有4站,分别是临山,双龙桥,乡会桥,团山.从临山开往团山方向,需要准备()种不同的单程车票.",
+        "options":  [
+
+                    ],
+        "answer":  "6",
+        "solution":  "【分析】分别列举出每种情况即可求解.\n【详解】需要准备的单程票:临山→双龙桥,临山→乡会桥,临山→团山,双龙桥→乡会桥,双龙桥→团山,乡会桥→团山,共6种.需要准备6种不同的单程车票.",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "22-23二年级上·河南南阳·期末"
+    },
+    {
+        "id":  "341",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "用3,5,8可以组成()个两位数,最大的是(),最小的是().",
+        "options":  [
+
+                    ],
+        "answer":  "6;85;35",
+        "solution":  "【分析】用3,5,8组成的两位数,可以用其中一个数作为十位,另外两个数分别做个位,组成的数有:35,38,53,58,83,85共6个;比较它们的大小时,都是两位数,就从最高位比起,最高位大的数就大;最高位相同比较下一位,直到比较出结果.\n【详解】用3,5,8可以组成6个两位数,最大的是85,最小的是35.",
+        "knowledge_points":  [
+                                 "搭配问题",
+                                 "100以内数的比大小",
+                                 "100以内数的组成"
+                             ],
+        "source":  "22-23二年级上·河南南阳·期末"
+    },
+    {
+        "id":  "342",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "用数字4,8,9组成两位数,最小的是().",
+        "options":  [
+
+                    ],
+        "answer":  "48",
+        "solution":  "【分析】把4放在十位上,组成的数字有48和49;把8放在十位上,组成的数字有84和89;把9放在十位上,组成的数字有94和98,这些数字由大到小的排列顺序是:98\u003e94\u003e89\u003e84\u003e49\u003e48,最小的数是48.\n【详解】用数字4,8,9组成两位数,最小的是48.",
+        "knowledge_points":  [
+                                 "搭配问题",
+                                 "100以内数的比大小"
+                             ],
+        "source":  "22-23二年级上·全国·随堂练习"
+    },
+    {
+        "id":  "343",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "用数字2,4,7能组成()个两位数.",
+        "options":  [
+
+                    ],
+        "answer":  "6",
+        "solution":  "【分析】可以把2放在十位上,组成的数字有24和27;把4放在十位上,组成的数字有42和47;把7放在十位上,组成的数字有72和74,这样用数字2,4,7能组成6个两位数.\n【详解】用数字2,4,7能组成6个两位数.",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "22-23二年级上·全国·随堂练习"
+    },
+    {
+        "id":  "344",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "从2,7,0三个数中任意选取其中2个求和,得数有()种可能.",
+        "options":  [
+
+                    ],
+        "answer":  "3",
+        "solution":  "【分析】可以选取2和7,7和0,2和0,分别求和.\n【详解】2+7=9;7+0=7;2+0=2;从2,7,0三个数中任意选取其中2个求和,得数有3种可能.",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "22-23二年级上·全国·随堂练习"
+    },
+    {
+        "id":  "345",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "从6,3,8三个数中任意选取其中2个求和,得数有()种可能.",
+        "options":  [
+
+                    ],
+        "answer":  "3",
+        "solution":  "【分析】可以选取6和3,3和8,6和8,分别求和.\n【详解】6+3=9;3+8=11;6+8=14,从6,3,8三个数中任意选取其中2个求和,得数有3种可能.",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "22-23二年级上·全国·随堂练习"
+    },
+    {
+        "id":  "346",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "小巧所在的小组进行比赛,共有10人,每2人进行一场,小巧所在的小组一共要进行()场比赛.",
+        "options":  [
+
+                    ],
+        "answer":  "45",
+        "solution":  "【分析】每人要和另外9人赛一场,一共10×9=90(场),又因为两人之间只赛一场,去掉重复计算,实际只赛90/2场.\n【详解】10×9=90(场),90/2=45(场),因此一共要进行45场比赛.",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "22-23二年级上·全国·课后作业"
+    },
+    {
+        "id":  "347",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "小明要买一支圆珠笔和一个笔记本,现有两种圆珠笔,三种笔记本可供选择,小明一共有()种买法.",
+        "options":  [
+
+                    ],
+        "answer":  "6",
+        "solution":  "【分析】一支圆珠笔配一个笔记本,现有三种笔记本,所以一支圆珠笔有3种不同的搭配,又因为有两种圆珠笔,根据乘法原理可得2×3种买法.\n【详解】2×3=6(种),因此小明一共有6种买法.",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "22-23二年级上·全国·课后作业"
+    },
+    {
+        "id":  "348",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "从《童话故事》,《神话故事》,《寓言故事》和《成语故事》四本书中任选两本,一共有()种不同的选择方案.",
+        "options":  [
+
+                    ],
+        "answer":  "6",
+        "solution":  "【分析】列举所有两两组合:《童话故事》+《神话故事》,《童话故事》+《寓言故事》,《童话故事》+《成语故事》,《神话故事》+《寓言故事》,《神话故事》+《成语故事》,《寓言故事》+《成语故事》.\n【详解】一共有6种不同的选择方案.",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "22-23二年级上·全国·课后作业"
+    },
+    {
+        "id":  "349",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "从小芳(女),小兰(女),小东(男),小强(男)四个人中,选2人参加乒乓球男女混合双打比赛,一共有()种选法.",
+        "options":  [
+
+                    ],
+        "answer":  "4",
+        "solution":  "【分析】男女混合,需要一男一女,组合为:小芳+小东,小芳+小强,小兰+小东,小兰+小强,共4种.\n【详解】从四人中选2人参加乒乓球男女混合双打比赛,一共有4种选法.",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "23-24二年级上·全国·课后作业"
+    },
+    {
+        "id":  "350",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "口袋里有0,4,5,6四张数字卡片,从中任意摸出两张来组成两位数,组成的两位数有()种可能.",
+        "options":  [
+
+                    ],
+        "answer":  "9",
+        "solution":  "【分析】列举所有两位数,注意0不能在十位:40,50,60,45,46,56,54,64,65,共9个.\n【详解】口袋里有0,4,5,6四张数字卡片,从中任意摸出两张来组成两位数,组成的两位数有9种可能.",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "23-24二年级上·全国·课后作业"
+    },
+    {
+        "id":  "351",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "从面包和饮料中各选一种作为早餐,一共有()种选法.\n\n![](images/2026-03-03%20091528.jpg)",
+        "options":  [
+
+                    ],
+        "answer":  "9",
+        "solution":  "【分析】共有3种面包和3种饮料,每种面包可搭配3种饮料,根据乘法原理3×3种选法.\n【详解】从面包和饮料中各选一种作为早餐,一共有9种选法.",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "23-24二年级上·全国·课后作业"
+    },
+    {
+        "id":  "352",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "如图,小兔子回家有()种不同的走法,它最少需要花()分钟到家.\n\n![](images/510c653e2df24c7aadfa18703686ea982a015a929d331b84cd3136843a0bef01.jpg)",
+        "options":  [
+
+                    ],
+        "answer":  "6;9",
+        "solution":  "【分析】小兔先有3种选法,再有2种选法,根据搭配原理3×2种走法;最短路线两段时间相加即可.\n【详解】3×2=6(种),5+4=9(分钟),小兔子回家有6种不同的走法,它最少需要花9分钟到家.",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "22-23二年级上·湖北黄石·期末"
+    },
+    {
+        "id":  "353",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "从3,5,8这3个数中,任意选2个求和,结果有()种可能.",
+        "options":  [
+
+                    ],
+        "answer":  "3",
+        "solution":  "【分析】可能的和有:3+8,3+5,5+8.\n【详解】3+8=11,3+5=8,5+8=13,因此结果有3种可能.",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "22-23二年级上·河南南阳·期末"
+    },
+    {
+        "id":  "354",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "用3,6,9组成两位数,每个两位数的十位数字和个位数字不能一样,能组成()个两位数.",
+        "options":  [
+
+                    ],
+        "answer":  "6",
+        "solution":  "【分析】利用枚举法:十位为3时有36,39;十位为6时有63,69;十位为9时有93,96,共6个.\n【详解】用3,6,9组成两位数,每个两位数的十位数字和个位数字不能一样,能组成36,39,63,69,93,96,共6个两位数.",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "21-22二年级上·山东济宁·期末"
+    },
+    {
+        "id":  "355",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "小明,小红,小亮坐成一排合影,有()种坐法.",
+        "options":  [
+
+                    ],
+        "answer":  "6",
+        "solution":  "【分析】列举排列:小明小红小亮,小明小亮小红,小红小明小亮,小红小亮小明,小亮小明小红,小亮小红小明,共6种.\n【详解】小明,小红,小亮坐成一排合影,有6种坐法.",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "20-21二年级上·湖南岳阳·期末"
+    },
+    {
+        "id":  "356",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "有3个数7,1,4,任意选取其中2个求和,得数有()种可能.",
+        "options":  [
+
+                    ],
+        "answer":  "3",
+        "solution":  "【分析】可能的组合:7和1,7和4,1和4,共3种.\n【详解】有3个数7,1,4,任意选取2个求和,得数有3种可能.",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "20-21二年级上·湖南岳阳·期末"
+    },
+    {
+        "id":  "357",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "聪聪有3件不同的衬衫,4条不同的裤子,她一共有()种不同的搭配方法.",
+        "options":  [
+
+                    ],
+        "answer":  "12",
+        "solution":  "【分析】从3件衬衫中选一件有3种选法,从4条裤子中选一条有4种选法,根据乘法原理3×4种搭配.\n【详解】3×4=12(种),共有12种不同的搭配方法.",
+        "knowledge_points":  [
+                                 "搭配问题",
+                                 "4的乘法口诀及应用"
+                             ],
+        "source":  "21-22二年级上·浙江绍兴·期末"
+    },
+    {
+        "id":  "358",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "用数字2,5,8可以组成()个十位数字和个位数字不同的两位数,最大的数比最小的数多().",
+        "options":  [
+
+                    ],
+        "answer":  "6;60",
+        "solution":  "【分析】十位有3种选择,个位有2种选择,共3×2=6个;最大是85,最小是25,差为60.\n【详解】可以组成6个十位数字和个位数字不同的两位数,最大的数比最小的数多60.",
+        "knowledge_points":  [
+                                 "搭配问题",
+                                 "100以内数的组成",
+                                 "两位数与两位数的不退位减法"
+                             ],
+        "source":  "20-21二年级上·山东临沂·期末"
+    },
+    {
+        "id":  "359",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "用2,3,4可以组成()个不同的两位数,其中最小的是().",
+        "options":  [
+
+                    ],
+        "answer":  "6;23",
+        "solution":  "【分析】十位是2:23,24;十位是3:32,34;十位是4:43,42,共6个,最小为23.\n【详解】用2,3,4可以组成6个不同的两位数,其中最小的是23.",
+        "knowledge_points":  [
+                                 "搭配问题",
+                                 "100以内数的比大小"
+                             ],
+        "source":  "22-23二年级上·全国·期末"
+    },
+    {
+        "id":  "360",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "有香蕉,桔子和梨三种水果,每次只能拿两种水果,有()种拿法.",
+        "options":  [
+
+                    ],
+        "answer":  "3",
+        "solution":  "【分析】列举:香蕉+桔子,香蕉+梨,桔子+梨,共3种.\n【详解】有香蕉,桔子和梨三种水果,每次只能拿两种水果,一共有3种拿法.",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "20-21二年级下·河南信阳·期末"
+    },
+    {
+        "id":  "361",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "一个两位数,十位上和个位上的数字和是4,这样的两位数有()个,其中最小的是().",
+        "options":  [
+
+                    ],
+        "answer":  "4;13",
+        "solution":  "【分析】相加等于4的有0+4,4+0,1+3,3+1,2+2,最高位不能是0,因此两位数为40,13,31,22,共4个,其中最小为13.\n【详解】这样的两位数有13,31,22,40,共4个,最小的是13.",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "21-22一年级下·湖北随州·期末"
+    },
+    {
+        "id":  "362",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "用5,6,7三个数字可以组成()个不同的两位数,其中最大的数比最小的数多().",
+        "options":  [
+
+                    ],
+        "answer":  "6;20",
+        "solution":  "【分析】5,6,7各作十位可得6个两位数,最大76,最小56,差20.\n【详解】可以组成6个不同的两位数,其中最大的数比最小的数多20.",
+        "knowledge_points":  [
+                                 "排列组合问题",
+                                 "100以内数的比大小",
+                                 "两位数与两位数的不退位减法"
+                             ],
+        "source":  "21-22二年级下·贵州铜仁·期末"
+    },
+    {
+        "id":  "363",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "用4,0,6这三个数能组成()个两位数.最大与最小的差是().",
+        "options":  [
+
+                    ],
+        "answer":  "4;24",
+        "solution":  "【分析】十位只能是4或6,两位数有40,46,60,64,共4个;最大64,最小40,差24.\n【详解】能组成4个两位数,其中最大的数是64,最小的数是40,64-40=24.",
+        "knowledge_points":  [
+                                 "搭配问题",
+                                 "100以内数的比大小",
+                                 "100以内数的组成",
+                                 "两位数与整十数的减法"
+                             ],
+        "source":  "21-22二年级上·贵州黔西·期末"
+    },
+    {
+        "id":  "364",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "用3,4,8三张卡片可以组成()个不同的两位数,其中最大的数与最小的数差().",
+        "options":  [
+
+                    ],
+        "answer":  "6;50",
+        "solution":  "【分析】十位有3种选择,再排个位有2种选择,共3×2=6个不同两位数;最大84,最小34,差50.\n【详解】可以组成6个不同的两位数,其中最大的数与最小的数差50.",
+        "knowledge_points":  [
+                                 "搭配问题",
+                                 "100以内数的比大小",
+                                 "两位数与两位数的不退位减法"
+                             ],
+        "source":  "21-22二年级上·湖北孝感·期末"
+    },
+    {
+        "id":  "365",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "小明有两件不同颜色的上衣,3条不同颜色的裤子,他有()种穿法.",
+        "options":  [
+
+                    ],
+        "answer":  "6",
+        "solution":  "【分析】每件上衣可以和3条颜色不同的裤子搭配,从2件上衣选一件有2种选法,从3条裤子选一条有3种选法,根据乘法原理可得2×3种.\n【详解】2×3=6(种),可以配成6套不同服装.",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "21-22二年级上·湖北黄冈·期末"
+    },
+    {
+        "id":  "366",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "用2,0,4三张数字卡片能摆成()个不同的两位数,它们分别是().",
+        "options":  [
+
+                    ],
+        "answer":  "4;20,24,42,40",
+        "solution":  "【分析】十位不能为0,只能是2或4.十位是2有20,24;十位是4有42,40,共4个.\n【详解】一共能摆成4个不同的两位数,分别是20,24,42,40.",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "21-22二年级上·山东菏泽·期末"
+    },
+    {
+        "id":  "367",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "用2,3,4可以组成()个没有重复数字的两位数.",
+        "options":  [
+
+                    ],
+        "answer":  "6",
+        "solution":  "【分析】十位有3种选择,个位有2种选择(去掉十位用过的数字),一共3×2=6个.\n【详解】所有可能的两位数为:23,24,32,34,42,43,共6个.故答案为6.",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "19-20二年级上·广东肇庆·期末"
+    },
+    {
+        "id":  "368",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "你能用0,3,6这三个数字组成()个不同的两位数,其中最大的数是(),最小的数是().",
+        "options":  [
+
+                    ],
+        "answer":  "4;63;30",
+        "solution":  "【分析】十位不能为0,只能是3或6.十位是3时有30,36;十位是6时有60,63,共4个,其中最大63,最小30.\n【详解】一共能组成4个不同的两位数,最大的数是63,最小的数是30.",
+        "knowledge_points":  [
+                                 "搭配问题",
+                                 "100以内数的比大小"
+                             ],
+        "source":  "21-22二年级上·河南漯河·期末"
+    },
+    {
+        "id":  "369",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "用0,3,5这三张数字卡片可以组成()个不同的两位数,其中最大的两位数是().",
+        "options":  [
+
+                    ],
+        "answer":  "4;53",
+        "solution":  "【分析】用0,3,5组成两位数时,0不能在十位,用3和5分别作十位,剩余两个数分别作个位.据此求出组成的两位数并比较大小.\n【详解】组成的两位数有:30,35,50,53,一共组成4个不同的两位数;30\u003c35\u003c50\u003c53,最大的是53.",
+        "knowledge_points":  [
+                                 "搭配问题",
+                                 "100以内数的比大小"
+                             ],
+        "source":  "21-22二年级上·山西吕梁·期末"
+    },
+    {
+        "id":  "370",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "从4,0,9这三个数中任意选取其中的两个数求和,得数有()种可能,其中最大的和与最小的和相差().",
+        "options":  [
+
+                    ],
+        "answer":  "3;9",
+        "solution":  "【分析】从4,0,9三个数中任意选取两个数求和,属于组合问题,与顺序无关.分别列出所有可能的两个数的组合,求出和,再找出最大和与最小和,计算它们的差.\n【详解】所有可能的组合及和:4+0=4;4+9=13;0+9=9,一共有3种不同的和.其中最大的和是13,最小的和是4,13-4=9.",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "21-22二年级上·福建莆田·期末"
+    },
+    {
+        "id":  "371",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "每两个同学通一次电话,3个同学一共通了()次电话.",
+        "options":  [
+
+                    ],
+        "answer":  "3",
+        "solution":  "【分析】每两个同学通一次电话,与顺序无关,属于两两组合问题.3个同学,每两人通一次电话,可以列举出来.\n【详解】假设三个同学分别为A,B,C,他们通电话的组合为:A和B,A和C,B和C,共3次.",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "20-21二年级上·云南玉溪·期末"
+    },
+    {
+        "id":  "372",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "用1,2,3三个数字能组成()个两位数.",
+        "options":  [
+
+                    ],
+        "answer":  "6",
+        "solution":  "【分析】用1,2,3三个数字组成没有重复数字的两位数:十位有3种选择,个位有2种选择,所以一共有3×2个两位数.\n【详解】所有可能的两位数为:12,13,21,23,31,32,共6个.",
+        "knowledge_points":  [
+                                 "排列组合问题"
+                             ],
+        "source":  "20-21二年级上·黑龙江·期末"
+    },
+    {
+        "id":  "373",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "小强,小明,小刚三人进行羽毛球比赛,每两人进行一场比赛,一共要进行()场比赛.",
+        "options":  [
+
+                    ],
+        "answer":  "3",
+        "solution":  "【分析】每两人进行一场比赛,与顺序无关,属于两两组合问题.3个人,每两人比赛一场,可以列举出来.\n【详解】小强,小明,小刚三人比赛的组合为:小强和小明,小强和小刚,小明和小刚,共3场.",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "21-22二年级上·青海西宁·期末"
+    },
+    {
+        "id":  "374",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "有3个数2,4,6,任意选取其中2个求和,得数有()种可能.",
+        "options":  [
+
+                    ],
+        "answer":  "3",
+        "solution":  "【分析】从2,4,6三个数中任意选取两个数求和,属于组合问题,与顺序无关.分别列出所有可能的两个数的组合,求出和即可.\n【详解】所有可能的组合及和:2+4=6;2+6=8;4+6=10,一共有3种不同的和.",
+        "knowledge_points":  [
+                                 "搭配问题",
+                                 "加法表(10以内)"
+                             ],
+        "source":  "20-21二年级上·云南楚雄·期末"
+    },
+    {
+        "id":  "375",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "用2,0和5组成两位数,每个两位数的十位数字和个位数字不能一样,能组成()个两位数,其中最大的两位数是(),最小的两位数是(),它们相差().",
+        "options":  [
+
+                    ],
+        "answer":  "4;52;20;32",
+        "solution":  "【分析】用2,0,5组成两位数,十位上不能为0,所以十位只能是2或5.分别列举出所有可能的两位数,再找出最大和最小,求差即可.\n【详解】十位是2的两位数有:20,25;十位是5的两位数有:50,52;一共能组成4个不同的两位数.其中最大的数是52,最小的数是20,52-20=32.",
+        "knowledge_points":  [
+                                 "搭配问题",
+                                 "100以内数的比大小",
+                                 "100以内数的组成",
+                                 "两位数与两位数的不退位减法"
+                             ],
+        "source":  "20-21二年级上·贵州安顺·期末"
+    },
+    {
+        "id":  "376",
+        "unit":  "搭配",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "有3个数5,2,7,任意选取其中两个求和,得数有6种可能.()",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】用5,2,7任意选取其中两个求和时,可用5+2,5+7,2+7求和,得数共有3种可能,不是6种.\n【详解】5+2=7;5+7=12;2+7=9,得数有3种可能.原题说法错误.故答案为: ×",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "19-20二年级上·天津·期末"
+    },
+    {
+        "id":  "377",
+        "unit":  "搭配",
+        "question_type":  "判断题",
+        "difficulty":  0.65,
+        "question":  "四个班进行拔河比赛,每两个班要比一场,一共要比6场.()",
+        "options":  [
+
+                    ],
+        "answer":  "√",
+        "solution":  "【分析】每个班要与另外3个班各比赛一场,一共有4×3=12(场),但每两班之间只比赛一场,去掉重复,实际比赛场数为12/2=6.\n【详解】4×3/2=12/2=6(场),原题说法正确.故答案为:√",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "22-23二年级上·浙江杭州·期末"
+    },
+    {
+        "id":  "378",
+        "unit":  "搭配",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "用1,5,0三个数字能组成6个不同的两位数.()",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】用1,5,0组成两位数时,十位不能为0,只能是1或5.两位数有10,15,50,51,一共4个,不是6个.\n【详解】用1,5,0三个数字能组成4个不同的两位数.原题说法错误.故答案为: ×",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "22-23二年级上·广东佛山·期末"
+    },
+    {
+        "id":  "379",
+        "unit":  "搭配",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "3个小朋友互相通一次电话,一共要通3次电话.()",
+        "options":  [
+
+                    ],
+        "answer":  "√",
+        "solution":  "【分析】第1个小朋友要和第2个,第3个小朋友通电话,共2次;第2个小朋友要和第3个小朋友通电话,共1次,总共3次.\n【详解】3个小朋友互相通一次电话,一共要通3次电话.原题说法正确.故答案为:√",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "22-23二年级上·贵州铜仁·期末"
+    },
+    {
+        "id":  "380",
+        "unit":  "搭配",
+        "question_type":  "判断题",
+        "difficulty":  0.65,
+        "question":  "由2,3,7三张数字卡片中任意两张组成的最大数是73.()",
+        "options":  [
+
+                    ],
+        "answer":  "√",
+        "solution":  "【分析】任意两张组成两位数,要得到最大数,十位应为7,个位为3,组成73.\n【详解】由2,3,7三张数字卡片中任意两张组成的最大数是73.原题说法正确.故答案为:√",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "22-23二年级上·全国·课后作业"
+    },
+    {
+        "id":  "381",
+        "unit":  "搭配",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "小乐的姐姐要参加朋友的生日派对,她挑中了3件上衣,2条短裙,这样,她就有5种搭配.()",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】3件上衣,2条短裙,一件上衣配一条短裙,有2×3种搭配,即6种,不是5种.\n【详解】3×2=6(种),小乐的姐姐一共有6种搭配.原题说法错误.故答案为: ×",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "22-23二年级上·全国·课后作业"
+    },
+    {
+        "id":  "382",
+        "unit":  "搭配",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "从1,2,3,4这四张数卡中依次抽出两张,拼成两位整数,一共能拼出6个不同的单数.()",
+        "options":  [
+
+                    ],
+        "answer":  "√",
+        "solution":  "【分析】从1,2,3,4中依次抽出两张,拼成两位整数,个位必须为奇数1或3.可以拼成的单数有:13,23,43,21,31,41,共6个.\n【详解】从1,2,3,4这四张数卡中依次抽出两张,拼成两位整数,共能拼出6个不同的单数.故答案为:√",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "22-23二年级上·全国·课后作业"
+    },
+    {
+        "id":  "383",
+        "unit":  "搭配",
+        "question_type":  "判断题",
+        "difficulty":  0.65,
+        "question":  "甲乙丙三个进入象棋比赛决赛,他们三人的名次排列有6种可能.()",
+        "options":  [
+
+                    ],
+        "answer":  "√",
+        "solution":  "【分析】先排第一名有3种排法,第二名有2种排法,第三名有1种排法,共3×2×1=6种.\n【详解】甲,乙,丙的排列共有6种,原题说法正确.故答案为:√",
+        "knowledge_points":  [
+                                 "搭配问题",
+                                 "3的乘法口诀及应用"
+                             ],
+        "source":  "22-23二年级上·全国·课后作业"
+    },
+    {
+        "id":  "384",
+        "unit":  "搭配",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "如图,从A地经B地到C地有5种走法.()\n\n![](images/5d51448f5319800f413b409bed5ba87e8ef9dd8c18b7ff2d11d0a8581c409a73.jpg)",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】从A地到B地有3种选择,从B地到C地有2种选择,根据乘法原理3×2种走法,应为6种,而不是5种.\n【详解】3×2=6(种),从A地经B地到C地有6种走法.原题说法错误.故答案为: ×",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "23-24二年级上·全国·课后作业"
+    },
+    {
+        "id":  "385",
+        "unit":  "搭配",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "车站有客车和货车共6辆,客车和货车的辆数可能有5种情况.()",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】客车和货车辆数之和为6,可能的搭配有:0+6,1+5,2+4,3+3,4+2,5+1,6+0,共7种,不是5种.\n【详解】车站有客车和货车共6辆,客车和货车的辆数可能有7种情况.原题说法错误.故答案为: ×",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "23-24二年级上·全国·课后作业"
+    },
+    {
+        "id":  "386",
+        "unit":  "搭配",
+        "question_type":  "判断题",
+        "difficulty":  0.65,
+        "question":  "小刚,小贝和小乐坐成一排合影,一共有6种坐法.()",
+        "options":  [
+
+                    ],
+        "answer":  "√",
+        "solution":  "【分析】三人排成一排,有3×2×1=6种不同的坐法.\n【详解】列举所有排法可知共有6种坐法.原题说法正确.故答案为:√",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "22-23二年级上·河南郑州·期末"
+    },
+    {
+        "id":  "387",
+        "unit":  "搭配",
+        "question_type":  "判断题",
+        "difficulty":  0.65,
+        "question":  "用5,6,0这三个数可以组成6个不同的两位数.()",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】0不能在十位.先排个位是0的,有50,60;再排个位是6和5的,有56,65,共4种,而不是6种.\n【详解】用5,6,0这三个数可以组成两位数有:50,60,56,65,共4个.原题说法错误.故答案为: ×",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "20-21二年级上·江西赣州·期末"
+    },
+    {
+        "id":  "388",
+        "unit":  "搭配",
+        "question_type":  "判断题",
+        "difficulty":  0.65,
+        "question":  "有三个小朋友,每两个小朋友相互握手一次,一共要握3次.()",
+        "options":  [
+
+                    ],
+        "answer":  "√",
+        "solution":  "【分析】3个小朋友,每个小朋友需要和另外两个小朋友握手,用3×2/2除去重复,得到总次数.\n【详解】3×2/2=6/2=3(次),所以一共要握手3次.原题说法正确.故答案为:√",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "20-21二年级上·黑龙江·期末"
+    },
+    {
+        "id":  "389",
+        "unit":  "搭配",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "毛毛有5元和2元面值的人民币各5张.如果要买一本20元的字典,有几种恰好付20元的方式?",
+        "options":  [
+
+                    ],
+        "answer":  "2种",
+        "solution":  "【分析】只有5元和2元两种面额,可以只用5元,也可以5元和2元搭配.用列表的方法把不同的付款方式一一列举出来.\n【详解】付款方式如下表:①5元4张,2元0张,共20元;②5元2张,2元5张,共20元.答:一共有2种恰好付20元的方式.",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "19-20三年级上·湖南常德·期中"
+    },
+    {
+        "id":  "390",
+        "unit":  "搭配",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "每两个人打一次电话,3个人一共要打几次电话?",
+        "options":  [
+
+                    ],
+        "answer":  "3次",
+        "solution":  "【分析】假设三人分别为甲,乙,丙,甲和乙打一次电话,甲和丙打一次电话,乙和丙打一次电话,共3次.\n【详解】3个人一共要打3次电话.",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "22-23二年级上·全国·随堂练习"
+    },
+    {
+        "id":  "391",
+        "unit":  "搭配",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "如果用0,2,3三个数字,能组成几个两位数?",
+        "options":  [
+
+                    ],
+        "answer":  "4个",
+        "solution":  "【分析】3个数字中0不能放在十位.把2放在十位,组成20,23;把3放在十位,组成30,32,一共4个.\n【详解】答:能组成4个两位数.",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "22-23二年级上·全国·随堂练习"
+    },
+    {
+        "id":  "392",
+        "unit":  "搭配",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "学校举行乒乓球比赛.A,B两个小组各有16人,每组两人一对进行比赛,负者被淘汰,胜者进入下一轮,最后两组第一名进行决赛.两个小组一共要进行多少场比赛?",
+        "options":  [
+
+                    ],
+        "answer":  "31场",
+        "solution":  "【分析】每轮比赛场次等于参赛人数/2.第一轮16人每组共16场;之后依次人数减半直至1人,累加各轮场次.\n【详解】第一轮:16/2=8(场),两组共16场;第二轮:16/2=8(场);第三轮:8/2=4(场);第四轮:4/2=2(场);第五轮:2/2=1(场);16+8+4+2+1=31(场),答:两个小组一共要进行31场比赛.",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "23-24三年级上·全国·随堂练习"
+    },
+    {
+        "id":  "393",
+        "unit":  "搭配",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "幼儿园阿姨拿着苹果,桃子和梨3个水果分给小东和小华,每人分一个,一共有几种不同的分法?",
+        "options":  [
+
+                    ],
+        "answer":  "6种",
+        "solution":  "【分析】小东从3个水果中选一种有3种选法;小华从剩下的2个水果中选一种有2种选法,根据乘法原理共有3×2种分法.\n【详解】3×2=6(种),答:一共有6种不同的分法.",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "22-23二年级上·全国·课后作业"
+    },
+    {
+        "id":  "394",
+        "unit":  "搭配",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "小丽有4件不同的外套和4个不同颜色的包,一件外套搭配一个颜色的包,有多少种不同的搭配方法?",
+        "options":  [
+
+                    ],
+        "answer":  "16种",
+        "solution":  "【分析】一件外套可以搭配4个不同颜色的包,共有4种搭配;有4件不同外套,根据乘法原理4×4种搭配.\n【详解】4×4=16(种),答:有16种不同的搭配方法.",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "22-23二年级上·全国·课后作业"
+    },
+    {
+        "id":  "395",
+        "unit":  "搭配",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "四个小朋友去划船,小船一次坐两人,一条小船一次能有多少种不同的坐法?",
+        "options":  [
+
+                    ],
+        "answer":  "6种",
+        "solution":  "【分析】把4个小朋友编号为1,2,3,4,任意两人一组的组合有:1和2,1和3,1和4,2和3,2和4,3和4,共6种.\n【详解】一条小船一次能有6种不同的坐法.",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "23-24二年级上·全国·课后作业"
+    },
+    {
+        "id":  "396",
+        "unit":  "搭配",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "甲,乙,丙三个同学排队,一共有几种不同的排法?",
+        "options":  [
+
+                    ],
+        "answer":  "6种",
+        "solution":  "【分析】先排第一个有3种排法,第二个有2种排法,第三个有1种排法,3×2×1种排法.\n【详解】甲,乙,丙的排列有6种,答:一共有6种不同的排法.",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "23-24二年级上·全国·课后作业"
+    },
+    {
+        "id":  "397",
+        "unit":  "搭配",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "用0,2,8能摆成哪几个不同的两位数?",
+        "options":  [
+
+                    ],
+        "answer":  "20,28,80,82",
+        "solution":  "【分析】十位不能为0.十位为2时有20,28;十位为8时有80,82,共4个.\n【详解】能摆成4个不同的两位数,分别是20,28,80,82.",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "23-24二年级上·全国·课后作业"
+    },
+    {
+        "id":  "398",
+        "unit":  "搭配",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "买其中两样物品,有多少种不同的买法?最多需要多少钱?最少需要多少钱?\n\n![](images/72fceb64586734ec81c1d8bf3a4f87979918997bc5b868c625bceeeb5ba346a9.jpg)\n36元\n![](images/fd9e03cd707f22e15def7cf17916651b3b5f0b437454691811e9f34e230cd52e.jpg)\n48元\n![](images/767be020a52797138fbc2e21259f986a648ea6a1f722b9db1ed6ffc217702737.jpg)\n52元",
+        "options":  [
+
+                    ],
+        "answer":  "3种;100元;84元",
+        "solution":  "【分析】有三种不同的买法:轮船与飞机,飞机与蛋糕,轮船与蛋糕,分别用加法求得所花费用,再比较大小即可.\n【详解】买法:轮船与飞机,飞机与蛋糕,轮船与蛋糕共3种;36+48=84(元),48+52=100(元),36+52=88(元),100\u003e88\u003e84.答:有3种不同的买法,最多需要100元,最少需要84元.",
+        "knowledge_points":  [
+                                 "搭配问题",
+                                 "两位数与两位数的不进位加法",
+                                 "两位数与两位数的进位加法"
+                             ],
+        "source":  "22-23二年级上·全国·单元测试"
+    },
+    {
+        "id":  "399",
+        "unit":  "搭配",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "爸爸,妈妈和我一家三口坐成一排拍合影,一共有多少种不同的坐法?",
+        "options":  [
+
+                    ],
+        "answer":  "6种",
+        "solution":  "【分析】3个人排成一排,有3×2×1=6种坐法,可以用列表法列出所有情况.\n【详解】坐法共有6种,答:一共有6种不同的坐法.",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "22-23二年级上·全国·课后作业"
+    },
+    {
+        "id":  "400",
+        "unit":  "搭配",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "用6,0,7能摆成几个不同的两位数?",
+        "options":  [
+
+                    ],
+        "answer":  "4个",
+        "solution":  "【分析】当十位是6时,能摆成60,67;当十位是7时,能摆成76,70,共4个不同的两位数.\n【详解】2+2=4(个),答:能摆成4个不同的两位数.",
+        "knowledge_points":  [
+                                 "搭配问题",
+                                 "100以内数的组成"
+                             ],
+        "source":  "22-23二年级上·全国·课后作业"
+    },
+    {
+        "id":  "401",
+        "unit":  "搭配",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "由2,3,4三个数可以组成()个两位数.",
+        "options":  [
+                        "A. 3",
+                        "B. 6",
+                        "C. 4"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】第一步先确定十位上的数字,因为有2,3,4这三个数字可供选择,所以十位上有3种选择方法;第二步,当十位上的数字确定后,个位上还剩下另外两个数字可以选择,也就是有2种选择方法.根据排列组合的乘法原理,将十位上的选择方法数与个位上的选择方法数相乘,就能得出总共可以组成的两位数的个数.\n【详解】十位上是2时,个位可以是3或4,组成的数为23,24;十位上是3时,个位可以是2或4,组成的数为32,34;十位上是4时,个位可以是2或3,组成的数为42,43.总共组成的两位数个数为:3×2=6(个),故答案为:B",
+        "knowledge_points":  [
+                                 "搭配问题",
+                                 "100以内数的组成"
+                             ],
+        "source":  "21-22二年级上·贵州黔南·期末"
+    },
+    {
+        "id":  "402",
+        "unit":  "搭配",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "用(2,7,0)可以组成()个两位数.",
+        "options":  [
+                        "A. 3",
+                        "B. 4",
+                        "C. 5"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】十位上不能是0,如果十位上是7,则两位数可以是70,72;如果十位上是2,则两位数可以是20,27.本题可一一列举出所有可能,要做到不重复,不遗漏.\n【详解】用这些牌可以组成70,72,20,27,一共4个两位数.故答案为:B",
+        "knowledge_points":  [
+                                 "搭配问题",
+                                 "100以内数的组成"
+                             ],
+        "source":  "20-21二年级上·贵州六盘水·期末"
+    },
+    {
+        "id":  "403",
+        "unit":  "搭配",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "三个同学下棋,每两人下一盘,一共要下()盘.",
+        "options":  [
+                        "A. 1",
+                        "B. 2",
+                        "C. 3",
+                        "D. 4"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】三个同学下棋,每两人下一盘,可以列举为:第一个同学和第二个同学,第二个同学和第三个同学,第一个同学和第三个同学,共3盘.\n【详解】三个同学下棋,每两人下一盘,一共要下3盘.故答案为:C",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "20-21二年级上·贵州铜仁·期末"
+    },
+    {
+        "id":  "404",
+        "unit":  "搭配",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "3个好朋友见面,每2人握手1次,一共要握手()次.",
+        "options":  [
+                        "A. 2",
+                        "B. 3",
+                        "C. 6"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】本题考查简单的组合问题.每两人握手一次,与顺序无关.3个人,每两人握手一次,可以列举出来.\n【详解】假设3个好朋友分别为A,B,C,他们握手的组合为:A和B,A和C,B和C,共3次.故答案为:B",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "21-22二年级上·广西河池·期末"
+    },
+    {
+        "id":  "405",
+        "unit":  "搭配",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "用2,6,0三个数字组成个位数字和十位数字不同的两位数有()个.",
+        "options":  [
+                        "A. 2",
+                        "B. 4",
+                        "C. 6"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】所组成的两位数最高位不能为0,列举出所有组成的两位数,即可解答.\n【详解】2,6,0三个数字组成个位数字和十位数字不同的两位数有:26,20,62,60,有4个.故答案为:B",
+        "knowledge_points":  [
+                                 "搭配问题",
+                                 "100以内数的组成"
+                             ],
+        "source":  "15-16二年级上·全国·课后作业"
+    },
+    {
+        "id":  "406",
+        "unit":  "搭配",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "用0,1,2这三个数可以组成()个不同的两位数.",
+        "options":  [
+                        "A. 4",
+                        "B. 6",
+                        "C. 2"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】用0,1,2组成两位数,十位可以是1或2(不能是0).\n【详解】十位是1的两位数有:10,12;十位是2的两位数有:20,21;一共能组成4个不同的两位数.故答案为:A.",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "20-21二年级上·广西南宁·期末"
+    },
+    {
+        "id":  "407",
+        "unit":  "搭配",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "用2,5和6组成两位数,每个两位数的十位数字和个位数字不能一样,能组成()个两位数.",
+        "options":  [
+                        "A. 2",
+                        "B. 4",
+                        "C. 6"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】用2,5,6三个数字组成两位数,要求十位和个位数字不能一样,且都不为0.十位有3种选择,个位有2种选择,所以一共有3×2个不同的两位数.\n【详解】所有可能的两位数为:25,26,52,56,62,65,共6个.故答案为:C",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "20-21二年级上·湖北襄阳·期末"
+    },
+    {
+        "id":  "408",
+        "unit":  "搭配",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "用3,0,8能组成()个不同的两位数.",
+        "options":  [
+                        "A. 4",
+                        "B. 6",
+                        "C. 12"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】用3,0,8三个数字组成两位数,要求十位和个位数字不能重复,且十位上不能为0.十位只能是3或8.\n【详解】十位是3的两位数有:30,38;十位是8的两位数有:80,83;一共能组成4个不同的两位数.故答案为:A",
+        "knowledge_points":  [
+                                 "搭配问题",
+                                 "100以内数的组成"
+                             ],
+        "source":  "21-22二年级上·江西鹰潭·期末"
+    },
+    {
+        "id":  "409",
+        "unit":  "搭配",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "有四个同学排队,小刚固定站在第一位,有()种排法.",
+        "options":  [
+                        "A. 8",
+                        "B. 7",
+                        "C. 6",
+                        "D. 4"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】小刚固定在第一位,剩下3个同学在后面三个位置全排列,有3×2×1种排法.\n【详解】3×2×1=6(种),故答案为:C",
+        "knowledge_points":  [
+                                 "排列组合问题"
+                             ],
+        "source":  "21-22二年级上·内蒙古乌兰察布·期末"
+    },
+    {
+        "id":  "410",
+        "unit":  "搭配",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "有3个数5,8,10,任意选取其中两个求和,得数有()种可能.",
+        "options":  [
+                        "A. 3",
+                        "B. 4",
+                        "C. 6"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】算式可能有:5+8,5+10,8+10.\n【详解】5+8=13,5+10=15,8+10=18,得数有3种可能.故答案为:A",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "18-19二年级上·全国·期末"
+    },
+    {
+        "id":  "411",
+        "unit":  "搭配",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "联欢会上,每两个小朋友合唱一首歌,3个小朋友一共唱了()首歌.",
+        "options":  [
+                        "A. 1",
+                        "B. 3",
+                        "C. 6"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】每两个小朋友合唱一首歌,与顺序无关.3个小朋友,每两人合唱一首歌,有3种选法.\n【详解】假设3个小朋友分别为A,B,C,他们合唱的组合为:A和B,A和C,B和C,共3首歌.故答案为:B",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "20-21二年级上·内蒙古兴安盟·期末"
+    },
+    {
+        "id":  "412",
+        "unit":  "搭配",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "从3,5,6三张卡片任意抽两张求和,所得的得数一共有()结果.",
+        "options":  [
+                        "A. 3种",
+                        "B. 4种",
+                        "C. 6种"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】从3,5,6中任意抽取两张求和,分别列出所有可能的两个数的组合.\n【详解】3+5=8,3+6=9,5+6=11,一共有3种不同的和.故答案为:A",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "20-21二年级上·四川德阳·期末"
+    },
+    {
+        "id":  "413",
+        "unit":  "搭配",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "用数字卡片(0,1,2,3)可以摆出()个不同的两位数.",
+        "options":  [
+                        "A. 6",
+                        "B. 9",
+                        "C. 12"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】首位固定法:用一个非0的数在十位,其它数字轮流在个位,可组成3个不同两位数,有3个非0数,所以3×3个两位数.\n【详解】可摆出的两位数有:32,31,30,23,21,20,13,12,10,一共有9个两位数.故答案为:B",
+        "knowledge_points":  [
+                                 "搭配问题",
+                                 "100以内数的组成"
+                             ],
+        "source":  "20-21二年级上·四川内江·期末"
+    },
+    {
+        "id":  "414",
+        "unit":  "搭配",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "三只小动物站成一排照相,有()种站法.",
+        "options":  [
+                        "A. 1",
+                        "B. 3",
+                        "C. 6"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】用列举法,把三个小动物分别用ABC代表,则站法有ABC,ACB,BAC,BCA,CAB,CBA,共6种.\n【详解】共有6种站法.故答案为:C",
+        "knowledge_points":  [
+                                 "排列组合问题"
+                             ],
+        "source":  "20-21二年级上·四川绵阳·期末"
+    },
+    {
+        "id":  "415",
+        "unit":  "搭配",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "用7,0,8能组成()个不同的两位数(个位数字和十位数字不一样).",
+        "options":  [
+                        "A. 6",
+                        "B. 2",
+                        "C. 4"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】用7,0,8组成两位数,要求个位和十位数字不同,且十位不能为0,十位只能是7或8.\n【详解】十位是7的两位数有:70,78;十位是8的两位数有:80,87;一共能组成4个不同的两位数.故答案为:C",
+        "knowledge_points":  [
+                                 "搭配问题",
+                                 "100以内数的组成"
+                             ],
+        "source":  "21-22二年级上·四川广元·期末"
+    },
+    {
+        "id":  "416",
+        "unit":  "搭配",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "有3个数3,7,9任意选取其中2个数求和,得数有()种可能.",
+        "options":  [
+                        "A. 2",
+                        "B. 6",
+                        "C. 3"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】从3,7,9三个数中任意选取两个求和,列出所有组合即可.\n【详解】3+7=10;3+9=12;7+9=16,一共有3种不同的和.故答案为:C",
+        "knowledge_points":  [
+                                 "搭配问题",
+                                 "9加几的进位加法",
+                                 "7,6加几的进位加法"
+                             ],
+        "source":  "20-21二年级上·河南·期末"
+    },
+    {
+        "id":  "417",
+        "unit":  "搭配",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "三个人下棋比赛,每两人比赛一场,一共要比赛()场.",
+        "options":  [
+                        "A. 3",
+                        "B. 4",
+                        "C. 2"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】每两人之间进行一场比赛.甲和乙,甲和丙,乙和丙,共3种不同的组合.\n【详解】三个人下棋比赛,每两人比赛一场,一共要比赛3场.故答案为:A",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "19-20二年级上·安徽黄山·期末"
+    },
+    {
+        "id":  "418",
+        "unit":  "搭配",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "甲,乙,丙三位同学坐成一排照相,一共有()种不同的坐法.",
+        "options":  [
+                        "A. 4",
+                        "B. 6",
+                        "C. 8"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】三位同学坐成一排,是全排列问题.第一个位置3种选择,第二个2种,第三个1种,总共3×2×1种.\n【详解】可能坐法为:甲乙丙,甲丙乙,乙甲丙,乙丙甲,丙甲乙,丙乙甲,共6种.故答案为:B",
+        "knowledge_points":  [
+                                 "排列组合问题",
+                                 "搭配问题"
+                             ],
+        "source":  "21-22二年级上·内蒙古呼和浩特·期末"
+    },
+    {
+        "id":  "419",
+        "unit":  "搭配",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "用5,8,9这三个数字组成不同的两位数,每个两位数的十位数字和个位数字不能一样,组成的数中最大的两位数与最小的两位数的差是().",
+        "options":  [
+                        "A. 40",
+                        "B. 56",
+                        "C. 37"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】用5,8,9组成两位数,十位和个位不能重复.列出所有两位数,找出最大和最小,做差即可.\n【详解】可以组成的两位数有:58,59,85,89,95,98.其中最大的两位数是98,最小的是58,98-58=40.故答案为:A",
+        "knowledge_points":  [
+                                 "搭配问题",
+                                 "100以内数的比大小",
+                                 "两位数与两位数的不退位减法"
+                             ],
+        "source":  "21-22二年级上·广东汕尾·期末"
+    },
+    {
+        "id":  "420",
+        "unit":  "搭配",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "用0,1和2组成两位数,每个两位数的个位数字与十位数字不能一样,能组成()个两位数.",
+        "options":  [
+                        "A. 2",
+                        "B. 4",
+                        "C. 6"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】用0,1,2组成两位数,十位不能为0,且个位与十位不同.十位只能是1或2.\n【详解】十位是1的两位数有:10,12;十位是2的两位数有:20,21;一共能组成4个不同的两位数.故答案为:B",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "20-21二年级上·湖北咸宁·期末"
+    },
+    {
+        "id":  "421",
+        "unit":  "搭配",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "3个小朋友互相打电话问好,每两个小朋友进行一次通话,一共要进行()次通话.",
+        "options":  [
+                        "A. 3",
+                        "B. 5",
+                        "C. 6"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】每两个小朋友进行一次通话,与顺序无关.3个小朋友,每两人通话一次,有3种组合.\n【详解】假设3个小朋友分别为A,B,C,他们通话的组合为:A和B,A和C,B和C,共3次.故答案为:A",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "20-21二年级上·湖北随州·期末"
+    },
+    {
+        "id":  "422",
+        "unit":  "搭配",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "用2,6,0能摆出()个不同的两位数.",
+        "options":  [
+                        "A. 2",
+                        "B. 4",
+                        "C. 6"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】十位不能为0,因此十位只能是2或6.十位2时有20,26;十位6时有60,62,共2×2=4种.\n【详解】2×2=4(种),故答案为:B",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "19-20二年级下·贵州铜仁·期末"
+    },
+    {
+        "id":  "423",
+        "unit":  "搭配",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "有4,5,8三个数,任取2个求和,得数有()种可能.",
+        "options":  [
+                        "A. 3",
+                        "B. 4",
+                        "C. 5"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】从4,5,8三个数中任意选取两个数求和,属于组合问题,与顺序无关.\n【详解】4+5=9;4+8=12;5+8=13,一共有3种不同的和.故答案为:A",
+        "knowledge_points":  [
+                                 "搭配问题",
+                                 "8加几的进位加法"
+                             ],
+        "source":  "20-21二年级上·山西忻州·期末"
+    },
+    {
+        "id":  "424",
+        "unit":  "搭配",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "小明从10元,5元,2元,1元中拿走两张,他最多拿走()元钱.",
+        "options":  [
+                        "A. 8元",
+                        "B. 3元",
+                        "C. 15元",
+                        "D. 11元"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】先比较四种钱的面值大小,把最大两张相加就是最多能拿走的钱数.\n【详解】10\u003e5\u003e2\u003e1,10+5=15(元),他最多拿走15元.故答案为:C",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "21-22二年级上·黑龙江鹤岗·期末"
+    },
+    {
+        "id":  "425",
+        "unit":  "搭配",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "用2,3和5组成两位数,每个两位数的十位数字和个位数字不能一样,能组成()个两位数.",
+        "options":  [
+                        "A. 3",
+                        "B. 6",
+                        "C. 9"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】用2,3,5三个数字组成两位数,要求十位和个位数字不能重复.十位3种选择,个位2种选择,一共有3×2个两位数.\n【详解】所有可能的两位数为:23,25,32,35,52,53,共6个.故答案为:B",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "21-22二年级上·河南三门峡·期末"
+    },
+    {
+        "id":  "426",
+        "unit":  "搭配",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "用3,5,7可以组成()个不同的两位数.",
+        "options":  [
+                        "A. 6",
+                        "B. 8",
+                        "C. 9"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】用3,5,7组成两位数,十位3种选择,个位2种选择,一共有3×2种不同的两位数.\n【详解】所有可能的两位数为:35,37,53,57,73,75,共6个.故答案为:A",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "20-21二年级上·西藏林芝·期末"
+    },
+    {
+        "id":  "427",
+        "unit":  "搭配",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "1,3,7三个数,任意选取2个数求积,得数有()种可能.",
+        "options":  [
+                        "A. 5",
+                        "B. 4",
+                        "C. 3"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】从1,3,7中任取两个求积,列出所有组合:1×3,1×7,3×7.\n【详解】1×3=3;1×7=7;3×7=21,得数有3种可能.故答案为:C",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "20-21二年级上·广东汕尾·期末"
+    },
+    {
+        "id":  "428",
+        "unit":  "搭配",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "用5,6,9这三个数字组成不同的两位数,每个两位数的十位数字和个位数字不能一样,最大的两位数与最小的两位数的差是().",
+        "options":  [
+                        "A. 44",
+                        "B. 50",
+                        "C. 40"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】用5,6,9组成两位数,十位和个位不同.列出所有两位数,找最大和最小再做差.\n【详解】可以组成的两位数有:56,59,65,69,95,96.最大的两位数为96,最小为56,96-56=40.故答案为:C",
+        "knowledge_points":  [
+                                 "搭配问题",
+                                 "100以内数的比大小",
+                                 "两位数与两位数的不退位减法"
+                             ],
+        "source":  "19-20二年级上·广东汕尾·期末"
+    },
+    {
+        "id":  "429",
+        "unit":  "搭配",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "甲,乙,丙三人坐成一排,3人共有多少种不同的坐法?",
+        "options":  [
+                        "A. 3",
+                        "B. 4",
+                        "C. 5",
+                        "D. 6"
+                    ],
+        "answer":  "D",
+        "solution":  "【分析】甲,乙,丙三人一排,是3个元素的全排列,3×2×1=6种.\n【详解】共有6种不同的坐法,故答案为:D",
+        "knowledge_points":  [
+                                 "搭配问题",
+                                 "排列问题"
+                             ],
+        "source":  "19-20二年级上·全国·单元测试"
+    },
+    {
+        "id":  "430",
+        "unit":  "搭配",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "用4,9,5组成两位数,每个两位数的十位与个位上的数字不能一样,最大的两位数比最小的两位数大().",
+        "options":  [
+                        "A. 35",
+                        "B. 50",
+                        "C. 45"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】用4,9,5组成十位和个位不同的两位数,列举所有可能,找出最大和最小,再求差.\n【详解】可组成的两位数有:49,45,94,95,54,59,其中最大的是95,最小的是45,95-45=50.故答案为:B",
+        "knowledge_points":  [
+                                 "搭配问题",
+                                 "100以内数的比大小",
+                                 "两位数与两位数的不退位减法"
+                             ],
+        "source":  "21-22二年级上·四川南充·期末"
+    },
+    {
+        "id":  "431",
+        "unit":  "搭配",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "小明,小强,小亮3人站成一排合影,有()种不同的站法.",
+        "options":  [
+                        "A. 1",
+                        "B. 3",
+                        "C. 6"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】3个人一排,是全排列问题,3×2×1=6种.\n【详解】小明,小强,小亮3人站成一排合影,有6种不同的站法.故答案为:C",
+        "knowledge_points":  [
+                                 "搭配问题",
+                                 "排列问题"
+                             ],
+        "source":  "21-22二年级上·湖南长沙·期末"
+    },
+    {
+        "id":  "432",
+        "unit":  "搭配",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "班主任老师要从4名学生中选2人负责布置教室,有多少种不同的选择方法?",
+        "options":  [
+                        "A. 3",
+                        "B. 4",
+                        "C. 6"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】4名学生中选2人,是组合问题,可以按顺序列举,做到不重复,不遗漏.\n【详解】把4名学生分别记作甲,乙,丙,丁,可以选甲和乙,甲和丙,甲和丁,乙和丙,乙和丁,丙和丁,共6种不同的选择方法.故答案为:C",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "21-22二年级上·湖南长沙·期末"
+    },
+    {
+        "id":  "433",
+        "unit":  "搭配",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "小丽,小红,小芳,小兰4人,每两人之间要进行一场乒乓球比赛,一共要进行多少场比赛?",
+        "options":  [
+                        "A. 4",
+                        "B. 5",
+                        "C. 6"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】4人中每两人比赛一场,可以先固定一人,有3场;再固定第二人,有2场;剩下两人还有1场,一共3+2+1场.\n【详解】3+2+1=6(场),答:一共要进行6场比赛.故答案为:C",
+        "knowledge_points":  [
+                                 "搭配问题",
+                                 "比赛问题"
+                             ],
+        "source":  "21-22二年级上·湖南长沙·期末"
+    },
+    {
+        "id":  "434",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "用数字0,6,9能组成()个十位数字和个位数字不同的两位数,其中最大的数和最小的数相差().",
+        "options":  [
+
+                    ],
+        "answer":  "4;36",
+        "solution":  "【分析】用0,6,9三个数字组成两位数,要求十位和个位数字不能一样,且十位上不能为0,所以十位只能是6或9.分别列举出所有可能的两位数,再找出最大的数和最小的数,求出它们的差.\n【详解】十位是6的两位数有:60,69;十位是9的两位数有:90,96;一共能组成4个不同的两位数:60,69,90,96.其中最大的数是96,最小的数是60,96-60=36.",
+        "knowledge_points":  [
+                                 "搭配问题",
+                                 "两位数与两位数的不退位减法"
+                             ],
+        "source":  "20-21二年级上·贵州铜仁·期末"
+    },
+    {
+        "id":  "435",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "小丁和爸爸,妈妈站成一排拍照,可以有()种不同的站法.如果小丁只能站中间,可以有()种不同的站法.",
+        "options":  [
+
+                    ],
+        "answer":  "6;2",
+        "solution":  "【分析】当小丁站任意位置时,是3人全排列,有3×2×1=6种.若小丁只能站中间,左右两位只能是爸爸和妈妈互换位置,有2种站法.\n【详解】2×3=6(种),1+1=2(种),小丁和爸爸,妈妈站成一排拍照,可以有6种不同的站法.如果小丁只能站中间,可以有2种不同的站法.",
+        "knowledge_points":  [
+                                 "排列组合问题"
+                             ],
+        "source":  "20-21二年级上·广西百色·期末"
+    },
+    {
+        "id":  "436",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "用写有2,5,8数字的三张卡片,可以摆出()个不同的两位数,其中最大的数是(),最小的数是().",
+        "options":  [
+
+                    ],
+        "answer":  "6;85;25",
+        "solution":  "【分析】用2,5,8三个数字组成两位数,十位3种选择,个位2种选择,3×2=6个;比较大小找出最大和最小.\n【详解】所有可能的两位数为:25,28,52,58,82,85,共6个.其中最大的数是85,最小的数是25.故答案为:6;85;25",
+        "knowledge_points":  [
+                                 "搭配问题",
+                                 "100以内数的比大小"
+                             ],
+        "source":  "21-22二年级上·广西河池·期末"
+    },
+    {
+        "id":  "437",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "从4,5,6三个数中任意选其中2个求和,得数有()种可能.",
+        "options":  [
+
+                    ],
+        "answer":  "3",
+        "solution":  "【分析】从4,5,6中任意选2个,列出所有求和组合.\n【详解】4+5=9;4+6=10;5+6=11,一共有3种不同的和.",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "21-22二年级上·广西柳州·期末"
+    },
+    {
+        "id":  "438",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "用3,7,2组成两位数,每个两位数的十位数字和个位数字不能一样,可以组成()个不同的两位数.如果从3,7,2中任意取其中2个求积,积有()种可能.",
+        "options":  [
+
+                    ],
+        "answer":  "6;3",
+        "solution":  "【分析】排列:十位3种,个位2种,共3×2=6个不同两位数;从3,7,2中任取2个求积有3种组合.\n【详解】可组成的两位数有:32,37,23,27,73,72,共6个.求积时有3×7=21,3×2=6,7×2=14,共3种不同的积.",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "20-21二年级上·湖北咸宁·期末"
+    },
+    {
+        "id":  "439",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "用0,4,7可以组成()个不同的两位数,其中最大的数是(),最小的数是().",
+        "options":  [
+
+                    ],
+        "answer":  "4;74;40",
+        "solution":  "【分析】十位不能为0,十位只能是4或7.十位4时有40,47;十位7时有70,74,共4个.\n【详解】可组成的两位数有:40,47,70,74,一共4个不同的两位数.其中最大的数是74,最小的数是40.",
+        "knowledge_points":  [
+                                 "搭配问题",
+                                 "100以内数的比大小",
+                                 "100以内数的组成"
+                             ],
+        "source":  "20-21二年级上·湖北襄阳·期末"
+    },
+    {
+        "id":  "440",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "小明,小强,小军,小华四个小朋友,每两人握一次手,四人一共要握()次手.",
+        "options":  [
+
+                    ],
+        "answer":  "6",
+        "solution":  "【分析】4人两两握手,可以先固定一人,有3次;再固定第二人,有2次;剩下两人还有1次,一共3+2+1次.\n【详解】组合为:A和B,A和C,A和D,B和C,B和D,C和D,共6次.",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "20-21二年级上·江西吉安·期末"
+    },
+    {
+        "id":  "441",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "用3,5,8这三张数字卡片,能摆成()个不同的两位数,其中最大的数是(),最小的数是().",
+        "options":  [
+
+                    ],
+        "answer":  "6;85;35",
+        "solution":  "【分析】用3,5,8排列两位数,十位3种,个位2种,共3×2=6个.\n【详解】所有可能的两位数有:35,38,53,58,83,85,共6个.其中最大的数是85,最小的是35.",
+        "knowledge_points":  [
+                                 "搭配问题",
+                                 "100以内数的比大小"
+                             ],
+        "source":  "20-21二年级上·江西吉安·期末"
+    },
+    {
+        "id":  "442",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "用数字4,0,9可以组成()个不同的两位数.",
+        "options":  [
+
+                    ],
+        "answer":  "4",
+        "solution":  "【分析】十位不能为0,十位只能是4或9.各有2种个位选择,共2×2=4个.\n【详解】十位是4的两位数有:40,49;十位是9的两位数有:90,94;一共4个不同的两位数.",
+        "knowledge_points":  [
+                                 "排列组合问题"
+                             ],
+        "source":  "20-21二年级上·江西赣州·期末"
+    },
+    {
+        "id":  "443",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "从5,7,9这三个数中,任意选取其中两个数字组成两位数,共能组成()个不同的两位数.这些两位数中,最大的是(),最小的是(),它们相差().",
+        "options":  [
+
+                    ],
+        "answer":  "6;97;57;40",
+        "solution":  "【分析】用5,7,9组成无重复两位数,十位3种,个位2种,共3×2=6个,找出最大最小并作差即可.\n【详解】所有两位数为:57,59,75,79,95,97,共6个.其中最大是97,最小是57,97-57=40.",
+        "knowledge_points":  [
+                                 "排列组合问题",
+                                 "100以内数的比大小",
+                                 "两位数与两位数的不退位减法"
+                             ],
+        "source":  "20-21二年级上·黑龙江哈尔滨·期末"
+    },
+    {
+        "id":  "444",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "小明有两件颜色不同的上衣和三条颜色不同的裤子,他可以有()种不同的穿法.",
+        "options":  [
+
+                    ],
+        "answer":  "6",
+        "solution":  "【分析】每件上衣可以搭配3条裤子,有2件上衣,共2×3种穿法.\n【详解】2×3=6(种),所以一共有6种不同的穿法.",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "21-22二年级上·内蒙古乌兰察布·期末"
+    },
+    {
+        "id":  "445",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "用0,4,7可以组成()个两位数,这些两位数中最大的是(),最小的是(),它们相差().",
+        "options":  [
+
+                    ],
+        "answer":  "4;74;40;34",
+        "solution":  "【分析】十位只能是4或7,个位为剩余两数中的一个,共4个两位数.找最大最小并作差.\n【详解】两位数有:40,47,70,74.其中最大是74,最小是40,74-40=34.故答案为:4;74;40;34",
+        "knowledge_points":  [
+                                 "搭配问题",
+                                 "100以内数的比大小",
+                                 "两位数与整十数的减法"
+                             ],
+        "source":  "21-22二年级上·内蒙古乌兰察布·期末"
+    },
+    {
+        "id":  "446",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "3个人进行摔跤比赛,每2人赛一场,一共要赛()场.",
+        "options":  [
+
+                    ],
+        "answer":  "3",
+        "solution":  "【分析】三人两两比赛一场,可以先固定第1个人,与其他2个人各比赛一场,再加上剩下两人比赛一场.\n【详解】2+1=3(场),一共要赛3场.",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "20-21二年级上·内蒙古赤峰·期末"
+    },
+    {
+        "id":  "447",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "用6,2,7三个数字,能组成()个不同的两位数,它们分别是().",
+        "options":  [
+
+                    ],
+        "answer":  "6;26,27,62,67,72,76",
+        "solution":  "【分析】用6,2,7组成无重复两位数,十位3种,个位2种,共3×2=6个,列出即可.\n【详解】所有两位数为:26,27,62,67,72,76,共6个.故答案为:6;26,27,62,67,72,76",
+        "knowledge_points":  [
+                                 "搭配问题",
+                                 "100以内数的组成"
+                             ],
+        "source":  "20-21二年级上·内蒙古呼伦贝尔·期末"
+    },
+    {
+        "id":  "448",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "四瓶饮料中,选出两瓶装入箱子,有()种不同的选法.",
+        "options":  [
+
+                    ],
+        "answer":  "6",
+        "solution":  "【分析】四瓶不同饮料中选两瓶装箱,可以先固定第一瓶,有3种选法;再固定第二瓶,有2种选法;剩下两瓶还有1种选法,一共3+2+1种.\n【详解】3+2+1=6(种),共有6种不同的选法.",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "21-22二年级上·湖北黄石·期末"
+    },
+    {
+        "id":  "449",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "用6,2,7三个数字,能组成()个不同的两位数,最大是().",
+        "options":  [
+
+                    ],
+        "answer":  "6;76",
+        "solution":  "【分析】用6,2,7组成无重复两位数,十位3种选择,个位2种选择,共3×2=6个,列出后比较大小即可.\n【详解】所有两位数为:26,27,62,67,72,76,其中最大的是76.",
+        "knowledge_points":  [
+                                 "搭配问题",
+                                 "100以内数的比大小",
+                                 "100以内数的组成"
+                             ],
+        "source":  "20-21二年级上·四川攀枝花·期末"
+    },
+    {
+        "id":  "450",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "从1,5,10这三个数字中任意选出两个数字求和,得数有()种可能.有1元,5元,10元面值的人民币各一张,它们一共可以搭配组成()种不同的币值.",
+        "options":  [
+
+                    ],
+        "answer":  "3;7",
+        "solution":  "【分析】第一问是三数任取两数求和,第二问是1,5,10三张人民币取若干张的不同金额组合.\n【详解】1+5=6,1+10=11,5+10=15,得数3种.币值可以是:1,5,10,6,11,15,16,共7种.故答案为:3;7",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "20-21二年级上·四川内江·期末"
+    },
+    {
+        "id":  "451",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "莉莉有3支不同的铅笔和3支不同的签字笔,她上学时想带1支铅笔和1支签字笔,共有()种不同的方法.",
+        "options":  [
+
+                    ],
+        "answer":  "9",
+        "solution":  "【分析】从3支铅笔选1支有3种,从3支签字笔选1支有3种,根据乘法原理3×3种方法.\n【详解】3×3=9(种),共有9种不同的方法.",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "21-22二年级上·湖南岳阳·期末"
+    },
+    {
+        "id":  "452",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "有20元,10元,5元纸币各一张,从这3张纸币中取纸币,一共可以取出()种不同的币值.",
+        "options":  [
+
+                    ],
+        "answer":  "7",
+        "solution":  "【分析】取1张,2张或3张纸币,分别列出金额并去重统计.\n【详解】取一张:20,10,5,共3种;取两张:20+10=30,20+5=25,10+5=15,共3种;取三张:20+10+5=35,共1种,总共3+3+1=7种不同的币值.",
+        "knowledge_points":  [
+                                 "搭配问题",
+                                 "整十数加减一位数",
+                                 "整十数之间的加减法"
+                             ],
+        "source":  "20-21二年级上·广东佛山·期末"
+    },
+    {
+        "id":  "453",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "3个小朋友下棋,每两人下一盘,一共下了()盘.",
+        "options":  [
+
+                    ],
+        "answer":  "3",
+        "solution":  "【分析】3个小朋友下棋,每两人下一盘,可以列举出所有下棋情况.\n【详解】甲和乙,甲和丙,丙和乙,共下3盘棋.",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "20-21二年级上·广东肇庆·期末"
+    },
+    {
+        "id":  "454",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "用2,4,3能组成()个不同的两位数,其中最大的两位数是(),最小的两位数是(),它们相差().",
+        "options":  [
+
+                    ],
+        "answer":  "6;43;23;20",
+        "solution":  "【分析】用2,4,3组成两位数,十位3种,个位2种,共3×2=6个,找出最大最小并作差.\n【详解】所有可能的两位数为:23,24,32,34,42,43,共6个.其中最大的是43,最小的是23,43-23=20.",
+        "knowledge_points":  [
+                                 "搭配问题",
+                                 "两位数与两位数的不退位减法"
+                             ],
+        "source":  "20-21二年级上·广东肇庆·期末"
+    },
+    {
+        "id":  "455",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "用4,0,1这三张数字卡片可以摆出()个不同的两位数;任意选取这些两位数中的两个数求和,得数有()种可能.",
+        "options":  [
+
+                    ],
+        "answer":  "4;6",
+        "solution":  "【分析】首先列出用4,0,1组成的不重复两位数,再计算任意两数求和的不同结果种数.\n【详解】第一问:十位是4有40,41;十位是1有10,14,一共4个不同的两位数.第二问:40+41=81,40+10=50,40+14=54,41+10=51,41+14=55,10+14=24,共6种不同的和.",
+        "knowledge_points":  [
+                                 "搭配问题",
+                                 "100以内数的组成"
+                             ],
+        "source":  "20-21二年级上·湖南张家界·期末"
+    },
+    {
+        "id":  "456",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "用2,3和5组成两位数,每个两位数的十位数字和个位数字不能一样,能组成()个两位数.其中最大的两位数与最小的两位数的和是(),差是().",
+        "options":  [
+
+                    ],
+        "answer":  "6;76;30",
+        "solution":  "【分析】2,3,5组成无重复两位数有6个,按大小排出最大,最小再求和与差.\n【详解】两位数有:23,25,32,35,52,53,23\u003c25\u003c32\u003c35\u003c52\u003c53,53+23=76,53-23=30.",
+        "knowledge_points":  [
+                                 "排列组合问题",
+                                 "100以内数的比大小",
+                                 "两位数与两位数的不进位加法",
+                                 "两位数与两位数的不退位减法"
+                             ],
+        "source":  "21-22二年级上·河南南阳·期末"
+    },
+    {
+        "id":  "457",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "从2名男生和3名女生中选出一对羽毛球混合双打选手,有()种不同的组队方案.",
+        "options":  [
+
+                    ],
+        "answer":  "6",
+        "solution":  "【分析】从2名男生中选1人有2种,从3名女生中选1人有3种,乘法原理2×3种方案.\n【详解】2×3=6(种),故一共有6种不同的组队方案.",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "20-21二年级上·河南安阳·期末"
+    },
+    {
+        "id":  "458",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "用1,3,8可以组成()个个位数字和十位数字不同的两位数,其中最大的数是(),最小的数是(),它们相差().",
+        "options":  [
+
+                    ],
+        "answer":  "6;83;13;70",
+        "solution":  "【分析】1,3,8组成两位数,十位3种,个位2种,共3×2=6个,找出最大,最小并作差.\n【详解】两位数有:13,18,31,38,81,83,共6个,其中最大83,最小13,83-13=70.",
+        "knowledge_points":  [
+                                 "搭配问题",
+                                 "100以内数的比大小",
+                                 "两位数与两位数的不退位减法"
+                             ],
+        "source":  "20-21二年级上·河南·期末"
+    },
+    {
+        "id":  "459",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "从1角,5角和1元三枚硬币中,任意取出两枚,一共可以组成()种不同的币值.",
+        "options":  [
+
+                    ],
+        "answer":  "3",
+        "solution":  "【分析】列出所有两枚硬币的组合及其币值.\n【详解】1角+5角=6角;1角+1元=1元1角;5角+1元=1元5角,一共有3种不同的币值.",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "19-20二年级上·安徽铜陵·期末"
+    },
+    {
+        "id":  "460",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "用\"2,5,8\"三个数字能组成()个不同的两位数,最大的数是(),最小的数是().",
+        "options":  [
+
+                    ],
+        "answer":  "6;85;25",
+        "solution":  "【分析】用2,5,8组成无重复两位数,十位3种选择,个位2种选择,共6个,比较得到最大,最小.\n【详解】两位数为:25,28,52,58,82,85,共6个,其中最大是85,最小是25.",
+        "knowledge_points":  [
+                                 "搭配问题",
+                                 "100以内数的比大小",
+                                 "100以内数的组成"
+                             ],
+        "source":  "20-21二年级上·安徽淮南·期末"
+    },
+    {
+        "id":  "461",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "有2,6,5三个数,任意选出其中的两个数求和,得数有()种可能.",
+        "options":  [
+
+                    ],
+        "answer":  "3",
+        "solution":  "【分析】2+6,2+5,6+5三种组合求和即可.\n【详解】2+6=8;2+5=7;6+5=11,所以得数一共有3种可能.",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "20-21二年级上·河南焦作·期末"
+    },
+    {
+        "id":  "462",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "用3,2,0三个数可以组成()个不同的两位数,其中最小的数是().",
+        "options":  [
+
+                    ],
+        "answer":  "4;20",
+        "solution":  "【分析】写出用3,2,0组成的所有两位数,注意0不能放在最高位上.\n【详解】用3,2,0三个数可以组成的两位数有:32,30,23,20,一共4个.32\u003e30\u003e23\u003e20,用3,2,0三个数可以组成4个不同的两位数,其中最小的数是20.",
+        "knowledge_points":  [
+                                 "搭配问题",
+                                 "100以内数的比大小",
+                                 "100以内数的组成"
+                             ],
+        "source":  "19-20二年级上·安徽黄山·期末"
+    },
+    {
+        "id":  "463",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "从2,5,8三个数中任意选2个,可以组成()个不同的两位数,其中最大的两位数与最小的两位数相差().",
+        "options":  [
+
+                    ],
+        "answer":  "6;60",
+        "solution":  "【分析】用2,5,8三个数字组成两位数,十位有3种选择,个位有2种选择,所以一共有3×2个不同的两位数,再找出最大和最小求差.\n【详解】两位数有:25,28,52,58,82,85,共6个.其中最大的是85,最小的是25,85-25=60.故答案为:6;60",
+        "knowledge_points":  [
+                                 "搭配问题",
+                                 "100以内数的比大小",
+                                 "两位数与两位数的退位减法"
+                             ],
+        "source":  "21-22二年级上·内蒙古呼和浩特·期末"
+    },
+    {
+        "id":  "464",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "用2,5,6这三个数可以组成()个没有重复数字的两位数,其中最大的两位数是(),最小的两位数是().",
+        "options":  [
+
+                    ],
+        "answer":  "6;65;25",
+        "solution":  "【分析】用2,5,6组成两位数且无重复数字,十位3种,个位2种,共3×2=6个,比较大小求出最大和最小.\n【详解】两位数为:25,26,52,56,62,65,共6个.其中最大的数是65,最小的数是25.故答案为:6;65;25",
+        "knowledge_points":  [
+                                 "搭配问题",
+                                 "100以内数的比大小"
+                             ],
+        "source":  "20-21二年级上·浙江台州·期末"
+    },
+    {
+        "id":  "465",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "小朋友互相握手,每两人握1次手,3人一共握了()次手,()个人要握6次手.",
+        "options":  [
+
+                    ],
+        "answer":  "3;4",
+        "solution":  "【分析】3个人握手:A和B,A和C,B和C,共3次.要握6次手,则需4个人,分别是第1人与其他3人握手,第2人与后面2人握手,第3人与第4人握手,共3+2+1=6次.\n【详解】3人一共握了3次手;4个人要握6次手.",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "20-21二年级上·浙江台州·期末"
+    },
+    {
+        "id":  "466",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "每两人握一次手,3人一共握()次手.",
+        "options":  [
+
+                    ],
+        "answer":  "3",
+        "solution":  "【分析】3人每两人握一次手,可以列举为:第1人与第2人,第1人与第3人,第2人与第3人,共3次.\n【详解】每两人握一次手,3人一共握3次手.",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "18-19二年级上·河南郑州·期末"
+    },
+    {
+        "id":  "467",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "你能用0,3,6这三张数字卡片组成()个不同的两位数,其中最大的数是(),最小的数是(),它们相差().",
+        "options":  [
+
+                    ],
+        "answer":  "4;63;30;33",
+        "solution":  "【分析】数字卡片为0,3,6,十位不能为0,只能是3或6.列出所有两位数并比较大小求差.\n【详解】十位是3的两位数有:30,36;十位是6的两位数有:60,63;共4个不同的两位数:30,36,60,63.其中最大的数是63,最小的数是30,63-30=33.故答案为:4;63;30;33",
+        "knowledge_points":  [
+                                 "搭配问题",
+                                 "100以内数的比大小",
+                                 "两位数与两位数的不退位减法"
+                             ],
+        "source":  "20-21二年级上·湖北襄阳·期末"
+    },
+    {
+        "id":  "468",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "用1,2,3这3张卡片能组成()个不同的两位数.",
+        "options":  [
+
+                    ],
+        "answer":  "6",
+        "solution":  "【分析】用1,2,3组成不重复两位数,十位3种,个位2种,共3×2个.\n【详解】两位数为:12,13,21,23,31,32,共6个.",
+        "knowledge_points":  [
+                                 "搭配问题",
+                                 "100以内数的组成"
+                             ],
+        "source":  "21-22二年级上·四川南充·期末"
+    },
+    {
+        "id":  "469",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "有4只小动物,每两只小动物进行一场赛跑,一共需要进行()场赛跑.",
+        "options":  [
+
+                    ],
+        "answer":  "6",
+        "solution":  "【分析】4只小动物两两比赛一次,可以先固定一只,有3场;再固定第二只,有2场;剩下两只还有1场,一共3+2+1场.\n【详解】3+2+1=6(场),有4只小动物,每两只小动物进行一场赛跑,一共需要进行6场赛跑.",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "21-22二年级上·河北张家口·期末"
+    },
+    {
+        "id":  "470",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "用2,6,7可以组成()个不同的两位数,其中最大的数是(),最小的数是().",
+        "options":  [
+
+                    ],
+        "answer":  "6;76;26",
+        "solution":  "【分析】用2,6,7可以组成26,27,62,67,72,76六个不同的两位数,比较它们的大小,找到最大和最小的即可.\n【详解】用2,6,7可以组成6个不同的两位数,其中最大的数是76,最小的数是26.",
+        "knowledge_points":  [
+                                 "搭配问题",
+                                 "100以内数的比大小",
+                                 "100以内数的组成"
+                             ],
+        "source":  "20-21二年级上·湖北随州·期末"
+    },
+    {
+        "id":  "471",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "从5,8,9这三个数中选两个数相乘,积最小是(),最大是().",
+        "options":  [
+
+                    ],
+        "answer":  "40;72",
+        "solution":  "【分析】从5,8,9三个数中任意选取两个数相乘,列出所有乘积,再找出最小和最大.\n【详解】5×8=40;5×9=45;8×9=72,其中最小的积是40,最大的积是72.故答案为:40;72",
+        "knowledge_points":  [
+                                 "搭配问题",
+                                 "8的乘法口诀及应用",
+                                 "9的乘法口诀及应用"
+                             ],
+        "source":  "21-22二年级上·广东揭阳·期末"
+    },
+    {
+        "id":  "472",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "用5,0,8可以组成()个不同的两位数,其中最大的是().",
+        "options":  [
+
+                    ],
+        "answer":  "4;85",
+        "solution":  "【分析】0不能放在最高位.十位是5时,有50,58;十位是8时,有80,85,一共4个,两位数中最大是85.\n【详解】85\u003e80\u003e58\u003e50,用5,0,8可以组成4个不同的两位数,其中最大的是85.",
+        "knowledge_points":  [
+                                 "搭配问题",
+                                 "100以内数的比大小",
+                                 "100以内数的组成"
+                             ],
+        "source":  "21-22三年级上·河南周口·期末"
+    },
+    {
+        "id":  "473",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "从2,5,7这三个数中,任选2个求积.得数可能是(),(),().",
+        "options":  [
+
+                    ],
+        "answer":  "10;14;35",
+        "solution":  "【分析】2,5,7任选两个数求积都不同,列举所有乘积即可.\n【详解】2×5=10,2×7=14,5×7=35,得数可能是10,14,35.",
+        "knowledge_points":  [
+                                 "搭配问题",
+                                 "5的乘法口诀及应用",
+                                 "7的乘法口诀及应用"
+                             ],
+        "source":  "21-22二年级上·浙江嘉兴·期末"
+    },
+    {
+        "id":  "474",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "用4,5,9组成的两位数,每个两位数的十位数字和个位数字不能一样,能组成()个两位数.",
+        "options":  [
+
+                    ],
+        "answer":  "6",
+        "solution":  "【分析】用4,5,9组成两位数且不重复,十位有3种选择,个位有2种选择,共3×2个.\n【详解】所有两位数为:45,49,54,59,94,95,共6个.",
+        "knowledge_points":  [
+                                 "搭配问题",
+                                 "100以内数的组成"
+                             ],
+        "source":  "20-21二年级上·山西忻州·期末"
+    },
+    {
+        "id":  "475",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "从8,6,0中任选两个数可以组成()个不同的两位数.",
+        "options":  [
+
+                    ],
+        "answer":  "4",
+        "solution":  "【分析】十位不能为0,只能是8或6.十位为8:80,86;十位为6:60,68,共4个.\n【详解】用8,6,0组成的两位数有80,86,60,68,一共4个.故答案为:4",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "21-22二年级上·山东临沂·期末"
+    },
+    {
+        "id":  "476",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "三个同学两两握手,一共能握()次手.",
+        "options":  [
+
+                    ],
+        "answer":  "3",
+        "solution":  "【分析】三个同学两两握手,可以列举出所有握手组合.\n【详解】握手组合为A和B,A和C,B和C,共3次.",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "21-22二年级上·新疆阿克苏·期末"
+    },
+    {
+        "id":  "477",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "1,3,5组成()个不同的两位数,最大的是(),最小的是(),它们的和是().",
+        "options":  [
+
+                    ],
+        "answer":  "6;53;13;66",
+        "solution":  "【分析】1,3,5组成无重复两位数,十位3种,个位2种,共3×2=6个;最大53,最小13,其和为66.\n【详解】两位数为:13,15,31,35,51,53,共6个,其中最大是53,最小是13,53+13=66.故答案为:6;53;13;66",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "21-22二年级上·新疆阿克苏·期末"
+    },
+    {
+        "id":  "478",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "用0,5,7这三个数字卡片能摆出()个不同的两位数,最大的数是(),最小的数是(),它们相差().",
+        "options":  [
+
+                    ],
+        "answer":  "4;75;50;25",
+        "solution":  "【分析】用0,5,7组成两位数,十位不能为0.两位数有50,57,70,75,最大75,最小50,差25.\n【详解】用0,5,7能组成的两位数有:50,57,70,75,一共4个;50\u003c57\u003c70\u003c75,最小是50,最大是75,75-50=25.",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "21-22二年级上·福建莆田·期末"
+    },
+    {
+        "id":  "479",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "每两人进行一场乒乓球比赛,3人一共要赛()场.",
+        "options":  [
+
+                    ],
+        "answer":  "3",
+        "solution":  "【分析】三人两两比赛一次,可以列举出所有比赛组合.\n【详解】比赛组合为A和B,A和C,B和C,共3场.",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "20-21二年级上·西藏林芝·期末"
+    },
+    {
+        "id":  "480",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "用4和5可以组成的两位数是(),(),它们的和是().",
+        "options":  [
+
+                    ],
+        "answer":  "45;54;99",
+        "solution":  "【分析】4和5组成两位数有45,54,两数求和即可.\n【详解】用4和5可以组成的两位数是45和54.45+54=99.故答案为:45;54;99",
+        "knowledge_points":  [
+                                 "搭配问题",
+                                 "100以内数的组成",
+                                 "两位数与两位数的不进位加法"
+                             ],
+        "source":  "19-20二年级上·西藏林芝·期中"
+    },
+    {
+        "id":  "481",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "用2,3,4可以摆()个不同的两位数,三个小朋友每两人握一次手可以握()次.",
+        "options":  [
+
+                    ],
+        "answer":  "6;3",
+        "solution":  "【分析】2,3,4组成无重复两位数有3×2=6个;3个小朋友每两人握一次手,可以列举出3种握手组合.\n【详解】两位数为:23,24,32,34,42,43,共6个;握手组合为A和B,A和C,B和C,共3次.",
+        "knowledge_points":  [
+                                 "搭配问题",
+                                 "100以内数的组成"
+                             ],
+        "source":  "21-22二年级上·黑龙江鹤岗·期末"
+    },
+    {
+        "id":  "482",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "有1元,5元,10元的人民币各一张,一共可以组成()种不同币值.",
+        "options":  [
+
+                    ],
+        "answer":  "7",
+        "solution":  "【分析】取1张,2张或3张,计算所有不同金额数目.\n【详解】取一张:1元,5元,10元;取两张:1+5=6元,1+10=11元,5+10=15元;取三张:1+5+10=16元,共7种不同币值.",
+        "knowledge_points":  [
+                                 "搭配问题",
+                                 "人民币的认识与计算"
+                             ],
+        "source":  "21-22二年级上·湖北随州·期末"
+    },
+    {
+        "id":  "483",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "你能用1,3,6这三张数字卡片组成()个不同的两位数.",
+        "options":  [
+
+                    ],
+        "answer":  "6",
+        "solution":  "【分析】用1,3,6组成无重复两位数,十位3种,个位2种,共3×2个.\n【详解】两位数为:13,16,31,36,61,63,共6个.故答案为:6",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "21-22二年级上·云南玉溪·期末"
+    },
+    {
+        "id":  "484",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "用三张不同且不为0的数字卡片可以组成()个两位数.",
+        "options":  [
+
+                    ],
+        "answer":  "6",
+        "solution":  "【分析】设三张卡片上的数字互不相同且不为0,用其中一个作十位,另外两个作个位,一共3×2=6个.\n【详解】三张不同数字卡片能组成6个不同的两位数.",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "19-20二年级上·西藏林芝·期末"
+    },
+    {
+        "id":  "485",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "2件上衣,4条裤子搭配一套衣服,共有()种搭配.",
+        "options":  [
+
+                    ],
+        "answer":  "8",
+        "solution":  "【分析】每件上衣可以配4条裤子,共2件上衣,2×4种搭配.\n【详解】2×4=8(种).",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "18-19三年级上·浙江丽水·期末"
+    },
+    {
+        "id":  "486",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "厨房有3种糕点,2种水果,要选1种糕点和1种水果搭配,共有()种不同的搭配方法.",
+        "options":  [
+
+                    ],
+        "answer":  "6",
+        "solution":  "【分析】糕点3种,水果2种,搭配数=3×2.\n【详解】2×3=6(种).",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "20-21三年级上·浙江丽水·期末"
+    },
+    {
+        "id":  "487",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "用3,0,9,5能组成()个没有重复数字的两位数,其中最大的是(),最小的是().",
+        "options":  [
+
+                    ],
+        "answer":  "9;95;30",
+        "solution":  "【分析】用3,0,9,5四个数字组成无重复两位数,十位可为3,5,9,各自对应3个两位数,共9个,比较大小找最大,最小.\n【详解】能组成的两位数有:30,39,35,90,93,95,50,53,59,共9个,其中最大95,最小30.",
+        "knowledge_points":  [
+                                 "排列组合问题",
+                                 "搭配问题",
+                                 "100以内数的比大小"
+                             ],
+        "source":  "19-20三年级下·河北石家庄·期末"
+    },
+    {
+        "id":  "488",
+        "unit":  "搭配",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "小丑表演节目时有4顶不同的帽子可戴,有2条不同的裤子可穿,他共有()种搭配穿法.",
+        "options":  [
+
+                    ],
+        "answer":  "8",
+        "solution":  "【分析】每顶帽子可配2条裤子,共4顶帽子,2×4种搭配.\n【详解】2×4=8(种).",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "18-19三年级上·河南商丘·期末"
+    },
+    {
+        "id":  "489",
+        "unit":  "搭配",
+        "question_type":  "判断题",
+        "difficulty":  0.65,
+        "question":  "有4名同学去打羽毛球,每两人打一场,一共要打8场.()",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】4人两两比赛一场,可以先固定一人,有3场;再固定第二人,有2场;剩下两人还有1场,一共3+2+1=6场,不是8场.\n【详解】3+2+1=6(场),所以一共要打6场.原题说法错误.故答案为: ×",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "21-22二年级上·贵州黔南·期末"
+    },
+    {
+        "id":  "490",
+        "unit":  "搭配",
+        "question_type":  "判断题",
+        "difficulty":  0.65,
+        "question":  "用7,2,0三个数字能组成4个不同的两位数.()",
+        "options":  [
+
+                    ],
+        "answer":  "√",
+        "solution":  "【分析】用7,2,0组成两位数时,十位不能是0,十位可以是7或2.\n【详解】用7,2,0可以组成不同的两位数有72,70,20,27,共4个,所以题干说法正确.故答案为:√",
+        "knowledge_points":  [
+                                 "搭配问题",
+                                 "100以内数的组成"
+                             ],
+        "source":  "20-21二年级上·广东佛山·期末"
+    },
+    {
+        "id":  "491",
+        "unit":  "搭配",
+        "question_type":  "判断题",
+        "difficulty":  0.65,
+        "question":  "4个人之间,每两个人握一次手,共握手8次.()",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】4人握手,可以先固定一人,有3次;再固定第二人,有2次;剩下两人还有1次,一共3+2+1=6次,不是8次.\n【详解】3+2+1=6(次),原题说握手8次错误.故答案为: ×",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "21-22二年级上·河南南阳·期末"
+    },
+    {
+        "id":  "492",
+        "unit":  "搭配",
+        "question_type":  "判断题",
+        "difficulty":  0.65,
+        "question":  "从1,4,7,9中任意取2个数求和,得数有6种可能.()",
+        "options":  [
+
+                    ],
+        "answer":  "√",
+        "solution":  "【分析】从4个数中任取2个,可以有序列举所有组合,每种组合的和不同,所以得数有6种可能.\n【详解】从1,4,7,9中任意取2个数求和,所有组合为1和4,1和7,1和9,4和7,4和9,7和9,共6种,得数有6种可能.故答案为:√",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "20-21二年级上·安徽宣城·期末"
+    },
+    {
+        "id":  "493",
+        "unit":  "搭配",
+        "question_type":  "判断题",
+        "difficulty":  0.65,
+        "question":  "5个人之间,每两个人握一次手,共握手6次.()",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】5人握手,可以先固定一人,有4次;再固定第二人,有3次;接着有2次,1次,一共4+3+2+1=10次,不是6次.\n【详解】5个人之间,每两个人握一次手,共握10次.原题说6次错误.故答案为: ×",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "21-22二年级上·广东汕尾·期末"
+    },
+    {
+        "id":  "494",
+        "unit":  "搭配",
+        "question_type":  "判断题",
+        "difficulty":  0.65,
+        "question":  "三个小动物站成一排照相,有3种站法.()",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】三只小动物排成一排有3×2×1=6种站法,不是3种.\n【详解】共有6种站法,原题说法错误.故答案为: ×",
+        "knowledge_points":  [
+                                 "排列组合问题"
+                             ],
+        "source":  "20-21二年级上·山西忻州·期末"
+    },
+    {
+        "id":  "495",
+        "unit":  "搭配",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "3个好朋友见面互相拥抱一次,一共要拥抱3次.()",
+        "options":  [
+
+                    ],
+        "answer":  "√",
+        "solution":  "【分析】三人两两拥抱一次,可以列举出所有拥抱组合.\n【详解】拥抱组合为A和B,A和C,B和C,共3次.原题说法正确.故答案为:√",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "21-22二年级上·山东临沂·期末"
+    },
+    {
+        "id":  "496",
+        "unit":  "搭配",
+        "question_type":  "判断题",
+        "difficulty":  0.65,
+        "question":  "用4,0,5三个数可以组成6个没有重复数字的两位数.()",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】十位不能为0,用4,0,5组成的无重复两位数只有4个:40,45,50,54.\n【详解】只能组成40,45,50,54共4个两位数,原题说6个错误.故答案为: ×",
+        "knowledge_points":  [
+                                 "搭配问题",
+                                 "100以内数的组成"
+                             ],
+        "source":  "21-22二年级上·湖北随州·期末"
+    },
+    {
+        "id":  "497",
+        "unit":  "搭配",
+        "question_type":  "判断题",
+        "difficulty":  0.65,
+        "question":  "3件不同的上衣和4条不同的裤子有7种不同的搭配方法.()",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】搭配数为3×4=12种,不是7种.\n【详解】3件上衣和4条裤子,共3×4=12(种)不同的搭配方法.原题说7种错误.故答案为: ×",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "20-21二年级上·湖北黄冈·期末"
+    },
+    {
+        "id":  "498",
+        "unit":  "搭配",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "用1,3,5能组成几个两位数?要求:个位数字和十位数字不能一样,在下面按一定的顺序写一写.",
+        "options":  [
+
+                    ],
+        "answer":  "6;13,15,31,35,51,53",
+        "solution":  "【分析】1,3,5组成无重复两位数,十位3种,个位2种,共3×2=6个,再按顺序写出.\n【详解】所有两位数为:13,15,31,35,51,53,共6个.故答案为:6;13,15,31,35,51,53",
+        "knowledge_points":  [
+                                 "搭配问题",
+                                 "100以内数的组成"
+                             ],
+        "source":  "20-21二年级上·内蒙古赤峰·期末"
+    },
+    {
+        "id":  "499",
+        "unit":  "搭配",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "每两个人握1次手,3人一共握几次手?",
+        "options":  [
+
+                    ],
+        "answer":  "3次",
+        "solution":  "【分析】三人每两个人握1次手,可以先固定第1个人,与另外2个人各握一次,再让第2个人与第3个人握一次.\n【详解】第1个人与另外2个人各握一次,共2次;第2个人再与第3个人握一次,共1次,所以一共2+1=3次.",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "21-22二年级上·湖南常德·期末"
+    },
+    {
+        "id":  "500",
+        "unit":  "搭配",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "妈妈到商场买了4件上衣和2条裤子,一共有几种搭配方法?",
+        "options":  [
+
+                    ],
+        "answer":  "8种",
+        "solution":  "【分析】每件上衣可以配2条裤子,共4件上衣,搭配数为4×2.\n【详解】4件上衣和2条裤子,搭配方法有4×2=8(种).答:一共有8种搭配方法.",
+        "knowledge_points":  [
+                                 "搭配问题"
+                             ],
+        "source":  "20-21二年级上·西藏林芝·期末"
+    }
+]
\ No newline at end of file
diff --git "a/\344\272\214\345\271\264\347\272\247\351\242\230\351\233\206/\344\272\214\345\271\264\347\272\247\344\270\212/\344\272\214\345\271\264\347\272\247\344\270\212\347\254\254\345\205\255\345\215\225\345\205\203\350\241\250\345\206\205\344\271\230\346\263\225\357\274\210\344\272\214\357\274\211.json" "b/\344\272\214\345\271\264\347\272\247\351\242\230\351\233\206/\344\272\214\345\271\264\347\272\247\344\270\212/\344\272\214\345\271\264\347\272\247\344\270\212\347\254\254\345\205\255\345\215\225\345\205\203\350\241\250\345\206\205\344\271\230\346\263\225\357\274\210\344\272\214\357\274\211.json"
new file mode 100644
index 0000000000000000000000000000000000000000..a198abe0379a71de158f2125d433ed2b38d484f1
--- /dev/null
+++ "b/\344\272\214\345\271\264\347\272\247\351\242\230\351\233\206/\344\272\214\345\271\264\347\272\247\344\270\212/\344\272\214\345\271\264\347\272\247\344\270\212\347\254\254\345\205\255\345\215\225\345\205\203\350\241\250\345\206\205\344\271\230\346\263\225\357\274\210\344\272\214\357\274\211.json"
@@ -0,0 +1,8923 @@
+[
+    {
+        "id":  "1",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "6个星期共有( )天。",
+        "options":  [
+                        "A. 30",
+                        "B. 36",
+                        "C. 42"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】1个星期有7天，用7乘6即可求出6个星期共有多少天.\n【详解】7×6=42(天),6个星期共有42天。故答案为:C",
+        "knowledge_points":  [
+                                 "7的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·河南信阳·期末"
+    },
+    {
+        "id":  "2",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "得数最接近 50 的算式是( )。",
+        "options":  [
+                        "A. 7×7",
+                        "B. 82 - 19",
+                        "C. 35 + 19"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】先算出各算式的结果，然后算出结果和50之间的差，差越小则越接近.\n【详解】A。7×7=49,50-49=1;B。82-19=63,63-50=13;C。35+19=54,54-50=4.1\u003c4\u003c13。得数最接近50的算式是7×7。故答案为:A",
+        "knowledge_points":  [
+                                 "20以内数的比大小",
+                                 "两位数与两位数的进位加法",
+                                 "两位数与两位数的退位减法",
+                                 "7 的乘法口诀及应用"
+                             ],
+        "source":  "24-25 二年级上·浙江台州·期末"
+    },
+    {
+        "id":  "3",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "与算式 7 + 7 + 7 + 5 的结果不相等的是( )。",
+        "options":  [
+                        "A. 7×3 + 5",
+                        "B. 7×4 + 5",
+                        "C. 7×4 - 2"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】算出各算式的结果，然后作对比。整数混合运算中，同级运算时，从左到右依次计算;两级运算时，先算乘除，后算加减.\n【详解】7+7+7+5=26;A。7×3+5=21+5=26;B。7×4+5=28+5=33;C。7×4-2=28-2=26，与算式7+7+7+5的结果不相等的是7×4+5。故答案为:B",
+        "knowledge_points":  [
+                                 "表内乘加，乘减"
+                             ],
+        "source":  "24-25二年级上·浙江台州·期末"
+    },
+    {
+        "id":  "4",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "下列口诀中，只能写出一个乘法算式的是( )。",
+        "options":  [
+                        "A. 三四十二",
+                        "B. 六六三十六",
+                        "C. 五七三十五"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】根据乘法口诀写乘法算式时，口诀中的前两个数是乘数，可互换位置，后一个数是积，由此解答.\n【详解】A。三四十二：写出的乘法算式为3×4=12,4×3=12，不符合题意;B。六六三十六：写出的乘法算式为6×6=36，符合题意;C。五七三十五：写出的乘法算式为5×7=35,7×5=35，不符合题意。则只能写出一个乘法算式的是六六三十六。故答案为:B",
+        "knowledge_points":  [
+                                 "4 的乘法口诀及应用",
+                                 "6 的乘法口诀及应用",
+                                 "7的乘法口诀及应用"
+                             ],
+        "source":  "24-25 二年级上·贵州黔南·期末"
+    },
+    {
+        "id":  "5",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "小刚和3个同学去公园游玩，票价为每人 7 元，一共花了( )元。",
+        "options":  [
+                        "A. 21",
+                        "B. 10",
+                        "C. 28"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】根据题意，先用加法计算出一共有几人，再用每张门票的价格和人数相乘，就是一共要花的钱数.\n【详解】1+3=4(人),7×4=28(元),一共花了28元。故答案为:C",
+        "knowledge_points":  [
+                                 "7 的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·贵州黔南·期末"
+    },
+    {
+        "id":  "6",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "下列口诀中，只能写出一道乘法算式的是( )。",
+        "options":  [
+                        "A. 二二得四",
+                        "B. 三五十五",
+                        "C. 六七四十二"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】根据乘法口诀，再进行解答即可.\n【详解】A。根据\"二二得四\"可得:2×2=4，只能写出一道乘法算式，符合题意。B。根据\"三五十五\"可得:3×5=15,5×3=15，能写出两道乘法算式，不符合题意。C。根据\"六七四十二\"可得:6×7=42,7×6=42，能写出两道乘法算式，不符合题意。故答案为:A",
+        "knowledge_points":  [
+                                 "5 的乘法口诀及应用",
+                                 "2 的乘法口诀及应用",
+                                 "7的乘法口诀及应用"
+                             ],
+        "source":  "24-25 二年级上·广东云浮·期末"
+    },
+    {
+        "id":  "7",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "下边的三个算式，结果最接近 40 的是( )。",
+        "options":  [
+                        "A. 19 + 11",
+                        "B. 78 - 39",
+                        "C. 6×7"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】分别计算出各项算式的结果，再用结果和40相减，把它们的差比较大小，哪个数最小，那个数就更接近40，即可解答.\n【详解】A。19+11=30,40-30=10，和40相差10;B。78-39=39,40-39=1，和40相差1;C。6×7=42,42-40=2，和40相差2.10\u003e2\u003e1，结果最接近40的是78-39。故答案为:B",
+        "knowledge_points":  [
+                                 "两位数与两位数的进位加法",
+                                 "两位数与两位数的退位减法",
+                                 "7 的乘法口诀及应用"
+                             ],
+        "source":  "24-25 二年级上·湖南长沙·期末"
+    },
+    {
+        "id":  "8",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "袜子每双3元，妈妈带了 20 元，想买 7 双袜子，钱够吗。( )",
+        "options":  [
+                        "A. 够",
+                        "B. 不够",
+                        "C. 不确定"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】袜子每双3元，先用乘法求出买7双袜子，一共需要多少钱，然后与20元比较大小，即可解决.\n【详解】 3×7 = 21(元),21 \u003e 20，即，袜子每双3元，妈妈带了20元，想买7双袜子，钱不够。故答案为:B",
+        "knowledge_points":  [
+                                 "100以内数的比大小",
+                                 "7的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·湖南长沙·期末"
+    },
+    {
+        "id":  "9",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "下列口诀中，只能写出一个乘法算式的是( )。",
+        "options":  [
+                        "A. 三四十二",
+                        "B. 七七四十九",
+                        "C. 五六三十"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】乘法算式中两个乘数是口诀中的前两个数，积是口诀中的后一个数，写算式时两个乘数可互换位置。当前面的两个乘数相同时只能写出一个乘法口诀。写出每项中的乘法算式即可求解.\n【详解】A。 3×4 = 12 或 4×3 = 12;B. 7×7 = 49;C. 5×6 = 30 或 6×5 = 30，只能写出一个乘法算式的是七七四十九。故答案为:B",
+        "knowledge_points":  [
+                                 "4 的乘法口诀及应用",
+                                 "6 的乘法口诀及应用",
+                                 "7的乘法口诀及应用"
+                             ],
+        "source":  "23-24二年级上·湖南长沙·期末"
+    },
+    {
+        "id":  "10",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "下面的算式中，与6×7 相等的是( )。",
+        "options":  [
+                        "A. 6 + 7",
+                        "B. 5×7 + 7",
+                        "C. 7×5 + 5"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】分别算出各算式的结果，然后对比是否相等。整数混合运算中，同级运算时，从左到右依次计算;两级运算时，先算乘除，后算加减.\n【详解】 6×7 = 42,A. 6 + 7，与 6×7 不相等;B。5×7 + 7= 35 + 7= 42，与 6×7 相等;C。7×5 + 5 = 35 + 5= 40，与 6×7 不相等;与 6×7 相等的是 5×7 + 7。故答案为:B",
+        "knowledge_points":  [
+                                 "7,6 加几的进位加法",
+                                 "7 的乘法口诀及应用",
+                                 "表内乘加，乘减"
+                             ],
+        "source":  "24-25二年级上·湖南娄底·期末"
+    },
+    {
+        "id":  "11",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "不能用\"四七二十八\"这句口诀来计算的算式是( )。",
+        "options":  [
+                        "A. 7 + 7 + 7 + 7",
+                        "B. 7×4",
+                        "C. 7 + 4"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】四七二十八是乘法口诀，则用于乘法算式.\n【详解】A。 7 + 7 + 7 + 7 求几个相同数连加可用乘法表示，列式为 4×7 或 7×4，可用乘法口诀\"四七二十八\"这句口诀来计算，不符合题意。B。 7×4 可用乘法口诀\"四七二十八\"这句口诀来计算，不符合题意。C。7 + 4 加法算式, 7 + 4 = 11，则符合题意。故答案为:C",
+        "knowledge_points":  [
+                                 "7 的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·浙江杭州·期末"
+    },
+    {
+        "id":  "12",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "□*7 \u003c 40,□里最大填( )。",
+        "options":  [
+                        "A. 6",
+                        "B. 5",
+                        "C. 4"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】根据乘法口诀,5×7=35,6×7=42,35\u003c40\u003c42，所以□里最大填5.\n【详解】□*7 \u003c 40,□里最大填5。故答案为:B",
+        "knowledge_points":  [
+                                 "7 的乘法口诀及应用"
+                             ],
+        "source":  "24-25 二年级上·江西南昌·期末"
+    },
+    {
+        "id":  "13",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "要求李白的这首古诗一共有几个字(含题目，不含标点),不正确的算式是( ).\n\n望庐山瀑布\n\n日照香炉生紫烟,\n遥看瀑布挂前川.\n飞流直下三千尺,\n疑是银河落九天。",
+        "options":  [
+                        "A. 7×4 + 5",
+                        "B. 5×7 + 2",
+                        "C. 7×5 - 2"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】这首古诗的正文一排有7个字，有4排，题目有5个字，根据分析可知，每排汉字的字数乘排数，再加上题目的汉字，即可求出一共多少个汉字;或者把标题也看成7个汉字，每排汉字的字数乘排数，减去标题中多计算的2个汉字，也可以求出一共多少个汉字，据此解答.\n【详解】根据题意可列算式:7×4+5或7×5-2，不正确的算式是5×7+2。故答案为:B",
+        "knowledge_points":  [
+                                 "7 的乘法口诀及应用",
+                                 "表内乘加，乘减"
+                             ],
+        "source":  "24-25二年级上·四川广元·期末"
+    },
+    {
+        "id":  "14",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "如图中，与小兔子身高最接近的是( ).\n\n![](images/f4447e3d210f99dffd79b32ee303f7479daaa56e2067e321f6bb33398afb1709.jpg)",
+        "options":  [
+                        "A. 11 厘米",
+                        "B. 40 厘米",
+                        "C. 28厘米"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】从图上可得：小兔子的身高大约等于旁边7个罐头的高度，已知每个罐头高4厘米，根据乘法的意义，用 4×7 进行解答即可.\n【详解】 4×7 = 28(厘米),所以小兔子大约身高28厘米。最接近的是C。故答案为:C",
+        "knowledge_points":  [
+                                 "7 的乘法口诀及应用"
+                             ],
+        "source":  "24-25 二年级上·广东江门·期末"
+    },
+    {
+        "id":  "15",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "下面可以用5×7解决的问题是( )。",
+        "options":  [
+                        "A. 小明折纸，第一天折了 5 张，第二天折了 7 张，两天一共折了几张纸。",
+                        "B. 丽丽看书，每天看 5 页，一个星期看了多少页。",
+                        "C. 花花有 5 颗星星，小美有 7 颗星星，小美和花花相差几颗。"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】把两天折的张数相加即可求出一共折的张数;用每天看书的页数乘一个星期的天数即可求出一个星期看的页数;用小美有的星星颗数减去花花有的星星颗数，即可求出小美和花花相差的颗数.\n【详解】A。列式为5+7，不能用5×7解决，不符合题意;B。列式为5×7，能用5×7解决，符合题意;C。列式为7-5，不能用5×7解决，不符合题意。故答案为:B",
+        "knowledge_points":  [
+                                 "7 的加减法",
+                                 "5~2 加几的进位加法",
+                                 "7 的乘法口诀及应用"
+                             ],
+        "source":  "23-24 二年级上·浙江·期末"
+    },
+    {
+        "id":  "16",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "一共有多少个三角形。正确的列式是( ).\n\n![](images/9fc237d27efb8b9008af271e179b87e3c3f758eb3345d43137c8fe94a307d958.jpg)\n\n![](images/9547242e19fc9d7b897b1b6507a184f831c667a4fac24dc7027a60f44bac52a8.jpg)\n\n![](images/a18f18df740522a15be5ad3441f7e91394133be874f5782a9230e529b2b61412.jpg)",
+        "options":  [
+                        "A. 2×7 + 3",
+                        "B. 2×7 + 2",
+                        "C. 3×7 - 2"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】这是一道乘加，乘减的题目，一只小船需要7个三角形，两只小船需要2个7相加的三角形，再加上最后的2个三角形，列出乘加算式即可;或者把最后一组也看成一只小船，这时三角形的个数就是求 3 个 7 相加，再减去多算的 5 个三角形，列出乘减算式即可;据此解答.\n【详解】根据分析可得：乘加算式: 2×7 + 2;乘减算式: 3×7 - 5，答案 B 是正确算式。故答案为:B",
+        "knowledge_points":  [
+                                 "图文问题",
+                                 "表内乘加，乘减"
+                             ],
+        "source":  "24-25 二年级上·山东济宁·期末"
+    },
+    {
+        "id":  "17",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "7○7○7 = 56，要使左边的等式成立,○里应填的运算符号是( )。",
+        "options":  [
+                        "A. +; +",
+                        "B. *; -",
+                        "C. *; +"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】根据乘法口诀七八五十六可知,7×8=56，也就是8个7的和是56。则题目可以变成7个7的和再加上1个7，结果就是8个7的和，即7×7+7。也可以将各选项的符号代入到算式中计算出结果进行解答.\n【详解】A。7+7+7=21，不符合题意;B。7×7-7=49-7=42，不符合题意;C。7×7+7=49+7=56，符合题意。所以○里应填的运算符号是*,+。故答案为:C",
+        "knowledge_points":  [
+                                 "100以内数的连加运算",
+                                 "表内乘加，乘减"
+                             ],
+        "source":  "23-24 二年级上·河北保定·期末"
+    },
+    {
+        "id":  "18",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "下列口诀中，只能用来计算一道乘法算式的是( )。",
+        "options":  [
+                        "A. 二三得六",
+                        "B. 七七四十九",
+                        "C. 三七二十一"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】乘法口诀中，当两个乘数相同时，只能用来计算一道乘法算式;其余的口诀可以用来计算两道乘法算式，据此解答.\n【详解】A.\"二三得六\"这句口诀，可以用来计算:2×3=6或3×2=6;B.\"七七四十九\"这句口诀，只能用来计算:7×7=49;C.\"三七二十一\"这句口诀，可以用来计算:3×7=21或7×3=21。故答案为:B",
+        "knowledge_points":  [
+                                 "3 的乘法口诀及应用",
+                                 "7 的乘法口诀及应用"
+                             ],
+        "source":  "23-24 二年级上·江西赣州·期末"
+    },
+    {
+        "id":  "19",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "2 个 7 相乘是( )。",
+        "options":  [
+                        "A. 9",
+                        "B. 49",
+                        "C. 14"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】由题意可知,2个7相乘，就是 7×7，根据7的乘法口诀，计算出乘积，即可解答.\n【详解】 7×7 = 49，即,2 个 7 相乘是 49。故答案为:B",
+        "knowledge_points":  [
+                                 "7的乘法口诀及应用"
+                             ],
+        "source":  "23-24 二年级上·新疆昌吉·期末"
+    },
+    {
+        "id":  "20",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "兰兰的爸爸妈妈参加新年集福卡活动。谁集的福卡多。( )\n\n![](images/2026-02-26%20155755.jpg)",
+        "options":  [
+                        "A. 兰兰妈妈",
+                        "B. 兰兰爸爸",
+                        "C. 一样多"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】根据题意，分别计算出兰兰妈妈和兰兰爸爸集卡的数量再比较大小即可，比较时，位数多的数就大;位数相同比较最高位，最高位大的数就大;最高位相同比较下一位，直到比较出结果为止。兰兰妈妈集卡的数量为7个6的和，用乘法计算，每种卡的张数和卡的种类相乘，就是总张数;兰兰爸爸集卡的数量用加法计算，一种的张数 + 另一种的张数 = 总张数.\n【详解】兰兰妈妈: 6×7 = 42 (张);兰兰爸爸: 7 + 6 = 13 (张);42 \u003e 13，兰兰妈妈集的福卡多。故答案为:A",
+        "knowledge_points":  [
+                                 "图文问题",
+                                 "100以内数的比大小",
+                                 "7,6加几的进位加法",
+                                 "7 的乘法口诀及应用"
+                             ],
+        "source":  "24-25 二年级上·河南周口·期中"
+    },
+    {
+        "id":  "21",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "一只兔子一天吃 3个胡萝卜，一个星期吃( )个胡萝卜。",
+        "options":  [
+                        "A. 15",
+                        "B. 10",
+                        "C. 21"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】一个星期是7天，根据乘法的意义，用一只兔子一天吃胡萝卜的数量 * 7 即可求出一个星期吃胡萝卜的数量，据此解答即可.\n【详解】 3×7 = 21(个),所以一只兔子一天吃 3 个胡萝卜，一个星期吃 21 个胡萝卜。故答案为:C",
+        "knowledge_points":  [
+                                 "7 的乘法口诀及应用"
+                             ],
+        "source":  "24-25 二年级上·广东梅州·期中"
+    },
+    {
+        "id":  "22",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "二(2)班同学进行分组，每5人一组剩下2人，每7人一组也剩下2人，那么二(2)班至少有( )人。",
+        "options":  [
+                        "A. 33",
+                        "B. 35",
+                        "C. 37"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】根据题意，每5人一组剩下2人，每7人一组也剩下2人，也就是几个5的和加上2和几个7的和加上2相等，则最少的人数也就是5个7的和或7个5的和再加2，由此解答.\n【详解】5×7+2=35+2=37(人),二(2)班至少有37人。故答案为:C",
+        "knowledge_points":  [
+                                 "表内乘加，乘减"
+                             ],
+        "source":  "23-24 二年级上·湖北孝感·期中"
+    },
+    {
+        "id":  "23",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "在括号里最大能填几。\n\n( )×7 \u003c 36;5×( ) \u003c 23",
+        "options":  [
+
+                    ],
+        "answer":  "5;4",
+        "solution":  "【分析】通过乘法口诀依次计算，找到满足条件的最大数即可.\n【详解】5×7=35,6×7=42,35\u003c36\u003c42，所以括号里最大能填5，即5×7\u003c36;5×4=20,5×5=25,20\u003c23\u003c25，所以括号里最大能填4，即5×4\u003c23。",
+        "knowledge_points":  [
+                                 "100 以内数的比大小",
+                                 "5 的乘法口诀及应用",
+                                 "7的乘法口诀及应用"
+                             ],
+        "source":  "23-24二年级下·甘肃天水·期末"
+    },
+    {
+        "id":  "24",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "有一堆苹果，比 40个多，比50个少，分得的份数和每份的个数同样多，这堆苹果有( )个。",
+        "options":  [
+
+                    ],
+        "answer":  "49",
+        "solution":  "【分析】根据题意，这堆苹果的数量比40个多，比50个少，分得的份数和每份的个数同样多，也就是两个相同数的积在40和50之间，根据乘法口诀找到对应的数即可.\n【详解】根据乘法口诀七七四十九可知:7×7=49(个),40\u003c49\u003c50。有一堆苹果，比40个多，比50个少，分得的份数和每份的个数同样多，这堆苹果有49个。",
+        "knowledge_points":  [
+                                 "100 以内数的比大小",
+                                 "7 的乘法口诀及应用"
+                             ],
+        "source":  "24-25 二年级下·河南南阳·期中"
+    },
+    {
+        "id":  "25",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "上体育课时，小明在方阵队伍中从前，后，左，右数都是第4个，这个方阵有( )人。",
+        "options":  [
+
+                    ],
+        "answer":  "49",
+        "solution":  "【分析】根据题意，从左，右数，小明都排在第4个，则每行的人数为(4 + 4 - 1)人;从前，后数，小明也是排在第4个，则每一列的人数也是(4 + 4 - 1)人;再把每行的人数和每列的人数相乘，就是总人数.\n【详解】 4 + 4 - 1 = 7 (人),7×7 = 49 (人),上体育课时，小明在方阵队伍中从前，后，左，右数都是第 4 个，这个方阵有 49 人。",
+        "knowledge_points":  [
+                                 "加减混合运算(10以内)",
+                                 "7的乘法口诀及应用",
+                                 "方阵问题"
+                             ],
+        "source":  "24-25 二年级上·湖北黄冈·期末"
+    },
+    {
+        "id":  "26",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "爸爸买了一盒巧克力，每天吃3块，吃了一个星期后还剩2块，这盒巧克力共有( )块。",
+        "options":  [
+
+                    ],
+        "answer":  "23",
+        "solution":  "【分析】根据题意可知，每天吃的块数乘一个星期的 7 天，再加上还剩下的2块，等于这盒巧克力共有多少块，据此解答.\n【详解】 3×7 + 2 = 21 + 2 = 23(块),这盒巧克力共有 23 块。",
+        "knowledge_points":  [
+                                 "7 的乘法口诀及应用",
+                                 "表内乘加，乘减"
+                             ],
+        "source":  "24-25二年级上·云南保山·期末"
+    },
+    {
+        "id":  "27",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "一个乘数是7，另一个乘数是 4，它们的积是( ),列算式( ),读作( )。",
+        "options":  [
+
+                    ],
+        "answer":  "28;4×7=28;4乘7等于28",
+        "solution":  "【分析】乘法算式中两个乘数是口诀中的前两个数，积是口诀中的后一个数，根据乘法口诀即可填空;写算式时两个乘数可互换位置，根据乘数×乘数=积，可以写出算式;读乘法算式时，依次从左往右读，数字直接读出来，\"*\"读作乘，\"=\"读作等于，据此解答.\n【详解】根据对乘法的认识及乘法口诀可知：一个乘数是7，另一个乘数是4，它们的积是28，列算式4×7=28，读作4乘7等于28。",
+        "knowledge_points":  [
+                                 "初步认识乘法意义",
+                                 "7的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·云南保山·期末"
+    },
+    {
+        "id":  "28",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "7×5 + 7 = ( )×( )。",
+        "options":  [
+
+                    ],
+        "answer":  "7;6",
+        "solution":  "【分析】乘法算式可以表示几个相同加数的和，若前一个乘数是相同加数，则后一个乘数是相同加数的个数;若前个乘数是相同加数的个数，则后一个乘数是相同加数，由此解答.\n【详解】 7×5 + 7 表示5个7的和再加上1个7，结果是6个7 的和。则 7×5 + 7 = 7×6 (或 6×7)。",
+        "knowledge_points":  [
+                                 "初步认识乘法意义",
+                                 "7 的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·浙江台州·期末"
+    },
+    {
+        "id":  "29",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "一只青蛙 4 条腿,7只青蛙( )条腿。",
+        "options":  [
+
+                    ],
+        "answer":  "28",
+        "solution":  "【分析】一只青蛙 4 条腿，求 7 只青蛙多少条腿，就是求 7个 4 的和是多少，用乘法列式解决.\n【详解】 4×7 = 28(条),即，一只青蛙4条腿,7只青蛙28条腿。",
+        "knowledge_points":  [
+                                 "7的乘法口诀及应用"
+                             ],
+        "source":  "24-25 二年级上·云南保山·期末"
+    },
+    {
+        "id":  "30",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "8个7减去5个7是( )个7，结果是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "3;21",
+        "solution":  "【分析】8减5得几则8个7减去5个7就是几个7。几个相同加数相加，可以写成加数与个数相乘的形式。乘法算式中两个乘数是口诀中的前两个数，积是口诀中的后一个数，写算式时两个乘数可互换位置.\n【详解】 8 - 5 = 3 (个),3×7 = 21,8个7减去5个7是 3 个7，结果是 21。",
+        "knowledge_points":  [
+                                 "同数连加的应用",
+                                 "7的乘法口诀及应用"
+                             ],
+        "source":  "24-25 二年级上·安徽黄山·期末"
+    },
+    {
+        "id":  "31",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "3 个 7 的和是( ),再加 4 个 7 就是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "21;49",
+        "solution":  "【分析】根据求几个相同数连加的和，可以用乘法表示.\n【详解】 3×7 = 21,21 + 4×7 = 21 + 28 = 49，则 3 个 7 的和是 21，再加 4 个 7 就是 49。",
+        "knowledge_points":  [
+                                 "7的乘法口诀及应用"
+                             ],
+        "source":  "24-25 二年级上·浙江杭州·期末"
+    },
+    {
+        "id":  "32",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "8 名男生站成一排，相邻两个男生之间站 3 个女生。男，女生一共有( )名。",
+        "options":  [
+
+                    ],
+        "answer":  "29",
+        "solution":  "【分析】由题意可知,8名男生排队，站成一排，每相邻两个男生之间站3个女生。求出8名男生之间有几个间隔，即一个间隔3名女生，就可以知道一共可以站几名女生。用间隔数乘每个间隔的女生人数，再加上男生的人数即可.\n【详解】 8 - 1 = 7 (个),7×3 = 21(名),21 + 8 = 29(名),男，女生一共有 29 名。",
+        "knowledge_points":  [
+                                 "两位数与一位数的加法(不进位)",
+                                 "7的乘法口诀及应用"
+                             ],
+        "source":  "24-25 二年级上·浙江杭州·期末"
+    },
+    {
+        "id":  "33",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "积是 42 的乘法口诀是( ),根据这句乘法口诀写出的乘法算式是( )或()。",
+        "options":  [
+
+                    ],
+        "answer":  "六七四十二;6×7=42;7×6=42",
+        "solution":  "【分析】根据表内乘法口诀填写即可，写乘法算式时，口诀中的前两个数是乘数可互换位置，后一个数是积，由此解答.\n【详解】积是42的乘法口诀是六七四十二，根据这句乘法口诀写出的乘法算式是 6×7 = 42 或 7×6 = 42。",
+        "knowledge_points":  [
+                                 "7 的乘法口诀及应用"
+                             ],
+        "source":  "24-25 二年级上·湖北随州·期末"
+    },
+    {
+        "id":  "34",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在括号里填上\"\u003e\"\"\u003c\"或\"=\".\n\n45+7( )47+5;2×1( )2+1\n\n3×6( )2×7;3+5+5( )3×5",
+        "options":  [
+
+                    ],
+        "answer":  "=;\u003c;\u003e;\u003c",
+        "solution":  "【分析】根据整数加减法的计算法则及乘法口诀，算出各个算式的结果，再按照整数比较大小的方法解答即可;比较数的大小，先看位数的多少，位数多的数就大;如果位数相同，从最高位开始比较，最高位上的数大则这个数就大，最高位相同，就比较下一位，以此类推.\n【详解】(1)左边:45+7=52，右边:47+5=52,52=52，故45+7=47+5;(2)左边:2×1=2，右边:2+1=3,2小于3，故2×1\u003c2+1;(3)左边:3×6=18，右边:2×7=14,18大于14，所以3×6\u003e2×7;(4)左边:3+5+5=13，右边:3×5=15,13小于15，所以3+5+5\u003c3×5。",
+        "knowledge_points":  [
+                                 "5 以内数的加法",
+                                 "一位数与两位数的进位加法",
+                                 "6的乘法口诀及应用",
+                                 "7的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·江西赣州·期末"
+    },
+    {
+        "id":  "35",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "括号里最大能填几。\n\n( )×4 \u003c 25;30-( ) \u003e 25;23+( ) \u003c 29;6×( ) \u003c 32",
+        "options":  [
+
+                    ],
+        "answer":  "6;4;5;5",
+        "solution":  "【分析】根据表内乘法口诀，整数加法计算法则及整数比较大小的方法和结合题干要求进行解答即可.\n【详解】 6×4 = 24 , 7×4 = 28 , 24 \u003c 25 \u003c 28，故, 6×4 \u003c 25;30 - 25 = 5 , 5 - 1 = 4 , 30 - 4 = 26 , 26 \u003e 25，故, 30 - 4 \u003e 25;29 - 23 = 6, 6 - 1 = 5 , 23 + 5 = 28 , 28 \u003c 29，故, 23 + 5 \u003c29;6×5 = 30 , 6×6 = 36 , 30 \u003c 32 \u003c 36，故, 6×5 \u003c 32。",
+        "knowledge_points":  [
+                                 "100 以内数的比大小",
+                                 "两位数与两位数的退位减法",
+                                 "5 的乘法口诀及应用",
+                                 "7 的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·重庆奉节·期末"
+    },
+    {
+        "id":  "36",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "7+7+7+7+5=( )×( )+( );6+6+6+6+6+6+4=( )×( )-( )。",
+        "options":  [
+
+                    ],
+        "answer":  "7;4;5;6;7;2",
+        "solution":  "【分析】几个相同加数相加，可以写成加数与个数相乘的形式，写算式时两个乘数可互换位置;6+6+6+6+6+6+4为6个6加上1个4，那么看作7个6，多算了6-4=2，那么再减去1个2即可;据此解答.\n【详解】7+7+7+7+5=7×4+5或4×7+5;6+6+6+6+6+6+4=6×7-2。",
+        "knowledge_points":  [
+                                 "初步认识乘法意义",
+                                 "6 的乘法口诀及应用",
+                                 "7 的乘法口诀及应用",
+                                 "表内乘加，乘减"
+                             ],
+        "source":  "24-25二年级上·河南驻马店·期末"
+    },
+    {
+        "id":  "37",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在括号里填上合适的数.\n\n7×2+7=( )×( );6×6-6=( )×( );8+8+8+4=( )×( );5+5+5+2+3+5=( )×( )",
+        "options":  [
+
+                    ],
+        "answer":  "7;3;6;5;4;7;5;5",
+        "solution":  "【分析】 7×2 + 7 表示2个7的和再加上1个7，也就是求3个 7 的和是多少，即 7×2 + 7 = 7×3;6×6 - 6 表示 6 个 6 的和再减去 1 个 6，也就是求 5 个 6 的和是多少，即 6×6 - 6 = 6×5;1个8等于2个4，则3个8就等于6个4，所以 8 + 8 + 8 + 4 = 4 + 4 + 4 + 4 + 4 + 4 + 4 + 4，即 8 + 8 + 8 + 4 可以表示7个4的和是多少，即 8 + 8 + 8 + 4 = 7×4;2 + 3 = 5，则 5 + 5 + 5 + 2 + 3 + 5 = 5 + 5 + 5 + 5 + 5，即 5 + 5 + 5 + 2 + 3 + 5 可以表示5个5的和是多少，即 5 + 5 + 5 + 2 + 3 + 5 = 5×5 .\n【详解】 7×2 + 7 = 7×3;6×6 - 6 = 6×5;8 + 8 + 8 + 4 = 4×7;5 + 5 + 5 + 2 + 3 + 5 = 5×5。",
+        "knowledge_points":  [
+                                 "初步认识乘法意义",
+                                 "表内乘加，乘减"
+                             ],
+        "source":  "24-25 二年级上·重庆奉节·期末"
+    },
+    {
+        "id":  "38",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "![](images/a9ef581a6508856f5c0e3fb63e2ca541aed26a4ce8b18ed37f72e96c9b77e243.jpg)\n图中表示( )个( )相加，列乘法算式是( )或( ),计算时所用的口诀是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "3;7;3×7=21;7×3=21;三七二十一",
+        "solution":  "【分析】一组苹果有7个，求这样的3组苹果有几个，就是 求3个7的和是多少，可以用乘法列式解决;即 3×7 或 7×3。计算时所用的口诀是：三七二十一.\n【详解】由题意分析得：图中表示3个7相加，列乘法算式是 3×7 = 21 或 7×3 = 21，计算时所用的口诀是：三七二十一。",
+        "knowledge_points":  [
+                                 "初步认识乘法意义",
+                                 "7的乘法口诀及应用"
+                             ],
+        "source":  "24-25 二 年 级 上 · 河 南 南 阳 · 期 末"
+    },
+    {
+        "id":  "39",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在括号里填上\" \u003e \"\" \u003c \"或 \"=\".\n\n45 + 13 ( ) 23 + 15;71 - 35 ( ) 45;7×6 ( ) 36;7×4 ( ) 7×5 - 7",
+        "options":  [
+
+                    ],
+        "answer":  "\u003e;\u003c;\u003e;=",
+        "solution":  "【分析】有算式先算出算式的得数，再进行比较大小即可得出答案.\n【详解】45+13=58,23+15=48,58\u003e48，所以45+13\u003e23+15;71-35=36,36\u003c45，所以71-35\u003c45;7×6=42,42\u003e36，所以7×6\u003e36;7×4=28,7×5-7=35-7=28，所以7×4=7×5-7。",
+        "knowledge_points":  [
+                                 "100以内数的比大小",
+                                 "两位数与两位数的不进位加法",
+                                 "7 的乘法口诀及应用",
+                                 "表内乘加，乘减"
+                             ],
+        "source":  "24-25 二年级上·广东江门·期末"
+    },
+    {
+        "id":  "40",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在括号填上\" \u003e \"\" \u003c \"或\"=\".\n\n32 - 7( )35;4 + 46( )86 - 40;16 厘米 + 84 厘米( )1 米\n\n4×5( )7×3;18 + 18( )40;1 米 - 20 厘米( )70 厘米",
+        "options":  [
+
+                    ],
+        "answer":  "\u003c;\u003e;=;\u003c;\u003c;\u003e",
+        "solution":  "【分析】先计算出每个算式的结果或先统一单位，然后比较大小即可。整数比较大小方法:①位数多的数大于位数少的数;②位数相同的，先比较最高位上的数，最高位上大的，数就大，最高位数相同的，就比较下一位，以此类推。1米=100厘米.\n【详解】32-7=25，故32-7\u003c35;4+46=50,86-40=46，故4+46\u003e86-40;16厘米+84厘米=100厘米,100厘米=1米，即16厘米+84厘米=1米;4×5=20,7×3=21，故4×5\u003c7×3;18+18=36，故18+18\u003c40;1米=100厘米,100厘米-20厘米=80厘米，即1米-20厘米=80厘米，故1米-20厘米\u003e70厘米。",
+        "knowledge_points":  [
+                                 "100 以内数的比大小",
+                                 "5 的乘法口诀及应用",
+                                 "7的乘法口诀及应用",
+                                 "厘米和米之间的进率与换算"
+                             ],
+        "source":  "24-25二年级上·山东济宁·期末"
+    },
+    {
+        "id":  "41",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "如果☆+☆+☆=15,○+○+☆=19，那么☆*○=( )。",
+        "options":  [
+
+                    ],
+        "answer":  "35",
+        "solution":  "【分析】☆+☆+☆=15，表示3个相同的数相加等于15，再结合5+5+5=15，可知☆=5;把☆=5代入到○+○+☆=19中，再结合加法计算法则可求出○表示的数，最后把☆和○表示的数相乘，求出积，即可解决.\n【详解】由☆+☆+☆=15和5+5+5=15，得☆=5;把☆=5代入到○+○+☆=19中，得○+○+5=19，则○+○=19-5=14，且7+7=14，故○=7;5×7=35，故☆*○=35。",
+        "knowledge_points":  [
+                                 "不退位减法(20 以内)",
+                                 "7,6 加几的进位加法",
+                                 "连加(20 以内)",
+                                 "7 的乘法口诀及应用"
+                             ],
+        "source":  "24-25 二年级上·甘肃庆阳·期末"
+    },
+    {
+        "id":  "42",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "在括号里填上\" \u003e \"\" \u003c \"或\" = \".\n\n7×6 ( ) 70;46 ( ) 29 + 17;47 - 12 ( ) 47 + 12;56 ( ) 6×5",
+        "options":  [
+
+                    ],
+        "answer":  "\u003c;=;\u003c;\u003e",
+        "solution":  "【分析】根据整数加减法的计算法则及表内乘法口诀，依次计算出各算式的结果再比较大小。比较时，位数多的数就大;位数相同比较最高位，最高位大的数就大;最高位相同比较下一位，直到比较出结果为止.\n【详解】7×6=42,42\u003c70，则7×6\u003c70;29+17=46，则46=29+17;47-12=35,47+12=59,35\u003c59，则47-12\u003c47+12;6×5=30,56\u003e30，则56\u003e6×5。",
+        "knowledge_points":  [
+                                 "100 以内数的比大小",
+                                 "两位数与两位数的进位加法",
+                                 "6的乘法口诀及应用",
+                                 "7的乘法口诀及应用"
+                             ],
+        "source":  "24-25 二年级上·广东江门·期末"
+    },
+    {
+        "id":  "43",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "一本笔记本 6 元，明明想买 7 本，可是还差 3 元，他带了( )元。",
+        "options":  [
+
+                    ],
+        "answer":  "39",
+        "solution":  "【分析】一本笔记本6元，先用乘法求出7本一共需要多少钱，再减去3元，求出差，即可解决.\n【详解】6×7-3=42-3=39(元),即一本笔记本6元，明明想买7本，可是还差3元，他带了39元。",
+        "knowledge_points":  [
+                                 "表内乘加，乘减"
+                             ],
+        "source":  "24-25 二年级上·福建福州·期末"
+    },
+    {
+        "id":  "44",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "体操队的同学在排练体操，竖着看每列有 5 人，横着看每行有 7 人，一共有()人在排练体操。",
+        "options":  [
+
+                    ],
+        "answer":  "35",
+        "solution":  "【分析】根据乘法的意义，用每列的人数乘每行的人数，即 5×7 即可得出一共有多少人.\n【详解】 5×7 = 35 (人),所以一共有35人在排练体操。",
+        "knowledge_points":  [
+                                 "7 的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·河北保定·期末"
+    },
+    {
+        "id":  "45",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "如图，一个小丑耍 5个球,3 个小丑耍( )个球,7 个小丑耍( )个球.\n\n![](images/bec8b7b6a36a7d736a960d22dc15efde6c107dcfb64c9bffa74ae7eff5b036b9.jpg)",
+        "options":  [
+
+                    ],
+        "answer":  "15;35",
+        "solution":  "【分析】要求 3 个小丑耍几个球，根据乘法的意义，用 3×5 或 5×3 即可得出答案。要求 7 个小丑耍几个球，根据乘法的意义，用 7×5 或 5×7 即可得出答案.\n【详解】 3×5 = 15(个),所以 3 个小丑耍 15 个球。7×5 = 35(个),所以7个小丑耍35个球。",
+        "knowledge_points":  [
+                                 "5 的乘法口诀及应用",
+                                 "7 的乘法口诀及应用"
+                             ],
+        "source":  "24-25 二年级上·河北保定·期末"
+    },
+    {
+        "id":  "46",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "下图中的木条长()厘米,6 根这样的木条连接起来长( )厘米.\n\n![](images/fcdadb1cec225e8952f89dac8a8c8b0315f9f5da37399f5c97c10c724352d3ef.jpg)",
+        "options":  [
+
+                    ],
+        "answer":  "7;42",
+        "solution":  "【分析】用直尺去测量物体的长度时，要把直尺上的\"0\"刻度线和物体的左端对齐，物体的右端对应数字是几，就表示这个物体有多长。若测量时，不是\"0\"刻度线与左侧对齐的话，就用测量结束的刻度减去测量起始的刻度即可。用每根木条的长度乘木条的根数，即可求出一共长多少厘米。用乘法列式计算即可.\n【详解】 8 - 1 = 7(厘米),7×6 = 42(厘米)下图中的木条长7厘米,6根这样的木条连接起来长42厘米。",
+        "knowledge_points":  [
+                                 "长度的测量方法",
+                                 "8,9的加减法",
+                                 "7的乘法口诀及应用"
+                             ],
+        "source":  "24-25 二年级上·河南开封·期末"
+    },
+    {
+        "id":  "47",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "一只蚂蚁6条腿,7只蚂蚁( )条腿。",
+        "options":  [
+
+                    ],
+        "answer":  "42",
+        "solution":  "【分析】根据题意，用每只蚂蚁腿的数量乘蚂蚁的只数，即可求出一共有多少条腿.\n【详解】 6×7 = 42(条),一只蚂蚁 6 条腿,7 只蚂蚁 42 条腿。",
+        "knowledge_points":  [
+                                 "7的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·河南开封·期末"
+    },
+    {
+        "id":  "48",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "春天到了，日照植物园里的花儿竞相开放。一朵七色花有 7 片花瓣,5 朵七色花有多少片花瓣。列乘法算式是( )×( ) = ( )(片),其中( )和( )是乘数,( )是积。",
+        "options":  [
+
+                    ],
+        "answer":  "7;5;35;7;5;35",
+        "solution":  "【分析】根据题意可知：求一共多少个花瓣，用一朵有的花瓣数量乘朵数即可。然后根据乘数×乘数=积，即可填空.\n【详解】7×5=35(片),则春天到了，日照植物园里的花儿竞相开放。一朵七色花有7片花瓣,5朵七色花有多少片花瓣。列乘法算式是7×5=35(片),其中7和5是乘数,35是积。",
+        "knowledge_points":  [
+                                 "7 的乘法口诀及应用"
+                             ],
+        "source":  "24-25 二年级上·山东日照·期末"
+    },
+    {
+        "id":  "49",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "6 个 4 相加，和是();2 和 7 相乘，积是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "24;14",
+        "solution":  "【分析】求几个相同加数的和，可以用乘法计算，用相同加数×个数或个数×相同加数;乘法算式为乘数×乘数=积,2和7相乘，也就是乘数是2和7，由此解答.\n【详解】6×4=24;2×7=14,6个4相加，和是24;2和7相乘，积是14。",
+        "knowledge_points":  [
+                                 "初步认识乘法意义",
+                                 "6 的乘法口诀及应用",
+                                 "7 的乘法口诀及应用"
+                             ],
+        "source":  "24-25 二年级上·广东江门·期末"
+    },
+    {
+        "id":  "50",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "![](images/2026-02-26%20162902.jpg)。像这样继续摆下去，摆第 4个图形需要( )个小正方形，摆第 7 个图形需要( )个小正方形。",
+        "options":  [
+
+                    ],
+        "answer":  "16;49",
+        "solution":  "【分析】由图可知：第1个图形中小正方形的个数为每行有1个，有1行，用1×1计算;第2个图形中小正方形的个数为每行有2个，有2行，用2×2计算;第3个图形中小正方形的个数为每行有3个，有3行，用3×3计算;则第4个图形中小正方形的个数为每行有4个，有4行，用4×4计算;第7个图形中小正方形的个数为每行有7个，有7行，用7×7计算.\n【详解】4×4=16(个),7×7=49(个)。像这样继续摆下去，摆第4个图形需要16个小正方形，摆第7个图形需要49个小正方形。",
+        "knowledge_points":  [
+                                 "3 的乘法口诀及应用",
+                                 "4 的乘法口诀及应用",
+                                 "7的乘法口诀及应用"
+                             ],
+        "source":  "23-24 二年级上·福建三明·期末"
+    },
+    {
+        "id":  "51",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "7 乘 5 等于 35 列式为( );其中乘数是( )和( ),积是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "7×5=35;7;5;35",
+        "solution":  "【分析】写乘法算式时，依次从左往右写，\"乘\"写作*,\"等于\"写作=,数字直接写出来。乘法算式中两个乘数是口诀中的前两个数，积是口诀中的后一个数，写算式时两个乘数可互换位置.\n【详解】7乘5等于35列式为:7×5=35;其中乘数是7和5，积是35。",
+        "knowledge_points":  [
+                                 "7 的乘法口诀及应用"
+                             ],
+        "source":  "23-24 二年级上·重庆丰都·期末"
+    },
+    {
+        "id":  "52",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "找规律填一填.\n\n7,14,( ),( ),35,( )。",
+        "options":  [
+
+                    ],
+        "answer":  "21;28;42",
+        "solution":  "【分析】这组数字依次为: 1×7 = 7;2×7 = 14;3×7 = 21;4×7 = 28;5×7 = 35;6×7 = 42，依次填写 21,28,42.\n【详解】填写如下:7,14,21,28,35,42。",
+        "knowledge_points":  [
+                                 "7 的乘法口诀及应用",
+                                 "整数排列的规律"
+                             ],
+        "source":  "24-25 二年级上·吉林四平·期末"
+    },
+    {
+        "id":  "53",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "二(1)班同学排成正方形的队伍参加表演。从前，后，左，右数，小明都是排第 4，参加表演的共有( )人。",
+        "options":  [
+
+                    ],
+        "answer":  "49",
+        "solution":  "【分析】从前数小明排第4, 4 - 1 = 3 (人),说明小明前面有 3 人;从后数小明也排第 4，说明小明后面也有 3 人,3 + 3 + 1 = 7 (人),加上小明一列共 7 人;同理可知一行也有 7 人;求一共有多少人，就是求 7 个 7 的和是多少，可以用乘法列式解决.\n【详解】 4 - 1 = 3 (人),3 + 3 + 1 = 7 (人),7×7 = 49 (人),即，二(1)班同学排成正方形的队伍参加表演。从前，后，左，右数，小明都是排第4，参加表演的共有49人。",
+        "knowledge_points":  [
+                                 "连加，连减(10 以内)",
+                                 "7 的乘法口诀及应用"
+                             ],
+        "source":  "23-24二年级上·河北保定·期末"
+    },
+    {
+        "id":  "54",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "6+6+6+6+6+6+6改写成乘法算式是( ),表示( )个( )相加的和。",
+        "options":  [
+
+                    ],
+        "answer":  "6×7=42或7×6=42;7;6",
+        "solution":  "【分析】几个相同加数相加，可以写成加数与个数相乘的形式。乘法算式中两个乘数是口诀中的前两个数，积是口诀中的后一个数，写算式时两个乘数可互换位置.\n【详解】6+6+6+6+6+6+6改写成乘法算式是6×7=42或7×6=42，表示7个6相加的和。",
+        "knowledge_points":  [
+                                 "同数连加的应用",
+                                 "7 的乘法口诀及应用"
+                             ],
+        "source":  "23-24 二年级上·广东韶关·期末"
+    },
+    {
+        "id":  "55",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "2+2+2+2+2+2+2=14，可以用( )法表示，写成( )。",
+        "options":  [
+
+                    ],
+        "answer":  "乘;7×2=14或2×7=14",
+        "solution":  "【分析】几个相同加数相加，可以写成加数与个数相乘的形式。乘法算式中两个乘数是口诀中的前两个数，积是口诀中的后一个数，写算式时两个乘数可互换位置.\n【详解】2+2+2+2+2+2+2=14，可以用乘法表示，写成7×2=14或2×7=14。",
+        "knowledge_points":  [
+                                 "同数连加的应用",
+                                 "7 的乘法口诀及应用"
+                             ],
+        "source":  "23-24 二年级上·重庆丰都·期末"
+    },
+    {
+        "id":  "56",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "7 + 7 + 7 + 5 = 7×( ) + 5 = 7×4 - ( )。",
+        "options":  [
+
+                    ],
+        "answer":  "3;2",
+        "solution":  "【分析】求几个相同加数的和，可以用乘法计算，用相同加数×个数或个数×相同加数。 7 + 7 + 7 + 5 可以表示3个7的和再加5，也可以表示4个7的和再减2，由此解答.\n【详解】由分析得:7 + 7 + 7 + 5 = 7×3 + 5 = 7×4 - 2 。",
+        "knowledge_points":  [
+                                 "表内乘加，乘减"
+                             ],
+        "source":  "23-24 二年级上·重庆秀山·期末"
+    },
+    {
+        "id":  "57",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "如果☆+8=17,○+○+○=21,☆-○=( )。",
+        "options":  [
+
+                    ],
+        "answer":  "2",
+        "solution":  "【分析】根据和-一个加数=另一个加数，求出☆代表的数。求几个相同加数的和可以用乘法计算，用相同加数×个数或个数×相同加数，三个○的和是21，也就是3*○=21，根据乘法口诀求出○代表的数，再代入到☆-○中，计算出结果即可.\n【详解】☆+8=17，则17-8=9,☆=9;○+○+○=21,3*○=21，根据乘法口诀三七二十一可知,3×7=21，即○=7;☆-○=9-7=2。",
+        "knowledge_points":  [
+                                 "8,9的加减法",
+                                 "十几减8的退位减法",
+                                 "7的乘法口诀及应用"
+                             ],
+        "source":  "23-24 二年级上·湖南湘西·期末"
+    },
+    {
+        "id":  "58",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "一个星期有 7 天,3个星期有( )天,6 个星期有( )天。",
+        "options":  [
+
+                    ],
+        "answer":  "21;42",
+        "solution":  "【分析】3个星期的天数也就是3个7的和,6个星期的天数也就是6个7的和，分别用乘法计算，每个星期的天数和星期数相乘，就是总天数.\n【详解】 7×3 = 21(天),7×6 = 42(天),一个星期有 7 天,3 个星期有 21 天,6 个星期有 42 天。",
+        "knowledge_points":  [
+                                 "7的乘法口诀及应用"
+                             ],
+        "source":  "23-24 二年级上·河南安阳·期末"
+    },
+    {
+        "id":  "59",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "找规律填数.\n\n7,14,21,( ),( ),42,49。",
+        "options":  [
+
+                    ],
+        "answer":  "28;35",
+        "solution":  "【分析】该组规律为：数字从左到右依次加 7.\n【详解】 7 + 7 = 14 , 14 + 7 = 21 , 21 + 7 = 28 ,28 + 7 = 35, 35 + 7 = 42 , 42 + 7 = 49。填数如下:7,14,21,(28),(35),42,49。",
+        "knowledge_points":  [
+                                 "两位数与一位数的加法(不进位)",
+                                 "一位数与两位数的进位加法",
+                                 "7的乘法口诀及应用",
+                                 "整数排列的规律"
+                             ],
+        "source":  "23-24 二年级上·云南红河·期末"
+    },
+    {
+        "id":  "60",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在括号里填上\" \u003e \"\" \u003c \"或\" = \".\n\n26( )17 + 18;31 - 8( ) 3×7;99 厘米( )99 米",
+        "options":  [
+
+                    ],
+        "answer":  "\u003c;\u003e;\u003c",
+        "solution":  "【分析】算式先计算出各算式的答案，然后比较大小即可。单位不统一的，根据1米=100厘米将单位换算统一，再比较。整数比较大小，位数多的，该数就大，数位相同，就看最高位上的数，若最高位上大该数就大，若最高位数字相同，依次看下一位即可.\n【详解】17+18=35,26\u003c35，则26\u003c17+18;31-8=23,3×7=21,23\u003e21，则31-8\u003e3×7;1米=100厘米,99\u003c100，则99厘米\u003c99米。",
+        "knowledge_points":  [
+                                 "100以内数的比大小",
+                                 "两位数与两位数的进位加法",
+                                 "7的乘法口诀及应用",
+                                 "厘米和米之间的进率与换算"
+                             ],
+        "source":  "23-24 二年级上·云南红河·期末"
+    },
+    {
+        "id":  "61",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "括号里最大能填几。\n\n( )×4 \u003c 25;( ) - 6 \u003c 32;10 \u003e ( )×2\n20 \u003e ( )×5;( )×3 \u003c 15;5 + ( ) \u003c 22",
+        "options":  [
+
+                    ],
+        "answer":  "6;37;4;3;4;16",
+        "solution":  "【分析】第1,3,4,5题根据含有小于号左侧或大于号右侧已知数的乘法口诀，找出结果小于且最接近另一侧数的即可;第2题：比32小的数有31,30,29。其中最大的是31，则左侧算式结果为31即可，根据减数 + 差 = 被减数计算;第6题：比22小的数有21,20,19。其中最大的是21，则左侧算式结果为21即可，根据和 - 一个加数 = 另一个加数计算.\n【详解】 6×4 = 24 \u003c 25;7×4 = 28 \u003e 25，括号里最大能填 6;( ) - 6 = 31 , 6 + 31 = 37，则 37 - 6 \u003c 32，括号里最大能填 37;10 \u003e 4×2 = 8;10 = 5×2;10 \u003c 6×2 = 12，括号里最大能填4;20 \u003e 3×5 = 15;20 = 4×5;20 \u003c 5×5 = 25，括号里最大能填3;4×3 = 12 \u003c 15;5×3 = 15;6×3 = 18 \u003e 15，括号里最大能填4;5 + ( ) = 21 , 21 - 5 = 16，则 5 + 16 \u003c 22，括号里最大能填 16。",
+        "knowledge_points":  [
+                                 "100以内数的比大小",
+                                 "一位数与两位数的退位减法",
+                                 "6的乘法口诀及应用",
+                                 "7的乘法口诀及应用"
+                             ],
+        "source":  "24-25 二年级上·江西宜春·期中"
+    },
+    {
+        "id":  "62",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "括号里最大能填几。\n\n( )×4\u003c25;30-( )\u003e15;23+( )\u003c29;6×( )\u003c32",
+        "options":  [
+
+                    ],
+        "answer":  "6;14;5;5",
+        "solution":  "【分析】根据表内乘法口诀及整数加减法的计算法则和整数比较大小的方法来解决此题即可.\n【详解】6×4=24,7×4=28,24\u003c25\u003c28，故,6×4\u003c25;30-15=15,15-1=14,30-14=16,16\u003e15，故,30-14\u003e15;29-23=6,6-1=5,23+5=28,28\u003c29，故,23+5\u003c29;6×5=30,6×6=36,30\u003c32\u003c36，故,6×5\u003c32。",
+        "knowledge_points":  [
+                                 "100 以内数的比大小",
+                                 "两位数与两位数的退位减法",
+                                 "6 的乘法口诀及应用",
+                                 "7 的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·福建泉州·期中"
+    },
+    {
+        "id":  "63",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "6×7 - 6 = 7×5。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】6×7-6表示7个6的和减去1个6的差是多少,7×5表示7个5的和是多少，据此先算出各个算式的得数，再进行解答即可.\n【详解】6×7-6=42-6=36;7×5=35,36\u003e35，所以原题说法错误。故答案为: ×",
+        "knowledge_points":  [
+                                 "7的乘法口诀及应用",
+                                 "表内乘加，乘减"
+                             ],
+        "source":  "24-25 二年级上·云南保山·期末"
+    },
+    {
+        "id":  "64",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "计算 6×7 和 7×6 时用同一句乘法口诀\"六七四十二\"。( )",
+        "options":  [
+
+                    ],
+        "answer":  "√",
+        "solution":  "【分析】根据乘法口诀计算时，乘法算式中两个乘数(可交换位置)是口诀中的前两个数，积是口诀中后一个数，据此判断即可.\n【详解】计算 6×7 和 7×6 时用同一句乘法口诀\"六七四十二\"。原说法正确。故答案为:√",
+        "knowledge_points":  [
+                                 "7的乘法口诀及应用"
+                             ],
+        "source":  "24-25 二年级上·湖南株洲·期末"
+    },
+    {
+        "id":  "65",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "在乘法算式中，一个乘数是 3，另一个乘数是 7，这两个数的积是 10。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】根据\"乘数×乘数=积\"及乘法口诀来解决此题.\n【详解】3×7=21，即，在乘法算式中，一个乘数是3，另一个乘数是7，这两个数的积是21。原题说法错误。故答案为: ×",
+        "knowledge_points":  [
+                                 "7 的乘法口诀及应用"
+                             ],
+        "source":  "24-25 二年级上·陕西延安·期末"
+    },
+    {
+        "id":  "66",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "判断题",
+        "difficulty":  0.65,
+        "question":  "3×6 + 3 可以当作3×7 计算。( )",
+        "options":  [
+
+                    ],
+        "answer":  "√",
+        "solution":  "【分析】根据题意 3×6 + 3 可以表示 6 个 3 加上 1 个 3，是 7个 3，即 7×3.\n【详解】 3×6 + 3 表示6个3加上1个3，是7个3，即7×3，所以 3×6 + 3 可以当作 3×7 计算。故答案为:√",
+        "knowledge_points":  [
+                                 "6的乘法口诀及应用",
+                                 "7的乘法口诀及应用"
+                             ],
+        "source":  "24-25 二年级上·四川广元·期末"
+    },
+    {
+        "id":  "67",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "判断题",
+        "difficulty":  0.65,
+        "question":  "每层楼高 4 米，小明站在他家 8 楼阳台上，他距离地面 28 米。( )",
+        "options":  [
+
+                    ],
+        "answer":  "√",
+        "solution":  "【分析】小明站在他家8楼阳台上，说明他家下面有7层，每层楼高4米，求他站在家的阳台上距离地面多少米，就是求7个4的和是多少，用乘法列式解决即可.\n【详解】 8 - 1 = 7 (层),7×4 = 28(米),即，每层楼高4米，小明站在他家8楼阳台上，他距离地面28米。此说法正确。故答案为:√",
+        "knowledge_points":  [
+                                 "7的乘法口诀及应用"
+                             ],
+        "source":  "24-25 二年级上·河南南阳·期末"
+    },
+    {
+        "id":  "68",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "2 个 7 相加的和是9。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】求几个相同数连加的和，可用乘法计算.\n【详解】2×7=14，则2个7相加的和是14，则原题说法错误。故答案为: ×",
+        "knowledge_points":  [
+                                 "同数连加的应用",
+                                 "7的乘法口诀及应用"
+                             ],
+        "source":  "24-25 二年级上·吉林四平·期末"
+    },
+    {
+        "id":  "69",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "求5个7相加的和是多少，列式是 5 + 7。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】根据题意可知：求几个相同数连加的和，可以用乘法表示，列式为: 5×7 或 7×5.\n【详解】求 5 个 7 相加的和是多少，列式是 5×7 或 7×5 。原题说法错误。故答案为: ×",
+        "knowledge_points":  [
+                                 "同数连加的应用",
+                                 "7的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·河北秦皇岛·期末"
+    },
+    {
+        "id":  "70",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "5 与 7 的和是 12,5个 7 的和是 35。( )",
+        "options":  [
+
+                    ],
+        "answer":  "√",
+        "solution":  "【分析】5与7的和，也就是一个加数是5，另一个加数是7，用加法计算;求几个相同加数的和，可以用乘法计算，用相同加数×个数或个数×相同加数，也就是5个7的和用5和7相乘，由此解答.\n【详解】 5 + 7 = 12;5×7 = 35,5 与 7 的和是 12,5 个 7 的和是 35。原题说法正确。故答案为:√",
+        "knowledge_points":  [
+                                 "5 ~ 2 加几的进位加法",
+                                 "7 的乘法口诀及应用"
+                             ],
+        "source":  "23-24 二年级上·四川德阳·期末"
+    },
+    {
+        "id":  "71",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "1 袋饼干 7 元，妈妈买 3 袋饼干，带 20 元就够了。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】买3袋饼干需要的钱数也就是3个7的和，用乘法计算，每袋饼干的钱数和袋数相乘，就是总钱数，再和20元比较大小。需要的总钱数大于20元不够，小于或等于20元够.\n【详解】 7×3 = 21(元),21 \u003e 20,1袋饼干7元，妈妈买3袋饼干，带20元不够，原题说法错误。故答案为: ×",
+        "knowledge_points":  [
+                                 "100 以内数的比大小",
+                                 "7 的乘法口诀及应用"
+                             ],
+        "source":  "24-25 二年级上·河南周口·期中"
+    },
+    {
+        "id":  "72",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "5 与 7 相乘的积的个位上是 5。( )",
+        "options":  [
+
+                    ],
+        "answer":  "√",
+        "solution":  "【分析】一个整数，从右往左依次为个位，十位。乘法算式为：乘数×乘数 = 积,5与7相乘，也就是两个乘数分别是 5 和 7，由此计算出结果解答即可.\n【详解】 5×7 = 35,5与7相乘的积的个位上是5。原题说法正确。故答案为:√",
+        "knowledge_points":  [
+                                 "100以内数的组成",
+                                 "7的乘法口诀及应用"
+                             ],
+        "source":  "24-25 二年级上·河南周口·期中"
+    },
+    {
+        "id":  "73",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "判断题",
+        "difficulty":  0.65,
+        "question":  "一盒维生素C有20片，每天吃 3 片，这盒维生素 C 可以吃一个星期。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】一个星期是7天，先根据乘法的意义，用每天吃的片数 * 7 求出吃1个星期需要维生素C的片数，再与20片比较即可.\n【详解】 3×7 = 21(片),21 片 \u003e 20 片，所以一盒维生素C有20片，每天吃3片，这盒维生素C不可以吃一个星期，原题说法错误。故答案为: ×",
+        "knowledge_points":  [
+                                 "7 的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·河南郑州·期中"
+    },
+    {
+        "id":  "74",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "计算题",
+        "difficulty":  0.85,
+        "question":  "看图把算式补充完整.\n\n![](images/a15eb4538eb64fdae9d6bfef4df9d227d2fa1202c16f493a269576cae069eae4.jpg)\n\n□○□=□(米)",
+        "options":  [
+
+                    ],
+        "answer":  "2×7=14",
+        "solution":  "【分析】数一数每两个花之间有多少个间隔，数出一共有7个间隔，间隔数乘2等于一共有多少米.\n【详解】2×7=14(米),一共有14米。",
+        "knowledge_points":  [
+                                 "7的乘法口诀及应用",
+                                 "植树问题(两端都栽)"
+                             ],
+        "source":  "24-25二年级上·河南郑州·期末"
+    },
+    {
+        "id":  "75",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "计算题",
+        "difficulty":  0.65,
+        "question":  "看图列式计算.\n\n![](images/363fc4bb2d52a2bc64298f4762053ed7079972d9f322fc551cbdbdf576ce9f1f.jpg)\n\n□○□○□=□(个)",
+        "options":  [
+
+                    ],
+        "answer":  "7×4+5=33或7×5-2=33",
+        "solution":  "【分析】每串有7个，有这样的4串，还多5个，则总数量为4个7的和再加5，即每串的数量7个×串数4串+多的数量5个;也可以看成每串有7个，有5串，再减去多算的2个，则总数量为5个7的和再减2，即每串的数量7个×串数5串-多算的数量2个，由此解答.\n【详解】7×4+5=28+5=33(个);7×5-2=35-2=33(个),一共有33个。",
+        "knowledge_points":  [
+                                 "图文问题",
+                                 "表内乘加，乘减"
+                             ],
+        "source":  "23-24二年级上·河北保定·期末"
+    },
+    {
+        "id":  "76",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "一本故事书有 45 页，小红每天看5页，一周能看完吗。(一周按7天算)",
+        "options":  [
+
+                    ],
+        "answer":  "看不完",
+        "solution":  "【分析】先用每天看的页数乘看的天数，求出一周一共能看多少页，再和书的总页数进行比较，如果一周看的页数等于或大于书的总页数，那么一周就能看完;如果一周看的页数小于书的总页数，那么一周就不能看完.\n【详解】5×7=35(页),35\u003c45，答：每天看5页，一周看不完。",
+        "knowledge_points":  [
+                                 "100 以内数的比大小",
+                                 "7 的乘法口诀及应用"
+                             ],
+        "source":  "24-25 二年级下·湖南长沙·期中"
+    },
+    {
+        "id":  "77",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "同学们去郊游，租了5辆面包车，每辆面包车上坐了7人。所有人上车后还有3个空位。这次一共去了多少人。",
+        "options":  [
+
+                    ],
+        "answer":  "32人",
+        "solution":  "【分析】根据题意可知，每辆面包车可乘的人数乘面包车的数量，再减去3个空位，等于这次一共去的人数，据此解答即可.\n【详解】根据分析可得:5×7 - 3 = 35 - 3 = 32(人),答：这次一共去了32人。",
+        "knowledge_points":  [
+                                 "7 的乘法口诀及应用",
+                                 "表内乘加，乘减"
+                             ],
+        "source":  "24-25二年级上·云南保山·期末"
+    },
+    {
+        "id":  "78",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "二(2)班全体学生上体育课，体育委员发现有3名同学没有到，来了的人正好排成 6 行，每行 7 人。二(2)班实际有多少人。",
+        "options":  [
+
+                    ],
+        "answer":  "45人",
+        "solution":  "【分析】根据题意，先用每行的人数和行数相乘，求出6行共有多少人，再加上没到的人数，就是二(2)班实际的总人数.\n【详解】7×6+3=42+3=45(人),答：二(2)班实际有45人。",
+        "knowledge_points":  [
+                                 "表内乘加，乘减"
+                             ],
+        "source":  "24-25二年级上·湖南株洲·期末"
+    },
+    {
+        "id":  "79",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "一本绘本故事书有38页，小红每天看5页，一个星期能看完吗。",
+        "options":  [
+
+                    ],
+        "answer":  "不能",
+        "solution":  "【分析】一个星期有7天，则用每天看的页数和看的天数相乘，求出 7 天可以看多少页，再和书的总页数比较大小。7天可以看的页数大于或等于书的总页数能看完，小于书的总页数看不完.\n【详解】 5×7 = 35(页),35 \u003c 38，答：一个星期不能看完。",
+        "knowledge_points":  [
+                                 "100以内数的比大小",
+                                 "7的乘法口诀及应用"
+                             ],
+        "source":  "24-25 二年级上·安徽黄山·期末"
+    },
+    {
+        "id":  "80",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "一共有多少米。\n\n![](images/0b0db6928ff19bb5b82fa6b7f007e3aca66c83b386b108d198e5c98643f6e086.jpg)\n\n□○□=□(米)",
+        "options":  [
+
+                    ],
+        "answer":  "5×7=35",
+        "solution":  "【分析】数一数每两个气球之间有多少个间隔，有7个间隔，间隔数乘5等于一共多少米.\n【详解】5×7=35(米),答：一共有35米。",
+        "knowledge_points":  [
+                                 "7 的乘法口诀及应用",
+                                 "植树问题(两端都栽)"
+                             ],
+        "source":  "24-25 二年级上·江西鹰潭·期末"
+    },
+    {
+        "id":  "81",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "7 组小朋友做游戏，每组有 5 人，一共有多少人。",
+        "options":  [
+
+                    ],
+        "answer":  "35人",
+        "solution":  "【分析】用做游戏的组数乘每组的小朋友人数，即可求出总人数，据此解答.\n【详解】 7×5 = 35(人),答：一共有35人。",
+        "knowledge_points":  [
+                                 "7 的乘法口诀及应用"
+                             ],
+        "source":  "24-25 二年级上·青海西宁·期末"
+    },
+    {
+        "id":  "82",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "王老师带着 30 位同学去公园划船，每条船可以坐4人,7条船够吗。",
+        "options":  [
+
+                    ],
+        "answer":  "不够",
+        "solution":  "【分析】每条船可以坐4人，先用乘法求出7条船一共可以坐几人;然后用加法算出老师和学生一共有几人，最后比较大小，即可解决.\n【详解】 4×7 = 28(人),30 + 1 = 31(人),28 \u003c 31，答:7 条船不够。",
+        "knowledge_points":  [
+                                 "100 以内数的比大小",
+                                 "整十数加，减一位数",
+                                 "7的乘法口诀及应用"
+                             ],
+        "source":  "23-24 二年级上·浙江杭州·期末"
+    },
+    {
+        "id":  "83",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "二(3)班同学，排成一个方阵做操，从前，后，左，右数时，梅梅都排在第4个，做操的同学一共有多少个。",
+        "options":  [
+
+                    ],
+        "answer":  "49个",
+        "solution":  "【分析】从左，右数，梅梅都排在第4个，则每一行的人数是(4+4-1)个;从前，后数，梅梅也都排在第4个，则每一列的人数也是(4+4-1)个;最后把行数与列数乘起来，求出积，就是一共的做操学生数量.\n【详解】4+4-1=8-1=7(个);7×7=49(个),答：做操的同学一共有49个。",
+        "knowledge_points":  [
+                                 "加减混合运算(10 以内)",
+                                 "7 的乘法口诀及应用"
+                             ],
+        "source":  "23-24 二年级上·浙江杭州·期末"
+    },
+    {
+        "id":  "84",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "丽丽想存钱给妈妈买一盒 40 元的巧克力作为生日礼物，她计划每天存 6 元，存一个星期的钱够吗。",
+        "options":  [
+
+                    ],
+        "answer":  "够",
+        "solution":  "【分析】一个星期有7天，用6乘7得到一个星期存的总钱数，用存的总钱数与40作比较，大于等于40则钱够，小于40则钱不够.\n【详解】 6×7 = 42(元),42 元 \u003e 40 元，答：存一个星期的钱够。",
+        "knowledge_points":  [
+                                 "100以内数的比大小",
+                                 "7的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·湖南娄底·期末"
+    },
+    {
+        "id":  "85",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "王老师带儿子小明去书店买书。小明买了一本《趣味语文》和一本《看图说话》,小明一共花了多少钱。王老师买了 6 本《趣味数学》,王老师一共花了多少钱。\n\n\u003ctable\u003e\u003ctr\u003e\u003ctd\u003e趣味数学\u003c/td\u003e\u003ctd\u003e趣味语文\u003c/td\u003e\u003ctd\u003e看图说话\u003c/td\u003e\u003c/tr\u003e\u003ctr\u003e\u003ctd\u003e7\u003c/td\u003e\u003ctd\u003e8\u003c/td\u003e\u003ctd\u003e5\u003c/td\u003e\u003c/tr\u003e\u003c/table\u003e",
+        "options":  [
+
+                    ],
+        "answer":  "13元;42元",
+        "solution":  "【分析】把一本《趣味语文》和一本《看图说话》的钱数相加求出小明一共花的钱数;用一本《趣味数学》的钱数乘买的本数，即可求出王老师一共花的钱数.\n【详解】 8 + 5 = 13(元),7×6 = 42 (元),答：小明一共花了 13 元，王老师一共花了 42 元。",
+        "knowledge_points":  [
+                                 "8加几的进位加法",
+                                 "7的乘法口诀及应用"
+                             ],
+        "source":  "23-24 二年级上·浙江·期末"
+    },
+    {
+        "id":  "86",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "奶奶把买来的橘子装在盘子里，每盘装 7 个，装了 5 盘刚好装完。奶奶一共买了多少个橘子。",
+        "options":  [
+
+                    ],
+        "answer":  "35个",
+        "solution":  "【分析】每盘装7个橘子，装了5盘刚好装完，求一共有多少个橘子，就是求5个7的和是多少，用乘法列式解决.\n【详解】 7×5 = 35(个),答：奶奶一共买了35个橘子。",
+        "knowledge_points":  [
+                                 "7的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·广东江门·期末"
+    },
+    {
+        "id":  "87",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "小米和 6 个小朋友一起去游乐园玩。每张门票 6 元，一共需要多少元。",
+        "options":  [
+
+                    ],
+        "answer":  "42元",
+        "solution":  "【分析】先用加法算出一共有几个小朋友，再用人数乘每张门票的价钱即可求解.\n【详解】 1 + 6 = 7 (个),7×6 = 42 (元),答：一共需要 42 元。",
+        "knowledge_points":  [
+                                 "经济问题",
+                                 "7的乘法口诀及应用"
+                             ],
+        "source":  "24-25 二年级上·河南周口·期末"
+    },
+    {
+        "id":  "88",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "8岁的晨晨和他的5位好朋友去动物园玩，儿童票每人 7 元，他们买票一共要花多少元。",
+        "options":  [
+
+                    ],
+        "answer":  "42元",
+        "solution":  "【分析】根据8岁的晨晨和他的5位好朋友去动物园玩，先用加法计算出一共有几人，再用每张儿童票的价格和人数相乘，就是买门票一共要花的钱数.\n【详解】 5 + 1 = 6(人),7×6 = 42 (元),答：他们买票一共要花 42 元。",
+        "knowledge_points":  [
+                                 "7的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·河北保定·期末"
+    },
+    {
+        "id":  "89",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "小林家阳台上的地砖，横着看每行7块，竖着看每列5块，一共铺了多少块地砖。",
+        "options":  [
+
+                    ],
+        "answer":  "35块",
+        "solution":  "【分析】要求一共铺了多少块地砖，根据乘法的意义，用横着看每行的块数乘竖着看每列的块数解答即可.\n【详解】 7×5 = 35(块),答：一共铺了35块地砖。",
+        "knowledge_points":  [
+                                 "7 的乘法口诀及应用"
+                             ],
+        "source":  "23-24 二年级上·新疆昌吉·期末"
+    },
+    {
+        "id":  "90",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "这些鸡蛋够兰兰家吃 7 天吗。\n\n![](images/dfed7432e0844f2dca3f070cd5b3e557534f32b8b9fa87944270b8bb58b59041.jpg)",
+        "options":  [
+
+                    ],
+        "answer":  "够",
+        "solution":  "【分析】根据题意，先用兰兰家每天吃鸡蛋的数量和吃的天数相乘，求出7天一共要吃多少个鸡蛋，再和28比较大小。一共要吃的数量大于 28 个不够，小于或等于 28 个够.\n【详解】 4×7 = 28(个),28 = 28，答：这些鸡蛋够兰兰家吃 7 天。",
+        "knowledge_points":  [
+                                 "图文问题",
+                                 "100 以内数的比大小",
+                                 "7 的乘法口诀及应用"
+                             ],
+        "source":  "23-24 二年级上·河北保定·期末"
+    },
+    {
+        "id":  "91",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "一共有多少个山楂。\n\n![](images/d3502a5ec2e5d1bcac778e296135571f88b9ac70f0d1a683e2cc8735c42dab71.jpg)\n\n□○□○□=□(个)",
+        "options":  [
+
+                    ],
+        "answer":  "7×3+4=25",
+        "solution":  "【分析】左边3串每串7个，用乘法算出有多少个，然后加上另外的4个即可.\n【详解】7×3+4=21+4=25(个),答：一共有25个山楂。",
+        "knowledge_points":  [
+                                 "图文问题",
+                                 "7的乘法口诀及应用",
+                                 "表内乘加，乘减"
+                             ],
+        "source":  "23-24 二年级上·河北保定·期末"
+    },
+    {
+        "id":  "92",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "有 37 位乘客,7 辆车能坐得下吗。\n\n![](images/d91be0d8ff8ee330d95b5c4ce0c6068f31734852e8782042dc98cb39c27737a3.jpg)",
+        "options":  [
+
+                    ],
+        "answer":  "能",
+        "solution":  "【分析】每辆车最多坐6位乘客，先用乘法求出7辆车最多能坐下几位乘客，然后与乘客人数比较大小，即可解决.\n【详解】 6×7 = 42(位),42 \u003e 37，答:7辆车能坐得下。",
+        "knowledge_points":  [
+                                 "100以内数的比大小",
+                                 "7的乘法口诀及应用"
+                             ],
+        "source":  "23-24 二年级上·广东韶关·期末"
+    },
+    {
+        "id":  "93",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "这本书一共有多少页。\n\n![](images/2026-02-26%20165607.jpg)",
+        "options":  [
+
+                    ],
+        "answer":  "84页",
+        "solution":  "【分析】已知每天看7页，看了7天，可用每天看的页数乘天数即可得出一周一共看了多少页，再加上剩下的35页即可得出一共多少页.\n【详解】据分析可得:7×7 + 35= 49 + 35= 84 (页),答：这本书一共有84页。",
+        "knowledge_points":  [
+                                 "7的乘法口诀及应用",
+                                 "乘加，乘减混合运算"
+                             ],
+        "source":  "23-24二年级上·河北石家庄·期末"
+    },
+    {
+        "id":  "94",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "在\"书香阅读活动\"中，张华坚持每天背诵3首古诗，他一个星期(7天)能背诵多少首古诗。",
+        "options":  [
+
+                    ],
+        "answer":  "21首",
+        "solution":  "【分析】求一个星期背诵古诗的数量，也就是求7个3的和是多少，用乘法计算，即每天背诵古诗的数量和天数相乘，就是背诵的总数量.\n【详解】 3×7 = 21(首),答：他一个星期(7天)能背诵21首古诗。",
+        "knowledge_points":  [
+                                 "7的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·广东梅州·期中"
+    },
+    {
+        "id":  "95",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "图书角里有图书 40本，小明，小英等7人，每人都借走了5本，一共借走了多少本。",
+        "options":  [
+
+                    ],
+        "answer":  "35本",
+        "solution":  "【分析】根据题意可知：求一共借走的数量，用每人借走的数量乘共有的人数即可.\n【详解】 5×7 = 35(本),答：一共借走了 35 本。",
+        "knowledge_points":  [
+                                 "7的乘法口诀及应用"
+                             ],
+        "source":  "23-24 二年级上·福建福州·期末"
+    },
+    {
+        "id":  "96",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "一卷铁丝剪下 7 段，每段长 3 米，还剩下 2 米。这卷铁丝原来有多少米。",
+        "options":  [
+
+                    ],
+        "answer":  "23米",
+        "solution":  "【分析】据题意，铁丝每段长3米，一共有7段，用每段的长度乘总的段数再加上剩下的2米即可得出铁丝原来有多少米.\n【详解】 7×3 + 2 = 21 + 2 = 23 (米),答：这卷铁丝原来有23米。",
+        "knowledge_points":  [
+                                 "7 的乘法口诀及应用",
+                                 "表内乘加，乘减"
+                             ],
+        "source":  "23-24 二年级上·重庆云阳·期末"
+    },
+    {
+        "id":  "97",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "一套《寓言故事》共有7本，每本6元。小明买一套，需要多少钱。",
+        "options":  [
+
+                    ],
+        "answer":  "42元",
+        "solution":  "【分析】已知一本的价格是6元，一套里面有7本，用一本的价格乘总的本数即可得出一共需要多少钱.\n【详解】6×7=42(元),答：小明买一套，需要42元。",
+        "knowledge_points":  [
+                                 "7的乘法口诀及应用"
+                             ],
+        "source":  "23-24 二年级上·河南安阳·期末"
+    },
+    {
+        "id":  "98",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "中国四大名著是《水浒传》,《三国演义》,《西游记》,《红楼梦》。张老师买了 7 套四大名著，他一共买了多少本。\n\n![](images/94e937335a160f17430807f893cf4355fb0edc32f8d4f4cc24332d1837b32ce3.jpg)",
+        "options":  [
+
+                    ],
+        "answer":  "28本",
+        "solution":  "【分析】根据题意可知，一套是4本，买了7套，求一共买了多少本，也就是求7个4的和是多少，用乘法计算，每套的本数和套数相乘，就是总本数.\n【详解】 4×7 = 28(本),答：他一共买了28本。",
+        "knowledge_points":  [
+                                 "7 的乘法口诀及应用"
+                             ],
+        "source":  "24-25 二年级上·河南周口·期中"
+    },
+    {
+        "id":  "99",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "董叔叔去上海出差了3周，你知道他一共出差多少天吗。",
+        "options":  [
+
+                    ],
+        "answer":  "21天",
+        "solution":  "【分析】一周是 7 天，董叔叔去上海出差了 3 周，一共的天数就是 3 个 7 相加，列出乘法算式计算即可.\n【详解】根据分析可知, 3×7 = 21(天),答：他一共出差 21 天。",
+        "knowledge_points":  [
+                                 "7的乘法口诀及应用"
+                             ],
+        "source":  "24-25 二年级上·山东济南·期中"
+    },
+    {
+        "id":  "100",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "一辆\n\n![](images/629c72e1710f40365d15448e35973b210ec37226dd710e7db3e50115b022faec.jpg)\n\n有 4 个车轮,7 辆车有几个车轮。",
+        "options":  [
+
+                    ],
+        "answer":  "28个",
+        "solution":  "【分析】根据乘法的意义，用1辆车有车轮的数量 * 7 即可求出7辆车有车轮的数量，据此解答即可.\n【详解】 4×7 = 28 (个),答:7辆车有28个车轮。",
+        "knowledge_points":  [
+                                 "7的乘法口诀及应用"
+                             ],
+        "source":  "23-24 二年级上·山东济南·期中"
+    },
+    {
+        "id":  "101",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "□*8\u003c72,□内最大能填( )。",
+        "options":  [
+                        "A. 6",
+                        "B. 7",
+                        "C. 9",
+                        "D. 8"
+                    ],
+        "answer":  "D",
+        "solution":  "【分析】根据乘法口诀及整数比较大小的方法解答即可;根据乘法口诀计算结果，乘法算式中两个乘数(可交换位置)是口诀中的前两个数，积是口诀中的后一个数;比较数的大小，先看位数的多少，位数多的数就大;如果位数相同，从最高位开始比较，最高位上的数大则这个数大，最高位上的数相同，就比较下一位，依次类推.\n【详解】因为8×8=64,9×8=72，所以8×8\u003c72,□内最大能填8。故答案为:D",
+        "knowledge_points":  [
+                                 "100以内数的比大小",
+                                 "8的乘法口诀及应用",
+                                 "9的乘法口诀及应用"
+                             ],
+        "source":  "23-24二年级下·福建龙岩·期末"
+    },
+    {
+        "id":  "102",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "二年级买了8包笔记本，一共有多少本。解决这个问题，横线上还需要补充( )。",
+        "options":  [
+                        "A. 每个班分6包",
+                        "B. 老师又买来27本",
+                        "C. 笔记本比铅笔多9包",
+                        "D. 每包有7本"
+                    ],
+        "answer":  "D",
+        "solution":  "【分析】根据题意，买了8包笔记本，要求一共有多少本，则需要知道的是每包里面有几本，用每包的本数和包数相乘，就是总本数.\n【详解】A。每个班分6包，不能计算出总本数;B。老师又买来27本，不知道原有的本数，不能计算出总本数;C。笔记本比铅笔多9包，铅笔的数量与笔记本的数量无关，不能计算出总本数;D。每包有7本，则7×8=56(本),一共有56本。解决这个问题，横线上还需要补充每包有7本。故答案为:D",
+        "knowledge_points":  [
+                                 "\"提问题\"\"填条件\"问题",
+                                 "8的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级下·福建龙岩·期中"
+    },
+    {
+        "id":  "103",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "下面算式中，积是18的是( )。",
+        "options":  [
+                        "A. 3×5",
+                        "B. 2×9",
+                        "C. 6×4"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】根据选项中给出的乘法算式，根据乘法口诀计算出结果，选择结果是18的即可得出答案.\n【详解】A。3×5=15，不符合题意;B。2×9=18，符合题意;C。6×4=24，不符合题意。故答案为:B",
+        "knowledge_points":  [
+                                 "5的乘法口诀及应用",
+                                 "6的乘法口诀及应用",
+                                 "9的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级下·湖南岳阳·期中"
+    },
+    {
+        "id":  "104",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "学校开展夺星活动，小远获得了8颗星，迎迎所获星的颗数比小远的3倍多,4倍少。迎迎最少获得多少颗星。最多获得多少颗星。下面的结果正确的是( )。",
+        "options":  [
+                        "A. 25;33",
+                        "B. 23;33",
+                        "C. 25;31"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】由题意可知，迎迎所获星的颗数比小远的3倍多，小远获得了8颗星，那么迎迎最少获得的星数就是小远星数的3倍再多1颗，即8×3+1 = 25(颗);迎迎所获星的颗数比小远的4倍少，那么迎迎最多获得的星数就是小远星数的4倍再少1颗，即8×4-1 = 31(颗).\n【详解】由分析可知:8×3+1=24+1=25(颗),8×4-1=32-1=31(颗),迎迎最少获得25颗星，最多获得31颗星。故答案为:C",
+        "knowledge_points":  [
+                                 "8的乘法口诀及应用",
+                                 "表内乘加，乘减"
+                             ],
+        "source":  "24-25二年级上·河南周口·期末"
+    },
+    {
+        "id":  "105",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "妈妈微信\"钱包\"有100元，除夕那天发出6个红包，每个9元，后来她又抢了15元。下列说法正确的是()。",
+        "options":  [
+                        "A. ①妈妈发完红包后还剩54元。",
+                        "B. ②抢了红包后微信\"钱包\"有61元。",
+                        "C. ③如果买五碗馄饨只需要50元。",
+                        "D. ④妈妈今天支出的钱是64元。"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】根据题意，除夕那天发出6个红包，每个9元，可以用乘法算出发的红包，接着用减法算出还剩的钱;又抢了15元，再用加法就可以算出微信钱包现有多少钱.\n【详解】根据分析可得:100-6×9=100-54=46(元),妈妈发完红包后还剩46元，说法错误;② 46+15=61(元),抢了红包后微信\"钱包\"有61元，说法正确。③说法与本题没有任何关系，说法错误。④6×9=54(元),妈妈今天支出的钱是发的红包54元，说法错误。故答案为:B",
+        "knowledge_points":  [
+                                 "乘加，乘减混合运算"
+                             ],
+        "source":  "24-25二年级上·浙江温州·期末"
+    },
+    {
+        "id":  "106",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "一本连环画一共有18页，排页码时一个铅字只能排一位数字，排这本书的页码一共需要( )个铅字。",
+        "options":  [
+                        "A. 18",
+                        "B. 26",
+                        "C. 27",
+                        "D. 36"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】根据题意，第1页到第9页，每页用1个铅字，需要9个铅字;再算第10页到第18页有多少页，用最后的18页减去10页，再加上第10页，共9页，每页用2个铅字，页数乘每页需要用的2个铅字，等于从第10页到18页需要多少个铅字，据此分析列式计算即可.\n【详解】根据分析可得:18-10+1=9(页),9+9×2=9+18=27(个),排这本书的页码一共需要27个铅字。故答案为:C",
+        "knowledge_points":  [
+                                 "加减混合运算(20以内)",
+                                 "9的乘法口诀及应用",
+                                 "表内乘加，乘减"
+                             ],
+        "source":  "24-25二年级上·浙江温州·期末"
+    },
+    {
+        "id":  "107",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "哥哥有8张画片，将哥哥的画片数乘4再加上6的结果就是弟弟的画片数，弟弟给哥哥()张，弟弟的画片就比哥哥的画片少2张。",
+        "options":  [
+                        "A. 14",
+                        "B. 15",
+                        "C. 16",
+                        "D. 17"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】用哥哥的画片数乘4再加上6求出弟弟原来的画片数，是38张，无论谁给谁画片，两个人画片的总张数是不变的，将两个人画片张数相加求出总张数，是46张，再减去少的两张，等于44张，找出两个同样的数相加等于44，用44减去22等于22，这个数就是22，即是弟弟现在的张数，再用弟弟原来的38张减去弟弟现在的22张，即可求出弟弟给哥哥多少张后，弟弟的画片就比哥哥的画片少2张.\n【详解】根据分析可得:8×4+6=32+6=38(张);38+8=46(张);46-2=44(张);44-22=22(张);38-22=16(张),所以，弟弟给哥哥16张画片后，弟弟的画片就比哥哥的画片少2张。故答案为:C",
+        "knowledge_points":  [
+                                 "和差倍问题",
+                                 "两位数与两位数的不退位减法",
+                                 "8的乘法口诀及应用",
+                                 "表内乘加，乘减"
+                             ],
+        "source":  "24-25二年级上·浙江温州·期末"
+    },
+    {
+        "id":  "108",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "计算4×8=( )。",
+        "options":  [
+                        "A. 30",
+                        "B. 32",
+                        "C. 36",
+                        "D. 12"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】根据8的乘法口诀计算此题即可.\"四八三十二\".\n【详解】4×8=32，故答案为:B",
+        "knowledge_points":  [
+                                 "8的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·浙江温州·期末"
+    },
+    {
+        "id":  "109",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "3×6=18和2×9=18( )相同。",
+        "options":  [
+                        "A. 表示的意义",
+                        "B. 乘法口诀",
+                        "C. 得数"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】3×6=18，根据口诀\"三六十八\"可算出得数;表示3个6的和或6个3的和是多少;2×9=18，根据口诀\"二九十八\"可算出得数;表示2个9的和或9个2的和是多少;即，对于3×6=18和2×9=18，得数相同，用到的口诀不同，意义也不同.\n【详解】由题意分析得:3×6=18和2×9=18得数相同，用到的口诀和意义都不同。故答案为:C",
+        "knowledge_points":  [
+                                 "初步认识乘法意义",
+                                 "6的乘法口诀及应用",
+                                 "9的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·云南保山·期末"
+    },
+    {
+        "id":  "110",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "会操表演时，二年级的同学排成了一个正方形队伍，无论是从前往后数还是从后往前数，贝贝都排在第4个，这个方阵一共有( )个人。",
+        "options":  [
+                        "A. 36",
+                        "B. 49",
+                        "C. 64",
+                        "D. 81"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】从前面数，贝贝排在第4个，从后面数，也排在第4个，说明都包括他自己，所以用4加上4求出和，再减去贝贝自己1人求出每行每列的人数，再用乘法解答即可.\n【详解】4+4-1=8-1=7(人);7×7=49(人),则这个方阵一共有49个人。故答案为:B",
+        "knowledge_points":  [
+                                 "7的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·浙江温州·期末"
+    },
+    {
+        "id":  "111",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "老师买了7本同样的书，花了六十多元，每本书可能是( )元。",
+        "options":  [
+                        "A. 7",
+                        "B. 8",
+                        "C. 9"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】乘法算式中两个乘数是口诀中的前两个数，积是口诀中的后一个数。找出7的乘法口诀中积是60多的那个口诀，口诀中的另一个乘数就是每本书的价钱.\n【详解】七九六十三,7×9 = 63(元),每本书可能是9元。故答案为:C",
+        "knowledge_points":  [
+                                 "经济问题",
+                                 "9的乘法口诀及应用"
+                             ],
+        "source":  "20-21二年级上·湖南长沙·期末"
+    },
+    {
+        "id":  "112",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "口诀\"六八四十八\"可以用来计算( )。",
+        "options":  [
+                        "A. 6+8",
+                        "B. 6×8",
+                        "C. 12+36"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】根据乘法口诀可以写出乘法算式，前两个数为乘数，可互换位置，后一个数为积，由此解答.\n【详解】A。加法算式不能用乘法口诀计算，不符合题意;B。6×8用的口诀是\"六八四十八\"，符合题意;C。加法算式不能用乘法口诀计算，不符合题意。所以能用口诀\"六八四十八\"可以用来计算6×8。故答案为:B",
+        "knowledge_points":  [
+                                 "两位数与两位数的不进位加法",
+                                 "8的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·湖南湘西·期末"
+    },
+    {
+        "id":  "113",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "与6×6得数相等的乘法算式是( )。",
+        "options":  [
+                        "A. 30+6",
+                        "B. 9×4",
+                        "C. 40-4"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】先看看是否是乘法算式，不是则不符合，如果是乘法算式就算出各算式的结果作对比.\n【详解】6×6 = 36,A。30+6是加法算式不是乘法算式，不符合;B。9×4 = 36，与6×6得数相等，符合;C。40-4是减法算式不是乘法算式，不符合;与6×6得数相等的乘法算式是9×4。故答案为:B",
+        "knowledge_points":  [
+                                 "6的乘法口诀及应用",
+                                 "9的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·山东济宁·期末"
+    },
+    {
+        "id":  "114",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "9×( )\u003c64，在括号里最大填( )。",
+        "options":  [
+                        "A. 8",
+                        "B. 6",
+                        "C. 7"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】根据题意，依次将各选项的数字代入到算式中，计算出结果再和64比较大小，选择结果小于且最接近64的即可.\n【详解】A。9×8 = 72\u003e64，不符合题意;B。9×6 = 54 \u003c 64;C。9×7 = 63 \u003c 64;54\u003c63\u003c64;最接近64的是63，也就是括号里最大填7。故答案为:C",
+        "knowledge_points":  [
+                                 "100以内数的比大小",
+                                 "9的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·河南周口·期末"
+    },
+    {
+        "id":  "115",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "9个6的和是多少。正确的算式是( )。",
+        "options":  [
+                        "A. 9+6",
+                        "B. 9×6",
+                        "C. 9+9+9+9+9+9"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】逐项分析各个算式的意义即可解答.\n【详解】A。9+6表示：把9和6合并成一个数是多少，答案不正确;B。9×6表示:9个6的和是多少，答案正确;C。9+9+9+9+9+9表示:6个9的和是多少，答案不正确;故答案为:B",
+        "knowledge_points":  [
+                                 "9加几的进位加法",
+                                 "初步认识乘法意义",
+                                 "6的乘法口诀及应用",
+                                 "9的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·山东济宁·期末"
+    },
+    {
+        "id":  "116",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "下面的乘法口诀中，只能用来计算一个乘法算式的是( )。",
+        "options":  [
+                        "A. 二三得六",
+                        "B. 四五二十",
+                        "C. 八八六十四"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】将三个选项中的乘法口诀改写成乘法算式，找出只能用来计算一个乘法算式的口诀即可.\n【详解】A。二三得六，可以用来计算两个乘法算式:2×3=6,3×2=6;B。四五二十，可以用来计算两个乘法算式:4×5 = 20,5×4=20;C。八八六十四，可以用来计算一个乘法算式:8×8 = 64。故答案为:C",
+        "knowledge_points":  [
+                                 "5的乘法口诀及应用",
+                                 "3的乘法口诀及应用",
+                                 "8的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·广西贵港·期末"
+    },
+    {
+        "id":  "117",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "下列口诀中，只能用来计算1个乘法算式的是( )。",
+        "options":  [
+                        "A. 七七四十九",
+                        "B. 四八三十二",
+                        "C. 二三得六"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】根据选项写出所有的乘法算式，找出只能写一个算式的乘法口诀即可.\n【详解】A。七七四十九只能写出一个乘法算式:7×7=49;B。四八三十二可以写出两个乘法算式:4×8 = 32,8×4=32;C。二三得六可以写出两道乘法算式:2×3 = 6,3×2 = 6. 故答案为:A",
+        "knowledge_points":  [
+                                 "3的乘法口诀及应用",
+                                 "7的乘法口诀及应用",
+                                 "8的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·江西赣州·期末"
+    },
+    {
+        "id":  "118",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "下面算式中，得数最小的是( )。",
+        "options":  [
+                        "A. 75-39",
+                        "B. 4×9+9",
+                        "C. 6+38"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】按照整数加减法的计算法则及整数混合运算的运算顺序，先计算出每个算式的得数，然后找出得数最小的算式即可。既有乘法又有加法，先算乘法，再算加法.\n【详解】A。75-39=36;B。4×9+9=36+9=45;C。6+38 = 44;36\u003c44\u003c45，即，得数最小的算式是75-39。故答案为:A",
+        "knowledge_points":  [
+                                 "100以内数的比大小",
+                                 "一位数与两位数的进位加法",
+                                 "两位数与两位数的退位减法",
+                                 "表内乘加，乘减"
+                             ],
+        "source":  "24-25二年级上·四川南充·期末"
+    },
+    {
+        "id":  "119",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "括号里最大能填几。\n\n( )×4\u003c35;8×( )\u003c57\n\n( )×5\u003c31;51\u003e( )×7",
+        "options":  [
+
+                    ],
+        "answer":  "8;7;6;7",
+        "solution":  "【分析】根据表内乘法口诀及整数比较大小的方法解答即可.\n【详解】4×8 = 32,4×9 = 36,32\u003c35\u003c36，故:8×4 \u003c 35;7×8 = 56,8×8 = 64,56 \u003c 57 \u003c 64，故:8×7 \u003c 57;5×6 = 30,5×7 = 35,30 \u003c 31 \u003c 35，故:6×5 \u003c 31;7×7 = 49,7×8 = 56,49\u003c51\u003c56，故:51\u003e7×7。",
+        "knowledge_points":  [
+                                 "100以内数的比大小",
+                                 "7的乘法口诀及应用",
+                                 "8的乘法口诀及应用",
+                                 "9的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级下·河北石家庄·期中"
+    },
+    {
+        "id":  "120",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "括号里最大能填几。\n\n( )×8\u003c40;38\u003e( )×5;( )×9\u003c55",
+        "options":  [
+
+                    ],
+        "answer":  "4;7;6",
+        "solution":  "【分析】通过乘法口诀依次计算，找到满足条件的最大数即可.\n【详解】4×8 = 32,5×8 = 40,6×8 = 48,32\u003c40\u003c48，所以括号里最大能填4，即(4)×8\u003c40;7×5 = 35,8×5 = 40,40\u003e38\u003e35，所以括号里最大能填7，即38\u003e(7)×5;6×9 = 54,7×9 = 63,54\u003c55\u003c63，所以括号里最大能填6，即(6)×9\u003c55。",
+        "knowledge_points":  [
+                                 "100以内数的比大小",
+                                 "7的乘法口诀及应用",
+                                 "8的乘法口诀及应用",
+                                 "9的乘法口诀及应用"
+                             ],
+        "source":  "23-24二年级下·福建龙岩·期末"
+    },
+    {
+        "id":  "121",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "括号里最大能填几。\n\n( )×4\u003c30;34\u003e5×( )\n60\u003e( )×8;81\u003e( )×9",
+        "options":  [
+
+                    ],
+        "answer":  "7;6;7;8",
+        "solution":  "【分析】根据表内乘法口诀，结合100以内整数比较大小和题干要求进行解答即可.\n【详解】由\"四七二十八\"\"四八三十二\"可知:4×7=28,4×8 = 32,28\u003c30,32\u003e30，所以括号内最大能填7。由\"五六三十\"\"五七三十五\"可知:5×6 = 30,5×7=35,30\u003c34,35\u003e34，所以括号内最大能填6。由\"七八五十六\"\"七九六十三\"可知:7×8 = 56,7×9=63,56\u003c60,63\u003e60，所以括号内最大能填7。由\"八九七十二\"\"九九八十一\"可知: 8×9 =72,9×9=81,72\u003c81,81=81，所以括号内最大能填8。",
+        "knowledge_points":  [
+                                 "100以内数的比大小",
+                                 "8的乘法口诀及应用",
+                                 "9的乘法口诀及应用"
+                             ],
+        "source":  "23-24二年级上·新疆乌鲁木齐·期末"
+    },
+    {
+        "id":  "122",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "括号里最大能填几。\n\n5×( )\u003c28;7×( )\u003c50;34\u003e6×( )\n( )×4\u003c29;40\u003e( )×9;8×( )\u003c55",
+        "options":  [
+
+                    ],
+        "answer":  "5;7;5;7;4;6",
+        "solution":  "【分析】通过乘法口诀依次计算，找到满足条件的最大数即可.\n【详解】5×5 = 25,5×6 = 30,25 \u003c 28 \u003c 30，所以括号里最大能填5，即5×(5)\u003c28;7×7 = 49,7×8 = 56,49\u003c50\u003c56，所以括号里最大能填7，即7×(7)\u003c50;6×5 = 30,6×6 = 36,36\u003e34\u003e30，所以括号里最大能填5，即34\u003e6×(5);7×4=28,8×4 = 32,28\u003c29\u003c32，所以括号里最大能填7，即(7)×4\u003c29;4×9 = 36,5×9 = 45,45 \u003e 40 \u003e 36，所括号里最大能填4，即40 \u003e (4)×9;8×6 = 48,8×7 = 56,48\u003c55\u003c56，所以括号里最大能填6，即8×(6)\u003c55。",
+        "knowledge_points":  [
+                                 "100以内数的比大小",
+                                 "5的乘法口诀及应用",
+                                 "8的乘法口诀及应用",
+                                 "9的乘法口诀及应用"
+                             ],
+        "source":  "23-24二年级上·新疆乌鲁木齐·期末"
+    },
+    {
+        "id":  "123",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "两个加数都是9，和是( );两个乘数都是9，积是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "18;81",
+        "solution":  "【分析】两个加数都是9，求它们的和，用加法计算，列式为9+9，求出结果填空即可;两个乘数都是9，求它们的积，用乘法计算，列式为9×9，求出结果填空即可.\n【详解】9+9=18,9×9=81，两个加数都是9，和是(18);两个乘数都是9，积是(81)。",
+        "knowledge_points":  [
+                                 "9加几的进位加法",
+                                 "9的乘法口诀及应用"
+                             ],
+        "source":  "23-24二年级上·新疆乌鲁木齐·期末"
+    },
+    {
+        "id":  "124",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "7×9=( )。",
+        "options":  [
+
+                    ],
+        "answer":  "63",
+        "solution":  "【分析】乘法的意义：求几个相同的加数的和的简便运算，叫做乘法。7×9相当于7个9相加:9+9+9+9+9+9+9+9=63。据此解答.\n【详解】根据分析可知,7×9=63。",
+        "knowledge_points":  [
+                                 "9的乘法口诀及应用"
+                             ],
+        "source":  "23-24六年级下·北京东城·期末"
+    },
+    {
+        "id":  "125",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "将一堆书，平均分给4个同学，或平均分给9个同学，都正好分完，这堆书最少有()本。",
+        "options":  [
+
+                    ],
+        "answer":  "36",
+        "solution":  "【分析】乘法算式中两个乘数是口诀中的前两个数，积是口诀中的后一个数。找到4和9的乘法口诀中相同并且最小的那个积，这时的积就是这堆书至少有的本数.\n【详解】四九三十六，这堆书最少有36本。",
+        "knowledge_points":  [
+                                 "4的乘法口诀及应用",
+                                 "9的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级下·山东日照·期中"
+    },
+    {
+        "id":  "126",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "括号里最大能填几。\n\n( )×4\u003c30;7×( )\u003c64;5×( )\u003c21",
+        "options":  [
+
+                    ],
+        "answer":  "7;9;4",
+        "solution":  "【分析】通过乘法口诀依次计算，找到符合条件的最大数即可.\n【详解】7×4=28,8×4 = 32,28\u003c30\u003c32，括号里最大能填7，即(7)×4\u003c30;7×9=63,63\u003c 64，括号最大能填9，即7×(9)\u003c 64;5×4=20,5×5=25,20\u003c 21\u003c 25，括号里最大能填4，即5×(4)\u003c 21。",
+        "knowledge_points":  [
+                                 "100以内数的比大小",
+                                 "5的乘法口诀及应用",
+                                 "7的乘法口诀及应用",
+                                 "9的乘法口诀及应用"
+                             ],
+        "source":  "23-24二年级下·湖南常德·期中"
+    },
+    {
+        "id":  "127",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "一本书8元钱，买3本这样的书要( )钱。",
+        "options":  [
+
+                    ],
+        "answer":  "24元",
+        "solution":  "【分析】买3本这样的书花的钱数也就是3个8的和，用乘法计算，即每本的钱数和买的本数相乘，就是总钱数.\n【详解】 8×3 = 24(元),一本书8元钱，买3本这样的书要24元钱。",
+        "knowledge_points":  [
+                                 "8的乘法口诀及应用"
+                             ],
+        "source":  "23-24二年级下·湖南常德·期中"
+    },
+    {
+        "id":  "128",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在括号里最大能填几。\n\n( )×6\u003c25;7×( )\u003c50;4×( )\u003c17",
+        "options":  [
+
+                    ],
+        "answer":  "4;7;4",
+        "solution":  "【分析】根据题意，用含有小于号左侧已知数的乘法口诀，找出结果小于且最接近右侧数的即可.\n【详解】4×6 = 24 \u003c 25;5×6 = 30\u003e25，所以括号里最大能填4;7×7=49\u003c50;7×8 = 56\u003e50，所以括号里最大能填7;4×4 = 16 \u003c 17;4×5 = 20\u003e17，所以括号里最大能填4。",
+        "knowledge_points":  [
+                                 "100以内数的比大小",
+                                 "6的乘法口诀及应用",
+                                 "7的乘法口诀及应用",
+                                 "8的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级下·黑龙江佳木斯·期中"
+    },
+    {
+        "id":  "129",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "括号里最大能填几。\n\n( )×7\u003c39;3×( )\u003c25;50\u003e( )×8",
+        "options":  [
+
+                    ],
+        "answer":  "5;8;6",
+        "solution":  "【分析】根据题意，分别用含有小于号左侧或大于号右侧已知数的乘法口诀，找出结果小于且最接近另一侧数的即可.\n【详解】5×7 = 35 \u003c 39;6×7 = 42 \u003e 39，则括号里最大填5;3×8 = 24 \u003c 25;3×9 = 27 \u003e 25，则括号里最大填8;50 \u003e 6×8 = 48;50 \u003c 7×8 = 56，则括号里最大填6。",
+        "knowledge_points":  [
+                                 "100以内数的比大小",
+                                 "7的乘法口诀及应用",
+                                 "8的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级下·陕西渭南·期中"
+    },
+    {
+        "id":  "130",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "括号里应填几。\n\n6×()=12;()×5=35;()×9=45;()×4=28;7×()=21;8×()=64",
+        "options":  [
+
+                    ],
+        "answer":  "2;7;5;7;3;8",
+        "solution":  "【分析】由题意可知：分别用乘法口诀即可算出括号里的数，据此可解。乘法算式中两个乘数是口诀中的前两个数，积是口诀中的后一个数，写算式时两个乘数可互换位置.\n【详解】由分析可得:6×() =12用的乘法口诀是：二六十二，故填2;()×5 = 35用的乘法口诀是：五七三十五，故填7;()×9=45用的乘法口诀是：五九四十五，故填5;()×4=28用的乘法口诀是：四七二十八，故填7;7×() =21用的乘法口诀是：三七二十一，故填3;8×() =64用的乘法口诀是：八八六十四，故填8;6×2=12;7×5=35;5×9=45;7×4=28;7×3=21;8×8=64",
+        "knowledge_points":  [
+                                 "6的乘法口诀及应用",
+                                 "7的乘法口诀及应用",
+                                 "8的乘法口诀及应用",
+                                 "9的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级下·山东济南·期中"
+    },
+    {
+        "id":  "131",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "18-□-□=6,□*○=48，那么□=( ),○=( )。",
+        "options":  [
+
+                    ],
+        "answer":  "6;8",
+        "solution":  "【分析】用18减6可以得到两个□的和，然后除以2即可得出□是多少。乘法算式中两个乘数是口诀中的前两个数，积是口诀中的后一个数，写算式时两个乘数可互换位置。据此求出○是多少.\n【详解】18-6=12,12÷2=6,□=6。六八四十八,6×8=48,○=8.18-□-□=6,□*○=48，那么□=6,○=8。",
+        "knowledge_points":  [
+                                 "8的乘法口诀及应用",
+                                 "连减(20以内)"
+                             ],
+        "source":  "24-25二年级下·贵州六盘水·期中"
+    },
+    {
+        "id":  "132",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "根据规律填数.\n\n(1)3,6,9,12,( ).\n(2)40,35,30,25,( )。",
+        "options":  [
+
+                    ],
+        "answer":  "15;20",
+        "solution":  "【分析】(1)1×3 = 3,2×3 = 6,3×3 = 9,4×3 = 12,5×3 = 15;(2)8×5 = 40,7×5 = 35,6×5 = 30,5×5 = 25,4×5 = 20，据此填空即可.\n【详解】(1)由分析可知:3,6,9,12,15。(2)40,35,30,25,20。",
+        "knowledge_points":  [
+                                 "6的乘法口诀及应用",
+                                 "7的乘法口诀及应用",
+                                 "8的乘法口诀及应用",
+                                 "整数排列的规律"
+                             ],
+        "source":  "24-25二年级下·湖南长沙·期中"
+    },
+    {
+        "id":  "133",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "☆*△=36;☆-△=5,☆=( );△=( )",
+        "options":  [
+
+                    ],
+        "answer":  "9;4",
+        "solution":  "【分析】根据乘法口诀\"四九三十六\"得9×4=36，且9-4=5;据此解决即可.\n【详解】由分析可知:9×4=36,9-4=5;当☆*△=36,☆-△=5时,☆=9,△=4。",
+        "knowledge_points":  [
+                                 "8,9的加减法",
+                                 "9的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级下·山东菏泽·期中"
+    },
+    {
+        "id":  "134",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "△,□,○分别代表三个数.\n\n△*□=27;△+○=10.\n\n△=( ),○=( ),□=( )",
+        "options":  [
+
+                    ],
+        "answer":  "3;7;9",
+        "solution":  "【分析】三九二十七，因此△和□可以分别是3和9。再将△的数值代入△+○=10，根据和-加数=另一个加数，可以求出○的数值.\n【详解】3×9=27，则△=3,□=9。△+○=10，即3+○=10,10-3=7，则○=7。",
+        "knowledge_points":  [
+                                 "10的加减法",
+                                 "9的乘法口诀及应用",
+                                 "加，减法的意义和各部分间的关系"
+                             ],
+        "source":  "24-25二年级下·山东济南·期中"
+    },
+    {
+        "id":  "135",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "6元8角=( )角;3米=( )厘米;一九( );( )六十四;( )四十二",
+        "options":  [
+
+                    ],
+        "answer":  "68;300;得九;八八;六七",
+        "solution":  "【分析】①根据1元=10角将单位统一;②根据1米=100厘米将单位统一;③④⑤根据乘法口诀填写.\n【详解】6元8角=60角+8角=68角;3米=300厘米;一九得九;八八六十四;六七四十二。",
+        "knowledge_points":  [
+                                 "7的乘法口诀及应用",
+                                 "8的乘法口诀及应用",
+                                 "元，角，分的认识及换算",
+                                 "毫米，厘米，分米，米之间的进率与换算"
+                             ],
+        "source":  "24-25二年级下·广东梅州·开学考试"
+    },
+    {
+        "id":  "136",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.94,
+        "question":  "三七( );五八( );( )十六;七( )五十六;一六( );( )二十四",
+        "options":  [
+
+                    ],
+        "answer":  "二十一;四十;四四或二八;八;得六;三八或四六",
+        "solution":  "【分析】乘法算式中两个乘数是口诀中的前两个数，积是口诀中的后一个数，牢记乘法口诀填写即可.\n【详解】三七二十一，五八四十，四四十六(或二八十六),七八五十六，一六得六，三八二十四(或四六二十四)。",
+        "knowledge_points":  [
+                                 "4的乘法口诀及应用",
+                                 "6的乘法口诀及应用",
+                                 "7的乘法口诀及应用",
+                                 "8的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级下·河南许昌·开学考试"
+    },
+    {
+        "id":  "137",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "括号里最大能填几。\n\n4×( )\u003c30;38\u003e( )×6;( )×7\u003c37",
+        "options":  [
+
+                    ],
+        "answer":  "7;6;5",
+        "solution":  "【分析】根据含有小于号左侧或大于号右侧已知数的乘法口诀，找出结果满足不等式且尽量接近另一侧数的数.\n【详解】4×7=28,4×8=32,28\u003c30\u003c32，则4×7\u003c30，括号最大填7;6×6=36,7×6=42,36\u003c38\u003c42，则38\u003e6×6，括号最大填6;5×7=35,6×7=42,35\u003c37\u003c42，则5×7\u003c37，括号最大填5。",
+        "knowledge_points":  [
+                                 "6的乘法口诀及应用",
+                                 "7的乘法口诀及应用",
+                                 "8的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级下·广东梅州·开学考试"
+    },
+    {
+        "id":  "138",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "按规律填一填.\n\n(1)18,27,36,45,( ),( ).\n(2)56,48,40,32,( ),( )。",
+        "options":  [
+
+                    ],
+        "answer":  "54;63;24;16",
+        "solution":  "【分析】(1) 这组数是9的乘法口诀中从二九十八到七九六十三的积;(2) 这组数是8的乘法口诀中从七八五十六到二八十六的积.\n【详解】(1) 六九五十四，七九六十三，数列为18,27,36,45,54,63.\n(2) 三八二十四，二八十六，数列为56,48,40,32,24,16。",
+        "knowledge_points":  [
+                                 "8的乘法口诀及应用",
+                                 "9的乘法口诀及应用",
+                                 "整数排列的规律"
+                             ],
+        "source":  "24-25二年级上·湖北荆州·期末"
+    },
+    {
+        "id":  "139",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "( )里最大能填几。\n\n( )×4\u003c34;( )\u003c6×7;( )×9\u003c28",
+        "options":  [
+
+                    ],
+        "answer":  "8;41;3",
+        "solution":  "【分析】乘法算式中两个乘数是口诀中的前两个数，积是口诀中的后一个数;比较整数大小时先看位数，再看各位上的数字.\n【详解】四八三十二，四九三十六，最大填8，有8×4\u003c34;6×7=42,42-1=41，所以41\u003c6×7;三九二十七，四九三十六，最大填3，有3×9\u003c28。",
+        "knowledge_points":  [
+                                 "100以内数的比大小",
+                                 "7的乘法口诀及应用",
+                                 "8的乘法口诀及应用",
+                                 "9的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·浙江嘉兴·期末"
+    },
+    {
+        "id":  "140",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "在括号里填上\"\u003e\"\"\u003c\"或\"=\".\n\n4×9( )9×3+9;43+36( )26+43",
+        "options":  [
+
+                    ],
+        "answer":  "=;\u003e",
+        "solution":  "【分析】先算出各算式结果，再比较大小。比较整数时位数多的数大;位数相同看最高位，其次看下一位.\n【详解】4×9=36;9×3+9=27+9=36,36=36，所以4×9=9×3+9;43+36=79,26+43=69,79\u003e69，所以43+36\u003e26+43。",
+        "knowledge_points":  [
+                                 "100以内数的比大小",
+                                 "两位数与两位数的不进位加法",
+                                 "9的乘法口诀及应用",
+                                 "表内乘加，乘减"
+                             ],
+        "source":  "24-25二年级上·贵州黔南·期末"
+    },
+    {
+        "id":  "141",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "5个7相加的和是( );6和8相加的和是( );两个乘数都是9，积是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "35;14;81",
+        "solution":  "【分析】几个相同加数的和可以用乘法表示;两个数相加用加法;乘法算式为乘数×乘数=积.\n【详解】5×7=35,6+8=14,9×9=81，故5个7相加的和是35;6和8相加的和是14;两个乘数都是9，积是81。",
+        "knowledge_points":  [
+                                 "7,6加几的进位加法",
+                                 "初步认识乘法意义",
+                                 "7的乘法口诀及应用",
+                                 "9的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·贵州黔南·期末"
+    },
+    {
+        "id":  "142",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "括号里最大能填几。\n\n22\u003e( )×6;5×( )\u003c47;37\u003e5×( )\n28\u003e7×( );( )×3\u003c19;4×( )\u003c36",
+        "options":  [
+
+                    ],
+        "answer":  "3;9;7;3;6;8",
+        "solution":  "【分析】根据已知一侧的数和乘法口诀，找出积小于(或使不等式成立)且最接近的乘数.\n【详解】22\u003e3×6=18,22\u003c4×6=24，所以最大填3;5×9=45\u003c47，所以最大填9;37\u003e5×7=35,37\u003c5×8=40，所以最大填7;28\u003e7×3=21,7×4=28,7×5=35，所以最大填3;6×3=18\u003c19,7×3=21\u003e19，所以最大填6;4×8=32\u003c36,4×9=36，所以最大填8。",
+        "knowledge_points":  [
+                                 "100以内数的比大小",
+                                 "6的乘法口诀及应用",
+                                 "8的乘法口诀及应用",
+                                 "9的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·福建福州·期末"
+    },
+    {
+        "id":  "143",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "括号里最大填几。\n\n5×( )\u003c47;53-( )\u003e21;39+( )\u003c80",
+        "options":  [
+
+                    ],
+        "answer":  "9;31;40",
+        "solution":  "【分析】第1题：利用含有5的乘法口诀，找出积小于且最接近47的;第2题：比21大的最小整数是22，用53-差=减数;第3题：比80小的最大整数是79，用和-一个加数=另一个加数.\n【详解】5×9=45\u003c47,5×10=50\u003e47，所以最大填9;53-31=22\u003e21,53-32=21，所以最大填31;39+40=79\u003c80,39+41=80，所以最大填40。",
+        "knowledge_points":  [
+                                 "100以内数的比大小",
+                                 "两位数与两位数的不退位减法",
+                                 "9的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·浙江台州·期末"
+    },
+    {
+        "id":  "144",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "( )里最大能填几。\n\n( )×3\u003c20;7×( )\u003c36;58\u003e8×( )",
+        "options":  [
+
+                    ],
+        "answer":  "6;5;7",
+        "solution":  "【分析】根据表内乘法口诀和整数比较大小的方法求出各式中乘数的最大值.\n【详解】6×3=18,7×3=21,18\u003c20\u003c21，故6×3\u003c20;7×5=35,7×6=42,35\u003c36\u003c42，故7×5\u003c36;8×7=56,8×8=64,56\u003c58\u003c64，故58\u003e8×7。",
+        "knowledge_points":  [
+                                 "100以内数的比大小",
+                                 "6的乘法口诀及应用",
+                                 "7的乘法口诀及应用",
+                                 "8的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·广东云浮·期末"
+    },
+    {
+        "id":  "145",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "积是36的乘法口诀有两句，分别是:( )和( )。",
+        "options":  [
+
+                    ],
+        "answer":  "四九三十六;六六三十六",
+        "solution":  "【分析】根据乘法口诀中积为36的两句找出乘法口诀.\n【详解】四九三十六和六六三十六的积都为36。",
+        "knowledge_points":  [
+                                 "6的乘法口诀及应用",
+                                 "9的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·浙江温州·期末"
+    },
+    {
+        "id":  "146",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在括号里填上合适的数.\n\n( )×5=45;( )×7=49;4×6=( )×8",
+        "options":  [
+
+                    ],
+        "answer":  "9;7;3",
+        "solution":  "【分析】利用乘法口诀反向确定乘数.\n【详解】\"五九四十五\",9×5=45，故填9;\"七七四十九\",7×7=49，故填7;4×6=24，\"三八二十四\",3×8=24，故填3。",
+        "knowledge_points":  [
+                                 "7的乘法口诀及应用",
+                                 "8的乘法口诀及应用",
+                                 "9的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·浙江温州·期末"
+    },
+    {
+        "id":  "147",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "用\"八九七十二\"这句乘法口诀可以写出两道乘法算式，它们是( )和( )。",
+        "options":  [
+
+                    ],
+        "answer":  "8×9=72;9×8=72",
+        "solution":  "【分析】乘法口诀中前两个数是乘数，顺序可以互换，后一个数是积.\n【详解】\"八九七十二\"可写成8×9=72和9×8=72。",
+        "knowledge_points":  [
+                                 "9的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·云南保山·期末"
+    },
+    {
+        "id":  "148",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "把口诀补充完整.\n\n三五( );四( )十六;( )得八\n七八( );( )二十八;( )五十四",
+        "options":  [
+
+                    ],
+        "answer":  "十五;四;一八或二四;五十六;四七;六九",
+        "solution":  "【分析】根据熟记的乘法口诀填写空缺部分.\n【详解】三五十五，四四十六，一八得八(二四得八);七八五十六，四七二十八，六九五十四。",
+        "knowledge_points":  [
+                                 "5的乘法口诀及应用",
+                                 "4的乘法口诀及应用",
+                                 "8的乘法口诀及应用",
+                                 "9的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·河南信阳·期末"
+    },
+    {
+        "id":  "149",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "6+6+6+6=( )×( );8+8+8+8+8+8+6=( )×( )-( )",
+        "options":  [
+
+                    ],
+        "answer":  "6;4;8;7;2",
+        "solution":  "【分析】求几个相同加数的和可以用乘法计算。第二题中6可以看作8-2，将和改写为\"几个8的和减去2\".\n【详解】6+6+6+6=6×4;8+8+8+8+8+8+6=8×7-2。",
+        "knowledge_points":  [
+                                 "同数连加的应用",
+                                 "初步认识乘法意义",
+                                 "8的乘法口诀及应用",
+                                 "表内乘加，乘减"
+                             ],
+        "source":  "24-25二年级上·河南信阳·期末"
+    },
+    {
+        "id":  "150",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "括号里最大能填几.\n\n( )×9\u003c56;30\u003e7×( );6×( )\u003c20",
+        "options":  [
+
+                    ],
+        "answer":  "6;4;3",
+        "solution":  "【分析】利用乘法口诀，找到使不等式成立的最大整数.\n【详解】6×9=54\u003c56,7×9=63\u003e56，所以最大填6;7×4=28\u003c30,7×5=35\u003e30，所以最大填4;6×3=18\u003c20,6×4=24\u003e20，所以最大填3。",
+        "knowledge_points":  [
+                                 "100以内数的比大小",
+                                 "6的乘法口诀及应用",
+                                 "7的乘法口诀及应用",
+                                 "9的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·湖北荆州·期末"
+    },
+    {
+        "id":  "151",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "括号里最大能填几。\n\n7×( )\u003c62;6×( )\u003c42;29\u003e4×( )",
+        "options":  [
+
+                    ],
+        "answer":  "8;6;7",
+        "solution":  "【分析】同样用乘法口诀和比较大小的方法求最大整数.\n【详解】7×8=56\u003c62,7×9=63\u003e62，所以最大填8;6×6=36\u003c42,6×7=42=42，所以最大填6;4×7=28\u003c29,4×8=32\u003e29，所以最大填7。",
+        "knowledge_points":  [
+                                 "6的乘法口诀及应用",
+                                 "7的乘法口诀及应用",
+                                 "8的乘法口诀及应用",
+                                 "9的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·贵州黔南·期末"
+    },
+    {
+        "id":  "152",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "括号里最大能填几.\n\n65\u003e8×( );9×( )\u003c56;( )×6\u003c23;46\u003e7×( );3×( )\u003c20;( )×4\u003c29",
+        "options":  [
+
+                    ],
+        "answer":  "8;6;3;6;6;7",
+        "solution":  "【分析】利用乘法口诀和整数大小比较，逐一确定每个括号的最大整数.\n【详解】8×9=72,8×8=64,72\u003e65\u003e64，故65\u003e8×8，最大填8;9×6=54\u003c56,9×7=63\u003e56，最大填6;3×6=18,4×6=24,18\u003c23\u003c24，最大填3;7×6=42,7×7=49,49\u003e46\u003e42，最大填6;3×6=18,3×7=21,18\u003c20\u003c21，最大填6;7×4=28,8×4=32,28\u003c29\u003c32，最大填7。",
+        "knowledge_points":  [
+                                 "6的乘法口诀及应用",
+                                 "7的乘法口诀及应用",
+                                 "8的乘法口诀及应用",
+                                 "9的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·贵州铜仁·期末"
+    },
+    {
+        "id":  "153",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "○+○+○+○=28,△+○+○=20,○=( ),△=( )。",
+        "options":  [
+
+                    ],
+        "answer":  "7;6",
+        "solution":  "【分析】○+○+○+○=28，表示4个○的和是28，可写成4*○=28，再由\"四七二十八\"可知○=7。将○=7代入第二个等式即可求△.\n【详解】4×7=28，所以○=7;代入△+7+7=20，得△=20-7-7=6。",
+        "knowledge_points":  [
+                                 "初步认识乘法意义",
+                                 "7的乘法口诀及应用",
+                                 "连减(20以内)"
+                             ],
+        "source":  "24-25二年级上·福建龙岩·期末"
+    },
+    {
+        "id":  "154",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "植物园门票每张8元，元旦小长假对儿童免费。二年级的可可元旦和爸爸妈妈一起去植物园，需要花( )元。",
+        "options":  [
+
+                    ],
+        "answer":  "16",
+        "solution":  "【分析】儿童免费，只需支付两位大人的门票，用票价乘买票的人数即可.\n【详解】8×2=16(元),答：需要花16元。",
+        "knowledge_points":  [
+                                 "8的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·福建福州·期末"
+    },
+    {
+        "id":  "155",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "( )比50少25;3个6加5个6是( )个6，结果是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "25;8;48",
+        "solution":  "【分析】\"比50少25\"的数用减法求;3个6加5个6共8个6，用乘法求和.\n【详解】50-25=25;3+5=8;6×8=48。即25比50少25;3个6加5个6是8个6，结果是48。",
+        "knowledge_points":  [
+                                 "8,9的加减法",
+                                 "两位数与两位数的退位减法",
+                                 "8的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·福建福州·期末"
+    },
+    {
+        "id":  "156",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "①○+○=16,○=( );②△+△+△+△+△=10,△=( )。",
+        "options":  [
+
+                    ],
+        "answer":  "8;2",
+        "solution":  "【分析】○+○=16，表示2个○的和是16，写成2*○=16，对应\"二八十六\"，得○=8。△+△+△+△+△=10，表示5个△的和是10，写成5*△=10，对应\"二五一十\"，得△=2。",
+        "knowledge_points":  [
+                                 "初步认识乘法意义",
+                                 "5的乘法口诀及应用",
+                                 "8的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·河南南阳·期末"
+    },
+    {
+        "id":  "157",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "在( )里填上\"\u003e\"\"\u003c\"\"+\"或\"-\".\n\n9×5( )5×9;36( )10=26;50( )24=26\n7×1( )7+1;5米( )50厘米;7+5( )7×5",
+        "options":  [
+
+                    ],
+        "answer":  "=;-;-;\u003c;\u003e;\u003c",
+        "solution":  "【分析】先计算每个算式的结果，再比较大小;含有单位的先统一单位(1米=100厘米).\n【详解】9×5=45,5×9=45，故9×5=5×9;36-10=26;50-24=26;7×1=7,7+1=8，所以7×1\u003c7+1;5米\u003e1米=100厘米\u003e50厘米，故5米\u003e50厘米;7+5=12,7×5=35，故7+5\u003c7×5。",
+        "knowledge_points":  [
+                                 "两位数与整十数的减法",
+                                 "两位数与两位数的退位减法",
+                                 "9的乘法口诀及应用",
+                                 "厘米和米之间的进率与换算"
+                             ],
+        "source":  "24-25二年级上·福建龙岩·期末"
+    },
+    {
+        "id":  "158",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "( )里最大能填几。\n\n35\u003e( )×4;( )×8\u003c57;25+( )\u003c72",
+        "options":  [
+
+                    ],
+        "answer":  "8;7;46",
+        "solution":  "【分析】用乘法口诀和加法计算，找出满足不等式的最大整数.\n【详解】四八三十二，四九三十六，最大填8,35\u003e8×4;七八五十六，八八六十四，最大填7,7×8\u003c57;72-25=47,47-1=46，故最大为46，有25+46\u003c72。",
+        "knowledge_points":  [
+                                 "100以内数的比大小",
+                                 "两位数与两位数的退位减法",
+                                 "8的乘法口诀及应用",
+                                 "9的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·福建龙岩·期末"
+    },
+    {
+        "id":  "159",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "( )里最大能填几。\n\n5×( )\u003c40;7×( )\u003c63;42\u003e( )×7",
+        "options":  [
+
+                    ],
+        "answer":  "7;8;5",
+        "solution":  "【分析】使用乘法口诀和数的大小比较确定各式中乘数的最大值.\n【详解】五七三十五，五八四十，最大填7,5×7\u003c40;七八五十六，七九六十三，最大填8,7×8\u003c63;五七三十五，六七四十二，最大填5,42\u003e5×7。",
+        "knowledge_points":  [
+                                 "100以内数的比大小",
+                                 "7的乘法口诀及应用",
+                                 "8的乘法口诀及应用",
+                                 "9的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·山东菏泽·期末"
+    },
+    {
+        "id":  "160",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "括号里最大能填几.\n\n4×( )\u003c30;( )×9\u003c63",
+        "options":  [
+
+                    ],
+        "answer":  "7;6",
+        "solution":  "【分析】用乘法口诀算出临界值，再比较大小确定最大整数.\n【详解】4×7=28,4×8=32,28\u003c30\u003c32，故最大填7;6×9=54,7×9=63,54\u003c63=63，故最大填6。",
+        "knowledge_points":  [
+                                 "100以内数的比大小",
+                                 "7的乘法口诀及应用",
+                                 "8的乘法口诀及应用",
+                                 "9的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·云南保山·期末"
+    },
+    {
+        "id":  "161",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "8个6相加的和是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "48",
+        "solution":  "【分析】求8个6相加的和，用乘法计算即可.\n【详解】8×6=48，所以8个6相加的和是48。",
+        "knowledge_points":  [
+                                 "初步认识乘法意义",
+                                 "8的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·云南保山·期末"
+    },
+    {
+        "id":  "162",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "小明看一本故事书，每天看9页，看了7天，他一共看了( )页。",
+        "options":  [
+
+                    ],
+        "answer":  "63",
+        "solution":  "【分析】要求7天共看了多少页，就是求7个9的和，用乘法计算即可.\n【详解】9×7 = 63(页),答：一共看了63页。",
+        "knowledge_points":  [
+                                 "9的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·浙江温州·期末"
+    },
+    {
+        "id":  "163",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "每个鱼缸放8条金鱼,5个鱼缸有( )条鱼。",
+        "options":  [
+
+                    ],
+        "answer":  "40",
+        "solution":  "【分析】用每个鱼缸的金鱼数乘鱼缸的个数即可.\n【详解】8×5 = 40(条),答:5个鱼缸有40条鱼。",
+        "knowledge_points":  [
+                                 "8的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·湖南湘西·期末"
+    },
+    {
+        "id":  "164",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "判断题",
+        "difficulty":  0.65,
+        "question":  "小明在超市买了3盒牛奶，每盒8元，他付了25元，找回1元。( )",
+        "options":  [
+
+                    ],
+        "answer":  "√",
+        "solution":  "【分析】先算出3盒牛奶的总价，再用付款金额减去总价，看是否等于1元.\n【详解】总价:3×8 = 24(元)。付款25元，应找回25-24=1(元)。与题意一致，故说法正确，答案为:√",
+        "knowledge_points":  [
+                                 "8的乘法口诀及应用",
+                                 "十元以下人民币的认识与计算"
+                             ],
+        "source":  "24-25三年级下·黑龙江佳木斯·期末"
+    },
+    {
+        "id":  "165",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "在乘法计算里，积一定比其中任何一个乘数都大。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】只要举一个反例即可.\n【详解】例如:1×8=8，积与乘数8相等而不是更大，因此积不一定比乘数大。原说法错误，故答案为: ×",
+        "knowledge_points":  [
+                                 "8的乘法口诀及应用"
+                             ],
+        "source":  "2014三年级·全国·课后作业"
+    },
+    {
+        "id":  "166",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "6个4的和与3个8的和相等。( )",
+        "options":  [
+
+                    ],
+        "answer":  "√",
+        "solution":  "【分析】把两个和分别写成乘法算式比较.\n【详解】6×4 = 24,3×8=24，二者相等，因此原说法正确，答案为:√",
+        "knowledge_points":  [
+                                 "6的乘法口诀及应用",
+                                 "8的乘法口诀及应用"
+                             ],
+        "source":  "23-24二年级下·湖北黄冈·期末"
+    },
+    {
+        "id":  "167",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "白，红，黄三种颜色的花每样有9朵，一共有3朵。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】白，红，黄三种花各9朵，一共是3个9的和.\n【详解】9×3 = 27(朵),实际应有27朵，不是3朵，原说法错误，答案为:*",
+        "knowledge_points":  [
+                                 "9的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级下·湖南永州·月考"
+    },
+    {
+        "id":  "168",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "9的乘法口诀有九句，每相邻两句口诀的得数相差9，每句口诀都对应两个乘法算式。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】9的乘法口诀有九句，相邻两句的积确实相差9;但\"九九八十一\"中两个乘数相同，只对应1个算式.\n【详解】前半句正确：相邻两句积相差9;后半句错误：九九八十一只能写出一个算式9×9=81。因此整体说法错误，答案为:*",
+        "knowledge_points":  [
+                                 "9的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·河南南阳·期末"
+    },
+    {
+        "id":  "169",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "计算题",
+        "difficulty":  0.85,
+        "question":  "直接写出得数.\n\n6×7=( );4×5=( );9×9=( );9×7=( );5×7=( );6×8=( );4×7=( );5×9=( );5+8=( );9-6=( );4×6=( );5+7=( );2×6=( );9-9=( )",
+        "options":  [
+
+                    ],
+        "answer":  "42;20;81;63;35;48;28;45;13;3;24;12;12;0",
+        "solution":  "【分析】本题包含乘法口诀和20以内的加减法，按口诀或基本加减法则直接计算.\n【详解】6×7=42;4×5=20;9×9=81;9×7=63;5×7=35;6×8=48;4×7=28;5×9=45;5+8=13;9-6=3;4×6=24;5+7=12;2×6=12;9-9=0。",
+        "knowledge_points":  [
+                                 "5~2加几的进位加法",
+                                 "5的乘法口诀及应用",
+                                 "7的乘法口诀及应用",
+                                 "9的乘法口诀及应用"
+                             ],
+        "source":  "23-24二年级上·新疆乌鲁木齐·期末"
+    },
+    {
+        "id":  "170",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "计算题",
+        "difficulty":  0.85,
+        "question":  "直接写出得数.\n\n54+30=( );28+9=( );44+36=( );25-8=( );8×6=( );9×9-9=( );9×5-20=( );63-3×6=( )",
+        "options":  [
+
+                    ],
+        "answer":  "84;37;80;17;48;72;25;45",
+        "solution":  "【分析】本题包含两位数加减一位数，两位数加减两位数，乘法口诀以及乘加，乘减混合运算。加减法要注意进位和退位;乘加，乘减算式先算乘法再算加减法.\n【详解】54+30=84;28+9=37;44+36=80;25-8=17;8×6=48;9×9-9=81-9=72;9×5-20=45-20=25;63-3×6=63-18=45。",
+        "knowledge_points":  [
+                                 "一位数与两位数的进位加法",
+                                 "一位数与两位数的退位减法",
+                                 "9的乘法口诀及应用",
+                                 "表内乘加，乘减"
+                             ],
+        "source":  "24-25二年级上·福建福州·期末"
+    },
+    {
+        "id":  "171",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "计算题",
+        "difficulty":  0.85,
+        "question":  "直接写出得数.\n\n3×4=( );6×7=( );58+1=( );9×4-5=( );9×6=( );78-4=( );8×5=( );10+8×8=( )",
+        "options":  [
+
+                    ],
+        "answer":  "12;42;59;31;54;74;40;74",
+        "solution":  "【分析】本题包含乘法口诀，两位数加减一位数及乘加，乘减混合运算。乘法直接用口诀;混合运算先乘后加减.\n【详解】3×4=12;6×7=42;58+1=59;9×4-5=36-5=31;9×6=54;78-4=74;8×5=40;10+8×8=10+64=74。",
+        "knowledge_points":  [
+                                 "7的乘法口诀及应用",
+                                 "8的乘法口诀及应用",
+                                 "9的乘法口诀及应用",
+                                 "表内乘加，乘减"
+                             ],
+        "source":  "24-25二年级上·河南南阳·期末"
+    },
+    {
+        "id":  "172",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "计算题",
+        "difficulty":  0.85,
+        "question":  "直接写出得数.\n\n3×7=( );4×8=( );6×6=( );7×9=( );56+28=( );90-35=( );4×2+23=( );9×9-9=( );6×7+8=( );7×8-7=( )",
+        "options":  [
+
+                    ],
+        "answer":  "21;32;36;63;84;55;31;72;50;49",
+        "solution":  "【分析】含乘法口诀，两位数加减两位数及乘加，乘减混合运算。先乘后加减，注意加减法中的进退位.\n【详解】3×7=21;4×8=32;6×6=36;7×9=63;56+28=84;90-35=55;4×2+23=8+23=31;9×9-9=81-9=72;6×7+8=42+8=50;7×8-7=56-7=49。",
+        "knowledge_points":  [
+                                 "两位数与两位数的进位加法",
+                                 "两位数与两位数的退位减法",
+                                 "9的乘法口诀及应用",
+                                 "表内乘加，乘减"
+                             ],
+        "source":  "24-25二年级上·贵州黔南·期末"
+    },
+    {
+        "id":  "173",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "计算题",
+        "difficulty":  0.85,
+        "question":  "直接写出得数.\n\n47+26=( );42-23=( );37+15=( );60-43=( );81-9×3=( );8×6+34=( );7×(81-76)=( )",
+        "options":  [
+
+                    ],
+        "answer":  "73;19;52;17;54;82;35",
+        "solution":  "【分析】含两位数加减两位数，乘加以及带括号的混合运算。先算括号，再算乘法，最后加减;加减注意进退位.\n【详解】47+26=73;42-23=19;37+15=52;60-43=17;81-9×3=81-27=54;8×6+34=48+34=82;7×(81-76)=7×5=35。",
+        "knowledge_points":  [
+                                 "两位数与两位数的进位加法",
+                                 "两位数与两位数的退位减法",
+                                 "表内乘加，乘减"
+                             ],
+        "source":  "24-25二年级上·湖北黄冈·期末"
+    },
+    {
+        "id":  "174",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "计算题",
+        "difficulty":  0.85,
+        "question":  "直接写得数.\n\n17+6=( );5×3=( );8×6+6=( );9×5-9=( );97-27=( );8×9=( );5×7-16=( );86-22-30=( )",
+        "options":  [
+
+                    ],
+        "answer":  "23;15;54;36;70;72;19;34",
+        "solution":  "【分析】包含一位数与两位数加法，乘法口诀，乘加乘减及连减运算。混合运算先乘后加减，连减按从左到右依次计算.\n【详解】17+6=23;5×3=15;8×6+6=48+6=54;9×5-9=45-9=36;97-27=70;8×9=72;5×7-16=35-16=19;86-22-30=64-30=34。",
+        "knowledge_points":  [
+                                 "两位数与两位数的不退位减法",
+                                 "100以内数的连减运算",
+                                 "9的乘法口诀及应用",
+                                 "表内乘加，乘减"
+                             ],
+        "source":  "24-25二年级上·浙江温州·期末"
+    },
+    {
+        "id":  "175",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "计算题",
+        "difficulty":  0.85,
+        "question":  "直接写得数.\n\n4×5=( );8×6=( );83+7=( );3×6+6=( );13+50=( );75-20=( );3×9=( );92-2-20=( )",
+        "options":  [
+
+                    ],
+        "answer":  "20;48;90;24;63;55;27;70",
+        "solution":  "【分析】含乘法口诀，两位数加减整十数，乘加及连减运算。加减注意对齐数位，乘加，连减按运算顺序计算.\n【详解】4×5=20;8×6=48;83+7=90;3×6+6=18+6=24;13+50=63;75-20=55;3×9=27;92-2-20=90-20=70。",
+        "knowledge_points":  [
+                                 "两位数与整十数的加法",
+                                 "100以内数的连减运算",
+                                 "8的乘法口诀及应用",
+                                 "表内乘加，乘减"
+                             ],
+        "source":  "24-25二年级上·云南保山·期末"
+    },
+    {
+        "id":  "176",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "计算题",
+        "difficulty":  0.85,
+        "question":  "口算.\n\n2×7=( );5×6=( );54+9=( );8×9=( );7×6-40=( );8×3+6=( );4×5+30=( );3×5+27=( )",
+        "options":  [
+
+                    ],
+        "answer":  "14;30;63;72;2;30;50;42",
+        "solution":  "【分析】含乘法口诀，两位数加一位数及乘加乘减混合运算。口算时先乘后加减，注意加法进位和减法退位.\n【详解】2×7=14;5×6=30;54+9=63;8×9=72;7×6-40=42-40=2;8×3+6=24+6=30;4×5+30=20+30=50;3×5+27=15+27=42。",
+        "knowledge_points":  [
+                                 "6的乘法口诀及应用",
+                                 "7的乘法口诀及应用",
+                                 "9的乘法口诀及应用",
+                                 "表内乘加，乘减"
+                             ],
+        "source":  "24-25二年级上·河南信阳·期末"
+    },
+    {
+        "id":  "177",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "计算题",
+        "difficulty":  0.85,
+        "question":  "直接写出得数.\n\n5×8=( );4+2=( );6×7=( );46-8=( );5×8-5=( );9×6=( );2×9=( );4×9=( );6×4=( );2+3×8=( )",
+        "options":  [
+
+                    ],
+        "answer":  "40;6;42;38;35;54;18;36;24;26",
+        "solution":  "【分析】包含乘法口诀，一位数与两位数加减及乘加乘减混合运算。乘加乘减先乘后加减.\n【详解】5×8=40;4+2=6;6×7=42;46-8=38;5×8-5=40-5=35;9×6=54;2×9=18;4×9=36;6×4=24;2+3×8=2+24=26。",
+        "knowledge_points":  [
+                                 "6的乘法口诀及应用",
+                                 "8的乘法口诀及应用",
+                                 "9的乘法口诀及应用",
+                                 "表内乘加，乘减"
+                             ],
+        "source":  "24-25二年级上·浙江嘉兴·期末"
+    },
+    {
+        "id":  "178",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "计算题",
+        "difficulty":  0.85,
+        "question":  "直接写出得数.\n\n3×9=( );4×4=( );3×2=( );62+20=( );29+(24-7)=( );6+49=( );8×7=( );7+6=( );28+3=( );3+3×3=( )",
+        "options":  [
+
+                    ],
+        "answer":  "27;16;6;82;46;55;56;13;31;12",
+        "solution":  "【分析】本题含乘法口诀，带括号的混合运算和乘加混合运算。先算括号，先算乘法，再算加减.\n【详解】3×9=27;4×4=16;3×2=6;62+20=82;29+(24-7)=29+17=46;6+49=55;8×7=56;7+6=13;28+3=31;3+3×3=3+9=12。",
+        "knowledge_points":  [
+                                 "一位数与两位数的进位加法",
+                                 "8的乘法口诀及应用",
+                                 "9的乘法口诀及应用",
+                                 "表内乘加，乘减"
+                             ],
+        "source":  "24-25二年级上·浙江嘉兴·期末"
+    },
+    {
+        "id":  "179",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "计算题",
+        "difficulty":  0.85,
+        "question":  "直接写出得数.\n\n37+40=( );6×2=( );2×7=( );6×4=( );8×6=( );40+36=( );9×6=( );4×8=( );9×4=( );16+80=( );56-20=( );4×7=( );6×6=( );8×2=( );5×9+9=( );6×7-8=( )",
+        "options":  [
+
+                    ],
+        "answer":  "77;12;14;24;48;76;54;32;36;96;36;28;36;16;54;34",
+        "solution":  "【分析】包含两位数与整十数的加法，乘法口诀以及乘加乘减混合运算。加减时注意对齐数位，混合运算先乘后加减.\n【详解】37+40=77;6×2=12;2×7=14;6×4=24;8×6=48;40+36=76;9×6=54;4×8=32;9×4=36;16+80=96;56-20=36;4×7=28;6×6=36;8×2=16;5×9+9=45+9=54;6×7-8=42-8=34。",
+        "knowledge_points":  [
+                                 "两位数与整十数的加法",
+                                 "8的乘法口诀及应用",
+                                 "9的乘法口诀及应用",
+                                 "表内乘加，乘减"
+                             ],
+        "source":  "24-25二年级上·湖北武汉·期末"
+    },
+    {
+        "id":  "180",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "计算题",
+        "difficulty":  0.85,
+        "question":  "直接写出得数.\n\n5×4=( );3×4=( );5×7=( );5×5=( );37-8=( );30-5=( );5×6=( );8×8=( );4×4=( );61-5=( );4×6=( );7×9=( )",
+        "options":  [
+
+                    ],
+        "answer":  "20;12;35;25;29;25;30;64;16;56;24;63",
+        "solution":  "【分析】本题是乘法口诀和一位数与两位数退位减法的练习。乘法用口诀，退位减法注意向高位借1.\n【详解】5×4=20;3×4=12;5×7=35;5×5=25;37-8=29;30-5=25;5×6=30;8×8=64;4×4=16;61-5=56;4×6=24;7×9=63。",
+        "knowledge_points":  [
+                                 "一位数与两位数的退位减法",
+                                 "5的乘法口诀及应用",
+                                 "8的乘法口诀及应用",
+                                 "9的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·湖北武汉·期末"
+    },
+    {
+        "id":  "181",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "计算题",
+        "difficulty":  0.85,
+        "question":  "直接写出得数.\n\n9×3=( );6×2=( );8×8=( );7×9-7=( );7×6=( );8×4=( );5+9=( );3×8+2=( )",
+        "options":  [
+
+                    ],
+        "answer":  "27;12;64;56;42;32;14;26",
+        "solution":  "【分析】含乘法口诀,20以内加法以及乘减，乘加混合运算。混合运算先乘后加减.\n【详解】9×3=27;6×2=12;8×8=64;7×9-7=63-7=56;7×6=42;8×4=32;5+9=14;3×8+2=24+2=26。",
+        "knowledge_points":  [
+                                 "7的乘法口诀及应用",
+                                 "8的乘法口诀及应用",
+                                 "9的乘法口诀及应用",
+                                 "表内乘加，乘减"
+                             ],
+        "source":  "24-25二年级上·贵州铜仁·期末"
+    },
+    {
+        "id":  "182",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "计算题",
+        "difficulty":  0.85,
+        "question":  "直接写出得数.\n\n85-20=( );7+47=( );4×8=( );78-60=( );1×7=( );1×9=( );8×8=( );10+(23-3)=( );35-19=( );5×8+7=( )",
+        "options":  [
+
+                    ],
+        "answer":  "65;54;32;18;7;9;64;30;16;47",
+        "solution":  "【分析】包括两位数加减整十数，一位数与两位数进位加法，乘法口诀，带括号的加减混合和乘加混合运算。先括号，再乘，再加减.\n【详解】85-20=65;7+47=54;4×8=32;78-60=18;1×7=7;1×9=9;8×8=64;10+(23-3)=10+20=30;35-19=16;5×8+7=40+7=47。",
+        "knowledge_points":  [
+                                 "一位数与两位数的进位加法",
+                                 "8的乘法口诀及应用",
+                                 "9的乘法口诀及应用",
+                                 "表内乘加，乘减"
+                             ],
+        "source":  "24-25二年级上·四川乐山·期末"
+    },
+    {
+        "id":  "183",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "计算题",
+        "difficulty":  0.94,
+        "question":  "直接写得数.\n\n8×3=( );7×7-7=( );8×4=( );4×5+16=( );8×5+48=( );8×9-45=( );7×6+8=( );5×9-17=( )",
+        "options":  [
+
+                    ],
+        "answer":  "24;42;32;36;88;27;50;28",
+        "solution":  "【分析】考查乘法口诀与乘加，乘减混合运算。先算乘法，再算加减.\n【详解】8×3=24;7×7-7=49-7=42;8×4=32;4×5+16=20+16=36;8×5+48=40+48=88;8×9-45=72-45=27;7×6+8=42+8=50;5×9-17=45-17=28。",
+        "knowledge_points":  [
+                                 "7的乘法口诀及应用",
+                                 "8的乘法口诀及应用",
+                                 "9的乘法口诀及应用",
+                                 "表内乘加，乘减"
+                             ],
+        "source":  "24-25二年级上·山东菏泽·期末"
+    },
+    {
+        "id":  "184",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "王老师为班级购置奖品，一个笔记本7元，王老师买了9个笔记本，付给收银员100元，应找回多少钱。",
+        "options":  [
+
+                    ],
+        "answer":  "37元",
+        "solution":  "【分析】先用乘法求出9个笔记本的总价，再用付款金额减去总价求找回的钱数.\n【详解】9×7=63(元),100-63=37(元),答：应找回37元钱。",
+        "knowledge_points":  [
+                                 "两位数与两位数的退位减法",
+                                 "7的乘法口诀及应用",
+                                 "9的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级下·河北张家口·期末"
+    },
+    {
+        "id":  "185",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "有两盒珠子，每盒有7颗，一共有多少颗。",
+        "options":  [
+
+                    ],
+        "answer":  "14颗",
+        "solution":  "【分析】总颗数=盒数×每盒颗数.\n【详解】2×7=14(颗),答：一共有14颗。",
+        "knowledge_points":  [
+                                 "7的乘法口诀及应用"
+                             ],
+        "source":  "25-26二年级上·全国·课前预习"
+    },
+    {
+        "id":  "186",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "果园里有苹果树9棵，梨树的棵数是苹果树的4倍，梨树有多少棵。两种树共有多少棵。",
+        "options":  [
+
+                    ],
+        "answer":  "36棵;45棵",
+        "solution":  "【分析】梨树棵数=苹果树棵数*4;总棵数=苹果树棵数+梨树棵数.\n【详解】9×4=36(棵),36+9=45(棵),答：梨树有36棵，两种树共有45棵。",
+        "knowledge_points":  [
+                                 "一位数与两位数的进位加法",
+                                 "9的乘法口诀及应用",
+                                 "求一个数的几倍是多少"
+                             ],
+        "source":  "24-25一年级下·湖南岳阳·期中"
+    },
+    {
+        "id":  "187",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "每只小猫钓6条鱼,3只小猫钓多少条鱼。9只呢。",
+        "options":  [
+
+                    ],
+        "answer":  "18条;54条",
+        "solution":  "【分析】钓鱼总数=每只小猫钓的条数×小猫只数.\n【详解】3只:6×3=18(条);9只:6×9=54(条)。答:3只小猫钓18条鱼,9只小猫钓54条鱼。",
+        "knowledge_points":  [
+                                 "6的乘法口诀及应用",
+                                 "9的乘法口诀及应用"
+                             ],
+        "source":  "23-24二年级上·新疆乌鲁木齐·期末"
+    },
+    {
+        "id":  "188",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "看图回答.\n\n![](images/2632e55589a198ce811e546c199a011fadafd32cd84279f07eb0a4ad01cd4457.jpg)\n6元\n![](images/9bc80d9f0c74b783f8ca7170d6f8c584b32c4ce93a588b5861ed63279462ac9b.jpg)\n9元\n![](images/7bb02690faa5c451ef9d6bda7dfec27af893a61ada03c2cf80083df4ce9ab88b.jpg)\n4元\n![](images/a6389db2d34f6e4954aed3b884a2ec121db22c34f6759d7aa01f924432559937.jpg)\n3元\n\n买7把剪刀需要多少钱。",
+        "options":  [
+
+                    ],
+        "answer":  "28元",
+        "solution":  "【分析】由图可知一把剪刀4元，总价=单价×数量.\n【详解】4×7=28(元),答：买7把剪刀需要28元钱。",
+        "knowledge_points":  [
+                                 "7的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级下·山东滨州·期末"
+    },
+    {
+        "id":  "189",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "沿河县某小学开展课外兴趣小组活动，小明用红，黄，蓝三种颜色的彩纸各一张做纸鹤，每张彩纸可以做8只纸鹤，小明一共可以做多少只纸鹤。",
+        "options":  [
+
+                    ],
+        "answer":  "24只",
+        "solution":  "【分析】共有3张彩纸，每张8只，总数=3×8.\n【详解】3×8=24(只),答：小明一共可以做24只纸鹤。",
+        "knowledge_points":  [
+                                 "8的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级下·贵州铜仁·期末"
+    },
+    {
+        "id":  "190",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "花店原来有9把鲜花，每把8朵，卖出了38朵。原来一共有多少朵鲜花。还剩多少朵鲜花。",
+        "options":  [
+
+                    ],
+        "answer":  "72朵;34朵",
+        "solution":  "【分析】原来总数=9×8;剩余=原来总数-卖出的朵数.\n【详解】9×8=72(朵),72-38=34(朵),答：原来一共有72朵鲜花，还剩34朵鲜花。",
+        "knowledge_points":  [
+                                 "两位数与两位数的退位减法",
+                                 "9的乘法口诀及应用"
+                             ],
+        "source":  "23-24二年级下·贵州黔南·期末"
+    },
+    {
+        "id":  "191",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "学校组织植树活动，二(1)班种了4行树，每行9棵，二(2)班种了35棵。哪个班种的多。多多少棵。",
+        "options":  [
+
+                    ],
+        "answer":  "二(1)班多;1棵",
+        "solution":  "【分析】先求二(1)班种树总数，再与二(2)班比较，多的减去少的得到相差棵数.\n【详解】4×9=36(棵),36\u003e35,36-35=1(棵),答：二(1)班种的多，多1棵。",
+        "knowledge_points":  [
+                                 "100以内数的比大小",
+                                 "两位数与两位数的不退位减法",
+                                 "9的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级下·湖南长沙·期中"
+    },
+    {
+        "id":  "192",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "同学们排队做操，每行站8人，站了5行，一共有多少人。",
+        "options":  [
+
+                    ],
+        "answer":  "40人",
+        "solution":  "【分析】总人数=每行人数×行数.\n【详解】8×5=40(人),答：一共有40人。",
+        "knowledge_points":  [
+                                 "8的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级下·黑龙江佳木斯·期中"
+    },
+    {
+        "id":  "193",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "搭8个![](images/2026-02-26%20192843.jpg)一共要用多少个。",
+        "options":  [
+
+                    ],
+        "answer":  "32个",
+        "solution":  "【分析】从图可知一组由4个立方体组成,8组共需要8个4，即4×8.\n【详解】4×8=32(个),答：一共要用32个。",
+        "knowledge_points":  [
+                                 "8的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级下·贵州黔东南·期中"
+    },
+    {
+        "id":  "194",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "二(1)班举行\"我爱阅读\"活动.\n(1)小刚第一天读了46页，第二天读了18页。两天一共读了多少页。\n(2)小丽每天读9页书,7天一共读了多少页。",
+        "options":  [
+
+                    ],
+        "answer":  "64页;63页",
+        "solution":  "【分析】(1)总页数=两天页数相加;(2)总页数=每天阅读页数×天数.\n【详解】(1)46+18=64(页);(2)9×7=63(页)。",
+        "knowledge_points":  [
+                                 "两位数与两位数的进位加法",
+                                 "9的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级下·河南许昌·开学考试"
+    },
+    {
+        "id":  "195",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "林老师买了5盒铅笔和4盒水笔，每盒铅笔有8支。一共买了多少支铅笔。",
+        "options":  [
+
+                    ],
+        "answer":  "40支",
+        "solution":  "【分析】只问铅笔数量，铅笔总支数=每盒铅笔支数×盒数.\n【详解】8×5=40(支),答：一共买了40支铅笔。",
+        "knowledge_points":  [
+                                 "8的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·福建福州·期末"
+    },
+    {
+        "id":  "196",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "小松鼠和它的7个小伙伴去采松果，每只采了5个松果，它们一共采了多少个松果。",
+        "options":  [
+
+                    ],
+        "answer":  "40个",
+        "solution":  "【分析】共有1+7=8只松鼠，总数=每只采的数量×只数.\n【详解】1+7=8(只),5×8=40(个),答：它们一共采了40个松果。",
+        "knowledge_points":  [
+                                 "8的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·浙江台州·期末"
+    },
+    {
+        "id":  "197",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "点点一共要写60个毛笔字，他每天写9个，他一个星期(7天)能写完吗。",
+        "options":  [
+
+                    ],
+        "answer":  "能",
+        "solution":  "【分析】一周写的总字数=9×7，与60比较大小判断是否能写完.\n【详解】9×7=63\u003e60，答：他一个星期能写完。",
+        "knowledge_points":  [
+                                 "100以内数的比大小",
+                                 "9的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·浙江台州·期末"
+    },
+    {
+        "id":  "198",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "同学们在操场上跳绳，每8个人一组，分成4组。一共有多少人在跳绳。",
+        "options":  [
+
+                    ],
+        "answer":  "32人",
+        "solution":  "【分析】总人数=每组人数×组数.\n【详解】8×4=32(人),答：一共有32人在跳绳。",
+        "knowledge_points":  [
+                                 "8的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·广东云浮·期末"
+    },
+    {
+        "id":  "199",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "除夕当晚，京京家准备了一桌丰盛的年夜饭。家里一共有9人，每人需要一双筷子，京京需要给大家准备多少根筷子。",
+        "options":  [
+
+                    ],
+        "answer":  "18根",
+        "solution":  "【分析】每人一双筷子等于2根，总根数=人数*2.\n【详解】9×2=18(根),答：需要准备18根筷子。",
+        "knowledge_points":  [
+                                 "9的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·河南三门峡·期末"
+    },
+    {
+        "id":  "200",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "春节期间，合力超市举办优惠活动，下面的商品买满80元可减10元.\n\n![](images/1a485d6f581e56943e6d1403ac30a3883af5285fde32b91c3e78b25bfcda39e6.jpg)\n![](images/e3552554d7b6c296f2c330f4db787a8cc0db5ceb3f9d02c1c8c95d86b50e9b70.jpg)\n![](images/425e3ad025e1525d9db012219379da83fff10f508a4f3a592f58b750725355a5.jpg)\n![](images/6e49f13a660dcbea8cab73f83795b4c6914fa1188a5244e64b03243c161b9ff2.jpg)\n\n(1)小红买了9盒巧克力，要付多少钱。\n(2)玲玲带了15元钱，正好买两样零食(不重复),她买了哪两样零食。",
+        "options":  [
+
+                    ],
+        "answer":  "71元;一盒巧克力和一袋水果糖",
+        "solution":  "【分析】(1)先用9*单价求出总价，根据是否满80决定是否减10;(2)根据价格表找出两种商品价格之和为15的组合.\n【详解】(1)9×9=81(元),81\u003e80，可享受满80减10优惠，实付81-10=71(元).\n(2)9+6=15(元),说明玲玲买了一盒巧克力和一袋水果糖。",
+        "knowledge_points":  [
+                                 "\"提问题\"\"填条件\"问题",
+                                 "100以内数的比大小",
+                                 "9加几的进位加法",
+                                 "9的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·贵州铜仁·期末"
+    },
+    {
+        "id":  "201",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "王阿姨买了3盒羽毛球，每盒8个，还买了3盒乒乓球。下面的问题中，可以根据以上数学信息解决的是( )。",
+        "options":  [
+                        "A. 王阿姨一共买了多少个球。",
+                        "B. 王阿姨买了多少个乒乓球。",
+                        "C. 王阿姨买了多少个羽毛球。"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】羽毛球的总个数可以由\"每盒8个,3盒\"算出;乒乓球没有给出每盒多少个，无法算出乒乓球或总球数.\n【详解】8×3=24(个),可以求出王阿姨买了24个羽毛球，因此能解决的问题是\"王阿姨买了多少个羽毛球。\"。故答案为:C",
+        "knowledge_points":  [
+                                 "\"提问题\"\"填条件\"问题",
+                                 "8的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·河南商丘·期末"
+    },
+    {
+        "id":  "202",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "每人浇4棵树,8个人浇( )棵。",
+        "options":  [
+                        "A. 12",
+                        "B. 30",
+                        "C. 32"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】总棵数=每人浇的棵数×人数.\n【详解】4×8=32(棵),8个人浇32棵。故答案为:C",
+        "knowledge_points":  [
+                                 "8的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·青海西宁·期末"
+    },
+    {
+        "id":  "203",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "根据( )只能写出一个乘法算式。",
+        "options":  [
+                        "A. 一九得九",
+                        "B. 四四十六",
+                        "C. 六八四十八"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】两个乘数相同的口诀只能写出1个乘法算式;乘数不同的口诀能写出2个(交换乘数顺序).\n【详解】\"一九得九\"可写1×9和9×1;\"六八四十八\"可写6×8和8×6;\"四四十六\"只能写4×4=16。故答案为:B",
+        "knowledge_points":  [
+                                 "4的乘法口诀及应用",
+                                 "8的乘法口诀及应用",
+                                 "9的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·青海西宁·期末"
+    },
+    {
+        "id":  "204",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "二年级1班图书角的书架有9层，每层放9本书，同学们借走了8本书，还剩( )本书。",
+        "options":  [
+                        "A. 89",
+                        "B. 73",
+                        "C. 63"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】总书数=每层本数×层数，再减去借走的本数.\n【详解】9×9-8=81-8=73(本),还剩73本。故答案为:B",
+        "knowledge_points":  [
+                                 "9的乘法口诀及应用",
+                                 "表内乘加，乘减"
+                             ],
+        "source":  "24-25二年级上·陕西延安·期末"
+    },
+    {
+        "id":  "205",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "小勇看一本课外书，按照他说的话，这本书不可能有( )页.\n\n![](images/7934d12dbb96a486c2a86b6813ebe8ce3733a05667cf68b577da51b142b348ca.jpg)",
+        "options":  [
+                        "A. 41",
+                        "B. 46",
+                        "C. 49"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】他每天最多看6页，连续看8天最多能看6×8=48页，所以书的总页数不可能大于48.\n【详解】6×8=48(页),8天最多看48页，所以书不可能有49页。故答案为:C",
+        "knowledge_points":  [
+                                 "8的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·浙江台州·期末"
+    },
+    {
+        "id":  "206",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "结果比63大的式子是( )。",
+        "options":  [
+                        "A. 7×8-23",
+                        "B. 7+7+7",
+                        "C. 8×8+17"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】分别算出三个式子的值，与63比较大小.\n【详解】7×8-23=56-23=33\u003c63;7+7+7=21\u003c63;8×8+17=64+17=81\u003e63。比63大的只有8×8+17。故答案为:C",
+        "knowledge_points":  [
+                                 "100以内数的比大小",
+                                 "同数连加的应用",
+                                 "乘加，乘减混合运算"
+                             ],
+        "source":  "24-25二年级上·四川广元·期末"
+    },
+    {
+        "id":  "207",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "找规律填数.\n\n(1)( ),24,32,40,48.\n(2)64,59,( ),49,44。",
+        "options":  [
+
+                    ],
+        "answer":  "16;54",
+        "solution":  "【分析】(1) 24,32,40,48是8的乘法口诀中3×8到6×8的积，前一项应是2×8;(2) 64到59,49到44都是每次减5，中间项=59-5.\n【详解】2×8=16;59-5=54。所以填16;54。",
+        "knowledge_points":  [
+                                 "两位数与两位数的退位减法",
+                                 "8的乘法口诀及应用",
+                                 "整数排列的规律"
+                             ],
+        "source":  "24-25二年级上·四川乐山·期末"
+    },
+    {
+        "id":  "208",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "有一些水果，比40个多，比50个少，把这些水果平均分给8个小朋友正好分完。这些水果有( )个。",
+        "options":  [
+
+                    ],
+        "answer":  "48",
+        "solution":  "【分析】在8的乘法口诀中找积在40与50之间的数:5×8=40,6×8=48,7×8=56.\n【详解】40\u003c48\u003c50\u003c56，因此这些水果有48个。",
+        "knowledge_points":  [
+                                 "100以内数的比大小",
+                                 "8的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·湖南湘西·期末"
+    },
+    {
+        "id":  "209",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "4+4+4=( )×( ),( )×6+9=63。",
+        "options":  [
+
+                    ],
+        "answer":  "3;4;9",
+        "solution":  "【分析】同数连加可改写为乘法;第二空先用63-9求出几个6的和，再反推乘法算式.\n【详解】4+4+4表示3个4相加，可写成3×4或4×3;63-9=54,6×9=54，所以9×6+9=63。故答案为:3;4;9。",
+        "knowledge_points":  [
+                                 "初步认识乘法意义",
+                                 "9的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·湖南湘西·期末"
+    },
+    {
+        "id":  "210",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "括号里最大能填几。\n\n4×( )\u003c29;45\u003e( )×8\n( )×9\u003c40;55\u003e6×( )",
+        "options":  [
+
+                    ],
+        "answer":  "7;5;4;9",
+        "solution":  "【分析】对每个不等式用相关乘法口诀和大小比较，找满足条件的最大整数.\n【详解】4×7=28\u003c29,4×8=32\u003e29，故最大为7;5×8=40\u003c45,6×8=48\u003e45，故45\u003e5×8，最大为5;4×9=36\u003c40,5×9=45\u003e40，故最大为4;6×9=54\u003c55,6×10=60\u003e55，故55\u003e6×9，最大为9。",
+        "knowledge_points":  [
+                                 "100以内数的比大小",
+                                 "7的乘法口诀及应用",
+                                 "8的乘法口诀及应用",
+                                 "9的乘法口诀及应用"
+                             ],
+        "source":  "23-24二年级上·湖南长沙·期末"
+    },
+    {
+        "id":  "211",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "8+8+8+8=( ),写成乘法算式是( ),用口诀( )计算。",
+        "options":  [
+
+                    ],
+        "answer":  "32;4×8=32或8×4=32;四八三十二",
+        "solution":  "【分析】4个8的和可以写作乘法;乘法口诀\"四八三十二\"可计算.\n【详解】8+8+8+8=32，乘法为4×8=32或8×4=32，用\"四八三十二\"计算。",
+        "knowledge_points":  [
+                                 "同数连加的应用",
+                                 "8的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·湖南湘西·期末"
+    },
+    {
+        "id":  "212",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "9+9+9+9=( ),写成乘法算式是( )或( ),计算时用的乘法口诀是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "36;4×9=36;9×4=36;四九三十六",
+        "solution":  "【分析】4个9的和改写为乘法，利用9的乘法口诀求值.\n【详解】9+9+9+9=36，写成乘法是4×9=36或9×4=36，口诀\"四九三十六\"。",
+        "knowledge_points":  [
+                                 "同数连加的应用",
+                                 "9的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·广东肇庆·期末"
+    },
+    {
+        "id":  "213",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "按规律，填数.\n\n7,14,( ),28,35,( )。",
+        "options":  [
+
+                    ],
+        "answer":  "21;42",
+        "solution":  "【分析】这是7的乘法口诀的积按顺序排列，从1×7到6×7.\n【详解】2×7=14,3×7=21,4×7=28,5×7=35,6×7=42，故数列为7,14,21,28,35,42。",
+        "knowledge_points":  [
+                                 "7的乘法口诀及应用",
+                                 "整数排列的规律"
+                             ],
+        "source":  "24-25二年级上·湖南湘西·期末"
+    },
+    {
+        "id":  "214",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "一个乘数是9，另一个乘数是3，积是( );4个6相加，和是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "27;24",
+        "solution":  "【分析】根据9和3的乘法口诀，\"四六二十四\"求值.\n【详解】9×3=27;4×6=24。故积是27,4个6的和是24。",
+        "knowledge_points":  [
+                                 "同数连加的应用",
+                                 "6的乘法口诀及应用",
+                                 "9的乘法口诀及应用"
+                             ],
+        "source":  "20-21二年级上·湖南长沙·期末"
+    },
+    {
+        "id":  "215",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "买6支标价为8元的钢笔，全部用10元的现金付，至少要付( )张。",
+        "options":  [
+
+                    ],
+        "answer":  "5",
+        "solution":  "【分析】总价=单价×数量，再看用多少张10元纸币才能达到或超过这个金额.\n【详解】8×6=48(元),用10元纸币至少要5张(50元)才够，故答案为5张。",
+        "knowledge_points":  [
+                                 "8的乘法口诀及应用",
+                                 "十元以上人民币的认识与计算"
+                             ],
+        "source":  "24-25二年级上·湖南株洲·期末"
+    },
+    {
+        "id":  "216",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "找规律:\n\n16,24,32,( )。",
+        "options":  [
+
+                    ],
+        "answer":  "40",
+        "solution":  "【分析】这些数是8的乘法口诀中2×8,3×8,4×8,5×8的积.\n【详解】2×8=16,3×8=24,4×8=32,5×8=40。",
+        "knowledge_points":  [
+                                 "8的乘法口诀及应用",
+                                 "整数排列的规律"
+                             ],
+        "source":  "24-25二年级上·湖南株洲·期末"
+    },
+    {
+        "id":  "217",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "括号里最大能填几。\n\n( )×4\u003c19;34\u003e5×( )\n25\u003e( )×6;17\u003e3×( )",
+        "options":  [
+
+                    ],
+        "answer":  "4;6;4;5",
+        "solution":  "【分析】利用含4,5,6,3的乘法口诀和不等式，把握\"小于且最接近\"和\"大于且最接近\"的思路求最大整数.\n【详解】4×4=16\u003c19,5×4=20\u003e19，所以最大填4;5×6=30,5×7=35,30\u003c34\u003c35，所以最大填6;4×6=24\u003c25,5×6=30\u003e25，所以最大填4;3×5=15\u003c17,3×6=18\u003e17，所以最大填5。",
+        "knowledge_points":  [
+                                 "100以内数的比大小",
+                                 "5的乘法口诀及应用",
+                                 "6的乘法口诀及应用",
+                                 "7的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·安徽黄山·期末"
+    },
+    {
+        "id":  "218",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.94,
+        "question":  "填口诀，讲故事。《西游记》讲述了唐僧师徒四人历经九九( )难去西天取经的故事，途中孙悟空施展八九( )般变化，猪八戒拿着九齿钉耙，不管三七( ),把妖怪打得落花流水。",
+        "options":  [
+
+                    ],
+        "answer":  "八十一;七十二;二十一",
+        "solution":  "【分析】根据九九，八九，三七等乘法口诀填成完整的句子.\n【详解】九九八十一，八九七十二，三七二十一。",
+        "knowledge_points":  [
+                                 "7的乘法口诀及应用",
+                                 "9的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·湖南湘西·期末"
+    },
+    {
+        "id":  "219",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "括号里最大能填几。\n\n35+( )\u003c74;45\u003e5×( );91-( )\u003c45",
+        "options":  [
+
+                    ],
+        "answer":  "38;8;47",
+        "solution":  "【分析】第1,3题用\"比某数小1\"法求和或差，再反求括号;第2题用5的乘法口诀找小于45的最大积.\n【详解】35+()最大但\u003c74，和应为73,73-35=38;45\u003e5×8=40,45=5×9，故最大填8;91-()最大但\u003c45，差应为44,91-44=47。",
+        "knowledge_points":  [
+                                 "100以内数的比大小",
+                                 "两位数与两位数的退位减法",
+                                 "8的乘法口诀及应用",
+                                 "9的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·湖南湘西·期末"
+    },
+    {
+        "id":  "220",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "综合填空题",
+        "difficulty":  0.85,
+        "question":  "在括号内填上\"+\"\"-\"\"*\"\"\u003e\"\"\u003c\"或\"=\".\n\n8( )5=40;56( )9=65;8( )12-4;7( )4( )5=23;2×2( )2+2;73( )8×9;8×3( )6×4;1+1( )1×1;66( )9=57;11( )8=3",
+        "options":  [
+
+                    ],
+        "answer":  "*;+;=;*;-;=;\u003e;=;\u003e;-;-",
+        "solution":  "【分析】前两题看等号两侧大小决定加/乘/减;后面先算式子再比较，或用乘法，加减法等价变形判断运算符或比较符号.\n【详解】8×5=40;56+9=65;8=12-4;7×4-5=23;2×2=2+2;73\u003e8×9;8×3=6×4;1+1\u003e1×1;66-9=57;11-8=3。",
+        "knowledge_points":  [
+                                 "一位数与两位数的退位减法",
+                                 "6的乘法口诀及应用",
+                                 "8的乘法口诀及应用",
+                                 "9的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·河南郑州·期末"
+    },
+    {
+        "id":  "221",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "把乘法口诀补充完整.\n\n二三( );三( )十二;( )九二十七;( )( )三十六",
+        "options":  [
+
+                    ],
+        "answer":  "得六;四;三;六;六",
+        "solution":  "【分析】按照熟悉的口诀\"二三得六\"\"三四十二\"\"三九二十七\"\"六六三十六\"等补全汉字.\n【详解】二三得六;三四十二;三九二十七;六六三十六。",
+        "knowledge_points":  [
+                                 "3的乘法口诀及应用",
+                                 "4的乘法口诀及应用",
+                                 "6的乘法口诀及应用",
+                                 "9的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·河南郑州·期末"
+    },
+    {
+        "id":  "222",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "有一个两位数，它是7与一位数相乘的积，个位上的数字比十位上的数字大1，这个两位数是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "56",
+        "solution":  "【分析】在7的乘法口诀中找积为两位数且个位比十位大1的积.\n【详解】7×8=56,5和6满足个位比十位大1，因此该两位数是56。",
+        "knowledge_points":  [
+                                 "8的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·浙江杭州·期末"
+    },
+    {
+        "id":  "223",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "括号里最大能填几。\n\n6×7\u003e( );8×( )\u003c72;20\u003e( )×8;9×4\u003e( )+18;31+( )\u003c5×9;( )×8\u003c46+19",
+        "options":  [
+
+                    ],
+        "answer":  "41;8;2;17;13;8",
+        "solution":  "【分析】结合乘法口诀和加减法，分别算出等式一侧的值，再确定另一侧的最大整数使不等式刚好成立但不破坏大小关系.\n【详解】6×7=42，所以括号里最大填41;8×8=64\u003c72,8×9=72，所以最大填8;2×8=16\u003c20,3×8=24\u003e20，所以最大填2;9×4=36,17+18=35\u003c36,18+18=36，所以最大填17;5×9=45,31+13=44\u003c45,31+14=45，所以最大填13;46+19=65,8×8=64\u003c65,9×8=72\u003e65，所以最大填8。",
+        "knowledge_points":  [
+                                 "100以内数的比大小",
+                                 "两位数与两位数的退位减法",
+                                 "8的乘法口诀及应用",
+                                 "9的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·浙江杭州·期末"
+    },
+    {
+        "id":  "224",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "在括号里填上\"\u003e\"\"\u003c\"或\"=\".\n\n3×4( )2×6;5×7( )40;8×4( )32;6×5( )32-3",
+        "options":  [
+
+                    ],
+        "answer":  "=;\u003c;=;\u003e",
+        "solution":  "【分析】先求每个算式结果，再比较大小.\n【详解】3×4=12,2×6=12，故\"=\";5×7=35\u003c40，故\"\u003c\";8×4=32，与32相等，故\"=\";6×5=30,32-3=29,30\u003e29，故\"\u003e\"。",
+        "knowledge_points":  [
+                                 "100以内数的比大小",
+                                 "6的乘法口诀及应用",
+                                 "7的乘法口诀及应用",
+                                 "8的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·江西南昌·期末"
+    },
+    {
+        "id":  "225",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "把下面的乘法口诀填写完整.\n\n七( )六十三;四( )二十四;( )八四十八",
+        "options":  [
+
+                    ],
+        "answer":  "九;六;六",
+        "solution":  "【分析】根据乘法口诀填写缺少的部分.\n【详解】根据乘法口诀依次可得：七九六十三;四六二十四;六八四十八。",
+        "knowledge_points":  [
+                                 "6的乘法口诀及应用",
+                                 "8的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·江西南昌·期末"
+    },
+    {
+        "id":  "226",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在括号填上合适的数.\n\n6×( )=42;( )×8=72;( )×( )=36",
+        "options":  [
+
+                    ],
+        "answer":  "7;9;6;6",
+        "solution":  "【分析】用相应的乘法口诀反向确定乘数.\n【详解】六七四十二，所以6×7=42;八九七十二，所以9×8=72;六六三十六，所以6×6=36。",
+        "knowledge_points":  [
+                                 "6的乘法口诀及应用",
+                                 "7的乘法口诀及应用",
+                                 "9的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·河南商丘·期末"
+    },
+    {
+        "id":  "227",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "8×7-8=( );5×7=5×5+( )",
+        "options":  [
+
+                    ],
+        "answer":  "48;10",
+        "solution":  "【分析】8×7-8表示7个8减1个8，即6个8;第二小题用七五三十五和五五二十五比较差值.\n【详解】8×7-8=56-8=48;5×7=35,5×5=25,35-25=10，所以5×7=5×5+10。",
+        "knowledge_points":  [
+                                 "两位数与两位数的不退位减法",
+                                 "5的乘法口诀及应用",
+                                 "7的乘法口诀及应用",
+                                 "8的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·山东济宁·期末"
+    },
+    {
+        "id":  "228",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "在( )里填上合适的数.\n\n9×( )=18;46-( )=6;( )×2=2;23+5-( )=10;7×( )=63",
+        "options":  [
+
+                    ],
+        "answer":  "2;40;1;18;9",
+        "solution":  "【分析】依次根据乘法口诀和加减法的逆运算求出括号内的数.\n【详解】9×2=18;46-40=6，所以填40;1×2=2，所以填1;23+5=28,28-18=10，所以填18;7×9=63，所以填9。",
+        "knowledge_points":  [
+                                 "100以内数的加减混合运算",
+                                 "2的乘法口诀及应用",
+                                 "9的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·河南郑州·期末"
+    },
+    {
+        "id":  "229",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "计算7×9-7时，可以用口诀( )求得数。",
+        "options":  [
+
+                    ],
+        "answer":  "七八五十六",
+        "solution":  "【分析】7×9-7表示9个7的和减去1个7，结果是8个7的和，即7×8.\n【详解】7×8或8×7都可用口诀\"七八五十六\"，因此计算7×9-7可以用口诀七八五十六求得数。",
+        "knowledge_points":  [
+                                 "8的乘法口诀及应用",
+                                 "9的乘法口诀及应用",
+                                 "表内乘加，乘减"
+                             ],
+        "source":  "24-25二年级上·河南郑州·期末"
+    },
+    {
+        "id":  "230",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "括号里最大能填几。\n\n( )+15\u003c55;40\u003e( )×9;6×( )\u003c50",
+        "options":  [
+
+                    ],
+        "answer":  "39;4;8",
+        "solution":  "【分析】①和要比55小1最大为54，再反求加数;②③用乘法口诀找出合适的乘数.\n【详解】55-1=54,54-15=39，所以39+15\u003c55;4×9=36,5×9=45,36\u003c40\u003c45，故40\u003e4×9，最大填4;6×8=48\u003c50,6×9=54\u003e50，故最大填8。",
+        "knowledge_points":  [
+                                 "两位数与两位数的退位减法",
+                                 "8的乘法口诀及应用",
+                                 "9的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·江西鹰潭·期末"
+    },
+    {
+        "id":  "231",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "一个乘数是6，另一个乘数是8，积是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "48",
+        "solution":  "【分析】求两个乘数的积，用乘法计算.\n【详解】6×8=48，因此这两个乘数的积是48。",
+        "knowledge_points":  [
+                                 "8的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·江西南昌·期末"
+    },
+    {
+        "id":  "232",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "3个8相加的和是( ),4和9相加的和是( ),28比( )少5。",
+        "options":  [
+
+                    ],
+        "answer":  "24;13;33",
+        "solution":  "【分析】求3个8相加的和用乘法计算，求4和9相加的和用加法计算，已知28比一个数少5，用28加5求这个数.\n【详解】3×8=24;4+9=13;要使\"28比□少5\"，则□=28+5=33。",
+        "knowledge_points":  [
+                                 "5~2加几的进位加法",
+                                 "一位数与两位数的进位加法",
+                                 "8的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·湖北随州·期末"
+    },
+    {
+        "id":  "233",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "聪聪看一本绘本，从第一页看起，平均每天看8页，看了5天，第6天应该从( )页开始看起。",
+        "options":  [
+
+                    ],
+        "answer":  "41",
+        "solution":  "【分析】先求前5天共看了多少页，再加1页就是第6天开始的页码.\n【详解】8×5=40(页),前5天共看40页，第6天应从第41页开始看。",
+        "knowledge_points":  [
+                                 "表内乘加，乘减"
+                             ],
+        "source":  "24-25二年级上·湖北随州·期末"
+    },
+    {
+        "id":  "234",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "括号里最大能填几。\n\n( )×6\u003c28;9×( )\u003c50;7×( )\u003c65",
+        "options":  [
+
+                    ],
+        "answer":  "4;5;9",
+        "solution":  "【分析】根据表内乘法口诀及整数比较大小的方法来解决此题即可.\n【详解】4×6=24,5×6=30,24\u003c28\u003c30，故,4×6\u003c28;9×5=45,9×6=54,45\u003c50\u003c54，故,9×5\u003c50;7×9=63,63\u003c65，故,7×9\u003c65。",
+        "knowledge_points":  [
+                                 "100以内数的比大小",
+                                 "6的乘法口诀及应用",
+                                 "9的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·河南商丘·期末"
+    },
+    {
+        "id":  "235",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "读故事，填口诀。唐僧师徒四人去西天取经。孙悟空有经过( )四十九天炼成的火眼金睛，他施展出( )九七十二般变化，遇到妖怪不管三( )二十一，举起金箍棒就打。护送师傅历经九九( )难终于取得真经。",
+        "options":  [
+
+                    ],
+        "answer":  "七七;八;七;八十一",
+        "solution":  "【分析】根据生活经验及表内乘法口诀来解决此题即可.\n【详解】由题意分析得：唐僧师徒四人去西天取经。孙悟空有经过七七四十九天炼成的火眼金睛，他施展出八九七十二般变化，遇到妖怪不管三七二十一，举起金箍棒就打。护送师傅历经九九八十一难终于取得真经。",
+        "knowledge_points":  [
+                                 "7的乘法口诀及应用",
+                                 "8的乘法口诀及应用",
+                                 "9的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·河南郑州·期末"
+    },
+    {
+        "id":  "236",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "( )里最大填几.\n\n75\u003e( )×8;7×( )\u003c58;( )+40\u003c62",
+        "options":  [
+
+                    ],
+        "answer":  "9;8;21",
+        "solution":  "【分析】整数的大小比较：比较数的大小，先看位数的多少，位数多的数就大;位数相同，从高位开始比较，高位上的数大则这个数大，高位上的数相同，就比较下一位。几个十就是几十。乘法算式中两个乘数是口诀中的前两个数，积是口诀中的后一个数，写算式时两个乘数可互换位置。前面两小题根据数的大小关系和乘法口诀解题。最后一题把小于号看作等号算出另一个加数，然后用另个加数减1即可求解.\n【详解】八九七十二,8个10是80，最大填9,75\u003e9×8;七八五十六，七九六十三，最大填8,7×8\u003c58;62-40=22,22-1=21，所以21+40\u003c62。",
+        "knowledge_points":  [
+                                 "100以内数的比大小",
+                                 "两位数与整十数的减法",
+                                 "8的乘法口诀及应用",
+                                 "9的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·山东济宁·期末"
+    },
+    {
+        "id":  "237",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "小明看一本故事书，每天看9页，看了6天，一共看了( )页，还有32页没有看完，这本故事书共有( )页。",
+        "options":  [
+
+                    ],
+        "answer":  "54;86",
+        "solution":  "【分析】用每天看的页数乘看的天数，即可求出6天看的页数;总页数=看的页数+没看的页数，据此解答即可.\n【详解】9×6=54(页),54+32=86(页),小明看一本故事书，每天看9页，看了6天，一共看了54页，还有32页没有看完，这本故事书共有86页。",
+        "knowledge_points":  [
+                                 "两位数与两位数的不进位加法",
+                                 "9的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·青海西宁·期末"
+    },
+    {
+        "id":  "238",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在括号里填\"\u003e\"\"\u003c\"或\"=\".\n\n9×2( )18;4×7( )25;97-25-47( )26;3×8( )20;6×6( )38;78-24+39( )83",
+        "options":  [
+
+                    ],
+        "answer":  "=;\u003e;\u003c;\u003e;\u003c;\u003e",
+        "solution":  "【分析】先根据乘法口诀或两位数加减法的计算法则，计算得出结果，再比较大小即可.\n【详解】9×2=18;4×7=28，故4×7\u003e25;97-25-47=72-47=25，故97-25-47\u003c26;3×8=24，故3×8\u003e20;6×6=36，故6×6\u003c38;78-24+39=54+39=93，故78-24+39\u003e83。",
+        "knowledge_points":  [
+                                 "100以内数的比大小",
+                                 "100以内数的加减混合运算",
+                                 "8的乘法口诀及应用",
+                                 "9的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·青海西宁·期末"
+    },
+    {
+        "id":  "239",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "把乘法口诀补充完整.\n\n四五( );五九( );六( )四十二\n三( )二十一;七八( );九九( )",
+        "options":  [
+
+                    ],
+        "answer":  "二十;四十五;七;七;五十六;八十一",
+        "solution":  "【分析】根据乘法口诀填空。口诀中的前两个数是乘数，可交换位置，后一个数是积，填空时，缺少口诀中的哪个数，就把那个数填在括号即可.\n【详解】四五二十;五九四十五;六七四十二;三七二十一;七八五十六;九九八十一。",
+        "knowledge_points":  [
+                                 "7的乘法口诀及应用",
+                                 "8的乘法口诀及应用",
+                                 "9的乘法口诀及应用",
+                                 "乘法表"
+                             ],
+        "source":  "24-25二年级上·青海西宁·期末"
+    },
+    {
+        "id":  "240",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "1辆小汽车有4个轮子,6辆小汽车有( )个轮子,9辆小汽车有( )个轮子.\n\n![](images/f5ab294fca1439cb2830419c5062971495de01c90fb1c4bba5ba0e4a9e1c2416.jpg)",
+        "options":  [
+
+                    ],
+        "answer":  "24;36",
+        "solution":  "【分析】每辆小汽车需要的车轮乘小汽车的数量，等于一共需要的车轮数，据此解答即可.\n【详解】6辆小汽车:4×6=24(个),9辆小汽车:4×9=36(个),1辆小汽车有4个轮子,6辆小汽车有24个轮子,9辆小汽车有36个轮子。",
+        "knowledge_points":  [
+                                 "6的乘法口诀及应用",
+                                 "9的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·陕西延安·期末"
+    },
+    {
+        "id":  "241",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "用8厘米长的尺子量一本书的长，正好量了3次。这本书长( )厘米。",
+        "options":  [
+
+                    ],
+        "answer":  "24",
+        "solution":  "【分析】由题意可知，这本书的长度量了3次，量一次是8厘米，则这本书的长度等于3个8厘米，用乘法求出3个8的和是多少即可解决.\n【详解】8×3=24(厘米),即，用8厘米长的尺子量一本书的长，正好量了3次。这本书长24厘米。",
+        "knowledge_points":  [
+                                 "初步认识乘法意义",
+                                 "8的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·湖北随州·期末"
+    },
+    {
+        "id":  "242",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "把下面的乘法口诀补充完整.\n\n三七( );五( )四十;( )十六;( )八十一",
+        "options":  [
+
+                    ],
+        "answer":  "二十一;八;四四或二八;九九",
+        "solution":  "【分析】根据题意，熟练掌握表内乘法口诀，一一得一，二二得四，一三得三，二三得六，三三得九，四二得八，三四十二，四四十六，一五得五，二五一十，三五十五，四五二十，五五二十五，一六得六，二六十二，三六十八，四六二十四，五六三十，六六三十六，一七得七，二七十四，三七二十一，四七二十八，五七三十五，六七四十二，七七四十九，一八得八，二八十六，三八二十四，四八三十二，五八四十，六八四十八，七八五十六，八八六十四，一九得九，二九十八，三九二十七，四九三十六，五九四十五，六九五十四，七九六十三，八九七十二，九九八十一，据此解答.\n【详解】三七二十一;五八四十;四四十六或二八十六;九九八十一。",
+        "knowledge_points":  [
+                                 "4的乘法口诀及应用",
+                                 "7的乘法口诀及应用",
+                                 "8的乘法口诀及应用",
+                                 "9的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·贵州黔西·期末"
+    },
+    {
+        "id":  "243",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "在括号里填上\"\u003e\"\"\u003c\"或\"=\".\n\n7×8( )9×6;7×4-18( )28;1米-35厘米( )40厘米;5×6+18( )7×9-24;54-16( )30+8;98厘米( )1米",
+        "options":  [
+
+                    ],
+        "answer":  "\u003e;\u003c;\u003e;\u003e;=;\u003c",
+        "solution":  "【分析】(1)根据乘法口诀\"七八五十六\"和\"六九五十四\"把结果计算出来，再进行比较即可;(2)将7×4-18结果计算出来，再与28进行比较即可;(3)根据1米=100厘米，将1米-35厘米结果计算出来，再与40厘米进行比较即可;(4)将5×6+18和7×9-24结果计算出来，再进行比较即可;(5)将54-16和30+8结果计算出来，再进行比较即可;(6)根据米和厘米之间的进率1米=100厘米，将1米转化成100厘米，再与98厘米进行比较即可.\n【详解】(1)7×8=56,6×9=54,56\u003e54，所以7×8\u003e6×9;(2)7×4-18=28-18=10,10\u003c28，所以7×4-18\u003c28;(3)1米=100厘米,1米-35厘米=65厘米,65\u003e40，所以1米-35厘米\u003e40厘米;(4)5×6+18=30+18=48和7×9-24=63-24=39,48\u003e39，所以5×6+18\u003e7×9-24;(5)54-16=38,30+8=38,38=38，所以54-16=30+8;(6)1米=100厘米,98\u003c100，所以98厘米\u003c1米。",
+        "knowledge_points":  [
+                                 "两位数与两位数的退位减法",
+                                 "9的乘法口诀及应用",
+                                 "乘加，乘减混合运算",
+                                 "厘米和米之间的进率与换算"
+                             ],
+        "source":  "24-25二年级上·四川广元·期末"
+    },
+    {
+        "id":  "244",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "比80少7的数是( );( )比72多8;比7个9的和少12的数是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "73;80;51",
+        "solution":  "【分析】求比一个数少几的数是多少用减法计算，求比80少7的数是多少，用80减7;求比一个数多几的数是多少用加法计算，求比72多8的数是多少，用72加8;求7个9相加用7乘9，求比7个9的和少12的数是多少，即用7乘9再减去12即可.\n【详解】80-7=73;72+8=80;7×9-12=63-12=51，所以比80少7的数是73;80比72多8;比7个9的和少12的数是51。",
+        "knowledge_points":  [
+                                 "一位数与两位数的进位加法",
+                                 "一位数与两位数的退位减法",
+                                 "表内乘加，乘减"
+                             ],
+        "source":  "24-25二年级上·四川广元·期末"
+    },
+    {
+        "id":  "245",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在括号里填上\"+\"\"-\"或\"*\".\n\n25( )5=30;2( )9=6( )3;56( )12=80( )12",
+        "options":  [
+
+                    ],
+        "answer":  "+;*;*;+;-",
+        "solution":  "【分析】填上\"+\"\"-\"或\"*\"的算式，根据整数加减法的计算法则及表内乘法口诀解答，如果最大的数出现在等号的右边，应该用加法或乘法，如果最大的数出现在等号的左边，应该用减法，通过验证解答即可.\n【详解】(1)通过观察，最大的数在等号的右边，考虑加法或乘法，由于20比较大，大数的乘法没有学过，验证加法算式,25+5=30,30=30，所以括号里填+;(2)通过观察，这组数大小差不多，并且数字较小，考虑乘法,2×9=18,6×3=18,18=18，所以第一个括号填*,第二个括号填*;(3)通过观察，这组数大小差不多，数字较大，有两位数不考虑乘法,56-12=44,80和12不管是加法或减法时，没有与它相等的结果;再考虑56+12=68,80-12=68,68=68，所以第一个括号填+,第二个括号填-。",
+        "knowledge_points":  [
+                                 "两位数与两位数的不进位加法",
+                                 "两位数与两位数的退位减法",
+                                 "6的乘法口诀及应用",
+                                 "9的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·四川广元·期末"
+    },
+    {
+        "id":  "246",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "比56多27的数是( );34比18多( );3个9的和是( );3和9的和是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "83;16;27;12",
+        "solution":  "【分析】求比一个数多几的数是多少，用加法计算;求一个数比另一个数多多少，用减法计算;求3个9的和是多少，用乘法计算;求3和9的和是多少，用加法计算，据此解答.\n【详解】56+27=83;34-18=16;3×9=27;3+9=12。比56多27的数是83;34比18多16;3个9的和是27;3和9的和是12。",
+        "knowledge_points":  [
+                                 "9加几的进位加法",
+                                 "两位数与两位数的进位加法",
+                                 "两位数与两位数的退位减法",
+                                 "9的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·四川广元·期末"
+    },
+    {
+        "id":  "247",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "比38多47的数是( );6个9相加的和是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "85;54",
+        "solution":  "【分析】求比38多47的数是多少，用加法计算;求6个9相加的和是多少，用乘法计算.\n【详解】38+47=85;6×9=54，比38多47的数是85;6个9相加的和是54。",
+        "knowledge_points":  [
+                                 "两位数与两位数的进位加法",
+                                 "9的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·湖北黄石·期末"
+    },
+    {
+        "id":  "248",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在括号里填上\"+\"\"-\"\"*\"或\"\u003e\"\"\u003c\"\"=\".\n\n4( )6=24;6( )9=15;5×7( )32;8×9( )73;25+8( )35;30( )6=24;2×6( )12;4×9( )34",
+        "options":  [
+
+                    ],
+        "answer":  "*;+;\u003e;\u003c;\u003c;-;=;\u003e",
+        "solution":  "【分析】①②⑥根据算式右边的数大于算式左边的数，结合乘法口诀可填\"+\"或\"*\"，算式右边的数小于算式左边的数可填\"-\";③④⑤⑦⑧先计算出各算式的答案，然后再进行比较大小。比较时，位数多的数就大;位数相同比较最高位，最高位大的数就大;最高位相同比较下一位，直到比较出结果为止.\n【详解】4(*)6=24;6(+)9=15;5×7=35,35\u003e32，则5×7\u003e32;8×9=72,72\u003c73，则8×9\u003c73;25+8=33,33\u003c35，则25+8\u003c35;30-6=24;2×6=12;4×9=36,36\u003e34，则4×9\u003e34。",
+        "knowledge_points":  [
+                                 "100以内数的比大小",
+                                 "一位数与两位数的进位加法",
+                                 "7的乘法口诀及应用",
+                                 "9的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·江西抚州·期末"
+    },
+    {
+        "id":  "249",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "5+5+5+5+4=( )×( )+( );8×3=( )+( )+( )",
+        "options":  [
+
+                    ],
+        "answer":  "5;4;4;8;8;8",
+        "solution":  "【分析】根据乘法的意义，求几个相同加数的和的简便运算叫做乘法;故求几个相同加数的和是多少，用乘法进行解答，此题即求4个5相加的和与4相加是多少;反之8×3，用3个8相加即可;据此解答.\n【详解】根据分析：求4个5相加的和与4相加是多少，根据乘法的意义,4个5相加的和是5×4，则:5+5+5+5+4=5×4+4=20+4=24,8×3，用3个8相加，则:8×3=8+8+8=24，所以5+5+5+5+4=5×4+4;8×3=8+8+8。",
+        "knowledge_points":  [
+                                 "同数连加的应用",
+                                 "初步认识乘法意义",
+                                 "5的乘法口诀及应用",
+                                 "8的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·湖南娄底·期末"
+    },
+    {
+        "id":  "250",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "春节到，人欢笑，贴窗花，放鞭炮。除夕夜，欢欢一家一起包饺子，一共包了8行，每行9个，一共包了( )个饺子。他们吃了54个饺子，还剩( )个饺子。",
+        "options":  [
+
+                    ],
+        "answer":  "72;18",
+        "solution":  "【分析】每行的个数乘行数等于一共包饺子的数量，用乘法计算;包饺子的总数量减去吃了的数量，等于还剩下饺子的数量，用减法计算，据此解答.\n【详解】根据分析可得:8×9=72(个),72-54=18(个),他们一共包了72个饺子，吃了一些后还剩下18个饺子。",
+        "knowledge_points":  [
+                                 "两位数与两位数的退位减法",
+                                 "9的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·河南驻马店·期末"
+    },
+    {
+        "id":  "251",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "小明在做一道乘法题时，把其中一个乘数9看成了6，算出的结果是30，正确的积应是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "45",
+        "solution":  "【分析】将错就错，既然将其中一个乘数看成了6，结果是30，那么我们可以这样想:□*6=30，根据乘法口诀\"五六三十\"，即5×6=30，可知□是5，也就是另一个乘数是5，然后用5×9来求出正确的积.\n【详解】由5×6=30，可知另一个乘数是5.5×9=45。小明在做一道乘法题时，把其中一个乘数9看成了6，算出的结果是30，正确的积应是45。",
+        "knowledge_points":  [
+                                 "6的乘法口诀及应用",
+                                 "9的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·湖北黄石·期末"
+    },
+    {
+        "id":  "252",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在括号里填上\"\u003e\"\"\u003c\"或\"=\".\n\n5×6( )5×5+5;9×9( )9+9;1米( )80厘米;6×7( )8×6;37+19( )6×9;6×6( )38",
+        "options":  [
+
+                    ],
+        "answer":  "=;\u003e;\u003e;\u003c;\u003e;\u003c",
+        "solution":  "【分析】根据乘法口诀，依次计算出各个算式的结果再比较大小。长度单位比较时，根据1米=100厘米，统一单位后再比较大小。比较时，位数多的数就大，位数相同比较最高位，最高位大的数就大，最高位相同比较下一位，直到比较出大小为止.\n【详解】5×6=30,5×5+5=30,30=30，故5×6=5×5+5;9×9=81,9+9=18,81大于18，故9×9\u003e9+9;1米=100厘米,100厘米大于80厘米，故1米\u003e80厘米;6×7=42,8×6=48,42小于48，故6×7\u003c8×6;37+19=56,6×9=54,56大于54，故37+19\u003e6×9;6×6=36,36小于38，故6×6\u003c38。",
+        "knowledge_points":  [
+                                 "100以内数的比大小",
+                                 "6的乘法口诀及应用",
+                                 "8的乘法口诀及应用",
+                                 "9的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·四川南充·期末"
+    },
+    {
+        "id":  "253",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "( )里最大能填几。\n\n6×( )\u003c50;( )×8\u003c41;7×( )\u003c30;24+( )\u003c31",
+        "options":  [
+
+                    ],
+        "answer":  "8;5;4;6",
+        "solution":  "【分析】根据表内乘法口诀，整数加减法计算法则及整数比较大小的方法来解决此题.\n【详解】6×8=48,6×9=54,48\u003c50\u003c54，故,6×8\u003c50;5×8=40,6×8=48,40\u003c41\u003c48，故,5×8\u003c41;7×4=28,7×5=35,28\u003c30\u003c35，故,7×4\u003c30;31-24=7,24+7=31,24+6=30,30\u003c31，故,24+6\u003c31。",
+        "knowledge_points":  [
+                                 "100以内数的比大小",
+                                 "7的乘法口诀及应用",
+                                 "8的乘法口诀及应用",
+                                 "9的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·河南南阳·期末"
+    },
+    {
+        "id":  "254",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "9个5相加的和是多少。列式是9+5=14。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】求几个相同加数的和，可以用乘法计算，用相同加数×个数或个数×相同加数.\n【详解】9个5相加的和是多少。列式是9×5=45，原题说法错误。故答案为: ×",
+        "knowledge_points":  [
+                                 "初步认识乘法意义",
+                                 "9的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·湖南湘西·期末"
+    },
+    {
+        "id":  "255",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "积是18，乘数一定是6和3。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】由乘法口诀\"三六十八\"可知，积是18，乘数是6和3;由乘法口诀\"二九十八\"可知，积是18，乘数是2和9;据此解决即可.\n【详解】由题意分析得：积是18，乘数是6和3，乘数也可以是2和9;原题说法错误。故答案为: ×",
+        "knowledge_points":  [
+                                 "6的乘法口诀及应用",
+                                 "9的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·河南郑州·期末"
+    },
+    {
+        "id":  "256",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "7个9相加的和是63。( )",
+        "options":  [
+
+                    ],
+        "answer":  "√",
+        "solution":  "【分析】求几个几相加的和是多少，用乘法计算，据此解答即可.\n【详解】7×9=63,7个9相加的和是63。故答案为:√",
+        "knowledge_points":  [
+                                 "9的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·河南郑州·期末"
+    },
+    {
+        "id":  "257",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "3个9相加和9个3相加的结果相等。( )",
+        "options":  [
+
+                    ],
+        "answer":  "√",
+        "solution":  "【分析】几个相同加数相加，可以写成加数与个数相乘的形式。乘法算式中两个乘数是口诀中的前两个数，积是口诀中的后一个数，写算式时两个乘数可互换位置.\n【详解】3个9相加和9个3相加都可以列式为:3×9=27。原题说法正确。故答案为:√",
+        "knowledge_points":  [
+                                 "同数连加的应用",
+                                 "9的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·湖北孝感·期末"
+    },
+    {
+        "id":  "258",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "做1朵花用8厘米彩带，做6朵这样的花要用48厘米彩带。( )",
+        "options":  [
+
+                    ],
+        "answer":  "√",
+        "solution":  "【分析】做一朵花用彩带的长度乘做的花朵数，求出共需要的彩带长度，即可解答.\n【详解】8×6=48(厘米),因此，做6朵这样的花要用48厘米彩带。原题说法正确。故答案为:√",
+        "knowledge_points":  [
+                                 "8的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·青海西宁·期末"
+    },
+    {
+        "id":  "259",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "李华和3个同学去看戏，票价每人8元，他们买票一共花了32元。( )",
+        "options":  [
+
+                    ],
+        "answer":  "√",
+        "solution":  "【分析】根据题意，先算出来一共有多少人，再用人数乘票价，即可算出一共花多少钱，最后判断对错.\n【详解】1+3=4(人),4×8=32(元),他们买票一共花了32元。故答案为:√",
+        "knowledge_points":  [
+                                 "8的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·湖北黄石·期末"
+    },
+    {
+        "id":  "260",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "判断题",
+        "difficulty":  0.65,
+        "question":  "7+7+7+7+7+5=7×5+5=8×5。( )",
+        "options":  [
+
+                    ],
+        "answer":  "√",
+        "solution":  "【分析】根据乘法的意义：求几个相同加数的和的简便运算，据此结合题干要求进行解答即可.\n【详解】7+7+7+7+7+5表示5个7的和加上1个5的和，即7×5+5=35+5=40,8×5表示8个5或5个8相加的和,8×5=40。所以7+7+7+7+7+5=7×5+5=8×5，原题说法正确。故答案为:√",
+        "knowledge_points":  [
+                                 "同数连加的应用",
+                                 "初步认识乘法意义",
+                                 "8的乘法口诀及应用",
+                                 "表内乘加，乘减"
+                             ],
+        "source":  "24-25二年级上·四川南充·期末"
+    },
+    {
+        "id":  "261",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "计算题",
+        "difficulty":  0.85,
+        "question":  "看谁算得又对又快.\n\n42-6=( );5×8=( );18-6=( );56+44=( );82-26=( );8×8=( );45-9=( );5×6=( )",
+        "options":  [
+
+                    ],
+        "answer":  "36;40;12;100;56;64;36;30",
+        "solution":  "【分析】本题包含一位数与两位数的退位减法，两位数与两位数的进位加法以及乘法口诀的应用。计算加减法时要注意进位和退位;乘法直接应用对应的口诀得出结果.\n【详解】42-6=36(个位2减6不够，向十位借1,12-6=6，十位剩3，得36);5×8=40(口诀\"五八四十\");18-6=12(个位8-6=2，十位1不变，不退位);56+44=100(个位6+4=10，向十位进1，十位5+4+1=10，向百位进1，得100);82-26=56(个位2减6不够，向十位借1,12-6=6，十位8借1剩7,7-2=5，得56);8×8=64(口诀\"八八六十四\");45-9=36(个位5减9不够，向十位借1,15-9=6，十位剩3，得36);5×6=30(口诀\"五六三十\")",
+        "knowledge_points":  [
+                                 "一位数与两位数的退位减法",
+                                 "两位数与两位数的进位加法",
+                                 "6的乘法口诀及应用",
+                                 "8的乘法口诀及应用"
+                             ],
+        "source":  "23-24二年级下·河北邢台·期中"
+    },
+    {
+        "id":  "262",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "计算题",
+        "difficulty":  0.85,
+        "question":  "看图列式计算.\n\n![](images/85bcc1a96178c4236d43c0389e9c12c493dd9058b8e38c377a60556e419fe207.jpg)\n\n□○□=□(条)",
+        "options":  [
+
+                    ],
+        "answer":  "8×4=32",
+        "solution":  "【分析】螃蟹用一段表示，是8只，小鱼的数量是同样长的4段，也就是4个8的和，可以用乘法计算，即每段表示的数量和段数相乘，就是总数量.\n【详解】8×4=32(条),小鱼有32条。",
+        "knowledge_points":  [
+                                 "图文问题",
+                                 "8的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·广东肇庆·期末"
+    },
+    {
+        "id":  "263",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "计算题",
+        "difficulty":  0.85,
+        "question":  "直接写得数.\n\n1×6=( );43+7=( );70+23=( );4×7+30=( );5×6+6=( );7×9-9=( );2×4=( );36-6=( );3×6=( );37+10-5=( );50-30+7=( );74-(80-6)=( );6×8=( );34+9=( );8×5=( );8×6-34=( );6×4-10=( );42-(6+34)=( )",
+        "options":  [
+
+                    ],
+        "answer":  "6;50;93;58;36;54;8;30;18;42;27;0;48;43;40;14;14;2",
+        "solution":  "【分析】本题包含乘法口诀，两位数加减法，加减混合运算，带括号的混合运算以及乘加乘减计算。计算时，乘法直接应用口诀;加减法要注意进位和退位;乘加乘减要先算乘法再算加减法;有括号的算式要先算括号里面的;没有括号的加减混合运算按从左到右的顺序计算.\n【详解】1×6=6(口诀\"一六得六\");43+7=50(个位3+7=10，向十位进1，十位4+1=5);70+23=93(个位0+3=3，十位7+2=9，不进位);4×7+30=28+30=58(先算乘法4×7=28，再算加法28+30=58);5×6+6=30+6=36(先算乘法5×6=30，再算加法30+6=36);7×9-9=63-9=54(先算乘法7×9=63，再算减法63-9=54);2×4=8(口诀\"二四得八\");36-6=30(个位6-6=0，十位3不变);3×6=18(口诀\"三六十八\");37+10-5=47-5=42(先算37+10=47，再算47-5=42);50-30+7=20+7=27(先算50-30=20，再算20+7=27);74-(80-6)=74-74=0(先算括号内80-6=74，再算74-74=0);6×8=48(口诀\"六八四十八\");34+9=43(个位4+9=13，向十位进1，十位3+1=4);8×5=40(口诀\"五八四十\");8×6-34=48-34=14(先算乘法8×6=48，再算减法48-34=14);6×4-10=24-10=14(先算乘法6×4=24，再算减法24-10=14);42-(6+34)=42-40=2(先算括号内6+34=40，再算减法42-40=2)",
+        "knowledge_points":  [
+                                 "两位数与两位数的不进位加法",
+                                 "100以内数的加减混合运算",
+                                 "6的乘法口诀及应用",
+                                 "8的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·河南郑州·期末"
+    },
+    {
+        "id":  "264",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "计算题",
+        "difficulty":  0.65,
+        "question":  "直接写出得数.\n\n2×8=( );97-17=( );5×5=( );52+7=( );7×8=( );45-18=( );44+49=( );32-8=( );29+16=( );9×2+58=( );47-(22-7)=( );55+15-36=( )",
+        "options":  [
+
+                    ],
+        "answer":  "16;80;25;59;56;27;93;24;45;76;32;34",
+        "solution":  "【分析】本题包含乘法口诀，两位数加减法(进位，退位),乘加以及带括号的加减混合运算。计算时，乘法直接应用口诀;加减法要注意进位和退位;乘加算式要先算乘法再算加法;有括号的算式要先算括号里面的;加减混合运算按从左到右的顺序计算.\n【详解】2×8=16(口诀\"二八十六\");97-17=80(个位7-7=0，十位9-1=8，不退位);5×5=25(口诀\"五五二十五\");52+7=59(个位2+7=9，十位5不变，不进位);7×8=56(口诀\"七八五十六\");45-18=27(个位5减8不够，向十位借1,15-8=7，十位4借1剩3,3-1=2，得27);44+49=93(个位4+9=13，向十位进1，十位4+4+1=9，得93);32-8=24(个位2减8不够，向十位借1,12-8=4，十位剩2，得24);29+16=45(个位9+6=15，向十位进1，十位2+1+1=4，得45);9×2+58=18+58=76(先算乘法9×2=18，再算加法18+58=76);47-(22-7)=47-15=32(先算括号内22-7=15，再算减法47-15=32);55+15-36=70-36=34(先算55+15=70，再算70-36=34)",
+        "knowledge_points":  [
+                                 "两位数与两位数的进位加法",
+                                 "两位数与两位数的退位减法",
+                                 "5的乘法口诀及应用",
+                                 "8的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·浙江杭州·期末"
+    },
+    {
+        "id":  "265",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "计算题",
+        "difficulty":  0.85,
+        "question":  "直接写出得数.\n\n9×7=( );8×3=( );56+21=( );3×3=( );7×6=( );61-35=( );4×6=( );9×5=( );6×8+30=( );4×8=( );2×6=( );7×5-13=( )",
+        "options":  [
+
+                    ],
+        "answer":  "63;24;77;9;42;26;24;45;78;32;12;22",
+        "solution":  "【分析】本题包含乘法口诀，两位数加减法以及乘加乘减混合运算。计算时，乘法直接应用对应的口诀;加减法要注意进位和退位;乘加乘减算式要先算乘法，再算加减法.\n【详解】9×7=63(口诀\"七九六十三\");8×3=24(口诀\"三八二十四\");56+21=77(个位6+1=7，十位5+2=7，不进位);3×3=9(口诀\"三三得九\");7×6=42(口诀\"六七四十二\");61-35=26(个位1减5不够，向十位借1,11-5=6，十位6借1剩5,5-3=2，得26);4×6=24(口诀\"四六二十四\");9×5=45(口诀\"五九四十五\");6×8+30=48+30=78(先算乘法6×8=48，再算加法48+30=78);4×8=32(口诀\"四八三十二\");2×6=12(口诀\"二六十二\");7×5-13=35-13=22(先算乘法7×5=35，再算减法35-13=22)",
+        "knowledge_points":  [
+                                 "两位数与两位数的退位减法",
+                                 "8的乘法口诀及应用",
+                                 "9的乘法口诀及应用",
+                                 "乘加，乘减混合运算"
+                             ],
+        "source":  "24-25二年级上·湖北孝感·期末"
+    },
+    {
+        "id":  "266",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "计算题",
+        "difficulty":  0.85,
+        "question":  "直接写出得数.\n\n8×7=( );79-63=( );58+23=( );4×7+8=( );6×9=( );3×7=( );4×8=( );9×7-8=( );7+35=( );72-42=( );7×9-6=( );8×8+12=( )",
+        "options":  [
+
+                    ],
+        "answer":  "56;16;81;36;54;21;32;55;42;30;57;76",
+        "solution":  "【分析】本题包含乘法口诀，两位数加减法以及乘加乘减混合运算。计算时，乘法直接应用对应的口诀;加减法要注意进位和退位;乘加乘减算式要先算乘法，再算加减法.\n【详解】8×7=56(口诀\"七八五十六\");79-63=16(个位9-3=6，十位7-6=1，不退位);58+23=81(个位8+3=11，向十位进1，十位5+2+1=8，得81);4×7+8=28+8=36(先算乘法4×7=28，再算加法28+8=36);6×9=54(口诀\"六九五十四\");3×7=21(口诀\"三七二十一\");4×8=32(口诀\"四八三十二\");9×7-8=63-8=55(先算乘法9×7=63，再算减法63-8=55);7+35=42(个位7+5=12，向十位进1，十位3+1=4，得42);72-42=30(个位2-2=0，十位7-4=3，不退位);7×9-6=63-6=57(先算乘法7×9=63，再算减法63-6=57);8×8+12=64+12=76(先算乘法8×8=64，再算加法64+12=76)",
+        "knowledge_points":  [
+                                 "两位数与两位数的进位加法",
+                                 "8的乘法口诀及应用",
+                                 "9的乘法口诀及应用",
+                                 "表内乘加，乘减"
+                             ],
+        "source":  "24-25二年级上·山东济宁·期末"
+    },
+    {
+        "id":  "267",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "计算题",
+        "difficulty":  0.85,
+        "question":  "口算.\n\n7×8=( );5×8=( );6×9-9=( );6×8+40=( );23+32=( );73-20=( );48+8=( );100-60+12=( )",
+        "options":  [
+
+                    ],
+        "answer":  "56;40;45;88;55;53;56;52",
+        "solution":  "【分析】本题包含乘法口诀，两位数加减法，乘减以及加减混合运算。计算时，乘法直接应用口诀;加减法要注意进位和退位;乘减算式要先算乘法再算减法;加减混合运算按从左到右的顺序计算.\n【详解】7×8=56(口诀\"七八五十六\");5×8=40(口诀\"五八四十\");6×9-9=54-9=45(先算乘法6×9=54，再算减法54-9=45);6×8+40=48+40=88(先算乘法6×8=48，再算加法48+40=88);23+32=55(个位3+2=5，十位2+3=5，不进位);73-20=53(个位3-0=3，十位7-2=5，不退位);48+8=56(个位8+8=16，向十位进1，十位4+1=5，得56);100-60+12=40+12=52(先算100-60=40，再算40+12=52)",
+        "knowledge_points":  [
+                                 "两位数与两位数的不进位加法",
+                                 "一位数与两位数的进位加法",
+                                 "8的乘法口诀及应用",
+                                 "表内乘加，乘减"
+                             ],
+        "source":  "24-25二年级上·湖北随州·期末"
+    },
+    {
+        "id":  "268",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "计算题",
+        "difficulty":  0.85,
+        "question":  "直接写得数.\n\n8×2=( );1×1=( );8×4=( );85-32=( );6×7=( );6+9=( );9×5=( );6×3=( );48-15=( );32+9=( );6×6=( );8×8-6=( )",
+        "options":  [
+
+                    ],
+        "answer":  "16;1;32;53;42;15;45;18;33;41;36;58",
+        "solution":  "【分析】本题包含乘法口诀，两位数加减法以及乘减混合运算。计算时，乘法直接应用对应的口诀;加减法要注意进位和退位;乘减算式要先算乘法，再算减法.\n【详解】8×2=16(口诀\"二八十六\");1×1=1(口诀\"一一得一\");8×4=32(口诀\"四八三十二\");85-32=53(个位5-2=3，十位8-3=5，不退位);6×7=42(口诀\"六七四十二\");6+9=15(6加9等于15);9×5=45(口诀\"五九四十五\");6×3=18(口诀\"三六十八\");48-15=33(个位8-5=3，十位4-1=3，不退位);32+9=41(个位2+9=11，向十位进1，十位3+1=4，得41);6×6=36(口诀\"六六三十六\");8×8-6=64-6=58(先算乘法8×8=64，再算减法64-6=58)",
+        "knowledge_points":  [
+                                 "7的乘法口诀及应用",
+                                 "8的乘法口诀及应用",
+                                 "9的乘法口诀及应用",
+                                 "表内乘加，乘减"
+                             ],
+        "source":  "24-25二年级上·辽宁抚顺·期末"
+    },
+    {
+        "id":  "269",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "计算题",
+        "difficulty":  0.94,
+        "question":  "直接写出答案.\n\n30-6=( );6+9=( );4×7=( );9×9-9=( );65-50=( );6×7=( );4×9=( );2×5+4=( )",
+        "options":  [
+
+                    ],
+        "answer":  "24;15;28;72;15;42;36;14",
+        "solution":  "【分析】本题包含两位数减整十数,20以内加法，乘法口诀以及乘减，乘加混合运算。计算时，加减法要注意相同数位对齐;乘法直接应用口诀;乘减算式要先算乘法再算减法;乘加算式要先算乘法再算加法.\n【详解】30-6=24(个位0减6不够，向十位借1,10-6=4，十位剩2，得24);6+9=15(6加9等于15);4×7=28(口诀\"四七二十八\");9×9-9=81-9=72(先算乘法9×9=81，再算减法81-9=72);65-50=15(个位5-0=5，十位6-5=1，不退位);6×7=42(口诀\"六七四十二\");4×9=36(口诀\"四九三十六\");2×5+4=10+4=14(先算乘法2×5=10，再算加法10+4=14)",
+        "knowledge_points":  [
+                                 "两位数与两位数的不退位减法",
+                                 "7的乘法口诀及应用",
+                                 "9的乘法口诀及应用",
+                                 "表内乘加，乘减"
+                             ],
+        "source":  "24-25二年级上·湖南娄底·期末"
+    },
+    {
+        "id":  "270",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "计算题",
+        "difficulty":  0.85,
+        "question":  "直接写出得数.\n\n26+50=( );6×7=( );68-8=( );3×9=( );8+8=( );5×3+3=( );9×4+7=( );45-3×7=( );4×4+6=( );5×6-6=( )",
+        "options":  [
+
+                    ],
+        "answer":  "76;42;60;27;16;18;43;24;22;24",
+        "solution":  "【分析】本题包含两位数加整十数，乘法口诀,20以内加法以及乘加乘减混合运算。计算时，加减法要注意相同数位对齐;乘法直接应用口诀;乘加乘减算式要先算乘法，再算加减法.\n【详解】26+50=76(个位6+0=6，十位2+5=7，不进位);6×7=42(口诀\"六七四十二\");68-8=60(个位8-8=0，十位6不变，得60);3×9=27(口诀\"三九二十七\");8+8=16(8加8等于16);5×3+3=15+3=18(先算乘法5×3=15，再算加法15+3=18);9×4+7=36+7=43(先算乘法9×4=36，再算加法36+7=43);45-3×7=45-21=24(先算乘法3×7=21，再算减法45-21=24);4×4+6=16+6=22(先算乘法4×4=16，再算加法16+6=22);5×6-6=30-6=24(先算乘法5×6=30，再算减法30-6=24)",
+        "knowledge_points":  [
+                                 "两位数与两位数的不进位加法",
+                                 "7的乘法口诀及应用",
+                                 "9的乘法口诀及应用",
+                                 "表内乘加，乘减"
+                             ],
+        "source":  "24-25二年级上·四川广元·期末"
+    },
+    {
+        "id":  "271",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "看图列式计算.\n\n![](images/147325fdcaf64b8ab9ee84610f9814838c9b3369c68750f9a72af4bce2420b55.jpg)\n\n□○□=□(个)",
+        "options":  [
+
+                    ],
+        "answer":  "3×7=21",
+        "solution":  "【分析】每组7个，有这样的3组。几个相同加数相加，可以写成加数与个数相乘的形式。乘法算式中两个乘数是口诀中的前两个数，积是口诀中的后一个数，写算式时两个乘数可互换位置.\n【详解】3×7=21(个)。",
+        "knowledge_points":  [
+                                 "图文问题",
+                                 "7的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·湖北襄阳·期末"
+    },
+    {
+        "id":  "272",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "看图列式.\n\n![](images/d0a2d6720ede20140c123138d224f62735a25c779e2f0cd056ea429c1851f682.jpg)\n\n□○□=□(米)",
+        "options":  [
+
+                    ],
+        "answer":  "5×9=45",
+        "solution":  "【分析】先数一数有几个间隔，再用间隔数乘相邻两棵树的长度，即可求出一共有多少米.\n【详解】根据分析可得:5×9=45(米),一共有45米。",
+        "knowledge_points":  [
+                                 "图文问题",
+                                 "9的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·湖北襄阳·期末"
+    },
+    {
+        "id":  "273",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "计算题",
+        "difficulty":  0.85,
+        "question":  "直接写出得数.\n\n7×8=( );4×5=( );8×2+8=( );6×9+9=( );75-6=( );36+4=( );5×9-7=( );90-5×5=( )",
+        "options":  [
+
+                    ],
+        "answer":  "56;20;24;63;69;40;38;65",
+        "solution":  "【分析】本题包含乘法口诀，一位数与两位数的加减法以及乘加乘减混合运算。计算时，乘法直接应用口诀;加减法要注意进位和退位;乘加乘减算式要先算乘法，再算加减法.\n【详解】7×8=56(口诀\"七八五十六\");4×5=20(口诀\"四五二十\");8×2+8=16+8=24(先算乘法8×2=16，再算加法16+8=24);6×9+9=54+9=63(先算乘法6×9=54，再算加法54+9=63);75-6=69(个位5减6不够，向十位借1,15-6=9，十位剩6，得69);36+4=40(个位6+4=10，向十位进1，十位3+1=4，得40);5×9-7=45-7=38(先算乘法5×9=45，再算减法45-7=38);90-5×5=90-25=65(先算乘法5×5=25，再算减法90-25=65)。",
+        "knowledge_points":  [
+                                 "一位数与两位数的进位加法",
+                                 "一位数与两位数的退位减法",
+                                 "表内乘加，乘减"
+                             ],
+        "source":  "24-25二年级上·湖北黄石·期末"
+    },
+    {
+        "id":  "274",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "计算题",
+        "difficulty":  0.85,
+        "question":  "直接写得数.\n\n7×4=( );48+22=( );6×4=( );4×9+9=( );46-14-12=( );53-15=( );3×8=( );5+7=( );8×4-10=( );34+16+30=( )",
+        "options":  [
+
+                    ],
+        "answer":  "28;70;24;45;20;38;24;12;22;80",
+        "solution":  "【分析】本题包含乘法口诀，两位数加减法，连加连减以及乘加乘减混合运算。计算时，乘法直接应用口诀;加减法要注意进位和退位;乘加乘减要先算乘法再算加减法;连加连减按从左到右的顺序计算.\n【详解】7×4=28(口诀\"四七二十八\");48+22=70(个位8+2=10，向十位进1，十位4+2+1=7，得70);6×4=24(口诀\"四六二十四\");4×9+9=36+9=45(先算乘法4×9=36，再算加法36+9=45);46-14-12=32-12=20(先算46-14=32，再算32-12=20);53-15=38(个位3减5不够，向十位借1,13-5=8，十位5借1剩4,4-1=3，得38);3×8=24(口诀\"三八二十四\");5+7=12;8×4-10=32-10=22;34+16+30=50+30=80。",
+        "knowledge_points":  [
+                                 "100以内数的连加运算",
+                                 "8的乘法口诀及应用",
+                                 "9的乘法口诀及应用",
+                                 "表内乘加，乘减"
+                             ],
+        "source":  "24-25二年级上·河南南阳·期末"
+    },
+    {
+        "id":  "275",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "看图列式并计算.\n\n![](images/39375d07524e5eb3d50f0aa52b035103658f5a00fd19b88fe064dde6439e52e2.jpg)\n\n□*□=□(米)",
+        "options":  [
+
+                    ],
+        "answer":  "4×9=36",
+        "solution":  "【分析】已知两个气球之间的间隔是4米，数一数一共有9个间隔，相乘即可得出答案.\n【详解】据分析可得列式:4×9=36(米),所以一共有36米。",
+        "knowledge_points":  [
+                                 "图文问题",
+                                 "9的乘法口诀及应用"
+                             ],
+        "source":  "23-24二年级上·江西赣州·期末"
+    },
+    {
+        "id":  "276",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "二(1)班有8个小组，每个小组6个同学，二(1)班一共有多少个同学。",
+        "options":  [
+
+                    ],
+        "answer":  "48人",
+        "solution":  "【分析】每个小组的人数乘小组个数，等于二(1)班一共有多少个同学，据此解答.\n【详解】6×8=48(人),答：二(1)班一共有48个同学。",
+        "knowledge_points":  [
+                                 "8的乘法口诀及应用"
+                             ],
+        "source":  "20-21二年级上·湖南长沙·期末"
+    },
+    {
+        "id":  "277",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "寒假里，妙妙和爸爸，妈妈一起去游乐城玩，一张成人票8元，一张儿童票6元，他们一共需要付多少钱。",
+        "options":  [
+
+                    ],
+        "answer":  "22元",
+        "solution":  "【分析】根据题意可知，他们需要买2张成人票和1张儿童票，则用每张成人票的价格和买的数量相乘，求出2张成人票的钱数，再和1张儿童票的钱数相加，就是要付的总钱数.\n【详解】8×2+6=16+6=22(元),答：他们一共需要付22元钱。",
+        "knowledge_points":  [
+                                 "表内乘加，乘减"
+                             ],
+        "source":  "24-25二年级上·安徽黄山·期末"
+    },
+    {
+        "id":  "278",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "彤彤从一楼到二楼用了7秒，按照这样的速度，从一楼到9楼，一共需要多少秒。",
+        "options":  [
+
+                    ],
+        "answer":  "56秒",
+        "solution":  "【分析】彤彤从一楼到二楼用了7秒，说明每层需要7秒，用结束的楼层数减开始的楼层数算出一共走的层数，最后用一共走的层数乘每层需要的时间即可求解.\n【详解】9-1=8(层),8×7=56(秒),答：一共需要56秒。",
+        "knowledge_points":  [
+                                 "8的乘法口诀及应用"
+                             ],
+        "source":  "23-24二年级下·广东汕头·期中"
+    },
+    {
+        "id":  "279",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "两个小组浇树，第一小组6个同学，每人浇8棵，第二小组浇了45棵，两个小组一共浇树多少棵。",
+        "options":  [
+
+                    ],
+        "answer":  "93棵",
+        "solution":  "【分析】根据题意，先用第一小组的人数和每人浇的棵数相乘，求出第一小组一共浇了多少棵树，再和第二小组浇的数量相加，就是两个小组浇的总数量.\n【详解】6×8+45=48+45=93(棵),答：两个小组一共浇树93棵。",
+        "knowledge_points":  [
+                                 "表内乘加，乘减"
+                             ],
+        "source":  "24-25二年级上·湖南长沙·期末"
+    },
+    {
+        "id":  "280",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "一箱牛奶:37元\n\n![](images/df8615d28626ed884710582046b6f546d0c637f1fa569427dbeb21900397866c.jpg)\n饼干:25元\n\n![](images/d90da35e6b6bd38489c0b7ecfcf5f5c4c298d00e23cbd46fa112a72f5e150cb6.jpg)\n蛋挞:4元\n\n![](images/2184efb772a667daee463075e91b9a4989d71c4d793e135d1adc473d63803c65.jpg)\n蛋糕:48元\n\n(1)买8个蛋挞，要付多少钱。\n(2)买一盒饼干比一个蛋糕便宜多少钱。",
+        "options":  [
+
+                    ],
+        "answer":  "32元;23元",
+        "solution":  "【分析】(1)买8个蛋挞要付的钱数也就是8个4的和，用乘法计算，即每个蛋挞的价格和数量相乘，就是要付的总钱数;(2)求一个数比另一个数少多少，用减法计算，即一个蛋糕的钱数-一盒饼干的钱数=一盒饼干比一个蛋糕便宜的钱数.\n【详解】(1)4×8=32(元),答：要付32元钱。(2)48-25=23(元),答：买一盒饼干比一个蛋糕便宜23元钱。",
+        "knowledge_points":  [
+                                 "图文问题",
+                                 "两位数与两位数的不退位减法",
+                                 "8的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·广东肇庆·期末"
+    },
+    {
+        "id":  "281",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "购物中的数学问题.\n\n![](images/433a7c4c0cf179ff52461db4408226c268183e0bcdafa349c66962a613a4aa00.jpg)\n文具盒每个9元\n\n![](images/7943ae0fee96a01414f83a5c9f9ba82f6e618844c0c24b028673636f79ca5e8a.jpg)\n钢笔每支8元\n\n![](images/54e2550781f2cffa94f2a5c213b0c22d3089853445ff92cc4433d140d7908033.jpg)\n羽毛球每个3元\n\n(1)小红的钱正好能买4支钢笔，小红有多少元钱。\n(2)小丽买2个文具盒和1个羽毛球需要多少钱。",
+        "options":  [
+
+                    ],
+        "answer":  "32元;21元",
+        "solution":  "【分析】(1)每支钢笔8元，求买4支钢笔多少元，就是求4个8的和是多少，可以用乘法列式解决。(2)先用乘法求出买2个文具盒多少钱，然后加上1个羽毛球的价钱，求出和，就是共需要花多少钱.\n【详解】(1)4×8=32(元),答：小红有32元钱。(2)2×9+3=18+3=21(元),答：小丽买2个文具盒和1个羽毛球需要21元。",
+        "knowledge_points":  [
+                                 "\"提问题\"\"填条件\"问题",
+                                 "5的乘法口诀及应用",
+                                 "8的乘法口诀及应用",
+                                 "表内乘加，乘减"
+                             ],
+        "source":  "24-25二年级上·湖南湘西·期末"
+    },
+    {
+        "id":  "282",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "2024年10月1日是祖国母亲的75岁生日。学校组织学生做\"美丽祖国\"的手抄报。二(1)班分成了5组，每组做了8份。二(1)班一共做了多少份手抄报。",
+        "options":  [
+
+                    ],
+        "answer":  "40份",
+        "solution":  "【分析】求一共做了多少份手抄报，也就是求5个8的和是多少，用乘法计算，即每组做的份数和组数相乘，就是做的总份数.\n【详解】8×5=40(份),答：二(1)班一共做了40份手抄报。",
+        "knowledge_points":  [
+                                 "8的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·湖南株洲·期末"
+    },
+    {
+        "id":  "283",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "经典诵读：为了提升同学们对我国传统文化的兴趣，学校开展了经典诵读比赛。二(1)班需要给参加诵读的42名同学和2位老师每人买一个领结，已知每包领结有5个，李老师买了9包领结，够吗。",
+        "options":  [
+
+                    ],
+        "answer":  "够",
+        "solution":  "【分析】先用加法求出学生和老师一共有几人，然后用乘法算出一包领结有5个,9包一共有多少个，最后比较大小，即可解决.\n【详解】42+2=44(个),9×5=45(个),45\u003e44，答：李老师买了9包领结，够。",
+        "knowledge_points":  [
+                                 "100以内数的比大小",
+                                 "两位数与一位数的加法(不进位)",
+                                 "9的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·河南郑州·期末"
+    },
+    {
+        "id":  "284",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "小朋友们比赛跳绳，分成了8组，每组4人，一共多少人参加跳绳比赛。",
+        "options":  [
+
+                    ],
+        "answer":  "32人",
+        "solution":  "【分析】每组的人数乘组数即可得到总人数.\n【详解】4×8=32(人),答：一共32人参加跳绳比赛。",
+        "knowledge_points":  [
+                                 "8的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·江西南昌·期末"
+    },
+    {
+        "id":  "285",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "二年级(1)班有60人，大课间同学们分组进行拔河比赛，每8人一组，分了6组，其余的同学来为大家加油，那么其余没分到组的同学有多少人。",
+        "options":  [
+
+                    ],
+        "answer":  "12人",
+        "solution":  "【分析】根据题意，先用每组的人数和分的组数相乘，求出分到组的有多少人，再用总人数-分到组的人数=没分到组的人数.\n【详解】8×6=48(人),60-48=12(人),答：其余没分到组的同学有12人。",
+        "knowledge_points":  [
+                                 "两位数与两位数的退位减法",
+                                 "8的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·河南郑州·期末"
+    },
+    {
+        "id":  "286",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "文具店原有8盒圆珠笔，每盒有8支。卖掉了15支后，文具店现在还有多少支圆珠笔。",
+        "options":  [
+
+                    ],
+        "answer":  "49支",
+        "solution":  "【分析】先用每盒的支数乘盒数，求出圆珠笔的总支数，再用总支数减去卖掉的支数，即可求出现在还有多少支圆珠笔.\n【详解】8×8-15=64-15=49(支),答：文具店现在还有49支圆珠笔。",
+        "knowledge_points":  [
+                                 "两位数与两位数的退位减法",
+                                 "8的乘法口诀及应用",
+                                 "表内乘加，乘减"
+                             ],
+        "source":  "24-25二年级上·青海西宁·期末"
+    },
+    {
+        "id":  "287",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "运动会开幕式，体操队员站成了4排，前3排每排8人，最后一排6人，体操队有多少人。",
+        "options":  [
+
+                    ],
+        "answer":  "30人",
+        "solution":  "【分析】前3排每排的人数乘排数，再加上最后一排的人数，等于体操队的总人数，据此解答.\n【详解】8×3+6=24+6=30(人),答：体操队有30人。",
+        "knowledge_points":  [
+                                 "8的乘法口诀及应用",
+                                 "表内乘加，乘减"
+                             ],
+        "source":  "24-25二年级上·山东济宁·期末"
+    },
+    {
+        "id":  "288",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "聪聪和他的4位同学制作风车，每人做了8个，一共做了多少个风车。",
+        "options":  [
+
+                    ],
+        "answer":  "40个",
+        "solution":  "【分析】先求出一共有多少位同学，再用每人做风车的数量乘人数，等于一共做风车的数量，据此解答.\n【详解】1+4=5(位),5×8=40(个),答：一共做了40个风车。",
+        "knowledge_points":  [
+                                 "5以内数的加法",
+                                 "8的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·山东济宁·期末"
+    },
+    {
+        "id":  "289",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "一件外套用8个扣子,7件用多少个扣子。",
+        "options":  [
+
+                    ],
+        "answer":  "56个",
+        "solution":  "【分析】一件外套用8个扣子，求7件用多少个扣子，就是求7个8的和是多少，用乘法列式解决.\n【详解】8×7=56(个),答:7件用56个扣子。",
+        "knowledge_points":  [
+                                 "8的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·辽宁抚顺·期末"
+    },
+    {
+        "id":  "290",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "到达万峰林后，一家人去品尝当地名小吃\"蛋炒饭\"，小明和爸爸，妈妈每人一碗，需要付多少元。\n\n![](images/2026-02-26%20224234.jpg)",
+        "options":  [
+
+                    ],
+        "answer":  "27元",
+        "solution":  "【分析】用人数乘每碗\"蛋炒饭\"的价钱即可求出需要付多少元.\n【详解】3×9=27(元),答：需要付27元。",
+        "knowledge_points":  [
+                                 "经济问题",
+                                 "9的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·贵州黔西·期末"
+    },
+    {
+        "id":  "291",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "妈妈买了一些果子，淘淘第一天吃了这些果子的一半，第二天吃了剩下果子的一半，第三天吃了4个刚好吃完，这些果子一共有多少个。",
+        "options":  [
+
+                    ],
+        "answer":  "16个",
+        "solution":  "【分析】第二天吃了剩下果子的一半，第三天吃了4个刚好吃完，说明第二天吃了4个并且剩下4个，用4乘2即可算出第一天剩下的个数;淘淘第一天吃了这些果子的一半，说明第一天吃的个数和剩下的个数一样多，用第一天剩下的个数乘2即可算出这些果子一共有多少个。本题可以通过倒推的策略解决。从后面往前推算，即抓住最后得到的数量，从后向前进行推理.\n【详解】4×2=8(个),8×2=16(个),答：这些果子一共有16个。",
+        "knowledge_points":  [
+                                 "倒推问题"
+                             ],
+        "source":  "24-25二年级上·四川广元·期末"
+    },
+    {
+        "id":  "292",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "箱子里原来有24个苹果，现在还剩几个苹果。\n\n![](images/2026-02-26%20224406.jpg)",
+        "options":  [
+
+                    ],
+        "answer":  "3个",
+        "solution":  "【分析】一周有7天，一天吃3个苹果，先用乘法求出7个3的和是多少，就是求出吃了的苹果数量，然后用原来苹果的数量减去吃了的数量，求出差，就是还剩的数量.\n【详解】3×7=21(个),24-21=3(个),答：现在还剩3个苹果。",
+        "knowledge_points":  [
+                                 "两位数与两位数的不退位减法",
+                                 "7的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·浙江台州·期末"
+    },
+    {
+        "id":  "293",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "一根铁丝50米长，每次剪8米，剪了3次，这根铁丝比原来短了多少米。",
+        "options":  [
+
+                    ],
+        "answer":  "24米",
+        "solution":  "【分析】每次剪8米，剪3次的长度和，就是这根铁丝比原来短了多少米。故，用乘法求出3个8的和是多少，可以用乘法计算，即可解决此题.\n【详解】8×3=24(米),答：这根铁丝比原来短了24米。",
+        "knowledge_points":  [
+                                 "8的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·浙江台州·期末"
+    },
+    {
+        "id":  "294",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "二年级9个班举行\"人人写好字\"活动，每个班要选出8幅书法作品，一共要选出多少幅书法作品。",
+        "options":  [
+
+                    ],
+        "answer":  "72幅",
+        "solution":  "【分析】每个班要选出8幅书法作品，求二年级9个班一共要选出多少幅书法作品，就是求9个8的和是多少，用乘法列式解决.\n【详解】8×9=72(幅),答：一共要选出72幅书法作品。",
+        "knowledge_points":  [
+                                 "9的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·四川南充·期末"
+    },
+    {
+        "id":  "295",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "一根绳子对折再对折后，量出每段绳子长9厘米，这根绳子长多少厘米。",
+        "options":  [
+
+                    ],
+        "answer":  "36厘米",
+        "solution":  "【分析】一根绳子把它对折后被平均分成2份，再对折就被平均分成4份，此时每段绳子长9厘米，也就是每份长9厘米，求这根绳子有多长，用每份的长度乘被平均分成的份数即可.\n【详解】9×4=36(厘米),答：这根绳子长36厘米。",
+        "knowledge_points":  [
+                                 "9的乘法口诀及应用"
+                             ],
+        "source":  "23-24二年级上·浙江杭州·期末"
+    },
+    {
+        "id":  "296",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "红气球有8个，黄气球的个数比红气球的5倍多5个，黄气球有多少个。",
+        "options":  [
+
+                    ],
+        "answer":  "45个",
+        "solution":  "【分析】根据题意可知：求一个数的几倍，用乘法计算，先求出5倍是多少再加上多出的5个即可求出黄气球的个数.\n【详解】8×5+5=40+5=45(个),答：黄气球有45个。",
+        "knowledge_points":  [
+                                 "8的乘法口诀及应用",
+                                 "求一个数的几倍是多少"
+                             ],
+        "source":  "24-25二年级上·江西抚州·期末"
+    },
+    {
+        "id":  "297",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "老师讲台上摆了8盘苹果，每盘有7个苹果，一共有多少个苹果。",
+        "options":  [
+
+                    ],
+        "answer":  "56个",
+        "solution":  "【分析】根据题意可知：每盘有的数量乘盘数即可求出共有的数量.\n【详解】7×8=56(个),答：一共有56个苹果。",
+        "knowledge_points":  [
+                                 "8的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·江西抚州·期末"
+    },
+    {
+        "id":  "298",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "重阳节，要敬老，踏秋赏菊去登高。重阳节到了，鸡公山下热闹非凡，有许多老年人准备乘车观光。有50名旅客要同时乘车，准备6辆大车和1辆小车够吗。\n\n![](images/f2243e88b8307b00dad11acca264f893366300a22034dd5ba697afe51a7fe4ea.jpg)\n大车坐8人\n\n![](images/b2305cd7e1c3a0d8af4484b2a6abf1d34889d5d68a5416abd631d65a447bde65.jpg)\n小车坐4人",
+        "options":  [
+
+                    ],
+        "answer":  "够",
+        "solution":  "【分析】用大车的数量乘每个大车坐的人数，再加上1辆小车可以坐的人数，求出一共可以坐多少人，然后和旅客人数作比较。旅客人数大于可以坐的人数则不够，反之就够.\n【详解】6×8+4=48+4=52(名),52\u003e50，够。答：准备6辆大车和1辆小车够。",
+        "knowledge_points":  [
+                                 "图文问题",
+                                 "100以内数的比大小",
+                                 "表内乘加，乘减"
+                             ],
+        "source":  "24-25二年级上·河南驻马店·期末"
+    },
+    {
+        "id":  "299",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "购物.\n\n![](images/14534f48d75892d0e17e3dfee0cd91f597e014ded37932b8103b4bf7a5849cc4.jpg)\n6元\n\n![](images/7e83f9604d188faf6caf1e9b52b46e48f7c4c71b57ede2b1ff81ffe9b378017c.jpg)\n43元\n\n![](images/4f4f3214af1a5f7668d167b3966f2d69d5ad313224f75d05e6ab8b1ed7a10229.jpg)\n。元\n\n(1)买一个机器人的钱正好可以买6根跳绳，一个机器人多少元。\n(2)王叔叔要买8根跳绳和一辆遥控汽车，他带了100元，够吗。",
+        "options":  [
+
+                    ],
+        "answer":  "36元;够",
+        "solution":  "【分析】(1)一根跳绳6元，用乘法求出6根跳绳的总价钱，即求出一个机器人的价钱;(2)一根跳绳6元，用乘法求出8根跳绳的总价钱，然后加上一辆遥控汽车的价钱，求出它们的和，最后再用它们的和与100元比较大小，即可解答.\n【详解】(1)6×6=36(元),答：一个机器人36元。(2)6×8+43=48+43=91(元),100元\u003e91元，答：王叔叔带了100元，够。",
+        "knowledge_points":  [
+                                 "经济问题",
+                                 "6的乘法口诀及应用",
+                                 "8的乘法口诀及应用",
+                                 "表内乘加，乘减"
+                             ],
+        "source":  "24-25二年级上·四川南充·期末"
+    },
+    {
+        "id":  "300",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "学校开展课外阅读活动中，小军一个星期(7天)刚好读完一本故事书。他每天读9页，这本书一共有多少页。",
+        "options":  [
+
+                    ],
+        "answer":  "63页",
+        "solution":  "【分析】用一个星期的天数乘每天读的页数即可求解.\n【详解】7×9=63(页),答：这本书一共有63页。",
+        "knowledge_points":  [
+                                 "9的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·黑龙江哈尔滨·期末"
+    },
+    {
+        "id":  "301",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "一只熊猫每天吃8根竹子,8天吃了( )根竹子。",
+        "options":  [
+                        "A. 17",
+                        "B. 72",
+                        "C. 64"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】根据题意可知：用每天吃的数量乘天数即可求出8天吃的数量.\n【详解】8×8=64(根),则8天吃了64根竹子。故答案为:C",
+        "knowledge_points":  [
+                                 "8的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·江西抚州·期末"
+    },
+    {
+        "id":  "302",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "一条彩带沿同一方向对折三次后，测量出对折后的彩带长3厘米，彩带原来长( )厘米。",
+        "options":  [
+                        "A. 12厘米",
+                        "B. 9厘米",
+                        "C. 24厘米"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】一根彩带对折一次变成1×2=2段，再对折一次变成2×2=4段，再对折一次变成2×4=8段;即一条彩带沿同一方向对折三次后变成8段，对折后的彩带长3厘米，求彩带原来长多少厘米，就是求8个3的和是多少，用乘法列式解决.\n【详解】1×2=2(段),2×2=4(段),2×4=8(段),3×8=24(厘米),即，一条彩带沿同一方向对折三次后，测量出对折后的彩带长3厘米，彩带原来长24厘米。故答案为:C",
+        "knowledge_points":  [
+                                 "2的乘法口诀及应用",
+                                 "4的乘法口诀及应用",
+                                 "8的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·河南南阳·期末"
+    },
+    {
+        "id":  "303",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "同学们排成正方形队列做操，人数比30人多，比40人少，一共有( )人做操。",
+        "options":  [
+                        "A. 25人",
+                        "B. 32人",
+                        "C. 36人"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】从题干可以知道，同学们排成正方形队列(正方形队列是指行数与列数一样多)做操，人数比30人多，比40人少;再结合乘法口诀(六六三十六)可知，在30和40之间，只有36人可以构成正方形队列(每行6人，一共6列).\n【详解】A。25人\u003c30人，不符合题意;B。4×8=32，每行4人，一共8列(或每行8人，一共4列),也就是32人不能排成正方形队列，不符合题意;C。6×6=36，每行6人，一共6列,36人比30人多，比40人少，也就是36人能排成正方形队列，符合题意;即，同学们排成正方形队列做操，人数比30人多，比40人少，一共有36人做操。故答案为:C",
+        "knowledge_points":  [
+                                 "100以内数的比大小",
+                                 "6的乘法口诀及应用",
+                                 "8的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·河南南阳·期末"
+    },
+    {
+        "id":  "304",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "❀这样的8朵花共有( )个花瓣。",
+        "options":  [
+                        "A. 64",
+                        "B. 40",
+                        "C. 32"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】❀这样的1朵花有5个花瓣，求8朵这样的花共有多少个花瓣，就是求8个5的和是多少，用乘法列式解决.\n【详解】5×8=40(个),即,❀这样的8朵花共有40个花瓣。故答案为:B",
+        "knowledge_points":  [
+                                 "8的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·内蒙古通辽·期末"
+    },
+    {
+        "id":  "305",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "8个9比80少( )。",
+        "options":  [
+                        "A. 9",
+                        "B. 8",
+                        "C. 5"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】根据题意，先求出8个9是多少，用乘法列式8×9=72或9×8=72，再用80减去72即可.\n【详解】8×9=72,80-72=8,8个9比80少8。故答案为:B",
+        "knowledge_points":  [
+                                 "100以内数的比大小",
+                                 "两位数与两位数的退位减法",
+                                 "9的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·内蒙古通辽·期末"
+    },
+    {
+        "id":  "306",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "下面的问题中，不能用\"7×4\"解决的是( )。",
+        "options":  [
+                        "A. 有4列队伍，每列有7名同学，一共有多少名同学。",
+                        "B. 明明在纸上画了7个正方形，这些正方形一共有多少个直角。",
+                        "C. 有两条船，一条船坐7人，另一条船坐4人，一共坐了多少人。"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】求几个相同加数的和是多少，可以用乘法列式解决;求两个数的和是多少，用加法列式解决。据此分析每一个选项，找出符合题意的选项即可.\n【详解】A。每列有7名同学，求4列一共有多少名同学，就是求4个7的和是多少，可以用\"7×4\"解决;B。一个正方形有4个直角，求7个正方形一共有多少个直角，就是求7个4的和是多少，可以用\"7×4\"解决;C。有两条船，一条船坐7人，另一条船坐4人，求一共坐了多少人，就是求7与4的和是多少，可以用\"7+4\"解决;即，不能用\"7×4\"解决的是：有两条船，一条船坐7人，另一条船坐4人，一共坐了多少人。故答案为:C",
+        "knowledge_points":  [
+                                 "7,6加几的进位加法",
+                                 "初步认识乘法意义",
+                                 "7的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·福建福州·期末"
+    },
+    {
+        "id":  "307",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "9名同学参加献爱心活动，每人捐了4本笔记本，一共捐了( )本笔记本。",
+        "options":  [
+                        "A. 3",
+                        "B. 35",
+                        "C. 36"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】每人捐了4本笔记本，求9名同学一共捐了几本笔记本，就是求9个4的和是多少，用乘法列式解决.\n【详解】9×4=36(本),即,9名同学参加献爱心活动，每人捐了4本笔记本，一共捐了36本笔记本。故答案为:C",
+        "knowledge_points":  [
+                                 "9的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·甘肃天水·期末"
+    },
+    {
+        "id":  "308",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "与9×7+1相等的式子是( )。",
+        "options":  [
+                        "A. 9×8-8",
+                        "B. 8×7+7",
+                        "C. 9×7+8"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】几个相同加数相加，可以写成加数与个数相乘的形式。1可以看成9减8，则9×7+1可以看成8个9减8.\n【详解】A。9×8-8可看作9×7+9-8，所以9×8-8与9×7+1相等。B。8×7+7表示9×7，所以8×7+7与9×7+1不相等。C。9×7+8与9×7+1不相等。故答案为:A",
+        "knowledge_points":  [
+                                 "9的乘法口诀及应用",
+                                 "表内乘加，乘减"
+                             ],
+        "source":  "24-25二年级上·广东汕头·期末"
+    },
+    {
+        "id":  "309",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "小兔子高( )厘米.\n\n![](images/a2472c64a338ef3cce9adacf379f77d2bcffe187b26ca233b05b0a31721f7dbc.jpg)",
+        "options":  [
+                        "A. 12",
+                        "B. 27",
+                        "C. 18"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】观察图片可知：兔子和左边的积木一样高，一个积木高3厘米，则有9个积木，即9个3相加，可以用乘法表示，列式:3×9=27.\n【详解】3×9=27(厘米),则小兔子高27厘米。故答案为:B",
+        "knowledge_points":  [
+                                 "9的乘法口诀及应用"
+                             ],
+        "source":  "21-22二年级上·山东·单元测试"
+    },
+    {
+        "id":  "310",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "在5×8=40中，积是( )。",
+        "options":  [
+                        "A. 5",
+                        "B. 40",
+                        "C. 8"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】根据乘数×乘数=积即可解答.\n【详解】在5×8=40中，积是40。故答案为:B",
+        "knowledge_points":  [
+                                 "初步认识乘法意义",
+                                 "8的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·陕西西安·期末"
+    },
+    {
+        "id":  "311",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "在万平口游玩时，聪聪在文创店买了3张不同的明信片，要解决\"聪聪一共花了多少钱\"的问题，需要补充的条件是( )。",
+        "options":  [
+                        "A. 一张明信片8元",
+                        "B. 一个茶杯35元",
+                        "C. 聪聪带了50元"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】根据题意可知：求聪聪花的钱数，则缺失的是有关钱数的条件，已给出明信片的数量，则需要明信片的价格.\n【详解】由分析可得：在万平口游玩时，聪聪在文创店买了3张不同的明信片，要解决\"聪聪一共花了多少钱\"的问题，需要补充的条件是一张明信片8元。故答案为:A",
+        "knowledge_points":  [
+                                 "\"提问题\"\"填条件\"问题",
+                                 "8的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·山东日照·期末"
+    },
+    {
+        "id":  "312",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "用口诀\"二九十八\"来计算的是( )。",
+        "options":  [
+                        "A. 9×2",
+                        "B. 2+9",
+                        "C. 9×9"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】乘法算式中两个乘数是口诀中的前两个数，积是口诀中的后一个数，写算式时两个乘数可互换位置.\n【详解】用口诀\"二九十八\"来计算的是9×2或2×9，故答案为:A",
+        "knowledge_points":  [
+                                 "9的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·吉林四平·期末"
+    },
+    {
+        "id":  "313",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "81,64,49,36,□。,按照规律□里应该填( )。",
+        "options":  [
+                        "A. 27",
+                        "B. 25",
+                        "C. 29",
+                        "D. 16"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】根据题意可知:9×9=81,8×8=64,7×7=49,6×6=36，则□为5×5=25.\n【详解】由分析可得:81,64,49,36,□。,按照规律□里应该填25。故答案为:B",
+        "knowledge_points":  [
+                                 "7的乘法口诀及应用",
+                                 "8的乘法口诀及应用",
+                                 "9的乘法口诀及应用",
+                                 "整数排列的规律"
+                             ],
+        "source":  "23-24二年级上·浙江宁波·期末"
+    },
+    {
+        "id":  "314",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "选择题",
+        "difficulty":  0.94,
+        "question":  "用口诀\"七八五十六\"计算的乘法算式是( )。",
+        "options":  [
+                        "A. 7×8=56",
+                        "B. 7+8=56",
+                        "C. 8-7=56"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】用口诀\"七八五十六\"计算的乘法算式有:7×8=56,8×7=56.\n【详解】A。7×8=56是用口诀\"七八五十六\"计算的乘法算式;B。7+8=56是加法算式，且计算结果不正确;C。8-7=56是减法算式，且计算结果不正确;即，用口诀\"七八五十六\"计算的乘法算式是7×8=56。故答案为:A",
+        "knowledge_points":  [
+                                 "8的乘法口诀及应用"
+                             ],
+        "source":  "23-24二年级上·河北保定·期末"
+    },
+    {
+        "id":  "315",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "下面算式中，积最大的是( )。",
+        "options":  [
+                        "A. 8×9",
+                        "B. 6×6",
+                        "C. 9×9"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】分别求出它们的乘积，再比较大小，找出积最大选项即可。据此解答.\n【详解】A。8×9=72;B。6×6=36;C。9×9=81,36\u003c72\u003c81;故答案为:C.",
+        "knowledge_points":  [
+                                 "6的乘法口诀及应用",
+                                 "9的乘法口诀及应用"
+                             ],
+        "source":  "23-24二年级上·河北保定·期末"
+    },
+    {
+        "id":  "316",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "明明去商店买气球，求他一共要付多少钱，需要用到的数学信息是( ).\n\n①买了8束气球 ②每束气球5个 ③每束气球7元",
+        "options":  [
+                        "A. ①和②",
+                        "B. ②和③",
+                        "C. ①和③"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】要求\"买气球一共要付多少钱\"，即求气球的总价;①已知买气球的束数(即数量),②已知每束气球的个数,③已知每束气球的价钱(即单价),根据\"总价=单价×数量\"可知，需要用到的信息有单价和数量。据此选择.\n【详解】由题意分析得：明明去商店买气球，求他一共要付多少钱，需要用到的数学信息是(①买了8束气球和③每束气球7元)。故答案为:C",
+        "knowledge_points":  [
+                                 "\"提问题\"\"填条件\"问题",
+                                 "8的乘法口诀及应用"
+                             ],
+        "source":  "23-24二年级上·河北保定·期末"
+    },
+    {
+        "id":  "317",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "下列哪些物品可用50元买到。( )",
+        "options":  [
+                        "A. 4杯9元的果汁",
+                        "B. 一个篮球26元，一个足球27元",
+                        "C. 2个28元的铅笔盒"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】要想50元能买到，也就是物品的总钱数要小于或等于50元，由此计算出各选项物品需要的钱数再和50比较大小即可。比较时，位数多的数就大;位数相同比较最高位，最高位大的数就大;最高位相同比较下一位，直到比较出结果为止。求几个相同加数的和，可以用乘法计算.\n【详解】A。9×4=36(元);36\u003c50，符合题意;B。26+27=53(元);53\u003e50，不符合题意;C。28+28=56(元);56\u003e50，不符合题意。所以4杯9元的果汁可用50元买到。故答案为:A",
+        "knowledge_points":  [
+                                 "100以内数的比大小",
+                                 "两位数与两位数的进位加法",
+                                 "9的乘法口诀及应用"
+                             ],
+        "source":  "23-24二年级上·河北保定·期末"
+    },
+    {
+        "id":  "318",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "把乘法口诀补充完整.\n\n八九( );( )三十六;三八( );( )十五;四七( );( )十八",
+        "options":  [
+
+                    ],
+        "answer":  "七十二;六六;二十四;三五;二十八;二九",
+        "solution":  "【分析】根据乘法口诀即可解答.\n【详解】八九七十二;六六三十六;三八二十四;三五十五;四七二十八;二九十八。",
+        "knowledge_points":  [
+                                 "6的乘法口诀及应用",
+                                 "7的乘法口诀及应用",
+                                 "8的乘法口诀及应用",
+                                 "9的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·江西抚州·期末"
+    },
+    {
+        "id":  "319",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "一个排球要9元，买7个排球要( )元。列式是( )(元),这式子读作:( ),口诀是:( )。",
+        "options":  [
+
+                    ],
+        "answer":  "63;7×9=63;7乘9等于63;七九六十三",
+        "solution":  "【分析】一个排球要9元，求买7个排球要多少元，就是求7个9的和是多少，用乘法列式计算，即7×9，然后根据\"七九六十三\"算出结果即可;读乘法算式时，从左往右读，是几就读作几，\"*\"读作\"乘\";据此解决.\n【详解】由题意分析得:7×9=63(元),即，一个排球要9元，买7个要63元。列式是:7×9=63，这式子读作:7乘9等于63，口诀是：七九六十三。",
+        "knowledge_points":  [
+                                 "初步认识乘法意义",
+                                 "9的乘法口诀及应用"
+                             ],
+        "source":  "23-24二年级上·新疆昌吉·期末"
+    },
+    {
+        "id":  "320",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "《西游记》讲述了唐僧师徒经历九九( )难去取经的故事，途中孙悟空施展八( )七十二般变化，猪八戒拿着九齿钉耙，不管( )七二十一，就把妖怪打得落花流水。",
+        "options":  [
+
+                    ],
+        "answer":  "八十一;九;三",
+        "solution":  "【分析】根据乘法口诀可知：九九八十一，八九七十二，三七二十一.\n【详解】《西游记》讲述了唐僧师徒经历九九八十一难去取经的故事，途中孙悟空施展八九七十二般变化，猪八戒拿着九齿钉耙，不管三七二十一，就把妖怪打得落花流水。",
+        "knowledge_points":  [
+                                 "7的乘法口诀及应用",
+                                 "9的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·内蒙古通辽·期末"
+    },
+    {
+        "id":  "321",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "比较大小.\n\n43+5( )50;79( )95-16;8×8( )8+8;70+9( )9×9",
+        "options":  [
+
+                    ],
+        "answer":  "\u003c;=;\u003e;\u003c",
+        "solution":  "【分析】整数的大小比较：比较数的大小，先看位数的多少，位数多的数就大;位数相同，从高位开始比较，高位上的数大则这个数大，高位上的数相同，就比较下一位。含有算式的，可以先计算出算式的结果，再比较大小.\n【详解】43+5=48，所以43+5\u003c50;95-16=79，即79=95-16;8×8=64,8+8=16，所以8×8\u003e8+8;70+9=79,9×9=81，所以70+9\u003c9×9。",
+        "knowledge_points":  [
+                                 "100以内数的比大小",
+                                 "两位数与两位数的退位减法",
+                                 "8的乘法口诀及应用",
+                                 "9的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·内蒙古通辽·期末"
+    },
+    {
+        "id":  "322",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "8个5相加的和是( );2个5相乘的积是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "40;25",
+        "solution":  "【分析】几个相同加数相加，可以写成加数与个数相乘的形式。乘法算式中两个乘数是口诀中的前两个数，积是口诀中的后一个数，写算式时两个乘数可互换位置。2个5相乘就是5乘5，据此计算.\n【详解】8×5=40,5×5=25,8个5相加的和是40;2个5相乘的积是25。",
+        "knowledge_points":  [
+                                 "同数连加的应用",
+                                 "5的乘法口诀及应用",
+                                 "8的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·内蒙古通辽·期末"
+    },
+    {
+        "id":  "323",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "在括号里填上合适的\"\u003e\"\"\u003c\"或\"=\".\n\n48+22( )56;8+8( )4×4;86-5( )57+21;96厘米( )1米;4×7+7( )6×7-7;5×9( )70-29",
+        "options":  [
+
+                    ],
+        "answer":  "\u003e;=;\u003e;\u003c;=;\u003e",
+        "solution":  "【分析】先计算出每个算式的结果或先统一单位，然后比较大小即可。整数比较大小方法:①位数多的数大于位数少的数;②位数相同的，先比较最高位上的数，最高位上大的，数就大，最高位数相同的，就比较下一位，以此类推。1米=100厘米.\n【详解】48+22=70，故,48+22\u003e56;8+8=16,4×4=16，故,8+8=4×4;86-5=81,57+21=78，故,86-5\u003e57+21;1米=100厘米，故,96厘米\u003c1米;4×7+7=28+7=35,6×7-7=42-7=35，故,4×7+7=6×7-7;5×9=45,70-29=41，故,5×9\u003e70-29。",
+        "knowledge_points":  [
+                                 "100以内数的比大小",
+                                 "9的乘法口诀及应用",
+                                 "厘米和米之间的进率与换算",
+                                 "表内乘加，乘减"
+                             ],
+        "source":  "24-25二年级上·甘肃庆阳·期末"
+    },
+    {
+        "id":  "324",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "在括号里填上\"\u003e\"\"\u003c\"或\"=\".\n\n39+19( )60;4×5( )14+5;8+8( )8×8",
+        "options":  [
+
+                    ],
+        "answer":  "\u003c;\u003e;\u003c",
+        "solution":  "【分析】根据整数加减法的计算法则及表内乘法口诀，依次计算出各算式的结果再比较大小。比较时，位数多的数就大;位数相同比较最高位，最高位大的数就大;最高位相同比较下一位，直到比较出结果为止.\n【详解】39+19=58;58\u003c60，则39+19\u003c60;4×5=20;14+5=19;20\u003e19，则4×5\u003e14+5;8+8=16;8×8=64;16\u003c64，则8+8\u003c8×8。",
+        "knowledge_points":  [
+                                 "100以内数的比大小",
+                                 "两位数与两位数的进位加法",
+                                 "8的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·内蒙古巴彦淖尔·期末"
+    },
+    {
+        "id":  "325",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在计算6×9和9×6时都要用到口诀( )。",
+        "options":  [
+
+                    ],
+        "answer":  "六九五十四",
+        "solution":  "【分析】根据乘法口诀计算乘法算式时，算式中的两个乘数是口诀中的前两个数，积是口诀中的后一个数，由此解答.\n【详解】在计算6×9和9×6时都要用到口诀六九五十四。",
+        "knowledge_points":  [
+                                 "9的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·内蒙古巴彦淖尔·期末"
+    },
+    {
+        "id":  "326",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "( )里最大能填几。\n\n3×( )\u003c16;9×( )\u003c70;60\u003e( )×7",
+        "options":  [
+
+                    ],
+        "answer":  "5;7;8",
+        "solution":  "【分析】根据表内乘法口诀及整数比较大小的方法来解决此题即可.\n【详解】3×5=15,3×6=18,15\u003c16\u003c18，故,3×5\u003c16;9×7=63,9×8=72,63\u003c70\u003c72，故,9×7\u003c70;8×7=56,9×7=63,63\u003e60\u003e56，故,60\u003e8×7。",
+        "knowledge_points":  [
+                                 "100以内数的比大小",
+                                 "6的乘法口诀及应用",
+                                 "8的乘法口诀及应用",
+                                 "9的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·甘肃庆阳·期末"
+    },
+    {
+        "id":  "327",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "一个乘数是8，另一个乘数是6，积是( ),写成乘法算式是( ),读作( )。",
+        "options":  [
+
+                    ],
+        "answer":  "48;8×6=48;8乘6等于48",
+        "solution":  "【分析】乘法算式中两个乘数是口诀中的前两个数，积是口诀中的后一个数，写算式时两个乘数可互换位置。读乘法算式时，依次从左往右读，\"*\"读作乘，\"=\"读作等于，数字直接读出来.\n【详解】8×6=48或6×8=48，一个乘数是8，另一个乘数是6积是48，写成乘法算式是8×6=48或6×8=48，读作:8乘6等于48或6乘8等于48。",
+        "knowledge_points":  [
+                                 "初步认识乘法意义",
+                                 "8的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·黑龙江哈尔滨·期末"
+    },
+    {
+        "id":  "328",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "括号里最大能填几。\n\n( )×7\u003c37;25\u003e4×( );8×( )\u003c51",
+        "options":  [
+
+                    ],
+        "answer":  "5;6;6",
+        "solution":  "【分析】根据6,7,8的乘法口诀找到与一侧已知数相近的算式，然后找出最大的数即可解答.\n【详解】5×7=35;6×7=42;35\u003c37\u003c42，则5×7\u003c37，最大填5;4×6=24;4×7=28;28\u003e25\u003e24，则25\u003e4×6，最大填6;8×6=48;8×7=56;48\u003c51\u003c56，则8×6\u003c51，最大填6。",
+        "knowledge_points":  [
+                                 "100以内数的比大小",
+                                 "6的乘法口诀及应用",
+                                 "7的乘法口诀及应用",
+                                 "8的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·广东汕头·期末"
+    },
+    {
+        "id":  "329",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "在下面的括号里填上\"\u003e\"\"\u003c\"或\"=\".\n\n1米( )80厘米;8×8( )54;52+39( )39+52;61-30( )9×4",
+        "options":  [
+
+                    ],
+        "answer":  "\u003e;\u003e;=;\u003c",
+        "solution":  "【分析】依次计算出各算式的结果再比较大小。比较时，位数多的数就大;位数相同比较最高位，最高位大的数就大;最高位相同比较下一位，直到比较出结果为止。单位不统一的，先换算成统一单位再比较大小,1米=100厘米.\n【详解】1米=100厘米,100厘米\u003e80厘米，则1米\u003e80厘米;8×8=64,64\u003e54，则8×8\u003e54;52+39=91,39+52=91，则52+39=39+52;61-30=31,9×4=36,31\u003c36，则61-30\u003c9×4。",
+        "knowledge_points":  [
+                                 "100以内数的比大小",
+                                 "8的乘法口诀及应用",
+                                 "9的乘法口诀及应用",
+                                 "厘米和米之间的进率与换算"
+                             ],
+        "source":  "24-25二年级上·广东汕头·期末"
+    },
+    {
+        "id":  "330",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在括号里填上\"\u003e\"或\"\u003c\".\n\n9+9( )9×9;1厘米( )1米;6×2( )10",
+        "options":  [
+
+                    ],
+        "answer":  "\u003c;\u003c;\u003e",
+        "solution":  "【分析】比较大小，首先要将需要计算的算式计算出来，其次要区分大小等于号，再进行数字大小的比较即可，需要进行单位换算的，先进行换算,1米=100厘米.\n【详解】9+9=18,9×9=81,18\u003c81，所以9+9\u003c9×9;1米=100厘米,1厘米\u003c100厘米，所以1厘米\u003c1米;6×2=12,12\u003e10，所以6×2\u003e10。",
+        "knowledge_points":  [
+                                 "6的乘法口诀及应用",
+                                 "9的乘法口诀及应用",
+                                 "厘米和米之间的进率与换算"
+                             ],
+        "source":  "24-25二年级上·陕西西安·期末"
+    },
+    {
+        "id":  "331",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "一副成人手套8元，一副儿童手套6元。买4副成人手套和5副儿童手套一共需要( )元钱。",
+        "options":  [
+
+                    ],
+        "answer":  "62",
+        "solution":  "【分析】根据题意可知：先求出4副成人手套和5副儿童手套各需要的钱数，用购买的数量乘对应每副手套的价格即可，然后将两者相加即可求出一共需要的钱数.\n【详解】4×8=32(元),5×6=30(元),32+30=62(元),则买4副成人手套和5副儿童手套一共需要62元钱。",
+        "knowledge_points":  [
+                                 "两位数与整十数的加法",
+                                 "6的乘法口诀及应用",
+                                 "8的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·河北邯郸·期末"
+    },
+    {
+        "id":  "332",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "2只螃蟹16条腿,8只螃蟹( )条腿。",
+        "options":  [
+
+                    ],
+        "answer":  "64",
+        "solution":  "【分析】首先求出1只螃蟹几条腿，就是求16里面有几个2，用除法列式计算;然后再求8只螃蟹几条腿，就是求8个8的和是多少，用乘法列式计算，据此解答.\n【详解】根据分析可得:16÷2=8(条),8×8=64(条),所以8只螃蟹64条腿。",
+        "knowledge_points":  [
+                                 "8的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·河北邯郸·期末"
+    },
+    {
+        "id":  "333",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "6×5-6=( )×( );7+7+7-7=( )×( )",
+        "options":  [
+
+                    ],
+        "answer":  "4;6;2;7",
+        "solution":  "【分析】求几个相同加数的和的简便运算，可以用加法列式计算，也可以用乘法列式计算。6×5-6表示5个6相加的和减去1个6，即4个6相加的和;7+7+7-7表示3个7相加的和再减去1个7，即2个7相加的和，据此列式.\n【详解】6×5-6=4×6,7+7+7-7=7×2。",
+        "knowledge_points":  [
+                                 "初步认识乘法意义",
+                                 "表内乘加，乘减"
+                             ],
+        "source":  "24-25二年级上·山东临沂·期末"
+    },
+    {
+        "id":  "334",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "( )里最大能填几。\n\n( )×4\u003c30;8×( )\u003c42;50\u003e9×( )",
+        "options":  [
+
+                    ],
+        "answer":  "7;5;5",
+        "solution":  "【分析】根据表内乘法口诀及整数比较大小的方法来解决此题即可.\n【详解】7×4=28,8×4=32,28\u003c30\u003c32，故,7×4\u003c30;8×5=40,8×6=48,40\u003c42\u003c48，故,8×5\u003c42;9×5=45,9×6=54,54\u003e50\u003e45，故,50\u003e9×5。",
+        "knowledge_points":  [
+                                 "100以内数的比大小",
+                                 "7的乘法口诀及应用",
+                                 "8的乘法口诀及应用",
+                                 "9的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·福建福州·期末"
+    },
+    {
+        "id":  "335",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "一根电线，先用去一半，再用去剩下的一半，还剩下8米，这根电线原来长( )米。",
+        "options":  [
+
+                    ],
+        "answer":  "32",
+        "solution":  "【分析】由题意可知，一根电线，先用去一半，再用去剩下的一半，还剩下8米，即8米是电线一半的一半，用8乘2求出积，就是电线一半的长度;最后用电线一半的长度加上一半的长度，求出和，就是这根电线原来的长度.\n【详解】8×2=16(米),16+16=32(米),即，这根电线原来长32米。",
+        "knowledge_points":  [
+                                 "两位数与两位数的进位加法",
+                                 "8的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·河北保定·期末"
+    },
+    {
+        "id":  "336",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "二十四节气中的冬至这天，白昼最短，黑夜最长。从冬至开始\"数九\"，每个\"九\"都有9天，\"九九\"过后，春暖花开。那么\"数九\"要经过( )天。",
+        "options":  [
+
+                    ],
+        "answer":  "81",
+        "solution":  "【分析】每个\"九\"都有9天，求\"九九\"过后一共有多少天，就是求9个9的和是多少，用乘法列式解决即可.\n【详解】9×9=81(天),即，\"数九\"要经过81天。",
+        "knowledge_points":  [
+                                 "9的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·河北保定·期末"
+    },
+    {
+        "id":  "337",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "一个乘数是3，另一个乘数是9，积是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "27",
+        "solution":  "【分析】根据乘数×乘数=积，列出算式，再根据乘法口诀，算出结果，据此解答.\n【详解】根据分析可得:3×9=27，一个乘数是3，另一个乘数是9，积是27。",
+        "knowledge_points":  [
+                                 "9的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·甘肃天水·期末"
+    },
+    {
+        "id":  "338",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "找规律.\n\n8,16,24,( ),40,( )。",
+        "options":  [
+
+                    ],
+        "answer":  "32;48",
+        "solution":  "【分析】这组数字依次为:1×8=8;2×8=16;3×8=24;4×8=32;5×8=40;6×8=48，填写32,48.\n【详解】填写如下:8,16,24,32,40,48。",
+        "knowledge_points":  [
+                                 "8的乘法口诀及应用",
+                                 "整数排列的规律"
+                             ],
+        "source":  "24-25二年级上·山东济宁·期末"
+    },
+    {
+        "id":  "339",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "( )里最大能填几。\n\n4×( )\u003c24;( )×7\u003c36;9×( )\u003c64",
+        "options":  [
+
+                    ],
+        "answer":  "5;5;7",
+        "solution":  "【分析】根据小于号的左侧和已知数的乘法口诀，找出结果小于且接近右侧数的即可.\n【详解】4×6=24,4×5=20,20\u003c24，则4×5\u003c24;5×7=35,6×7=42,35\u003c36\u003c42，则5×7\u003c36;9×7=63,9×8=72,63\u003c64\u003c72，则9×7\u003c64。",
+        "knowledge_points":  [
+                                 "100以内数的比大小",
+                                 "8的乘法口诀及应用",
+                                 "9的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·山东济宁·期末"
+    },
+    {
+        "id":  "340",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "把口诀补充完整.\n\n四六( );三( )十五;五( )四十五",
+        "options":  [
+
+                    ],
+        "answer":  "二十四;五;九",
+        "solution":  "【分析】根据表内乘法口诀填写即可，注意要写汉字.\n【详解】四六二十四;三五十五;五九四十五。",
+        "knowledge_points":  [
+                                 "5的乘法口诀及应用",
+                                 "6的乘法口诀及应用",
+                                 "9的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·广东江门·期末"
+    },
+    {
+        "id":  "341",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "8+8+8=( ),表示( )个( )相加，用乘法算式表示为( ),读作( )。",
+        "options":  [
+
+                    ],
+        "answer":  "24;3;8;3×8=24;3乘8等于24",
+        "solution":  "【分析】几个相同加数相加，可以写成加数与个数相乘的形式。乘法算式中两个乘数是口诀中的前两个数，积是口诀中的后一个数，写算式时两个乘数可互换位置。读乘法算式时，依次从左往右读，\"*\"读作乘，\"=\"读作等于，数字直接读出来.\n【详解】8+8+8=24，表示3个8相加，用乘法算式表示为3×8=24或8×3=24，读作3乘8等于24或8乘3等于24。",
+        "knowledge_points":  [
+                                 "同数连加的应用",
+                                 "初步认识乘法意义",
+                                 "8的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·河南周口·期末"
+    },
+    {
+        "id":  "342",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "在括号里填上\"\u003c\"\"\u003e\"或\"=\".\n\n9×7( )8×8;12厘米+88厘米( )1米;79-6( )76-9",
+        "options":  [
+
+                    ],
+        "answer":  "\u003c;=;\u003e",
+        "solution":  "【分析】整数的大小比较：比较数的大小，先看位数的多少，位数多的数就大;位数相同，从高位开始比较，高位上的数大则这个数大，高位上的数相同，就比较下一位。含有算式的，可以先计算出算式的结果，再比较大小;1米=100厘米，单位不统一时，先化成相同单位，再比较大小.\n【详解】9×7=63,8×8=64，所以9×7\u003c8×8;12厘米+88厘米=100厘米,100厘米=1米，所以12厘米+88厘米=1米;79-6=73,76-9=67，所以79-6\u003e76-9。",
+        "knowledge_points":  [
+                                 "100以内数的比大小",
+                                 "一位数与两位数的退位减法",
+                                 "9的乘法口诀及应用",
+                                 "厘米和米之间的进率与换算"
+                             ],
+        "source":  "24-25二年级上·吉林·期末"
+    },
+    {
+        "id":  "343",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "在括号里填上\"+\"\"-\"或\"*\".\n\n8( )5=40;36=73( )37;9( )7=63;2( )2=4;42=6( )7;18( )9=9",
+        "options":  [
+
+                    ],
+        "answer":  "*;-;*;+或*;*;-",
+        "solution":  "【分析】根据整数加减法的计算法则及表内乘法口诀解答即可。根据乘法口诀\"五八四十\"可知,8×5=40,73-37=36;根据乘法口诀\"七九六十三\"可知,9×7=63;2和2合起来就是4，即2+2=4;根据乘法口诀\"二二得四\"可知,2×2=4;根据乘法口诀\"六七四十二\"可知,42=6×7;18可以分成9和9，即18-9=9.\n【详解】8×5=40,36=73-37,9×7=63,2+2=4或2×2=4,42=6×7,18-9=9。",
+        "knowledge_points":  [
+                                 "十几减9的退位减法",
+                                 "两位数与两位数的退位减法",
+                                 "8的乘法口诀及应用",
+                                 "9的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·吉林·期末"
+    },
+    {
+        "id":  "344",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "把口诀补充完整.\n\n四八( );六九( );七八( )",
+        "options":  [
+
+                    ],
+        "answer":  "三十二;五十四;五十六",
+        "solution":  "【分析】根据表内乘法口诀填写即可.\n【详解】由表内乘法口诀得：四八三十二;六九五十四;七八五十六。",
+        "knowledge_points":  [
+                                 "8的乘法口诀及应用",
+                                 "9的乘法口诀及应用"
+                             ],
+        "source":  "23-24二年级上·广东韶关·期末"
+    },
+    {
+        "id":  "345",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "括号里最大能填几。\n\n( )×7\u003c38;( )×8\u003c55;6×( )\u003c20",
+        "options":  [
+
+                    ],
+        "answer":  "5;6;3",
+        "solution":  "【分析】(1)根据7的乘法口诀,5×7=35,6×7=42,35\u003c38\u003c42，所以( )×7\u003c38的( )最大填5;(2)根据8的乘法口诀,6×8=48,7×8=56,48\u003c55\u003c56，所以( )×8\u003c55的( )最大填6;(3)根据6的乘法口诀,3×6=18,4×6=24,18\u003c20\u003c24，所以6×( )\u003c20的( )最大填3.\n【详解】括号里依次最大能填5,6,3。",
+        "knowledge_points":  [
+                                 "100以内数的比大小",
+                                 "6的乘法口诀及应用",
+                                 "7的乘法口诀及应用",
+                                 "8的乘法口诀及应用"
+                             ],
+        "source":  "23-24二年级上·广东韶关·期末"
+    },
+    {
+        "id":  "346",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "( )里最大能填几。\n\n( )×8\u003c34;3×( )\u003c26;45\u003e( )×6;9×( )\u003c62",
+        "options":  [
+
+                    ],
+        "answer":  "4;8;7;6",
+        "solution":  "【分析】根据含有小于号左侧或大于号右侧已知数的乘法口诀，找出结果小于且最接近另一侧数的即可.\n【详解】4×8=32,5×8=40,32\u003c34\u003c40，则4×8\u003c34;3×8=24,3×9=27,24\u003c26\u003c27，则3×8\u003c26;7×6=42,8×6=48,42\u003c45\u003c48，则45\u003e7×6;9×7=63,9×6=54,54\u003c62\u003c63，则9×6\u003c62。",
+        "knowledge_points":  [
+                                 "100以内数的比大小",
+                                 "7的乘法口诀及应用",
+                                 "8的乘法口诀及应用",
+                                 "9的乘法口诀及应用"
+                             ],
+        "source":  "23-24二年级上·浙江宁波·期末"
+    },
+    {
+        "id":  "347",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在( )里填入合适的数.\n\n9×5+9=( )×9;7+8+9=( )×3\n86-68=9×( );( )×( )=20+5",
+        "options":  [
+
+                    ],
+        "answer":  "6;8;2;5;5",
+        "solution":  "【分析】(1)先算出左边有几个9，左边等于右边，那么右边等于几个9，据此解答;(2)先算出左边有几个8，左边等于右边，那么右边等于几个8，据此解答;(3)先算出左边的差，左边等于右边，那么右边等于几9，据此解答;(4)先算出右边等于多少，左边等于右边，找到两个数的积等于右边即可.\n【详解】(1)左边:9×5是5个9，再加上1个9等于6个9，左边等于右边，右边：括号里可以填6，也是6个9，所以9×5+9=6×9。(2)左边:7+8+9=24,3个8等于24，左边等于右边，右边：括号里可以填8，也是3个8，即24。所以7+8+9=8×3;(3)左边:86-68=18，是2个9，左边等于右边，右边：括号里可以填2，也是2个9，即18。所以86-68=9×2;(4)右边:20+5=25，左边等于右边，左边：括号里各填5，即5×5。所以5×5=20+5(答案不唯一)。",
+        "knowledge_points":  [
+                                 "两位数与两位数的退位减法",
+                                 "5的乘法口诀及应用",
+                                 "8的乘法口诀及应用",
+                                 "9的乘法口诀及应用"
+                             ],
+        "source":  "23-24二年级上·浙江宁波·期末"
+    },
+    {
+        "id":  "348",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "括号里最大能填几。\n\n( )×5\u003c50;8×( )\u003c40;30\u003e6×( );18\u003e4×( )",
+        "options":  [
+
+                    ],
+        "answer":  "9;4;4;4",
+        "solution":  "【分析】根据含有小于号左侧或大于号右侧已知数的乘法口诀，找出结果小于且最接近另一侧数的即可.\n【详解】9×5=45\u003c50，所以括号里最大能填9;8×4=32\u003c40,8×5=40,8×6=48\u003e40，所以括号里最大能填4;30\u003e6×4=24,30=6×5,30\u003c6×6=36，所以括号里最大能填4;18\u003e4×4=16,18\u003c4×5=20，所以括号里最大能填4。",
+        "knowledge_points":  [
+                                 "100以内数的比大小",
+                                 "6的乘法口诀及应用",
+                                 "8的乘法口诀及应用",
+                                 "9的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·吉林·期末"
+    },
+    {
+        "id":  "349",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "把口诀补充完整.\n\n四六( );六八( );( )六十三",
+        "options":  [
+
+                    ],
+        "answer":  "二十四;四十八;七九",
+        "solution":  "【分析】根据表内乘法口诀填写即可，注意要写汉字.\n【详解】四六二十四;六八四十八;七九六十三。",
+        "knowledge_points":  [
+                                 "6的乘法口诀及应用",
+                                 "8的乘法口诀及应用",
+                                 "9的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·吉林四平·期末"
+    },
+    {
+        "id":  "350",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "在( )里填上\"\u003e\"\"\u003c\"或\"=\".\n\n36+49( )75;60( )9×7;41( )74-38;48+22( )70;4×4( )10;6×5( )30",
+        "options":  [
+
+                    ],
+        "answer":  "\u003e;\u003c;\u003e;=;\u003e;=",
+        "solution":  "【分析】根据题意，依次计算出各算式的结果再比较大小。比较时，位数多的数就大;位数相同比较最高位，最高位大的数就大;最高位相同比较下一位，直到比较出结果为止.\n【详解】36+49=85,85\u003e75，则36+49\u003e75;9×7=63,60\u003c63，则60\u003c9×7;74-38=36,41\u003e36，则41\u003e74-38;48+22=70，所以48+22=70;4×4=16,16\u003e10，所以4×4\u003e10;6×5=30，所以6×5=30。",
+        "knowledge_points":  [
+                                 "100以内数的比大小",
+                                 "两位数与两位数的进位加法",
+                                 "两位数与两位数的退位减法",
+                                 "9的乘法口诀及应用"
+                             ],
+        "source":  "23-24二年级上·河北保定·期末"
+    },
+    {
+        "id":  "351",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.94,
+        "question":  "把口诀补充完整.\n\n四( )二十;五( )三十五;( )二十七;( )六十四",
+        "options":  [
+
+                    ],
+        "answer":  "五;七;三九;八八",
+        "solution":  "【分析】根据表内乘法口诀填写即可，注意要写汉字.\n【详解】四(五)二十;五(七)三十五;(三九)二十七;(八八)六十四。",
+        "knowledge_points":  [
+                                 "5的乘法口诀及应用",
+                                 "7的乘法口诀及应用",
+                                 "8的乘法口诀及应用",
+                                 "9的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·广东揭阳·期末"
+    },
+    {
+        "id":  "352",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "4个6的和是( ),再加上1个6是( );9个9的和是( ),再减去1个9是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "24;30;81;72",
+        "solution":  "【分析】求几个相同加数的和，用乘法计算，用相同加数×个数或个数×相同加数。4个6的和，用4和6相乘，所求的结果再加上6即可;9个9的和，用9和9相乘，所求的结果再减去9即可.\n【详解】4×6=24,24+6=30;9×9=81,81-9=72.4个6的和是24，再加上1个6是30;9个9的和是81，再减去1个9是72。",
+        "knowledge_points":  [
+                                 "一位数与两位数的进位加法",
+                                 "一位数与两位数的退位减法",
+                                 "6的乘法口诀及应用",
+                                 "9的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·广东揭阳·期末"
+    },
+    {
+        "id":  "353",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "在括号里填上\"\u003e\"\"\u003c\"或\"=\".\n\n2×7( )1+4;5+5( )5×5;3×8+9( )25;45厘米+54厘米( )1米",
+        "options":  [
+
+                    ],
+        "answer":  "\u003e;\u003c;\u003e;\u003c",
+        "solution":  "【分析】根据题意，依次计算出各算式的结果再比较大小。比较时，位数多的数就大;位数相同比较最高位，最高位大的数就大;最高位相同比较下一位，直到比较出结果为止。长度单位的题目根据1米=100厘米换算单位再比较。既有乘法又有加法的算式，先算乘法，再算加法.\n【详解】2×7=14,1+4=5,14\u003e5，则2×7\u003e1+4;5+5=10,5×5=25,10\u003c25，则5+5\u003c5×5;3×8+9=24+9=33,33\u003e25;45厘米+54厘米=99厘米,1米=100厘米,99厘米\u003c100厘米，则45厘米+54厘米\u003c1米。",
+        "knowledge_points":  [
+                                 "100以内数的比大小",
+                                 "7的乘法口诀及应用",
+                                 "厘米和米之间的进率与换算",
+                                 "表内乘加，乘减"
+                             ],
+        "source":  "23-24二年级上·河北保定·期末"
+    },
+    {
+        "id":  "354",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在1~9的乘法口诀中，只能写出一个乘法算式的口诀有( )句。",
+        "options":  [
+
+                    ],
+        "answer":  "9",
+        "solution":  "【分析】乘法算式中两个乘数是口诀中的前两个数，积是口诀中的后一个数，写算式时两个乘数可互换位置.\n【详解】1×1=1,2×2=4,3×3=9,4×4=16,5×5=25,6×6=36,7×7=49,8×8=64,9×9=81，在1~9的乘法口诀中，只能写出一个乘法算式的口诀有9句。",
+        "knowledge_points":  [
+                                 "5的乘法口诀及应用",
+                                 "6的乘法口诀及应用",
+                                 "9的乘法口诀及应用"
+                             ],
+        "source":  "23-24二年级上·河北保定·期末"
+    },
+    {
+        "id":  "355",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "学校快放寒假了，寒假整整有4个星期，共有( )天。",
+        "options":  [
+
+                    ],
+        "answer":  "28",
+        "solution":  "【分析】一个星期7天，用7乘4即可求出一共有多少天.\n【详解】4×7=28(天),共有28天。",
+        "knowledge_points":  [
+                                 "7的乘法口诀及应用"
+                             ],
+        "source":  "23-24二年级上·河北保定·期末"
+    },
+    {
+        "id":  "356",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "括号里最大能填几。\n\n( )×3\u003c20;5×( )\u003c26;60\u003e8×( )",
+        "options":  [
+
+                    ],
+        "answer":  "6;5;7",
+        "solution":  "【分析】根据表内乘法口诀及整数比较大小的方法来解决此题即可.\n【详解】6×3=18,7×3=21,18\u003c20\u003c21，故,6×3\u003c20;5×5=25,5×6=30,25\u003c26\u003c30，故,5×5\u003c26;8×7=56,8×8=64,64\u003e60\u003e56，故,60\u003e8×7。",
+        "knowledge_points":  [
+                                 "100以内数的比大小",
+                                 "6的乘法口诀及应用",
+                                 "7的乘法口诀及应用",
+                                 "8的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·全国·期末"
+    },
+    {
+        "id":  "357",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "如果![](images/2026-02-26%20234905.jpg),☆+☆+☆=15，那么![](images/2026-02-26%20234937.jpg)。",
+        "options":  [
+
+                    ],
+        "answer":  "35",
+        "solution":  "【分析】几个相同加数相加，可以写成加数与个数相乘的形式。4乘几得28则爱心表示几。3乘几得15则☆表示几.\n【详解】4×7=28，所以爱心=7;3×5=15，所以星星=5。爱心*☆=7×5=35。",
+        "knowledge_points":  [
+                                 "同数连加的应用",
+                                 "初步认识乘法意义",
+                                 "5的乘法口诀及应用",
+                                 "7的乘法口诀及应用"
+                             ],
+        "source":  "23-24二年级上·浙江杭州·期末"
+    },
+    {
+        "id":  "358",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "括号里最大能填几。\n\n5×( )\u003c28;9×( )\u003c40;34\u003e6×( )\n( )×8\u003c55;60\u003e( )×9;( )\u003c3×7",
+        "options":  [
+
+                    ],
+        "answer":  "5;4;5;6;6;20",
+        "solution":  "【分析】根据表内乘法口诀，结合100以内整数比较大小，即可得出答案.\n【详解】5×5=25,5×6=30,25\u003c28,30\u003e28，所以括号内最大能填5;4×9=36,5×9=45,36\u003c40,45\u003e40，所以括号内最大能填4;6×5=30,6×6=36,36\u003e34,30\u003c34，所以括号内最大能填5;6×8=48,7×8=56,48\u003c55,56\u003e55，所以括号内最大能填6;6×9=54,7×9=63,54\u003c60,63\u003e60，所以括号内最大能填6;3×7=21，小于21最大的数是20，所以括号内最大能填20。",
+        "knowledge_points":  [
+                                 "100以内数的比大小",
+                                 "6的乘法口诀及应用",
+                                 "8的乘法口诀及应用",
+                                 "9的乘法口诀及应用"
+                             ],
+        "source":  "23-24二年级上·江西赣州·期末"
+    },
+    {
+        "id":  "359",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "1只蜘蛛8条腿,3只蜘蛛( )条腿,7只蜘蛛( )条腿。",
+        "options":  [
+
+                    ],
+        "answer":  "24;56",
+        "solution":  "【分析】1只蜘蛛8条腿,3只蜘蛛几条腿，就是求3个8的和是多少，用乘法列式计算。7只蜘蛛几条腿，就是求7个8的和是多少，用乘法列式计算.\n【详解】3×8=24(条),7×8=56(条),1只蜘蛛8条腿,3只蜘蛛24条腿,7只蜘蛛56条腿。",
+        "knowledge_points":  [
+                                 "8的乘法口诀及应用"
+                             ],
+        "source":  "23-24二年级上·福建福州·期末"
+    },
+    {
+        "id":  "360",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "计算8×7和7×8时都要用到的口诀是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "七八五十六",
+        "solution":  "【分析】乘法口诀前两个数是乘数，后面一个数是积，列算式时，两个乘数可以互换位置.\n【详解】计算8×7和7×8时都要用到的口诀是七八五十六。",
+        "knowledge_points":  [
+                                 "8的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·吉林四平·期末"
+    },
+    {
+        "id":  "361",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在算式3×9=27中,3和9是( ),积是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "乘数;27",
+        "solution":  "【分析】根据\"乘数×乘数=积\"来解决此题即可.\n【详解】由题意分析得：在算式3×9=27中,3和9是乘数，积是27。",
+        "knowledge_points":  [
+                                 "初步认识乘法意义",
+                                 "9的乘法口诀及应用"
+                             ],
+        "source":  "23-24二年级上·新疆昌吉·期末"
+    },
+    {
+        "id":  "362",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "一个乘数是9，另一个乘数是7，积是( ),计算时所用的乘法口诀是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "63;七九六十三",
+        "solution":  "【分析】根据乘数×乘数=积,9的乘法口诀计算即可.\n【详解】9×7=63，一个乘数是9，另一个乘数是7，积是63，计算时所用的乘法口诀是七九六十三。",
+        "knowledge_points":  [
+                                 "初步认识乘法意义",
+                                 "9的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·广东揭阳·期末"
+    },
+    {
+        "id":  "363",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "( )里最大能填几。\n\n( )×4\u003c30;34\u003e5×( );( )+18\u003c46;61-( )\u003e43",
+        "options":  [
+
+                    ],
+        "answer":  "7;6;27;17",
+        "solution":  "【分析】根据表内乘法口诀，整数加减法的计算法则及整数比较大小的方法来解决此题.\n【详解】7×4=28,8×4=32,28\u003c30\u003c32，故,7×4\u003c30;5×6=30,5×7=35,35\u003e34\u003e30，故,34\u003e5×6;46-18=28,28-1=27,27+18=45,45\u003c46，故,27+18\u003c46;61-43=18,18-1=17,61-17=44,44\u003e43，故,61-17\u003e43。",
+        "knowledge_points":  [
+                                 "100以内数的比大小",
+                                 "两位数与两位数的退位减法",
+                                 "7的乘法口诀及应用",
+                                 "8的乘法口诀及应用"
+                             ],
+        "source":  "23-24二年级上·河北保定·期末"
+    },
+    {
+        "id":  "364",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "找规律填数.\n\n(1)4,8,12,( ).\n(2)81,72,63,( )。",
+        "options":  [
+
+                    ],
+        "answer":  "16;54",
+        "solution":  "【分析】(1)这组数字依次为:1×4=4;2×4=8;3×4=12;4×4=16，填写16;(2)这组数字依次为:9×9=81;8×9=72;7×9=63;6×9=54，填写54.\n【详解】(1)4,8,12,16。(2)81,72,63,54。",
+        "knowledge_points":  [
+                                 "4的乘法口诀及应用",
+                                 "9的乘法口诀及应用",
+                                 "整数排列的规律"
+                             ],
+        "source":  "23-24二年级上·广东韶关·期末"
+    },
+    {
+        "id":  "365",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "有7盒七巧板，红红拼图用去23块，还剩( )块。",
+        "options":  [
+
+                    ],
+        "answer":  "26",
+        "solution":  "【分析】根据题意可知，一盒七巧板有7块，有7盒七巧板，用每盒七巧板的数量乘盒数，求出7盒七巧板的数量，再减去用去的数量，即可求出还剩多少块.\n【详解】7×7-23=49-23=26(块),有7盒七巧板，红红拼图用去23块，还剩26块。",
+        "knowledge_points":  [
+                                 "7的乘法口诀及应用",
+                                 "表内乘加，乘减",
+                                 "用七巧板拼图形"
+                             ],
+        "source":  "23-24二年级上·浙江绍兴·期末"
+    },
+    {
+        "id":  "366",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "4个8相加是12。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】几个相同加数相加，可以写成加数与个数相乘的形式。乘法算式中两个乘数是口诀中的前两个数，积是口诀中的后一个数，写算式时两个乘数可互换位置.\n【详解】4×8=32,4个8相加是32。原题说法错误。故答案为: ×",
+        "knowledge_points":  [
+                                 "同数连加的应用",
+                                 "8的乘法口诀及应用"
+                             ],
+        "source":  "19-20二年级上·全国·期末"
+    },
+    {
+        "id":  "367",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "因为3×8和4×6的积相等，所以可以用同一句口诀。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】乘法算式中两个乘数是口诀中的前两个数，积是口诀中的后一个数，写算式时两个乘数可互换位置.\n【详解】3×8用口诀\"三八二十四\";4×6用口诀\"四六二十四\"，不是用同一句口诀。原题说法错误。故答案为: ×",
+        "knowledge_points":  [
+                                 "6的乘法口诀及应用",
+                                 "8的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·黑龙江哈尔滨·期末"
+    },
+    {
+        "id":  "368",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "计算2×8和4×4时，可以用同一句口诀。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】2×8可以用乘法口诀\"二八十六\"计算出结果,4×4可以用乘法口诀\"四四十六\"计算出结果;据此解答.\n【详解】根据分析:2×8=16,4×4=16，结果一样，但是计算时用到的乘法口诀不同，原题说法错误。故答案为: ×",
+        "knowledge_points":  [
+                                 "4的乘法口诀及应用",
+                                 "8的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·河北邯郸·期末"
+    },
+    {
+        "id":  "369",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "两个因数都是8，积是多少。列式是2×8=16。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】因数×因数=积，乘法算式中两个乘数是口诀中的前两个数，积是口诀中的后一个数，写算式时两个乘数可互换位置.\n【详解】8×8=64，两个因数都是8，积是多少。列式是8×8=64。原题说法错误。故答案为: ×",
+        "knowledge_points":  [
+                                 "8的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·河南周口·期末"
+    },
+    {
+        "id":  "370",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "计算9×8和8×9用的是同一句口诀。( )",
+        "options":  [
+
+                    ],
+        "answer":  "√",
+        "solution":  "【分析】根据乘法口诀计算乘法算式时，算式中的两个乘数是口诀中的前两个数，积是口诀中的后一个数，由此写出口诀解答即可.\n【详解】计算9×8用到的口诀是八九七十二;计算8×9用到的口诀是八九七十二，用的是同一句口诀。原题说法正确。故答案为:√",
+        "knowledge_points":  [
+                                 "8的乘法口诀及应用",
+                                 "9的乘法口诀及应用"
+                             ],
+        "source":  "23-24二年级上·河北保定·期末"
+    },
+    {
+        "id":  "371",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "计算题",
+        "difficulty":  0.85,
+        "question":  "直接写出得数.\n\n50-18=( );89-74=( );36+16=( );54+30=( );83-26=( );4×5=( );9×8=( );6×7=( );2×7=( );3×9=( )",
+        "options":  [
+
+                    ],
+        "answer":  "32;15;52;84;57;20;72;42;14;27",
+        "solution":  "【分析】本题包含两位数加减法以及乘法口诀的应用。计算加减法时要注意相同数位对齐，并根据情况判断是否需要进位或退位;乘法直接应用对应的口诀得出结果.\n【详解】50-18=32;89-74=15;36+16=52;54+30=84;83-26=57;4×5=20(口诀\"四五二十\");9×8=72(口诀\"八九七十二\");6×7=42(口诀\"六七四十二\");2×7=14(口诀\"二七十四\");3×9=27(口诀\"三九二十七\")。",
+        "knowledge_points":  [
+                                 "两位数与两位数的进位加法",
+                                 "两位数与两位数的退位减法",
+                                 "7的乘法口诀及应用",
+                                 "9的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·内蒙古通辽·期末"
+    },
+    {
+        "id":  "372",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "计算题",
+        "difficulty":  0.85,
+        "question":  "口算.\n\n29+40=( );61+25=( );72-9=( );98-8=( );82-50=( );3×8=( );7×5=( );9×4=( );1×1=( );4×7=( )",
+        "options":  [
+
+                    ],
+        "answer":  "69;86;63;90;32;24;35;36;1;28",
+        "solution":  "【分析】本题包含两位数加减法以及乘法口诀的应用。计算加减法时要注意相同数位对齐，并根据情况判断是否需要进位或退位;乘法直接应用对应的口诀得出结果.\n【详解】29+40=69;61+25=86;72-9=63;98-8=90;82-50=32;3×8=24(口诀\"三八二十四\");7×5=35(口诀\"五七三十五\");9×4=36(口诀\"四九三十六\");1×1=1(口诀\"一一得一\");4×7=28(口诀\"四七二十八\")。",
+        "knowledge_points":  [
+                                 "两位数与两位数的不进位加法",
+                                 "一位数与两位数的退位减法",
+                                 "8的乘法口诀及应用",
+                                 "9的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·内蒙古巴彦淖尔·期末"
+    },
+    {
+        "id":  "373",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "计算题",
+        "difficulty":  0.85,
+        "question":  "直接写得数.\n\n99-66=( );75-38=( );48-6-4=( );8×6-6=( );32+58=( );100-33=( );47+39=( );7×2+7=( )",
+        "options":  [
+
+                    ],
+        "answer":  "33;37;38;42;90;67;86;21",
+        "solution":  "【分析】本题包含两位数加减法，连减以及乘减，乘加混合运算。计算加减法时要注意进位和退位;连减按从左到右的顺序计算;乘加乘减算式要先算乘法，再算加减法.\n【详解】99-66=33;75-38=37;48-6-4=42-4=38;8×6-6=48-6=42;32+58=90;100-33=67;47+39=86;7×2+7=14+7=21。",
+        "knowledge_points":  [
+                                 "两位数与两位数的进位加法",
+                                 "两位数与两位数的退位减法",
+                                 "表内乘加，乘减"
+                             ],
+        "source":  "24-25二年级上·河北邯郸·期末"
+    },
+    {
+        "id":  "374",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "计算题",
+        "difficulty":  0.85,
+        "question":  "直接写出得数.\n\n3×4=( );5×9=( );48+8=( );59-(34-14)=( );9×6=( );64-9=( );7×5=( );5+5×2=( )",
+        "options":  [
+
+                    ],
+        "answer":  "12;45;56;39;54;55;35;15",
+        "solution":  "【分析】本题包含乘法口诀，一位数与两位数的退位减法，带括号的加减混合运算以及乘加混合运算。计算时，乘法直接应用口诀;退位减法要注意个位不够减时向十位借一;有括号的算式要先算括号里面的;乘加算式要先算乘法，再算加法.\n【详解】3×4=12(口诀\"三四十二\");5×9=45(口诀\"五九四十五\");48+8=56;59-(34-14)=59-20=39;9×6=54(口诀\"六九五十四\");64-9=55;7×5=35(口诀\"五七三十五\");5+5×2=5+10=15。",
+        "knowledge_points":  [
+                                 "一位数与两位数的退位减法",
+                                 "9的乘法口诀及应用",
+                                 "带有小括号的混合运算",
+                                 "表内乘加，乘减"
+                             ],
+        "source":  "24-25二年级上·山东日照·期末"
+    },
+    {
+        "id":  "375",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "计算题",
+        "difficulty":  0.85,
+        "question":  "算一算.\n\n5×6=( );79-7=( );2×3=( );6×9=( );6×4+6=( );2×5-5=( );5×3+2=( );4×4+2=( )",
+        "options":  [
+
+                    ],
+        "answer":  "30;72;6;54;30;5;17;18",
+        "solution":  "【分析】本题包含乘法口诀，两位数减一位数(不退位)以及乘加乘减混合运算。计算时，乘法直接应用口诀;减法要注意相同数位相减，不需要退位时直接计算;乘加乘减算式要先算乘法，再算加减法.\n【详解】5×6=30(口诀\"五六三十\");79-7=72;2×3=6(口诀\"二三得六\");6×9=54(口诀\"六九五十四\");6×4+6=24+6=30;2×5-5=10-5=5;5×3+2=15+2=17;4×4+2=16+2=18。",
+        "knowledge_points":  [
+                                 "两位数与一位数的减法(不退位)",
+                                 "6的乘法口诀及应用",
+                                 "9的乘法口诀及应用",
+                                 "表内乘加，乘减"
+                             ],
+        "source":  "24-25二年级上·广东江门·期末"
+    },
+    {
+        "id":  "376",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "计算题",
+        "difficulty":  0.65,
+        "question":  "直接写出得数.\n\n30+13+8=( );53-(20+25)=( );45-8+12=( );3×6+10=( );6×8-12=( );12-5×2=( )",
+        "options":  [
+
+                    ],
+        "answer":  "51;8;49;28;36;2",
+        "solution":  "【分析】本题包含100以内数的连加，带括号的加减混合运算以及乘加乘减混合运算。计算时，连加按从左到右的顺序计算;有括号的算式要先算括号里面的;加减混合运算按从左到右的顺序计算;乘加乘减算式要先算乘法，再算加减法.\n【详解】30+13+8=43+8=51;53-(20+25)=53-45=8;45-8+12=37+12=49;3×6+10=18+10=28;6×8-12=48-12=36;12-5×2=12-10=2。",
+        "knowledge_points":  [
+                                 "100以内数的连加运算",
+                                 "100以内数的加减混合运算",
+                                 "表内乘加，乘减"
+                             ],
+        "source":  "24-25二年级上·广东江门·期末"
+    },
+    {
+        "id":  "377",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "看图列式并计算.\n\n![](images/fdbf7273178f0e6be8a7c53937d12a7fff36af4abf5aef1602dc505c1c53fce1.jpg)\n\n□ ○ □ = □(米)",
+        "options":  [
+
+                    ],
+        "answer":  "2×7=14",
+        "solution":  "【分析】数一数，共8朵花，有7个间隔，每个间隔2米长，用2乘7即可求出一共多长.\n【详解】2×7=14(米),一共长14米。",
+        "knowledge_points":  [
+                                 "图文问题",
+                                 "7的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·吉林·期末"
+    },
+    {
+        "id":  "378",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "计算题",
+        "difficulty":  0.85,
+        "question":  "直接写得数.\n\n2×6=( );4×5=( );6×1+15=( );4×4+70=( );9×7=( );8×6=( );9×5-24=( );3×6-9=( )",
+        "options":  [
+
+                    ],
+        "answer":  "12;20;21;86;63;48;21;9",
+        "solution":  "【分析】本题包含乘法口诀，乘加乘减混合运算。计算时，乘法直接应用对应的口诀;乘加乘减算式要先算乘法，再算加减法.\n【详解】2×6=12(口诀\"二六十二\");4×5=20(口诀\"四五二十\");6×1+15=6+15=21;4×4+70=16+70=86;9×7=63(口诀\"七九六十三\");8×6=48(口诀\"六八四十八\");9×5-24=45-24=21;3×6-9=18-9=9。",
+        "knowledge_points":  [
+                                 "4的乘法口诀及应用",
+                                 "6的乘法口诀及应用",
+                                 "9的乘法口诀及应用",
+                                 "表内乘加，乘减"
+                             ],
+        "source":  "23-24二年级上·河北保定·期末"
+    },
+    {
+        "id":  "379",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "看图列式.\n\n![](images/b9b8a8285acdecdf48157641fab8327cb112cfc1a735b840dd3b77f3130c5833.jpg)\n\n□ ○ □ = □(只)",
+        "options":  [
+
+                    ],
+        "answer":  "3×8=24或8×3=24",
+        "solution":  "【分析】根据题意，已知蝴蝶有8只，蜻蜓是蝴蝶的3倍，用蝴蝶的数量乘3即可求出蜻蜓有多少只，据此列式计算.\n【详解】3×8=24(只)或8×3=24(只),蜻蜓有24只。",
+        "knowledge_points":  [
+                                 "图文问题",
+                                 "8的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·全国·假期作业"
+    },
+    {
+        "id":  "380",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "计算题",
+        "difficulty":  0.85,
+        "question":  "认真口算.\n\n4×8=( );5+79=( );41-6=( );5×8+6=( );50-13=( );9×3=( );5×6=( );26+19-8=( );7×7=( );2×6=( );4×9=( );4×4-10=( )",
+        "options":  [
+
+                    ],
+        "answer":  "32;84;35;46;37;27;30;37;49;12;36;6",
+        "solution":  "【分析】本题包含乘法口诀，加减法以及乘加乘减混合运算。乘法直接应用口诀;加减法要注意进位和退位;乘加乘减要先算乘法再算加减法;加减混合运算按从左到右的顺序计算.\n【详解】4×8=32;5+79=84;41-6=35;5×8+6=40+6=46;50-13=37;9×3=27;5×6=30;26+19-8=45-8=37;7×7=49;2×6=12;4×9=36;4×4-10=16-10=6。",
+        "knowledge_points":  [
+                                 "100以内数的加减混合运算",
+                                 "8的乘法口诀及应用",
+                                 "9的乘法口诀及应用",
+                                 "表内乘加，乘减"
+                             ],
+        "source":  "23-24二年级上·河南郑州·期末"
+    },
+    {
+        "id":  "381",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "42名同学参加夏令营划船活动，每条船限坐8人,5条船能坐下吗。",
+        "options":  [
+
+                    ],
+        "answer":  "不能",
+        "solution":  "【分析】每条船限坐8人，先用乘法求出5条船最多能坐下多少人，然后与42比较大小，即可解决.\n【详解】8×5=40(人),42\u003e40，答:5条船不能坐下。",
+        "knowledge_points":  [
+                                 "100以内数的比大小",
+                                 "8的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·山东济宁·期末"
+    },
+    {
+        "id":  "382",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "二年级有8个班，每班有3名女学生参加画画班，后来画画班又增加了25名男生，现在画画班有多少名学生。",
+        "options":  [
+
+                    ],
+        "answer":  "49名",
+        "solution":  "【分析】每班有3名女学生参加画画班，先用乘法求出8个班共有几名女生参加，然后加上增加的男生人数，求出和，即可解决.\n【详解】8×3+25=24+25=49(名),答：现在画画班有49名学生。",
+        "knowledge_points":  [
+                                 "表内乘加，乘减"
+                             ],
+        "source":  "24-25二年级上·山东济宁·期末"
+    },
+    {
+        "id":  "383",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "小明看一本故事书，看了7天，每天看8页。一共看了多少页。还有32页没有看，这本书一共有多少页。",
+        "options":  [
+
+                    ],
+        "answer":  "56页;88页",
+        "solution":  "【分析】用看的天数乘每天看的页数即可求出一共看了多少页。用一共看了的页数加还没有看的页数即可求出一共有多少页.\n【详解】7×8=56(页),56+32=88(页),答：一共看了56页;这本书一共有88页。",
+        "knowledge_points":  [
+                                 "两位数与两位数的不进位加法",
+                                 "8的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·内蒙古通辽·期末"
+    },
+    {
+        "id":  "384",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "绘画班有5个小组，每个小组有9人，绘画班一共有多少人。",
+        "options":  [
+
+                    ],
+        "answer":  "45人",
+        "solution":  "【分析】此题是求5个9相加是多少，用乘法计算，据此解答.\n【详解】5×9=45(人),或9×5=45(人),答：绘画班一共有45人。",
+        "knowledge_points":  [
+                                 "9的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·甘肃天水·期末"
+    },
+    {
+        "id":  "385",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "(1)买一个篮球的钱相当于9个皮球的钱，买一个篮球需要多少钱。\n(2)小红买了6个羽毛球和1副乒乓球拍，付给售货员50元。小红付的钱够吗。\n\n![](images/acf7eaed02f0716a0806bdb8102a752dc740d2fbc5f80f5b8cf98dd206cd8626.jpg)\n8元\n\n![](images/91209b59c0fabc8567df1b6fd54f1319b98ffa7d21d88ddcb3d23726e7b84640.jpg)\n3元\n\n![](images/f01bc813a8f37d3060ea57db0bc47843269ff4684752467d188d297e59f30b9d.jpg)\n25元",
+        "options":  [
+
+                    ],
+        "answer":  "72元;够",
+        "solution":  "【分析】(1)一个皮球8元，用乘法求出9个皮球的总价钱，就是求出一个篮球的价钱。(2)一个羽毛球3元，先用乘法求出6个羽毛球多少钱，然后加上1副乒乓球拍的价钱，求出和，最后与50元比较大小，即可解决.\n【详解】(1)8×9=72(元),答：买一个篮球需要72元。(2)3×6+25=18+25=43(元),50\u003e43，答：小红付的钱够。",
+        "knowledge_points":  [
+                                 "100以内数的比大小",
+                                 "9的乘法口诀及应用",
+                                 "表内乘加，乘减"
+                             ],
+        "source":  "23-24二年级上·江西抚州·期末"
+    },
+    {
+        "id":  "386",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "小明和爸爸，妈妈，爷爷，奶奶一起去动物园玩，他们一家人买门票一共要多少元。\n\n![](images/2026-02-27%20004511.jpg)",
+        "options":  [
+
+                    ],
+        "answer":  "42元",
+        "solution":  "【分析】由题可知，爸爸，妈妈，爷爷和奶奶需要买4张成人票，小明需要买1张儿童票，则用每张成人票的价格和要买的数量相乘，求出买4张成人票需要的钱数，再和1张儿童票的价格相加，就是他们一家人买门票需要的总钱数.\n【详解】9×4+6=36+6=42(元),答：他们一家人买门票一共要42元。",
+        "knowledge_points":  [
+                                 "表内乘加，乘减"
+                             ],
+        "source":  "23-24二年级上·江西抚州·期末"
+    },
+    {
+        "id":  "387",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "学校组织同学们去融创乐园研学。划船小组每个小船有7名同学,9个小船有多少名同学。碰碰车小组比划船小组多了12人，碰碰车小组一共有多少人。",
+        "options":  [
+
+                    ],
+        "answer":  "75人",
+        "solution":  "【分析】用划船小组每个小船的人数乘小船的数量即可求出划船小组的总人数，然后加上碰碰车小组比划船小组多的人数即可求出碰碰车小组一共有多少人.\n【详解】7×9=63(名),63+12=75(名),答：碰碰车小组一共有75人。",
+        "knowledge_points":  [
+                                 "两位数与两位数的不进位加法",
+                                 "9的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·黑龙江哈尔滨·期末"
+    },
+    {
+        "id":  "388",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "学校美化环境，二年级一班走廊粘贴了学生手工作品，横着看每行粘贴9个作品，竖着看每列粘贴3个作品，一共粘贴了多少个手工作品。",
+        "options":  [
+
+                    ],
+        "answer":  "27个",
+        "solution":  "【分析】用横着看每行的作品数量乘竖着看每列的作品数量，即可求出手工作品总数量.\n【详解】9×3=27(个),答：一共粘贴了27个手工作品。",
+        "knowledge_points":  [
+                                 "9的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·黑龙江哈尔滨·期末"
+    },
+    {
+        "id":  "389",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "一二年级共有6组同学参加书法比赛，每组8人，一二年级参加书法比赛的一共有多少人。",
+        "options":  [
+
+                    ],
+        "answer":  "48人",
+        "solution":  "【分析】用组数乘每组的人数，即可求出一二年级参加书法比赛的一共有多少人.\n【详解】6×8=48(人),答：一二年级参加书法比赛的一共有48人。",
+        "knowledge_points":  [
+                                 "8的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·广东汕头·期末"
+    },
+    {
+        "id":  "390",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "商店周年庆，满50元减5元.\n\n(1)买6个机器人和1辆玩具车，一共要花多少元。\n\n![](images/c10e32fda77bb3a4e518e87add0764474d55fadeb945e4e4534111da15fb5768.jpg)\n7元\n\n![](images/6b44242826b46e4a6bcb2f9817e13cf4381f7bdb7f87b78f4e5fd5e17a03e954.jpg)\n9元\n\n![](images/a5cb104212797185696fedcf6fd0972e536543f4ce86c2109a82da82056a4fb0.jpg)\n6元\n\n![](images/bf47bbcbb8d1b5bb730e90c16843ba486f980e1af5fe754f4800264026c8504b.jpg)\n18元",
+        "options":  [
+
+                    ],
+        "answer":  "46元",
+        "solution":  "【分析】(1)用1个机器人的价钱乘6算出6个机器人的价钱，再加上1辆玩具车的价钱算出总价钱，然后比较，大于或等于50元则可以优惠，反之不可以.\n【详解】(1)7×6+9=42+9=51(元);51\u003e50;51-5=46(元),答：一共要花46元。",
+        "knowledge_points":  [
+                                 "图文问题",
+                                 "经济问题",
+                                 "\"提问题\"\"填条件\"问题",
+                                 "表内乘加，乘减"
+                             ],
+        "source":  "24-25二年级上·河南开封·期末"
+    },
+    {
+        "id":  "391",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "两个小组栽树。第一小组有4人，每人栽了8棵树.\n\n(1)第一小组一共栽了多少棵树。\n(2)第二小组比第一小组少栽19棵树，第二小组一共栽了多少棵树。两个小组一共栽了多少棵。\n\n![](images/fb9f12df914dc8548bfcdcad705a2aa519d5d1f1cfd6d1870976a99dfd00d7f8.jpg)",
+        "options":  [
+
+                    ],
+        "answer":  "32棵;13棵;45棵",
+        "solution":  "【分析】(1)求4个8相加是多少，用乘法计算，可以算出第一小组栽树多少棵，据此解答。(2)用第一小组栽的棵树减去19棵树，就能算出第二小组栽多少棵树;第一小组栽的树加上第二小组栽的树，算出两个小组一共栽树多少棵。据此解答.\n【详解】(1)4×8=32(棵),答：第一小组一共栽了32棵树。(2)32-19=13(棵);32+13=45(棵),答：第二小组一共栽了13棵树;两个小组一共栽了45棵。",
+        "knowledge_points":  [
+                                 "两位数与两位数的不进位加法",
+                                 "两位数与两位数的退位减法",
+                                 "8的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·河南开封·期末"
+    },
+    {
+        "id":  "392",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "花店扎了9束玫瑰花，每束7枝，一共有多少枝玫瑰花。",
+        "options":  [
+
+                    ],
+        "answer":  "63枝",
+        "solution":  "【分析】求一共有多少枝玫瑰花，也就是求9个7的和是多少，用乘法计算，即每束的枝数和束数相乘，就是总枝数.\n【详解】7×9=63(枝),答：一共有63枝玫瑰花。",
+        "knowledge_points":  [
+                                 "9的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·河南周口·期末"
+    },
+    {
+        "id":  "393",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "合唱队排队表演节目，站成了4排，每排9人，合唱队一共有多少人。",
+        "options":  [
+
+                    ],
+        "answer":  "36人",
+        "solution":  "【分析】求一共有多少人，也就是求4个9的和是多少，用乘法计算，即每排的人数和排数相乘，就是总人数.\n【详解】9×4=36(人),答：合唱队一共有36人。",
+        "knowledge_points":  [
+                                 "9的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·河南周口·期末"
+    },
+    {
+        "id":  "394",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "停车场停着6排小汽车，每排9辆，大客车比小汽车多37辆。停车场上停着多少辆大客车。",
+        "options":  [
+
+                    ],
+        "answer":  "91辆",
+        "solution":  "【分析】根据乘法的意义先求出小汽车的数量，用小汽车每排的辆数乘排数，得出小汽车的辆数，再用小汽车的辆数加37，就可以求出停车场大客车的辆数。据此解答.\n【详解】小汽车的辆数:6×9=54(辆),大客车的辆数:54+37=91(辆),答：停车场上停了91辆大客车。",
+        "knowledge_points":  [
+                                 "两位数与两位数的进位加法",
+                                 "9的乘法口诀及应用"
+                             ],
+        "source":  "23-24二年级上·浙江宁波·期末"
+    },
+    {
+        "id":  "395",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "一个笔筒9元，一个魔方14元，李老师买6个笔筒和1个魔方，一共需要多少元。",
+        "options":  [
+
+                    ],
+        "answer":  "68元",
+        "solution":  "【分析】用1个笔筒的价钱乘笔筒的数量，再加上1个魔方的价钱即可.\n【详解】9×6+14=54+14=68(元),答：一共需要68元。",
+        "knowledge_points":  [
+                                 "经济问题",
+                                 "乘加，乘减混合运算"
+                             ],
+        "source":  "23-24二年级上·河北保定·期末"
+    },
+    {
+        "id":  "396",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "操场上同学们分成6组踢毽子，每组8人。踢毽子的一共有多少人。旁边还有39人在踢足球，踢足球的比踢毽子的少多少人。",
+        "options":  [
+
+                    ],
+        "answer":  "48人;9人",
+        "solution":  "【分析】踢毽子的6组乘每组的8人，就可以求出踢毽子的总人数;再用踢毽子的总人数减去踢足球的人数，就能算出踢足球的比踢毽子的少的人数。据此解答.\n【详解】(1)6×8=48(人),答：踢毽子的一共有48人。(2)48-39=9(人),答：踢足球的比踢毽子的少9人。",
+        "knowledge_points":  [
+                                 "两位数与两位数的退位减法",
+                                 "8的乘法口诀及应用"
+                             ],
+        "source":  "23-24二年级上·江西赣州·期末"
+    },
+    {
+        "id":  "397",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "一共有多少只蝴蝶。\n\n![](images/2026-02-27%20005358.jpg)\n\n□ ○ □ = □(只)",
+        "options":  [
+
+                    ],
+        "answer":  "8×4=32",
+        "solution":  "【分析】观察图片可知：小鸟有8只，一格代表8只，则蝴蝶有4个格，就是求4个8的和，可以用乘法计算.\n【详解】8×4=32(只),答：一共有32只蝴蝶。",
+        "knowledge_points":  [
+                                 "8的乘法口诀及应用"
+                             ],
+        "source":  "23-24二年级上·浙江宁波·期末"
+    },
+    {
+        "id":  "398",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "一个茶壶36元，一个茶杯4元。买8个茶杯和一个茶壶一共需要多少元。",
+        "options":  [
+
+                    ],
+        "answer":  "68元",
+        "solution":  "【分析】一个茶杯4元，先用乘法求出8个茶杯多少钱，然后加上一个茶壶的价钱，求出和，就是一共需要的钱数.\n【详解】4×8+36=32+36=68(元),答：买8个茶杯和一个茶壶一共需要68元。",
+        "knowledge_points":  [
+                                 "表内乘加，乘减"
+                             ],
+        "source":  "23-24二年级上·河北保定·期末"
+    },
+    {
+        "id":  "399",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "二(1)班全体同学做早操，班长发现今天有2人生病没有来。队伍正好站了8排，每排4人。二(1)班一共有多少人。",
+        "options":  [
+
+                    ],
+        "answer":  "34人",
+        "solution":  "【分析】用站的排数乘每排的人数，再加上没有来的2人即可求出二(1)班一共有多少人.\n【详解】8×4+2=32+2=34(人),答：二(1)班一共有34人。",
+        "knowledge_points":  [
+                                 "表内乘加，乘减"
+                             ],
+        "source":  "23-24二年级上·河北石家庄·期末"
+    },
+    {
+        "id":  "400",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "买玩具.\n\n(1)黄老师买5辆玩具坦克和1个玩具熊，一共花了多少钱。\n(2)丁丁有80元，他买1个玩具熊和1架玩具飞机后，还剩多少元。\n\n![](images/15368ff013dc22228eceaa8a2ed7a358392ec7b01ecf343f15c90a5512cd2b75.jpg)\n26元\n\n![](images/10f46f30574314464fcc635496604cbb9b9228a7d764346693e7ef58bf2b90ca.jpg)\n9元\n\n![](images/bcafefbbfa16732433318f6eb381982193c9bc8b846277f9e767b251e73018c1.jpg)\n45元",
+        "options":  [
+
+                    ],
+        "answer":  "71元;9元",
+        "solution":  "【分析】(1)根据题意，先用每辆玩具坦克的价格和数量相乘，求出5辆玩具坦克的钱数，再和1个玩具熊的钱数相加，就是买5辆玩具坦克和1个玩具熊一共要花的钱数;(2)求还剩多少元，用减法计算，即丁丁的钱数-1个玩具熊的钱数-1架玩具飞机的钱数=还剩的钱数.\n【详解】(1)9×5+26=45+26=71(元),答：一共花了71元钱。(2)80-26-45=9(元),答：还剩9元。",
+        "knowledge_points":  [
+                                 "图文问题",
+                                 "100以内数的连减运算",
+                                 "表内乘加，乘减"
+                             ],
+        "source":  "23-24二年级上·河北保定·期末"
+    },
+    {
+        "id":  "401",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "一根绳子对折2次后长度是8厘米，这根绳子原来长( )厘米。",
+        "options":  [
+                        "A. 32",
+                        "B. 24",
+                        "C. 16"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】根据题意，一根绳子对折1次被平均分成了2份，对折2次，则被平均分成了4份，已知对折2次后的长度是8厘米，那么原来这根绳子的长是(8×4)厘米，据此解答.\n【详解】8×4=32(厘米),所以一根绳子对折2次后长度是8厘米，这根绳子原来长32厘米。故答案为:A",
+        "knowledge_points":  [
+                                 "图形的折叠问题",
+                                 "8的乘法口诀及应用"
+                             ],
+        "source":  "23-24二年级上·浙江台州·期末"
+    },
+    {
+        "id":  "402",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "( )可以用\"九九八十一\"计算。",
+        "options":  [
+                        "A. 2个9相加",
+                        "B. 9个9相乘",
+                        "C. 2个9相乘"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】几个相同加数相加，可以写成加数与个数相乘的形式。乘法算式中两个乘数是口诀中的前两个数，积是口诀中的后一个数，写算式时两个乘数可互换位置.\n【详解】A。2个9相加用口诀\"二九十八\";B。9个9相乘，有9个乘数，不能用口诀\"九九八十一\";C。2个9相乘用\"九九八十一\"计算。2个9相乘可以用\"九九八十一\"计算。故答案为:C",
+        "knowledge_points":  [
+                                 "9的乘法口诀及应用"
+                             ],
+        "source":  "23-24二年级上·四川广元·期末"
+    },
+    {
+        "id":  "403",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "一根绳子剪去一半，再剪去剩下的一半后，还剩8米，这根绳子原来长( )。",
+        "options":  [
+                        "A. 32米",
+                        "B. 24米",
+                        "C. 16米"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】根据题意，一根绳子剪去一半，又剪去剩下的一半，还剩下8米，那么剩下的8米乘2，就是绳子的一半，绳子的一半再加上另一半就是原来绳子的长度.\n【详解】8×2=16(米),16+16=32(米),这根绳子原来长32米。故答案为:A",
+        "knowledge_points":  [
+                                 "两位数与两位数的进位加法",
+                                 "8的乘法口诀及应用"
+                             ],
+        "source":  "23-24二年级上·浙江杭州·期末"
+    },
+    {
+        "id":  "404",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "下面可以列式为4×8的数学问题是( )。",
+        "options":  [
+                        "A. 池塘里有8只鸭子，游走了4只，还剩下几只。",
+                        "B. 一班得了4面小旗，二班得了8面小旗。两个班一共得了几面小旗。",
+                        "C. 每人做4朵花,8人一共做几朵花。"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】依次将各选项用算式表示出来，找到符合题意的即可。4×8表示的是4个8相加的和，或者8个4相加的和.\n【详解】A。池塘里有8只鸭子，游走了4只，还剩下几只。求还剩的数量，用减法计算，列式为:8-4=4，则不符合题意。B。一班得了4面小旗，二班得了8面小旗。两个班一共得了几面小旗。用一班得的数量加二班得的数量即可求出两班一共得了多少，列式为:4+8，则不符合题意。C。每人做4朵花,8人一共做几朵花。根据题意可知：用每人做的数量乘人数即可求出8人一共做的数量，列式为:4×8，则符合题意。故答案为:C",
+        "knowledge_points":  [
+                                 "8的乘法口诀及应用"
+                             ],
+        "source":  "23-24二年级上·贵州黔南·期末"
+    },
+    {
+        "id":  "405",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "学雷锋小组的同学被分成了6个小组，每个小组有8个同学，一共有( )个同学参加了学雷锋小组。",
+        "options":  [
+                        "A. 14",
+                        "B. 45",
+                        "C. 48"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】已知每个小组有8个同学，共有6个小组，用每个组的人数乘小组的数量即可得出一共有几个同学参加学雷锋小组.\n【详解】8×6=48(个),所以一共有48人参加了学雷锋小组。故答案为:C",
+        "knowledge_points":  [
+                                 "8的乘法口诀及应用"
+                             ],
+        "source":  "23-24二年级上·河南南阳·期末"
+    },
+    {
+        "id":  "406",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "下列算式中，得数最大的是( )。",
+        "options":  [
+                        "A. 6×8",
+                        "B. 9×7",
+                        "C. 36+54"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】根据整数加减法的计算法则及表内乘法口诀，依次计算出各算式的结果再比较大小。比较时，位数多的数就大;位数相同比较最高位，最高位大的数就大;最高位相同比较下一位，直到比较出结果为止.\n【详解】A。6×8=48;B。9×7=63;C。36+54=90;90\u003e63\u003e48，得数最大的是36+54。故答案为:C",
+        "knowledge_points":  [
+                                 "100以内数的比大小",
+                                 "两位数与两位数的进位加法",
+                                 "8的乘法口诀及应用",
+                                 "9的乘法口诀及应用"
+                             ],
+        "source":  "23-24二年级上·重庆秀山·期末"
+    },
+    {
+        "id":  "407",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "一个盒子可以装8块饼干，有60块饼干，用8个盒子装的结果是( )。",
+        "options":  [
+                        "A. 不能装满",
+                        "B. 正好全部装满",
+                        "C. 装不下"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】根据题意，先用每个盒子装饼干的数量和盒数相乘，求出8个盒子一共可以装多少块饼干，再和60比较大小。能装的数量大于60不能装满，小于60装不下，等于60正好全部装满.\n【详解】8×8=64(块),64\u003e60，用8个盒子装的结果是不能装满。故答案为:A",
+        "knowledge_points":  [
+                                 "100以内数的比大小",
+                                 "8的乘法口诀及应用"
+                             ],
+        "source":  "23-24二年级上·重庆秀山·期末"
+    },
+    {
+        "id":  "408",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "一个数比4个8大，比5个7小，这个数可能是( )。",
+        "options":  [
+                        "A. 32",
+                        "B. 33",
+                        "C. 38"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】求几个相同加数的和，可以用乘法计算，用相同加数×个数或个数×相同加数，由此分别用乘法计算出4个8和5个7是多少，再和选项中的数比较大小。比较时，位数多的数就大;位数相同比较最高位，最高位大的数就大;最高位相同比较下一位，直到比较出结果为止.\n【详解】4个8:8×4=32;5个7:7×5=35。A。32=32\u003c35，不符合题意;B。32\u003c33\u003c35，符合题意;C。32\u003c35\u003c38，不符合题意。所以这个数可能是33。故答案为:B",
+        "knowledge_points":  [
+                                 "100以内数的比大小",
+                                 "7的乘法口诀及应用",
+                                 "8的乘法口诀及应用"
+                             ],
+        "source":  "23-24二年级上·湖南湘西·期末"
+    },
+    {
+        "id":  "409",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "6个8比8个8( )。",
+        "options":  [
+                        "A. 少2",
+                        "B. 少16",
+                        "C. 少8"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】求几个相同加数的和，可以用乘法计算，用相同加数×个数或个数×相同加数。由此分别计算出6个8和8个8的结果，再相减即可计算出相差多少.\n【详解】8×6=48;8×8=64;64-48=16,6个8比8个8少16。故答案为:B",
+        "knowledge_points":  [
+                                 "两位数与两位数的退位减法",
+                                 "8的乘法口诀及应用"
+                             ],
+        "source":  "23-24二年级上·重庆璧山·期末"
+    },
+    {
+        "id":  "410",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "一个乘数是4，另一个乘数是8，积是( )。",
+        "options":  [
+                        "A. 12",
+                        "B. 32",
+                        "C. 36"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】乘法算式为：乘数×乘数=积，由此代入计算即可.\n【详解】4×8=32，一个乘数是4，另一个乘数是8，积是32。故答案为:B",
+        "knowledge_points":  [
+                                 "8的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·河南周口·期中"
+    },
+    {
+        "id":  "411",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "小明和小红各买了4支钢笔，每支钢笔3元，他们一共花了( )元。",
+        "options":  [
+                        "A. 16",
+                        "B. 24",
+                        "C. 32"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】先根据加法的意义，用小明买的钢笔数加上小红买的钢笔数求出他们买的钢笔总数，再根据乘法的意义，用他们买的钢笔总数×每支钢笔的价钱即可.\n【详解】4+4=8(支),3×8=24(元),所以小明和小红各买了4支钢笔，每支钢笔3元，他们一共花了24元。故答案为:B",
+        "knowledge_points":  [
+                                 "8,9的加减法",
+                                 "8的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·广东揭阳·期中"
+    },
+    {
+        "id":  "412",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "积是24的算式是( )。",
+        "options":  [
+                        "A. 20-2",
+                        "B. 3×8",
+                        "C. 2+9"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】乘数×乘数=积，首先确定乘法算式，再根据乘法口诀计算出乘法算式的积，找到积是24的乘法算式即可.\n【详解】A。20-2=18，差是18，不符合题意;B。3×8=24，积是24，符合题意;C。2+9=11，和是11，不符合题意。故答案为:B",
+        "knowledge_points":  [
+                                 "9加几的进位加法",
+                                 "一位数与两位数的退位减法",
+                                 "8的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·广东揭阳·期中"
+    },
+    {
+        "id":  "413",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "不能用口诀\"二九十八\"来计算的是( )。",
+        "options":  [
+                        "A. 2×9",
+                        "B. 3×6",
+                        "C. 9×2"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】根据乘法口诀计算乘法算式，乘法算式中两个乘数(可交换位置)是口诀中的前两个数，积是口诀中的后一个数，据此解答即可.\n【详解】A。2×9=18，能用口诀\"二九十八\"来计算;B。3×6=18，不能用口诀\"二九十八\"来计算;C。9×2=18，能用口诀\"二九十八\"来计算。故答案为:B",
+        "knowledge_points":  [
+                                 "6的乘法口诀及应用",
+                                 "9的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·河南郑州·期中"
+    },
+    {
+        "id":  "414",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "明明买了同样一种物品正好花了9元，他可能买的是( )。",
+        "options":  [
+                        "A. ![](images/309725a2ae4f5867f0f6b1c1ab95a6580a4069471a5c843da846ee4aa5f52062.jpg)每本3元",
+                        "B. ![](images/4b1d114f49002f29f51f766d955db2e12c9d894fcff515849ac3963a499a0fd5.jpg)每双5元",
+                        "C. ![](images/430bed7c993881034b3d40b55e2e53ae7ef2d4cfbb3022156cfe8dffb06af656.jpg)每辆4元"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】已知物品的总价是9元，那么得数是9的口诀有\"一九得九，三三得九\"这两句。据此可知这个物品的单价可能是9或1或3。据此选择即可.\n【详解】用\"数量×每个物品的价格=花的总价\"，据此用算式分析:1×9=9(元),3×3=9(元),这个物品的单价可能是9或1或3，选项里只有3符合题意。故答案为:A",
+        "knowledge_points":  [
+                                 "3的乘法口诀及应用",
+                                 "9的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·内蒙古鄂尔多斯·期中"
+    },
+    {
+        "id":  "415",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "把下面的乘法口诀补充完整.\n\n四( )三十六;二( )十四",
+        "options":  [
+
+                    ],
+        "answer":  "九;七",
+        "solution":  "【分析】根据表内乘法口诀填写即可，注意要写汉字.\n【详解】四九三十六;二七十四。",
+        "knowledge_points":  [
+                                 "7的乘法口诀及应用",
+                                 "9的乘法口诀及应用"
+                             ],
+        "source":  "23-24二年级上·河北保定·期末"
+    },
+    {
+        "id":  "416",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "6×8=( )×9-6。",
+        "options":  [
+
+                    ],
+        "answer":  "6",
+        "solution":  "【分析】根据乘法的意义可知:6乘8表示8个6的和是多少，据此结合题干要求可知:9个几的和减去6等于8个6，据此解答即可.\n【详解】9个6的和减去1个6等于8个6，即6×9-6=6×8。",
+        "knowledge_points":  [
+                                 "初步认识乘法意义",
+                                 "8的乘法口诀及应用",
+                                 "表内乘加，乘减"
+                             ],
+        "source":  "23-24二年级上·甘肃天水·期末"
+    },
+    {
+        "id":  "417",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "括号里最大能填几。\n\n4×( )\u003c37;( )×8\u003c58\n35\u003e6×( );70\u003e8×( )",
+        "options":  [
+
+                    ],
+        "answer":  "9;7;5;8",
+        "solution":  "【分析】根据表内乘法口诀及整数比较大小的方法来解决此题.\n【详解】4×9=36,36\u003c37，故,4×9\u003c37;7×8=56,8×8=64,56\u003c58\u003c64，故,7×8\u003c58;6×5=30,6×6=36,36\u003e35\u003e30，故,35\u003e6×5;8×8=64,8×9=72,72\u003e70\u003e64，故,70\u003e8×8。",
+        "knowledge_points":  [
+                                 "100以内数的比大小",
+                                 "6的乘法口诀及应用",
+                                 "8的乘法口诀及应用",
+                                 "9的乘法口诀及应用"
+                             ],
+        "source":  "23-24二年级上·甘肃天水·期末"
+    },
+    {
+        "id":  "418",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "6个8相加，和比50少( )。",
+        "options":  [
+
+                    ],
+        "answer":  "2",
+        "solution":  "【分析】根据整数乘法的意义可知：求几个相同加数的和的简便运算，据此先求出6个8的和是多少，再用50减去它们的和，即可得出答案.\n【详解】6×8=48,50-48=2，所以6个8相加，和比50少2。",
+        "knowledge_points":  [
+                                 "两位数与两位数的退位减法",
+                                 "8的乘法口诀及应用"
+                             ],
+        "source":  "23-24二年级上·甘肃天水·期末"
+    },
+    {
+        "id":  "419",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "括号里最大能填几。\n\n( )×5\u003c32;( )×4\u003c29;9×( )\u003c75",
+        "options":  [
+
+                    ],
+        "answer":  "6;7;8",
+        "solution":  "【分析】乘法算式中两个乘数是口诀中的前两个数，积是口诀中的后一个数，写算式时两个乘数可互换位置。整数的大小比较：比较数的大小，先看位数的多少，位数多的数就大;位数相同，从高位开始比较，高位上的数大则这个数大，高位上的数相同，就比较下一位。根据乘法口诀和数的大小关系解答.\n【详解】五六三十，五七三十五，最大填6，所以6×5\u003c32;四七二十八，四八三十二，最大填7，所以7×4\u003c29;八九七十二，九九八十一，最大填8，所以9×8\u003c75。",
+        "knowledge_points":  [
+                                 "100以内数的比大小",
+                                 "7的乘法口诀及应用",
+                                 "8的乘法口诀及应用",
+                                 "9的乘法口诀及应用"
+                             ],
+        "source":  "23-24二年级上·河南郑州·期末"
+    },
+    {
+        "id":  "420",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "括号里最大能填几。\n\n( )×7\u003c63;54\u003e8×( );72-( )\u003e9",
+        "options":  [
+
+                    ],
+        "answer":  "8;6;62",
+        "solution":  "【分析】根据表内乘法口诀和100以内整数减法运算，结合整数比较大小，即可得出答案.\n【详解】根据\"七八五十六\"\"七九六十三\"可知:7×8=56,7×9=63,56\u003c63,63=63，所以括号内最大能填8;根据\"六八四十八\"\"六九五十四\"可知:6×8=48,6×9=54,48\u003c54,54=54，所以括号内最大能填6;72-9=63，小于63最大的数是62，所以括号内最大能填62。",
+        "knowledge_points":  [
+                                 "100以内数的比大小",
+                                 "一位数与两位数的退位减法",
+                                 "8的乘法口诀及应用",
+                                 "9的乘法口诀及应用"
+                             ],
+        "source":  "23-24二年级上·浙江台州·期末"
+    },
+    {
+        "id":  "421",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "9和3相加是( ),9个3相加是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "12;27",
+        "solution":  "【分析】本题涉及加法运算和乘法运算的概念。对于第一空，根据加法的定义，把两个数合并成一个数的运算叫做加法，直接将9和3相加即可;对于第二空，根据乘法的意义，求几个相同加数的和的简便运算叫做乘法,9个3相加可以转化为乘法运算，即9乘以3或者3×9.\n【详解】通过分析可列式:(1)9+3=12;(2)9×3=27或者3×9=27，所以,9和3相加是12,9个3相加是27。",
+        "knowledge_points":  [
+                                 "9加几的进位加法",
+                                 "9的乘法口诀及应用"
+                             ],
+        "source":  "23-24二年级上·浙江台州·期末"
+    },
+    {
+        "id":  "422",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "在下面括号里最大能填几。\n\n( )×3\u003c27;34\u003e5×( );( )×8\u003c55",
+        "options":  [
+
+                    ],
+        "answer":  "8;6;6",
+        "solution":  "【分析】根据表内乘法口诀及整数比较大小的方法来解决此题即可.\n【详解】8×3=24,9×3=27,24\u003c27，故,8×3\u003c27;5×6=30,5×7=35,35\u003e34\u003e30，故,34\u003e5×6;6×8=48,7×8=56,48\u003c55\u003c56，故,6×8\u003c55。",
+        "knowledge_points":  [
+                                 "100以内数的比大小",
+                                 "6的乘法口诀及应用",
+                                 "7的乘法口诀及应用",
+                                 "8的乘法口诀及应用"
+                             ],
+        "source":  "23-24二年级上·新疆昌吉·期末"
+    },
+    {
+        "id":  "423",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "两个乘数都是8，积是( );6个加数都是5，和是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "64;30",
+        "solution":  "【分析】对于乘法，乘数乘乘数等于积;6个5相加的和，根据乘法的意义，求几个相同加数的和用乘法计算，这两道题我们都可以用乘法进行计算，据此解答.\n【详解】根据分析:8×8=64;6×5=30;所以，两个乘数都是8，积是64;6个加数都是5，和是30。",
+        "knowledge_points":  [
+                                 "6的乘法口诀及应用",
+                                 "8的乘法口诀及应用"
+                             ],
+        "source":  "23-24二年级上·甘肃天水·期末"
+    },
+    {
+        "id":  "424",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "( )最大能填几。\n\n( )×3\u003c28;34\u003e5×( );7×( )\u003c30;4×( )\u003c38",
+        "options":  [
+
+                    ],
+        "answer":  "9;6;4;9",
+        "solution":  "【分析】根据乘法口诀和数的大小关系解答。乘法算式中两个乘数是口诀中的前两个数，积是口诀中的后一个数，写算式时两个乘数可互换位置。整数的大小比较：比较数的大小，先看位数的多少，位数多的数就大;位数相同，从高位开始比较，高位上的数大则这个数大;高位上的数相同，就比较下一位.\n【详解】三九二十七,3个10是30，最大填9,9×3\u003c28;五六三十，五七三十五，最大填6,34\u003e5×6;四七二十八，五七三十五，最大填4,7×4\u003c30;四九三十六,4个10是40，最大填9,4×9\u003c38。",
+        "knowledge_points":  [
+                                 "100以内数的比大小",
+                                 "6的乘法口诀及应用",
+                                 "7的乘法口诀及应用",
+                                 "9的乘法口诀及应用"
+                             ],
+        "source":  "23-24二年级上·四川广元·期末"
+    },
+    {
+        "id":  "425",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "根据口诀填空.\n\n四九( );三八( );七七( );( )七四十二;( )四十八;五( )四十五",
+        "options":  [
+
+                    ],
+        "answer":  "三十六;二十四;四十九;六;六八;九",
+        "solution":  "【分析】根据表内乘法口诀填写即可，注意要写汉字.\n【详解】四九三十六;三八二十四;七七四十九;六七四十二;六八四十八;五九四十五。",
+        "knowledge_points":  [
+                                 "7的乘法口诀及应用",
+                                 "8的乘法口诀及应用",
+                                 "9的乘法口诀及应用"
+                             ],
+        "source":  "23-24二年级上·四川德阳·期末"
+    },
+    {
+        "id":  "426",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "8个4相加的和是( );8与4相加的和是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "32;12",
+        "solution":  "【分析】几个相同加数相加，可以写成加数与个数相乘的形式。乘法算式中两个乘数是口诀中的前两个数，积是口诀中的后一个数，写算式时两个乘数可互换位置。8个4相加可以用8乘4计算;8和4相加用8加4计算.\n【详解】8×4=32,8+4=12,8个4相加的和是32;8与4相加的和是12。",
+        "knowledge_points":  [
+                                 "8加几的进位加法",
+                                 "同数连加的应用",
+                                 "8的乘法口诀及应用"
+                             ],
+        "source":  "23-24二年级上·浙江杭州·期末"
+    },
+    {
+        "id":  "427",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在下面的( )里最大能填几。\n\n4×( )\u003c31;62\u003e( )×7;8×( )\u003c65",
+        "options":  [
+
+                    ],
+        "answer":  "7;8;8",
+        "solution":  "【分析】根据含有小于号左侧或大于号右侧已知数的乘法口诀，找出结果小于且最接近另一侧数的即可.\n【详解】4×7=28,4×8=32,28\u003c31\u003c32，则4×7\u003c31;9×7=63,8×7=56,56\u003c62\u003c63，则62\u003e8×7;8×8=64,8×9=72,64\u003c65\u003c72，则8×8\u003c65。",
+        "knowledge_points":  [
+                                 "100以内数的比大小",
+                                 "8的乘法口诀及应用",
+                                 "9的乘法口诀及应用"
+                             ],
+        "source":  "23-24二年级上·福建三明·期末"
+    },
+    {
+        "id":  "428",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "9个6相加，和是( );9和6相加，和是( );两个乘数都是8，积是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "54;15;64",
+        "solution":  "【分析】求9个6的和，可以用乘法计算，用相同加数×个数或个数×相同加数，也就是用9和6相乘;加法算式为加数+加数=和,9和6相加，也就是一个加数是9，另一个加数是6;乘法算式为乘数×乘数=积，两个乘数都是8，代入计算即可.\n【详解】9×6=54;9+6=15;8×8=64.9个6相加，和是54;9和6相加，和是15;两个乘数都是8，积是64。",
+        "knowledge_points":  [
+                                 "9加几的进位加法",
+                                 "8的乘法口诀及应用",
+                                 "9的乘法口诀及应用"
+                             ],
+        "source":  "23-24二年级上·河南安阳·期末"
+    },
+    {
+        "id":  "429",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "计算4×6和6×4用的乘法口诀是( );用\"五七三十五\"可以计算( )或( )。",
+        "options":  [
+
+                    ],
+        "answer":  "四六二十四;5×7=35;7×5=35",
+        "solution":  "【分析】计算乘法算式时用到的口诀，用汉字填写，两个乘数是口诀中的前两个数，积是口诀中的后一个数;根据乘法口诀计算乘法算式时，口诀中的前两个数是乘数可互换位置，后一个数是积，由此写出算式.\n【详解】计算4×6和6×4用的乘法口诀是\"四六二十四\";用\"五七三十五\"可以计算5×7=35或7×5=35。",
+        "knowledge_points":  [
+                                 "6的乘法口诀及应用",
+                                 "7的乘法口诀及应用"
+                             ],
+        "source":  "23-24二年级上·河南安阳·期末"
+    },
+    {
+        "id":  "430",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "一个乘数是8，另一个乘数是( ),积是48。",
+        "options":  [
+
+                    ],
+        "answer":  "6",
+        "solution":  "【分析】根据乘法的认识和乘法口诀，\"六八四十八\"，即6×8=48，由此求出另一个乘数.\n【详解】六八四十八,6×8=48，所以一个乘数是8，另一个乘数是6，积是48。",
+        "knowledge_points":  [
+                                 "8的乘法口诀及应用"
+                             ],
+        "source":  "23-24二年级上·云南红河·期末"
+    },
+    {
+        "id":  "431",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "8个9相加，写成乘法算式是:( ),这个式子读作:( )。",
+        "options":  [
+
+                    ],
+        "answer":  "8×9=72;8乘9等于72",
+        "solution":  "【分析】求几个相同加数的和，可以用乘法计算，用相同加数×个数或个数×相同加数。乘法算式从左往右读，数字是几就读几，\"*\"读作乘，\"=\"读作等于，由此解答.\n【详解】8个9相加，写成乘法算式是:8×9=72，这个式子读作:8乘9等于72。或写成乘法算式是:9×8=72，这个式子读作:9乘8等于72。",
+        "knowledge_points":  [
+                                 "初步认识乘法意义",
+                                 "9的乘法口诀及应用"
+                             ],
+        "source":  "23-24二年级上·重庆永川·期末"
+    },
+    {
+        "id":  "432",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "括号里最大能填几。\n\n( )×6\u003c31;( )×4\u003c25;39\u003e6×( )",
+        "options":  [
+
+                    ],
+        "answer":  "5;6;6",
+        "solution":  "【分析】根据含有小于号左侧或大于号右侧已知数的乘法口诀，找出结果小于且最接近另一侧数的即可.\n【详解】5×6=30\u003c31;6×6=36\u003e31，所以括号里最大能填5;6×4=24\u003c25;7×4=28\u003e25，所以括号里最大能填6;39\u003e6×6=36;39\u003c6×7=42，所以括号里最大能填6。",
+        "knowledge_points":  [
+                                 "100以内数的比大小",
+                                 "6的乘法口诀及应用",
+                                 "7的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·山东临沂·期中"
+    },
+    {
+        "id":  "433",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "一个五角星有5个角,8个五角星一共有( )个角。",
+        "options":  [
+
+                    ],
+        "answer":  "40",
+        "solution":  "【分析】求8个五角星一共有几个角，也就是求8个5的和是多少，用乘法计算，每个五角星角的数量和五角星的个数相乘，就是角的总数量.\n【详解】5×8=40(个),一个五角星有5个角,8个五角星一共有40个角。",
+        "knowledge_points":  [
+                                 "8的乘法口诀及应用"
+                             ],
+        "source":  "23-24二年级上·重庆云阳·期末"
+    },
+    {
+        "id":  "434",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "括号里最大能填几。\n\n( )×4\u003c29;43\u003e5×( );6×9\u003e( )",
+        "options":  [
+
+                    ],
+        "answer":  "7;8;53",
+        "solution":  "【分析】一题和二题可根据含有小于号左侧或大于号右侧已知数的乘法口诀，找出结果小于且最接近另一侧数的即可。三题：计算出算式的答案，填写的数比该答案小1，则该数为最大.\n【详解】8×4=32,7×4=28,28\u003c29\u003c32，则7×4\u003c29;5×8=40,5×9=45,40\u003c43\u003c45，则43\u003e5×8;6×9=54,54-1=53,54\u003e53，则6×9\u003e53。",
+        "knowledge_points":  [
+                                 "100以内数的比大小",
+                                 "7的乘法口诀及应用",
+                                 "8的乘法口诀及应用",
+                                 "9的乘法口诀及应用"
+                             ],
+        "source":  "23-24二年级上·浙江温州·期末"
+    },
+    {
+        "id":  "435",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "二(1)班全体同学去学校礼堂参加历史讲座，每排坐6人，正好坐满了9排，二(1)班一共有( )名同学。",
+        "options":  [
+
+                    ],
+        "answer":  "54",
+        "solution":  "【分析】求一共有多少名同学，也就是求9个6的和是多少，用乘法计算，每排的人数和排数相乘就是总人数.\n【详解】6×9=54(名),二(1)班全体同学去学校礼堂参加历史讲座，每排坐6人，正好坐满了9排，二(1)班一共有54名同学。",
+        "knowledge_points":  [
+                                 "9的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·河南周口·期中"
+    },
+    {
+        "id":  "436",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在括号里填\"+\"\"-\"或\"*\".\n\n6( )6=12;9( )2=7;5( )6=30;8( )7=56;7( )9=63;8( )2=10",
+        "options":  [
+
+                    ],
+        "answer":  "+;-;*;*;*;+",
+        "solution":  "【分析】根据整数加减法的计算法则及表内乘法口诀解答。6和6合起来就是12，即6+6=12;9可以分成2和7，即9-2=7;根据乘法口诀\"五六三十\"可知,5×6=30;根据乘法口诀\"七八五十六\"可知,8×7=56;根据乘法口诀\"七九六十三\"可知,7×9=63;8和2合起来就是10，即8+2=10.\n【详解】6+6=12,9-2=7,5×6=30,8×7=56,7×9=63,8+2=10。",
+        "knowledge_points":  [
+                                 "8,9的加减法",
+                                 "7,6加几的进位加法",
+                                 "8的乘法口诀及应用",
+                                 "9的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·河南周口·期中"
+    },
+    {
+        "id":  "437",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "括号里最大能填几。\n\n8×( )\u003c65;40-12\u003e4×( );( )×9\u003c65",
+        "options":  [
+
+                    ],
+        "answer":  "8;6;7",
+        "solution":  "【分析】根据给出的算式，和乘法口诀可计算。小于65的最大数是64，根据乘法口诀\"八八六十四\"可得出答案;先计算减法算式等于28，\"四七二十八\"，需要小于28，括号中填小于7的数字中最大的即可;根据乘法口诀\"七九六十三\"，刚好小于65.\n【详解】8×8=64,64\u003c65，所以8×8\u003c65;40-12=28,4×6=24，所以40-12\u003e4×6;7×9=63,63\u003c65，所以7×9\u003c65。",
+        "knowledge_points":  [
+                                 "100以内数的比大小",
+                                 "6的乘法口诀及应用",
+                                 "8的乘法口诀及应用",
+                                 "9的乘法口诀及应用"
+                             ],
+        "source":  "23-24二年级上·浙江杭州·期末"
+    },
+    {
+        "id":  "438",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "在括号里填上\"\u003e\"\"\u003c\"或\"=\".\n\n2×7( )3×8;90( )74+16;1米( )99厘米",
+        "options":  [
+
+                    ],
+        "answer":  "\u003c;=;\u003e",
+        "solution":  "【分析】比较数字的大小，先将需要计算的算式计算出来，乘法计算根据乘法口诀即可得出答案;加法的计算，相同数位对齐，从各位算起，满十进一;长度单位的大小比较，需要先将单位进行换算,1米=100厘米，然后再进行比较.\n【详解】2×7=14,3×8=24,14\u003c24，所以2×7\u003c3×8;74+16=90,90=90，所以90=74+16;1米=100厘米,100厘米\u003e99厘米，所以1米\u003e99厘米。",
+        "knowledge_points":  [
+                                 "100以内数的比大小",
+                                 "两位数与两位数的进位加法",
+                                 "8的乘法口诀及应用",
+                                 "厘米和米之间的进率与换算"
+                             ],
+        "source":  "23-24二年级上·湖南湘西·期末"
+    },
+    {
+        "id":  "439",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "把下面的乘法口诀补充完整.\n\n三七( );五( )四十;( )十六",
+        "options":  [
+
+                    ],
+        "answer":  "二十一;八;二八或四四",
+        "solution":  "【分析】根据题意，熟练掌握表内乘法口诀：一一得一，一二得二，二二得四，一三得三，二三得六，三三得九,。,九九八十一，据此解答.\n【详解】根据分析：三七(二十一);五(八)四十;(二八)十六(或者\"四四十六\")。",
+        "knowledge_points":  [
+                                 "4的乘法口诀及应用",
+                                 "7的乘法口诀及应用",
+                                 "8的乘法口诀及应用"
+                             ],
+        "source":  "23-24二年级上·湖南湘西·期末"
+    },
+    {
+        "id":  "440",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "把口诀补充完整.\n\n( )八三十二;七( )六十三;三七( )\n六九( );五( )四十;九九( )",
+        "options":  [
+
+                    ],
+        "answer":  "四;九;二十一;五十四;八;八十一",
+        "solution":  "【分析】根据表内乘法口诀填写，注意要写汉字.\n【详解】四八三十二;七九六十三;三七二十一;六九五十四;五八四十;九九八十一。",
+        "knowledge_points":  [
+                                 "7的乘法口诀及应用",
+                                 "8的乘法口诀及应用",
+                                 "9的乘法口诀及应用"
+                             ],
+        "source":  "23-24二年级上·重庆璧山·期末"
+    },
+    {
+        "id":  "441",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在括号里填上\"\u003e\"\"\u003c\"或\"=\".\n\n9×5( )46;67+28( )100;47( )8×6;36+47( )47-28;24( )7×6;8×3( )4×6",
+        "options":  [
+
+                    ],
+        "answer":  "\u003c;\u003c;\u003c;\u003e;\u003c;=",
+        "solution":  "【分析】先计算出各算式的答案，然后比较大小即可。整数比较大小，位数多的，该数就大;数位相同，就看最高位上的数，若最高位上大该数就大，若最高位数字相同，依次看下一位即可.\n【详解】9×5=45,45\u003c46，则9×5\u003c46;67+28=95,95\u003c100，则67+28\u003c100;8×6=48,47\u003c48，则47\u003c8×6;36+47=83,47-28=19,83\u003e19，则36+47\u003e47-28;7×6=42,24\u003c42，则24\u003c7×6;8×3=24,4×6=24,24=24，则8×3=4×6。",
+        "knowledge_points":  [
+                                 "两位数与两位数的进位加法",
+                                 "8的乘法口诀及应用",
+                                 "9的乘法口诀及应用"
+                             ],
+        "source":  "23-24二年级上·重庆璧山·期末"
+    },
+    {
+        "id":  "442",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "在括号里填上\"\u003e\"\"\u003c\"或\"=\".\n\n1米( )90厘米;7×6+6( )8×6;3厘米+4米( )7米",
+        "options":  [
+
+                    ],
+        "answer":  "\u003e;=;\u003c",
+        "solution":  "【分析】第1,3题，根据1米=100厘米统一单位再比较;第2题,7×6+6先算乘法，再算加法,8×6根据乘法口诀分别计算出两个式子的结果，再进行比较.\n【详解】1米=100厘米,100厘米\u003e90厘米，则1米\u003e90厘米;7×6+6=42+6=48,8×6=48,48=48，则7×6+6=8×6;7米=3米+4米,3厘米+4米和3米+4米中，都有4米，则比较3厘米和3米的大小即可,3厘米\u003c300厘米=3米，则3厘米+4米\u003c7米。",
+        "knowledge_points":  [
+                                 "100以内数的比大小",
+                                 "8的乘法口诀及应用",
+                                 "厘米和米之间的进率与换算",
+                                 "表内乘加，乘减"
+                             ],
+        "source":  "23-24二年级上·福建三明·期末"
+    },
+    {
+        "id":  "443",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "两个乘数都是7，积是( );4个8相加的和是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "49;32",
+        "solution":  "【分析】乘法算式为：乘数×乘数=积，由此代入计算;求几个相同加数的和，用乘法计算，用相同加数×个数或个数×相同加数。据此作答.\n【详解】7×7=49,4×8=32，两个乘数都是7，积是49;4个8相加的和是32。",
+        "knowledge_points":  [
+                                 "同数连加的应用",
+                                 "7的乘法口诀及应用",
+                                 "8的乘法口诀及应用"
+                             ],
+        "source":  "23-24二年级上·福建三明·期末"
+    },
+    {
+        "id":  "444",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "9×6=( ),读作( ),表示( )。",
+        "options":  [
+
+                    ],
+        "answer":  "54;9乘6等于54;9个6相加的和是54",
+        "solution":  "【分析】根据乘法口诀\"六九五十四\"即可求出积。读乘法算式时，依次从左往右读，\"*\"读作乘，\"=\"读作等于，数字直接读出来。9×6=54表示的是9个6相加的和是54，或者6个9相加的和是54.\n【详解】由分析可得:9×6=54，读作9乘6等于54，表示9个6相加的和是54。",
+        "knowledge_points":  [
+                                 "初步认识乘法意义",
+                                 "9的乘法口诀及应用"
+                             ],
+        "source":  "23-24二年级上·福建三明·期末"
+    },
+    {
+        "id":  "445",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "按规律填数.\n\n(1)81,72,63,( ),45.\n(2)14,21,28,( ),42。",
+        "options":  [
+
+                    ],
+        "answer":  "54;35",
+        "solution":  "【分析】观察可知:(1)此规律从左到右依次是9乘9,8,7,6,5;(2)从左到右依次是7乘2,3,4,5,6;据此解答.\n【详解】(1)9×9=81,9×8=72,9×7=63,9×6=54,9×5=45,81,72,63,54,45;(2)7×2=14,7×3=21,7×4=28,7×5=35,7×6=42,14,21,28,35,42。",
+        "knowledge_points":  [
+                                 "7的乘法口诀及应用",
+                                 "9的乘法口诀及应用",
+                                 "整数排列的规律"
+                             ],
+        "source":  "23-24二年级上·河南安阳·期末"
+    },
+    {
+        "id":  "446",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "7和6相加的和是( );两个乘数都是9，积是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "13;81",
+        "solution":  "【分析】加法算式为：加数+加数=和,7和6相加，也就是一个加数是7，另一个加数是6，代入计算即可;乘法算式为：乘数×乘数=积，两个乘数都是9，代入计算即可.\n【详解】7+6=13,9×9=81,7和6相加的和是13;两个乘数都是9，积是81。",
+        "knowledge_points":  [
+                                 "7,6加几的进位加法",
+                                 "9的乘法口诀及应用"
+                             ],
+        "source":  "23-24二年级上·重庆永川·期末"
+    },
+    {
+        "id":  "447",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "5×4+5=( )×( );9×6=( )×( )+9",
+        "options":  [
+
+                    ],
+        "answer":  "5;5;9;5",
+        "solution":  "【分析】求几个相同加数的和可以用乘法计算，写成乘法算式时用相同加数乘个数或个数乘相同加数。4个5相加再加5，即为5个5相加，也就是5乘5.9×6表示6个9的和，右侧应为5个9的和再加上9，结果是6个9的和.\n【详解】5×4+5=(5)×(5);9×6=(9)×(5)+9。",
+        "knowledge_points":  [
+                                 "5的乘法口诀及应用",
+                                 "9的乘法口诀及应用",
+                                 "表内乘加，乘减"
+                             ],
+        "source":  "23-24二年级上·云南红河·期末"
+    },
+    {
+        "id":  "448",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "2和9的和是( ),2个9的和是( ),2个9的积是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "11;18;81",
+        "solution":  "【分析】求两个数的和是多少，用加法列式计算;求几个相同加数的和是多少，可以用乘法列式计算，用加数的个数乘加数;求两个数的积是多少，用乘法列式计算.\n【详解】2+9=11,2×9=18,9×9=81，即,2和9的和是11,2个9的和是18,2个9的积是81。",
+        "knowledge_points":  [
+                                 "9加几的进位加法",
+                                 "9的乘法口诀及应用"
+                             ],
+        "source":  "23-24二年级上·云南红河·期末"
+    },
+    {
+        "id":  "449",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "在括号里填上\"\u003e\"\"\u003c\"或\"=\".\n\n6×4( )8×3;6+6( )6×6;60-23( )9×4",
+        "options":  [
+
+                    ],
+        "answer":  "=;\u003c;\u003e",
+        "solution":  "【分析】根据整数加减法的计算法则及表内乘法口诀，依次计算出各算式的结果再比较大小。比较时，位数多的数就大;位数相同比较最高位，最高位大的数就大;最高位相同比较下一位，直到比较出结果为止.\n【详解】6×4=24;8×3=24;24=24，则6×4=8×3;6+6=12;6×6=36;12\u003c36，则6+6\u003c6×6;60-23=37;9×4=36;37\u003e36，则60-23\u003e9×4。",
+        "knowledge_points":  [
+                                 "100以内数的比大小",
+                                 "两位数与两位数的退位减法",
+                                 "8的乘法口诀及应用",
+                                 "9的乘法口诀及应用"
+                             ],
+        "source":  "23-24二年级上·福建福州·期末"
+    },
+    {
+        "id":  "450",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "按规律在括号里填上合适的数.\n\n(1)7,14,( ),28,( ),42,49.\n(2)81,64,49,36,( ),( )。",
+        "options":  [
+
+                    ],
+        "answer":  "21;35;25;16",
+        "solution":  "【分析】根据题意:(1)7×1=7,7×2=14,7×3=21,7×4=28，由此规律发现，第几个数就是7乘几的积，据此规律填写;(2)9×9=81,8×8=64,7×7=49,6×6=36，由此规律发现，第几个数就是两个相同的数相乘的积，相同的数按9,8,7,6,5,4,3,2,1的顺序;据此解答.\n【详解】(1)7×1=7,7×2=14,7×3=21,7×4=28,7×5=35,7×6=42,7×7=49，所以7,14,21,28,35,42,49;(2)9×9=81,8×8=64,7×7=49,6×6=36,5×5=25,4×4=16，所以81,64,49,36,25,16。",
+        "knowledge_points":  [
+                                 "7的乘法口诀及应用",
+                                 "8的乘法口诀及应用",
+                                 "9的乘法口诀及应用",
+                                 "整数排列的规律"
+                             ],
+        "source":  "23-24二年级上·河南洛阳·期末"
+    },
+    {
+        "id":  "451",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "括号里最大能填几。\n\n7×( )\u003c38;3×( )\u003c25;45\u003e8×( );52\u003e9×( )",
+        "options":  [
+
+                    ],
+        "answer":  "5;8;5;5",
+        "solution":  "【分析】根据表内乘法口诀进行计算，然后再比较大小，填上合适的数即可.\n【详解】5×7=35,6×7=42，因为42\u003e38,35\u003c38，所以7×5\u003c38;3×8=24,3×9=27，因为24\u003c25,27\u003e25，所以3×8\u003c25;5×8=40,6×8=48，因为45\u003e40,45\u003c48，所以45\u003e8×5;5×9=45,6×9=54，因为52\u003e45,52\u003c54，所以52\u003e9×5。",
+        "knowledge_points":  [
+                                 "100以内数的比大小",
+                                 "7的乘法口诀及应用",
+                                 "8的乘法口诀及应用",
+                                 "9的乘法口诀及应用"
+                             ],
+        "source":  "2024二年级上·全国·专题练习"
+    },
+    {
+        "id":  "452",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "括号里最大能填几。\n\n9×( )\u003c72;33\u003e4×( );( )×6\u003c45",
+        "options":  [
+
+                    ],
+        "answer":  "7;8;7",
+        "solution":  "【分析】根据表内乘法口诀及100以内数的比较大小的方法来解决此题.\n【详解】7×9=63,8×9=72,63\u003c72，故9×7\u003c72，最大填7;4×8=32,4×9=36,33\u003e32，故33\u003e4×8，最大填8;6×7=42,6×8=48,42\u003c45，故7×6\u003c45，最大填7。",
+        "knowledge_points":  [
+                                 "100以内数的比大小",
+                                 "7的乘法口诀及应用",
+                                 "8的乘法口诀及应用",
+                                 "9的乘法口诀及应用"
+                             ],
+        "source":  "23-24二年级上·湖南湘西·期末"
+    },
+    {
+        "id":  "453",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "4×8=32读作( ),乘法口诀是( ),其中4和8是( ),32是( )。把这道算式改写成加法算式是( )或( )。",
+        "options":  [
+
+                    ],
+        "answer":  "4乘8等于32;四八三十二;乘数;积;4+4+4+4+4+4+4+4=32;8+8+8+8=32",
+        "solution":  "【分析】乘法算式为：乘数×乘数=积，要从左往右读，数字是几就读几，\"*\"读作乘，\"=\"读作等于;算式中两个乘数是口诀中的前两个数，积是口诀中的后一个数。乘法算式可以表示几个相同加数的和，若前一个乘数为相同加数，则后一个乘数为相同加数的个数;若前一个乘数为相同加数的个数，则后一个乘数为相同加数，由此写出加法算式.\n【详解】4×8=32读作4乘8等于32，乘法口诀是\"四八三十二\"，其中4和8是乘数,32是积。把这道算式改写成加法算式是4+4+4+4+4+4+4+4=32或8+8+8+8=32。",
+        "knowledge_points":  [
+                                 "同数连加的应用",
+                                 "初步认识乘法意义",
+                                 "8的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·广东韶关·期中"
+    },
+    {
+        "id":  "454",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "4个8相加，和是( )。两个因数都是8，积是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "32;64",
+        "solution":  "【分析】求几个相同加数的和是多少，可以用乘法列式解决;因数×因数=积;据此解决此题.\n【详解】4×8=32,8×8=64，即4个8相加，和是32;两个因数都是8，积是64。",
+        "knowledge_points":  [
+                                 "初步认识乘法意义",
+                                 "8的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·山东济南·期中"
+    },
+    {
+        "id":  "455",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "括号里最大能填几。\n\n3×( )\u003c17;4×( )\u003c25;( )×1\u003c6;6×5\u003e( )",
+        "options":  [
+
+                    ],
+        "answer":  "5;6;5;29",
+        "solution":  "【分析】乘法算式中两个乘数是口诀中的前两个数，积是口诀中的后一个数，写算式时两个乘数可互换位置。整数的大小比较：比较数的大小，先看位数的多少，位数多的数就大;位数相同，从高位开始比较，高位上的数大则这个数大，高位上的数相同，就比较下一位。根据数的大小关系和乘法口诀解答即可.\n【详解】三五十五，三六十八，最大填5,3×5\u003c17;四六二十四，四七二十八，最大填6,4×6\u003c25;一五得五，一六得六，最大填5,5×1\u003c6;6×5=30，最大填29,6×5\u003e29。",
+        "knowledge_points":  [
+                                 "100以内数的比大小",
+                                 "5的乘法口诀及应用",
+                                 "6的乘法口诀及应用",
+                                 "7的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·福建福州·期中"
+    },
+    {
+        "id":  "456",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "括号里最大能填几。\n\n( )×4\u003c25;8×( )\u003c52;27\u003e( )×5;30\u003e4×( )",
+        "options":  [
+
+                    ],
+        "answer":  "6;6;5;7",
+        "solution":  "【分析】根据表内乘法口诀及整数比较大小的方法来解决此题即可.\n【详解】6×4=24,7×4=28,24\u003c25\u003c28，故6×4\u003c25;8×6=48,8×7=56,48\u003c52\u003c56，故8×6\u003c52;5×5=25,6×5=30,30\u003e27\u003e25，故27\u003e5×5;4×7=28,4×8=32,32\u003e30\u003e28，故30\u003e4×7。",
+        "knowledge_points":  [
+                                 "100以内数的比大小",
+                                 "6的乘法口诀及应用",
+                                 "7的乘法口诀及应用",
+                                 "8的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·山东济南·期中"
+    },
+    {
+        "id":  "457",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "把口诀补充完整.\n\n三七( );四六( );二八( );五五( );二五( );四( )三十二",
+        "options":  [
+
+                    ],
+        "answer":  "二十一;二十四;十六;二十五;一十;八",
+        "solution":  "【分析】乘法算式中两个乘数是口诀中的前两个数，积是口诀中的后一个数，牢记乘法口诀并填空.\n【详解】三七二十一;四六二十四;二八十六;五五二十五;二五一十;四八三十二。",
+        "knowledge_points":  [
+                                 "5的乘法口诀及应用",
+                                 "6的乘法口诀及应用",
+                                 "7的乘法口诀及应用",
+                                 "8的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·河南商丘·期中"
+    },
+    {
+        "id":  "458",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "括号里最大能填几。\n\n4×( )\u003c22;( )×6\u003c38;12\u003e2×( );5×( )\u003c24",
+        "options":  [
+
+                    ],
+        "answer":  "5;6;5;4",
+        "solution":  "【分析】乘法算式中两个乘数是口诀中的前两个数，积是口诀中的后一个数，写算式时两个乘数可互换位置。整数的大小比较：比较数的大小，先看位数的多少，位数多的数就大;位数相同，从高位开始比较，高位上的数大则这个数大，高位上的数相同，就比较下一位。根据乘法口诀和数的大小关系即可解答.\n【详解】四五二十，四六二十四，最大填5;六六三十六，六七四十二，最大填6;二五一十，二六十二，最大填5;四五二十，五五二十五，最大填4.4×5\u003c22;6×6\u003c38;12\u003e2×5;5×4\u003c24。",
+        "knowledge_points":  [
+                                 "5的乘法口诀及应用",
+                                 "6的乘法口诀及应用",
+                                 "7的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·湖南衡阳·期中"
+    },
+    {
+        "id":  "459",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "8×5=40，乘数是( )和( ),积是( ),计算时运用的口诀是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "8;5;40;五八四十",
+        "solution":  "【分析】根据\"乘数×乘数=积\"找出各部分的数，然后运用8的乘法口诀\"五八四十\"算出结果.\n【详解】由题意分析得:8×5=40，乘数是8和5，积是40，计算时运用的口诀是\"五八四十\"。",
+        "knowledge_points":  [
+                                 "8的乘法口诀及应用"
+                             ],
+        "source":  "23-24二年级上·山东菏泽·期中"
+    },
+    {
+        "id":  "460",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "在括号里填上\"\u003e\"\"\u003c\"或\"=\".\n\n2+1( )2×1;2×8( )4×4;7元( )4元+7角;39+33+7( )78;4×8( )42;10元( )5元+5元",
+        "options":  [
+
+                    ],
+        "answer":  "\u003e;=;\u003e;\u003e;\u003c;=",
+        "solution":  "【分析】比较数的大小，先看位数的多少，位数多的数就大;如果位数相同，从最高位开始比较，最高位上的数大则这个数大，最高位上的数相同，就比较下一位，依次类推。含有算式的大小比较，可以先计算出每个算式的结果，再比较大小。单位不相同的两个数比较大小，先根据1元=10角，统一单位后再比较即可.\n【详解】2+1=3,2×1=2，所以2+1\u003e2×1;2×8=16,4×4=16，所以2×8=4×4;7元=70角,4元+7角=40角+7角=47角，所以7元\u003e4元+7角;39+33+7=72+7=79，所以39+33+7\u003e78;4×8=32，所以4×8\u003c42;5元+5元=10元，所以10元=5元+5元。",
+        "knowledge_points":  [
+                                 "100以内数的连加运算",
+                                 "4的乘法口诀及应用",
+                                 "8的乘法口诀及应用",
+                                 "元，角，分的认识及换算"
+                             ],
+        "source":  "24-25二年级上·广东梅州·期中"
+    },
+    {
+        "id":  "461",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "如果▲*○=35,○-▲=2，那么▲=( ),○=( )。",
+        "options":  [
+
+                    ],
+        "answer":  "5;7",
+        "solution":  "【分析】据题意三角形和圆形相乘等于35，根据乘法口诀我们可以知道5乘7等于35，已知圆形减三角形等于2，可以判断圆形比三角形大，所以得出圆形等于7，三角形等于5。考查学生乘法口诀的使用.\n【详解】如果▲*○=35,○-▲=2，那么▲=5,○=7。",
+        "knowledge_points":  [
+                                 "7的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·山东济宁·期中"
+    },
+    {
+        "id":  "462",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "括号里最大能填几。\n\n( )×7\u003c36;56\u003e9×( )",
+        "options":  [
+
+                    ],
+        "answer":  "5;6",
+        "solution":  "【分析】可用7的乘法口诀\"六七四十二\"以及\"五七三十五\"，分别计算出结果再比较;可用9的乘法口诀\"七九六十三\"以及\"六九五十四\"，分别计算出结果再比较;据此解答.\n【详解】6×7=42,5×7=35,35\u003c36\u003c42，则5×7\u003c36;9×7=63,9×6=54,54\u003c56\u003c63，则56\u003e9×6。",
+        "knowledge_points":  [
+                                 "7的乘法口诀及应用",
+                                 "9的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·山东济宁·期中"
+    },
+    {
+        "id":  "463",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "把口诀补充完整.\n\n三六( );七( )六十三\n( )三十二;六九( )",
+        "options":  [
+
+                    ],
+        "answer":  "十八;九;四八;五十四",
+        "solution":  "【分析】根据表内乘法口诀填写即可，注意要写汉字.\n【详解】三六十八;七九六十三;四八三十二;六九五十四。",
+        "knowledge_points":  [
+                                 "6的乘法口诀及应用",
+                                 "8的乘法口诀及应用",
+                                 "9的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·山东济宁·期中"
+    },
+    {
+        "id":  "464",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "12=○+○+○,○=( );▲*○=32,▲=( )。",
+        "options":  [
+
+                    ],
+        "answer":  "4;8",
+        "solution":  "【分析】12=○+○+○,也就是3个○的和是12，根据乘法的意义可列式为3*○=12，再结合乘法口诀\"三四十二\"可知○=4;然后把○=4代入▲*○=32中，即▲*4=32，再结合乘法口诀\"四八三十二\"可知▲=8，据此解决.\n【详解】4×3=12，则○=4;8×4=32，则▲=8，即12=○+○+○,○=4,▲*○=32,▲=8。",
+        "knowledge_points":  [
+                                 "初步认识乘法意义",
+                                 "4的乘法口诀及应用",
+                                 "8的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·北京平谷·期中"
+    },
+    {
+        "id":  "465",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "5×9=5×8+( );4×6=4×7-( )",
+        "options":  [
+
+                    ],
+        "answer":  "5;4",
+        "solution":  "【分析】求几个相同加数的和可以用乘法计算，写成乘法算式时用相同加数×个数或个数×相同加数。第1题:5×9表示9个5的和，右侧应为8个5的和再加上1个5，结果是9个5的和;第2题:4×6表示6个4的和，右侧应为7个4的和再减去1个4，结果是6个4的和.\n【详解】由分析填写如下:5×9=5×8+5;4×6=4×7-4。",
+        "knowledge_points":  [
+                                 "初步认识乘法意义",
+                                 "6的乘法口诀及应用",
+                                 "9的乘法口诀及应用",
+                                 "表内乘加，乘减"
+                             ],
+        "source":  "24-25二年级上·北京平谷·期中"
+    },
+    {
+        "id":  "466",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "括号里面最大能填几。\n\n( )×4\u003c39;25\u003e( )×7;8×( )\u003c35",
+        "options":  [
+
+                    ],
+        "answer":  "9;3;4",
+        "solution":  "【分析】根据乘法口诀及整数比较大小的方法解答即可;根据乘法口诀计算结果，乘法算式中两个乘数(可交换位置)是口诀中的前两个数，积是口诀中的后一个数;比较数的大小，先看位数的多少，位数多的数就大;如果位数相同，从最高位开始比较，高位上的数大则这个数大，最高位上的数相同，就比较下一位，依次类推.\n【详解】9×4=36，所以9×4\u003c39，括号里最大能填9;3×7=21,4×7=28，所以25\u003e3×7，括号里最大能填3;8×4=32,8×5=40，所以8×4\u003c35，括号里最大能填4。",
+        "knowledge_points":  [
+                                 "100以内数的比大小",
+                                 "7的乘法口诀及应用",
+                                 "8的乘法口诀及应用",
+                                 "9的乘法口诀及应用"
+                             ],
+        "source":  "23-24二年级上·广东韶关·期中"
+    },
+    {
+        "id":  "467",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "在8×7=56中,8和7都是乘数,56是积。( )",
+        "options":  [
+
+                    ],
+        "answer":  "√",
+        "solution":  "【分析】乘数×乘数=积，乘法算式中两个乘数是口诀中的前两个数，积是口诀中的后一个数，写算式时两个乘数可互换位置.\n【详解】在8×7=56中,8和7都是乘数,56是积。原题说法正确。故答案为:√",
+        "knowledge_points":  [
+                                 "8的乘法口诀及应用"
+                             ],
+        "source":  "23-24二年级上·河南郑州·期末"
+    },
+    {
+        "id":  "468",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "9个6相加，和是15。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】求几个相同加数的和是多少，可以用乘法列式计算;先算出结果，再判断对错.\n【详解】由题意分析得:9×6=54，即9个6相加，和是54。原题说法错误。故答案为: ×",
+        "knowledge_points":  [
+                                 "初步认识乘法意义",
+                                 "9的乘法口诀及应用"
+                             ],
+        "source":  "23-24二年级上·甘肃天水·期末"
+    },
+    {
+        "id":  "469",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "计算题",
+        "difficulty":  0.85,
+        "question":  "口算题.\n\n45+23=( );78-46=( );2×9=( );37-19=( );5×4=( );3×8=( );7×3=( );6×2=( );2×6+5=( );10-2×4=( );28+(20-13)=( )。",
+        "options":  [
+
+                    ],
+        "answer":  "68;32;18;18;20;24;21;12;17;2;35",
+        "solution":  "【分析】本题包含两位数加减法，乘法口诀，乘加乘减以及带括号的混合运算。计算加减法时要注意进位和退位;乘法直接应用口诀;乘加乘减算式要先算乘法再算加减法;有括号的算式要先算括号里面的.\n【详解】45+23=68(个位5+3=8，十位4+2=6，不进位);78-46=32(个位8-6=2，十位7-4=3，不退位);2×9=18(口诀\"二九十八\");37-19=18(个位7减9不够，向十位借1,17-9=8，十位3借1剩2,2-1=1，得18);5×4=20(口诀\"四五二十\");3×8=24(口诀\"三八二十四\");7×3=21(口诀\"三七二十一\");6×2=12(口诀\"二六十二\");2×6+5=12+5=17(先算乘法2×6=12，再算加法12+5=17);10-2×4=10-8=2(先算乘法2×4=8，再算减法10-8=2);28+(20-13)=28+7=35(先算括号内20-13=7，再算加法28+7=35)。",
+        "knowledge_points":  [
+                                 "两位数与两位数的退位减法",
+                                 "9的乘法口诀及应用",
+                                 "乘加，乘减混合运算",
+                                 "带有小括号的混合运算"
+                             ],
+        "source":  "23-24二年级上·河南郑州·期末"
+    },
+    {
+        "id":  "470",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "计算题",
+        "difficulty":  0.85,
+        "question":  "直接写得数.\n\n7×9=( );45-40=( );9-6=( );4×6=( );5×7+20=( );38+21=( );5+8=( );9×6-38=( );30+5×4=( );9×9-9=( )。",
+        "options":  [
+
+                    ],
+        "answer":  "63;5;3;24;55;59;13;16;50;72",
+        "solution":  "【分析】本题包含乘法口诀，两位数加减整十数，两位数加两位数(不进位),20以内加减法以及乘加乘减混合运算。计算时，乘法直接应用口诀;加减法要注意相同数位对齐;乘加乘减算式要先算乘法，再算加减法.\n【详解】7×9=63(口诀\"七九六十三\");45-40=5(个位5-0=5，十位4-4=0，得5);9-6=3(9减6等于3);4×6=24(口诀\"四六二十四\");5×7+20=35+20=55(先算乘法5×7=35，再算加法35+20=55);38+21=59(个位8+1=9，十位3+2=5，不进位);5+8=13(5加8等于13);9×6-38=54-38=16(先算乘法9×6=54，再算减法54-38=16);30+5×4=30+20=50(先算乘法5×4=20，再算加法30+20=50);9×9-9=81-9=72(先算乘法9×9=81，再算减法81-9=72)。",
+        "knowledge_points":  [
+                                 "两位数与整十数的减法",
+                                 "两位数与两位数的不进位加法",
+                                 "9的乘法口诀及应用",
+                                 "表内乘加，乘减"
+                             ],
+        "source":  "24-25二年级上·西藏那曲·期末"
+    },
+    {
+        "id":  "471",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "看图列式计算.\n\n![](images/f645c76f156835dbfac57b6565a740f4102971a59fa7251e5d86c3d53fdfd509.jpg)\n\n□ ○ □ ○ □ = □(元)",
+        "options":  [
+
+                    ],
+        "answer":  "4×9+52=88",
+        "solution":  "【分析】根据题意，有4个足球，每个足球9元，先求出足球共多少钱，用足球的钱加上书包钱，即可求出足球和书包一共多少钱，据此列式计算.\n【详解】4×9+52=36+52=88(元),足球和书包一共88元。",
+        "knowledge_points":  [
+                                 "表内乘加，乘减"
+                             ],
+        "source":  "23-24二年级下·四川乐山·期中"
+    },
+    {
+        "id":  "472",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "计算题",
+        "difficulty":  0.85,
+        "question":  "直接写出得数.\n\n2×5=( );3×6=( );4×5=( );1×2=( );5×8=( );2×8=( );3×9=( );4×8=( )。",
+        "options":  [
+
+                    ],
+        "answer":  "10;18;20;2;40;16;27;32",
+        "solution":  "【分析】本题主要考查乘法口诀的直接应用。根据乘法口诀，直接计算出各算式的结果即可.\n【详解】2×5=10(口诀\"二五一十\");3×6=18(口诀\"三六十八\");4×5=20(口诀\"四五二十\");1×2=2(口诀\"一二得二\");5×8=40(口诀\"五八四十\");2×8=16(口诀\"二八十六\");3×9=27(口诀\"三九二十七\");4×8=32(口诀\"四八三十二\")。",
+        "knowledge_points":  [
+                                 "5的乘法口诀及应用",
+                                 "6的乘法口诀及应用",
+                                 "8的乘法口诀及应用",
+                                 "9的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·广东梅州·期中"
+    },
+    {
+        "id":  "473",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "计算题",
+        "difficulty":  0.85,
+        "question":  "直接写出得数.\n\n18+6=( );44-8=( );5×5=( );25-8=( );7×2=( );5×9=( );5×7=( );71-50=( )。",
+        "options":  [
+
+                    ],
+        "answer":  "24;36;25;17;14;45;35;21",
+        "solution":  "【分析】本题包含一位数与两位数的加减法以及乘法口诀的应用。计算加减法时要注意进位和退位;乘法直接应用对应的口诀得出结果.\n【详解】18+6=24(个位8+6=14，向十位进1，十位1+1=2，得24);44-8=36(个位4减8不够，向十位借1,14-8=6，十位剩3，得36);5×5=25(口诀\"五五二十五\");25-8=17(个位5减8不够，向十位借1,15-8=7，十位剩1，得17);7×2=14(口诀\"二七十四\");5×9=45(口诀\"五九四十五\");5×7=35(口诀\"五七三十五\");71-50=21(个位1-0=1，十位7-5=2，不退位)。",
+        "knowledge_points":  [
+                                 "一位数与两位数的进位加法",
+                                 "一位数与两位数的退位减法",
+                                 "7的乘法口诀及应用",
+                                 "9的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·广东韶关·期中"
+    },
+    {
+        "id":  "474",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "看图列算式.\n\n![](images/7187253e2b7ae6f9b853d216018cdf61cf65f2daa5931d64d38dad85ff131515.jpg)\n\n□ ○ □ ○ □ = □(元)",
+        "options":  [
+
+                    ],
+        "answer":  "9×3+38=65",
+        "solution":  "【分析】题中一个书包38元，每支钢笔9元，有3支，求书包和钢笔一共多少元，可以先用每支钢笔的价格和数量相乘，求出3支钢笔一共多少元，再和书包的价格相加，就是总钱数.\n【详解】9×3+38=27+38=65(元),书包和钢笔一共65元。",
+        "knowledge_points":  [
+                                 "图文问题",
+                                 "表内乘加，乘减"
+                             ],
+        "source":  "23-24二年级上·湖南湘西·期末"
+    },
+    {
+        "id":  "475",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "计算题",
+        "difficulty":  0.85,
+        "question":  "直接写出得数.\n\n2×9=( );9×5=( );3×6=( );53+22=( );3×7=( );8+2=( );4×9=( );7×4=( )。",
+        "options":  [
+
+                    ],
+        "answer":  "18;45;18;75;21;10;36;28",
+        "solution":  "【分析】本题包含乘法口诀,10以内加法以及两位数加两位数(不进位)。计算时，乘法直接应用对应的口诀;加法要注意相同数位对齐，不需要进位时直接相加.\n【详解】2×9=18(口诀\"二九十八\");9×5=45(口诀\"五九四十五\");3×6=18(口诀\"三六十八\");53+22=75(个位3+2=5，十位5+2=7，不进位);3×7=21(口诀\"三七二十一\");8+2=10(8加2等于10);4×9=36(口诀\"四九三十六\");7×4=28(口诀\"四七二十八\")。",
+        "knowledge_points":  [
+                                 "10的加减法",
+                                 "两位数与两位数的不进位加法",
+                                 "6的乘法口诀及应用",
+                                 "9的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·广东梅州·期中"
+    },
+    {
+        "id":  "476",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "赵晶逛国光超市.\n\n![](images/ab9c97934ca25e17c6328b445835f092579e20e2f7d8d572f8b25213a8c9ec61.jpg)\n巧克力\n![](images/4da99747fadea9708e7e10157f7a4b4b8ba67d839bb1e85553094315804c11a1.jpg)\n饼干3元\n![](images/f4c27dfa8f4a41017392917fd2c72e54849faca5551202f4bfb2e55ec7eae5dd.jpg)\n可乐\n\n(1)一盒巧克力的价钱和9袋饼干的价钱相同，一盒巧克力多少元钱。\n(2)一瓶可乐的价钱比一盒巧克力便宜20元，一瓶可乐多少元钱。\n(3)你能提出一个问题并解决吗。",
+        "options":  [
+
+                    ],
+        "answer":  "27元;7元;示例：买一盒巧克力和一瓶可乐一共多少钱。34元(答案不唯一)",
+        "solution":  "【分析】(1)根据乘法的意义，用3×9或9×3先算出9袋饼干需要多少钱，据此即可得出一盒巧克力的价钱。(2)已知一瓶可乐的价钱比一盒巧克力便宜20元，根据减法的意义，用一盒巧克力的价钱减去20元，即可得出答案。(3)根据学过的数学知识，结合题干信息，提出问题并解答即可，本小题答案不唯一，例如：买一盒巧克力和一瓶可乐一共多少钱。用加法计算即可.\n【详解】(1)3×9=27(元),答：一盒巧克力27元钱。(2)27-20=7(元),答：一瓶可乐7元钱。(3)买一盒巧克力和一瓶可乐一共多少钱。27+7=34(元),答：买一盒巧克力和一瓶可乐一共34元钱。(答案不唯一)。",
+        "knowledge_points":  [
+                                 "\"提问题\"\"填条件\"问题",
+                                 "两位数与整十数的减法",
+                                 "一位数与两位数的进位加法",
+                                 "9的乘法口诀及应用"
+                             ],
+        "source":  "23-24二年级上·江西赣州·期末"
+    },
+    {
+        "id":  "477",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "小明和爸爸妈妈去游乐园玩，买门票一共要花多少钱。\n\n![](images/2026-02-27%20102258.jpg)",
+        "options":  [
+
+                    ],
+        "answer":  "20元",
+        "solution":  "【分析】爸爸妈妈买门票各需要8元，小明买门票需要4元，则先用乘法求出2个8是多少，然后加上4，求出和，即可解决.\n【详解】8×2+4=16+4=20(元),答：买门票一共要花20元。",
+        "knowledge_points":  [
+                                 "表内乘加，乘减"
+                             ],
+        "source":  "23-24二年级上·山东菏泽·期末"
+    },
+    {
+        "id":  "478",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "一支铅笔2元，一个文具盒9元，一块橡皮3元.\n①买一支铅笔和一块橡皮要花多少钱。\n②买8块橡皮和1个文具盒一共要花多少钱。",
+        "options":  [
+
+                    ],
+        "answer":  "5元;33元",
+        "solution":  "【分析】第一道题涉及加法的数学概念，把两个数合并成一个数的运算。用一支铅笔的钱加上一块橡皮的钱，可以算出一共花了多少钱;第二道题是乘加应用题，首先算出8块橡皮的总价，再加上1个文具盒的钱，即可解答.\n【详解】(1)2+3=5(元),答：买一支铅笔和一块橡皮要花5元。(2)8块橡皮用的钱:3×8=24(元),一共花的钱:24+9=33(元),答：买8块橡皮和1个文具盒一共要花33元。",
+        "knowledge_points":  [
+                                 "经济问题",
+                                 "5以内数的加法",
+                                 "乘加，乘减混合运算"
+                             ],
+        "source":  "23-24二年级上·甘肃天水·期末"
+    },
+    {
+        "id":  "479",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "王伯伯种了5行杨梅树和4行枇杷树，每行种8棵，两种果树共种了多少行。枇杷树种了多少棵。",
+        "options":  [
+
+                    ],
+        "answer":  "9行;32棵",
+        "solution":  "【分析】本题涉及到加法和乘法的基本运算概念。对于求两种果树共种的行数，只需将杨梅树的行数和枇杷树的行数相加;求枇杷树的棵数，根据乘法的意义，用枇杷树的行数乘以每行的棵数即可.\n【详解】两种果树的行数:5+4=9(行);枇杷树的棵数:4×8=32(棵),答：两种果树共种了9行，枇杷树种了32棵。",
+        "knowledge_points":  [
+                                 "8,9的加减法",
+                                 "8的乘法口诀及应用"
+                             ],
+        "source":  "23-24二年级上·浙江台州·期末"
+    },
+    {
+        "id":  "480",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "一辆![](images/f9e940e04c959e3f8dfd95f8960250bf60fa3463478f83424b7ea5fa3855b56b.jpg)价是9元，一个![](images/2b8aa6f3647f567ad5a06392c1f16d73242aa9b52790eb87847bf91e106acab8.jpg)单价是5元。买7辆小汽车和一个玩具熊，需要多少钱。",
+        "options":  [
+
+                    ],
+        "answer":  "68元",
+        "solution":  "【分析】根据题意，先用每辆小汽车的价格和买的数量相乘，求出7辆小汽车的钱数，再和一个玩具熊的价格相加，就是买7辆小汽车和一个玩具熊一共需要的钱数.\n【详解】9×7+5=63+5=68(元),答：需要68元钱。",
+        "knowledge_points":  [
+                                 "表内乘加，乘减"
+                             ],
+        "source":  "24-25二年级上·西藏那曲·期末"
+    },
+    {
+        "id":  "481",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "有10名同学站队，每两名同学之间的距离是3米，这支队伍长多少米。",
+        "options":  [
+
+                    ],
+        "answer":  "27米",
+        "solution":  "【分析】根据题意，每两名同学之间的距离是3米，则2名同学有1个间隔,3名同学有2个间隔。10名同学的间隔数量用10减1计算，再用每个间隔的长度和间隔的数量相乘，就是队伍的总长度.\n【详解】10-1=9(个),3×9=27(米)。答：这支队伍长27米。",
+        "knowledge_points":  [
+                                 "9的乘法口诀及应用"
+                             ],
+        "source":  "23-24二年级上·江西抚州·期末"
+    },
+    {
+        "id":  "482",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "买水果.\n\n![](images/8d9e57b82a4a8feae1d127604b2145fdc9dd0ca9e2c194d627f1be9bcff6853a.jpg)\n8元/千克\n![](images/c650b03fff62b74cf862801fe86b8cbba0e0ab2e051ee044de98efa6c089ec38.jpg)\n6元/千克\n![](images/fe9827381fc71e4f4f6ce2b3a435a30023208243c1e4e7fe86b8132a60ca6ca8.jpg)\n9元/千克\n\n(1)买3千克橘子和1千克草莓，一共要花多少元。\n(2)买5千克苹果和1千克草莓,50元够吗。",
+        "options":  [
+
+                    ],
+        "answer":  "27元;够",
+        "solution":  "【分析】(1)根据题意，先用每千克橘子的钱数和千克数相乘，求出3千克橘子的价钱，再和1千克草莓的价钱相加，就是一共要花的钱数;(2)先用每千克苹果的钱数和千克数相乘，求出5千克苹果的价钱，再和1千克草莓的价钱相加，求出一共需要多少钱，再和50元比较大小，需要的钱数大于50元不够，小于或等于50元够.\n【详解】(1)6×3+9=18+9=27(元),答：一共要花27元。(2)8×5+9=40+9=49(元),49\u003c50，答:50元够。",
+        "knowledge_points":  [
+                                 "图文问题",
+                                 "100以内数的比大小",
+                                 "表内乘加，乘减"
+                             ],
+        "source":  "23-24二年级上·河南南阳·期末"
+    },
+    {
+        "id":  "483",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "每辆小客车最多可以载乘8名乘客,6辆这样的车可以坐下二(1)班全班的同学吗。\n\n![](images/4651cd20c1023c0021ba2e8aebf41cccba4f25d938c4fd0250a89ba129633ef0.jpg)",
+        "options":  [
+
+                    ],
+        "answer":  "可以",
+        "solution":  "【分析】已知每辆小客车最多可以载乘8名乘客，有6辆这样的车，用每辆车的载乘人数乘车辆的总数即可得出6辆车共可以坐多少人，再与二(1)班人数比较即可.\n【详解】8×6=48(人),48\u003e45，一共可以坐48人，二(1)班一共有45人，所以可以坐下。答:6辆这样的车可以坐下二(1)班全班同学。",
+        "knowledge_points":  [
+                                 "100以内数的比大小",
+                                 "8的乘法口诀及应用"
+                             ],
+        "source":  "23-24二年级上·河南南阳·期末"
+    },
+    {
+        "id":  "484",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "购物.\n\n![](images/807fc61ef8d8a43f6e156bcb829d9c614616543f64cd84933db6db9ab2226daf.jpg)\n![](images/db8e3df8f0c9f88322082f1580b1349053182cd04af57bc25c468e0a4593fd51.jpg)\n![](images/844ff09359239c80fc871568c4465ac8f8d4d12a2ca40f95557aff6ca62d00bb.jpg)\n\n(1)一个地球仪比一副三角尺贵45元，一个地球仪多少元。\n(2)丽丽和她的三位朋友，每人都买了6副三角尺，她们一共买了多少副三角尺。\n(3)小红买4块橡皮，准备3元够不够。",
+        "options":  [
+
+                    ],
+        "answer":  "47元;24副;不够",
+        "solution":  "【分析】根据题意,(1)求比一个数多几的数是多少，用加法列式计算。用一副三角尺的价格加上45，即可求出一个地球仪多少元;(2)丽丽和她的三位朋友，一共有4人，每人都买了6副三角尺，求她们一共买了多少副三角尺，就是求4个6的和是多少，可以用乘法列式计算;(3)先求出买4块橡皮多少元，再与3元比较大小，据此解答.\n【详解】(1)2+45=47(元),答：一个地球仪47元。(2)6×4=24(副),答：她们一共买了24副三角尺。(3)4×8=32(角),32角=3元2角,3元\u003c3元2角，答：小红买4块橡皮，准备3元不够。",
+        "knowledge_points":  [
+                                 "两位数与一位数的加法(不进位)",
+                                 "6的乘法口诀及应用",
+                                 "8的乘法口诀及应用",
+                                 "元，角，分的认识及换算"
+                             ],
+        "source":  "23-24二年级上·河南洛阳·期末"
+    },
+    {
+        "id":  "485",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "小红过生日，共有35个人参加。餐厅准备了3张8人座的桌子和1张6人座的桌子。餐厅的椅子够不够。",
+        "options":  [
+
+                    ],
+        "answer":  "不够",
+        "solution":  "【分析】根据题意，几人座也就是有几把椅子。先用每张桌子坐的人数8人和张数3张相乘，求出3张8人座的桌子可以坐多少人，再加上6人，就是3张8人座的桌子和1张6人座的桌子一共可以坐的人数，再和35比较大小，可以坐的人数大于或等于35够，小于35不够.\n【详解】8×3+6=24+6=30(人),30\u003c35，答：餐厅的椅子不够。",
+        "knowledge_points":  [
+                                 "100以内数的比大小",
+                                 "表内乘加，乘减"
+                             ],
+        "source":  "23-24二年级上·四川德阳·期末"
+    },
+    {
+        "id":  "486",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "如图所示:\n\n![](images/4b7fb0ad89018d2ea15355078540b71f1889aebae9860323d8b68cc6058e3543.jpg)\n50元\n![](images/24b6516ec3df4a1cec3752ff5157ff4154df561a7d748978fdad769ebdae2eb2.jpg)\n32元\n![](images/a78ad9df54ae492245499ec82c3f6af56559af2b238491a08fc39c4eff1d4cf3.jpg)\n9元\n![](images/71fd748e22f0de50514147a588de18efa9b8ef0760316c345126e7699846766c.jpg)\n8元\n\n(1)张老师买了8个铅笔盒，一共花了多少钱。\n(2)王校长买4支钢笔和1件衣服，一共要花多少钱。\n(3)你还能提出什么数学问题，并解答。",
+        "options":  [
+
+                    ],
+        "answer":  "72元;82元;示例：买一件上衣和一部电话一共需要多少钱。82元",
+        "solution":  "【分析】(1)根据题意可知：用铅笔盒的单价乘买的数量即可求出一共花的钱数。(2)先求出4支钢笔的钱数，用钢笔的单价乘买的数量，再加上衣服的钱数即可求出买4支钢笔和1件衣服，一共要花的钱数。(3)根据题意，提出问题合理即可，例如：买一件上衣和一部电话一共需要多少钱。用上衣的价格加电话的价格即可.\n【详解】(1)9×8=72(元),答：一共花了72元钱。(2)8×4=32(元),32+50=82(元),答：一共要花82元钱。(3)买一件上衣和一部电话一共需要多少钱。50+32=82(元),答：买一件上衣和一部电话一共需要82元钱。(答案不唯一)。",
+        "knowledge_points":  [
+                                 "\"提问题\"\"填条件\"问题",
+                                 "8的乘法口诀及应用",
+                                 "9的乘法口诀及应用"
+                             ],
+        "source":  "23-24二年级上·浙江绍兴·期末"
+    },
+    {
+        "id":  "487",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "停车场上停着5排小汽车，每排8辆，大客车比小汽车多34辆。停车场上停有多少辆大客车。",
+        "options":  [
+
+                    ],
+        "answer":  "74辆",
+        "solution":  "【分析】根据题意可知：先求出小汽车的数量，用停的排数乘每排的数量即可，然后再根据求比一个数多几的数，用加法计算，用小汽车的数量加上大客车比小汽车多的数量即可求出大客车的数量.\n【详解】5×8+34=40+34=74(辆),答：停车场上停有74辆大客车。",
+        "knowledge_points":  [
+                                 "8的乘法口诀及应用",
+                                 "表内乘加，乘减"
+                             ],
+        "source":  "23-24二年级上·河南南阳·期末"
+    },
+    {
+        "id":  "488",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "一个文具盒9元，买3个送1个，李老师想买8个，要付多少钱。",
+        "options":  [
+
+                    ],
+        "answer":  "54元",
+        "solution":  "【分析】根据题意可知：文具盒买3个送1个，则付3个的钱可以得到3+1=4个，因为李老师想买8个，即8=4+4，即要买2组3个文具盒，所以李老师想买8个文具盒需要付3×2=6个的钱，则用付的个数乘文具盒的单价即可求出要付的钱数.\n【详解】3+1=4(个),8=4+4,3×2=6(个),6×9=54(元),答：要付54元钱。",
+        "knowledge_points":  [
+                                 "3的乘法口诀及应用",
+                                 "9的乘法口诀及应用"
+                             ],
+        "source":  "23-24二年级上·浙江温州·期末"
+    },
+    {
+        "id":  "489",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "丁丁家一共养了8只兔子，每天给每只兔子吃了9个胡萝卜，每天8只兔子要吃几个胡萝卜。",
+        "options":  [
+
+                    ],
+        "answer":  "72个",
+        "solution":  "【分析】根据题意可知：用兔子的数量乘每只兔子吃的数量即可求出8只兔子要共吃多少，据此解答.\n【详解】8×9=72(个),答：每天8只兔子要吃72个胡萝卜。",
+        "knowledge_points":  [
+                                 "9的乘法口诀及应用"
+                             ],
+        "source":  "23-24二年级上·云南红河·期末"
+    },
+    {
+        "id":  "490",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "二年级同学在操场站队做操，站成了5排，每排8人，二年级一共有多少人。",
+        "options":  [
+
+                    ],
+        "answer":  "40人",
+        "solution":  "【分析】求一共有多少人，也就是求5个8的和是多少，用乘法计算，每排的人数和排数相乘，就是总人数.\n【详解】8×5=40(人),答：二年级一共有40人。",
+        "knowledge_points":  [
+                                 "8的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·河南商丘·期中"
+    },
+    {
+        "id":  "491",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "小美和她的8个好朋友每人订了一份《小学生优秀作文周刊》,每份7元。她们一共花了多少元。",
+        "options":  [
+
+                    ],
+        "answer":  "63元",
+        "solution":  "【分析】根据题意，先用加法计算出一共有几人，也就是共订了几份，用每份的钱数和份数相乘，就是花的总钱数.\n【详解】1+8=9(份),7×9=63(元),答：她们一共花了63元。",
+        "knowledge_points":  [
+                                 "9的乘法口诀及应用"
+                             ],
+        "source":  "23-24二年级上·河南南阳·期末"
+    },
+    {
+        "id":  "492",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "有5名男生和3名女生在一起玩拼七巧板游戏，每个人拼了4种图案，一共拼了多少种图案。",
+        "options":  [
+
+                    ],
+        "answer":  "32种",
+        "solution":  "【分析】根据题意，先用加法计算出一共有多少人，再用每人拼的种类和人数相乘，就是一共拼的种类.\n【详解】5+3=8(人),4×8=32(种),答：一共拼了32种图案。",
+        "knowledge_points":  [
+                                 "8的乘法口诀及应用",
+                                 "用七巧板拼图形"
+                             ],
+        "source":  "23-24二年级上·重庆永川·期末"
+    },
+    {
+        "id":  "493",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "一套童话书共有8本，每本9元，买一套需要多少元。",
+        "options":  [
+
+                    ],
+        "answer":  "72元",
+        "solution":  "【分析】已知一套童话书共有8本，每本9元，用每本的钱数乘总本数即可得出一套需要多少钱。考查学生9的乘法口诀的运用.\n【详解】8×9=72(元),答：买一套需要72元。",
+        "knowledge_points":  [
+                                 "9的乘法口诀及应用"
+                             ],
+        "source":  "23-24二年级上·重庆璧山·期末"
+    },
+    {
+        "id":  "494",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "学校买了一些鲜花，在国旗台前摆了3行，每行9盆，还剩6盆没摆完。一共买了多少盆鲜花。",
+        "options":  [
+
+                    ],
+        "answer":  "33盆",
+        "solution":  "【分析】根据乘法的意义，用3×9或9×3先算出3行一共有多少盆，再加上剩下的6盆，即可得出一共买了多少盆鲜花.\n【详解】3×9+6=27+6=33(盆),答：一共买了33盆鲜花。",
+        "knowledge_points":  [
+                                 "表内乘加，乘减"
+                             ],
+        "source":  "24-25二年级上·河南商丘·期中"
+    },
+    {
+        "id":  "495",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "张大伯种了8行青椒，每行有8棵。一共种了多少棵青椒。",
+        "options":  [
+
+                    ],
+        "answer":  "64棵",
+        "solution":  "【分析】根据题意，用种青椒每行的棵数乘行数，即可求出种的青椒的总棵数，据此解答.\n【详解】8×8=64(棵),答：一共种了64棵青椒。",
+        "knowledge_points":  [
+                                 "8的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·河南周口·期中"
+    },
+    {
+        "id":  "496",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "举办活动的办公楼共有3层，每层8间教室，一共有多少间教室。",
+        "options":  [
+
+                    ],
+        "answer":  "24间",
+        "solution":  "【分析】求一共有多少间教室，也就是求3个8的和是多少，用乘法计算，每层教室的数量和层数相乘，就是教室的总数量.\n【详解】8×3=24(间),答：一共有24间教室。",
+        "knowledge_points":  [
+                                 "8的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·河南周口·期中"
+    },
+    {
+        "id":  "497",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "小红的爸爸妈妈把他们的工资存放在某支付平台里，如果每天可收益8元，一个星期可以收益多少钱。",
+        "options":  [
+
+                    ],
+        "answer":  "56元",
+        "solution":  "【分析】用每天收益的钱数乘一星期的天数(7天),即可求出一个星期总共收益的钱数.\n【详解】8×7=56(元),答：一个星期可以收益56元钱。",
+        "knowledge_points":  [
+                                 "8的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级上·江苏·单元测试"
+    },
+    {
+        "id":  "498",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "如图所示:\n\n![](images/2026-02-27%20104213.jpg)\n\n(1)叶梓买了最贵的两样，付了100元，应找回多少钱。\n(2)买7本笔记本和6支笔一共需要多少钱。",
+        "options":  [
+
+                    ],
+        "answer":  "27元;53元",
+        "solution":  "【分析】(1)叶梓买了最贵的两样，将这些价格进行比较选择最大的两个即最贵的，把这两种物品的价钱相加，求出一共花的钱数，再用付了的100元减去一共花的钱数，即可求出应找回多少钱。(2)先求出买7本笔记本的价钱，用一本笔记本的价钱乘买的数量，求出6支笔的价钱，用一支笔的价钱乘买的数量，然后相加即可求出一共需要多少钱.\n【详解】(1)46\u003e27\u003e21\u003e5\u003e3,27+46=73(元),100-73=27(元),答：应找回27元。(2)7×5=35(元),6×3=18(元),35+18=53(元),答：买7本笔记本和6支笔一共需要53元。",
+        "knowledge_points":  [
+                                 "两位数与两位数的进位加法",
+                                 "6的乘法口诀及应用",
+                                 "7的乘法口诀及应用"
+                             ],
+        "source":  "23-24二年级上·河南驻马店·期中"
+    },
+    {
+        "id":  "499",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "二年级有8个班，每班有3名女学生参加画画班，二年级一共有多少人参加画画班。后来画画班又增加了25名男生，现在画画班有多少人。",
+        "options":  [
+
+                    ],
+        "answer":  "24人;49人",
+        "solution":  "【分析】用班级数乘每班参加画画班的人数即可求出二年级一共有多少人参加画画班。用二年级参加画画班的人数加上后面增加的人数即可求出现在画画班有多少人.\n【详解】8×3=24(人),24+25=49(人),答：二年级一共有24人参加画画班;现在画画班有49人。",
+        "knowledge_points":  [
+                                 "两位数与两位数的不进位加法",
+                                 "8的乘法口诀及应用"
+                             ],
+        "source":  "23-24二年级上·广东韶关·期中"
+    },
+    {
+        "id":  "500",
+        "unit":  "第六单元表内乘法（二）",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "琦琦看一本故事书，每天看7页，已经看了9天，还剩8页没看。这本故事书一共有多少页。",
+        "options":  [
+
+                    ],
+        "answer":  "71页",
+        "solution":  "【分析】先根据乘法的意义，用每天看的页数*9求出已经看了的页数，再根据加法的意义，用前面求出的积加上没看的8页即可求出这本故事书的总页数，据此解答即可.\n【详解】7×9+8=63+8=71(页),答：这本故事书一共有71页。",
+        "knowledge_points":  [
+                                 "9的乘法口诀及应用",
+                                 "表内乘加，乘减"
+                             ],
+        "source":  "23-24二年级上·河南周口·期中"
+    }
+]
\ No newline at end of file
diff --git "a/\344\272\214\345\271\264\347\272\247\351\242\230\351\233\206/\344\272\214\345\271\264\347\272\247\344\270\212/\344\272\214\345\271\264\347\272\247\344\270\212\347\254\254\345\233\233\345\215\225\345\205\203\350\241\250\345\206\205\344\271\230\346\263\225.json" "b/\344\272\214\345\271\264\347\272\247\351\242\230\351\233\206/\344\272\214\345\271\264\347\272\247\344\270\212/\344\272\214\345\271\264\347\272\247\344\270\212\347\254\254\345\233\233\345\215\225\345\205\203\350\241\250\345\206\205\344\271\230\346\263\225.json"
new file mode 100644
index 0000000000000000000000000000000000000000..12742b756a6adc7e8d66d921c959330f74c52f80
--- /dev/null
+++ "b/\344\272\214\345\271\264\347\272\247\351\242\230\351\233\206/\344\272\214\345\271\264\347\272\247\344\270\212/\344\272\214\345\271\264\347\272\247\344\270\212\347\254\254\345\233\233\345\215\225\345\205\203\350\241\250\345\206\205\344\271\230\346\263\225.json"
@@ -0,0 +1,8095 @@
+[
+  {
+    "id": "1",
+    "unit": "第四单元 表内乘法",
+    "question_type": "填空题",
+    "difficulty": 0.94,
+    "question": "一本书每天看 5 页，已经看了 4 天。根据这两个条件可以知道( )。",
+    "options": [
+      "A. 还剩多少页没看",
+      "B. 已经看了多少页",
+      "C. 这本书一共有多少页"
+    ],
+    "answer": "B",
+    "solution": "【分析】由题意分析可得，每天看的页数×看的天数=看的页数，据此解答即可.\n【详解】每天看 5 页，看了 4 天，可以求出已经看了几页。5×4 = 20(页)。故答案为:B",
+    "knowledge_points": [
+      "5的乘法口诀及应用"
+    ],
+    "source": "2025 二年级上·全国·专题练习"
+  },
+  {
+    "id": "2",
+    "unit": "第四单元 表内乘法",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "妈妈和 4 位朋友一起吃饭，每一位一双筷子，需要( )根筷子。",
+    "options": [
+      "A. 5 根",
+      "B. 4 根",
+      "C. 10 根"
+    ],
+    "answer": "C",
+    "solution": "【分析】由题意可知：妈妈和4位朋友，一共是5个人，一双筷子是2根,5人需要5个2根，即5乘2，求出的积是需要筷子的根数。据此解答.\n【详解】由分析可得:5×2 = 10 (根),需要10根筷子。故答案为:C",
+    "knowledge_points": [
+      "5的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级下·甘肃天水·期末"
+  },
+  {
+    "id": "3",
+    "unit": "第四单元 表内乘法",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "工人师傅要把一根10米长的木头锯成5段，锯一次需要4分钟，锯完这根木头需要( )分钟。",
+    "options": [
+      "A. 16",
+      "B. 20",
+      "C. 30"
+    ],
+    "answer": "A",
+    "solution": "【分析】一根木头锯成5段，需要锯4次，每锯断一次需要4 分钟，根据乘法的意义，用 4×4 即可解答.\n【详解】5 - 1 = 4(次),4×4 = 16(分钟),所以锯完这根木头需要16分钟。故答案为:A",
+    "knowledge_points": [
+      "4的乘法口诀及应用"
+    ],
+    "source": "23-24二年级上·新疆乌鲁木齐·期末"
+  },
+  {
+    "id": "4",
+    "unit": "第四单元 表内乘法",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "将一条彩带对折2次后长是 3 米，这条彩带原来长( )。",
+    "options": [
+      "A. 6米",
+      "B. 12米",
+      "C. 9米"
+    ],
+    "answer": "B",
+    "solution": "【分析】根据题意，对折一次变成了同样长的2段，对折2次变成了同样长的4段，则用每段的长度和段数相乘，就是总长度.\n【详解】2×2 = 4(段),3×4 = 12(米),这条彩带原来长12米。故答案为:B",
+    "knowledge_points": [
+      "4的乘法口诀及应用"
+    ],
+    "source": "23-24二年级下·云南曲靖·期末"
+  },
+  {
+    "id": "5",
+    "unit": "第四单元 表内乘法",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "一瓶可乐 5 元，购买 5 瓶及以上，每瓶优惠 1 元。对以上信息理解错误的是( )。",
+    "options": [
+      "A. 买 5 瓶可乐，每瓶 4 元",
+      "B. 买4瓶可乐，每瓶5元",
+      "C. 买4瓶可乐和买5瓶可乐花的钱是一样的",
+      "D. 买 5 瓶可乐和买 6 瓶可乐花的钱是一样的"
+    ],
+    "answer": "D",
+    "solution": "【分析】根据题意，当购买的数量是 5 瓶或 5 瓶以上时，单价是 5 减 1 元。根据单价×数量=总价可以算出买可乐花的钱数。逐项分析.\n【详解】5 - 1 = 4(元),A。买 5 瓶可乐时，每瓶 4 元，原题说法正确;B。买 4 瓶可乐时，每瓶 5 元，原题说法正确;C。4×5 = 20(元),5×4 = 20(元),买 4 瓶可乐和买 5 瓶可乐花的钱是一样的，原题说法正确;D。5×4 = 20(元),6×4 = 24(元),买 5 瓶可乐和买 6 瓶可乐花的钱不一样，原题说法错误。故答案为:D",
+    "knowledge_points": [
+      "经济问题",
+      "5 的乘法口诀及应用",
+      "6 的乘法口诀及应用"
+    ],
+    "source": "23-24 二年级下·福建莆田·期末"
+  },
+  {
+    "id": "6",
+    "unit": "第四单元 表内乘法",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "体育器材室有一些足球，个数比 30 多，比 40 少，这些足球平均分成的份数和每份的个数同样多，这些足球可能有( )个。",
+    "options": [
+      "A. 32",
+      "B. 35",
+      "C. 36"
+    ],
+    "answer": "C",
+    "solution": "【分析】足球的总数 = 平均分成的份数×每份的个数，因为份数和每份的个数同样多，即两个乘数相等。根据乘法口诀进行解答，两个乘数相等且积比 30 多，比 40 少，只有六六三十六这句口诀。以此解答.\n【详解】由分析可得：符合题意的只有六六三十六这句口诀，列式:6×6 = 36，份数和每份数都是 6，足球的个数就是 36。故答案为:C",
+    "knowledge_points": [
+      "100 以内数的比大小",
+      "6 的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级下·福建莆田·期中"
+  },
+  {
+    "id": "7",
+    "unit": "第四单元 表内乘法",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "二(2)班有 4 个小组，每组有 6 人，列式 4×6 解决的问题是( )。",
+    "options": [
+      "A. 全班有多少人。",
+      "B. 每组有多少人。",
+      "C. 4 组有多少人。",
+      "D. 无法确定"
+    ],
+    "answer": "C",
+    "solution": "【分析】算式 4×6 可以表示 4 个 6 的和是多少，也可以表示 6 个 4 的和是多少;二(2)班有4个小组，每组有6人，求4组有多少人，也就是求4个6的和是多少，可以用 4×6 解决.\n【详解】由题意分析得：二(2)班有 4 个小组，每组有 6 人，列式 4×6 解决的问题是:4 组有多少人。故答案为:C",
+    "knowledge_points": [
+      "\"提问题\"\"填条件\"问题",
+      "6 的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级下·湖南长沙·期中"
+  },
+  {
+    "id": "8",
+    "unit": "第四单元 表内乘法",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "小兔子捡来的胡萝卜平均放在 6 个竹筐里，正好能放完，这些胡萝卜可能有( )个。",
+    "options": [
+      "A. 26",
+      "B. 30",
+      "C. 46"
+    ],
+    "answer": "B",
+    "solution": "【分析】根据题意，胡萝卜的个数是 6 的乘法口诀中积的个数。一六得六，二六十二，三六十八，四六二十四，五六三十，六六三十六，六七四十二，六八四十八，六九五十四。据此解答.\n【详解】A。26 不是 6 的乘法口诀中的积;B。五六三十，可能是 30;C。46 不是 6 的乘法口诀中的积。这些胡萝卜可能有30个。故答案为:B",
+    "knowledge_points": [
+      "6 的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级下·福建福州·期中"
+  },
+  {
+    "id": "9",
+    "unit": "第四单元 表内乘法",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "16 > 5 * □,□里最大能填( )。",
+    "options": [
+      "A. 3",
+      "B. 4",
+      "C. 5"
+    ],
+    "answer": "A",
+    "solution": "【分析】结合乘法口诀判断即可。乘法算式中两个乘数是口诀中的前两个数，积是口诀中的后一个数，写算式时两个乘数可互换位置.\n【详解】三五十五，四五二十,16 > 5 * □,□里最大能填 3。故答案为:A",
+    "knowledge_points": [
+      "20以内数的比大小",
+      "5的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级下·辽宁鞍山·阶段练习"
+  },
+  {
+    "id": "10",
+    "unit": "第四单元 表内乘法",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "笑笑买了 6 个汉堡，一共花了多少元。还应该知道( )。",
+    "options": [
+      "A. 每个汉堡5元钱",
+      "B. 带了30元钱",
+      "C. 其中 1 个汉堡 6 元钱"
+    ],
+    "answer": "A",
+    "solution": "【分析】根据总价 = 单价×数量，要求一共花的钱数，已知汉堡的数量，还需知道汉堡的价格.\n【详解】由分析可得：笑笑买了6个汉堡，一共花了多少元。还应该知道每个汉堡 5 元钱。故答案为:A",
+    "knowledge_points": [
+      "6 的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级下·广东梅州·开学考试"
+  },
+  {
+    "id": "11",
+    "unit": "第四单元 表内乘法",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面算式得数与 3 + 3 + 3 + 3 + 2 不相等的是( )。",
+    "options": [
+      "A. 3×4 + 2",
+      "B. 3×2 + 4",
+      "C. 3×5 - 1",
+      "D. 4×3 + 2"
+    ],
+    "answer": "B",
+    "solution": "【分析】根据题意可知：先计算出题干中算式的答案，然后再计算出各选项中的答案，然后选出不相等的选项即可.\n【详解】3 + 3 + 3 + 3 + 2 = 6 + 3 + 3 + 2 = 9 + 3 + 2 = 12 + 2 = 14。A。3×4 + 2 = 12 + 2 = 14;B。3×2 + 4 = 6 + 4 = 10;C。3×5 - 1 = 15 - 1 = 14;D。4×3 + 2 = 12 + 2 = 14，则得数与 3 + 3 + 3 + 3 + 2 不相等的是 3×2 + 4。故答案为:B",
+    "knowledge_points": [
+      "5的乘法口诀及应用",
+      "4的乘法口诀及应用",
+      "表内乘加，乘减"
+    ],
+    "source": "24-25 二年级上·福建福州·期末"
+  },
+  {
+    "id": "12",
+    "unit": "第四单元 表内乘法",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "丰丰在超市买了 3 个苹果花了5元,2根香蕉花了3元，丰丰一共花了多少钱。列式计算是( )。",
+    "options": [
+      "A. 5 + 3 = 8(元)",
+      "B. 3×5 = 15(元)",
+      "C. 2×3 = 6(元)"
+    ],
+    "answer": "A",
+    "solution": "【分析】求一共花了多少钱，用加法计算，即买苹果花的钱数 + 买香蕉花的钱数 = 一共花的钱数，由此解答.\n【详解】A。5 + 3 = 8(元),与题意相符;B。3×5 = 15(元),表示每个苹果 5 元，买了 3 个，与题意不符;C。2×3 = 6(元),表示每根香蕉 3 元，买了 2 根，与题意不符。所以列式应是 5 + 3 = 8(元)。故答案为:A",
+    "knowledge_points": [
+      "8,9 的加减法",
+      "5 的乘法口诀及应用",
+      "3 的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·河南三门峡·期末"
+  },
+  {
+    "id": "13",
+    "unit": "第四单元 表内乘法",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "与 3×4 的计算结果不相等的是( )。",
+    "options": [
+      "A. 4 + 4 + 4",
+      "B. 3 + 3 + 3 + 3",
+      "C. 4×4 - 4",
+      "D. 2×3 + 1×4"
+    ],
+    "answer": "D",
+    "solution": "【分析】算出各个算式的结果，然后对比。整数混合运算中，同级运算时，从左到右依次计算;两级运算时，先算乘除，后算加减.\n【详解】3×4 = 12。A。4 + 4 + 4 = 12，相等;B。3 + 3 + 3 + 3 = 12，相等;C。4×4 - 4 = 16 - 4 = 12，相等;D。2×3 + 1×4 = 6 + 4 = 10，不相等。与 3×4 的计算结果不相等的是 2×3 + 1×4。故答案为:D",
+    "knowledge_points": [
+      "同数连加的应用",
+      "表内乘加，乘减"
+    ],
+    "source": "24-25 二年级上·福建龙岩·期末"
+  },
+  {
+    "id": "14",
+    "unit": "第四单元 表内乘法",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面能用 \"5×2\" 解决的生活问题是( )。",
+    "options": [
+      "A. 买文具盒时，乐乐付了 2 张 5 元，他花了多少钱。",
+      "B. 买故事书时，甜宝付了 1 张 5 元和 2 张 1 元，他花了多少钱。",
+      "C. 买数学本时，小飞付了1张5元，收银元找给他2元，他花了多少钱。",
+      "D. 买钢笔时，小军付了1张5元和1张2元，他花了多少钱。"
+    ],
+    "answer": "A",
+    "solution": "【分析】乘法算式中，两个乘数表示每份的数量和份数，积表示总数。求和用加法计算，逐项分析即可.\n【详解】A。能用\"5×2\"解决;B。用\"5 + 1 + 1\"解决;C。用\"5 - 2\"解决;D。用\"5 + 2\"解决。能用\"5×2\"解决的生活问题是：买文具盒时，乐乐付了 2 张 5 元，他花了多少钱。故答案为:A",
+    "knowledge_points": [
+      "经济问题",
+      "5以内数的减法",
+      "7的加减法",
+      "初步认识乘法意义"
+    ],
+    "source": "24-25二年级上·福建龙岩·期末"
+  },
+  {
+    "id": "15",
+    "unit": "第四单元 表内乘法",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "有一个大盒子，这个大盒子里面装有4个小盒子，每个小盒子里面又装有3个更小的盒子。大大小小的盒子一共有( )个。",
+    "options": [
+      "A. 12",
+      "B. 13",
+      "C. 16",
+      "D. 17"
+    ],
+    "answer": "D",
+    "solution": "【分析】要求一共有几个盒子，用大盒子的数量，小盒子的数量与更小盒子的数量相加即可解决问题，由于小盒子里有 3 个更小的盒子，那么 4 个小盒子里就由 4 个 3 的更小的盒子，用 4×3 求出更小的盒子数量.\n【详解】大盒子的数量:1 个，小盒子的数量: 1×4 = 4 (个),更小盒子的数量: 4×3 = 12(个),1 + 4 + 12 = 17(个),所以，大大小小的盒子一共有17个。故答案为:D",
+    "knowledge_points": [
+      "连加(20 以内)",
+      "4 的乘法口诀及应用"
+    ],
+    "source": "24-25二年级上·浙江温州·期末"
+  },
+  {
+    "id": "16",
+    "unit": "第四单元 表内乘法",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "一只小猫5分钟吃掉一条鱼,5只小猫每只吃5条同样的小鱼需要( )分钟。",
+    "options": [
+      "A. 5",
+      "B. 10",
+      "C. 15",
+      "D. 25"
+    ],
+    "answer": "D",
+    "solution": "【分析】5 只小猫同时吃鱼，所用时间和 1 只小猫吃 5 条同样的小鱼的时间相等。先算 1 只小猫吃 5 条鱼需要多少分钟即可.\n【详解】5×5 = 25(分钟),所以5只小猫每只吃5条同样的小鱼需要25分钟。故答案为:D",
+    "knowledge_points": [
+      "5的乘法口诀及应用"
+    ],
+    "source": "24-25二年级上·浙江温州·期末"
+  },
+  {
+    "id": "17",
+    "unit": "第四单元 表内乘法",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面不能直接改写成乘法算式的是( )。",
+    "options": [
+      "A. 7 + 7 + 7",
+      "B. 3 + 3 + 4 + 3 + 3",
+      "C. 8 + 8 + 8 + 8"
+    ],
+    "answer": "B",
+    "solution": "【分析】求几个相同加数的和，可以用乘法计算。逐项分析下面选项即可解答.\n【详解】A。7 + 7 + 7，三个 7 相加，可写成 7×3 或 3×7;B。3 + 3 + 4 + 3 + 3，包含 4 和多个 3，加数不完全相同，无法直接改写成乘法;C。8 + 8 + 8 + 8，四个 8 相加，可写成 8×4 或 4×8。因此，选项 B 不能直接改写为乘法算式。故答案为:B",
+    "knowledge_points": [
+      "初步认识乘法意义"
+    ],
+    "source": "24-25 二年级上·湖北荆州·期末"
+  },
+  {
+    "id": "18",
+    "unit": "第四单元 表内乘法",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "4 个 6 相加不能列式为( )。",
+    "options": [
+      "A. 4 + 4 + 4 + 4 + 4 + 4 + 4",
+      "B. 6×4",
+      "C. 6 + 6 + 6 + 6"
+    ],
+    "answer": "A",
+    "solution": "【分析】求几个相同数连加的和，可用乘法表示。则 4 个 6 相加可以用 6×4 或者 4×6，也可用 6 + 6 + 6 + 6.\n【详解】由分析可得:4 个 6 相加不能列式为 4 + 4 + 4 + 4 + 4 + 4 + 4。故答案为:A",
+    "knowledge_points": [
+      "同数连加的应用"
+    ],
+    "source": "24-25 二年级上·贵州黔南·期末"
+  },
+  {
+    "id": "19",
+    "unit": "第四单元 表内乘法",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "有 2 排桌子，一排有 5 张，另一排有 4 张，一共有多少张。列式正确的是( )。",
+    "options": [
+      "A. 5 + 4",
+      "B. 5×2",
+      "C. 5×4"
+    ],
+    "answer": "A",
+    "solution": "【分析】根据加法的意义，一排桌子的数量 + 另一排桌子的数量 = 桌子的总数量，由此解答.\n【详解】A。5 + 4 求出的是一共有多少张桌子，符合题意;B. 5×2 表示每排有 5 张，有 2 排，或者每排有 2 张，有 5排，不符合题意;C. 5×4 表示每排有5张，有4排，或者每排有4张，有5排，不符合题意。所以列式正确的是 5 + 4。故答案为:A",
+    "knowledge_points": [
+      "8,9 的加减法",
+      "5 的乘法口诀及应用"
+    ],
+    "source": "20-21 二年级上·湖北咸宁·期末"
+  },
+  {
+    "id": "20",
+    "unit": "第四单元 表内乘法",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "这学期即将结束，如果下面三项表现都做到了，我可以得到( )朵小红花。",
+    "options": [
+      "A. 3",
+      "B. 2",
+      "C. 1"
+    ],
+    "answer": "A",
+    "solution": "【分析】根据题意，下面三项表现都做到时，每项可以得一朵小红花，一共可以得3 朵小红花.\n【详解】3×1 = 3(朵),这学期即将结束，如果下面三项表现都做到了，我可以得到3朵小红花。故答案为:A",
+    "knowledge_points": [
+      "3 的乘法口诀及应用"
+    ],
+    "source": "24-25 三年级上·重庆巫山·期末"
+  },
+  {
+    "id": "21",
+    "unit": "第四单元 表内乘法",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "和算式 3 + 3 + 3 + 3 + 1 得数不相等的是( )。",
+    "options": [
+      "A. 3×4 + 1",
+      "B. 3×4 - 1",
+      "C. 3×5 - 2"
+    ],
+    "answer": "B",
+    "solution": "【分析】根据题意，依次计算出各算式的结果，观察得数即可解答.\n【详解】 3 + 3 + 3 + 3 + 1 = 13。A。3×4 + 1 = 12 + 1 = 13;B. 3×4 - 1 = 12 - 1 = 11;C. 3×5 - 2= 15 - 2 = 13。和算式 3 + 3 + 3 + 3 + 1 得数不相等的是 3×4 - 1。故答案为:B",
+    "knowledge_points": [
+      "表内乘加，乘减"
+    ],
+    "source": "24-25 二年级上·四川乐山·期末"
+  },
+  {
+    "id": "22",
+    "unit": "第四单元 表内乘法",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "关于\"5×6 = 30\"和\"6×5 = 30\"，下列说法错误的是( )。",
+    "options": [
+      "A. 乘法口诀相同",
+      "B. 都表示5个6相加的和",
+      "C. 计算结果相同",
+      "D. 都表示5和6相加的和"
+    ],
+    "answer": "D",
+    "solution": "【分析】\"5×6 = 30\"和\"6×5 = 30\"，表示的是 5 个 6 相加的和是 30 或者 6 个 5 相加的和是 30，都是利用乘法口诀\"五六三十\"，两者计算结果都相等.\n【详解】由分析可得：关于\"5×6 = 30\"和\"6×5 = 30\"，说法错误的是都表示 5 和 6 相加的和,5 和 6 相加的和列式为:5 + 6 = 11。故答案为:D",
+    "knowledge_points": [
+      "初步认识乘法意义",
+      "6 的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·福建福州·期末"
+  },
+  {
+    "id": "23",
+    "unit": "第四单元 表内乘法",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面物体的总数既可以用 3 个 5 表示，又可以用 5 个 3 表示的是( )。",
+    "options": [
+      "A. ![](images/e742e4d4d5103d747b96d1eb7394e015ec9c42f98e824449f2d616676b33b740.jpg)",
+      "B. ![](images/e6aee6738e72c1906abb1e1a49264470da6a4e8f8c6ab4cc3999f9a5a1f0d7db.jpg)",
+      "C. ![](images/6bdfd827c0fe72a8049ccd8a880c98930b124a8d4e5c50e399dd052c1fe92f10.jpg)"
+    ],
+    "answer": "A",
+    "solution": "【分析】物体的总数既可以用3个5表示，又可以用5个3表示，根据乘法的意义，可以列式为: 3×5 或者 5×3，结合题图，进行解答即可.\n【详解】根据分析可得:A。横着看，每一横行5个，有3行，表示3个5，列式 5×3;竖着看，每一竖行 3 个，有 5 行，表示 5 个 3，列式3×5，符合题意，说法正确;B。每串有 5 个香蕉，共 3 串，表示 3 个 5，列式 5×3;不能表示5个3，说法错误，不符合题意;C。第一行5个，第二行3个，列式5 + 3，不能用乘法的意义表示，说法错误，不符合题意。故答案为:A",
+    "knowledge_points": [
+      "初步认识乘法意义",
+      "5 的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·河南南阳·期末"
+  },
+  {
+    "id": "24",
+    "unit": "第四单元 表内乘法",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "梅花的花瓣通常有5瓣，但有些特殊品种可能具有6瓣或3瓣。算式\"5×3\"可以解决的问题是( ).\n①5 朵 3 瓣的梅花，共有几个花瓣\n②3 朵 5 瓣的梅花，共有几个花瓣\n③1 朵 5 瓣和 1 朵 3 瓣的梅花，共有几个花瓣",
+    "options": [
+      "A. ①",
+      "B. ②",
+      "C. ③",
+      "D. ① 和 ②"
+    ],
+    "answer": "D",
+    "solution": "【分析】几个相同加数相加，可以写成加数与个数相乘的形式。乘法交换两个乘数，积不变;求和用加法计算.\n【详解】①5朵3瓣的梅花，共有几个花瓣，可以列式为 5×3;②3朵5瓣的梅花，共有几个花瓣，可以列式为 3×5，也可以用 5×3 表示总花瓣数;③1朵5瓣和1朵3瓣的梅花，共有几个花瓣，用算式\"5 + 3\"可以解决。算式\"5×3\"可以解决的问题是①和②。故答案为:D",
+    "knowledge_points": [
+      "\"提问题\"\"填条件\"问题",
+      "8,9 的加减法",
+      "初步认识乘法意义"
+    ],
+    "source": "24-25二年级上·福建龙岩·期末"
+  },
+  {
+    "id": "25",
+    "unit": "第四单元 表内乘法",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下列算式中，与算式 6 + 6 + 6 + 6 + 6 + 5 相等的一项是( )。",
+    "options": [
+      "A. 6×5 + 5",
+      "B. 6×5 + 6",
+      "C. 6×6 + 5",
+      "D. 6×6 + 6"
+    ],
+    "answer": "A",
+    "solution": "【分析】根据题意，算式 6 + 6 + 6 + 6 + 6 + 5 中，数一数可知算式中有5个6相加的和，再加上5，逐项分析各个选项，找出和它相等即可.\n【详解】A。6×5 + 5，算式表示 5 个 6 相加的和，再加上 5 是多少，答案正确;B。6×5 + 6，算式表示 5 个 6 相加的和，再加上 6 是多少，答案不正确;C。6×6 + 5，算式表示 6 个 6 相加的和，再加上 5 是多少，答案不正确;D。6×6 + 6，算式表示 6 个 6 相加的和，再加上 6 是多少，答案不正确。故答案为:A",
+    "knowledge_points": [
+      "6的乘法口诀及应用",
+      "表内乘加，乘减"
+    ],
+    "source": "24-25二年级上·浙江温州·期末"
+  },
+  {
+    "id": "26",
+    "unit": "第四单元 表内乘法",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "图中一共有多少个涂色方块。可以用算式( )来表示.\n\n![](images/b310081c38a4af6297284a9dfa4af0d56d3931e7911b4e0c988c837d9d629033.jpg)",
+    "options": [
+      "A. 6×3 + 4",
+      "B. 4×5 + 6",
+      "C. 6×5 + 4"
+    ],
+    "answer": "B",
+    "solution": "【分析】根据图片可知：涂满色的一共有4列，每列有5个涂色方块，还有6个涂色方块。求一共有多少个涂色方块，用列数乘每列的数量，再加上多出的数量即可.\n【详解】由分析可得：图中一共有多少个涂色方块，可以用算式(4×5 + 6)来表示。故答案为:B",
+    "knowledge_points": [
+      "同数连加的应用",
+      "初步认识乘法意义",
+      "表内乘加，乘减"
+    ],
+    "source": "24-25 二年级上·湖北武汉·期末"
+  },
+  {
+    "id": "27",
+    "unit": "第四单元 表内乘法",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面哪一道算式不能表示 4 个 3 相加。( )",
+    "options": [
+      "A. 3 + 3 + 3 + 3",
+      "B. 3×3 + 4",
+      "C. 3×3 + 3",
+      "D. 5×3 - 3"
+    ],
+    "answer": "B",
+    "solution": "【分析】求几个相同加数的和，可以用乘法计算，用相同加数×个数或个数×相同加数，由此分析解答.\n【详解】A。 3 + 3 + 3 + 3 表示 4 个 3 相加;B。3×3 + 4 表示 3 个 3 的和再加上 1 个 4，不能表示 4 个 3相加;C。3×3 + 3 表示 3 个 3 的和再加上 1 个 3，结果是 4 个 3 的和;D。5×3 - 3 表示 5 个 3 的和再减去 1 个 3，结果是 4 个 3 的和。所以 3×3 + 4 不能表示 4 个 3 相加。故答案为:B",
+    "knowledge_points": [
+      "同数连加的应用",
+      "初步认识乘法意义",
+      "表内乘加，乘减"
+    ],
+    "source": "24-25 二年级上·湖南湘西·期末"
+  },
+  {
+    "id": "28",
+    "unit": "第四单元 表内乘法",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "5×6 的积比 6×6 的积少( )。",
+    "options": [
+      "A. 1",
+      "B. 5",
+      "C. 6"
+    ],
+    "answer": "C",
+    "solution": "【分析】分别求出 5×6 和 6×6 的积，再把它们的积相减，即可求出来 5×6 的积比 6×6 的积少多少，据此解答.\n【详解】根据分析可得:5×6 = 30,6×6 = 36,36 - 30 = 6。故答案为:C",
+    "knowledge_points": [
+      "两位数与两位数的不退位减法",
+      "6的乘法口诀及应用"
+    ],
+    "source": "23-24 二年级上·湖南长沙·期末"
+  },
+  {
+    "id": "29",
+    "unit": "第四单元 表内乘法",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "有 4 盘梨，前 3 盘各有 4 个，第 4 盘有 3 个，一共有( )个梨。",
+    "options": [
+      "A. 12",
+      "B. 15",
+      "C. 16"
+    ],
+    "answer": "B",
+    "solution": "【分析】一盘梨有 4 个，先用乘法求出 3 盘这样的共有几个，然后加上 3 个，求出和，就是一共的梨数量.\n【详解】4×3 + 3 = 12 + 3 = 15(个),即，有 4 盘梨，前 3 盘各有 4 个，第 4 盘有 3 个，一共有 15 个梨。故答案为:B",
+    "knowledge_points": [
+      "表内乘加，乘减"
+    ],
+    "source": "24-25 二年级上·湖北随州·期末"
+  },
+  {
+    "id": "30",
+    "unit": "第四单元 表内乘法",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "6 + 6 + 6 + 6 + 5 不可以改成算式( )。",
+    "options": [
+      "A. 5×6",
+      "B. 4×6 + 5",
+      "C. 5×6 - 1"
+    ],
+    "answer": "A",
+    "solution": "【分析】根据乘法的意义，逐项分析各项，找出符合题意的算式即可.\n【详解】A。5×6 表示:5 + 5 + 5 + 5 + 5 + 5 或者 6 + 6 + 6 + 6 + 6，而题目是 6 + 6 + 6 + 6 + 5，两者不一样，不能改写，故答案正确;B。6 + 6 + 6 + 6 + 5 表示:4 个 6 相加的和，再加上 5，列式为 4×6 + 5，可以改写，故答案不正确;C。6 + 6 + 6 + 6 + 5 还可以表示:5 个 6 相加的和，再减去多算的 1，列式为 5×6 - 1，可以改写，故答案不正确;故答案为:A",
+    "knowledge_points": [
+      "初步认识乘法意义",
+      "6的乘法口诀及应用",
+      "表内乘加，乘减"
+    ],
+    "source": "24-25二年级上·山东济宁·期末"
+  },
+  {
+    "id": "31",
+    "unit": "第四单元 表内乘法",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "下面算式能改写成乘法算式的是( )。",
+    "options": [
+      "A. 3 + 3 + 3 - 2",
+      "B. 6 + 6 + 6 + 6",
+      "C. 4 + 4 + 4 + 5"
+    ],
+    "answer": "B",
+    "solution": "【分析】几个相同加数相加，可以直接写成加数与个数相乘的形式，写算式时两个乘数可互换位置。据此逐项分析.\n【详解】A。3 + 3 + 3 - 2 不能直接改写成乘法算式;B。6 + 6 + 6 + 6 可以写成 6×4 或 4×6，符合;C。4 + 4 + 4 + 5 不能直接改写成乘法算式。能改写成乘法算式的是 6 + 6 + 6 + 6。故答案为:B",
+    "knowledge_points": [
+      "初步认识乘法意义",
+      "表内乘加，乘减"
+    ],
+    "source": "24-25 二年级上·河南驻马店·期末"
+  },
+  {
+    "id": "32",
+    "unit": "第四单元 表内乘法",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "\"二四得八\"这句乘法口诀表示的意思是( )。",
+    "options": [
+      "A. 2个4相加的和是8",
+      "B. 2个4相乘的积是 8",
+      "C. 2 加 4 等于 8"
+    ],
+    "answer": "A",
+    "solution": "【分析】乘法算式中两个乘数是口诀中的前两个数，积是口诀中的后一个数，写算式时两个乘数可互换位置。逐项分析即可.\n【详解】A。2 个 4 相加可以列式为 2×4 = 8，用到的乘法口诀是\"二四得八\"，符合;B。2 个 4 相乘列式为 4×4 = 16，用到的乘法口诀是\"四四十六\"，不符合;C。2 加 4 列式为 2 + 4 = 6，不符合.\"二四得八\"这句乘法口诀表示的意思是:2个4相加的和是 8。故答案为:A",
+    "knowledge_points": [
+      "6的加减法",
+      "4的乘法口诀及应用"
+    ],
+    "source": "24-25二年级上·湖北黄冈·期末"
+  },
+  {
+    "id": "33",
+    "unit": "第四单元 表内乘法",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "下列计算不能用口诀\"三六十八\"解决的是( )。",
+    "options": [
+      "A. 3个6相加",
+      "B. 3 + 3 + 3 + 3 + 3 + 3",
+      "C. 3 和 6 相加"
+    ],
+    "answer": "C",
+    "solution": "【分析】几个相同加数相加，可以写成加数与个数相乘的形式。乘法算式中两个乘数是口诀中的前两个数，积是口诀中的后一个数，写算式时两个乘数可互换位置.\n【详解】A。3 个 6 相加列式为 6 + 6 + 6 = 18，即 3×6 = 18，可以用口诀\"三六十八\"解决;B。3 + 3 + 3 + 3 + 3 + 3 列式为 3×6 = 18，可以用口诀\"三六十八\"解决;C。3 和 6 相加列式为 3 + 6，不可以用口诀\"三六十八\"解决。3 和 6 相加不能用口诀\"三六十八\"解决。故答案为:C",
+    "knowledge_points": [
+      "同数连加的应用",
+      "6 的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·湖北黄石·期末"
+  },
+  {
+    "id": "34",
+    "unit": "第四单元 表内乘法",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面得数最大的是( )。",
+    "options": [
+      "A. 2和6相加",
+      "B. 6和6相乘",
+      "C. 2个6相加"
+    ],
+    "answer": "B",
+    "solution": "【分析】分别计算各选项中的得数，然后进行比较大小，选择最大的即可.\n【详解】A。2 和 6 相加,2 + 6 = 8;B。6 和 6 相乘,6×6 = 36;C。2 个 6 相加,6 + 6 = 12;36 > 12 > 8，则得数最大的是 6 和 6 相乘。故答案为:B",
+    "knowledge_points": [
+      "6 的乘法口诀及应用"
+    ],
+    "source": "24-25二年级上·贵州铜仁·期末"
+  },
+  {
+    "id": "35",
+    "unit": "第四单元 表内乘法",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "二年级有 4 个班参加篮球社团活动,( ),二年级一共有多少人参加篮球社团活动。列式为 4×5，横线上应填的条件是( )。",
+    "options": [
+      "A. 有男生 4 人，女生 5 人",
+      "B. 每个班有 4 人参加",
+      "C. 每个班有5个小组",
+      "D. 每个班有5人参加"
+    ],
+    "answer": "D",
+    "solution": "【分析】乘法算式表示几个相同加数的和,4×5 表示 4 个 5 的和或 5 个 4 的和。求一共有多少人，知道了班级数，则再需要的条件应是每个班的人数，由此解答.\n【详解】A。男生 4 人，女生 5 人，列式为 4 + 5，不符合题意;B。每个班有 4 人参加，列式为 4×4，不符合题意;C。每个班有 5 个小组，不知道每个小组的人数，不能求出总人数，不符合题意;D。每个班有 5 人参加，列式为 4×5，符合题意。则横线上应填的条件是每个班有 5 人参加。故答案为:D",
+    "knowledge_points": [
+      "\"提问题\"\"填条件\"问题",
+      "8,9 的加减法",
+      "5的乘法口诀及应用",
+      "4 的乘法口诀及应用"
+    ],
+    "source": "24-25二年级上·福建龙岩·期末"
+  },
+  {
+    "id": "36",
+    "unit": "第四单元 表内乘法",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "求 4 个 5 相加的和是多少，列式错误的是( )。",
+    "options": [
+      "A. 4 + 4 + 4 + 4 + 4",
+      "B. 4×5",
+      "C. 5 + 5 + 5 +5",
+      "D. 5×4"
+    ],
+    "answer": "A",
+    "solution": "【分析】求几个相同加数的和，列加法算式时，用加号连接相同加数，列乘法算式时，用相同加数×个数或个数×相同加数，由此解答.\n【详解】A。4 + 4 + 4 + 4 + 4 表示 5 个 4 的和;B。4×5 可以表示 4 个 5 的和;C。5 + 5 + 5 + 5 表示 4 个 5 的和;D。5×4 可以表示 4 个 5 的和。则求4个5相加的和是多少，列式错误的是 4 + 4 + 4 + 4 + 4。故答案为:A",
+    "knowledge_points": [
+      "同数连加的应用",
+      "初步认识乘法意义"
+    ],
+    "source": "24-25 二年级上·福建龙岩·期末"
+  },
+  {
+    "id": "37",
+    "unit": "第四单元 表内乘法",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "每两面旗隔 6 米，从第 1 面旗到第 6 面旗隔( )米.\n\n![](images/790c5f78d4adb69508c10a847ac79e73e24ce61f9305ef9703ea9eb39d7e0919.jpg)",
+    "options": [
+      "A. 30",
+      "B. 36",
+      "C. 42"
+    ],
+    "answer": "A",
+    "solution": "【分析】用旗的面数减1算出有几个间隔，用间隔数乘每个间隔的长度即可求解.\n【详解】6 - 1 = 5(个),6×5 = 30(米)。从第1面旗到第6面旗隔30米。故答案为:A",
+    "knowledge_points": [
+      "6的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·湖南长沙·期末"
+  },
+  {
+    "id": "38",
+    "unit": "第四单元 表内乘法",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "5 个 3 相加是多少。正确的列式是( )。",
+    "options": [
+      "A. 3 + 3 + 3 = 9",
+      "B. 5 + 3 = 8",
+      "C. 5×3 = 15"
+    ],
+    "answer": "C",
+    "solution": "【分析】几个相同加数相加，可以写成加数与个数相乘的形式。乘法算式中两个乘数是口诀中的前两个数，积是口诀中的后一个数，写算式时两个乘数可互换位置.\n【详解】A。3 + 3 + 3 = 9 表示 3 个 3 相加;B。5 + 3 = 8 表示 5 和 3 相加;C。5×3 = 15 可以表示 5 个 3 相加。5 个 3 相加是多少。正确的列式是 5×3 = 15。故答案为:C",
+    "knowledge_points": [
+      "8,9 的加减法",
+      "同数连加的应用",
+      "5 的乘法口诀及应用"
+    ],
+    "source": "15-16 二年级上·全国·课后作业"
+  },
+  {
+    "id": "39",
+    "unit": "第四单元 表内乘法",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "15 + 15 + 15，可以改写成乘法算式( )。",
+    "options": [
+      "A. 5×3",
+      "B. 10×5",
+      "C. 15×3"
+    ],
+    "answer": "C",
+    "solution": "【分析】几个相同加数相加，可以写成加数与个数相乘的形式，写算式时两个乘数可互换位置.\n【详解】15 + 15 + 15，可以改写成乘法算式 15×3 或 3×15。故答案为:C",
+    "knowledge_points": [
+      "同数连加的应用",
+      "初步认识乘法意义"
+    ],
+    "source": "20-21 二年级上·湖南长沙·期末"
+  },
+  {
+    "id": "40",
+    "unit": "第四单元 表内乘法",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "求下图中一共有多少个桃，不正确的算式是( ).\n\n![](images/2026-02-24%20205607.jpg)",
+    "options": [
+      "A. 3×4 + 2",
+      "B. 3×5 - 1",
+      "C. 3×5 - 2"
+    ],
+    "answer": "C",
+    "solution": "【分析】每盘有3个桃子，有这样的4盘，还多2个，则桃子的总数量为4个3的和再加2，即每盘桃子的数量3个×盘数4盘 + 多的数量2个;也可以看成有5盘，每盘有3个，再减去多算的1个，则桃子的总数量为5个3的和再减1，即每盘桃子的数量3个×盘数5盘 - 多算的数量1个，由此解答.\n【详解】A。3×4 + 2 表示 4 个 3 的和再加 2，算式正确;B。3×5 - 1 表示 5 个 3 的和再减 1，算式正确;C。3×5 - 2 表示 5 个 3 的和再减 2，算式不正确。则不正确的算式是 3×5 - 2。故答案为:C",
+    "knowledge_points": [
+      "图文问题",
+      "表内乘加，乘减"
+    ],
+    "source": "24-25 二年级上·湖南株洲·期末"
+  },
+  {
+    "id": "41",
+    "unit": "第四单元 表内乘法",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "一只手有5个手指头，一双手有( )个手指头。",
+    "options": [
+      "A. 5 + 2 = 7(个)",
+      "B. 5 + 5 = 10(个)",
+      "C. 2 + 5 = 7(个)"
+    ],
+    "answer": "B",
+    "solution": "【分析】根据生活常识可知，一双手是两只手，一只手有5个手指头，则一双手手指头的数量为 2 个 5 的和，由此解答.\n【详解】A。5 + 2 = 7(个)表示 5 和 2 的和，不符合题意;B。5 + 5 = 10(个)表示 2 个 5 的和，符合题意;C。2 + 5 = 7(个)表示 2 和 5 的和，不符合题意。所以一只手有 5 个手指头，一双手有 10 个手指头。故答案为:B",
+    "knowledge_points": [
+      "同数连加的应用"
+    ],
+    "source": "23-24二年级下·广东汕头·期中"
+  },
+  {
+    "id": "42",
+    "unit": "第四单元 表内乘法",
+    "question_type": "填空题",
+    "difficulty": 0.94,
+    "question": "在括号里填上\"+\"\"-\"或\"*\".\n5 ( ) 6 = 11;4 ( ) 3 = 12;3 ( ) 3 = 0\n4 ( ) 5 = 20;6 ( ) 6 = 12;6 ( ) 4 = 2",
+    "options": [],
+    "answer": "+;*;-;*;+;-",
+    "solution": "【分析】根据表内乘法和20以内加减法进行计算，填出正确的符号即可.\n【详解】由题意分析得:5 + 6 = 11;4×3 = 12;3 - 3 = 0;4×5 = 20;6 + 6 = 12;6 - 4 = 2。",
+    "knowledge_points": [
+      "6的加减法",
+      "4的乘法口诀及应用"
+    ],
+    "source": "25-26 二年级上·全国·单元测试"
+  },
+  {
+    "id": "43",
+    "unit": "第四单元 表内乘法",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "如图，将一条线段连续对折 3 次得到下面的线段，原来线段的长度是( )厘米.\n![](images/2026-02-24%20210059.jpg)",
+    "options": [],
+    "answer": "48",
+    "solution": "【分析】线段每对折一次，得到的段数就是原来的 2 倍，所以把一条线段连续对折 3 次就是把这条线段平均分成 8 段，对折 3 次后每段长 6 厘米，原来线段长度为 8 段的长度之和，即 6×8 = 48(厘米);据此解答.\n【详解】2×2×2 = 4×2 = 8(段),6×8 = 48(厘米),原来线段的长度是48厘米。",
+    "knowledge_points": [
+      "图形的折叠问题",
+      "6 的乘法口诀及应用"
+    ],
+    "source": "24-25 三年级上·河南安阳·期中"
+  },
+  {
+    "id": "44",
+    "unit": "第四单元 表内乘法",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "钟面上，分针从 12旋转到 5 所经过的时间是( )分，所形成的角是( )角。",
+    "options": [],
+    "answer": "25;钝",
+    "solution": "【分析】钟面被分为12个大格，分针每走1大格是5分;分针从 12 旋转到 5，走了 5 大格，时间为 5×5 = 25 分。在三角板上，最大角就是直角，钝角比直角大，锐角比直角小，分针从指向12到指向5，所形成的角比直角大一些，也就是钝角.\n【详解】由分析可知：分针从 12 旋转到 5，走了 5 大格，时间为: 5×5 = 25(分),即钟面上，分针从12旋转到5所经过的时间是25分，所形成的角是钝角。",
+    "knowledge_points": [
+      "直角，钝角，锐角的认识及特征",
+      "时，分，秒有关的计算"
+    ],
+    "source": "24-25 二年级下·河南信阳·期中"
+  },
+  {
+    "id": "45",
+    "unit": "第四单元 表内乘法",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "4 个 5 相加的和是( ),3与8相加的和是( )。比 28 多 43 的数是( ),比36 少 12 的数是( ),55 比 39 多( )。",
+    "options": [],
+    "answer": "20;11;71;24;16",
+    "solution": "【分析】求几个相同加数的和，用乘法计算比较简便，故求4个5相加的和，用乘法计算;求3与8的和用加法计算;用28加43算出的得数，就是比28多43的数;用36减12算出的得数，就是比36少12的数;用55减39算出的得数，就是55比39多出的数;据此解答.\n【详解】由分析可得:①4×5 = 20;②3 + 8 = 11;③28 + 43 = 71;④36 - 12 = 24;⑤55 - 39 = 16.4 个5相加的和是20,3与8相加的和是11，比28多43的数是71，比36少12的数是24,55比39多16。",
+    "knowledge_points": [
+      "谁比谁多/少几的问题",
+      "两位数与两位数的进位加法",
+      "两位数与两位数的退位减法",
+      "5 的乘法口诀及应用"
+    ],
+    "source": "23-24 二年级下·湖北黄冈·期末"
+  },
+  {
+    "id": "46",
+    "unit": "第四单元 表内乘法",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "8 + 8 + 8 + 8 + 8 = ( )×( )。4 + 4 + 4 - 3 = ( )×( ) - ( )。",
+    "options": [],
+    "answer": "8;5;4;3;3",
+    "solution": "【分析】8 + 8 + 8 + 8 + 8 表示5个8相加的和，根据乘法的意义，可以写成乘法算式 8×5 或 5×8;4 + 4 + 4 - 3 前面有3个4相加，然后再减去3，根据乘法的意义,3个4相加可以写成 4×3 或 3×4，所以整个式子可以写成 4×3 - 3.\n【详解】由分析填写如下:8 + 8 + 8 + 8 + 8 = (8)×(5)。4 + 4 + 4 - 3 = (4)×(3) - (3)。",
+    "knowledge_points": [
+      "初步认识乘法意义",
+      "4 的乘法口诀及应用",
+      "表内乘加，乘减"
+    ],
+    "source": "23-24 二年级上·新疆乌鲁木齐·期末"
+  },
+  {
+    "id": "47",
+    "unit": "第四单元 表内乘法",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "有二十几个橘子，平均分给一些小朋友，每个小朋友拿到的橘子数和小朋友的数量相同，这堆橘子有( )个。",
+    "options": [],
+    "answer": "25",
+    "solution": "【分析】根据题意可知：小朋友的人数×每个人分到的橘子数 = 共有的橘子数;每个小朋友拿到的橘子数和小朋友数量相同，所以需要考虑两个乘数相等的乘法口诀，而且口诀得数是二十几。据此解答.\n【详解】由分析可得：乘数相等而且得数是二十几的口诀，符合条件的只有一句：五五二十五;5×5 = 25(个),有二十几个橘子，平均分给一些小朋友，每个小朋友拿到的橘子数和小朋友的数量相同，这堆橘子有 25 个。",
+    "knowledge_points": [
+      "5 的乘法口诀及应用"
+    ],
+    "source": "22-23 二年级下·新疆乌鲁木齐·期中"
+  },
+  {
+    "id": "48",
+    "unit": "第四单元 表内乘法",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "面包原来 10 元一个，现在优惠促销，每买 3 个面包 27 元，买 3 个面包便宜( )元，买 7 个面包便宜( )元。",
+    "options": [],
+    "answer": "3;6",
+    "solution": "【分析】先算出原来3个面包共多少元，再用减法算出优惠促销后，买 3 个面包便宜了多少元;根据题意，每买3个面包27元，买7个面包花的钱包含2组3个面包，还余下1个面包按原价10元算，用每组面包便宜的钱 * 2，即可求出买7个面包便宜的钱，据此解答.\n【详解】10 + 10 + 10 = 30(元),30 - 27 = 3(元),买3个面包便宜了3元。3×2 = 6(元),买 7 个面包便宜了 6 元。",
+    "knowledge_points": [
+      "两位数与两位数的退位减法",
+      "100以内数的连加运算",
+      "3的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级下·内蒙古赤峰·期中"
+  },
+  {
+    "id": "49",
+    "unit": "第四单元 表内乘法",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "6 个 9 相加的和是( );68 比( )少 17。",
+    "options": [],
+    "answer": "54;85",
+    "solution": "【分析】几个相同加数的和可以用乘法来算;比多少问题中求多的数应该用加法来算。据此解答.\n【详解】由分析可得:6×9 = 54;6 个 9 相加的和是54;68 + 17 = 85;所以 68 比 85 少 17。",
+    "knowledge_points": [
+      "两，三位数的一次进位加法",
+      "初步认识乘法意义"
+    ],
+    "source": "24-25 二年级下·贵州铜仁·期末"
+  },
+  {
+    "id": "50",
+    "unit": "第四单元 表内乘法",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "写出三个得数是12的乘法算式.\n( )×( ) = 12;( )×( ) = 12;( )×( ) = 12",
+    "options": [],
+    "answer": "2;6;3;4;4;3",
+    "solution": "【分析】乘法算式为：乘数×乘数 = 积，乘法口诀中前两个数是乘数，可互换位置，后一个数是积，由此根据积是12的乘法口诀填写算式即可.\n【详解】根据乘法口诀二六十二，三四十二可知:2×6 = 12;3×4 = 12;4×3 = 12。(答案不唯一)",
+    "knowledge_points": [
+      "4的乘法口诀及应用",
+      "6的乘法口诀及应用"
+    ],
+    "source": "24-25二年级下·贵州铜仁·期末"
+  },
+  {
+    "id": "51",
+    "unit": "第四单元 表内乘法",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "蜗牛每小时可爬行5米,3小时能爬行多少米。解决这个问题可以用( )法计算，因为( )。",
+    "options": [],
+    "answer": "乘;乘法是求几个相同加数和的简便运算",
+    "solution": "【分析】蜗牛每小时可爬行5米，求3小时能爬行多少米，就是求3个5的和是多少，根据乘法的意义(求几个相同加数和是多少，可以用乘法简便运算)可知，这个问题可以用乘法列式计算.\n【详解】蜗牛每小时可爬行5米，要求3小时能爬行多少米，列式为:5×3 = 15(米),可以用乘法计算，因为乘法是求几个相同加数和的简便运算。",
+    "knowledge_points": [
+      "初步认识乘法意义",
+      "5 的乘法口诀及应用"
+    ],
+    "source": "24-25四年级下·海南省直辖县级单位·期中"
+  },
+  {
+    "id": "52",
+    "unit": "第四单元 表内乘法",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "有一盆杨梅,2 个2个数,4个4个数,6个6个数都能正好数完，这盆杨梅至少有( )个。",
+    "options": [],
+    "answer": "12",
+    "solution": "【分析】根据题目可知，这样数杨梅的方法，正好满足乘法的意义。利用表内乘法，分别列出和2,4,6有关的乘法口诀算得的数，找出这些数中和2,4,6同时有关的最小的那个数，即可求解.\n【详解】关于2的乘法口诀得到的数:2,4,6,8,10,12,14,16,18,20。关于4的乘法口诀得到的数:4,8,12,16,20。关于 6 的乘法口诀得到的数:6,12,18,24。由此可知，最小的和2,4,6都相关的那个数为 12。故此，这盆杨梅至少有12个。",
+    "knowledge_points": [
+      "2 的乘法口诀及应用",
+      "4 的乘法口诀及应用",
+      "6的乘法口诀及应用"
+    ],
+    "source": "23-24 二年级下·浙江舟山·期末"
+  },
+  {
+    "id": "53",
+    "unit": "第四单元 表内乘法",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "把\"9 + 9 + 9 + 9 + 9 = 45\"写成乘法算式是( ),这个乘法算式读作( ),其中( )和( )是乘数,( )是积。",
+    "options": [],
+    "answer": "9×5 = 45;9乘5等于45;9;5;45",
+    "solution": "【分析】同数连加可以写成乘法算式，相同的加数在前，个数在后，即用相同加数×个数，乘法算式为乘数×乘数=积，要从左往右读，数字直接读出来，\"*\"读作乘，\"=\"读作等于.\n【详解】把\"9 + 9 + 9 + 9 + 9 = 45\"写成乘法算式是9×5 = 45，这个乘法算式读作9乘5等于45，其中9和5是乘数,45是积。",
+    "knowledge_points": [
+      "同数连加的应用",
+      "初步认识乘法意义"
+    ],
+    "source": "23-24 二年级下·湖北黄冈·期末"
+  },
+  {
+    "id": "54",
+    "unit": "第四单元 表内乘法",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "每个花盆里有 6 朵花,3 个花盆有( )朵花。",
+    "options": [],
+    "answer": "18",
+    "solution": "【分析】根据乘法的意义，花的总数 = 每个花盆里花的数量×花盆数，列式计算得出答案即可求解.\n【详解】6×3 = 18(朵),所以 3 个花盆有 18 朵花。",
+    "knowledge_points": [
+      "6 的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级下·广东云浮·期中"
+  },
+  {
+    "id": "55",
+    "unit": "第四单元 表内乘法",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "蓝天小学 5 名同学去参加创意绘画比赛，每人需要准备 2 个纸盘，他们一共需要准备( )个纸盘。",
+    "options": [],
+    "answer": "10",
+    "solution": "【分析】根据题意，求一共需要准备几个纸盘，用乘法计算，用每人需要准备纸盘的个数×参加创意绘画比赛的同学人数，即可解答.\n【详解】由分析可得:2×5 = 10(个),蓝天小学5名同学去参加创意绘画比赛，每人需要准备2个纸盘，他们一共需要准备10个纸盘。",
+    "knowledge_points": [
+      "5 的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级下·贵州六盘水·期中"
+  },
+  {
+    "id": "56",
+    "unit": "第四单元 表内乘法",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "有一些巧克力，比30多，比40少，平均分成的份数和每份的块数同样多，这些巧克力有( )块。",
+    "options": [],
+    "answer": "36",
+    "solution": "【分析】乘法算式中两个乘数是口诀中的前两个数，积是口诀中的后一个数。找出两个乘数一样，积在30到40之间的算式，这个积就是巧克力的块数.\n【详解】六六三十六,6×6 = 36(块),这些巧克力有 36 块。",
+    "knowledge_points": [
+      "100 以内数的比大小",
+      "6 的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级下·辽宁鞍山·阶段练习"
+  },
+  {
+    "id": "57",
+    "unit": "第四单元 表内乘法",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "有 3 盘苹果，每盘放 2 个，一共有多少个苹果。列加法算式是( ),表示( )个( )相加，列乘法算式是( )。",
+    "options": [],
+    "answer": "2 + 2 + 2 = 6(个);3;2;2×3 = 6(个)或3×2 = 6(个)",
+    "solution": "【分析】求一共多少个苹果，即3个2相加，根据求几个相同数连加的和，也可用乘法计算，列式为2×3 = 6或3×2 = 6.\n【详解】2 + 2 + 2 = 6(个),2×3 = 6或3×2 = 6，则有3盘苹果，每盘放2个，一共有多少个苹果。列加法算式是2 + 2 + 2 = 6(个),表示(3)个(2)相加，列乘法算式是2×3 = 6(个)或3×2 = 6(个)。",
+    "knowledge_points": [
+      "同数连加的应用",
+      "初步认识乘法意义",
+      "3的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级下·广东梅州·开学考试"
+  },
+  {
+    "id": "58",
+    "unit": "第四单元 表内乘法",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "如果△ + △ + △ = 12,3 * △ = 12,○ + ○ + ○ = 6,3 * ○ = 6，求△ * ○。",
+    "options": [],
+    "answer": "8",
+    "solution": "【分析】求几个相同加数的和，可以用乘法计算，用相同加数×个数或个数×相同加数。△ + △ + △ = 12，可写成 3 * △ = 12;○ + ○ + ○ = 6，可写成 3 * ○ = 6，根据乘法口诀计算出△和○代表的数，再代入到 △ * ○ 中计算即可.\n【详解】3 * △ = 12，根据乘法口诀\"三四十二\"可知,3×4 = 12，即 △ = 4;3 * ○ = 6，根据乘法口诀\"二三得六\"可知,3×2 = 6，即 ○ = 2;那么 △ * ○ = 4×2 = 8。",
+    "knowledge_points": [
+      "初步认识乘法意义",
+      "3的乘法口诀及应用",
+      "4的乘法口诀及应用"
+    ],
+    "source": "24-25二年级上·浙江嘉兴·期末"
+  },
+  {
+    "id": "59",
+    "unit": "第四单元 表内乘法",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "小明和 5 个好朋友吃饭，他们要准备( )个碗和( )根筷子。",
+    "options": [],
+    "answer": "6;12",
+    "solution": "【分析】先用加法计算出一共有几个人。根据生活经验可知，每人需要1个碗，每人需要2根筷子，则用人数和每人需要碗的数量相乘，求出需要碗的总数量;人数和每人需要筷子的根数相乘，求出需要筷子的总根数.\n【详解】1 + 5 = 6(人),碗:6×1 = 6(个),筷子:6×2 = 12(根),小明和 5 个好朋友吃饭，他们要准备 6 个碗和 12 根筷子。",
+    "knowledge_points": [
+      "6 的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·湖北黄冈·期末"
+  },
+  {
+    "id": "60",
+    "unit": "第四单元 表内乘法",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "在加法算式 8 + 8 + 8 + 8 + 8 + 5 中，如果再加上( ),就可以用乘法算式 8×6 表示;如果再减去( ),就可以用乘法算式 8×5 表示。",
+    "options": [],
+    "answer": "3;5",
+    "solution": "【分析】通过观察加法算式 8 + 8 + 8 + 8 + 8 + 5，可知算式中有 5 个 8 和 1 个 5 相加，如果把算式中的 1 个 5 加上 3，就变成6个8相加，就可以用乘法算式 8×6 表示;如果把算式中的1个5减去，就变成5个8相加，就可以用乘法算式8×5 表示.\n【详解】由分析可知：在加法算式 8 + 8 + 8 + 8 + 8 + 5 中，如果再加上3，就可以用乘法算式 8×6 表示;如果再减去5，就可以用乘法算式8×5 表示。",
+    "knowledge_points": [
+      "初步认识乘法意义"
+    ],
+    "source": "24-25 二年级上·福建龙岩·期末"
+  },
+  {
+    "id": "61",
+    "unit": "第四单元 表内乘法",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "按规律填数:1,4,9,( ),25。",
+    "options": [],
+    "answer": "16",
+    "solution": "【分析】1×1 = 1,2×2 = 4,3×3 = 9,4×4 = 16,5×5 = 25,6×6 = 36。此题的规律是每个位置的数等于它的序数乘自身.\n【详解】由分析可知:1×1 = 1;2×2 = 4;3×3 = 9;4×4 = 16;5×5 = 25;所以，按规律填数:1,4,9,(16),25。",
+    "knowledge_points": [
+      "整数排列的规律"
+    ],
+    "source": "24-25六年级上·新疆克孜勒苏·期末"
+  },
+  {
+    "id": "62",
+    "unit": "第四单元 表内乘法",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "春天到了，小青蛙从冬眠中醒来。1 只青蛙 1 张嘴,2 只眼睛 4 条腿;6 只青蛙( )张嘴,( )只眼睛,( )条腿。",
+    "options": [],
+    "answer": "6;12;24",
+    "solution": "【分析】根据题意可知,1只青蛙1张嘴,2只眼睛4条腿,6只青蛙就是 6×1 = 6(张)嘴,6×2 = 12(只)眼睛,6×4 = 24(条)腿，据此解答.\n【详解】根据分析可得:6×1 = 6(张),6×2 = 12(只),6×4 = 24(条),春天到了，小青蛙从冬眠中醒来。1只青蛙1张嘴,2只眼睛4条腿;6只青蛙6张嘴,12只眼睛,24条腿。",
+    "knowledge_points": [
+      "6的乘法口诀及应用"
+    ],
+    "source": "24-25二年级上·河南南阳·期末"
+  },
+  {
+    "id": "63",
+    "unit": "第四单元 表内乘法",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "在括号里填上\"+\"\"-\"\"*\"或\">\"\"<\"\"=\".\n4 ( ) 2 = 6;9 ( ) 2 = 7;5×4 ( ) 20\n3 ( ) 3 = 9;8 ( ) 5 = 13;9 cm ( ) 1 m",
+    "options": [],
+    "answer": "+;-;=;*;+;<",
+    "solution": "【分析】结合整数加减法的计算法则，乘法口诀和整数比较大小的方法来解决此题即可。4和2合起来就是6，则4 + 2 = 6;9可以分成2和7，则9 - 2 = 7;由乘法口诀\"四五二十\"得:5×4 = 20;由乘法口诀\"三三得九\"得:3×3 = 9;8和5合成13，则8 + 5 = 13;1 m = 100 cm,9 cm < 100 cm,故9 cm < 1 m.\n【详解】由题意分析得:4 + 2 = 6;9 - 2 = 7;5×4 = 20;3×3 = 9;8 + 5 = 13;9 cm < 1 m.",
+    "knowledge_points": [
+      "8,9的加减法",
+      "5的乘法口诀及应用",
+      "3的乘法口诀及应用",
+      "厘米和米之间的进率与换算"
+    ],
+    "source": "24-25二年级上·湖南湘西·期末"
+  },
+  {
+    "id": "64",
+    "unit": "第四单元 表内乘法",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "在括号里填上\"+\"\"-\"或\"*\".\n5 ( ) 4 = 20;15 ( ) 5 = 10;46 ( ) 54 = 100",
+    "options": [],
+    "answer": "*;-;+",
+    "solution": "【分析】算式中若等号右侧的数比左侧的数大或相等可试填\"+\"或\"*\";若等号右侧的数比左侧第一个数小，可试填\"-\"。一般情况下，加法和乘法运算会让得数变多或不变，减法运算会让得数变少或不变.\n【详解】5×4 = 20;15 - 5 = 10;46 + 54 = 100。",
+    "knowledge_points": [
+      "不退位减法(20 以内)",
+      "两位数与两位数的进位加法",
+      "5 的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·广东肇庆·期末"
+  },
+  {
+    "id": "65",
+    "unit": "第四单元 表内乘法",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "王阿姨有一些苹果，苹果的数量比 30 多，比 40 少，将它们平均分给 6 只小猴，刚好分完。这堆苹果有( )个。",
+    "options": [],
+    "answer": "36",
+    "solution": "【分析】根据题意，小猴的数量×每只小猴分的苹果数量=苹果的总数量，根据含有6的乘法口诀，找出结果在30和40之间的即可.\n【详解】6×5 = 30(个),30不符合\"比30多\"的条件;6×6 = 36(个),30 < 36 < 40，符合题意。则这堆苹果有36个。",
+    "knowledge_points": [
+      "100 以内数的比大小",
+      "6 的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·湖北黄冈·期末"
+  },
+  {
+    "id": "66",
+    "unit": "第四单元 表内乘法",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "2 与 5 的和是( );2 个 5 的和是( );2 与 5 的积是( )。",
+    "options": [],
+    "answer": "7;10;10",
+    "solution": "【分析】2与5的和，加数分别是2和5;2个5的和，加数分别是5和5;2与5的积，乘数分别是2和5，据此计算.\n【详解】2 + 5 = 7;5 + 5 = 10;2×5 = 10.2与5的和是7;2个5的和是10;2与5的积是10。",
+    "knowledge_points": [
+      "7的加减法",
+      "10的加减法",
+      "初步认识乘法意义",
+      "5 的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·福建福州·期末"
+  },
+  {
+    "id": "67",
+    "unit": "第四单元 表内乘法",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "2×5 = 10，这个算式读作( ),算式中的积是( ),用到的乘法口诀是( )。",
+    "options": [],
+    "answer": "2乘5等于10;10;二五一十",
+    "solution": "【分析】乘法算式从左往右读，数字是几就读几，\"*\"读作乘，\"=\"读作等于。乘法算式为乘数×乘数 = 积，两个乘数是口诀中的前两个数，积是口诀中的后一个数.\n【详解】2×5 = 10，这个算式读作 2 乘 5 等于 10，算式中的积是10，用到的乘法口诀是二五一十。",
+    "knowledge_points": [
+      "初步认识乘法意义",
+      "5 的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·湖北黄冈·期末"
+  },
+  {
+    "id": "68",
+    "unit": "第四单元 表内乘法",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "6 个 3 的和是( );6 与 3 的和是( )。",
+    "options": [],
+    "answer": "18;9",
+    "solution": "【分析】求几个相同加数的和是多少，用乘法列式解决;求两个数的和是多少，用加法列式解决.\n【详解】6×3 = 18;6 + 3 = 9，即,6 个 3 的和是18;6 与 3 的和是9。",
+    "knowledge_points": [
+      "8,9 的加减法",
+      "初步认识乘法意义",
+      "6 的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·浙江温州·期末"
+  },
+  {
+    "id": "69",
+    "unit": "第四单元 表内乘法",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "新年的钟声敲响,3个人互发短信祝贺新年，一共要发( )条短信。",
+    "options": [],
+    "answer": "6",
+    "solution": "【分析】3 个人互发短信，每人发 2 条，用每人发的条数乘人数，即可求出一共要发的条数，据此解答.\n【详解】3×2 = 6(条),所以一共要发6条短信。",
+    "knowledge_points": [
+      "3 的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·贵州铜仁·期末"
+  },
+  {
+    "id": "70",
+    "unit": "第四单元 表内乘法",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "3 个 5 相加的和是( );7 和 8 相加的和是( )。",
+    "options": [],
+    "answer": "15;15",
+    "solution": "【分析】求几个相同加数的和，可以用乘法计算，用相同加数×个数或个数×相同加数。求一个数和另一个数的和，用加法计算，即一个数 + 另一个数 = 它们的和，由此解答.\n【详解】3×5 = 15;7 + 8 = 15,3 个 5 相加的和是15;7 和 8 相加的和是15。",
+    "knowledge_points": [
+      "7,6加几的进位加法",
+      "初步认识乘法意义",
+      "5的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·广东肇庆·期末"
+  },
+  {
+    "id": "71",
+    "unit": "第四单元 表内乘法",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "一根绳子对折两次后的长度是 3 厘米，这根绳子原来长( )厘米。",
+    "options": [],
+    "answer": "12",
+    "solution": "【分析】一根绳子对折1次后折成2段，对折2次后折成4段，每段长3厘米，用每段的长度乘段数来求出绳子原来的长度.\n【详解】2×2 = 4(段),3×4 = 12(厘米),即，一根绳子对折两次后的长度是 3 厘米，这根绳子原来长12 厘米。",
+    "knowledge_points": [
+      "2 的乘法口诀及应用",
+      "4 的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·河北保定·期末"
+  },
+  {
+    "id": "72",
+    "unit": "第四单元 表内乘法",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "元元和五个小伙伴每人都有 6 枚邮票，他们共有( )枚邮票。",
+    "options": [],
+    "answer": "36",
+    "solution": "【分析】根据题意，先用加法计算出一共有多少人，再用每人有邮票的数量和人数相乘，就是邮票的总数量.\n【详解】5 + 1 = 6(人),6×6 = 36(枚),元元和五个小伙伴每人都有 6 枚邮票，他们共有 36 枚邮票。",
+    "knowledge_points": [
+      "6 的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·湖南湘西·期末"
+  },
+  {
+    "id": "73",
+    "unit": "第四单元 表内乘法",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "1只蚂蚁6条腿,6只蚂蚁( )条腿。",
+    "options": [],
+    "answer": "36",
+    "solution": "【分析】用蚂蚁的只数乘 1 只蚂蚁的腿的条数，即可求出 6只蚂蚁一共有多少条腿，根据\"六六三十六\"解答.\n【详解】6×6 = 36(条),1 只蚂蚁 6 条腿,6 只蚂蚁 36 条腿。",
+    "knowledge_points": [
+      "6 的乘法口诀及应用"
+    ],
+    "source": "24-25二年级上·湖南长沙·期末"
+  },
+  {
+    "id": "74",
+    "unit": "第四单元 表内乘法",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "同学们排队做操，每行站 9 人，站了 4 行，一共有( )人做操。写成加法算式是( ),写成乘法算式是( )。",
+    "options": [],
+    "answer": "36;9 + 9 + 9 + 9 = 36(人);9×4 = 36(人)或4×9 = 36(人)",
+    "solution": "【分析】将每行的人数加起来即可算出总人数。将几个相同加数相加，可以写成加数与个数相乘的形式。乘法算式中两个乘数是口诀中的前两个数，积是口诀中的后一个数，写算式时两个乘数可互换位置.\n【详解】9 + 9 + 9 + 9 = 36(人),同学们排队做操，每行站 9 人，站了 4 行，一共有 36 人做操。写成加法算式是 9 + 9 + 9 + 9 = 36(人),写成乘法算式是 9×4 = 36(人)或 4×9 = 36(人)。",
+    "knowledge_points": [
+      "同数连加的应用",
+      "初步认识乘法意义",
+      "乘法的简单应用(应用加法计算结果)"
+    ],
+    "source": "24-25二年级上·湖南株洲·期末"
+  },
+  {
+    "id": "75",
+    "unit": "第四单元 表内乘法",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "括号里最大能填几.\n5×( ) < 16;14 > 4×( );( ) + 28 < 56",
+    "options": [],
+    "answer": "3;3;27",
+    "solution": "【分析】整数的大小比较：比较数的大小，先看位数的多少，位数多的数就大;位数相同，从高位开始比较，高位上的数大则这个数大，高位上的数相同，就比较下一位。乘法算式中两个乘数是口诀中的前两个数，积是口诀中的后一个数，写算式时两个乘数可互换位置。前两个小题根据数的大小关系和乘法口诀填空。第三空：先把小于号看作等号，算出另一个加数，然后减去1即可.\n【详解】三五十五，四五二十，最大填3,5×3 < 16;三四十二，四四十六，最大填3,14 > 4×3;56 - 28 = 28,28 - 1 = 27，所以 27 + 28 < 56。",
+    "knowledge_points": [
+      "100以内数的比大小",
+      "两位数与两位数的退位减法",
+      "5 的乘法口诀及应用",
+      "4 的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·浙江宁波·期末"
+  },
+  {
+    "id": "76",
+    "unit": "第四单元 表内乘法",
+    "question_type": "判断题",
+    "difficulty": 0.65,
+    "question": "4×5 表示 4 个 5 相加或 5 个 4 相加。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】乘法算式的意义：几个相同加数的和可以用乘法来算，乘法算式表示几个几相加。据此解答.\n【详解】由分析可得:4×5 表示 5 个 4 相加，也可以表示 4 个 5 相加。故答案为:√",
+    "knowledge_points": [
+      "初步认识乘法意义"
+    ],
+    "source": "24-25 二年级下·贵州铜仁·期末"
+  },
+  {
+    "id": "77",
+    "unit": "第四单元 表内乘法",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "在 5 的乘法口诀里，前一句和后一句的得数相差 5。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】5 的乘法口诀中，每相邻两句的乘数依次增加1，因此得数相差一个5。例如:1×5 = 5，下一句 2×5 = 10,10 - 5 = 5;2×5 = 10，下一句 3×5 = 15,15 - 10 = 5。以此类推，所有相邻两句的得数均相差5.\n【详解】据分析可得：在5的乘法口诀里，前一句和后一句的得数相差5。题干表述正确。故答案为:√",
+    "knowledge_points": [
+      "初步认识乘法意义",
+      "5 的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·河南三门峡·期末"
+  },
+  {
+    "id": "78",
+    "unit": "第四单元 表内乘法",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "2 + 3×5 = 25。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】整数混合运算中，同级运算时，从左到右依次计算;两级运算时，先算乘除，后算加减.\n【详解】2 + 3×5 = 2 + 15 = 17，原题说法错误。故答案为: ×",
+    "knowledge_points": [
+      "表内乘加，乘减"
+    ],
+    "source": "24-25 二年级上·河南南阳·期末"
+  },
+  {
+    "id": "79",
+    "unit": "第四单元 表内乘法",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "因为 2 + 2 = 2×2，所以 1 + 1 = 1×1。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】几个相同加数相加，可以写成加数与个数相乘的形式，写算式时两个乘数可互换位置.\n【详解】2 + 2 = 2×2 成立，是因为 2 + 2 表示 2 个 2 相加;而 1 + 1 表示 2 个 1 相加，与 1×1(1 个 1)不同，所以 1 + 1 != 1×1。原题说法错误。故答案为: ×",
+    "knowledge_points": [
+      "同数连加的应用",
+      "初步认识乘法意义"
+    ],
+    "source": "24-25 二年级上·广东肇庆·期末"
+  },
+  {
+    "id": "80",
+    "unit": "第四单元 表内乘法",
+    "question_type": "判断题",
+    "difficulty": 0.65,
+    "question": "5×6 的积比 4×6 的积多 1。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】分别算出 5×6 和 4×6 的积，再比较两个积的差.\n【详解】5×6 = 30,4×6 = 24,30 - 24 = 6，所以 5×6 的积比 4×6 的积多 6，不是多 1。原题说法错误。故答案为: ×",
+    "knowledge_points": [
+      "表内乘加，乘减",
+      "6 的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·全国·课堂作业"
+  },
+  {
+    "id": "81",
+    "unit": "第四单元 表内乘法",
+    "question_type": "判断题",
+    "difficulty": 0.65,
+    "question": "5 个 5 的和是 25。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】5 个 5 的和表示 5 + 5 + 5 + 5 + 5，可以用乘法 5×5 来计算.\n【详解】5×5 = 25，所以 5 个 5 的和是 25。原题说法正确。故答案为:√",
+    "knowledge_points": [
+      "同数连加的应用",
+      "5 的乘法口诀及应用"
+    ],
+    "source": "23-24 二年级上·全国·课后作业"
+  },
+  {
+    "id": "82",
+    "unit": "第四单元 表内乘法",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "3 + 3 + 3 + 3 = 3×4。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】几个相同加数相加可以写成乘法算式，相同加数是乘法算式的一个乘数，加数的个数是另一个乘数.\n【详解】3 + 3 + 3 + 3 表示 4 个 3 相加，可写成 3×4 或 4×3.3×4 = 12，与 3 + 3 + 3 + 3 的和相等。原题说法正确。故答案为:√",
+    "knowledge_points": [
+      "同数连加的应用",
+      "初步认识乘法意义"
+    ],
+    "source": "23-24 二年级上·全国·单元测试"
+  },
+  {
+    "id": "83",
+    "unit": "第四单元 表内乘法",
+    "question_type": "判断题",
+    "difficulty": 0.65,
+    "question": "4×3 和 3×4 的积相同。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】乘法中两个乘数可以交换位置，积不变，这个性质叫乘法交换律.\n【详解】4×3 = 12,3×4 = 12，二者的积相同。原题说法正确。故答案为:√",
+    "knowledge_points": [
+      "初步认识乘法意义"
+    ],
+    "source": "20-21 二年级上·全国·课堂练习"
+  },
+  {
+    "id": "84",
+    "unit": "第四单元 表内乘法",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "6×5 = 5×6。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】根据乘法交换律，两个乘数交换位置，积不变.\n【详解】6×5 = 30,5×6 = 30，二者相等。原题说法正确。故答案为:√",
+    "knowledge_points": [
+      "初步认识乘法意义",
+      "5 的乘法口诀及应用",
+      "6 的乘法口诀及应用"
+    ],
+    "source": "23-24 二年级上·全国·课堂练习"
+  },
+  {
+    "id": "85",
+    "unit": "第四单元 表内乘法",
+    "question_type": "判断题",
+    "difficulty": 0.65,
+    "question": "5×4 + 4 表示 5 个 4 相加的和。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】5×4 表示 5 个 4 的和，再加 4 表示 6 个 4 的和.\n【详解】5×4 + 4 = 4 + 4 + 4 + 4 + 4 + 4，是 6 个 4 的和，而不是 5 个 4 的和。原题说法错误。故答案为: ×",
+    "knowledge_points": [
+      "表内乘加，乘减",
+      "初步认识乘法意义"
+    ],
+    "source": "23-24 二年级上·全国·练习题"
+  },
+  {
+    "id": "86",
+    "unit": "第四单元 表内乘法",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "2×6 和 3×4 的积相等。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】分别计算两个乘法算式的积，进行比较即可.\n【详解】2×6 = 12,3×4 = 12，积相等。原题说法正确。故答案为:√",
+    "knowledge_points": [
+      "4 的乘法口诀及应用",
+      "6 的乘法口诀及应用"
+    ],
+    "source": "20-21 二年级上·全国·作业本"
+  },
+  {
+    "id": "87",
+    "unit": "第四单元 表内乘法",
+    "question_type": "判断题",
+    "difficulty": 0.65,
+    "question": "3×5 的积比 2×5 的积大 5。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】分别求出两个乘法算式的积，再计算它们的差.\n【详解】3×5 = 15,2×5 = 10,15 - 10 = 5，所以 3×5 的积比 2×5 的积大 5。原题说法正确。故答案为:√",
+    "knowledge_points": [
+      "5 的乘法口诀及应用",
+      "表内乘加，乘减"
+    ],
+    "source": "24-25 二年级上·全国·课堂练习"
+  },
+  {
+    "id": "88",
+    "unit": "第四单元 表内乘法",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "因为 2×5 = 10，所以 10 里面有 2 个 5。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】2×5 = 10 表示 2 个 5 的和是 10，也说明 10 里面正好有 2 个 5.\n【详解】因为 2×5 = 10，所以 10 里面有 2 个 5。原题说法正确。故答案为:√",
+    "knowledge_points": [
+      "初步认识乘法意义"
+    ],
+    "source": "23-24 二年级上·全国·作业本"
+  },
+  {
+    "id": "89",
+    "unit": "第四单元 表内乘法",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "把 20 个苹果平均分成 5 份，每份 4 个苹果。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】平均分成 5 份，就是用总数 20 除以 5，求出每份有几个.\n【详解】20÷5 = 4(个),所以把 20 个苹果平均分成 5 份，每份 4 个苹果。原题说法正确。故答案为:√",
+    "knowledge_points": [
+      "平均分",
+      "表内乘除关系"
+    ],
+    "source": "24-25 二年级上·全国·单元测试"
+  },
+  {
+    "id": "90",
+    "unit": "第四单元 表内乘法",
+    "question_type": "判断题",
+    "difficulty": 0.65,
+    "question": "3×5 = 5×3，所以 3 个 5 和 5 个 3 的和相等。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】3 个 5 的和为 5 + 5 + 5，对应 3×5;5 个 3 的和为 3 + 3 + 3 + 3 + 3，对应 5×3。因为 3×5 = 5×3.\n【详解】3×5 = 15,5×3 = 15，两个乘法算式的积相等，因此 3 个 5 的和与 5 个 3 的和相等。原题说法正确。故答案为:√",
+    "knowledge_points": [
+      "同数连加的应用",
+      "初步认识乘法意义"
+    ],
+    "source": "24-25 二年级上·全国·课堂练习"
+  },
+  {
+    "id": "91",
+    "unit": "第四单元 表内乘法",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "4×5 的积比 4×4 的积多 5。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】分别计算 4×5 和 4×4 的积，然后比较差.\n【详解】4×5 = 20,4×4 = 16,20 - 16 = 4，不是 5。原题说法错误。故答案为: ×",
+    "knowledge_points": [
+      "表内乘加，乘减",
+      "4 的乘法口诀及应用",
+      "5 的乘法口诀及应用"
+    ],
+    "source": "23-24 二年级上·全国·测试题"
+  },
+  {
+    "id": "92",
+    "unit": "第四单元 表内乘法",
+    "question_type": "判断题",
+    "difficulty": 0.65,
+    "question": "一支铅笔 5 元，买 3 支同样的铅笔，一共要 15 元。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】根据总价=单价×数量，用一支铅笔的价钱乘3即可.\n【详解】5×3 = 15(元),所以一支铅笔 5 元，买 3 支同样的铅笔，一共要 15 元。原题说法正确。故答案为:√",
+    "knowledge_points": [
+      "经济问题",
+      "5 的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·全国·练习"
+  },
+  {
+    "id": "93",
+    "unit": "第四单元 表内乘法",
+    "question_type": "判断题",
+    "difficulty": 0.65,
+    "question": "\"四五二十\"表示 4 个 5 相加或 5 个 4 相加。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】乘法口诀\"四五二十\"对应算式 4×5 或 5×4，分别表示 4 个 5 的和和 5 个 4 的和.\n【详解】4×5 = 5 + 5 + 5 + 5,5×4 = 4 + 4 + 4 + 4 + 4，二者的积都是 20。原题说法正确。故答案为:√",
+    "knowledge_points": [
+      "初步认识乘法意义",
+      "5 的乘法口诀及应用"
+    ],
+    "source": "23-24 二年级上·全国·课后作业"
+  },
+  {
+    "id": "94",
+    "unit": "第四单元 表内乘法",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "\"五五二十五\"表示 5 个 5 相加的和是 25。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】乘法口诀\"五五二十五\"对应乘法算式 5×5 = 25，表示 5 个 5 相加的和.\n【详解】5×5 = 25，表示 5 + 5 + 5 + 5 + 5 的和是 25。原题说法正确。故答案为:√",
+    "knowledge_points": [
+      "同数连加的应用",
+      "5 的乘法口诀及应用"
+    ],
+    "source": "20-21 二年级上·全国·单元测试"
+  },
+  {
+    "id": "95",
+    "unit": "第四单元 表内乘法",
+    "question_type": "判断题",
+    "difficulty": 0.65,
+    "question": "一个数乘 5，积一定是 5 的倍数。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】乘法中，一个因数是 5，另一个是整数时，积一定含有因数 5，因此是 5 的倍数.\n【详解】设整数 a,与 5 相乘为 5×a,5×a 一定可以被 5 整除，说明它是 5 的倍数。原题说法正确。故答案为:√",
+    "knowledge_points": [
+      "5 的乘法口诀及应用",
+      "倍数的直观认识"
+    ],
+    "source": "24-25 二年级上·全国·练习"
+  },
+  {
+    "id": "96",
+    "unit": "第四单元 表内乘法",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "一个数乘 6 的积一定是偶数。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】6 是偶数，偶数乘任何整数，积都是偶数.\n【详解】设整数 a,与 6 相乘为 6×a,因为 6 可以表示为 2×3，所以 6×a = 2×(3a),积中含有因数 2，因此一定是偶数。原题说法正确。故答案为:√",
+    "knowledge_points": [
+      "6 的乘法口诀及应用",
+      "偶数与奇数"
+    ],
+    "source": "23-24 二年级上·全国·课后作业"
+  },
+  {
+    "id": "97",
+    "unit": "第四单元 表内乘法",
+    "question_type": "判断题",
+    "difficulty": 0.65,
+    "question": "5×4 和 4×5 的得数相同。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】根据乘法交换律，两个乘数交换位置，积不变.\n【详解】5×4 = 20,4×5 = 20，二者得数相同。原题说法正确。故答案为:√",
+    "knowledge_points": [
+      "初步认识乘法意义",
+      "5 的乘法口诀及应用",
+      "4 的乘法口诀及应用"
+    ],
+    "source": "18-19 二年级上·全国·单元测试"
+  },
+  {
+    "id": "98",
+    "unit": "第四单元 表内乘法",
+    "question_type": "判断题",
+    "difficulty": 0.65,
+    "question": "3×5 比 5×3 多。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】计算两个乘法算式的积进行比较.\n【详解】3×5 = 15,5×3 = 15，二者相等，并没有谁多谁少。原题说法错误。故答案为: ×",
+    "knowledge_points": [
+      "初步认识乘法意义",
+      "5 的乘法口诀及应用"
+    ],
+    "source": "20-21 二年级上·全国·课堂练习"
+  },
+  {
+    "id": "99",
+    "unit": "第四单元 表内乘法",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "6×5 的得数一定比 5×5 的得数大。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】分别计算 6×5 和 5×5 的积，再比较大小即可.\n【详解】6×5 = 30,5×5 = 25,30 > 25，所以 6×5 的得数比 5×5 的得数大。原题说法正确。故答案为:√",
+    "knowledge_points": [
+      "5 的乘法口诀及应用",
+      "6 的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·全国·单元测试"
+  },
+  {
+    "id": "100",
+    "unit": "第四单元 表内乘法",
+    "question_type": "判断题",
+    "difficulty": 0.65,
+    "question": "3×6 = 2×9。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】分别计算两个乘法算式的积进行比较.\n【详解】3×6 = 18,2×9 = 18，二者相等。原题说法正确。故答案为:√",
+    "knowledge_points": [
+      "6 的乘法口诀及应用",
+      "9 的乘法口诀及应用"
+    ],
+    "source": "23-24 二年级上·全国·课后作业"
+  },
+  {
+    "id": "101",
+    "unit": "第四单元 表内乘法",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "7×4 不能表示( )。",
+    "options": [
+      "A. 4 个 7 相加",
+      "B. 7 和 4 相加",
+      "C. 7 个 4 相加"
+    ],
+    "answer": "B",
+    "solution": "【分析】乘法算式表示几个相同加数的和，若前一个乘数是相同加数，则后一个乘数是相同加数的个数;若前一个乘数是相同加数的个数，则后一个乘数是相同加数。由此解答.\n【详解】A。4 个 7 相加可以用 7×4 表示;B。7 和 4 相加列式为 7 + 4，不能用 7×4 表示;C。7 个 4 相加可以用 7×4 表示。所以 7×4 不能表示 7 和 4 相加。故答案为:B",
+    "knowledge_points": [
+      "7,6 加几的进位加法",
+      "初步认识乘法意义"
+    ],
+    "source": "24-25 二年级上·河南郑州·期末"
+  },
+  {
+    "id": "102",
+    "unit": "第四单元 表内乘法",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "小猴子每天吃 6 块糖,5 天吃了( )块糖。",
+    "options": [
+      "A. 11",
+      "B. 30",
+      "C. 12"
+    ],
+    "answer": "B",
+    "solution": "【分析】小猴子每天吃 6 块糖，求 5 天吃了多少块糖，就是求 5 个 6 的和是多少，用乘法列式解决.\n【详解】5×6 = 30(块),即，小猴子每天吃 6 块糖,5 天吃了 30 块糖。故答案为:B",
+    "knowledge_points": [
+      "6的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·江西南昌·期末"
+  },
+  {
+    "id": "103",
+    "unit": "第四单元 表内乘法",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "5 个 6 的和是多少，列式为( )。",
+    "options": [
+      "A. 6 + 5",
+      "B. 6×5",
+      "C. 5 + 6"
+    ],
+    "answer": "B",
+    "solution": "【分析】根据乘法的意义可知，求几个相同加数的和是多少，可以用乘法列式解决。故，求 5 个 6 的和是多少，列式为:6×5 或 5×6.\n【详解】由题意分析得:5 个 6 的和是多少，列式为:6×5。故答案为:B",
+    "knowledge_points": [
+      "初步认识乘法意义"
+    ],
+    "source": "24-25二年级上·江西南昌·期末"
+  },
+  {
+    "id": "104",
+    "unit": "第四单元 表内乘法",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面的算式中，不能直接改写成乘法算式的是( )。",
+    "options": [
+      "A. 6 + 6 + 6 + 6 + 6",
+      "B. 8 + 8 + 5 + 5",
+      "C. 15 + 15 + 15"
+    ],
+    "answer": "B",
+    "solution": "【分析】根据乘法的意义来解决此题。乘法的意义：求几个相同加数的和是多少，可以用乘法简便计算.\n【详解】A。6 + 6 + 6 + 6 + 6 = 6×5;B。8 + 8 + 5 + 5 = 8×2 + 5×2;C。15 + 15 + 15 = 15×3。即，不能直接改写成乘法算式的是 (8 + 8 + 5 + 5)。故答案为:B",
+    "knowledge_points": [
+      "初步认识乘法意义"
+    ],
+    "source": "24-25二年级上·河南郑州·期末"
+  },
+  {
+    "id": "105",
+    "unit": "第四单元 表内乘法",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "求5个6是多少，算式是( )。",
+    "options": [
+      "A. 6 + 6 + 6 + 6",
+      "B. 5 + 6",
+      "C. 5×6"
+    ],
+    "answer": "C",
+    "solution": "【分析】求几个相同加数的和用乘法计算，据此解答即可.\n【详解】根据分析可知，求 5 个 6 是多少。用乘法表示是 5×6。故答案为:C",
+    "knowledge_points": [
+      "初步认识乘法意义"
+    ],
+    "source": "24-25二年级上·辽宁抚顺·期末"
+  },
+  {
+    "id": "106",
+    "unit": "第四单元 表内乘法",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "能用算式 3×6 = 18 解决的实际问题是( )。",
+    "options": [
+      "A. ①②",
+      "B. ①③",
+      "C. ②③"
+    ],
+    "answer": "B",
+    "solution": "题干实际问题:①每盒牛奶有6瓶,3盒有多少瓶。②一个货架放 6 罐饮料，另一个货架有 3 罐饮料，共有多少罐饮料。③蚂蚁一分钟可以爬 6 米,3 分钟可以爬多少米。\n【分析】①每盒牛奶的数量乘盒数，等于一共有多少瓶，算式:3×6 = 18(瓶),能用算式 3×6 = 18 解答问题;②一个货架的数量加上另一个货架的数量，算式 6 + 3 = 9(罐),不能用 3×6 = 18 解决问题;③蚂蚁一分钟爬 6 米,3 分钟可以爬多少米，列式 3×6 = 18(米),能用算式 3×6 = 18 解答问题.\n【详解】根据分析可得:①③可以用算式 3×6 = 18 解决的实际问题。故答案为:B",
+    "knowledge_points": [
+      "9以内加减法实际应用",
+      "初步认识乘法意义",
+      "6的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·湖北襄阳·期末"
+  },
+  {
+    "id": "107",
+    "unit": "第四单元 表内乘法",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面算式中，列式不正确的是( ).\n\n![](images/ea8a1254745c64b3b2189e9fbedbf2ce7c30a356fbf095193e7fb0fccfe8338e.jpg)\n![](images/4985e0672ee4c8c2d60effc16e97f21cdf672a6791597eacd0bfb2790633137c.jpg)\n![](images/4deb0d3cac3b2a2fd60a2ee108104575b929a5e79c8ac1461cc0795835b0813b.jpg)",
+    "options": [
+      "A. 5×3 - 1",
+      "B. 5×3 + 4",
+      "C. 5×2 + 4"
+    ],
+    "answer": "B",
+    "solution": "【分析】一组碗有 5 个，先用乘法求出 3 组这样的碗有几个，然后减去 1 个，据此列出算式求出结果，就是一共的碗数量，即 5×3 - 1;一组碗有 5 个，先用乘法求出 2 组这样的碗有几个，然后加上 4 个，据此列出算式求出结果，也是一共的碗数量，即 5×2 + 4;据此解决.\n【详解】A。图中的碗数量可以看作是 3 个 5 减 1，列式为 5×3 - 1 是正确的;B。5×3 + 4 表示图中的碗数量可以看作 3 个 5 加 4，与图不符，这是不正确的列式;C。图中的碗数量可以看作是 2 个 5 加 4，列式为 5×2 + 4 是正确的。即，这些算式中，列式不正确的是 5×3 + 4。故答案为:B",
+    "knowledge_points": [
+      "图文问题",
+      "表内乘加，乘减"
+    ],
+    "source": "24-25 二年级上·四川南充·期末"
+  },
+  {
+    "id": "108",
+    "unit": "第四单元 表内乘法",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "小红和4个好朋友栽树，每人栽 4 棵，一共栽( )棵。",
+    "options": [
+      "A. 5",
+      "B. 16",
+      "C. 20"
+    ],
+    "answer": "C",
+    "solution": "【分析】小红和 4 个好朋友栽树，也就是一共有 5 人，每人栽 4 棵，求一共栽多少棵，就是求 5 个 4 的和是多少，用乘法列式解决.\n【详解】1 + 4 = 5(人),4×5 = 20(棵),即，小红和 4 个好朋友栽树，每人栽 4 棵，一共栽 20 棵。故答案为:C",
+    "knowledge_points": [
+      "5 的乘法口诀及应用"
+    ],
+    "source": "23-24二年级上·浙江杭州·期末"
+  },
+  {
+    "id": "109",
+    "unit": "第四单元 表内乘法",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "一个乘数是 6，另一个乘数是 3，积是( )。",
+    "options": [
+      "A. 18",
+      "B. 9",
+      "C. 2"
+    ],
+    "answer": "A",
+    "solution": "【分析】根据\"乘数×乘数 = 积\"及表内口诀来解决此题即可.\n【详解】6×3 = 18，即，一个乘数是 6，另一个乘数是 3，积是 18。故答案为:A",
+    "knowledge_points": [
+      "6的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·江西抚州·期末"
+  },
+  {
+    "id": "110",
+    "unit": "第四单元 表内乘法",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "求 4 个 3 相加的和列成加法算式是( )。",
+    "options": [
+      "A. 4 + 4 + 4",
+      "B. 3 + 3 + 3 + 3",
+      "C. 3×4"
+    ],
+    "answer": "B",
+    "solution": "【分析】4 个 3 相加，相同加数是 3，个数是 4 个，由此列算式即可.\n【详解】A。4 + 4 + 4 表示 3 个 4 的和，不符合题意;B。3 + 3 + 3 + 3 表示 4 个 3 的和，符合题意;C。3×4 是乘法算式，不符合题意。求 4 个 3 列成加法算式是 3 + 3 + 3 + 3。故答案为:B",
+    "knowledge_points": [
+      "同数连加的应用",
+      "初步认识乘法意义"
+    ],
+    "source": "24-25 二年级上·河南南阳·期末"
+  },
+  {
+    "id": "111",
+    "unit": "第四单元 表内乘法",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "6 + 6 + 6 + 3 + 3 不可以改写成( )。",
+    "options": [
+      "A. 6×5",
+      "B. 3×8",
+      "C. 4×6"
+    ],
+    "answer": "A",
+    "solution": "【分析】乘法的意义，求几个相同加数的和是多少，可以用乘法简便计算。6 = 3 + 3，则 6 + 6 + 6 + 3 + 3 = 3 + 3 + 3 + 3 + 3 + 3 + 3 + 3，是 8 个 3 的和，可写成 3×8;也可以看成 6 + 6 + 6 + 6，是 4 个 6 的和，可写成 4×6.\n【详解】A。6×5 = 6 + 6 + 6 + 6 + 6，表示 5 个 6 的和;B。6 + 6 + 6 + 3 + 3 可以化为 3×8;C。6 + 6 + 6 + 3 + 3 可以化为 4×6。即,6 + 6 + 6 + 3 + 3 不可以改写成 6×5。故答案为:A",
+    "knowledge_points": [
+      "初步认识乘法意义"
+    ],
+    "source": "24-25 二年级上·河南南阳·期末"
+  },
+  {
+    "id": "112",
+    "unit": "第四单元 表内乘法",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "3 个 5 相加，和是多少。列式错误的是( )。",
+    "options": [
+      "A. 5 + 5 + 5",
+      "B. 3 + 5",
+      "C. 5×3"
+    ],
+    "answer": "B",
+    "solution": "【分析】求 3 个 5 相加的和是多少，用加法计算列式为 5 + 5 + 5，用乘法计算列式为 3×5 或 5×3，据此判断选择即可.\n【详解】A。5 + 5 + 5 表示 3 个 5 相加的和是多少，列式正确;B。3 + 5 表示 3 和 5 的和，不能表示 3 个 5 相加的和，列式错误;C。5×3 表示 3 个 5 相加的和，列式正确。故答案为:B",
+    "knowledge_points": [
+      "同数连加的应用",
+      "初步认识乘法意义"
+    ],
+    "source": "24-25 二年级上·广东江门·期末"
+  },
+  {
+    "id": "113",
+    "unit": "第四单元 表内乘法",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "算式 4×6 不能表示的加法算式是( )。",
+    "options": [
+      "A. 6 + 6 + 6 + 6",
+      "B. 4 + 6",
+      "C. 4 + 4 + 4 + 4 + 4 + 4"
+    ],
+    "answer": "B",
+    "solution": "【分析】根据乘法的意义，求几个相同加数的和的简便运算。4×6 可以表示 4 个 6 或 6 个 4 相加的和是多少.\n【详解】A。6 + 6 + 6 + 6 表示 4 个 6 相加的和是多少，即 4×6;B。4 + 6 表示 4 和 6 相加的和是多少;C。4 + 4 + 4 + 4 + 4 + 4 表示 6 个 4 相加的和是多少，即 4×6。故答案为:B",
+    "knowledge_points": [
+      "同数连加的应用",
+      "初步认识乘法意义"
+    ],
+    "source": "24-25二年级上·河北保定·期末"
+  },
+  {
+    "id": "114",
+    "unit": "第四单元 表内乘法",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "求3个5的和，正确的是( )。",
+    "options": [
+      "A. 3 + 5",
+      "B. 3 + 3 + 3 + 3 + 3",
+      "C. 3×5"
+    ],
+    "answer": "C",
+    "solution": "【分析】两个数相加，表示求这两个数的和;几个相同的数连加，表示求几个相同加数的和;两个数相乘，可以表示几个相同加数的和;据此解决.\n【详解】A。3 + 5 是求 3 与 5 的和;B。3 + 3 + 3 + 3 + 3 是求 5 个 3 的和;C。3×5 可以表示求 3 个 5 的和或 5 个 3 的和。即，求 3 个 5 的和，正确的是 3×5。故答案为:C",
+    "knowledge_points": [
+      "同数连加的应用",
+      "初步认识乘法意义"
+    ],
+    "source": "23-24二年级上·浙江·期末"
+  },
+  {
+    "id": "115",
+    "unit": "第四单元 表内乘法",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "用画图的方法表示 3×2，不正确的是( )。",
+    "options": [
+      "A. 图 A",
+      "B. 图 B",
+      "C. 图 C"
+    ],
+    "answer": "A",
+    "solution": "【分析】乘法算式可以表示几个相同加数的和，用相同加数×个数或个数×相同加数，由此解答.\n【详解】3×2 表示 2 个 3 的和或 3 个 2 的和。A。图表示 3 和 2 的和，与算式不符;B。表示 2 个 3 的和，与算式相符;C。表示 3 个 2 的和，与算式相符。所以用画图的方法表示 3×2，不正确的是 A。故答案为:A",
+    "knowledge_points": [
+      "初步认识乘法意义"
+    ],
+    "source": "24-25 二年级上·内蒙古巴彦淖尔·期末"
+  },
+  {
+    "id": "116",
+    "unit": "第四单元 表内乘法",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "与\"8×4\"意义不相同的算式是( )。",
+    "options": [
+      "A. 4×7 + 4",
+      "B. 8×3 + 1",
+      "C. 8 + 8 + 8 + 8"
+    ],
+    "answer": "B",
+    "solution": "【分析】8×4 表示 4 个 8 相加的和，或 8 个 4 相加的和.\n【详解】A。4×7 + 4 表示 7 个 4 相加的和再加 4，即 8 个 4 相加的和，与 8×4 同义;B。8×3 + 1 表示 3 个 8 相加的和再加 1，或 8 个 3 相加的和再加 1，与\"4 个 8 或 8 个 4\"不相同;C。8 + 8 + 8 + 8 表示 4 个 8 相加的和，与 8×4 同义。故意义不相同的是:B。答案为:B",
+    "knowledge_points": [
+      "同数连加的应用",
+      "初步认识乘法意义"
+    ],
+    "source": "24-25 二年级上·河南开封·期末"
+  },
+  {
+    "id": "117",
+    "unit": "第四单元 表内乘法",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "下面图形中，能用 4×3 表示的是( ).\n\nA。 ![](images/2026-02-24%20230248.jpg)\nB。 ![](images/2026-02-24%20230303.jpg)\nC。 ![](images/4efd1c5f1a974ad47bb629948257e58ab29ef3b6ff57310cfd25e3a34f2c08fe.jpg)",
+    "options": [
+      "A. 图 A",
+      "B. 图 B",
+      "C. 图 C"
+    ],
+    "answer": "C",
+    "solution": "【分析】4×3 表示 4 个 3 相加的和，列式:3 + 3 + 3 + 3，或 3 个 4 相加的和，列式:4 + 4 + 4.\n【详解】A。表示 2 个 4，列式 2×4 或 4×2;B。表示 2 个 3，列式 2×3 或 3×2;C。表示 4 个 3，列式 4×3 或 3×4，能用 4×3 表示的是图 C。故答案为:C",
+    "knowledge_points": [
+      "初步认识乘法意义"
+    ],
+    "source": "24-25 二年级上·陕西西安·期末"
+  },
+  {
+    "id": "118",
+    "unit": "第四单元 表内乘法",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "求\"3 个 7 相加的和是多少\"，列式错误的是( )。",
+    "options": [
+      "A. 7×3",
+      "B. 7+3",
+      "C. 7+7+7"
+    ],
+    "answer": "B",
+    "solution": "【分析】求几个相同加数的和的简便运算，可以用加法列式计算，也可以用乘法列式计算.\n【详解】求\"3个7相加的和是多少\"用加法列式:7 + 7 + 7，用乘法列式:7×3。所以列式错误的是 7 + 3。故答案为:B",
+    "knowledge_points": [
+      "同数连加的应用",
+      "初步认识乘法意义"
+    ],
+    "source": "24-25 二年级上·河北邯郸·期末"
+  },
+  {
+    "id": "119",
+    "unit": "第四单元 表内乘法",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "如图所示，这个正方体盒子一共有( )个直角.\n\n![](images/a26fc664443aff49ea036b6fdbba09c27b7dc42697df3c3055118d639ce9df70.jpg)",
+    "options": [
+      "A. 12",
+      "B. 4",
+      "C. 24"
+    ],
+    "answer": "C",
+    "solution": "【分析】角由一个顶点和两条边组成，和书本，黑板的角相同大小的角是直角。正方体是方方正正的，每个面都是正方形。每个正方形有 4 个直角，求一个正方体一共有多少个直角，也就是求 6 个 4 的和是多少，用乘法计算，每个面直角的数量和面数相乘，就是直角的总数量.\n【详解】4×6 = 24(个),这个正方体盒子一共有 24 个直角。故答案为:C",
+    "knowledge_points": [
+      "6的乘法口诀及应用",
+      "角的初步认识及辨认"
+    ],
+    "source": "24-25 二年级上·河北邯郸·期末"
+  },
+  {
+    "id": "120",
+    "unit": "第四单元 表内乘法",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面不能用\"3×2\"表示的图是( ).\n\nA。 ![](images/2026-02-24%20230614.jpg)\nB。 ![](images/2026-02-24%20230626.jpg)\nC。 ![](images/2026-02-24%20230635.jpg)",
+    "options": [
+      "A. 图 A",
+      "B. 图 B",
+      "C. 图 C"
+    ],
+    "answer": "C",
+    "solution": "【分析】乘法算式中，两个乘数表示每份的数量和份数，积表示总数。3×2 可以表示 3 个 2 的和或者 2 个 3 的和.\n【详解】A。表示 2 个 3 的和，可以用\"3×2\"表示;B。表示 3 个 2 的和，可以用\"3×2\"表示;C。表示 3 和 2 的和，不能用\"3×2\"表示。不能用\"3×2\"表示的图是 C。故答案为:C",
+    "knowledge_points": [
+      "5以内数的加法",
+      "初步认识乘法意义"
+    ],
+    "source": "24-25 二年级上·河南周口·期末"
+  },
+  {
+    "id": "121",
+    "unit": "第四单元 表内乘法",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "书店促销，标价如下表。李老师买了几本故事书和科技书，根据算式 10×2 + 3×8，我们可以知道李老师一共买了( )本书.\n\n<table><tr><td>类型</td><td>故事书</td><td>参考书</td><td>科技书</td></tr><tr><td>每本价格(元)</td><td>10</td><td>7</td><td>8</td></tr></table>",
+    "options": [
+      "A. 10",
+      "B. 8",
+      "C. 5"
+    ],
+    "answer": "C",
+    "solution": "【分析】根据算式 10×2 + 3×8 可知，李老师买了 2 本故事书和 3 本科技书，将两种书的数量相加，即可求出李老师一共买了多少本书.\n【详解】2 + 3 = 5(本),李老师一共买了 5 本书。故答案为:C",
+    "knowledge_points": [
+      "初步认识乘法意义"
+    ],
+    "source": "24-25 二年级上·吉林·期末"
+  },
+  {
+    "id": "122",
+    "unit": "第四单元 表内乘法",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "一首唐诗有 4 行，每行有 5 个字，这首唐诗一共有( )个字。",
+    "options": [
+      "A. 9",
+      "B. 15",
+      "C. 20"
+    ],
+    "answer": "C",
+    "solution": "【分析】唐诗有 4 行，每行有 5 个字，求这首唐诗一共有多少个字，即求 4 个 5 相加是多少，用 4×5 即可.\n【详解】4×5 = 20(个),所以这首唐诗一共有 20 个字。故答案为:C",
+    "knowledge_points": [
+      "初步认识乘法意义",
+      "5 的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·全国·期末"
+  },
+  {
+    "id": "123",
+    "unit": "第四单元 表内乘法",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "把一根彩带每4米剪成一段，剪了 4 段还多 2 米，这根彩带原来长( )米。",
+    "options": [],
+    "answer": "18",
+    "solution": "【分析】根据题意可知：用剪的段数乘每段的长度再加上多的数量，即可求出这根彩带原来长度.\n【详解】4×4 + 2 = 16 + 2 = 18(米),则这根彩带原来长 18 米。",
+    "knowledge_points": [
+      "表内乘加，乘减"
+    ],
+    "source": "24-25二年级上·浙江杭州·期末"
+  },
+  {
+    "id": "124",
+    "unit": "第四单元 表内乘法",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "5 + 5 + 5 + 5 + 5 = ( )×( )。2 + 2 + 2 + 2 + 2 + 2 + 2 = ( )×( )。",
+    "options": [],
+    "answer": "5;5;2;7",
+    "solution": "【分析】根据乘法的意义，求几个相同加数的和是多少，可以用乘法简便计算.\n【详解】由题意分析得:5 + 5 + 5 + 5 + 5 = 5×5;2 + 2 + 2 + 2 + 2 + 2 + 2 = 2×7。",
+    "knowledge_points": [
+      "初步认识乘法意义"
+    ],
+    "source": "24-25 二年级上·河南商丘·期末"
+  },
+  {
+    "id": "125",
+    "unit": "第四单元 表内乘法",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "1 张 100 元可以换()张 20 元和( )张 10 元;3 枚 1 元的硬币可以换( )枚 5角的硬币。",
+    "options": [],
+    "answer": "4;2;6",
+    "solution": "【分析】根据整数加减法的计算法则，找出几个 20 的和与几个 10 的和刚好等于 100，就可以知道 1 张 100 元可以换几张 20 元和几张 10 元;3 枚 1 元的硬币就是 3 元,3 元 = 30 角，再结合乘法口诀，算出几个 5 角是 30 角;据此解决.\n【详解】20 + 20 + 20 + 20 = 80(元),10 + 10 = 20(元),80 + 20 = 100(元),也就是 4 个 20 元和 2 个 10 元刚好等于 100 元;3 元 = 30 角,5×6 = 30(角),也就是 30 角里面有 6 个 5 角;即,1 张 100 元可以换 4 张 20 元和 2 张 10 元;3 枚 1 元的硬币可以换 6 枚 5 角的硬币。(前两个空答案不唯一)",
+    "knowledge_points": [
+      "100以内数的连加运算",
+      "6的乘法口诀及应用",
+      "十元以下人民币的认识与计算",
+      "十元以上人民币的认识与计算"
+    ],
+    "source": "24-25 二年级上·河南郑州·期末"
+  },
+  {
+    "id": "126",
+    "unit": "第四单元 表内乘法",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "把 5×3 改写成加法算式是( )或( )。",
+    "options": [],
+    "answer": "5 + 5 + 5 = 15;3 + 3 + 3 + 3 + 3 = 15",
+    "solution": "【分析】乘法算式表示几个相同加数的和，若前一个乘数是相同加数，则后一个乘数是相同加数的个数;若前一个乘数是相同加数的个数，则后一个乘数是相同加数。5×3 表示 3 个 5 的和或 5 个 3 的和.\n【详解】把 5×3 改写成加法算式是 5 + 5 + 5 = 15 或 3 + 3 + 3 + 3 + 3 = 15。",
+    "knowledge_points": [
+      "同数连加的应用",
+      "初步认识乘法意义"
+    ],
+    "source": "24-25二年级上·河南郑州·期末"
+  },
+  {
+    "id": "127",
+    "unit": "第四单元 表内乘法",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "△ + △ + △ + △ = 16, ○ + ○ + ○ = 15,△ * ○ = ( )。",
+    "options": [],
+    "answer": "20",
+    "solution": "【分析】根据求几个相同数连加的和，可以用乘法表示，则 △ + △ + △ + △ = 16,○ + ○ + ○ = 15 可用乘法表示,4 * △ = 16,3 * ○ = 15，根据乘法口诀即可求出.\n【详解】4 * △ = 16,3 * ○ = 15,4×4 = 16,3×5 = 15，则 △ = 4,○ = 5。则 △ * ○ = 4×5 = 20。",
+    "knowledge_points": [
+      "同数连加的应用",
+      "5的乘法口诀及应用",
+      "4的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·浙江杭州·期末"
+  },
+  {
+    "id": "128",
+    "unit": "第四单元 表内乘法",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "△ * △ = 36,△ + ○ = 15,△ = ( ),○ = ( )。",
+    "options": [],
+    "answer": "6;9",
+    "solution": "【分析】△ * △ = 36 表示两个相同的数相乘等于 36，再结合乘法口诀\"六六三十六\"可知 △ = 6;然后把 △ = 6 代入到 △ + ○ = 15 中，可求出 ○ 表示的数.\n【详解】由题意分析得:△ * △ = 36，且 6×6 = 36，故 △ = 6;把 △ = 6 代入到 △ + ○ = 15 中，得 6 + ○ = 15，则 ○ = 15 - 6 = 9，即 ○ = 9。",
+    "knowledge_points": [
+      "十几减 7,6 的退位减法",
+      "6 的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·湖北随州·期末"
+  },
+  {
+    "id": "129",
+    "unit": "第四单元 表内乘法",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "8 个 7 比 7 个 7 多(),比 9 个 7 少( )。",
+    "options": [],
+    "answer": "7;7",
+    "solution": "【分析】8 个 7 比 7 个 7 多 1 个 7，即 7;比 9 个 7 少 1 个 7，即 7;据此解答即可.\n【详解】根据分析可得:8 个 7 比 7 个 7 多 7，比 9 个 7 少 7。",
+    "knowledge_points": [
+      "初步认识乘法意义"
+    ],
+    "source": "24-25 二年级上·湖北随州·期末"
+  },
+  {
+    "id": "130",
+    "unit": "第四单元 表内乘法",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "一个人吃饭要用一双筷子，聪聪和他的爸爸，妈妈一起吃饭，一共要( )根筷子。",
+    "options": [],
+    "answer": "6",
+    "solution": "【分析】先算出来吃饭的总人数，再乘 2，即可求出一共需要筷子的数量，据此解答即可.\n【详解】1 + 1 + 1 = 3(人),3×2 = 6(根),因此一共要 6 根筷子。",
+    "knowledge_points": [
+      "3 的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·湖北随州·期末"
+  },
+  {
+    "id": "131",
+    "unit": "第四单元 表内乘法",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "4×5 = 20，口诀( ),把这道算式改写成加法算式是( )或( )。",
+    "options": [],
+    "answer": "四五二十;5 + 5 + 5 + 5 = 20;4 + 4 + 4 + 4 + 4 = 20",
+    "solution": "【分析】算式中两个乘数是口诀中的前两个数，积是口诀中的后一个数。乘法算式可以表示几个相同加数的和，若前一个乘数为相同加数，则后一个乘数为相同加数的个数;若前一个乘数为相同加数的个数，则后一个乘数为相同加数，由此写出加法算式.\n【详解】由乘法口诀知，口诀是\"四五二十\"，改写成加法算式是:4 + 4 + 4 + 4 + 4 = 20 或 5 + 5 + 5 + 5 = 20。",
+    "knowledge_points": [
+      "5 的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·贵州黔西·期末"
+  },
+  {
+    "id": "132",
+    "unit": "第四单元 表内乘法",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "括号里最大能填几。\n30 > ( )×5;42 + ( ) < 60;26 > 64 - ( )",
+    "options": [],
+    "answer": "5;17;39",
+    "solution": "【分析】根据表内乘法口诀及整数加减法的计算法则和整数比较大小的方法来解决此题.\n【详解】5×5 = 25,6×5 = 30,30 > 25，故 30 > 5×5;60 - 42 = 18,18 - 1 = 17,42 + 17 = 59,59 < 60，故 42 + 17 < 60;64 - 26 = 38,38 + 1 = 39,64 - 39 = 25,26 > 25，故 26 > 64 - 39。",
+    "knowledge_points": [
+      "100以内数的比大小",
+      "两位数与两位数的进位加法",
+      "两位数与两位数的退位减法",
+      "6的乘法口诀及应用"
+    ],
+    "source": "24-25二年级上·江西抚州·期末"
+  },
+  {
+    "id": "133",
+    "unit": "第四单元 表内乘法",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "一辆小汽车有 4 个轮子,3 辆小汽车有( )个轮子。",
+    "options": [],
+    "answer": "12",
+    "solution": "【分析】用一辆小汽车的轮子数量乘 3 即可求出 3 辆小汽车的轮子数量.\n【详解】4×3 = 12(个),一辆小汽车有 4 个轮子,3 辆小汽车有 12 个轮子。",
+    "knowledge_points": [
+      "4的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·贵州黔西·期末"
+  },
+  {
+    "id": "134",
+    "unit": "第四单元 表内乘法",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "图书室每个星期周日只开放 4 个小时，其他每天都开放 6 小时。那么周一到周五一共开放( )小时，周末一共开放( )小时。",
+    "options": [],
+    "answer": "30;10",
+    "solution": "【分析】周一到周五一共有5天，图书室每天开放6小时，求5天一共开放多少小时，就是求5个6的和是多少，用乘法列式解决;周末有2天，图书室周六开放6小时，周日开放4小时，求周末一共开放几小时，就是求两个数的和，用加法列式解决.\n【详解】5×6 = 30(小时),6 + 4 = 10(小时)。即，图书室每个星期周日只开放4个小时，其他每天都开放 6 小时。那么周一到周五一共开放 30 小时，周末一共开放 10 小时。",
+    "knowledge_points": [
+      "10 的加减法",
+      "6 的乘法口诀及应用"
+    ],
+    "source": "23-24 二年级上·浙江杭州·期末"
+  },
+  {
+    "id": "135",
+    "unit": "第四单元 表内乘法",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "如果 ● + ● + ● = 18,○ + ○ = 10，那么 ● * ○ = ( )。",
+    "options": [],
+    "answer": "30",
+    "solution": "【分析】三个相同的数相加得 18，由此算出 ● 表示多少。两个相同的数相加得10，由此算出 ○ 表示多少，最后将数据代入 ● * ○ 直接计算即可.\n【详解】● + ● + ● = 18,6 + 6 + 6 = 18，所以 ● = 6;○ + ○ = 10,5 + 5 = 10，所以 ○ = 5;所以 ● * ○ = 6×5 = 30。",
+    "knowledge_points": [
+      "同数连加的应用",
+      "6 的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·湖北黄冈·期末"
+  },
+  {
+    "id": "136",
+    "unit": "第四单元 表内乘法",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "在括号里填上\">\"\"<\"或\"=\".\n26( )15 + 19;6×5 - 5( )5×5;1 拃( )30 厘米",
+    "options": [],
+    "answer": "<;=;<",
+    "solution": "【分析】根据整数加减法的计算法则及乘法口诀，依次计算出各个算式的结果再比较大小。根据生活经验可知,1拃大约12厘米左右。比较时，位数多的数就大，位数相同比较最高位，最高位大的数就大，最高位相同比较下一位.\n【详解】(1)左边:26，右边:15 + 19 = 34,26 小于 34，所以 26 < 15 + 19;(2)左边:6×5 = 30,30 - 5 = 25，右边:5×5 = 25,25 等于 25，所以 6×5 - 5 = 5×5;(3)左边:1 拃大约 12 厘米，右边 30 厘米,12 厘米小于 30 厘米，所以 1 拃 < 30 厘米。",
+    "knowledge_points": [
+      "两位数与两位数的进位加法",
+      "6的乘法口诀及应用",
+      "厘米的认识",
+      "表内乘加，乘减",
+      "\"身体尺\"的认识及应用"
+    ],
+    "source": "24-25 二年级上·湖北襄阳·期末"
+  },
+  {
+    "id": "137",
+    "unit": "第四单元 表内乘法",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "长方体一共有 6 个面，每个面上有( )个直角,6 个面一共有( )个直角.\n\n![](images/ae69ba150a9daba0d9e12c34971e6487b0f7db6a816f6ca569d73f623576992d.jpg)",
+    "options": [],
+    "answer": "4;24",
+    "solution": "【分析】长方体一共有6个面，每个面上有4个直角，求6个面一共有几个直角，就是求6个4的和是多少，用乘法列式解决.\n【详解】6×4 = 24(个),即，长方体一共有6个面，每个面上有4个直角,6个面一共有24个直角。",
+    "knowledge_points": [
+      "长方体的认识及特征",
+      "6的乘法口诀及应用",
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "24-25 二年级上·福建三明·期末"
+  },
+  {
+    "id": "138",
+    "unit": "第四单元 表内乘法",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "同学们佩戴的红领巾上有( )个角，其中最大的角是( )。现在老师手中有 4 条红领巾，一共有( )个角，列式计算( )。",
+    "options": [],
+    "answer": "3;钝角;12;3×4 = 12(个)",
+    "solution": "【分析】由一个点引出两条直直的线所组成的图形是角。三角尺上最大的角为直角，用三角板的直角进行比较测量，比直角小的是锐角，比直角大的是钝角。红领巾上有3个角，用 3 乘红领巾的数量即可求出一共多少个角.\n【详解】3×4 = 12(个),同学们佩戴的红领巾上有3个角，其中最大的角是钝角。现在老师手中有4条红领巾，一共有12个角，列式计算:3×4 = 12(个)。",
+    "knowledge_points": [
+      "4的乘法口诀及应用",
+      "角的初步认识及辨认",
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "24-25 二年级上·黑龙江哈尔滨·期末"
+  },
+  {
+    "id": "139",
+    "unit": "第四单元 表内乘法",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "丁丁从头开始看一本故事书，每天看 6 页，看了 3 天后，第 4 天应从第( )页开始看。",
+    "options": [],
+    "answer": "19",
+    "solution": "【分析】根据乘法的意义，用 6×3 先算出丁丁前面3天一共读了多少页，再加上1，即可得出第4天应从第几页开始看.\n【详解】6×3 = 18(页),18 + 1 = 19(页),所以第 4 天应从第 19 页开始看。",
+    "knowledge_points": [
+      "6 的乘法口诀及应用"
+    ],
+    "source": "24-25二年级上·河北保定·期末"
+  },
+  {
+    "id": "140",
+    "unit": "第四单元 表内乘法",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "改写算式.\n2×5 - 2 = ( )×( );5×5 + 5 = ( )×( )\n4 + 4 + 4 = ( )×( );2×6 - 6 = ( )×( )",
+    "options": [],
+    "answer": "2;4;5;6;4;3;6;1",
+    "solution": "【分析】求几个相同加数的和的简便运算，可以用加法列式计算，也可以用乘法列式计算。2×5 - 2 表示 5 个 2 相加的和，减去 1 个 2，即 4 个 2 相加的和;5×5 + 5 表示 5 个 5 相加的和，再加上 1 个 5，即 6 个 5 相加的和;4 + 4 + 4 表示 3 个 4 相加的和;2×6 - 6 表示 2 个 6 相加的和，再减去 1 个 6，即 1 个 6.\n【详解】2×5 - 2 = 2×4;5×5 + 5 = 5×6;4 + 4 + 4 = 4×3;2×6 - 6 = 6×1。",
+    "knowledge_points": [
+      "初步认识乘法意义"
+    ],
+    "source": "24-25 二年级上·河北邯郸·期末"
+  },
+  {
+    "id": "141",
+    "unit": "第四单元 表内乘法",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "括号里最大填多少。\n4×( ) < 26;13 + ( ) < 29 + 6",
+    "options": [],
+    "answer": "6;21",
+    "solution": "【分析】(1)在六的乘法口诀中，找出 4 乘几的积比 26 小;(2)先算出来右边的得数，再用得数减去左边13，再减去1就能算出最大填几.\n【详解】(1)4×6 = 24,4×7 = 28,24 < 26 < 28，括号里最大填 6，所以 4×6 < 26;(2)右边等于 29 + 6 = 35,35 - 13 = 22,22 - 1 = 21，所以 13 + 21 < 29 + 6。",
+    "knowledge_points": [
+      "一位数与两位数的进位加法",
+      "6的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·河北邯郸·期末"
+  },
+  {
+    "id": "142",
+    "unit": "第四单元 表内乘法",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "5 个 6 相加，和是( )。",
+    "options": [],
+    "answer": "30",
+    "solution": "【分析】求 5 个 6 相加，和是多少，用乘法计算，把结果填空即可.\n【详解】5×6 = 30，所以 5 个 6 相加，和是 30。",
+    "knowledge_points": [
+      "初步认识乘法意义",
+      "6的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·甘肃天水·期末"
+  },
+  {
+    "id": "143",
+    "unit": "第四单元 表内乘法",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "8 + 8 + 8 + 8 + 8 + 8，改写成乘法算式是( ),表示( )个( )相加。",
+    "options": [],
+    "answer": "8×6;6;8",
+    "solution": "【分析】求几个相同加数的和是多少，可以用乘法计算。8 + 8 + 8 + 8 + 8 + 8 表示求 6 个 8 的和是多少，可以写成乘法算式:8×6 或 6×8.\n【详解】8 + 8 + 8 + 8 + 8 + 8 改写成乘法算式是 8×6，表示 6 个 8 相加。",
+    "knowledge_points": [
+      "初步认识乘法意义"
+    ],
+    "source": "24-25二年级上·甘肃庆阳·期末"
+  },
+  {
+    "id": "144",
+    "unit": "第四单元 表内乘法",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "5 + 5 + 5 + 5 + 5 = ( )×( );6 + 6 + 6 + 6 + 6 + 6 + 6 = ( )×( )",
+    "options": [],
+    "answer": "5;5;6;7",
+    "solution": "【分析】根据求几个相同数连加的和，可用乘法计算.\n【详解】5 + 5 + 5 + 5 + 5 = 5×5;6 + 6 + 6 + 6 + 6 + 6 + 6 = 6×7。",
+    "knowledge_points": [
+      "同数连加的应用",
+      "初步认识乘法意义"
+    ],
+    "source": "24-25 二年级上·陕西西安·期末"
+  },
+  {
+    "id": "145",
+    "unit": "第四单元 表内乘法",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "1 个正方形有( )个直角,5 个正方形有( )个直角。",
+    "options": [],
+    "answer": "4;20",
+    "solution": "【分析】正方形一个有4个直角，用正方形的个数乘 4 即可求出一共多少个直角.\n【详解】4×5 = 20(个),1 个正方形有 4 个直角,5 个正方形有 20 个直角。",
+    "knowledge_points": [
+      "5的乘法口诀及应用",
+      "长方形，正方形，三角形和圆的初步认识",
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "24-25 二年级上·河南周口·期末"
+  },
+  {
+    "id": "146",
+    "unit": "第四单元 表内乘法",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "下图用加法算式表示是( ),用乘法算式表示是( ),运用的乘法口诀是().\n\n![](images/a17840f568434a0b1e9368c26bdd7bed240944115f31ef9f632912f37358651f.jpg)",
+    "options": [],
+    "answer": "2 + 2 + 2 + 2 = 8;2×4 = 8 或 4×2 = 8;二四得八",
+    "solution": "【分析】观察图可知，一组中 2 个苹果，这样的 4 组，求 4 个 2 相加的和，即可列出加法算式;再根据乘法的意义，求几个相同加数的和用乘法计算，可列出乘法算式，据算式想:2乘几等于8，便知运用的乘法口诀.\n【详解】下图用加法算式表示是 2 + 2 + 2 + 2 = 8，用乘法算式表示是 2×4 = 8 或 4×2 = 8，运用的乘法口诀是二四得八。",
+    "knowledge_points": [
+      "图文问题",
+      "初步认识乘法意义",
+      "4 的乘法口诀及应用"
+    ],
+    "source": "24-25二年级上·吉林·期末"
+  },
+  {
+    "id": "147",
+    "unit": "第四单元 表内乘法",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "每个小朋友有一副手套,3 个小朋友有( )只手套。",
+    "options": [],
+    "answer": "6",
+    "solution": "【分析】根据生活经验可知，每副手套有 2 只,3 个小朋友也就是一共有 3 副手套，则用每副手套的只数和手套的副数相乘，就是总只数.\n【详解】2×3 = 6(只),每个小朋友有一副手套,3 个小朋友有 6 只手套。",
+    "knowledge_points": [
+      "3 的乘法口诀及应用"
+    ],
+    "source": "23-24 二年级上·河北保定·期末"
+  },
+  {
+    "id": "148",
+    "unit": "第四单元 表内乘法",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "6 的 4 倍是( ),4 个 5 相加的和是( )。",
+    "options": [],
+    "answer": "24;20",
+    "solution": "【分析】要求 6 的 4 倍是多少，根据乘法的意义，用 6×4 或 4×6 进行解答即可;要求 4 个 5 相加的和，根据乘法的意义，用 4×5 或 5×4 进行解答即可.\n【详解】6×4 = 24，所以 6 的 4 倍是 24;4×5 = 20，所以 4 个 5 相加的和是 20。",
+    "knowledge_points": [
+      "5的乘法口诀及应用",
+      "求一个数的几倍是多少"
+    ],
+    "source": "23-24 二年级上·江西赣州·期末"
+  },
+  {
+    "id": "149",
+    "unit": "第四单元 表内乘法",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "5×6 = 30，读作( ),计算时用的口诀是( )。",
+    "options": [],
+    "answer": "5乘6等于30;五六三十",
+    "solution": "【分析】5 和 6 都是乘数，\"*\"读作\"乘\"，\"=\"读作\"等于\"，据此可读出这个算式;再结合乘法口诀可完成解答.\n【详解】5×6 = 30，读作 5 乘 6 等于 30，计算时用的口诀是\"五六三十\"。",
+    "knowledge_points": [
+      "初步认识乘法意义",
+      "6的乘法口诀及应用"
+    ],
+    "source": "23-24 二年级上·重庆云阳·期末"
+  },
+  {
+    "id": "150",
+    "unit": "第四单元 表内乘法",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "算式 6 + 6 + 6 + 6 + 5 列成含有乘法的算式是( )。",
+    "options": [],
+    "answer": "6×4 + 5 = 29或6×5 - 1 = 29",
+    "solution": "【分析】可以将 6 + 6 + 6 + 6 + 5 看作 4 个 6 的和，另外还有 5 个;也可以看作 5 个 6 的和并且少了 1 个。几个相同加数相加，可以写成加数与个数相乘的形式.\n【详解】6×4 + 5 = 24 + 5 = 29，或 6×5 - 1 = 30 - 1 = 29。算式 6 + 6 + 6 + 6 + 5 列成含有乘法的算式是 6×4 + 5 = 29 或 6×5 - 1 = 29。",
+    "knowledge_points": [
+      "6 的乘法口诀及应用",
+      "表内乘加，乘减"
+    ],
+    "source": "23-24 二年级上·重庆丰都·期末"
+  },
+  {
+    "id": "151",
+    "unit": "第四单元 表内乘法",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "上图中一共有( )个苹果，用加法算式表示为( ),用乘法算式表示为( )或( ).\n\n![](images/77fcac28e9165792bd8fcd1206eb4a7e918b2664b392057e5793cccd4c1fb957.jpg)\n![](images/e5a35d6f0aa722e2b597d38996575378477523206b72d930dc5367d117c6fa08.jpg)\n![](images/caea890ab278134aeb7af71f5e0b68afbaa108e5e2a791aa40c1fde281f5ec28.jpg)",
+    "options": [],
+    "answer": "18;6 + 6 + 6 = 18(个);3×6 = 18(个);6×3 = 18(个)",
+    "solution": "【分析】先数一数一个盘中有几个苹果，再数一数一共有几盘。把每盘中的数量相加即可，然后根据求几个相同数连加的和，可以用乘法表示.\n【详解】该图中一共有 18 个苹果，用加法算式表示为 6 + 6 + 6 = 18(个),用乘法算式表示为 3×6 = 18(个)或 6×3 = 18(个)。",
+    "knowledge_points": [
+      "同数连加的应用",
+      "初步认识乘法意义",
+      "6的乘法口诀及应用"
+    ],
+    "source": "24-25二年级上·河北秦皇岛·期末"
+  },
+  {
+    "id": "152",
+    "unit": "第四单元 表内乘法",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "5 + 5 + 5 + 5 + 4 可以改写成 5×5 + 4。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】根据求几个相同数连加的和，可以用乘法表示。5 + 5 + 5 + 5 + 4 表示的是 4 个 5 相加的和多加 4，可列式为:4×5 + 4 或 5×4 + 4;也可表示为 5 个 5 相加的和少加 1，用乘法计算列式为 5×5 - 1.\n【详解】5 + 5 + 5 + 5 + 4 可以改写成 4×5 + 4 或 5×4 + 4 或 5×5 - 1，则原题说法错误。故答案为: ×",
+    "knowledge_points": [
+      "同数连加的应用",
+      "表内乘加，乘减"
+    ],
+    "source": "24-25 二年级上·浙江宁波·期末"
+  },
+  {
+    "id": "153",
+    "unit": "第四单元 表内乘法",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "在表内乘法中，所有的乘法口诀都能计算两道乘法算式。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】乘法算式中两个乘数是口诀中的前两个数，积是口诀中的后一个数，写算式时两个乘数可互换位置。有的口诀只能计算一条算式.\n【详解】\"四四十六\"计算的乘法算式是 4×4 = 16，只有一个，原题说法错误。故答案为: ×",
+    "knowledge_points": [
+      "4 的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·山东济宁·期末"
+  },
+  {
+    "id": "154",
+    "unit": "第四单元 表内乘法",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "5 + 5 + 5 + 5 + 4 可以改写成 5×5÷4。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】根据乘法的意义,5 + 5 + 5 + 5 + 4 表示 4 个 5 的和，再加上 4;也可以表示 5 个 5 的和，再减去 1，据此解决即可.\n【详解】5 + 5 + 5 + 5 + 4 可以改写成 5×4 + 4 或 5×5 - 1;原题做法错误。故答案为: ×",
+    "knowledge_points": [
+      "初步认识乘法意义",
+      "5的乘法口诀及应用",
+      "表内乘加，乘减"
+    ],
+    "source": "24-25 二年级上·浙江宁波·期末"
+  },
+  {
+    "id": "155",
+    "unit": "第四单元 表内乘法",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "因为 2 + 2 = 2×2，所以 4 + 4 = 4×40。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】根据乘法的意义，求几个相同加数的和的简便运算，结合题干要求进行解答即可.\n【详解】2 + 2 表示 2 个 2 的和，写成乘法算式是 2×2，即 2 + 2 = 2×2;4 + 4 表示 2 个 4 的和，写成乘法算式是 4×2 或 2×4，即 4 + 4 = 4×2 或 4 + 4 = 2×4，因此原题说法错误。故答案为: ×",
+    "knowledge_points": [
+      "初步认识乘法意义"
+    ],
+    "source": "24-25 二年级上·广西贵港·期末"
+  },
+  {
+    "id": "156",
+    "unit": "第四单元 表内乘法",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "计算 3×4 = 12 和 2×6 =12 时，都可以用\"三四十二\"这句口诀。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】口诀\"三四十二\"可以计算乘法算式 3×4 = 12 和 4×3 = 12;口诀\"二六十二\"可以计算乘法算式 2×6 = 12 和 6×2 = 12.\n【详解】计算 3×4 = 12 时，用\"三四十二\"这句口诀;而计算 2×6 = 12 时，用\"二六十二\"这句口诀;原题说法错误。故答案为: ×",
+    "knowledge_points": [
+      "4 的乘法口诀及应用",
+      "6 的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·四川南充·期末"
+  },
+  {
+    "id": "157",
+    "unit": "第四单元 表内乘法",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "两个乘数都是 4，算式是 2 + 4。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】根据\"乘数×乘数 = 积\"来列式解决即可.\n【详解】由题意分析得：两个乘数都是 4，算式是 4×4。原题说法错误。故答案为: ×",
+    "knowledge_points": [
+      "初步认识乘法意义"
+    ],
+    "source": "24-25 二年级上·重庆奉节·期末"
+  },
+  {
+    "id": "158",
+    "unit": "第四单元 表内乘法",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "3×4 和 2×6 的积相等，计算时运用的乘法口诀相同。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】结合题意，分别确定出两个算式计算时用的乘法口诀是什么，并算出积，即可解决.\n【详解】用口诀\"三四十二\"计算 3×4 = 12;用口诀\"二六十二\"计算 2×6 = 12;即 3×4 和 2×6 的积相等，但计算时运用的乘法口诀不相同。原题说法错误。故答案为: ×",
+    "knowledge_points": [
+      "4 的乘法口诀及应用",
+      "6 的乘法口诀及应用"
+    ],
+    "source": "20-21二年级上·河北·单元测试"
+  },
+  {
+    "id": "159",
+    "unit": "第四单元 表内乘法",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "3 ○ 3 = 9,○ 里应填 + 。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】结合整数加减法的计算法则及乘法口诀来解决此题即可.\n【详解】3 + 3 = 6;3×3 = 9，即 3 ○ 3 = 9,○ 里应填 *。原说法错误。故答案为: ×",
+    "knowledge_points": [
+      "6的加减法",
+      "3的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·甘肃天水·期末"
+  },
+  {
+    "id": "160",
+    "unit": "第四单元 表内乘法",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "两个数相加的和一定没有这两个数相乘的积大。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】此类题可以举例说明.\n【详解】1 + 1 = 2,1×1 = 1,2 > 1,1 和 1 相加的和比 1 和 1 相乘的积大，原题说法错误。故答案为: ×",
+    "knowledge_points": [
+      "初步认识乘法意义"
+    ],
+    "source": "24-25 二年级上·吉林·期末"
+  },
+  {
+    "id": "161",
+    "unit": "第四单元 表内乘法",
+    "question_type": "判断题",
+    "difficulty": 0.65,
+    "question": "4 + 3 表示 4 个 3 的和,4×3 表示 4 个 3 相加。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】4 + 3 表示 4 和 3 相加的和;4 个 3 相加，用加法列式是 3 + 3 + 3 + 3，根据整数乘法的意义，求几个相同加数和的简便运算，用乘法列式为 4×3.\n【详解】由分析可得:4 + 3 表示 4 和 3 相加的和,4×3 表示 4 个 3 相加。原题说法错误。故答案为: ×",
+    "knowledge_points": [
+      "初步认识乘法意义",
+      "4的乘法口诀及应用"
+    ],
+    "source": "23-24 二年级上·河北保定·期末"
+  },
+  {
+    "id": "162",
+    "unit": "第四单元 表内乘法",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "在计算 5×4 和 4×5 时都用乘法口诀\"四五二十\"。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】由乘法口诀\"四五二十\"可知，两个乘数是4和5，积是20，口诀可以用来计算乘法算式 5×4 和 4×5.\n【详解】在计算 5×4 和 4×5 时都用乘法口诀\"四五二十\"，此说法正确。故答案为:√",
+    "knowledge_points": [
+      "5 的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·广东揭阳·期末"
+  },
+  {
+    "id": "163",
+    "unit": "第四单元 表内乘法",
+    "question_type": "解答题",
+    "difficulty": 0.85,
+    "question": "看图列式计算.\n\n![](images/4fe2d1acd07487b4be99f94f30d64b06940ea906955205b1ed3e2ec6434de471.jpg)\n□ ○ □ = □ (元)",
+    "options": [],
+    "answer": "4×5 = 20(元)",
+    "solution": "【分析】根据图片可知：一共 4 个杯子，一个 5 元，求一共多少钱。用杯子数乘每个杯子的钱数即可.\n【详解】4×5 = 20(元),一共是 20 元。",
+    "knowledge_points": [
+      "5 的乘法口诀及应用"
+    ],
+    "source": "24-25二年级上·江西抚州·期末"
+  },
+  {
+    "id": "164",
+    "unit": "第四单元 表内乘法",
+    "question_type": "解答题",
+    "difficulty": 0.85,
+    "question": "看图列式.\n\n![](images/372a489541dd6d0907e48d39d0e3b716e15887428f6d1b06a890cca15f83add8.jpg)\n□ ○ □ ○ □ = □ (个)",
+    "options": [],
+    "answer": "5×3 + 3 = 18",
+    "solution": "【分析】前面3组每组5个，用乘法算出前面3组的个数，然后加上另外的3个即可求出一共多少个.\n【详解】5×3 + 3 = 15 + 3 = 18，一共有 18 个。",
+    "knowledge_points": [
+      "图文问题",
+      "表内乘加，乘减"
+    ],
+    "source": "24-25 二年级上·内蒙古通辽·期末"
+  },
+  {
+    "id": "165",
+    "unit": "第四单元 表内乘法",
+    "question_type": "解答题",
+    "difficulty": 0.85,
+    "question": "看图列式，我最行.\n\n![](images/c35c383296727643f0b493761f61d2c27f4dd99e591dbaddb43cc44c20455bdf.jpg)\n□ ○ □ ○ □ = □(个)",
+    "options": [],
+    "answer": "5×4 + 3 = 23(个)",
+    "solution": "【分析】一组草莓有5个，先用乘法求出这样的4组草莓有几个，然后加上3个，求出和，即可解决.\n【详解】5×4 + 3 = 20 + 3 = 23(个),一共有 23 个草莓。",
+    "knowledge_points": [
+      "图文问题",
+      "表内乘加，乘减"
+    ],
+    "source": "24-25 二年级上·福建福州·期末"
+  },
+  {
+    "id": "166",
+    "unit": "第四单元 表内乘法",
+    "question_type": "解答题",
+    "difficulty": 0.65,
+    "question": "看图列式.\n\n![](images/de73ae0bb5877caf630994ab88530ed81cd7bb38bbdc54f443bf802c17a15d1f.jpg)\n□ ○ □ ○ □ = □ (个)",
+    "options": [],
+    "answer": "3×5 + 2 = 17(个)",
+    "solution": "【分析】观察发现前面5组，每组的个数是一样的，用每组的个数乘组数即可求出前面5组的个数，再加上最后2个即可求出一共的个数.\n【详解】3×5 + 2 = 15 + 2 = 17(个),所以一共 17 个。",
+    "knowledge_points": [
+      "图文问题",
+      "表内乘加，乘减"
+    ],
+    "source": "24-25 二年级上·广东汕头·期末"
+  },
+  {
+    "id": "167",
+    "unit": "第四单元 表内乘法",
+    "question_type": "解答题",
+    "difficulty": 0.65,
+    "question": "看图列式.\n\n![](images/dc6880de1521d3d34f47ce72aff4d6beeaeea8ea18aa5222a6f146598bdd5842.jpg)\n□ ○ □ = □ (个)",
+    "options": [],
+    "answer": "4×6 = 24(个)",
+    "solution": "【分析】用每组的个数乘组数即可求出一共多少个.\n【详解】4×6 = 24(个),所以共有 24 个。",
+    "knowledge_points": [
+      "图文问题",
+      "6 的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·广东汕头·期末"
+  },
+  {
+    "id": "168",
+    "unit": "第四单元 表内乘法",
+    "question_type": "解答题",
+    "difficulty": 0.85,
+    "question": "看图列式计算.\n\n![](images/6d8dd01c4e543a6d82d8d8a286138a093faa67ff04e719af10233bf12013720a.jpg)\n□ ○ □ ○ □ = □ (个)",
+    "options": [],
+    "answer": "3×3 + 2 = 11",
+    "solution": "【分析】由图可知，左边 3 盘每盘有 3 个桃子，右边这盘只有 2 个桃子，求一共有多少个桃子，先根据乘法的意义，用 3×3 计算出左边 3 盘桃子的数量，再根据加法的意义，用求出来的积加上 2 即可.\n【详解】3×3 + 2 = 9 + 2 = 11(个),所以一共有 11 个桃子。",
+    "knowledge_points": [
+      "图文问题",
+      "3 的乘法口诀及应用",
+      "表内乘加，乘减"
+    ],
+    "source": "24-25二年级上·全国·假期作业"
+  },
+  {
+    "id": "169",
+    "unit": "第四单元 表内乘法",
+    "question_type": "解答题",
+    "difficulty": 0.85,
+    "question": "看图列式计算.\n\n![](images/f6aa34dfbcc122850efba23644f307591dc4d30704f532313bd2a5362ff7dd86.jpg)\n□ ○ □ = □ (个)",
+    "options": [],
+    "answer": "3×4 = 12 或 4×3 = 12",
+    "solution": "【分析】每组有 4 个菠萝，共 3 组，求一共有多少个菠萝，也就是求 3 个 4 的和是多少，可以用乘法计算。每组菠萝的数量和组数相乘就是菠萝的总数量.\n【详解】3×4 = 12(个)或 4×3 = 12(个),一共有 12 个菠萝。",
+    "knowledge_points": [
+      "图文问题",
+      "4的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·全国·假期作业"
+  },
+  {
+    "id": "170",
+    "unit": "第四单元 表内乘法",
+    "question_type": "计算题",
+    "difficulty": 0.65,
+    "question": "看图列式.\n\n![](images/3c2c07216674a9fe960ff2cc0befcf3e9cf60e0071084d9b0e6997c0f84b3d2e.jpg)\n![](images/bf8f3bd965794a0e6322d4f4603e18d07593bd252ffd05011e354c9712cd033e.jpg)\n![](images/f615bb1564197d348501d44f517470d4fe61e5cc106a85ea0bd837ec024ed235.jpg)\n![](images/07a077436a5f1de3cd00e2b37cf4ac7f75abf5f9878cb341a67372a516cb45e1.jpg)\n\n□ * □ ○ □ = □(个)",
+    "options": [],
+    "answer": "3×4 + 3 = 15 或 4×4 - 1 = 15",
+    "solution": "【分析】由图可知，每组有4个，有这样的3组，用组数乘每组的个数，另外还有 3 个，再加上 3 即可求出一共的个数。或每组有4个，有这样的4组，用组数乘每组的个数，另外还少1个，再减去1即可求出一共的个数.\n【详解】3×4 + 3 = 12 + 3 = 15(个),或 4×4 - 1 = 16 - 1 = 15(个)。",
+    "knowledge_points": [
+      "图文问题",
+      "4的乘法口诀及应用",
+      "表内乘加，乘减"
+    ],
+    "source": "24-25 二年级上·全国·假期作业"
+  },
+  {
+    "id": "171",
+    "unit": "第四单元 表内乘法",
+    "question_type": "计算题",
+    "difficulty": 0.65,
+    "question": "看图写算式.\n\n![](images/9ce33434ee628430e98579e8b10135b75a01d7dad48e703c0552646601a8f3f9.jpg)\n![](images/0b0376100fc01cb4f95392df9ab62ffd217f0c62ed865731313d32e0abf81c43.jpg)\n![](images/d814c600218ff4adee14dfabd0ece93a4ea096579227bd4ace11298645a35f93.jpg)\n![](images/1f28e3aa0be5a21295515bb4e1e0c1dc6bc51e295f69c6b2af13e4a8c83dbffb.jpg)\n\n□ ○ □ ○ □ = □(个)",
+    "options": [],
+    "answer": "4×3 + 3 = 15 或 4×4 - 1 = 15",
+    "solution": "【分析】每组有4个球，有这样的3组还多3个，则总数量为3个4的和再加3，即每组的数量4个×组数3组 + 多的数量3个;也可以看成有4组，每组有4个，再减去多算的1个，则总数量为4个4的和再减1，即每组的数量4个×组数4组 - 多算的数量1个，由此解答.\n【详解】4×3 + 3 = 12 + 3 = 15(个);4×4 - 1 = 16 - 1 = 15(个),一共有15个球。",
+    "knowledge_points": [
+      "图文问题",
+      "表内乘加，乘减"
+    ],
+    "source": "24-25 二年级上·吉林四平·期末"
+  },
+  {
+    "id": "172",
+    "unit": "第四单元 表内乘法",
+    "question_type": "作图题",
+    "difficulty": 0.65,
+    "question": "找规律，画一画，填一填.\n\n![](images/75f54e2283870663b5cc3a41adb4d2c0e3efc53f153b45744ee1491ccbd67422.jpg)\n![](images/8f256a6ff306d4fad530ba69bd8124ad58400dfaaf86465154f98c215afa55b9.jpg)\n![](images/1225bdb645ec8048123262742f2f0f966e562b61f5453f4c3a774a6e8be22792.jpg)\n![](images/e2b45cad3cdfa4f7d1343b8b0c65bfacba4c64ec0213e93acd502847b2c87c8a.jpg)\n\n4×4 = 16;5×5 = 25",
+    "options": [],
+    "answer": "画一画见详解;4×4 = 16;5×5 = 25",
+    "solution": "【分析】由题意分析可知，第一个图，一行有2个圆，有2行这样的，列式为:2×2 = 4;第二个图，一行有3个圆，有3行这样的，列式为:3×3 = 9;第三个图，一行有4个圆，有4行这样的，列式为:4×4 = 16;第四个图，一行有5个圆，有5行这样的，列式为:5×5 = 25;据此解决.\n【详解】由题意分析得:\n\n![](images/a34d45ba81aea43e98e9f3dadcae44e2c857628bf403aaec5366b1abb48fecdd.jpg)",
+    "knowledge_points": [
+      "5 的乘法口诀及应用",
+      "4 的乘法口诀及应用",
+      "图形的变化规律"
+    ],
+    "source": "24-25 二年级上·湖北随州·期末"
+  },
+  {
+    "id": "173",
+    "unit": "第四单元 表内乘法",
+    "question_type": "作图题",
+    "difficulty": 0.65,
+    "question": "用你喜欢的方式表示 3×6。",
+    "options": [],
+    "answer": "见详解",
+    "solution": "【分析】求几个相同加数的和的简便运算可以用乘法列式计算。3×6 表示3个6相加的和，列式为 6 + 6 + 6;或6个3相加的和，列式为 3 + 3 + 3 + 3 + 3 + 3。据此解答.\n【详解】\n\n![](images/0509827637532a01aa15b94fa7e83787b9b7c2397e8533de48c13c45e72318eb.jpg)\n\n(答案不唯一)",
+    "knowledge_points": [
+      "初步认识乘法意义"
+    ],
+    "source": "24-25 二年级上·山东日照·期末"
+  },
+  {
+    "id": "174",
+    "unit": "第四单元 表内乘法",
+    "question_type": "作图题",
+    "difficulty": 0.85,
+    "question": "用你喜欢的方法表示算式 3×4。",
+    "options": [],
+    "answer": "见详解",
+    "solution": "【分析】乘法算式 3×4 所表示的意义，就是 3 个 4 相加或 4 个 3 相加，用画 ○ 的方式表示，即每行 4 个，共 3 行，或每行 3 个，共 4 行，据此画图即可。(任选一种即可)\n【详解】由分析可得:\n\n![](images/3dd2648e1f884b663d1e16aeaae62147ef885b208d447764f3c9312a800b4b5a.jpg)\n\n(画图不唯一)",
+    "knowledge_points": [
+      "初步认识乘法意义",
+      "4 的乘法口诀及应用"
+    ],
+    "source": "23-24 二年级上·浙江宁波·期末"
+  },
+  {
+    "id": "175",
+    "unit": "第四单元 表内乘法",
+    "question_type": "解答题",
+    "difficulty": 0.85,
+    "question": "二(1)班举行口算比赛，老师准备评出 25 名\"口算之星\"和 10 名\"进步之星\"，每人奖励一个奖章，下边这些奖章够吗。\n\n![](images/a166227d8d1386e7c6359e871e51d530c9a0bc7c83b6006b929b6842c90a1a5d.jpg)",
+    "options": [],
+    "answer": "不够",
+    "solution": "【分析】先求出一共要的奖章数量，用评出\"口算之星\"的人数加\"进步之星\"的人数即可，然后再求出图中的奖章数量，观察图片可知：一行5个的有3行，即3个5相加，行6个的有3行，即3个6相加,3个5和3个6相加即可求出图中共有的奖章，然后和需要的奖章比较即可，若大于或等于需要的奖章数，则够，若小于需要的奖章数则不够.\n【详解】25 + 10 = 35(个),3×5 = 15(个),3×6 = 18(个),15 + 18 = 33(个),35 > 33。答：不够。",
+    "knowledge_points": [
+      "两位数与整十数的加法",
+      "两位数与两位数的进位加法",
+      "5的乘法口诀及应用",
+      "6的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·浙江杭州·期末"
+  },
+  {
+    "id": "176",
+    "unit": "第四单元 表内乘法",
+    "question_type": "解答题",
+    "difficulty": 0.65,
+    "question": "王老师组织同学观看了神舟十九号飞船发射的视频，让每个小组的同学制作航天知识的手抄报，有2个小组，每个小组做6张手抄报，一共可以做多少张手抄报。",
+    "options": [],
+    "answer": "12 张",
+    "solution": "【分析】有2个小组，每个小组做6张手抄报，求一共可以做多少张手抄报，就是求2个6的和是多少，用乘法计算，用每个小组做的手抄报数量乘小组的数量.\n【详解】 6×2 = 12(张),答：一共可以做 12 张手抄报。",
+    "knowledge_points": [
+      "6的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·陕西延安·期末"
+  },
+  {
+    "id": "177",
+    "unit": "第四单元 表内乘法",
+    "question_type": "解答题",
+    "difficulty": 0.65,
+    "question": "张大伯种了 4 行青椒，每行有 6 棵。一共种了多少棵青椒。",
+    "options": [],
+    "answer": "24 棵",
+    "solution": "【分析】根据题意，用每行青椒的棵数乘行数，即可求出共种了多少棵青椒.\n【详解】 6×4 = 24(棵),答：一共种了24棵青椒。",
+    "knowledge_points": [
+      "6的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·青海西宁·期末"
+  },
+  {
+    "id": "178",
+    "unit": "第四单元 表内乘法",
+    "question_type": "解答题",
+    "difficulty": 0.65,
+    "question": "两个小组种树。第一小组有 5 个同学，每人种树 4 棵，第二小组比第一小组多种了 9 棵，第二小组一共种树多少棵。 两个小组一共种树多少棵。",
+    "options": [],
+    "answer": "29棵;49棵",
+    "solution": "【分析】用第一小组的人数乘每人种的棵数即可求出第一小组种的棵数。用第一小组种的棵数加第二小组比第一小组多种的棵数即可求出第二小组种的棵数。将第一小组和第二小组种的棵数相加即可求出两个小组一共种树多少棵.\n【详解】5×4 = 20(棵),20 + 9 = 29(棵),20 + 29 = 49(棵)。答：第二小组一共种树29棵;两个小组一共种树49棵。",
+    "knowledge_points": [
+      "整十数加，减一位数",
+      "两位数与整十数的加法",
+      "5的乘法口诀及应用"
+    ],
+    "source": "23-24 二年级上·浙江杭州·期末"
+  },
+  {
+    "id": "179",
+    "unit": "第四单元 表内乘法",
+    "question_type": "解答题",
+    "difficulty": 0.65,
+    "question": "过中秋，吃月饼，十五圆月当空照。中秋节，欢欢的大姨和小姨看望姥姥，她俩一共买了多少个月饼。\n\n![](images/2026-02-25%20112434.jpg)",
+    "options": [],
+    "answer": "28个",
+    "solution": "【分析】用蛋黄月饼的盒数乘每盒的个数算出蛋黄月饼的总数，最后将三种月饼的个数相加即可求解.\n【详解】3×6 = 18(个),18 + 4 + 6 = 28(个),答：她俩一共买了 28 个月饼。",
+    "knowledge_points": [
+      "图文问题",
+      "100 以内数的连加运算",
+      "6 的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·河南驻马店·期末"
+  },
+  {
+    "id": "180",
+    "unit": "第四单元 表内乘法",
+    "question_type": "解答题",
+    "difficulty": 0.85,
+    "question": "体育课上，王老师在每个小朋友面前都摆放了如图所示的5个障碍物，每相邻两个障碍物之间的距离是 2 米。第一个障碍物与最后一个障碍物之间的距离是多少米。\n\n![](images/2026-02-25%20112743.jpg)",
+    "options": [],
+    "answer": "8 米",
+    "solution": "【分析】首先算出来有多少个间隔，间隔数 = 障碍物的个数 - 1;然后用间隔数×相邻两个障碍物之间的距离 = 第一个障碍物与最后一个障碍物之间的距离，据此解答即可.\n【详解】5 - 1 = 4(个),4×2 = 8(米),答：第一个障碍物与最后一个障碍物之间的距离是8米。",
+    "knowledge_points": [
+      "5 以内数的减法",
+      "4 的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·四川广元·期末"
+  },
+  {
+    "id": "181",
+    "unit": "第四单元 表内乘法",
+    "question_type": "解答题",
+    "difficulty": 0.65,
+    "question": "超市里的 7 号电池有一板装 4 节的，也有一板装 6 节的.\n(1)如果买 3 板 6 节装的电池，一共有多少节。\n(2)两种包装的电池各一板，一共是多少节电池。",
+    "options": [],
+    "answer": "18节;10节",
+    "solution": "【分析】(1)一板电池 6 节，用 6 乘 3，即可得到 3 板 6 节装的电池一共有多少节;(2)求两种包装的电池各一板一共是多少节电池，用一板装4节的数量加上一板装6节的数量即可.\n【详解】(1)3×6 = 18(节),答：如果买3板6节装的电池，一共有18节。(2)4 + 6 = 10(节),答：两种包装的电池各一板，一共是10节电池。",
+    "knowledge_points": [
+      "10 的加减法",
+      "6 的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·四川广元·期末"
+  },
+  {
+    "id": "182",
+    "unit": "第四单元 表内乘法",
+    "question_type": "解答题",
+    "difficulty": 0.65,
+    "question": "每相邻2棵树之间相距4米，小亮一口气从第1棵树跑到第6棵树，小亮一共跑了多少米。",
+    "options": [],
+    "answer": "20米",
+    "solution": "【分析】每相邻两棵树之间有一段，段数 = 棵数 - 1，所以用6减1求出差，就是6棵树之间的段数;每相邻2棵树之间相距4米，就是每段长4米;然后用每段的长度乘段数，求出积，就是小亮一共跑了多少米.\n【详解】6 - 1 = 5(段),4×5 = 20(米),答：小亮一共跑了20米。",
+    "knowledge_points": [
+      "5 的乘法口诀及应用",
+      "植树问题(两端都栽)"
+    ],
+    "source": "23-24 二年级上·浙江杭州·期末"
+  },
+  {
+    "id": "183",
+    "unit": "第四单元 表内乘法",
+    "question_type": "解答题",
+    "difficulty": 0.85,
+    "question": "二(1)班举行\"我爱阅读\"活动.\n(1)小刚第一天读了16页，第二天读了14页。两天一共读了多少页。\n(2)小丽每天读 6 页书,5 天一共读了多少页。",
+    "options": [],
+    "answer": "30页;30页",
+    "solution": "【分析】(1)第一天读的页数加上第二天读的页数，等于两天一共读的页数，用加法计算，据此解答。(2)每天读的页数乘天数，等于5天一共读的页数，是求5个6相加是多少，用乘法计算，据此解答.\n【详解】根据分析可得:(1)16 + 14 = 30(页),答：两天一共读了30页。(2)6×5 = 30(页)或 5×6 = 30(页),答:5天一共读了30页。",
+    "knowledge_points": [
+      "两位数与两位数的进位加法",
+      "6的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·河南开封·期末"
+  },
+  {
+    "id": "184",
+    "unit": "第四单元 表内乘法",
+    "question_type": "解答题",
+    "difficulty": 0.65,
+    "question": "剪\"福\"字，过幸福年。一个小朋友剪4个\"福\"字,5个小朋友能剪多少个\"福\"字。",
+    "options": [],
+    "answer": "20 个",
+    "solution": "【分析】根据题意，用一个小朋友剪的数量乘小朋友的个数即可求出一共能剪多少个\"福\"字.\n【详解】 4×5 = 20(个),答:5个小朋友能剪20个\"福\"字。",
+    "knowledge_points": [
+      "5 的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·陕西西安·期末"
+  },
+  {
+    "id": "185",
+    "unit": "第四单元 表内乘法",
+    "question_type": "解答题",
+    "difficulty": 0.65,
+    "question": "一张桌子坐4人,6张桌子能坐下 22 人吗。",
+    "options": [],
+    "answer": "能",
+    "solution": "【分析】根据题意，用一张桌子坐的人数乘桌子的数量，求出6张桌子坐的人数，再比较大小.\n【详解】4×6 = 24(人),24 > 22，答:6张桌子能坐下22人。",
+    "knowledge_points": [
+      "100 以内数的比大小",
+      "6 的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·河北邯郸·期末"
+  },
+  {
+    "id": "186",
+    "unit": "第四单元 表内乘法",
+    "question_type": "解答题",
+    "difficulty": 0.85,
+    "question": "超市里的酸奶有两种规格(如图)。天天两种酸奶各买 1 盒，军军买了 4 盒 6杯装的酸奶，他们分别买了多少杯酸奶。\n\n![](images/2026-02-25%20113219.jpg)",
+    "options": [],
+    "answer": "9杯;24杯",
+    "solution": "【分析】用加法把两种酸奶各买一盒的数量加起来，求出和，就是天天买了几杯酸奶。1盒酸奶6杯，用乘法求出这样的4盒有多少杯，就是军军买了几杯酸奶.\n【详解】3 + 6 = 9(杯),6×4 = 24(杯),答：天天买了9杯酸奶，军军买了24杯酸奶。",
+    "knowledge_points": [
+      "8,9的加减法",
+      "6的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·福建福州·期末"
+  },
+  {
+    "id": "187",
+    "unit": "第四单元 表内乘法",
+    "question_type": "解答题",
+    "difficulty": 0.65,
+    "question": "凤凰百货搞促销活动，每盒酸奶 3 元，若购买的酸奶超出 2 盒，则超出部分每盒 5 元。妈妈要买 6 盒酸奶，带 30 元钱够吗。",
+    "options": [],
+    "answer": "够",
+    "solution": "【分析】每盒酸奶 3 元，先用乘法求出购买 2 盒多少钱;然后用妈妈要买的酸奶数量减去2盒，求出差，就是超出部分;用超出部分的数量乘5元，求出积，再加上前面2盒酸奶的钱数，求出和，最后与 30 元比较大小，即可解决.\n【详解】3×2 = 6(元),6 - 2 = 4(盒),4×5 + 6 = 20 + 6 = 26(元),26 < 30，答：带 30 元钱够。",
+    "knowledge_points": [
+      "100 以内数的比大小",
+      "3 的乘法口诀及应用",
+      "表内乘加，乘减"
+    ],
+    "source": "24-25 二年级上·河北保定·期末"
+  },
+  {
+    "id": "188",
+    "unit": "第四单元 表内乘法",
+    "question_type": "解答题",
+    "difficulty": 0.85,
+    "question": "妈妈编一个中国结需要5根红绳，编4个中国结需要多少根红绳。",
+    "options": [],
+    "answer": "20 根",
+    "solution": "【分析】这道题是求4个5相加是多少，用乘法计算，据此解答.\n【详解】根据分析可得:4×5 = 20(根)或 5×4 = 20(根),答：编 4 个中国结需要 20 根红绳。",
+    "knowledge_points": [
+      "5 的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·甘肃天水·期末"
+  },
+  {
+    "id": "189",
+    "unit": "第四单元 表内乘法",
+    "question_type": "解答题",
+    "difficulty": 0.65,
+    "question": "王老师和 4 个小朋友一起折纸鹤，王老师折了 8 个，每个小朋友折了 6 个。他们一共折了多少个纸鹤。",
+    "options": [],
+    "answer": "32 个",
+    "solution": "【分析】根据题意，先用每个小朋友折的数量和小朋友的人数相乘，求出4个小朋友折了多少个，再加上王老师折的数量，就是他们一共折纸鹤的数量.\n【详解】6×4 + 8 = 24 + 8 = 32(个),答：他们一共折了 32 个纸鹤。",
+    "knowledge_points": [
+      "表内乘加，乘减"
+    ],
+    "source": "24-25 二年级上·甘肃庆阳·期末"
+  },
+  {
+    "id": "190",
+    "unit": "第四单元 表内乘法",
+    "question_type": "解答题",
+    "difficulty": 0.85,
+    "question": "2024 年 12 月 13 日是第十一个南京大屠杀死难者国家公祭日，我们一定要勿忘国耻，牢记使命。二(1)班 6 个小组分别做国家公祭日主题手抄报，每个小组做 3 张，这 6 个小组一共做了多少张。",
+    "options": [],
+    "answer": "18 张",
+    "solution": "【分析】求一共做了多少张，也就是求 6 个 3 的和是多少，用乘法计算，即每个小组做的张数和组数相乘，就是做的总张数.\n【详解】 3×6 = 18(张),答：这6个小组一共做了18张。",
+    "knowledge_points": [
+      "6 的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·陕西西安·期末"
+  },
+  {
+    "id": "191",
+    "unit": "第四单元 表内乘法",
+    "question_type": "解答题",
+    "difficulty": 0.85,
+    "question": "为了做好冬季树木养护工作，提高树木的抗寒和抗虫能力，环保工人给树木进行涂白工作，帮树木穿上防寒防虫的\"防护衣\"。下图是张叔叔负责的树木，他一共要给多少棵树木涂白。\n\n![](images/c2ad58a782df0e30e9a47565d385be9e185b341d3496b822ad5884bdd9394921.jpg)",
+    "options": [],
+    "answer": "12 棵",
+    "solution": "【分析】由图可知，有4排树，每排种植3棵，求一共有多少棵。用每排种的棵数乘种的排数，即可求出一共要给多少棵树木涂白。据此解答.\n【详解】 4×3 = 12(棵),答：他一共要给12棵树木涂白。",
+    "knowledge_points": [
+      "图文问题",
+      "4 的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·山东日照·期末"
+  },
+  {
+    "id": "192",
+    "unit": "第四单元 表内乘法",
+    "question_type": "解答题",
+    "difficulty": 0.65,
+    "question": "李老师带 6 名同学去公园玩，带40元够吗。\n\n![](images/15ccaae0493ea6ed3a6bfa69ebdbc13327a23308a84beea55015be05e980a721.jpg)\n\n成人票:8元\n儿童票:6元",
+    "options": [],
+    "answer": "不够",
+    "solution": "【分析】根据题意，李老师需要购买成人票8元，同学需要购买儿童票每人6元，用儿童的票价乘同学的数量，加上老师的票价，即可求出一共需要多少元，再与带的钱数比较。据此解答.\n【详解】6×6 + 8 = 36 + 8 = 44(元),44 > 40，答：带40元不够。",
+    "knowledge_points": [
+      "图文问题",
+      "100 以内数的比大小",
+      "表内乘加，乘减"
+    ],
+    "source": "24-25 二年级上·山东临沂·期末"
+  },
+  {
+    "id": "193",
+    "unit": "第四单元 表内乘法",
+    "question_type": "解答题",
+    "difficulty": 0.65,
+    "question": "把一根 30 厘米的铁丝剪成 6 段，每剪一次要用 2 分钟，一共需要多少分钟。",
+    "options": [],
+    "answer": "10分钟",
+    "solution": "【分析】根据题意，铁丝被剪成 6 段，其实只剪了 5 次，即 6 - 1 = 5(次),每剪1次需要2分钟，要求一共需要多少分钟，就是求5个2是多少，用剪的次数乘每剪一次的时间，即可求出一共需要多少分钟.\n【详解】6 - 1 = 5(次),5×2 = 10(分钟),答：一共需要10分钟。",
+    "knowledge_points": [
+      "6 的加减法",
+      "5 的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·山东临沂·期末"
+  },
+  {
+    "id": "194",
+    "unit": "第四单元 表内乘法",
+    "question_type": "解答题",
+    "difficulty": 0.85,
+    "question": "超市里的7号电池有一板装4节的，也有一板装6节的。两种包装的电池各买一板，一共是多少节电池。如果买 3 板 6 节装的，一共是多少节电池。",
+    "options": [],
+    "answer": "10节;18节",
+    "solution": "【分析】把一板4节电池和一板6节电池合并起来，用加法计算，可以求出两种包装各买一板的电池数量;求3个6的和是多少，用乘法计算，可以求出买3板6节装的电池数量，据此解答.\n【详解】根据分析可得:(1)4 + 6 = 10(节),答：两种包装的电池各买一板，一共是10节电池。(2)3×6 = 18(节),答：如果买3板6节装的，一共是18节电池。",
+    "knowledge_points": [
+      "10的加减法",
+      "6的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·河北邯郸·期末"
+  },
+  {
+    "id": "195",
+    "unit": "第四单元 表内乘法",
+    "question_type": "解答题",
+    "difficulty": 0.65,
+    "question": "下图是停车场收费标准.\n\n![](images/ec1d7880a7f6b4220b66cf7910aec6870bb027c4feccb9cfcc8e7304745247c8.jpg)\n\n(1)停靠 3 辆面包车要收费多少钱。\n(2)停靠 1 辆货车和 6 辆小汽车一共要收费多少钱。",
+    "options": [],
+    "answer": "18元;32元",
+    "solution": "【分析】(1)用停靠一辆面包车的钱数乘 3 即可求解。(2)用停靠一辆货车的钱数加停靠 6 辆小汽车的钱数即可，停靠一辆小汽车的钱数乘6即可求出停靠6辆小汽车的钱数.\n【详解】(1)6×3 = 18(元),答：停靠 3 辆面包车要收费 18 元钱。(2)8 + 4×6 = 8 + 24 = 32(元),答：停靠1辆货车和6辆小汽车一共要收费32元钱。",
+    "knowledge_points": [
+      "6 的乘法口诀及应用",
+      "表内乘加，乘减"
+    ],
+    "source": "24-25 二年级上·吉林·期末"
+  },
+  {
+    "id": "196",
+    "unit": "第四单元 表内乘法",
+    "question_type": "解答题",
+    "difficulty": 0.85,
+    "question": "面包店今天做了 88 个面包，上午卖出 50 个，下午卖出 32 个.\n(1)面包店还剩下多少个面包。\n(2)如果每个面包 3 元钱，剩下的面包可以卖多少元。",
+    "options": [],
+    "answer": "6个;18元",
+    "solution": "【分析】(1)用今天做的面包数量先减去上午卖出的数量，求出差，再减去下午卖出的数量，求出差，即可解决。(2)用每个面包的价钱乘剩下的面包数量，求出积，就是剩下的面包可以卖出的价钱.\n【详解】(1)88 - 50 - 32 = 38 - 32 = 6(个),答：面包店还剩下6个面包。(2)3×6 = 18(元),答：剩下的面包可以卖18元。",
+    "knowledge_points": [
+      "100 以内数的连减运算",
+      "6 的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·全国·期末"
+  },
+  {
+    "id": "197",
+    "unit": "第四单元 表内乘法",
+    "question_type": "解答题",
+    "difficulty": 0.85,
+    "question": "同学们装饰教室，二(1)班买 2 盒气球，一盒 5 个，一盒 6 个;二(2)班买5 盒气球，每盒 6 个。哪个班买的气球多。",
+    "options": [],
+    "answer": "二(2)班多",
+    "solution": "【分析】已知二(1)班买了 2 盒气球，一盒 5 个，一盒 6 个，相加即可得出一共有多少个气球;已知二(2)班买了 5 盒气球，每盒 6 个，加法计算为 6 + 6 + 6 + 6 + 6，可转换为乘法计算即 5 乘 6，再对比两个班的数量即可.\n【详解】 5 + 6 = 11(个),5×6 = 30(个),因为 30 > 11，所以 2 班比 1 班多。答：二(2)班买的气球多。",
+    "knowledge_points": [
+      "100 以内数的比大小",
+      "7,6 加几的进位加法",
+      "6的乘法口诀及应用"
+    ],
+    "source": "23-24 二年级上·河北石家庄·期末"
+  },
+  {
+    "id": "198",
+    "unit": "第四单元 表内乘法",
+    "question_type": "解答题",
+    "difficulty": 0.85,
+    "question": "两个小组给树浇水。第一小组有 5 名同学，每人浇了 4 棵树，第一小组一共浇了多少棵树。第二小组比第一小组多浇了 6 棵树，第二小组一共浇了多少棵树。",
+    "options": [],
+    "answer": "20棵;26棵",
+    "solution": "【分析】第一小组有5名同学，每人浇了4棵树，求第一小组一共浇了多少棵树，就是求5个4的和是多少，用乘法列式解决;然后用第一小组浇树的棵数加上6棵，求出和，就是第二小组浇树的棵数.\n【详解】 4×5 = 20(棵),20 + 6 = 26(棵),答：第一小组一共浇了20棵树;第二小组一共浇了26棵树。",
+    "knowledge_points": [
+      "整十数加，减一位数",
+      "5 的乘法口诀及应用"
+    ],
+    "source": "23-24 二年级上·山东菏泽·期末"
+  },
+  {
+    "id": "199",
+    "unit": "第四单元 表内乘法",
+    "question_type": "解答题",
+    "difficulty": 0.65,
+    "question": "一根绳子对折两次后长3米，这根绳子原来长多少米。",
+    "options": [],
+    "answer": "12 米",
+    "solution": "【分析】根据题意，因为绳子对折两次后折成了4段，而每段的长都是3米，用每段绳子的长度乘绳子的段数即可求出绳子原来长多少米，据此解答即可.\n【详解】 3×4 = 12(米),答：这根绳子原来长12米。",
+    "knowledge_points": [
+      "图形的折叠问题",
+      "4 的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·河北秦皇岛·期末"
+  },
+  {
+    "id": "200",
+    "unit": "第四单元 表内乘法",
+    "question_type": "解答题",
+    "difficulty": 0.65,
+    "question": "花店里面的花有一朵 3 瓣，一朵 6 瓣，一朵 24 瓣的.\n(1)买 4 朵 3 瓣和一朵 24 瓣的，一共有多少瓣花。\n(2)4 朵 6 瓣的和一朵 24 瓣的比较，哪种多。\n(3)自己提出一个问题，并解答。",
+    "options": [],
+    "answer": "36瓣;一样多;5朵6瓣的花一共有多少瓣花。30瓣(本小题答案不唯一)",
+    "solution": "【分析】(1)根据乘法的意义，用 4×3 先算出4朵3瓣的花有多少瓣，再加上一朵24瓣的，即可得出答案;(2)根据乘法的意义，用 4×6 先求出4朵6瓣的花有多少瓣，再跟24进行比较大小，即可得出答案;(3)根据题干信息，结合学过的数学信息，提出问题并解答即可，本小题答案不唯一。例如:5朵6瓣的花一共有多少瓣花。\n【详解】(1)4×3 + 24 = 12 + 24 = 36(瓣),答：一共有36瓣花。(2)4×6 = 24(瓣),24 = 24，答:4朵6瓣的和一朵24瓣一样多。(3)5朵6瓣的花一共有多少瓣花。5×6 = 30(瓣),答:5朵6瓣的花一共有30瓣花。(本小题答案不唯一)",
+    "knowledge_points": [
+      "\"提问题\"\"填条件\"问题",
+      "6的乘法口诀及应用",
+      "表内乘加，乘减"
+    ],
+    "source": "23-24 二年级上·新疆昌吉·期末"
+  },
+  {
+    "id": "201",
+    "unit": "第四单元 表内乘法",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "5×6 + 28 的结果是()。",
+    "options": [
+      "A. 48",
+      "B. 58",
+      "C. 56"
+    ],
+    "answer": "B",
+    "solution": "【分析】混合运算中有加法和乘法，先算乘法，再算加法.\n【详解】5×6 + 28 = 30 + 28 = 58,5×6 + 28 的结果是 58。故答案为:B.",
+    "knowledge_points": [
+      "表内乘加，乘减"
+    ],
+    "source": "23-24 二年级上·河北保定·期末"
+  },
+  {
+    "id": "202",
+    "unit": "第四单元 表内乘法",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面哪个问题不可以用 3×5 解决。( )。",
+    "options": [
+      "A. ![](images/83f45c1cddea43116a4436fd101f1393f8695dea29e6d850610927c60424bd0a.jpg)",
+      "B. ![](images/b679ee35353168492aaabdc815e96ea2184e70952309037715e1588659a2e7e0.jpg)",
+      "C. ![](images/9b135c4dfe6c06db4140e5f89f2713355a83b1ead65fddc402766506c5fa06b6.jpg)"
+    ],
+    "answer": "B",
+    "solution": "【分析】乘法表示几个相同加数的和。能用 3×5 表示的问题必须是\"3 个 5 的和\"或\"5 个 3 的和\".\n【详解】A 表示一包 5 片,3 包一共几片，是 3 个 5 的和，可用 3×5;B 表示左边 3 元，右边 5 元，一共多少钱，是 3 + 5;C 表示一段长 3 厘米，一支笔相当于 5 段，是 5 个 3 的和，可用 3×5。只有 B 不能用 3×5 解决。故答案为:B.",
+    "knowledge_points": [
+      "8,9的加减法",
+      "初步认识乘法意义"
+    ],
+    "source": "23-24 二年级上·河北保定·期末"
+  },
+  {
+    "id": "203",
+    "unit": "第四单元 表内乘法",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "( )能用算式\"5×2\"表示。",
+    "options": [
+      "A. ![](images/82f4cb4c7b9c6a425a20c0e0ec158fab5c542433eb9d077281db18b52c569821.jpg)",
+      "B. ![](images/84d0c091427e264885ac3a656d418a41bdefc1f4ebcf8f00465552c174e95f3a.jpg)",
+      "C. ![](images/13b88e022ff07d98a2299b0f7453465df0d7bab32a21513792af4d2f1f02a64a.jpg)"
+    ],
+    "answer": "A",
+    "solution": "【分析】5×2 可以表示 2 个 5 的和或 5 个 2 的和.\n【详解】A 图：每行 5 个，共 2 行，是 2 个 5 的和，符合 5×2;B 图：第一行 2 个，第二行 5 个，表示 2 和 5 的和;C 图：第一行 4 个，第二行 5 个，表示 4 和 5 的和。故能用\"5×2\"表示的是 A。答案为:A.",
+    "knowledge_points": [
+      "图文问题",
+      "初步认识乘法意义"
+    ],
+    "source": "23-24 二年级上·河北保定·期末"
+  },
+  {
+    "id": "204",
+    "unit": "第四单元 表内乘法",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "积是 12 的算式是()。",
+    "options": [
+      "A. 6 + 6",
+      "B. 6×2",
+      "C. 6×6"
+    ],
+    "answer": "B",
+    "solution": "【分析】乘法中乘数×乘数 = 积，直接用口诀判断积.\n【详解】A:6 + 6 = 12，是和不是积;B:6×2 = 12，积是 12;C:6×6 = 36，积是 36。故选 6×2。答案为:B.",
+    "knowledge_points": [
+      "7,6加几的进位加法",
+      "6的乘法口诀及应用"
+    ],
+    "source": "23-24 二年级上·广东韶关·期末"
+  },
+  {
+    "id": "205",
+    "unit": "第四单元 表内乘法",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "李老师带领 6 名同学去信丰县城参加诗词大赛，去时买车票需要( )元钱.\n\n![](images/2026-02-25%20132733.jpg)",
+    "options": [
+      "A. 30",
+      "B. 35",
+      "C. 38"
+    ],
+    "answer": "C",
+    "solution": "【分析】需买 6 张儿童票和 1 张成人票。先算 6 名同学的票钱，再加成人票钱.\n【详解】儿童票 5 元，成人票 8 元。6 名同学:6×5 = 30(元),再加 8 元:30 + 8 = 38(元)。故去时买车票需要 38 元。答案为:C.",
+    "knowledge_points": [
+      "乘加，乘减混合运算"
+    ],
+    "source": "23-24 二年级上·江西赣州·期末"
+  },
+  {
+    "id": "206",
+    "unit": "第四单元 表内乘法",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "5 个 4 相加，下列算式错误的是( )。",
+    "options": [
+      "A. 5 + 4",
+      "B. 5×4",
+      "C. 4 + 4 + 4 + 4 + 4"
+    ],
+    "answer": "A",
+    "solution": "【分析】5 个 4 相加，可以用加法算式或乘法算式表示.\n【详解】A:5 + 4 表示 5 和 4 的和，不是 5 个 4 的和;B:5×4 可以表示 5 个 4 的和;C:4 + 4 + 4 + 4 + 4 是 5 个 4 的和。错误的是 A。答案为:A.",
+    "knowledge_points": [
+      "同数连加的应用",
+      "初步认识乘法意义"
+    ],
+    "source": "23-24 二年级上·山东菏泽·期末"
+  },
+  {
+    "id": "207",
+    "unit": "第四单元 表内乘法",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "适合改写成乘法算式的是( )。",
+    "options": [
+      "A. 9 + 8 + 7 + 6",
+      "B. 6 + 6 + 6 + 6",
+      "C. 4 - 2 - 2"
+    ],
+    "answer": "B",
+    "solution": "【分析】只有\"几个相同加数连加\"才能方便地改写成乘法算式.\n【详解】A:加数不同;B:6 + 6 + 6 + 6 是 4 个 6 相加，可写成 4×6 或 6×4;C:连减不能直接写成乘法算式。故答案为:B.",
+    "knowledge_points": [
+      "同数连加的应用",
+      "初步认识乘法意义"
+    ],
+    "source": "23-24 二年级上·河南郑州·期末"
+  },
+  {
+    "id": "208",
+    "unit": "第四单元 表内乘法",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "7 + 7 + 7 + 5 可以改写成算式( )。",
+    "options": [
+      "A. 7×4",
+      "B. 7×3 + 5",
+      "C. 7×4 + 2"
+    ],
+    "answer": "B",
+    "solution": "【分析】7 + 7 + 7 + 5 可以看作 3 个 7 的和再加 5，也可看作 4 个 7 的和再减 2.\n【详解】改写成与选项形式一致的:7×3 + 5 或 7×4 - 2。B 正确;A 缺少 +5;C 表示 4 个 7 再加 2，不符合原式。故答案为:B.",
+    "knowledge_points": [
+      "表内乘加，乘减"
+    ],
+    "source": "23-24 二年级上·河南郑州·期末"
+  },
+  {
+    "id": "209",
+    "unit": "第四单元 表内乘法",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "两个乘数都是 6 的算式是( )。",
+    "options": [
+      "A. 2×6",
+      "B. 6×6",
+      "C. 6 + 6"
+    ],
+    "answer": "B",
+    "solution": "【分析】乘法中两个数字都是 6 的算式才符合条件.\n【详解】A:乘数是 2 和 6;B:两个乘数都是 6;C:是加法不是乘法。故答案为:B.",
+    "knowledge_points": [
+      "7,6加几的进位加法",
+      "初步认识乘法意义"
+    ],
+    "source": "23-24 二年级上·浙江台州·期末"
+  },
+  {
+    "id": "210",
+    "unit": "第四单元 表内乘法",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下图中一共有多少个。下面的算式错误的是( ).\n\n![](images/94c925cdd9098ffa72834805c53983e2bf6b395ff0ba5aed3c9fd137a3b126c5.jpg)",
+    "options": [
+      "A. 6×3 + 3",
+      "B. 6×4 - 3",
+      "C. 6×4 + 3"
+    ],
+    "answer": "C",
+    "solution": "【分析】从图可看出，每行 6 个，一共有 4 行，但少 3 个;也可看作 3 行 6 个再多 3 个.\n【详解】6×3 + 3 和 6×4 - 3 都能正确表示图中数量;6×4 + 3 表示\"4 行 6 个再多 3 个\"，比图中多 6 个，不符合。故错误的是 C.",
+    "knowledge_points": [
+      "表内乘加，乘减"
+    ],
+    "source": "23-24 三年级上·吉林四平·期末"
+  },
+  {
+    "id": "211",
+    "unit": "第四单元 表内乘法",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "2 + 2 + 2 + 2 + 2 + 1 可以写成( )。",
+    "options": [
+      "A. 5×2",
+      "B. 6×2 - 1",
+      "C. 2×5 - 1"
+    ],
+    "answer": "B",
+    "solution": "【分析】算式里有 5 个 2 和 1 个 1，可把 2 + 2 + 2 + 2 + 2 + 1 看成 6 个 2 相加再减 1.\n【详解】A:5×2 只是 5 个 2 的和;B:6×2 - 1 = 12 - 1，先把 6 个 2 相加再减 1，等于原式;C:2×5 - 1 是 5 个 2 的和再减 1，不等于原式。故答案为:B.",
+    "knowledge_points": [
+      "表内乘加，乘减"
+    ],
+    "source": "24-25 二年级上·新疆乌鲁木齐·期中"
+  },
+  {
+    "id": "212",
+    "unit": "第四单元 表内乘法",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "2×5 这个算式表示的意义是( )。",
+    "options": [
+      "A. 2个5相乘",
+      "B. 2和5相加",
+      "C. 2个5相加"
+    ],
+    "answer": "C",
+    "solution": "【分析】乘法算式表示几个相同加数的和.\n【详解】A:2 个 5 相乘应写成 5×5;B:2 和 5 相加应写成 2 + 5;C:2×5 表示 2 个 5 相加，符合题意。故答案为:C.",
+    "knowledge_points": [
+      "初步认识乘法意义"
+    ],
+    "source": "24-25 二年级上·新疆乌鲁木齐·期中"
+  },
+  {
+    "id": "213",
+    "unit": "第四单元 表内乘法",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "如图，在这个正六边形上摆珠子，每条边上摆 4 颗，至少要摆( ).\n\n![](images/e2040c1474a6cc517646a74b543805594091bce647d21793c303efe9e8561713.jpg)",
+    "options": [
+      "A. 20 颗",
+      "B. 24 颗",
+      "C. 18 颗"
+    ],
+    "answer": "C",
+    "solution": "【分析】要珠子总数最少，每个顶点只摆 1 颗,6 条边每边 4 颗，共 6×4，但每个顶点被两条边重复计算一次，需要减去 6 颗重复的.\n【详解】4×6 - 6 = 24 - 6 = 18(颗),至少要摆 18 颗。故答案为:C.",
+    "knowledge_points": [
+      "表内乘加，乘减"
+    ],
+    "source": "23-24 二年级上·浙江杭州·期末"
+  },
+  {
+    "id": "214",
+    "unit": "第四单元 表内乘法",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "如果 ○ + ○ + ○ + ○ + ○ = 10,△ + △ = 10，那么 ○ * △ = ( )。",
+    "options": [
+      "A. 5",
+      "B. 10",
+      "C. 15"
+    ],
+    "answer": "B",
+    "solution": "【分析】5 个 ○ 的和是 10,2 个 △ 的和是 10，先求出 ○ 和 △ 的值，再相乘.\n【详解】5×2 = 10，所以 ○ = 2;2×5 = 10，所以 △ = 5;○ * △ = 2×5 = 10。故答案为:B.",
+    "knowledge_points": [
+      "5的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·广东梅州·期中"
+  },
+  {
+    "id": "215",
+    "unit": "第四单元 表内乘法",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "求 4 个 6 相加的和是多少，列成乘法算式是( )。",
+    "options": [
+      "A. 4 + 6",
+      "B. 6 + 6 + 6 + 6",
+      "C. 4×6 或 6×4"
+    ],
+    "answer": "C",
+    "solution": "【分析】几个相同加数的和可以写成乘法算式，用\"相同加数×个数\"或\"个数×相同加数\".\n【详解】4 个 6 相加的和是 6 + 6 + 6 + 6，可写成乘法算式 4×6 或 6×4。故答案为:C.",
+    "knowledge_points": [
+      "同数连加的应用",
+      "初步认识乘法意义"
+    ],
+    "source": "24-25 二年级上·广东梅州·期中"
+  },
+  {
+    "id": "216",
+    "unit": "第四单元 表内乘法",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "求下图中一共有多少个黑色小正方形，列式正确的是( ).\n\n![](images/2bb1cf991b0cd71311c4d779f4819ee408c1d25aab57bb1f7129507da27040e8.jpg)",
+    "options": [
+      "A. 4×5 + 1",
+      "B. 5×4 - 1",
+      "C. 5×4 - 3"
+    ],
+    "answer": "C",
+    "solution": "【分析】可以看作每组 4 个，有 5 组少 3 个，也可以有其他等价写法.\n【详解】5×4 - 3 正确表示\"5 组 4 个再少 3 个\"。其他两项与图中数量不符。故答案为:C.",
+    "knowledge_points": [
+      "图文问题",
+      "4的乘法口诀及应用",
+      "表内乘加，乘减"
+    ],
+    "source": "23-24 二年级上·福建三明·期末"
+  },
+  {
+    "id": "217",
+    "unit": "第四单元 表内乘法",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "用 2×6 可以解决下面哪个问题。我的选择是( )。",
+    "options": [
+      "A. ![](images/de92f890b446783198fa87d3cfb9ea051ff8d6f2145cd4d511ff9b061a1b612b.jpg)",
+      "B. ![](images/9d617febb7a8e6706c041f576feab78bf1de4e20f76cb0696ec8950898251f9c.jpg)",
+      "C. ![](images/2026-02-25%20134222.jpg)"
+    ],
+    "answer": "C",
+    "solution": "【分析】2×6 表示\"6 个 2 的和\"或\"2 个 6 的和\"，即\"一个 2 元，一共 6 个\"这类问题.\n【详解】A:是 2 + 6 的情景;B:是 6 - 2 的情景;C:每个 2 元，一共 6 个，总价用 2×6 表示，符合。故答案为:C.",
+    "knowledge_points": [
+      "6 的加减法",
+      "8,9 的加减法",
+      "6 的乘法口诀及应用"
+    ],
+    "source": "23-24 二年级上·福建三明·期末"
+  },
+  {
+    "id": "218",
+    "unit": "第四单元 表内乘法",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "如图，两幢房子之间每隔 6 米有一棵树，这两幢房子之间相距( )米.\n\n![](images/72a84df58515b98ff5731d32981025ccaad137088fbc3ee084cb4c4cb89ef57e.jpg)",
+    "options": [],
+    "answer": "36",
+    "solution": "【分析】图中一共有 5 棵树，两端还包括房子间的 6 个间隔，每个间隔 6 米.\n【详解】共有 6 个间隔，每个 6 米:6×6 = 36(米)。两幢房子之间相距 36 米。",
+    "knowledge_points": [
+      "图文问题",
+      "6 的乘法口诀及应用"
+    ],
+    "source": "23-24 二年级上·河北保定·期末"
+  },
+  {
+    "id": "219",
+    "unit": "第四单元 表内乘法",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "如图，求上图一共有多少块手表，列乘法算式是( )(块),读作( ).\n\n![](images/2026-02-25%20135021.jpg)",
+    "options": [],
+    "answer": "3×5 = 15;3乘5等于15",
+    "solution": "【分析】几行，每行几个，可以用乘法算式表示手表总数.\n【详解】每行 5 块，共 3 行:3×5 = 15(块),读作\"3 乘 5 等于 15\"。",
+    "knowledge_points": [
+      "图文问题",
+      "5的乘法口诀及应用"
+    ],
+    "source": "23-24 二年级上·河北保定·期末"
+  },
+  {
+    "id": "220",
+    "unit": "第四单元 表内乘法",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "5 + 5 + 5 + 5 = ( ),写成乘法算式是( ),所用的口诀是( )。",
+    "options": [],
+    "answer": "20;5×4 = 20;四五二十",
+    "solution": "【分析】5 + 5 + 5 + 5 表示 4 个 5 相加，可写成乘法算式.\n【详解】5 + 5 + 5 + 5 = 20，写成乘法算式是 5×4 = 20，所用的口诀是\"四五二十\"。",
+    "knowledge_points": [
+      "同数连加的应用",
+      "5 的乘法口诀及应用"
+    ],
+    "source": "23-24 二年级上·河北保定·期末"
+  },
+  {
+    "id": "221",
+    "unit": "第四单元 表内乘法",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "4 和 5 相加，和是( ),4 个 5 相加，和是( )。",
+    "options": [],
+    "answer": "9;20",
+    "solution": "【分析】前一空是加法，后一空是几个 5 相加的乘法.\n【详解】4 + 5 = 9;4 个 5 相加:4×5 = 20。",
+    "knowledge_points": [
+      "8,9 的加减法",
+      "初步认识乘法意义",
+      "5 的乘法口诀及应用"
+    ],
+    "source": "23-24 二年级上·山东菏泽·期末"
+  },
+  {
+    "id": "222",
+    "unit": "第四单元 表内乘法",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "每串有( )个，共有( )串。列乘法算式是:( )×( ) = ( ),乘法口诀是( ).\n\n![](images/a81f7ba941faa91d707e581785e35f24ebab0db11011ea09840e88855e0139a6.jpg)",
+    "options": [],
+    "answer": "4;3;4;3;12;三四十二",
+    "solution": "【分析】先数每串的个数，再数串数，乘起来得总数，再写出对应口诀.\n【详解】每串 4 个，共 3 串:4×3 = 12，口诀是\"三四十二\"。",
+    "knowledge_points": [
+      "同数连加的应用",
+      "初步认识乘法意义",
+      "4 的乘法口诀及应用"
+    ],
+    "source": "23-24 二年级上·河南郑州·期末"
+  },
+  {
+    "id": "223",
+    "unit": "第四单元 表内乘法",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "在括号里面填上相同的数，使算式成立:\n( )×( ) = ( ) + ( )",
+    "options": [],
+    "answer": "2;2;2;2",
+    "solution": "【分析】要使乘法和加法结果相等，且四个括号里填相同的数.\n【详解】2×2 = 4,2 + 2 = 4，因此填 2×2 = 2+2。故四个括号都填 2。",
+    "knowledge_points": [
+      "同数连加的应用",
+      "初步认识乘法意义",
+      "2的乘法口诀及应用"
+    ],
+    "source": "23-24 二年级上·重庆丰都·期末"
+  },
+  {
+    "id": "224",
+    "unit": "第四单元 表内乘法",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "如图表示( )个( ),列乘法算式是( )或( ),计算时用到的乘法口诀是( ).\n\n![](images/875b7a29b7faddc84235ba4bd9797cf712be00ed0a3c9482f9c9c32a73197eee.jpg)\n![](images/8a43d21ebe946fbf43732e16d6afa516ee6aad29cf93c24891ce8fe98e90345f.jpg)\n![](images/ca02fb8356e4083d1be85cc96fca4d5c3621fd78a07e1b8082300a4a713f9d8a.jpg)",
+    "options": [],
+    "answer": "3;6;6×3 = 18;3×6 = 18;三六十八",
+    "solution": "【分析】图表示\"3 个 6\"，可以写成 6×3 或 3×6，两种写法都对应口诀\"三六十八\".\n【详解】如图表示 3 个 6，乘法算式是 6×3 = 18 或 3×6 = 18，计算时用到乘法口诀\"三六十八\"。",
+    "knowledge_points": [
+      "图文问题",
+      "6 的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·重庆·期中"
+  },
+  {
+    "id": "225",
+    "unit": "第四单元 表内乘法",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "8 + 8 + 8 + 8 + 8 写成乘法算式是( ),读作( )。",
+    "options": [],
+    "answer": "8×5;8乘5等于40",
+    "solution": "【分析】8 + 8 + 8 + 8 + 8 是 5 个 8 相加，可以写成\"相同加数×个数\".\n【详解】乘法算式是 8×5，读作\"8 乘 5\"。",
+    "knowledge_points": [
+      "同数连加的应用",
+      "初步认识乘法意义"
+    ],
+    "source": "23-24 二年级上·四川德阳·期末"
+  },
+  {
+    "id": "226",
+    "unit": "第四单元 表内乘法",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "在括号里填上\">\"\"<\"或\"=\".\n400 厘米( )4 米;62 + 17( )89;6×2( )3×4\n1 米 - 22 厘米( )88 厘米;78 - 15( )62;5×2( )4×4",
+    "options": [],
+    "answer": "=;<;=;<;>;<",
+    "solution": "【分析】先把各算式算出结果，再比较大小;涉及单位的要统一单位.\n【详解】400 厘米 = 4 米;62 + 17 = 79 < 89;6×2 = 12,3×4 = 12，故\"=\";1 米 - 22 厘米 = 100 - 22 = 78 厘米 < 88 厘米;78 - 15 = 63 > 62;5×2 = 10 < 4×4 = 16。",
+    "knowledge_points": [
+      "100 以内数的比大小",
+      "5 的乘法口诀及应用",
+      "6的乘法口诀及应用",
+      "厘米和米之间的进率与换算"
+    ],
+    "source": "24-25 二年级上·新疆乌鲁木齐·期中"
+  },
+  {
+    "id": "227",
+    "unit": "第四单元 表内乘法",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "你喜欢的乘法口诀是( ),根据这句口诀写一个加法算式和一个乘法算式。",
+    "options": [],
+    "answer": "示例：四五二十;5 + 5 + 5 + 5 = 20;4×5 = 20",
+    "solution": "【分析】任选一条乘法口诀，将\"几个相同加数的和\"写成加法算式和乘法算式即可.\n【详解】例如选\"四五二十\"，加法算式:5 + 5 + 5 + 5 = 20;乘法算式:4×5 = 20。(本题答案不唯一。)",
+    "knowledge_points": [
+      "初步认识乘法意义",
+      "5 的乘法口诀及应用"
+    ],
+    "source": "23-24 二年级上·福建福州·期末"
+  },
+  {
+    "id": "228",
+    "unit": "第四单元 表内乘法",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "算式 6 + 6 + 6 + 6 中，相同的加数是( ),相同的加数有( )个，改写成乘法算式是( )或( )。",
+    "options": [],
+    "answer": "6;4;6×4 = 24;4×6 = 24",
+    "solution": "【分析】同数连加：相同加数为 6，加数个数为 4.\n【详解】6 + 6 + 6 + 6 中相同加数是 6，有 4 个，乘法算式是 6×4 = 24 或 4×6 = 24。",
+    "knowledge_points": [
+      "同数连加的应用",
+      "初步认识乘法意义"
+    ],
+    "source": "24-25 二年级上·湖北十堰·期中"
+  },
+  {
+    "id": "229",
+    "unit": "第四单元 表内乘法",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "在括号里填上\">\"\"<\"或\"=\".\n28( )5×6;2×5( )2 + 5;5×3( )5×4 - 5\n20 元( )20 角;54 角( )4 元 5 角;1 元 5 角( )15 角",
+    "options": [],
+    "answer": "<;>;=;>;>;=",
+    "solution": "【分析】先算出各算式的值，人民币统一成同一单位(角或元)比较.\n【详解】5×6 = 30,28 < 30;2×5 = 10,2 + 5 = 7,10 > 7;5×3 = 15,5×4 - 5 = 20 - 5 = 15，相等;20 角 = 2 元,20 元 > 2 元;4 元 5 角 = 45 角,54 角 > 45 角;1 元 5 角 = 15 角，等于 15 角。",
+    "knowledge_points": [
+      "100以内数的比大小",
+      "6的乘法口诀及应用",
+      "元，角，分的认识及换算",
+      "表内乘加，乘减"
+    ],
+    "source": "24-25 二年级上·广东梅州·期中"
+  },
+  {
+    "id": "230",
+    "unit": "第四单元 表内乘法",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "4×6 用到的乘法口诀是( )。",
+    "options": [],
+    "answer": "四六二十四",
+    "solution": "【分析】从乘法口诀表中找到 4 和 6 的口诀即可.\n【详解】4×6 的口诀是\"四六二十四\"。",
+    "knowledge_points": [
+      "6的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·广西贵港·期中"
+  },
+  {
+    "id": "231",
+    "unit": "第四单元 表内乘法",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "30÷5 = ( ),计算时需要用到口诀( )。",
+    "options": [],
+    "answer": "6;五六三十",
+    "solution": "【分析】用乘法口诀反推除法：被除数是口诀中的积，除数和商是前两个数.\n【详解】\"五六三十\"表示 5×6 = 30，所以 30÷5 = 6，需要用到口诀\"五六三十\"。",
+    "knowledge_points": [
+      "6的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·广西贵港·期中"
+  },
+  {
+    "id": "232",
+    "unit": "第四单元 表内乘法",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "有十几个小朋友在玩游戏，把他们平均分成 6 组，每组人数一样多，最多有( )个小朋友。",
+    "options": [],
+    "answer": "18",
+    "solution": "【分析】人数是\"十几\"，即 10~19 之间，同时要能被 6 整除.\n【详解】6 的乘法口诀中:1×6 = 6,2×6 = 12,3×6 = 18,4×6 = 24。十几的倍数只有 12 和 18，且最多的是 18。所以最多有 18 个小朋友。",
+    "knowledge_points": [
+      "20 以内数的比大小",
+      "6 的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·河南新乡·期中"
+  },
+  {
+    "id": "233",
+    "unit": "第四单元 表内乘法",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "如果 ○ + ○ = 10,△ + △ + △ = 9，那么 ○ * △ = ( )。",
+    "options": [],
+    "answer": "15",
+    "solution": "【分析】把同数连加改写成乘法，先求出 ○ 和 △ 各是多少，再相乘.\n【详解】2 * ○ = 10，由\"二五一十\"得 ○ = 5;3 * △ = 9，由\"三三得九\"得 △ = 3;○ * △ = 5×3 = 15。",
+    "knowledge_points": [
+      "初步认识乘法意义",
+      "5的乘法口诀及应用",
+      "3的乘法口诀及应用"
+    ],
+    "source": "23-24 二年级上·河南南阳·期末"
+  },
+  {
+    "id": "234",
+    "unit": "第四单元 表内乘法",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "6 + 6 + 6 + 6 + 4 = ( )×( ) - ( )。",
+    "options": [],
+    "answer": "5;6;2",
+    "solution": "【分析】6 + 6 + 6 + 6 + 4 可以看作 5 个 6 的和再减去 2.5 个 6 的和写成乘法算式是 5×6.\n【详解】6 + 6 + 6 + 6 + 4 = 5×6 - 2，所以括号里依次填 5,6,2。",
+    "knowledge_points": [
+      "表内乘加，乘减"
+    ],
+    "source": "23-24 二年级上·河南南阳·期末"
+  },
+  {
+    "id": "235",
+    "unit": "第四单元 表内乘法",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "在括号里填上\">\"\"<\"或\"=\".\n6×2( )11;5×6( )28;3×4( )6×2\n4×5( )4 + 5;99 厘米( )1 米;2 + 2( )2×2",
+    "options": [],
+    "answer": ">;>;=;>;<;=",
+    "solution": "【分析】【详解】6×2 = 12,12 > 11;5×6 = 30,30 > 28;3×4 = 12,6×2 = 12，所以 3×4 = 6×2;4×5 = 20,4 + 5 = 9，所以 20 > 9;1 米 = 100 厘米,99 厘米 < 100 厘米，所以 99 厘米 < 1 米;2 + 2 = 4,2×2 = 4，所以 2 + 2 = 2×2。",
+    "knowledge_points": [
+      "100以内数的比大小",
+      "5的乘法口诀及应用",
+      "6的乘法口诀及应用",
+      "厘米和米之间的进率与换算"
+    ],
+    "source": "24-25 二年级上·河南漯河·期中"
+  },
+  {
+    "id": "236",
+    "unit": "第四单元 表内乘法",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "在括号里填上\">\"\"<\"或\"=\".\n6×2( )11;5×6( )28;3×4( )6×2\n4×5( )4 + 5;9 厘米( )1 米;2 + 2( )2×2",
+    "options": [],
+    "answer": ">;>;=;>;<;=",
+    "solution": "【分析】【详解】6×2 = 12 > 11;5×6 = 30 > 28;3×4 = 12,6×2 = 12，所以 3×4 = 6×2;4×5 = 20 > 4 + 5 = 9;9 厘米 < 1 米 = 100 厘米;2 + 2 = 4 = 2×2。",
+    "knowledge_points": [
+      "100 以内数的比大小",
+      "5 的乘法口诀及应用",
+      "6的乘法口诀及应用",
+      "厘米和米之间的进率与换算"
+    ],
+    "source": "24-25 二年级上·河南驻马店·期中"
+  },
+  {
+    "id": "237",
+    "unit": "第四单元 表内乘法",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "3 个 3 相加的和是( )。3 和 3 相加的和是( )。",
+    "options": [],
+    "answer": "9;6",
+    "solution": "【分析】3 个 3 相加是\"3 个 3 的和\",3 和 3 相加是\"两个数 3 和 3 的和\".\n【详解】3×3 = 9，所以 3 个 3 相加的和是 9;3 + 3 = 6，所以 3 和 3 相加的和是 6。",
+    "knowledge_points": [
+      "初步认识乘法意义",
+      "3 的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·河南漯河·期中"
+  },
+  {
+    "id": "238",
+    "unit": "第四单元 表内乘法",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "5 + 5 + 5 + 4 写成乘加算式( ),也可以写成乘减算式( )。",
+    "options": [],
+    "answer": "5×3 + 4 = 19;5×4 - 1 = 19",
+    "solution": "【分析】5 + 5 + 5 + 4 可以看作 3 个 5 的和再加 4，也可以看作 4 个 5 的和再减 1.\n【详解】5 + 5 + 5 + 4 = 5×3 + 4 = 15 + 4 = 19，也可以写成 5×4 - 1 = 20 - 1 = 19。",
+    "knowledge_points": [
+      "初步认识乘法意义",
+      "表内乘加，乘减"
+    ],
+    "source": "23-24 二年级上·重庆永川·期末"
+  },
+  {
+    "id": "239",
+    "unit": "第四单元 表内乘法",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "在 5 + 5 + 5 + 5 = 20 中，相同加数是( ),相同加数的个数是( ),写成乘法算式是( )或( )。",
+    "options": [],
+    "answer": "5;4;5×4 = 20;4×5 = 20",
+    "solution": "【分析】5 + 5 + 5 + 5 表示 4 个 5 相加的和.\n【详解】相同加数是 5，相同加数个数是 4，写成乘法算式是 5×4 = 20 或 4×5 = 20。",
+    "knowledge_points": [
+      "初步认识乘法意义"
+    ],
+    "source": "24-25 二年级上·河南周口·期中"
+  },
+  {
+    "id": "240",
+    "unit": "第四单元 表内乘法",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "在括号里填上\">\"\"<\"或\"=\".\n86 - 60( )33;4×6( )6 + 6 + 6 + 6;70 米( )1 米 - 30 厘米",
+    "options": [],
+    "answer": "<;=;>",
+    "solution": "【分析】【详解】86 - 60 = 26 < 33;4×6 = 24,6 + 6 + 6 + 6 = 24，所以相等;70 米远大于 1 米 - 30 厘米 = 100 厘米 - 30 厘米 = 70 厘米，所以 70 米 > 1 米 - 30 厘米。",
+    "knowledge_points": [
+      "100以内数的比大小",
+      "两位数与整十数的减法",
+      "6的乘法口诀及应用",
+      "厘米和米之间的进率与换算"
+    ],
+    "source": "24-25 二年级上·广东汕头·期中"
+  },
+  {
+    "id": "241",
+    "unit": "第四单元 表内乘法",
+    "question_type": "解答题",
+    "difficulty": 0.85,
+    "question": "乐乐和他的 5 个好朋友一起用积木拼小汽车，每人拼了3辆小汽车，一共拼了( )辆小汽车。",
+    "options": [],
+    "answer": "18",
+    "solution": "【分析】先求出一共有几个人，再用人数乘每人拼的小汽车数量.\n【详解】乐乐和 5 个好朋友共 1 + 5 = 6(人),每人 3 辆:3×6 = 18(辆)。答：一共拼了 18 辆小汽车。",
+    "knowledge_points": [
+      "6的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·广西南宁·期中"
+  },
+  {
+    "id": "242",
+    "unit": "第四单元 表内乘法",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "两个乘数都是 4，积是( ),两个加数都是 3，和是( )。",
+    "options": [],
+    "answer": "16;6",
+    "solution": "【分析】乘法用\"乘数×乘数 = 积\"，加法用\"加数 + 加数 = 和\".\n【详解】4×4 = 16，所以两个乘数都是 4，积是 16;3 + 3 = 6，所以两个加数都是 3，和是 6。",
+    "knowledge_points": [
+      "6的加减法",
+      "4的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·西藏拉萨·期中"
+  },
+  {
+    "id": "243",
+    "unit": "第四单元 表内乘法",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "在括号里填上\"+\"或\"*\".\n4( )3 = 12;1( )4 = 5;4( )5 = 20;3( )5 = 8\n5( )3 = 15;4( )2 = 6;2( )3 = 6;4( )4 = 16",
+    "options": [],
+    "answer": "*;+;*;+;*;+;*;*",
+    "solution": "【分析】根据等号右边的结果判断应填加号还是乘号，结合乘法口诀和简单加法.\n【详解】4×3 = 12;1 + 4 = 5;4×5 = 20;3 + 5 = 8;5×3 = 15;4 + 2 = 6;2×3 = 6;4×4 = 16。",
+    "knowledge_points": [
+      "5以内数的减法",
+      "5的乘法口诀及应用",
+      "4的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·河北沧州·期中"
+  },
+  {
+    "id": "244",
+    "unit": "第四单元 表内乘法",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "6 + 6 + 6 + 6 = ( ),写成乘法算式是( ),读作( ),计算时用的乘法口诀是( )。",
+    "options": [],
+    "answer": "24;6×4 = 24;6乘4等于24;四六二十四",
+    "solution": "【分析】4 个 6 相加可以写成乘法算式 6×4 或 4×6.\n【详解】6 + 6 + 6 + 6 = 24，写成乘法算式是 6×4 = 24(或 4×6 = 24),读作\"6 乘 4 等于 24\"，用到的乘法口诀是\"四六二十四\"。",
+    "knowledge_points": [
+      "初步认识乘法意义",
+      "6 的乘法口诀及应用"
+    ],
+    "source": "23-24 二年级上·浙江温州·期末"
+  },
+  {
+    "id": "245",
+    "unit": "第四单元 表内乘法",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "括号里最大能填几。\n( )×4 < 20;13 > 4×( );( )×6 < 21",
+    "options": [],
+    "answer": "4;3;3",
+    "solution": "【分析】根据乘法口诀找出使不等式成立且\"最大\"的数.\n【详解】4×4 = 16 < 20,4×5 = 20 不小于 20，所以第一个括号填 4;4×3 = 12 < 13,4×4 = 16 > 13，所以第二个括号填 3;3×6 = 18 < 21,4×6 = 24 > 21，所以第三个括号填 3。",
+    "knowledge_points": [
+      "100 以内数的比大小",
+      "5 的乘法口诀及应用",
+      "4的乘法口诀及应用",
+      "6 的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·新疆乌鲁木齐·期中"
+  },
+  {
+    "id": "246",
+    "unit": "第四单元 表内乘法",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "5 + 5 + 5 + 5 = 20，也就是求( )个( )相加的和是多少，改写成乘法算式是( ),计算时用到的乘法口诀是( )。",
+    "options": [],
+    "answer": "4;5;5×4 = 20;四五二十",
+    "solution": "【分析】5 + 5 + 5 + 5 表示 4 个 5 相加的和.\n【详解】是求 4 个 5 的和，改写成乘法算式是 5×4 = 20 或 4×5 = 20，计算时用到的乘法口诀是\"四五二十\"。",
+    "knowledge_points": [
+      "同数连加的应用",
+      "初步认识乘法意义",
+      "5 的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·新疆乌鲁木齐·期中"
+  },
+  {
+    "id": "247",
+    "unit": "第四单元 表内乘法",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "2 个 8 相加是( ),2 和 8 相加是( ),8 个 5 相加写成乘法算式是( )。",
+    "options": [],
+    "answer": "16;10;5×8 = 40",
+    "solution": "【分析】前两空是加法结果，第三空是同数连加改写成乘法.\n【详解】2 个 8 相加:8 + 8 = 16;2 和 8 相加:2 + 8 = 10;8 个 5 相加写成乘法算式是 5×8 = 40(或 8×5 = 40)。",
+    "knowledge_points": [
+      "初步认识乘法意义"
+    ],
+    "source": "23-24 二年级上·浙江绍兴·期末"
+  },
+  {
+    "id": "248",
+    "unit": "第四单元 表内乘法",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "8 + 8 + 8 + 8 + 8 + 8 + 8 = ( )×( );3 + 3 + 3 + 6 = ( )×( ) 。",
+    "options": [],
+    "answer": "8;7;3;5",
+    "solution": "【分析】同数连加可以写成乘法算式，注意把 6 分解成 3 + 3.\n【详解】8 + 8 + 8 + 8 + 8 + 8 + 8 是 7 个 8 的和，写成乘法算式是 8×7(或 7×8);3 + 3 + 3 + 6 中,6 = 3 + 3，总共是 5 个 3 的和，写成乘法算式是 3×5(或 5×3)。",
+    "knowledge_points": [
+      "同数连加的应用",
+      "初步认识乘法意义"
+    ],
+    "source": "23-24 二年级上·浙江杭州·期末"
+  },
+  {
+    "id": "249",
+    "unit": "第四单元 表内乘法",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "3 个 5 是( ),加法算式是( ),乘法算式是( ),读作( ),口诀是( )。",
+    "options": [],
+    "answer": "15;5 + 5 + 5 = 15;3×5 = 15;3乘5等于15;三五十五",
+    "solution": "【分析】3 个 5 是 3 个 5 相加的和，可以用加法和乘法两种形式表示.\n【详解】3 个 5 是 15;加法算式是 5 + 5 + 5 = 15;乘法算式是 3×5 = 15;读作\"3 乘 5 等于 15\";口诀是\"三五十五\"。",
+    "knowledge_points": [
+      "同数连加的应用",
+      "初步认识乘法意义",
+      "5 的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·广西玉林·期中"
+  },
+  {
+    "id": "250",
+    "unit": "第四单元 表内乘法",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "把加法算式改写成乘法算式.\n8 + 8 = 16;6 + 6 + 6 + 6 = 24;9 + 9 + 9 = 27\n( )×( ) = ( );( )×( ) = ( );( )×( ) = ( )",
+    "options": [],
+    "answer": "2;8;16;4;6;24;3;9;27",
+    "solution": "【分析】同数连加改写成乘法，用\"个数×相同加数\"或\"相同加数×个数\".\n【详解】8 + 8 = 16 写成乘法算式是 2×8 = 16;6 + 6 + 6 + 6 = 24 写成乘法算式是 4×6 = 24;9 + 9 + 9 = 27 写成乘法算式是 3×9 = 27(或 9×3 = 27)。",
+    "knowledge_points": [
+      "初步认识乘法意义"
+    ],
+    "source": "24-25 二年级上·河南商丘·期中"
+  },
+  {
+    "id": "251",
+    "unit": "第四单元 表内乘法",
+    "question_type": "解答题",
+    "difficulty": 0.85,
+    "question": "有一些梨，比 20 个多，比 30 个少，平均放在一些盘子里，每个盘子里的梨个数和盘子数一样多，共有( )个梨。",
+    "options": [],
+    "answer": "25",
+    "solution": "【分析】梨的个数大于 20 小于 30，又能表示成\"盘子数×每盘个数\"，且两个乘数相等.\n【详解】两乘数相等的表内乘法有:4×4 = 16,5×5 = 25,6×6 = 36。其中只有 25 在 20 和 30 之间，所以共有 25 个梨。",
+    "knowledge_points": [
+      "5 的乘法口诀及应用",
+      "4 的乘法口诀及应用",
+      "6的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·河南周口·期中"
+  },
+  {
+    "id": "252",
+    "unit": "第四单元 表内乘法",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "两个乘数都是 5，积是( ),用乘法口诀( )来计算。",
+    "options": [],
+    "answer": "25;五五二十五",
+    "solution": "【分析】乘法口诀中两个乘数都是 5 的是\"五五二十五\".\n【详解】5×5 = 25，两个乘数都是 5，积是 25，用乘法口诀\"五五二十五\"计算。",
+    "knowledge_points": [
+      "5 的乘法口诀及应用"
+    ],
+    "source": "20-21 二年级上·福建厦门·期末"
+  },
+  {
+    "id": "253",
+    "unit": "第四单元 表内乘法",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "如果一个\"□\"等于 6，那么\"品\"等于 ( )。",
+    "options": [],
+    "answer": "18",
+    "solution": "【分析】一个\"品\"由 3 个\"□\"组成，如果一个\"□\"等于 6，那么一个\"品\"是 3 个 6 的和.\n【详解】3×6 = 18，所以\"品\"等于 18。",
+    "knowledge_points": [
+      "6的乘法口诀及应用"
+    ],
+    "source": "23-24 二年级上·福建福州·期末"
+  },
+  {
+    "id": "254",
+    "unit": "第四单元 表内乘法",
+    "question_type": "解答题",
+    "difficulty": 0.65,
+    "question": "2 张![](images/b5c7bbbcba57f30523228c122b90254de3d65dbda85ada7120a5201ee1ac1109.jpg)和 4 张![](images/0ba341fbdc6f8eb1d69692580377ba36570d6726f3efa322aba6d1358f6c69ef.jpg)合起来是( )元。",
+    "options": [],
+    "answer": "42",
+    "solution": "【分析】2 张 20 元是 2 个 20 的和;4 张 5 角是 4 个 5 的和，再把角换算成元.\n【详解】2 张 20 元:20 + 20 = 40(元);4 张 5 角:4×5 = 20(角)= 2(元);合起来 40 + 2 = 42(元)。",
+    "knowledge_points": [
+      "整十数之间的加减法",
+      "5的乘法口诀及应用",
+      "元，角，分的认识及换算"
+    ],
+    "source": "24-25 二年级上·广东梅州·期中"
+  },
+  {
+    "id": "255",
+    "unit": "第四单元 表内乘法",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "6 与 3 的和是( ),4 个 5 的和是( ),6 与 6 的积是( )。",
+    "options": [],
+    "answer": "9;20;36",
+    "solution": "【分析】前两空是加法和\"几个相同加数的和\"，最后一空是乘法积.\n【详解】6 + 3 = 9;4 个 5 的和:5×4 = 20;6 与 6 的积:6×6 = 36。",
+    "knowledge_points": [
+      "8,9 的加减法",
+      "初步认识乘法意义",
+      "6 的乘法口诀及应用"
+    ],
+    "source": "23-24 二年级上·福建福州·期末"
+  },
+  {
+    "id": "256",
+    "unit": "第四单元 表内乘法",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "6 和 7 的和，列式是6×7。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】两个数的和用加法表示，几个相同加数的和可以用乘法表示.\n【详解】6 和 7 的和应列式 6 + 7;6 个 7 的和才列式 6×7。题目把\"和\"写成乘法，错误。故答案为: ×。",
+    "knowledge_points": [
+      "7,6 加几的进位加法",
+      "初步认识乘法意义"
+    ],
+    "source": "23-24 二年级上·河南郑州·期末"
+  },
+  {
+    "id": "257",
+    "unit": "第四单元 表内乘法",
+    "question_type": "判断题",
+    "difficulty": 0.65,
+    "question": "只有加数完全相同的加法算式才能写成与乘法有关的算式。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】可以先把不完全相同的加法通过拆分或合并，变成同数连加，再与乘法联系起来.\n【详解】例如 2 + 2 + 4,4 = 2 + 2，这个算式实际是 4 个 2 的和，可以写成 2×4 或 4×2。说明不是只有加数完全相同的加法才能写成与乘法有关的算式。故答案为: ×。",
+    "knowledge_points": [
+      "初步认识乘法意义"
+    ],
+    "source": "23-24 二年级上·重庆丰都·期末"
+  },
+  {
+    "id": "258",
+    "unit": "第四单元 表内乘法",
+    "question_type": "判断题",
+    "difficulty": 0.65,
+    "question": "4 + 4 改写成乘法算式是 4×4 。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】4 + 4 表示 2 个 4 的和.\n【详解】4 + 4 = 2 个 4 的和，改写成乘法算式是 2×4 或 4×2，而不是 4×4。故答案为: ×。",
+    "knowledge_points": [
+      "初步认识乘法意义",
+      "4 的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·西藏拉萨·期中"
+  },
+  {
+    "id": "259",
+    "unit": "第四单元 表内乘法",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "5 + 5×5，可以写成 5×5。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】先把 5×5 换成加法，再加上前面的 5，就能看出有几个 5 相加.\n【详解】5×5 表示 5 + 5 + 5 + 5 + 5，再加上前面一个 5，总共是 6 个 5，相当于 5×6 或 6×5，而不是 5×5。故原说法错误，答案为:*。",
+    "knowledge_points": [
+      "初步认识乘法意义",
+      "5 的乘法口诀及应用",
+      "6 的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·新疆乌鲁木齐·期中"
+  },
+  {
+    "id": "260",
+    "unit": "第四单元 表内乘法",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "两个数相加的和一定小于这两个数相乘的积。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】可以举反例：当两个数较小时，加法结果反而可能更大.\n【详解】取两个数 1 和 2:1 + 2 = 3,1×2 = 2,3 > 2。说明和不一定小于积。故原说法错误，答案为:*。",
+    "knowledge_points": [
+      "2 的乘法口诀及应用"
+    ],
+    "source": "23-24 三年级上·四川攀枝花·期末"
+  },
+  {
+    "id": "261",
+    "unit": "第四单元 表内乘法",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "求几个相同加数的和，用乘法算比较简便。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】同数连加既可以用加法，也可以用乘法表示，但乘法更简便.\n【详解】例如 3 + 3 + 3 + 3 + 3，用乘法写成 3×5 或 5×3，乘法写法简短，计算方便，所以\"用乘法算比较简便\"是正确的。答案为:√。",
+    "knowledge_points": [
+      "同数连加的应用",
+      "初步认识乘法意义"
+    ],
+    "source": "20-21 二年级上·河南驻马店·期中"
+  },
+  {
+    "id": "262",
+    "unit": "第四单元 表内乘法",
+    "question_type": "计算题",
+    "difficulty": 0.85,
+    "question": "看图列式计算.\n\n![](images/ee69b1c1f3e277472916cfa02aac153cb639ed3002d81a589199859b1dddc6be.jpg)\n![](images/b9a6085e590f3906eb355f5588702b73e9a3afbc3951d52feb5ea73512442c5f.jpg)\n![](images/29b687d031c79e3160c78f242446ea44462019a5b2731e970cfe21c4ff230d19.jpg)\n![](images/54596c2e240d1955eb7ca8af9e26c338ecafdd22600ac63bc9c7110c5ae71e6e.jpg)\n\n□ ○ □ = □",
+    "options": [],
+    "answer": "3×4 = 12",
+    "solution": "【分析】图中每组有 3 个圆柱，一共有 4 组，求总个数就是求 4 个 3 的和.\n【详解】3×4 = 12，一共有 12 个圆柱。",
+    "knowledge_points": [
+      "图文问题",
+      "4的乘法口诀及应用"
+    ],
+    "source": "23-24 二年级上·河北保定·期末"
+  },
+  {
+    "id": "263",
+    "unit": "第四单元 表内乘法",
+    "question_type": "计算题",
+    "difficulty": 0.85,
+    "question": "看图列式并计算.\n\n![](images/86e86b3f1523c0c0e08efd4679ddbf238f94082f7f127ee190ee55b3f8e92aae.jpg)",
+    "options": [],
+    "answer": "6×3 + 3 = 21",
+    "solution": "【分析】前 3 盘每盘 6 个，最后一盘 3 个，求总数就是 3 个 6 的和再加 3.\n【详解】6×3 + 3 = 18 + 3 = 21(个),月饼一共有 21 个。",
+    "knowledge_points": [
+      "6 的乘法口诀及应用",
+      "表内乘加，乘减"
+    ],
+    "source": "23-24 二年级上·河北石家庄·期末"
+  },
+  {
+    "id": "264",
+    "unit": "第四单元 表内乘法",
+    "question_type": "计算题",
+    "difficulty": 0.65,
+    "question": "看图列式计算.\n\n![](images/47c2bf9f6187ae771bc02925d0d64a028fa0c4d898eb58e17e3a848609ec6c32.jpg)\n\n□ ○ □ = □(米)",
+    "options": [],
+    "answer": "4×5 = 20(米)",
+    "solution": "【分析】每两棵树之间间隔 4 米，一共有 5 个间隔，总长度是间隔数与每个间隔长度的乘积.\n【详解】4×5 = 20(米),总长度是 20 米。",
+    "knowledge_points": [
+      "图文问题",
+      "5 的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·西藏那曲·期末"
+  },
+  {
+    "id": "265",
+    "unit": "第四单元 表内乘法",
+    "question_type": "计算题",
+    "difficulty": 0.65,
+    "question": "看图列式计算.\n\n![](images/4e6c51261fc53a569a3cebf3a3142a9bc117b7bb9d6a5a684eacd9058731ddf7.jpg)",
+    "options": [],
+    "answer": "3×4 + 2 = 14 或 3×5 - 1 = 14",
+    "solution": "【分析】前 4 份每份 3 个，最后一份 2 个，可以看作 4 个 3 的和再加 2;也可以看作 5 个 3 的和再减 1.\n【详解】3×4 + 2 = 12 + 2 = 14(个),或 3×5 - 1 = 15 - 1 = 14(个),一共有 14 个桃子。",
+    "knowledge_points": [
+      "图文问题",
+      "表内乘加，乘减"
+    ],
+    "source": "24-25 二年级上·西藏那曲·期末"
+  },
+  {
+    "id": "266",
+    "unit": "第四单元 表内乘法",
+    "question_type": "计算题",
+    "difficulty": 0.94,
+    "question": "直接写出得数.\n2×4 =();6×3 =();4×4 =();5×2 =();6×6 =();3×4 =();5×1 =();4×6 =()",
+    "options": [],
+    "answer": "8;18;16;10;36;12;5;24",
+    "solution": "【分析】【详解】根据乘法口诀:2×4 = 8;6×3 = 18;4×4 = 16;5×2 = 10;6×6 = 36;3×4 = 12;5×1 = 5;4×6 = 24。",
+    "knowledge_points": [
+      "5的乘法口诀及应用",
+      "4的乘法口诀及应用",
+      "6的乘法口诀及应用"
+    ],
+    "source": "23-24 二年级上·陕西安康·期末"
+  },
+  {
+    "id": "267",
+    "unit": "第四单元 表内乘法",
+    "question_type": "计算题",
+    "difficulty": 0.85,
+    "question": "直接写出得数.\n53 - 6 =();42 + 15 =();93 - 27 =();3 + 6×1 =();3×5 =();2×4 =();12 + 34 =();9 - 2×4 =();22 - 7 =();45 - 23 =();6×3 =();34 - 16 + 2 =()",
+    "options": [],
+    "answer": "47;57;66;9;15;8;46;1;15;22;18;20",
+    "solution": "【分析】包含加减法，乘法和乘加，乘减混合运算，注意先算乘法再算加减.\n【详解】53 - 6 = 47;42 + 15 = 57;93 - 27 = 66;3 + 6×1 = 3 + 6 = 9;3×5 = 15;2×4 = 8;12 + 34 = 46;9 - 2×4 = 9 - 8 = 1;22 - 7 = 15;45 - 23 = 22;6×3 = 18;34 - 16 + 2 = 18 + 2 = 20。",
+    "knowledge_points": [
+      "两位数与两位数的退位减法",
+      "4的乘法口诀及应用",
+      "6 的乘法口诀及应用",
+      "表内乘加，乘减"
+    ],
+    "source": "24-25 二年级上·新疆乌鲁木齐·期中"
+  },
+  {
+    "id": "268",
+    "unit": "第四单元 表内乘法",
+    "question_type": "计算题",
+    "difficulty": 0.65,
+    "question": "看图列式计算.\n\n![](images/082616948fcc4c8a3d42d0481ae71432b5cd5e0dc273052463ef576ce0498721.jpg)",
+    "options": [],
+    "answer": "3×6 + 4 = 22",
+    "solution": "【分析】左边 3 筐，每筐 6 个，右边还有 4 个，一共是 3 个 6 的和再加 4.\n【详解】3×6 + 4 = 18 + 4 = 22(个)。",
+    "knowledge_points": [
+      "图文问题",
+      "6的乘法口诀及应用",
+      "乘加，乘减混合运算"
+    ],
+    "source": "24-25 二年级上·河南周口·期中"
+  },
+  {
+    "id": "269",
+    "unit": "第四单元 表内乘法",
+    "question_type": "计算题",
+    "difficulty": 0.85,
+    "question": "直接写得数.\n98 - 20 =();9 + 40 =();80 - 17 =();36 + 30 =();48 - 6 - 4 =();32 + 40 - 12 =();70 - 9 + 10 =();90 - 8 - 60 =();5×3 =();4×2 =();6×6 =();3×6 =();2×4 + 3 =();3×5 - 4 =();6×5 - 10 =();5×4 + 3 =()",
+    "options": [],
+    "answer": "78;49;63;66;38;60;71;22;15;8;36;18;11;11;20;23",
+    "solution": "【分析】先按加减法和乘法的运算规则计算，乘加，乘减要先乘后加减.\n【详解】98 - 20 = 78;9 + 40 = 49;80 - 17 = 63;36 + 30 = 66;48 - 6 - 4 = 38;32 + 40 - 12 = 60;70 - 9 + 10 = 71;90 - 8 - 60 = 22;5×3 = 15;4×2 = 8;6×6 = 36;3×6 = 18;2×4 + 3 = 8 + 3 = 11;3×5 - 4 = 15 - 4 = 11;6×5 - 10 = 30 - 10 = 20;5×4 + 3 = 20 + 3 = 23。",
+    "knowledge_points": [
+      "100以内数的加减混合运算",
+      "6的乘法口诀及应用",
+      "表内乘加，乘减"
+    ],
+    "source": "24-25 二年级上·河南新乡·期中"
+  },
+  {
+    "id": "270",
+    "unit": "第四单元 表内乘法",
+    "question_type": "计算题",
+    "difficulty": 0.85,
+    "question": "看图列式.\n\n![](images/c7e02c5b6ab6417812464081149ecf36931d4439b29fc22a1c4f26df4e60d271.jpg)",
+    "options": [],
+    "answer": "5×3 = 15",
+    "solution": "【分析】根据图意，每份有 3 个，共 5 份，求一共多少个，就是求 5 个 3 的和，用乘法计算.\n【详解】5×3 = 15(个),所以一共有 15 个。",
+    "knowledge_points": [
+      "图文问题",
+      "5 的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·江西宜春·期中"
+  },
+  {
+    "id": "271",
+    "unit": "第四单元 表内乘法",
+    "question_type": "计算题",
+    "difficulty": 0.85,
+    "question": "看图列式计算.\n\n![](images/77461661bc1bf5885bab4cf51a24263cee2f0b65d7906152482fddf31fa56c24.jpg)\n\n□ ○ □ ○ □ = □(瓶)",
+    "options": [],
+    "answer": "3×5 + 2 = 17(瓶)",
+    "solution": "【分析】从图中可以看出：一组有 5 瓶水，有 3 组，还多 2 瓶，求一共多少瓶，就是先用乘法求出 3 组有几瓶，再加上多出的 2 瓶.\n【详解】3×5 + 2 = 15 + 2 = 17(瓶),所以一共有 17 瓶水。",
+    "knowledge_points": [
+      "图文问题",
+      "表内乘加，乘减"
+    ],
+    "source": "24-25 二年级上·湖北武汉·期中"
+  },
+  {
+    "id": "272",
+    "unit": "第四单元 表内乘法",
+    "question_type": "计算题",
+    "difficulty": 0.65,
+    "question": "看图列式.\n\n![](images/f05d6623b423bebb3d6f538c967e41dccfddead7347e7c321cdeeca8b5075940.jpg)\n\n□ * □ ○ □ = □",
+    "options": [],
+    "answer": "4×5 + 3 = 23",
+    "solution": "【分析】前 4 束每束 5 个，是 4 个 5 的和，再加上最后一束的 3 个，就是总个数.\n【详解】4×5 + 3 = 20 + 3 = 23，因此一共有 23 个。",
+    "knowledge_points": [
+      "图文问题",
+      "表内乘加，乘减"
+    ],
+    "source": "24-25 二年级上·江西宜春·期中"
+  },
+  {
+    "id": "273",
+    "unit": "第四单元 表内乘法",
+    "question_type": "计算题",
+    "difficulty": 0.65,
+    "question": "看图列式计算.\n\n![](images/fdcda00f5d237dfd9211c538c34b751f810db5d02f2d4310c405d979c7f8efe4.jpg)\n\n□ * □ + □ = □(条)\n□ * □ - □ = □(条)",
+    "options": [],
+    "answer": "3×5 + 4 = 19;4×5 - 1 = 19",
+    "solution": "【分析】前 3 个鱼缸每缸 5 条鱼，第 4 个鱼缸 4 条鱼，可以看作 3 个 5 的和再加 4;也可看作 4 个 5 的和再减 1.\n【详解】3×5 + 4 = 15 + 4 = 19(条),或者 4×5 - 1 = 20 - 1 = 19(条),一共有 19 条鱼。",
+    "knowledge_points": [
+      "图文问题",
+      "5的乘法口诀及应用",
+      "表内乘加，乘减"
+    ],
+    "source": "24-25 二年级上·山东青岛·期中"
+  },
+  {
+    "id": "274",
+    "unit": "第四单元 表内乘法",
+    "question_type": "计算题",
+    "difficulty": 0.85,
+    "question": "直接写出得数.\n4×3 =();5×4 =();16 + 21 =();2×5 =();3×2 =();82 - 59 =();46 - 25 =();54 + 28 =();",
+    "options": [],
+    "answer": "12;20;37;10;6;23;21;82",
+    "solution": "【分析】乘法算式用乘法口诀直接求得，加减法注意是否进位或退位.\n【详解】4×3 = 12;5×4 = 20;16 + 21 = 37;2×5 = 10;3×2 = 6;82 - 59 = 23;46 - 25 = 21;54 + 28 = 82。",
+    "knowledge_points": [
+      "两位数与两位数的进位加法",
+      "两位数与两位数的退位减法",
+      "5的乘法口诀及应用",
+      "4的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·河南周口·期中"
+  },
+  {
+    "id": "275",
+    "unit": "第四单元 表内乘法",
+    "question_type": "计算题",
+    "difficulty": 0.85,
+    "question": "列式计算。一个乘数是 5，另一个乘数是 3，积是多少。",
+    "options": [],
+    "answer": "15",
+    "solution": "【分析】根据\"乘数×乘数 = 积\"列出乘法算式.\n【详解】5×3 = 15，所以积是 15。",
+    "knowledge_points": [
+      "5的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·广东汕头·期中"
+  },
+  {
+    "id": "276",
+    "unit": "第四单元 表内乘法",
+    "question_type": "计算题",
+    "difficulty": 0.85,
+    "question": "直接写出得数.\n6×3 =();64 + 8 =();24 + 53 =();3×5 + 9 =();4×4 =();96 - 33 =();1×6 =();4×6 - 7 =();5×2 =();100 - 80 =();3×2 =();5×5 - 4 =()",
+    "options": [],
+    "answer": "18;72;77;24;16;63;6;17;10;20;6;21",
+    "solution": "【分析】乘法用口诀，乘加，乘减要先算乘法再算加减.\n【详解】6×3 = 18;64 + 8 = 72;24 + 53 = 77;3×5 + 9 = 15 + 9 = 24;4×4 = 16;96 - 33 = 63;1×6 = 6;4×6 - 7 = 24 - 7 = 17;5×2 = 10;100 - 80 = 20;3×2 = 6;5×5 - 4 = 25 - 4 = 21。",
+    "knowledge_points": [
+      "两位数与两位数的不进位加法",
+      "两位数与两位数的不退位减法",
+      "6的乘法口诀及应用",
+      "表内乘加，乘减"
+    ],
+    "source": "24-25 二年级上·广东汕头·期中"
+  },
+  {
+    "id": "277",
+    "unit": "第四单元 表内乘法",
+    "question_type": "计算题",
+    "difficulty": 0.85,
+    "question": "看图写算式.\n\n![](images/753260cfccedbeb17324b310bf025f42e8468cbd114b8a3bfd452b45c317c497.jpg)",
+    "options": [],
+    "answer": "4×6 + 3 = 27(颗)",
+    "solution": "【分析】一组糖有 4 颗，有 6 组，再加上 3 颗，总数是 6 个 4 的和再加 3.\n【详解】4×6 + 3 = 24 + 3 = 27(颗),一共有 27 颗糖。",
+    "knowledge_points": [
+      "图文问题",
+      "表内乘加，乘减"
+    ],
+    "source": "24-25 二年级上·山东济南·期中"
+  },
+  {
+    "id": "278",
+    "unit": "第四单元 表内乘法",
+    "question_type": "解答题",
+    "difficulty": 0.65,
+    "question": "小九，小威，小帮和我每人从盒子里拿了6颗糖果，盒子里还剩下37颗糖果，盒子里原来有多少颗糖果。",
+    "options": [],
+    "answer": "61颗",
+    "solution": "【分析】先算 4 个人一共拿了多少颗糖，再加上盒子里剩下的颗数，就是原来盒子里的糖果数.\n【详解】4 个人:6×4 = 24(颗),原来有 24 + 37 = 61(颗)。答：盒子里原来有 61 颗糖果。",
+    "knowledge_points": [
+      "6的乘法口诀及应用",
+      "乘加，乘减混合运算"
+    ],
+    "source": "23-24 二年级上·河北保定·期末"
+  },
+  {
+    "id": "279",
+    "unit": "第四单元 表内乘法",
+    "question_type": "解答题",
+    "difficulty": 0.65,
+    "question": "一盒巧克力的价钱和 4 袋锅巴的价钱相同，一盒巧克力多少元。一听可乐的价钱比一盒巧克力便宜 15 元，一听可乐多少元。\n\n![](images/f95e18b1d5f5891cbe3fe66b8376f15b24e9c1ab3725e51bd662723ab341af6c.jpg)\n![](images/f9a652e1634e95fe8ade8cbbdbc2bdb95e735dd91d0b48b825fd7f1424dedb62.jpg)\n![](images/7d25230e0d23da6d1ac4549083f861ef59431dd78e5ed8395f8ca1d64681df98.jpg)",
+    "options": [],
+    "answer": "20元;5元",
+    "solution": "【分析】(1)用 1 袋锅巴的价钱乘 4 得到一盒巧克力的价钱。(2)用一盒巧克力的价钱减去 15 元得到一听可乐的价钱.\n【详解】(1)5×4 = 20(元),答：一盒巧克力 20 元。(2)20 - 15 = 5(元),答：一听可乐 5 元。",
+    "knowledge_points": [
+      "经济问题",
+      "两位数与两位数的退位减法",
+      "5的乘法口诀及应用"
+    ],
+    "source": "23-24 二年级上·河北保定·期末"
+  },
+  {
+    "id": "280",
+    "unit": "第四单元 表内乘法",
+    "question_type": "解答题",
+    "difficulty": 0.65,
+    "question": "把一根丝带连续对折两次后，每段长度都是 6 米，奶奶需要 15 米丝带做花边，这根丝带够吗。",
+    "options": [],
+    "answer": "够",
+    "solution": "【分析】连续对折两次后，一根丝带被分成 4 段。已知每段 6 米，先求出丝带原来的总长度，再与 15 米比较.\n【详解】2×2 = 4(段),6×4 = 24(米),24 > 15，所以这根丝带够。答：够。",
+    "knowledge_points": [
+      "100以内数的比大小",
+      "2的乘法口诀及应用",
+      "6的乘法口诀及应用"
+    ],
+    "source": "23-24 二年级上·甘肃天水·期末"
+  },
+  {
+    "id": "281",
+    "unit": "第四单元 表内乘法",
+    "question_type": "解答题",
+    "difficulty": 0.85,
+    "question": "二(1)班同学去郊游，租了5辆面包车，每辆面包车坐6人，所有人上车后还有 2 个空座位。这次一共去了多少人。",
+    "options": [],
+    "answer": "28人",
+    "solution": "【分析】先求 5 辆面包车一共可以坐多少人，再减去空座位的数量，得到实际去的人数.\n【详解】5×6 = 30(人),30 - 2 = 28(人)。答：这次一共去了 28 人。",
+    "knowledge_points": [
+      "表内乘加，乘减"
+    ],
+    "source": "23-24 二年级上·甘肃天水·期末"
+  },
+  {
+    "id": "282",
+    "unit": "第四单元 表内乘法",
+    "question_type": "解答题",
+    "difficulty": 0.85,
+    "question": "解决问题.\n\n![](images/a67c98aefe24224a432c5fe530d1215a106f0ef27d28aa3d8879b3e4ffb51865.jpg)\n\n一个 5 元，一共多少元。(元)\n\n□ ○ □ = □(元)",
+    "options": [],
+    "answer": "5×6 = 30(元)",
+    "solution": "【分析】图中共有 6 个，每个 5 元，用单价乘数量即可求出总价.\n【详解】5×6 = 30(元),答：一共 30 元。",
+    "knowledge_points": [
+      "图文问题",
+      "6 的乘法口诀及应用"
+    ],
+    "source": "23-24 二年级上·四川广元·期末"
+  },
+  {
+    "id": "283",
+    "unit": "第四单元 表内乘法",
+    "question_type": "解答题",
+    "difficulty": 0.85,
+    "question": "(1)女生组浇树，一行3棵，一行6棵。女生组浇了多少棵。\n(2)男生组浇树，浇了 3 行，每行 6 棵。男生组浇了多少棵。",
+    "options": [],
+    "answer": "9棵;18棵",
+    "solution": "【分析】(1)女生组是两行树，直接相加即可;(2)男生组是几行，每行几棵，用乘法计算.\n【详解】(1)3 + 6 = 9(棵),答：女生组浇了 9 棵.\n(2)3×6 = 18(棵),答：男生组浇了 18 棵。",
+    "knowledge_points": [
+      "8,9的加减法",
+      "6的乘法口诀及应用"
+    ],
+    "source": "23-24 二年级上·四川德阳·期末"
+  },
+  {
+    "id": "284",
+    "unit": "第四单元 表内乘法",
+    "question_type": "解答题",
+    "difficulty": 0.65,
+    "question": "教室里原来有4排桌子，每排6张，同学们搬走了3张，现在教室里还剩多少张桌子。",
+    "options": [],
+    "answer": "21 张",
+    "solution": "【分析】先用乘法求出原来教室里一共有多少张桌子，再减去搬走的数量.\n【详解】原来有 4×6 = 24(张),搬走 3 张,24 - 3 = 21(张)。答：现在教室里还剩 21 张桌子。",
+    "knowledge_points": [
+      "表内乘加，乘减"
+    ],
+    "source": "24-25 二年级上·新疆乌鲁木齐·期中"
+  },
+  {
+    "id": "285",
+    "unit": "第四单元 表内乘法",
+    "question_type": "解答题",
+    "difficulty": 0.85,
+    "question": "每盘有5个苹果，有3盘，一共有多少个苹果。\n\n![](images/1837f7c022edf669bcbc1874e91b15f2ceee8e5ad8130dbb7185feb39525f14a.jpg)\n![](images/c4d12f52bb6ff989fef66de12da8008fa2fc76aa02a1836b1383394fd576e774.jpg)\n![](images/0d1e08d1208120036cb1fb4bd4380078423d0ca576917982ffd93819c0b60d99.jpg)",
+    "options": [],
+    "answer": "15个",
+    "solution": "【分析】每盘 5 个，有 3 盘，是求 3 个 5 的和，用乘法计算更简便.\n【详解】5×3 = 15(个),答：一共有 15 个苹果。",
+    "knowledge_points": [
+      "图文问题",
+      "5 的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·湖北十堰·期中"
+  },
+  {
+    "id": "286",
+    "unit": "第四单元 表内乘法",
+    "question_type": "解答题",
+    "difficulty": 0.65,
+    "question": "提一个可以用 4×5 = 20 解决的数学问题。",
+    "options": [],
+    "answer": "示例：每个笔记本4元，买5个笔记本需要多少元。",
+    "solution": "【分析】4×5 表示 4 个 5 的和或 5 个 4 的和，可以设计\"每个 4 元，买 5 个\"或\"每个 5 元，买 4 个\"的问题.\n【详解】示例：每个笔记本 4 元，买 5 个笔记本需要多少元。4×5 = 20(元)。答：买 5 个笔记本需要 20 元。(本题答案不唯一。)",
+    "knowledge_points": [
+      "\"提问题\"\"填条件\"问题",
+      "5 的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·河南驻马店·期中"
+  },
+  {
+    "id": "287",
+    "unit": "第四单元 表内乘法",
+    "question_type": "解答题",
+    "difficulty": 0.65,
+    "question": "面包店做了一些蛋挞，每盒装3个，装了5盒，还剩2个，面包店一共做多少个蛋挞。",
+    "options": [],
+    "answer": "17个",
+    "solution": "【分析】先用乘法求出 5 盒一共装了多少个，再加上剩下的 2 个，就是一共做的个数.\n【详解】3×5 + 2 = 15 + 2 = 17(个)。答：面包店一共做了 17 个蛋挞。",
+    "knowledge_points": [
+      "表内乘加，乘减"
+    ],
+    "source": "24-25 二年级上·河南驻马店·期中"
+  },
+  {
+    "id": "288",
+    "unit": "第四单元 表内乘法",
+    "question_type": "解答题",
+    "difficulty": 0.65,
+    "question": "购物.\n\n![](images/2026-02-25%20163844.jpg)\n\n(1)明明买了 4 块三明治和 1 杯果汁，一共要付多少钱。\n(2)丽丽买了 3 块巧克力和 1 盒牛奶，付给售货员 50 元，应找回多少钱。",
+    "options": [],
+    "answer": "12元;32元",
+    "solution": "【分析】(1)三明治用乘法求 4 块的价钱，再加果汁的钱;(2)先求 3 块巧克力加 1 盒牛奶一共花了多少，再用 50 元减去花掉的钱.\n【详解】(1)4×2 = 8(元),8 + 4 = 12(元)。答：一共要付 12 元.\n(2)3×5 = 15(元),15 + 3 = 18(元),50 - 18 = 32(元)。答：应找回 32 元。(本题中还可另提乘法问题，略。)",
+    "knowledge_points": [
+      "5 的乘法口诀及应用",
+      "3 的乘法口诀及应用",
+      "4的乘法口诀及应用",
+      "表内乘加，乘减"
+    ],
+    "source": "24-25 二年级上·福建厦门·期中"
+  },
+  {
+    "id": "289",
+    "unit": "第四单元 表内乘法",
+    "question_type": "解答题",
+    "difficulty": 0.65,
+    "question": "买文具.\n\n![](images/f4643217b52118a97c0d39fd067f8ccee38b271f6148b5bd694ce347bf89a648.jpg)\n3元/盒\n\n![](images/9df706f7fe7851f01051b82c22db9e5b81133e41a8758900816b3d68dc7be971.jpg)\n6元/个\n\n![](images/1bbc453d98c279435ff897bf020d2db7850a633705108ecdcaefb15a37d0c952.jpg)\n2元/本\n\n![](images/1d78d3bf40b05030b593aedf198f9a3ca3201683e5f2d393f9358f3c77aa1af9.jpg)\n5元/支\n\n(1)买 5 盒蜡笔一共需要多少元。\n(2)买 3 个文具盒和 1 支钢笔一共需要多少元。",
+    "options": [],
+    "answer": "15元;23元",
+    "solution": "【分析】(1)蜡笔用单价乘数量;(2)先求 3 个文具盒的钱，再加 1 支钢笔的钱.\n【详解】(1)3×5 = 15(元)。答：买 5 盒蜡笔一共需要 15 元.\n(2)6×3 + 5 = 18 + 5 = 23(元)。答：买 3 个文具盒和 1 支钢笔一共需要 23 元。",
+    "knowledge_points": [
+      "图文问题",
+      "\"提问题\"\"填条件\"问题",
+      "5 的乘法口诀及应用",
+      "表内乘加，乘减"
+    ],
+    "source": "24-25 二年级上·山东菏泽·期中"
+  },
+  {
+    "id": "290",
+    "unit": "第四单元 表内乘法",
+    "question_type": "解答题",
+    "difficulty": 0.65,
+    "question": "超市的一些物品标价如下.\n\n<table><tr><td>物 品</td><td>饼干</td><td>饮料</td><td>面包</td><td>牛奶</td></tr><tr><td>标 价</td><td>每包 5元</td><td>每瓶 2元</td><td>每个 3元</td><td>每盒 4元</td></tr></table>\n\n(1)丽丽的钱正好能买 3 包饼干，丽丽有多少钱。\n(2)爷爷买了 4 盒牛奶，要付多少钱。",
+    "options": [],
+    "answer": "15元;16元",
+    "solution": "【分析】(1)单价乘数量;(2)同样用乘法计算.\n【详解】(1)3×5 = 15(元),答：丽丽有 15 元.\n(2)4×4 = 16(元),答：爷爷买 4 盒牛奶要付 16 元。",
+    "knowledge_points": [
+      "5 的乘法口诀及应用",
+      "4 的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·河南周口·期中"
+  },
+  {
+    "id": "291",
+    "unit": "第四单元 表内乘法",
+    "question_type": "解答题",
+    "difficulty": 0.65,
+    "question": "小小商店.\n\n![](images/2026-02-25%20164638.jpg)\n\n(1)买 3 个玩具娃娃需要多少元。\n(2)一双运动鞋的价钱比榕树盆景贵 22 元，一双运动鞋多少元。",
+    "options": [],
+    "answer": "15元;51元",
+    "solution": "【分析】(1)用玩具娃娃的单价乘数量;(2)榕树盆景的价钱加上多出的 22 元即为运动鞋的价钱.\n【详解】(1)5×3 = 15(元)。答：买 3 个玩具娃娃需要 15 元.\n(2)榕树盆景 29 元，一双运动鞋 29 + 22 = 51(元)。答：一双运动鞋 51 元。",
+    "knowledge_points": [
+      "图文问题",
+      "\"提问题\" \"填条件\"问题",
+      "两位数与两位数的进位加法",
+      "5的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·广西玉林·期中"
+  },
+  {
+    "id": "292",
+    "unit": "第四单元 表内乘法",
+    "question_type": "解答题",
+    "difficulty": 0.85,
+    "question": "2 只猴子每天合起来吃 4 个桃子,5 天正好吃完一筐。这筐桃一共有多少个。",
+    "options": [],
+    "answer": "20个",
+    "solution": "【分析】每天 4 个,5 天正好吃完，就是求 5 个 4 的和，用乘法计算.\n【详解】4×5 = 20(个),答：这筐桃一共有 20 个。",
+    "knowledge_points": [
+      "5的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·河南周口·期中"
+  },
+  {
+    "id": "293",
+    "unit": "第四单元 表内乘法",
+    "question_type": "解答题",
+    "difficulty": 0.65,
+    "question": "踢毽子比赛.\n\n<table><tr><td>姓名</td><td>小明</td><td>小丽</td><td>小红</td><td>小亮</td><td>小东</td></tr><tr><td>踢毽子的个数</td><td></td><td>28</td><td></td><td>32</td><td>37</td></tr></table>\n\n![](images/2026-02-25%20164958.jpg)\n\n(1)小明踢了多少个。\n(2)小红比小亮多踢了 9 个，小红踢了多少个。",
+    "options": [],
+    "answer": "25个;41个",
+    "solution": "【分析】(1)从图可知小明每次踢 5 个，踢了 5 次，用乘法计算;(2)小亮踢了 32 个，小红比小亮多 9 个，用加法求出小红的个数.\n【详解】(1)5×5 = 25(个),答：小明踢了 25 个.\n(2)32 + 9 = 41(个),答：小红踢了 41 个。",
+    "knowledge_points": [
+      "\"提问题\" \"填条件\"问题",
+      "一位数与两位数的进位加法",
+      "两位数与两位数的退位减法",
+      "5的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·湖北孝感·期中"
+  },
+  {
+    "id": "294",
+    "unit": "第四单元 表内乘法",
+    "question_type": "解答题",
+    "difficulty": 0.65,
+    "question": "看图解答.\n\n![](images/2026-02-25%20165254.jpg)\n\n(1)张爷爷的两辆运货车一共有多少个轮子。\n(2)3 辆四轮车有多少个轮子。",
+    "options": [],
+    "answer": "7个;12个",
+    "solution": "【分析】(1)从图看出一辆是 3 个轮子，另一辆 4 个轮子，用加法计算;(2)3 辆四轮车是 3 个 4 的和，用乘法计算.\n【详解】(1)3 + 4 = 7(个),答：张爷爷的两辆运货车一共有 7 个轮子.\n(2)3×4 = 12(个),答:3 辆四轮车有 12 个轮子。",
+    "knowledge_points": [
+      "7的加减法",
+      "4的乘法口诀及应用"
+    ],
+    "source": "23-24 二年级上·福建福州·期末"
+  },
+  {
+    "id": "295",
+    "unit": "第四单元 表内乘法",
+    "question_type": "解答题",
+    "difficulty": 0.85,
+    "question": "丽丽买了 4 块橡皮，每块 5 角，丽丽一共花了多少钱。",
+    "options": [],
+    "answer": "2元",
+    "solution": "【分析】先用角为单位计算 4 块橡皮一共多少钱，再把角换算成元.\n【详解】5×4 = 20(角),20 角 = 2 元。答：丽丽一共花了 2 元钱。",
+    "knowledge_points": [
+      "5 的乘法口诀及应用",
+      "元，角，分的认识及换算",
+      "十元以下人民币的认识与计算"
+    ],
+    "source": "24-25 二年级上·河北沧州·期中"
+  },
+  {
+    "id": "296",
+    "unit": "第四单元 表内乘法",
+    "question_type": "解答题",
+    "difficulty": 0.85,
+    "question": "超市里的巧克力有一盒装 4 块的，也有一盒装 6 块的。爸爸买了 4 盒 6 块装的，一共买了多少块巧克力。",
+    "options": [],
+    "answer": "24 块",
+    "solution": "【分析】只买了 4 盒 6 块装的，用盒数乘每盒巧克力块数即可.\n【详解】6×4 = 24(块),答：一共买了 24 块巧克力。",
+    "knowledge_points": [
+      "6 的乘法口诀及应用"
+    ],
+    "source": "23-24 二年级上·重庆秀山·期末"
+  },
+  {
+    "id": "297",
+    "unit": "第四单元 表内乘法",
+    "question_type": "解答题",
+    "difficulty": 0.85,
+    "question": "手工小组的 5 名同学，每人做了 6 个灯笼，一共做了多少个灯笼。",
+    "options": [],
+    "answer": "30个",
+    "solution": "【分析】总数等于人数乘每人做的数量，是求 5 个 6 的和.\n【详解】6×5 = 30(个),答：一共做了 30 个灯笼。",
+    "knowledge_points": [
+      "6的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·河南周口·期中"
+  },
+  {
+    "id": "298",
+    "unit": "第四单元 表内乘法",
+    "question_type": "解答题",
+    "difficulty": 0.65,
+    "question": "同学们在马路两边种树.\n(1)如果一边种5棵，另一边种6棵，两边一共种了多少棵树。\n(2)如果每边都种 6 棵树，两边一共种了多少棵树。",
+    "options": [],
+    "answer": "11棵;12棵",
+    "solution": "【分析】(1)一边 5 棵，另一边 6 棵，用加法计算;(2)两边各 6 棵，用乘法计算.\n【详解】(1)5 + 6 = 11(棵),答：两边一共种了 11 棵树.\n(2)6×2 = 12(棵),答：两边一共种了 12 棵树。",
+    "knowledge_points": [
+      "5~2 加几的进位加法",
+      "6 的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·新疆乌鲁木齐·期中"
+  },
+  {
+    "id": "299",
+    "unit": "第四单元 表内乘法",
+    "question_type": "解答题",
+    "difficulty": 0.65,
+    "question": "一支钢笔5元，张老师带了 45 元钱，买了 6 支钢笔，还剩多少元。",
+    "options": [],
+    "answer": "15元",
+    "solution": "【分析】先用钢笔单价和数量求出买钢笔花了多少钱，再用带的钱减去花的钱.\n【详解】5×6 = 30(元),45 - 30 = 15(元)。答：还剩 15 元。",
+    "knowledge_points": [
+      "两位数与两位数的不退位减法",
+      "6的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·河南周口·期中"
+  },
+  {
+    "id": "300",
+    "unit": "第四单元 表内乘法",
+    "question_type": "解答题",
+    "difficulty": 0.85,
+    "question": "练习本每本 3 元，花花买了 5 本这样的练习本，应付多少元。",
+    "options": [],
+    "answer": "15元",
+    "solution": "【分析】练习本单价是 3 元，买 5 本，用乘法计算总价.\n【详解】3×5 = 15(元),答：应付 15 元。",
+    "knowledge_points": [
+      "初步认识乘法意义",
+      "5 的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·河南周口·期中"
+  },
+  {
+    "id": "301",
+    "unit": "第四单元 表内乘法",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "不能改写成 4×5 的算式是( )。",
+    "options": [
+      "A. 4 + 4 + 4 + 4 + 5",
+      "B. 5 + 5 + 5 + 5",
+      "C. 4 + 4 + 4 + 4 + 4"
+    ],
+    "answer": "A",
+    "solution": "【分析】4×5 表示 4 个 5 的和或 5 个 4 的和.\n【详解】A:4 + 4 + 4 + 4 + 5 表示 4 个 4 的和再加 5，不能写成 4×5;B:5 + 5 + 5 + 5 表示 4 个 5 的和，可以写成 4×5;C:4 + 4 + 4 + 4 + 4 表示 5 个 4 的和，也可以写成 4×5。不能改写成 4×5 的是 A.",
+    "knowledge_points": [
+      "同数连加的应用",
+      "初步认识乘法意义"
+    ],
+    "source": "24-25 二年级上·广西贵港·期中"
+  },
+  {
+    "id": "302",
+    "unit": "第四单元 表内乘法",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "\"2 + 2 + 2 + 2 + 2 + 2 - 1\"可以写成( )。",
+    "options": [
+      "A. 2×6 - 1",
+      "B. 2×6 + 1",
+      "C. 2×7 + 1"
+    ],
+    "answer": "A",
+    "solution": "【分析】2 + 2 + 2 + 2 + 2 + 2 是 6 个 2 的和.\n【详解】2 + 2 + 2 + 2 + 2 + 2 - 1 = 2×6 - 1，故选 A.",
+    "knowledge_points": [
+      "初步认识乘法意义",
+      "6 的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·河南南阳·期中"
+  },
+  {
+    "id": "303",
+    "unit": "第四单元 表内乘法",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "能表示\"3 + 3 + 3 + 3\"算式是( )。",
+    "options": [
+      "A. 4 + 3",
+      "B. 4×3",
+      "C. 4 - 3"
+    ],
+    "answer": "B",
+    "solution": "【分析】3 + 3 + 3 + 3 是 4 个 3 的和.\n【详解】A:4 + 3 是两数的和;B:4×3 可以表示 3 + 3 + 3 + 3，符合;C:4 - 3 是差。故选 B.",
+    "knowledge_points": [
+      "同数连加的应用",
+      "初步认识乘法意义",
+      "4 的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·河南南阳·期中"
+  },
+  {
+    "id": "304",
+    "unit": "第四单元 表内乘法",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "两个乘数都是4，算式是( )。",
+    "options": [
+      "A. 2 + 4",
+      "B. 2×4",
+      "C. 4×4"
+    ],
+    "answer": "C",
+    "solution": "【分析】乘法算式\"乘数×乘数 = 积\".\n【详解】只有 4×4 的两个乘数都是 4，故选 C.",
+    "knowledge_points": [
+      "初步认识乘法意义"
+    ],
+    "source": "24-25 二年级上·河南漯河·期中"
+  },
+  {
+    "id": "305",
+    "unit": "第四单元 表内乘法",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面的乘法口诀中，只能写出一道乘法算式的是( )。",
+    "options": [
+      "A. 一五得五",
+      "B. 二三得六",
+      "C. 四四十六"
+    ],
+    "answer": "C",
+    "solution": "【分析】两个乘数是口诀中的前两个数，可以交换位置.\n【详解】\"一五得五\"对应 1×5 和 5×1;\"二三得六\"对应 2×3 和 3×2;\"四四十六\"只有 4×4 一种。故选 C.",
+    "knowledge_points": [
+      "5 的乘法口诀及应用",
+      "3 的乘法口诀及应用",
+      "4 的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·河南漯河·期中"
+  },
+  {
+    "id": "306",
+    "unit": "第四单元 表内乘法",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "下面算式中，结果小于50的是( )。",
+    "options": [
+      "A. 43 + 8",
+      "B. 6×6",
+      "C. 89 - 23"
+    ],
+    "answer": "B",
+    "solution": "【分析】分别计算三个算式的结果再比较.\n【详解】43 + 8 = 51;6×6 = 36;89 - 23 = 66。只有 36 < 50，故选 B.",
+    "knowledge_points": [
+      "100 以内数的比大小",
+      "两位数与两位数的不退位减法",
+      "一位数与两位数的进位加法",
+      "6 的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·重庆·期中"
+  },
+  {
+    "id": "307",
+    "unit": "第四单元 表内乘法",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "张老师买了一些小红旗，付了5 张5 元，找回的钱不到5 元。这些小红旗的价格可能是( )。",
+    "options": [
+      "A. 20 元",
+      "B. 27 元",
+      "C. 22 元"
+    ],
+    "answer": "C",
+    "solution": "【分析】付了 5×5 = 25 元，价格要小于 25 且找零 < 5.\n【详解】A:20 元,25 - 20 = 5(元),找回 5 元，不符合\"不到 5 元\";B:27 元 > 25 元，不可能;C:22 元,25 - 22 = 3(元),小于 5 元。故选 C.",
+    "knowledge_points": [
+      "100 以内数的比大小",
+      "两位数与整十数的减法",
+      "两位数与两位数的不退位减法",
+      "5 的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·山东临沂·期中"
+  },
+  {
+    "id": "308",
+    "unit": "第四单元 表内乘法",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "一共有多少个 △。可以写成算式是( ).\n\n△ △ △ △ △ △ △ △ △ △ △ △ △ △ △ △ △ △ △",
+    "options": [
+      "A. 4×4",
+      "B. 4×5",
+      "C. 4×4 + 3"
+    ],
+    "answer": "C",
+    "solution": "【分析】从排版可看作每组 4 个，一共 4 组多 3 个.\n【详解】一共有 4×4 + 3 个，也可以看作 4×5 - 1。选项中正确的是 4×4 + 3，故选 C.",
+    "knowledge_points": [
+      "5 的乘法口诀及应用",
+      "4 的乘法口诀及应用",
+      "表内乘加，乘减"
+    ],
+    "source": "24-25 二年级上·广东汕头·期中"
+  },
+  {
+    "id": "309",
+    "unit": "第四单元 表内乘法",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "能用 3×4 表示的图形是( )。",
+    "options": [
+      "A. ![](images/afe94aee8d8412c16789ee4b2a6b7ddb2d52026b59d4f7e08b55baf67e3d6ab8.jpg)",
+      "B. ![](images/bae08cbf1fa668ce40c76c22593dd3bf30131fbfcce415d1a51f815f602b43ad.jpg)",
+      "C. ![](images/屏幕截图%202026-02-25%20173456.png)"
+    ],
+    "answer": "B",
+    "solution": "【分析】3×4 表示 3 个 4 的和或 4 个 3 的和.\n【详解】A:每行 3 个，有 3 行，是 3 个 3 的和;B:每串 4 个，有 3 串，是 3 个 4 的和，符合 3×4;C:每组 4 个，有 2 组，是 2 个 4 的和。故选 B.",
+    "knowledge_points": [
+      "图文问题",
+      "初步认识乘法意义"
+    ],
+    "source": "24-25 二年级上·广西南宁·期中"
+  },
+  {
+    "id": "310",
+    "unit": "第四单元 表内乘法",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "得数是 20 的算式是( )。",
+    "options": [
+      "A. 2×4 + 3",
+      "B. 5×3 + 5",
+      "C. 4×5 - 6"
+    ],
+    "answer": "B",
+    "solution": "【分析】依次计算三式的值.\n【详解】2×4 + 3 = 8 + 3 = 11;5×3 + 5 = 15 + 5 = 20;4×5 - 6 = 20 - 6 = 14。得数为 20 的是 B.",
+    "knowledge_points": [
+      "5 的乘法口诀及应用",
+      "表内乘加，乘减"
+    ],
+    "source": "24-25 二年级上·西藏拉萨·期中"
+  },
+  {
+    "id": "311",
+    "unit": "第四单元 表内乘法",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "小明吃了7 个，还剩多少个。下面算式正确的是( ).\n\n![](images/96a5df066af31fa09254a64c62f22b5d64039049b0adf0d914fdfc8dc515ddd0.jpg)",
+    "options": [
+      "A. 4 + 3 - 7",
+      "B. 4×3 + 7",
+      "C. 4×3 - 7"
+    ],
+    "answer": "C",
+    "solution": "【分析】每盘 4 个，共 3 盘，一共有 4×3 个，吃掉 7 个后剩下的数量是总数减去 7.\n【详解】4×3 - 7 = 12 - 7 = 5，用该式表示\"吃了 7 个，还剩多少个\"，故选 C.",
+    "knowledge_points": [
+      "图文问题",
+      "表内乘加，乘减"
+    ],
+    "source": "24-25 二年级上·山东临沂·期中"
+  },
+  {
+    "id": "312",
+    "unit": "第四单元 表内乘法",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "春节前，莉莉和她的 3 个好朋友一起动手编中国结。每人编织了 6 个中国结，她们一共编织了( )个中国结。",
+    "options": [
+      "A. 9",
+      "B. 18",
+      "C. 24"
+    ],
+    "answer": "C",
+    "solution": "【分析】莉莉和 3 个好朋友，一共 4 人，每人 6 个.\n【详解】6×4 = 24(个),她们一共编织了 24 个中国结，故选 C.",
+    "knowledge_points": [
+      "6 的乘法口诀及应用"
+    ],
+    "source": "23-24 二年级上·湖南湘西·期末"
+  },
+  {
+    "id": "313",
+    "unit": "第四单元 表内乘法",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "每个队伍 4 名运动员，排名前三的参赛队伍上颁奖台领奖，颁奖台上共( )名运动员。",
+    "options": [
+      "A. 12",
+      "B. 7",
+      "C. 1"
+    ],
+    "answer": "A",
+    "solution": "【分析】有 3 个队，每队 4 人，是 3 个 4 的和.\n【详解】4×3 = 12(名),故选 A.",
+    "knowledge_points": [
+      "4 的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·河北沧州·期中"
+  },
+  {
+    "id": "314",
+    "unit": "第四单元 表内乘法",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下列算式中，得数最小的是( )。",
+    "options": [
+      "A. 15 - 3",
+      "B. 5×2",
+      "C. 4×3"
+    ],
+    "answer": "B",
+    "solution": "【分析】分别求出三个算式的得数进行比较.\n【详解】15 - 3 = 12;5×2 = 10;4×3 = 12。最小的是 10，故选 B.",
+    "knowledge_points": [
+      "100 以内数的比大小",
+      "不退位减法(20 以内)",
+      "5 的乘法口诀及应用",
+      "4 的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·河北沧州·期中"
+  },
+  {
+    "id": "315",
+    "unit": "第四单元 表内乘法",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "有 2 盆花，每盆开了 5 朵，共开了( )朵。",
+    "options": [
+      "A. 7",
+      "B. 10",
+      "C. 2"
+    ],
+    "answer": "B",
+    "solution": "【分析】总朵数为盆数乘每盆朵数.\n【详解】2×5 = 10(朵),故选 B.",
+    "knowledge_points": [
+      "5 的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·河北沧州·期中"
+  },
+  {
+    "id": "316",
+    "unit": "第四单元 表内乘法",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "积是10 的算式是()。",
+    "options": [
+      "A. 5×5",
+      "B. 5 + 5",
+      "C. 5×2"
+    ],
+    "answer": "C",
+    "solution": "【分析】看哪个算式是乘法且积为 10.\n【详解】5×5 = 25;5 + 5 = 10(和不是积);5×2 = 10。故选 C.",
+    "knowledge_points": [
+      "10 的加减法",
+      "5 的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·河南商丘·期中"
+  },
+  {
+    "id": "317",
+    "unit": "第四单元 表内乘法",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面算式中,( )不能改写成 6×3。",
+    "options": [
+      "A. 6 + 6 + 6",
+      "B. 6×2 + 6",
+      "C. 6 + 3"
+    ],
+    "answer": "C",
+    "solution": "【分析】6×3 表示 3 个 6 或 6 个 3 的和.\n【详解】A:6 + 6 + 6 是 3 个 6 的和，可写成 6×3;B:6×2 + 6 是 2 个 6 再加 1 个 6，一共 3 个 6，可写成 6×3;C:6 + 3 是 6 和 3 的和，不能写成 6×3。故选 C.",
+    "knowledge_points": [
+      "8,9 的加减法",
+      "初步认识乘法意义",
+      "表内乘加，乘减"
+    ],
+    "source": "24-25 二年级上·河南商丘·期中"
+  },
+  {
+    "id": "318",
+    "unit": "第四单元 表内乘法",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "两位同学比赛算口算题，明明3 分钟算了18 题，奇奇4 分钟算了20 题,( )算得快。",
+    "options": [
+      "A. 明明",
+      "B. 奇奇",
+      "C. 无法确定"
+    ],
+    "answer": "A",
+    "solution": "【分析】比较单位时间内做题数量.\n【详解】明明:18÷3 = 6(题/分钟);奇奇:20÷4 = 5(题/分钟)。明明每分钟多做 1 题，所以明明算得快，选 A.",
+    "knowledge_points": [
+      "5 的乘法口诀及应用",
+      "6 的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·河南周口·期中"
+  },
+  {
+    "id": "319",
+    "unit": "第四单元 表内乘法",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "5×5 + 5 还可以用下面的算式( )来表示。",
+    "options": [
+      "A. 5×5",
+      "B. 5×6",
+      "C. 3×5"
+    ],
+    "answer": "B",
+    "solution": "【分析】5×5 是 5 个 5 的和，再加 1 个 5，一共是 6 个 5 的和.\n【详解】5×5 + 5 = 5 个 5 的和再加 1 个 5，等于 6 个 5 的和，即 5×6 或 6×5。选项中只有 5×6，故选 B.",
+    "knowledge_points": [
+      "初步认识乘法意义",
+      "表内乘加，乘减"
+    ],
+    "source": "24-25 二年级上·河南周口·期中"
+  },
+  {
+    "id": "320",
+    "unit": "第四单元 表内乘法",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下列各算式中，能改写成两数相乘的是( )。",
+    "options": [
+      "A. 6 + 6 + 6 + 6 + 6",
+      "B. 6 + 6 + 6 + 5",
+      "C. 6×5 + 7"
+    ],
+    "answer": "A",
+    "solution": "【分析】只有\"几个相同加数连加\"能直接改写成乘法.\n【详解】A:6 + 6 + 6 + 6 + 6 是 5 个 6 的和，可写成 6×5;B,C 中加数不全相同，不能直接写成单个乘法算式。故选 A.",
+    "knowledge_points": [
+      "初步认识乘法意义"
+    ],
+    "source": "24-25 二年级上·河南周口·期中"
+  },
+  {
+    "id": "321",
+    "unit": "第四单元 表内乘法",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "小琳买了1 卷彩带折星星，折1 颗星星需要2 分米彩带，折了5 颗星星后，还剩 1 分米。这卷彩带原来长( )分米。",
+    "options": [
+      "A. 8",
+      "B. 9",
+      "C. 11"
+    ],
+    "answer": "C",
+    "solution": "【分析】折 5 颗星星用去 5×2 分米，再加剩下的 1 分米，就是原来长度.\n【详解】5×2 + 1 = 10 + 1 = 11(分米),故选 C.",
+    "knowledge_points": [
+      "5 的乘法口诀及应用",
+      "表内乘加，乘减"
+    ],
+    "source": "24-25 二年级上·河南周口·期中"
+  },
+  {
+    "id": "322",
+    "unit": "第四单元 表内乘法",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "二(3)班有4 个小组，每个小组有5 人，全班乘车去秋游，乘( )座的车最合适。",
+    "options": [
+      "A. 15",
+      "B. 20",
+      "C. 25"
+    ],
+    "answer": "B",
+    "solution": "【分析】先求总人数，再选与人数相等的座位数.\n【详解】5×4 = 20(人),乘 20 座的车最合适，故选 B.",
+    "knowledge_points": [
+      "5 的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·山东济南·期中"
+  },
+  {
+    "id": "323",
+    "unit": "第四单元 表内乘法",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "积是15 的算式是( )。",
+    "options": [
+      "A. 5×3",
+      "B. 10 + 5",
+      "C. 35 - 20"
+    ],
+    "answer": "A",
+    "solution": "【分析】积是乘法的结果.\n【详解】5×3 = 15 为积;10 + 5 = 15 是和;35 - 20 = 15 是差。故选 A.",
+    "knowledge_points": [
+      "不进位加法(20 以内)",
+      "两位数与整十数的减法",
+      "5 的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·河南三门峡·期中"
+  },
+  {
+    "id": "324",
+    "unit": "第四单元 表内乘法",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "2 个4 相乘列式为( ),2 和4 相加列式为( ),2 个4 相加列式为( ).\n① 2 + 4 ② 2×4 ③ 4×4",
+    "options": [
+      "A. ②①③",
+      "B. ②③①",
+      "C. ③①②"
+    ],
+    "answer": "C",
+    "solution": "【分析】分别对应\"2 个 4 相乘\"\"2 和 4 相加\"\"2 个 4 相加\".\n【详解】2 个 4 相乘是 4×4(③);2 和 4 相加是 2 + 4(①);2 个 4 相加是 2×4(②)。顺序是 ③①②,故选 C.",
+    "knowledge_points": [
+      "6 的加减法",
+      "同数连加的应用",
+      "初步认识乘法意义"
+    ],
+    "source": "24-25 二年级上·河南三门峡·期中"
+  },
+  {
+    "id": "325",
+    "unit": "第四单元 表内乘法",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "8 + 8 + 8 + 8 =( )×( );6 + 6 + 6 + 3 = ( )×( )。",
+    "options": [],
+    "answer": "8;4;7;3",
+    "solution": "【分析】同数连加改写为乘法.\n【详解】8 + 8 + 8 + 8 是 4 个 8 的和，可写为 8×4 或 4×8;6 + 6 + 6 + 3 中,3 可以拆成 1 + 1 + 1，合并后为 7 + 7 + 7，为 3 个 7 的和，可写为 7×3 或 3×7。示例填法为:8×4,7×3。",
+    "knowledge_points": [
+      "同数连加的应用",
+      "初步认识乘法意义"
+    ],
+    "source": "23-24 二年级上·福建三明·期末"
+  },
+  {
+    "id": "326",
+    "unit": "第四单元 表内乘法",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "一根绳子先用去一半，又用去剩下的一半，还剩下 3 米，原来绳子长( )米。",
+    "options": [],
+    "answer": "12",
+    "solution": "【分析】用去一半再用去一半后，剩下的是原长的 1÷4。已知剩下 3 米，则 3 米是原来的 1÷4.\n【详解】3×2 = 6(米)是一半，再 6×2 = 12(米)是全长。答：原来绳子长 12 米。",
+    "knowledge_points": [
+      "3 的乘法口诀及应用",
+      "6 的乘法口诀及应用"
+    ],
+    "source": "23-24 二年级上·河南安阳·期末"
+  },
+  {
+    "id": "327",
+    "unit": "第四单元 表内乘法",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "括号里最大填几.\n( ) + 8 < 33;27 > ( ) - 9;( ) < 3×4",
+    "options": [],
+    "answer": "24;35;11",
+    "solution": "【分析】把不等式改写为关于括号中数的范围问题.\n【详解】(1) x + 8 < 33，所以 x < 25，最大整数是 24;(2) 27 > y - 9，所以 y - 9 < 27，即 y < 36，最大整数是 35;(3) z < 3×4 = 12,z 最大为 11。",
+    "knowledge_points": [
+      "100 以内数的比大小",
+      "一位数与两位数的进位加法",
+      "一位数与两位数的退位减法",
+      "4 的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·河南三门峡·期中"
+  },
+  {
+    "id": "328",
+    "unit": "第四单元 表内乘法",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "3 + 3 改写成乘法算式是( ),1 + 1 + 1 改写成乘法算式是( ),5 + 5 + 5 改写成乘法算式是( )。",
+    "options": [],
+    "answer": "3×2 = 6;1×3 = 3;5×3 = 15",
+    "solution": "【分析】同数连加写成\"相同加数×个数\".\n【详解】3 + 3 是 2 个 3 的和，可写成 3×2 或 2×3;1 + 1 + 1 是 3 个 1 的和，可写成 1×3 或 3×1;5 + 5 + 5 是 3 个 5 的和，可写成 5×3 或 3×5。",
+    "knowledge_points": [
+      "同数连加的应用",
+      "初步认识乘法意义"
+    ],
+    "source": "24-25 二年级上·河南三门峡·期中"
+  },
+  {
+    "id": "329",
+    "unit": "第四单元 表内乘法",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "在括号里填上\">\"\"<\"或者\"=\".\n53 + 36( )43 + 46;80 - 53( )18 + 17;4×5( )50 - 30",
+    "options": [],
+    "answer": "=;<;=",
+    "solution": "【分析】先求两边的得数，再比较大小.\n【详解】53 + 36 = 89,43 + 46 = 89，相等;80 - 53 = 27,18 + 17 = 35,27 < 35;4×5 = 20,50 - 30 = 20，相等。",
+    "knowledge_points": [
+      "100 以内数的比大小",
+      "两位数与两位数的进位加法",
+      "两位数与两位数的退位减法",
+      "5 的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·河南三门峡·期中"
+  },
+  {
+    "id": "330",
+    "unit": "第四单元 表内乘法",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "把下面的算式改写为乘法算式.\n3 + 3 + 3 =( )×( );2 + 2 + 2 + 2 + 2 + 2 =( )×( )\n6 + 6 + 6 + 6 + 6 =( )×( );4 + 4 + 4 + 4 + 4 =( )×( )",
+    "options": [],
+    "answer": "3;3;2;6;6;5;4;5",
+    "solution": "【分析】同数连加用\"相同加数×个数\".\n【详解】3 + 3 + 3 = 3×3;2 + 2 + 2 + 2 + 2 + 2 = 2×6;6 + 6 + 6 + 6 + 6 = 6×5;4 + 4 + 4 + 4 + 4 = 4×5。",
+    "knowledge_points": [
+      "同数连加的应用",
+      "初步认识乘法意义"
+    ],
+    "source": "24-25 二年级上·广西贵港·期中"
+  },
+  {
+    "id": "331",
+    "unit": "第四单元 表内乘法",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "4×5 = ( ) + ( ) + ( ) + ( ) + ( )。",
+    "options": [],
+    "answer": "4;4;4;4;4",
+    "solution": "【分析】4×5 表示 5 个 4 的和，也可以表示 4 个 5 的和.\n【详解】4×5 = 4 + 4 + 4 + 4 + 4，所以括号里依次填 4,4,4,4,4。",
+    "knowledge_points": [
+      "同数连加的应用",
+      "初步认识乘法意义"
+    ],
+    "source": "24-25 二年级上·河南南阳·期中"
+  },
+  {
+    "id": "332",
+    "unit": "第四单元 表内乘法",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "把加法算式写成乘法算式.\n6 + 6 + 6 = ( )×( );7 + 7 = ( )×( );4 + 4 + 4 + 4 + 4 = ( )×( );2 + 2 + 2 + 2 + 2 + 2 = ( )×( );12 + 12 + 12 + 12 = ( )×( );1 + 1 + 1 = ( )×( )",
+    "options": [],
+    "answer": "6;3;7;2;4;5;2;6;12;4;1;3",
+    "solution": "【分析】每一行都是同数连加，直接写\"相同加数×个数\".\n【详解】6 + 6 + 6 = 6×3;7 + 7 = 7×2;4 + 4 + 4 + 4 + 4 = 4×5;2 + 2 + 2 + 2 + 2 + 2 = 2×6;12 + 12 + 12 + 12 = 12×4;1 + 1 + 1 = 1×3。",
+    "knowledge_points": [
+      "同数连加的应用",
+      "初步认识乘法意义"
+    ],
+    "source": "24-25 二年级上·河南漯河·期中"
+  },
+  {
+    "id": "333",
+    "unit": "第四单元 表内乘法",
+    "question_type": "解答题",
+    "difficulty": 0.65,
+    "question": "把一根木头锯成两段需要3 分钟，照这样的速度，锯成5 段，需要多少分钟。",
+    "options": [],
+    "answer": "12",
+    "solution": "【分析】锯成 n 段需要锯 n - 1 次。一根木头锯成 2 段是锯 1 次，需要 3 分钟。锯成 5 段需要锯 4 次.\n【详解】5 - 1 = 4(次),4×3 = 12(分钟)。答：锯成 5 段需要 12 分钟。",
+    "knowledge_points": [
+      "5 以内数的减法",
+      "4 的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·河南周口·期中"
+  },
+  {
+    "id": "334",
+    "unit": "第四单元 表内乘法",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "6 + 6 + 6 + 6 + 4 = ( )×( ) - ( )。",
+    "options": [],
+    "answer": "5;6;2",
+    "solution": "【分析】6 + 6 + 6 + 6 + 4 可以看作 5 个 6 的和再减去 2.\n【详解】6 + 6 + 6 + 6 + 4 = 5×6 - 2，因此依次填 5,6,2。",
+    "knowledge_points": [
+      "表内乘加，乘减"
+    ],
+    "source": "23-24 二年级上·河南南阳·期末"
+  },
+  {
+    "id": "335",
+    "unit": "第四单元 表内乘法",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "在括号里填上\">\"\"<\"或\"=\".\n6×2( )11;5×6( )28;3×4( )6×2\n4×5( )4 + 5;99 厘米( )1 米;2 + 2( )2×2",
+    "options": [],
+    "answer": ">;>;=;>;<;=",
+    "solution": "【详解】6×2 = 12 > 11;5×6 = 30 > 28;3×4 = 12,6×2 = 12，相等;4×5 = 20 > 4 + 5 = 9;99 厘米 < 1 米 = 100 厘米;2 + 2 = 4 = 2×2。",
+    "knowledge_points": [
+      "100 以内数的比大小",
+      "5 的乘法口诀及应用",
+      "6 的乘法口诀及应用",
+      "厘米和米之间的进率与换算"
+    ],
+    "source": "24-25 二年级上·河南漯河·期中"
+  },
+  {
+    "id": "336",
+    "unit": "第四单元 表内乘法",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "在括号里填上\">\"\"<\"或\"=\".\n6×2( )11;5×6( )28;3×4( )6×2\n4×5( )4 + 5;9 厘米( )1 米;2 + 2( )2×2",
+    "options": [],
+    "answer": ">;>;=;>;<;=",
+    "solution": "【详解】6×2 = 12 > 11;5×6 = 30 > 28;3×4 = 12,6×2 = 12，相等;4×5 = 20 > 4 + 5 = 9;9 厘米 < 1 米 = 100 厘米;2 + 2 = 4 = 2×2。",
+    "knowledge_points": [
+      "100 以内数的比大小",
+      "5 的乘法口诀及应用",
+      "6 的乘法口诀及应用",
+      "厘米和米之间的进率与换算"
+    ],
+    "source": "24-25 二年级上·河南驻马店·期中"
+  },
+  {
+    "id": "337",
+    "unit": "第四单元 表内乘法",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "3 个 3 相加的和是( )。3 和 3 相加的和是( )。",
+    "options": [],
+    "answer": "9;6",
+    "solution": "【分析】3 个 3 相加是\"3 个 3 的和\",3 和 3 相加是\"两个数 3 和 3 的和\".\n【详解】3×3 = 9，所以 3 个 3 相加的和是 9;3 + 3 = 6，所以 3 和 3 相加的和是 6。",
+    "knowledge_points": [
+      "初步认识乘法意义",
+      "3 的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·河南漯河·期中"
+  },
+  {
+    "id": "338",
+    "unit": "第四单元 表内乘法",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "5 + 5 + 5 + 4 写成乘加算式( ),也可以写成乘减算式( )。",
+    "options": [],
+    "answer": "5×3 + 4 = 19;5×4 - 1 = 19",
+    "solution": "【分析】5 + 5 + 5 + 4 可以看作 3 个 5 的和再加 4，也可以看作 4 个 5 的和再减 1.\n【详解】5 + 5 + 5 + 4 = 5×3 + 4 = 15 + 4 = 19，也可以写成 5×4 - 1 = 20 - 1 = 19。",
+    "knowledge_points": [
+      "初步认识乘法意义",
+      "表内乘加，乘减"
+    ],
+    "source": "23-24 二年级上·重庆永川·期末"
+  },
+  {
+    "id": "339",
+    "unit": "第四单元 表内乘法",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "在 5 + 5 + 5 + 5 = 20 中，相同加数是( ),相同加数的个数是( ),写成乘法算式是( )或( )。",
+    "options": [],
+    "answer": "5;4;5×4 = 20;4×5 = 20",
+    "solution": "【分析】5 + 5 + 5 + 5 是 4 个 5 的和.\n【详解】相同加数是 5，有 4 个，乘法算式是 5×4 或 4×5，结果都是 20。",
+    "knowledge_points": [
+      "初步认识乘法意义"
+    ],
+    "source": "24-25 二年级上·河南周口·期中"
+  },
+  {
+    "id": "340",
+    "unit": "第四单元 表内乘法",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "在括号里填上\">\"\"<\"或\"=\".\n86 - 60( )33;4×6( )6 + 6 + 6 + 6;70 米( )1 米 - 30 厘米",
+    "options": [],
+    "answer": "<;=;>",
+    "solution": "【详解】86 - 60 = 26 < 33;4×6 = 24,6 + 6 + 6 + 6 = 24，相等;1 米 - 30 厘米 = 100 厘米 - 30 厘米 = 70 厘米，而 70 米远大于 70 厘米，所以 70 米 > 1 米 - 30 厘米。",
+    "knowledge_points": [
+      "100以内数的比大小",
+      "两位数与整十数的减法",
+      "6的乘法口诀及应用",
+      "厘米和米之间的进率与换算"
+    ],
+    "source": "24-25 二年级上·广东汕头·期中"
+  },
+  {
+    "id": "341",
+    "unit": "第四单元 表内乘法",
+    "question_type": "解答题",
+    "difficulty": 0.85,
+    "question": "乐乐和他的 5 个好朋友一起用积木拼小汽车，每人拼了3辆小汽车，一共拼了多少辆小汽车。",
+    "options": [],
+    "answer": "18",
+    "solution": "【分析】乐乐和 5 个好朋友一共 6 人，每人 3 辆，用人数乘每人拼的辆数.\n【详解】1 + 5 = 6(人),3×6 = 18(辆)。答：一共拼了 18 辆小汽车。",
+    "knowledge_points": [
+      "6的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·广西南宁·期中"
+  },
+  {
+    "id": "342",
+    "unit": "第四单元 表内乘法",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "两个乘数都是 4，积是( ),两个加数都是 3，和是( )。",
+    "options": [],
+    "answer": "16;6",
+    "solution": "【分析】乘法用\"乘数×乘数 = 积\"，加法用\"加数 + 加数 = 和\".\n【详解】4×4 = 16;3 + 3 = 6。",
+    "knowledge_points": [
+      "6的加减法",
+      "4的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·西藏拉萨·期中"
+  },
+  {
+    "id": "343",
+    "unit": "第四单元 表内乘法",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "在括号里填上\"+\"或\"*\".\n4( )3 = 12;1( )4 = 5;4( )5 = 20;3( )5 = 8\n5( )3 = 15;4( )2 = 6;2( )3 = 6;4( )4 = 16",
+    "options": [],
+    "answer": "*;+;*;+;*;+;*;*",
+    "solution": "【分析】根据等号右边结果判断应填加号还是乘号.\n【详解】4×3 = 12;1 + 4 = 5;4×5 = 20;3 + 5 = 8;5×3 = 15;4 + 2 = 6;2×3 = 6;4×4 = 16。",
+    "knowledge_points": [
+      "5以内数的减法",
+      "5的乘法口诀及应用",
+      "4的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·河北沧州·期中"
+  },
+  {
+    "id": "344",
+    "unit": "第四单元 表内乘法",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "6 + 6 + 6 + 6 = ( ),写成乘法算式是( ),读作( ),计算时用的乘法口诀是( )。",
+    "options": [],
+    "answer": "24;6×4 = 24;6乘4等于24;四六二十四",
+    "solution": "【分析】4 个 6 相加可以写成乘法算式 6×4(或 4×6).\n【详解】6 + 6 + 6 + 6 = 24;乘法算式为 6×4 = 24;读作\"6 乘 4 等于 24\";用到的口诀是\"四六二十四\"。",
+    "knowledge_points": [
+      "初步认识乘法意义",
+      "6 的乘法口诀及应用"
+    ],
+    "source": "23-24 二年级上·浙江温州·期末"
+  },
+  {
+    "id": "345",
+    "unit": "第四单元 表内乘法",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "括号里最大能填几。\n( )×4 < 20;13 > 4×( );( )×6 < 21",
+    "options": [],
+    "answer": "4;3;3",
+    "solution": "【分析】利用 4 和 6 的乘法口诀找出不等式中最大的整数解.\n【详解】4×4 = 16 < 20,4×5 = 20 不小于 20，所以第一个括号最大填 4;4×3 = 12 < 13,4×4 = 16 > 13，第二个括号最大填 3;3×6 = 18 < 21,4×6 = 24 > 21，第三个括号最大填 3。",
+    "knowledge_points": [
+      "100 以内数的比大小",
+      "5 的乘法口诀及应用",
+      "4的乘法口诀及应用",
+      "6 的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·新疆乌鲁木齐·期中"
+  },
+  {
+    "id": "346",
+    "unit": "第四单元 表内乘法",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "5 + 5 + 5 + 5 = 20，也就是求( )个( )相加的和是多少，改写成乘法算式是( ),计算时用到的乘法口诀是( )。",
+    "options": [],
+    "answer": "4;5;5×4 = 20;四五二十",
+    "solution": "【分析】5 + 5 + 5 + 5 是 4 个 5 的和.\n【详解】是求 4 个 5 相加的和，乘法算式为 5×4 = 20(或 4×5 = 20),用到的口诀是\"四五二十\"。",
+    "knowledge_points": [
+      "同数连加的应用",
+      "初步认识乘法意义",
+      "5 的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·新疆乌鲁木齐·期中"
+  },
+  {
+    "id": "347",
+    "unit": "第四单元 表内乘法",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "2 个 8 相加是( ),2 和 8 相加是( ),8 个 5 相加写成乘法算式是( )。",
+    "options": [],
+    "answer": "16;10;5×8 = 40",
+    "solution": "【分析】前两空是加法，后一空是同数连加写成乘法.\n【详解】2 个 8 相加:8 + 8 = 16;2 和 8 相加:2 + 8 = 10;8 个 5 相加写成乘法算式为 5×8 = 40(或 8×5 = 40)。",
+    "knowledge_points": [
+      "初步认识乘法意义"
+    ],
+    "source": "23-24 二年级上·浙江绍兴·期末"
+  },
+  {
+    "id": "348",
+    "unit": "第四单元 表内乘法",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "8 + 8 + 8 + 8 + 8 + 8 + 8 = ( )×( );3 + 3 + 3 + 6 = ( )×( )。",
+    "options": [],
+    "answer": "8;7;3;5",
+    "solution": "【分析】同数连加写成乘法，注意第二个算式中把 6 分解为 3 + 3.\n【详解】8 + 8 + 8 + 8 + 8 + 8 + 8 是 7 个 8 的和，可写成 8×7(或 7×8);3 + 3 + 3 + 6 中的 6 = 3 + 3，总共是 5 个 3 的和，可写成 3×5(或 5×3)。",
+    "knowledge_points": [
+      "同数连加的应用",
+      "初步认识乘法意义"
+    ],
+    "source": "23-24 二年级上·浙江杭州·期末"
+  },
+  {
+    "id": "349",
+    "unit": "第四单元 表内乘法",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "3 个 5 是( ),加法算式是( ),乘法算式是( ),读作( ),口诀是( )。",
+    "options": [],
+    "answer": "15;5 + 5 + 5 = 15;3×5 = 15;3乘5等于15;三五十五",
+    "solution": "【分析】3 个 5 相加的和用加法和乘法两种形式表示.\n【详解】3 个 5 是 15;加法算式:5 + 5 + 5 = 15;乘法算式:3×5 = 15;读作\"3 乘 5 等于 15\";口诀是\"三五十五\"。",
+    "knowledge_points": [
+      "同数连加的应用",
+      "初步认识乘法意义",
+      "5 的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·广西玉林·期中"
+  },
+  {
+    "id": "350",
+    "unit": "第四单元 表内乘法",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "把加法算式改写成乘法算式.\n8 + 8 = 16;6 + 6 + 6 + 6 = 24;9 + 9 + 9 = 27\n( )×( ) = ( );( )×( ) = ( );( )×( ) = ( )",
+    "options": [],
+    "answer": "2;8;16;4;6;24;3;9;27",
+    "solution": "【分析】同数连加用\"相同加数×个数\".\n【详解】8 + 8 = 16:2×8 = 16;6 + 6 + 6 + 6 = 24:4×6 = 24;9 + 9 + 9 = 27:3×9 = 27。",
+    "knowledge_points": [
+      "初步认识乘法意义"
+    ],
+    "source": "24-25 二年级上·河南商丘·期中"
+  },
+  {
+    "id": "351",
+    "unit": "第四单元 表内乘法",
+    "question_type": "解答题",
+    "difficulty": 0.85,
+    "question": "有一些梨，比 20 个多，比 30 个少，平均放在一些盘子里，每个盘子里的梨个数和盘子数一样多，共有多少个梨。",
+    "options": [],
+    "answer": "25",
+    "solution": "【分析】梨的总数在 20 到 30 之间，且\"盘子数 = 每盘个数\"，即总数是某个数的平方.\n【详解】表内平方有:4×4 = 16,5×5 = 25,6×6 = 36，只有 25 在 20 和 30 之间，故共有 25 个梨。",
+    "knowledge_points": [
+      "5 的乘法口诀及应用",
+      "4 的乘法口诀及应用",
+      "6的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·河南周口·期中"
+  },
+  {
+    "id": "352",
+    "unit": "第四单元 表内乘法",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "5×( ) < 33,52 > 6×( ),括号里最大能填几。",
+    "options": [],
+    "answer": "6;8",
+    "solution": "【分析】利用 5 和 6 的乘法口诀找出最大满足条件的数.\n【详解】5×6 = 30 < 33,5×7 = 35 > 33，第一个括号里最大填 6;6×8 = 48 < 52,6×9 = 54 > 52，第二个括号里最大填 8。",
+    "knowledge_points": [
+      "5 的乘法口诀及应用",
+      "6 的乘法口诀及应用"
+    ],
+    "source": "23-24 二年级上·重庆秀山·期末"
+  },
+  {
+    "id": "353",
+    "unit": "第四单元 表内乘法",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "重百商场叫\"木林森\"的品牌鞋店，这个品牌的名字一共有( )画。",
+    "options": [],
+    "answer": "24",
+    "solution": "【分析】\"木林森\"中\"木\"有 4 画，\"林\"有 2 个\"木\"，\"森\"有 3 个\"木\"。总共 6 个\"木\".\n【详解】一个\"木\"4 画,6 个\"木\"总笔画数为 4×6 = 24(画)。",
+    "knowledge_points": [
+      "初步认识乘法意义",
+      "6 的乘法口诀及应用"
+    ],
+    "source": "23-24 二年级上·重庆秀山·期末"
+  },
+  {
+    "id": "354",
+    "unit": "第四单元 表内乘法",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "汉字\"木\"的笔画是4 画，汉字\"林\"的笔画是( )画，汉字\"森\"的笔画是( )画。",
+    "options": [],
+    "answer": "8;12",
+    "solution": "【分析】\"林\"由 2 个\"木\"构成，\"森\"由 3 个\"木\"构成.\n【详解】林:4×2 = 8(画);森:4×3 = 12(画)。",
+    "knowledge_points": [
+      "4 的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·河南商丘·期中"
+  },
+  {
+    "id": "355",
+    "unit": "第四单元 表内乘法",
+    "question_type": "解答题",
+    "difficulty": 0.65,
+    "question": "3 个苹果可以榨 1 杯果汁,15 个苹果可以榨多少杯果汁。榨 6 杯苹果汁需要多少个苹果。",
+    "options": [],
+    "answer": "5;18",
+    "solution": "【分析】3 个苹果 1 杯,15 个苹果几杯，是 15÷3;6 杯需要几个苹果，是 6×3.\n【详解】15÷3 = 5(杯);3×6 = 18(个)。答:15 个苹果可以榨 5 杯果汁;榨 6 杯苹果汁需要 18 个苹果。",
+    "knowledge_points": [
+      "同数连加的应用",
+      "6 的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·河南周口·期中"
+  },
+  {
+    "id": "356",
+    "unit": "第四单元 表内乘法",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "将下列乘法口诀补充完整.\n四( )二十;三( )十八;五( )二十五\n二( )十二;( )七四十二;( )六三十六",
+    "options": [],
+    "answer": "五;六;五;六;六;六",
+    "solution": "【分析】根据熟记的乘法口诀表补全空格.\n【详解】四五二十;三六十八;五五二十五;二六十二;六七四十二;六六三十六。",
+    "knowledge_points": [
+      "5 的乘法口诀及应用",
+      "6 的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·河南周口·期中"
+  },
+  {
+    "id": "357",
+    "unit": "第四单元 表内乘法",
+    "question_type": "解答题",
+    "difficulty": 0.85,
+    "question": "一串冰糖葫芦串 5 个山楂,4 串冰糖葫芦需多少个山楂。列乘法算式为( ),计算时用到的口诀为( )。",
+    "options": [],
+    "answer": "20;5×4 = 20;四五二十",
+    "solution": "【分析】4 串，每串 5 个，是 4 个 5 的和.\n【详解】5×4 = 20(个),用到的乘法口诀是\"四五二十\"。答：需要 20 个山楂。",
+    "knowledge_points": [
+      "初步认识乘法意义",
+      "5 的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·河南周口·期中"
+  },
+  {
+    "id": "358",
+    "unit": "第四单元 表内乘法",
+    "question_type": "解答题",
+    "difficulty": 0.85,
+    "question": "春天百花开，朵朵放异彩，五朵五朵地数，可以数五次。花儿共有多少朵。",
+    "options": [],
+    "answer": "25",
+    "solution": "【分析】五朵五朵地数，可以数 5 次，是 5 个 5 的和.\n【详解】5×5 = 25(朵),答：花儿共有 25 朵。",
+    "knowledge_points": [
+      "5 的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·山东济南·期中"
+  },
+  {
+    "id": "359",
+    "unit": "第四单元 表内乘法",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "求2 个5 相加的和列加法算式是( ),也可以列乘法算式( )或( )。",
+    "options": [],
+    "answer": "5 + 5 = 10;5×2 = 10;2×5 = 10",
+    "solution": "【分析】2 个 5 相加是同数连加.\n【详解】加法算式是 5 + 5 = 10;乘法算式是 5×2 = 10 或 2×5 = 10。",
+    "knowledge_points": [
+      "同数连加的应用",
+      "初步认识乘法意义"
+    ],
+    "source": "24-25 二年级上·河南三门峡·期中"
+  },
+  {
+    "id": "360",
+    "unit": "第四单元 表内乘法",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "6 + 6 + 6 + 6 = 6×5 - 6。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】6 + 6 + 6 + 6 是 4 个 6 的和;6×5 - 6 是 5 个 6 的和减 1 个 6.\n【详解】6×5 - 6 = 30 - 6 = 24;6 + 6 + 6 + 6 = 24，所以等式成立。故答案为:√。",
+    "knowledge_points": [
+      "同数连加的应用",
+      "初步认识乘法意义",
+      "表内乘加，乘减"
+    ],
+    "source": "23-24 二年级上·河南安阳·期末"
+  },
+  {
+    "id": "361",
+    "unit": "第四单元 表内乘法",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "在乘法算式里，积一定比乘数小。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】可以举几个反例，如 1×2,2×2 等.\n【详解】1×1 = 1，积等于乘数;2×2 = 4，积大于乘数;1×2 = 2，积等于其中一个乘数。积与乘数比较不一定总是小。故原说法错误，答案为:*。",
+    "knowledge_points": [
+      "2 的乘法口诀及应用",
+      "3 的乘法口诀及应用"
+    ],
+    "source": "23-24 二年级上·河南安阳·期末"
+  },
+  {
+    "id": "362",
+    "unit": "第四单元 表内乘法",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "因为 3×4 和 2×6 的积都是 12，所以运用的乘法口诀也是一样的。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】3×4 和 2×6 的乘法口诀不同.\n【详解】3×4 用\"三四十二\",2×6 用\"二六十二\"。虽然积相同，但用的口诀不同。故答案为: ×。",
+    "knowledge_points": [
+      "4 的乘法口诀及应用",
+      "6 的乘法口诀及应用"
+    ],
+    "source": "23-24 二年级上·河南南阳·期末"
+  },
+  {
+    "id": "363",
+    "unit": "第四单元 表内乘法",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "几个相同加数相加时，可以用乘法表示比较简便。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】这是乘法意义的核心之一.\n【详解】如 3 + 3 + 3 + 3 + 3，用乘法表示为 3×5，更简便，所以说法正确。答案为:√。",
+    "knowledge_points": [
+      "同数连加的应用",
+      "初步认识乘法意义"
+    ],
+    "source": "24-25 二年级上·河南南阳·期中"
+  },
+  {
+    "id": "364",
+    "unit": "第四单元 表内乘法",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "\" 2×5 + 2 \"可以看作 \"2×6\"。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】2×5 是 5 个 2 的和，再加 2 就是 6 个 2 的和.\n【详解】2×5 + 2 = (2 + 2 + 2 + 2 + 2) + 2 = 6 个 2 的和 = 2×6，所以可以看作 2×6。答案为:√。",
+    "knowledge_points": [
+      "初步认识乘法意义",
+      "6 的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·河南南阳·期中"
+  },
+  {
+    "id": "365",
+    "unit": "第四单元 表内乘法",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "\" 3×6 = 18 \"和\"6×3 =18\"用到的乘法口诀都是\"三六十八\"。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】两个算式的乘数只是交换了位置.\n【详解】3×6 和 6×3 都用\"三六十八\"这句口诀，故答案为:√。",
+    "knowledge_points": [
+      "6 的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·河南南阳·期中"
+  },
+  {
+    "id": "366",
+    "unit": "第四单元 表内乘法",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "2×6 和 4×3 的结果相同，所用的乘法口诀也相同。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】两个算式虽然积相同，但乘数不同，对应的口诀也不同.\n【详解】2×6 = 12，用\"二六十二\";4×3 = 12，用\"三四十二\"。积相同但用的口诀不同。故答案为: ×。",
+    "knowledge_points": [
+      "4 的乘法口诀及应用",
+      "6 的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·河南漯河·期中"
+  },
+  {
+    "id": "367",
+    "unit": "第四单元 表内乘法",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "6×9 表示6 个9 相乘的积是多少。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】表内乘法在本册仅表示\"几个相同加数的和\"，不是\"几个相同数相乘很多次\"的幂的概念.\n【详解】6×9 表示 6 个 9 相加的和是多少，而不是 6 个 9 连乘的积。原说法错误，答案为:*。",
+    "knowledge_points": [
+      "初步认识乘法意义"
+    ],
+    "source": "23-24 二年级上·云南红河·期末"
+  },
+  {
+    "id": "368",
+    "unit": "第四单元 表内乘法",
+    "question_type": "判断题",
+    "difficulty": 0.65,
+    "question": "4×5 + 5 可以看做5×5。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】4×5 是 4 个 5 的和，再加 1 个 5，一共是 5 个 5 的和.\n【详解】4×5 + 5 = 20 + 5 = 25，就是 5 个 5 的和，可表示为 5×5。说法正确，答案为:√。",
+    "knowledge_points": [
+      "初步认识乘法意义",
+      "5 的乘法口诀及应用",
+      "表内乘加，乘减"
+    ],
+    "source": "24-25 二年级上·山东临沂·期中"
+  },
+  {
+    "id": "369",
+    "unit": "第四单元 表内乘法",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "3×4 = 12 和 2×6 = 12，积相同，但所用的口诀不同。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】3×4 用 4 的乘法口诀,2×6 用 6 的乘法口诀.\n【详解】3×4 = 12，用\"三四十二\";2×6 = 12，用\"二六十二\"。积相同，口诀不同，故答案为:√。",
+    "knowledge_points": [
+      "4 的乘法口诀及应用",
+      "6 的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·广东汕头·期中"
+  },
+  {
+    "id": "370",
+    "unit": "第四单元 表内乘法",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "5 个 4 相加是多少。列式为 5 + 4。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】5 个 4 相加，列加法算式时，相同加数是 4，加数的个数是 5 个;列乘法算式时，相同加数×个数或个数×相同加数，由此解答.\n【详解】由分析可知,5 个 4 相加，列式为 4 + 4 + 4 + 4 + 4 或 5×4 或 4×5。原题说法错误。故答案为: ×。",
+    "knowledge_points": [
+      "同数连加的应用",
+      "初步认识乘法意义"
+    ],
+    "source": "24-25 二年级上·西藏拉萨·期中"
+  },
+  {
+    "id": "371",
+    "unit": "第四单元 表内乘法",
+    "question_type": "判断题",
+    "difficulty": 0.65,
+    "question": "两个数的积总是比这两个数的和更大。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】两个数的积用乘法计算，两个数的和用加法计算，由此可举例计算出结果进行比较解答.\n【详解】若两个数都为 1:1×1 = 1,1 + 1 = 2,1 < 2，则两个数的积小于两个数的和;若两个数都为 2:2 + 2 = 4,2×2 = 4,4 = 4，则两个数的积等于两个数的和;若两个数为 2 和 3:2×3 = 6,2 + 3 = 5,6 > 5，则两个数的积大于两个数的和。由此可知，两个数的积和两个数的和相比，无法确定谁大谁小。原题说法错误。故答案为: ×。",
+    "knowledge_points": [
+      "10 以内数的比大小",
+      "5 以内数的加法",
+      "2 的乘法口诀及应用",
+      "3 的乘法口诀及应用"
+    ],
+    "source": "23-24 二年级上·重庆云阳·期末"
+  },
+  {
+    "id": "372",
+    "unit": "第四单元 表内乘法",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "求7 个6 相加是多少的算式是 7 + 6。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】求 7 个 6 的和，列加法算式时，相同加数是 6，加数的个数是 7 个;求几个相同加数的和，可以用乘法计算，用相同加数×个数或个数×相同加数，由此解答.\n【详解】求 7 个 6 相加是多少，算式是 6 + 6 + 6 + 6 + 6 + 6 + 6 或 7×6 或 6×7。原题说法错误。故答案为: ×。",
+    "knowledge_points": [
+      "同数连加的应用",
+      "初步认识乘法意义"
+    ],
+    "source": "23-24 二年级上·重庆秀山·期末"
+  },
+  {
+    "id": "373",
+    "unit": "第四单元 表内乘法",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "4×3 与 6×2 的积相同，表示的意义也相同。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】据题意,4×3 是指 4 个 3 相加或者 3 个 4 相加,6×2 是指 6 个 2 相加或者 2 个 6 相加，据此即可得出判断.\n【详解】4×3 与 6×2 的积相同，但表示的意义不相同，所以题干错误。故答案为: ×。",
+    "knowledge_points": [
+      "初步认识乘法意义",
+      "4 的乘法口诀及应用",
+      "6 的乘法口诀及应用"
+    ],
+    "source": "23-24 二年级上·重庆秀山·期末"
+  },
+  {
+    "id": "374",
+    "unit": "第四单元 表内乘法",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "2 个 8 相加的和可以列算式为 2 + 8。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】根据乘法的意义，求几个相同加数的和可以用乘法计算,2 个 8 相加的和列加法算式是 8 + 8，也可以列乘法算式 2×8 或 8×2，据此解答.\n【详解】根据分析,2 个 8 相加的和可以列式为 8 + 8，或者 2×8，或者 8×2。原题说法错误。故答案为: ×。",
+    "knowledge_points": [
+      "初步认识乘法意义"
+    ],
+    "source": "23-24 二年级上·湖南湘西·期末"
+  },
+  {
+    "id": "375",
+    "unit": "第四单元 表内乘法",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "5×7 + 7 = 6×7 = 7×7 - 7。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】5×7 + 7 中,5×7 表示 5 个 7，加 7 表示多了 1 个 7，所以变成了 6 个 7，可列式为 6×7.7×7 - 7 中,7×7 表示 7 个 7，减 7 表示减少 1 个 7，所以变成了 6 个 7，可列式为 6×7.\n【详解】由题意分析得:5×7 + 7 = 6×7 = 7×7 - 7。此等式成立。故答案为:√。",
+    "knowledge_points": [
+      "初步认识乘法意义",
+      "表内乘加，乘减"
+    ],
+    "source": "23-24 二年级上·重庆璧山·期末"
+  },
+  {
+    "id": "376",
+    "unit": "第四单元 表内乘法",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "2×4 和 2 + 4 都可以表示2 个 4 相加。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】乘法算式可以表示几个相同加数的和，若前一个乘数是相同加数，则后一个乘数是相同加数的个数;若前一个乘数是相同加数的个数，则后一个乘数是相同加数。加法算式表示一个数与另一个数的和，由此解答.\n【详解】由分析可知,2×4 可以表示 2 个 4 相加，也可以表示 4 个 2 相加;2 + 4 表示 2 和 4 相加。原题说法错误。故答案为: ×。",
+    "knowledge_points": [
+      "初步认识乘法意义"
+    ],
+    "source": "23-24 二年级上·重庆·期末"
+  },
+  {
+    "id": "377",
+    "unit": "第四单元 表内乘法",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "5×3 = 15，可以表示3 个 5 相加，也可以表示 5 和 3 相加。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】乘法算式可以表示几个相同加数的和。若前一个乘数是相同加数，则后一个乘数是相同加数的个数;若前一个乘数是相同加数的个数，则后一个乘数是相同加数，由此解答.\n【详解】5×3 = 15，可以表示 3 个 5 相加，也可以表示 5 个 3 相加。原题说法错误。故答案为: ×。",
+    "knowledge_points": [
+      "初步认识乘法意义",
+      "5 的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·河南商丘·期中"
+  },
+  {
+    "id": "378",
+    "unit": "第四单元 表内乘法",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "2 个 7 相加的和是多少。列式是 7×7。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】求几个相同加数的和，可以用乘法计算，用相同加数×个数或个数×相同加数，由此解答.\n【详解】2 个 7 相加的和，列式是 2×7 或 7×2。原题说法错误。故答案为: ×。",
+    "knowledge_points": [
+      "初步认识乘法意义"
+    ],
+    "source": "24-25 二年级上·河南商丘·期中"
+  },
+  {
+    "id": "379",
+    "unit": "第四单元 表内乘法",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "求6 个3 的和的算式是 6 + 3。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】根据题意可知，求几个相同数连加的和，可以用乘法表示，列式为 3×6 或 6×3.\n【详解】求 6 个 3 的和，算式是 3×6 或 6×3。原题说法错误。故答案为: ×。",
+    "knowledge_points": [
+      "同数连加的应用",
+      "初步认识乘法意义"
+    ],
+    "source": "24-25 二年级上·河南周口·期中"
+  },
+  {
+    "id": "380",
+    "unit": "第四单元 表内乘法",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "下图表示 3 个 2，列式为 3×2。( )\n\n![](images/48bdebc90c798c336fb011d1dad39a74bd55b2842ba1474ff8ddcaeefb9553f1.jpg)\n\n![](images/184f15b6e7a32e572b4e5b37ced3edcdd6537f19eab8ea3a3d8e1ed5c9f55108.jpg)",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】由图可知，每行有 3 个圆，有 2 行，也就是表示 2 个 3 的和，列乘法算式时，可以用每行的数量×行数或行数×每行的数量，由此解答.\n【详解】由分析可知，该图按行看表示 2 个 3，不表示 3 个 2。原题说法错误。故答案为: ×。",
+    "knowledge_points": [
+      "初步认识乘法意义"
+    ],
+    "source": "24-25 二年级上·河南三门峡·期中"
+  },
+  {
+    "id": "381",
+    "unit": "第四单元 表内乘法",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "4×3 和 3×4 读法相同，表示的含义也相同。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】据题意,4×3 表示 4 个 3 的和是多少或 3 个 4 的和是多少，读作 4 乘 3;3×4 表示 3 个 4 的和是多少或 4 个 3 的和是多少，读作 3 乘 4，由此可得出判断.\n【详解】据分析可得,4×3 和 3×4 的读法不同，表示的含义相同，原题说法错误。故答案为: ×。",
+    "knowledge_points": [
+      "初步认识乘法意义",
+      "4 的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·河南三门峡·期中"
+  },
+  {
+    "id": "382",
+    "unit": "第四单元 表内乘法",
+    "question_type": "计算题",
+    "difficulty": 0.85,
+    "question": "口算.\n\n40 - 8 = ( );3×4 + 5 = ( );5×3 - 4 = ( );100 - 80 = ( );75 - 25 = ( );5×4 = ( );1×1 = ( );52 + 8 = ( )",
+    "options": [],
+    "answer": "32;17;11;20;50;20;1;60",
+    "solution": "【分析】本题包含100以内加减法，乘法口诀以及乘加乘减混合运算。计算时，加减法要注意进位和退位，乘法直接应用口诀，乘加乘减要先算乘法再算加减法.\n【详解】40 - 8 = 32(个位0减8不够，向十位借1,10 - 8 = 2，十位剩3);3×4 + 5 = 12 + 5 = 17;5×3 - 4 = 15 - 4 = 11;100 - 80 = 20;75 - 25 = 50(个位5 - 5 = 0，十位7 - 2 = 5);5×4 = 20(口诀\"四五二十\");1×1 = 1(口诀\"一一得一\");52 + 8 = 60(个位2 + 8 = 10，向十位进1，十位5 + 1 = 6)",
+    "knowledge_points": [
+      "一位数与两位数的进位加法",
+      "一位数与两位数的退位减法",
+      "5 的乘法口诀及应用",
+      "表内乘加，乘减"
+    ],
+    "source": "24-25 二年级上·河南三门峡·期中"
+  },
+  {
+    "id": "383",
+    "unit": "第四单元 表内乘法",
+    "question_type": "计算题",
+    "difficulty": 0.85,
+    "question": "直接写出得数.\n\n84 - 18 = ( );20 + 35 = ( );62 - (70 - 8) = ( );3×6 - 4 = ( );6×4 + 4 = ( );87 - 17 = ( );33 - (16 + 6) = ( );15 + 20 + 8 = ( )",
+    "options": [],
+    "answer": "66;55;0;14;28;70;11;43",
+    "solution": "【分析】本题包含两位数加减法，带括号的加减混合运算以及乘加乘减计算。计算时要注意运算顺序：有括号的先算括号里面的;乘加，乘减算式先算乘法，再算加减法;没有括号的加减法按从左到右的顺序计算.\n【详解】84 - 18 = 66(个位4减8不够，向十位借1,14 - 8 = 6，十位8借1剩7,7 - 1 = 6);20 + 35 = 55(个位0 + 5 = 5，十位2 + 3 = 5);62 - (70 - 8) = 62 - 62 = 0(先算括号内70 - 8 = 62，再算62 - 62 = 0);3×6 - 4 = 18 - 4 = 14(先算乘法3×6 = 18，再算减法);6×4 + 4 = 24 + 4 = 28(先算乘法6×4 = 24，再算加法);87 - 17 = 70(个位7 - 7 = 0，十位8 - 1 = 7);33 - (16 + 6) = 33 - 22 = 11(先算括号内16 + 6 = 22，再算33 - 22 = 11);15 + 20 + 8 = 43(按顺序先算15 + 20 = 35，再算35 + 8 = 43)",
+    "knowledge_points": [
+      "两位数与两位数的退位减法",
+      "100 以内数的加减混合运算",
+      "表内乘加，乘减"
+    ],
+    "source": "24-25 二年级上·河南南阳·期中"
+  },
+  {
+    "id": "384",
+    "unit": "第四单元 表内乘法",
+    "question_type": "计算题",
+    "difficulty": 0.65,
+    "question": "看图列式计算.\n\n![](images/dcc2d1ebcf20c53029a5b2d63d30dc0adfa657e26651b5c9494108454a5582f8.jpg)\n\n□ ○ □ ○ □ = □(条)",
+    "options": [],
+    "answer": "4×4 + 1 = 17(条)",
+    "solution": "[知识点]图文问题，表内乘加，乘减\n【分析】由图可知，每个鱼缸里平均放4 条鱼，放了这样的4 个鱼缸，还多1 条，求一共有多少条鱼，用乘加计算.\n【详解】 4×4 + 1 = 16 + 1 = 17(条),一共有 17 条鱼。",
+    "knowledge_points": [
+      "图文问题",
+      "表内乘加，乘减"
+    ],
+    "source": "24-25 二年级上·重庆·期中"
+  },
+  {
+    "id": "385",
+    "unit": "第四单元 表内乘法",
+    "question_type": "计算题",
+    "difficulty": 0.65,
+    "question": "看图列算式.\n\n![](images/5ccc9abb52b5be6cfa19caa61ead6a5ffc5ded92280aace2a993ed989920454c.jpg)\n\n□ ○ □ ○ □ = □ (条)",
+    "options": [],
+    "answer": "4×3 + 5 = 17(条)",
+    "solution": "【分析】每个鱼缸中有4 条鱼，有3 个鱼缸，第4 个鱼缸里有5 条鱼，求一共有几条鱼，也就是求3 个4 的和再加5 是多少，用每个鱼缸中鱼的数量4条×鱼缸的数量3个 + 多的数量5 条，计算即可.\n【详解】4×3 + 5 = 12 + 5 = 17 (条) ,一共有 17 条鱼。",
+    "knowledge_points": [
+      "图文问题",
+      "表内乘加，乘减"
+    ],
+    "source": "24-25 二年级上·山东临沂·期中"
+  },
+  {
+    "id": "386",
+    "unit": "第四单元 表内乘法",
+    "question_type": "计算题",
+    "difficulty": 0.85,
+    "question": "看图列式计算.\n\n![](images/450f7c3d9c69ef51c8a7f67269ff0157a5d04179b292acd15c206bb40fd0eb42.jpg)",
+    "options": [],
+    "answer": "4×3 = 12(只)",
+    "solution": "【分析】每组有4 只小鸭，有3 组，求一共有多少只小鸭，也就是求3个4的和是多少，用加法计算时，相同加数是4，加数的个数是3 个，用乘法计算时，每组的数量×组数或组数×每组的数量.\n【详解】 4×3 = 12(只)或 3×4 = 12(只)或 4 + 4 + 4 = 12(只),一共有 12 只小鸭。",
+    "knowledge_points": [
+      "图文问题",
+      "同数连加的应用",
+      "4 的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·广东汕头·期中"
+  },
+  {
+    "id": "387",
+    "unit": "第四单元 表内乘法",
+    "question_type": "计算题",
+    "difficulty": 0.85,
+    "question": "看图列式计算.\n\n![](images/5f49b2814600a54eef6f10d03657fa6baa452a8525676c73c382559a6f9aa32f.jpg)\n\n□ * □ = □(朵)\n□ * □ = □(朵)",
+    "options": [],
+    "answer": "4×2 = 8;2×4 = 8",
+    "solution": "【分析】每组有4 朵花，有2 组，求一共有几朵，用每组的数量×组数或组数×每组的数量.\n【详解】 4×2 = 8(朵);2×4 = 8(朵),一共有 8 朵。",
+    "knowledge_points": [
+      "图文问题",
+      "4 的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·广西南宁·期中"
+  },
+  {
+    "id": "388",
+    "unit": "第四单元 表内乘法",
+    "question_type": "计算题",
+    "difficulty": 0.65,
+    "question": "看图列式计算.\n\n![](images/050c94d14b77b82ca8c343d972af66cd986aca4d02b663405a9c8843acd8bae4.jpg)\n\n□ * □ = □(元)",
+    "options": [],
+    "answer": "3×5 = 15(元)",
+    "solution": "【分析】由图可知,1 个甜筒5 元钱，求 3 个甜筒多少元就是求 3 个 5 相加的和，用乘法列式计算.\n【详解】 3×5 = 15(元)(列式不唯一)",
+    "knowledge_points": [
+      "图文问题",
+      "5 的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·广西南宁·期中"
+  },
+  {
+    "id": "389",
+    "unit": "第四单元 表内乘法",
+    "question_type": "计算题",
+    "difficulty": 0.85,
+    "question": "口算.\n\n54 - 8 = ( );47 + 43 = ( );92 - 87 = ( );28 - 12 + 8 = ( );23 + 54 = ( );4×4 = ( );5×3 = ( );76 - (20 - 4) = ( )",
+    "options": [],
+    "answer": "46;90;5;24;77;16;15;60",
+    "solution": "【分析】本题包含100以内加减法，乘法口诀以及加减混合运算。计算时，加减法要注意进位和退位，乘法直接应用口诀，加减混合运算按从左到右的顺序进行，有括号的先算括号里面的.\n【详解】54 - 8 = 46(个位4减8不够，向十位借1,14 - 8 = 6，十位剩4，得46);47 + 43 = 90(个位7 + 3 = 10，向十位进1，十位4 + 4 + 1 = 9，得90);92 - 87 = 5(个位2减7不够，向十位借1,12 - 7 = 5，十位9借1剩8,8 - 8 = 0，得5);28 - 12 + 8 = 16 + 8 = 24(先算28 - 12 = 16，再算16 + 8 = 24);23 + 54 = 77(个位3 + 4 = 7，十位2 + 5 = 7，不进位，得77);4×4 = 16(口诀\"四四十六\");5×3 = 15(口诀\"三五十五\");76 - (20 - 4) = 76 - 16 = 60(先算括号内20 - 4 = 16，再算76 - 16 = 60)",
+    "knowledge_points": [
+      "一位数与两位数的退位减法",
+      "两位数与两位数的进位加法",
+      "5 的乘法口诀及应用",
+      "4 的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·河南南阳·期中"
+  },
+  {
+    "id": "390",
+    "unit": "第四单元 表内乘法",
+    "question_type": "计算题",
+    "difficulty": 0.85,
+    "question": "直接写得数.\n\n45 - 8 = ( );6×2 = ( );3×4 = ( );98 - 81 + 7 = ( );52 + 1 = ( );39 + 1 = ( );5 + 8 = ( );35 + 11 + 7 = ( )",
+    "options": [],
+    "answer": "37;12;12;24;53;40;13;53",
+    "solution": "【分析】本题包含一位数与两位数的退位减法，乘法口诀，连加以及加减混合运算。计算时，退位减法要注意个位不够减时向十位借一;乘法直接应用对应的乘法口诀;连加和加减混合按从左到右的顺序依次计算.\n【详解】45 - 8 = 37(个位5减8不够，向十位借1,15 - 8 = 7，十位剩3，得37);6×2 = 12(口诀\"二六十二\");3×4 = 12(口诀\"三四十二\");98 - 81 + 7 = 17 + 7 = 24(先算98 - 81 = 17，再算17 + 7 = 24);52 + 1 = 53(个位2 + 1 = 3，十位5不变);39 + 1 = 40(个位9 + 1 = 10，向十位进1，十位3 + 1 = 4);5 + 8 = 13(5加8等于13);35 + 11 + 7 = 46 + 7 = 53(先算35 + 11 = 46，再算46 + 7 = 53)",
+    "knowledge_points": [
+      "一位数与两位数的退位减法",
+      "100 以内数的连加运算",
+      "100 以内数的加减混合运算",
+      "6 的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·湖北武汉·期中"
+  },
+  {
+    "id": "391",
+    "unit": "第四单元 表内乘法",
+    "question_type": "解答题",
+    "difficulty": 0.85,
+    "question": "二(1)班在排练节目，男生有 4 行，每行 5 人，女生有 5 列，每列 3 人。二(1)班一共有多少人参加节目。",
+    "options": [],
+    "answer": "35 人",
+    "solution": "【分析】根据题意，男生的人数为 4 个 5 的和，用每行的人数和行数相乘，求出男生的人数;女生的人数为 5 个 3 的和，用每列的人数和列数相乘，求出女生的人数，将男生和女生的人数相加，就是总人数.\n【详解】男生:5×4 = 20(人);女生:3×5 = 15(人);一共:20 + 15 = 35(人)。答：二(1)班一共有 35 人参加节目。",
+    "knowledge_points": [
+      "两位数与整十数的加法",
+      "5 的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·山东济南·期中"
+  },
+  {
+    "id": "392",
+    "unit": "第四单元 表内乘法",
+    "question_type": "解答题",
+    "difficulty": 0.85,
+    "question": "妈妈在超市买 4 排酸奶，每排 6 瓶，一共有多少瓶。",
+    "options": [],
+    "answer": "24 瓶",
+    "solution": "【分析】求一共有多少瓶，也就是求 4 个 6 的和是多少，用乘法计算，每排的瓶数和排数相乘，就是总瓶数.\n【详解】 6×4 = 24(瓶),答：一共有 24 瓶。",
+    "knowledge_points": [
+      "6 的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·河南漯河·期中"
+  },
+  {
+    "id": "393",
+    "unit": "第四单元 表内乘法",
+    "question_type": "解答题",
+    "difficulty": 0.65,
+    "question": "如下图:\n\n![](images/屏幕截图%202026-02-25%20203430.png)\n\n(1)买 6 个玩具小熊需要多少元。\n(2)典典买了一辆玩具汽车和一个书包，能节省 5 元吗。",
+    "options": [],
+    "answer": "30;不能",
+    "solution": "【分析】(1)买 6 个玩具小熊需要的钱数也就是 6 个 5 的和，用乘法计算，每个玩具小熊的钱数和玩具小熊的数量相乘，就是总钱数;(2)根据题意，先用加法计算出一辆玩具汽车和一个书包的总钱数，再和 50 元比较大小，大于或等于 50 元能节省 5 元，小于 50 元不能节省 5 元.\n【详解】(1)5×6 = 30(元),答：买 6 个玩具小熊需要 30 元。(2)18 + 24 = 42(元),42 < 50，答：不能节省 5 元。",
+    "knowledge_points": [
+      "图文问题",
+      "100 以内数的比大小",
+      "两位数与两位数的进位加法",
+      "6 的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·重庆·期中"
+  },
+  {
+    "id": "394",
+    "unit": "第四单元 表内乘法",
+    "question_type": "解答题",
+    "difficulty": 0.85,
+    "question": "一辆小汽车坐 5 人,5 辆小汽车能坐多少人。",
+    "options": [],
+    "answer": "25 人",
+    "solution": "【分析】根据题意,5 辆小汽车能坐的人数也就是5 个5 的和，用乘法计算，每辆小汽车能坐的人数和小汽车的数量相乘，就是能坐的总人数.\n【详解】 5×5 = 25(人),答:5 辆小汽车能坐 25 人。",
+    "knowledge_points": [
+      "5 的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·广东汕头·期中"
+  },
+  {
+    "id": "395",
+    "unit": "第四单元 表内乘法",
+    "question_type": "解答题",
+    "difficulty": 0.65,
+    "question": "幼儿园 35 个小朋友每人吃 1 个鸡蛋，这些鸡蛋够吗。\n\n![](images/e6478d26407ac5709cc8d35e878f41dc52427ba8da7a07580fdb4553af87262b.jpg)",
+    "options": [],
+    "answer": "不够",
+    "solution": "【分析】根据题意，先计算出一共有多少个鸡蛋，再和小朋友的人数比较大小。人数大于鸡蛋的数量不够，小于或等于鸡蛋的数量够。每行有6个鸡蛋，有5行，还多4个，则鸡蛋的数量用每行的数量×行数 + 多的数量计算.\n【详解】 6×5 + 4 = 30 + 4 = 34(个),34 < 35，答：这些鸡蛋不够。",
+    "knowledge_points": [
+      "图文问题",
+      "100 以内数的比大小",
+      "表内乘加，乘减"
+    ],
+    "source": "2024 二年级上·全国·专题练习"
+  },
+  {
+    "id": "396",
+    "unit": "第四单元 表内乘法",
+    "question_type": "解答题",
+    "difficulty": 0.85,
+    "question": "买 3 杯可乐需要多少元。\n\n![](images/ae15b0213a5557dfb5496d9e278d5207caf125e3fed80b2f0f7d026ba669206e.jpg)\n\n![](images/fb5b4ef7b3cfa597b649f6fd45a8fda831a2dbf5b0d26f815265a1906bed0378.jpg)\n\n![](images/bbc84f710585decc50cd87f0a2522567cdfa7924c4458917f18adf211cff8c2a.jpg)",
+    "options": [],
+    "answer": "18 元",
+    "solution": "【分析】买3 杯可乐需要的钱数，也就是求3 个6 的和是多少，用乘法计算，每杯可乐的钱数和杯数相乘，就是需要的总钱数.\n【详解】 6×3 = 18(元),答：买 3 杯可乐需要 18 元。",
+    "knowledge_points": [
+      "图文问题",
+      "经济问题",
+      "6 的乘法口诀及应用"
+    ],
+    "source": "2024 二年级上·全国·专题练习"
+  },
+  {
+    "id": "397",
+    "unit": "第四单元 表内乘法",
+    "question_type": "解答题",
+    "difficulty": 0.65,
+    "question": "小明和爸爸，妈妈要去参观民俗园，门票一共要花多少钱。\n\n![](images/屏幕截图%202026-02-25%20203743.png)",
+    "options": [],
+    "answer": "12 元",
+    "solution": "【分析】根据题意可知，一共要买 2 张成人票和 1 张儿童票。用一张成人票的价钱乘 2，再加一张儿童票的价钱即可.\n【详解】5×2 + 2 = 10 + 2 = 12(元),答：门票一共要花 12 元钱。",
+    "knowledge_points": [
+      "图文问题",
+      "经济问题",
+      "表内乘加，乘减"
+    ],
+    "source": "24-25 二年级上·福建三明·期中"
+  },
+  {
+    "id": "398",
+    "unit": "第四单元 表内乘法",
+    "question_type": "解答题",
+    "difficulty": 0.65,
+    "question": "明明的书如果每 3 本放一堆，可以放 4 堆，还剩 1 本，小华的书如果每 5 本放一堆，可以放 3 堆，还差 3 本.\n(1)明明一共有多少本书。\n(2)小华一共有多少本书。",
+    "options": [],
+    "answer": "13;12",
+    "solution": "【分析】(1)求明明一共有多少本书，也就是求 4 个 3 的和再加 1 是多少，用每堆书的本数×堆数 + 还剩的本数;(2)求小华一共有多少本书，也就是求 3 个 5 的和再减 3 是多少，用每堆书的本数×堆数 - 还差的本数.\n【详解】(1)3×4 + 1 = 12 + 1 = 13(本),答：明明一共有 13 本书。(2)5×3 - 3 = 15 - 3 = 12(本),答：小华一共有 12 本书。",
+    "knowledge_points": [
+      "表内乘加，乘减"
+    ],
+    "source": "24-25 二年级上·河南南阳·期中"
+  },
+  {
+    "id": "399",
+    "unit": "第四单元 表内乘法",
+    "question_type": "解答题",
+    "difficulty": 0.85,
+    "question": "二一班有 6 人参加书法小组，参加合唱小组的人数是书法小组的 3 倍。参加合唱小组有多少人。",
+    "options": [],
+    "answer": "18 人",
+    "solution": "【分析】根据题意可知，求一个数的几倍，用乘法计算.\n【详解】6×3 = 18(人),答：参加合唱小组有 18 人。",
+    "knowledge_points": [
+      "求一个数的几倍是多少"
+    ],
+    "source": "23-24 二年级上·重庆云阳·期末"
+  },
+  {
+    "id": "400",
+    "unit": "第四单元 表内乘法",
+    "question_type": "解答题",
+    "difficulty": 0.85,
+    "question": "手工课上，玲玲用一张纸做了 3 朵红花,5 张纸可以做多少朵花。",
+    "options": [],
+    "answer": "15 朵",
+    "solution": "【分析】一张纸做了3 朵红花，求5 张纸可以做多少朵花，就是求5 个3 的和是多少，可以用乘法列式解决.\n【详解】 3×5 = 15(朵),答:5 张纸可以做15 朵花。",
+    "knowledge_points": [
+      "5 的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·河北沧州·期中"
+  },
+  {
+    "id": "401",
+    "unit": "第四单元 表内乘法",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "在4的乘法口诀中，每相邻两句的积之间相差( )。",
+    "options": [
+      "A. 2",
+      "B. 4",
+      "C. 8"
+    ],
+    "answer": "B",
+    "solution": "【分析】据题意，是4的乘法口诀之间的计算，可先将4的乘法口诀写出来，再计算每个结果之间的差即可得出答案.\n【详解】1×4 = 4,2×4 = 8,3×4 = 12,4×4 = 16,8 - 4 = 4,12 - 8 = 4,16 - 12 = 4，由此可以看出 4 的乘法口诀每相邻两句口诀的积相差 4。故答案为:B",
+    "knowledge_points": [
+      "4 的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·广东韶关·期中"
+  },
+  {
+    "id": "402",
+    "unit": "第四单元 表内乘法",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "求 3 个 5 相加的和，列式错误的是( )。",
+    "options": [
+      "A. 5 + 5 + 5",
+      "B. 3 + 3 + 3 + 3 + 3",
+      "C. 3×5"
+    ],
+    "answer": "B",
+    "solution": "【分析】据题意，是 3 个 5 相加，加法算式为 5 + 5 + 5，转换为乘法算式为 3×5 或 5×3，再根据选项选出答案即可.\n【详解】A。5 + 5 + 5 是 3 个 5 相加;B。3 + 3 + 3 + 3 + 3 是 5 个 3 相加;C。3×5 可以写为 5 + 5 + 5，表示 3 个 5 相加。所以求 3 个 5 相加的和，列式错误的是 3 + 3 + 3 + 3 + 3。故答案为:B.",
+    "knowledge_points": [
+      "同数连加的应用",
+      "初步认识乘法意义",
+      "5 的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·广东韶关·期中"
+  },
+  {
+    "id": "403",
+    "unit": "第四单元 表内乘法",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "下面哪个问题不能用 4×3 解决的是( )。",
+    "options": [
+      "A. 明明在纸上画了 3 个独立的正方形，那么这些正方形一共有多少个直角。",
+      "B. \"木\"字的笔画是 4 画，\"森\"字的笔画是多少画。",
+      "C. 第一组有 4 个人，第二组有 3 个人，一共有多少人。"
+    ],
+    "answer": "C",
+    "solution": "【分析】算式 4×3 表示 4 个 3 相加或者 3 个 4 相加。逐个分析选项，看哪个问题不能用 4×3 解决.\n【详解】A。每个正方形有 4 个直角,3 个正方形一共有多少个直角，就是 3 个 4 的和，列式为 4×3;B.\"木\"字 4 画，\"森\"字有 3 个\"木\"，就是 3 个 4 的和，列式为 4×3;C。第一组 4 人，第二组 3 人，一共有多少人用加法 4 + 3 计算。故答案为:C",
+    "knowledge_points": [
+      "4 的乘法口诀及应用",
+      "直角，钝角，锐角的认识及特征"
+    ],
+    "source": "24-25 二年级上·福建厦门·期中"
+  },
+  {
+    "id": "404",
+    "unit": "第四单元 表内乘法",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "一堆桔子,3 个 3 个地数正好数完,4 个 4 个地数也正好数完，这堆桔子至少有( )个。",
+    "options": [
+      "A. 9",
+      "B. 12",
+      "C. 16"
+    ],
+    "answer": "B",
+    "solution": "【分析】3 个 3 个数和 4 个 4 个数都正好数完，说明桔子个数是 3 和 4 的公倍数，且至少几个，用 3×4 即可.\n【详解】3×4 = 12(个),故答案为:B",
+    "knowledge_points": [
+      "4 的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·福建三明·期中"
+  },
+  {
+    "id": "405",
+    "unit": "第四单元 表内乘法",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "计算图中桃子的数量，列式错误的是( ).\n\n![](images/2026-02-25%20214402.jpg)",
+    "options": [
+      "A. 3×5",
+      "B. 3×4 + 1",
+      "C. 3×5 - 2"
+    ],
+    "answer": "A",
+    "solution": "【分析】每盘有 3 个桃子，有 4 盘，第 5 盘有 1 个，可以用 4 个 3 的和再加 1 计算;也可以看成有 5 盘，每盘 3 个，再减去多算的 2 个.\n【详解】A。3×5 表示 5 个 3 的和，与题意不符，列式错误;B。3×4 + 1 表示 4 个 3 的和再加 1，正确;C。3×5 - 2 表示 5 个 3 的和再减 2，正确。故答案为:A",
+    "knowledge_points": [
+      "图文问题",
+      "5 的乘法口诀及应用",
+      "表内乘加，乘减"
+    ],
+    "source": "24-25 二年级上·福建三明·期中"
+  },
+  {
+    "id": "406",
+    "unit": "第四单元 表内乘法",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "画图表示 2×3 的含义，错误的是( ).\n\nA。![](images/2026-02-25%20214600.jpg)\n\nB。![](images/2026-02-25%20214614.jpg)\n\nC。![](images/2026-02-25%20214637.jpg)\n\nD。![](images/2026-02-25%20214654.jpg)",
+    "options": [
+      "A. 图 A",
+      "B. 图 B",
+      "C. 图 C",
+      "D. 图 D"
+    ],
+    "answer": "C",
+    "solution": "【分析】2×3 可以表示 2 个 3 的和，也可以表示 3 个 2 的和.\n【详解】A。一行有 3 个 ○,有 2 行，可以表示 2×3;B。一列有 2 个 ○,有 3 列，可以表示 2×3;C。一行有 3 个 ○,另一行有 2 个 ○,表示 2 + 3，不是 2×3;D。一组有 3 个 ○,有 2 组，可以表示 2×3。故答案为:C",
+    "knowledge_points": [
+      "初步认识乘法意义"
+    ],
+    "source": "24-25 二年级上·福建龙岩·期中"
+  },
+  {
+    "id": "407",
+    "unit": "第四单元 表内乘法",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "要计算下边共有多少个苹果，错误的算式是( ).\n\n![](images/f7ad934de4ed27f3b0813978d41299958ee0fc7a5024829a998ffdb4b3367392.jpg)",
+    "options": [
+      "A. 5×2 + 3",
+      "B. 5×3 + 2",
+      "C. 3×3 + 4"
+    ],
+    "answer": "B",
+    "solution": "【分析】一行苹果 5 个。可用\"2 行的 5 个再加 3 个\"或\"3 行的 3 个再加 4 个\"等方式列式.\n【详解】A。5×2 + 3：一行 5 个,2 行共 10 个，再加 3 个，符合图意;B。5×3 + 2：一行 5 个,3 行 15 个，再加 2 个，不符合图意;C。3×3 + 4：一行 3 个,3 行 9 个，再加 4 个，也可以表示图意。故答案为:B",
+    "knowledge_points": [
+      "图文问题",
+      "表内乘加，乘减"
+    ],
+    "source": "24-25 二年级上·福建福州·期中"
+  },
+  {
+    "id": "408",
+    "unit": "第四单元 表内乘法",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "5 个 5 相加的和是多少。列式错误的是( )。",
+    "options": [
+      "A. 5 + 5",
+      "B. 5×5",
+      "C. 5 + 5 + 5 + 5 + 5"
+    ],
+    "answer": "A",
+    "solution": "【分析】5 个 5 相加，列加法时相同加数是 5，加数个数是 5 个;也可以用乘法表示.\n【详解】A。5 + 5 表示 2 个 5 相加，错误;B。5×5 表示 5 个 5 相加，正确;C。5 + 5 + 5 + 5 + 5 表示 5 个 5 相加，正确。故答案为:A",
+    "knowledge_points": [
+      "同数连加的应用",
+      "初步认识乘法意义"
+    ],
+    "source": "24-25 二年级上·河南南阳·期中"
+  },
+  {
+    "id": "409",
+    "unit": "第四单元 表内乘法",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下列算式中，能直接写成乘法算式的是( )。",
+    "options": [
+      "A. 5 + 5 + 5",
+      "B. 3 + 3 + 3 + 3 + 4",
+      "C. 2 + 2 + 2 + 5"
+    ],
+    "answer": "A",
+    "solution": "【分析】能直接写成乘法算式，必须是几个相同加数连加.\n【详解】A。5 + 5 + 5 是 3 个 5 相加，可直接写成 3×5 或 5×3;B。3 + 3 + 3 + 3 + 4 需要先变形，不能直接写成乘法;C。2 + 2 + 2 + 5 同样不能直接写成乘法。故答案为:A",
+    "knowledge_points": [
+      "同数连加的应用",
+      "初步认识乘法意义",
+      "表内乘加，乘减"
+    ],
+    "source": "24-25 二年级上·湖北武汉·期中"
+  },
+  {
+    "id": "410",
+    "unit": "第四单元 表内乘法",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "用画图法表示 3×4，错误的是( ).\n\nA。![](images/2026-02-25%20215249.jpg)\n\nB。![](images/2026-02-25%20215307.jpg)\n\nC。![](images/2026-02-25%20215319.jpg)",
+    "options": [
+      "A. 图 A",
+      "B. 图 B",
+      "C. 图 C"
+    ],
+    "answer": "C",
+    "solution": "【分析】3×4 表示 3 个 4 或 4 个 3.\n【详解】A。表示 4 个 3，可以表示 3×4;B。表示 3 个 4，可以表示 3×4;C。表示 2 个 4 再多 3 个，不是 3×4。故答案为:C",
+    "knowledge_points": [
+      "初步认识乘法意义"
+    ],
+    "source": "24-25 二年级上·江西宜春·期中"
+  },
+  {
+    "id": "411",
+    "unit": "第四单元 表内乘法",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下列算式与 8 + 7 的结果相等的是( )。",
+    "options": [
+      "A. 72 - 65 + 9",
+      "B. 3×4 + 3",
+      "C. 21 - 16"
+    ],
+    "answer": "B",
+    "solution": "【分析】先分别算出每个算式的结果，再比较.\n【详解】8 + 7 = 15;A。72 - 65 + 9 = 7 + 9 = 16;B。3×4 + 3 = 12 + 3 = 15;C。21 - 16 = 5。与 8 + 7 结果相等的是 3×4 + 3。故答案为:B",
+    "knowledge_points": [
+      "8加几的进位加法",
+      "两位数与两位数的退位减法",
+      "100 以内数的加减混合运算",
+      "表内乘加，乘减"
+    ],
+    "source": "24-25 二年级上·江西宜春·期中"
+  },
+  {
+    "id": "412",
+    "unit": "第四单元 表内乘法",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "能用 3×4 表示的图形是( ).\n\nA。![](images/ce60d5e52ef6f4a85cb5ee580482586291fa4c05c4496198ace8f269619bcd98.jpg)\n\nB。![](images/2ecd54e1f7f00efecf8aad03146a5646c286eaa4edc73f134ef469acebba31fe.jpg)\n\nC。![](images/6ec51c6d075c85c36c1fb20a344be60aa27231ad012fb0b66ab5a704607c1f9b.jpg)",
+    "options": [
+      "A. 图 A",
+      "B. 图 B",
+      "C. 图 C"
+    ],
+    "answer": "B",
+    "solution": "【分析】3×4 表示 3 个 4 的和或 4 个 3 的和.\n【详解】A。每行 3 个，共 3 行，是 3×3;B。一个四边形 4 条边，有 3 个四边形，是 3×4;C。左 4 个右 3 个，表示 4 和 3 的和。故答案为:B",
+    "knowledge_points": [
+      "同数连加的应用",
+      "初步认识乘法意义"
+    ],
+    "source": "24-25 二年级上·山东日照·期中"
+  },
+  {
+    "id": "413",
+    "unit": "第四单元 表内乘法",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面算式中，不能用\"三五十五\"这句口诀计算的是( )。",
+    "options": [
+      "A. 3×5",
+      "B. 2×5",
+      "C. 5×3"
+    ],
+    "answer": "B",
+    "solution": "【分析】口诀中的前两个数是乘数，可互换位置，后一个数是积.\n【详解】A。3×5 用\"三五十五\";B。2×5 用\"二五一十\";C。5×3 也用\"三五十五\"。不能用\"三五十五\"的是 2×5。故答案为:B",
+    "knowledge_points": [
+      "5 的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·山东青岛·期中"
+  },
+  {
+    "id": "414",
+    "unit": "第四单元 表内乘法",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "3×2 用画 ○ 的方法可以表示为( )。",
+    "options": [
+      "A. ○ ○ ○ ○ ○",
+      "B. ○ ○ ○ ○",
+      "C. ○ ○ ○ ○ ○ ○"
+    ],
+    "answer": "C",
+    "solution": "【分析】3×2 表示 3 个 2 的和或 2 个 3 的和.\n【详解】A。表示 3 和 2 的和;B。表示 2 个 2 的和;C。表示 2 个 3 的和，符合 3×2 的含义。故答案为:C",
+    "knowledge_points": [
+      "初步认识乘法意义"
+    ],
+    "source": "24-25 二年级上·河南南阳·期中"
+  },
+  {
+    "id": "415",
+    "unit": "第四单元 表内乘法",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "求一共有多少只小兔子，最简便的方法是( ).\n\n![](images/200548e05321af417ca4564aece57da8dbfa2bba353f9fe7d1495eb918aac7b0.jpg)",
+    "options": [
+      "A. 6 + 6 + 6",
+      "B. 3 + 3 + 3 + 3 + 3 + 3",
+      "C. 3×6"
+    ],
+    "answer": "C",
+    "solution": "【分析】每组有 6 只小兔子，有 3 组，是 3 个 6 的和，乘法最简便.\n【详解】用乘法列式 3×6，最简便。故答案为:C",
+    "knowledge_points": [
+      "初步认识乘法意义"
+    ],
+    "source": "24-25 二年级上·河南南阳·期中"
+  },
+  {
+    "id": "416",
+    "unit": "第四单元 表内乘法",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "与 5 + 5 + 5 + 4 的计算结果相等的算式是( )。",
+    "options": [
+      "A. 5×4",
+      "B. 5×3 + 4",
+      "C. 4×5 + 1"
+    ],
+    "answer": "B",
+    "solution": "【分析】5 + 5 + 5 + 4 表示 3 个 5 的和再加 4.\n【详解】A。5×4 表示 4 个 5 或 5 个 4;B。5×3 + 4 表示 3 个 5 的和再加 4，与原式相同;C。4×5 + 1 表示 4 个 5 的和再加 1。故答案为:B",
+    "knowledge_points": [
+      "5 的乘法口诀及应用",
+      "表内乘加，乘减"
+    ],
+    "source": "24-25 二年级上·广西玉林·期中"
+  },
+  {
+    "id": "417",
+    "unit": "第四单元 表内乘法",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "\"三五十五\"，列式正确的是( )。",
+    "options": [
+      "A. 3 + 5",
+      "B. 3×5",
+      "C. 5 - 3"
+    ],
+    "answer": "B",
+    "solution": "【分析】乘法口诀中前两个数是乘数，后一个数是积.\n【详解】A。3 + 5 是和;B。3×5 = 15，用\"三五十五\";C。5 - 3 是差。故答案为:B",
+    "knowledge_points": [
+      "5 以内数的减法",
+      "8,9 的加减法",
+      "5 的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·广西玉林·期中"
+  },
+  {
+    "id": "418",
+    "unit": "第四单元 表内乘法",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "4 * □ < 16,□ 里最大填( )。",
+    "options": [
+      "A. 3",
+      "B. 4",
+      "C. 5"
+    ],
+    "answer": "A",
+    "solution": "【分析】将选项代入算式比较与 16 的大小.\n【详解】A。4×3 = 12 < 16;B。4×4 = 16;C。4×5 = 20 > 16，满足小于 16 且最大的为 3。故答案为:A",
+    "knowledge_points": [
+      "20 以内数的比大小",
+      "5 的乘法口诀及应用",
+      "4 的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·山东济南·期中"
+  },
+  {
+    "id": "419",
+    "unit": "第四单元 表内乘法",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "一个日记本 5 元,4 个日记本( )元。",
+    "options": [
+      "A. 20",
+      "B. 9",
+      "C. 1"
+    ],
+    "answer": "A",
+    "solution": "【分析】4 个日记本，用 4 个 5 的和即可.\n【详解】5×4 = 20(元),故答案为:A",
+    "knowledge_points": [
+      "5 的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·山东济南·期中"
+  },
+  {
+    "id": "420",
+    "unit": "第四单元 表内乘法",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "赵阿姨家有 4 盒饼干和 5 盒糖果，每盒糖果里有 6 颗糖。根据这些信息，无法解决的问题是( )。",
+    "options": [
+      "A. 饼干和糖果一共有多少盒",
+      "B. 一共有多少块饼干",
+      "C. 一共有多少颗糖果"
+    ],
+    "answer": "B",
+    "solution": "【分析】已知:4 盒饼干,5 盒糖果，每盒糖果 6 颗.\n【详解】A。盒数相加可得总盒数;B。只知道饼干盒数，不知道每盒多少块，无法求饼干块数;C。5 盒糖果，每盒 6 颗，可求总颗数。故无法解决的是\"饼干一共有多少块\"。答案为:B",
+    "knowledge_points": [
+      "6 的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·河南郑州·期中"
+  },
+  {
+    "id": "421",
+    "unit": "第四单元 表内乘法",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "有 2 行树，一行 4 棵，另一行 6 棵，一共有( )棵。",
+    "options": [
+      "A. 2×4 + 6 = 14",
+      "B. 4×6 = 24",
+      "C. 4 + 6 = 10"
+    ],
+    "answer": "C",
+    "solution": "【分析】两行树棵数不同，用加法:4 + 6.\n【详解】A。2×4 + 6 表示 2 个 4 的和再加 6;B。4×6 表示 4 个 6 的和;C。4 + 6 表示 4 和 6 的和，符合题意，一共有 10 棵。故答案为:C",
+    "knowledge_points": [
+      "10 的加减法",
+      "6 的乘法口诀及应用",
+      "表内乘加，乘减"
+    ],
+    "source": "24-25 二年级上·山东济宁·期中"
+  },
+  {
+    "id": "422",
+    "unit": "第四单元 表内乘法",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "下面说法正确的是( )。",
+    "options": [
+      "A. 一个角的边越长，角就越大。",
+      "B. 34 比 29 多 5，也可说 29 比 34 少 5。",
+      "C. 4 乘 2 可以表示 4 个 2 相乘，也可以表示 2 个 4 相乘。"
+    ],
+    "answer": "B",
+    "solution": "【分析】考察角的大小，差的关系，乘法意义.\n【详解】A。角大小与边长无关，与夹角有关，错误;B.\"多 5\"与\"少 5\"互为逆叙述，正确;C。4 乘 2 表示 4 个 2 相加或 2 个 4 相加，不是\"相乘\"，表述错误。故答案为:B",
+    "knowledge_points": [
+      "两位数与两位数的退位减法",
+      "初步认识乘法意义",
+      "角的初步认识及辨认"
+    ],
+    "source": "24-25 二年级上·云南文山·期中"
+  },
+  {
+    "id": "423",
+    "unit": "第四单元 表内乘法",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "《千字文》是中国早期的蒙学课本，自宋代开始广为流传。下面是其中的一部分，计算一共有多少个汉字。列式不正确的是( ).\n\n天地玄黄，宇宙洪荒。日月盈昃，辰宿列张。寒来暑往，秋收冬藏。",
+    "options": [
+      "A. 4 + 4 + 4",
+      "B. 4×6",
+      "C. 8×3"
+    ],
+    "answer": "A",
+    "solution": "【分析】一行 4 个字，共 6 行，是 6 个 4;或一整句 8 个字，共 3 句，是 3 个 8.\n【详解】正确列式有 4×6 或 6×4，也有 8×3 或 3×8.4 + 4 + 4 只表示 3 行，不正确。故答案为:A",
+    "knowledge_points": [
+      "同数连加的应用",
+      "初步认识乘法意义"
+    ],
+    "source": "24-25 二年级上·湖北孝感·期中"
+  },
+  {
+    "id": "424",
+    "unit": "第四单元 表内乘法",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "二年级 4 个班，每班 5 名近视学生，横线上应填的问题是( )。",
+    "options": [
+      "A. 二年级共有多少人",
+      "B. 每个班有多少人",
+      "C. 二年级共有多少名近视学生"
+    ],
+    "answer": "C",
+    "solution": "【分析】已知\"4 个班，每班 5 名近视学生\"，自然提问\"共有多少名近视学生\".\n【详解】横线应填\"二年级共有多少名近视学生\"。故答案为:C",
+    "knowledge_points": [
+      "\"提问题\"\"填条件\"问题",
+      "5 的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·江西九江·期中"
+  },
+  {
+    "id": "425",
+    "unit": "第四单元 表内乘法",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "在括号里填上\" > \"\" < \"或\" = \".\n\n33 + 8 ( ) 52 - 8;2×3 ( ) 2 + 3;26 - 7 ( ) 6×3;69 - 35 ( ) 5×4;20 厘米 + 70 厘米 ( ) 1 米;1 米 - 50 厘米 ( ) 50 厘米",
+    "options": [],
+    "answer": "<;>;>;>;<;=",
+    "solution": "【分析】先分别计算两边的得数，再比较大小;长度单位要统一成厘米或米再比.\n【详解】33 + 8 = 41;52 - 8 = 44,41 < 44;2×3 = 6;2 + 3 = 5,6 > 5;26 - 7 = 19;6×3 = 18,19 > 18;69 - 35 = 34;5×4 = 20,34 > 20;20 厘米 + 70 厘米 = 90 厘米,1 米 = 100 厘米,90 < 100;1 米 - 50 厘米 = 100 厘米 - 50 厘米 = 50 厘米，等号成立。",
+    "knowledge_points": [
+      "100以内数的比大小",
+      "一位数与两位数的进位加法",
+      "6 的乘法口诀及应用",
+      "厘米和米之间的进率与换算"
+    ],
+    "source": "24-25 二年级上·山东菏泽·期中"
+  },
+  {
+    "id": "426",
+    "unit": "第四单元 表内乘法",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "5 + 5 + 5 表示( )个( )相加，改写成乘法算式是( )或( ),计算时运用的乘法口诀是( )。",
+    "options": [],
+    "answer": "3;5;5×3;3×5;三五十五",
+    "solution": "【分析】5 + 5 + 5 是 3 个 5 相加，可写成乘法算式.\n【详解】5 + 5 + 5 表示 3 个 5 相加，改写成乘法算式是 5×3 或 3×5，计算时用\"三五十五\"。",
+    "knowledge_points": [
+      "初步认识乘法意义",
+      "5 的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·山东菏泽·期中"
+  },
+  {
+    "id": "427",
+    "unit": "第四单元 表内乘法",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "在括号里填上合适的数.\n\n4×( ) = 20;3×( ) = 9;( )×6 = 30;5×( ) = 25;4×( ) = 24;( )×3 = 6",
+    "options": [],
+    "answer": "5;3;5;5;6;2",
+    "solution": "【分析】根据表内乘法口诀，已知一个乘数和积，求另一个乘数.\n【详解】四五二十知 4×5 = 20;三三得九知 3×3 = 9;五六三十知 5×6 = 30;五五二十五知 5×5 = 25;四六二十四知 4×6 = 24;二三得六知 2×3 = 6。",
+    "knowledge_points": [
+      "5 的乘法口诀及应用",
+      "3 的乘法口诀及应用",
+      "6 的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·山东青岛·期中"
+  },
+  {
+    "id": "428",
+    "unit": "第四单元 表内乘法",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "如下图所示，上图表示( )个( )相加。列成乘法算式是( )或( ),计算时用到的乘法口诀是( ).\n\n![](images/2c7ed6938ebd6e6a76d0e90cf9df13949300c6de114144c6bb98ab8c166c03c6.jpg)\n\n![](images/fb3e81b2d04890c55acdd4076a6313aa6a8010c61a0496e0baf74ac6b33316aa.jpg)\n\n![](images/1261547bcae58b4e54cdffb4145b1700a0be05cf2591cce4346dfc0175700b5b.jpg)\n\n![](images/8f9d377506955cf6e7c762d91b217870fde40f639609ada62ee5c4870cecaa6c.jpg)",
+    "options": [],
+    "answer": "4;3;4×3 = 12(根);3×4 = 12(根);三四十二",
+    "solution": "【分析】每把有 3 根香蕉，有 4 把，是 4 个 3 的和.\n【详解】上图表示 4 个 3 相加。列成乘法算式是 4×3 = 12(根)或 3×4 = 12(根),用到的乘法口诀是\"三四十二\"。",
+    "knowledge_points": [
+      "初步认识乘法意义",
+      "4 的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·山东青岛·期中"
+  },
+  {
+    "id": "429",
+    "unit": "第四单元 表内乘法",
+    "question_type": "填空题",
+    "difficulty": 0.94,
+    "question": "把下面的口诀填完整.\n\n二四( );三( )得九;( )( )十二;五五( );二( )一十;( )三得三",
+    "options": [],
+    "answer": "得八;三;三;四;二十五;五;一",
+    "solution": "【分析】依据熟记的乘法口诀表补全空缺文字.\n【详解】二四得八;三三得九;三四十二;五五二十五;二五一十;一三得三。",
+    "knowledge_points": [
+      "5 的乘法口诀及应用",
+      "3 的乘法口诀及应用",
+      "4 的乘法口诀及应用",
+      "6 的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·江西宜春·期中"
+  },
+  {
+    "id": "430",
+    "unit": "第四单元 表内乘法",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "2×4 = ( ),读作( ),其中 2 和 4 是( ),积是( ),计算时所用口诀是( )。",
+    "options": [],
+    "answer": "8;2 乘 4 等于 8;乘数;8;二四得八",
+    "solution": "【分析】乘法算式为乘数×乘数 = 积，读法从左到右.\n【详解】2×4 = 8，读作\"2 乘 4 等于 8\"，其中 2 和 4 是乘数，积是 8，所用口诀是\"二四得八\"。",
+    "knowledge_points": [
+      "初步认识乘法意义",
+      "4 的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·山东济南·期中"
+  },
+  {
+    "id": "431",
+    "unit": "第四单元 表内乘法",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "在括号里填上\" > \"\" < \"或\" = \".\n\n5×4 ( ) 25;58 - 14 ( ) 40;26 + 29 ( ) 60;4×4 ( ) 20;2×2 ( ) 4;2×3 ( ) 2×4",
+    "options": [],
+    "answer": "<;>;<;<;=;<",
+    "solution": "【分析】先分别算出算式结果，再比较大小.\n【详解】5×4 = 20 < 25;58 - 14 = 44 > 40;26 + 29 = 55 < 60;4×4 = 16 < 20;2×2 = 4，与 4 相等;2×3 = 6 < 8 = 2×4。",
+    "knowledge_points": [
+      "100以内数的比大小",
+      "两位数与两位数的进位加法",
+      "5 的乘法口诀及应用",
+      "4 的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·山东济南·期中"
+  },
+  {
+    "id": "432",
+    "unit": "第四单元 表内乘法",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "乐乐说：\"我种了 2 行树，一行 3 棵，另一行 4 棵.\"欢欢说：\"我种了 2 行树，每行 4 棵.\"乐乐种了( )棵树，欢欢种了( )棵树。",
+    "options": [],
+    "answer": "7;8",
+    "solution": "【分析】乐乐是 3 + 4;欢欢是 2 行，每行 4 棵.\n【详解】乐乐:3 + 4 = 7(棵);欢欢:4×2 = 8(棵)。",
+    "knowledge_points": [
+      "7 的加减法",
+      "4 的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·云南文山·期中"
+  },
+  {
+    "id": "433",
+    "unit": "第四单元 表内乘法",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "把口诀补充完整.\n\n三( )得九;一五( );五六( );( )得六",
+    "options": [],
+    "answer": "三;得五;三十;一六或二三",
+    "solution": "【分析】根据乘法口诀表补充空缺.\n【详解】三三得九;一五得五;五六三十;一六得六或二三得六。",
+    "knowledge_points": [
+      "5 的乘法口诀及应用",
+      "3 的乘法口诀及应用",
+      "6 的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·云南文山·期中"
+  },
+  {
+    "id": "434",
+    "unit": "第四单元 表内乘法",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "在括号里填上\" > \"\" < \"或\" = \".\n\n56 + 12 ( ) 60;85 - 7 ( ) 87 - 5;80 - 23 - 15 ( ) 80 - (23 + 15);3×5 + 5 ( ) 5×5",
+    "options": [],
+    "answer": ">;<;=;<",
+    "solution": "【分析】左右两边有算式的先计算出结果再比较大小;左边加减混合从左到右算出得数，右边有括号先算括号里面的，再算减法得出得数，再比较两个得数大小;用表内乘法口诀求出两边的得数，再比较大小.\n【详解】56 + 12 = 68,68 > 60，故 56 + 12 > 60;85 - 7 = 78,87 - 5 = 82,78 < 82，故 85 - 7 < 87 - 5;80 - 23 - 15 = 57 - 15 = 42;80 - (23 + 15) = 80 - 38 = 42，故 80 - 23 - 15 = 80 - (23 + 15);3×5 + 5 = 15 + 5 = 20;5×5 = 25;20 < 25，故 3×5 + 5 < 5×5。",
+    "knowledge_points": [
+      "100以内数的加减混合运算",
+      "5 的乘法口诀及应用",
+      "带有小括号的混合运算",
+      "表内乘加，乘减"
+    ],
+    "source": "24-25 二年级上·云南文山·期中"
+  },
+  {
+    "id": "435",
+    "unit": "第四单元 表内乘法",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "在括号里填上\" > \"\" < \"或\" = \".\n\n4 米 ( ) 4 厘米;25 + 47 ( ) 35 + 35;5×5 ( ) 84 - 48",
+    "options": [],
+    "answer": ">;>;<",
+    "solution": "【分析】含有算式的比较大小，先按照整数加减法的计算法则或乘法口诀算出结果，再比较大小;含有单位的比较大小，先根据\"1 米 = 100 厘米\"换算统一单位，再比较大小.\n【详解】4 米 = 400 厘米,400 厘米 > 4 厘米，故 4 米 > 4 厘米;25 + 47 = 72,35 + 35 = 70,72 > 70，故 25 + 47 > 35 + 35;5×5 = 25,84 - 48 = 36,25 < 36，故 5×5 < 84 - 48。",
+    "knowledge_points": [
+      "两位数与两位数的进位加法",
+      "两位数与两位数的退位减法",
+      "5 的乘法口诀及应用",
+      "厘米和米之间的进率与换算"
+    ],
+    "source": "24-25 二年级上·河南郑州·期中"
+  },
+  {
+    "id": "436",
+    "unit": "第四单元 表内乘法",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "比 46 多 39 的数是( );( )比 80 少 48;两个乘数都是 4，积是( );比 5 个 3 多 18 的数是( )。",
+    "options": [],
+    "answer": "85;32;16;33",
+    "solution": "【分析】求比一个数多几的数是多少，用加法;求比一个数少几的数是多少，用减法;两个乘数都是 4，即 4×4;5 个 3 即 5×3，再加 18.\n【详解】46 + 39 = 85;80 - 48 = 32;4×4 = 16;5×3 + 18 = 15 + 18 = 33。",
+    "knowledge_points": [
+      "两位数与两位数的进位加法",
+      "两位数与两位数的退位减法",
+      "5 的乘法口诀及应用",
+      "4 的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·河南郑州·期中"
+  },
+  {
+    "id": "437",
+    "unit": "第四单元 表内乘法",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "26 比 49 少( );78 比( )多 23;一个乘数是 4，另一个乘数是 5，积是( )。",
+    "options": [],
+    "answer": "23;55;20",
+    "solution": "【分析】一个数比另一个数少几，用减法;一个数比另一个数多几，求另一个数，用这个数减多的数;乘法用口诀计算.\n【详解】49 - 26 = 23;78 - 23 = 55;4×5 = 20。",
+    "knowledge_points": [
+      "两位数与两位数的不退位减法",
+      "4 的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·湖北孝感·期中"
+  },
+  {
+    "id": "438",
+    "unit": "第四单元 表内乘法",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "根据乘法口诀\"三五十五\"可以写出的乘法算式是( )和( ),计算 6×6 时用到的乘法口诀是( )。",
+    "options": [],
+    "answer": "3×5 = 15;5×3 = 15;六六三十六",
+    "solution": "【分析】乘法算式中两个乘数是口诀中的前两个数，积是口诀中的后一个数，写算式时两个乘数可互换位置.\n【详解】\"三五十五\"可写为 3×5 = 15 和 5×3 = 15;6×6 用\"六六三十六\"。",
+    "knowledge_points": [
+      "5 的乘法口诀及应用",
+      "6 的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·江西九江·期中"
+  },
+  {
+    "id": "439",
+    "unit": "第四单元 表内乘法",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "一根铁丝对折再对折，每段长 3 厘米，这根铁丝原来长( )厘米。",
+    "options": [],
+    "answer": "12",
+    "solution": "【分析】一根铁丝对折再对折后平均分成 4 段，每段 3 厘米，总长为 3×4.\n【详解】3×4 = 12(厘米),这根铁丝原来长 12 厘米。",
+    "knowledge_points": [
+      "4 的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·福建厦门·期中"
+  },
+  {
+    "id": "440",
+    "unit": "第四单元 表内乘法",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "小明和他的 4 个好朋友一起玩拼图，每人完成 3 个拼图，一共完成了( )个拼图。",
+    "options": [],
+    "answer": "15",
+    "solution": "【分析】先算一共人数:1 + 4 = 5(人),再用每人完成数量乘人数.\n【详解】1 + 4 = 5(人),3×5 = 15(个),一共完成 15 个拼图。",
+    "knowledge_points": [
+      "5 的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·福建厦门·期中"
+  },
+  {
+    "id": "441",
+    "unit": "第四单元 表内乘法",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "在括号里填上\" > \"\" < \"或\" = \".\n\n37 + 63 ( ) 100;2×3 ( ) 2 + 3;5×4 ( ) 47 - 18",
+    "options": [],
+    "answer": "=;>;<",
+    "solution": "【分析】先计算，再比较.\n【详解】37 + 63 = 100;2×3 = 6,2 + 3 = 5,6 > 5;5×4 = 20,47 - 18 = 29,20 < 29。",
+    "knowledge_points": [
+      "100以内数的比大小",
+      "两位数与两位数的进位加法",
+      "2 的乘法口诀及应用",
+      "4 的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·福建三明·期中"
+  },
+  {
+    "id": "442",
+    "unit": "第四单元 表内乘法",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "2×4 = 8，读作( ),其中( )和( )是乘数,( )是积。",
+    "options": [],
+    "answer": "2 乘 4 等于 8;2;4;8",
+    "solution": "【分析】读乘法算式从左到右读，\"*\"读作\"乘\"，\"=\"读作\"等于\";乘号两边是乘数，结果是积.\n【详解】2×4 = 8 读作 2 乘 4 等于 8，其中 2 和 4 是乘数,8 是积。",
+    "knowledge_points": [
+      "初步认识乘法意义",
+      "4 的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·福建三明·期中"
+  },
+  {
+    "id": "443",
+    "unit": "第四单元 表内乘法",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "2 个 3 相乘的积是( )。",
+    "options": [],
+    "answer": "9",
+    "solution": "【分析】2 个 3 相乘就是 3×3.\n【详解】3×3 = 9，积是 9。",
+    "knowledge_points": [
+      "3 的乘法口诀及应用"
+    ],
+    "source": "24-25 三年级上·湖南邵阳·期中"
+  },
+  {
+    "id": "444",
+    "unit": "第四单元 表内乘法",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "在括号里填上\" > \"\" < \"或\" = \".\n\n32 - 7 ( ) 35;4 + 46 ( ) 86 - 40;4×5 ( ) 5×3;18 + 18 ( ) 40;1 米 - 20 厘米 ( ) 70 厘米;16 厘米 + 84 厘米 ( ) 1 米",
+    "options": [],
+    "answer": "<;>;>;<;>;=",
+    "solution": "【分析】先算出每个算式的结果或先统一单位，然后比较大小。1 米 = 100 厘米.\n【详解】32 - 7 = 25,25 < 35;4 + 46 = 50,86 - 40 = 46,50 > 46;4×5 = 20,5×3 = 15,20 > 15;18 + 18 = 36,36 < 40;1 米 - 20 厘米 = 80 厘米,80 > 70;16 + 84 = 100 厘米,100 厘米 = 1 米。",
+    "knowledge_points": [
+      "100 以内数的比大小",
+      "两位数与两位数的进位加法",
+      "5 的乘法口诀及应用",
+      "厘米和米之间的进率与换算"
+    ],
+    "source": "24-25 二年级上·河南南阳·期中"
+  },
+  {
+    "id": "445",
+    "unit": "第四单元 表内乘法",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "☆ + ☆ + ☆ + ☆ + ☆ = 30,△ + △ + △ = 12,☆ * △ = ( )",
+    "options": [],
+    "answer": "24",
+    "solution": "【分析】5 个 ☆ 的和是 30，可得 ☆ = 6;3 个 △ 的和是 12，可得 △ = 4;再相乘.\n【详解】☆ = 6,△ = 4,☆ * △ = 6×4 = 24。",
+    "knowledge_points": [
+      "同数连加的应用",
+      "5 的乘法口诀及应用",
+      "3 的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·湖北武汉·期中"
+  },
+  {
+    "id": "446",
+    "unit": "第四单元 表内乘法",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "在括号里填上\" > \"\" < \"或\" = \".\n\n5×6 ( ) 30;3×3 ( ) 3 + 3;1 米 ( ) 10 厘米;35 + 9 ( ) 44;47 ( ) 91 - 47;33 厘米 + 60 厘米 ( ) 1 米",
+    "options": [],
+    "answer": "=;>;>;=;>;<",
+    "solution": "【分析】先计算出结果再比较;长度单位先统一:1 米 = 100 厘米.\n【详解】5×6 = 30;3×3 = 9,3 + 3 = 6,9 > 6;1 米 = 100 厘米,100 > 10;35 + 9 = 44;91 - 47 = 44,47 > 44;33 + 60 = 93 厘米,93 < 100。",
+    "knowledge_points": [
+      "100以内数的比大小",
+      "两位数与两位数的退位减法",
+      "6 的乘法口诀及应用",
+      "厘米和米之间的进率与换算"
+    ],
+    "source": "24-25 二年级上·湖北武汉·期中"
+  },
+  {
+    "id": "447",
+    "unit": "第四单元 表内乘法",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "5 个 6 相加，和是( ),5 和 6 相加，和是( )。",
+    "options": [],
+    "answer": "30;11",
+    "solution": "【分析】5 个 6 的和用乘法 5×6;5 和 6 的和用加法 5 + 6.\n【详解】5×6 = 30,5 + 6 = 11。",
+    "knowledge_points": [
+      "5~2 加几的进位加法",
+      "初步认识乘法意义",
+      "6 的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·湖北武汉·期中"
+  },
+  {
+    "id": "448",
+    "unit": "第四单元 表内乘法",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "乘法算式:3×7 = 21，读作( )乘( )等于( ),其中 3 和 7 是( ),21 是( )。",
+    "options": [],
+    "answer": "3;7;21;乘数;积",
+    "solution": "【分析】读乘法算式从左往右读，\"*\"读作\"乘\"，\"=\"读作\"等于\";乘号两边是乘数，结果是积.\n【详解】3×7 = 21 读作 3 乘 7 等于 21，其中 3 和 7 是乘数,21 是积。",
+    "knowledge_points": [
+      "初步认识乘法意义",
+      "3 的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·河南南阳·期中"
+  },
+  {
+    "id": "449",
+    "unit": "第四单元 表内乘法",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "根据下图写算式.\n\n![](images/92aa431070554d51dc3c1af27c3631b5a71e94b112067fde38b401ddbf21d4f3.jpg)\n\n加法算式:( );乘法算式:( )或( )。",
+    "options": [],
+    "answer": "5 + 5 + 5 = 15(个);5×3 = 15(个);3×5 = 15(个)",
+    "solution": "【分析】一行 5 个,3 行就是 3 个 5 的和.\n【详解】加法:5 + 5 + 5 = 15(个);乘法:5×3 = 15(个)或 3×5 = 15(个)。",
+    "knowledge_points": [
+      "图文问题",
+      "初步认识乘法意义"
+    ],
+    "source": "24-25 二年级上·内蒙古通辽·期中"
+  },
+  {
+    "id": "450",
+    "unit": "第四单元 表内乘法",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "把 5 + 5 + 5 + 5 - 4 改写成乘减算式是( )。",
+    "options": [],
+    "answer": "4×5 - 4或5×4 - 4",
+    "solution": "【分析】4 个 5 相加可写成 4×5 或 5×4，再减 4.\n【详解】可改写为 4×5 - 4 或 5×4 - 4。",
+    "knowledge_points": [
+      "表内乘加，乘减"
+    ],
+    "source": "24-25 二年级上·江西宜春·期中"
+  },
+  {
+    "id": "451",
+    "unit": "第四单元 表内乘法",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "在括号里填上合适的数.\n\n( )×5 = 30;( ) + 21 = 60;( ) - 27 = 45;( )×4 = 16;( ) + 31 = 72;90 - ( ) = 44",
+    "options": [],
+    "answer": "6;39;72;4;41;46",
+    "solution": "【分析】第 1,4 题用乘法口诀;第 2,5 题用\"和 - 一个加数 = 另一个加数\";第 3 题用\"减数 + 差 = 被减数\";第 6 题用\"被减数 - 差 = 减数\".\n【详解】6×5 = 30;60 - 21 = 39;27 + 45 = 72;4×4 = 16;72 - 31 = 41;90 - 44 = 46。",
+    "knowledge_points": [
+      "两位数与两位数的进位加法",
+      "两位数与两位数的退位减法",
+      "4 的乘法口诀及应用",
+      "6 的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·山东济宁·期中"
+  },
+  {
+    "id": "452",
+    "unit": "第四单元 表内乘法",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "商场促销，手套买两双送一双，李阿姨买两双手套，一共可以得到( )只手套。",
+    "options": [],
+    "answer": "6",
+    "solution": "【分析】先将买的双数和送的双数相加算出一共多少双，每双有 2 只，然后用双数乘 2 即可求出一共可以得到多少只手套.\n【详解】2 + 1 = 3(双),3×2 = 6(只),一共可以得到 6 只手套。",
+    "knowledge_points": [
+      "3 的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·河南郑州·期中"
+  },
+  {
+    "id": "453",
+    "unit": "第四单元 表内乘法",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "3×6 = ( ),读作( ),口诀是( )。",
+    "options": [],
+    "answer": "18;3 乘 6 等于 18;三六十八",
+    "solution": "【分析】根据乘法口诀\"三六十八\"得出 3×6 的结果等于 18;读作时，从左往右读，是几就读几，\"*\"读作\"乘\"，\"=\"读作\"等于\".\n【详解】3×6 = 18，读作 3 乘 6 等于 18，口诀是三六十八。",
+    "knowledge_points": [
+      "6 的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·山东济宁·期中"
+  },
+  {
+    "id": "454",
+    "unit": "第四单元 表内乘法",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "两个乘数都是 4，积是( );2 乘 4 的积是( )。",
+    "options": [],
+    "answer": "16;8",
+    "solution": "【分析】乘法算式为：乘数×乘数 = 积，由此代入计算。写乘法算式时，数字是几就写几，\"乘\"写作\"*\".\n【详解】4×4 = 16;2×4 = 8。两个乘数都是 4，积是 16;2 乘 4 的积是 8。",
+    "knowledge_points": [
+      "4 的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·山东济宁·期中"
+  },
+  {
+    "id": "455",
+    "unit": "第四单元 表内乘法",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "2 个 4 相加，和是( );一个乘数是 4，一个乘数是 2，积是( )。",
+    "options": [],
+    "answer": "8;8",
+    "solution": "【分析】几个相同加数相加，可以写成加数与个数相乘的形式。乘法算式中两个乘数是口诀中的前两个数，积是口诀中的后一个数，写算式时两个乘数可互换位置.\n【详解】4 + 4 = 8,4×2 = 8.2 个 4 相加，和是 8;一个乘数是 4，一个乘数是 2，积是 8。",
+    "knowledge_points": [
+      "同数连加的应用",
+      "4 的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·江西九江·期中"
+  },
+  {
+    "id": "456",
+    "unit": "第四单元 表内乘法",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "有一堆黄沙，先运走一半，又运走剩下的一半，这时还剩下 5 吨，这堆黄沙原来有( )吨。",
+    "options": [],
+    "answer": "20",
+    "solution": "【分析】5 吨是这堆黄沙一半的一半，也就是这堆黄沙的四分之一。先求一半的一半:5×2 得到一半;再把两个一半相加得到原来.\n【详解】黄沙的一半:5×2 = 10(吨),原来的黄沙:10 + 10 = 20(吨),这堆黄沙原来有 20 吨。",
+    "knowledge_points": [
+      "倒推问题",
+      "整十数之间的加减法",
+      "5的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·福建三明·期中"
+  },
+  {
+    "id": "457",
+    "unit": "第四单元 表内乘法",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "3 + 3 表示 3 个 2 相加。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】3 + 3 中相同加数是 3，加数的个数是 2 个，也就是表示 2 个 3 相加.\n【详解】3 + 3 表示 2 个 3 相加，原题说法错误。故答案为: ×。",
+    "knowledge_points": [
+      "同数连加的应用",
+      "初步认识乘法意义"
+    ],
+    "source": "24-25 二年级上·山东济南·期中"
+  },
+  {
+    "id": "458",
+    "unit": "第四单元 表内乘法",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "4 个小朋友，每个小朋友分 6 块糖，一共需要 10 块糖。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】求一共需要糖的数量，也就是求 4 个 6 的和是多少，用乘法计算:6×4.\n【详解】6×4 = 24(块),一共需要 24 块糖。原题说法错误。故答案为: ×。",
+    "knowledge_points": [
+      "6的乘法口诀及应用"
+    ],
+    "source": "24-25二年级上·河北保定·期中"
+  },
+  {
+    "id": "459",
+    "unit": "第四单元 表内乘法",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "6 个 4 和 4 个 6 同样多。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】求几个相同加数的和可以用乘法计算，用相同加数×个数或个数×相同加数，由此计算出结果比较即可.\n【详解】6 个 4:4×6 = 24;4 个 6:6×4 = 24;24 = 24。原题说法正确。故答案为:√。",
+    "knowledge_points": [
+      "初步认识乘法意义",
+      "6 的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·山东菏泽·期中"
+  },
+  {
+    "id": "460",
+    "unit": "第四单元 表内乘法",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "3 + 3 + 3 + 3 + 4 可以改写成 3×5 - 1。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】4 个 3 相加再加 4，可以把 4 看成 3 再多 1，那么就是 5 个 3 相加再加 1，所以应改写为 3×5 + 1.\n【详解】3 + 3 + 3 + 3 + 4 可以改写成 3×5 + 1，原题说法错误。故答案为: ×。",
+    "knowledge_points": [
+      "同数连加的应用",
+      "初步认识乘法意义",
+      "表内乘加，乘减"
+    ],
+    "source": "24-25 二年级上·山东济宁·期中"
+  },
+  {
+    "id": "461",
+    "unit": "第四单元 表内乘法",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "只要是加法都可以用乘法表示。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】求几个相同加数的和，可以用乘法计算;加数不同的加法不能用乘法表示。例如 4 + 4 + 4 可用 3×4 或 4×3 表示;3 + 4 + 6 的加数不同，不能用乘法计算.\n【详解】原题说法错误。故答案为: ×。",
+    "knowledge_points": [
+      "同数连加的应用",
+      "初步认识乘法意义"
+    ],
+    "source": "24-25 二年级上·江西九江·期中"
+  },
+  {
+    "id": "462",
+    "unit": "第四单元 表内乘法",
+    "question_type": "计算题",
+    "difficulty": 0.85,
+    "question": "直接写得数.\n18 + 13 = ( );5×2 = ( );17 + 20 = ( );2×6 = ( );62 - 7 = ( );29 + 6 = ( );50 - 16 = ( );5×5 = ( )",
+    "options": [],
+    "answer": "31;10;37;12;55;35;34;25",
+    "solution": "【分析】本题包含两位数加减法以及乘法口诀的应用。计算加减法时要注意进位和退位;乘法直接应用对应的乘法口诀快速得出结果.\n【详解】18 + 13 = 31;5×2 = 10;17 + 20 = 37;2×6 = 12;62 - 7 = 55;29 + 6 = 35;50 - 16 = 34;5×5 = 25。",
+    "knowledge_points": [
+      "两位数与两位数的进位加法",
+      "两位数与两位数的退位减法",
+      "5的乘法口诀及应用",
+      "6的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·山东菏泽·期中"
+  },
+  {
+    "id": "463",
+    "unit": "第四单元 表内乘法",
+    "question_type": "计算题",
+    "difficulty": 0.85,
+    "question": "直接写出得数.\n27 + 30 = ( );5×5 = ( );2×3 = ( );3×4 = ( );4×5 - 12 = ( );65 - 40 = ( );26 - 3 = ( );24 + 6 = ( );4×2 + 25 = ( );8 + 18 - 15 = ( )",
+    "options": [],
+    "answer": "57;25;6;12;8;25;23;30;33;11",
+    "solution": "【分析】本题包含两位数与整十数的加减法，乘法口诀以及乘加，乘减混合运算。计算时，加减法要注意相同数位对齐;乘法直接应用口诀;乘加，乘减要先算乘法，再算加减法;没有括号的加减混合运算按从左到右的顺序计算.\n【详解】27 + 30 = 57;5×5 = 25;2×3 = 6;3×4 = 12;4×5 - 12 = 8;65 - 40 = 25;26 - 3 = 23;24 + 6 = 30;4×2 + 25 = 33;8 + 18 - 15 = 11。",
+    "knowledge_points": [
+      "两位数与整十数的加法",
+      "两位数与整十数的减法",
+      "5的乘法口诀及应用",
+      "表内乘加，乘减"
+    ],
+    "source": "24-25 二年级上·江西宜春·期中"
+  },
+  {
+    "id": "464",
+    "unit": "第四单元 表内乘法",
+    "question_type": "计算题",
+    "difficulty": 0.94,
+    "question": "直接写出得数.\n42 + 8 = ( );72 - 4 = ( );20 + 35 = ( );92 - 60 = ( );2×2 = ( );6×4 = ( );2×4 + 3 = ( );4×4 - 2 = ( );36 厘米 - 9 厘米 = ( )厘米;30 厘米 + 70 厘米 = ( )米",
+    "options": [],
+    "answer": "50;68;55;32;4;24;11;14;27;1",
+    "solution": "【分析】本题包含一位数与两位数的加减法，乘法口诀，乘加乘减以及长度单位的计算。加减法计算时要注意进位和退位;乘法直接应用口诀;乘加乘减要先算乘法再算加减法;长度单位计算时，单位相同的可以直接相加减，并根据 100 厘米 = 1 米进行换算.\n【详解】42 + 8 = 50;72 - 4 = 68;20 + 35 = 55;92 - 60 = 32;2×2 = 4;6×4 = 24;2×4 + 3 = 11;4×4 - 2 = 14;36 厘米 - 9 厘米 = 27 厘米;30 厘米 + 70 厘米 = 100 厘米 = 1 米。",
+    "knowledge_points": [
+      "一位数与两位数的退位减法",
+      "6的乘法口诀及应用",
+      "厘米和米之间的进率与换算",
+      "表内乘加，乘减"
+    ],
+    "source": "24-25 二年级上·云南文山·期中"
+  },
+  {
+    "id": "465",
+    "unit": "第四单元 表内乘法",
+    "question_type": "计算题",
+    "difficulty": 0.85,
+    "question": "直接写出得数.\n4×3 = ( );3×2 = ( );3×3 = ( );50 - 20 = ( );31 - 2 = ( );2×4 = ( );60 - 30 = ( );42 - 3 = ( )",
+    "options": [],
+    "answer": "12;6;9;30;29;8;30;39",
+    "solution": "【分析】本题包含乘法口诀，整十数加减法以及一位数与两位数的退位减法。计算时，乘法直接应用对应的口诀;整十数加减法注意相同数位相加减;退位减法注意个位不够减时向十位借一.\n【详解】4×3 = 12;3×2 = 6;3×3 = 9;50 - 20 = 30;31 - 2 = 29;2×4 = 8;60 - 30 = 30;42 - 3 = 39。",
+    "knowledge_points": [
+      "整十数之间的加减法",
+      "一位数与两位数的退位减法",
+      "3 的乘法口诀及应用",
+      "4 的乘法口诀及应用"
+    ],
+    "source": "24-25二年级上·河南郑州·期中"
+  },
+  {
+    "id": "466",
+    "unit": "第四单元 表内乘法",
+    "question_type": "计算题",
+    "difficulty": 0.85,
+    "question": "直接写得数.\n78 - 40 = ( );35 - 12 = ( );3×4 = ( );3×3 = ( );57 - 48 = ( );41 + 34 = ( );5×3 = ( );1×3 = ( );52 + 8 = ( );48 + 32 = ( );4×2 = ( );5×5 = ( )",
+    "options": [],
+    "answer": "38;23;12;9;9;75;15;3;60;80;8;25",
+    "solution": "【分析】本题包含两位数加减法以及乘法口诀的应用。计算加减法时要注意相同数位对齐，并根据情况判断是否需要进位或退位;乘法直接应用对应的乘法口诀得出结果.\n【详解】78 - 40 = 38;35 - 12 = 23;3×4 = 12;3×3 = 9;57 - 48 = 9;41 + 34 = 75;5×3 = 15;1×3 = 3;52 + 8 = 60;48 + 32 = 80;4×2 = 8;5×5 = 25。",
+    "knowledge_points": [
+      "两位数与两位数的进位加法",
+      "5的乘法口诀及应用",
+      "3 的乘法口诀及应用",
+      "4 的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·山东日照·期中"
+  },
+  {
+    "id": "467",
+    "unit": "第四单元 表内乘法",
+    "question_type": "计算题",
+    "difficulty": 0.85,
+    "question": "直接写得数.\n4×5 = ( );1×5 = ( );3×3 = ( );4×6 = ( );2×6 - 8 = ( );15 - (9 + 6) = ( );2×4 = ( );3×1 = ( );87 - 57 = ( );4×3 + 8 = ( )",
+    "options": [],
+    "answer": "20;5;9;24;4;0;8;3;30;20",
+    "solution": "【分析】本题包含乘法口诀，带有小括号的加减混合运算以及乘加乘减计算。计算时，乘法直接应用口诀;有括号的算式要先算括号里面的;乘加，乘减算式要先算乘法，再算加减法.\n【详解】4×5 = 20;1×5 = 5;3×3 = 9;4×6 = 24;2×6 - 8 = 4;15 - (9 + 6) = 0;2×4 = 8;3×1 = 3;87 - 57 = 30;4×3 + 8 = 20。",
+    "knowledge_points": [
+      "3的乘法口诀及应用",
+      "6的乘法口诀及应用",
+      "带有小括号的混合运算",
+      "表内乘加，乘减"
+    ],
+    "source": "24-25 二年级上·江西九江·期中"
+  },
+  {
+    "id": "468",
+    "unit": "第四单元 表内乘法",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "看图列式.\n![](images/8cca35b9ec8a4fd6b1d06fe36401ba3990192257f6757d5edda27d3db453a9b7.jpg)\n□ ○ □ = □(个)",
+    "options": [],
+    "answer": "5×5 = 25(个)",
+    "solution": "【分析】每组 5 个，这样的有 5 组，用 5 乘 5 即可求出一共有多少个.\n【详解】5×5 = 25(个)。",
+    "knowledge_points": [
+      "图文问题",
+      "5 的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·江西九江·期中"
+  },
+  {
+    "id": "469",
+    "unit": "第四单元 表内乘法",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "看图列式计算.\n![](images/04fa6d24d03b7551eb93095bae6c86ab8a24b5dc88d05dfbb412bb14cb3f5774.jpg)\n□ ○ □ ○ □ = □",
+    "options": [],
+    "answer": "6×3 + 3 = 21",
+    "solution": "【分析】由图可知，一共有 4 串珠子，从左数前 3 串都是 6，后面第 4 串是 3。可以按 3 个 6 相加，再加 1 个 3 这样算:6 + 6 + 6 + 3 = 21;还可以按 4 个 6 相加，再减 1 个 3 这样算:6 + 6 + 6 + 6 - 3 = 21;加数相同的加法可以用乘法表示，用乘法列式:3×6 + 3 = 21 或 4×6 - 3 = 21.\n【详解】6×3 + 3 = 18 + 3 = 21(列式不唯一)。",
+    "knowledge_points": [
+      "图文问题",
+      "表内乘加，乘减"
+    ],
+    "source": "24-25二年级上·河北唐山·期中"
+  },
+  {
+    "id": "470",
+    "unit": "第四单元 表内乘法",
+    "question_type": "计算题",
+    "difficulty": 0.85,
+    "question": "直接写出得数.\n\n41 + 8 = ( );81 - 7 = ( );( )×4 = 12;6×3 = ( );43 + ( ) = 67;43 - ( ) = 29;2×3 + 5 = ( );6×4 - 15 = ( )。",
+    "options": [],
+    "answer": "49;74;3;18;24;14;11;9",
+    "solution": "【分析】本题包含两位数加减法，乘法口诀，乘加乘减以及求括号里的未知数。计算时，加减法要注意进位和退位;乘法直接应用口诀;乘加乘减要先算乘法再算加减法;求括号里的数可以利用加减法各部分之间的关系进行计算.\n【详解】41 + 8 = 49(个位 1 + 8 = 9，十位 4 不变，不进位);81 - 7 = 74(个位 1 减 7 不够，向十位借 1,11 - 7 = 4，十位剩 7，得 74);( )×4 = 12，用口诀\"三四十二\"，括号里填 3;6×3 = 18(口诀\"三六十八\");43 + ( ) = 67,67 - 43 = 24，括号里填 24;43 - ( ) = 29,43 - 29 = 14，括号里填 14;2×3 + 5 = 6 + 5 = 11;6×4 - 15 = 24 - 15 = 9。",
+    "knowledge_points": [
+      "两位数与两位数的不进位加法",
+      "两位数与两位数的退位减法",
+      "6 的乘法口诀及应用",
+      "表内乘加，乘减"
+    ],
+    "source": "24-25 二年级上·福建厦门·期中"
+  },
+  {
+    "id": "471",
+    "unit": "第四单元 表内乘法",
+    "question_type": "计算题",
+    "difficulty": 0.85,
+    "question": "直接写出得数.\n\n48 + 50 = ( );1×1 = ( );39 - 20 = ( );5×5 = ( );4×5 - 8 = ( );3×3 = ( );80 - 7 = ( );28 + 32 = ( );3×2 = ( );3×5 + 9 = ( )。",
+    "options": [],
+    "answer": "98;1;19;25;12;9;73;60;6;24",
+    "solution": "【分析】本题包含两位数加减法，乘法口诀以及乘加混合运算。计算时，加减法要注意进位和退位;乘法直接应用对应的口诀;乘加算式要先算乘法，再算加法.\n【详解】48 + 50 = 98;1×1 = 1;39 - 20 = 19;5×5 = 25;4×5 - 8 = 20 - 8 = 12;3×3 = 9;80 - 7 = 73;28 + 32 = 60;3×2 = 6;3×5 + 9 = 15 + 9 = 24。",
+    "knowledge_points": [
+      "一位数与两位数的进位加法",
+      "5 的乘法口诀及应用",
+      "3 的乘法口诀及应用",
+      "表内乘加，乘减"
+    ],
+    "source": "24-25 二年级上·福建三明·期中"
+  },
+  {
+    "id": "472",
+    "unit": "第四单元 表内乘法",
+    "question_type": "计算题",
+    "difficulty": 0.85,
+    "question": "看图列式计算.\n\n![](images/25cb2f5fc27defd98f0e15881d2819c967b7c3a3d6238f01b3ecad5535d98857.jpg)\n\n□ * □ = □(个)。",
+    "options": [],
+    "answer": "2×5 = 10(个)",
+    "solution": "【分析】由图可知，一共有 5 组 ○,每组有 2 个 ○,求一共有几个 ○,根据乘法的意义，用每组 ○ 的数量×组数即可.\n【详解】2×5 = 10(个),所以一共有 10 个 ○。",
+    "knowledge_points": [
+      "图文问题",
+      "5 的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·河南南阳·期中"
+  },
+  {
+    "id": "473",
+    "unit": "第四单元 表内乘法",
+    "question_type": "计算题",
+    "difficulty": 0.85,
+    "question": "看图列式计算.\n\n![](images/78d2661569e31e53c3c55b396d94df6626284b04e6e9e103ce7c531249b2ac2a.jpg)\n\n□ * □ = □(个)。",
+    "options": [],
+    "answer": "3×3 = 9(个)",
+    "solution": "【分析】由图可知，一共有 3 组 △,每组有 3 个，求一共有几个 △,用每组 △ 的个数×组数即可.\n【详解】3×3 = 9(个),所以一共有 9 个 △。",
+    "knowledge_points": [
+      "图文问题",
+      "3 的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·河南南阳·期中"
+  },
+  {
+    "id": "474",
+    "unit": "第四单元 表内乘法",
+    "question_type": "计算题",
+    "difficulty": 0.85,
+    "question": "直接写得数.\n\n3×6 = ( );15 + 8 = ( );51 - 9 = ( );45 - (14 + 6) = ( );7 + 4 = ( );76 - 52 = ( );45 + 4 = ( );67 - 12 - 9 = ( )。",
+    "options": [],
+    "answer": "18;23;42;25;11;24;49;46",
+    "solution": "【分析】本题包含乘法口诀，一位数与两位数的加减法，带括号的混合运算以及连减运算。计算时，乘法直接应用口诀;加减法要注意进位和退位;有括号的算式要先算括号里面的;连减运算按从左到右的顺序计算.\n【详解】3×6 = 18;15 + 8 = 23;51 - 9 = 42;45 - (14 + 6) = 45 - 20 = 25;7 + 4 = 11;76 - 52 = 24;45 + 4 = 49;67 - 12 - 9 = 55 - 9 = 46。",
+    "knowledge_points": [
+      "两位数与两位数的不退位减法",
+      "一位数与两位数的退位减法",
+      "100以内数的连减运算",
+      "6 的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·湖北武汉·期中"
+  },
+  {
+    "id": "475",
+    "unit": "第四单元 表内乘法",
+    "question_type": "计算题",
+    "difficulty": 0.85,
+    "question": "直接写得数.\n\n1×3 = ( );2×4 = ( );25 + 13 = ( );46 - 21 = ( );2×5 = ( );39 - 18 = ( );1×4 = ( );3×4 = ( );23 + 14 = ( );2×3 = ( )。",
+    "options": [],
+    "answer": "3;8;38;25;10;21;4;12;37;6",
+    "solution": "【分析】本题包含乘法口诀以及两位数加减法(不进位，不退位)。计算时，乘法直接应用对应的口诀;加减法注意相同数位对齐.\n【详解】1×3 = 3;2×4 = 8;25 + 13 = 38;46 - 21 = 25;2×5 = 10;39 - 18 = 21;1×4 = 4;3×4 = 12;23 + 14 = 37;2×3 = 6。",
+    "knowledge_points": [
+      "两位数与两位数的不进位加法",
+      "两位数与两位数的不退位减法",
+      "3 的乘法口诀及应用",
+      "4 的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·山东济南·期中"
+  },
+  {
+    "id": "476",
+    "unit": "第四单元 表内乘法",
+    "question_type": "计算题",
+    "difficulty": 0.85,
+    "question": "看图列式.\n\n![](images/f4006a9d4318eba5674100abe86e318b3e4c1e14cca36cea8d529e3959e373df.jpg)\n\n( )×( ) = ( )(个)",
+    "options": [],
+    "answer": "3×2 = 6(个)",
+    "solution": "【分析】一行有 3 个 ○,有 2 行，求一共有多少个 ○,用每行个数×行数或行数×每行个数.\n【详解】3×2 = 6(个)。",
+    "knowledge_points": [
+      "3 的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·山东济南·期中"
+  },
+  {
+    "id": "477",
+    "unit": "第四单元 表内乘法",
+    "question_type": "计算题",
+    "difficulty": 0.85,
+    "question": "看谁算得又对又快.\n\n3×5 = ( );17 - 5 = ( );82 - 40 = ( );3×3 = ( );3×2 = ( );5×4 = ( );1×3 = ( );3×4 = ( )。",
+    "options": [],
+    "answer": "15;12;42;9;6;20;3;12",
+    "solution": "【分析】本题包含乘法口诀,20 以内不退位减法以及两位数与整十数的减法.\n【详解】3×5 = 15;17 - 5 = 12;82 - 40 = 42;3×3 = 9;3×2 = 6;5×4 = 20;1×3 = 3;3×4 = 12。",
+    "knowledge_points": [
+      "不退位减法(20以内)",
+      "两位数与整十数的减法",
+      "5 的乘法口诀及应用",
+      "4 的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·河北沧州·期中"
+  },
+  {
+    "id": "478",
+    "unit": "第四单元 表内乘法",
+    "question_type": "计算题",
+    "difficulty": 0.85,
+    "question": "看图列式计算.\n\n![](images/cbd5bd9e8f1602d2366b9b838151806ff63b721723fd3a43a861416a9fe0ade3.jpg)",
+    "options": [],
+    "answer": "3×4 = 12(颗)",
+    "solution": "【分析】一行有 4 颗白菜，有 3 行，求一共有多少颗，用行数×每行数量.\n【详解】3×4 = 12(颗)。",
+    "knowledge_points": [
+      "4 的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·山东菏泽·期中"
+  },
+  {
+    "id": "479",
+    "unit": "第四单元 表内乘法",
+    "question_type": "计算题",
+    "difficulty": 0.85,
+    "question": "一共有几个桃子。\n\n![](images/c67782fd5a3b02d0c9c69a1d3398a065e2ba7c54c815e6a7e0a76396b6a14eca.jpg)",
+    "options": [],
+    "answer": "3×4 + 3 = 15(个)",
+    "solution": "【分析】一组有 4 个桃子，有 3 组还多 3 个，用组数×每组个数 + 多出的数量.\n【详解】3×4 + 3 = 12 + 3 = 15(个),一共有 15 个桃子。",
+    "knowledge_points": [
+      "表内乘加，乘减"
+    ],
+    "source": "24-25 二年级上·江西九江·期中"
+  },
+  {
+    "id": "480",
+    "unit": "第四单元 表内乘法",
+    "question_type": "计算题",
+    "difficulty": 0.85,
+    "question": "直接写得数.\n\n7 + 58 = ( );12 + 40 = ( );56 - 40 = ( );83 - 30 = ( );69 - 20 = ( );77 - 9 = ( );9 + 82 = ( );45 + 13 = ( );3×4 = ( );4×4 = ( )。",
+    "options": [],
+    "answer": "65;52;16;53;49;68;91;58;12;16",
+    "solution": "【分析】本题包含一位数与两位数的加减法，两位数与两位数的加减法以及乘法口诀。计算加减法时要注意相同数位对齐，并判断是否需要进位或退位;乘法直接应用口诀.\n【详解】7 + 58 = 65;12 + 40 = 52;56 - 40 = 16;83 - 30 = 53;69 - 20 = 49;77 - 9 = 68;9 + 82 = 91;45 + 13 = 58;3×4 = 12;4×4 = 16。",
+    "knowledge_points": [
+      "两位数与两位数的不进位加法",
+      "一位数与两位数的进位加法",
+      "一位数与两位数的退位减法",
+      "4 的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·山东临沂·期中"
+  },
+  {
+    "id": "481",
+    "unit": "第四单元 表内乘法",
+    "question_type": "解答题",
+    "difficulty": 0.65,
+    "question": "购物.\n\n![](images/2026-02-25%20234906.jpg)\n\n(1)买 5 个苹果需要多少元。\n\n□ ○ □ = □( )\n\n(2)买 4 杯咖啡需要多少元。\n\n□ ○ □ = □( )",
+    "options": [],
+    "answer": "5×3 = 15(元);4×5 = 20(元)",
+    "solution": "【分析】(1)1 个苹果 3 元,5 个苹果是 5 个 3 的和，用乘法 5×3;(2)1 杯咖啡 5 元,4 杯咖啡是 4 个 5 的和，用乘法 4×5.\n【详解】(1)5×3 = 15(元),答：买 5 个苹果需要 15 元。(2)4×5 = 20(元),答：买 4 杯咖啡需要 20 元。",
+    "knowledge_points": [
+      "初步认识乘法意义",
+      "5 的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·广东揭阳·期中"
+  },
+  {
+    "id": "482",
+    "unit": "第四单元 表内乘法",
+    "question_type": "解答题",
+    "difficulty": 0.85,
+    "question": "星期天课外活动小组的 6 名同学去浇树，每人浇了 5 棵树，还剩 3 棵没人浇，一共有多少棵树。",
+    "options": [],
+    "answer": "33 棵",
+    "solution": "【分析】先求 6 名同学共浇了多少棵：每人 5 棵，用 5×6;再加上还剩的 3 棵.\n【详解】5×6 + 3 = 30 + 3 = 33(棵),答：一共有 33 棵树。",
+    "knowledge_points": [
+      "表内乘加，乘减"
+    ],
+    "source": "24-25 二年级上·山东济宁·期中"
+  },
+  {
+    "id": "483",
+    "unit": "第四单元 表内乘法",
+    "question_type": "解答题",
+    "difficulty": 0.85,
+    "question": "同学们植树.\n\n(1)第一组种了 4 行，每行 5 棵，第一组种了多少棵树。\n(2)第二组种了 2 行，一行 4 棵，一行 5 棵，第二组种了多少棵。",
+    "options": [],
+    "answer": "20;9",
+    "solution": "【分析】(1)4 行每行 5 棵，是 4 个 5 的和，用 5×4;(2)两行棵数不同，用 4 + 5.\n【详解】(1)5×4 = 20(棵),答：第一组种了 20 棵树。(2)4 + 5 = 9(棵),答：第二组种了 9 棵。",
+    "knowledge_points": [
+      "8,9 的加减法",
+      "5 的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·山东济南·期中"
+  },
+  {
+    "id": "484",
+    "unit": "第四单元 表内乘法",
+    "question_type": "解答题",
+    "difficulty": 0.65,
+    "question": "小飞和 4 名同学一起去游乐园坐旋转木马，旋转木马收费是每人 5 元，他们一共花了多少元。",
+    "options": [],
+    "answer": "25 元",
+    "solution": "【分析】先求人数:4 + 1 = 5(人),再乘每人 5 元.\n【详解】4 + 1 = 5(人),5×5 = 25(元),答：他们一共花了 25 元。",
+    "knowledge_points": [
+      "5 的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·山东日照·期中"
+  },
+  {
+    "id": "485",
+    "unit": "第四单元 表内乘法",
+    "question_type": "解答题",
+    "difficulty": 0.85,
+    "question": "一辆玩具车需要 4 节电池,4 辆这样的玩具车一共需要多少节电池。",
+    "options": [],
+    "answer": "16 节",
+    "solution": "【分析】用每辆需要的电池数乘玩具车辆数.\n【详解】4×4 = 16(节),答：一共需要 16 节电池。",
+    "knowledge_points": [
+      "4 的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·江西九江·期中"
+  },
+  {
+    "id": "486",
+    "unit": "第四单元 表内乘法",
+    "question_type": "解答题",
+    "difficulty": 0.65,
+    "question": "购物.\n\n![](images/2026-02-25%20235442.jpg)\n\n(1)买一支铅笔，一个放大镜和一本笔记本，一共需要多少元。\n(2)买 5 副尺和 1 支铅笔,20 元够吗。\n(3)你能提出一个数学问题并解决吗。",
+    "options": [],
+    "answer": "36;不够;买一个放大镜和一本笔记本一共需要多少钱。15 + 19 = 34(元)",
+    "solution": "【分析】(1)总价用加法;(2)先算 5 副尺的钱数，再加铅笔钱，与 20 比较;(3)提出问题合理即可.\n【详解】(1)2 + 15 + 19 = 36(元),答：一共需要 36 元。(2)4×5 + 2 = 20 + 2 = 22(元),22 > 20，答:20 元不够。(3)例如：买一个放大镜和一本笔记本一共需要多少钱。15 + 19 = 34(元),答：一共 34 元。",
+    "knowledge_points": [
+      "\"提问题\"\"填条件\"问题",
+      "100 以内数的比大小",
+      "100以内数的连加运算",
+      "表内乘加，乘减"
+    ],
+    "source": "24-25 二年级上·湖北省直辖县级单位·期中"
+  },
+  {
+    "id": "487",
+    "unit": "第四单元 表内乘法",
+    "question_type": "解答题",
+    "difficulty": 0.85,
+    "question": "林叔叔要用一些花盆摆一个正方形的花圃，每行，每列各摆 5 盆。已经运来了 20 盆，还要再运来多少盆。",
+    "options": [],
+    "answer": "5 盆",
+    "solution": "【分析】正方形花圃每行每列各 5 盆，共 5×5 盆，再减去已运来的 20 盆.\n【详解】5×5 - 20 = 25 - 20 = 5(盆),答：还要再运来 5 盆。",
+    "knowledge_points": [
+      "表内乘加，乘减"
+    ],
+    "source": "24-25 二年级上·福建福州·期中"
+  },
+  {
+    "id": "488",
+    "unit": "第四单元 表内乘法",
+    "question_type": "解答题",
+    "difficulty": 0.65,
+    "question": "超市里的酸奶有一板 3 杯的，也有一板 5 杯的，小明买 3 板 3 杯的和一板 5 杯的，一共有多少杯酸奶。",
+    "options": [],
+    "answer": "14 杯",
+    "solution": "【分析】先算 3 板 3 杯共有多少杯:3×3，再加上 5 杯.\n【详解】3×3 + 5 = 9 + 5 = 14(杯),答：一共有 14 杯酸奶。",
+    "knowledge_points": [
+      "表内乘加，乘减"
+    ],
+    "source": "24-25 二年级上·湖北武汉·期中"
+  },
+  {
+    "id": "489",
+    "unit": "第四单元 表内乘法",
+    "question_type": "解答题",
+    "difficulty": 0.85,
+    "question": "一个星期有 7 天，小军前 5 天每天做两道\"思考题\"，这个星期小军已经做了多少道\"思考题\"。",
+    "options": [],
+    "answer": "10 道",
+    "solution": "【分析】前 5 天每天 2 道，是 5 个 2 的和，用乘法.\n【详解】2×5 = 10(道),答：已经做了 10 道\"思考题\"。",
+    "knowledge_points": [
+      "5 的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·河南南阳·期中"
+  },
+  {
+    "id": "490",
+    "unit": "第四单元 表内乘法",
+    "question_type": "解答题",
+    "difficulty": 0.65,
+    "question": "李老师要买 2 盒点心和 1 瓶果汁，每盒点心 5 元，每瓶果汁 8 元，李老师带 20 元钱够吗。",
+    "options": [],
+    "answer": "够",
+    "solution": "【分析】先算 2 盒点心的钱:2×5，再加果汁 8 元，与 20 比较.\n【详解】2×5 + 8 = 10 + 8 = 18(元),18 < 20，答：带 20 元钱够。",
+    "knowledge_points": [
+      "表内乘加，乘减"
+    ],
+    "source": "24-25 二年级上·江西宜春·期中"
+  },
+  {
+    "id": "491",
+    "unit": "第四单元 表内乘法",
+    "question_type": "解答题",
+    "difficulty": 0.65,
+    "question": "果园里有梨树 3 行，每行 5 棵;杏树有 12 棵。果园里的梨树和杏树一共有多少棵。",
+    "options": [],
+    "answer": "27",
+    "solution": "【分析】梨树 3 行每行 5 棵，用 3×5 求梨树棵数，再加 12 棵杏树.\n【详解】3×5 + 12 = 15 + 12 = 27(棵),答：一共有 27 棵。",
+    "knowledge_points": [
+      "初步认识乘法意义",
+      "乘加，乘减混合运算"
+    ],
+    "source": "24-25 二年级上·江西宜春·期中"
+  },
+  {
+    "id": "492",
+    "unit": "第四单元 表内乘法",
+    "question_type": "解答题",
+    "difficulty": 0.85,
+    "question": "每袋面包有 5 片，李阿姨买来 4 袋这样的面包，一共有多少片。",
+    "options": [],
+    "answer": "20 片",
+    "solution": "【分析】4 袋每袋 5 片，是 4 个 5 的和，用乘法.\n【详解】5×4 = 20(片),答：一共有 20 片。",
+    "knowledge_points": [
+      "5 的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·江西宜春·期中"
+  },
+  {
+    "id": "493",
+    "unit": "第四单元 表内乘法",
+    "question_type": "解答题",
+    "difficulty": 0.85,
+    "question": "安装一辆自行车需要 2 个车轮，安装 4 辆自行车 10 个车轮够吗。",
+    "options": [],
+    "answer": "够",
+    "solution": "【分析】4 辆车需要的轮子数是 4 个 2，用乘法 2×4 求出后与 10 比较.\n【详解】2×4 = 8(个),8 < 10，答:10 个车轮够。",
+    "knowledge_points": [
+      "4 的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·山东济南·期中"
+  },
+  {
+    "id": "494",
+    "unit": "第四单元 表内乘法",
+    "question_type": "解答题",
+    "difficulty": 0.65,
+    "question": "李老师要带领同学们去参加活动，每辆车坐满可以坐 5 人(司机除外).\n\n(1)坐满 3 辆车可以坐多少人(司机除外)。\n(2)一共有 21 人去参加活动,4 辆车够坐吗。",
+    "options": [],
+    "answer": "15;不够",
+    "solution": "【分析】(1)3 辆车坐满的人数是 3 个 5，用 5×3;(2)4 辆车坐满人数为 5×4，与 21 比较.\n【详解】(1)5×3 = 15(人),答：坐满 3 辆车可以坐 15 人。(2)5×4 = 20(人),20 < 21，答:4 辆车不够坐。",
+    "knowledge_points": [
+      "100以内数的比大小",
+      "5 的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·河北沧州·期中"
+  },
+  {
+    "id": "495",
+    "unit": "第四单元 表内乘法",
+    "question_type": "解答题",
+    "difficulty": 0.65,
+    "question": "为招待春节期间的客人，妈妈买了两盒不同的饼干，一盒有 36 块，另一盒有 48 块。还买了 4 盒巧克力，每盒有 4 颗.\n\n(1)妈妈买了多少块饼干。\n(2)妈妈买了多少颗巧克力。",
+    "options": [],
+    "answer": "84;16",
+    "solution": "【分析】(1)两盒饼干块数相加;(2)4 盒每盒 4 颗，是 4×4.\n【详解】(1)36 + 48 = 84(块),答：买了 84 块饼干。(2)4×4 = 16(颗),答：买了 16 颗巧克力。",
+    "knowledge_points": [
+      "两位数与两位数的进位加法",
+      "4 的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·河南郑州·期中"
+  },
+  {
+    "id": "496",
+    "unit": "第四单元 表内乘法",
+    "question_type": "解答题",
+    "difficulty": 0.85,
+    "question": "乘坐轿车.\n\n(1)每辆轿车可以坐 5 人,3 辆这样的轿车一共可以坐多少人。\n\n![](images/0636722e11e9b25d2c63b63bdb7fe46af19be25a718807590c2ed5dfb943b3d8.jpg)\n\n(2)有两辆轿车，一辆坐了 5 人，另一辆坐了 3 人，一共坐了多少人。",
+    "options": [],
+    "answer": "15;8",
+    "solution": "【分析】(1)3 辆车每辆 5 人，是 3 个 5，用 5×3;(2)用加法 5 + 3.\n【详解】(1)5×3 = 15(人),答：一共可以坐 15 人。(2)5 + 3 = 8(人),答：一共坐了 8 人。",
+    "knowledge_points": [
+      "8,9 的加减法",
+      "5 的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·山东济宁·期中"
+  },
+  {
+    "id": "497",
+    "unit": "第四单元 表内乘法",
+    "question_type": "解答题",
+    "difficulty": 0.85,
+    "question": "玩具店里玩具小汽车有 4 个轮子,3 辆小汽车共有多少个轮子。",
+    "options": [],
+    "answer": "12 个",
+    "solution": "【分析】3 辆车轮子总数是 3 个 4 的和，用乘法.\n【详解】4×3 = 12(个),答：共有 12 个轮子。",
+    "knowledge_points": [
+      "4 的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·山东临沂·期中"
+  },
+  {
+    "id": "498",
+    "unit": "第四单元 表内乘法",
+    "question_type": "解答题",
+    "difficulty": 0.65,
+    "question": "二年级有 4 个班，每班选 3 名男生和 2 名女生参加跳绳比赛，参加跳绳比赛的一共有多少人。",
+    "options": [],
+    "answer": "20 人",
+    "solution": "【分析】先求每班参加人数:3 + 2 = 5(名),再乘班级数 4.\n【详解】3 + 2 = 5(名),5×4 = 20(人),答：一共有 20 人参加。",
+    "knowledge_points": [
+      "4 的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·湖南怀化·期中"
+  },
+  {
+    "id": "499",
+    "unit": "第四单元 表内乘法",
+    "question_type": "解答题",
+    "difficulty": 0.85,
+    "question": "\"学习强国\"里面有一个项目是\"观看视频\"，每天看视频可得 6 分，爸爸连续 6 天观看视频，一共得了多少分。",
+    "options": [],
+    "answer": "36 分",
+    "solution": "【分析】连续 6 天每天 6 分，是 6 个 6 的和，用乘法.\n【详解】6×6 = 36(分),答：一共得了 36 分。",
+    "knowledge_points": [
+      "6 的乘法口诀及应用"
+    ],
+    "source": "24-25 二年级上·湖南怀化·期中"
+  },
+  {
+    "id": "500",
+    "unit": "第四单元 表内乘法",
+    "question_type": "解答题",
+    "difficulty": 0.65,
+    "question": "小丽和她的 3 个朋友一起去划船，每张船票 4 元，她们一共要花多少元。",
+    "options": [],
+    "answer": "16 元",
+    "solution": "【分析】根据乘法的意义，用总人数乘每张船票的价钱即可。注意人数要把小丽算进去:3 + 1 = 4(人).\n【详解】(3 + 1)×4 = 4×4 = 16(元),答：一共要花 16 元。",
+    "knowledge_points": [
+      "乘加，乘减混合运算",
+      "带有小括号的混合运算"
+    ],
+    "source": "2024 二年级上·全国·专题练习"
+  }
+]
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+[
+    {
+        "id":  "1",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "下面是三(1)班某些同学数学期中考试成绩:98758991877795928689958188918975991007994 其中成绩高于 90 分的有( )人。",
+        "options":  [
+                        "A. 4",
+                        "B. 7",
+                        "C. 9"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】比较大小,数出比90大的数的个数即可.\n\n【详解】如图![](images/bb3a68a1a1cf34af1bd91e2bf446dbd661a36f4440f49be3a53f4f9c7561a444.jpg)所以其中成绩高于90分的有9人。故答案为:C",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "25-26 三年级上·河南周口·阶段练习"
+    },
+    {
+        "id":  "2",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "下面是三(3)班男同学的身高调查结果记录。(单位:厘米)110112100120121112114120100121112115112120121110105109113118 如果身高在 112~120 厘米为标准身高,那么身高达到标准的有( )人。",
+        "options":  [
+                        "A. 10",
+                        "B. 11",
+                        "C. 12"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】数出上述数据中处于112-120(包括112和120)范围的数量,即可解答.\n\n【详解】根据分析可知:如果身高在 112~120厘米为标准身高,那么身高达到标准的有 11 人。故答案为:B",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "25-26 三年级上·河南周口·阶段练习"
+    },
+    {
+        "id":  "3",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "\"捐一份书香,留一份真情.\"二(1)班同学想要解决\u0027给希望小学捐赠哪类书籍\u0027的问题,他们要收集的信息是希望小学的同学们( )。",
+        "options":  [
+                        "A. 每周看几本书",
+                        "B. 看书用的时间",
+                        "C. 爱看的书目"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】要解决\u0027给希望小学捐赠哪类书籍\u0027的问题,关键是知道同学们要看的书目,这样才能有针对性地购买书籍。而\u0027每周看几本书\u0027\u0027看书用的时间\u0027与购买书籍这目的关联不大,据此解答即可.\n\n【详解】由分析可知:想要解决\u0027给希望小学捐赠哪类书籍\u0027的问题,他们要收集的信息是希望小学的同学们爱看的书目。故答案为:C",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "24-25 二年级下·湖北武汉·期末"
+    },
+    {
+        "id":  "4",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "想知道 301 班同学最喜欢吃什么水果,需要先( )。",
+        "options":  [
+                        "A. 分析数据",
+                        "B. 整理数据",
+                        "C. 收集数据"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】明确数据处理的步骤:数据处理的常规流程为:收集数据→整理数据→分析数据。因此,若想得到最终结果,必须先收集原始数据.\n\n【详解】要了解301班同学最喜欢吃的水果,需要按照数据处理的基本流程进行,即先收集数据,再整理和分析。故答案为:C",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "24-25 三年级下·浙江杭州·期末"
+    },
+    {
+        "id":  "5",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "二(1)班同学想帮助学校图书室解决\u0027买什么书\u0027的问题,他们最需要收集的信息是同学们( )。",
+        "options":  [
+                        "A. 看书的数量",
+                        "B. 看书的时长",
+                        "C. 喜欢看的书的种类"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】本题需要根据解决\u0027买什么书\u0027的问题来判断需要收集的信息,关键在于明确要购买的书应符合同学们的喜好,所以要收集与同学们喜好相关的信息。逐项分析各个选项,找出正确答案即可.\n\n【详解】A。同学们看书的数量,只能知道同学们看书的多少情况,不能明确同学们具体喜欢哪些种类的书,因此不能依据这个信息来决定学校图书室购买什么书,不符合要求。B。同学们看书的时长,只能反映出同学们花费在看书上的时间多少,不能体现出同学们对不同种类书籍的喜好,也就无法根据这个信息来确定学校图书室应该买什么书,不符合题意。C。同学们喜欢看的书的种类,直接体现了同学们的阅读喜好。学校图书室购买同学们喜欢的书的种类,能够满足同学们的阅读需求,所以要解决\u0027买什么书\u0027的问题,最需要收集的信息就是同学们喜欢看的书的种类,符合要求。故答案为:C",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "24-25 二年级下·山西长治·期中"
+    },
+    {
+        "id":  "6",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "二(1)班投票选班长,得票最多的是( )。",
+        "options":  [
+                        "A. 王明(正正)",
+                        "B. 李丽(正正正)",
+                        "C. 张强(正正正一)"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】用\u0027正\u0027字统计票数时,\u0027正\u0027字的每一笔代表1票,一个\u0027正\u0027字代表5票,由此计算出每人得到的票数,比较大小即可.\n\n【详解】A。5×2=10(票);B。5×3=15(票);C。5×3=15(票),15+1=16(票);16\u003e15\u003e10,则得票最多的是张强。故答案为:C",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "20以内数的比大小"
+                             ],
+        "source":  "24-25二年级下·湖北孝感·期中"
+    },
+    {
+        "id":  "7",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "学校要举办演讲比赛,二(1)班两位候选人的班级评选情况是:静静 18 票,可可 23 票。如果当天有缺勤人员,缺勤( )人一定不会影响评选结果。",
+        "options":  [
+                        "A. 3",
+                        "B. 5",
+                        "C. 6"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】根据题意,选项中缺勤的人全部给静静投票,若可可仍然领先时,结果不会改变;若平票或静静票数大于可可的票数,会影响评选结果,逐项分析各个选项,找出正确答案即可.\n\n【详解】A。缺勤3人时,若这3人全部给静静投票,静静最多得18+3=21(票),可可23票,结果不变。此选项正确。B。缺勤5人时,若这5人全部给静静投票,静静最多得18+5=23(票),与可可平票,可能影响结果。此选项错误。C。缺勤6人时,若这6人全部给静静投票,静静最多得18+6=24(票),超过可可,结果改变。此选项错误。综上,缺勤3人时,评选结果一定不会改变。故答案为:A",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "24-25二年级下·福建莆田·期中"
+    },
+    {
+        "id":  "8",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "下边是小明记录的一个月的天气情况,下面说法正确的是( )。![](images/164553.png)",
+        "options":  [
+                        "A. 阴天天数最多",
+                        "B. 晴天比阴天少3天",
+                        "C. 这个月有31天",
+                        "D. 这个月有30天"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】一个\u0027正\u0027字是5笔,分别数出每种天气的天数,去判断各选项的结论是否正确.\n\n【详解】晴天有15天,阴天有12天,下雪天有4天。A。15\u003e12\u003e4,晴天天数最多,\u0027阴天天数最多\u0027的说法错误;B。15-12=3(天),晴天比阴天多3天,\u0027晴天比阴天少3天\u0027的说法错误;C。15+12+4=31(天),\u0027这个月有31天\u0027的说法正确;D。15+12+4=31(天),\u0027这个月有30天\u0027的说法错误。故答案为:C",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "24-25二年级下·福建龙岩·期中"
+    },
+    {
+        "id":  "9",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "小明为班会买水果,想知道本班大多数同学最喜欢吃什么水果,他收集数据合理的方法是( )。",
+        "options":  [
+                        "A. 请本班的每一位同学告诉自己最喜欢吃的一种水果",
+                        "B. 调查本年级另一个班同学最喜欢吃的水果",
+                        "C. 调查学校门口的超市什么水果最畅销"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】要想知道本班大多数同学最喜欢吃什么水果,则需要收集本班每位同学最喜欢吃的一种水果的数据,不能调查本年级另一个班同学最喜欢吃的水果的情况,也不能调查学校门口的超市什么水果最畅销,据此选答案.\n\n【详解】A。请本班的每一位同学告诉自己最喜欢的一种水果,收集这个数据可以更好地了解本班大部分同学最喜欢吃什么水果,符合题意;B。调查本年级另一个班同学最喜欢吃的水果,收集这个数据可以知道另一个班同学最喜欢吃的水果情况,与本班大多数同学最喜欢吃什么水果没有联系,不符合题意;C。调查学校门口的超市什么水果最畅销,收集这个数据可以知道超市哪种水果最畅销,与本班大多数同学最喜欢吃什么水果没有联系,不符合题意。故答案为:A",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "24-25二年级下·湖北随州·期末"
+    },
+    {
+        "id":  "10",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "三年级同学想帮助学校食堂解决午饭浪费的问题,你认为他们最需要收集的信息是( )。",
+        "options":  [
+                        "A. 调查同学们午餐喜欢吃的食物",
+                        "B. 调查同学们吃午餐的地点",
+                        "C. 调查同学们吃午餐用的时间"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】要解决学校食堂午餐浪费粮食的问题,关键是了解与食物本身和同学们饮食习惯相关的信息.\n\n【详解】A。了解同学们喜欢吃的食物很重要,如果食堂提供的都是同学们不喜欢的食物,可能会导致更多的浪费。B。调查同学们吃午餐的地点与午餐浪费粮食的问题关联不大,无论在何处用餐,都不直接影响是否浪费粮食。C。同学们吃午餐用的时间长短通常也不是导致浪费粮食的主要因素。所以,最需要收集的信息是A选项,调查同学们喜欢吃的食物,这样有助于食堂调整菜品,减少浪费。故答案为:A",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "24-25 四年级下·内蒙古通辽·期末"
+    },
+    {
+        "id":  "11",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "选择题",
+        "difficulty":  0.94,
+        "question":  "用\u0027正\u0027字统计成绩,\u0027正\u0027字代表( )人。",
+        "options":  [
+                        "A. 5",
+                        "B. 4",
+                        "C. 3"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】\u0027正\u0027字有5笔,因此用\u0027正\u0027字统计人数的时候,一个\u0027正\u0027字代表5人.\n\n【详解】由分析可知:用\u0027正\u0027字统计成绩,\u0027正\u0027字代表(5)人。故答案为:A",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "24-25 二年级下·山东济宁·期末"
+    },
+    {
+        "id":  "12",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "\u0027双减\u0027政策落实后,学校想统计学生们每天的睡眠时间,你认为应该收集的信息是( )。",
+        "options":  [
+                        "A. 同学们每天睡眠的环境",
+                        "B. 同学们每天睡眠的总时间",
+                        "C. 同学们每天交通往返的总时间"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】题目要求统计学生每天的睡眠时间,应直接收集与睡眠时间相关的数据,由此解答.\n\n【详解】A。睡眠环境,属于影响因素而非时间本身,不符合题意;B。\u0027睡眠的总时间\u0027直接对应目标数据,符合题意;C。是交通时间,与睡眠时间无关,不符合题意。则应该收集的信息是同学们每天睡眠的总时间。故答案为:B",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "24-25 二年级下·内蒙古赤峰·期中"
+    },
+    {
+        "id":  "13",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "下面是某班男生的立定跳远成绩。(单位:厘米)142132128154152157155145129146131159136148 根据结果完成下面各题.\n(1)该班的男同学一共有( )人.\n(2)成绩超过140厘米的男同学一共有( )人.\n(3)这次立定跳远的最好成绩是( )厘米,最差成绩是( )厘米。",
+        "options":  [
+
+                    ],
+        "answer":  "14;9;159;128",
+        "solution":  "【分析】(1)由题意得,一共有14个立定跳远成绩,所以该班的男同学一共有14人。(2)由题意得,成绩超过140厘米的有:142,154,152,157,155,145,146,159,148,一共有9人。(3)由题意得,求这次立定跳远的最好成绩是多少厘米,最差成绩是多少厘米,直接比较所有人的立定跳远成绩的大小即可.\n\n【详解】(1)该班的男同学一共有14人。(2)成绩超过140厘米的男同学一共有9人。(3)159\u003e157\u003e155\u003e154\u003e152\u003e148\u003e146\u003e145\u003e142\u003e136\u003e132\u003e131\u003e129\u003e128,这次立定跳远的最好成绩是159厘米,最差成绩是128厘米。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "25-26 三年级上·河南周口·阶段练习"
+    },
+    {
+        "id":  "14",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "填空题",
+        "difficulty":  0.94,
+        "question":  "下面是同同调查的本班同学掉牙的情况。![](images/164819.png)\n(1)全班一共有( )人.\n(2)掉( )颗牙的人数最少.\n(3)掉( )颗牙的人数和掉( )颗牙的人数相等。",
+        "options":  [
+
+                    ],
+        "answer":  "45;0;2;3",
+        "solution":  "【分析】(1)将4种掉牙情况的人数相加即可得知全班总人数;(2)将4种掉牙情况的人数进行大小对比即可解答;(3)将4种掉牙情况的人数进行大小对比,发现掉2颗牙和掉3颗牙的人数都是10人,据此解答.\n\n【详解】(1)7+18+10+10=25+10+10=35+10=45(人),所以全班一共有45人。(2)18\u003e10=10\u003e7,所以掉0颗牙的人数最少。(3)10=10,所以掉2颗牙的人数和掉3颗牙的人数相等。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "单式统计表的特点及填补"
+                             ],
+        "source":  "25-26 三年级上·河南周口·阶段练习"
+    },
+    {
+        "id":  "15",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "下面是二(1)班学生喜欢图书的人数统计情况。连环画:○○○○○○○○○○○○○○○ 故事书:△△△△△△△△△△△△△ 科技书:√√√√√√√ 其他:正\n(1)喜欢看( )的人最多,喜欢看( )的人最少.\n(2)喜欢看科技书的人比喜欢看故事书的少( )人,喜欢看连环画的人比喜欢看科技书的多( )人.\n(3)二(1)班共有( )人。",
+        "options":  [
+
+                    ],
+        "answer":  "故事书;其他;10;8;44",
+        "solution":  "【分析】由题意可知:(1)前三种图书:一个图形代表1人;分别数一数喜欢各图书的人数,并记录下来;其他:\u0027正\u0027字统计法说明:1画代表1人,一个\u0027正\u0027字5画,代表5人,数一数,记录下来。把统计的喜欢各图书的人数,按照从大到小的顺序排列,即可知喜欢看什么图书的人最多,喜欢看什么图书的人最少。(2)用喜欢看故事书的人数减去喜欢看科技书的人数,即是喜欢看科技书的人比喜欢看故事书少的人数;用喜欢看连环画的人减去喜欢看科技书的人数,即是喜欢看连环画的人比喜欢看科技书的多的人数。(3)把统计的喜欢各种图书的人数相加,即是二(1)班共有的人数。据此解答.\n\n【详解】(1)由分析可得:连环画:15人,故事书:17人,科技书:7人,其他:5人。17\u003e15\u003e7\u003e5,喜欢看故事书的人最多,喜欢看其他书的人最少。(2)由分析可得:17-7=10(人),15-7=8(人),喜欢看科技书的人比喜欢看故事书的少10人,喜欢看连环画的人比喜欢看科技书的多8人。(3)由分析可得:15+17+7+5=44(人),二(1)班共有44人。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "100以内数的连加运算"
+                             ],
+        "source":  "24-25二年级下·甘肃庆阳·期末"
+    },
+    {
+        "id":  "16",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "某班有两位同学竞选班长,每位同学必须投一票,且只能投一票,最终得票数如下图。![](images/165111.png)\n(1)小刚得了( )票,小雨得了( )票.\n(2)有3名同学因缺勤没参加投票,这个班共有( )人。",
+        "options":  [
+
+                    ],
+        "answer":  "20;17;40",
+        "solution":  "【分析】(1)一个正字5票,数一数可知小刚和小雨分别得了几票;(2)把小刚和小雨的得票数加起来,再加上没参加投票的数量,即可求出这个班共有几人.\n\n【详解】(1)5×4=20(票),5×3+2=15+2=17(票),小刚得了20票,小雨得了17票。(2)20+17+3=40(人),这个班共有40人。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "100以内数的连加运算",
+                                 "5的乘法口诀及应用",
+                                 "表内乘加",
+                                 "乘减"
+                             ],
+        "source":  "24-25 二年级下·江西九江·期末"
+    },
+    {
+        "id":  "17",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "下面是二(1)班同学最喜欢吃的蔬菜情况统计表。(每人只投一票)![](images/182607.png)\n(1)完成下表。![](images/165231.png)\n(2)最喜欢吃( )的人最少,最喜欢吃( )的人最多.\n(3)最喜欢吃黄瓜的比最喜欢吃西红柿的多( )人。",
+        "options":  [
+
+                    ],
+        "answer":  "25;18;15;20;白菜;黄瓜;7",
+        "solution":  "【分析】由题意可知:(1)\u0027正\u0027字统计法说明:1画代表1人,一个\u0027正\u0027字5画,代表5人,数一数填入表格中。(2)把统计结果按照从小到大的顺序排列,即可知最喜欢吃什么蔬菜的人最少,最喜欢吃什么蔬菜的人最多。(3)用最喜欢吃黄瓜的人数减去最喜欢吃西红柿的人数,即是多出的人数;据此解答.\n\n【详解】由分析可得:(1)数一数填入表格中,黄瓜25人,西红柿18人,白菜15人,豆角20人。(2)15\u003c18\u003c20\u003c25,最喜欢吃白菜的人最少,最喜欢吃黄瓜的人最多。(3)25-18=7(人),最喜欢吃黄瓜的比最喜欢吃西红柿的多7人。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "单式统计表的特点及填补",
+                                 "100以内数的比大小",
+                                 "两位数与两位数的退位减法"
+                             ],
+        "source":  "24-25二年级下·广东阳江·期末"
+    },
+    {
+        "id":  "18",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "下面是二(5)班全班同学最喜欢的电视节目调查情况。(每位同学只能选择一项)![](images/165402.png)\n(1)把调查结果填在下表中。![](images/165407.png)\n(2)最喜欢( )的人数最多,最喜欢( )的人数最少.\n(3)最喜欢动画片的和最喜欢体育节目的一共有( )人.\n(4)最喜欢电视剧的比最喜欢新闻的多( )人.\n(5)这个班一共有( )人。",
+        "options":  [
+
+                    ],
+        "answer":  "14;9;11;7;动画片;新闻;23;4;41",
+        "solution":  "【分析】由题意可知:(1)\u0027正\u0027字统计法说明:1画代表1人,一个\u0027正\u0027字5画,代表5人,数一数填入表格中。(2)把统计的结果按照大到小的顺序排列,即可知最喜欢哪种电视节目的人数最多,最喜欢哪种电视节目的人数最少。(3)把最喜欢动画片的人数和最喜欢体育节目的人数相加,即是喜欢两项电视节目一共有的人数。(4)用最喜欢电视剧的人数减去最喜欢新闻的人数,即是多出的人数。(5)把统计的各项结果相加,即是这个班一共有的人数。据此解答.\n\n【详解】由分析可得:(1)把调查结果填在下表中:动画片14人,体育节目9人,电视剧11人,新闻7人。(2)14\u003e11\u003e9\u003e7,最喜欢动画片的人数最多,最喜欢新闻的人数最少。(3)14+9=23(人),最喜欢动画片的和最喜欢体育节目的一共有23人。(4)11-7=4(人),最喜欢电视剧的比最喜欢新闻的多4人。(5)14+9+11+7=23+11+7=34+7=41(人),这个班一共有41人。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "单式统计表的特点及填补",
+                                 "位数与两位数的进位加法",
+                                 "100以内数的连加运算"
+                             ],
+        "source":  "24-25 二年级下·湖北孝感·期末"
+    },
+    {
+        "id":  "19",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "统计问题:下表是二(1)班同学最喜欢的玩具统计结果,根据统计结果回答问题.\n| 玩具 | 小汽车 | 积木 | 玩偶 | 恐龙 |\n| ---- | ------ | ---- | ---- | ---- |\n| 人数 | 12 | 8 | 10 | 6 |\n(1)最喜欢( )的人数最多.\n(2)最喜欢玩偶的比喜欢恐龙的多( )人.\n(3)全班共有( )人。",
+        "options":  [
+
+                    ],
+        "answer":  "小汽车;4;36",
+        "solution":  "【分析】由题意可知:(1)把统计结果按照从大到小的顺序排列,即可知道最喜欢哪种玩具的人数最多;(2)用最喜欢玩偶的人数减去喜欢恐龙的人数,即是最喜欢玩偶的比喜欢恐龙多的人数;(3)把统计的结果全部相加,即是全班共有的人数;据此解答.\n\n【详解】(1)12\u003e10\u003e8\u003e6,最喜欢小汽车的人数最多。(2)10-6=4(人),最喜欢玩偶的比喜欢恐龙的人数多4人。(3)12+8+10+6=20+10+6=30+6=36(人),全班共有36人。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "单式统计表的特点及填补",
+                                 "20以内数的比大小",
+                                 "100以内数的连加运算"
+                             ],
+        "source":  "24-25 二年级下·湖北孝感·期中"
+    },
+    {
+        "id":  "20",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "潮州某特产店统计潮州三宝销售情况。(每个△表示4件商品)![](images/165814.png)\n(1)( )的销量最高,是( )件;( )的销量最低,是( )件。\n(2)黄皮鼓比佛手果多销售( )件,老药桔比黄皮鼓少销售( )件。\n(3)特产店一共销售了( )件潮州三宝。",
+        "options":  [
+
+                    ],
+        "answer":  "黄皮鼓;24;老药桔;12;4;12;56",
+        "solution":  "【分析】(1)每个△表示4件商品,各项商品的总件数=△的个数*4,然后再比较大小;(2)黄皮鼓比佛手果多销售的件数=黄皮鼓销售的件数-佛手果销售的件数;老药桔比黄皮鼓少销售的件数=黄皮鼓销售的件数-老药桔销售的件数;(3)根据加法的意义,特产店一共销售潮州三宝的件数=老药桔销售的件数+佛手果销售的件数+黄皮鼓销售的件数,由此列出算式算出答案即可解答.\n\n【详解】(1)潮州三宝销售情况:老药桔4×3=12(件),佛手果4×5=20(件),黄皮鼓4×6=24(件)。24\u003e20\u003e12,黄皮鼓的销量最高,是24件;老药桔的销量最少,是12件。(2)24-20=4(件),24-12=12(件),所以黄皮鼓比佛手果多销售4件,老药桔比黄皮鼓少销售12件。(3)12+20+24=56(件),所以特产店一共销售了56件潮州三宝。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "24-25二年级下·广东潮州·期末"
+    },
+    {
+        "id":  "21",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "二(4)班的同学们正在为春游做准备。余老师给了生活委员壮壮一幅本班同学最喜欢喝的饮料情况统计图。(每人都投且只投一票)![](images/170207.png)\n(1)把统计结果填入表中。\n(2)壮壮在计算票数时,列出算式3×5-3,算的是( )的票数。\n(3)如果给每位同学买一个面包,壮壮应该买( )个面包。\n(4)票数最多的饮料和票数最少的饮料相差( )票。",
+        "options":  [
+
+                    ],
+        "answer":  "11;12;18;8;酸梅汤;49;10",
+        "solution":  "【分析】(1)根据统计的数据,一个\u0027正\u0027字表示5人,分别数出矿泉水,酸梅汤,橙汁和酸奶的数量完成填表。(2)求出3×5-3的结果,找出结果与统计表中数据相等的数量,即可解答。(3)如果给每位同学买一个面包,把统计表中最喜欢喝的各种饮料数量相加,即是同学们的数量,也是壮壮应该买面包的个数。(4)用票数最多的饮料减去票数最少的饮料,即可票数最多的饮料和票数最少的饮料相差的票数.\n\n【详解】(1)统计表如下:矿泉水11人,酸梅汤12人,橙汁18人,酸奶8人。(2)3×5-3=15-3=12(票),酸梅汤是12票。所以壮壮在计算票数时,列出算式3×5-3,算的是酸梅汤的票数。(3)11+12+18+8=49(个),答:如果给每位同学买一个面包,壮壮应该买49个面包。(4)18-8=10(票),答:票数最多的饮料和票数最少的饮料相差10票。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "24-25 二年级下·福建福州·期末"
+    },
+    {
+        "id":  "22",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "小学生研学是一种重要的教育方式,可以拓展学生的视野和知识面,增强综合素质,培养团队合作精神。学校打算组织二年级学生去研学,提前调查了同学们最喜欢去的地方,调查结果如下。(每人只选一个地方)![](images/170257.png)\n(1)把上面的统计结果填入下表。![](images/170315.png)\n(2)最喜欢去( )的人数最多,最喜欢去( )的人数最少,相差( )人.\n(3)二年级应该选择去( )研学。",
+        "options":  [
+
+                    ],
+        "answer":  "28;35;31;19;博物馆;森林公园;16;博物馆",
+        "solution":  "【分析】(1)一个○表示1人,一个√表示1人,一个正字表示5人,数一数可知,去四个地方研学的各有几人,将数据填入表格中;(2)把表中的四个数据比较大小,即可知道最喜欢去哪个地方的人数最多,最喜欢去哪个地方的人数最少,用表中最大数据减去最小数据算出差,即可知道相差几人;(3)二年级应该选择去人数最多,人气高的地方研学.\n\n【详解】(1)数一数可知,去植物园的有28人,去博物馆的有35人,去滨河公园的有31人,去森林公园的有19人。(2)35\u003e31\u003e28\u003e19,35-19=16(人),最喜欢去博物馆的人数最多,最喜欢去森林公园的人数最少,相差16人。(3)最喜欢去博物馆的人数最多,这个地方的人气很高,所以二年级应该选择去博物馆研学。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "100以内数的比大小"
+                             ],
+        "source":  "24-25二年级下·福建漳州·期中"
+    },
+    {
+        "id":  "23",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "下面是小明调查的二年级(1)班同学最喜欢吃的蔬菜情况。(每人只投一票)。豆角:√√√√√√√√√√√√√ 白菜:○○○○○○ 土豆:正正正正正正 黄瓜:▲▲▲▲▲▲▲▲▲▲▲\n(1)根据上面的调查结果完成统计表。![](images/170441.png)\n(2)一共调查了( )名同学。喜欢吃( )的人数最多,喜欢吃( )的人数最少。喜欢吃黄瓜的比喜欢吃土豆的少( )人。",
+        "options":  [
+
+                    ],
+        "answer":  "13;6;30;11;60;土豆;白菜;19",
+        "solution":  "【分析】(1)一个√表示1人,一个○表示1人,一个▲表示1人,一个正字表示5人,数一数可知,最喜欢吃各种蔬菜的分别有几人,将数据填在表格里即可;(2)把最喜欢吃各种蔬菜的人数全部加起来,即可求出共调查了几名同学;将四个数据比较大小,即可知道喜欢吃哪种蔬菜的人数最多,喜欢吃哪种蔬菜的人数最少;用喜欢吃土豆的人数减去喜欢吃黄瓜的人数,即可求出喜欢吃黄瓜的比喜欢吃土豆的少几人.\n\n【详解】(1)数一数可知:最喜欢吃豆角的有13人,最喜欢吃白菜的有6人,最喜欢吃土豆的有30人,最喜欢吃黄瓜的有11人,填表如下:豆角13人,白菜6人,土豆30人,黄瓜11人。(2)13+6+30+11=60(名),30\u003e13\u003e11\u003e6,30-11=19(人),共调查了60名同学。喜欢吃土豆的人数最多,喜欢吃白菜的人数最少。喜欢吃黄瓜的比喜欢吃土豆的少19人。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "100以内数的连加运算"
+                             ],
+        "source":  "24-25 二年级下·甘肃天水·期末"
+    },
+    {
+        "id":  "24",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "下面是二(1)班同学最喜欢的季节的调查情况:![](images/172246.png)\n(1)请你根据上面的记录完成下表:![](images/170538.png)\n(2)二(1)班一共有( )人,喜欢( )季的人数最多,喜欢( )季的人数最少,相差( )人.\n(3)如果组织二(1)班同学去游玩,最好安排在( )季。",
+        "options":  [
+
+                    ],
+        "answer":  "20;11;8;3;42;春;冬;17;春",
+        "solution":  "【分析】(1)用正字统计票时,一个笔画代表1人,则数数得到正字的比较即可,用○,√或其他图案统计票数,代表1人,则有几个图形,则有几人;(2)将各季节得到的票数进行相加,即可求出一共有的人数;将各季节得的票数进行比较,选择最多和最少的即可,然后根据用多的数量减去少的数即可求出相差的人数;(3)根据题意可知:投票最多的则是大家最先去的,将各季节得的票数进行比较,选择最多的即可.\n\n【详解】(1)填表:春季20人,夏季11人,秋季8人,冬季3人。(2)20+11+8+3=31+8+3=39+3=42(人),20\u003e11\u003e8\u003e3,20-3=17(人),则二(1)班一共有42人,喜欢春季的人数最多,喜欢冬季的人数最少,相差17人。(3)20\u003e11\u003e8\u003e3,则如果组织二(1)班同学去游玩,最好安排在春季。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "100以内数的连加运算"
+                             ],
+        "source":  "24-25 二年级下·贵州黔东南·期末"
+    },
+    {
+        "id":  "25",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "下表是二年级两个班学生最喜欢的课外项目统计情况。![](images/172511.png)\n(1)二年级最喜欢( )的人数最多,最喜欢( )的人数最少.\n(2)二年级一共有( )人.\n(3)喜欢唱歌的比喜欢画画的少( )人。",
+        "options":  [
+
+                    ],
+        "answer":  "画画;跳舞;70;10",
+        "solution":  "【分析】由题意可知:(1)\u0027正\u0027字统计法说明:1画代表1人,一个\u0027正\u0027字5画,代表5人;数一数即可知道最喜欢的课外项目的统计数据;把这些数据按照从大到小的顺序排列,最大的数据即是最喜欢的人数最多的项目,最小的数据即是最喜欢的人数最少的项目;(2)把统计的数据全部相加,即是二年级一共有的人数;(3)用喜欢画画的人数减去喜欢唱歌的人数,即是喜欢唱歌比喜欢画画少的人数。据此解答.\n\n【详解】(1)由分析可知:画画:25人,踢球:20人,唱歌:15人,跳舞:10人。25\u003e20\u003e15\u003e10,二年级最喜欢画画的人数最多,最喜欢跳舞的人数最少。(2)25+20+15+10=70(人),二年级一共有70人。(3)25-15=10(人),喜欢唱歌的比喜欢画画的少10人。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "单式统计表的特点及填补",
+                                 "100以内数的比大小",
+                                 "100以内数的连加运算"
+                             ],
+        "source":  "24-25 二年级下·辽宁鞍山·期末"
+    },
+    {
+        "id":  "26",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "如表是2024年巴黎奥运会五个国家获得金牌数量的统计情况。(截至2025.2)![](images/172555.png)\n(1)获得金牌数一样多的国家是( )与( ),获得金牌数最少的国家是( ).\n(2)中国的金牌数比日本多( )枚,法国的金牌数比日本少( )枚。",
+        "options":  [
+
+                    ],
+        "answer":  "中国;美国;法国;20;4",
+        "solution":  "【分析】(1)一个正字5画,表示5枚金牌,数一数5个国家分别获得了几枚金牌,将数据进行比较,得出获得金牌数一样多的是哪两个国家,获得金牌数最少的是哪个国家;(2)用中国的金牌数减去日本的金牌数,即可求出中国的金牌数比日本多几枚;用日本的金牌数减去法国的金牌数,即可求出法国的金牌数比日本少几枚.\n\n【详解】(1)数一数可知:中国获得40枚金牌,美国获得40枚金牌,日本获得20枚金牌,澳大利亚获得18枚金牌,法国获得16枚金牌;40=40\u003e20\u003e18\u003e16,获得金牌数一样多的国家是中国与美国,获得金牌数最少的国家是法国。(2)40-20=20(枚),20-16=4(枚),中国的金牌数比日本多20枚,法国的金牌数比日本少4枚。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "整十数之间的加减法",
+                                 "两位数与两位数的退位减法"
+                             ],
+        "source":  "24-25 二年级下·湖北武汉·期末"
+    },
+    {
+        "id":  "27",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "下面是一(2)班同学喜欢的水果情况统计表。![](images/172846.png)\n(1)喜欢( )的人数最多,喜欢( )的人数最少.\n(2)喜欢苹果的比喜欢梨的多( )人。",
+        "options":  [
+
+                    ],
+        "answer":  "苹果;梨;6",
+        "solution":  "【分析】(1)将表中喜欢水果情况的人数进行比较,即可知道喜欢哪种水果的人数最多,喜欢哪种水果的人数最少;(2)用喜欢苹果的人数减去喜欢梨的人数,即可求出喜欢苹果的比喜欢梨的多几人.\n\n【详解】(1)12\u003e10\u003e8\u003e6,喜欢苹果的人数最多,喜欢梨的人数最少。(2)12-6=6(人),喜欢苹果的比喜欢梨的多6人。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "20以内数的比大小"
+                             ],
+        "source":  "24-25 一年级下·广东汕尾·期末"
+    },
+    {
+        "id":  "28",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "三(1)班的学生每人从家里带来一些课外书,办起一个小小图书角,共有科技书20本,故事书18本,连环画12本,其他书8本。\n(1)请你把各种书的本数填在下表里。\n| 种类 | 连环画 | 科技书 | 故事书 | 其他书 |\n| ------- | ------ | ------ | ------ | ------ |\n| 数量/本 | | | 18 | 8 |\n(2)( )书的本数最多,( )书的本数最少。\n(3)科技书比连环画多( )本。",
+        "options":  [
+
+                    ],
+        "answer":  "12;20;18;8;科技;其他;8",
+        "solution":  "【分析】(1)根据题目中的信息将统计表补充完整即可。(2)求哪种书的本数最多或最少,直接比较几种书数量的多少即可。(3)科技书有20本,连环画有12本,求科技书比连环画多多少本,用减法计算.\n\n【详解】(1)填入数据即可:连环画12本,科技书20本,故事书18本,其他书8本。(2)20\u003e18\u003e12\u003e8,故科技书的本数最多,其他书的本数最少。(3)20-12=8(本),故科技书比连环画多8本。",
+        "knowledge_points":  [
+                                 "单式统计表的特点及填补"
+                             ],
+        "source":  "24-25 三年级下·湖南·期末"
+    },
+    {
+        "id":  "29",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "下面是二年级⑴班同学对水果的爱好情况调查记录。![](images/172936.png) 喜欢吃( )的人数最多;喜欢吃( )的人数最少。",
+        "options":  [
+
+                    ],
+        "answer":  "苹果;梨",
+        "solution":  "【分析】依据收集和整理的数据,一个\u0027正\u0027代表5人,先数一数,再填写统计表,然后比较大小,即可得出喜欢吃哪种水果的人数最多,喜欢吃哪种水果的人数最少.\n\n【详解】统计表:苹果18人,梨9人,香蕉10人,桃15人。18\u003e15\u003e10\u003e9,喜欢吃苹果的人数最多,喜欢吃梨的人数最少。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "20以内数的比大小"
+                             ],
+        "source":  "24-25二年级下·广东佛山·期末"
+    },
+    {
+        "id":  "30",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "下面是二(1)班同学最喜欢的动物情况统计。![](images/173000.png)\n(1)最喜欢( )的人数最多,比最喜欢小兔的多( )人.\n(2)这个班一共有( )人参与了调查。",
+        "options":  [
+
+                    ],
+        "answer":  "小狗;8;42",
+        "solution":  "【分析】(1)比较最喜欢各种小动物的人数,即可知喜欢哪种小动物的人数最多,哪种人数最少,通过比较可知,最喜欢小狗的人数最多,最喜欢小狗的人数减去最喜欢小兔的人数,等于喜欢小狗比最喜欢小兔的多几人;(2)把最喜欢各种小动物的人数相加,即可求出一共有多少人参与了调查.\n\n【详解】(1)6\u003c8\u003c12\u003c16,16-8=8(人),最喜欢小狗的人数最多,比最喜欢小兔的多8人。(2)12+16+8+6=42(人),这个班一共有42人参与了调查。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "24-25 二年级下·浙江绍兴·期末"
+    },
+    {
+        "id":  "31",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "下面是某超市一周工作日的饮料销售记录:周一:△△△△△△△△△△△△△△△△△△△ 周二:○○○○○○○○○○○○○○○ 周三:√√√√√√√√√√ 周四:◊◊◊◊◊◊◊◊◊◊◊◊◊◊◊◊◊◊◊◊ 周五:正正正正正正正\n(1)将统计表补充完整.\n| 星期 | 周一 | 周二 | 周三 | 周四 | 周五 |\n| ---- | ---------- | ---------- | ---------- | ---------- | ---------- |\n| 销量 | ( )瓶 | ( )瓶 | ( )瓶 | ( )瓶 | ( )瓶 |\n(2)统计表中( )的饮料销售量最多,( )的饮料销售量最少.\n(3)周五比周一多卖出( )瓶。",
+        "options":  [
+
+                    ],
+        "answer":  "19;15;10;20;35;周五;周三;16",
+        "solution":  "【分析】(1)1个符号代表1瓶饮料;\u0027正\u0027字法说明:1画代表1瓶,一个\u0027正\u0027字5画,代表5瓶;根据销售记录的数据完成填表即可;(2)比较统计表中周一到周五的销售数据,即可找出销售量最多或最少的饮料;(3)用周五销售的瓶数减去周一销售的瓶数,即是周五比周一多卖出的瓶数.\n\n【详解】(1)将统计表补充完整:周一19瓶,周二15瓶,周三10瓶,周四20瓶,周五35瓶。(2)从小到大排列数据:10\u003c15\u003c19\u003c20\u003c35,统计表中周五的饮料销售量最多,周三的饮料销售量最少。(3)35-19=16(瓶),周五比周一多卖出16瓶。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "100以内数的比大小",
+                                 "两位数与两位数的退位减法"
+                             ],
+        "source":  "24-25 二年级下·湖南长沙·期末"
+    },
+    {
+        "id":  "32",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "学校对二年级(1)班同学最喜欢的手工活动做了调查(每人只选择一种),记录如表。![](images/173134.png)\n(1)把调查结果填入表中。\n(2)一共有( )名同学参加了这次调查,喜欢( )手工活动的人数最多,有( )人。喜欢剪纸的同学比喜欢编织的多( )人。",
+        "options":  [
+
+                    ],
+        "answer":  "9;6;12;5;32;剪纸;12;6",
+        "solution":  "【分析】(1)一般用\u0027正\u0027代表票数,则1票是一笔画,则数一数\u0027正\u0027字有几笔就知道是几票。(2)根据题意可知:把所有票数进行相加即可求出一共的同学数量;将各活动的票数进行比较,票数越多则为喜欢的人数最多;求一个数比另一个是多几,用减法计算即可.\n\n【详解】(1)填表:叶画9人,编织6人,剪纸12人,其他5人。(2)9+6+12+5=15+12+5=27+5=32(人),5\u003c6\u003c9\u003c12,12-6=6(人),则一共有32名同学参加了这次调查,喜欢剪纸手工活动的人数最多,有12人。喜欢剪纸的同学比喜欢编织的多6人。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "100以内数的连加运算"
+                             ],
+        "source":  "24-25 二年级下·广东东莞·期末"
+    },
+    {
+        "id":  "33",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "下面是二(1)班同学最喜欢的玩具统计情况。(每人只能选一项)![](images/173442.png)\n(1)把统计结果填入表中。\n(2)最喜欢( )的人最多,最喜欢( )的人最少。\n(3)喜欢磁力积木的比喜欢乐高的少( )人。\n(4)如果这班的班主任要选择一种玩具作为奖品,选择( )最合适。",
+        "options":  [
+
+                    ],
+        "answer":  "4;5;16;8;乐高;拼图;11;乐高",
+        "solution":  "【分析】(1)一个一个地数,最后数到几就是几。正字的每一笔表示1人。(2)比较各人数的大小即可。(3)用喜欢乐高的人数减喜欢磁力积木的人数即可求解。(4)选择喜欢的人数最多的比较合适.\n\n【详解】(1)把统计的结果填入表:拼图4人,磁力积木5人,乐高16人,棋类8人。(2)4\u003c5\u003c8\u003c16,最喜欢乐高的人最多,最喜欢拼图的人最少。(3)16-5=11(人),喜欢磁力积木的比喜欢乐高的少11人。(4)如果这班的班主任要选择一种玩具作为奖品,选择乐高最合适。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "24-25 二年级下·河南郑州·期中"
+    },
+    {
+        "id":  "34",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "下面是小华调查本班同学最喜欢的传统节日的情况。![](images/172246.png)\n(1)把统计结果填入表中。\n(2)本班同学最喜欢( )的人数最多。",
+        "options":  [
+
+                    ],
+        "answer":  "10;11;8;24;中秋节",
+        "solution":  "【分析】(1)一个\"√\"表示一票,一个\"正\"表示5票,一个\"○\"表示一票,数出每个同学最喜欢传统节日的情况,将数据填入表格即可;(2)根据填表的数据比较可知,本班同学最喜欢哪个传统节日的人数最多.\n\n【详解】(1)填表如下:春节10人,元宵节11人,端午节8人,中秋节24人。(2)24\u003e11\u003e10\u003e8,本班同学最喜欢中秋节的人数最多。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "100以内数的比大小"
+                             ],
+        "source":  "23-24 二年级下·湖南长沙·期末"
+    },
+    {
+        "id":  "35",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "下面是二(1)班同学最喜欢的水果情况:![](images/172246.png)\n(1)把统计结果填在表格里,一笔代表1人.\n(2)最喜欢( )的人数最多,最喜欢( )的人数最少.\n(3)二(1)班一共有( )人参与了调查。",
+        "options":  [
+
+                    ],
+        "answer":  "10;6;15;10;草莓;香蕉;41",
+        "solution":  "【分析】(1)一个\"正\"字有5笔,一笔代表1人,数一数即可知最喜欢各种水果的有多少人。(2)比较统计出的最喜欢各种水果的人数,即可知最喜欢哪种水果的人数最多,最喜欢哪种水果的人数最少。(3)把最喜欢各种水果的人数加起来,即可知一共有多少人参与了调查.\n\n【详解】(1)填表:苹果10人,香蕉6人,草莓15人,西瓜10人。(2)15\u003e10=10\u003e6,最喜欢草莓的人数最多,最喜欢香蕉的人数最少。(3)10+6+15+10=41(人),二(1)班一共有41人参与了调查。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "23-24 二年级下·甘肃天水·期末"
+    },
+    {
+        "id":  "36",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "根据下面的统计结果回答问题。老师调查了二年一班学生最喜欢吃的蔬菜情况,下表是调查结果。![](images/212949.png)\n(1)喜欢吃( )的人数最多,共有( )人.\n(2)喜欢吃蘑菇和吃西红柿的一共有( )人.\n(3)喜欢吃绿叶菜的人数比喜欢吃蘑菇的人数多( )人。",
+        "options":  [
+
+                    ],
+        "answer":  "绿叶菜;15;17;5",
+        "solution":  "【分析】(1)从图表中我们可以看出喜欢吃萝卜的有5人,喜欢吃辣椒的有3人,喜欢吃蘑菇的有10人,喜欢吃西红柿的有7人,喜欢吃绿叶菜的有15人,比较这些数据的大小可知,其中15最大,所以喜欢吃绿叶菜的人数最多,共有15人;(2)喜欢吃蘑菇的人数加上喜欢吃西红柿的人数,即可求出喜欢吃蘑菇和西红柿的一共有多少人;(3)喜欢吃绿叶菜的人数减去喜欢吃蘑菇的人数,即可求出喜欢吃绿叶菜的人数比喜欢吃蘑菇的人数多多少人.\n\n【详解】(1)3\u003c5\u003c7\u003c10\u003c15,因此喜欢吃绿叶菜的人数最多,共有15人。(2)10+7=17(人),因此喜欢吃蘑菇和吃西红柿的一共有17人。(3)15-10=5(人),因此喜欢吃绿叶菜的人数比喜欢吃蘑菇的人数多5人。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "23-24 二年级下·天津河东·期末"
+    },
+    {
+        "id":  "37",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "调查二(1)班同学最喜欢的运动项目(每人只能选一项),投票结果如下表。![](images/213007.png)\n(1)最喜欢( )的人数最多,最喜欢( )的人数最少.\n(2)最喜欢跳绳比最喜欢踢毽子的多( )人.\n(3)一共有( )人参加投票。",
+        "options":  [
+
+                    ],
+        "answer":  "跑步;踢毽子;6;47",
+        "solution":  "【分析】(1)数一数,依次15人,12人,14人,6人,比较即可求解。20以内的数从小到大排列是:1\u003c2\u003c3\u003c4\u003c5\u003c6\u003c7\u003c8\u003c9\u003c10\u003c11\u003c12\u003c13\u003c14\u003c15\u003c16\u003c17\u003c18\u003c19\u003c20。(2)用最喜欢跳绳的人数减最喜欢踢毽子的人数即可求解。(3)将各人数相加即可求解.\n\n【详解】(1)6\u003c12\u003c14\u003c15,最喜欢跑步的人数最多,最喜欢踢毽子的人数最少。(2)12-6=6(人),最喜欢跳绳比最喜欢踢毽子的多6人。(3)15+12+14+6=27+14+6=41+6=47(人),一共有47人参加投票。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "23-24 二年级下·浙江嘉兴·期末"
+    },
+    {
+        "id":  "38",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "4位同学正在统计一个路口10分钟内所通过的各种交通工具的数量。![](images/e14f436bc21296992fc75498fd969ea0390c8df1e64951fd5dcbac1b1e1b4b52.jpg)\n(1)把他们统计的结果填入下表中。![](images/213035.png)\n(2)这个路口10分钟内通过的( )最多,( )最少.\n(3)这个路口10分钟内通过的大巴车比电瓶车少( )辆.\n(4)如果再观察10分钟,你认为( )通过数量可能最多。",
+        "options":  [
+
+                    ],
+        "answer":  "5;13;19;4;小轿车;大巴车;9;小轿车",
+        "solution":  "【分析】(1)一个一个地数,最后数到几就是几。正字的每一笔表示一辆车。(2)比较各种车的辆数即可求解。(3)用电瓶车的数量减大巴车的数量即可求解。(4)观察的10分钟内小轿车通过的数量最多,则再观察10分钟,小轿车通过的数量可能还是最多.\n\n【详解】(1)把他们统计的结果填入下表中:面包车5辆,电瓶车13辆,小轿车19辆,大巴车4辆。(2)4\u003c5\u003c13\u003c19,这个路口10分钟内通过的小轿车最多,大巴车最少。(3)13-4=9(辆),这个路口10分钟内通过的大巴车比电瓶车少9辆。(4)如果再观察10分钟,我认为小轿车通过数量可能最多。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "23-24 二年级下·福建福州·期末"
+    },
+    {
+        "id":  "39",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "这是二年级体育代表队参加运动会获奖情况。![](images/213114.png)",
+        "options":  [
+
+                    ],
+        "answer":  "15;30;30",
+        "solution":  "【分析】一个\"正\"字是5画,数一数即可知每个名次的有多少人.\n\n【详解】通过数\"正\"字填表如下:第一名15人,第二名30人,第三名30人。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "23-24 二年级下·山东菏泽·期末"
+    },
+    {
+        "id":  "40",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "下面是二(2)班同学参加兴趣小组的情况。![](images/213219.png)\n(1)参加书法小组的和参加乐器小组的一共有( )人.\n(2)参加绘画小组的比参加棋类小组的少( )人.\n(3)你最喜欢的项目是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "15;4;绘画",
+        "solution":  "【分析】(1)根据加法的意义,参加书法小组的人数+参加乐器小组的人数=参加书法和乐器小组的总人数,列出算式算出答案即可解答;(2)根据减法的意义,参加棋类小组的人数-参加绘画小组的人数=参加绘画小组比参加棋类小组少的人数,列出算式算出答案即可解答;(3)从乐器,棋类,书法,绘画四个兴趣小组随意选择一个喜欢的即可,如喜欢绘画.\n\n【详解】(1)6+9=15(人),所以参加书法小组的和参加乐器小组的一共有15人。(2)12-8=4(人),所以参加绘画小组的比参加棋类小组的少4人。(3)最喜欢的项目是绘画。(答案不唯一)",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "十几减8的退位减法",
+                                 "9加几的进位加法"
+                             ],
+        "source":  "24-25 二年级下·河北邢台·期中"
+    },
+    {
+        "id":  "41",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "二(3)班有56人,同学们参加第二课堂的情况如下图。![](images/213322.png)\n(1)把统计结果填入表中。\n(2)二(3)班一共有( )人参加第二课堂,有( )人没参加。\n(3)( )小组最受同学们欢迎。",
+        "options":  [
+
+                    ],
+        "answer":  "5;10;15;11;10;51;5;画画",
+        "solution":  "【分析】(1)一个\"正\"字表示5人,分别数一数参加每个课外小组的人数,填表即可。(2)根据表格中的数据,用加法求出二(3)班参加第二课堂的人数;求有几人没参加第二课堂,用总人数减去一共参加的人数即可解答;(3)比较参加各课外小组的人数,人数最多的,表示这个小组最受同学们欢迎.\n\n【详解】(1)填表:鼓号队5人,足球10人,画画15人,舞蹈11人,书法10人。(2)5+10+15+11+10=51(人),56-51=5(人),二(3)班一共有51人参加第二课堂,有5人没参加。(3)15\u003e11\u003e10=10\u003e5,画画小组最受同学们欢迎。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "单式统计表的特点及填补"
+                             ],
+        "source":  "23-24 二年级下·贵州黔南·期末"
+    },
+    {
+        "id":  "42",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "下面是二(3)班同学参加兴趣小组的统计情况。航模组 书法组 合唱组 舞蹈组 美术组 ![](images/a0475e4b9fb4a2012b9ea01b14bb78bf01550081a32ce0ed1b969baa085e4394.jpg)\n(1)把上面统计出的数据整理到下面的表格中。![](images/213359.png)\n(2)( )组的人数最多,( )组的人数最少.\n(3)舞蹈组比航模组多( )人,比合唱组少( )人。",
+        "options":  [
+
+                    ],
+        "answer":  "7;5;14;13;4;合唱;美术;6;1",
+        "solution":  "【分析】(1)通过数一数即可知各兴趣小组各有多少人。(2)通过比较各兴趣小组的人数即可知哪个兴趣小组人数最多,哪个兴趣小组人最少。(3)用舞蹈组的人数减去航模组的人数,即可求出舞蹈组比航模组多多少人;用合唱组的人数减去舞蹈组的人数,即可求出舞蹈组比合唱组少多少人.\n\n【详解】(1)通过数一数填表如下:航模组7人,书法组5人,合唱组14人,舞蹈组13人,美术组4人。(2)14\u003e13\u003e7\u003e5\u003e4,合唱组的人数最多,美术组的人数最少。(3)13-7=6(人),14-13=1(人),舞蹈组比航模组多6人,比合唱组少1人。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "23-24 二年级下·河北唐山·期末"
+    },
+    {
+        "id":  "43",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "二(3)班要从王兰、李红两位同学中选出一位同学担任学习委员,下面是全班三个组的投票记录。(每人只能投一票)![](images/213424.png)\n(1)三个组共有( )人投票。\n(2)把记录的结果填入下表。![](images/213438.png)\n(3)根据投票结果,应该选( )担任学习委员。",
+        "options":  [
+
+                    ],
+        "answer":  "47;27;20;王兰",
+        "solution":  "【分析】(1)根据题意,因为每人只能投一票,故将一组,二组和三组的投票加起来即可解答;(2)分别将王兰和李红在各组中的投票加起来即可解答;(3)谁得到的投票票数最多,谁就担任学习委员.\n\n【详解】(1)9+10+8+6+6+8=19+8+6+6+8\n=27+6+6+8\n=33+6+8\n=39+8\n=47(人)\n即,三个组共有47人投票。(2)王兰:\n9+10+8\n=19+8\n=27(人)\n李红:\n6+6+8\n=12+8\n=20(人)\n(3)根据投票结果,王兰27票,李红20票,王兰票数多,应选王兰担任学习委员。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "23-24二年级下·云南曲靖·期末"
+    },
+    {
+        "id":  "44",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "在统计数据时,要做到不重复,不遗漏。( )",
+        "options":  [
+
+                    ],
+        "answer":  "√",
+        "solution":  "【分析】在统计过程中,确保数据的准确性和完整性是基本要求。教材中强调收集数据时需使用如画\"正\"字等方法,每个数据只能统计一次,避免重复或遗漏.\n\n【详解】由题意分析得:统计数据的核心原则是准确记录所有对象且每个对象仅统计一次。题目中\"不重复,不遗漏\"符合统计的基本要求,因此正确。故答案为:√",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "24-25二年级下·湖北省直辖县级单位·期末"
+    },
+    {
+        "id":  "45",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "用\"正\"字统计5月份天气情况,一个\"正\"字代表1天。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】\"正\"字书写简单,笔画除了横就是竖,笔画数是5,\"正\"字每写一画,代表着数量增加1,写出一个完整的\"正\"字代表着数量是5,便于我们统计数据,据此解答.\n\n【详解】由分析可得:用\"正\"字统计5月份天气情况,一个\"正\"字代表5天,原题说法错误。故答案为: ×",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "24-25 二年级下·云南昭通·期中"
+    },
+    {
+        "id":  "46",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "记录数据时,一个正字代表5个数据。( )",
+        "options":  [
+
+                    ],
+        "answer":  "√",
+        "solution":  "【分析】\"正\"字计数法:\"正\"字一笔表示数量1,一个\"正\"字表示数量5,由此解答.\n\n【详解】由分析可知:记录数据时,一个正字代表5个数据。原题说法正确。故答案为:√",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "24-25 二年级下·湖南张家界·期末"
+    },
+    {
+        "id":  "47",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "用\"正\"字统计4月份天气情况,一个\"正\"字代表1天。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】\"正\"字书写简单,笔画除了横就是竖,笔画数是5,\"正\"字每写一画,代表着数量增加1,写出一个完整的\"正\"字代表着数量是5,便于我们统计数据,据此解答.\n\n【详解】由分析可知:用\"正\"字统计4月份天气情况,一个\"正\"字代表5天,原题说法错误。故答案为: ×",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "24-25二年级下·河南南阳·期中"
+    },
+    {
+        "id":  "48",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "明明收集了本班20名同学某个星期天课外阅读的时间(单位:分),结果如下![](images/215143.png)\n(1)根据以上数据填写统计表。![](images/215155.png)\n(2)这20名同学中阅读时间最长的是( )分钟,最短的是( )分钟.\n(3)这20名同学中阅读时间少于30分钟的有( )人,大于1小时的有( )人.\n(4)小芳的阅读时间是65分,按从多到少的顺序排列,她排在这20名同学中的第( )个。",
+        "options":  [
+
+                    ],
+        "answer":  "4;7;2;7;95;20;4;7;7",
+        "solution":  "【分析】(1)通过数一数,阅读时间在20~30的有4人,在31~50的有7人,在51~60的有2人,在61及以上的有7人,据此填表;(2)这20名同学中阅读时间最长的一定是在61及以上,将7人的时间进行排序,找到时间最长的即可,最短的一定在20~30,将4人成绩进行排序,找到时间最短的即可。(3)根据表格,20~30对应的人数中去掉时长是30分钟的人数即为阅读时间少于30分钟的人数,61及以上对应的人数就是大于1小时的有多少人。(4)65分在61分以上,将65和61以上的数按照从多到少的排序,看65所处的位置即可.\n\n【详解】(1)填表:20~30分4人,31~50分7人,51~60分2人,61及以上7人。(2)65\u003c70\u003c75\u003c80\u003c90\u003c95;20\u003c25,这20名同学中阅读时间最长的是95分钟,最短的是20分钟。(3)这20名同学中,阅读时间少于30分钟的有4人,大于1小时的有7人。(4)95\u003e90\u003e80\u003e75\u003e70\u003e65,小芳的阅读时间是65分,按从多到少的顺序排列,她排在这20名同学中的第7个。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "100以内数的排序"
+                             ],
+        "source":  "25-26三年级上·福建宁德·期中"
+    },
+    {
+        "id":  "49",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "几个同学整理了一个路口十分钟内通过的各种交通工具的数量。![](images/000014.png)\n(1)把上面的整理结果填入下表。![](images/215243.png)\n(2)这个路口十分钟内通过的( )车最多,( )车最少.\n(3)这个路口十分钟内通过的小轿车比大巴车多( )辆.\n(4)如果再观察十分钟,( )车通过的辆数可能最多。",
+        "options":  [
+
+                    ],
+        "answer":  "59;6;8;33;12;小轿;面包;25;小轿",
+        "solution":  "【分析】(1)分别数出各种交通工具的数量填表即可,注意正字按笔画数量计数;(2)根据(1)中数据的大小得出结论即可;(3)小轿车的数量减大巴车的数量得出小轿车比大巴车多的数量即可;(4)根据(1)中数据得出结论即可.\n\n【详解】(1)合计:59;面包车:6;大巴车:8;小轿车:33;摩托车:12。(2)6\u003c8\u003c12\u003c33,故这个路口十分钟内所通过的小轿车最多,面包车最少。(3)33-8=25(辆),故这个路口十分钟内通过的小轿车比大巴车多25辆。(4)如果再观察十分钟,小轿车通过的辆数可能最多。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "24-25 三年级上·湖北十堰·期中"
+    },
+    {
+        "id":  "50",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "三年级学生的体重正常标准是28~35千克。下面是希望小学三(3)班学生的体重情况。(单位:千克)![](images/215303.png)\n(1)通过对数据的整理,你知道这个班有多少名学生应该注意控制饮食吗。\n(2)这个班有几名同学需要加强营养呢。\n(3)这个班的同学体重在哪个数值的人最多。",
+        "options":  [
+
+                    ],
+        "answer":  "6名;3名;体重在32千克和33千克的人最多",
+        "solution":  "【分析】(1)由题意得,三年级学生的体重正常标准是28~35千克,体重超过35千克的同学需要注意控制饮食。由数据可知,体重在35千克以上的有:38,39,44,36,37,41,一共有6名同学。(2)由题意得,三年级学生的体重正常标准是28~35千克,体重低于28千克的同学需要加强营养。由数据可知,体重在28千克以下的有:23,26,24,一共有3名同学。(3)由题意得,可以将体重在各个数值的人数全部整理出来,然后对比找出体重在哪个数值的人最多.\n\n【详解】(1)答:这个班有6名学生应该注意控制饮食。(2)答:这个班有3名同学需要加强营养。(3)根据数据整理表格如下:体重23有1人,24有1人,26有1人,28有1人,29有1人,30有1人,31有2人,32有4人,33有4人,34有3人,36有1人,37有1人,38有1人,39有1人,41有1人,44有1人。4=4\u003e3\u003e2\u003e1=1=1=1=1=1=1=1=1=1=1=1,答:这个班的同学体重在32千克和33千克的人最多。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "25-26 三年级上·河南周口·阶段练习"
+    },
+    {
+        "id":  "51",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "下面是三(2)班学生的视力统计情况表。![](images/215323.png)\n(1)三(2)班一共有( )名同学,视力在5.0(不含5.0)以下的有( )人.\n(2)老师对三(2)班同学说:\"检查结果在5.0及5.0以上是视力正常,我们班每3个人中有两人的视力是正常的.\"对此,你对三(2)班同学的有什么建议。请写下来。",
+        "options":  [
+
+                    ],
+        "answer":  "42;14;答案见详解",
+        "solution":  "【分析】(1)由题意得,求三(2)班一共有多少名同学,直接把表格中的人数全部加起来即可;求视力在5.0(不含5.0)以下的有多少人,直接把视力为4.9~4.7,4.6~4.3,4.2以下(含4.2)的人数全部加起来即可。(2)由题意得,三(2)班的同学近视的人数较多,这部分同学需要注意保护自己的眼睛,避免长时间近距离用眼,多参加户外活动等.\n\n【详解】(1)28+8+5+1=36+5+1=41+1=42(名),8+5+1=13+1=14(人),三(2)班一共有42名同学,视力在5.0(不含5.0)以下的有14人。(2)答:建议视力不正常的同学注意保护自己的眼睛,避免长时间近距离用眼,多参加户外活动等。",
+        "knowledge_points":  [
+                                 "单式统计表的特点及填补"
+                             ],
+        "source":  "24-25三年级下·河南洛阳·期末"
+    },
+    {
+        "id":  "52",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "二(5)班要组织外出活动,下面是大家希望去的地点调查记录。![](images/215347.png)\n(1)二(5)班一共有( )人.\n(2)二(5)班希望去( )的人数最少,比希望去动物园的人数少( )人.\n(3)二(5)班外出活动选择去什么地点比较合适。为什么。",
+        "options":  [
+
+                    ],
+        "answer":  "45;图书馆;12;动物园;理由见详解",
+        "solution":  "【分析】(1)将希望去每个地点的人数相加就是总人数;(2)比较希望去每个地点的人数,找到人数最少的即可;用希望去动物园的人数减去最少的人数,即可求出少的人数;(3)选择地点时,应考虑多数同学的意愿,由此解答.\n\n【详解】(1)18+13+6+8=45(人),二(5)班一共有45人。(2)18\u003e13\u003e8\u003e6,18-6=12(人),二(5)班希望去图书馆的人数最少,比希望去动物园的人数少12人。(3)选择去动物园比较合适,因为希望去动物园的人数最多,这样能满足更多同学的需求。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "24-25二年级下·江西赣州·期末"
+    },
+    {
+        "id":  "53",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "为落实国家\"双减\"政策,光明小学积极开展阳光体育活动,强化学生体质健康监测。以下是三年级小军所在班级所有男生立定跳远的成绩数据。![](images/215541.png)\n(1)该班男生立定跳远的最好成绩是( )厘米,最差成绩是( )厘米。两者相差多少( )厘米.\n(2)国家体质健康标准中,三年级男生立定跳远优秀成绩需达到140厘米及以上,成绩达到优秀的有( )人。跳远成绩低于130厘米(需加强锻炼)的有( )人.\n(3)小军的跳远成绩是第六名,小军跳了( )厘米。",
+        "options":  [
+
+                    ],
+        "answer":  "149;121;28;5;5;139",
+        "solution":  "【分析】(1)在立定跳远的比赛中,谁跳得远,谁的成绩就好。由题意得,可以将表格中所有男生立定跳远的成绩按从大到小的顺序排列,然后找出最好和最差的成绩。求两者相差多少,用减法计算。(2)由题意得,三年级男生立定跳远成绩达到140厘米及以上为优秀,立定跳远成绩低于130厘米的需加强锻炼,可以根据(1)中的排序结果分别数出立定跳远成绩达到140厘米及以上或立定跳远成绩低于130厘米的人数。(3)由题意得,小军的跳远成绩是第六名,可以根据(1)中的排序结果按从大到小的顺序数出第6名的成绩.\n\n【详解】(1)将所有男生立定跳远的成绩按从大到小排列为:149\u003e144\u003e143\u003e142\u003e141\u003e139\u003e138\u003e137\u003e136\u003e135\u003e133\u003e132\u003e131\u003e130\u003e130\u003e128\u003e127\u003e126\u003e124\u003e121,故该班男生立定跳远的最好成绩是149厘米,最差成绩是121厘米。149-121=28(厘米),该班男生立定跳远的最好成绩是149厘米,最差成绩是121厘米。两者相差28厘米。(2)立定跳远优秀成绩达到140厘米及以上的有:149,144,143,142,141,一共有5人。立定跳远优秀成绩低于130厘米的有:128,127,126,124,121,一共有5人。国家体质健康标准中,三年级男生立定跳远优秀成绩需达到140厘米及以上,成绩达到优秀的有5人。跳远成绩低于130厘米(需加强锻炼)的有5人。(3)由(1)的排序结果可知,第一名到第六名的成绩分别为:149,144,143,142,141,139。小军的跳远成绩是第六名,所以他的成绩为139厘米。小军的跳远成绩是第六名,小军跳了139厘米。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "24-25 三年级下·河南新乡·期末"
+    },
+    {
+        "id":  "54",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "二(5)班要组织外出活动,下面是大家希望去的地点调查记录。![](images/215637.png)\n(1)二(5)班一共有( )人。\n(2)二(5)班希望去( )的人数最少,比希望去动物园的人数少( )人。\n(3)二(5)班外出活动选择去什么地点比较合适。为什么。",
+        "options":  [
+
+                    ],
+        "answer":  "40;图书馆;9;选择去博物馆比较合适,因为希望去博物馆的人数最多。",
+        "solution":  "【分析】(1)将希望去的四个地点的人数相加,即可求出二(5)班一共有多少人。(2)比较题干中各个数据的大小,找出最小值,故希望去图书馆的人数最少;希望去动物园的人数减去希望去图书馆的人数,等于希望去图书馆比希望去动物园的人数少多少人。(3)根据已知数据,找出希望去地方最多的人数,作为外出活动的地方比较合适.\n\n【详解】(1)13+8+4+15=40(人),二(5)班一共有40人。(2)15\u003e13\u003e8\u003e4,13-4=9(人),二(5)班希望去图书馆的人数最少,比希望去动物园的人数少9人。(3)答:二(5)班外出活动选择去博物馆,因为有15人选择去博物馆,人数最多,选择去博物馆最合适。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "24-25 二年级下·江西赣州·期末"
+    },
+    {
+        "id":  "55",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "下面是学校对二(1)班同学最喜欢的手工实践活动人数的调查情况。![](images/215714.png)\n(1)把统计结果填入表中。\n(2)一共有( )名同学参与了这次调查。\n(3)最喜欢( )手工实践活动的人数最多,最喜欢( )手工实践活动的人数最少。\n(4)如果班主任想选一种手工艺品作为本班的特色,选( )比较合适。",
+        "options":  [
+
+                    ],
+        "answer":  "12;5;10;15;42;叶画;编织;叶画",
+        "solution":  "【分析】由题意可知:(1)\"正\"字统计法说明:1画代表1人,一个\"正\"字5画,代表5人,数一数填入表格中。(2)把统计的数据相加,即是一共参与了这次调查的同学数。(3)把统计的数据按照从大到小的顺序排列,即可知最喜欢哪种手工实践活动的人数最多,最喜欢哪种手工实践活动的人数最少。(4)如果班主任想选一种手工艺品作为本班的特色,选喜欢人数最多的手工比较合适.\n\n【详解】(1)填一填:泥塑12人,编织5人,剪纸10人,叶画15人。(2)12+5+10+15=17+10+15=27+15=42(名),一共有42名同学参与了这次调查。(3)15\u003e12\u003e10\u003e5,最喜欢叶画手工实践活动的人数最多,最喜欢编织手工实践活动的人数最少。(4)如果班主任想选一种手工艺品作为本班的特色,选叶画比较合适。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "单式统计表的特点及填补",
+                                 "20以内数的比大小",
+                                 "100以内数的连加运算"
+                             ],
+        "source":  "24-25 二年级下·广东潮州·期末"
+    },
+    {
+        "id":  "56",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "下面是红红调查的自己班同学最喜欢吃的水果的情况。(每人只选1种水果)![](images/215739.png)\n(1)把调查结果写在下表中\n\n| 葡萄 | 菠萝 | 梨 | 西瓜 |\n| ---- | ---- | ---- | ---- |\n| () | () | () | () |\n\n(2)最喜欢吃( )的人最多,最喜欢吃( )的人最少.\n(3)如果运动会需要买一种水果,你会选择买什么水果。请说明理由。",
+        "options":  [
+
+                    ],
+        "answer":  "8;13;12;18;西瓜;葡萄;建议选择西瓜,因为喜欢吃西瓜的人数最多。(答案不唯一)",
+        "solution":  "【分析】(1)1个\"√\"\"○\"\"*\"表示1人;\"正\"字统计法说明:1画代表1人,一个\"正\"字5画,代表5人,数一数填入表格中。(2)把统计的结果按照从大到小的顺序排列,即可知最喜欢吃什么水果的人最多,最喜欢吃什么水果的人最少。(3)建议买喜欢人数最多的水果.\n\n【详解】(1)填表:葡萄8人,菠萝13人,梨12人,西瓜18人。(2)18\u003e13\u003e12\u003e8,最喜欢吃西瓜的人最多,最喜欢吃葡萄的人最少。(3)建议买西瓜,因为喜欢吃西瓜的人最多。(答案不唯一)",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "单式统计表的特点及填补",
+                                 "20以内数的比大小"
+                             ],
+        "source":  "24-25 二年级下·浙江杭州·期末"
+    },
+    {
+        "id":  "57",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "同学们统计了五一出游交通方式的数量,记录结果如下:![](images/215839.png)\n(1)把统计结果填入表中。\n(2)根据统计结果,出游交通方式中( )最多,( )最少。",
+        "options":  [
+
+                    ],
+        "answer":  "6;8;33;12;私家车;飞机",
+        "solution":  "【分析】(1)依据收集和整理的数据,先数一数,然后填写统计表,\"正\"字的每一笔代表1;(2)将每种交通方式的数量比较大小,找到数量最多和最少的即可.\n\n【详解】(1)表格填写如下:飞机6辆,高铁8辆,私家车33辆,大巴车12辆。(2)33\u003e12\u003e8\u003e6,根据统计结果,出游交通方式中私家车最多,飞机最少。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "24-25 二年级下·浙江台州·期末"
+    },
+    {
+        "id":  "58",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "小明调查了本班学生最喜欢的运动会项目(每人只选一种),结果如下。![](images/215857.png)\n(1)把统计结果填入表中。\n(2)参与调查的学生一共( )人;喜欢( )项目的人数最多。\n(3)调查当天有2名学生请假没有参与调查,如果他们也参与调查,结果会怎样。",
+        "options":  [
+
+                    ],
+        "answer":  "8;16;12;10;46;跳绳;如果未参加的2名同学参加,则不会影响喜欢跳绳项目排名,可能会影响喜欢50米、拔河、接力赛项目的排名。",
+        "solution":  "【分析】(1)数出每种运动喜欢的人数,并将数出的人数填入表格中即可解答;(2)根据加法的意义,将每种运动的喜欢人数进行相加,算出的人数就是参与调查的总人数。将每种运动的喜欢人数进行从大到小排序,找出人数最多的项目即可解答。(3)观察每项运动的喜欢人数,如果每个相邻的排名之间相差的人数\u003e2人,则请假没来的学生不会影响排序结果,反之则可能会影响排序结果.\n\n【详解】(1)喜欢50米的人有8人,喜欢跳绳的人有16人,喜欢拔河的人有12人,喜欢接力赛的人有10人。填入表格中如下图所示:50米8人,跳绳16人,拔河12人,接力赛10人。(2)8+16+12+10=46(人),16\u003e12\u003e10\u003e8,答:参与调查的学生一共有46人;喜欢跳绳的人数最多。(3)16-12=4(人),4\u003e2,不会影响这两种运动的结果;12-10=2(人),2=2,会影响这两种运动的结果;10-8=2(人),2=2,会影响这两种运动的结果。答:如果未参加的2名同学参加,则不会影响喜欢跳绳项目排名,可能会影响喜欢50米,拔河,接力赛项目的排名。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "24-25二年级下·河南郑州·期末"
+    },
+    {
+        "id":  "59",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "小明统计了树林里各种树的数量,记录结果如下。![](images/215917.png)\n(2)树林里,( )树最多,( )树最少.\n(3)柳树比梧桐树多( )棵。",
+        "options":  [
+
+                    ],
+        "answer":  "17;15;8;12;杨;梧桐;7",
+        "solution":  "【分析】由题意可知:(1)\"正\"字统计法说明:1画代表1棵,一个\"正\"字5画,代表5棵,数一数填入表格中;(2)把统计的数据按照从大到小的顺序排列,即可知最多的树和最少的树;(3)用柳树的棵数减去梧桐树的棵数,即是柳树比梧桐树多出的棵数。据此解答.\n\n【详解】(1)数一数填入表格中:杨树17棵,柳树15棵,梧桐树8棵,松树12棵。(2)17\u003e15\u003e12\u003e8,树林里,杨树最多,梧桐树最少。(3)15-8=7(棵),柳树比梧桐树多7棵。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "单式统计表的特点及填补",
+                                 "20以内数的比大小",
+                                 "十几减8的退位减法"
+                             ],
+        "source":  "24-25 二年级下·山东济宁·期中"
+    },
+    {
+        "id":  "60",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "聪聪和芳芳调查了二(1)班同学最喜欢参加的体育运动,下面是他们的调查记录。(每人都选且只选一种)![](images/215924.png)\n(1)喜欢( )的同学最多;喜欢参加( )的同学最少.\n(2)喜欢( )和( )的人数同样多.\n(3)喜欢跑步的同学比喜欢打乒乓球的少( )人.\n(4)算一算,二(1)班一共有学生多少人。",
+        "options":  [
+
+                    ],
+        "answer":  "打乒乓;跑步;打篮球;跳绳;6;34人",
+        "solution":  "【分析】(1)数出每种体育运动喜欢的人数,找出喜欢人数最多和喜欢人数最少的体育运动,即可解答。(2)找出体育运动喜欢人数相同的项目即可解答。(3)根据减法的意义,喜欢打乒乓球的人数-喜欢跑步的人数=喜欢跑步的同学比喜欢打乒乓球的少的人数,列出算式算出答案即可解答。(4)将每种项目喜欢的人数进行相加,算出的人数即为班级总人数.\n\n【详解】(1)打篮球的有6人,打乒乓球的有10人,跳绳的有6人,踢毽子的有8人,跑步的有4人。10\u003e8\u003e6=6\u003e4,所以喜欢打乒乓球的同学最多,喜欢参加跑步的同学最少。(2)根据10\u003e8\u003e6=6\u003e4可知,喜欢打篮球和跳绳的人数同样多。(3)10-4=6(人),所以喜欢跑步的同学比喜欢打乒乓球的少6人。(4)6+10+6+8+4=16+6+8+4=22+8+4=30+4=34(人),答:二(1)班一共有学生34人。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "24-25 二年级下·湖北黄冈·期中"
+    },
+    {
+        "id":  "61",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "下面是二(1)班同学最喜欢吃的蔬菜统计情况。![](images/215958.png)\n(1)把统计结果填入表中。\n(2)请你根据统计表填一填。①最喜欢吃( )的人数最多,最喜欢吃( )的人数最少。②如果每位同学只选了一种蔬菜,那么二(1)班一共有( )人。\n(3)你还能提出其他数学问题并解答吗。",
+        "options":  [
+
+                    ],
+        "answer":  "12;20;11;4;土豆;茄子;47;喜欢吃土豆的人数比喜欢吃西红柿的多多少人。9人(答案不唯一)",
+        "solution":  "【分析】(1)根据统计符号(一个\"正\"表示5人)的数量分别数一数喜欢每种蔬菜的人数各是多少并填表即可。(2)①比较喜欢各种蔬菜的人数大小来确定喜欢什么蔬菜的人数最多和喜欢什么蔬菜的人数最少;②把喜欢各种蔬菜的人数加起来,求出和就是总人数。(3)根据已知条件提出数学问题,合理即可,答案不唯一。如:喜欢吃土豆的人数比喜欢吃西红柿的多多少人。用减法列式解决.\n\n【详解】(1)填表:胡萝卜12人,土豆20人,西红柿11人,茄子4人。(2)①20\u003e12\u003e11\u003e4,最喜欢吃土豆的人数最多,最喜欢吃茄子的人数最少。②12+20+11+4=47(人),如果每位同学只选了一种蔬菜,那么二(1)班一共有47人。(3)喜欢吃土豆的人数比喜欢吃西红柿的多多少人。20-11=9(人),答:喜欢吃土豆的人数比喜欢吃西红柿的多9人。(答案不唯一)",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "单式统计表的特点及填补",
+                                 "20以内数的比大小",
+                                 "100以内数的连加运算"
+                             ],
+        "source":  "24-25 二年级下·河北邯郸·期中"
+    },
+    {
+        "id":  "62",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "二(1)班投票选举劳动小能手(每人只能投一票),投票结果如下:![](images/220028.png)\n(1)把统计结果填入表中。\n(2)根据统计表回答问题:①( )的票数最多,( )的票数最少,( )可能成为劳动小能手。②李亮比王欣多得( )票,陈明比王欣少得( )票。",
+        "options":  [
+
+                    ],
+        "answer":  "16;12;11;李亮;陈明;李亮;4;1",
+        "solution":  "【分析】(1)一个正字表示5票,一个○表示1票,一个√表示1票,数一数可知,三位同学分别得了几票,并将数据填入表格中;(2)将表格中的数据比较大小,即可知道哪位同学的票数最多,哪位同学的票数最少,哪位同学可能成为劳动小能手;(3)用李亮的票数减去王欣的票数,即可求出李亮比王欣多得几票;用王欣的票数减去陈明的票数,即可求出陈明比王欣少得几票.\n\n【详解】(1)数一数可知:李亮得了16票,王欣得了12票,陈明得了11票,填表如下:李亮16票,王欣12票,陈明11票。(2)16\u003e12\u003e11,李亮的票数最多,陈明的票数最少,李亮可能成为劳动小能手。(3)16-12=4(票),12-11=1(票),李亮比王欣多得4票,陈明比王欣少得1票。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "24-25二年级下·广东潮州·期中"
+    },
+    {
+        "id":  "63",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "下面是二(1)班同学最喜欢的春游地点情况。(每人只选一个)游乐园:正正 动物园:○○○○○○○○ 植物园:√√√√√√ 科技园:√√√√√√√\n(1)把上面统计的结果填在下表中。![](images/220327.png)\n(2)二(1)班一共有多少人。口答:二(1)班一共有人。",
+        "options":  [
+
+                    ],
+        "answer":  "10;8;6;7 表见详解 31;31人",
+        "solution":  "【分析】(1)一个正字表示5人,一个○表示1人,一个√表示1人,数一数即可知道,最喜欢哪个春游地点的有几人,将数据填入表中;(2)把喜欢4个春游地点的人数全部加起来,即可求出二(1)班一共有多少人.\n\n【详解】(1)数一数可知,喜欢游乐园的有10人,喜欢动物园的有8人,喜欢植物园的有6人,喜欢科技园的有7人,填表如下:游乐园10人,动物园8人,植物园6人,科技园7人。(2)10+8+6+7=31(人),答:二(1)班一共有31人。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "100以内数的连加运算"
+                             ],
+        "source":  "24-25 二年级下·新疆阿克苏·期末"
+    },
+    {
+        "id":  "64",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "实验小学倡导每位同学争做环保小卫士。王磊,张雨,刘明,李帅分别将他们家一周内使用塑料袋的情况做了如下统计。王磊家:正正 张雨家:●●● 刘明家:√√√√√√ 李帅家:△△△△\n(1)把记录的结果填在下表中。![](images/220344.png)\n(2)四个家庭这一周内一共使用了( )个塑料袋,( )家使用塑料袋最多.\n(3)塑料垃圾又称\"白色污染\"。你对王磊家有什么好的建议吗。",
+        "options":  [
+
+                    ],
+        "answer":  "14;3;6;4 27;王磊 应当少用塑料袋,多用环保袋,防止造成白色污染。(答案不唯一)",
+        "solution":  "【分析】(1)\"正\"字计数法:\"正\"字一笔表示数量1,一个\"正\"字表示数量5,一个●,√,△表示1,依据收集和整理的数据,先数一数,再填写统计表;(2)四个家庭这一周内一共使用塑料袋的个数=四个家庭这一周内每家使用塑料袋的个数相加,然后再比较大小;(3)答案不唯一,可以为:建议用布袋代替塑料袋,或者重复使用塑料袋.\n\n【详解】(1)把记录的结果填在下表中:王磊家14个,张雨家3个,刘明家6个,李帅家4个。(2)14+3+6+4=17+6+4=23+4=27(个),所以四个家庭这一周内一共使用了27个塑料袋。14\u003e6\u003e4\u003e3,所以王磊家使用塑料袋最多。(3)答:我的建议:应当少用塑料袋,多用环保袋,防止造成白色污染。(答案不唯一)",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "100以内数的连加运算"
+                             ],
+        "source":  "23-24 二年级下·云南昭通·期末"
+    },
+    {
+        "id":  "65",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "下面是二(3)班同学最喜欢吃的水果的调查情况。(每人只能选一种)![](images/220445.png)\n(2)二(3)班喜欢吃( )的同学最多,喜欢吃( )的同学最少.\n(3)二(3)班一共有( )人。",
+        "options":  [
+
+                    ],
+        "answer":  "8;10;18;9 草莓;香蕉 45",
+        "solution":  "【分析】由题意可知:(1)一个图形代表1人;\"正\"字统计法说明:1画代表1人,一个\"正\"字5画,代表5人,数一数填入表格中。(2)把各项统计结果按从大到小排列,即可知喜欢吃哪种水果的人最多,喜欢吃哪种水果的人最少;(3)把统计的各项人数相加即是全班共有的人数;据此解答.\n\n【详解】(1)把统计的结果填在下表中:香蕉8人,苹果10人,草莓18人,西瓜9人。(2)18\u003e10\u003e9\u003e8,二(3)班喜欢吃草莓的同学最多,喜欢吃香蕉的同学最少。(3)8+10+18+9=18+18+9=36+9=45(人),二(3)班一共有45人。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "单式统计表的特点及填补",
+                                 "20以内数的比大小",
+                                 "100以内数的连加运算"
+                             ],
+        "source":  "24-25 二年级下·河南许昌·期中"
+    },
+    {
+        "id":  "66",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "下表是王老师统计的二(1)班同学的兴趣爱好。(每人只选一个喜欢的项目)![](images/220525.png)\n(1)二(1)班喜欢( )的人最多,喜欢( )的人最少.\n(2)二(1)班一共有( )人.\n(3)喜欢踢球的比喜欢唱歌的多( )人.\n(4)你能提出一个数学问题并解答吗。",
+        "options":  [
+
+                    ],
+        "answer":  "玩游戏;跳舞 63 1 喜欢玩游戏的人比喜欢跳舞的多多少人。(答案不唯一)8人",
+        "solution":  "【分析】(1)比较喜欢各项目的人数,即可知喜欢什么的人最多,喜欢什么的人最少。(2)因为每人只选一个喜欢的项目,所以把喜欢各项目的人数加起来,即可知二(1)班一共有多少人。(3)用喜欢踢球的人数减去喜欢唱歌的人数,即可知喜欢踢球的比喜欢唱歌的人多多少人。(4)根据题中所给信息,提出一个合理的问题即可,如:喜欢玩游戏的人比喜欢跳舞的多多少人。用喜欢玩游戏的人数减去喜欢跳舞的人数即可。(答案不唯一)\n\n【详解】(1)20\u003e16\u003e15\u003e12,二(1)班喜欢玩游戏的人最多,喜欢跳舞的人最少。(2)20+16+15+12=63(人),二(1)班一共有63人。(3)16-15=1(人),喜欢踢球的比喜欢唱歌的人多1人。(4)喜欢玩游戏的人比喜欢跳舞的多多少人。(答案不唯一)20-12=8(人),答:喜欢玩游戏的人比喜欢跳舞的多8人。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "\"提问题\"\"填条件\"问题"
+                             ],
+        "source":  "24-25 二年级下·甘肃天水·期中"
+    },
+    {
+        "id":  "67",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "下面是实验小学二(1)班同学在春节期间观看电影的调查统计情况。![](images/220602.png)\n(1)二(1)班同学春节期间一共看电影有( )人次.\n(2)观看电影( )的人数最多,观看电影( )的人数最少.\n(3)调查统计那天,芳芳因病请假没能参加。如果春节期间她去电影院看了一场电影,她可能看的电影是什么。为什么。",
+        "options":  [
+
+                    ],
+        "answer":  "93 哪吒之魔童降世;战火西岐 哪吒之魔童降世;因为观看的人数最多",
+        "solution":  "【分析】(1)将每场电影看的人数进行相加即可得到一共看电影的人次;(2)将观看每场电影的人数进行比较,哪场电影数字最小即是最少,哪场电影数字最大即是最多;(3)选择观看人数最多的电影即可.\n\n【详解】(1)8+3+42+28+12=11+42+28+12=53+28+12=81+12=93(人次),所以二(1)班同学春节期间一共看电影有93人次。(2)42\u003e28\u003e12\u003e8\u003e3,观看电影哪吒之魔童降世的人数最多,观看电影战火西岐的人数最少。(3)42\u003e28\u003e12\u003e8\u003e3,芳芳可能看的电影是哪吒之魔童降世,因为观看哪吒之魔童降世的人数最多。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "100以内数的比大小",
+                                 "100以内数的连加运算"
+                             ],
+        "source":  "24-25 二年级下·福建龙岩·期末"
+    },
+    {
+        "id":  "68",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "二(2)班同学最喜欢的水果情况如下表。![](images/220626.png)\n(1)最喜欢( )的人数最多,最喜欢( )的人数最少.\n(2)最喜欢苹果的比最喜欢香蕉的多几人。",
+        "options":  [
+
+                    ],
+        "answer":  "苹果;橘子 6人",
+        "solution":  "【分析】(1)根据20以内的数比较大小,按照从小到大的顺序将每种水果最喜欢的人数进行排序,找到人数最多的和人数最少的即可解答。(2)根据减法的意义,最喜欢苹果的人数-最喜欢香蕉的人数=最喜欢苹果的人数比最喜欢香蕉的人数多的部分,由此列出算式算出答案即可解答.\n\n【详解】(1)7\u003c9\u003c11\u003c15,所以最喜欢苹果的人数最多,最喜欢橘子的人数最少。(2)15-9=6(人),答:最喜欢苹果的比最喜欢香蕉的多6人。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "24-25 二年级下·黑龙江佳木斯·期末"
+    },
+    {
+        "id":  "69",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "下面是整理三(1)班学生一星期阅读课外读物的册数。![](images/220636.png)\n(2)阅读《连环画》的册数比《故事大王》多( )册.\n(3)同学们最喜欢看的课外读物是( ).\n(4)全班共读了( )册课外读物。",
+        "options":  [
+
+                    ],
+        "answer":  "16;17;12 5 《连环画》 45",
+        "solution":  "【分析】(1)根据\"√\"数量数出每种读物的册数填入表中;(2)阅读《连环画》的册数-阅读《故事大王》的册数=阅读《连环画》的册数比《故事大王》多的册数;(3)三种读物册数比较,找出最多的即为所答。(4)三种读物册数相加即可.\n\n【详解】(1)填表:《少儿文艺》16册,《连环画》17册,《故事大王》12册。(2)17-12=5(册),阅读《连环画》的册数比《故事大王》多5册。(3)17\u003e16\u003e12,同学们最喜欢看的课外读物是《连环画》。(4)16+17+12=45(册),全班共读了45册课外读物。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "单式统计表的特点及填补"
+                             ],
+        "source":  "24-25 三年级下·广东揭阳·期末"
+    },
+    {
+        "id":  "70",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "二年级(1)班一共有46人,每人只选一个最喜欢的课外社团活动项目,下表是统计情况。![](images/220704.png)\n(2)二年级(1)班最喜欢的人数最多,最喜欢的人数最少.\n(3)最喜欢跳舞和最喜欢绘画的一共有人,最喜欢唱歌比最喜欢跳舞的多人.\n(4)根据调查结果,你对学校各社团招收学员工作有什么建议。",
+        "options":  [
+
+                    ],
+        "answer":  "7;17;14;8 唱歌;跳舞 21;10 可以根据学生喜好调整社团规模和课程",
+        "solution":  "【分析】(1)一个□表示1人,一个0表示1人,一个正字表示5人,数一数可知,参加每个课外社团活动的有几人;用全班的总人数减去喜欢跳舞,唱歌,绘画的人数,即可求出喜欢书法的人数,将数据填入表格中;(2)将表中的数据比较大小,即可知道最喜欢哪个社团活动的人数最多,最喜欢哪个社团活动的人数最少;(3)用最喜欢跳舞的人数加上最喜欢绘画的人数,即可求出一共有多少人;用最喜欢唱歌的人数减去最喜欢跳舞的人数,即可求出最喜欢唱歌比最喜欢跳舞的多几人;(4)合理即可。如:可以根据学生喜好调整社团规模和课程.\n\n【详解】(1)数一数可知:喜欢跳舞社团的有7人,喜欢唱歌社团的有17人,喜欢绘画社团的有14人,喜欢书法社团的有46-7-17-14=8人。填表:跳舞7人,唱歌17人,绘画14人,书法8人。(2)17\u003e14\u003e8\u003e7,二年级(1)班最喜欢唱歌的人数最多,最喜欢跳舞的人数最少。(3)7+14=21(人),17-7=10(人),最喜欢跳舞和最喜欢绘画的一共有21人,最喜欢唱歌比最喜欢跳舞的多10人。(4)可以根据学生喜好调整社团规模和课程。(答案不唯一)",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "100以内数的连减运算"
+                             ],
+        "source":  "24-25二年级下·山东济南·期末"
+    },
+    {
+        "id":  "71",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "根据我区3月份上半月空气质量监测数据统计表,完成下面各题。![](images/220726.png)\n(1)根据统计表数据涂色完成上面的统计图.\n(2)从统计图中可以看出,3月份上半月空气质量( )的天数最多,( )的天数最少。",
+        "options":  [
+
+                    ],
+        "answer":  "见详解 优;差",
+        "solution":  "【分析】(1)根据表中数据,可以先统计出各空气质量的天数;按照1格表示1天,在对应统计图中涂色即可。(2)根据统计图中信息,把各空气质量的天数比较大小,或根据涂色部分的高低,找出天数最多和最少的空气质量,即可解答.\n\n【详解】(1)根据分析,统计如下:优6天,良5天,中3天,差1天。如图:略。(2)6\u003e5\u003e3\u003e1,所以从统计图中可以看出,3月份上半月空气质量优的天数最多,差的天数最少。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "24-25 三年级下·重庆黔江·期末"
+    },
+    {
+        "id":  "72",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "学校组织学生向贫困山区儿童献爱心。李明捐了9元,赵聪捐了10元,李丽捐了15元,刘虹捐了13元,王伟捐了11元.\n(1)把统计表填完整。![](images/220747.png)\n(2)捐款最多的是( ),捐款最少的是( ).\n(3)这5个人一共捐了多少元。",
+        "options":  [
+
+                    ],
+        "answer":  "9元;10元;15元;13元;11元 李丽;李明 58元",
+        "solution":  "【分析】(1)根据题目中的信息将统计表补充完整即可。(2)由题意得,要想知道捐款最多或最少的是谁,直接比较几个人捐款钱数的多少即可。(3)求这5个人一共捐了多少元,直接把5个人捐款的钱数全部加起来即可.\n\n【详解】(1)填表:李明9元,赵聪10元,李丽15元,刘虹13元,王伟11元。(2)15\u003e13\u003e11\u003e10\u003e9,故捐款最多的是李丽,捐款最少的是李明。(3)9+10+15+13+11=19+15+13+11=34+13+11=47+11=58(元),答:这5个人一共捐了58元。",
+        "knowledge_points":  [
+                                 "单式统计表的特点及填补",
+                                 "100以内数的连加运算"
+                             ],
+        "source":  "24-25 三年级下·广东揭阳·期末"
+    },
+    {
+        "id":  "73",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "下面是淘气调查二(1)班全体同学最喜欢的卡通人物的记录(每人只能选一个):![](images/220818.png)\n(1)完成上面的调查记录.\n(2)喜欢( )的人数最少,喜欢喜羊羊的人数比喜欢孙悟空的多( )人.\n(3)喜欢( )的人数和喜欢猪猪侠的人数最接近;喜欢光头强的人数比喜欢喜羊羊的少( )人.\n(4)二(1)班一共有( )人。",
+        "options":  [
+
+                    ],
+        "answer":  "6人;7人;9人;11人 光头强;2 光头强;5 33",
+        "solution":  "【分析】(1)根据题目中的符号记录,每个符号代表1人,分别数一数喜欢每个卡通人物的人数,完成填表。(2)把喜欢各种卡通人物的人数从小到大排列,人数最少的那种,即是二(1)班喜欢这种卡通人物人数最少的选项;喜欢喜羊羊的人数减去喜欢孙悟空的人数,等于喜欢喜羊羊的人数比喜欢孙悟空的少多少人。(3)用喜欢光头强,孙悟空和喜羊羊的人数与喜欢猪猪侠相减,找出差最小的哪一种,便是和喜欢猪猪侠的人数最接近的;喜欢喜羊羊的人数减去喜欢光头强的人数,等于喜欢光头强的人数比喜欢喜羊羊的少几人。(4)把喜欢各种卡通人物的人数相加,即可求出二(1)班一共有多少人.\n\n【详解】(1)填表如下:光头强6人,猪猪侠7人,孙悟空9人,喜羊羊11人。(2)6\u003c7\u003c9\u003c11,11-9=2(人),喜欢光头强的人数最少,喜欢喜羊羊的人数比喜欢孙悟空的多2人。(3)7-6=1(人),9-7=2(人),11-7=4(人),1\u003c2\u003c4,喜欢光头强的人数与喜欢猪猪侠的人数相差1人,差最少;11-6=5(人),喜欢光头强的人数和喜欢猪猪侠的人数最接近;喜欢光头强的人数比喜欢喜羊羊的少5人。(4)6+7+9+11=13+9+11=22+11=33(人),二(1)班一共有33人。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "单式统计表的特点及填补"
+                             ],
+        "source":  "24-25 二年级下·广东云浮·期末"
+    },
+    {
+        "id":  "74",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "二(2)班通过投票来选班长,4名候选人的得票情况如下:![](images/220851.png)\n(1)请统计4名候选人得的票数,填写在表格中.\n(2)二(2)班参加投票的有( )人,根据投票结果,应该选( )为班长.\n(3)有2名同学因请假没参加投票。如果他们也参加投票,结果会改变吗。说说你的理由。",
+        "options":  [
+
+                    ],
+        "answer":  "15;5;10;8 38;明明 不会改变,理由见解析。",
+        "solution":  "【分析】(1)分别计算或者数出各个候选人的得票,并把结果填入表中。明明:每个\"正\"代表5票,有3个\"正\"明明得15票;方方:一个一个地数一数\"√\",方方得5票;同同:一个一个地数一数\"○\",同同得10票;红红:一个一个地数一数\"☆\",红红得8票;(2)把他们每人得票数相加,即可求出参与投票有多少名,根据投票结果,将明明,方方,同同,红红的得票数从小到大排序,谁的得票多谁就当选为班长;(3)有2名同学因请假没参加投票,如果他们也参加投票,把这2票分别增加到除最高分同学之外,看看他们的得分是否会超过最高分,若超过则能改变结果,否则不能改变,据此说明原因.\n\n【详解】(1)填表如下:明明15票,方方5票,同同10票,红红8票。(2)15+5+10+8=38(名),5\u003c8\u003c10\u003c15,二(2)班参加投票的共有38名,根据投票结果,应该选明明为班长。(3)5+2=7(票),8+2=10(票),10+2=12(票),7\u003c10\u003c12\u003c15,答:有2名同学因请假没参加投票,如果他们也参加投票,结果不会改变;因为即使那2名请假的同学都参加投票,并且把票投给除明明之外的任意一位候选人,该候选人的票数最多只能增加到12票,仍比不上明明的15票,因此投票结果不会改变。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "24-25 二年级下·福建漳州·期末"
+    },
+    {
+        "id":  "75",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "二(1)班要竞选班长,每个人只能投一票,且不能投弃权票,下面是同学们的投票情况。![](images/220919.png)\n(2)二(1)班共有人参加投票,根据统计结果,应该选为班长.\n(3)投票当天有两位同学请假没来,如果他们也投票,影响班长人选。(填\"会\"或\"不会\")",
+        "options":  [
+
+                    ],
+        "answer":  "15;10;9;11 45;张丽 不会",
+        "solution":  "【分析】(1)依据收集和整理的数据,先数一数,然后填写统计表。(2)参加投票的总人数=每人的票数相加,应选票数最多的张丽为班长。(3)如果当天请假的两人投票给第二名方刚,方刚的票数11+2=13(票),还不是票数最多的,则不会影响班长人选.\n\n【详解】(1)通过数一数填写如下:张丽15票,林芳10票,陈明9票,方刚11票。(2)15+10+9+11=45(人),15\u003e11\u003e10\u003e9,二(1)班共有45人参加投票,根据统计结果,应该选张丽为班长。(3)11+2=13(票),15\u003e13,投票当天有两位同学请假没来,如果他们也投票,不会影响班长人选。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "单式统计表的特点及填补"
+                             ],
+        "source":  "24-25二年级下·浙江温州·期末"
+    },
+    {
+        "id":  "76",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "今年端午节,小冬调查本班同学最喜欢的粽子种类,情况如下表。(每人都参与且只选一种)![](images/220942.png)\n(1)把统计的结果填入表中.\n(2)最喜欢吃( )的人最多,最喜欢吃( )的人最少.\n(3)请你提出一个数学问题并解答。",
+        "options":  [
+
+                    ],
+        "answer":  "7;26;23;10 肉粽;米粽 喜欢肉粽的比喜欢豆粽多几人。3人",
+        "solution":  "【分析】(1)根据题意可知:用\"正\"来统计票数,则一笔画代表一人,则一个完整的正字代表5人。然后数一数即可。(2)把数出的数量进行比较,数量最多的则喜欢的人数最多,数量最少的则喜欢的最少。(3)根据题意提出问题合理即可,例如:喜欢肉粽的比喜欢豆粽多几人。用喜欢肉粽的人数减去喜欢豆粽的人数即可.\n\n【详解】(1)填表如下:米粽7人,肉粽26人,豆粽23人,蜜枣粽10人。(2)26\u003e23\u003e10\u003e7,最喜欢吃肉粽的人最多,最喜欢吃米粽的人最少。(3)喜欢肉粽的比喜欢豆粽多几人。26-23=3(人),答:喜欢肉粽的比喜欢豆粽多3人。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "两位数与两位数的不退位减法"
+                             ],
+        "source":  "24-25 二年级下·湖北黄冈·期末"
+    },
+    {
+        "id":  "77",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "几位同学调查了二(1)班45位学生课余时间最喜欢的运动项目情况,以下是调查结果:![](images/221015.png)\n(2)二(1)班同学最喜欢( )的人数最多,最喜欢( )的人数最少.\n(3)最喜欢跳绳的人数比最喜欢踢球的人数多( )人.\n(4)你还能提出一个数学问题吗。",
+        "options":  [
+
+                    ],
+        "answer":  "17人;8人;15人;5人 跳绳;游泳 9 最喜欢踢毽子和最喜欢游泳的一共有多少人。(答案不唯一)15+5=20(人);20人",
+        "solution":  "【分析】(1)依次数出最喜欢每种运动项目的人数填表即可,\"正\"字的每一笔代表1人;(2)比较最喜欢每种项目的人数,找到人数最多和最少的即可;(3)根据减法的意义,最喜欢跳绳的人数-最喜欢踢球的人数=最喜欢跳绳比最喜欢踢球多的人数;(4)提出的问题符合题意即可,可提出最喜欢踢毽子和最喜欢游泳的一共有多少人。\n\n【详解】(1)表格填写如下:跳绳17人,踢球8人,踢毽子15人,游泳5人。(2)17\u003e15\u003e8\u003e5,二(1)班同学最喜欢跳绳的人数最多,最喜欢游泳的人数最少。(3)17-8=9(人),最喜欢跳绳的人数比最喜欢踢球的人数多9人。(4)最喜欢踢毽子和最喜欢游泳的一共有多少人。(答案不唯一)15+5=20(人),答:最喜欢踢毽子和最喜欢游泳的一共有20人。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "\"提问题\"\"填条件\"问题"
+                             ],
+        "source":  "24-25 二年级下·浙江温州·期末"
+    },
+    {
+        "id":  "78",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "学校要开展跳绳竞赛活动,二(1)班通过投票的方法推荐一名同学参加。下面是投票情况。(每人只能投一票)。![](images/221045.png)\n把上边表中的统计结果填写在下面的表中,再回答问题.\n(1)一共有( )人参加了投票.\n(2)根据统计结果,选( )参加比较合适.\n(3)有两名同学缺勤没有参加投票,如果她们也参加了这次统计,结果可能会怎样。",
+        "options":  [
+
+                    ],
+        "answer":  "11;16;15\n42 涛涛 兰兰可能成为票数最多的",
+        "solution":  "【分析】正字的每一笔表示1票,数一数填空。(1)将各票数相加即可求解。(2)选票数最多的人比较合适。(3)将这两票投给第二名,看看名次是否会发生变化即可.\n\n【详解】填表如下:明明11票,涛涛16票,兰兰15票。(1)11+16+15=27+15=42(人),一共有42人参加了投票。(2)16\u003e15\u003e11,根据统计结果,选涛涛参加比较合适。(3)15+2=17(票),17\u003e16,答:如果她们都投给了兰兰,结果可能会变,兰兰可能成为票数最多的。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "单式统计表的特点及填补",
+                                 "100以内数的连加运算"
+                             ],
+        "source":  "24-25二年级下·重庆秀山·期末"
+    },
+    {
+        "id":  "79",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "晓晓对某路段10分钟内通过的车辆进行了统计。小汽车:正正正正 大货车;√√√√√√ 中巴车:○○○○○ 摩托车:正正\n(1)把统计的结果填在下表中。![](images/221126.png)\n(2)10分钟内共经过了( )辆车.\n(3)在下一个10分钟内,经过最多的车辆最有可能是( ).\n(4)你还能提出其他数学问题并解答吗。",
+        "options":  [
+
+                    ],
+        "answer":  "22;6;5;14 47 小汽车 小汽车比大货车多几辆。16辆",
+        "solution":  "【分析】(1)一般用\"正\"代表辆数,则1辆是一笔画,则数一数\"正\"字有几笔就知道是几辆。用\"√\"\"○\"代表辆数,一个\"√\"\"○\"代表一辆,然后数一数\"√\"\"○\"各有多少个就是各有多少辆。(2)把所有车辆的数量相加即可求出共经过的辆数。(3)由(1)数出哪个车多下一个10分钟就有可能是那个车。(4)结合题意提出问题合理即可。例如小汽车比大货车多几辆。(答案不唯一)用小汽车的数量减去大货车的数量即可.\n\n【详解】(1)由分析可得:小汽车22辆,大货车6辆,中巴车5辆,摩托车14辆。(2)22+6+5+14=28+5+14=33+14=47(辆),则10分钟内共经过了47辆车。(3)22\u003e14\u003e6\u003e5,则在下一个10分钟内,经过最多的车辆最有可能是小汽车。(4)小汽车比大货车多几辆。22-6=16(辆),答:小汽车比大货车多16辆。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "\"提问题\"\"填条件\"问题"
+                             ],
+        "source":  "23-24 二年级下·湖北荆州·期末"
+    },
+    {
+        "id":  "80",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "4月23日是\"全民阅读日\",小川同学对12名同学周末阅读的时间进行调查,结果如下表。(时间:分)![](images/221201.png)\n(1)这12名同学中,阅读时间最长的是( )分,最短的是( )分.\n(2)这12名同学中,阅读时间小于30分的有( )人,大于60分钟的有( )人.\n(3)对于阅读时间小于30分钟的同学,你有什么想对他说的。",
+        "options":  [
+
+                    ],
+        "answer":  "95;20 2;5 要加强阅读训练,每个周末抽出更多时间进行阅读",
+        "solution":  "【分析】(1)由题意得,要想知道阅读时间最长或最短是多少分,直接比较这12名同学的阅读时间的长短即可。(2)由表格可知,阅读时间小于30分的有:20,25,即一共有2人;阅读时间大于60分的有:70,95,65,80,75,即一共有5人。(3)由(2)可知,阅读时间小于30分钟的同学有2人,这部分同学的阅读时间明显不足。他们要加强阅读训练,每个周末抽出更多时间进行阅读.\n\n【详解】(1)20\u003c25\u003c35\u003c40\u003c45\u003c50\u003c60\u003c65\u003c70\u003c75\u003c80\u003c95,故这12名同学中,阅读时间最长的是95分,最短的是20分。(2)由分析得,这12名同学中,阅读时间小于30分的有2人,大于60分钟的有5人。(3)答:要加强阅读训练,每个周末抽出更多时间进行阅读。(答案不唯一,合理即可)",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "24-25 三年级下·福建龙岩·期末"
+    },
+    {
+        "id":  "81",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "二年(1)一共有45位同学,开学初的某一天,该班通过投票竞选一名数学课代表。每人只能投一票,而且不能弃权。当天有2位同学请假了,下面是四位候选人的得票情况:李群:正正正 洪畅:正正丁 周艳:正下 赵游:![](images/276a2d788434ed984bc3d7ececf4a79c824fff79411523bdb3fd70b75c24bddb.jpg)\n(1)根据上面的统计情况填写下表。![](images/223708.png)\n(2)获得的票数最多,当选为数学课代表.\n(3)如果这2位请假的同学回来参加投票,当选的结果会改变吗。为什么。",
+        "options":  [
+
+                    ],
+        "answer":  "15;12;8;8 李群 不会改变当选结果;理由见详解",
+        "solution":  "【分析】(1)根据\"正\"字统计法:一个\"正\"5画,一画代表1票,5画代表5票;分别数数前3人的票数,填入表中;赵游的票数=班上总人数-请假的2人-前3个人的总票数;(2)把四人的票数从大到小排列,票数最多的当选数学课代表;(3)如果请假的2人都投票给第二名洪畅,通过计算,如果洪畅的票数超过第一名李群,则会改变结果;如果没有超过第一名的李群,则不会改变当选结果.\n\n【详解】(1)前三人的总票数:15+12+8=27+8=35(票),赵游的票数:45-2-35=43-35=8(票),填表:李群15票,洪畅12票,周艳8票,赵游8票。(2)15\u003e12\u003e8=8,李群获得的票数最多,当选为数学课代表。(3)不会改变当选结果;如果请假的2人都投票给第二名的洪畅,洪畅的票数=12票+2票=14票,仍没有超过第一名15票的李群,故不会改变当选结果。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "20以内数的比大小",
+                                 "100以内数的连加运算",
+                                 "100以内数的连减运算"
+                             ],
+        "source":  "24-25二年级下·浙江温州·期末"
+    },
+    {
+        "id":  "82",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "下面是二(1)班同学最喜欢的体育项目统计情况。(每个表示2人)![](images/223823.png)\n(2)最喜欢( )的人数最多,最喜欢( )的人数最少.\n(3)喜欢拍球和喜欢跳绳的相差多少人。",
+        "options":  [
+
+                    ],
+        "answer":  "6人;12人;14人;8人 踢足球;跑步 4人",
+        "solution":  "【分析】(1)依次数出喜欢每种体育项目的格数,每个格代表2人,则用格数*2=人数,填表即可;(2)比较喜欢每种体育项目的人数,找到人数最多和最少的即可;(3)根据减法的意义,喜欢拍球的人数-喜欢跳绳的人数=相差的人数.\n\n【详解】(1)喜欢跑步的有:3×2=6(人);喜欢拍球的有:6×2=12(人);喜欢踢足球的有:7×2=14(人);喜欢跳绳的有:4×2=8(人)。填表:跑步6人,拍球12人,踢足球14人,跳绳8人。(2)14\u003e12\u003e8\u003e6,最喜欢踢足球的人数最多,最喜欢跑步的人数最少。(3)12-8=4(人),答:喜欢拍球和喜欢跳绳的相差4人。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "20以内数的比大小",
+                                 "7的乘法口诀及应用"
+                             ],
+        "source":  "23-24二年级下·河南许昌·期末"
+    },
+    {
+        "id":  "83",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "下表是二年级各班回收废旧电池的情况。![](images/223850.png)\n(2)全年级一共回收了( )节旧电池.\n(3)二(4)班比二(3)班多回收了( )节废旧电池。",
+        "options":  [
+
+                    ],
+        "answer":  "20;18;15;25 78 10",
+        "solution":  "【分析】(1)数一数即可知每个班级收集的废旧电池的节数。(2)把四个班级收集的废旧电池的节数加在一起,即可求出全年级一共回收了多少节旧电池。(3)用二(4)班收集的旧电池节数减去二(3)班收集的旧电池节数,即可求出二(4)班比二(3)班多回收了多少节废旧电池.\n\n【详解】(1)填表:二(1)20节,二(2)18节,二(3)15节,二(4)25节。(2)20+18+15+25=78(节),全年级一共回收了78节旧电池。(3)25-15=10(节),二(4)班比二(3)班多回收了10节废旧电池。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "24-25 二年级下·山东临沂·期末"
+    },
+    {
+        "id":  "84",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "下面的统计表记录的是二年级(2)班同学最喜欢吃的水果情况:![](images/223916.png)\n(1)二(2)班同学最喜欢吃( )的人最多,最喜欢吃( )的人最少.\n(2)你最喜欢吃( ),全班最喜欢吃这种水果的有( )人.\n(3)班里要开联欢会,请你根据调查结果,说说买哪几种水果合理。",
+        "options":  [
+
+                    ],
+        "answer":  "桔子;梨 葡萄;16 买桔子,葡萄和苹果合理。",
+        "solution":  "【分析】(1)通过比较最喜欢吃各种水果的人数,即可知喜欢吃哪种水果的人最多,喜欢吃哪种水果的人最少。(2)选择自己最喜欢吃的水果,并填上对应的人数即可。(答案不唯一)(3)购买喜欢人数较多的几种水果,才能满足多数同学的需求.\n\n【详解】(1)20\u003e16\u003e10\u003e6\u003e3,二(2)班同学最喜欢吃桔子的人最多,最喜欢吃梨的人最少。(2)你最喜欢吃葡萄,全班最喜欢吃这种水果的有16人。(答案不唯一)(3)买桔子,葡萄和苹果合理。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "22-23二年级下·新疆乌鲁木齐·期中"
+    },
+    {
+        "id":  "85",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "下面是二(1)班同学最喜欢吃的水果情况。(每人只选一种)![](images/223939.png)\n(2)最喜欢吃( )的人数最多,最喜欢吃( )的人数最少.\n(3)如果全班同学都参加了调查,那么二(1)班一共有( )人.\n(4)如果你去为班级买水果,根据调查情况应多买( ),请说明理由。",
+        "options":  [
+
+                    ],
+        "answer":  "21;9;5;8 苹果;梨 43 苹果;喜欢吃苹果的人最多",
+        "solution":  "【分析】(1)一个正字代表5,再根据统计表中的信息,分别数出苹果,桃,梨和香蕉的数量,完成统计表。(2)比较喜欢吃各种水果人数的多少,找出最多和最少的人数完成填空。(3)求喜欢吃各种水果的人数之和,即是二(1)班一共多少人。(4)根据喜欢各种水果的情况,多买一些同学们最爱吃的水果,写出自己的见解.\n\n【详解】(1)填表如下:苹果21人,桃9人,梨5人,香蕉8人。(2)21\u003e9\u003e8\u003e5,最喜欢吃苹果的人数最多,最喜欢吃梨的人数最少。(3)21+9+5+8=43(人),如果全班同学都参加了调查,二(1)班一共有43人。(4)答:如果为班级买水果,根据调查情况应多买苹果,因为喜欢吃苹果的人最多。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "24-25 二年级下·福建福州·期末"
+    },
+    {
+        "id":  "86",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "调查全班同学喜欢的运动项目如下表。![](images/224228.png)\n(1)参加( )的人数最多,参加( )的人数最少,参加这两项运动的人数相差( )人.\n(2)参加跳远和拍球的一共有( )人.\n(3)我最喜欢参加的项目是( ),全班喜欢这个项目的有( )人。",
+        "options":  [
+
+                    ],
+        "answer":  "跳绳;踢毽子;14 20 跳绳;18",
+        "solution":  "【分析】由题意可知:(1)把参加项目的人数从大到小排列,最大数对应的项目即是参加人数最多的项目,最小数对应的项目即是参加人数最少的项目;把最大数和最小数相减,即是参加这两项运动相差的人数;(2)把参加跳远和拍球的人数相加,即是一共的人数;(3)填出最喜欢参加的项目,在表格中找出全班喜欢这个项目的人数.\n\n【详解】(1)由分析可得:18\u003e16\u003e14\u003e6\u003e4,18-4=14(人),参加跳绳的人数最多,参加踢毽子的人数最少,参加这两项运动的人数相差14人。(2)6+14=20(人),参加跳远和拍球的一共有20人。(3)我最喜欢参加的项目是跳绳,全班喜欢这个项目的有18人。(答案不唯一)",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "24-25 二年级下·山东菏泽·期末"
+    },
+    {
+        "id":  "87",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "小哪吒统计了他们班里图书角中各类图书的数量,记录结果如下。文史类:正正正正正正正 科普类:正正正 动漫类:正正正正\n(1)根据上面的数据完成下表。![](images/224238.png)\n(2)图书角中( )数量最多.\n(3)如果要新添一些图书,你建议添加(填图书种类),原因:。",
+        "options":  [
+
+                    ],
+        "answer":  "30;15;20 文史类 科普类;科普类图书数量最少,需要补充(答案不唯一)",
+        "solution":  "【分析】(1)正字每一笔表示1本,数一数。(2)比较各类书数量即可求解。(3)可以添加比较少的书籍。合理即可.\n\n【详解】(1)填表:文史类30本,科普类15本,动漫类20本。(2)30\u003e20\u003e15,图书角中文史类数量最多。(3)如果要新添一些图书,我建议添加科普类,原因:科普类图书数量最少,需要补充。(答案不唯一)",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "24-25 二年级下·广东广州·期末"
+    },
+    {
+        "id":  "88",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "二(1)班投票选举班长,每人只能选一人,除了丽丽因生病请假外,其他所有同学都参与了投票,投票统计情况如下。![](images/224246.png)\n(1)根据上面统计的结果完成上面的统计表.\n(2)( )的票数最高,( )的票数最低,两人相差( )票.\n(3)二(1)一共有( )名学生.\n(4)如果丽丽也参与投票,最后谁当选班长。说说理由。",
+        "options":  [
+
+                    ],
+        "answer":  "12;20;16;5 洋洋;英英;15 54 最后洋洋当选班长。因为丽丽这一票不管投给谁,都是洋洋票数最高。",
+        "solution":  "【分析】(1)根据\"正\"字统计法,一画代表一票,一个\"正\"字是5画代表5票,多出来的有几画就算几票。据此计算。(2)把四个人的得票数从小到大排列出来就能找出得票最高和最低的票数,用最高票数-最低票数=两人相差票数。(3)四位同学的得票数加起来,再加请假的1人,即为全班人数.\n\n【详解】(1)亮亮:2个\"正\"字,加一个\"T\",2×5=10(票),10+2=12(票);洋洋:4个\"正\"字,5×4=20(票);林林:3个\"正\"字,加一个\"一\",3×5=15(票),15+1=16(票);英英:1个\"正\"字,是5票。填表:亮亮12票,洋洋20票,林林16票,英英5票。(2)5\u003c12\u003c16\u003c20,20-5=15(票),洋洋的票数最高,英英的票数最低,两人相差15票。(3)12+20+16+5+1=54(人),二(1)一共有54名学生。(4)如果丽丽也参与投票,最后洋洋当选班长;因为得票最高的是洋洋20票,排第二的是林林16票,如果丽丽也参加投票,即使她把票投给林林,林林最终17票还是低于洋洋的20票。所以丽丽这一票不管投给谁,都是洋洋票数最高。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "23-24 二年级下·山东日照·期中"
+    },
+    {
+        "id":  "89",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "请你开动脑筋,动手统计。下面是二(2)班同学最喜欢的图书统计情况。图 书漫 画科 技故 事历 史其 他人 数正 正 正正正 下正 一正 T\n(1)根据上面统计的结果把下面的统计表补充完整。![](images/224257.png)\n(2)二(2)班一共有( )人.\n(3)二(2)班喜欢( )书的人数最多,最多的比最少的多( )人.\n(4)你还能提出哪些数学问题并解答吗。",
+        "options":  [
+
+                    ],
+        "answer":  "5;7 41 漫画;10 喜欢故事书和喜欢历史书的一共有多少人。14人",
+        "solution":  "【分析】(1)\"正\"字计数法:\"正\"字一笔表示数量1,一个\"正\"字表示数量5,据此进行解答即可。根据观察最喜欢的图书统计情况可知,喜欢科技的有5人,喜欢其他的有7人,据此把统计表补充完整即可。(2)将喜欢各种图书的人数相加,即可得出二(2)班一共有多少人。(3)根据整数比较大小,对喜欢各种图书的人数进行比较,得出喜欢哪类书的人数最多。再用最多的人数减去最少的人数,求出最多的比最少的多的人数。(4)根据题干数学信息,结合学过的数学知识,提出问题并解答即可。本小题答案不唯一,例如:喜欢故事书和喜欢历史书的一共有多少人。用喜欢故事书的人数加上喜欢历史书的人数即可.\n\n【详解】(1)填表如下:漫画15人,科技5人,故事8人,历史6人,其他7人。(2)15+5+8+6+7=20+8+6+7=28+6+7=34+7=41人),二(2)班一共有41人。(3)15\u003e8\u003e7\u003e6\u003e5,15-5=10(人),二(2)班喜欢漫画书的人数最多,最多的比最少的多10人。(4)喜欢故事书和喜欢历史书的一共有多少人。(答案不唯一)8+6=14(人),答:喜欢故事书和喜欢历史书的一共有14人。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "\"提问题\"\"填条件\"问题",
+                                 "单式统计表的特点及填补",
+                                 "100以内数的连加运算"
+                             ],
+        "source":  "22-23 二年级下·新疆乌鲁木齐·期末"
+    },
+    {
+        "id":  "90",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "下面的统计表记录的是二年级(2)班同学最喜欢吃的水果情况:![](images/224305.png)\n(1)二(2)班同学最喜欢吃( )的人最多,最喜欢吃( )的人最少.\n(2)你最喜欢吃( ),全班最喜欢吃这种水果的有( )人.\n(3)班里要开联欢会,请你根据调查结果,说说买哪几种水果合理。",
+        "options":  [
+
+                    ],
+        "answer":  "桔子;梨 苹果;10(答案不唯一) 见详解",
+        "solution":  "【分析】(1)比较喜欢吃几种水果的人数,即可得出结论;(2)合理即可,示例:我最喜欢吃苹果,根据表格得出班里最喜欢吃这种水果的有多少人即可。(3)根据喜欢吃各种水果人数的多少提出买水果的建议,合理即可.\n\n【详解】(1)3\u003c6\u003c10\u003c16\u003c20,二(2)班同学最喜欢吃桔子的人数最多,最喜欢吃梨的人数最少。(2)我最喜欢吃苹果,班里最喜欢吃这种水果的有10人。(答案不唯一)(3)苹果,梨,香蕉,桔子,葡萄都要买,但桔子和葡萄多买些,梨和香蕉少买些。(答案不唯一)",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "22-23 二年级下·新疆乌鲁木齐·期末"
+    },
+    {
+        "id":  "91",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "二(1)班同学要去动物园游玩。下面是同学们最喜欢的一种动物的调查情况。![](images/224311.png)\n(1)最喜欢( )的人数最多,最喜欢( )的人数最少.\n(2)算一算,一辆限乘客40人的大巴车,够二(1)班的同学坐吗。\n(3)班主任李老师要安排各动物馆的游览时间,你有什么建议。",
+        "options":  [
+
+                    ],
+        "answer":  "孔雀;大象 够 可以安排游览孔雀馆和猴子馆的时间长点,大象馆的时间短点。(答案不唯一)",
+        "solution":  "【分析】(1)根据整数比较大小,即可得最喜欢哪种动物的人数最多,喜欢最哪种动物的人数最少。(2)根据加法的意义,将喜欢各种动物的人数相加,算出二(1)班有多少人,若人数小于40人,则够坐,若大于40人,则不够坐,据此解答即可。(3)根据喜欢的人数进行安排即可,本小题答案不唯一.\n\n【详解】(1)13\u003e10\u003e8\u003e6\u003e2,所以最喜欢孔雀的人数最多,最喜欢大象的人数最少。(2)6+2+8+10+13=8+8+10+13=16+10+13=26+13=39(人),39\u003c40,答:一辆限乘客40人的大巴车,够二(1)班的同学坐。(3)因为喜欢孔雀和猴子的人数比较多,所以可以安排游览孔雀馆和猴子馆的时间长点,喜欢大象的人数比较少,所以游览大象馆的时间短点。(本题答案不唯一)",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "20以内数的比大小",
+                                 "100以内数的连加运算"
+                             ],
+        "source":  "24-25二年级下·广西玉林·期末"
+    },
+    {
+        "id":  "92",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "如表所示是某地区六月份的天气情况,请你根据统计表中的信息回答问题。![](images/224317.png)\n(1)这个月中,天气情况最多的是( ),最少的是( ).\n(2)这个月中,晴天比雨天多( )天.\n(3)这个月中,一共有( )天没下雨。",
+        "options":  [
+
+                    ],
+        "answer":  "晴天;阴天 9 25",
+        "solution":  "【分析】(1)根据各个天气的天数进行比较大小即可;(2)根据减法的意义,用晴天的天数减去雨天的天数即可;(3)根据加法的意义,用晴天的天数加上多云的天数再加上阴天的天数即可求出这个月没有下雨的天数,据此解答即可.\n\n【详解】(1)14\u003e8\u003e5\u003e3,所以这个月中,天气情况最多的是晴天,最少的是阴天。(2)14-5=9(天),所以这个月中,晴天比雨天多9天。(3)14+8+3=25(天),所以这个月中,一共有25天没下雨。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "23-24 二年级下·天津和平·期末"
+    },
+    {
+        "id":  "93",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "下面是二年级同学在庆\"六一\"活动中,参加节目的人数情况。![](images/224333.png)\n(2)参加( )节目的人数最多,参加( )节目的人数最少.\n(3)参加唱歌的比参加跳舞的少( )人。",
+        "options":  [
+
+                    ],
+        "answer":  "19人;25人;13人;20人;8人 跳舞;演小品 6",
+        "solution":  "【分析】(1)依次数出参加每种节目的人数填表即可,\"正\"字的每一笔代表1人;(2)比较参加每种节目的人数,找到人数最多和最少的即可;(3)根据减法的意义,参加跳舞的人数-参加唱歌的人数=参加唱歌比参加跳舞少的人数.\n\n【详解】(1)表格填写如下:唱歌19人,跳舞25人,讲故事13人,弹琴20人,演小品8人。(2)25\u003e20\u003e19\u003e13\u003e8,参加跳舞节目的人数最多,参加演小品节目的人数最少。(3)25-19=6(人),参加唱歌的比参加跳舞的少6人。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "100以内数的比大小",
+                                 "两位数与两位数的退位减法"
+                             ],
+        "source":  "23-24 二年级下·广东东莞·期末"
+    },
+    {
+        "id":  "94",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "\"白色污染\"给我们的环境带来很大的危害,要尽量减少塑料袋的使用。二(1)班4个同学统计了自己家一周内塑料袋的使用情况。![](images/224351.png)\n(1)把统计结果填入表中。\n(2)( )家这一周使用的塑料袋最多,( )家这一周使用的塑料袋最少。\n(3)小刚家比小明家这一周少使用( )个塑料袋。\n(4)他们四家一共使用了( )个塑料袋。\n(5)根据上面的统计结果,你有什么建议。",
+        "options":  [
+
+                    ],
+        "answer":  "18;20;10;7;小云;小刚;11;55;尽量少使用塑料袋,多使用可以多次利用的购物袋。(答案不唯一)",
+        "solution":  "【分析】依次数出每家使用塑料袋的数量填表即可,\"正\"字的每一笔代表1个;(1)比较每家使用塑料袋的数量,找到数量最多和最少的即可;(2)根据减法的意义,小明家使用塑料袋的数量-小刚家使用塑料袋的数量=小刚家比小明家少使用的数量;(3)将每家使用塑料袋的数量相加,就是一共用的数量;(4)依据统计结果,结合生活常识去提出合理的建议即可.\n\n【详解】表格填写如下:小明家18个,小云家20个,天天家10个,小刚家7个。(1)20\u003e18\u003e10\u003e7,小云家这一周使用的塑料袋最多,小刚家这一周使用的塑料袋最少。(2)18-7=11(个),小刚家比小明家这一周少使用11个塑料袋。(3)18+20+10+7=55(个),他们四家一共使用了55个塑料袋。(4)我的建议:尽量少使用塑料袋,多使用可以多次利用的购物袋。(答案不唯一)",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "23-24 二年级下·重庆酉阳·期末"
+    },
+    {
+        "id":  "95",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "下面是3月份二(1)班同学在图书角借阅课外书的统计情况。![](images/224401.png)\n(1)根据上面的统计结果完成下面的表格。\n种类 连环画 故事书 科技书 作文书\n本数(本)\n(2)( )借得最多,( )最少,两种书相差( )本。",
+        "options":  [
+
+                    ],
+        "answer":  "30;12;20;6;连环画;作文书;24",
+        "solution":  "【分析】(1)一个一个地数,最后数到几就是几。正字的每一笔表示1本。(2)比较各种书的数量,然后用最多的减最少的即可.\n\n【详解】(1)填表:连环画30本,故事书12本,科技书20本,作文书6本。(2)6\u003c12\u003c20\u003c30,30-6=24(本),连环画借得最多,作文书最少,两种书相差24本。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "23-24 二年级下·浙江台州·期末"
+    },
+    {
+        "id":  "96",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "下面是二(1)班同学最喜欢的昆虫的统计情况。![](images/235942.png)\n(1)如果每人只能选其中一种昆虫,那么二(1)班共有( )人.\n(2)最喜欢( )的人数最多,最喜欢( )的比最喜欢( )的少( )人.\n(3)你还能提出其他数学问题并解答吗。",
+        "options":  [
+
+                    ],
+        "answer":  "40;蝴蝶;蜻蜓;蝴蝶;4(后3空答案不唯一);最喜欢蝴蝶的比最喜欢蜜蜂的多多少人。6人(答案不唯一)",
+        "solution":  "【分析】(1)根据加法的意义,将喜欢各种昆虫的人数相加,即可得出二(1)一共有多少人;(2)再根据20以内整数的排序,对喜欢各种昆虫的人数比较大小,据此解答即可。(3)根据题干的数学信息,结合学过的数学知识,提出问题并解答即可。例如:最喜欢蝴蝶的比最喜欢蜜蜂的多多少人。\n\n【详解】(1)8+12+10+4+6=20+10+4+6=30+4+6=34+6=40(人),所以二(1)班共有40人。(2)12\u003e10\u003e8\u003e6\u003e4,所以最喜欢蝴蝶的人数最多。12-8=4(人),所以最喜欢蜻蜓的比最喜欢蝴蝶的少4人。(后3空答案不唯一)(3)最喜欢蝴蝶的比最喜欢蜜蜂的多多少人。12-6=6(人),答:最喜欢蝴蝶的比最喜欢蜜蜂的多6人。(答案不唯一)",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "\"提问题\"\"填条件\"问题"
+                             ],
+        "source":  "23-24 二年级下·湖南岳阳·期末"
+    },
+    {
+        "id":  "97",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "在一次班干部选举中,有四名班长候选人,他们的得票如下。![](images/224415.png)\n(1)把统计结果填入表中。\n(2)( )的得票数最多,( )的得票数最少。\n(3)如果选一人为班长,选( )比较合适。\n(4)选举那天,王芳因病请假没能参加投票,如果她也投了票,结果会改变吗。为什么。",
+        "options":  [
+
+                    ],
+        "answer":  "7;12;8;15;亮亮;明明;亮亮;结果不会改变。因为跟亮亮最接近的是红红,红红再加1票是13票,还是小于15票的亮亮,所以结果不会改变。",
+        "solution":  "【分析】由题意可知:在统计过程中用到了正字统计法和符号统计法,\"正\"字每一画代表一票,一个\"正\"字代表5票,符合统计法,一个符号代表一票。据此解答.\n\n【详解】(1)明明得7个\"√\",故明明的票数为7;红红得2个\"正\"加\"T\",故红红的得票为5×2+2=12(票);兰兰得8个\"○\",故兰兰的票数为8;亮亮得3个\"正\"字,故亮亮的票数为:3×5=15(票)。填表:明明7票,红红12票,兰兰8票,亮亮15票。(2)7\u003c8\u003c12\u003c15,故亮亮的得票数最多,明明的得票数最少。(3)如果选一人为班长,会选得票最多的那个,亮亮得票最多,故选亮亮比较合适。(4)如果王芳也参加投票,无论她投给谁都不影响结果,因为跟亮亮的票数最接近的是红红,红红再加1票是13票,还是小于15票的亮亮,所以结果不会改变。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "20以内数的比大小"
+                             ],
+        "source":  "23-24 二年级下·浙江台州·期末"
+    },
+    {
+        "id":  "98",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "我是小小调查员。下面是某小学二年级(一)班的同学们最喜欢看的动画片的调查结果。![](images/224422.png)\n(1)你最喜欢看的动画片是( ).\n(2)喜欢看( )的人最多,喜欢看( )的人最少.\n(3)喜欢看( )和( )的人数一样多.\n(4)请你提出一个数学问题,并解答。",
+        "options":  [
+
+                    ],
+        "answer":  "熊出没(答案不唯一);熊出没;小鸡彩虹;小猪佩奇;托马斯和朋友;喜欢看小猪佩奇的和喜欢看小鸡彩虹的一共有多少人。(答案不唯一);26人",
+        "solution":  "【分析】(1)写出自己最喜欢看的动画片即可。(答案不唯一)(2)比较喜欢看各种不同动画片的人数,即可知道喜欢看什么动画片的人最多,喜欢看什么动画片的人最少。(3)比较喜欢看各种不同动画片的人数,即可知道喜欢看什么动画片和什么动画片的人数一样多。(4)根据条件提出问题,合理即可,如:喜欢看小猪佩奇的和喜欢看小鸡彩虹的一共有多少人。用喜欢看小猪佩奇的人数加上喜欢看小鸡彩虹的人数即可。(答案不唯一)\n\n【详解】(1)你最喜欢看的动画片是熊出没。(答案不唯一)(2)18\u003e16=16\u003e13\u003e10,喜欢看熊出没的人最多,喜欢看小鸡彩虹的人最少。(3)18\u003e16=16\u003e13\u003e10,喜欢看小猪佩奇和托马斯和朋友的人数一样多。(4)喜欢看小猪佩奇的和喜欢看小鸡彩虹的一共有多少人。(答案不唯一)16+10=26(人),答:喜欢看小猪佩奇的和喜欢看小鸡彩虹的一共有26人。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "\"提问题\"\"填条件\"问题"
+                             ],
+        "source":  "23-24 二年级下·河北张家口·期中"
+    },
+    {
+        "id":  "99",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "下面是二年级同学最喜欢的体育活动情况,根据调查结果完成统计表。![](images/224431.png)\n(1)根据调查结果,你认为本校应多准备哪种体育器材。\n(2)你还能提出其他数学问题并解答吗。",
+        "options":  [
+
+                    ],
+        "answer":  "24;14;22;25;9;乒乓球;喜欢踢毽的人数比喜欢跳绳的人数少多少。2人(答案不唯一)",
+        "solution":  "【分析】根据题目给出的统计结果,数出每项运动的喜爱人数,并填入表格中。按照100内的数比较大小:位数越多的数越大;位数相同时,十位上越大的数越大;十位上的数相同时,个位上越大的数越大,对喜欢每项运动的人数进行比较大小并从小到大排序。找出喜欢人数最多的体育项目,就是学校应多准备的体育器材。根据题目给出的信息,合理提出问题并解答即可。如:喜欢踢毽的人数比喜欢跳绳的人数少多少。根据减法的意义,喜欢跳绳的人数-喜欢踢毽的人数=喜欢踢毽比喜欢跳绳少的人数,列出算式算出答案即可解答.\n\n【详解】根据分析可知,喜欢跳绳的有24人,喜欢舞蹈的有14人,喜欢踢毽的有22人,喜欢乒乓球的有25人,喜欢其他的有9人。填入表格中如下图所示:跳绳24人,舞蹈14人,踢毽22人,乒乓球25人,其他9人。24,14,22,25,9五个数字中:9的位数最少,所以9最小;剩下的四个数中,14十位上的数最小,所以五个数中14第二小;24,22,25十位相同,个位上2\u003c4\u003c5,所以22\u003c24\u003c25;所以9\u003c14\u003c22\u003c24\u003c25,则喜欢乒乓球的人数最多,学校应多准备乒乓球的体育器材。喜欢踢毽的人数比喜欢跳绳的人数少多少。(答案不唯一)24-22=2(人),答:喜欢踢毽的人数比喜欢跳绳的人数少2人。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "\"提问题\"\"填条件\"问题"
+                             ],
+        "source":  "23-24 二年级下·河北邯郸·期末"
+    },
+    {
+        "id":  "100",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "下面是二(3)班同学喜欢的运动项目统计情况。![](images/224442.png)\n(1)把上面的统计结果填入下表中。项目足球篮球排球踢毽子人数\n(2)喜欢( )运动的人最多;喜欢( )运动的人最少.\n(3)如果让你给二(3)班买体育器材,你准备买什么。为什么。",
+        "options":  [
+
+                    ],
+        "answer":  "8;10;12;30;踢毽子;足球;我准备买毽子,因为喜欢踢毽子的人数最多,购买后能满足更多人的使用需求。",
+        "solution":  "【分析】(1)一个\"正\"字是5画,数\"正\"字即可知喜欢每个项目的人数。(2)通过比较喜欢不同项目的人数,即可知喜欢哪种运动的人最多,喜欢哪种运动的人最少。(3)喜欢哪种项目的人最多,就买哪种体育器材,购买后能满足更多人的使用需求.\n\n【详解】(1)通过数一数填表如下:足球8人,篮球10人,排球12人,踢毽子30人。(2)8\u003c10\u003c12\u003c30,喜欢踢毽子运动的人最多;喜欢足球运动的人最少。(3)我准备买毽子,因为喜欢踢毽子的人数最多,购买后能满足更多人的使用需求。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "23-24 二年级下·山东临沂·期末"
+    },
+    {
+        "id":  "101",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "选班长时有2名同学没投票,如果他们补投,( )影响选举结果。",
+        "options":  [
+                        "一定会",
+                        "一定不会",
+                        "可能会"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】将2名同学的投票给第二名,这时第二名能超过第一名则会影响选举结果,否则不会.\n\n【详解】由分析可知:选班长时有2名同学没投票,如果他们补投,可能会影响选举结果。故答案为:C",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "23-24二年级下·重庆丰都·期末"
+    },
+    {
+        "id":  "102",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "我们在班上用举手法调查最喜欢的老师时,下列做法错误的是( )。",
+        "options":  [
+                        "每位同学都要参加",
+                        "每位同学只能举一次",
+                        "班长可以举2次手"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】用举手法调查最喜欢的老师时,需要知道每个同学的想法,一个人举一次手即可表达自己的观点,据此解答.\n\n【详解】A。每位同学都要参加,正确;B。每位同学只能举一次,正确;C。班长可以举2次手,错误。做法错误的是:班长可以举2次手。故答案为:C",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "23-24二年级下·重庆丰都·期末"
+    },
+    {
+        "id":  "103",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "小希想用\u0027正\u0027字统计自己家在城市四月份的天气情况,画两个\u0027正\u0027字代表( )天。",
+        "options":  [
+                        "2",
+                        "5",
+                        "10"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】\u0027正\u0027字统计法是一种常用的计数方法。每个\u0027正\u0027字由5笔组成,因此一个\u0027正\u0027字代表5天,两个\u0027正\u0027字代表2个5天,由此解答.\n\n【详解】5×2=10(天),小希想用\u0027正\u0027字统计自己家在城市四月份的天气情况,画两个\u0027正\u0027字代表10天。故答案为:C",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "24-25二年级下·贵州黔西·期中"
+    },
+    {
+        "id":  "104",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "贵州某校开展了主题为\u0027青春\u0027碳\u0027路,\u0027绿\u0027动未来\u0027的文明出行活动。以下( )项调查,可以帮助我们了解该校学生践行\u0027绿色出行\u0027的情况。",
+        "options":  [
+                        "全校学生上(放)学出行方式的调查",
+                        "全校学生到校时间调查",
+                        "全校各年级学生人数调查"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】根据数据的搜集与整理,\u0027绿色出行\u0027指的是乘坐公交车,地铁,骑自行车等出行方式,由此即可解答.\n\n【详解】A。全校学生上(放)学出行方式的调查,涉及出行方式,正确;B。全校学生到校时间调查,不涉及出行方式,错误;C。全校各年级学生人数调查,不涉及出行方式,错误。故答案为:A",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "24-25二年级下·青海果洛·期中"
+    },
+    {
+        "id":  "105",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "陈老师想了解本班同学整体视力情况,他需要收集信息的对象是( )。",
+        "options":  [
+                        "本班男生",
+                        "本班女生",
+                        "本班所有学生",
+                        "本年级所有学生"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】根据题意,要调查本班同学的视力情况,故必须全面调查。逐项分析.\n\n【详解】A。按性别收集,不是全面调查;B。按性别收集,不是全面调查;C。是全面调查;D。范围太广,只需调查本班即可。陈老师想了解本班同学整体视力情况,他需要收集信息的对象是本班所有学生。故答案为:C",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "24-25二年级下·福建龙岩·期中"
+    },
+    {
+        "id":  "106",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "调查同学们喜欢课外书籍情况统计表。三(1)班里要办一个图书角,应该多买( )。种类故事书科技书漫画书连环画人数正正正正正正正一正1",
+        "options":  [
+                        "故事书",
+                        "科技书",
+                        "漫画书",
+                        "连环画"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】一笔表示一人,一个\u0027正\u0027字表示5个人,通过数数笔画数确定喜欢各种图书的人数,哪种图书喜欢的人数多,就应该多买哪种图书.\n\n【详解】通过统计可知:喜欢故事书的有10人,喜欢科技书的有15人,喜欢漫画书的有11人,喜欢连环画的有7人。因为15\u003e11\u003e10\u003e7,所以喜欢科技书的人数最多,应该多买一些科技书。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "24-25二年级下·湖南怀化·期中"
+    },
+    {
+        "id":  "107",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "二(3)班要从王兰,李红两位同学中选出一人同学担任学习委员,下面是全班三个组的投票记录。(每人只能投一票)![](images/1182.png)\n(1)三个组共有( )人投票.\n(2)把记录的结果填入下表。姓名王兰李红得票数\n(3)根据投票结果,应该选( )担任学习委员。",
+        "options":  [
+
+                    ],
+        "answer":  "47;27;20;王兰",
+        "solution":  "【分析】(1)根据题意,因为每人只能投一票,故将一组,二组和三组的投票加起来即可解答;(2)分别将王兰和李红在各组中的投票加起来即可解答;(3)谁得到的投票票数最多,谁就担任学习委员.\n\n【详解】(1)9+10+8+6+6+8=19+8+6+6+8=27+6+6+8=33+6+8=39+8=47(人),即三个组共有47人投票。(2)王兰:9+10+8=19+8=27(人),李红:6+6+8=12+8=20(人),填表如下:王兰27票,李红20票。(3)27\u003e20,根据投票结果,应该选王兰担任学习委员。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "23-24 二年级下·云南曲靖·期末"
+    },
+    {
+        "id":  "108",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "数据整理:二(1)班同学最喜欢的颜色统计如下:红色11人,黄色20人,蓝色18人,( )色人数最多,( )色人数最少。",
+        "options":  [
+
+                    ],
+        "answer":  "黄;红",
+        "solution":  "【分析】根据20以内的数比较大小:位数越多的数越大;位数相同时,十位上越大的数越大;十位上的数相同时,个位上越大的数越大。把统计结果进行比较大小,找出最大和最小的,即可解答.\n\n【详解】11,20,18三个数位数都相同,十位上1=1\u003c2,所以20是三个数中最大的一个;11和18十位上的数相同,个位上1\u003c8,则11\u003c18,则11是三个数中最小的。11\u003c18\u003c20,则黄色人数最多,喜欢红色人数最少。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "20以内数的比大小"
+                             ],
+        "source":  "24-25 二年级下·湖南长沙·期中"
+    },
+    {
+        "id":  "109",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "下面是二(3)班同学出生季节统计情况。![](images/1183.png)\n(1)完成上表.\n(2)在秋季出生的有( )人,比在春季出生的少( )人.\n(3)在春季和冬季出生的共有( )人.\n(4)在秋季出生的比在冬季出生的多( )人.\n(5)在( )季出生的比在( )季出生的多2人。",
+        "options":  [
+
+                    ],
+        "answer":  "27;10;12;7 12;15 34 5 秋;夏",
+        "solution":  "【分析】(1)根据数\u0027正\u0027字的方法完成表格即可;(2)根据统计的表格直接作答即可,根据减法的意义,用春季出生的人数减去秋季出生的人数即可;(3)根据加法的意义,用春季出生的人数加上冬季出生的人数即可;(4)根据减法的意义,用秋季出生的人数减去冬季出生的人数即可;(5)根据统计的表格可知,秋季出生人数12人,夏季出生人数10人,秋季出生的比夏季出生的多2人,据此解答.\n\n【详解】(1)如下所示:春季27人,夏季10人,秋季12人,冬季7人。(2)根据统计可知,在秋季出生的有12人;27-12=15(人),即秋季出生的比在春季出生的少15人。(3)27+7=34(人),即在春季和冬季出生的共有34人。(4)12-7=5(人),即在秋季出生的比在冬季出生的多5人。(5)12-10=2(人),即在秋季出生的比在夏季出生的多2人。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "十几减7,6的退位减法",
+                                 "两位数与两位数的不退位减法"
+                             ],
+        "source":  "23-24二年级下·内蒙古通辽·期中"
+    },
+    {
+        "id":  "110",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "中国的货币历史悠久,种类繁多。早期古代人使用贝壳、牛羊等实物作为货币,春秋战国时期主要使用刀币、布币、钱,秦统一中国后使用圆形方孔的半两钱,解决了货币不一、交流不便、不方便收拾等问题,北宋出现了世界上最早的纸币——交子,货币的演变体现了古代人民的聪明智慧。\n(1)生活中使用的货币形状有( )形和( )形。\n(2)为什么后来人们不用实物和铜钱,而改用纸币呢。",
+        "options":  [
+
+                    ],
+        "answer":  "长方;圆;因为实物和铜钱货币不一,交流不便,不方便收拾,不易携带,制造成本高。",
+        "solution":  "【分析】(1)长方形是长长方方的,有4条直直的边,对边相等;圆没有直直的边。结合生活实际可知,生活中使用的货币有纸币和硬币两种,其中纸币都是长方形的,硬币都是圆形的,据此解答即可。(2)根据题目给出的信息,不用实物作为货币是因为货币不一,交流不便,不方便收拾。不用铜钱的原因,可以在此基础上结合生活实际回答,如:不易携带,制造成本高,不方便大额交易等,言之有理即可.\n\n【详解】(1)根据分析可知,生活中使用的货币形状有长方形和圆形。(2)根据分析可知,因为实物和铜钱货币不一,交流不便,不方便收拾,不易携带,制造成本高等原因,而改用纸币。(答案不唯一)",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "长方形,正方形,三角形和圆的初步认识"
+                             ],
+        "source":  "23-24二年级下·重庆酉阳·期末"
+    },
+    {
+        "id":  "111",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "二(1)班同学最喜欢的运动统计如下:跳绳:正正正 足球:正正 篮球:正\n(1)喜欢跳绳的比足球多( )人.\n(2)最喜欢( )的人数最多。",
+        "options":  [
+
+                    ],
+        "answer":  "5;跳绳",
+        "solution":  "【分析】(1)依次数出喜欢每种运动的人数,\u0027正\u0027字的每一笔代表1人;根据减法的意义,喜欢跳绳的人数-喜欢足球的人数=喜欢跳绳比喜欢足球多的人数;(2)比较喜欢每种运动的人数,找到人数最多的即可.\n\n【详解】(1)喜欢跳绳的有15人;喜欢足球的有10人;喜欢篮球的有5人;15-10=5(人),喜欢跳绳的比足球多5人。(2)15\u003e10\u003e5,最喜欢跳绳的人数最多。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "24-25 一年级下·湖南岳阳·期中"
+    },
+    {
+        "id":  "112",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "下面是兴趣小组的同学们积累的有关数字的成语。![](images/1184.png)\n(1)把统计结果填入表中。\n(2)根据统计结果,如果让同学们再积累一些带数字的成语,你建议带数字( )的再多积累些。\n(3)如果把每个成语制成4张卡片发给班级的4个小组,那么带\"五\"字的成语需要制成( )张卡片。",
+        "options":  [
+
+                    ],
+        "answer":  "3;5;8;2;3;6;1;九;32",
+        "solution":  "【分析】(1)根据给出的成语,数出出现数字的个数,并填入表格中即可解答;(2)比较每个数字出现的个数的大小,按照从小到大排序,其中出现个数最小的那个数字就是需要增加积累的;(3)根据乘法的意义,每个成语需要制作的卡片数量×带有\u0027五\u0027成语的数量=需要制作的卡片数量,列出算式算出答案即可解答.\n\n【详解】(1)数出带有\u0027三\u0027的成语出现3个,带有\u0027四\u0027的成语出现5个,带有\u0027五\u0027的成语出现8个,带有\u0027六\u0027的成语出现2个,带有\u0027七\u0027的成语出现3个,带有\u0027八\u0027的成语出现6个,带有\u0027九\u0027的成语出现1个。填入表格中如下图所示:数字三有3个,四有5个,五有8个,六有2个,七有3个,八有6个,九有1个。(2)对出现的个数进行从小到大排序有:1\u003c2\u003c3=3\u003c5\u003c6\u003c8,可知,带有\u0027九\u0027的成语出现的个数最少,则建议带数字(九)的成语再多积累些。(3)4×8=32(张),所以带\u0027五\u0027字的成语需要制成32张。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "单式统计表的特点及填补"
+                             ],
+        "source":  "23-24二年级下·福建莆田·期末"
+    },
+    {
+        "id":  "113",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "下面是希望小学二(1)班同学最喜欢的乐器情况。![](images/1185.png)\n(1)把统计结果填入表中。\n(2)二(1)班同学最喜欢钢琴的人数比最喜欢架子鼓的少( )人。\n(3)二(1)班同学最喜欢吉他的人数比最喜欢鼓的多( )人。\n(4)二(1)班一共有( )人,如果班主任想选一种乐器作为本班特色,那么选( )(填序号)最合适。",
+        "options":  [
+
+                    ],
+        "answer":  "20;9;8;6;1;14;43;①",
+        "solution":  "【分析】(1)一个一个地数,最后数到几就是几。正字的每一笔代表1人。(2)用最喜欢钢琴的人数减最喜欢架子鼓的人数即可求解。(3)用最喜欢吉他的人数减最喜欢鼓的人数即可求解。(4)将每种人数相加即可。选最喜欢的人数最多的那种比较合适.\n\n【详解】(1)把二(1)班同学最喜欢的乐器情况填入下表中:乐器①20人,②9人,③8人,④6人。(2)9-8=1(人),二(1)班同学最喜欢②的人数比最喜欢③的少1人。(3)20-6=14(人),二(1)班同学最喜欢①的人数比最喜欢④的多14人。(4)20+9+8+6=29+8+6=37+6=43(人),6\u003c8\u003c9\u003c20,二(1)班一共有43人,如果班主任想选一种乐器作为本班特色,那么选①最合适。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "23-24 二年级下·湖南岳阳·期末"
+    },
+    {
+        "id":  "114",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "二(6)班小文调查本班同学最喜欢吃的蔬菜情况。(每人只能选一类)![](images/1186.png)\n(1)把统计结果填入表中。\n(2)最喜欢吃( )的人数最多,喜欢吃( )的人数最少。\n(3)二(6)班共有( )人。",
+        "options":  [
+
+                    ],
+        "answer":  "5;8;8;14;土豆;胡萝卜;35",
+        "solution":  "【分析】(1)依次数出喜欢吃每种蔬菜的人数填表即可,\u0027正\u0027字的每一笔代表1人;(2)比较喜欢吃每种蔬菜的人数即可解答;(3)将喜欢吃每种蔬菜的人数相加就是总人数.\n\n【详解】(1)表格填写如下:胡萝卜5人,白菜8人,茄子8人,土豆14人。(2)14\u003e8=8\u003e5,最喜欢吃土豆的人数最多,喜欢吃胡萝卜的人数最少。(3)5+8+8+14=35(人),二(6)班共有35人。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "23-24 二年级下·河南信阳·期末"
+    },
+    {
+        "id":  "115",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "下面是二年级2班参加兴趣活动人数的统计结果。![](images/093046.png)\n(1)喜欢( )兴趣活动的人数最多,喜欢( )兴趣活动的人数最少。\n(2)喜欢踢球的人数比喜欢跳舞的人数多( )人,喜欢游戏的人数比喜欢跳舞的人数少( )人。\n(3)二年级2班一共有( )人参加兴趣活动。",
+        "options":  [
+
+                    ],
+        "answer":  "踢球;游戏;5;1;52",
+        "solution":  "【分析】(1)数一数,依次是10人,16人,15人,11人,比较即可。(2)用喜欢踢球的人数减喜欢跳舞的人数即可;用喜欢跳舞的人数减喜欢游戏的人数即可。(3)将所有人数相加即可求解.\n\n【详解】(1)10\u003c11\u003c15\u003c16,喜欢踢球兴趣活动的人数最多,喜欢游戏兴趣活动的人数最少。(2)16-11=5(人),11-10=1(人),喜欢踢球的人数比喜欢跳舞的人数多5人,喜欢游戏的人数比喜欢跳舞的人数少1人。(3)10+16+15+11=26+15+11=41+11=52(人),二年级2班一共有52人参加兴趣活动。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "24-25二年级下·山东临沂·期中"
+    },
+    {
+        "id":  "116",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "![](images/1187.png)\n(1)填统计表.\n(2)售出的( )最多,( )最少.\n(3)售出的科技书和故事书相差( )本.\n(4)售出的科技书和连环画一共( )本。",
+        "options":  [
+
+                    ],
+        "answer":  "40;35;15;25 科技书;连环画 5 55",
+        "solution":  "【分析】(1)一个正字有5笔,表示5本,分别数出各种图书的本数,将数据填入表格即可;(2)比较统计表中四种图书数量的多少,即可知道一天内哪种书售出的数量最多,哪种书售出的数量最少;(3)用减法即可求出售出的科技书和故事书相差几本;(4)用加法即可求出售出的科技书和连环画一共有几本.\n\n【详解】(1)某儿童书店在一天内售书情况统计表:科技书40本,故事书35本,连环画15本,其他书25本。(2)40\u003e35\u003e25\u003e15,售出的科技书最多,连环画最少。(3)40-35=5(本),售出的科技书和故事书相差5本。(4)40+15=55(本),售出的科技书和连环画一共55本。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "100以内数的比大小",
+                                 "两位数与两位数的退位减法"
+                             ],
+        "source":  "23-24二年级下·天津河北·期末"
+    },
+    {
+        "id":  "117",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "端午节到了,下面是二(1)班同学最喜欢吃粽子记录单。![](images/1188.png)\n(2)喜欢吃( )的人最多,喜欢吃( )的人最少.\n(3)喜欢吃白水粽的人比喜欢吃枣子粽的多( )人.\n(4)一共调查了( )名学生。",
+        "options":  [
+
+                    ],
+        "answer":  "16;7;8;10 白水粽,豆沙粽 8 41",
+        "solution":  "【分析】(1)\u0027正\u0027字计数法:\u0027正\u0027字一笔表示数量1,一个\u0027正\u0027字表示数量5,数清楚喜欢各种粽子的人数,并将数字填入相对应的人数栏;(2)比较统计表中喜欢吃各种粽子人数的大小,然后得出结论;(3)用喜欢吃白水粽的人数减去喜欢吃枣子粽的人数,即可得出答案;(4)将统计表中喜欢各种粽子的人数相加即可得出答案.\n\n【详解】(1)把上面的整理结果填入下表:白水粽16人,豆沙粽7人,枣子粽8人,肉丁粽10人。(2)16\u003e10\u003e8\u003e7,喜欢吃白水粽的人最多,喜欢吃豆沙粽的人最少。(3)16-8=8(人),喜欢吃白水粽的人比喜欢吃枣子粽的多8人。(4)16+7+8+10=23+8+10=31+10=41(名),所以一共调查了41名学生。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "20以内数的比大小",
+                                 "100以内数的连加运算"
+                             ],
+        "source":  "23-24 二年级下·重庆潼南·期末"
+    },
+    {
+        "id":  "118",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "根据统计表填空。![](images/1189.png)\n喜欢( )的人数最多,喜欢香蕉的比苹果少( )人。",
+        "options":  [
+
+                    ],
+        "answer":  "橘子 4",
+        "solution":  "【分析】通过比较喜欢各种水果的人数,可知喜欢哪种水果的人数最多;用喜欢苹果的人数减去喜欢香蕉的人数,即可求出喜欢香蕉的比苹果少多少人.\n\n【详解】15\u003e12\u003e8,12-8=4(人),喜欢橘子的人数最多,喜欢香蕉的比苹果少4人。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "20以内数的比大小",
+                                 "十几减8的退位减法"
+                             ],
+        "source":  "24-25 二年级下·湖南湘潭·期中"
+    },
+    {
+        "id":  "119",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "下面是二(1)班女生最喜欢看的动画片统计情况(每人限选一种,每个表示1人).\n(1)完成下表。![](images/1190.png)\n(2)回答问题。①二(1)班一共有( )名女生。②最喜欢看( )的人最多,最喜欢看( )的人最少。",
+        "options":  [
+
+                    ],
+        "answer":  "5;6;10;6 ①27 ②《巧手鲁班》;《西游记》",
+        "solution":  "【分析】(1)因为每个表示1人,据此数清楚每种动画片的喜欢人数,将数据填入表格即可。(2)①要求二(1)班一共有多少名女生,将喜欢各种动画片的人数相加即可得出答案。②根据10以内整数的排序,找出喜欢人数最多和喜欢人数最少的动画片分别是什么.\n\n【详解】(1)填表:《西游记》5人,《神厨小福贵》6人,《巧手鲁班》10人,《大鱼海棠》6人。(2)①5+6+10+6=11+10+6=21+6=27(人),答:二(1)班一共有27名女生。②10\u003e6=6\u003e5,所以最喜欢看《巧手鲁班》的人最多,最喜欢看《西游记》的人最少。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "100以内数的比大小",
+                                 "100以内数的连加运算"
+                             ],
+        "source":  "24-25二年级下·山东济宁·期末"
+    },
+    {
+        "id":  "120",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "下面是四位同学统计的二(1)班学生课外兴趣爱好情况。![](images/1191.png)\n(1)二(1)班最喜欢( )的人最多,最喜欢( )的人最少.\n(2)最喜欢玩游戏的比最喜欢跳舞的多( )人.\n(3)二(1)班一共有( )人。",
+        "options":  [
+
+                    ],
+        "answer":  "22;6;10;7\n玩游戏;踢球 15 45",
+        "solution":  "【分析】先整理数据,一个一个地数,最后数到几就是几,然后把表格补充完整。(1)将各课外兴趣爱好的学生人数作比较即可求解。(2)用最喜欢玩游戏的人数减最喜欢跳舞的人数即可求解。(3)将各课外兴趣爱好的学生人数相加即可求解.\n\n【详解】填表如下:玩游戏22人,踢球6人,跳绳10人,跳舞7人。(1)22\u003e10\u003e7\u003e6,二(1)班最喜欢玩游戏的人最多,最喜欢踢球的人最少。(2)22-7=15(人),最喜欢玩游戏的比最喜欢跳舞的多15人。(3)22+6+10+7=28+10+7=38+7=45(人),二(1)班一共有45人。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "单式统计表的特点及填补",
+                                 "100以内数的比大小",
+                                 "100以内数的连加运算"
+                             ],
+        "source":  "24-25二年级下·山东临沂·期中"
+    },
+    {
+        "id":  "121",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "二(1)班举行评选班长的投票活动。投票当天,班上有2名同学生病请假,到校的每名同学都参与了投票而且只投一票,统计结果如下表。![](images/1192.png)\n(1)乐乐得了8票,用画\u0027正\u0027字的方法表示为.\n(2)全班一共有名同学,根据投票结果,会当选班长.\n(3)如果这2名生病的同学也参与投票,(填\u0027会\u0027或\u0027不会\u0027)影响评选结果。",
+        "options":  [
+
+                    ],
+        "answer":  "正下 38 小冬 不会",
+        "solution":  "【分析】(1)用画\u0027正\u0027字的方法表示时,\u0027正\u0027字的每一笔代表1票,一个\u0027正\u0027字表示5票;(2)将每人的得票数相加,计算出总票数,也就是投票的总人数,再加上请假的2人,就是全班的人数;比较每人得的票数,得票最多的会当选班长;(3)假如两名请假的同学都投给得票数第二的人,得到的票数如果超过第一名,则结果会改变,反之不会改变.\n\n【详解】(1)乐乐得了8票,用画\u0027正\u0027字的方法表示为正下。(2)8+5+10+13+2=38(人),13\u003e10\u003e8\u003e5,全班一共有38名同学,根据投票结果,小冬会当选班长。(3)得票数第二的是甜甜,10+2=12(票),12\u003c13,如果这2名生病的同学也参与投票,不会影响评选结果。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "24-25 二年级下·贵州黔西·期中"
+    },
+    {
+        "id":  "122",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "二(5)班投票选举班长(每人只能投一票),投票结果如下表。![](images/1193.png)\n②( )的得票数最多,( )的得票数最少,( )可能成为班长.\n③小丽比小平多得( )张票,小明比小丽少得( )张票.\n④一共有( )人参加投票。",
+        "options":  [
+
+                    ],
+        "answer":  "①10;16;21;47 ②小丽;小平;小丽 ③11;5 ④47",
+        "solution":  "【分析】①一笔一笔地数,一共数了多少笔就是多少张票。将三人的票数一起数,数出来的数就是合计的票数,据此把表格补充完整。②比较他们的票数,票数最多的可能成为班长。③用小丽的票数减小平的票数,求出小丽比小平多的票数;用小丽的票数减小明的票数,求出小明比小丽少的票数。④合计的票数是多少就有多少人参加投票.\n\n【详解】①填表:小平10票,小明16票,小丽21票,合计47票。②21\u003e16\u003e10,小丽的得票数最多,小平的得票数最少,小丽可能成为班长。③21-10=11(张),21-16=5(张),小丽比小平多得11张票,小明比小丽少得5张票。④一共有47人参加投票。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "100以内数的比大小",
+                                 "两位数与两位数的退位减法",
+                                 "100以内数的连加运算"
+                             ],
+        "source":  "24-25 二年级下·吉林松原·期中"
+    },
+    {
+        "id":  "123",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "超凡体育用品专卖店统计了上周销售各种球的数量。记录结果如下。![](images/1194.png)\n(1)把统计的结果填在表中。球的种类足球篮球排球橄榄球个数\n(2)根据统计结果,( )球销售的最多,( )球销售的最少.\n(3)销售的篮球比足球多( )个,销售的橄榄球比排球少( )个。",
+        "options":  [
+
+                    ],
+        "answer":  "15;21;13;9 篮;橄榄 6;4",
+        "solution":  "【分析】(1)依次数出每种球销售的数量填表即可;\u0027正\u0027字的每一笔代表1个;(2)比较每种球销售的数量,即可解答;(3)根据减法的意义,销售篮球的数量-销售足球的数量=销售篮球比足球多的数量;销售排球的数量-销售橄榄球的数量=销售橄榄球比销售排球少的数量.\n\n【详解】(1)表格填写如下:足球15个,篮球21个,排球13个,橄榄球9个。(2)21\u003e15\u003e13\u003e9,根据统计结果,篮球销售的最多,橄榄球销售的最少。(3)21-15=6(个),13-9=4(个),销售的篮球比足球多6个,销售的橄榄球比排球少4个。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "24-25二年级下·山东济南·期中"
+    },
+    {
+        "id":  "124",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "下面是二(1)班全体同学最喜欢的蔬菜情况统计表。![](images/119.png)\n(1)二(1)班共有( )人.\n(2)最喜欢吃( )的人数最多.\n(3)最喜欢吃豆角的人数比最喜欢吃黄瓜的人数少( )人。",
+        "options":  [
+
+                    ],
+        "answer":  "42 西红柿 3",
+        "solution":  "【分析】(1)依次数出最喜欢每种蔬菜的人数,相加就是总人数,\u0027正\u0027字的每一笔代表1人;(2)比较喜欢每种蔬菜的人数,找到人数最多的即可;(3)根据减法的意义,最喜欢吃黄瓜的人数-最喜欢吃豆角的人数=最喜欢吃豆角比最喜欢吃黄瓜少的人数.\n\n【详解】(1)最喜欢西红柿的有17人;最喜欢黄瓜的有11人;最喜欢胡萝卜的有6人;最喜欢豆角的有8人。17+11+6+8=42(人),二(1)班共有42人。(2)17\u003e11\u003e8\u003e6,最喜欢吃西红柿的人数最多。(3)11-8=3(人),最喜欢吃豆角的人数比最喜欢吃黄瓜的人数少3人。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "20以内数的比大小",
+                                 "100以内数的连加运算"
+                             ],
+        "source":  "24-25 二年级下·青海果洛·期中"
+    },
+    {
+        "id":  "125",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "小明用\u0027○\u0027记录班级同学的生日月份,3月份画了4个\u0027○\u0027,每个\u0027○\u0027代表2人,3月份过生日的有( )人。",
+        "options":  [
+
+                    ],
+        "answer":  "8",
+        "solution":  "【分析】用○的个数乘每个○代表的人数即可求解.\n\n【详解】4×2=8(人),3月份过生日的有8人。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "4的乘法口诀及应用"
+                             ],
+        "source":  "24-25 二年级下·山东临沂·期中"
+    },
+    {
+        "id":  "126",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "学校春季运动会要统计各班参赛人数,二(1)班用画\u0027正\u0027字记录跳绳比赛人数,共写了4个\u0027正\u0027字,参赛人数是( )人。",
+        "options":  [
+
+                    ],
+        "answer":  "20",
+        "solution":  "【分析】根据题意,\u0027正\u0027字的每一笔代表1人,一个\u0027正\u0027字代表5人,4个\u0027正\u0027字代表的人数,也就是4个5的和,用乘法计算.\n\n【详解】5×4=20(人),学校春季运动会要统计各班参赛人数,二(1)班用画\u0027正\u0027字记录跳绳比赛人数,共写了4个\u0027正\u0027字,参赛人数是20人。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "5的乘法口诀及应用"
+                             ],
+        "source":  "24-25 二年级下·山东济宁·期中"
+    },
+    {
+        "id":  "127",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "以下是二(2)班同学对最喜欢的课外活动的调查数据。![](images/1196.png)\n从数据可知,最喜欢( )的同学人数最多,最喜欢( )的同学人数最少。",
+        "options":  [
+
+                    ],
+        "answer":  "跳绳;踢毽子",
+        "solution":  "【分析】根据题意,比较喜欢每种课间活动的人数,找到人数最多和最少的即可。10以内数从大到小关系为:10\u003e9\u003e8\u003e7\u003e6\u003e5\u003e4\u003e3\u003e2\u003e1,由此比较.\n\n【详解】10\u003e9\u003e7\u003e6,从数据可知,最喜欢跳绳的同学人数最多,最喜欢踢毽子的同学人数最少。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "24-25 二年级下·黑龙江佳木斯·期中"
+    },
+    {
+        "id":  "128",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "投篮比赛。二(1)班:○○○○○○○○○○ 二(2)班:√√√√√√√√√ 二(3)班:▲▲▲▲▲▲▲ 二(4)班:正正正\n(1)请你将投篮结果填入下表:![](images/1197.png)(3)班二(4)班个数\n(2)班投中的个数最多,班投中的个数最少,两个班相差个。",
+        "options":  [
+
+                    ],
+        "answer":  "10;9;7;15 二;二;8",
+        "solution":  "【分析】(1)一个一个地数,最后数到几就是几个。正字的每一笔表示1个。据此把表格补充完整。(2)比较数据大小即可,然后用减法计算。20以内的数从小到大排列是:1\u003c2\u003c3\u003c4\u003c5\u003c6\u003c7\u003c8\u003c9\u003c10\u003c11\u003c12\u003c13\u003c14\u003c15\u003c16\u003c17\u003c18\u003c19\u003c20.\n\n【详解】(1)投篮结果填表如下:二(1)班10个,二(2)班9个,二(3)班7个,二(4)班15个。(2)15\u003e10\u003e9\u003e7,15-7=8(个),二(4)班投中的个数最多,二(3)班投中的个数最少,两个班相差8个。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "24-25 二年级下·内蒙古通辽·期中"
+    },
+    {
+        "id":  "129",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "二(1)班投票选班级班牌的颜色(下图),我认为选择( )色最合适。![](images/1198.png)",
+        "options":  [
+
+                    ],
+        "answer":  "蓝",
+        "solution":  "【分析】根据题意,比较选择每种颜色的人数,选择哪种颜色的人数最多,就用哪种颜色.\n\n【详解】16\u003e5\u003e4\u003e2,选择蓝色的人数最多,我认为选择蓝色最合适。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "24-25 二年级下·内蒙古通辽·期中"
+    },
+    {
+        "id":  "130",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "下面是六(1)班同学五一假期期间最想去游玩的风景区投票的统计情况(每人只能投一票)。六(1)班同学最想去游玩的风景区统计表:![](images/111.png)\n(1)全班共有( )人.\n(2)这个班最有可能去( )风景区游玩.\n(3)最想去普者黑风景区的人数比最想去人工湖的人数多( )人.\n(4)这个班最想去( )风景区和( )风景区的人数相同,都是( )人。",
+        "options":  [
+
+                    ],
+        "answer":  "60 普者黑 15 舍得草场 南国草原 10",
+        "solution":  "【分析】(1)将最想去各景区的人数相加,就是总人数;(2)比较最想去各景区的人数,哪种人数最多就最有可能去哪个景区游玩;(3)根据减法的意义,最想去普者黑风景区的人数-最想去人工湖的人数=最想去普者黑比最想去人工湖多的人数;(4)最想去舍得草场和南国草原的都是10人.\n\n【详解】(1)21+13+10+10+6=60(人),全班共有60人。(2)21\u003e13\u003e10=10\u003e6,这个班最有可能去普者黑风景区游玩。(3)21-6=15(人),最想去普者黑风景区的人数比最想去人工湖的人数多15人。(4)10=10,这个班最想去舍得草场风景区和南国草原风景区的人数相同,都是10人。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "24-25二年级下·重庆渝中·期中"
+    },
+    {
+        "id":  "131",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "二年级每个班要在\u0027花中四君子\u0027中选出一种花作为\u0027班花\u0027,下面是涵涵统计的全班同学最喜欢的\u0027班花\u0027的投票情况。梅花:○○○○○○○○○○○○ 兰花:△△△△△△△△ 翠竹:正正正 菊花:√√√√√√\n(1)把得票情况填入下表。![](images/1199.png)\n(2)最喜欢菊花的学生比最喜欢梅花的少人.\n(3)涵涵班一共有人;得票最多的是,得票最少的是。",
+        "options":  [
+
+                    ],
+        "answer":  "12;8;13;6 6 39;翠竹;菊花",
+        "solution":  "【分析】(1)依次数出喜欢每种花的数量,填表即可。\u0027正\u0027字的每一笔代表1票;(2)根据减法的意义,最喜欢梅花的人数-最喜欢菊花的人数=最喜欢菊花比最喜欢梅花少的人数;(3)将喜欢每种花的人数相加就是总人数;比较喜欢每种花的人数,即可得出票数最多和最少的.\n\n【详解】(1)表格填写如下:梅花12票,兰花8票,翠竹13票,菊花6票。(2)12-6=6(人),最喜欢菊花的学生比最喜欢梅花的少6人。(3)12+8+13+6=39(人),13\u003e12\u003e8\u003e6,涵涵班一共有39人;得票最多的是翠竹,得票最少的是菊花。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "24-25 二年级下·广东汕头·期中"
+    },
+    {
+        "id":  "132",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在创建\u0027书香校园\u0027活动中,张老师统计了二(1)班学生最喜欢的图书情况如图。![](images/11100.png)\n(1)二(1)班学生最喜欢绘本的有( )人,最喜欢历史的有( )人.\n(2)如果张老师打算给二(1)班购买一些书,根据调查结果,多买( )更合理。",
+        "options":  [
+
+                    ],
+        "answer":  "72 故事书",
+        "solution":  "【分析】(1)涂色的每个格代表1人,则依次数出最喜欢绘本和最喜欢历史的有几个格,也就是有几人;(2)数出喜欢每种图书的人数,比较人数的多少,最喜欢哪种图书的人数最多就多买哪种书.\n\n【详解】(1)二(1)班学生最喜欢绘本的有7人,最喜欢历史的有2人。(2)最喜欢故事书的有9人;最喜欢百科的有5人;9\u003e7\u003e5\u003e2,如果张老师打算给二(1)班购买一些书,根据调查结果,多买故事书更合理。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "10以内数的比大小"
+                             ],
+        "source":  "24-25 二年级下·陕西渭南·期中"
+    },
+    {
+        "id":  "133",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "三(1)班准备开联欢会,老师调查全班同学最喜欢的水果情况,调查当天有2名同学请假。调查完后,老师决定购买喜欢人数前三的水果,也就是草莓,菠萝,桔子。调查情况如下表:![](images/11101.png)\n这2名学生没有参与投票,( )老师买水果的种类。(填\u0027影响\u0027或\u0027不影响\u0027)",
+        "options":  [
+
+                    ],
+        "answer":  "不影响",
+        "solution":  "【分析】判断两名未参与投票学生是否影响购买水果种类,关键在于分析补票后\u0027喜欢人数前三\u0027的水果是否会发生变化,需从现有数据排名和极端补票情况进行推理.\n\n【详解】20\u003e14\u003e7\u003e2\u003e0,当前喜欢人数前三的水果依次为草莓,菠萝,桔子,第四名苹果和第五名香蕉与第三名桔子的差距分别为5人和7人。若两人均投票给苹果:2+2=4(人),仍低于桔子的7人,不影响前三排名。若两人均投票给香蕉:0+2=2(人),仍为最后一名,不影响前三。若两人均投票给桔子:7+2=9(人),仍为第3名,不改变前三格局。综上,这2名学生没有参与投票,不影响老师买水果的种类。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "24-25 三年级下·湖北襄阳·期中"
+    },
+    {
+        "id":  "134",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "下面是三(1)班部分同学体育达标测试成绩统计表。![](images/11102.png)\n(1)根据上面的数据分等级:优(90-100分),良(70-89分),合格(60-69分),女生得优的有( )人,合格的有( )人;男生得优的有( )人,得良的有( )人.\n(2)第1组一共有( )人。如果三(1)班正好可以分成这样的4个小组,那么三(1)班一共有( )人。",
+        "options":  [
+
+                    ],
+        "answer":  "1224 1248",
+        "solution":  "【分析】(1)根据统计表,以及等级划分的分数段,找出女生得优的几个,合格几个。男生得优的几人,得良几人即可。(2)数出女生和男生各有几个,再相加。就知道第一小组共几人。用小组人数乘4,就是三(1)班一共多少人.\n\n【详解】(1)根据统计表,女生得优的有1人,合格的有2人;男生得优的有2人,得良的有4人。(2)6+6=12(人),12×4=48(人),所以第1组一共有12人。如果三(1)班正好可以分成这样的4个小组,那么三(1)班一共有48人。",
+        "knowledge_points":  [
+                                 "单式统计表的特点及填补"
+                             ],
+        "source":  "24-25 三年级下·广东江门·期中"
+    },
+    {
+        "id":  "135",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "班级里同学们最喜欢的颜色调查结果如下:![](images/11103.png)\n(2)根据统计表,回答以下问题:①喜欢( )色的人数最多;喜欢( )色的人数最少。②喜欢蓝色的人数比喜欢绿色的人数少( )人;喜欢红色的人数比喜欢黄色的人数多( )人。③全班共有( )人参加了这次调查。",
+        "options":  [
+
+                    ],
+        "answer":  "22;7;10;5;红;黄;3;17;44",
+        "solution":  "【分析】(1)数一数即可知喜欢每种颜色的有多少人。(2)①通过(1)中统计表中的数据,比一比即可知喜欢哪种颜色的人数最多;喜欢哪种颜色的人数最少。②用喜欢绿色的人数减去喜欢蓝色的人数,即可求出喜欢蓝色的人数比喜欢绿色的人数少多少人;用喜欢红色的人数减去喜欢黄色的人数,即可求出喜欢红色的人数比喜欢黄色的人数多多少人。③把喜欢各种颜色的人数加在一起,即可求出全班共有多少人参加了这次调查.\n\n【详解】(1)填表:红色22人,蓝色7人,绿色10人,黄色5人。(2)①22\u003e10\u003e7\u003e5,喜欢红色的人数最多;喜欢黄色的人数最少。②10-7=3(人),22-5=17(人),喜欢蓝色的人数比喜欢绿色的人数少3人;喜欢红色的人数比喜欢黄色的人数多17人。③22+7+10+5=44(人),全班共有44人参加了这次调查。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "24-25 二年级下·广东广州·期中"
+    },
+    {
+        "id":  "136",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "下图是二(2)班三位候选人竞选班长的得票情况表,( )当选为班长。有2名同学因缺勤没参加投票,如果他们投票,结果( )改变(填\u0027会\u0027或\u0027不会\u0027)。![](images/11104.png)",
+        "options":  [
+
+                    ],
+        "answer":  "赵志;不会",
+        "solution":  "【分析】从表格可知每位候选人的票数,谁的票数高,谁就当选,再求出第一名和第二名的票数差距,如果大于2,则缺勤的人参与投票不会改变结果,若小于2,则可能改变投票结果.\n\n【详解】24\u003e12\u003e8,所以赵志票数最多,则赵志当选为班长;24-12=12(票),12票\u003e2票,所以赵志和李红两人的票数相差超过2票,所以缺勤的2名同学参加投票,结果不会改变。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "单式统计表的特点及填补"
+                             ],
+        "source":  "24-25 二年级下·浙江温州·期中"
+    },
+    {
+        "id":  "137",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "二(1)班同学最喜欢的颜色调查结果如下(每名同学只选一种):红色:12人 蓝色:8人 黄色:5人 绿色:7人\n最喜欢色的人数最多,最喜欢绿色的人数比蓝色少人。",
+        "options":  [
+
+                    ],
+        "answer":  "红;1",
+        "solution":  "【分析】先比较喜欢各种最喜欢颜色人数的多少,然后用最喜欢蓝色的人数减去最喜欢绿色的人数,求出差,即可解决.\n\n【详解】12\u003e8\u003e7\u003e5,8-7=1(人),即最喜欢红色的人数最多,最喜欢绿色的人数比蓝色少1人。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "24-25 二年级下·湖南长沙·期中"
+    },
+    {
+        "id":  "138",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "二(2)班准备去春游,下面是同学们最想去的地方的统计情况.\n科技馆:正正T;动物园:正正正;东湖:正下;植物园:正正\n(1)根据统计情况完成下表![](images/11105.png)\n(2)二(2)班想去( )的人数最多,想去( )的人数最少,想去科技馆的比想去东湖的多( )人,他们最有可能去( )玩。",
+        "options":  [
+
+                    ],
+        "answer":  "12;15;8;10 动物园;东湖;4;动物园",
+        "solution":  "【分析】(1)一笔一笔的数,最后数到几就是几人,正字的每一笔表示一人。(2)比较各类人数即可,最有可能去想去的人数最多的地方。用想去科技馆的人数减想去东湖的人数即可求出想去科技馆的比想去东湖的多多少人.\n\n【详解】(1)填表:科技馆12人,动物园15人,东湖8人,植物园10人。(2)8\u003c10\u003c12\u003c15,12-8=4(人),二(2)班想去动物园的人数最多,想去东湖的人数最少,想去科技馆的比想去东湖的多4人,他们最有可能去动物园玩。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "24-25 二年级下·山东济宁·期中"
+    },
+    {
+        "id":  "139",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "下图是格力空调销售情况统计表。星期( )和星期( )销售量相同。![](images/11106.png)",
+        "options":  [
+
+                    ],
+        "answer":  "二;三",
+        "solution":  "【分析】根据统计表中的信息,格力空调在星期二和星期三都卖了25台,所以星期二和星期三销售量相同.\n\n【详解】格力空调在星期二和星期三都卖了25台,所以星期二和星期三销售量相同。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "24-25 二年级下·广东珠海·期中"
+    },
+    {
+        "id":  "140",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "下面是星星调查的二(1)班同学的牙齿健康情况。![](images/11107.png)\n(2)有蛀牙的有( )人,二(1)班一共有( )人。",
+        "options":  [
+
+                    ],
+        "answer":  "26;9;6;3;18;44",
+        "solution":  "【分析】(1)一个一个地数,最后数到几就是几。正字的每一笔表示1个人。(2)用1颗蛀牙的人数加2颗蛀牙的人数再加3颗蛀牙的人数即可求出有蛀牙的人数。用有蛀牙的人数加没有蛀牙的人数就是二(1)班的总人数.\n\n【详解】(1)根据记录情况填写下表:没有蛀牙26人,1颗蛀牙9人,2颗蛀牙6人,3颗蛀牙3人。(2)9+6+3=18(人),18+26=44(人),有蛀牙的有18人,二(1)班一共有44人。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "24-25 二年级下·河南南阳·期中"
+    },
+    {
+        "id":  "141",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "二(2)班同学准备去春游,下面是同学们最想去的地方的统计情况。![](images/11108.png)\n(2)根据以上信息,想一想,填一填。①二(2)班想去( )的人数最多,想去( )的人数最少。②想去动物园的比想去东湖的多( )人。③估计一下,他们最有可能去( )玩。",
+        "options":  [
+
+                    ],
+        "answer":  "10;14;6;9;动物园;东湖;8;动物园",
+        "solution":  "【分析】(1)正字每一笔表示一人,数一数即可求解。(2)20以内的数从小到大排列是:1\u003c2\u003c3\u003c4\u003c5\u003c6\u003c7\u003c8\u003c9\u003c10\u003c11\u003c12\u003c13\u003c14\u003c15\u003c16\u003c17\u003c18\u003c19\u003c20。比较即可求解。用想去动物园的人数减想去东湖的人数即可求出想去动物园的比想去东湖的多多少人。最有可能去想去的人最多的地方玩.\n\n【详解】(1)根据统计情况完成下表:磨山10人,动物园14人,东湖6人,植物园9人。(2)6\u003c9\u003c10\u003c14,①二(2)班想去动物园的人数最多,想去东湖的人数最少。②14-6=8(人),想去动物园的比想去东湖的多8人。③估计一下,他们最有可能去动物园玩。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "24-25 二年级下·河南信阳·期中"
+    },
+    {
+        "id":  "142",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "用画\u0027正\u0027字法统计票数时,一个\u0027正\u0027字代表一票。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】\u0027正\u0027字计数法:\u0027正\u0027字一笔表示数量1,一个\u0027正\u0027字代表5,据此进行解答即可.\n\n【详解】据分析可知:用画\u0027正\u0027字法统计票数时,一个\u0027正\u0027字代表5票。原题说法错误。故答案为: ×",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "23-24二年级下·湖南常德·期中"
+    },
+    {
+        "id":  "143",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "判断题",
+        "difficulty":  0.65,
+        "question":  "统计人数时,一个\u0027正\u0027字代表5人。( )",
+        "options":  [
+
+                    ],
+        "answer":  "√",
+        "solution":  "【分析】用画\u0027正\u0027字统计数据时,1个\u0027正\u0027字有5画,代表5个被统计的量.\n\n【详解】由分析得:统计人数时,一个\u0027正\u0027字代表5人,原题说法正确。故答案为:√",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "24-25 二年级下·湖南湘潭·期中"
+    },
+    {
+        "id":  "144",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "安安想统计全班同学最喜欢哪个季节,可以用统计表来呈现统计数据。( )",
+        "options":  [
+
+                    ],
+        "answer":  "√",
+        "solution":  "【分析】统计表是一种常用的数据呈现工具,特别适合用于分类数据的整理和展示。例如,安安可以制作一个简单的表格,列出\u0027季节\u0027(如春,夏,秋,冬)和对应的\u0027喜欢人数\u0027,这样就能清晰地看出全班同学对每个季节的偏好分布,据此解答.\n\n【详解】安安想统计全班同学最喜欢哪个季节,可以用统计表来呈现统计数据。故答案为:√",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "24-25二年级下·贵州黔西·期中"
+    },
+    {
+        "id":  "145",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "统计数据时必须用写\u0027正\u0027字的方法。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】整理原始数据时的方法很多,如可以用画\u0027正\u0027字的方法,可以用画\u0027√\u0027的方法,也可以用画\u0027△\u0027的方法等等,据此判断.\n\n【详解】据分析可知:整理原始数据时的方法很多,所以本题\u0027统计数据时必须用写\u0027正\u0027字的方法\u0027说法错误。故答案为: ×",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "24-25 二年级下·内蒙古通辽·期中"
+    },
+    {
+        "id":  "146",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "数据整理时,用\u0027正\u0027字记录法最方便。( )",
+        "options":  [
+
+                    ],
+        "answer":  "√",
+        "solution":  "【分析】用\u0027正\u0027字记录数据是一种常见的简便方法。\u0027正\u0027字每一笔代表一个数据,每个\u0027正\u0027字有5画,每记录一个数据就添一笔,最后通过数\u0027正\u0027字的数量快速得出总数.\n\n【详解】由分析可知:数据整理时,用\u0027正\u0027字记录法最方便。故答案为:√",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "24-25 二年级下·湖南长沙·期中"
+    },
+    {
+        "id":  "147",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "用\u0027正\u0027字统计四月份天气情况,一个\u0027正\u0027字代表5天。( )",
+        "options":  [
+
+                    ],
+        "answer":  "√",
+        "solution":  "【分析】用\u0027正\u0027统计四月份的天气情况,一个\u0027正\u0027有5笔,1笔代表1天,据此解答.\n\n【详解】一个\u0027正\u0027字有5笔,所以一个\u0027正\u0027字代表5天,原题说法正确。故答案为:√",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "24-25 二年级下·河南三门峡·期中"
+    },
+    {
+        "id":  "148",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "下面是二(3)班同学喜欢的运动项目统计情况。![](images/11109.png)\n(1)把上面的统计结果填入下表中。项目足球篮球排球踢毽子人数\n(2)喜欢( )运动的人最多;喜欢( )运动的人最少.\n(3)如果让你给二(3)班买体育器材,你准备买什么。为什么。",
+        "options":  [
+
+                    ],
+        "answer":  "8;10;12;30;踢毽子;足球;我准备买毽子,因为喜欢踢毽子的人数最多,购买后能满足更多人的使用需求。",
+        "solution":  "【分析】(1)一个\u0027正\u0027字是5画,数\u0027正\u0027字即可知喜欢每个项目的人数。(2)通过比较喜欢不同项目的人数,即可知喜欢哪种运动的人最多,喜欢哪种运动的人最少。(3)喜欢哪种项目的人最多,就买哪种体育器材,购买后能满足更多人的使用需求.\n\n【详解】(1)通过数一数填表如下:足球8人,篮球10人,排球12人,踢毽子30人。(2)8\u003c10\u003c12\u003c30,喜欢踢毽子运动的人最多;喜欢足球运动的人最少。(3)我准备买毽子,因为喜欢踢毽子的人数最多,购买后能满足更多人的使用需求。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "23-24 二年级下·山东临沂·期末"
+    },
+    {
+        "id":  "149",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "做统计:下面是二(1)班学生春游最喜欢去的地方情况调查。![](images/11110.png)\n(1)根据上面统计的结果填表。\n地点 西和小镇 莲麻小镇 国医小镇\n人数 6\n(2)一共有( )人参加了调查统计。\n(3)最喜欢去( )的人最多。\n(4)你能根据上面的数学信息提出数学问题并解答吗。问题:________。解答:________。",
+        "options":  [
+
+                    ],
+        "answer":  "21;9;36;莲麻小镇;最喜欢去莲麻小镇的比最喜欢去西和小镇的多几人。(答案不唯一);21-6=15(人)",
+        "solution":  "【分析】(1)依次数出最喜欢去每个地方的人数,填表即可。\u0027正\u0027字的每一笔代表1人;(2)将最喜欢每个地方的人数相加,就是总人数;(3)比较最喜欢去每个地方的人数,找到人数最多的即可;(4)提出的问题符合题意即可,可提出最喜欢去莲麻小镇的比最喜欢去西和小镇的多几人。用减法计算.\n\n【详解】(1)表格填写如下:西和小镇6人,莲麻小镇21人,国医小镇9人。(2)6+21+9=36(人),一共有36人参加了调查统计。(3)21\u003e9\u003e6,最喜欢去莲麻小镇的人最多。(4)问题:最喜欢去莲麻小镇的比最喜欢去西和小镇的多几人。(答案不唯一)解答:21-6=15(人),答:最喜欢去莲麻小镇的比最喜欢去西和小镇的多15人。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "\"提问题\"\"填条件\"问题"
+                             ],
+        "source":  "23-24 二年级下·广东广州·期末"
+    },
+    {
+        "id":  "150",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "我是小小调查员。下面是李红同学统计的本班同学最喜欢哪一季节的情况。![](images/11111.png)\n(1)把记录的结果填在下表中。\n季节 春 夏 秋 冬\n人数\n(2)喜欢( )季的人数最多,喜欢( )季的人数最少。\n(3)我最喜欢( )季,全班喜欢这个季节的有( )人。\n(4)如果安排同学们去游玩,最好安排在哪个季节。",
+        "options":  [
+
+                    ],
+        "answer":  "22;13;7;3;春;冬;夏;13(本题答案不唯一);春季",
+        "solution":  "【分析】(1)根据数据记录的方法,一般采用画\u0027正\u0027字的方法,一个\u0027正\u0027字表示5人,根据记录单完成统计表。(2)根据整数比较大小,将喜欢各个季节的人数进行比较大小,据此即可得出喜欢什么的人数最多,喜欢什么的人数最少。(3)根据自己的喜好回答问题,并结合表格找出喜欢同一季节的人物即可。(4)如果组织同学们去游玩,选择喜欢人数最多的季节即可。据此解答即可.\n\n【详解】(1)把记录的结果填在下表中:春季22人,夏季13人,秋季7人,冬季3人。(2)22\u003e13\u003e7\u003e3,所以喜欢春季的人数最多,喜欢冬季的人数最少。(3)我最喜欢夏季,全班喜欢这个季节的有13人。(4)因为喜欢春季的人数最多,所以如果安排同学们去游玩,最好安排在春季。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "100以内数的比大小"
+                             ],
+        "source":  "23-24 二年级下·河北邢台·期中"
+    },
+    {
+        "id":  "151",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "下面是二年级二班同学1分钟跳绳成绩的统计表。![](images/11112.png)\n(1)请问这个班一共有多少人。\n(2)成绩在120-149的人数是多少。\n(3)你还能提出什么数学问题并解答。",
+        "options":  [
+
+                    ],
+        "answer":  "63人;47人;成绩在140-149的人数比成绩在150及以上的人数多多少人。21-5=16(人)(答案不唯一)",
+        "solution":  "【分析】(1)把二年级二班同学1分钟跳绳各成绩段的人数相加,即可求出这个班一共有多少人;(2)把成绩在120-149的人数相加,即可解答;(3)二年级二班同学1分钟跳绳成绩的统计表,提出合理数学问题即可。成绩在140-149的人数比成绩在150及以上的人数多多少人。用成绩在140-149的人数减去成绩在150及以上的人数,即可解答.\n\n【详解】(1)11+7+19+21+5=18+19+21+5=37+21+5=58+5=63(人),答:这个班一共有63人。(2)7+19+21=26+21=47(人),答:成绩在120-149的人数是47人。(3)成绩在140-149的人数比成绩在150及以上的人数多多少人。21-5=16(人),答:成绩在140-149的人数比成绩在150及以上的人数多16人。(答案不唯一)",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "\"提问题\"\"填条件\"问题",
+                                 "单式统计表的特点及填补",
+                                 "100以内数的连加运算"
+                             ],
+        "source":  "23-24三年级下·广东湛江·期末"
+    },
+    {
+        "id":  "152",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "老师带二(3)班同学统计一个路口10分钟内所通过的各种交通工具的数量,其中4位同学统计情况如下。![](images/11113.png)\n(1)把统计结果填入表中。\n(2)这个路口10分钟内通过的( )车最多,( )车最少。\n(3)如果再观察10分钟,哪种车通过的数量最多。请说明理由。",
+        "options":  [
+
+                    ],
+        "answer":  "7;5;19;12;小轿;大巴;小轿车;见详解",
+        "solution":  "【分析】(1)正字每一笔表示一辆车,数一数。(2)比较数据大小即可。20以内的数从小到大排列是:1\u003c2\u003c3\u003c4\u003c5\u003c6\u003c7\u003c8\u003c9\u003c10\u003c11\u003c12\u003c13\u003c14\u003c15\u003c16\u003c17\u003c18\u003c19\u003c20。(3)根据统计表中10分钟内通过不同车的数量,即可预测下一个10分钟,通过哪种车多.\n\n【详解】(1)填一填:面包车7辆,大巴车5辆,小轿车19辆,摩托车12辆。(2)5\u003c7\u003c12\u003c19,这个路口10分钟内通过的小轿车最多,大巴车最少。(3)根据这10分钟的统计结果,推断再过10分钟小轿车通过的数量可能最多。因为统计的10分钟内通过的小轿车最多。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "23-24 二年级下·广东揭阳·期末"
+    },
+    {
+        "id":  "153",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "下面是果果记录的一个月的天气情况。![](images/11114.png)\n(2)这个月一共有( )天.\n(3)晴天比雪天多几天。",
+        "options":  [
+
+                    ],
+        "answer":  "15;12;4;31;11",
+        "solution":  "【分析】根据题图,用正字表示天数,正表示5天,一个笔画表示1天。3个正表示天数,3×5=15,2个正和2画表示天数,2×5+2=12,4画表示4天,这个月的总天数用这三种天气的天数相加;晴天比雪天的天数=晴天的天数-雪天的天数,据此解答.\n\n【详解】(1)把记录的结果填在下表中:晴15天,阴12天,雪4天。(2)15+12+4=31(天),这个月一共有31天。(3)15-4=11(天),答:晴天比雪天多11天。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "23-24二年级下·浙江嘉兴·期末"
+    },
+    {
+        "id":  "154",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "下面是某班同学的出生季节的情况,把表补充完整。![](images/11115.png)\n(1)( )季出生的人最多.\n(2)夏季出生的比春季出生的少几人。\n(3)这个班一共有几人。",
+        "options":  [
+
+                    ],
+        "answer":  "13;11;14;7;秋;2人;45人",
+        "solution":  "【分析】根据一个\u0027正\u0027字表示5人,补全表格;①比较表格中的数据即可得出哪个季节出生的人最多;②用春季出生的人数减去夏季出生的人数即可。③要求这个班一共有几个人,将四个季节的出生人数相加,据此解答即可.\n\n【详解】春正正下(13)人,夏正正一(11)人,秋正正正(14)人,冬正T(7)人。(1)14\u003e13\u003e11\u003e7,所以秋季出生的人最多。(2)13-11=2(人),答:夏季出生的比春季出生的少2人。(3)13+11+14+7=24+14+7=38+7=45(人),答:这个班一共有45人。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "20以内数的比大小",
+                                 "100以内数的连加运算"
+                             ],
+        "source":  "23-24二年级下·河北邯郸·期末"
+    },
+    {
+        "id":  "155",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "下面是某书店连续5天卖出连环画和故事书的数量情况.\n(1)将卖故事书的数量情况统计表填写完整。![](images/11116.png)\n(2)书店5天一共卖出( )本连环画.\n(3)星期( )和星期( )卖出的连环画同样多。星期( )卖出的连环画和故事书同样多。",
+        "options":  [
+
+                    ],
+        "answer":  "6;6;8;11;40;二;四;五",
+        "solution":  "【分析】(1)依次数出每天卖出故事书的数量填表即可,\u0027正\u0027字的每一笔代表1本;(2)将每天卖出连环画的数量相加,就是一共卖出的数量;(3)比较这5天卖出连环画的数量,找出数量相同的即可;将每天卖出连环画的数量和故事书的数量相比较,找出数量相同的即可.\n\n【详解】(1)表格填写如下:星期一6本,星期二6本,星期三8本,星期四11本。(2)连环画:星期一卖出6本;星期二卖出7本;星期三卖出9本;星期四卖出7本;星期五卖出11本;6+7+9+7+11=40(本),书店5天一共卖出40本连环画。(3)连环画:11\u003e9\u003e7=7\u003e6,星期一:故事书卖出4本;连环画卖出6本;不相同;星期二:故事书卖出6本;连环画卖出7本;不相同;星期三:故事书卖出6本;连环画卖出9本;不相同;星期四:故事书卖出8本;连环画卖出7本;不相同;星期五:故事书卖出11本;连环画卖出11本;相同;星期二和星期四卖出的连环画同样多。星期五卖出的连环画和故事书同样多。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "23-24二年级下·浙江舟山·期末"
+    },
+    {
+        "id":  "156",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "二(2)班全班同学要从右面三名同学中选出一名同学参加演讲比赛,每人只能投1票,投票情况如图。![](images/11117.png)\n(1)根据投票结果,应该选( )参加演讲比赛.\n(2)有2名同学缺勤没能投票,如果他们也投了票,结果会改变吗。为什么。",
+        "options":  [
+
+                    ],
+        "answer":  "黄霏霏;会;理由见详解",
+        "solution":  "【分析】(1)先根据投票情况,数出三位同学的得票数量。再根据位数越多的数越大,位数相同时,十位上越大的数越大,十位上的数相同时,个位上越大的数越大。比较三位同学得票数量的大小,选出得票数量最大的同学参加演讲比赛即可。(2)计算出淘淘和依依分别与黄霏霏票数的差距,如果票数差距大于2,则两名缺勤的同学投票不会影响结果;如果票数差距小于或等于2,则两名同学的投票结果可能会导致同学的排名发生改变,从而影响结果。比如,两票都给依依,则依依的票数会比黄霏霏多,此时依依会变成票数最高的;一票给依依,一票给淘淘,则依依的票数会和黄霏霏一样多,此时黄霏霏和依依都是票数最高的.\n\n【详解】(1)根据投票结果可知,黄霏霏13票,淘淘10票,依依12票。13,10,12三个数,十位上都相同,个位上0\u003c2\u003c3,则10\u003c12\u003c13。可知,黄霏霏的票数最多,应该选黄霏霏参加演讲比赛。(2)黄霏霏和淘淘票数差距为:13-10=3(票),黄霏霏和依依票数差距为:13-12=1(票),黄霏霏和依依票数差距仅为1会小于2,根据分析可知缺勤的2名同学投票会改变结果,因为票数最高的人可能会发生改变。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "23-24 二年级下·广东东莞·期末"
+    },
+    {
+        "id":  "157",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "下面是一家超市一周内销售果汁的情况,请回答下列问题。![](images/11118.png)\n(1)把统计结果填入表中。\n(2)一周内一共销售果汁( )箱,( )种果汁销售量最多,它比销售量最少的果汁多销售( )箱。\n(3)请你根据调查结果,说说下周超市怎样进货更为合理,写出你的建议。",
+        "options":  [
+
+                    ],
+        "answer":  "7;15;9;8;2;41;B;13;见详解",
+        "solution":  "【分析】(1)依次数出每种口味的果汁销售的数量填表即可,\u0027正\u0027字的每一笔代表1箱;(2)将每种口味果汁销售的数量相加就是总数量;比较每种果汁销售的数量,找出最多的和最少的,相减即可计算出最多的比最少的多几箱;(3)根据比较的结果,哪种销售的多可多进一些,销售的少可少进一些,合理即可.\n\n【详解】(1)填表:A7箱,B15箱,C9箱,D8箱,E2箱。(2)7+15+9+8+2=22+9+8+2=31+8+2=39+2=41箱),15\u003e9\u003e8\u003e7\u003e2,15-2=13(箱),即一周内一共销售果汁41箱,B种果汁销售量最多,它比销售量最少的果汁多销售13箱。(3)建议:B口味的果汁销售数量最多,应该多购进一些,E口味的果汁销售的数量最少,应该少购进一些。(答案不唯一)",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "单式统计表的特点及填补",
+                                 "20以内数的比大小",
+                                 "100以内数的连加运算"
+                             ],
+        "source":  "23-24 二年级下·广东东莞·期中"
+    },
+    {
+        "id":  "158",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "根据二(1)班同学参加课外小组的情况,完成下表并填空。![](images/11119.png)\n(1)把统计结果填入表中。\n(2)舞蹈小组去掉10人后,和( )小组的人数同样多。\n(3)如果每人只参加1个课外小组,则二(1)班共有( )人。\n(4)你还能提出什么数学问题,并解答。",
+        "options":  [
+
+                    ],
+        "answer":  "20;10;5;4;2;体操;40;参加音乐小组的人数和参加美术小组的人数一共有多少人。5+2=7(人)(答案不唯一)",
+        "solution":  "【分析】(1)数出表格中每类课外小组参与人员的数量,将数据填入对应的表格中即可解答;(2)根据减法的意义,舞蹈小组的人数-10=舞蹈小组去掉10个人后的数量,找出此时和哪个小组的人数相同即可解答;(3)根据加法的意义,参与舞蹈小组的人数+参与体操小组的人数+参与音乐小组的人数+参与篮球小组的人数+参与美术小组的人数=班上一共的人数,列出算式算出答案即可解答;(4)根据题目给出的信息,提出一个合理的问题即可。如:参加音乐小组的人数和参加美术小组的人数一共有多少人。根据加法的意义,参加音乐小组的人数+参加美术小组的人数=参加两组课外小组的总人数,列出算式算出答案即可解答.\n\n【详解】(1)参加舞蹈小组的有20人,参加体操小组的有10人,参加音乐小组的有5人,参加篮球小组的有4人,参加美术小组的有2人。把数据填入表格中:舞蹈20人,体操10人,音乐5人,篮球4人,美术2人。(2)20-10=10(人),舞蹈小组去掉10人后,和体操小组的人数同样多。(3)20+10+5+4+2=30+5+4+2=35+4+2=39+2=40(人),则二(1)班共有40人。(4)参加音乐小组的人数和参加美术小组的人数一共有多少人。5+2=7(人),答:参加音乐小组的人数和参加美术小组的人数一共有7人。(答案不唯一)",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "\"提问题\"\"填条件\"问题"
+                             ],
+        "source":  "23-24 二年级下·山东临沂·期末"
+    },
+    {
+        "id":  "159",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "在第35个\u0027全国爱牙日\u0027,学校开展了\u0027牙齿健康,口腔美丽\u0027主题宣传活动。二一班的李老师对全班学生进行了问卷调查,结果如下:![](images/11120.png)\n(1)把统计结果填入表中。\n(2)没有蛀牙的学生比有蛀牙的学生多( )人。\n(3)在你认为下面预防蛀牙建议是正确的后面打\u0027√\u0027,错误的打\u0027*\u0027。①早晚刷牙,饭后漱口。( ) ②少吃糖,少喝碳酸饮料,多吃水果、蔬菜。( ) ③睡前喝止咳糖浆,可以不漱口。( )",
+        "options":  [
+
+                    ],
+        "answer":  "33;6;4;2;21;√;√;*",
+        "solution":  "【分析】(1)根据统计情况,分别数一数各种牙齿健康情况的人数各是多少,然后填空即可。(2)根据加法的意义,1颗蛀牙的人数+2颗蛀牙的人数+3颗蛀牙的人数=有蛀牙的人数,根据减法的意义,没有蛀牙的人数-有蛀牙的人数=没有蛀牙比有蛀牙多的人数,算出答案即可求解。(3)为预防蛀牙,同学们保持口腔卫生,养成饭后刷牙的习惯;晚上刷牙后不再进食;多吃蔬菜水果,少吃碳酸饮料,糖果和饼干等.\n\n【详解】(1)由题可知,没有蛀牙的人数为33,1颗蛀牙的人数为6,2颗蛀牙的人数为4,3颗蛀牙的人数为2。填表如下:没有蛀牙33人,1颗蛀牙6人,2颗蛀牙4人,3颗蛀牙2人。(2)6+4+2=12(人),33-12=21人),所以没有蛀牙的学生比有蛀牙的学生多21人。(3)根据分析可得:①早晚刷牙,饭后漱口。(√) ②少吃糖,少喝碳酸饮料,多吃水果,蔬菜。(√) ③睡前喝止咳糖浆,可以不漱口。(*)",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "23-24二年级下·河南南阳·期末"
+    },
+    {
+        "id":  "160",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "三(3)班参加校运动会项目情况如下图所示,根据统计图回答问题。![](images/11121.png)\n(1)每格代表( )人.\n(2)参加( )的人最多,参加( )的人最少.\n(3)参加跳绳的比跑步的多( )人。",
+        "options":  [
+
+                    ],
+        "answer":  "4;跳绳;踢毽子;12",
+        "solution":  "【分析】(1)根据统计图的最左侧数字可知,每一格代表4人;(2)比较参加每种项目的人数即可解答;(3)根据减法的意义,参加跳绳的人数-参加跑步的人数=参加跳绳比参加跑步多的人数.\n\n【详解】(1)每格代表4人。(2)跳绳的有24人;踢毽子的有4人;跳远的有20人;跑步的有12人。24\u003e20\u003e12\u003e4,参加跳绳的人最多,参加踢毽子的人最少。(3)24-12=12(人),参加跳绳的比跑步的多12人。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "23-24 二年级下·浙江·期末"
+    },
+    {
+        "id":  "161",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "\u0027白色污染\u0027给我们的环境带来很大的危害,要尽量减少塑料袋的使用。为深入贯彻落实习近平总书记在全国生态环境保护大会上的重要讲话精神,激发起全社会共同呵护生态环境的内生动力,推动形成绿色低碳生活方式,生态环境部宣传教育中心面向全国小学生,组织开展\u0027美丽中国,我是行动者\u0027的环境保护活动。实验小学二(1)班几个同学统计了自己家一周内塑料袋的使用情况。典典家:正正正下 蓝蓝家:正正正正 天天家:正正 梦梦家:正T\n(1)( )家这一周使用的塑料袋最多,( )家这一周使用的塑料袋最少.\n(2)梦梦家这一周比典典家少使用( )个塑料袋.\n(3)他们四家这一周一共使用了( )个塑料袋.\n(4)根据上面的统计结果,你有什么建议。",
+        "options":  [
+
+                    ],
+        "answer":  "蓝蓝;梦梦;11;55;见详解",
+        "solution":  "【分析】(1)数一数,典典家18个,蓝蓝家20个,天天家10个,梦梦家7个,比较即可求解。(2)用典典家使用的个数减梦梦家使用的个数即可求解。(3)将每家使用的塑料袋个数相加即可。(4)依据统计结果,结合生活常识去解答。本小题答案不唯一,例如:尽量少使用塑料袋,多使用可以多次利用的购物袋.\n\n【详解】(1)7\u003c10\u003c18\u003c20,蓝蓝家这一周使用的塑料袋最多,梦梦家这一周使用的塑料袋最少。(2)18-7=11(个),梦梦家这一周比典典家少使用11个塑料袋。(3)18+20+10+7=38+10+7=48+7=55(个),他们四家这一周一共使用了55个塑料袋。(4)我的建议是:尽量少使用塑料袋,多使用可以多次利用的购物袋。(本小题答案不唯一)",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "23-24 二年级下·湖北黄石·期末"
+    },
+    {
+        "id":  "162",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "下面是二(1)班全体同学最喜欢的玩具情况统计。![](images/11123.png)\n(1)把统计结果填入表中。\n(2)二(1)班喜欢( )的人数最多,喜欢( )的人数最少;这个班一共有( )人。\n(3)如果你是商店老板,你会多购进( ),因为。",
+        "options":  [
+
+                    ],
+        "answer":  "16;10;8;9;小汽车;洋娃娃;43;小汽车;喜欢小汽车玩具的人数多",
+        "solution":  "【分析】(1)数出每个玩具同学的投票情况,将数得的数填入表格中即可。(2)比较两位数和一位数的大小时,位数越多的数越大,位数相同时,十位上越大的数越大,十位相同时,个位上越大的数越大。将表格中的人数进行比较大小后排序,找出喜欢人数最多的玩具和喜欢人数最小的玩具;把喜欢每个玩具的人数进行相加,算出来的和就是整个班的人数,即可解答。(3)根据商店老板会想要卖出更多的货物,获取更多的金钱,所以进购的会是喜欢人数更多的玩具,即可解答.\n\n【详解】(1)根据分析,数出洋娃娃有7人喜欢,小汽车有15人喜欢,手枪有12人喜欢,飞机有9人喜欢。将数据填入表格中:洋娃娃7人,小汽车15人,手枪12人,飞机9人。(2)7,15,12,9四个数,15和12的位数更多,则15,12比7,9都大;15和12十位上相同,个位上5\u003e2,所以15\u003e12,且7\u003c9;则有7\u003c9\u003c12\u003c15.7+9+12+15=43(人),故此,二(1)班喜欢小汽车的人数最多,喜欢洋娃娃的人数最少;这个班一共有43人。(3)商店老板会选择多进购更多人喜欢的小汽车,因为喜欢小汽车玩具的人数多。(答案不唯一)",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "23-24二年级下·重庆大渡口·期末"
+    },
+    {
+        "id":  "163",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "下面是四年级同学参加兴趣小组的人数情况表。![](images/11124.png)\n(1)( )组的人数最多,( )组的人最少.\n(2)美术组比航模组多( )人,比书法组多( )人.\n(3)你还能提出什么数学问题。",
+        "options":  [
+
+                    ],
+        "answer":  "美术;书法 2;5 电脑组比科技组多几人。(答案不唯一)",
+        "solution":  "【分析】(1)比较每组的人数,找到人数最多和最少的即可;(2)根据减法的意义,美术组的人数-航模组的人数=美术组比航模组多的人数;美术组的人数-书法组的人数=美术组比书法组多的人数;(3)提出的问题符合题意即可,可提出电脑组比科技组多几人。\n\n【详解】(1)10\u003e8=8\u003e7\u003e5,美术组的人数最多,书法组的人最少。(2)10-8=2(人),10-5=5(人),美术组比航模组多2人,比书法组多5人。(3)电脑组比科技组多几人。(答案不唯一)8-7=1(人),答:电脑组比科技组多1人。",
+        "knowledge_points":  [
+                                 "\"提问题\"\"填条件\"问题",
+                                 "单式统计表的特点及填补"
+                             ],
+        "source":  "23-24 二年级下·河南漯河·期末"
+    },
+    {
+        "id":  "164",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "下面是军军在一个十字路口统计的10分钟内通过的车辆情况![](images/11125.png)\n(2)这个路口10分钟内通过的( )最多,通过的( )最少.\n(3)10分钟内通过的小轿车的数量与大货车的数量相差( )辆.\n(4)根据上面的数学信息,请你提一个数学问题,并解答。",
+        "options":  [
+
+                    ],
+        "answer":  "6;20;12;5 小轿车;大货车 15 10分钟内通过的电动车和大货车一共有多少辆。(答案不唯一)12+5=17(辆)",
+        "solution":  "【分析】(1)数出表格中经过的每类车的数量,将数据填入对应的表格中即可解答;(2)根据20以内的数比较大小,先对每类车辆的数量进行比较大小,再找出数量最多的和最少的即可解答;(3)根据减法的意义,小轿车通过的数量-大货车通过的数量=小轿车和大货车相差的数量,列出算式算出答案即可解答;(4)根据题目给出的信息,提出一个合理的问题即可。如:10分钟内通过的电动车和大货车一共有多少辆。根据加法的意义,电动车通过的数量+大货车通过的数量=两种车辆一共通过的数量,列出算式算出答案即可解答.\n\n【详解】(1)根据题目给出的表格,可数出10分钟内公交车通过6辆,小轿车通过20辆,电动车通过12辆,大货车通过5辆。填入表格中如下图所示:公交车6辆,小轿车20辆,电动车12辆,大货车5辆。(2)6,20,12,5四个数中:6和5位数最少,所以会比20和12都小,且6\u003e5;20和12位数相同,十位上2\u003e1,所以20\u003e12;则5\u003c6\u003c12\u003c20。所以,这个路口10分钟内通过的小轿车最多,通过的大货车最少。(3)20-5=15(辆),答:10分钟内通过的小轿车的数量与大货车的数量相差15辆。(4)10分钟内通过的电动车和大货车一共有多少辆。(答案不唯一)12+5=17(辆),答:10分钟内通过的电动车和大货车一共17辆。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "\"提问题\"\"填条件\"问题"
+                             ],
+        "source":  "23-24 二年级下·湖北襄阳·期末"
+    },
+    {
+        "id":  "165",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "下边是气象小组记录的今年5月份的天气情况.\n(1)把各种天气情况的天数分别填在下表中。![](images/11126.png)\n(2)( )天数最多,( )天数最少.\n(3)5月份一共下了( )天雨。",
+        "options":  [
+
+                    ],
+        "answer":  "11;2;4;13;1 阴;晴 17",
+        "solution":  "【分析】(1)每个格代表1天,依次数出每种天气有多少个格,也就是有多少天,由此填表即可;(2)比较每种天气情况的天数即可解答;(3)根据表格填写的数据,将小雨,中雨和大雨的天数相加就是下雨的总天数.\n\n【详解】(1)表格填写如下:晴11天,阴2天,多云4天,小雨13天,中雨1天。(2)13\u003e11\u003e4\u003e2\u003e1,阴天数最多,晴天数最少。(3)11+2+4=17(天),5月份一共下了17天雨。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "23-24 二年级下·福建龙岩·期末"
+    },
+    {
+        "id":  "166",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "![](images/11127.png)\n(1)用画\u0027正\u0027字的方法整理上面的物品。玩具: 文具: 鞋袜衣帽:\n(2)把整理结果用数字填写在下面表格中。![](images/11128.png)\n(3)从统计结果看,一共有( )件物品.\n(4)统计中( )类物品最多,( )类物品最少。",
+        "options":  [
+
+                    ],
+        "answer":  "见详解 2;5;4 11 文具;玩具",
+        "solution":  "【分析】(1)(2)一个一个地数,最后数到几就是几,然后用正字表示出来,并填表。(3)将三种数量相加即可求解。(4)将三种物品的数量相比较即可。5以内数的大小关系为:0\u003c1\u003c2\u003c3\u003c4\u003c5.\n\n【详解】(1)用画\u0027正\u0027字的方法整理上面的物品。玩具:下,文具:正,鞋袜衣帽:正。(2)把整理结果用数字填写在下面表格中:玩具2件,文具5件,鞋袜衣帽4件。(3)2+5+4=11(件),从统计结果看,一共有11件物品。(4)2\u003c4\u003c5,统计中文具类物品最多,玩具类物品最少。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "23-24 二年级下·重庆丰都·期末"
+    },
+    {
+        "id":  "167",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "二(1)班同学统计了班里图书角中各类图书的数量。记录结果如下。![](images/11129.png)\n(2)图书角哪一类图书最多。\n(3)如果要添一些图书,你建议添加哪一类。",
+        "options":  [
+
+                    ],
+        "answer":  "45;15;35 文学类 建议添加文学类图书,较受同学们喜爱。(答案不唯一,合理即可)",
+        "solution":  "【分析】(1)根据一个\u0027正\u0027字表示5本,数清楚各种图书的数量,并将数据填入表格即可;(2)比较这三类书本数的大小,找出数量最多的哪一类即可。(3)根据表格数据提出合理建议即可.\n\n【详解】(1)把同学们统计的结果填入下表:文学类45本,历史类15本,科学类35本。(2)45\u003e35\u003e15,答:图书角文学类图书最多。(3)答:如果要添一些图书,我建议添加文学类图书,因为文学类图书比较受同学们的喜爱。(答案不唯一)",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "23-24 二年级下·河南信阳·期末"
+    },
+    {
+        "id":  "168",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "(1)![](images/11130.png)(2)喜欢( )的人数最多,喜欢( )的人数最少.\n(3)这个班一共有( )人。",
+        "options":  [
+
+                    ],
+        "answer":  "15;7;9;5 松树;杨树 36",
+        "solution":  "【分析】(1)一个\u0027正\u0027字表示5人,一画表示1人;据此分别数一数,最喜欢各种植物的各有几人并填空。(2)比较一下最喜欢各种植物的人数的大小,即可知道喜欢什么植物的人数最多,喜欢什么植物的人数最少。(3)用加法把最喜欢各种植物的人数全部加起来,求出和即可.\n\n【详解】(1)填表:松树15人,柏树7人,柳树9人,杨树5人。(2)15\u003e7\u003e9\u003e5,即喜欢松树的人数最多,喜欢杨树的人数最少。(3)15+7+9+5=22+9+5=31+5=36(人),即这个班一共有36人。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "20以内数的比大小",
+                                 "100以内数的连加运算"
+                             ],
+        "source":  "24-25 二年级下·福建福州·期中"
+    },
+    {
+        "id":  "169",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "6月5日是世界环境日,保护环境,人人有责。下面是4名同学记录的一周自己家使用塑料袋数量的情况。![](images/11131.png)\n(2)( )家这一周使用的塑料袋数量最多,( )家这一周使用的塑料袋数量最少.\n(3)小田家这一周使用的塑料袋比小文家少( )个.\n(4)塑料垃圾被称为\u0027白色污染\u0027,你对大家使用塑料袋有什么好建议。请你写下来。",
+        "options":  [
+
+                    ],
+        "answer":  "18;12;7;8 小天;小乐 4 建议大家合理使用塑料袋,尽量使用布袋。",
+        "solution":  "【分析】(1)每个\u0027正\u0027字表示5个,一个\u0027○\u0027表示1个,一个\u0027√\u0027表示1个,分别数出四个家庭一周自己家使用塑料袋数量的个数,填表即可。(2)比较统计表中的数据,即可知道哪一家一周使用的塑料袋数量最多,哪一家一周使用的塑料袋数量最少。(3)用减法即可求出小田家这一周使用的塑料袋比小文家少几个。(4)从\u0027环保意识\u0027出发,建议大家合理使用塑料袋,减少\u0027白色污染\u0027,合理即可.\n\n【详解】(1)填表:小天家18个,小文家12个,小乐家7个,小田家8个。(2)18\u003e12\u003e8\u003e7,小天家这一周使用的塑料袋数量最多,小乐家这一周使用的塑料袋数量最少。(3)12-8=4(个),小田家这一周使用的塑料袋比小文家少4个。(4)建议大家合理使用塑料袋,尽量使用布袋。(答案不唯一)",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "24-25 二年级下·陕西延安·期中"
+    },
+    {
+        "id":  "170",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "下面是二(3)班同学最喜欢的季节统计表,补全表格并回答问题。![](images/11132.png)\n喜欢夏季的比秋季多5人,喜欢夏季的有( )人。喜欢春季和夏季的一共有多少人。",
+        "options":  [
+
+                    ],
+        "answer":  "15;30人",
+        "solution":  "【分析】根据加法的意义,喜欢秋季的人数+喜欢夏季比秋季多的人数=喜欢夏季的人数,喜欢春季的人数+喜欢夏季的人数=喜欢春季和夏季的总人数,列出算式算出答案即可解答.\n\n【详解】10+5=15(人),即喜欢夏季的有15人。15+15=30(人),答:喜欢春季和夏季的一共有30人。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "24-25 二年级下·湖南湘潭·期中"
+    },
+    {
+        "id":  "171",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "二(1)班参加研学活动的同学准备报看电影项目,要从3种电影中选出1种,下面是本班同学的投票情况。(每人只投一票)![](images/11133.png)\n(2)一共有多少人参加投票。\n(3)根据统计结果,应该选( ).\n(4)如果班主任李老师也参加投票,那么投票结果会发生变化吗。",
+        "options":  [
+
+                    ],
+        "answer":  "10;15;16 41人 《哪吒之魔望降世》 如果李老师投《喜羊羊与灰太狼》投票结果会发生变化,会和《哪吒之魔童降世》平票。",
+        "solution":  "【分析】(1)\u0027正\u0027字的每一笔表示1人,据此统计填表。(2)求一共有多少人用加法计算。(3)哪部电影的票数最多就选哪部电影。(4)如果班主任李老师也参加投票,那么选举的结果会发生改变。《喜洋洋与灰太狼》比《哪吒之魔童降世》少1票,若李老师投《喜羊羊与灰太狼》投票结果会发生变化,会和《哪吒之魔童降世》平票.\n\n【详解】(1)填表:《熊出没》10人,《喜洋洋与灰太狼》15人,《哪吒之魔童降世》16人。(2)10+15+16=25+16=41人),答:一共有41人参加投票。(3)10\u003c15\u003c16,所以《哪吒之魔望降世》票数最多,应该选《哪吒之魔望降世》。(4)15+1=16(票),16=16,答:如果李老师投《喜洋洋与灰太狼》投票结果会发生变化,会和《哪吒之魔童降世》平票。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "100以内数的连加运算"
+                             ],
+        "source":  "24-25 二年级下·湖北武汉·期中"
+    },
+    {
+        "id":  "172",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "二年级(1)班组织评选\u0027阅读之星\u0027(每人只能投一票),投票结果如下。![](images/11134.png)\n(2)如果本次要评出两名\u0027阅读之星\u0027,根据投票结果,( )和( )获评.\n(3)有两名同学缺勤没能参加投票,如果他们也投了票,获评\u0027阅读之星\u0027的同学会改变吗。请说明理由。",
+        "options":  [
+
+                    ],
+        "answer":  "10;16;7;14 小美;小明 不会;理由见详解",
+        "solution":  "【分析】(1)依次数出每人得到的票数填表即可,\u0027正\u0027字的每一笔代表1票;(2)比较每人得到的票数,票数多的两人会获评;(3)根据题意,可将这两票分别与第三名和第四名的票数相加,若超过第一名和第二名的票数,结果会改变,反之不会改变.\n\n【详解】(1)表格填写如下:小海10票,小美16票,小聪7票,小明14票。(2)16\u003e14\u003e10\u003e7,如果本次要评出两名\u0027阅读之星\u0027,根据投票结果,小美和小明获评。(3)第三名是小海:10+2=12(票);12\u003c14\u003c16,第四名是小聪:7+2=9(票);9\u003c12\u003c16;有两名同学缺勤没能参加投票,如果他们也投了票,获评\u0027阅读之星\u0027的同学不会改变。理由:缺勤的两名同学的票无论都投给小海还是小聪,他们的得票数都不会超过小美和小明,所以结果不会改变。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "100以内数的比大小"
+                             ],
+        "source":  "24-25 二年级下·福建龙岩·期中"
+    },
+    {
+        "id":  "173",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "下面是某班同学出生季节的情况,把表补充完整,并回答问题![](images/11135.png)\n(1)( )季出生的人最多.\n(2)夏季出生的比春季出生的少几人。\n(3)这个班一共有多少人。",
+        "options":  [
+
+                    ],
+        "answer":  "14;10;12;8 春 4人 44人",
+        "solution":  "【分析】由题意可知:本题采用的是\u0027正字\u0027统计法,\u0027正\u0027字的笔画代表一个人,一个\u0027正\u0027字5画,不完整的\u0027正\u0027字,按具体笔画数进行统计。春季:正正TF,5+5+4=14(人);夏季:正正,5+5=10(人);秋季:正正T,5+5+2=12(人);冬季:正下,5+3=8(人);(1)把统计出来的春季,夏季,秋季,冬季出生的人数进行比较找出最大的即可。(2)春季出生的人数-夏季出生的人数=夏季比春季少的人数;(3)春季的人数+夏季的人数+秋季的人数+冬季的人数=全班一共的人数.\n\n【详解】春正正TF(14)人,夏正正(10)人,秋正正T(12)人,冬正下(8)人。(1)14\u003e12\u003e10\u003e8,春季出生的人最多。(2)14-10=4(人),答:夏季出生的比春季出生的少4人。(3)14+10+12+8=24+12+8=36+8=44(人),答:这个班一共有44人。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "24-25 二年级下·河北邯郸·期中"
+    },
+    {
+        "id":  "174",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "下面是二(2)班同学最喜欢的动物情况统计表。![](images/11136.png)\n(1)根据上面的统计结果完成下表。动物猴子兔子松鼠熊猫人数(人)\n(2)这个班一共有( )人。喜爱熊猫的同学比喜爱猴子的同学多( )人.\n(3)如果这个班要去动物园,你认为应该先去观看( )动物最合适。",
+        "options":  [
+
+                    ],
+        "answer":  "10;5;6;22 43;12 熊猫",
+        "solution":  "【分析】(1)依次数出喜欢每种动物的人数填表即可,\u0027正\u0027字的每一笔代表1人;(2)将喜欢每种动物的人数相加就是总人数;根据减法的意义,喜欢熊猫的人数-喜欢猴子的人数=喜欢熊猫比喜欢猴子多的人数;(3)比较喜欢每种动物的人数,喜欢哪种动物的人数最多,则先去观看哪种动物最合适.\n\n【详解】(1)表格填写如下:猴子10人,兔子5人,松鼠6人,熊猫22人。(2)10+5+6+22=43(人),22-10=12(人),这个班一共有43人。喜爱熊猫的同学比喜爱猴子的同学多12人。(3)22\u003e10\u003e6\u003e5,如果这个班要去动物园,你认为应该先去观看熊猫最合适。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "单式统计表的特点及填补"
+                             ],
+        "source":  "24-25 二年级下·新疆喀什·期中"
+    },
+    {
+        "id":  "175",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "书法是汉字的书写艺术。下面是幸福小学的学生最喜欢的书法字体投票结果(每人只投一票)。![](images/11137.png)\n(2)最喜欢( )号字体的人数最多,最喜欢( )号字体的人数最少.\n(3)一共有( )名学生投票,最喜欢①号字体的比最喜欢④号字体的少( )人。",
+        "options":  [
+
+                    ],
+        "answer":  "9;6;25;20;13 ③;② 73;11",
+        "solution":  "【分析】(1)每个\u0027正\u0027字5画,表示5票,数出五种书法字体所得的\u0027正\u0027字笔画数,填表即可;(2)比较各种书法字体得票数的多少即可;(3)将所有票数相加求和即可;用喜欢④号字体的人数减去喜欢①号字体的人数,即可得出答案.\n\n【详解】(1)把投票结果填在下表中:①9票,②6票,③25票,④20票,⑤13票。(2)25\u003e20\u003e13\u003e9\u003e6,最喜欢③号字体的人数最多,最喜欢②号字体的人数最少。(3)25+20+13+9+6=45+13+9+6=58+9+6=67+6=73(人),20-9=11(人),答:一共有73名学生投票,最喜欢①号字体的比最喜欢④号字体的少11人。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "单式统计表的特点及填补"
+                             ],
+        "source":  "24-25 二年级下·河南南阳·期中"
+    },
+    {
+        "id":  "176",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "二(1)班新学期选班长,要从候选人李冬,王海,张鹏这三名同学中选出一名,下面是同学们的投票情况。(每人只投一票)![](images/11138.png)\n(2)根据投票结果,应选( )当班长.\n(3)一共有( )人参加投票.\n(4)如果班主任孙老师也参加投票,老师只投一票,那么结果会发生改变吗。",
+        "options":  [
+
+                    ],
+        "answer":  "15;11;9 李冬 35 不会",
+        "solution":  "【分析】(1)一个一个地数,最后数到几就是几个。(2)比一比,应选票数最多的当班长。(3)将所有票数相加即可求出参加投票的总人数。(4)将票数投给第二名看看有没有变化即可.\n\n【详解】(1)根据投票的结果填写下表:李冬15票,王海11票,张鹏9票。(2)15\u003e11\u003e9,根据投票结果,应选李冬当班长。(3)15+11+9=35(人),一共有35人参加投票。(4)11+1=12(票),12\u003c15,答:结果不会发生改变。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "24-25 二年级下·湖南怀化·期中"
+    },
+    {
+        "id":  "177",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "下表是小优对二(4)班学生爱好的调查结果。(每人限选一项)![](images/11139.png)\n(1)二(4)班喜欢( )的人数最多,喜欢( )和喜欢( )的人数同样多.\n(2)二(4)班一共有( )人,喜欢看书的人数比喜欢跳舞的人数多( )人.\n(3)请你再提出一个数学问题并解答。",
+        "options":  [
+
+                    ],
+        "answer":  "看书;唱歌;球类 32;10 喜欢唱歌和喜欢跳舞的一共有多少人。(答案不唯一)5+6=11(人);11人",
+        "solution":  "【分析】(1)依次数出喜欢每种项目的人数再比较大小即可解答。\u0027正\u0027字的每一笔代表1人;(2)将喜欢每种项目的人数相加就是总人数;根据减法的意义,喜欢看书的人数-喜欢跳舞的人数=喜欢看书比喜欢跳舞多的人数;(3)提出的问题符合题意即可,可提出喜欢唱歌和喜欢跳舞的一共有多少人。用加法计算.\n\n【详解】(1)喜欢唱歌的有5人;喜欢跳舞的有6人;喜欢看书的有16人;喜欢球类的有5人;16\u003e6\u003e5=5,二(4)班喜欢看书的人数最多,喜欢唱歌和喜欢球类的人数同样多。(2)5+6+16+5=32(人),16-6=10(人),二(4)班一共有32人,喜欢看书的人数比喜欢跳舞的人数多10人。(3)喜欢唱歌和喜欢跳舞的一共有多少人。(答案不唯一)5+6=11人),答:喜欢唱歌和喜欢跳舞的一共有11人。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "24-25 二年级下·浙江宁波·期中"
+    },
+    {
+        "id":  "178",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "王老师统计了二(4)班学生最喜欢的体育项目,记录结果如下:![](images/11140.png)\n(2)二(4)班学生最喜欢( )的人数最多,最喜欢( )的人数最少.\n(3)你最喜欢上面的哪种体育项目。二(4)班学生最喜欢这个体育项目的有多少人。",
+        "options":  [
+
+                    ],
+        "answer":  "5;10;16;12 跳绳;打篮球 打篮球;5人",
+        "solution":  "【分析】(1)一个一个地数,最后数到几就是几。正字的每一笔表示一人。(2)比较人数多少即可。20以内的数从小到大排列是:1\u003c2\u003c3\u003c4\u003c5\u003c6\u003c7\u003c8\u003c9\u003c10\u003c11\u003c12\u003c13\u003c14\u003c15\u003c16\u003c17\u003c18\u003c19\u003c20。(3)根据自己的爱好回答即可,然后写出二(4)班对应项目的人数.\n\n【详解】(1)填表:打篮球5人,踢毽子10人,跳绳16人,打乒乓球12人。(2)5\u003c10\u003c12\u003c16,二(4)班学生最喜欢跳绳的人数最多,最喜欢打篮球的人最少。(3)答:我最喜欢打篮球;二(4)班学生最喜欢这个体育项目的有5人。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "24-25 二年级下·陕西渭南·期中"
+    },
+    {
+        "id":  "179",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "下表是玩具店售出的毛绒玩具的情况记录。![](images/11141.png)\n(2)( )毛绒玩具售出的数量最多.\n(3)( )毛绒玩具和( )毛绒玩具售出的数量同样多.\n(4)如果你是玩具店的老板,下次再进货买毛绒玩具时,你会怎么做。",
+        "options":  [
+
+                    ],
+        "answer":  "4;24;10;10 小熊 小猴;小狗 见详解",
+        "solution":  "【分析】(1)依次数出售出每种毛绒玩具的数量填表即可,\u0027正\u0027字的每一笔代表1个;(2)比较售出的数量,可得出售出数量最多的是哪种玩具;(3)根据比较的结果即可解答;(4)根据售出情况,哪种玩具售出的多就多进哪种玩具,哪种玩具售出的少就少进哪种玩具.\n\n【详解】(1)表格填写如下:小猫4个,小熊24个,小猴10个,小狗10个。(2)24\u003e10=10\u003e4,小熊毛绒玩具售出的数量最多。(3)小猴毛绒玩具和小狗毛绒玩具售出的数量同样多。(4)小熊玩具售出的数量最多,小猫玩具售出的数量最少。则我会多进小熊毛绒玩具,少进小猫毛绒玩具。(答案不唯一)",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "24-25 二年级下·辽宁鞍山·期中"
+    },
+    {
+        "id":  "180",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "下面是本班同学喜欢的运动项目的情况统计表。![](images/11142.png)\n(1)最喜欢( )的人数最多,比喜欢打篮球的人数多( )人.\n(2)全班一共有( )人.\n(3)如果我们班要购买运动物品,你有什么建议。",
+        "options":  [
+
+                    ],
+        "answer":  "羽毛球;10 46 见详解",
+        "solution":  "【分析】(1)把喜欢各种运动项目的人数比较大小;最喜欢羽毛球比最喜欢打篮球多的人数=最喜欢羽毛球的人数-最喜欢打篮球的人数。(2)用喜欢各种运动项目的人数相加即可求出全班一共的人数;(3)建议多买羽毛球,因为喜欢羽毛球的人数最多.\n\n【详解】(1)22\u003e12\u003e9\u003e3,22-12=10(人),最喜欢羽毛球的人数最多,比喜欢打篮球的人数多10人。(2)12+22+9+3=46(人),全班一共有46人。(3)答:建议多买羽毛球,因为喜欢羽毛球的人数最多。(答案不唯一)",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "24-25 二年级下·广东云浮·期中"
+    },
+    {
+        "id":  "181",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "丽丽调查全班同学最喜欢吃下面五种蔬菜中的哪一种,结果如下。(每人只选一种)![](images/11143.png)\n丽丽:最喜欢茄子的人数是被除数和除数都是9的算式的商。小明:最喜欢西红柿的人数是4个4的和.\n(1)根据信息将表格补充完整.\n(2)最喜欢白菜的同学比最喜欢黄瓜的多( )人.\n(3)学校食堂要给全校同学准备午饭,请你帮食堂选择两种蔬菜,并说明理由。",
+        "options":  [
+
+                    ],
+        "answer":  "1;16 5 选白菜和西红柿,因为喜欢这两种蔬菜的人最多,能满足大多数同学的口味偏好。",
+        "solution":  "【分析】(1)因为\u0027最喜欢茄子的人数是被除数和除数都是9的算式的商\u0027,所以最喜欢茄子的人数是9/9=1(人);因为\u0027最喜欢西红柿的人数是4个4的和\u0027,4个4的和列式为4×4=16(人),所以最喜欢西红柿的人是16人。(2)用最喜欢白菜的同学人数减去最喜欢黄瓜的同学人数,即可求出最喜欢白菜的同学比最喜欢黄瓜的多多少人。(3)先把喜欢各种蔬菜的人数进行排序,选出两种喜欢人数最多的蔬菜,因为选择它们能满足大多数同学的口味偏好.\n\n【详解】(1)由分析填表如下:白菜12人,萝卜6人,茄子1人,西红柿16人,黄瓜7人。(2)12-7=5(人),最喜欢白菜的同学比最喜欢黄瓜的多5人。(3)1\u003c6\u003c7\u003c12\u003c16,选白菜和西红柿,因为喜欢这两种蔬菜的人最多,能满足大多数同学的口味偏好。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "24-25 二年级下·河北沧州·期中"
+    },
+    {
+        "id":  "182",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "为响应垃圾分类的号召,各居民小区要对本小区的垃圾桶进行重新布置。下面是实施垃圾分类后某小区一周内产生的各种垃圾的质量统计情况。(每格表示2吨)![](images/11144.png)\n(1)这个小区一周内产生了( )吨厨余垃圾.\n(2)这个小区一周内产生的可回收垃圾比其他垃圾少( )吨.\n(3)如果每格表示1吨,小区一周内产生的有害垃圾为( )吨.\n(4)如果小区要配置一批新的垃圾桶,( )的垃圾桶多买一些,因为( )。",
+        "options":  [
+
+                    ],
+        "answer":  "38 4 3 其他垃圾 其他垃圾最多",
+        "solution":  "【分析】(1)将所有阴影格子数一数,求出一共有19个格子,每个表示2吨,一共是19×2=38(吨)。据此即可求解。(2)数一数,用其他垃圾的吨数减可回收垃圾的吨数即可求解。(3)一个一个地数,数一数有害垃圾的阴影格数。每格表示1吨,阴影格数是多少,有害垃圾就是几吨。(4)比一比阴影格子的高低,越高的则说明需要的垃圾桶也越多.\n\n【详解】(1)19×2=38(吨),这个小区一周内产生了38吨厨余垃圾。(2)14-10=4(吨),这个小区一周内产生的可回收垃圾比其他垃圾少4吨。(3)如果每格表示1吨,小区一周内产生的有害垃圾为3吨。(4)如果小区要配置一批新的垃圾桶,其他垃圾的垃圾桶多买一些,因为其他垃圾最多。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "24-25 二年级下·福建福州·期中"
+    },
+    {
+        "id":  "183",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "统计。文文对周末同学们想去游玩的地方进行了调查。(一个√代表一个人)![](images/11145.png)\n(1)想去( )的人最多,想去( )的人最少.\n(2)想去博物馆的比想去欢乐谷的少( )人,比想去动物园的多( )人.\n(3)如果你是老师,打算带同学们去游玩,你觉得哪个地方合适。为什么。",
+        "options":  [
+
+                    ],
+        "answer":  "欢乐谷;动物园 4;1 欢乐谷;理由见详解",
+        "solution":  "【分析】(1)根据题意,一个√代表1,整理出周末想去的各个地方的人数,再直接比较大小即可;(2)根据减法的意义,用想去欢乐谷的人数减去想去博物馆的人数即可;用想去博物馆的人数减去想去动物园的人数即可;(3)如果老师打算带同学们去旅游,合适的地方可能是最多同学想去的地方,据此解答即可.\n\n【详解】(1)12\u003e9\u003e8\u003e7,所以想去欢乐谷的人最多,想去动物园的人最少。(2)12-8=4(人),8-7=1(人),所以想去博物馆的比想去欢乐谷的少4人,比想去动物园的多1人。(3)答:因为想去欢乐谷的人数最多,所以我推荐的地方是欢乐谷。(答案不唯一)",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "24-25 三年级下·河北保定·期中"
+    },
+    {
+        "id":  "184",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "下面是调查二(1)班最喜欢的画册的记录情况。(每位小朋友只选一种)![](images/11146.png)\n(2)二(1)班一共有( )人.\n(3)你还能提出其他数学问题并解答吗。\n(4)根据调查结果,若你是二(1)班老师,你认为应多准备哪种画册。为什么。",
+        "options":  [
+
+                    ],
+        "answer":  "9;10;9;20 48 喜欢《一千零一夜》的人数比《熊出没》多多少人。20-9=11(人) 《一千零一夜》;因为喜欢《一千零一夜》的人数最多,说明需求最大,多准备可满足更多学生的阅读兴趣。",
+        "solution":  "【分析】(1)一个√代表一票,一个△代表一票,一个○代表一票,一个正字代表5票,分别数出各种画册的票数,填在对应画册下边即可;(2)每位小朋友只选一种,把喜欢这4种画册的人数加起来,即可求出一共的人数,据此解答;(3)根据题目中的信息,提出问题为:喜欢《一千零夜》的人数比《熊出没》多多少人。喜欢《一千零一夜》的人数减去喜欢《熊出没》的人数,等于喜欢《一千零一夜》的人数比《熊出没》多多少人。(4)根据调查结果,比较调查结果中数量的大小,找出喜欢人数最多的画册,多准备一些这种,因为同学们喜欢的人多,需求量大,据此解答.\n\n【详解】(1)填空如下:《熊出没》9人,《我爱我家》10人,《格林童话》9人,《一千零一夜》20人。(2)9+10+9+20=48(人),答:二(1)班一共有48人。(3)提出的问题:喜欢《一千零一夜》的人数比《熊出没》多多少人。(提问题和答案不唯一)20-9=11人),答:喜欢《一千零一夜》的人数比《熊出没》多11人。(4)9=9\u003c10\u003c20,答:应多准备《一千零一夜》,因为喜欢《一千零一夜》的人数最多,说明需求最大,多准备可满足更多学生的阅读兴趣。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "\"提问题\"\"填条件\"问题",
+                                 "100以内数的比大小",
+                                 "100以内数的连加运算"
+                             ],
+        "source":  "24-25 二年级下·江西赣州·期中"
+    },
+    {
+        "id":  "185",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "下面是\u0027小小动物园\u0027里几种小动物只数的统计情况。![](images/11147.png)\n(2)\u0027小小动物园\u0027里一共有( )只动物.\n(3)动物园给动物们准备食物,你认为动物园应多准备哪种动物的食物。",
+        "options":  [
+
+                    ],
+        "answer":  "27;8;20;6 61 猴子",
+        "solution":  "【分析】(1)依次数出每种小动物的数量填表即可,\u0027正\u0027字的每一笔代表1只;(2)将每种动物的数量相加,就是动物的总数量;(3)比较每种动物的数量,哪种动物最多,就多准备哪种动物的食物即可.\n\n【详解】(1)填写如下:猴子27只,袋鼠8只,松鼠20只,熊猫6只。(2)27+8+20+6=61(只),\u0027小小动物园\u0027里一共有61只动物。(3)27\u003e20\u003e8\u003e6,答:猴子的数量最多,则动物园应多准备猴子的食物。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "100以内数的比大小",
+                                 "100以内数的连加运算"
+                             ],
+        "source":  "24-25 二年级下·湖南岳阳·期中"
+    },
+    {
+        "id":  "186",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "下面是小明记录的全班同学最喜欢吃的食品情况。![](images/11148.png)\n(2)全班一共有( )名同学.\n(3)喜欢吃( )的人数最多,喜欢吃( )的人数最少.\n(4)我喜欢吃( ),喜欢吃这类食品的有( )人.\n(5)班上召开美食节,需要采购食品,你有什么建议。",
+        "options":  [
+
+                    ],
+        "answer":  "15;13;11;7 46 水果;豆制品 水果;15;(答案不唯一) 见详解",
+        "solution":  "【分析】(1)依次数出喜欢每种种类食品的人数,填表即可,\u0027正\u0027字的每一笔代表1人;(2)将喜欢每种种类食品的人数相加,就是总人数;(3)比较喜欢每种种类食品的人数,找到人数最多和最少的即可;(4)根据自己的实际情况填写,写出对应类别的人数即可;(5)根据比较的结果,采购时,喜欢哪种类别食品的人数多,就多采购哪种类别,其它类别的适量采购即可.\n\n【详解】(1)把记录的结果填在下表中:水果15人,肉类13人,蔬菜11人,豆制品7人。(2)15+13+11+7=46(名),全班一共有46名同学。(3)15\u003e13\u003e11\u003e7,喜欢吃水果的人数最多,喜欢吃豆制品的人数最少。(4)我喜欢吃水果,喜欢吃这类食品的有15人。(答案不唯一)(5)我的建议:喜欢吃水果的人数最多,应多采购水果,其它种类的食品适量采购,这样才能照顾到不同同学的口味。(答案不唯一)",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "20以内数的比大小",
+                                 "100以内数的连加运算"
+                             ],
+        "source":  "24-25 二年级下·广东东莞·期中"
+    },
+    {
+        "id":  "187",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "二年(1)班一共有45人,每人只选一个最喜欢的课外社团活动项目,下表是统计情况。![](images/11149.png)\n(2)二年(1)班最喜欢( )的人数最多,最喜欢( )的人数最少.\n(3)最喜欢跳舞的和最喜欢绘画的一共有( )人,最喜欢唱歌的比最喜欢跳舞的多( )人.\n(4)根据调查结果,你对学校各社团招收学员工作有什么建议。",
+        "options":  [
+
+                    ],
+        "answer":  "8;17;14;6 唱歌;书法 22;9 多招些唱歌和绘画的学员(答案不唯一)",
+        "solution":  "【分析】(1)根据减法的意义,用全班人数减去喜欢跳舞,唱歌,绘画的人数即是喜欢书法的人数,然后填表即可;(2)根据统计表找出喜欢人数最多和喜欢人数最少的项目即可;(3)根据加法的意义,用最喜欢跳舞的人数加上最喜欢绘画的人数即是所求;根据减法的意义,最喜欢唱歌的人数减去最喜欢跳舞的人数即是所求;(4)根据统计表,言之有理即可,答案不唯一。例如:多招些唱歌和绘画的学员.\n\n【详解】(1)喜欢跳舞人数8人,喜欢唱歌人数17人,喜欢绘画人数14人。45-8-17-14=37-17-14=20-14=6(人),所以喜欢书法人数有6人。填表:跳舞8人,唱歌17人,绘画14人,书法6人。(2)17\u003e14\u003e8\u003e6,所以二年(1)班最喜欢唱歌的人数最多,最喜欢书法的人数最少。(3)8+14=22(人),所以最喜欢跳舞的和最喜欢绘画的一共有22人;17-8=9(人),所以最喜欢唱歌的比最喜欢跳舞的多9人。(4)根据调查结果,对学校各社团招收学员工作建议有:多招些唱歌和绘画的学员。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "单式统计表的特点及填补"
+                             ],
+        "source":  "24-25 二年级下·浙江温州·期中"
+    },
+    {
+        "id":  "188",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "下面是二(1)班同学最喜欢的春游地点统计情况。(每人只能投一票)![](images/11150.png)\n(2)一共有( )人参与投票.\n(3)二(1)班同学最喜欢的春游地点是( ).\n(4)你还能提出一个数学问题并解答吗。",
+        "options":  [
+
+                    ],
+        "answer":  "15;8;7;6 36 游乐园 最喜欢去游乐园比最喜欢去植物园的多几人。(答案不唯一)15-8=7(人);7人",
+        "solution":  "【分析】(1)依次数出喜欢每个地点的人数填表即可,\u0027正\u0027字的每一笔代表1人;(2)将喜欢每个地点的人数相加,就是总人数;(3)比较喜欢每个地点的人数,找到人数最多的即可;(4)提出的问题符合题意即可,可提出最喜欢去游乐园比最喜欢去植物园的多几人。用减法计算.\n\n【详解】(1)填写如下:游乐园15人,植物园8人,动物园7人,森林公园6人。(2)15+8+7+6=36(人),一共有36人参与投票。(3)15\u003e8\u003e7\u003e6,二(1)班同学最喜欢的春游地点是游乐园。(4)最喜欢去游乐园比最喜欢去植物园的多几人。(答案不唯一)15-8=7(人),答:最喜欢去游乐园比最喜欢去植物园的多7人。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "\"提问题\"\"填条件\"问题",
+                                 "20以内数的比大小",
+                                 "100以内数的连加运算"
+                             ],
+        "source":  "24-25 二年级下·江西宜春·期中"
+    },
+    {
+        "id":  "189",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "小朋友参加投球比赛,每个人投10次。每次投中的画\u0027☆\u0027,没有投中的画\u0027〇\u0027,投球结果记录如下。![](images/11151.png)\n(1)乐乐一共投中( )次.\n(2)四个人都投中的是第( )次和第( )次.\n(3)按投中次数从多到少来排名:\u003e\u003e\u003e。(填名字)",
+        "options":  [
+
+                    ],
+        "answer":  "7;3;6;乐乐;东东;朵朵;笑笑",
+        "solution":  "【分析】(1)通过观察投球结果记录表可知,每次投中的画\u0027☆\u0027,一个一个地数☆的数量,最后数到几,乐乐一共投中几次;(2)通过观察投球结果记录表可知,他们的第3次和第6次,全部都是☆,故四个人都投中的是第3次和第6次;(3)观察投球结果记录表,数一数可知,乐乐投中了7次,笑笑投中了4次,朵朵投中了5次,东东投中了6次,根据整数大小比较的方法,把他们投中的次数进行比较,即可完成排名.\n\n【详解】(1)乐乐一共投中7次。(2)四个人都投中的是第3次和第6次。(3)7\u003e6\u003e5\u003e4,按投中次数从多到少来排名:乐乐\u003e东东\u003e朵朵\u003e笑笑。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "数一数",
+                                 "10以内数的比大小"
+                             ],
+        "source":  "24-25 二年级下·福建厦门·期中"
+    },
+    {
+        "id":  "190",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "二(四)班通过投票竞选班长,每位同学只能投一票,情况如下。![](images/11152.png)\n(1)把统计结果填入表中。\n(2)全班一共有( )人参加了投票。\n(3)根据投票,( )当选班长。当天有2名同学因病请假没有参加投票,如果他们也来投票,结果会怎么样。为什么。",
+        "options":  [
+
+                    ],
+        "answer":  "0;14;10;7;31;晨晨;结果不变;见详解",
+        "solution":  "【分析】(1)一个一个地数,最后数到几就是几票。正字每1笔表示1票。(2)将所有票数相加即可。(3)票数最多的当选班长,比较即可求解。用第二名的票数加2,看看是否能超过第一名,能超过就会影响结果.\n\n【详解】(1)填表:涵涵0票,晨晨14票,依依10票,媛媛7票。(2)0+14+10+7=31(人),全班一共有31人参加了投票。(3)0\u003c7\u003c10\u003c14,根据投票,晨晨当选班长。10+2=12(票),12\u003c14,答:当天有2名同学因病请假没有参加投票,如果他们也来投票,不会改变结果,因为第一名不会发生变化。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "24-25 二年级下·浙江杭州·期中"
+    },
+    {
+        "id":  "191",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "[时事热点]数据整理。(2024年巴黎奥运会金牌榜情况)![](images/11153.png)\n(1)根据统计结果,填写下表。\n国家 美国 中国 日本 澳大利亚\n金牌数\n(2)这四个国家中,( )和( )得的金牌同样多,( )得的金牌最少。\n(3)美国和中国一共得了( )块金牌。\n(4)你还知道了什么信息。",
+        "options":  [
+
+                    ],
+        "answer":  "40;40;20;18;美国;中国;澳大利亚;80;中国比日本多得了20块金牌(答案不唯一)",
+        "solution":  "【分析】(1)依次数出每个国家获得金牌的数量,填表即可,\u0027正\u0027字的每一笔代表1块;(2)比较各国家获得金牌的数量,找到数量相同及最少的即可;(3)根据加法的意义,美国获得金牌的数量+中国获得金牌的数量=美国和中国一共获得的数量;(4)根据统计的结果填写合理的信息即可.\n\n【详解】(1)表格填写如下:美国40枚,中国40枚,日本20枚,澳大利亚18枚。(2)40=40\u003e20\u003e18,这四个国家中,美国和中国得的金牌同样多,澳大利亚得的金牌最少。(3)40+40=80(块),美国和中国一共得了80块金牌。(4)40-20=20(块),我还知道:中国比日本多得了20块金牌。(答案不唯一)",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "100以内数的比大小",
+                                 "整十数之间的加减法"
+                             ],
+        "source":  "24-25 二年级下·河南郑州·期中"
+    },
+    {
+        "id":  "192",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "投球训练时,投中的打\u0027○\u0027,不中的打\u0027*\u0027。下面是四位小朋友的投球记录。![](images/11154.png)\n(1)把统计结果填入表中。\n(2)( )投中的次数最多,( )投中的次数最少。\n(3)如果你是体育老师,你会派谁去参加投球比赛。请说明理由。",
+        "options":  [
+
+                    ],
+        "answer":  "9;5;4;7;李玲;王芳;见详解",
+        "solution":  "【分析】(1)根据投球记录,分别数一数每人投中了几次,然后填表即可。(2)先比较投中次数的多少,然后找出谁投中的次数最多和谁投中的次数最少即可。(3)根据比较结果,选择投中次数最多的同学去参加比赛即可.\n\n【详解】(1)填表:李玲9次,张明5次,王芳4次,陈立7次。(2)9\u003e7\u003e5\u003e4,即李玲投中的次数最多,王芳投中的次数最少。(3)答:如果我是体育老师,我会派李玲去参加投篮比赛。理由:在投球10次时,李玲投中的次数最多,所以会派李玲去参加投球比赛。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "单式统计表的特点及填补",
+                                 "10以内数的比大小"
+                             ],
+        "source":  "24-25 二年级下·广东东莞·期中"
+    },
+    {
+        "id":  "193",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "学校对本班同学最喜欢吃的水果进行了调查(每人只选一种),记录如下。![](images/11155.png)\n(1)一共有( )名同学参加了这次活动。\n(2)喜欢吃( )的人数最多。喜欢吃( )的人数最少.\n(3)班里要开联欢会,根据调查结果,怎样买水果更合理。",
+        "options":  [
+
+                    ],
+        "answer":  "60;车厘子;香蕉;应该多买车厘子,购买苹果、草莓和桃的量要比购买车厘子的量少一些,买香蕉的量要最少(答案不唯一)",
+        "solution":  "【分析】(1)将喜欢吃每种水果的人数相加,就是参加活动的总人数;(2)比较喜欢吃每种水果的人数,找到人数最多和最少的即可;(3)根据调查结果,喜欢吃哪种水果的人多就多买这种水果,喜欢吃哪种水果的人数居中,就适量购买,喜欢吃哪种水果的人少,就少买哪种水果.\n\n【详解】(1)7+12+13+10+18=60(名),一共有60名同学参加了这次活动。(2)18\u003e13\u003e12\u003e10\u003e7,喜欢吃车厘子的人数最多。喜欢吃香蕉的人数最少。(3)喜欢吃车厘子的人数最多,喜欢吃苹果,草莓,桃的人数居中,喜欢吃香蕉的人数最少。答:应该多买车厘子,购买苹果,草莓和桃的量要比购买车厘子的量少一些,买香蕉的量要最少。(答案不唯一)",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "20以内数的比大小",
+                                 "100以内数的连加运算"
+                             ],
+        "source":  "24-25 二年级下·山东济南·期中"
+    },
+    {
+        "id":  "194",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "乐乐调查了班上的同学们喜欢喝的早餐粥的情况。(每人只选一种)![](images/11156.png)\n(1)把统计结果填入表中。\n(2)乐乐一共调查了( )名同学。\n(3)最喜欢喝( )粥的人数最多,最喜欢喝( )粥的人数最少。\n(4)最喜欢喝南瓜粥的同学比最喜欢喝瘦肉粥的同学少( )人。",
+        "options":  [
+
+                    ],
+        "answer":  "4;6;5;3;15;33;瘦肉;青菜;10",
+        "solution":  "【分析】(1)依次数出喜欢喝每种早晨粥的人数,填表即可,\u0027正\u0027字的每一笔代表1人;(2)将表中填写的人数相加就是总人数;(3)比较喜欢喝每种早餐粥的人数,找到人数最多和最少的即可;(4)根据减法的意义,最喜欢喝瘦肉粥的人数-最喜欢喝南瓜粥的人数=最喜欢喝南瓜粥比最喜欢喝瘦肉粥少的人数.\n\n【详解】(1)填写如下:小米粥4人,玉米粥6人,南瓜粥5人,青菜粥3人,瘦肉粥15人。(2)4+6+5+3+15=33(名),乐乐一共调查了33名同学。(3)15\u003e6\u003e5\u003e4\u003e3,最喜欢喝瘦肉粥的人数最多,最喜欢喝青菜粥的人数最少。(4)15-5=10(人),最喜欢喝南瓜粥的同学比最喜欢喝瘦肉粥的同学少10人。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "20以内数的比大小",
+                                 "不退位减法(20以内)",
+                                 "100以内数的连加运算"
+                             ],
+        "source":  "24-25 二年级下·辽宁鞍山·阶段练习"
+    },
+    {
+        "id":  "195",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "\u0027白色污染\u0027给我们的环境带来很大的危害,要尽量减少塑料袋的使用。二(1)班几个同学统计了自己家一周内塑料袋的使用情况。![](images/11157.png)\n(1)( )家这一周使用的塑料袋最多,( )家这一周使用的塑料袋最少.\n(2)他们四家这一周一共使用了多少个塑料袋。\n(3)根据上面的统计结果,你有什么建议。",
+        "options":  [
+
+                    ],
+        "answer":  "蓝蓝;梦梦;55个;尽量少使用塑料袋,多使用可以多次利用的购物袋。",
+        "solution":  "【分析】(1)一个\u0027正\u0027字是5笔,通过数\u0027正\u0027字可知每家一周内用了几个塑料袋,然后比较大小,即可知谁家使用的塑料袋最多,谁家使用的塑料袋最少。(2)把四家使用的塑料袋个数加再一起,即可求出四家一共使用了多少个塑料袋。(3)根据统计结果,结合生活常识去解答,如:尽量少使用塑料袋,多使用可以多次利用的购物袋。(答案不唯一)\n\n【详解】(1)通过数一数可知:典典家用了18个塑料袋,蓝蓝家用了20个塑料袋,天天家用了10个塑料袋,梦梦家用了7个塑料袋。20\u003e18\u003e10\u003e7,蓝蓝家这一周使用的塑料袋最多,梦梦家这一周使用的塑料袋最少。(2)18+20+10+7=38+10+7=48+7=55(个),答:他们四家这一周一共使用了55个塑料袋。(3)答:我的建议是:尽量少使用塑料袋,多使用可以多次利用的购物袋。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "20以内数的比大小",
+                                 "100以内数的连加运算"
+                             ],
+        "source":  "24-25 二年级下·河南南阳·期末"
+    },
+    {
+        "id":  "196",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "欢欢调查班里同学们最喜欢的贴纸形状,除了欢欢每位同学都选择了一张贴纸图片。![](images/11158.png)\n(1)收集数据记录。用画\u0027正\u0027字记录:☆,○,△,□.\n(2)填写统计表。☆数量( )个,○数量( )个,△数量( )个,□数量( )个.\n(3)喜欢( )的最多,喜欢( )的最少,相差( )个.\n(4)欢欢班上一共有( )人。",
+        "options":  [
+
+                    ],
+        "answer":  "8;3;5;6;☆;○;5;23",
+        "solution":  "【分析】(1)按照从上往下,从左往右的顺序分别数出各个图形的数量,并用画\u0027正\u0027字记录表中;(2)每个\u0027正\u0027字是五笔,根据记录的笔画数填表即可;(3)通过比一比可知,喜欢☆的最多,喜欢○的最少,用喜欢☆的人数减去喜欢○的人数,等于相差多少个;(4)贴纸总数表示除欢欢以外的同学人数,逐一数清每种形状的贴纸数,加上欢欢本人得到全班人数.\n\n【详解】(1)收集数据记录。用画\u0027正\u0027字记录:☆正下,○下,△正,□正一。(2)填写统计表:☆8个,○3个,△5个,□6个。(3)8\u003e6\u003e5\u003e3,8-3=5(个),答:喜欢☆的最多,喜欢○的最少,相差5个。(4)8+6+5+3+1=23(人),答:欢欢班上一共有23人。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "10以内数的比大小",
+                                 "8,9的加减法",
+                                 "100以内数的连加运算"
+                             ],
+        "source":  "24-25 二年级下·湖南长沙·期中"
+    },
+    {
+        "id":  "197",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "下面是手工组制作手工的件数情况。![](images/11159.png)\n(1)把统计结果填入表中。\n(2)手工组一共制作了( )件手工。\n(3)第( )组制作的手工最多,第( )组制作的手工最少。\n(4)你还能提出什么数学问题并解答。",
+        "options":  [
+
+                    ],
+        "answer":  "7;5;15;19;46;四;二;第一组和第三组共制作多少件。(问题不唯一)7+15=22(件)",
+        "solution":  "【分析】(1)一个一个地数,最后数到几就是几。正字的每一笔表示1件。(2)将每种手工的件数相加即可求出一共多少件。(3)将各件数作比较即可。20以内的数从小到大排列是:1\u003c2\u003c3\u003c4\u003c5\u003c6\u003c7\u003c8\u003c9\u003c10\u003c11\u003c12\u003c13\u003c14\u003c15\u003c16\u003c17\u003c18\u003c19\u003c20。(4)合理即可,如:第一组和第三组共制作多少件。\n\n【详解】(1)把记录结果填在下表中:第一组7件,第二组5件,第三组15件,第四组19件。(2)7+5+15+19=46(件),手工组一共制作了46件手工。(3)5\u003c7\u003c15\u003c19,第四组制作的手工最多,第二组制作的手工最少。(4)第一组和第三组共制作多少件。(问题不唯一)7+15=22(件),答:第一组和第三组共制作22件。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "\"提问题\"\"填条件\"问题",
+                                 "20以内数的比大小",
+                                 "100以内数的连加运算"
+                             ],
+        "source":  "24-25 二年级下·浙江舟山·期末"
+    },
+    {
+        "id":  "198",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "统计与比较:回答以下问题:苹果:5个 香蕉:8根 梨:7个 桃子:6个\n(1)香蕉比苹果多多少根。\n(2)桃子再买几个就和梨一样多。",
+        "options":  [
+
+                    ],
+        "answer":  "3根;1个",
+        "solution":  "【分析】已知香蕉有8根,苹果有5个,用香蕉数量减去苹果的数量即可得出答案;已知桃子有6个,梨有7个,梨的数量比桃子多,用梨的数量减去桃子的数量即可得出答案.\n\n【详解】(1)8-5=3(根),答:香蕉比苹果多3根。(2)7-6=1(个),答:桃子再买1个就和梨一样多。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "8,9的加减法"
+                             ],
+        "source":  "24-25 二年级下·湖南岳阳·期中"
+    },
+    {
+        "id":  "199",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "观察统计表,下面是气象小组记录的4月份的天气情况。![](images/11160.png)\n(1)把统计结果填入表中。\n(2)从上表中可以看出:这个月中( )的天数最多,( )的天数最少。\n(3)这个月中阴天比晴天少( )天。\n(4)这个月中晴天比雨天多( )天。\n(5)这个月一共有( )天。",
+        "options":  [
+
+                    ],
+        "answer":  "15;6;5;4;晴天;雨天;9;11;30",
+        "solution":  "【分析】(1)依次数出每种天气情况的天数,填写即可,\u0027正\u0027字的每一笔代表1天;(2)比较每种天气情况的天数,找到天数最多和最少的即可;(3)根据减法的意义,晴天的天数-阴天的天数=阴天比晴天少的天数;(4)根据减法的意义,晴天的天数-雨天的天数=晴天比雨天多的天数;(5)将每种天气情况的天数相加就是这个月的总天数.\n\n【详解】(1)表格填写如下:晴天15天,阴天6天,多云5天,雨天4天。(2)15\u003e6\u003e5\u003e4,从上表中可以看出:这个月中晴天的天数最多,雨天的天数最少。(3)15-6=9(天),这个月中阴天比晴天少9天。(4)15-4=11(天),这个月中晴天比雨天多11天。(5)15+6+5+4=30(天),这个月一共有30天。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "20以内数的比大小",
+                                 "十几减7,6的退位减法",
+                                 "100以内数的连加运算"
+                             ],
+        "source":  "24-25 二年级下·山东济宁·期中"
+    },
+    {
+        "id":  "200",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "下面是调查二(4)班同学喜欢的饮料情况。(每人只选一种)![](images/11161.png)\n(1)把统计结果填入表中。\n(2)二(4)班一共有( )个学生。\n(3)如果班上开联欢会,请你根据调查结果,说说买哪几种饮料合理。",
+        "options":  [
+
+                    ],
+        "answer":  "8;5;12;9;11;45;见详解",
+        "solution":  "【分析】(1)根据调查二(4)班同学喜欢的饮料情况,分别数一数喜欢每种饮料的有多少人,然后将结果填入表格中即可;(2)将各种饮料人数相加,即可求出二(4)班一共有多少个学生;(3)如果班上开联欢会,根据调查结果,因为喜欢橙汁和草莓汁的人数比较多,喜欢芒果汁,牛奶和红茶的人数相对较少,所以多买橙汁和草莓汁,少买芒果汁,牛奶和红茶.\n\n【详解】(1)填表:牛奶8人,红茶5人,橙汁12人,芒果汁9人,草莓汁11人。(2)8+5+12+9+11=13+12+9+11=25+9+11=34+11=45(个),答:二(4)班一共有45个学生。(3)12\u003e11\u003e9\u003e8\u003e5,答:如果班上开联欢会,根据调查结果,多买橙汁和草莓汁,少买芒果汁,牛奶和红茶。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "20以内数的比大小",
+                                 "100以内数的连加运算"
+                             ],
+        "source":  "23-24 二年级下·辽宁鞍山·期中"
+    },
+    {
+        "id":  "201",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "妙妙统计布娃娃的个数时,用画\u0027正\u0027字来记录,\u0027正正正T\u0027表示娃娃的个数是( )。",
+        "options":  [
+                        "A. 15个",
+                        "B. 3个",
+                        "C. 17个"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】由题可知,一笔表示1个布娃娃,一个\u0027正\u0027字有5笔,所以表示5个布娃娃。一共有3个正字还多2笔,则娃娃的总数量是3个5的和再加2,由此解答.\n\n【详解】3×5+2=15+2=17(个),所以\u0027正正正T\u0027表示娃娃的个数是17个。故答案为:C",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "表内乘加",
+                                 "乘减"
+                             ],
+        "source":  "23-24二年级下·辽宁鞍山·期中"
+    },
+    {
+        "id":  "202",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "下表是学校门口十分钟内所通过各种车辆的情况。那么这十分钟内通过数量最多的车辆是( )。![](images/124424.png)",
+        "options":  [
+                        "A. 货车",
+                        "B. 小汽车",
+                        "C. 公交车"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】根据题意,依次数出每种车通过的数量再比较大小即可,\u0027正\u0027字的每一笔代表1辆。比较时,位数多的数就大,位数相同比较最高位,最高位大的数就大,最高位相同比较下一位,直到比较出结果为止.\n\n【详解】货车通过了9辆;小汽车通过了12辆;公交车通过了15辆;15\u003e12\u003e9,则这十分钟内通过数量最多的车辆是公交车。故答案为:C",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "单式统计表的特点及填补",
+                                 "20以内数的比大小"
+                             ],
+        "source":  "24-25 二年级下·河北石家庄·月考"
+    },
+    {
+        "id":  "203",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "学校要为各班购买新书,如果想知道你们班的同学最喜欢哪类图书,选择( )方式收集数据最合适。",
+        "options":  [
+                        "A. 到书店问问哪类书卖得最好",
+                        "B. 问你的好朋友喜欢什么书",
+                        "C. 请每名同学写出自己最喜欢的一类图书"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】要想知道班上同学最喜欢哪类图书,那么需要记录好班上每位同学最喜欢的图书类目,而不能通过某个人的喜好或者其它方式的推荐来统计,据此解答.\n\n【详解】A。到书店问问哪类书卖得最好,只能知道买书的人喜欢哪类图书,而不是班上同学喜欢哪类图书;B。问好朋友喜欢什么书,只能知道好朋友的喜好,不能知道班上同学喜欢哪类书;C。请每个同学写出自己最喜欢的一类图书,可以很清楚的记录好班上每位同学最喜欢的图书类目,从而进行购买;所以选择请每名同学写出自己最喜欢的一类图书来收集数据最合适。故答案为:C",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "22-23二年级下·福建厦门·期末"
+    },
+    {
+        "id":  "204",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "下表是学校门口十分钟内所通过各种车辆的情况。那么这十分钟内通过数量最多的车辆是( )。![](images/124437.png)",
+        "options":  [
+                        "A. 大货车",
+                        "B. 小汽车",
+                        "C. 公交车"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】依次数出每种车辆通过的数量,比较数量的多少即可。\u0027正\u0027字的每一笔代表1辆.\n\n【详解】大货车:9辆;小汽车:10辆;公交车:15辆。15\u003e10\u003e9,这十分钟内通过数量最多的车辆是公交车。故答案为:C",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "20以内数的比大小"
+                             ],
+        "source":  "22-23二年级下·福建厦门·期末"
+    },
+    {
+        "id":  "205",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "下面是二(2)班同学出生的季节情况统计表。冬季出生的比春季出生的少( )人。![](images/124455.png)",
+        "options":  [
+                        "A. 8",
+                        "B. 3",
+                        "C. 5"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】根据题意,依次数出冬季和春季出生的人数,再用春季出生的人数-冬季出生的人数=冬季比春季出生少的人数。\u0027正\u0027字的每一笔代表1人.\n\n【详解】冬季出生的有7人;春季出生的有15人。15-7=8(人),冬季出生的比春季出生的少8人。故答案为:A",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "单式统计表的特点及填补"
+                             ],
+        "source":  "23-24 二年级下·河北石家庄·期末"
+    },
+    {
+        "id":  "206",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "下面是四年级一班男同学的身高情况统计表。![](images/124503.png)\n按从高到矮的顺序,李军的身高在男生中排第10名,他的身高在( )厘米之间。",
+        "options":  [
+                        "A. 136~140",
+                        "B. 141~145",
+                        "C. 146~150",
+                        "D. 大于150"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】由表格可知,身高大于150厘米,身高在146~150厘米之间,身高在141~145厘米之间的男生分别有多少人,然后再根据李军的身高在男生中排第10名来推测他的身高即可.\n\n【详解】由表格可知,身高大于150厘米的有4人。李军的身高在男生中排第10名,10\u003e4,所以他的身高不可能大于150厘米。身高在146~150厘米之间的有8人。那么身高大于146厘米的人数为:4+8=12(人)。12\u003e10,那么李军的身高应该在146~150厘米之间。故答案为:C",
+        "knowledge_points":  [
+                                 "单式统计表的特点及填补"
+                             ],
+        "source":  "23-24 四年级上·全国·课后作业"
+    },
+    {
+        "id":  "207",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "选择题",
+        "difficulty":  0.94,
+        "question":  "现在倡导的\u0027绿色出行\u0027是指采用对环境影响较小的出行方式。以下( )项调查,可以帮助我们了解某校学生践行\u0027绿色出行\u0027的情况。",
+        "options":  [
+                        "A. 全校学生上(放)学出行方式的调查",
+                        "B. 全校学生上(放)学所需时间的调查",
+                        "C. 全校各年级学生人数调查",
+                        "D. 全校学生到校时间调查"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】\u0027绿色出行\u0027情况调查是出行方式,交通方式的调查。据此找出合适的选项.\n\n【详解】A。全校学生上(放)学出行方式的调查,可以帮助我们了解某校学生践行\u0027绿色出行\u0027的情况;B。全校学生上(放)学所需时间的调查,可以帮助我们了解学生的上下学花费的时间;C。全校各年级学生人数调查,可以帮助我们了解全校学生人数情况;D。全校学生到校时间调查,可以帮助我们了解学生的到校时间。故答案为:A",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "23-24六年级下·湖南常德·期末"
+    },
+    {
+        "id":  "208",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "小雪统计了一包水果糖中各种口味的糖的颗数,记录结果如下。![](images/124509.png)\n(1)把统计的结果填在下面的表格里。\n口味 苹果味 香蕉味 甜桃味 芒果味\n颗数\n(2)这包水果糖中,( )味的糖最多,( )味的糖最少。\n(3)这包水果糖一共有( )颗。",
+        "options":  [
+
+                    ],
+        "answer":  "14;10;4;16;芒果;甜桃;44",
+        "solution":  "【分析】(1)一个一个地数,最后数到几就是几。(2)将数据进行比较,20以内的数从小到大排列是:1\u003c2\u003c3\u003c4\u003c5\u003c6\u003c7\u003c8\u003c9\u003c10\u003c11\u003c12\u003c13\u003c14\u003c15\u003c16\u003c17\u003c18\u003c19\u003c20。(3)将4种颗数相加即可求出一共多少颗.\n\n【详解】(1)把统计的结果填在下面的表格里:苹果味14颗,香蕉味10颗,甜桃味4颗,芒果味16颗。(2)4\u003c10\u003c14\u003c16,这包水果糖中,芒果味的糖最多,甜桃味的糖最少。(3)14+10+4+16=44(颗),这包水果糖一共有44颗。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "24-25 二年级下·山东济南·阶段练习"
+    },
+    {
+        "id":  "209",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "李老师调查了二(1)班同学最喜欢哪种花的情况,结果如下。![](images/124533.png)\n(1)最喜欢( )花的人数最多,最喜欢( )花的人数最少.\n(2)最喜欢菊花的比最喜欢百合花的多( )人。",
+        "options":  [
+
+                    ],
+        "answer":  "茉莉;百合;3",
+        "solution":  "【分析】(1)比较喜欢每种花的人数,找到人数最多和最少的即可;(2)根据减法的意义,最喜欢菊花的人数-最喜欢百合花的人数=最喜欢菊花比最喜欢百合花多的人数.\n\n【详解】(1)14\u003e12\u003e10\u003e9,最喜欢茉莉花的人数最多,最喜欢百合花的人数最少。(2)12-9=3(人),最喜欢菊花的比最喜欢百合花的多3人。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "20以内数的比大小",
+                                 "十几减9的退位减法"
+                             ],
+        "source":  "24-25二年级下·山东济南·阶段练习"
+    },
+    {
+        "id":  "210",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "下面是小明调查二(1)班同学喜欢吃水果的情况。![](images/124537.png)\n(1)二(1)班一共有学生( )人.\n(2)喜欢吃( )的人数最多,喜欢吃( )的人数最少.\n(3)喜欢吃( )的人数比喜欢吃桃子的人数多6人。",
+        "options":  [
+
+                    ],
+        "answer":  "37;苹果;梨;苹果",
+        "solution":  "【分析】(1)将喜欢吃每种水果的人数相加,就是总人数;(2)比较喜欢吃每种水果的人数,即可解答;(3)根据题意,喜欢吃桃子的人数加上6人,根据结果即可得知是喜欢吃哪种水果的人数.\n\n【详解】(1)14+9+6+8=37(人),二(1)班一共有学生37人。(2)14\u003e9\u003e8\u003e6,喜欢吃苹果的人数最多,喜欢吃梨的人数最少。(3)8+6=14(人),喜欢吃苹果的人数比喜欢吃桃子的人数多6人。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "20以内数的比大小",
+                                 "8加几的进位加法",
+                                 "100以内数的连加运算"
+                             ],
+        "source":  "24-25 二年级下·湖南永州·阶段练习"
+    },
+    {
+        "id":  "211",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "在创建\u0027书香校园\u0027活动中,二(1)班对班级图书角的图书进行了统计,结果如下:![](images/124558.png)\n(1)把统计结果填入表中。\n(2)( )书最多,( )书最少。\n(3)绘本书比历史书多( )本;百科书比童话书少( )本。",
+        "options":  [
+
+                    ],
+        "answer":  "24;10;27;16;童话;百科;8;17",
+        "solution":  "【分析】(1)依次数清楚各种书本的数量,填入表格即可,\u0027正\u0027字的每一笔代表1本;(2)将每种书的数量进行比较,找出数量最多的和最少的即可;比较时,位数多的数就大;位数相同比较最高位,最高位大的数就大;最高位相同比较下一位,直到比较出结果为止;(3)根据减法的意义,绘本书的数量-历史书的数量=绘本书比历史书多的数量;童话书的数量-百科书的数量=百科书比童话书少的数量.\n\n【详解】(1)填表如下:绘本24本,百科10本,童话27本,历史16本。(2)27\u003e24\u003e16\u003e10,童话书最多,百科书最少。(3)24-16=8(本),27-10=17(本),绘本书比历史书多8本;百科书比童话书少17本。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "100以内数的比大小",
+                                 "两位数与整十数的减法",
+                                 "两位数与两位数的退位减法"
+                             ],
+        "source":  "24-25 二年级下·全国·假期作业"
+    },
+    {
+        "id":  "212",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "下面是二(1)班同学最喜欢的颜色情况。![](images/124606.png)\n(1)把统计结果填入表中。\n(2)二(1)班同学最喜欢( )色的人数最多。",
+        "options":  [
+
+                    ],
+        "answer":  "正正;正正;正;正正正;橙",
+        "solution":  "【分析】(1)\u0027正\u0027字中的每一笔代表1,一个\u0027正\u0027字代表5,根据题中整理出来的数据依次用\u0027正\u0027字统计即可;(2)直接比较最喜欢各种颜色的人数,找出最喜欢人数最多的颜色即可.\n\n【详解】(1)填空如下:蓝色正正,红色正正,绿色正,橙色正正正。(2)15\u003e13\u003e10\u003e5,所以二(1)班同学最喜欢橙色的人数最多。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "23-24 二年级下·河北廊坊·期末"
+    },
+    {
+        "id":  "213",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "每年的3月12日是植树节,植树不仅可以美化环境,还能净化空气。二年级各个班植树的棵数情况统计如下:![](images/124617.png)\n(1)把统计结果填入表中。\n(2)二( )班植树棵数最多,二( )班植树棵数最少。\n(3)人人动手,绿化祖国,从我做起,我会尽量( )植树。(填\u0027多\u0027或\u0027少\u0027)",
+        "options":  [
+
+                    ],
+        "answer":  "10;11;7;14;4;3;多",
+        "solution":  "【分析】(1)依次数出每个班植树的棵树填表即可,\u0027正\u0027字的每一笔代表1棵;(2)比较每个班植树的数量,找出数量最多的和最少的;(3)树木多了可以美化环境,净化空气,所以应该多植树.\n\n【详解】(1)表格填写如下:二(1)班10棵,二(2)班11棵,二(3)班7棵,二(4)班14棵。(2)14\u003e11\u003e10\u003e7,二(4)班植树棵数最多,二(3)班植树棵数最少。(3)人人动手,绿化祖国,从我做起,我会尽量多植树。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "20以内数的比大小"
+                             ],
+        "source":  "23-24二年级下·湖北武汉·期末"
+    },
+    {
+        "id":  "214",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "育才小学二(1)班同学最喜欢吃的水果情况统计表。![](images/124622.png)\n(1)最喜欢吃香蕉的有( )人.\n(2)最喜欢吃西瓜的有( )人.\n(3)最喜欢吃苹果的有( )人.\n(4)最喜欢吃桃子的有( )人.\n(5)育才小学二(1)班全班共有( )人。",
+        "options":  [
+
+                    ],
+        "answer":  "15;20;10;10;55",
+        "solution":  "【分析】根据题意分析,在统计数据时,通常用\u0027正\u0027字表示法,\u0027正\u0027字一个笔画代表一个人,一个\u0027正\u0027字表示5个人,据此计算出最喜欢吃的水果的情况人数即可;将所有的最喜欢吃的水果的人数统计出来,然后相加,即可得到全班的人数.\n\n【详解】(1)最喜欢吃香蕉的人数:有3个\u0027正\u0027,即3×5=15(人)。(2)最喜欢吃西瓜的人数:有4个\u0027正\u0027,即4×5=20(人)。(3)最喜欢吃苹果的人数:有2个\u0027正\u0027,即2×5=10(人)。(4)最喜欢吃桃子的人数:有2个\u0027正\u0027,即2×5=10(人)。(5)15+20+10+10=35+10+10=45+10=55(人),所以育才小学二(1)班全班共有55人。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "100以内数的连加运算"
+                             ],
+        "source":  "23-24 二年级下·广东江门·期末"
+    },
+    {
+        "id":  "215",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "调查全班同学最喜欢的运动项目。![](images/124628.png)\n(1)最喜欢( )的人数最多,最喜欢( )的人数最少。\n(2)最喜欢跳绳和踢毽子的一共有( )人。\n(3)最喜欢踢球的比最喜欢跑步的多( )人。",
+        "options":  [
+
+                    ],
+        "answer":  "跳绳;跑步 29 2",
+        "solution":  "【分析】(1)\u0027正\u0027字的每一笔代表1人。最喜欢跳绳的有15人;最喜欢踢球的有12人;最喜欢踢毽子的有14人;最喜欢跑步的有10人。比较人数的多少,找出人数最多的和最少的即可;(2)根据加法的意义,最喜欢跳绳的人数+最喜欢踢毽子的人数=最喜欢跳绳和踢毽子一共的人数;(3)根据减法的意义,最喜欢踢球的人数-最喜欢跑步的人数=最喜欢踢球的比最喜欢跑步的多的人数.\n\n【详解】(1)15\u003e14\u003e12\u003e10,最喜欢跳绳的人数最多,最喜欢跑步的人数最少。(2)15+14=29(人),最喜欢跳绳和踢毽子的一共有29人。(3)12-10=2(人),最喜欢踢球的比最喜欢跑步的多2人。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "20以内数的比大小",
+                                 "两位数与两位数的不进位加法"
+                             ],
+        "source":  "22-23二年级下·江西吉安·期末"
+    },
+    {
+        "id":  "216",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在投票选举时,聪聪得了10票,用画\u0027正\u0027字的方法表示为( ),明明得了17票,用画\u0027正\u0027字的方法表示为( )。",
+        "options":  [
+
+                    ],
+        "answer":  "正正;正正正",
+        "solution":  "【分析】在投票选举时,用画\u0027正\u0027字的方法表示票数,一个\u0027正\u0027字表示5票,一笔表示1票。得了10票,需要画2个\u0027正\u0027字表示;得了17票,需要画3个\u0027正\u0027字加两笔表示;据此解决.\n\n【详解】由题意分析得:在投票选举时,聪聪得了10票,用画\u0027正\u0027字的方法表示为:正正,明明得了17票,用画\u0027正\u0027字的方法表示为:正正正。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "23-24 二年级下·内蒙古通辽·期末"
+    },
+    {
+        "id":  "217",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "小丽站在马路边,对10分钟内经过的车辆做了统计,情况如下:![](images/124635.png)\n(2)( )车最少,( )车最多.\n(3)10分钟内共经过了( )辆车.\n(4)在下一个10分钟内,经过最多的车辆可能是( )车。",
+        "options":  [
+
+                    ],
+        "answer":  "7;13;25;12 摩托;小汽 57 小汽",
+        "solution":  "【分析】(1)依次数出各种车辆的数量填空即可,\u0027正\u0027字的每一笔代表1辆;(2)比较各种车辆的数量,找出最多的和最少的即可;(3)将每种车辆的数量相加就是总数量;(4)10分钟内经过的哪种车最多,则下一个10分钟内就有可能是哪种车经过的最多.\n\n【详解】(1)填写如下:摩托车7辆,面包车13辆,小汽车25辆,大卡车12辆。(2)25\u003e13\u003e12\u003e7,摩托车最少,小汽车最多。(3)7+13+25+12=57(辆),10分钟内共经过了57辆车。(4)在下一个10分钟内,经过最多的车辆可能是小汽车。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "100以内数的比大小",
+                                 "100以内数的连加运算"
+                             ],
+        "source":  "23-24 二年级下·湖南常德·期末"
+    },
+    {
+        "id":  "218",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "下面是二(1)班全体同学兴趣爱好统计情况。![](images/124642.png)\n(2)二(1)班喜欢( )的人数最多,喜欢( )的人数最少.\n(3)二(1)班一共有( )人.\n(4)喜欢踢球的比喜欢唱歌的多( )人,喜欢跳舞的比喜欢看书的少( )人。",
+        "options":  [
+
+                    ],
+        "answer":  "20;16;15;11 看书;跳舞 62 1;9",
+        "solution":  "【分析】(1)根据正数的笔画数出各种兴趣爱好的人数,然后填表。(2)根据(1)中数据的大小得出结论即可。20以内的数从小到大排列是:1\u003c2\u003c3\u003c4\u003c5\u003c6\u003c7\u003c8\u003c9\u003c10\u003c11\u003c12\u003c13\u003c14\u003c15\u003c16\u003c17\u003c18\u003c19\u003c20。(3)根据(1)中数据求和得出结论即可。(4)喜欢踢球的人数-喜欢唱歌的人数=喜欢踢球的比喜欢唱歌的多的人数,喜欢看书的人数-喜欢跳舞的人数=喜欢跳舞的比喜欢看书的少的人数,据此列式计算得出结论即可.\n\n【详解】(1)填表:看书20人,踢球16人,唱歌15人,跳舞11人。(2)11\u003c15\u003c16\u003c20,故二(1)班喜欢看书的人数最多,喜欢跳舞的人数最少。(3)20+16+15+11=36+15+11=51+11=62(人),故二(1)班一共有62人。(4)16-15=1(人),20-11=9(人),故喜欢踢球的比喜欢唱歌的多1人,喜欢跳舞的比喜欢看书的少9人。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "23-24 二年级下·广东珠海·期末"
+    },
+    {
+        "id":  "219",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "下面是光明小学二(1)班同学\u0027竞选班长\u0027情况统计。![](images/133912.png)\n(2)( )的得票数最多,( )的得票数最少.\n(3)二(1)班( )能成功竞选上班长.\n(4)小芳比小红多得( )票。",
+        "options":  [
+
+                    ],
+        "answer":  "149117 小芳 小名 小芳 5",
+        "solution":  "【分析】(1)分别数一数每人的得票数,完成填空即可。(2)比较一下每人的得票数,即可知道谁的得票数最多,谁的得票数最少。(3)得票数最多的同学会竞选上班长。(4)用小芳的得票数减去小红的得票数,求出差,即可解决.\n\n【详解】(1)小芳得票数:14票,小红得票数:9票,小军得票数:11票,小名得票数:7票。(2)14\u003e11\u003e9\u003e7,即小芳的得票数最多,小名的得票数最少。(3)二(1)班小芳能成功竞选上班长。(4)14-9=5(票),即小芳比小红多得5票。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "20以内数的比大小",
+                                 "十几减9的退位减法"
+                             ],
+        "source":  "23-24二年级下·广东江门·期末"
+    },
+    {
+        "id":  "220",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "奇奇,聪聪,妙妙和甜甜四人参加投篮测试,每人投30次,投中数量分别如下。![](images/124701.png)\n(2)如果要选出一名同学去参加篮球比赛,你认为四人中的( )比较合适.\n(3)如果每人再投5次,你认为妙妙( )获得第一名。(填\u0027可能\u0027或\u0027不可能\u0027)",
+        "options":  [
+
+                    ],
+        "answer":  "15;8;11;7 奇奇 不可能",
+        "solution":  "【分析】(1)分别数一数每人的投中次数各是多少(一个正字表示5次),然后完成填空即可。(2)比较一下,谁投中的次数最多,就选谁去参加篮球比赛比较合适。(3)妙妙投中7次,7+5=12(次),再投5次就算妙妙全中,她也就是投中12次;奇奇就算后面5次都不中,12\u003c15,还是奇奇投中的次数多,所以妙妙不可能获得第一名.\n\n【详解】(1)填表:奇奇15次,聪聪8次,妙妙7次,甜甜11次。(2)15\u003e11\u003e8\u003e7,即因为奇奇投中的次数最多,所以如果要选出一名同学去参加篮球比赛,我认为选奇奇比较合适。(3)7+5=12(次),12\u003c15,故如果每人再投5次,我认为妙妙不可能获得第一名。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "单式统计表的特点及填补",
+                                 "20以内数的比大小",
+                                 "7,6加几的进位加法"
+                             ],
+        "source":  "23-24二年级下·山东菏泽·期末"
+    },
+    {
+        "id":  "221",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "小刚调查了本班同学最喜欢吃的水果。![](images/124733.png)\n(1)最喜欢吃( )的人数最多,有( )人;最喜欢( )的人数最少,只有( )人.\n(2)最喜欢吃西瓜的比最喜欢吃榴莲多( )人.\n(3)这个班一共有( )名同学。",
+        "options":  [
+
+                    ],
+        "answer":  "西瓜 15 榴莲 5 10 43",
+        "solution":  "【分析】(1)比较一下最喜欢各种水果人数的多少,即可知道最喜欢吃什么水果的人数最多和最喜欢吃什么水果的人数最少。(2)用最喜欢吃西瓜的人数减去最喜欢吃榴莲的人数,求出差,即可解决。(3)把喜欢各种水果的人数全部加起来,求出和,即可解决.\n\n【详解】(1)15\u003e10\u003e7\u003e6\u003e5,即最喜欢吃西瓜的人数最多,有15人;最喜欢榴莲的人数最少,只有5人。(2)15-5=10(人),最喜欢吃西瓜的比最喜欢吃榴莲多10人。(3)6+10+15+7+5=16+15+7+5=31+7+5=38+5=43(人),即这个班一共有43名同学。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "20以内数的比大小",
+                                 "不退位减法(20以内)",
+                                 "100以内数的连加运算"
+                             ],
+        "source":  "23-24二年级下·新疆克孜勒苏·期末"
+    },
+    {
+        "id":  "222",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "同学们统计了一个路口10分钟内经过的各种车的数量。记录结果如下:![](images/124805.png)\n(2)根据统计结果,这个路口10分钟内经过的( )车最多.\n(3)下一分钟有一辆车经过,最有可能是( )车。",
+        "options":  [
+
+                    ],
+        "answer":  "6;8;33;12 小轿 小轿",
+        "solution":  "【分析】(1)依次数出每种车的数量填空即可;\u0027正\u0027字的每一笔代表1辆;(2)比较各种车的数量,找到最多的即可;(3)10分钟内经过哪种车最多,则下一分钟就有可能是哪种车经过.\n\n【详解】(1)填写如下:货车6辆,大巴车8辆,小轿车33辆,摩托车12辆。(2)33\u003e12\u003e8\u003e6,根据统计结果,这个路口10分钟内经过的小轿车最多。(3)下一分钟有一辆车经过,最有可能是小轿车。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "100以内数的比大小"
+                             ],
+        "source":  "23-24二年级下·贵州铜仁·期末"
+    },
+    {
+        "id":  "223",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "下面是二(1)班学生喜欢图书的人数统计情况。![](images/124817.png)\n(2)喜欢看( )的人最多,喜欢( )的人最少.\n(3)喜欢看科技书的人比喜欢看故事书的人少( )人,喜欢看连环画的同学和喜欢看故事书的同学共有( )人.\n(4)二(1)班共有( )人。",
+        "options":  [
+
+                    ],
+        "answer":  "14;17;7;5 故事书;其他 10;31 43",
+        "solution":  "【分析】(1)依次数出喜欢各种书的人数填空即可,\u0027正\u0027字的每一笔代表1人;(2)比较喜欢各种书的人数,找出最多的和最少的;(3)根据减法的意义,喜欢看故事书的人数-喜欢看科技书的人数=喜欢看科技书比喜欢看故事书少的人数;喜欢看连环画的人数+喜欢看故事书的人数=喜欢看连环画和故事书一共的人数;(4)将所有人数相加就是总人数.\n\n【详解】(1)表格填写如下:连环画14人,故事书17人,科技书7人,其他5人。(2)17\u003e14\u003e7\u003e5,喜欢看故事书的人最多,喜欢其他的人最少。(3)17-7=10(人);14+17=31(人),喜欢看科技书的人比喜欢看故事书的人少10人,喜欢看连环画的同学和喜欢看故事书的同学共有31人。(4)14+17+7+5=43(人),二(1)班共有43人。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "20以内数的比大小",
+                                 "100以内数的连加运算"
+                             ],
+        "source":  "23-24 二年级下·广东汕头·期末"
+    },
+    {
+        "id":  "224",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "用\u0027正\u0027字记录数据非常麻烦。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】用\u0027正\u0027字记录数据是一种常见的简便方法。\u0027正\u0027字的每一笔代表1个数据,每个\u0027正\u0027字有5画,每记录一个数据就添加一笔,最后通过数\u0027正\u0027字的数量快速得出总数(每组5个),由此解答.\n\n【详解】由分析可知,用\u0027正\u0027字记录数据非常简便,原题说法错误。故答案为: ×",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "24-25 二年级下·河北石家庄·月考"
+    },
+    {
+        "id":  "225",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "整理数据就是把原始数据按照一定的顺序和范围进行整理。( )",
+        "options":  [
+
+                    ],
+        "answer":  "√",
+        "solution":  "【分析】根据统计的需要和数据范围的具体情况,把数据的范围划分成几组,并按照一定的顺序排列编制成表,据此解答即可.\n\n【详解】由分析可知:整理数据就是把原始数据按照一定的顺序和范围进行整理。原题说法正确。故答案为:√",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "24-25 六年级下·海南海口·单元测试"
+    },
+    {
+        "id":  "226",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "从两位同学中选一位当班长,不可以用举手的方式决定。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】在数据统计中,哪个同学得票多就可以选为班长,举手是一种简单直接,公平公开的方式,举手时可以统计出同学们支持哪位同学,进而确定当选的结果,由此解答.\n\n【详解】由分析可知,从两位同学中选一位当班长,可以用举手的方式决定。原题说法错误。故答案为: ×",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "24-25二年级下·全国·单元测试"
+    },
+    {
+        "id":  "227",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "在选体育委员的投票中,小明得到的票数是\u0027正正\u0027,他得到了10票。( )",
+        "options":  [
+
+                    ],
+        "answer":  "√",
+        "solution":  "【分析】正字的每一笔代表一个一,一个正字表示5,据此解答.\n\n【详解】5+5=10(票),在选体育委员的投票中,小明得到的票数是\u0027正正\u0027,他得到了10票。原题说法正确。故答案为:√",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "23-24 二年级下·四川绵阳·期末"
+    },
+    {
+        "id":  "228",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "在统计数据时,一定要用画\u0027正\u0027字的方法表示。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】统计数据的方法有多种多样,根据数据的具体情况,选择合适的统计方法即可,用画\u0027正\u0027字的方法表示只是其中的一种方法;还有别的方法,比如还可以画\u0027√\u0027,画\u0027○\u0027等表示方法.\n\n【详解】由题意分析得:在统计数据时,一定要用画\u0027正\u0027字的方法表示;此说法不正确。故答案为: ×",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "23-24 二年级下·内蒙古通辽·期末"
+    },
+    {
+        "id":  "229",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "将下列图形分类统计(画出简单统计表)。○ □○ □○ △ △ △ ○有( )个,△有( )个,□有( )个。",
+        "options":  [
+
+                    ],
+        "answer":  "3;3;2;统计表见详解",
+        "solution":  "【分析】圆形没有直直的边;三角形有3条直直的边;正方形是方方正正的,有四条直直的边,每条边都相等。根据题意,依次数出每种图形的数量,填写即可,画统计表时,第一行是图形的种类,第二行是各图形的数量.\n\n【详解】由分析得:○有3个,△有3个,□有2个。统计表:图形○△□数量(个)332",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "长方形",
+                                 "正方形",
+                                 "三角形和圆的初步认识"
+                             ],
+        "source":  "24-25 一年级下·湖南岳阳·期中"
+    },
+    {
+        "id":  "230",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "聪聪芳芳调查了二(2)班同学最喜欢参加的体育运动,下面是他的调查记录。(每人都选且只选一种)![](images/124842.png)\n(1)喜欢( )的同学最多;喜欢参加( )的同学最少.\n(2)喜欢( )和( )的人数同样多.\n(3)喜欢跑步的同学比喜欢打乒乓球的少( )人.\n(4)算一算,二(1)班一共有学生多少人。\n(5)根据调查记录自己提出一个数学问题,并解答。",
+        "options":  [
+
+                    ],
+        "answer":  "打乒乓球;跑步 打篮球;跳绳 6 6+10+6+8+4=34(人);34人 喜欢踢毽子的比喜欢跑步的多几人。(答案不唯一)8-4=4(人)",
+        "solution":  "【分析】(1)一个正字表示5个人,一个图形表示一个人,数数再进行比较即可;(2)根据数数即可知道喜欢打篮球和跳绳的人数同样多;(3)用喜欢打乒乓球的人数减去喜欢跑步的人数即可;(4)把所有运动的人数加起来即可;(5)喜欢踢毽子的比喜欢跑步的多几人。(答案不唯一)\n\n【详解】(1)10\u003e8\u003e6\u003e4,喜欢打乒乓球的同学最多;喜欢参加跑步的同学最少。(2)喜欢打篮球和跳绳的人数同样多。(3)10-4=6(人),喜欢跑步的同学比喜欢打乒乓球的少6人。(4)6+10+6+8+4=34(人),答:二(1)班一共有学生34人。(5)喜欢踢毽子的比喜欢跑步的多几人。(答案不唯一)8-4=4(人),答:喜欢踢毽子的比喜欢跑步的多4人。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "\u0027提问题\u0027\u0027填条件\u0027问题",
+                                 "数一数"
+                             ],
+        "source":  "24-25 二年级下·湖南永州·阶段练习"
+    },
+    {
+        "id":  "231",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "根据下面的统计信息回答问题。二(1)班同学喜欢吃水果的人数 ![](images/124846.png)\n(1)喜欢吃( )的人最多,喜欢吃( )的人最少.\n(2)喜欢吃西瓜的比喜欢吃梨的多( )人.\n(3)一共统计了( )人。",
+        "options":  [
+
+                    ],
+        "answer":  "西瓜 梨 9 46",
+        "solution":  "【分析】(1)分别根据正字的笔画数量数出喜欢各种水果的人的数量,依次是7人,15人,16人,8人,然后比较大小得出结论即可。(2)喜欢吃西瓜的人数-喜欢吃梨的人数=喜欢吃西瓜的比喜欢吃梨的多的人数。(3)把喜欢各种水果的人数相加得出一共统计的人数.\n\n【详解】(1)7\u003c8\u003c15\u003c16,故喜欢吃西瓜的人最多,喜欢吃梨的人最少。(2)16-7=9(人),故喜欢吃西瓜的比喜欢吃梨的多9人。(3)7+15+16+8=22+16+8=38+8=46(人),故一共统计了46人。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "22-23 二年级下·四川凉山·期末"
+    },
+    {
+        "id":  "232",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "二(1)班投票选举班长(每人只投一票,票数最多的人当选班长),投票结果如下表:![](images/124851.png)\n(2)( )的票数最少;根据统计结果,应该选( )当班长.\n(3)李华比李明少( )票.\n(4)有两位同学缺勤没能参加投票,如果他们也投票,结果( )改变。(填\u0027会\u0027或\u0027不会\u0027)",
+        "options":  [
+
+                    ],
+        "answer":  "6;16;12;9 张亮;刘英 3 不会",
+        "solution":  "【分析】(1)依次数出每个候选人的票数填表即可,\u0027正\u0027字的每一笔代表1票;(2)比较每个候选人的票数,找出票数最少的和最多的,最多的就是能当选班长的人;(3)根据减法的意义,李明的票数-李华的票数=李华比李明少的票数;(4)根据题意,看票数第二名的再加上2票会不会超过第一名的票数,若超过或等于结果会改变,小于不会改变.\n\n【详解】(1)表格填写如下:张亮6票,刘英16票,李明12票,李华9票。(2)16\u003e12\u003e9\u003e6,张亮的票数最少;根据统计结果,应该选刘英当班长。(3)12-9=3(票),李华比李明少3票。(4)12+2=14(票);14\u003c16,有两位同学缺勤没能参加投票,如果他们也投票,结果不会改变。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "20以内数的比大小",
+                                 "不进位加法(20以内)",
+                                 "十几减9的退位减法"
+                             ],
+        "source":  "22-23二年级下·四川广元·期末"
+    },
+    {
+        "id":  "233",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "下面是二(1)班同学体育课上参加体育活动的情况,每个表示1人。![](images/124859.png)\n(2)( )的人数最多,有( )人.\n(3)( )的人数最少,有( )人.\n(4)套圈的比踢毽子的少( )人。",
+        "options":  [
+
+                    ],
+        "answer":  "5人;8人;3人;7人 踢球;8 套圈;3 4",
+        "solution":  "【分析】(1)依次数出参加每种体育活动的人数,填表即可;(2)(3)比较喜欢每种体育活动的人数,找出人数最多的和最少的即可;(4)根据减法的意义,踢毽子的人数-套圈的人数=套圈比踢毽子少的人数.\n\n【详解】(1)表格填写如下:跳绳5人,踢球8人,套圈3人,踢毽子7人。(2)8\u003e7\u003e5\u003e3,踢球的人数最多,有8人。(3)套圈的人数最少,有3人。(4)7-3=4(人),套圈的比踢毽子的少4人。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "10以内数的比大小",
+                                 "7的加减法"
+                             ],
+        "source":  "23-24 二年级下·四川南充·期末"
+    },
+    {
+        "id":  "234",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "下面是二年级同学最喜欢的体育运动情况。![](images/124907.png)\n(1)最喜欢( )的同学最多,有( )人。最喜欢( )的同学最少.\n(2)最喜欢打球比最喜欢赛跑的多( )人.\n(3)这次共统计了( )人.\n(4)你还能提出其他数学问题吗。",
+        "options":  [
+
+                    ],
+        "answer":  "跳远;45;赛跑 20 100 最喜欢赛跑和最喜欢打球的一共有多少人。(答案不唯一)",
+        "solution":  "【分析】(1)依次数出喜欢每种体育运动的人数再比较大小,找出人数最多的和最少的即可,比较时,位数多的数就大,位数相同比较最高位,最高位大的数就大;最高位相同比较下一位,直到比较出结果为止,\u0027正\u0027字的每笔代表1人;(2)根据减法的意义,最喜欢打球的人数-最喜欢赛跑的人数=最喜欢打球比最喜欢赛跑多的人数;(3)将喜欢每种体育运动的人数相加,就是统计的总人数;(4)提出的问题符合题意即可,可提出最喜欢赛跑和最喜欢打球的一共有多少人。用加法计算.\n\n【详解】(1)喜欢赛跑的有10人;喜欢打球的有30人;喜欢跳远的有45人;喜欢其他的有15人。45\u003e30\u003e15\u003e10,最喜欢跳远的同学最多,有45人。最喜欢赛跑的同学最少。(2)30-10=20(人),最喜欢打球比最喜欢赛跑的多20人。(3)10+30+45+15=100(人),这次共统计了100人。(4)最喜欢赛跑和最喜欢打球的一共有多少人。(答案不唯一)10+30=40(人),答:最喜欢赛跑和最喜欢打球的一共有40人。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "100以内数的比大小",
+                                 "整十数之间的加减法",
+                                 "100以内数的连加运算"
+                             ],
+        "source":  "22-23二年级下·四川乐山·期末"
+    },
+    {
+        "id":  "235",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "在一次班干部选举中,有四名\u0027学习委员\u0027候选人,他们的得票情况如下![](images/124913.png)\n(1)( )的得票数最多,( )的得票数最少.\n(2)按得票的多少选一人为学习委员,选( )比较合适.\n(3)选举那天,然然因病请假没能参加投票,如果她也投了票,结果可能会怎样。为什么。",
+        "options":  [
+
+                    ],
+        "answer":  "填表:军军15人,明明16人,红红8人,华华12人 明明;红红 明明 见详解",
+        "solution":  "【分析】数一数,依次是15票,16票,8票,12票。(1)(2)比较数据大小即可求解。整数的大小比较:比较数的大小,先看位数的多少,位数多的数就大;位数相同,从高位开始比较,高位上的数大则这个数大,高位上的数相同,就比较下一位。(3)看看然然投票后四人的排序结果是否会变化,不变则无影响,有变化则有影响.\n\n【详解】(1)把统计的结果填在下表中:军军15人,明明16人,红红8人,华华12人。(1)16\u003e15\u003e12\u003e8,明明的得票数最多,红红的得票数最少。(2)按得票的多少选一人为学习委员,选明明比较合适。(3)结果可能会变。如果然然投给军军,军军和明明得票相同,可再投票一次决定学习委员人选。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "20以内数的比大小"
+                             ],
+        "source":  "23-24 二年级下·四川乐山·期末"
+    },
+    {
+        "id":  "236",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "下面是实验小学二(1)班同学最喜欢水果的人数统计情况。![](images/124918.png)\n(2)喜欢吃( )的同学最多。喜欢吃( )的同学最少.\n(3)这个班一共有( )名同学.\n(4)你还能提出其他数学问题并解答吗。",
+        "options":  [
+
+                    ],
+        "answer":  "12;10;5;18;8 西瓜;香蕉 53 喜欢吃西瓜的比喜欢吃芒果的多几人。(答案不唯一)18-10=8(人);8人",
+        "solution":  "【分析】(1)依次数出喜欢每种水果的人数填表即可,\u0027正\u0027字的每一笔代表1人;(2)比较喜欢每种水果的人数,找出人数最多的和最少的即可;(3)将喜欢每种水果的人数相加,就是总人数;(4)提出的问题符合题意即可,可提出喜欢吃西瓜的比喜欢吃芒果的多几人。用减法计算.\n\n【详解】(1)表格填写如下:草莓12人,芒果10人,香蕉5人,西瓜18人,其他8人。(2)18\u003e12\u003e10\u003e8\u003e5,喜欢吃西瓜的同学最多。喜欢吃香蕉的同学最少。(3)12+10+5+18+8=53(名),这个班一共有53名同学。(4)喜欢吃西瓜的比喜欢吃芒果的多几人。(答案不唯一)18-10=8(人),答:喜欢吃西瓜的比喜欢吃芒果的多8人。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "\u0027提问题\u0027\u0027填条件\u0027问题",
+                                 "20以内数的比大小",
+                                 "100以内数的连加运算"
+                             ],
+        "source":  "23-24 二年级下·四川乐山·期中"
+    },
+    {
+        "id":  "237",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "下面是二(1)班同学最喜欢的手工实践活动的调查情况。![](images/124928.png)\n(2)一共有( )名同学参与了这次调查.\n(3)最喜欢( )手工实践活动的人数最多,最喜欢( )手工实践活动的人数最少.\n(4)如果班主任想选一种手工艺品作为本班的特色,选( )比较合适。",
+        "options":  [
+
+                    ],
+        "answer":  "9;6;12;5 32 剪纸;泥塑 剪纸",
+        "solution":  "【分析】(1)\u0027正\u0027字中的每一笔代表1,一个\u0027正\u0027字代表5,根据题中整理出来的\u0027正\u0027字的数据直接填写即可;(2)根据加法的意义,将选择每个手工实践活动的人数全部相加求和即可;(3)直接比较选择各手工实践活动的人数,找出人数最多和最少的手工实践活动分别是什么即可;(4)应该选择班级最多人数喜欢的手工实践活动作为本班的特色.\n\n【详解】(1)填空如下:叶画9人,编织6人,剪纸12人,泥塑5人。(2)9+6+12+5=32(人),所以一共有32名同学参与了这次调查。(3)12\u003e9\u003e6\u003e5,所以最喜欢剪纸手工实践活动的人数最多,最喜欢泥塑手工实践活动的人数最少。(4)如果班主任想选一种手工艺品作为本班的特色,选剪纸比较合适。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "100以内数的连加运算"
+                             ],
+        "source":  "23-24 二年级下·河南南阳·期末"
+    },
+    {
+        "id":  "238",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "观察统计。二(2)班投票选举班长(每人只能投一票),投票结果如下表。![](images/124940.png)\n(1)( )的得票数最多,( )的得票数最少,( )可能成为班长.\n(2)一共有( )人参加投票。",
+        "options":  [
+
+                    ],
+        "answer":  "11;16;17 小兰;小红;小兰 44",
+        "solution":  "【分析】根据\u0027正\u0027的一笔代表1人,一个\u0027√\u0027,\u0027○\u0027都代表1人,确定各个候选人获得票数情况,完成统计表;(1)比较表中数据,确定谁的得票数最多,谁的得票数最少;得票数越多越有可能成为班长;(2)将所有人数得到的票数相加,即可得出有多少人参加投票.\n\n【详解】填表:小红11票,小伟16票,小兰17票。(1)17\u003e16\u003e11,所以小兰的得票数最多,小红的得票数最少,小兰可能成为班长。(2)11+16+17=27+17=44(人),答:一共有44人参加投票。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "100以内数的比大小",
+                                 "100以内数的连加运算"
+                             ],
+        "source":  "23-24 二年级下·贵州六盘水·期末"
+    },
+    {
+        "id":  "239",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "四位同学统计了二(2)班学生参加社团的情况。(每人只参加一种)。![](images/124945.png)\n(2)参加( )社团的人数最多,参加( )社团的人数最少。一共有( )人参加了社团.\n(3)参加书法社团的人数比参加舞蹈社团的多( )人。",
+        "options":  [
+
+                    ],
+        "answer":  "22;6;10;7 书法;朗诵;45 15",
+        "solution":  "【分析】(1)根据\u0027正\u0027的一笔代表1人,一个\u0027√\u0027\u0027△\u0027\u0027○\u0027都代表1人,确定参加各社团的人数,完成统计表;(2)比较表中数据,确定人数最多,最少的社团名称;再将各个社团的人数相加,即可得出一共有多少人参加社团;(3)根据减法的意义列式计算,用参加书法社团的人数减去参加舞蹈社团的人数,即可解答.\n\n【详解】(1)如下表:书法22人,朗诵6人,航模10人,舞蹈7人。(2)22\u003e10\u003e7\u003e6,所以二(1)班参加书法社团的人数最多,参加朗诵社团的人数最少。22+10+7+6=45(人),二(1)班一共有45人参加了社团。(3)22-7=15(人),答:二(1)班参加书法社团的人数比参加舞蹈社团的人数多15人。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "100以内数的比大小",
+                                 "100以内数的连加运算"
+                             ],
+        "source":  "23-24 二年级下·河南濮阳·期末"
+    },
+    {
+        "id":  "240",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "下面是小文对本班同学暑假最想去的地方调查情况统计。(每人只能选一种)![](images/124952.png)\n(1)把统计结果填入表中。\n(2)根据统计结果,暑假最想去( )的人数最多,最想去( )的人数最少。\n(3)参加这次调查的同学有( )人。\n(4)最想去北京的同学比最想去广州的少( )人,最想去厦门和杭州的同学一共有( )人。\n(5)你暑假最想去哪玩。那个地方哪一点最吸引你。",
+        "options":  [
+
+                    ],
+        "answer":  "9;21;7;12;厦门;杭州;49;3;28;见详解",
+        "solution":  "【分析】(1)根据调查情况统计,分别数一数暑假最想去的地方各有几人,然后完成统计表即可。(2)比较一下暑假最想去的地方人数的多少,即可知道想去哪个地方的人数最多,想去哪个地方的人数最少。(3)用加法把所有的调查人数加起来,求出和,即可解决。(4)用最想去广州的人数减去最想去北京的人数,求出差,就是最想去北京的同学比最想去广州的少多少人;把最想去厦门的人数与最想去杭州的人数加起来,求出和,就是最想去厦门和杭州的同学一共有多少人。(5)根据自己的想法,写出想去的地方,并说明吸引自己的点是什么即可,答案不唯一.\n\n【详解】(1)填表:北京9人,厦门21人,杭州7人,广州12人。(2)21\u003e12\u003e9\u003e7,即根据统计结果,暑假最想去厦门的人数最多,最想去杭州的人数最少。(3)9+21+7+12=49(人),即参加这次调查的同学有49人。(4)12-9=3(人),21+7=28(人),即最想去北京的同学比最想去广州的少3人,最想去厦门和杭州的同学一共有28人。(5)答:暑假最想去北京;北京天安门前的每天升国旗最吸引我,想去看看。(答案不唯一)",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "单式统计表的特点及填补",
+                                 "100以内数的比大小",
+                                 "100以内数的连加运算"
+                             ],
+        "source":  "23-24 二年级下·江西赣州·期末"
+    },
+    {
+        "id":  "241",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "下面是学校对二(1)班同学最喜欢的手工实践活动人数调查情况。![](images/124958.png)\n(1)把统计结果填入表中。\n(2)一共有( )名同学参加了这次调查。\n(3)最喜欢( )手工实践活动的人数最多,最喜欢( )手工实践活动的人数最少。\n(4)如果班主任李老师想选一种手工实践活动作为本班的特色,选( )比较合适。",
+        "options":  [
+
+                    ],
+        "answer":  "9;6;12;5;32;折纸;剪纸;折纸",
+        "solution":  "【分析】(1)依次数出喜欢每种手工实践活动的人数填表即可,\u0027正\u0027字的每一笔代表1人;(2)将喜欢每种手工实践活动的人数相加就是总人数;(3)比较喜欢每种手工实践活动的人数,找出人数最多的和人数最少的;(4)喜欢哪种手工实践活动的人数最多就选择哪种作为本班特色.\n\n【详解】(1)表格填写如下:贴画9人,编织6人,折纸12人,剪纸5人。(2)9+6+12+5=32(名),一共有32名同学参加了这次调查。(3)12\u003e9\u003e6\u003e5,最喜欢折纸手工实践活动的人数最多,最喜欢剪纸手工实践活动的人数最少。(4)因为喜欢折纸的人数最多,所以如果班主任李老师想选一种手工实践活动作为本班的特色,选折纸比较合适。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "20以内数的比大小",
+                                 "100以内数的连加运算"
+                             ],
+        "source":  "23-24 二年级下·湖南衡阳·期末"
+    },
+    {
+        "id":  "242",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "小军统计10分钟内从路口经过的车辆,他的记录如下:![](images/125004.png)\n(1)把统计结果填入表中。\n(2)10分钟内一共( )辆车经过路口。货车比小汽车少( )辆。\n(3)10分钟后开来的第一辆车最有可能是( )车。",
+        "options":  [
+
+                    ],
+        "answer":  "30;15;25;70;5;小汽车",
+        "solution":  "【分析】(1)依次数出每种车的数量填表即可,\u0027正\u0027字的每一笔代表1辆;(2)将每种车的数量相加就是总数量;根据减法的意义,小汽车的数量-货车的数量=货车比小汽车少的数量;(3)这10分钟内经过的哪种车最多,则10分钟后开来的第一辆就可能是什么车.\n\n【详解】(1)表格填写如下:小汽车30辆,客车15辆,货车25辆。(2)30+15+25=70(辆);30-25=5(辆),10分钟内一共70辆车经过路口。货车比小汽车少5辆。(3)30\u003e25\u003e15,10分钟内小汽车经过的最多。10分钟后开来的第一辆车最有可能是小汽车。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "100以内数的比大小",
+                                 "两位数与两位数的退位减法",
+                                 "100以内数的连加运算"
+                             ],
+        "source":  "23-24 二年级下·湖北恩施·期末"
+    },
+    {
+        "id":  "243",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "二(1)班同学的生日在四季中的情况如下表。![](images/125013.png)\n(1)把统计结果填入表中。\n(2)从表中我们可以看出,二(1)班共有( )名同学参与了调查。\n(3)( )季过生日的人数最多,( )季过生日的人数最少。\n(4)你还能提出其他数学问题并解答吗。",
+        "options":  [
+
+                    ],
+        "answer":  "13;10;16;8;47;秋;冬;春季和夏季一共有多少人过生日。(答案不唯一);13+10=23(人)",
+        "solution":  "【分析】(1)依次数出在每个季节过生日的人数填表即可,\u0027正\u0027字的每一笔代表1人;(2)将每个季节过生日的人数相加就是参与调查的总人数;(3)比较每个季节过生日的人数,找出人数最多的和最少的;(4)提出的问题符合题意即可,可提出春季和夏季一共有多少人过生日。用加法计算.\n\n【详解】(1)表格填写如下:春季13人,夏季10人,秋季16人,冬季8人。(2)13+10+16+8=47(名),从表中我们可以看出,二(1)班共有47名同学参与了调查。(3)16\u003e13\u003e10\u003e8,秋季过生日的人数最多,冬季过生日的人数最少。(4)春季和夏季一共有多少人过生日。(答案不唯一)13+10=23(人),答:春季和夏季一共有23人过生日。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "\u0027提问题\u0027\u0027填条件\u0027问题",
+                                 "20以内数的比大小",
+                                 "100以内数的连加运算"
+                             ],
+        "source":  "23-24 二年级下·福建漳州·期末"
+    },
+    {
+        "id":  "244",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "林林调查全班同学最喜欢吃的水果,结果如下。![](images/125025.png)\n(1)把统计结果填入表中。\n(2)最喜欢吃( )的人数最多。林林最喜欢吃橘子,全班最喜欢吃这种水果的有( )人。\n(3)班里要开联欢会,如果你是采购员,该怎样买水果比较合理。",
+        "options":  [
+
+                    ],
+        "answer":  "15;10;21;20;7;香蕉;20;根据调查结果,喜欢吃香蕉和橘子的人数多,就多买些香蕉和橘子,少买一些其他水果。(答案不唯一)",
+        "solution":  "【分析】(1)依次数出喜欢每种水果的人数填表即可,\u0027正\u0027字的每一笔代表1人;(2)比较喜欢每种水果的人数,找出人数最多的,从填写的表格中找出喜欢吃橘子的人数即可;(3)喜欢哪几种水果的人数较多,就多买哪几种水果,其他的就少买些,只要合理即可.\n\n【详解】(1)表格填写如下:苹果15人,梨10人,香蕉21人,橘子20人,其他7人。(2)21\u003e20\u003e15\u003e10\u003e7,最喜欢吃香蕉的人数最多。林林最喜欢吃橘子,全班最喜欢吃这种水果的有20人。(3)班里要开联欢会,如果我是采购员,根据调查结果,喜欢吃香蕉和橘子的人数多,就多买些香蕉和橘子,少买些其他水果。(答案不唯一)",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "23-24 二年级下·河北保定·期末"
+    },
+    {
+        "id":  "245",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "小华调查了班上20个同学星期天体育锻炼的时间(单位:分),结果如下:![](images/125033.png)\n(1)这20个同学中,体育锻炼时间最长是( )分,最短是( )分,最长的比最短的多( )分.\n(2)这20个同学中,体育锻炼时间少于半小时的有( )人,多于1小时的有( )人。",
+        "options":  [
+
+                    ],
+        "answer":  "75;10;65 6;5",
+        "solution":  "【分析】我们需要从提供的数据中找出体育锻炼时间最长和最短的同学,并计算两者的差值。还需要统计体育锻炼时间少于半小时(即30分钟)和多于1小时(即60分钟)的同学数量.\n\n【详解】(1)观察数据,我们可以发现:体育锻炼时间最长的同学是序号17的同学,时间为75分钟。体育锻炼时间最短的同学是序号7的同学,时间为10分钟。最长的比最短的多:75-10=65(分钟)。这20个同学中,体育锻炼时间最长是75分,最短是10分,最长的比最短的多65分。(2)体育锻炼时间少于半小时的同学有:序号3(25分钟),序号7(10分钟),序号9(20分钟),序号14(25分钟),序号18(20分钟),序号20(15分钟),共6人。体育锻炼时间多于1小时的同学有:序号5(70分钟),序号8(65分钟),序号13(65分钟),序号17(75分钟),序号19(70分钟),共5人。体育锻炼时间少于半小时的有6人,多于1小时的有5人。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "时,分的认识及换算"
+                             ],
+        "source":  "23-24三年级下·安徽合肥·期末"
+    },
+    {
+        "id":  "246",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "下面是二(1)班全体同学最喜欢的体育活动的统计情况。(每人只选一项)![](images/125038.png)\n(1)把统计图的结果填在上表空格中.\n(2)最喜欢( )的人数最多,最喜欢( )的人数最少,他们相差( )人。",
+        "options":  [
+
+                    ],
+        "answer":  "8;10;18;12 打篮球;踢球;10",
+        "solution":  "【分析】(1)依次数出喜欢每种体育活动的人数,填写即可,\u0027正\u0027字的每一笔代表1人;(2)比较喜欢每种体育活动的人数,找出人数最多的和最少的,相减即可求出相差多少人.\n\n【详解】(1)表格填写如下:踢球8人,打羽毛球10人,打篮球18人,跳绳12人。(2)18\u003e12\u003e10\u003e8;18-8=10(人),最喜欢打篮球的人数最多,最喜欢踢球的人数最少,他们相差10人。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "20以内数的比大小",
+                                 "不退位减法(20以内)"
+                             ],
+        "source":  "23-24 二年级下·山东济宁·期末"
+    },
+    {
+        "id":  "247",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "下面是小霞调查了本班同学最喜欢的科目,下面是她的调查记录。![](images/125042.png)\n(1)喜欢语文课的有( )人,喜欢数学课的有( )人。喜欢英语课的有( )人,喜欢音乐课的有( )人.\n(2)小霞一共调查了( )人.\n(3)( )是本班同学最喜欢的科目。",
+        "options":  [
+
+                    ],
+        "answer":  "8;9;5;6 28 数学",
+        "solution":  "【分析】(1)数一数,依次是8人,9人,5人,6人,据此填空。(2)将各人数相加即可求出总人数。(3)比较数据大小即可,10以内数大小关系为:0\u003c1\u003c2\u003c3\u003c4\u003c5\u003c6\u003c7\u003c8\u003c9\u003c10.\n\n【详解】(1)喜欢语文课的有8人,喜欢数学课的有9人。喜欢英语课的有5人,喜欢音乐课的有6人。(2)8+9+5+6=28(人),小霞一共调查了28人。(3)9\u003e8\u003e6\u003e5,数学是本班同学最喜欢的科目。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "10以内数的比大小",
+                                 "100以内数的连加运算"
+                             ],
+        "source":  "23-24二年级下·河南驻马店·期末"
+    },
+    {
+        "id":  "248",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "二(1)班有4人参与竞选班长,每名同学只能投一票。投票情况如下:![](images/125047.png)\n(1)把统计结果填入表中。\n(2)二(1)班共有( )人参加了投票。根据票数,( )应该当选班长。\n(3)有2名同学缺勤没有参加投票,如果他们也参加投票,结果( )改变。(填\u0027会\u0027或\u0027不会\u0027)",
+        "options":  [
+
+                    ],
+        "answer":  "5;9;16;13;43;天天;不会",
+        "solution":  "【分析】(1)根据每个人下方的图案数出对应的票数,笑笑的票数等于红红的票数加4即可;(2)求总共用加法,让票数最多的人当选;(3)跟天天票数最接近的是笑笑,就算这2名同学都投给笑笑,笑笑的票数也不超过天天,所以如果他们也参加投票,结果不会改变.\n\n【详解】(1)丽丽下方有5个√,所以丽丽有5票;红红下方有9个○,所以红红有9票;天天下方有3个完整的正字加一划,一个完整的正字是5划,所以天天的票数:5+5+5+1=16(票);笑笑的票数:9+4=13(票)。填表:丽丽5票,红红9票,天天16票,笑笑13票。(2)二(1)班共有:5+9+16+13=43(人);天天获得的票数最多,所以天天应该当选班长。(3)13+2=15(票),15\u003c16,所以不管这两名同学投给谁,天天的票数都是最多的,结果不会改变。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "单式统计表的特点及填补"
+                             ],
+        "source":  "23-24二年级下·浙江台州·期末"
+    },
+    {
+        "id":  "249",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "连江拥有众多自然风光和人文景观。实验小学三年级同学开展研学活动,下面是每个班级随机抽取6名同学做\u0027最喜欢游览的景点\u0027调查(每名同学只能选一个景点)。\u0027最喜欢游览的景点\u0027调查表 ![](images/125053.png)\n(1)一共调查了( )名同学;实验小学三年级一共有( )个班级.\n(2)喜欢游览( )和( )的人数差不多.\n(3)根据调查结果,你预测实验小学三年级同学的研学活动最终会确定哪个景点。请说明理由。",
+        "options":  [
+
+                    ],
+        "answer":  "48;8 长门炮台;贝里蟹谷 青芝山;理由见详解",
+        "solution":  "【分析】(1)把调查表中选择各个旅游景点的人数加起来,求出和,就是一共调查的人数;再用一共调查的人数除以6,求出商,就表示一共有几个班。(2)找出喜欢游览人数差不多的两个景点即可。(3)比较一下喜欢游览的景点人数的多少,然后找出喜欢人数最多的景点,就是研学活动最终会确定的景点.\n\n【详解】(1)16+8+9+4+11=24+9+4+11=33+4+11=37+11=48(人),48/6=8(个),即一共调查了48名同学;实验小学三年级一共有8个班级。(2)由调查表可知,喜欢景点长门炮台的有8人,喜欢景点贝里蟹谷的有9人;故喜欢游览长门炮台和贝里蟹谷的人数差不多。(3)16\u003e11\u003e9\u003e8\u003e4,答:根据调查结果,我预测实验小学三年级同学的研学活动最终会确定去青芝山;理由:根据调查结果可以知道,喜欢去青芝山的人数最多,故实验小学三年级同学的研学活动最终会确定去青芝山。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "数的相对大小关系",
+                                 "100以内数的连加运算"
+                             ],
+        "source":  "23-24二年级下·福建福州·期末"
+    },
+    {
+        "id":  "250",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "二年(1)班同学要开展研学活动,班主任张老师要根据学生的喜好选择研学地点。下面是张老师调查收集的二年(1)班同学最喜欢去的研学地点统计表。(每人只投1票,每票只投1个研学地点)![](images/125100.png)\n(1)二年(1)一共有( )人参加调查。喜欢去( )研学的人数最少.\n(2)根据调查结果,你建议张老师带学生到( )研学,理由是( ).\n(3)调查那天,二年(1)班有2个同学请假没能参加调查,如果她们也参加调查,( )改变你的建议。(填\u0027会\u0027或\u0027不会\u0027)",
+        "options":  [
+
+                    ],
+        "answer":  "47;竹种园;仙都秋千谷;喜欢去仙都秋千谷研学的人数最多;不会",
+        "solution":  "【分析】(1)将每种票数相加即可求出总人数。20以内的数从小到大排列是:1\u003c2\u003c3\u003c4\u003c5\u003c6\u003c7\u003c8\u003c9\u003c10\u003c11\u003c12\u003c13\u003c14\u003c15\u003c16\u003c17\u003c18\u003c19\u003c20,据此比较。(2)根据各项的投票人数建议即可。(3)即使从16票中减去两票,仙都秋千谷仍然是投票最多的地点,所以不会改变.\n\n【详解】(1)16+6+13+7+5=47(人),16\u003e13\u003e7\u003e6\u003e5,二年(1)一共有47人参加调查。喜欢去竹种园研学的人数最少。(2)16\u003e13\u003e7\u003e6\u003e5,根据调查结果,你建议张老师带学生到仙都秋千谷研学,理由是喜欢去仙都秋千谷研学的人数最多。(3)调查那天,二年(1)班有2个同学请假没能参加调查,如果她们也参加调查,不会改变我的建议。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "20以内数的比大小",
+                                 "100以内数的连加运算"
+                             ],
+        "source":  "23-24二年级下·福建漳州·期末"
+    },
+    {
+        "id":  "251",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "刘老师统计二(1)班全体同学每人最喜欢的一种书。![](images/125106.png)\n(1)把统计的数据结果填在空格中.\n(2)喜欢( )的同学最多,喜欢漫画书的同学比喜欢故事书的少( )人,喜欢童话书和喜欢故事书的同学一共有( )人.\n(3)二(1)班一共有( )人。",
+        "options":  [
+
+                    ],
+        "answer":  "10;15;20;5;故事书;5;30;50",
+        "solution":  "【分析】一个\u0027正\u0027字表示5人;(1)分别数一数喜欢各类图书的人数各有多少,然后完成填空即可。(2)比较一下喜欢各种图书的人数大小,即可知道喜欢什么图书人数最多;求喜欢漫画书的同学比喜欢故事书的少多少人,用减法列式计算;求喜欢童话书和喜欢故事书的同学一共有多少人,用加法列式计算。(3)求二(1)班一共有多少人,用加法列式计算.\n\n【详解】(1)填表:童话书10人,漫画书15人,故事书20人,其他5人。(2)20\u003e15\u003e10\u003e5,20-15=5(人),10+20=30(人),即喜欢故事书的同学最多,喜欢漫画书的同学比喜欢故事书的少5人,喜欢童话书和喜欢故事书的同学一共有30人。(3)10+15+20+5=25+20+5=45+5=50(人),即二(1)班一共有50人。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "100以内数的比大小",
+                                 "整十数之间的加减法",
+                                 "100以内数的连加运算"
+                             ],
+        "source":  "23-24 二年级下·河北邯郸·期末"
+    },
+    {
+        "id":  "252",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "下面是二年级同学周末上兴趣班的情况。电脑编程:![](images/125119.png)\n(2)上( )兴趣班的人数最多,上( )兴趣班的人数最少.\n(3)一共有( )人上兴趣班.\n(4)如果二年级又转来一名男生,他可能上( )兴趣班。",
+        "options":  [
+
+                    ],
+        "answer":  "13;10;6;15;书法;舞蹈;44;电脑编程(答案不唯一)",
+        "solution":  "【分析】(1)依次数出每个兴趣班的人数填表即可,\u0027正\u0027字的每一笔代表1人;(2)比较每个兴趣班的人数,找出人数最多的和最少的;(3)每个兴趣班的人数相加就是总人数;(4)他可以上人数最多的兴趣班,因为人数最多说明大家对这一项很感兴趣;也可以通过他是男生,对电脑或者科技制作感兴趣来选择,合理即可.\n\n【详解】(1)表格填写如下:电脑编程13人,科技制作10人,舞蹈6人,书法15人。(2)15\u003e13\u003e10\u003e6,上书法兴趣班的人数最多,上舞蹈兴趣班的人数最少。(3)13+10+6+15=44(人),一共有44人上兴趣班。(4)这名同学是男生,男生对电脑编程和科技制作比较感兴趣,学习电脑编程的人数比科技制作的人数多,可能会选电脑编程。如果二年级又转来一名男生,他可能上电脑编程兴趣班。(答案不唯一)",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "20以内数的比大小",
+                                 "100以内数的连加运算"
+                             ],
+        "source":  "23-24二年级下·河南周口·期末"
+    },
+    {
+        "id":  "253",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "下面是二(1)班学生最喜欢吃的水果调查记录。![](images/125132.png)\n(1)最喜欢吃( )的人数最少.\n(2)该班一共有( )名学生.\n(3)为召开\u0027六一\u0027联欢会,准备买三种水果,如果老师让你买,你会买( ),( ),( )多一些。",
+        "options":  [
+
+                    ],
+        "answer":  "梨;32;苹果;香蕉;葡萄",
+        "solution":  "【分析】(1)通过观察统计表可知,对喜欢吃各种水果的人数进行比较大小,喜欢吃梨的人数最少。(2)根据加法的意义,把这个班喜欢吃各种水果的人数合并起来即可。(3)假如我去买水果,我会根据调查的情况多买苹果,香蕉,葡萄,少买桃,西瓜和梨.\n\n【详解】(1)8\u003e7\u003e6\u003e5\u003e4\u003e2,所以喜欢吃梨的人数最少。(2)8+6+5+4+2+7=14+5+4+2+7=19+4+2+7=23+2+7=25+7=32(名),答:该班一共有32名学生。(3)观察表格可知:喜欢吃苹果,香蕉,葡萄的人数比较多。所以如果老师让我买,我会买苹果,香蕉,葡萄多一些。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "连加(20以内)"
+                             ],
+        "source":  "23-24二年级下·河南商丘·期末"
+    },
+    {
+        "id":  "254",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "动物王国竞选国王,每只动物只能投一票,四只参加竞选的动物得票情况如下![](images/125136.png)\n(1)( )的得票数最多,( )的得票数最少.\n(2)一共有( )只动物参加投票.\n(3)根据统计情况,( )应该当选为动物王国的国王.\n(4)如果有两只动物生病没能参加投票,如果它们也投了票,结果会受影响吗。为什么。",
+        "options":  [
+
+                    ],
+        "answer":  "猴子;兔子;31;猴子;不影响;因为猴子有绝对优势。",
+        "solution":  "【分析】(1)小鹿有8票,大熊猫有6票,兔子有2票,猴子有15票,比较票数即可;(2)每个动物得到的票数加起来即可;(3)应选择票数最多的动物当选国王;(4)如果有两只动物生病没能参加投票,把这两票加在第二名动物上,看是否超过第一名即可判断.\n\n【详解】(1)15\u003e8\u003e6\u003e2,猴子的得票数最多,兔子的得票数最少。(2)8+6+2+15=31(只),一共有31只动物参加投票。(3)根据统计情况,猴子应该当选为动物王国的国王。(4)8+2=10(票),10\u003c15,答:结果不影响;因为猴子有绝对优势。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "23-24 二年级下·山东济南·期末"
+    },
+    {
+        "id":  "255",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "二(1)班同学竞选班长,三位候选人的得票情况如下:![](images/125157.png)\n(2)( )得到的票数最少,( )得到的票数最多.\n(3)( )最有可能当选班长。",
+        "options":  [
+
+                    ],
+        "answer":  "8;12;17;小明;小乐;小乐",
+        "solution":  "【分析】(1)依次数出每人的票数填写表格即可,\u0027正\u0027字的每一笔代表1票;(2)比较每人得票的数量,找出数量最多的和最少的;(3)票数最多的就可能当选班长.\n\n【详解】(1)表格填写如下:小明8票,小天12票,小乐17票。(2)17\u003e12\u003e8,小明得到的票数最少,小乐得到的票数最多。(3)小乐票数最多,所以小乐最有可能当选班长。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "20以内数的比大小"
+                             ],
+        "source":  "23-24二年级下·河北保定·期末"
+    },
+    {
+        "id":  "256",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "下表是统计二(1)班同学的兴趣爱好。![](images/125202.png)\n(1)二(1)班喜欢( )的人最多,喜欢( )的人最少.\n(2)二(1)班一共有( )人.\n(3)喜欢踢球的人比喜欢唱歌的多( )人。",
+        "options":  [
+
+                    ],
+        "answer":  "跳皮筋;跳舞;52;6",
+        "solution":  "【分析】(1)\u0027正\u0027字的每一笔代表1人。喜欢跳皮筋的有20人;喜欢踢球的有16人;喜欢唱歌的有10人;喜欢跳舞的有6人;比较人数的大小,找出人数最多的和最少的;(2)将喜欢每个运动项目的人数相加就是总人数;(3)根据减法的意义,喜欢踢球的人数-喜欢唱歌的人数=喜欢踢球比喜欢唱歌多的人数.\n\n【详解】(1)20\u003e16\u003e10\u003e6,二(1)班喜欢跳皮筋的人最多,喜欢跳舞的人最少。(2)20+16+10+6=52(人),二(1)班一共有52人。(3)16-10=6(人),喜欢踢球的人比喜欢唱歌的多6人。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "20以内数的比大小",
+                                 "100以内数的连加运算"
+                             ],
+        "source":  "23-24 二年级下·广东汕尾·期末"
+    },
+    {
+        "id":  "257",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "下面是5个同学栽花的情况,请根据它完成下面各题。(每小格代表2株花)![](images/125207.png)\n(2)( )栽的花最多,( )栽的花最少.\n(3)5个同学一共栽了多少株花。",
+        "options":  [
+
+                    ],
+        "answer":  "6;6;2;8;6;李勇;郑昆;28株",
+        "solution":  "【分析】(1)两个两个地数,有几格就数几次,数到几就有几株。(2)10以内数大小关系为:0\u003c1\u003c2\u003c3\u003c4\u003c5\u003c6\u003c7\u003c8\u003c9\u003c10,据此比较。(3)将每个人栽的数量相加即可求解.\n\n【详解】(1)把信息整理在表中:刘帅6株,张亮6株,郑昆2株,李勇8株,闫小鹏6株。(2)8\u003e6\u003e2,李勇栽的花最多,郑昆栽的花最少。(3)6+6+2+8+6=28(株),答:5个同学一共栽了28株花。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "10以内数的比大小",
+                                 "100以内数的连加运算"
+                             ],
+        "source":  "23-24 二年级下·江西吉安·期末"
+    },
+    {
+        "id":  "258",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "下面是某校二(3)班学生左眼视力情况。![](images/125212.png)\n(2)5.0及以上的视力是正常的,左眼视力正常的有( )人;低于5.0的有( )人.\n(3)你觉得这个班同学的左眼视力整体情况好吗。你想对他们说什么。答:我觉得这个班同学的左眼视力整体情况( )(填\u0027好\u0027或\u0027不好\u0027),我想对他们说:( )。",
+        "options":  [
+
+                    ],
+        "answer":  "6;4;2;4;3;3;2;12;12;不好;同学们要保护视力,勤做眼保健操,积极参加户外活动。(答案不唯一)",
+        "solution":  "【分析】(1)依次数出每种视力的人数填表即可;(2)将5.0及以上的人数相加就是视力正常的人数;5.0以下的人数相加就是低于5.0的人数;(3)根据统计的结果进行分析,提出合理建议即可.\n\n【详解】(1)表格填写如下:4.7有6人,4.8有4人,4.9有2人,5.0有4人,5.1有3人,5.2有3人,5.3有2人。(2)5.0及以上的人数:4+3+3+2=12(人),低于5.0的人数:6+4+2=12(人),5.0及以上的视力是正常的,左眼视力正常的有12人;低于5.0的有12人。(3)12=12;近视的人数和视力正常的人数同样多,也就是近视的人数占一半。我觉得这个班同学的左眼视力整体情况不好,我想对他们说:同学们要保护视力,勤做眼保健操,积极参加户外活动。(答案不唯一)",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "23-24 二年级下·福建龙岩·期末"
+    },
+    {
+        "id":  "259",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "三年级(1)班同学某天的睡眠情况记录如下:(单位:小时)![](images/125218.png)\n(2)睡眠时间在( )的人最多,国家规定小学生的睡眠时间要达到10小时,这个班有( )名学生达到了国家规定的睡眠时间.\n(3)为了保证充足的睡眠时间,你有什么好的建议。",
+        "options":  [
+
+                    ],
+        "answer":  "1;16;8;7~9小时;8;见详解",
+        "solution":  "【分析】(1)分别数出各个睡眠时间的人数,再填入统计表中。(2)比较各个睡眠时间的人数大小。睡眠时间在10~12小时的学生人数就是达到了国家规定的睡眠时间的学生人数。(3)为了保证充足的睡眠时间,提出合理建议即可.\n\n【详解】(1)根据上面的数据填写下表:7小时以下1人,7~9小时16人,10~12小时8人。(2)16\u003e8\u003e1,睡眠时间在7~9小时的人最多,国家规定小学生的睡眠时间要达到10小时,这个班有8名学生达到了国家规定的睡眠时间。(3)为了保证充足的睡眠时间,我建议早点上床睡觉,睡觉前不玩手机。(答案不唯一)",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "单式统计表的特点及填补"
+                             ],
+        "source":  "23-24三年级下·河南新乡·期末"
+    },
+    {
+        "id":  "260",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "欢欢站在马路边,对5分钟内经过的车辆做了统计,情况如图所示。![](images/125223.png)\n(2)经过的( )车最多,( )车最少。",
+        "options":  [
+
+                    ],
+        "answer":  "25;12;8;19;小汽车;中巴",
+        "solution":  "【分析】(1)依次数出每种车辆的数量填表即可,\u0027正\u0027字的每一笔代表1辆;(2)比较每种车辆的数量,找出最多的和最少的即可.\n\n【详解】(1)表格填写如下:小汽车25辆,面包车12辆,中巴车8辆,电瓶车19辆。(2)25\u003e19\u003e12\u003e8,经过的小汽车最多,中巴车最少。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "100以内数的比大小"
+                             ],
+        "source":  "22-23 二年级下·甘肃天水·期末"
+    },
+    {
+        "id":  "261",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "下面是一家超市一周内销售果汁的情况,请回答下列问题。![](images/125226.png)\n(2)一周内一共销售果汁( )箱,( )种果汁销售量最多,它比销售量最少的果汁多销售( )箱.\n(3)请你根据调查结果,说说下周超市怎样进货更为合理,写出你的建议。",
+        "options":  [
+
+                    ],
+        "answer":  "5;16;14;8;2;45;B;14;B口味的果汁销售数量最多,应该多购进一些,E口味的果汁销售的数量最少,应该少购进一些。(答案不唯一)",
+        "solution":  "【分析】(1)依次数出每种口味的果汁销售的数量填表即可,\u0027正\u0027字的每一笔代表1箱;(2)将每种口味果汁销售的数量相加就是总数量;比较每种果汁销售的数量,找出最多的和最少的,相减即可计算出最多的比最少的多几箱;(3)根据比较的结果,哪种销售的多可多进一些,销售的少可少进一些,合理即可.\n\n【详解】(1)表格填写如下:A5箱,B16箱,C14箱,D8箱,E2箱。(2)5+16+14+8+2=45(箱),16\u003e14\u003e8\u003e5\u003e2,16-2=14(箱),一周内一共销售果汁45箱,B种果汁销售量最多,它比销售量最少的果汁多销售14箱。(3)建议:B口味的果汁销售数量最多,应该多购进一些,E口味的果汁销售的数量最少,应该少购进一些。(答案不唯一)",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "20以内数的比大小",
+                                 "100以内数的连加运算"
+                             ],
+        "source":  "23-24 二年级下·湖南湘西·期末"
+    },
+    {
+        "id":  "262",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "二(1)班要选出\u0027六一\u0027节出游的公园,小小因为请假没有参加投票,班上的同学投票结果如表:![](images/125239.png)\n(1)二(1)班一共有学生( )人.\n(2)愿意去水上乐园的人比愿意去植物园的人多( )人.\n(3)如果小小参加投票,他最有可能去( ).\n(4)全校愿意去水上乐园游玩的人数最多。这一说法合适吗。为什么。",
+        "options":  [
+
+                    ],
+        "answer":  "46;20人;水上乐园;这个说法不合适,因为愿意去水上乐园人数多的是个班级,不能代表全校。",
+        "solution":  "【分析】已知二年级1班同学\u0027六一\u0027节出游公园的投票情况统计,且小小请假未参与投票,分析以下问题;(1)表格中投票人数相加即可得出投票总人数,小小请假未参与投票,投票总人数加上小小即本班总人数;(2)愿意去水上乐园的人有25人,愿意去植物园的人有5人,两者相减即可得答案;(3)票数最多的公园是水上乐园,比其他公园的投票总数还高,所以小小投水上乐园的概率最大;(4)此投票结果为二年级1班的结果,不是全校的投票结果.\n\n【详解】(1)5+10+5+25+1=46(人),故二(1)班共有学生46人。(2)25-5=20(人),愿意去水上乐园的人比愿意去植物园的人多20人。(3)如果小小参加投票,他最有可能去水上乐园。(4)这个说法不合适,因为此投票统计只代表本班意愿,不能代表全校。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "23-24二年级下·湖南长沙·期末"
+    },
+    {
+        "id":  "263",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "以下某年某市6月的天气统计情况。![](images/125244.png)\n(1)完成上面的表格.\n(2)6月份一共有( )天.\n(3)根据上面的信息,请你能提出一个数学问题并解答。",
+        "options":  [
+
+                    ],
+        "answer":  "11;10;9;30;晴天比阴天多多少天。(答案不唯一);11-9=2(天)",
+        "solution":  "【分析】(1)依次数出每种天气的数量填写即可,\u0027正\u0027字的每一笔代表1天;(2)将每种天气的数量相加就是总天数;(3)提出的问题符合题意即可,可提出,晴天比阴天多多少天。用减法计算.\n\n【详解】(1)表格填写如下:晴天11天,雨天10天,阴天9天。(2)11+10+9=30(天),6月份一共有30天。(3)晴天比阴天多多少天。(答案不唯一)11-9=2(天),答:晴天比阴天多2天。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "\u0027提问题\u0027\u0027填条件\u0027问题"
+                             ],
+        "source":  "22-23 二年级下·江西吉安·期末"
+    },
+    {
+        "id":  "264",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "平平和南南调查本班所有同学最喜欢的球类运动,调查结果如下。(每人只能选一种)![](images/125249.png)\n(2)这个班一共有( )人;最喜欢( )运动的人数最多,最喜欢( )运动的人数最少.\n(3)王老师要为同学们购买一些球类用品,你有什么建议。",
+        "options":  [
+
+                    ],
+        "answer":  "7;10;9;15 41;羽毛球;篮球 喜欢羽毛球的人数最多,可多购买一些羽毛球。(答案不唯一)",
+        "solution":  "【分析】(1)根据平平或南南统计的结果,数出数据填表即可,\u0027正\u0027字的每一笔代表1人;(2)将统计出来的人数相加就是总人数;比较每种运动的人数,即可找出人数最多的和人数最少的;(3)根据比较的结果,喜欢哪种球类的运动人多可多购买这个球类用品,答案合理即可.\n\n【详解】(1)表格填写如下:篮球7人,足球10人,排球9人,羽毛球15人。(2)7+10+9+15=41(人),15\u003e10\u003e9\u003e7,这个班一共有41人;最喜欢羽毛球运动的人数最多,最喜欢篮球运动的人数最少。(3)建议:喜欢羽毛球的人数最多,可多购买一些羽毛球。(答案不唯一)",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "20以内数的比大小",
+                                 "100以内数的连加运算"
+                             ],
+        "source":  "23-24二年级下·广西柳州·期末"
+    },
+    {
+        "id":  "265",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "下面是大课间二(1)班同学参加体育活动的调查情况。![](images/125300.png)\n(1)打羽毛球的比踢毽子的多( )人.\n(2)参加体育活动的一共有( )人.\n(3)根据调查结果,你认为二(1)应多准备( )的活动器材。",
+        "options":  [
+
+                    ],
+        "answer":  "6;20;10;3 17 39 羽毛球",
+        "solution":  "【分析】依次数出每种体育活动的人数填表即可,\u0027正\u0027字的每一笔代表1人;(1)根据减法的意义,打羽毛的人数-踢毽子的人数=打羽毛球的比踢毽子多的人数;(2)每种体育活动的人数相加就是总人数;(3)比较每种体育活动的人数,哪种人数最多就应该多准备哪种活动器材.\n\n【详解】表格填写如下:跳绳6人,打羽毛球20人,打乒乓球10人,踢毽子3人。(1)20-3=17(人),打羽毛球的比踢毽子的多17人。(2)6+20+10+3=39(人),参加体育活动的一共有39人。(3)20\u003e10\u003e6\u003e3,根据调查结果,我认为二(1)应多准备羽毛球的活动器材。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "20以内数的比大小",
+                                 "一位数与两位数的退位减法",
+                                 "100以内数的连加运算"
+                             ],
+        "source":  "23-24 二年级下·四川凉山·期末"
+    },
+    {
+        "id":  "266",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "六一儿童节到了,二(1)班准备表演合唱,要从下面四首歌曲中投票选择一首,下面是同学们的投票结果。(每人只投一票)![](images/125305.png)\n(2)选择( )的人数最多,选择( )的人数最少,相差( )人.\n(3)有两名同学请假没能参加投票,如果他们也投了票对最终结果( )产生影响。(填\u0027会\u0027或\u0027不会\u0027)\n(4)你还能提出其他数学问题并解答吗。",
+        "options":  [
+
+                    ],
+        "answer":  "8;5;15;7 《小苹果》;《小燕子》;10 不会 《虫儿飞》和《小燕子》一共有多少票。(答案不唯一)8+5=13(票)",
+        "solution":  "【分析】(1)依次数出每首歌曲投票的数量填表即可,\u0027正\u0027字的每一笔代表1票;(2)比较每首歌曲的票数,找出最多的和最少的,相减即可计算出相差的数量;(3)如果他们都投给票数第二的歌曲,没能超过第一的票数就不会影响结果;反之会影响;(4)提出的问题符合题意即可,可提出,《虫儿飞》和《小燕子》一共有多少票。用加法计算.\n\n【详解】(1)表格填写如下:《虫儿飞》8票,《小燕子》5票,《小苹果》15票,《捉泥鳅》7票。(2)15\u003e8\u003e7\u003e5;15-5=10(人),选择《小苹果》的人数最多,选择《小燕子》的人数最少,相差10人。(3)7+2=9(票);9\u003c15,有两名同学请假没能参加投票,如果他们也投了票对最终结果不会产生影响。(4)《虫儿飞》和《小燕子》一共有多少票。(答案不唯一)8+5=13(票),答:《虫儿飞》和《小燕子》一共有13票。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "\u0027提问题\u0027\u0027填条件\u0027问题",
+                                 "20以内数的比大小",
+                                 "9加几的进位加法"
+                             ],
+        "source":  "22-23 二年级下·四川绵阳·期末"
+    },
+    {
+        "id":  "267",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "下面是二(1)班同学每天运动时间情况。![](images/125311.png)\n(2)二(1)班同学每天运动时间在( )分钟的人数最多;每天运动时间在( )分钟的人数最少.\n(3)全班一共有( )人.\n(4)国家规定小学生每天的运动时间不少于1小时,二(1)班有( )人达到国家规定的运动时间。",
+        "options":  [
+
+                    ],
+        "answer":  "2;10;13;25 多于60分钟;少于30分钟 50 25",
+        "solution":  "【分析】(1)据题意可知,班级内同学的运动情况统计表,一个正字代表5人,可统计出每个时间段的人数。(2)各时间段人数相加即可得出总人数。(3)根据题目要求找到表格中的对应人数即可得出答案.\n\n【详解】(1)统计表:少于30分钟2人,30~45分钟10人,大于45分钟小于60分钟13人,多于60分钟25人。(2)二(1)班同学每天运动时间在(多于60分钟)分钟的人数最多;每天运动时间在(少于30分钟)分钟的人数最少。(3)2+10+13+25=50(人),全班一共有50人。(4)国家规定小学生每天的运动时间不少于1小时,二(1)班有25人达到国家规定的运动时间。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "23-24 二年级下·广东肇庆·期末"
+    },
+    {
+        "id":  "268",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "下面是调查二(2)班学生喜欢的课外书的情况:喜欢《少儿百科全书》的学生有9人 喜欢《奥特曼》的学生有22人 喜欢《宠物小精灵》的学生人数比喜欢《奥特曼》的人数少3人 ![](images/125318.png)\n(1)根据上面的信息填写统计表.\n(2)喜欢( )的人数最多,有( )人。",
+        "options":  [
+
+                    ],
+        "answer":  "19;9;22 《奥特曼》;22",
+        "solution":  "【分析】(1)根据题目中的信息可知,喜欢《少儿百科全书》的学生有9人;喜欢《奥特曼》的学生有22人;喜欢《宠物小精灵》的学生人数比喜欢《奥特曼》的人数少3人,也就是比22人少3人,即22-3;据此完成统计表。(2)比较统计表中的数据即可.\n\n【详解】(1)22-3=19(人),填表:《宠物小精灵》19人,《少儿百科全书》9人,《奥特曼》22人。(2)22\u003e19\u003e9,喜欢《奥特曼》的人数最多,有22人。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "23-24 二年级下·河南南阳·期末"
+    },
+    {
+        "id":  "269",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "下面是某品牌家电公司某周末的家电销售情况。![](images/125323.png)\n根据调查结果,你认为该品牌家电公司近期应该多进哪种电器。",
+        "options":  [
+
+                    ],
+        "answer":  "空调",
+        "solution":  "【分析】根据题意,依次数出每种家电销售的数量再比较大小,选择数量最多的就是应该多进的电器。\u0027正\u0027字的每一笔代表1台.\n\n【详解】电视机销售了10台;冰箱销售了11台;空调销售了15台;洗衣机销售了6台。15\u003e11\u003e10\u003e6,答:我认为该品牌家电公司近期应该多进空调。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "23-24 二年级下·吉林四平·期末"
+    },
+    {
+        "id":  "270",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "下面是我区某书店一周内图书销售情况统计表。![](images/125327.png)\n(2)该书店一周内卖出去多少本书。\n(3)如果书店打算新购进一批书,你有什么建议。",
+        "options":  [
+
+                    ],
+        "answer":  "15;6;12;10 43本 多购入故事类和漫画类,少购入科普类。(答案不唯一)",
+        "solution":  "【分析】(1)1个\u0027正\u0027字有5画,表示5本;(2)把故事类,科普类,漫画类和文学类的本数加起来即可;(3)应多购进销量好的书,少购进销量不好的书。(答案不唯一)\n\n【详解】(1)填表:故事类15本,科普类6本,漫画类12本,文学类10本。(2)15+6=21(本),12+10=22(本),21+22=43(本),答:该书店一周内卖出去43本书。(3)应多购进销量好的书,少购进销量不好的书。(答案不唯一)",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "两位数与两位数的不进位加法"
+                             ],
+        "source":  "23-24二年级下·贵州铜仁·期末"
+    },
+    {
+        "id":  "271",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "如图是二(1)班同学参加课外小组活动的统计情况。![](images/125331.png)每个表示1人.\n(1)参加( )小组的人数最少.\n(2)参加计算机小组的比参加篮球小组的多( )人,参加舞蹈小组的比参加跑步小组少( )人.\n(3)如果每人必须参加,且只能参加一个课外小组,那么二(1)班共有( )人。",
+        "options":  [
+
+                    ],
+        "answer":  "舞蹈 33 40",
+        "solution":  "【分析】(1)根据图示统计汇总参加各个小组的人数后比较大小即可;(2)根据减法的意义,用参加计算机小组的人数减去参加篮球小组的人数即可解答前面的空,用参加舞蹈小组的人数减去参加跑步小组的人数即可解答后面的空;(3)根据加法的意义,把各个小组的人数相加求和即可.\n\n【详解】(1)篮球:9人;舞蹈:8人;计算机:12人;跑步:11人。8\u003c9\u003c11\u003c12,即参加舞蹈小组的人数最少。(2)12-9=3(人),参加计算机小组的比参加篮球小组的多3人;11-8=3(人),参加舞蹈小组的比参加跑步小组少3人。(3)9+8+12+11=17+23=40(人),二(1)班共有40人。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "十几减9的退位减法",
+                                 "十几减8的退位减法",
+                                 "100以内数的连加运算"
+                             ],
+        "source":  "23-24 二年级下·湖南常德·期末"
+    },
+    {
+        "id":  "272",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "如图是二年级(1)班同学\u0027我的理想\u0027的调查情况。![](images/125336.png)\n(1)想当( )的人最多.\n(2)想当警察的比想当医生的多( )人.\n(3)二年级(1)班一共有( )人.\n(4)你长大了想当什么。为什么。",
+        "options":  [
+
+                    ],
+        "answer":  "老师 5 38 我长大了想当医生,因为医生可以治病救人。",
+        "solution":  "【分析】(1)一格表示数量1,据此数清楚喜欢各种职业的人数,再结合题干要求进行解答;(2)要求想当警察的比想当医生的多多少人,根据减法的意义,用想当警察的人数减去想当医生的人数,即可得出答案;(3)根据加法的意义,将喜欢各种职业的人数相加,即可得出一共有多少人;(4)依据自己情况去解答。本小题答案不唯一,例如:我长大了想当医生,因为医生可以治病救人.\n\n【详解】(1)12\u003e10\u003e8\u003e5\u003e3,想当老师的人最多。(2)10-5=5(人),答:想当警察的比想当医生的多5人。(3)5+3+12+10+8=8+12+10+8=20+10+8=30+8=38(人),答:二年级(1)班一共有38人。(4)答:我长大了想当医生,因为医生可以治病救人。(答案不唯一)",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "20以内数的比大小",
+                                 "100以内数的连加运算"
+                             ],
+        "source":  "23-24 二年级下·黑龙江双鸭山·期末"
+    },
+    {
+        "id":  "273",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "二年级二班新学期选举班长,从候选人张丽,王强,孙伟这三名同学中选出一位,下面是同学们记录投票的情况。![](images/125341.png)\n(2)根据统计结果,应该选( )为班长.\n(3)有多少人参加投票。",
+        "options":  [
+
+                    ],
+        "answer":  "13;10;8 张丽 31人",
+        "solution":  "【分析】(1)根据题意,将投票记录数出来,记录在表格里即可;(2)把数出的张丽,王强,孙伟的票数进行比较,票数多的人当选班长;(3)将张丽,王强,孙伟的票数加起来,即可得到有多少人投票.\n\n【详解】(1)投票结果如下表:张丽13票,王强10票,孙伟8票。(2)13\u003e10\u003e8,张丽的票数最多,应该选张丽为班长。(3)13+10+8=23+8=31(人),答:有31人参加投票。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "一位数与两位数的进位加法"
+                             ],
+        "source":  "23-24二年级下·湖南邵阳·期末"
+    },
+    {
+        "id":  "274",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "下面是一年级参加文艺汇演的人数情况(每格代表1人)。![](images/125346.png)\n(1)从图中可以看出,一年级一共有( )人参加文艺汇演.\n(2)参加( )的人数最多,参加( )的人数最少。",
+        "options":  [
+
+                    ],
+        "answer":  "8;6;9;5;28 28 小品;朗诵",
+        "solution":  "【分析】从图上可得:每格代表1,据此数清楚喜欢每个项目的人数,将数据填入表格即可。(1)将喜欢各种项目的人数相加,即可得出一年级一共有多少人参加文艺汇演。(2)根据整数比较大小,找出喜欢人数最多和最少的项目,即可得出答案.\n\n【详解】填表:唱歌8人,跳舞6人,小品9人,朗诵5人,合计28人。(1)8+6+9+5=14+14=28(人),所以一年级一共有28人参加文艺汇演。(2)9\u003e8\u003e6\u003e5,所以喜欢小品的人数最多,喜欢朗诵的人数最少。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "10以内数的比大小",
+                                 "100以内数的连加运算"
+                             ],
+        "source":  "23-24二年级下·广东汕头·期末"
+    },
+    {
+        "id":  "275",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "下表是二(1)班同学的兴趣爱好统计情况。![](images/125352.png)\n(1)二(1)班喜欢( )的人最多,喜欢( )的人最少.\n(2)二(1)班一共有( )人.\n(3)喜欢踢球的比喜欢唱歌的多( )人。",
+        "options":  [
+
+                    ],
+        "answer":  "画画 跳舞 63 2",
+        "solution":  "【分析】一个\u0027正\u0027表示5人,一画表示一人,据此分别数出各种兴趣爱好的人数各有多少。(1)比较一下各种兴趣爱好人数的大小,即可知道什么爱好的人最多,什么爱好的人最少。(2)把各种兴趣爱好的人数加起来,求出和,即可解决。(3)用喜欢踢球的人数减去喜欢唱歌的人数,求出差,即可解决.\n\n【详解】(1)画画:20人,踢球:17人,唱歌15人,跳舞:11人。20\u003e17\u003e15\u003e11,即二(1)班喜欢画画的人最多,喜欢跳舞的人最少。(2)20+17+15+11=37+15+11=52+11=63(人),即二(1)班一共有63人。(3)17-15=2(人),即喜欢踢球的比喜欢唱歌的多2人。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "20以内数的比大小",
+                                 "不退位减法(20以内)",
+                                 "100以内数的连加运算"
+                             ],
+        "source":  "22-23二年级下·陕西宝鸡·期中"
+    },
+    {
+        "id":  "276",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "二(2)班要评选出一名\u0027三好学生\u0027,全班投票记录如下。![](images/125356.png)\n(2)用\u0027○\u0027代替得票数画一画。王文: 李兴伟: 张芳: 刘明:\n(3)全班一共有( )名同学.\n(4)得票最多的是( ),最少的是( ).\n(5)( )可当选为\u0027三好学生\u0027。",
+        "options":  [
+
+                    ],
+        "answer":  "11;13;10;8 见详解 42 李兴伟;刘明 李兴伟",
+        "solution":  "【分析】(1)根据正字的笔画数数出各位同学的票数,然后填表即可。(2)根据(1)中票数作图即可,有多少张票,就在对应名字的上方画多少个圆。(3)把所有人的票数求和得出全班的人数即可。(4)根据(1)中的数据得出得票最多的和最少的人即可。(5)票数最多的学生当选为\u0027三好学生\u0027即可.\n\n【详解】(1)填表:王文11票,李兴伟13票,张芳10票,刘明8票。(2)作图略。(3)11+13+10+8=24+10+8=34+8=42(名),故全班一共有42名同学。(4)得票最多的是李兴伟,最少的是刘明。(5)李兴伟可当选为\u0027三好学生\u0027。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "23-24二年级下·河南周口·期末"
+    },
+    {
+        "id":  "277",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "下面是对二(1)班同学最喜欢《西游记》中的人物的统计记录。![](images/125403.png)\n(2)最喜欢猪八戒的比最喜欢唐僧的多( )人.\n(3)假如这些人物来到校园,让同学们给他们献花,根据上面的统计结果,( )收到的花可能最多。",
+        "options":  [
+
+                    ],
+        "answer":  "11;19;15;8;53 7 孙悟空",
+        "solution":  "【分析】(1)分别数一数各种人物记录的\u0027正\u0027字的笔画各是多少,然后完成填空即可;合计就是全部合起来是多少,用加法计算。一个\u0027正\u0027字表示5人,一画表示1人。(2)用最喜欢猪八戒的人数减去最喜欢唐僧的人数,求出差,即可解决。(3)比较统计表中各数据的大小即可解决.\n\n【详解】(1)11+19+15+8=53(人),统计表如下:唐僧11人,孙悟空19人,猪八戒15人,沙僧8人,合计53人。(2)15-8=7(人),所以最喜欢猪八戒的比最喜欢唐僧的多7人。(3)19\u003e15\u003e11\u003e8,即假如这些人物来到校园,让同学们给他们献花,根据上面的统计结果,孙悟空收到的花可能最多。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "单式统计表的特点及填补",
+                                 "100以内数的比大小",
+                                 "100以内数的连加运算"
+                             ],
+        "source":  "23-24二年级下·四川内江·期末"
+    },
+    {
+        "id":  "278",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "我会收集整理数据。二(2)班同学参加兴趣社团情况如下:![](images/125408.png)\n(2)根据上表填空。①参加( )社团的人数最多。②参加美术社团的人数比参加武术社团的人数多( )人。③二(2)班参加社团一共有( )人。",
+        "options":  [
+
+                    ],
+        "answer":  "10;8;20;10 ①美术 ②10 ③48",
+        "solution":  "【分析】(1)对于统计人数,因为一个\u0027正\u0027字代表5人,所以数\u0027正\u0027字的个数并乘5就能得出相应社团的人数;(2)①要找出参加人数最多的社团,比较四个社团人数的大小即可;②计算参加美术社团比参加武术社团多的人数,用参加美术社团的人数减去参加武术社团的人数即可;③计算二(2)班参加社团的总人数,将四个社团的人数相加即可.\n\n【详解】(1)武术社团有两个\u0027正\u0027字,即2×5=10(人);足球社团有一个\u0027正\u0027字加3画,即5+3=8(人);美术社团有四个\u0027正\u0027字,即4×5=20(人);舞蹈社团有两个\u0027正\u0027字,即2×5=10(人)。填表如下:武术社团10人,足球社团8人,美术社团20人,舞蹈社团10人。(2)①20\u003e10\u003e8,所以参加美术社团人数最多。②20-10=10(人),所以参加美术社团的人数比参加武术社团的人数多10人。③10+8+20+10=18+20+10=38+10=48(人),二(2)班参加社团一共有48人。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "单式统计表的特点及填补",
+                                 "5的乘法口诀及应用"
+                             ],
+        "source":  "23-24 二年级下·广东肇庆·期末"
+    },
+    {
+        "id":  "279",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "解决问题。下面是二(1)班同学参加课外活动小组情况。(每位同学都参加,并且只参加一项。)![](images/125419.png)\n(1)这个班一共有( )人.\n(2)这个班参加( )的人数最多,参加( )的人数最少.\n(3)参加书法的比参加舞蹈的少( )人。",
+        "options":  [
+
+                    ],
+        "answer":  "45 体育 手工 1",
+        "solution":  "【分析】(1)把参加每个小组的人数加起来,求出和,就是这个班的总人数。(2)比较各项课外活动小组的人数大小后,即可判断参加哪个小组的人数最多,参加哪个小组的人数最少。(3)用减法计算参加书法的比参加舞蹈的少几人.\n\n【详解】(1)9+15+7+8+6=24+7+8+6=31+8+6=39+6=45(人),故这个班一共有45人。(2)6\u003c7\u003c8\u003c9\u003c15,故这个班参加体育的人数最多,参加手工的人数最少。(3)8-7=1(人),故参加书法的比参加舞蹈的少1人。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "20以内数的比大小",
+                                 "8,9的加减法",
+                                 "100以内数的连加运算"
+                             ],
+        "source":  "23-24 二年级下·浙江宁波·期末"
+    },
+    {
+        "id":  "280",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "下表是二(2)班5月份在学校图书室的借书情况:![](images/125424.png)\n(2)最喜欢( )的人最多,最喜欢( )的人最少.\n(3)喜欢故事书的比喜欢科技书的多( )人.\n(4)根据以上信息,你还能提出一个其他的数学问题并解答吗。",
+        "options":  [
+
+                    ],
+        "answer":  "31;13;11;16 故事书;连环画 18 喜欢科技书和连环画的共有几人。13+11=24(人)(答案不唯一)",
+        "solution":  "【分析】(1)根据题意可知:数一数各书下面的正字和各图形的数量。(正字的笔划代表1人,数一数有几个正字,一共多少笔划,就是多少人已投票,每个图形代表1人)。(2)将喜欢各书得的票数进行比较,选出得票最多和最少的。(3)求一个数比另一个数多几,用减法计算。(4)结合题意,得出的信息合理即可。例如:喜欢科技书和连环画的共有几人。用喜欢科技书的数量加上喜欢连环画的人数.\n\n【详解】(1)填表如下:故事书31本,科技书13本,连环画11本,其他书16本。(2)31\u003e16\u003e13\u003e11,则最喜欢故事书的人最多,最喜欢连环画的人最少。(3)31-13=18(人),喜欢故事书的比喜欢科技书的多18人。(4)喜欢科技书和连环画的共有几人。13+11=24(人),答:喜欢科技书和连环画的共有24人。(答案不唯一)",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "\u0027提问题\u0027\u0027填条件\u0027问题",
+                                 "100以内数的比大小"
+                             ],
+        "source":  "23-24 二年级下·广西柳州·期末"
+    },
+    {
+        "id":  "281",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "我会想。二(3)班新学期选举班长,要从候选人张丽,王强,孙伟这3名同学中选出一名(每人只投一票)![](images/125430.png)\n(2)根据统计结果,应该选( )当班长.\n(3)一共有( )人参加投票。",
+        "options":  [
+
+                    ],
+        "answer":  "13;10;8 张丽 31",
+        "solution":  "【分析】(1)根据投票结果,分别数一数每个人的得票数,填空即可。(2)把(1)中每个人的得票数按从大到小排序,得票最多的当选班长。(3)因为每人只投一票,所以把张丽,王强,孙伟三个人的得票数加在一起,即为参加投票的人数.\n\n【详解】(1)统计表如下:张丽13票,王强10票,孙伟8票。(2)13\u003e10\u003e8,根据统计结果,应该选张丽当班长。(3)13+10+8=31(人),一共有31人参加投票。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "单式统计表的特点及填补",
+                                 "20以内数的比大小"
+                             ],
+        "source":  "23-24 二年级下·浙江台州·期末"
+    },
+    {
+        "id":  "282",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "![](images/125438.png)\n(2)在家里( )的人数最多,二(1)班一共有( )人。",
+        "options":  [
+
+                    ],
+        "answer":  "11;14;6;6 扫地;37",
+        "solution":  "【分析】(1)分别数一数做各类家务的人数各有多少(一个正字表示5人,一笔表示1人),然后完成填空即可。(2)比较一下做各类家务的人数的多少,即可知道做什么家务的人数最多;把所有做家务的人数加起来,求出和,就是一共的人数.\n\n【详解】(1)填表:叠被子11人,扫地14人,洗碗6人,洗袜子6人。(2)14\u003e11\u003e6=6,11+14+6+6=25+6+6=31+6=37(人),即在家里扫地的人数最多,二(1)班一共有37人。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "单式统计表的特点及填补",
+                                 "20以内数的比大小",
+                                 "100以内数的连加运算"
+                             ],
+        "source":  ""
+    },
+    {
+        "id":  "283",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "下面是小红调查的本班同学喜欢图书种类的情况。![](images/125446.png)\n(1)喜欢( )的人数最多.\n(2)喜欢故事书的比喜欢连环画的少( )人.\n(3)喜欢连环画的和喜欢科技书的一共有( )人。",
+        "options":  [
+
+                    ],
+        "answer":  "连环画 6 26",
+        "solution":  "【分析】(1)比较一下喜欢各类图书人数的多少,即可找出喜欢哪类书的人数最多。(2)用喜欢连环画的人数减去喜欢故事书的人数,求出差,即可解决。(3)把喜欢连环画的和喜欢科技书的人数加起来,求出和,即可解决.\n\n【详解】(1)18\u003e12\u003e8\u003e4,故喜欢连环画的人数最多。(2)18-12=6(人),故喜欢故事书的比喜欢连环画的少6人。(3)18+8=26(人),故喜欢连环画的和喜欢科技书的一共有26人。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "20以内数的比大小",
+                                 "不退位减法(20以内)",
+                                 "一位数与两位数的进位加法"
+                             ],
+        "source":  "23-24 二年级下·内蒙古通辽·期末"
+    },
+    {
+        "id":  "284",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "下面记录的是二(1)班同学的牙齿情况:![](images/125451.png)\n(2)有蛀牙的同学一共有( )人.\n(3)根据调查结果,你想对这个班的同学说什么。",
+        "options":  [
+
+                    ],
+        "answer":  "26;8;5;1 14 见详解",
+        "solution":  "【分析】(1)数一数,没有蛀牙的26人,1颗蛀牙的8人,2颗蛀牙的5人,3颗蛀牙的1人,据此填表。(2)将1颗蛀牙的人数和2颗蛀牙的人数和3颗蛀牙的人数相加即可。(3)可以从保护牙齿方面给出建议,建议合理即可,答案不唯一.\n\n【详解】(1)填表:没有蛀牙26人,1颗蛀牙8人,2颗蛀牙5人,3颗蛀牙1人。(2)8+5+1=14(人),有蛀牙的同学一共有14人。(3)我想对这个班的同学说:少吃甜品,注意牙齿的卫生。(答案不唯一)",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "连加(20以内)"
+                             ],
+        "source":  "23-24二年级下·青海果洛·期末"
+    },
+    {
+        "id":  "285",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "二(1)班同学调查了大家最喜欢的蔬菜情况,调查结果如下。![](images/125502.png)\n(2)二(1)班同学最喜欢( )的人数最多。",
+        "options":  [
+
+                    ],
+        "answer":  "10;16;5 土豆",
+        "solution":  "【分析】(1)分别数一数喜欢各类蔬菜的人数各是多少,然后填空即可。一个正字表示5人,一画表示1人。(2)比较一下喜欢各类蔬菜的人数大小,即可知道同学们最喜欢什么蔬菜.\n\n【详解】(1)填表:白萝卜5人,西红柿10人,土豆16人,黄瓜5人。(2)16\u003e10\u003e5,即二(1)班同学最喜欢土豆的人数最多。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "单式统计表的特点及填补",
+                                 "20以内数的比大小"
+                             ],
+        "source":  "23-24二年级下·贵州黔西·期末"
+    },
+    {
+        "id":  "286",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "二(1)班同学参加学校\u0027经典诵读\u0027比赛,投票决定诵读内容(每人只能投一票),投票结果如下。![](images/125508.png)\n(2)根据统计结果,应选( )为诵读内容.\n(3)有一位同学因缺勤未能参与投票,如果他也投票了,( )影响结果。(填\u0027会\u0027或\u0027不会\u0027)",
+        "options":  [
+
+                    ],
+        "answer":  "18;7;7;10 《三字经》 不会",
+        "solution":  "【分析】(1)根据统计结果,分别数一数每种朗诵内容各有几票,然后完成填空即可。一个正字表示5票,一笔表示1票。(2)比较一下每种朗诵内容票数的大小关系,找出得票最高的朗诵内容,即可解决。(3)18-10=8(票),得票第一名的朗诵内容比第二名的多8票,不管这1票投给哪种朗诵内容,第一名的得票还是第一名,不会影响结果.\n\n【详解】(1)填表:《三字经》18票,《论语》7票,《弟子规》7票,《千字文》10票。(2)18\u003e10\u003e7,即根据统计结果,应选《三字经》为诵读内容。(3)因为得票第一名的朗诵内容比第二名的多8票,一位同学因缺勤未能参与投票,如果他也投票了,这1票不会影响第一名的排名,所以不会影响结果。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "单式统计表的特点及填补",
+                                 "20以内数的比大小"
+                             ],
+        "source":  "23-24 二年级下·海南省直辖县级单位·期末"
+    },
+    {
+        "id":  "287",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "下面是二(2)班16个同学写字比赛得情况。![](images/125513.png)\n(2)得分最高的是( )分,得分最少的是( )分.\n(3)统计表中,得分在( )范围内的人数最多,有( )人。",
+        "options":  [
+
+                    ],
+        "answer":  "1;3;4;8 100;68 90分以上;8",
+        "solution":  "【分析】(1)61-70分的有:68(1人);71-80分的有:75,79,72(3人);81-90分的有:88,87,88,90(4人);90分以上的有:98,100,95,98,97,93,100,92(8人);(2)得分最高的选数字最大的,得分最少的选数字最小的;(3)8\u003e4\u003e3\u003e1,得分在90分以上范围内的人数最多,有8人.\n\n【详解】(1)填表:61-70分1人,71-80分3人,81-90分4人,90分以上8人。(2)得分最高的是100分,得分最少的是68分。(3)得分在90分以上范围内的人数最多,有8人。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "100以内数的比大小"
+                             ],
+        "source":  "23-24二年级下·山东济南·期末"
+    },
+    {
+        "id":  "288",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "下面是二(1)班同学喜欢的球类运动项目统计情况。(所有同学都参与了这次调查,每位同学只能选一个项目)![](images/125518.png)\n(2)二(1)班一共有学生( )人,喜欢( )运动的人最多,喜欢( )运动的人最少。",
+        "options":  [
+
+                    ],
+        "answer":  "13;15;6;12 46;篮球;排球",
+        "solution":  "【分析】(1)\u0027正\u0027字的每一笔代表1人,由此数出人数填写即可;(2)将每个项目的人数相加就是总人数;比较喜欢各种项目的人数,找出最多的人数和最少的人数.\n\n【详解】(1)表格填写如下:足球13人,篮球15人,排球6人,羽毛球12人。(2)13+15+6+12=46(人);15\u003e13\u003e12\u003e6,二(1)班一共有学生46人,喜欢篮球运动的人最多,喜欢排球运动的人最少。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "20以内数的比大小",
+                                 "100以内数的连加运算"
+                             ],
+        "source":  "23-24二年级下·贵州六盘水·期末"
+    },
+    {
+        "id":  "289",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "下面是小明对二年级两个班的学生关于\u0027春游最想去的地方\u0027调查情况统计表。(每人只能选一个地方)![](images/125522.png)\n(1)二年级两个班一共有( )人.\n(2)最想去( )的人数最多,最想去( )的人数最少.\n(3)如果你要组织二年级两个班的学生集体去春游,组织去( )比较合适.\n(4)你还能提出其他数学问题并解答吗。",
+        "options":  [
+
+                    ],
+        "answer":  "80;动物世界;快乐农庄;动物世界;想去水上乐园的人数比想去快乐农庄的多多少人。(答案不唯一);23-9=14(人)",
+        "solution":  "【分析】(1)将想去每个地点的人数相加,就是总人数;(2)比较想去各地点的人数,找出最多的和最少的;(3)哪个地点想去的人多,去哪就比较合适;(4)提出的问题符合题意即可,可提出,想去水上乐园的人数比想去快乐农庄的多多少人。用减法计算.\n\n【详解】(1)23+9+30+18=80(人),二年级两个班一共有80人。(2)30\u003e23\u003e18\u003e9,最想去动物世界的人数最多,最想去快乐农庄的人数最少。(3)想去动物世界的人数最多,所以组织去动物世界比较合适。(4)想去水上乐园的人数比想去快乐农庄的多多少人。(答案不唯一)23-9=14(人),答:想去水上乐园的人数比想去快乐农庄的多14人。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "\u0027提问题\u0027\u0027填条件\u0027问题",
+                                 "100以内数的比大小",
+                                 "100以内数的连加运算"
+                             ],
+        "source":  "23-24二年级下·湖南张家界·期末"
+    },
+    {
+        "id":  "290",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "二(1)班有52人,下面是他们参加课外兴趣小组的统计情况。(每人只参加一个课外兴趣小组)![](images/125526.png)\n(2)电脑组比航模组多( )人,比美术组少( )人.\n(3)二(1)班一共有( )人参加课外兴趣小组,有( )人没参加课外兴趣小组。",
+        "options":  [
+
+                    ],
+        "answer":  "7;5;14;13;4 6;1 43;9",
+        "solution":  "【分析】(1)依次数出各小组的人数填表即可;(2)电脑组的人数-航模组的人数=电脑组比航模组多的人数;美术组的人数-电脑组的人数=电脑组比美术组少的人数;(3)每个小组的人数相加就是参加课外兴趣小组的总人数;二(1)班的总人数-参加课外小组的人数=没参加课外小组的人数.\n\n【详解】(1)表格填写如下:航模组7人,书法组5人,美术组14人,电脑组13人,科技组4人。(2)13-7=6(人);14-13=1(人),电脑组比航模组多6人,比美术组少1人。(3)7+5+14+13+4=43(人);52-43=9(人),二(1)班一共有43人参加课外兴趣小组,有9人没参加课外兴趣小组。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "两位数与两位数的退位减法",
+                                 "100以内数的连加运算"
+                             ],
+        "source":  "23-24二年级下·湖北孝感·期末"
+    },
+    {
+        "id":  "291",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "新华学校二年一班正在竞选班长,投票结果如下:![](images/125553.png)\n(2)老师最后宣布:\u0027( )得了( )票,当选为班长!( )的票数第二,当选为副班长。\u0027\n(3)二年一班有1位同学请假,没能参加投票。如果他也参与投票,( )最有可能当选班长。",
+        "options":  [
+
+                    ],
+        "answer":  "9;16;14;8 果果;16;豆豆 果果",
+        "solution":  "【分析】(1)根据投票结果,分别数一数每人的得票数量,然后填空即可。一个正字表示5票,一笔表示1票。(2)比较一下每人的得票数量多少,得票最多的,当选为班长,得票第二的,当选为副班长。(3)第一名得票16票(果果),第二名得票14票,请假这位同学的票不管投给谁,都没有办法超过第一名的得票,故,果果还是最有可能当选班长.\n\n【详解】(1)填表:壮壮9票,果果16票,豆豆14票,明明8票。(2)16\u003e14\u003e9\u003e8,即老师最后宣布:\u0027果果得了16票,当选为班长!豆豆的票数第二,当选为副班长。\u0027(3)二年一班有1位同学请假,没能参加投票。如果他也参与投票,果果最有可能当选班长。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "单式统计表的特点及填补",
+                                 "20以内数的比大小"
+                             ],
+        "source":  "23-24二年级下·内蒙古通辽·期末"
+    },
+    {
+        "id":  "292",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "下面是二年级同学在庆\u0027六一\u0027活动中,参加节目的人数情况。![](images/125608.png)\n(2)参加节目( )的人数最多,参加节目( )的人数最少.\n(3)参加唱歌的比参加跳舞的少( )人。",
+        "options":  [
+
+                    ],
+        "answer":  "20;25;13;20;8 跳舞;演小品 5",
+        "solution":  "【分析】(1)一个正字表示5人,每一笔表示一个人,分别计算出参加各活动的人数,填在对应的表格中,据此解答。(2)根据第一问中表格的填写内容,找到参加人数最多的活动和参加人数最少的活动,填在空里,据此解答。(3)用跳舞的人数减去唱歌的人数,就是参加唱歌的比参加跳舞的少几人,据此解答.\n\n【详解】(1)填表如下:唱歌20人,跳舞25人,讲故事13人,弹琴20人,演小品8人。(2)参加节目(跳舞)的人数最多,参加节目(演小品)的人数最少。(3)25-20=5(人),参加唱歌的比参加跳舞的少5人。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "两位数与整十数的减法"
+                             ],
+        "source":  "23-24 二年级下·广东东莞·期末"
+    },
+    {
+        "id":  "293",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "调查全班同学最喜欢哪一种球类运动。![](images/125616.png)\n(1)最喜欢( )运动的人最多,最喜欢( )人最少.\n(2)如果你是体育委员,根据这次调查推荐课堂两种活动,你会推荐什么。",
+        "options":  [
+
+                    ],
+        "answer":  "羽毛球;足球 羽毛球和乒乓球",
+        "solution":  "【分析】(1)把喜欢各种球类运动的人数比较大小,找出最多的和最少的;(2)我会推荐同学们喜欢的球类运动人数比较多的两项.\n\n【详解】(1)20\u003e15\u003e8\u003e2,最喜欢羽毛球运动的人最多,最喜欢足球人最少。(2)因为喜欢羽毛球和乒乓球的人数比较多,所以我推荐羽毛球和乒乓球。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "23-24 二年级下·江西九江·期末"
+    },
+    {
+        "id":  "294",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "温习旧知识,可以帮我们找出薄弱点,查漏补缺。二(4)班学生学习的薄弱点的情况如下。(每人只有一个学习薄弱点)![](images/125620.png)\n(1)算一算,二(4)班一共有多少人。\n(2)如果你是二(4)班的数学老师,你会重点对哪些知识进行温习。为什么。",
+        "options":  [
+
+                    ],
+        "answer":  "45人 混合运算;因为这个学习薄弱点的人数最多。",
+        "solution":  "【分析】(1)\u0027正\u0027字的每一笔代表1人,依次数出每项的人数,相加即可计算出总人数;(2)比较各种薄弱点的人数,选择人数最多的就是需要重点温习的知识.\n\n【详解】(1)2+3+17+15+8=45(人),答:二(4)班一共有45人。(2)17\u003e15\u003e8\u003e3\u003e2,我会重点对混合运算进行温习,因为这个学习薄弱点的人数最多。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "20以内数的比大小",
+                                 "100以内数的连加运算"
+                             ],
+        "source":  "23-24 二年级下·广东汕头·期末"
+    },
+    {
+        "id":  "295",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "下面是二(1)班小朋友喜欢喝的饮料调查记录。![](images/125626.png)\n(2)喜欢喝( )的人最多,喜欢喝( )的人最少.\n(3)如果每人只选其中一种饮料,那么调查的二(1)班一共有( )人.\n(4)根据统计结果,你想对二(1)班小朋友说些什么。",
+        "options":  [
+
+                    ],
+        "answer":  "3;9;10 奶茶;白开水 39 见详解",
+        "solution":  "【分析】(1)依据收集和整理的数据,先数一数,再填写统计表;(2)把喜欢喝各种饮料的人数比较大小,即可解此题;(3)将喜欢喝各种饮料的人数相加,求出调查的二(1)班总人数;(4)提出合理的建议即可,答案不唯一.\n\n【详解】(1)填表:奶茶11人,白开水3人,可乐6人,果汁9人,酸奶10人。(2)11\u003e10\u003e9\u003e6\u003e3,即喜欢喝奶茶的人最多,喜欢喝白开水的人最少。(3)11+3+6+9+10=39(人),即如果每人只选其中一种饮料,那么调查的二(1)班一共有39人。(4)我想对二(1)班小朋友说,同学们尽量少喝饮料,里面都有添加剂,对身体不好。(答案不唯一)",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "20以内数的比大小",
+                                 "100以内数的连加运算"
+                             ],
+        "source":  "23-24 二年级下·江西赣州·期末"
+    },
+    {
+        "id":  "296",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "下面是二年级同学最喜欢的体育活动情况。![](images/125633.png)\n(1)根据调查结果,你认为应给二年级多准备哪种体育用品。\n(2)你还能提出其他数学问题并解答吗。",
+        "options":  [
+
+                    ],
+        "answer":  "填表:20;14;15;25;9 毽子 喜欢打乒乓球的比喜欢踢足球的多几人。15-14=1(人)(答案不唯一)",
+        "solution":  "【分析】根据正字的笔画数量数出最喜欢的体育活动的人数,然后填表,根据表中信息准备喜欢人数最多的体育活动的用品,然后提出合理的问题并解决。如喜欢打乒乓球的比喜欢踢足球的多几人。喜欢打乒乓球的人数-喜欢踢足球的人数=喜欢打乒乓球的比喜欢踢足球的多的人数.\n\n【详解】填表:跳绳20人,踢足球14人,打乒乓球15人,踢毽子25人,其他9人。(1)9\u003c14\u003c15\u003c20\u003c25,故应给二年级多准备毽子。(2)喜欢打乒乓球的比喜欢踢足球的多几人。15-14=1(人),答:喜欢打乒乓球的比喜欢踢足球的多1人。(答案不唯一)",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "23-24二年级下·黑龙江哈尔滨·期末"
+    },
+    {
+        "id":  "297",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "学校开运动会,调查了同学们参加运动会各种项目的情况(每人只参加一项)如下表。![](images/125702.png)\n(1)从表中看,参加运动会的同学一共有( )人.\n(2)参加( )的人数最多.\n(3)拍球的同学比跳远的多( )人.\n(4)你还能提出什么数学问题。",
+        "options":  [
+
+                    ],
+        "answer":  "35;拍球;11;拍球和跳绳的一共多少人。(答案不唯一);14+10=24(人)",
+        "solution":  "【分析】(1)\u0027正\u0027字的每一笔代表1人,每个\u0027正\u0027字是5人,由此数出每项运动的人数,相加即可;(2)比较参加各种项目的人数,找出最多的即可;(3)根据减法的意义,拍球的人数-跳远的人数=拍球比跳远多的人数;(4)提出的问题符合题意即可。可提出,拍球和跳绳的一共多少人。用加法计算.\n\n【详解】(1)拍球的有14人;跳绳的有10人;跳远的有3人;跑步的有8人。14+10+3+8=35(人),参加运动会的同学一共有35人。(2)14\u003e10\u003e8\u003e3,参加拍球的人数最多。(3)14-3=11(人),拍球的同学比跳远的多11人。(4)拍球和跳绳的一共多少人。(答案不唯一)14+10=24(人),答:拍球和跳绳的一共24人。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "\u0027提问题\u0027\u0027填条件\u0027问题",
+                                 "20以内数的比大小"
+                             ],
+        "source":  "23-24 二年级下·山东菏泽·期末"
+    },
+    {
+        "id":  "298",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "树木种类知多少。这是探险队行走了5分钟记录下来的数据。![](images/125712.png)\n(2)记录的5分钟里( )数量最多,( )数量最少。如果再记录5分钟,可能是哪种树的数量最多。( )\n(3)你还能提出什么数学问题并解答。问题: 列式解答:",
+        "options":  [
+
+                    ],
+        "answer":  "12;8;23;6;枫树;榕树;枫树;松树和榕树一共有多少棵。(答案不唯一);8+6=14(棵)",
+        "solution":  "【分析】(1)依据收集和整理的数据,先数一数,再填写统计表,然后画出直条,并且标上数据;(2)把各种树的数量比较大小,找出最多的和最少的;哪种数量最多,则再记录5分钟也可能是最多的;(3)提出符合题意的问题即可,可提出松树和榕树一共有多少棵。用加法计算.\n\n【详解】(1)填写涂色如下:樟树12棵,松树8棵,枫树23棵,榕树6棵。(2)23\u003e12\u003e8\u003e6,记录的5分钟里枫树数量最多,榕树数量最少。如果再记录5分钟,可能是枫树的数量最多。(3)问题:松树和榕树一共有多少棵。(答案不唯一)列式解答:8+6=14(棵),答:松树和榕树一共有14棵。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "\u0027提问题\u0027\u0027填条件\u0027问题"
+                             ],
+        "source":  "23-24 二年级下·浙江宁波·期末"
+    },
+    {
+        "id":  "299",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "下面是几个同学记录的一个路口10分钟内所通过的各种交通工具的数量。![](images/125719.png)\n(2)这个路口这10分钟内所通过的( )车最多,( )车最少.\n(3)这个路口这10分钟内一共通过了多少辆车。(列式解答)",
+        "options":  [
+
+                    ],
+        "answer":  "6;8;33;5;小汽车;摩托;6+8+33+5=52(辆)",
+        "solution":  "【分析】(1)由记录表可以得出:这个路口这10分钟内所通过的面包车辆数为表格中面包车一栏所写\u0027正\u0027字笔画数目;大巴车辆数为表格中大巴车一栏所画\u0027√\u0027个数;小汽车辆数为表格中小汽车一栏所写\u0027正\u0027字笔画数目;摩托车辆数为表格中摩托车一栏所画\u0027○\u0027个数。(2)比较(1)中数据的大小得出结论即可。(3)各种车的数量相加得出结论即可.\n\n【详解】(1)填表:面包车6辆,大巴车8辆,小汽车33辆,摩托车5辆。(2)5\u003c6\u003c8\u003c33,故这个路口这10分钟内所通过的小汽车最多,摩托车最少。(3)6+8+33+5=14+33+5=47+5=52(辆),答:这个路口这10分钟内一共通过了52辆车。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "22-23 二年级下·江苏·课后作业"
+    },
+    {
+        "id":  "300",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "二(1)班一共有45位同学,其中有2位同学请假。下面是竞选数学课代表时四位同学的得票情况,每位同学只能投一次票,而且不投弃权票。![](images/125728.png)\n(2)根据投票情况,( )最有可能担任数学课代表.\n(3)如果请假的2位同学参加投票,结果( )(填\u0027会\u0027或\u0027不会\u0027)改变。请说明理由:。",
+        "options":  [
+
+                    ],
+        "answer":  "12;15;7;9 李丽 不会;因为这2位同学都投给赵刚,也不会超过李丽的票数。",
+        "solution":  "【分析】(1)\u0027正\u0027字的每一笔代表1张票,由此统计前三位同学的票数,然后用总人数减去请假的人数,再减去前三位同学的票数即可求出王红的票数,然后填表即可;(2)比较每人的票数,得票数最多的最有可能担任数学课代表;(3)如果请假的2位同学都把票投给第二名,仍然小于15票,所以这2位同学参加投票并不影响投票结果.\n\n【详解】(1)45-2-12-15-7=9(张),填表:赵刚12票,李丽15票,王强7票,王红9票。(2)7\u003c9\u003c12\u003c15,所以李丽最有可能担任数学课代表。(3)如果请假的2位同学参加投票,结果不会改变。理由:因为这2位同学都投给赵刚,也不会超过李丽的票数。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "20以内数的比大小",
+                                 "100以内数的连减运算"
+                             ],
+        "source":  "23-24二年级下·浙江·期末"
+    },
+    {
+        "id":  "301",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "学校开运动会,李老师要为全班同学订购具有班级特色的服装,要使每位同学的服装尺码合适,你认为李老师最需要调查收集的信息是( )。",
+        "options":  [
+                        "A. 调查每位同学喜欢的服装款式",
+                        "B. 调查每位同学喜欢的服装颜色",
+                        "C. 调查每位同学喜欢的运动项目",
+                        "D. 调查每位同学的身高和体重"
+                    ],
+        "answer":  "D",
+        "solution":  "【分析】李老师要为全班同学订购具有班级特色的服装,重点是要使每位同学的服装尺码合适。因为一个人的服装尺码与他的身高,体重,胖瘦有关,李老师调查的重点应放在同学们的身高体重上.\n\n【详解】A。调查的是服装款式,款式合适,尺码不一定合适。B。调查的是服装颜色,颜色合适,尺码不一定合适。C。调查的是每位同学喜欢的运动项目,与服装无关。D。调查的是身高和体重,身高和体重确定就可以确定服装的尺码。李老师最需要调查收集的信息是:调查每位同学的身高和体重。故答案为:D",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "23-24四年级下·北京东城·期末"
+    },
+    {
+        "id":  "302",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "小林用画\"正\"字的方法,统计自行车在街道上的辆数:20分钟统计得\"正正正正一\"票,结果自行车是( )。",
+        "options":  [
+                        "A. 21辆",
+                        "B. 20辆",
+                        "C. 15辆"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】\"正\"字一笔表示一辆自行车,一个\"正\"字表示5辆自行车,据此解答即可.\n\n【详解】有4个\"正\"字:4×5=20,20+1=21(辆),自行车有21辆。故答案为:A",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "23-24二年级下·湖南怀化·期末"
+    },
+    {
+        "id":  "303",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "学校设立\"红领巾交换书屋\"鼓励学生课外借阅,校长想了解全校学生年阅读量情况。以下( )同学介绍的关于书屋的信息对他最有帮助。",
+        "options":  [
+                        "A. 东东:去年全校人均借阅18.5本",
+                        "B. 青青:周一被借出368本",
+                        "C. 红红:六(1)班去年借阅1023本",
+                        "D. 莎莎:我上周借阅2本"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】要体现全校学生的年阅读量情况,信息中必须包含一年的时间和全校的学生阅读量.\n\n【详解】A。去年全校人均借阅18.5本,即体现了全年又包含全校阅读情况,符合要求;B。周一被借出368本,无法体现全年阅读情况,不符合要求;C。六(1)班去年借阅1023本,无法体现全校阅读情况,不符合要求;D。我上周借阅2本,无法体现全校全年阅读情况,不符合要求。故答案为:A",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "23-24六年级下·广东广州·期末"
+    },
+    {
+        "id":  "304",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "铁道部门规定,儿童身高在120厘米以下乘火车免费,120~150厘米享受半价票,150厘米以上需购买全价票。希望小学合唱队乘火车去外地演出,队员身高如表所示。把合唱队员从矮到高排成一排,李军排在第16位,他的情况是( )。![](images/134149.png)",
+        "options":  [
+                        "A. 免票",
+                        "B. 购买半价票",
+                        "C. 购买全价票"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】根据统计表可知:120以下的3人,120~150的12人,把合唱队员从矮到高排成一排,3+12=15(人),李军排在第16位,16\u003e15,说明李军在150以上,150以上需要购买全价票,据此解答即可.\n\n【详解】3+12=15(人),16\u003e15,铁道部门规定,儿童身高在120厘米以下乘火车免费,120~150厘米享受半价票,150厘米以上需购买全价票。希望小学合唱队乘火车去外地演出,队员身高如表所示。把合唱队员从矮到高排成一排,李军排在第16位,他的情况是购买全票。故答案为:C",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "单式统计表的特点及填补",
+                                 "统计图表的综合应用"
+                             ],
+        "source":  "23-24 三年级下·湖北武汉·期中"
+    },
+    {
+        "id":  "305",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "要想知道全校学生最喜欢的校服款式情况,最科学合理的方法是( )。",
+        "options":  [
+                        "A. 进行全校调查,获取数据",
+                        "B. 高年级学生决定",
+                        "C. 询问别的学校"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】根据题意,调查对象是全校的学生,范围较大,人数较多,所以要想知道全校学生最喜欢的校服款式情况,可以进行全校调查统计,根据数据即可得出结论.\n\n【详解】因为全校学生人数较多,所以要想知道全校学生最喜欢的校服款式情况,最科学合理的方法是进行全校调查,获取数据;高年级学生决定只代表部分学生的意见,询问别的学校不能代表本学校学生的意见。所以要想知道全校学生最喜欢的校服款式情况,最科学合理的方法是进行全校调查,获取数据。故答案为:A",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "23-24三年级下·河南漯河·期中"
+    },
+    {
+        "id":  "306",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "用\"正\"字统计四月份天气情况,一个\"正\"字代表( )天。",
+        "options":  [
+                        "A. 1",
+                        "B. 3",
+                        "C. 5"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】在统计时,一个\"正\"表示数量5,一笔表示数量1;据此解决.\n\n【详解】由题意分析得:用\"正\"字统计四月份天气情况,一个\"正\"字代表5天。故答案为:C",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "23-24二年级下·河南三门峡·期中"
+    },
+    {
+        "id":  "307",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "记者柴静深度调查雾霾的纪录片《穹顶之下》自2015年2月28日播出后受到了社会的广泛关注,让人们再次深刻了解到雾霾天气的危害。2014年下半年北京市平均每月雾霾天气有4天,具体情况如下表所示,7月份有( )天是雾霾天气。![](images/134153.png)",
+        "options":  [
+                        "A. 2",
+                        "B. 3",
+                        "C. 4",
+                        "D. 5"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】已知下半年有6个月,下半年北京市平均每月雾霾天气有4天,则下半年北京市一共有(6×4)天是雾霾天气,也就是24天,再用24天减去8~12月的雾霾天气天数,即可求出7月的雾霾天气天数.\n\n【详解】6×4=24(天),1+1+10+4+6=22(天),24-22=2(天),7月份有2天是雾霾天气。故答案为:A",
+        "knowledge_points":  [
+                                 "单式统计表的特点及填补"
+                             ],
+        "source":  "2015三年级下·全国·竞赛"
+    },
+    {
+        "id":  "308",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "如图是聪聪调查全班50名同学生日分别在哪个季度的统计表。根据调查结果,第三季过生日的同学有( )人。![](images/134158.png)",
+        "options":  [
+                        "A. 24",
+                        "B. 23",
+                        "C. 14",
+                        "D. 13"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】用全班人数减去第一,二,四季度过生日的人数即是第三季度过生日的人数.\n\n【详解】50-8-19-9=14(人),第三季过生日的同学有14人。故答案为:C",
+        "knowledge_points":  [
+                                 "单式统计表的特点及填补"
+                             ],
+        "source":  "23-24 三年级上·福建莆田·期末"
+    },
+    {
+        "id":  "309",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "四年级同学想帮助学校食堂解决午饭浪费粮食的问题,你认为他们最需要收集的信息是( )。",
+        "options":  [
+                        "A. 调查同学们吃午餐的地点",
+                        "B. 调查同学们喜欢用的餐具",
+                        "C. 调查同学们吃午餐用的时间",
+                        "D. 调查同学们喜欢吃的食物"
+                    ],
+        "answer":  "D",
+        "solution":  "【分析】根据生活经验可知,要想帮助学校食堂解决午饭浪费粮食的问题,需要调查同学们喜欢吃的食物种类,和用餐地点,餐具,用餐的时间都没有关系,依此选择.\n\n【详解】四年级同学想帮助学校食堂解决午饭浪费粮食的问题,我认为他们最需要收集的信息是调查同学们喜欢吃的食物。故答案为:D",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "22-23 四年级下·北京东城·期末"
+    },
+    {
+        "id":  "310",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "二(3)班要选一位数学课代表,下面是四名候选人的得票情况。(每人只投一票,无人请假)![](images/134202.png)\n(2)二(3)班一共有( )人.\n(3)根据统计结果,应该选( )当数学课代表。",
+        "options":  [
+
+                    ],
+        "answer":  "11;4;8;19;42;聪聪",
+        "solution":  "【分析】(1)统计时画图形的按照图形的个数确定票数,画\"正\"字的根据\"正\"字的笔画确定票数,然后填表即可;(2)把每人得的票数相加就是这个班的总人数;(3)比较每人得的票数,得票数最多的就应该当选为课代表.\n\n【详解】(1)根据统计结果填表:轩轩11票,涵涵4票,可可8票,聪聪19票。(2)11+4+8+19=42(人),二(3)班一共有42人。(3)4\u003c8\u003c11\u003c19,应该选聪聪当数学课代表。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "23-24 二年级下·浙江杭州·期末"
+    },
+    {
+        "id":  "311",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "如下表统计的是二(1)班每个同学最喜欢的运动项目调查情况。![](images/134206.png)\n(1)最喜欢打羽毛球的有( )人,最喜欢踢毽子的有( )人.\n(2)喜欢( )项目的人最少.\n(3)二(1)班准备开展课外活动,根据统计结果,他们最可能开展的活动是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "6;10;跑步;跳绳",
+        "solution":  "【分析】一个正表示5人,一笔表示1人;(1)依据收集和整理的数据,先数一数,再填空即可。(2)把同学最喜欢的各项运动项目数量进行比较大小,即可解决。(3)他们最可能开展的活动是喜欢人数最多的项目.\n\n【详解】打羽毛球:6人;跳绳:13人;跑步:5人;踢毽子:10人;踢足球:8人;(1)最喜欢打羽毛球的有6人,最喜欢踢毽子的有10人。(2)13\u003e10\u003e8\u003e6\u003e5,即喜欢跑步项目的人最少。(3)二(1)班准备开展课外活动,根据统计结果,他们最可能开展的活动是跳绳。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "20以内数的比大小"
+                             ],
+        "source":  "23-24 二年级下·湖南怀化·期末"
+    },
+    {
+        "id":  "312",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "二(2)班同学最想参加劳动课程统计表。![](images/134216.png)\n(2)喜欢参加( )课程的人最多,比想参加工艺制作的人多( )人,想参加( )的人最少。",
+        "options":  [
+
+                    ],
+        "answer":  "5;6;12;16;农耕实验;10;收纳整理",
+        "solution":  "【分析】一个正字表示5人,一笔表示1人。(1)根据给出的统计表,分别数一数最想参加各项劳动课的人数各有多少,然后完成填空即可。(2)比较一下最想参加各项劳动课人数的多少,即可知道喜欢哪个课程人数最多,喜欢哪个课程人数最少,用喜欢课程人数最多的减去想参加工艺制作的人数,求出差,就是喜欢参加课程的人最多的比想参加工艺制作的人多多少人.\n\n【详解】(1)填表:收纳整理5人,工艺制作6人,烧菜实践12人,农耕实验16人。(2)16\u003e12\u003e6\u003e5,16-6=10(人),喜欢参加农耕实验课程的人最多,比想参加工艺制作的人多10人,想参加收纳整理的人最少。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "单式统计表的特点及填补",
+                                 "20以内数的比大小",
+                                 "不退位减法(20以内)"
+                             ],
+        "source":  "23-24 二年级下·山东临沂·期末"
+    },
+    {
+        "id":  "313",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "米日古丽老师为了了解本班学生的视力检测结果,记录得到下表。![](images/134227.png)\n(2)该班一共有( )名学生.\n(3)5.0及以上的是正常的,视力不正常的共有( )名。",
+        "options":  [
+
+                    ],
+        "answer":  "25;10;3;38;13",
+        "solution":  "【分析】(1)依次数出每种视力情况的人数填表即可,\"正\"字的每一笔代表1人;(2)将每种视力情况的人数相加就是总人数;(3)5.0及以上为正常,则把4.9-4.7的人数和4.6-4.2的人数相加,就是视力不正常的人数.\n\n【详解】(1)表格填写如下:5.0及以上25人,4.9-4.7有10人,4.6-4.2有3人。(2)25+10+3=38(名),该班一共有38名学生。(3)10+3=13(名),5.0及以上的是正常的,视力不正常的共有13名。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "不进位加法(20以内)",
+                                 "100以内数的连加运算"
+                             ],
+        "source":  "23-24二年级下·新疆和田·期末"
+    },
+    {
+        "id":  "314",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "二(1)班同学调查了本班男生最喜欢的球类运动,下面是他们的记录:![](images/134232.png)\n二(1)班男生喜欢( )的人数最多,喜欢( )的人数最少,它们相差( )人。",
+        "options":  [
+
+                    ],
+        "answer":  "3;10;2;6;3;足球;排球;8",
+        "solution":  "【分析】数一数,依次是3人,10人,2人,6人,3人,据此填表。比较各类人数的数据大小,10以内数大小关系为:0\u003c1\u003c2\u003c3\u003c4\u003c5\u003c6\u003c7\u003c8\u003c9\u003c10。然后用最多的人数减最少的人数即可.\n\n【详解】填表:喜欢篮球的3人,喜欢足球的10人,喜欢排球的2人,喜欢乒乓球的6人,喜欢羽毛球的3人。2\u003c3\u003c6\u003c10,10-2=8(人),二(1)班男生喜欢足球的人数最多,喜欢排球的人数最少,它们相差8人。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "23-24 二年级下·湖南邵阳·期末"
+    },
+    {
+        "id":  "315",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "下表是金山小学统计二(1)班同学\"竞选班长\"情况统计。![](images/134243.png)\n( )的得票数最多,( )的得票数最少.\n(2)二(1)班一共有( )人.\n(3)张亮比杨红少得( )票。",
+        "options":  [
+
+                    ],
+        "answer":  "15;10;11;7;王明;李丽;43;1",
+        "solution":  "【分析】(1)数一数,依次是15张,10张,11张,7张,比较票数即可求解;(2)将4人的票数相加即可求出一共有多少人;(3)用杨红的票数减张亮的票数即可求解.\n\n【详解】(1)填表:王明15票,张亮10票,杨红11票,李丽7票。15\u003e11\u003e10\u003e7,王明的得票数最多,李丽的得票数最少。(2)15+10+11+7=43(人),二(1)班一共有43人。(3)11-10=1(票),张亮比杨红少得1票。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "23-24二年级下·重庆大足·期末"
+    },
+    {
+        "id":  "316",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "二(1)班同学统计了最喜欢的水果情况,记录结果如下。![](images/134247.png)\n(2)最喜欢吃( )的人数最多,最喜欢吃( )的人数最少.\n(3)二(1)班一共有( )人。",
+        "options":  [
+
+                    ],
+        "answer":  "12;18;10;8;西瓜;桃子;48",
+        "solution":  "【分析】(1)数一数,从上到下依次是12人,18人,10人,8人,据此填空。(2)将人数作比较即可求解。20以内的数从小到大排列是:1\u003c2\u003c3\u003c4\u003c5\u003c6\u003c7\u003c8\u003c9\u003c10\u003c11\u003c12\u003c13\u003c14\u003c15\u003c16\u003c17\u003c18\u003c19\u003c20。(3)将各人数相加即可求出总人数.\n\n【详解】(1)填表:苹果12人,西瓜18人,草莓10人,桃子8人。(2)18\u003e12\u003e10\u003e8,最喜欢吃西瓜的人数最多,最喜欢吃桃子的人数最少。(3)12+18+10+8=48(人),二(1)班一共有48人。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "23-24 二年级下·河北邢台·期末"
+    },
+    {
+        "id":  "317",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "同学们统计一个路口10分钟内所通过的各种交通工具的数量.\n![](images/134258.png)\n(2)10分钟内一共通过了( )辆车。最多的比最少的多( )辆。",
+        "options":  [
+
+                    ],
+        "answer":  "6;8;33;12;59;27",
+        "solution":  "【分析】(1)依次数出各种交通工具的数量填表即可;\"正\"字的每一笔代表1;1个对勾,1个圆点也代表1。(2)将每种车辆的数量相加就是总数量。比较每种车辆的数量,找出最多的和最少的,相减即可求出最多的比最少的多几辆.\n\n【详解】(1)表格填写如下:面包车6辆,大巴车8辆,小轿车33辆,摩托车12辆。(2)6+8+33+12=59(辆),33\u003e12\u003e8\u003e6,33-6=27(辆),10分钟内一共通过了59辆车。最多的比最少的多27辆。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "23-24 二年级下·湖北襄阳·期末"
+    },
+    {
+        "id":  "318",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "如图:是统计二(1)班同学的兴趣爱好统计表。(每人只能选一项)![](images/134304.png)\n(1)爱好乒乓球有( )人,爱好唱歌的有( )人.\n(2)二(1)班喜欢( )的人最多,喜欢( )的人最少.\n(3)二(1)班一共有( )人。",
+        "options":  [
+
+                    ],
+        "answer":  "15;5;足球;唱歌;47",
+        "solution":  "【分析】(1)数一数,从左到右依次是15人,16人,5人,11人,据此填空。(2)比较数字大小即可求解。20以内的数从小到大排列是:1\u003c2\u003c3\u003c4\u003c5\u003c6\u003c7\u003c8\u003c9\u003c10\u003c11\u003c12\u003c13\u003c14\u003c15\u003c16\u003c17\u003c18\u003c19\u003c20。(3)将各类人数相加即可求出总人数.\n\n【详解】(1)爱好乒乓球有15人,爱好唱歌的有5人。(2)16\u003e15\u003e11\u003e5,二(1)班喜欢足球的人最多,喜欢唱歌的人最少。(3)15+16+5+11=47(人),二(1)班一共有47人。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "23-24二年级下·湖南怀化·期末"
+    },
+    {
+        "id":  "319",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "二(3)班同学调查了本年级部分同学上学的方式,调查结果如下。![](images/134307.png)\n(2)一共调查了( )人,其中( )的人数最少,是( )人.\n(3)步行上学的有( )人,比坐公交车上学的多( )人。",
+        "options":  [
+
+                    ],
+        "answer":  "12;9;3;10;34;骑自行车;3;12;3",
+        "solution":  "【分析】(1)数出表中各种上学方式的人数,然后填表即可;(2)根据(1)中数据计算出调查的总人数,并根据数据大小得出人数最少的上学方式;(3)步行上学的人数-坐公交上学的人数=步行上学比坐公交上学多的人数,据此得出结论.\n\n【详解】(1)根据分析填表如下:步行12人,坐公交车9人,骑自行车3人,父母接送10人。(2)12+9+3+10=21+3+10=24+10=34(人),故一共调查了34人,其中骑自行车的人数最少,是3人。(3)12-9=3(人),故步行上学的有12人,比坐公交车上学的多3人。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "23-24 二年级下·四川乐山·期末"
+    },
+    {
+        "id":  "320",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "二(2)班同学选班长;三位候选人的得票情况如下:![](images/134314.png)\n(1)请把投票结果填入下面的统计表内。姓名于东王小天马莉莉票数\n(2)一共有( )人参加投票.\n(3)根据统计结果,( )当选班长。",
+        "options":  [
+
+                    ],
+        "answer":  "15;20;8;43;王小天",
+        "solution":  "【分析】(1)依次数出每人得票的数量填写即可,\"正\"字的每一笔代表1票;(2)将得票数相加就是总人数;(3)票数最多的就是当选班长的人,比较票数的多少即可.\n\n【详解】(1)表格填写如下:于东15票,王小天20票,马莉莉8票。(2)15+20+8=43(人),一共有43人参加投票。(3)20\u003e15\u003e8,根据统计结果,王小天当选班长。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "20以内数的比大小",
+                                 "100以内数的连加运算"
+                             ],
+        "source":  "23-24 二年级下·江西萍乡·期末"
+    },
+    {
+        "id":  "321",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "小军调查自己班的同学喜欢吃的水果情况如下:![](images/134319.png)\n(2)喜欢吃( )的人数最多,喜欢吃( )的人数最少.\n(3)喜欢吃菠萝的同学比喜欢吃梨的同学少( )人。",
+        "options":  [
+
+                    ],
+        "answer":  "10;12;14;6 梨;葡萄 4",
+        "solution":  "【分析】(1)一个\"正\"字表示5人,数一数,喜欢菠萝的10人,喜欢香蕉的12人,喜欢梨的14人,喜欢葡萄的6人。(2)将喜欢各种水果的人数比较大小即可求解。(3)用喜欢吃梨的人数减喜欢吃菠萝的人数即可求解.\n\n【详解】(1)把调查结果填在表中:菠萝10人,香蕉12人,梨14人,葡萄6人。(2)14\u003e12\u003e10\u003e6,喜欢吃梨的人数最多,喜欢吃葡萄的人数最少。(3)14-10=4(人),喜欢吃菠萝的同学比喜欢吃梨的同学少4人。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "23-24 二年级下·河南漯河·期末"
+    },
+    {
+        "id":  "322",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "下面是笑笑调查的本班同学最喜欢的节目情况。(每人只选一样)![](images/134332.png)\n(2)喜欢( )节目的最多,喜欢( )节目的人数最少,相差( )人.\n(3)笑笑一共调查了( )名同学。",
+        "options":  [
+
+                    ],
+        "answer":  "17;8;9;11;动画片;歌曲;9;45",
+        "solution":  "【分析】(1)根据记录结果,分别数一数各有几人,然后填空即可。一个\"正\"字表示5人,一笔表示1人。(2)比较一下喜欢各类节目人数的多少,即可知道喜欢哪个节目人数最多,喜欢那个人数节目最少,然后用喜欢人数最多的减去喜欢人数最少的,求出差,即可解决。(3)把所有的调查人数加起来,求出和,就是一共调查的人数.\n\n【详解】(1)填表:动画片17人,歌曲8人,舞蹈9人,人与自然11人。(2)17\u003e11\u003e9\u003e8,17-8=9(名),即喜欢动画片节目的最多,喜欢歌曲节目的人数最少,相差9人。(3)17+8+9+11=25+9+11=34+11=45(名),即笑笑一共调查了45名同学。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "单式统计表的特点及填补",
+                                 "20以内数的比大小",
+                                 "100以内数的连加运算"
+                             ],
+        "source":  "23-24二年级下·河南信阳·期末"
+    },
+    {
+        "id":  "323",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "下图是二(1)班同学最喜欢的体育运动项目情况。![](images/134341.png)\n(2)喜欢( )运动的人最多;喜欢( )运动的人最少.\n(3)二(1)班一共有( )人。",
+        "options":  [
+
+                    ],
+        "answer":  "7;22;9;6 足球;羽毛球 44",
+        "solution":  "【分析】(1)一个圆圈代表数量1,正字的一笔表示数量1,一个√表示数量1,据此数清楚喜欢各种项目的人数即可。(2)根据第(1)小题得出的人数,结合整数比较大小的方法,即可得出喜欢什么运动的人数最多,喜欢什么运动的人数最少。(3)根据加法的意义,将喜欢各项的运动人数相加,即可得出答案.\n\n【详解】(1)根据上面的统计结果完成下面统计表:跳绳7人,足球22人,篮球9人,羽毛球6人。(2)6\u003c7\u003c9\u003c22,所以喜欢足球运动的人最多;喜欢羽毛球运动的人最少。(3)7+22+9+6=29+15=44(人),所以二(1)班一共有44人。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "100以内数的比大小",
+                                 "100以内数的连加运算"
+                             ],
+        "source":  "22-23 二年级下·浙江宁波·期末"
+    },
+    {
+        "id":  "324",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "下面是二(4)班同学参加课外活动的统计情况。![](images/134350.png)\n(1)参加( )的人最多,有( )人,参加( )的人最少,有( )人.\n(2)参加跳绳的比参加拍球的多( )人.\n(3)二(4)班一共有( )人。",
+        "options":  [
+
+                    ],
+        "answer":  "跳绳;19;踢毽子;8;7;49",
+        "solution":  "【分析】(1)数一数,参加跑步的有10人,拍球的12人,跳绳的19人,踢毽子的8人,比较数据的大小即可。(2)用参加跳绳的人数减参加拍球的人数即可。(3)将各类人数相加即可求出总人数.\n\n【详解】(1)19\u003e12\u003e10\u003e8,参加跳绳的人最多,有19人,参加踢毽子的人最少,有8人。(2)19-12=7(人),参加跳绳的比参加拍球的多7人。(3)10+12+19+8=49(人),二(4)班一共有49人。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "20以内数的比大小",
+                                 "不退位减法(20以内)",
+                                 "100以内数的连加运算"
+                             ],
+        "source":  "22-23 二年级下·浙江宁波·期末"
+    },
+    {
+        "id":  "325",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "下面是二(1)班全体同学\"最喜欢的体育活动\"调查记录。(每名同学只选一种)(单位:人)![](images/134353.png)\n(1)最喜欢( )的人数最多,最喜欢( )的人数最少。(填序号)\n(2)最喜欢跳绳的再添上( )人,就和最喜欢踢足球的人数同样多.\n(3)如果这个班女生有28人,那么男生有( )人.\n(4)看了这个调查情况,你想说什么。",
+        "options":  [
+
+                    ],
+        "answer":  "③ ④ 2 24 同学们可以进行多样的体育活动。",
+        "solution":  "【分析】(1)比较喜欢各项体育活动的人数,找到最多的和最少的即可;(2)要想喜欢跳绳和最喜欢踢足球的人数同样多,根据减法的意义,喜欢踢足球的人数-喜欢跳绳的人数=喜欢跳绳应该再添上的人数;(3)先将喜欢各项活动的人数相加计算出总人数,再减去女生的人数,就是男生的人数;(4)根据统计出的数据填写想法,合理即可,答案不唯一.\n\n【详解】(1)①踢足球有9人;②跑步有15人;③打乒乓球有21人;④跳绳有7人。21\u003e15\u003e9\u003e7,最喜欢③的人数最多,最喜欢④的人数最少。(2)9-7=2(人),最喜欢跳绳的再添上2人,就和最喜欢踢足球的人数同样多。(3)9+15+21+7=52(人);52-28=24(人),如果这个班女生有28人,那么男生有24人。(4)我想说:同学们可以进行多样的体育活动。(答案不唯一)",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "100以内数的比大小",
+                                 "100以内数的连加运算"
+                             ],
+        "source":  "22-23二年级下·福建福州·期末"
+    },
+    {
+        "id":  "326",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "二(1)班一共有42人,他们参加各个兴趣小组的统计情况如下表。(每人只参加一个兴趣小组)![](images/134359.png)\n(2)参加( )兴趣小组的人数最少,比参加绘画兴趣小组的人数少( )人.\n(3)参加舞蹈的人数至少再增加( )人就可以超过绘画小组的人数.\n(4)同学们最喜欢的两个兴趣小组一共有( )人。",
+        "options":  [
+
+                    ],
+        "answer":  "16;13;6;7;足球;10;4;29",
+        "solution":  "【分析】(1)根据参加绘画,舞蹈,围棋的数据填表(一个\"正\"表示5人,一笔表示1人);用总人数减参加绘画,舞蹈,围棋的人数,求出差,可以得出参加足球的人数。(2)比较各个兴趣小组人数的多少即可解答,再用参加绘画兴趣小组的人数减这个兴趣小组的人数即可。(3)绘画小组的人数减去舞蹈小组的人数,求出差,再加1,求出和,即可解答。(4)把人数多的两个小组人数相加,求出和即可.\n\n【详解】(1)42-16-13-7=26-13-7=13-7=6(人),填表:绘画16人,舞蹈13人,足球6人,围棋7人。(2)6\u003c7\u003c13\u003c16,16-6=10(人),即参加足球兴趣小组的人数最少,比参加绘画兴趣小组的人数少10人。(3)16-13=3(人),3+1=4(人),即参加舞蹈的人数至少再增加4人就可以超过绘画小组的人数。(4)16+13=29(人),即同学们最喜欢的两个兴趣小组一共有29人。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "单式统计表的特点及填补",
+                                 "20以内数的比大小",
+                                 "两位数与两位数的不进位加法"
+                             ],
+        "source":  "22-23 二年级下·福建厦门·期末"
+    },
+    {
+        "id":  "327",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "下面是夏日商店一星期出售雪糕的情况。![](images/134404.png)\n(1)星期()售出的雪糕最多,星期()售出的雪糕最少.\n(2)这个星期一共售出雪糕()箱.\n(3)你若是此店的经理,应在星期(),星期(),星期()安排店员轮休。",
+        "options":  [
+
+                    ],
+        "answer":  "六;三 390 一;二;三",
+        "solution":  "【分析】(1)比较统计表中星期一到星期日各销售数据的大小,即可解答;(2)将统计表中星期一到星期日销售的数据相加,即可解答;(3)根据统计表可知,星期一,星期二,星期三,这3天,销售雪糕数量较少,所以应安排店员在销售雪糕数量较少的这三天轮休.\n\n【详解】(1)70\u003e65\u003e60\u003e55\u003e50\u003e48\u003e42,星期六售出的雪糕最多,星期三售出的雪糕最少。(2)50+48+42+55+65+70+60=98+42+55+65+70+60=140+55+65+70+60=195+65+70+60=260+70+60=330+60=390(箱),这个星期一共售出雪糕390箱。(3)根据统计表可知,星期一,星期二,星期三,这3天,销售雪糕数量较少,应在星期一,星期二,星期三安排店员轮休。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "单式统计表的特点及填补"
+                             ],
+        "source":  "23-24三年级下·湖南郴州·期中"
+    },
+    {
+        "id":  "328",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "数一数,填一填。二(2)班投票选举班长(每人只能投一票),投票结果如下表。![](images/134408.png)\n(1)欢欢比聪聪多得( )票,明明比乐乐少得( )票.\n(2)根据投票结果,( )最有可能担班长。",
+        "options":  [
+
+                    ],
+        "answer":  "5;8;15;17;10;9;乐乐",
+        "solution":  "【分析】数一数,4人的得票数分别是5票,8票,15票,17票。(1)用欢欢的得票数减聪聪的得票数即可求出欢欢比聪聪多得的票数。用乐乐的得票数减明明的得票数即可求出明明比乐乐少得的票数。(2)得票数最多的最有可能担班长.\n\n【详解】填表:聪聪5票,明明8票,欢欢15票,乐乐17票。(1)15-5=10(票),17-8=9(票),欢欢比聪聪多得10票,明明比乐乐少得9票。(2)17\u003e15\u003e8\u003e5,根据投票结果,乐乐最有可能担班长。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "20-21 二年级下·河北廊坊·期末"
+    },
+    {
+        "id":  "329",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "下面是明明统计的班内同学最喜欢的球类运动的情况。![](images/134413.png)\n(2)最喜欢( )的人数最多,最喜欢( )的人数最少,相差( )人.\n(3)明明一共统计了( )名同学.\n(4)你最喜欢( )球,你们班中最喜欢这项运动的有( )人。",
+        "options":  [
+
+                    ],
+        "answer":  "11;13;15;8;篮球;乒乓球;7;47;篮;15",
+        "solution":  "【分析】(1)数一数,分别是11个,13个,15个,8个。(2)将各人数作对比即可。(3)将各人数相加即可。(4)根据自身情况作答,答案不唯一.\n\n【详解】1。填表:排球11人,足球13人,篮球15人,乒乓球8人。2.15\u003e13\u003e11\u003e8,15-8=7(人),最喜欢篮球的人数最多,最喜欢乒乓球的人数最少,相差7人。3.11+13+15+8=47(名),明明一共统计了47名同学。4。我最喜欢篮球,我们班中最喜欢这项运动的有15人。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "100以内数的比大小",
+                                 "100以内数的连加运算"
+                             ],
+        "source":  "23-24二年级下·全国·假期作业"
+    },
+    {
+        "id":  "330",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "下面是二(1)班竞选班长投票记录情况,每人只投一票.\n(1)请将票数的结果填入下表。![](images/134417.png)\n(2)( )票数最多,( )票数最少,张亮比李明多( )票.\n(3)一共有( )人投票,根据统计结果,( )应该当选班长。",
+        "options":  [
+
+                    ],
+        "answer":  "12;8;20;王小菲;李明;4;40;王小菲",
+        "solution":  "【分析】(1)根据投票记录结果,分别数一数每人各得几票(一个\"正\"字表示5票),然后完成填空即可。(2)比较一下各人得票的多少,即可知道谁得票最多,谁得票最少;用张亮的得票数减去李明的得票数,求出差即可。(3)把三人的得票数加起来,求出和,就是一共有几人投票;得票数最多的应该当选班长.\n\n【详解】(1)填表:张亮12票,李明8票,王小菲20票。(2)20\u003e12\u003e8,12-8=4(票),王小菲票数最多,李明票数最少,张亮比李明多4票。(3)12+8+20=20+20=40(票),一共有40人投票,根据统计结果,王小菲应该当选班长。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "单式统计表的特点及填补",
+                                 "十几减8的退位减法",
+                                 "100以内数的连加运算"
+                             ],
+        "source":  "22-23 二年级下·浙江绍兴·期末"
+    },
+    {
+        "id":  "331",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "![](images/134425.png)\n(1)喜欢( )的人数最多,喜欢( )的人数最少.\n(2)喜欢唱歌的比喜欢踢球的多( )人,喜欢跳舞的比喜欢踢球的少( )人.\n(3)统计时,二(1)班有2人缺勤,这个班一共有( )人。",
+        "options":  [
+
+                    ],
+        "answer":  "唱歌;跳舞;7;8;39",
+        "solution":  "【分析】一个\"正\"表示5,一笔表示1;据此统计人数多少。(1)比较一下喜欢各类项目人数的多少,即可解决。(2)求一个数比另一个数多(少)多少,用减法列式计算。(3)先用加法计算出喜欢各类项目人数的和是多少,再加上缺勤人数,求出和,就是总人数.\n\n【详解】(1)绘画:5人,踢球:11人,唱歌:18人,跳舞:3人;3\u003c5\u003c11\u003c18,喜欢唱歌的人数最多,喜欢跳舞的人数最少。(2)18-11=7(人),11-3=8(人),喜欢唱歌的比喜欢踢球的多7人,喜欢跳舞的比喜欢踢球的少8人。(3)5+11+18+3+2=16+18+3+2=34+3+2=37+2=39(人),这个班一共有39人。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "20以内数的比大小",
+                                 "不进位加法(20以内)",
+                                 "100以内数的连加运算"
+                             ],
+        "source":  "22-23二年级下·湖北武汉·期中"
+    },
+    {
+        "id":  "332",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "二(1)班调查大家最喜欢农场里的蔬菜,调查记录结果如下图。(x代表1票)![](images/134437.png)\n二(1)班喜欢( )的人数最多,喜欢( )和( )的人数同样多。一共有( )人参与调查。",
+        "options":  [
+
+                    ],
+        "answer":  "土豆;白萝卜;茄子;36",
+        "solution":  "【分析】依次数出喜欢各种蔬菜的人数,再比较大小。找到人数最多的和人数相同的。将所有人数相加就是总人数.\n\n【详解】喜欢白萝卜的有5人;喜欢西红柿的有10人;喜欢土豆的有16人;喜欢茄子的有5人。16\u003e10\u003e5=5,5+10+16+5=36(人),二(1)班喜欢土豆的人数最多,喜欢白萝卜和茄子的人数同样多。一共有36人参与调查。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "20以内数的比大小",
+                                 "100以内数的连加运算"
+                             ],
+        "source":  "23-24 二年级下·贵州铜仁·期中"
+    },
+    {
+        "id":  "333",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "学校开运动会,小兰调查了同学们参加各运动项目的情况(每人只参加一项),作了如下记录。![](images/134441.png)\n跑步的同学比跳绳的少( )人,喜欢( )运动项目的人数最多。参加运动会的同学一共有( )人。",
+        "options":  [
+
+                    ],
+        "answer":  "5;拍球;41",
+        "solution":  "【分析】依次数出参加各项运动的人数。跳绳的人数-跑步的人数=跑步比跳绳少的人数;比较各项运动人数的大小,找到最多的即可。将各项运动的人数相加就是总人数.\"正\"字的每一笔代表1.\n\n【详解】参加拍球的有14人,参加跳绳的有10人;参加跳远的有12人;参加跑步的有5人。10-5=5(人);14\u003e12\u003e10\u003e5;14+10+12+5=41(人)。跑步的同学比跳绳的少5人,喜欢拍球运动项目的人数最多。参加运动会的同学一共有41人。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "20以内数的比大小",
+                                 "10的加减法",
+                                 "100以内数的连加运算"
+                             ],
+        "source":  "23-24 二年级下·贵州铜仁·期中"
+    },
+    {
+        "id":  "334",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "下面是二(1)班所有同学最喜欢的图书情况。(每人只选一本)![](images/134445.png)\n(2)最喜欢《 》的人数最多,最喜欢《 》的人数最少.\n(3)这个班一共有( )人。",
+        "options":  [
+
+                    ],
+        "answer":  "7;8;15;8;5;昆虫记;成语故事;43",
+        "solution":  "【分析】(1)数一数,二(1)班所有同学最喜欢的图书所占的人数分别是7人,8人,15人,8人,5人。(2)将喜欢各种图书的人数作比较即可。(3)将喜欢各种图书的人数依次相加即可求出总人数.\n\n【详解】(1)填表:《二年级的小豆豆》7人,《格林童话》8人,《昆虫记》15人,《父与子》8人,《成语故事》5人。(2)15\u003e8\u003e7\u003e5,最喜欢《昆虫记》的人数最多,最喜欢《成语故事》的人数最少。(3)7+8+15+8+5=43(人),这个班一共有43人。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "100以内数的连加运算"
+                             ],
+        "source":  "23-24二年级下·广东珠海·期中"
+    },
+    {
+        "id":  "335",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "统计比较多的数量时,一般用画\u0027正\u0027字法统计,画2个\u0027正\u0027字表示( );\u0027正正正下\u0027表示( );统计结果是8,用画\u0027正\u0027字法表示为( )。",
+        "options":  [
+
+                    ],
+        "answer":  "10;18;正下",
+        "solution":  "【分析】一个\u0027正\u0027表示数量5,一笔表示数量1;几个\u0027正\u0027就表示几个5,几笔就表示几个1;据此解决。统计结果是8,用画\u0027正\u0027字法表示,需要画一个\u0027正\u0027,再另外画三笔.\n\n【详解】由题意分析得:5+5=10,5+5+5+3=18,统计比较多的数量时,一般用画\u0027正\u0027字法统计,画2个\u0027正\u0027字表示10;\u0027正正正下\u0027表示18;统计结果是8,用画\u0027正\u0027字法表示为\u0027正下\u0027。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "23-24 二年级下·福建莆田·期中"
+    },
+    {
+        "id":  "336",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "平平对本班学生作\"周末调查\",请你根据调查结果填空。![](images/134450.png)\n喜欢( )人数最多,喜欢做家务的有( )人,如果可以再加一项,你会选择( )。(填出你喜欢的种类)",
+        "options":  [
+
+                    ],
+        "answer":  "课外阅读 28 看电视",
+        "solution":  "【分析】比较喜欢各种项目人数的大小,即可知道喜欢什么项目的人数最多;从调查结果中即可知道喜欢做家务的有多少人;根据自己的实际情况提出喜欢的种类即可,答案不唯一.\n\n【详解】30\u003e28\u003e25,喜欢课外阅读人数最多,喜欢做家务的有28人,如果可以再加一项,我会选择看电视。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "100以内数的比大小"
+                             ],
+        "source":  "23-24 二年级下·河南三门峡·期中"
+    },
+    {
+        "id":  "337",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "二(1)班同学最喜欢的运动项目统计如下:![](images/134502.png)\n(1)最喜欢( )的人数最多,最喜欢( )的人数最少.\n(2)最喜欢跳皮筋的比最喜欢踢毽子的多( )人.\n(3)参与此次调查的一共有( )人。",
+        "options":  [
+
+                    ],
+        "answer":  "跳皮筋 扔沙包 4 51",
+        "solution":  "【分析】(1)依次数出喜欢各种运动项目的人数,比较大小,找到人数最多的和最少的即可;(2)喜欢跳皮筋的人数-喜欢踢毽子的人数=最喜欢跳皮筋的比最喜欢踢毽子的多的人数;(3)将各种运动项目的人数相加就是总人数.\n\n【详解】(1)喜欢跳皮筋的有16人;喜欢踢毽子的有12人;喜欢跑步的有14人;喜欢扔沙包的有9人。16\u003e14\u003e12\u003e9,最喜欢跳皮筋的人数最多,最喜欢扔沙包的人数最少。(2)16-12=4(人),最喜欢跳皮筋的比最喜欢踢毽子的多4人。(3)16+12+14+9=51(人),参与此次调查的一共有51人。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "20以内数的比大小",
+                                 "不退位减法(20以内)",
+                                 "100以内数的连加运算"
+                             ],
+        "source":  "22-23二年级下·贵州遵义·期中"
+    },
+    {
+        "id":  "338",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "下面是二一班学生最喜欢的校服颜色情况。![](images/134508.png)\n(1)最喜欢( )颜色校服的人数最多,最喜欢( )颜色的人最少.\n(2)最喜欢蓝颜色校服的有( )人,最喜欢黄颜色校服的有( )人.\n(3)我建议本班选择( )颜色的校服,因为( )。",
+        "options":  [
+
+                    ],
+        "answer":  "红;黄;6;3;红;喜欢红色的人数最多",
+        "solution":  "【分析】(1)比较喜欢各种颜色人数的多少,找出最多的和最少的即可;(2)从表格中找出喜欢蓝色和黄色的人数填写;(3)根据表格中喜欢哪种颜色的最多,就建议选择什么颜色.\n\n【详解】(1)16\u003e6\u003e5\u003e3,最喜欢红颜色校服的人数最多,最喜欢黄颜色的人最少。(2)最喜欢蓝颜色校服的有6人,最喜欢黄颜色校服的有3人。(3)我建议本班选择红颜色的校服,因为喜欢红色的人数最多。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "22-23 二年级下·河南驻马店·期中"
+    },
+    {
+        "id":  "339",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "如图所示是小丽调查本班同学喜欢的午餐菜肴情况。(每人只能选一种)\n![](images/134513.png)\n(2)喜欢红烧鱼的比喜欢蚝油生菜的少( )人,比喜欢蜜汁鸡翅的多( )人.\n(3)参加这次调查的同学有( )人.\n(4)如果要评选出一道本班同学最喜欢的菜肴,因病没来的小刚同学的选择会对调查结果产生影响吗。在正确的上画\"√\"。会 不会",
+        "options":  [
+
+                    ],
+        "answer":  "12;18;7;5;6;5;42;不会",
+        "solution":  "【分析】(1)依次数出喜欢各种菜肴的人数填空即可;(2)喜欢蚝油生菜的人数-喜欢红烧鱼的人数=喜欢红烧鱼的比喜欢蚝油生菜的少的人数;喜欢红烧鱼的人数-喜欢蜜汁鸡翅的人数=喜欢红烧鱼的比喜欢蜜汁鸡翅多的人数;(3)将所有人数相加就是总人数;(4)结果会不会有影响,就看喜欢各种菜肴的人数最多的会不会变.\n\n【详解】(1)喜欢红烧鱼的有12人;喜欢蚝油生菜的有18人;喜欢蜜汁鸡翅的有7人;喜欢红烧羊肉的有5人。填写如下:红烧鱼12人,蚝油生菜18人,蜜汁鸡翅7人,红烧羊肉5人。(2)18-12=6(人);12-7=5(人),喜欢红烧鱼的比喜欢蚝油生菜的少6人,比喜欢蜜汁鸡翅的多5人。(3)12+18+7+5=42(人),参加这次调查的同学有42人。(4)小刚的选择不会对结果产生影响,因为喜欢蚝油生菜的人数最多有18人,即使有1人没来,还是喜欢蚝油生菜的人数最多。填写如下:不会。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "22-23二年级下·河南郑州·期中"
+    },
+    {
+        "id":  "340",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "下面是二(1)班竞选班长投票记录情况,每人只投一票.\n![](images/134518.png)\n(2)( )的票数最多。",
+        "options":  [
+
+                    ],
+        "answer":  "12;8;20;王小菲",
+        "solution":  "【分析】(1)依次数出每人得票的数量填空即可;\u0027正\u0027字的每一笔代表1;(2)比较得票数量的多少,找到最多的即可.\n\n【详解】(1)张亮12票;李明8票;王小菲20票。填写如下:张亮12票,李明8票,王小菲20票。(2)20\u003e12\u003e8,王小菲的票数最多。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "20以内数的比大小"
+                             ],
+        "source":  "22-23二年级下·广西河池·期中"
+    },
+    {
+        "id":  "341",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "下面是三(1)班同学最喜欢的科目统计表。(每人只选一个科目)![](images/134521.png)\n(1)最喜欢( )的人数最多,最喜欢( )的人数最少,最喜欢( )和( )的人数相同.\n(2)最喜欢语文和数学的一共有( )人.\n(3)上述科目中,我最喜欢( ),三(1)班最喜欢这个科目的有( )人。",
+        "options":  [
+
+                    ],
+        "answer":  "数学 科学 英语 音乐 18 数学 10",
+        "solution":  "【分析】(1)先将每个科目最喜欢的人数进行大小排序,并观察统计表即可解答。(2)将最喜欢语文的人数和最喜欢数学的人数加起来即可。(3)根据自己喜好进行解答,并观察上表进行填空即可.\n\n【详解】(1)10\u003e9\u003e8\u003e6\u003e4\u003e2,最喜欢数学的人数最多,最喜欢科学的人数最少,最喜欢英语和音乐的人数相同。(2)8+10=18(人),最喜欢语文和数学的一共有18人。(3)上述科目中,我最喜欢数学,三(1)班最喜欢这个科目的有10人。(答案不唯一)",
+        "knowledge_points":  [
+                                 "单式统计表的特点及填补"
+                             ],
+        "source":  "22-23 三年级下·广西贵港·期中"
+    },
+    {
+        "id":  "342",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "下面是二(1)班同学一星期阅读课外读物的册数情况。![](images/134527.png)\n(2)二(1)班同学最喜欢读( ),读的《漫画》比《少儿文艺》多( )册.\n(3)全班一共读了( )册课外读物。这四种课外读物中,你最喜欢读的是( ),这个班一星期阅读这种课外读物( )册.\n(4)如果要在班上办个图书角,应该多买( ),少买( )。",
+        "options":  [
+
+                    ],
+        "answer":  "7;12;8;9 《童话故事》;2 36;《童话故事》;12 《童话故事》;《少儿文艺》",
+        "solution":  "【分析】(1)依次数出各种书的数量填空即可;(2)比较统计出的数量的多少,找到最多的就是最喜欢读的书;用读《漫画》的数量-读《少儿文艺》的数量=读的《漫画》比《少儿文艺》多的数量;(3)将各册数相加即可求出总册数。根据自己喜欢的填写即可;(4)根据数据,可买数量最多的,少买数量最少的.\n\n【详解】(1)《少儿文艺》有7册;《童话故事》有12册;《脑筋急转弯》有8册;《漫画》有9册。填写如下:《少儿文艺》7册,《童话故事》12册,《脑筋急转弯》8册,《漫画》9册。(2)12\u003e9\u003e8\u003e7;9-7=2(册),二(1)班同学最喜欢读《童话故事》,读的《漫画》比《少儿文艺》多2册。(3)7+12+8+9=36(册),全班一共读了36册课外读物。这四种课外读物中,你最喜欢读的是《童话故事》,这个班一星期阅读这种课外读物12册。(后两空答案不唯一)(4)如果要在班上办个图书角,应该多买《童话故事》,少买《少儿文艺》。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "22-23二年级下·云南玉溪·期中"
+    },
+    {
+        "id":  "343",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "装扮会场.\n![](images/134531.png)\n(2)( )做的花最多,( )做的花最少,他们做的花相差( )朵.\n(3)小兰比小明多做了( )朵花.\n(4)四位同学一共做了( )朵花。",
+        "options":  [
+
+                    ],
+        "answer":  "15;20;25;10;小红;小亮;15;5;70",
+        "solution":  "【分析】(1)用小兰做的朵数加5就是小红做的朵数,用小明做的朵数减5就是小亮做的朵数;(2)①比较统计表中的数据,再作差;②用小兰做的朵数减小明做的朵数即可;③用加法将统计表中的数据相加即可.\n\n【详解】(1)20+5=25(朵),15-5=10(朵),填表:小明15朵,小兰20朵,小红25朵,小亮10朵。(2)25\u003e20\u003e15\u003e10,25-10=15(朵),小红做的花最多,小亮做的花最少,他们做的花相差15朵。(3)20-15=5(朵),小兰比小明多做了5朵花。(4)15+20+25+10=70(朵),四位同学一共做了70朵。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "22-23 二年级下·河南南阳·期中"
+    },
+    {
+        "id":  "344",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "学校开运动会,王力调查了同学们参加各运动项目的情况。(每人只参加一项),作了如表记录。![](images/134534.png)\n(1)从表中看,参加运动会的同学一共有( )人.\n(2)参加( )的人数最多.\n(3)拍球的同学比跳远的多( )人。",
+        "options":  [
+
+                    ],
+        "answer":  "35;拍球;11",
+        "solution":  "【分析】(1)从表中可知,参加拍球的有14人,参加跳绳的有10人,参加跳远的有3人,参加跑步的有8人;然后再把这些人数相加即可;(2)比较可知,参加拍球的人数最多;(3)求拍球的同学比跳远的多几人,用参加拍球的人数减去参加跳远的人数,即14减3,据此解答即可.\n\n【详解】(1)从表中可知,参加拍球的有14人,参加跳绳的有10人,参加跳远的有3人,参加跑步的有8人;14+10+3+8=24+3+8=27+8=35(人),参加运动会的同学一共有35人。(2)14\u003e10\u003e8\u003e3,参加拍球的人数最多。(3)14-3=11(人),拍球的同学比跳远的多11人。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "20以内数的比大小",
+                                 "不退位减法(20以内)",
+                                 "100以内数的连加运算"
+                             ],
+        "source":  "22-23 二年级下·广东东莞·期中"
+    },
+    {
+        "id":  "345",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "下面是二年级(三)班的同学们最喜爱的主持人调查结果。![](images/134538.png)\n(1)喜欢( )的人最多,喜欢( )的人最少.\n(2)我最喜欢的主持人是( ),全班喜欢这个主持人的有( )人.\n(3)喜欢小鹿姐姐的小朋友比喜欢黄伟哥哥的小朋友少( )人。",
+        "options":  [
+
+                    ],
+        "answer":  "黄伟哥哥;小鹿姐姐;红果果;12;7",
+        "solution":  "【分析】(1)把最喜爱的主持人的人数比较大小即可得解;(2)根据自己的喜好,结合题干要求进行填写即可,本小题答案不唯一,例如:我最喜欢的主持人是红果果,全班喜欢这个主持人的有12人;(3)喜欢小鹿姐姐的小朋友比喜欢黄伟哥哥的小朋友少的人数=喜欢黄伟哥哥的小朋友人数-喜欢小鹿姐姐的小朋友人数.\n\n【详解】(1)16\u003e13\u003e12\u003e11\u003e9,喜欢黄伟哥哥的人最多,喜欢小鹿姐姐的人最少;(2)我最喜欢的主持人是红果果,全班喜欢这个主持人的有12人(答案不唯一);(3)16-9=7(人),所以喜欢小鹿姐姐的小朋友比喜欢黄伟哥哥的小朋友少7人。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "20以内数的比大小",
+                                 "十几减9的退位减法"
+                             ],
+        "source":  "22-23 二年级下·河北保定·期中"
+    },
+    {
+        "id":  "346",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "下表是明明一家从3月12日至20日购买生鲜蔬菜的支出记录。![](images/134545.png)\n(1)明明一家从3月12日至20日购买生鲜蔬菜一共支出了( )元.\n(2)请你预测一下:3月21日明明家购买生鲜蔬菜可能支出( )元。",
+        "options":  [
+
+                    ],
+        "answer":  "88;30",
+        "solution":  "【分析】(1)根据题意,将支出的钱数相加即可;(2)由表格数据可知,明明家每三天中,第一天有支出,后两天没有支出,而且每次的支出都接近30元。所以31日支出在30元左右,由此解答.\n\n【详解】(1)28+29+31=88(元),明明一家从3月12日至20日购买生鲜蔬菜一共支出了88元。(2)3月21日明明家购买生鲜蔬菜可能支出30元。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "100以内数的连加运算"
+                             ],
+        "source":  "22-23 二年级下·福建莆田·期中"
+    },
+    {
+        "id":  "347",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "李老师用\u0027正\u0027字统计一星期以来分别用不同方式跟老师沟通孩子学习情况的家长人数,但她忘了标注姓名了。你能根据提示填写统计表吗。用微信沟通的比用电话沟通的多3人。用QQ沟通的比见面沟通的少2人。李老师的统计:![](images/134550.png)",
+        "options":  [
+
+                    ],
+        "answer":  "10;7;9;11",
+        "solution":  "【分析】\u0027正\u0027字统计时,每一笔代表1。统计的人数分别为10人;9人;7人;11人。用微信沟通的比用电话沟通的多3人,题中只有10比7大3;用QQ沟通的比见面的少2人,题中只有9比11少2,由此解答.\n\n【详解】10-7=3(人);11-9=2(人)。所以用微信的是10人;用电话的是7人;用QQ的是9人;见面的是11人。填写如下:微信10人,电话7人,QQ9人,见面11人。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "23-24 二年级下·全国·课后作业"
+    },
+    {
+        "id":  "348",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "动物学校评选\"勇者之星\"(每只小动物只能投一票),投票结果如下表:![](images/134553.png)\n(2)回答下面问题。( )可能获选\"勇者之星\"。狮子比大象多得( )张票,大象比猎豹少得( )张票。一共有( )只小动物参加投票。",
+        "options":  [
+
+                    ],
+        "answer":  "13;15;21;猎豹;2;8;49",
+        "solution":  "【分析】(1)一个\u0027正\u0027表示5票,一画表示1票;数一数各种动物各得几票,然后填空即可。(2)得票最多的可能获选\"勇者之星\";求一个数比另个数多多少,用减法列式计算;求几个数的和,用加法列式计算.\n\n【详解】(1)填表:大象13票,狮子15票,猎豹21票。(2)21\u003e15\u003e13,15-13=2(张),21-13=8(张),13+15+21=28+21=49(张),故猎豹可能获选\"勇者之星\"。狮子比大象多得2张票,大象比猎豹少得8张票。一共有49只小动物参加投票。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "单式统计表的特点及填补",
+                                 "100以内数的比大小",
+                                 "两位数与两位数的退位减法"
+                             ],
+        "source":  "22-23 二年级下·山西朔州·期中"
+    },
+    {
+        "id":  "349",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "下面是二(1)班全体同学参加学校社团活动的情况统计。(每人只参加一种)![](images/134582.png)\n(1)把统计的结果填在上表空格中.\n(2)参加( )组的人数最多,参加( )组的人数最少。它们相差( )人.\n(3)参加绘画组的人数比参加书法组的人数多( )人.\n(4)二(1)班共有( )人。",
+        "options":  [
+
+                    ],
+        "answer":  "13;7;16;10;4 舞蹈;声乐;12 6 50",
+        "solution":  "【分析】(1)绘画组13人,书法组7人,舞蹈组16人,乒乓球组10人,声乐组4人;(2)将人数比较大小,然后用最多的人数减最少的人数;(3)用参加绘画组的人数减去参加书法组的人数即可;(4)将所有人数加起来即可求解.\n\n【详解】(1)填表:绘画组13人,书法组7人,舞蹈组16人,乒乓球组10人,声乐组4人。(2)4\u003c7\u003c10\u003c13\u003c16,16-4=12(人),参加舞蹈组的人数最多,参加声乐组的人数最少。它们相差12人。(3)13-7=6(人),参加绘画组的人数比参加书法组的人数多6人。(4)13+7+16+10+4=50(人),二(1)班共有50人。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "20以内数的比大小",
+                                 "不退位减法(20以内)",
+                                 "十几减7",
+                                 "6的退位减法"
+                             ],
+        "source":  "22-23二年级下·山东济宁·期中"
+    },
+    {
+        "id":  "350",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "下面是二年级同学最喜欢的动画片的投票结果。(每人只能投一部动画片)![](images/134603.png)\n(2)根据投票结果,如果老师想给其他班同学推荐动画片,老师可能会推荐( )。",
+        "options":  [
+
+                    ],
+        "answer":  "10;32;11;7;《大闹天宫》",
+        "solution":  "【分析】(1)分别数出每种动画片的票数,然后记录下来,注意一个\u0027正\u0027字是5票,每一个笔画代表1票,其他的每个图形代表1票。(2)根据票数的多少,推荐票数最多的动画片即可.\n\n【详解】(1)根据分析填表如下:《哪吒闹海》10票,《大闹天宫》32票,《寻梦环游记》11票,《熊出没》7票。(2)32\u003e11\u003e10\u003e7,故老师可能会推荐《大闹天宫》。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "22-23二年级下·陕西宝鸡·期末"
+    },
+    {
+        "id":  "351",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "调查本班同学最喜欢参加哪个课外小组。![](images/134608.png)\n(1)参加( )小组的人数最多,参加( )小组的人数最少.\n(2)我们班参加计算机小组的有( )人.\n(3)我喜欢( )小组,喜欢这个小组的有( )人。",
+        "options":  [
+
+                    ],
+        "answer":  "10;7;5;8;计算机;体操;10;篮球;7",
+        "solution":  "【分析】题中未给出数据,只要自己填写的数据合理即可,先填全表格信息:(1)比较各小组的人数,找到最多的和最少的即可;(2)从表格中找到参加计算机小组的有几人即可;(3)可根据自己的喜好填写,再找到相应的人数.\n\n【详解】统计表填写如下:计算机小组10人,篮球小组7人,体操组5人,乒乓球组8人。(1)10\u003e8\u003e7\u003e5,参加计算机小组的人数最多,参加体操小组的人数最少。(2)我们班参加计算机小组的有10人。(3)我喜欢篮球小组,喜欢这个小组的有7人。(本题答案不唯一)",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "10以内数的比大小"
+                             ],
+        "source":  "22-23二年级下·全国·随堂练习"
+    },
+    {
+        "id":  "352",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "调查本班同学最喜欢去哪里春游。![](images/134615.png)\n(1)最喜欢去( )的人数最多,最喜欢去( )的人数最少.\n(2)最喜欢去植物园的有( )人.\n(3)你最喜欢去( ),喜欢去这里的同学有( )人。",
+        "options":  [
+
+                    ],
+        "answer":  "8;10;12;6;5;游乐园;河滨公园;8;游乐园;12",
+        "solution":  "【分析】根据调查的数据先填写表格:(1)比较喜欢各地点的人数,找到最多的和最少的即可;(2)从表格中找到最喜欢去植物园的有多少人;(3)从表格中选择我最喜欢去的地方,即可找到有多少人喜欢去这里.\n\n【详解】统计表填写如下:植物园8人,动物园10人,游乐园12人,森林公园6人,河滨公园5人。(1)12\u003e10\u003e8\u003e6\u003e5,最喜欢去游乐园的人数最多,最喜欢去河滨公园的人数最少。(2)最喜欢去植物园的有8人。(3)你最喜欢去游乐园,喜欢去这里的同学有12人。(本题答案不唯一)",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "20以内数的比大小"
+                             ],
+        "source":  "22-23二年级下·全国·随堂练习"
+    },
+    {
+        "id":  "353",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "统计数据时,只能用写\u0027正\u0027字的方法记录。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】整理原始数据时的方法很多,如可以用画\u0027正\u0027字的方法,可以用画\"√\"号的方法,也可以用画\"△\"字的方法等等,据此判断.\n\n【详解】据分析可知:整理原始数据时的方法很多,所以本题\"统计数据时,只能用写\u0027正\u0027字的方法记录\"说法错误。故答案为: ×",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "23-24二年级下·河南信阳·期末"
+    },
+    {
+        "id":  "354",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "在\"三好学生\"投票中,王盼得票是\"正一\",她得了6票。( )",
+        "options":  [
+
+                    ],
+        "answer":  "√",
+        "solution":  "【分析】一个\u0027正\u0027表示5票,一笔表示1票,5+1=6(票),据此判断.\n\n【详解】5+1=6(票),在\"三好学生\"投票中,王盼得票是\"正一\",她得了6票。此说法正确。故答案为:√",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "23-24 二年级下·湖南怀化·期中"
+    },
+    {
+        "id":  "355",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "统计停车场停放的车辆,可以用画\u0027正\u0027字的方法来记录。( )",
+        "options":  [
+
+                    ],
+        "answer":  "√",
+        "solution":  "【分析】根据数据收集和整理的方法,停车场的流动性很大,统计停车场停放的车辆,可以用画\u0027正\u0027字的方法来记录,由此解答.\n\n【详解】由分析可知,统计停车场停放的车辆,可以用画\u0027正\u0027字的方法来记录。原题说法正确。故答案为:√",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "22-23 二年级下·云南玉溪·期中"
+    },
+    {
+        "id":  "356",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "下面是一家大型超市一周内销售果汁的情况,请你按要求回答问题。![](images/134623.png)\n(2)一周内一共销售果汁( )箱.\n(3)( )品种果汁销售量最大,它比销售最少的果汁多( )箱.\n(4)请你根据调查结果,说说下周超市怎样进货更为合理,写出你的建议。",
+        "options":  [
+
+                    ],
+        "answer":  "7;15;10;8;5;45;B;10;B品种果汁多进一些,E品种果汁少进一些",
+        "solution":  "【分析】(1)一个\u0027正\u0027字表示5箱,一笔表示1箱;根据销售统计结果,分别数一数各种果汁的数量各是多少,然后填空即可。(2)把所有果汁的数量加起来,求出和,就是一共的销售数量。(3)比较一下各种果汁的数量的多少,即可知道哪种果汁销售量最大,哪种果汁销售量最少;用销售量最大的减去销售量最少的,求出差即可。(4)销售量多的果汁,多进一些货;销售量少的果汁,少进一些货.\n\n【详解】(1)填表:A7箱,B15箱,C10箱,D8箱,E5箱。(2)7+15+10+8+5=22+10+8+5=32+8+5=40+5=45(箱),即一周内一共销售果汁45箱。(3)15\u003e10\u003e8\u003e7\u003e5,15-5=10(箱),即B品种果汁销售量最大,它比销售最少的果汁多10箱。(4)B品种果汁销售量最大,下周超市要多进一些B品种果汁;而E品种果汁销售量最少,下周超市要少进一些E品种果汁。(答案不唯一)",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "100以内数的比大小",
+                                 "100以内数的连加运算"
+                             ],
+        "source":  "23-24二年级下·福建厦门·期末"
+    },
+    {
+        "id":  "357",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "竞选班长。这里有4位班长候选人,请根据下图完成下列各题。![](images/134629.png)\n(2)比一比,填一填。①( )得的票数最多,( )得的票数最少。②李佳比张彤多得( )票。③竞选那天有2位同学请假了,如果他们也参与投票,( )改变结果吗。(填\"会\"或\"不会\")④你还能提出什么问题。请提出并解答。",
+        "options":  [
+
+                    ],
+        "answer":  "18;8;10;12;李烁;张彤;4;不会;李烁比张彤多几票;18-8=10(票)",
+        "solution":  "【分析】根据题意可知:(1)根据图片中的\u0027正\u0027字(一个完整的\u0027正\u0027是5画)来数一数,并填一填即可。(2)根据(1)数出的结果比一比,就知道:①谁得的票数最多,谁得的票数最少。②李佳比张彤多得的票数=李佳的票数-张彤的票数。③将2位请假的同学的票数+票数第二多的同学,看能够超过第一名的票数,如果超过则结果改变,不超过则不会改变结果。④根据表中的数据可以提出:李烁比张彤多几票。并且解答。据此解答.\n\n【详解】(1)数一数,填一填:李烁18票,张彤8票,王宁10票,李佳12票。(2)比一比,填一填。①因为18\u003e12\u003e10\u003e8,对应的人依次是李烁,李佳,王宁,张彤,所以李烁得的票数最多,张彤得的票数最少。②12-8=4(票),答:李佳比张彤多得4票。③票数第二的是李佳,有12票;竞选那天有2位同学请假了,如果他们也参与投票,且全部投给李佳,则李佳现在的票数是12+2=14(票),14\u003c18,即李佳现在的票数小于李烁的票数,所以不会改变结果。④李烁比张彤多几票。18-8=10(票),答:李烁比张彤多10票。(答案不唯一)",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "\"提问题\"\"填条件\"问题",
+                                 "20以内数的排序",
+                                 "十几减8的退位减法"
+                             ],
+        "source":  "23-24二年级下·湖南株洲·期末"
+    },
+    {
+        "id":  "358",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "下面是二(1)班全班学生参加社团的情况,请你按要求回答问题。(每人只参加一个社团)![](images/134635.png)\n(2)二(1)班一共有( )人.\n(3)这几个社团中,你最想参加( )社团,二(1)班参加这个社团的有( )人.\n(4)二(1)班参加( )社团的人数最多.\n(5)参加啦啦操社团的学生比参加机器人社团的学生多多少人。",
+        "options":  [
+
+                    ],
+        "answer":  "9;11;6;12;38;机器人;6;绘画;5",
+        "solution":  "【分析】根据题意可知:(1)根据图中的统计信息填写表格:篮球社团中,一个完整的\u0027正\u0027字笔画有5画,代表5,还有剩余的4画,所以篮球社团人数是5+4=9;啦啦操社团数出\"√\"的个数即可;机器人社团数出○的个数即可;绘画社团中,一个完整的\u0027正\u0027字笔画有5画,代表5,2个完整的\u0027正\u0027,是10画,还有剩余的2画,所以绘画社团人数是5+5+2=12。(2)因为每人只参加一个社团,所以二(1)班共有的人数是每个社团的人数全部加起来,即9+11+6+12。(3)根据4个社团的情况,选择一个社团,并说出这个社团的人数即可。(4)通过比较数的大小可以知道二(1)班参加人数最多的社团。(5)参加啦啦操社团的学生比参加机器人社团的学生多多少人,用参加啦啦操社团的学生-参加机器人社团的学生即可。据此解答.\n\n【详解】(1)根据上面的信息填写表格:篮球社团9人,啦啦操社团11人,机器人社团6人,绘画社团12人。(2)9+11+6+12=20+6+12=26+12=38(人),所以二(1)班一共有38人。(3)这几个社团中,你最想参加机器人社团,二(1)班参加这个社团的有6人(答案不唯一)。(4)因为12\u003e11\u003e9\u003e6,所以二(1)班参加绘画社团的人数最多。(5)11-6=5(人),所以参加啦啦操社团的学生比参加机器人社团的学生多5人。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "20以内数的比大小",
+                                 "十几减7",
+                                 "6的退位减法",
+                                 "100以内数的连加运算"
+                             ],
+        "source":  "23-24二年级下·湖北黄冈·期末"
+    },
+    {
+        "id":  "359",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "希望小学举办\"小学生诗词大会\",各班派一名代表参加。下面是二(1)班40名同学对4名候选人的投票结果(每人投1票)。![](images/134640.png)\n(2)得票最多的是( ),得票最少的是( ).\n(3)你还能得到什么信息。写一写。",
+        "options":  [
+
+                    ],
+        "answer":  "10;14;9;7;聪聪;思思;聪聪比小可多5票",
+        "solution":  "【分析】(1)根据题意可知:\u0027正\u0027字的笔划代表1人,数一数有几个\u0027正\u0027字,一共多少笔划,就是多少人已投票,然后用共有的人数减去已投的人数即可求出思思的票数。然后再根据各自所得票数进行填空;(2)将各同学得的票数进行比较,选出得票最多和最少的同学;(3)结合题意,得出的信息合理即可。例如:可以得出聪聪比小可多多少票,用聪聪的票数减去小可的票数即可.\n\n【详解】(1)40-10=30(票),30-14=16(票),16-9=7(票),则思思得7票。填空如下:小明10票,聪聪14票,小可9票,思思7票。(2)14\u003e10\u003e9\u003e7,则得票最多的是聪聪,得票最少的是思思。(3)14-9=5(票),答:可以得出聪聪比小可多5票。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "两位数与两位数的退位减法"
+                             ],
+        "source":  "23-24 二年级下·湖北随州·期末"
+    },
+    {
+        "id":  "360",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "二(1)班同学统计了班图书角中的各类图书数量,结果如下。![](images/134644.png)\n(2)图书角中( )类图书最多,( )类图书最少.\n(3)如果要新添一些图书,你建议添加( )类图书。",
+        "options":  [
+
+                    ],
+        "answer":  "30;23;27;2;文学;历史;历史",
+        "solution":  "[analysis](1)根据一个\u0027正\u0027字表示5本,分别数出各类图书的数量,据此填表即可;(2)比较这四类书本数的大小即可;(3)根据表格中的数据,合理建议即可.\n\n【详解】(1)文学类图书有30本,历史类图书有23本,旅游类图书有27本,历史类图书有2本。填表:文学类30本,科学类23本,旅游类27本,历史类2本。(2)30\u003e27\u003e23\u003e2,文学类图书最多,历史类图书最少。(3)如果要新添一些图书,建议添加历史类图书,因为历史类图书太少了。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "23-24 二年级下·湖南岳阳·期末"
+    },
+    {
+        "id":  "361",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "二(1)班参加课外活动情况绘画组![](images/134647.png)\n(1)参加( )组的人最多,参加( )组的人最少.\n(2)参加( )组和( )组的人数相同.\n(3)你还能提出什么问题并解答。",
+        "options":  [
+
+                    ],
+        "answer":  "绘画;体育;音乐;舞蹈;参加绘画组的人数比参加体育组的人数多几人;13-4=9(人)",
+        "solution":  "【分析】(1)先通过数\u0027正\u0027字的方法,数出每个课外小组的人数,再比一比各组的人数即可知参加哪个组的人最多,参加哪个组的人最少。(2)通过(1)得到的各小组人数,即可知哪两个组的人数相同。(3)根据统计表提出合理的问题并解答.\n\n【详解】(1)通过数\u0027正\u0027字可知:绘画组13人,音乐组12人,舞蹈组12人,体育组4人。13\u003e12=12\u003e4,参加绘画组的人最多,参加体育组的人最少。(2)参加音乐组和舞蹈组的人数相同。(3)参加绘画组的人数比参加体育组的人数多几人。(答案不唯一)13-4=9(人),答:参加绘画组的人数比参加体育组的人数多9人。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "\"提问题\"\"填条件\"问题",
+                                 "十几减5~2的退位减法"
+                             ],
+        "source":  "23-24 二年级下·河北邯郸·期末"
+    },
+    {
+        "id":  "362",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "二年级(1)班投票选举班长(每人只能投一票),投票结果如下。![](images/134659.png)\n(2)完成以下题目:①本次参与投票的同学一共有( )人。②得票最多的是( ),得票最少的是( ),他们之间相差( )票。③如果得票数最多的同学当班长,那么( )会当选。④选举投票那天,小明因病请假没能参加投票,如果她也参加了投票,会对结果产生影响吗。为什么。",
+        "options":  [
+
+                    ],
+        "answer":  "7;8;8;20;43;张丽;徐平;13;张丽;不会,因为8票再加1票得9票,9票还是比20票少,当选的还是张丽。",
+        "solution":  "【分析】(1)数一数,分别有7人,8人,8人,20人,据此填空;(2)将各人数相加即可;将人数作比较,20以内的数从小到大排列是:1\u003c2\u003c3\u003c4\u003c5\u003c6\u003c7\u003c8\u003c9\u003c10\u003c11\u003c12\u003c13\u003c14\u003c15\u003c16\u003c17\u003c18\u003c19\u003c20。然后用最多的人数减最少的人数。将小明的票投给第二名再比较即可求解.\n\n【详解】(1)填表:徐平7票,李明8票,陈雪8票,张丽20票。(2)①7+8+8+20=43(人),本次参与投票的同学一共有43人。②20\u003e8\u003e7,得票最多的是张丽,得票最少的是徐平,他们之间相差13票。③如果得票数最多的同学当班长,那么张丽会当选。④不会,因为8票再加1票得9票,9票还是比20票少,当选的还是张丽。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "23-24 二年级下·浙江温州·期末"
+    },
+    {
+        "id":  "363",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "下面是通城县万家乐市端午节一天的家电销售数量记录。![](images/134821.png)\n(2)上表中,卖出的最多。卖出的空调比冰箱多台.\n(3)请你再提出一个数学问题,并解答。",
+        "options":  [
+
+                    ],
+        "answer":  "7;11;25;15;空调;14;卖出的电视机比洗衣机多多少台;15-7=8(台)",
+        "solution":  "【分析】(1)一个\"√\"表示1票,一个\u0027正\u0027字表示5票,数出表中\"√\"的个数和\u0027正\u0027字的笔画数,完成填表;(2)通过比较各电器卖出的数量,选出卖的最多的填空即可;用卖出的空调数量,减去冰箱的销量;(3)(答案不唯一)提出合理问题并解答即可.\n\n【详解】(1)填表如下:洗衣机7台,冰箱11台,空调25台,电视机15台。(2)25\u003e15\u003e11\u003e7;25-11=14(台)填空如下:上表中,卖出的空调最多。卖出的空调比冰箱多14台。(3)(答案不唯一)提问:卖出的电视机比洗衣机多多少台。15-7=8(台),答:卖出的电视机比洗衣机多8台。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "\"提问题\"\"填条件\"问题"
+                             ],
+        "source":  "22-23 二年级下·湖北咸宁·期末"
+    },
+    {
+        "id":  "364",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "下面是通城县万家乐市端午节一天的家电销售数量记录。![](images/134821.png)\n(2)上表中,卖出的最多。卖出的空调比冰箱多台.\n(3)请你再提出一个数学问题,并解答。",
+        "options":  [
+
+                    ],
+        "answer":  "7;11;25;15;空调;14;卖出的电视机比洗衣机多多少台;15-7=8(台)",
+        "solution":  "【分析】(1)一个\"√\"表示1票,一个\u0027正\u0027字表示5票,数出表中\"√\"的个数和\u0027正\u0027字的笔画数,完成填表;(2)通过比较各电器卖出的数量,选出卖的最多的填空即可;用卖出的空调数量,减去冰箱的销量;(3)(答案不唯一)提出合理问题并解答即可.\n\n【详解】(1)填表如下:洗衣机7台,冰箱11台,空调25台,电视机15台。(2)25\u003e15\u003e11\u003e7;25-11=14(台)填空如下:上表中,卖出的空调最多。卖出的空调比冰箱多14台。(3)(答案不唯一)提问:卖出的电视机比洗衣机多多少台。15-7=8(台),答:卖出的电视机比洗衣机多8台。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "\"提问题\"\"填条件\"问题"
+                             ],
+        "source":  "22-23 二年级下·湖北咸宁·期末"
+    },
+    {
+        "id":  "365",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "通城县万家乐市端午节一天的家电销售数量记录。![](images/134821.png)\n(2)上表中,卖出的最多。卖出的空调比冰箱多台.\n(3)请你再提出一个数学问题,并解答。",
+        "options":  [
+
+                    ],
+        "answer":  "7;11;25;15;空调;14;卖出的电视机比洗衣机多多少台;15-7=8(台)",
+        "solution":  "【分析】(1)一个\"√\"表示1票,一个\u0027正\u0027字表示5票,数出表中\"√\"的个数和\u0027正\u0027字的笔画数,完成填表;(2)通过比较各电器卖出的数量,选出卖的最多的填空即可;用卖出的空调数量,减去冰箱的销量;(3)(答案不唯一)提出合理问题并解答即可.\n\n【详解】(1)填表如下:洗衣机7台,冰箱11台,空调25台,电视机15台。(2)25\u003e15\u003e11\u003e7;25-11=14(台)填空如下:上表中,卖出的空调最多。卖出的空调比冰箱多14台。(3)(答案不唯一)提问:卖出的电视机比洗衣机多多少台。15-7=8(台),答:卖出的电视机比洗衣机多8台。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "\"提问题\"\"填条件\"问题"
+                             ],
+        "source":  "22-23 二年级下·湖北咸宁·期末"
+    },
+    {
+        "id":  "366",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "下面是通城县万家乐市端午节一天的家电销售数量记录。![](images/134821.png)\n(2)上表中,卖出的最多。卖出的空调比冰箱多台.\n(3)请你再提出一个数学问题,并解答。",
+        "options":  [
+
+                    ],
+        "answer":  "7;11;25;15;空调;14;卖出的电视机比洗衣机多多少台;15-7=8(台)",
+        "solution":  "【分析】(1)一个\"√\"表示1票,一个\u0027正\u0027字表示5票,数出表中\"√\"的个数和\u0027正\u0027字的笔画数,完成填表;(2)通过比较各电器卖出的数量,选出卖的最多的填空即可;用卖出的空调数量,减去冰箱的销量;(3)(答案不唯一)提出合理问题并解答即可.\n\n【详解】(1)填表如下:洗衣机7台,冰箱11台,空调25台,电视机15台。(2)25\u003e15\u003e11\u003e7;25-11=14(台)填空如下:上表中,卖出的空调最多。卖出的空调比冰箱多14台。(3)(答案不唯一)提问:卖出的电视机比洗衣机多多少台。15-7=8(台),答:卖出的电视机比洗衣机多8台。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "\"提问题\"\"填条件\"问题"
+                             ],
+        "source":  "22-23 二年级下·湖北咸宁·期末"
+    },
+    {
+        "id":  "367",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "小海站在路边,对5分钟内经过的车辆做了统计,情况如下所示。![](images/134844.png)\n(2)这5分钟内,( )车最少,( )车最多.\n(3)5分钟内这四种车一共经过了( )辆.\n(4)在下一个5分钟里,经过最多的可能是( )车。",
+        "options":  [
+
+                    ],
+        "answer":  "25;11;7;17;摩托;小汽车;60;小汽车",
+        "solution":  "【分析】(1)分别数一数每辆车下面的\u0027正\u0027字有多少个有多少笔划,然后把数得的笔划数填入表格即可。(2)把每辆车得的票数进行比较,选出最小的和最大的即可。(3)把所有车辆得的票数相加即可。(4)通过比较,票数最多的数小汽车,其他车辆都小于小汽车,再过5分钟,小汽车的票数还是会涨,所以小汽车票数还是最多的.\n\n【详解】(1)由分析可得:小汽车25辆,面包车11辆,摩托车7辆,大卡车17辆。(2)25\u003e17\u003e11\u003e7,则这5分钟内,摩托最少,小汽车最多。(3)25+11+7+17=36+7+17=43+17=60(辆),所以5分钟内这四种车一共经过了60辆。(4)在下一个5分钟里,经过最多的可能是小汽车。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "100以内数的连加运算"
+                             ],
+        "source":  "22-23 二年级下·浙江宁波·期末"
+    },
+    {
+        "id":  "368",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "二年级各班班级拥有图书总数统计图如图所示。![](images/134849.png)\n(1)从统计图能看出,一格代表( )本书,半格就代表( )本书.\n(2)( )班拥有图书最多,( )班拥有图书最少.\n(3)全年级共有图书( )本.\n(4)201班比202班多( )本,203班比204班少( )本。",
+        "options":  [
+
+                    ],
+        "answer":  "33;24;18;21;6;3;201;203;96;9;3",
+        "solution":  "【分析】(1)观察统计图可知一格是0-6,则表明一格有6本书,半格就表示3本书。(2)根据(1)数出各班各有多少本书,分别填入表格中,再比较大小选出最多的班和最少的班。(3)把各班有的数量相加减即可。(4)求201班比202班多多少本。用201班有的数量减去202班的数量即可;求203班比204班少多少本。用204班的数量减去203班的数量即可.\n\n【详解】(1)从统计图能看出,一格代表(6)本书,半格就代表(3)本书。(2)由分析可得:201班33本,202班24本,203班18本,204班21本。33\u003e24\u003e21\u003e18,由此可知201班拥有图书最多,203班拥有图书最少。(3)33+24+21+18=57+21+18=78+18=96(本),所以全年级共有图书96本。(4)33-24=9(本),24-21=3(本),所以201班比202班多9本,203班比204班少3本。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "100以内数的比大小",
+                                 "100以内数的连加运算"
+                             ],
+        "source":  "22-23 二年级下·浙江宁波·期末"
+    },
+    {
+        "id":  "369",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "下面是二年级同学最喜欢的体育活动情况。(每人只选一种)![](images/134858.png)\n(2)根据调查结果,你认为本校应多准备哪种体育器材。\n(3)你还能提出其他数学问题并解答吗。",
+        "options":  [
+
+                    ],
+        "answer":  "25;20;15;10;5;跳绳;最喜欢跳绳和跳舞的一共有多少人;25+20=45(人)",
+        "solution":  "【分析】(1)数出喜欢各体育活动的人数,填写表格即可,\u0027正\u0027字的每一笔代表1人;(2)比较喜欢各种体育活动的人数,喜欢哪种体育活动的人数多就多准备哪种体育器材;(3)提出的问题符合题意即可;可提出,最喜欢跳绳和跳舞的一共有多少人。用加法计算.\n\n【详解】(1)填表:跳绳25人,跳舞20人,打乒乓球15人,踢毽子10人,其他5人。(2)25\u003e20\u003e15\u003e10\u003e5,答:我认为本校应多准备跳绳。(3)最喜欢跳绳和跳舞的一共有多少人。(答案不唯一)25+20=45(人),答:最喜欢跳绳和跳舞的一共有45人。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "\"提问题\"\"填条件\"问题",
+                                 "100以内数的比大小",
+                                 "两位数与整十数的加法"
+                             ],
+        "source":  "22-23 二年级下·浙江宁波·期末"
+    },
+    {
+        "id":  "370",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "小海站在路边,对5分钟内经过的车辆做了统计,情况如下所示。![](images/134844.png)\n(2)这5分钟内,( )车最少,( )车最多.\n(3)5分钟内这四种车一共经过了( )辆.\n(4)在下一个5分钟里,经过最多的可能是( )车。",
+        "options":  [
+
+                    ],
+        "answer":  "25;11;7;17;摩托;小汽车;60;小汽车",
+        "solution":  "【分析】(1)分别数一数每辆车下面的\u0027正\u0027字有多少个有多少笔划,然后把数得的笔划数填入表格即可。(2)把每辆车得的票数进行比较,选出最小的和最大的即可。(3)把所有车辆得的票数相加即可。(4)通过比较,票数最多的是小汽车,其他车辆都小于小汽车,再过5分钟,小汽车的票数还是会涨,所以小汽车票数还是最多的.\n\n【详解】(1)由分析可得:小汽车25辆,面包车11辆,摩托车7辆,大卡车17辆。(2)25\u003e17\u003e11\u003e7,则这5分钟内,摩托最少,小汽车最多。(3)25+11+7+17=36+7+17=43+17=60(辆),所以5分钟内这四种车一共经过了60辆。(4)在下一个5分钟里,经过最多的可能是小汽车。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "100以内数的连加运算"
+                             ],
+        "source":  "22-23 二年级下·浙江宁波·期末"
+    },
+    {
+        "id":  "371",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "二年级各班班级拥有图书总数统计图如图所示。![](images/134849.png)\n(1)从统计图能看出,一格代表( )本书,半格就代表( )本书.\n(2)( )班拥有图书最多,( )班拥有图书最少.\n(3)全年级共有图书( )本.\n(4)201班比202班多( )本,203班比204班少( )本。",
+        "options":  [
+
+                    ],
+        "answer":  "33;24;18;21;6;3;201;203;96;9;3",
+        "solution":  "【分析】(1)观察统计图可知一格是0-6,则表明一格有6本书,半格就表示3本书。(2)根据(1)数出各班各有多少本书,分别填入表格中,再比较大小选出最多的班和最少的班。(3)把各班有的数量相加即可。(4)求201班比202班多多少本。用201班有的数量减去202班的数量即可;求203班比204班少多少本。用204班的数量减去203班的数量即可.\n\n【详解】(1)从统计图能看出,一格代表(6)本书,半格就代表(3)本书。(2)由分析可得:201班33本,202班24本,203班18本,204班21本。33\u003e24\u003e21\u003e18,由此可知201班拥有图书最多,203班拥有图书最少。(3)33+24+21+18=57+21+18=78+18=96(本),所以全年级共有图书96本。(4)33-24=9(本),21-18=3(本),所以201班比202班多9本,203班比204班少3本。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "100以内数的比大小",
+                                 "100以内数的连加运算"
+                             ],
+        "source":  "22-23 二年级下·浙江宁波·期末"
+    },
+    {
+        "id":  "372",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "下面是二年级同学最喜欢的体育活动情况。(每人只选一种)![](images/134858.png)\n(2)根据调查结果,你认为本校应多准备哪种体育器材。\n(3)你还能提出其他数学问题并解答吗。",
+        "options":  [
+
+                    ],
+        "answer":  "25;20;15;10;5;跳绳;最喜欢跳绳和跳舞的一共有多少人;25+20=45(人)",
+        "solution":  "【分析】(1)数出喜欢各体育活动的人数,填写表格即可,\u0027正\u0027字的每一笔代表1人;(2)比较喜欢各种体育活动的人数,喜欢哪种体育活动的人数多就多准备哪种体育器材;(3)提出的问题符合题意即可;可提出最喜欢跳绳和跳舞的一共有多少人,用加法计算.\n\n【详解】(1)填表:跳绳25人,跳舞20人,打乒乓球15人,踢毽子10人,其他5人。(2)25\u003e20\u003e15\u003e10\u003e5,答:我认为本校应多准备跳绳。(3)最喜欢跳绳和跳舞的一共有多少人。(答案不唯一)25+20=45(人),答:最喜欢跳绳和跳舞的一共有45人。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "\"提问题\"\"填条件\"问题",
+                                 "100以内数的比大小",
+                                 "两位数与整十数的加法"
+                             ],
+        "source":  "22-23二年级下·浙江宁波·期末"
+    },
+    {
+        "id":  "373",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "二(1)班一共有42人,他们参加各个兴趣小组的情况如下表。(每人只参加一个兴趣小组)![](images/134906.png)\n(2)参加( )小组的人数最少,比参加绘画小组的人数少( )人.\n(3)参加舞蹈小组的人数至少再增加( )人就可以超过参加绘画小组的人数.\n(4)参加绘画和舞蹈小组的一共有( )人。",
+        "options":  [
+
+                    ],
+        "answer":  "16;13;6;7;足球;10;4;29",
+        "solution":  "【分析】(1)将每个小组的人数数出来填写即可;\u0027正\u0027字的每一笔代表1人;(2)比较各小组的人数,找出最少的即可。求人数最少的小组比绘画小组少几人,用减法计算;(3)舞蹈小组的人数要超过绘画小组的人数,则最少为绘画小组的人数+1,再减去原来的人数,就是要增加的人数;(4)绘画小组的人数+舞蹈小组的人数=一共的人数.\n\n【详解】(1)表格填写如下:绘画16人,舞蹈13人,足球6人,围棋7人。(2)16\u003e13\u003e7\u003e6;16-6=10(人),参加足球小组的人数最少,比参加绘画小组的人数少10人。(3)16+1-13=4(人),参加舞蹈小组的人数至少再增加4人就可以超过参加绘画小组的人数。(4)16+13=29(人),参加绘画和舞蹈小组的一共有29人。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "20以内数的比大小",
+                                 "两位数与两位数的不进位加法"
+                             ],
+        "source":  "22-23二年级下·福建厦门·期末"
+    },
+    {
+        "id":  "374",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "二(5)班通过投票来选班长,4名候选人的得票情况如下。(每人只能投一票).\n![](images/134916.png)\n(2)二(5)班参加投票的有( )名同学,( )的票数最多,( )的票数最少.\n(3)根据票数的多少,( )应该当选班长。",
+        "options":  [
+
+                    ],
+        "answer":  "15;7;12;8;42;元元;奇奇;元元",
+        "solution":  "【分析】(1)元元的票数按\u0027正\u0027字笔画数,奇奇的票数按小棒的数量数,思思的票数按圆圈的数量数,丁丁的票数按对号的数量数,据此得出结论。(2)先将每名同学的票数相加,再比较4名候选人的票数得出结论即可。(3)根据票数的多少,选票数最多的同学当班长即可.\n\n【详解】(1)根据分析填表如下:元元15票,奇奇7票,思思12票,丁丁8票。(2)15+7+12+8=22+12+8=34+8=42(人),15\u003e12\u003e8\u003e7,故二(5)班参加投票的有42名同学,元元的票数最多,奇奇的票数最少。(3)15\u003e12\u003e8\u003e7,故元元应该当选班长。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "22-23二年级下·山西运城·期末"
+    },
+    {
+        "id":  "375",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "以下是中心小学二年(1)班小朋友参加课外兴趣小组的情况:(每人只能参加一个小组)![](images/134926.png)\n(2)参加( )小组的人最多,有( )人;参加( )小组的人最少,他们相差( )人;(3)你还能提出其他数学问题并解答吗。",
+        "options":  [
+
+                    ],
+        "answer":  "18;12;6;9;计算机;18;跳舞;12;参加足球和画画的有多少人;12+9=21(人)",
+        "solution":  "【分析】(1)一个\u0027正\u0027字代表5人,每一笔代表1人,分别计算出计算机,足球,跳舞,画画的人数写在对应的表格里即可,据此解答。(2)在第一问填好的表格里,选出人数最多的组和最少的组填在括号里,用减法计算出他们相差多少人,据此解答。(3)合理提出问题并解答即可.\n\n【详解】(1)计算机18人,足球12人,跳舞6人,画画9人,填表如下:计算机18人,足球12人,跳舞6人,画画9人。(2)18\u003e12\u003e9\u003e6,计算机人数最多18人,跳舞人数最少6人,18-6=12(人)。(3)(答案不唯一)参加足球和画画的有多少人。12+9=21(人),答:参加足球和画画的有21人。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "\"提问题\"\"填条件\"问题"
+                             ],
+        "source":  "22-23 二年级下·福建莆田·期末"
+    },
+    {
+        "id":  "376",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "二(1)班投票选举一位\"环保小卫士\",每人只能投一票,投票结果如下图。![](images/134934.png)\n(2)根据投票结果,( )应当选\"环保小卫士\".\n(3)票数最多的与最少的相差( )票.\n(4)有2名同学请假没能参加投票,如果他们也投票,那么结果( )改变。(填\"会\"或\"不会\")",
+        "options":  [
+
+                    ],
+        "answer":  "18;8;10;12;李烁;10;不会",
+        "solution":  "【分析】(1)分别数一数每个同学名字下面的\u0027正\u0027字有多少个有多少笔划,然后把数得的笔划数填入表格即可。(2)把每个同学得的票数进行比较,谁的多就是\"环保小卫士\"。(3)用票数最多的减去票数最少的即可。(4)请假2人则是2票,把这两票分别加到各同学名下然后再进行比较,票数多的还是李烁则说明不变.\n\n【详解】(1)由分析可得:李烁18票,张彤8票,王宁10票,李佳12票。(2)18\u003e12\u003e10\u003e8,则李烁的票数最多,所以李烁应当选\"环保小卫士\"。(3)18-8=10(票),所以票数最多的与最少的相差10票。(4)李烁:18+2=20(票),张彤:8+2=10(票),王宁:10+2=12(票),李佳:12+2=14(票),20\u003e14\u003e12\u003e10,还是李烁票数多,所以结果不会改变。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "不进位加法(20以内)"
+                             ],
+        "source":  "22-23 二年级下·云南昭通·期末"
+    },
+    {
+        "id":  "377",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "在一次班干部选举中,有四名班长候选人,他们的得票数如下。豆豆乐乐兰兰刚刚正正正正![](images/134944.png)\n2。( )的得票数最多,( )的得票数最少.\n3。如果选一人为班长,选( )比较合适.\n4。选举那天,王芳因病请假没能参加投票。如果她也投了票,结果会怎样。为什么。",
+        "options":  [
+
+                    ],
+        "answer":  "5;6;9;3;兰兰;刚刚;兰兰;不影响。因为兰兰与其他人的票数相差大于1票。",
+        "solution":  "【分析】1。按\u0027正\u0027字的笔画数量得出得票的数量。2。根据题1的数据的大小得出结论即可。3。选票数最多的人为班长即可。4。因为兰兰与其他人的票数相差大于1票,则王芳的票投给谁都不影响结果.\n\n【详解】1。根据分析填表如下:豆豆5票,乐乐6票,兰兰9票,刚刚3票。2。兰兰的得票数最多,刚刚的得票数最少。3。如果选一人为班长,选兰兰比较合适。4。不影响。因为兰兰与其他人的票数相差大于1票,则王芳的票投给谁都不影响结果。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "23-24 二年级下·全国·假期作业"
+    },
+    {
+        "id":  "378",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "小欣调查了本班同学最喜欢的课外书情况。![](images/134948.png)\n1。喜欢( )的人数最多,喜欢( )的人数最少.\n2。如果这个班要购买课外书,你有什么建议。",
+        "options":  [
+
+                    ],
+        "answer":  "2;7;14;19;连环画;科技书;多购进一些连环画",
+        "solution":  "【分析】根据√的数量得出喜欢科技书和漫画书的人数,根据\u0027正\u0027字的笔画数量得出喜欢故事书和连环画的人数,据此填表即可。1。根据表中的数据大小得出结论即可。2。可以建议多买些较多人喜欢的图书,此题答案不唯一合理即可.\n\n【详解】填表:科技书2人,漫画7人,故事书14人,连环画19人。1。喜欢连环画的人数最多,喜欢科技书的人数最少。2。多购进一些连环画。(答案不唯一)",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "23-24 二年级下·全国·假期作业"
+    },
+    {
+        "id":  "379",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "下面是创力家电公司某周末的家电销售情况。![](images/134959.png)\n(2)根据调查结果,你认为创力家电公司近期多进哪种电器。\n(3)你还能提出其他数学问题并解答吗。",
+        "options":  [
+
+                    ],
+        "answer":  "9;11;15;6;创力家电公司近期应多进空调;这个周末空调比电视机多销售多少台;15-9=6(台)",
+        "solution":  "【分析】(1)根据统计结果先分别数一数各种电器销售数量的多少,然后填空即可。一个\u0027正\u0027表示5台,一笔表示1台。(2)先比较一下这些电器销售数量的多少,销售数量最多的电器应多进一些。(3)根据已知条件提出数学问题,合理即可,答案不唯一.\n\n【详解】(1)填表:电视机9台,冰箱11台,空调15台,洗衣机6台。(2)15\u003e11\u003e9\u003e6,这周末空调的销售数量最多;答:创力家电公司近期应多进空调。(3)这个周末空调比电视机多销售多少台。15-9=6(台),答:这个周末空调比电视机多销售6台。(答案不唯一)",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "\"提问题\"\"填条件\"问题",
+                                 "单式统计表的特点及填补",
+                                 "十几减9的退位减法"
+                             ],
+        "source":  "21-22 二年级下·河南信阳·期末"
+    },
+    {
+        "id":  "380",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "小小统计员。乐乐玩具店为了了解小猴,小狗,熊猫和小马四种毛绒玩具的销售量,作了下面的记录表![](images/135008.png)\n(2)( )毛绒玩具和( )毛绒玩具销售的数量同样多。",
+        "options":  [
+
+                    ],
+        "answer":  "5;10;10;13;小猴;小狗",
+        "solution":  "【分析】(1)依次数出各种毛绒玩具的数量填空即可;\u0027正\u0027字的每一笔代表1;(2)比较毛绒玩具的数量,找到同样多的即可.\n\n【详解】(1)请把上面记录的数据填在下面的表格里:熊猫5个,小猴10个,小狗10个,小马13个。(2)13\u003e10=10\u003e5,小猴毛绒玩具和小狗毛绒玩具销售的数量同样多。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "20以内数的比大小"
+                             ],
+        "source":  "22-23 二年级下·江西上饶·期中"
+    },
+    {
+        "id":  "381",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "如表统计表记录的是二(1)班同学的课余生活情况。![](images/135013.png)\n(1)喜欢的人数最多,喜欢的人数最少.\n(2)喜欢看动画片的人数比喜欢去户外玩的多人.\n(3)你还能提出什么数学问题并解答吗。",
+        "options":  [
+
+                    ],
+        "answer":  "打游戏机;读课外书;5;课余时间打游戏机的人数比喜欢读课外书的人数多多少人;18-5=13(人)",
+        "solution":  "【分析】(1)将人数作比较即可求解;(2)用喜欢看动画片的人数减去喜欢去户外玩的人数即可;(3)合理即可,如:课余时间打游戏机的人数比喜欢读课外书的人数多多少人。\n\n【详解】(1)18\u003e13\u003e8\u003e5,喜欢打游戏机的人数最多,喜欢读课外书的人数最少。(2)13-8=5(人),喜欢看动画片的人数比喜欢去户外玩的多5人。(3)课余时间打游戏机的人数比喜欢读课外书的人数多多少人。(答案不唯一)18-5=13(人),答:课余时间打游戏机的人数比喜欢读课外书的人数多13人。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "\"提问题\"\"填条件\"问题",
+                                 "20以内数的比大小"
+                             ],
+        "source":  "22-23 二年级下·广东佛山·期中"
+    },
+    {
+        "id":  "382",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "二(1)班同学的生日在四季中的情况如下表。![](images/135018.png)\n(2)从图中我们可以看出,二(1)班共有( )名同学参与了调查.\n(3)( )季过生日的人数最多,( )季过生日的人数最少.\n(4)你还能提出什么数学问题并解答。",
+        "options":  [
+
+                    ],
+        "answer":  "13;10;16;7;46;秋;冬;春季过生日和秋季过生日的人数一共有多少;13+16=29(人)",
+        "solution":  "【分析】(1)通过\u0027正\u0027字来统计同学生日在四季中的人数,每个\u0027正\u0027字有5笔说明有5个人。(2)把四个季节的人数加起来即可。(3)把四个季节的人数做比较即可。(4)结合题意,提出问题合理即可。例如:春季过生日和秋季过生日的人数一共有多少。用春季的人数加上秋季的人数即可.\n\n【详解】(1)由分析可得:春季13人,夏季10人,秋季16人,冬季7人。(2)13+10+16+7=23+16+7=39+7=46(名),所以二(1)班共有46名同学参与了调查。(3)16\u003e13\u003e10\u003e7,所以秋季过生日的人数最多,冬季过生日的人数最少。(4)春季过生日和秋季过生日的人数一共有多少。13+16=29(人),答:春季过生日和秋季过生日的人数一共有29人。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "\"提问题\"\"填条件\"问题",
+                                 "两位数与两位数的不进位加法",
+                                 "100以内数的连加运算"
+                             ],
+        "source":  "23-24二年级下·湖南张家界·期中"
+    },
+    {
+        "id":  "383",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "二(1)班要评选出一个先锋小队,下面是统计的各小队在\"雏鹰争章\"活动中获得雏鹰奖章的数量情况。![](images/135023.png)\n(1)二(1)班一共获得了( )枚雏鹰奖章.\n(2)二(1)班第( )小队获得的雏鹰奖章最少,第一小队比第三小队多获得了( )枚雏鹰奖章.\n(3)第几小队最有可能被评为先锋小队。为什么。",
+        "options":  [
+
+                    ],
+        "answer":  "34;二;4;第一小队;因为第一小队获得的雏鹰奖章最多",
+        "solution":  "【分析】(1)依次数出各小队获得奖章的数量,相加即可求出总数量;(2)比较各小队获得奖章的数量,找到最少的即可;第一小队获得的数量-第三小队获得的数量=第一小队比第三小队多获得的数量;(3)获得奖章最多的,就是最有可能被评为先锋小队的.\n\n【详解】(1)第一小队获得12枚;第二小队获得5枚;第三小队获得8枚;第四小队获得9枚。12+5+8+9=34(枚),二(1)班一共获得了34枚雏鹰奖章。(2)12\u003e9\u003e8\u003e5;12-8=4,二(1)班第二小队获得的雏鹰奖章最少,第一小队比第三小队多获得了4枚雏鹰奖章。(3)第一小队最有可能被评为先锋小队。因为他们获得的雏鹰奖章最多。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "20以内数的比大小",
+                                 "十几减8的退位减法",
+                                 "100以内数的连加运算"
+                             ],
+        "source":  "23-24二年级下·贵州黔南·期中"
+    },
+    {
+        "id":  "384",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "下面是三(1)班同学体重情况记录表。![](images/135034.png)\n(1)把全班同学的体重整理在下表中。体重(kg)25及以下26~3031~3536~4041及以上人数\n(2)从上表可以看出,体重在( )千克这一段的人数最多,体重在( )千克这一段的人数最少。",
+        "options":  [
+
+                    ],
+        "answer":  "1;5;7;9;3;36~40;25及以下",
+        "solution":  "【分析】(1)按顺序,不重复,不遗漏的数出各种规格的体重人数;(2)比较各种规格的体重人数,再选出人数最多和人数最少的规格;据此解答.\n\n【详解】(1)根据分析:25及以下1人,26~30有5人,31~35有7人,36~40有9人,41及以上有3人。(2)1\u003c3\u003c5\u003c7\u003c9,所以体重在36~40千克这一段的人数最多,体重在25及以下千克这一段的人数最少。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "单式统计表的特点及填补"
+                             ],
+        "source":  "23-24 三年级下·河北唐山·期中"
+    },
+    {
+        "id":  "385",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "笑笑统计了本班同学最喜欢的动画角色的情况。记录结果如下。(每人只选一个动画角色![](images/135044.png)\n(2)最喜欢( )的人数最多,最喜欢( )的人数最少.\n(3)笑笑一共统计了( )人。",
+        "options":  [
+
+                    ],
+        "answer":  "22;6;8;9;白雪公主;孙悟空;45",
+        "solution":  "【分析】(1)一个\u0027正\u0027字代表5票,一个√代表1票,一个☆代表1票,一个○代表1票,分别计算出多少票填在对应名字下边即可,据此解答。(2)比较大小时,先比较位数,位数多的数就大,个位数比较大小时,哪个数大哪个就大,据此解答。(3)喜欢白雪公主的人数,喜欢孙悟空的人数,喜欢米老鼠的人数和喜欢灰太狼的人数加起来就是一共的人数,据此解答.\n\n【详解】(1)填空如下:白雪公主22人,孙悟空6人,米老鼠8人,灰太狼9人。(2)22\u003e9\u003e8\u003e6,故填空为:最喜欢白雪公主的人数最多,最喜欢孙悟空的人数最少。(3)22+6+8+9=45(人),答:笑笑一共统计了45人。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "22-23二年级下·河南南阳·期中"
+    },
+    {
+        "id":  "386",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "下面是二(1)班同学最想去春游的地方的统计情况。![](images/135047.png)\n(2)用自己喜欢的方式表示喜欢去游乐园的人数.\n(3)根据上面的调查情况,你建议去哪里春游。为什么。",
+        "options":  [
+
+                    ],
+        "answer":  "10;6;6;25;正正正正正;游乐园;因为想去游乐园的人数最多",
+        "solution":  "【分析】(1)数一数,动物园10人,植物园6人,科技馆6人,填表即可。(2)一个\u0027正\u0027字表示5,可以用5个\u0027正\u0027字表示。(3)可以建议去想去的人数最多的地方春游.\n\n【详解】(1)填表:动物园10人,植物园6人,科技馆6人,游乐园25人。(2)动物园:正正 科技馆:○○○○○○ 植物园:√√√√√√ 游乐园:正正正正正(3)我建议去游乐园春游。因为想去游乐园的人数最多。(答案不唯一)",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "23-24二年级下·福建莆田·期中"
+    },
+    {
+        "id":  "387",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "滨海小学二年级(2)班对全班同学最喜欢阅读图书进行调查(每人只选一种图书)。![](images/135057.png)\n(1)二年级(2)班一共有( )人,喜欢( )的人数最多.\n(2)喜欢《童话》和《历史故事》一共有( )人.\n(3)如果二年级(2)班准备期中考后再购买一批图书,你有什么建议。",
+        "options":  [
+
+                    ],
+        "answer":  "45;《童话》;30;《童话》多购买一些,其它图书少购买一些",
+        "solution":  "【分析】(1)用加法把喜欢阅读各种图书的人数加起来,求出和;再比较喜欢阅读各种图书人数的多少,即可解决。(2)用加法把喜欢《童话》的人数和《历史故事》的人数加起来,求出和,即可解决。(3)根据已知条件提建议,合理即可,答案不唯一.\n\n【详解】(1)11+22+8+4=33+8+4=41+4=45(人),22\u003e11\u003e8\u003e4,二年级(2)班一共有45人,喜欢《童话》的人数最多。(2)22+8=30(人),喜欢《童话》和《历史故事》一共有30人。(3)建议:《童话》多购买一些,其它图书少购买一些。(答案不唯一)",
+        "knowledge_points":  [
+                                 "单式统计表的特点及填补",
+                                 "20以内数的比大小",
+                                 "一位数与两位数的进位加法",
+                                 "100以内数的连加运算"
+                             ],
+        "source":  "23-24二年级下·湖南怀化·期中"
+    },
+    {
+        "id":  "388",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "下表是对二年1班45名同学最喜欢看的一种图书的统计情况如下。![](images/135101.png)\n(1)算一算,最喜欢看科技书的有( )人.\n(2)最喜欢看( )的人数最多,喜欢看( )的人数最少.\n(3)最喜欢看漫画书的比最喜欢看连环画的少( )人.\n(4)如果班里要开办一个图书角,应该多买哪几种书比较合适。",
+        "options":  [
+
+                    ],
+        "answer":  "13;故事书;漫画书;5;故事书、科技书、连环画",
+        "solution":  "【分析】(1)一个图形表示1,一个\u0027正\u0027字表示5,据此数清楚喜欢其他图书的人有多少,再用二年1班的总人数减去喜欢其他图书的人数,即可得出答案。(2)根据表格和第(1)小题得出的答案,结合整数比较大小,即可得出答案。(3)用喜欢看连环画的人数减去喜欢看漫画的人数,即可得出答案。(4)结合喜欢各种图书的人数进行分析即可.\n\n【详解】(1)喜欢故事书的人有15人,喜欢漫画书的人有6人,喜欢连环画的人有11人,45-15-6-11=30-6-11=24-11=13(人),所以最喜欢看科技书的有13人。(2)15\u003e13\u003e11\u003e6,所以最喜欢看故事书的人数最多,最喜欢看漫画书的人数最少。(3)11-6=5(人),所以最喜欢看漫画书的比最喜欢看连环画的少5人。(4)答:应该多买故事书,科技书和连环画。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "20以内数的比大小",
+                                 "100以内数的连减运算"
+                             ],
+        "source":  "22-23 二年级下·辽宁鞍山·阶段练习"
+    },
+    {
+        "id":  "389",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "下面是小明统计的二班同学最喜欢吃的水果情况。![](images/135105.png)\n(1)二班同学最喜欢吃( )的人数最多,有( )人。最喜欢吃( )的人数最少,有( )人.\n(2)最喜欢吃( )和( )的人数相等.\n(3)如果班级举行庆祝活动需要买水果,你认为该怎么安排最合适。",
+        "options":  [
+
+                    ],
+        "answer":  "桃子;15;香蕉;5;草莓;苹果;各种水果都要买,草莓、桃子和苹果多买些,香蕉少买些",
+        "solution":  "【分析】(1)依次数出喜欢吃各种水果的人数,比较人数的多少,找到最多的和最少的即可,\u0027正\u0027字的每一笔代表1;(2)根据人数多少的比较,找到数量相等的即可;(3)根据统计的数据提出合理的安排即可,答案不唯一.\n\n【详解】(1)喜欢吃草莓的有11人;喜欢吃香蕉的有5人;喜欢吃苹果的有11人;喜欢吃桃子的有15人。15\u003e11=11\u003e5,二班同学最喜欢吃桃子的人数最多,有15人。最喜欢吃香蕉的人数最少,有5人。(2)最喜欢吃草莓和苹果的人数相等。(3)我认为各种水果都要买,草莓,桃子和苹果多买些,香蕉少买些。(答案不唯一)",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "22-23 二年级下·湖南张家界·期中"
+    },
+    {
+        "id":  "390",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "如表是二(1)班同学的牙齿情况。![](images/135008.png)\n(2)( )的人数最多,( )人数最少.\n(3)二(1)班一共有( )人.\n(4)你有什么建议想对二(1)班同学说。",
+        "options":  [
+
+                    ],
+        "answer":  "18;3;6;4;没有蛀牙;一颗蛀牙;31;尽量少吃甜品,注意牙齿的卫生,早晚坚持刷牙",
+        "solution":  "【分析】(1)根据调查的二(1)班同学的牙齿健康情况,分别数一数每种牙齿情况的有多少人,然后将数据填入表格中即可;(2)比较表中各数据的大小,找到人数最多的和最少的即可;(3)将所有人数相加,即可求出二(1)班一共有多少人;(4)答案不唯一,写出合理建议即可.\n\n【详解】(1)填表如下:没有蛀牙18人,一颗蛀牙3人,两颗蛀牙6人,三颗蛀牙4人。(2)18\u003e6\u003e4\u003e3,没有蛀牙的人数最多,一颗蛀牙的人数最少。(3)18+3+6+4=31(人),二(1)班一共有31人。(4)我的建议是:尽量少吃甜品,注意牙齿的卫生,早晚坚持刷牙。(答案不唯一)",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "20以内数的比大小",
+                                 "100以内数的连加运算"
+                             ],
+        "source":  "22-23 二年级下·山东临沂·期中"
+    },
+    {
+        "id":  "391",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "选班长。本次班长评选投票的情况是这样的.\n![](images/135114.png)\n(2)( )的票数最少,( )的得票数最多.\n(3)谁会担任班长。为什么。",
+        "options":  [
+
+                    ],
+        "answer":  "13;10;16;5;孙楠;赵东;赵东会担任班长,因为他的票数最多。",
+        "solution":  "【分析】一个\u0027正\u0027字5画,一画代表1票。一个\u0027正\u0027字代表5票,分别数出票数填上即可,比较大小后选出谁多谁少,说出选择谁当班长的理由即可,据此解答.\n\n【详解】张兰:2×5+3=10+3=13(票),李浩:2×5=10(票),赵东:3×5+1=15+1=16(票),孙楠:1×5=5(票),故填表为:张兰13票,李浩10票,赵东16票,孙楠5票。(2)16\u003e13\u003e10\u003e5,故填空为:孙楠的票数最少,赵东的得票数最多。(3)赵东会担任班长,因为他的票数最多。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "22-23 二年级下·广东汕尾·期中"
+    },
+    {
+        "id":  "392",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "下面是某书店一周售出部分书的数量统计结果。![](images/135123.png)\n(2)你能获得哪些信息。如果你是书店老板,下次进货时你打算多进什么书。",
+        "options":  [
+
+                    ],
+        "answer":  "14;18;8;6;知道了各种书售出的数量。童话书卖得最多,下次进货时多进童话书。",
+        "solution":  "【分析】(1)依次数出各种书售出的数量填空即可,\u0027正\u0027字的每一笔表示1;(2)根据表格填写合理的信息即可。可以比较各种书售出数量的多少,哪种卖的多就进哪种书.\n\n【详解】(1)故事书售出14本;童话书售出18本;漫画书售出8本;绘画书售出6本。填写如下:故事书14本,童话书18本,漫画书8本,绘画书6本。(2)我获得的信息:知道了各种书售出的数量。18\u003e14\u003e8\u003e6,童话书卖得最多,下次进货时多进童话书。(答案不唯一)",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "23-24二年级下·全国·课后作业"
+    },
+    {
+        "id":  "393",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "下面是二(1)班学生暑假期间在读经典名著活动中的读书情况。![](images/135128.png)\n(1)全班一共有( )人.\n(2)阅读( )的人数最多,阅读( )的人数最少.\n(3)阅读《千字文》的人数比阅读《弟子规》的人数少( )人.\n(4)二(1)班要在图书角增添一些经典名著,你有什么建议。",
+        "options":  [
+
+                    ],
+        "answer":  "32;《弟子规》;《百家姓》;7;读《弟子规》的人多,建议增添《弟子规》",
+        "solution":  "【分析】(1)将读每种书的人数相加就是全班的人数;(2)比较读每种书人数的大小,找到最多的和最少的;(3)求一个数比另一个数少多少,用减法计算;(4)根据题中数据提出合适的建议即可.\n\n【详解】(1)3+6+2+5+12+4=32(人),全班一共有32人。(2)12\u003e6\u003e5\u003e4\u003e3\u003e2,阅读《弟子规》的人数最多,阅读《百家姓》的人数最少。(3)12-5=7(人),阅读《千字文》的人数比阅读《弟子规》的人数少7人。(4)读《弟子规》的人多,建议增添《弟子规》。(答案不唯一)",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "20以内数的比大小",
+                                 "十几减5~2的退位减法"
+                             ],
+        "source":  "23-24二年级下·全国·课后作业"
+    },
+    {
+        "id":  "394",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "二(1)班四个小组参加回收塑料垃圾袋的环保活动。回收情况如下。![](images/135131.png)\n(1)第( )小组回收塑料垃圾袋的数量最多,是( )个.\n(2)第( )小组回收塑料垃圾袋的数量最少,是( )个.\n(3)第三小组回收的塑料垃圾袋比第二小组多( )个.\n(4)你还能提出其他数学问题并解答吗。",
+        "options":  [
+
+                    ],
+        "answer":  "四;15;一;6;4;四个小组一共回收了多少个塑料垃圾袋;6+8+12+15=41(个)",
+        "solution":  "【分析】(1)(2)(3)根据统计图,比较图有颜色的方块可得出;(4)参照前三问,提出问题,据此解答即可.\n\n【详解】根据统计图,每个□表示1个回收塑料垃圾袋得出:(1)第四小组回收塑料垃圾袋的数量最多,是15个;(2)第一小组回收塑料垃圾袋的数量最少,是6个;(3)第三小组回收的塑料垃圾袋比第二小组多4个;(4)可提出问题:四个小组一共回收了多少个塑料垃圾袋。6+8+12+15=41(个),答:四个小组一共回收了41个塑料垃圾袋。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "23-24二年级下·全国·课后作业"
+    },
+    {
+        "id":  "395",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "看图回答问题:\n![](images/135135.png)\n(1)奇思调查了( )名同学.\n(2)( )的最多,( )的最少.\n(3)说一说,在饮食方面,你有什么建议。",
+        "options":  [
+
+                    ],
+        "answer":  "15;肉和菜都爱吃;只爱吃菜;肉和菜都要吃,不能挑食",
+        "solution":  "【分析】(1)将各项人数相加即可得到总人数;(2)比较各项人数的大小,找到最多的和最少的即可;(3)根据调查结果提出符合实际的建议即可.\n\n【详解】(1)3+5+7=8+7=15(名),奇思调查了15名同学。(2)7\u003e5\u003e3,肉和菜都爱吃的最多,只爱吃菜的最少。(3)我的建议:肉和菜都要吃,不能挑食。(答案不唯一)",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "连加(20以内)"
+                             ],
+        "source":  "22-23二年级下·全国·随堂练习"
+    },
+    {
+        "id":  "396",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "看图回答问题:![](images/135138.png)\n(1)借阅童话书的有( )人.\n(2)借阅( )书的人最多.\n(3)图书室要新买一批图书,你有什么建议。",
+        "options":  [
+
+                    ],
+        "answer":  "11;童话;因为借阅童话书的人数比较多,可以多买一些童话书",
+        "solution":  "【分析】(1)根据表格内容,找出借阅童话书的人数即可。(2)对借阅图书的人数进行比较大小,即可得出答案。(3)根据表格内容提出建议即可,可以根据借阅人数越多的图书,多买一些,本小题答案不唯一.\n\n【详解】(1)借阅童话书的有11人。(2)11\u003e9\u003e8,所以借阅童话书的人最多。(3)答:图书室要新买一批图书,我的建议是:因为借阅童话书的人数比较多,可以多买一些童话书。(本小题答案不唯一)",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "20以内数的比大小"
+                             ],
+        "source":  "22-23 二年级下·全国·随堂练习"
+    },
+    {
+        "id":  "397",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "调查全班同学最喜欢吃哪一种水果。![](images/135143.png)\n(1)最喜欢吃( )的人数最多,最喜欢吃( )的人数最少.\n(2)我喜欢吃( ),全班最喜欢吃这种水果的有( )人.\n(3)班里要开联欢会,请你根据调查结果,说说买哪几种水果合理。",
+        "options":  [
+
+                    ],
+        "answer":  "苹果;橘子;梨;12;买苹果、梨这2种水果合理。因为这两种水果喜欢的人最多。",
+        "solution":  "【分析】(1)根据对班级学生的调查,将结果填入表格内,再对喜欢各种水果的人数进行比较大小,据此解答即可。(2)结合自己的喜好和表内调查内容进行解答即可。(3)根据调查结果,选择喜欢水果人数比较多的进行购买比较合理。(本题答案不唯一)\n\n【详解】示例:苹果15人,梨12人,香蕉7人,橘子4人。(1)15\u003e12\u003e7\u003e4,最喜欢吃苹果的人数最多,最喜欢吃橘子的人数最少。(2)我喜欢吃梨,全班最喜欢吃这种水果的有12人。(3)答:班里要开联欢会,请根据调查结果,买苹果,梨这2种水果合理。因为这两种水果喜欢的人最多。(本题答案不唯一)",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "20以内数的比大小"
+                             ],
+        "source":  "22-23二年级下·全国·随堂练习"
+    },
+    {
+        "id":  "398",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "调查本班同学最喜欢哪一个季节,把结果填入下表。![](images/135147.png)\n(1)喜欢什么季节的人数最多。\n(2)如果组织同学们去游玩,最好应安排在哪个季节。\n(3)你还能提出其他问题并解答吗。",
+        "options":  [
+
+                    ],
+        "answer":  "春季;春季;喜欢春季的人比喜欢冬季的人多多少人;15-11=4(人)",
+        "solution":  "【分析】(1)根据对班级学生的调查,将结果填入表格内,再对喜欢各个季节的人数进行比较大小,据此解答即可。(答案不唯一)(2)根据调查结果,选择喜欢人数最多的季节组织学生去游玩。(3)根据表格所提供的数学信息提出问题,并结合学过的数学知识进行解答即可。本小题答案不唯一.\n\n【详解】示例:春季15人,夏季9人,秋季5人,冬季11人。(1)15\u003e11\u003e9\u003e5,所以喜欢春季的人数最多。(2)因为喜欢春季的人数最多,所以组织同学去游玩,最好应安排在春季。(3)喜欢春季的人比喜欢冬季的人多多少人。15-11=4(人),答:喜欢春季的人比喜欢冬季的人多4人。(本小题答案不唯一)",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "\"提问题\"\"填条件\"问题",
+                                 "20以内数的比大小",
+                                 "不退位减法(20以内)"
+                             ],
+        "source":  "22-23二年级下·全国·随堂练习"
+    },
+    {
+        "id":  "399",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "某学校对三年级同学睡眠时间做了一次调查,情况如下(单位:小时):![](images/135153.png)人\n(2)睡眠时间在( )小时的人数最多,在( )小时的人数最少.\n(3)国家明确了小学生每天睡眠时间应达到10小时,有( )名学生达到国家规定。",
+        "options":  [
+
+                    ],
+        "answer":  "3;7;6;2;7~8;11~12;5",
+        "solution":  "【分析】(1)根据调查结果可知:不足7小时的有3人,7~8小时的有7人,9~10小时的有6人,11~12小时的有2人,依此填表。(2)直接将每个睡眠时间段的人数进行大小排序,然后再填空即可。(3)直接根据调查结果填空即可.\n\n【详解】(1)填表如下:不足7小时3人,7~8小时7人,9~10小时6人,11~12小时2人。(2)7人\u003e6人\u003e3人\u003e2人,即睡眠时间在7~8小时的人数最多,在11~12小时的人数最少。(3)根据调查结果可知,有5名学生达到国家规定。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "22-23 三年级下·广西梧州·期末"
+    },
+    {
+        "id":  "400",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "下面是二(1)班同学体育课上参加体育活动的情况。![](images/135158.png)\n(2)参加哪种体育活动的人数最多。参加哪种体育活动的人数最少。\n(3)这个班有4个同学缺勤,如果他们都来上体育课且参加踢毽子,此时参加哪两种体育活动的人数同样多。\n(4)你还能提出什么数学问题。",
+        "options":  [
+
+                    ],
+        "answer":  "8;6;12;10;4;踢球;踢毽子;跳远和踢毽子;参加跳远和跳绳的一共有多少人;8+6=14(人)",
+        "solution":  "【分析】(1)根据统计图中的数据,即可得出每种体育活动的运动人数,据此完成统计表。(2)比较参加各种活动的人数,即可得出结论。(3)把踢毽子人数加上4,得8人,与跳远人数相等,据此解答。(4)根据题干中获得的数学信息,结合学过的数学知识,提出问题并解答即可。本小题答案不唯一。例如:参加跳远和跳绳的一共有多少人。\n\n【详解】(1)2×4=8(人),所以参加跳远的人数有8人。2×3=6(人),所以参加跳绳的人数有6人。2×6=12(人),所以参加踢球的人数有12人。2×5=10(人),所以参加跑步的人数有10人。2×2=4(人),所以参加踢毽子的人数有4人。填表如下:跳远8人,跳绳6人,踢球12人,跑步10人,踢毽子4人。(2)12\u003e10\u003e8\u003e6\u003e4,所以参加踢球活动的人数最多;参加踢毽子活动的人数最少。(3)4+4=8(人),8=8,此时参加跳远和踢毽子活动的人数同样多。(4)参加跳远和跳绳的一共有多少人。8+6=14(人),答:参加跳远和跳绳的一共有14人。(本题答案不唯一)",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "统计图表的综合应用",
+                                 "20以内数的比大小",
+                                 "8加几的进位加法"
+                             ],
+        "source":  "22-23 二年级·全国·假期作业"
+    },
+    {
+        "id":  "401",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "为了了解学生的体质健康状况,要收集学生身高,体重等数据。学校收集这些数据常用的方法是( )。",
+        "options":  [
+                        "A. 调查",
+                        "B. 实验",
+                        "C. 测量"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】为了了解学生的体质健康状况,要收集学生身高,体重等数据,这些数据需要去测量,由此求解.\n【详解】为了了解学生的体质健康状况,要收集学生身高,体重等数据。学校收集这些数据常用的方法是测量。故答案为:C",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "2023六年级下·广东广州·专题练习"
+    },
+    {
+        "id":  "402",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "二(1)班投票评选\u0027书香少年\u0027,有4位候选人,下面是同学们的投票情况。![](images/142956.png)\n选举那天,王芳因病请假没能参加投票,如果她也投了票,那么( )。",
+        "options":  [
+                        "A. 龙龙有可能被评为\u0027书香少年\u0027",
+                        "B. 一定还是兰兰被评为\u0027书香少年\u0027",
+                        "C. 元元有可能被评为\u0027书香少年\u0027"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】先总结目前投票的结果,再去结合未参与投票的情况来判断结果.\n【详解】根据投票结果:龙龙11票,元元10票,兰兰15票,刚刚5票。A。如果王芳投票给了龙龙,那龙龙12票,也不可能被评为\u0027书香少年\u0027;B。不论王芳的票投给谁,票数都不可能超过兰兰,所以一定还是兰兰被评为\u0027书香少年\u0027;C。如果王芳投票给元元,元元11票,也不可能被评为\u0027书香少年\u0027。故答案为:B",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "22-23 二年级下·全国·单元测试"
+    },
+    {
+        "id":  "403",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "小明发现他有一大堆东西,\"ABCBABCBAB\"要整理。这个时候他用( )比较好。",
+        "options":  [
+                        "A. 自己的脑子记",
+                        "B. 写在小纸条上",
+                        "C. 表格"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】本题根据题意可以得知数据杂乱无章,要选择出分类整理的最好的方式。三种方法对比选取即可.\n【详解】A。自己的脑子记,此方式容易出错;B。写在纸条上,这个方法也可以,但是比较乱;C。用表格的方式,收集整理就比较清晰,不易出错,容易整理。故答案为:C",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "22-23 二年级下·全国·单元测试"
+    },
+    {
+        "id":  "404",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "要想了解不同年级同学课外阅读习惯,可以先( )。",
+        "options":  [
+                        "A. 组织采访活动",
+                        "B. 开一次交流会",
+                        "C. 设计调查表调查"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】要想知道\u0027不同年级同学课外阅读习惯\u0027,可以先设计调查表调查,收集数据,即把不同年级同学课外阅读习惯收集起来,再汇总统计结果,据此解答即可.\n【详解】要想了解不同年级同学课外阅读习惯,可以先设计调查表调查。故答案为:C",
+        "knowledge_points":  [
+                                 "设计简单的调查表"
+                             ],
+        "source":  "22-23二年级下·全国·单元测试"
+    },
+    {
+        "id":  "405",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "为了了解同学们每天参加体育活动的时间,可以选择调查表( )。![](images/143004.png)",
+        "options":  [
+                        "A",
+                        "B",
+                        "C",
+                        "D"
+                    ],
+        "answer":  "D",
+        "solution":  "【分析】判断各选项调查表调查的内容与题目要调查的内容是否一样,据此即可解答.\n【详解】A。此项调查表调查的是最喜欢的体育活动,与题意不符;B。此项调查表调查的是每天上体育课的节数,与题意不符;C。此项调查表调查的是除了学校的体育运动,在家是否运动,与题意不符;D。此项调查表调查的是每天参加体育活动的时间,与题意相符合。为了了解同学们每天参加体育活动的时间,可以选择调查表D。故答案为:D",
+        "knowledge_points":  [
+                                 "设计简单的调查表"
+                             ],
+        "source":  "22-23 四年级上·山东临沂·期末"
+    },
+    {
+        "id":  "406",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "下面是同学们最喜欢的课外书的调查情况统计表。班里要办一个图书角,应该多买( )。![](images/143009.png)",
+        "options":  [
+                        "A. 故事书",
+                        "B. 科技书",
+                        "C. 漫画书"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】根据统计表中的\u0027正\u0027统计出数据,再比较大小,选取比较多的课外书即可.\n【详解】10\u003c11\u003c12\u003c15,故事书本数\u003c漫画书本数\u003c连环画本数\u003c科技书本数,所以班里要办一个图书角,应该多买科技书。故答案为:B",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "20以内数的比大小"
+                             ],
+        "source":  "22-23二年级下·全国·单元测试"
+    },
+    {
+        "id":  "407",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "读下面的\u0027某商场售卖物品数量统计图\u0027,其中,一个格子代表3个东西。![](images/143015.png)卖出了( )支铅笔。",
+        "options":  [
+                        "A. 3",
+                        "B. 8",
+                        "C. 9"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】铅笔占了3个格子,一个格子代表3个东西,用3乘3即可求解.\n【详解】3×3=9(支),所以卖出了9支铅笔。故答案为:C",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "3的乘法口诀及应用"
+                             ],
+        "source":  "22-23二年级下·全国·单元测试"
+    },
+    {
+        "id":  "408",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "李明同学想帮助学校解决午饭浪费的问题,你认为他们最需要收集的信息是( )。",
+        "options":  [
+                        "A. 调查同学们吃午餐的地点",
+                        "B. 调查同学们喜欢吃的食物种类",
+                        "C. 调查同学们吃午餐用的时间"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】统计的是解决午饭浪费的问题,午饭浪费一般多是因为学生对某种食物不爱吃或者午饭打的太多吃不完,所以收集的应该是跟食物种类和学生午饭饭量有关联的信息,据此解答.\n【详解】A。同学们吃午餐的地点跟午餐浪费关系不大;B。同学们喜欢吃的食物种类跟午餐浪费关系非常密切;C。同学们吃午餐用的时间跟午餐浪费关系不太紧密。故答案为:B",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "22-23 二年级下·全国·单元测试"
+    },
+    {
+        "id":  "409",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "有10个人接受了市场调查访问:在过去一个月,去了超市多少次。调查结果是:3,4,2,2,2,3,1,5,3,4。下面哪个点子图正确表达了这个调查报告的数据。( )![](images/143021.png)",
+        "options":  [
+                        "A",
+                        "B",
+                        "C",
+                        "D"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】由题意可知,线段上的数字表示次数,黑点表示人数,去过1次的有1人,去过2次的有3人,去多3次的有3人,去过4次的有2人,去过5次的有1人,据此选择即可.\n【详解】由分析可知:C项能正确表达了这个调查报告的数据。故答案为:C",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "20-21 六年级下·浙江宁波·期末"
+    },
+    {
+        "id":  "410",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "下表是二年级学生最喜欢的图书的人数统计表。![](images/143026.png)\n最喜欢科技书的和最喜欢连环画的一共有( )人。",
+        "options":  [
+                        "A. 25",
+                        "B. 27",
+                        "C. 34",
+                        "D. 15"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】将喜欢科技书的和喜欢连环画的人数相加即可.\n【详解】16+18=34(人),最喜欢科技书的和最喜欢连环画的一共有34人。故答案为:C",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "两位数与两位数的进位加法"
+                             ],
+        "source":  "21-22 二年级下·福建漳州·期中"
+    },
+    {
+        "id":  "411",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "少年强则国强,体育强则中国强。仰卧起坐达标测试规定,1分钟做40个以上(含40个)为优秀,做21至39个为及格,做21个以下为不及格。你们小组同学1分钟仰卧起坐成绩统计如表,如果你的成绩排名第7,你可能做了( )个。![](images/225436.png)",
+        "options":  [
+                        "A. 27",
+                        "B. 38",
+                        "C. 39",
+                        "D. 43"
+                    ],
+        "answer":  "D",
+        "solution":  "【分析】根据题意可知,1分钟做40个以上(含40个)为优秀,小组内1分钟仰卧起坐成绩优秀的有9人,排名第7可能做了43个。据此解答.\n【详解】因为成绩优秀的有9人,排名第7,做的数量大于40个,所以可能做了43个。故答案为:D",
+        "knowledge_points":  [
+                                 "单式统计表的特点及填补",
+                                 "统计图表的综合应用"
+                             ],
+        "source":  "2022·湖北省直辖县级单位·小升初真题"
+    },
+    {
+        "id":  "412",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "小明发现他有一大堆东西,\"ABCBABCBAB\"要整理。这个时候他用( )比较好。",
+        "options":  [
+                        "A. 自己的脑子记",
+                        "B. 写在小纸条上",
+                        "C. 把它背下来记",
+                        "D. 表格"
+                    ],
+        "answer":  "D",
+        "solution":  "【分析】本题考查对信息整理方法的理解与选择。题目中\"ABCBABCBAB\"是一串较长且有一定规律但不易直接记忆的数据,如果仅依靠大脑记忆(A)或背诵(C),容易出错且效率较低;写在小纸条上(B)虽然可以记录,但不利于分类和整理信息,也不方便观察数据之间的关系。而表格(D)是一种常用的数据整理工具,可以将信息进行分类,统计和对比,使数据更加清晰,有条理,便于分析和使用。因此选择表格最为合适.\n【详解】对于\"ABCBABCBAB\"这类数据,如果使用表格,可以把不同字母分类记录,例如分别统计A,B,C出现的次数,或按顺序进行整理,这样不仅能避免遗漏,还能更直观地看出数据特点。相比之下,单纯依靠记忆或简单记录都不够高效。表格能够帮助我们系统地整理信息,提高准确性和效率,所以应选择用表格进行整理。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "21-22 二年级下·全国·单元测试"
+    },
+    {
+        "id":  "413",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "全班同学大部分喜欢1,少数同学喜欢2,那么你觉得班级的幸运数字应该是( )。",
+        "options":  [
+                        "A. 1",
+                        "B. 2",
+                        "C. 两个都要",
+                        "D. 不选"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】班级的幸运数字应该大部分同学喜欢的数字,据此解答.\n【详解】根据分析可知:全班同学大部分喜欢1,少数同学喜欢2,那么你觉得班级的幸运数字应该是1。故答案为:A",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "21-22二年级下·全国·单元测试"
+    },
+    {
+        "id":  "414",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "用\"正\"字统计5月份天气情况,一个\"正\"字代表( )天。",
+        "options":  [
+                        "A. 1",
+                        "B. 3",
+                        "C. 5"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】\"正\"有5笔,每一笔表示1个统计量,由此判断.\n【详解】用写\"正\"字的方法统计5月份的天气情况,一个\"正\"字代表5天。故答案为:C",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "18-19二年级下·湖南湘西·期中"
+    },
+    {
+        "id":  "415",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "要想知道全班同学最喜欢什么课外读物,应选择下面第( )种收集数据的方法。",
+        "options":  [
+                        "A. 到书店问问哪种课外读物最畅销",
+                        "B. 询问班里的个别同学最喜欢什么课外读物",
+                        "C. 请全班每位同学写下自己最喜欢的课外读物"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】由于每个人的爱好兴趣不同,每个同学的喜好也不一定相同,所以想知道全班同学最喜欢的课外读物,可以请全班每一个同学写下自己最喜欢的课外读物,这种方法收集数据更合理;据此解答.\n【详解】根据分析可知:要想知道全班同学最喜欢什么课外读物,可以请全班每位同学写下自己最喜欢的课外读物,这种方法收集数据更合理。故答案为:C.",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "21-22 二年级下·湖南岳阳·期中"
+    },
+    {
+        "id":  "416",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "学校要为各班添新书,如果想知道你们班的同学最喜欢哪类图书,选择( )方式收集数据最合适。",
+        "options":  [
+                        "A. 到书店问问哪类书卖得最好",
+                        "B. 问问班里的某一个同学",
+                        "C. 请每个同学写出自己最喜欢的一类图书"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】要知道班上同学最喜欢哪类图书,那么需要记录好班上每位同学最喜欢的图书类目;据此解答.\n【详解】根据分析:A。到书店问问哪类书卖得最好,只能知道买书的人喜欢哪类图书,而不是班上同学喜欢哪类图书;B。问问班里的某一个同学,不记录下来,会统计的不清晰;C。请每个同学写出自己最喜欢的一类图书,可以很清楚的记录好班上每位同学最喜欢的图书类目,从而进行购买;所以选择\"请每个同学写出自己最喜欢的一类图书\"方式收集数据最合适。故答案为:C",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "20-21二年级下·河南郑州·期末"
+    },
+    {
+        "id":  "417",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "填空题",
+        "difficulty":  0.94,
+        "question":  "晓晓用\"正\"统计四月份的天气情况,一个\"正\"代表( )天。",
+        "options":  [
+
+                    ],
+        "answer":  "5",
+        "solution":  "【分析】\"正\"字计数法:\"正\"字一笔表示数量1,一个\"正\"字表示数量5,据此进行解答即可.\n【详解】晓晓用\"正\"统计四月份的天气情况,一个\"正\"代表5天。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "22-23 二年级·全国·假期作业"
+    },
+    {
+        "id":  "418",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "下表是统计二(1)班同学的兴趣爱好。![](images/143037.png)\n(2)二(1)班喜欢( )的人最多,喜欢( )的人最少.\n(3)喜欢踢球的人比喜欢唱歌的少( )人.\n(4)二(1)班一共有( )人。",
+        "options":  [
+
+                    ],
+        "answer":  "15;16;20;11 唱歌;跳舞 4 62",
+        "solution":  "【分析】(1)根据正字统计法,正字的每一笔代表\"1\",喜欢打乒乓球的有15人,喜欢踢球的有16人,喜欢唱歌的有20人,喜欢跳舞的有11人,据此填写即可;(2)将喜欢各项目的人数进行比较大小,即可找出人数最多和最少的;(3)求喜欢踢球的比喜欢唱歌的少多少,根据减法的意义,列算式即可;(4)将喜欢各项目的人数相加即可.\n【详解】(1)把上面的统计结果填入下表中:打乒乓球15人,踢球16人,唱歌20人,跳舞11人。(2)20\u003e16\u003e15\u003e11,二(1)班喜欢唱歌的人最多,喜欢跳舞的人最少。(3)20-16=4(人),喜欢踢球的人比喜欢唱歌的少4人。(4)15+16+20+11=31+20+11=51+11=62(人),二(1)班一共有62人。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "100以内数的比大小",
+                                 "100以内数的连加运算"
+                             ],
+        "source":  "20-21 二年级下·广东广州·期末"
+    },
+    {
+        "id":  "419",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "下面是二年级同学最喜欢吃的蔬菜情况统计表。(每人只投一票)黄瓜土豆白菜豆角正正正正√√√√√√√√√√√√√√○○○○○○○○○○○○○○○○○○○○○○○○○○○○○○○![](images/143052.png)\n(2)喜欢吃( )的人数最多,喜欢吃( )的人数最少.\n(3)喜欢吃白菜的人数比喜欢吃豆角的多( )人。",
+        "options":  [
+
+                    ],
+        "answer":  "25;18;15;6 黄瓜;豆角 9",
+        "solution":  "【分析】根据统计表中的信息进行表达即可。(1)黄瓜是由正字来统计的,先数一数有多个正字,一个正字是5笔,要知道喜欢黄瓜一共有多少人,用一共有的正字数量乘5即可;土豆是用√来统计的,直接数数有多少个√即可;白菜是用⚪进行统计,直接数一数有多少个即可,豆角是△来进行统计的,直接数一数△有多少个即可。(2)根据黄瓜,土豆,白菜,豆角统计的数量进行比较即可。(3)根据求一个数比另一个数多多少,用减法计算.\n【详解】(1)黄瓜:5×5=25(人),土豆:18人,白菜:15人,豆角:6人。填表:黄瓜25人,土豆18人,白菜15人,豆角6人。(2)25\u003e18\u003e15\u003e6,所以喜欢吃黄瓜的人数最多,喜欢吃豆角的人数最少。(3)15-6=9(人),所以喜欢吃白菜的人数比喜欢吃豆角的多9人。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "21-22二年级下·广东江门·期末"
+    },
+    {
+        "id":  "420",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "六(1)班学生的视力检测结果,记录如下。![](images/143103.png)\n(2)六(1)班一共有( )人.\n(3)5.0及以上为视力正常,视力正常的有( )人,视力不正常的有( )人。我想对六(1)班的同学说:\"( )\"。",
+        "options":  [
+
+                    ],
+        "answer":  "33;8;4 45 33;12;要保护好自己的眼睛,注意用眼习惯。",
+        "solution":  "【分析】(1)根据记录的数据填表即可;(2)将三种人数相加就是总人数;(3)视力正常的为33人,不正常的将表中另外两项的人数相加即可。根据统计表写出自己的合理意见即可.\n【详解】(1)据分析表格填写如下:5.0及以上33人,4.9-4.5有8人,4.5以下有4人。(2)33+8+4=41+4=45(人),六(1)班一共有45人。(3)8+4=12(人),5.0及以上为视力正常,视力正常的有33人,视力不正常的有12人。我想对六(1)班的同学说:\"要保护好自己的眼睛,注意用眼习惯\"。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "100以内数的连加运算"
+                             ],
+        "source":  "21-22 二年级下·广东佛山·期末"
+    },
+    {
+        "id":  "421",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "整理全班一周阅读课外读物的册数.\n(1)把记录的结果填在表中。![](images/143109.png)\n(2)全班共读了( )册课外读物.\n(3)同学们最喜欢看的课外读物是( ).\n(4)读连环画的册数比故事大王多( )册。",
+        "options":  [
+
+                    ],
+        "answer":  "15;18;12 45 连环画 6",
+        "solution":  "【分析】(1)根据正字统计图中的信息,填写表格即可;(2)把三种类别的书的数量相加,即可求出全班共读了多少册课外读物;(3)将三种数量进行比较,找到最多的即可;(4)求一个数比另一个数多多少,根据减法的意义,列算式即可.\n【详解】(1)记录的结果填写如下:少儿文艺15册,连环画18册,故事大王12册。(2)15+18+12=33+12=45(册),全班共读了45册课外读物。(3)根据18\u003e15\u003e12可知,同学们最喜欢看的课外读物是连环画。(4)18-12=6(册),读连环画的册数比故事大王多6册。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "20以内数的比大小",
+                                 "100以内数的连加运算"
+                             ],
+        "source":  "19-20二年级下·广东广州·期末"
+    },
+    {
+        "id":  "422",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "下面记录的是二(1)班所有同学最喜欢看的图书情况。![](images/143114.png)\n(2)二(1)班共有( )人.\n(3)最喜欢( )类图书的人最多,最喜欢文学类的人数比最喜欢漫画类的人数少( )人。",
+        "options":  [
+
+                    ],
+        "answer":  "20;4;13;6 43 童话;7",
+        "solution":  "【分析】(1)根据正字统计法,每个\"正\"字的一笔代表1人,据此填表;(2)把喜欢各类图书的人数相加即可;(3)将喜欢各类图书的人数进行比较大小,即可找到喜欢哪类的人最多,求一个数比另一个数少多少用减法计算.\n【详解】(1)根据上面调查结果完成下面的统计表:童话类20人,科普类4人,漫画类13人,文学类6人。(2)20+4+13+6=24+13+6=37+6=43(人),二(1)班共有43人。(3)20\u003e13\u003e6\u003e4;13-6=7(人),最喜欢童话类图书的人最多,最喜欢文学类的人数比最喜欢漫画类的人数少7人。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "20以内数的比大小",
+                                 "100以内数的连加运算"
+                             ],
+        "source":  "21-22二年级下·广东广州·期末"
+    },
+    {
+        "id":  "423",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "二(1)班投票选举班长(每人只能投一票),有三位候选人,他们的得票数如图:![](images/143121.png)\n(2)一共有( )人参加投票.\n(3)如果只选一人为班长,当选的是( )\n(4)选举那天,王萍因病请假没能参加投票,如果她也投了票,结果( )改变。(填\"会\"或\"不会\")",
+        "options":  [
+
+                    ],
+        "answer":  "13;10;19 42 黄菲 不会",
+        "solution":  "【分析】(1)根据正字统计图中的信息,填写表格即可;(2)把三人的得票数相加,即可求出一共有多少人参加投票;(3)比较四人得票情况,根据得票最多的是黄菲,可知黄菲当选班长;(4)根据四人得票情况可知,黄菲与第二名徐平相差19-13=6(票),所以即使王萍投票,也不会改变选举结果.\n【详解】(1)根据统计的结果填表:徐平13票,张丽10票,黄菲19票。(2)13+10+19=23+19=42(人),一共有42人参加投票。(3)根据分析可知,如果只选一人为班长,当选的是黄菲。(4)根据分析可知,选举那天,王萍因病请假没能参加投票,如果她也投了票,结果不会改变。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "100以内数的连加运算"
+                             ],
+        "source":  "19-20 二年级下·广东广州·期末"
+    },
+    {
+        "id":  "424",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "统计数据的时候,可以用举手,画\"( )\"字和画圆圈等方法。",
+        "options":  [
+
+                    ],
+        "answer":  "正",
+        "solution":  "【详解】统计数据的时候,可以用举手,画\"正\"字和画圆圈等方法。举手一人表示1票,画圆圈等方法,一个图形表示1票,\"正\"字计数法,一笔表示1票,一个\"正\"表示5票。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "22-23二年级下·全国·课前预习"
+    },
+    {
+        "id":  "425",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "读表并回答问题。![](images/143135.png)\n(1)全班共有( )人.\n(2)最喜欢( )色的人数最多.\n(3)如果这个班订做校服,选择( )色合适。",
+        "options":  [
+
+                    ],
+        "answer":  "38 蓝 蓝",
+        "solution":  "【分析】根据题意,喜欢红色的有9人,喜欢黄色的有6人,喜欢蓝色的有15人,喜欢白色的有8人,人数相加就是全班的人数;根据大小比较15\u003e9\u003e8\u003e6可以找出喜欢什么颜色的人数最多;喜欢哪种颜色人数最多就订做哪种颜色即可.\n【详解】(1)9+6+15+8=15+15+8=30+8=38(人),全班共有38人。(2)根据分析可知,最喜欢蓝色的人数最多。(3)因为喜欢蓝色的人数最多,如果这个班订做校服,选择蓝色合适。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "20以内数的比大小",
+                                 "100以内数的连加运算"
+                             ],
+        "source":  "22-23二年级下·全国·课前预习"
+    },
+    {
+        "id":  "426",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "下面是三(1)班同学最喜欢的运动项目情况。(每人只选一种![](images/143140.png)\n(2)喜欢( )运动项目的人最多,喜欢( )运动项目的人最少,这个班一共有( )人。",
+        "options":  [
+
+                    ],
+        "answer":  "7;7;9;4;3 篮球;跳高;30",
+        "solution":  "【分析】(1)根据给出的信息,统计出相应的数据,并填入统计表中即可;(2)比较统计表的数据,喜欢运动项目人数最多的是篮球;喜欢运动项目人数最少的是跳高,最后把统计表中的数据相加,即可求出这个班的总人数,据此解答.\n【详解】(1)如图所示:游泳7人,足球7人,篮球9人,长跑4人,跳高3人。(2)3人\u003c4人\u003c7人=7人\u003c9人,7+7+9+4+3=14+9+4+3=23+4+3=27+3=30(人),喜欢篮球运动项目的人最多,喜欢跳高运动项目的人最少,这个班一共有30人。",
+        "knowledge_points":  [
+                                 "单式统计表的特点及填补"
+                             ],
+        "source":  "21-22三年级下·广东茂名·期末"
+    },
+    {
+        "id":  "427",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "请你根据表中的数据填空。![](images/143146.png)\n(1)参加课外兴趣小组的一共有( )人.\n(2)参加( )组的人数最多,参加( )组的人数最少.\n(3)选择篮球组的人数比选择舞蹈组的人数多( )人.\n(4)选择绘画组和书法组的共有( )人。",
+        "options":  [
+
+                    ],
+        "answer":  "69;羽毛球;围棋;5;23",
+        "solution":  "[analysis](1)把各个兴趣小组的人数加起来,求出和,即可解决此题。(2)比较一下各个兴趣小组的人数的大小,找出参加人数最多和参加人数最少的兴趣小组即可。(3)求一个数比另一个数多多少,用减法计算。(4)求两个数的和是多少,用加法计算.\n【详解】(1)12+8+13+7+18+11=20+13+7+18+11=33+7+18+11=40+18+11=58+11=69(人),故参加课外兴趣小组的一共有69人。(2)18\u003e13\u003e12\u003e11\u003e8\u003e7,故参加羽毛球组的人数最多,参加围棋组的人数最少。(3)13-8=5(人),故选择篮球组的人数比选择舞蹈组的人数多5人。(4)11+12=23(人),故选择绘画组和书法组的共有23人。",
+        "knowledge_points":  [
+                                 "单式统计表的特点及填补"
+                             ],
+        "source":  "21-22二年级下·河北廊坊·期中"
+    },
+    {
+        "id":  "428",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "![](images/143151.png)\n从统计表中可看出,槐树棵数一定最少。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】由统计表可知:柳树,杨树,槐树和其他的棵树,其他表示除了柳树,杨树,槐树以外的树种,所以并不能说明槐树最少;据此解答即可.\n【详解】由分析可知:除了柳树,杨树,槐树,还有其他的树种,其他中的某一种数的棵树可能小于10棵,所以槐树不一定最少。故答案为: ×",
+        "knowledge_points":  [
+                                 "统计图表的综合应用"
+                             ],
+        "source":  "22-23 三年级下·全国·单元测试"
+    },
+    {
+        "id":  "429",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "下面是某班级同学在体质监测仰卧起坐项目中的记录。![](images/143204.png)\n(2)最多的一个同学做了( )个,最少的一个同学做了( )个,他们做的仰卧起坐个数相差( )个.\n(3)做仰卧起坐的个数在( )-( )范围内的人数最多。",
+        "options":  [
+
+                    ],
+        "answer":  "2;11;9;4;26 55;23;32 30;39",
+        "solution":  "【分析】(1)20-29个的有:23个,26个;30-39个的有:33个,36个,32个,38个,34个,37个,32个,34个,37个,38个,37个;40-49个的有:45个,43个,44个,41个,47个,40个,48个,40个,46个;50-59个的有:52个,54个,50个,55个。依此填空即可。(2)直接比较20-29个,50-59个之间仰卧起坐个数的大小即可,然后用最多的个数减最少的个数即可。(3)将做每个仰卧起坐个数的范围的人数,进行大小排序即可填空.\n【详解】(1)根据分析,填空如下:20-29有2人,30-39有11人,40-49有9人,50-59有4人,合计26人。(2)23个\u003c26个\u003c50个\u003c52个\u003c54个\u003c55个,55-23=32(个),即最多的一个同学做了55个,最少的一个同学做了23个,他们做的仰卧起坐个数相差32个。(3)11\u003e9\u003e4\u003e2,即做仰卧起坐的个数在30-39范围内的人数最多。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "21-22 四年级上·广东东莞·期末"
+    },
+    {
+        "id":  "430",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "在创建\"书香校园\"活动中,二(1)班对班级图书角的图书进行了统计,结果如下:![](images/143209.png)\n(2)( )书最多,( )书最少.\n(3)绘本书比历史书多( )本;百科书比童话书少( )本。",
+        "options":  [
+
+                    ],
+        "answer":  "24;10;27;16 童话;百科 8;17",
+        "solution":  "【分析】(1)一笔表示1个人,所以一个\"正\"字表示5个人,据此数清楚各种书本的数量,填入表格即可。(2)将各种书本的数量进行比较,即可得出答案。(3)根据减法的意义,列式解答即可.\n【详解】(1)填表如下:绘本24本,百科10本,童话27本,历史16本。(2)27\u003e24\u003e16\u003e10,所以童话书最多,百科书最少。(3)24-16=8(本),所以绘本书比历史书多8本。27-10=17(本),所以百科书比童话书少17本。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "单式统计表的特点及填补",
+                                 "100以内数的比大小",
+                                 "两位数与两位数的退位减法"
+                             ],
+        "source":  "21-22二年级下·山东济宁·期末"
+    },
+    {
+        "id":  "431",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "下面是小军整理的二(1)班同学喜欢课外兴趣活动的人数情况书![](images/143216.png)\n(2)二(1)班同学最喜欢的课外兴趣活动是( ).\n(3)二(1)班共有( )名同学。",
+        "options":  [
+
+                    ],
+        "answer":  "7;10;11;12 体育 40",
+        "solution":  "【分析】(1)根据统计数据,填入统计表即可;(2)根据统计表中的数据大小,即可得出二(1)班同学最喜欢的课外兴趣活动;(3)将统计表中数据相加,即可得出一共有多少人.\n【详解】(1)二(1)班同学喜欢课外兴趣活动的人数情况表:书法7人,科技10人,艺术11人,体育12人。(2)12\u003e11\u003e10\u003e7,所以二(1)班同学最喜欢的课外兴趣活动是体育。(3)7+10+11+12=40(名),所以二年(1)班一共有40名同学。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "21-22二年级下·四川自贡·期末"
+    },
+    {
+        "id":  "432",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "一(1)班同学参加课后服务兴趣小组统计情况书法组:正正 足球组:正正正 经典诵读组:正\n(1)把统计结果填在下表中。![](images/143222.png)\n(2)( )组的人数最多,( )组的人数最少.\n(3)书法组比足球组少( )人,比经典诵读组多( )人.\n(4)一(1)班同学参加课后服务兴趣小组一共有( )人。",
+        "options":  [
+
+                    ],
+        "answer":  "9;11;15;4 足球;经典诵读 6;5 39",
+        "solution":  "【分析】(1)根据各组用\"正\"字统计的情况填表。(2)从统计表中比较出人数最多的组和人数最少的组。(3)先用足球组的人数减去书法组的人数,求出书法组比足球组少几人;再用书法组的人数减去经典诵读组的人数,求出书法组比经典诵读组多几人。(4)将4个课后服务兴趣小组的人数相加即可.\n【详解】(1)填表如下:书法组9人,绘画组11人,足球组15人,经典诵读组4人。(2)15\u003e11\u003e9\u003e4,所以足球组的人数最多,经典诵读组的人数最少。(3)15-9=6(人),9-4=5(人),所以书法组比足球组少6人,比经典诵读组多5人。(4)9+11+15+4=39(人),所以一(1)班同学参加课后服务兴趣小组一共有39人。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "20以内数的比大小",
+                                 "100以内数的连加运算"
+                             ],
+        "source":  "21-22 二年级下·贵州铜仁·期末"
+    },
+    {
+        "id":  "433",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "二(1)班同学\"我最喜欢的视频节目\"调查情况统计表。![](images/143228.png)\n(1)最喜欢看( )的人数最多,最喜欢看( )的人数最少.\n(2)最喜欢看\"纪录片\"的再多( )人,就和最喜欢看\"动画片\"的人数同样多.\n(3)如果这个班男生28人,那么女生有( )人.\n(4)新转来一位同学,这位同学最有可能喜欢( )视频节目。",
+        "options":  [
+
+                    ],
+        "answer":  "动画片;新闻报道 6 24 动画片",
+        "solution":  "【分析】(1)观察统计表中\"正\"字的笔画数即可完成作答;(2)用喜欢看动画片的人数减去喜欢看纪录片的人数即可解答;(3)先计算出全班总人数,用全班人数的总人数减去男生人数即可;(4)根据同学们最喜欢看的电视节目是动画片作答.\n【详解】(1)相声小品:9人,纪录片15人,动画片:21人,新闻报道7人,21\u003e15\u003e9\u003e7,最喜欢看动画片的人数最多,最喜欢看新闻报道的人数最少。(2)21-15=6(人),最喜欢看\"纪录片\"的再多6人,就和最喜欢看\"动画片\"的人数同样多。(3)9+15+21+7=52(人),52-28=24(人),如果这个班男生28人,那么女生有24人。(4)因为最喜欢看动画片的人数最多,所以新转来一位同学,这位同学最有可能喜欢动画片视频节目。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "两位数与两位数的退位减法",
+                                 "100以内数的连加运算"
+                             ],
+        "source":  "21-22 二年级下·湖北随州·期末"
+    },
+    {
+        "id":  "434",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "下面是小东调查本班同学最喜欢吃的水果的情况。![](images/143234.png)\n(2)全班最喜欢吃( )的同学最多.\n(3)最喜欢吃香蕉的比最喜欢吃苹果的多( )人。",
+        "options":  [
+
+                    ],
+        "answer":  "5;10;12;7 西瓜 3",
+        "solution":  "【分析】(1)一个正字表示5,其他图形一个表示1,由此数出完成统计表;(2)比较统计表中数据,即可得出全班最喜欢吃哪种水果的同学最多。(3)用最喜欢吃香蕉的人数减去最喜欢吃苹果的人数即可.\n【详解】(1)填表:桃5人,香蕉10人,西瓜12人,苹果7人。(2)12\u003e10\u003e7\u003e5,全班最喜欢吃西瓜的同学最多。(3)10-7=3(人),最喜欢吃香蕉的比最喜欢吃苹果的多3人。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "单式统计表的特点及填补"
+                             ],
+        "source":  "20-21 二年级下·江西赣州·期末"
+    },
+    {
+        "id":  "435",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "三年级同学在二月到六月份做好事的件数如下:![](images/143241.png)\n(2)( )月份做的好事最多,( )月份做的好事最少.\n(3)三月份比五月份多做好事( )件.\n(4)二到六月份一共做好事( )件。",
+        "options":  [
+
+                    ],
+        "answer":  "20;40;30;25;35;150 三;二 15 150",
+        "solution":  "【分析】(1)把三年级同学各个月做好事的件数相加求和,并完成统计表如下;(2)比较统计表中数据可知,三月份做的好事最多,二月份做的好事最少。(3)观察统计表可知,三月份比五月份多做好事(40-25)件。(4)根据统计表可知,二到六月份一共做好事150件.\n【详解】(1)20+40+30+25+35=150(件),完成统计表如下:二月20件,三月40件,四月30件,五月25件,六月35件,合计150件。(2)40\u003e35\u003e30\u003e25,所以,三月份做的好事最多,二月份做的好事最少。(3)40-25=15(件),所以,三月份比五月份多做好事15件。(4)根据统计表可知,二到六月份一共做好事150件。",
+        "knowledge_points":  [
+                                 "单式统计表的特点及填补"
+                             ],
+        "source":  "21-22 三年级下·湖北黄冈·期末"
+    },
+    {
+        "id":  "436",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "如图是二(1)班学生平均每天睡眠时间的调查情况。![](images/143249.png)\n(2)二(1)班一共有学生( )人。",
+        "options":  [
+
+                    ],
+        "answer":  "26;8;3 37",
+        "solution":  "【分析】(1)根据记录的情况,分别数出各个睡眠时间段的人数,填表即可;(2)将表中数据相加即可.\n【详解】(1)填表如下:10小时26人,9小时8人,8小时3人。(2)26+8+3=37(人),所以二(1)班一共有学生37人。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "21-22二年级下·广东江门·期末"
+    },
+    {
+        "id":  "437",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "几位同学统计了学校图书室星期二借阅的各种图书的数量.\n(1)请你把统计结果填在下表中,再回答问题。![](images/143255.png)\n(2)( )的借阅量最多,( )的借阅最少,借阅数量最多的书和最少的书相差( )本.\n(3)漫画书的借阅量比童话书多( )本,连环画的借阅量比童话书少( )本,星期二的借阅量一共有( )本。",
+        "options":  [
+
+                    ],
+        "answer":  "5;34;13;9 漫画;连环画;29 21;8;61",
+        "solution":  "【分析】(1)数一数每种情况的数量并填空;(2)将数据作比较,然后用最多的书减去最少的书;(3)用漫画书的借阅量减去童话书的借阅量;用童话书的借阅量减去连环画的借阅量;最后把各种书的借阅量相加即可.\n【详解】(1)填表:连环画5本,漫画34本,童话13本,故事书9本。(2)5\u003c9\u003c13\u003c34,34-5=29(本),漫画的借阅量最多,连环画的借阅最少,借阅数量最多的书和最少的书相差29本。(3)34-13=21(本),13-5=8(本),5+34+13+9=61(本),漫画书的借阅量比童话书多21本,连环画的借阅量比童话书少8本,星期二的借阅量一共有61本。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "100以内数的比大小",
+                                 "一位数与两位数的退位减法",
+                                 "100以内数的连加运算"
+                             ],
+        "source":  "21-22 二年级下·山东临沂·期末"
+    },
+    {
+        "id":  "438",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "下面是二(1)班同学最喜欢的课外活动情况。![](images/143306.png)\n(2)最喜欢( )的人数最多,最喜欢( )的人数最少,相差( )人.\n(3)一共调查了( )人。",
+        "options":  [
+
+                    ],
+        "answer":  "12;8;11;10 跳绳;羽毛球;4 41",
+        "solution":  "【分析】(1)根据二(1)班同学最喜欢的课外活动情况统计表,一个√代表1个人,一个○代表1个人,一个△代表1个人,正字的一个笔画代表1个人,一个正字代表5个人,数出每个种类的人数在填表即可。(2)比较每个种类的人数,再用人数最多的减去人数最少的即可。(3)把各个种类的人数相加在一起即可.\n【详解】(1)如表:跳绳12人,羽毛球8人,乒乓球11人,其他10人。(2)12\u003e11\u003e10\u003e8,12-8=4(人),所以最喜欢跳绳的人数最多,最喜欢羽毛球的人数最少,相差4人。(3)12+8+11+10=20+21=41(人),所以一共调查了41人。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "21-22二年级下·湖北孝感·期末"
+    },
+    {
+        "id":  "439",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "小兰班上的同学每月看课外书情况统计如下:![](images/143315.png)\n(1)每月看5本书或5本以上课外书的有( )人,每月几乎没有看书的有( )人.\n(2)每月看课外书( )的人数最多。这个班一共有( )人。",
+        "options":  [
+
+                    ],
+        "answer":  "7;2 3-4本;36",
+        "solution":  "【分析】数一数每种情况的人数,然后将这些数作比较,并将它们加起来即可求解.\n【详解】(1)每月看5本书或5本以上课外书的有7人,每月几乎没有看书的有2人。(2)看5本或5本以上的有7人,3-4本的有18人,1-2本的有9人,几乎没看的有2人。2\u003c7\u003c9\u003c18,2+7+9+18=36(人),每月看课外书3-4本的人数最多。这个班一共有36人。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "20以内数的比大小",
+                                 "100以内数的连加运算"
+                             ],
+        "source":  "21-22 二年级下·内蒙古通辽·期末"
+    },
+    {
+        "id":  "440",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "如表是二(1)班同学竞选班长的投票情况。![](images/143319.png)\n(2)根据统计表回答问题。①( )的票数最多,( )的票数最少,( )可能成为班长。②张明比李平多得( )票,林丽比张明少得( )票。③二(1)班有( )人参加投票。",
+        "options":  [
+
+                    ],
+        "answer":  "13;21;17 张明;李平;张明;8;4;51",
+        "solution":  "【分析】(1)根据\"正\"字查出一共有多少画,就是有多少票,据此填表即可;(2)①比较票数的多少,再填空;票数的多的可能成为班长。②用张明的票数减去李平的票数;张明的票数减去林莉的票数;③把三人一共的得票数加起来即可.\n【详解】(1)填表:李平13票,张明21票,林丽17票。(2)①21\u003e17\u003e13,所以张明的票数最多,李平的票数最少,张明可能成为班长。②21-13=8(票),21-17=4(票),所以张明比李平多得8票,林丽比张明少得4票。③13+21+17=34+17=51(人),所以二(1)班有51人参加投票。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "21-22二年级下·福建漳州·期末"
+    },
+    {
+        "id":  "441",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "下面是龙江小学二(1)班同学最喜欢吃的水果情况(每人只选一种)。![](images/143324.png)\n(2)最喜欢吃( )的人数最多,最喜欢吃( )的人数最少.\n(3)如果全班同学都参加了调查,那么二(1)班一共有( )人.\n(4)如果你去为班级买水果,根据调查情况应多买( )。",
+        "options":  [
+
+                    ],
+        "answer":  "21;9;5;8 苹果;梨 43 苹果",
+        "solution":  "【分析】(1)一个正字代表5,再根据统计表中的信息,分别数出后完成统计表。(2)比较喜欢各种水果的人数,完成填空。(3)求喜欢各种水果的人数之和即可。(4)根据喜欢各种水果的情况写出自己的见解.\n【详解】(1)填表:苹果21人,桃9人,梨5人,香蕉8人。(2)21\u003e9\u003e8\u003e5,最喜欢吃苹果的人数最多,最喜欢吃梨的人数最少。(3)21+9+5+8=43(人),二(1)班一共有43人。(4)如果你去为班级买水果,根据调查情况应多买苹果。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "单式统计表的特点及填补"
+                             ],
+        "source":  "21-22二年级下·浙江温州·期末"
+    },
+    {
+        "id":  "442",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "小红和小明竞选班长,小红得票记录单上写着6个\"正\"字,她得了( )票,小明得到12票,用\"正\"字表示为( )。",
+        "options":  [
+
+                    ],
+        "answer":  "30;正正",
+        "solution":  "【分析】一个\"正\"字是5票,6个\"正\"字,用乘法计算即可;按照票数写出\"正\"字即可.\n【详解】5×6=30(票),所以小红得了30票;小明得到12票,用\"正\"字表示为正正。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "20-21 二年级下·湖北十堰·期末"
+    },
+    {
+        "id":  "443",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "下面记录的是二(1)班所有同学最喜欢看的图书情况。![](images/143339.png)\n(1)二(1)班喜欢( )的人最多,喜欢( )的人最少.\n(2)二(1)班一共有( )人.\n(3)最喜欢文学类的人数比最喜欢漫画类的人数少( )人。",
+        "options":  [
+
+                    ],
+        "answer":  "童话类;文学类 62 4",
+        "solution":  "【分析】(1)一个\"正\"表示5人,通过观察统计表可知,喜欢童话类的人数最多,喜欢文学类的人数最少;(2)根据加法的意义,把喜欢各种书的人数合并起来就是全班人数;(3)根据减法的意义,用最喜欢漫画类的人数减最喜欢文学类的人数即可解答.\n【详解】(1)最喜欢童话类的人数:20人,最喜欢科普类的人数:16人,最喜欢漫画类的人数:15人,最喜欢文学类的人数:11人,二(1)班喜欢童话类的人数最多,喜欢文学类的人数最少。(2)20+16+15+11=36+15+11=51+11=62(人),二(1)班一共有62人。(3)15-11=4(人),最喜欢文学类的人数比最喜欢漫画类的人数少4人。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "21-22 二年级下·山东菏泽·期末"
+    },
+    {
+        "id":  "444",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "如表是二(1)班同学未来想要从事职业的情况统计表。(每人只选一种)![](images/143346.png)\n(1)二(1)班想当( )的同学最多,想当( )的同学最少,相差( )人.\n(2)二(1)班一共有( )人,如果这个班男生有28人,那么女生有( )人。",
+        "options":  [
+
+                    ],
+        "answer":  "科学家;飞行员;15 51;23",
+        "solution":  "【分析】(1)一个\"正\"字表示5人,每一笔表示1人,据此解答。(2)用加法求出总人数,用总人数减去男生人数就是女生人数.\n【详解】(1)由题可知21\u003e15\u003e9\u003e6,所以二(1)班想当科学家的同学有21人最多,想当飞行员的同学有6人最少,21-6=15(人),所以相差15人。(2)5+9+21+6+10=14+21+6+10=35+6+10=41+10=51(人),51-28=23(人)。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "21-22 二年级下·陕西咸阳·期末"
+    },
+    {
+        "id":  "445",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "表中说明了蟋蟀鸣叫的次数与室外的温度相关。例如:当室外温度是24℃时,一只蟋蟀就鸣叫144次,如果这种关系不变,当室外温![](images/143349.png)",
+        "options":  [
+
+                    ],
+        "answer":  "186",
+        "solution":  "【分析】观察表中数据可知,温度每增加1℃,鸣叫次数增加7次。据此解题.\n【详解】144+(30-24)×7=144+6×7=144+42=186(次),所以,蟋蟀每分钟鸣叫186次。",
+        "knowledge_points":  [
+                                 "数表中的规律",
+                                 "单式统计表的特点及填补"
+                             ],
+        "source":  "20-21 六年级下·浙江宁波·期末"
+    },
+    {
+        "id":  "446",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "二(2)班3名同学进行投篮比赛,每人投20个。下面是3名同学投中个数统计的结果。![](images/143353.png)\n(2)( )投中的个数最多,( )投中的个数最少.\n(3)如果每人再接着投5个球,( )最有可能获得第一名。",
+        "options":  [
+
+                    ],
+        "answer":  "13;18;12 小强;小兵 小强",
+        "solution":  "【分析】根据记录的情况分别数出小明,小强和小兵的个数,填表即可;(1)比较表中各数据的大小即可;(2)如果每人再投5个球,小明最多投中18个,小强只需再投中一个就能保持第一名,所以最有可能获得第一名的是小强.\n【详解】(1)填表:小明13个,小强18个,小兵12个。(2)18\u003e13\u003e12,小强投中的个数最多,小兵投中的个数最少。(3)如果每人再接着投5个球,小强最有可能获得第一名。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "单式统计表的特点及填补"
+                             ],
+        "source":  "21-22 二年级下·湖南常德·期末"
+    },
+    {
+        "id":  "447",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "下面是二(1)班同学最喜欢的体育项目情况记录。![](images/143357.png)(1)![](images/143400.png)\n(2)喜欢( )项目的人数最多,喜欢( )项目的人数最少.\n(3)从图中可以看出,一共调查了( )人.\n(4)如果班上想开展一项活动,根据这次调查,我认为最好开展( )项目。",
+        "options":  [
+
+                    ],
+        "answer":  "8;10;7;15 跑步;游泳 40 跑步",
+        "solution":  "【分析】根据情况记录表中数据,直接填表即可;(1)比较表中各数据的多少,即可得出喜欢哪种项目的人数最多,喜欢哪种项目的人数最少;(2)将人数相加即可求出总人数;(3)根据表中数据最多的项目人数,即可解题.\n【详解】(1)填表:跳绳8人,乒乓球10人,游泳7人,跑步15人。(2)7\u003c8\u003c10\u003c15,喜欢跑步项目的人数最多,喜欢游泳项目的人数最少。(3)8+10+7+15=40(人),一共调查了40人。(4)如果班上想开展一项活动,根据这次调查,我认为最好开展跑步项目。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "20-21 二年级下·福建南平·期末"
+    },
+    {
+        "id":  "448",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "二(2)班举行朗读比赛,参赛同学的票数如下。![](images/143409.png)\n(2)根据统计结果,我们可以知道,这次班级朗读比赛的第一名是( ),得票数最少的是( ).\n(3)四位参赛同学也参与投票,如果每人只投一票,二(2)班共有( )人。",
+        "options":  [
+
+                    ],
+        "answer":  "15;7;11;9 王子;刘笑 42",
+        "solution":  "【分析】(1)根据统计的数据完成统计表。(2)根据统计结果,我们可以知道,这次班级朗读比赛的第一名是王子,得票数最少的是刘笑。(3)把统计表中的数据合起来即可.\n【详解】(1)填表:王子15票,刘笑7票,李强11票,严丹丹9票。(2)根据统计结果,我们可以知道,这次班级朗读比赛的第一名是王子,得票数最少的是刘笑。(3)15+7+11+9=42(人),二(2)班共有42人。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "21-22二年级下·湖南岳阳·期末"
+    },
+    {
+        "id":  "449",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "下面是二(1)班竞选班长投票记录情况,每人只投一票。![](images/143414.png)\n(2)( )票数最多,( )票数最少,张亮比李明多( )票.\n(3)一共有( )人投票,根据统计结果,( )应该当选班长。",
+        "options":  [
+
+                    ],
+        "answer":  "12;8;20;王小菲;李明;4;40;王小菲",
+        "solution":  "【分析】(1)分别计数各种计票方式的结果即可;(2)根据计票结果,分析比较数据;(3)把握关键:每人只投一票。所以三个数据没有重复,相加即可;根据票数最多的当选,即可解答.\n【详解】(1)填表:张亮12票,李明8票,王小菲20票。(2)20\u003e12\u003e8,12-8=4(票),王小菲票数最多,李明票数最少,张亮比李明多4票。(3)20+12+8=40(票),一共有40人投票,根据统计结果,王小菲应该当选班长。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "21-22二年级下·湖南怀化·期末"
+    },
+    {
+        "id":  "450",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "二年级要举办联欢会。下面是调查的全班同学喜欢吃的水果情况。(每人只能选一类)![](images/143419.png)\n(1)喜欢吃( )的人数最多,喜欢吃( )的人数最少.\n(2)如果你去买水果,你会根据调查情况多买( ).\n(3)二年级共有( )人。",
+        "options":  [
+
+                    ],
+        "answer":  "苹果;桃;苹果;38",
+        "solution":  "【分析】(1)根据人数比较大小即可;(2)多买喜欢吃的人数最多的水果;(3)把所有的人数相加即可.\n【详解】(1)14\u003e10\u003e8\u003e6,所以喜欢吃苹果的人数最多,喜欢吃桃的人数最少;(2)根据(1)可知喜欢吃苹果的人数最多,所以多买苹果;(3)14+8+6+10=22+6+10=28+10=38(人)。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "20-21二年级下·海南省直辖县级单位·期中"
+    },
+    {
+        "id":  "451",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "下面是某小学三(1)班同学生日情况统计表。![](images/143426.png)\n(2)大月生日的有( )人,小月生日的有( )人.\n(3)第( )季度过生日的人最少,第( )季度过生日的人最多;第四季度比第二季度过生日的同学多( )人。",
+        "options":  [
+
+                    ],
+        "answer":  "7;18;10;20 35;16 一;四;2",
+        "solution":  "【分析】(1)分别求出各个季度过生日的人数,在把表格填充完整的即可。(2)根据题意,大月是指一个月有31天的月份;小月是指一个月有30天的月份;一年有31天的月份有:一月份,三月份,五月份,七月份,八月份,十月份,十二月份,共7个月份;所以,一年有7个大月;一年有30天的月份有:四月份,六月份,九月份,十一月份,共4个月份;所以,年有4个小月,据此用加法分别求出大月过生日的人数和小月过生日的人数。(3)把各个季度过生日的人数进行比较,即可解题.\n【详解】(1)1+4+2=7(人),6+9+3=18(人),5+3+2=10(人),8+5+7=20(人),把下表补充完整,如下:第一季度7人,第二季度18人,第三季度10人,第四季度20人。(2)1+2+9+5+3+8+7=35(人),4+3+2+5=14(人),所以,大月生日的有35人,小月生日的有14人。(3)7\u003c10\u003c18\u003c20,20-18=2(人),所以,第一季度过生日的人最少,第四季度过生日的人最多;第四季度比第二季度过生日的同学多2人。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "单式统计表的特点及填补"
+                             ],
+        "source":  "21-22三年级下·河南新乡·期末"
+    },
+    {
+        "id":  "452",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "下面是二(1)班同学参加课外小组的情况.\n(1)把表格补充完整。![](images/143433.png)\n(2)( )小组的人最多,( )小组的人数最少.\n(3)如果每人只能参加其中的1个课外小组,那么二(1)班一共有( )人.\n(4)舞蹈小组的人数是音乐小组人数的( )倍.\n(5)美术小组比体操小组少( )人。",
+        "options":  [
+
+                    ],
+        "answer":  "20;15;11;5 舞蹈;音乐 51 4 4",
+        "solution":  "【分析】(1)根据\"正\"字统计法,一个正字表示5人,由此完成表格;(2)比较每个小组的人数,即可得出最多和最少分别是哪个小组;(3)将每个小组的人数相加即可解答;(4)用舞蹈小组的人数除以音乐小组人数即可求出舞蹈小组的人数是音乐小组人数的几倍;(5)用体操小组的人数减去美术小组的人数即可解答.\n【详解】(1)填表:舞蹈小组20人,体操小组15人,美术小组11人,音乐小组5人。(2)20\u003e15\u003e11\u003e5,舞蹈小组的人最多,音乐小组的人数最少。(3)20+15+11+5=51(人)。(4)20/5=4,舞蹈小组的人数是音乐小组人数的4倍。(5)15-11=4(人),美术小组比体操小组少4人。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "单式统计表的特点及填补"
+                             ],
+        "source":  "21-22 二年级下·广东韶关·期末"
+    },
+    {
+        "id":  "453",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "下面是二(1)班同学最喜欢的玩具统计情况.\n(1)根据上面的统计结果完成下面的统计表。![](images/143438.png)\n(2)二(1)班同学喜欢( )的人数最多,喜欢( )的人数最少.\n(3)如果你是商店老板,应多购进( )玩具。",
+        "options":  [
+
+                    ],
+        "answer":  "7;15;12;9;小汽车;洋娃娃;小汽车",
+        "solution":  "【详解】(1)根据统计情况填写即可。(2)根据统计表可知:7\u003c9\u003c12\u003c15,所以喜欢小汽车的人数最多,喜欢洋娃娃的人数最少。(3)应多进购喜欢的人数多的玩具,喜欢小汽车的人数最多,所以应多进购小汽车。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "20-21二年级下·河南漯河·期中"
+    },
+    {
+        "id":  "454",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "想知道某一路口10分钟内所通过的哪种车最多,通常采用制作表格,派几个同学分别统计这一路口10分钟内所通过的各种交通工具的( )。",
+        "options":  [
+
+                    ],
+        "answer":  "数量",
+        "solution":  "【详解】要想知道某一路口10分钟内所通过的哪种车最多,先要进行数据的收集,即派几个同学分别统计这一路口10分钟内所通过的各种交通工具的数量,然后把统计的数量填到表格里面进行整理分析,据此解答。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "21-22 二年级下·河南南阳·期中"
+    },
+    {
+        "id":  "455",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "秋季开学后,学校规定同学们可以根据个人情况,对秋季校服进行补订。下面是青年街小学二年级同学秋季校服补订情况。![](images/143447.png)\n(1)( )班补订校服的人数最多,( )班补订校服的人数最少.\n(2)四班补订校服的有( )人.\n(3)全校二年级补订校服的一共有( )人。",
+        "options":  [
+
+                    ],
+        "answer":  "三;二 15 62",
+        "solution":  "【分析】(1)根据表格将各班补订校服的人数进行比较即可;(2)由表格得:四班补订校服的人数有15人;(3)将各班补订校服的人数加起来即可.\n【详解】(1)18\u003e15\u003e12\u003e9\u003e8,由此可知:三班补订校服的人数最多,二班补订校服的人数最少。(2)由表格得:四班补订校服的人数有15人。(3)12+8+18+15+9=20+18+15+9=38+15+9=53+9=62(人),答:全校二年级补订校服的一共有62人。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "20以内数的比大小",
+                                 "100以内数的连加运算"
+                             ],
+        "source":  "21-22 二年级下·山东菏泽·期中"
+    },
+    {
+        "id":  "456",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "三(1)班投票选举班长,10名同学参加竞选(以编号代替姓名),全班46名同学参加了投票选举,得票情况如下:![](images/143451.png)\n(1)得票数最多的是( )号,最少的是( )号.\n(2)得票数过半的同学才能当选本届班委,那么本次投票选举中共有( )名同学当选本届班委。",
+        "options":  [
+
+                    ],
+        "answer":  "9;5 6",
+        "solution":  "【分析】(1)根据整数比较大小的方法,比较这10名同学得票大小解答。(2)全班46名同学,票数过半应是46/2=23票,先看哪些同学的得票大于23票,再数清这些同学的人数即可.\n【详解】(1)44\u003e42\u003e37\u003e35\u003e33\u003e28\u003e22\u003e21\u003e19\u003e16,得票数最多的是9号,最少的是5号。(2)46/2=23(票),得票数超过23票的有1,2,4,6,9,10号同学,共6名同学当选本届班委。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "21-22 三年级下·海南省直辖县级单位·期末"
+    },
+    {
+        "id":  "457",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "下面是二(3)班全班同学最喜欢的体育活动调查情况,![](images/143456.png)\n(1)最喜欢( )的人数最多,最喜欢( )的人数最少.\n(2)这个班一共有( )。",
+        "options":  [
+
+                    ],
+        "answer":  "打篮球;踢足球 48",
+        "solution":  "【分析】(1)根据统计图表,找出最多和最少的人数所对应的活动即可;(2)将所有活动对应的人数相加即可.\n【详解】(1)16\u003e10\u003e9\u003e7\u003e6,最喜欢打篮球的人数最多,最喜欢踢足球的人数最少。(2)9+10+16+6+7=48(人),这个班一共有48人。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "100以内数的连加运算"
+                             ],
+        "source":  "21-22二年级下·福建漳州·期中"
+    },
+    {
+        "id":  "458",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "学校要组织春季运动会,要求每人参加一项体育活动。下面是同学们参加报名的情况。![](images/143500.png)\n(2)跳绳的人数比踢足球的人数多( )人,打篮球的人数比跑步的人数多( )人.\n(3)打篮球和跳绳的一共有( )人。",
+        "options":  [
+
+                    ],
+        "answer":  "8;14;11;10 3;4 25",
+        "solution":  "【分析】(1)根据报名各项体育活动的人数进行填表即可;(2)用跳绳的人数减去踢足球的人数,用打篮球的人数减去跑步的人数即可;(3)用打篮球的人数加上跳绳的人数即可.\n【详解】(1)由报名各项体育活动的人数进行填表如下:踢足球8人,打篮球14人,跳绳11人,跑步10人。(2)11-8=3(人),14-10=4(人),所以跳绳的人数比踢足球的人数多3人,打篮球的人数比跑步的人数多4人。(3)14+11=25(人),所以打篮球和跳绳的一共有25人。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "十几减8的退位减法",
+                                 "两位数与整十数的减法",
+                                 "两位数与两位数的不进位加法"
+                             ],
+        "source":  "21-22 二年级下·山东菏泽·期中"
+    },
+    {
+        "id":  "459",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "下面是二(1)班最喜欢的运动情况。![](images/143507.png)\n(2)二(1)班一共有( )人.\n(3)二年级同学喜欢( )的人最多,喜欢( )的最少。",
+        "options":  [
+
+                    ],
+        "answer":  "20;6;8;12 46 跳绳;篮球",
+        "solution":  "【分析】(1)根据统计数据,填入统计表即可;(2)将统计表中数据相加,即可得出一共有多少人;(3)根据统计表中的数据大小,即可得出喜欢哪一类活动人数最多,喜欢哪一类活动人数最少.\n【详解】(1)根据图中数据,跳绳20人,篮球6人,足球8人,踢毽12人;(2)20+6+8+12=46(人),二(1)班一共有46人;(3)20\u003e12\u003e8\u003e6,二年级同学喜欢跳绳的人最多,喜欢篮球的最少。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "20以内数的比大小",
+                                 "100以内数的连加运算"
+                             ],
+        "source":  "21-22 二年级下·广东东莞·期末"
+    },
+    {
+        "id":  "460",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "几个同学正在统计一个路口10分钟内所通过的各种交通工具的数量.\n![](images/143513.png)\n(2)这个路口10分钟内通过的( )车最多,( )车最少.\n(3)如果再观察10分钟,( )车通过的数量可能最多.\n(4)这个路口10分钟内通过的大巴车比摩托车少( )辆。",
+        "options":  [
+
+                    ],
+        "answer":  "6;10;19;12 小轿;面包车 小轿车 2",
+        "solution":  "【分析】(1)根据学生统计的结果填表即可;(2)根据统计表可得出这个路口10分钟内所通过的哪种车最多,哪种车最少;(3)根据统计表中数据,小轿车通过的数量最多,如果再观察10分钟,小轿车通过的数量也可能最多;(4)用10分钟内通过的摩托车数量减去大巴车数量即可.\n【详解】(1)面包车6辆;大巴车10辆;小轿车19辆;摩托车12辆;(2)因为19\u003e12\u003e10\u003e6,所以这个路口10分钟内通过的小轿车最多,面包车最少;(3)如果再观察10分钟,小轿车通过的数量可能最多。(4)12-10=2(辆),这个路口10分钟内通过的大巴车比摩托车少2辆。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "20以内数的比大小",
+                                 "不退位减法(20以内)"
+                             ],
+        "source":  "21-22 二年级下·甘肃陇南·期末"
+    },
+    {
+        "id":  "461",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "下面是希望小学(1)班同学选\"劳动委员\"情况统计。![](images/143518.png)\n(2)( )的得票数最多,( )的得票数最少.\n(3)根据统计结果,应该选( )当劳动委员。张红比孙晓少得( )票。",
+        "options":  [
+
+                    ],
+        "answer":  "15;11;9;7 罗明;吴明 罗明;2",
+        "solution":  "【分析】(1)\"正\"一笔表示一票,整个字表示5票,通过数笔画的方法把他们的票数填入表格中;(2)比较4个人票数的多少,数字最大的就是最多的,数字最小的就是最少的;(3)通过比较票数最多的当选劳动委员;孙晓的票数减张红的票数即可解答.\n【详解】(1)罗明:5×3=15(票),孙晓:5×2+1=10+1=11(票),张红:5+4=9(票),吴明:5+2=7(票)。(2)15\u003e11\u003e9\u003e7,罗明的得票数最多,吴明的得票数最少。(3)根据统计结果,应该选罗明当劳动委员。11-9=2(票),张红比孙晓少得2票。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "21-22 二年级下·福建龙岩·期末"
+    },
+    {
+        "id":  "462",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "观察和统计。二年级2班投票选班长,每人只能投一票。投票情况如下:![](images/143528.png)\n(2)根据统计结果,( )的票数最多,( )的票数最少,( )最有可能被选为班长.\n(3)二年级2班共有( )人。",
+        "options":  [
+
+                    ],
+        "answer":  "15;9;4;11 卓玛;旦增;卓玛 39",
+        "solution":  "【分析】(1)\"正\"字计数法一笔表示一票,一个\"*\"表示一票,一个\"○\"表示一票,一个\"√\"表示一票,据此数出所有人的票数即可。(2)根据第(1)小题统计出来的票数,即可解答。(3)将所有人的票数相加,据此即可得出班级的人数.\n【详解】(1)填表:卓玛15票,达瓦9票,旦增4票,益西11票。(2)根据统计结果,卓玛的票数最多,旦增的票数最少,卓玛最有可能被选为班长。(3)15+9+4+11=39(人),所以,二年级2班共有39人。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "100以内数的连加运算"
+                             ],
+        "source":  "21-22 二年级下·西藏那曲·期末"
+    },
+    {
+        "id":  "463",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "下表是小红期末考试的成绩,根据表格完成题目。![](images/143532.png)\n(1)通过表格,小红考试分数最高的科目是( ),考试分数最低的科目是( ).\n(2)学校规定,90-100分为优秀,小红优秀的科目有( )个。",
+        "options":  [
+
+                    ],
+        "answer":  "数学;音乐 1",
+        "solution":  "【分析】(1)比较小红期末考试各科成绩的大小解答。(2)90-100分为优秀,则比较各科成绩与90分的大小,看哪些科目的成绩大于等于90分.\n【详解】(1)98\u003e88\u003e87\u003e85\u003e83\u003e80\u003e79\u003e66,通过表格,小红考试分数最高的科目是数学,考试分数最低的科目是音乐。(2)学校规定,90-100分为优秀,小红优秀的科目只有数学,即优秀的科目有1个。",
+        "knowledge_points":  [
+                                 "单式统计表的特点及填补"
+                             ],
+        "source":  "21-22 三年级下·湖南邵阳·期末"
+    },
+    {
+        "id":  "464",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "乐乐调查出班上同学们最喜欢吃的早餐粥的情况如下表。![](images/143537.png)\n(2)乐乐一共调查了( )名同学.\n(3)最喜欢吃( )粥的同学最多,最喜欢吃( )粥的同学最少.\n(4)最喜欢吃南瓜粥的同学比最喜欢吃瘦肉粥的同学少( )人。",
+        "options":  [
+
+                    ],
+        "answer":  "46538 26 瘦肉 青菜 3",
+        "solution":  "【详解】(1)先根据统计图数一数每种早餐粥喜欢的人数:小米粥下面有4个\"*\",表示4人;玉米粥下面有6个\"√\",表示6人;南瓜粥下面有5个\"○\",表示5人;青菜粥下面有3个\"△\",表示3人;瘦肉粥下面有1个正字和3笔,表示8人。所以表中应填写:小米粥4人,玉米粥6人,南瓜粥5人,青菜粥3人,瘦肉粥8人。(2)把喜欢各种粥的人数合起来,就是乐乐一共调查的人数:4+6+5+3+8=26(人)。所以乐乐一共调查了26名同学。(3)比较这几种粥对应的人数:4,6,5,3,8,其中8最大,3最小,所以最喜欢吃瘦肉粥的同学最多,最喜欢吃青菜粥的同学最少。(4)喜欢南瓜粥的有5人,喜欢瘦肉粥的有8人,求南瓜粥比瘦肉粥少多少人,用减法计算:8-5=3(人)。所以最喜欢吃南瓜粥的同学比最喜欢吃瘦肉粥的同学少3人。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "20-21 二年级下·四川广元·期末"
+    },
+    {
+        "id":  "465",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "校庆到了,二(1)班要准备合唱表演,要从下面四首歌曲中投票选择一首。下面是同学们的投票结果。(每人只投一票)![](images/143545.png)\n(2)选择( )的人数最多,选择( )的人数最少,相差( )人.\n(3)根据投票结果,二(1)班应该选择合唱( ).\n(4)有两名同学请假没能参加投票,如果他们也投了票,对最终结果( )产生影响。(填\"会\"或\"不会\")",
+        "options":  [
+
+                    ],
+        "answer":  "8;5;16;9 《明日歌》;《三字经》;11 《明日歌》 不会",
+        "solution":  "【分析】(1)一个\"√\"代表1票,有几个\"√\",就有几票;一个\"正\"字代表5票,几个\"正\"字,就有几个5票;一个\"○\"代表1票,有几个\"○\",就有几票;据此数出每首歌曲喜欢的票数,填表即可;(2)比较各个数据的大小,即可判断喜欢人数最多或最少的歌曲,用最多的人数减去最少的人数,即可求出相差的人数;(3)因为大部分学生喜欢《明日歌》,所以应该选择合唱《明日歌》;(4)即使两名请假的同学来投票,都投除了《明日歌》之外最多的《读唐诗》,那么《读唐诗》一共是9+2=11票,11票小于16票,还是喜欢《明日歌》的人数最多,所以对最终结果不会产生影响.\n【详解】(1)填表:《长歌行》8票,《三字经》5票,《明日歌》16票,《读唐诗》9票。(2)16-5=11(人),选择《明日歌》的人数最多,选择《三字经》的人数最少,相差11人。(3)根据投票结果,二(1)班应该选择合唱《明日歌》。(4)9+2=11票,11\u003c16,所以,有两名同学请假没能参加投票,如果他们也投了票,对最终结果不会产生影响。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "单式统计表的特点及填补"
+                             ],
+        "source":  "20-21 二年级下·山西阳泉·期末"
+    },
+    {
+        "id":  "466",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "\"六一\"儿童节,老师要带三⑴班学生开展快乐一日游活动,为了确定同学们的游玩地点,进行了投票,每个人都要参与投票,而且只能投一票,并将数据记录如下:\n![](images/143551.png)\n(1)同学们最想去的地方是( ).\n(2)一共有( )投票。",
+        "options":  [
+
+                    ],
+        "answer":  "游乐场 30人",
+        "solution":  "【分析】(1)观察统计表,那个项目对勾最多说明想去的人数最多。(2)把各项目想去的人数相加求和即可解答.\n【详解】(1)想去游乐场的人数最多有13人。(2)13+6+11=19+11=30(人)。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "18-19 三年级下·河南商丘·期末"
+    },
+    {
+        "id":  "467",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "在统计有多少名学生参加兴趣小组时,可以用画\"正\"字的方法来记录。( )",
+        "options":  [
+
+                    ],
+        "answer":  "√",
+        "solution":  "【分析】根据数据整理和收集的方法,在统计有多少名学生参加兴趣小组时,可以用画\"正\"字的方法来记录,便于操作即可.\n【详解】在统计有多少名学生参加兴趣小组时,可以用画\"正\"字的方法来记录。所以原题说法正确。故答案为:√",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "22-23 二年级·全国·假期作业"
+    },
+    {
+        "id":  "468",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "用\"正\"收集数据,一个\"正\"代表数量1。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】\"正\"字计数法一笔表示数量1,一个\"正\"表示数量5,据此进行判断即可.\n【详解】据分析可知:一个\"正\"代表数量5。题干说法错误。故答案为: ×",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "22-23 二年级·全国·假期作业"
+    },
+    {
+        "id":  "469",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "判断题",
+        "difficulty":  0.65,
+        "question":  "小亮6岁时身高118cm,小冬9岁时身高135cm,小强12岁时身高152cm,说明身高随着年龄的增加而增高。( )",
+        "options":  [
+
+                    ],
+        "answer":  "√",
+        "solution":  "【分析】年龄从6岁到12岁,身高从118到152,数值在逐渐增加,据此解答即可.\n【详解】小亮6岁时身高118cm,小冬9岁时身高135cm,小强12岁时身高152cm,说明身高随着年龄的增加而增高。原题说法正确。故答案为:√",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "厘米的认识"
+                             ],
+        "source":  "21-22 五年级下·重庆彭水·期末"
+    },
+    {
+        "id":  "470",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "在用正字统计时,一个正字代表1个数据。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】在统计数据的时候,我们可以先通过画\"正\"字的方法整理数据,一个正字代表的数量是5.\n【详解】在统计原始数据的时候,在用正字统计时,一个正字代表5个数据。故答案为: ×",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "21-22 二年级下·湖北武汉·期末"
+    },
+    {
+        "id":  "471",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "用\"正\"统计四月份的天气情况,一个\"正\"代表一天。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】一个正字有五画,那么利用正字统计四月份的天气情况,一个正字代表5天,据此判断.\n【详解】用\"正\"统计四月份的天气情况,一个\"正\"代表5天。原题说法错误。故答案为: ×",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "20-21 二年级下·甘肃陇南·期中"
+    },
+    {
+        "id":  "472",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "判断题",
+        "difficulty":  0.65,
+        "question":  "《数据收集整理》这单元学会通过调查收集数据,用\"正\"记录数据很方便。( )",
+        "options":  [
+
+                    ],
+        "answer":  "√",
+        "solution":  "【分析】整理数据时,用画\"正\"字的方法记录数据比较简便;\"正\"字的一笔代表1个数据,一个\"正\"字代表5个数据;由此判断即可.\n【详解】根据数据收集和整理的方法可知:用\"正\"字来记录数据很方便,一个\"正\"字表示5个数据。所以本题说法正确。故答案为:√",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "21-22二年级下·河南南阳·期中"
+    },
+    {
+        "id":  "473",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "用\"正\"字统计五月份的天气情况,一个\"正\"字代表5天。( )",
+        "options":  [
+
+                    ],
+        "answer":  "√",
+        "solution":  "【分析】用\"正\"统计五月份的天气情况,一个\"正\"有5笔,1笔代表1天,据此解答.\n【详解】一个\"正\"字有5笔,所以一个\"正\"字代表5天,所以原题干说法正确。故答案为:√",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "21-22 二年级下·河南南阳·期中"
+    },
+    {
+        "id":  "474",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "下面是某冷饮店各种口味雪糕的销售情况。![](images/143558.png)\n(2)卖得最多的是( )口味,卖得最少的是( )口味.\n(3)如果要进货,( )口味要多进一些.\n(4)你还能提出其他数学问题并解答吗。",
+        "options":  [
+
+                    ],
+        "answer":  "16;14;30;9;2 巧克力;香蕉 巧克力 问题:卖出的草莓口味比菠萝口味多多少箱。16-14=2(箱)(本小题答案不唯一)",
+        "solution":  "【分析】(1)\"正\"字计数法一笔表示1箱,一个\"正\"字表示5箱,据此数出各种口味雪糕的销售情况即可。(2)将第(1)小题统计出来的各种口味雪糕的销售情况进行比较即可得出答案。(3)根据各种口味雪糕的销售情况,应选择销售量最好的口味多进一些。(4)根据题干的数学信息,结合学过的数学知识进行解答即可。例如:卖出的草莓口味比菠萝口味多多少箱。本小题答案不唯一.\n【详解】(1)填表:草莓16箱,菠萝14箱,巧克力30箱,芒果9箱,香蕉2箱。(2)30\u003e16\u003e14\u003e9\u003e2,卖得最多的是巧克力口味,卖得最少的是香蕉口味。(3)因为巧克力口味的销售量最好,如果要进货,巧克力口味要多进一些。(4)问题:卖出的草莓口味比菠萝口味多多少箱。16-14=2(箱),答:卖出的草莓口味比菠萝口味多2箱。(本小题答案不唯一)",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "\"提问题\"\"填条件\"问题",
+                                 "100以内数的比大小"
+                             ],
+        "source":  "20-21 二年级下·广东广州·期末"
+    },
+    {
+        "id":  "475",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "把图中的统计结果填入表中并完成下面的问题。![](images/143603.png)\n(1)根据统计结果,应该选( )参加比赛.\n(2)有两位同学缺勤,没能参加投票,如果他们也投了票,结果可能会怎样。",
+        "options":  [
+
+                    ],
+        "answer":  "15;22 陈小菲 即使这两人都选王明明,结果不会变,还是陈小菲票数多。",
+        "solution":  "【分析】\"正\"字计数法一笔表示1票,图上的其他计数法,一个\"√\"表示1票,一个\"○\"表示1票,据此数出王明明和陈小菲的票数即可。(1)票数最多的,应被选为代表参加比赛。(2)结合每个人的票数进行比较,假设将这2票全部投给王明明,看票数会不会超过陈小菲,再进行分析即可.\n【详解】填表:王明明15票,陈小菲22票。(1)根据统计结果,15\u003c22,应该选陈小菲参加比赛。(2)若将这两位同学的两票全部投给王小明,此时王小明有17票,17\u003c22,所以结果不会变,还是陈小菲票数多。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "22-23 二年级下·全国·课前预习"
+    },
+    {
+        "id":  "476",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "填一填。四(2)班同学投票确定春游地点。(每人填一个地点),下面是同学们最喜欢去的景区记录结果。![](images/143609.png)\n(1)四(2)班有( )人.\n(2)喜欢大峡谷的比喜欢凤凰山的少( )人.\n(3)你对选择出游的景区有什么建议。",
+        "options":  [
+
+                    ],
+        "answer":  "45;7;建议去凤凰山",
+        "solution":  "【分析】(1)\"正\"字中一笔画代表1人,由此可知,喜欢去大峡谷的有10人,喜欢去龙川景区的有7人,喜欢去棋盘村的有11人,喜欢去凤凰山的有17人,依此计算出这个班的总人数即可。(2)用喜欢凤凰山的人数减喜欢大峡谷的人数即可,依此计算并填空。(3)喜欢哪一个景点的人数最多,则就选择这个景点为春游地点,依此解答.\n【详解】(1)10+7+11+17=45(人),即四(2)班有45人。(2)17-10=7(人),即喜欢大峡谷的比喜欢凤凰山的少7人。(3)如果选择出游的景区,我建议去凤凰山,因为选择凤凰山的人数最多。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "单式统计表的特点及填补"
+                             ],
+        "source":  "21-22三年级下·广东广州·期末"
+    },
+    {
+        "id":  "477",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "佳美电器商店电视机一周销售情况统计表。![](images/143613.png)\n(1)这一星期中,哪一天销售的最多,哪一天销售的最少。\n(2)这星期一共销售出多少台。",
+        "options":  [
+
+                    ],
+        "answer":  "星期六;星期二;195台",
+        "solution":  "【分析】(1)将这一星期电视机的销量进行大小排序,然后再进行解答;(2)将每天的销量相加即可.\n【详解】(1)50\u003e45\u003e30\u003e25\u003e20\u003e15\u003e10,因此这一星期中,星期六销售的最多,星期二销售的最少。(2)15+10+20+25+30+50+45=195(台),答:这星期一共销售出195台。",
+        "knowledge_points":  [
+                                 "单式统计表的特点及填补"
+                             ],
+        "source":  "22-23 四年级上·全国·课前预习"
+    },
+    {
+        "id":  "478",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "下表是二(3)班学生每天看电视时间情况统计表:![](images/143617.png)\n(1)每个\"正\"字表示( )个人.\n(2)这个班有( )名同学.\n(3)根据上面的统计表,你发现了什么。你有什么建议。我发现了:。我的建议:。",
+        "options":  [
+
+                    ],
+        "answer":  "5 45 我发现了:每天看电视时间在30分钟-1小时的人数最多。我的建议:将学生每天的看电视时间控制在30分-1小时,学生比较能接受。(本小题答案不唯一)",
+        "solution":  "【分析】(1)因为一个\"正\"字有5画,所以每个\"正\"字表示5人。(2)根据加法的意义,把各时间段看电视的人数加起来即可。(3)通过观察统计表,写出自己的发现和建议即可,本小题答案不唯一。例如:我发现每天看电视时间在30分钟~1小时的人数最多。我的建议将学生每天的看电视时间控制在30分-1小时,学生比较能接受.\n【详解】(1)每个\"正\"字表示5人。(2)15+25+5=45(名),答:这个班有45名学生。(3)我发现了:每天看电视时间在30分钟-1小时的人数最多。我的建议:将学生每天的看电视时间控制在30分-1小时,学生比较能接受。(本小题答案不唯一)",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "统计图表的综合应用"
+                             ],
+        "source":  "21-22二年级下·福建龙岩·期末"
+    },
+    {
+        "id":  "479",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "下面是二(1)班小朋友最喜欢的水果统计情况.\n![](images/143621.png)\n(2)喜欢吃桔子的同学比喜欢吃梨的多多少人。\n(3)喜欢吃苹果,梨和香蕉的一共多少人。",
+        "options":  [
+
+                    ],
+        "answer":  "10;8;4;10 4人 24人",
+        "solution":  "【分析】(1)通过观察统计结果可知,喜欢吃苹果的有10人,喜欢吃桔子的有8人,喜欢吃梨的有4人,喜欢吃香蕉的有10人,据此填表即可。(2)用喜欢吃桔子的人数减去喜欢吃梨的人数即可。(3)把喜欢吃苹果,梨和香蕉的人数合起来即可.\n【详解】(1)填表如下:苹果10人,桔子8人,梨4人,香蕉10人。(2)8-4=4(人),答:喜欢吃桔子的同学比喜欢吃梨的多4人。(3)10+4+10=24(人),答:喜欢吃苹果,梨和香蕉的一共24人。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "统计图表的综合应用",
+                                 "100以内数的连加运算"
+                             ],
+        "source":  "20-21 二年级下·重庆黔江·期末"
+    },
+    {
+        "id":  "480",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "下面是二(3)班最喜欢吃的水果情况统计表。![](images/143626.png)\n(1)喜欢芒果的人比喜欢梨子的少5人,那么喜欢芒果的有( )人,每人只能选一种,那么二(3)班一共有( )人.\n(2)喜欢( )的人最多,喜欢( )的人最少,喜欢( )和( )的人一样多.\n(3)你还发现了什么数学信息,请写出一条。",
+        "options":  [
+
+                    ],
+        "answer":  "8;58 梨子;桃子;香蕉;西瓜 喜欢香蕉的人数比喜欢苹果的人数多2人。(本小题答案不唯一)",
+        "solution":  "【分析】(1)喜欢芒果的人比喜欢梨子的少5人,从图中得知喜欢梨子的人数是13,所以用减法;每人只能选一种喜欢的水果,那么这些数据就没有重复,所以把所有的数据相加就可以得到总人数。(2)比较数据,我们就可以很容易看出喜欢梨子的人最多,喜欢桃子的人最少,喜欢香蕉和西瓜的人一样多。(3)结合表格写出数学信息即可,本小题答案不唯一。例如:喜欢香蕉的人数比喜欢苹果的人数多2人.\n【详解】(1)13-5=8(人),9+11+11+8+13+6=58(人),答:喜欢芒果的有8人,二(3)班一共有58人。(2)13\u003e11\u003e9\u003e8\u003e6,所以喜欢梨子的人最多,喜欢桃子的人最少,喜欢香蕉和西瓜的人一样多。(3)数学信息:喜欢香蕉的人数比喜欢苹果的人数多2人。(本小题答案不唯一)",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "\"提问题\"\"填条件\"问题"
+                             ],
+        "source":  "21-22二年级下·湖北黄石·期末"
+    },
+    {
+        "id":  "481",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "下面是二(1)班的同学最喜欢借阅哪类书的调查统计情况(每人只选一类)![](images/143638.png)\n(2)最喜欢借阅( )书的人数最多,最喜欢借阅( )书的人数最少.\n(3)二(1)班一共有( )个人.\n(4)如果二(1)班的老师要购入一些新书,你有什么建议。",
+        "options":  [
+
+                    ],
+        "answer":  "20;5;13;6;故事;科技;44;因为喜欢借阅故事书的人数比较多,建议老师在购入新书的时候可以多购买故事书。",
+        "solution":  "【分析】(1)根据\"正\"字的笔画数即可填表;(2)从表中可以看出喜欢哪种图书的人数最多及最少;(3)将喜欢各种书的人数相加,即可得出二(1)班的总人数;(4)建议老师买同学们喜欢看的书,答案不唯一.\n【详解】(1)填表如下:故事书20人,科技书5人,漫画书13人,其他6人。(2)20\u003e13\u003e6\u003e5,所以最喜欢借阅故事书的人数最多,最喜欢借阅科技书的人数最少。(3)20+5+13+6=44(个),答:二(1)班一共有44个人。(4)因为喜欢借阅故事书的人数比较多,建议老师在购入新书的时候可以多购买故事书。(答案不唯一)",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "20以内数的比大小",
+                                 "100以内数的连加运算"
+                             ],
+        "source":  "20-21二年级下·江西赣州·期中"
+    },
+    {
+        "id":  "482",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.4,
+        "question":  "下面是四位同学统计的二(1)班学生课外兴趣爱好情况。我统计的是玩游戏:![](images/143642.png)\n把他们记录的结果填在下表中。项目玩游戏踢球跳绳跳舞人数\n(1)二(1)班最喜欢( )的人最多,最喜欢( )的人最少.\n(2)最喜欢玩游戏的比最喜欢跳舞的多( )人.\n(3)请你再提出一个数学问题,并解答。",
+        "options":  [
+
+                    ],
+        "answer":  "22;6;10;7;玩游戏;踢球;15;最喜欢玩游戏的比最喜欢跳绳的多多少人;22-10=12(人)",
+        "solution":  "【分析】在统计数据的时候,一个\"正\"字代表的数量是5;其他同学的统计情况,通过数数即可,从而完成统计表。(1)根据统计表即可解答问题;(2)最喜欢玩游戏的人数减去最喜欢跳舞的人数即可得到答案;(3)根据统计表,合理提出问题即可,答案不唯一.\n【详解】填表:玩游戏22人,踢球6人,跳绳10人,跳舞7人。(1)二(1)班最喜欢玩游戏的人最多,最喜欢踢球的人最少。(2)22-7=15(人),所以最喜欢玩游戏的比最喜欢跳舞的多15人。(3)最喜欢玩游戏的比最喜欢跳绳的多多少人。(答案不唯一)22-10=12(人),答:最喜欢玩游戏的比最喜欢跳绳的多12人。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "\"提问题\"\"填条件\"问题",
+                                 "单式统计表的特点及填补"
+                             ],
+        "source":  "21-22二年级下·山东济宁·期末"
+    },
+    {
+        "id":  "483",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "下面是对二(1)班最喜欢的校服颜色调查情况。![](images/143646.png)\n(1)最喜欢( )的人数最多,最喜欢( )的人数最少.\n(2)这个班定做校服,选择( )合适.\n(3)如果每人只选择一种颜色,这个班一共有多少人。",
+        "options":  [
+
+                    ],
+        "answer":  "蓝色;黄色 蓝色 44人",
+        "solution":  "【分析】(1)根据数据记录的方法,一个\"正\"字表5人,通过观察统计表可知,最喜欢蓝色的人数最多,最喜欢黄色的人数最少。(2)喜欢蓝色的人数多,因此这个班定做校服,选择蓝色合适。(3)根据加法的意义,把喜欢各种颜色的人数合并起来即可.\n【详解】(1)由统计表可知:喜欢红色的有13人;喜欢黄色的有7人;喜欢蓝色的有15人;喜欢白色的有9人;15\u003e13\u003e9\u003e7,最喜欢蓝色的人数最多,最喜欢黄色的人数最少。(2)喜欢蓝色的人数多,这个班定做校服,选择蓝色合适。(3)13+7+15+9=44(人),答:这个班一共有44人。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "21-22 二年级下·河北邯郸·期末"
+    },
+    {
+        "id":  "484",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "聪聪调查了本班学生喜欢阅读的课外书情况。![](images/143650.png)\n(2)喜欢( )书的人最少.\n(3)喜欢漫画书的比文艺书的多( )人\n(4)班上要新买一批图书,你有什么建议。",
+        "options":  [
+
+                    ],
+        "answer":  "18;10;6 文艺书 18 我建议多买一些漫画书",
+        "solution":  "【分析】(1)\"正\"字的每一笔代表一个人,一个\"正\"字代表5个人,数一数填入对应的课外书下面;(2)将整理出来的数据作比较即可得出结论;(3)用喜欢漫画书的人数减去喜欢文艺书的人数即可;(4)可以建议多买最受欢迎的书,答案不唯一,合理即可.\n【详解】(1)填表:故事书18人,科技书10人,漫画书24人,文艺书6人。(2)6\u003c10\u003c18\u003c24,所以喜欢文艺书的人最少。(3)24-6=18(人)。(4)我建议多买一些漫画书。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "100以内数的比大小",
+                                 "一位数与两位数的退位减法"
+                             ],
+        "source":  "21-22二年级下·四川南充·期末"
+    },
+    {
+        "id":  "485",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "看表填空。下面是二(1)班同学的兴趣爱好统计表。![](images/143654.png)\n(2)二(1)班喜欢( )的人最多,喜欢( )的人最少.\n(3)二(1)班一共有( )人.\n(4)喜欢踢球的人比喜欢唱歌的多( )人.\n(5)你能提一个数学问题并解答吗。",
+        "options":  [
+
+                    ],
+        "answer":  "20;16;15;11 游戏;跳舞 62 1 答案不唯一,如:喜欢唱歌和喜欢跳舞的一共多少人。26人",
+        "solution":  "【分析】(1)观察统计表中\"正\"字的笔画数,依次填出即可;(2)比较每个兴趣小组的人数,即可得出谁最多谁最少;(3)把表中所有\"正\"字的笔画数相加即可;(4)用喜欢踢球的人数减去喜欢唱歌的人数;(5)提出合理问题并解答即可,答案不唯一.\n【详解】(1)填表:游戏20人,踢球16人,唱歌15人,跳舞11人。(2)20\u003e16\u003e15\u003e11,二(1)班喜欢游戏的人最多,喜欢跳舞的人最少。(3)20+16+15+11=62(人),二(1)班一共有62人。(4)16-15=1(人),喜欢踢球的人比喜欢唱歌的多1人。(5)答案不唯一,如:喜欢唱歌和喜欢跳舞的一共多少人。15+11=26(人),答:喜欢唱歌和喜欢跳舞的一共26人。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "\"提问题\"\"填条件\"问题",
+                                 "单式统计表的特点及填补"
+                             ],
+        "source":  "21-22 二年级下·山东临沂·期中"
+    },
+    {
+        "id":  "486",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "下表是统计二(1)班学生的兴趣爱好。![](images/143701.png)\n(1)二(1)班喜欢( )的人数最多,喜欢( )人数最少.\n(2)二(1)班一共有( )人.\n(3)喜欢游戏的人数比喜欢跳舞的多多少人。\n(4)你能提一个数学问题并解答吗。",
+        "options":  [
+
+                    ],
+        "answer":  "游戏;跳舞 42 9人 本题答案不唯一,如:喜欢游戏和踢球的一共多少人。26人",
+        "solution":  "【分析】(1)根据正字统计法。一个\"正\"字表示5,由此得出每个兴趣小组的人数,再比较即可解答;(2)将每个兴趣小组的人数相加即可;(3)用喜欢游泳的人数减去喜欢跳舞的人数即可解答;(4)本题答案不唯一,如:喜欢游戏和踢球的一共多少人。\n【详解】(1)15\u003e11\u003e10\u003e6,所以二(1)班喜欢游戏的人数最多,喜欢跳舞人数最少。(2)15+11+10+6=42(人),二(1)班一共有42人。(3)15-6=9(人),答:喜欢游戏的人数比喜欢跳舞的多9人。(4)本题答案不唯一,如:喜欢游戏和踢球的一共多少人。15+11=26(人),答:喜欢游戏和踢球的一共26人。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "\"提问题\"\"填条件\"问题"
+                             ],
+        "source":  "20-21 二年级下·甘肃陇南·期中"
+    },
+    {
+        "id":  "487",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "下面是二(2)班同学喜欢的体育运动统计情况。![](images/143710.png)\n(2)二(2)班共有( )名学生.\n(3)二(2)班喜欢( )的同学最多,喜欢( )的同学最少;喜欢打篮球的同学比喜欢踢足球的人数多( )人.\n(4)如果学校要买一批体育器材,你建议:",
+        "options":  [
+
+                    ],
+        "answer":  "15;6;4;6;37;打篮球;跳绳;9;多买一些篮球",
+        "solution":  "【分析】(1)根据调查表的情况填写即可;(2)把每项体育运动的人数相加即可解答;(3)把每项体育运动喜欢的人数进行比较,最大的就是喜欢最多,最小的就是喜欢的最少;用喜欢打篮球的人数减喜欢踢足球的人数,就是喜欢打篮球比喜欢踢足球多的人数;(4)结合实际填写即可。(答案不唯一)\n【详解】(1)填表:打篮球15人,踢足球6人,打乒乓球6人,跳绳4人,其他6人。(2)15+6+6+4+6=21+6+4+6=27+4+6=31+6=37(人),所以二(2)班共有37名学生。(3)15\u003e6\u003e4,所以喜欢打篮球的同学最多,喜欢跳绳的学生最少;15-6=9(人),所以喜欢打篮球的同学比喜欢踢足球的人数多9人;(4)因为喜欢打篮球的学生最多,所以建议:多买一些篮球(答案不唯一)",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "21-22 二年级下·四川广元·期末"
+    },
+    {
+        "id":  "488",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "下面是某小学二(1)班所有同学参加课后服务社团的人数统计情况(每位同学只能参加一个社团。一个正字表示5人)。![](images/143716.png)\n(2)参加( )社团的人数最多,参加( )社团的人数最少.\n(3)参加美术社团的人数比足球社团的人数多( )人.\n(4)根据统计表中的信息,请你再提出一个其他的数学问题,并解答。",
+        "options":  [
+
+                    ],
+        "answer":  "8;19;10;6;书法;科技;2;参加书法社团的比足球社团的人数多多少人;19-8=11(人)",
+        "solution":  "【分析】(1)根据正字表逐一查出每个社团有多少人;(2)根据(1)表,比较参加每个社团人数的大小,最大的就是人数最多的社团,最小及时人数最少的社团;(3)用参加美术社团的人数减足球社团的人数计算即可;(4)答案不唯一,合理即可.\n【详解】(1)填表:足球8人,书法19人,美术10人,科技6人。(2)19\u003e10\u003e8\u003e6,所以参加书法社团的人数最多,参加科技社团的人数最少。(3)10-8=2(人),所以参加美术社团的人数比足球社团的人数多2人。(4)参加书法社团的比足球社团的人数多多少人。19-8=11(人),答:参加书法社团的比足球社团的人数多11人。(答案不唯一)",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "21-22二年级下·四川凉山·期末"
+    },
+    {
+        "id":  "489",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "下面是创力家电公司某周末的家电销售情况。![](images/143721.png)\n(1)( )的销售量最多,( )的销售量最少.\n(2)( )和( )的销售量相差最少.\n(3)你能提出一个数学问题并解答吗。",
+        "options":  [
+
+                    ],
+        "answer":  "空调;洗衣机;电视机;冰箱;空调比电视机多销售多少台;15-9=6(台)",
+        "solution":  "【分析】(1)先根据统计表得出各种家电的销售量,再比较即可。(2)通过计算可得电视机和冰箱的销售量相差最少。(3)空调比电视机多销售多少台。用空调销售的台数减电视机销售的台数即可.\n【详解】(1)电视机:9台,空调:15台,冰箱:11台,洗衣机:6台,6\u003c9\u003c11\u003c15,所以,空调的销售量最多,洗衣机的销售量最少。(2)电视机和冰箱的销售量相差最少。(3)空调比电视机多销售多少台。(答案不唯一)15-9=6(台),答:空调比电视机多销售6台。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "\"提问题\"\"填条件\"问题"
+                             ],
+        "source":  "2022·云南保山·小升初真题"
+    },
+    {
+        "id":  "490",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "中国从1980年开始参加冬奥会,当时是在美国举行的普莱西德湖冬奥会,截止到2022年在中国北京举行的冬奥会,中国队总共参加了12届冬奥会,其中有9届冬奥会上夺得过奖牌。如下:![](images/143728.png)\n(1)中国到2022年目前总共获得( )枚冬奥会奖牌.\n(2)获得奖牌最多的是( )年,获得( )枚.\n(3)看了上面的统计你有什么想法。",
+        "options":  [
+
+                    ],
+        "answer":  "77 2022;15 我国获得冬奥会金牌的数量在逐渐增多,这也说明我国的体育水平在逐步提高。(合理即可)",
+        "solution":  "【分析】(1)把每一届获得的奖牌数加起来,即可求出获得奖牌的总数量;(2)通过观察统计表,即可了解哪一届的奥运会上获得的金牌数最多以及获得金牌的数量;(3)分析统计表,只要是通过统计表数据得出的结论即可.\n【详解】(1)3+3+8+8+11+11+9+9+15=77(枚)。(2)通过观察统计表的数据可知,获得奖牌最多的是2022年,获得了15枚金牌;(3)我国获得冬奥会金牌的数量在逐渐增多,说明我国的体育水平在逐步提高。(合理即可)",
+        "knowledge_points":  [
+                                 "单式统计表的特点及填补"
+                             ],
+        "source":  "21-22 三年级下·浙江金华·期末"
+    },
+    {
+        "id":  "491",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "阳光小学二年级参加科技小组的人数如下:![](images/143733.png)\n(1)完成以上统计表.\n(2)二年级参加( )组的人数最多,参加( )组的人数最少。参加纸飞机的人数是参加速叠杯的人的( )倍.\n(3)二年级参加科技组的一共有( )人.\n(4)你还能提出哪些数学问题并解答。",
+        "options":  [
+
+                    ],
+        "answer":  "15;7;19;14 华容道;速叠杯;2 55 答案不唯一,如:参加魔方和速叠杯的一共多少人。22人",
+        "solution":  "【分析】(1)根据正字统计法,一个正字表示5个人,由此数出每项的人数;(2)分别比较每组的人数,即可求出最多和最少的人数;求一个数是另一个数的几倍,用除法计算;(3)将每项的人数相加,即可解答;(4)答案不唯一,只要合适即可。如:参加魔方和速叠杯的一共多少人。\n【详解】(1)填表:魔方15人,速叠杯7人,华容道19人,纸飞机14人。(2)19\u003e15\u003e14\u003e7,二年级参加华容道组的人数最多,参加速叠杯组的人数最少。14/7=2,参加纸飞机的人数是参加速叠杯的人的2倍。(3)15+7+19+14=55(人)。(4)答案不唯一,如:参加魔方和速叠杯的一共多少人。15+7=22(人),答:参加魔方和速叠杯的一共22人。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "20-21 二年级下·山西长治·期中"
+    },
+    {
+        "id":  "492",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "下面的统计表记录的是二年级(1)班和(2)班同学的课余生活情况:![](images/143737.png)\n(1)二(1)班同学在课余时间喜欢( )的人最多.\n(2)二(2)班同学在课余时间喜欢( )的人最少.\n(3)你还能提出其它数学问题并解答吗。",
+        "options":  [
+
+                    ],
+        "answer":  "打游戏机;读课外书;二(1)班和二(2)班同学喜欢看动画片的人数共有多少人;11+13=24(人)",
+        "solution":  "【分析】(1)把二(1)班同学在课余时间参加活动的人数进行对比即可;(2)把二(2)班同学在课余时间参加活动的人数进行对比即可;(3)根据统计表中的内容提出相应数学问题并解答即可。(答案不唯一)\n【详解】(1)12\u003e11\u003e8\u003e7,所以二(1)班同学在课余时间喜欢打游戏机的人最多。(2)13\u003e10\u003e9\u003e4,所以二(2)班同学在课余时间喜欢读课外书的人最少。(3)二(1)班和二(2)班同学喜欢看动画片的人数共有多少人。11+13=24(人),答:二(1)班和二(2)班同学喜欢看动画片的人数共有24人。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "\"提问题\"\"填条件\"问题",
+                                 "两位数与两位数的不进位加法"
+                             ],
+        "source":  "20-21二年级下·江西抚州·期末"
+    },
+    {
+        "id":  "493",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "三(1)班选举大家最喜欢的鲜花,选举记录如下图。(x代表1票)\n![](images/143744.png)\n(1)喜欢( )花的人最多,有( )人;喜欢( )花的人最少,有( )人.\n(2)一共有( )人投票.\n(3)喜欢月季花的比喜欢茉莉花的多( )人,喜欢玫瑰花和芍药花的一共有( )人。",
+        "options":  [
+
+                    ],
+        "answer":  "芍药;10;茉莉;3 25 1;18",
+        "solution":  "【分析】(1)X代表1票,因此哪一种花对应的X最多,即喜欢这种花的人数最多,有几个x,就表示有多少人;哪种花对应的x最少,即喜欢这种花的人数最少,有几个x,就表示有多少人;(2)直接将喜欢每种花的人数加起来即可;(3)用喜欢月季花的人数减去喜欢茉莉花的人数即可;用喜欢玫瑰花的人数加喜欢芍药的人数即可,依此计算.\n【详解】(1)喜欢玫瑰花的有8人,喜欢月季的有4人,喜欢茉莉的有3人,喜欢芍药的有10人,10\u003e8\u003e4\u003e3,因此喜欢芍药花的人最多,有10人;喜欢茉莉花的人最少,有3人。(2)8+4+3+10=25(人)。(3)4-3=1(人),8+10=18(人),因此喜欢月季花的比喜欢茉莉花的多1人,喜欢玫瑰花和芍药花的一共有18人。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "21-22三年级下·黑龙江大兴安岭地·期末"
+    },
+    {
+        "id":  "494",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "下表是二(1)班学生的兴趣运动统计情况:![](images/143750.png)\n(1)二(1)班最喜欢( )的人最多,最喜欢( )的人最少.\n(2)二(1)班一共有( )人.\n(3)最喜欢踢球的比最喜欢唱歌的多( )人.\n(4)你能提出一个数学问题并解答吗。",
+        "options":  [
+
+                    ],
+        "answer":  "画画;跳舞;70;5;喜欢画画的比喜欢跳舞的多多少人;25-10=15(人)",
+        "solution":  "【分析】(1)数一数正字,哪个项目正字最多,哪个项目正字最少即可解答;(2)把喜欢每个项目的人数相加可以求出二(1)班一共有多少人;(3)最喜欢踢球的人数与最喜欢唱歌的人数相减即可求出;(4)根据统计表提供的信息提出问题并解答,合理即可.\n【详解】(1)二(1)班最喜欢画画的人最多,最喜欢跳舞的人最少。(2)25+20+15+10=70(人),所以二(1)班一共有70人。(3)20-15=5(人),所以最喜欢踢球的比最喜欢唱歌的多5人。(4)喜欢画画的比喜欢跳舞的多多少人。(答案不唯一)25-10=15(人),答:喜欢画画的比喜欢跳舞的多15人。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "\"提问题\"\"填条件\"问题"
+                             ],
+        "source":  "21-22 二年级下·河南信阳·期末"
+    },
+    {
+        "id":  "495",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "东东对二(一)班学生喜欢的课外书进行了调查,统计结果如下。![](images/143753.png)\n(2)喜欢( )书的人数最多,喜欢( )书的人数最少.\n(3)喜欢故事书的人数比喜欢科技书的多( )人.\n(4)学校最近要购进一批课外书,你有什么建议。",
+        "options":  [
+
+                    ],
+        "answer":  "12;20;6;5;故事;作文;14;多进一些故事书,作文书少进一些。",
+        "solution":  "【分析】(1)数出每种书喜欢的人数填入统计表中即可;(2)比较各种书喜欢的人数多少即可得解;(3)用喜欢故事书的人数减去喜欢科技书的人数即可;(4)喜欢人数多的书可以多进一些,喜欢人数少的书可以少进一些;据此解答.\n【详解】(1)填表:漫画书12人,故事书20人,科技书6人,作文书5人。(2)20\u003e12\u003e6\u003e5,喜欢故事书的人数最多,喜欢作文书的人数最少;(3)20-6=14(人),喜欢故事书的人数比喜欢科技书的多14人;(4)多进一些故事书,作文书少进一些。(答案不唯一)",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "21-22 二年级下·天津蓟州·期末"
+    },
+    {
+        "id":  "496",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "下面是二(2)班同学读书情况(每人只能选一种)。![](images/143757.png)\n(1)喜欢科技书的比喜欢漫画的多( )人.\n(2)喜欢( )书的人数最多.\n(3)这个班一共有( )人.\n(4)从表中你发现了什么。",
+        "options":  [
+
+                    ],
+        "answer":  "4;故事;57;我发现喜欢童话的人数比喜欢漫画的人数多7人。",
+        "solution":  "【分析】(1)喜欢科技书的人数减喜欢漫画的人数等于喜欢科技书的比喜欢漫画的多人数;(2)比较表格中读书人数的大小,最大的就是喜欢的人数最多的;(3)把表格中所有的人数相加即可解答;(4)根据表格中数据进行总结即可。\r\n【详解】(1)12-8=4(人)。(2)16\u003e15\u003e12\u003e8\u003e6,喜欢故事书的人数最多。(3)16+12+8+15+6=57(人)。(4)我发现喜欢童话的人数比喜欢漫画的人数多7人。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "20-21 二年级下·河南安阳·期中"
+    },
+    {
+        "id":  "497",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "下面是二(2)班同学读书情况(每人只能选一种)。![](images/143801.png)\n(1)喜欢科技书的比喜欢漫画的多( )人.\n(2)喜欢( )书的人数最多.\n(3)这个班一共有( )人.\n(4)从表中你发现了什么。",
+        "options":  [
+
+                    ],
+        "answer":  "4;故事;57;我发现喜欢童话的人数比喜欢漫画的人数多7人。",
+        "solution":  "【分析】(1)喜欢科技书的人数减喜欢漫画的人数等于喜欢科技书的比喜欢漫画的多人数;(2)比较表格中读书人数的大小,最大的就是喜欢的人数最多的;(3)把表格中所有的人数相加即可解答;(4)根据表格中数据进行总结即可。(答案不唯一合理即可)\n【详解】(1)12-8=4(人)。(2)16\u003e15\u003e12\u003e8\u003e6,喜欢故事书的人数最多。(3)16+12+8+15+6=57(人)。(4)我发现喜欢童话的人数比喜欢漫画的人数多7人。(答案不唯一)",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "20-21 二年级下·河南安阳·期中"
+    },
+    {
+        "id":  "498",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "调查二(1)班同学最喜欢的歌曲情况.\n(1)请把下表填写完整。![](images/143806.png)\n(2)喜欢( )的人数最多,比喜欢《郊游》的多( )人.\n(3)二(1)班一共有( )人.\n(4)如果班级要参加歌咏比赛,你觉得最有可能选择哪首歌曲。请说明你的理由!",
+        "options":  [
+
+                    ],
+        "answer":  "14;21;9;《阿西里西》;7;44;《阿西里西》;喜欢《阿西里西》的人数最多",
+        "solution":  "【分析】(1)根据上图的题意:喜欢《郊游》的用△表示共14个人;喜欢《阿西里西》的用\"正\"字表示;《幸福拍手歌》用○表示,人数如下:(2)喜欢《阿西里西》的人数是21人,《郊游》的是14人,《幸福拍手歌》的是9人,所以《阿西里西》的人最多,比喜欢《郊游》的多,用喜欢《阿西里西》的人数减去喜欢《郊游》的人数即可。(3)把喜欢这三首歌的人数加起来就是全班总人数;(4)从上图中看出选择这首《阿西里西》歌曲人比较多,所以选择《阿西里西》.\n【详解】(1)《郊游》14个人,《阿西里西》21人,《幸福拍手歌》9人。(2)所以喜欢《阿西里西》的人最多;多21-14=7人。(3)共有14+21+9=44人。(4)喜欢《阿西里西》的人数最多,所以最有可能选《阿西里西》这首歌曲。(答案不唯一)",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "统计图表的综合应用"
+                             ],
+        "source":  "21-22 二年级下·福建泉州·期末"
+    },
+    {
+        "id":  "499",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "小明在统计他家人的年龄。下面是他做的统计表。![](images/143811.png)\n(1)妈妈不想告诉小明她的年龄,她说:\"17年后我比你爸小2岁.\"那么妈妈今年几岁。\n(2)再过10年,小明家里年龄最大的人会改变吗。\n(3)爷爷也想让小明猜一猜他的年龄。他说,\"假如现在有人们排成一个正方形做操,如果把这个方阵里面的人去掉一行,再去掉一列,则去掉了15人。这个方阵原来的人数就是我的年龄.\"那么爷爷多少岁。\n(4)弟弟比妈妈小几岁。",
+        "options":  [
+
+                    ],
+        "answer":  "36岁;不会;64岁;29岁",
+        "solution":  "【分析】(1)不过过去多少年,妈妈一直比爸爸小2岁,已知爸爸今年是38岁,则用38-2即可求出妈妈今年的年龄;(2)家里年龄最大的人是爷爷,爷爷的身高面貌不会有变化;(3)因为行数和列数一样,一行一列中有1个人是重复的,去掉了15人,所以两行一共有(15+1)人,也就是16人,用16/2即可求出每行每列的人数;然后用乘法即可求出方阵原来的人数;(4)用妈妈的年龄减去弟弟的年龄即可求出他们的年龄差.\n【详解】(1)38-2=36(岁),答:妈妈今年36岁。(2)家里年龄最大的人是爷爷,爷爷的身高面貌不会有变化;(3)15+1=16(人),16/2=8(人),8×8=64(人),答:爷爷64岁。(4)36-7=29(岁),答:弟弟比妈妈小29岁。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "21-22 二年级下·全国·单元测试"
+    },
+    {
+        "id":  "500",
+        "unit":  "第一单元 数据收集和整理",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "调查二(1)班喜欢的体育运动项目如下:![](images/143816.png)\n(2)三(1)班有( )名学生,喜欢( )人数最多,喜欢( )人数最少.\n(3)班上准备购买一批体育用品,你有什么建议。",
+        "options":  [
+
+                    ],
+        "answer":  "10;18;5;13;46;跳绳;篮球;喜欢跳绳的人数较多,建议多购买跳绳",
+        "solution":  "【分析】先根据统计图数出喜欢各项体育运动的人数,再比较人数多少,求出总人数,最后根据喜欢人数较多的项目提出购买建议。\r\n【详解】(1)填表:跳绳10人,踢球18人,篮球5人,跑步13人。(2)10+18+5+13=46(名),所以三(1)班有46名学生,喜欢跳绳人数最多,喜欢篮球人数最少。(3)因为喜欢跳绳的人数较多,所以建议多购买跳绳。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "20以内数的比大小"
+                             ],
+        "source":  "20-21 二年级下·贵州黔南·期末"
+    }
+]
diff --git "a/\344\272\214\345\271\264\347\272\247\351\242\230\351\233\206/\344\272\214\345\271\264\347\272\247\344\270\213/\344\272\214\345\271\264\347\272\247\344\270\213\347\254\254\344\270\203\345\215\225\345\205\203\344\270\207\344\273\245\345\206\205\346\225\260\347\232\204\350\256\244\350\257\206.json" "b/\344\272\214\345\271\264\347\272\247\351\242\230\351\233\206/\344\272\214\345\271\264\347\272\247\344\270\213/\344\272\214\345\271\264\347\272\247\344\270\213\347\254\254\344\270\203\345\215\225\345\205\203\344\270\207\344\273\245\345\206\205\346\225\260\347\232\204\350\256\244\350\257\206.json"
new file mode 100644
index 0000000000000000000000000000000000000000..a2cd7c3aa054c2b95283bde61972733a95203f23
--- /dev/null
+++ "b/\344\272\214\345\271\264\347\272\247\351\242\230\351\233\206/\344\272\214\345\271\264\347\272\247\344\270\213/\344\272\214\345\271\264\347\272\247\344\270\213\347\254\254\344\270\203\345\215\225\345\205\203\344\270\207\344\273\245\345\206\205\346\225\260\347\232\204\350\256\244\350\257\206.json"
@@ -0,0 +1,8640 @@
+[
+    {
+        "id":  "1",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "一个三位数，十位上的数字是5，百位上的数字比十位上的数字多2，个位上的数字比十位上的数字少3，这个数是( )。",
+        "options":  [
+                        "A. 752",
+                        "B. 572",
+                        "C. 725"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】由题意得，一个三位数，十位上的数字是5，百位上的数字比十位上的数字多2,5+2=7，所以这个数的百位上是7;个位上的数字比十位上的数字少3,5-3=2，即这个数的个位上是2。所以这个数是752。\n\n【详解】由分析得，这个三位数是752。故答案为:A",
+        "knowledge_points":  [
+                                 "1000以内数的组成"
+                             ],
+        "source":  "25-26 三年级上·云南曲靖·阶段练习"
+    },
+    {
+        "id":  "2",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "选择题",
+        "difficulty":  0.94,
+        "question":  "下面各数中，一个零也不读的是( )。",
+        "options":  [
+                        "A. 305",
+                        "B. 350",
+                        "C. 503"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】1000以内数的读法核心是从高位读起，按数位依次读取，末尾的0不读，中间有0需读\"零\"。根据读数的法则进行判断。\n\n【详解】由分析可得:A。305读作：三百零五，中间的0要读;B。350读作：三百五十，末尾的0不读;C。503读作：五百零三，中间的0要读。故答案为:B",
+        "knowledge_points":  [
+                                 "1000以内数的读，写法"
+                             ],
+        "source":  "25-26 三年级上·云南曲靖·阶段练习"
+    },
+    {
+        "id":  "3",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "小华家，小明家和学校都在笔直的中山路的一旁，小华家距离学校298米，小明家距离学校374米。小华家与小明家的距离示意图不可能是( ).\n![](images/fec84dbaac2111ea6db3b5c90dd5253b2c27adf03a147d2ce361b26d9ae08db8.jpg)",
+        "options":  [
+
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】由题可知，小明家到学校的距离比小华家到学校的距离远，再结合三个选项的示意图，将小明家和小华家到学校的图上距离进行比较，找出不可能的示意图。\n\n【详解】A。小明家到学校的距离比小华家到学校的距离远；B。小明家到学校的距离比小华家到学校的距离近；C。小明家到学校的距离比小华家到学校的距离远。所以小华家与小明家的距离示意图不可能是B。故答案为：B",
+        "knowledge_points":  [
+                                 "1000以内数的比大小",
+                                 "米的认识"
+                             ],
+        "source":  "24-25 三年级上·湖北荆州·期中"
+    },
+    {
+        "id":  "4",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "下面哪个数中的\"6\"与\"5613\"中的\"6\"表示的意义一样( )。",
+        "options":  [
+                        "A. ![](images/9d7b158bd0358e4959011bc775385a1ee17732fb5fcd98f62df48ee6ee7bb8c3.jpg)",
+                        "B. ![](images/d7b5ed09a88a0a5132c194499bccaec9a420239168556648a5e7317d7bcaa30b.jpg)",
+                        "C. 2516"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】一个四位数，从右往左依次为个位，十位，百位，千位。千位是几表示几个千，百位是几表示几个百，十位是几表示几个十，个位是几表示几个一;5613中\"6\"在百位上，表示6个百，逐项分析各个选项，找出正确答案即可解答。算盘上一个上珠表示5，一个下珠表示1。\n\n【详解】A。:千位上是7，表示7个千，百位上是6，表示6个百，十位上是1，表示1个十，个位上是2，表示2个一。B。:百位上是4，表示4个百，十位上是6，表示6个十。C。2516：千位上是2，表示2个千，百位上是5，表示5个百，十位上是1，表示1个十，个位上是6，表示6个一。选项中A的\"6\"与\"5613\"中的\"6\"表示的意义一样，都表示6个百。故答案为:A",
+        "knowledge_points":  [
+                                 "万以内数的组成"
+                             ],
+        "source":  "24-25二年级下·四川南充·期末"
+    },
+    {
+        "id":  "5",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "下图中箭头所指的点大约表示( ).\n![](images/35520798479864ffa592f1add38e03d44fc9d8f991b02bfb06975496a233d17f.jpg)",
+        "options":  [
+                        "A. 5500",
+                        "B. 7500",
+                        "C. 9500"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】在图中，把5000到10000之间平均分成5份，然后找一找箭头所指的点大约指向的数是多少即可。\n\n【详解】如下图，箭头所指的点大约表示(7500)。![](images/a8471e16db0624418bb9712fd36a575a6f5f4e05dcbf7a0bff9d179c1f0c7b35.jpg)故答案为:B",
+        "knowledge_points":  [
+                                 "万以内数的估计"
+                             ],
+        "source":  "24-25 二年级下·四川南充·期末"
+    },
+    {
+        "id":  "6",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "商场周年庆进行抽奖活动，获奖号码可能是( ).\n![](images/3f5e709856a34f57505b731dd1cef6429f1757d3d3a6430239387ff3c39ab514.jpg)",
+        "options":  [
+                        "A. 3920",
+                        "B. 3480",
+                        "C. 2890"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】获奖号码大于3000，小于4000，说明这个号码是三千多，故2890可以排出掉，分别找出3920和3480最接近的整千整百数，再分别和3500相减，差最小的即是最接近的，也是获奖号码。据此解答。\n\n【详解】由分析可得:3920≈3900,3480≈3500;3900-3500=400;3500-3500=0;0<400,3480最接近3500;获奖号码可能是3480。故答案为:B",
+        "knowledge_points":  [
+                                 "万以内数加减法的估算",
+                                 "整百数",
+                                 "几百几十数的加减法口算",
+                                 "万以内数的估计",
+                                 "万以内数的大小比较"
+                             ],
+        "source":  "24-25 二年级下·甘肃庆阳·期末"
+    },
+    {
+        "id":  "7",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "下列各数中，一个\"零\"都不读的是( )。",
+        "options":  [
+                        "A. 5600",
+                        "B. 5006",
+                        "C. 5060"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】一个整数，从右往左依次为个位，十位，百位，千位。读数时，从高位读起，按照数位顺序读。千位是几就读几千，百位是几就读几百。中间有一个0或两个0，只读一个零;末尾不管有几个0，都不读，由此解答。\n\n【详解】A。5600读作五千六百，符合题意;B。5006读作五千零六，不符合题意;C。5060读作五千零六十，不符合题意。则一个\"零\"都不读的是5600。故答案为:A",
+        "knowledge_points":  [
+                                 "万以内数的读，写法"
+                             ],
+        "source":  "24-25二年级下·山西阳泉·期末"
+    },
+    {
+        "id":  "8",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "妈妈带了1000元，想买下面两件物品，够吗。( )\n![](images/17ad278a236847821db03eaa8a50b913.png)",
+        "options":  [
+                        "A. 肯定不够",
+                        "B. 肯定够了",
+                        "C. 无法确定"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】根据题意，将两件物品的价格看成与之接近的整百数，再相加计算出总钱数和1000元比较大小即可解答。\n\n【详解】把电风扇的价格看成400元;把电饭煲的价格看成600元，两件物品的价格都估大了。400+600=1000(元),1000=1000，则实际的价格要小于1000元。则妈妈带了1000元，想买下面两件物品，肯定够了。故答案为:B",
+        "knowledge_points":  [
+                                 "万以内数加减法的估算"
+                             ],
+        "source":  "24-25 二年级下·云南文山·期末"
+    },
+    {
+        "id":  "9",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "下列各数中一个零都不读的是( )。",
+        "options":  [
+                        "A. 4500",
+                        "B. 4005",
+                        "C. 4050"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】一个四位数，从右往左依次为个位、十位、百位、千位；读数时，从高位读起，按照数位顺序读。千位是几就读几千，百位是几就读几百，十位上是几就读几十，个位上是几就读几，中间有一个0或两个0，只读一个零；末尾不管有几个0，都不读。\n\n【详解】A。4500读作四千五百，末尾的零都不读，符合题意；B。4005读作四千零五，中间不管有几个零，只读一个零，不符合题意；C。4050读作四千零五十，末尾的零不读，中间的零要读，不符合题意。故答案为：A",
+        "knowledge_points":  [
+                                 "万以内数的读，写法"
+                             ],
+        "source":  "24-25 二年级下·河北保定·期末"
+    },
+    {
+        "id":  "10",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "下列数中，比6000小，比3500大的是( )。",
+        "options":  [
+                        "A. 5098",
+                        "B. 6001",
+                        "C. 3050"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】比较数的大小时，位数多的数就大，位数相同比较最高位，最高位大的数就大，最高位相同就比较下一位，直到比出大小为止。\n\n【详解】A。5098的千位数字是5,3500的千位数字是3,6000的千位数字是6,3<5<6，所以3500<5098<6000，符合题意;B。6001和6000比，千位，百位和十位的数字都相同，比较个位1>0，所以6001>6000，不符合题意;C。3050和3500比，千位数字相同，比较百位0<5，所以3050<3500，不符合题意;故答案为:A",
+        "knowledge_points":  [
+                                 "万以内数的大小比较"
+                             ],
+        "source":  "24-25 二年级下·河北保定·期末"
+    },
+    {
+        "id":  "11",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "如图，箭头所指的点表示的数大约是( ).\n![](images/6110d8a13e29952fc31e34cafb84979898fc0d9920ab3b93f70a92494f79edb9.jpg)",
+        "options":  [
+                        "A. 6000",
+                        "B. 7800",
+                        "C. 9100"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】通过观察，数轴上的一格表示5000，箭头所指的大概在5000和10000中间的位置,5000的一半是2500,5000+2500=7500,7800和7500最相近，据此可选择。\n\n【详解】由分析可得：箭头所指的点表示的数大约是7800。故答案为:B",
+        "knowledge_points":  [
+                                 "整百数",
+                                 "几百几十数的加减法口算",
+                                 "万以内数的估计"
+                             ],
+        "source":  "24-25二年级下·湖北恩施·期末"
+    },
+    {
+        "id":  "12",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "由5个十和7个千组成的数是( )。",
+        "options":  [
+                        "A. 700",
+                        "B. 5070",
+                        "C. 7050",
+                        "D. 7500"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】一个四位数，从右往左依次为个位，十位，百位，千位;千位是几表示几个千，百位是几表示几个百，十位是几表示几个十，个位是几表示几个一。这个数千位是7，十位是5;据此解答。\n\n【详解】由分析可得：由5个十和7个千组成的数是7050。故答案为:C",
+        "knowledge_points":  [
+                                 "万以内数的组成"
+                             ],
+        "source":  "24-25二年级下·福建龙岩·期末"
+    },
+    {
+        "id":  "13",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "下面数中的\"7\"与6278中的\"7\"表示的意义相同的是( )。",
+        "options":  [
+                        "A. 7635",
+                        "B. 2793",
+                        "C. 1687",
+                        "D. 2073"
+                    ],
+        "answer":  "D",
+        "solution":  "【分析】从右边起，第一位是个位，个位上是几就表示几个一;第二位是十位，十位上是几就表示几个十;第三位是百位，百位上是几就表示几个百;第四位是千位，千位上是几就表示几个千，据此判断出各个数字中的\"7\"分别表示多少，再进行选择即可。\n\n【详解】6278中的\"7\"表示7个十。A。7635中的\"7\"表示7个千;B。2793中的\"7\"表示7个百;C。1687中的\"7\"表示7个一;D。2073中的\"7\"表示7个十。故答案为:D",
+        "knowledge_points":  [
+                                 "万以内数的组成"
+                             ],
+        "source":  "24-25二年级下·福建龙岩·期末"
+    },
+    {
+        "id":  "14",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "下面各数中，一个0都不需要读出来的数是( )。",
+        "options":  [
+                        "A. 3003",
+                        "B. 3030",
+                        "C. 3000"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】一个四位数，从右往左依次是个位，十位，百位，千位，读数时，从高位读起，千位上是几就读几千，百位上是几就读几百，十位上是几就读几十，个位上是几就读几，中间有一个0或者两个0，只读一个\"零\"，末尾不管有几个0都不读;由此解答。\n\n【详解】A。3003读作三千零三，读了一个0，不符合题意;B。3030读作三千零三十，读了一个0，不符合题意;C。3000读作三千，一个0都不读，符合题意;故答案为:C",
+        "knowledge_points":  [
+                                 "万以内数的读，写法"
+                             ],
+        "source":  "24-25二年级下·山东菏泽·期末"
+    },
+    {
+        "id":  "15",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "下列各数中一个零也不读的数是( )。",
+        "options":  [
+                        "A. 9001",
+                        "B. 9100",
+                        "C. 9010"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】万以内整数的读法：从万位起，按照数位顺序读。千位上是几就读几千，百位上是几就读几百。十位上是几就读几十，个位上是几就读几。末尾的0不需要读出，中间的0只读一个零。据此读出各数即可。\n\n【详解】A。9001读作：九千零一，只读一个零，不符合题意;B。9100读作：九千一百，一个零也不读，符合题意;C。9010读作：九千零一十，只读一个零，不符合题意。故答案为:B",
+        "knowledge_points":  [
+                                 "万以内数的读，写法"
+                             ],
+        "source":  "24-25 二年级下·贵州铜仁·期末"
+    },
+    {
+        "id":  "16",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "13个一是□,13个十是□,填入的数正确的是( )。",
+        "options":  [
+                        "A. 13,1300",
+                        "B. 13,130",
+                        "C. 130,1300"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】根据整数的组成可知:13个一是13;10个十是100,3个十是30，所以13个十是130。据此解答即可。\n\n【详解】据分析可知:13个一是13,13个十是130。故答案为:B",
+        "knowledge_points":  [
+                                 "20以内数的组成",
+                                 "1000以内数的组成"
+                             ],
+        "source":  "24-25二年级下·广东江门·期末"
+    },
+    {
+        "id":  "17",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "下面各数中的\"7\"表示7个百的是( )。",
+        "options":  [
+                        "A. 3570",
+                        "B. 7011",
+                        "C. 6720"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】一个四位数，从右往左依次为个位，十位，百位，千位;千位是几表示几个千，百位是几表示几个百，十位是几表示几个十，个位是几表示几个一。百位上的\"7\"表示7个百;从各项中找出百位是7的数，即是符合题意的，据此解答。\n\n【详解】由分析可得:A。3570:7在十位上，不符合题意;B。7011:7在千位上，不符合题意;C。6720:7在百位上，符合题意。下面各数中的\"7\"表示7个百的是6720。故答案为:C",
+        "knowledge_points":  [
+                                 "万以内数的组成"
+                             ],
+        "source":  "24-25二年级下·四川凉山·期末"
+    },
+    {
+        "id":  "18",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "与2999相邻的两个数是( )。",
+        "options":  [
+                        "A. 298和300",
+                        "B. 2998和3000",
+                        "C. 298和3000",
+                        "D. 2998和300"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】根据题意，与2999相邻的数，一个是比它多1，另一个是比它少1的数。\n\n【详解】2999+1=3000,2999-1=2998，所以，与2999相邻的两个数是2998和3000。故答案为:B",
+        "knowledge_points":  [
+                                 "数万以内的数"
+                             ],
+        "source":  "25-26三年级上·湖南永州·阶段练习"
+    },
+    {
+        "id":  "19",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "下面只读一个零的数是( )。",
+        "options":  [
+                        "A. 4500",
+                        "B. 4005",
+                        "C. 4520"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】万以内的数的读法：读数时，从高位读起，按照数位顺序读;千位上是几就读几千，百位上是几就读几百，十位上是几就读几十，个位上是几就读几;中间有一个0或两个0，都只读一个零;末尾不管有几个0，都不读。据此解答。\n\n【详解】A。4500读作：四千五百，一个零都不读。不满足题意。B。4005读作：四千零五，只读了一个零。满足题意。C。4520读作：四千五百二十，一个零都不读。不满足题意。故答案为:B",
+        "knowledge_points":  [
+                                 "万以内数的读，写法"
+                             ],
+        "source":  "25-26 三年级上·黑龙江佳木斯·开学考试"
+    },
+    {
+        "id":  "20",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "5472>5□76,□里最大能填( )。",
+        "options":  [
+                        "A. 3",
+                        "B. 4",
+                        "C. 5"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】整数比较大小方法:①位数多的数大于位数少的数;②位数相同的，先比较最高位上的数，最高位上大的数就大，最高位数相同的，就比较下一位，以此类推。\n\n【详解】若□填大于4的数，即5,6,7。,千位相同，则5□76的百位大于4,5□76>5472，不符合题意;若□=4，比较5472和5476的大小，千位相同，百位和十位相同，个位2<6，因此5472<5476，不符合题意;若□填小于4的数，即3,2,1,0，千位相同，则5□76的百位小于4,5472>5□76，符合题意。□可以是0,1,2,3，其中最大的是3.5472>5□76,□里最大能填3。故答案为:A",
+        "knowledge_points":  [
+                                 "万以内数的大小比较"
+                             ],
+        "source":  "24-25 二年级下·山东菏泽·期末"
+    },
+    {
+        "id":  "21",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "在6060这个数中，左边的\"6\"表示( )。",
+        "options":  [
+                        "A. 6个千",
+                        "B. 6个百",
+                        "C. 6个十"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】一个四位数，从右往左依次为个位，十位，百位，千位，千位是几表示几个千，百位是几表示几个百，十位是几表示几个十，个位是几表示几个一，据此解答。\n\n【详解】在6060这个数中，左边的\"6\"在千位上，表示6个千。故答案为:A",
+        "knowledge_points":  [
+                                 "万以内数的组成"
+                             ],
+        "source":  "24-25二年级下·山东菏泽·期末"
+    },
+    {
+        "id":  "22",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "39□5<3946,□里最大能填( )。",
+        "options":  [
+                        "A. 3",
+                        "B. 4",
+                        "C. 9"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】位数多的数大于位数少的数;位数相同的数，要从高位开始一级一级的往下比较大小。\n\n【详解】由分析可得:39□5<3946，则前面两位相同，比较第三位，右边是4，则左边应是4或3，则比较第4位,5<6，则第三位最大为4。故答案为:B",
+        "knowledge_points":  [
+                                 "万以内数的大小比较"
+                             ],
+        "source":  "24-25 二年级下·浙江杭州·期末"
+    },
+    {
+        "id":  "23",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "下面哪个数一个\"0\"都不读。( )",
+        "options":  [
+                        "A. 3060",
+                        "B. 3006",
+                        "C. 3600"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】一个四位数，从右往左依次是个位，十位，百位，千位，读数时，从高位读起，千位上是几就读几千，百位上是几就读几百，十位上是几就读几十，个位上是几就读几，中间有一个0或者两个0，只读一个\"零\"，末尾不管有几个0都不读;由此解答。\n\n【详解】A。3060读作：三千零六十，读了一个0，不符合题意;B。3006读作：三千零六，读了一个0，不符合题意;C。3600读作：三千六百，一个0也不读，符合题意;故答案为:C",
+        "knowledge_points":  [
+                                 "万以内数的读，写法"
+                             ],
+        "source":  "24-25 二年级下·江西九江·期末"
+    },
+    {
+        "id":  "24",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "妈妈买一台286元的电扇和一台589元的烤箱，要带多少元才够。( )",
+        "options":  [
+                        "A. 700",
+                        "B. 800",
+                        "C. 900"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】把电扇和烤箱的价格看成与之接近的整百或整百整十数，相加求出和，就是买两件商品要带多少元，据此解答。\n\n【详解】把286元看成300元，把589元看成600元,300+600=900(元),妈妈买一台286元的电扇和一台589元的烤箱，要带900元才够。故答案为:C",
+        "knowledge_points":  [
+                                 "万以内数加减法的估算",
+                                 "整百数",
+                                 "几百几十数的加减法口算"
+                             ],
+        "source":  "24-25 二年级下·江西九江·期末"
+    },
+    {
+        "id":  "25",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "下列说法正确的是( )。",
+        "options":  [
+                        "A. 用\"正\"字来记录数据，一个\"正\"字表示5个数据",
+                        "B. 45÷5和54÷9可以用同一句乘法口诀计算",
+                        "C. 512,305,850这三个数中的\"5\"表示的意义相同"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】分析各项说法，找出说法正确的即可;A.\"正\"字统计法说明:1画代表1个数据，一个\"正\"字5画，代表5个数据;说法正确，符合题意;B。45÷5用的口诀是五九四十五,54÷9用的口诀是六九五十四，不是用的同一句乘法口诀计算;说法错误，不符合题意;C。512中的5在百位上，表示5个百;305中的5在个位上，表示5个一;850中的5在十位上，表示5个十;这三个数中的\"5\"表示的意义不同;说法错误，不符合题意;据此可选择。\n\n【详解】由分析可得：说法正确的是用\"正\"字来记录数据，一个\"正\"字表示5个数据。故答案为:A",
+        "knowledge_points":  [
+                                 "用7~9的乘法口诀求商",
+                                 "1000以内数的组成",
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "24-25 二年级下·青海果洛·期末"
+    },
+    {
+        "id":  "26",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "某电器店第一季度卖出597台电视，第二季度卖出306台，两个季度大约共卖出( )台。",
+        "options":  [
+
+                    ],
+        "answer":  "900",
+        "solution":  "【分析】第一季度卖出的电视数加第二季度卖出的电视数等于两个季度卖出的电视数，估算的时候接近哪个整十或整百的数就估算成哪个数进行计算。\n\n【详解】由分析可得:597+306≈600+300=900(台),某电器店第一季度卖出597台电视，第二季度卖出306台，两个季度大约共卖出900台。",
+        "knowledge_points":  [
+                                 "万以内数加减法的估算"
+                             ],
+        "source":  "24-25 三年级上·云南曲靖·期中"
+    },
+    {
+        "id":  "27",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在括号里填上“>”“<”或“=”。\n1米( )1厘米  115厘米( )2米  300厘米( )3米\n99厘米( )9米  80厘米( )8米  500厘米( )7米",
+        "options":  [
+
+                    ],
+        "answer":  ">;<;=;<;<;<",
+        "solution":  "【分析】单位相同的直接比较，单位不同的根据1米=100厘米统一单位再比较。比较数的大小时，位数多的数就大；位数相同比较最高位，最高位大的数就大，最高位相同比较下一位，直到比较出结果为止。\n\n【详解】1米=100厘米；100厘米>1厘米，则1米>1厘米；115厘米可以分成100厘米和15厘米；100厘米=1米；2米=1米+1米，两边都有1米，则比较15厘米和1米即可；15厘米<100厘米=1米，则115厘米<2米；300厘米=3米；99厘米<100厘米=1米；1米<9米，则99厘米<9米；80厘米<100厘米=1米；1米<8米，则80厘米<8米；500厘米=5米；5米<7米，则500厘米<7米。",
+        "knowledge_points":  [
+                                 "厘米和米之间的进率与换算"
+                             ],
+        "source":  "25-26 二年级上·全国·单元测试"
+    },
+    {
+        "id":  "28",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "用2,4,8,0组成一个最大的四位数是( ),最小的四位数是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "8420;2048",
+        "solution":  "【分析】要想组成最大的四位数，要把数字按照从大到小的顺序从高位到低位排下来;要想组成最小的四位数，要把数字按照从小到大的顺序从高位到低位排下来，但是最高位不能是零，据此解答即可。\n\n【详解】用2,4,8,0组成一个最大的四位数是8420，最小的四位数是2048。",
+        "knowledge_points":  [
+                                 "万以内数的大小比较",
+                                 "万以内数的组成"
+                             ],
+        "source":  "24-25 三年级上·广东江门·期中"
+    },
+    {
+        "id":  "29",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "用2,0,5三个数字可以组成( )个不同的三位数，其中最大的是( ),最小的是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "4;520;205",
+        "solution":  "【分析】一个三位数，从右往左依次为个位，十位，百位;组成三位数时，将其中一个数字写在百位(最高位不能是0),另外两个数字分别写在十位，个位，由此写出组成的三位数;比较数的大小时，位数多的数就大，位数相同比较最高位，最高位大的数就大，最高位相同就比较下一位，直到比出大小为止。\n\n【详解】组成的三位数有:205,250,502,520;205<250<502<520;所以用2,0,5三个数字可以组成4个不同的三位数，其中最大的是520，最小的是205。",
+        "knowledge_points":  [
+                                 "1000以内数的比大小",
+                                 "1000以内数的组成"
+                             ],
+        "source":  "25-26 三年级上·云南曲靖·阶段练习"
+    },
+    {
+        "id":  "30",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在括号里填上“>”“<”或“=”。\n426( )462  780( )870  999( )1000",
+        "options":  [
+
+                    ],
+        "answer":  "<;<;<",
+        "solution":  "【分析】比较数的大小时，位数多的数就大；位数相同比较最高位，最高位大的数就大；最高位相同比较下一位，直到比较出结果为止。由此解答。\n\n【详解】426和462位数相同，百位数相同，十位数2<6，故426<462；780和870位数相同，百位数7<8，故780<870；999是三位数，1000是四位数，故999<1000。",
+        "knowledge_points":  [
+                                 "1000以内数的比大小"
+                             ],
+        "source":  "25-26三年级上·云南曲靖·阶段练习"
+    },
+    {
+        "id":  "31",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "352是由( )个百,( )个十和( )个一组成的。",
+        "options":  [
+
+                    ],
+        "answer":  "3;5;2",
+        "solution":  "【分析】万以内的数位从右往左数，第一位是个位，第二位是十位，第三位是百位，第四位是千位，看清数字在此数的什么数位上和这个数位的计数单位，它就表示有几个这样的计数单位，由此解答。\n\n【详解】根据分析可知,352是由3个百,5个十和2个一组成的。",
+        "knowledge_points":  [
+                                 "1000以内数的组成"
+                             ],
+        "source":  "25-26 三年级上·云南曲靖·阶段练习"
+    },
+    {
+        "id":  "32",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "书店，学校，超市在同一条路上，书店离学校280米，超市离学校540米，书店离超市( )米。",
+        "options":  [
+
+                    ],
+        "answer":  "820或260",
+        "solution":  "【分析】书店，超市有可能在学校的两边，如图：书店280米学校540米超市，书店距超市(280+540)米。书店，超市也有可能在学校的同一侧，如图：学校280米书店540米超市，书店距离超市(540-280)米。\n\n【详解】540+280=820(米),540-280=260(米),书店，学校，超市在同一条路上，书店离学校280米，超市离学校540米，书店离超市820米或260米。",
+        "knowledge_points":  [
+                                 "整百数",
+                                 "几百几十数的加减法口算"
+                             ],
+        "source":  "24-25三年级上·福建漳州·期中"
+    },
+    {
+        "id":  "33",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "选择题",
+        "difficulty":  0.94,
+        "question":  "一个三位数，百位上是5，十位上是0，个位上是7，这个数是( ),与它相邻的两个数分别是( )和( )。",
+        "options":  [
+
+                    ],
+        "answer":  "507;506;508",
+        "solution":  "【分析】写数时，从高位写起，百位上是几就在百位上写几，十位上是几就在十位上写几，个位上是几就在个位上写几。相邻的两个自然数相差1，求一个数相邻的两个数，就是用这个数减去1和加上1。\n\n【详解】(1)根据题干可知是一个三位数，百位上是5，十位上是0，个位上是7，所以这个数是507。(2)求与507相邻的两个数，用507减去1是506，用507加上1是508。一个三位数，百位上是5，十位上是0，个位上是7，这个数是507，与它相邻的两个数分别是506和508。",
+        "knowledge_points":  [
+                                 "1000以内数的组成"
+                             ],
+        "source":  "25-26 三年级上·广东广州·期中"
+    },
+    {
+        "id":  "34",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "一个三位数，百位上是7，十位上的数字比百位上少3，个位上是0，这个数是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "740",
+        "solution":  "【分析】一个三位数，从右往左依次是个位，十位，百位。数位上是几，就在那一位上写几。据此解答即可。\n\n【详解】百位上是7。十位上的数字比百位上少3,7-3=4，所以十位上是4。个位上是0。因此，这个数是740。",
+        "knowledge_points":  [
+                                 "万以内数的组成"
+                             ],
+        "source":  "25-26 三年级上·广东韶关·期中"
+    },
+    {
+        "id":  "35",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "一个三位数，百位上是4，十位上是5，个位上是0，这个数是( ),读作( )。",
+        "options":  [
+
+                    ],
+        "answer":  "450;四百五十",
+        "solution":  "【分析】从高位开始写起，每个数位上是几就写几，哪个数位上一个计数单位也没有写0;1000以内数的读，写法：从最高位开始读，百位上是几就读几百，十位上是几就读几十，个位上是几就读几，中间不管有几个0只需要读一次，末尾的0不用读。据此解答。\n\n【详解】由分析可知：一个三位数，百位上是4，十位上是5，个位上是0，这个数是450，读作四百五十。",
+        "knowledge_points":  [
+                                 "1000以内数的组成",
+                                 "1000以内数的读，写法"
+                             ],
+        "source":  "25-26 三年级上·甘肃天水·阶段练习"
+    },
+    {
+        "id":  "36",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "一个三位数，个位上是5，十位上是0，百位上是7，这个数是( ),读作( )。",
+        "options":  [
+
+                    ],
+        "answer":  "705;七百零五",
+        "solution":  "【分析】万以内的数的读法：读数时，从高位读起，按照数位顺序读;千位上是几就读几千，百位上是几就读几百，十位上是几就读几十，个位上是几就读几;中间有一个0或两个0，都只读一个零;末尾不管有几个0，都不读。由题意得，一个三位数，个位上是5，十位上是0，百位上是7，那么这个数是705.705读作：七百零五。\n\n【详解】一个三位数，个位上是5，十位上是0，百位上是7，这个数是705，读作：七百零五。",
+        "knowledge_points":  [
+                                 "万以内数的读，写法"
+                             ],
+        "source":  "25-26 三年级上·甘肃天水·阶段练习"
+    },
+    {
+        "id":  "37",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "一百一百地数,10个一百是( ),1000里有( )个10，与999相邻的两个数是( )和( )。",
+        "options":  [
+
+                    ],
+        "answer":  "1000;100;998;1000",
+        "solution":  "【分析】1个一百是100,2个一百是200。10个一百是1000;10个十是100,100个十是1000;和999相邻的两个数分别是:999前面一个数和999后面的一个数;据此解答。\n\n【详解】由分析可得：一百一百地数,10个一百是1000,1000里有100个10，与999相邻的两个数是998和1000。",
+        "knowledge_points":  [
+                                 "相邻的数",
+                                 "1000以内数的组成",
+                                 "数1000以内的数"
+                             ],
+        "source":  "24-25 二年级下·四川南充·期末"
+    },
+    {
+        "id":  "38",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "由8个千,5个十组成的数是( ),它是( )位数，它的最高位是( )位。( )个百是7600，和它相邻的数是( )和( )。",
+        "options":  [
+
+                    ],
+        "answer":  "8050;四;千;76;7599;7601",
+        "solution":  "【分析】一个四位数，从右往左依次为个位，十位，百位，千位。万以内数的写法：写数时，从高位写起，几个千就在千位上写几，几个百就在百位上写几，几个十就在十位上写几，几个一就在个位上写几，哪一位上一个数字也没有就写\"0\"占位;一个整数，有几个数字组成就是几位数;最左边的那一位是它的最高位。1000里面有10个百，则,7000里面有70个百，且600里面有6个百,70个百和6个百合起来是76个百,7600里面有76个百，即76个百是7600;数数时,7600的前一个数是7599，后一个数是7601，故和7600相邻的数是7599和7601。\n\n【详解】由8个千,5个十组成的数是8050，它是四位数，它的最高位是千位。76个百是7600，和它相邻的数是7599和7601。",
+        "knowledge_points":  [
+                                 "万以内数的组成",
+                                 "万以内数的读，写法",
+                                 "数万以内的数"
+                             ],
+        "source":  "24-25 二年级下·湖北省直辖县级单位·期末"
+    },
+    {
+        "id":  "39",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "( )个百,( )个十,( )个一组成的数是654。",
+        "options":  [
+
+                    ],
+        "answer":  "6;5;4",
+        "solution":  "【分析】百位上的计数单位是百，十位上的计数单位是十，个位上的计数单位是个(一),654中,6在百位上,5在十位上,4在个位上，哪个数位上是几，就有几个对应的计数单位，据此解答。\n\n【详解】6个百,5个十,4个一组成的数是654。",
+        "knowledge_points":  [
+                                 "1000以内数的组成"
+                             ],
+        "source":  "24-25 四年级上·山东德州·期中"
+    },
+    {
+        "id":  "40",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "下面的数写作( ),它是由( )个千,( )个百,( )个十和( )个一组成的.\n![](images/bdc402726c774bee347033a2014fc418651e75bc2679d7a3ec8cca951e65d442.jpg)",
+        "options":  [
+
+                    ],
+        "answer":  "3745;3;7;4;5",
+        "solution":  "【分析】一个整数，从右往左依次为个位，十位，百位，千位。写数时，从高位写起，按照数位顺序写;有几个千就在千位写几，有几个百就在百位写几。中间或末尾哪一位上一个也没有，就在那一位上写0。算盘上1个上珠表示5,1个下珠表示1，由此解答。\n\n【详解】由分析得：千位有3个下珠，表示3个千(3000);百位有1个上珠,2个下珠，表示7个百(700);十位有4个下珠，表示4个十(40);个位有1个上珠，表示5个一(5)。则下面的数写作3745，它是由3个千,7个百,4个十和5个一组成的。![](images/7229e0e0c6de4507d6dc5517086401dfdcc18867c5ffbcea7ab2298891a82879.jpg)",
+        "knowledge_points":  [
+                                 "万以内数的组成",
+                                 "万以内数的读，写法",
+                                 "算盘的认识与使用"
+                             ],
+        "source":  "24-25 二年级下·云南文山·期末"
+    },
+    {
+        "id":  "41",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "南京长江大桥铁路桥长6772米，公路桥长4589米。“6772”读作( )；用“↑”标出4589的大致位置。\n![](images/e68adf00fdf6bb2a16b072460a880c6ef94cc1663c694ab1be47c81c89805bf2.jpg)",
+        "options":  [
+
+                    ],
+        "answer":  "六千七百七十二;图见详解",
+        "solution":  "【分析】读一个四位数，从高位往低位读，千位上的数读作几千，百位上的数读作几百，十位上的数读作几十，个位上的数读作几，中间的一个0或连续两个0，都只读一个“零”，末尾的0不用读。4000到5000之间相差1000，且有10小格，则每小格表示100，从4000开始往后数6小格就表示4600，4589比4600小一点，故“↑”标在4600的左边一点即可表示4589的大致位置。\n\n【详解】南京长江大桥铁路桥长6772米，公路桥长4589米。“6772”读作六千七百七十二。用“↑”标出4589的大致位置如下：![](images/b427b102dc62e5f49481d3790d4c9d8597a40163bc97d110b7186d2f43cc43c9.jpg)",
+        "knowledge_points":  [
+                                 "万以内数的估计",
+                                 "万以内数的大小比较",
+                                 "万以内数的读，写法"
+                             ],
+        "source":  "24-25 二年级下·湖北省直辖县级单位·期末"
+    },
+    {
+        "id":  "42",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "下图表示的数是( ),读作( ),它接近的整千数是( ),百位上是( ),表示( ).\n![](images/6c2940b5c495698328cb3e414fb4bea3f8511cb609ef6b0cdbcecb5e2a1c1455.jpg)",
+        "options":  [
+
+                    ],
+        "answer":  "1827;一千八百二十七;2000;8;8个百",
+        "solution":  "【分析】算盘上一个上珠表示5，一个下珠表示1。算盘千位上有1个下珠，表示1个千;百位上有1个上珠和3个下珠，表示8个百;十位上有2个下珠，表示2个十;个位上有1个上珠和2个下珠，表示7个一，据此写出这个数。读数时，从高位读起，百位上是几就读几百，十位上是几就读几十，个位上是几就读几;中间有一个0，读作零，末尾不管几个0，都不读。据此结合题干要求进行解答即可。\n\n【详解】图中表示的数是(1827),读作(一千八百二十七),它最接近的整千数是(2000),百位上是(8),表示(8个百)。",
+        "knowledge_points":  [
+                                 "万以内数的组成",
+                                 "万以内数的读，写法",
+                                 "算盘的认识与使用"
+                             ],
+        "source":  "24-25 二年级下·福建龙岩·期末"
+    },
+    {
+        "id":  "43",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "北京某高速路口收费站昨天通过8004辆汽车，约是( )辆;一本书有294页，约是( )页。(取整百或整千数)",
+        "options":  [
+
+                    ],
+        "answer":  "8000;300",
+        "solution":  "【分析】估算时，一般要根据\"四舍五入\"法把数看作是整十，整百，整千。的数;据此解答即可。\n\n【详解】8004≈8000,294≈300，北京某高速路口收费站昨天通过8004辆汽车，约是8000辆;一本书有294页，约是300页。",
+        "knowledge_points":  [
+                                 "1000以内数的估计",
+                                 "万以内数的估计"
+                             ],
+        "source":  "24-25 二年级下·山西阳泉·期末"
+    },
+    {
+        "id":  "44",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "用\"5\"\"7\"\"0\"\"0\"组成的四位数中，一个\"零\"都不读出来的是( ),组成最小的四位数是( ),组成最大的四位数是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "5700或7500;5007;7500",
+        "solution":  "【分析】读一个四位数，从高位往低位读，千位上的数读作几千，百位上的数读作几百，十位上的数读作几十，个位上的数读作几，中间的一个0或连续两个0，都只读一个\"零\"，末尾的0不用读。一个\"零\"都不读的数：末尾的0不读，因此两个0必须放在末尾。可能的组合为前两位是5和7，后两位是0，即5700(读作五千七百)和7500(读作七千五百)。最小的四位数：高位取最小非零数5，剩余数字0,0,7按升序排列为007，组成5007。最大的四位数：数字按降序排列为7,5,0,0，组成7500。\n\n【详解】由题意分析得：用\"5\"\"7\"\"0\"\"0\"组成的四位数中，一个\"零\"都不读出来的是5700和7500，组成最小的四位数是5007，组成最大的四位数是7500。",
+        "knowledge_points":  [
+                                 "万以内数的读，写法",
+                                 "万以内数的组成",
+                                 "万以内数的大小比较"
+                             ],
+        "source":  "24-25 二年级下·山西阳泉·期末"
+    },
+    {
+        "id":  "45",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "和2000相邻的两个数是( )和( )。",
+        "options":  [
+
+                    ],
+        "answer":  "1999;2001",
+        "solution":  "【分析】和2000相邻的数是数数时它前边的一个数和它后边的一个数，根据1,2,3。1998,1999,2000,2001。找到对应的数即可。\n\n【详解】由分析得：和2000相邻的两个数是1999和2001。",
+        "knowledge_points":  [
+                                 "数万以内的数"
+                             ],
+        "source":  "24-25 二年级下·山西阳泉·期末"
+    },
+    {
+        "id":  "46",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "4003读作( );三千零五写作( );在3451中，\"5\"在( )位上，表示( )。",
+        "options":  [
+
+                    ],
+        "answer":  "四千零三;3005;十;5个十",
+        "solution":  "【分析】读一个四位数，从高位往低位读，千位上的数读作几千，百位上的数读作几百，十位上的数读作几十，个位上的数读作几，中间的一个0或连续两个0，都只读一个\"零\"，末尾的0不用读。万以内数的写法，从高位往低位写，几千就在千位上写几，几百就在百位上写几，几十就在十位上写几，几就在个位上写几，哪一位上一个也没有，就在那个数位上写0占位。一个四位数，从右往左数，第一位是个位，个位上的数表示几个一;第二位是十位，十位上的数表示几个十;第三位是百位，百位上的数表示几个百;第四位是千位，千位上的数表示几个千。据此解决。\n\n【详解】由题意分析得:4003读作：四千零三;三千零五写作:3005;在3451中，\"5\"在十位上，表示5个十。",
+        "knowledge_points":  [
+                                 "万以内数的读，写法",
+                                 "万以内数的组成"
+                             ],
+        "source":  "24-25 二年级下·山西阳泉·期末"
+    },
+    {
+        "id":  "47",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在5500,5005,5055,5505这四个数中，一个零都不读的是( ),最接近5000的是( ),比5000大500的是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "5500;5005;5500",
+        "solution":  "【分析】找出只有末尾有0的数字，即是一个零都不读的数;用以上四个数分别都和5000相减，得数最小的即是最接近的;用5000加上500得出的和，即是比5000大500的数;据此解答。\n\n【详解】由分析可得:5500只有末尾有0;5500-5000=500,5005-5000=5,5055-5000=55,5505-5000=505;5<55<500<505;5000+500=5500，在5500,5005,5055,5505这四个数中，一个零都不读的是5500，最接近5000的是5005，比5000大500的是5500。",
+        "knowledge_points":  [
+                                 "整百数",
+                                 "几百几十数的加减法口算",
+                                 "万以内数的读，写法",
+                                 "1000以内数的比大小"
+                             ],
+        "source":  "24-25 二年级下·四川南充·期末"
+    },
+    {
+        "id":  "48",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "一件上衣358元，一件下装218元，买这两件服装，带500元钱( )。(填\"够\"或\"不够\")",
+        "options":  [
+
+                    ],
+        "answer":  "不够",
+        "solution":  "【分析】根据题意，将两件服装的价格看成与之接近的整百或整百整十数，相加计算出结果再和500元比较大小即可解答。\n\n【详解】由分析得：把358元看成360元，把218元看成220元，两件服装的价格都估小了。360+220=580(元),580>500，则实际的价格也大于500元。一件上衣358元，一件下装218元，买这两件服装，带500元钱不够。",
+        "knowledge_points":  [
+                                 "万以内数加减法的估算"
+                             ],
+        "source":  "24-25 二年级下·湖北恩施·期末"
+    },
+    {
+        "id":  "49",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "用3,0,8,9这四个数字组成最大的四位数是( ),最小的四位数是( ),最接近8000的数是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "9830;3089;8039",
+        "solution":  "【分析】一个四位数，从右往左依次为个位，十位，百位，千位，组成最大的四位数时，先比较3,0,8,9的大小，然后把数字按照从大到小的顺序从高位到低位排下来，组成最小的四位数时，把0以外最小的数写在最高位，剩余数字按从小到大的顺序依次写在百位，十位和个位上;把8放到千位上，剩余的数字按照从小到大的顺序排列，组成的数最接近8000。\n\n【详解】用3,0,8,9这四个数字组成最大的四位数是9830，最小的四位数是3089，最接近8000的数是8039。",
+        "knowledge_points":  [
+                                 "万以内数的大小比较",
+                                 "万以内数的组成"
+                             ],
+        "source":  "24-25 二年级下·湖北恩施·期末"
+    },
+    {
+        "id":  "50",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.94,
+        "question":  "3998后面的三个数是( ),( ),( )。",
+        "options":  [
+
+                    ],
+        "answer":  "3999;4000;4001",
+        "solution":  "【分析】接着3998向后面一个一个的数，再数出三个数，分别是3999,4000,4001;据此可解。\n\n【详解】由分析可得:3998后面的三个数是3999,4000,4001。",
+        "knowledge_points":  [
+                                 "数万以内的数"
+                             ],
+        "source":  "24-25 二年级下·甘肃庆阳·期末"
+    },
+    {
+        "id":  "51",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "6□45<6553，能填( )个数字，最大能填( )。",
+        "options":  [
+
+                    ],
+        "answer":  "6;5",
+        "solution":  "【分析】比较数的大小时，位数多的数就大，位数相同比较最高位，最高位大的数就大，最高位相同就比较下一位，直到比出大小为止。\n\n【详解】6□45和6553都是四位数，千位数字相同，左边数的十位<右边数的十位，要让左边的数<右边的数，比较百位，即□小于或等于5即可，括号里可以填0,1,2,3,4,5，一共6个数字，最大可以填5.6□45<6553，能填6个数字，最大能填5。",
+        "knowledge_points":  [
+                                 "万以内数的大小比较"
+                             ],
+        "source":  "24-25 二年级下·山东菏泽·期末"
+    },
+    {
+        "id":  "52",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "五千六百八十五写作( ),它是( )位数，最高位是( )位。",
+        "options":  [
+
+                    ],
+        "answer":  "5685;四;千",
+        "solution":  "【分析】一个四位数，从右往左依次为个位，十位，百位，千位;写数时，从高位写起，几个千就在千位上写几，几个百就在百位上写几，几个十就在十位上写几，几个一就在个位上写几，哪一位上一个数字也没有就写\"0\"占位。这个数千位是5，百位是6，十位是8，个位是5;这个数占了千位，百位，十位，个位，共四位;右数的第四位是最高位;据此解答。\n\n【详解】由分析可得：五千六百八十五写作5685，它是四位数，最高位是千位。",
+        "knowledge_points":  [
+                                 "万以内数的组成",
+                                 "万以内数的读，写法"
+                             ],
+        "source":  "24-25 二年级下·山东菏泽·期末"
+    },
+    {
+        "id":  "53",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "5522从左边数第一个5在( )位上，表示5个( ),第二个5在( )位上，表示5个( )。",
+        "options":  [
+
+                    ],
+        "answer":  "千;千;百;百",
+        "solution":  "【分析】一个四位数，从右往左依次为个位，十位，百位，千位;千位是几表示几个千，百位是几表示几个百，十位是几表示几个十，个位是几表示几个一。5522左边的5在千位上，右边的5在百位上;据此解答。\n\n【详解】由分析可得:5522从左边数第一个5在千位上，表示5个千，第二个5在百位上，表示5个百。",
+        "knowledge_points":  [
+                                 "万以内数的组成"
+                             ],
+        "source":  "24-25 二年级下·山东菏泽·期末"
+    },
+    {
+        "id":  "54",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "用6,2,0,0三个数字，组成最小的四位数是( ),组成一个0都不读的四位数是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "2006;2600,6200",
+        "solution":  "【分析】要想组成的数最小，要把数按照从小到大的顺序从高位到低位排下来，但是最高位不能是零;根据整数中0的读法，每一级末尾的0都不读出来，其余数位连续几个0都只读一个零，要想一个零也不读，就要把所有的0都写在每级的末尾;据此解答即可。\n\n【详解】据分析可知：用6,2,0,0三个数字，组成最小的四位数是2006。组成一个0都不读的四位数是2600,6200。",
+        "knowledge_points":  [
+                                 "万以内数的组成"
+                             ],
+        "source":  "24-25 二年级下·广东潮州·期末"
+    },
+    {
+        "id":  "55",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "在计数器上用5颗珠子拨出最大的四位数是( ),最小的四位数是( ),最接近3500的数是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "5000;1004;3200",
+        "solution":  "【分析】把5颗珠子全部放在千位上，组成的数就是最大的四位数，也就是5000;把1颗珠子放在千位上，剩下的4颗珠子放在个位上，组成的数就是最小的四位数，也就是1004;把3颗珠子放在千位上,2颗珠子放在百位上，组成的数是3200，最接近3500。\n\n【详解】在计数器上用5颗珠子拨出最大的四位数是5000，最小的四位数是1004，最接近3500的数是3200。",
+        "knowledge_points":  [
+                                 "万以内数的组成",
+                                 "万以内数的大小比较"
+                             ],
+        "source":  "24-25 二年级下·广东汕头·期末"
+    },
+    {
+        "id":  "56",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "珠穆朗玛峰是世界上最高峰，海拔约是(八千八百四十九)米。括号中的数写作( )。它是由( )个千,( )个百,( )个十和( )个一组成的。",
+        "options":  [
+
+                    ],
+        "answer":  "8849;8;8;4;9",
+        "solution":  "【分析】一个四位数，从右往左依次是个位，十位，百位，千位，千位上是几就表示几个千，百位上是几就表示几个百，十位上是几就表示几个十，个位上是几就表示几个一;写数时从高位写起，几个千就在千位上写几，几个百就在百位上写几，几个十就在十位写几，几个一就在个位写几;【详解】珠穆朗玛峰是世界上最高峰，海拔约是(八千八百四十九)米。括号中的数写作8849。它是由8个千,8个百,4个十和9个一组成的。",
+        "knowledge_points":  [
+                                 "万以内数的读，写法",
+                                 "万以内数的组成"
+                             ],
+        "source":  "24-25 二年级下·广东汕头·期末"
+    },
+    {
+        "id":  "57",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "与8889相邻的两个数是( )和( )。",
+        "options":  [
+
+                    ],
+        "answer":  "8888;8890",
+        "solution":  "【分析】相邻的两个数相差1，前一个数比后一个数少1，后一个数比前一个数多1;即，与8889相邻的两个数是8888和8890。\n\n【详解】由分析可知：与8889相邻的两个数是8888和8890。",
+        "knowledge_points":  [
+                                 "相邻的数"
+                             ],
+        "source":  "24-25 二年级下·贵州铜仁·期末"
+    },
+    {
+        "id":  "58",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "一个四位数，最高位是最大的一位数，百位上的数与个位上的数相同且和是8，十位上是最小的单数，这个数是( ),读作:( ),从右边起第一个数表示( )个( ),第三个数表示( )个( )。",
+        "options":  [
+
+                    ],
+        "answer":  "9414;九千四百一十四;4;一;4;百",
+        "solution":  "【分析】一个四位数，从右往左数，第一位是个位，个位上的数表示几个一;第二位是十位，十位上的数表示几个十;第三位是百位，百位上的数表示几个百;第四位是千位，千位上的数表示几个千。最大的一位数是9，则千位上是9;4+4=8，而百位上的数与个位上的数相同且和是8，则百位上的数与个位上的数都是4;最小的单数是1，则十位上1，这个数是9414。读一个四位数，从高位往低位读，千位上的数读作几千，百位上的数读作几百，十位上的数读作几十，个位上的数读作几，中间的一个0或连续两个0，都只读一个\"零\"，末尾的0不用读。\n\n【详解】由分析可知：一个四位数，最高位是最大的一位数，百位上的数与个位上的数相同且和是8，十位上是最小的单数，这个数是9414，读作：九千四百一十四，从右边起第一个数表示4个一，第三个数表示4个百。",
+        "knowledge_points":  [
+                                 "万以内数的读，写法",
+                                 "万以内数的组成"
+                             ],
+        "source":  "24-25 二年级下·贵州铜仁·期末"
+    },
+    {
+        "id":  "59",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "用2,0,7,9这4个数字组成的四位数中，最大的数是( ),最接近9000的数是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "9720;9027",
+        "solution":  "【分析】要想组成的数最大，要把数字按照从大到小的顺序从高位到低位排下来;最接近9000的数，就是与9000差最小的数，这个数千位上是9，百位，十位及个位从小到大排列。\n\n【详解】据分析可知：用2,0,7,9组成的四位数中，最大的数是9720，最接近9000的数是9027。",
+        "knowledge_points":  [
+                                 "万以内数的组成"
+                             ],
+        "source":  "24-25 二年级下·四川凉山·期末"
+    },
+    {
+        "id":  "60",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "6028是一个( )位数，最高位是( )位;806是一个( )位数，最高位是( )位。",
+        "options":  [
+
+                    ],
+        "answer":  "四;千;三;百",
+        "solution":  "【分析】根据数位顺序，从右到左，依次是个位，十位，百位，千位;一个数是由几个数字组成的，就是几位数。据此解答即可。\n\n【详解】由题意分析得:6028是一个四位数，最高位是千位;806是一个三位数，最高位是百位。",
+        "knowledge_points":  [
+                                 "万以内数的组成"
+                             ],
+        "source":  "24-25 二年级下·四川凉山·期末"
+    },
+    {
+        "id":  "61",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "8500里面有( )个百;由5个千,7个十和9个一组成的数是( ),与它相邻的数是( )和( )。",
+        "options":  [
+
+                    ],
+        "answer":  "85;5079;5078;5080",
+        "solution":  "【分析】从右边起第一位是个位，个位上是几，就表示几个一;第二位是十位，十位上是几，就表示几个十，第三位是百位，百位上是几，就表示几个百，第四位是千位，千位上是几，就表示几个千，据此结合题干要求进行解答即可。要求与它相邻的数是多少，即求比这个数多1和少1的数分别是多少。\n\n【详解】8500里面有85个百;由5个千,7个十和9个一组成的数是5079，与它相邻的数是5078和5080。",
+        "knowledge_points":  [
+                                 "万以内数的组成"
+                             ],
+        "source":  "24-25 二年级下·四川凉山·期末"
+    },
+    {
+        "id":  "62",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "某学校图书馆的藏书量为八千四百二十五册。横线上的数写作( ),它有( )个千,( )个百,( )个十和( )个一。",
+        "options":  [
+
+                    ],
+        "answer":  "8425;8;4;2;5",
+        "solution":  "【分析】一个四位数，从右往左依次是个位，十位，百位，千位，千位是几表示几个千，百位是几表示几个百，十位是几表示几个十，个位是几表示几个一;写数时，从高位写起，有几个千就在千位写几，有几个百就在百位写几，有几个十就在十位写几，有几个一就在个位写几，哪一位上一个单位也没有，就在那一位上写0。\n\n【详解】某学校图书馆的藏书量为八千四百二十五册。横线上的数写作8425，它有8个千,4个百,2个十和5个一。",
+        "knowledge_points":  [
+                                 "万以内数的组成",
+                                 "万以内数的读，写法"
+                             ],
+        "source":  "24-25二年级下·四川成都·期末"
+    },
+    {
+        "id":  "63",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "从个位起，第( )位是万位，第四位是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "五;千位",
+        "solution":  "【分析】万以内的数位顺序：在整数中，从右往左数，第一位是个位，第二位是十位，第三位是百位，第四位是千位，第五位是万位。\n\n【详解】由分析得：从个位起，第五位是万位，第四位是千位。",
+        "knowledge_points":  [
+                                 "整数的数级",
+                                 "数位和计数单位的认识"
+                             ],
+        "source":  "25-26 三年级上·湖南永州·阶段练习"
+    },
+    {
+        "id":  "64",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "从0,3,5,8中选三个数组成不同的三位数，其中最大的数是( ),最小的数是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "853;305",
+        "solution":  "【分析】要想组成最大的三位数：要把数字按照从大到小的顺序从高位到低位排下来。要想组成最小的三位数：要把数字按照从小到大的顺序从高位到低位排下来(数字首位不能是0),选择最小的非零数字作为首位，然后将剩余数字从小到大排列。\n\n【详解】8>5>3>0，从0,3,5,8中选三个数组成不同的三位数，其中最大的数是(853),最小的数是(305)。",
+        "knowledge_points":  [
+                                 "1000以内数的比大小",
+                                 "1000以内数的组成"
+                             ],
+        "source":  "25-26 二年级上·黑龙江佳木斯·开学考试"
+    },
+    {
+        "id":  "65",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "由4个千,2个百和7个一组成的数是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "4207",
+        "solution":  "【分析】根据整数的写法：从高位到低位，一级一级地写，哪一个数位上一个单位也没有，就在那个数位上写0。据此写出这个数即可。\n\n【详解】由4个千,2个百和7个一组成的数是4207。",
+        "knowledge_points":  [
+                                 "万以内数的组成"
+                             ],
+        "source":  "25-26 三年级上·黑龙江佳木斯·开学考试"
+    },
+    {
+        "id":  "66",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "3608读作( ),五千零六十写作( )。",
+        "options":  [
+
+                    ],
+        "answer":  "三千六百零八;5060",
+        "solution":  "【分析】读数方法：从高位读起，千位上是几就读几千，百位上是几就读几百;中间有一个0或两个0，都只读一个0;末尾不管有几个0，都不读;写数方法：从高位写起，按照数位顺序写;几千就在千位上写几，几百就在百位上写几，几十就在十位上写几;哪个数位上一个单位也没有，就在那个数位上写0;据此解答。\n\n【详解】根据分析可知:3608读作三千六百零八，五千零六十写作5060。",
+        "knowledge_points":  [
+                                 "万以内数的读，写法"
+                             ],
+        "source":  "25-26 三年级上·黑龙江佳木斯·开学考试"
+    },
+    {
+        "id":  "67",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "比大小：3456( )3465，1000( )999。",
+        "options":  [
+
+                    ],
+        "answer":  "<;>",
+        "solution":  "【分析】数的大小比较：数位不相同时，数位多的数大；数位相同时，从最高位开始比起，最高位上数大的那个数就大，如果最高位相同，就比较下一位，直至比较出大小。\n\n【详解】3456和3465的千位和百位上的数字都相同，比较十位上的数字，3456十位上是5，3465十位上是6，5<6，所以3456<3465；1000是四位数，999是三位数，所以1000>999。",
+        "knowledge_points":  [
+                                 "万以内数的大小比较"
+                             ],
+        "source":  "25-26 三年级上·黑龙江佳木斯·开学考试"
+    },
+    {
+        "id":  "68",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "一个数由4个千,2个百和5个一组成，这个数是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "4205",
+        "solution":  "【分析】根据数的组成，几个千就是几千，就在千位上写几;几个百就是几百，就在百位上写几;几个十就是几十，就在十位上写几;几个一就是几，在个位上写几;据此解答。\n\n【详解】根据分析可知：一个数由4个千,2个百和5个一组成，这个数是4205。",
+        "knowledge_points":  [
+                                 "万以内数的组成"
+                             ],
+        "source":  "25-26 三年级上·黑龙江佳木斯·开学考试"
+    },
+    {
+        "id":  "69",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "由8,0,3,2组成的最大的四位数是( ),最小的四位数是( ),它们的最高位是( )位。",
+        "options":  [
+
+                    ],
+        "answer":  "8320;2038;千",
+        "solution":  "【分析】一个四位数，从右往左依次是个位，十位，百位，千位，四位数的最高位是千位。要组成最大的四位数，就把这四个数字从大到小排列，得到8,3,2,0，所以最大的四位数是8320;要组成最小的四位数，因为0不能在最高位，所以把除0外最小的数字2放在千位，然后把剩下的数字从小到大排列，得到0,3,8，所以最小的四位数是2038。\n\n【详解】由分析得：由8,0,3,2组成的最大的四位数是(8320),最小的四位数是(2038),它们的最高位是(千)位。",
+        "knowledge_points":  [
+                                 "万以内数的大小比较",
+                                 "万以内数的组成"
+                             ],
+        "source":  "24-25 二年级下·山东菏泽·期末"
+    },
+    {
+        "id":  "70",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "3个千,5个十,6个一组成的数是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "3056",
+        "solution":  "【分析】万以内整数的写法：从高级单位到低位依次写出各位上的数字，哪位上一个单位也没有，就在那位上写0，据此即可写出此数。\n\n【详解】3个千,5个十,6个一组成的数是3056。",
+        "knowledge_points":  [
+                                 "万以内数的组成",
+                                 "万以内数的读，写法"
+                             ],
+        "source":  "24-25 二年级下·湖北武汉·期末"
+    },
+    {
+        "id":  "71",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "厦门环岛路全程约43千米，沿途设有55个观景台，每年接待游客约1255万人次。旅游旺季日均车流量达3000辆，附近停车场可容纳4565辆车。\n(1)上述横线上的数，1255读作( )，4565读作( )。\n(2)1255中从左到右的两个\"5\"分别表示5个( )和5个( )。\n(3)4565是由( )个千，( )个百，( )个十和( )个一组成的。",
+        "options":  [
+
+                    ],
+        "answer":  "一千二百五十五;四千五百六十五;十;一;4;5;6;5",
+        "solution":  "【分析】(1)读数时，从高位读起，千位是几读作几千，百位是几读作几百。中间有一个0或连续两个0，只读一个零，末尾不管有几个0都不读；(2)(3)一个四位数，从右往左依次为个位、十位、百位、千位。千位是几就有几个千，百位是几就有几个百，十位是几就有几个十，个位是几就有几个一；据此解决即可。\n\n【详解】(1)横线上的数，1255读作：一千二百五十五，4565读作：四千五百六十五。(2)1255中从左到右的两个\"5\"分别表示5个十和5个一。(3)4565是由4个千，5个百，6个十和5个一组成的。",
+        "knowledge_points":  [
+                                 "万以内数的组成",
+                                 "万以内数的读，写法"
+                             ],
+        "source":  "24-25二年级下·福建厦门·期末"
+    },
+    {
+        "id":  "72",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "用4,0,7,0写成的四位数中，最大的数是( );最小的数是( ),一个0也不读的数有( ),( )。",
+        "options":  [
+
+                    ],
+        "answer":  "7400;4007;4700;7400",
+        "solution":  "【分析】读一个四位数，从高位往低位读，千位上的数读作几千，百位上的数读作几百，十位上的数读作几十，个位上的数读作几，中间的一个0或连续两个0，都只读一个\"零\"，末尾的0不用读。要使组成的四位数最大，则应把7放在千位，把4放在百位，把0放在十位和个位。要使组成的四位数最小,0不能放在最高位，则应把4放在千位，把0放在百位和十位，把7放在个位。要使组成的四位数一个零也不读，则将0分别放在个位和十位即可。\n\n【详解】由题意分析得：用4,0,7,0写成的四位数中，最大的数是7400;最小的数是4007，一个0也不读的数有4700,7400。",
+        "knowledge_points":  [
+                                 "万以内数的大小比较",
+                                 "万以内数的组成",
+                                 "万以内数的读，写法"
+                             ],
+        "source":  "24-25 二年级下·浙江杭州·期末"
+    },
+    {
+        "id":  "73",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "一个四位数，千位上的数是6，个位上的数字比千位小2，其余各个数位上的数都是0，这个数是( ),读作( )。",
+        "options":  [
+
+                    ],
+        "answer":  "6004;六千零四",
+        "solution":  "【分析】一个四位数，从右往左数，第一位是个位，第二位是十位，第三位是百位，第四位是千位。读一个四位数，从高位往低位读，千位上的数读作几千，百位上的数读作几百，十位上的数读作几十，个位上的数读作几，中间的一个0或连续两个0，都只读一个\"零\"，末尾的0不用读。据此解决此题。\n\n【详解】6-2=4，一个四位数，千位上的数是6，个位上的数字比千位小2，其余各个数位上的数都是0，这个数是6004，读作：六千零四。",
+        "knowledge_points":  [
+                                 "万以内数的组成",
+                                 "万以内数的读，写法"
+                             ],
+        "source":  "24-25 二年级下·浙江杭州·期末"
+    },
+    {
+        "id":  "74",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "4257=( )×1000+( )×100+( )×10+( )×1",
+        "options":  [
+
+                    ],
+        "answer":  "4;2;5;7",
+        "solution":  "【分析】4257是由4个1000,2个100,5个10和7个1组成;几个几是多少用乘法计算;据此解答。\n\n【详解】4257=4×1000+2×100+5×10+7×1",
+        "knowledge_points":  [
+                                 "万以内数的组成"
+                             ],
+        "source":  "2025 三年级上·海南海口·专题练习"
+    },
+    {
+        "id":  "75",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "518=( )×100+( )×10+( )×1.4320=4×( )+3×( )+2×( )。",
+        "options":  [
+
+                    ],
+        "answer":  "5;1;81000;100;10",
+        "solution":  "【分析】根据数位顺序表，从右往左依次是个位，十位，百位，千位等，个位上的数字表示几个一，十位上的数字表示几个十，百位上的数字表示几个百，千位上的数字表示几个千。对于518，百位上是5，表示5个百，即5×100;十位上是1，表示1个十，即1×10;个位上是8，表示8个一，即8×1.4320是一个四位数，从右往左数，第四位是千位，第三位是百位，第二位是十位。千位上是4，表示4个千，即4×1000;百位上是3，表示3个百，即3×100;十位上是2，表示2个十，即2×10。\n\n【详解】由分析可知,518=5×100+1×10+8×1.4320=4×1000+3×100+2×10。",
+        "knowledge_points":  [
+                                 "整数的数级",
+                                 "数位和计数单位的认识",
+                                 "万以内数的组成"
+                             ],
+        "source":  "2025 三年级上·海南海口·专题练习"
+    },
+    {
+        "id":  "76",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "3600里有( )个百,10张100元的人民币一共是( )元。",
+        "options":  [
+
+                    ],
+        "answer":  "36;1000",
+        "solution":  "【分析】1个百是100,2个百是200,3个百是300。,36个百是3600;1张100元是100元,2张100元是200元,3张100元是300元。,10张100元是1000元，据此解答。\n\n【详解】3600里有36个百,10张100元的人民币一共是1000元。",
+        "knowledge_points":  [
+                                 "万以内数的组成",
+                                 "十元以上人民币的认识与计算"
+                             ],
+        "source":  "24-25 二年级下·江西九江·期末"
+    },
+    {
+        "id":  "77",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "9个千和4个一组成的数是( ),读作( )。",
+        "options":  [
+
+                    ],
+        "answer":  "9004;九千零四",
+        "solution":  "【分析】一个四位数，从右往左依次是个位，十位，百位，千位，千位是几表示几个千，百位是几表示几个百，十位是几表示几个十，个位是几表示几个一;读数时，从高位读起，千位上是几就读几千，百位上是几就读几百，十位上是几就读几十，个位上是几就读几，中间有一个0或者两个0，只读一个\"零\"，末尾不管有几个0都不读;由此解答。\n\n【详解】9个千和4个一组成的数是9004，读作九千零四。",
+        "knowledge_points":  [
+                                 "万以内数的读，写法",
+                                 "万以内数的组成"
+                             ],
+        "source":  "24-25二年级下·江西九江·期末"
+    },
+    {
+        "id":  "78",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "一千八百，写作( ),与它相邻的两个数是( )和( ),其中\"8\"在( )位上，表示8个( )。",
+        "options":  [
+
+                    ],
+        "answer":  "1800;1799;1801;百;百",
+        "solution":  "【分析】一个四位数，从右往左依次是个位，十位，百位，千位，写数时，从高位写起，有几个千就在千位写几，有几个百就在百位写几，有几个十就在十位写几，有几个一就在个位写几，哪一位上一个单位也没有，就在那一位上写0;求一个数的相邻数，前面的数比这个数少1，后面的数比这个数多1;千位是几表示几个千，百位是几表示几个百，十位是几表示几个十，个位是几表示几个一，据此解答。\n\n【详解】一千八百，写作1800，与它相邻的两个数是1799和1801，其中\"8\"在百位上，表示8个百。",
+        "knowledge_points":  [
+                                 "万以内数的读，写法",
+                                 "万以内数的组成",
+                                 "相邻的数"
+                             ],
+        "source":  "24-25 二年级下·江西九江·期末"
+    },
+    {
+        "id":  "79",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "判断题",
+        "difficulty":  0.65,
+        "question":  "678=6×100+7×10+8×1。( )",
+        "options":  [
+
+                    ],
+        "answer":  "√",
+        "solution":  "【分析】根据数的组成,6在\"百位\"上：百位的1个数字代表1个\"100\"，所以6在百位就是6个100，也就是6×100;7在\"十位\"上：十位的1个数字代表1个\"10\"，所以7在十位就是7个10，也就是7×10;8在\"个位\"上：个位的1个数字代表1个\"1\"，所以8在个位就是8个1，也就是8×1;据此解答。\n\n【详解】由分析知:678=6×100+7×10+8×1。故答案为:√",
+        "knowledge_points":  [
+                                 "1000以内数的组成"
+                             ],
+        "source":  "25-26三年级上·云南楚雄·期中"
+    },
+    {
+        "id":  "80",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "560里面有56个百。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】560的百位数字是5，代表5个百，十位数字是6，代表6个十，因此560是由5个百和6个十组成，即56个十。据此解答。\n\n【详解】根据分析可知,560里面有56个十，而非56个百，所以该说法错误。故答案为: ×",
+        "knowledge_points":  [
+                                 "万以内数的组成"
+                             ],
+        "source":  "25-26 三年级上·甘肃武威·期中"
+    },
+    {
+        "id":  "81",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "我国长江的长度约是6300千米。6300读作六千零三百。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】读数时，从高位到低位一级一级地读，每级末尾的0都不读出来，其他数位连续几个0都只读一个“零”。据此判断即可。\n\n【详解】6300读作六千三百，不读作六千零三百。原题说法错误。故答案为：×",
+        "knowledge_points":  [
+                                 "万以内数的读，写法"
+                             ],
+        "source":  "25-26 三年级上·甘肃武威·期中"
+    },
+    {
+        "id":  "82",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "判断题",
+        "difficulty":  0.65,
+        "question":  "用2,0,6,4四个数字组成无重复数字的四位数，最大的是6402。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】根据题意，要组成最大的四位数，需将数字按从高位到低位从大到小排列。但需注意首位不能为0。将2,0,6,4按降序排列为6,4,2,0，因此最大四位数应为6420，而非6402。\n\n【详解】根据分析可知，用2,0,6,4组成无重复数字的最大四位数是6420，原题说法错误。故答案为: ×",
+        "knowledge_points":  [
+                                 "万以内数的大小比较"
+                             ],
+        "source":  "23-24三年级上·贵州铜仁·期中"
+    },
+    {
+        "id":  "83",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "最小的四位数比最大的三位数多900。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】一个整数，从右往左依次为个位，十位，百位，千位。最小的四位数，千位是1，其它数位都是0，即1000;最大的三位数，每个数位都是9，即999。数数时,1,2,3。998,999,1000.999后边就是1000，也就是它们之间相差1，由此解答。\n\n【详解】由分析得：最小的四位数比最大的三位数多1，原题说法错误。故答案为: ×",
+        "knowledge_points":  [
+                                 "1000以内数的组成",
+                                 "数1000以内的数"
+                             ],
+        "source":  "24-25 二年级下·山西阳泉·期末"
+    },
+    {
+        "id":  "84",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "2050是由2个千，五个百组成的。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】从右边起，第一位是个位，个位上是几就表示几个一;第二位是十位，十位上是几就表示几个十;第三位是百位，百位上是几就表示几个百;第四位是千位，千位上是几就表示几个千，据此解答即可。\n\n【详解】2050的千位是2，表示2个千(2000);百位是0，表示0个百;十位是5，表示5个十(50);个位是0。因此,2050由2个千和5个十组成。题目中\"五个百\"说法错误。故答案为: ×",
+        "knowledge_points":  [
+                                 "万以内数的组成"
+                             ],
+        "source":  "24-25 二年级下·广东汕头·期末"
+    },
+    {
+        "id":  "85",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "数位顺序表中右起第一位是个位，第二位是十位，第三位是百位，第四位是千位。( )",
+        "options":  [
+
+                    ],
+        "answer":  "√",
+        "solution":  "【分析】从右边起，第一位是个位，个位上是几就表示几个一;第二位是十位，十位上是几就表示几个十;第三位是百位，百位上是几就表示几个百;第四位是千位，千位上是几就表示几个千。据此解答即可。\n\n【详解】据分析可知：数位顺序表中右起第一位是个位，第二位是十位，第三位是百位，第四位是千位。原题说法正确。故答案为:√",
+        "knowledge_points":  [
+                                 "万以内数的组成"
+                             ],
+        "source":  "24-25二年级下·广东·期末"
+    },
+    {
+        "id":  "86",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "一台电风扇215元，一个电饭煲308元，妈妈用500元钱不够买这两件商品。( )",
+        "options":  [
+
+                    ],
+        "answer":  "√",
+        "solution":  "【分析】先用加法估算出买一台电风扇和一个电饭煲需要多少钱，然后判断500元够不够买这两件商品。\n\n【详解】200+300=500(元),其中一台电风扇215元比200元多，一个电饭煲308元比300元多，所以妈妈用500元钱不够买这两件商品。故答案为:√",
+        "knowledge_points":  [
+                                 "万以内数加减法的估算"
+                             ],
+        "source":  "24-25 二年级下·四川凉山·期末"
+    },
+    {
+        "id":  "87",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "比最小的四位数少1的数是999。( )",
+        "options":  [
+
+                    ],
+        "answer":  "√",
+        "solution":  "【分析】根据题意可知：最小的四位数是1000，则求比最小的四位数少1的数，用最小的四位数减去1即可。\n\n【详解】1000-1=999，则比最小的四位数少1的数是999，原题说法正确。故答案为:√",
+        "knowledge_points":  [
+                                 "数1000以内的数"
+                             ],
+        "source":  "24-25 二年级下·四川凉山·期末"
+    },
+    {
+        "id":  "88",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "王叔叔上个月的工资是4019元，约是5000元。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】根据四舍五入的规则，四舍五入到千位时，要看百位上的数,4019的百位是0，直接舍去，看成4000，据此解答。\n\n【详解】4019元大约是4000元;王叔叔上个月的工资是4019元，约是5000元，原题说法错误。故答案为: ×",
+        "knowledge_points":  [
+                                 "万以内数的估计"
+                             ],
+        "source":  "24-25二年级下·四川成都·期末"
+    },
+    {
+        "id":  "89",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "购物。\n![](images/78baf372e40b0f1e176edacc0819b9e9.png)\n(1)买一台洗衣机和一台冰箱一共要多少钱？\n(2)爸爸想买一台电扇和一台电视机，带3500元够吗？",
+        "options":  [
+
+                    ],
+        "answer":  "7800元;不够",
+        "solution":  "【分析】(1)根据加法的意义，一台洗衣机的钱数加一台冰箱的钱数，等于买一台洗衣机和一台冰箱一共要的钱数；(2)根据题意，将电扇和电视机的价格看成与之接近的整百数，相加计算出结果，再和3500比较大小即可解答。\n\n【详解】(1)2800+5000=7800(元)，答：买一台洗衣机和一台冰箱一共要7800元。(2)把528元看成500元，把3098元看成3000元，500+3000=3500(元)，3500=3500，因为两个数都估小了，则实际的价格要大于3500元，所以带3500元不够。答：带3500元不够。",
+        "knowledge_points":  [
+                                 "万以内数加减法的估算",
+                                 "整百数",
+                                 "几百几十数的加减法口算"
+                             ],
+        "source":  "24-25 二年级下·湖北恩施·期末"
+    },
+    {
+        "id":  "90",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "学校礼堂有1000个座位，\"六一\"节要在学校礼堂举行六一表演，全校男生有492名，女生有456名，全校学生都能坐得下吗。\n口答：全校学生都( )坐得下(选填\"能\"和\"不能\")。",
+        "options":  [
+
+                    ],
+        "answer":  "能",
+        "solution":  "【分析】由题意可知：找出全校男，女生的人数最接近整百数的近似数，再相加，算出全校大概的人数，再和1000个座位数对比，小于等于1000，能坐得下;大于1000，不能坐下;据此解答。\n\n【详解】由分析可得:492≈500,456≈500;500+500=1000(名),1000=1000，答：全校学生都能坐得下。",
+        "knowledge_points":  [
+                                 "万以内数加减法的估算",
+                                 "整百数",
+                                 "几百几十数的加减法口算",
+                                 "1000以内数的比大小"
+                             ],
+        "source":  "24-25 二年级下·四川南充·期末"
+    },
+    {
+        "id":  "91",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "![](images/66fa1346c3372c7fd36a1a575bafca20.png)\n(1)买一台电视机和一台冰箱，一共需要多少元钱。\n(2)妈妈带了10000元钱，想买这三样商品各一件，够吗。",
+        "options":  [
+
+                    ],
+        "answer":  "7000元;够",
+        "solution":  "【分析】(1)用一台电视机的钱加上一台冰箱的钱，即可求出一共需要多少元钱；(2)把2980元看成与之接近的整千数，再把三样商品的钱加起来，与10000元比较大小，若三样商品的钱小于或等于10000元，则够，反之则不够。\n\n【详解】(1)2000+5000=7000(元)，答：一共需要7000元钱。(2)把2980元看成3000元，2000+3000+5000=5000+5000=10000(元)，10000元=10000元，答：妈妈带了10000元钱，想买这三样商品各一件，够。",
+        "knowledge_points":  [
+                                 "万以内数加减法的估算",
+                                 "整百数",
+                                 "几百几十数的加减法口算"
+                             ],
+        "source":  "24-25 二年级下·山东菏泽·期末"
+    },
+    {
+        "id":  "92",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "我每月能领到4000元退休金。\n![](images/07370b840799f1ef163b36f033f23132.png)\n我每月能领到的退休金比你多500元。\n(1)奶奶一个月能领到的退休金是多少元？\n(2)爷爷和奶奶一个月领到的退休金共多少元？",
+        "options":  [
+
+                    ],
+        "answer":  "4500元;8500元",
+        "solution":  "【分析】(1)因为奶奶每个月可以比爷爷多领500元退休金，根据加法的意义，用4000+500即可得出答案。(2)要求爷爷和奶奶一个月领到的退休金共多少元，根据加法的意义，将两人领的退休金钱数相加，即可得出答案。\n\n【详解】(1)4000+500=4500(元)，答：奶奶一个月能领到的退休金是4500元。(2)4000+4500=8500(元)，答：爷爷和奶奶一个月领到的退休金共8500元。",
+        "knowledge_points":  [
+                                 "整百数",
+                                 "几百几十数的加减法口算"
+                             ],
+        "source":  "24-25 二年级下·四川成都·期末"
+    },
+    {
+        "id":  "93",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "一本故事书，笑笑每天看8页，看了9天，还剩149页，这本故事书一共有多少页。",
+        "options":  [
+
+                    ],
+        "answer":  "221页",
+        "solution":  "【分析】已知每天看8页，看了9天，先求这9天一共看了多少页，再加上剩下的149页，就是本书的总页数。\n\n【详解】8×9=72(页)，72+149=221(页)，答：这本故事书一共有221页。",
+        "knowledge_points":  [
+                                 "乘加，乘减混合运算"
+                             ],
+        "source":  "24-25二年级下·广东湛江·期末"
+    },
+    {
+        "id":  "94",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "城关镇礼堂有2300个座位，城关镇的三所小学各有800多名学生。如果这三所小学的学生同时来参加活动，礼堂的座位够吗。",
+        "options":  [
+
+                    ],
+        "answer":  "不够",
+        "solution":  "【分析】三所小学各有800多名学生，如果每个学校至少都有800人，那么总人数就是3个800人，先求出三所学校最少有多少人，再与2300比较即可求解。\n\n【详解】800+800+800=2400(人)，2400>2300，所以礼堂的2300个座位不够。答：礼堂的座位不够。",
+        "knowledge_points":  [
+                                 "万以内数加减法的估算",
+                                 "整百数",
+                                 "几百几十数的加减法口算"
+                             ],
+        "source":  "24-25 二年级下·福建龙岩·期末"
+    },
+    {
+        "id":  "95",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "未来小学举办课间操比赛，其中低年级参赛人员有96人，高年级参赛人员有303人。高年级的参赛人员比低年级的大约多多少人。",
+        "options":  [
+
+                    ],
+        "answer":  "200人",
+        "solution":  "【分析】把96和303看成与之接近的整百数或整百整十数，再用高年级的参赛人员减去低年级的参赛人员，即可求出高年级的参赛人员比低年级的大约多多少人。\n\n【详解】把96看成100,303看成300,300-100=200(人),答：高年级的参赛人员比低年级的大约多200人。",
+        "knowledge_points":  [
+                                 "万以内数加减法的估算",
+                                 "整百数",
+                                 "几百几十数的加减法口算"
+                             ],
+        "source":  "24-25 二年级下·湖北武汉·期末"
+    },
+    {
+        "id":  "96",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "学校体育馆有900个座位。运动会时，一年级有428名学生，二年级有567名学生，一二年级要一起在体育馆观看比赛，估一估，座位够这两个年级的学生坐吗。",
+        "options":  [
+
+                    ],
+        "answer":  "不够",
+        "solution":  "【分析】先估算出一二年级一共有几名学生，然后与体育馆的座位数比较大小，即可估计出座位数够不够。\n\n【详解】一年级有428名学生，估成400名学生;二年级有567名学生，估成500名学生;400+500=900(名),由于两个年级的人数都估少了，所以实际学生人数要比900名多;答：座位不够这两个年级的学生坐。",
+        "knowledge_points":  [
+                                 "万以内数加减法的估算"
+                             ],
+        "source":  "24-25 二年级下·福建厦门·期末"
+    },
+    {
+        "id":  "97",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "一台阅读机原价是902元，现价是697元。这样的话，大约便宜了多少元。",
+        "options":  [
+
+                    ],
+        "answer":  "200元",
+        "solution":  "【分析】由题意可知：先找出阅读机原价和现价最接近整百数的近似数，再相减，即可知大约便宜了多少元;据此解答。\n\n【详解】由分析可得:902≈900,697≈700;900-700=200(元),答：大约便宜了200元。",
+        "knowledge_points":  [
+                                 "万以内数加减法的估算",
+                                 "整百数",
+                                 "几百几十数的加减法口算",
+                                 "1000以内数的估计"
+                             ],
+        "source":  "24-25 二年级下·山东菏泽·期末"
+    },
+    {
+        "id":  "98",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "买600元以上送笔记本；买1000元以上送卷纸；买3000元以上送玩具汽车。\n| (1)电脑 | (2)烧水壶 | (3)电饭锅 | (4)微波炉 |\n| --------- | ----------- | ----------- | ----------- |\n| 3800元 | 180元 | 308元 | 798元 |\n(1)洋洋妈妈买了两件东西，商店送了卷纸，她可能买了( )号物品和( )号物品。\n(2)丽丽爸爸买了一台电脑，月月妈妈买了(4)号物品。请你估一估丽丽爸爸比月月妈妈大约多付多少元钱。",
+        "options":  [
+
+                    ],
+        "answer":  "3;4;3000元",
+        "solution":  "【分析】(1)洋洋妈妈买了两件东西，商店送了卷纸，表示洋洋妈妈买的物品价格之和超过了1000元，把(2)(3)(4)号物品的价格分别看成与之接近的整百数或整百整十数，进行估算，看哪两种物品的价格之和超过1000元即可；(2)把(4)号物品的价格看成与之接近的整百数或整百整十数，用电脑的价格减去(4)号物品的价格，即可求出丽丽爸爸比月月妈妈大约多付多少元钱。\n\n【详解】(1)180元可以看成180元，308元可以看成300元，798元可以看成800元；180+300=480(元)，480元<1000元；180+800=980(元)，980元<1000元；300+800=1100(元)，1100元>1000元；洋洋妈妈买了两件东西，商店送了卷纸，她可能买了(3)号物品和(4)号物品。(2)798元可以看成800元，3800-800=3000(元)，答：丽丽爸爸比月月妈妈大约多付3000元钱。",
+        "knowledge_points":  [
+                                 "万以内数加减法的估算",
+                                 "整百数",
+                                 "几百几十数的加减法口算",
+                                 "万以内数的大小比较",
+                                 "1000以内数的比大小"
+                             ],
+        "source":  "24-25 二年级下·浙江杭州·期末"
+    },
+    {
+        "id":  "99",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "超市有1200瓶娃哈哈矿泉水，卖掉700瓶后又进来480瓶，现在超市有多少瓶娃哈哈矿泉水。",
+        "options":  [
+
+                    ],
+        "answer":  "980瓶",
+        "solution":  "【分析】根据题意可知：用超市有的数量减去卖掉的数量，再加上又进来的数量，即可求出现在超市有的数量。\n\n【详解】1200-700+480=500+480=980(瓶),答：现在超市有980瓶娃哈哈矿泉水。",
+        "knowledge_points":  [
+                                 "两，三位数的加减混合运算"
+                             ],
+        "source":  "24-25二年级下·浙江杭州·期末"
+    },
+    {
+        "id":  "100",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "科技园区有机器人800台，无人机700台，又引进了400台机器人。现在无人机比机器人少多少台。",
+        "options":  [
+
+                    ],
+        "answer":  "500台",
+        "solution":  "【分析】先用科技园区原有的机器人台数加上又引进的机器人台数，求出现在机器人的台数，再用现在机器人的台数减去无人机的台数，即可求出现在无人机比机器人少多少台。\n\n【详解】800+400=1200(台),1200-700=500(台),答：现在无人机比机器人少500台。",
+        "knowledge_points":  [
+                                 "整百数",
+                                 "几百几十数的加减法口算"
+                             ],
+        "source":  "24-25 二年级下·青海果洛·期末"
+    },
+    {
+        "id":  "101",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "下面的数中，一个零也不读的是( )。",
+        "options":  [
+                        "A. 5600",
+                        "B. 9003",
+                        "C. 2308"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】读数时，从高位读起，千位是几就读几千，百位是几就读几百，十位是几就读几十，个位是几就读几，中间有一个0或两个0，只读一个\"零\"，末尾不管有几个0，都不读。分别读出各选项的数，选出一个零也不读的即可。\n\n【详解】A。5600读作：五千六百，一个零也不读;B。9003读作：九千零三，读了一个零;C。2308读作：二千三百零八，读了一个零。一个零也不读的是5600。故答案为:A",
+        "knowledge_points":  [
+                                 "万以内数的读，写法"
+                             ],
+        "source":  "24-25二年级下·青海果洛·期末"
+    },
+    {
+        "id":  "102",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "下面各数中，最接近4000的数是( )。",
+        "options":  [
+                        "A. 399",
+                        "B. 3995",
+                        "C. 4100"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】分别找出各项数字最接近的整百整千数，再和4000相减，差最小的，即是最接近4000的数。据此解答。\n\n【详解】由分析可得:A。399≈400,4000-400=3600;B。3995≈4000,4000-4000=0;C。4100,4100-4000=100.0<100<3600，最接近4000的数是3995。故答案为:B",
+        "knowledge_points":  [
+                                 "万以内数加减法的估算",
+                                 "整百数",
+                                 "几百几十数的加减法口算",
+                                 "万以内数的估计",
+                                 "万以内数的大小比较"
+                             ],
+        "source":  "24-25二年级下·陕西延安·期末"
+    },
+    {
+        "id":  "103",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "4□38<4647,□里最大能填( )。",
+        "options":  [
+                        "A. 5",
+                        "B. 6",
+                        "C. 4"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】四位数之间的比较大小，从高位比起，千位上大的数就大；千位上相同，就比较百位上的数，百位上大的数就大；百位上相同，就比较十位上的数，十位上大的数就大；十位上相同，就比较个位上的数，个位上大的数就大；据此解决。\n\n【详解】4□38与4647千位上的数字相同，先比较百位。要使4□38<4647，□应小于6；若□=6，再比较十位，3<4，也符合题意。所以□里最大能填6。故答案为：B",
+        "knowledge_points":  [
+                                 "万以内数的大小比较"
+                             ],
+        "source":  "24-25 二年级下·湖南张家界·期末"
+    },
+    {
+        "id":  "104",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "下面的数中( )的\"6\"表示6个百。",
+        "options":  [
+                        "A. 3690",
+                        "B. 6404",
+                        "C. 7061"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】一个四位数，从右往左数，第一位是个位，个位上的数表示几个一;第二位是十位，十位上的数表示几个十;第三位是百位，百位上的数表示几个百;第四位是千位，千位上的数表示几个千;据此分析，找出正确答案即可。\n\n【详解】A。3690的\"6\"在百位上，表示6个百;B。6404的\"6\"在千位上，表示6个千;C。7061的\"6\"在十位上，表示6个十。故答案为:A",
+        "knowledge_points":  [
+                                 "万以内数的组成"
+                             ],
+        "source":  "24-25 二年级下·湖南张家界·期末"
+    },
+    {
+        "id":  "105",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "用0,2,5,8这四个数字组成的四位数中，最大的数是( )。",
+        "options":  [
+                        "A. 8520",
+                        "B. 8250",
+                        "C. 8052"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】一个四位数，从右往左依次为个位，十位，百位，千位，要组成最大的四位数，则将数字从大到小按数位从千位到个位排列即可。\n\n【详解】用0,2,5,8这四个数字组成的四位数中，最大的数是8520。故答案为:A",
+        "knowledge_points":  [
+                                 "万以内数的大小比较",
+                                 "万以内数的组成"
+                             ],
+        "source":  "25-26 四年级上·黑龙江佳木斯·开学考试"
+    },
+    {
+        "id":  "106",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "由6个千和3个一组成的数是( )。",
+        "options":  [
+                        "A. 6003",
+                        "B. 6030",
+                        "C. 6300"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】千位上的数是几就是几个千，个位上的数是几就是几个一。整数的写法，从高位到低位，一级一级地写，哪一个数位上一个单位也没有，就在那个数位上写0。\n\n【详解】由6个千和3个一组成的数是6003。故答案为:A",
+        "knowledge_points":  [
+                                 "万以内数的组成"
+                             ],
+        "source":  "25-26 三年级上·黑龙江鹤岗·开学考试"
+    },
+    {
+        "id":  "107",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "要使7□95>7595,□里有( )种填法。",
+        "options":  [
+                        "A. 5",
+                        "B. 4",
+                        "C. 6"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】比较数的大小时，位数多的数就大;位数相同比较最高位，最高位大的数就大;最高位相同比较下一位，直到比较出结果为止。题中千位相同，十位相同，个位相同，整体左边的数大于右边的数，则左边百位上的数一定大于右边百位上的数。由此解答。\n\n【详解】根据分析可得：比5大的数有6,7,8,9，要使7□95>7595,□里有4种填法。故答案为:B",
+        "knowledge_points":  [
+                                 "万以内数的大小比较"
+                             ],
+        "source":  "24-25 二年级下·湖北黄冈·期末"
+    },
+    {
+        "id":  "108",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "下面各数中，最接近4000的数是( )。",
+        "options":  [
+                        "A. 3998",
+                        "B. 4999",
+                        "C. 4028"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】根据题意，依次数出各数与4000之间间隔几个数字，间隔数字越少越接近。\n\n【详解】A。3998和4000之间间隔的数字有:3999，共1个;B。4999和4000之间间隔的数字有:4001,4002,4003。有很多个;C。4028和4000之间间隔的数字有:4001,4002,4003。有很多个。则间隔数字最少的是3998，也就是最接近4000的数是3998。故答案为:A",
+        "knowledge_points":  [
+                                 "数万以内的数"
+                             ],
+        "source":  "24-25二年级下·安徽淮南·期末"
+    },
+    {
+        "id":  "109",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "星期天，妈妈带700元钱去华联商场买下面两件衣服，带的钱够吗。( ).\n![](images/20e08f5b932349a4f048a7aada1fcae5.png)",
+        "options":  [
+                        "A. 够",
+                        "B. 不够",
+                        "C. 无法判断"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】先用加法表示出这两件衣服的价钱之和，然后进行估算，判断一下所带的钱够不够即可。\n\n【详解】两件衣服钱数和是:518+239,518>500,239>200,500+200=700，所以518+239>700，即，妈妈带700元钱去华联商场买这两件衣服，带的钱不够。故答案为:B",
+        "knowledge_points":  [
+                                 "万以内数加减法的估算",
+                                 "1000以内数的比大小"
+                             ],
+        "source":  "24-25二年级下·湖北孝感·期末"
+    },
+    {
+        "id":  "110",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "下图中，点( )表示的数与7500离得最近.\n![](images/95b2c33dbf3a5cb4f6055a3d5aaf116d95dacddfdfab088884a96d08f55613f3.jpg)",
+        "options":  [
+                        "A. ①",
+                        "B. ②",
+                        "C. ③"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】通过观察数轴上各点的位置，判断哪个点所表示的数与7500的差值最小，就是与7500离得最近。\n\n【详解】A。点①在5500和6000之间，且靠近6000，与7500相差很大。B。点②在7000和7500之间，且靠近7000，与7500相差较大。C。点③在7500和8000之间，且靠近7500，与7500相差很小。即，点③表示的数与7500离得最近。故答案为:C",
+        "knowledge_points":  [
+                                 "万以内数的估计"
+                             ],
+        "source":  "24-25 二年级下·湖北孝感·期末"
+    },
+    {
+        "id":  "111",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "在下图中\"↓\"处表示的数可能是( ).\n![](images/81f648b879a3aa564555398aca22be80554e2fb56ffdb26e25e989546c24cda3.jpg)",
+        "options":  [
+                        "A. 4580",
+                        "B. 4780",
+                        "C. 4880"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】根据题图可知，在4500至5000之间，平均分成了5格，每格表示100，即\"↓\"是在第4格里，即接近4900，逐项分析各个选项，找出正确答案即可。\n\n【详解】A。4580在从左往右数的第1格里，与题图不符，不正确;B。4780在从左往右数的第3格里，与题图不符，不正确;C。4880在从左往右数的第4格里，靠近4900的位置，与题图相符，正确;图中\"↓\"处表示的数可能是4880。故答案为:C",
+        "knowledge_points":  [
+                                 "万以内数的估计"
+                             ],
+        "source":  "24-25 二年级下·浙江台州·期末"
+    },
+    {
+        "id":  "112",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "342+24□的结果可能是( )所表示的数.\n![](images/d8c8131f10ed23fff480bd2f31df8744e620699263e3b6f4bb54292dd18a58a8.jpg)",
+        "options":  [
+                        "A. □",
+                        "B. ☆",
+                        "C. △"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】估算出342+24□的大概得数，然后分析各选项所表示的位置是否符合。\n\n【详解】342+24□≈350+250=600，两个加数都估大了，所以实际应该小于600并且接近600。A。□小于600并且接近600，符合。B。☆大于600，不符合。C。△大于600，不符合。342+24□的结果可能是□所表示的数。故答案为:A",
+        "knowledge_points":  [
+                                 "万以内数加减法的估算"
+                             ],
+        "source":  "24-25二年级下·四川成都·期中"
+    },
+    {
+        "id":  "113",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "下列说法错误的是( )。",
+        "options":  [
+                        "A. 把18个梨分成9份，每份一定是2个。",
+                        "B. 36÷4=9与4×9=36是用同一句口诀。",
+                        "C. 读万以内的四位数时，末尾的0都不读。"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】平均分指在分物体时，尽可能地分完且每份得到的数量一样多。根据乘法口诀计算乘法算式时，口诀中的前两个数是乘数，可互换位置，后一个数是积;计算除法算式时，口诀中的后一个数是被除数，前两个数可分别为除数和商。读一个四位数，从高位往低位读，千位上的数读作几千，百位上的数读作几百，十位上的数读作几十，个位上的数读作几，中间的一个0或连续两个0，都只读一个\"零\"，末尾的0不用读。据此解决此题。\n\n【详解】A。题目未说明\"平均分\"，分成9份可能存在不同数量，因此每份不一定是2个。此选项错误。B。36÷4=9和4×9=36均用\"四九三十六\"口诀。此选项正确。C。四位数末尾的0不读(如2300读作二千三百)。此选项正确。故答案为:A",
+        "knowledge_points":  [
+                                 "整数平均分的意义及应用",
+                                 "9的乘法口诀及应用",
+                                 "万以内数的读，写法"
+                             ],
+        "source":  "24-25 二年级下·湖北孝感·期末"
+    },
+    {
+        "id":  "114",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "在算盘上，拨6颗算珠，表示的数可能是( )。",
+        "options":  [
+                        "A. 6000",
+                        "B. 3610",
+                        "C. 452"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】算盘上的1颗上珠表示5,1颗下珠表示1，逐项分析各个选项，找出可以拨6颗算珠表示的数，即可解答。\n\n【详解】A。6000：千位上拨1颗上珠和1颗下珠，百位，十位和个位不需要拨算珠，共2颗算珠，不符合题意;B。3610：千位上拨3颗下珠，百位上拨1颗上珠和1颗下珠，十位上拨1颗下珠，个位上不需要拨珠子;总珠子数:3+2+1+0=6(颗),符合题意。C。452：百位上拨4颗下珠，十位上拨1颗上珠，个位上拨2颗下珠，总珠子数:4+1+2=7(颗),不符合题意。因此，在算盘上，拨6颗算珠，表示的数可能是3610。故答案为:B",
+        "knowledge_points":  [
+                                 "算盘的认识与使用",
+                                 "1000以内数的组成",
+                                 "万以内数的组成"
+                             ],
+        "source":  "24-25 二年级下·浙江台州·期末"
+    },
+    {
+        "id":  "115",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "6□38<6472,□里可以填的数字有( )个。",
+        "options":  [
+                        "A. 3",
+                        "B. 4",
+                        "C. 5"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】万以内整数比较大小，先看数位，数位多的数比较大；数位相同先看千位，千位上大的数就大；如果千位上的数字相同，百位上大的数字就大；如果百位上的数字相同，再比较十位和个位。\n\n【详解】6□38<6472，千位上的数字相同，先比较百位。要使左边的数小于右边的数，□可以填0、1、2、3、4；若填5、6、7、8、9，则左边的数会大于6472。所以□里可以填的数字有5个。故答案为：C",
+        "knowledge_points":  [
+                                 "万以内数的大小比较"
+                             ],
+        "source":  "24-25 二年级下·浙江台州·期末"
+    },
+    {
+        "id":  "116",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "四位数6600，千位上的\"6\"和百位上的\"6\"相比,( )。",
+        "options":  [
+                        "A. 一样大",
+                        "B. 大5400",
+                        "C. 大1000"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】一个四位数，从右往左依次为个位，十位，百位，千位。千位是几就有几个千(几个千就是几千),百位是几就有几个百(几个百就是几百),十位是几就有几个十(几个十就是几十),个位是几就有几个一(几个一就是几)。将千位和百位上表示的数写出来再相减即可解答。\n\n【详解】由分析可知：千位上的\"6\"表示6个千，即6000;百位上的\"6\"表示6个百，即600.6000-600=5400，则四位数6600，千位上的\"6\"和百位上的\"6\"相比，大5400。故答案为:B",
+        "knowledge_points":  [
+                                 "万以内数的组成",
+                                 "整百数",
+                                 "几百几十数的加减法口算"
+                             ],
+        "source":  "24-25 二年级下·浙江台州·期末"
+    },
+    {
+        "id":  "117",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "下面各数中，一个零都不读的数是( )。",
+        "options":  [
+                        "A. 8002",
+                        "B. 8200",
+                        "C. 8020",
+                        "D. 以上都不读"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】一个四位数，从右往左依次为个位，十位，百位，千位。读数时，从高位读起，按照数位顺序读。千位是几就读几千，百位是几就读几百，十位上是几就读几十，个位上是几就读几，中间有一个0或两个0，只读一个零;末尾不管有几个0，都不读;据此读出各数，再逐项分析各个选项，找出正确答案即可。\n\n【详解】A。8002读作：八千零二，中间有两个0，只读一个零;B。8200读作：八千二百，末尾有两个0，一个零都不读;C。8020读作：八千零二十，中间的零，读出来，末尾的零，都不读;D。以上都不读，说法错误。一个零都不读的数是8200。故答案为:B",
+        "knowledge_points":  [
+                                 "万以内数的读，写法"
+                             ],
+        "source":  "24-25 二年级下·浙江湖州·期末"
+    },
+    {
+        "id":  "118",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "在\"环保活动\"中，阳光小学的学生们共收集了479节废旧电池。关于横线上的数，说法错误的是( )。",
+        "options":  [
+                        "A. 它读作四百七十九",
+                        "B. 它用算盘表示需要拨11颗珠子",
+                        "C. 与它相邻的两个数是478和480"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】一个三位数，从右往左依次为个位，十位，百位。读数时，从高位读起，按照数位顺序读。百位是几就读几百，十位上是几就读几十，个位上是几就读几，中间的0，需要读出来，末尾的0，都不读，据此读出这个数;在算盘上，一个上珠表示5，一个下珠表示1，数出用算盘表示479时，个位，十位和百位上所有珠子的总数即可;与一个数相邻的两个数，即数数时，这个数的前一个数和后一个数。逐项分析各个选项，找出说法错误的选项即可。\n\n【详解】A。479的百位是4，十位是7，个位是9，读作：四百七十九，说法正确;B。百位4：拨4颗下珠，十位7：拨1颗上珠和2颗下珠，共3颗，个位9：拨1颗上珠和4颗下珠，共5颗，总珠子数:4+3+5=12(颗)。选项说\"11颗珠子\"，因此说法错误;C。479的前一个数是478，后一个数是480，与它相邻的两个数是478和480，说法正确。综上，说法错误的是B选项。故答案为:B",
+        "knowledge_points":  [
+                                 "算盘的认识与使用",
+                                 "数1000以内的数",
+                                 "1000以内数的读，写法",
+                                 "1000以内数的组成"
+                             ],
+        "source":  "24-25二年级下·福建厦门·期末"
+    },
+    {
+        "id":  "119",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "在1998这个数中，两个\"9\"所表示的数相差( )。",
+        "options":  [
+                        "A. 10",
+                        "B. 100",
+                        "C. 810"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】一个整数，从右往左依次为个位，十位，百位，千位。千位是几表示几个千(几个千就是几千),百位是几表示几个百(几个百就是几百),十位是几表示几个十(几个十就是几十),个位是几表示几个一(几个一就是几),由此将两个9所表示的数相减即可解答。\n\n【详解】由分析得：从左往右数，第一个9在百位，表示9个百，即900;第二个9在十位，表示9个十，即90.900-90=810，则在1998这个数中，两个\"9\"所表示的数相差810。故答案为:C",
+        "knowledge_points":  [
+                                 "万以内数的组成",
+                                 "整百数",
+                                 "几百几十数的加减法口算"
+                             ],
+        "source":  "24-25 二年级下·江西赣州·期末"
+    },
+    {
+        "id":  "120",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "一台空调的价格是3998元，大约是( )元。",
+        "options":  [
+                        "A. 3000",
+                        "B. 4000",
+                        "C. 5000"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】根据题意，一个数的近似数也就是与之接近的整千或整千整百数，由此解答。\n\n【详解】根据分析可得:3998接近4000，所以，一台空调的价格是3998元，大约是4000元。故答案为:B",
+        "knowledge_points":  [
+                                 "万以内数的估计"
+                             ],
+        "source":  "24-25 二年级下·湖北孝感·期末"
+    },
+    {
+        "id":  "121",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "下面各数中，一个\"零\"都不读的是( )。",
+        "options":  [
+                        "A. 2003",
+                        "B. 2200",
+                        "C. 2030"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】一个四位数，从右往左依次为个位，十位，百位，千位。读数时，从高位读起，按照数位顺序读。千位是几就读几千，百位是几就读几百，十位上是几就读几十，个位上是几就读几，中间有一个0或两个0，只读一个零;末尾不管有几个0，都不读;据此读出各数，再逐项分析各个选项，找出正确答案即可。\n\n【详解】A。2003：读作\"二千零三\"，读了一个零。B。2200：读作\"二千二百\"，一个零都不读。C。2030：读作\"二千零三十\"，读了一个零。因此，一个零都不读是2200。故答案为:B",
+        "knowledge_points":  [
+                                 "万以内数的读，写法"
+                             ],
+        "source":  "24-25 二年级下·湖北孝感·期末"
+    },
+    {
+        "id":  "122",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "下面各数一个零也不读的是( )。",
+        "options":  [
+                        "A. 3007",
+                        "B. 4050",
+                        "C. 8000"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】一个四位数，从右往左依次为个位，十位，百位，千位。万以内数的读法：从高位读起，千位上是几，读作几千;百位上是几，读作几百;十位上是几，读作几十;个位上是几，读作几;末尾的0不读，中间的1个或连续2个0，只读1个零。据此读出选项中各个数，找出一个零都不读的数即可。\n\n【详解】A。3007读作三千零七，读出一个零，不符合题意;B。4050读作四千零五十，读出一个零，不符合题意;C。8000读作八千，末尾的零不读，符合题意。故答案为:C",
+        "knowledge_points":  [
+                                 "万以内数的读，写法"
+                             ],
+        "source":  "24-25二年级下·河南郑州·期末"
+    },
+    {
+        "id":  "123",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "妈妈想买一件458元的衣服和一条三百多元的裤子，带1000元够吗。( )。",
+        "options":  [
+                        "A. 够了",
+                        "B. 不够",
+                        "C. 无法确定",
+                        "D. 其他说法都不对"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】根据题意，把衣服和裤子的价格分别看成与之接近的整百数或整百整十数，相加求和后与1000元比较大小，即可解答。\n\n【详解】把458元看成500元，把三百多看成400元，两个价格都估大了。500+400=900(元),900<1000，带1000元够了。故答案为:A",
+        "knowledge_points":  [
+                                 "1000以内数的比大小",
+                                 "万以内数加减法的估算"
+                             ],
+        "source":  "24-25 二年级下·浙江台州·期末"
+    },
+    {
+        "id":  "124",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "下面各数中一个零都不读的数是( )。",
+        "options":  [
+                        "A. 3070",
+                        "B. 5067",
+                        "C. 6009",
+                        "D. 8000"
+                    ],
+        "answer":  "D",
+        "solution":  "【分析】一个四位数，从右往左依次为个位，十位，百位，千位。万以内数的读法：从高位读起，千位上是几，读作几千;百位上是几，读作几百;十位上是几，读作几十;个位上是几，读作几;末尾的0不读，中间的1个或连续2个0，只读一个零。据此读出选项中各个数，找出一个零都不读的数即可。\n\n【详解】A。3070读作：三千零七十，读出一个零;B。5067读作：五千零六十七，读出一个零;C。6009读作：六千零九，读出一个零;D。8000读作：八千，一个零也不读。故答案为:D",
+        "knowledge_points":  [
+                                 "万以内数的读，写法"
+                             ],
+        "source":  "24-25二年级下·浙江台州·期末"
+    },
+    {
+        "id":  "125",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "500张A4复印纸摞起来大约厚5厘米。现在有1500张同样的A4复印纸，摞起来大约厚( )厘米。",
+        "options":  [
+                        "A. 10",
+                        "B. 12",
+                        "C. 15",
+                        "D. 20"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】根据题意,500张复印纸摞起来大约厚5厘米，看1500里面有多少个500，就是1500张纸有几个5厘米。以此答题即可。\n\n【详解】根据分析可知:500+500+500=1000+500=1500(张),1500里面有3个500.3×5=15(厘米),500张A4复印纸摞起来大约厚5厘米。现在有1500张同样的A4复印纸，摞起来大约厚15厘米。故答案为:C",
+        "knowledge_points":  [
+                                 "5的乘法口诀及应用",
+                                 "整百数",
+                                 "几百几十数的加减法口算"
+                             ],
+        "source":  "25-26 三年级上·全国·阶段练习"
+    },
+    {
+        "id":  "126",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "估一估，结果小于400的算式是( )。",
+        "options":  [
+                        "A. 289+302",
+                        "B. 198+201",
+                        "C. 299+204"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】把每个选项中的两个加数看成与之接近的整百数或整百整十数，求出和再与400比较大小，选出结果小于400的算式即可。\n\n【详解】A。289+302，把289看作300，把302看作300,300+300=600,600>400，结果大于400，不符合题意;B。198+201，把198看作200，估大2，把201看作200，估小了1,200+200=400,400=400，实际的结果小于400，符合题意;C。299+204，把299看作300，把204看作200,300+200=500,500>400，结果大于400，不符合题;故答案为:B",
+        "knowledge_points":  [
+                                 "万以内数加减法的估算",
+                                 "1000以内数的比大小"
+                             ],
+        "source":  "24-25 二年级下·山东济南·期中"
+    },
+    {
+        "id":  "127",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "下面三个数中，一个零也不读的数是( )。",
+        "options":  [
+                        "A. 6030",
+                        "B. 6400",
+                        "C. 5004"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】读一个四位数，从高位往低位读，千位上的数读作几千，百位上的数读作几百，十位上的数读作几十，个位上的数读作几，中间的一个0或连续两个0，都只读一个\"零\"，末尾的0不用读。据此读出每一个数，找出符合题意的选项即可。\n\n【详解】A。6030读作\"六千零三十\"，中间的零需读出，不符合条件。B。6400读作\"六千四百\"，末尾的零不读，符合条件。C。5004读作\"五千零四\"，中间的零需读出，不符合条件。即，一个零也不读的数是(6400)。故答案为:B",
+        "knowledge_points":  [
+                                 "万以内数的读，写法"
+                             ],
+        "source":  "24-25 二年级下·广东阳江·期末"
+    },
+    {
+        "id":  "128",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "5964>593□,□里最大能填( )。",
+        "options":  [
+                        "A. 9",
+                        "B. 8",
+                        "C. 7"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】整数比较大小的方法，位数多的数大于位数少的数;位数相同的数，从最高位比起，最高位上大的数就大，最高位上相同的，就比较下一位，以此类推。据此解决此题。\n\n【详解】5964和593□都是四位数，从高位开始逐位比较。千位和百位相同，十位上6>3，因此无论个位填何数,5964都大于593□,故□最大可填9。故答案为:A",
+        "knowledge_points":  [
+                                 "万以内数的大小比较"
+                             ],
+        "source":  "24-25 二年级下·广东阳江·期末"
+    },
+    {
+        "id":  "129",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "6982中的8表示( )。",
+        "options":  [
+                        "A. 8个一",
+                        "B. 8个十",
+                        "C. 8个百"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】一个四位数，从右往左数，第一位是个位，个位上的数表示几个一;第二位是十位，十位上的数表示几个十;第三位是百位，百位上的数表示几个百;第四位是千位，千位上的数表示几个千;据此解决即可。\n\n【详解】6982中的8在十位上，表示(8个十)。故答案为:B",
+        "knowledge_points":  [
+                                 "万以内数的组成"
+                             ],
+        "source":  "24-25 二年级下·广东阳江·期末"
+    },
+    {
+        "id":  "130",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "下面各数中，一个零也不读的是( )。",
+        "options":  [
+                        "A. 3008",
+                        "B. 3080",
+                        "C. 3800"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】根据整数的读法：从高位到低位，一级一级地读，每一级末尾的0都不读出来，其余数位连续几个0都只读一个零，逐个分析选项即可解答。\n\n【详解】A。3008读作三千零八，不符合题意;B。3080读作三千零八十，不符合题意;C。3800读作三千八百，符合题意。故答案为:C",
+        "knowledge_points":  [
+                                 "万以内数的读，写法"
+                             ],
+        "source":  "24-25二年级下·甘肃兰州·期末"
+    },
+    {
+        "id":  "131",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "妈妈本月支出生活费297元，爸爸支出405元，爸爸妈妈大约一共支出( )元。",
+        "options":  [
+
+                    ],
+        "answer":  "700",
+        "solution":  "【分析】由题意可知：分别找出爸爸妈妈本月支出生活费最接近整百数的近似数，再相加，即可知爸爸妈妈大约共支出的钱数;据此解答。\n\n【详解】由分析可得:297≈300,405≈400;300+400=700(元),妈妈本月支出生活费297元，爸爸支出405元，爸爸妈妈大约一共支出700元。",
+        "knowledge_points":  [
+                                 "1000以内数的估计",
+                                 "整百数",
+                                 "几百几十数的加减法口算",
+                                 "万以内数加减法的估算"
+                             ],
+        "source":  "24-25 二年级下·青海果洛·期末"
+    },
+    {
+        "id":  "132",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "由3个千,5个百和7个十组成的数是( ),读作( )。",
+        "options":  [
+
+                    ],
+        "answer":  "3570;三千五百七十",
+        "solution":  "【分析】3个千就是3000,5个百就是500,7个十就是70，合起来就是3570;读一个四位数，从高位往低位读，千位上的数读作几千，百位上的数读作几百，十位上是几就读几十，个位上的数读作几，中间的一个0或连续两个0，都只读一个\"零\"，末尾的0不用读。\n\n【详解】由题意分析得：由3个千,5个百和7个十组成的数是3570，读作：三千五百七十。",
+        "knowledge_points":  [
+                                 "万以内数的读，写法",
+                                 "万以内数的组成"
+                             ],
+        "source":  "24-25 二年级下·陕西延安·期末"
+    },
+    {
+        "id":  "133",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在数位顺序表中，从右边起第三位是( )位;一个四位数的最高位是( )位。",
+        "options":  [
+
+                    ],
+        "answer":  "百;千",
+        "solution":  "【分析】数位顺序表中，从右往左数，第一位是个位，第二位是十位，第三位是百位，第四位是千位。一个整数，最左边的数位是最高位，由此解答。\n\n【详解】由分析得：在数位顺序表中，从右边起第三位是百位;一个四位数的最高位是千位，如1000的最高位是千位。",
+        "knowledge_points":  [
+                                 "整数的数级",
+                                 "数位和计数单位的认识",
+                                 "1000以内数的组成"
+                             ],
+        "source":  "24-25 二年级下·湖南张家界·期末"
+    },
+    {
+        "id":  "134",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "一个数由6个千和7个十组成，这个数写作( ),它前面第四个数是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "6070;6066",
+        "solution":  "【分析】一个四位数，从右往左依次为个位，十位，百位，千位;千位是几表示几个千，百位是几表示几个百，十位是几表示几个十，个位是几表示几个一;这个数千位是6，十位是7;把这个数前面的4个数都找出来数一数，即可知它前面第四个数是几;据此解答。\n\n【详解】由分析可得：这个数是6070，它前面的4个数分别是:6069,6068,6067,6066，故第四个数是6066;一个数由6个千和7个十组成，这个数写作6070，它前面第四个数是6066。",
+        "knowledge_points":  [
+                                 "万以内数的组成",
+                                 "万以内数的读，写法",
+                                 "数万以内的数"
+                             ],
+        "source":  "24-25 二年级下·江西赣州·期末"
+    },
+    {
+        "id":  "135",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在\"2002\"中，从左边起第一个2表示2个( ),第二个2表示2个( )。",
+        "options":  [
+
+                    ],
+        "answer":  "千;一",
+        "solution":  "【分析】一个四位数，从右往左依次为个位，十位，百位，千位;千位是几表示几个千，百位是几表示几个百，十位是几表示几个十，个位是几表示几个一;2002左边第一个2在千位上，第二个2在个位上;据此解答。\n\n【详解】由分析可得：在\"2002\"中，从左边起第一个2表示2个千，第二个2表示2个一。",
+        "knowledge_points":  [
+                                 "万以内数的组成"
+                             ],
+        "source":  "24-25 二年级下·江西赣州·期末"
+    },
+    {
+        "id":  "136",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "60个十是( ),10000里面有( )个一百。",
+        "options":  [
+
+                    ],
+        "answer":  "600;100",
+        "solution":  "【分析】10个十是100,20个十是200。60个十是600;10个一百是1000,100个一百是10000;据此可解。\n\n【详解】由分析可得:60个十是600,10000里面有100个一百。",
+        "knowledge_points":  [
+                                 "万以内数的组成",
+                                 "1000以内数的组成"
+                             ],
+        "source":  "24-25 二年级下·江西赣州·期末"
+    },
+    {
+        "id":  "137",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "一台电脑的价格是4998元，大约是( )元，一台冰箱的价格是2001元，电脑比冰箱大约贵( )元。",
+        "options":  [
+
+                    ],
+        "answer":  "5000;3000",
+        "solution":  "【分析】根据题意，将电脑和冰箱的价格看成与之接近的整千数，相减即可计算出一部电脑比一台冰箱大约贵多少元。\n\n【详解】4998元看成5000元;2001元看成2000元。5000-2000=3000(元),一台电脑的价格是4998元，大约是5000元，一台冰箱的价格是2001元，电脑比冰箱大约贵3000元。",
+        "knowledge_points":  [
+                                 "万以内数加减法的估算",
+                                 "万以内数的估计"
+                             ],
+        "source":  "24-25二年级下·湖南张家界·期末"
+    },
+    {
+        "id":  "138",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "5030读作( ),最高位上的5表示( ),3在( )位上，表示( )。",
+        "options":  [
+
+                    ],
+        "answer":  "五千零三十;5个千;十;3个十",
+        "solution":  "【分析】一个整数，从右往左依次为个位，十位，百位，千位。千位是几表示几个千，百位是几表示几个百，十位是几表示几个十，个位是几表示几个一。读数时，从高位读起，按照数位顺序读。千位是几就读几千，百位是几就读几百。中间有一个0或两个0，只读一个零;末尾不管有几个0，都不读。\n\n【详解】5030读作五千零三十，最高位上的5表示5个千,3在十位上，表示3个十。",
+        "knowledge_points":  [
+                                 "万以内数的组成",
+                                 "万以内数的读，写法"
+                             ],
+        "source":  "24-25 二年级下·湖南张家界·期末"
+    },
+    {
+        "id":  "139",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "口算450-210时，可以想:( )个十减去( )个十得( )个十，所以结果也就是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "45;21;24;240",
+        "solution":  "【分析】根据整数口算的计算法则，十位上数字几表示几个十，百位上数字几表示几十个十，然后进行减法运算，最后将结果转化成具体的数。据此解答。\n\n【详解】45-21=24，所以，口算450-210时，可以想:45个十减去21个十得24个十，所以结果也就是240。",
+        "knowledge_points":  [
+                                 "整百数",
+                                 "几百几十数的加减法口算"
+                             ],
+        "source":  "25-26三年级上·广东汕头·开学考试"
+    },
+    {
+        "id":  "140",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "下面是二(1)班同学1分钟跳绳比赛成绩.\n\n| 学号 | 下数 | 学号 | 下数 | 学号 | 下数 | 学号 | 下数 |\n| ---- | ---- | ---- | ---- | ---- | ---- | ---- | ---- |\n| 1号 | 65 | 11号 | 87 | 21号 | 142 | 31号 | 96 |\n| 2号 | 90 | 12号 | 79 | 22号 | 98 | 32号 | 108 |\n| 3号 | 85 | 13号 | 114 | 23号 | 103 | 33号 | 74 |\n| 4号 | 110 | 14号 | 139 | 24号 | 99 | 34号 | 89 |\n| 5号 | 123 | 15号 | 101 | 25号 | 87 | 35号 | 93 |\n| 6号 | 94 | 16号 | 98 | 26号 | 95 | 36号 | 97 |\n| 7号 | 99 | 17号 | 88 | 27号 | 93 | 37号 | 104 |\n| 8号 | 132 | 18号 | 86 | 28号 | 90 | 38号 | 118 |\n| 9号 | 108 | 19号 | 79 | 29号 | 81 | 39号 | 135 |\n| 10号 | 85 | 20号 | 56 | 30号 | 95 | 40号 | 120 |\n\n(1)一共有( )名同学参加了跳绳比赛.\n(2)跳绳最多的跳了( )下，跳绳最少的跳了( )下.\n(3)16号同学比3号同学多跳了( )下,19号同学比25号同学少跳了( )下。",
+        "options":  [
+
+                    ],
+        "answer":  "40;142;56;13;8",
+        "solution":  "【分析】(1)表格中有学号1号至40号，每个学号均有对应的跳绳个数，因此参赛人数为40名。(2)比较所有数据找出最大、最小数，即可知道跳绳最多跳了几下，跳绳最少跳了几下；(3)用16号同学跳的下数减去3号同学跳的下数，就是16号同学比3号同学多跳的下数；用25号同学跳的下数减去19号同学跳的下数，就是19号同学比25号同学少跳了多少下；据此解答。\n\n【详解】(1)由分析可得：一共有40名同学参加了跳绳比赛。(2)观察所有跳绳下数：最大数是21号同学跳了142下；最小数是20号同学跳了56下；跳绳最多的跳了142下，跳绳最少的跳了56下。(3)16号同学跳了98下，3号同学跳了85下，98-85=13(下)；19号同学跳了79下，25号同学跳了87下，87-79=8(下)，16号同学比3号同学多跳了13下，19号同学比25号同学少跳了8下。",
+        "knowledge_points":  [
+                                 "两位数与两位数的退位减法",
+                                 "两位数与两位数的不退位减法",
+                                 "1000以内数的比大小",
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "24-25 二年级下·湖北黄冈·期末"
+    },
+    {
+        "id":  "141",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "10张100元人民币是( )元,( )张100元人民币是10000元。",
+        "options":  [
+
+                    ],
+        "answer":  "1000;100",
+        "solution":  "【分析】根据数的组成可知,1个百是100,2个百是200。10个百是1000，也就是10张100元是1000元;100个百是10000，也就是100张100元是10000元。\n\n【详解】10张100元人民币是1000元,100张100元人民币是10000元。",
+        "knowledge_points":  [
+                                 "十元以上人民币的认识与计算",
+                                 "万以内数的组成"
+                             ],
+        "source":  "24-25 二年级下·湖北黄冈·期末"
+    },
+    {
+        "id":  "142",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.94,
+        "question":  "一百一百地数,4500后面是( ),一十一十地数,2150前面是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "4600;2140",
+        "solution":  "【分析】一百一百地数，求4500后面的数是多少，即求比4500多100的数是多少，用4500加100即可求得;一十一十地数，求2150前面的数是多少，即求比2150少10的数是多少，用2150减去10即可求得。\n\n【详解】4500+100=4600,2150-10=2140，一百一百地数,4500后面是4600，一十一十地数,2150前面是2140。",
+        "knowledge_points":  [
+                                 "整百数",
+                                 "几百几十数的加减法口算",
+                                 "数万以内的数"
+                             ],
+        "source":  "24-25 二年级下·湖北黄冈·期末"
+    },
+    {
+        "id":  "143",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "一个密码锁的密码是7650，它是( )位数，最高位是( )位，数字6在( )位上，表示( )个( )。",
+        "options":  [
+
+                    ],
+        "answer":  "四;千;百;6;百",
+        "solution":  "【分析】7650由四个数字(7,6,5,0)组成，所以是四位数，一个四位数，从右往左依次为个位，十位，百位，千位;最左的那一位就是它的最高位,7650最高位是千位;千位是几表示几个千，百位是几表示几个百，十位是几表示几个十，个位是几表示几个一，据此解答。\n\n【详解】根据分析可得：一个密码锁的密码是7650，它是四位数，最高位是千位，数字6在百位上，表示6个百。",
+        "knowledge_points":  [
+                                 "万以内数的组成"
+                             ],
+        "source":  "24-25 二年级下·湖北黄冈·期末"
+    },
+    {
+        "id":  "144",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "用6,6,0,9这四个数字组成的最大的四位数是( ),组成的最小的四位数是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "9660;6069",
+        "solution":  "【分析】一个四位数，从右往左依次为个位，十位，百位，千位。要组成最大的四位数，则把数字从大到小按数位从千位到个位排列;要组成最小的四位数，千位不能为0，则把0以外最小的数字写在千位，剩下的数字从小到大依次写在百位，十位和个位。\n\n【详解】0<6=6<9，用6,6,0,9这四个数字组成的最大的四位数是9660，组成的最小的四位数是6069。",
+        "knowledge_points":  [
+                                 "万以内数的大小比较",
+                                 "万以内数的组成"
+                             ],
+        "source":  "24-25 二年级下·安徽淮南·期末"
+    },
+    {
+        "id":  "145",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "太平洋的平均深度大约是三千九百五十七米。横线上的数写作( ),它的近似数是( )(填整千数)。",
+        "options":  [
+
+                    ],
+        "answer":  "3957;4000",
+        "solution":  "【分析】首先将汉字\"三千九百五十七\"转化为数字，按数位顺序写出每一位对应的数字，三千表示千位是3，九百表示百位是9，五十表示十位是5，七表示个位是7，按照从左向右依次是\"千百十个\"，所以数字3957，根据百位上的数字判断，百位是9，大于5，因此接近4000。\n\n【详解】太平洋的平均深度大约是三千九百五十七米。横线上的数写作3957，它的近似数是4000(填整千数)。",
+        "knowledge_points":  [
+                                 "万以内数的估计",
+                                 "万以内数的组成",
+                                 "万以内数的读，写法"
+                             ],
+        "source":  "24-25 二年级下·安徽淮南·期末"
+    },
+    {
+        "id":  "146",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "1545是由( )个千,( )个百,( )个十和( )个一组成的，读作( )。",
+        "options":  [
+
+                    ],
+        "answer":  "1;5;4;5;一千五百四十五",
+        "solution":  "【分析】一个整数，从右往左依次为个位，十位，百位，千位。千位是几就有几个千，百位是几就有几个百，十位是几就有几个十，个位是几就有几个一。读数时，从高位读起，按照数位顺序读。千位是几就读几千，百位是几就读几百。中间有一个0或两个0，只读一个零;末尾不管有几个0，都不读。\n\n【详解】1545是由1个千,5个百,4个十和5个一组成的，读作一千五百四十五。",
+        "knowledge_points":  [
+                                 "万以内数的组成",
+                                 "万以内数的读，写法"
+                             ],
+        "source":  "24-25 二年级下·安徽淮南·期末"
+    },
+    {
+        "id":  "147",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "用3,9,0,1这四个数字组成四位数.\n组成最大的四位数是( )。 组成最小的四位数是( ).\n只读一个零的数是( )。 一个零都不读的数是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "9310;1039;1039、1093、1309、1903、3019、3091、3109、3901、9013、9031、9103、9301;9310、9130、3910、3190、1930、1390",
+        "solution":  "【分析】把3、9、0、1这四个数字，按照从大到小的顺序排列，组成的即是最大的四位数；把3、9、0、1这四个数字，按照从小到大的顺序排列，0不能放到最高位上，就和排第二的数字交换位置，这样组成的即是最小的四位数；万以内数的读法：从高位读起，千位上是几，读作几千；百位上是几，读作几百；十位上是几，读作几十；个位上是几，读作几；末尾的0不读，中间的1个或连续2个0，只读1个零。据此可解。\n\n【详解】由分析可得：组成最大的四位数是9310，组成最小的四位数是1039。只读一个零的数是1039、1093、1309、1903、3019、3091、3109、3901、9013、9031、9103、9301。一个零都不读的数是9310、9130、3910、3190、1930、1390。",
+        "knowledge_points":  [
+                                 "万以内数的读，写法",
+                                 "万以内数的组成",
+                                 "万以内数的大小比较"
+                             ],
+        "source":  "24-25 二年级下·云南曲靖·期末"
+    },
+    {
+        "id":  "148",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "\"六·一\"儿童节，小红买书用了306元，买文具用了189元。她一共大约用了( )元钱。",
+        "options":  [
+
+                    ],
+        "answer":  "500",
+        "solution":  "【分析】由题意可知：题目要求估算小红一共用了多少钱，先找出两个数接近整百数的近似数，再相加;据此解答。\n\n【详解】由分析可得:306≈300,189≈200;300+200=500(元),\"六·一\"儿童节，小红买书用了306元，买文具用了189元。她一共大约用了500元钱。",
+        "knowledge_points":  [
+                                 "万以内数加减法的估算",
+                                 "1000以内数的估计"
+                             ],
+        "source":  "24-25 二年级下·云南曲靖·期末"
+    },
+    {
+        "id":  "149",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "下图中箭头指向的数，大约是( ).\n![](images/184f55c6cba1a7e84b4e0338c5020ddad160d4e467304d81778cb1b1825b6ecc.jpg)",
+        "options":  [
+
+                    ],
+        "answer":  "9750",
+        "solution":  "【分析】由题图可知：通过观察，横轴上一格表示100，从9500向后数格分别是:9600,9700,9800,9900，箭头所在的位置位于9700和9800之间正中间的位置，故箭头指向的数字大约是9750;据此解答。\n\n【详解】由分析可得：下图中箭头指向的数，大约是9750。",
+        "knowledge_points":  [
+                                 "万以内数的估计"
+                             ],
+        "source":  "24-25 二年级下·海南省直辖县级单位·期末"
+    },
+    {
+        "id":  "150",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "一个数由3个千和6个一组成，这个数写作( ),它后面第五个数是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "3006;3011",
+        "solution":  "【分析】一个四位数，从右往左依次是个位、十位、百位、千位，写数时，从高位写起，有几个千就在千位写几，有几个百就在百位写几，有几个十就在十位写几，有几个一就在个位写几，哪一位上一个单位也没有，就在那一位上写0；求它后面第五个数是几，从这个数开始往后数5个数即可。\n\n【详解】一个数由3个千和6个一组成，这个数写作3006，它后面第五个数是3011。",
+        "knowledge_points":  [
+                                 "数万以内的数",
+                                 "万以内数的读，写法",
+                                 "万以内数的组成"
+                             ],
+        "source":  "24-25 二年级下·江西赣州·期末"
+    },
+    {
+        "id":  "151",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在\"5050\"中，从右边起第一个5表示5个( ),第二个5表示5个( )。",
+        "options":  [
+
+                    ],
+        "answer":  "十;千",
+        "solution":  "【分析】一个四位数，从右往左依次为个位，十位，百位，千位，千位是几表示几个千，百位是几表示几个百，十位是几表示几个十，个位是几表示几个一，据此解答。\n\n【详解】在\"5050\"中，从右边起第一个5在十位上，表示5个十，第二个5在千位上，表示5个千。",
+        "knowledge_points":  [
+                                 "万以内数的组成"
+                             ],
+        "source":  "24-25 二年级下·江西赣州·期末"
+    },
+    {
+        "id":  "152",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "40个十是( ),5400里面有( )个百。",
+        "options":  [
+
+                    ],
+        "answer":  "400;54",
+        "solution":  "【分析】1个十是10,2个十是20。40个十是400;1个百是100,2个百是200。54个百是5400，故5400里面有54个百，据此解答。\n\n【详解】根据分析可得:40个十是400,5400里面有54个百。",
+        "knowledge_points":  [
+                                 "1000以内数的组成",
+                                 "万以内数的组成"
+                             ],
+        "source":  "24-25 二年级下·江西赣州·期末"
+    },
+    {
+        "id":  "153",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "图中\"●\"表示的数是( ),它与最小的三位数相差( ).\n![](images/85947ba5c367cf28f0e833f04359c5bfda62088a53e19a01988cc19c1147bc8b.jpg)",
+        "options":  [
+
+                    ],
+        "answer":  "1060;960",
+        "solution":  "【分析】1000与1100相差100,1000与1100之间平均分成10小格，则每小格就表示10;1000到\"●\"之间有6小格，也就是\"●\"表示的数比1000大60，即\"●\"表示的数是1060。再用减法求出1060与最小的三位数(100)的差即可解决。\n\n【详解】1060-100=960，即，图中\"●\"表示的数是1060，它与最小的三位数相差960。",
+        "knowledge_points":  [
+                                 "整百数",
+                                 "几百几十数的加减法口算"
+                             ],
+        "source":  "24-25 二年级下·四川成都·期中"
+    },
+    {
+        "id":  "154",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在9,0,0,2组成的四位数中，组成的最小四位数是( ),它的近似数是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "2009;2000",
+        "solution":  "【分析】一个四位数，从右往左依次为个位，十位，百位，千位。要组成最小的四位数，千位不能为0，则把0以外最小的数写在千位，剩下的数字从小到大依次写在百位，十位和个位。它的近似数可以是与之接近的整千数。\n\n【详解】0<2<9，在9,0,0,2组成的四位数中，组成的最小四位数是2009，它的近似数是2000。",
+        "knowledge_points":  [
+                                 "万以内数的估计",
+                                 "万以内数的组成"
+                             ],
+        "source":  "24-25 二年级下·湖北孝感·期末"
+    },
+    {
+        "id":  "155",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "用4张卡片2,6,0,9组成的四位数中，最大的是( ),最接近9000的是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "9620;9026",
+        "solution":  "【分析】由题意可知：把2,6,0,9这几个数字按从大到小顺序排列，组成的数即是最大的四位数;把9放到千位上，剩余的数字按照从小到大的顺序排列，组成的数是最接近9000的数。\n\n【详解】由分析可得：用4张卡片2,6,0,9组成的四位数中，最大的是9620，最接近9000的是9026。",
+        "knowledge_points":  [
+                                 "万以内数的组成",
+                                 "万以内数的大小比较"
+                             ],
+        "source":  "24-25 二年级下·浙江杭州·期末"
+    },
+    {
+        "id":  "156",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "由7个千,8个十和9个一组成的数是( ),与它相邻的两个数是( )和( )。",
+        "options":  [
+
+                    ],
+        "answer":  "7089;7088;7090",
+        "solution":  "【分析】一个四位数，从右往左依次为个位，十位，百位，千位;千位是几表示几个千，百位是几表示几个百，十位是几表示几个十，个位是几表示几个一;这个数：千位是7，百位上是0，十位是8，个位是9;与这个数相邻的两个数分别是：它前面比它小1的数，和它后面比它大1的数;据此解答。\n\n【详解】由分析可得：由7个千,8个十和9个一组成的数是7089，与它相邻的两个数是7088和7090。",
+        "knowledge_points":  [
+                                 "万以内数的组成",
+                                 "相邻的数"
+                             ],
+        "source":  "24-25 二年级下·浙江杭州·期末"
+    },
+    {
+        "id":  "157",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "3699和3701中间的数是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "3700",
+        "solution":  "【分析】由题意可知:3699向后数一个数是3700,3701向前数一个数也是3700，故3700是3699和3701中间的数;据此可填空。\n\n【详解】由分析可得:3699和3701中间的数是3700。",
+        "knowledge_points":  [
+                                 "数万以内的数"
+                             ],
+        "source":  "24-25 二年级下·广东潮州·期末"
+    },
+    {
+        "id":  "158",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "( )里最大能填几？\n685 > ( )93\n6 × ( ) < 50\n17 > ( ) × 8\n( ) ÷ 8 = 4……( )",
+        "options":  [
+
+                    ],
+        "answer":  "5;8;2;39;7",
+        "solution":  "【分析】比较大小方法：①位数多的数大于位数少的数；②位数相同的，先比较最高位上的数，最高位上大的数就大，最高位数相同的，就比较下一位，以此类推。第1题从最高位百位比较起，找出比百位数字6小的数字，再从中找出最大的数即可；第2、3题用不等号两边的数比较大小，求出括号里最大能填几；第4题余数要比除数小，除数是8，余数最大是7，再根据被除数=商×除数+余数求出最大的被除数，据此解答。\n\n【详解】由分析可得：685 > ( )93，比百位数字6小的数字有5、4、3、2、1，最大填5，故685 > 593；6 × ( ) < 50，50÷6=8……2，故6 × 8 < 50；17 > ( ) × 8，17÷8=2……1，故17 > 2 × 8；( ) ÷ 8 = 4……( )，最大的余数是7，4×8+7=32+7=39，故39÷8=4……7。",
+        "knowledge_points":  [
+                                 "1000以内数的比大小",
+                                 "余数与除数的关系",
+                                 "100以内有余数的除法计算",
+                                 "有余数的除法验算"
+                             ],
+        "source":  "24-25 二年级下·广东潮州·期末"
+    },
+    {
+        "id":  "159",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "6个千和4个一是( ),读作( )。",
+        "options":  [
+
+                    ],
+        "answer":  "6004;六千零四",
+        "solution":  "【分析】一个四位数，从右往左依次为个位，十位，百位，千位;千位是几表示几个千，百位是几表示几个百，十位是几表示几个十，个位是几表示几个一;读数时，从高位读起，按照数位顺序读。千位是几就读几千，百位是几就读几百，十位上是几就读几十，个位上是几就读几，中间有一个0或两个0，只读一个零;末尾不管有几个0，都不读。这个数：千位是6，个位是4;据此解答。\n\n【详解】由分析可得:6个千和4个一是6004，读作六千零四。",
+        "knowledge_points":  [
+                                 "万以内数的读，写法",
+                                 "万以内数的组成"
+                             ],
+        "source":  "24-25 二年级下·广东潮州·期末"
+    },
+    {
+        "id":  "160",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "用0,4,5,9这4个数字组数，最小的且一个零也不读的四位数是( ),最接近5000的数是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "4590;5049",
+        "solution":  "【分析】一个四位数，从右往左依次为个位，十位，百位，千位，要想组成的数最小：先比较四个数字的大小，然后把0以外最小的数写在最高位，剩余数字按从小到大的顺序依次写在百位，十位和个位;读数时，从高位读起，千位是几就读几千，百位上是几就读几百，十位上是几就读几十。中间有一个0或两个0的，只读一个\"零\"，末尾不管有几个0都不读;要组成最小且一个零也不读的四位数，千位数字要最小,0要放在末尾，剩余数字从小到大依次写在百位和十位;最接近5000的数，千位应是5，剩余的数字从小到大依次写在百位，十位和个位。\n\n【详解】0<4<5<9，用0,4,5,9这4个数字组数，最小的且一个零也不读的四位数是4590，最接近5000的数是5049。",
+        "knowledge_points":  [
+                                 "万以内数的读，写法",
+                                 "万以内数的组成",
+                                 "万以内数的大小比较"
+                             ],
+        "source":  "24-25二年级下·浙江台州·期末"
+    },
+    {
+        "id":  "161",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "一台电视机2098元，约是( )元，购买这台电视机至少要带( )张面值为100元的人民币。",
+        "options":  [
+
+                    ],
+        "answer":  "2100;21",
+        "solution":  "【分析】后面求需要多少张面值100元的人民币，则估为整千整百数。2098元百位上是0，十位上是9，大于5，则大约是2100元,2100里面有21个百，所以购买这台电视机至少要带21张面值为100元的人民币。\n\n【详解】一台电视机2098元，约是2100元，购买这台电视机至少要带21张面值为100元的人民币。",
+        "knowledge_points":  [
+                                 "万以内数的组成",
+                                 "万以内数的估计",
+                                 "十元以上人民币的认识与计算"
+                             ],
+        "source":  "24-25 二年级下·浙江台州·期末"
+    },
+    {
+        "id":  "162",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "由数字2,6,0,8组成的最大的四位数是( ),最小的四位数是( ),这两个数大约相差( )。",
+        "options":  [
+
+                    ],
+        "answer":  "8620;2068;6500",
+        "solution":  "【分析】据题意，组成的是4位数，所以0不能在千位，最大的四位数，千位应该是最大的8，百位的数是剩余中最大的数6，十位的数是剩余中最大的数2，个位是0，即可组成最大的四位数;最小的四位数，千位应该是最小的2，百位的数是剩余中最小的数0，十位的数是剩余中最小的数6，个位是8，即可组成最小的四位数;再简单估算这两个四位数的差即可。\n\n【详解】据分析可得：最大的数是8620，最小的数是2068，两数相差8620-2068≈6500。所以，由数字2,6,0,8组成的最大的四位数是8620，最小的四位数是2068，这两个数大约相差6500。",
+        "knowledge_points":  [
+                                 "万以内数的组成",
+                                 "万以内数的大小比较",
+                                 "万以内数的估计"
+                             ],
+        "source":  "24-25 二年级下·浙江湖州·期末"
+    },
+    {
+        "id":  "163",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "由8个千,3个十和9个一组成的数是( ),与它接近的整千数是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "8039;8000",
+        "solution":  "【分析】一个四位数从右往左依次是个位，十位，百位，千位，四位数千位上的数表示几个千，百位上的数表示几个百，十位上的数表示几个十，个位上的数表示几个一;找一个数的近似数时，把这个整数看作和它接近的整十，整百或整千数。\n\n【详解】由8个千,3个十和9个一组成的数是8039，与它接近的整千数是8000。",
+        "knowledge_points":  [
+                                 "万以内数的组成",
+                                 "万以内数的估计"
+                             ],
+        "source":  "24-25 二年级下·浙江湖州·期末"
+    },
+    {
+        "id":  "164",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "收费站昨天通过了8007辆车，约是( )辆。",
+        "options":  [
+
+                    ],
+        "answer":  "8000",
+        "solution":  "【分析】根据题意，将8007看成与之接近的整千数即可解答。\n\n【详解】8007接近8000，则收费站昨天通过了8007辆车，约是8000辆。",
+        "knowledge_points":  [
+                                 "万以内数的估计"
+                             ],
+        "source":  "24-25 二年级下·福建厦门·期末"
+    },
+    {
+        "id":  "165",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "小新的爸爸喜欢走路锻炼身体，今天他的手机软件上显示走了9630步，这个数读作( ),它是由( )个千( )个百和( )个十组成的。",
+        "options":  [
+
+                    ],
+        "answer":  "九千六百三十;9;6;3",
+        "solution":  "【分析】一个整数，从右往左依次为个位，十位，百位，千位。千位是几表示几个千，百位是几表示几个百，十位是几表示几个十，个位是几表示几个一。读数时，从高位读起，按照数位顺序读。千位是几就读几千，百位是几就读几百。中间有一个0或两个0，只读一个零;末尾不管有几个0，都不读。\n\n【详解】小新的爸爸喜欢走路锻炼身体，今天他的手机软件上显示走了9630步，这个数读作九千六百三十，它是由9个千6个百和3个十组成的。",
+        "knowledge_points":  [
+                                 "万以内数的读，写法",
+                                 "万以内数的组成"
+                             ],
+        "source":  "24-25 二年级下·江西赣州·期末"
+    },
+    {
+        "id":  "166",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在学校组织的古诗词大赛中，三年级同学背诵的古诗词数量最多，二年级同学背诵的古诗词数量比一年级同学多一些。请你根据条件把下表填完整.\n\n| ( )年级 | ( )年级 | ( )年级 |\n| ------------ | ------------ | ------------ |\n| 310首 | 140首 | 175首 |",
+        "options":  [
+
+                    ],
+        "answer":  "三;一;二",
+        "solution":  "【分析】整数比较大小的方法，位数多的数大于位数少的数;位数相同的数，从最高位比起，最高位上大的数就大，最高位上相同的，就比较下一位，以此类推。根据题意可知，三年级同学背诵的古诗词数量最多，二年级同学背诵的古诗词数量排第二，一年级同学背诵的古诗词数量最少。比较各数的大小，找出答案并填空即可。\n\n【详解】由题意分析得:310>175>140，故，三年级同学背诵的古诗词是310首，二年级同学背诵的古诗词是175首，一年级同学背诵的古诗词是140首.\n\n| 三年级 | 一年级 | 二年级 |\n| ------ | ------ | ------ |\n| 310首 | 140首 | 175首 |",
+        "knowledge_points":  [
+                                 "1000以内数的比大小"
+                             ],
+        "source":  "24-25二年级下·湖北孝感·期末"
+    },
+    {
+        "id":  "167",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "用2,4,0,9组成四位数，其中组成的最大的数是( ),最小的数是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "9420;2049",
+        "solution":  "【分析】用2,4,0,9组成四位数，要组成最大的数，就需要把这四个数字从大到小依次排序在高位到低位;要组成最小的数，就需要先把除了0以外的最小数字2放在最高位，然后把剩下的三个数字从小到大依次排序在高位到低位;据此解决。\n\n【详解】由分析可知：用2,4,0,9组成四位数，其中组成的最大的数是9420，最小的数是2049。",
+        "knowledge_points":  [
+                                 "万以内数的组成",
+                                 "万以内数的大小比较"
+                             ],
+        "source":  "24-25 二年级下·湖北孝感·期末"
+    },
+    {
+        "id":  "168",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "2075读作( ),它是由( )个千,( )个十,( )个一组成的，它的最高位是( )位。",
+        "options":  [
+
+                    ],
+        "answer":  "二千零七十五;2;7;5;千",
+        "solution":  "【分析】读一个四位数，从高位往低位读，千位上的数读作几千，百位上的数读作几百，十位上的数读作几十，个位上的数读作几，中间的一个0或连续两个0，都只读一个\"零\"，末尾的0不用读。一个四位数，最高位是千位，从右往左数，第一位是个位，个位上的数表示几个一;第二位是十位，十位上的数表示几个十;第三位是百位，百位上的数表示几个百;第四位是千位，千位上的数表示几个千;据此填空即可。\n\n【详解】由题意分析得:2075读作：二千零七十五，它是由2个千,7个十,5个一组成的，它的最高位是千位。",
+        "knowledge_points":  [
+                                 "万以内数的读，写法",
+                                 "万以内数的组成"
+                             ],
+        "source":  "24-25 二年级下·湖北孝感·期末"
+    },
+    {
+        "id":  "169",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "口算150-60，可以这样想:( )。",
+        "options":  [
+
+                    ],
+        "answer":  "15个十减去6个十，得到9个十,9个十就是90，所以150-60=90。",
+        "solution":  "【分析】整十数相减，将被减数和减数看作几个十，然后进行减法运算，最后将结果转化成具体的数。\n\n【详解】150可以看作15个十,60可以看作6个十,15个十减去6个十，得到9个十,9个十就是90。所以口算150-60，可以这样想:15个十减去6个十，得到9个十,9个十就是90，所以150-60=90。",
+        "knowledge_points":  [
+                                 "整百数",
+                                 "几百几十数的加减法口算"
+                             ],
+        "source":  "24-25 二年级下·河南郑州·期末"
+    },
+    {
+        "id":  "170",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "一个四位数，最高位上是7，个位上是3，其余数位上都是0，这个数是( ),读作( )。",
+        "options":  [
+
+                    ],
+        "answer":  "7003;七千零三",
+        "solution":  "【分析】千位上是几就有几个千，百位上是几就有几个百，十位上是几就有几个十，个位上是几就有几个一。几个千就是几千，几个百就是几百，几个十就是几十，几个一就是几。整数的写法：从高位到低位，一级一级地写，哪一个数位上一个单位也没有，就在那个数位上写0。整数的读法：从高位到低位，一级一级地读，每一级末尾的0都不读出来，其余数位连续几个0都只读一个零。\n\n【详解】根据分析可得：一个四位数，最高位上是7，个位上是3，其余数位上都是0，这个数是7003，读作七千零三。",
+        "knowledge_points":  [
+                                 "万以内数的读，写法"
+                             ],
+        "source":  "24-25 二年级下·河南郑州·期末"
+    },
+    {
+        "id":  "171",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "用0,5,2,8这四张卡片摆四位数，其中最大的数是( );最小的数是( );大于5000并且小于5800的数有( )和( )。",
+        "options":  [
+
+                    ],
+        "answer":  "8520;2058;5028;5082",
+        "solution":  "【分析】一个四位数，从右往左依次为个位，十位，百位，千位。要组成最大的数，则将数字从大到小按数位从千位到个位排列;要组成最小的数，千位不能为0，则把0以外最小的数写在千位，剩下的数字从小到大依次写在百位，十位和个位;比较数的大小时，位数多的数就大，位数相同比较最高位，最高位大的数就大，最高位相同比较下一位，直到比较出结果为止。要组成大于5000且小于5800的数，则千位是5，百位是0或2，由此写数即可。\n\n【详解】0<2<5<8,5000<5028<5082<5208<5280<5800，用0,5,2,8这四张卡片摆四位数，其中最大的数是8520;最小的数是2058;大于5000并且小于5800的数有5028和5082。(最后两空答案不唯一)",
+        "knowledge_points":  [
+                                 "万以内数的组成",
+                                 "万以内数的大小比较"
+                             ],
+        "source":  "24-25 二年级下·浙江台州·期末"
+    },
+    {
+        "id":  "172",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "10000里面有( )个千,54个百是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "10;5400",
+        "solution":  "【分析】根据数的组成可知,1个千是1000,2个千是2000。10个千是10000;1个百是100,2个百是200。54个百是5400。\n\n【详解】10000里面有10个千,54个百是5400。",
+        "knowledge_points":  [
+                                 "万以内数的组成"
+                             ],
+        "source":  "24-25 二年级下·浙江台州·期末"
+    },
+    {
+        "id":  "173",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "小华家到学校有1008米，大约是( )米。",
+        "options":  [
+
+                    ],
+        "answer":  "1000",
+        "solution":  "【分析】由题意可知：找出小华家到学校距离最接近整千的近似数，即是大约的米数;据此解答。\n\n【详解】由分析可得:1008≈1000，小华家到学校有1008米，大约是1000米。",
+        "knowledge_points":  [
+                                 "万以内数的估计"
+                             ],
+        "source":  "24-25 二年级下·广东阳江·期末"
+    },
+    {
+        "id":  "174",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "2个千,5个十和4个一组成的数是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "2054",
+        "solution":  "【分析】四位数从右往左分别是：个位，十位，百位，千位;个位上是几，就表示几个一;十位上是几，就表示几个十;百位上是几，就表示几个百;千位上是几，就表示几个千。\n\n【详解】2个千表示千位上是2,5个十表示十位上是5,4个一表示个位上是4，百位上没有数用0占位。所以,2个千,5个十和4个一组成的数是2054。",
+        "knowledge_points":  [
+                                 "万以内数的组成"
+                             ],
+        "source":  "24-25二年级下·广东阳江·期末"
+    },
+    {
+        "id":  "175",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "由7个千和7个一组成的数是( ),它的最高位是( )位。",
+        "options":  [
+
+                    ],
+        "answer":  "7007;千",
+        "solution":  "【分析】一个四位数，从右往左依次为个位，十位，百位，千位;千位是几表示几个千，百位是几表示几个百，十位是几表示几个十，个位是几表示几个一;这个数：千位是7，个位是7;这个数从右往左数，第四位是千位;据此解答。\n\n【详解】由分析可得：由7个千和7个一组成的数是7007，它的最高位是千位。",
+        "knowledge_points":  [
+                                 "万以内数的组成"
+                             ],
+        "source":  "24-25 二年级下·广东阳江·期末"
+    },
+    {
+        "id":  "176",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "( )个一百是1000;10个十是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "10;100",
+        "solution":  "【分析】由题意可知:1000里面有10个一百,100里面有10个十;据此解答。\n\n【详解】由分析可得:10个一百是1000;10个十是100。",
+        "knowledge_points":  [
+                                 "1000以内数的组成",
+                                 "100以内数的组成"
+                             ],
+        "source":  "24-25 二年级下·广东阳江·期末"
+    },
+    {
+        "id":  "177",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "2026,2006,2600都只读一个零。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】一个四位数，从右往左依次为个位，十位，百位，千位;读数时，从高位读起，按照数位顺序读。千位是几就读几千，百位是几就读几百，十位上是几就读几十，个位上是几就读几，中间有一个0或两个0，只读一个零;末尾不管有几个0，都不读。2026中间有1个0，读一个0;2006中间有2个0，只读一个0;2600末尾有2个0，都不读;据此可判断。\n\n【详解】由分析可得:2026,2006都只读一个零,2600一个0也不读。故答案为: ×",
+        "knowledge_points":  [
+                                 "万以内数的读，写法"
+                             ],
+        "source":  "24-25 二年级下·江西赣州·期末"
+    },
+    {
+        "id":  "178",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "用900元买一个258元的锅和一床525元的被子肯定够。( )",
+        "options":  [
+
+                    ],
+        "answer":  "√",
+        "solution":  "【分析】由题意可知：找出一个锅和一床被子价格最接近整百数的近似数，把近似数相加，再和900元对比，小于等于900元，够;大于900元不够;据此解答。\n\n【详解】由分析可得:258≈300,525≈500;300+500=800(元),800<900，用900元买一个258元的锅和一床525元的被子肯定够。故答案为:√",
+        "knowledge_points":  [
+                                 "万以内数加减法的估算",
+                                 "整十",
+                                 "整百",
+                                 "整千数与一位数的乘法",
+                                 "1000以内数的比大小"
+                             ],
+        "source":  "24-25 二年级下·江西赣州·期末"
+    },
+    {
+        "id":  "179",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "读3080时，两个0都要读出来。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】一个整数，从右往左依次为个位，十位，百位，千位。读数时，从高位读起，按照数位顺序读。千位是几就读几千，百位是几就读几百。中间有一个0或两个0，只读一个零;末尾不管有几个0，都不读。\n\n【详解】由分析得:3080读作三千零八十。则读3080时，中间的0要读出来，末尾的0不读，原题说法错误。故答案为: ×",
+        "knowledge_points":  [
+                                 "万以内数的读，写法"
+                             ],
+        "source":  "24-25 二年级下·湖南张家界·期末"
+    },
+    {
+        "id":  "180",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "在算盘上表示\"506\"，需要用3颗算珠。( )",
+        "options":  [
+
+                    ],
+        "answer":  "√",
+        "solution":  "【分析】在算盘上表示数字时，上珠每颗代表5，下珠每颗代表1。需分别计算每一位数字所需的算珠数量，再求和。\n\n【详解】百位上的5：用1颗上珠(5),共1颗算珠。十位上的0：不拨动任何算珠，共0颗。个位上的6：用1颗上珠(5)和1颗下珠(1),共2颗算珠。1+2=3，因此，在算盘上表示506需要用3颗算珠。原题描述正确。故答案为:√",
+        "knowledge_points":  [
+                                 "1000以内数的组成",
+                                 "算盘的认识与使用"
+                             ],
+        "source":  "24-25 二年级下·湖北黄冈·期末"
+    },
+    {
+        "id":  "181",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "6030中的\"3\"表示3个十。( )",
+        "options":  [
+
+                    ],
+        "answer":  "√",
+        "solution":  "【分析】一个四位数，从右往左依次为个位，十位，百位，千位。千位是几表示几个千，百位是几表示几个百，十位是几表示几个十，个位是几表示几个一。\n\n【详解】6030中的\"3\"，在十位上表示3个十。原题说法正确。故答案为:√",
+        "knowledge_points":  [
+                                 "万以内数的组成"
+                             ],
+        "source":  "24-25 二年级下·云南曲靖·期末"
+    },
+    {
+        "id":  "182",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "一台电风扇原价698元，现价589元，大约便宜了100元。( )",
+        "options":  [
+
+                    ],
+        "answer":  "√",
+        "solution":  "【分析】由题意可知：找出电风扇原价和现价最接近的整百数，再把近似数相减;据此解答。\n\n【详解】由分析可得:698≈700,589≈600;700-600=100(元),一台电风扇原价698元，现价589元，大约便宜了100元。故答案为:√",
+        "knowledge_points":  [
+                                 "万以内数加减法的估算"
+                             ],
+        "source":  "24-25 二年级下·河南郑州·期末"
+    },
+    {
+        "id":  "183",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "5□34<5336,□里能填的数字有3个。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】比较数的大小，先看位数的多少，位数多的数就大;如果位数相同，从最高位开始比较，最高位上的数大则这个数就大，最高位相同，就比较下一位，以此类推。据此解答。\n\n【详解】由分析可得:5□34<5336：两个数的千位数字均为5，就比较百位数字，当百位数字分别填:3,2,1,0时，不等式都成立;□里能填的数字有4个。故答案为: ×",
+        "knowledge_points":  [
+                                 "万以内数的大小比较"
+                             ],
+        "source":  "24-25 二年级下·四川成都·期中"
+    },
+    {
+        "id":  "184",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "4449中从高位起，第二个\"4\"表示4个十。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】一个四位数，从右往左依次为个位，十位，百位，千位;千位是几表示几个千，百位是几表示几个百，十位是几表示几个十，个位是几表示几个一;从高位起，第二位是百位，百位上的4表示4个百。据此可判断。\n\n【详解】由分析可得:4449中从高位起，第二个\"4\"表示4个百。故答案为: ×",
+        "knowledge_points":  [
+                                 "万以内数的组成"
+                             ],
+        "source":  "24-25 二年级下·广东梅州·期中"
+    },
+    {
+        "id":  "185",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "2002读作二百零二。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】一个整数，从右往左依次为个位，十位，百位，千位。读法：从高位到低位，一级一级地读，几个千就读几千，有几个百就读几百。,每一级末尾的0都不读出来，其他数位连续几个0都只读一个零。\n\n【详解】2002读作\"二千零二\"，而非\"二百零二\"。原题读法错误。故答案为: ×",
+        "knowledge_points":  [
+                                 "万以内数的读，写法"
+                             ],
+        "source":  "24-25 二年级下·广东梅州·期中"
+    },
+    {
+        "id":  "186",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "6400是由64个百组成的。( )",
+        "options":  [
+
+                    ],
+        "answer":  "√",
+        "solution":  "【分析】由题意可知:1000里面有10个百,6000里面有60个百,400里面有4个百，故6400里面有64个百。\n\n【详解】由分析可得:6400是由64个百组成的。原说法正确。故答案为:√",
+        "knowledge_points":  [
+                                 "万以内数的组成"
+                             ],
+        "source":  "24-25 二年级下·广东阳江·期末"
+    },
+    {
+        "id":  "187",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "一个数的最高位是千位，这个数是四位数。( )",
+        "options":  [
+
+                    ],
+        "answer":  "√",
+        "solution":  "【分析】根据数位顺序，四位数的最高位是千位，因此最高位为千位的数必定是四位数。\n\n【详解】在整数数位顺序表中，从右往左依次是个位，十位，百位，千位，万位。四位数的最高位是千位，例如:1234的最高位是千位，它是一个四位数。因此，一个数的最高位是千位，这个数一定是四位数。题干说法正确。故答案为:√",
+        "knowledge_points":  [
+                                 "1000以内数的组成"
+                             ],
+        "source":  "23-24二年级下·云南昭通·期末"
+    },
+    {
+        "id":  "188",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "809读作八百九十。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】千以内整数的读法：百位上是几就读几百，十位上是几就读几十，个位上是几就读几。末尾的0不需要读出，中间的0只读一个零。据此判断即可。\n\n【详解】809读作八百零九，不读作八百九十。原题说法错误。故答案为：×",
+        "knowledge_points":  [
+                                 "1000以内数的读，写法"
+                             ],
+        "source":  "24-25 二年级下·湖南岳阳·期中"
+    },
+    {
+        "id":  "189",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "用0,1,4,9组成的最小四位数是4109。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】由题意可知：把0,1,4,9这四个数字按照从小到大的顺序排列，最高位上的数字不能为0，故与排第二的数字交换位置，这样组成的四位数即是最小的四位数;据此解答。\n\n【详解】0<1<4<9，用0,1,4,9组成的最小四位数是1049。原题说法错误。故答案为: ×",
+        "knowledge_points":  [
+                                 "万以内数的组成",
+                                 "万以内数的大小比较"
+                             ],
+        "source":  "24-25 二年级下·广东阳江·期末"
+    },
+    {
+        "id":  "190",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "3500里面有5个百。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】根据数的组成可知,1个百是100,2个百是200。35个百是3500，由此解答。\n\n【详解】由分析可知:3500里面有35个百，原题说法错误。故答案为: ×",
+        "knowledge_points":  [
+                                 "万以内数的组成"
+                             ],
+        "source":  "24-25 二年级下·河南郑州·期末"
+    },
+    {
+        "id":  "191",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "判断题",
+        "difficulty":  0.65,
+        "question":  "在算盘上同一个数位,1颗上珠表示的数比1颗下珠大。( )",
+        "options":  [
+
+                    ],
+        "answer":  "√",
+        "solution":  "【分析】在算盘中，每个数位的一颗上珠代表5，一颗下珠代表1。\n\n【详解】在同一个数位中,1颗上珠表示的数为5,1颗下珠表示的数为1。因为5>1，所以1颗上珠表示的数比1颗下珠大。故答案为:√",
+        "knowledge_points":  [
+                                 "算盘的认识与使用"
+                             ],
+        "source":  "24-25 二年级下·河南郑州·期末"
+    },
+    {
+        "id":  "192",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "8030,8003,8300都只读一个零。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】一个四位数，从右往左依次是个位，十位，百位，千位，读数时，从高位读起，按照数位顺序读。千位上是几就读几千，百位上是几就读几百，十位上是几就读几十，个位上是几就读几，中间有一个0或者两个0，只读一个\"零\"，末尾不管几个0都不读;由此解答。\n\n【详解】8030读作：八千零三十，只读一个0;8003读作：八千零三，只读一个0;8300读作：八千三百，一个0也不读;8030,8003,8300都只读一个零，原题说法错误。故答案为: ×",
+        "knowledge_points":  [
+                                 "万以内数的读，写法"
+                             ],
+        "source":  "24-25 二年级下·江西赣州·期末"
+    },
+    {
+        "id":  "193",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "判断题",
+        "difficulty":  0.65,
+        "question":  "用900元买一个358元的锅和一床625元的被子肯定够。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】根据题意，一个锅358元，一床被子625元，可以这样想：只看百位300+600=900，那么358+625肯定大于900，带的钱不够。据此解答即可。\n\n【详解】由分析可得:300+600=900(元),358+625>900，不够。用900元买一个358元的锅和一床625元的被子肯定够，原题说法错误。故答案为: ×",
+        "knowledge_points":  [
+                                 "万以内数加减法的估算",
+                                 "整百数",
+                                 "几百几十数的加减法口算",
+                                 "1000以内数的比大小"
+                             ],
+        "source":  "24-25 二年级下·江西赣州·期末"
+    },
+    {
+        "id":  "194",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "李师傅要烧制一批陶瓷碗，上午烧制了319个，下午烧制了403个，李师傅一天烧制了大约多少个陶瓷碗。\n答：李师傅一天烧制了大约( )个陶瓷碗。",
+        "options":  [
+
+                    ],
+        "answer":  "720个",
+        "solution":  "【分析】根据题意，将上午和下午烧制的数量看成与之接近的整百或整百整十数，相加计算出结果即可。\n\n【详解】把319看成320;把403看成400.320+400=720(个),答：李师傅一天烧制了大约720个陶瓷碗。",
+        "knowledge_points":  [
+                                 "万以内数加减法的估算"
+                             ],
+        "source":  "24-25二年级下·湖南张家界·期末"
+    },
+    {
+        "id":  "195",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "商场电视机3600一台，冰箱比电视机便宜500元，妈妈要买这两样商品，要准备多少元钱。\n答：要准备( )元。",
+        "options":  [
+
+                    ],
+        "answer":  "6700元",
+        "solution":  "【分析】根据题意，先用电视机的钱数减去冰箱比电视机便宜的钱数，计算出冰箱的钱数，再和电视机的钱数相加，就是妈妈要准备的钱数。\n\n【详解】3600-500+3600=6700(元),答：要准备6700元。",
+        "knowledge_points":  [
+                                 "整百数",
+                                 "几百几十数的加减法口算"
+                             ],
+        "source":  "24-25 二年级下·湖南张家界·期末"
+    },
+    {
+        "id":  "196",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "工人叔叔修一条路，第一天修了400米，第二天修了400米，还剩1000米没修，这条路一共长多少米。",
+        "options":  [
+
+                    ],
+        "answer":  "1800米",
+        "solution":  "【分析】根据题意可知，第一天修的长度加上第二天修的长度，再加上没修的长度，等于这条路的总长度，据此解答。\n\n【详解】根据分析可得:400+400+1000=800+1000=1800(米),答：这条路一共长1800米。",
+        "knowledge_points":  [
+                                 "整百数",
+                                 "几百几十数的加减法口算"
+                             ],
+        "source":  "24-25 二年级下·湖北黄冈·期末"
+    },
+    {
+        "id":  "197",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "(如图)狮子馆到熊猫馆相距560米，熊猫馆到孔雀馆相距多少米。\n![](images/860134180a30108976184b20e7c4a01d930c41ea1592ca28361841055f3f6d53.jpg)\n答：熊猫馆到孔雀馆相距( )米。",
+        "options":  [
+
+                    ],
+        "answer":  "410米",
+        "solution":  "【分析】根据题意，用狮子馆到熊猫馆的距离减去狮子馆到猴子馆的距离，求出猴子馆到熊猫馆的距离；再用猴子馆到孔雀馆的距离减去猴子馆到熊猫馆的距离，求出熊猫馆到孔雀馆的距离。\n\n【详解】560-350=210(米)，620-210=410(米)，答：熊猫馆到孔雀馆相距410米。",
+        "knowledge_points":  [
+                                 "整百数",
+                                 "几百几十数的加减法口算"
+                             ],
+        "source":  "24-25 二年级下·四川成都·期中"
+    },
+    {
+        "id":  "198",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "妈妈上个月网购手机支出了3200元，这个月网购空气净化器支出了2500元，这两个月妈妈网购共支出了多少元。\n答：这两个月妈妈网购共支出了( )元。",
+        "options":  [
+
+                    ],
+        "answer":  "5700元",
+        "solution":  "【分析】由题意可知：用妈妈上个月网购手机支出的钱数，加上这个月网购空气净化器支出的钱数，即是这两个月妈妈网购共支出的钱数;据此解答。\n\n【详解】由分析可得:3200+2500=5700(元),答：这两个月妈妈网购共支出了5700元。",
+        "knowledge_points":  [
+                                 "整百数",
+                                 "几百几十数的加减法口算"
+                             ],
+        "source":  "24-25 二年级下·广东潮州·期末"
+    },
+    {
+        "id":  "199",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "阳光小学有女生381人，男生279人去观看电影，准备700个座位够吗。",
+        "options":  [
+
+                    ],
+        "answer":  "够",
+        "solution":  "【分析】根据题意，将男生和女生的人数看成与之接近的整百数，再相加计算出结果，和座位数比较大小即可。\n\n【详解】381接近400;279接近300;人数都估大了。400+300=700(人),700=700，实际的人数要小于700人。答：准备700个座位够。",
+        "knowledge_points":  [
+                                 "万以内数加减法的估算"
+                             ],
+        "source":  "24-25 二年级下·浙江台州·期末"
+    },
+    {
+        "id":  "200",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "用自己喜欢的方式在下面表示出\"2053\"这个数。",
+        "options":  [
+
+                    ],
+        "answer":  "见详解",
+        "solution":  "【分析】题目要求用不同方式表示\"2053\"，需结合数的组成知识。2053是四位数，由2个千,0个百,5个十,3个一组成的，可描述数位进行表达即可解答。\n\n【详解】根据分析可得:2053是四位数，由2个千,0个百,5个十,3个一组成，如下图所示:\n\n| 千位 | 百位 | 十位 | 个位 |\n| ---- | ---- | ---- | ---- |\n| 2 | 0 | 5 | 3 |\n\n(答案不唯一)",
+        "knowledge_points":  [
+                                 "万以内数的组成"
+                             ],
+        "source":  "24-25 二年级下·河南郑州·期末"
+    },
+    {
+        "id":  "201",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "长城是人类文明史上伟大的建筑工程之一，西周时期开始修建，明长城总长度约8852千米。下面选项中能表示明长城长度的是( ).\n![](images/2dbcd70d5beeb36a22aa64059c39a484.png)",
+        "options":  [
+
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】根据题意可知，找出选项圆点的位置能准确表示8852千米,8852千米是在8850千米和8900千米之间，比8850大，比8900小，更靠近8850千米，逐项分析各个选项，找出正确答案即可解答。\n\n【详解】A。所标注的点在8800千米与8850千米之间，略靠近8800千米，比8850千米还要小，而8852千米比8850千米还要大，不符合题意。B。所标注的点在8800千米与8850千米之间，更靠近8850千米，比8850千米还要小，而8852千米比8850千米还要大，不符合题意。C。所标注的点在8850千米与8900千米之间，比8850大，比8900小，靠近8850千米，符合题意。能表示明长城长度的是8800千米 8850千米 8900千米。故答案为:C",
+        "knowledge_points":  [
+                                 "万以内数的大小比较",
+                                 "万以内数的估计"
+                             ],
+        "source":  "24-25二年级下·福建厦门·期末"
+    },
+    {
+        "id":  "202",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "在算盘上用6颗珠子表示4位数，其中最大的数是( )。",
+        "options":  [
+                        "A. 6000",
+                        "B. 9100",
+                        "C. 9500"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】一个四位数，从右往左依次为个位，十位，百位，千位;千位是几表示几个千，百位是几表示几个百，十位是几表示几个十，个位是几表示几个一;算盘上一颗上珠表示5，一颗下珠表示1，把5颗珠子都放在最高位千位上，其中1颗上珠4颗下珠，剩余的1颗珠子放到百位上，占一颗上珠，那么这个数就是最大的数;据此解答。\n\n【详解】由分析可得：千位上有1颗上珠4颗下珠，千位上是9;百位上有1颗上珠，百位上是5;在算盘上用6颗珠子表示4位数，其中最大的数是9500。故答案为:C",
+        "knowledge_points":  [
+                                 "算盘的认识与使用",
+                                 "万以内数的组成",
+                                 "万以内数的大小比较"
+                             ],
+        "source":  "24-25 二年级下·四川成都·期中"
+    },
+    {
+        "id":  "203",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "下列各数中，读作三千零二十的是( )。",
+        "options":  [
+                        "A. 3200",
+                        "B. 3002",
+                        "C. 3020"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】一个四位数，从右往左依次是个位，十位，百位，千位，读数时，从高位读起，千位上是几就读几千，百位上是几就读几百，十位上是几就读几十，个位上是几就读几，中间有一个0或者两个0，只读一个\"零\"，末尾不管有几个0都不读;由此解答。\n\n【详解】由分析可得:A。3200读作：三千二百，不符合题意;B。3002读作：三千零二，不符合题意;C。3020读作：三千零二十，符合题意。故答案为:C",
+        "knowledge_points":  [
+                                 "万以内数的读，写法"
+                             ],
+        "source":  "24-25二年级下·四川成都·期中"
+    },
+    {
+        "id":  "204",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "下面各数中，只读一个零的是( )。",
+        "options":  [
+                        "A. 550",
+                        "B. 505",
+                        "C. 555"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】根据整数的读法，从高位读起，百位上是几就读几百，十位上是几就读几十，个位上是几就读几，末尾的0都不读出来，其余数位连续几个0都只读一个零，即可读出各数。\n\n【详解】A。550读作五百五十;B。505读作五百零五;C。555读作五百五十五。只读一个零的是505。故答案为:B",
+        "knowledge_points":  [
+                                 "1000以内数的读，写法"
+                             ],
+        "source":  "24-25 二年级下·湖南岳阳·期中"
+    },
+    {
+        "id":  "205",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "小明用小圆片在数位表上摆出了数263，小红添上了两个小圆片，现在这个数不可能变成( )。\n| 百 | 十 | 个 |\n| ---- | ---- | ---- |\n| ●● | ●●●●●● | ●●● |",
+        "options":  [
+                        "A. 463",
+                        "B. 363",
+                        "C. 274"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】个位上的数表示几个一，十位上的数表示几个十，百位上的数表示几个百。小红添上了两个小圆片，表示只能在原来的263基础上再增加2个计数单位。\n\n【详解】A。463是把263的百位上添两个小圆片得到的，可能；B。363比263只多了100，相当于只添上了一个小圆片，不可能；C。274是把263十位上添一个小圆片，个位上添一个小圆片得到的，可能。故答案为：B",
+        "knowledge_points":  [
+                                 "1000以内数的读，写法",
+                                 "1000以内数的组成"
+                             ],
+        "source":  "23-24 二年级下·云南昭通·期末"
+    },
+    {
+        "id":  "206",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "在982,283,389三个数中，表示的意义相同的数字是( )。",
+        "options":  [
+                        "A. 9",
+                        "B. 2",
+                        "C. 8"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】由题意可知：同数位上的数字表示的意义相同;找出三个数中数位一致，数字相等的即是正确答案;据此可选择。\n\n【详解】由分析可得:A。9：一个在百位，一个在个位，数位不同，不符合题意;B。2：一个在百位，一个在个位，数位不同，不符合题意;C。8：都在十位上，表示的意义相同，符合题意。故答案为:C",
+        "knowledge_points":  [
+                                 "1000以内数的组成"
+                             ],
+        "source":  "24-25 二年级下·广西贵港·期中"
+    },
+    {
+        "id":  "207",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "估算341+560的结果最接近( )。",
+        "options":  [
+                        "A. 800",
+                        "B. 900",
+                        "C. 700"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】将加数看作最接近它们的整百或整十数，然后再进行相加即可。\n\n【详解】341+560看作340+560,340+560=900，所以估算341+560的结果最接近900。故答案为:B",
+        "knowledge_points":  [
+                                 "万以内数加减法的估算"
+                             ],
+        "source":  "24-25 二年级下·广东云浮·期中"
+    },
+    {
+        "id":  "208",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "把10个黑点如下图这样画在数位顺序表中，表示217。这10个黑点在这个数位顺序表中可以表示的最大三位数是( ).\n| 百位 | 十位 | 个位 |\n| ---- | ---- | ------- |\n| ●● | ● | ●●●●●●● |",
+        "options":  [
+                        "A. 109",
+                        "B. 910",
+                        "C. 999",
+                        "D. 1000"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】观察发现百位上有2个黑点，十位上有1个黑点，个位上有7个黑点，表示217;要使这10个黑点在这个数位顺序表中表示最大的三位数，那么这里最高位百位上要放9个黑点，十位上放1个黑点，个位上不放黑点即可;据此解答。\n\n【详解】根据分析如图:\n\n| 百位 | 十位 | 个位 |\n| -------------- | ---- | ---- |\n| ●●●●●●● ●● | ● | |\n\n所以这10个黑点在这个数位顺序表中可以表示的最大三位数是910。故答案为:B",
+        "knowledge_points":  [
+                                 "1000以内数的组成"
+                             ],
+        "source":  "24-25 四年级下·福建泉州·期末"
+    },
+    {
+        "id":  "209",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "用2个0,1个3,1个9组成四位数，最接近3000的是( )。",
+        "options":  [
+                        "A. 3900",
+                        "B. 9003",
+                        "C. 3009"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】由题意可知：用0,0,3,9组成的四位数中，最接近3000的数，千位上是3，其它位上的数字按照从小到大的顺序排列即可;据此解答。\n\n【详解】由分析可得：用2个0,1个3,1个9组成四位数，最接近3000的是3009。故答案为:C",
+        "knowledge_points":  [
+                                 "万以内数的组成",
+                                 "万以内数的大小比较"
+                             ],
+        "source":  "24-25 二年级下·重庆沙坪坝·期末"
+    },
+    {
+        "id":  "210",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "与3999相邻的数是( )。",
+        "options":  [
+                        "A. 3998,4001",
+                        "B. 4000,3998",
+                        "C. 3997,3998"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】根据题意，与3999相邻的两个数是3999-1和3999+1，据此解答。\n\n【详解】3999-1=3998,3999+1=4000，故答案为:B",
+        "knowledge_points":  [
+                                 "数万以内的数"
+                             ],
+        "source":  "24-25 二年级下·湖北黄冈·期末"
+    },
+    {
+        "id":  "211",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "下面各数中，只读一个零的是( )。",
+        "options":  [
+                        "A. 4500",
+                        "B. 4050",
+                        "C. 4560"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】读一个四位数，从高位往低位读，千位上的数读作几千，百位上的数读作几百，十位上的数读作几十，个位上的数读作几，中间的一个0或连续两个0，都只读一个\"零\"，末尾的0不用读。先读出每一个数，然后找出符合要求的即可。\n\n【详解】A。4500读作：四千五百，一个零也不读;B。4050读作：四千零五十，只读一个零;C。4560读作：四千五百六十，一个零也不读;故答案为:B",
+        "knowledge_points":  [
+                                 "万以内数的读，写法"
+                             ],
+        "source":  "24-25二年级下·黑龙江佳木斯·期末"
+    },
+    {
+        "id":  "212",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "对下列名山高度的比较说法正确的是( ).\n| 喜马拉雅山 | 华山 | 恒山 | 龙虎山 |\n| ---------- | ------ | ------ | ------ |\n| 8844米 | 2691米 | 2016米 | 247米 |",
+        "options":  [
+                        "A. 恒山比华山高一些",
+                        "B. 喜马拉雅山比龙虎山高得多",
+                        "C. 龙虎山比华山矮一些"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】比较两个数的多少时，如果两个数的大小比较接近，就说大数比小数多一些，或小数比大数少一些;如果两个数的大小相差很多，就说大数比小数多得多，或小数比大数少得多;据此选答案。\n\n【详解】由分析可得:A。恒山2016米，华山2691米,2016米比2691米矮一些，所以恒山比华山高一些说法错误;B。喜马拉雅山8844米，龙虎山247米,8844米比247米高得多，所以喜马拉雅山比龙虎山高得多，说法正确;C。龙虎山247米，华山2691米,247米比2691米矮得多，所以龙虎山比华山矮一些说法错误;故答案为:B",
+        "knowledge_points":  [
+                                 "数的相对大小关系",
+                                 "万以内数的大小比较"
+                             ],
+        "source":  "24-25二年级下·湖北随州·期末"
+    },
+    {
+        "id":  "213",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "爸爸要购买三件商品，第一件商品300多元，第二件商品200多元，第三件商品的价格看不清楚，只知道最高位百位上的数是4，爸爸带900元够吗。( )",
+        "options":  [
+                        "A. 够",
+                        "B. 不够",
+                        "C. 不能确定"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】根据题意，把三件商品的价格看成与之接近的整百或整百整十数，相加计算出结果后与900元比较大小即可。\n\n【详解】把第一件商品看成300元，第二件商品看成200元，第三件商品百位上的数是4，可以看成400元，三个价格都估小了。300+200+400=900(元),则实际三件商品的价格要大于900元，所以爸爸带900元不够。故答案为:B",
+        "knowledge_points":  [
+                                 "万以内数加减法的估算"
+                             ],
+        "source":  "24-25 二年级下·广东潮州·期末"
+    },
+    {
+        "id":  "214",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "在5960这个数中，\"6\"表示( )。",
+        "options":  [
+                        "A. 6个千",
+                        "B. 6个百",
+                        "C. 6个十"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】一个四位数，从右往左依次为个位，十位，百位，千位。千位是几表示几个千，百位是几表示几个百，十位是几表示几个十，个位是几表示几个一，由此解答。\n\n【详解】在5960这个数中，\"6\"在十位上，表示6个十。故答案为:C",
+        "knowledge_points":  [
+                                 "万以内数的组成"
+                             ],
+        "source":  "24-25 二年级下·山东济南·期末"
+    },
+    {
+        "id":  "215",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "1000里面有( )个100。",
+        "options":  [
+                        "A. 10",
+                        "B. 100",
+                        "C. 1000"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】根据万以内数的认识即可解答。一个百一个百数:100,200,300,400,500,600,700,800,900,1000。然后数一数数了几次即有几个一百。\n\n【详解】由分析可得:1000里面有(10)个100。故答案为:A",
+        "knowledge_points":  [
+                                 "万以内数的组成"
+                             ],
+        "source":  "24-25 二年级下·黑龙江佳木斯·期末"
+    },
+    {
+        "id":  "216",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "下面各数中，中间只有一个\"0\"的是( )。",
+        "options":  [
+                        "A. 三千零八",
+                        "B. 三千零八十八",
+                        "C. 三千八百"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】一个四位数，从右往左依次是个位，十位，百位，千位，写数时，从高位写起，有几个千就在千位写几，有几个百就在百位写几，有几个十就在十位写几，有几个一就在个位写几，哪一位上一个单位也没有，就在那一位上写0;由此选答案。\n\n【详解】A。三千零八写作:3008，中间有两个\"0\"，不符合题意;B。三千零八十八写作:3088，中间只有一个\"0\"，符合题意;C。三千八百写作:3800，末尾有两个\"0\"，不符合题意;故答案为:B",
+        "knowledge_points":  [
+                                 "万以内数的读，写法"
+                             ],
+        "source":  "24-25 二年级下·山东济宁·期末"
+    },
+    {
+        "id":  "217",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "要使6□72<6563,□里有( )种填法。",
+        "options":  [
+                        "A. 4",
+                        "B. 5",
+                        "C. 6"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】万以内数比较大小的方法：比较数的大小，先看位数的多少，位数多的数就大;如果位数相同，从最高位开始比较，最高位上的数大则这个数大，最高位上的数相同，就比较下一位，依次类推。\n\n【详解】6□72和6563位数相同，千位上也相同，十位上7>6，所以6□72要小于6563，一定要百位上的数小于5，则方框可以填:4,3,2,1,0。即□内有5种填法。故答案为:B",
+        "knowledge_points":  [
+                                 "万以内数的大小比较"
+                             ],
+        "source":  "24-25 二年级下·山东济宁·期末"
+    },
+    {
+        "id":  "218",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "小猴摘的葡萄比小狐狸少得多，小狐狸摘的葡萄比小熊多一些，小熊摘了( )。",
+        "options":  [
+                        "A. 209",
+                        "B. 197",
+                        "C. 98"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】根据题意可知：小猴摘的葡萄比小狐狸少得多，小狐狸摘的葡萄比小熊多一些，则小狐狸摘的最多，小熊比小狐狸摘的少一些，小猴摘的最少，则把选项中的数进行比较，选择较小的即可。\n\n【详解】由分析可得:209>197>98，则小熊摘了197。故答案为:B",
+        "knowledge_points":  [
+                                 "数的相对大小关系",
+                                 "1000以内数的比大小"
+                             ],
+        "source":  "24-25 二年级下·甘肃天水·期末"
+    },
+    {
+        "id":  "219",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "花园小学开展读书活动。一年级有258名学生，二年级有327名学生，如果两个年级每人发一本书，估一估，学校准备( )本最合适。",
+        "options":  [
+                        "A. 500",
+                        "B. 550",
+                        "C. 600"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】由题意可知：分别把一年级和二年级人数最接近的整百数找出来，再相加，即可找出最适合的本数;据此可解。\n\n【详解】由分析可得:258≈300,327≈300;300+300=600(本),学校准备600本最合适。故答案为:C",
+        "knowledge_points":  [
+                                 "万以内数的估计",
+                                 "整百数",
+                                 "几百几十数的加减法口算",
+                                 "万以内数加减法的估算"
+                             ],
+        "source":  "24-25二年级下·福建福州·期末"
+    },
+    {
+        "id":  "220",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "下面三个数中，只读一个零的是( )。",
+        "options":  [
+                        "A. 5500",
+                        "B. 4002",
+                        "C. 990"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】读数时，千位上是几就读几千，百位上是几就读几百，十位上是几就读几十，个位上是几就读几，中间有一个0或两个0，只读一个0，末尾的0不读。分析各项，找出只读一个零的数;据此可解。\n\n【详解】由分析可得:A。5500读作：五千五百，不符合题意;B。4002读作：四千零二，符合题意;C。990读作：九百九十，不符合题意。上面三个数中，只读一个零的是4002。故答案为:B",
+        "knowledge_points":  [
+                                 "万以内数的读，写法"
+                             ],
+        "source":  "24-25 二年级下·福建福州·期末"
+    },
+    {
+        "id":  "221",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "只读一个\"零\"的数是( )。",
+        "options":  [
+                        "A. 6500",
+                        "B. 5006",
+                        "C. 5600"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】读一个四位数，从高位往低位读，千位上的数读作几千，百位上的数读作几百，十位上的数读作几十，个位上的数读作几，中间的一个0或连续两个0，都只读一个\"零\"，末尾的0不用读。先读出每一个数，然后找出符合题意的即可。\n\n【详解】A。6500读作：六千五百，一个\"零\"也不读;B。5006读作：五千零六，只读一个\"零\";C。5600读作：五千六百，一个\"零\"也不读;即，只读一个\"零\"的数是(5006)。故答案为:B",
+        "knowledge_points":  [
+                                 "万以内数的读，写法"
+                             ],
+        "source":  "24-25 二年级下·黑龙江佳木斯·期末"
+    },
+    {
+        "id":  "222",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "5505中千位上的5比百位上的5多( )。",
+        "options":  [
+                        "A. 4500",
+                        "B. 500",
+                        "C. 4995"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】一个四位数，从右往左数，第一位是个位，个位上的数表示几个一;第二位是十位，十位上的数表示几个十;第三位是百位，百位上的数表示几个百;第四位是千位，千位上的数表示几个千。则，千位上的5表示5个千，即5000;百位上的5表示5个百，即500，然后作差，即可解决。\n\n【详解】由分析可知:5000-500=4500,5505中所以千位上的5比百位上的5多4500。故答案为:A",
+        "knowledge_points":  [
+                                 "万以内数的组成",
+                                 "整百数",
+                                 "几百几十数的加减法口算"
+                             ],
+        "source":  "24-25 二年级下·黑龙江佳木斯·期末"
+    },
+    {
+        "id":  "223",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "用4,0,0,6组成的四位数中，一个零都不读的是( )。",
+        "options":  [
+                        "A. 4006",
+                        "B. 4600",
+                        "C. 4060"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】一个整数，从右往左依次为个位，十位，百位，千位。读数时，从高位读起，千位上是几就读几千，百位上是几就读几百。中间有0的，只读一个\"零\"，末尾不管有几个0都不读;由此解答。\n\n【详解】A。4006读作：四千零六，读了一个零，不符合题意;B。4600读作：四千六百，一个零都不读，符合题意;C。4060读作：四千零六十，读了一个零，不符合题意;用4,0,0,6组成的四位数中，一个零都不读的是4600。故答案为:B",
+        "knowledge_points":  [
+                                 "万以内数的读，写法"
+                             ],
+        "source":  "24-25 二年级下·广东揭阳·期末"
+    },
+    {
+        "id":  "224",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "小明想用算珠拨出数字6，他应该拨( )。",
+        "options":  [
+                        "A. 上珠2颗，下珠4颗",
+                        "B. 上珠1颗，下珠5颗",
+                        "C. 上珠1颗，下珠1颗"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】算盘上1颗上珠表示5,1颗下珠表示1;用算珠拨出数字6，应该拨1颗表示5的上珠，和1颗表示1的下珠即可;据此可解。\n\n【详解】由分析可得：小明想用算珠拨出数字6，他应该拨上珠1颗，下珠1颗。故答案为:C",
+        "knowledge_points":  [
+                                 "算盘的认识与使用"
+                             ],
+        "source":  "24-25二年级下·甘肃天水·期末"
+    },
+    {
+        "id":  "225",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "6083中的\"6\"表示的是( )。",
+        "options":  [
+                        "A. 6个百",
+                        "B. 6个千",
+                        "C. 6个十"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】一个四位数，从右往左依次为个位，十位，百位，千位;千位是几表示几个千，百位是几表示几个百，十位是几表示几个十，个位是几表示几个一;6083中的\"6\"在千位上;据此可解。\n\n【详解】由分析可得:6083中的\"6\"表示的是6个千。故答案为:B",
+        "knowledge_points":  [
+                                 "万以内数的组成"
+                             ],
+        "source":  "24-25 二年级下·吉林四平·期末"
+    },
+    {
+        "id":  "226",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "下面的数中，一个零也不读的是( )。",
+        "options":  [
+                        "A. 4900",
+                        "B. 4009",
+                        "C. 4090"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】万以内整数的读法：从高位起，按照数位顺序读。千位上是几就读几千，百位上是几就读几百。十位上是几就读几十，个位上是几就读几。末尾的0不需要读出，中间的0只读一个零。据此解答即可。\n\n【详解】A。4900读作：四千九百，一个零也不读;B。4009读作：四千零九，只读一个零;C。4090读作：四千零九十，只读一个零。故答案为:A",
+        "knowledge_points":  [
+                                 "万以内数的读，写法"
+                             ],
+        "source":  "24-25 二年级下·云南红河·期末"
+    },
+    {
+        "id":  "227",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "下面的数中,( )中的\"8\"表示8个十。",
+        "options":  [
+                        "A. 2008",
+                        "B. 3080",
+                        "C. 5801"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】一个四位数，从右往左数，第一位是个位，表示几个一;第二位是十位，表示几个十;第三位是百位，表示几个百;第四位是千位，表示几个千。要确定数字中的\"8\"表示8个十，需分析每个选项中\"8\"所在的数位。\n\n【详解】A。2008中的\"8\"在个位上，表示8个一;B。3080中的\"8\"在十位上，表示8个十;C。5801中的\"8\"在百位上，表示8个百。故答案为:B",
+        "knowledge_points":  [
+                                 "万以内数的组成"
+                             ],
+        "source":  "24-25 二年级下·广东揭阳·期末"
+    },
+    {
+        "id":  "228",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "下面的三个数中，一个零都不读的是( )。",
+        "options":  [
+                        "A. 1020",
+                        "B. 1002",
+                        "C. 1200"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】读数时，从高位读起，千位是几就读几千，百位是几就读几百，十位是几就读几十，个位是几就读几，中间有一个0或两个0，只读一个\"零\"，末尾不管有几个0，都不读。\n\n【详解】A。1020读作：一千零二十，读了一个零;B。1002读作：一千零二，读了一个零;C。1200读作：一千二百，一个零都没读。一个零都不读的是1200。故答案为:C",
+        "knowledge_points":  [
+                                 "万以内数的读，写法"
+                             ],
+        "source":  "24-25 二年级下·辽宁鞍山·期末"
+    },
+    {
+        "id":  "229",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "用3、8、0、6组成最大的四位数是( )，读作( )；组成最小的四位数是( )，读作( )。",
+        "options":  [
+
+                    ],
+        "answer":  "8630;八千六百三十;3068;三千零六十八",
+        "solution":  "【分析】要想组成的数最大，要把数按照从大到小的顺序从高位到低位排下来；要想组成的数最小，要把数按照从小到大的顺序从高位到低位排下来，但是最高位不能是零。再根据万以内整数的读法读出各数即可。\n\n【详解】由分析可知，用3、8、0、6组成最大的四位数是8630，读作八千六百三十；组成最小的四位数是3068，读作三千零六十八。",
+        "knowledge_points":  [
+                                 "万以内数的读，写法",
+                                 "万以内数的组成"
+                             ],
+        "source":  "24-25 二年级下·甘肃兰州·期末"
+    },
+    {
+        "id":  "230",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "一台电脑4978元，一台打印机982元，买这两件物品一共大约需要( )元。",
+        "options":  [
+
+                    ],
+        "answer":  "6000",
+        "solution":  "【分析】先将这两件商品的价钱估成整百，整千数，然后相加，即可求出买这两件物品一共大约需要多少元。\n\n【详解】4978≈5000,982≈1000,5000+1000=6000(元),买这两件物品一共大约需要(6000)元。",
+        "knowledge_points":  [
+                                 "万以内数加减法的估算"
+                             ],
+        "source":  "24-25 二年级下·甘肃兰州·期末"
+    },
+    {
+        "id":  "231",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "6238的最高位是( )位，百位上是( )，表示( )个( )；千位上是5，百位上是9，其余数位上的数是0，这个数是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "千;2;2;百;5900",
+        "solution":  "【分析】一个四位数，从右往左依次是个位、十位、百位、千位，千位上是几就表示几个千，百位上是几就表示几个百，十位上是几就表示几个十，个位上是几就表示几个一；写数时，从高位起按照数位顺序写，有几个千就在千位上写几，有几个百就在百位上写几，有几个十就在十位上写几，有几个一就在个位上写几，中间或末尾哪一位上一个也没有，就在哪一位上写0占位。\n\n【详解】由分析可知：6238的最高位是千位，百位上是2，表示2个百；千位上是5，百位上是9，其余数位上的数是0，这个数是5900。",
+        "knowledge_points":  [
+                                 "万以内数的读，写法",
+                                 "万以内数的组成"
+                             ],
+        "source":  "24-25 二年级下·甘肃兰州·期末"
+    },
+    {
+        "id":  "232",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "4599后面的第3个数是( ),4003前面的第4个数是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "4602;3999",
+        "solution":  "【分析】由题意可知:4599向后数三个数：第1个数是4600，第2个数是4601，第3个数是4602;4003向前数四个数：第1个数是:4002，第2个数4001，第3个数4000，第4个数3999;据此可解。\n\n【详解】由分析可得:4599后面的第3个数是4602,4003前面的第4个数是3999。",
+        "knowledge_points":  [
+                                 "数万以内的数"
+                             ],
+        "source":  "24-25 二年级下·山东济南·期中"
+    },
+    {
+        "id":  "233",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "46个百是( );6000里面有( )个千，再添上( )个千就是10000。",
+        "options":  [
+
+                    ],
+        "answer":  "4600;6;4",
+        "solution":  "【分析】1个百是100,2个百是200。46个百是4600;1个千是1000,2个千是2000。6个千是6000,6个千再添上4个千是10个千,10个千是10000，据此解答。\n\n【详解】46个百是4600;6000里面有6个千，再添上4个千就是10000。",
+        "knowledge_points":  [
+                                 "万以内数的读，写法",
+                                 "万以内数的组成"
+                             ],
+        "source":  "24-25 二年级下·山东济南·期中"
+    },
+    {
+        "id":  "234",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "一个四位数，从右边数第一位和第三位都是8，最高位是6，还有一位是0，这个数是( ),与它相邻的两个数是( )和( )。",
+        "options":  [
+
+                    ],
+        "answer":  "6808;6807;6809",
+        "solution":  "【分析】一个四位数，从右往左依次为个位，十位，百位，千位，千位是几表示几个千，百位是几表示几个百，十位是几表示几个十，个位是几表示几个一，与它相邻的两个数分别比它少1和多1，据此解答。\n\n【详解】由分析可得：一个四位数，从右边数第一位和第三位都是8，即个位和百位是8，最高位是6，即千位是6，还有一位是0，即十位是0，这个数是6808，数一数可知，与它相邻的两个数是6807和6809。",
+        "knowledge_points":  [
+                                 "数万以内的数",
+                                 "万以内数的组成"
+                             ],
+        "source":  "24-25 二年级下·山东济南·期中"
+    },
+    {
+        "id":  "235",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "用数字0,1,4,8组成的四位数中，最小的数是( ),最接近4000的数是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "1048;4018",
+        "solution":  "【分析】组成最小的四位数需将最小的非零数字放在千位，其余数字按从小到大排列;最接近4000的数需千位为4，剩余数字按从小到大排列;据此解决。\n\n【详解】由题意分析得：用数字0,1,4,8组成的四位数中，最小的数是1048，最接近4000的数是4018。",
+        "knowledge_points":  [
+                                 "万以内数的组成",
+                                 "万以内数的大小比较"
+                             ],
+        "source":  "24-25 二年级下·四川成都·期中"
+    },
+    {
+        "id":  "236",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "一个数由5个千和9个十组成，这个数是( ),与它相邻的两个数是( )和( )。",
+        "options":  [
+
+                    ],
+        "answer":  "5090;5089;5091",
+        "solution":  "【分析】一个四位数，从右往左依次为个位，十位，百位，千位;千位是几表示几个千，百位是几表示几个百，十位是几表示几个十，个位是几表示几个一;这个数千位是5，十位是9;和它相邻的数是它前面的一个数和它后面的一个数;据此解答。\n\n【详解】由分析可得：一个数由5个千和9个十组成，这个数是5090，与它相邻的两个数是5089和5091。",
+        "knowledge_points":  [
+                                 "数万以内的数",
+                                 "万以内数的组成",
+                                 "相邻的数"
+                             ],
+        "source":  "24-25 二年级下·四川成都·期中"
+    },
+    {
+        "id":  "237",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "按规律填一填。\n(1)1700，1800，1900，( )，( )。\n(2)850，800，( )，( )，650。",
+        "options":  [
+
+                    ],
+        "answer":  "2000;2100;750;700",
+        "solution":  "【分析】(1)1700和1800相差100，1800和1900相差100，所以这列数字从左往右依次增加100；(2)850和800相差50，所以这列数字从左往右依次减少50。\n\n【详解】(1)1900+100=2000，2000+100=2100，所以这列数字是1700，1800，1900，2000，2100。(2)800-50=750，750-50=700，所以这列数字是850，800，750，700，650。",
+        "knowledge_points":  [
+                                 "数万以内的数",
+                                 "整百数",
+                                 "几百几十数的加减法口算",
+                                 "整数排列的规律"
+                             ],
+        "source":  "24-25 二年级下·新疆阿克苏·期末"
+    },
+    {
+        "id":  "238",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "五千零二十写作( ),这个数是一个( )位数，它的最高位是( )位，它是由( )个千和2个( )组成的。",
+        "options":  [
+
+                    ],
+        "answer":  "5020;四;千;5;十",
+        "solution":  "【分析】一个整数，从右往左依次为个位，十位，百位，千位。写数时，从高位写起，按照数位顺序写;几千就在千位写几，几百就在百位写几。中间或末尾哪一位上一个也没有，就在那一位上写0。这个数中有几个数字就是几位数，最左边的数位是最高位。千位是几表示几个千(几个千就是几千),百位是几表示几个百(几个百就是几百),十位是几表示几个十(几个十就是几十),个位是几表示几个一(几个一就是几)。\n\n【详解】五千零二十写作5020，这个数是一个四位数，它的最高位是千位，它是由5个千和2个十组成的。",
+        "knowledge_points":  [
+                                 "万以内数的读，写法",
+                                 "万以内数的组成"
+                             ],
+        "source":  "24-25二年级下·新疆阿克苏·期末"
+    },
+    {
+        "id":  "239",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "按规律填数。\n(1)150，200，250，( )，( )。\n(2)999，899，799，( )，( )。",
+        "options":  [
+
+                    ],
+        "answer":  "300;350;699;599",
+        "solution":  "【分析】(1)这组数字依次变大，每后一个数比前一个数大50，也就是从150开始，五十五十地正着数到350；(2)这组数字依次变小，每后一个数比前一个数小100，也就是从999开始，一百一百地倒着数到599。\n\n【详解】(1)150，200，250，300，350。(2)999，899，799，699，599。",
+        "knowledge_points":  [
+                                 "数1000以内的数",
+                                 "整数排列的规律"
+                             ],
+        "source":  "24-25 二年级下·湖南岳阳·期中"
+    },
+    {
+        "id":  "240",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "由5个百和8个一组成的数是( ),比它小10的数是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "508;498",
+        "solution":  "【分析】一个整数，从右往左依次为个位，十位，百位。百位是几就有几个百(几个百就是几百),十位是几就有几个十(几个十就是几十),个位是几就有几个一(几个一就是几)。比它小10的数，是数数时它前边的第10个数，根据1,2,3。495,496,497,498,499,500,501,502,503,504,505,506,507,508，找到对应的数即可。\n\n【详解】5个百是500,8个一是8，则由5个百和8个一组成的数是508，比它小10的数是498。",
+        "knowledge_points":  [
+                                 "数1000以内的数",
+                                 "1000以内数的组成"
+                             ],
+        "source":  "24-25二年级下·湖南岳阳·期中"
+    },
+    {
+        "id":  "241",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.94,
+        "question":  "318是( )位数，最高位是( )位。",
+        "options":  [
+
+                    ],
+        "answer":  "三;百",
+        "solution":  "【分析】要确定一个数是几位数，需从左到右数其数字的个数，且最高位是指该数最左边的数位。318由三个数字组成，因此它是三位数，一个三位数，从右往左依次是个位，十位，百位，因此最高位是百位。\n\n【详解】由分析可知:318是(三)位数，最高位是(百)位。",
+        "knowledge_points":  [
+                                 "1000以内数的组成"
+                             ],
+        "source":  "24-25 二年级下·广西玉林·期中"
+    },
+    {
+        "id":  "242",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "按规律填数.\n165,170,175,( ),( )。",
+        "options":  [
+
+                    ],
+        "answer":  "180;185",
+        "solution":  "【分析】从题干可知:165和170相差5,170和175相差5，所以这列数字从左往右依次增加5。\n\n【详解】这组数据从左到右依次增加5，所以这列数字是165,170,175,180,185。",
+        "knowledge_points":  [
+                                 "数1000以内的数",
+                                 "整数排列的规律"
+                             ],
+        "source":  "24-25 二年级下·广西玉林·期中"
+    },
+    {
+        "id":  "243",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "4个百和9个一组成( ),读作( )。",
+        "options":  [
+
+                    ],
+        "answer":  "409;四百零九",
+        "solution":  "【分析】一个三位数，从右往左依次是个位，十位，百位，百位上是几就表示几个百，十位上是几就表示几个十，个位上是几就表示几个一;读数时，从高位读起，百位是几就读几百，十位是几就读几十，个位是几就读几，中间的0要读出来，末尾的0不读。\n\n【详解】由分析得:4个百和9个一组成(409),读作(四百零九)。",
+        "knowledge_points":  [
+                                 "1000以内数的读，写法",
+                                 "1000以内数的组成"
+                             ],
+        "source":  "24-25 二年级下·广西玉林·期中"
+    },
+    {
+        "id":  "244",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "625是由( )个百,( )个十和( )个一组成。",
+        "options":  [
+
+                    ],
+        "answer":  "6;2;5",
+        "solution":  "【分析】一个三位数，从右往左依次是个位，十位，百位，百位上是几就表示几个百，十位上是几就表示几个十，个位上是几就表示几个一。\n\n【详解】由分析得:625是由(6)个百,(2)个十和(5)个一组成的。",
+        "knowledge_points":  [
+                                 "1000以内数的组成"
+                             ],
+        "source":  "24-25 二年级下·广西玉林·期中"
+    },
+    {
+        "id":  "245",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "由4个千,7个百和9个一组成的数是( ),读作( )。",
+        "options":  [
+
+                    ],
+        "answer":  "4709;四千七百零九",
+        "solution":  "【分析】一个四位数，从右往左依次为个位，十位，百位，千位;千位是几表示几个千，百位是几表示几个百，十位是几表示几个十，个位是几表示几个一;读数时，从高位读起，按照数位顺序读。千位是几就读几千，百位是几就读几百，十位上是几就读几十，个位上是几就读几，中间有一个0或两个0，只读一个零;末尾不管有几个0，都不读。这个数千位是4，百位是7，个位是9;据此可解。\n\n【详解】由分析可得：由4个千,7个百和9个一组成的数是4709，读作四千七百零九。",
+        "knowledge_points":  [
+                                 "万以内数的读，写法",
+                                 "万以内数的组成"
+                             ],
+        "source":  "24-25 二年级下·广东梅州·期中"
+    },
+    {
+        "id":  "246",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "80里面有( )个十,400里面有( )个百。46里面有( )个十和( )个一。",
+        "options":  [
+
+                    ],
+        "answer":  "8;4;4;6",
+        "solution":  "【分析】根据题意，数位顺序表从右往左依次是个位，十位，百位，千位，万位。,对应的计数单位依次是个(一),十，百，千，万。这个数位上是几，就表示有几个这样的计数单位，据此解答。\n\n【详解】根据分析,80的十位上是8,400的百位上是4,46的十位上是4，个位上是6。所以80里面有8个十,400里面有4个百。46里面有4个十和6个一。",
+        "knowledge_points":  [
+                                 "1000以内数的组成"
+                             ],
+        "source":  "24-25 三年级下·陕西宝鸡·期末"
+    },
+    {
+        "id":  "247",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "865是( )位数，读作( )。这个数是由( )个百,( )个十和( )个一组成的。",
+        "options":  [
+
+                    ],
+        "answer":  "三;八百六十五;8;6;5",
+        "solution":  "【分析】一个数有几个数字就是几位数,865有8,6,5三个数字，所以是三位数;读数时，从高位读起，百位是几就读几百，十位上是几就读几十，个位上是几就读几，中间的0读作零，末尾不管有几个0，都不读。一个三位数，从右往左依次为个位，十位，百位。百位是几表示几个百，十位是几表示几个十，个位是几表示几个一，据此解答。\n\n【详解】865是三位数，读作八百六十五。这个数是由8个百,6个十和5个一组成的。",
+        "knowledge_points":  [
+                                 "1000以内数的读，写法",
+                                 "1000以内数的组成"
+                             ],
+        "source":  "24-25 二年级下·广西贵港·期中"
+    },
+    {
+        "id":  "248",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "按规律填一填.\n2020,2031,2042,( ),( )。",
+        "options":  [
+
+                    ],
+        "answer":  "2053;2064",
+        "solution":  "【分析】观察前三个数发现相邻两个数的差是11，用前一个数加11等于后一个数，根据此规律依次计算后续的数。\n\n【详解】2042+11=2053;2053+11=2064;所以,2020,2031,2042,2053,2064。",
+        "knowledge_points":  [
+                                 "万以内数的组成",
+                                 "整数排列的规律"
+                             ],
+        "source":  "24-25 二年级下·广东云浮·期中"
+    },
+    {
+        "id":  "249",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "用3,0,9,5四个数字组成不同的四位数，其中最大的数是( ),最小的数是( ),最接近5000的数是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "9530;3059;5039",
+        "solution":  "【分析】一个四位数，从右往左依次为个位，十位，百位，千位。要组成最大的四位数，则将数字从大到小按数位从高位到低位排列;要组成最小的四位数，最高位不能为0，则把0以外最小的数字写在千位，剩余的数字从小到大依次写在百位，十位和个位。最接近5000的数，千位应为5，剩余的数字从小到大依次写在百位，十位和个位。\n\n【详解】0<3<5<9，用3,0,9,5四个数字组成不同的四位数，其中最大的数是9530，最小的数是3059，最接近5000的数是5039。",
+        "knowledge_points":  [
+                                 "万以内数的组成",
+                                 "万以内数的大小比较"
+                             ],
+        "source":  "24-25 二年级下·广东云浮·期中"
+    },
+    {
+        "id":  "250",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在括号里填“>”“<”或“=”。\n347( )374  1020( )999  2605( )2650",
+        "options":  [
+
+                    ],
+        "answer":  "<;>;<",
+        "solution":  "【分析】整数的大小比较：比较数的大小，先看位数的多少，位数多的数就大；位数相同，从高位开始比较，高位上的数大则这个数大，高位上的数相同，就比较下一位，直到分出大小。\n\n【详解】347和374比较：百位相同，十位4<7，因此347<374；1020和999比较：1020是四位数，999是三位数，位数多的数更大，因此1020>999；2605和2650比较：千位相同，百位相同，十位0<5，因此2605<2650。",
+        "knowledge_points":  [
+                                 "1000以内数的比大小",
+                                 "万以内数的大小比较"
+                             ],
+        "source":  "24-25 二年级下·广东云浮·期中"
+    },
+    {
+        "id":  "251",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "一个数从右边起，第五位是( )位，和百位相邻的是( )位和( )位。",
+        "options":  [
+
+                    ],
+        "answer":  "万;十;千",
+        "solution":  "【分析】一个整数，从右往左数，第一位是个位，第二位是十位，第三位是百位，第四位是千位，第五位是万位，和百位相邻的数位是第二位(十位)和第四位(千位),由此解答。\n\n【详解】由分析得：一个数从右边起，第五位是万位，和百位相邻的是十位和千位。",
+        "knowledge_points":  [
+                                 "万以内数的组成",
+                                 "整数的数级",
+                                 "数位和计数单位的认识"
+                             ],
+        "source":  "24-25 二年级下·广东云浮·期中"
+    },
+    {
+        "id":  "252",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "用4,0,8可以组成( )个不同的三位数。",
+        "options":  [
+
+                    ],
+        "answer":  "4",
+        "solution":  "【分析】要确定用4,0,8能组成多少个不同的三位数，需注意三位数的首位(百位)不能为0，否则就不是三位数了。分别确定百位，十位和个位上的数，就可以举出所有可能的组合。\n\n【详解】确定百位上的数字，百位上只能选择4或8(因为0不能在首位):百位是4时：十位和个位可以从剩下的0和8中选择，组成的数为:408,480。百位是8时：十位和个位可以从剩下的0和4中选择，组成的数为:804,840。所以符合条件的三位数有408,480,804,840，共4个。用4,0,8可以组成4个不同的三位数。",
+        "knowledge_points":  [
+                                 "数字中的排列问题"
+                             ],
+        "source":  "24-25 四年级下·山东济宁·期末"
+    },
+    {
+        "id":  "253",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "小玲在算盘上用3颗算珠表示了一个四位数，这个四位数最小是( ),最大是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "1002;7000",
+        "solution":  "【分析】由题意可知：算盘上，一颗上珠表示5,1颗下珠表示1;在千位上拨1颗下珠，在个位上拨2颗下珠，即可组成最小四位数;在千位上拨1颗上珠,2颗下珠，即可组成最大四位数;据此解答。\n\n【详解】由分析可得：小玲在算盘上用3颗算珠表示了一个四位数，这个四位数最小是1002，最大是7000。",
+        "knowledge_points":  [
+                                 "算盘的认识与使用",
+                                 "万以内数的组成",
+                                 "万以内数的大小比较"
+                             ],
+        "source":  "24-25二年级下·重庆沙坪坝·期末"
+    },
+    {
+        "id":  "254",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "900-400，想9个( )减4个( )得( )个( ),也就是( )。560+70，想56个( )加7个( )得( )个( ),也就是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "百;百;5;百;500;十;十;63;十;630",
+        "solution":  "【分析】根据1个百是100,1个十是10，即可完成解答。对于题目\"900-400\":900可以看作9个百,400可以看作4个百。相减时,9个百减4个百得到5个百，即500。对于题目\"560+70\":560可以看作56个十,70可以看作7个十。相加时,56个十加7个十得到63个十，即630。\n\n【详解】900-400，想9个(百)减4个(百)得(5)个(百),也就是(500)。560+70，想56个(十)加7个(十)得(63)个(十),也就是(630)。",
+        "knowledge_points":  [
+                                 "整百数",
+                                 "几百几十数的加减法口算"
+                             ],
+        "source":  "24-25 二年级下·重庆沙坪坝·期末"
+    },
+    {
+        "id":  "255",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "用7,0,0,8组成四位数，最大的数是( ),最小的数是( ),一个零也不读的数是( )和( )。",
+        "options":  [
+
+                    ],
+        "answer":  "8700;7008;8700;7800",
+        "solution":  "【分析】要想组成的数最大：要把数字按照从大到小的顺序从高位到低位排下来。要想组成的数最小：要把数字按照从小到大的顺序从高位到低位排下来(数字首位不能是0)。万以内整数的读法：千位上是几就读几千，百位上是几就读几百，十位上是几就读几十，个位上是几就读几，末尾的0都不读出来，其余数位连续几个0都只读一个零，即读出此数。\n\n【详解】8>7>0，则用7,0,0,8组成四位数，最大的数是(8700),最小的数是(7008),一个零也不读的数是(8700)和(7800)。",
+        "knowledge_points":  [
+                                 "万以内数的读，写法",
+                                 "万以内数的组成",
+                                 "万以内数的大小比较"
+                             ],
+        "source":  "24-25 二年级下·湖北黄冈·期末"
+    },
+    {
+        "id":  "256",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "10个十是( ),( )个一百是10000;290里有( )个十,46个百是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "100;100;29;4600",
+        "solution":  "【分析】根据数的组成，通过计数单位间的进率进行计算即可。10个十需要向前一位进一，即为1个百。10000的万位上是1，其余位数上是0,1个万代表10个千，也表示100个百。290的百位上是2，代表有2个百，十位上9代表有9个十,1个百代表10个十，则290一共有29个十。1个千代表10个百，据此可知46个百是几，由此解答即可。\n\n【详解】根据分析可得:10个十是100,100个一百是10000;290里有29个十,46个百是4600。",
+        "knowledge_points":  [
+                                 "万以内数的组成"
+                             ],
+        "source":  "24-25 二年级下·湖北黄冈·期末"
+    },
+    {
+        "id":  "257",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "5010读作( ),三千六百写作( )。",
+        "options":  [
+
+                    ],
+        "answer":  "五千零一十;3600",
+        "solution":  "【分析】千位上是几就有几个千，百位上是几就有几个百，十位上是几就有几个十，个位上是几就有几个一。几个千就是几千，几个百就是几百，几个十就是几十，几个一就是几。整数的写法：从高位到低位，一级一级地写，哪一个数位上一个单位也没有，就在那个数位上写0。整数的读法：从高位到低位，一级一级地读，每一级末尾的0都不读出来，其余数位连续几个0都只读一个零。\n\n【详解】根据分析可得:5010读作五千零一十，三千六百写作3600。",
+        "knowledge_points":  [
+                                 "万以内数的读，写法"
+                             ],
+        "source":  "24-25 二年级下·黑龙江佳木斯·期末"
+    },
+    {
+        "id":  "258",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "一个数由4个千,6个十和9个一组成，这个数是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "4069",
+        "solution":  "【分析】千位上是几就有几个千，百位上是几就有几个百，十位上是几就有几个十，个位上是几就有几个一。几个千就是几千，几个百就是几百，几个十就是几十，几个一就是几。\n\n【详解】根据分析可得：一个数由4个千,6个十和9个一组成，这个数是4069。",
+        "knowledge_points":  [
+                                 "万以内数的组成"
+                             ],
+        "source":  "24-25 二年级下·黑龙江佳木斯·期末"
+    },
+    {
+        "id":  "259",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "8906是( )位数，读作:( ),\"9\"在( )位上，表示( )个( )。",
+        "options":  [
+
+                    ],
+        "answer":  "四;八千九百零六;百;9;百",
+        "solution":  "【分析】一个整数有几个数字组成就是几位数;一个四位数，从右往左数，第一位是个位，表示几个一;第二位是十位，表示几个十;第三位是百位，表示几个百;第四位是千位，表示几个千。整数的写法：从高位到低位，一级一级地写，哪一个数位上一个单位也没有，就在那个数位上写0。整数的读法：从高位到低位，一级一级地读，每一级末尾的0都不读出来，其余数位连续几个0都只读一个零。\n\n【详解】根据分析可得:8906是由4个数字组成的，所以是四位数。8906的千位上是8代表有8个千，百位上是9代表有9个百，十位上是0代表有0个十，个位上是6代表有6个一。所以,8906是四位数，读作八千九百零六，\"9\"在百位上，表示9个百。",
+        "knowledge_points":  [
+                                 "万以内数的读，写法",
+                                 "万以内数的组成"
+                             ],
+        "source":  "24-25 二年级下·湖南·期末"
+    },
+    {
+        "id":  "260",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在算盘上用5颗珠子表示的四位数中，最大的数是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "9000",
+        "solution":  "【分析】根据题意，在算盘上，一颗上珠表示5，一颗下珠表示1，用5颗珠子表示4位数，最高位是千位，尽可能的把珠子放在千位上,1颗上珠,4颗下珠，这个数是9000，据此解答。\n\n【详解】根据分析：在算盘上用5颗珠子表示的四位数中，最大的数是(9000)。",
+        "knowledge_points":  [
+                                 "算盘的认识与使用",
+                                 "万以内数的组成",
+                                 "万以内数的大小比较"
+                             ],
+        "source":  "24-25 二年级下·湖北随州·期末"
+    },
+    {
+        "id":  "261",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "一个四位数，它的最低位和最高位都是6，其他各位上都是0，这个数是( ),与它相邻的两个数分别是( )和( )。",
+        "options":  [
+
+                    ],
+        "answer":  "6006;6005;6007",
+        "solution":  "【分析】一个四位数，从右往左依次是个位，十位，百位，千位，千位上的数是几就表示几个千，百位上的数是几就表示几个百，十位上的数是几就表示几个十，个位上的数是几就表示几个一。写数时，从高位起按照数位顺序写，有几个千就在千位上写几，有几个百就在百位上写几，有几个十就在十位上写几，有几个一就在个位上写几，中间或末尾哪一位上一个也没有，就在哪一位上写0占位。和一个数相邻的两个数，分别是它前面的比它少1的数和它后面的比它多1的数。\n\n【详解】由分析可知：一个四位数，它的最低位和最高位都是6，其他各位上都是0，这个数是(6006),与它相邻的两个数分别是(6005)和(6007)。",
+        "knowledge_points":  [
+                                 "万以内数的读，写法",
+                                 "万以内数的组成",
+                                 "相邻的数"
+                             ],
+        "source":  "24-25 二年级下·湖北随州·期末"
+    },
+    {
+        "id":  "262",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "3405里面有( )个千,( )个百和( )个一。",
+        "options":  [
+
+                    ],
+        "answer":  "3;4;5",
+        "solution":  "【分析】根据题意,3405是一个四位数，最高位是千位，千位上是几，就表示几个千，百位上是几，就表示几个百，十位上是几表示几个十，个位上是几表示几个一，据此解答。\n\n【详解】根据分析:3405里面有(3)个千,(4)个百和(5)个一。",
+        "knowledge_points":  [
+                                 "万以内数的组成"
+                             ],
+        "source":  "24-25 二年级下·湖北随州·期末"
+    },
+    {
+        "id":  "263",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "由6个千和5个十组成的数是( );最小的四位数是由( )个百组成的。",
+        "options":  [
+
+                    ],
+        "answer":  "6050;10",
+        "solution":  "【分析】一个四位数，从右往左依次是个位，十位，百位，千位，千位上的数是几表示几个千，百位上的数是几表示几个百，十位上的数是几表示几个十，个位上的数是几表示几个一，哪一位上一个数也没有，用0占位;最小的四位数是1000，数一数可知:1个百是100,2个百是200,3个百是300,4个百是400。,10个百是1000，据此解答。\n\n【详解】由6个千和5个十组成的数是6050;最小的四位数是由10个百组成的。",
+        "knowledge_points":  [
+                                 "万以内数的组成"
+                             ],
+        "source":  "24-25 二年级下·广东潮州·期末"
+    },
+    {
+        "id":  "264",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "一台电视机的价格是4888元，大约是( )元;一台洗衣机的价格是2099元，大约是( )元，一台洗衣机比一台电视机大约便宜( )元。",
+        "options":  [
+
+                    ],
+        "answer":  "5000;2000;3000",
+        "solution":  "【分析】由题意可知：找出电视机和洗衣机价格最接近的整千数，即是它们的近似数;用电视机价格的近似数减去洗衣机价格的近似数，即是一台洗衣机比一台电视机大约便宜的钱数;据此解答。\n\n【详解】由分析可得:4888≈5000,2099≈2000,5000-2000=3000(元),一台电视机的价格是4888元，大约是5000元;一台洗衣机的价格是2099元，大约是2000元，一台洗衣机比一台电视机大约便宜3000元。",
+        "knowledge_points":  [
+                                 "万以内数的估计",
+                                 "整百数",
+                                 "几百几十数的加减法口算",
+                                 "万以内数加减法的估算"
+                             ],
+        "source":  "24-25二年级下·福建福州·期末"
+    },
+    {
+        "id":  "265",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "与1099相邻的两个数是( )和( )。",
+        "options":  [
+
+                    ],
+        "answer":  "1098;1100",
+        "solution":  "【分析】由题意可知：与1099相邻的两个数分别是：它前面的一个数，和它后面的一个数;据此解答。\n\n【详解】由分析可得：与1099相邻的两个数是1098和1100。",
+        "knowledge_points":  [
+                                 "数万以内的数",
+                                 "相邻的数"
+                             ],
+        "source":  "24-25 二年级下·福建福州·期末"
+    },
+    {
+        "id":  "266",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "福清市体育馆承办过中国女排联赛和第一届青运会等高规格赛事，一共有4024个固定座位，读作( ),这个数里面有2个\"4\"，左边的\"4\"表示( ),右边的\"4\"表示( )。",
+        "options":  [
+
+                    ],
+        "answer":  "四千零二十四;4个千;4个一",
+        "solution":  "【分析】万以内数的读法：读数时，要从高位读起，万位上是几就读几万，千位上是几就读几千，百位上是几就读几百，十位上是几就读几十，个位上是几就读几，中间有一个\"0\"或者连续两个\"0\"就只读一个\"零\"，末尾不管有几个0都不读。然后根据数位知识,4024这个数里面有2个\"4\"，左边的\"4\"在千位上，表示4个千，右边的\"4\"在个位上，表示4个一。据此结合题意分析解答即可。\n\n【详解】根据分析可得:4024读作：四千零二十四，这个数里面有2个\"4\"，左边的\"4\"表示4个千，右边的\"4\"表示4个一。",
+        "knowledge_points":  [
+                                 "万以内数的读，写法",
+                                 "万以内数的组成"
+                             ],
+        "source":  "24-25 二年级下·福建福州·期末"
+    },
+    {
+        "id":  "267",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "一个数由5个千和3个一组成，这个数是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "5003",
+        "solution":  "【分析】一个四位数，从右往左依次是个位，十位，百位，千位，千位上的数是几表示几个千，百位上的数是几表示几个百，十位上的数是几表示几个十，个位上的数是几表示几个一，哪一位上一个数也没有，用0占位;据此解答。\n\n【详解】由分析可得：一个数由5个千和3个一组成，这个数是5003。",
+        "knowledge_points":  [
+                                 "万以内数的组成"
+                             ],
+        "source":  "24-25 二年级下·黑龙江佳木斯·期末"
+    },
+    {
+        "id":  "268",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "在算盘上拨4颗算珠表示一个四位数，最大是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "8000",
+        "solution":  "【分析】整数的大小比较：比较数的大小，先看位数的多少，位数多的数就大;位数相同，从高位开始比较，高位上的数大则这个数大，高位上的数相同，就比较下一位，直到分出大小。算盘上一颗上珠表示5，一颗下珠表示1，将珠子尽量往高位上放即可。千位上放1颗上珠，剩余3颗放在千位下面。\n\n【详解】在算盘上拨4颗算珠表示一个四位数，最大是8000。",
+        "knowledge_points":  [
+                                 "算盘的认识与使用",
+                                 "万以内数的组成",
+                                 "万以内数的大小比较"
+                             ],
+        "source":  "24-25 二年级下·山东济宁·期末"
+    },
+    {
+        "id":  "269",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "18个十是( );5600里面有( )个百;3400是由( )个千和( )个百组成的。",
+        "options":  [
+
+                    ],
+        "answer":  "180;56;3;4",
+        "solution":  "【分析】一个四位数，从右往左依次为个位，十位，百位，千位;千位是几表示几个千，百位是几表示几个百，十位是几表示几个十，个位是几表示几个一。18个十:10个十是100,8个十是80，故18个十是180;5600:5000里面有50个百,6百里面有6个百，故5600里面有56个百;3400千位是3，百位是4;据此可解。\n\n【详解】由分析可得:18个十是180;5600里面有56个百;3400是由3个千和4个百组成的。",
+        "knowledge_points":  [
+                                 "1000以内数的组成",
+                                 "万以内数的组成"
+                             ],
+        "source":  "24-25 二年级下·山东济宁·期末"
+    },
+    {
+        "id":  "270",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "用6,0,0,8组成四位数。其中，最大的一个数是( ),最小的一个数是( )。读数时只读出一个零的四个数中最大的一个是( ),一个零也不读的两个数中最小的一个是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "8600;6008;8060;6800",
+        "solution":  "【分析】读数时，从高位读起，按照数位顺序读。千位是几就读几千，百位是几就读几百，十位上是几就读几十，个位上是几就读几，中间有一个0或两个0，只读一个零;末尾不管有几个0，都不读。①把四个数字按照从大到小的顺序排列，组成的四位数即是最大的数;②把四个数字按照从小到大的顺序排列,0不能放到最高位上，就和排第三位的数字交换位置，组成的四位数即是最小数;③找出只读一个0的所有数字，再从大到小排列，即可找出最大的数;④找出一个0也不读的所有数，再从小到大排列，即可找出最小的数。据此解答。\n\n【详解】由分析可得:①组成最大的数是:8600;②组成最小的数是:6008;③读数时只读一个0的数有:6008,6080,8006,8060;从大到小排列:8060>8006>6080>6008;最大的数是8060。④读数时一个0也不读的数有:6800,8600;从小到大排列:6800<8600;最小的数是6800;用6,0,0,8组成四位数。其中，最大的一个数是8600，最小的一个数是6008。读数时只读出一个零的四个数中最大的一个是8060，一个零也不读的两个数中最小的一个是6800。",
+        "knowledge_points":  [
+                                 "万以内数的读，写法",
+                                 "万以内数的组成",
+                                 "万以内数的大小比较"
+                             ],
+        "source":  "24-25 二年级下·甘肃天水·期末"
+    },
+    {
+        "id":  "271",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "一个数是由4个千和7个一组成的，这个数是( ),它后面的第5个数是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "4007;4012",
+        "solution":  "【分析】一个四位数，从右往左依次为个位，十位，百位，千位;千位是几表示几个千，百位是几表示几个百，十位是几表示几个十，个位是几表示几个一;写数时，从高位写起，几个千就在千位上写几，几个百就在百位上写几，几个十就在十位上写几，几个一就在个位上写几，哪一位上一个数字也没有就写\"0\"占位;这个数千位是4，个位是7;在这个数后面数5个数，第5个数即是它后面的第5个数;据此解答。\n\n【详解】由分析可得：这个数是4007;4007后面5个数分别是:4008,4009,4010,4011,4012;4007后面第5个数是4012。一个数是由4个千和7个一组成的，这个数是4007，它后面的第5个数是4012。",
+        "knowledge_points":  [
+                                 "数万以内的数",
+                                 "万以内数的组成"
+                             ],
+        "source":  "24-25二年级下·甘肃天水·期末"
+    },
+    {
+        "id":  "272",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "某高速公路收费站昨天通过5008辆汽车，约( )辆。",
+        "options":  [
+
+                    ],
+        "answer":  "5000",
+        "solution":  "【分析】根据整数估算的方法，把整数估算成与它相近的整千的数或几千几百的数，据此解答。\n\n【详解】据分析可知，某高速公路收费站昨天通过5008辆汽车，约5000辆。",
+        "knowledge_points":  [
+                                 "万以内数的估计"
+                             ],
+        "source":  "24-25 二年级下·福建福州·期末"
+    },
+    {
+        "id":  "273",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "用0,7,3,9四张数字卡片组成的四位数中，最大的数是( ),最小的数是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "9730;3079",
+        "solution":  "【分析】要想组成的数最大，要把数字按照从大到小的顺序从高位到低位排下来;要想组成的数最小，要把数按照从小到大的顺序从高位到低位排下来，但是最高位不能是零。\n\n【详解】据分析可知：由0,7,3,9四张数字卡片组成的四位数中，最大的数是9730，最小的数是3079。",
+        "knowledge_points":  [
+                                 "万以内数的组成",
+                                 "万以内数的大小比较"
+                             ],
+        "source":  "24-25 二年级下·福建福州·期末"
+    },
+    {
+        "id":  "274",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "武汉长江大桥全长约一千六百七十米，写作( )。它由( )个千,( )个百和( )个十组成。",
+        "options":  [
+
+                    ],
+        "answer":  "1670;1;6;7",
+        "solution":  "【分析】整数的写法：从高位到低位，一级一级地写，哪一个数位上一个单位也没有，就在那个数位上写0。整数中，从右到左分别是个位，十位，百位，千位。个位上是几表示几个一，十位上是几表示几个十，百位上是几表示几个百，千位上是几表示几个千。\n\n【详解】由分析可得：武汉长江大桥全长约一千六百七十米，写作1670。它由1个千,6个百和7个十组成。",
+        "knowledge_points":  [
+                                 "万以内数的读，写法",
+                                 "万以内数的组成"
+                             ],
+        "source":  "24-25 二年级下·黑龙江佳木斯·期末"
+    },
+    {
+        "id":  "275",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "由3个千,4个十和8个一组成的数是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "3048",
+        "solution":  "【分析】一个整数，从右往左依次为个位，十位，百位，千位。千位是几就有几个千(几个千就是几千),百位是几就有几个百(几个百就是几百),十位是几就有几个十(几个十就是几十),个位是几就有几个一(几个一就是几),由此解答。\n\n【详解】3个千是3000;4个十是40;8个一是8。则由3个千,4个十和8个一组成的数是3048。",
+        "knowledge_points":  [
+                                 "万以内数的组成"
+                             ],
+        "source":  "24-25二年级下·黑龙江佳木斯·期末"
+    },
+    {
+        "id":  "276",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "按规律填数.\n(1)225,230,235,( ),( ),( ).\n(2)2080,2090,( ),2110,( ),( )。",
+        "options":  [
+
+                    ],
+        "answer":  "240;245;250 2100;2120;2130",
+        "solution":  "【分析】(1)数列中的每一个数字都比前一个数字大5,235+5=240,240+5=245,245+5=250，依次填入即可。(2)数列中的每一个数字都比前一个数字大10,2090+10=2100,2100+10=2110,2110+10=2120,2120+10=2130，依次填入即可。\n\n【详解】(1)225,230,235,240,245,250。(2)2080,2090,2100,2110,2120,2130。",
+        "knowledge_points":  [
+                                 "整数排列的规律"
+                             ],
+        "source":  "24-25 二年级下·广东揭阳·期末"
+    },
+    {
+        "id":  "277",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "川江是长江上游河段，全长1020千米，横线上的数读作( ),它里面有( )个十。",
+        "options":  [
+
+                    ],
+        "answer":  "一千零二十;102",
+        "solution":  "【分析】万以内数的读法：读数时，要从高位起，千位上是几就读几千，百位上是几就读几百，十位上是几就读几十，个位上是几就读几，中间有一个0或两个0，只读一个\"零\"，末尾不管有几个0，都不读;1020中千位上是1，百位上是0，十位上是2，个位上的0，说明是由1个千和2个十组成,1个千也就是1000,1000中有100个十，那么100个十和2个十合起来是102个十;据此解答。\n\n【详解】根据分析：横线上的数读作一千零二十，它里面有102个十。",
+        "knowledge_points":  [
+                                 "万以内数的组成",
+                                 "万以内数的读，写法"
+                             ],
+        "source":  "24-25 二年级下·内蒙古赤峰·期末"
+    },
+    {
+        "id":  "278",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "一个数是4个千和7个一和2个十组成的，这个数写作( ),它的近似数是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "4027;4000",
+        "solution":  "【分析】写数时从高位写起,4个千即千位上是4,2个十即十位上是2,7个一即个位上是7，写作4027;4027的近似数保留整千是4000。\n\n【详解】由分析可知：一个数是4个千和7个一和2个十组成的，这个数写作4027，它的近似数是4000。",
+        "knowledge_points":  [
+                                 "万以内数的读，写法",
+                                 "万以内数的组成",
+                                 "万以内数的估计"
+                             ],
+        "source":  "24-25二年级下·内蒙古赤峰·期末"
+    },
+    {
+        "id":  "279",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "在计数器上表示506，需要拨( )个珠;在算盘上表示506，需要拨( )个珠靠梁。",
+        "options":  [
+
+                    ],
+        "answer":  "11;3",
+        "solution":  "【分析】算盘一个上珠表示5，一个下珠表示1，据此数清楚各个数位上珠子的数量，即可得出答案。计数器百位上有几个珠子表示几个百，十位上有几个珠子表示几个十，个位上有几个珠子表示几个一，据此数清楚各个数位上的珠子，即可得出答案。\n\n【详解】在计数器上表示506，百位上需要拨5个珠子，个位上需要拨6个珠子，一共需要拨11个珠子。在算盘上表示506，百位上需要拨1个上珠靠梁，个位上需要拨1个上珠和1个下珠靠梁，所以一共需要拨3个珠靠梁。",
+        "knowledge_points":  [
+                                 "算盘的认识与使用",
+                                 "1000以内数的组成"
+                             ],
+        "source":  "24-25 二年级下·内蒙古赤峰·期末"
+    },
+    {
+        "id":  "280",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "4600里面有( )个百,52个十是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "46;520",
+        "solution":  "【分析】1个百是100,2个百是200。46个百是4600，故4600里面有46个百;1个十是10,2个十是20。52个十是520，据此解答。\n\n【详解】4600里面有46个百,52个十是520。",
+        "knowledge_points":  [
+                                 "1000以内数的组成",
+                                 "万以内数的组成"
+                             ],
+        "source":  "24-25 二年级下·甘肃天水·期末"
+    },
+    {
+        "id":  "281",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "用数字4,9,0,3组成的四位数中，最大的是( ),最小的是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "9430;3049",
+        "solution":  "【分析】要组成最大的四位数，需将数字从大到小排列;组成最小的四位数时，最高位不能为0，需选择最小的非零数字作为最高位，剩余数字从小到大排列。\n\n【详解】最大四位数：将数字4,9,0,3按从大到小排列为9,4,3,0，因此最大数为9430。最小四位数：最高位选择最小的非零数字，即3;剩余数字0,4,9按从小到大排列为0,4,9;因此最小数为3049。",
+        "knowledge_points":  [
+                                 "万以内数的组成",
+                                 "万以内数的大小比较"
+                             ],
+        "source":  "24-25二年级下·甘肃天水·期末"
+    },
+    {
+        "id":  "282",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "青藏铁路全长1956千米，大约是( )千米，它由( )个千,( )个百,( )个十和( )个一组成。",
+        "options":  [
+
+                    ],
+        "answer":  "2000;1;9;5;6",
+        "solution":  "【分析】求大约数就找到与实际接近的整数，由此可知;1956和2000接近;一个四位数，从右往左依次为个位，十位，百位，千位;千位是几就有几个千，百位是几就有几个百，十位是几就有几个十，个位是几就有几个一。\n\n【详解】青藏铁路全长1956千米，大约是(2000)千米，它由(1)个千,(9)个百,(5)个十和(6)个一组成。",
+        "knowledge_points":  [
+                                 "万以内数的估计",
+                                 "万以内数的组成"
+                             ],
+        "source":  "24-25 二年级下·甘肃天水·期末"
+    },
+    {
+        "id":  "283",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "找规律写数.\n6500,6300,6100,( ),( ),( )。",
+        "options":  [
+
+                    ],
+        "answer":  "5900;5700;5500",
+        "solution":  "【分析】该组规律为：数字从左到右依次减200。\n\n【详解】6500-200=6300;6300-200=6100;6100-200=5900;5900-200=5700;5700-200=5500。则填空如下:6500,6300,6100,(5900),(5700),(5500)。",
+        "knowledge_points":  [
+                                 "整百数",
+                                 "几百几十数的加减法口算",
+                                 "整数排列的规律"
+                             ],
+        "source":  "24-25 二年级下·吉林四平·期末"
+    },
+    {
+        "id":  "284",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "1000里面有100个( );30连续减去( )个5等于0。",
+        "options":  [
+
+                    ],
+        "answer":  "10;6",
+        "solution":  "【分析】10个10是100,20个10是200,。,100个10是1000;求30连续减去几个5等于0，就是求30里面有几个5，用30÷5计算。\n\n【详解】由分析可知:30÷5=6,100个10是1000，因此1000里面有100个(10);30连续减去(6)个5等于0。",
+        "knowledge_points":  [
+                                 "用6的乘法口诀求商",
+                                 "1000以内数的组成"
+                             ],
+        "source":  "24-25 二年级下·云南红河·期末"
+    },
+    {
+        "id":  "285",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "某植物园共栽培了6909株植物，约是( )株，横线上的数读作( )。",
+        "options":  [
+
+                    ],
+        "answer":  "7000;六千九百零九",
+        "solution":  "【分析】找整数近似数的方法：把这个整数看作和它接近的整十，整百或整千数。读数时，从高位读起，千位是几就读几千，百位是几就读几百，十位是几就读几十，个位是几就读几，中间有一个0或两个0，只读一个\"零\"，末尾不管有几个0，都不读。\n\n【详解】6909比较接近7000，因此6909≈7000。(答案不唯一)某植物园共栽培了6909株植物，约是(7000)株，横线上的数读作(六千九百零九)。",
+        "knowledge_points":  [
+                                 "万以内数的估计",
+                                 "万以内数的读，写法"
+                             ],
+        "source":  "24-25二年级下·云南红河·期末"
+    },
+    {
+        "id":  "286",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "49个百是( ),与它相邻的两个数是( )和( )。",
+        "options":  [
+
+                    ],
+        "answer":  "4900;4899;4901",
+        "solution":  "【分析】1个百是100,2个百是200。49个百是4900;数数时,4900相邻的两个数，即4900的前一个数4899和4900后一个数4901，据此解答。\n\n【详解】根据分析可得:49个百是4900，与它相邻的两个数是4899和4901。",
+        "knowledge_points":  [
+                                 "相邻的数",
+                                 "万以内数的组成"
+                             ],
+        "source":  "24-25 二年级下·贵州黔东南·期末"
+    },
+    {
+        "id":  "287",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "从3,4,5,0中选三个数字组成三位数，最大的数是( ),最小的数是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "543;304",
+        "solution":  "【分析】一个三位数，从右往左依次为个位，十位，百位。要组成最大的三位数，则将数字中较大的三个数，从大到小依次写在百位，十位和个位;要组成最小的三位数,0不能在最高位，则把0以外最小的数写在百位，剩余数字中两个较小的数，从小到大依次写在十位和个位。\n\n【详解】0<3<4<5，从3,4,5,0中选三个数字组成三位数，最大的数是543，最小的数是304。",
+        "knowledge_points":  [
+                                 "1000以内数的比大小",
+                                 "1000以内数的组成"
+                             ],
+        "source":  "24-25 一年级下·黑龙江佳木斯·期末"
+    },
+    {
+        "id":  "288",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "一个数由8个千和4个一组成，这个数是( ),它的近似数是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "8004;8000",
+        "solution":  "【分析】一个四位数，从右往左依次为个位，十位，百位，千位;千位是几表示几个千，百位是几表示几个百，十位是几表示几个十，个位是几表示几个一;写数时，从高位写起，几个千就在千位上写几，几个百就在百位上写几，几个十就在十位上写几，几个一就在个位上写几，哪一位上一个数字也没有就写\"0\"占位;8个千和4个一：千位上是8，个位上是4;找出这个数最接近的整千数，即是它的近似数;据此可解。\n\n【详解】由分析可得：一个数由8个千和4个一组成，这个数是8004，它的近似数是8000。",
+        "knowledge_points":  [
+                                 "万以内数的组成",
+                                 "万以内数的估计"
+                             ],
+        "source":  "24-25二年级下·辽宁鞍山·期末"
+    },
+    {
+        "id":  "289",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "光明小学大礼堂有900个座位，\"六一\"节要举行文艺汇演，全校有男生428名，女生有436名，请你估一估，全校学生一起去观看,( )坐下。(填\"能\"或\"不能\")",
+        "options":  [
+
+                    ],
+        "answer":  "能",
+        "solution":  "【分析】由题意可知：把男女生的人数都估成最接近的整百整十数，然后相加，求出全校大概的人数，再和900个座位对比，小于等于900，能坐下;大于900，不能坐下;据此解答。\n\n【详解】由分析可得:428≈430,436≈440;430+440=870(名),870<900，每个数估大的情况下还比900小，故能坐下。光明小学大礼堂有900个座位，\"六一\"节要举行文艺汇演，全校有男生428名，女生有436名，请你估一估，全校学生一起去观看，能坐下。",
+        "knowledge_points":  [
+                                 "万以内数加减法的估算"
+                             ],
+        "source":  "24-25 二年级下·浙江台州·期末"
+    },
+    {
+        "id":  "290",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "用0,0,2,7组成的四位数中，不读零的有( )和( )。",
+        "options":  [
+
+                    ],
+        "answer":  "2700;7200",
+        "solution":  "【分析】万以内数读法，从高位往低位读，千位上的数读作几千，百位上的数读作几百，十位上的数读作几十，个位上的数读作几，中间的一个0或连续两个0，都只读一个\"零\"，末尾的0不用读。\n\n【详解】用0,0,2,7组成的四位数中，不读零的数,0要放在末尾，即是2700和7200。",
+        "knowledge_points":  [
+                                 "万以内数的读，写法",
+                                 "万以内数的组成"
+                             ],
+        "source":  "24-25 二年级下·浙江台州·期末"
+    },
+    {
+        "id":  "291",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "在算盘上，一个下珠表示1，一个上珠表示5。( )",
+        "options":  [
+
+                    ],
+        "answer":  "√",
+        "solution":  "【分析】算盘的基本计数规则是：一个上珠表示5，一个下珠表示1;据此可判断。\n\n【详解】由分析可得：在算盘上，一个下珠表示1，一个上珠表示5。故答案为:√",
+        "knowledge_points":  [
+                                 "算盘的认识与使用"
+                             ],
+        "source":  "19-20一年级上·全国·课后作业"
+    },
+    {
+        "id":  "292",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "一台吸尘器的价格是409元，李叔叔带了595元，买一台吸尘器后，大约还剩多少元。",
+        "options":  [
+
+                    ],
+        "answer":  "200元",
+        "solution":  "【分析】由题意可知：找出吸尘器价格和李叔叔带的钱最接近整百数的近似数;再把两个近似数相减，即是大约还剩的钱数;据此解答。\n\n【详解】由分析可得:409≈400,595≈600;600-400=200(元),答：大约还剩200元。",
+        "knowledge_points":  [
+                                 "1000以内数的估计",
+                                 "万以内数加减法的估算"
+                             ],
+        "source":  "24-25 二年级下·山东济南·期末"
+    },
+    {
+        "id":  "293",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "水果店有苹果280千克，卖出150千克后，又运来90千克，现在有多少千克苹果。",
+        "options":  [
+
+                    ],
+        "answer":  "220千克",
+        "solution":  "【分析】用水果店原来苹果的重量减去卖出的重量，然后加上又运来的重量即可求解。\n\n【详解】280-150+90=130+90=220(千克),答：现在有220千克苹果。",
+        "knowledge_points":  [
+                                 "整百数",
+                                 "几百几十数的加减法口算",
+                                 "两，三位数的加减混合运算"
+                             ],
+        "source":  "24-25 二年级下·湖南岳阳·期中"
+    },
+    {
+        "id":  "294",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "果园里种了600棵苹果树，梨树比苹果树多300棵，果园里苹果树和梨树一共有多少棵。",
+        "options":  [
+
+                    ],
+        "answer":  "1500棵",
+        "solution":  "【分析】因为梨树比苹果树多300棵，根据加法的意义，用600+300先求出梨树的数量，再将梨树和苹果树的数量相加，即可得出果园里苹果树和梨树一共有多少棵。600+300+600=900+600=1500(棵),答：果园里苹果树和梨树一共有1500棵。\n\n【详解】600+300=900(棵),900+600=1500(棵),答：果园里苹果树和梨树一共有1500棵。",
+        "knowledge_points":  [
+                                 "整百数",
+                                 "几百几十数的加减法口算"
+                             ],
+        "source":  "23-24 二年级下·云南昭通·期末"
+    },
+    {
+        "id":  "295",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "\"双十一\"期间，妈妈在网上给明明买了一套故事书和一个80元的书包，共花了120元，一套故事书有5本，平均每本故事书多少钱。",
+        "options":  [
+
+                    ],
+        "answer":  "8元",
+        "solution":  "【分析】由题意可知：用共花的钱减去一个书包的钱，即是一套故事书的钱，再除以一套故事书的本数，即是平均每本故事书的钱;据此解答。\n\n【详解】由分析可得:(120-80)÷5=40÷5=8(元),答：平均每本故事书8元钱。",
+        "knowledge_points":  [
+                                 "整百数",
+                                 "几百几十数的加减法口算",
+                                 "用7~9的乘法口诀求商",
+                                 "带有小括号的混合运算"
+                             ],
+        "source":  "23-24 二年级下·云南昭通·期末"
+    },
+    {
+        "id":  "296",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "学校食堂今天运进土豆5000千克，西红柿4000千克，还运进了一些大白菜.\n(1)一共运进土豆和西红柿多少千克。\n(2)大白菜比西红柿少2000千克，运进多少千克的大白菜。",
+        "options":  [
+
+                    ],
+        "answer":  "9000千克;2000千克",
+        "solution":  "【分析】(1)根据加法的意义，运进土豆的重量+运进西红柿的重量=运进土豆和西红柿的总重量;(2)根据减法的意义，运进西红柿的重量-运进大白菜比西红柿少的重量=运进大白菜的重量。\n\n【详解】(1)5000+4000=9000(千克),答：一共运进土豆和西红柿9000千克。(2)4000-2000=2000(千克),答：运进2000千克的大白菜。",
+        "knowledge_points":  [
+                                 "整百数",
+                                 "几百几十数的加减法口算"
+                             ],
+        "source":  "24-25 二年级下·湖南·期末"
+    },
+    {
+        "id":  "297",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "端午节学校食堂包粽子，红枣粽子包了500个，比肉粽子少200个。红枣粽子和肉粽子一共多少个。",
+        "options":  [
+
+                    ],
+        "answer":  "1200个",
+        "solution":  "【分析】用红枣粽子的个数加红枣粽子比肉粽子少的个数算出肉粽子的个数，然后将两种粽子的个数相加即可求解。500+200+500=700+500=1200(个),答：红枣粽子和肉粽子一共1200个。\n\n【详解】500+200=700(个),700+500=1200(个),答：红枣粽子和肉粽子一共1200个。",
+        "knowledge_points":  [
+                                 "整百数",
+                                 "几百几十数的加减法口算"
+                             ],
+        "source":  "24-25二年级下·山东济宁·期末"
+    },
+    {
+        "id":  "298",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "一年级和二年级学生要去礼堂听报告，一年级有489人，二年级有493人，一共有1000人座位，请你估一估，坐得下吗。",
+        "options":  [
+
+                    ],
+        "answer":  "坐得下",
+        "solution":  "【分析】由题意可知：分别找出一二年级人数最接近的整百数，再相加算出总人数，再和1000对比，小于等于1000，坐得下;大于1000，坐不下;据此解答。\n\n【详解】由分析可得:489≈500,493≈500;500+500=1000(人),1000=1000，每个数都估大的情况下，总人数恰好是1000人。答：坐得下。",
+        "knowledge_points":  [
+                                 "万以内数的大小比较",
+                                 "万以内数的估计",
+                                 "整百数",
+                                 "几百几十数的加减法口算",
+                                 "万以内数加减法的估算"
+                             ],
+        "source":  "24-25 二年级下·甘肃天水·期末"
+    },
+    {
+        "id":  "299",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "用数字卡片0,2,5,7可以组成多少个不同的三位数。请写出其中最大的和最小的三位数。",
+        "options":  [
+
+                    ],
+        "answer":  "18个;752;205",
+        "solution":  "【分析】一个三位数，从右往左依次为个位，十位，百位。组成三位数时，百位不能为0，百位可以是2,5,7中的任意一个数，有3种选择;十位从剩余的数字中选，有3种选择;个位从剩余的2个数中选，有2种选择;组成三位数的总数量为3×3×2;最大的三位数，将数字中较大的三个数，从大到小分别写在百位，十位和个位;最小的三位数，把0以外最小的数字写在百位，剩余数字中较小的两个数，从小到大分别写在十位和个位。\n\n【详解】0<2<5<7,3×3×2=18(个),答：可以组成18个不同的三位数，最大的三位数是752，最小的三位数是205。",
+        "knowledge_points":  [
+                                 "含0的组数问题",
+                                 "1000以内数的比大小",
+                                 "1000以内数的组成"
+                             ],
+        "source":  "24-25 二年级下·黑龙江佳木斯·期末"
+    },
+    {
+        "id":  "300",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "小王家，小李家与长江学校在同一条笔直的街道上，小王家距离学校1700米，小李家距离学校800米，小王家与小李家相距多少米。",
+        "options":  [
+
+                    ],
+        "answer":  "2500米或900米",
+        "solution":  "【分析】①当小王家与小李家在学校的两侧时，小王家与小李家相距的路程=小王家距离学校的路程+小李家距离学校的路程;②当小王家与小李家在学校的同侧时，小王家与小李家相距的路程=小王家距离学校的路程-小李家距离学校的路程。\n\n【详解】①1700+800=2500(米);②1700-800=900(米);答：小王家与小李家相距2500米或者900米。",
+        "knowledge_points":  [
+                                 "整百数",
+                                 "几百几十数的加减法口算"
+                             ],
+        "source":  "24-25 二年级下·浙江台州·期末"
+    },
+    {
+        "id":  "301",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "和3999相邻的两个数是( )。",
+        "options":  [
+                        "A. 4000和4001",
+                        "B. 3899和4000",
+                        "C. 3998和4000"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】相邻的两个数是指比给定数小1和大1的数。3999的前一个数是3998，后一个数是4000。\n\n【详解】3999-1=3998,3999+1=4000，即，和3999相邻的两个数是(3998和4000)。故答案为:C",
+        "knowledge_points":  [
+                                 "相邻的数"
+                             ],
+        "source":  "24-25二年级下·广东汕头·期末"
+    },
+    {
+        "id":  "302",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "下面三个数中，一个零都不读的是( )。",
+        "options":  [
+                        "A. 9700",
+                        "B. 9070",
+                        "C. 9007"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】读一个四位数，从高位往低位读，千位上的数读作几千，百位上的数读作几百，十位上的数读作几十，个位上的数读作几，中间的一个0或连续两个0，都只读一个\"零\"，末尾的0不用读。据此读出每一个数即可解决。\n\n【详解】A。9700读作：九千七百，一个零都不读;B。9070读作：九千零七十，读出一个零;C。9007读作：九千零七，读出一个零;即，一个零都不读的是(9700)。故答案为:A",
+        "knowledge_points":  [
+                                 "万以内数的读，写法"
+                             ],
+        "source":  "24-25 二年级下·广东汕头·期末"
+    },
+    {
+        "id":  "303",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "一个数的最高位是千位，那么这个数是( )位数。",
+        "options":  [
+                        "A. 三",
+                        "B. 四",
+                        "C. 五"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】一个数的最高位是千位，说明该数包含千位，百位，十位和个位，共有四位。例如：最小的四位数是1000，最高位是千位;最大的四位数是9999，最高位同样是千位。因此这个数是四位数。\n\n【详解】由题意分析得：一个数的最高位是千位，那么这个数是四位数。故答案为:B",
+        "knowledge_points":  [
+                                 "万以内数的组成"
+                             ],
+        "source":  "24-25二年级下·广东汕头·期末"
+    },
+    {
+        "id":  "304",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "下面一个零也不读的数是( )。",
+        "options":  [
+                        "A. 6017",
+                        "B. 6071",
+                        "C. 6700"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】一个四位数，从右往左依次为个位，十位，百位，千位。读数时，从高位读起，按照数位顺序读。千位是几就读几千，百位是几就读几百，十位上是几就读几十，个位上是几就读几，中间有一个0或两个0，只读一个零;末尾不管有几个0，都不读。逐项分析各个选项，找出一个零也不读的数，即可解答。\n\n【详解】A。6017：读作\"六千零一十七\"。百位是0，读出\"零\"。B。6071：读作\"六千零七十一\"。百位是0，读出\"零\"。C。6700：读作\"六千七百\"。百位是7，十位和个位都是0，且位于末尾，末尾的0不读出，没有读出\"零\"。只有6700在读出时\"一个零也不读\"，符合题意。故答案为:C",
+        "knowledge_points":  [
+                                 "万以内数的读，写法"
+                             ],
+        "source":  "24-25二年级下·广东江门·期末"
+    },
+    {
+        "id":  "305",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "下面的数中，只读一个0的数是( )。",
+        "options":  [
+                        "A. 4770",
+                        "B. 4007",
+                        "C. 4700"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】根据整数的读法：从高位到低位，一级一级地读，每一级末尾的0都不读出来，其余数位连续几个0都只读一个零，分析每个选项找出符合题意的选项即可解答。\n\n【详解】A。4770读作四千七百七十，不符合题意;B。4007读作四千零七，符合题意;C。4700读作四千七百，不符合题意。故答案为:B",
+        "knowledge_points":  [
+                                 "万以内数的读，写法"
+                             ],
+        "source":  "24-25 二年级下·河北张家口·期末"
+    },
+    {
+        "id":  "306",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "京杭大运河是世界上里程最长的古代运河，全长约1794千米，下面( )中的\"7\"和1794中的\"7\"表示的意义相同。",
+        "options":  [
+                        "A. 6017",
+                        "B. 735",
+                        "C. 1176"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】一个四位数，从右往左数，第一位是个位，表示几个一;第二位是十位，表示几个十;第三位是百位，表示几个百;第四位是千位，表示几个千。1794中的\"7\"在百位上，代表\"7\"个百，据此解答即可。\n\n【详解】A。6017中的\"7\"在个位上，不符合题意;B。735中的\"7\"在百位上，代表7个百，符合题意;C。1176中的\"7\"在十位上，不符合题意。故答案为:B",
+        "knowledge_points":  [
+                                 "万以内数的组成"
+                             ],
+        "source":  "24-25 二年级下·河北张家口·期末"
+    },
+    {
+        "id":  "307",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "一个0也不读的数是( )。",
+        "options":  [
+                        "A. 2090",
+                        "B. 2009",
+                        "C. 2900"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】万以内数的读法：从高位读起，千位上是几，读作几千;百位上是几，读作几百;十位上是几，读作几十;个位上是几，读作几;末尾的0不读，中间的1个或连续2个0，只读1个零。据此读出选项中各数，找出一个零也不读的数，即可解答。\n\n【详解】A。2090读作\"二千零九十\"，中间的0被读出，不符合条件;B。2009读作\"二千零九\"，中间的0被读出，不符合条件;C。2900读作\"二千九百\"，末尾的0不读，符合条件。故答案为:C",
+        "knowledge_points":  [
+                                 "万以内数的读，写法"
+                             ],
+        "source":  "23-24 二年级下·河南信阳·期末"
+    },
+    {
+        "id":  "308",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "最小的四位数再加1是( )。",
+        "options":  [
+                        "A. 101",
+                        "B. 1001",
+                        "C. 10001"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】一个四位数，从右往左依次是个位，十位，百位，千位。最小的四位数，千位上是1，其它数位都是0，即1000,1000加1也就是数数时，从1000开始数，再往后数一个数即1001，逐项分析各个选项，找出正确答案即可。\n\n【详解】A。101：是三位数，不符合要求。B。1001：是四位数，且是1000加1的结果。C。10001：是五位数，不符合要求。最小的四位数再加1是1001。故答案为:B",
+        "knowledge_points":  [
+                                 "数万以内的数",
+                                 "万以内数的组成"
+                             ],
+        "source":  "24-25 二年级下·湖南长沙·期末"
+    },
+    {
+        "id":  "309",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "下面表示的数中，一个零也不读的数是( )。",
+        "options":  [
+                        "A. ![](images/d78cb92b0c7f922f1034a361e768ead15bd0a3dc859dce5d5e5b6744c48d8550.jpg)",
+                        "B. ![](images/76586e6e921c64f922542603a97784a04726fcf141f2236bac46de772ac7974b.jpg)",
+                        "C. ![](images/637351bca4e6077bc1d00adff0211378e2e1bded66e0d7229a33315900f358e5.jpg)"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】根据整数的读法：从高位到低位，一级一级地读，每一级末尾的0都不读出来，其余数位连续几个0都只读一个零，据此读出此数。\n\n【详解】A。一大正方体有1000个小正方体表示的是1个千，散落的4个小正方体表示的是4个一，则写作1004，则读作一千零四。不符合题意。B。!计数器表示数，千位上有几个珠子则表示几个千，百位上有几个珠子表示几个百，十位上有几个珠子，就表示几个十，个位上有几个珠子，就表示几个一，一个也没有，用\"0\"表示，则图中表示的是2503，则读作：二千五百零三，不符合题意。C。算盘上一个上珠表示5，一个下珠表示1，则图中的数是1300，读作一千三百，符合题意。则一个零也不读的数是C。故答案为:C",
+        "knowledge_points":  [
+                                 "算盘的认识与使用",
+                                 "万以内数的读，写法",
+                                 "万以内数的组成"
+                             ],
+        "source":  "24-25 二年级下·福建福州·期末"
+    },
+    {
+        "id":  "310",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "下面各数中，一个零都不读的是( )。",
+        "options":  [
+                        "A. 3030",
+                        "B. 5000",
+                        "C. 2023"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】读一个四位数，从高位往低位读，千位上的数读作几千，百位上的数读作几百，十位上的数读作几十，个位上的数读作几，中间的一个0或连续两个0，都只读一个\"零\"，末尾的0不用读。需逐项分析各数的读法，判断是否读出零。\n\n【详解】A。3030读作\"三千零三十\"，中间的0被读出，因此读出一个零，不符合条件。B。5000读作\"五千\"，末尾的0均不读，因此一个零都不读，符合条件。C。2023读作\"二千零二十三\"，中间的0被读出，因此读出一个零，不符合条件。故答案为:B",
+        "knowledge_points":  [
+                                 "万以内数的读，写法"
+                             ],
+        "source":  "24-25 二年级下·广西玉林·期末"
+    },
+    {
+        "id":  "311",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "一个粮仓有900袋大米，第一次运走了200袋，第二次运走了300袋，还剩多少袋大米。下面列式错误的是( )。",
+        "options":  [
+                        "A. 900-200+300",
+                        "B. 900-(200+300)",
+                        "C. 900-200-300"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】①用粮仓大米的总数先减去第一次运走的数量，求出差，再减去第二次运走的数量，即900-200-300;②用粮仓大米的总数减去两次运走的数量和，即900-(200+300);据此解决即可。\n\n【详解】A。900-200+300计算过程为:900-200=700,700+300=1000，错误地将第二次运走的300袋视为\"增加\"，与题意矛盾。B。900-(200+300)计算过程为：先求两次运走的数量和200+300=500，再求还剩的数量900-500=400，符合题意。C。900-200-300计算过程为：先求第一次运走后还剩的数量900-200=700，再求最后还剩的数量700-300=400，符合题意。故答案为:A",
+        "knowledge_points":  [
+                                 "两，三位数的连减运算",
+                                 "两，三位数的加减混合运算",
+                                 "带有小括号的混合运算"
+                             ],
+        "source":  "24-25二年级下·陕西延安·期末"
+    },
+    {
+        "id":  "312",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "785<□84,□里最小能填( )。",
+        "options":  [
+                        "A. 7",
+                        "B. 8",
+                        "C. 9"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】整数比较大小的方法，位数多的数大于位数少的数;位数相同的数，从最高位比起，最高位上大的数就大，最高位上相同的，就比较下一位，以此类推。左边数785的百位是7，右边数□84的百位是□。要使□84>785，需满足：若□>7，则无论十位和个位如何,□84一定大于785。此时□最小为8。若□=7，则比较十位：两边十位均为8，接着比较个位，左边个位5>右边个位4，此时784<785，不满足条件。因此,□里最小填8。\n\n【详解】由分析可知:A。□=7,785>784，不符合题意;B。□=8,785<884，符合题意;C。□=9,785<984，但9>8，不符合最小能填的数;785<□84,□里最小能填(8)。故答案为:B",
+        "knowledge_points":  [
+                                 "1000以内数的比大小"
+                             ],
+        "source":  "24-25 二年级下·陕西延安·期末"
+    },
+    {
+        "id":  "313",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "下列数中，比7000小，比4700大的是( )。",
+        "options":  [
+                        "A. 4098",
+                        "B. 4760",
+                        "C. 7050"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】比较各选项数值与4700和7000的大小关系，选出符合4700<数值<7000的选项。比较时，位数多的数就大，位数相同比较最高位，最高位大的数就大，最高位相同比较下一位，直到比较出结果为止。\n\n【详解】A。4098<4700<7000，不符合题意;B。4700<4760<7000，符合题意;C。4700<7000<7050，不符合题意。则比7000小，比4700大的是4760。故答案为:B",
+        "knowledge_points":  [
+                                 "万以内数的大小比较"
+                             ],
+        "source":  "24-25 二年级下·甘肃天水·期末"
+    },
+    {
+        "id":  "314",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "下图直线上的点表示的数可能是( ).\n![](images/5a99ab1355e9602868bc4ca28f46f40a39b941ee0645b13be041b5cdffd342fd.jpg)",
+        "options":  [
+                        "A. 4060",
+                        "B. 3650",
+                        "C. 3950"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】这个点位于3500和4000之间，所以这个数大于3500小于4000，点的位置靠近4000，所以这个数接近4000，逐项分析各个选项，找出正确选项即可解答。\n\n【详解】A。4060的位置在4000右边，不符合题意;B。3650的位置靠近3500，不符合题意;C。3950的位置靠近4000，符合题意;这个点表示的数可能是3950。故答案为:C",
+        "knowledge_points":  [
+                                 "万以内数的估计"
+                             ],
+        "source":  "24-25 二年级下·贵州铜仁·期末"
+    },
+    {
+        "id":  "315",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "要使3□82>3473,□里最小填( )。",
+        "options":  [
+                        "A. 3",
+                        "B. 4",
+                        "C. 9"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】整数的大小比较：先看位数，位数多的数大;位数相同，从最高位看起，相同数位上的数大那个数就大。\n\n【详解】两个数的千位都是3，相等;左边数的百位是□,右边数的百位是4，若□>4，则3□82>3473;若□=4，继续比较十位：左边数的十位是8，右边数的十位是7，由于8>7，此时3□82>3473;若□<4，则3□82<3473;所以要使3□82>3473,□里最小填4。故答案为:B",
+        "knowledge_points":  [
+                                 "万以内数的大小比较"
+                             ],
+        "source":  "24-25 二年级下·湖北黄冈·期末"
+    },
+    {
+        "id":  "316",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "小刚家种植果树580棵，丁丁家种的果树比小刚家多得多，丁丁家种植的果树可能是( )。",
+        "options":  [
+                        "A. 560棵",
+                        "B. 600棵",
+                        "C. 1850棵"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】比较数的大小，先看位数的多少，位数多的数就大;如果位数相同，从最高位开始比较，最高位上的数大则这个数大，最高位上的数相同，就比较下一位，依次类推。描述数的大小关系的方法：通过比较具体数，用\"多些\"\"少一些\"描述相差较小的两个数;用\"多得多\"\"少得多\"描述相差较大的两个数，根据数的相对大小，结合题干要求进行解答即可。\n\n【详解】A。560和580相差较小，且560比580小，即560比580少一些，不符合题意;B。600和580相差较小，且600比580大，即600比580多一些，不符合题意;C。1850和580相差很大，且1850比580大，即1850比580多得多，符合题意。故答案为:C",
+        "knowledge_points":  [
+                                 "万以内数的大小比较",
+                                 "数的相对大小关系"
+                             ],
+        "source":  "24-25 二年级下·河北张家口·期末"
+    },
+    {
+        "id":  "317",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "下面各数中，一个零也不读的是( )。",
+        "options":  [
+                        "A. 2500",
+                        "B. 2005",
+                        "C. 5020"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】读一个四位数，从高位往低位读，千位上的数读作几千，百位上的数读作几百，十位上的数读作几十，个位上的数读作几，中间的一个0或连续两个0，都只读一个\"零\"，末尾的0不用读。读出每一个数，即可解决。\n\n【详解】A。2500读作：二千五百，末尾两个0不读，一个零也不读，符合题意。B。2005读作：二千零五，中间两个0读一个\"零\"，不符合题意。C。5020读作：五千零二十，中间的0需读\"零\"，不符合题意。故答案为:A",
+        "knowledge_points":  [
+                                 "万以内数的组成"
+                             ],
+        "source":  "24-25 二年级下·天津河西·期末"
+    },
+    {
+        "id":  "318",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "下面各数中，一个零也不读的数是( )。",
+        "options":  [
+                        "A. 5006",
+                        "B. 5600",
+                        "C. 5060"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】读数时，从高位读起，千位是几就读几千，百位是几就读几百，十位是几就读几十，个位是几就读几，中间有一个0或两个0，只读一个\"零\"，末尾不管有几个0，都不读。\n\n【详解】A。5006读作：五千零六，读了一个\"零\"，不符合题意;B。5600读作：五千六百，一个\"零\"也没读，符合题意;C。5060读作：五千零六十，读了一个\"零\"，不符合题意。故答案为:B",
+        "knowledge_points":  [
+                                 "万以内数的读，写法"
+                             ],
+        "source":  "24-25二年级下·广东汕尾·期末"
+    },
+    {
+        "id":  "319",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "2457的最高位是( )位，百位上的数表示( )个( )。",
+        "options":  [
+
+                    ],
+        "answer":  "千;4;百",
+        "solution":  "【分析】四位数的最高位是千位;一个四位数，从右往左数，第一位是个位，个位上的数表示几个一;第二位是十位，十位上的数表示几个十;第三位是百位，百位上的数表示几个百;第四位是千位，千位上的数表示几个千;据此填空即可。\n\n【详解】由题意分析得:2457的最高位是千位，百位上的数表示4个百。",
+        "knowledge_points":  [
+                                 "万以内数的组成"
+                             ],
+        "source":  "24-25 二年级下·浙江台州·期末"
+    },
+    {
+        "id":  "320",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "学校共有2289名学生，和这个数最接近的整百数是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "2300",
+        "solution":  "【分析】根据题意可知，要找2289最接近的整百数，则需要看十位,2289十位上是8，接近10，则十位需要向前位进1，所以2289名学生接近整百数2300名学生。\n\n【详解】根据分析可得：学校共有2289名学生，和这个数最接近的整百数是2300。",
+        "knowledge_points":  [
+                                 "万以内数的估计"
+                             ],
+        "source":  "24-25 二年级下·浙江台州·期末"
+    },
+    {
+        "id":  "321",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "找规律，填一填。\n(1)940，950，960，( )，980，( )。\n(2)895，896，897，( )，899，( )。",
+        "options":  [
+
+                    ],
+        "answer":  "970;990;898;900",
+        "solution":  "【分析】(1)观察数列940，950，960，发现每个数依次增加10，遵循此规律填写出后面需要的数即可解答；(2)观察数列895，896，897，发现每个数依次增加1，遵循此规律填写出后面需要的数即可解答。\n\n【详解】(1)10个10个往后数，960后面是970；10个10个往后数，980后面是990。所以，这组数是940，950，960，(970)，980，(990)。\n(2)1个1个往后数，897后面是898；1个1个往后数，899后面是900。所以，这组数是895，896，897，(898)，899，(900)。",
+        "knowledge_points":  [
+                                 "数1000以内的数",
+                                 "整数排列的规律"
+                             ],
+        "source":  "24-25 二年级下·广东汕头·期末"
+    },
+    {
+        "id":  "322",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "东方小学的图书室有673本书，约( )本。",
+        "options":  [
+
+                    ],
+        "answer":  "670或700",
+        "solution":  "【分析】673接近的整十数是670，也就是673约是670;或673接近的整百数是700，也就是673也可以约是700;【详解】由题意分析得：东方小学的图书室有673本书，约670本(或700本)。",
+        "knowledge_points":  [
+                                 "1000以内数的估计"
+                             ],
+        "source":  "24-25二年级下·广东汕头·期末"
+    },
+    {
+        "id":  "323",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "由3,0,5,8组成的最大的四位数是( ),最小的四位数是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "8530;3058",
+        "solution":  "【分析】万以内数比较大小的方法：比较数的大小，先看位数的多少，位数多的数就大;如果位数相同，从最高位开始比较，最高位上的数大则这个数大，最高位上的数相同，就比较下一位，依次类推。将3,0,5,8四个数按照从小到大的顺序进行排序，从最大的数放在千位上依次往后在各个位数上放上数，可以得到最大的四位数。将3放在千位上，剩下的数按照从小到大的顺序依次放在百位，十位，个位上，可以得到最小的四位数。由此即可解答。\n\n【详解】根据分析可得:0<3<5<8，所以，由3,0,5,8组成的最大的四位数是8530，最小的四位数是3058。",
+        "knowledge_points":  [
+                                 "万以内数的组成",
+                                 "万以内数的大小比较"
+                             ],
+        "source":  "24-25 二年级下·广东汕头·期末"
+    },
+    {
+        "id":  "324",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "一个数，它的千位和十位都是6，其余数位上是0，这个数是( ),读作( )。",
+        "options":  [
+
+                    ],
+        "answer":  "6060;六千零六十",
+        "solution":  "【分析】根据题目描述，千位和十位上的数字是6，其余数位均为0。按照整数的写法，从高位到低位依次填写对应数位的数字，空缺的数位用0补足。读一个四位数，从高位往低位读，千位上的数读作几千，百位上的数读作几百，十位上的数读作几十，个位上的数读作几，中间的一个0或连续两个0，都只读一个\"零\"，末尾的0不用读。\n\n【详解】由题意分析：一个数，它的千位上和十位都是6，其余数位上是0，这个数是6060，读作：六千零六十。",
+        "knowledge_points":  [
+                                 "万以内数的读，写法",
+                                 "万以内数的组成"
+                             ],
+        "source":  "24-25 二年级下·广东汕头·期末"
+    },
+    {
+        "id":  "325",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "由8个千,8个百,8个十组成的数是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "8880",
+        "solution":  "【分析】一个四位数，从右往左依次为：个位，十位，百位，千位;写数时，从高位起，几个千就在千位上写几，几个百就在百位上写几，几个十就在十位上写几，几个一就在个位上写几，哪一位一个数字也没有就写\"0\"占位，按照数位顺序写出数字;8个千在千位上写8,8个百在百位上写8,8个十在十位上写8，个位上一个数也没有，写\"0\"占位;据此解答。\n\n【详解】根据分析可得：由8个千,8个百,8个十组成的数是8880。",
+        "knowledge_points":  [
+                                 "万以内数的组成"
+                             ],
+        "source":  "24-25 二年级下·福建漳州·期末"
+    },
+    {
+        "id":  "326",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "3800里有( )个百,10个一百是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "38;1000",
+        "solution":  "【分析】千位上是几就有几个千，百位上是几就有几个百，十位上是几就有几个十，个位上是几就有几个一。几个千就是几千，几个百就是几百，几个十就是几十，几个一就是几。\n\n【详解】3800的千位上是3代表3个千，百位上是8代表8个百,1个千代表10个百，则3个千代表30个百。所以,3800里有38个百,10个一百是1000。",
+        "knowledge_points":  [
+                                 "万以内数的组成"
+                             ],
+        "source":  "24-25 二年级下·广东江门·期末"
+    },
+    {
+        "id":  "327",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "近年来，随着共享单车的普及，\"共享\"成为高频热词。2024年某市投放共享单车7988辆，横线上的数大约是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "8000",
+        "solution":  "【分析】取近似数的方法：四舍五入法：根据要求保留相应的位数，舍去后面的尾数。当尾数的最高位小于5时，直接舍去;当尾数的最高位大于或等于5时，向前一位进1。\n\n【详解】7988需要保留四位数，观察7988的百位数字是9，大于等于5，所以向千位进1。千位的7变为8，其余低位补0，最终得到7988的近似数。所以，横线上的数大约是8000。",
+        "knowledge_points":  [
+                                 "万以内数的估计"
+                             ],
+        "source":  "24-25二年级下·湖北武汉·期末"
+    },
+    {
+        "id":  "328",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "唐古拉山主峰各拉丹冬雪山的海拔为6621米，长江是我国第一大河，干流全长约六千三百千米。\n(1)横线上的数读作( )，左边的“6”表示( )，右边的“6”表示( )。\n(2)波浪线上的数写作( )，百位上是( )，个位上是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "六千六百二十一;6个千;6个百;6300;3;0",
+        "solution":  "【分析】千位上是几就有几个千，百位上是几就有几个百，十位上是几就有几个十，个位上是几就有几个一。几个千就是几千，几个百就是几百，几个十就是几十，几个一就是几。整数的写法：从高位到低位，一级一级地写，哪一个数位上一个单位也没有，就在那个数位上写0。整数的读法：从高位到低位，一级一级地读，每一级末尾的0都不读出来，其余数位连续几个0都只读一个零。\n\n【详解】(1)根据分析可得：横线上的数读作六千六百二十一，左边的“6”表示6个千，右边的“6”表示6个百。\n(2)根据分析可得：波浪线上的数写作6300，百位上是3，个位上是0。",
+        "knowledge_points":  [
+                                 "万以内数的读，写法",
+                                 "万以内数的组成"
+                             ],
+        "source":  "24-25 二年级下·湖北武汉·期末"
+    },
+    {
+        "id":  "329",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "下图中的计算工具叫( )，它是我国古代劳动人民发明创造的一种简便的计算工具。图中表示的数是( )。\n![](images/9566b3380b26834e3a2ef6536d3e286ac59efda6fa68359ae59729965f066bcd.jpg)",
+        "options":  [
+
+                    ],
+        "answer":  "算盘;1526",
+        "solution":  "【分析】根据图可知，该计算工具为算盘。算盘上1颗上珠表示5，1颗下珠表示1，从右往左分别为个位、十位、百位、千位，据此数出算珠的数量。千位上是几就有几个千，百位上有几个百，十位上有几个十，个位上是几就有几个一。几个千就是几千，几个百就是几百，几个十就是几十，几个一就是几，写出表示的这个数即可解答。\n\n【详解】根据分析可得：个位上的上珠有1颗，下珠有1颗，所以个位上是6；十位上的上珠有0颗，下珠有2颗，所以十位上是2；百位上的上珠有1颗，下珠有0颗，所以百位上是5；千位上的上珠有0颗，下珠有1颗，所以千位上是1；则这个数是1526。所以，这个工具叫算盘，图中表示的数是1526。",
+        "knowledge_points":  [
+                                 "算盘的认识与使用",
+                                 "万以内数的组成"
+                             ],
+        "source":  "24-25 二年级下·江西抚州·期末"
+    },
+    {
+        "id":  "330",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "4个千,1个十和4个一组成的数是( ),大约是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "4014;4000",
+        "solution":  "【分析】一个四位数，从右往左依次是个位，十位，百位，千位，千位上是几就表示几个千，百位上是几就表示几个百，十位上是几就表示几个十，个位上是几就表示几个一。找整数近似数的方法：把这个整数看作和它接近的整十，整百或整千数。\n\n【详解】4个千是4000,1个十是10,4个一是4，合起来是4014,4014比较接近4000.4个千,1个十和4个一组成的数是(4014),大约是(4000)。",
+        "knowledge_points":  [
+                                 "万以内数的组成",
+                                 "万以内数的估计"
+                             ],
+        "source":  "24-25 二年级下·内蒙古呼伦贝尔·期末"
+    },
+    {
+        "id":  "331",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "6090读作( ),七千零六写作( )。在9493中，从右边数第二个9在( )位，表示( )。",
+        "options":  [
+
+                    ],
+        "answer":  "六千零九十;7006;千;9个千",
+        "solution":  "【分析】千位上是几就有几个千，百位上是几就有几个百，十位上是几就有几个十，个位上是几就有几个一。几个千就是几千，几个百就是几百，几个十就是几十，几个一就是几。整数的写法：从高位到低位，一级一级地写，哪一个数位上一个单位也没有，就在那个数位上写0。整数的读法：从高位到低位，一级一级地读，每一级末尾的0都不读出来，其余数位连续几个0都只读一个零。\n\n【详解】根据分析可得:6090读作六千零九十，七千零六写作7006。在9493中，从右边数第二个9在千位，表示9个千。",
+        "knowledge_points":  [
+                                 "万以内数的组成",
+                                 "万以内数的读，写法"
+                             ],
+        "source":  "24-25 二年级下·云南昭通·期末"
+    },
+    {
+        "id":  "332",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "100张100元是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "10000元",
+        "solution":  "【分析】100个100是10000，则100张100元是10000元。\n\n【详解】由分析可知:100张100元是10000元。",
+        "knowledge_points":  [
+                                 "十元以上人民币的认识与计算",
+                                 "万以内数的组成"
+                             ],
+        "source":  "24-25 二年级下·云南昭通·期末"
+    },
+    {
+        "id":  "333",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "用“3，8，0，0”组成的四位数中，一个零都不读出来的是( )，组成最小的四位数是( )，组成最大的四位数是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "3800、8300;3008;8300",
+        "solution":  "【分析】根据整数中“零”的读法，每一级末尾的0都不读出来，其余数位连续几个0都只读一个零。要想一个“零”都不读出来，就要把这两个0写在这个数的末尾；要想组成的数最小，要把数按照从小到大的顺序从高位到低位排下来，但是最高位不能是0；要想组成的数最大，要把数按照从大到小的顺序从高位到低位排下来。\n\n【详解】由题意分析得：用“3，8，0，0”组成的四位数中，一个零都不读出来的是3800和8300，组成最小的四位数是3008，组成最大的四位数是8300。",
+        "knowledge_points":  [
+                                 "万以内数的大小比较",
+                                 "万以内数的组成",
+                                 "万以内数的读，写法"
+                             ],
+        "source":  "24-25 二年级下·云南昭通·期末"
+    },
+    {
+        "id":  "334",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "按规律填数。\n(1)1234，1244，1254，( )，( )。\n(2)480，460，440，( )，( )。",
+        "options":  [
+
+                    ],
+        "answer":  "1264;1274;420;400",
+        "solution":  "【分析】(1)相邻的两个数，十位上依次是3，4，5，6，7，其它数位上的数不变。\n(2)相邻的两个数，后一个数比前一个数依次少20，据此解决。\n\n【详解】(1)1234，1244，1254，1264，1274。\n(2)440-20=420，420-20=400，即480，460，440，420，400。",
+        "knowledge_points":  [
+                                 "整数排列的规律"
+                             ],
+        "source":  "24-25 二年级下·黑龙江佳木斯·期末"
+    },
+    {
+        "id":  "335",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "由7个百,8个十和5个一组成的数是( ),这个数再加上( )就是800。",
+        "options":  [
+
+                    ],
+        "answer":  "785;15",
+        "solution":  "【分析】根据百位上是几就有几个百，十位上是几就有几个十，个位上是几就有几个一。几个百就是几百，几个十就是几十，几个一就是几，写出这个数。从这个数开始向后数，一直数到800，数了多少个数，就是需要再加上多少才能到800。\n\n【详解】根据分析可得：由7个百,8个十和5个一组成的数是785.785往后数是786,787,788,789,790,791,792,793,794,795,796,797,798,799,800，一共数了15个数。所以，由7个百,8个十和5个一组成的数是785，这个数再加上15就是800。",
+        "knowledge_points":  [
+                                 "数1000以内的数",
+                                 "1000以内数的组成"
+                             ],
+        "source":  "24-25 二年级下·黑龙江佳木斯·期末"
+    },
+    {
+        "id":  "336",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "实验小学共有2986名学生，大约是( )名，学校图书藏书9986本，大约是( )本。",
+        "options":  [
+
+                    ],
+        "answer":  "3000;10000",
+        "solution":  "【分析】因为2986比较接近整千数是3000，所以学生大约是3000名;9986比较接近整万数10000，所以图书大约是10000本;由此解答即可。\n\n【详解】由分析可知：实验小学共有2986名学生，大约是3000名，学校图书藏书9986本，大约是10000本。",
+        "knowledge_points":  [
+                                 "万以内数的估计"
+                             ],
+        "source":  "24-25 二年级下·湖南长沙·期末"
+    },
+    {
+        "id":  "337",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "7004里面有7个( )和4个( );8000里有( )个百。",
+        "options":  [
+
+                    ],
+        "answer":  "千;一;80",
+        "solution":  "【分析】一个四位数，从右往左依次为个位，十位，百位，千位。千位是几表示几个千，百位是几表示几个百，十位是几表示几个十，个位是几表示几个一;一百一百地数,80个百是8000，据此解答。\n\n【详解】根据分析可得:7004里面有7个千和4个一;8000里有80个百。",
+        "knowledge_points":  [
+                                 "数万以内的数",
+                                 "万以内数的组成"
+                             ],
+        "source":  "24-25 二年级下·湖南长沙·期末"
+    },
+    {
+        "id":  "338",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "育才小学有学生三千零一十八人，横线上的数写作( )。这是一个( )位数，也可以说育才小学大约有学生( )人。",
+        "options":  [
+
+                    ],
+        "answer":  "3018;四;3000",
+        "solution":  "【分析】万以内整数的写法：从高级单位到低位依次写出各位上的数字，哪位上一个单位也没有，就在那位上写0，据此即可写出此数。根据写出的数可知是一个四位数，求大约的人数也就是找到最接近整数的数即可。\n\n【详解】由分析可得：育才小学有学生三千零一十八人，横线上的数写作(3018)。这是一个(四)位数，也可以说育才小学大约有学生(3000)人。",
+        "knowledge_points":  [
+                                 "万以内数的读，写法",
+                                 "万以内数的组成",
+                                 "亿以内数的近似数"
+                             ],
+        "source":  "24-25 二年级下·河北张家口·期末"
+    },
+    {
+        "id":  "339",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "1109读作( ),其中千位上的\"1\"表示( ),百位上的\"1\"表示( ),它们之间相差( )。",
+        "options":  [
+
+                    ],
+        "answer":  "一千一百零九;1个千;1个百;900",
+        "solution":  "【分析】整数的读法：从高位到低位，一级一级地读，每级末尾的0都不读出来，其余数位连续几个0都只读一个零。千位上是几就有几个千，百位上是几就有几个百，十位上是几就有几个十，个位上是几就有几个一。几个千就是几千，几个百就是几百，几个十就是几十，几个一就是几。求相差多少用减法计算即可。\n\n【详解】根据分析可得:1109读作一千一百零九,1109千位上的\"1\"表示1个千，百位上的\"1\"表示1个百。1000-100=900，它们之间相差900。所以,1109读作一千一百零九，其中千位上的\"1\"表示1个千，百位上的\"1\"表示1个百，它们之间相差900。",
+        "knowledge_points":  [
+                                 "万以内数的读，写法",
+                                 "万以内数的组成",
+                                 "整百数",
+                                 "几百几十数的加减法口算"
+                             ],
+        "source":  "24-25 二年级下·河北张家口·期末"
+    },
+    {
+        "id":  "340",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "嫦娥五号归来带回月球土壤约1700克。划线的数字是由( )个千和( )个百组成的，一个一个地数，和它相邻的两个数是( )和( )。",
+        "options":  [
+
+                    ],
+        "answer":  "1;7;1699;1701",
+        "solution":  "【分析】一个整数，从右往左依次为个位、十位、百位、千位。千位是几表示几个千，百位是几表示几个百，十位是几表示几个十，个位是几表示几个一。相邻的两个数中，左边这个数比这个数小1，右边这个数比这个数大1，故和1700相邻的两个数是1699和1701。\n\n【详解】由题意分析得：嫦娥五号归来带回月球土壤约1700克。划线的数字是由1个千和7个百组成的，一个一个地数，和它相邻的两个数是1699和1701。",
+        "knowledge_points":  [
+                                 "数万以内的数",
+                                 "万以内数的组成"
+                             ],
+        "source":  "24-25 二年级下·湖南株洲·期末"
+    },
+    {
+        "id":  "341",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "陕西省建成多个教育服务平台，累计宣传推介全国和省级\"百姓学习之星\"六百二十五名。六百二十五写作( ),它里面有( )个百,( )个十和( )个一。",
+        "options":  [
+
+                    ],
+        "answer":  "625;6;2;5",
+        "solution":  "【分析】根据1000以内整数的写法：从高位到低位依次写出各位上的数字，哪位上一个单位也没有，就在那位上写0，据此即可写出此数。从右边起第一位是个位，个位上是几就表示几个一，第二位是十位，十位上是几就表示几个十，第三位是百位，百位上是几就表示几个百，据此结合题干要求进行解答即可。\n\n【详解】六百二十五写作:625，它里面有6个百,2个十和5个一。",
+        "knowledge_points":  [
+                                 "1000以内数的组成",
+                                 "1000以内数的读，写法"
+                             ],
+        "source":  "24-25 二年级下·陕西渭南·期末"
+    },
+    {
+        "id":  "342",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "用6颗算珠在算盘上表示四位数，其中最大四位数是( ),只读一个0的最小四位数是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "9500;1009",
+        "solution":  "【分析】千位上是几就有几个千，百位上是几就有几个百，十位上是几就有几个十，个位上是几就有几个一。几个千就是几千，几个百就是几百，几个十就是几十，几个一就是几。整数的读法：从高位到低位，一级一级地读，每一级末尾的0都不读出来，其余数位连续几个0都只读一个零。万以内数比较大小的方法：比较数的大小，先看位数的多少，位数多的数就大;如果位数相同，从最高位开始比较，最高位上的数大则这个数大，最高位上的数相同，就比较下一位，依次类推。算盘上1颗上珠代表5,1颗下珠代表1，要组成最大的四位数，则千位上的数要是最大，即千位上1颗上珠,4颗下珠，百位上1颗上珠，十位和个位上0颗算珠，此时得到的四位数最大。要组成只读一个0的最小的四位数，则千位上1颗下珠，百位和十位上0颗算珠，个位上1颗上珠和4颗下珠，此时得到只读一个0的最小四位数。\n\n【详解】根据分析可得：最大的四位数是千位上1颗上珠,4颗下珠，百位上1颗上珠，十位和个位上0颗算珠，这个数的千位上是9，百位上是5，十位和个位上是0，这个数是9500。只读一个0的最小四位数千位上1颗下珠，百位和十位上0颗算珠，个位上5颗下珠，这个数的千位上是1，百位和十位上是0，个位上是9，这个数是1009。所以，用6颗算珠在算盘上表示四位数，其中最大四位数是9500，只读一个0的最小四位数是1009。",
+        "knowledge_points":  [
+                                 "万以内数的大小比较",
+                                 "万以内数的组成",
+                                 "万以内数的读，写法",
+                                 "算盘的认识与使用"
+                             ],
+        "source":  "24-25 二年级下·山东济南·期末"
+    },
+    {
+        "id":  "343",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "用2,0,1,8这四个数字组成的四位数中，最小的数是( ),最接近8000的数是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "1028;8012",
+        "solution":  "【分析】要想组成的数最小，要把数字2,0,1,8按照从小到大的顺序从高位到低位排下来，最高位不能是零;首先比较数字2,0,1,8的大小，然后选择相应的数字进行组合;组成最接近8000的数，让8在千位上，剩下3个数字按从小到大排列即可，据此解答。\n\n【详解】0<1<2<8，组成最小的四位数是:1028;用2,0,1,8这四个数字组成的四位数中，最小的数是1028，最接近8000的数是8012。",
+        "knowledge_points":  [
+                                 "万以内数的组成",
+                                 "万以内数的大小比较"
+                             ],
+        "source":  "24-25二年级下·广东揭阳·期中"
+    },
+    {
+        "id":  "344",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "找规律，填一填。\n(1)2560，2580，( )，( )，( )。\n(2)7300，7200，( )，( )，( )。",
+        "options":  [
+
+                    ],
+        "answer":  "2600;2620;2640;7100;7000;6900",
+        "solution":  "【分析】(1)这组数依次变大，后面的每一个数比前一个数大20，也就是从2560开始，二十二十地正着数；\n(2)这组数依次变小，后面的每一个数比前一个数小100，也就是从7300开始，一百一百地倒着数。\n\n【详解】(1)2560，2580，2600，2620，2640。\n(2)7300，7200，7100，7000，6900。",
+        "knowledge_points":  [
+                                 "数万以内的数",
+                                 "整数排列的规律"
+                             ],
+        "source":  "24-25 二年级下·广东揭阳·期中"
+    },
+    {
+        "id":  "345",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "10个一是( ),10个十是( ),10个一百是( ),一万里面有( )个一千。",
+        "options":  [
+
+                    ],
+        "answer":  "十;一百;一千;10",
+        "solution":  "【分析】根据万以内整数的组成，相邻的计数单位之间的进率是10，据此解答即可。\n\n【详解】10个一是十,10个十是一百,10个一百是一千，一万里面有10个一千。",
+        "knowledge_points":  [
+                                 "万以内数的组成"
+                             ],
+        "source":  "24-25 二年级下·广东揭阳·期中"
+    },
+    {
+        "id":  "346",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "2306是由2个( ),3个( )和6个( )组成的。",
+        "options":  [
+
+                    ],
+        "answer":  "千;百;一",
+        "solution":  "【分析】一个四位数，从右往左依次为个位，十位，百位，千位;千位是几表示几个千，百位是几表示几个百，十位是几表示几个十，个位是几表示几个一。2306千位上是2，百位上是3，个位上是6;据此可解。\n\n【详解】由分析可得:2306是由2个千,3个百和6个一组成的。",
+        "knowledge_points":  [
+                                 "万以内数的组成"
+                             ],
+        "source":  "24-25 二年级下·广东揭阳·期中"
+    },
+    {
+        "id":  "347",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "五台山是中华十大名山之一。占地面积二千八百三十七平方公里，其最高点北台叶斗峰海拔3061米，被称为“华北屋脊”。横线上的数写作( )。波浪线上的数读作( )。3061里有( )个千，( )个十和( )个一。",
+        "options":  [
+
+                    ],
+        "answer":  "2837;三千零六十一;3;6;1",
+        "solution":  "【分析】千位上是几就有几个千，百位上有几个百，十位上是几就有几个十，个位上是几就有几个一。几个千就是几千，几个百就是几百，几个十就是几十，几个一就是几。整数的写法：从高位到低位，一级一级地写，哪一个数位上一个单位也没有，就在那个数位上写0。整数的读法：从高位到低位，一级一级地读，每一级末尾的0都不读出来，其余数位连续几个0都只读一个零。\n\n【详解】根据分析可得：横线上的数写作2837。波浪线上的数读作三千零六十一。3061里有3个千，6个十和1个一。",
+        "knowledge_points":  [
+                                 "万以内数的读，写法",
+                                 "万以内数的组成"
+                             ],
+        "source":  "24-25 二年级下·陕西延安·期末"
+    },
+    {
+        "id":  "348",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "552>5□3,□里最大能填( );1029<1□19,□里最小能填( )。",
+        "options":  [
+
+                    ],
+        "answer":  "4;1",
+        "solution":  "【分析】552和5□3的百位数相等，且552的个位数小于5□3的个位数;故要使552>5□3,□最大能填的数，只要比552十位上的5小1即可;□里最大能填4;1029和1□19的千位，个位数相等，且1029的十位数大于1□19的十位数，故要使1029<1□19,□最小能填的数，就是比1029百位上的0大1的数即可,□里最小能填1。\n\n【详解】根据分析:552>5□3,□里最大能填4;1029<1□19,□里最小能填1。",
+        "knowledge_points":  [
+                                 "万以内数的大小比较"
+                             ],
+        "source":  "24-25 二年级下·广东云浮·期中"
+    },
+    {
+        "id":  "349",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "梵净山位于贵州省铜仁市江口、印江、松桃三县交界处，是武陵山脉主峰，最高峰凤凰山海拔2572米，读作：( )，它是由( )个千，5个百，( )个十和( )个一组成的。",
+        "options":  [
+
+                    ],
+        "answer":  "二千五百七十二;2;7;2",
+        "solution":  "【分析】一个四位数，从右往左依次为个位、十位、百位、千位；千位是几表示几个千，百位是几表示几个百，十位是几表示几个十，个位上是几就有几个一；读数时，从高位读起，按照数位顺序读。千位是几就读几千，百位上是几就读几百，十位上是几就读几十，个位上是几就读几，中间有一个0或两个0，只读一个零；末尾不管有几个0，都不读。\n\n【详解】由分析可得：梵净山位于贵州省铜仁市江口、印江、松桃三县交界处，是武陵山脉主峰，最高峰凤凰山海拔2572米，读作：二千五百七十二，它是由2个千，5个百，7个十和2个一组成的。",
+        "knowledge_points":  [
+                                 "万以内数的读，写法",
+                                 "万以内数的组成"
+                             ],
+        "source":  "24-25 二年级下·贵州铜仁·期末"
+    },
+    {
+        "id":  "350",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "用0,1,7,9这4个数字组成最小的四位数是( ),最大的四位数是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "1079;9710",
+        "solution":  "【分析】要想组成的数最小，要把数按照从小到大的顺序从高位到低位排下来，但是最高位不能是零;要想组成的数最大，要把数按照从大到小的顺序从高位到低位排下来;据此写出这两个数。\n\n【详解】用0,1,7,9这4个数字组成最小的四位数是1079，最大的四位数是9710。",
+        "knowledge_points":  [
+                                 "万以内数的组成",
+                                 "万以内数的大小比较"
+                             ],
+        "source":  "24-25 二年级下·广东汕尾·期末"
+    },
+    {
+        "id":  "351",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "《孔雀东南飞》是一首长篇叙事诗，总计1785字，是中国汉代乐府民歌中的高峰之作。1785读作( ),1785最接近的整千数是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "一千七百八十五;2000",
+        "solution":  "【分析】根据万以内整数的读法：千位上是几就读几千，百位上是几就读几百，十位上是几就读几十，个位上是几就读几，末尾的0都不读出来，其余数位连续几个0都只读一个零，即可读出此数。根据整数估算的方法，把整数估算成与它相近的整千的数,1785与2000比较接近，所以1785最接近的整千数是2000。据此解答即可。\n\n【详解】1785读作：一千七百八十五,1785最接近的整千数是2000。",
+        "knowledge_points":  [
+                                 "万以内数的读，写法",
+                                 "万以内数的估计"
+                             ],
+        "source":  "24-25 二年级下·陕西渭南·期末"
+    },
+    {
+        "id":  "352",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "找规律，填一填。\n5266，5166，( )，( )，4866。",
+        "options":  [
+
+                    ],
+        "answer":  "5066;4966",
+        "solution":  "【分析】观察已知数据可知，后一个数比前一个数少100，也就是从5266开始，一百一百地倒着数，依次填写5066、4966。\n\n【详解】5266，5166，5066，4966，4866。",
+        "knowledge_points":  [
+                                 "数万以内的数",
+                                 "整数排列的规律"
+                             ],
+        "source":  "24-25 二年级下·重庆梁平·期末"
+    },
+    {
+        "id":  "353",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "用7,0,9,8四个数字组成的四位数中，最小的数是( ),最接近8000的数是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "7089;7980",
+        "solution":  "【分析】由题意可知：把7,0,9,8这四个数字从小到大排列,0不能放到最高位上，和排第二的数字交换位置，即可组成最小四位数;最接近8000的数，要么8000多，要么7000多;8000多：千位数字是8，其它数字按从小到大的顺序排列，组成的数更接近8000;7000多：千位数字是7，其它数字按从大到小的顺序排列，组成的数更接近8000;两个组成的数字分别都和8000对比，相差最小的那个数，即是最接近8000的数;据此解答。\n\n【详解】由分析可得：组成最小的数是7089;最接近8000的数:8000多:8079;7000多:7980;8079和8000相差79;7980和8000相差20;20<79，故7980最接近8000;用7,0,9,8四个数字组成的四位数中，最小的数是7089，最接近8000的数是7980。",
+        "knowledge_points":  [
+                                 "万以内数的组成",
+                                 "万以内数的大小比较"
+                             ],
+        "source":  "24-25 二年级下·重庆梁平·期末"
+    },
+    {
+        "id":  "354",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "在括号里填上“>”“<”或“=”。\n4089( )4092\n39个百( )3个千\n95-(18+12)( )95-18-12\n63÷7÷3( )63÷7×3",
+        "options":  [
+
+                    ],
+        "answer":  "<;>;=;<",
+        "solution":  "【分析】比较数的大小方法：①位数多的数大于位数少的数；②位数相同的，先比较最高位上的数，最高位上大的，数就大，最高位数相同的，就比较下一位，以此类推。在没有括号的算式里，如果只有加减法或者只有乘除法，要从左往右依次计算。在没有括号的算式里，如果既有乘除法又有加减法，要先算乘除法，再算加减法。在有括号的算式里，要先算括号里面的，再算括号外面的。据此解答。\n\n【详解】由分析可得：4089与4092比较，四位数比较，从高位到低位逐位比较，十位数字8<9，故4089<4092；39个百与3个千比较，39个百=3900，3个千=3000，3900>3000，故39个百>3个千；95-(18+12)与95-18-12比较，95-(18+12)=95-30=65，95-18-12=77-12=65，65=65，故95-(18+12)=95-18-12；63÷7÷3与63÷7×3比较，63÷7÷3=9÷3=3，63÷7×3=9×3=27，3<27，故63÷7÷3<63÷7×3。",
+        "knowledge_points":  [
+                                 "万以内数的组成",
+                                 "万以内数的大小比较",
+                                 "表内乘除混合运算",
+                                 "带有小括号的混合运算"
+                             ],
+        "source":  "24-25 二年级下·重庆梁平·期末"
+    },
+    {
+        "id":  "355",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "一个数的千位和个位上都是6，其余各数位上都是0，这个数写作( ),读作( )。",
+        "options":  [
+
+                    ],
+        "answer":  "6006;六千零六",
+        "solution":  "【分析】万以内数的写法：写数时，从高位写起，按照数位顺序写;几千就在千位写几，几百就在百位写几。中间或末尾哪一位上一个也没有，就在那一位上写0。万以内数的读法：读数时，从高位读起，按照数位顺序读。千位是几就读几千，百位是几就读几百。中间有一个0或两个0，只读一个零;末尾不管有几个0，都不读。一个整数，从右往左依次为个位，十位，百位，千位。千位是6，百位是0，十位是0，个位是6，据此写数，再读数即可。\n\n【详解】一个数的千位和个位上都是6，其余各数位上都是0，这个数写作6006，读作六千零六。",
+        "knowledge_points":  [
+                                 "万以内数的读，写法",
+                                 "万以内数的组成"
+                             ],
+        "source":  "24-25 二年级下·重庆梁平·期末"
+    },
+    {
+        "id":  "356",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "在408，374，764，117，821这些数中，选择合适的数填在( )里。\n(1)在400和800之间的数有( )。\n(2)比800多一些的数是( )，比800少一些的数是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "408、764;821;764",
+        "solution":  "【分析】根据数的相对大小可知：比较两个数的多少时，如果两个数的大小比较接近，可以说两者差不多，也可以说大数比小数多一些，或者小数比大数少一些；如果两个数的大小相差很多，就说大数比小数多得多，或者说小数比大数少得多。\n(1)在400和800之间的数：比400大，比800小，找出既比400大，又比800小的数即可。\n(2)找出比800大，但相差不多的数，即是比800多一些的数；找出比800少，但相差不多的数，即是比800少一些的数，据此解答。\n\n【详解】(1)由分析可得：408，764都在400和800之间。\n(2)821比800大，而且相差不大，符合题意；408，374，764，117这四个数都比800小，但只有764和800相差不多，故764符合题意。比800多一些的数是821，比800少一些的数是764。",
+        "knowledge_points":  [
+                                 "数的相对大小关系",
+                                 "1000以内数的比大小"
+                             ],
+        "source":  "24-25 二年级下·河北唐山·期末"
+    },
+    {
+        "id":  "357",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "7895是由( )个千,( )个百,( )个十和( )个一组成，再添上( )个一就是7900了。",
+        "options":  [
+
+                    ],
+        "answer":  "7;8;9;5;5",
+        "solution":  "【分析】一个四位数，从右往左依次为个位，十位，百位，千位。千位是几就有几个千，百位是几就有几个百，十位是几就有几个十，个位是几就有几个一。7895后边的第几个数是7900，也就是再添上几个一。\n\n【详解】7895后边的第一个数是7896，第二个数是7897，第三个数是7898，第四个数是7899，第五个数是7900。填空如下:7895是由(7)个千,(8)个百,(9)个十和(5)个一组成，再添上(5)个一就是7900了。",
+        "knowledge_points":  [
+                                 "数万以内的数",
+                                 "万以内数的组成"
+                             ],
+        "source":  "24-25 二年级下·天津河西·期末"
+    },
+    {
+        "id":  "358",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "一台洗衣机售价为2098元，约( )元。",
+        "options":  [
+
+                    ],
+        "answer":  "2100",
+        "solution":  "【分析】一台洗衣机售价为2098元，2098接近2100，所以2098元大约是2100元。\n\n【详解】据分析可知：2098元大约是2100元。",
+        "knowledge_points":  [
+                                 "万以内数的估计"
+                             ],
+        "source":  "24-25 二年级下·广东佛山·期末"
+    },
+    {
+        "id":  "359",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "在括号里填上“>”“<”或“=”。\n1771( )1177\n4510( )4051\n12÷2( )6\n56÷8( )8",
+        "options":  [
+
+                    ],
+        "answer":  ">;>;=;<",
+        "solution":  "【分析】比较大小方法：①位数多的数大于位数少的数；②位数相同的，先比较最高位上的数，最高位上大的，数就大，最高位数相同的，就比较下一位，以此类推。有算式的先计算出算式得数，再比较大小，据此解答。\n\n【详解】由分析可得：1771( )1177，千位数字相等，百位数字7>1，故1771>1177；4510( )4051，千位数字相等，百位数字5>0，故4510>4051；12÷2( )6，12÷2=6，故12÷2=6；56÷8( )8，56÷8=7，7<8，故56÷8<8。",
+        "knowledge_points":  [
+                                 "万以内数的大小比较",
+                                 "用6的乘法口诀求商",
+                                 "用7~9的乘法口诀求商"
+                             ],
+        "source":  "24-25二年级下·甘肃庆阳·期末"
+    },
+    {
+        "id":  "360",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "钓鱼岛及其附属岛屿都是中国的固有领土。钓鱼岛长约三千六百四十一米，宽约1905米。横线上的数写作( )，波浪线上的数读作( )。",
+        "options":  [
+
+                    ],
+        "answer":  "3641;一千九百零五",
+        "solution":  "【分析】一个四位数，从右往左依次是个位、十位、百位、千位。写数时，从高位写起，有几个千就在千位写几，有几个百就在百位写几，有几个十就在十位写几，有几个一就在个位写几，哪一位上一个单位也没有，就在那一位上写0；读数时，从高位读起，千位上是几就读几千，百位上是几就读几百，十位上是几就读几十，个位上是几就读几，中间有一个0或者两个0，只读一个“零”，末尾不管有几个0都不读，由此解答。\n\n【详解】三千六百四十一写作3641，1905读作一千九百零五。所以横线上的数写作3641，波浪线上的数读作一千九百零五。",
+        "knowledge_points":  [
+                                 "万以内数的读，写法"
+                             ],
+        "source":  "24-25 二年级下·甘肃庆阳·期末"
+    },
+    {
+        "id":  "361",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "某镇有9998人，约1000人。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】9998这个四位数的千位，百位和十位上都是9，个位上是8，与10000只相差2，所以9998人大约是10000人，据此解答。\n\n【详解】由分析可得：某镇有9998人，约10000人，不是约1000人。原题说法错误。故答案为: ×",
+        "knowledge_points":  [
+                                 "万以内数的估计"
+                             ],
+        "source":  "24-25 二年级下·广东潮州·期末"
+    },
+    {
+        "id":  "362",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "5794>5□93,□里最大能填7。( )",
+        "options":  [
+
+                    ],
+        "answer":  "√",
+        "solution":  "【分析】比较数的大小时，位数多的数就大，位数相同比较最高位，最高位大的数就大，最高位相同就比较下一位，直到比出大小为止。\n\n【详解】由分析可得：两个数都是四位数，且千位，十位的数字相同，左边数的个位>右边数的个位，要让左边的数>右边的数，左边数的百位要大于或者等于右边数的百位，所以□里最大能填7.5794>5□93,□里最大能填7，原题说法正确。故答案为:√",
+        "knowledge_points":  [
+                                 "万以内数的大小比较"
+                             ],
+        "source":  "24-25 二年级下·广东潮州·期末"
+    },
+    {
+        "id":  "363",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "判断题",
+        "difficulty":  0.65,
+        "question":  "两个三位数相减，差不可能是三位数。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】两个三位数相减，可以是两个整百数进行相减，得到的差也是整百数，是三位数。如500-400=100，就是一个三位数减去另一个三位数，差为三位数。\n\n【详解】根据分析可得：两个三位数相减，差可能是三位数。原说法错误。故答案为: ×",
+        "knowledge_points":  [
+                                 "整百数",
+                                 "几百几十数的加减法口算"
+                             ],
+        "source":  "24-25 二年级下·广东揭阳·期末"
+    },
+    {
+        "id":  "364",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "由7个千,4个百,2个十和9个一组成的数是7492。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】写数时，几个千就在千位上写几，几个百就在百位上写几，几个十就在十位上写几，几个一就在个位上写几，哪位上一个也没有，就写0占位。故，由7个千,4个百,2个十和9个一组成的数应为7429。\n\n【详解】由分析可知：由7个千,4个百,2个十和9个一组成的数应为7429，而非7492。故答案为: ×",
+        "knowledge_points":  [
+                                 "万以内数的组成"
+                             ],
+        "source":  "24-25二年级下·贵州黔东南·期末"
+    },
+    {
+        "id":  "365",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "判断题",
+        "difficulty":  0.65,
+        "question":  "最小的四位数比最大的三位数大1。( )",
+        "options":  [
+
+                    ],
+        "answer":  "√",
+        "solution":  "【分析】最小的四位数是1000，最大的三位数是999，计算两者的差即可判断。\n\n【详解】1000-999=1，最小的四位数比最大的三位数大1。原题说法正确。故答案为:√",
+        "knowledge_points":  [
+                                 "1000以内数的比大小"
+                             ],
+        "source":  "24-25 二年级下·贵州黔东南·期末"
+    },
+    {
+        "id":  "366",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "计算1500-600就是用15个百减6个百等于9个百，也就是900。( )",
+        "options":  [
+
+                    ],
+        "answer":  "√",
+        "solution":  "【分析】题目中将1500和600分别看作15个百和6个百，通过整百数的减法计算得出结果。\n\n【详解】1500是由15个百组成,600是由6个百组成。计算时，用15个百减去6个百，得到9个百，即:15个百-6个百=9个百，因为1个百等于100，所以9个百为9百，即900。原题的说法正确。故答案为:√",
+        "knowledge_points":  [
+                                 "整百数",
+                                 "几百几十数的加减法口算"
+                             ],
+        "source":  "24-25 二年级下·甘肃兰州·期末"
+    },
+    {
+        "id":  "367",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "由4个百和4个一组成的数是404。( )",
+        "options":  [
+
+                    ],
+        "answer":  "√",
+        "solution":  "【分析】根据百位上是几就有几个百，十位上是几就有几个十，个位上是几就有几个一。几个百就是几百，几个十就是几十，几个一就是几。由4个百组成的数是400，由4个一组成的数是4，进行判断即可。\n\n【详解】根据分析可得：由4个百和4个一组成的数是404，原说法正确。故答案为:√",
+        "knowledge_points":  [
+                                 "1000以内数的组成"
+                             ],
+        "source":  "24-25 二年级下·广东汕头·期末"
+    },
+    {
+        "id":  "368",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "三位数一定比四位数大。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】比较数的大小时，数位多的数一定大于数位少的数。四位数有四个数位，三位数有三个数位，因此四位数一定比三位数大。\n\n【详解】根据数的组成规则，四位数的最小值为1000，三位数的最大值为999。显然1000>999，因此三位数不可能比四位数大。原题说法错误。故答案为: ×",
+        "knowledge_points":  [
+                                 "万以内数的大小比较"
+                             ],
+        "source":  "24-25 二年级下·广东汕头·期末"
+    },
+    {
+        "id":  "369",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "某村庄有1999人，约2000人。( )",
+        "options":  [
+
+                    ],
+        "answer":  "√",
+        "solution":  "【分析】1999的千位是1，百位，十位和个位都是9，且与2000只相差1，故1999最接近2000，即约2000。据此解决。\n\n【详解】由分析可知：某村庄有1999人，约2000人。此说法正确。故答案为:√",
+        "knowledge_points":  [
+                                 "万以内数的估计"
+                             ],
+        "source":  "24-25 二年级下·陕西延安·期末"
+    },
+    {
+        "id":  "370",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "从990数起，十个十个地数，数到第五个数是1050。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】十个十个地数，即每次增加10。从990开始，依次加10，计算第五个数是否为1050。\n\n【详解】从990开始，十个十个地数：第1个数:990;第2个数:990+10=1000;第3个数:1000+10=1010;第4个数:1010+10=1020;第5个数:1020+10=1030。因此，第五个数是1030，而非1050。题目说法错误。故答案为: ×",
+        "knowledge_points":  [
+                                 "数万以内的数"
+                             ],
+        "source":  "24-25二年级下·陕西延安·期末"
+    },
+    {
+        "id":  "371",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "3个千和5个一组成的数是305。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】一个四位数，从右往左依次为个位，十位，百位，千位，千位是几表示几个千，百位是几表示几个百，十位是几表示几个十，个位是几表示几个一，哪一位上一个单位也没有就写\"0\"占位，据此解答。\n\n【详解】3个千，表示千位是3,5个一，表示个位是5，其余数位用0占位，组成的数是3005，原题说法错误。故答案为: ×",
+        "knowledge_points":  [
+                                 "万以内数的组成",
+                                 "万以内数的读，写法"
+                             ],
+        "source":  "24-25 二年级下·云南红河·期末"
+    },
+    {
+        "id":  "372",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "与4990相邻的是4980和5000。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】相邻的两个数是指一个数前面和后面紧接着的整数，即比它小1和大1的数。根据这一定义，与4990相邻的两个数应为4990-1和4990+1。\n\n【详解】4990-1=4989,4990+1=4991。题目中给出的4980和5000与4990相差10，不符合相邻数的定义，因此判断错误。故答案为: ×",
+        "knowledge_points":  [
+                                 "相邻的数"
+                             ],
+        "source":  "24-25 二年级下·甘肃天水·期末"
+    },
+    {
+        "id":  "373",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "8404这个数中的两个\"4\"表示的意义一样。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】根据分析可得:8404这个数中的两个\"4\"表示的意义不一样。故答案为: ×\n\n【详解】8404这个数中，左边的\"4\"位于百位，表示4个百(即400),右边的\"4\"位于个位，表示4个一(即4)。由于两个\"4\"所在的数位不同，表示的意义也不相同。",
+        "knowledge_points":  [
+                                 "万以内数的组成"
+                             ],
+        "source":  "24-25 二年级下·甘肃天水·期末"
+    },
+    {
+        "id":  "374",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "十个十个地数,380后面第四个数是420。( )",
+        "options":  [
+
+                    ],
+        "answer":  "√",
+        "solution":  "【分析】十个十个地数，即每次增加10。从380开始，依次多10，数一数第四个数是否为420。\n\n【详解】十个十个地数,380后面的数依次为:390,400,410,420。因此,380后面第四个数是420，原题说法正确。故答案为:√",
+        "knowledge_points":  [
+                                 "数万以内的数"
+                             ],
+        "source":  "24-25 二年级下·山东济宁·期末"
+    },
+    {
+        "id":  "375",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "3360>3□50,□里可填的数字只有1和2。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】比较两个四位数的大小，千位相同，比较百位。当右边数的百位数字小于或等于3时，右边数可能小于3360。进一步分析十位和个位，确定□的取值范围。\n\n【详解】左边数为3360，右边数为3□50。千位均为3，比较百位：若□<3，则3□50的百位小于3，此时右边数一定小于3360,□可填0,1,2。若□=3，右边数为3350，比较十位：左边十位为6，右边十位为5,3350<3360，因此□可填3。综上,□可填0,1,2,3。题目中\"只有1和2\"说法错误。故答案为: ×",
+        "knowledge_points":  [
+                                 "万以内数的大小比较"
+                             ],
+        "source":  "24-25 二年级下·甘肃天水·期末"
+    },
+    {
+        "id":  "376",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "5358中两个5表示的意思一样。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】一个四位数，从右往左依次是个位，十位，百位，千位，千位上的数是几表示几个千，百位上的数是几表示几个百，十位上的数是几表示几个十，个位上的数是几表示几个一。\n\n【详解】5358中的左起第一个5在千位上，表示5个千;第二个5在十位上，表示5个十;两个5表示的意思不一样，原题说法错误。故答案为: ×",
+        "knowledge_points":  [
+                                 "万以内数的组成"
+                             ],
+        "source":  "24-25 二年级下·贵州铜仁·期末"
+    },
+    {
+        "id":  "377",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "一个有两个0的四位数，只读一个0。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】读数时，从高位读起，按照数位顺序读。千位是几就读几千，百位是几就读几百，十位上是几就读几十，个位上是几就读几，中间有一个0或两个0，只读一个零;末尾不管有几个0，都不读。如果两个0分别在中间的百位和十位上，只读一个0;如果两个0一个在百位，一个在个位，百位的0要读，个位的0不读，只读一个0;如果两个0分别在十位和个位上，末尾的0都不读，一个0都不读;据此可判断。\n\n【详解】由分析可得：一个有两个0的四位数，有时候只读一个0，有时候一个0也不读。故答案为: ×",
+        "knowledge_points":  [
+                                 "万以内数的读，写法"
+                             ],
+        "source":  "24-25二年级下·贵州铜仁·期末"
+    },
+    {
+        "id":  "378",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "一个四位数，从左数，第四位是千位。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】一个四位数，从右往左数第一位是个位，第二位是十位，第三位是百位，第四位是千位。由此解答。\n\n【详解】由分析举例如下:1234中，从右数，第四位\"1\"在千位;从左数，第四位\"4\"在个位，原题说法错误。故答案为: ×",
+        "knowledge_points":  [
+                                 "万以内数的组成",
+                                 "整数的数级",
+                                 "数位和计数单位的认识"
+                             ],
+        "source":  "24-25 二年级下·湖北黄冈·期末"
+    },
+    {
+        "id":  "379",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "在1050,7500,4003,2609中，只读一个零的数有3个。( )",
+        "options":  [
+
+                    ],
+        "answer":  "√",
+        "solution":  "【分析】一个四位数，从右往左依次是个位，十位，百位，千位，读数时，从高位读起，千位上是几就读几千，百位上是几就读几百，十位上是几就读几十，个位上是几就读几，中间有一个0或者两个0，只读一个\"零\"，末尾不管有几个0都不读;由此解答。\n\n【详解】由分析可得:1050读作：一千零五十，只读一个零;7500读作：七千五百，没有读零;4003读作：四千零三，只读一个零;2609读作：二千六百零九，只读一个零;在1050,7500,4003,2609中，只读一个零的数有3个，原题说法正确。故答案为:√",
+        "knowledge_points":  [
+                                 "万以内数的读，写法"
+                             ],
+        "source":  "24-25 二年级下·广东揭阳·期末"
+    },
+    {
+        "id":  "380",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "和8100相邻的两个数是8000和8200。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】由题意可知：和8100相邻的两个数分别是8100前面比它小1的数，和8100后面比它大1的数;据此解答。\n\n【详解】由分析可得：与8100相邻的两个数分别是8099和8101。故答案为: ×",
+        "knowledge_points":  [
+                                 "相邻的数",
+                                 "数万以内的数"
+                             ],
+        "source":  "24-25 二年级下·广东揭阳·期中"
+    },
+    {
+        "id":  "381",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "5480>5□60,□里有4种填法。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】比较两个四位数的大小，千位相同，比较百位。若左边百位4大于右边百位□,则5480>5□60;若百位相等，则比较十位，左边十位8大于右边十位6，此时仍满足不等式。因此□可填0,1,2,3,4，共5种填法。故答案为: ×\n\n【详解】1。千位均为5，比较百位：左边4，右边□。2。若4>□,则□可填0,1,2,3(4种)。3。若4=□,此时比较十位：左边8>右边6，故□=4仍满足条件。4。综上,□可填0,1,2,3,4，共5种填法。",
+        "knowledge_points":  [
+                                 "万以内数的组成",
+                                 "万以内数的大小比较"
+                             ],
+        "source":  "24-25 二年级下·内蒙古赤峰·期末"
+    },
+    {
+        "id":  "382",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "用4,0,0,5这四个数字能组成6个不同的四位数，其中一个零也不读的有4个，只读一个零的是2个。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】根据四位数的组成规则，首位不能为0，且读数时，从高位读起，千位是几就读几千，百位是几就读几百，十位是几就读几十，个位是几就读几，中间有一个0或两个0，只读一个\"零\"，末尾不管有几个0，都不读。\n\n【详解】组成四位数：首位为4时，剩余数字0,0,5可组成4005,4050,4500;首位为5时，剩余数字0,0,4可组成5004,5040,5400。共6个不同的四位数。读数分析：一个零也不读：末尾的0不读，符合条件的数为4500(读作：四千五百),5400(读作：五千四百),共2个。只读一个零：中间有1个或连续2个0需读一个零，符合条件的数为4005(读作：四千零五),4050(读作：四千零五十),5004(读作：五千零四),5040(读作：五千零四十),共4个。因此，用4,0,0,5这四个数字能组成6个不同的四位数，其中一个零也不读的有2个，只读一个零的是4个。原题说法错误。故答案为: ×",
+        "knowledge_points":  [
+                                 "万以内数的组成",
+                                 "万以内数的读，写法"
+                             ],
+        "source":  "24-25 二年级下·内蒙古赤峰·期末"
+    },
+    {
+        "id":  "383",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "903里的9和4982里的9表示的大小相等。( )",
+        "options":  [
+
+                    ],
+        "answer":  "√",
+        "solution":  "【分析】比较两个数字中\"9\"所在的数位及其表示的数值大小。\n\n【详解】在数字903中,9位于百位，表示9个百，即900;在数字4982中,9位于百位，表示9个百，即900。两者均表示900，因此大小相等。原题说法正确。故答案为:√",
+        "knowledge_points":  [
+                                 "1000以内数的组成",
+                                 "1000以内数的比大小",
+                                 "万以内数的组成"
+                             ],
+        "source":  "24-25 二年级下·内蒙古赤峰·期末"
+    },
+    {
+        "id":  "384",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "7502=7000+500+20。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】根据数的组成,7502的千位是7，表示7000，百位是5，表示500，十位是0，个位是2，表示2。题目中将个位上的2错误地分解为20，导致等式不成立。\n\n【详解】7502的正确分解应为:7502=7000+500+2，而题目中给出的分解为:7502=7000+500+20，因此原题等式错误。故答案为: ×",
+        "knowledge_points":  [
+                                 "万以内数的组成"
+                             ],
+        "source":  "24-25二年级下·陕西延安·期末"
+    },
+    {
+        "id":  "385",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "判断题",
+        "difficulty":  0.94,
+        "question":  "算盘是我国古代发明的计算工具。( )",
+        "options":  [
+
+                    ],
+        "answer":  "√",
+        "solution":  "【分析】算盘的发明与古代中国密切相关，且在多个朝代的文献中均有记载。例如，元代王祯的《农书》中明确描述了算盘的构造及使用方法，进一步印证了其古代发明的属性。\n\n【详解】由分析可知：题干中\"我国古代发明的计算工具\"这一描述是正确的。故答案为:√",
+        "knowledge_points":  [
+                                 "算盘的认识与使用"
+                             ],
+        "source":  "24-25 二年级下·浙江台州·期末"
+    },
+    {
+        "id":  "386",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "读8008时要读两个零。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】根据整数的读法：从高位到低位，一级一级地读，每一级末尾的0都不读出来，其余数位连续几个0都只读一个零，进行解答即可。\n\n【详解】8008读作：八千零八，只读一个零，原说法错误。故答案为: ×",
+        "knowledge_points":  [
+                                 "万以内数的读，写法"
+                             ],
+        "source":  "24-25 二年级下·浙江台州·期末"
+    },
+    {
+        "id":  "387",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "6999接近的整千数是6000。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】判断一个数接近的整千数，需看该数千位后的数值。6999的千位上是6，百位，十位和个位上都是9，且与7000只相差1，所以6999接近的整千数是7000;据此解决。\n\n【详解】由分析的可得:6999接近的整千数是7000，而非6000。因此原题说法错误。故答案为: ×",
+        "knowledge_points":  [
+                                 "万以内数的估计"
+                             ],
+        "source":  "24-25二年级下·云南昭通·期末"
+    },
+    {
+        "id":  "388",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "3003读作三千零零三。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】读一个四位数，从高位往低位读，千位上的数读作几千，百位上的数读作几百，十位上的数读作几十，个位上的数读作几，中间的一个0或连续两个0，都只读一个\"零\"，末尾的0不用读。\n\n【详解】3003读作\"三千零三\"，题目中读作\"三千零零三\"，多读了一个零，故读法错误。故答案为: ×",
+        "knowledge_points":  [
+                                 "万以内数的读，写法"
+                             ],
+        "source":  "24-25 二年级下·云南昭通·期末"
+    },
+    {
+        "id":  "389",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "一个沙发的售价是9996元，约是10000元。( )",
+        "options":  [
+
+                    ],
+        "answer":  "√",
+        "solution":  "【分析】9996的千位，百位和十位上都是9，个位上是6，且与10000只相差4，所以9996接近的数是10000，故9996约是10000，据此解决。\n\n【详解】由分析可知：一个沙发的售价是9996元，约是10000元，此说法正确。故答案为:√",
+        "knowledge_points":  [
+                                 "万以内数的估计"
+                             ],
+        "source":  "24-25 二年级下·广西玉林·期末"
+    },
+    {
+        "id":  "390",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "7080读作七千八十。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】读一个四位数，从高位往低位读，千位上的数读作几千，百位上的数读作几百，十位上的数读作几十，个位上的数读作几，中间的一个0或连续两个0，都只读一个\"零\"，末尾的0不用读。据此解决。\n\n【详解】7080的千位是7，百位是0，十位是8，个位是0。正确读法应为\"七千零八十\"。题目中\"七千八十\"省略了中间的\"零\"，因此错误。故答案为: ×",
+        "knowledge_points":  [
+                                 "万以内数的读，写法"
+                             ],
+        "source":  "24-25 二年级下·广西玉林·期末"
+    },
+    {
+        "id":  "391",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "5个千和6个一组成的数是506。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】判断由5个千和6个一组成的数是否为506，需根据数位组成规则分析：千位上的数字表示几个千，个位上的数字表示几个一，中间未提及的数位用0补足。\n\n【详解】5个千对应千位上的数字5，表示5000;6个一对应个位上的数字6，表示6。百位和十位没有计数单位，因此用0占位。组合后的数5006，而非506。故原题说法错误。故答案为: ×",
+        "knowledge_points":  [
+                                 "万以内数的组成"
+                             ],
+        "source":  "24-25 二年级下·广西玉林·期末"
+    },
+    {
+        "id":  "392",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "3090读作：三千九十。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】整数的读法：从高位到低位，一级一级地读，每级末尾的0都不读出来，其余数位连续几个0都只读一个零。\n\n【详解】3090读作三千零九十，原说法错误。故答案为: ×",
+        "knowledge_points":  [
+                                 "万以内数的读，写法"
+                             ],
+        "source":  "24-25二年级下·黑龙江佳木斯·期末"
+    },
+    {
+        "id":  "393",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "1400里有14个千。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】一百一百地数,1个百是100,2个百是200,3个百是300。,14个百是1400，据此解答。\n\n【详解】14个百是1400，即1400里面有14个百。原题说法错误。故答案为: ×",
+        "knowledge_points":  [
+                                 "万以内数的组成"
+                             ],
+        "source":  "24-25 二年级下·内蒙古呼伦贝尔·期末"
+    },
+    {
+        "id":  "394",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "(1)一台电视机比一台冰箱贵多少钱。\n(2)买一台洗衣机和一台冰箱一共需要多少钱。\n![](images/4166949aebed8045a41fb5511843a861.png)",
+        "options":  [
+
+                    ],
+        "answer":  "500元;7800元",
+        "solution":  "【分析】(1)一台电视机比一台冰箱贵的钱=一台电视机的钱-一台冰箱的钱；\n(2)买一台洗衣机和一台冰箱一共需要的钱=一台洗衣机的钱+一台冰箱的钱，据此解决。\n\n【详解】(1)5500-5000=500(元)，答：一台电视机比一台冰箱贵500元。\n(2)2800+5000=7800(元)，答：买一台洗衣机和一台冰箱一共需要7800元。",
+        "knowledge_points":  [
+                                 "整百数",
+                                 "几百几十数的加减法口算"
+                             ],
+        "source":  "24-25 二年级下·广东汕头·期末"
+    },
+    {
+        "id":  "395",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "下面是今年植树节种植树木的情况。(单位：棵)\n| 香樟 | 黄花风铃 | 紫花风铃 |\n| ---- | -------- | -------- |\n| 1200 | 1800 | 2000 |\n(1)香樟和黄花风铃一共多少棵？\n(2)香樟比紫花风铃少多少棵？",
+        "options":  [
+
+                    ],
+        "answer":  "3000棵;800棵",
+        "solution":  "【分析】(1)根据题意，用香樟树的数量加上黄花风铃树的数量，即可求出一共多少棵，用加法列式计算；\n(2)用紫花风铃树的数量减去香樟树的数量，即可求出香樟比紫花风铃树少多少棵，用减法列式计算。\n\n【详解】(1)1200+1800=3000(棵)，答：香樟和黄花风铃树一共3000棵。\n(2)2000-1200=800(棵)，答：香樟比紫花风铃树少800棵。",
+        "knowledge_points":  [
+                                 "整百数",
+                                 "几百几十数的加减法口算"
+                             ],
+        "source":  "24-25二年级下·广东江门·期末"
+    },
+    {
+        "id":  "396",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "请仔细阅读下文，回答下面的问题：\n赛龙舟是中国端午节的习俗之一，也是端午节最重要的节日民俗活动之一。龙舟的大小因地而异。如广州黄埔郊区一带龙船长33米，船上有100人，桡手约80人。湖南汨罗市龙舟长22米，桡手24-48人。福建福州龙舟长18米，桡手32人。比赛是在规定距离内，同时起航，以到达终点先后决定名次。\n(1)文中介绍的龙舟尺寸中，最短的是( )（填名称），长是( )。（答案要带单位）\n(2)请你算一算，文中最长的龙舟与最短的龙舟之间相差多少厘米。",
+        "options":  [
+
+                    ],
+        "answer":  "福建福州龙舟;18米;1500厘米",
+        "solution":  "【分析】根据题意，先明确各龙舟的长度：广州黄埔龙舟33米，湖南汨罗市龙舟22米，福建福州龙舟18米。比较数值可知最短为18米，最长为33米。用最长的龙舟长度减去最短的龙舟长度，再根据1米=100厘米，把米换算成厘米，据此答题即可。\n\n【详解】根据分析可知：\n(1)33>22>18，文中介绍的龙舟尺寸中，最短的是福建福州龙舟，长是18米。\n(2)1米=100厘米，33米=3300厘米，18米=1800厘米，3300-1800=1500(厘米)。答：最长的龙舟与最短的龙舟之间相差1500厘米。",
+        "knowledge_points":  [
+                                 "厘米和米之间的进率与换算",
+                                 "整百数",
+                                 "几百几十数的加减法口算",
+                                 "100以内数的比大小"
+                             ],
+        "source":  "24-25 三年级下·广东广州·期末"
+    },
+    {
+        "id":  "397",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "参与图书修补可以增强学生的动手能力，还能提醒同学们要阅读书籍。刘老师准备组织同学们对书架上的书进行修补。其中文学类有523本，科学类有380本，艺术类有225本。请你估一估，这三个书架上的图书总数有1000本吗。",
+        "options":  [
+
+                    ],
+        "answer":  "有",
+        "solution":  "【分析】根据题意，把文学类、科学类和艺术类这三类书的本数看成与之接近的整百数，用加法计算出结果，再和1000本比较大小即可解答。\n\n【详解】把523本看成500本，380本看成400本，225本看成200本，这三类书的本数都估少了。500+400+200=1100(本)，1100>1000，在这三类书的本数都估少的情况下，三个书架上的图书总数还是大于1000本。答：这三个书架上的图书总数有1000本。",
+        "knowledge_points":  [
+                                 "万以内数的大小比较",
+                                 "万以内数加减法的估算"
+                             ],
+        "source":  "24-25 二年级下·湖北武汉·期末"
+    },
+    {
+        "id":  "398",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "食堂里有500千克大米，用去了200千克，剩下的比用去的多多少。",
+        "options":  [
+
+                    ],
+        "answer":  "100千克",
+        "solution":  "【分析】根据减法的意义，食堂大米的总数量-用去的大米数量=剩余的大米数量，列出算式先算出剩余大米的数量。再用剩余的大米数量-用去的大米数量=剩余的比用去的大米多的数量，列出算式算出答案即可解答。\n\n【详解】500-200=300(千克),300-200=100(千克),答：剩下的比用去的多100千克。",
+        "knowledge_points":  [
+                                 "整百数",
+                                 "几百几十数的加减法口算"
+                             ],
+        "source":  "24-25 二年级下·河北张家口·期末"
+    },
+    {
+        "id":  "399",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "学校礼堂有1000个座位，\"六一\"节要在学校礼堂举行演唱会，全校男生有473人，男生比女生少25人，学校礼堂能坐下所有学生吗。",
+        "options":  [
+
+                    ],
+        "answer":  "能",
+        "solution":  "【分析】根据题意，可将男生的人数看成与之接近的整百或整百整十数，将男生比女生少的人数看成与之接近的整十数，先计算出女生大约有多少人，再将男生和女生大约的人数相加计算出总人数，再和座位数比较大小即可。\n\n【详解】473接近480，将人数估大了;男生比女生少25人,25接近30;则女生人数约为:480+30=510(人),女生的人数也估大了;480+510=990(人),990<1000，则实际的人数也小于1000。答：学校礼堂能坐下所有学生。",
+        "knowledge_points":  [
+                                 "1000以内数的比大小",
+                                 "万以内数加减法的估算"
+                             ],
+        "source":  "24-25 二年级下·重庆梁平·期末"
+    },
+    {
+        "id":  "400",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "果园里有李树800棵，桃树600棵，苹果树2000棵。桃树比苹果树少多少棵。",
+        "options":  [
+
+                    ],
+        "answer":  "1400棵",
+        "solution":  "【分析】根据减法的意义，苹果树的总数量-桃树的总数量=桃树比苹果树少的棵树，由此列出算式算出答案即可解答。\n\n【详解】2000-600=1400(棵),答：桃树比苹果树少1400棵。",
+        "knowledge_points":  [
+                                 "整百数",
+                                 "几百几十数的加减法口算"
+                             ],
+        "source":  "24-25 二年级下·重庆梁平·期末"
+    },
+    {
+        "id":  "401",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "6087中的\"8\"表示( )。",
+        "options":  [
+                        "A. 8个一",
+                        "B. 8个十",
+                        "C. 8个百"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】一个四位数，从右往左依次为个位，十位，百位，千位。千位是几表示几个千，百位是几表示几个百，十位是几表示几个十，个位是几表示几个一;6087中的\"8\"在十位上;据此解答。\n\n【详解】由分析可得:6087中的\"8\"表示8个十;故答案为:B",
+        "knowledge_points":  [
+                                 "万以内数的组成"
+                             ],
+        "source":  "24-25二年级下·广东汕尾·期末"
+    },
+    {
+        "id":  "402",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "下面各数中，一个零也不读的是( )。",
+        "options":  [
+                        "A. 5003",
+                        "B. 5300",
+                        "C. 5030"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】读数时，从高位读起，按照数位顺序读。千位是几就读几千，百位是几就读几百，十位上是几就读几十，个位上是几就读几，中间有一个0或两个0，只读一个零;末尾不管有几个0，都不读。找出只有末位有0的数即可;据此解答。\n\n【详解】由分析可得:A。5003，中间的两个0只读一个0;不符合题意;B。5300，末位的0都不读;符合题意;C。5030，中间的0读，末位的0不读;不符合题意;故答案为:B",
+        "knowledge_points":  [
+                                 "万以内数的读，写法"
+                             ],
+        "source":  "24-25 二年级下·广东汕尾·期末"
+    },
+    {
+        "id":  "403",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "小才和小强在同一所学校上学，小才家离学校230米，小强家离学校570米。小才家离小强家( )。",
+        "options":  [
+                        "A. 800米",
+                        "B. 340米",
+                        "C. 不能确定"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】已知小才家离学校230米，小强家离学校570米，如果在同一方向，小强家离学校的距离减去小才家离学校的距离，如果不在同一方向，小才家离学校的距离+小强家离学校的距离，分别计算对照选项进行选择。\n\n【详解】A。800米,230+570=800(米),两家不在同一方向的距离，题目中未说明在不同方向;B。340米,570-230=340米(米),两家在同一方向的距离，题目中未说明在相同方向;C。不能确定，题目中只说明了两个人家距离学校的距离，并未表明方向，所以答案不确定，答案正确。故答案为:C",
+        "knowledge_points":  [
+                                 "两，三位数的一次进位加法",
+                                 "两，三位数的不退位减法"
+                             ],
+        "source":  "24-25 二年级下·广东揭阳·期末"
+    },
+    {
+        "id":  "404",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "一千里面有( )个百。",
+        "options":  [
+                        "A. 1",
+                        "B. 10",
+                        "C. 100"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】数数时，一个一个地数,10个一是十，一十一十地数,10个十是一百，一百一百地数,10个百是一千，据此解答。\n\n【详解】根据分析可得:10个百是一千，则一千里面有10个百。故答案为:B",
+        "knowledge_points":  [
+                                 "1000以内数的组成"
+                             ],
+        "source":  "24-25二年级下·广东佛山·期末"
+    },
+    {
+        "id":  "405",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "用8,5,7三个数字组成的最大三位数是( )。",
+        "options":  [
+                        "A. 875",
+                        "B. 857",
+                        "C. 785"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】要想组成的数最大，要把数字按照从大到小的顺序从高位到低位排下来，据此结合题干要求进行解答即可。\n\n【详解】8>7>5，所以用8,5,7三个数字组成的最大三位数是875。故答案为:A",
+        "knowledge_points":  [
+                                 "1000以内数的组成",
+                                 "1000以内数的比大小"
+                             ],
+        "source":  "24-25 二年级下·河北保定·期末"
+    },
+    {
+        "id":  "406",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "用加法算式表示\"4308\"的组成，正确的是( )。",
+        "options":  [
+                        "A. 4+3+8",
+                        "B. 4000+30+8",
+                        "C. 4000+300+8"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】给出的数字是一个4位数,4在千位表示4000;3在百位表示300;十位是0，在加法中可省略;8在个位表示8，按照从左向右的顺序加起来即可。\n\n【详解】A。4+3+8=15，结果是15，不等于4308，不符合题意;B。4000+30+8=4038，百位的3是300，不是30，不符合题意;C。4000+300+8=4308，符合题意。故答案为:C",
+        "knowledge_points":  [
+                                 "万以内数的组成"
+                             ],
+        "source":  "24-25 二年级下·福建三明·期末"
+    },
+    {
+        "id":  "407",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "与2048中的\"4\"表示一致的是( )。",
+        "options":  [
+                        "A. ![](images/31cd7e06a89dc50973cb94059d7a50880c68e6220b384f603fc9481dd22f2177.jpg)",
+                        "B. ![](images/6f0151f2860257851922e8ac112b018225864918cda3d8f5a694837f67415daa.jpg)",
+                        "C. ![](images/155028f847be7584d2e8dcf299abee3fe3e98566176452b3fee1fe289ab1127c.jpg)"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】用计数器表示数时，百位有几颗珠子就表示几个百，十位有几颗珠子就表示几个十，个位有几颗珠子就表示几个一;2048中的\"4\"在十位上，表示4个十;找出数字4表示4个十的计数器即可;据此解答。\n\n【详解】由分析可得:A。4个珠子在百位上，表示4个百，不符合题意;B。4个珠子在十位上，表示4个十，符合题意;C。4个珠子在个位上，表示4个一，不符合题意。故答案为:B",
+        "knowledge_points":  [
+                                 "万以内数的组成"
+                             ],
+        "source":  "24-25 二年级下·福建福州·期末"
+    },
+    {
+        "id":  "408",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "小明从家里出发，中途休息了一会儿，估一估，小明家到学校大约有( )。\n![](images/cad8b91758470969dcdf7fb4d3b54edc.png)",
+        "options":  [
+                        "A. 4000米",
+                        "B. 6000米",
+                        "C. 8000米"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】从图上可得：每一格表示2000米，小明家到学校大约有4格。根据加法的意义，求出4个2000的和是多少即可。2000+2000+2000+2000=8000(米)，所以小明家到学校大约有8000米。故答案为：C。",
+        "knowledge_points":  [
+                                 "整百数",
+                                 "几百几十数的加减法口算"
+                             ],
+        "source":  "24-25 二年级下·浙江温州·期末"
+    },
+    {
+        "id":  "409",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "用2,0,5三张数字卡片摆三位数，最多可以摆成( )个不同的三位数。",
+        "options":  [
+                        "A. 2",
+                        "B. 3",
+                        "C. 4",
+                        "D. 6"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】根据百位上数字的不同，我们可以将它们分成两类(因为百位上不能是0):①百位上是2时，能组成哪些三位数;②百位上是5时，能组成哪些三位数。\n\n【详解】由分析可得:①百位上是2时，组成的数有:205;250;②百位上是5时，组成的数有:502;520。则最多可以摆成4个不同的三位数。故答案为:C",
+        "knowledge_points":  [
+                                 "1000以内数的组成"
+                             ],
+        "source":  "24-25 二年级下·四川乐山·期末"
+    },
+    {
+        "id":  "410",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "下面各数只读一个\"0\"的是( )。",
+        "options":  [
+                        "A. 6300",
+                        "B. 6000",
+                        "C. 6003",
+                        "D. 10000"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】万以内整数的读法：千位上是几就读几千，百位上是几就读几百，十位上是几就读几十，个位上是几就读几，末尾的0都不读出来，其余数位连续几个0都只读一个零，即可读出此数。\n\n【详解】A。6300读作六千三百，一个零也不读，不符合题意;B。6000读作六千，一个零也不读，不符合题意;C。6003读作六千零三，则只读一个零，符合题意;D。10000读作一万，一个零也不读，不符合题意。故答案为:C",
+        "knowledge_points":  [
+                                 "万以内数的读，写法"
+                             ],
+        "source":  "24-25 二年级下·四川乐山·期末"
+    },
+    {
+        "id":  "411",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "6900里面有( )。",
+        "options":  [
+                        "A. 69个十",
+                        "B. 69个百",
+                        "C. 69个千"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】6900的千位上是6，代表6个千，百位上是9，代表9个百，十位和个位上都是0。一个千中有10个百,1个百中有10个十，由此即可解答。\n\n【详解】A。6900里面有690个十，原说法错误，不选;B。6900里面有69个百，原说法正确，当选;C。6900里面有6个千和9个百，原说法错误，不选。故答案为:B",
+        "knowledge_points":  [
+                                 "万以内数的组成"
+                             ],
+        "source":  "24-25 二年级下·广东东莞·期末"
+    },
+    {
+        "id":  "412",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "下面各数中，一个零也不读的是( )。",
+        "options":  [
+                        "A. 6075",
+                        "B. 8006",
+                        "C. 8900"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】整数的读法：从高位到低位，一级一级地读，每级末尾的0都不读出来，其余数位连续几个0都只读一个零。读出各数即可求解。\n\n【详解】A。6075读作六千零七十五;B。8006读作八千零六;C。8900读作八千九百。一个零也不读的是8900。故答案为:C",
+        "knowledge_points":  [
+                                 "万以内数的读，写法"
+                             ],
+        "source":  "24-25 二年级下·山东菏泽·期末"
+    },
+    {
+        "id":  "413",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "下面的数中，一个零也不读的是( )。",
+        "options":  [
+                        "A. 6606",
+                        "B. 6006",
+                        "C. 6060",
+                        "D. 6600"
+                    ],
+        "answer":  "D",
+        "solution":  "【分析】万以内数的读法：从高位读起，千位上是几，读作几千;百位上是几，读作几百;十位上是几，读作几十;个位上是几，读作几;末尾的0不读，中间的1个或连续2个0，只读1个零。据此读出选项中各数，找出一个零也不读的数，即可解答。\n\n【详解】A。6606：读作\"六千六百零六\"，读出\"零\"，不符合。B。6006：读作\"六千零六\"，读出\"零\"，不符合。C。6060：读作\"六千零六十\"，读出\"零\"，不符合。D。6600：读作\"六千六百\"，末尾两个0均不读，符合条件。故答案为:D",
+        "knowledge_points":  [
+                                 "万以内数的读，写法"
+                             ],
+        "source":  "24-25 二年级下·浙江绍兴·期末"
+    },
+    {
+        "id":  "414",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "七千零五写作( )。",
+        "options":  [
+                        "A. 705",
+                        "B. 7050",
+                        "C. 7005"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】一个整数，从右往左依次为个位，十位，百位，千位。写数时，从高位写起，按照数位顺序写;有几个千就在千位写几，有几个百就在百位写几。中间或末尾哪一位上一个单位也没有，就在那一位上写0。\n\n【详解】七千零五写作:7005。故答案为:C",
+        "knowledge_points":  [
+                                 "万以内数的读，写法"
+                             ],
+        "source":  "24-25 二年级下·湖北襄阳·期末"
+    },
+    {
+        "id":  "415",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "一个密码箱的密码是下面三个数中的一个，这个密码大于6000，小于7000，最接近7000，该密码是( )。",
+        "options":  [
+                        "A. 6559",
+                        "B. 6907",
+                        "C. 7001"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】根据题目条件，密码需满足:①大于6000且小于7000;②最接近7000。逐一分析选项是否符合条件。\n\n【详解】由分析可得:A。6559大于6000且小于7000，满足条件①;与7000的差距较大，不满足条件②,不符合题意;B。6907大于6000且小于7000，满足条件①;接近7000，满足条件②,符合题意;C。7001大于7000，不满足条件①,不符合题意;综上，最接近7000且符合条件的密码是6907。故答案为:B",
+        "knowledge_points":  [
+                                 "万以内数的大小比较",
+                                 "万以内数的估计"
+                             ],
+        "source":  "24-25二年级下·重庆秀山·期末"
+    },
+    {
+        "id":  "416",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "下面三个数中，一个0都不读的是( )。",
+        "options":  [
+                        "A. 5050",
+                        "B. 5005",
+                        "C. 5500"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】读数时，从高位读起，按照数位顺序读。千位是几就读几千，百位是几就读几百，十位上是几就读几十，个位上是几就读几;中间有一个0或两个0，只读一个零;末尾不管有几个0，都不读。根据读数法则，逐项读出各数，找出一个0都不读的数;据此解答。\n\n【详解】由分析可得:A。5050读作：五千零五十，读一个零，不符合题意;B。5005读作：五千零五，读一个零，不符合题意;C。5500读作：五千五百，一个0都不读，符合题意。故答案为:C",
+        "knowledge_points":  [
+                                 "万以内数的读，写法"
+                             ],
+        "source":  "24-25 二年级下·广西河池·期末"
+    },
+    {
+        "id":  "417",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "王老师想买一台电风扇和一个电饭煲，但标价个位上的数字都看不清了，请你帮王老师看一看，他带了1000元，够吗。( )\n![](images/fe1684589539a68267613dabe7b1f831.png)",
+        "options":  [
+                        "A. 肯定不够",
+                        "B. 肯定够了",
+                        "C. 无法确定"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】根据题意，把这两个三位数用四舍五入法估算，然后用加法计算出结果和1000比较大小。如果结果小于等于1000，说明够；大于1000，说明不够，据此解答。\n\n【详解】根据分析：37□十位上是7，大于5，舍去向百位进一，约等于400，估大了。59□十位上是9，大于5，舍去向百位进一，约等于600，估大了。400+600=1000(元)，两个数都估大了，实际价钱小于1000元，1000元肯定够了。故答案为：B。",
+        "knowledge_points":  [
+                                 "万以内数加减法的估算"
+                             ],
+        "source":  "24-25 二年级下·河北邢台·期末"
+    },
+    {
+        "id":  "418",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "下面的排队正确的是( )。\n![](images/74e9c03c524fd4c190a489a94c08b9da.png)",
+        "options":  [
+                        "A. 9009<9090<9910<999",
+                        "B. 999<9910<9090<9009",
+                        "C. 9090<9910<999<9009",
+                        "D. 999<9009<9090<9910"
+                    ],
+        "answer":  "D",
+        "solution":  "【分析】整数比较大小方法：①位数多的数大于位数少的数；②位数相同的，先比较最高位上的数，最高位上大的，数就大，最高位数相同的，就比较下一位，以此类推，据此解答。\n\n【详解】由分析可得：999是三位数，三位数小于四位数，故是最小数，从小到大应排在第1位；剩余的三个数都是四位数，最高位上都是9，就比较百位数字，9009和9090百位都是0，9910百位数字是9，故9910最大，应排在末尾；比较9009和9090十位数字，0<9，故9009<9090。从小到大排列：999<9009<9090<9910。故答案为：D。",
+        "knowledge_points":  [
+                                 "万以内数的大小比较"
+                             ],
+        "source":  "24-25 二年级下·山东菏泽·期末"
+    },
+    {
+        "id":  "419",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "下面各数中的4表示的数最大的是( )。",
+        "options":  [
+                        "A. ![](images/9255169db07ba025663762942ebab3c275e7337ca99de83de5aa96329ac0dbb5.jpg)",
+                        "B. ![](images/769a6db5cbe5f4157bbc95406a745ff69adcd5e7d4a8139c3144a1ae1731f424.jpg)",
+                        "C. ![](images/4a2acae740f6f027c597cd9e2c6ae3677c63690439cd124b40ea925323bbed72.jpg)"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】百位上是几就是几百，十位上是几就是几十，个位上是几就是几。据此逐项分析。\n\n【详解】A. 437中的4表示4个百，即400；B. 304中的4表示4个一，即4；C. 740中的4表示4个十，即40。因为4<40<400，所以各数中的4表示的数最大的是A。故答案为：A。",
+        "knowledge_points":  [
+                                 "1000以内数的组成",
+                                 "1000以内数的比大小",
+                                 "整数的数级",
+                                 "数位和计数单位的认识"
+                             ],
+        "source":  "24-25 二年级下·山东菏泽·期末"
+    },
+    {
+        "id":  "420",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "用算盘表示605，需要拨( )颗珠子。",
+        "options":  [
+                        "A. 3",
+                        "B. 5",
+                        "C. 7"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】在算盘上，一颗上珠表示5，一颗下珠表示1。用算盘表示605，需要在百位拨一颗上珠，拨一颗下珠，在个位上拨一颗上珠，一共需要拨3颗珠子。\n\n【详解】百位是\"6\"，拨2颗珠子，拨一颗上珠和一颗下珠;十位是\"0\"，不拨;个位是\"5\"，拨一颗上珠，即可表示605.2+1=3(颗),用算盘表示605，需要拨3颗珠子。故答案为:A",
+        "knowledge_points":  [
+                                 "算盘的认识与使用",
+                                 "1000以内数的组成"
+                             ],
+        "source":  "24-25 二年级下·湖南长沙·期末"
+    },
+    {
+        "id":  "421",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "下面各数中，最接近600的数是( )。",
+        "options":  [
+                        "A. 598",
+                        "B. 603",
+                        "C. 589"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】两个数之间间隔的数越少，表示这两个数越接近，从589数到603，一个一个地数一数，找出两数之间有几个数，即可解答。\n\n【详解】由分析可得:589,590,591,592,593,594,595,596,597,598,599,600,601,602,603。A。598,598和600之间有1个数;B。603,600和603之间有2个数;C。589,589和600之间有10个数;所以最接近600的数是598。故答案为:A",
+        "knowledge_points":  [
+                                 "数1000以内的数",
+                                 "1000以内数的估计"
+                             ],
+        "source":  "24-25 二年级下·湖南长沙·期末"
+    },
+    {
+        "id":  "422",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "下面各数中，一个零也不读的是( )。",
+        "options":  [
+                        "A. 3006",
+                        "B. 3600",
+                        "C. 6030"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】根据万以内数的读法：从高位到低位，按照数位顺序读，末尾的0都不读出来，其它数位连续几个0都只读一个零。读出各数，即可解答。\n\n【详解】A。3006读作：三千零六，读一个零;B。3600读作：三千六百，一个零也不读;C。6030读作：六千零三十，读一个零。所以一个零也不读的是3600。故答案为:B",
+        "knowledge_points":  [
+                                 "万以内数的读，写法",
+                                 "万以内数的组成"
+                             ],
+        "source":  "24-25二年级下·湖南长沙·期末"
+    },
+    {
+        "id":  "423",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "下面的三个数中，一个零都不读的是( )。",
+        "options":  [
+                        "A. 1050",
+                        "B. 1005",
+                        "C. 1500"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】万以内数的读法：读数时，从高位读起，千位是几就读几千，百位是几就读几百，十位上几就读几十，个位上是几就读几，中间有一个0或两个0，只读一个零;末尾不管有几个0，都不读。由此解答。\n\n【详解】A。1050：读作\"一千零五十\"。这里的零在百位，是中间的零，所以读出来。B。1005：读作\"一千零五\"。这里的零在百位和十位，但连续时读一个\"零\"，所以读出来。C。1500：读作\"一千五百\"。这里的两个零都在末尾，所以一个零都不读。因此，只有选项1500，一个零都不读。故答案为:C",
+        "knowledge_points":  [
+                                 "万以内数的读，写法"
+                             ],
+        "source":  "24-25 二年级下·江西赣州·期末"
+    },
+    {
+        "id":  "424",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "下面的三个数中，只读一个零的是( )。",
+        "options":  [
+                        "A. 1009",
+                        "B. 8200",
+                        "C. 7640"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】万以内数的读法：从高位读起，末尾不管有几个0都不读，其他数位有一个0或连续几个0，都只读一个零。\n\n【详解】A。1009读作：一千零九，只读一个零;B。8200读作：八千二百，一个零也不读;C。7640读作：七千六百四十，一个零也不读。故答案为:A",
+        "knowledge_points":  [
+                                 "万以内数的读，写法"
+                             ],
+        "source":  "24-25 二年级下·浙江温州·期末"
+    },
+    {
+        "id":  "425",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "在下面算盘中,( )上的数读作七千三百八十。",
+        "options":  [
+                        "A. ![](images/4fc568223e228a2c101e4c3040562e8b2beef68414b6342d0c919be4d27c987b.jpg)",
+                        "B. ![](images/956622012b923b4b5b95a660f5da0240d902318e972071fb2d595433ee80d70e.jpg)",
+                        "C. ![](images/01ad6dc4b186dd56ab899bb9a536381b9777fe824435f23e9c9290f44d0c2998.jpg)"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】算盘的一颗上珠表示5，一颗下珠表示1。千位上是几就是几千，百位上是几就是几百，十位上是几就是几十，个位上是几就是几。整数的写法：从高位到低位，一级一级地写，哪一个数位上一个单位也没有，就在那个数位上写0。整数的读法：从高位到低位，一级一级地读，每一级末尾的0都不读出来，其余数位连续几个0都只读一个零。\n\n【详解】A。7380，读作七千三百八十;B。最高位不在千位上，不符合;C。最高位不在千位上，不符合。A上的数读作七千三百八十。故答案为:A",
+        "knowledge_points":  [
+                                 "算盘的认识与使用",
+                                 "万以内数的读，写法",
+                                 "整数的数级",
+                                 "数位和计数单位的认识"
+                             ],
+        "source":  "24-25 二年级下·河南周口·期末"
+    },
+    {
+        "id":  "426",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "要买下面这两件商品，所带的钱数肯定不够的是( )。\n![](images/c4f9d82319f6d0816a51762f5111f698.png)",
+        "options":  [
+                        "A. 620元",
+                        "B. 700元",
+                        "C. 800元"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】手表的单价是429元，鞋子的单价最少200元，429+200=629(元)，买这两件商品的总钱数大于或等于629元，629元>620元，所以带620元不够。\n\n【详解】429>400，2□□大于或等于200；429+200=629(元)。即买这两件商品的总钱数大于或等于629元，则带620元不够。故答案为：A。",
+        "knowledge_points":  [
+                                 "经济问题",
+                                 "1000以内数的比大小",
+                                 "两，三位数的不进位加法"
+                             ],
+        "source":  "24-25 二年级下·浙江温州·期末"
+    },
+    {
+        "id":  "427",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "爸爸要买两件衣服，第一件300元，第二件衣服的价格看不清楚，只知道最高位百位上的数字是2，爸爸带( )元就一定够买这两件衣服。",
+        "options":  [
+                        "A. 400",
+                        "B. 500",
+                        "C. 600"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】根据题意可知，第二件商品的价格是三位数，范围在200元到299元之间(包括200),分别计算出这两件商品的最小总价和最大总价，若爸爸带的钱够用，她必须准备至少最大可能的总价格，逐项分析各个选项，找出正确答案即可。\n\n【详解】最小总价:300+200=500(元),最大总价:300+299=599(元)。A。400<500小于最小总价，不能买这两件衣服。B。500=500<599当第二件衣服是299，则不够买。C。600>599>500，大于最大总价，则够买。故答案为:C",
+        "knowledge_points":  [
+                                 "整百数",
+                                 "几百几十数的加减法口算"
+                             ],
+        "source":  "24-25 二年级下·广东东莞·期末"
+    },
+    {
+        "id":  "428",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "9800中的两个\"0\"( )。",
+        "options":  [
+                        "A. 读两个零",
+                        "B. 都不读",
+                        "C. 读一个零"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】一个整数，从右往左依次为个位，十位，百位，千位。读数时，从高位读起，按照数位顺序读。千位是几就读几千，百位是几就读几百。中间有一个0或两个0，只读一个零;末尾不管有几个0，都不读。由此解答。\n\n【详解】由分析得:9800读作九千八百，则9800中的两个\"0\"都不读。故答案为:B",
+        "knowledge_points":  [
+                                 "万以内数的读，写法"
+                             ],
+        "source":  "24-25 二年级下·河北邢台·期末"
+    },
+    {
+        "id":  "429",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "长江全长约六千三百九十七米。画横线的数写作( )。",
+        "options":  [
+
+                    ],
+        "answer":  "6397",
+        "solution":  "【分析】万以内数的写法：从高位起按照数位顺序写。几个千就在千位上写几，几个百就在百位上写几，几个十就在十位上写几，几个一就在个位上写几，中间或末尾哪一位上一个也没有，就在那一位上写0占位。\n\n【详解】长江全长约六千三百九十七米。画横线的数写作(6397)。",
+        "knowledge_points":  [
+                                 "万以内数的读，写法"
+                             ],
+        "source":  "24-25 二年级下·广东汕尾·期末"
+    },
+    {
+        "id":  "430",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "一台洗衣机卖3010元，约( )元。",
+        "options":  [
+
+                    ],
+        "answer":  "3000",
+        "solution":  "【分析】题目要求将3010元近似为整百或整千的数。根据四舍五入规则，若近似到千位,3010的百位是0(小于5),故舍去后三位，结果为3000元;若近似到百位，十位是1(小于5),同样舍去后两位，结果仍为3000元。\n\n【详解】一台洗衣机卖3010元，约3000元。",
+        "knowledge_points":  [
+                                 "万以内数的估计"
+                             ],
+        "source":  "24-25 二年级下·广东汕尾·期末"
+    },
+    {
+        "id":  "431",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "用2,0,7,6组成的最大四位数是( ),最小四位数是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "7620;2067",
+        "solution":  "【分析】要想组成的数最大，要把数按照从大到小的顺序从高位到低位排下来;要想组成的数最小，就要把数按照从小到大的顺序从高位到低位排下来，但是要注意最高位不能是0。\n\n【详解】用2,0,7,6组成的最大四位数是7620，最小四位数是2067。",
+        "knowledge_points":  [
+                                 "万以内数的组成",
+                                 "万以内数的大小比较"
+                             ],
+        "source":  "24-25二年级下·广东汕尾·期末"
+    },
+    {
+        "id":  "432",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "5680里面有( )个千,( )个百和( )个十。",
+        "options":  [
+
+                    ],
+        "answer":  "5;6;8",
+        "solution":  "【分析】一个四位数，从右往左数，第一位是个位，个位上的数表示几个一;第二位是十位，十位上的数表示几个十;第三位是百位，百位上的数表示几个百;第四位是千位，千位上的数表示几个千;据此填空即可。\n\n【详解】5680里面有5个千,6个百和8个十。",
+        "knowledge_points":  [
+                                 "万以内数的组成"
+                             ],
+        "source":  "24-25 二年级下·广东汕尾·期末"
+    },
+    {
+        "id":  "433",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "5680里面有( )个千,( )个百和( )个十。",
+        "options":  [
+
+                    ],
+        "answer":  "5;6;8",
+        "solution":  "【分析】一个四位数，从右往左数，第一位是个位，个位上的数表示几个一;第二位是十位，十位上的数表示几个十;第三位是百位，百位上的数表示几个百;第四位是千位，千位上的数表示几个千;据此填空即可。\n\n【详解】5680里面有5个千,6个百和8个十。",
+        "knowledge_points":  [
+                                 "万以内数的组成"
+                             ],
+        "source":  "24-25 二年级下·广东汕尾·期末"
+    },
+    {
+        "id":  "434",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "由5个千,3个十和8个一组成的数是( ),读作( )。",
+        "options":  [
+
+                    ],
+        "answer":  "5038;五千零三十八",
+        "solution":  "【分析】一个四位数，从右往左依次是个位，十位，百位，千位，写数时，从高位写起，有几个千就在千位写几，有几个百就在百位写几，有几个十就在十位写几，有几个一就在个位写几，哪一位上一个单位也没有，就在那一位上写0;读数时，从高位读起，千位上是几就读几千，百位上是几就读几百，十位上是几就读几十，个位上是几就读几，中间有一个0或两个0，只读一个\"零\"，末尾不管有几个0都不读;由此解答。\n\n【详解】由5个千,3个十和8个一组成的数是5038，读作五千零三十八。",
+        "knowledge_points":  [
+                                 "万以内数的读，写法",
+                                 "万以内数的组成"
+                             ],
+        "source":  "24-25 二年级下·广东汕尾·期末"
+    },
+    {
+        "id":  "435",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "用数字卡片0,3,6,7可以组成( )个没有重复数字的两位数，如果将这些数按照从小到大的顺序排列起来，排在第5个的是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "9;63",
+        "solution":  "【分析】要用0,3,6,7组成没有重复数字的两位数,0不能放在十位，所以十位上的数字只能是3,6,7，再分别搭配剩下的数字当个位。据此列举解答即可。\n\n【详解】十位是3时，能组成30,36,37，共3个;十位是6时，能组成60,63,67，共3个;十位是7时，能组成70,73,76，共3个。共有3+3+3=9(个)这样的两位数。按从小到大排列:30,36,37,60,63,67,70,73,76，排在第5个的是63。",
+        "knowledge_points":  [
+                                 "100以内数的组成",
+                                 "100以内数的比大小"
+                             ],
+        "source":  "24-25 三年级下·浙江温州·期末"
+    },
+    {
+        "id":  "436",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "由5个千,8个百和2个一组成的数是( ),这个数的最高位是( )位。",
+        "options":  [
+
+                    ],
+        "answer":  "5802;千",
+        "solution":  "【分析】一个四位数，从右往左依次为个位，十位，百位，千位。几个千就在千位上写几，几个百就在百位上写几，几个十就在十位上写几，几个一就在个位上写几，哪一位上一个数字也没有就写\"0\"占位;5个千,8个百和2个一：千位是5，百位是8，个位是2;这个数的最高位是第四位千位;据此可解。\n\n【详解】由分析可知：由5个千,8个百和2个一组成的数是5802，这个数的最高位是千位。",
+        "knowledge_points":  [
+                                 "万以内数的组成"
+                             ],
+        "source":  "24-25 二年级下·广东佛山·期末"
+    },
+    {
+        "id":  "437",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "由3个千和8个百组成的数是( ),再加上2个( )是4个千。",
+        "options":  [
+
+                    ],
+        "answer":  "3800;百",
+        "solution":  "【分析】3个千是3000,8个百是800，两者相加就是由3个千和8个百组成的数,4个千是4000，用4000减去3个千和8个百相加的数，即再加上2个多少是4个千。\n\n【详解】3000+800=3800,4000-3800=200,200表示2个百。所以，由3个千和8个百组成的数是3800，再加上2个百是4个千。",
+        "knowledge_points":  [
+                                 "万以内数的读，写法",
+                                 "万以内数的组成",
+                                 "整百数",
+                                 "几百几十数的加减法口算"
+                             ],
+        "source":  "24-25 二年级下·河南南阳·期末"
+    },
+    {
+        "id":  "438",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "3张100元,1张50元,5张10元,2张1元的人民币合起来是( )元。",
+        "options":  [
+
+                    ],
+        "answer":  "402",
+        "solution":  "【分析】分别计算每种面值人民币的总金额，再相加求和即可。\n\n【详解】3张100元的总金额300元;1张50元的总金额50元;5张10元的总金额50元;2张1元的总金额2元;300+50+50+2=350+50+2=400+2=402(元),因此,3张100元,1张50元,5张10元,2张1元的人民币合起来是402元。",
+        "knowledge_points":  [
+                                 "十元以上人民币的认识与计算"
+                             ],
+        "source":  "24-25 二年级下·河南南阳·期末"
+    },
+    {
+        "id":  "439",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "985是由( )个百,( )个十,( )个一组成的，这个数与最小的四位数相差( )。",
+        "options":  [
+
+                    ],
+        "answer":  "9;8;5;15",
+        "solution":  "【分析】一个三位数，从右往左依次为个位，十位，百位，百位上是几表示几个百，十位上是几表示几个十，个位上是几表示几个一;用数数的方法可以求出这个数与最小的四位数相差多少，据此解答。\n\n【详解】由分析可得:985是由9个百,8个十,5个一组成的，这个数与最小的四位数相差15。",
+        "knowledge_points":  [
+                                 "1000以内数的组成",
+                                 "数1000以内的数"
+                             ],
+        "source":  "24-25 二年级下·河北保定·期末"
+    },
+    {
+        "id":  "440",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "故宫博物院现有1134件珍宝藏品，横线上的数是由( )个千,( )个百,( )个十和( )个一组成的。",
+        "options":  [
+
+                    ],
+        "answer":  "1;1;3;4",
+        "solution":  "【分析】一个四位数，从右往左依次为个位，十位，百位，千位。千位是几表示几个千，百位是几表示几个百，十位是几表示几个十，个位是几表示几个一;1134千位是1，百位是1，十位是3，个位是4;据此解答。\n\n【详解】由分析可得：故宫博物院现有1134件珍宝藏品，横线上的数是由1个千,1个百,3个十和4个一组成的。",
+        "knowledge_points":  [
+                                 "万以内数的组成"
+                             ],
+        "source":  "24-25 二年级下·河南三门峡·期末"
+    },
+    {
+        "id":  "441",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "一个一个地数，与8999相邻的两个数是( )和( )。",
+        "options":  [
+
+                    ],
+        "answer":  "8998;9000",
+        "solution":  "【分析】一个一个地数,8999往前数依次是8998,8997,8996,。等,8999往后数依次是9000,9001,9002,。等;据此解答。\n\n【详解】根据分析：一个一个地数，与8999相邻的两个数是8998和9000。",
+        "knowledge_points":  [
+                                 "数万以内的数"
+                             ],
+        "source":  "24-25 二年级下·福建三明·期末"
+    },
+    {
+        "id":  "442",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "860里面有( )个十,35个百是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "86;3500",
+        "solution":  "【分析】一个整数，从右往左依次为个位，十位，百位，千位。,根据整数的组成,860百位上是8，表示8个百，十位上是6，表示6个十，个位上是0，表示一个单位也没有，用0占位;35个百，表示35个100是3500，据此解答。\n\n【详解】根据分析:860里面有(86)个十,35个百是(3500)。",
+        "knowledge_points":  [
+                                 "1000以内数的组成",
+                                 "万以内数的组成"
+                             ],
+        "source":  "24-25 二年级下·湖南衡阳·期末"
+    },
+    {
+        "id":  "443",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在算盘上表示\"7\"只需要用( )颗珠子，比用计数器表示少用( )颗珠子。",
+        "options":  [
+
+                    ],
+        "answer":  "3;4",
+        "solution":  "【分析】算盘表示数字\"7\"：上珠每颗代表5，下珠每颗代表1。表示数字\"7\"时，通常拨动一颗上珠和两颗下珠，因此，总共使用3颗珠子;计数器表示数字\"7\"：计数器每颗珠子代表1。表示数字\"7\"时，需要拨入7颗珠子，因此使用7颗珠子。计数器用珠子的颗数减去算盘上用珠子的颗数，等于算盘比计数器少用多少颗。\n\n【详解】7-3=4(颗),在算盘上表示数字\"7\"需要3颗珠子;比用计数器表示少用4颗珠子。",
+        "knowledge_points":  [
+                                 "算盘的认识与使用"
+                             ],
+        "source":  "24-25二年级下·四川乐山·期末"
+    },
+    {
+        "id":  "444",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "按规律填数。\n(1)4050，4100，4150，( )，( )。\n(2)1，4，9，16，( )，36。",
+        "options":  [
+
+                    ],
+        "answer":  "4200;4250;25",
+        "solution":  "【分析】(1)观察数字4050，4100，4150，发现后一个数比前一个数多50，按照规律数一数即可。\n(2)观察数字1，4，9，16，发现1=1×1，4=2×2，9=3×3，16=4×4，依次类推，括号中应该是5×5=25，验证36=6×6。\n\n【详解】(1)4050，4100，4150，4200，4250。\n(2)1，4，9，16，25，36。",
+        "knowledge_points":  [
+                                 "数万以内的数",
+                                 "整数排列的规律"
+                             ],
+        "source":  "24-25 二年级下·山东济宁·期末"
+    },
+    {
+        "id":  "445",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "一台电脑售价3010元，约为( )元。",
+        "options":  [
+
+                    ],
+        "answer":  "3000",
+        "solution":  "【分析】题目要求将3010元近似为整百或整千的数。根据四舍五入规则，若近似到千位,3010的百位是0(小于5),故舍去后三位，结果为3000元;若近似到百位，十位是1(小于5),同样舍去后两位，结果仍为3000元。\n\n【详解】一台电脑售价3010元，约为3000元。",
+        "knowledge_points":  [
+                                 "万以内数的估计"
+                             ],
+        "source":  "24-25 二年级下·山西长治·期末"
+    },
+    {
+        "id":  "446",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "一个数由5个千和2个一组成，这个数写作( )，读作( )。",
+        "options":  [
+
+                    ],
+        "answer":  "5002;五千零二",
+        "solution":  "【分析】万以内整数的写法：从高级到低级依次写出各位上的数字，哪一位上一个单位也没有，就在那一位上写0，据此即可写出此数。万以内整数的读法：千位上是几就读几千，百位上是几就读几百，十位上是几就读几十，个位上是几就读几，末尾的0都不读出来，其余数位连续几个0都只读一个零，即可读出此数。\n\n【详解】一个数由5个千和2个一组成，这个数写作5002，读作五千零二。",
+        "knowledge_points":  [
+                                 "万以内数的读，写法"
+                             ],
+        "source":  "24-25 二年级下·山西长治·期末"
+    },
+    {
+        "id":  "447",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "4850是由( )个千,( )个百和( )个十组成。",
+        "options":  [
+
+                    ],
+        "answer":  "4;8;5",
+        "solution":  "【分析】一个四位数，从右往左数，第一位是个位，个位上是几就表示几个一，第二位是十位，十位是几就表示几个十，第三位是百位，百位上是几就表示几个百，第四位是千位，千位是几就表示几个千。\n\n【详解】4850是由(4)个千,(8)个百和(5)个十组成。",
+        "knowledge_points":  [
+                                 "万以内数的组成"
+                             ],
+        "source":  "24-25 二年级下·山西长治·期末"
+    },
+    {
+        "id":  "448",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "5600里面有( )个百;63个十是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "56;630",
+        "solution":  "【分析】根据整数的组成，千位上是几就表示有几个千，百位上是几就表示有几个百，十位上是几就表示几个十，个位上是几就表示有几个一，据此解答。\n\n【详解】根据分析:5600是由56个百组成,5600里面有(56)个百;63个十是(630)。",
+        "knowledge_points":  [
+                                 "万以内数的组成"
+                             ],
+        "source":  "24-25 二年级下·山东菏泽·期末"
+    },
+    {
+        "id":  "449",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "在( )里填上“>”“<”或“=”。\n6062( )6026\n700克( )7千克\n3999克( )4千克",
+        "options":  [
+
+                    ],
+        "answer":  ">;<;<",
+        "solution":  "【分析】先根据“1千克=1000克”换算单位，然后比较大小即可。整数比较大小的方法：位数多的数大于位数少的数；位数相同的数，从最高位比起，最高位上大的数就大，最高位上相同的，就比较下一位，以此类推。\n\n【详解】千位都是6，百位都是0，十位6>2，故6062>6026；7千克=7000克，故700克<7000克；4千克=4000克，故3999克<4000克。",
+        "knowledge_points":  [
+                                 "万以内数的大小比较",
+                                 "克，千克之间的换算与比较"
+                             ],
+        "source":  "24-25 二年级下·山东菏泽·期末"
+    },
+    {
+        "id":  "450",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "小红练习跑步，跑了804米，约( )米，一台电视机标价2998元约为( )元。",
+        "options":  [
+
+                    ],
+        "answer":  "800;3000",
+        "solution":  "【分析】804接近的整百数是800，故,804约是800;2998接近的整千数是3000，故,2998约是3000;据此解决。\n\n【详解】由分析可知：小红练习跑步，跑了804米，约800米，一台电视机标价2998元约为3000元。",
+        "knowledge_points":  [
+                                 "万以内数的估计"
+                             ],
+        "source":  "24-25 二年级下·山东菏泽·期末"
+    },
+    {
+        "id":  "451",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "与5999相邻的两个数分别是( )和( )。",
+        "options":  [
+
+                    ],
+        "answer":  "5998;6000",
+        "solution":  "【分析】根据题意,5999相邻的两个数是用5999-1和5999+1这两数，据此解答。\n\n【详解】根据分析:5999-1=5998,5999+1=6000，与5999相邻的两个数分别是(5998)和(6000)。",
+        "knowledge_points":  [
+                                 "数万以内的数",
+                                 "相邻的数"
+                             ],
+        "source":  "24-25二年级下·山东菏泽·期末"
+    },
+    {
+        "id":  "452",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "用8,6,0,4组成一个四位数，其中最小的数是( ),最大的数是( ),最接近8000的数是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "4068;8640;8046",
+        "solution":  "【分析】最小四位数：千位选最小非零数4，剩余数字按升序排列为0,6,8，得到4068。最大四位数：将数字按从大到小排列，即8,6,4,0，得到8640。最接近8000的数：千位固定为8，剩余数字组成最小的三位数，即0,4,6，得到8046。\n\n【详解】由分析可知：用8,6,0,4组成一个四位数，其中最小的数是4068，最大的数是8640，最接近8000的数是8046。",
+        "knowledge_points":  [
+                                 "万以内数的组成",
+                                 "万以内数的大小比较"
+                             ],
+        "source":  "24-25 二年级下·山东菏泽·期末"
+    },
+    {
+        "id":  "453",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "一个儿童电话手表298元，约是( )元，学校图书馆有《故事书》4050本，约是( )本。",
+        "options":  [
+
+                    ],
+        "answer":  "300;4000",
+        "solution":  "【分析】根据题意，整数的近似数看次高位上的数，用四舍五入的方法取值，比5小直接舍去，大于等于5，舍去进一，三位数的近似数看十位上的数，十位上的数大于等于5舍去，向前一位进一，小于5直接舍去;四位数的近似数看百位上的数，百位上的数小于5直接舍去，百位上的数大于等于5舍去向前一位进一，据此解答。\n\n【详解】根据分析:298≈300,4050≈4000，一个儿童电话手表298元，约是(300)元，学校图书馆有《故事书》4050本，约是(4000)本。",
+        "knowledge_points":  [
+                                 "万以内数的估计"
+                             ],
+        "source":  "24-25二年级下·湖南长沙·期末"
+    },
+    {
+        "id":  "454",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在下面的括号里最大能填几。\n7×( )<46\n78>9×( )\n( )999<9005",
+        "options":  [
+
+                    ],
+        "answer":  "6;8;8",
+        "solution":  "【分析】①②用小于号右侧或大于号左侧的数除以另一侧的已知数，若除不尽，则商是能填的最大的数；若能除尽，则商-1是能填的最大的数。\n③比较两个数时，位数相同，先比较最高位，最高位大的数就大；最高位相同，再比较下一位，直到比较出结果为止。\n\n【详解】46÷7=6……4，则6×7=42，42<46，所以7×(6)<46；78÷9=8……6，则8×9=72，72<78，所以78>9×(8)；两个数位数相同，百位上的数字9>0，所以千位上的数字应小于9，故最大填8，即8999<9005。",
+        "knowledge_points":  [
+                                 "万以内数的大小比较",
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "24-25二年级下·湖北襄阳·期末"
+    },
+    {
+        "id":  "455",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "用6,0,5,8组成一个没有重复数字的四位数，则组成的最大的四位数是( ),最小的四位数是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "8650;5068",
+        "solution":  "【分析】根据题意，用6,0,5,8组成一个没有重复数字的四位数，先把这些数按照从大到小的顺序排列,8>6>5>0，要组成最大的数，把这些数字从大到小排列即可，最高位千位上是最大的数字8，百位上是次大数字6，十位上是第三大数字5，个位上是最小的数字0;要组成最小的四位数，最高位不能为0，最高位千位上是次小的数字5，百位上是最小的数字0，十位上是次大的数字6，个位上是最大的数字8，据此解答。\n\n【详解】根据分析:8>6>5>0，用6,0,5,8组成一个没有重复数字的四位数，则组成的最大的四位数是(8650),最小的四位数是(5068)。",
+        "knowledge_points":  [
+                                 "万以内数的组成",
+                                 "万以内数的大小比较"
+                             ],
+        "source":  "24-25 二年级下·湖北襄阳·期末"
+    },
+    {
+        "id":  "456",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "4734的( )位和( )位都是4;7表示7个( ),3表示3个( )。",
+        "options":  [
+
+                    ],
+        "answer":  "千;个;百;十",
+        "solution":  "【分析】一个整数从右边起，第一位是个位，第二位是十位，第三位是百位，第四位是千位。根据整数的组成，千位上是几表示几个千，百位上是几就表示几个百，十位上是几就表示几个十，个位上是几就表示几个一，据此解答。\n\n【详解】根据分析:4734的(千)位和(个)位都是4;7表示7个(百),3表示3个(十)。",
+        "knowledge_points":  [
+                                 "万以内数的组成"
+                             ],
+        "source":  "24-25 二年级下·湖北襄阳·期末"
+    },
+    {
+        "id":  "457",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "一件衣服原价802元，现价是597元。大约便宜了( )元。",
+        "options":  [
+
+                    ],
+        "answer":  "200",
+        "solution":  "【分析】将802元看作是800元,597看作是600元，用原价减去现价，算出的答案即为大约便宜的金额。\n\n【详解】800-600=200(元),所以，大约便宜了200元。",
+        "knowledge_points":  [
+                                 "万以内数加减法的估算"
+                             ],
+        "source":  "24-25 二年级下·重庆秀山·期末"
+    },
+    {
+        "id":  "458",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "用0,0,3,9四个数字，写出只读一个零的最大的四位数( ),再写出一个零都不读的最小的四位数( )。",
+        "options":  [
+
+                    ],
+        "answer":  "9030;3900",
+        "solution":  "【分析】根据四位数中0的读法规则，只读一个零时需有一个0在中间位置(不在末尾),而一个零都不读时所有0必须在末尾。求最大数时，将高位尽可能大;求最小数时，将高位尽可能小，同时满足0的位置要求。\n\n【详解】千位选最大数字9，剩余数字0,0,3，将0放在百位或十位，使中间出现一个0。最大组合为9030(读作九千零三十),符合只读一个零且数值最大。千位选最小非零数字3，剩余数字0,0,9，将两个0放在末尾，组成3900(读作三千九百),数值最小且不读零。即，用0,0,3,9四个数字，写出只读一个零的最大的四位数9030，再写出一个零都不读的最小的四位数3900。",
+        "knowledge_points":  [
+                                 "万以内数的读，写法",
+                                 "万以内数的组成"
+                             ],
+        "source":  "24-25 二年级下·重庆秀山·期末"
+    },
+    {
+        "id":  "459",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "一个四位数，最高位上的数是3，十位上的数是7，其他数位上的数都是0，这个数是( ),读作( )。",
+        "options":  [
+
+                    ],
+        "answer":  "3070;三千零七十",
+        "solution":  "【分析】万以内数的写法：写数时，从高位写起，几个千就在千位上写几，几个百就在百位上写几，几个十就在十位上写几，几个一就在个位上写几，哪一位上一个数字也没有就写\"0\"占位;万以内数的读法：从高位读起，千位上是几，读作几千;百位上是几，读作几百;十位上是几，读作几十;个位上是几，读作几;末尾的0不读，中间的1个或连续2个0，只读1个零。一个四位数，最高位是千位，千位上写3，百位上写0，十位上写7，个位上写0。据此写数，再根据万以内的读法读出此数。\n\n【详解】根据分析可得：一个四位数，最高位上的数是3，十位上的数是7，其他数位上的数都是0，这个数是3070，读作三千零七十。",
+        "knowledge_points":  [
+                                 "万以内数的读，写法",
+                                 "万以内数的组成"
+                             ],
+        "source":  "24-25 二年级下·重庆秀山·期末"
+    },
+    {
+        "id":  "460",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "小雨骑行了1978米，姐姐骑行了2038米，两人共骑行了约( )米。",
+        "options":  [
+
+                    ],
+        "answer":  "4000",
+        "solution":  "【分析】题目要求估算两人骑行的总路程，先找出每个数最接近的整千数，然后相加即可。\n\n【详解】1978米接近2000米,2038米接近2000米;2000+2000=4000(米)所以，两人共骑行了约4000米。",
+        "knowledge_points":  [
+                                 "万以内数加减法的估算"
+                             ],
+        "source":  "24-25二年级下·湖北黄石·期末"
+    },
+    {
+        "id":  "461",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "用0,0,2,5组成的四位数中，只读一个零的数是( ),一个零也不读的数是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "2005、2050、5002、5020;2500、5200",
+        "solution":  "【分析】根据四位数的组成规则，千位不能为0，因此千位只能是2或5。剩下的三位需包含两个0和一个非零数字。读数时，中间连续两个0或单个的0都只读一个零，末尾的0不读。通过列举所有可能的四位数并验证读法，确定符合条件的数。\n\n【详解】千位为2的情况：2005，读作“两千零五”，中间的0被读出，只读一个零；2050，读作“两千零五十”，中间的0被读出，末尾的0不读，只读一个零；2500，读作“两千五百”，末尾的0不读，一个零也不读。\n千位为5的情况：5002，读作“五千零二”，中间的0被读出，只读一个零；5020，读作“五千零二十”，中间的0被读出，末尾的0不读，只读一个零；5200，读作“五千二百”，末尾的0不读，一个零也不读。\n综上，只读一个零的数为2005、2050、5002、5020；一个零也不读的数为2500、5200。",
+        "knowledge_points":  [
+                                 "万以内数的读，写法",
+                                 "万以内数的组成"
+                             ],
+        "source":  "24-25 二年级下·湖北黄石·期末"
+    },
+    {
+        "id":  "462",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "目前仅存的明朝赵秉忠状元卷全文2460字,2460是一个( )位数，其中\"6\"在( )位上，表示( )个( )。",
+        "options":  [
+
+                    ],
+        "answer":  "四;十;6;十",
+        "solution":  "【分析】数位顺序：从右往左依次为个位，十位，百位，千位。千位是几表示几个千，百位是几表示几个百，十位是几表示几个十，个位是几表示几个一;2460占了个位，十位，百位，千位，共四位;\"6\"在右数第二位，十位上的数表示几个十;据此可解。\n\n【详解】由分析可得：目前仅存的明朝赵秉忠状元卷全文2460字,2460是一个四位数，其中\"6\"在十位上，表示6个十。",
+        "knowledge_points":  [
+                                 "万以内数的组成"
+                             ],
+        "source":  "24-25 二年级下·湖北黄石·期末"
+    },
+    {
+        "id":  "463",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "某小学举办校庆活动，一至三年级一共有816名学生，四至六年级一共有723名学生。每人坐一把椅子，准备1500把椅子( )。(填\"够\"或者\"不够\")",
+        "options":  [
+
+                    ],
+        "answer":  "不够",
+        "solution":  "【分析】根据整数估算的方法，把整数估算成与它相近的整千的数或几千几百的数，据此解答。再将得数和1500进行比较，若大于1500则不够，若小于1500则够。\n\n【详解】816+723≈800+700=1500(名),因为估算的800和700都比实际的人数小，所以估算人数比实际人数少。即实际人数比1500多。所以每人坐一把椅子，准备1500把椅子不够。",
+        "knowledge_points":  [
+                                 "万以内数加减法的估算"
+                             ],
+        "source":  "24-25 二年级下·重庆·期末"
+    },
+    {
+        "id":  "464",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "中国的第二长河是黄河，它全长5464米，它也是世界第五长河。5464是一个( )位数，它的最高位是( )位，这个数是由( )个千,( )个百,( )个十和( )个一组成的。",
+        "options":  [
+
+                    ],
+        "answer":  "四;千;5;4;6;4",
+        "solution":  "【分析】有几个数字就是几位数。整数中，从右到左分别是个位，十位，百位，千位。个位上是几表示几个一，十位上是几表示几个十，百位上是几表示几个百，千位上是几表示几个千。\n\n【详解】中国的第二长河是黄河，它全长5464米，它也是世界第五长河。5464是一个四位数，它的最高位是千位，这个数是由5个千,4个百,6个十和4个一组成的。",
+        "knowledge_points":  [
+                                 "万以内数的组成",
+                                 "整数的数级",
+                                 "数位和计数单位的认识"
+                             ],
+        "source":  "24-25 二年级下·重庆·期末"
+    },
+    {
+        "id":  "465",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "一个四位数，个位和百位上都是0，千位和十位上都是3，这个数是( ),读作( )。",
+        "options":  [
+
+                    ],
+        "answer":  "3030;三千零三十",
+        "solution":  "【分析】一个四位数，从右往左依次是个位，十位，百位，千位，千位上是几就表示几个千，百位上是几就表示几个百，十位上是几就表示几个十，个位上是几就表示几个一。写数时，从高位写起，几个千就在千位上写几，几个百就在百位上写几，几个十就在十位上写几，几个一就在个位上写几，中间或末尾哪一位上一个也没有，就在哪一位上写0占位。读数时，从高位读起，千位是几就读几千，百位是几就读几百，十位是几就读几十，个位是几就读几，中间有一个0或两个0，只读一个\"零\"，末尾不管有几个0，都不读。\n\n【详解】由分析可知：一个四位数，个位和百位上都是0，千位和十位上都是3，这个数是(3030),读作(三千零三十)。",
+        "knowledge_points":  [
+                                 "万以内数的读，写法",
+                                 "万以内数的组成"
+                             ],
+        "source":  "24-25二年级下·天津静海·期末"
+    },
+    {
+        "id":  "466",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "用2,0,7三个数字可以组成( )个不同的三位数，其中最大的是( ),最小的是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "4;720;207",
+        "solution":  "【分析】一个三位数，从右往左依次为个位，十位，百位;组成三位数时，将其中一个数字写在百位(最高位不能是0),另外两个数字分别写在十位，个位，由此写出组成的三位数;比较数的大小时，位数多的数就大，位数相同比较最高位，最高位大的数就大，最高位相同就比较下一位，直到比出大小为止。\n\n【详解】组成的三位数有:207,270,702,720;207<270<702<720;用2,0,7三个数字可以组成4个不同的三位数，其中最大的是720，最小的是207。",
+        "knowledge_points":  [
+                                 "1000以内数的组成",
+                                 "1000以内数的比大小"
+                             ],
+        "source":  "24-25 二年级下·湖南长沙·期末"
+    },
+    {
+        "id":  "467",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "一台空调5000元，一台洗衣机1500元，一台空调比一台洗衣机贵( )元。",
+        "options":  [
+
+                    ],
+        "answer":  "3500",
+        "solution":  "【分析】由题意可知：用一台空调的价钱减去一台洗衣机的价钱即是一台空调比一台洗衣机多出的钱数;据此解答。\n\n【详解】由分析可得:5000-1500=3500(元),一台空调5000元，一台洗衣机1500元，一台空调比一台洗衣机贵3500元。",
+        "knowledge_points":  [
+                                 "万以内的加减法巧算"
+                             ],
+        "source":  "24-25 二年级下·湖南长沙·期末"
+    },
+    {
+        "id":  "468",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在括号里填“>”“<”或“=”。\n45-18( )27\n36÷4( )2×4\n4000+50( )4500",
+        "options":  [
+
+                    ],
+        "answer":  "=;>;<",
+        "solution":  "【分析】根据整数加减法、表内乘除法的计算法则，先计算出算式的得数，再比较大小即可。\n\n【详解】45-18=27，所以45-18=27；36÷4=9，2×4=8，9>8，所以36÷4>2×4；4000+50=4050，4050<4500，所以4000+50<4500。",
+        "knowledge_points":  [
+                                 "100以内数的比大小",
+                                 "万以内数的大小比较",
+                                 "两位数与两位数的退位减法",
+                                 "用7~9的乘法口诀求商"
+                             ],
+        "source":  "24-25二年级下·湖南长沙·期末"
+    },
+    {
+        "id":  "469",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "按规律填数：\n(1)2，3，5，8，12，( )，( )。\n(2)405，410，415，( )，( )。\n(3)720，700，680，( )，( )。",
+        "options":  [
+
+                    ],
+        "answer":  "17;23;420;425;660;640",
+        "solution":  "【分析】(1)根据已知数据可知，后一个数是前一个数依次加1、加2、加3、加4、加5、加6所得，据此计算出后两个数即可；\n(2)观察已知数据可知，后一个数比前一个数多5，从405开始，五个五个正着数，依次填420，425；\n(3)观察已知数据可知，后一个数比前一个数少20，从720开始，二十个二十个地倒着数，依次填660，640。\n\n【详解】(1)12+5=17，17+6=23，所以是2，3，5，8，12，17，23。\n(2)405，410，415，420，425。\n(3)720，700，680，660，640。",
+        "knowledge_points":  [
+                                 "数1000以内的数",
+                                 "整数排列的规律"
+                             ],
+        "source":  "24-25 二年级下·湖南长沙·期末"
+    },
+    {
+        "id":  "470",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "在4705,7450,5047,4750,7054中，最大的是( ),最小的是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "7450;4705",
+        "solution":  "【分析】万以内数比较大小的方法：比较数的大小，先看位数的多少，位数多的数就大;如果位数相同，从最高位开始比较，最高位上的数大则这个数大，最高位上的数相同，就比较下一位，依次类推。找出千位数字最大的数，再比较大小，即可找出最大数;找出千位数字最小的数，再比较大小，即可找出最小数;【详解】比较这几个数的最高位千位数字，千位数字7最大,4最小;7450和7054对比，千位数字相同，比较百位数字,4>0,7450>7054，故最大的数是7450;4750和4705对比，千位百位数字都相同，比较十位数字,5>0,4750>4705，故最小的数是4705;在4705,7450,5047,4750,7054中，最大的是7450，最小的是4705。",
+        "knowledge_points":  [
+                                 "万以内数的大小比较"
+                             ],
+        "source":  "24-25 二年级下·湖南长沙·期末"
+    },
+    {
+        "id":  "471",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "由3个百,6个十和5个一组成的数是( ),读作:( )。",
+        "options":  [
+
+                    ],
+        "answer":  "365;三百六十五",
+        "solution":  "【分析】一个三位数，从右往左依次是个位，十位，百位。几个百就在百位上写几，几个十就在十位上写几，几个一就在个位上写几，据此写数;读数时，从高位读起，百位上是几就读几百，十位上是几就读几十，个位上是几就读几;中间有一个0，读作零，末尾不管几个0，都不读，据此读出这个数。\n\n【详解】根据分析可得：由3个百,6个十和5个一组成的数是365，读作：三百六十五。",
+        "knowledge_points":  [
+                                 "1000以内数的读，写法",
+                                 "1000以内数的组成"
+                             ],
+        "source":  "24-25 二年级下·湖南长沙·期末"
+    },
+    {
+        "id":  "472",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "\"六一\"儿童节新华书店抽奖结果揭晓了，大奖的号码是由7,3,5组成的三位数，这个三位数十位上的数字不是最小的，个位上的数字是最大的，大奖号码是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "357",
+        "solution":  "【分析】由数字7,3,5组成三位数，个位是最大的数字7，十位不是最小的数字3，因此十位只能是5，百位为剩下的3，组合即可。\n\n【详解】\"六一\"儿童节新华书店抽奖结果揭晓了，大奖的号码是由7,3,5组成的三位数，这个三位数十位上的数字不是最小的，个位上的数字是最大的，大奖号码是357。",
+        "knowledge_points":  [
+                                 "1000以内数的读，写法",
+                                 "1000以内数的组成"
+                             ],
+        "source":  "24-25 二年级下·江西赣州·期末"
+    },
+    {
+        "id":  "473",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "按规律填数.\n( ),2050,2100,2150,( )。",
+        "options":  [
+
+                    ],
+        "answer":  "2000;2200",
+        "solution":  "【分析】观察已知数列2050,2100,2150，发现相邻的两数，后一个数比前一个数多50。根据规律，第一个空应填2050的前一个数(2050-50),最后一个空应填2150的后一个数(2150+50)。\n\n【详解】由分析可知:2050-50=2000,2150+50=2200;即,2000,2050,2100,2150,2200。",
+        "knowledge_points":  [
+                                 "整数排列的规律"
+                             ],
+        "source":  "24-25 二年级下·湖南长沙·期末"
+    },
+    {
+        "id":  "474",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "用3,7,0,9四个数字组成不同的四位数。组成的数中最小的是( ),最接近7300的是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "3079;7309",
+        "solution":  "【分析】由题意可知：将四个数字按数位顺序从小到大排列，但0不能放最高位千位上，就和百位数字交换位置，即可组成最小数;组成的数中最接近7300的数，千位上应该是7，百位上是3，然后将剩余数字从小到大排列即可;据此解答。\n\n【详解】用3,7,0,9四个数字组成不同的四位数。组成的数中最小的是3079，最接近7300的是7309。",
+        "knowledge_points":  [
+                                 "万以内数的组成",
+                                 "万以内数的大小比较"
+                             ],
+        "source":  "24-25二年级下·浙江温州·期末"
+    },
+    {
+        "id":  "475",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "7500这个数是由( )个千和( )个百组成的，也可以说是由( )个百组成的。",
+        "options":  [
+
+                    ],
+        "answer":  "7;5;75",
+        "solution":  "【分析】一个四位数，从右往左依次是个位，十位，百位，千位，千位上的数是几表示几个千，百位上的数是几表示几个百，十位上的数是几表示几个十，个位上的数是几表示几个一，哪一位上一个数也没有，用0占位;根据万以内整数的组成，相邻数位之间的进率是10，即10个百是一千，据此解答。\n\n【详解】由分析可得:7500由7个千和5个百组成的，也可以说是由75个百组成的。",
+        "knowledge_points":  [
+                                 "万以内数的组成"
+                             ],
+        "source":  "24-25 二年级下·浙江温州·期末"
+    },
+    {
+        "id":  "476",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "一件上衣298元，一条裤子204元，这套衣服大约要( )元。",
+        "options":  [
+
+                    ],
+        "answer":  "500",
+        "solution":  "【分析】这是一道估算的题，解题思路是把上衣和裤子的售价近似看成整百数，然后相加得到大约需要的钱数。\n\n【详解】298≈300,204≈200,300+200=500(元),这套衣服大约要500元。",
+        "knowledge_points":  [
+                                 "万以内数加减法的估算"
+                             ],
+        "source":  "24-25 二年级下·浙江温州·期末"
+    },
+    {
+        "id":  "477",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "一件上衣697元，一件裤子502元。买一件上衣和一件裤子大约共( )元。",
+        "options":  [
+
+                    ],
+        "answer":  "1200",
+        "solution":  "【分析】买一件上衣和一件裤子的总钱数=上衣的单价+裤子的单价;万以内加减法的估算，把三位数分别看作和它接近的整百，整十数，然后再相加减。\n\n【详解】697≈700,502≈500，则700+500=1200(元)。买一件上衣和一件裤子大约共1200元。",
+        "knowledge_points":  [
+                                 "1000以内数的估计",
+                                 "万以内数加减法的估算"
+                             ],
+        "source":  "24-25 二年级下·浙江温州·期末"
+    },
+    {
+        "id":  "478",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "塘岙底隧道工程南起瑞安市瑞祥新区瑞枫大道文定路口，北至瑞安市塘下镇三都村荣昌路，全长约3810米，横线上的数的最高位在( )位，这位上的\"3\"表示( )个( )。",
+        "options":  [
+
+                    ],
+        "answer":  "千;3;千",
+        "solution":  "【分析】四位数的最高位是千位，四位数千位上的数表示几个千，百位上的数表示几个百，十位上的数表示几个十，个位上的数表示几个一。\n\n【详解】根据分析可知:3810的最高位在千位，这位上的\"3\"表示3个千。",
+        "knowledge_points":  [
+                                 "万以内数的组成"
+                             ],
+        "source":  "24-25 二年级下·浙江温州·期末"
+    },
+    {
+        "id":  "479",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "![](images/5537f2c4aebe07fbf2c8c33b5700a31b265212eb5ec04cc78ddf49a4e978bbc2.jpg)\n![](images/43ccc2e1c51d525b65319f0e06ec8920e7f2ad1242bcf54db403f7a5ae62f6bc.jpg)\n这个数是由( )个千，( )个十和( )个一组成的，写作：( )，读作：( )。",
+        "options":  [
+
+                    ],
+        "answer":  "2;6;4;2064;二千零六十四",
+        "solution":  "【分析】一个四位数，从右往左依次为个位、十位、百位、千位。千位上的数表示几个千，百位上的数表示几个百，十位上的数表示几个十，个位上的数表示几个一。写数时，从高位写起，几个千就在千位上写几，几个百就在百位上写几，几个十就在十位上写几，几个一就在个位上写几，哪一位上一个数字也没有就写0占位。读数时，从高位读起，按照数位顺序读。千位是几就读几千，百位上是几就读几百，十位上是几就读几十，个位上是几就读几，中间有一个0或两个0，只读一个零，末尾不管有几个0，都不读。\n\n【详解】由分析可得：这个数是由2个千、6个十和4个一组成的，写作：2064，读作：二千零六十四。",
+        "knowledge_points":  [
+                                 "万以内数的读，写法",
+                                 "万以内数的组成"
+                             ],
+        "source":  "24-25 二年级下·山东临沂·期末"
+    },
+    {
+        "id":  "480",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "4200里面有( )个百,68个十是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "42;680",
+        "solution":  "【分析】几百里面就有几个百，几千里面就有几十个百，则200里面有2个百,4000里面有40个百，那么4200里面就有42个百;几个十就是几十，几十个十就是几百，则8个十是80,60个十是600，那么68个十就是680。\n\n【详解】由分析可知:4200里面有(42)个百,68个十是(680)。",
+        "knowledge_points":  [
+                                 "1000以内数的组成",
+                                 "万以内数的组成"
+                             ],
+        "source":  "24-25 二年级下·山东临沂·期末"
+    },
+    {
+        "id":  "481",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "下面五个小动物手中各有一个数字。\n![](images/212601.png)\n(1)选择4个数字组成最小的四位数是( )。\n(2)选择4个数字组成最大的四位数是( )。\n(3)选择4个数字组成最接近7000的数是( )。\n(4)组成一个比4000大，比7000小，只读一个0的四位数是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "4007;9740;7004;4097",
+        "solution":  "【分析】(1)一个四位数，从右往左依次为个位、十位、百位、千位。要组成最小的四位数，千位不能为0，则把0以外最小的数字4写在千位，剩下的数字中较小的三个数字，从小到大依次写在百位、十位和个位；\n(2)要组成最大的四位数，则把数字中较大的四个数字，从大到小按数位从高位到低位排列；\n(3)最接近7000的数，千位应为7，剩下的数字中较小的三个数，从小到大依次写在百位、十位和个位；\n(4)读数时，从高位读起，按照数位顺序读。千位是几就读几千，百位是几就读几百。中间有一个0或两个0，只读一个零；末尾不管有几个0，都不读。要组成比4000大，比7000小、只读一个0的数，则千位是4，0可以在中间，也可以在中间和末尾，但是两个0不能同时在末尾。\n\n【详解】(1)选择4个数字组成最小的四位数是4007。\n(2)选择4个数字组成最大的四位数是9740。\n(3)选择4个数字组成最接近7000的数是7004。\n(4)组成一个比4000大，比7000小、只读一个0的四位数是4097。(答案不唯一)",
+        "knowledge_points":  [
+                                 "万以内数的读，写法",
+                                 "万以内数的组成",
+                                 "万以内数的大小比较"
+                             ],
+        "source":  "23-24 二年级下·河南许昌·期末"
+    },
+    {
+        "id":  "482",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在括号里最大能填几。\n( )×6<4150>( )×7\n6687>6( )872500>2( )99",
+        "options":  [
+
+                    ],
+        "answer":  "6;7;5;4",
+        "solution":  "【分析】整数比较大小：先看位数的多少，位数多的数大;位数相同，从最高位比起，最高位上的数大这个数就大，若最高位上的数相同，就比较下一位，依次类推。( )×6<41和50>( )×7通过乘法口诀依次计算，找到满足条件的最大数即可;6687>6( )87和2500>2( )99按照整数比大小的方法找到合适的数填空即可。\n\n【详解】6×6=36,7×6=42,36<41<42，所以括号里最大能填6，即(6)×6<41;7×7=49,8×7=56,56>50>49，所以括号里最大能填7，即50>(7)×7;6687>6( )87，两个数都是四位数，且千位，十位，个位上的数字都相同，要使左边的数大于右边的数，则括号里填的数要小于6，小于6的最大数是5，所以括号里最大能填5，即6687>6(5)87;2500>2( )99，两个数都是四位数，千位上的数字相同，且左边的数十位，个位上的数均小于右边十位和个位上的数，要使左边的数大于右边的数，所以右边百位上的数要小于左边百位上的数5，比5小的最大数是4，所以括号里最大能填4，即2500>2(4)00。",
+        "knowledge_points":  [
+                                 "万以内数的大小比较",
+                                 "6的乘法口诀及应用",
+                                 "7的乘法口诀及应用",
+                                 "8的乘法口诀及应用"
+                             ],
+        "source":  "24-25二年级下·山西长治·期末"
+    },
+    {
+        "id":  "483",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "按规律填空.\n9970,9980,( ),( ),10010。",
+        "options":  [
+
+                    ],
+        "answer":  "9990;10000",
+        "solution":  "【分析】观察可知，数据从左往右依次多10。\n\n【详解】9970,9980,9990,10000,10010。",
+        "knowledge_points":  [
+                                 "数万以内的数",
+                                 "整数排列的规律"
+                             ],
+        "source":  "24-25 二年级下·湖北襄阳·期末"
+    },
+    {
+        "id":  "484",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "用0,2,6,8组成的没有重复数字的四位数中，最大的数是( ),最小的数是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "8620;2068",
+        "solution":  "【分析】一个四位数，从右往左依次为个位，十位，百位，千位。要组成最大的四位数，则把数字从大到小按数位从高位到低位排列;要组成最小的四位数，千位不能为0，则把0以外最小的数写在千位，剩下的数字从小到大依次写在百位，十位和个位。\n\n【详解】0<2<6<8，用0,2,6,8组成的没有重复数字的四位数中，最大的数是8620，最小的数是2068。",
+        "knowledge_points":  [
+                                 "万以内数的组成",
+                                 "万以内数的大小比较"
+                             ],
+        "source":  "24-25 二年级下·湖北襄阳·期末"
+    },
+    {
+        "id":  "485",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "一台液晶电视2980元。这里的2980是由2个( ),( )个百和( )个十组成，读作:( )。",
+        "options":  [
+
+                    ],
+        "answer":  "千;9;8;二千九百八十",
+        "solution":  "【分析】整数中，从右到左分别是个位，十位，百位，千位。个位上是几表示几个一，十位上是几表示几个十，百位上是几表示几个百，千位上是几表示几个千。整数的读法：从高位到低位，一级一级地读，每一级末尾的0都不读出来，其余数位连续几个0都只读一个零。\n\n【详解】一台液晶电视2980元。这里的2980是由2个千,9个百和8个十组成，读作：二千九百八十。",
+        "knowledge_points":  [
+                                 "万以内数的读，写法",
+                                 "万以内数的组成"
+                             ],
+        "source":  "24-25 二年级下·湖北襄阳·期末"
+    },
+    {
+        "id":  "486",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "排序题",
+        "difficulty":  0.85,
+        "question":  "将3062,2603,6032,3260按照从大到小的顺序排一排。",
+        "options":  [
+
+                    ],
+        "answer":  "6032>3260>3062>2603",
+        "solution":  "【分析】比较数的大小，先看位数的多少，位数多的数就大;如果位数相同，从最高位开始比较，最高位上的数大则这个数就大，最高位相同，就比较下一位，以此类推。\n\n【详解】由分析可得:6032千位6最大;2603千位2最小。3260与3062千位相同，比较百位:2>0，故3260>3062。从大到小排列为:6032>3260>3062>2603。",
+        "knowledge_points":  [
+                                 "万以内数的大小比较"
+                             ],
+        "source":  "24-25 二年级下·河南三门峡·期末"
+    },
+    {
+        "id":  "487",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "2320只读一个零。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】万以内数的读法：从高位起，千位上是几就读几，百位上是几就读几，中间有一个0或两个0，只读一个\"零\"，末尾不管有几个0，都不读;2320千位上是2，表示2个千，百位上是3，表示3个百，十位上是2，表示2个十，个位上没有，用0表示，读作二千三百二十。\n\n【详解】2320读作二千三百二十，末尾的0不读。原题说法错误。故答案为: ×",
+        "knowledge_points":  [
+                                 "万以内数的读，写法"
+                             ],
+        "source":  "24-25 二年级下·广东云浮·期末"
+    },
+    {
+        "id":  "488",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "判断题",
+        "difficulty":  0.65,
+        "question":  "读数时中间有一个0或两个0，只读一个零；末尾不管有几个0，都不读。( )",
+        "options":  [
+
+                    ],
+        "answer":  "√",
+        "solution":  "【分析】根据读数规则，读数时要从高位读起，中间无论有一个0还是连续两个0，都只读一个零；末尾的0都不读。\n\n【详解】读数时，中间有一个0或连续两个0，按照规则都只读一个零，例如：4005读作“四千零五”，1020读作“一千零二十”。末尾无论有多少个0均不读，例如：4500读作“四千五百”。原题说法正确。故答案为：√",
+        "knowledge_points":  [
+                                 "万以内数的读，写法"
+                             ],
+        "source":  "24-25 二年级下·广东汕尾·期末"
+    },
+    {
+        "id":  "489",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "读1100和1001这两个数时，都只读一个零。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】根据四位数的读法规则，末尾的零不读，中间连续几个零只读一个。分析1100和1001的读法即可判断。\n\n【详解】1100读作一千一百，末尾的两个零都不读，没有读出\"零\";1001读作一千零一，中间的连续两个零只读一个。因此，原题中\"都只读一个零\"的说法错误。故答案为: ×",
+        "knowledge_points":  [
+                                 "万以内数的读，写法"
+                             ],
+        "source":  "24-25 二年级下·广东汕尾·期末"
+    },
+    {
+        "id":  "490",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "读数和写数都是从最高位开始。( )",
+        "options":  [
+
+                    ],
+        "answer":  "√",
+        "solution":  "【分析】根据整数的读写规则，读数时从最高位开始依次读出各位数字及其计数单位，例如123读作\"一百二十三\";写数时同样从最高位开始依次写出各位数字，例如\"三百零五\"写作305。\n\n【详解】由分析可得：读数和写数都从最高位开始。故答案为:√",
+        "knowledge_points":  [
+                                 "万以内数的读，写法"
+                             ],
+        "source":  "15-16 四年级上·陕西·课后作业"
+    },
+    {
+        "id":  "491",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "8009读作\"八千零九\"。( )",
+        "options":  [
+
+                    ],
+        "answer":  "√",
+        "solution":  "【分析】根据整数的读法规则，从高位到低位，每一级末尾的0不读，中间连续几个0只读一个零。8009的百位和十位均为0，属于连续的两个0，只需读一个\"零\"。\n\n【详解】8009的千位是8，百位和十位是0，个位是9。按照读法规则，中间的连续两个0读作一个\"零\"，因此8009读作\"八千零九\"。题干中的描述正确。故答案为:√",
+        "knowledge_points":  [
+                                 "万以内数的读，写法"
+                             ],
+        "source":  "24-25 二年级下·山东济宁·期末"
+    },
+    {
+        "id":  "492",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "一条隧道长2003米，可看作大约2000米。( )",
+        "options":  [
+
+                    ],
+        "answer":  "√",
+        "solution":  "【分析】根据四舍五入的规则，四舍五入到千位时，需看百位上的数。2003的百位是0，直接舍去,2003≈2000。据此解答。\n\n【详解】2003≈2000，一条隧道长2003米，可看作大约2000米。说法正确。故答案为:√",
+        "knowledge_points":  [
+                                 "万以内数的估计"
+                             ],
+        "source":  "24-25 二年级下·四川乐山·期末"
+    },
+    {
+        "id":  "493",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "5856中的两个\"5\"表示的意义不同。( )",
+        "options":  [
+
+                    ],
+        "answer":  "√",
+        "solution":  "【分析】根据题意，一个整数从右往左依次是个位，十位，百位，千位。同一个数字在不同数位上表示的意义不同。5856中，左边的\"5\"在千位上，表示5个千;右边的\"5\"在十位上，表示5个十，因此意义不同。据此解答。\n\n【详解】根据分析：在5856中，左边的\"5\"位于千位，表示5个千(即5000);右边的\"5\"位于十位上，表示5个十(即50)。两个\"5\"所在的数位不同，表示的意义也不同。原题说法正确，故答案为:√",
+        "knowledge_points":  [
+                                 "万以内数的组成"
+                             ],
+        "source":  "24-25二年级下·山东菏泽·期末"
+    },
+    {
+        "id":  "494",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "计算题",
+        "difficulty":  0.85,
+        "question":  "直接写出得数。\n9×4= 54÷9= 42÷7= 32÷8=\n340+80= 3600-900= 3500-500= 800+700=",
+        "options":  [
+
+                    ],
+        "answer":  "36;6;6;4;420;2700;3000;1500",
+        "solution":  "【分析】根据表内乘除法和整百、整千数加减法，直接口算即可。\n\n【详解】9×4=36，54÷9=6，42÷7=6，32÷8=4，340+80=420，3600-900=2700，3500-500=3000，800+700=1500。",
+        "knowledge_points":  [
+                                 "整百数",
+                                 "几百几十数的加减法口算",
+                                 "9的乘法口诀及应用",
+                                 "用7~9的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·广东汕尾·期末"
+    },
+    {
+        "id":  "495",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "计算题",
+        "difficulty":  0.85,
+        "question":  "口算。\n30÷6= 24÷8= 9×7= 15÷3=\n14÷7= 400+900= 7000-3000= 1000-200=",
+        "options":  [
+
+                    ],
+        "answer":  "5;3;63;5;2;1300;4000;800",
+        "solution":  "【分析】根据表内乘除法和整百、整千数加减法，直接口算即可。\n\n【详解】30÷6=5，24÷8=3，9×7=63，15÷3=5，14÷7=2，400+900=1300，7000-3000=4000，1000-200=800。",
+        "knowledge_points":  [
+                                 "整百数",
+                                 "几百几十数的加减法口算",
+                                 "用2~5的乘法口诀求商",
+                                 "用6的乘法口诀求商",
+                                 "用7~9的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·山西长治·期末"
+    },
+    {
+        "id":  "496",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "7026中的\"7\"在什么数位上。表示多少。",
+        "options":  [
+
+                    ],
+        "answer":  "千位;7000",
+        "solution":  "【分析】根据整数的组成，千位上是几表示几个千，百位上是几表示几个百，十位上是几表示几个十，个位数是几表示几个一，据此解答。\n\n【详解】根据分析:7026中的7在千位上，表示7个千是7000。",
+        "knowledge_points":  [
+                                 "万以内数的组成"
+                             ],
+        "source":  "24-25 二年级下·湖南长沙·期末"
+    },
+    {
+        "id":  "497",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "王奶奶平时以捡破烂为生，她四月份捡了1997个塑料瓶，五月份捡了2003个塑料瓶。王奶奶这两个月一共大约捡了多少个塑料瓶。",
+        "options":  [
+
+                    ],
+        "answer":  "4000个",
+        "solution":  "【分析】根据题意，要求大约数，用四舍五入的方法估算，都是四位数，看百位上的数，百位上的数字大于等于5，舍去向前一位进一，百位上的数字小于5，直接舍去，用加法计算即可。\n\n【详解】根据分析:1997≈2000,2003≈2000,2000+2000=4000(个),答：王奶奶这两个月一共大约捡了4000个塑料瓶。",
+        "knowledge_points":  [
+                                 "万以内数加减法的估算"
+                             ],
+        "source":  "24-25 二年级下·湖北襄阳·期末"
+    },
+    {
+        "id":  "498",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "明明一家去旅游，初步估计住宿费要500多元，往返交通费要900多元，游玩，吃饭等费用要800多元，准备2500元够用吗。为什么。答：准备2500元( )用。",
+        "options":  [
+
+                    ],
+        "answer":  "够;理由见详解",
+        "solution":  "【分析】将500多元看作600元,900多元看作1000元,800多元看作900元，把三笔费用估高后的费用进行相加，比较相加后的数和2500的大小。如果相加后的数或者小于2500，则准备的钱够，反之，则可能不够。\n\n【详解】600+1000+900=1600+900=2500(元),估大的数相加后的数和2500相等，且实际的花费均小于估大的数。答：准备2500元够用。因为每笔费用估大后相加所得的费用正好等于准备的2500元，说明实际花费不足2500元。",
+        "knowledge_points":  [
+                                 "万以内数加减法的估算"
+                             ],
+        "source":  "24-25 二年级下·重庆秀山·期末"
+    },
+    {
+        "id":  "499",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "儿童节这天，野生动物园上午接待了2500名游客，下午比上午少接待了500名，这天野生动物园共接待了多少名游客。",
+        "options":  [
+
+                    ],
+        "answer":  "4500名",
+        "solution":  "【分析】根据题意，先用减法求出下午接待游客的数量，再用上午接待游客的数量加上下午接待游客的数量，即可求出这天野生动物园共接待多少名游客。\n\n【详解】2500-500=2000(名),2500+2000=4500(名),答：这天野生动物园共接待了4500名游客。",
+        "knowledge_points":  [
+                                 "整百数",
+                                 "几百几十数的加减法口算"
+                             ],
+        "source":  "24-25二年级下·江西赣州·期末"
+    },
+    {
+        "id":  "500",
+        "unit":  "第七单元 万以内数的认识",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "爸爸带小南去游玩，汽车上了公路后，小南看到了一个指示牌，这条公路有多长。\n![](images/890e75738538890b3b6ff24ea8942f07.png)",
+        "options":  [
+
+                    ],
+        "answer":  "1500千米",
+        "solution":  "【分析】由题意可知：用离起点的距离加上离终点的距离，等于这条公路的长;据此解答。\n\n【详解】由分析可得:600+900=1500(千米),答：这条公路有1500千米长。",
+        "knowledge_points":  [
+                                 "整百数",
+                                 "几百几十数的加减法口算"
+                             ],
+        "source":  "23-24 二年级下·河南许昌·期末"
+    }
+]
\ No newline at end of file
diff --git "a/\344\272\214\345\271\264\347\272\247\351\242\230\351\233\206/\344\272\214\345\271\264\347\272\247\344\270\213/\344\272\214\345\271\264\347\272\247\344\270\213\347\254\254\344\270\211\345\215\225\345\205\203\345\233\276\345\275\242\347\232\204\350\277\220\345\212\250\357\274\210\344\270\200).json" "b/\344\272\214\345\271\264\347\272\247\351\242\230\351\233\206/\344\272\214\345\271\264\347\272\247\344\270\213/\344\272\214\345\271\264\347\272\247\344\270\213\347\254\254\344\270\211\345\215\225\345\205\203\345\233\276\345\275\242\347\232\204\350\277\220\345\212\250\357\274\210\344\270\200).json"
new file mode 100644
index 0000000000000000000000000000000000000000..e67f82873c1d94aed4e15399abeb2100f3905da4
--- /dev/null
+++ "b/\344\272\214\345\271\264\347\272\247\351\242\230\351\233\206/\344\272\214\345\271\264\347\272\247\344\270\213/\344\272\214\345\271\264\347\272\247\344\270\213\347\254\254\344\270\211\345\215\225\345\205\203\345\233\276\345\275\242\347\232\204\350\277\220\345\212\250\357\274\210\344\270\200).json"
@@ -0,0 +1,8499 @@
+[
+  {
+    "id": "1",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "在日常生活中的下列现象中，你发现( )不属于平移。",
+    "options": [
+      "乘电梯",
+      "风扇转动",
+      "升旗"
+    ],
+    "answer": "B",
+    "solution": "【分析】根据平移的意义，将一个图形沿某个方向移动一定的距离，这种图形运动叫做平移。根据旋转的意义，把一个图形绕某一个点，旋转一定的角度，这种图形运动叫做旋转。\n【详解】A. 乘电梯是平移;B. 风扇转动是旋转，不是平移;C. 升旗是平移。故答案为:B",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "25-26 五年级上·广东韶关·期中"
+  },
+  {
+    "id": "2",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面物体的运动中，是平移的是( )。",
+    "options": [
+      "工作的风扇",
+      "拧水龙头",
+      "乘坐摩天轮",
+      "沿直线滑雪"
+    ],
+    "answer": "D",
+    "solution": "【分析】比如像在平面上推东西、开关抽屉，这些物体都是沿着直线移动，这样的现象叫做平移;像转动方向盘、电扇的转动、旋转木马，这些物体都是绕着一个点或一个轴移动，这样的现象叫做旋转。\n【详解】A. 风扇是绕着一个轴运动的，是旋转现象;B. 拧水龙头是绕着一个轴运动的，是旋转现象;C. 乘坐摩天轮是绕着一个轴运动的，是旋转现象;D. 沿直线滑雪是沿着直线移动，是平移现象。所以是平移的是“沿直线滑雪”。故答案为:D",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "25-26 五年级上·广东佛山·阶段练习"
+  },
+  {
+    "id": "3",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "要想将下图中的三角形ABC平移到三角形DEF的位置，应( ).\n![](images/d3b7d822e6a246f5d1af49eaf669381ffd2c2630eab895d5cd759aa0bcaca993.jpg)",
+    "options": [
+      "三角形ABC先向左平移4格，再向下平移2格",
+      "三角形ABC先向右平移4格，再向下平移2格",
+      "三角形ABC先向右平移4格，再向上平移2格"
+    ],
+    "answer": "C",
+    "solution": "【分析】根据图中可得：图中两个三角形的顶点是A点对应D点，B点对应E点，C点对应F点;可看A点的平移，先向右平移4格，再向上平移2格。B点、C点也是这样的平移路径得到E点、F点。据此可得出答案。\n【详解】将下图中的三角形ABC平移到三角形DEF的位置，应三角形ABC先向右平移4格，再向上平移2格。故答案为:C",
+    "knowledge_points": [
+      "平移与平移现象"
+    ],
+    "source": "24-25 五年级上·广东河源·期中"
+  },
+  {
+    "id": "4",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下列字母中，不是轴对称图形的是( )。",
+    "options": [
+      "![](images/0864b5bb586ec709ae185e899110899d82e522e4cf70be42aabb8480c9de07ad.jpg)",
+      "![](images/397bad3d3106847586d01d9757ec9c1f95084dfd492047ae8294b62a99a162e3.jpg)",
+      "![](images/b4dc8a46ccefa88861c0ef878a9648413254414897b6b8aa8ccf886e0a3ecdcd.jpg)"
+    ],
+    "answer": "B",
+    "solution": "【分析】一个图形沿一条直线对折，直线两旁的图形完全重合，这样的图形叫做轴对称图形，折痕所在的直线是对称轴，由此解答。\n【详解】A. 有对称轴，是轴对称图形;B. 没有对称轴，不是轴对称图形;C. 有对称轴，是轴对称图形。则B不是轴对称图形。故答案为:B",
+    "knowledge_points": [
+      "轴对称的认识及辨认"
+    ],
+    "source": "24-25 二年级下·湖北恩施·期末"
+  },
+  {
+    "id": "5",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面各组图形中经过平移可以重合的是( )。",
+    "options": [
+      "![](images/eda7c6b16750d299508a7c251624bf86baeac8f47d7407b8469d65241f134e4f.jpg)",
+      "![](images/d287c96f4e596c4d97ea3aef10b33206a2ad137ebc9fd2da6ae8ddf567191f55.jpg)",
+      "![](images/acb6da38cfe2a6b6e32bd41807a5aa52ef2f631083615a03da620abd2169e773.jpg)"
+    ],
+    "answer": "A",
+    "solution": "【分析】在平面内沿着某个方向做直线运动，这样的图形运动叫做平移。平移的特征是大小、形状和方向都不变，只有位置发生变化。据此作答。\n【详解】A. 两个图形的大小、形状和方向都不变，只有位置发生变化，符合题意;B. 两个图形的大小、形状相同，但是方向发生了变化，不符合题意;C. 两个图形的大小、形状相同，但是方向发生了变化，不符合题意。故答案为:A",
+    "knowledge_points": [
+      "平移与平移现象"
+    ],
+    "source": "24-25 三年级上·山东济南·期中"
+  },
+  {
+    "id": "6",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面( )不是轴对称图形。",
+    "options": [
+      "![](images/0864b5bb586ec709ae185e899110899d82e522e4cf70be42aabb8480c9de07ad.jpg)",
+      "![](images/397bad3d3106847586d01d9757ec9c1f95084dfd492047ae8294b62a99a162e3.jpg)",
+      "![](images/b4dc8a46ccefa88861c0ef878a9648413254414897b6b8aa8ccf886e0a3ecdcd.jpg)"
+    ],
+    "answer": "B",
+    "solution": "【分析】一个图形沿一条直线对折，直线两旁的图形完全重合，这样的图形叫做轴对称图形，折痕所在的直线是对称轴，由此解答。\n【详解】A. 有对称轴，是轴对称图形;B. 没有对称轴，不是轴对称图形;C. 有对称轴，是轴对称图形。则B不是轴对称图形。故答案为:B",
+    "knowledge_points": [
+      "轴对称的认识及辨认"
+    ],
+    "source": "24-25 二年级下·云南文山·期末"
+  },
+  {
+    "id": "7",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下列运动中，不是旋转现象的是( )。",
+    "options": [
+      "![](images/ab81a648f68f4703e9ca505642cd0dd43b76d3ec3f8dfa3c94df89ccba19a6a2.jpg)",
+      "![](images/771b1158cdf5db62502de3e22afdf13579ebc034ffc2da394721ebb1f4cce083.jpg)",
+      "![](images/f6f7d115d0b8677c6f9b8a4274ea1134ee9a1a130f85a8b19a3ef7f5e4e06ba1.jpg)"
+    ],
+    "answer": "A",
+    "solution": "【分析】平移是指物体在平面内沿着某个方向移动，移动过程中物体的形状、大小和方向都不发生变化。平移可以看作是物体在平面内的“滑动”。旋转是指物体绕着一个固定点(旋转中心)转动，转动过程中物体的形状和大小不变，但方向会发生变化。\n【详解】A. 在平面内的“滑动”，是平移运动，符合题意;B. 是绕着一个固定点转动，则属于旋转运动，不符合题意;C. 是绕着一个固定点转动，则属于旋转运动，不符合题意。故答案为:A",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "24-25 二年级下·山西阳泉·期末"
+  },
+  {
+    "id": "8",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面现象中,( )不是旋转。",
+    "options": [
+      "![](images/b59a2d55215941902080b0797ec886d89063e74c26170a90a3aa21d7328efffd.jpg)",
+      "![](images/4f06f71efa4320c9872f5a65bc977ebe2a48343aef3b4e4e94741e32eaccbe0c.jpg)",
+      "![](images/ebb22c1a00193275b7369be1b09988b04a54aeb610772c247f32683f747d3453.jpg)"
+    ],
+    "answer": "A",
+    "solution": "【分析】平移：在平面内，将一个图形上的所有点都按照某个方向作相同距离移动的图形运动。平移后图形的位置改变，形状、大小、方向不变。旋转：在平面内，将一个图形绕一点按某个方向转动一定的角度，这样的运动叫做图形的旋转。旋转前后图形的位置和方向改变，形状、大小不变。据此解答即可。\n【详解】A. 窗户的移动是平移运动;B. 风车的转动是旋转运动;C. 时针和分针的运动是旋转运动。故答案为:A",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "24-25 二年级下·山东菏泽·期末"
+  },
+  {
+    "id": "9",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下列运动中，不是旋转的是( )。",
+    "options": [
+      "![](images/d114b00f92acd4cffd58a46cd06317861c1b35bf7c3775be51ee188307a00b94.jpg)",
+      "![](images/eb02d172fe55c3f83235f1a2a5fd7e62a0a044db4924bbee170c5ec0dd275823.jpg)",
+      "![](images/9b01051f5e5fea9b4b47fa3aec8d53d285f3135ed85b858aa7854bf2e1a70fb4.jpg)"
+    ],
+    "answer": "A",
+    "solution": "【分析】平移是指在平面内将一个图形上的所有点都按照某个直线方向做相同距离的移动，这样的运动叫做图形的平移运动。旋转是指在平面内将一个图形绕一点按某个方向转动一个角度，这样的运动叫做图形的旋转运动。据此逐项分析每个选项。\n【详解】A. 属于平移;B. 属于旋转;C. 属于旋转。故答案为:A",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "24-25 二年级下·河北保定·期末"
+  },
+  {
+    "id": "10",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "小兰用纸折了一棵\"树\"，下面( )通过平移可以和右边的\"树\"重合。\n![](images/4eb3a04c4aa923948a693e131f4cf7322efbdb22eafb658375a6a86924c8c3dc.jpg)",
+    "options": [
+      "![](images/c188841115caf6263e91f23bd7be52deb2f9b74925dff16831127c1199c04a0a.jpg)",
+      "![](images/5bdcee25d797d894d50912bc061a7b7d0537f48237f0813a6f15cf8646f5adec.jpg)",
+      "![](images/8add2ff0af02e1d066b613f0f69fcc84c8196e0a28c6f689f28c8ce6885bb56b.jpg)"
+    ],
+    "answer": "A",
+    "solution": "【分析】平移：在平面内，将一个图形上的所有点都按照某个方向作相同距离移动的图形运动。平移后图形的位置改变，形状、大小、方向不变。旋转：在平面内，将一个图形绕一点按某个方向转动一定的角度，这样的运动叫做图形的旋转。旋转前后图形的位置和方向改变，形状、大小不变。据此解答即可。\n【详解】A. 通过平移可以和题干中的“树”重合;B. 通过旋转可以和题干中的“树”重合;C. 通过旋转可以和题干中的“树”重合。故答案为:A",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "24-25 二年级下·广东汕头·期末"
+  },
+  {
+    "id": "11",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "手工社团心灵手巧的同学们正在做手工。下面是他们剪出的一些图形，其中不是轴对称图形的是( )。",
+    "options": [
+      "![](images/2f422399fa2e4bb9f1fc9cbec6a985d5ca8f6238de3b22334ac68d13a491d03d.jpg)",
+      "![](images/c6716b3e2c0ac580a51406fb4f973fff6e618c677b2473e7ace93f2edf3bf9c6.jpg)",
+      "![](images/0947c5576bb09f191dd6f6339c19ce6ece275b0512619a3c28248711fbd4896e.jpg)"
+    ],
+    "answer": "C",
+    "solution": "【分析】轴对称：如果一个图形沿着一条直线对折，两侧的图形能够完全重合，这个图形就是轴对称图形。根据轴对称图形的定义进行解答即可。\n【详解】A. 是轴对称图形;B. 是轴对称图形;C. 不是轴对称图形。故答案为:C",
+    "knowledge_points": [
+      "轴对称的认识及辨认"
+    ],
+    "source": "24-25 二年级下·广东汕头·期末"
+  },
+  {
+    "id": "12",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面是小朋友绘制的三幅作品，分别代表二十四节气中的\"芒种\"，\"谷雨\"和\"大雪\"，其中是轴对称图形的是( )。",
+    "options": [
+      "![](images/b7ad9ba3a23e84f10b11b6cb3f2a768dbfb12f4c724197d8cec3a71cc2d523f8.jpg)",
+      "![](images/6bff887fbe3114209b0078de7f87c08ae85ad9cd206b300dcac27a736c07518c.jpg)",
+      "![](images/5e4f235537e7a7057235c72d1e95f7c77a25c3ae99454fe660122d097978a5b9.jpg)"
+    ],
+    "answer": "C",
+    "solution": "【分析】轴对称图形的定义：如果一个图形沿着一条直线对折后两部分完全重合，那么这样的图形就叫做轴对称图形。\n【详解】A. 不是轴对称图形;B. 不是轴对称图形;C. 是轴对称图形。故答案为:C",
+    "knowledge_points": [
+      "轴对称的认识及辨认"
+    ],
+    "source": "24-25 二年级下·贵州铜仁·期末"
+  },
+  {
+    "id": "13",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "甲骨文是中国的一种古代文字，是汉字的早期形式，下面哪个汉字( )不是轴对称图形。",
+    "options": [
+      "![](images/ae10cc93b91d9a83fdffac3734fd1e3a21769661100ccf10fbb17aed0b4bf0b5.jpg)",
+      "![](images/8af132ba6e74afd588748a68f916956bc1cdc62a025dddeb57a92aa6529beaca.jpg)",
+      "![](images/46da26bcf80ffa19e8ee29ea56334d62bac36268434f0e95efa49ee3530f8bd3.jpg)"
+    ],
+    "answer": "C",
+    "solution": "【分析】依据轴对称图形的概念，在平面内，如果沿着一条直线折叠，直线两旁的部分能够完全重合，这样的图形叫轴对称图形。A:沿竖中线左右对折后，两边能完全重合，是轴对称图形;B:沿竖中线左右对折后，两边能完全重合，是轴对称图形;C:沿竖中线左右对折后，两边不能完全重合，不是轴对称图形。据此可选择.\n【详解】由分析可得：甲骨文是中国的一种古代文字，是汉字的早期形式，下面汉字C不是轴对称图形。故答案为:C",
+    "knowledge_points": [
+      "轴对称的认识及辨认"
+    ],
+    "source": "24-25 二年级下·四川南充·期末"
+  },
+  {
+    "id": "14",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "钟面上的时针和分针都在做( )运动。",
+    "options": [
+      "轴对称",
+      "平移",
+      "旋转"
+    ],
+    "answer": "C",
+    "solution": "【分析】平移：在平面内，将一个图形上的所有点都按照某个方向作相同距离移动的图形运动。平移后图形的位置改变，形状，大小，方向不变。旋转：在平面内，将一个图形绕一点按某个方向转动一定的角度，这样的运动叫做图形的旋转。旋转前后图形的位置和方向改变，形状，大小不变。据此解答即可.\n【详解】据分析可知：钟面上的时针和分针都在做旋转运动。故答案为:C",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "24-25 二年级下·广东江门·期末"
+  },
+  {
+    "id": "15",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面的字母中,( )不是轴对称图形。",
+    "options": [
+      "N",
+      "M",
+      "E"
+    ],
+    "answer": "A",
+    "solution": "【分析】一个平面图形沿着一条直线对折后，直线两旁的部分能够互相重合，这个图形叫做轴对称图形，这条直线是图形的对称轴。判断一个图形是否是轴对称图形，关键是看在这个图形中能否找到一条直线(对称轴)，让图形沿着这条直线对折后能够完全重合。\n【详解】A. N 找不到对称轴，不是轴对称图形;B. M 可以从中间竖着画一条对称轴，是轴对称图形;C. E 可以从中间横着画一条对称轴，是轴对称图形。故答案为:A",
+    "knowledge_points": [
+      "轴对称的认识及辨认"
+    ],
+    "source": "24-25 二年级下·四川成都·期末"
+  },
+  {
+    "id": "16",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "下面图形中,( )是轴对称图形。",
+    "options": [
+      "![](images/0d285194526e4b9991dc8052111e454a3129d572988257dc24286b1cfa1dc4e2.jpg)",
+      "![](images/8369507266c504d2364768d5fe277cd9ac1cd7c2808a2dcdfa4d181f57882150.jpg)",
+      "![](images/a5ec89bef4c4dcc2f55619f758a014daaa1b10048d6d4911d88a4048403f7877.jpg)"
+    ],
+    "answer": "C",
+    "solution": "【分析】如果一个图形沿着一条直线对折后两部分完全重合，这样的图形叫做轴对称图形，判断给定图形是否为轴对称图形需要找该图形是否存在这样的一条直线.\n【详解】A。 观察选项的图形，找不到一条直线，使图形沿着这条直线对折后两部分完全重合，所以选项A不是轴对称图形;B. 观察选项的图形，找不到一条直线，使图形沿着这条直线对折后两部分完全重合，所以选项B不是轴对称图形;C. 观察选项的图形，能找到一条水平方向的直线，使图形沿着这条直线对折后两部分完全重合，所以选项C是轴对称图形。故答案为:C",
+    "knowledge_points": [
+      "轴对称的认识及辨认"
+    ],
+    "source": "25-26 三年级上·黑龙江佳木斯·开学考试"
+  },
+  {
+    "id": "17",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "下面各图标展示了宁波地区著名的旅游打卡点，其中不是轴对称图形的是( )。",
+    "options": [
+      "![](images/6aab432948524ec52ad46b5943d17d6a145319ba265fcc98ca5dfe5babebd0e5.jpg)",
+      "![](images/450f4ca0f12eab36e418f87bcfda894fe0d5c14b05074b09b80f4e289fd1ab54.jpg)",
+      "![](images/3ec5d42c24472e21974763b564824470718c54bcd080038e2c7f6fe9a5f815f6.jpg)",
+      "![](images/9b55797d48bb9a4a26d99f1686d900f553e058b3f75de98ae80b91050b023a50.jpg)"
+    ],
+    "answer": "D",
+    "solution": "【分析】轴对称图形：如果一个图形沿着一条直线对折，直线两边的图形能够完全重合，这样的图形叫作轴对称图形.\n【详解】A:天封塔沿着图形正中间那条直线对折，直线两边的图形能够完全重合，为轴对称图形;B:鼓楼沿着图形正中间那条直线对折，直线两边的图形能够完全重合，为轴对称图形;C:天一阁沿着图形正中间那条直线对折，直线两边的图形能够完全重合，为轴对称图形;D:宁波博物馆无论沿着哪条直线对折，直线两边的图形都无法重合，所以宁波博物馆不是轴对称图形。故答案为:D",
+    "knowledge_points": [
+      "轴对称的认识及辨认"
+    ],
+    "source": "2025·浙江宁波·小升初真题"
+  },
+  {
+    "id": "18",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面是几种汽车的标志，在这几个标志图案中是轴对称图形的有( ).\n![](images/cae65e2dfe65913cca958431d437a1e4b838e6d4ce086ca481d83a4ed0d635f4.jpg)\n![](images/46df028efaef0f933889d35ea76a158416e4ca8f46588ea5a01102ebcbb00d46.jpg)\n![](images/2a41d45c88aa4ae14f4915fc40d18a71cc37df342c8d3bffc64d9c0ce332956e.jpg)\n![](images/a110d4322330ca8560c588e74565cd797d89c3ccd99956010290b79a587a766e.jpg)",
+    "options": [
+      "1个",
+      "2个",
+      "3个",
+      "4个"
+    ],
+    "answer": "C",
+    "solution": "【分析】如果一个图形沿着一条直线对折后两部分完全重合，这样的图形叫做轴对称图形，这条直线叫做对称轴。据此分析各图形，进而确定正确答案.\n【详解】第一个图形：无论沿着哪条直线对折，两部分都不能完全重合，不是轴对称图形;第二个图形：沿着中间竖直的直线对折后，两部分能够完全重合，是轴对称图形;第三个图形：沿着中间竖直的直线对折后，两部分能够完全重合，是轴对称图形;第四个图形：沿着中间竖直的直线对折后，两部分能够完全重合，是轴对称图形。所以轴对称图形有3个。故答案为:C",
+    "knowledge_points": [
+      "轴对称的认识及辨认"
+    ],
+    "source": "24-25 六年级下·河南新乡·期末"
+  },
+  {
+    "id": "19",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "在我们的生活当中，会遇到下列这些现象。通过我们学到的知识，判断( )是平移现象。",
+    "options": [
+      "车轮转动",
+      "电梯上升",
+      "电风扇转动"
+    ],
+    "answer": "B",
+    "solution": "【分析】在平面内，一个图形整体沿着某条直线方向平行移动一定距离的过程，称为平移;在平面内，一个图形围绕某一个固定点按照顺时针或逆时针方向转动一定角度的过程，称为旋转.\n【详解】A。 \"车轮转动\"是旋转现象，不符合题意;B. \"电梯上升\"是平移现象，符合题意;C. \"电风扇转动\"是旋转现象，不符合题意。故答案为:B",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "24-25 二年级下·云南昭通·期中"
+  },
+  {
+    "id": "20",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面( )的运动是旋转。",
+    "options": [
+      "推拉门",
+      "风扇转动",
+      "电梯上下"
+    ],
+    "answer": "B",
+    "solution": "【分析】在平面内，一个图形绕着一个定点旋转一定的角度得到另一个图形的变化叫做旋转;平移是指在同一个平面内，如果一个图形上的所有点都按照某个直线方向做相同距离的移动，那么这样的图形运动就叫做图形的平移运动，简称平移，平移不改变图形的形状和大小;依此选择.\n【详解】A。 推拉门的运动是平移;B. 风扇转动的运动是旋转;C. 电梯上下的运动是平移。故答案为:B",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "25-26 三年级上·黑龙江鹤岗·开学考试"
+  },
+  {
+    "id": "21",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "如图的图形中，轴对称图形有( )个.\n![](images/30d77de7dd8486837c5ee77d3bd53e92549b17f9dd7c8dcba3b24fd2c1703d23.jpg)\n![](images/5e63c1420ea529591093ed87e22bb05008d1528bce113e1aa212865a1ee6ace5.jpg)\n![](images/b2a245072eabb91b33146612a4d877c6722fd4d40c4915034373711df0646657.jpg)\n![](images/147dd9ce0c53cfa984c33c0906d8e6b6902efb57150fe45ee7613cb727f7c70f.jpg)",
+    "options": [
+      "4",
+      "3",
+      "2",
+      "1"
+    ],
+    "answer": "B",
+    "solution": "【分析】如果一个图形沿着一条直线对折，直线两边的图形能够完全重合，这样的图形叫轴对称图形，这条直线叫对称轴，据此结合题意分析解答即可.\n【详解】第一个图形：沿着中间竖直的直线对折后，两部分能够完全重合，是轴对称图形;第二个图形：沿着中间竖直的直线对折后，两部分能够完全重合，是轴对称图形;第三个图形：无论沿着哪条直线对折，两部分都不能完全重合，不是轴对称图形;第四个图形：沿着中间竖直的直线对折后，两部分能够完全重合，是轴对称图形。所以轴对称图形有3个，分别是第一个，第二个和第四个图形。故答案为:B",
+    "knowledge_points": [
+      "轴对称的认识及辨认"
+    ],
+    "source": "24-25 六年级下·湖南长沙·期末"
+  },
+  {
+    "id": "22",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "交通标志在道路交通方面发挥着重要作用，以下交通标志是轴对称的是( )。",
+    "options": [
+      "![](images/1d6653af3fdd921cb15892cd2aeea51a92d7edb3cfff8e9fe91a4a55a98f256f.jpg)",
+      "![](images/c29c2a07e3e96bf307ffeb096a6bfc506f1d12628c9404835da0990ff07b42a2.jpg)",
+      "![](images/8e589b5a0546d494be394d277ed63ff321bd37ceefc0e9fdfd8deea110c42305.jpg)"
+    ],
+    "answer": "B",
+    "solution": "【分析】一个图形沿着一条直线折叠，直线两侧的部分能够完全重合，这样的图形就是轴对称图形，据此解题.\n【详解】A。 此图形不是轴对称图形，找不到一条直线折叠能够使两边完全重合;B. 此图形是轴对称图形，对称轴如下图;C. 此图形不是轴对称图形，找不到一条直线折叠能够使两边完全重合。故答案为:B",
+    "knowledge_points": [
+      "轴对称的认识及辨认"
+    ],
+    "source": "24-25 三年级下·内蒙古包头·期末"
+  },
+  {
+    "id": "23",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "在下面图形中,( )不是轴对称图形。",
+    "options": [
+      "![](images/e97f969b744d9e4304ec0151c61fe65d807bf453ac2144bb7e699315a5d31130.jpg)",
+      "![](images/afa46667ce752e37f3982627d233e482ca0d190e5bcc1121476b8bc9e22e4e4b.jpg)",
+      "![](images/622ba95bf3a0d53aaf62aa99c4e9b6f48afdee0c74c0b258a9e715557593b157.jpg)"
+    ],
+    "answer": "C",
+    "solution": "【分析】如果一个平面图形沿一条直线折叠，直线两旁的部分能够完全重合，这个图形就叫做轴对称图形。据此解答.\n【详解】A。 ![](images/e40c0f78d713721a2fd301931e0563cfddbe3a30a769601ad1dd8fa2c404c273.jpg) 左右(或上下)对折后能够完全重合，故此图是轴对称图形;B. 上下对折后能够完全重合，故此图是轴对称图形;C. 无论如何对折，都不能完全重合，故此图不是轴对称图形。故答案为:C",
+    "knowledge_points": [
+      "轴对称的认识及辨认"
+    ],
+    "source": "24-25 二年级下·湖北孝感·期末"
+  },
+  {
+    "id": "24",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面的图形不是轴对称图形的是( )。",
+    "options": [
+      "![](images/ca08a7ae3501ea70b7019561aa91a40c3c404856cd57ee17262ca68c36d2b745.jpg)",
+      "![](images/86c481815ab054cc252997a7e272e71b32e8dfa02368f013eb8de1c2a905d3e7.jpg)",
+      "![](images/ca8893832156051e898f145f2a7227ca0299cb3d39947ac0d734f1d20846a1ca.jpg)"
+    ],
+    "answer": "B",
+    "solution": "【分析】一个图形沿一条直线对折，直线两旁的图形完全重合，这样的图形叫做轴对称图形，折痕所在的直线是对称轴，由此解答.\n【详解】A。 有对称轴，是轴对称图形;B. 没有对称轴，不是轴对称图形;C. ![](images/a0d524a6ace4e2880259a070cd1a90e04216b6b8d82111734c6715516e942571.jpg) 有对称轴，是轴对称图形。故答案为:B",
+    "knowledge_points": [
+      "轴对称的认识及辨认"
+    ],
+    "source": "24-25 二年级下·浙江台州·期末"
+  },
+  {
+    "id": "25",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面有( )个轴对称图形。\n![](images/e5c474c3b04eaa4baa0857b22e53a5b23e5d6e72c7ba39c85e9e4360d3a86cad.jpg)\n![](images/aaf799bfb0c4c8b47598a92125bfee66b5f59d2b28af14fb93d4a5585c48c255.jpg)\n![](images/360b4da6d12d7fd70b54925274073bb9db5e39b2271039ac2b9a6acdd7d994fc.jpg)\n![](images/f35dbe934c5c56d23d096b6efdf441de8f54b10a8a0a5abf3e8b969f32614b4e.jpg)",
+    "options": [
+      "1",
+      "2",
+      "3",
+      "4"
+    ],
+    "answer": "B",
+    "solution": "【分析】依据轴对称图形的定义判断：平面内，一个图形沿一条直线折叠，直线两旁的部分能够完全重合，这个图形就是轴对称图形;其中的这条直线就是对称轴。逐项分析各个图形，找出哪些图形是轴对称图形，数出它们的数量即可。\n【详解】图1左右或上下对折后，两侧能完全重合，是轴对称图形;图4左右对折后，两侧能完全重合，是轴对称图形。图1、图4是轴对称图形，共2个轴对称图形，其余不是轴对称图形。故答案为:B",
+    "knowledge_points": [
+      "轴对称的认识及辨认"
+    ],
+    "source": "24-25 二年级下·浙江湖州·期末"
+  },
+  {
+    "id": "26",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面的现象中，是平移的是( )。",
+    "options": [
+      "![](images/cadb98bf6c0d4c352d1d8124d965b7d823bc003fd28246ec668ba1fec702c37b.jpg)",
+      "![](images/96c3ec4cf70b3c177b04b331b1ff0f5b2292b0f64343ec7594c3fb9c2579ed8c.jpg)",
+      "![](images/be55be2d4f4cc3e66b51e22a0b8343a3ec4e93de17bb7f7ef1b7d8eacb6b9913.jpg)",
+      "![](images/dab4bed90634a9bb9502738829572a446ba2afdc967c1f12bf2ba88b4e96bea5.jpg)"
+    ],
+    "answer": "B",
+    "solution": "【分析】在平面内，把一个图形整体沿某条直线方向平行移动一定距离的过程，称为平移。常见的平移现象有滑滑梯，电梯的移动等;在平面内，把一个图形围绕某一固定点按顺时针或逆时针方向转动一定的角度的过程，称为旋转。常见的旋转现象有旋转木马，摩天轮等。逐项分析各个选项，找出是平移现象的选项即可.\n【详解】A。 是旋转现象;B. 是平移现象;C. 是旋转现象;D. 是旋转现象。故答案为:B",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "24-25 二年级下·浙江湖州·期末"
+  },
+  {
+    "id": "27",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面的图形中，轴对称图形有( )个.\n![](images/image.png)",
+    "options": [
+      "2",
+      "3",
+      "4"
+    ],
+    "answer": "A",
+    "solution": "【分析】一个图形沿着一条直线对折后，直线两旁的部分能够完全重合，这样的图形就叫做轴对称图形，据此解答.\n【详解】第一个图形不是轴对称图形;第二个图形不是轴对称图形;第三个图形是轴对称图形;第四个图形不是轴对称图形;第五个图形不是轴对称图形;第六个图形是轴对称图形。因此，是轴对称图形的有第三个和第六个，共2个。故答案为:A",
+    "knowledge_points": [
+      "轴对称的认识及辨认"
+    ],
+    "source": "24-25 二年级下·福建厦门·期末"
+  },
+  {
+    "id": "28",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面属于轴对称图形的有( )个。\n![](images/82b642953b307941c5407f09c39462365260c1efc9204e303f75625f45368a6e.jpg)\n![](images/2fecc0501f578b881fcef71ae27d5776f6cb07c2bacbc947066d832eff86e908.jpg)\n![](images/cf84c3a1824b916f21dd364cd2b57cd43b987b26d1c1b777c0d8c233e10d7344.jpg)\n![](images/f66d482879f653614f1c2788dd99de2fcf0ffba350e3ee618af0c7b4f4416e45.jpg)",
+    "options": [
+      "1",
+      "2",
+      "3",
+      "4"
+    ],
+    "answer": "B",
+    "solution": "【分析】如果一个平面图形沿着一条直线对折后，直线两旁的部分能够互相重合，那么这个图形叫做轴对称图形，这条直线是图形的对称轴，据此解答。\n【详解】由分析可得：属于轴对称图形的有2个。故答案为:B",
+    "knowledge_points": [
+      "轴对称的认识及辨认"
+    ],
+    "source": "24-25 二年级下·浙江台州·期末"
+  },
+  {
+    "id": "29",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下图中，( )是轴对称图形。",
+    "options": [
+      "![](images/d2586ce33472b1fe081dff622710a33b1c2177d73885ab9140e854c4c521abe6.jpg)",
+      "![](images/ed3c01e909557c14920dfb0c17ceaa9b1c154339ba221541098a2b554c7202d8.jpg)",
+      "![](images/76e0004df32c6c92efe480060dd1f9ff9ecd078098d0765cbfed5b56bfc9c040.jpg)"
+    ],
+    "answer": "B",
+    "solution": "【分析】在平面内，如果沿着一条直线折叠，直线两旁的部分能够完全重合，这样的图形叫轴对称图形。据此解答。\n【详解】A. 任意两旁沿着一条直线折叠后都不能完全重合，故此图不是轴对称图形;B. 左右两旁沿着一条直线折叠后能够完全重合，故此图是轴对称图形;C. 任意两旁沿着一条直线折叠后都不能完全重合，故此图不是轴对称图形。故答案为:B",
+    "knowledge_points": [
+      "轴对称的认识及辨认"
+    ],
+    "source": "24-25 二年级下·山东菏泽·期中"
+  },
+  {
+    "id": "30",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下列图形中，( )不是由原图旋转得到的。\n![](images/47672d9b6c0ea43e287482f16afb8c0390e0e7bf7d2d594eef5ea28219786459.jpg)",
+    "options": [
+      "![](images/a2a5d5e711d4bb51b7ad6952a26197de945360198b1c911c321a42a1c605bebb.jpg)",
+      "![](images/c33c56656fe7b5274a5bbdfa3d78e3d57ed8a44f56c8877e12be7781e4e7dd81.jpg)",
+      "![](images/95d240aae846d18b019b8c1a962101bf36061fe285f3843a89c50c6042831f4d.jpg)"
+    ],
+    "answer": "B",
+    "solution": "【分析】在平面内，把一个图形围绕某一固定点按顺时针或逆时针方向转动一定的角度的过程，称为旋转，据此解答。\n【详解】由分析可得：A是由原图按顺时针方向转动90°得到的图形，不符合题意;B不是由原图旋转得到的图形，符合题意;C是由原图按逆时针方向转动90°得到的图形，不符合题意。故答案为:B",
+    "knowledge_points": [
+      "旋转与旋转现象"
+    ],
+    "source": "24-25 二年级下·山东菏泽·期中"
+  },
+  {
+    "id": "31",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "下面图案( )是由原图通过平移拼成的。\n![](images/a90b5d64b316ad181f258f549f1e9ad7b600ba11b56e71a927b7814854fa071e.jpg)",
+    "options": [
+      "![](images/44e36bdb3bf3086453503659f80256141059c274a3ddb694a857d5b6fb814977.jpg)",
+      "![](images/75383959225e189f67f43c4902305fdce042603831717da86cdd3d575c68a561.jpg)",
+      "![](images/8c37eb6ff13b85b1b27b55948c3fc4057db8380b13ac42d3bb65510c0b50cf80.jpg)"
+    ],
+    "answer": "A",
+    "solution": "【分析】根据图形平移的特征，将一个图形上的所有点都按照某个方向作相同距离的移动，这样的图形运动叫作图形的平移。平移不改变图形的形状、大小和方向，平移可以是水平的，也可以是垂直的。\n【详解】由分析可知：A与原图案方向相同，是原图平移后的图形;B与原图案方向不同，是原图平移再旋转后的图形;C与原图左右方向相反，是原图平移再旋转后的图形。故答案为:A",
+    "knowledge_points": [
+      "平移与平移现象"
+    ],
+    "source": "24-25 二年级下·江西九江·期中"
+  },
+  {
+    "id": "32",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面图形不是轴对称图形的是( )。",
+    "options": [
+      "![](images/6d6fac643645b6dc9d4882d27a00bd75ed263b8db3e8fc6babcd82683782fcbf.jpg)",
+      "![](images/9710498b0fd0ea9cd5885d154064b550ddaa7caef2a57e0a55eb6b53eefc6e80.jpg)",
+      "![](images/7167e80210ea19c38fa9e801197ce41a76418833b7405598fc9e76f5fde3229d.jpg)"
+    ],
+    "answer": "B",
+    "solution": "【分析】依据轴对称图形的定义判断：平面内，一个图形沿一条直线折叠，直线两旁的部分能够完全重合，这个图形就是轴对称图形;其中的这条直线就是对称轴。\n【详解】A. 沿着图中的直线对折，直线两旁的部分能够完全重合，它是轴对称图形;B. 不管沿着哪条直线对折，对折后两侧的图形都不能完全重合，它不是轴对称图形;C. 沿着图中的直线对折，直线两旁的部分能够完全重合，它是轴对称图形。不是轴对称图形的是B。故答案为:B",
+    "knowledge_points": [
+      "轴对称的认识及辨认"
+    ],
+    "source": "24-25 二年级下·浙江杭州·期末"
+  },
+  {
+    "id": "33",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面选项中,( )是平移现象。",
+    "options": [
+      "![](images/2fcbd7c9702406ac18dcb4fe893002e6ae32c20d4e784e967389f6fc4832916c.jpg) 缆车的运动",
+      "![](images/7bf0e987843e18a2b0669fa2d22c66b85b7daf05b0bb2c84a51eec6399a426d9.jpg) 螺旋桨的运动",
+      "![](images/29d91d78394357e90f784bd69a04e1187e5079ffbacfb21f947828dd18952655.jpg) 表针的运动"
+    ],
+    "answer": "A",
+    "solution": "【分析】在平面内，把一个图形整体沿某条直线方向平行移动一定距离的过程，称为平移。常见的平移现象有滑滑梯，电梯的移动等;在平面内，把一个图形围绕某一固定点按顺时针或逆时针方向转动一定的角度的过程，称为旋转。常见的旋转现象有旋转木马，摩天轮等。由此解答.\n【详解】A。 缆车的运动，属于平移现象;B. 螺旋桨的运动，属于旋转现象;C. 表针的运动，属于旋转现象。故答案为:A",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "24-25 二年级下·湖北孝感·期末"
+  },
+  {
+    "id": "34",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下列哪个汉字不是轴对称图形。( )",
+    "options": [
+      "品",
+      "工",
+      "水"
+    ],
+    "answer": "C",
+    "solution": "【分析】一个图形沿一条直线对折，直线两旁的图形完全重合，这样的图形叫做轴对称图形，折痕所在的直线是对称轴，由此解答。\n【详解】A. 有对称轴，是轴对称图形;B. 有对称轴，是轴对称图形;C. 水没有对称轴，不是轴对称图形。则不是轴对称图形的汉字是水。故答案为:C",
+    "knowledge_points": [
+      "轴对称的认识及辨认"
+    ],
+    "source": "24-25 二年级下·江西九江·期中"
+  },
+  {
+    "id": "35",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下列现象中，不属于平移的是( )。",
+    "options": [
+      "钟表上秒针的转动",
+      "乘垂直电梯从一楼到九楼",
+      "动车在笔直的轨道上行驶"
+    ],
+    "answer": "A",
+    "solution": "【分析】在平面内，一个图形整体沿着某条直线方向平行移动一定距离的过程，称为平移;在平面内，一个图形围绕某一个固定点按照顺时针或逆时针方向转动一定角度的过程，称为旋转。据此判断哪个不属于平移即可.\n【详解】A。 钟表上秒针的转动，属于旋转现象;B. 乘垂直电梯从一楼到九楼，属于平移现象;C. 动车在笔直的轨道上行驶，属于平移现象。因此，不属于平移的是钟表上秒针的转动。故答案为:A",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "24-25 二年级下·山西晋中·期中"
+  },
+  {
+    "id": "36",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面( )的运动是平移。",
+    "options": [
+      "转动的电风扇",
+      "推拉抽屉",
+      "翻书"
+    ],
+    "answer": "B",
+    "solution": "【分析】平移是指在平面内将一个图形上的所有点都按照某个直线方向做相同距离的移动，这样的运动叫做图形的平移运动。旋转是指在平面内将一个图形绕一点按某个方向转动一个角度，这样的运动叫做图形的旋转运动。根据平移和旋转的含义解决即可.\n【详解】A。 \"转动的电风扇\"属于旋转;B. \"推拉抽屉\"属于平移;C. \"翻书\"属于旋转。故答案为:B",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "24-25 二年级下·湖北孝感·期中"
+  },
+  {
+    "id": "37",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下列图形不是轴对称的是( )。",
+    "options": [
+      "圆",
+      "平行四边形",
+      "长方形"
+    ],
+    "answer": "B",
+    "solution": "【分析】一个图形沿着一条直线对折后，直线两旁的部分能够完全重合，这样的图形就叫做轴对称图形，据此解答.\n【详解】A。 圆沿着这样一条直线对折后，直线两旁的部分能够完全重合，所以它是轴对称图形;B. 平行四边形沿着一条直线对折后，直线两旁的部分不能够完全重合，所以它不是轴对称图形;C. 长方形沿着这样一条直线对折后，直线两旁的部分能够完全重合，所以它是轴对称图形。不是轴对称图形的是平行四边形。故答案为:B",
+    "knowledge_points": [
+      "轴对称的认识及辨认"
+    ],
+    "source": "24-25 二年级下·湖北孝感·期末"
+  },
+  {
+    "id": "38",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "电风扇叶片的运动是( )现象;电梯上下是( )现象.\n①平移 ②旋转 ③对称",
+    "options": [
+      "①②",
+      "②①",
+      "①③"
+    ],
+    "answer": "B",
+    "solution": "【分析】在平面内，把一个图形整体沿某条直线方向平行移动一定距离的过程，称为平移。常见的平移现象有推拉窗户，滑滑梯等。在平面内，把一个图形围绕某一固定点按顺时针或逆时针方向转动一定的角度的过程，称为旋转。常见的旋转现象有旋转木马，摩天轮等.\n【详解】由分析得：电风扇叶片的运动是旋转现象;电梯上下是平移现象。也就是选择②①。故答案为:B",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "24-25 二年级下·河南信阳·期中"
+  },
+  {
+    "id": "39",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "木瓜的英文是\"papaya\"，用字母卡片拼出，这些卡片中不是轴对称图形的是( )。",
+    "options": [
+      "P",
+      "A",
+      "Y"
+    ],
+    "answer": "A",
+    "solution": "【分析】依据轴对称图形的概念，在平面内，如果沿着一条直线折叠，直线两旁的部分能够完全重合，这样的图形叫轴对称图形。字母P:沿竖中线左右对折，两边不能完全重合，故不是轴对称图形;字母A和Y:沿横中线上下对折，两边能完全重合，故是轴对称图形。据此可选择.\n【详解】由分析可得：这些卡片中不是轴对称图形的是P。故答案为:A",
+    "knowledge_points": [
+      "轴对称的认识及辨认"
+    ],
+    "source": "24-25 二年级下·河南南阳·期中"
+  },
+  {
+    "id": "40",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下列现象属于平移的是( )。",
+    "options": [
+      "拧瓶盖",
+      "推拉窗户",
+      "荡秋千"
+    ],
+    "answer": "B",
+    "solution": "【分析】在平面内，把一个图形整体沿某条直线方向平行移动一定距离的过程，称为平移，常见的平移现象有滑滑梯，电梯的移动等。在平面内，把一个图形围绕某一固定点按顺时针或逆时针方向转动一定的角度的过程，称为旋转，常见的旋转现象有旋转木马，摩天轮等.\n【详解】A。 拧瓶盖属于旋转现象，不符合题意;B. 推拉窗户属于平移现象，符合题意;C. 荡秋千属于旋转现象，不符合题意。则属于平移的是推拉窗户。故答案为:B",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "24-25 二年级下·广东潮州·期中"
+  },
+  {
+    "id": "41",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面字母中,( )是轴对称图形。",
+    "options": [
+      "N",
+      "H",
+      "P"
+    ],
+    "answer": "B",
+    "solution": "【分析】如果沿某条直线对折，对折的两部分是完全重合的，这样的图形为轴对称图形。这条直线叫做这个图形的对称轴。判断一个图案是否是轴对称图形的关键是看在这个图形中能否找到一条直线，使图形沿着这条直线对折后能够完全重合.\n【详解】A。 N 找不到对称轴，不是轴对称图形;B. H 可以从中间竖着画一条对称轴，是轴对称图形;C. P 找不到对称轴，不是轴对称图形。H是轴对称图形。故答案为:B",
+    "knowledge_points": [
+      "轴对称的认识及辨认"
+    ],
+    "source": "24-25 二年级下·河南周口·期中"
+  },
+  {
+    "id": "42",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "下列图形中是轴对称图形的是( )。",
+    "options": [
+      "![](images/be9a53ebe64fc1b79a9435d19020bcb3d331032f30b2777058b5b911419659ee.jpg)",
+      "![](images/412646e93a7621dd0be830819e10581e3b24b9cad1da882a4f1984510711de59.jpg)",
+      "![](images/6252a909ec749ea8167f92479690d5e9870d0a25ea8d26c37caecfe8cc6ac6ad.jpg)"
+    ],
+    "answer": "C",
+    "solution": "【分析】根据题意，轴对称图形是指一个图形沿着一条直线折叠后，能够与另一部分完全重合的现象。据此解答即可。\n【详解】根据分析可知：A. 无论怎样对折，两边都不能完全重合，不是轴对称图形;B. 无论怎样对折，两边都不能完全重合，不是轴对称图形;C. 能够沿着一条直线折叠后两边都能够完全重合，是轴对称图形。故答案为:C",
+    "knowledge_points": [
+      "轴对称的认识及辨认"
+    ],
+    "source": "24-25 三年级下·山东济宁·期末"
+  },
+  {
+    "id": "43",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下列现象中,( )是旋转现象。",
+    "options": [
+      "电梯升降",
+      "钟表指针转动",
+      "推拉窗户"
+    ],
+    "answer": "B",
+    "solution": "【分析】在平面内，把一个图形整体沿某条直线方向平行移动一定距离的过程，称为平移;常见的平移现象有滑滑梯，电梯的移动等;在平面内，把一个图形围绕某一固定点按顺时针或逆时针方向转动一定的角度的过程，称为旋转;常见的旋转现象有旋转木马，摩天轮等.\n【详解】A。 电梯升降是平移现象;B. 钟表指针转动是旋转现象;C. 推拉窗户是平移现象。故答案为:B",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "24-25 二年级下·湖南岳阳·期中"
+  },
+  {
+    "id": "44",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "翻动书页时，书页的运动是( )。",
+    "options": [
+      "平移",
+      "旋转",
+      "平移或旋转"
+    ],
+    "answer": "B",
+    "solution": "【分析】在平面内，把一个图形整体沿某条直线方向平行移动一定距离的过程，称为平移，平移后图形的位置改变，形状，大小，方向不变。在平面内，把一个图形围绕某一固定点按顺时针或逆时针方向转动一定的角度的过程，称为旋转，旋转前后图形的位置和方向改变，形状，大小不变.\n【详解】由分析可知：翻动书页时，书页的一端固定在书脊(装订处),另一端绕书脊转动，则书页的运动是旋转。故答案为:B",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "24-25 二年级下·广西玉林·期中"
+  },
+  {
+    "id": "45",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面现象中，属于旋转的是( )。",
+    "options": [
+      "玩直滑梯",
+      "早上穿衣服时拉好校服的拉链",
+      "风扇的扇叶转动"
+    ],
+    "answer": "C",
+    "solution": "【分析】在平面内，把一个图形围绕某一固定点按顺时针或逆时针方向转动一定角度的过程，称为旋转;常见的旋转现象有旋转木马，摩天轮等，据此选答案.\n【详解】A。 玩直滑梯，是平移现象，不属于旋转，不符合题意;B. 早上穿衣服时拉好校服的拉链，是平移现象，不属于旋转，不符合题意;C. 风扇的扇叶转动，属于旋转，符合题意。故答案为:C",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "24-25 二年级下·福建福州·期中"
+  },
+  {
+    "id": "46",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面是国内四家银行的图标，是轴对称图形的有( ).\n![](images/81c86f67fd8c69957f29b7dd9c6e27145e02854e0078695a8386587b824669b3.jpg)\n![](images/3b341adc581b2b598503d3a1c21224551b4d4cce61def22a014b5c9b651f4461.jpg)\n![](images/985c3f5e7a0d557d99d3f35672f1035c8be910b00ec3076c4d9ea1252929b573.jpg)\n![](images/0339e7c67bd50f2c56424feab2cdc306b8014fa125e36159dabc2dd7fb674c2c.jpg)",
+    "options": [
+      "4个",
+      "3个",
+      "2个",
+      "1个"
+    ],
+    "answer": "C",
+    "solution": "【分析】根据轴对称图形的特点：沿一直线折叠，两侧的图形能够完全重合，据此解答.\n【详解】第一个图形有两条对称轴，是轴对称图形;第二个图形没有对称轴，不是轴对称图形;第三个图形没有对称轴，不是轴对称图形;第四个图形有两条对称轴，是轴对称图形;所以一共有两个图形是轴对称图形。故答案为:C",
+    "knowledge_points": [
+      "轴对称的认识及辨认"
+    ],
+    "source": "24-25 六年级下·天津·期末"
+  },
+  {
+    "id": "47",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "下面( )的运动是旋转现象。",
+    "options": [
+      "打开推拉门",
+      "升国旗",
+      "拧瓶盖",
+      "拉抽屉"
+    ],
+    "answer": "C",
+    "solution": "【分析】在平面内，一个图形整体沿着某条直线方向平行移动一定距离的过程，称为平移;在平面内，一个图形围绕某一个固定点按照顺时针或逆时针方向转动一定角度的过程，称为旋转。据此判断各选项属于哪种运动，选出旋转的即可.\n【详解】A。 打开推拉门的运动是平移现象，不符合题意;B. 升国旗的运动是平移现象，不符合题意;C. 拧瓶盖的运动是旋转现象，符合题意;D. 拉抽屉的运动是平移现象，不符合题意。因此，拧瓶盖的运动是旋转现象。故答案为:C",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "24-25 二年级下·福建龙岩·期中"
+  },
+  {
+    "id": "48",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面图形中，是轴对称图形的是( )。",
+    "options": [
+      "![](images/a53e1d10ffa98f4532d9e232f86beb34f8cfe19ff0545a7bfce3cf70590fe806.jpg)",
+      "![](images/48b24fed4ecca6262de11a9cb0873092f935ba21bb9a4566d3acd77420da5f02.jpg)",
+      "![](images/cbbfef17f8c3149fe653e5b49e25343474cf14a0a968a0d43547997d90653f9d.jpg)"
+    ],
+    "answer": "B",
+    "solution": "【分析】轴对称：在平面内，如果一个图形沿一条直线对折，对折后的两部分都能完全重合，这样的图形叫作轴对称图形，这条直线就是其对称轴.\n【详解】A。 沿一条直线对折，对折后的两部分不能完全重合，则不是轴对称图形，不符合题意;B. 沿一条直线对折，对折后的两部分都能完全重合，则是轴对称图形，符合题意;C. ![](images/a9b110844cf3035303ac88405501322f7bc166129515e5e85155e1c5a7b4708d.jpg) 沿一条直线对折，对折后的两部分不能完全重合，则不是轴对称图形，不符合题意。故答案为:B",
+    "knowledge_points": [
+      "轴对称的认识及辨认"
+    ],
+    "source": "24-25二年级下·福建福州·期末"
+  },
+  {
+    "id": "49",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "依次按如图所示步骤剪一个图案，打开后是图( )。\n![](images/df53ff75e54770af4e5cd5e8d5874d211596b29aca69b8e0cb967bcf7e507024.jpg)",
+    "options": [
+      "![](images/9e888ceb9a8158e0cad74750b4b34388379115a04d1ef7c0d983775e05204876.jpg)",
+      "![](images/27f511c3d5f0a94963841934923c6ff4f96dadc16a3e9de3bb57fc42e472b6c4.jpg)",
+      "![](images/93297b706e4d3d12b2edb9fd32461e80676df0f616714ce3b7342273132a8421.jpg)"
+    ],
+    "answer": "C",
+    "solution": "【分析】从题目给出的操作步骤可以看到，正方形纸经过了两次对折。第一次对折将正方形沿一条对称轴对折，变成一个长方形;第二次对折又将长方形沿另一条对称轴对折，变成一个小的正方形。在对折两次后的小正方形上进行裁剪，裁剪的位置是在小正方形的中间剪去一个小圆形。由于经过了两次对折，展开后会出现4个对称分布的小圆形。因为每次对折都是对称的操作，所以剪去的一个小圆形，展开后会在原来正方形纸的4个对称位置上出现4个相同的小圆形。\n【详解】由分析可知：打开后是图C。故答案为:C",
+    "knowledge_points": [
+      "轴对称的剪纸问题"
+    ],
+    "source": "24-25 二年级下·山东济南·期末"
+  },
+  {
+    "id": "50",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面的图形中，( )是轴对称图形。",
+    "options": [
+      "![](images/40b1730a8fcd8e5b104f5514ebdf841469db109c0cb6863dfb0cd3d83313354e.jpg)",
+      "![](images/e20eddc59985c3a38c50b686dae46f8a480c75d9745287875daa19f78f8763a1.jpg)",
+      "![](images/efd9a161e7dfad4ecd5d736f6550c3607ed860c51d6fb46030d6976e776c3f79.jpg)"
+    ],
+    "answer": "A",
+    "solution": "【分析】根据轴对称图形的意义：如果一个图形沿着一条直线对折后两部分完全重合，这样的图形叫作轴对称图形，这条直线叫作对称轴，据此解答即可。\n【详解】A. 沿竖中线对折后，左右两边能完全重合，是轴对称图形;B. 沿任何方向的直线对折后，两边都不能完全重合，不是轴对称图形;C. 沿任何方向的直线对折后，两边都不能完全重合，不是轴对称图形。故答案为:A",
+    "knowledge_points": [
+      "轴对称的认识及辨认"
+    ],
+    "source": "24-25 二年级下·山东济南·期末"
+  },
+  {
+    "id": "51",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面( )的运动是平移。",
+    "options": [
+      "转动的风扇",
+      "行驶的汽车车轮",
+      "拉抽屉"
+    ],
+    "answer": "C",
+    "solution": "【分析】平移是指物体在平面内沿着某个方向移动，移动过程中物体的形状、大小和方向都不发生变化。平移可以看作是物体在平面内的\"滑动\"。旋转是指物体绕着一个固定点(旋转中心)转动，转动过程中物体的形状和大小不变，但方向会发生变化。\n【详解】A. 转动的风扇绕着一个固定点转动，是旋转，不符合题意;B. 行驶的汽车车轮绕着车轴转动，是旋转，不符合题意;C. 拉抽屉时，抽屉沿着某个方向直线移动，是平移，符合题意。故答案为:C",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "24-25二年级下·黑龙江佳木斯·期末"
+  },
+  {
+    "id": "52",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面图形中，( )是轴对称图形。",
+    "options": [
+      "平行四边形图形",
+      "三角形图形",
+      "长方形图形"
+    ],
+    "answer": "C",
+    "solution": "【分析】轴对称图形是指沿一条直线对折后，两部分能完全重合的图形，据此解答即可。\n【详解】A. 平行四边形沿一条直线对折后，两部分不能完全重合，不是轴对称图形，不符合题意;B. 三角形不一定是轴对称图形，题目没有说明是哪一种三角形，所以不能选;C. 长方形沿一条直线对折后，两部分能完全重合，是轴对称图形，符合题意。故答案为:C",
+    "knowledge_points": [
+      "轴对称的认识及辨认"
+    ],
+    "source": "24-25 二年级下·黑龙江佳木斯·期末"
+  },
+  {
+    "id": "53",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面是轴对称图形的是( )。",
+    "options": [
+      "![](images/5f2fe845c848419f5aca873e27a58a81436587314a818643b8c55dc509199bbf.jpg)",
+      "![](images/fa8abac5dc7698d1fba9b576e130e8815f1ae7cceec8b0cb4afe7e246fb5b04c.jpg)",
+      "![](images/69af8276eb3c689c879f417cce4c00fe20d80b2e2795d031ab11ca5721d930e3.jpg)"
+    ],
+    "answer": "C",
+    "solution": "【分析】如果一个图形沿着一条直线对折，直线两边的图形能够完全重合，这样的图形叫轴对称图形，这条直线叫对称轴，据此结合题意分析解答即可。\n【详解】A. 不是轴对称图形;B. 不是轴对称图形;C. 是轴对称图形。故答案为:C",
+    "knowledge_points": [
+      "轴对称的认识及辨认"
+    ],
+    "source": "24-25 二年级下·福建福州·期末"
+  },
+  {
+    "id": "54",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "\"和谐号\"动车驶离车站时车身的运动是( );悬挂的灯笼被风吹摇晃是( )。",
+    "options": [
+      "轴对称现象;旋转现象",
+      "轴对称现象;平移现象",
+      "平移现象;旋转现象"
+    ],
+    "answer": "C",
+    "solution": "【分析】平移是指在平面内将一个图形上的所有点都按照某个直线方向做相同距离的移动，这样的运动叫做图形的平移运动。旋转是指在平面内将一个图形绕一点按某个方向转动一个角度，这样的运动叫做图形的旋转运动。据此解答即可。\n【详解】\"和谐号\"动车驶离车站时，车身是沿直线向前运动的，属于平移现象;悬挂的灯笼被风吹摇晃时，是绕着悬挂点转动的，属于旋转现象。故答案为:C",
+    "knowledge_points": [
+      "轴对称的认识及辨认",
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "24-25 三年级下·重庆黔江·期末"
+  },
+  {
+    "id": "55",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下列( )不是平移现象。",
+    "options": [
+      "乘坐中的电梯",
+      "拉开抽屉",
+      "翻开书页",
+      "国旗的升降运动"
+    ],
+    "answer": "C",
+    "solution": "【分析】把一个图形整体沿某一个方向移动一定的距离，图形的这种移动叫平移，平移前后的图形位置变化，形状、大小不变，据此解答。\n【详解】A. 乘坐中的电梯是沿着上下方向移动的，是平移，不符合题意;B. 拉开抽屉是沿着直线向外移动的，是平移，不符合题意;C. 翻开书页是绕着书脊转动的，不是平移，符合题意;D. 国旗的升降运动是沿着旗杆上下移动的，是平移，不符合题意。故答案为:C",
+    "knowledge_points": [
+      "平移与平移现象"
+    ],
+    "source": "24-25 三年级下·重庆忠县·期末"
+  },
+  {
+    "id": "56",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "火车在铁轨上行驶，车身的运动现象是( )。",
+    "options": [
+      "平移",
+      "旋转",
+      "轴对称"
+    ],
+    "answer": "A",
+    "solution": "【分析】平移是指在平面内将一个图形上的所有点都按照某个直线方向做相同距离的移动，这样的运动叫做图形的平移运动。旋转是指在平面内将一个图形绕一点按某个方向转动一个角度，这样的运动叫做图形的旋转运动。在平面内，如果一个图形沿一条直线折叠，直线两旁的部分能够完全重合，这样的图形就叫做轴对称图形，这条直线叫做对称轴。据此解答即可.\n【详解】火车在铁轨上行驶时，车身的每个部分均沿直线方向移动相同距离，没有旋转或对称轴的变化，因此运动现象是平移。故答案为:A",
+    "knowledge_points": [
+      "轴对称的认识及辨认",
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "24-25 二年级下·贵州黔东南·期末"
+  },
+  {
+    "id": "57",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "填空题",
+    "difficulty": 0.94,
+    "question": "中国汉字博大精深，字体形态各异，用黑体字写出的\"日\"\"田\"\"王\"都是轴对称图形，请你再写出两个这样的汉字:( )，( )。",
+    "options": [],
+    "answer": "中;口",
+    "solution": "【分析】轴对称图形定义为平面内，一个图形沿一条直线折叠，直线两旁的部分能够完全重合的图形，折痕所在的直线叫做对称轴，据此写出轴对称图形的汉字。\n【详解】轴对称图形的黑体汉字有：中、口。(答案不唯一)",
+    "knowledge_points": [
+      "轴对称的认识及辨认"
+    ],
+    "source": "24-25 五年级上·广东韶关·期中"
+  },
+  {
+    "id": "58",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "自行车的车轮转了一圈又一圈是( )现象。电梯的升降属于( )现象。",
+    "options": [],
+    "answer": "旋转;平移",
+    "solution": "【分析】图形的旋转是图形上的每一点在平面上绕着某个固定点旋转固定角度的位置移动，其中对应点到旋转中心的距离相等，对应线段的长度，对应角的大小相等，旋转前后图形的大小和形状没有改变;图形的平移是在平面内，把一个图形整体沿某条直线方向平行移动一定距离的过程，它们的形状，大小，方向都不改变，只是位置发生了变化，据此解答.\n【详解】根据分析可知，自行车的车轮转了一圈又一圈是旋转现象。电梯的升降属于平移现象。",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "24-25三年级上·山东菏泽·期中"
+  },
+  {
+    "id": "59",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "电梯的升降是( )现象，自行车的车轮转动是( )现象，轮船螺旋桨的运动是( )现象。",
+    "options": [],
+    "answer": "平移;旋转;旋转",
+    "solution": "【分析】平移是指在平面内，将一个图形上的所有点都按照某个直线方向做相同距离的移动，这样的图形运动叫做图形的平移运动，简称平移;在平面内，将一个图形绕着一个点按某个方向转动一定的角度，这样的运动叫做图形的旋转。\n【详解】电梯的升降是平移现象;自行车的车轮转动是旋转现象;轮船螺旋桨的运动是旋转现象。",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "24-25 三年级上·山东济南·期中"
+  },
+  {
+    "id": "60",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "升旗时，国旗的运动是( )现象。开车时，方向盘的转动是( )现象。",
+    "options": [],
+    "answer": "平移;旋转",
+    "solution": "【分析】平移是指物体在平面内沿着某个方向移动，移动过程中物体的形状，大小和方向都不发生变化。平移可以看作是物体在平面内的\"滑动\"。旋转：旋转是指物体绕着一个固定点(旋转中心)转动，转动过程中物体的形状和大小不变，但方向会发生变化.\n【详解】由分析可得：升旗时，国旗的运动是平移现象。开车时，方向盘的转动是旋转现象。",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "19-20 三年级下·河南商丘·期末"
+  },
+  {
+    "id": "61",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "2024年9月6日，我国使用长征六号运载火箭，成功将吉利星座03组卫星发射升空。卫星升空时属于( )现象，当卫星开始绕地球飞行时属于( )现象。(填\"平移\"或\"旋转\")",
+    "options": [],
+    "answer": "平移;旋转",
+    "solution": "【分析】在平面内，把一个图形整体沿某条直线方向平行移动一定距离的过程，称为平移。常见的平移现象有滑滑梯，电梯的移动等。在平面内，把一个图形围绕某一固定点按顺时针或逆时针方向转动一定的角度的过程，称为旋转。常见的旋转现象有旋转木马，摩天轮等。由此解答.\n【详解】根据分析可知：卫星升空时属于平移现象，当卫星开始绕地球飞行时属于旋转现象。",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "24-25 二年级下·湖北省直辖县级单位·期末"
+  },
+  {
+    "id": "62",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "司机拉开出租车车门，车门做( )运动，把钥匙插进钥匙孔，钥匙做( )运动，扭动钥匙发动汽车，钥匙做( )运动，汽车开动了，车轮做( )运动。(均填\"平移\"或\"旋转\")",
+    "options": [],
+    "answer": "旋转;平移;旋转;旋转",
+    "solution": "【分析】平移和旋转都是物体或图形的位置发生变化而形状，大小不变。区别在于，平移时物体沿直线运动，本身方向不发生改变;旋转是物体绕着某一点或轴运动，本身方向发生了变化。据此解答即可.\n【详解】司机拉开出租车车门，车门做旋转运动，把钥匙插进钥匙孔，钥匙做平移运动，扭动钥匙发动汽车，钥匙做旋转运动，汽车开动了，车轮做旋转运动。",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "24-25 三年级下·山西吕梁·期末"
+  },
+  {
+    "id": "63",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "下列运动是什么现象。(填\"旋转\"或\"平移\")\n玩魔方( );升降国旗( );车轮的运动( )。",
+    "options": [],
+    "answer": "旋转;平移;旋转",
+    "solution": "【分析】在平面内，把一个图形整体沿某条直线方向平行移动一定距离的过程，称为平移，常见的平移现象有电梯的移动，推拉门等。在平面内，把一个图形围绕某一固定点按顺时针或逆时针方向转动一定的角度的过程，称为旋转，常见的旋转现象有旋转木马，摩天轮等.\n【详解】由分析得：转动魔方时，每个面绕中心轴转动，属于旋转;国旗沿旗杆上下移动，属于平移;车轮绕车轴转动，属于旋转。玩魔方(旋转);升降国旗(平移);车轮的运动(旋转)。",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "24-25 二年级下·湖北恩施·期末"
+  },
+  {
+    "id": "64",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "教室门的打开和关闭，门的运动是( )现象;上下拨算盘上的算珠是( )运动。",
+    "options": [],
+    "answer": "旋转;平移",
+    "solution": "【分析】平移：在平面内，将一个图形上的所有点都按照某个方向作相同距离移动的图形运动。平移后图形的位置改变，形状，大小，方向不变。旋转：在平面内，将一个图形绕一点按某个方向转动一定的角度，这样的运动叫做图形的旋转。旋转前后图形的位置和方向改变，形状，大小不变。据此结合题干要求进行解答即可.\n【详解】据分析可知：教室门的打开和关闭，门的运动是旋转现象;上下拨算盘上的算珠是平移运动。",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "24-25 二年级下·福建龙岩·期末"
+  },
+  {
+    "id": "65",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "汽车沿着直线行驶时，车轮做( )运动，车身做( )运动。",
+    "options": [],
+    "answer": "旋转;平移",
+    "solution": "【分析】把一个物体沿某条直线方向平行移动一定距离的过程，称为平移。常见的平移现象有滑滑梯，电梯的移动等;在平面内，一个物体围绕某一固定点按顺时针或逆时针方向转动一定的角度的过程，称为旋转。常见的旋转现象有旋转木马，摩天轮等。车轮转动是车轮绕车轴旋转的运动，车身则是在车轮的带动下沿水平的方向直线平移.\n【详解】由分析可得：直线行驶的汽车，车轮绕着车轴不停地旋转，是旋转运动;车身在车轮的带动下水平直线向前移动，是平移运动。汽车沿着直线行驶时，车轮做旋转运动，车身做平移运动。",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "24-25 三年级下·河南安阳·期末"
+  },
+  {
+    "id": "66",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "翻动书页属于( )现象，电梯的运行属于( )现象。",
+    "options": [],
+    "answer": "旋转;平移",
+    "solution": "【分析】在平面内，一个图形整体沿着某条直线方向平行移动一定距离的过程，称为平移;在平面内，一个图形围绕某一个固定点按照顺时针或逆时针方向转动一定角度的过程，称为旋转.\n【详解】由分析可知：翻动书页属于(旋转)现象，电梯的运行属于(平移)现象。",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "24-25 二年级下·山东菏泽·期末"
+  },
+  {
+    "id": "67",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "在( )里填上\"平移\"\"旋转\"或\"轴对称\".\n琪琪把一张中国结剪纸对折后能完全重合，这个中国结是( )图形;妙妙家的沙漏在流动时，沙子在做( )运动;聪聪的玩具直升机在起飞时，是靠它顶部的螺旋桨( )上升。",
+    "options": [],
+    "answer": "轴对称;平移;旋转",
+    "solution": "【分析】如果一个图形沿着一条直线对折后两部分能完全重合，这样的图形叫做轴对称图形，这条直线叫做对称轴。平移是指在平面内将一个图形上的所有点都按照某个直线方向做相同距离的移动，这样的运动叫做图形的平移运动。旋转是指在平面内将一个图形绕一点按某个方向转动一个角度，这样的运动叫做图形的旋转运动。据此解决.\n【详解】由题意分析得：琪琪把一张中国结剪纸对折后能完全重合，这个中国结是轴对称图形;妙妙家的沙漏在流动时，沙子在做平移运动;聪聪的玩具直升机在起飞时，是靠它顶部的螺旋桨旋转上升。",
+    "knowledge_points": [
+      "轴对称的认识及辨认",
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "24-25 二年级下·湖北武汉·期末"
+  },
+  {
+    "id": "68",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "钟面转动是( )现象，升国旗是( )现象。",
+    "options": [],
+    "answer": "旋转;平移",
+    "solution": "【分析】平移是指在平面内将一个图形上的所有点都按照某个直线方向做相同距离的移动，这样的运动叫做图形的平移运动。故，升国旗是平移。旋转是指在平面内将一个图形绕一点按某个方向转动一个角度，这样的运动叫做图形的旋转运动。故，钟面转动是旋转.\n【详解】由分析可知：钟面转动是旋转现象，升国旗是平移现象。",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "24-25 二年级下·江西赣州·期末"
+  },
+  {
+    "id": "69",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "直升机竖直起飞时，机身的运动是( ),桨叶的运动是( )。(填\"平移\"或\"旋转\")",
+    "options": [],
+    "answer": "平移;旋转",
+    "solution": "【分析】平移是指在平面内将一个图形上的所有点都按照某个直线方向做相同距离的移动，这样的运动叫做图形的平移运动。故，机身的运动是平移。旋转是指在平面内将一个图形绕一点按某个方向转动一个角度，这样的运动叫做图形的旋转运动。故，桨叶的运动是旋转.\n【详解】由分析可知：直升机竖直起飞时，机身的运动是平移，桨叶的运动是旋转。",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "24-25 二年级下·湖南张家界·期末"
+  },
+  {
+    "id": "70",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "时针的运动是( )现象，算珠的运动是( )现象。\n![](images/bddea7366a61ff0f76ce2e8ea1df009059696c9ce429525ec7f322ef765cbcc9.jpg)\n![](images/a5a1d828692bdbe7bf25952c87764706b1acf5df72c60bd51c81e5d813d307fb.jpg)",
+    "options": [],
+    "answer": "旋转;平移",
+    "solution": "【分析】平移是物体运动时，物体上任意两点间，从一点到另一点的方向与距离都不变的运动;旋转是物体运动时，每一个点离同一个点(可以在物体外)的距离不变的运动，称为绕这个点的转动，这个点称为物体的转动中心。所以，它并不一定是绕某个轴的;也可以这样说平移是不转动的，旋转自然是转动的，依此根据平移与旋转定义判断即可.\n【详解】时针在钟面上是围绕钟表的中心进行运动，所以时针的运动是旋转现象;算珠在算盘上沿着直线上下移动，所以算珠的运动是平移现象。",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "24-25 三年级下·内蒙古包头·期末"
+  },
+  {
+    "id": "71",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "火车前进是( )现象，火车轮子的转动是( )现象。",
+    "options": [],
+    "answer": "平移;旋转",
+    "solution": "【分析】在平面内，把一个图形整体沿某条直线方向平行移动一定距离的过程，称为平移;常见的平移现象有滑滑梯，电梯的移动等;在平面内，把一个图形围绕某一固定点按顺时针或逆时针方向转动一定的角度的过程，称为旋转;常见的旋转现象有旋转木马，摩天轮等;据此解答.\n【详解】由分析可得：火车前进是平移现象，火车轮子的转动是旋转现象。",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "24-25 二年级下·广东潮州·期末"
+  },
+  {
+    "id": "72",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "直升机竖直起飞，机身运动是( )，桨叶运动是( )。(填\"平移\"或\"旋转\")",
+    "options": [],
+    "answer": "平移;旋转",
+    "solution": "【分析】在平面内，把一个图形整体沿某条直线方向平行移动一定距离的过程，称为平移，常见的平移现象有滑滑梯，电梯的移动等。在平面内，把一个图形围绕某一固定点按顺时针或逆时针方向转动一定的角度的过程，称为旋转，常见的旋转现象有旋转木马，摩天轮等.\n【详解】直升机竖直起飞机身运动是平移，桨叶运动是旋转。",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "24-25 二年级下·福建厦门·期末"
+  },
+  {
+    "id": "73",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "街道上的清扫车向前开时，可以看成是车身向前( ),转弯时要( )方向盘。(选填\"旋转\"或\"平移\")",
+    "options": [],
+    "answer": "平移;旋转",
+    "solution": "【分析】平移是指物体在平面内沿着某个方向移动，移动过程中物体的形状、大小和方向都不发生变化。平移可以看作是物体在平面内的\"滑动\"。旋转是指物体绕着一个固定点(旋转中心)转动，转动过程中物体的形状和大小不变，但方向会发生变化。\n【详解】街道上的清扫车向前开时，可以看成是车身向前平移;转弯时要旋转方向盘。",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "24-25 二年级下·山西长治·期中"
+  },
+  {
+    "id": "74",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "想要剪出1个纸人，需先将纸对折( )次，再沿折痕画半个小人，剪后展开即可。",
+    "options": [],
+    "answer": "1",
+    "solution": "【分析】根据剪纸对称图形的原理，将纸对折1次后，沿折痕画出半个小人，剪下并展开即可得到1个完整的纸人.\n【详解】根据分析可得：想要剪出1个纸人，需先将纸对折1次，再沿折痕画半个小人，剪后展开即可。",
+    "knowledge_points": [
+      "轴对称的剪纸问题"
+    ],
+    "source": "24-25 二年级下·江西九江·期中"
+  },
+  {
+    "id": "75",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "升国旗时，国旗的运动是( )现象，打开电扇，电扇的运动是( )现象。",
+    "options": [],
+    "answer": "平移;旋转",
+    "solution": "【分析】平移是指在平面内将一个图形上的所有点都按照某个直线方向做相同距离的移动，这样的运动叫做图形的平移运动。旋转是指在平面内将一个图形绕一点按某个方向转动一个角度，这样的运动叫做图形的旋转运动。升国旗时，国旗沿旗杆直线上升，属于平移;电扇叶片绕轴转动，属于旋转.\n【详解】由题意分析得：升国旗时，国旗的运动是平移现象，打开电扇，电扇的运动是旋转现象。",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "24-25 二年级下·湖北黄冈·期中"
+  },
+  {
+    "id": "76",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "举例:( )是\"平移\"现象;( )是\"旋转\"现象。",
+    "options": [],
+    "answer": "电梯上下运动;风车转动",
+    "solution": "【分析】在平面内，把一个图形整体沿某条直线方向平行移动一定距离的过程，称为平移。平移后图形的位置改变，形状，大小，方向不变。在平面内，把一个图形围绕某一固定点按顺时针或逆时针方向转动一定的角度的过程，称为旋转。旋转前后图形的位置和方向改变，形状，大小不变.\n【详解】由分析得：举例：电梯上下运动是\"平移\"现象;风车转动是\"旋转\"现象。(答案不唯一)",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "24-25 二年级下·河南南阳·期中"
+  },
+  {
+    "id": "77",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "在( )里填上\"旋转\"或\"平移\".\n(1)打开抽屉是( )现象.\n(2)拧开水龙头是( )现象。",
+    "options": [],
+    "answer": "平移;旋转",
+    "solution": "【分析】在平面内，把一个图形整体沿某条直线方向平行移动一定距离的过程，称为平移。平移后图形的位置改变，形状，大小，方向不变，常见的平移现象有滑滑梯，电梯的移动等。在平面内，把一个图形围绕某一固定点按顺时针或逆时针方向转动一定的角度的过程，称为旋转。旋转前后图形的位置和方向改变，形状，大小不变。常见的旋转现象有旋转木马，摩天轮等.\n【详解】(1)打开抽屉是平移现象。(2)拧开水龙头是旋转现象。",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "24-25 二年级下·湖南衡阳·期中"
+  },
+  {
+    "id": "78",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "拉动抽屉是( )现象，旋转的陀螺是( )现象。",
+    "options": [],
+    "answer": "平移;旋转",
+    "solution": "【分析】在平面内，把一个图形整体沿某条直线方向平行移动一定距离的过程，称为平移，常见的平移现象有滑滑梯，电梯的移动等;在平面内，把一个图形围绕某一固定点按顺时针或逆时针方向转动一定的角度的过程，称为旋转，常见的旋转现象有旋转木马，摩天轮等.\n【详解】由分析得：拉动抽屉是平移现象，旋转的陀螺是旋转现象。",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "24-25 二年级下·广西玉林·期中"
+  },
+  {
+    "id": "79",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "电梯上升是( )现象，风车转动是( )现象。",
+    "options": [],
+    "answer": "平移;旋转",
+    "solution": "【分析】在平面内，把一个图形整体沿某条直线方向平行移动一定距离的过程，称为平移。常见的平移现象有滑滑梯，电梯的移动等;在平面内，把一个图形围绕某一固定点按顺时针或逆时针方向转动一定的角度的过程，称为旋转。常见的旋转现象有旋转木马，摩天轮等。由此解答.\n【详解】电梯上升是平移现象，风车转动是旋转现象。",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "24-25 二年级下·广东潮州·期中"
+  },
+  {
+    "id": "80",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "开锁时，钥匙插入锁孔是( )现象，拧动钥匙属于( )现象。(填\"平移\"或\"旋转\")",
+    "options": [],
+    "answer": "平移;旋转",
+    "solution": "【分析】平移是指物体在平面内沿着某个方向移动，移动过程中物体的形状、大小和方向都不发生变化。平移可以看作是物体在平面内的\"滑动\"。旋转是指物体绕着一个固定点(旋转中心)转动，转动过程中物体的形状和大小不变，但方向会发生变化。\n【详解】由分析可得：开锁时，钥匙插入锁孔是平移现象，拧动钥匙属于旋转现象。",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "24-25 二年级下·广西柳州·期中"
+  },
+  {
+    "id": "81",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "拉抽屉的运动是( )现象，门随门轴的转动是( )现象。",
+    "options": [],
+    "answer": "平移;旋转",
+    "solution": "【分析】平移是指物体在平面内沿着某个方向移动，移动过程中物体的形状、大小和方向都不发生变化。平移可以看作是物体在平面内的\"滑动\"。旋转是指物体绕着一个固定点转动，转动过程中物体的形状和大小不变，但方向会发生变化。\n【详解】由分析可得：拉抽屉的运动是平移现象;门随门轴的转动是旋转现象。",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "24-25 二年级下·广东潮州·期末"
+  },
+  {
+    "id": "82",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "2025年4月24日17时17分神舟二十号载人飞船在酒泉卫星发射中心成功升空。神舟二十号从地面发射升空是( )现象。我国首款专用武装直升机武直-10上螺旋桨运转是( )现象。",
+    "options": [],
+    "answer": "平移;旋转",
+    "solution": "【分析】在平面内，把一个图形整体沿某条直线方向平行移动一定距离的过程，称为平移。常见的平移现象有滑滑梯、电梯的移动等;在平面内，把一个图形围绕某一固定点按顺时针或逆时针方向转动一定的角度的过程，称为旋转。常见的旋转现象有旋转木马、摩天轮等。神舟二十号从地面发射升空符合平移现象;我国首款专用武装直升机武直-10上的螺旋桨运转符合旋转现象。据此可解。\n【详解】由分析可得：神舟二十号从地面发射升空是平移现象。我国首款专用武装直升机武直-10上的螺旋桨运转是旋转现象。",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "24-25 二年级下·福建福州·期末"
+  },
+  {
+    "id": "83",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "教室门的打开与关闭是( )现象。",
+    "options": [],
+    "answer": "旋转",
+    "solution": "【分析】在平面内，把一个图形整体沿某条直线方向平行移动一定距离的过程，称为平移。在平面内，把一个图形围绕某一固定点按顺时针或逆时针方向转动一定的角度的过程，称为旋转。教室门的打开与关闭，是绕着门轴按顺时针或逆时针方向转动一定的角度的过程，故属于旋转现象;据此可解.\n【详解】由分析可得：教室门的打开与关闭是旋转现象。",
+    "knowledge_points": [
+      "旋转与旋转现象"
+    ],
+    "source": "24-25 二年级下·山东济宁·期末"
+  },
+  {
+    "id": "84",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "算盘里拨算珠是( )现象，摩天轮是( )现象。",
+    "options": [],
+    "answer": "平移;旋转",
+    "solution": "【分析】平移：平移是指物体在平面内沿着某个方向移动，移动过程中物体的形状，大小和方向都不发生变化。平移可以看作是物体在平面内的\"滑动\"。例如：推拉抽屉，电梯上下移动，火车在直轨上行驶等。旋转：旋转是指物体绕着一个固定点(旋转中心)转动，转动过程中物体的形状和大小不变，但方向会发生变化。例如：风车转动，钟表的指针转动，旋转木马等.\n【详解】算盘里拨算珠是(平移)现象，摩天轮是(旋转)现象。",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "24-25 二年级下·内蒙古赤峰·期末"
+  },
+  {
+    "id": "85",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "长江渔船在江面上行驶是( )现象;螺旋桨转动是( )现象。(选填\"平移\"或\"旋转\")",
+    "options": [],
+    "answer": "平移;旋转",
+    "solution": "【分析】比如像在平面上推东西，开关抽屉。这些物体都是沿着直线移动，这样的现象叫做平移;像转动方向盘，电扇的转动，旋转木马。这些物体都是绕着一个点或一个轴移动，这样的现象我们把它叫做旋转。据此可解.\n【详解】由分析可得：长江渔船在江面上行驶是平移现象;螺旋桨转动是旋转现象。",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "24-25 二年级下·浙江台州·期末"
+  },
+  {
+    "id": "86",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "钟表上的指针都做平移运动。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】平移是指在同一个平面内，如果一个图形上的所有点都按照某个直线方向做相同距离的移动，那么这样的图形运动就叫做图形的平移运动，简称平移;在平面内，一个图形绕着一个定点旋转一定的角度得到另一个图形的变化叫做旋转。钟表指针的运动是绕中心轴旋转，因此不属于平移.\n【详解】钟表上的指针围绕表盘中心做旋转运动，属于旋转现象，而非平移运动。故答案为: ×",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "24-25 五年级上·广东韶关·期中"
+  },
+  {
+    "id": "87",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "汽车在笔直的公路上行驶，车轮的运动是平移。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】平移是物体上所有点沿直线方向移动相同距离，而旋转是围绕某一点做圆周运动。汽车行驶时，车轮的运动是绕轴旋转，而非平移.\n【详解】车轮绕轴做圆周运动，属于旋转现象，而非平移。原说法错误。故答案为: ×",
+    "knowledge_points": [
+      "旋转与旋转现象"
+    ],
+    "source": "24-25 五年级上·河南商丘·期中"
+  },
+  {
+    "id": "88",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "只有形状，大小，方向完全相同的图形通过平移才能互相重合。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】若两个图形通过平移重合，必须满足形状、大小完全相同，且方向一致。若方向不同(如旋转后的图形)，则无法通过平移重合，必须借助旋转或翻转。因此，题干中的说法是正确的。\n【详解】平移是指在同一平面内，将一个图形沿某个方向移动一定的距离，不改变图形的形状、大小和方向。平移后的图形与原图形形状、大小、方向完全相同，仅位置改变。因此，只有形状、大小、方向完全相同的图形，才能通过平移互相重合。故答案为:√",
+    "knowledge_points": [
+      "平移与平移现象"
+    ],
+    "source": "24-25 二年级下·湖北·期末"
+  },
+  {
+    "id": "89",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "平行四边形是轴对称图形。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】轴对称图形是指沿一条直线对折后，直线两侧的部分能完全重合。平行四边形只有特殊的类型(如矩形，菱形)才是轴对称图形，而一般的平行四边形不存在这样的对称轴.\n【详解】将平行四边形沿任意一条直线对折，两侧的部分无法完全重合。例如，普通平行四边形沿对角线对折时，两边形状不重合;沿对边中点连线对折时，也无法完全重合。因此，平行四边形不一定是轴对称图形。故答案为: ×",
+    "knowledge_points": [
+      "轴对称的认识及辨认",
+      "平行四边形的初步认识"
+    ],
+    "source": "2018·山东·小升初真题"
+  },
+  {
+    "id": "90",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "汉字\"由\"、\"田\"和字母\"A\"都是轴对称图形。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】轴对称图形是指沿一条直线对折后，两部分能完全重合的图形，据此解答即可。\n【详解】由分析可得：汉字\"由\"、\"田\"和字母\"A\"都是轴对称图形，原题说法正确。故答案为:√",
+    "knowledge_points": [
+      "轴对称的认识及辨认"
+    ],
+    "source": "24-25 二年级下·云南昭通·期中"
+  },
+  {
+    "id": "91",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "字母E和F都是轴对称图形。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】依据轴对称图形的概念，在平面内，如果沿着一条直线折叠，直线两旁的部分能够完全重合，这样的图形叫轴对称图形。字母E沿横中线上下对折后，图形能够完全重合，故是轴对称图形;字母F沿横中线上下对折后，图形不能够完全重合，故不是轴对称图形;据此可判断.\n【详解】由分析可得：字母E是轴对称图形，字母F不是轴对称图形。故答案为: ×",
+    "knowledge_points": [
+      "轴对称的认识及辨认"
+    ],
+    "source": "24-25 二年级下·江西赣州·期末"
+  },
+  {
+    "id": "92",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "平移时，方向和大小也发生了变化。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】平移是指在平面内将一个图形上的所有点都按照某个直线方向做相同距离的移动，这样的运动叫做图形的平移运动。平移只改变图形的位置，不改变方向和大小。\n【详解】由分析可知：平移时，只改变图形的位置，不改变方向和大小。故答案为: ×",
+    "knowledge_points": [
+      "平移与平移现象"
+    ],
+    "source": "24-25 二年级下·湖南张家界·期末"
+  },
+  {
+    "id": "93",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "这种折法能剪出3个手拉手的纸人。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】要想剪出3个手拉手的纸人，需要先把纸连续对折，再按折法和画法剪开，展开后能得到3个手拉手的纸人，据此判断。\n【详解】由分析可得：这种折法能剪出3个手拉手的纸人，原题说法正确。故答案为:√",
+    "knowledge_points": [
+      "轴对称的剪纸问题"
+    ],
+    "source": "24-25 二年级下·河南南阳·期末"
+  },
+  {
+    "id": "94",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "物体或图形发生平移运动时，它们的方向不会改变。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】在平面内，把一个图形整体沿某条直线方向平行移动一定距离的过程，称为平移。平移是物体或图形沿直线移动，不改变形状，大小和方向。据此可判断.\n【详解】由分析可得：物体或图形发生平移运动时，它们的方向不会改变，改变的是物体或图形的位置。故答案为:√",
+    "knowledge_points": [
+      "平移与平移现象"
+    ],
+    "source": "24-25 二年级下·山东菏泽·期中"
+  },
+  {
+    "id": "95",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "汉字\"口\"、\"回\"、\"王\"都是轴对称图形。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】如果沿某条直线对折，对折的两部分是完全重合的，这样的图形为轴对称图形。这条直线叫做这个图形的对称轴。判断一个图案是否是轴对称图形，关键是看能否找到一条直线，使图形沿着这条直线对折后能够完全重合。\n【详解】\"口\"可以沿中间竖着画一条对称轴，是轴对称图形;\"回\"可以沿中间竖着画一条对称轴，是轴对称图形;\"王\"可以沿中间竖着画一条对称轴，是轴对称图形。综上，三个汉字均为轴对称图形，原题说法正确。故答案为:√",
+    "knowledge_points": [
+      "轴对称的认识及辨认"
+    ],
+    "source": "24-25 二年级下·广西柳州·期中"
+  },
+  {
+    "id": "96",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "物体在平移的过程中，大小，方向和形状都不变。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】平移是物体上的所有点都沿同一方向移动相同距离，平移过程中物体的形状，大小和方向均不发生改变.\n【详解】根据分析可得：物体在平移的过程中，大小，方向和形状都不变，说法正确。故答案为:√",
+    "knowledge_points": [
+      "平移与平移现象"
+    ],
+    "source": "24-25 二年级下·江西九江·期中"
+  },
+  {
+    "id": "97",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "所有的轴对称图形都只有一条对称轴。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】根据轴对称图形的定义，对称轴的数量取决于图形的形状。如长方形有2条对称轴，正方形有4条对称轴，圆有无数条对称轴。因此，并非所有轴对称图形都只有一条对称轴.\n【详解】根据分析可知，轴对称图形的对称轴数量不一定只有一条。原题说法错误。故答案为: ×",
+    "knowledge_points": [
+      "对称轴的画法及数量"
+    ],
+    "source": "24-25 二年级下·甘肃天水·期中"
+  },
+  {
+    "id": "98",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "这个图形是轴对称图形。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】一个图形沿着一条直线对折后，直线两旁的部分能够完全重合，这样的图形就叫做轴对称图形，据此解答。\n【详解】不管沿着哪条直线对折，对折后直线两旁的部分都不能够完全重合，因此不是轴对称图形，原题说法错误。故答案为: ×",
+    "knowledge_points": [
+      "轴对称的认识及辨认"
+    ],
+    "source": "24-25 二年级下·山东菏泽·期中"
+  },
+  {
+    "id": "99",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "汉字\"品\"是轴对称图形。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】如果沿某条直线对折，对折的两部分是完全重合的，这样的图形为轴对称图形。这条直线叫做这个图形的对称轴。判断一个图案是否是轴对称图形，关键是看在这个图形中能否找到一条直线，使图形沿着这条直线对折后能够完全重合。观察\"品\"字的结构，左右两侧对应部分关于中间的竖直直线对称，因此符合轴对称图形的定义。\n【详解】汉字\"品\"若沿中间的竖直直线对折，左右两侧能够完全重合，因此\"品\"是轴对称图形。原题说法正确。故答案为:√",
+    "knowledge_points": [
+      "轴对称的认识及辨认"
+    ],
+    "source": "24-25 二年级下·河北廊坊·期中"
+  },
+  {
+    "id": "100",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "平移和旋转只能改变图形的位置，不能改变它的大小。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】平移是将图形沿某一直线方向移动，旋转是将图形绕某一点转动一定角度。这两种变换均不改变图形的形状和大小，仅改变其位置。据此可判断。\n【详解】由分析可得：平移和旋转只能改变图形的位置，不能改变它的大小。故答案为:√",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "24-25 二年级下·河南周口·期中"
+  },
+  {
+    "id": "101",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面图案中，不是轴对称图形的是( )。",
+    "options": [
+      "A. ![](images/a5f75e3936eff31825f02db193d2fd05b0ff4723f4238cd09e04761bd8b04c87.jpg)",
+      "B. ![](images/dd405d77299fca794bfa354e53700e3d958c5704eedabfe75bcc84dbea7e0a88.jpg)",
+      "C. ![](images/7d42f5c7d113ceeb8a884eef6c44ff8069ba49c092935c9e68a89ae1e69aed19.jpg)"
+    ],
+    "answer": "A",
+    "solution": "【分析】如果沿某条直线对折，对折的两部分是完全重合的，这样的图形为轴对称图形。这条直线叫做这个图形的对称轴。判断一个图案是否是轴对称图形，关键是看能否找到一条直线，使图形沿着这条直线对折后能够完全重合。\n\n【详解】A. 不是轴对称图形;B. 是轴对称图形;C. 是轴对称图形。故答案为:A",
+    "knowledge_points": [
+      "轴对称的认识及辨认"
+    ],
+    "source": "23-24二年级下·福建福州·期末"
+  },
+  {
+    "id": "102",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面几个图形中，轴对称图形共有( )个。\n![](images/bd7b16203c1eab89e3c33ffbed411133c58bbc2ccf655a76391368b1d0ea07a2.jpg)\n![](images/7cfd4afa9f4f71afaa889844956bf4e3a3c34cad14ac37f77940e97a3c674503.jpg)\n![](images/1e327399688f3a8cc8654b3ca7da7967662d43ce6f6e6c9776aacf2928145b07.jpg)\n![](images/f56890daaa330d8e7ecccd7d717849c9258ea95f383cb86ece48e60439e65813.jpg)",
+    "options": [
+      "A. 4",
+      "B. 3",
+      "C. 2"
+    ],
+    "answer": "B",
+    "solution": "【分析】一个图形沿一条直线对折，直线两旁的图形完全重合，这样的图形叫做轴对称图形;逐项分析每个图形，找出是轴对称图形，数出一共有几个即可解答。\n\n【详解】第一个图形沿着水平的直线对折，两侧能完全重合，是轴对称图形;第二个图形不论怎么对折，两侧不能完全重合，所以不是轴对称图形;第三个图形沿着竖直或者水平的直线对折，两侧能完全重合，是轴对称图形;第四个图形沿着竖直或者水平的直线对折，两侧能完全重合，是轴对称图形。共有3个。故答案为:B",
+    "knowledge_points": [
+      "轴对称的认识及辨认"
+    ],
+    "source": "23-24二年级下·浙江嘉兴·期末"
+  },
+  {
+    "id": "103",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下列图形中，不是轴对称图形的是( )。\n![](images/f6f68ea46f22fa0661d3d172d7217306e6ece37ba18e6fb7eccb4d301ec19472.jpg)",
+    "options": [],
+    "answer": "B",
+    "solution": "【分析】依据轴对称图形的概念，在平面内，如果沿着一条直线折叠，直线两旁的部分能够完全重合，这样的图形叫轴对称图形。据此解答。\n\n【详解】A. 是轴对称图形;B. 不是轴对称图形;C. 是轴对称图形。故答案选:B",
+    "knowledge_points": [
+      "轴对称的认识及辨认"
+    ],
+    "source": "23-24 二年级下·山东菏泽·期末"
+  },
+  {
+    "id": "104",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面的交通标志图案中，( )是轴对称图形。",
+    "options": [
+      "A. ![](images/0a2a9cf8f7dd40e37f3f3475186895d235b43825c93b69ae833cc3a874b96a9d.jpg)",
+      "B. ![](images/4947e64ba228a82ce6b01f046acc02d2ed58052367197ea7b35d4c3488e5f932.jpg)",
+      "C. ![](images/282739dc318d1bbb0c2cd8a47d7a373bc2f42498bf0829074645599ee93d5186.jpg)"
+    ],
+    "answer": "B",
+    "solution": "【分析】在平面内，如果沿着一条直线折叠，直线两旁的部分能够完全重合，这样的图形叫轴对称图形;据此逐项分析各个选项，找出是轴对称图形的选项即可解答。\n\n【详解】A. 不论怎么对折，两侧都不能完全重合，所以不是轴对称图形;B. 沿着竖直的直线对折，两侧能完全重合，是轴对称图形;C. 不论怎么对折，两侧都不能完全重合，所以不是轴对称图形。故答案为:B",
+    "knowledge_points": [
+      "轴对称的认识及辨认"
+    ],
+    "source": "24-25 二年级下·湖南·期中"
+  },
+  {
+    "id": "105",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "端午节前，东东做了一个纸鸢如图，这个图形是一个( )图形。\n![](images/333295babe3b924cb65825b910a38dd8537212dc46847e8d0f2fda11a7d86f68.jpg)",
+    "options": [
+      "A. 平移",
+      "B. 旋转",
+      "C. 轴对称"
+    ],
+    "answer": "C",
+    "solution": "【分析】在平面内，把一个图形整体沿某条直线方向平行移动一定距离的过程，称为平移。常见的平移现象有滑滑梯，电梯的移动等;在平面内，把一个图形围绕某一固定点按顺时针或逆时针方向转动一定的角度的过程，称为旋转。常见的旋转现象有旋转木马，摩天轮等;在平面内，如果沿着一条直线折叠，直线两旁的部分能够完全重合，这样的图形叫轴对称图形。\n\n【详解】根据分析可得:A. 这个图形无法通过平移得到;B. 这个图形无法通过旋转得到;C. 沿着纸鸢头部到尾部的直线对折，两侧能完全重合，所以这个图形是轴对称图形。故答案为:C",
+    "knowledge_points": [
+      "轴对称的认识及辨认",
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "23-24 二年级下·山西晋中·期末"
+  },
+  {
+    "id": "106",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面的图形不是轴对称图形的是( )。",
+    "options": [
+      "A. ![](images/572f39745a8615b18fa2f4093d7a049e857d03d06b3af52a9b0be9e1b3dc3c01.jpg)",
+      "B. ![](images/632bb1345e493f0a9860bbaffb94dae2984998b7a1c5c252430f4e1c7bf9635d.jpg)",
+      "C. ![](images/2ddfab3e31b489e29391384b2e5dcf267a05f11b93a752a248b08726e660434d.jpg)"
+    ],
+    "answer": "B",
+    "solution": "【分析】在平面内，如果沿着一条直线折叠，直线两旁的部分能够完全重合，这样的图形叫做轴对称图形。这条直线是图形的对称轴。\n\n【详解】A. 左右两旁对折后能够完全重合，是轴对称图形;B. 任意方向对折后都不能完全重合，不是轴对称图形;C. 左右两旁对折后能够完全重合，是轴对称图形。故答案为:B",
+    "knowledge_points": [
+      "轴对称的认识及辨认"
+    ],
+    "source": "23-24 二年级下·湖南常德·期中"
+  },
+  {
+    "id": "107",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面各图中，( )不是对称的。\n① ![](images/074ed900d0e5a3764027887ee5724d635121f0689ce475c75cae3658ef447dee.jpg)\n② ![](images/f7902c8977cd52a51bda02a6618b281c791720b22fc33c57b1063ca30ef78118.jpg)\n③ ![](images/e89f3ba5c1c636fff14721482ba0300f4b3604dd1a0a2fb53a272f13aac552e3.jpg)\n④ ![](images/f0331c3e341cee79ea412926996e046e6bfe25f546d8ed854993db3507d12374.jpg)",
+    "options": [
+      "A. ①",
+      "B. ②",
+      "C. ③",
+      "D. ④"
+    ],
+    "answer": "B",
+    "solution": "【分析】一个图形沿一条直线对折，直线两旁的图形完全重合，这样的图形叫做轴对称图形，折痕所在的直线是对称轴，由此解答。\n\n【详解】① 有对称轴，是轴对称图形;② 没有对称轴，不是轴对称图形;③ 有对称轴，是轴对称图形;④ 有对称轴，是轴对称图形。故答案为:B",
+    "knowledge_points": [
+      "轴对称的认识及辨认"
+    ],
+    "source": "23-24二年级下·山东菏泽·期末"
+  },
+  {
+    "id": "108",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下列现象中，( )是平移现象。",
+    "options": [
+      "A. 呼拉圈运动",
+      "B. 举重",
+      "C. 钟表指针运动"
+    ],
+    "answer": "B",
+    "solution": "【分析】平移是物体运动时，物体上任意两点间，从一点到另一点的方向与距离都不变的运动;旋转是物体运动时，每一个点离同一个点(可以在物体外)的距离不变的运动，称为绕这个点的转动，这个点称为物体的转动中心。所以，它并不一定是绕某个轴的;也可以这样说平移是不转动的，旋转自然是转动的，依此根据平移与旋转定义判断即可。\n\n【详解】A。 呼啦圈运动绕着一个点转动，是旋转现象;B. 举重运动物体上两点间距离不变，是平移现象;C. 钟表指针运动绕着一个点转动，是旋转现象。故答案为:B",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "23-24 二年级下·河北邯郸·期末"
+  },
+  {
+    "id": "109",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面汉字中，( )不是轴对称图形。",
+    "options": [
+      "A. 国",
+      "B. 回",
+      "C. 干"
+    ],
+    "answer": "A",
+    "solution": "【分析】一个图形沿一条直线对折，直线两旁的图形完全重合，这样的图形叫做轴对称图形，折痕所在的直线是对称轴，由此解答。\n\n【详解】A。 国没有对称轴，不是轴对称图形;B. 回有对称轴，是轴对称图形;C. 干有对称轴，是轴对称图形。则国不是轴对称图形。故答案为:A",
+    "knowledge_points": [
+      "轴对称的认识及辨认"
+    ],
+    "source": "23-24 二年级下·黑龙江佳木斯·期末"
+  },
+  {
+    "id": "110",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下列图形中不是轴对称图形的是( )。",
+    "options": [
+      "A. ![](images/f923a5f0d23e63a16aed14cceebd745ffa9352640278fd6ce5bd89c35470512d.jpg)",
+      "B. ![](images/afad6886734bc4de9a83d9ffec95f9c5e20675af6849033432833f5bbcc909ba.jpg)",
+      "C. ![](images/353838df879857d897b7ab07d9e7c454deb115dc613b80066deae7d8d333e39d.jpg)"
+    ],
+    "answer": "C",
+    "solution": "【分析】一个图形沿一条直线对折后，直线两旁的部分能够完全重合，这样的图形叫做轴对称图形，这条直线叫做对称轴。逐项分析各个选项，找出不属于轴对称图形的选项即可解答。\n\n【详解】A。 沿着竖直的直线对折，两侧能完全重合，是轴对称图形;B. 沿着水平的直线对折，两侧能完全重合，是轴对称图形;C. 不论怎么对折，两侧不能完全重合，所以不是轴对称图形。故答案为:C",
+    "knowledge_points": [
+      "轴对称的认识及辨认"
+    ],
+    "source": "24-25 二年级下·内蒙古鄂尔多斯·期中"
+  },
+  {
+    "id": "111",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下列各组图形，可以经过平移变换由一个图形得到另一个图形的是( )。",
+    "options": [
+      "A. ![](images/cfbe3cdd591cff44fbd7742be86526c1baaac14834c29ee10ec85bb223a91c05.jpg)",
+      "B. ![](images/760c145dbc4715ffafd292de6ad171d47d498f46bfbf6d8f4ae789174fbc1523.jpg)",
+      "C. ![](images/aa35952e3e15f5ff59cb7fc3d47138ee873a2cfa37b3f463c0bab9bbdd16f2b6.jpg)"
+    ],
+    "answer": "A",
+    "solution": "【分析】平移是物体运动时，物体上任意两点间，从一点到另一点的方向与距离都不变的运动;旋转是物体运动时，每一个点离同一个点(可以在物体外)的距离不变的运动，称为绕这个点的转动，这个点称为物体的转动中心。所以，它并不一定是绕某个轴的;也可以这样说平移是不转动的，旋转自然是转动的，依此根据平移与旋转定义判断即可。\n\n【详解】A。 两个图形的大小和形状都没有发生变换，物体上任何两点之间，方向距离都不变，该运动为平移，符合题意;B. 两个图形大小发生改变，物体上任何两点之间，距离发生改变，该运动不是平移，不符合题意;C. 两个图形是通过一个图形绕点旋转得到另一个图形，该运动是旋转，不符合题意。故答案为:A",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "24-25二年级下·内蒙古鄂尔多斯·期中"
+  },
+  {
+    "id": "112",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面三幅图中，图( )是通过下图平移得到的。\n![](images/07ba75bfc7fc8c762fda3cee3a54a55155c5031c2d207e68da439f2e23952b10.jpg)",
+    "options": [
+      "A. ![](images/ef5ce029b49e94b3d49c30a0b8560e953b4542f3d62d68b5913086a43fa81b68.jpg)",
+      "B. ![](images/6b0dd415a11fdee7b8ef13787254cda8f221fae99ab8752b0150417465ea5032.jpg)",
+      "C. ![](images/c543f355d88b34027662133fecf158cc77eb915407f55239ce0aaf3e467b98ea.jpg)"
+    ],
+    "answer": "B",
+    "solution": "【分析】平移是指在平面内将一个图形上的所有点都按照某个直线方向做相同距离的移动，这样的运动叫做图形的平移运动。平移只改变图形的位置，不改变图形的大小、形状和方向。\n\n【详解】A. 图中花的方向与原图不一样，所以不能通过平移得到;B. 与原图完全一样，所以能通过平移得到;C. 图中花的方向与原图不一样，所以不能通过平移得到。故答案为:B",
+    "knowledge_points": [
+      "平移与平移现象"
+    ],
+    "source": "23-24 二年级下·福建龙岩·期末"
+  },
+  {
+    "id": "113",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "河南卢氏剪纸是国家级非物质文化遗产之一，其内容和题材多种多样，形成了一道独特的文化景观。下列剪纸图案中，不是轴对称图形的是( )。",
+    "options": [
+      "A. ![](images/5a038ef5765c156bb57491cd695cd73d94f551e1c51833ca2349dae32655fe86.jpg)",
+      "B. ![](images/ba72a97f38134c1c2800fda063c661cd01b8a31fc4fcaf356bebbf8475030fe1.jpg)",
+      "C. ![](images/49050ad45d24ddfca5a1da4fcbebd61678dda46ac265f74803a2496a800d5a27.jpg)"
+    ],
+    "answer": "C",
+    "solution": "【分析】一个图形沿一条直线对折后，直线两旁的部分能够完全重合，这样的图形叫做轴对称图形，这条直线叫做对称轴。逐项分析各个选项，找出不属于轴对称图形的选项即可解答。\n\n【详解】A. 沿着竖直的直线对折，两侧能完全重合，是轴对称图形;B. 沿着竖直的直线对折，两侧能完全重合，是轴对称图形;C. 不论怎么对折，两侧都不能完全重合，所以不是轴对称图形。故答案为:C",
+    "knowledge_points": [
+      "轴对称的认识及辨认"
+    ],
+    "source": "23-24 二年级下·河南濮阳·期末"
+  },
+  {
+    "id": "114",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下列现象属于旋转的是( )。",
+    "options": [
+      "A. 推拉抽屉",
+      "B. 电风扇转动",
+      "C. 升国旗",
+      "D. 坐电梯"
+    ],
+    "answer": "B",
+    "solution": "【分析】在平面内，把一个图形整体沿某条直线方向平行移动一定距离的过程，称为平移，常见的平移现象有滑滑梯，传送带的移动等。在平面内，把一个图形围绕某一固定点按顺时针或逆时针方向转动一定的角度的过程，称为旋转，常见的旋转现象有旋转木马，摩天轮等。由此解答。\n\n【详解】A。 推拉抽屉是平移现象，不符合题意;B. 电风扇转动是旋转现象，符合题意;C. 升国旗是平移现象，不符合题意;D. 坐电梯是平移现象，不符合题意。则属于旋转的是电风扇转动。故答案为:B",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "24-25 一年级下·湖南岳阳·期中"
+  },
+  {
+    "id": "115",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面虚线是对称轴的是( )。",
+    "options": [
+      "A. ![](images/2f6eff8350d4ef57f8cb5397a9aa3ef9b6b5bcc31954fa5b8ce37f03293c4fc9.jpg)",
+      "B. ![](images/a1933e517dbaaa07fcd1c36757a49cfc46153020e56ffee3ad894e108dc2220f.jpg)",
+      "C. ![](images/aa0da4448f27552ecde5987dd44a1117d9cfe090c8ceadf7182ad96dfccd6314.jpg)",
+      "D. ![](images/c51ae5b0ccf87f36b0a3a36051aaaa908a901b586d8c73d7e0c39f973d74e8a2.jpg)"
+    ],
+    "answer": "A",
+    "solution": "【分析】一个图形沿一条直线对折，直线两旁的图形完全重合，这样的图形叫做轴对称图形，折痕所在的直线是对称轴，由此解答。\n\n【详解】A. 沿虚线对折后，两侧的图形能完全重合，所以虚线是对称轴;B. 沿虚线对折后，两侧的图形不能完全重合，所以虚线不是对称轴;C. 沿虚线对折后，两侧的图形不能完全重合，所以虚线不是对称轴;D. 沿虚线对折后，两侧的图形不能完全重合，所以虚线不是对称轴。故答案为:A",
+    "knowledge_points": [
+      "轴对称的认识及辨认"
+    ],
+    "source": "23-24 二年级下·广东东莞·期末"
+  },
+  {
+    "id": "116",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面的运动现象中，平移的有( )个，旋转的有( )个。\n![](images/88d7299a892f2d59128d3f9211b483d7f5449143895a863af3123179c9702b21.jpg)",
+    "options": [
+      "A. 4;4",
+      "B. 3;4",
+      "C. 4;3",
+      "D. 5;2"
+    ],
+    "answer": "A",
+    "solution": "【分析】平移是物体运动时，物体上任意两点间，从一点到另一点的方向与距离都不变的运动;旋转是物体运动时，每一个点离同一个点(可以在物体外)的距离不变的运动，称为绕这个点的转动，这个点称为物体的转动中心。所以，它并不一定是绕某个轴的;也可以这样说平移是不转动的，旋转自然是转动的，依此根据平移与旋转定义判断即可。\n\n【详解】图一，转盘转动的运动是旋转现象;图二，推玻璃的运动是平移现象;图三，转动方向盘的运动是旋转现象;图四，上下拨动算珠的运动是平移现象;图五，拉开抽屉的运动是平移现象;图六，旋转玻璃门的运动是旋转现象;图七，光盘进出的运动是平移运动;图八，扭动水龙头的运动是旋转现象。由此可知，平移现象有4个，旋转现象有4个。故答案为:A",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "23-24二年级下·山东菏泽·期末"
+  },
+  {
+    "id": "117",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下列图形中不是轴对称图形的是( )。",
+    "options": [
+      "A. ![](images/40e750c4fbfea8f70fe06d77772339dc745e8484c97a12440f5d1b8e7aad54e1.jpg)",
+      "B. ![](images/1ae2c6e29339a2b92dc2e724ed87a1a6da783e7cc6d7c1f8e69c0f6811682913.jpg)",
+      "C. ![](images/c7b4c4e7fc07acf0725d72f34c832e5620534df0bd609b6c5abdbf94d78bb72a.jpg)"
+    ],
+    "answer": "C",
+    "solution": "【分析】根据一个图形沿一条直线对折，直线两旁的图形完全重合，这样的图形叫做轴对称图形，折痕所在的直线就是对称轴，逐个分析选项即可解答。\n\n【详解】A。 沿着图形中间对折，折痕两边能完全重合，是轴对称图形;B. 沿着图形中间对折，折痕两边能完全重合，是轴对称图形;C. 沿着图形任意方向对齐，折痕两边不能完全重合，不是轴对称图形。故答案为:C",
+    "knowledge_points": [
+      "轴对称的认识及辨认"
+    ],
+    "source": "23-24二年级下·山东临沂·期末"
+  },
+  {
+    "id": "118",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下列现象中,( )是旋转现象。",
+    "options": [
+      "A. 电梯移动",
+      "B. 锯木材",
+      "C. 拧瓶盖"
+    ],
+    "answer": "C",
+    "solution": "【分析】在平面内，把一个图形整体沿某条直线方向平行移动一定距离的过程，称为平移。常见的平移现象有滑滑梯，电梯的移动等;在平面内，把一个图形围绕某一固定点按顺时针或逆时针方向转动一定的角度的过程，称为旋转。常见的旋转现象有旋转木马，摩天轮等。由此解答。\n\n【详解】A。 电梯移动是平移现象;B. 锯木材是平移现象;C. 拧瓶盖是旋转现象。故答案为:C",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "23-24二年级下·河北邯郸·期末"
+  },
+  {
+    "id": "119",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "折叠后，沿图案边缘线剪下来，能剪出( )个完整的台灯图案.\n![](images/510d3d98d7ce0a601428c6b0f393886b0707d1585f51a62428fd557e61a2a516.jpg)",
+    "options": [
+      "A. 1",
+      "B. 2",
+      "C. 3",
+      "D. 4"
+    ],
+    "answer": "B",
+    "solution": "【分析】根据给出图案，只显示了台灯的一半，可以推测纸张的另一页有与其对称的另一半台灯，沿着图案边缘剪下来，展开后就可以得到一个完整的台灯，图案中给出了两个台灯的一半，所以可以得到两个。\n\n【详解】据分析可得：能剪出2个完整的台灯图案。故答案为:B",
+    "knowledge_points": [
+      "轴对称的剪纸问题"
+    ],
+    "source": "23-24 二年级下·福建莆田·期末"
+  },
+  {
+    "id": "120",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "脸谱，是中国传统戏曲演员脸上的绘画，属于中国传统艺术。以下脸谱中属于轴对称的图形有( )个.\n![](images/e4e7a8e0fbc70ab3402af309f4568fb99960f1cbe7955e8f4a6acb6c3787d093.jpg)\n![](images/fa10f981a2d6cbb97f80886fb2f929e0be9911a400e04e4f807c7103ae0e45b7.jpg)\n![](images/0666f944c3d74e529398083154d29b13bbfed8f3f14a1be1f1ee350a21b37745.jpg)\n![](images/7c1c92b6f24d61e11ff7e7afe359b4dbc7a7a116e47bc69c44134ef3268b4b4d.jpg)",
+    "options": [
+      "A. 1",
+      "B. 2",
+      "C. 3"
+    ],
+    "answer": "B",
+    "solution": "【分析】一个图形沿一条直线对折，直线两旁的图形完全重合，这样的图形叫做轴对称图形，折痕所在的直线是对称轴，由此解答。\n\n【详解】由分析得：属于轴对称的图形有2个。故答案为:B",
+    "knowledge_points": [
+      "轴对称的认识及辨认"
+    ],
+    "source": "23-24 二年级下·浙江舟山·期末"
+  },
+  {
+    "id": "121",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "下列图形中，不是轴对称图形的是( )。",
+    "options": [
+      "A. O",
+      "B. E",
+      "C. N"
+    ],
+    "answer": "C",
+    "solution": "【分析】在平面内，如果沿着一条直线折叠，直线两旁的部分能够完全重合，这样的图形叫轴对称图形。据此分析。\n\n【详解】A. O通过它的中心画一条直线，沿着这条线对折就能重合，是轴对称图形;B. E通过中间的横线画一条直线，沿着这条线对折就能重合，是轴对称图形;C. N找不到对称轴，不是轴对称图形。故答案为:C",
+    "knowledge_points": [
+      "轴对称的认识及辨认"
+    ],
+    "source": "23-24二年级下·浙江·期末"
+  },
+  {
+    "id": "122",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下列各种现象中，属于旋转的有( )种。\n打开水龙头时，水龙头的运动;秋千荡起来时，秋千的运动;\n汽车开动时，车轮的运动;升国旗时，国旗的运动。",
+    "options": [
+      "A. 1",
+      "B. 2",
+      "C. 3",
+      "D. 4"
+    ],
+    "answer": "C",
+    "solution": "【分析】在平面内，把一个图形整体沿某条直线方向平行移动一定距离的过程，称为平移。常见的平移现象有滑滑梯、电梯的移动等;在平面内，把一个图形围绕某一固定点按顺时针或逆时针方向转动一定的角度的过程，称为旋转。常见的旋转现象有旋转木马、摩天轮等。逐项分析题干给出的4种情况属于哪种现象，数出旋转的有几种即可解答。\n\n【详解】打开水龙头时，水龙头的运动是旋转;秋千荡起来时，秋千的运动是旋转;汽车开动时，车轮的运动是旋转;升国旗时，国旗的运动是平移。这些现象中，属于旋转的有3种。故答案为:C",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "23-24 二年级下·福建龙岩·期末"
+  },
+  {
+    "id": "123",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "如图，有( )条小鱼平移后与涂色小鱼重合.\n![](images/5adb6933ca5b11abfb2acf12182cdf4b053bcf4600ab4915a4624deafd11f1e9.jpg)",
+    "options": [
+      "A. 2",
+      "B. 3",
+      "C. 6"
+    ],
+    "answer": "B",
+    "solution": "【分析】在平面内，把一个图形整体沿某条直线方向平行移动一定距离的过程，称为平移。物体或图形平移后，大小，形状，方向都不变，只有位置发生变化，由此解答。\n\n【详解】由分析得：有3条小鱼平移后与涂色小鱼重合。故答案为:B",
+    "knowledge_points": [
+      "平移与平移现象"
+    ],
+    "source": "23-24 二年级下·湖北襄阳·期末"
+  },
+  {
+    "id": "124",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "下面小船( )是由原图通过平移拼成的。",
+    "options": [
+      "A. ![](images/5f091928addc0a6442601fb6f78ec9f08baf4f94a122e7ac419ed2d67ae666a7.jpg)",
+      "B. ![](images/d39e269a06c12154a74eb6c537035cca57e04605b365bd74ab82a3950dd193ba.jpg)",
+      "C. ![](images/5086a301fe4642601bcdd1ad7f8b9a77d53b1328fd7f1f652e665d893f20446f.jpg)"
+    ],
+    "answer": "C",
+    "solution": "【分析】在平面内，把一个图形整体沿某条直线方向平行移动一定距离的过程，称为平移。常见的平移现象有滑滑梯、电梯的移动等。据此解答。\n\n【详解】由分析可得：A. 这个小船中船帆三角形的尖朝左，题目中的三角形尖朝右，不能通过平移拼成，不符合题意;B. 这个小船中的各个图形都倾斜了一定的角度，不可能通过平移拼成，不符合题意;C. 这个小船中的各个图形跟题目中的图形都能一一对应，方向、角度都一致，可以通过平移拼成，符合题意。故答案为:C",
+    "knowledge_points": [
+      "平移与平移现象"
+    ],
+    "source": "23-24 二年级下·湖北黄石·期末"
+  },
+  {
+    "id": "125",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "下列图形中对称轴最多的是( )。",
+    "options": [
+      "A. ![](images/7dfd9cc7027790e342850231968d026333152273d9394c130d848283aabfb715.jpg)",
+      "B. ![](images/d5c9d4854ad07fd6321f517c83454a932abea99d3165d9a9ba861b7be190059f.jpg)",
+      "C. ![](images/d5ca87aa41345584dab16c24ec6ffb3c5da1155833ccf636f1f854b96a24f563.jpg)"
+    ],
+    "answer": "A",
+    "solution": "【分析】一个图形沿一条直线对折，直线两旁的图形完全重合，这样的图形叫做轴对称图形，折痕所在的直线就是对称轴。据此解答。\n\n【详解】由分析可得：A. 有2条对称轴;B. 有1条对称轴;C. 有1条对称轴。因为2>1，所以对称轴最多的是A。故答案为:A",
+    "knowledge_points": [
+      "对称轴的画法及数量"
+    ],
+    "source": "23-24 二年级下·湖北黄石·期末"
+  },
+  {
+    "id": "126",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下边的图打开后是( )。\n![](images/37fddc1190a72859ba2fe87cc9681b553522355159e388327a57467a42e1aacd.jpg)",
+    "options": [
+      "A. ![](images/fffea26d68eb45d866bdcdf3f6ef9ad831756f06bb359c0e78c9257a79243a34.jpg)",
+      "B. ![](images/af740bbeafc54265001988f5d185944e41a843891bb5aed3fcfa4b46596119cb.jpg)",
+      "C. ![](images/14664fdc34f5345cb5f35fe6f1606d62e7746621d06fc29103801b73f31ff554.jpg)"
+    ],
+    "answer": "A",
+    "solution": "【分析】一个图形沿一条直线对折，直线两旁的图形完全重合，这样的图形叫做轴对称图形，折痕所在的直线就是对称轴;由于该图是把一张纸对折的图形，展开后的图形是轴对称图形，折痕就是图形的对称轴，并且对称轴一侧的上边三角形的一个角远离折痕，下边长方形也远离折痕。据此解答。\n\n【详解】A。 对称轴一侧的上边三角形的一个角远离折痕，下边长方形也远离折痕，符合题意;B. 对称轴一侧的上边三角形的一个角靠近折痕，下边长方形远离折痕，不符合题意;C. 对称轴一侧的上边三角形的一个角靠近折痕，下边长方形也靠近折痕，不符合题意。故答案为:A",
+    "knowledge_points": [
+      "轴对称的剪纸问题"
+    ],
+    "source": "23-24 二年级下·重庆大渡口·期末"
+  },
+  {
+    "id": "127",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面图形中，轴对称图形有几个。( )\n![](images/4c841f251797585c678777466ffd5238.png)",
+    "options": [
+      "A. 2个",
+      "B. 3个",
+      "C. 4个"
+    ],
+    "answer": "B",
+    "solution": "【分析】如果一个图形沿着一条直线对折，直线两边的图形能够完全重合，这样的图形叫轴对称图形，这条直线叫对称轴，据此解答即可。\n\n【详解】由分析得：图一，图二和图四有对称轴，是轴对称图形，所以轴对称图形有3个。故答案为:B",
+    "knowledge_points": [
+      "轴对称的认识及辨认"
+    ],
+    "source": "23-24 二年级下·天津和平·期末"
+  },
+  {
+    "id": "128",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面的图形中，是轴对称图形的是( )。",
+    "options": [
+      "A. ![](images/a4970f673da9b40630d16a297d1e41fbbb716a5193121f4c31a26011aa50a7ad.jpg)",
+      "B. ![](images/ce010b1a835277bab553de83e352c7db99e64f489a725226c7a9633ec095a6f9.jpg)",
+      "C. ![](images/0693397f9bc62a7f7f70d1e5115d42827055aa2388bac70c2274c6d2fd816c51.jpg)"
+    ],
+    "answer": "A",
+    "solution": "【分析】一个图形沿一条直线对折，直线两旁的图形完全重合，这样的图形叫做轴对称图形，折痕所在的直线就是对称轴。由此依次分析每个选项是否满足对折之后完全重合，即可解答。\n\n【详解】A. 两朵花沿着中间对折后，能够完全重合，符合题意;B. 两只蝴蝶都朝着右上方，无论怎么对折，都不能完全重合，不符合题意;C. 两只小牛沿着中间对折后，尾巴无法重合，不符合题意。故答案为:A",
+    "knowledge_points": [
+      "轴对称的认识及辨认"
+    ],
+    "source": "23-24 二年级下·河南南阳·期末"
+  },
+  {
+    "id": "129",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面现象中,( )不是旋转。",
+    "options": [
+      "A. ![](images/0d8832876a33d8e97541641970c01d22995d46e842514b26d44e2348a5e59522.jpg) 拧水龙头",
+      "B. ![](images/b916ae607ddee7a4005a9560068271624efc0c8dd6064a224d8426bb97e61c57.jpg) 乘自动扶梯",
+      "C. ![](images/6ef674e262abb1ab90166a2f72afc349a3ca58a3c494eaf4da6a641afa27f21c.jpg) 吊扇旋转"
+    ],
+    "answer": "B",
+    "solution": "【分析】平移是指在平面内，将一个图形上的所有点都按照某个直线方向做相同距离的移动，这样的图形运动叫做图形的平移运动，简称平移。平移后图形的位置改变，形状、大小、方向不变。旋转是指在平面内，将一个图形绕一点按某个方向转动一定的角度，这样的运动叫做图形的旋转。旋转后图形的位置和方向改变，形状、大小不变。\n\n【详解】A. 拧水龙头是旋转;B. 乘自动扶梯是平移;C. 吊扇旋转是旋转。故答案为:B",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "23-24二年级下·湖北襄阳·期末"
+  },
+  {
+    "id": "130",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面图形中，不属于轴对称图形的是( )。",
+    "options": [
+      "A. ![](images/056f0763fcc33512e82a097cf0caa0855bae0ffe845cb59b23b69424f9bdad29.jpg)",
+      "B. ![](images/e8e75c032f09ff1a64600e2a0818fffbc3b4cf1255205ad3d94d5f78b9913602.jpg)",
+      "C. ![](images/a7849e4ae7921248a8691596095670a343183391b448d1627ce6b35f97329d72.jpg)",
+      "D. ![](images/ddf032bc9413f4848e9d1d202b8b61d05db2b8a566eee79fe5f019c742fb0f45.jpg)"
+    ],
+    "answer": "A",
+    "solution": "【分析】一个图形沿一条直线对折后，直线两旁的部分能够完全重合，这样的图形叫做轴对称图形，这条直线叫做对称轴。逐项分析各个选项，找出不属于轴对称图形的选项即可解答。\n\n【详解】A. 不论怎么对折，两侧都不能完全重合，所以不是轴对称图形;B. 沿着水平的直线对折，两侧能完全重合，是轴对称图形;C. 沿着竖直的直线对折，两侧能完全重合，是轴对称图形;D. 沿着竖直或者水平的直线对折，两侧能完全重合，是轴对称图形。故答案为:A",
+    "knowledge_points": [
+      "轴对称的认识及辨认"
+    ],
+    "source": "23-24 二年级下·福建龙岩·期末"
+  },
+  {
+    "id": "131",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "这些现象中( )是旋转。",
+    "options": [
+      "A. ![](images/897ab9ec674e4c82a969d3612553dc407eb277d4fa5bd8d7cd363d55753e28a1.jpg)",
+      "B. ![](images/f4cad44afbe8bac0af3a3fddb246afc09a92dd5c3b2fa3d34123f51f8335d3b6.jpg)",
+      "C. ![](images/da52ac86807c12f67811c2bff4581981746adee80bbf68201f029237373398b3.jpg)"
+    ],
+    "answer": "C",
+    "solution": "【分析】在平面内，把一个图形整体沿某条直线方向平行移动一定距离的过程，称为平移。常见的平移现象有滑滑梯、电梯的移动等;在平面内，把一个图形围绕某一固定点按顺时针或逆时针方向转动一定的角度的过程，称为旋转。常见的旋转现象有旋转木马、摩天轮等。由此解答。\n\n【详解】A. 属于平移现象;B. 属于平移现象;C. 属于旋转现象。故答案为:C",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "23-24二年级下·重庆永川·期末"
+  },
+  {
+    "id": "132",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面是平移运动的是( )。",
+    "options": [
+      "A. 国旗缓缓升起",
+      "B. 风扇叶片的转动",
+      "C. 荡秋千"
+    ],
+    "answer": "A",
+    "solution": "【分析】平移是指在平面内，将一个图形上的所有点都按照某个直线方向做相同距离的移动，这样的图形运动叫做图形的平移运动，简称平移。平移后图形的位置改变，形状，大小，方向不变。旋转：在平面内，将一个图形绕一点按某个方向转动一定的角度，这样的运动叫做图形的旋转。旋转后图形的位置和方向改变，形状，大小不变。\n\n【详解】A。 国旗缓缓升起是平移现象;B. 风扇叶片的转动是旋转现象;C. 荡秋千是旋转现象。是平移运动的是：国旗缓缓升起。故答案为:A",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "23-24二年级下·河南信阳·期末"
+  },
+  {
+    "id": "133",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面是旋转现象的是( )。",
+    "options": [
+      "A. 开关滑窗",
+      "B. 开关教室门",
+      "C. 推拉抽屉"
+    ],
+    "answer": "B",
+    "solution": "【分析】旋转：在平面内，将一个图形绕一点按某个方向转动一定的角度，这样的运动叫做图形的旋转。旋转后图形的位置和方向改变，形状，大小不变。平移是指在平面内，将一个图形上的所有点都按照某个直线方向做相同距离的移动，这样的图形运动叫做图形的平移运动，简称平移。平移后图形的位置改变，形状，大小，方向不变。\n\n【详解】A。 开关滑窗是平移现象;B. 开关教室门是旋转现象;C. 推拉抽屉是平移现象。是旋转现象的是开关教室门。故答案为:B",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "23-24二年级下·重庆丰都·期末"
+  },
+  {
+    "id": "134",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面图形的对称轴不正确的是( )。",
+    "options": [
+      "A. ![](images/47c5a475e7d6a0bb95c76b705fa4ef6c03a6b82214a14391dc43679d9be966ff.jpg)",
+      "B. ![](images/6f5b0eee06977593b5b61d1893ea5c60db14c71455ecc1a784a3ea6aa2a1fcf4.jpg)",
+      "C. ![](images/4a8e8e8e5c72a17b60d7fe93bec4019456f04e94b41bcb1d2a5829475bb4b3fb.jpg)"
+    ],
+    "answer": "A",
+    "solution": "【分析】依据轴对称图形的概念解决;在平面内，如果沿着一条直线折叠，直线两旁的部分能够完全重合，这样的图形叫做轴对称图形;这条直线是图形的对称轴。\n\n【详解】A. 上下两旁对折后不能够完全重合，所以此图对称轴不正确;B. 左右两旁对折后能够完全重合，所以此图对称轴正确;C. 上下两旁对折后能够完全重合，所以此图对称轴正确。故答案为:A",
+    "knowledge_points": [
+      "轴对称的认识及辨认",
+      "对称轴的画法及数量"
+    ],
+    "source": "24-25二年级下·福建福州·期中"
+  },
+  {
+    "id": "135",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "钟面上指针的运动是( )现象。",
+    "options": [
+      "A. 轴对称",
+      "B. 平移",
+      "C. 旋转"
+    ],
+    "answer": "C",
+    "solution": "【分析】在平面内，把一个图形整体沿某条直线方向平行移动一定距离的过程，称为平移。常见的平移现象有滑滑梯，电梯的移动等;在平面内，把一个图形围绕某一固定点按顺时针或逆时针方向转动一定的角度的过程，称为旋转。常见的旋转现象有旋转木马，摩天轮等。由此解答。\n\n【详解】根据分析可得：钟面上指针的运动是绕表芯顺时针转动的，是旋转现象。故答案为:C",
+    "knowledge_points": [
+      "旋转与旋转现象"
+    ],
+    "source": "23-24 二年级下·天津河东·期末"
+  },
+  {
+    "id": "136",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面图形中不是轴对称图形的是( )。",
+    "options": [
+      "A. ![](images/4c0db9828527684bb505f345bbf278848deb56025fce2a8e577d611bdbcfe7a9.jpg)",
+      "B. ![](images/f56f5c32e86b7fe44f5ecfc6b9fe0a5b6a089959dc5d26e9caaf190d8689f442.jpg)",
+      "C. ![](images/b5fdd502fe39ae2c679640d285d6682bca84cd09e744d66f01452231029f31ec.jpg)"
+    ],
+    "answer": "C",
+    "solution": "【分析】一个图形沿一条直线对折，直线两旁的图形完全重合，这样的图形叫做轴对称图形，折痕所在的直线是对称轴，由此解答。\n\n【详解】A. 有对称轴，是轴对称图形;B. 有对称轴，是轴对称图形;C. 没有对称轴，不是轴对称图形。故答案为:C",
+    "knowledge_points": [
+      "轴对称的认识及辨认"
+    ],
+    "source": "23-24 二年级下·天津河东·期末"
+  },
+  {
+    "id": "137",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面( )现象属于旋转。",
+    "options": [
+      "A. 拨算盘",
+      "B. 风扇转动",
+      "C. 滑滑梯"
+    ],
+    "answer": "B",
+    "solution": "【分析】平移是指在平面内，将一个图形上的所有点都按照某个直线方向做相同距离的移动，这样的图形运动叫做图形的平移运动，简称平移。平移后图形的位置改变，形状，大小，方向不变。旋转：在平面内，将一个图形绕一点按某个方向转动一定的角度，这样的运动叫做图形的旋转。旋转后图形的位置和方向改变，形状，大小不变。\n\n【详解】A。 拨算盘属于平移现象;B. 风扇转动属于旋转现象;C. 滑滑梯属于平移现象。风扇转动现象属于旋转。故答案为:B",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "23-24二年级下·河南漯河·期末"
+  },
+  {
+    "id": "138",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "夏天天气热，老师给大家打开风扇，风扇的扇叶在( )。",
+    "options": [
+      "A. 平移",
+      "B. 旋转",
+      "C. 轴对称"
+    ],
+    "answer": "B",
+    "solution": "【分析】在平面内，把一个图形整体沿某条直线方向平行移动一定距离的过程，称为平移。常见的平移现象有滑滑梯，电梯的移动等;在平面内，把一个图形围绕某一固定点按顺时针或逆时针方向转动一定的角度的过程，称为旋转。常见的旋转现象有旋转木马，摩天轮等。由此解答。\n\n【详解】根据分析可知：夏天天气热，老师给大家打开风扇，风扇的扇叶在旋转。故答案为:B",
+    "knowledge_points": [
+      "旋转与旋转现象"
+    ],
+    "source": "23-24 二年级下·河南信阳·期末"
+  },
+  {
+    "id": "139",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面现象中属于旋转的是( )。",
+    "options": [
+      "A. 推拉抽屉",
+      "B. 风车转动",
+      "C. 缆车行驶"
+    ],
+    "answer": "B",
+    "solution": "【分析】在平面内，把一个图形整体沿某条直线方向平行移动一定距离的过程，称为平移，常见的平移现象有滑滑梯，电梯的移动等。在平面内，把一个图形围绕某一固定点按顺时针或逆时针方向转动一定的角度的过程，称为旋转，常见的旋转现象有旋转木马，摩天轮等。由此解答。\n\n【详解】A。 推拉抽屉是平移现象，不符合题意;B. 风车转动是旋转现象，符合题意;C. 缆车行驶是平移现象，不符合题意。则属于旋转的是风车转动。故答案为:B",
+    "knowledge_points": [
+      "旋转与旋转现象"
+    ],
+    "source": "24-25 二年级下·湖南湘潭·期中"
+  },
+  {
+    "id": "140",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下列图形中，通过平移可以得到的是( )。\n![](images/32723d44ca10d68fc8709684161f412eb375dcc2accc12ee322898d48c44bc88.jpg)",
+    "options": [
+      "A. ![](images/4ee9356f7d2d126d62dd4f209908cfc27c21fc2d634a1a641a5305c1239af88b.jpg)",
+      "B. ![](images/dc7e1e1ecc8a796817a41812e61ffae01fb75c2808c4e53e157f76937deb291f.jpg)",
+      "C. ![](images/7d9a0a61d661adef843ff25effab9af58f4071525e273e1844e8549f2a3b67aa.jpg)"
+    ],
+    "answer": "C",
+    "solution": "【分析】平移是指在平面内将一个图形上的所有点都按照某个直线方向做相同距离的移动，这样的运动叫做图形的平移运动;平移不改变图形的形状、大小和方向，只改变位置。旋转是指在平面内将一个图形绕一点按某个方向转动一个角度，这样的运动叫做图形的旋转运动;旋转不改变图形的形状和大小，但会改变方向和位置。据此选择即可。\n\n【详解】A. 通过旋转可以得到;B. 通过旋转可以得到;C. 通过平移可以得到。故答案为:C",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "24-25 二年级下·山东济宁·期末"
+  },
+  {
+    "id": "141",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面的图形中，( )是轴对称图形。",
+    "options": [
+      "A. ![](images/2e9964ee6fd4dc52cc085021c1894a8d7f5888535ecc6d54936539356c6b5def.jpg)",
+      "B. ![](images/d6d95546550012a1be64b67bfdf250d53eb23e93c41f2a175e7b4adcd031233c.jpg)",
+      "C. ![](images/f267ab3906acb4060d6f9dc8e3bfad5a7a8006db043c686ed2c584197b5db947.jpg)"
+    ],
+    "answer": "A",
+    "solution": "【分析】如果一个图形沿着一条直线对折，两侧的图形能完全重合，这个图形就是轴对称图形。折痕所在的这条直线叫做对称轴。由此找出图形的对称轴即可解答。\n\n【详解】A. 有对称轴，是轴对称图形;B. 没有对称轴，不是轴对称图形;C. 没有对称轴，不是轴对称图形。故答案为:A",
+    "knowledge_points": [
+      "轴对称的认识及辨认"
+    ],
+    "source": "24-25二年级下·贵州黔西·期中"
+  },
+  {
+    "id": "142",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "左图的图案是从下面的第( )个对折后的图形上剪下来展开后得到的。\n![](images/88cd6c42f63f59ccd26355412f4281bf3b143315a386a6291a8950f039072bf5.jpg)",
+    "options": [
+      "A. ![](images/6d062c15caa8e2a4280cf5991d65370280a31e7ae99afbca7bf0381a267c3629.jpg)",
+      "B. ![](images/b5c74154d104c28fb2f4d342e561e9fb220eff22fa6bbee2f50289ccadaabba1.jpg)",
+      "C. ![](images/0bb361d8018b7bc6529d96a69d21483a7079fb2a5559724d9c7446f80bae67d9.jpg)"
+    ],
+    "answer": "C",
+    "solution": "【分析】根据题意，明确轴对称是指一个图形沿一条直线(对称轴)对折后，两部分能够完全重合。在剪纸问题中，对折的纸相当于对称轴，剪出的图案展开后会形成轴对称图形。把题干中的图形左右对折，对折后图形与选项中哪个图形缺少的部分能重合，就说明这个图形是从题干中的图形上剪下来的，据此即可解答。\n\n【详解】把题干中的图形左右对折后得到图形;A. 对折后图形与选项中图形缺少的部分不能重合，答案不正确;B. 对折后图形与选项中图形缺少的部分不能重合，答案不正确;C. 对折后图形与选项中图形缺少的部分能重合，答案正确。故答案为:C",
+    "knowledge_points": [
+      "轴对称的剪纸问题"
+    ],
+    "source": "24-25二年级下·辽宁鞍山·期中"
+  },
+  {
+    "id": "143",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面图形中，是轴对称图形的是( )。",
+    "options": [
+      "A. ![](images/82ba718245c64c8dca7e59586a475ebcbee6b62f6fdb7554732b8be38e4ed1e4.jpg)",
+      "B. ![](images/4f432b9a21a4c69ba04c862d9e4b712a940a087358eede5ea8c94a4aaf325f46.jpg)",
+      "C. ![](images/18f9342156cb3bfbdfa6e2c1fd38b132fb276ec26f3a6936485ddebf148d0477.jpg)"
+    ],
+    "answer": "A",
+    "solution": "【分析】如果一个平面图形沿着一条直线对折后，直线两旁的部分能够互相重合，那么这个图形叫做轴对称图形，这条直线是图形的对称轴，据此解答。\n\n【详解】A. 沿图中直线对折后，直线两旁的部分可以互相重合，是轴对称图形，符合题意;B. 不能沿一条直线对折，让直线两旁的部分互相重合，不是轴对称图形;C. 不能沿一条直线对折，让直线两旁的部分互相重合，不是轴对称图形。故答案为:A",
+    "knowledge_points": [
+      "轴对称的认识及辨认"
+    ],
+    "source": "24-25二年级下·陕西延安·期中"
+  },
+  {
+    "id": "144",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下图是从哪张对折后的纸上剪下来的。( )\n![](images/f2e681ce588d297b0f72a403ccb06b18816489b44dc4a6e3401691adeae9d4c1.jpg)",
+    "options": [
+      "A. ![](images/14e262bc1694dec12b29ee5baed11210df27fc7eed7c303de793139158e419e4.jpg)",
+      "B. ![](images/cb606a5bfddd70dc35f48f54e5c69a3951ba607b7eff79fcf3503206c25b6182.jpg)",
+      "C. ![](images/bb49aeac60fb0b25c5adfcda77be85cae0479e500674e6bc728c7b80673811ca.jpg)"
+    ],
+    "answer": "C",
+    "solution": "【分析】一个图形沿一条直线对折，直线两旁的图形完全重合，这样的图形叫做轴对称图形，折痕所在的直线是对称轴。由此画出图形的对称轴，将图形分成两部分，找到与其中一部分相同的即可。\n\n【详解】由分析作图如下:A. 与图形的哪一部分都不相同，不符合题意;B. 与图形的哪一部分都不相同，不符合题意;C. 与图形的右半部分相同，符合题意。则原图是从C上剪下来的。故答案为:C",
+    "knowledge_points": [
+      "轴对称的剪纸问题"
+    ],
+    "source": "24-25 二年级下·福建龙岩·期末"
+  },
+  {
+    "id": "145",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面的数字中，是轴对称数字的是。( )",
+    "options": [
+      "A. 0",
+      "B. 2",
+      "C. 4"
+    ],
+    "answer": "A",
+    "solution": "【分析】根据轴对称图形的意义：如果一个图形沿着一条直线对折后两部分完全重合，这样的图形叫做轴对称图形，据此逐项分析各个选项，找出是轴对称数字即可。\n\n【详解】A. 数字0在标准书写中是圆形或椭圆形，左右或者上下对折后，两侧能完全重合，因此是轴对称数字;B. 数字2左右不对称，对折后两半不能重合，因此不是轴对称数字;C. 数字4通常左边是斜线，右边是直线，左右不对称，对折后两半不能重合，因此不是轴对称数字。综上，只有选项A中的数字0是轴对称数字。故答案为:A",
+    "knowledge_points": [
+      "轴对称的认识及辨认"
+    ],
+    "source": "24-25 二年级下·新疆喀什·期中"
+  },
+  {
+    "id": "146",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面( )是轴对称图形。",
+    "options": [
+      "A. F",
+      "B. Z",
+      "C. 8"
+    ],
+    "answer": "C",
+    "solution": "【分析】如果一个图形沿着一条直线对折，两侧的图形能够完全重合，这个图形就是轴对称图形。据此解答即可。\n\n【详解】据分析可知：\"F\"和\"Z\"不是轴对称图形，\"8\"是轴对称图形。故答案为:C",
+    "knowledge_points": [
+      "轴对称的认识及辨认"
+    ],
+    "source": "24-25二年级下·黑龙江佳木斯·期中"
+  },
+  {
+    "id": "147",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下列通过下图平移得到的是图( )。\n![](images/a33b92dcdf383b535c4f3a13cc64b2a882525fb76b57a25f61e691b9c6d5b60b.jpg)",
+    "options": [
+      "A. ![](images/e0e5f8f795cba9f3c99e771b859716ec50d10d2c3e6bf08c40691e461fb7d3a8.jpg)",
+      "B. ![](images/f7dbb2a1f3ba23320fdd1451274450529c8595eb8e15dfdedd0f2126a9b181ab.jpg)",
+      "C. ![](images/052a92dd23f11612ab754041b1833b6140f79fa0dba57013b90eb1b4c1586855.jpg)"
+    ],
+    "answer": "C",
+    "solution": "【分析】在平面内，把一个图形整体沿某条直线方向平行移动一定距离的过程，称为平移。物体或图形平移后，大小、形状、方向都不变，只有位置发生变化，由此解答。\n\n【详解】A. 方向发生了变化，不符合题意;B. 方向发生了变化，不符合题意;C. 大小、形状、方向都不变，只有位置发生变化，符合题意。故答案为:C",
+    "knowledge_points": [
+      "平移与平移现象"
+    ],
+    "source": "24-25二年级下·福建龙岩·期中"
+  },
+  {
+    "id": "148",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下列是平移现象的是( )。",
+    "options": [
+      "A. 荡秋千",
+      "B. 风车转动",
+      "C. 拉抽屉"
+    ],
+    "answer": "C",
+    "solution": "【分析】平移是指在平面内，将一个图形上的所有点都按照某个直线方向做相同距离的移动，这样的图形运动叫做图形的平移运动，简称平移。平移后图形的位置改变，形状，大小，方向不变。旋转：在平面内，将一个图形绕一点按某个方向转动一定的角度，这样的运动叫做图形的旋转。旋转后图形的位置和方向改变，形状，大小不变。\n\n【详解】A。 荡秋千是旋转现象;B. 风车转动是旋转现象;C. 拉抽屉是平移现象。故答案为:C",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "24-25 二年级下·新疆喀什·期中"
+  },
+  {
+    "id": "149",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面现象中,( )不是旋转。",
+    "options": [
+      "A. 钟表指针的运动",
+      "B. 电梯的升降",
+      "C. 风车的转动"
+    ],
+    "answer": "B",
+    "solution": "【分析】在平面内，把一个图形整体沿某条直线方向平行移动一定距离的过程，称为平移。常见的平移现象有滑滑梯、电梯的移动等;在平面内，把一个图形围绕某一固定点按顺时针或逆时针方向转动一定的角度的过程，称为旋转。常见的旋转现象有旋转木马、摩天轮等。由此解答。\n\n【详解】A. 钟表指针是绕中心轴转动，属于旋转现象;B. 电梯的升降是电梯整体上下移动，属于平移现象;C. 风车的转动是风叶绕中心轴转动，属于旋转现象。故答案为:B",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "24-25 二年级下·黑龙江佳木斯·期中"
+  },
+  {
+    "id": "150",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面( )是轴对称图形。",
+    "options": [
+      "A. P",
+      "B. F",
+      "C. T"
+    ],
+    "answer": "C",
+    "solution": "【分析】一个图形沿着一条直线对折后，直线两旁的部分能够完全重合，这样的图形就叫做轴对称图形，据此解答。\n\n【详解】A. P沿着一条直线对折后，直线两旁的部分不能完全重合，所以它不是轴对称图形;B. F沿着一条直线对折后，直线两旁的部分不能完全重合，所以它不是轴对称图形;C. T沿着一条直线对折后，直线两旁的部分能够完全重合，所以它是轴对称图形。故答案为:C",
+    "knowledge_points": [
+      "轴对称的认识及辨认"
+    ],
+    "source": "24-25 二年级下·黑龙江佳木斯·期中"
+  },
+  {
+    "id": "151",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面汉字不是轴对称图形的是( )。",
+    "options": [
+      "A. 由",
+      "B. 中",
+      "C. 国"
+    ],
+    "answer": "C",
+    "solution": "【分析】一个图形沿一条直线对折，直线两旁的图形完全重合，这样的图形叫做轴对称图形，折痕所在的直线是对称轴，由此解答。\n\n【详解】A. \"由\"有对称轴，是轴对称图形;B. \"中\"有对称轴，是轴对称图形;C. \"国\"没有对称轴，不是轴对称图形。故答案为:C",
+    "knowledge_points": [
+      "轴对称的认识及辨认"
+    ],
+    "source": "24-25 二年级下·陕西渭南·期中"
+  },
+  {
+    "id": "152",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下列图形不是轴对称图形的是( )。",
+    "options": [
+      "A. ![](images/59521a9f2fab04eb33e461d61dfec79450df371c1bf0bc984ece564179b1fb1f.jpg)",
+      "B. ![](images/0cd16949a9db31051384db77fb99a582de164377e3b978ae8502e2654a078659.jpg)",
+      "C. ![](images/fb53d560e83554e61d2b1dcd81dff1dc8f489078aef5c1a3a95f0514b5b01ff4.jpg)"
+    ],
+    "answer": "A",
+    "solution": "【分析】根据一个图形沿一条直线对折，直线两旁的图形完全重合，这样的图形叫做轴对称图形，据此作答。\n\n【详解】A. 无论沿哪条直线对折，直线两旁的图形都不能完全重合，所以该图形不是轴对称图形;B. 沿着该图形正中间的直线对折，两旁图形完全重合，该图形是轴对称图形;C. 沿着该图形正中间的直线对折，两旁图形完全重合，该图形是轴对称图形。故答案为:A",
+    "knowledge_points": [
+      "轴对称的认识及辨认"
+    ],
+    "source": "24-25 二年级下·吉林松原·期中"
+  },
+  {
+    "id": "153",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面不是轴对称图形的是( )。",
+    "options": [
+      "A. ![](images/1dee90c37816adf7e52395d133537f77e914c49179292c579ec01a79a12e5754.jpg)",
+      "B. ![](images/716a2a4f292d54fd9f79b2ff98d8ea0e905c1c7854933231d64ca721c7675065.jpg)",
+      "C. ![](images/72ece4b5c5af02acd268e064869e1fda747a023235339389580b1ae7d105c26f.jpg)"
+    ],
+    "answer": "C",
+    "solution": "【分析】一个图形沿一条直线对折，直线两旁的图形完全重合，这样的图形叫做轴对称图形，折痕所在的直线就是对称轴，逐项分析各个选项，找到不是轴对称图形的即可。\n\n【详解】A. 沿虚线上下对折或者左右对折，两旁图形完全重合，是轴对称图形;B. 沿虚线上下对折或者左右对折，两旁图形完全重合，是轴对称图形;C. 不论怎么画虚线，两旁图形都不能重合，不是轴对称图形。故答案为:C",
+    "knowledge_points": [
+      "轴对称的认识及辨认"
+    ],
+    "source": "24-25 二年级下·四川乐山·期中"
+  },
+  {
+    "id": "154",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面现象中，( )是旋转。",
+    "options": [
+      "A. ![](images/4b7b0d7d2b5c43de0f7563569864c5211e3fa7c144e1290fb6a8ca82c9f8ae7d.jpg)",
+      "B. ![](images/14e5d12dadcf7c7f0804076015143f99744a7b72e602c9a3d6b1abd0c223c744.jpg)",
+      "C. ![](images/f8a30506819d2e68e4dad099d676c7b54b3270fb84e630e9863297ad86dc81bf.jpg)"
+    ],
+    "answer": "C",
+    "solution": "【分析】在平面内，把一个图形整体沿某条直线方向平行移动一定距离的过程，称为平移，常见的平移现象有滑滑梯、电梯的移动等。在平面内，把一个图形围绕某一固定点按顺时针或逆时针方向转动一定的角度的过程，称为旋转，常见的旋转现象有旋转木马、摩天轮等。由此解答。\n\n【详解】A. 推动箱子是平移现象，不符合题意;B. 推拉窗户是平移现象，不符合题意;C. 电风扇的转动是旋转现象，符合题意。故答案为:C",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "24-25二年级下·山东济南·期末"
+  },
+  {
+    "id": "155",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面的运动( )是平移现象。",
+    "options": [
+      "A. ![](images/695e65468de59a57a7de2a202f2bc27a519379aeb1813cc2efecaae3950c662d.jpg)",
+      "B. ![](images/316cd23b28504c2ca9604d2cc4098c54fc27b73bd40c2dde1236282cedfe6f86.jpg)",
+      "C. ![](images/63ae240cc3d6caf70d961d85614dc43d700ec14cc05f7b85c5964fb3aa32c739.jpg)"
+    ],
+    "answer": "C",
+    "solution": "【分析】在平面内，把一个图形整体沿某条直线方向平行移动一定距离的过程，称为平移，常见的平移现象有滑滑梯，推拉窗户等。在平面内，把一个图形围绕某一固定点按顺时针或逆时针方向转动一定的角度的过程，称为旋转，常见的旋转现象有旋转木马，摩天轮等。\n\n【详解】A。 直升机旋翼的转动是旋转现象;B. 圆盘的转动是旋转现象;C. 拨动算珠是平移现象。则C是平移现象。故答案为:C",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "24-25二年级下·广东云浮·期中"
+  },
+  {
+    "id": "156",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面是由原图通过平移拼成的小船是( )。\n![](images/f0c9b24f1c5b8907bd8f0474de72647972f1cff0a94558478d2acd934cd64b08.jpg)",
+    "options": [
+      "A. ![](images/44905925cdb92810267d3bc37838d590a57edadec909a5fb01d40e912ae49266.jpg)",
+      "B. ![](images/b689fe8c1bda38be591a7f85bdd5ad00cc45f124e5e0d21058a34827a887efbd.jpg)",
+      "C. ![](images/eeecc380b757c0b6780d6577ac23475e30f622fbd60b6740effe7875885515b5.jpg)"
+    ],
+    "answer": "C",
+    "solution": "【分析】在平面内，把一个图形整体沿某条直线方向平行移动一定距离的过程，称为平移。平移不改变图形的大小，方向，形状，只有位置发生了变化，由此解答。\n\n【详解】A。 图中三角形的方向发生了变化，不符合题意;B. 图中图形的方向都发生了变化，不符合题意;C. 图中所有图形的大小，方向，形状都没有发生变化，符合题意。则由原图通过平移拼成的小船是C。故答案为:C",
+    "knowledge_points": [
+      "平移与平移现象"
+    ],
+    "source": "24-25 二年级下·贵州铜仁·期中"
+  },
+  {
+    "id": "157",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "魔法对称图形：巫师用魔法变出以下图形,( )不能对折后完全重合。",
+    "options": [
+      "A. ![](images/3d11e67c7b0a62abadec24d04e0d183a20b49d25db82854c5be49c980b95a52d.jpg)",
+      "B. ![](images/e02254db5eb916acdb5ae6a1a4663f9fe72bbc7dbf205a75381ca0d2bf0b77d8.jpg)",
+      "C. ![](images/3931ecedecb5e776cc4662f0890a80492441282e4c7f95242577745f5383bb37.jpg)",
+      "D. ![](images/4596f7393470523291e392f11ca2edb1c1c447a5166befa3c704371dd326850d.jpg)"
+    ],
+    "answer": "C",
+    "solution": "【分析】如果沿某条直线对折，对折的两部分是完全重合的，这样的图形为轴对称图形。这条直线叫做这个图形的对称轴。判断一个图案是否是轴对称图形的关键是看在这个图形中能否找到一条直线，使图形沿着这条直线对折后能够完全重合。\n\n【详解】A。 能对折后完全重合;B。能对折后完全重合;C. 不能对折后完全重合;D. ![](images/82d7d6445e34ad16b311541c3b19c488e45f4da2715caf871f8fd4e46b7e68cd.jpg) 能对折后完全重合。故答案为:C",
+    "knowledge_points": [
+      "轴对称的认识及辨认"
+    ],
+    "source": "24-25 二年级下·山东济宁·期末"
+  },
+  {
+    "id": "158",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面几种传统文化图片中，有( )个是轴对称图形。\n![](images/image-1.png)",
+    "options": [
+      "A. 1",
+      "B. 2",
+      "C. 3"
+    ],
+    "answer": "B",
+    "solution": "【分析】轴对称：在平面内，如果一个图形沿一条直线对折，对折后的两部分都能完全重合，这样的图形叫做轴对称图形，这条直线就是其对称轴。\n\n【详解】据分析可知：剪纸、太极不是轴对称图形，脸谱、石雕是轴对称图形，所以有2个是轴对称图形。故答案为:B",
+    "knowledge_points": [
+      "轴对称的认识及辨认"
+    ],
+    "source": "24-25二年级下·福建莆田·期中"
+  },
+  {
+    "id": "159",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面图形中，对称轴数量最多的是( )。",
+    "options": [
+      "A. 正方形",
+      "B. 圆形",
+      "C. 长方形",
+      "D. 三角形"
+    ],
+    "answer": "B",
+    "solution": "【分析】一个图形沿一条直线对折，直线两旁的部分能够完全重合，这个图形就是轴对称图形，这条直线就是它的对称轴;据此并结合对轴对称图形的认识，逐项分析选项中的图形，找出对称轴数量最多的即可解答。\n\n【详解】A. 正方形有4条对称轴;B. 圆形有无数条对称轴;C. 长方形有2条对称轴;D. 三角形不一定有3条对称轴，只有等边三角形有3条对称轴。对称轴条数最多的是圆形。故答案为:B",
+    "knowledge_points": [
+      "对称轴的画法及数量"
+    ],
+    "source": "24-25 二年级下·山东济宁·期末"
+  },
+  {
+    "id": "160",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "小明在公园里看到下面现象，不属于旋转的是( )。",
+    "options": [
+      "A. 荡秋千",
+      "B. 摩天轮",
+      "C. 滑梯",
+      "D. 风车转动"
+    ],
+    "answer": "C",
+    "solution": "【分析】根据题意，平移是指在平面内将一个图形上的所有点都按照某个直线方向做相同距离的移动，这样的运动叫做图形的平移运动。旋转是指在平面内将一个图形绕一点按某个方向转动一个角度，这样的运动叫做图形的旋转运动。据此解答。\n\n【详解】根据分析:A. 荡秋千是秋千绕悬挂点摆动，属于绕支点的往复旋转运动，不符合题意;B. 摩天轮是座舱绕中心轴做圆周运动，是典型的旋转，不符合题意;C. 滑梯是小朋友从滑梯滑下是沿斜面的直线下滑运动，属于平移现象，符合题意;D. 风车转动是叶片绕中心轴旋转，不符合题意。故答案为:C",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "24-25 二年级下·山东济宁·期末"
+  },
+  {
+    "id": "161",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面不是轴对称图形的是( )。",
+    "options": [
+      "A. ![](images/54bb1aa3caab080603cd4845dcc4fad1ed10e2212eb3bdc96ee8cf10431d010c.jpg)",
+      "B. ![](images/61a7584372eaea4ee355f6e2f07b506691a9820910f11484422af0684f862fc2.jpg)",
+      "C. ![](images/faaedeb8c067f72b3ff764943a64e0e62868da4d81a91df35fe0d8996e1d0d61.jpg)"
+    ],
+    "answer": "C",
+    "solution": "【分析】一个图形沿一条直线对折，直线两旁的图形完全重合，这样的图形叫做轴对称图形，折痕所在的直线是对称轴，由此解答。\n\n【详解】A。 有对称轴，是轴对称图形;B。有对称轴，是轴对称图形;C. ![](images/99a974b5da5f8889da0f6b0610941c9e596ed5ae11935f9ea58221796f564d5a.jpg) 没有对称轴，不是轴对称图形。故答案为:C",
+    "knowledge_points": [
+      "轴对称的认识及辨认"
+    ],
+    "source": "24-25 二年级下·贵州铜仁·期中"
+  },
+  {
+    "id": "162",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面图形是轴对称图形的有( )个.\n![](images/aff6b6774333c7acdcea487b380962dd6ea8b8cf0346ac5c2f05a233a6ce8b44.jpg)\n![](images/6d17412b989d5f993a04b1e1befb86e1c806c802bff44ac3bc62a724195dc005.jpg)\n![](images/6e1580ab3c182da6bb3276ed5b36ec2a3a7f13ed33e70734c5d88659e46624ab.jpg)\n![](images/932206d1307c4a1824259b1cd18f01421266f9cf086177b9a3a84e7d4be0d3d9.jpg)",
+    "options": [
+      "A. 2",
+      "B. 3",
+      "C. 4"
+    ],
+    "answer": "B",
+    "solution": "【分析】如果沿某条直线对折，对折的两部分是完全重合的，这样的图形为轴对称图形。这条直线叫做这个图形的对称轴。判断一个图案是否是轴对称图形的关键是看在这个图形中能否找到一条直线，使图形沿着这条直线对折后能够完全重合。\n\n【详解】是轴对称图形的有3个。故答案为:B",
+    "knowledge_points": [
+      "轴对称的认识及辨认"
+    ],
+    "source": "24-25二年级下·内蒙古通辽·期中"
+  },
+  {
+    "id": "163",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面呈现的现象里,( )属于旋转。",
+    "options": [
+      "A. 升旗时国旗的上升",
+      "B. 拉窗帘的动作",
+      "C. 摩天轮的转动"
+    ],
+    "answer": "C",
+    "solution": "【分析】旋转是物体运动时，每一个点离同一个点(可以在物体外)的距离不变的运动，称为绕这个点的转动，这个点称为物体的转动中心;平移是物体运动时，物体上任意两点间，从一点到另一点的方向与距离都不变的运动。也可以这样说平移是不转动的，旋转自然是转动的，依此根据平移与旋转定义判断即可。\n\n【详解】A。 升旗时国旗的上升，是平移现象;B. 拉窗帘的动作，是平移现象;C. 摩天轮的转动，是旋转现象。故答案为:C",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "24-25 二年级下·黑龙江佳木斯·期中"
+  },
+  {
+    "id": "164",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面的图形,( )不是轴对称图形。",
+    "options": [
+      "A. ![](images/09d709c28280017642f6e2c6615f5f2198367568ad29de82300e2b36e82e2dc3.jpg)",
+      "B. ![](images/716337aea38956a6d43cd0a844a9860411ddad13f98e15755a88eb705f437cf1.jpg)",
+      "C. ![](images/5f5c9bbc4c21d6acb844d38bb56bfbd1d8111a0e7ff76f8fa462878cdc3680ff.jpg)"
+    ],
+    "answer": "B",
+    "solution": "【分析】依据轴对称图形的定义判断：平面内，一个图形沿一条直线折叠，直线两旁的部分能够完全重合，这个图形就是轴对称图形;其中的这条直线就是对称轴。\n\n【详解】由分析可得：图形B对折后两侧的图形不能完全重合，所以不是轴对称图形。故答案为:B",
+    "knowledge_points": [
+      "轴对称的认识及辨认"
+    ],
+    "source": "24-25 二年级下·广东云浮·期中"
+  },
+  {
+    "id": "165",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "在下面这些漂亮的剪纸中,( )既是轴对称图形，又有旋转现象。",
+    "options": [
+      "A. ![](images/81e8fee5242b3a9e4cc29d7fa8d272434b678f1ed66c9520f703195061b259d5.jpg)",
+      "B. ![](images/487c96a1defcf22a75b0bf2c34540e2e92be7e1936c136b2fa181fda726996f2.jpg)",
+      "C. ![](images/eab315249940561871ad1a2b3fdf800453b09e021efebfef093bd48e098bb379.jpg)",
+      "D. ![](images/0fd9b711f7b8baaca88eff2a64bc31cb1b8db495f6c03607c462ace75c442df0.jpg)"
+    ],
+    "answer": "B",
+    "solution": "【分析】一个图形如果沿某条直线折叠后，两侧图形能够完全重合，这个图形就是轴对称图形。在平面内，将一个图形绕一点按某个方向转动一定的角度，这样的运动叫做图形的旋转。旋转后图形的位置和方向改变，形状，大小不变。\n\n【详解】A。 经过对折后可以重合，所以是轴对称图形，绕中心旋转后不能与原图形重合，所以没有旋转现象;B. 经过对折后可以重合，所以是轴对称图形，绕中心旋转后与原图形重合，所以有旋转现象;C. 经过对折后不能重合，所以不是轴对称图形，绕中心旋转后与原图形重合，所以有旋转现象;D. 经过对折后可以重合，所以是轴对称图形，绕中心旋转后不能与原图形重合，所以没有旋转现象。B既是轴对称图形，又有旋转现象。故答案为:B",
+    "knowledge_points": [
+      "轴对称的认识及辨认",
+      "旋转与旋转现象"
+    ],
+    "source": "24-25二年级下·福建龙岩·期中"
+  },
+  {
+    "id": "166",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面图形不是轴对称图形的是( )。",
+    "options": [
+      "A. ![](images/925414c46018bdac5ac2488093d86f8a22aea5cc7ecbfc4fdf50e15023fd678a.jpg)",
+      "B. ![](images/a375bec3e42c1de7dde04bd2037cc112084c25be9c5389c57143e618c97bec1b.jpg)",
+      "C. ![](images/9e13e0fb5e4e9a5ddc047a9516b4f0f4c6eb6f2dd549494729426f417cfe5815.jpg)"
+    ],
+    "answer": "B",
+    "solution": "【分析】在平面内，如果一个图形沿一条直线对折，对折后的两部分都能完全重合，这样的图形叫做轴对称图形。据此判断即可解答。\n\n【详解】A。 沿一条直线对折，对折后的两部分能完全重合，是轴对称图形;B. 沿一条直线对折，对折后的向左拐的箭头两部分不能完全重合，不是轴对称图形;C. 沿一条直线对折，对折后的两部分能完全重合，是轴对称图形。故答案为:B",
+    "knowledge_points": [
+      "轴对称的认识及辨认"
+    ],
+    "source": "24-25 二年级下·青海果洛·期中"
+  },
+  {
+    "id": "167",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "钟表上时针转动属于( )现象，汽车在笔直公路上直线行驶属于( )现象。",
+    "options": [],
+    "answer": "旋转;平移",
+    "solution": "【分析】平移是物体运动时，物体上任意两点间，从一点到另一点的方向与距离都不变的运动;旋转是物体运动时，每一个点离同一个点(可以在物体外)的距离不变的运动，称为绕这个点的转动，这个点称为物体的转动中心。所以，它并不一定是绕某个轴的;也可以这样说平移是不转动的，旋转自然是转动的，依此根据平移与旋转定义判断即可。\n\n【详解】根据分析可知，钟表上时针转动属于旋转现象，汽车在笔直公路上直线行驶属于平移现象。",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "23-24二年级下·湖北省直辖县级单位·期末"
+  },
+  {
+    "id": "168",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "在括号里填上\"平移\"或\"旋转\"。\n飞机的螺旋桨转动是( )现象，推纸箱前进是( )现象。",
+    "options": [],
+    "answer": "旋转;平移",
+    "solution": "【分析】平移：在平面内，将一个图形上的所有点都按照某个方向作相同距离移动的图形运动。平移后图形的位置改变，形状、大小、方向不变。旋转：在平面内，将一个图形绕一点按某个方向转动一定的角度，这样的运动叫做图形的旋转。旋转前后图形的位置和方向改变，形状、大小不变。\n\n【详解】飞机的螺旋桨转动是旋转现象，推纸箱前进是平移现象。",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "23-24二年级下·河北邢台·期中"
+  },
+  {
+    "id": "169",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "在( )里填\"平移\"或\"旋转\"。\n汽车轮胎转动属于( )现象，推拉门属于( )现象。",
+    "options": [],
+    "answer": "旋转;平移",
+    "solution": "【分析】在平面内，一个图形整体沿着某条直线方向平行移动一定距离的过程，称为平移;在平面内，一个图形围绕某一个固定点按照顺时针或逆时针方向转动一定角度的过程，称为旋转。\n\n【详解】由分析可知：汽车轮胎转动属于旋转现象，推拉门属于平移现象。",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "23-24二年级下·河北张家口·期中"
+  },
+  {
+    "id": "170",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "钟面上时针的转动属于( )现象。下图中，分针从12走到所指的位置时，所经过的时间是( )分钟。\n![](images/1f8d1536ecfcc9966ceb3cdf4c6ffe9ee02ff4fa87f9b625ef3e55ecb7f3ae88.jpg)",
+    "options": [],
+    "answer": "旋转;15",
+    "solution": "【分析】在平面内，把一个图形围绕某一固定点按顺时针或逆时针方向转动一定的角度的过程，称为旋转，常见的旋转现象有旋转木马、摩天轮等;钟面上长针是分针，短针是时针，有12个大格，分针走1大格是5分钟，由此先计算出分针走的格数，再计算出经过的时间即可。\n\n【详解】分针从12走到3，走了3个大格，3×5=15(分钟)。钟面上时针的转动属于旋转现象。分针从12走到所指的位置时，所经过的时间是15分钟。",
+    "knowledge_points": [
+      "旋转与旋转现象",
+      "时，分，秒有关的计算"
+    ],
+    "source": "23-24二年级下·福建龙岩·期末"
+  },
+  {
+    "id": "171",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "车轮的转动是( )现象;抽屉的推拉是( )现象。(旋转或平移)",
+    "options": [],
+    "answer": "旋转;平移",
+    "solution": "【分析】平移：在平面内，将一个图形上的所有点都按照某个方向作相同距离移动的图形运动。平移后图形的位置改变，形状，大小，方向不变。旋转：在平面内，将一个图形绕一点按某个方向转动一定的角度，这样的运动叫做图形的旋转。旋转前后图形的位置和方向改变，形状，大小不变。\n\n【详解】车轮的转动是(旋转)现象;抽屉的推拉是(平移)现象。",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "23-24二年级下·黑龙江佳木斯·期末"
+  },
+  {
+    "id": "172",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "电梯上升的运动属于( )现象，钟表指针的转动属于( )现象。",
+    "options": [],
+    "answer": "平移;旋转",
+    "solution": "【分析】平移：在平面内，将一个图形上的所有点都按照某个方向作相同距离移动的图形运动。平移后图形的位置改变，形状，大小，方向不变。旋转：在平面内，将一个图形绕一点按某个方向转动一定的角度，这样的运动叫做图形的旋转。旋转前后图形的位置和方向改变，形状，大小不变。\n\n【详解】据分析可知：电梯上升的运动属于平移现象，钟表指针的转动属于旋转现象。",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "24-25二年级下·湖南长沙·期末"
+  },
+  {
+    "id": "173",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "轴对称图形\"★\"有( )条对称轴，长方形有( )条对称轴。",
+    "options": [],
+    "answer": "5;2",
+    "solution": "【分析】如果沿某条直线对折，对折的两部分是完全重合的，这样的图形为轴对称图形。这条直线叫做这个图形的对称轴。判断一个图案是否是轴对称图形的关键是看在这个图形中能否找到一条直线，使图形沿着这条直线对折后能够完全重合。\n\n【详解】轴对称图形\"★\"有5条对称轴，长方形有2条对称轴。",
+    "knowledge_points": [
+      "对称轴的画法及数量"
+    ],
+    "source": "24-25一年级下·湖南岳阳·期中"
+  },
+  {
+    "id": "174",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "\"神舟十六号\"飞船发射升空是( )现象，螺旋桨工作是( )现象。",
+    "options": [],
+    "answer": "平移;旋转",
+    "solution": "【分析】平移：在平面内，将一个图形上的所有点都按照某个方向作相同距离移动的图形运动。平移后图形的位置改变，形状，大小，方向不变。旋转：在平面内，将一个图形绕一点按某个方向转动一定的角度，这样的运动叫做图形的旋转。旋转前后图形的位置和方向改变，形状，大小不变。据此解答即可。\n\n【详解】由题意分析可得：\"神舟十六号\"飞船发射升空是平移现象，螺旋桨工作是旋转现象。",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "23-24二年级下·广东东莞·期末"
+  },
+  {
+    "id": "175",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "下图中,( )是轴对称图形,( )不是轴对称图形。(填序号)\n![](images/dc263de41374a5c963d5f5278edc8925f1ccc00e5c0f10b332c49ecd22feaf33.jpg)\n![](images/f80328a2f87d745c9f48d33f922ed20bfc2532edd4af9eb2e3107f2e2d4f12ab.jpg)\n![](images/90f2a5c75c1cf7ac81f633cc351863aa3b3e03fbdbe63b2792b620b657245645.jpg)\n![](images/374072fe1b0c1f0f120b48b31ef7b83edf72e2bb4771bb0106be345e648c8f82.jpg)",
+    "options": [],
+    "answer": "①③;②④",
+    "solution": "【分析】在平面内，如果沿着一条直线折叠，直线两旁的部分能够完全重合，这样的图形叫轴对称图形。据此解答。\n\n【详解】①从五角星最上面的角竖着画一条线，沿这条线对折，左右两边就能够完全重合，所以是轴对称图形;②树叶是一个不规则图形，无法找到对称轴，不是轴对称图形;③从囍字左右中间画一条线，沿这条线对折，左右两边就能够完全重合，所以是轴对称图形;④房顶左边有一个烟囱，右边没有，所以两边不能完全重合，不是轴对称图形。下图中，①③是轴对称图形，②④不是轴对称图形。",
+    "knowledge_points": [
+      "轴对称的认识及辨认"
+    ],
+    "source": "23-24二年级下·湖南岳阳·期末"
+  },
+  {
+    "id": "176",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "黄石花湖机场是亚洲第一个，全球第四个专业货运机场，直升机在起飞的过程中，机身的运动是( )现象，螺旋桨的运动是( )现象。",
+    "options": [],
+    "answer": "平移;旋转",
+    "solution": "【分析】在平面内，把一个图形整体沿某条直线方向平行移动一定距离的过程，称为平移，常见的平移现象有滑滑梯，推拉窗户等。在平面内，把一个图形围绕某一固定点按顺时针或逆时针方向转动一定的角度的过程，称为旋转，常见的旋转现象有摩天轮，旋转木马等。由此解答。\n\n【详解】由分析得：直升机在起飞的过程中，机身的运动是平移现象，螺旋桨的运动是旋转现象。",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "23-24二年级下·湖北黄石·期末"
+  },
+  {
+    "id": "177",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "下边的这种运动属于( )现象.\n![](images/ece187eaa39bbe126c167441b9ec02a9a18370207f7c4fdfd82e073a900e9970.jpg)",
+    "options": [],
+    "answer": "旋转",
+    "solution": "【分析】在平面内，把一个图形整体沿某条直线方向平行移动一定距离的过程，称为平移。常见的平移现象有滑滑梯，电梯的移动等;在平面内，把一个图形围绕某一固定点按顺时针或逆时针方向转动一定的角度的过程，称为旋转。常见的旋转现象有旋转木马，摩天轮等。由此解答。\n\n【详解】根据分析可得：开门这种图形的运动属于旋转现象。",
+    "knowledge_points": [
+      "旋转与旋转现象"
+    ],
+    "source": "23-24二年级下·河南信阳·期末"
+  },
+  {
+    "id": "178",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "在括号里填上\"旋转\"或\"平移\"。\n(1)推拉抽屉是( )现象。\n(2)拧开水龙头是( )现象。\n(3)飞机降落后在跑道上滑行，机身的运动是( )现象。\n(4)风力发电机叶片的运动是( )现象。",
+    "options": [],
+    "answer": "平移;旋转;平移;旋转",
+    "solution": "【分析】在平面内，把一个图形整体沿某条直线方向平行移动一定距离的过程，称为平移，常见的平移现象有滑滑梯、电梯的移动等。在平面内，把一个图形围绕某一固定点按顺时针或逆时针方向转动一定的角度的过程，称为旋转，常见的旋转现象有旋转木马、摩天轮等。由此解答。\n\n【详解】(1)推拉抽屉是平移现象;(2)拧开水龙头是旋转现象;(3)飞机降落后在跑道上滑行，机身的运动是平移现象;(4)风力发电机叶片的运动是旋转现象。",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "24-25二年级下·湖北武汉·期末"
+  },
+  {
+    "id": "179",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "一个图形对折后两边完全重合，这个图形是( )图形。",
+    "options": [],
+    "answer": "轴对称",
+    "solution": "【分析】轴对称：如果一个图形沿着一条直线对折，两侧的图形能够完全重合，这个图形就是轴对称图形。据此解答即可。\n\n【详解】据分析可知：一个图形对折后两边完全重合，这个图形是轴对称图形。",
+    "knowledge_points": [
+      "轴对称的认识及辨认"
+    ],
+    "source": "24-25二年级下·湖南湘潭·期末"
+  },
+  {
+    "id": "180",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "电梯的升降属于( )现象;风扇叶片的转动属于( )现象。",
+    "options": [],
+    "answer": "平移;旋转",
+    "solution": "【分析】在平面内，把一个图形整体沿某条直线方向平行移动一定距离的过程，称为平移。常见的平移现象有滑滑梯、电梯的移动等;在平面内，把一个图形围绕某一固定点按顺时针或逆时针方向转动一定的角度的过程，称为旋转。常见的旋转现象有旋转木马、摩天轮等。由此解答。\n\n【详解】电梯的升降是电梯整体上下移动，属于平移现象;风扇叶片的转动是风扇叶片绕中心轴转动，属于旋转现象。",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "24-25二年级下·新疆喀什·期中"
+  },
+  {
+    "id": "181",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "风扇的转动属于( )现象，拉开抽屉属于( )现象。",
+    "options": [],
+    "answer": "旋转;平移",
+    "solution": "【分析】在平面内，一个图形整体沿着某条直线方向平行移动一定距离的过程，称为平移;在平面内，一个图形围绕某一个固定点按照顺时针或逆时针方向转动一定角度的过程，称为旋转。\n\n【详解】由分析可知：风扇的转动属于旋转现象，拉开抽屉属于平移现象。",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "24-25二年级下·黑龙江佳木斯·期末"
+  },
+  {
+    "id": "182",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "钟面上的分针从12走到6，经过了( )分钟，这里分针的运动属于( )(填\"旋转\"或\"平移\")现象。",
+    "options": [],
+    "answer": "30;旋转",
+    "solution": "【分析】钟面上长针是分针，有12个大格，分针走1大格是5分钟，由此先计算出走了几个大格，再计算出经过的时间即可;在平面内，把一个图形整体沿某条直线方向平行移动一定距离的过程，称为平移，常见的平移现象有滑滑梯，电梯的移动等。在平面内，把一个图形围绕某一固定点按顺时针或逆时针方向转动一定的角度的过程，称为旋转，常见的旋转现象有旋转木马，摩天轮等。\n\n【详解】分针从12走到6，走了6个大格,6×5=30(分钟)。钟面上的分针从12走到6，经过了30分钟，这里分针的运动属于旋转现象。",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象",
+      "时，分，秒有关的计算"
+    ],
+    "source": "24-25二年级下·贵州黔西·期中"
+  },
+  {
+    "id": "183",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "摩天轮转动是( )现象，在计数器上拨珠子是( )现象。(填\"平移\"或\"旋转\")",
+    "options": [],
+    "answer": "旋转;平移",
+    "solution": "【分析】在平面内，把一个图形整体沿某条直线方向平行移动一定距离的过程，称为平移。常见的平移现象有滑滑梯，电梯的移动等;在平面内，把一个图形围绕某一固定点按顺时针或逆时针方向转动一定的角度的过程，称为旋转。常见的旋转现象有旋转木马，摩天轮等。由此解答。\n\n【详解】由分析可得：摩天轮转动符合旋转的特点;计数器上拨珠子符合平移的特点。摩天轮转动是旋转现象，在计数器上拨珠子是平移现象。",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "24-25二年级下·陕西渭南·期末"
+  },
+  {
+    "id": "184",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "风扇转动是( )现象，推拉抽屉是( )现象。(填\"平移\"或\"旋转\")",
+    "options": [],
+    "answer": "旋转;平移",
+    "solution": "【分析】平移是物体运动时，物体上任意两点间，从一点到另一点的方向与距离都不变的运动;旋转是物体运动时，每一个点离同一个点(可以在物体外)的距离不变的运动，称为绕这个点的转动，这个点称为物体的转动中心。\n\n【详解】根据分析可知，风扇转动是旋转现象，推拉抽屉是平移现象。",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "24-25二年级下·黑龙江佳木斯·期末"
+  },
+  {
+    "id": "185",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "下面( )是平移现象,( )是旋转现象。(填序号)\n![](images/2b0d3aad02886dcc4432fe1b8d292b4c6a334f4884b9d2ceb1d05e5d4a1a87c8.jpg)\n![](images/5fc948f7fc5821cfef535484ff0498c5e3c3069401f7bfad6b48a054579f0fa6.jpg)\n![](images/5b4296894b934652ff3d539283600a078ddd1cd97155803cbec98d59f3ceb1b4.jpg)\n![](images/b7771e9e25bbbd06259f2bdcc88eb0b7c178e509f92148bab72fad75d5e977f8.jpg)",
+    "options": [],
+    "answer": "②③;①④",
+    "solution": "【分析】平移是指在平面内，将一个图形上的所有点都按照某个直线方向做相同距离的移动，这样的图形运动叫做图形的平移运动，简称平移。平移后图形的位置改变，形状、大小、方向不变。旋转是指在平面内，将一个图形绕一点按某个方向转动一定的角度，这样的运动叫做图形的旋转。旋转后图形的位置和方向改变，形状、大小不变。\n\n【详解】下面②③是平移现象，①④是旋转现象。",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "24-25二年级下·四川乐山·期末"
+  },
+  {
+    "id": "186",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "车轮转动属于( )现象;电梯上下移动属于( )现象。(填\"平移\"或\"旋转\")",
+    "options": [],
+    "answer": "旋转;平移",
+    "solution": "【分析】在平面内，把一个图形整体沿某条直线方向平行移动一定距离的过程，称为平移，常见的平移现象有滑滑梯，推拉窗户等。在平面内，把一个图形围绕某一固定点按顺时针或逆时针方向转动一定的角度的过程，称为旋转，常见的旋转现象有旋转木马，摩天轮等。由此解答。\n\n【详解】由分析可知：车轮转动属于旋转现象;电梯上下移动属于平移现象。",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "24-25二年级下·贵州铜仁·期末"
+  },
+  {
+    "id": "187",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "钟面分针运动属于( );举重运动属于( )。(填\"旋转\"或\"平移\")\n![](images/45cb2a9c320cceb5ff805d5dbca111de1e6ccab7ef12dca29a21a0496d873963.jpg)\n![](images/60afb6d67f6dfa7c1ef833b2b3a039c341dd18e15a3b7899c04108151c03c4a6.jpg)",
+    "options": [],
+    "answer": "旋转;平移",
+    "solution": "【分析】平移是指在平面内，将一个图形上的所有点都按照某个直线方向做相同距离的移动，这样的图形运动叫做图形的平移运动，简称平移。平移后图形的位置改变，形状，大小，方向不变。旋转：在平面内，将一个图形绕一点按某个方向转动一定的角度，这样的运动叫做图形的旋转。旋转后图形的位置和方向改变，形状，大小不变。\n\n【详解】钟面分针运动属于旋转;举重运动属于平移。",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "24-25二年级下·湖南怀化·期中"
+  },
+  {
+    "id": "188",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "滑滑梯运动是平移现象。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】平移：在平面内，将一个图形上的所有点都按照某个方向作相同距离移动的图形运动。平移后图形的位置改变，形状，大小，方向不变。据此解答即可。\n\n【详解】据分析可知：滑滑梯运动是平移现象。原题说法正确。故答案为:√",
+    "knowledge_points": [
+      "平移与平移现象"
+    ],
+    "source": "23-24二年级下·湖南岳阳·期末"
+  },
+  {
+    "id": "189",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "\"口\"、\"〇\"、\"@\"都是轴对称图形。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】一个图形沿一条直线对折，直线两旁的图形完全重合，这样的图形叫做轴对称图形，折痕所在的直线是对称轴，由此解答。\n\n【详解】由分析得：\"口\"、\"〇\"有对称轴，是轴对称图形，\"@\"没有对称轴，不是轴对称图形。原题说法错误。故答案为: ×",
+    "knowledge_points": [
+      "轴对称的认识及辨认"
+    ],
+    "source": "23-24二年级下·湖南岳阳·期末"
+  },
+  {
+    "id": "190",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "\"T\"和\"J\"都是轴对称图形。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】轴对称：如果一个图形沿着一条直线对折，两侧的图形能够完全重合，这个图形就是轴对称图形。\n\n【详解】\"T\"是轴对称图形，\"J\"不是轴对称图形。原题说法错误。故答案为: ×",
+    "knowledge_points": [
+      "轴对称的认识及辨认"
+    ],
+    "source": "23-24二年级下·河北邢台·期中"
+  },
+  {
+    "id": "191",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "这个图形运动是平移。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】在平面内，把一个图形整体沿某条直线方向平行移动一定距离的过程，称为平移。物体或图形平移后，大小，形状，方向都不变，只有位置发生了变化，由此解答。\n\n【详解】由分析得：图形的方向发生了变化，则原图的运动不是平移，原题说法错误。故答案为: ×",
+    "knowledge_points": [
+      "平移与平移现象"
+    ],
+    "source": "23-24二年级下·云南曲靖·期末"
+  },
+  {
+    "id": "192",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "判断题",
+    "difficulty": 0.65,
+    "question": "平移后的图形大小和形状都不变。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】平移是指在同一个平面内，如果一个图形上的所有点都按照某个直线方向做相同距离的移动，这样的图形运动就叫平移。平移不改变图形的形状，大小以及方向，只改变图形的位置。据此解答。\n\n【详解】由分析可得：平移是图形整体的平行移动，不会改变图形的大小和形状。故答案为:√",
+    "knowledge_points": [
+      "平移与平移现象"
+    ],
+    "source": "24-25一年级下·湖南岳阳·期中"
+  },
+  {
+    "id": "193",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "正方形，平行四边形都是轴对称图形。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】如果沿某条直线对折，对折的两部分是完全重合的，这样的图形为轴对称图形。这条直线叫做这个图形的对称轴。判断一个图案是否是轴对称图形的关键是看在这个图形中能否找到一条直线，使图形沿着这条直线对折后能够完全重合。\n\n【详解】正方形是轴对称图形，平行四边形不是轴对称图形。原题说法错误。故答案为: ×",
+    "knowledge_points": [
+      "轴对称的认识及辨认"
+    ],
+    "source": "24-25一年级下·湖南岳阳·期中"
+  },
+  {
+    "id": "194",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "判断题",
+    "difficulty": 0.65,
+    "question": "风车转动是旋转现象，升降国旗是平移现象。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】在平面内，把一个图形整体沿某条直线方向平行移动一定距离的过程，称为平移。常见的平移现象有滑滑梯，电梯的移动等;在平面内，把一个图形围绕某一固定点按顺时针或逆时针方向转动一定的角度的过程，称为旋转。常见的旋转现象有旋转木马，摩天轮等。由此解答。\n\n【详解】由分析可得：风车转动是风车的叶轮绕着车轴转动，属于旋转。升降国旗是国旗顺着旗杆上下平行移动，属于平移。原题说法正确。故答案为:√",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "23-24二年级下·湖南岳阳·期末"
+  },
+  {
+    "id": "195",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "在笔直的公路上行驶，车身的运动是平移现象。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】平移是指在平面内，将一个图形上的所有点都按照某个直线方向做相同距离的移动，这样的图形运动叫做图形的平移运动，简称平移。平移后图形的位置改变，形状，大小，方向不变。\n\n【详解】在笔直的公路上行驶，车身的运动是平移现象。原题说法正确。故答案为:√",
+    "knowledge_points": [
+      "平移与平移现象"
+    ],
+    "source": "23-24二年级下·湖北黄石·期末"
+  },
+  {
+    "id": "196",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "左边的图形都是轴对称图形。( )\n![](images/94eacb2f2b28f1115d4dc3c34f99dbbe10ca00ea984531a4baba82e6ab75802e.jpg)\n![](images/87760488ae6fd174ed75b6a3f652978e4fa93438c4d678ff37199bd7b28a5068.jpg)\n![](images/60a64caab4e718c4831211c2b0c0219a7d4b1f6e5ac303c5b79a05a97dfe9958.jpg)\n![](images/ff578e1765fad0585ec72c99d5d9e59984065d0b076119d6a88d713db3011c55.jpg)",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】根据轴对称图形的意义，如果一个图形沿着一条直线对折，两侧的图形能够完全重合，这样的图形就是轴对称图形。逐项分析左边的图形，即可解答。\n\n【详解】第一个图形沿着一条直线对折后，直线两旁的部分能够完全重合，它是轴对称图形;第二个图形沿着一条直线对折后，直线两旁的部分能够完全重合，它是轴对称图形;第三个图形不论沿着哪条直线对折后，直线两旁的部分不能够完全重合，它不是轴对称图形;第四个图形沿着一条直线对折后，直线两旁的部分能够完全重合，它是轴对称图形。左边的图形中第一个，第二个，第四个是轴对称图形，而第三个不是轴对称图形，原题说法错误。故答案为: ×",
+    "knowledge_points": [
+      "轴对称的认识及辨认"
+    ],
+    "source": "23-24二年级下·河南信阳·期末"
+  },
+  {
+    "id": "197",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "这是轴对称图形。( )\n![](images/5046fed5ceb0a08c10d8e8c4375e82d9413be29daf052dddb51420e382963fda.jpg)",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】一个图形沿着一条直线对折后，直线两旁的部分能够完全重合，这样的图形就叫做轴对称图形，据此解答。\n\n【详解】沿着这样一条直线对折后，直线两旁的部分能够完全重合，所以它是轴对称图形，原题说法正确。故答案为:√",
+    "knowledge_points": [
+      "轴对称的认识及辨认"
+    ],
+    "source": "23-24二年级下·重庆永川·期末"
+  },
+  {
+    "id": "198",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "向前推箱子和拧开果汁的盖子都是旋转运动。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】平移是指在平面内，将一个图形上的所有点都按照某个直线方向做相同距离的移动，这样的图形运动叫做图形的平移运动，简称平移。平移后图形的位置改变，形状，大小，方向不变。旋转：在平面内，将一个图形绕一点按某个方向转动一定的角度，这样的运动叫做图形的旋转。旋转后图形的位置和方向改变，形状，大小不变。\n\n【详解】向前推箱子是平移运动，拧开果汁的盖子是旋转运动。原题说法错误。故答案为: ×",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "23-24二年级下·河南漯河·期末"
+  },
+  {
+    "id": "199",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "一个快递箱子在地面上被向前推动是平移现象。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】在平面内，把一个图形整体沿某条直线方向平行移动一定距离的过程，称为平移。物体或图形平移后，大小，形状，方向都不变;只有位置发生变化，由此解答。\n\n【详解】由分析可知：一个快递箱子在地面上被向前推动，大小，形状，方向都不变;只有位置发生变化，是平移现象。原题说法正确。故答案为:√",
+    "knowledge_points": [
+      "平移与平移现象"
+    ],
+    "source": "24-25二年级下·陕西延安·期末"
+  },
+  {
+    "id": "200",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "通过平移能与原图重合。( )\n![](images/8b67c65f29fcc157d90c5b0800327810b685281097150ec053234e38ded53848.jpg)\n![](images/883230c628580227fb9b106a86434c152a55c55ec7043e1e584bf5183e4a8bc8.jpg)",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】在平面内，把一个图形整体沿某条直线方向平行移动一定距离的过程，称为平移。常见的平移现象有滑滑梯，电梯的移动等;据此解答。\n\n【详解】由分析可得：原图的把手朝上，向右沿直线方向平行移动后，把手依然朝上才是平移现象。而选项图形把手朝左，显然平移后不能重合。故答案为: ×",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "24-25二年级下·山东济南·期末"
+  },
+  {
+    "id": "201",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "一根小棒向右平移了5厘米，小红量得平移后的小棒长8厘米。原来这根小棒长( )。",
+    "options": [
+      "A. 8厘米",
+      "B. 5厘米",
+      "C. 3厘米"
+    ],
+    "answer": "A",
+    "solution": "【分析】题目中明确说明，平移后小红量得小棒的长度为8厘米。根据平移的性质，平移只是位置发生了变化，而小棒的长短不变，所以平移前小棒的长度与平移后相同，原来小棒的长度也是8厘米，据此解答。\n\n【详解】根据分析可得：一根小棒向右平移了5厘米，小红量得平移后的小棒长8厘米。原来这根小棒长8厘米。故答案为:A",
+    "knowledge_points": [
+      "平移与平移现象"
+    ],
+    "source": "24-25二年级下·浙江台州·期末"
+  },
+  {
+    "id": "202",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "风可以用来发电，由于风力发电不需要使用燃料，所以也不会产生空气污染。如图是风力发电的装置，风带动扇叶转动的过程是( )现象。![](images/7f052a8315ba47cab543465d71f938da8ca39a5141130b99b3685845a7d94385.jpg)",
+    "options": [
+      "A. 平移",
+      "B. 对称",
+      "C. 旋转"
+    ],
+    "answer": "C",
+    "solution": "【分析】在平面内，把一个图形围绕某一固定点按顺时针或逆时针方向转动一定的角度的过程，称为旋转。据此解答。\n\n【详解】根据分析可知，风带动扇叶转动的过程是旋转现象。故答案为:C",
+    "knowledge_points": [
+      "轴对称的认识及辨认",
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "24-25 二年级下·湖北武汉·期末"
+  },
+  {
+    "id": "203",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下列现象是旋转现象的是( )。",
+    "options": [
+      "A. 行驶中汽车的车轮",
+      "B. 货物被直线传送带传送",
+      "C. 电梯门的开与关"
+    ],
+    "answer": "A",
+    "solution": "【分析】平移是物体运动时，物体上任意两点间，从一点到另一点的方向与距离都不变的运动。在平面内，将一个图形绕一点按某个方向转动一个角度，这样的运动叫作图形的旋转。据此进行判断即可。\n\n【详解】A. 行驶中汽车的车轮是旋转现象;B. 货物被直线传送带传送是平移现象;C. 电梯门的开与关是平移现象。故答案为:A",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "24-25 三年级下·重庆铜梁·期末"
+  },
+  {
+    "id": "204",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面( )不是平移现象。",
+    "options": [
+      "A. 火箭升空",
+      "B. 电梯上升",
+      "C. 电风扇转动"
+    ],
+    "answer": "C",
+    "solution": "【分析】平移是指在平面内将一个图形上的所有点都按照某个直线方向做相同距离的移动，这样的运动叫做图形的平移运动。旋转是指在平面内将一个图形绕一点按某个方向转动一个角度，这样的运动叫做图形的旋转运动。根据定义判断即可。\n\n【详解】A. 火箭升空是平移现象;B. 电梯上升是平移现象;C. 电风扇转动不是平移现象，是旋转现象。故答案为:C",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "24-25二年级下·云南昭通·期末"
+  },
+  {
+    "id": "205",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "下面的汉字是轴对称图形的是( )。",
+    "options": [
+      "A. 小",
+      "B. 未",
+      "C. 火"
+    ],
+    "answer": "B",
+    "solution": "【分析】轴对称图形的判断方法：把某个图形沿某条直线折叠，如果图形的两部分能够完全重合，那么这个图形就是轴对称图形。\n\n【详解】A. \"小\"不是轴对称图形;B. \"未\"是轴对称图形;C. \"火\"不是轴对称图形。故答案为:B",
+    "knowledge_points": [
+      "轴对称的认识及辨认"
+    ],
+    "source": "24-25二年级下·云南昭通·期末"
+  },
+  {
+    "id": "206",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面是由一个图形旋转得到的图案有( )。![](images/image-2.png)",
+    "options": [
+      "A. 1个",
+      "B. 2个",
+      "C. 3个"
+    ],
+    "answer": "C",
+    "solution": "【分析】平移是指在平面内，将一个图形上的所有点都按照某个直线方向做相同距离的移动，这样的图形运动叫做图形的平移运动，简称平移。平移后图形的位置改变，形状，大小，方向不变。旋转：在平面内，将一个图形绕一点按某个方向转动一定的角度，这样的运动叫做图形的旋转。旋转后图形的位置和方向改变，形状，大小不变。逐项分析。\n\n【详解】图一是旋转得到，图二是平移得到，图三是旋转得到，图四是平移得到，图五是旋转得到，由一个图形旋转得到的图案有3个。故答案为:C",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "24-25 二年级下·贵州铜仁·期末"
+  },
+  {
+    "id": "207",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "下图中，将字母所在的小正方形涂色，若只涂1个，不能得到轴对称图形的是涂( )。![](images/ec1b89548d54752c9b07b891417a1ba036bc783d2d04f1ea743827ead471fb0b.jpg)",
+    "options": [
+      "A. A",
+      "B. B",
+      "C. C"
+    ],
+    "answer": "A",
+    "solution": "【分析】根据一个图形沿一条直线对折，直线两旁的图形完全重合，这样的图形叫做轴对称图形，折痕所在的直线就是对称轴，按照选项要求进行涂色，找出无法形成轴对称图形的选项即可解答。\n\n【详解】A。 涂A处如图所示：无论沿着哪条线折叠都不会完全重叠，无法形成轴对称图形;B. 涂B处如图所示：沿着虚线位置折叠两边会完全折叠，可以形成轴对称图形;C. 涂C处如图所示：沿着虚线位置折叠两边会完全折叠，可以形成轴对称图形。故答案为:A",
+    "knowledge_points": [
+      "轴对称的认识及辨认"
+    ],
+    "source": "24-25二年级下·河北邢台·期末"
+  },
+  {
+    "id": "208",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "一个宽是4厘米的长方形，对折成两个正方形，这个长方形的长是( )。",
+    "options": [
+      "A. 4厘米",
+      "B. 6厘米",
+      "C. 8厘米"
+    ],
+    "answer": "C",
+    "solution": "【分析】已知长方形的宽是4厘米，正方形的4个边都相等，说明每个正方形的边长等于长方形的宽，正方形的边长是4厘米，长方形对折成了两个正方形，那么长方形的长是两个正方形的边长，对照选项进行验证即可。\n\n【详解】A。 4厘米，太小，对折后不能形成正方形，不符合题意;B. 6厘米，对折后部分长3厘米宽4厘米，不是正方形，不符合题意;C. 8厘米，可以对折成两个正方形，符合题意。故答案为:C",
+    "knowledge_points": [
+      "长方形的概念及特点",
+      "正方形的概念及特点"
+    ],
+    "source": "24-25 二年级下·河北保定·期末"
+  },
+  {
+    "id": "209",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "对于图形的平移说法正确的是( )。",
+    "options": [
+      "A. 改变了图形的大小和位置",
+      "B. 图形的大小和位置都没改变",
+      "C. 只改变图形的位置，不改变图形的大小"
+    ],
+    "answer": "C",
+    "solution": "【分析】在平面内，把一个图形整体沿某条直线方向平行移动的过程，称为平移。平移时图形的位置发生变化而形状，大小不变。平移时图形沿直线运动，本身方向不发生改变;据此即可解答。\n\n【详解】A。 根据分析可知，平移改变了图形的位置，但不改变图形的大小，原说法错误;B. 根据分析可知，平移时图形的位置发生变化而形状，大小不变，原说法错误;C. 根据分析可知，平移时图形的位置发生变化而形状，大小不变，原说法正确。故答案为:C",
+    "knowledge_points": [
+      "平移与平移现象"
+    ],
+    "source": "24-25 四年级下·河南南阳·期末"
+  },
+  {
+    "id": "210",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面的图形里，不是轴对称图形的是( )。",
+    "options": [
+      "A. ![](images/2d268e27b8e002a1d0dbe886a3c9944674b36b7ce1c4109de5276cce7cdc8567.jpg)",
+      "B. ![](images/5a05440564849c8afd3c5bfd5e9b8065631f09ca3464f17ee11a0aad89082d34.jpg)",
+      "C. ![](images/98162dd335a3015a5b408f14fbc8190316efc254faa83c8192593f8ed4d3201c.jpg)"
+    ],
+    "answer": "C",
+    "solution": "【分析】根据题意，轴对称，把图形按照一条直线对折，直线两边的部分能够完全重合，这样的图形叫做轴对称图形，这条直线就是图形的对称轴。\n\n【详解】A。 有对称轴，是轴对称图形;B. 有对称轴，是轴对称图形;C. ![](images/98162dd335a3015a5b408f14fbc8190316efc254faa83c8192593f8ed4d3201c.jpg) 不是轴对称图形。故答案为:C",
+    "knowledge_points": [
+      "轴对称的认识及辨认"
+    ],
+    "source": "24-25 二年级下·湖北武汉·期末"
+  },
+  {
+    "id": "211",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面的图形中，能够通过平移与图形重合的是( )。![](images/9fa692b43380b55045043c645520c3bc33f6af28bf805de83d99533349a6aba9.jpg)",
+    "options": [
+      "A. ![](images/a517e96b7f704d0d4706af5bbfbfa7c6e09614a2bb5dc31a4da3368e05b5ea21.jpg)",
+      "B. ![](images/febe586268e20267347544e04c16faf54f9fc28d5aea3fa797ac9d7d7fa2347a.jpg)",
+      "C. ![](images/f5e136a3fd5d594ca8f4701310d00887470f08d2f673e15fb053aa0f13ee2b3e.jpg)"
+    ],
+    "answer": "A",
+    "solution": "【分析】根据题意，平移是指在平面内将一个图形上的所有点都按照某个直线方向做相同距离的移动，这样的运动叫做图形的平移运动。平移后的形状、大小、方向不发生改变，据此解答。\n\n【详解】根据分析：A. 形状、大小、方向没发生改变，符合题意;B. 发生了改变，不符合题意;C. 发生了改变，不符合题意。故答案为:A",
+    "knowledge_points": [
+      "平移与平移现象"
+    ],
+    "source": "24-25 二年级下·河南郑州·期中"
+  },
+  {
+    "id": "212",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面字母不是轴对称图形的是( )。",
+    "options": [
+      "A. H",
+      "B. A",
+      "C. E",
+      "D. P"
+    ],
+    "answer": "D",
+    "solution": "【分析】依据轴对称图形的定义判断：平面内，一个图形沿一条直线折叠，直线两旁的部分能够完全重合，这个图形就是轴对称图形;其中的这条直线就是对称轴。\n\n【详解】A. H对折后两侧的图形能够完全重合，是轴对称图形，不符合题意;B. A对折后两侧的图形能够完全重合，是轴对称图形，不符合题意;C. E对折后两侧的图形能够完全重合，是轴对称图形，不符合题意;D. P无论怎样对折，两侧的图形都不能完全重合，不是轴对称图形，符合题意。故答案为:D",
+    "knowledge_points": [
+      "轴对称的认识及辨认"
+    ],
+    "source": "24-25 二年级下·四川乐山·期末"
+  },
+  {
+    "id": "213",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下列运动中属于平移的是( )。",
+    "options": [
+      "A. 拧瓶盖",
+      "B. 拉抽屉",
+      "C. 风车转动"
+    ],
+    "answer": "B",
+    "solution": "【分析】在平面内，一个图形整体沿着某条直线方向平行移动一定距离的过程，称为平移;在平面内，一个图形围绕某一个固定点按照顺时针或逆时针方向转动一定角度的过程，称为旋转。\n\n【详解】A. 拧瓶盖属于旋转，不符合题意;B. 拉抽屉属于平移，符合题意;C. 风车转动属于旋转，不符合题意。故答案为:B",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "24-25 二年级下·山东济宁·期末"
+  },
+  {
+    "id": "214",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下列现象中，属于旋转现象的是( )。",
+    "options": [
+      "A. ![](images/a5cf3f55ec993333fd9ef4a024265fc44f2c955c7ebc166d88af9fa2221ac406.jpg)",
+      "B. ![](images/d249016fd244716a34284d8cf8bbced368b6a4865bfa3d045e02752dc9cc8469.jpg)",
+      "C. ![](images/aa31a672dff068ad0fb55ca55db441e61e64531ce7afd8fb0d270a9aa246dec4.jpg)"
+    ],
+    "answer": "B",
+    "solution": "【分析】平移：在平面内，将一个图形上的所有点都按照某个方向作相同距离移动的图形运动。平移后图形的位置改变，形状、大小、方向不变。旋转：在平面内，将一个图形绕一点按某个方向转动一定的角度，这样的运动叫做图形的旋转。旋转前后图形的位置和方向改变，形状、大小不变。\n\n【详解】A. 属于平移现象;B. 属于旋转现象;C. 属于平移现象。故答案为:B",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "24-25 二年级下·浙江温州·期末"
+  },
+  {
+    "id": "215",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "下边的哪个图案是通过平移上面的图案得到的。( )\n![](images/d08aba3b94fb2d44892c3c7a6b73969fa28b5923991cbb007ed92cd6f44a3d64.jpg)",
+    "options": [
+      "A. ![](images/b9e011f1fe4d3dabd693ebfa752ea25310ea8c43efba71209977aa656325de8f.jpg)",
+      "B. ![](images/6e7acef30d4b3bc845436b2d29ad41c627bce6491768ba6d7237760371775eb2.jpg)",
+      "C. ![](images/297e54868939934db6ea9300c09d786fa0b7d7e4236bcf849d04f8fb4774d79d.jpg)"
+    ],
+    "answer": "B",
+    "solution": "【分析】在平面内，把一个图形整体沿某条直线方向平行移动一定距离的过程，称为平移。在平面内，把一个图形围绕某一固定点按顺时针或逆时针方向转动一定的角度的过程，称为旋转。平移后的图形不会发生方向变化，旋转后的图形方向会发生变化;由此解答。\n\n【详解】由分析可得：A. 按顺时针旋转后得到的图案，是旋转得到的，不符合题意;B. 图案没有变化，是平移后得到的，符合题意;C. 翻转后得到的图形，既不是旋转也不是平移，不符合题意。故答案为:B",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "24-25二年级下·山东菏泽·期末"
+  },
+  {
+    "id": "216",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "下面的运动现象是旋转的是( )。",
+    "options": [
+      "A. ![](images/4c14e86dabb216147296c0ec8e14a49e727cdd1df7636f8fa49f5e4359934568.jpg)",
+      "B. ![](images/f8cf56a7f8f15199da39522860537166f2ead58151b7a879669bc4e64615918f.jpg)",
+      "C. ![](images/82ca715e6ba7591e58ca8e99dcec8ccdffe85fd2d4816f51cd92e64a3b32e225.jpg)",
+      "D. ![](images/931f33dbc3b65cbfca7591d34da2d339906c6d98dba6555ec1680642363741f0.jpg)"
+    ],
+    "answer": "B",
+    "solution": "【分析】在平面内，把一个图形整体沿某条直线方向平行移动一定距离的过程，称为平移。常见的平移现象有滑滑梯、电梯的移动等;在平面内，把一个图形围绕某一固定点按顺时针或逆时针方向转动一定的角度的过程，称为旋转。常见的旋转现象有旋转木马、摩天轮等。逐项分析，找出旋转运动现象即可。\\n\\n【详解】由分析可得：A. 推窗户是沿直线平行移动，属于平移现象;B. 钟摆绕固定点左右摆动，属于旋转现象;C. 推桌子是沿某条直线方向平行移动，属于平移现象;D. 在车厢里坐的人随着车的移动而移动，属于平移现象。故答案为:B",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "24-25二年级下·山东菏泽·期末"
+  },
+  {
+    "id": "217",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面图形是轴对称图形的有( )个。\n![](images/a2c0813b9d61dddf8fe593499ba094234ec099df93685e2f4cd239a26b0f90cb.jpg)\n![](images/c7aec22b9b37f8f3ae23a9b84b1faad85a164fc1685ebcff5485170e73a334a7.jpg)\n![](images/4882eafbefbca3daebff1a5e5fd3d13fa8ed9e253e94d3fbd3385b4c406623af.jpg)\n![](images/85dbcaa5b6384614fa94c217be64d5f7626e3361529fa6f1b00a20342aa04f52.jpg)",
+    "options": [
+      "A. 1",
+      "B. 2",
+      "C. 3"
+    ],
+    "answer": "A",
+    "solution": "【分析】一个图形沿一条直线对折，直线两旁的图形完全重合，这样的图形叫做轴对称图形，折痕所在的直线是对称轴，由此解答。\n\n【详解】第一个图形不是轴对称图形;第二个图形不是轴对称图形;第三个图形不是轴对称图形;第四个图形是轴对称图形。即，图形中是轴对称图形的有1个。故答案为:A",
+    "knowledge_points": [
+      "轴对称的认识及辨认"
+    ],
+    "source": "24-25 二年级下·山西长治·期中"
+  },
+  {
+    "id": "218",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面的图形是用数学家的名字命名的，其中是轴对称图形的是( )。",
+    "options": [
+      "A. ![](images/274d70bc5e2a64ab35cd48f1b1c5b6d2c28aaf37dd7768e8361ed6e3ba2af178.jpg) 赵爽弦图",
+      "B. ![](images/9787bcbfc9dd3067ed5636a860fd30f7a227ecce25c8b81da28fe629cd7cac9d.jpg) 科克曲线",
+      "C. ![](images/0110d57f194e1c513637f50ff0498586ce69f9aa7898164c62ce110d104e1a1f.jpg) 费马螺线"
+    ],
+    "answer": "B",
+    "solution": "【分析】一个图形沿一条直线对折，直线两旁的图形完全重合，这样的图形叫做轴对称图形，折痕所在的直线是对称轴，由此解答。\n\n【详解】A。 没有对称轴，不是轴对称图形;B. ![](images/5d54494094545cd994a25125a49ebd5c7c7d217f6c9b3ae1b1bfbf17d22911fb.jpg) 有对称轴，是轴对称图形;C. 没有对称轴，不是轴对称图形。则是轴对称图形的是科克曲线。故答案为:B",
+    "knowledge_points": [
+      "轴对称的认识及辨认"
+    ],
+    "source": "24-25 二年级下·山西晋中·期末"
+  },
+  {
+    "id": "219",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面四幅作品分别代表二十四节气中的“雨水”“立夏”“秋分”“小雪”，属于轴对称图形的有( )个。\n![](images/14e652b067796437b21cab498515721fdc907ef4c5d74db71ab0508750f2a550.jpg)\n![](images/a628c361b36389cab80ce2dbe7607180e2479712e09cbe5fb119f3ae24bd1c68.jpg)\n![](images/db187053a54e71c30322507927ea17e87f19535cede2094006bfd558a1f2e4f5.jpg)\n![](images/077b5172fa93a6de873d5e995deb483e316adafe95628b984cf3ae955bbb2a1c.jpg)",
+    "options": [
+      "A. 1",
+      "B. 2",
+      "C. 3"
+    ],
+    "answer": "B",
+    "solution": "【分析】一个图形沿一条直线对折，直线两旁的图形完全重合，这样的图形叫做轴对称图形，折痕所在的直线是对称轴，由此解答。\n\n【详解】由分析得：图3，图4有对称轴，是轴对称图形。则属于轴对称图形的有2个。故答案为:B",
+    "knowledge_points": [
+      "轴对称的认识及辨认"
+    ],
+    "source": "24-25 二年级下·内蒙古赤峰·期中"
+  },
+  {
+    "id": "220",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面字母可以看作是轴对称图形的有( )个。\nH P M S T F J O",
+    "options": [
+      "A. 4",
+      "B. 5",
+      "C. 6"
+    ],
+    "answer": "A",
+    "solution": "【分析】如果一个平面图形沿着一条直线对折后，直线两旁的部分能够互相重合，那么这个图形叫做轴对称图形，这条直线是图形的对称轴，据此解答。\n\n【详解】由分析可知，是轴对称图形的字母有H、M、T、O，共4个。故答案为:A",
+    "knowledge_points": [
+      "轴对称的认识及辨认"
+    ],
+    "source": "24-25 二年级下·河南新乡·期末"
+  },
+  {
+    "id": "221",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "下面( )号图是轴对称图形。",
+    "options": [
+      "A. ![](images/2802ccc5b742aa52b87b1ed96053781a38c664b4243b5d3bc65ddf075541602f.jpg)",
+      "B. ![](images/4a16f9536ad995e90534363504fc1c905451bb6b453206d3a70de076fdc93a08.jpg)",
+      "C. ![](images/92ef67d0e2f4d1213e0b77fc81f52de9c2e2fa4df9f542ecf66151966d363c3e.jpg)"
+    ],
+    "answer": "A",
+    "solution": "【分析】如果一个平面图形沿着一条直线对折后，直线两旁的部分能够完全重合，那么这个图形叫做轴对称图形，这条直线是图形的对称轴，据此解答。\n\n【详解】A. 沿直线对折后两侧的图形能够完全重合，是轴对称图形;B. 无论怎么对折，两侧的图形都不能完全重合，不是轴对称图形;C. 无论怎么对折，两侧的图形都不能完全重合，不是轴对称图形。故答案为:A",
+    "knowledge_points": [
+      "轴对称的认识及辨认"
+    ],
+    "source": "24-25 二年级下·江西赣州·期末"
+  },
+  {
+    "id": "222",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面的运动方式不是平移的是( )。",
+    "options": [
+      "A. ![](images/496b8b1adf5f72c3a162a83e190055f294e10ce2fc67cdb60abf8895c9417cc7.jpg)",
+      "B. ![](images/dda9a199c4b7f052a88adc37a2578dc8022717229e99f42eec0097a19a5291b4.jpg)",
+      "C. ![](images/41262e13e97c14899b0f84f36d6040389664f0eaf9c639e87d83d960d92e69a2.jpg)"
+    ],
+    "answer": "C",
+    "solution": "【分析】平移是指在平面内将一个图形上的所有点都按照某个直线方向做相同距离的移动，这样的图形运动叫做图形的平移运动。旋转是指在平面内将一个图形绕一点按某个方向转动一个角度，这样的运动叫做图形的旋转。据此分析并选择。\n\n【详解】A. 是平移;B. 是平移;C. 是旋转。故答案为:C",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "24-25 三年级下·福建泉州·期末"
+  },
+  {
+    "id": "223",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "观察下面物体的运动，是旋转的为( )。\n![](images/4768e177b9694c4d5ac6e262cb6f2de22b619382911fd210f588e7abee9a2c2a.jpg)\n![](images/15ac95aa504ca5f98ef121db6e3b07c7db27b1718cc48e8fd42a10e1054c209e.jpg)\n![](images/15728a4715254c65138827ca861f797ec2800e411313dcd1ec78df86a68607f2.jpg)",
+    "options": [
+      "A. A",
+      "B. B",
+      "C. C"
+    ],
+    "answer": "B",
+    "solution": "【分析】在平面内，把一个图形整体沿某条直线方向平行移动一定距离的过程，称为平移;在平面内，把一个图形围绕某一固定点或某一条线按某个方向转动一定的角度的过程，称为旋转。据此解答。\n\n【详解】A。 由图可知，抽屉沿着轨道运动，属于平移现象，不满足题意;B. 由图可知，门绕着中间的轴转动，属于旋转现象，满足题意;C. 由图可知，珠子沿着轨道上下运动，属于平移现象，不满足题意。故答案为:B",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "24-25 三年级下·江西九江·期末"
+  },
+  {
+    "id": "224",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面的三个图案中,( )是轴对称图形。",
+    "options": [
+      "A. ![](images/cab23769aed23da507e56013a8020fb4a7c1d57fb8e8819b5825735958e6c9eb.jpg)",
+      "B. ![](images/5b077de1ffa9fde554c88a8798f80fe184e13a50b8c8d9f59c1d20065303c3e9.jpg)",
+      "C. ![](images/da4b36c86a8d9f035522d7cb7389b2e5697183650489b826c6963545e12e002d.jpg)"
+    ],
+    "answer": "B",
+    "solution": "【分析】依据轴对称图形的定义判断：平面内，一个图形沿一条直线折叠，直线两旁的部分能够完全重合，这个图形就是轴对称图形;其中的这条直线就是对称轴。\n\n【详解】A. 无论怎样对折，两侧的图形都不能完全重合，不是轴对称图形;B. 对折后两侧的图形能够完全重合，是轴对称图形;C. 无论怎样对折，两侧的图形都不能完全重合，不是轴对称图形。故答案为:B",
+    "knowledge_points": [
+      "轴对称的认识及辨认"
+    ],
+    "source": "24-25二年级下·浙江温州·期末"
+  },
+  {
+    "id": "225",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面的三个图案中,( )不是轴对称图形。",
+    "options": [
+      "A. ![](images/08618744a387b19af1b8e1fd6783b29022b24f5ea9291487dbc60159fac5a4a3.jpg)",
+      "B. ![](images/f7cf8ca9e02e7678368c61265b7b4b5adb256e48bef6456e69cabcba4a0a57dc.jpg)",
+      "C. ![](images/3e2291719deb84246c52f969dad9c7fc33ed0de320ade7b9addb48385ce4eb7e.jpg)"
+    ],
+    "answer": "B",
+    "solution": "【分析】依据轴对称图形的定义判断：平面内，一个图形沿一条直线折叠，直线两旁的部分能够完全重合，这个图形就是轴对称图形;其中的这条直线就是对称轴。\n\n【详解】A. 沿着这样一条直线对折后，直线两旁的部分能够完全重合，所以它是轴对称图形;B. 沿着一条直线对折后，直线两旁的部分不能完全重合，所以它不是轴对称图形;C. 沿着这样一条直线对折后，直线两旁的部分能够完全重合，所以它是轴对称图形。故答案为:B",
+    "knowledge_points": [
+      "轴对称的认识及辨认"
+    ],
+    "source": "24-25二年级下·浙江温州·期末"
+  },
+  {
+    "id": "226",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面( )不是轴对称图形。",
+    "options": [
+      "A. ![](images/bc927abc61113213034026b34ae958eab5fcc3552ae13a099ca98bd1ee925e86.jpg)",
+      "B. ![](images/532ebd525c5fb6317e5a532baee04ce2cf64181f50b2c0d680fba4758c822c3e.jpg)",
+      "C. ![](images/f10bc231c87208173fd3b166aca246c5d378cc1d8902a8e3bc7865f52110da03.jpg)"
+    ],
+    "answer": "A",
+    "solution": "【分析】在平面内，如果一个图形沿一条直线折叠，直线两旁的部分能够完全重合，这样的图形就叫做轴对称图形，这条直线叫做对称轴。\n\n【详解】A. 此图不是轴对称图形;B. 此图是轴对称图形;C. 此图是轴对称图形。故答案为:A",
+    "knowledge_points": [
+      "轴对称的认识及辨认"
+    ],
+    "source": "22-23二年级下·新疆乌鲁木齐·期末"
+  },
+  {
+    "id": "227",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下列图形中，不是轴对称图形的是( )。",
+    "options": [
+      "A. ![](images/9e5bf953ef0a8f083dbf22e84af96a8f3769b25a63b6e3565366e6d448d587d0.jpg)",
+      "B. ![](images/c2997e5c6e9e8bab5c6b85407dfc802d453aee7c914b5441ce9297c2a0b29b3e.jpg)",
+      "C. ![](images/4dd7f6c566bd9e6adb7276d51f8f00dd1f14f87453f2fd7342e0cefcd2c7c23d.jpg)",
+      "D. ![](images/51803c6f324e0ab27fa806ed0b1fb0b87204e222b15f047d1907f7f43df0b0a3.jpg)"
+    ],
+    "answer": "D",
+    "solution": "【分析】如果沿某条直线对折，对折的两部分是完全重合的，这样的图形为轴对称图形。这条直线叫做这个图形的对称轴。判断一个图案是否是轴对称图形的关键是看在这个图形中能否找到一条直线，使图形沿着这条直线对折后能够完全重合。\n\n【详解】A. 是轴对称图形;B. 是轴对称图形;C. 是轴对称图形;D. 不是轴对称图形。故答案为:D",
+    "knowledge_points": [
+      "轴对称的认识及辨认"
+    ],
+    "source": "24-25一年级下·湖南岳阳·期中"
+  },
+  {
+    "id": "228",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面图形中，( )是轴对称图形。",
+    "options": [
+      "A. ![](images/1353489b52615cf1f55946312807a5fc7e591aeded72ae84a6ca6cc61e1b8742.jpg)",
+      "B. ![](images/a15cf0a27a8cf51690311046c5df1dc8f82762fcfb9fe2d645e2f5f115cf0811.jpg)",
+      "C. ![](images/4429edc2af64dc1f9fc9400dd26bdd876f36b016c8055f71e9e17ddb399bfade.jpg)",
+      "D. ![](images/7bcf70c245fc4e662602bec5cbd62aeafe6ca7cec982337b610eb518460136c8.jpg)"
+    ],
+    "answer": "A",
+    "solution": "【分析】如果沿某条直线对折，对折的两部分是完全重合的，这样的图形为轴对称图形。这条直线叫做这个图形的对称轴。判断一个图案是否是轴对称图形的关键是看在这个图形中能否找到一条直线，使图形沿着这条直线对折后能够完全重合。\n\n【详解】根据分析可知：A. 是轴对称图形;B. 不是轴对称图形;C. 不是轴对称图形;D. 不是轴对称图形。故答案为:A",
+    "knowledge_points": [
+      "轴对称的认识及辨认"
+    ],
+    "source": "23-24二年级下·广东揭阳·期末"
+  },
+  {
+    "id": "229",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面的图形中，( )是轴对称图形。",
+    "options": [
+      "A. ![](images/f28d1ed3326d8de2e0ee26cae243be9c33bd030f2e11d425fc3a113e8c32efc7.jpg)",
+      "B. ![](images/8b77a0bcfe5961725941b6830f5f1fd915d8abd768e48f04c85976adaabeb069.jpg)",
+      "C. ![](images/524fcfeafe22de75074152546a3f1c21ca3fd6f0b3f13e5eda8ec134539074e6.jpg)"
+    ],
+    "answer": "C",
+    "solution": "【分析】根据题意，把图形按照一条直线对折，直线两边的部分能够完全重合，这样的图形叫做轴对称图形，这条直线就是图形的对称轴。\n\n【详解】根据分析可知：A. 没有对称轴，不是轴对称图形;B. 没有对称轴，不是轴对称图形;C. 有1条对称轴，是轴对称图形。故答案为:C",
+    "knowledge_points": [
+      "轴对称的认识及辨认",
+      "对称轴的画法及数量"
+    ],
+    "source": "24-25 二年级下·河北邢台·期末"
+  },
+  {
+    "id": "230",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面图形中，( )不是轴对称图形。",
+    "options": [
+      "A. 心形",
+      "B. 平行四边形",
+      "C. 圆"
+    ],
+    "answer": "B",
+    "solution": "【分析】依据轴对称图形的概念，在平面内，如果沿着一条直线折叠，直线两旁的部分能够完全重合，这样的图形叫做轴对称图形。根据轴对称图形的概念，逐项分析，找出不符合的图形，据此解答。\n\n【详解】由分析可得：A. 心形沿中间画一条对称轴，对称轴左右两边图形能完全重合，所以是轴对称图形;B. 平行四边形沿一条直线对折后，两边不能完全重合，所以不是轴对称图形;C. 通过圆心任意画一条直线作对称轴，对称轴两边图形都能完全重合，所以是轴对称图形。故答案为:B",
+    "knowledge_points": [
+      "轴对称的认识及辨认"
+    ],
+    "source": "24-25二年级下·湖南岳阳·期中"
+  },
+  {
+    "id": "231",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "下面生活现象不属于旋转的是( )。",
+    "options": [
+      "A. 钟表指针的运动",
+      "B. 汽车方向盘的转动",
+      "C. 电梯的运动",
+      "D. 电风扇扇叶的运动"
+    ],
+    "answer": "C",
+    "solution": "【分析】像推东西、开关抽屉这样沿着直线移动的现象叫做平移;像转动方向盘、电风扇转动、旋转木马这样绕着一个点或一个轴运动的现象叫做旋转。\n\n【详解】A. 钟表指针的运动属于旋转;B. 汽车方向盘的转动属于旋转;C. 电梯的运动属于平移;D. 电风扇扇叶的运动属于旋转。故答案为:C",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "24-25 三年级下·河南驻马店·期末"
+  },
+  {
+    "id": "232",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "下列现象中，( )不是旋转现象。",
+    "options": [
+      "A. ![](images/ab176e52a9823c3be7d5912bf548458cc8f8ffcf45be84f3b450c252f0ad1a8a.jpg)",
+      "B. ![](images/10501ae34e3352d1e4ea62c3180cf405704dbd98ea93ed5d6df0dfd7a800af09.jpg)",
+      "C. ![](images/30e5487580606c9a735b8715a4a062a85cc7f671fa240598b7496909354501d6.jpg)"
+    ],
+    "answer": "B",
+    "solution": "【分析】在平面内，把一个物体或图形整体沿某条直线方向平行移动一定距离的过程，称为平移;在平面内，把一个物体或图形围绕某一固定点或某一条线按某个方向转动一定的角度的过程，称为旋转。据此解答。\n\n【详解】A. 由图可知，扇叶绕着中心点转动，属于旋转现象;B. 由图可知，珠子沿着轨道上下移动，属于平移现象;C. 由图可知，指针绕着中心点转动，属于旋转现象。故答案为:B",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "24-25 三年级下·重庆潼南·期末"
+  },
+  {
+    "id": "233",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下列运动属于旋转的是( )。",
+    "options": [
+      "A. 汽车转动的车轮",
+      "B. 直线行驶的高铁",
+      "C. 火箭升空"
+    ],
+    "answer": "A",
+    "solution": "【分析】在平面内，把一个图形整体沿某条直线方向平行移动一定距离的过程，称为平移，常见的平移现象有滑滑梯、推拉窗户等。在平面内，把一个图形围绕某一固定点按顺时针或逆时针方向转动一定的角度的过程，称为旋转，常见的旋转现象有旋转木马、摩天轮等。\n\n【详解】A. 汽车转动的车轮是旋转现象，符合题意;B. 直线行驶的高铁是平移现象，不符合题意;C. 火箭升空是平移现象，不符合题意。故答案为:A",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "24-25 二年级下·广东广州·期末"
+  },
+  {
+    "id": "234",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下列现象中，( )不是旋转现象。",
+    "options": [
+      "A. ![](images/ab176e52a9823c3be7d5912bf548458cc8f8ffcf45be84f3b450c252f0ad1a8a.jpg)",
+      "B. ![](images/10501ae34e3352d1e4ea62c3180cf405704dbd98ea93ed5d6df0dfd7a800af09.jpg)",
+      "C. ![](images/30e5487580606c9a735b8715a4a062a85cc7f671fa240598b7496909354501d6.jpg)"
+    ],
+    "answer": "B",
+    "solution": "【分析】在平面内，把一个物体或图形整体沿某条直线方向平行移动一定距离的过程，称为平移;在平面内，把一个物体或图形围绕某一固定点或某一条线按某个方向转动一定的角度的过程，称为旋转。据此解答。\n\n【详解】A. 由图可知，扇叶绕着中心点转动，属于旋转现象;B. 由图可知，珠子沿着轨道上下移动，属于平移现象;C. 由图可知，指针绕着中心点转动，属于旋转现象。故答案为:B",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "24-25 三年级下·重庆潼南·期末"
+  },
+  {
+    "id": "235",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下列运动属于旋转的是( )。",
+    "options": [
+      "A. 汽车转动的车轮",
+      "B. 直线行驶的高铁",
+      "C. 火箭升空"
+    ],
+    "answer": "A",
+    "solution": "【分析】在平面内，把一个图形整体沿某条直线方向平行移动一定距离的过程，称为平移，常见的平移现象有滑滑梯，推拉窗户等。在平面内，把一个图形围绕某一固定点按顺时针或逆时针方向转动一定的角度的过程，称为旋转，常见的旋转现象有旋转木马，摩天轮等。\n\n【详解】A。 汽车转动的车轮是旋转现象，符合题意;B. 直线行驶的高铁是平移现象，不符合题意;C. 火箭升空是平移现象，不符合题意。则属于旋转的是汽车转动的车轮。故答案为:A",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "24-25 二年级下·广东广州·期末"
+  },
+  {
+    "id": "236",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "寓意深远的汉字文化中也蕴含着数学的美。在“昌、正、比、台、全”这些汉字中，有( )个轴对称的字。",
+    "options": [
+      "A. 1",
+      "B. 2",
+      "C. 3"
+    ],
+    "answer": "B",
+    "solution": "【分析】根据轴对称图形的意义：如果一个图形沿着一条直线对折后两部分完全重合，这样的图形叫做轴对称图形，这条直线叫做对称轴;依次进行判断即可。\n\n【详解】由分析可得：只有“昌”“全”这两个字左右对折后，两侧能够完全重合。在“昌、正、比、台、全”这些汉字中，有2个轴对称的字。故答案为:B",
+    "knowledge_points": [
+      "轴对称的认识及辨认"
+    ],
+    "source": "24-25 二年级下·广西柳州·期末"
+  },
+  {
+    "id": "237",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下列哪幅图不是轴对称图形( )。",
+    "options": [
+      "A. ![](images/c9de814a8e26e8e16bbec5b8be54c0295fdb6a302a43f7e798022b3337a962b3.jpg)",
+      "B. ![](images/eaad443c79705e8de2e61262a468f313b075c7383a7975efac202ff0a542e239.jpg)",
+      "C. ![](images/44a5d7637aedf15585c5b6a57aabdd5ca9fda1dff27d66782443feee7dc85ec2.jpg)"
+    ],
+    "answer": "A",
+    "solution": "【分析】轴对称：在平面内，如果一个图形沿一条直线对折，对折后的两部分都能完全重合，这样的图形叫做轴对称图形，这条直线就是其对称轴。\n\n【详解】A. 不是轴对称图形;B. 沿虚线对折可以完全重合，是轴对称图形;C. 沿虚线对折可以完全重合，是轴对称图形。故答案为:A",
+    "knowledge_points": [
+      "轴对称的认识及辨认"
+    ],
+    "source": "24-25二年级下·浙江温州·期末"
+  },
+  {
+    "id": "238",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下列图形中，不是轴对称图形的是( )。",
+    "options": [
+      "A. ![](images/9fbf46066b2374d2faa62877b11d61f8a5f6a335555e9bd9d78b8e88c3e8cf4e.jpg)",
+      "B. ![](images/de89d5807913365a69aa5ff5a170d4890b4f64ec1cfb9ef3bef3b923e1e36b7d.jpg)",
+      "C. ![](images/f1ac8405fdc6c3038225afa92b4f4f0ce6892cd0aaab4e898789b322ef96e0fd.jpg)",
+      "D. ![](images/4f385b374be3d06fba2309ce47b9b2b13089dc59fdc6b458232685c947bcb75c.jpg)"
+    ],
+    "answer": "D",
+    "solution": "【分析】一个图形沿着一条直线折叠，直线两侧的部分能够完全重合，这样的图形就是轴对称图形，据此解题。\n\n【详解】A. 是轴对称图形;B. 是轴对称图形;C. 是轴对称图形;D. 不是轴对称图形。故答案为:D",
+    "knowledge_points": [
+      "轴对称的认识及辨认"
+    ],
+    "source": "22-23 三年级下·青海西宁·期末"
+  },
+  {
+    "id": "239",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下列现象中属于平移的是( )。",
+    "options": [
+      "A. 风车旋转",
+      "B. 电梯升降",
+      "C. 拧开水龙头",
+      "D. 荡秋千"
+    ],
+    "answer": "B",
+    "solution": "【分析】平移是指在平面内将一个图形上的所有点都按照某个直线方向做相同距离的移动，这样的图形运动叫做图形的平移运动。旋转是指在平面内将一个图形绕一点按某个方向转动一个角度，这样的运动叫做图形的旋转。\n\n【详解】A. 风车旋转属于旋转;B. 电梯升降属于平移;C. 拧开水龙头属于旋转;D. 荡秋千属于旋转。故答案为:B",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "24-25 三年级下·湖南长沙·期中"
+  },
+  {
+    "id": "240",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "将一张长方形纸对折一次，照着图( )剪，打开后会有两个连着的三角形。",
+    "options": [
+      "A. ![](images/3dd12d829781e8b4626eacab3b560ad92085890b37628d16a55f5cb016f7a2b3.jpg)",
+      "B. ![](images/8962d3598cff36fd9494c4140b92c088a68aafc34888e70caf640e49d3e22ad7.jpg)",
+      "C. ![](images/1dee28d1caee66b001fd437da35db456220ad326553a0eb37ac49bf80278b253.jpg)"
+    ],
+    "answer": "C",
+    "solution": "【分析】一个图形沿一条直线对折，直线两旁的图形完全重合，这样的图形叫做轴对称图形，折痕所在的直线是对称轴。要想打开后有两个连着的三角形，说明对称轴一侧应有1个完整的三角形，据此解答。\n\n【详解】A. 对称轴一侧只有半个三角形，打开后只有1个三角形，不符合题意;B. 对称轴一侧有2个三角形，打开后有4个连着的三角形，不符合题意;C. 对称轴一侧有1个三角形，打开后有2个连着的三角形，符合题意。故答案为:C",
+    "knowledge_points": [
+      "轴对称的剪纸问题"
+    ],
+    "source": "24-25二年级下·浙江嘉兴·期末"
+  },
+  {
+    "id": "241",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面四个银行标志中，( )不是轴对称图形。",
+    "options": [
+      "A. ![](images/56fb07cbb6209d0576c473dd7092d88aec1ce5887c63fd2debb80c9ddb42bd43.jpg)",
+      "B. ![](images/741fd68823bb4b01eef1b296718ed01d9f4316c53966b6e6eb0e9fded0621779.jpg)",
+      "C. ![](images/b5547769a61b3559745a5d619d220ea814ddfda6857869cc38e99fe180974725.jpg)",
+      "D. ![](images/9553a96f5d655288d4ff01b0525709f01d5341c5d8f1c6b62ddbe31fb1c575c0.jpg)"
+    ],
+    "answer": "A",
+    "solution": "【分析】一个图形沿着一条直线对折后，直线两旁的部分能够完全重合，这样的图形就叫做轴对称图形，据此解答。\n\n【详解】A. 沿着一条直线对折后，直线两旁的部分不能完全重合，所以它不是轴对称图形;B. 沿着这样一条直线对折后，直线两旁的部分能够完全重合，所以它是轴对称图形;C. 沿着这样一条直线对折后，直线两旁的部分能够完全重合，所以它是轴对称图形;D. 沿着这样一条直线对折后，直线两旁的部分能够完全重合，所以它是轴对称图形。故答案为:A",
+    "knowledge_points": [
+      "轴对称的认识及辨认"
+    ],
+    "source": "23-24 二年级下·浙江台州·期末"
+  },
+  {
+    "id": "242",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "下面哪个图案可以看成轴对称图形。( )",
+    "options": [
+      "A. ![](images/7aa715c07b800afb7cb01f4e4daa942fbb3833e0905b89e4b2446d8aa3099762.jpg)",
+      "B. ![](images/3f73dd41676019e622b78be021543221fc6df05d06c9e7893b7e957f74a85f4e.jpg)",
+      "C. ![](images/9bfaebaea07d2f2a3d4a44bd29eb82d894868374f9f409a62131e76a884a9dfb.jpg)"
+    ],
+    "answer": "C",
+    "solution": "【分析】在平面内，如果一个图形沿一条直线折叠，直线两旁的部分能够完全重合，这样的图形就叫做轴对称图形，这条直线叫做对称轴。据此解答。\n\n【详解】A. 不能沿一条直线折叠重合，此图不可以看成轴对称图形;B. 不能沿一条直线折叠重合，此图不可以看成轴对称图形;C. 能沿一条直线折叠重合，此图可以看成轴对称图形。故答案为:C",
+    "knowledge_points": [
+      "轴对称的认识及辨认"
+    ],
+    "source": "22-23 二年级下·新疆乌鲁木齐·期末"
+  },
+  {
+    "id": "243",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "妈妈在处理一张图片时做了下面一系列动作，下面能依次正确描述这些动作的是( )。![](images/29638fa7ed49ec75571ec061443920051247de89944cd449baf36732f70d2ca4.jpg)",
+    "options": [
+      "A. 旋转;平移;平移",
+      "B. 旋转;平移;旋转",
+      "C. 平移;旋转;平移"
+    ],
+    "answer": "B",
+    "solution": "【分析】在平面内，一个图形整体沿着某条直线方向平行移动一定距离的过程，称为平移;在平面内，一个图形围绕某一个固定点按照顺时针或逆时针方向转动一定角度的过程，称为旋转。\n\n【详解】由分析可知：图1经过旋转得到图2，图2经过平移得到图3，图3经过旋转得到图4。因此，这些动作依次是旋转、平移、旋转。故答案为:B",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "24-25 二年级下·山西长治·期中"
+  },
+  {
+    "id": "244",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "在以下现象中，属于平移的是( )。",
+    "options": [
+      "A. 时钟的分针走过",
+      "B. 同学们做荡秋千游戏",
+      "C. 乘电梯"
+    ],
+    "answer": "C",
+    "solution": "【分析】平移：在平面内，将一个图形上的所有点都按照某个方向作相同距离移动的图形运动。平移后图形的位置改变，形状、大小、方向不变。旋转：在平面内，将一个图形绕一点按某个方向转动一定的角度，这样的运动叫做图形的旋转。旋转前后图形的位置和方向改变，形状、大小不变。\n\n【详解】A. 时钟的分针走动属于旋转现象;B. 同学们做荡秋千游戏属于旋转现象;C. 乘电梯属于平移现象。故答案为:C",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "24-25 二年级下·山东日照·期中"
+  },
+  {
+    "id": "245",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "按下面左边这样的方法剪，剪出来的是( )。\n![](images/697ae079327905e4df7733a76ffe38c148fcb87ad0d0e8b78f489f9ee99b9768.jpg)",
+    "options": [
+      "A. ![](images/00e4b973fa5bfed17d7f8c31daf57fc21bb6dcf3cf958b53cd996d791786a824.jpg)",
+      "B. ![](images/58d98cfb45dd0358edafadcf97fd817681907537da3c0968744b65fa4bbc7c03.jpg)",
+      "C. ![](images/8f1a51f2159c2695a9d62c7bf24178ae61fbecd434abff91f196783006987a38.jpg)"
+    ],
+    "answer": "C",
+    "solution": "【分析】观察左边的剪纸方法可知，纸张是对折后再剪的，打开后得到的图形应左右对称。根据剪口的形状判断展开后的图案即可。\n\n【详解】按左边这样的方法剪，打开后得到的图案是C。故答案为:C",
+    "knowledge_points": [
+      "轴对称的剪纸问题"
+    ],
+    "source": "23-24 二年级下·浙江台州·期末"
+  },
+  {
+    "id": "246",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面的图案中，( )不是轴对称图形。",
+    "options": [
+      "A. ![](images/82b3fe39d001ee6bd47fd4009049eeec82ca34564c4e083ea2915f6325dbb402.jpg)",
+      "B. ![](images/6ad79c95eafad3ebc877884dc97736d04794fc63c1eb0a8eb26591741f062cc0.jpg)",
+      "C. ![](images/cae1f5ecde68ce6977a2a8a55daabfc134e44d991663465a9ac9fb19f78a17b2.jpg)"
+    ],
+    "answer": "C",
+    "solution": "【分析】如果沿某条直线对折，对折的两部分是完全重合的，这样的图形为轴对称图形。这条直线叫做这个图形的对称轴。判断一个图案是否是轴对称图形的关键是看在这个图形中能否找到一条直线，使图形沿着这条直线对折后能够完全重合。\n\n【详解】A. 是轴对称图形;B. 是轴对称图形;C. 不是轴对称图形。故答案为:C",
+    "knowledge_points": [
+      "轴对称的认识及辨认"
+    ],
+    "source": "23-24 二年级下·新疆昌吉·期末"
+  },
+  {
+    "id": "247",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "我们在按要求进行图形的旋转时，要用到( ).\n①旋转中心 ②旋转方向 ③旋转角度",
+    "options": [
+      "A. ①②",
+      "B. ②③",
+      "C. ①②③"
+    ],
+    "answer": "C",
+    "solution": "【分析】旋转的三要素是旋转中心、旋转方向、旋转角度。旋转图形时必须有一个固定不变的点，整个图形绕着这个点旋转，这个点就是旋转中心;旋转方向分为顺时针和逆时针;转多少由旋转角度决定。\n\n【详解】我们在按要求进行图形的旋转时，要用到旋转中心、旋转方向、旋转角度，即①②③都要用到。故答案为:C",
+    "knowledge_points": [
+      "旋转三要素及旋转图形"
+    ],
+    "source": "23-24 五年级下·重庆丰都·期末"
+  },
+  {
+    "id": "248",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下列( )现象属于平移。",
+    "options": [
+      "A. 转动的风扇",
+      "B. 指南针",
+      "C. 推拉窗户"
+    ],
+    "answer": "C",
+    "solution": "【分析】平移是指在平面内，将一个图形上的所有点都按照某个直线方向做相同距离的移动，这样的图形运动叫做图形的平移运动，简称平移。平移后图形的位置改变，形状、大小、方向不变。旋转：在平面内，将一个图形绕一点按某个方向转动一定的角度，这样的运动叫做图形的旋转。旋转后图形的位置和方向改变，形状、大小不变。\n\n【详解】A. 转动的风扇属于旋转;B. 指南针属于旋转;C. 推拉窗户属于平移。故答案为:C",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "24-25 二年级下·河南漯河·期末"
+  },
+  {
+    "id": "249",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "国旗的升降运动是( )现象。",
+    "options": [
+      "A. 旋转",
+      "B. 平移",
+      "C. 对称"
+    ],
+    "answer": "B",
+    "solution": "【分析】国旗沿旗杆上下移动，方向不变，属于平移现象。据此解答。\n\n【详解】由分析可知：国旗的升降运动是平移现象。故答案为:B",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "24-25 二年级下·河南周口·期末"
+  },
+  {
+    "id": "250",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下图中有( )个轴对称图形。![](images/image-3.png)",
+    "options": [
+      "A. 6",
+      "B. 4",
+      "C. 3",
+      "D. 2"
+    ],
+    "answer": "D",
+    "solution": "【分析】如果沿某条直线对折，对折的两部分是完全重合的，这样的图形为轴对称图形。这条直线叫做这个图形的对称轴。判断一个图案是否是轴对称图形的关键是看在这个图形中能否找到一条直线，使图形沿着这条直线对折后能够完全重合。\n\n【详解】图中有2个轴对称图形。故答案为:D",
+    "knowledge_points": [
+      "轴对称的认识及辨认"
+    ],
+    "source": "23-24 二年级下·福建龙岩·期末"
+  },
+  {
+    "id": "251",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面通过平移可以和原图重合的图形是( )。![](images/4f169b6870ca39cf3f41155e70a0a4a8af3a8c617fbd1eccedefa579a171dd92.jpg)",
+    "options": [
+      "A. ![](images/62ed345f85d6d5a9fbe2581d7d3e18f1879cbb4e8e11a15ab9daacc571dc7d3f.jpg)",
+      "B. ![](images/f9ec2330d4e671003928c15d17cb3d008cbca500387a386b5b48bbcc3260e177.jpg)",
+      "C. ![](images/f28e01088dda9e80a8ef87c4b9bc5d95cb9474ec7a53b25473c2d320947c5e72.jpg)"
+    ],
+    "answer": "A",
+    "solution": "【分析】平移是指在平面内，将一个图形上的所有点都按照某个直线方向做相同距离的移动，这样的图形运动叫做图形的平移运动，简称平移。平移后图形的位置改变，形状，大小，方向不变。旋转：在平面内，将一个图形绕一点按某个方向转动一定的角度，这样的运动叫做图形的旋转。旋转后图形的位置和方向改变，形状，大小不变。\n\n【详解】A。 形状，大小，方向不变，可以通过平移重合;B. 方向变了，不能通过平移重合;C. 方向变了，不能通过平移重合。通过平移可以和原图重合的图形是A。故答案为:A",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "24-25 二年级下·山东日照·期中"
+  },
+  {
+    "id": "252",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "下面的几幅图中，通过图A平移得到的是图( ),通过图A旋转得到的是图( )。![](images/2d47f73180799627adb22d8b4eaf7e18f3df7136d1cc40e46bf95d200b182a6a.jpg)![](images/1d8845d8d09a8cdc10411bdcb2e6453292731bb133d5888b61a181436ae6314e.jpg)![](images/9b4fb1158bb252216bff775ec8bcbbf2c50d19764c0bbdae97f8bf176e6ed92d.jpg)![](images/f94c32ffcbc532c07b5fd23e51eb5d930a33b59dfc986af8e4fc8637f10abfc4.jpg)",
+    "options": [
+      "A. ①②",
+      "B. ②③",
+      "C. ①③"
+    ],
+    "answer": "B",
+    "solution": "【分析】在平面内，把一个图形整体沿某条直线方向平行移动一定距离的过程，称为平移。常见的平移现象有滑滑梯，电梯的移动等;在平面内，把一个图形围绕某一固定点按顺时针或逆时针方向转动一定的角度的过程，称为旋转。常见的旋转现象有旋转木马，摩天轮等。由此解答。\n\n【详解】由分析可得:①图中树枝的方向跟A图中树枝的方向相反，无法通过平移或旋转得到;②图中树枝的方向跟A图中树枝的方向一致，其它部分也跟A图相同，可以通过平移得到;③图绕正方形中心旋转之后就能得到跟③图方向一致的图案，故可以通过旋转得到。故答案为:B",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "24-25 二年级下·河北邢台·期末"
+  },
+  {
+    "id": "253",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面每组图形中,( )的两个图形经过平移可以完全重合。",
+    "options": [
+      "A. ![](images/b8c419c2d46b872672e16446cc9a076f3e507cba9cb36087d63fbc2c8d2928d1.jpg)",
+      "B. ![](images/038ca77e85133a036338c6f0ff2080e19a208674ceabcf8cd50d45e7b80dba46.jpg)",
+      "C. ![](images/a8f447674d832ec3dd3aa2b6b2b7b9b6b2a79ef449b368fe12668596f8b293c8.jpg)"
+    ],
+    "answer": "C",
+    "solution": "【分析】平移是指在平面内，将一个图形上的所有点都按照某个直线方向做相同距离的移动，这样的图形运动叫做图形的平移运动，简称平移。平移后图形的位置改变，形状，大小，方向不变。旋转：在平面内，将一个图形绕一点按某个方向转动一定的角度，这样的运动叫做图形的旋转。旋转后图形的位置和方向改变，形状，大小不变。如果沿某条直线对折，对折的两部分是完全重合的，这样的图形为轴对称图形。这条直线叫做这个图形的对称轴。判断一个图案是否是轴对称图形的关键是看在这个图形中能否找到一条直线，使图形沿着这条直线对折后能够完全重合。逐项分析。\n\n【详解】A。 是轴对称图形，不能经过平移完全重合;B。方向变了，不能经过平移完全重合;C. 两个图形经过平移可以完全重合。故答案为:C",
+    "knowledge_points": [
+      "轴对称的认识及辨认",
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "23-24 二年级下·浙江嘉兴·期末"
+  },
+  {
+    "id": "254",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面这些拼图卡片中，是轴对称图形的是( )。![](images/5a01ddb0e3354239232089d605ad7d008a084ba48939cd977114f4c1ec913ca0.jpg)![](images/b7aa7774ffbc083378d8352d8fcbc17617d9d68228c6611392ad100171760fe3.jpg)![](images/a4ea23757d9b5bba03739067bb7fc515f48d2420a0407717e5a3a28712a28931.jpg)",
+    "options": [
+      "A. A",
+      "B. B",
+      "C. C"
+    ],
+    "answer": "A",
+    "solution": "【分析】如果沿某条直线对折，对折的两部分是完全重合的，这样的图形为轴对称图形。这条直线叫做这个图形的对称轴。判断一个图案是否是轴对称图形的关键是看在这个图形中能否找到一条直线，使图形沿着这条直线对折后能够完全重合。\n\n【详解】A。 ![](images/34ff439dac6c3639f9364ec28b323088ae932cf78aa2b0299eedd97afe823f1e.jpg) 是轴对称图形;B. 不是轴对称图形;C. 不是轴对称图形。是轴对称图形的是A。故答案为:A",
+    "knowledge_points": [
+      "轴对称的认识及辨认"
+    ],
+    "source": "24-25二年级下·陕西渭南·期末"
+  },
+  {
+    "id": "255",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面现象中,( )是旋转。",
+    "options": [
+      "A. ![](images/dc490213dc6fd30fc606810df8479e655e3ea25ec3605aefdecfae3b07a3009a.jpg)",
+      "B. ![](images/28b255b91d864f57a6a05192545a312a8be1e738de57968abc100fdf4db60909.jpg)",
+      "C. ![](images/6271c648a8f0c392c64a84cbc3063fd91bc0fb831da735e9e4eca3303b14438d.jpg)"
+    ],
+    "answer": "C",
+    "solution": "【分析】在平面内，把一个图形整体沿某条直线方向平行移动一定距离的过程，称为平移，常见的平移的现象有滑滑梯，推拉窗户等。在平面内，把一个图形围绕某一固定点按顺时针或逆时针方向转动一定的角度的过程，称为旋转，常见的旋转现象有旋转木马，摩天轮等。由此解答。\n\n【详解】A。 推动箱子是平移现象，不符合题意;B. 推拉窗户是平移现象，不符合题意;C. 电风扇的转动是旋转现象，符合题意。则C是旋转。故答案为:C",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "24-25 二年级下·甘肃庆阳·期中"
+  },
+  {
+    "id": "256",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "汽车行驶时车轮的运动是( )现象。",
+    "options": [
+      "A. 旋转",
+      "B. 平移",
+      "C. 移动"
+    ],
+    "answer": "A",
+    "solution": "【分析】根据题意，平移是指在平面内将一个图形上的所有点都按照某个直线方向做相同距离的移动，这样的运动叫做图形的平移运动。旋转是指在平面内将一个图形绕一点按某个方向转动一个角度，这样的运动叫做图形的旋转运动。\n\n【详解】根据分析：汽车行驶时的车轮的运动是旋转现象。故答案为:A",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "23-24 二年级下·贵州黔南·期末"
+  },
+  {
+    "id": "257",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面那个汉字是轴对称图形( )。",
+    "options": [
+      "A. 光",
+      "B. 由",
+      "C. 立"
+    ],
+    "answer": "B",
+    "solution": "【分析】根据题意，轴对称，把图形按照一条直线对折，直线两边的部分能够完全重合，这样的图形叫做轴对称图形，这条直线就是图形的对称轴。\n\n【详解】A。 光没有对称轴，不是轴对称图形，不符合题意;B. 由有对称轴，是轴对称图形，符合题意;C. 立没有对称轴，不是轴对称图形，不符合题意。故答案为:B",
+    "knowledge_points": [
+      "轴对称的认识及辨认"
+    ],
+    "source": "23-24 二年级下·贵州黔南·期末"
+  },
+  {
+    "id": "258",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "以下不是平移现象的是( )。\n![](images/1c0def0bddd345907f88b28d4a2750d7e22cdc35687e4c0cbd5bbc5252d55c36.jpg)\n![](images/b43f64782bd769d3b47231eb283274632fcd81a6d6376f4723c0d7ba73689929.jpg)\n![](images/21f4ee9387beae578f2d41d3def981b74c902bf7352c5155c1f96a45a763df4b.jpg)",
+    "options": [
+      "A. 电梯的运动",
+      "B. 风车的转动",
+      "C. 拨算珠"
+    ],
+    "answer": "B",
+    "solution": "【分析】在平面内，把一个图形整体沿某条直线方向平行移动一定距离的过程，称为平移，常见的平移现象有滑滑梯、推拉窗户等。在平面内，把一个图形围绕某一固定点按顺时针或逆时针方向转动一定的角度的过程，称为旋转，常见的旋转现象有旋转木马、摩天轮等。\n\n【详解】A. 电梯的运动是平移现象，符合题意;B. 风车的转动是旋转现象，不符合题意;C. 拨算珠是平移现象，符合题意。故答案为:B",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "23-24 二年级下·河北唐山·期末"
+  },
+  {
+    "id": "259",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "观察如图所示三张图片，飞船的发射升空运动是( )现象，二七纪念塔的造型设计蕴含着( )现象，“风力发电机”的转动过程中蕴含着( )现象，以下三个答案都正确的是( )。\n![](images/7886ba51a549b1702e27df7a8ba67375c3ca36944d8316d2f827e56cdc0f3ebd.jpg)\n![](images/c657173b8d0ba1cc25e3d8b5f2e9f60d520fe6c7bb8ffa67328406c8a4d4a6e5.jpg)\n![](images/a8b8f1258e88c736b87657eab427753ec6dc48d20e38a36c1396949b9139f684.jpg)",
+    "options": [
+      "A. 平移，旋转，轴对称",
+      "B. 轴对称，平移，旋转",
+      "C. 平移，轴对称，旋转"
+    ],
+    "answer": "C",
+    "solution": "【分析】在平面内，一个图形整体沿着某条直线方向平行移动一定距离的过程，称为平移;在平面内，一个图形围绕某一个固定点按照顺时针或逆时针方向转动一定角度的过程，称为旋转;一个图形沿着一条直线对折后，直线两旁的部分能够完全重合，这样的图形就叫做轴对称图形，据此解答。\n\n【详解】飞船的发射升空运动是平移现象，二七纪念塔的造型设计蕴含着轴对称现象，“风力发电机”的转动过程中蕴含着旋转现象。故答案为:C",
+    "knowledge_points": [
+      "轴对称的认识及辨认",
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "23-24二年级下·河南信阳·期末"
+  },
+  {
+    "id": "260",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "下面属于旋转现象的有( )。\n①汽车行驶在笔直的路上 ②电风扇的转动\n③钟表指针的转动 ④电梯上下运动",
+    "options": [],
+    "answer": "②③",
+    "solution": "【分析】在平面内，把一个图形整体沿某条直线方向平行移动一定距离的过程，称为平移。在平面内，把一个图形围绕某一固定点按顺时针或逆时针方向转动一定的角度的过程，称为旋转。①汽车行驶在笔直的路上，属于平移现象，不符合题意;②电风扇的转动，属于旋转现象，符合题意;③钟表指针的转动，属于旋转现象，符合题意;④电梯上下运动，属于平移现象，不符合题意;据此可解。\n\n【详解】由分析可得：属于旋转现象的有②③。",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "24-25 二年级下·辽宁鞍山·期末"
+  },
+  {
+    "id": "261",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "开门时，钥匙的运动属于( )现象;滑一下手机屏幕接听电话，手指的运动属于( )现象。(填'平移'或'旋转')",
+    "options": [],
+    "answer": "旋转;平移",
+    "solution": "【分析】在平面内，把一个图形整体沿某条直线方向平行移动一定距离的过程，称为平移。常见的平移现象有滑滑梯，电梯的移动等;在平面内，把一个图形围绕某一固定点按顺时针或逆时针方向转动一定的角度的过程，称为旋转。常见的旋转现象有旋转木马，摩天轮等。由此解答。\n\n【详解】根据分析可得：开门时，钥匙的运动属于旋转现象;滑一下手机屏幕接听电话，手指的运动属于平移现象。",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "24-25 二年级下·福建漳州·期末"
+  },
+  {
+    "id": "262",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "国旗的升降是( )现象，方向盘的转动是( )现象。(填'平移'或'旋转')",
+    "options": [],
+    "answer": "平移;旋转",
+    "solution": "【分析】平移是指在平面内将一个图形上的所有点都按照某个直线方向做相同距离的移动，这样的运动叫做图形的平移运动。旋转是指在平面内将一个图形绕一点按某个方向转动一个角度，这样的运动叫做图形的旋转运动。国旗升降是直线运动，属于平移;方向盘绕轴转动，属于旋转。\n\n【详解】由分析可知：国旗的升降是平移现象，方向盘的转动是旋转现象。",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "24-25 二年级下·广西玉林·期末"
+  },
+  {
+    "id": "263",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "你在生活中见到的( )和( )都是轴对称图形。",
+    "options": [],
+    "answer": "圆形钟面;课桌面",
+    "solution": "【分析】依据轴对称图形的概念，在平面内，如果沿着一条直线折叠，直线两旁的部分能够完全重合，这条线叫对称轴，这样的图形叫轴对称图形。\n\n【详解】由分析可得：圆形钟面通过钟面指针轴，任意画一条线都可以作对称轴，沿着对称轴折叠，两旁的部分能够完全重合;课桌面是一个长方形，通过长边或短边中点向对边中点画线，都可以作长方形的对称轴，沿着对称轴折叠，两旁的部分能够完全重合。所以在生活中见到的圆形钟面和课桌面都是轴对称图形。(答案不唯一)",
+    "knowledge_points": [
+      "轴对称的认识及辨认"
+    ],
+    "source": "24-25 二年级下·山西长治·期末"
+  },
+  {
+    "id": "264",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "选择正确的序号填空:①平移 ②旋转\n![](images/26e7beb4d55bb6be9529d57e07d96a3fe826851ff8f7d06564bd8bc9b7d74969.jpg)\n![](images/85171d8326449d1b45d8651ed84af70b35a90edcb12f6ec199e3ea21d92c18bf.jpg)\n![](images/258385f55b288f29426e75cc8492e08cffc7d8d298602a0c39f6a0d65515bde0.jpg)\n直升机旋翼转动( );缆车的前行( );火箭的直线上升( )。",
+    "options": [],
+    "answer": "②;①;①",
+    "solution": "【分析】平移是指在平面内将一个图形上的所有点都按照某个直线方向做相同距离的移动，这样的运动叫做图形的平移运动。故，缆车的前行和火箭的直线上升是平移。旋转是指在平面内将一个图形绕一点按某个方向转动一个角度，这样的运动叫做图形的旋转运动。故，直升机旋翼转动是旋转。\n\n【详解】由分析可知：直升机旋翼转动(②);缆车的前行(①);火箭的直线上升(①)。",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "24-25二年级下·山西长治·期中"
+  },
+  {
+    "id": "265",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "在下列运动现象中，是平移的画△，是旋转的画○。\n![](images/caf237b92660283108004a5634be3e29458dba91aa36387da05f24ab8d8d635d.jpg)\n![](images/bdd56766f3bda015ee827c9025f6395e7f3d4b00d2a9997940d31f5250bd8671.jpg)\n![](images/6b5a3899d966db3f169764219a7c06604b03f16439cb94ed1df92b030d79c890.jpg)\n( )( )( )",
+    "options": [],
+    "answer": "△;△;○",
+    "solution": "【分析】平移是指在平面内，将一个图形上的所有点都按照某个直线方向做相同距离的移动，这样的图形运动叫做图形的平移运动，简称平移。平移后图形的位置改变，形状，大小，方向不变。旋转：在平面内，将一个图形绕一点按某个方向转动一定的角度，这样的运动叫做图形的旋转。旋转后图形的位置和方向改变，形状，大小不变。\n\n【详解】第一个是平移现象;第二个是平移现象;第三个是旋转现象。",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "24-25 二年级下·山东菏泽·期末"
+  },
+  {
+    "id": "266",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "小林从滑梯上往下滑是( )现象;互相咬合的齿轮不停运动是( )现象。(填'平移'或'旋转')",
+    "options": [],
+    "answer": "平移;旋转",
+    "solution": "【分析】平移：平移是指物体在平面内沿着某个方向移动，移动过程中物体的形状，大小和方向都不发生变化。平移可以看作是物体在平面内的'滑动'。例如：推拉抽屉，电梯上下移动，火车在直轨上行驶等。旋转：旋转是指物体绕着一个固定点(旋转中心)转动，转动过程中物体的形状和大小不变，但方向会发生变化。例如：风车转动，钟表的指针转动，旋转木马等。\n\n【详解】由平移，旋转的特点可知：小林从滑梯上往下滑是(平移)现象;互相咬合的齿轮不停运动是(旋转)现象。",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "24-25 二年级下·河南南阳·期末"
+  },
+  {
+    "id": "267",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "下图是小明家的冰箱，小明打开冰箱门时，属于( )现象;他拉出最底下的抽屉时，属于( )现象。(填'平移'或'旋转')![](images/7a52867b5567973487aa154ac28828ed054cddad9de321910ad6bb3170f319da.jpg)",
+    "options": [],
+    "answer": "旋转;平移",
+    "solution": "【分析】平移是指在平面内，将一个图形上的所有点都按照某个直线方向做相同距离的移动，这样的图形运动叫做图形的平移运动，简称平移。平移后图形的位置改变，形状，大小，方向不变。旋转：在平面内，将一个图形绕一点按某个方向转动一定的角度，这样的运动叫做图形的旋转。旋转后图形的位置和方向改变，形状，大小不变。\n\n【详解】下图是小明家的冰箱，小明打开冰箱门时，属于旋转现象;他拉出最底下的抽屉时，属于平移现象。",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "23-24二年级下·福建龙岩·期末"
+  },
+  {
+    "id": "268",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "选填“旋转”或者“平移”。\n风车转动是在做( )运动，推拉抽屉是在做( )运动。",
+    "options": [],
+    "answer": "旋转;平移",
+    "solution": "【分析】平移是物体运动时，物体上任意两点间，从一点到另一点的方向与距离都不变的运动;旋转是物体运动时，每一个点离同一个点(可以在物体外)的距离不变的运动，称为绕这个点的转动，这个点称为物体的转动中心。所以，它并不一定是绕某个轴的;也可以这样说平移是不转动的，旋转自然是转动的，依此根据平移与旋转定义判断即可。\n\n【详解】根据分析可知：风车转动是在做旋转运动，推拉抽屉是在做平移运动。",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "24-25 二年级下·浙江温州·期末"
+  },
+  {
+    "id": "269",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "选填“旋转”或者“平移”。\n“神舟二十号”飞船发射升空是在做( )运动;电风扇工作时是在做( )运动。",
+    "options": [],
+    "answer": "平移;旋转",
+    "solution": "【分析】平移是指在平面内将一个图形上的所有点都按照某个直线方向做相同距离的移动，这样的运动叫做图形的平移运动。旋转是指在平面内将一个图形绕一点按某个方向转动一个角度，这样的运动叫做图形的旋转运动。据此解答。\n\n【详解】根据分析可知：“神舟二十号”飞船发射升空是在做平移运动;电风扇工作时是在做旋转运动。",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "24-25 二年级下·浙江温州·期末"
+  },
+  {
+    "id": "270",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "电梯升降是( )现象，风扇转动是( )现象。(填'平移'或'旋转')",
+    "options": [],
+    "answer": "平移;旋转",
+    "solution": "【分析】在平面内，把一个图形整体沿某条直线方向平行移动一定距离的过程，称为平移，常见的平移现象有滑滑梯，电梯的移动等。在平面内，把一个图形围绕某一固定点按顺时针或逆时针方向转动一定的角度的过程，称为旋转，常见的旋转现象有旋转木马，摩天轮等。由此解答。\n\n【详解】由分析得：电梯升降是平移现象，风扇转动是旋转现象。",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "24-25 二年级下·湖南岳阳·期中"
+  },
+  {
+    "id": "271",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "汽车方向盘的运动是( )现象，运动中的电梯是( )现象。",
+    "options": [],
+    "answer": "旋转;平移",
+    "solution": "【分析】平移是指在平面内，将一个图形上的所有点都按照某个直线方向做相同距离的移动，这样的图形运动叫做图形的平移运动，简称平移。平移后图形的位置改变，形状，大小，方向不变。旋转：在平面内，将一个图形绕一点按某个方向转动一定的角度，这样的运动叫做图形的旋转。旋转后图形的位置和方向改变，形状，大小不变。\n\n【详解】汽车方向盘的运动是旋转现象，运动中的电梯是平移现象。",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "24-25 二年级下·湖北武汉·期末"
+  },
+  {
+    "id": "272",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "小海放学回家，他乘升降电梯上楼是( )现象，推开家门是( )现象。(填'平移'或'旋转')",
+    "options": [],
+    "answer": "平移;旋转",
+    "solution": "【分析】平移：在平面内，将一个图形上的所有点都按照某个方向作相同距离移动的图形运动。平移后图形的位置改变，形状，大小，方向不变。旋转：在平面内，将一个图形绕一点按某个方向转动一定的角度，这样的运动叫做图形的旋转。旋转前后图形的位置和方向改变，形状，大小不变。\n\n【详解】据分析可知：小海放学回家，他乘升降电梯上楼是平移现象，推开家门是旋转现象。",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "24-25 二年级下·福建福州·期末"
+  },
+  {
+    "id": "273",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "2023年5月30日神舟十六号载人飞船成功发射，神舟十六号从地面发射升空是( )现象。我国首款专用武装直升机武直-10上螺旋桨的工作是( )现象。",
+    "options": [],
+    "answer": "平移;旋转",
+    "solution": "【分析】平移是指在平面内将一个图形上的所有点都按照某个直线方向做相同距离的移动，这样的运动叫做图形的平移运动。故，神舟十六号从地面发射升空是平移。旋转是指在平面内将一个图形绕一点按某个方向转动一个角度，这样的运动叫做图形的旋转运动。故，螺旋桨的工作是旋转。\n\n【详解】由题意分析得:2023年5月30日神舟十六号载人飞船成功发射，神舟十六号从地面发射升空是平移现象。我国首款专用武装直升机武直-10上螺旋桨的工作是旋转现象。",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "24-25 二年级下·湖北黄石·期末"
+  },
+  {
+    "id": "274",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "下面是轴对称图形的有[填序号]( )。![](images/image-4.png)",
+    "options": [],
+    "answer": "①③④",
+    "solution": "【分析】轴对称：在平面内，如果一个图形沿一条直线对折，对折后的两部分都能完全重合，这样的图形叫做轴对称图形，这条直线就是其对称轴。据此解答即可。\n\n【详解】对于图形①(正方形)，沿其对边中点连线或对角线对折，直线两侧的部分能够完全重合，所以图形①是轴对称图形;图形②(平行四边形)，无论沿哪条直线对折，直线两侧的部分都不能完全重合，所以图形②不是轴对称图形;图形③(圆)，沿任意一条直径所在的直线对折，直线两侧的部分都能完全重合，所以图形③是轴对称图形;图形④(箭头)，沿中间竖直方向的直线对折，直线两侧的部分能够完全重合，所以图形④是轴对称图形;图形⑤(波浪图)，不存在一条直线使沿其对折后两侧部分完全重合，所以图形⑤不是轴对称图形;图形⑥(笑脸)不是轴对称图形。所以轴对称图形有①③④。",
+    "knowledge_points": [
+      "轴对称的认识及辨认"
+    ],
+    "source": "24-25 二年级下·河南郑州·期末"
+  },
+  {
+    "id": "275",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "传送带的运动属于( ),火车车轮的运动属于( )。(填'平移'或'旋转')",
+    "options": [],
+    "answer": "平移;旋转",
+    "solution": "【分析】在平面内，把一个图形整体沿某条直线方向平行移动一定距离的过程，称为平移，常见的平移现象有滑滑梯，推拉窗户等。在平面内，把一个图形围绕某一固定点按顺时针或逆时针方向转动一定的角度的过程，称为旋转，常见的旋转现象有旋转木马，摩天轮等。由此解答。\n\n【详解】由分析得：传送带的运动属于平移，火车车轮的运动属于旋转。",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "24-25二年级下·浙江嘉兴·期末"
+  },
+  {
+    "id": "276",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "请你写两个是轴对称的汉字:( ),( )。",
+    "options": [],
+    "answer": "中;日",
+    "solution": "【分析】轴对称图形是指沿一条直线对折后，两部分能完全重合的图形。根据这一定义，寻找结构对称的汉字即可。例如:'中'字沿中间的竖线对折后左右重合;'日'字沿中间的竖线或横线对折后均能重合。\n\n【详解】由分析可得：两个轴对称的汉字：中，日。(答案不唯一)",
+    "knowledge_points": [
+      "轴对称的认识及辨认"
+    ],
+    "source": "24-25 二年级下·山东日照·期末"
+  },
+  {
+    "id": "277",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "在括号里填上“平移”或“旋转”。\n方向盘的转动( )，电梯的上下移动( )。",
+    "options": [],
+    "answer": "旋转;平移",
+    "solution": "【分析】在平面内，把一个图形整体沿某条直线方向平行移动一定距离的过程，称为平移。常见的平移现象有滑滑梯、电梯的移动等;在平面内，把一个图形围绕某一固定点按顺时针或逆时针方向转动一定的角度的过程，称为旋转。常见的旋转现象有旋转木马、摩天轮等。由此解答。\n\n【详解】由分析可得：方向盘的转动是方向盘绕中轴转动，属于旋转;电梯的上下移动是电梯沿垂直方向上下移动，属于平移。即：方向盘的转动(旋转)，电梯的上下移动(平移)。",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "24-25二年级下·河南周口·期末"
+  },
+  {
+    "id": "278",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "电风扇转动是( )现象;火车在铁轨上行驶，是( )现象。",
+    "options": [],
+    "answer": "旋转;平移",
+    "solution": "【分析】平移：在平面内，将一个图形上的所有点都按照某个方向作相同距离移动的图形运动。平移后图形的位置改变，形状，大小，方向不变。旋转：在平面内，将一个图形绕一点按某个方向转动一定的角度，这样的运动叫做图形的旋转。旋转前后图形的位置和方向改变，形状，大小不变。\n\n【详解】据分析可知：电风扇转动是旋转现象;火车在铁轨上行驶，是平移现象。",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "22-23 二年级下·新疆乌鲁木齐·期中"
+  },
+  {
+    "id": "279",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "钟表上分针的转动是( )现象，打算盘时算珠的运动是( )现象。",
+    "options": [],
+    "answer": "旋转;平移",
+    "solution": "【分析】平移：在平面内，将一个图形上的所有点都按照某个方向作相同距离移动的图形运动。平移后图形的位置改变，形状，大小，方向不变。旋转：在平面内，将一个图形绕一点按某个方向转动一定的角度，这样的运动叫做图形的旋转。旋转前后图形的位置和方向改变，形状，大小不变。\n\n【详解】据分析可知：钟表上分针的转动是旋转现象，打算盘时算珠的运动是平移现象。",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "24-25二年级下·广西玉林·期末"
+  },
+  {
+    "id": "280",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "图形A通过( )(填'平移'或'旋转')才能与B图形重合。",
+    "options": [],
+    "answer": "旋转",
+    "solution": "【分析】平移是指在平面内，将一个图形上的所有点都按照某个直线方向做相同距离的移动，这样的图形运动叫做图形的平移运动，简称平移。平移后图形的位置改变，形状，大小，方向不变。旋转：在平面内，将一个图形绕一点按某个方向转动一定的角度，这样的运动叫做图形的旋转。旋转后图形的位置和方向改变，形状，大小不变。A和B形状，大小一样，方向，位置不一样。\n\n【详解】图形A通过旋转才能与B图形重合。",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "23-24 二年级下·河南许昌·期末"
+  },
+  {
+    "id": "281",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "下面字母可以看作是轴对称图形的有( )。\nH P M S T F J O",
+    "options": [],
+    "answer": "H、M、T、O",
+    "solution": "【分析】如果一个平面图形沿着一条直线对折后，直线两旁的部分能够互相重合，那么这个图形叫做轴对称图形，这条直线是图形的对称轴，据此解答。\n\n【详解】由分析可知，是轴对称图形的有H、M、T、O。",
+    "knowledge_points": [
+      "轴对称的认识及辨认"
+    ],
+    "source": "23-24 二年级下·湖北荆州·期末"
+  },
+  {
+    "id": "282",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "滑滑梯是( )现象，爸爸用螺丝刀拧螺丝，螺丝刀的运动是( )现象。",
+    "options": [],
+    "answer": "平移;旋转",
+    "solution": "【分析】据题意，滑滑梯是从上面滑到下面，位置改变了，但是方向没有变，属于平移;拧螺丝，使用螺丝刀一圈一圈的转圈，方向改变了，属于旋转。\n\n【详解】据分析可得：滑滑梯是平移现象，爸爸用螺丝刀拧螺丝，螺丝刀的运动是旋转现象。",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "24-25 二年级下·山东日照·期末"
+  },
+  {
+    "id": "283",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "小丽把一张正方形的纸对折，剪出的❤是( )图形;亮亮家的电风扇在转动时，叶片在做( )运动;明明家的推拉窗是利用( )的方法开关的。(填'轴对称','平移'或'旋转')",
+    "options": [],
+    "answer": "轴对称;旋转;平移",
+    "solution": "【分析】根据题意，平移是指在平面内将一个图形上的所有点都按照某个直线方向做相同距离的移动，这样的运动叫做图形的平移运动。推拉窗是平移现象。旋转是指在平面内将一个图形绕一点按某个方向转动一个角度，这样的运动叫做图形的旋转运动。风扇的扇叶运动是旋转现象。轴对称，把图形按照一条直线对折，直线两边的部分能够完全重合，这样的图形叫做轴对称图形，这条直线就是图形的对称轴。对折之后的剪纸，打开后是轴对称图形。据此解答。\n\n【详解】根据分析：小丽把一张正方形的纸对折，剪出的❤是轴对称图形;亮亮家的电风扇在转动时，叶片在做旋转运动;明明家的推拉窗是利用平移的方法开关的。",
+    "knowledge_points": [
+      "轴对称的认识及辨认",
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "23-24二年级下·湖南长沙·期末"
+  },
+  {
+    "id": "284",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "钟面上指针的转动属于( )现象，而在笔直轨道上行驶的火车车身的运动是( )现象。(请填'平移'或者'旋转')",
+    "options": [],
+    "answer": "旋转;平移",
+    "solution": "【分析】在平面内，把一个图形整体沿某条直线方向平行移动一定距离的过程，称为平移，常见的平移现象有滑滑梯，推拉窗户等。在平面内，把一个图形围绕某一固定点按顺时针或逆时针方向转动一定的角度的过程，称为旋转，常见的旋转现象有旋转木马，摩天轮等。由此解答。\n\n【详解】由分析得：钟面上指针的转动属于旋转现象，而在笔直轨道上行驶的火车车身的运动是平移现象。",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "24-25二年级下·黑龙江佳木斯·期末"
+  },
+  {
+    "id": "285",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "龙舟在笔直的赛道上前进时，这一现象属于( )现象。(括号内填'平移'或'旋转')",
+    "options": [],
+    "answer": "平移",
+    "solution": "【分析】平移：在平面内，将一个图形上的所有点都按照某个方向作相同距离移动的图形运动。平移后图形的位置改变，形状，大小，方向不变。据此解答即可。\n\n【详解】据分析可知：龙舟在笔直的赛道上前进时，这一现象属于平移现象。",
+    "knowledge_points": [
+      "平移与平移现象"
+    ],
+    "source": "23-24二年级下·山西晋中·期末"
+  },
+  {
+    "id": "286",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "拧开矿泉水瓶盖所做的运动是( )现象。",
+    "options": [],
+    "answer": "旋转",
+    "solution": "【分析】旋转：在平面内，将一个图形绕一点按某个方向转动一定的角度，这样的运动叫做图形的旋转。旋转前后图形的位置和方向改变，形状，大小不变。据此解答即可。\n\n【详解】据分析可知：拧开矿泉水瓶盖所做的运动是旋转现象。",
+    "knowledge_points": [
+      "旋转与旋转现象"
+    ],
+    "source": "23-24二年级下·湖南岳阳·期末"
+  },
+  {
+    "id": "287",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "左边图形不是轴对称图形。( )\n![](images/604127083b341435c1758994b3b148a474f8e2d6806437fdabea6d996c8d7a0c.jpg)",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】沿一条直线对折后左右两边能完全重合的图形叫轴对称图形，以此判断即可。\n\n【详解】此图形是轴对称图形。故答案为: ×",
+    "knowledge_points": [
+      "轴对称的认识及辨认"
+    ],
+    "source": "24-25三年级下·重庆忠县·期末"
+  },
+  {
+    "id": "288",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "判断题",
+    "difficulty": 0.65,
+    "question": "春夏秋冬，这是自然界的重复现象。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【详解】春夏秋冬是地球公转引起的周期性季节更替现象，每年按照固定顺序循环出现，属于自然界的重复现象。根据自然规律，四季(春，夏，秋，冬)每年循环一次，周而复始。原题说法正确。故答案为:√",
+    "knowledge_points": [
+      "图形的运动规律"
+    ],
+    "source": "24-25 二年级下·广东揭阳·期末"
+  },
+  {
+    "id": "289",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "汉字“里”“一”“网”“众”都可以看作轴对称图形。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】依据轴对称图形的概念，在平面内，如果沿着一条直线折叠，直线两旁的部分能够完全重合，这样的图形叫轴对称图形，这条直线叫对称轴。里：若沿竖中线对折，左右两边完全重合，故是轴对称图形;一：沿竖中线对折后左右两边完全重合，故是轴对称图形;网：沿竖中线对折，左右笔画不能完全重合，故不是轴对称图形;众：沿竖中线对折后，左右两边笔画不能完全重合，故不是轴对称图形。据此可解。\n\n【详解】由分析可得：“里”“一”可以看作轴对称图形，“网”“众”不可以。原题说法错误。故答案为: ×",
+    "knowledge_points": [
+      "轴对称的认识及辨认"
+    ],
+    "source": "24-25 二年级下·陕西延安·期末"
+  },
+  {
+    "id": "290",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "推抽屉是平移现象，滚铁环是旋转现象。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】根据平移和旋转的定义，平移是物体沿直线运动，各部分运动方向和距离相同;旋转是物体绕某一点或轴做圆周运动。推抽屉是直线运动，属于平移;滚铁环时铁环绕中心轴转动，属于旋转。\n\n【详解】推抽屉时，抽屉整体沿直线运动，各部分运动方向和距离一致，属于平移现象。滚铁环时，铁环绕其中心轴做圆周运动，属于旋转现象;因此原题说法正确。故答案为:√",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "24-25 二年级下·甘肃天水·期末"
+  },
+  {
+    "id": "291",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "从算盘上拨算珠属于旋转现象，风扇转动属于平移现象。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】平移是指物体在平面内沿着某个方向移动，移动过程中物体的形状，大小和方向都不发生变化。平移可以看作是物体在平面内的'滑动'。旋转：旋转是指物体绕着一个固定点(旋转中心)转动，转动过程中物体的形状和大小不变，但方向会发生变化。\n\n【详解】由分析可得：算盘拨算珠时，算珠在平面内沿着某个方向移动，移动过程中物体的形状，大小和方向都不发生变化属于平移现象;风扇转动时，叶片绕中心轴做圆周运动，属于旋转现象;因此原题中说法错误。故答案为: ×",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "24-25 二年级下·云南红河·期末"
+  },
+  {
+    "id": "292",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "图形在平移运动后，形状和大小都不变。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】在平面内，把一个图形整体沿某条直线方向平行移动一定距离的过程，称为平移;平移不改变图形的形状，大小以及方向，只改变图形的位置。\n\n【详解】由分析可得：图形在平移运动后，形状和大小都不变，原题说法正确。故答案为:√",
+    "knowledge_points": [
+      "平移与平移现象"
+    ],
+    "source": "24-25 二年级下·贵州铜仁·期末"
+  },
+  {
+    "id": "293",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "'田''中''虫'三个汉字都是轴对称图形。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】一个图形沿一条直线对折，直线两旁的图形完全重合，这样的图形叫做轴对称图形，折痕所在的直线是对称轴，由此解答。\n\n【详解】由分析得:'田''中'有对称轴，是轴对称图形;'虫'没有对称轴，不是轴对称图形。原题说法错误。故答案为: ×",
+    "knowledge_points": [
+      "轴对称的认识及辨认"
+    ],
+    "source": "24-25 二年级下·湖北黄冈·期末"
+  },
+  {
+    "id": "294",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "判断题",
+    "difficulty": 0.65,
+    "question": "天气炎热，奇奇打开风扇，风扇叶片的运动是旋转。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】根据旋转的定义，物体围绕一个固定点或轴做圆周运动称为旋转。风扇叶片工作时是围绕中心轴转动，符合旋转的特征。\n\n【详解】风扇叶片在转动时，每个叶片都围绕中心轴做圆周运动，因此其运动属于旋转现象。故答案为:√",
+    "knowledge_points": [
+      "旋转与旋转现象"
+    ],
+    "source": "24-25 二年级下·陕西渭南·期末"
+  },
+  {
+    "id": "295",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "车轮的转动是旋转现象，抽屉的推拉是平移现象。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】平移是指在平面内将一个图形上的所有点都按照某个直线方向做相同距离的移动，这样的运动叫做图形的平移运动。旋转是指在平面内将一个图形绕一点按某个方向转动一个角度，这样的运动叫做图形的旋转运动。\n\n【详解】车轮转动时绕轴做圆周运动，属于旋转现象;抽屉推拉时沿直线移动，属于平移现象。因此题目描述正确。故答案为:√",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "24-25二年级下·湖南株洲·期末"
+  },
+  {
+    "id": "296",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "两个图形只要形状，方向，大小一样，就能通过平移相互重合。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】平移：在平面内，将一个图形上的所有点都按照某个方向作相同距离移动的图形运动。平移后图形的位置改变，形状，大小，方向不变。据此结合题干要求进行解答即可。\n\n【详解】据分析可知：两个图形只要形状，方向，大小一样，就能通过平移相互重合。原题说法正确。故答案为:√",
+    "knowledge_points": [
+      "平移与平移现象"
+    ],
+    "source": "24-25二年级下·广东汕尾·期末"
+  },
+  {
+    "id": "297",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "轿车行驶时，轿车本身的运动是旋转。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】平移是指在平面内，将一个图形上的所有点都按照某个直线方向做相同距离的移动，这样的图形运动叫做图形的平移运动，简称平移。平移后图形的位置改变，形状，大小，方向不变。旋转：在平面内，将一个图形绕一点按某个方向转动一定的角度，这样的运动叫做图形的旋转。旋转后图形的位置和方向改变，形状，大小不变。\n\n【详解】轿车行驶时，其整体沿直线方向移动，所有部分运动方向一致，属于平移现象。因此，轿车本身的运动不是旋转。原题说法错误。故答案为: ×",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "24-25二年级下·山东济南·期末"
+  },
+  {
+    "id": "298",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "是一个轴对称图形。( )![](images/e7eada62070dcc9da81571c2f94bc01063b6dd8cf99b75d04baa6ac70f979376.jpg)",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】如果沿某条直线对折，对折的两部分是完全重合的，这样的图形为轴对称图形。这条直线叫做这个图形的对称轴。判断一个图案是否是轴对称图形的关键是看在这个图形中能否找到一条直线，使图形沿着这条直线对折后能够完全重合。\n\n【详解】原图不是一个轴对称图形。原题说法错误。故答案为: ×",
+    "knowledge_points": [
+      "轴对称的认识及辨认"
+    ],
+    "source": "24-25 二年级下·山东日照·期中"
+  },
+  {
+    "id": "299",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "拉抽屉是平移现象，直升机螺旋桨的运动属于旋转现象。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】在平面内，把一个图形整体沿某条直线方向平行移动一定距离的过程，称为平移。在平面内，把一个图形围绕某一固定点按顺时针或逆时针方向转动一定的角度的过程，称为旋转。由此解答。\n\n【详解】拉抽屉时，抽屉沿轨道直线移动，是平移现象;直升机螺旋桨围绕中心轴转动，属于旋转现象。原题说法正确。故答案为:√",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "24-25二年级下·河南周口·期末"
+  },
+  {
+    "id": "300",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "平移和旋转都不改变物体的大小。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】平移是沿直线移动，旋转是绕某点转动。这两种运动都不会改变物体的形状和大小，只会改变其位置或方向。原题说法正确。故答案为:√\n\n【详解】平移是将物体沿直线移动一定距离，旋转是将物体绕某一点转动一定角度。在平移和旋转过程中，物体的形状、大小均保持不变，仅位置或方向发生改变。",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "24-25 二年级下·山东济宁·期末"
+  },
+  {
+    "id": "301",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面的图案中，( )不是轴对称图形。",
+    "options": [
+      "A. ![](images/3234824f5d7ede1e4473ef8fa6d56bf08af1c5e6e97a8cd0bdd088ab26043293.jpg)",
+      "B. ![](images/78f6ba0fbb4e53e99d01f9c7820092023839da959bd3301ae57f43305a2c0149.jpg)",
+      "C. ![](images/4a6c4c938887cc455bb83053e519ddd1bbb7360bcf8958b3b77b63735e7d9ebe.jpg)",
+      "D. ![](images/ae2a66cb3d5c7c605749b53ca20028e24e92a8d844b0788ac809454c26ee990e.jpg)"
+    ],
+    "answer": "C",
+    "solution": "【分析】如果一个图形沿着一条直线对折后，直线两旁的部分能够互相重合，那么这个图形叫做轴对称图形，这条直线是图形的对称轴，由此解答。\n\n【详解】A. 有对称轴，是轴对称图形;B. 有对称轴，是轴对称图形;C. 没有对称轴，不是轴对称图形;D. 有对称轴，是轴对称图形。故答案为:C",
+    "knowledge_points": [
+      "轴对称的认识及辨认"
+    ],
+    "source": "24-25 二年级下·浙江宁波·期中"
+  },
+  {
+    "id": "302",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面给出的图形中，( )属于轴对称图形。\n![](images/e88c9172a2710fe787f023ada09ddf3a.png)",
+    "options": [
+      "A. ①②",
+      "B. ③④",
+      "C. ②③",
+      "D. ①④"
+    ],
+    "answer": "D",
+    "solution": "【分析】如果一个图形沿着一条直线对折后，直线两旁的部分能够互相重合，则这个图形叫做轴对称图形，这条直线是图形的对称轴，由此解答。\n\n【详解】①是轴对称图形;②不是轴对称图形;③不是轴对称图形;④是轴对称图形。则①④属于轴对称图形。故答案为:D",
+    "knowledge_points": [
+      "轴对称的认识及辨认"
+    ],
+    "source": "24-25 二年级下·黑龙江佳木斯·期中"
+  },
+  {
+    "id": "303",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "左图的会徽通过平移可以与图( )重合。\n![](images/44fa39159ac126ff5e2c5c8c4dc22d4e622ca87f88cb10af8b596cbf26c2de8e.jpg)",
+    "options": [
+      "A. ![](images/8f923d3e8c42de02186d1fd8a165e0dbc9bc6f8c0efaebbed71671609c8f75e7.jpg)",
+      "B. ![](images/5319e46c24fc276eb517bc7201e9bb65bb996f6fd369b7c4217e04f2cbd5cb65.jpg)",
+      "C. ![](images/9e2e602327f4a4a2587a54e577ba1f0c7ee2c5c1b0324dc71c1c1195dd4544e0.jpg)"
+    ],
+    "answer": "C",
+    "solution": "【分析】在平面内，把一个图形整体沿某条直线方向平行移动一定距离的过程，称为平移。平移后的图形大小、形状、方向都不变，只有位置发生变化，由此解答。\n\n【详解】A. 方向发生变化，不符合题意;B. 方向发生变化，不符合题意;C. 大小、形状、方向都没有变化，符合题意。则左图的会徽通过平移可以与图C重合。故答案为:C",
+    "knowledge_points": [
+      "平移与平移现象"
+    ],
+    "source": "24-25二年级下·青海果洛·期中"
+  },
+  {
+    "id": "304",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "将一张正方形纸先左右对折，再上下对折，然后剪去一个圆，展开后的图形是( )。\n![](images/0dfc89bf9ebd13521eebf193a65e039f1eb8306eb5786cbb0267bd2dd12d0418.jpg)",
+    "options": [
+      "A. ![](images/8e15f5c530d23c2930acb01a0dd162adc01305181eca3a6bf0deb62d39b5177d.jpg)",
+      "B. ![](images/abf36c14ce97c9d959607d981e4017e2139b40225976fbc6ea97b5966bc91e6f.jpg)",
+      "C. ![](images/6d5b8b165127f1206377847e37bccaa6ec7e6f3685d7b8ea015c71f46caf13db.jpg)"
+    ],
+    "answer": "B",
+    "solution": "【分析】根据题意，将正方形纸左右对折后再上下对折，分成了同样大小的四个小正方形。在对折后的纸中间剪去一个圆，展开后每一个小正方形的中间都有一个圆，由此解答。\n\n【详解】由分析可知：展开后的图形是B。故答案为:B",
+    "knowledge_points": [
+      "轴对称的剪纸问题"
+    ],
+    "source": "24-25 二年级下·湖南怀化·期中"
+  },
+  {
+    "id": "305",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面属于旋转现象的是( )。",
+    "options": [
+      "A. 摩天轮转动",
+      "B. 推拉抽屉",
+      "C. 电梯上下移动"
+    ],
+    "answer": "A",
+    "solution": "【分析】平移是指在平面内将一个图形上的所有点都按照某个直线方向做相同距离的移动，这样的运动叫做图形的平移运动。旋转是指在平面内将一个图形绕一点按某个方向转动一个角度，这样的运动叫做图形的旋转运动。据此解答。\n\n【详解】A. 摩天轮转动属于旋转;B. 推拉抽屉属于平移;C. 电梯上下移动属于平移。故答案为:A",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "24-25 二年级下·贵州六盘水·期中"
+  },
+  {
+    "id": "306",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面( )不是轴对称图形。",
+    "options": [
+      "A. ![](images/505919cc27aabb3dfe80e9d1cc7edf14be09256e55dc8ffdb209a617d6486d58.jpg)",
+      "B. ![](images/96ed9532f686e27db99bca6ceeb14c2d3d4017c9cc526d9ddabd9e8c29bdcf83.jpg)",
+      "C. ![](images/54b61bcb914652d2d01858bca4b57d02d1a37a208e065b4e915a3acaf72d3ba1.jpg)"
+    ],
+    "answer": "B",
+    "solution": "【分析】如果一个图形沿着一条虚线对折，两侧的图形完全重合，这个图形就叫做轴对称图形。逐项分析各个选项中的图形，找出不是轴对称图形的即可解答。\n\n【详解】A. 沿着虚线对折后，两侧的图形能完全重合，是轴对称图形;B. 沿着虚线对折后，中间的图形不能重合，不是轴对称图形;C. 沿着虚线对折后，两侧的图形能完全重合，是轴对称图形。故答案为:B",
+    "knowledge_points": [
+      "轴对称的认识及辨认"
+    ],
+    "source": "24-25 二年级下·湖北省直辖县级单位·期中"
+  },
+  {
+    "id": "307",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面( )图形通过平移可以和 ![](images/01ad5eca0e3ecc57ca0fe327ce34a175635cfe97535ad8638386cce586b8aca1.jpg) 重合。\n![](images/f277bc5c50a03e35ece197f7c489485b5c6763dcc3b45f0f126ebf8879543e62.jpg)",
+    "options": [
+      "A. A",
+      "B. B",
+      "C. C"
+    ],
+    "answer": "C",
+    "solution": "【分析】平移是指在平面内，将一个图形上的所有点都按照某个直线方向做相同距离的移动，这样的图形运动叫做图形的平移运动，简称平移。平移后图形的位置改变，形状、大小、方向不变。\n\n【详解】图形C通过平移可以和原图重合。故答案为:C",
+    "knowledge_points": [
+      "平移与平移现象"
+    ],
+    "source": "24-25 二年级下·山东临沂·期中"
+  },
+  {
+    "id": "308",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面图形中，是轴对称图形的是( )。",
+    "options": [
+      "A. ![](images/c8ec1dde518087110c89eb832501289f3bdc146ec1668002b7121c4bf39d00f9.jpg)",
+      "B. ![](images/da8d64868de4843e4e9a2fc8f9d4c5cec228626148f141e78c19d87bcef01da4.jpg)",
+      "C. ![](images/5f52e37054b825595f1edb1a76bf9ee3375e335dc5ef4f2cc10c6ac04c355d7a.jpg)"
+    ],
+    "answer": "B",
+    "solution": "【分析】一个图形沿着一条直线对折后，直线两旁的部分能够完全重合，这样的图形就叫做轴对称图形，据此解答。\n\n【详解】A. 沿着一条直线对折后，直线两旁的部分不能完全重合，所以它不是轴对称图形;B. 沿着这条直线对折后，直线两旁的部分能够完全重合，所以它是轴对称图形;C. 沿着一条直线对折后，直线两旁的部分不能完全重合，所以它不是轴对称图形。故答案为:B",
+    "knowledge_points": [
+      "轴对称的认识及辨认"
+    ],
+    "source": "24-25 二年级下·河北唐山·期中"
+  },
+  {
+    "id": "309",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面各图案中，( )不是轴对称图形。",
+    "options": [
+      "A. ![](images/0aabb048f4b885fbd3d5bddff3c8894d9bd649dd8f6fd7611aafc77fbf00d3b0.jpg)",
+      "B. ![](images/4892c23da56a175de3f81a5bb8e46d1bc90afa5ab062e705a33ccf486639fab2.jpg)",
+      "C. ![](images/3fb02135259b688c4dd067946fc84187a8849d390ccaff9054257b97a4b8a791.jpg)"
+    ],
+    "answer": "C",
+    "solution": "【分析】如果一个平面图形沿着一条直线对折后，直线两旁的部分能够互相重合，那么这个图形叫做轴对称图形，这条直线是图形的对称轴，据此解答。\n\n【详解】A. 有对称轴，是轴对称图形;B. 有对称轴，是轴对称图形;C. 没有对称轴，不是轴对称图形。故答案为:C",
+    "knowledge_points": [
+      "轴对称的认识及辨认"
+    ],
+    "source": "24-25 二年级下·浙江温州·期中"
+  },
+  {
+    "id": "310",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下列字母或图形中，表示的不是轴对称图形的是( )。",
+    "options": [
+      "A. ![](images/a8968f5dbd750e1ca392d2084ac5d1599129e000425eed610e73e0c5f92971fe.jpg)",
+      "B. ![](images/ff2598c6934faf2365b72d20c8c65d5a362dbdae95a846b3ac83799abefb780c.jpg)",
+      "C. ![](images/5a39eae41967a706aaa23cb4282182762d22e0f588a43473137ae064da8729a3.jpg)",
+      "D. ![](images/46fca96ac21f4ddacfd2bd034cb6d5cf721eda8e382a091fd74bb4e3bb6eb5a2.jpg)"
+    ],
+    "answer": "A",
+    "solution": "【分析】在平面内，如果一个图形沿一条直线折叠，直线两旁的部分能够完全重合，这样的图形就叫做轴对称图形，这条直线叫做对称轴。据此解答即可。\n\n【详解】A. 不是轴对称图形;B. 是轴对称图形;C. 是轴对称图形;D. 是轴对称图形。故答案为:A",
+    "knowledge_points": [
+      "轴对称的认识及辨认"
+    ],
+    "source": "24-25 二年级下·山东菏泽·期中"
+  },
+  {
+    "id": "311",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面现象属于旋转的是( )。",
+    "options": [
+      "A. 推拉抽屉",
+      "B. 电梯上升",
+      "C. 风车转动",
+      "D. 缆车移动"
+    ],
+    "answer": "C",
+    "solution": "【分析】平移是指在平面内将一个图形上的所有点都按照某个直线方向做相同距离的移动，这样的运动叫做图形的平移运动。旋转是指在平面内将一个图形绕一点按某个方向转动一个角度，这样的运动叫做图形的旋转运动。据此解答。\n\n【详解】A. 推拉抽屉属于平移;B. 电梯上升属于平移;C. 风车转动属于旋转;D. 缆车移动属于平移。故答案为:C",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "24-25二年级下·湖南长沙·期中"
+  },
+  {
+    "id": "312",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "左图是三角形经过( )得到的。\n![](images/db659b19654b607e85cb36f1a2f7c74d99417a5ee4957f00a39735ae2d462c48.jpg)",
+    "options": [
+      "A. 平移",
+      "B. 旋转",
+      "C. 既平移又旋转"
+    ],
+    "answer": "B",
+    "solution": "【分析】平移是指在平面内，将一个图形上的所有点都按照某个直线方向做相同距离的移动，这样的图形运动叫做图形的平移运动，简称平移。平移后图形的位置改变，形状、大小、方向不变。旋转：在平面内，将一个图形绕一点按某个方向转动一定的角度，这样的运动叫做图形的旋转。旋转后图形的位置和方向改变，形状、大小不变。\n\n【详解】左图是三角形经过旋转得到的。故答案为:B",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "24-25 二年级下·湖北武汉·期中"
+  },
+  {
+    "id": "313",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面图形中有( )个轴对称图形。\n![](images/29d3285863900f62c1ec321728b39478d44b1e065404047c440936a783e286d6.jpg)\n![](images/9348d3663ab7831e96e6d3d015cdc83b9d2558a656c16b72af2fd0ce26243786.jpg)\n![](images/6f36baaa3c0d61eb089637b2a37e0952b97e340cfda160db560c26580d4e7cbd.jpg)\n![](images/2ee478bdac711e5477e8db97bc075764dfe5a62965a833edac956c7979a18096.jpg)",
+    "options": [
+      "A. 2",
+      "B. 3",
+      "C. 4"
+    ],
+    "answer": "B",
+    "solution": "【分析】在平面内，如果一个图形沿一条直线折叠，直线两旁的部分能够完全重合，这样的图形就叫做轴对称图形，这条直线叫做对称轴。\n\n【详解】由题意分析得：有3个轴对称图形。故答案为:B",
+    "knowledge_points": [
+      "轴对称的认识及辨认"
+    ],
+    "source": "24-25 二年级下·广东东莞·期中"
+  },
+  {
+    "id": "314",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面现象中不是旋转的是( )。",
+    "options": [
+      "A. ![](images/257431fe92c4347d5736c543787ff591b82f94529f01602f6eeae78954b1152f.jpg)",
+      "B. ![](images/b36e5219f707acf6de102933ef5dea808094059c9f295d9965e8110435d6f00b.jpg)",
+      "C. ![](images/846e089bcea77e373bf563d4f03d1b81e421b445a53d932c70b11fcce4fa3a7f.jpg)"
+    ],
+    "answer": "C",
+    "solution": "【分析】平移是指在平面内将一个图形上的所有点都按照某个直线方向做相同距离的移动，这样的运动叫做图形的平移运动。旋转是指在平面内将一个图形绕一点按某个方向转动一个角度，这样的运动叫做图形的旋转运动。据此解答。\n\n【详解】A. 是旋转现象;B. 是旋转现象;C. 是平移现象，不是旋转现象。故答案为:C",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "24-25二年级下·山东济宁·期中"
+  },
+  {
+    "id": "315",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面图形中通过平移可以和原图重合的是( )。",
+    "options": [
+      "A. ![](images/05286ada8246c4b0c3ae9a1f0b287fbe65cd561d52000990eeed9f9fb7cf4439.jpg)",
+      "B. ![](images/792ae4df84418343bfc0ecfc4ae23d36cf3a19406e14664c82c4dff9a2928cb0.jpg)",
+      "C. ![](images/f234af36f534e4ee9b7b64c5346b5358b2641355820a7971362ad247726ed5af.jpg)"
+    ],
+    "answer": "C",
+    "solution": "【分析】平移：在平面内，将一个图形上的所有点都按照某个方向作相同距离移动的图形运动。平移后图形的位置改变，形状、大小、方向不变。旋转：在平面内，将一个图形绕一点按某个方向转动一定的角度，这样的运动叫做图形的旋转。旋转前后图形的位置和方向改变，形状、大小不变。\n\n【详解】A. 通过旋转得到;B. 通过旋转得到;C. 通过平移得到。故答案为:C",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "19-20 二年级下·全国·期中"
+  },
+  {
+    "id": "316",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面( )不是轴对称图形。",
+    "options": [
+      "A. ![](images/c491fcf3163be71111890617aff120cd3cd997e88784a9cc9bfd5b7035c0ee18.jpg)",
+      "B. ![](images/b6b00903ddaf30f7821c1270f2a78630b7c716c017ccba35b8f54cf06adf226d.jpg)",
+      "C. ![](images/1ee37513d9b55f83dba36a711d286174ec3079feedea54757ae655f045c2d593.jpg)",
+      "D. ![](images/246349ea82d699ce3267c5788ef102b6113ad4ba9b127d5cb54f28f72bd7f7fd.jpg)"
+    ],
+    "answer": "D",
+    "solution": "【分析】如果一个平面图形沿着一条直线对折后，直线两旁的部分能够互相重合，那么这个图形叫做轴对称图形，这条直线是图形的对称轴，据此解答。\n\n【详解】A. 有对称轴，是轴对称图形;B. 有对称轴，是轴对称图形;C. 有对称轴，是轴对称图形;D. 没有对称轴，不是轴对称图形。故答案为:D",
+    "knowledge_points": [
+      "轴对称的认识及辨认"
+    ],
+    "source": "24-25二年级下·广东广州·期中"
+  },
+  {
+    "id": "317",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下列图形不是轴对称图形的是( )。",
+    "options": [
+      "A. ![](images/fe530a2214caf9cb972e535f20099118106e598f9f9485aa6409336ef0bc320a.jpg)",
+      "B. ![](images/680357d3f343ae79e40735e079ca5b6d4fa931e8e80db1b5bfc00b796a733712.jpg)",
+      "C. ![](images/057c04a0a9be16a61666bb9864c00314c2a362970eacaeedc58f9ff409134d87.jpg)"
+    ],
+    "answer": "A",
+    "solution": "【分析】平面内，一个图形沿一条直线对折，直线两侧的部分能够完全重合的图形叫做轴对称图形，逐项分析各个选项，找出不是轴对称图形的选项即可。\n\n【详解】A. 图形(小船)只有一面船帆，无论怎么对折，两侧都不能完全重合，不是轴对称图形;B. 图形(面具)沿中线对折，两侧能完全重合，是轴对称图形;C. 图形(叶子)通常以主叶脉对折，两侧能完全重合，是轴对称图形。故答案为:A",
+    "knowledge_points": [
+      "轴对称的认识及辨认"
+    ],
+    "source": "24-25二年级下·江西赣州·期中"
+  },
+  {
+    "id": "318",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "第( )条鱼是由原图通过平移拼成的。\n![](images/8ed2d21a1c6d81f95dbc274b544d6bd9cdca6666f628646c24fe5e6869c3a7bc.jpg)",
+    "options": [
+      "A. ![](images/eb050d85402bde0d5c3c649972a3324faaff1b1ae20de3ed239bea65435ff249.jpg)",
+      "B. ![](images/56c8911867352bba6843df64f44c3163d6dab57ad583b46a5c5df29d1aa604cb.jpg)",
+      "C. ![](images/a6bce6fa9d47a5f7039c599e68d6ded2ba345aec5b95abcc5c272343a6de2933.jpg)"
+    ],
+    "answer": "A",
+    "solution": "【分析】图形平移的特征是位置发生改变，但图形本身的形状、大小和方向不发生改变。逐项分析各个选项，找出正确答案即可。\n\n【详解】A. 小鱼图与给出的图形相比，每个图形的形状、大小和方向都没有发生变化，只是位置发生了改变，可以通过平移得到，所以这幅图符合题意;B. 小鱼图与给出的图形相比，图形方向发生了变化，不符合题意;C. 小鱼图与给出的图形相比，图形方向发生了变化，不符合题意。故答案为:A",
+    "knowledge_points": [
+      "平移与平移现象"
+    ],
+    "source": "24-25 二年级下·广东东莞·期中"
+  },
+  {
+    "id": "319",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "要想得到下面的图案，应该将正方形的纸按方式( )剪掉多余的部分。\n![](images/1a97c6633415ad62100691c3e8acd2c05b19b278468488c987f8a0b7d5d5d8f0.jpg)",
+    "options": [
+      "A. ![](images/9c48c4fdc93404121fc116e51e49c7f33d2dae176f4d3c8495102811a37ae80d.jpg)",
+      "B. ![](images/763efc5e04d5f424705e662d62868624a04431e9d5cad9ed2999bd50b6b290e7.jpg)",
+      "C. ![](images/8f768b88bdbe478873de658b1594795765b5226cb5b4df6416ac88b5961d91fa.jpg)"
+    ],
+    "answer": "A",
+    "solution": "【分析】在平面内，如果一个图形沿一条直线折叠，直线两旁的部分能够完全重合，这样的图形就叫做轴对称图形，这条直线叫做对称轴。先找出要得到的图案的对称轴，再找出图案右半部分与正方形纸上的剪痕一致的，就是要找的正确答案。\n\n【详解】由分析可知：应该将正方形的纸按方式A剪掉多余的部分。故答案为:A",
+    "knowledge_points": [
+      "轴对称的剪纸问题"
+    ],
+    "source": "24-25二年级下·山东济宁·期中"
+  },
+  {
+    "id": "320",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下图的哪两个图案通过平移不能得到。( )\n![](images/image-5.png)",
+    "options": [
+      "A. ①和⑤",
+      "B. ②和⑥",
+      "C. ③和④"
+    ],
+    "answer": "A",
+    "solution": "【分析】在平面内，把一个图形整体沿某条直线方向平行移动一定距离的过程，称为平移。平移前后图形的形状、大小和自身方向都不变;逐项分析各个选项，找出正确答案即可。\n\n【详解】A. ①和⑤这两个图形方向发生了改变，不能通过平移得到;B. ②和⑥这两个图形平移前后形状、大小和自身方向都不变，可以通过平移得到;C. ③和④这两个图形平移前后形状、大小和自身方向都不变，可以通过平移得到。故答案为:A",
+    "knowledge_points": [
+      "平移与平移现象"
+    ],
+    "source": "24-25 二年级下·山东济南·期末"
+  },
+  {
+    "id": "321",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面图形不是轴对称图形的是( )。",
+    "options": [
+      "A. ![](images/2ad0ed4f50050720829871d073ee926c6ff8acd0c693ccf75ccd1855d0d6374e.jpg)",
+      "B. ![](images/7ae5c655a7bc5caf60fe5f589b2aacd09bb118b9179f1059f6caed31af3eeae3.jpg)",
+      "C. ![](images/1d7f010d4ca2a9a9c6f7222dfa0937b6182d92fa13de33d5400e56342e3aab30.jpg)"
+    ],
+    "answer": "B",
+    "solution": "【分析】一个图形沿着某一条直线对折，如果直线两旁的部分能够互相重合，那么这个图形是轴对称图形，这条线是图形的对称轴，由此找出图形的对称轴即可解答。\n\n【详解】A. 有对称轴，是轴对称图形;B. 没有对称轴，不是轴对称图形;C. 有对称轴，是轴对称图形。则不是轴对称图形的是B。故答案为:B",
+    "knowledge_points": [
+      "轴对称的认识及辨认"
+    ],
+    "source": "24-25二年级下·河南南阳·期中"
+  },
+  {
+    "id": "322",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下列交通标识中，是轴对称图形的是( )。",
+    "options": [
+      "A. ![](images/a6003e4b222348d71498c907fd80716988d6b44109337214bdb1610e9dbacf78.jpg)",
+      "B. ![](images/4f921c5b00bd6c50e50fec64c9635b767568433f59a8fe212d216ed4170580cb.jpg)",
+      "C. ![](images/4494416376a7520fd4ce5485d3024d2f3717bfef1909a1368702e198c3a406a8.jpg)",
+      "D. ![](images/b82a771e0d7699d81a2dade8b30489bd0d5c12ae51065cfa098b8056b394c28f.jpg)"
+    ],
+    "answer": "A",
+    "solution": "【分析】在一个平面内，一个图形沿一条直线折叠，直线两旁的部分能够完全重合的图形叫做轴对称图形。据此作答。\n\n【详解】A. 从中间对折可以重叠，是轴对称图形;B. 无法对折重叠，不是轴对称图形;C. 无法对折重叠，不是轴对称图形;D. 无法对折重叠，不是轴对称图形。故答案为:A",
+    "knowledge_points": [
+      "轴对称的认识及辨认"
+    ],
+    "source": "2024·重庆云阳·小升初真题"
+  },
+  {
+    "id": "323",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下边这只松鼠在水中的倒影是( )。\n![](images/1052c278652d6346af475e08bd4c3c727021be16f196393ce9887512661c7e7e.jpg)",
+    "options": [
+      "A. ![](images/287fcd36438bc38257db8cffdda456c8ff46b87c6e14fd35236bef1bcd58223b.jpg)",
+      "B. ![](images/1fce41180bcd1216ff6c3f1132ff70458e7e65a8d4dfdbea3eb9bb0008744ba2.jpg)",
+      "C. ![](images/86494483585e444f4d304b07e8cab11d49bb045b16cc85a8fd83b0902fd55237.jpg)"
+    ],
+    "answer": "A",
+    "solution": "【分析】根据题意可知，物体在水中的倒影就是镜面对称，是以水面为对称轴的轴对称图形，与实际物体上下完全相反，前后方向一致;据此逐项分析各个选项，找出正确答案即可。\n\n【详解】A. 松鼠上下完全相反，前后方向一致，符合题意，选项正确;B. 松鼠上下方向一致，前后方向相反，不符合题意，选项不正确;C. 松鼠上下方向一致，前后方向相同，不符合题意，选项不正确。故答案为:A",
+    "knowledge_points": [
+      "镜面对称"
+    ],
+    "source": "24-25 二年级下·浙江杭州·期末"
+  },
+  {
+    "id": "324",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面的图形中不是轴对称图形的是( )。",
+    "options": [
+      "A. ![](images/5ce9d229fa0b944dc892cf70348295a6c42c72e47e61f93f361d832f458401f8.jpg)",
+      "B. ![](images/969fba8d3056e2b8d3a3b662d5ad6095523519161859f910c2b1e1d238d3861a.jpg)",
+      "C. ![](images/b78c243d59e1e10b13baf5fec6e46ca05b3e017ca6fc0c594cc539898705b2ee.jpg)"
+    ],
+    "answer": "A",
+    "solution": "【分析】如果沿某条直线对折，对折的两部分是完全重合的，这样的图形是轴对称图形。这条直线是这个图形的对称轴。由此找出图形的对称轴即可解答。\n\n【详解】A. 没有对称轴，不是轴对称图形;B. 有对称轴，是轴对称图形;C. 有对称轴，是轴对称图形。则不是轴对称图形的是A。故答案为:A",
+    "knowledge_points": [
+      "轴对称的认识及辨认"
+    ],
+    "source": "24-25 二年级下·广东江门·期中"
+  },
+  {
+    "id": "325",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面图案中( )不是轴对称图形。",
+    "options": [
+      "A. ![](images/28c4773545421ceece9b4785b4854a1d62bf520fd52242ef19f589dabcc32f20.jpg)",
+      "B. ![](images/851c2765f4a46204d85e2d2e89e99f13ebbf3401c752a1be678bde855d95bcab.jpg)",
+      "C. ![](images/4c4d31f13fac1de93e933adabcedbaf4ea986e2b7133481b97e45888c77b8a3d.jpg)"
+    ],
+    "answer": "B",
+    "solution": "【分析】如果沿某条直线对折，对折的两部分是完全重合的，这样的图形为轴对称图形。这条直线叫做这个图形的对称轴。判断一个图案是否是轴对称图形的关键是看在这个图形中能否找到一条直线，使图形沿着这条直线对折后能够完全重合。\n\n【详解】A. 是轴对称图形;B. 不是轴对称图形;C. 是轴对称图形。故答案为:B",
+    "knowledge_points": [
+      "轴对称的认识及辨认"
+    ],
+    "source": "24-25 二年级下·河南信阳·期中"
+  },
+  {
+    "id": "326",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下列字母是轴对称图形的是( )。",
+    "options": [
+      "A. ![](images/547322e9764fecd2360cd0d1855cace2c14b530be505f9216a77a7076de1a481.jpg)",
+      "B. ![](images/33c688d2bdd929f521c7c4f28b8c59e8d9820c20d1e7f1571615c96d2a605e07.jpg)",
+      "C. ![](images/784bea1713d44bc6aebb3fca48ed62b26fa3c214855f0837fd49535cf402f751.jpg)"
+    ],
+    "answer": "C",
+    "solution": "【分析】如果一个图形沿着一条直线对折后两部分完全重合，这样的图形叫做轴对称图形，这条线叫对称轴，由此找出字母的对称轴即可解答。\n\n【详解】A. S没有对称轴，不是轴对称图形;B. 没有对称轴，不是轴对称图形;C. 有对称轴，是轴对称图形。故答案为:C",
+    "knowledge_points": [
+      "轴对称的认识及辨认"
+    ],
+    "source": "24-25二年级下·山东济宁·期末"
+  },
+  {
+    "id": "327",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "通过平移,( )能与原图重合。",
+    "options": [
+      "A. ![](images/d90f9631fa437b635e3ba7fcd1e4d3f8a8103446fdf19cb5d79bb7244926689a.jpg)",
+      "B. ![](images/233fa547c35c3524e2bd674fd67c463a618dcab456d8533542704292541cd5fc.jpg)",
+      "C. ![](images/9c0760fcbfada730ab608ff36b9b41a6a3d136a711c2aff1b25c2329735a635b.jpg)"
+    ],
+    "answer": "C",
+    "solution": "【分析】在平面内，把一个图形整体沿某条直线方向平行移动一定距离的过程，不改变图形的朝向和大小，称为平移。常见的平移现象有滑滑梯、电梯的移动等;逐项分析各个选项，找出正确答案即可。\n\n【详解】A. 车被倒过来，通过平移不能与原图重合;B. 车方向相反，通过平移不能与原图重合;C. 与原图的方向和大小都相同，因此通过平移就能与原图重合。故答案为:C",
+    "knowledge_points": [
+      "平移与平移现象"
+    ],
+    "source": "24-25 二年级下·湖南长沙·期中"
+  },
+  {
+    "id": "328",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下列字母是轴对称图形的是( )。",
+    "options": [
+      "A. S",
+      "B. M",
+      "C. N"
+    ],
+    "answer": "B",
+    "solution": "【分析】如果一个图形沿着一条直线对折后两部分完全重合，这样的图形叫做轴对称图形，这条线叫对称轴，由此找出字母的对称轴即可解答。\n\n【详解】A. S没有对称轴，不是轴对称图形;B. M有对称轴，是轴对称图形;C. N没有对称轴，不是轴对称图形。故答案为:B",
+    "knowledge_points": [
+      "轴对称的认识及辨认"
+    ],
+    "source": "24-25 二年级下·河北邢台·期中"
+  },
+  {
+    "id": "329",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面物体中，( )的运动是旋转现象。",
+    "options": [
+      "A. 电梯升降",
+      "B. 风车转动",
+      "C. 推拉抽屉"
+    ],
+    "answer": "B",
+    "solution": "【分析】在平面内，把一个图形整体沿某条直线方向平行移动一定距离的过程，称为平移。常见的平移现象有滑滑梯、电梯的移动等;在平面内，把一个图形围绕某一固定点按顺时针或逆时针方向转动一定的角度的过程，称为旋转。常见的旋转现象有旋转木马、摩天轮等。由此解答。\n\n【详解】A. 电梯升降：电梯上下移动是沿直线运动，属于平移现象;B. 风车转动：风车叶片绕中心轴转动，是旋转现象;C. 推拉抽屉：抽屉前后移动是沿直线运动，属于平移现象。故答案为:B",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "24-25 二年级下·湖南岳阳·期中"
+  },
+  {
+    "id": "330",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下列运动现象属于平移现象的有( )。\n![](images/image-6.png)",
+    "options": [
+      "A. ①④⑥",
+      "B. ④⑤⑥",
+      "C. ①③⑥",
+      "D. ②④⑤"
+    ],
+    "answer": "C",
+    "solution": "【分析】平移是指在平面内，将一个图形上的所有点都按照某个直线方向做相同距离的移动，这样的图形运动叫做图形的平移运动，简称平移。平移后图形的位置改变，形状、大小、方向不变。旋转：在平面内，将一个图形绕一点按某个方向转动一定的角度，这样的运动叫做图形的旋转。旋转后图形的位置和方向改变，形状、大小不变。\n\n【详解】属于平移现象的有①③⑥。故答案为:C",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "24-25 二年级下·山东济南·期中"
+  },
+  {
+    "id": "331",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下列各图中，表示的不是轴对称图形的是( )。",
+    "options": [
+      "A. ![](images/378064e3ab6335c646752ad94608ad01b8dba860055876e11fc2f28b2547376e.jpg)",
+      "B. ![](images/2c2282a5ec2bde98f99a09593eac12ec580e3d78b85c2a6412861ced4705dd1c.jpg)",
+      "C. ![](images/b3e946f700b3373b094ae183dbc83d0ab8be15bebe60daf4907d91a06ee19b57.jpg)",
+      "D. ![](images/1e629881f1a2a4438f1a500b9d186c40712e779fc5b65002b16acdcfe280b211.jpg)"
+    ],
+    "answer": "C",
+    "solution": "【分析】如果沿某条直线对折，对折的两部分是完全重合的，这样的图形为轴对称图形。这条直线叫做这个图形的对称轴。判断一个图案是否是轴对称图形的关键是看在这个图形中能否找到一条直线，使图形沿着这条直线对折后能够完全重合。\n\n【详解】A. 是轴对称图形;B. 是轴对称图形;C. 不是轴对称图形;D. 是轴对称图形。表示的不是轴对称图形的是C。故答案为:C",
+    "knowledge_points": [
+      "轴对称的认识及辨认"
+    ],
+    "source": "24-25 二年级下·山东济南·期末"
+  },
+  {
+    "id": "332",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面的图形中，不是轴对称图形的是( )。",
+    "options": [
+      "A. ![](images/8c2eb8617a5972d8f3be03a25c0814d3137f4b4ac225953603b901ea4c168187.jpg)",
+      "B. ![](images/ef6896e78f57dfefbe2131f67e26eed11a0f70b61dc02aac4e1a95f0110d1f35.jpg)",
+      "C. ![](images/c838f742e912db390e1113170406162f3503e92c5284164cb6cc18bd32770412.jpg)",
+      "D. ![](images/9e308e829a9f3573a39f7bf12ab20554af0f39b847603ce9aa41c890ad920b97.jpg)"
+    ],
+    "answer": "C",
+    "solution": "【分析】如果一个图形沿着一条直线对折后两部分完全重合，这样的图形叫做轴对称图形，这条线叫对称轴，由此找出图形的对称轴即可解答。\n\n【详解】A. 有对称轴，是轴对称图形;B. 有对称轴，是轴对称图形;C. 没有对称轴，不是轴对称图形;D. 有对称轴，是轴对称图形。则不是轴对称图形的是C。故答案为:C",
+    "knowledge_points": [
+      "轴对称的认识及辨认"
+    ],
+    "source": "24-25二年级下·广东东莞·期末"
+  },
+  {
+    "id": "333",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "如图所示图中，可以通过平移得到并相互重合的是( )。\n![](images/f51e39b8ebd52c405bea8fd0cd1d32b926630356317f11df9749ebf983213999.jpg)",
+    "options": [
+      "A. ![](images/12e78f40d0d81ae86fa150e559e05118012fe28f7cfd44c7715c0d633f2497ee.jpg)",
+      "B. ![](images/d4fe8eb1d4314fbb11770840f92a83cac4f22cec5190701a629b87215ca39f7e.jpg)",
+      "C. ![](images/b1a77ad1443ffd7b11f03548552476b3fdb13ad0a32706555e85883b42b2808e.jpg)"
+    ],
+    "answer": "C",
+    "solution": "【分析】把一个图形整体沿某一方向移动一定的距离，图形的这种移动，叫作平移。平移后图形的位置改变，方向、形状、大小不变，据此解答即可。\n\n【详解】A. 图形的方向发生了变化，不是平移;B. 图形的方向发生了变化，不是平移;C. 图形的大小、方向、形状都没发生变化，是平移。则可以通过平移得到并相互重合的是C。故答案为:C",
+    "knowledge_points": [
+      "平移与平移现象"
+    ],
+    "source": "23-24 二年级下·辽宁鞍山·期中"
+  },
+  {
+    "id": "334",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "如图所示标识牌中，( )不是轴对称图形。",
+    "options": [
+      "A. ![](images/117430867189a4d3d76a87d99955022bba8b4b866d507b1f679b2e354dc3ed2f.jpg)",
+      "B. ![](images/1fa32f456f28b67bb799b8cb8067fb2b61fa1c3763b25ef0e17d35b0468221e6.jpg)",
+      "C. ![](images/78bd2cacc6afff99fc283b1c1358bb472fe5ddbcbd04b7188461b4f6557234b9.jpg)"
+    ],
+    "answer": "C",
+    "solution": "【分析】如果一个图形沿着一条直线对折，直线两边的图形能够完全重合，这样的图形叫作轴对称图形，这条直线叫作对称轴，据此解答即可。\n\n【详解】A. 当心弯道图从有两条弧线的角进行对折，两边的图形完全重合，是轴对称图形;B. 注意安全图从上面的角进行对折，两边的图形完全重合，是轴对称图形;C. 当心触电图不论从哪个方向进行对折，两边的图形都不能重合，不是轴对称图形。故答案为:C",
+    "knowledge_points": [
+      "轴对称的认识及辨认"
+    ],
+    "source": "23-24 二年级下·辽宁鞍山·期中"
+  },
+  {
+    "id": "335",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面关于环保的四个标志中，是轴对称图形的是( )。",
+    "options": [
+      "A. ![](images/b17cf4657fac6ed676d18abd6fe1938acf7c7bcb9c126eb2ccded9f45dc2237a.jpg)",
+      "B. ![](images/5033364b99a2c5e714957841c8ef5e8457e466e512a7a7620340bcb49590e087.jpg)",
+      "C. ![](images/45a6f9bd83426c6f6413043dbd0cdb4c7574de75ab740bc7dbd4385369e57543.jpg)",
+      "D. ![](images/f805c88db69c1f666b597b03192c5a75a03b4da29dad1b48ac5dd08d12847cf8.jpg)"
+    ],
+    "answer": "B",
+    "solution": "【分析】根据轴对称图形的意义：如果一个图形沿着一条直线对折后两部分完全重合，这样的图形叫做轴对称图形，这条直线叫做对称轴，据此解答即可。\n\n【详解】A. 不是轴对称图形，不符合题意;B. 是轴对称图形，符合题意;C. 不是轴对称图形，不符合题意;D. 不是轴对称图形，不符合题意。故答案为:B",
+    "knowledge_points": [
+      "轴对称的认识及辨认"
+    ],
+    "source": "2024·浙江温州·小升初真题"
+  },
+  {
+    "id": "336",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "如图，风扇转动的过程称作( )。\n![](images/5dd7fff6eb28ae10ac1a19cbfef8a1a1526f7d5357c0c0a907e2ea034b063f12.jpg)",
+    "options": [
+      "A. 平移",
+      "B. 复制",
+      "C. 对称",
+      "D. 旋转"
+    ],
+    "answer": "D",
+    "solution": "【分析】旋转：在平面内，将一个图形绕一点按某个方向转动一定的角度，这样的运动叫做图形的旋转;平移：在平面内，把一个图形整体沿某条直线方向平行移动一定距离的过程，称为平移;轴对称图形是一个图形沿着一条直线对折后两部分完全重合的图形。据此解答。\n\n【详解】根据分析可知：如图，风扇转动的过程称作旋转。故答案为:D",
+    "knowledge_points": [
+      "轴对称的认识及辨认",
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "24-25 二年级上·浙江温州·期末"
+  },
+  {
+    "id": "337",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "下面图中，不是轴对称图形的是( )。",
+    "options": [
+      "A. ![](images/0dce7ce864dbd35290aebcffb6477ec40df55739f7b8027c0b69bbf1b2a7f976.jpg)",
+      "B. ![](images/33aef52e8037868e448c2b3f2e138dada88289c4a92e3f286cdb0af2033fce67.jpg)",
+      "C. ![](images/2a93b1c90a93d7164efcfd1f23f384e4b72b8bd5de549373f9e0a3299b492536.jpg)"
+    ],
+    "answer": "A",
+    "solution": "【分析】如果一个平面图形沿一条直线折叠，直线两旁的部分能够互相重合，这个图形就叫做轴对称图形，据此解答。\n\n【详解】A. 不是轴对称图形;B. 是轴对称图形;C. 是轴对称图形。故答案为:A",
+    "knowledge_points": [
+      "轴对称的认识及辨认"
+    ],
+    "source": "24-25五年级下·海南海口·单元测试"
+  },
+  {
+    "id": "338",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下列现象属于平移的是( )。",
+    "options": [
+      "A. ![](images/4060488f1584abea285d77c6246ecafa564a689a99dcb5622a208bde69b09b80.jpg)",
+      "B. ![](images/efddb46784401192c6aa657843e6c7cfab3c346e3ed91a8e8a9b0c4791a2c3dc.jpg)",
+      "C. ![](images/09124dcce2ffbb5a555653a19c9c674562daa0c7b6256bfb6cc5de1dcfdfa4c1.jpg)"
+    ],
+    "answer": "C",
+    "solution": "【分析】平移是指在平面内，将一个图形上的所有点都按照某个直线方向做相同距离的移动，这样的图形运动叫做图形的平移运动，简称平移。平移后图形的位置改变，形状、大小、方向不变。旋转：在平面内，将一个图形绕一点按某个方向转动一定的角度，这样的运动叫做图形的旋转。旋转后图形的位置和方向改变，形状、大小不变。\n\n【详解】A. 是旋转现象;B. 是旋转现象;C. 是平移现象。故答案为:C",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "23-24 二年级下·浙江温州·期中"
+  },
+  {
+    "id": "339",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "下面运动是平移的是( )。",
+    "options": [
+      "A. ![](images/9ba3797c756bac14c0854035a0af5308ccf489b5ef421189e49d8ae55b94693f.jpg)",
+      "B. ![](images/a5bdaf4b08253550461747fb812c0af91247442f4f22668f7c2e229d2a9de90b.jpg)",
+      "C. ![](images/bb12fed3e8551459d8d9300cb97b5bcbc3e6052f25289166672bd1c3781c7d4f.jpg)"
+    ],
+    "answer": "C",
+    "solution": "【分析】平移是指将物体或图形沿着平行的路径移动，而不改变其形状和方向。旋转是指将物体或图形绕着一个点旋转，使其按照特定的角度改变方向。据此得出结论即可。\n\n【详解】A. 钟表指针的运动是旋转，不符合题意;B. 电扇扇叶的运动是旋转，不符合题意;C. 吸尘器的运动是平移，符合题意。故答案为:C",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "22-23 二年级下·四川凉山·期末"
+  },
+  {
+    "id": "340",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "下列图案中，( )是通过一个基本图形平移得到的。",
+    "options": [
+      "A. ![](images/450a6686ff0704c8072b9cea2a151ef8037540bc8d87728fbbcad33c81a79aec.jpg)",
+      "B. ![](images/e9a72c0278bb0f71f0b4ce10da58752c1e243b8fe8af107079d0c77efae3c2b4.jpg)",
+      "C. ![](images/8eca121fb553981d95800c05753ce376066f843e296b2f1a5a023dba97eef61f.jpg)"
+    ],
+    "answer": "B",
+    "solution": "【分析】平移是指在平面内，将一个图形上的所有点都按照某个直线方向做相同距离的移动，这样的图形运动叫做图形的平移运动，简称平移。平移后图形的位置改变，形状、大小、方向不变。在平面内，将一个图形绕一点按某个方向转动一定的角度，这样的运动叫做图形的旋转。旋转后图形的位置和方向改变，形状、大小不变。如果沿某条直线对折，对折的两部分是完全重合的，这样的图形为轴对称图形。\n\n【详解】A. 是轴对称图形;B. 是通过一个基本图形平移得到的;C. 是通过一个基本图形旋转得到的。故答案为:B",
+    "knowledge_points": [
+      "轴对称的认识及辨认",
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "22-23 二年级下·四川广元·期末"
+  },
+  {
+    "id": "341",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "( )图形是由“△○□”通过平移拼成的。",
+    "options": [
+      "A. ![](images/af465613f5b76667f13f4f87b26c173a89b1b0e4071522852c5a8f66231defc1.jpg)",
+      "B. ![](images/90ab67e535d170975e71b839e50279a203f9463912b1dc39d2a18f5cf0a8ca11.jpg)",
+      "C. ![](images/8b84e10311b71677c70a60d448827047bc1fdf85edd83e152e890723138165f5.jpg)"
+    ],
+    "answer": "C",
+    "solution": "【分析】在平面内，把一个图形整体沿某条直线方向平行移动一定距离的过程，称为平移。物体或图形平移后，它们的形状、大小、方向都不改变，只是位置发生了变化。由此解答。\n\n【详解】A. 图中三角形的方向发生了变化，不符合题意;B. 图中三角形和两个长方形的方向发生了变化，不符合题意;C. 所有图形的形状、大小、方向都没有发生变化，符合题意。所以C是由原图通过平移拼成的。故答案为:C",
+    "knowledge_points": [
+      "平移与平移现象"
+    ],
+    "source": "19-20 二年级下·全国·期中"
+  },
+  {
+    "id": "342",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面图形不是轴对称图形的是( )。",
+    "options": [
+      "A. ![](images/ca3a308efc946d9a1d755fd60ce38ee2cb14c659f915095921a61315ebf7e5ee.jpg)",
+      "B. ![](images/8a26451dbb2ae6a89f9769f7514469e8148c9ec80b915ca05a8c53ce6ab97019.jpg)",
+      "C. ![](images/39c98af729f3d620fb3553dfebe44133ea9d26da70702bbf7ff7e2a7d0b3b8d0.jpg)",
+      "D. ![](images/c4279849e78c996fccb556667931eca87be82b14ad29e0d6f8d8dfaf8b7ea5ca.jpg)"
+    ],
+    "answer": "B",
+    "solution": "【分析】如果沿某条直线对折，对折的两部分是完全重合的，这样的图形为轴对称图形。这条直线叫做这个图形的对称轴。判断一个图案是否是轴对称图形的关键是看在这个图形中能否找到一条直线，使图形沿着这条直线对折后能够完全重合。\n\n【详解】A. 是轴对称图形;B. 不是轴对称图形;C. 是轴对称图形;D. 是轴对称图形。故答案为:B",
+    "knowledge_points": [
+      "轴对称的认识及辨认"
+    ],
+    "source": "22-23 二年级下·四川乐山·期末"
+  },
+  {
+    "id": "343",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面图形中，( )是轴对称图形。",
+    "options": [
+      "A. ![](images/9f519154ccf3bd70e023f052859b12e6f9126e3f60d616ecf34078512a4b42bb.jpg)",
+      "B. ![](images/a70c2db62364fb0583c8fd21cfbab8d734e3f80a0a44821c3b569ad1279c3aba.jpg)",
+      "C. ![](images/9b51d70a0b5a27440c7a976a70bcc3b8f425daf585390e7224834e53c55ea735.jpg)"
+    ],
+    "answer": "B",
+    "solution": "【分析】如果沿某条直线对折，对折的两部分是完全重合的，这样的图形为轴对称图形。这条直线叫做这个图形的对称轴。判断一个图案是否是轴对称图形的关键是看在这个图形中能否找到一条直线，使图形沿着这条直线对折后能够完全重合。\n\n【详解】A. 没有对称轴，不是轴对称图形;B. 是轴对称图形;C. 没有对称轴，不是轴对称图形。故答案为:B",
+    "knowledge_points": [
+      "轴对称的认识及辨认"
+    ],
+    "source": "22-23二年级下·四川南充·期末"
+  },
+  {
+    "id": "344",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "芳芳在对折好的纸上剪了两个洞，展开后的图形是( )。\n![](images/fae14a1da767e398b60795ff4483e3acc9c33988d961d3a242eab7be6780713c.jpg)",
+    "options": [
+      "A. ![](images/9802e35f56f9c0c7e8ef252f500294c6b643c384a743d0798df27acb45d420a1.jpg)",
+      "B. ![](images/1d1704d4028e77c632a2f6a184887dcc7824b1aa4304709b803e98b713d06de9.jpg)",
+      "C. ![](images/b3ac99aa35b1d1af6339afe4751b117a688fb390648f10712380400ece03947c.jpg)"
+    ],
+    "answer": "C",
+    "solution": "【分析】一个图形沿一条直线对折，直线两旁的图形完全重合，这样的图形叫做轴对称图形，折痕所在的直线就是对称轴。由此可知，展开后的图形应在左上角有1个三角形，右上角有1个三角形，下边中间折痕两侧有2个三角形，据此解答。\n\n【详解】由分析可知，展开后的图形应是C。故答案为:C",
+    "knowledge_points": [
+      "轴对称的认识及辨认",
+      "轴对称的剪纸问题"
+    ],
+    "source": "23-24 二年级下·四川南充·期末"
+  },
+  {
+    "id": "345",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面不是轴对称图形的是( )。",
+    "options": [
+      "A. ![](images/837fef9acc7f2418e2c776fde45b54c21cfe8af4237930e09539662096067e40.jpg)",
+      "B. ![](images/92bcdacdc2414049a139dd29bed252121141a7b70bedb52690bded41cc345fda.jpg)",
+      "C. ![](images/85fd4baa491a5121cd3047f9540ea613d63e70c9f7512c4e2d9df704e0ff7de9.jpg)",
+      "D. ![](images/357489fcd413377f49b6160e4894fa8ba953c5344607093a5ea8e82ee991efb8.jpg)"
+    ],
+    "answer": "B",
+    "solution": "【分析】如果沿某条直线对折，对折的两部分是完全重合的，这样的图形为轴对称图形。这条直线叫做这个图形的对称轴。判断一个图案是否是轴对称图形的关键是看在这个图形中能否找到一条直线，使图形沿着这条直线对折后能够完全重合。\n\n【详解】A. 是轴对称图形;B. 不是轴对称图形;C. 是轴对称图形;D. 是轴对称图形。故答案为:B",
+    "knowledge_points": [
+      "轴对称的认识及辨认"
+    ],
+    "source": "23-24 二年级下·四川乐山·期末"
+  },
+  {
+    "id": "346",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "下面的字母中，( )不是轴对称图形。",
+    "options": [
+      "A. C",
+      "B. T",
+      "C. N"
+    ],
+    "answer": "C",
+    "solution": "【分析】一个图形沿一条直线对折，直线两旁的图形完全重合，这样的图形叫做轴对称图形，折痕所在的直线就是对称轴。判断一个图案是否是轴对称图形的关键是看在这个图形中能否找到一条直线，使图形沿着这条直线对折后能够完全重合。\n\n【详解】A. 字母C通过对折，两边能够完全重合，是轴对称图形;B. 字母T通过对折，两边能够完全重合，是轴对称图形;C. 字母N通过对折，两边不能完全重合，不是轴对称图形。故答案为:C",
+    "knowledge_points": [
+      "轴对称的认识及辨认"
+    ],
+    "source": "23-24 二年级下·四川乐山·期中"
+  },
+  {
+    "id": "347",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "是从对折的( )上剪下来的。",
+    "options": [
+      "A. ![](images/02d6802a50d5ed871526e745153e931602cd9f1b50cf47eb4d2810572c83c45f.jpg)",
+      "B. ![](images/ef73d43a31b9866daffe314fa918d52b22801f1a1f5c8589fb0d59f32d7c7e33.jpg)",
+      "C. ![](images/83263d68e2f4d249d4a4a92ae49a179cafb8ff213f8b3d79753a79e5885e7f8c.jpg)"
+    ],
+    "answer": "B",
+    "solution": "【分析】通过对折，两边能够完全重合的图形叫做轴对称图形;将题目中图形通过对折，与选项中的剪痕进行对比即可。\n\n【详解】通过对折可知，原图是从对折的B上剪下来的。故答案为:B",
+    "knowledge_points": [
+      "轴对称的剪纸问题"
+    ],
+    "source": "24-25 二年级上·广东梅州·期中"
+  },
+  {
+    "id": "348",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "如图所示图形中，不能由一张纸对折后剪出来的是( )。",
+    "options": [
+      "A. ![](images/53ba614709a9777b6b5ca7c5498e445b95f377a1fc02f975f673d794acb405f1.jpg)",
+      "B. ![](images/6e9f7f3035ba882429f32fc701120136718734066e9e492ddb3219b7c7199ed3.jpg)",
+      "C. ![](images/e76eaf284aa7820b6cdc1a542afc5be9664bde35bfe810cb1f98adb24587784b.jpg)"
+    ],
+    "answer": "B",
+    "solution": "【分析】把一个图形沿着某一条直线折叠，如果直线两旁的部分能够互相重合，那么称这个图形是轴对称图形，这条直线就是对称轴，据此解答即可。\n\n【详解】A. 沿着一条直线折叠，直线两旁的部分能够互相重合，可以由一张纸对折后剪出来;B. 沿着一条直线折叠，直线两旁的部分不能够互相重合，不能由一张纸对折后剪出来;C. 沿着一条直线折叠，直线两旁的部分能够互相重合，可以由一张纸对折后剪出来。故答案为:B",
+    "knowledge_points": [
+      "轴对称的认识及辨认",
+      "轴对称的剪纸问题"
+    ],
+    "source": "24-25 二年级上·广东韶关·期中"
+  },
+  {
+    "id": "349",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "一张正方形纸对折三次，沿着折痕所在的直线画出花朵的一半，把它沿边缘线剪下来，能剪出( )完整的花。",
+    "options": [
+      "A. 2朵",
+      "B. 3朵",
+      "C. 4朵",
+      "D. 6朵"
+    ],
+    "answer": "C",
+    "solution": "【分析】轴对称：在平面内，如果一个图形沿一条直线对折，对折后的两部分都能完全重合，这样的图形叫做轴对称图形，这条直线就是其对称轴。剪纸属于一种轴对称图形，据此解答即可。\n\n【详解】一张正方形纸对折三次，也就是把这张正方形纸平均分成了8份，沿着折痕所在的直线画出花朵的一半，把它沿边缘线剪下来，动手剪一剪可知，能剪出8个花朵的一半，2个花朵的一半可以拼成1朵完整的花，所以能剪出4朵完整的花。故答案为:C",
+    "knowledge_points": [
+      "轴对称的剪纸问题"
+    ],
+    "source": "24-25 二年级上·河南郑州·期中"
+  },
+  {
+    "id": "350",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下列各图案是某种衣服的洗涤说明，可以利用图形的旋转得到的图案是( )。",
+    "options": [
+      "A. ![](images/0651bfa01c312dc2fe6eb03557c17b535136c1d6b4132c909abb277c9ef5088f.jpg)",
+      "B. ![](images/fef55ddff165e48619a3723f65b26ad9c7185d29a57e04f228f23129910809ae.jpg)",
+      "C. ![](images/6e7b148d990b38864e4987b7c18e8d05923cbdae1edd38ecaecb9fcd20974ada.jpg)"
+    ],
+    "answer": "C",
+    "solution": "【分析】在平面内，把一个图形围绕某一固定点转动一定的角度的过程，称为旋转。常见的旋转现象有旋转木马、摩天轮等。物体或图形旋转后，它们的形状、大小都不改变，只是位置发生了变化，据此即可解答。\n\n【详解】A. 不能通过旋转得到;B. 不能通过旋转得到;C. 这部分图形可以通过旋转得到。故答案为:C",
+    "knowledge_points": [
+      "旋转与旋转现象"
+    ],
+    "source": "24-25二年级上·河南郑州·期中"
+  },
+  {
+    "id": "351",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下列常用的标志中，是轴对称图形的是( )。",
+    "options": [
+      "A. ![](images/60ded0251a964cbdf535ef719b0f00758c7b2aeb03d79ee4dc33655c6975eb15.jpg)",
+      "B. ![](images/ec055f10c9db09b0b826d2211c94060c6415e7614d2cbf46ae3058cd0650a1f6.jpg)",
+      "C. ![](images/4ab7c9bebe6949d3d5f712b167c8d6d629e732c62c31a26be8bd27549f2fe31c.jpg)"
+    ],
+    "answer": "B",
+    "solution": "【分析】一个图形沿着某一条直线折叠，如果直线两旁的部分能够互相重合，那么称这个图形是轴对称图形，这条直线就是对称轴，据此解答即可.\n【详解】A。 找不到一条对称轴，不是轴对称图形;B. 是轴对称图形;C. 找不到一条对称轴，不是轴对称图形。故答案为:B",
+    "knowledge_points": [
+      "轴对称的认识及辨认"
+    ],
+    "source": "23-24 二年级下·河南南阳·期末"
+  },
+  {
+    "id": "352",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面的图形是轴对称的是( )。",
+    "options": [
+      "A. ![](images/71715038ffc89e0e6d8c8a11a99ef385b7d3268ebc96704cf05d4dfb05e678be.jpg)",
+      "B. ![](images/a65d34faeb1171a7e226b99288f3beb2f901f075a766cf5530ddc49a868c37fd.jpg)",
+      "C. ![](images/4861cad5122ef5cc2ee6951056706fd6cd77438fbe95c76de7da5b32969beaf5.jpg)"
+    ],
+    "answer": "A",
+    "solution": "【分析】一个图形沿着某一条直线折叠，如果直线两旁的部分能够互相重合，那么称这个图形是轴对称图形，这条直线就是对称轴，据此解答即可.\n【详解】A。 是轴对称图形;B. 找不到一条对称轴，不是轴对称图形;C. 找不到一条对称轴，不是轴对称图形。故答案为:A",
+    "knowledge_points": [
+      "轴对称的认识及辨认"
+    ],
+    "source": "23-24二年级下·贵州六盘水·期末"
+  },
+  {
+    "id": "353",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面不属于旋转现象的是( )。",
+    "options": [
+      "A. 旋转木马的运动",
+      "B. 打开推拉门",
+      "C. 钟面上指针的运动"
+    ],
+    "answer": "B",
+    "solution": "【分析】在平面内，把一个图形围绕某一固定点按顺时针或逆时针方向转动一定的角度的过程，称为旋转，常见的旋转现象有摩天轮，风扇的转动等;在平面内，把一个图形整体沿某条直线方向平行移动一定距离的过程，称为平移，常见的平移现象有滑滑梯，电梯的移动等。由此解答.\n【详解】A。 旋转木马的运动是旋转现象;B. 打开推拉门是平移现象;C. 钟面上指针的运动是旋转现象;所以不属于旋转现象的是打开推拉门。故答案为:B",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "23-24二年级下·河南濮阳·期末"
+  },
+  {
+    "id": "354",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面的图案中( )是轴对称图形。",
+    "options": [
+      "A. ![](images/012985e3b238f5c0c1ce2c3987e92bdd0127f7c5897911e00c1138d18123ecf7.jpg)",
+      "B. ![](images/a1c934eb345e64311c7e045686ec4fbd873e827e2eaf69f328f9a92b8c801546.jpg)",
+      "C. ![](images/0c3a2d6c5c6b0bc2bc87792c4e30615f01fd4169e3d845447ef402cbb8935339.jpg)"
+    ],
+    "answer": "A",
+    "solution": "【分析】一个图形沿一条直线对折，直线两旁的图形完全重合，这样的图形叫做轴对称图形，折痕所在的直线就是对称轴，由此找出图形的对称轴即可.\n【详解】A。 有对称轴，是轴对称图形;B。没有对称轴，不是轴对称图形;C. 没有对称轴，不是轴对称图形。所以A是轴对称图形。故答案为:A",
+    "knowledge_points": [
+      "轴对称的认识及辨认"
+    ],
+    "source": "23-24二年级下·江西赣州·期末"
+  },
+  {
+    "id": "355",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "升国旗时，国旗的运动是( )现象;钟表上，分针的运动是( )现象。",
+    "options": [],
+    "answer": "平移;旋转",
+    "solution": "【分析】在平面内，把一个图形整体沿某条直线方向平行移动一定距离的过程，称为平移，常见的平移现象有滑滑梯，推拉窗户等。在平面内，把一个图形围绕某一固定点按顺时针或逆时针方向转动一定的角度的过程，称为旋转，常见的旋转现象有旋转木马，摩天轮等.\n【详解】由分析可知：升国旗时，国旗的运动是平移现象;钟表上，分针的运动是旋转现象。",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "24-25二年级下·湖北省直辖县级单位·期中"
+  },
+  {
+    "id": "356",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "在平直的马路上行驶的汽车，汽车本身的运动是( ),汽车轮子的运动是( )。",
+    "options": [],
+    "answer": "平移;旋转",
+    "solution": "【分析】在平面内，把一个图形整体沿某条直线方向平行移动一定距离的过程，称为平移。常见的平移现象有滑滑梯，电梯的移动等;在平面内，把一个图形围绕某一固定点按顺时针或逆时针方向转动一定的角度的过程，称为旋转。常见的旋转现象有旋转木马，摩天轮等;由此解答.\n【详解】由分析可得：汽车本身的运动符合平移的特点;汽车轮子的运动符合旋转的特点。在平直的马路上行驶的汽车，汽车本身的运动是平移，汽车轮子的运动是旋转。",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "24-25 二年级下·重庆渝中·期中"
+  },
+  {
+    "id": "357",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "选填'平移'或'旋转'.\n![](images/5ebebf45576bd74ac498dd525762fc38935539cfa86e72d2983abc1e605024fd.jpg)\n![](images/9e0d9c957d0f75a7339d67a75cbb1d808e9a711d8d9ed381eb3d075d2a95d8d4.jpg)\n![](images/31b5f64fdd251da37bde7694851fa63d0d62ea9694787d728c6ce79784d73a42.jpg)\n![](images/3069a4e8c6af7c4d5c4ef30ff1f83a18407c03b5ae0b064d9257e15c4d08d9c1.jpg)\n沿直轨前行的高铁( )现象;无人机螺旋桨的转动( )现象;快递沿直线传送( )现象;电风扇扇页的转动( )现象。",
+    "options": [],
+    "answer": "平移;旋转;平移;旋转",
+    "solution": "【分析】平移是物体运动时，物体上任意两点间，从一点到另一点的方向与距离都不变的运动;旋转是物体运动时，每一个点离同一个点(可以在物体外)的距离不变的运动，称为绕这个点的转动，这个点称为物体的转动中心。所以，它并不一定是绕某个轴的;也可以这样说平移是不转动的，旋转自然是转动的，依此根据平移与旋转定义判断即可.\n【详解】高铁沿直线行驶在铁路上，是平移现象;无人机螺旋桨绕点转动，是旋转现象;快递沿直线传送，是平移现象;电风扇扇叶转动，是旋转现象。",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "24-25 二年级下·青海果洛·期中"
+  },
+  {
+    "id": "358",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "升旗时国旗的运动属于( )现象;拧水龙头属于( )现象。(填'旋转'或'平移')",
+    "options": [],
+    "answer": "平移;旋转",
+    "solution": "【分析】平移是指在平面内，将一个图形上的所有点都按照某个直线方向做相同距离的移动，这样的图形运动叫做图形的平移运动，简称平移。平移后图形的位置改变，形状，大小，方向不变。旋转：在平面内，将一个图形绕一点按某个方向转动一定的角度，这样的运动叫做图形的旋转。旋转后图形的位置和方向改变，形状，大小不变.\n【详解】升旗时国旗的运动属于平移现象;拧水龙头属于旋转现象。",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "24-25 二年级下·河北唐山·期中"
+  },
+  {
+    "id": "359",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "这学期，我们认识了生活中的三种运动现象：平移，旋转，轴对称。如果要剪出如图所示的四个小人，需要对折( )次，利用的数学知识是( )。如果给出一个完整的小人，我们还可以通过( )运动变换出这样的四个小人.\n![](images/824c75c76ebe844070e93165287a3472c710a056b224700d6a94e051676bce8f.jpg)",
+    "options": [],
+    "answer": "3;轴对称;平移",
+    "solution": "【分析】轴对称：在平面内，如果一个图形沿一条直线对折，对折后的两部分都能完全重合，这样的图形叫做轴对称图形，这条直线就是其对称轴。对折1次剪好展开可以剪出1个小人，对折2次剪好展开可以剪出2个小人，对折3次剪好展开可以剪出3个小人。因为每次对折后，纸张的层数翻倍，剪出的小人数量也相应增加。这里要剪出4个小人，所以需要对折3次。平移：在平面内，将一个图形上的所有点都按照某个方向作相同距离移动的图形运动。平移后图形的位置改变，形状，大小，方向不变。据此解答即可.\n【详解】这学期，我们认识了生活中的三种运动现象：平移，旋转，轴对称。如果要剪出如图所示的四个小人，需要对折(3)次，利用的数学知识是(轴对称)。如果给出一个完整的小人，我们还可以通过(平移)运动变换出这样的四个小人。",
+    "knowledge_points": [
+      "平移与平移现象",
+      "轴对称的剪纸问题"
+    ],
+    "source": "24-25二年级下·浙江宁波·期中"
+  },
+  {
+    "id": "360",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "风扇转动是( )现象，拉开抽屉是( )现象，钟面上分针的运动是( )现象。(填'平移'或'旋转')",
+    "options": [],
+    "answer": "旋转;平移;旋转",
+    "solution": "【分析】在平面内，一个图形整体沿着某条直线方向平行移动一定距离的过程，称为平移;在平面内，一个图形围绕某一个固定点按照顺时针或逆时针方向转动一定角度的过程，称为旋转.\n【详解】由分析可知：风扇转动是(旋转)现象，拉开抽屉是(平移)现象，钟面上分针的运动是(旋转)现象。",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "24-25 二年级下·广东广州·期中"
+  },
+  {
+    "id": "361",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "风扇转动是( )现象，推拉抽屉是( )现象。",
+    "options": [],
+    "answer": "旋转;平移",
+    "solution": "【分析】在平面内，把一个图形整体沿某条直线方向平行移动一定距离的过程，称为平移，例如滑滑梯，电梯的移动等。在平面内，把一个图形围绕某一固定点按顺时针或逆时针方向转动一定的角度的过程，称为旋转，例如旋转木马，摩天轮等.\n【详解】由分析得：风扇转动是旋转现象，推拉抽屉是平移现象。",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "24-25 二年级下·湖南岳阳·期中"
+  },
+  {
+    "id": "362",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "风扇转动的过程称作( ),电梯的上下运动称作( )。",
+    "options": [],
+    "answer": "旋转;平移",
+    "solution": "【分析】平移：在平面内，将一个图形上的所有点都按照某个方向作相同距离移动的图形运动。平移后图形的位置改变，形状，大小，方向不变。旋转：在平面内，将一个图形绕一点按某个方向转动一定的角度，这样的运动叫做图形的旋转。旋转前后图形的位置和方向改变，形状，大小不变.\n【详解】根据分析可知：风扇转动的过程称作旋转，电梯的上下运动称作平移。",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "24-25 二年级下·广东珠海·期中"
+  },
+  {
+    "id": "363",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "下列图形是轴对称图形的是( )和( )。(填序号)\n![](images/39770a60a66c9d814a7bf00af91231478413cd8bcbbe7fb1f8fc540ac2acf7be.jpg)\n![](images/8d478c0c62551b8420046cb1bd631ccc6f2fa89d0f6e746a90a80c7fdedb7dfc.jpg)\n![](images/59c4747a5dcf16f714aa8152b69c932d12c3952e7e04304bf1488576ef545f6c.jpg)\n![](images/e4e91aee1542ce0905eccd7c3267996277c2bfc05067a5018665adb28732e75b.jpg)",
+    "options": [],
+    "answer": "①;③",
+    "solution": "【分析】如果沿某条直线对折，对折的两部分是完全重合的，这样的图形是轴对称图形。这条直线是这个图形的对称轴。由此找出图形的对称轴即可解答.\n【详解】① 有对称轴，是轴对称图形;② 没有对称轴，不是轴对称图形;③有对称轴，是轴对称图形;④ 没有对称轴，不是轴对称图形。则是轴对称图形的是①和③。",
+    "knowledge_points": [
+      "轴对称的认识及辨认"
+    ],
+    "source": "24-25 二年级下·河北邢台·期中"
+  },
+  {
+    "id": "364",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "风车的转动是( )现象，推拉门窗是( )现象。",
+    "options": [],
+    "answer": "旋转;平移",
+    "solution": "【分析】在平面内，把一个图形整体沿某条直线方向平行移动一定距离的过程，称为平移，例如滑滑梯，电梯的移动等。在平面内，把一个图形围绕某一固定点按顺时针或逆时针方向转动一定的角度的过程，称为旋转，例如旋转木马，摩天轮等.\n【详解】由分析得：风车的转动是旋转现象，推拉门窗是平移现象。",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "24-25 二年级下·山东济宁·期末"
+  },
+  {
+    "id": "365",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "下面哪些图形是轴对称图形。在( )里画'√'错的画*.\n![](images/8fdb99e565c672c48608de503d7febee83834461f34bd59d832f5012dce9397c.jpg)()![](images/e28fe026cee4cf4e840965ebe5633cb9339a2c81b9076e914a5b1c3b4979b279.jpg)( )![](images/734befaa67236ddaa92cc0b8d1dc56ba7c07394599ac5e7bc6198df7169c06d5.jpg)()\n( )",
+    "options": [],
+    "answer": "*;*;√",
+    "solution": "【分析】轴对称图形，是指在平面内沿一条直线折叠，直线两旁的部分能够完全重合的图形，据此得出结论即可.\n【详解】根据分析可得：第三个是轴对称图形。",
+    "knowledge_points": [
+      "轴对称的认识及辨认"
+    ],
+    "source": "23-24 二年级下·甘肃兰州·期中"
+  },
+  {
+    "id": "366",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "下面( )现象属于平移,( )现象属于旋转。(填序号)\n![](images/image-7.png)",
+    "options": [],
+    "answer": "①③⑤;②④",
+    "solution": "【分析】平移是指在平面内，将一个图形上的所有点都按照某个直线方向做相同距离的移动，这样的图形运动叫做图形的平移运动，简称平移。平移后图形的位置改变，形状、大小、方向不变。旋转是指在平面内，将一个图形绕一点按某个方向转动一定的角度。旋转后图形的位置和方向改变，形状、大小不变。\n\n【详解】下面①③⑤现象属于平移，②④现象属于旋转。",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "24-25 二年级下·福建福州·期中"
+  },
+  {
+    "id": "367",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "下面( )是平移现象,( )是旋转现象。(填序号)\n![](images/d9c21f79bd69b6ce7839a0adafa5da7a.png)",
+    "options": [],
+    "answer": "③④;①②",
+    "solution": "【分析】根据给出的图片进行分析：小猴吹风车，风车是围着一个中心进行旋转的；钟表的指针也是围着中心进行旋转；火箭发射是向上的运动；小熊拉车是向前拉，是水平运动。\n\n【详解】据分析可得：下面③④是平移现象，①②是旋转现象。",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "24-25 二年级下·河南信阳·期中"
+  },
+  {
+    "id": "368",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "下列运动中是平移的是( ),是旋转的是( )。(填序号)\n![](images/1009d58283fc7f5786eebdf68d6b96ca.png)",
+    "options": [],
+    "answer": "②③;①④",
+    "solution": "【分析】在平面内，把一个图形整体沿某条直线方向平行移动一定距离的过程，称为平移，例如滑滑梯、电梯的运动等。在平面内，把一个图形围绕某一固定点按顺时针或逆时针方向转动一定的角度的过程，称为旋转，例如摩天轮、旋转木马等。由此解答。\n\n【详解】风车的转动、钟面上指针的转动是旋转现象；高铁的移动、推拉抽屉是平移现象。下列运动中是平移的是②③，是旋转的是①④。",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "24-25 二年级下·山东济宁·期中"
+  },
+  {
+    "id": "369",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "下面是一些交通标志图案，其中是轴对称图形的有( )个。\n![](images/image-8.png)",
+    "options": [],
+    "answer": "3",
+    "solution": "【分析】如果沿某条直线对折，对折的两部分能够完全重合，这样的图形就是轴对称图形。这条直线叫做这个图形的对称轴。判断一个图案是否是轴对称图形，关键是看能否找到这样一条直线，使图形沿着这条直线对折后能够完全重合。\n\n【详解】其中是轴对称图形的有3个。",
+    "knowledge_points": [
+      "轴对称的认识及辨认"
+    ],
+    "source": "24-25 二年级下·福建福州·期末"
+  },
+  {
+    "id": "370",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "风车的转动属于( )现象，拉开抽屉属于( )现象。(填'平移'或'旋转')",
+    "options": [],
+    "answer": "旋转;平移",
+    "solution": "【分析】在平面内，把一个图形整体沿某条直线方向平行移动一定距离的过程，称为平移。常见的平移现象有滑滑梯、电梯的移动等；在平面内，把一个图形围绕某一固定点按顺时针或逆时针方向转动一定的角度的过程，称为旋转。常见的旋转现象有旋转木马、摩天轮等。由此解答。\n\n【详解】根据分析可得：风车的转动属于旋转现象，拉开抽屉属于平移现象。",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "23-24 二年级下·甘肃兰州·期中"
+  },
+  {
+    "id": "371",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "汽车在笔直的马路上行驶是( )现象，而汽车车轮的转动是( )现象。",
+    "options": [],
+    "answer": "平移;旋转",
+    "solution": "【分析】在平面内，一个图形整体沿着某条直线方向平行移动一定距离的过程，称为平移；在平面内，一个图形围绕某一个固定点按照顺时针或者逆时针方向转动一定角度的过程，称为旋转。据此解答。\n\n【详解】根据分析可得：汽车在笔直的马路上行驶是平移现象，而汽车车轮的转动是旋转现象。",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "2025二年级下·全国·专题练习"
+  },
+  {
+    "id": "372",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "风扇扇叶的转动是( )现象：推箱子是( )现象。(填平移或旋转)。",
+    "options": [],
+    "answer": "旋转;平移",
+    "solution": "【分析】在平面内，将一个图形绕一点按某个方向转动一定的角度，这样的运动叫做图形的旋转。旋转后图形的位置和方向改变，形状、大小不变。平移是指在平面内，将一个图形上的所有点都按照某个直线方向做相同距离的移动，这样的图形运动叫做图形的平移运动，简称平移。平移后图形的位置改变，形状、大小、方向不变。\n\n【详解】风扇扇叶的转动是旋转现象；推箱子是平移现象。",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "22-23 二年级下·四川乐山·期末"
+  },
+  {
+    "id": "373",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "拉抽屉是( )现象;车轮转动是( )现象。(填平移或旋转)",
+    "options": [],
+    "answer": "平移;旋转",
+    "solution": "【分析】在平面内，把一个图形整体沿某条直线方向平行移动一定距离的过程，称为平移，常见的平移现象有滑滑梯、电梯的移动等；在平面内，把一个图形围绕某一固定点按顺时针或逆时针方向转动一定的角度的过程，称为旋转，常见的旋转现象有旋转木马、摩天轮等。\n\n【详解】由平移、旋转的特征可知：拉抽屉是平移现象；车轮转动是旋转现象。",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "23-24 二年级下·四川乐山·期末"
+  },
+  {
+    "id": "374",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "升国旗是( )现象，风车转动是( )现象。",
+    "options": [],
+    "answer": "平移;旋转",
+    "solution": "【分析】在平面内，一个图形绕着一个定点旋转一定的角度得到另一个图形的变化叫做旋转。在平面内，将一个图形上的所有点都按照某个方向作相同距离的移动，这样的图形运动叫平移。据此解答。\n\n【详解】由题意分析得：升国旗是平移现象，风车转动是旋转现象。",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "22-23 二年级下·四川凉山·期末"
+  },
+  {
+    "id": "375",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "旋转现象会改变物体原本的形状与大小。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】在平面内，把一个图形围绕某一固定点按顺时针或逆时针方向转动一定的角度的过程，称为旋转。物体或图形旋转后，它们的形状、大小都不改变，只是位置发生了变化，由此解答。\n\n【详解】由分析可知：旋转现象不会改变物体原本的形状与大小。原题说法错误。故答案为：×",
+    "knowledge_points": [
+      "旋转与旋转现象"
+    ],
+    "source": "24-25 二年级下·黑龙江佳木斯·期中"
+  },
+  {
+    "id": "376",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "一个图形旋转后，图形的形状改变了。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】在平面内，把一个图形围绕某一固定点按顺时针或逆时针方向转动一定的角度的过程，称为旋转。物体或图形旋转后，它们的形状、大小都不改变，只是位置和方向发生了变化，由此解答。\n\n【详解】由分析可知：一个图形旋转后，图形的形状没有改变，原题说法错误。故答案为：×",
+    "knowledge_points": [
+      "旋转与旋转现象"
+    ],
+    "source": "24-25 二年级下·贵州铜仁·期中"
+  },
+  {
+    "id": "377",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "钟面上时针，分针的运动是旋转现象。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】在平面内，把一个图形围绕某一固定点按顺时针或逆时针方向转动一定的角度的过程，称为旋转，常见的旋转现象有旋转木马、摩天轮等。\n\n【详解】由分析可知：钟面上时针、分针是绕表盘中心转动的，则时针、分针的运动是旋转现象。原题说法正确。故答案为：√",
+    "knowledge_points": [
+      "旋转与旋转现象"
+    ],
+    "source": "24-25 二年级下·内蒙古通辽·期中"
+  },
+  {
+    "id": "378",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "时钟的分针转动是旋转现象。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】在平面内，把一个图形围绕某一固定点按顺时针或逆时针方向转动一定的角度的过程，称为旋转，常见的旋转现象有旋转木马、摩天轮等，由此解答。\n\n【详解】由分析可知：时钟的分针转动是旋转现象。原题说法正确。故答案为：√",
+    "knowledge_points": [
+      "旋转与旋转现象"
+    ],
+    "source": "24-25 二年级下·广东云浮·期中"
+  },
+  {
+    "id": "379",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "电梯上升是一种平移现象。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】在平面内，把一个图形整体沿某条直线方向平行移动一定距离的过程，称为平移。特点是大小、形状、方向不变，位置变化。常见的平移现象有滑滑梯、推拉窗户等，由此解答。\n\n【详解】由分析可知：电梯上升时，大小、形状、方向不变，只有位置变化，则是一种平移现象。原题说法正确。故答案为：√",
+    "knowledge_points": [
+      "平移与平移现象"
+    ],
+    "source": "24-25二年级下·湖北省直辖县级单位·期中"
+  },
+  {
+    "id": "380",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "钟表面上时针和分针的运动现象是旋转。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】旋转是指在平面内将一个图形绕一点按某个方向转动一个角度，这样的运动叫做图形的旋转运动。\n\n【详解】根据旋转的特点可知：钟表面上时针和分针的运动现象是旋转，原说法正确。故答案为：√",
+    "knowledge_points": [
+      "旋转与旋转现象"
+    ],
+    "source": "24-25 二年级下·山东菏泽·期中"
+  },
+  {
+    "id": "381",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "电梯运行是平移现象。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】在平面内，一个图形整体沿着某条直线方向平行移动一定距离的过程，称为平移，电梯运行是平移现象。\n\n【详解】由分析可知：电梯运行是平移现象。故答案为：√",
+    "knowledge_points": [
+      "平移与平移现象"
+    ],
+    "source": "24-25 二年级下·江西赣州·期中"
+  },
+  {
+    "id": "382",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "汽车沿直线行驶时，车轮的运动是旋转现象，车身的运动是平移现象。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】在平面内，把一个图形整体沿某条直线方向平行移动一定距离的过程，称为平移；在平面内，把一个图形围绕某一固定点按一定的方向转动一定的角度的过程，称为旋转。因此汽车沿直线行驶时，车轮的运动是旋转现象，车身的运动是平移现象。\n\n【详解】由分析可知：汽车沿直线行驶时，车轮的运动是旋转现象，车身的运动是平移现象。说法正确。故答案为：√",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "24-25二年级下·湖北武汉·期中"
+  },
+  {
+    "id": "383",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "卫星发射升空是平移现象，卫星绕地球飞行是旋转现象。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】平移是指物体在平面内沿着某个方向移动，移动过程中物体的形状、大小和方向都不发生变化。例如：推拉抽屉、电梯上下移动、火车在直轨上行驶等。旋转是指物体绕着一个固定点转动，转动过程中物体的形状和大小不变，但方向会发生变化。例如：风车转动、钟表的指针转动、旋转木马等。\n\n【详解】根据旋转、平移的特点可知：卫星发射升空是平移现象，卫星绕地球飞行是旋转现象。原题说法正确。故答案为：√",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "24-25二年级下·湖南岳阳·期中"
+  },
+  {
+    "id": "384",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "“中”“国”“田”“土”这四个汉字都可以看作是轴对称图形。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】在平面内，如果一个图形沿一条直线折叠，直线两旁的部分能够完全重合，这样的图形就叫做轴对称图形。据此判断一个图形是否是轴对称图形。\n\n【详解】由题意分析得：“中”“国”“田”“土”这四个汉字中，“国”字不是轴对称图形，原题说法错误。故答案为：×",
+    "knowledge_points": [
+      "轴对称的认识及辨认"
+    ],
+    "source": "24-25 二年级下·山东济宁·期末"
+  },
+  {
+    "id": "385",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "向前推箱子和拧开饮料瓶的盖子都是旋转现象。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】平移是指在平面内将一个图形上的所有点都按照某个直线方向做相同距离的移动，这样的运动叫做图形的平移运动，所以向前推箱子是平移。旋转是指在平面内将一个图形绕一点按某个方向转动一个角度，这样的运动叫做图形的旋转运动，所以拧开饮料瓶的盖子是旋转。\n\n【详解】由分析可知：向前推箱子是平移现象，拧开饮料瓶的盖子是旋转现象。原题说法错误。故答案为：×",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "24-25 二年级下·山东济宁·期末"
+  },
+  {
+    "id": "386",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "是从对折后的纸上剪下来的。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】一个图形沿一条直线对折，直线两旁的图形能够完全重合，这样的图形叫轴对称图形。根据题意，把原图自上而下沿着中间对折，再与剪刀痕迹处比较即可解答。\n\n【详解】根据分析，动手操作一下，原图对折后得到的一半能够与另一半完全重合。原题说法正确。故答案为：√",
+    "knowledge_points": [
+      "轴对称的剪纸问题"
+    ],
+    "source": "24-25二年级下·河北邢台·期末"
+  },
+  {
+    "id": "387",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "它们都是轴对称图形。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】如果沿某条直线对折，对折的两部分能够完全重合，这样的图形是轴对称图形。这条直线是这个图形的对称轴。由此找出图形的对称轴即可解答。\n\n【详解】图1、图3有对称轴，是轴对称图形；图2没有对称轴，不是轴对称图形。原题说法错误。故答案为：×",
+    "knowledge_points": [
+      "轴对称的认识及辨认"
+    ],
+    "source": "24-25 二年级下·广东江门·期末"
+  },
+  {
+    "id": "388",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "车轮运动的现象是旋转，在笔直的路上，整个车身的运动现象是平移。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】在平面内，把一个图形整体沿某条直线方向平行移动一定距离的过程，称为平移；在平面内，把一个图形围绕某一固定点按顺时针或逆时针方向转动一定的角度的过程，称为旋转。需要根据车轮和车身的运动特点，判断它们分别属于哪种现象。\n\n【详解】根据分析可得：车轮运动的现象是旋转，在笔直的路上，整个车身的运动现象是平移。原题说法正确。故答案为：√",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "24-25 二年级下·山东济南·期末"
+  },
+  {
+    "id": "389",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "轴对称，平移和旋转都是图形的运动方式。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】把一个图形沿着某一条直线折叠，如果它能够与另一个图形重合，那么就说这两个图形关于这条直线对称。在这个过程中，图形的形状和大小都没有发生改变，只是图形的位置发生了相对的变化，也是一种图形运动方式。在平面内，把一个图形整体沿某条直线方向平行移动的过程，称为平移。在平面内，把一个图形围绕某一固定点按顺时针或逆时针方向转动一定的角度的过程，称为旋转。\n\n【详解】图形的运动包括轴对称、平移和旋转三种方式，原说法正确。故答案为：√",
+    "knowledge_points": [
+      "轴对称的认识及辨认",
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "24-25 二年级下·山东济南·期末"
+  },
+  {
+    "id": "390",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "可以通过平移得到。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】把一个图形整体沿某一方向移动一定的距离，图形的这种移动叫做平移，平移后图形的位置改变，形状、大小和方向不变；在平面内，把一个图形围绕某一固定点按顺时针或逆时针方向转动一定的角度的过程，称为旋转。据此解答。\n\n【详解】图中图形不能只通过平移得到，还可以通过旋转得到。因此原题说法错误。故答案为：×",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "24-25二年级下·河南南阳·期末"
+  },
+  {
+    "id": "391",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "是从上剪下来的。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】剪下来的图形左右两边都有3个白色的正方形，据此比较求解。\n\n【详解】不是从上剪下来的，原题说法错误。故答案为：×",
+    "knowledge_points": [
+      "轴对称的剪纸问题"
+    ],
+    "source": "24-25 二年级下·河南·期中"
+  },
+  {
+    "id": "392",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "行驶中的汽车车轮在做旋转运动。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】旋转是指图形绕着一个定点按一定方向转动。汽车行驶时，车轮绕车轴转动，符合旋转的特点。\n\n【详解】汽车行驶时，车轮是绕着车轴这个定点转动的，所以行驶中的汽车车轮在做旋转运动。该说法正确。故答案为：√",
+    "knowledge_points": [
+      "旋转与旋转现象"
+    ],
+    "source": "2023·河北石家庄·小升初真题"
+  },
+  {
+    "id": "393",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "风车转动10圈后变小了。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】在平面内，一个图形围绕某一个固定点按照顺时针或者逆时针方向转动一定的角度的过程，称为旋转。风车转动是旋转现象，无论转多少圈，风车的大小都不会变化，据此解答。\n\n【详解】根据分析可得：风车转动10圈后，风车的大小不会变化。原题说法错误。故答案为：×",
+    "knowledge_points": [
+      "旋转与旋转现象"
+    ],
+    "source": "2025 二年级下·全国·专题练习"
+  },
+  {
+    "id": "394",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "开关电梯门，推拉抽屉，升降国旗都属于平移现象。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】在平面内，把一个物体或一个图形整体沿某条直线方向平行移动一定距离的过程，称为平移。据此解答。\n\n【详解】开关电梯门时，门沿着轨道运动；推拉抽屉时，抽屉沿着轨道运动；升降国旗时，国旗上下移动。所以开关电梯门、推拉抽屉、升降国旗都属于平移现象。原题说法正确。故答案为：√",
+    "knowledge_points": [
+      "平移与平移现象"
+    ],
+    "source": "24-25 三年级上·山东济宁·期末"
+  },
+  {
+    "id": "395",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "是轴对称图形。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】如果沿某条直线对折，对折的两部分能够完全重合，这样的图形就是轴对称图形。这条直线叫做这个图形的对称轴。判断一个图案是否是轴对称图形，关键是看能否找到一条直线，使图形沿着这条直线对折后能够完全重合。\n\n【详解】不是轴对称图形。原题说法错误。故答案为：×",
+    "knowledge_points": [
+      "轴对称的认识及辨认"
+    ],
+    "source": "19-20 三年级下·四川·单元测试"
+  },
+  {
+    "id": "396",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "将旋转，就可得到。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】在平面内，将一个图形绕一点按某个方向转动一定的角度，这样的运动叫做图形的旋转。旋转后图形的位置和方向改变，形状、大小不变。\n\n【详解】图形形状发生了变化，不能由旋转得到。原题说法错误。故答案为：×",
+    "knowledge_points": [
+      "旋转与旋转现象"
+    ],
+    "source": "22-23 二年级下·四川南充·期末"
+  },
+  {
+    "id": "397",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "旋转后图形的大小，形状，方向都不会发生改变。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】在平面内，将一个图形绕一点按某个方向转动一定的角度，这样的运动叫做图形的旋转。旋转后图形的位置和方向改变，形状、大小不变。\n\n【详解】旋转后图形的大小、形状不会发生改变，方向会发生变化。原题说法错误。故答案为：×",
+    "knowledge_points": [
+      "旋转与旋转现象"
+    ],
+    "source": "23-24 二年级下·四川绵阳·期中"
+  },
+  {
+    "id": "398",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "客车在笔直的公路上行驶，车身的运动是平移现象，车轮的运动是旋转现象。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】本题主要考查对平移和旋转这两种运动现象的理解，需要根据车轮和车身的运动特点，判断它们分别属于哪种现象。\n\n【详解】在平面内，把一个图形整体沿某条直线方向平行移动一定距离的过程，称为平移；在平面内，把一个图形围绕某一固定点按顺时针或逆时针方向转动一定的角度的过程，称为旋转。因此，客车在笔直的公路上行驶时，车身运动属于平移现象，车轮运动属于旋转现象。故答案为：√",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "18-19 二年级下·全国·单元测试"
+  },
+  {
+    "id": "399",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "汽车在笔直的马路上行驶是平移现象，车轮的转动是旋转现象。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】在平面内，把一个图形整体沿某条直线方向平行移动一定距离的过程，称为平移，常见的平移现象有滑滑梯、电梯的移动等；在平面内，把一个图形围绕某一固定点按顺时针或逆时针方向转动一定的角度的过程，称为旋转，常见的旋转现象有旋转木马、摩天轮等，由此解答。\n\n【详解】由分析可知，汽车在笔直的马路上行驶是平移现象，车轮的转动是旋转现象。原题说法正确。故答案为：√",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "23-24 二年级下·河南南阳·期末"
+  },
+  {
+    "id": "400",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "图形平移后形状和大小都不变，而汽车方向盘的转动属于平移现象。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】在平面内，把一个图形整体沿某条直线方向平行移动一定距离的过程，称为平移。常见的平移现象有滑滑梯、推拉窗户等；物体或图形平移后，它们的形状、大小、方向都不改变，只是位置发生了变化。在平面内，把一个图形围绕某一固定点按顺时针或逆时针方向转动一定的角度的过程，称为旋转。常见的旋转现象有旋转木马、摩天轮等，由此解答。\n\n【详解】由分析可知，图形平移后形状和大小都不变，而汽车方向盘的转动属于旋转现象，原题说法错误。故答案为：×",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "23-24 二年级下·贵州铜仁·期末"
+  },
+  {
+    "id": "401",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "用下面的硬纸板和火柴棍制成不同形状的陀螺(图中的点表示火柴棍扎的位置),转得最稳的是( )。",
+    "options": [
+      "A. ![](images/53737a1cedad2b633517f8f2e84e4eec4781f81c963ab40bea5baf8d9e7908e7.jpg)",
+      "B. ![](images/9b11f21569f19b3d3f1aaecabe39fcfb7bc52e5504f18e46dbbd72cb0d781282.jpg)",
+      "C. ![](images/fe74c48fdc315a81cb0b927e114f27248d35f4fc2aa63cf037d00170c74da04e.jpg)",
+      "D. ![](images/3803d29117cd601acfbbbed9273163dbcc337fac15388762ed296d2f5cb1e668.jpg)"
+    ],
+    "answer": "C",
+    "solution": "【分析】圆形的中心到圆上的距离都相等，所以把火柴棍扎在圆形的中心位置，制成的陀螺转得最稳。\n\n【详解】A. 图中心到四周的距离不等，转得不稳；B. 图中心到四周的距离不等，转得不稳；C. 图中圆的中心到四周的距离相等，转得最稳；D. 图中心到四周的距离不等，转得不稳。故答案为：C",
+    "knowledge_points": [
+      "旋转与旋转现象"
+    ],
+    "source": "23-24二年级上·广东深圳·期中"
+  },
+  {
+    "id": "402",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "用圆形硬纸板和火柴棍制作陀螺，火柴棍扎在( )位置时，陀螺转得最稳。",
+    "options": [
+      "A. ![](images/11cec622d8508f3deebef7735c4f9511e36bc6f18da56cbd5bd532d60c7ed30d.jpg)",
+      "B. ![](images/974efb87c87b514d727555140bcd318acc2895b7580320610ccf0ac10a91b116.jpg)",
+      "C. ![](images/5e8915793928398275c4a32a42688ecb7e590668fbef5bc49849f9bde0481073.jpg)"
+    ],
+    "answer": "B",
+    "solution": "【分析】用圆形硬纸板和火柴棍制作陀螺时，火柴棍扎在圆心的位置最稳。\n\n【详解】用圆形硬纸板和火柴棍制作陀螺，火柴棍扎在圆心位置时，陀螺转得最稳。故答案为：B",
+    "knowledge_points": [
+      "圆的概念及特点"
+    ],
+    "source": "23-24 二年级上·河南驻马店·期中"
+  },
+  {
+    "id": "403",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "下面图形中，不是轴对称图形的是( )。",
+    "options": [
+      "A. ![](images/a6003e4b222348d71498c907fd80716988d6b44109337214bdb1610e9dbacf78.jpg)",
+      "B. ![](images/4f921c5b00bd6c50e50fec64c9635b767568433f59a8fe212d216ed4170580cb.jpg)",
+      "C. ![](images/4494416376a7520fd4ce5485d3024d2f3717bfef1909a1368702e198c3a406a8.jpg)",
+      "D. ![](images/b82a771e0d7699d81a2dade8b30489bd0d5c12ae51065cfa098b8056b394c28f.jpg)"
+    ],
+    "answer": "A",
+    "solution": "【分析】一个图形沿一条直线对折，直线两旁的图形能够完全重合，这样的图形叫做轴对称图形，折痕所在的直线就是对称轴。据此解答。\n\n【详解】A. 平行四边形不是轴对称图形；B. 是轴对称图形；C. 是轴对称图形；D. 是轴对称图形。故答案为：A",
+    "knowledge_points": [
+      "轴对称的认识及辨认"
+    ],
+    "source": "23-24 四年级下·四川广元·期末"
+  },
+  {
+    "id": "404",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "如图，纸上能剪下的图案是( )。\n![](images/21d7904d575f9e68036d359b1ca80e4eb324c16039a692a8f3551867ca0dc452.jpg)",
+    "options": [
+      "A. ![](images/38b6a89aa123da734e94a6a5c8be8c2a30606791502383826835fdead7869751.jpg)",
+      "B. ![](images/d9e7bada73a0b319b73d82bbf189ee0e39ff79b8821af88f07aa73beb1109ea8.jpg)",
+      "C. ![](images/9149b5ccaf6d599bf3ebcdbf857c801eebf773789486a3cf404cfd5dec106520.jpg)"
+    ],
+    "answer": "C",
+    "solution": "【分析】把一个图形沿着某一条直线折叠，如果直线两旁的部分能够互相重合，那么这个图形就是轴对称图形，这条直线就是对称轴。\n\n【详解】图纸上能剪下的图案是C。故答案为：C",
+    "knowledge_points": [
+      "轴对称的剪纸问题"
+    ],
+    "source": "23-24 二年级上·河南商丘·期中"
+  },
+  {
+    "id": "405",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "下面( )形状的陀螺转得最稳。",
+    "options": [
+      "A. ![](images/c63c36914a977329dd8ea2226ea8d9aa4d093f05c0e5cf2d394783c634d1d4fd.jpg)",
+      "B. ![](images/09d753d67ccc19da2c1bf1c2e01998f3354533b5ac8fc73523c1eca0e33a776a.jpg)",
+      "C. ![](images/0e87809d708be6ce9c05674ce74fd59d387317a30ca1aed779b6383babf18105.jpg)"
+    ],
+    "answer": "B",
+    "solution": "【分析】陀螺要想转得稳，小棒到纸板各个点的距离应尽量相等，圆形最适合做陀螺，据此解答即可。\n\n【详解】由分析可得，B的陀螺转得最稳。故答案为：B",
+    "knowledge_points": [
+      "旋转与旋转现象"
+    ],
+    "source": "23-24二年级上·河南商丘·期中"
+  },
+  {
+    "id": "406",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "用硬纸板和火柴棍制作陀螺，下面( )种形状的陀螺转得最稳。",
+    "options": [
+      "A. ![](images/3052848601f39622881d85316ba0f08f3f54f9c2fb8e0f71a30bd3e91b479445.jpg)",
+      "B. ![](images/7d7bb2823a1dc166cbc35d0096e876348a7d9cf6705ec8ddb1dcf0b639d6d050.jpg)",
+      "C. ![](images/afc7f824af80f1902943966b2a2fd0a4d5abea250275cb1d7bb209d5fe3c0dda.jpg)"
+    ],
+    "answer": "C",
+    "solution": "【分析】要想转得最稳，这个图形的中心到四周的距离应相等，由此解答。\n\n【详解】A. 图中心到四周的距离不相等，转得不稳；B. 图中心到四周的距离不相等，转得不稳；C. 图中心到四周的距离相等，转得最稳。所以用C制作的陀螺转得最稳。故答案为：C",
+    "knowledge_points": [
+      "旋转与旋转现象"
+    ],
+    "source": "23-24二年级上·山西朔州·期中"
+  },
+  {
+    "id": "407",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面图形中是轴对称图形的有( )个。\n![](images/136e3eba9d7f966fc28d964cfca7d426.png)",
+    "options": [
+      "A. 2",
+      "B. 3",
+      "C. 4"
+    ],
+    "answer": "B",
+    "solution": "【分析】如果一个图形沿着一条直线对折，两侧的图形能够完全重合，这个图形就是轴对称图形。\n\n【详解】由分析可得：梳子不是轴对称图形，其他三个都是轴对称图形。轴对称图形有3个。故答案为：B",
+    "knowledge_points": [
+      "轴对称的认识及辨认"
+    ],
+    "source": "23-24二年级下·湖北恩施·期末"
+  },
+  {
+    "id": "408",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下图中可以通过平移和原图重合的有( )条。\n![](images/c56e9c604663547efd2d612ee20a3de33d26abaefc62c8f46a210ecfb842eb6d.jpg)",
+    "options": [
+      "A. 1",
+      "B. 3",
+      "C. 4",
+      "D. 5"
+    ],
+    "answer": "B",
+    "solution": "【分析】平移后图形的位置改变，形状、大小、方向不变。\n\n【详解】下图中可以通过平移和原图重合的有3条。故答案为：B",
+    "knowledge_points": [
+      "平移与平移现象"
+    ],
+    "source": "23-24 二年级下·福建漳州·期末"
+  },
+  {
+    "id": "409",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "下面的图形中，( )不是轴对称图形。",
+    "options": [
+      "A. ![](images/90bbdb6f0da32aa9c82181cea53690d0e4bc507c49b7f5a616f8db535f09edc2.jpg)",
+      "B. ![](images/fc58a7df9df22cdaa24e7d7e8f6507a39b2685df0b6ff372f2cec060678317e6.jpg)",
+      "C. ![](images/5448aeb471c0e95334cc8819ef7e0f9e57f8fc7133f1c4cc2d3adf95ac0f80a3.jpg)"
+    ],
+    "answer": "C",
+    "solution": "【分析】如果沿某条直线对折，对折的两部分能够完全重合，这样的图形就是轴对称图形。这条直线叫做这个图形的对称轴。判断一个图案是否是轴对称图形，关键是看能否找到一条直线，使图形沿着这条直线对折后能够完全重合。\n\n【详解】A. 是轴对称图形；B. 是轴对称图形；C. 不是轴对称图形。故答案为：C",
+    "knowledge_points": [
+      "轴对称的认识及辨认"
+    ],
+    "source": "23-24 二年级下·河南商丘·期末"
+  },
+  {
+    "id": "410",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "下面的图案中，图形甲到乙的运动可以通过平移得到的是( )。",
+    "options": [
+      "A. ![](images/396c2fb50defd0859a9c018ce084deb72d93647bf4f637f15e37284d8f2c25be.jpg)",
+      "B. ![](images/ba97c0c07f25f5c8b6c51e77429f70e7a1d5deae40b81f99b2e82095939acb7f.jpg)",
+      "C. ![](images/e50c30341e5b56c0ae334343f4705b94d66260282e4a3aec03376ea11853be76.jpg)"
+    ],
+    "answer": "C",
+    "solution": "【分析】平移后图形的位置改变，形状、大小、方向不变。\n\n【详解】A. 甲到乙方向变了，不可以通过平移得到；B. 甲到乙方向变了，不可以通过平移得到；C. 甲到乙的运动可以通过平移得到。故答案为：C",
+    "knowledge_points": [
+      "平移与平移现象"
+    ],
+    "source": "23-24 二年级下·山西长治·期末"
+  },
+  {
+    "id": "411",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "下列运动中，不是旋转的是( )。",
+    "options": [
+      "A. ![](images/f00181790da4832086a66ed07410e142caae217c56adc6e2322283f99d6e6186.jpg)",
+      "B. ![](images/840dd975a29411029a08338bb0b271feb0be3f95d927e6fe540a8bcfb313d384.jpg)",
+      "C. ![](images/335cd471414a8ce0b0e5f58924d64d55ad6686d7d5f45b7fe587e900699283ee.jpg)"
+    ],
+    "answer": "B",
+    "solution": "【分析】平移和旋转都是物体或图形的位置发生变化而形状、大小不变。区别在于，平移时物体沿直线运动，本身方向不发生改变；旋转是物体绕着某一点或轴运动，本身方向发生变化。据此解答即可。\n\n【详解】A. 是旋转运动，不符合题意；B. 是平移运动，符合题意；C. 是旋转运动，不符合题意。故答案为：B",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "23-24 二年级下·湖南郴州·期末"
+  },
+  {
+    "id": "412",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面物体一共有( )个是旋转现象的。\n![](images/image-9.png)",
+    "options": [
+      "A. 3",
+      "B. 4",
+      "C. 5"
+    ],
+    "answer": "A",
+    "solution": "【分析】在平面内，一个图形绕着一个定点转动一定的角度，这样的变化叫做旋转；将一个图形沿某个方向作相同距离的移动，这样的运动叫平移。据此解答。\n\n【详解】由题意分析得：平移现象有滑滑梯、拨算珠、推拉窗；旋转现象有风车、陀螺、风扇。一共有3个是旋转现象。故答案为：A",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "23-24 二年级下·浙江台州·期末"
+  },
+  {
+    "id": "413",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "甲骨文是我国的一种古代文字，是汉字的早期形式。下面( )是通过平移得到完整的文字。",
+    "options": [
+      "A. ![](images/f05a475276ab66deb2adbb14baedb869a0c41eb42d12cd5e1cdd786d874d3f51.jpg)",
+      "B. ![](images/f2164ae280cc1f980b406198308064165c602b030de1b5903e946a46889e16f6.jpg)",
+      "C. ![](images/5d13afff816d787200ed132667c8eccd219458c7c900336de683eedc07801d8f.jpg)",
+      "D. ![](images/fe761c9bf9074c40c94daf088dab5d0294fd8e6215855e44945dea4aeae8ac5a.jpg)"
+    ],
+    "answer": "B",
+    "solution": "【分析】平移后图形的位置改变，形状、大小、方向不变。据此解答。\n\n【详解】A. 此文字不可以通过平移得到；B. 此文字可以通过平移得到；C. 此文字不可以通过平移得到；D. 此文字不可以通过平移得到。故答案为：B",
+    "knowledge_points": [
+      "平移与平移现象"
+    ],
+    "source": "23-24二年级下·福建福州·期末"
+  },
+  {
+    "id": "414",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下图中轴对称图形有( )个。\n![](images/image-10.png)",
+    "options": [
+      "A. 4个",
+      "B. 3个",
+      "C. 2个"
+    ],
+    "answer": "B",
+    "solution": "【分析】一个图形沿一条直线对折，直线两旁的图形能够完全重合，这样的图形就是轴对称图形，折痕所在的直线就是对称轴。据此判断即可。\n\n【详解】图1、图3、图5有对称轴，是轴对称图形。轴对称图形有3个。故答案为：B",
+    "knowledge_points": [
+      "轴对称的认识及辨认"
+    ],
+    "source": "23-24 二年级下·湖南衡阳·期末"
+  },
+  {
+    "id": "415",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面不是轴对称图形的是( )。",
+    "options": [
+      "A. ![](images/d86712d52c66a6b758964c05f70e55d82ed85763bbef908cadb82b3c8c899dac.jpg)",
+      "B. ![](images/430445af24d1bc44fdfff17ad2f6ff7ed2c6e6c69a102bb8365606daf3929c31.jpg)",
+      "C. ![](images/183e4c2789cfcfe624b04534a335b083a1ebcf08179bc3ad280ded586fdd0cf9.jpg)"
+    ],
+    "answer": "B",
+    "solution": "【分析】一个图形沿着一条直线对折后，两边能够完全重合，这个图形就是轴对称图形，折痕所在的直线就是对称轴，据此解答即可。\n\n【详解】A. 可以找到一条直线对折后两边完全重合，是轴对称图形；B. 不能找到一条直线对折后两边完全重合，不是轴对称图形；C. 可以找到一条直线对折后两边完全重合，是轴对称图形。故答案为：B",
+    "knowledge_points": [
+      "轴对称的认识及辨认"
+    ],
+    "source": "23-24 二年级下·福建福州·期末"
+  },
+  {
+    "id": "416",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面属于平移现象的是( )。",
+    "options": [
+      "A. 风扇扇叶的转动",
+      "B. 电梯上下移动",
+      "C. 车轮转动"
+    ],
+    "answer": "B",
+    "solution": "【分析】平移和旋转都是物体或图形的位置发生变化而形状、大小不变。区别在于，平移时物体沿直线运动，本身方向不发生改变；旋转是物体绕着某一点或轴运动，本身方向发生变化。据此解答即可。\n\n【详解】A. 风扇扇叶的转动是旋转现象，不符合题意；B. 电梯上下移动是平移现象，符合题意；C. 车轮转动是旋转现象，不符合题意。故答案为：B",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "23-24 二年级下·福建福州·期末"
+  },
+  {
+    "id": "417",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面现象中属于平移的是( )。",
+    "options": [
+      "A. 荡秋千",
+      "B. 电梯上升",
+      "C. 风扇转动"
+    ],
+    "answer": "B",
+    "solution": "【分析】在平面内，一个图形绕着一个定点转动一定的角度，这样的变化叫做旋转；将一个图形上的所有点都按照某个方向作相同距离的移动，这样的运动叫平移。据此判断。\n\n【详解】A. 荡秋千属于旋转现象；B. 电梯上升属于平移现象；C. 风扇转动属于旋转现象。故答案为：B",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "23-24二年级下·河北邯郸·期末"
+  },
+  {
+    "id": "418",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "汽车沿直线向前行驶，车身的运动是( )。",
+    "options": [
+      "A. 旋转",
+      "B. 平移",
+      "C. 对称"
+    ],
+    "answer": "B",
+    "solution": "【分析】平移后图形的位置改变，形状、大小、方向不变；旋转前后图形的位置和方向改变，形状、大小不变。\n\n【详解】据分析可知：汽车沿直线向前行驶，车身的运动是平移。故答案为：B",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "23-24二年级下·山东临沂·期末"
+  },
+  {
+    "id": "419",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面的图形中，( )不是轴对称图形。",
+    "options": [
+      "A. ![](images/ce5c71ccaa83452bfb8294baa76d55a2a8f15c1d8be2247f9467d8cd523dbcda.jpg)",
+      "B. ![](images/d3793943a582dc20bae9cd682cd693ef458433b25482c9f9214e35b33b8e1c65.jpg)",
+      "C. ![](images/ec274cd01890341be6396ac6cfcacbe1721ab389f788ad054daf52c6122c4346.jpg)"
+    ],
+    "answer": "B",
+    "solution": "【分析】一个图形沿一条直线对折，直线两旁的图形能够完全重合，这样的图形就是轴对称图形，折痕所在的直线就是对称轴，据此判断即可。\n\n【详解】A. 有对称轴，是轴对称图形；B. 没有对称轴，不是轴对称图形；C. 有对称轴，是轴对称图形。故答案为：B",
+    "knowledge_points": [
+      "轴对称的认识及辨认"
+    ],
+    "source": "23-24 二年级下·河南周口·期末"
+  },
+  {
+    "id": "420",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面三幅图中，图( )是通过左图平移得到的。\n![](images/cf4b76b2281d3568589238e25cd520896a3599ea822884386a875e04522fc1d2.jpg)",
+    "options": [
+      "A. ![](images/b31da0b42947b44e620e021a9889b25837be46b736648ae66b34e9afca6ff20f.jpg)",
+      "B. ![](images/c725928b12aab4223cf17e52bb4da2f411c814821cf9cf142940ca6ffee2f878.jpg)",
+      "C. ![](images/6384963760c6ba09040dff0c44e329827d3d5ac884a5382c16ac97489b614160.jpg)"
+    ],
+    "answer": "A",
+    "solution": "【分析】物体或图形平移后，形状、大小、方向都不改变，只是位置发生变化。由此解答。\n\n【详解】A. 形状、大小、方向都没改变，是平移；B. 方向发生了变化，不是平移；C. 方向发生了变化，不是平移。A是通过左图平移得到的。故答案为：A",
+    "knowledge_points": [
+      "平移与平移现象"
+    ],
+    "source": "23-24 二年级下·广东江门·期末"
+  },
+  {
+    "id": "421",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下列运动中，不是旋转的是( )。",
+    "options": [
+      "A. ![](images/66a3b1dba56a363782d5b4a1771abdb9890084a60fb901f355971aac7792bf51.jpg)",
+      "B. ![](images/343e15b1ffb8b2807089081eea4ba410e2c3100f4bafc71e652a6889e9bcbd31.jpg)",
+      "C. ![](images/dff1cb9d00bacb1a0930bbcc150bd3ac30c1ea2e77ba9738f616658cfeaf3e66.jpg)"
+    ],
+    "answer": "A",
+    "solution": "【分析】平移和旋转都是物体或图形的位置发生变化而形状、大小不变。区别在于，平移时物体沿直线运动，本身方向不发生改变；旋转是物体绕着某一点或轴运动，本身方向发生变化。据此解答即可。\n\n【详解】A. 拨算盘是平移运动，符合题意；B. 开关门是旋转运动，不符合题意；C. 滚轮子是旋转运动，不符合题意。故答案为：A",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "23-24 二年级下·湖北荆门·期末"
+  },
+  {
+    "id": "422",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面( )图形是由原图平移得到的。\n![](images/a9ba223a0bfaa8c451ef29df7007b6748de52891135183e33d86e0a74f5c611e.jpg)",
+    "options": [
+      "A. ![](images/59f5979a9b955e2d935693c2114e228c78acbc6f58dff2cc720f9fa42a4b1991.jpg)",
+      "B. ![](images/f73db146adfcd42660437dfee549ce9faf7ae6cb23361728c30468e6c66d2d4a.jpg)",
+      "C. ![](images/5b0e71dc9ac16c33a1a957a5c5dd1fc78ddeb2eb1eb5c08c632c6d936c077c84.jpg)"
+    ],
+    "answer": "A",
+    "solution": "【分析】物体或图形平移后，它们的形状、大小、方向都不改变，只是位置发生变化。由此解答。\n\n【详解】A. 形状、大小、方向都没发生变化，是平移；B. 方向发生了变化，不是平移；C. 方向发生了变化，不是平移。所以A是由原图平移得到的。故答案为：A",
+    "knowledge_points": [
+      "平移与平移现象"
+    ],
+    "source": "23-24 二年级下·山东济宁·期末"
+  },
+  {
+    "id": "423",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "图形( )是下边三角板平移后得到的图形。\n![](images/0e52efe4b45ad63ea4ccbd92a81432cdbc690dd06ffdde7d07f2de837d0a9b40.jpg)",
+    "options": [
+      "A. ![](images/0a4984c89f34f9fa3650047d2536ac26bb82be0ca5c46ca09634ebba61aaef06.jpg)",
+      "B. ![](images/d752c842743076079ffc4d152f44ebae76b89d6e53202bc4d01735bf46f2463e.jpg)",
+      "C. ![](images/1ed8e7c4ef97120d564f5da669120efa7d83111b31561612278d4d4250a414e7.jpg)"
+    ],
+    "answer": "C",
+    "solution": "【分析】物体或图形平移后，它们的形状、大小、方向都不改变，只是位置发生变化。由此解答。\n\n【详解】A. 三角板方向发生了变化，不是平移；B. 三角板方向发生了变化，不是平移；C. 三角板形状、大小、方向都没发生变化，是平移。所以C是平移后得到的图形。故答案为：C",
+    "knowledge_points": [
+      "平移与平移现象"
+    ],
+    "source": "23-24二年级下·湖南衡阳·期末"
+  },
+  {
+    "id": "424",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "轴对称图形有( )个。\n![](images/cba9e7898827ce0bd6eb6656d2ece16b07a70c77453b1fd2e7599cf0826c5125.jpg)\n![](images/5cc9a413cecf11094999d06d91b19ef59391aa906751f91802665314c18f9294.jpg)\n![](images/272e520df96d7bd8c33d8169c0d85c00ff0d931d45c2f64fe3422f0d0099e453.jpg)\n![](images/a863711af84160dbb078889f0ea02983a4620f03f76c1cb1b8f66803c0fd596b.jpg)",
+    "options": [
+      "A. 2个",
+      "B. 3个",
+      "C. 4个"
+    ],
+    "answer": "B",
+    "solution": "【分析】一个图形沿一条直线对折，直线两旁的图形能够完全重合，这样的图形就是轴对称图形，折痕所在的直线就是对称轴。据此判断即可。\n\n【详解】图1、图2、图3有对称轴，是轴对称图形；图4没有对称轴，不是轴对称图形。所以轴对称图形有3个。故答案为：B",
+    "knowledge_points": [
+      "轴对称的认识及辨认"
+    ],
+    "source": "23-24二年级下·湖南衡阳·期末"
+  },
+  {
+    "id": "425",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "琪琪画了三个奥运会项目的简笔画，其中是轴对称图形的是( )。",
+    "options": [
+      "A. ![](images/2caa53f58e33e9303da8d2e1d2433a39d498dda820c5e72c0bea3edeb6a609e8.jpg)",
+      "B. ![](images/b36d43816d173fc2ac8262c73fdc4e154def7e2a39408a74ab590ccfde97ad98.jpg)",
+      "C. ![](images/2978d6ed87b8e297a0db888fb7763a219c53098f671d499da94e63cd541acde7.jpg)"
+    ],
+    "answer": "C",
+    "solution": "【分析】一个图形沿一条直线对折，直线两旁的图形能够完全重合，这样的图形就是轴对称图形，折痕所在的直线就是对称轴。据此进行判断即可。\n\n【详解】A. 不是轴对称图形；B. 不是轴对称图形；C. 是轴对称图形。故答案为：C",
+    "knowledge_points": [
+      "轴对称的认识及辨认"
+    ],
+    "source": "23-24 二年级下·山东济南·期末"
+  },
+  {
+    "id": "426",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "下边的哪个图案是通过平移下面的图案得到的。( )\n![](images/de2648e7c16fbe85de6871c0b6b043806dd91853de021b53d7736c6379edf4a8.jpg)",
+    "options": [
+      "A. ![](images/09183273c762008efec1246a26cb8d4df73d97e8fad0dadd208671ffc30d70d4.jpg)",
+      "B. ![](images/65401f24a6dba07069eacbe54b9bf4539c1f2aeaf9bf4c6e3f0d07e4f8c05d2b.jpg)",
+      "C. ![](images/d37d028c5f1306415ab28d070e68e79029bc482dbb6711f4af6e2cd9df9496b6.jpg)"
+    ],
+    "answer": "B",
+    "solution": "【分析】在平面内，将一个图形沿某个方向移动一定的距离，这样的图形运动叫做平移。平移不改变图形的形状和大小。\n\n【详解】A. 改变了形状，不属于平移；B. 没有改变图形的形状和大小，符合题意；C. 改变了形状，不属于平移。故答案为：B",
+    "knowledge_points": [
+      "平移与平移现象"
+    ],
+    "source": "23-24 二年级下·山东菏泽·期末"
+  },
+  {
+    "id": "427",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "下面的运动现象中，平移的有( )个，旋转的有( )个。\n![](images/b617515abd1d2cc79ee505aa20e699a6.png)",
+    "options": [
+      "A. 2;5",
+      "B. 3;4",
+      "C. 4;4",
+      "D. 5;2"
+    ],
+    "answer": "C",
+    "solution": "【分析】平移和旋转都是物体或图形的位置发生变化而形状、大小不变。区别在于，平移时物体沿直线运动，本身方向不发生改变；旋转是物体绕着某一点或轴运动，本身方向发生变化。据此解答即可。\n\n【详解】由分析可知，从左到右、从上到下看，图二、图四、图五、图七是平移现象；图一、图三、图六、图八是旋转现象。所以平移的有4个，旋转的有4个。故答案为：C",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "23-24二年级下·山东菏泽·期末"
+  },
+  {
+    "id": "428",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面图形中不是轴对称的是( )。",
+    "options": [
+      "A. ![](images/fba5841fb27484524cf19894cd3b1e05e6004b47e5fd75927c0dc56175f69f32.jpg)",
+      "B. ![](images/556c468d6e8629141c993bd02e1c1173714577ce541bfe0c642af39d3dbc5862.jpg)",
+      "C. ![](images/f4abc4ffd1f9409cddcfd69939d36e57f4079ec95986ec43e83f18f02c18cc76.jpg)"
+    ],
+    "answer": "B",
+    "solution": "【分析】一个图形沿一条直线对折，直线两旁的图形能够完全重合，这样的图形就是轴对称图形，折痕所在的直线就是对称轴。据此判断即可。\n\n【详解】A. 有对称轴，是轴对称图形；B. 没有对称轴，不是轴对称图形；C. 有对称轴，是轴对称图形。故答案为：B",
+    "knowledge_points": [
+      "轴对称的认识及辨认"
+    ],
+    "source": "23-24 二年级下·河北保定·期末"
+  },
+  {
+    "id": "429",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下列图形中，( )不是轴对称图形。",
+    "options": [
+      "A. ![](images/943b8eac79cba83883fb53e9e7a0c3058983db035adba345e8f05e5619926c36.jpg)",
+      "B. ![](images/9c9306271c24e28b20fc935cb84db70bd0dec09d1193f1bbf453c72ac532ec30.jpg)",
+      "C. ![](images/ef1571f02f38eec2c2e350bdb7b6479230f48ee3c53a8c9d869dccc100e15b87.jpg)"
+    ],
+    "answer": "B",
+    "solution": "【分析】如果一个平面图形沿一条直线折叠，直线两旁的部分能够互相重合，这个图形就叫做轴对称图形，这条线叫做图形的对称轴。\n\n【详解】A. 是轴对称图形；B. 不是轴对称图形；C. 是轴对称图形。故答案为：B",
+    "knowledge_points": [
+      "轴对称的认识及辨认"
+    ],
+    "source": "23-24二年级下·浙江温州·期末"
+  },
+  {
+    "id": "430",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面这些现象中，不是旋转现象的是( )。",
+    "options": [
+      "A. 旋转木马",
+      "B. 升降国旗",
+      "C. 风扇转动"
+    ],
+    "answer": "B",
+    "solution": "【分析】平移和旋转都是物体或图形的位置发生变化而形状、大小不变。区别在于，平移时物体沿直线运动，本身方向不发生改变；旋转是物体绕着某一点或轴运动，本身方向发生变化。据此解答即可。\n\n【详解】A. 旋转木马是旋转现象；B. 升降国旗是平移现象；C. 风扇转动是旋转现象。故答案为：B",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "23-24二年级下·江西吉安·期末"
+  },
+  {
+    "id": "431",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "图形经历了( )。\n![](images/e08ffc0af2a677a772d64cab5dfd5ccabc6eb7a38f00927db666d162b37c9799.jpg)",
+    "options": [
+      "A. 平移，旋转，旋转",
+      "B. 旋转，平移，平移",
+      "C. 旋转，平移，旋转"
+    ],
+    "answer": "C",
+    "solution": "【分析】平移后图形的形状、大小、方向不变；旋转后图形的形状、大小不变，但方向会发生变化。由此解答。\n\n【详解】由分析可知：图1到图2是旋转；图2到图3是平移；图3到图4是旋转。图形经历了旋转、平移、旋转。故答案为：C",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "22-23 二年级下·福建厦门·期末"
+  },
+  {
+    "id": "432",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "将一张纸对折后，如下图那样剪去两个长方形。展开后是( )。\n![](images/11cacf37a011d5ebbd4c3e3df9bc41e03337e9bdd8862f1011a23c99c2e3d19e.jpg)",
+    "options": [
+      "A. ![](images/a9e17487c51d95ac74c222667ec8f68b481392cce51dfb3ef9a0413870b721d5.jpg)",
+      "B. ![](images/f09bae5f35b57cf744e745360ddfd429aa089527852fd2fdd3f956d15e04c595.jpg)",
+      "C. ![](images/7034a3f82db6117472fbfd81bfccd8252c48fc155936cf537a8f2d3ec84120fe.jpg)"
+    ],
+    "answer": "A",
+    "solution": "【分析】一张纸对折后剪出的图形，展开后应是轴对称图形，折痕就是对称轴。并且上边的长方形远离折痕，下边的长方形挨着折痕，据此解答。\n\n【详解】A. 是轴对称图形，并且上边的长方形远离折痕，下边的长方形挨着折痕，符合题意；B. 是轴对称图形，但是上边折痕处多了两个长方形缺口，不符合题意；C. 不是轴对称图形，不符合题意。故答案为：A",
+    "knowledge_points": [
+      "轴对称的剪纸问题"
+    ],
+    "source": "23-24 二年级下·江西抚州·期末"
+  },
+  {
+    "id": "433",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "笑笑在对折好的纸上剪了两个洞，打开后是( )。\n![](images/6e358373daa9a5733dcf24ce6f3d00bedd2a5a6d4c8b08a147e11c1370944b6c.jpg)",
+    "options": [
+      "A. ![](images/af06aecaffae3dba0317948a1a1d6a975ea3ddedfdfbbc639e38881fa82e9d30.jpg)",
+      "B. ![](images/33a5d3e0a326cfb78727588410978014ca6ca676f0015937dad04dcdf8158bba.jpg)",
+      "C. ![](images/101dbb737a003c901f7d498b4752722c0f4f89138eefeda5a0d1d8f58a989d2a.jpg)"
+    ],
+    "answer": "C",
+    "solution": "【分析】一个图形沿一条直线对折，直线两旁的图形能够完全重合，这样的图形就是轴对称图形，折痕所在的直线就是对称轴。据此解答。\n\n【详解】根据分析，将对折的边看作对称轴，那么展开的纸上，中间偏上有1个五边形的洞，左下角和右下角各有1个正方形，所以打开后是C。故答案为：C",
+    "knowledge_points": [
+      "轴对称的认识及辨认",
+      "轴对称的剪纸问题"
+    ],
+    "source": "23-24 三年级下·广东梅州·期末"
+  },
+  {
+    "id": "434",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面( )不是平移运动。",
+    "options": [
+      "A. 拉抽屉",
+      "B. 风扇转动",
+      "C. 国旗升起",
+      "D. 电梯运动"
+    ],
+    "answer": "B",
+    "solution": "【分析】平移时，物体沿某个方向作相同距离的移动，形状、大小不变；旋转时，物体围绕某个固定点转动，形状、大小也不变。\n\n【详解】A. 拉抽屉是平移运动；B. 风扇转动是旋转运动；C. 国旗升起是平移运动；D. 电梯运动是平移运动。故答案为：B",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "23-24 四年级下·广东东莞·期末"
+  },
+  {
+    "id": "435",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "下面( )不是轴对称图形。",
+    "options": [
+      "A. 正方形",
+      "B. 长方形",
+      "C. 平行四边形",
+      "D. 圆"
+    ],
+    "answer": "C",
+    "solution": "【分析】一个图形沿一条直线折叠，直线两旁的部分能够完全重合，这样的图形叫做轴对称图形。\n\n【详解】A. 正方形是轴对称图形；B. 长方形是轴对称图形；C. 平行四边形不是轴对称图形；D. 圆是轴对称图形。故答案为：C",
+    "knowledge_points": [
+      "轴对称的认识及辨认"
+    ],
+    "source": "23-24 二年级下·四川凉山·期末"
+  },
+  {
+    "id": "436",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下图中的轴对称图形有( )个。\n![](images/9414723e7d8ae961d414e30110af83d2.png)",
+    "options": [
+      "A. 1",
+      "B. 3",
+      "C. 2"
+    ],
+    "answer": "C",
+    "solution": "【分析】一个图形沿一条直线对折，直线两旁的图形能够完全重合，这样的图形就是轴对称图形，折痕所在的直线就是对称轴。据此判断即可。\n\n【详解】图1、图3有对称轴，是轴对称图形。轴对称图形有2个。故答案为：C",
+    "knowledge_points": [
+      "轴对称的认识及辨认"
+    ],
+    "source": "22-23 二年级下·四川绵阳·期末"
+  },
+  {
+    "id": "437",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面图形中轴对称图形有( )个。\n![](images/d278817ffb4273b98c0413d2f1db2848.png)",
+    "options": [
+      "A. 2",
+      "B. 3",
+      "C. 4"
+    ],
+    "answer": "B",
+    "solution": "【分析】一个图形沿一条直线对折，直线两旁的图形能够完全重合，这样的图形就是轴对称图形，折痕所在的直线就是对称轴。据此判断即可。\n\n【详解】图1、图2、图4有对称轴，是轴对称图形。轴对称图形有3个。故答案为：B",
+    "knowledge_points": [
+      "轴对称的认识及辨认"
+    ],
+    "source": "23-24 二年级下·湖北黄石·期末"
+  },
+  {
+    "id": "438",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "下面的汉字是轴对称的是( )。",
+    "options": [
+      "A. 田",
+      "B. 子",
+      "C. 上"
+    ],
+    "answer": "A",
+    "solution": "【分析】通过对折，两边能够完全重合的图形叫轴对称图形。根据轴对称的意义，看每个选项对折之后是否能够完全重合即可。\n\n【详解】A. “田”字对折后可以完全重合；B. “子”字对折后不可以完全重合；C. “上”字对折后不可以完全重合。故答案为：A",
+    "knowledge_points": [
+      "轴对称的认识及辨认"
+    ],
+    "source": "23-24 二年级下·甘肃平凉·期末"
+  },
+  {
+    "id": "439",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "下面图形中，不是轴对称图形的是( )。",
+    "options": [
+      "A. ![](images/44b06748a1425a74aa934a0be837f7263d63b0c470012013b2dad87be85045c9.jpg)",
+      "B. ![](images/37f68169b03b79dcd27d02ceb45b127400ed6500635b31eb90ca9a0429763c01.jpg)",
+      "C. ![](images/ee17b97e433775ca4592028852ec133ad32054f8248ffd2fe7ef424b3ec4b867.jpg)"
+    ],
+    "answer": "B",
+    "solution": "【分析】一个图形沿一条直线折叠，直线两旁的部分能够完全重合，这样的图形叫做轴对称图形；折痕所在的直线叫做对称轴，据此判断即可。\n\n【详解】A. 对折后能够完全重合，是轴对称图形；B. 无论怎么折叠都无法完全重合，不是轴对称图形；C. 对折后能够完全重合，是轴对称图形。故答案为：B",
+    "knowledge_points": [
+      "轴对称的认识及辨认"
+    ],
+    "source": "23-24 二年级下·山东济宁·期末"
+  },
+  {
+    "id": "440",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下列图形中，( )不是轴对称图形。",
+    "options": [
+      "A. ![](images/c3bdd66fe3fa5ff0b4defbbcb7bb46aef7bc4ac70652a61c19277c03d631393c.jpg)",
+      "B. ![](images/a1b2fae4b848ca3718f66de81fe5ec5ca952c6ea47058e7ff10046985c60f21e.jpg)",
+      "C. ![](images/71bd33c29347423d2d8b81dcdd9781b187deed2959d716941343ef45ea3aaad8.jpg)"
+    ],
+    "answer": "B",
+    "solution": "【分析】一个图形沿一条直线对折，直线两旁的图形能够完全重合，这样的图形就是轴对称图形，折痕所在的直线就是对称轴。据此判断即可。\n\n【详解】A. 有对称轴，是轴对称图形；B. 没有对称轴，不是轴对称图形；C. 有对称轴，是轴对称图形。故答案为：B",
+    "knowledge_points": [
+      "轴对称的认识及辨认"
+    ],
+    "source": "23-24 二年级下·广东汕头·期末"
+  },
+  {
+    "id": "441",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "在下面字母中，( )是轴对称图形。",
+    "options": [
+      "A. O",
+      "B. L",
+      "C. R"
+    ],
+    "answer": "A",
+    "solution": "【分析】如果一个图形沿着一条直线对折，直线两边的图形能够完全重合，这样的图形叫轴对称图形，这条直线叫对称轴，据此判断即可。\n\n【详解】A. O有对称轴，是轴对称图形；B. L没有对称轴，不是轴对称图形；C. R没有对称轴，不是轴对称图形。故答案为：A",
+    "knowledge_points": [
+      "轴对称的认识及辨认"
+    ],
+    "source": "23-24 二年级下·河南南阳·期末"
+  },
+  {
+    "id": "442",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下列运动现象不属于旋转的是( )。",
+    "options": [
+      "A. ![](images/97305bd80ec12bafc532db6c5d8e66bc7cf5c8cf8df49076f3d40d583087e9d4.jpg)",
+      "B. ![](images/d76cc4774e4805a334bf644f0500664e5052b4123aced0d99b4dbdf99e0270a1.jpg)",
+      "C. ![](images/9b7a1b9cf2e042eb79e660d0491e3fb9c2d15e9e06996ecadfbf234f96379297.jpg)"
+    ],
+    "answer": "B",
+    "solution": "【分析】平移时，物体沿直线运动，本身方向不发生改变；旋转时，物体绕着某一点或轴运动，本身方向发生变化。据此判断即可。\n\n【详解】A. 打开瓶盖是旋转现象，不符合题意；B. 抽拉抽屉属于平移运动，符合题意；C. 方向盘转动属于旋转现象，不符合题意。故答案为：B",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "23-24 二年级下·甘肃兰州·期末"
+  },
+  {
+    "id": "443",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面的图形,( )是轴对称图形。",
+    "options": [
+      "A. ![](images/bc37cbd4a4b0f93f3d9c4109d554ab4e13d9a156d5be9ade26c676b406b1d325.jpg)",
+      "B. ![](images/44863d12993569b92131f4240986bd091004d85c98dabb57cb2128875fbd8a9d.jpg)",
+      "C. ![](images/3af3e70b350c33534e4820122d93dbbdf3f89d814819d6e1710ea7abe87a15ff.jpg)"
+    ],
+    "answer": "A",
+    "solution": "【分析】在平面内，如果一个图形沿一条直线对折，对折后的两部分都能完全重合，这样的图形叫做轴对称图形。\n\n【详解】A. 是轴对称图形；B. 不是轴对称图形；C. 不是轴对称图形。故答案为：A",
+    "knowledge_points": [
+      "轴对称的认识及辨认"
+    ],
+    "source": "23-24二年级下·广东肇庆·期末"
+  },
+  {
+    "id": "444",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面是几种汽车的标志，在这几个标志图案中，是轴对称的图形有( )个。\n![](images/96c60f8e823cda5f6050d6c34a596b6b.png)",
+    "options": [
+      "A. 1",
+      "B. 2",
+      "C. 3"
+    ],
+    "answer": "B",
+    "solution": "【分析】一个图形沿一条直线对折，直线两旁的图形能够完全重合，这样的图形就是轴对称图形，折痕所在的直线就是对称轴。据此判断即可。\n\n【详解】由图可知，图1和图3有对称轴，是轴对称图形。轴对称图形有2个。故答案为：B",
+    "knowledge_points": [
+      "轴对称的认识及辨认"
+    ],
+    "source": "23-24 二年级下·吉林四平·期末"
+  },
+  {
+    "id": "445",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面的图形中轴对称图形有( )个。\n![](images/d78a3e00af1957f25cb561befe68034a.png)",
+    "options": [
+      "A. 4",
+      "B. 2",
+      "C. 3",
+      "D. 1"
+    ],
+    "answer": "C",
+    "solution": "【分析】一个图形沿一条直线对折，直线两旁的图形能够完全重合，这样的图形就是轴对称图形，折痕所在的直线就是对称轴。据此判断即可。\n\n【详解】图1、图3和图4有对称轴，是轴对称图形。所以轴对称图形有3个。故答案为：C",
+    "knowledge_points": [
+      "轴对称的认识及辨认"
+    ],
+    "source": "22-23 二年级下·江西吉安·期末"
+  },
+  {
+    "id": "446",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "轮船向前航行是( )现象，时针和分针的走动是( )现象。",
+    "options": [
+      "A. 旋转;对称",
+      "B. 平移;旋转",
+      "C. 对称;平移"
+    ],
+    "answer": "B",
+    "solution": "【分析】平移时，物体沿某个方向作相同距离的移动；旋转时，物体围绕某个固定点转动。据此判断。\n\n【详解】由分析可得：轮船向前航行是平移现象，时针和分针的走动是旋转现象。故答案为：B",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "22-23 二年级下·江西吉安·期末"
+  },
+  {
+    "id": "447",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "下面是几种汽车标志，在这几个标志图案中，轴对称图形有( )个。\n![](images/4817abe307648ded1a65e790ead93a2e.png)",
+    "options": [
+      "A. 2个",
+      "B. 3个",
+      "C. 4个",
+      "D. 1个"
+    ],
+    "answer": "B",
+    "solution": "【分析】如果一个图形沿着一条直线对折后，两部分能够完全重合，这样的图形叫做轴对称图形，这条直线叫做对称轴。\n\n【详解】A. 是轴对称图形；B. 无论怎样对折，图形两部分都不能完全重合，不是轴对称图形；C. 是轴对称图形；D. 是轴对称图形。轴对称图形有3个。故答案为：B",
+    "knowledge_points": [
+      "轴对称的认识及辨认"
+    ],
+    "source": "23-24 二年级下·贵州铜仁·期末"
+  },
+  {
+    "id": "448",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "能和图形拼成轴对称图形的是( )。\n![](images/6a8dad3a959cbd0b185071b3584bf3a90345650e8d3eebaab0ab5749562eb549.jpg)",
+    "options": [
+      "A. ![](images/fa4a09519177c13fa482574b50309e2ae55ed231125e41100d2b7f8bbbb0b0da.jpg)",
+      "B. ![](images/b080c5fa074010ebc89017edc70c2786292c94c38ac70ea9c5c908454a592bb7.jpg)",
+      "C. ![](images/c9bef615d038cbcf6a39feb4985e3c036f725295257fba5f2968ae5403d44912.jpg)"
+    ],
+    "answer": "B",
+    "solution": "【分析】在平面内，如果一个图形沿一条直线折叠，直线两旁的部分能够完全重合，这样的图形叫作轴对称图形，这条直线就是它的对称轴，据此解答即可。\n\n【详解】能和图形拼成轴对称图形的是B。故答案为：B",
+    "knowledge_points": [
+      "轴对称的认识及辨认"
+    ],
+    "source": "23-24 二年级下·湖南常德·期末"
+  },
+  {
+    "id": "449",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面不是轴对称图形的是( )。",
+    "options": [
+      "A. ![](images/d4670bac66c174b2700cdfda02a5cee776740dcaf0e8a4f11b3a6b3602e582d5.jpg)",
+      "B. ![](images/89fb8465595ebc3328cd7530e449cd53837ada069a4c2b2be5ab8650788c66e6.jpg)",
+      "C. ![](images/5c8324d625033bb3124888c2dbd5f4c70b4a3dbeb8583802e5ae118be38814d6.jpg)"
+    ],
+    "answer": "C",
+    "solution": "【分析】依据轴对称图形的概念，在平面内，如果一个图形沿一条直线折叠，直线两旁的部分能够完全重合，这样的图形叫做轴对称图形，这条直线就是它的对称轴，据此解答即可。\n\n【详解】A. 是轴对称图形；B. 是轴对称图形；C. 不是轴对称图形。故答案为：C",
+    "knowledge_points": [
+      "轴对称的认识及辨认"
+    ],
+    "source": "23-24二年级下·湖南常德·期末"
+  },
+  {
+    "id": "450",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下列运动属于旋转的是( )。",
+    "options": [
+      "A. ![](images/788721f171505e3d13db0e37733615c0d9867d2f604535e86d3c420a1bcfbddb.jpg)",
+      "B. ![](images/5a02ba62a2688708b3b9e9e1cedfb8c5e65e3656096373e394a72c23ad125fa9.jpg)",
+      "C. ![](images/a6366e2f078cef8e9890b1899196112b1d992fc5917d01ac20d719252f6e4665.jpg)"
+    ],
+    "answer": "A",
+    "solution": "【分析】在平面内，把一个图形围绕某一固定点按顺时针或逆时针方向转动一定的角度的过程，称为旋转；把一个图形整体沿某条直线方向平行移动一定距离的过程，称为平移。由此解答。\n\n【详解】A. 风车转动属于旋转现象；B. 推拉窗户属于平移现象；C. 推拉抽屉属于平移现象。属于旋转的是A。故答案为：A",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "22-23 二年级下·四川绵阳·期末"
+  },
+  {
+    "id": "451",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下列现象中，( )是平移，( )是旋转。\n![](images/ef7484f531dfb0b43eaa12df35039f91.png)",
+    "options": [
+      "A. ①②",
+      "B. ②①"
+    ],
+    "answer": "A",
+    "solution": "【分析】把一个图形整体沿某一方向移动一定的距离，图形的这种运动叫平移；平移后图形的位置改变，形状、大小不变。在平面内，一个图形绕着一个定点转动一定的角度，这样的变化叫做旋转；旋转前后图形的大小和形状没有改变。据此解答即可。\n\n【详解】由题意分析得：图一是平移现象，图二是旋转现象。故答案为：A",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "23-24 二年级下·黑龙江双鸭山·期末"
+  },
+  {
+    "id": "452",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下列图形中，是轴对称图形的是( )。",
+    "options": [
+      "A. ![](images/5680a12c928ff14018ae8a7c6f0c6084af053c967a0295ee9f2bbaf7a8288b92.jpg)",
+      "B. ![](images/d83b1d013661f01ddd2176704c31396985326d777cf1ac9eac18bb7bba0b7d57.jpg)",
+      "C. ![](images/74ec1a8b580a3889a4e117cce88034ae0cf2e7852605a1bb6123b65b3a709f41.jpg)"
+    ],
+    "answer": "A",
+    "solution": "【分析】如果沿某条直线对折，对折的两部分能够完全重合，这样的图形就是轴对称图形。这条直线叫做这个图形的对称轴。判断一个图案是否是轴对称图形，关键是看能否找到一条直线，使图形沿着这条直线对折后能够完全重合。\n\n【详解】A. 是轴对称图形；B. 找不到一条直线，使图形沿着这条直线对折后能够完全重合，所以不是轴对称图形；C. 找不到一条直线，使图形沿着这条直线对折后能够完全重合，所以不是轴对称图形。故答案为：A",
+    "knowledge_points": [
+      "轴对称的认识及辨认"
+    ],
+    "source": "23-24 二年级下·山西晋中·期末"
+  },
+  {
+    "id": "453",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "如图不是轴对称图形的是( )。",
+    "options": [
+      "A. ![](images/8f82e6b93b4f85c04423eb687576770723b62153e95413a085f9886734d48902.jpg)",
+      "B. ![](images/8bd1d9cfb3138c674804bb075247ba3ce8f9aaab26dd3dd6de88cf32950c2712.jpg)",
+      "C. ![](images/c57a9b355c4d19e356b0a2ea860b27037d2b066ce2683be49f6b4d1d75a2815d.jpg)"
+    ],
+    "answer": "C",
+    "solution": "【分析】根据轴对称图形的意义：如果一个图形沿着一条直线对折后两部分完全重合，这样的图形叫作轴对称图形，这条直线叫作对称轴，据此解答即可。\n\n【详解】A. 是轴对称图形；B. 是轴对称图形；C. 不是轴对称图形。故答案为：C",
+    "knowledge_points": [
+      "轴对称的认识及辨认"
+    ],
+    "source": "23-24 二年级下·甘肃天水·期末"
+  },
+  {
+    "id": "454",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "下面运动属于旋转现象的是( )。",
+    "options": [
+      "A. 汽车行驶在笔直的路上的运动",
+      "B. 升旗时国旗的运动",
+      "C. 电风扇的运动",
+      "D. 拉抽屉的运动"
+    ],
+    "answer": "C",
+    "solution": "【分析】平移是物体沿着一条直线运动；旋转是物体绕着一个中心或轴做圆周运动。\n\n【详解】A. 汽车行驶在笔直的路上的运动、B. 升旗时国旗的运动、D. 拉抽屉的运动，这三个选项都是平移；C. 电风扇的运动是旋转。故答案为：C",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "23-24 二年级下·浙江宁波·期末"
+  },
+  {
+    "id": "455",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "下列图形中，( )不是轴对称图形。",
+    "options": [
+      "A. ![](images/e7406441b6b024a659a0ed0a050808c0ab635e7e4ac05d6d5c9b464b34ba94d2.jpg)",
+      "B. ![](images/96cf41c58ecec027fde9fc9bbaa70872cf04bc936e53ae83c9e17e8cd3aab92c.jpg)",
+      "C. ![](images/b892e889a0dd425bdbd244fef7f7c4228488636f19b29b7b2bbb82659e4b5139.jpg)"
+    ],
+    "answer": "B",
+    "solution": "【分析】根据轴对称的定义：在平面内，如果一个图形沿一条直线对折，对折后的两部分都能完全重合，这样的图形叫做轴对称图形，这条直线就是它的对称轴。据此解答。\n\n【详解】A. 左右对折能完全重合，所以此图形是轴对称图形；B. 无论怎样折都不能完全重合，所以此图形不是轴对称图形；C. 左右和上下对折都能完全重合，所以此图形是轴对称图形。故答案为：B",
+    "knowledge_points": [
+      "轴对称的认识及辨认"
+    ],
+    "source": "23-24二年级下·四川南充·期末"
+  },
+  {
+    "id": "456",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "一根红丝带向右平移6厘米后，现在长8厘米。这根红丝带原来长( )厘米。",
+    "options": [
+      "A. 8",
+      "B. 2",
+      "C. 6"
+    ],
+    "answer": "A",
+    "solution": "【分析】在平面内，将一个图形上的所有点都按照某个方向作相同距离的移动，这样的图形运动叫平移。平移不改变图形的形状、大小，只改变图形的位置。据此解答。\n\n【详解】由题意分析得：一根红丝带向右平移6厘米后，现在长8厘米。平移后长度不变，还是8厘米，所以这根红丝带原来长8厘米。故答案为：A",
+    "knowledge_points": [
+      "平移与平移现象",
+      "厘米的认识"
+    ],
+    "source": "23-24 二年级下·浙江台州·期末"
+  },
+  {
+    "id": "457",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面这些图形中，对称轴最多的是( )。",
+    "options": [
+      "A. ![](images/0854e9a40b8b1b80a9a51b00dd53862c6d8436df81c9c3f4c6e93ce70aee9e2c.jpg)",
+      "B. ![](images/beb6a6432bbaff35702fd2bb8ca9f42a5faaad00b7495f0d6960cdfd63daeb1f.jpg)",
+      "C. ![](images/5f4b5a3eae7e6ed3c74517fbce015edca403a7c829924a5dc7d9a44df1e493f1.jpg)"
+    ],
+    "answer": "C",
+    "solution": "【分析】一个图形沿着一条直线对折后两边能完全重合，这个图形就是轴对称图形，折痕所在的直线就是对称轴。先根据图形的特征判断对称轴的条数，再比较条数多少即可。\n\n【详解】A. 有4条对称轴；B. 有6条对称轴；C. 有无数条对称轴。故答案为：C",
+    "knowledge_points": [
+      "对称轴的画法及数量"
+    ],
+    "source": "23-24 二年级下·浙江台州·期末"
+  },
+  {
+    "id": "458",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面是轴对称图形的是( )。",
+    "options": [
+      "A. ![](images/f6ccfe18f7e4e182f79c2dc958b79126f147fb2ce0d579bd54ff0a24e6438218.jpg)",
+      "B. ![](images/ee09333f2d7f2b5a498aa51e078317981f6e26f5f71fb25a0752a5aa71e9ef5e.jpg)",
+      "C. ![](images/eb056c138563616203ba6fb639ea06d3cbb692bcab1168c66baeb051931eb786.jpg)"
+    ],
+    "answer": "B",
+    "solution": "【分析】如果一个平面图形沿一条直线折叠，直线两旁的部分能够互相重合，这个图形就叫做轴对称图形，这条线就是对称轴。\n\n【详解】A. 不是轴对称图形，不符合题意；B. 是轴对称图形，符合题意；C. 不是轴对称图形，不符合题意。故答案为：B",
+    "knowledge_points": [
+      "轴对称的认识及辨认"
+    ],
+    "source": "23-24 二年级下·广西柳州·期末"
+  },
+  {
+    "id": "459",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面不是轴对称图形的是( )。",
+    "options": [
+      "A. ![](images/ef8424b0af05ce0cc88a5666f5063276975218f18511fa11209a9456235987a6.jpg)",
+      "B. ![](images/c5c8ad076f0428790a1339a50b97e51d445ba7f7b80ffab24b75aa45797b91ab.jpg)",
+      "C. ![](images/63f07c2a2855c72bd13e556498c827afef6b70667b9cfadfacfe6f9aa108287a.jpg)",
+      "D. ![](images/e8eb4464705bf4813109006192529a39ccf2eac40328f576a447810e728d9eca.jpg)"
+    ],
+    "answer": "C",
+    "solution": "【分析】一个图形沿着一条直线对折后两边能完全重合，这个图形就是轴对称图形，折痕所在的直线就是对称轴。\n\n【详解】A. 沿着一条直线对折后两边能完全重合，是轴对称图形，不符合题意；B. 沿着一条直线对折后两边能完全重合，是轴对称图形，不符合题意；C. 沿着一条直线对折后两边不能完全重合，不是轴对称图形，符合题意；D. 沿着一条直线对折后两边能完全重合，是轴对称图形，不符合题意。故答案为：C",
+    "knowledge_points": [
+      "轴对称的认识及辨认"
+    ],
+    "source": "23-24 二年级下·浙江杭州·期末"
+  },
+  {
+    "id": "460",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面不是轴对称图形的是( )。",
+    "options": [
+      "A. ![](images/617b31eea46469782fc7084c2ea88e8eaf51bb784d2df7aa9aa1086c2428b010.jpg)",
+      "B. ![](images/59ab9e9ffd699614b5755c741c57e49da72ca76ebb9905f8f28abef489176a62.jpg)",
+      "C. ![](images/218e2087401336efea0d3455eb4ece31d91ae71a1272b8fcd0fad456d2ba5711.jpg)"
+    ],
+    "answer": "C",
+    "solution": "【分析】一个图形沿一条直线对折，直线两旁的图形完全重合，这样的图形叫做轴对称图形，折痕所在的直线就是对称轴，由此找出图形的对称轴即可。\n\n【详解】A。 有对称轴，是轴对称图形;B. 有对称轴，是轴对称图形;C. 没有对称轴，不是轴对称图形。故答案为:C",
+    "knowledge_points": [
+      "轴对称的认识及辨认"
+    ],
+    "source": "22-23二年级下·湖北恩施·阶段练习"
+  },
+  {
+    "id": "461",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面的图形中，( )是由一个图形经过旋转变换得到的。",
+    "options": [
+      "A. ![](images/49bb92c0f024a0cbdbdedc39dc504af35ec7ccbd55919d0ad085f335957558d7.jpg)",
+      "B. ![](images/16d637b05d75cb62a7eb2b1d71d4684422c50500c38cdb3e6866d4c2a81ab59b.jpg)",
+      "C. ![](images/971f58990cdf1839fcc6e51b8f853cff88059c9e4f73403ab9491f7c26d378ca.jpg)"
+    ],
+    "answer": "C",
+    "solution": "【分析】旋转后图形的形状、大小不变，但方向会发生变化；平移后图形的形状、大小、方向都不变，只是位置发生变化。由此解答。\n\n【详解】A. 图形的形状、大小、方向都没改变，只是位置发生了变化，是经过平移得到的；B. 图形的形状、大小、方向都没改变，只是位置发生了变化，是经过平移得到的；C. 图形的形状、大小不变，但方向发生了变化，是经过旋转得到的。故答案为：C",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "22-23 二年级下·湖北恩施·阶段练习"
+  },
+  {
+    "id": "462",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面的图形中不是轴对称图形的是( )。",
+    "options": [
+      "A. ![](images/749bfdf04f987f1e6ed5d726bca8974d60d912b9f2093d7143325d5199b53a19.jpg)",
+      "B. ![](images/b474d5941d103bce6d13187454df2d531645dc19170da99f98cd8e67d16230b7.jpg)",
+      "C. ![](images/ba6d31ad92239b352a67304497ad496bc96857fd486e1738f2d8d717fb785dbc.jpg)"
+    ],
+    "answer": "A",
+    "solution": "【分析】一个图形沿一条直线对折，直线两旁的图形能够完全重合，这样的图形叫做轴对称图形，折痕所在的直线就是对称轴。由此找出对称轴即可。\n\n【详解】A. 没有对称轴，不是轴对称图形；B. 有对称轴，是轴对称图形；C. 有对称轴，是轴对称图形。不是轴对称图形的是A。故答案为：A",
+    "knowledge_points": [
+      "轴对称的认识及辨认"
+    ],
+    "source": "22-23 二年级下·广东江门·期中"
+  },
+  {
+    "id": "463",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面图形,( )不是轴对称图形。",
+    "options": [
+      "A. ![](images/7f725ffd56935dcc5e9c4e63898e0bedde361456937a6e609d8978f6789f4dac.jpg)",
+      "B. ![](images/1da1a739302e15c73560b421bb1babfab28eecd910347c72d246e21fb60f1d1d.jpg)",
+      "C. ![](images/c380d300e99af3eb5a1573db021334317220ca82126f15b577e336e757b26867.jpg)"
+    ],
+    "answer": "B",
+    "solution": "【分析】一个图形沿一条直线对折，直线两旁的图形能够完全重合，这样的图形叫做轴对称图形，折痕所在的直线就是对称轴，由此找出图形的对称轴即可。\n\n【详解】A. 有对称轴，是轴对称图形；B. 没有对称轴，不是轴对称图形；C. 有对称轴，是轴对称图形。故答案为：B",
+    "knowledge_points": [
+      "轴对称的认识及辨认"
+    ],
+    "source": "22-23二年级下·湖北恩施·期中"
+  },
+  {
+    "id": "464",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下图中是轴对称图形的是( )。",
+    "options": [
+      "A. ![](images/5be1b67aefc0e0f36b428e8d6ac5d7f76369d0c0364a67486b79cb2779cc3664.jpg)",
+      "B. ![](images/2b2675a7f3222a83cc3c8017514aab5a718b8fdeec9b133039f6de4d5bbefe2d.jpg)",
+      "C. ![](images/d6f2e48b41cc8bdbcf83d32344c9e5fcda0ffcace3a6a48f6908bcabd6ab2e2a.jpg)"
+    ],
+    "answer": "C",
+    "solution": "【分析】一个图形沿一条直线对折，直线两旁的图形能够完全重合，这样的图形叫做轴对称图形，折痕所在的直线就是对称轴，由此找出图形的对称轴即可。\n\n【详解】A. 没有对称轴，不是轴对称图形；B. 没有对称轴，不是轴对称图形；C. 有对称轴，是轴对称图形。图中是轴对称图形的是C。故答案为：C",
+    "knowledge_points": [
+      "轴对称的认识及辨认"
+    ],
+    "source": "23-24 二年级下·广东肇庆·期末"
+  },
+  {
+    "id": "465",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下图中，( )是由原图\n![](images/b97bffdb46510578c879271e7e5f4472.png)\n平移得到的。",
+    "options": [
+      "A. ![](images/66aabd5438c6382fca15170be837517e.png)",
+      "B. ![](images/87ebe7feb1e1d063388e715753e6db31ba358aa13448c59ea47076c0e7c6bdc4.jpg)",
+      "C. ![](images/0502087e8ce799bfe1a7faaebfc1d42469fb12aa0890fbede51b432115d425da.jpg)"
+    ],
+    "answer": "C",
+    "solution": "【分析】在平面内，把一个图形整体沿某条直线方向平行移动一定距离的过程，称为平移。物体或图形平移后，它们的形状、大小、方向都不改变，只是位置发生变化。由此解答。\n\n【详解】A. 方向发生了变化，不是平移；B. 方向发生了变化，不是平移；C. 形状、大小、方向都没发生变化，是平移。所以C是由原图平移得到的。故答案为：C",
+    "knowledge_points": [
+      "平移与平移现象"
+    ],
+    "source": "23-24 二年级下·广东肇庆·期末"
+  },
+  {
+    "id": "466",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "下面图形中,( )是轴对称图形。",
+    "options": [
+      "A. ![](images/8e7a31821ea62061b51014b8443cadf07aef09768528003ed22b74411cb90378.jpg)",
+      "B. ![](images/51c55bbb68db4e32516f1c28ad37d5ae8e9aaf7dda7b6e3f0bab90b057ea7a19.jpg)",
+      "C. ![](images/075c5392757851652265c19bffb4b98baf27df91132d7282d1bb321067136371.jpg)"
+    ],
+    "answer": "A",
+    "solution": "【分析】如果一个平面图形沿一条直线折叠，直线两旁的部分能够互相重合，这个图形就叫做轴对称图形，这条线叫做图形的对称轴。据此解答。\n\n【详解】由题意分析得：A. 是轴对称图形；B. 不是轴对称图形；C. 不是轴对称图形。故答案为：A",
+    "knowledge_points": [
+      "轴对称的认识及辨认"
+    ],
+    "source": "23-24二年级下·贵州黔西·期末"
+  },
+  {
+    "id": "467",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "神舟十七号飞船升空是( )现象，其绕地球飞行是( )现象。",
+    "options": [],
+    "answer": "平移;旋转",
+    "solution": "【分析】在平面内，把一个图形整体沿某条直线方向平行移动一定距离的过程，称为平移；在平面内，把一个图形围绕某一固定点按顺时针或逆时针方向转动一定的角度的过程，称为旋转。据此解答。\n\n【详解】由分析可知：神舟十七号飞船升空是平移现象，其绕地球飞行是旋转现象。",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "23-24 二年级下·山东济宁·期末"
+  },
+  {
+    "id": "468",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "拉抽屉属于( )现象，地球绕太阳转属于( )现象。(填“平移”或“旋转”)",
+    "options": [],
+    "answer": "平移;旋转",
+    "solution": "【分析】在平面内，一个图形绕着一个定点转动一定的角度，这样的变化叫做旋转；将一个图形上的所有点都按照某个方向作相同距离的移动，这样的运动叫平移。据此解答。\n\n【详解】由分析可知：拉抽屉属于平移现象，地球绕太阳转属于旋转现象。",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "23-24 二年级下·山西长治·期末"
+  },
+  {
+    "id": "469",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "推拉抽屉时，抽屉的运动是( )现象。(填“平移”或“旋转”)",
+    "options": [],
+    "answer": "平移",
+    "solution": "【分析】在平面内，一个图形绕着一个定点转动一定的角度，这样的变化叫做旋转；将一个图形上的所有点都按照某个方向作相同距离的移动，这样的运动叫平移。\n\n【详解】推拉抽屉时，抽屉的运动是平移现象。",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "23-24 二年级下·河北保定·期末"
+  },
+  {
+    "id": "470",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "“王、水、中、羊、玉”这些汉字中，属于轴对称的有( )个。",
+    "options": [],
+    "answer": "3或三",
+    "solution": "【分析】一个图形沿一条直线对折后，直线两旁的部分能够完全重合，这样的图形叫做轴对称图形，据此进行判断即可。\n\n【详解】“王、水、中、羊、玉”这些汉字中，属于轴对称的有“王”“中”“羊”，一共有3个。",
+    "knowledge_points": [
+      "轴对称的认识及辨认"
+    ],
+    "source": "23-24 二年级下·湖南郴州·期末"
+  },
+  {
+    "id": "471",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "在括号里填上平移或旋转。拧开水龙头是( )现象;电梯上下是( )现象;风车转动是( )现象;开关推拉门是( )现象。",
+    "options": [],
+    "answer": "旋转;平移;旋转;平移",
+    "solution": "【分析】在平面内，把一个图形整体沿某条直线方向平行移动一定距离的过程，称为平移；在平面内，把一个图形围绕某一固定点按顺时针或逆时针方向转动一定的角度的过程，称为旋转。由此解答。\n\n【详解】拧开水龙头是旋转现象；电梯上下是平移现象；风车转动是旋转现象；开关推拉门是平移现象。",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "23-24 二年级下·河南周口·期末"
+  },
+  {
+    "id": "472",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "钟面上分针走动属于( )现象，滑滑梯属于( )现象。",
+    "options": [],
+    "answer": "旋转;平移",
+    "solution": "【分析】在平面内，把一个图形围绕某一固定点按顺时针或逆时针方向转动一定的角度的过程，称为旋转；在平面内，把一个图形整体沿某条直线方向平行移动一定距离的过程，称为平移，由此解答。\n\n【详解】由分析可知，钟面上分针走动属于旋转现象，滑滑梯属于平移现象。",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "23-24 二年级下·河北保定·期末"
+  },
+  {
+    "id": "473",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "选填“旋转”或者“平移”。汽车在笔直的公路上直行，车身在做( )运动，车轮在做( )运动。电梯升降是( )运动，电风扇扇叶转动是( )运动。",
+    "options": [],
+    "answer": "平移;旋转;平移;旋转",
+    "solution": "【分析】在平面内，一个图形绕着一个定点转动一定的角度，这样的变化叫做旋转；将一个图形上的所有点都按照某个方向作相同距离的移动，这样的运动叫平移。据此解答。\n\n【详解】由题意分析得：汽车在笔直的公路上直行，车身在做平移运动，车轮在做旋转运动。电梯升降是平移运动，电风扇扇叶转动是旋转运动。",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "23-24 二年级下·山东济南·期末"
+  },
+  {
+    "id": "474",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "升国旗时，国旗的运动是( )，教室里的风扇打开，扇叶的运动是( )。(选填“平移”或“旋转”)",
+    "options": [],
+    "answer": "平移;旋转",
+    "solution": "【分析】在平面内，把一个图形围绕某一固定点按顺时针或逆时针方向转动一定的角度的过程，称为旋转；在平面内，把一个图形整体沿某条直线方向平行移动一定距离的过程，称为平移。由此解答。\n\n【详解】由分析可知：升国旗时，国旗的运动是平移，教室里的风扇打开，扇叶的运动是旋转。",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "23-24 二年级下·江西宜春·期末"
+  },
+  {
+    "id": "475",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "在下列运动现象中，是平移的画△，是旋转的画○。飞机螺旋桨的转动( )，电梯上下运动( )。",
+    "options": [],
+    "answer": "○;△",
+    "solution": "【分析】平移和旋转都是物体或图形的位置发生变化而形状、大小不变。区别在于，平移时物体沿直线运动，本身方向不发生改变；旋转是物体绕着某一点或轴运动，本身方向发生变化。据此解答即可。\n\n【详解】飞机螺旋桨的转动是旋转现象，电梯上下运动是平移现象。所以飞机螺旋桨的转动画○，电梯上下运动画△。",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "23-24 二年级下·山东菏泽·期末"
+  },
+  {
+    "id": "476",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "车轮的运动是( )现象，电梯的运动是( )现象。",
+    "options": [],
+    "answer": "旋转;平移",
+    "solution": "【分析】在平面内，把一个图形围绕某一固定点按顺时针或逆时针方向转动一定的角度的过程，称为旋转；在平面内，把一个图形整体沿某条直线方向平行移动一定距离的过程，称为平移。由此解答。\n\n【详解】由分析可知，车轮的运动是旋转现象，电梯的运动是平移现象。",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "23-24 二年级下·河南南阳·期末"
+  },
+  {
+    "id": "477",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "下面图形通过平移能重合的是( )和( ),先通过平移再旋转才能重合的是( )和( )。(填序号)\n![](images/image-11.png)",
+    "options": [],
+    "answer": "①;③;②;⑤",
+    "solution": "【分析】平移是物体或图形沿着直线移动；旋转是物体或图形围绕一个点转动的现象。再根据图形的大小和方向，找出对应的图形即可。\n\n【详解】通过平移能重合的是①和③；先通过平移再旋转才能重合的是②和⑤。",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "22-23二年级下·福建厦门·期末"
+  },
+  {
+    "id": "478",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "从灯头上卸下灯泡是( )现象;拨算珠是( )现象。",
+    "options": [],
+    "answer": "旋转;平移",
+    "solution": "【分析】在平面内，把一个图形围绕某一固定点按顺时针或逆时针方向转动一定的角度的过程，称为旋转；在平面内，把一个图形整体沿某条直线方向平行移动一定距离的过程，称为平移。由此解答。\n\n【详解】由分析可知：从灯头上卸下灯泡是旋转现象；拨算珠是平移现象。",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "23-24 二年级下·河南开封·期末"
+  },
+  {
+    "id": "479",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "学校升国旗是( )现象，小朋友荡秋千是( )现象。",
+    "options": [],
+    "answer": "平移;旋转",
+    "solution": "【分析】在平面内，把一个图形整体沿某条直线方向平行移动的过程，称为平移；在平面内，把一个图形围绕某一固定点按顺时针或逆时针方向转动一定的角度的过程，称为旋转。\n\n【详解】根据分析可知，学校升国旗是平移现象，小朋友荡秋千是旋转现象。",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "23-24 三年级下·河南驻马店·期末"
+  },
+  {
+    "id": "480",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "翻书时，书页的运动是( )现象。",
+    "options": [],
+    "answer": "旋转",
+    "solution": "【分析】平移现象：物体或图形沿着直线移动，例如：电梯和缆车的运动;旋转现象：物体或图形围绕着一个点进行转动，例如：车轮和方向盘的运动。\n\n【详解】根据分析可知，翻书时，书页的运动是旋转现象。",
+    "knowledge_points": [
+      "旋转与旋转现象"
+    ],
+    "source": "23-24二年级下·湖南长沙·期末"
+  },
+  {
+    "id": "481",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "钟面上的分针由12旋转到6，经过了( )分钟，这时钟面上的分针运动是属于( )现象。",
+    "options": [],
+    "answer": "30;旋转",
+    "solution": "【分析】钟面上长针是分针，钟面有12个大格，分针走1大格是5分钟，由此计算出一共走了多少个大格，再算出经过的时间。分针绕中心转动，属于旋转现象。\n\n【详解】12到6一共走了6个大格，6×5=30(分)。钟面上的分针由12旋转到6，经过了30分钟，这时钟面上的分针运动属于旋转现象。",
+    "knowledge_points": [
+      "旋转与旋转现象",
+      "6的乘法口诀及应用",
+      "时，分，秒有关的计算"
+    ],
+    "source": "23-24二年级下·广东汕头·期末"
+  },
+  {
+    "id": "482",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "钟表上的分针绕其轴心运动是( )现象。(填“平移”或“旋转”)",
+    "options": [],
+    "answer": "旋转",
+    "solution": "【分析】在平面内，把一个图形围绕某一固定点按顺时针或逆时针方向转动一定的角度的过程，称为旋转；在平面内，把一个图形整体沿某条直线方向平行移动一定距离的过程，称为平移。由此解答。\n\n【详解】由分析可知，钟表上的分针绕其轴心运动时，轴心是固定点，所以其运动是旋转现象。",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "23-24二年级下·山东济宁·期末"
+  },
+  {
+    "id": "483",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "时钟里分针的运动属于( )现象，电梯从1楼到10楼的运动属于( )现象。(选填“平移”或“旋转”)",
+    "options": [],
+    "answer": "旋转;平移",
+    "solution": "【分析】平移时物体沿直线运动，本身方向不发生改变；旋转是物体绕着某一点或轴运动，本身方向发生变化。据此解答。\n\n【详解】根据分析：时钟里分针的运动属于旋转现象；电梯从1楼到10楼的运动属于平移现象。",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "23-24 三年级下·广东梅州·期末"
+  },
+  {
+    "id": "484",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "如图所示，小红、小丽、小明和小军四个人在画画。( )是小军画的，( )是小红画的，( )是小明画的，( )是小丽画的。\n![](images/229cd7c62c7281c4c59708fa8c9f6f9d.png)",
+    "options": [],
+    "answer": "小军;小红;小明;小丽",
+    "solution": "【分析】小红画的是房子的正面，有门有窗；小军画的是房子的侧面，有两个窗；小明画的是房子的后面，有一个窗；小丽画的是房子的另一侧面，没有窗也没有门。据此解答。\n\n【详解】由题意分析得：第一幅是小军画的，第二幅是小红画的，第三幅是小明画的，第四幅是小丽画的。",
+    "knowledge_points": [
+      "从不同位置观察单个物体"
+    ],
+    "source": "23-24 二年级上·福建莆田·期末"
+  },
+  {
+    "id": "485",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "摩天轮的运动是( )现象，汽车在笔直的公路上行驶是( )现象。",
+    "options": [],
+    "answer": "旋转;平移",
+    "solution": "【分析】平移后图形的位置改变，形状、大小、方向不变；旋转前后图形的位置和方向改变，形状、大小不变。\n\n【详解】据分析可知：摩天轮的运动是旋转现象，汽车在笔直的公路上行驶是平移现象。",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "23-24二年级下·广东汕头·期末"
+  },
+  {
+    "id": "486",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "风车遇到风会发生( )现象，电梯上升是( )现象。(括号里填“平移”或“旋转”)",
+    "options": [],
+    "answer": "旋转;平移",
+    "solution": "【分析】在平面内，把一个图形整体沿某条直线方向平行移动一定距离的过程，称为平移；在平面内，把一个图形围绕某一固定点按顺时针或逆时针方向转动一定的角度的过程，称为旋转。由此解答。\n\n【详解】风车遇到风会发生旋转现象；电梯上升是平移现象。",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "22-23二年级下·湖北恩施·阶段练习"
+  },
+  {
+    "id": "487",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "风车被吹动时是( )现象，抽屉的推拉是( )现象。",
+    "options": [],
+    "answer": "旋转;平移",
+    "solution": "【分析】在平面内，把一个图形整体沿某条直线方向平行移动一定距离的过程，称为平移；在平面内，把一个图形围绕某一固定点按顺时针或逆时针方向转动一定的角度的过程，称为旋转。据此进行判断即可。\n\n【详解】由分析可知：风车被吹动时是旋转现象，抽屉的推拉是平移现象。",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "23-24二年级下·甘肃平凉·期末"
+  },
+  {
+    "id": "488",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "商场的电梯的升降是平移现象。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】在平面内，把一个图形整体沿某条直线方向平行移动一定距离的过程，称为平移。平移前后，图形的形状、大小和方向均不会改变。据此解答。\n\n【详解】由分析可得，商场的电梯升降是平移现象，原题说法正确。故答案为：√",
+    "knowledge_points": [
+      "平移与平移现象"
+    ],
+    "source": "23-24二年级上·广东韶关·期中"
+  },
+  {
+    "id": "489",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "判断题",
+    "difficulty": 0.65,
+    "question": "按如图的方法剪一剪，展开后得到的是骨头。( )\n![](images/26233f7a100849177fd20f29806becc48b0086f17559e9545fd07ddb15dfa4b0.jpg)",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】把一个图形沿着某一条直线折叠，如果直线两旁的部分能够互相重合，那么这个图形就是轴对称图形，这条直线就是对称轴，据此解答即可。\n\n【详解】根据图示，按如图的方法剪一剪，展开后得到的是骨头。故答案为：√",
+    "knowledge_points": [
+      "轴对称的剪纸问题"
+    ],
+    "source": "23-24 二年级上·河南驻马店·期中"
+  },
+  {
+    "id": "490",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "树上的苹果掉在地上属于旋转现象。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】平移后图形的位置改变，形状、大小、方向不变。旋转后图形的位置和方向改变，形状、大小不变。\n\n【详解】树上的苹果掉在地上属于平移现象。原题说法错误。故答案为：×",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "23-24 二年级下·河南商丘·期末"
+  },
+  {
+    "id": "491",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "图形是通过旋转形成的。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】在平面内，把一个图形围绕某一固定点按顺时针或逆时针方向转动一定的角度的过程，称为旋转。物体或图形旋转后，它们的形状、大小都不改变，只是位置发生变化。由此判断即可。\n\n【详解】由分析可知，原图是由基本图形通过旋转形成的。原题说法正确。故答案为：√",
+    "knowledge_points": [
+      "旋转与旋转现象"
+    ],
+    "source": "23-24 二年级下·湖南衡阳·期末"
+  },
+  {
+    "id": "492",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "交通标志是一个轴对称图形。( )\n![](images/0b91456e33b4f188792ada6a24a1ee93a33ff3eefb0f17601cb398d9d9697e7e.jpg)",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】如果沿某条直线对折，对折的两部分能够完全重合，这样的图形就是轴对称图形。这条直线叫做这个图形的对称轴。判断一个图案是否是轴对称图形，关键是看能否找到这样一条直线，使图形对折后能够完全重合。\n\n【详解】找不到一条直线使图形沿着这条直线对折后能够完全重合，所以这个交通标志不是轴对称图形。原题说法错误。故答案为：×",
+    "knowledge_points": [
+      "轴对称的认识及辨认"
+    ],
+    "source": "23-24 二年级下·湖北孝感·期末"
+  },
+  {
+    "id": "493",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "□、△、☆都是轴对称图形。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】如果沿某条直线对折，对折的两部分能够完全重合，这样的图形就是轴对称图形。这条直线叫做这个图形的对称轴。判断一个图案是否是轴对称图形，关键是看能否找到一条直线，使图形沿着这条直线对折后能够完全重合。\n\n【详解】□、△、☆都是轴对称图形。原题说法正确。故答案为：√",
+    "knowledge_points": [
+      "轴对称的认识及辨认"
+    ],
+    "source": "23-24 二年级下·河南南阳·期末"
+  },
+  {
+    "id": "494",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "判断题",
+    "difficulty": 0.65,
+    "question": "我国的甲骨文中，都是轴对称的文字。( )\n![](images/4a12c97a7d83934f7237a98faa9afeeec989bdbb50ecf93fa800bc6e24cd42cb.jpg)\n![](images/64eb45f93d32b1ec1b56c25c7e1cd2890320abb027fe70a28f5add4da668e7f8.jpg)\n![](images/da9066f5977375dcfa3c77be8527184518c935a262973c36843cec9e8309726d.jpg)",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】一个图形沿一条直线对折，直线两旁的图形能够完全重合，这样的图形就是轴对称图形，折痕所在的直线就是对称轴。据此解答。\n\n【详解】由图可知，第一个字和第二个字是轴对称图形，而第三个字不是轴对称图形。原题说法错误。故答案为：×",
+    "knowledge_points": [
+      "轴对称的认识及辨认"
+    ],
+    "source": "23-24 四年级下·云南曲靖·期末"
+  },
+  {
+    "id": "495",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "“品”“工”“水”都是轴对称图形。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】如果一个图形沿着一条直线对折，两侧的图形能完全重合，这个图形就是轴对称图形。\n\n【详解】由分析可得：“品”“工”沿着一条直线对折后，两侧的图形能完全重合；“水”不能沿着一条直线对折后完全重合，所以“水”不是轴对称图形。原题说法错误。故答案为：×",
+    "knowledge_points": [
+      "轴对称的认识及辨认"
+    ],
+    "source": "23-24 二年级下·湖北荆门·期末"
+  },
+  {
+    "id": "496",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "判断题",
+    "difficulty": 0.65,
+    "question": "“1、2、3、4”这几个数字都是轴对称图形。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】如果一个图形沿某条直线对折，折痕两侧的部分能够完全重合，那么这个图形就是轴对称图形；对折时折痕所在的直线叫对称轴，据此解答。\n\n【详解】根据分析可得，这几个数字不都是轴对称图形，比如“2”“4”都不是轴对称图形。故答案为：×",
+    "knowledge_points": [
+      "轴对称的认识及辨认"
+    ],
+    "source": "23-24 二年级下·山东济宁·期末"
+  },
+  {
+    "id": "497",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "判断题",
+    "difficulty": 0.65,
+    "question": "自行车在公路上跑，既有旋转现象又有平移现象。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】平移和旋转都是物体或图形的位置发生变化而形状、大小不变。区别在于，平移时物体沿直线运动，本身方向不发生改变；旋转是物体绕着某一点或轴运动，本身方向发生变化。据此解答即可。\n\n【详解】自行车在公路上跑时，车轮的运动是旋转现象，车身的运动是平移现象，所以既有旋转现象又有平移现象。原说法正确。故答案为：√",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "23-24 二年级下·江西吉安·期末"
+  },
+  {
+    "id": "498",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "风车转动，电梯升降，推拉抽屉都是旋转现象。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】在平面内，把一个图形整体沿某条直线方向平行移动一定距离的过程，称为平移；在平面内，把一个图形围绕某一固定点按顺时针或逆时针方向转动一定的角度的过程，称为旋转。由此解答。\n\n【详解】由分析可知，风车转动是旋转现象；电梯升降、推拉抽屉是平移现象。原题说法错误。故答案为：×",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "23-24二年级下·河北·期末"
+  },
+  {
+    "id": "499",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "箱子在地面上被拖动是平移现象，钟表上分针的运动是旋转现象。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】在平面内，把一个图形整体沿某条直线方向平行移动一定距离的过程，称为平移；在平面内，把一个图形围绕某一固定点按顺时针或逆时针方向转动一定的角度的过程，称为旋转。由此解答。\n\n【详解】由分析可知，箱子在地面上被拖动是平移现象，钟表上分针的运动是旋转现象。原题说法正确。故答案为：√",
+    "knowledge_points": [
+      "平移与平移现象",
+      "旋转与旋转现象"
+    ],
+    "source": "22-23二年级下·四川绵阳·期末"
+  },
+  {
+    "id": "500",
+    "unit": "第三单元 图形的运动（一）",
+    "question_type": "解答题",
+    "difficulty": 0.65,
+    "question": "奶奶吃完晚饭从镜子里看到的时间是5:20，当她散步30分钟回到家，镜子里的时间应该是几时几分。",
+    "options": [],
+    "answer": "4:50",
+    "solution": "【分析】奶奶从镜子里看到的时间是5:20，说明实际时间是6:40。30分钟后是7:10，这个时间在镜子里应该是4:50，可借助钟面图辅助理解。\n![](images/00f0f1cc0671533e9af1ca174d2638d9.png)\n\n【详解】奶奶从镜子里看到的时间是5:20，说明实际时间是6:40。6:40+30分钟=7:10，这个时间在镜子里应该是4:50。答：镜子里的时间应该是4:50。",
+    "knowledge_points": [
+      "镜面对称",
+      "一般时间与钟面指针的位置"
+    ],
+    "source": "23-24 二年级上·全国·课后作业"
+  }
+]
+
diff --git "a/\344\272\214\345\271\264\347\272\247\351\242\230\351\233\206/\344\272\214\345\271\264\347\272\247\344\270\213/\344\272\214\345\271\264\347\272\247\344\270\213\347\254\254\344\271\235\345\215\225\345\205\203\346\216\250\347\220\206.json" "b/\344\272\214\345\271\264\347\272\247\351\242\230\351\233\206/\344\272\214\345\271\264\347\272\247\344\270\213/\344\272\214\345\271\264\347\272\247\344\270\213\347\254\254\344\271\235\345\215\225\345\205\203\346\216\250\347\220\206.json"
new file mode 100644
index 0000000000000000000000000000000000000000..2a337f893cc1e929c1d34fda6ba718e1fde84177
--- /dev/null
+++ "b/\344\272\214\345\271\264\347\272\247\351\242\230\351\233\206/\344\272\214\345\271\264\347\272\247\344\270\213/\344\272\214\345\271\264\347\272\247\344\270\213\347\254\254\344\271\235\345\215\225\345\205\203\346\216\250\347\220\206.json"
@@ -0,0 +1,4620 @@
+[
+  {
+    "id": "1",
+    "unit": "第九单元 推理",
+    "question_type": "选择题",
+    "difficulty": 0.4,
+    "question": "希望小学举行学科素养竞赛，同学们对一贯刻苦学习，爱好读书的4名学生的成绩进行了如下估计:\n(1)丙得第一，乙得第二;(2)丙得第二，丁得第三;(3)甲得第二，丁得第四.\n比赛结果一公布，果然是这4名学生获得前4名。但以上三种估计，每一种只对了一半。第一名是( )。",
+    "options": [
+      "A. 甲",
+      "B. 乙",
+      "C. 丙",
+      "D. 丁"
+    ],
+    "answer": "C",
+    "solution": "【分析】解答关键是假设的条件必须满足三种说法中对一半错一半;如果(1)丙得第一是正确的，那么乙得第二就是错的，从而(2)丙得第二是错的，丁得第三是正确的;所以根据(1)(2)小题的假设，丙是第一是正确的，丁是第三是正确的，乙是第二是错的，那么只有甲是可以是第二，从而可以满足(3)中甲得第二是正确的，丁得第四是错误的，此题可解.\n【详解】假设(1)中丙得第一是正确的，那么乙得第二就是错的;从而(2)中丙得第二是错，丁得第三是正确的，那么丙是第一是正确的，丁是第三是正确的，甲是可以是第二;(3)中甲得第二是正确的，丁得第四是错误的，最后乙是第四，满足(1)中一半对一半错。则丙第一，甲第二，丁第三，乙第四。故答案为:C",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "25-26六年级上·江西上饶·月考"
+  },
+  {
+    "id": "2",
+    "unit": "第九单元 推理",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "猜数游戏：笑笑想好一个20以内的数字，淘气提问笑笑，笑笑只能回答\"是\"或\"不是\"，猜中数字则游戏结束。为了减少猜的次数，淘气第一次应该问( )。",
+    "options": [
+      "A. 比10大吗",
+      "B. 比4小吗",
+      "C. 比18小吗"
+    ],
+    "answer": "A",
+    "solution": "【分析】在猜数游戏中，最有效的策略是每次将剩余数字尽可能均分。选项A将20个数分为两组各10个，无论回答\"是\"或\"不是\"，都能将范围缩小一半，减少后续提问次数。选项B和C的分割方式会导致剩余数字数量差异较大，效率较低.\n【详解】淘气第一次提问应选择能将数字范围均分的问题。选项A\"比10大吗\"将20以内的数分为1~10和11~20两组，每组10个数，无论回答如何，剩余数字数量减半，后续提问次数最少。选项B和C的分割方式导致剩余数字数量不均，需更多提问。故答案为:A",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "25-26 二年级上·山西晋中·阶段练习"
+  },
+  {
+    "id": "3",
+    "unit": "第九单元 推理",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "小华，小明，小雪，小红四个同学里，有一个人参加了剪纸小组，一个人参加了画画小组，一个人参加了声乐小组，一个人参加了舞蹈小组，已知小华没有参加舞蹈小组，小明参加了画画小组，小雪参加了声乐小组，那么小红参加了( )小组。",
+    "options": [
+      "A. 剪纸",
+      "B. 画画",
+      "C. 声乐",
+      "D. 舞蹈"
+    ],
+    "answer": "D",
+    "solution": "【分析】根据题意得：四个同学分别参加剪纸小组，画画小组，声乐小组，舞蹈小组，已知小明参加了画画小组，小雪参加了声乐小组，只剩下剪纸小组和舞蹈小组;小华没有参加舞蹈小组，则她参加了剪纸小组，剩下的即为小红参加的小组。据此可得出答案.\n【详解】已知小明参加了画画小组，小雪参加了声乐小组，只剩下剪纸小组和舞蹈小组;又已知小华没有参加舞蹈小组，则他参加了剪纸小组，剩下的小红则参加了舞蹈小组。故答案为:D",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "24-25 五年级上·广东广州·期中"
+  },
+  {
+    "id": "4",
+    "unit": "第九单元 推理",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "小红，丽丽，小艳在100米赛跑中获得了前三名。小红得的不是金牌，丽丽没有获得银牌，小艳跑得比丽丽快。三人中获得金牌的是( )。",
+    "options": [
+      "A. 小红",
+      "B. 丽丽",
+      "C. 小艳"
+    ],
+    "answer": "C",
+    "solution": "【分析】根据题意，小红得的不是金牌，则可能获得银牌或铜牌;丽丽没有获得银牌，则可能获得金牌或铜牌;小艳跑得比丽丽快，说明丽丽没获得金牌而是获得铜牌，小红则获得银牌，小艳则获得金牌。据此解答.\n【详解】根据分析可知：三人中获得金牌的是小艳。故答案为:C",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "24-25三年级下·山西吕梁·期末"
+  },
+  {
+    "id": "5",
+    "unit": "第九单元 推理",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "甲，乙，丙三人中，只有一人会游泳。甲说：\"我会\";乙说：\"甲不会\";丙说：\"我不会\"。已知只有一人说真话，会游泳的是( )。",
+    "options": [
+      "A. 甲",
+      "B. 乙",
+      "C. 丙",
+      "D. 无法确定"
+    ],
+    "answer": "C",
+    "solution": "【分析】甲说\"我会\"，乙说\"甲不会\"，甲和乙的话相互矛盾，根据\"矛盾关系必有一真一假\"，所以甲和乙之中必有一人说真话，一人说假话。因为甲和乙之中已经有一人说真话，且题目中明确只有一人说真话，所以丙说的定是假话。丙说\"我不会\"是假话，那么其反面\"我会\"就是真话，所以会游泳的是丙.\n【详解】甲说\"我会\"，乙说\"甲不会\"，所以甲和乙之中必有一人说真话，一人说假话。只有一人说真话，所以丙说\"我不会\"是假话，那么其反面\"我会\"就是真话。所以会游泳的是丙。故答案为:C",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "24-25 六年级下·广东东莞·期末"
+  },
+  {
+    "id": "6",
+    "unit": "第九单元 推理",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "在下边的方格中，每行每列都有6-9这四个数，并且每个数在每行，每列都只出现一次,B是( ).\n![](images/67d7e9b9368b0a65f2c56bdd41add917de39bf501335fe514c18c779050bfb75.jpg)",
+    "options": [
+      "A. 6",
+      "B. 7",
+      "C. 8",
+      "D. 9"
+    ],
+    "answer": "D",
+    "solution": "【分析】根据题意可知：每行每列都有6-9这四个数，并且每个数在每行，每列都只出现一次,B所在的列已有7和8，则B不能是7和8，只能是6和9，因B所在列从上往下数第二格的隔壁是9，则第二格不能是9，则为6,B所在列从上往下数为8,6,7，则B为9.\n【详解】由分析可得：在下边的方格中，每行每列都有6-9这四个数，并且每个数在每行，每列都只出现一次,B是(9)。故答案为:D",
+    "knowledge_points": [
+      "推理问题",
+      "数表中的规律"
+    ],
+    "source": "24-25 二年级下·福建龙岩·期末"
+  },
+  {
+    "id": "7",
+    "unit": "第九单元 推理",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "下面是四年级四位同学参加50米赛跑的成绩:\n![](images/8fffe76671ef6431dbe2ad9b697ddd8cccd1f990722d35293d3e6b81670e84a3.jpg)\n张晨跑得最快，李强比刘力跑得慢，比王健跑得快，李强的成绩是( )秒。",
+    "options": [
+      "A. 8",
+      "B. 9",
+      "C. 10"
+    ],
+    "answer": "B",
+    "solution": "【分析】根据赛跑成绩，用时越少跑得越快。张晨最快，成绩最小，所以张晨是7秒，李强比刘力慢但比王健快，说明李强成绩在刘力和王健之间，也就是张晨第一，刘力第二，李强第三，王健第四，据此解题.\n【详解】下面是四年级四位同学参加50米赛跑的成绩：张晨跑得最快，李强比刘力跑得慢，比王健跑得快，李强的成绩是9秒。故答案为:B",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "24-25三年级下·河南驻马店·期末"
+  },
+  {
+    "id": "8",
+    "unit": "第九单元 推理",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "东东，明明，丁丁三人比赛跑步，东东说：\"我不是最后一名\"。明明说：\"我跑得最快\"，丁丁是第( )名。",
+    "options": [
+      "A. 一",
+      "B. 二",
+      "C. 三"
+    ],
+    "answer": "C",
+    "solution": "【分析】根据题意，三人比赛跑步，则从快到慢依次为第一名，第二名，第三名。通过明明的话可以确定明明的名次，再根据东东的话确定东东及丁丁的名次即可.\n【详解】由分析得：明明跑得最快，也就是第一名;还剩下第二名和第三名;又知东东不是最后一名，则最后一名是丁丁，东东是第二名。丁丁是第三名。故答案为:C",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "24-25二年级下·云南文山·期末"
+  },
+  {
+    "id": "9",
+    "unit": "第九单元 推理",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "小红，小芳和小兰进行跳绳比赛，小红说：\"我跳的不是最少\"。小芳说：\"小兰跳的最多\"从多到少的顺序是( )。",
+    "options": [
+      "A. 小兰，小红，小芳",
+      "B. 小兰，小芳，小红",
+      "C. 小芳，小红，小兰",
+      "D. 小红，小芳，小兰"
+    ],
+    "answer": "A",
+    "solution": "【分析】由题意可知：小芳说：\"小兰跳的最多\"，小兰排第一;小红说：\"我跳的不是最少\"，小红排第二;小芳排第三;据此可选择.\n【详解】由分析可得：从多到少的顺序是：小兰，小红，小芳。故答案为:A",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "24-25 二年级下·福建龙岩·期末"
+  },
+  {
+    "id": "10",
+    "unit": "第九单元 推理",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "小青说\"我有一些糖果\"，小江说：\"我的不是最少的\"。小可说：\"小青的是最多的\"。从少到多的顺序是( )。",
+    "options": [
+      "A. 小红，小可，小青",
+      "B. 小可，小江，小青",
+      "C. 小青，小江，小可"
+    ],
+    "answer": "B",
+    "solution": "【分析】根据小可说：\"小青的是最多的\"，说明小青的糖果数量最多;根据小江说：\"我的不是最少的\"，说明小江的糖果数量不是最少，同时小江的糖果数量也不是最多的;则小可的糖果数量最少.\n【详解】由分析可得：三个同学的糖果数量从少到多的顺序是：小可，小江，小青。故答案为:B",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "24-25 二年级下·山东菏泽·期末"
+  },
+  {
+    "id": "11",
+    "unit": "第九单元 推理",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "聪聪，小欢，小明三个好朋友比赛跳绳，分别跳了65下,79下,76下，聪聪说：\"我跳的最接近80下\"，小欢说：\"我跳的不是最少的\"，由此推断小明跳了( )下。",
+    "options": [
+      "A. 65",
+      "B. 79",
+      "C. 76"
+    ],
+    "answer": "A",
+    "solution": "【分析】聪聪跳的下数最接近80下,79最接近80，所以聪聪跳了79下。又因为小欢不是跳的最少的，所以小明是三个人中跳的最少的，据此解答即可.\n【详解】据分析可知：小明是三个人中跳的下数最少的，所以小明跳了65下。故答案为:A",
+    "knowledge_points": [
+      "推理问题",
+      "100以内数的比大小"
+    ],
+    "source": "24-25 二年级下·四川凉山·期末"
+  },
+  {
+    "id": "12",
+    "unit": "第九单元 推理",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "在下边的方格中，每行，每列都有1~4这四个数，并且每个数在每行，每列都只出现一次。A应该是( ).\n![](images/6681aaa545f3b78525e3f80e37ae712d963136e1eeb29183fb58713e7f23acb5.jpg)",
+    "options": [
+      "A. 1",
+      "B. 2",
+      "C. 3"
+    ],
+    "answer": "A",
+    "solution": "【分析】要解决这个数独问题，我们需要根据\"每行，每列都有1~4这四个数，并且每个数在每行，每列都只出现一次\"的规则来推理。根据题目条件，每行每列都有1-4这四个数，且每个数在每行每列都只出现一次。观察A所在的行和列，发现其中已经出现了数字2和4，因此A不可能是2或4,A所在的行和列已有数字2,4，排除2和4，可能的取值为1或3，据此结合各个选项进行分析，排除重复的情况，即可得出答案.\n【详解】A。 若A=1，检查A所在的行和列是否有重复数字。此时,A所在的行和列中已有2,4，加上1后无重复;同时，第四行第2格为1，与第四行第1格的1不重复，其他行和列也无重复数字，因此A=1符合条件。B。 A所在的行或列中已经出现了数字2，若A=2，则会导致该行或列中出现两个2，不符合每个数在每行每列只出现一次的条件。C。 若A=3，此时第四行第2格为1，而第四行第1格已有1，导致第四行出现两个1，不符合条件。故答案为:A",
+    "knowledge_points": [
+      "数表中的规律"
+    ],
+    "source": "24-25 二年级下·四川成都·期末"
+  },
+  {
+    "id": "13",
+    "unit": "第九单元 推理",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "小聪，小明和小慧中有一人在阅读比赛中获得第一名。小聪说：我是第一名;小明说：我是第一名;小慧说：小明不是第一名。已知他们三人中有1人说了假话，说假话的是( )。",
+    "options": [
+      "A. 小聪",
+      "B. 小明",
+      "C. 小慧"
+    ],
+    "answer": "B",
+    "solution": "【分析】只有1人说了假话，其中小明和小慧两人说话相互矛盾，假设两个中1个说假话，再分析即可解答.\n【详解】三人中有1人说了假话，假设小慧说假话，则小明和小聪说的是真话，就会形成小聪是第一名与小明是第一名互相矛盾，所以小慧说的是真话，从而推断出说假话的是小明。故答案为:B",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "24-25六年级下·河南郑州·期末"
+  },
+  {
+    "id": "14",
+    "unit": "第九单元 推理",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "某小学举办了\"数学欢乐\"竞赛活动，竞赛项目有：酷炫的速叠杯，有趣的魔方，好玩的数字华容道。君君，萍萍，果果都只参加了一项竞赛项目，果果说：\"我没有参加酷炫的速叠杯\"，君君说：\"我既没有参加好玩的数字华容道也没有参加酷炫的速叠杯\"，萍萍参加了( )竞赛。",
+    "options": [
+      "A. 酷炫的速叠杯",
+      "B. 好玩的数字华容道",
+      "C. 有趣的魔方"
+    ],
+    "answer": "A",
+    "solution": "【分析】君君，萍萍，果果都只参加了一项竞赛项目，君君既没有参加好玩的数字华容道也没有参加酷炫的速叠杯，那君君参加的是有趣的魔方;而果果没有参加酷炫的速叠杯，那果果参加的是好玩的数字华容道;剩下的萍萍参加了酷炫的速叠杯.\n【详解】由题意分析得:A. 萍萍参加了酷炫的速叠杯竞赛;B. 果果参加了好玩的数字华容道竞赛;C. 君君参加了有趣的魔方竞赛;故答案为:A",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "24-25二年级下·贵州铜仁·期末"
+  },
+  {
+    "id": "15",
+    "unit": "第九单元 推理",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "甲乙丙三人中，有一个医生，一个教师，一个司机。甲说：我不是教师;乙说：我是医生;丙说：我不是司机。根据他们的描述确定甲的职业是( )。",
+    "options": [
+      "A. 医生",
+      "B. 教师",
+      "C. 司机"
+    ],
+    "answer": "C",
+    "solution": "【分析】根据题意，已知甲乙丙三人中，有一个医生，一个教师，一个司机。甲说：我不是教师;可知甲可能是医生或司机;乙说：我是医生;丙说：我不是司机;可以推断甲是司机，丙是教师，以此选择即可.\n【详解】根据分析可知：甲乙丙三人中，有一个医生，一个教师，一个司机。甲说：我不是教师;乙说：我是医生;丙说：我不是司机。根据他们的描述确定甲的职业是司机。故答案为:C",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "24-25 三年级下·广西贵港·期末"
+  },
+  {
+    "id": "16",
+    "unit": "第九单元 推理",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "早上,5个朋友各自拥有一部充满电且型号相同的手机。到了晚上，小敏的通话时间等于小红和小可通话时间的总和。小敏的手机没电了，小丽没有使用手机。小安的手机是( ).\n![](images/46e3613a0b9cb97144703375aae2dafbdf4cf2ae4d7c1804d2234f6f8354f492.jpg)",
+    "options": [
+      "A. 2",
+      "B. 3",
+      "C. 4",
+      "D. 5"
+    ],
+    "answer": "A",
+    "solution": "【分析】根据题意可知，小敏的手机没电了，观察图可知，图3是小敏的手机;小丽没有使用手机，所以小丽的手机是满电，观察图可知，图1是小丽的手机;小敏的通话时间等于小红和小可通话时间的总和，小敏手机没电，观察图可知，图4与图5总耗电量等于小敏的全部耗电量，图4和图5是小红和小可的手机，剩下的图2就是小安的手机，据此解答.\n【详解】根据分析可知，早上,5个朋友各自拥有一部充满电且型号相同的手机。到了晚上，小敏的通话时间等于小红和小可通话时间的总和。小敏的手机没电了，小丽没有使用手机。小安的手机是2。故答案为:A",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "24-25 五年级下·重庆渝中·期末"
+  },
+  {
+    "id": "17",
+    "unit": "第九单元 推理",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "小明，小红，小方三人进行跑步比赛。小明说：\"我不是第一名\"。小方说：\"我也不是第一名，但是我的成绩比小明好\"。那么以下说法正确的是( )。",
+    "options": [
+      "A. 第一名是小红，最后一名是小方",
+      "B. 第一名是小方，最后一名是小红",
+      "C. 第一名是小明，最后一名是小方",
+      "D. 第一名是小红，最后一名是小明"
+    ],
+    "answer": "D",
+    "solution": "【分析】由题意可知：小明说：\"我不是第一名\"，小方说：\"我也不是第一名，那么小红是第一名;小方说：\"我也不是第一名，但是我的成绩比小明好\"，说明小方排小明前面，是第二名，小明排最后一名;据此可选择.\n【详解】由分析可得：那么以下说法正确的是第一名是小红，最后一名是小明。故答案为:D",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "24-25 二年级下·福建厦门·期末"
+  },
+  {
+    "id": "18",
+    "unit": "第九单元 推理",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "在下边的方格里，每行每列都有1-4这四个数字，并且每行每列只出现1次,B是( ).\n| | 4 | | |\n| ---- | ---- | ---- | ---- |\n| | B | | 1 |\n| | 3 | | |\n| 2 | A | 3 | |",
+    "options": [
+      "A. 1",
+      "B. 2",
+      "C. 4"
+    ],
+    "answer": "B",
+    "solution": "【分析】与A,B同一列有数字4和3，则A,B只能是1或2;并且与B一行的有数字1，则B=2,A=1.\n【详解】根据分析可得:B=2。故答案为:B",
+    "knowledge_points": [
+      "数表中的规律"
+    ],
+    "source": "24-25 二年级下·浙江杭州·期末"
+  },
+  {
+    "id": "19",
+    "unit": "第九单元 推理",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "小雨，小芳，小明三人比赛跳绳，小明说：\"我不是最后一名.\"小芳说：\"我也不是最后一名，但小明跳的次数比我多一些.\"谁是第一名。( )",
+    "options": [
+      "A. 小明",
+      "B. 小雨",
+      "C. 小芳"
+    ],
+    "answer": "A",
+    "solution": "【分析】根据小明说：\"我不是最后一名.\"小芳说：\"我也不是最后一名，但小明跳的次数比我多一些.\"说明小明和小芳都不是第三名，他们是第一名和第二名，同时小明跳的次数比小芳多一些，说明小明是第一名，小芳是第二名，小雨是第三名，据此解答.\n【详解】由分析可得：小雨，小芳，小明三人比赛跳绳，小明说：\"我不是最后一名.\"小芳说：\"我也不是最后一名，但小明跳的次数比我多一些.\"小明是第一名。故答案为:A",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "24-25二年级下·海南省直辖县级单位·期末"
+  },
+  {
+    "id": "20",
+    "unit": "第九单元 推理",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "乐乐比贝贝重，皮皮比贝贝轻，最轻的是( )。",
+    "options": [
+      "A. 乐乐",
+      "B. 贝贝",
+      "C. 皮皮",
+      "D. 无法确定"
+    ],
+    "answer": "C",
+    "solution": "【分析】乐乐比贝贝重，皮皮比贝贝轻，则乐乐最重，皮皮最轻，把他们体重从重到轻排列起来：乐乐的体重>贝贝的体重>皮皮的体重，逐项分析各个选项，即可解答.\n【详解】A。 乐乐是最重的，不是最轻;B. 贝贝比皮皮重，不是最轻;C. 符合最轻的条件;D. 题目信息充分，可以确定皮皮最轻。故答案为:C",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "24-25 二年级下·浙江湖州·期末"
+  },
+  {
+    "id": "21",
+    "unit": "第九单元 推理",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "农场里鸭比鹅多一些，鸭比鸡少得多。哪种动物最少。( )",
+    "options": [
+      "A. 鸡",
+      "B. 鸭",
+      "C. 鹅"
+    ],
+    "answer": "C",
+    "solution": "【分析】根据题意，鸭比鹅多一些，说明鸭的数量多于鹅;鸭比鸡少得多，说明鸡的数量远多于鸭。因此，数量排序为鸡>鸭>鹅，鹅最少.\n【详解】根据分析，农场里鸭比鹅多一些，鸭比鸡少得多，则鸡>鸭>鹅，鹅最少。故答案为:C",
+    "knowledge_points": [
+      "数的相对大小关系",
+      "推理问题"
+    ],
+    "source": "24-25二年级下·四川成都·期中"
+  },
+  {
+    "id": "22",
+    "unit": "第九单元 推理",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "三个小朋友假期里分别在三个兴趣班学习，学的是唱歌，美术和舞蹈。小云说：\"我不爱唱歌.\"小红说：\"我和小云学的都不是美术.\"小云学的( )。",
+    "options": [
+      "A. 美术",
+      "B. 唱歌",
+      "C. 舞蹈"
+    ],
+    "answer": "C",
+    "solution": "【分析】总共有唱歌，美术和舞蹈三个兴趣班，根据小云说她学的不是唱歌，再根据小红说小云学的不是美术，那么小云只能学舞蹈.\n【详解】根据分析，小云学的不是唱歌，不是美术，只能学舞蹈。故答案为:C",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "24-25 二年级下·湖南·期末"
+  },
+  {
+    "id": "23",
+    "unit": "第九单元 推理",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "如下图，每行每列都有我，爱，黄，河这四个字，并且每个字在每行，每列中只出现一次,B是( ).\n![](images/8d7b642a4891a5cea1f67c04c26d1b294102495f41400cef10d125a841d4ea6b.jpg)",
+    "options": [
+      "A. 爱",
+      "B. 黄",
+      "C. 河"
+    ],
+    "answer": "B",
+    "solution": "【分析】根据第二行有爱和黄字，缺少我和河，第四行第三列有我，则第二行第三列不可能是我，只能是河，从而得出A的位置是我，第四行第一列是黄;根据第三列有我和河，缺少爱和黄，第三行第一列是爱，则B的位置不可能是爱，一定是黄;据此解答.\n【详解】由分析可得：如下图，每行每列都有我，爱，黄，河这四个字，并且每个字在每行，每列中只出现一次,B是黄。故答案为:B",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "24-25 二年级下·浙江台州·期末"
+  },
+  {
+    "id": "24",
+    "unit": "第九单元 推理",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "按☆△□□☆△□□。的规律排列，第26个图形是( )。",
+    "options": [
+      "A. ☆",
+      "B. △",
+      "C. □"
+    ],
+    "answer": "B",
+    "solution": "【分析】根据题意可知，每组以☆△□□4个图形循环，计算出第26个图形是第几组循环零几个图形，零几个图形就是每组循环中的第几个图形，即可判断其形状.\n【详解】26÷4=6(组)。2(个),则余数是2，为每组的第2个图形，是△。由此可知按☆△□□☆△□□。的规律排列，第26个图形是△。故答案为:B",
+    "knowledge_points": [
+      "100以内有余数的除法计算",
+      "图形的变化规律",
+      "周期问题"
+    ],
+    "source": "24-25二年级下·贵州黔东南·期末"
+  },
+  {
+    "id": "25",
+    "unit": "第九单元 推理",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "有甲，乙，丙三个人，一个是语文老师，一个是数学老师，一个是体育老师。甲，乙经常和体育老师学打乒乓球，乙带学生去找数学老师辅导数学。语文老师是( )。",
+    "options": [
+      "A. 甲",
+      "B. 乙",
+      "C. 丙"
+    ],
+    "answer": "B",
+    "solution": "【分析】根据题干信息，我们可以逐步推理出语文老师是谁。第一条信息：\"甲，乙经常和体育老师学打乒乓球.\"这说明体育老师既不是甲，也不是乙，因此，体育老师只能是丙。第二条信息：\"乙带学生去找数学老师辅导数学.\"这说明乙不是数学老师，结合第一条信息，体育老师是丙，所以乙不是体育老师，也不是数学老师。因此，乙只能是语文老师.\n【详解】根据分析可得：有甲，乙，丙三个人，一个是语文老师，一个是数学老师，一个是体育老师。甲，乙经常和体育老师学打乒乓球，乙带学生去找数学老师辅导数学。语文老师是乙。故答案为:B",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "24-25 二年级下·广东江门·期末"
+  },
+  {
+    "id": "26",
+    "unit": "第九单元 推理",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "三种蔬菜：白菜，萝卜和豆角，萝卜最便宜，白菜不是最贵的，最贵的是( )。",
+    "options": [
+      "A. 白菜",
+      "B. 萝卜",
+      "C. 豆角"
+    ],
+    "answer": "C",
+    "solution": "【分析】三种蔬菜：白菜，萝卜和豆角，萝卜最便宜;剩下的白菜和豆角，白菜不是最贵的，那白菜的价格排在第二，因此，最贵的是豆角;据此解决.\n【详解】由分析可知：三种蔬菜：白菜，萝卜和豆角，萝卜最便宜，白菜不是最贵的，最贵的是(豆角)。故答案为:C",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "24-25二年级下·云南昭通·期末"
+  },
+  {
+    "id": "27",
+    "unit": "第九单元 推理",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "小亮，小林，小兰三人踢毽子，分别踢了12下,8下和9下，小亮不是最少的，小林比小亮踢得多，小兰踢了( )下。",
+    "options": [
+      "A. 12",
+      "B. 8",
+      "C. 9"
+    ],
+    "answer": "B",
+    "solution": "【分析】根据小亮，小林，小兰三人踢毽子，分别踢了12下,8下和9下，小亮不是最少的，小林比小亮踢得多，说明小林踢得最多，是12下，小亮踢了9下，则小兰踢了8下.\n【详解】由分析可得：小亮，小林，小兰三人踢毽子，分别踢了12下,8下和9下，小亮不是最少的，小林比小亮踢得多，小兰踢了8下。故答案为:B",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "24-25 二年级下·黑龙江佳木斯·期末"
+  },
+  {
+    "id": "28",
+    "unit": "第九单元 推理",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "豆豆，泡泡和丁丁分别是语文，数学和英语三科的课代表中的一个。已知豆豆是语文课代表，泡泡不是英语课代表，则丁丁是( )。",
+    "options": [
+      "A. 语文课代表",
+      "B. 数学课代表",
+      "C. 英语课代表"
+    ],
+    "answer": "C",
+    "solution": "【分析】根据题意，豆豆，泡泡和丁丁分别是语文，数学和英语三科的课代表中的一个，其中豆豆是语文课代表，泡泡不是英语课代表，则泡泡就是数学课代表，那么丁丁就是英语课代表，据此选答案.\n【详解】由分析可得：豆豆，泡泡和丁丁分别是语文，数学和英语三科的课代表中的一个。已知豆豆是语文课代表，泡泡不是英语课代表，则丁丁是英语课代表。故答案为:C",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "24-25 二年级下·广西玉林·期末"
+  },
+  {
+    "id": "29",
+    "unit": "第九单元 推理",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "1分钟跳绳比赛，甲，乙，丙获得了前三名。甲说：\"我不是第一名.\"乙说：\"我不是第二名.\"丙说：\"甲和乙都比我跳得快.\"第一名是( )。",
+    "options": [
+      "A. 甲",
+      "B. 乙",
+      "C. 丙"
+    ],
+    "answer": "B",
+    "solution": "【分析】根据丙说：\"甲和乙都比我跳得快.\"说明丙跳的最少，是第三名;根据甲说：\"我不是第一名.\"说明甲是第二名;根据乙说：\"我不是第二名.\"说明乙是第一名;据此选答案.\n【详解】由分析可得:1分钟跳绳比赛，甲，乙，丙获得了前三名。甲说：\"我不是第一名.\"乙说：\"我不是第二名.\"丙说：\"甲和乙都比我跳得快.\"第一名是乙。故答案为:B",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "24-25 二年级下·贵州铜仁·期末"
+  },
+  {
+    "id": "30",
+    "unit": "第九单元 推理",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "有三张卡片，上面分别标有7,9,0，小明，文文，丁丁每人拿了一张，小明拿的不是7，文文拿的是最大的一位数。丁丁拿的是( )。",
+    "options": [
+      "A. 7",
+      "B. 9",
+      "C. 0"
+    ],
+    "answer": "A",
+    "solution": "【分析】由题意可知：小明拿的不是7，小明可能拿的是9或0，文文拿的是最大的一位数9，说明小明拿的是0，丁丁拿的是7;据此可解.\n【详解】由分析可得：有三张卡片，上面分别标有7,9,0，小明，文文，丁丁每人拿了一张，小明拿的不是7，文文拿的是最大的一位数。丁丁拿的是7。故答案为:A",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "24-25 二年级下·重庆梁平·期末"
+  },
+  {
+    "id": "31",
+    "unit": "第九单元 推理",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "如下图，在方格中，每行，每列都有1~4这四个数，并且每个数在每行，每列都只出现一次，则A表示的数是( ).\n| 3 | | 2 | |\n| ---- | ---- | ---- | ---- |\n| | 2 | | |\n| 4 | 1 | A | |\n| | | | |",
+    "options": [
+      "A. 4",
+      "B. 3",
+      "C. 2"
+    ],
+    "answer": "B",
+    "solution": "【分析】根据规则，第三行已有数字4和1，第三列已有数字2，因此A只能是3.\n【详解】第三行已有数字4和1，缺少2和3，那么A可能是2或3，第三列中第一行已有2，因此第三行第三列不能为2，只能填3。因此A表示的数是3。故答案为:B",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "24-25 二年级下·甘肃庆阳·期末"
+  },
+  {
+    "id": "32",
+    "unit": "第九单元 推理",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "二(1)班投票评选\"书香少年\"，有3位候选人，下面是同学们的投票情况。选举当天，禾禾因请假未能参与投票，如果他也投了票，那么( ).\n| 姓名 | 岚岚 | 诚诚 | 君君 |\n| ------ | ---- | ------ | ---- |\n| 得票数 | 正正 | 正正正 | 正 |",
+    "options": [
+      "A. 君君被评为\"书香少年\"",
+      "B. 诚诚仍被评为\"书香少年\"",
+      "C. 岚岚有可能被评为\"书香少年\""
+    ],
+    "answer": "B",
+    "solution": "【分析】先数一数票数：岚岚得票\"正正\"为10票，诚诚得票\"正正正\"为15票，君君得票\"正\"为5票。禾禾只有1票，无论投给谁，都不能改变诚诚票数最多这一结果.\n【详解】A。 君君原来得5票，禾禾投1票后最多6票，不可能超过诚诚的15票，不符合题意;B. 诚诚原来得15票，无论禾禾把票投给谁，诚诚仍然票数最多，符合题意;C. 岚岚原来得10票，禾禾投1票后最多11票，也不能超过诚诚的15票，不符合题意。故答案为:B",
+    "knowledge_points": [
+      "数据的搜集与整理",
+      "20以内数的比大小"
+    ],
+    "source": "24-25 二年级下·河南三门峡·期末"
+  },
+  {
+    "id": "33",
+    "unit": "第九单元 推理",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "观察下面的图形，找出规律。横线上缺少的图形是( ).\n![](images/6fa5f8ffa3611489ee880bdeee93b5be.png)",
+    "options": [],
+    "answer": "C",
+    "solution": "【分析】由图形排列的规律可知，图形是按字母的顺序排列的，即B,C,D,E,F,G;且用同一个字母组成轴对称图形。在平面内，如果沿着一条直线折叠，直线两旁的部分能够完全重合，这样的图形叫做轴对称图形.\n【详解】由题意分析得：图形的排列顺序是:B,C,D,E,F,G。横线上缺少的图形是E的轴对称图形。故答案为:C",
+    "knowledge_points": [
+      "轴对称的认识及辨认",
+      "图形的变化规律"
+    ],
+    "source": "24-25 二年级下·河南三门峡·期末"
+  },
+  {
+    "id": "34",
+    "unit": "第九单元 推理",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "在下边的方格中，每行，每列都有1~4这四个数，并且每个数在每行，每列都只出现一次。A是( ),B是( ).\n| | | | 1 |\n| ---- | ---- | ---- | ---- |\n| 1 | | 4 | 2 |\n| | A | 3 | |\n| | | | B |",
+    "options": [
+      "A. 1;3",
+      "B. 2;4",
+      "C. 3;2",
+      "D. 4;1"
+    ],
+    "answer": "A",
+    "solution": "【分析】根据题意，从上往下第二行缺少数字3，从左往右第四列缺少数字3和4，由于第三行有数字3，所以B处是数字3,B上面是数字4，第三行缺少数字1和2，第一列有数字1，所以A处填1，据此解答.\n【详解】根据分析:A是1,B是3。故答案为:A",
+    "knowledge_points": [
+      "数表中的规律",
+      "推理问题"
+    ],
+    "source": "24-25 二年级下·四川乐山·期末"
+  },
+  {
+    "id": "35",
+    "unit": "第九单元 推理",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "下图方格中每行，每列中都有1~4这几个数，并且每个数在每行，每列都只出现一次,B应该是( ).\n| | | | 1 |\n| ---- | ---- | ---- | ---- |\n| 1 | | 4 | 2 |\n| | A | 3 | 4 |\n| | | 1 | B |",
+    "options": [
+      "A. 1",
+      "B. 2",
+      "C. 3"
+    ],
+    "answer": "C",
+    "solution": "【分析】根据题意，每行，每列都有1~4这四个数，并且每个数只出现一次，可以先从数字较多的行，列开始推理.\n【详解】第二行已有1,4,2，缺少3，所以第二行第二列填3。第三行已有3,4，缺少1和2;第三列已有4,3,1，缺少2，所以第三行第一列填2，第三行第二列A填1。第四列已有1,2,4，缺少3，所以B=3。故答案为:C",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "24-25 二年级下·山东菏泽·期末"
+  },
+  {
+    "id": "36",
+    "unit": "第九单元 推理",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "小明，小红和小兰三个同学踢毽子，分别是踢了25个,28个,30个，小明踢的个数不是最多的，小红踢的个数也不是最多的，小明比小红踢得多，那么踢了28个的是( )。",
+    "options": [
+      "A. 小明",
+      "B. 小红",
+      "C. 小兰",
+      "D. 无法确定"
+    ],
+    "answer": "A",
+    "solution": "【分析】根据题目信息，三个数中,30是最大的(30>28>25);既然小明和小红都不是最多的，那么小兰一定是最多的，即小兰踢了30个;剩下25个和28个是小明和小红踢的个数;\"小明比小红踢得多\"意味着小明的个数大于小红的个数，即28>25。因此，小明踢了28个，小红踢了25个.\n【详解】小明，小红和小兰三个同学踢毽子，分别是踢了25个,28个,30个，小明踢的个数不是最多的，小红踢的个数也不是最多的，小明比小红踢得多，那么踢了28个的是小明。故答案为:A",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "24-25 二年级下·浙江绍兴·期末"
+  },
+  {
+    "id": "37",
+    "unit": "第九单元 推理",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "乐乐要把4种玩具放回柜子。皮球不在右边，玩具熊在皮球下面，飞机模型不在左边，乐高在飞机模型上面。①号柜子里放( ),③号柜子里放( ).\n![](images/960c6ecec6a2696c2f27cd6a7c76fc74abf0951a0f0c1363c6ae5e1a9fe50b16.jpg)",
+    "options": [
+      "A. 皮球;乐高",
+      "B. 玩具熊;乐高",
+      "C. 乐高;皮球"
+    ],
+    "answer": "A",
+    "solution": "【分析】先根据\"皮球不在右边\"和\"玩具熊在皮球下面\"确定皮球可能的位置范围，再结合其他玩具的位置条件进一步推理，最终确定①号和③号柜子所放玩具。已知皮球不在右边，那么皮球可能在①号或②号柜子。又因为玩具熊在皮球下面，所以皮球只能在①号柜子;②柜子里放玩具熊;已知飞机模型不在左边，那么飞机模型可能在③号或④号柜子。又因为乐高在飞机模型上面，所以飞机模型只能在④号柜子，乐高在③号柜子.\n【详解】根据分析可知:①号柜里放的是皮球;②号柜里放的是玩具熊;③号柜里放的是乐高;④号柜里放的是飞机模型。①号柜子里放皮球,③号柜子里放乐高。故答案为:A",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "24-25 二年级下·江西上饶·期末"
+  },
+  {
+    "id": "38",
+    "unit": "第九单元 推理",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "小丽，小芳，小明一起排队上车，小明说：\"我在小丽和小芳的中间.\"小丽说：\"我不是第一个上车的.\"( )排在最后。",
+    "options": [
+      "A. 小丽",
+      "B. 小芳",
+      "C. 小明"
+    ],
+    "answer": "A",
+    "solution": "【分析】小明在小丽和小芳中间，可能的排列为：小丽，小明，小芳 或 小芳，小明，小丽。小丽不是第一个，排除第一种排列。因此顺序为小芳(第1),小明(第2),小丽(第3),最后的是小丽.\n【详解】小丽，小芳，小明一起排队上车，小明说：\"我在小丽和小芳的中间.\"小丽说：\"我不是第一个上车的.\"小丽排在最后。故答案为:A",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "24-25二年级下·江西上饶·期末"
+  },
+  {
+    "id": "39",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.4,
+    "question": "有两只猴，一只猫，一只狗和一只猪，五只动物排成一纵队，并且:①两只猴不相邻;②猫不与猴相邻;③排在最前面和最后面的动物不是同一种动物;④猫的前面紧挨着狗。从前往后数，猪排在第( )个。",
+    "options": [],
+    "answer": "2",
+    "solution": "【分析】先根据\"猫的前面紧挨着狗\"确定狗和猫相邻，顺序是\"狗，猫\";再结合\"猫不与猴相邻\"和\"两只猴不相邻\"进行推理.\n【详解】因为猫前面紧挨着狗，所以狗，猫的位置是连在一起的。猫不与猴相邻，所以猫后面不能是猴，只能是猪。这样狗，猫只能排在第4,5位，前面依次排两只猴和猪。又因为两只猴不相邻，所以从前往后只能排成：猴，猪，猴，狗，猫。由此可知，猪排在第2个。故答案为:2",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "2024 三年级·全国·竞赛"
+  },
+  {
+    "id": "40",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "小明家，小丽家，小红家的门牌号分别是8号,15号,27号的其中一个。小明家的门牌号是27号，小丽家的门牌号不是最小的，小红家的门牌号是( )号。",
+    "options": [],
+    "answer": "8",
+    "solution": "【分析】根据题意可知，因为小明家的门牌号是27号，那么小丽家的门牌号是8号或者15号，又因为小丽家的门牌号不是最小的，即小丽家的门牌号是15号，所以小红家的门牌号是8号。据此解答.\n【详解】由分析得：小红家的门牌号是8号。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "23-24三年级上·贵州铜仁·期中"
+  },
+  {
+    "id": "41",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "三个小朋友分别买了水果味，巧克力味和奶油味的冰淇淋，小青说：\"我的冰淇淋是奶油味的.\"小丽说：\"我的冰淇淋不是水果味的.\"那么小丽的冰淇淋是( )味，小刚的冰淇淋是( )味。",
+    "options": [],
+    "answer": "巧克力;水果",
+    "solution": "【分析】根据题意，小青买的冰淇淋口味是已知的，还剩下另外两种口味，则根据小丽说的话可以知道小丽冰淇淋的口味，剩下的一种口味就是小刚的冰淇淋口味.\n【详解】由分析得：小青的冰淇淋是奶油味的，剩下水果味和巧克力味;小丽的冰淇淋不是水果味的，也就是巧克力味的;则水果味的就是小刚的冰淇淋。小丽的冰淇淋是巧克力味，小刚的冰淇淋是水果味。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "24-25 二年级下·湖北恩施·期末"
+  },
+  {
+    "id": "42",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "小丽，小华和小东三人获得讲故事比赛前三名。小丽说：\"我不是第一名.\"小东说：\"我也不是第一名，但比小丽的成绩好.\"小丽是第( )名，小华是第( )名，小东是第( )名。",
+    "options": [],
+    "answer": "三;一;二",
+    "solution": "【分析】因为小丽和小东都说自己不是第一名，所以小华是第一名。又因为小东说他的成绩比小丽好，所以小东是第二名，小丽是第三名，据此解答即可.\n【详解】据分析可知：小丽是第三名，小华是第一名，小东是第二名。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "24-25二年级下·广东潮州·期末"
+  },
+  {
+    "id": "43",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "小东，小强和小亮比高矮。小东说：\"我最高.\"小强说：\"我不是最矮的.\"猜一猜，最矮的是( )。",
+    "options": [],
+    "answer": "小亮",
+    "solution": "【分析】小东说：\"我最高.\"说明小东不是最矮的;小强说：\"我不是最矮的.\"说明小强也不是最矮的;所以三个同学中，小亮最矮.\n【详解】小东，小强和小亮比高矮。小东说：\"我最高.\"小强说：\"我不是最矮的.\"猜一猜，最矮的是小亮。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "24-25二年级下·四川成都·期末"
+  },
+  {
+    "id": "44",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "甲，乙，丙，丁4人中只有一人做了好事。甲说：\"不是我做的.\"乙说：\"是丁做的.\"丙说：\"不是我做的.\"丁说：\"是甲做的.\"已知他们4人中只有1个人说的真话。请问：是( )做了好事。",
+    "options": [],
+    "answer": "丙",
+    "solution": "【分析】由于有一人说的是真话，那么其他三个人就是说的假话，假如甲说的是真话，那么可知，不是甲做的，乙说的是假话，那么也不是丁做的，丙说的不是他做的，也是假话，就是丙做的，丁说，是甲做的，也是假话，则不是甲做的，通过这个可知是丙做的;假如乙说了真话，甲说不是他做的，那是假话，是甲做的，乙说是丁做的，是真话，那是丁做的，冲突了，不符合题意;假如是丙说的真话，则甲说不是他做的，这句话是假的，是甲做的，乙说是丁做的，这句话是假话，不是丁做的，丙说不是我做的，这句话是真话，不是丙做的，丁说是甲做的，这句话是假话，不是甲做的。这句话和最开始的矛盾，所以不符合。假如是丁说的真话。其他三个人是假话，甲说不是他做的，这是假话，结果是甲做的，乙说是丁做的，这是假话，不是丁做的，丙说不是我做的，这是假话，是丙做的，丁说是甲做的，这是真话，是甲做的，和丙说的话矛盾。由此可知，甲说的是真话，这个是丙做的.\n【详解】由分析可知：甲，乙，丙，丁4人中只有一人做了好事。甲说：\"不是我做的.\"乙说：\"是丁做的.\"丙说：\"不是我做的.\"丁说：\"是甲做的.\"已知他们4人中只有1个人说的真话。请问：是丙做的。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "24-25 六年级下·重庆南川·期末"
+  },
+  {
+    "id": "45",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "小明，小红，小月三人在跑步比赛中获得了前三名。小红说：\"我不是第二名.\"小月说：\"小红和小明都比我跑得快.\"第一名是( ),第二名是( ),第三名是( )。",
+    "options": [],
+    "answer": "小红;小明;小月",
+    "solution": "【分析】由小月说：\"小红和小明都比我跑得快\"可知小月获得了第三名;小月是第三名，小红又说自己不是第二名，因此可知小红是第一名;小红是第一名，小月是第三名，因此小明是第二名.\n【详解】由分析可知：第一名是小红，第二名是小明，第三名是小月。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "24-25 二年级下·江西九江·期末"
+  },
+  {
+    "id": "46",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "小亮，小丫，小可三个人手中分别拿着足球，象棋和跳绳。小亮拿的是跳绳，小丫拿的不是象棋，小可拿的是( ),小丫拿的是( )。",
+    "options": [],
+    "answer": "象棋;足球",
+    "solution": "【分析】由题意可知：小亮拿的是跳绳，小丫拿的不是象棋，那么小丫拿的就是足球，小可拿的是象棋;据此可解.\n【详解】由分析可得：小亮，小丫，小可三个人手中分别拿着足球，象棋和跳绳。小亮拿的是跳绳，小丫拿的不是象棋，小可拿的是象棋，小丫拿的是足球。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "24-25 二年级下·江西赣州·期末"
+  },
+  {
+    "id": "47",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "在下面的方格中，每行每列都有1~4这四个数，并且每个数在每行，每列都只出现一次，那么A表示( ),B表示( ).\n| 2 | | A | 3 |\n| ---- | ---- | ---- | ---- |\n| | 3 | 2 | |\n| B | 1 | | |\n| 4 | | 3 | 1 |",
+    "options": [],
+    "answer": "1;3",
+    "solution": "【分析】根据题意，第四行有1,3,4缺少数字2，则第4行方格中是2;第二列有1,2,3缺少数字4，则第二列方格中是4;第一行有2,3,4缺少数字1，即A是1;第二行缺少数字4和1，但第4列已经有1，则第二行最后方格中是4，第一个方格中是1;第一列有1,2,4缺少数字3，即B是3。据此填空.\n【详解】由分析可得：在下面的方格中，每行每列都有1~4这四个数，并且每个数在每行，每列都只出现一次，那么A表示1,B表示3。",
+    "knowledge_points": [
+      "数表中的规律"
+    ],
+    "source": "24-25 二年级下·湖北黄冈·期末"
+  },
+  {
+    "id": "48",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "小亮，小丫，小可三个人手中分别拿着足球，象棋和跳绳。小亮拿的是象棋，小丫拿的不是足球，小可拿的是( ),小丫拿的是( )。",
+    "options": [],
+    "answer": "足球;跳绳",
+    "solution": "【分析】根据题目条件，通过排除法确定每个人所拿物品。已知小亮拿的是象棋，剩下足球和跳绳由小丫和小可分配，结合小丫不拿足球的条件，说明小丫拿的是跳绳，剩下足球则是小可拿的，即可得出答案.\n【详解】根据分析可得：小亮，小丫，小可三个人手中分别拿着足球，象棋和跳绳。小亮拿的是象棋，小丫拿的不是足球，小可拿的是足球，小丫拿的是跳绳。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "24-25二年级下·江西赣州·期末"
+  },
+  {
+    "id": "49",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "如图，要使每行，每列都出现1,2,3,4这四个数，并且每个数在每行，每列都只出现一次，那么A应该是( ),B应该是( ).\n![](images/c3cb82f634c9e6eb8297d7a04207120ab598fae7c419ab23495c33a05390d9f8.jpg)",
+    "options": [],
+    "answer": "1;2",
+    "solution": "【分析】根据题意，每行，每列都出现1,2,3,4这四个数，并且每个数在每行，每列都只出现一次，则从出现数字较多的地方入手。通过A,B所在的行，列已经出现的数字，进而得知它们各自所代表的数字是几.\n【详解】由分析得:A所在的行，列出现了2,3,4，则A应该是1;B所在的行，列出现了1,3,4，则B应该是2。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "24-25 二年级下·江西赣州·期末"
+  },
+  {
+    "id": "50",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "欢欢，乐乐和笑笑看《少儿百科全书》,欢欢剩下450页没看，乐乐剩下735页没看，笑笑剩下313页没看,( )看得最快,( )看得最慢。",
+    "options": [],
+    "answer": "笑笑;乐乐",
+    "solution": "【分析】根据被减数-减数=差，在被减数相同时，差越大则减数越小，差越小则减数越大。由此可知，书本的总页数-已经看的页数=剩余未看的页数，剩余未看的页数越多则已经看的页数越少。再根据比较数的大小，先看位数的多少，位数多的数就大;如果位数相同，从最高位开始比较，最高位上的数大则这个数大，最高位上的数相同，就比较下一位，依次类推。进行解答即可.\n【详解】三个人剩余的页数排序从小到大为:313<450<735，所以剩下的页数中，笑笑没看的最少，乐乐没看的页数最多，则笑笑看得最快，乐乐看得最慢。",
+    "knowledge_points": [
+      "1000以内数的比大小",
+      "推理问题"
+    ],
+    "source": "24-25 二年级下·湖北孝感·期末"
+  },
+  {
+    "id": "51",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "乐乐，欢欢，明明三个小朋友，他们分别喜欢唱歌，跳舞，游泳，已知乐乐不喜欢跳舞，也不喜欢游泳;欢欢喜欢游泳，那么明明喜欢( )。",
+    "options": [],
+    "answer": "跳舞",
+    "solution": "【分析】由题意可知：乐乐不喜欢跳舞，也不喜欢游泳，那么乐乐喜欢唱歌;欢欢喜欢游泳，明明喜欢跳舞。据此可填空.\n【详解】由分析可得：乐乐，欢欢，明明三个小朋友，他们分别喜欢唱歌，跳舞，游泳，已知乐乐不喜欢跳舞，也不喜欢游泳;欢欢喜欢游泳，那么明明喜欢跳舞。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "24-25 二年级下·浙江杭州·期末"
+  },
+  {
+    "id": "52",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "小亮，小丫，小可三个人手中分别拿着魔方，象棋和陀螺。小亮拿的不是象棋，小丫拿的不是魔方也不是象棋，小可拿的是( )。",
+    "options": [],
+    "answer": "象棋",
+    "solution": "【分析】由题意可知：小丫拿的不是魔方也不是象棋，小丫拿的是陀螺;小亮拿的不是象棋，小亮拿的是魔方;小可拿的是象棋。据此可填空.\n【详解】由分析可得：小亮，小丫，小可三个人手中分别拿着魔方，象棋和陀螺。小亮拿的不是象棋，小丫拿的不是魔方也不是象棋，小可拿的是象棋。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "24-25 二年级下·广东潮州·期末"
+  },
+  {
+    "id": "53",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "甲，乙，丙三个好朋友分别和家人去平潭，武夷山，东山岛旅游。甲没去平潭，去武夷山的不是丙，甲和乙正在听另一个朋友讲他在东山岛的见闻。甲去的是( ),乙去的是( ),丙去的是( )。",
+    "options": [],
+    "answer": "武夷山;平潭;东山岛",
+    "solution": "【分析】根据甲和乙听另一个朋友讲去东山岛的见闻，也就是甲和乙没有去东山岛，可知丙去的是东山岛。剩下的还有平潭和武夷山。又知甲没去平潭，也就是甲去的是武夷山，剩下去平潭的就是乙.\n【详解】由分析得：甲去的是武夷山，乙去的是平潭，丙去的是东山岛。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "24-25二年级下·福建厦门·期末"
+  },
+  {
+    "id": "54",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "在下边的方格中，每行，每列都有1~4这四个数，并且每个数在每行，每列都只出现一次。A是( ),B是( ).\n| 3 | 2 | | |\n| ---- | ---- | ---- | ---- |\n| A | | B | 2 |\n| | | 3 | |\n| 1 | | | |",
+    "options": [],
+    "answer": "4;1",
+    "solution": "【分析】根据题意，每行，每列都有1~4这四个数，并且每个数在每行，每列都只出现一次，则从出现数字较多的地方入手，先推算出A代表的数字，进而推算出B代表的数字.\n【详解】由分析得:A所在的行，列出现了1,2,3，则A是4;B所在的行，列出现了2,3,4，则B是1。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "24-25 二年级下·河南郑州·期末"
+  },
+  {
+    "id": "55",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "下面的方格中，每行，每列都有1~4这四个数，并且每个数在每行每列都只出现一次。那么A是( ),B是( ),C是( ).\n| | 1 | | 2 |\n| ---- | ---- | ---- | ---- |\n| 2 | | C | |\n| | B | | 4 |\n| 4 | | 3 | A |",
+    "options": [],
+    "answer": "1;3;1",
+    "solution": "【分析】根据题意，每行，每列都有1~4这四个数，并且每个数在每行每列都只出现一次，则从出现数字较多的地方入手。先推算出A代表的数字，进而可知A所在的行，列所缺少的数字，再由此推算出B和C代表的数字即可.\n【详解】由分析可知:A所在的行，列出现了2,3,4，则A只能是1;则第四列第2格是3;第二列第4格是2;此时B所在的行，列出现了1,2,4，则B只能是3;则第二列第2格是4;此时C所在的行，列出现了2,3,4，则C只能是1。即A是1,B是3,C是1。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "24-25 二年级下·浙江台州·期末"
+  },
+  {
+    "id": "56",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "有音乐，数学，品德三种书，小豪，小丽，小红各拿一本;小豪说：\"我拿的不是音乐书\"。小丽说：\"我拿的是数学书\"，小红拿的是( )书。",
+    "options": [],
+    "answer": "音乐",
+    "solution": "【分析】根据题意，小丽说：\"我拿的是数学书.\"，则剩下的音乐书，品德书分别是小豪和小红两人拿的，又知小豪说：\"我拿的不是音乐书\"，那么小豪拿的是品德书，剩下的书只有音乐书，因此小红拿的是音乐书.\n【详解】有音乐，数学，品德三种书，小豪，小丽，小红各拿一本;小豪说：\"我拿的不是音乐书\"。小丽说：\"我拿的是数学书\"，小红拿的是音乐书。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "23-24二年级下·云南昭通·期末"
+  },
+  {
+    "id": "57",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "在下面的方格中，每行，每列都有\"我爱数学\"这四个字，并且每个字在每行，每列都只出现一次,A是( ),B是( ).\n| | 我 | | |\n| ---- | ---- | ---- | ---- |\n| 爱 | A | 数 | |\n| | | | |\n| 数 | B | | |",
+    "options": [],
+    "answer": "学;爱",
+    "solution": "【分析】根据题意可知：每行，每列都有\"我爱数学\"这四个字，并且每个字在每行，每列都只出现一次，则A所在的行已有\"爱\";\"数\";A可能是\"我\"和\"学\",A所在的列已有\"我\"，则A是\"学\",B所在的行已有\"数\"，则B可能是\"我\"，\"爱\"，\"学\",B所在的列已有\"我\"，\"学\"，由此可知是\"爱\".\n【详解】由分析可得：在下面的方格中，每行，每列都有\"我爱数学\"这四个字，并且每个字在每行，每列都只出现一次,A是(学),B是(爱)。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "24-25 二年级下·湖北黄冈·期末"
+  },
+  {
+    "id": "58",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "三个小朋友的体重分别是20千克,23千克,25千克。其中聪聪比明明重，方方比聪聪重，聪聪的体重是( )千克。",
+    "options": [],
+    "answer": "23",
+    "solution": "【分析】根据题意可知，聪聪比明明重，方方比聪聪重，则他们的体重关系为：明明<聪聪<方方，再比较给出体重的大小，进而确定每个小朋友的体重，即可解答.\n【详解】明明<聪聪<方方;20千克<23千克<25千克。明明是最轻的，所以明明体重为20千克。聪聪是中间的，所以聪聪体重为23千克。方方是最重的，所以方方体重为25千克。三个小朋友的体重分别是20千克,23千克,25千克。其中聪聪比明明重，方方比聪聪重，聪聪的体重是23千克。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "24-25 二年级下·湖北随州·期末"
+  },
+  {
+    "id": "59",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "小亮，小兵，小可三个人中分别拿着魔方，象棋和陀螺中的一个。小亮拿的不是魔方，小兵拿的不是魔方也不是象棋，小可拿的是( )。",
+    "options": [],
+    "answer": "魔方",
+    "solution": "【分析】由题意可知：小亮和小兵拿的都不是魔方，那么小可拿的是魔方;据此可解.\n【详解】由分析可得：小亮，小兵，小可三个人中分别拿着魔方，象棋和陀螺中的一个。小亮拿的不是魔方，小兵拿的不是魔方也不是象棋，小可拿的是魔方。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "24-25 二年级下·甘肃天水·期末"
+  },
+  {
+    "id": "60",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "平平，安安，乐乐称体重，安安说：\"我不是最重的，但是比平平重.\"他们三人中,( )最重,( )最轻。",
+    "options": [],
+    "answer": "乐乐;平平",
+    "solution": "【分析】根据安安说的话可知：他们三个，安安排第二重，平平最轻，那么乐乐最重;据此可解.\n【详解】由分析可得：平平，安安，乐乐称体重，安安说：\"我不是最重的，但是比平平重.\"他们三人中，乐乐最重，平平最轻。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "24-25 二年级下·福建福州·期末"
+  },
+  {
+    "id": "61",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "三个盘子里分别放着瓜子，糖果和饼干。2号盘放瓜子,3号盘不是饼干,1号盘放的是( ),3号盘放的是( )。",
+    "options": [],
+    "answer": "饼干;糖果",
+    "solution": "【分析】根据题意可知,2号盘放瓜子，剩下1号盘和3号盘，需要放糖果和饼干,3号盘不是饼干，则3号盘只能是糖果，那么1号盘放的就是饼干.\n【详解】三个盘子里分别放着瓜子，糖果和饼干。2号盘放瓜子,3号盘不是饼干,1号盘放的是饼干,3号盘放的是糖果。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "24-25二年级下·黑龙江佳木斯·期末"
+  },
+  {
+    "id": "62",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "小军，小林和小明来自长江边，黄河边，珠江边的城市。小林说：\"我没去过长江\"。小明说：\"我没去过长江和珠江\"。( )来自珠江边城市。",
+    "options": [],
+    "answer": "小林",
+    "solution": "【分析】根据题意可知，小明说：\"我没去过长江和珠江\"，小明来自黄河边城市;小林说：\"我没去过长江\"小林来自珠江边城市。剩余小军来自长江边城市。据此解答.\n【详解】根据分析可得：小军，小林和小明来自长江边，黄河边，珠江边的城市。小林说：\"我没去过长江\"。小明说：\"我没去过长江和珠江\"。小林来自珠江边城市。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "24-25 二年级下·浙江台州·期末"
+  },
+  {
+    "id": "63",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "欢欢，优优，乐乐三个小朋友分别喜欢绘画，书法和弹琴。欢欢喜欢弹琴，乐乐不喜欢绘画，那么优优喜欢( )。",
+    "options": [],
+    "answer": "绘画",
+    "solution": "【分析】根据题意可知：欢欢喜欢弹琴，乐乐不喜欢绘画，由此可以推断出乐乐喜欢书法，优优喜欢绘画.\n【详解】由分析可得：欢欢，优优，乐乐三个小朋友分别喜欢绘画，书法和弹琴。欢欢喜欢弹琴，乐乐不喜欢绘画，那么优优喜欢(绘画)。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "24-25 二年级下·甘肃天水·期末"
+  },
+  {
+    "id": "64",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "苗苗，君君和贝贝三人一起折幸运星，分别折了25颗,27颗和35颗.\n![](images/fa7d1a1102d8ca99cfe024c260ec42b0.png)\n苗苗折了( )颗，君君折了( )颗，贝贝折了( )颗。",
+    "options": [],
+    "answer": "25;35;27",
+    "solution": "【分析】因为苗苗和贝贝都不是折的最多，所以君君折了最多，又因为贝贝比苗苗折的多，所以贝贝折的第二多，苗苗折的最少，据此解答即可.\n【详解】据分析可知：君君折的幸运星数量最多，是35颗。贝贝折的幸运星数量在三人里面排第二，所以贝贝折了27颗。苗苗折的幸运星数量最少，是25颗。即苗苗折了25颗，君君折了35颗，贝贝折了27颗。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "24-25 二年级下·吉林四平·期末"
+  },
+  {
+    "id": "65",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "在杭州举办的第19届亚运会有3个吉祥物，分别是琮琮，莲莲和宸宸。小华，小明和大伟各拿着1个吉祥物，小华拿的不是宸宸，小明拿的既不是莲莲，也不是宸宸，那么大伟拿的是( )。",
+    "options": [],
+    "answer": "宸宸",
+    "solution": "【分析】由题意可知：小明拿的既不是莲莲，也不是宸宸，小明拿的是琮琮;小华拿的不是宸宸，小华拿的是莲莲;大伟拿的是宸宸;据此可解.\n【详解】由分析可得：在杭州举办的第19届亚运会有3个吉祥物，分别是琮琮，莲莲和宸宸。小华，小明和大伟各拿着1个吉祥物，小华拿的不是宸宸，小明拿的既不是莲莲，也不是宸宸，那么大伟拿的是宸宸。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "24-25 二年级下·云南红河·期末"
+  },
+  {
+    "id": "66",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "小明，小东，小亮进行跳绳比赛，小明说：\"我不是第一名.\"小东说：\"我也不是第一名，但我比小明好.\"那么小明是第( )名。",
+    "options": [],
+    "answer": "三",
+    "solution": "【分析】小明说：\"我不是第一名.\"，那就是第二名或第三名;小东说：\"我也不是第一名，但我比小明好.\"则小东是第二名，那么小明是第三名，小亮是第一名.\n【详解】由题意分析得：小明，小东，小亮进行跳绳比赛，小明说：\"我不是第一名.\"小东说：\"我也不是第一名，但我比小明好.\"那么小明是第三名。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "24-25 二年级下·浙江台州·期末"
+  },
+  {
+    "id": "67",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "小明，小丽，小华三位同学进行跳绳比赛，小明说：\"我不是最后一名.\"小丽说：\"我也不是最后一名，但是小明比我的成绩好.\"他们三人中,( )是第一名。",
+    "options": [],
+    "answer": "小明",
+    "solution": "【分析】小明，小丽，小华三人进行跳绳比赛，由小明的说法可知，小明是第一名或者第二名，由小丽的说法可知，她也是第一名或第二名，又因为小明跳的比小丽多，所以，小丽是第二名，小明是第一名，据此判断.\n【详解】根据分析可知，小明，小丽，小华三位同学进行跳绳比赛，小明说：\"我不是最后一名.\"小丽说：\"我也不是最后一名，但是小明比我的成绩好.\"他们三人中，小明是第一名。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "24-25 三年级下·河北保定·期末"
+  },
+  {
+    "id": "68",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "推理：谁是小雷锋。学校表彰了4位同学，其中有一人是主动打扫了图书馆卫生的\"小雷锋\"。甲说：\"我没打扫图书馆卫生.\"乙说：\"是丁打扫的图书馆卫生.\"丙说：\"我没打扫图书馆卫生.\"丁说：\"是甲打扫的图书馆卫生.\"已知他们4人中只有1人说了真话，请问主动打扫图书馆卫生的是谁。( )",
+    "options": [],
+    "answer": "丙",
+    "solution": "【分析】这是一道真假推理题，解题的关键在于找出矛盾关系，再结合只有一人说真话这一条件进行推理.\n【详解】观察发现甲说的\"我没打扫图书馆卫生\"和丁说的\"是甲打扫的图书馆卫生\"相互矛盾。因为矛盾关系必定一真一假，而题目中明确只有一人说真话，所以真话就在甲和丁之中。由此可知乙和丙说的都是假话。因为乙说\"是丁打扫的图书馆卫生\"是假的，所以不是丁打扫的。又因为丙说\"我没打扫图书馆卫生\"是假的，所以可以确定是丙打扫了图书馆卫生。综上，主动打扫图书馆卫生的是丙。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "24-25六年级下·湖南常德·期末"
+  },
+  {
+    "id": "69",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "小明，小强，小红三个小朋友分别拿着数字卡片63,72,107中的一张。小强说：\"我拿的不是72.\"小明说：\"我拿的数字个位和十位上都不是7\"。小明拿的是( ),小强拿的是( ),小红拿的是( )。",
+    "options": [],
+    "answer": "63;107;72",
+    "solution": "【分析】根据题意可知,72和107一个十位上是7，一个个位上是7，则小明拿的不会是72和107中的任何一个数，只能是63。又因为小强拿的不是72，所以小强拿的数只能是107。最后剩下的数则被小红拿走，由此解答即可.\n【详解】由小明说：\"我拿的数字个位和十位上都不是7\"可知：小明拿的是63，结合小强说：\"我拿的不是72.\"可知小强拿的是107，则小红拿的是72。综上可知：小明拿的是63，小强拿的是107，小红拿的是72。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "24-25 二年级下·河北张家口·期末"
+  },
+  {
+    "id": "70",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "小明和爸爸妈妈站成一排照相，小明站在中间可以照出( )张不同的照片。",
+    "options": [],
+    "answer": "2",
+    "solution": "【分析】用列举法，列举出小明站在中间时的站位情况，即可得出答案.\n【详解】第一种：爸爸，小明，妈妈;第二种：妈妈，小明，爸爸。所以小明站在中间可以照出2张不同的照片。",
+    "knowledge_points": [
+      "排列问题"
+    ],
+    "source": "24-25 二年级下·河北唐山·期末"
+  },
+  {
+    "id": "71",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "小力，小华，小敏三人进行跳绳比赛。小敏说：\"我不是第一名.\"小华说：\"我也不是第一名，但是我比小敏成绩好.\"小华是第( )名，小力是第( )名。",
+    "options": [],
+    "answer": "二;一",
+    "solution": "【分析】小敏和小华都说她们不是第一名，所以小力是第一名。又因为小华成绩比小敏好，所以小华是第二名，小敏是第三名，据此解答即可.\n【详解】小敏说：\"我不是第一名.\"小华说：\"我也不是第一名.\"由此推断，小力是第一名;小华说：\"我比小敏成绩好.\"由此推断，小华是第二名;那么小敏是第三名。填空如下：小华是第(二)名，小力是第(一)名。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "24-25 二年级下·甘肃庆阳·期末"
+  },
+  {
+    "id": "72",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "小明，小青和小杰三个人在赛跑。小明说：\"我跑得不是最快的，但比小杰快.\"( )跑得最快,( )跑得最慢。",
+    "options": [],
+    "answer": "小青;小杰",
+    "solution": "【分析】由题意可知：小明说：\"我跑得不是最快的，但比小杰快.\"说明小明，小杰都不是跑的最快的，小青是跑的最快的，小杰跑的最慢，小明跑的排第二;据此可解.\n【详解】由分析可得：小明，小青和小杰三个人在赛跑。小明说：\"我跑得不是最快的，但比小杰快.\"小青跑得最快，小杰跑得最慢。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "24-25 二年级下·四川乐山·期末"
+  },
+  {
+    "id": "73",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "欢欢，乐乐，聪聪，笑笑排队上车，笑笑在欢欢和乐乐中间，聪聪在最后。欢欢不是第一个,( )在最前面。",
+    "options": [],
+    "answer": "乐乐",
+    "solution": "【分析】根据题意，欢欢不是第一，笑笑在欢欢和乐乐中间，聪聪在最后，那么乐乐是第一个，笑笑是第二个，第三个是欢欢，第四个是聪聪，所以乐乐 笑笑 欢欢 聪聪这样排列，据此解答.\n【详解】根据分析：欢欢，乐乐，聪聪，笑笑排队上车，笑笑在欢欢和乐乐中间，聪聪在最后。欢欢不是第一个,(乐乐)在最前面。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "24-25二年级下·山东菏泽·期末"
+  },
+  {
+    "id": "74",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "在下边的方格中，每行，每列都有1~4这四个数，并且每个数在每行，每列都只出现一次.\n| | | | |\n| ---- | ---- | ---- | ---- |\n| 3 | B | | 1 |\n| | 2 | | |\n| | A | 3 | |\nA是( ),B是( )。",
+    "options": [],
+    "answer": "1;4",
+    "solution": "【分析】根据第二行已有数字3和1，缺少2和4，第三行第二列已有数字2，所以B的位置不可能是2，只能是4;第二列已有数字2和4，第四行第三列已有数字3，所以A的位置不可能是3，只能是1.\n【详解】由分析可得:A是1,B是4。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "24-25 二年级下·广东东莞·期末"
+  },
+  {
+    "id": "75",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "小芳，小红，小丽三个小朋友比赛跳绳。小芳说：\"我得分最少.\"小丽说：\"我不是第一名.\"请你猜一猜，小芳是第( )名，小红是第( )名。",
+    "options": [],
+    "answer": "三;一",
+    "solution": "【分析】根据题意，小芳的得分最少，说明小芳是第三名;小丽不是第一名，说明小丽是第二名;那小红就是第一名了.\n【详解】由分析可得：小芳，小红，小丽三个小朋友比赛跳绳。小芳说：\"我得分最少.\"小丽说：\"我不是第一名.\"请你猜一猜，小芳是第三名，小红是第一名。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "24-25 二年级下·广东东莞·期末"
+  },
+  {
+    "id": "76",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "小亮，小明，小丽三个人，有一个人属牛，有一个人属虎，还有一个人属兔。小亮说：\"我不属虎\"。小明说：\"我的属相不是吃草动物.\"小丽说：\"我不属牛\"。小亮属( ),小丽属( )。",
+    "options": [],
+    "answer": "牛;兔",
+    "solution": "【分析】根据题意，题中牛和兔是吃草动物，虎不是吃草的动物，小明说：\"我的属相不是吃草动物\"，由此可推断出小明的属相，再根据小丽说：\"我不属牛\"，推断出小丽的属相，最后即可推断出小亮的属相，据此解答.\n【详解】小明说：\"我的属相不是吃草动物\"，由此可推断出小明属虎，再根据小丽说：\"我不属牛\"，推断出小丽属兔，最后推断出小亮属牛。因此，小亮属牛，小丽属兔。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "24-25 二年级下·广西河池·期末"
+  },
+  {
+    "id": "77",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "在下面的方格中，每行，每列都有1~4这四个数，并且每行，每列都只出现一次。B应该是( ).\n![](images/93de6a67bec753f8571e094ac87b08696938b02e0829836227a31ba60a03ab81.jpg)",
+    "options": [],
+    "answer": "2",
+    "solution": "【分析】根据题意，每行，每列都有1~4这四个数，并且每个数在每行，每列都只出现一次。则先根据A所在的行，列出现的数字确定出A代表的数字，进而确定B代表的数字.\n【详解】A所在的行，列出现了1,3,4，则A应该是2;则第三行已出现了1,2,4，所以第三行第三个数是3;第一行已出现了2,3，第三列已有4，所以，第一行和第三列的交叉处是1;这样B所在的行，列出现了1,3,4，则B应该是2。",
+    "knowledge_points": [
+      "数表中的规律"
+    ],
+    "source": "24-25二年级下·湖北黄石·期末"
+  },
+  {
+    "id": "78",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "三人分别是厨师，司机，画家。甲：\"我不是厨师也不是司机.\"乙：\"我不是画家.\"丙：\"我不是司机.\"甲是( ),乙是( ),丙是( )。",
+    "options": [],
+    "answer": "画家;司机;厨师",
+    "solution": "【分析】根据题意，三人分别是厨师，司机，画家。通过甲：\"我不是厨师也不是司机.\"，可确定甲是画家;再通过丙：\"我不是司机.\"，可确定丙是厨师;再通过乙：\"我不是画家.\"，可确定乙是司机;据此解答.\n【详解】由分析可得：三人分别是厨师，司机，画家。甲：\"我不是厨师也不是司机.\"乙：\"我不是画家.\"丙：\"我不是司机.\"甲是画家，乙是司机，丙是厨师。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "24-25 三年级下·河北邯郸·期末"
+  },
+  {
+    "id": "79",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "在右面的方格中，每行，每列都有\"我\"\"爱\"\"祖\"\"国\"这四个字，并且每个字在每行，每列都只出现一次。请你想一想,A是( ),B是( ).\n![](images/321cfabdd934376b3ddda50a5d45651144c3c07f90601af180c59ffeb09ae672.jpg)",
+    "options": [],
+    "answer": "我;爱",
+    "solution": "【分析】根据题意，每行每列每个字只能出现一次，从左往右第三列缺少的字最少，缺少了我和国，从上往下第二行中有国，所以A只能是我，这时第二行缺少了爱和祖，由于第一列中有祖，所以B只能是爱，据此解答.\n【详解】根据分析：在图中的方格中，每行，每列都有\"我\"\"爱\"\"祖\"\"国\"这四个字，并且每个字在每行，每列都只出现一次。请你想一想,A是(我),B是(爱)。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "23-24 二年级下·湖北荆州·期末"
+  },
+  {
+    "id": "80",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "三名同学比高矮。小亮比小明高，小红比小明矮。这三名同学中( )最矮。",
+    "options": [],
+    "answer": "小红",
+    "solution": "【分析】小亮比小明高，小红比小明矮，则小亮最高，小红最矮。据此做题即可.\n【详解】三名同学比高矮。小亮比小明高，小红比小明矮。这三名同学中小红最矮。",
+    "knowledge_points": [
+      "比高矮",
+      "推理问题"
+    ],
+    "source": "24-25 二年级下·湖南长沙·期末"
+  },
+  {
+    "id": "81",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "淘气，笑笑和小明三人跑步比赛，笑笑说：\"我跑得既不是最快，又不是最慢\"，小明说：\"我后面没有人了\"，他们三人中( )是冠军。",
+    "options": [],
+    "answer": "淘气",
+    "solution": "【分析】小明说：\"我后面没有人了\"，说明小明跑得最慢，笑笑说：\"我跑得既不是最快，又不是最慢\"，说明笑笑比小明跑得快，比淘气跑得慢，综合可知淘气跑得最快.\n【详解】由分析可知：淘气跑得最快，笑笑第二，小明跑得最慢。因此，他们三人中淘气是冠军。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "24-25三年级下·四川成都·期末"
+  },
+  {
+    "id": "82",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "A,B,C三个小朋友比赛赛跑。A说：\"我跑得比C快.\"C说：\"我不是最慢的\"。请你猜一猜,( )跑第一,( )跑第二,( )跑最慢。",
+    "options": [],
+    "answer": "A;C;B",
+    "solution": "【分析】根据A和C的陈述进行逻辑推理。A比C快，说明A的名次在C之前;C不是最慢的，说明C只能是第一或第二。结合两者得出唯一可能的排名.\n【详解】由分析可知：若C是第1名，则A的陈述\"A比C快\"不成立(矛盾),排除此情况。若C是第2名，根据A的陈述,A必须比C快，即A是第1名。此时B只能是第3名，满足C的陈述(C不是最慢)。若C是第3名，与C的陈述矛盾，排除此情况。即,A跑第一,C跑第二,B跑最慢。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "24-25二年级下·湖南长沙·期末"
+  },
+  {
+    "id": "83",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "甲，乙，丙三人的职业分别是军人，老师，书法家其中的一种，甲不是军人，他和乙正在听书法家讲书法的相关知识，那么甲的职业是( )。",
+    "options": [],
+    "answer": "老师",
+    "solution": "【分析】根据题意，甲，乙，丙三人的职业分别是军人，老师，书法家其中的一种，甲不是军人，则甲可能是老师或书法家;又根据甲和乙正在听书法家讲书法的相关知识，说明丙是书法家，甲不是书法家，所以甲的职业是老师.\n【详解】由\"甲不是军人，他和乙正在听书法家讲书法的相关知识\"可知：甲的职业是老师。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "24-25 二年级下·湖北襄阳·期末"
+  },
+  {
+    "id": "84",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "环保小公民奇思比较了东北虎，扬子鳄，金丝猴，熊猫四种濒危动物的数量，发现金丝猴不是最多的，但比东北虎和熊猫多，熊猫比东北虎多，这四种濒危动物的数量从多到少排序，排在第三位的是( )。",
+    "options": [],
+    "answer": "熊猫",
+    "solution": "【分析】金丝猴不是最多的，但比东北虎和熊猫多，说明金丝猴的数量比东北虎和熊猫多，但不是最多，只可能扬子鳄数量最多，熊猫比东北虎多，那么四种濒危动物的数量扬子鳄数量>金丝猴的数量>熊猫的数量>东北虎的数量，据此解答.\n【详解】由分析可知：扬子鳄数量>金丝猴的数量>熊猫的数量>东北虎的数量，排在第三位的是熊猫。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "24-25三年级下·福建泉州·期末"
+  },
+  {
+    "id": "85",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "小亮，小刚和小李进行一分钟跳绳比赛。小亮说：\"我不是跳得最少的.\"小刚说：\"我不是第一名，也不是最后一名.\"那么,( )是第一名。",
+    "options": [],
+    "answer": "小亮",
+    "solution": "【分析】小刚说：\"我不是第一名，也不是最后一名.\"则小刚是第二名;小亮说：\"我不是跳得最少的.\"那么小亮是第一名，小李是第三名.\n【详解】根据分析：小亮，小刚和小李进行一分钟跳绳比赛。小亮说：\"我不是跳得最少的.\"小刚说：\"我不是第一名，也不是最后一名.\"那么，小亮是第一名。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "24-25二年级下·浙江温州·期末"
+  },
+  {
+    "id": "86",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "三个小朋友比身高，小明比小红高，小丽比小红矮，最矮的是( )。",
+    "options": [],
+    "answer": "小丽",
+    "solution": "【分析】根据题意小明比小红高，所以小明>小红，小丽比小红矮，所以小红>小丽。将三者之间的身高关系进行整理后，找出最矮的人即可解答.\n【详解】根据分析可知：他们的身高从高到低排列是：小明>小红>小丽。所以，最矮的是小丽。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "24-25 二年级下·浙江温州·期末"
+  },
+  {
+    "id": "87",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "小力，小华，小敏三人进行跳绳比赛。小敏说：\"我不是第一名.\"小华说：\"我也不是第一名，但是我比小敏成绩好.\"小华获得第( )名，小敏获得第( )名，小力获得第( )名。",
+    "options": [],
+    "answer": "二或2;三或3;一或1",
+    "solution": "【分析】根据题意，他们三人分别为第一名，第二名，第三名。通过小敏和小华不是第一名，可确定第一名是谁;再通过小华比小敏成绩好可得知小华和小敏的名次.\n【详解】由分析得：小敏和小华都不是第一名，则小力是第一名;小华成绩比小敏好，也就是名次比小敏高，则小华是第二名，小敏是第三名。小华获得第二(或2)名，小敏获得第三(或3)名，小力获得第一(或1)名。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "24-25二年级下·湖北襄阳·期末"
+  },
+  {
+    "id": "88",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "袋子里有红色，黄色，蓝色小球各1个，小伟，小林和小芳三位同学分别取出一个球。如果小伟没有取出黄球，小林取出的是红球，则小芳取出的小球是( )球，小伟取出的小球是( )球。",
+    "options": [],
+    "answer": "黄;蓝",
+    "solution": "【分析】根据题意，小伟没有取出黄球，说明他取出的是(红蓝)其中的一个，小林取出红球，小伟取出的是蓝球，还有一个黄球就是小芳取出的，据此解答.\n【详解】根据分析：袋子里有红色，黄色，蓝色小球各1个，小伟，小林和小芳三位同学分别取出一个球。如果小伟没有取出黄球，小林取出的是红球，则小芳取出的小球是黄球，小伟取出的小球是蓝球。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "24-25 二年级下·河北邢台·期末"
+  },
+  {
+    "id": "89",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "在下面的方格中，每行，每列都有1~4这四个数，并且每个数在每行，每列都只出现一次。那么B表示的数字是( ),A表示的数字是( ).\n| 2 | 3 | | |\n| ---- | ---- | ---- | ---- |\n| | | 4 | |\n| 4 | A | | 1 |\n| | | B | |",
+    "options": [],
+    "answer": "2;2",
+    "solution": "【分析】这是一道数字推理的逻辑题，解题关键在于利用每行，每列数字1~4都只出现一次的规则来逐步推导.\n【详解】确定A的值：观察A所在的行，已经有数字1和4。再看A所在的列，已经有数字3。因为每行，每列都要包含1~4这四个数，且每个数只能出现一次，所以A不能是1,3,4，那么A只能是2。确定B的值：因为A是2，所以A所在行的第3个数是3。那么B所在这一列，有了数字3和4，则B可能是1或2，而第一行有数字2和3，所以B所在这列的第一个数不能是2，只能为1。因为每行，每列都要包含1~4这四个数，且每个数只能出现一次，那么B只能是2。综上可知,B表示的数字是2,A表示的数字是2。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "24-25 二年级下·河北邢台·期末"
+  },
+  {
+    "id": "90",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "在下面的方格中，每行，每列都有1~4这四个数，并且每个数在每行，每列都只出现一次,A是( ),B是( ).\n| 4 | | B | |\n| ---- | ---- | ---- | ---- |\n| | | 3 | |\n| 1 | | A | 4 |\n| | | | |",
+    "options": [],
+    "answer": "2;1",
+    "solution": "【分析】第三行已有数字1和4，因此A所在位置(第三行第三列)只能填2或3。第三列中，第二行第三列已有3，因此A不能填3，只能填2。第一行第三列(B的位置)所在列已有数字3(第二行),2(第三行),因此B只能填1或4。第一行第一列已有4，因此B不能填4，只能填1.\n【详解】在下面的方格中，每行，每列都有1~4这四个数，并且每个数在每行，每列都只出现一次,A是2,B是1。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "24-25 二年级下·江西上饶·期末"
+  },
+  {
+    "id": "91",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "在下边的方格里，每行每列都有1~4这4个数字。并且每行每列都只出现1次,A是( ),B是( ).\n| | | | |\n| ---- | ---- | ---- | ---- |\n| | | B | 1 |\n| 4 | 3 | | |\n| 2 | A | 3 | |",
+    "options": [],
+    "answer": "1;2或4",
+    "solution": "【分析】每行，每列需填入1~4且不重复。通过观察表格中已知数字，逐步排除确定A和B的值。第四行已有数字2(列1),3(列3),因此该行缺少1和4。第四行中，若A填1，则第四行第四列需填4;若A填4，则第四行第四列需填1。但列4已有1(第二行),因此第四行第四列必须填4，故A=1。第二行第三列(B所在位置)所在的列3已有数字1(第三行)和3(第四行),因此B不能为1或3，只能为2或4.\n【详解】在下边的方格里，每行每列都有1~4这4个数字。并且每行每列都只出现1次,A是1,B是2或4。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "24-25 二年级下·湖北武汉·期末"
+  },
+  {
+    "id": "92",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "有语文，数学和英语三本书，下面三人各拿一本。安安拿的是语文书，乐乐拿的不是英语书，乐乐拿的是( )书，笑笑拿的是( )书。",
+    "options": [],
+    "answer": "数学;英语",
+    "solution": "【分析】根据题目条件，三人各拿一本不同的书。已知安安拿语文书，剩余数学和英语书由乐乐和笑笑分配。乐乐不拿英语书，因此只能拿数学书，剩下英语书由笑笑拿.\n【详解】有语文，数学和英语三本书，下面三人各拿一本。安安拿的是语文书，乐乐拿的不是英语书，乐乐拿的是数学书，笑笑拿的是英语书。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "24-25二年级下·湖北武汉·期末"
+  },
+  {
+    "id": "93",
+    "unit": "第九单元 推理",
+    "question_type": "排序题",
+    "difficulty": 0.65,
+    "question": "王老师发下数学试卷后，三(1)班A,B,C,D四名同学进行了以下谈话.\nA:\"只有一人成绩比我高.\"\nB:\"我比你们三人的成绩都高.\"\nC:\"我的成绩不是最低的.\"\nD:\"我这次没有发挥好，所以这次考试成绩不理想.\"\n请根据以上谈话内容，把四人数学成绩从高到低排序( )。",
+    "options": [],
+    "answer": "BACD",
+    "solution": "【分析】A说，只有一个人成绩比我高，那么A就是第二名;B说，我比你们三人的成绩都高，说明B是第一名;C说，我的成绩不是最低的，由于第一名和第二名已经确定，说明C是四个人中的第三名;已经确定第一，第二，第三名，则D就是第四名。据此解答.\n【详解】由分析可知,B是第一名,A是第二名,C是第三名,D是第四名，四个人数学成绩从高到低排序是BACD。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "24-25 三年级下·河北石家庄·期末"
+  },
+  {
+    "id": "94",
+    "unit": "第九单元 推理",
+    "question_type": "排序题",
+    "difficulty": 0.85,
+    "question": "4个好朋友玩猜年龄游戏。小睿说：\"我不是最大的，也不是最小的.\"小孟说：\"你们都是我的哥哥姐姐.\"小植说：\"只有小孟比我小.\"小夏说：\"我只比小睿大1岁.\"把年龄按照从大到小的顺序排排队:( )>( )>( )>( )。",
+    "options": [],
+    "answer": "小夏;小睿;小植;小孟",
+    "solution": "【分析】小孟说：\"你们都是我的哥哥姐姐.\"这意味着小孟比其他人年龄都小，因此小孟是最小的;小植说：\"只有小孟比我小.\"这表示：小孟比小植小，小植的年龄排第三;小睿说：\"我不是最大的，也不是最小的.\"结合小孟最小，小睿不是最小，符合题意;小睿不是最大，因此最大的一定是剩余的人(小夏);小夏说：\"我只比小睿大1岁.\"这确认小夏比小睿大1岁;因此小夏是最大的，小睿是第二大，据此解答.\n【详解】根据分析可得：把年龄按照从大到小的顺序排排队：小夏>小睿>小植>小孟。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "25-26一年级上·江苏·课后作业"
+  },
+  {
+    "id": "95",
+    "unit": "第九单元 推理",
+    "question_type": "排序题",
+    "difficulty": 0.65,
+    "question": "飞飞，明明，丁丁三位同学比身高，明明比飞飞矮，丁丁比飞飞高。他们的身高从高到矮排序正确的是( )>( )>( )。",
+    "options": [],
+    "answer": "丁丁;飞飞;明明",
+    "solution": "【分析】明明比飞飞矮，说明飞飞的身高>明明的身高，丁丁比飞飞高，说明丁丁的身高>飞飞的身高，然后进一步推断即可.\n【详解】明明比飞飞矮，说明飞飞的身高>明明的身高，丁丁比飞飞高，说明丁丁的身高>飞飞的身高，所以丁丁的身高>飞飞的身高>明明的身高，所以他们的身高从高到矮排序正确的是丁丁>飞飞>明明。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "24-25二年级下·福建福州·期末"
+  },
+  {
+    "id": "96",
+    "unit": "第九单元 推理",
+    "question_type": "判断题",
+    "difficulty": 0.65,
+    "question": "思思，小海，小文分别住在同一幢楼的一，二，三楼，思思不住在三楼，小海常去一楼找小文玩，则小海住在二楼。( )",
+    "options": [],
+    "answer": "×",
+    "solution": "【分析】根据题意，三人分别住在一，二，三楼且楼层不同。已知思思不住三楼，小海常去一楼找小文，说明小文住一楼。由此可推断思思住二楼，小海只能住三楼.\n【详解】根据分析可知，小文住在一楼，思思住在二楼，小海住在三楼，原说法错误。故答案为: ×",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "24-25 二年级下·陕西渭南·期末"
+  },
+  {
+    "id": "97",
+    "unit": "第九单元 推理",
+    "question_type": "判断题",
+    "difficulty": 0.65,
+    "question": "4个小朋友甲，乙，丙，丁，如果甲比丙轻，但比丁重，而丁比乙重，那么4人中最重的是丙。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】根据题目中的条件，将四个小朋友的体重关系进行比较，确定他们的体重顺序，从而判断最重的是否为丙.\n【详解】由题可知,1. 甲比丙轻，即丙>甲;2. 甲比丁重，即甲>丁;3. 丁比乙重，即丁>乙。将上述关系综合可得：丙>甲>丁>乙。因此，四人中最重的是丙，原题目结论正确。故答案为:√",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "24-25 六年级下·河南南阳·期末"
+  },
+  {
+    "id": "98",
+    "unit": "第九单元 推理",
+    "question_type": "解答题",
+    "difficulty": 0.85,
+    "question": "小轿车，客车，货车和公交车，四种车进行了4场比赛，比赛结果如下:\n(1)小轿车比客车跑得快;(2)客车比货车跑得快;(3)货车比公交车跑得快;(4)小轿车比公交车跑得快。哪一辆车跑得最快。",
+    "options": [],
+    "answer": "小轿车",
+    "solution": "【分析】根据题意可知:(1)小轿车比客车跑得快，则小轿车>客车;(2)客车比货车跑得快，则客车>货车，也就是小轿车>客车>货车;(3)货车比公交车跑得快，则货车>公交车，也就是小轿车>客车>货车>公交车;(4)小轿车比公交车跑得快，则小轿车>公交车.\n【详解】由分析可得：小轿车>客车>货车>公交车。答：小轿车跑得最快。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "25-26一年级上·全国·课后作业"
+  },
+  {
+    "id": "99",
+    "unit": "第九单元 推理",
+    "question_type": "解答题",
+    "difficulty": 0.85,
+    "question": "小芳，小丽和小宇三人赛跑。小芳说：\"我跑得不是最快的，但是比小丽快.\"谁跑得最快。谁跑得最慢。",
+    "options": [],
+    "answer": "小宇;小丽",
+    "solution": "【分析】根据题意可知：小芳说：\"我跑得不是最快的，但是比小丽快\"。据此可推出小宇跑得最快，紧接着是小芳，最后是小丽.\n【详解】由分析可得：小宇跑得最快，小丽跑得最慢。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "25-26 一年级上·江苏·课后作业"
+  },
+  {
+    "id": "100",
+    "unit": "第九单元 推理",
+    "question_type": "解答题",
+    "difficulty": 0.85,
+    "question": "在下面的方格中，每行，每列都有1~4这四个数，并且每个数在每行，每列都只出现一次。A是多少。B是多少。\n| 4 | 1 | | |\n| ---- | ---- | ---- | ---- |\n| A | 2 | | 3 |\n| 3 | | B | |\n| | | 1 | |",
+    "options": [],
+    "answer": "1;2",
+    "solution": "【分析】根据题意，每行，每列都有1~4这四个数，并且每个数在每行，每列都只出现一次。A所在的行，列出现了2,3,4，则A是1;再确定第二行第三列的数，这一行中出现了1,2,3，则这个位置是4，此时B所在的行，列出现了1,3,4，则B是2，据此解答.\n【详解】答：在下面的方格中，每行，每列都有1~4这四个数，并且每个数在每行，每列都只出现一次。A是1,B是2。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "24-25二年级下·湖南长沙·期末"
+  },
+  {
+    "id": "101",
+    "unit": "第九单元 推理",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "在下面的方格中，每行，每列都有1~4这四个数，并且每个数在每行，每列都只出现一次,M是( ),N是( ).\n\n| 2 | | | 3 |\n| ---- | ---- | ---- | ---- |\n| M | | 1 | N |\n| | | | |\n| 3 | | | |",
+    "options": [
+      "A. 4;2",
+      "B. 3;2",
+      "C. 2;1"
+    ],
+    "answer": "A",
+    "solution": "【分析】根据题目每个数在每行，每列都只出现一次，可知第一列中，第二个数不能是\"1\"，则第一列的\"1\"只能在第三个格子，所以第一列剩余的格子M代表的是\"4\"。第四列的第二个，第三个格子不能是\"1\"，则\"1\"只能出现在第四个格子，第四列的第二个格子不会是\"4\"，那么第4列第三个格子是\"4\"，所以第四列剩余的格子N代表的是\"2\".\n【详解】根据分析可以得到下图:\n\n| 2 | | | 3 |\n| ---- | ---- | ---- | ---- |\n| 4 | | 1 | 2 |\n| 1 | | | 4 |\n| 3 | | | 1 |\n\nM是4,N是2。故答案为:A",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "23-24二年级下·福建龙岩·期末"
+  },
+  {
+    "id": "102",
+    "unit": "第九单元 推理",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "有三个小朋友小亮，小雯和小辉，他们分别出生在天津，上海和重庆.\n![](images/9891f99678695c46c90799955f935db8.png)\n在天津出生的是( )。",
+    "options": [
+      "A. 小亮",
+      "B. 小雯",
+      "C. 小辉"
+    ],
+    "answer": "B",
+    "solution": "【分析】根据题意，有2个出生地不是小亮的出生地，可得知小亮在哪出生;小亮和小雯都不在上海出生，可知上海出生的是另一个小朋友，进而可知每个人的出生地.\n【详解】小亮不在天津出生，也不在上海出生，则他在重庆出生;小亮和小雯都不在上海出生，则小辉在上海出生;则在天津出生的是小雯。故答案为:B",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "23-24二年级下·天津河东·期末"
+  },
+  {
+    "id": "103",
+    "unit": "第九单元 推理",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "三名同学一分钟跳绳的个数分别是90下,115下,120下，小文比小强跳得多，小丽跳得最少，小强跳了( )下。",
+    "options": [
+      "A. 90",
+      "B. 115",
+      "C. 120"
+    ],
+    "answer": "B",
+    "solution": "【分析】根据题意，小丽跳得最少，还剩下数量最多和数量居中的;小文跳得比小强多，也就是小文跳得数量最多，小强跳得数量居中，由此比较他们跳的数量即可解答，比较时，位数多的数就大，位数相同比较最高位，最高位大的数就大，最高位相同比较下一位，直到比较出结果为止.\n【详解】由分析得:90<115<120，则小丽跳了90下;小文跳了120下;小强跳了115下。故答案为:B",
+    "knowledge_points": [
+      "推理问题",
+      "1000以内数的比大小"
+    ],
+    "source": "23-24二年级下·云南曲靖·期末"
+  },
+  {
+    "id": "104",
+    "unit": "第九单元 推理",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "苗苗，佳佳和月月三人分别在1,2,3班，佳佳不是3班的，苗苗下课后去1班找月月玩，苗苗是在( )。",
+    "options": [
+      "A. 1班",
+      "B. 2班",
+      "C. 3班"
+    ],
+    "answer": "C",
+    "solution": "【分析】根据题干信息，我们可以一步步推理出苗苗所在的班级，苗苗，佳佳和月月三人分别在1班,2班,3班，根据\"苗苗下课后去1班找月月玩\"，则月月一定在1班，苗苗自己一定不在1班那么剩下的2班和3班，已知\"佳佳不是3班的\"，因此佳佳只能在2班，因为1班已被月月占用，那么，苗苗只能在剩下的3班.\n【详解】根据分析可得：苗苗，佳佳和月月三人分别在1,2,3班，佳佳不是3班的，苗苗下课后去1班找月月玩，苗苗是在3班。故答案为:C",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "23-24 二年级下·河南濮阳·期末"
+  },
+  {
+    "id": "105",
+    "unit": "第九单元 推理",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "在下面的方格中，每行，每列都有1~4这四个数，并且每个数在每行，每列都只出现一次,△应是( ),○应是( ).\n\n| | | 1 | |\n| ---- | ---- | ---- | ---- |\n| | 2 | ☆ | 3 |\n| | △ | | |\n| | 3 | ○ | |",
+    "options": [
+      "A. 1;4",
+      "B. 1;2",
+      "C. 3;2",
+      "D. 4;3"
+    ],
+    "answer": "B",
+    "solution": "【分析】第一行第二列所在行和列已有1,2,3，则第一行第二列是4，所以△所在行和列已有2,3,4，则△是1。第二行第三列(☆)所在列和行已有1,2,3，故☆是4;第四行第三列(○)所在行和列已有3,4,1，故○是2.\n【详解】在下面的方格中，每行，每列都有1~4这四个数，并且每个数在每行，每列都只出现一次,△应是1,○应是2.\n\n| | | 1 | |\n| ---- | ---- | ---- | ---- |\n| | 2 | ☆ | 3 |\n| | △ | | |\n| | 3 | ○ | |\n\n故答案为:B",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "24-25 二年级下·山东菏泽·期末"
+  },
+  {
+    "id": "106",
+    "unit": "第九单元 推理",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "在下边的方格中，每行，每列都有1~4这四个数，且每个数在每行，每列都只出现一次。B是( ).\n\n| 1 | | | 2 |\n| ---- | ---- | ---- | ---- |\n| A | 4 | | |\n| 3 | | B | |\n| | | 2 | C |",
+    "options": [
+      "A. 1",
+      "B. 2",
+      "C. 4"
+    ],
+    "answer": "A",
+    "solution": "【分析】根据题意，通过观察，从左往右第一列缺少2和4，因为第一行有1和2，所以A处填2。从上往下，第一行缺少3和4，第二列有4，所以第二列第一个数填3，第三列第一个数填4，这时第三列缺少1和3,B处填1，据此解答.\n【详解】根据分析:\n\n| 1 | 3 | 4 | 2 |\n| ------ | ---- | ------ | ------ |\n| A(2) | 4 | 3 | 1 |\n| 3 | 2 | B(1) | 4 |\n| 4 | 1 | 2 | C(3) |\n\nB处应该是1。故答案为:A",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "24-25二年级下·河北邢台·期末"
+  },
+  {
+    "id": "107",
+    "unit": "第九单元 推理",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "白猫比花猫重，黑猫比花猫轻，最轻的是( )。",
+    "options": [
+      "A. 白猫",
+      "B. 花猫",
+      "C. 黑猫"
+    ],
+    "answer": "C",
+    "solution": "【分析】根据题意，白猫比花猫重，黑猫比花猫轻，也就是花猫比黑猫重，由此排列即可得到最轻的是哪只猫.\n【详解】由分析得：白猫的重量>花猫的重量>黑猫的重量，则最轻的是黑猫。故答案为:C",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "24-25 二年级下·河南周口·期末"
+  },
+  {
+    "id": "108",
+    "unit": "第九单元 推理",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "丁丁，丽丽和园园三个小朋友分别出生在上海，北京和山东。丁丁说：\"我从未到过上海.\"丽丽说：\"在上海出生的不是我，我也不是出生在山东的.\"园园说：\"我不告诉你.\"园园出生在( )。",
+    "options": [
+      "A. 山东",
+      "B. 北京",
+      "C. 上海"
+    ],
+    "answer": "C",
+    "solution": "【分析】丽丽说：\"在上海出生的不是我，我也不是出生在山东的.\"说明丽丽出生在北京;丁丁说：\"我从未到过上海.\"说明丁丁不在上海出生，也不在北京出生，所以丁丁出生在山东;从而得出园园出生在上海，据此选答案.\n【详解】根据分析可知：园园出生在上海。故答案为:C",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "23-24二年级下·湖南长沙·期末"
+  },
+  {
+    "id": "109",
+    "unit": "第九单元 推理",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "红红，明明，丁丁三个人进行跳绳比赛。红红说：\"我不是跳得最多的.\"明明说：\"我也不是跳得最多的，但我比红红跳得多\"。( )是跳得最少的。",
+    "options": [
+      "A. 红红",
+      "B. 明明",
+      "C. 丁丁"
+    ],
+    "answer": "A",
+    "solution": "【分析】根据题意可知，红红和明明都不是跳得最多的，则丁丁是跳得最多的，排名第一。明明比红红多，则明明排名第二，红红排名第三。据此解答即可.\n【详解】根据分析可知，红红跳得最少。故答案为:A",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "23-24二年级下·浙江嘉兴·期末"
+  },
+  {
+    "id": "110",
+    "unit": "第九单元 推理",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "在下面的方格中，每行，每列都有1~4这四个数，并且每个数在每行，每列都只出现一次,B是( ).\n![](images/image-1.png)",
+    "options": [
+      "A. 4",
+      "B. 3",
+      "C. 1"
+    ],
+    "answer": "C",
+    "solution": "【分析】根据题意，可以运用排除法，排除行列中已经出现的数字。由图可知,A所在行有2，所在列有1,3，所以A只能是4;B所在行有4,2，所在列有3，所以B是1，据此解答即可.\n【详解】根据分析可知：在下面的方格中，每行，每列都有1~4这四个数，并且每个数在每行，每列都只出现一次,B是1。故答案为:C",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "23-24 二年级下·福建福州·期末"
+  },
+  {
+    "id": "111",
+    "unit": "第九单元 推理",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "他们三个人分别有16张,21张和18张画片，东东有( )张画片.\n![](images/ca7dfaf64f1a2c48a169b02a0cc62f2effc612190baa2d76ed786b0eff07172b.jpg)",
+    "options": [
+      "A. 16",
+      "B. 21",
+      "C. 18"
+    ],
+    "answer": "A",
+    "solution": "【分析】由题意可知：小梅有21张是最多的，小亮不是最少的，所以东东是最少的16张，据此可解.\n【详解】由分析可得：他们三个人分别有16张,21张和18张画片，东东有16张画片。故答案选:A",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "23-24二年级下·湖南岳阳·期末"
+  },
+  {
+    "id": "112",
+    "unit": "第九单元 推理",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "在下边的图形中，每行，每列都有1至4这四个数字，并且每个数在每行，每列都只出现一次,B应该是( ).\n\n| 1 | 3 | | 2 |\n| ---- | ---- | ---- | ---- |\n| | | | |\n| | | B | 1 |\n| | | 2 | |",
+    "options": [
+      "A. 1",
+      "B. 3",
+      "C. 4"
+    ],
+    "answer": "B",
+    "solution": "【分析】根据题意，每行，每列都有1至4这四个数字，并且每个数在每行，每列都只出现一次，则从出现数字最多的地方入手。先推算出第一行空格中代表的数，进而推算出B代表的数.\n【详解】第一行第3格所在的行，列出现了1,2,3，则这个格里填写4;B所在的行，列出现了1,2,4，则B应该是3。故答案为:B",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "23-24 二年级下·云南曲靖·期末"
+  },
+  {
+    "id": "113",
+    "unit": "第九单元 推理",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "有九张数字卡片，上面分别写着1~9九个数字。甲，乙，丙，丁每人拿了两张。甲说：\"我的两张数字之和是9.\"乙说：\"我的两张数字之差是6.\"丙说：\"我的两张数字之积是12.\"丁说：\"我的两张数字之商是3.\"那么，剩下的一张上面写的数字是( )。",
+    "options": [
+      "A. 1",
+      "B. 3",
+      "C. 5",
+      "D. 8",
+      "E. 9"
+    ],
+    "answer": "D",
+    "solution": "【分析】9张数字卡片，按题所说组合有：甲:1+8,2+7,3+6,4+5;乙:7-1,8-2,9-3;丙:2×6,3×4;丁:3÷1,6÷2,9÷3;我们从最少数字的丙看起，假设用当丙为2和6时，那么把其他数字能用2和6的去除，甲剩下1+8,4+5;乙剩下7-1,9-3;丁剩下3-1,9-3;再假设丁为3和1，则乙就没有符合的两个数了，所以丁只能是9和3，那么乙就是7和1，甲就是4和5了，即可得出剩下的一张上面写的数字是8。据此解答.\n【详解】根据甲可知:9=1+8=2+7=3+6=4+5;根据乙可知:6=9-3=8-2=7-1;根据丙可知:12=2×6=3×4;根据丁可知:3=3÷1=6÷2=9÷3。根据用的数字最少的可能，从丙分析，假设丙拿到的卡片是2和6，则去掉卡片2和6后，甲的可能为9=1+8=4+5，乙的可能为6=9-3=7-1，丁的可能为3=3÷1=9÷3;再假设丁拿到的卡片是1和3，则乙就没有符合题意的卡片了，所以丁只能拿到卡片3和9，那么乙拿到的卡片只能是7和1，此时甲拿到的卡片为4和5，据此即可得到剩下的一张卡片是8，满足题意。故答案选:D",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "2024 四年级·广东深圳·竞赛"
+  },
+  {
+    "id": "114",
+    "unit": "第九单元 推理",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "在下面的方格中，每行每列都有\"月季之乡\"四个字，并且每行每列都只能出现一次，则花代表的是( )字.\n![](images/image-3.png)",
+    "options": [
+      "A. 月",
+      "B. 季",
+      "C. 之"
+    ],
+    "answer": "C",
+    "solution": "【分析】第二行第一列所在列有月，季，所在行有之，所以此处是乡。第二行第三列所在列有月，所在行有乡，之，所以此处是季。第二行第三列所在行有乡，之，季，所以此处是月。玫瑰花所在行有季，所在列有月，乡，所以此处是之.\n【详解】在下面的方格中，每行每列都有\"月季之乡\"四个字，并且每行每列都只能出现一次，则代表的是\"之\"字。故答案为:C",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "23-24二年级下·河南南阳·期末"
+  },
+  {
+    "id": "115",
+    "unit": "第九单元 推理",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "在下边的方格中，每行，每列都有1,2,3,4，并且每个数在每行，每列都只出现一次。B应该是( ).\n\n| 4 | 3 | | |\n| ---- | ---- | ---- | ---- |\n| A | 2 | | 3 |\n| 2 | | B | |\n| | | | 1 |",
+    "options": [
+      "A. 3",
+      "B. 2",
+      "C. 4"
+    ],
+    "answer": "A",
+    "solution": "【分析】这是一道推理题，解题关键是利用\"每行，每列都有1,2,3,4，且每个数在每行，每列都只出现一次\"的规则。第一行已有4,3，第四列不能填1(第四行有1),故第一行第四列填2，第一行补全为4,3,1,2。第二行已有2,3，第一列不能填4(第一行有4),故A填1，第二行补全为1,2,4,3。第三行已有2，第三列不能填1(第一行有1)和4(第二行有4),故B只能填3.\n【详解】由分析可知:B应该是3。故答案为:A",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "23-24 二年级下·浙江·期末"
+  },
+  {
+    "id": "116",
+    "unit": "第九单元 推理",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "小红，小芳，小兰进行一分钟跳绳比赛，她们分别跳了120,146,155下，小红说：\"我跳的不是最多的\"。小芳说：\"我跳的是最少的\"。小兰跳了( )下。",
+    "options": [
+      "A. 120",
+      "B. 146",
+      "C. 155"
+    ],
+    "answer": "C",
+    "solution": "【分析】根据比较数的大小，先看位数的多少，位数多的数就大;如果位数相同，从最高位开始比较，最高位上的数大则这个数大，最高位上的数相同，就比较下一位，依次类推直至比较出跳绳次数的大小。小红不是最多的，小方是最少的，可知小红应该是跳得次数第二多，小兰跳得次数最多，由此解答即可.\n【详解】120,146,155三个数，位数都相同，百位也相同，十位上2<4<5，所以120<146<155。根据分析，小兰跳得最多，即小兰跳了155下。故答案为:C",
+    "knowledge_points": [
+      "推理问题",
+      "1000以内数的比大小"
+    ],
+    "source": "23-24 二年级下·重庆大渡口·期末"
+  },
+  {
+    "id": "117",
+    "unit": "第九单元 推理",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "在下面的方格中，每行，每列都有\"我\"\"爱\"\"运\"\"动\"这四个字，并且每个字在每行，每列都只出现一次。甲和乙分别是( ).\n\n| | 运 | | |\n| ---- | ---- | ---- | ---- |\n| | | | 我 |\n| | 爱 | | |\n| 动 | 甲 | 爱 | 乙 |",
+    "options": [
+      "A. 爱，运",
+      "B. 我，运",
+      "C. 我，爱"
+    ],
+    "answer": "B",
+    "solution": "【分析】\"甲\"所在行有动和爱，所在列有运，则\"甲\"是我.\"乙\"所在行有动和爱，所在列有我，则\"乙\"是运.\n【详解】由分析可知，甲和乙分别是我，运。故答案为:B",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "23-24二年级下·河南信阳·期末"
+  },
+  {
+    "id": "118",
+    "unit": "第九单元 推理",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "小刚，小明和小伟在运动会50米跑步比赛中夺得了前三名。小刚说：\"我不是第一名。\"小伟说：\"我的成绩没有小刚好\"。小明是第( )名。",
+    "options": [
+      "A. 1",
+      "B. 2",
+      "C. 3"
+    ],
+    "answer": "A",
+    "solution": "【分析】根据题意，小刚不是第一名。小伟说：\"我的成绩没有小刚好\"，则小伟也不是第一名，所以小明是第一名.\n【详解】小刚，小明和小伟在运动会50米跑步比赛中夺得了前三名。小刚说：\"我不是第一名。\"小伟说：\"我的成绩没有小刚好\"。小明是第1名。故答案为:A",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "23-24二年级下·河南信阳·期末"
+  },
+  {
+    "id": "119",
+    "unit": "第九单元 推理",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "小勇，小冬，小灵与小胖四人进行跑步比赛，小冬不是最慢的，但比小勇，小灵慢，小勇比小灵慢，获得第一名的是( )。",
+    "options": [
+      "A. 小勇",
+      "B. 小冬",
+      "C. 小灵",
+      "D. 小胖"
+    ],
+    "answer": "C",
+    "solution": "【分析】根据\"小冬不是最慢的，但比小勇，小灵慢\"说明最慢的是小胖，小胖是第四名，小东是第三名，又因为\"小勇比小灵慢\"，所以最快的是小灵，那么小勇是第二名，小灵是第一名。据此推理即可解答.\n【详解】据分析可知，最快的是小灵，所以获得第一名的是小灵。故答案为:C",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "2024·重庆云阳·小升初真题"
+  },
+  {
+    "id": "120",
+    "unit": "第九单元 推理",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "有4位老师分别任教语文，数学，英语和科学。张老师说：我不是语文老师;李老师说：我不教数学;王老师说：我是英语老师;赵老师说：我不是数学老师，也不是科学老师。老师们的说法都正确，下面说法正确的是( )。",
+    "options": [
+      "A. 张老师教科学",
+      "B. 赵老师教科学",
+      "C. 李老师教语文",
+      "D. 赵老师教语文"
+    ],
+    "answer": "D",
+    "solution": "【分析】王老师明确是英语老师，先确定这一信息;赵老师排除数学和科学，结合王老师所教科目，能确定赵老师教语文;李老师排除数学，结合前面已确定信息，可推出李老师教科学，进而确定张老师教数学.\n【详解】已知王老师说自己是英语老师，所以王老师教英语;赵老师说自己不是数学老师也不是科学老师，且王老师已确定教英语，所以赵老师只能教语文;李老师说自己不教数学，此时王老师教英语，赵老师教语文，所以李老师教科学;所以张老师就只能教数学。所以张老师教数学;李老师教科学;王老师教英语;赵老师教语文。故答案为:D",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "2024·陕西安康·小升初真题"
+  },
+  {
+    "id": "121",
+    "unit": "第九单元 推理",
+    "question_type": "选择题",
+    "difficulty": 0.4,
+    "question": "a,b,c,d,e五位学生参加百米赛跑，甲，乙，丙，丁，戊五位学生对竞赛名次进行预测，预测情况如下：甲:b第三,c第五;乙:e第四,d第五;丙:a第一,e第四;丁:c第一,b第二;戊:a第三,d第四。结果表明，每个名次都有人猜中，下面说法正确的是( )。",
+    "options": [
+      "A. a第一",
+      "B. d第四",
+      "C. b第二"
+    ],
+    "answer": "C",
+    "solution": "【分析】把五位学生的说法整理在统计表中，因为每个名次都有人猜中，先假设各选项的说法是正确的，逐步推理出哪些选项的说法与五位学生的说法相矛盾，找出不矛盾的说法，即是正确的说法.\n【详解】A。假设\"a第一\"是正确的，则丙说的\"e第四\"就是错的，乙说的\"e第四\"也是错的，乙说的\"d第五\"是正确的，戊说的\"d第四\"是错的，则戊说的\"a第三\"是正确的，与假设\"a第一\"是正确的相矛盾，此假设不成立。B。假设\"d第四\"是正确的，则戊说的\"a第三\"就是错的，则丙说的\"a第一\"是正确的，与选项A的假设一致，所以此假设不成立;C。假设\"b第二\"是正确的，则丁说的\"c第一\"就是错的，那么甲说的\"c第五\"是正确的，甲说的\"b第三\"是错的，与假设\"b第二\"是正确的不矛盾，所以此假设成立。说法正确的是b第二。故答案为:C",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "2023·广东广州·小升初真题"
+  },
+  {
+    "id": "122",
+    "unit": "第九单元 推理",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "一个学生做了件好事，老师调查是谁做的好事。甲说：是乙做的。乙说：是丁做的。丙说：不是我做的。丁说：乙在说谎。已知这四个人中只有一个人说了实话。那么做好事的是( )。",
+    "options": [
+      "A. 甲",
+      "B. 乙",
+      "C. 丙",
+      "D. 丁"
+    ],
+    "answer": "C",
+    "solution": "【分析】根据已知可得，乙和丁的话是矛盾关系，则乙与丁必一真一假。因为这四个人中只有一个人说了实话，所以甲和丙说的都是假话，进一步分析即可解答题目.\n【详解】乙和丁的话是矛盾关系，所以乙与丁必有一真一假，则甲和丙说的都是假话。因为甲说的是假话，所以不是乙做的;因为丙说的是假话，所以好事是丙做的;由此可知乙说的假话，此时丁说的是真话。综上可知，说实话的是丁，做好事的是丙。故答案为:C",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "2024·海南省直辖县级单位·小升初真题"
+  },
+  {
+    "id": "123",
+    "unit": "第九单元 推理",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "小芳，小红，小兰三人比赛跳绳，小芳说：\"我跳的不是最多的，也不是最少的.\"小红说：\"我跳的比小芳多一些.\"小兰是第( )名。",
+    "options": [
+      "A. 三",
+      "B. 二",
+      "C. 一"
+    ],
+    "answer": "A",
+    "solution": "【分析】已知一共有3个人跳绳，小芳跳的不是最多的，也不是最少的，可知小芳是中间的第二名，小红说她比小芳跳的多一些你可知小红是第一名，所以得出小兰是第几名.\n【详解】据分析可知：小红是第一名，小芳是第二名，所以小兰是第三名。故答案为:A",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "22-23 二年级下·四川凉山·期末"
+  },
+  {
+    "id": "124",
+    "unit": "第九单元 推理",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "有香蕉，苹果，西瓜三种水果，明明说：\"每人只吃一种水果，我不吃西瓜.\"小东说：\"我既不吃苹果，也不吃西瓜.\"大伟吃( )。",
+    "options": [
+      "A. 苹果",
+      "B. 西瓜",
+      "C. 香蕉",
+      "D. 不能确定"
+    ],
+    "answer": "B",
+    "solution": "【分析】根据题意，小东不吃的水果有2种，则剩下1种就是小东吃的;进而可推断出明明吃的水果，最后剩下的一种水果就是大伟吃的，由此解答.\n【详解】小东不吃苹果，也不吃西瓜，则小东吃的是香蕉;还剩下苹果和西瓜，明明不吃西瓜，则明明吃的是苹果。则大伟吃的就是西瓜。故答案为:B",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "22-23 二年级下·四川凉山·期末"
+  },
+  {
+    "id": "125",
+    "unit": "第九单元 推理",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "有甲，乙，丙三个容器，如果把甲容器装满水倒入乙容器，乙容器没有装满;如果把丙容器装满水，倒入乙容器后，丙容器里的水还有剩余。最大的容器是( )。",
+    "options": [
+      "A. 甲",
+      "B. 乙",
+      "C. 丙"
+    ],
+    "answer": "C",
+    "solution": "【分析】根据把甲容器装满水，倒入乙容器中，乙容器没有倒满，得出乙容器大于甲容器;根据丙容器的水倒入乙容器中，丙容器的水还有剩余，可得丙容器大于乙容器，据此解答即可.\n【详解】由分析可知，甲容器<乙容器<丙容器，最大的容器是丙。故答案为:C",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "24-25 四年级上·河南洛阳·期中"
+  },
+  {
+    "id": "126",
+    "unit": "第九单元 推理",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "小明，小丽，小王三人比赛跑步，结束后，小明说：\"我是第二.\"小丽说：\"我在小明的前面.\"跑第三的是( )。",
+    "options": [
+      "A. 小明",
+      "B. 小丽",
+      "C. 小王"
+    ],
+    "answer": "C",
+    "solution": "【分析】由题可知，小明是第二名，小丽跑在小明的前面，说明小丽的名次比小明靠前，也就是小丽是第一名，最后剩下的小王是第三名，据此解答即可.\n【详解】由分析可得，小明，小丽，小王三人比赛跑步，结束后，小明说：\"我是第二.\"小丽说：\"我在小明的前面.\"跑第三的是小王。故答案为:C",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "23-24二年级下·贵州六盘水·期末"
+  },
+  {
+    "id": "127",
+    "unit": "第九单元 推理",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "陈亮，王明，李丽三个人，有一个人属牛，有一个人属虎，还有一个人属兔。陈亮说：\"我不属牛.\"王明说：\"我的属相不是吃草动物.\"李丽说：\"我不属虎.\"陈亮属( )。",
+    "options": [
+      "A. 牛",
+      "B. 虎",
+      "C. 兔"
+    ],
+    "answer": "C",
+    "solution": "【分析】根据题意，题中牛和兔是吃草动物，虎不是吃草的动物，由此可推断出王明的属相，再根据陈亮说他不属牛，推断出陈亮的属相.\n【详解】由分析可知，王明的属相不是吃草动物，则王明属虎;陈亮不属牛，则可能属虎或兔，而王明属虎，则陈亮只能是属兔。故答案为:C",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "23-24 二年级下·江西赣州·期末"
+  },
+  {
+    "id": "128",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "在下面的方格中，每行，每列都有\"春夏秋冬\"四个字，且只出现一次。则1是( ),2是( ).\n\n| 春 | | | |\n| ---- | ---- | ---- | ---- |\n| | | 夏 | |\n| 1 | | 2 | 冬 |\n| 夏 | 冬 | | |",
+    "options": [],
+    "answer": "秋;春",
+    "solution": "【分析】根据题意，每行，每列都有\"春夏秋冬\"四个字，且只出现一次。则从出现字较多的地方入手，根据1所在的行，列出现的字得出1代表的字;进而得出2代表的字.\n【详解】由分析得:1所在的行，列出现了春，夏，冬，则1只能是秋;2所在的行，列出现了夏，秋，冬，则2只能是春。则1是秋,2是春。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "24-25 二年级下·福建福州·期末"
+  },
+  {
+    "id": "129",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "有音乐，美术，数学三本书，小红，小刚和小丽各拿一本。小红拿的是音乐书，小丽拿的不是数学书。小刚拿的是( )书，小丽拿的是( )书。",
+    "options": [],
+    "answer": "数学;美术",
+    "solution": "【分析】小红拿的是音乐书，还剩下美术和数学书，小丽拿的不是数学书，则小丽拿的是美术书。剩下的小刚拿的是数学书.\n【详解】有音乐，美术，数学三本书，小红，小刚和小丽各拿一本。小红拿的是音乐书，小丽拿的不是数学书。小刚拿的是数学书，小丽拿的是美术书。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "24-25 二年级下·广西柳州·期末"
+  },
+  {
+    "id": "130",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "三个小朋友在玩踢毽子游戏，分别踢了12个,27个,43个。红红说：\"我踢得不是最多的.\"天天说：\"我踢了12个.\"那么，珍珍踢了( )个。",
+    "options": [],
+    "answer": "43",
+    "solution": "【分析】根据题意，先比较他们各自踢的数量，天天踢的数量已经知道了，根据红红踢得不是最多，可得出红红踢的数量，进而得知珍珍踢的数量.\n【详解】由分析得:12<27<43。天天踢了12个，还剩下27个和最多的43个，红红踢的不是最多，也就是红红踢了27个，则最多的就是珍珍踢的。珍珍踢了43个。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "24-25二年级下·浙江温州·期末"
+  },
+  {
+    "id": "131",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "小林，小青，小风三位同学每人拿着一张动物卡片，分别是小兔，小狗和小猫，小风拿的是小狗，小林拿的不是小猫，小青拿的是( ),小林拿的是( )。",
+    "options": [],
+    "answer": "小猫;小兔",
+    "solution": "【分析】根据题干可知，小风拿的是小狗，小林拿的不是小猫，可知小林拿的是小兔，则剩下的小猫应该被小青拿走了，由此解答即可.\n【详解】根据分析可知，小青拿的是小猫，小林拿的是小兔。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "23-24 二年级下·河北邯郸·期末"
+  },
+  {
+    "id": "132",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "三个小朋友拍皮球，分别拍了38下,46下,70下。小方拍了( )下，小英拍了( )下.\n![](images/0c3d875fb71cd3baba7c639839c18033ebaf4dfbce7d2abcc0be456a0b1114db.jpg)",
+    "options": [],
+    "answer": "46;70",
+    "solution": "【分析】根据题意可知：将三个小朋友拍的数量进行比较，由题意知小红拍的最少，则选择最小的一个数即可;小方拍的不是最多的，由此知小英拍的最多，选择最大的数即可.\n【详解】38<46<70，则小方拍了46下，小英拍了70下。",
+    "knowledge_points": [
+      "推理问题",
+      "100以内数的比大小"
+    ],
+    "source": "23-24二年级下·新疆昌吉·期末"
+  },
+  {
+    "id": "133",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "有甲，乙，丙三人，一个是语文老师，一个是数学老师，一个是体育老师。甲和丙经常跟体育老师学打羽毛球，丙带学生去找数学老师辅导数学。甲是( )老师，乙是( )老师，丙是( )老师。",
+    "options": [],
+    "answer": "数学;体育;语文",
+    "solution": "【分析】根据题意可知：甲，乙，丙三人，甲和丙经常跟体育老师学打羽毛球，由此可推出乙是体育老师;根据丙带学生去找数学老师辅导数学由此可知数学老师是甲;则丙是语文老师.\n【详解】由分析可得：有甲，乙，丙三人，一个是语文老师，一个是数学老师，一个是体育老师。甲和丙经常跟体育老师学打羽毛球，丙带学生去找数学老师辅导数学。甲是(数学)老师，乙是(体育)老师，丙是(语文)老师。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "23-24二年级下·河北邯郸·期末"
+  },
+  {
+    "id": "134",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "在下面的方格图中，若每行，每列都有1,2,3,4这四个数，并且每个数在每行，每列都只出现一次，则A是( ),B是( ).\n\n| | | A | |\n| ---- | ---- | ---- | ---- |\n| 3 | | | |\n| 1 | | 4 | B |\n| | 2 | 3 | |",
+    "options": [],
+    "answer": "1;2",
+    "solution": "【分析】根据第一列出现了数字1和3，第四行出现了数字2和3，每个数在每行，每列都只出现一次，所以第四行第一列的数字只能是4，第四行第四列的数字只能是1，第一行第一列的数字只能是2;根据第三行出现了数字1和4，第四行第二列出现了数字2，所以第三行第二列只能是数字3，第三行第四列只能是数字2;根据第二行第一列是数字3，第四列出现了数字1和2，所以第二行第四列只能是数字4，第一行第四列只能是数字3;根据第二列出现了数字2和3，第二行出现了数字3和4，所以第二行第二列只能是数字1，第二行第三列只能是数字2;根据第三列出现了数字2,3和4，所以第一行第三列只能是数字1，第一行第二列只能是数字4.\n【详解】由分析可得:\n\n| 2 | 4 | 1(A) | 3 |\n| ---- | ---- | ------ | ------ |\n| 3 | 1 | 2 | 4 |\n| 1 | 3 | 4 | 2(B) |\n| 4 | 2 | 3 | 1 |\n\nA是1,B是2。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "24-25二年级下·浙江嘉兴·期末"
+  },
+  {
+    "id": "135",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "在下边的方格中，每行，每列都有1~4这四个数，并且每个数在每行，每列中都只出现一次，则△是( ),☆是( ).\n\n| 2 | | 3 | |\n| ---- | ---- | ---- | ---- |\n| △ | 3 | | 1 |\n| 3 | | ☆ | |\n| | | 4 | |",
+    "options": [],
+    "answer": "4;1",
+    "solution": "【分析】根据题意,1~4各数每行每列只能出现一次，从左往右第一列缺少1和4，从上往下第二行中出现了1，所以△是4，第二行还缺少2,2填在第三列第二个位置，这时第三列缺少1，所以☆是1，据此解答.\n【详解】根据分析:\n\n| 2 | | 3 | |\n| ------ | ---- | ------ | ---- |\n| △(4) | 3 | 2 | 1 |\n| 3 | | ☆(1) | |\n| 1 | | 4 | |\n\n△是(4),☆是(1)。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "24-25二年级下·湖北武汉·期末"
+  },
+  {
+    "id": "136",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "狐狸，小熊，松鼠参加了跳绳比赛。小熊比狐狸少跳了3下，松鼠比小熊多跳了6下。这次跳绳比赛中,( )得第一,( )得第二,( )得第三。",
+    "options": [],
+    "answer": "松鼠;狐狸;小熊",
+    "solution": "【分析】由题意可知：小熊比狐狸少跳了3下，即狐狸比小熊多跳了3下，松鼠比小熊多跳了6下，松鼠和狐狸比，比狐狸多跳了3下，故松鼠跳的最多，是第一名，狐狸是第二名，小熊跳的最少，是第三名.\n【详解】由分析可得：狐狸，小熊，松鼠参加了跳绳比赛。小熊比狐狸少跳了3下，松鼠比小熊多跳了6下。这次跳绳比赛中，松鼠得第一，狐狸得第二，小熊得第三。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "24-25二年级下·湖北武汉·期末"
+  },
+  {
+    "id": "137",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "古时候科举考试的前三名分别是状元(第一名),榜眼(第二名),探花(第三名)。某次科举考试中甲，乙，丙获得前三名，甲不是状元，乙没甲的成绩好，那么状元是( )。",
+    "options": [],
+    "answer": "丙",
+    "solution": "【分析】甲不是状元，因此状元只能是乙或丙。乙的成绩比甲差，说明甲的名次比乙靠前。则甲只能是第二名，乙是第三名，状元为丙.\n【详解】古时候科举考试的前三名分别是状元(第一名),榜眼(第二名),探花(第三名)。某次科举考试中甲，乙，丙获得前三名，甲不是状元，乙没甲的成绩好，那么状元是丙。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "24-25 二年级下·山西晋中·期末"
+  },
+  {
+    "id": "138",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "小新，小青和小峰是班级语文，数学，英语三科的课代表。小新是语文课代表，小青不是数学课代表。小峰是( )课代表，小青是( )课代表。",
+    "options": [],
+    "answer": "数学;英语",
+    "solution": "【分析】根据已知条件，通过排除法确定每个人的对应科目。首先明确小新的科目，再根据小青的限制条件推断其科目，最后剩余科目即为小峰的。已知小新是语文课代表，因此语文科目已被小新担任。剩余科目为数学和英语，需由小青和小峰分配。条件\"小青不是数学课代表\"说明小青只能担任英语课代表(因语文已被小新担任)。最后剩下的数学课代表只能是小峰.\n【详解】由分析可知：小新，小青和小峰是班级语文，数学，英语三科的课代表。小新是语文课代表，小青不是数学课代表。小峰是数学课代表，小青是英语课代表。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "24-25 二年级下·河南新乡·期末"
+  },
+  {
+    "id": "139",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "在右面的方格中，每行，每列都有1~4这四个数，并且每个数在每行，每列都只出现一次。B应该是( ),C应该是( ).\n\n| | 1 | | |\n| ---- | ---- | ---- | ---- |\n| 4 | A | 2 | |\n| | | C | |\n| | B | 4 | |",
+    "options": [],
+    "answer": "2;1",
+    "solution": "【分析】根据每行，每列都有1~4这四个数，且每个数在每行，每列都只出现一次，由A所在的行和列可知,A不可能是1,4,2，所以A只能是3，再根据B和C所在的行和列进行解答即可.\n【详解】据分析可知:A是3，因为B跟A同一列，所以B不可能是1和3，又因为B所在的行有4，所以B是2。因为A是3,B是2，所以第二列的数从上到下依次是1,3,4,2。第二行从左往右依次是4,3,2,1。因为第一列到第三列，以及第二行到第四行已经有4，所以第一行第四列上面的数是4，又因为第四列有4和1，第四行有2和4，所以第四行第四列上的数是3。所以第四行从左往右依次是1,2,4,3。第四列从上到下依次是4,1,2,3。因为第一列有1和4，第三行有4和2，所以第一列的第三个数是3。因为第三行的数有3,4,2，所以C是1.\n\n| 2 | 1 | 3 | 4 |\n| ---- | ---- | ---- | ---- |\n| 4 | 3 | 2 | 1 |\n| 3 | 4 | 1 | 2 |\n| 1 | 2 | 4 | 3 |\n\n即,B应该是(2),C应该是(1)。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "22-23 二年级下·新疆乌鲁木齐·期末"
+  },
+  {
+    "id": "140",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "联欢会上要表演唱歌，舞蹈和朗诵，下面三人各表演一种.\n![](images/bab1aad66cfb2f8e179cbcb57e0f008c.png)\n朵朵表演的是( )。",
+    "options": [],
+    "answer": "唱歌",
+    "solution": "【分析】本题考查的是逻辑推理能力，从容易确定的人入手，逐个推理确定即可.\n【详解】三人表演的分别是唱歌，舞蹈和朗诵。贝贝表演的是朗诵，文文表演的不是唱歌，那么文文表演的就是舞蹈了，所以朵朵表演的肯定是唱歌。故朵朵表演的是唱歌。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "24-25 二年级下·广西玉林·期末"
+  },
+  {
+    "id": "141",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "在下边的方格中，每行，每列都有1~4这四个数，并且每个数在每行，每列都只出现一次，则A是( ),B是( ).\n![](images/image-10.png)",
+    "options": [],
+    "answer": "4;1",
+    "solution": "【分析】A所在列有2,3，所在行有1，则A是4。第二排已有4,3,1，则第二排第三列是2。所以B所在列有2,4，所在行有3，则B是1.\n【详解】根据分析，在下边的方格中，每行，每列都有1~4这四个数，并且每个数在每行，每列都只出现一次，则A是4,B是1。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "23-24 二年级下·浙江台州·期末"
+  },
+  {
+    "id": "142",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "在下边的方格中，每行，每列都有1,2,3,4这四个数字，并且每个数字在每行每列中都只出现一次，那么A表示( ),B表示( ).\n![](images/image-11.png)",
+    "options": [],
+    "answer": "4;1",
+    "solution": "【分析】根据题意，每行，每列都有1,2,3,4这四个数字，并且每个数字在每行每列中都只出现一次，则从出现数字较多的地方入手。先根据A所在的行，列出现的数字推算出A及第二列第2格的数字，再推算出B代表的数字即可.\n【详解】由分析得:A所在的行，列出现了1,2,3，则A是4;所以，第二列第2格只能是2;B所在的行，列出现了2,3,4，则B是1。因此,A表示4,B表示1。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "23-24二年级下·浙江台州·期末"
+  },
+  {
+    "id": "143",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "在如表的方格中，每行，每列都有1,2,3,4这四个数，并且每个数在每行，每列都只出现一次。A应该是( ),B应该是( ),C应该是( ).\n\n| 1 | A | | 2 |\n| ---- | ---- | ---- | ---- |\n| | 3 | | C |\n| 2 | | | |\n| 3 | B | 1 | |",
+    "options": [],
+    "answer": "4;2;1",
+    "solution": "【分析】A所在行有1,2，所在列有3，则A是4。B所在行有1,3，所在列有4，则B是2。第一列分别已有1,2,3，则第一列第二排是4。C所在行有3,4，所在列有2，则C是1.\n【详解】根据分析，在如表的方格中，每行，每列都有1,2,3,4这四个数，并且每个数在每行，每列都只出现一次。A应该是4,B应该是2,C应该是1。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "23-24二年级下·河南信阳·期末"
+  },
+  {
+    "id": "144",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "小明，小红，小华三人参加50米跑步比赛。小红得了第三名，小明不是第一名。小明得了第( )名，小华得了第( )名。",
+    "options": [],
+    "answer": "二;一",
+    "solution": "【分析】根据题意，小明，小红，小华三人参加50米跑步比赛，小红得了第三名，说明第一名和第二名是另外两个小朋友，其中小明不是第一名，那小明就是第二名，最后得出小华就是第一名，据此解答.\n【详解】由分析可得：小明，小红，小华三人参加50米跑步比赛。小红得了第三名，小明不是第一名，小明得了第二名，小华得了第一名。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "23-24 二年级下·福建福州·期末"
+  },
+  {
+    "id": "145",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "下面的方格中，每行，每列都有1,2,3,4这四个数，并且每个数在每行，每列都只出现一次。A是( ),B是( ).\n\n| | 3 | | |\n| ---- | ---- | ---- | ---- |\n| | | B | 1 |\n| | 2 | | |\n| 4 | A | 2 | |",
+    "options": [],
+    "answer": "1;3",
+    "solution": "【分析】首先从A开始分析，分别根据A所在行与所在列的已知数，即可推出A的可能值，再将其结合起来，即可确定A的值;然后结合上述结论，即可确定B左侧数的值，再仿照上述方法，即可推出B的值，据此解答.\n【详解】因为A所在行出现4和2，所以A可能是1或3。又因为A所在列出现2和3，所以A的值只能是1，所以B的左侧只能是4。又因为B所在行出现1和4，所以B可能是2或3。又因为B所在列出现2，所以B的值只能是3。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "23-24二年级下·湖北省直辖县级单位·期末"
+  },
+  {
+    "id": "146",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "甲，乙，丙三人住在一幢3层高的住宅楼的不同楼层，甲住在最高层，乙不住在1楼，则甲住( )楼，乙住( )楼，丙住( )楼。",
+    "options": [],
+    "answer": "3;2;1",
+    "solution": "【分析】根据题意，从低到高依次为1楼,2楼,3楼，甲在最高层，也就是3楼。乙不住1楼，也就是住1楼的是丙，剩下的2楼就是乙住的楼层.\n【详解】由分析得：甲，乙，丙三人住在一幢3层高的住宅楼的不同楼层，甲住在最高层，乙不住在一楼，则甲住3楼，乙住2楼，丙住1楼。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "23-24 二年级下·山东菏泽·期末"
+  },
+  {
+    "id": "147",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "密室逃脱有一关是破解图形密码。前四个密码锁上的图形如下图，密码分别为:185,742,452,248，但不知道哪幅图对应哪个密码。第五个密码锁上的图形为，这个密码是( )。",
+    "options": [],
+    "answer": "451",
+    "solution": "【分析】根据题意，从前四个密码锁上出现相同数位的相同数入手，找出与之相符的密码图，推出部分图形所代表的数，再根据知道的图形所代表的数，一一解开密码，并推出剩下图形所代表的数，从而巧解未知密码.\n【详解】四个密码中,742和452不仅个位上的数相同，都是2，而742的十位上和452百位上的数也相同，都是4。观察前四幅图，可以发现图①和图④个位上的图形相同，且图①十位上的图形与图④百位上的图形相同，则可以推断图①对应的密码是742，图④对应的密码是452，说明◇=7,○=4,△=2。由△=2，可知②对应的密码是248，说明另一个图形代表8;那么剩下的③对应的密码是185，说明☆=1。因此，第五个密码锁上的图形对应的密码是451。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "24-25 二年级下·江苏泰州·期末"
+  },
+  {
+    "id": "148",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "有三个小朋友，他们分别出生在北京，吉林和沈阳。毛毛从未去过北京，阳阳不是出生在北京，也不是出生在沈阳，贝贝出生在( )。",
+    "options": [],
+    "answer": "北京",
+    "solution": "【分析】阳阳不是出生在北京，也不是出生在沈阳，所以阳阳肯定出生在吉林;毛毛从未去过北京，说明他不是出生在北京，再去掉吉林就只剩下沈阳了，所以毛毛肯定出生在沈阳。最后可以肯定贝贝出生在北京.\n【详解】由分析可得：有三个小朋友，他们分别出生在北京，吉林和沈阳。毛毛从未去过北京，阳阳不是出生在北京，也不是出生在沈阳，贝贝出生在北京。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "23-24 二年级下·贵州黔南·期末"
+  },
+  {
+    "id": "149",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "三个小朋友拍皮球，分别拍了38下,45下,80下，小方拍了( )下，小红拍了( )下，小英拍了( )下.\n![](images/0c3d875fb71cd3baba7c639839c18033ebaf4dfbce7d2abcc0be456a0b1114db.jpg)",
+    "options": [],
+    "answer": "45;38;80",
+    "solution": "【分析】比较数据,38<45<80，小红拍的最少，则小红拍了38下。小方拍的不是最多的，则小英拍的最多，是80下。剩下的45下是小方拍的.\n【详解】38<45<80，由分析得，三个小朋友拍皮球，分别拍了38下,45下,80下，小方拍了45下，小红拍了38下，小英拍了80下。",
+    "knowledge_points": [
+      "推理问题",
+      "100以内数的比大小"
+    ],
+    "source": "23-24二年级下·浙江嘉兴·期末"
+  },
+  {
+    "id": "150",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "在方格图中，每行，每列都有1,2,3,4这四个数，并且每个数在每行，每列都只出现一次,A是( ).\n![](images/image-14.png)",
+    "options": [],
+    "answer": "1或3",
+    "solution": "【分析】根据每行，每列都有1,2,3,4这四个数，并且每个数在每行，每列都只出现一次，先从有数字的行推断，利用排除法尝试填空。据此解答.\n【详解】由分析可得：因为第二横排有3,1两个数字，所以第二排第二列不能是1和3，又因为第二列有数字4，因此第二排第二列不能是4，所以这个格里只能是2;第二列中还剩1和3两个数没填。A位置可以填1，也可以填3。在方格图中，每行，每列都有1,2,3,4这四个数，并且每个数在每行，每列都只出现一次,A是1或3。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "23-24二年级下·浙江嘉兴·期末"
+  },
+  {
+    "id": "151",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "在下面的方格中，每行，每列都有1~4这四个数，并且每个数在每行，每列都只出现一次。A是( ),B是( ).\n\n| | | | 2 |\n| ---- | ---- | ---- | ---- |\n| A | 4 | | B |\n| 2 | | | |\n| | | | 3 |",
+    "options": [],
+    "answer": "3;1",
+    "solution": "【分析】第四列已经有2和3，所以可以将B先锁定在1和4的范围内，又因为B所在的第二行已经有数字4，所以即可得出B表示1。再根据B表示1和第二行已经有的数字4，可以将A锁定在2和3的范围内。又因为A所在的第一列有数字2，所以即可得出数字A表示多少。据此解答即可.\n【详解】据分析可知：由第四列可以推出,B等于1或4，由第二行可知,B不等于4，所以B等于1。所以第二行中,A等于2或3，又因为第一列已经有2了,A不等于2，所以A等于3。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "23-24二年级下·河北邯郸·期末"
+  },
+  {
+    "id": "152",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "已知三个同学的爸爸一位是教师，一位是军人，一位是医生。根据下面三人的说法，判断小强的爸爸是( ),小芳的爸爸是( ),小刚的爸爸是( ).\n![](images/1a875fc0ded059d99472570f424987f7.png)",
+    "options": [],
+    "answer": "教师;军人;医生",
+    "solution": "【分析】因为小刚说，你们经常来医院找我爸爸看病，所以小刚的爸爸是医生。所以小强和小芳的爸爸的职业就是教师或者军人。又因为小强说，我的爸爸不是军人，所以小强的爸爸是教师，且小芳说，我的爸爸不是老师，所以小芳的爸爸是军人。据此解答即可.\n【详解】据分析可知：小强的爸爸是教师，小芳的爸爸是军人，小刚的爸爸是医生。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "23-24 二年级下·福建龙岩·期末"
+  },
+  {
+    "id": "153",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "在下面的方格中，每行，每列都有1-4这四个数，并且每个数都在每行，每列都只出现一次,A应该是( ),B应该是( ).\n\n| | | | 4 |\n| ---- | ---- | ---- | ---- |\n| | 3 | B | 1 |\n| | | 4 | |\n| 2 | | | A |",
+    "options": [],
+    "answer": "3;2",
+    "solution": "【分析】A所在的第四列已有了4和1，且所在的第四行已有2，故A是3;B所在的第三列已有了4，且所在的第二行已有3和1，故B是2;据此解答。\n【详解】由题意分析得：在方格中，每行，每列都有1-4这四个数，并且每个数都在每行，每列都只出现一次,A应该是3,B应该是2。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "23-24 二年级下·广东广州·期末"
+  },
+  {
+    "id": "154",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "学校举行跳绳比赛，进入决赛的3人成绩分别是160下,123下,108下，第一名是( ),第二名是( ).\n![](images/ec3e1291b92c539f7e92fa989df9555ddd5687fd3703662b9de5076d0d28cb6b.jpg)",
+    "options": [],
+    "answer": "青青;元元",
+    "solution": "【分析】由题意分析可知,160>123>108，且明明跳得最少，所以明明跳了108下，是第三名;而元元不是第一名，且跳得比青青少，所以，青青是第一名，元元是第二名;据此解决.\n【详解】由分析可知：学校举行跳绳比赛，进入决赛的3人成绩分别是160下,123下,108下，第一名是青青，第二名是元元。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "23-24 二年级下·广东广州·期末"
+  },
+  {
+    "id": "155",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "在下面的方格中，每行，每列都有1~4这四个数，并且每个数在每列，每行都只出现一次。则A=( ),B=( ).\n\n| 4 | 1 | | |\n| ---- | ---- | ---- | ---- |\n| A | | B | 1 |\n| | | 4 | |\n| 3 | | | |",
+    "options": [],
+    "answer": "2;3",
+    "solution": "【分析】根据题意每个数在每行，每列都只出现一次可知，第二行的第一个数，第三个数不能是\"4\"，则第二行的\"4\"在第二个格子。第一列的第二个数不能是\"1\"，所以第一列的\"1\"在第三个格子，由此可知A是\"2\"，第二行只剩下\"3\"，则B是\"3\".\n【详解】根据分析可得如下图:\n\n| 4 | 1 | | |\n| ---- | ---- | ---- | ---- |\n| 2 | 4 | 3 | 1 |\n| 1 | | 4 | |\n| 3 | | | 4 |\n\n根据分析可得:A=2,B=3。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "23-24 二年级下·山东菏泽·期末"
+  },
+  {
+    "id": "156",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "小亮，小林，小兰三人踢毽子，分别踢了12下,8下和9下，小亮不是最少的，小林比小亮踢得多，小兰踢了( )下。",
+    "options": [],
+    "answer": "8",
+    "solution": "【分析】因为小林比小亮踢得多，且小亮踢得不是最少的，所以小林踢毽子的数量是最多的，在12下,8下和9下中,12下是最多的，所以小林踢了12下;由于小亮踢得不是最少的，那么小亮踢得就不是8下，所以小亮踢了9下;现在已经确定小林踢了12下，小亮踢了9下，那么剩下的8下就是小兰踢的数量.\n【详解】由分析可知：小林踢了12下，小亮踢了9下，所以小兰踢了8下。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "23-24 二年级下·黑龙江佳木斯·期末"
+  },
+  {
+    "id": "157",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "在下面的方格中，每行，每列都有1~4这四个数，并且每个数在每行，每列都只出现一次。A是( ),B是( ).\n\n| | 4 | | |\n| ---- | ---- | ---- | ---- |\n| A | | | 3 |\n| | 2 | | |\n| 4 | B | 1 | |",
+    "options": [],
+    "answer": "2;3",
+    "solution": "【分析】根据题意可知：第2行和第3行的\"4\"不能在第1列，第2列，第2行只有在第3列的位置还有空，所以第2行的\"4\"应该在第3列的位置，则第3行的\"4\"会在第4列的位置;第2行剩余两个空中，\"2\"不能在第2列，则第2行的\"1\"在第2列，\"2\"在第一列;第2列剩余一个空，则\"3\"在第2列的最后一个空。由此即可推断出A,B代表哪个数.\n【详解】根据分析可知：第2行的数从左到右依次为:2,1,4,3，所以A代表2;第2列的数从上到下依次为:4,1,2,3，所以B代表3。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "23-24 二年级下·河北邯郸·期末"
+  },
+  {
+    "id": "158",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "小丽，小花，小东三人进行跳绳比赛。小东说：\"我不是最后一名.\"小花说：\"我也不是最后一名，但是小东的成绩比我好.\"小丽得第( )名。",
+    "options": [],
+    "answer": "三或3",
+    "solution": "【分析】根据小东和小花都不是最后一名可知，最后一名是另外一个小朋友;再根据小东比小花成绩好，可得出他们各自的名次.\n【详解】由分析得：小东和小花都不是最后一名，则小丽是最后一名;剩下第一名和第二名;小东成绩比小花好，则小东是第一名，小花是第二名;即小丽得第三名。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "23-24二年级下·福建莆田·期末"
+  },
+  {
+    "id": "159",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "在下边的方格中，每行，每列都有1~4这四个数，并且每个数在每行，每列都只出现一次。A是( ),B是( ).\n\n| 4 | | | |\n| ---- | ---- | ---- | ---- |\n| 2 | | | 3 |\n| A | 1 | | B |\n| | | 2 | |",
+    "options": [],
+    "answer": "3;2",
+    "solution": "【分析】根据题中已有的数据先确定比较容易确定的单元格，再逐个推理其他格中数据。据此解答.\n【详解】由分析可得：因为每行，每列都有1~4这四个数，并且每个数在每行，每列都只出现一次。第一列已经有4,2，所以A这一格只能是1和3，又因为第三行有1，所以A这一格只能是3;这样第三行就确定1和3的位置了，那么B这一格只能是2和4，又因为第三列有2，所以第三行第三列的位置不能是2，所以2只能在B的位置。故A是3,B是2。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "23-24二年级下·广东东莞·期末"
+  },
+  {
+    "id": "160",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "○+○+△+△=50,○-△=5,○=( ),△=( )。",
+    "options": [],
+    "answer": "15;10",
+    "solution": "【分析】由题意可知，两个圆加两个三角形等于50，那么一个圆加一个三角形等于25;又已知，一个圆减一个三角形等于5,25+5=30;所以两个圆等于30，则，一个圆等于15;25-15=10，即三角形等于10;据此解答即可.\n【详解】50=25+25;25+5=30;30=15+15;25-15=10;所以○=15,△=10。",
+    "knowledge_points": [
+      "两位数与两位数的进位加法",
+      "一位数与两位数的进位加法",
+      "两位数与两位数的不退位减法",
+      "推理问题"
+    ],
+    "source": "23-24 二年级下·山东菏泽·期末"
+  },
+  {
+    "id": "161",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "乙比甲矮3厘米，丙比乙高1厘米，则( )最矮。",
+    "options": [],
+    "answer": "乙",
+    "solution": "【分析】由题意可知：乙比甲矮3厘米，则甲比乙高3厘米;丙也比乙高1厘米，则甲和丙都比乙高，那么乙是最矮的，据此解答.\n【详解】由分析可得：乙比甲矮3厘米，丙比乙高1厘米，则乙最矮。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "23-24 二年级下·浙江舟山·期末"
+  },
+  {
+    "id": "162",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "小马，小青，小丽三人进行跳绳比赛。小马说：\"我不是第一名.\"小青说：\"我也不是第一名，但是我比小马跳的多.\"小马第( )名，小青第( )名，小丽第( )名。",
+    "options": [],
+    "answer": "三;二;一",
+    "solution": "【分析】根据题意，小马和小青都不是第一名，可知第一名是另一个小朋友;再根据小青比小马跳得多，可得知小青的名次要高于小马,(跳得越多，名次越高),由此得知每个人的名次.\n【详解】根据小马和小青都不是第一名，可知第一名是小丽;还剩下第二名和第三名，又知小青比小马跳得多，则小青应为第二名，剩下的第三名就是小马。即小马第三名，小青第二名，小丽第一名。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "23-24 二年级下·福建龙岩·期末"
+  },
+  {
+    "id": "163",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "如表所示的方格中每行，每列都有1~4这四个数，并且每个数在每行，每列都只出现一次。那么A是( ),B是( ).\n\n| | 2 | 3 | |\n| ---- | ---- | ---- | ---- |\n| | 1 | | |\n| 3 | A | | B |\n| | | 2 | 1 |",
+    "options": [],
+    "answer": "4;2",
+    "solution": "【分析】依据题意结合第一列和第四行的数可知，第四行第一个数是4，则第二个数是3，所以A是4，结合第四列的数可知，第三行第三个数是1，由此解答本题.\n【详解】由分析可得，如表所示的方格中每行，每列都有1~4这四个数，并且每个数在每行，每列都只出现一次。那么A是4,B是2。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "23-24二年级下·天津和平·期末"
+  },
+  {
+    "id": "164",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "下面的方格中，每行，每列都有1-4这四个数，且每个数在每行，每列都只出现一次。A是( ),B是( ),C是( ).\n![](images/image-21.png)",
+    "options": [],
+    "answer": "2;1;3",
+    "solution": "【分析】根据题意，每行，每列都有1-4这四个数，且每个数在每行，每列都只出现一次。则从出现数字较多的地方开始推算。也就是根据A所在的行，列出现的数字，推算出A是几，根据B所在的行，列出现的数字，推算出B是几，最后再推算出C是几.\n【详解】A所在的行，列出现是1,3,4，则A只能是2;B所在的行，列出现了2,3,4，则B只能是1;首先确定第二行，第三列的数字，第三列中出现4,1,2，则这里只能是3;接下来确定第二行，第四列的数字，这一行中出现了2,4,3，则这里只能是1;再确定第一列，第四行的数字，这列中出现了1,2,3，则这里只能填4;最后确定C的数字，所在的行，列中出现了1,2,4，则这里只能是3。所以方格中，每行，每列都有1-4这四个数，且每个数在每行，每列都只出现一次。A是2,B是1,C是3。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "23-24 二年级下·河南漯河·期末"
+  },
+  {
+    "id": "165",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "在下图的方格中，每行，每列都有2-5这四个数，并且每个数在每行，每列都只能出现一次。那么A=( ),B=( ).\n![](images/image-22.png)",
+    "options": [],
+    "answer": "4;3",
+    "solution": "【分析】从左往右第一列有2和3，那么A可能是4或5，又因为从上往下第四行里面有5了，所以A只能是4;从左往右第4列有4和5，那么第4列第3个数字就可能是2或3，又因为这一行已经有2了，所以第4列第3个数字只能是3，那么第4列第4个数字就是2;B所在的这一行已经有了4,5,2，因此B就是3.\n【详解】由分析可知：每行，每列都有2-5这四个数，并且每个数在每行，每列都只能出现一次。那么A=(4),B=(3)。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "23-24二年级下·重庆永川·期末"
+  },
+  {
+    "id": "166",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "有语文，数学和科学三本书，小红，小丽，小刚三人各拿一本，小红说：\"我拿的是数学书\"，小丽说：\"我拿的不是语文书\"，小刚拿的是( )书。",
+    "options": [],
+    "answer": "语文",
+    "solution": "【分析】小红，小丽和小刚三个人各自拿的书分别为语文，数学和科学，其中小红拿的是数学书，那么小丽和小刚两个人拿的书必定为语文和科学的其中一本，小丽说拿的不是语文书，说明小丽拿的是科学书，那么小刚拿的就是语文书.\n【详解】根据分析可得：有语文，数学和科学三本书，小红，小丽，小刚三人各拿一本，小红说：\"我拿的是数学书\"，小丽说：\"我拿的不是语文书\"，小刚拿的是语文书。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "23-24 二年级下·天津河北·期末"
+  },
+  {
+    "id": "167",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "在下面格中，每行，每列都有1-4这四个数字，且每个数在每行，每列都只出现一次，那么A是( ),B是( ).\n![](images/image-23.png)",
+    "options": [],
+    "answer": "1;3",
+    "solution": "【分析】已知第一行中出现了1和2，每行每列的数字只能出现一次，第二行出现3和4，所以第一行第三列的数只能是4，第一行第四列的数是3;已知第四列中出现了1,4,3，所以第四列第三行的数是2;已知第二行中出现了3和4，所以第二行第一列是2，第二行第二列是1;已知第一列中出现了1,2,4，所以第一列第三行的数是3;已知第三行出现了3,2，缺少1和4，因为第二行第二列中是1，所以第三行第二列只能是4，第三行第三列是1;已知第四行中出现了4和1，缺少2和3，因为第一行第二列中是2，所以第四行第二列只能是3，第四行第三列是2。\n【详解】据分析可得:A是1,B是3。",
+    "knowledge_points": [
+      "推理问题",
+      "数表中的规律"
+    ],
+    "source": "23-24 二年级下·重庆大渡口·期末"
+  },
+  {
+    "id": "168",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "在下面的方格中，每行，每列都有1~4这四个数，并且每个数在每行，每列都只出现一次。B应该是( ).\n![](images/image-24.png)",
+    "options": [],
+    "answer": "3",
+    "solution": "【分析】根据题意，每行，每列都有1~4这四个数，并且每个数在每行，每列都只出现一次。则先根据A所在的行，列出现的数字确定出A代表的数字，进而确定B代表的数字.\n【详解】A所在的行，列出现了1,2,3，则A应该是4;B所在的行，列出现了1,2,4，则B应该是3。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "23-24二年级下·天津河东·期末"
+  },
+  {
+    "id": "169",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "四个同学的体重分别是38千克,42千克,41千克,39千克。已知小强比小红重但又比小军轻，小兰比小红轻。那么小强的体重是( )千克。",
+    "options": [],
+    "answer": "41",
+    "solution": "【分析】根据题意，小强比小红重，但又比小军轻，说明小军的体重>小强的体重>小红的体重;小兰比小红轻，则他们四人的体重是：小军体重>小强体重>小红体重>小兰体重，即42千克>41千克>39千克>38千克，所以小强的体重是41千克，据此解答.\n【详解】根据分析可知，四个同学的体重分别是38千克,42千克,41千克,39千克。已知小强比小红重但又比小军轻，小兰比小红轻。那么小强的体重是41千克。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "2024·河北衡水·小升初真题"
+  },
+  {
+    "id": "170",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "涵涵，静静和芳芳每人拿着一种水果，分别是火龙果，橙子和苹果。涵涵说：\"我拿的是火龙果.\"芳芳说：\"我拿的不是苹果.\"静静拿的是( ),芳芳拿的是( )。",
+    "options": [],
+    "answer": "苹果;橙子",
+    "solution": "【分析】根据题意可知，涵涵的陈述：\"我拿的是火龙果.\"假设涵涵说真话，则她拿火龙果;芳芳的陈述：\"我拿的不是苹果.\"此时剩余水果为橙子和苹果，由于芳芳不能拿苹果，她只能拿橙子;剩下的水果：静静只能拿苹果.\n【详解】根据分析可得：静静拿的是苹果，芳芳拿的是橙子。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "2025二年级下·全国·专题练习"
+  },
+  {
+    "id": "171",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "聪聪，亮亮，红红分别参加了合唱，书法，绘画社团。①亮亮没参加书法社团;②聪聪既没参加合唱社团，也没参加绘画社团;③红红没参加绘画社团。根据上面信息判断他们参加的社团：聪聪-( )社团;亮亮-( )社团;红红-( )社团。",
+    "options": [],
+    "answer": "书法;绘画;合唱",
+    "solution": "【分析】根据条件②,聪聪既没参加合唱社团，也没参加绘画社团，那么在合唱，书法，绘画社团中，排除合唱和绘画社团后，聪聪只能参加书法社团。因为聪聪已经确定参加书法社团，再看条件③,红红没参加绘画社团，此时还剩下合唱社团，所以红红参加的是合唱社团。由于聪聪参加书法社团，红红参加合唱社团，那么剩下的亮亮就只能参加绘画社团，据此解答即可。\n【详解】由分析可知，聪聪-书法社团;亮亮-绘画社团;红红-合唱社团。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "23-24 三年级下·河北唐山·期末"
+  },
+  {
+    "id": "172",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "小王，小李，小张分别从事医生，教师，司机这三种职业中的一种。小王不会开车，小李每天都要批改作业。由此可知小王的职业是( ),小李的职业是( ),小张的职业是( )。",
+    "options": [],
+    "answer": "医生;教师;司机",
+    "solution": "【分析】根据题意可知，小李每天都要批改作业，所以小李的职业是教师;再根据小王不会开车，可知小王的职业是医生，进而可知小张是司机;据此解答.\n【详解】小王，小李，小张分别从事医生，教师，司机这三种职业中的一种。小王不会开车，小李每天都要批改作业。由此可知小王的职业是(医生),小李的职业是(教师),小张的职业是(司机)。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "2024·河北沧州·小升初真题"
+  },
+  {
+    "id": "173",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "王叔叔，刘叔叔，林叔叔和李叔叔的职业是工人，教师，军人中的一种。王叔叔是教师，林叔叔不是工人，只有刘叔叔和李叔叔的职业相同，则林叔叔是( ),刘叔叔是( ),李叔叔是( )。",
+    "options": [],
+    "answer": "军人;工人;工人",
+    "solution": "【分析】王叔叔的职业已确定为教师，剩下工人和军人两种职业需分配给刘，林，李三人。林叔叔不能是工人，因此林叔叔只能是军人。此时剩下工人职业需由刘叔叔和李叔叔共同担任(因只有他们职业相同),而军人已由林叔叔担任，教师由王叔叔担任，符合所有条件.\n【详解】根据分析可得：林叔叔是军人，刘叔叔是工人，李叔叔是工人。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "24-25 六年级下·海南海口·单元测试"
+  },
+  {
+    "id": "174",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.15,
+    "question": "甲，乙，丙，丁，戊五位同学在一次数学竞赛中得了前五名，发奖前老师要他们猜一猜各人所得的名次.\n甲猜：乙第三名，丙第五名;乙猜：戊第四名，丁第五名;丙猜：甲第一名，戊第四名;丁猜：丙第一名，乙第二名;戊猜：甲第三名，丁第四名.\n老师说：每个名次都有人猜对了，那么，获得第四名的是( )。",
+    "options": [],
+    "answer": "戊",
+    "solution": "【分析】由于每个名次都有人猜对，则以名次次数最少的入手思考，由于第二名出现了一次，则第二名为乙，进而根据第三名为甲，乙之一，结合乙的名次，可确定出甲为第三名，依此类推，可求出丙为第一名，丁为第五名，则余下的第四名就为戊.\n【详解】由于每个名次都有人猜对，且第二名只出现了乙，则乙为第二名;第三名不是乙就是甲，由于第二名是乙，则第三名为甲;第一名不是甲就是丙，而甲为第三名，则第一名为丙;第五名不是丙就是丁，而丙为第一名，则丁为第五名，余下的戊为第四名。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "24-25 六年级下·北京海淀·开学考试"
+  },
+  {
+    "id": "175",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "三层书架共有27本书，从第一层拿出5本放第二层，从第三层拿出3本放到第二层，这时三层书架中的本数相等，原来第二层有( )本书。",
+    "options": [],
+    "answer": "1",
+    "solution": "【分析】此题可以从移动后三层书架上的书的本数相等逆向思考：这时三层上都有27÷3=9(本),根据题干\"第一层拿出5本放到第二层\"，那么返回去，原来第一层就有9+5=14(本),由此类推，即可解决问题.\n【详解】27÷3=9(本);第一层:9+5=14(本);第三层:9+3=12(本);第二层:9-5-3=4-3=1(本)。所以原来第二层有1本书。",
+    "knowledge_points": [
+      "倒推问题"
+    ],
+    "source": "24-25三年级上·内蒙古呼伦贝尔·期末"
+  },
+  {
+    "id": "176",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "甲，乙，丙三人中只有1人会下象棋。甲说：\"我会下。\"乙说：\"我不会下。\"丙说：\"甲不会下。\"三人的话只有一句是真话，会下象棋的是( )。",
+    "options": [],
+    "answer": "乙",
+    "solution": "【分析】三人的话只有一句是真话，假设甲说的是真话，则乙说的是真话，丙说的是假话，不符合题意;假设甲说的是假话，则丙说的是真的，由于三人的话只有一句是真话，所以乙说的是假话，故可以推断出乙会下象棋.\n【详解】根据分析可知，会下象棋的是乙。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "2022 五年级·全国·竞赛"
+  },
+  {
+    "id": "177",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "小明，小红，小军比较年龄大小，小明说：\"我不是最小的\"。小军说：\"我也不是最小的，但比小明大\"。年龄最小的是( )。",
+    "options": [],
+    "answer": "小红",
+    "solution": "【分析】小明说：\"我不是最小的\"。小军说：\"我也不是最小的，但比小明大\"，说明小明和小军都不是最小的，共只有三个人，所以小红是最小的.\n【详解】小明，小红，小军比较年龄大小，小明说：\"我不是最小的\"。小军说：\"我也不是最小的，但比小明大\"。年龄最小的是小红。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "22-23二年级下·四川乐山·期末"
+  },
+  {
+    "id": "178",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "张兵，李林，王红，江风一起排队上车。江风在张兵，李林的中间，王红在最后，张兵不是第一个。请你把他们的名字从前往后写下来。( ),( ),( ),( )。",
+    "options": [],
+    "answer": "李林;江风;张兵;王红",
+    "solution": "【分析】根据王红在最后可确定江风，张兵，李林是前三个，再根据江风在张兵，李林的中间即可确定三人的顺序;据此解答.\n【详解】江风在张兵，李林的中间，王红在最后，说明江风排第二;张兵不是第一个，说明李林是第一个，则张兵是第三个。所以他们的名字从前往后是：李林，江风，张兵，王红。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "22-23 二年级下·四川乐山·期末"
+  },
+  {
+    "id": "179",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "芳芳，豆豆，洋洋年龄不同，芳芳没有洋洋大，洋洋没有豆豆大，三人中,( )的年龄最大,( )的年龄最小。",
+    "options": [],
+    "answer": "豆豆;芳芳",
+    "solution": "【分析】根据题意，芳芳没有洋洋大，也就是芳芳的年龄小于洋洋的年龄;洋洋没有豆豆大，也就是洋洋的年龄小于豆豆的年龄，由此排列他们的年龄大小即可.\n【详解】由分析可知：芳芳的年龄<洋洋的年龄<豆豆的年龄。则三人中，豆豆的年龄最大，芳芳的年龄最小。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "23-24 二年级下·四川南充·期末"
+  },
+  {
+    "id": "180",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "小强，小青和小玲三个人比高矮，小强不是最矮的但比小青矮，小玲没有小青高，也没有小强高，他们三人中,( )最高。",
+    "options": [],
+    "answer": "小青",
+    "solution": "【分析】根据题意，三个人比高矮，则分别为最高的，中间高的和最矮的。先推断出小玲的高度，进而可推断出小强和小青的高度.\n【详解】小玲没有小青高，也没有小强高，也就是小玲是最矮的;还剩下中间高的和最高的，又知小强不是最矮的但比小青矮，可知小强是中间高的，小青就是最高的。他们三人中，小青最高。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "23-24 二年级下·四川乐山·期末"
+  },
+  {
+    "id": "181",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "小红，小明，小丽进行拍皮球比赛。小红不是最多的，但是比小丽拍得多。他们三人中,( )是第一名。",
+    "options": [],
+    "answer": "小明",
+    "solution": "【分析】排除不是最多的两个人，剩下的就是最多的那个，也就是第一名.\n【详解】小红不是最多的，但是比小丽拍得多，则小丽也不是最多的，所以小明是最多的，小明是第一名。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "22-23 二年级下·四川广元·期末"
+  },
+  {
+    "id": "182",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "如方格图，每行，每列都有\"努，力，学，习\"这四个字，而且每个字在每行，每列都只出现一次。想一想,▲是( ),★是( ),●是( ).\n![](images/image-25.png)",
+    "options": [],
+    "answer": "力;努;学",
+    "solution": "【分析】根据每行，每列都有\"努，力，学，习\"这四个字，而且每个字在每行，每列都只出现一次，先确定▲,进而确定★和●即可.\n【详解】如方格图,▲所在列已经有\"努，学，习\"三个字，所以▲是\"力\";★所在行和列已经有\"力，学，习\"，所以★是\"努\";这时●所在行和列已经有\"努，力，习\"，所以●是\"学\"。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "22-23 二年级下·四川乐山·期末"
+  },
+  {
+    "id": "183",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "○+○+△=18,△+○=14，则○=( ),△=( )。",
+    "options": [],
+    "answer": "4;10",
+    "solution": "【分析】本题主要考查了加减法各部分之间的关系,△+○看作一个加数，那么把△+○=14代入○+○+△=18，根据一个加数加上另一个加数等于和，一个加数等于和减去另一个加数。可得○+14=18，由此可得○表示的数,○=18-14，再求△表示的数即可。\n【详解】根据分析可知：因为△+○=14，所以○+○+△=○+14=18，所以○=4,△=14-○=14-4=10。",
+    "knowledge_points": [
+      "加，减法的意义和各部分间的关系"
+    ],
+    "source": "22-23 三年级下·四川绵阳·期末"
+  },
+  {
+    "id": "184",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "下图方格中，每行，每列都有1~4这四个数，且每个数在每行，每列都只出现一次。A是( ),B是( ).\n![](images/image-26.png)",
+    "options": [],
+    "answer": "2;1",
+    "solution": "【分析】根据题意，每行，每列都有1~4这四个数，且每个数在每行，每列都只出现一次。则从出现数字较多的地方开始推算。也就是根据A所在的行，列出现的数字，推算出A是几，根据B所在的行，列出现的数字，推算出B是几.\n【详解】A所在的行，列出现是1,3,4，则A只能是2;B所在的行，列出现了2,3,4，则B只能是1。A是2,B是1。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "23-24二年级下·贵州铜仁·期末"
+  },
+  {
+    "id": "185",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "在下面的方格中，每行，每列都有1-4这四个数，并且每个数在每行，每列都只出现一次。A是( ).\n\n| | 2 | | |\n| ---- | ---- | ---- | ---- |\n| | | 2 | |\n| 1 | A | | |\n| | | 3 | |",
+    "options": [],
+    "answer": "3",
+    "solution": "【分析】先看第3列，已经有了2,3，并且第3行已经有了1，所以A右边这个数是4,A的所在行和列已经出现了1,2,4，所以可以确定A是3，据此解答即可.\n【详解】由分析可得，在下面的方格中，每行，每列都有1-4这四个数，并且每个数在每行，每列都只出现一次。A是3。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "23-24 二年级下·河南南阳·期末"
+  },
+  {
+    "id": "186",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "学校组织了唱歌，美术，书法三个兴趣小组。笑笑，文文，丫丫每个人只参加了一个组，但各不相同。笑笑说：\"我不喜欢书法.\"文文说：\"我既没有参加美术小组，也没有参加书法小组.\"丫丫参加了( )小组。",
+    "options": [],
+    "answer": "书法",
+    "solution": "【分析】文文既没有参加美术小组，也没有参加书法小组，那么文文参加了唱歌小组，笑笑不喜欢书法，则笑笑参加了美术小组;还剩下一个兴趣小组是书法，所以剩下的丫丫参加了书法小组.\n【详解】根据分析可得，文文参加了唱歌小组，笑笑参加了美术小组，丫丫参加了书法小组。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "23-24 三年级下·河北保定·期末"
+  },
+  {
+    "id": "187",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "李叔叔，王叔叔，赵叔叔，他们三人一位是医生，一位是警察，一位是教师。李叔叔是治病救人的，王叔叔不是警察，赵叔叔是( )。",
+    "options": [],
+    "answer": "警察",
+    "solution": "【分析】根据题意可知，李叔叔是治病救人的，所以李叔叔是医生，王叔叔不是警察，则王叔叔是教师，剩下赵叔叔只能是警察，由此解答本题.\n【详解】由分析可得，李叔叔是医生，王叔叔是教师，所以赵叔叔是警察。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "23-24二年级下·河南濮阳·期末"
+  },
+  {
+    "id": "188",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "张，王，李三位老师，分别从事语文，数学，英语三门学科的教学工作(每个人只教一门学科)。已知王老师上课时全部用汉语教学;英语老师是一位年龄较大的男老师，李老师是一位女教师，比数学老师的性格要开朗一些。根据以上信息请你推断：张老师教( ),王老师教( ),李老师教( )。",
+    "options": [],
+    "answer": "英语;数学;语文",
+    "solution": "【分析】根据条件可知，王老师上课时全部用汉语教学，则王老师不是英语老师，他是语文或者数学老师。李老师即不是英语老师也不是数学老师，故李老师是语文老师，则王老师是数学老师，最后张老师是英语老师。据此解答即可.\n【详解】张，王，李三位老师，分别从事语文，数学，英语三门学科的教学工作(每个人只教一门学科)。已知王老师上课时全部用汉语教学;英语老师是一位年龄较大的男老师，李老师是一位女教师，比数学老师的性格要开朗一些。根据以上信息请你推断：张老师教(英语),王老师教(数学),李老师教(语文)。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "23-24 三年级下·河北保定·期末"
+  },
+  {
+    "id": "189",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "在下面的方格中，每行，每列都有1~4这四个数，并且每个数在每行，每列都只出现一次。A应该是( ),B应该是( ),C应该是( ).\n\n| | 2 | | |\n| ---- | ---- | ---- | ---- |\n| 2 | | A | 4 |\n| | | 3 | C |\n| 1 | B | | |",
+    "options": [],
+    "answer": "1;4;2",
+    "solution": "【分析】根据题意，每行，每列都有1~4这四个数，并且每个数在每行，每列都只出现一次。从出现数字较多的地方开始推算。也就是先推算出A和A左边的数字;然后可推算出B和B上边的数字，最后可推算出C处的数字.\n【详解】A所在的行，列出现了2,3,4，则A是1;A左边是3;B所在的行，列出现了1,2,3，则B是4;B上边是1;C所在的行，列出现了1,3,4，则C是2。A应该是1,B应该是4,C应该是2。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "23-24 二年级下·湖北恩施·期末"
+  },
+  {
+    "id": "190",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "小亮，小明，小东三人比赛跑步。结束后，小亮说：\"我不是第一.\"小明说：\"我在小亮的后面.\"这次比赛第一名是( )。",
+    "options": [],
+    "answer": "小东",
+    "solution": "【分析】根据题意可知，他们的名次分别是第一，第二和第三。小亮不是第一，可得出他可能的名次不是第一名，再根据小明在小亮后面确定出小亮和小明的名次，进而可知小东的名次.\n【详解】小亮不是第一，就可能是第二或第三;小明在小亮后面，则小亮只能是第二，小明是第三，小东就是第一。这次的比赛第一名是小东。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "23-24二年级下·福建漳州·期末"
+  },
+  {
+    "id": "191",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "方格中，每行每列都有1-4这四个数，并且每个数在每行，每列都只出现一次，则△是( ),☆是( ).\n\n| 2 | | | |\n| ---- | ---- | ---- | ---- |\n| △ | 3 | | 1 |\n| 3 | | ☆ | |\n| | | 4 | |",
+    "options": [],
+    "answer": "4;1",
+    "solution": "【分析】根据每行每列都有1-4这四个数，并且每个数在每行，每列都只出现一次先确定△,再确定☆即可.\n【详解】△所在的行和列有2,3,1，所以△是4且△所在行的第三个数是2,☆所在的行和列有2,3,4，所以☆是1。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "23-24 二年级下·山东临沂·期末"
+  },
+  {
+    "id": "192",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.94,
+    "question": "小芳，小亮，小晶三人在阅读比赛中夺得前三名。小芳说：\"我不是第三名。\"小亮说：\"我也不是第三名，但小芳的成绩比我高。\"那么( )是第一名,( )是第二名,( )是第三名。",
+    "options": [],
+    "answer": "小芳;小亮;小晶",
+    "solution": "【分析】根据小亮说的话，小亮的名次比小芳低，并且小亮不是第三名，所以小亮不可能是第一名，那么小亮就是第二名，小芳是第一名，剩下的小晶是第三名.\n【详解】根据分析可知，小芳是第一名，小亮是第二名，小晶是第三名。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "23-24 二年级下·山东济宁·期末"
+  },
+  {
+    "id": "193",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "小丽，小华和小敏三人分别喜欢画画，唱歌，跳舞，小丽说：\"我不喜欢唱歌.\"小华说：\"我喜欢跳舞.\"小敏喜欢( )。",
+    "options": [],
+    "answer": "唱歌",
+    "solution": "【分析】由题意可知，小丽说：我不喜欢唱歌，所以小丽喜欢画画或者跳舞，再因为小华说：我喜欢跳舞，所以小丽喜欢画画，剩下小敏喜欢唱歌，据此解答即可.\n【详解】由分析可得，小丽，小华和小敏三人分别喜欢画画，唱歌，跳舞，小丽说：\"我不喜欢唱歌.\"小华说：\"我喜欢跳舞.\"小敏喜欢唱歌。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "23-24二年级下·河南三门峡·期末"
+  },
+  {
+    "id": "194",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "在下面的方格中，每行，每列都有1~4这四个数，并且每个数在每行，每列都只出现一次。A是( ),B是( ).\n![](images/image-30.png)",
+    "options": [],
+    "answer": "2;3",
+    "solution": "【分析】可以运用排除法，排除行列中已经出现的数字。由图可知,A所在行有4，所在列有1,3，所以A是2;B所在行有4,2，所在列有1，所以B是3，据此解答即可.\n【详解】由分析可得,A是2,B是3。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "23-24 二年级下·江西抚州·期末"
+  },
+  {
+    "id": "195",
+    "unit": "第九单元 推理",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "李，周，王三人分别是医生，司机和教师。已知医生不是王，司机不是李也不是王，那么教师是王。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】根据题意，先推断出司机是谁，再根据医生不是王推断出医生是谁，进而可知教师是谁.\n【详解】司机不是李也不是王，则司机是周。还剩下李和王，又知医生不是王，也就是医生是李，则教师是王。原题说法正确。故答案为:√",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "23-24 二年级下·河南南阳·期末"
+  },
+  {
+    "id": "196",
+    "unit": "第九单元 推理",
+    "question_type": "解答题",
+    "difficulty": 0.85,
+    "question": "王，李，刘三位老师都在同一所学校任教，他们各教一门课程：音乐，体育，美术。已知：王老师上课不用颜料，李老师上课用颜料，刘老师上课用乐器。你能说说三位老师各教什么学科吗。",
+    "options": [],
+    "answer": "王老师教体育;李老师教美术;刘老师教音乐",
+    "solution": "【分析】李老师上课用颜料，则李老师是美术老师。刘老师上课用乐器，则刘老师是音乐老师。剩下的王老师就是体育老师.\n【详解】答：王老师教体育;李老师教美术;刘老师教音乐。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "24-25二年级下·河南漯河·期末"
+  },
+  {
+    "id": "197",
+    "unit": "第九单元 推理",
+    "question_type": "解答题",
+    "difficulty": 0.65,
+    "question": "王刚，张明和李军三人，其中一位是工人，一位是农民，一位是士兵。现在知道:\n(1)李军比士兵年龄大;(2)王刚和农民不同岁;(3)农民比张明年龄小.\n请问，他们中谁是工人，谁是农民，谁是士兵。",
+    "options": [],
+    "answer": "工人是张明;农民是李军;士兵是王刚",
+    "solution": "【分析】先根据已知条件确定不属于他们各自的职业，找出其中两人同时不属于的职业，则这一职业就是另外一人的职业。进而通过年龄的大小比较确定另外两人的职业.\n【详解】根据(1)可知，李军比士兵大，也就是李军不是士兵;根据(2)可知，王刚和农民不同岁，也就是王刚不是农民;根据(3)可知，农民比张明年龄小，也就是张明也不是农民，则农民只能是李军;还剩下士兵和工人。由(1)我们知道李军比士兵年龄大，由(3)我们又知道李军比张明年龄小，也就是张明不可能是士兵，那么士兵只能是王刚，则剩下的工人就是张明。答：张明是工人，李军是农民，王刚是士兵。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "2025 二年级下·全国·专题练习"
+  },
+  {
+    "id": "198",
+    "unit": "第九单元 推理",
+    "question_type": "解答题",
+    "difficulty": 0.85,
+    "question": "在下面的方格中，每行，每列都有1~4这四个数，并且每个数在每行，每列都只出现一次。A,B方格应分别填几。\n![](images/image-31.png)",
+    "options": [],
+    "answer": "3;2",
+    "solution": "【分析】根据题意，每行，每列都有1~4这四个数，并且每个数在每行，每列都只出现一次。A和B所在的行，列出现的数字都比较多，可直接将出现的数字排除，确定它们各自代表的数字.\n【详解】A所在的行，列出现了1,2,4，则A只能是3;B所在的行，列出现了1,3,4，则B只能是2。答:A是3,B是2。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "2025二年级下·全国·专题练习"
+  },
+  {
+    "id": "199",
+    "unit": "第九单元 推理",
+    "question_type": "解答题",
+    "difficulty": 0.65,
+    "question": "丽丽，兰兰和芳芳去采摘草莓。采摘结束，丽丽给兰兰3颗，兰兰又给芳芳2颗，这时每人都有20颗草莓。兰兰原来有多少颗草莓。",
+    "options": [],
+    "answer": "19颗",
+    "solution": "【分析】兰兰又给芳芳2颗，这时每人都有20颗草莓，据此可知没送给芳芳前兰兰有20+2=22(颗),又已知丽丽给兰兰3颗，则用22减去3，即可求出兰兰原来有多少颗草莓.\n【详解】20+2=22(颗);22-3=19(颗)。答：兰兰原来有19颗草莓。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "23-24三年级上·北京顺义·期末"
+  },
+  {
+    "id": "200",
+    "unit": "第九单元 推理",
+    "question_type": "解答题",
+    "difficulty": 0.65,
+    "question": "吃完饭回家的路上，爸爸买了3袋薯片:2袋原味,1袋青柠味。爸爸把1袋青柠味的给了姐姐,1袋原味的给了妹妹，剩下的一袋给了妈妈。爸爸让姐妹俩猜一猜妈妈得到的是什么口味的薯片。同学们，你知道谁一定会猜对吗。(姐姐和妹妹都只知道自己薯片的口味)",
+    "options": [],
+    "answer": "姐姐",
+    "solution": "【分析】根据拿到的薯片口味和剩下的薯片口味进行分析。姐姐拿到的是1袋青柠味的薯片，则姐姐知道剩下的2袋一定都是原味的，即妈妈和妹妹的一定是原味，依此解答。\n【详解】姐姐拿到的是1袋青柠味的薯片，则姐姐知道剩下的2袋一定都是原味的，这剩下的2袋一袋分给了妹妹，一袋分给了妈妈，所以分给妈妈的一定是原味的薯片;妹妹分到的是1袋原味的，则剩下的2袋，一袋是原味的，一袋是青柠味的，姐姐和妹妹都只知道自己薯片的口味，所以妹妹不能猜出妈妈分到的薯片是原味的还是青柠味的。答：姐姐一定会猜对。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "24-25五年级上·吉林四平·期中"
+  },
+  {
+    "id": "201",
+    "unit": "第九单元 推理",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "小丽，小红和小英三个小朋友比赛跳绳，小丽说：\"我跳得最多。\"小红说：\"我跳得不是最少的。\"小英排第( )。",
+    "options": [
+      "A. 一",
+      "B. 二",
+      "C. 三"
+    ],
+    "answer": "C",
+    "solution": "【分析】根据小丽跳得最多，确定小丽的名次;再根据小红跳得不是最少的及小丽跳得最多，确定小红的名次;进而确定小英的名次;据此解答。\n【详解】小丽跳得最多，排名第一。小红跳得不是最少的，排名第二，所以小英跳得最少，排名第三。故答案为:C",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "23-24 二年级下·河北保定·期末"
+  },
+  {
+    "id": "202",
+    "unit": "第九单元 推理",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "小萱，小雅和小可比赛跳绳，她们分别跳了102下,120下,128下，小可说：\"我跳的是最多的。\"小萱说：\"我跳的不是最少的。\"请问( )跳的最少。",
+    "options": [
+      "A. 小萱",
+      "B. 小雅",
+      "C. 小可"
+    ],
+    "answer": "B",
+    "solution": "【分析】根据题意可知小可跳得最多，剩下的是跳得最少的和中间数量的，又知小萱跳得不是最少的，则她就是中间的，跳得最少的就是小雅。\n【详解】由分析可知，跳的数量从多到少分别是小可，小萱，小雅。小雅跳得最少。故答案为:B",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "23-24 二年级下·湖南郴州·期末"
+  },
+  {
+    "id": "203",
+    "unit": "第九单元 推理",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "有三名学生分别来自二(1),二(2),二(3)班。其中小丽不是二(3)班的，小雨下课后去找二(1)班的小东玩。二(3)学生是( )。",
+    "options": [
+      "A. 小丽",
+      "B. 小雨",
+      "C. 小东"
+    ],
+    "answer": "B",
+    "solution": "【分析】由题意可知，有三名学生分别来自二(1),二(2),二(3)班，小东是二(1)班的，而小丽不是二(3)班的，所以小丽是二(2)班的，小雨是二(3)班的，据此解答。\n【详解】由题意分析得:A. 小丽是二(2)班的;B. 小雨是二(3)班的;C. 小东是二(1)班的;即，有三名学生分别来自二(1),二(2),二(3)班。其中小丽不是二(3)班的，小雨下课后去找二(1)班的小东玩。二(3)班学生是小雨。故答案为:B",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "23-24 二年级下·浙江台州·期末"
+  },
+  {
+    "id": "204",
+    "unit": "第九单元 推理",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "小兰，小花，小刚三个小朋友赛跑，小花跑得不是最快的，但比小兰快,( )跑得最快。",
+    "options": [
+      "A. 小刚",
+      "B. 小花",
+      "C. 小兰"
+    ],
+    "answer": "A",
+    "solution": "【分析】小兰，小花，小刚三个小朋友赛跑，小花跑得不是最快的，那就是跑第二的或跑最慢的，但小花比小兰快，那说明小花跑在第二的位置;而小兰比小花慢，则说明小兰跑得是最慢的，小刚跑得是最快的，据此解决.\n【详解】小兰，小花，小刚三个小朋友赛跑，小花跑得不是最快的，但比小兰快，小刚跑得最快。故答案为:A",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "23-24 二年级下·山东济南·期末"
+  },
+  {
+    "id": "205",
+    "unit": "第九单元 推理",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "在下面的方格中，每行，每列都有1~4这四个数，并且每个数在每行，每列都只出现一次,B应是( ).\n\n| 1 | | | 3 |\n| ---- | ---- | ---- | ---- |\n| | | | |\n| B | 4 | | A |\n| | | | 1 |",
+    "options": [
+      "A. 1",
+      "B. 2",
+      "C. 3",
+      "D. 4"
+    ],
+    "answer": "C",
+    "solution": "【分析】第四列中有1和3，所以A应该为2或4，第三行中有4，所以A应该为2;第一列中有1，所以B应该为2或3或4，第三行中有4和2，所以B应该是3。\n【详解】在下面的方格中，每行，每列都有1~4这四个数，并且每个数在每行，每列都只出现一次,B应是3。故答案为:C",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "23-24 二年级下·山东菏泽·期末"
+  },
+  {
+    "id": "206",
+    "unit": "第九单元 推理",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "在下面的方格中，每行，每列都有6~9这四个数，并且每个数在每行，每列都只出现一次。表格中☆应该是( ).\n\n| | | 9 | |\n| ---- | ---- | ---- | ---- |\n| 7 | | | |\n| | | 8 | |\n| | 8 | 7 | 6 |",
+    "options": [
+      "A. 6",
+      "B. 7",
+      "C. 9"
+    ],
+    "answer": "C",
+    "solution": "【分析】根据题意，从出现数字较多的地方开始推算。也就是第三列，先确定第三列第2格的数字，进而就能确定☆表示的数字.\n【详解】第三列出现了7,8和9，则第三列第2格只能是6;此时☆所在的行，列出现了6,7和8，则☆只能是9。表格中☆应该是9。故答案为:C",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "23-24 二年级下·河北保定·期末"
+  },
+  {
+    "id": "207",
+    "unit": "第九单元 推理",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "有香蕉，苹果，橘子三种水果，小华说：\"每人只吃一种水果，我不吃橘子。\"小明说：\"我既不吃苹果，也不吃橘子。\"大伟吃( )。",
+    "options": [
+      "A. 苹果",
+      "B. 香蕉",
+      "C. 橘子"
+    ],
+    "answer": "C",
+    "solution": "【分析】根据题意，先判断小明吃的是哪种水果，再从剩下的两种水果里判断小华吃的是什么，剩下的就是大伟吃的水果。\n【详解】小明不吃苹果，也不吃橘子，可知他吃的是香蕉;剩下的是苹果和橘子，小华不吃橘子，他吃的就是苹果，大伟吃的就是橘子。故答案为:C",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "22-23 二年级下·四川绵阳·期末"
+  },
+  {
+    "id": "208",
+    "unit": "第九单元 推理",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "在下图的方格中，每行每列都有\"我爱数学\"四个字，并且每个字在每行每列都只出现一次。\"。\"格子里应该填( ).\n\n| | | | |\n| ---- | ---- | ---- | ---- |\n| | | | |\n| | | | |\n| | | | |",
+    "options": [
+      "A. 数",
+      "B. 爱",
+      "C. 学"
+    ],
+    "answer": "A",
+    "solution": "【分析】根据题意，每行每列都有\"我爱数学\"四个字，并且每个字在每行每列都只出现一次，从出现汉字最多的地方也就是第二行第1格开始推算，可得出第二行第1格和第3格的汉字，进而得出\"。\"处的汉字。\n【详解】第二行第1格所在的行，列出现了学，爱，数，可知第二行第1格是我，第3格是学;此时\"。\"所在的行列出现了我，爱，学，可知\"。\"为数。\"。\"格子里应该填数。故答案为:A",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "23-24二年级下·湖北黄石·期末"
+  },
+  {
+    "id": "209",
+    "unit": "第九单元 推理",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "2020年春，湖北省小学生都是进行线上学习的，王亮家有三个孩子，买了三部手机。第一部不是最贵的，第二部是最便宜的。三部手机价格分别为1300元,1680元,1270元。第三部手机价格是( )。",
+    "options": [
+      "A. 1300元",
+      "B. 1680元",
+      "C. 1270元"
+    ],
+    "answer": "B",
+    "solution": "【分析】根据题意可知，三部手机的价格分别是1300元,1680元,1270元，已知第一部手机不是最贵的，可以排除1680元，第二部手机是最便宜的，那么第二部手机的价格是1270元，那么第一部手机的价格是1300元。进而可知第三部手机的价格是1680元，即可得出答案。\n【详解】A. 1300元应该是第一部手机的价格，错误;B. 1680元应该是第三部手机的价格，正确;C. 1270元应该是第二部手机的价格，错误。故答案为:B",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "23-24 二年级下·甘肃平凉·期末"
+  },
+  {
+    "id": "210",
+    "unit": "第九单元 推理",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "他们三个人分别有17张,21张和20张画片，东东有( )张画片。\n![](images/ed92d859ba4844b78521b5dc8c587fc0d37e46db97dfd258d8b583c6c1c3fcd0.jpg)",
+    "options": [
+      "A. 17",
+      "B. 21",
+      "C. 20"
+    ],
+    "answer": "A",
+    "solution": "【分析】根据题意，先比较他们画片的数量,21张>20张>17张。小梅的画片数量是已知的，还剩下20张和17张,17张是数量最少的，小亮说他的不是最少的，则东东的就是最少的，由此解答。\n【详解】由分析可知，东东的画片数量最少，有17张画片。故答案为:A",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "23-24 二年级下·山东济宁·期末"
+  },
+  {
+    "id": "211",
+    "unit": "第九单元 推理",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "小红，小芳和小明三个人拍球，分别拍了70下,82下,68下。小红说：\"我拍的不是最少的。\"小明说：\"我拍了82下。\"小芳拍了( )下。",
+    "options": [
+      "A. 70",
+      "B. 82",
+      "C. 68",
+      "D. 无法判断"
+    ],
+    "answer": "C",
+    "solution": "【分析】根据题意，他们拍的数量从多到少为82>70>68，小明拍了82下，小红拍的可能是70下，也可能是68下，而小红说她拍的不是最少的，可知小红拍了70下，剩下的68下就是小芳拍的数量。\n【详解】由分析可知：小芳拍了68下。故答案为:C",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "22-23 二年级下·江西吉安·期末"
+  },
+  {
+    "id": "212",
+    "unit": "第九单元 推理",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "警察抓住了4个犯罪嫌疑人，其中的一个人是主谋。甲说：\"丁是主谋。\"乙说：\"我不是主谋。\"丙说：\"甲是主谋。\"丁说：\"我不是主谋。\"已知他们4个人中，只有一个人说了真话，主谋是( )。",
+    "options": [
+      "A. 甲",
+      "B. 乙",
+      "C. 丙",
+      "D. 丁"
+    ],
+    "answer": "B",
+    "solution": "【分析】假设甲是主谋：甲说：\"丁是主谋\"，则甲说的是假话;乙说：\"我不是主谋\"，是真话;丙说：\"甲是主谋\"，是真话;丁说：\"我不是主谋\"，是真话;此时三人说了真话，不符合只有一人说真话的条件。假设乙是主谋：甲说：\"丁是主谋\"，则甲说的是假话;乙说：\"我不是主谋\"，是假话;丙说：\"甲是主谋\"，是假话;丁说：\"我不是主谋\"，是真话，此时只有一人说真话，符合只有一人说真话的条件;假设丙是主谋：甲说：\"丁是主谋\"，则甲说的是假话;乙说：\"我不是主谋\"，是真话;丙说：\"甲是主谋\"，是假话;丁说：\"我不是主谋\"，是真话;此时有二人说真话，不符合只有一人说真话的条件;假设丁是主谋：甲说：\"丁是主谋\"，则甲说的是真话;乙说：\"我不是主谋\"，是真话;丙说：\"甲是主谋\"，是假话;丁说：\"我不是主谋\"，是假话，此时有二人说真话，不符合只有一人说真话的条件;据此解答。\n【详解】根据分析可知，主谋是乙。故答案为:B",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "23-24 六年级下·河南安阳·期末"
+  },
+  {
+    "id": "213",
+    "unit": "第九单元 推理",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "六年级有3个班，每个班有2个中队长，开中队长会时，每次每班只派一名中队长参加。第一次到会的有①,②,③;第二次到会的有②,④,⑤;第三次到会的有①,⑤,⑥。那么和①同班的是( )。",
+    "options": [
+      "A. ③",
+      "B. ④",
+      "C. ⑤",
+      "D. ⑥"
+    ],
+    "answer": "B",
+    "solution": "【分析】从第一次到会的情况来看,①不和②③同班,①只能和④⑤⑥同班;从第三次到会情况来看,①不和⑤⑥同班,①只能和④同班，据此解答即可。\n【详解】根据分析可知，和①同班的是④。故答案为:B",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "23-24 六年级下·湖南常德·期末"
+  },
+  {
+    "id": "214",
+    "unit": "第九单元 推理",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "如图，每行，每列都有〇,□,△三种图形并且每行，每列只出现一次,A应该是( ).\n![](images/58cbb0aaf2812f6329d7be50c34287908d37ff35f79291ee922f538381b82f03.jpg)",
+    "options": [
+      "A. 〇",
+      "B. □",
+      "C. △"
+    ],
+    "answer": "A",
+    "solution": "【分析】根据每行，每列都有〇,□,△三种图形并且每行，每列只出现一次;A所在的第一列和第三列已有□,△,故A是〇。\n【详解】由题意分析得：如图，每行，每列都有〇,□,△三种图形并且每行，每列只出现一次,A应该是〇。故答案为:A",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "23-24 二年级下·甘肃天水·期末"
+  },
+  {
+    "id": "215",
+    "unit": "第九单元 推理",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "有甲，乙，丙三个人，一个是语文老师，一个是数学老师，一个是体育老师。甲乙经常和体育老师学打乒乓球，乙带学生去找数学老师辅导数学。语文老师是( )。",
+    "options": [
+      "A. 甲",
+      "B. 乙",
+      "C. 丙",
+      "D. 甲乙丙都有可能"
+    ],
+    "answer": "B",
+    "solution": "【分析】根据\"甲乙经常和体育老师学打乒乓球\"可以判断：甲，乙是语文老师或者数学老师，再根据\"乙带学生去找数学老师辅导数学\"可以判断：乙不是数学老师，所以，乙是语文老师，甲是数学老师，丙是体育老师。据此解答。\n【详解】由题意分析得：语文老师是乙。故答案为:B",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "23-24 二年级下·浙江宁波·期末"
+  },
+  {
+    "id": "216",
+    "unit": "第九单元 推理",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "小兰，小华，小军三个小朋友赛跑，小华跑得不是最快的，但比小兰快。( )跑得最快。",
+    "options": [
+      "A. 小兰",
+      "B. 小华",
+      "C. 小军"
+    ],
+    "answer": "C",
+    "solution": "【分析】小兰，小华，小军三个小朋友赛跑，小华跑得不是最快的，那就是跑第二的或跑最慢的，但小华比小兰快，那说明小华跑在第二的位置;而小兰比小华慢，则说明小兰跑得是最慢的，小军跑得是最快的;据此解决.\n【详解】由题意分析得：小军跑得最快。故答案为:C",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "23-24二年级下·海南省直辖县级单位·期末"
+  },
+  {
+    "id": "217",
+    "unit": "第九单元 推理",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "妈妈要过生日了，哥哥，姐姐和东东分别用自己的压岁钱为妈妈买了个礼物。哥哥说：\"我买的不是最贵的.\"姐姐说：\"我买的礼物花钱最少.\"下面分别是三个人买礼物的钱数，东东买礼物花了( )元。",
+    "options": [
+      "A. 389",
+      "B. 125",
+      "C. 241"
+    ],
+    "answer": "A",
+    "solution": "【分析】根据题意，先比较三人买礼物钱数的大小。比较时，都是三位数，百位大的数就大;百位相同比较十位，十位大的数就大;十位相同比较个位，个位大的数就大;姐姐花的钱最少，也就是最小的数;哥哥买的不是最贵的，则东东买的就是最贵的，也就是钱数最多的。\n【详解】389>241>125。A. 389是最多的，也就是最贵的，是东东花的钱;B. 125是最少的，是姐姐花的钱;C. 241不是最多的，也不是最少的，是哥哥花的钱。东东买礼物花了389元。故答案为:A",
+    "knowledge_points": [
+      "推理问题",
+      "1000以内数的比大小"
+    ],
+    "source": "23-24 二年级下·青海果洛·期末"
+  },
+  {
+    "id": "218",
+    "unit": "第九单元 推理",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "实验小学举行书法比赛，王聪，李明，张亮取得了前三名。已知王聪不是第一名，张亮不是第一名也不是最后一名,( )是第一名。",
+    "options": [
+      "A. 王聪",
+      "B. 李明",
+      "C. 张亮"
+    ],
+    "answer": "B",
+    "solution": "【分析】先确定张亮的名次，然后根据王聪不是第一名确定王聪的名次，再确定李明的名次即可。\n【详解】张亮不是第一名也不是最后一名，张亮是第二名;王聪不是第一名，则王聪是第三名，所以李明是第一名。故答案为:B",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "23-24 二年级下·江西宜春·期末"
+  },
+  {
+    "id": "219",
+    "unit": "第九单元 推理",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "笑笑，壮壮，园园三人折千纸鹤，分别折了18只,15只,11只。笑笑不是最少的，园园折了15只。壮壮折了( )只千纸鹤。",
+    "options": [
+      "A. 18",
+      "B. 15",
+      "C. 11"
+    ],
+    "answer": "C",
+    "solution": "【分析】18>15>11。园园折了15只，还有18只和11只，笑笑不是最少的，也就是折了18只，最少的11只是壮壮折的.\n【详解】由分析可知，壮壮折了11只。故答案为:C",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "23-24 二年级下·江西南昌·期末"
+  },
+  {
+    "id": "220",
+    "unit": "第九单元 推理",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "小红，小芳，小兰三人做小红花，小红说：\"我做得不是最多的\"。小芳说：\"我比小红做得少.\"( )做得最多。",
+    "options": [
+      "A. 小红",
+      "B. 小芳",
+      "C. 小兰"
+    ],
+    "answer": "C",
+    "solution": "【分析】可以通过列表法来解决此题。小红，小芳，小兰三人做小红花，小红做的不是最多的，那就是第二多的或是最少的;若小红是最少的，那\"小芳比小红做得少\"就不成立了，所以小红做的是第二多的，小芳是最少的，小兰是最多的.\n【详解】由题意分析得：小兰做得最多。故答案为:C",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "23-24 二年级下·山东菏泽·期末"
+  },
+  {
+    "id": "221",
+    "unit": "第九单元 推理",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "桌子上有3盘苹果，小云说：\"第一盘比第二盘多3个.\"小玉说：第三盘比第二盘少5个。则第( )盘苹果最少。",
+    "options": [
+      "A. 一",
+      "B. 二",
+      "C. 三"
+    ],
+    "answer": "C",
+    "solution": "【分析】桌子上有3盘苹果，第三盘比第二盘少5个，也就是第二盘比第三盘多5个;第一盘又比第二盘多3个;所以第一盘苹果最多，第二盘排第二，第三盘苹果最少.\n【详解】由题意分析得：则第三盘苹果最少。故答案为:C",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "23-24二年级下·山西忻州·期末"
+  },
+  {
+    "id": "222",
+    "unit": "第九单元 推理",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "B应该是( ).\n![](images/4183d32253cc4e9106aed071b8d57921.png)",
+    "options": [
+      "A. 1",
+      "B. 2",
+      "C. 3",
+      "D. 4"
+    ],
+    "answer": "C",
+    "solution": "【分析】根据每个数在每行，每列中都只出现一次，先从每行，每列出现数字较多的地方入手，利用排除法尝试填空。\n【详解】A所在的行，列已有2,3,4，所以A是1;所以B左边的格子是4,B所在的行，列已有1,2,4，则B=3。故答案为:C",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "23-24 二年级下·湖北恩施·期末"
+  },
+  {
+    "id": "223",
+    "unit": "第九单元 推理",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "下图的方格中，每行每列都有1~4这四个数，并且每行，每列都只出现一次,B应该是( ).\n\n| 3 | 2 | |\n| ---- | ---- | ---- |\n| A | B | 2 |\n| | 3 | |\n| 1 | | |",
+    "options": [
+      "A. 1",
+      "B. 2",
+      "C. 3",
+      "D. 4"
+    ],
+    "answer": "A",
+    "solution": "【分析】先根据A所在的行有2,A所在的列有1和3，推出A是4，再根据B同一行，同一列的数字，然后逐步推测出B即可。\n【详解】A所在的行有2,A所在的列有1和3，推出A是4,B所在的行有2和4,B所在的列有3，那么B=1。故答案为:A",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "23-24二年级下·浙江宁波·期末"
+  },
+  {
+    "id": "224",
+    "unit": "第九单元 推理",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "小亮，小林和小刚进行跑步比赛。小亮说：\"我不是最后一名.\"小林说：\"我不是第一名，也不是最后一名.\"那么,( )是第一名。",
+    "options": [
+      "A. 小亮",
+      "B. 小林",
+      "C. 小刚"
+    ],
+    "answer": "A",
+    "solution": "【分析】根据小林说的话判断小林的名次，结合小林的名次，再根据小亮说的话判断小亮的名次，这样就能确定三人的名次.\n【详解】根据小林说的话可知小林是第二名，小亮不是最后一名，那么小亮一定是第一名。故答案为:A",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "23-24 二年级下·浙江·期末"
+  },
+  {
+    "id": "225",
+    "unit": "第九单元 推理",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "王晨，李磊，程翔三人比身高。王晨说：\"我比程翔高.\"程翔说：\"我比李磊矮.\"李磊说：\"王晨比我矮.\"( )最高,( )最矮。",
+    "options": [
+      "A. 王晨;程翔",
+      "B. 李磊;程翔",
+      "C. 程翔;王晨"
+    ],
+    "answer": "B",
+    "solution": "【分析】由王晨比程翔高，程翔比李磊矮，可知王晨，李磊都比程翔高，三人当中程翔最矮。又因为王晨比李磊矮，可知三人当中李磊最高.\n【详解】由分析可知：三人当中李磊最高，程翔最矮。故答案为:B",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "23-24 二年级下·河北保定·期末"
+  },
+  {
+    "id": "226",
+    "unit": "第九单元 推理",
+    "question_type": "选择题",
+    "difficulty": 0.85,
+    "question": "小云，小明，小亮踢毽子，分别踢了25下,36下,30下，小明踢得最多，小亮踢得不是最少的。小云踢了( )下。",
+    "options": [
+      "A. 25",
+      "B. 36",
+      "C. 30"
+    ],
+    "answer": "A",
+    "solution": "【分析】根据整数比较大小可知:36>30>25，因为小明踢得最多，所以小明踢了36下，又因为小亮不是踢得最少，所以小云踢得最少，小云踢了25下，小亮踢了30下.\n【详解】据分析可知：小云踢得最少，踢了25下。故答案为:A",
+    "knowledge_points": [
+      "100以内数的比大小",
+      "推理问题"
+    ],
+    "source": "23-24 二年级下·山东临沂·期末"
+  },
+  {
+    "id": "227",
+    "unit": "第九单元 推理",
+    "question_type": "选择题",
+    "difficulty": 0.65,
+    "question": "数学活动小组编写了一个程序，输入一个数，经过程序处理后，会输出另外一个数。下表是张明四次输入的数和输出的数:\n![](images/image-37.png)\n根据表中的信息，请你推测数学活动小组编写的程序是( )。",
+    "options": [
+      "A. 输入的数减去8得到输出的数",
+      "B. 输入的数加上8得到输出的数",
+      "C. 输入的数除以5得到输出的数"
+    ],
+    "answer": "C",
+    "solution": "【分析】第一次输入10，输出的是2,10÷5=2。第二次输入15，输出的是3,15÷5=3。第三次输入25，输出的是5,25÷5=5。第四次输入40，输出的是8,40÷5=8。都是输入的数除以5可以得到输出的数。\n【详解】数学活动小组编写的程序是：输入的数除以5得到输出的数。故答案为:C",
+    "knowledge_points": [
+      "用7~9的乘法口诀求商",
+      "用2~5的乘法口诀求商",
+      "数表中的规律"
+    ],
+    "source": "23-24 三年级下·北京东城·期末"
+  },
+  {
+    "id": "228",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "如图，每行，每列都有2,3,4,5这四个数，并且每个数在每行，每列都只出现一次。A是( ),B是( ).\n\n| | | 4 |\n| ---- | ---- | ---- |\n| 3 | | 5 |\n| 2 | A | 5 |\n| | | B |",
+    "options": [],
+    "answer": "4;3",
+    "solution": "【分析】A所在的第四行和第一列已有2,3,5，故A是4;第四列第3个数所在的第三行和第四列已有2,4,5，故第四列第3个数是3，第四列第4个数是2;B所在的第四行已有2,4,5，故B是3;据此解答。\n【详解】由题意分析得：每行，每列都有2,3,4,5这四个数，并且每个数在每行，每列都只出现一次。A是4,B是3。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "23-24二年级下·浙江台州·期末"
+  },
+  {
+    "id": "229",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "小贝，小丽，小军三人进行跳绳比赛。小贝说：\"我不是最后一名\"。小军说：\"我也不是最后一名，但是小贝成绩比我好\"。那么第一名是( ),最后一名是( )。",
+    "options": [],
+    "answer": "小贝;小丽",
+    "solution": "【分析】根据题意，小贝，小丽，小军三人进行跳绳比赛。小贝说：\"我不是最后一名\"，那么小贝是第一名或第二名;小军说：\"我也不是最后一名，但是小贝成绩比我好\"，那么小军是第二名，小贝是第一名，剩下小丽是最后一名;据此解答即可。\n【详解】由分析可得，第一名是小贝，最后一名是小丽。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "23-24 二年级下·福建福州·期末"
+  },
+  {
+    "id": "230",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "推理。\n![](images/image-39.png)\n在上面的方格中，每行，每列都有1-4这四个数，并且每个数在每行，每列都只出现一次，那么A是( ),B是( ),C是( ),D是( )。",
+    "options": [],
+    "answer": "1;3;4;4",
+    "solution": "【分析】A所在的第二行和第二列已有2,3,4，故A是1;C所在的第二列已有1,3，故C是2或4，而第二列第3个数所在的第三行已有4，故第二列第3个数是2，而C是4;第一行第1个数所在的行和列已有2,3,4，故第一行第1个数是1;第三列第1个数所在的行和列已有1,3,4，故第三列第1个数是2;故D是4;B所在的第三行和第三列已有1,2,4，故B是3;据此解答。\n【详解】由题意分析得:A是1,B是3,C是4,D是4。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "23-24 二年级下·河北邯郸·期末"
+  },
+  {
+    "id": "231",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "小红，小军，小刚三位小朋友正在比较年龄的大小，小红说：\"我不是最小的\"。小军说：\"我也不是最小的，但比小红大\"。年龄最大的是( )。",
+    "options": [],
+    "answer": "小军",
+    "solution": "【分析】根据小红和小军说的话，先推断出最小的是谁，再根据小军比小红大，可推断出年龄最大的是谁.\n【详解】小红和小军都不是最小的，则小刚是最小的;小军又比小红大，也就是小红是中间的，年龄最大的是小军。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "23-24 二年级下·湖南衡阳·期末"
+  },
+  {
+    "id": "232",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "小红，小明，小丽三名同学跳绳，分别跳了100下,87下,79下，小红说：\"我跳的不是最多的\"，小丽说：\"我跳了79下\"，那么小红跳了( )下，小明跳了( )下。",
+    "options": [],
+    "answer": "87;100",
+    "solution": "【分析】小红，小明，小丽三名同学跳绳，分别跳了100下,87下,79下，且100下>87下>79下;其中小丽跳了79下;小红跳的不是最多的，所以小明跳的是最多的，也就是小明跳了100下，剩下的小红跳了87下;据此解答。\n【详解】由题意分析得：小红跳了87下，小明跳了100下。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "23-24 二年级下·山东临沂·期末"
+  },
+  {
+    "id": "233",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "小亮，小兵，小马三位同学数学成绩，分别是96分,100分,89分。小马说：\"我的成绩是最好的.\"小兵说：\"我的成绩在三人中不是最差的.\"他们三人的排名是:( )第一,( )第二,( )第三。",
+    "options": [],
+    "answer": "小马;小兵;小亮",
+    "solution": "【分析】根据题意可知：小马说他的成绩是最好的，则小马会是第一名;小兵说我的成绩在三人中不是最差的，则小兵是第二，小亮是第三。\n【详解】他们三人的排名是:(小马)第一,(小兵)第二,(小亮)第三。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "23-24 二年级下·湖北荆门·期末"
+  },
+  {
+    "id": "234",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "在下边的方格中，每行，每列都有1-4这四个数，并且每个数在每行，每列都只出现一次.\n\n| 3 | 2 | | 1 |\n| ---- | ---- | ---- | ---- |\n| A | | B | 2 |\n| | | 3 | |\n| 1 | | | |\n\nA是( ),B是( )。",
+    "options": [],
+    "answer": "4;1",
+    "solution": "【分析】根据题意，每行，每列都有1-4这四个数，并且每个数在每行，每列都只出现一次，则从出现数字较多的地方开始推算。也就是根据A所在的行，列出现的数字可推算出A所表示的数字，进而推算出B所表示的数字.\n【详解】A所在的行，列出现了1,2和3，则A只能是4;此时B所在的行，列出现了2,3和4，则B只能是1。A是4,B是1。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "23-24二年级下·山东济宁·期末"
+  },
+  {
+    "id": "235",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "在六一跳蚤市场上，小东，小安，小月三人分别买了娃娃，铅笔和球，小东买的不是娃娃，小安买的不是娃娃也不是球。小东买了( ),小安买了( ),小月买了( )。",
+    "options": [],
+    "answer": "球;铅笔;娃娃",
+    "solution": "【分析】由题意可知小东，小安，小月三人分别买了娃娃，铅笔和球。因为小安买的不是娃娃也不是球，所以小安买的是铅笔;因为小东买的不是娃娃，那么小东买的可能是球或铅笔，而铅笔是小安买的，所以小东买的只能是球;因为球和铅笔分别被小东和小安买了，所以小月买的是娃娃。\n【详解】由分析可知：小东买了球，小安买了铅笔，小月买了娃娃。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "23-24 二年级下·山东济南·期末"
+  },
+  {
+    "id": "236",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "小亮，小明，小丽三人中，一个属牛，一个属虎，一个属兔。小亮说他不属牛，小明说他的属相不吃草，小丽说她不属兔。小亮属( ),小明属( ),小丽属( )。",
+    "options": [],
+    "answer": "兔;虎;牛",
+    "solution": "【分析】据题意可知，小明说他的属相不吃草，三个属相中只有虎不吃草，所以小明属虎，剩下牛和兔，小亮说他不属牛，那么小亮属兔，所以小丽属牛，据此即可得出答案。\n【详解】小亮属兔，小明属虎，小丽属牛。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "23-24 二年级下·陕西宝鸡·期末"
+  },
+  {
+    "id": "237",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "在下边的方格中，每行，每列都有1~4这四个数，并且每个数在每行，每列都只出现一次。那么B是( ).\n![](images/image-41.png)",
+    "options": [],
+    "answer": "3",
+    "solution": "【分析】根据每个数在每行，每列中都只出现一次，先从每行，每列出现数字较多的地方入手，利用排除法尝试填空。\n【详解】A所在的行，列已有2,3,4，所以A是1;B所在的行，列已有1,2,4，所以B是3。因此B是3。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "23-24 二年级下·广东江门·期末"
+  },
+  {
+    "id": "238",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "A,B,C三人分别是医生，老师，解放军,A不是老师，他和C正在听解放军讲军事演习情况。那么,A是( ),B是( ),C是( )。",
+    "options": [],
+    "answer": "医生;解放军;老师",
+    "solution": "【分析】根据A和C在听解放军讲军事演习情况，可知道谁是解放军，再根据A不是老师即可判断另外两人的职业。\n【详解】A和C在听解放军讲军事演习情况，说明他俩都不是解放军，可得出B是解放军;A不是老师，那就是医生，剩下的老师是C。A是医生,B是解放军,C是老师。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "23-24 二年级下·广东江门·期末"
+  },
+  {
+    "id": "239",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "猜年龄。\n![](images/ac06aefc976127b4a216ecbacfa51da6.png)\n年龄最小的是( ),年龄最大的是( )。",
+    "options": [],
+    "answer": "小倩;小玉",
+    "solution": "【分析】不知道小倩的年龄，但是小玉说她比小冬大，小冬说他不是最小的，可以判断小玉是最大的，而小冬不是最小的，只有小倩了，分析即可得出答案。\n【详解】年龄最小的是小倩，年龄最大的是小玉。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "23-24 二年级下·湖北武汉·期末"
+  },
+  {
+    "id": "240",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "在下图的方格中，每行，每列都有1-4这四个数，并且每个数在每行，每列都只出现一次,A是( ),B是( ).\n\n| 2 | | | 3 |\n| ---- | ---- | ---- | ---- |\n| | | | |\n| B | 4 | | A |\n| | | | 2 |",
+    "options": [],
+    "answer": "1;3",
+    "solution": "【分析】由题意可知：每行，每列都有1-4这四个数，并且每个数在每行，每列都只出现一次。A所在的列已经有2和3了，所以A可能是1或4，但是A所在的行已经有4了，所以A只能是1;B所在的行已经有了4和1，所以B可能是2或3，但是B所在的列已经有2了，所以B只能是3。\n【详解】由分析可知:A是1,B是3。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "23-24 二年级下·山东济南·期末"
+  },
+  {
+    "id": "241",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "思考：请用数学的思维推理。\n○+○+△+△=50,○-△=5\n○=( ),△=( )",
+    "options": [],
+    "answer": "15;10",
+    "solution": "【分析】由题意可知，两个圆加两个三角形等于50，那么一个圆加一个三角形等于25;又已知，一个圆减一个三角形等于5,25+5=30;所以两个圆等于30，则，一个圆等于15;25-15=10，即三角形等于10;据此解答即可.\n【详解】50=25+25;25+5=30;30=15+15;25-15=10;所以○=15,△=10。",
+    "knowledge_points": [
+      "两位数与两位数的进位加法",
+      "一位数与两位数的进位加法",
+      "两位数与两位数的不退位减法",
+      "推理问题"
+    ],
+    "source": "23-24 二年级下·山东菏泽·期末"
+  },
+  {
+    "id": "242",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "小丽，小红和小东三个人测量身高，小丽比小红矮，小丽比小东高，他们三人( )最高,( )最矮。",
+    "options": [],
+    "answer": "小红;小东",
+    "solution": "【分析】根据题意，小丽比小红矮，说明小红的身高>小丽的身高，小丽比小东高，小丽的身高>小东的身高，小红的身高>小丽的身高>小东的身高，据此解答.\n【详解】根据分析：他们三人小红最高，小东最矮。",
+    "knowledge_points": [
+      "比高矮",
+      "推理问题"
+    ],
+    "source": "23-24二年级下·山东临沂·期末"
+  },
+  {
+    "id": "243",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "在如图的方格中，每行，每列都有1~4这四个数，并且每个数在每行，每列都只出现一次。B是( ),C是( ).\n![](images/image-43.png)",
+    "options": [],
+    "answer": "1;3",
+    "solution": "【分析】先从A入手,A所在的行和列已经出现了4,1,3，确定A是2,A所在的列最后一个只能是4;B所在的行和列已有4,3,2，所以B是1;再结合行列排除可得C只能是3.\n【详解】所以B是1,C是3。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "23-24 二年级下·湖南长沙·期末"
+  },
+  {
+    "id": "244",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "在下图的方格中，每行，每列都是1~4这四个数，且每个数在每行，每列都只出现一次。\n![](images/image-44.png)\nA是( ),B是( )。",
+    "options": [],
+    "answer": "4;1",
+    "solution": "【分析】根据题意，每行，每列都是1~4这四个数，且每个数在每行，每列都只出现一次。从出现数字较多的地方开始解答。先通过A所在的行，列出现的数推断出A所表示的数，进而确定B所代表的数.\n【详解】A所在的行，列出现了1,2，和3，则A是4;此时B所在的行，列出现了3和4，则B可能是1或2。若B为2，则B右侧的数为1，与第4列的第2个数相同，不符合题意;则B只能为1。A是4,B是1。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "23-24二年级下·湖南湘西·期末"
+  },
+  {
+    "id": "245",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "小思，小维，小敏，小捷一起排队上车，小维站在小思和小捷的中间，小敏站在最后，小思不是第一个。那么他们的排队顺序从前到后是:( ),( ),( ),( )。",
+    "options": [],
+    "answer": "小捷;小维;小思;小敏",
+    "solution": "【分析】根据题意，将他们的顺序表示为第一，第二，第三和第四。小敏在最后也就是第四。小维在小思和小捷中间，则小维只能在第二，剩下第一和第三，又知小思不是第一个，则他就是第三个，第一个就是小捷.\n【详解】综上可知：他们的排队顺序从前到后是：小捷，小维，小思，小敏。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "23-24二年级下·广西柳州·期末"
+  },
+  {
+    "id": "246",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "小天，小方和小丽星期天去公园玩，她们都戴了一顶漂亮的太阳帽。太阳帽有三种颜色：红，黄，蓝。小天戴的不是红色，小方戴的不是红色，也不是黄色。那么小方戴的是( )色，小天戴的是( )色，小丽戴的是( )色。",
+    "options": [],
+    "answer": "蓝;黄;红",
+    "solution": "【分析】由题可知，小方戴的不是红色，也不是黄色，那么小方戴的一定是蓝色的帽子，再根据小天的表述推断即可.\n【详解】小方戴的是蓝色，小天戴的是黄色，小丽戴的是红色。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "23-24二年级下·四川凉山·期末"
+  },
+  {
+    "id": "247",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "白兔，灰兔和黑兔赛跑，白兔跑得不是最快的，但比灰兔快，它们三个中,( )跑得最快,( )跑得最慢。",
+    "options": [],
+    "answer": "黑兔;灰兔",
+    "solution": "【分析】根据题意，白兔跑得不是最快的，可能是在中间或最后。又知白兔比灰兔快，说明白兔在中间，灰兔在最后，最快的就是黑兔.\n【详解】由分析可知：黑兔跑得最快，灰兔跑得最慢。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "23-24 二年级下·广东汕头·期末"
+  },
+  {
+    "id": "248",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "有篮球，足球，排球各一个。聪聪，明明和亮亮三个人各拿一个。聪聪说：\"我拿的不是篮球，也不是足球。\"明明说：\"我拿的不是篮球。\"聪聪拿的是( ),明明拿的是( ),亮亮拿的是( )。",
+    "options": [],
+    "answer": "排球;足球;篮球",
+    "solution": "【分析】根据聪聪说的话先确定出他拿的是排球，再根据明明说的话确定明明拿的是什么球，剩下的就是亮亮拿的.\n【详解】聪聪拿的是排球，明明拿的是足球，亮亮拿的是篮球。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "23-24二年级下·河南南阳·期末"
+  },
+  {
+    "id": "249",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "三名同学跳绳，分别跳了69下,76下和84下，小芳说：\"我跳得最多。\"小林说：\"我跳得不是最少的。\"小红跳了( )下。",
+    "options": [],
+    "answer": "69",
+    "solution": "【分析】根据题意，他们跳得数量从多到少为84>76>69。小芳跳得最多也就是84下。小林跳得可能是76下，也可能是69下，而小林说他跳得不是最少的，可知跳得最少的是小红，由此解答.\n【详解】由分析可知，小红跳得最少，跳了69下。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "23-24 二年级下·湖北黄石·期末"
+  },
+  {
+    "id": "250",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "在下面的方格中，每行，每列都有1-4这四个数，并且每行每列都只出现一次。A是( ),B是( ).\n![](images/940db26aae5ed0de3d6c32669958db3a.png)",
+    "options": [],
+    "answer": "3;4",
+    "solution": "【分析】根据题意，这四个数字在每行每列都只出现一次。从出现数字较多的地方推算。先推算出A及A所在行空格的数，最后即可推算出B的数.\n【详解】A所在的行，列出现了1,2,4，则A只能是3，第一行第4格是2;此时B所在的行，列出现了1,2,3，则B只能是4。A是3,B是4。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "23-24 二年级下·山东济宁·期末"
+  },
+  {
+    "id": "251",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "在下边的方格中，每行，每列都有1-4这四个数，并且每个数在每行，每列都只出现一次。B应该是( ),A应该是( ).\n![](images/image-45.png)",
+    "options": [],
+    "answer": "3;1",
+    "solution": "【分析】因为1-4这四个数在每行，每列都只出现一次，所以A不可能是3,2,4,A只能是1。因为A=1，所以从这一列可以排除B等于1和4的可能，又因为B同一列已经出现2，所以B不可能是2，所以B只能是3，据此解答即可.\n【详解】A这一列已经出现3,2，同一行有4，所以A只能是1;B这一行已经出现了1,4，同一列出现了2，所以B只能是3。所以B=3,A=1。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "23-24 二年级下·贵州铜仁·期末"
+  },
+  {
+    "id": "252",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "在下面的方格中，每行，每列都有1-4这四个数字，并且每个数字在每行，每列都只出现一次。笑脸代表数字( ).\n![](images/image-47.png)",
+    "options": [],
+    "answer": "2",
+    "solution": "【分析】根据题意，每行，每列都有1-4这四个数字，并且每个数字在每行，每列都只出现一次。从出现数字最多的地方开始解答。可先推算出空格中所表示的数字，进而确定所在列空格中的数字，最后即可推算出笑脸代表的数字。\n【详解】由分析可知，第二行第1格所在的行，列出现了1,2,3，则这里是4，此时可知第二行第2格是1。笑脸所在的行，列出现了1,3,4，则笑脸是2。笑脸代表数字2。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "23-24二年级下·湖南常德·期末"
+  },
+  {
+    "id": "253",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "甲，乙，丙三人中，一人是教师，一人是警察，一人是司机。甲比老师大，丙与司机不同岁，司机比乙小。三人中,( )是警察,( )是老师。",
+    "options": [],
+    "answer": "乙;丙",
+    "solution": "【分析】丙与司机不同岁，则丙不是司机;司机比乙小，则乙不是司机，所以甲是司机;又因为司机比老师大，司机比乙小，说明乙是警察，所以丙是老师.\n【详解】由分析得：乙是警察，丙是老师。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "23-24 六年级下·湖北十堰·期末"
+  },
+  {
+    "id": "254",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "八戒买了一堆桃子，第一天吃了全部的一半少6个，第二天吃了余下的一半多6个，最后还剩6个桃子。这堆桃子原来有( )个。",
+    "options": [],
+    "answer": "36",
+    "solution": "【分析】第二天没吃之前有(6+6)×2=24(个)桃子，第一天没吃之前有(24-6)×2个桃子，据此求解即可.\n【详解】(6+6)×2=12×2=24(个);(24-6)×2=18×2=36(个)。所以这堆桃子原来有36个。",
+    "knowledge_points": [
+      "倒推问题",
+      "带有小括号的混合运算"
+    ],
+    "source": "23-24 二年级下·四川内江·期末"
+  },
+  {
+    "id": "255",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "在下面的方格中，每行，每列都有1~4这四个数字，并且每个数在每行，每列中都只出现一次，那么B是( ),A是( ).\n![](images/image-48.png)",
+    "options": [],
+    "answer": "3;1",
+    "solution": "【分析】根据每个数在每行，每列中都只出现一次，从出现数字最多的地方进行解答。先推算出A的数，进而推算出A所在的列空格中的数，最后即可推算出B的数.\n【详解】A所在的行，列出现了2,3,4，则A是1，第二行第2格就是4;此时B所在的行，列出现了1,2,4，则B是3。B是3,A是1。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "23-24 二年级下·浙江台州·期末"
+  },
+  {
+    "id": "256",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "四个小孩在校园内踢球。\"砰\"的一声，不知是谁踢的球把课堂窗户的玻璃打破了，王老师跑出来一看，问：\"是谁打破了玻璃?\"小张说：\"是小强打破的。\"小强说：\"是小胖打破的。\"小明说：\"我没有打破窗户的玻璃。\"小胖说：\"王老师，小强在说谎，不要相信他。\"这四个小孩只有一个说了真话。请判断说真话的是( );是( )打破窗户的玻璃。",
+    "options": [],
+    "answer": "小胖;小明",
+    "solution": "【分析】利用假设法，先后假设肇事者是小张，小强，小明和小胖，再判断各个情况下说真话的有几人，找出说真话的只有一人的情况，即可解题.\n【详解】(1)若小张是肇事者，由条件可知，小明，小胖都说了真话，这与其中只有一个孩子说了真话矛盾;(2)若小强是肇事者，由条件可知，小张，小明，小胖都说了真话，这与其中只有一个孩子说了真话矛盾;(3)若小明是肇事者，由条件可知，小胖说了真话，小明是肇事者;(4)若小胖是肇事者，由条件可知小强，小明都说了真话，也与题意矛盾;所以，小胖说了真话，小明是肇事者;因此，说真话的是小胖，是小明打破了玻璃。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "23-24 五年级上·全国·课后作业"
+  },
+  {
+    "id": "257",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "乐乐，小小，妙妙的头上各戴一顶帽子，自己看不见自己头上帽子的颜色。三顶帽子分别是两红，一黑。当乐乐看到妙妙头上帽子的颜色后，她就知道了每个人头上帽子的颜色，聪明的小朋友，你知道吗。\n![](images/image-49.png)",
+    "options": [],
+    "answer": "红色;红色;黑色",
+    "solution": "【分析】有三顶帽子，分别是两红，一黑;当乐乐看到妙妙的帽子颜色后，就知道自己头上的帽子，说明乐乐看到妙妙的帽子颜色是黑色的，而乐乐头上的帽子是红色的，同时小小头上的帽子颜色也是红色的;据此解决.\n【详解】由题意分析得：乐乐是红色，小小是红色，妙妙是黑色。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "23-24二年级上·全国·课后作业"
+  },
+  {
+    "id": "258",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "明明观看了乒乓球比赛，她说：\"A,B,C运动员是前三名,A运动员不是第三名,C运动员也不是第三名，但是A运动员的成绩要比C运动员的好。\"( )是第一名。",
+    "options": [],
+    "answer": "A运动员",
+    "solution": "【分析】A,B,C运动员是前三名,A运动员不是第三名,C运动员也不是第三名，那B运动员就是第三名，还剩下第一名和第二名;且A运动员的成绩要比C运动员好，所以A运动员是第一名,C运动员是第二名;据此解决.\n【详解】由题意分析得:A运动员是第一名。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "23-24 二年级下·四川南充·期末"
+  },
+  {
+    "id": "259",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "在学校运动会上,1号,2号,3号,4号运动员取得了800米赛跑的前4名。1号说：\"3号第一个冲过终点。\"另一名运动员说：\"2号不是第4名。\"裁判说：\"他们的号码与他们的名次都不相同。\"1号是第( )名,4号是第( )名。",
+    "options": [],
+    "answer": "4;2",
+    "solution": "【分析】由于3号第一个冲过终点，那么3号是第1名。2号不是第4名，并且2号的号码和他的名次不相同，那么2号是第3名。再根据裁判所说，那么1号是第4名,4号是第2名.\n【详解】1号是第4名,4号是第2名。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "2025·云南昆明·小升初真题"
+  },
+  {
+    "id": "260",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "小红，小亮，小强三人跳绳，分别跳了12下,28下,19下，小亮说：\"我跳的不是最少的。\"小红说：\"我比小亮跳得多。\"那么，小红跳了( )下。",
+    "options": [],
+    "answer": "28",
+    "solution": "【分析】先比较三个人跳的数量，小亮跳的不是最少，也就可能是最多的或中间数量的;又因为小红比小亮跳得多，所以小红跳得最多。由此解答.\n【详解】28>19>12。小红跳得最多，小红跳了28下。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "23-24 二年级下·甘肃天水·期末"
+  },
+  {
+    "id": "261",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "有音乐，美术和数学三本书，小红，小丽和小刚各拿一本。小红拿的是美术，小丽拿的不是数学书，请猜一猜小丽拿的是( )书，小刚拿的是( )书。",
+    "options": [],
+    "answer": "音乐;数学",
+    "solution": "【分析】有音乐，美术和数学三本书，小红拿的是美术，说明还剩下音乐和数学没拿;而小丽拿的不是数学书，那她拿的是音乐书，剩下的小刚拿数学书;据此解决.\n【详解】由题意分析得：小丽拿的是音乐书，小刚拿的是数学书。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "23-24二年级下·广西柳州·期末"
+  },
+  {
+    "id": "262",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "果果，球球和美美三人手中拿着红，蓝，黄三种不同颜色的珠子。美美拿的是红珠子，果果拿的既不是蓝珠子也不是红珠子，球球拿的是( )珠子。",
+    "options": [],
+    "answer": "蓝",
+    "solution": "【分析】美美拿的是红珠子，则还剩下蓝珠子和黄珠子;果果拿的既不是蓝珠子也不是红珠子，那她拿的是黄珠子，剩下球球拿蓝珠子;据此解决.\n【详解】由题意分析得：球球拿的是蓝珠子。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "23-24 二年级下·浙江杭州·期末"
+  },
+  {
+    "id": "263",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "一分钟跳绳比赛。三位同学分别跳了187下,163下,129下。丁丁跳了( )下。\n![](images/f0398bf9439dfe0b2398437ff68fe2ff823b845eb5e1d9daa3fd3ed934d50dc5.jpg)",
+    "options": [],
+    "answer": "129",
+    "solution": "【分析】比较他们跳的数量，最多的就是明明跳的;然后根据冬冬说的话可知丁丁跳的最少，找出最少的即可.\n【详解】187>163>129。明明跳的最多是187下，丁丁跳的最少，跳了129下。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "23-24 二年级下·浙江台州·期末"
+  },
+  {
+    "id": "264",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "在下边的方格中，每行，每列都有1~4这四个数,A应该是( ),B应该是( ).\n![](images/image-50.png)",
+    "options": [],
+    "answer": "1;3",
+    "solution": "【分析】A所在的列与行中有数字2,3,4，那么A一定是1;然后根据B所在的列与行中已有的数字确定B表示的数,B所在的列与行中有数字1,4,2，那么B一定是3.\n【详解】由分析可知,A应该是1,B应该是3。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "23-24 二年级下·浙江杭州·期末"
+  },
+  {
+    "id": "265",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "来自美国，英国，法国的三个外国人到石椅羌寨旅游，甲说：\"我不是美国人。\"乙说：\"我是法国人。\"所以，甲是( )国人，丙是( )国人。",
+    "options": [],
+    "answer": "英国;美国",
+    "solution": "【分析】乙是法国人，所以甲是美国人或者英国人，甲说自己不是美国人，所以甲是英国人，则丙是美国人。\n【详解】甲是英国人，丙是美国人。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "23-24 二年级下·四川绵阳·期末"
+  },
+  {
+    "id": "266",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "小亮，小明，小丽三人比高矮，小亮说\"我不是最高的。\"小丽说\"我既不是最高的，也不是最矮的。\"( )最高,( )最矮。",
+    "options": [],
+    "answer": "小明;小亮",
+    "solution": "【分析】小丽既不是最高的，也不是最矮的，那她的身高是排在第二的;小亮不是最高的，也不是排第二的，那就是最矮的;剩下的小明就是最高的;据此解决.\n【详解】由题意分析得：小明最高，小亮最矮。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "23-24 二年级下·山东济宁·期末"
+  },
+  {
+    "id": "267",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "学校举行数学知识竞赛，小东，小青，小红三人的数学成绩分别是95分,99分,93分。小东说:'我不是最高的，也不是最低的'。小青说:'我也不是最高的'。三人中，成绩最高的是( )。",
+    "options": [],
+    "answer": "小红",
+    "solution": "【分析】根据题意，小东分数不是最高的，也不是最低的，那就是中间的分数;还剩下最高的和最低的，小青分数不是最高的，那就是最低的;剩下最高的就是小红的分数.\n【详解】由分析可知，成绩最高的是小红。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "23-24 二年级下·贵州黔东南·期末"
+  },
+  {
+    "id": "268",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "在下边的方格中，每行，每列都有1~4这四个数，并且每个数在每行，每列都只出现一次。A是( ),B是( ).\n![](images/image-51.png)",
+    "options": [],
+    "answer": "3;2",
+    "solution": "【分析】A所在的第二行和第四列已有1,2,4，故,A是3;B所在的第四行和第四列已有1,3,4，故,B是2;据此解决.\n【详解】由题意分析得:A是3,B是2。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "23-24二年级下·海南省直辖县级单位·期末"
+  },
+  {
+    "id": "269",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "在下面的方格中，每行，每列都有A,B,C,D这四个字母，并且每个字母在每行每列都只出现一次。▲代表( ),●代表( ).\n![](images/image-52.png)",
+    "options": [],
+    "answer": "C;A",
+    "solution": "【分析】●所在的第二列和第四行已有字母:B,C,D,故,●代表A,且第二列第二个字母是D;▲所在的第三列和第二行已有字母:A,B,D,故,▲代表C;据此解决.\n【详解】由题意分析得:▲代表C,●代表A。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "23-24 二年级下·贵州六盘水·期末"
+  },
+  {
+    "id": "270",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "在下边的方格中，每行，每列都有1~4这四个数，并且每个数在每行，每列都只出现一次。那么A=( ),B=( ).\n![](images/image-53.png)",
+    "options": [],
+    "answer": "1;3",
+    "solution": "【分析】每行，每列都有1~4这四个数，并且每个数在每行，每列都只出现一次。第二列已出现3和4，第三行已出现2和3，所以A是1。因为A是1，所以第一行第二列是2，第三行第四列是4，所以B是3.\n【详解】由题意分析得:A=1,B=3。",
+    "knowledge_points": [
+      "推理问题",
+      "数表中的规律"
+    ],
+    "source": "23-24 二年级下·湖南张家界·期末"
+  },
+  {
+    "id": "271",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "在下面的方格中，每行，每列都有1~4这四个数，并且每个数在每行，每列都只出现一次,A是( ),B是( ).\n![](images/image-54.png)",
+    "options": [],
+    "answer": "4;3",
+    "solution": "【分析】根据A所在的列与行可知,A不是1,2,3，那么A一定是4。根据B所在的列与行可知,B不是1,2,4，那么B是3.\n【详解】由分析填写如下，可知A是4,B是3。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "23-24二年级下·江西宜春·期末"
+  },
+  {
+    "id": "272",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "郝悦，李明，王朗三人住在同一栋楼的一，二，三楼，李明住在二楼，郝悦回家要经过一楼。王朗住在( )楼，郝悦住在( )楼。",
+    "options": [],
+    "answer": "一;三",
+    "solution": "【分析】李明住在二楼，郝悦回家要经过一楼，说明郝悦不住在一二楼，郝悦住在三楼;李明住在二楼，郝悦住在三楼，那么王朗住在一楼.\n【详解】王朗住在一楼，郝悦住在三楼。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "23-24 二年级下·湖南常德·期末"
+  },
+  {
+    "id": "273",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "120名少先队员选大队长，候选人是甲，乙，丙三人。选举时，每人只能投票选举其中1人。开票中途累计，前100张选票中，甲得45票，乙得20票，丙得35票。如果这次选举没有弃权票，也没有废票，得票最多的人当选。那么，在尚未统计的选票中，甲至少再得( )票就能当选。",
+    "options": [],
+    "answer": "6",
+    "solution": "【分析】根据题意，还有20张选票，甲比丙多10张，甲比乙多25张。若20张都给丙，丙可能反超;若甲在20张中只得5张，则丙得15张时与甲持平。因此甲至少再得6张，才能保证超过丙.\n【详解】120-100=20(张);45-35=10(张);45+5=50(张);35+15=50(张)。甲得5张时可能与丙持平，所以甲至少再得6票就能当选。",
+    "knowledge_points": [
+      "简单推理",
+      "推理问题"
+    ],
+    "source": "2016 六年级·全国·竞赛"
+  },
+  {
+    "id": "274",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "有音乐，体育和美术三本书，下面三个人各拿一本。\n![](images/4d5f882fac59a245d3f69a4d70e51aec.png)\n小雨拿的是( )书，小英拿的是( )书。",
+    "options": [],
+    "answer": "美术;体育",
+    "solution": "【分析】丽丽拿的是音乐书，小雨拿的不是体育书，则小雨拿的是美术书，剩余小英拿的是体育书.\n【详解】丽丽拿的是音乐书，小雨拿的是美术书，剩余小英拿的是体育书。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "23-24二年级下·江西九江·期末"
+  },
+  {
+    "id": "275",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "在下面的方格中，每行，每列都有1-4这四个数，并且每个数在每行，每列都只出现一次。A是( ),B是( ).\n![](images/image-55.png)",
+    "options": [],
+    "answer": "1;4",
+    "solution": "【分析】A所在的第二列和第三行已有了2,3,4，所以A=1;B所在的第四列和第四行已有了1,2,3，所以B=4;据此解决.\n【详解】由题意分析得:A是1,B是4。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "23-24 二年级下·山东菏泽·期末"
+  },
+  {
+    "id": "276",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "亮亮，东东和丽丽三个人进行跳绳比赛。东东说：\"我不是第一名，丽丽比我成绩好。\"亮亮说\"我比丽丽多跳了5下。\"丽丽得了第( )名。",
+    "options": [],
+    "answer": "二",
+    "solution": "【分析】亮亮说'我比丽丽多跳了5下',说明亮亮比丽丽跳得多;东东说:'我不是第一名，丽丽比我成绩好。'说明丽丽比东东跳得多，所以第一名是亮亮，第二名是丽丽，第三名是东东.\n【详解】由分析可得：丽丽得了第二名。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "23-24 二年级下·湖南怀化·期末"
+  },
+  {
+    "id": "277",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "有《音乐》《美术》《体育》三本书，下面三个人各拿一本。\n![](images/e9d8df4382a18d30bc28dfe9ef6ef581.png)\n丽丽拿的是( )书，丁丁拿的是( )书。",
+    "options": [],
+    "answer": "体育;美术",
+    "solution": "【分析】园园拿的是音乐书，所以丽丽只能拿美术或体育，丽丽说拿的不是美术，所以丽丽只能拿体育书，丁丁只能拿美术书，据此解答.\n【详解】填空如下：丽丽拿的是(体育)书，丁丁拿的是(美术)书。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "23-24二年级下·广东汕头·期末"
+  },
+  {
+    "id": "278",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "大象，斑马，长颈鹿三只动物进行跑步比赛。大象说：\"我不是第二名。\"长颈鹿说：\"我跑得最快。\"那么斑马是第( )名。",
+    "options": [],
+    "answer": "二",
+    "solution": "【分析】长颈鹿说:'我跑得最快。'也就是长颈鹿是第一名;大象说:'我不是第二名。'那么大象是第三名，剩余斑马是第二名.\n【详解】由题意分析得：斑马是第二名。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "23-24 二年级下·江西赣州·期末"
+  },
+  {
+    "id": "279",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "如图，按规律第三个三角形中间的数为( )。\n![](images/d5063e68e2279bee16707ad3f290bd2a.png)",
+    "options": [],
+    "answer": "4",
+    "solution": "【分析】通过观察数之间的关系进行尝试，据此可知,1+3-4=0,5+2-3=4，所以三角形中间的数=三角形上面的数+三角形左下角的数-三角形右下角的数.\n【详解】5+3-4=4。按规律第三个三角形中间的数为4。",
+    "knowledge_points": [
+      "算式的规律(整数)"
+    ],
+    "source": "2017 三年级·全国·竞赛"
+  },
+  {
+    "id": "280",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "有篮球，足球和排球各1个，小红，小明和小丽三人各拿1个球，小红拿的不是足球。小丽拿的是排球。小红拿的是( ),小明拿的是( )。",
+    "options": [],
+    "answer": "篮球;足球",
+    "solution": "【分析】由题可知，小丽拿的是排球。剩下的是足球和篮球，小红拿的不是足球，就只能是篮球，足球就是小明拿的.\n【详解】小红拿的是篮球，小明拿的是足球。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "23-24二年级下·山东菏泽·期末"
+  },
+  {
+    "id": "281",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "小强，小明，小华三个好朋友踢毽子，分别踢了20个,35个,27个。小明说：\"我踢得个数不是最小的。\"小强说：\"我踢得最多。\"小华踢了( )个，小明踢了( )个，小强踢了( )个。",
+    "options": [],
+    "answer": "20;27;35",
+    "solution": "【分析】由题意可知：小强踢的最多，小明不是最少的，则小华踢的最少，据此得出结论即可.\n【详解】20<27<35。小强踢的最多，小明不是最少的，则小华踢了20个，小明踢了27个，小强踢了35个。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "23-24二年级下·新疆克孜勒苏·期末"
+  },
+  {
+    "id": "282",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "小红，小明和小丽三个人比身高，小丽说：\"我不是最高的，但比小明高。\"她们三个人从高到矮的顺序是( ),( ),( )。",
+    "options": [],
+    "answer": "小红;小丽;小明",
+    "solution": "【分析】小丽说她不是最高的，那小丽是第二高或最矮;若小丽最矮，则'比小明高'不成立，所以小丽是第二高，小明最矮，小红最高.\n【详解】由题意分析得：从高到矮是小红，小丽，小明。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "23-24 二年级下·福建厦门·期末"
+  },
+  {
+    "id": "283",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "三只可爱的小松鼠采橡子，分别采了32个,21个和37个。\n![](images/bd454cdf6f089cc3c67620bc79fbac61.png)\n欢欢采了( )个，乐乐采了( )个，笑笑采了( )个。",
+    "options": [],
+    "answer": "32;37;21",
+    "solution": "【分析】由题意可知：笑笑采的是最少的，而欢欢采的不是最多的，则欢欢采的是中间数量，剩下的乐乐采的最多.\n【详解】37>32>21，笑笑采的是最少的21个;欢欢采的是32个;乐乐采的是37个。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "23-24 二年级下·湖北恩施·期末"
+  },
+  {
+    "id": "284",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "小红，小华，小明三人进行跳绳比赛，小明说：\"我不是最后一名。\"小华说：\"我也不是最后一名，但是小明的成绩比我好。\"( )是第一名。",
+    "options": [],
+    "answer": "小明",
+    "solution": "【分析】一共三个人，小明和小华都不是最后一名，所以只有小红是最后一名;小明成绩比小华好，所以小明第一，小华第二.\n【详解】小明是第一名。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "23-24 二年级下·贵州铜仁·期末"
+  },
+  {
+    "id": "285",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "在下面的方格中，每行，每列都有1~4这四个数，并且每个数在每行，每列都只出现一次。A应该是( )。B应该是( ).\n![](images/image-56.png)",
+    "options": [],
+    "answer": "1;3",
+    "solution": "【分析】A所在的第四行和第二列已出现2,3,4，故A是1，且A所在的第二列第2个数是4。同理推出B的值即可.\n【详解】A所在的第四行和第二列已出现2,3,4，故A是1;B所在的第二行和第三列已出现1,2,4，故B是3。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "23-24 二年级下·河北保定·期末"
+  },
+  {
+    "id": "286",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "小明，小东，小亮三人进行50米赛跑。小东说：\"我不是第一名。\"小亮说：\"我也不是第一名，但我的成绩比小东好。\"获得最后一名的同学是( )。",
+    "options": [],
+    "answer": "小东",
+    "solution": "【分析】小东不是第一名，则可能第二或第三。若小东是第二，则小亮应是第一，但小亮也不是第一，矛盾;所以小东只能是第三名，即最后一名.\n【详解】由题意分析得：获得最后一名的同学是小东。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "23-24 二年级下·浙江杭州·期末"
+  },
+  {
+    "id": "287",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "下面的方格中，每行，每列都有1~4这四个数，并且每个数在每行每列都只出现一次。那么A是( ),B是( ),C是( ).\n![](images/image-57.png)",
+    "options": [],
+    "answer": "1;3;1",
+    "solution": "【分析】A所在的第四列与第四行分别有2,3,4，所以A是1;据此可继续排除确定B与C.\n【详解】由题意可得:A是1,B是3,C是1。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "23-24 二年级下·浙江·期末"
+  },
+  {
+    "id": "288",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "在下面的方格中，每行，每列都有1-4这四个数，并且每个数在每行，每列都只出现一次。A是( ),B是( ).\n![](images/image-58.png)",
+    "options": [],
+    "answer": "4;3",
+    "solution": "【分析】A所在的第一列和第三行已有1,2,3，所以A是4;B所在的第四列和第三行已有1,2,4，所以B是3.\n【详解】由题意分析得:A是4,B是3。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "23-24 二年级下·福建厦门·期末"
+  },
+  {
+    "id": "289",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "在下边的方格中，每行每列都有1~4这四个数，并且每行，每列都只出现一次。B应该是( ).\n![](images/image-59.png)",
+    "options": [],
+    "answer": "3",
+    "solution": "【分析】观察方格,A所在的第四列已有2和3，所在第二行已有4，故A=1;B所在第二行已有4和1，所在第一列已有2，故B=3.\n【详解】由题意分析得:B应该是3。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "23-24二年级下·湖南怀化·期末"
+  },
+  {
+    "id": "290",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.65,
+    "question": "下面方格中，每行，每列都有\"我爱数学\"这四个字，并且每个字在每行，每列都只出现一次,A是( ),C是( ).\n![](images/image-60.png)",
+    "options": [],
+    "answer": "学;我",
+    "solution": "【分析】根据每个字在每行，每列中都只出现一次，从每行，每列出现字较多的位置入手，利用排除法填空。\n【详解】A所在的行，列已经有\"我\"\"爱\"\"数\"，所以A是\"学\"；再逐步排除可得C是\"我\"。因此A是学，C是我。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "23-24二年级下·湖北随州·期末"
+  },
+  {
+    "id": "291",
+    "unit": "第九单元 推理",
+    "question_type": "填空题",
+    "difficulty": 0.85,
+    "question": "在下面的方格中，每行，每列都有1~4这四个数，并且每个数在每行，每列都只出现一次。B是( ),C是( ).\n![](images/image-61.png)",
+    "options": [],
+    "answer": "4;2",
+    "solution": "【分析】根据题意，从行列中已出现数字较多的位置入手，先确定B,再据此继续排除确定C.\n【详解】由分析可得:B是4,C是2。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "23-24 二年级下·湖南株洲·期末"
+  },
+  {
+    "id": "292",
+    "unit": "第九单元 推理",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "红红的体重和亮亮相等，亮亮的体重又和芳芳相等，则红红的体重和芳芳的也相等。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】假设红红的体重为40千克，因为红红的体重和亮亮相等，所以亮亮的体重是40千克;又因为亮亮的体重和芳芳相等，所以芳芳体重也是40千克，因此红红和芳芳体重相等.\n【详解】这句话正确。故答案为:√",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "23-24 三年级下·四川凉山·期末"
+  },
+  {
+    "id": "293",
+    "unit": "第九单元 推理",
+    "question_type": "判断题",
+    "difficulty": 0.85,
+    "question": "小猫，小狗和小熊中，若小熊最重，小狗不是最轻的，则小猫最轻。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】已知小熊最重，小狗不是最轻，因此最轻只能是小猫.\n【详解】根据分析可知该说法正确。故答案为:√",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "23-24 三年级下·河南驻马店·期末"
+  },
+  {
+    "id": "294",
+    "unit": "第九单元 推理",
+    "question_type": "判断题",
+    "difficulty": 0.65,
+    "question": "小星，小龙，小壮三个人中，小壮最重，小龙不是最轻的，则小星最轻。( )",
+    "options": [],
+    "answer": "√",
+    "solution": "【分析】总共三个人，小壮最重，因此不可能最轻;小龙也不是最轻，所以最轻只能是小星.\n【详解】该说法正确。故答案为:√",
+    "knowledge_points": [
+      "比轻重",
+      "推理问题"
+    ],
+    "source": "22-23 二年级下·甘肃天水·期末"
+  },
+  {
+    "id": "295",
+    "unit": "第九单元 推理",
+    "question_type": "解答题",
+    "difficulty": 0.65,
+    "question": "在下面的方格中，每行，每列都有1~4这四个数，并且每个数在每行，每列都只出现一次。B,C应该是几。\n\n| 1 | | 4 | |\n| ---- | ---- | ---- | ---- |\n| A | 4 | | |\n| 3 | | B | |\n| | | 2 | C |",
+    "options": [],
+    "answer": "1;3",
+    "solution": "【分析】先从A入手,A所在的行和列已经出现了4,1,3，确定A是2;再根据行列排除可得B所在位置应为1;继续排除得C所在位置应为3.\n【详解】可得完整方格中B=1,C=3。答:B是1,C是3。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "23-24二年级下·甘肃平凉·期末"
+  },
+  {
+    "id": "296",
+    "unit": "第九单元 推理",
+    "question_type": "解答题",
+    "difficulty": 0.65,
+    "question": "甲，乙，丙三位老师分别教语文，数学，外语。甲是一位女教师，她比数学老师活泼;外语老师是一位学生的哥哥;丙上课从来不说外语。这三位老师各教什么课。",
+    "options": [],
+    "answer": "甲是语文老师;乙是外语老师;丙是数学老师",
+    "solution": "【分析】由'丙上课从来不说外语'可知丙不是外语老师;外语老师是学生的哥哥，说明外语老师是男教师，而甲是女教师，所以甲也不是外语老师，故乙是外语老师。又由'甲比数学老师活泼'可知甲不是数学老师，因此甲是语文老师，丙是数学老师.\n【详解】答：甲是语文老师，乙是外语老师，丙是数学老师。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "23-24 六年级下·河南许昌·期末"
+  },
+  {
+    "id": "297",
+    "unit": "第九单元 推理",
+    "question_type": "解答题",
+    "difficulty": 0.65,
+    "question": "有三只袋子，一只放着糖，另外两只放着石子，它们分别写着:\n袋子A:'这只袋子放着石子。'\n袋子B:'这只袋子放着糖。'\n袋子C:'石子放在袋子B中。'\n三只袋子上写的内容，只有一只袋子写的是正确的。哪只袋子里放着糖。",
+    "options": [],
+    "answer": "A袋子中放着糖",
+    "solution": "【分析】B和C两句话互相矛盾，至少有一真一假。若B真，则A假,A中放糖，同时B也放糖，不符合只有一袋放糖;故B不能真。则C为真,B为假,B中不是糖;A也为假,A中不是石子，即A中放糖.\n【详解】答:A袋子中放着糖。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "23-24 五年级上·全国·课后作业"
+  },
+  {
+    "id": "298",
+    "unit": "第九单元 推理",
+    "question_type": "解答题",
+    "difficulty": 0.65,
+    "question": "某学校为表扬好人好事核实一件事，老师找了A,B,C三个学生。A说:'是B做的。'B说:'不是我做的。'C说:'不是我做的。'这三个学生中只有一人说了实话，这件好事是谁做的。",
+    "options": [],
+    "answer": "好事是C做的",
+    "solution": "【分析】A说是B做的,B说不是B做的，这两句话互为矛盾，必有一真一假。题目说三人中只有一人说真话，因此C必须说假话，即'不是我做的'为假，说明是C做的.\n【详解】根据分析可知，这件好事是C做的。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "23-24 四年级上·全国·课后作业"
+  },
+  {
+    "id": "299",
+    "unit": "第九单元 推理",
+    "question_type": "解答题",
+    "difficulty": 0.65,
+    "question": "小李，小徐和小张是同学，大学毕业后分别当了教师，数学家和工程师。小张年龄比工程师大;小李和数学家不同岁;数学家比小徐年龄小。谁是教师，谁是数学家，谁是工程师。",
+    "options": [],
+    "answer": "小徐是教师，小张是数学家，小李是工程师",
+    "solution": "【分析】由'小张年龄比工程师大'知小张不是工程师;由'小李和数学家不同岁'知小李不是数学家;由'数学家比小徐年龄小'知小徐不是数学家，因此数学家只能是小张。再由小张不是工程师，剩下工程师是小李，教师是小徐.\n【详解】答：小徐是教师，小张是数学家，小李是工程师。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "23-24四年级上·全国·课后作业"
+  },
+  {
+    "id": "300",
+    "unit": "第九单元 推理",
+    "question_type": "解答题",
+    "difficulty": 0.65,
+    "question": "卢刚，丁飞和陈瑜三人，一位是工程师，一位是医生，一位是飞行员。现在只知道：卢刚和医生不同岁;医生比丁飞年龄小，陈瑜比飞行员年龄大。问：谁是工程师，谁是医生，谁是飞行员。",
+    "options": [],
+    "answer": "丁飞是工程师;陈瑜是医生;卢刚是飞行员",
+    "solution": "【分析】由'卢刚和医生不同岁'可知卢刚不是医生;'医生比丁飞年龄小'可知丁飞不是医生;因此医生只能是陈瑜。又由'陈瑜比飞行员年龄大'可知陈瑜不是飞行员。剩下卢刚与丁飞中，丁飞不是医生，若丁飞是飞行员会与年龄关系矛盾，因此卢刚是飞行员，丁飞是工程师.\n【详解】答：丁飞是工程师，陈瑜是医生，卢刚是飞行员。",
+    "knowledge_points": [
+      "推理问题"
+    ],
+    "source": "2021 四年级下·全国·竞赛"
+  }
+]
diff --git "a/\344\272\214\345\271\264\347\272\247\351\242\230\351\233\206/\344\272\214\345\271\264\347\272\247\344\270\213/\344\272\214\345\271\264\347\272\247\344\270\213\347\254\254\344\272\214\345\215\225\345\205\203\350\241\250\345\206\205\351\231\244\346\263\225.json" "b/\344\272\214\345\271\264\347\272\247\351\242\230\351\233\206/\344\272\214\345\271\264\347\272\247\344\270\213/\344\272\214\345\271\264\347\272\247\344\270\213\347\254\254\344\272\214\345\215\225\345\205\203\350\241\250\345\206\205\351\231\244\346\263\225.json"
new file mode 100644
index 0000000000000000000000000000000000000000..09d92208f93b778cd2f968404080c17c6422b258
--- /dev/null
+++ "b/\344\272\214\345\271\264\347\272\247\351\242\230\351\233\206/\344\272\214\345\271\264\347\272\247\344\270\213/\344\272\214\345\271\264\347\272\247\344\270\213\347\254\254\344\272\214\345\215\225\345\205\203\350\241\250\345\206\205\351\231\244\346\263\225.json"
@@ -0,0 +1,8695 @@
+[
+    {
+        "id":  "1",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "12 个甜瓜，需要几个盘子。横线上应补充的条件是( )。",
+        "options":  [
+                        "A. 平均放在4个盘子里",
+                        "B. 每个盘子里放4个",
+                        "C. 送给小朋友4个"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】用甜瓜的总数12个除以平均每个盘子中甜瓜的个数即可求出需要几个盘子。\n\n【详解】12个甜瓜，每个盘子里放4个，即12÷4=3(个),则需要3个盘子，即需要补充的条件为：每个盘子里放4个。故答案为:B",
+        "knowledge_points":  [
+                                 "\"提问题\"\"填条件\"问题",
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "2025 二年级上·全国·专题练习"
+    },
+    {
+        "id":  "2",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "下面不能用8÷4=2表示的是( ).\n![](images/163706.png)",
+        "options":  [
+
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】根据除法的意义：把一个数每几个一份，求分成了几份;把一个数平均分成几份，求每份是多少，都用除法计算;分析下面各项，列出算式，找出和题目算式不一致的，即不能用8÷4=2表示。\n\n【详解】A。表示把8个点每4个一份，分成了2份;算式:8÷4=2，符合题意;B。表示把8个点平均分成4份，每份是2;算式:8÷4=2，符合题意;C。每份分的不是同样多，不是平均分，不能用8÷4=2表示，符合题意。故答案为:C",
+        "knowledge_points":  [
+                                 "整数平均分的意义及应用",
+                                 "除法的初步认识"
+                             ],
+        "source":  "24-25 二年级下·广东潮州·期末"
+    },
+    {
+        "id":  "3",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "12÷3=4，表示( )。",
+        "options":  [
+                        "A. 把12平均分成4份，每份是3",
+                        "B. 12里面有3个4",
+                        "C. 12里面有4个3"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】根据除法的两种意义：表示把一个数平均分成几份，求每份是多少，还表示一个数里有几个每份数。12÷3=4，表示把12平均分成3份，每份是4，还表示12里面有4个3。\n\n【详解】A。12÷3=4，表示把12平均分成3份，每份是4。不是把12平均分成4份，每份是3;B。12÷3=4，表示12里面有4个3，不是12里面有3个4;C。12÷3=4，表示12里面有4个3。所以,12÷3=4，表示12里面有4个3。故答案为:C",
+        "knowledge_points":  [
+                                 "除法的初步认识"
+                             ],
+        "source":  "25-26 三年级上·黑龙江佳木斯·开学考试"
+    },
+    {
+        "id":  "4",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "把18个面包平均分成6份，每份是( )个。",
+        "options":  [
+                        "A. 2",
+                        "B. 3",
+                        "C. 4"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】平均分需要用除法计算，再通过乘法口诀求出结果。\n\n【详解】由题意知把18个面包平均分成6份，求每份是多少，可列出除法算式:18÷6。计算18÷6时，我们可以利用乘法口诀来求解，根据乘法口诀\"三六十八\"，可知6×3=18，所以18÷6=3。故答案为:B",
+        "knowledge_points":  [
+                                 "整数平均分的意义及应用"
+                             ],
+        "source":  "25-26三年级上·黑龙江佳木斯·开学考试"
+    },
+    {
+        "id":  "5",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "下面选项( )可以用算式8÷2=4来表示。",
+        "options":  [
+                        "A. 有8个苹果，拿走了2个，还剩几个。",
+                        "B. 有8个苹果，平均放在4个盘子，每个盘子放几个。",
+                        "C. 有8个苹果，平均放在2个盘子，每个盘子放几个。"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】8÷2=4可以表示把8平均分成2份，每份是4;也可以表示8里面有4个2，由此解答。\n\n【详解】A。求还剩的数量，用减法计算，列式为8-2=6(个),不符合题意;B。求每个盘子放的数量，用除法计算，列式为8÷4=2(个),不符合题意;C。求每个盘子放的数量，用除法计算，列式为8÷2=4(个),符合题意。则有8个苹果，平均放在2个盘子，每个盘子放几个。可以用算式8÷2=4来表示。故答案为:C",
+        "knowledge_points":  [
+                                 "整数平均分的意义及应用",
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·湖北恩施·期末"
+    },
+    {
+        "id":  "6",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "唐代诗人柳宗元的《江雪》共有4句,20个字，每句诗的字数相同，每句诗有( )个字。",
+        "options":  [
+                        "A. 4",
+                        "B. 5",
+                        "C. 20"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】要求每句诗有几个字，根据除法的意义，即用20÷4进行解答即可。\n\n【详解】20÷4=5(个),所以每句诗有5个字。故答案为:B",
+        "knowledge_points":  [
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "24-25二年级下·广东潮州·期末"
+    },
+    {
+        "id":  "7",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "下面能表示\"12÷4=3\"的是( )。",
+        "options":  [
+                        "A. ![](images/8681fe54b382826d670eb880d06671a6eb74030312276dd2316a7306de347a05.jpg)",
+                        "B. ![](images/f8535eecd77693b9f1837e8a9abbbb026fc10ebf2044a2b1421cadd79980e21e.jpg)",
+                        "C. ![](images/023889a1cd2b9b973dd2cc3c5bdeb76014d489e7c9594a96a6dd38fc9963e5fa.jpg)"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】根据除法的意义,12÷4=3表示把12平均分成4份，每份是3，据此逐一分析三个选项，找出正确答案。\n\n【详解】A。表示把8个苹果平均分成2份，每份是4个苹果，不符合题意;B。表示把12个苹果平均分成6份，每份是2个苹果，不符合题意;C。表示把12个苹果平均分成4份，每份是3个苹果，符合题意;故答案为:C",
+        "knowledge_points":  [
+                                 "除法的初步认识",
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "24-25二年级下·四川成都·期末"
+    },
+    {
+        "id":  "8",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "45÷9=5，其中9是( )。",
+        "options":  [
+                        "A. 被除数",
+                        "B. 除数",
+                        "C. 商"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】根据\"被除数/除数=商\"来填空即可。\n\n【详解】根据分析可知，在算式45÷9=5中,45是被除数,9是除数,5是商;所以9是除数。故答案为:B",
+        "knowledge_points":  [
+                                 "除法的初步认识"
+                             ],
+        "source":  "25-26 三年级上·黑龙江佳木斯·开学考试"
+    },
+    {
+        "id":  "9",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "下面算式中，商最大的是( )。",
+        "options":  [
+                        "A. 12÷3",
+                        "B. 20÷4",
+                        "C. 24÷6"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】根据乘法口诀分别计算出每个选项中除法算式的商，再比较大小;找出商最大的算式即可;据此解答。\n\n【详解】A。根据三四十二可知,12÷3=4;B。根据四五二十可知,20÷4=5;C。根据四六二十四可知,24÷6=4;5\u003e4，所以20÷4的商最大。故答案为:B",
+        "knowledge_points":  [
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "25-26 三年级上·黑龙江佳木斯·开学考试"
+    },
+    {
+        "id":  "10",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "把12朵花平均分成3份，第( )种分法正确。",
+        "options":  [
+                        "A. ![](images/46ddd55f42deb83f8bcdec68fa8366d26657ac29272bbd3d5fc7ed3f59e6d79c.jpg)",
+                        "B. ![](images/296612c323a8f4e36171906317fd9f01e216fae61082a6a5cc71509abc29d459.jpg)",
+                        "C. ![](images/1750d1620b14e557c5bb936b3b84107549da6e4250f9a1bf9e00b4be67996126.jpg)"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】在分物体时，每份分得同样多是平均分，由此分析各选项即可解答。\n\n【详解】A。表示把12朵花平均分成4份，每份是3朵，不符合题意;B。把12朵花分成了3份，分别有3朵,4朵,5朵，每份数量不同，不是平均分，不符合题意;C。表示把12朵花平均分成了3份，每份是4朵，符合题意。故答案为:C",
+        "knowledge_points":  [
+                                 "整数平均分的意义及应用"
+                             ],
+        "source":  "24-25 二年级下·广东肇庆·期中"
+    },
+    {
+        "id":  "11",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "统计某段时间内进入学校的学生数量时，可以写\"正\"字记录数据。记录10名学生，要写( )个\"正\"字。",
+        "options":  [
+                        "A. 1",
+                        "B. 2",
+                        "C. 10"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】用\"正\"字统计数据时，\"正\"字的每一笔代表数量1，一个\"正\"字代表数量5，则用10/一个\"正\"字代表的数量=要写\"正\"字的个数。\n\n【详解】10÷5=2(个),记录10名学生，要写2个\"正\"字。故答案为:B",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·广东肇庆·期中"
+    },
+    {
+        "id":  "12",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "把12个梨平均分成3份，每份有( )个梨。",
+        "options":  [
+                        "A. 3",
+                        "B. 4",
+                        "C. 5"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】根据除法的意义，用12÷3即可得出每份有多少个梨。\n\n【详解】12÷3=4(个),每份有4个梨。故答案为:B",
+        "knowledge_points":  [
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "25-26 三年级上·黑龙江鹤岗·开学考试"
+    },
+    {
+        "id":  "13",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "下面图中的情况，不能用12÷4=3来表示的是( )。",
+        "options":  [
+                        "A. ![](images/cbbb2a5ed9dcba744ffbd3db541e167ce712dc2944665f4f8bc93990a8c9fa61.jpg)",
+                        "B. ![](images/7cca913f4d7c9cb26fe1b8db5b07faba48c245b4adedb85ad974070b3401b778.jpg)",
+                        "C. ![](images/459800332c50c2896827a0dd4623175b7dae66061a5f2c49938dcd6b6b3295c0.jpg)"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】分别列出每项的算式即可。除法算式中，被除数表示总数，除数表示平均分成的份数，商表示每份的数量;或者被除数表示总数，除数表示每份的数量，商表示平均分成的份数。\n\n【详解】A。能用12÷4=3来表示。B。不是平均分，不能用12÷4=3来表示。C。能用12÷4=3来表示。故答案为:B",
+        "knowledge_points":  [
+                                 "整数平均分的意义及应用",
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·山东临沂·期中"
+    },
+    {
+        "id":  "14",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "一根丝带长16米，对折之后再对折，然后沿着折痕剪开，每段长( )米。",
+        "options":  [
+                        "A. 8",
+                        "B. 4",
+                        "C. 2"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】根据题意，对折一次分成了同样长的2段，对折两次分成了同样长的4段，则用总长度/平均分成的段数=每段的长度。\n\n【详解】2×2=4(段),16÷4=4(米),一根丝带长16米，对折之后再对折，然后沿着折痕剪开，每段长4米。故答案为:B",
+        "knowledge_points":  [
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·浙江杭州·期末"
+    },
+    {
+        "id":  "15",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "把20个青团放在盘子里，每个盘子放5个，需要几个盘子。下面的思考过程错误的是( )。",
+        "options":  [
+                        "A. 想：四五二十;列式:20÷5=4(个)",
+                        "B. ![](images/b54c7242920dced31228116a8286885259326dd3066c0c0665d2de4bed8cd0a5.jpg)",
+                        "C. ![](images/0034abc8cd28909b0719931bde48545f8fab80c4668bc0b987ec090aeca46253.jpg)"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】根据除法的意义，用青团的总个数/每个盘子放的个数=需要几个盘子，据此选出错误的答案。\n\n【详解】A。20÷5=4(个),表示用青团的总个数/每个盘子放的个数=需要几个盘子，思考过程正确，不符合题意;B。图中有25个青团，每个盘子放5个，需要5个盘子，列式为:25÷5=5(个),思考过程错误，符合题意;C。有20个青团，每5个放一盘，需要4个盘子，列式为:20÷5=4(个),思考过程正确，不符合题意;故答案为:B",
+        "knowledge_points":  [
+                                 "除法的初步认识",
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·福建厦门·期末"
+    },
+    {
+        "id":  "16",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "风筝，古称\"鸢\"，在我国有着悠久的历史。李叔叔在制作风筝时，将一根20米的长丝带剪成同样长的短丝带，用来做风筝的尾巴。他一共剪了4次，平均每条短丝带长( )米。",
+        "options":  [
+                        "A. 3",
+                        "B. 4",
+                        "C. 5"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】根据题意可知，剪1次得2段，剪2次得3段，以此类推，剪4次得5段，剪的次数加1就是剪的段数，再用丝带的总长度除以剪的段数，等于平均每条丝带的长度，据此解答。\n\n【详解】4+1=5(段),20÷5=4(米),因此，将一根20米的长丝带剪成同样长的短丝带，用来做风筝的尾巴。他一共剪了4次，平均每条短丝带长4米。故答案为:B",
+        "knowledge_points":  [
+                                 "整数平均分的意义及应用",
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "24-25二年级下·山西长治·期末"
+    },
+    {
+        "id":  "17",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "下列选项不能表示算式12÷3=4的意义的是( )。",
+        "options":  [
+                        "A. ![](images/52736a82d70deb90150d33f54b216084f4ae8f0e556222c1b4c3cb6d9b2ab9b8.jpg)",
+                        "B. ![](images/bac6c96e734bf1caee3e0e4c149455492eba69f1861e1afe9431a4003e13d320.jpg)",
+                        "C. ![](images/405.jpg)"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】12÷3=4可以表示把12平均分成3份，每份是4个;也可以表示一共有12个，每份有3个，可以平均分成4份。据此判断进行选择即可。\n\n【详解】A。表示一共有12个○,每份有3个，求可以平均分成多少份，列式为12÷3=4;B。表示一共有12个○,平均分成3份，求每份有多少个，列式为12÷3=4;C。分成了3份，每份的个数都不一样，而12÷3=4表示的是平均分的情况，因此不能用算式12÷3=4计算。故答案为:C",
+        "knowledge_points":  [
+                                 "整数平均分的意义及应用"
+                             ],
+        "source":  "24-25 二年级下·山西晋中·期中"
+    },
+    {
+        "id":  "18",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "24个苹果，每天吃6个，几天吃完。列式正确的是( )。",
+        "options":  [
+                        "A. 24-6",
+                        "B. 24÷6",
+                        "C. 6×4"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】由题意可知：用苹果的总个数除以每天吃的个数，即是吃的天数;据此解答。\n\n【详解】24÷6=4(天),4天吃完。故答案为:B",
+        "knowledge_points":  [
+                                 "整数平均分的意义及应用",
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·湖北孝感·期中"
+    },
+    {
+        "id":  "19",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "因为\"△+△+△+△=20,10=□+□\"，所以\"△+□\"=( )。",
+        "options":  [
+                        "A. 15",
+                        "B. 10",
+                        "C. 8"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】求几个相同加数的和可以用乘法计算，相同加数在前，个数在后，即相同加数×个数。则算式可以改写为△*4=20,10=□*2，则分别用积/一个乘数=另一个乘数，计算出△和□代表的数，再代入到△+□计算出结果即可。\n\n【详解】△*4=20，则20÷4=5,△=5;10=□*2，则10÷2=5,□=5;则△+□=5+5=10。故答案为:B",
+        "knowledge_points":  [
+                                 "初步认识乘法意义",
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "24-25二年级下·河南南阳·期中"
+    },
+    {
+        "id":  "20",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "一道除法题，除数是6，华华把被除数的十位数字和个位数字看颠倒了，结果除得的商是7，正确的商应该是( )。",
+        "options":  [
+                        "A. 4",
+                        "B. 6",
+                        "C. 7"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】由题意可知：用错误的商和除数相乘等于错误的被除数，把错误的被除数的十位数字和个位数字交换回来，即是正确的被除数，用正确的被除数除以除数，即可得出正确的商;据此解答。\n\n【详解】7×6=42，正确的被除数是:24,24÷6=4，正确的商应该是4。故答案为:A",
+        "knowledge_points":  [
+                                 "7的乘法口诀及应用",
+                                 "用6的乘法口诀求商",
+                                 "乘，除法的意义和各部分间的关系"
+                             ],
+        "source":  "24-25二年级下·河南南阳·期中"
+    },
+    {
+        "id":  "21",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "下列算式中，商最小的是( )。",
+        "options":  [
+                        "A. 2×2",
+                        "B. 18÷3",
+                        "C. 25÷5"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】除法算式为被除数/除数=商，乘法算式为乘数×乘数=积，由此计算出各算式的结果再比较大小即可。\n\n【详解】A。2×2=4，积是4;B。18÷3=6，商是6;C。25÷5=5，商是5;5\u003c6，则商最小的是25÷5。故答案为:C",
+        "knowledge_points":  [
+                                 "2的乘法口诀及应用",
+                                 "用2~5的乘法口诀求商",
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·河南南阳·期中"
+    },
+    {
+        "id":  "22",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "下面哪个问题可以用\"24÷6=4\"解决。( )",
+        "options":  [
+                        "A. 奇奇用24元买了4个同样的面包，每个面包多少钱。",
+                        "B. 学校把24根跳绳分给各班，每6根跳绳分给一个班，可以分给几个班。",
+                        "C. 学校买来24个足球,6个分给二年级，还剩下多少个没有分。"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】除法算式为被除数/除数=商，可以表示把24平均分成6份，每份是4;或者把24按每6个为一份，可以分成4份，由此解答。\n\n【详解】A。求每个面包多少钱，列式为24÷4=6(元),不符合题意;B。求可以分给几个班，列式为24÷6=4(个),符合题意;C。求没有分的数量，列式为24-6=18(个),不符合题意。则可以用\"24÷6=4\"解决的是学校把24根跳绳分给各班，每6根跳绳分给一个班，可以分给几个班。故答案为:B",
+        "knowledge_points":  [
+                                 "\"提问题\"\"填条件\"问题",
+                                 "一位数与两位数的退位减法",
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "24-25二年级下·河南漯河·期中"
+    },
+    {
+        "id":  "23",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "皮皮分别到三家超市买了同一种饮料,( )最便宜。",
+        "options":  [
+                        "A. 5瓶15元",
+                        "B. 2瓶8元",
+                        "C. 3瓶12元"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】根据题意，用花的钱数/买的瓶数=每瓶饮料的钱数，分别算出到三家超市买同一种饮料时，每瓶饮料的钱数，再比较大小，即可得出哪种饮料最便宜。\n\n【详解】A。15÷5=3(元);B。8÷2=4(元);C。12÷3=4(元);3元\u003c4元,5瓶15元最便宜。故答案为:A",
+        "knowledge_points":  [
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·河南南阳·期中"
+    },
+    {
+        "id":  "24",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "下面的算式中商最大的是( )。",
+        "options":  [
+                        "A. 24÷6",
+                        "B. 25÷5",
+                        "C. 12÷2"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】比较各选项商的大小，根据乘法口诀直接计算每个算式的商即可确定商最大的选项。\n\n【详解】A。24÷6=4;B。25÷5=5;C。12÷2=6;6\u003e5\u003e4，因此商最大的是12÷2。故答案为:C",
+        "knowledge_points":  [
+                                 "7以内数的比大小",
+                                 "用2~5的乘法口诀求商",
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "24-25二年级下·河南南阳·期中"
+    },
+    {
+        "id":  "25",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "统计投票数时，可以写\"正\"字记录数据,20张票要写( )个\"正\"字。",
+        "options":  [
+                        "A. 20",
+                        "B. 10",
+                        "C. 4"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】每个\"正\"字有5画，每画代表1票，因此每个\"正\"字可记录5票。总票数为20张，用总票数除以每个\"正\"字记录的票数，即可得到所需\"正\"字的个数。\n\n【详解】20÷5=4(个),因此,20张票需要写4个\"正\"字。故答案为:C",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·湖北黄冈·期中"
+    },
+    {
+        "id":  "26",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "把18支铅笔平均分给3个小朋友，每人分到( )支。",
+        "options":  [
+                        "A. 5",
+                        "B. 6",
+                        "C. 9"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】用铅笔的总支数除以人数即可求出每人分到多少支。\n\n【详解】18÷3=6(支),每人分到6支。故答案为:B",
+        "knowledge_points":  [
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·湖南岳阳·期中"
+    },
+    {
+        "id":  "27",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "下面算式中，商最大的是( )(☆不为0)。",
+        "options":  [
+                        "A. ☆÷2",
+                        "B. ☆÷3",
+                        "C. ☆÷6"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】根据题意,☆不为0，假设☆是12，用除法分别求出三个选项的答案，再比较商的大小，选出商最大的即可。\n\n【详解】假设☆是12,A。12÷2=6;B。12÷3=4;C。12÷6=2;6\u003e4\u003e2,12÷2=6的商最大，也就是☆÷2的商最大。故答案为:A",
+        "knowledge_points":  [
+                                 "用2~5的乘法口诀求商",
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·福建福州·期中"
+    },
+    {
+        "id":  "28",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "有24支铅笔，每个小朋友分6支，可以分给几个小朋友。这道题实际( )。",
+        "options":  [
+                        "A. 24里面有多少个6。",
+                        "B. 24里面有几个4。",
+                        "C. 把24平均分成6份，每份是多少。"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】根据题意可知，有24支铅笔，要按照每个小朋友分6支的方式来分，可以分给几个小朋友。这就相当于在问24这个总数里面，按照每份6支来分，一共能有几份。据此逐项分析各个选项，找出正确答案即可解答。\n\n【详解】A.\"24里面有多少个6\"，这与我们的分铅笔情境是相符的。因为我们就是在看24支铅笔里面包含了几个6支，有几个6支就能分给几个小朋友。B.\"24里面有几个4\"，题目中是每个小朋友分6支铅笔，而不是4支，所以与本题的分配情况不相关，是错误的。C.\"把24平均分成6份，每份是多少\"，这里强调的是每份的数量，而本题问的是可以分给几个小朋友，也就是求份数，不是每份是多少，不符合题意。这道题实际是求24里面有多少个6。故答案为:A",
+        "knowledge_points":  [
+                                 "整数平均分的意义及应用",
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·福建莆田·期中"
+    },
+    {
+        "id":  "29",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "关于算式\"6÷3=2\"有以下四个说法，其中说法正确的有( ).\n(1)能表示6里面有2个3\n(2)被除数是6，除数是3，商是2\n(3)读作:6除3等于2\n(4)可以表示把6平均分成3份，每份是2",
+        "options":  [
+                        "A. 2个",
+                        "B. 3个",
+                        "C. 4个"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】本题主要考查除法算式的意义，各部分名称以及读法。我们需要根据这些知识点来逐一分析每个说法是否正确。\n\n【详解】(1)\"6里面有2个3\"，用除法算式表示应该是6÷3=2，这个算式能表示6里面包含2个3，所以该说法正确。(2)在除法算式6÷3=2中，根据除法算式各部分的名称，除号前面的数是被除数，除号后面的数是除数，等号后面的数是商。所以这里被除数是6，除数是3，商是2，该说法正确。(3)对于除法算式6÷3=2，正确的读法应该是\"6除以3等于2\"，所以\"6除3等于2\"这种读法错误，该说法错误。(4)根据除法的平均分意义,6÷3=2可以表示把6平均分成3份，每份是2，该说法正确。说法(1),(2),(4)正确，一共有3个正确的说法。故答案为:B",
+        "knowledge_points":  [
+                                 "整数平均分的意义及应用",
+                                 "除法的初步认识"
+                             ],
+        "source":  "24-25二年级下·湖北孝感·期中"
+    },
+    {
+        "id":  "30",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "24÷6表示( )。",
+        "options":  [
+                        "A. 24减去6是多少。",
+                        "B. 24加上6是多少。",
+                        "C. 24平均分成4份，每份是多少。",
+                        "D. 24减去6，几次为0。"
+                    ],
+        "answer":  "D",
+        "solution":  "【分析】24÷6表示把24个物体按每6个分一份，求分成几份，也可以表示24里面有几个6，据此逐项分析各个选项，找出正确的答案即可解答。\n\n【详解】A。24减去6是多少。对应减法运算24-6，与除法无关，此选项错误。B。24加上6是多少。对应加法运算24+6，与除法无关，此选项错误。C。24平均分成4份，每份是多少。对应算式是24÷4=6，此选项错误。D。24减去6，几次为0。24-6-6-6-6=0，减了4次，即求24里面包含几个6，用除法计算，可以用24÷6表示，此选项正确。故答案为:D",
+        "knowledge_points":  [
+                                 "整数平均分的意义及应用",
+                                 "除法的初步认识",
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·福建龙岩·期中"
+    },
+    {
+        "id":  "31",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "3月12日是植树节，实验小学二(5)班同学种了42棵树，平均栽成6行。42÷6表示的问题是( )。",
+        "options":  [
+                        "A. 平均栽成几行。",
+                        "B. 一共有多少棵树。",
+                        "C. 每行有几棵。",
+                        "D. 还剩几棵树。"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】这是一道关于除法意义理解的题目。需要我们掌握除法在平均分情境中的含义，即把一个总数平均分成若干份，求每份是多少。已知同学们种了42棵树，并且这些树平均栽成了6行。在数学里，当我们用总数除以平均分的份数时，得到的就是每份的数量。这里总数是42棵树，平均分的份数就是6行，那么42÷6的意思就是把42棵树平均分成6份，每份对应的就是每行树的数量。\n\n【详解】A.\"平均栽成几行\"，题目中已经明确给出是6行，所以该选项错误;B.\"一共有多少棵树\"，题目中已经告知是42棵树，所以该选项错误;C.\"每行有几棵\"，由分析可知42÷6表示的就是\"每行有几棵\"，所以该选项正确;D.\"还剩几棵树\"，题目中并没有涉及剩余树的相关信息，所以该选项错误。故答案为:C",
+        "knowledge_points":  [
+                                 "整数平均分的意义及应用"
+                             ],
+        "source":  "24-25 二年级下·福建龙岩·期中"
+    },
+    {
+        "id":  "32",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "一块橡皮5角钱，小亮有3元钱，能买( )块橡皮。",
+        "options":  [
+                        "A. 5",
+                        "B. 6",
+                        "C. 7"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】用小亮已有的总钱数除以每块橡皮的钱数，求出商，就是能买几块橡皮，计算时，要统一单位,1元=10角。\n\n【详解】3元=30角,30÷5=6(块),即能买6块橡皮。故答案为:B",
+        "knowledge_points":  [
+                                 "用6的乘法口诀求商",
+                                 "元，角，分的认识及换算"
+                             ],
+        "source":  "24-25 二年级下·黑龙江佳木斯·期末"
+    },
+    {
+        "id":  "33",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "聪聪感冒了，医生给他开了24片药，他几天能吃完。要解决这个问题，还需要知道下面哪个条件。( )",
+        "options":  [
+                        "A. 一次吃2片",
+                        "B. 每天吃4片",
+                        "C. 每天吃3次"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】已知医生给聪聪开了24片药，问他几天能吃完。根据天数=总药片数/每天吃的药片数，所以，需要补充的条件是每天吃多少片药。据此分析各个选项即可。\n\n【详解】A。一次吃2片，不知道一天吃几次，不符合题意;B。每天吃4片，符合题意;C。每天吃3次，不知道每次吃几片，不符合题意。故答案为:B",
+        "knowledge_points":  [
+                                 "除法的初步认识"
+                             ],
+        "source":  "24-25二年级下·湖北随州·期末"
+    },
+    {
+        "id":  "34",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "24根小棒，如果摆成○,那么可以摆( )个单独的○;如果摆成□,那么可以摆( )个单独的□。",
+        "options":  [
+
+                    ],
+        "answer":  "4;6",
+        "solution":  "【分析】一个○需要6根小棒，要求可以摆成几个单独的○,就是求24里面有几个6，列式为24÷6=4;同理，一个□需要4根小棒，要求可以摆成几个单独的□,就是求24里面有几个4，列式为24÷4=6。\n\n【详解】24÷6=4(个),24÷4=6(个),所以24根小棒，如果摆成○,那么可以摆4个单独的○;如果摆成□,那么可以摆6个单独的□。",
+        "knowledge_points":  [
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "25-26 二年级上·全国·单元测试"
+    },
+    {
+        "id":  "35",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "36里有( )个6，列算式为( )。",
+        "options":  [
+
+                    ],
+        "answer":  "6;36÷6=6",
+        "solution":  "【分析】求一个数里有几个另一个数，用这个数除以另一个数即可;据此解答。\n\n【详解】36÷6=6,36里有6个6，列算式为36÷6=6。",
+        "knowledge_points":  [
+                                 "整数平均分的意义及应用",
+                                 "除法的初步认识",
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·广东潮州·期末"
+    },
+    {
+        "id":  "36",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "24÷6=4，读作( ),表示把24平均分成( )份，每份是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "24除以6等于4;6;4",
+        "solution":  "【分析】除法算式中，\"/\"读作\"除以\"，算式24÷6=4应读作\"24除以6等于4\"。表示把24平均分成6份，每份是4。\n\n【详解】24÷6=4读作24除以6等于4;表示把24平均分成6份，每份是4。",
+        "knowledge_points":  [
+                                 "除法的初步认识"
+                             ],
+        "source":  "25-26 三年级上·黑龙江佳木斯·开学考试"
+    },
+    {
+        "id":  "37",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "18÷3=6，这个算式中,( )是被除数,( )是除数,( )是商。",
+        "options":  [
+
+                    ],
+        "answer":  "18;3;6",
+        "solution":  "【分析】在除法算式中，除号前面的是被除数，除号后面的是除数，等号后面的是商，据此来填写即可。\n\n【详解】18÷3=6，这个算式中,18是被除数,3是除数,6是商。",
+        "knowledge_points":  [
+                                 "除法的初步认识"
+                             ],
+        "source":  "25-26 三年级上·黑龙江佳木斯·开学考试"
+    },
+    {
+        "id":  "38",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "30÷5=6，这个式子中，被除数是( ),除数是( ),商是( )。它表示把( )平均分成( )份，每份是( );也能表示( )里面有( )个( )。",
+        "options":  [
+
+                    ],
+        "answer":  "30;5;6;30;5;6;30;6;5",
+        "solution":  "【分析】根据\"被除数/除数=商\"写出除法算式的各部分对应的数;再根据两个数相除，既可以表示把一个数平均分成几份，求每一份是多少，也可以表示一个数里面有几个相同的另一个数。\n\n【详解】30÷5=6，这个式子中:30是被除数,5是除数,6是商;它既可以表示把30平均分成5份，每份是6;也能表示30里面有6个5。所以30÷5=6，这个式子中：被除数是30，除数是5，商是6;它表示把30平均分成5份，每份是6;也能表示30里面有6个5。",
+        "knowledge_points":  [
+                                 "除法的初步认识"
+                             ],
+        "source":  "25-26 三年级上·黑龙江佳木斯·开学考试"
+    },
+    {
+        "id":  "39",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "把12个苹果平均分给3个小朋友，每个小朋友分( )个;如果每个小朋友分2个，可以分给( )个小朋友。",
+        "options":  [
+
+                    ],
+        "answer":  "4;6",
+        "solution":  "【分析】根据题意可知,12个苹果平均分给3个小朋友，用12除以3即可求出每个小朋友分得的个数;如果每个小朋友分2个，用12除以2即可求出可以分给几个小朋友;据此解答。\n\n【详解】12÷3=4(个),12÷2=6(个),所以把12个苹果平均分给3个小朋友，每个小朋友分4个;如果每个小朋友分2个，可以分给6个小朋友。",
+        "knowledge_points":  [
+                                 "整数平均分的意义及应用",
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "25-26 三年级上·黑龙江佳木斯·开学考试"
+    },
+    {
+        "id":  "40",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "18里面有( )个6,( )个3是15。",
+        "options":  [
+
+                    ],
+        "answer":  "3;5",
+        "solution":  "【分析】18里面有几个6，用18除以6可求得;几个3是15，就是求15里面有几个3，用15除以3可求得。\n\n【详解】18÷6=3,15÷3=5，所以18里面有3个6;5个3是15。",
+        "knowledge_points":  [
+                                 "用2~5的乘法口诀求商",
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "25-26 三年级上·黑龙江佳木斯·开学考试"
+    },
+    {
+        "id":  "41",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "36÷4=( ),读作( ),表示把36平均分成( )份，每份是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "9;36除以4等于9;4;9",
+        "solution":  "【分析】根据乘法口诀：四九三十六可以计算出结果;在读除法算式时，\"/\"读作除以，按照从左到右的顺序读出算式;对于一个除法算式，表示把一个数平均分成了几份，商为每份占多少，据此解答。\n\n【详解】36÷4=9，读作36除以4等于9，表示把36平均分成4份，每份是9。",
+        "knowledge_points":  [
+                                 "除法的初步认识"
+                             ],
+        "source":  "25-26 三年级上·黑龙江佳木斯·开学考试"
+    },
+    {
+        "id":  "42",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "在一道除法算式中，除数是5，元元把除号看成了减号，结果是25，正确的结果应是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "6",
+        "solution":  "【分析】先将错就错，根据\"被减数=差+减数\"来求出被减数(求出的结果实际上是正确的被除数),然后根据\"被除数/除数=商\"来求出正确的商即可。\n\n【详解】25+5=30,30÷5=6，在一道除法算式中，除数是5，元元把除号看成了减号，结果是25，正确的结果应是6。",
+        "knowledge_points":  [
+                                 "一位数与两位数的进位加法",
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·湖北武汉·期末"
+    },
+    {
+        "id":  "43",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "15÷3=5，读作( )除以( )等于( )。",
+        "options":  [
+
+                    ],
+        "answer":  "15;3;5",
+        "solution":  "【分析】读除法算式时，从左往右读，数字是几就读作几，\"/\"读作除以，\"=\"读作等于，据此解答。\n\n【详解】15÷3=5，读作15除以3等于5。",
+        "knowledge_points":  [
+                                 "除法的初步认识"
+                             ],
+        "source":  "24-25 二年级下·云南昭通·期中"
+    },
+    {
+        "id":  "44",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "有24个○,如果每6个装1盒，可以装( )盒;如果一个盒子放8个，其余放另一个盒子，另一个盒子放( )个。",
+        "options":  [
+
+                    ],
+        "answer":  "4;16",
+        "solution":  "【分析】根据题意，用○的总个数除以每盒装的个数，即可求出可以装几盒;用○的总个数减去一个盒子放的个数，即可求出另一个盒子放几个○,据此解答。\n\n【详解】24÷6=4(盒),24-8=16(个),有24个○,如果每6个装1盒，可以装4盒;如果一个盒子放8个，其余放另一个盒子，放16个。",
+        "knowledge_points":  [
+                                 "一位数与两位数的退位减法",
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·浙江台州·期末"
+    },
+    {
+        "id":  "45",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "如果一个大图形表示20，那么其中的一个小图形表示( )。",
+        "options":  [
+
+                    ],
+        "answer":  "5",
+        "solution":  "【分析】一个大图形可以平均分成4个同样的小图形，求其中一个小图形表示多少，就是把20平均分成4份，求每份是多少，用除法列式解决即可。\n\n【详解】20÷4=5，即如果一个大图形表示20，那么其中的一个小图形表示5。",
+        "knowledge_points":  [
+                                 "整数平均分的意义及应用",
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·山东菏泽·期中"
+    },
+    {
+        "id":  "46",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "把一根18米的绳子剪成每段3米的小段，需要剪( )次。",
+        "options":  [
+
+                    ],
+        "answer":  "5",
+        "solution":  "【分析】由题意可知：用绳子总长除以每段的米数，即是段数，剪的次数=段数-1;据此解答。\n\n【详解】18÷3=6(段),6-1=5(次),把一根18米的绳子剪成每段3米的小段，需要剪5次。",
+        "knowledge_points":  [
+                                 "用6的乘法口诀求商",
+                                 "植树问题(两端都不栽)"
+                             ],
+        "source":  "24-25二年级下·河南郑州·期末"
+    },
+    {
+        "id":  "47",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "18÷3=( ),读作( ),计算时用到的乘法口诀是( )。这句乘法口诀还能写出一道除法算式是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "6;18除以3等于6;三六十八;18÷6=3",
+        "solution":  "【分析】根据题意可知：计算18÷3=( )时，想3和几相乘的积是18，商就是几;读除法算式时，依次从左往右读，\"/\"读作除以，\"=\"读作等于，数字直接读出来;可以根据乘法口诀\"三六十八\"求出商;利用该乘法口诀还可以写出的除法算式是：口诀的得数除以6等于3;据此解答。\n\n【详解】18÷3=6，读作18除以3等于6，计算时用到的乘法口诀是三六十八。这句乘法口诀还能写出一道除法算式是18÷6=3。",
+        "knowledge_points":  [
+                                 "除法的初步认识",
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·山东临沂·期末"
+    },
+    {
+        "id":  "48",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在括号里填上\"+\"\"-\"\"*\"或\"/\"。46( )53=997( )6=4218( )6=3",
+        "options":  [
+
+                    ],
+        "answer":  "+;*;/",
+        "solution":  "【分析】根据整数加减法的计算法则或表内乘法口诀来完成此题即可。\n\n【详解】46+53=99;由口诀\"六七四十二\"得,7×6=42;由口诀\"三六十八\"得,18÷6=3。",
+        "knowledge_points":  [
+                                 "两位数与两位数的不进位加法",
+                                 "7的乘法口诀及应用",
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·江西九江·期中"
+    },
+    {
+        "id":  "49",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "9个蛋糕，每3个一份，能分成( )份。",
+        "options":  [
+
+                    ],
+        "answer":  "3",
+        "solution":  "【分析】此题考查包含除法的应用。已知总数和每份的数量，求份数，用除法计算。\n\n【详解】9÷3=3(份),能分成3份。",
+        "knowledge_points":  [
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·江西九江·期中"
+    },
+    {
+        "id":  "50",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "如果☆*4=24，那么☆÷3=( )。",
+        "options":  [
+
+                    ],
+        "answer":  "2",
+        "solution":  "【分析】根据题意，用24除以4，即可求出☆是多少，再把☆÷3中的☆换成刚才算出的数，即可解答。\n\n【详解】☆*4=24,☆=24÷4=6,☆÷3=6÷3=2，如果☆*4=24，那么☆÷3=2。",
+        "knowledge_points":  [
+                                 "用2~5的乘法口诀求商",
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·江西九江·期中"
+    },
+    {
+        "id":  "51",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "计算24÷4时用的乘法口诀是( ),计算24÷8时用的乘法口诀是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "四六二十四;三八二十四",
+        "solution":  "【分析】除法算式为：被除数/除数=商，根据乘法口诀计算除法算式时，口诀中的后一个数是被除数，前两个数分别为除数和商。\n\n【详解】计算24÷4时用的乘法口诀是四六二十四，计算24÷8时用的乘法口诀是三八二十四。",
+        "knowledge_points":  [
+                                 "用6的乘法口诀求商",
+                                 "用7~9的乘法口诀求商"
+                             ],
+        "source":  "24-25二年级下·江西九江·期中"
+    },
+    {
+        "id":  "52",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "36÷6=( ),读作( )。被除数是( ),除数是( ),商是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "6;36除以6等于6;36;6;6",
+        "solution":  "【分析】根据乘法口诀求商时，口诀中后面一个数作被除数，前面两个数一个数作除数，另一个数作商。读除法算式时，依次从左往右读，\"/\"读作除以，\"=\"读作等于，数字直接读出来。在除法算式中，除号前面的数是被除数，除号后面的数是除数，等号后面的数是商。\n\n【详解】36÷6=6，读作36除以6等于6。被除数是36，除数是6，商是6。",
+        "knowledge_points":  [
+                                 "除法的初步认识",
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·江西九江·期中"
+    },
+    {
+        "id":  "53",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "从18里连续减去( )个3，结果是0。",
+        "options":  [
+
+                    ],
+        "answer":  "6",
+        "solution":  "【分析】要求18里连续减去几个3，结果是0，就是求18里面有几个3，用除法计算。\n\n【详解】18÷3=6，从18里连续减去6个3，结果是0。",
+        "knowledge_points":  [
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·湖北孝感·期中"
+    },
+    {
+        "id":  "54",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "把30个☆平均分成5份，每份是( )个。",
+        "options":  [
+
+                    ],
+        "answer":  "6",
+        "solution":  "【分析】把一个数平均分成几份，求每份是多少，用除法列式解决，故用五角星的总数量除以分成的份数，求出商即可。\n\n【详解】30÷5=6(个),即把30个☆平均分成5份，每份是6个。",
+        "knowledge_points":  [
+                                 "整数平均分的意义及应用",
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "24-25二年级下·河南信阳·期中"
+    },
+    {
+        "id":  "55",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "32÷4=8，读作:( ),这个算式表示( ),还可以表示( )。",
+        "options":  [
+
+                    ],
+        "answer":  "32除以4等于8;把32平均分成4份，每份是8;32里面有8个4",
+        "solution":  "【分析】读除法算式时，从左往右读，是几就读作几，\"/\"读作\"除以\"，\"=\"读作\"等于\";两个数相除，可以表示把一个数平均分成几份，求每份是多少，也可以表示一个数里面有几个相同的数;据此解决即可。\n\n【详解】32÷4=8，读作:32除以4等于8，这个算式表示：把32平均分成4份，每份是8，还可以表示32里面有8个4。",
+        "knowledge_points":  [
+                                 "整数平均分的意义及应用",
+                                 "除法的初步认识"
+                             ],
+        "source":  "24-25 二年级下·福建龙岩·期中"
+    },
+    {
+        "id":  "56",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "先写一句口诀，再按这句口诀写一道除法算式。口诀( ),除法算式是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "四六二十四;24÷4=6",
+        "solution":  "【分析】除法算式为：被除数/除数=商，根据乘法口诀写除法算式时，口诀中的后一个数为被除数，前两个数分别为除数和商。\n\n【详解】口诀四六二十四，除法算式是24÷4=6。(答案不唯一)",
+        "knowledge_points":  [
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·河南南阳·期中"
+    },
+    {
+        "id":  "57",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "42÷7=6，这个算式读作( ),其中除数是( ),商是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "42除以7等于6;7;6",
+        "solution":  "【分析】读除法算式时，从左往右读，是几就读作几，\"/\"读作\"除以\"，\"=\"读作\"等于\";然后根据\"被除数/除数=商\"来写出各部分对应的数即可。\n\n【详解】42÷7=6，这个算式读作:42除以7等于6，其中除数是7，商是6。",
+        "knowledge_points":  [
+                                 "除法的初步认识"
+                             ],
+        "source":  "24-25 二年级下·河北邯郸·期中"
+    },
+    {
+        "id":  "58",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在括号里填\"+\"\"-\"\"*\"或\"/\"。8( )2=47( )5=3525( )20=518( )2=20",
+        "options":  [
+
+                    ],
+        "answer":  "/;*;-;+",
+        "solution":  "【分析】根据每个等式左右两边的数量关系，通过尝试加，减，乘，除四种运算，选择能使等式成立的运算符号;据此可解。\n\n【详解】8÷2=4,7×5=35,25-20=5,18+2=20。",
+        "knowledge_points":  [
+                                 "两位数与整十数的减法",
+                                 "一位数与两位数的进位加法",
+                                 "7的乘法口诀及应用",
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·河南漯河·期中"
+    },
+    {
+        "id":  "59",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "把10个☆平均分成5份，每份有( )个☆;20里面有( )个4。",
+        "options":  [
+
+                    ],
+        "answer":  "2;5",
+        "solution":  "【分析】根据除法的意义，把一个数平均分成几份，求每份是多少，用除法计算;用20除以4，求出的商即是4的个数;据此解答。\n\n【详解】10÷5=2,20÷4=5，把10个☆平均分成5份，每份有2个☆;20里面有5个4。",
+        "knowledge_points":  [
+                                 "整数平均分的意义及应用",
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "24-25二年级下·河南漯河·期中"
+    },
+    {
+        "id":  "60",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "统计二(2)班喜欢跳绳的人数时，如果用\"正\"字记录数据，记录15名学生要写( )个正字。",
+        "options":  [
+
+                    ],
+        "answer":  "3",
+        "solution":  "【分析】用\"正\"字统计人数时，\"正\"字的每一笔表示1人,1个\"正\"字表示5人，则用总人数/每个正字表示的人数=写正字的个数。\n\n【详解】15÷5=3(个),统计二(2)班喜欢跳绳的人数时，如果用\"正\"字记录数据，记录15名学生要写3个正字。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "24-25二年级下·河南南阳·期中"
+    },
+    {
+        "id":  "61",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "如果●●=▲,20/▲=5，那么●=( ),▲=( )。",
+        "options":  [
+
+                    ],
+        "answer":  "3;4",
+        "solution":  "【分析】根据被除数/商=除数，计算出▲代表的数。再代入到●●=▲中，根据乘法口诀可得出●代表的数。\n\n【详解】20/▲=5，即20÷5=4;●●=4，根据乘法口诀二二得四可知,2×2=4。则●=2,▲=4。",
+        "knowledge_points":  [
+                                 "2的乘法口诀及应用",
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·广东潮州·期中"
+    },
+    {
+        "id":  "62",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "有15块糖，每盒装5块，需要( )个盒子。",
+        "options":  [
+
+                    ],
+        "answer":  "3",
+        "solution":  "【分析】用糖的总数除以每盒装的块数，商就是需要的盒子数量。\n\n【详解】15÷5=3(个),需要3个盒子。",
+        "knowledge_points":  [
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·广东潮州·期中"
+    },
+    {
+        "id":  "63",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "把12个苹果平均分给3个小朋友，每人分到( )个，算式是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "4;12÷3=4(个)",
+        "solution":  "【分析】根据题意可知，苹果的总个数除以平均分给小朋友的个数，等于每人分到苹果的个数，据此列式计算即可。\n\n【详解】12÷3=4(个),把12个苹果平均分给3个小朋友，每人分到4个，算式是12÷3=4(个)。",
+        "knowledge_points":  [
+                                 "整数平均分的意义及应用",
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·广东潮州·期中"
+    },
+    {
+        "id":  "64",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在括号里填\"+\"\"-\"\"*\"或\"/\"。24( )6=47( )9=6335( )5=40",
+        "options":  [
+
+                    ],
+        "answer":  "/;*;+",
+        "solution":  "【分析】算式中若等号右侧的数比左侧的数大或相等可试填\"+\"或\"*\";若等号右侧的数比左侧第一个数小，可试填\"-\"或\"/\"。一般情况下，加法和乘法运算会让得数变多或不变，减法和除法运算会让得数变少或不变。\n\n【详解】24÷6=4,7×9=63,35+5=40。",
+        "knowledge_points":  [
+                                 "一位数与两位数的进位加法",
+                                 "9的乘法口诀及应用",
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "24-25二年级下·湖南岳阳·期中"
+    },
+    {
+        "id":  "65",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "把18个苹果平均分成3份，每份有( )个苹果，列成算式是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "6;18÷3=6(个)",
+        "solution":  "【分析】把一个数平均分成几份，求每份是几，用除法计算，即苹果的总个数/平均分成的份数=每份有几个苹果。\n\n【详解】18÷3=6(个),把18个苹果平均分成3份，每份有6个苹果，列成算式是18÷3=6(个)。",
+        "knowledge_points":  [
+                                 "整数平均分的意义及应用",
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·福建福州·期中"
+    },
+    {
+        "id":  "66",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "10÷5=2，读作( ),表示把( )平均分成( )份，每份是( );也可以表示10里有( )个5。",
+        "options":  [
+
+                    ],
+        "answer":  "10除以5等于2;10;5;2;2",
+        "solution":  "【分析】除法算式为被除数/除数=商，要从左往右读，数字直接读出来，\"/\"读作除以，\"=\"读作等于。除法算式表示把被除数平均分成除数的份数，商是每份的数，也可以表示被除数里有商个数的除数。\n\n【详解】10÷5=2，读作10除以5等于2，表示把10平均分成5份，每份是2;也可以表示10里有2个5。",
+        "knowledge_points":  [
+                                 "整数平均分的意义及应用",
+                                 "除法的初步认识"
+                             ],
+        "source":  "24-25 二年级下·湖南邵阳·期中"
+    },
+    {
+        "id":  "67",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "根据算式5×6=30填一填:30÷5=( ),30÷6=( )。",
+        "options":  [
+
+                    ],
+        "answer":  "6;5",
+        "solution":  "【分析】在乘法算式中：口诀中的前两个数，分别是算式中的两个乘数，口诀的得数，是算式中的积;在除法算式中：口诀的得数，是算式中的被除数，口诀中的前两个数，分别是算式中的除数和商;5×6=30用到的口诀是：五六三十;据此可解。\n\n【详解】根据算式5×6=30填一填:30÷5=6,30÷6=5。",
+        "knowledge_points":  [
+                                 "6的乘法口诀及应用",
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·甘肃临夏·期中"
+    },
+    {
+        "id":  "68",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "24÷4=6，表示把24平均分成( )份，每份是( );也可以表示24里面有( )个4。",
+        "options":  [
+
+                    ],
+        "answer":  "4;6;6",
+        "solution":  "【分析】两个数相除，既可以表示把一个数平均分成若干份，求每份是多少;也可以表示一个数里面有几个相同的数;据此解答即可。\n\n【详解】24÷4=6，表示把24平均分成4份，每份是6;也可以表示24里面有6个4。",
+        "knowledge_points":  [
+                                 "整数平均分的意义及应用",
+                                 "除法的初步认识"
+                             ],
+        "source":  "24-25二年级下·黑龙江佳木斯·期末"
+    },
+    {
+        "id":  "69",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "判断题",
+        "difficulty":  0.65,
+        "question":  "一根长12厘米的绳子，对折再对折，每段长6厘米。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】由题意得，一根绳子对折后，这根绳子被平均分成了2段。把这根绳子再对折，这根绳子被平均分成了4段。这根绳子长12厘米，直接用12厘米除以4即可算出每段绳子的长度。\n\n【详解】12÷4=3(厘米),即每段绳子长3厘米。原题说法错误。故答案为: ×",
+        "knowledge_points":  [
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "24-25三年级上·湖南益阳·期中"
+    },
+    {
+        "id":  "70",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "把25个苹果分成5份，每份一定是5个。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】把25个苹果分成5份，没有说明是平均分，根据平均分的意义，只有平均分时每份的数量才相等;如果不是平均分，每一份的数量可能不同;即把25个苹果平均分成5份，每份一定是5个，说法才正确，据此判断。\n\n【详解】由分析可得：把25个苹果分成5份，因为不确定是否为平均分，所以每份不一定是5个，所以原题说法错误。故答案为: ×",
+        "knowledge_points":  [
+                                 "整数平均分的意义及应用"
+                             ],
+        "source":  "24-25 二年级下·山东菏泽·期末"
+    },
+    {
+        "id":  "71",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "把9个桃分给3只猴子，每只猴子一定分到3个。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】把9个桃分给3只猴子，没有说明是平均分，根据平均分的意义，只有平均分时每份的数量才相等;如果不是平均分，每份的数量可能不相等;即把9个桃平均分给3只猴子，每只猴子一定分到3个，说法才正确，据此判断。\n\n【详解】把9个桃分给3只猴子，因为没有确定是否为平均分，所以每只猴子不一定分到3个，原题说法错误。故答案为: ×",
+        "knowledge_points":  [
+                                 "整数平均分的意义及应用"
+                             ],
+        "source":  "24-25 二年级下·广东汕头·期末"
+    },
+    {
+        "id":  "72",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "根据乘法口诀都可以写出2道乘法算式和2道除法算式。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】根据表内乘法口诀，结合题干要求。例如：二二得四，可以得出2×2=4,4÷2=2,1道乘法算式和1道除法算式。\n\n【详解】据分析可知：二二得四只能写出2×2=4,4÷2=2,1道乘法算式和1道除法算式。原题说法错误。故答案为: ×",
+        "knowledge_points":  [
+                                 "2的乘法口诀及应用",
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·广东江门·期末"
+    },
+    {
+        "id":  "73",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "计算36÷6与4个9相加的和是多少时，都可以用同一句口诀来计算。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】计算36÷6时，用口诀\"六六三十六\";乘法运算是求几个相同加数的和的简便运算，所以计算4个9相加的和是多少，根据乘法的意义4×9进行计算，用口诀\"四九三十六\"，据此解答。\n\n【详解】由\"六六三十六\"得:36÷6=6;由\"四九三十六\"得:4×9=36;所以计算36÷6和4×9时用的不是同一句口诀。原题说法错误。故答案为: ×",
+        "knowledge_points":  [
+                                 "9的乘法口诀及应用",
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·贵州铜仁·期末"
+    },
+    {
+        "id":  "74",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "在除法算式中，被除数一定大于除数。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】在除法算式中，被除数不一定都大于除数，例如:3÷3=1,6÷6=1，被除数和除数相等;据此可判断。\n\n【详解】由分析可得：在除法算式中，被除数不一定都大于除数。故答案为: ×",
+        "knowledge_points":  [
+                                 "除法的初步认识",
+                                 "用2~5的乘法口诀求商",
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·云南昭通·期中"
+    },
+    {
+        "id":  "75",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "判断题",
+        "difficulty":  0.65,
+        "question":  "小明将12个胡萝卜分给四只小兔，每只小兔一定有3个。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】把一些物品分成几份，每份分得同样多，叫平均分。将12个胡萝卜平均分给四只小兔，每只小兔分到3个。12个胡萝卜若不是平均分给四只小兔，每只小兔不一定都有3个;如：一只分2个，一只分3个，一只分3个，一只分4个。\n\n【详解】由分析可知：将12个胡萝卜分给四只小兔，每只小兔不一定都有3个;原题说法错误。故答案为: ×",
+        "knowledge_points":  [
+                                 "整数平均分的意义及应用"
+                             ],
+        "source":  "24-25二年级下·湖南张家界·期末"
+    },
+    {
+        "id":  "76",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "明明有12颗糖果，想分给3个好朋友，每人一定分4颗。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】题目中明明要将12颗糖果分给3个好朋友，但未明确说明是\"平均分\"。根据除法的定义，只有平均分时每人才能分到相同的数量。若分法不平均，每人分到的数量可能不同，因此结论不成立。\n\n【详解】题目未限定\"平均分\"，因此分法有多种可能。例如：明明可以给第一个朋友5颗，第二个朋友3颗，第三个朋友4颗，此时每人分到的数量不相等。只有当明确要求平均分时，每人才能分到12÷3=4(颗)。明明有12颗糖果，想平均分给3个好朋友，每人一定分4颗。原题说法错误。故答案为: ×",
+        "knowledge_points":  [
+                                 "整数平均分的意义及应用",
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·湖北黄冈·期末"
+    },
+    {
+        "id":  "77",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "判断题",
+        "difficulty":  0.65,
+        "question":  "口诀\"三三得九\"只能计算一个乘法算式和一个除法算式。( )",
+        "options":  [
+
+                    ],
+        "answer":  "√",
+        "solution":  "【分析】\"三三得九\"对应的乘法算式为3×3=9，由于两个因数相同，无法写出不同的乘法算式。除法算式为9÷3=3，同样只能写出一个。\n\n【详解】题目中\"只能计算一个乘法算式和一个除法算式\"的说法正确。故答案为:√",
+        "knowledge_points":  [
+                                 "3的乘法口诀及应用",
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "24-25二年级下·河南南阳·期中"
+    },
+    {
+        "id":  "78",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "所有乘法口诀都可以写出两道不同的除法算式。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】根据乘法口诀写出除法算式时，若口诀中的两个乘数不同，可写出两道不同的算式;但若两个乘数相同，只能写出一道算式。由此进行判断即可解答。\n\n【详解】乘法口诀不一定都可以写出两道不同的除法算式，原说法错误。故答案为: ×",
+        "knowledge_points":  [
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·江西九江·期末"
+    },
+    {
+        "id":  "79",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "判断题",
+        "difficulty":  0.65,
+        "question":  "把15个☆平均分成5份，每份是3个。( )",
+        "options":  [
+
+                    ],
+        "answer":  "√",
+        "solution":  "【分析】根据除法的意义,☆的总数量/分成的份数=每一份中☆的数量，由此列出算式算出答案即可解答。\n\n【详解】15÷5=3，所以，把15个☆平均分成5份，每份是3个，说法正确。故答案为:√",
+        "knowledge_points":  [
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·山东济宁·期末"
+    },
+    {
+        "id":  "80",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "在12÷3=4中,3是被除数,12是除数。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】在除法算式\"被除数/除数=商\"中，除号前面的数是被除数，后面的数是除数，等号后面的数是商，由此解答。\n\n【详解】在12÷3=4中,12是被除数,3是除数,4是商。原题说法错误。故答案为: ×",
+        "knowledge_points":  [
+                                 "除法的初步认识"
+                             ],
+        "source":  "24-25 二年级下·河南南阳·期中"
+    },
+    {
+        "id":  "81",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "8÷2=4表示8里面有2个4。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】除法算式中，被除数表示总数，除数表示平均分成的份数，商表示每份的数量;或者被除数表示总数，除数表示每份的数量，商表示平均分成的份数。\n\n【详解】8÷2=4表示把8平均分成2份，每份是4;或表示8里面有4个2，而非\"8里面有2个4\"。原题说法错误。故答案为: ×",
+        "knowledge_points":  [
+                                 "除法的初步认识",
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·河南南阳·期中"
+    },
+    {
+        "id":  "82",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "求8里有几个4，列式为8÷2=4。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】求一个数里面有几个另一个数，用这个数除以另一个数计算即可;据此解答。\n\n【详解】8÷4=2，求8里有几个4，列式为8÷4=2。故答案为: ×",
+        "knowledge_points":  [
+                                 "整数平均分的意义及应用",
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "24-25二年级下·湖南邵阳·期末"
+    },
+    {
+        "id":  "83",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "判断题",
+        "difficulty":  0.65,
+        "question":  "把18根香蕉分给6个小朋友，每人一定会分到3根。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】当把18根香蕉平均分给6个小朋友，每人一定会分到3根，但题目中并未说明分法是\"平均分\"，因此实际分配时可能存在不同的分法，导致每人分到的数量不一定都是3根。\n\n【详解】根据题意，将18根香蕉分给6个小朋友，若未明确要求\"平均分\"，则分配方式有多种可能。例如：可能有小朋友分到2根，另一个分到4根，其余4个小朋友各分到3根，总根数仍为18。因此，\"每人一定会分到3根\"的结论不一定成立。故答案为: ×",
+        "knowledge_points":  [
+                                 "整数平均分的意义及应用"
+                             ],
+        "source":  "24-25二年级下·江西九江·期末"
+    },
+    {
+        "id":  "84",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "45÷5=9表示把45分成5份。每份是9。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】除法算式为：被除数/除数=商，可以表示把被除数平均分成除数的份数，商是每份的数，由此解答。\n\n【详解】45÷5=9表示把45平均分成5份。每份是9，题干未说明是平均分，所以说法错误。故答案为: ×",
+        "knowledge_points":  [
+                                 "整数平均分的意义及应用"
+                             ],
+        "source":  "24-25二年级下·江西赣州·期末"
+    },
+    {
+        "id":  "85",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "判断题",
+        "difficulty":  0.65,
+        "question":  "在除法算式里，被除数一定大于商。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】在除法算式中，被除数是否一定大于商，需考虑除数的大小。当除数等于1时，被除数等于商;当除数大于1时，商小于被除数。\n\n【详解】当除数为1时,5÷1=5，被除数5等于商5;当除数为5时,5÷5=1，被除数5大于商1。以上反例说明被除数不一定大于商，因此原题说法错误。故答案为: ×",
+        "knowledge_points":  [
+                                 "乘，除法的意义和各部分间的关系"
+                             ],
+        "source":  "24-25 二年级下·湖北黄冈·期末"
+    },
+    {
+        "id":  "86",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "把30个小蛋糕分成6份，每份是30÷6=5(个)。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】根据题意，把30个小蛋糕分成6份，没有说明是平均分成6份;若分法不平均，每份的数量可能不同，因此，每份不一定是5个;据此判断。\n\n【详解】把30个小蛋糕分成6份，在没有说明是平均分的前提下，每份的数量不一定相等，所以原题说法错误。故答案为: ×",
+        "knowledge_points":  [
+                                 "整数平均分的意义及应用",
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "23-24 二年级下·云南昭通·期末"
+    },
+    {
+        "id":  "87",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "16÷4读作十六除四。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】除法算式读作：几除以几等于几，据此结合题干要求进行解答即可。\n\n【详解】16÷4读作：十六除以四，所以原题说法错误。故答案为: ×",
+        "knowledge_points":  [
+                                 "除法的初步认识"
+                             ],
+        "source":  "24-25 二年级下·广西玉林·期中"
+    },
+    {
+        "id":  "88",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "计算题",
+        "difficulty":  0.85,
+        "question":  "看图列式计算。",
+        "options":  [
+
+                    ],
+        "answer":  "15÷5=3(米)",
+        "solution":  "【分析】从图上可得：将15米平均分成5份，要求每份表示多少米，根据除法的意义，用15÷5进行解答即可。\n\n【详解】15÷5=3(米),所以每份表示3米。",
+        "knowledge_points":  [
+                                 "图文问题",
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·广东潮州·期末"
+    },
+    {
+        "id":  "89",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "购物.\n(1)用买一顶帽子的钱可以买几双拖鞋。\n(2)用50元买了一个灯笼后，剩下的钱可以买几条毛巾。",
+        "options":  [
+
+                    ],
+        "answer":  "4;6",
+        "solution":  "【分析】(1)根据题意可知：用帽子的钱数除以一双拖鞋的钱数即可求出可以买几双拖鞋.\n(2)根据题意可知：用50元减去一个灯笼的钱数，求出还剩的钱数，用还剩的钱数除以一条毛巾的钱数即可求出可以买的毛巾的条数。\n\n【详解】(1)24÷6=4(双),答：用买一顶帽子的钱可以买4双拖鞋。(2)50-20=30(元),30÷5=6(条),答：剩下的钱可以买6条毛巾。",
+        "knowledge_points":  [
+                                 "整十数之间的加减法",
+                                 "用2~5的乘法口诀求商",
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·云南文山·期末"
+    },
+    {
+        "id":  "90",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "水果店有各种各样的水果，其中梨每千克卖5元，桃子每千克卖6元，优优用30元钱可以买多少千克桃子。\n口答：优优用30元钱可以买( )千克桃子。",
+        "options":  [
+
+                    ],
+        "answer":  "5;5千克",
+        "solution":  "【分析】求30元能买多少千克桃子，也就是求30里面有几个6，用除法计算，即总钱数/每千克桃子的钱数=可以买桃子的重量。\n\n【详解】30÷6=5(千克),答：优优用30元钱可以买5千克桃子。",
+        "knowledge_points":  [
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·四川南充·期末"
+    },
+    {
+        "id":  "91",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "体操社团要进行体操表演，每排站9人，一共站了4排。变换体操队形后，每排站6人，可以站几排。",
+        "options":  [
+
+                    ],
+        "answer":  "6排",
+        "solution":  "【分析】根据乘法的意义，用9×4先计算总人数，再用总人数除以变换体操队形后每排人数得到排数。\n\n【详解】9×4=36(人),36÷6=6(排),答：可以站6排。",
+        "knowledge_points":  [
+                                 "9的乘法口诀及应用",
+                                 "用7~9的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·广东汕头·期末"
+    },
+    {
+        "id":  "92",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "学校买来30个篮球，平均分给5个班，每个班分得几个篮球。",
+        "options":  [
+
+                    ],
+        "answer":  "6个",
+        "solution":  "【分析】根据题意可知,30个篮球平均分给5个班，求每个班分得几个篮球，用除法计算;据此解答。\n\n【详解】30÷5=6(个),答：每个班分得6个篮球。",
+        "knowledge_points":  [
+                                 "整数平均分的意义及应用",
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "25-26 三年级上·黑龙江佳木斯·开学考试"
+    },
+    {
+        "id":  "93",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "植树节，二(2)班要植30棵树.\n(1)分5个小组进行，平均每个小组植多少棵树。\n(2)同学们已经完成了5棵，还有多少棵树没有种。",
+        "options":  [
+
+                    ],
+        "answer":  "6;25",
+        "solution":  "【分析】(1)根据题意可知，要植树的总棵数除以分的组数，等于平均每个小组植多少棵树.\n(2)要植树的总棵数减已经完成的棵数，等于还有多少棵树没有种，据此解答。\n\n【详解】(1)30÷5=6(棵),答：平均每个小组植6棵树。(2)30-5=25(棵),答：还有25棵树没有种。",
+        "knowledge_points":  [
+                                 "整十数加，减一位数",
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·江西九江·期末"
+    },
+    {
+        "id":  "94",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "植物园成人门票原来每张12元，\"五一\"期间门票优惠,3张27元.\"五一\"期间成人门票每张多少元。每张成人门票比原来便宜多少元。",
+        "options":  [
+
+                    ],
+        "answer":  "9元;3元",
+        "solution":  "【分析】根据题意可知：用五一期间门票的总价除以票数即可求出五一期间成人门票每张的价格。然后用原来的门票价格减去五一期间的门票价格即可求出每张成人门票比原来便宜的钱数。\n\n【详解】27÷3=9(元),12-9=3(元),答：\"五一\"期间成人门票每张9元，每张成人门票比原来便宜3元。",
+        "knowledge_points":  [
+                                 "十几减9的退位减法",
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·江西九江·期末"
+    },
+    {
+        "id":  "95",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "快递员用自己的辛勤付出保障着物流的畅通.\n(1)有24个大件快递，平均分给4名快递员，每名快递员分到多少个。\n(2)2名快递员要把12个快递放到对应的货架上，其中一人放2个，另一人放几个。",
+        "options":  [
+
+                    ],
+        "answer":  "6;10",
+        "solution":  "【分析】(1)用大件快递的个数除以平均分给的快递员人数，即可求出每名快递员分到多少个.\n(2)用快递总数减去一人放的2个等于另一人放的数量。\n\n【详解】(1)24÷4=6(个),答：每名快递员分到6个。(2)12-2=10(个),答：另一人放10个。",
+        "knowledge_points":  [
+                                 "不退位减法(20以内)",
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·山东济宁·期中"
+    },
+    {
+        "id":  "96",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "张老师买了24本笔记本，每本3元，准备给每个小朋友分发6本。这些笔记本一共分给多少个小朋友。",
+        "options":  [
+
+                    ],
+        "answer":  "4个",
+        "solution":  "【分析】求可以分给几个小朋友，也就是求24里面有几个6，用除法计算，即笔记本的总数量/每个小朋友分的数量=可以分的人数。\n\n【详解】24÷6=4(个),答：这些笔记本一共分给4个小朋友。",
+        "knowledge_points":  [
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·山东临沂·期中"
+    },
+    {
+        "id":  "97",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "王阿姨一共摘了20个南瓜，把这些南瓜平均装在4个筐里，每筐应装几个。",
+        "options":  [
+
+                    ],
+        "answer":  "5个",
+        "solution":  "【分析】由题意可知：用王阿姨一共摘的南瓜数，除以筐数，即是每筐应装的个数;据此解答。\n\n【详解】20÷4=5(个),每筐应装5个。",
+        "knowledge_points":  [
+                                 "整数平均分的意义及应用",
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·山东济宁·期中"
+    },
+    {
+        "id":  "98",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "24名同学在操场上做游戏，每组6人，可以分成几组。",
+        "options":  [
+
+                    ],
+        "answer":  "4组",
+        "solution":  "【分析】由题意可知：用同学的总人数除以每组的人数，即是可以分的组数;据此解答。\n\n【详解】24÷6=4(组),答：可以分成4组。",
+        "knowledge_points":  [
+                                 "整数平均分的意义及应用",
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·山东济宁·期中"
+    },
+    {
+        "id":  "99",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "母亲节到了，乐乐买了4枝花送给妈妈，甜甜买了8枝同样的花，甜甜比乐乐多花了24元。甜甜花了多少钱。",
+        "options":  [
+
+                    ],
+        "answer":  "48元",
+        "solution":  "【分析】根据题意，甜甜比乐乐多买的枝数为8-4=4(枝),对应多花的24元，用除法求出每枝花的单价，再用每枝花的价钱乘甜甜买的数量计算甜甜的总花费。\n\n【详解】8-4=4(枝),24÷4=6(元),6×8=48(元),答：甜甜花了48元钱。",
+        "knowledge_points":  [
+                                 "经济问题",
+                                 "8的乘法口诀及应用",
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·河南南阳·期中"
+    },
+    {
+        "id":  "100",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "一种硫磺皂原来7元一块，现在优惠促销，买3块15元，现在每块多少元，现在每块比原来便宜多少元。",
+        "options":  [
+
+                    ],
+        "answer":  "5元;2元",
+        "solution":  "【分析】根据题意，现在的总钱数除以购买硫磺皂的数量，等于现在每块硫磺皂多少钱，用原来每块硫磺皂的钱数减去现在每块硫磺皂的钱数，等于现在每块比原来便宜多少元，据此解答。\n\n【详解】15÷3=5(元),7-5=2(元),答：现在每块5元，现在每块比原来便宜2元。",
+        "knowledge_points":  [
+                                 "7的加减法",
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "24-25二年级下·河南周口·期中"
+    },
+    {
+        "id":  "101",
+        "unit":  "第二单元 表内除法1",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "小明有18颗糖果，分给3个好朋友，每人分6颗后还剩( )颗。",
+        "options":  [
+                        "A. 0",
+                        "B. 3",
+                        "C. 6"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】根据题意可知：用小明有的数量除以小朋友的数量即可求出每人分得数量，若有余数则为还剩的数量.\n【详解】18÷3=6(颗),则每人分6颗后还剩0颗。故答案为:A",
+        "knowledge_points":  [
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "24-25二年级下·黑龙江佳木斯·期末"
+    },
+    {
+        "id":  "102",
+        "unit":  "第二单元 表内除法1",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "南南有20块糖，明明有12块糖，南南给明明( )块，两人的糖就一样多。",
+        "options":  [
+                        "A. 4",
+                        "B. 6",
+                        "C. 8"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】由题意可知：用南南糖的块数减去明明糖的块数，即是南南比明明多出的块数;把多出的一半给明明，两人的糖就一样多;据此解答.\n【详解】20-12=8(块),8÷2=4(块),南南有20块糖，明明有12块糖，南南给明明4块，两人的糖就一样多。故答案为:A",
+        "knowledge_points":  [
+                                 "两位数与两位数的退位减法",
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·重庆梁平·期末"
+    },
+    {
+        "id":  "103",
+        "unit":  "第二单元 表内除法1",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "3位同学一共捡了12个矿泉水瓶，平均每位同学捡了多少个矿泉水瓶。下面画图表示题意不正确的是( )。",
+        "options":  [
+                        "A. ![](images/c42d3ba0df164b145abeb7a19de27c7a978b5e10657863020cc4c479ac7de446.jpg)",
+                        "B. ![](images/94c8d120ff747324e73a349c67400cbc6fd54971c70893a4ec0097582e62c284.jpg)",
+                        "C. ![](images/2dc9775ddf973c81ba7178a851fc17f914db8a8391de6c949935edbd67f9c68d.jpg)"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】除法算式中，被除数表示总数，除数表示平均分成的份数，商表示每份的数量;或者被除数表示总数，除数表示每份的数量，商表示平均分成的份数。3位同学一共捡了12个矿泉水瓶，则应该平均分成3份，据此逐项分析.\n【详解】A。表示把12平均分成3份，每份可以表示每位同学捡的个数。B。表示把12平均分成3份，每份可以表示每位同学捡的个数。C。表示把12平均分成4份，不符合题意。画图表示题意不正确的是C。故答案为:C",
+        "knowledge_points":  [
+                                 "图文问题",
+                                 "整数平均分的意义及应用",
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·江西上饶·期末"
+    },
+    {
+        "id":  "104",
+        "unit":  "第二单元 表内除法1",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "买1千克香蕉需要3元钱，现有15元钱，可买( )千克的香蕉。",
+        "options":  [
+                        "A. 500",
+                        "B. 50",
+                        "C. 5"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】用总钱数除以1千克香蕉的价钱，即可求出可以买多少千克香蕉.\n【详解】15÷3=5(千克),15元钱可以买5千克香蕉。故答案为:C",
+        "knowledge_points":  [
+                                 "经济问题",
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "24-25二年级下·广东佛山·期末"
+    },
+    {
+        "id":  "105",
+        "unit":  "第二单元 表内除法1",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "把30朵小红花分给小小和她的5个好朋友，平均每人分到( )朵。",
+        "options":  [
+                        "A. 5",
+                        "B. 6",
+                        "C. 25"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】题目要求将30朵小红花平均分给小小和她的5个好朋友。首先明确总人数为1(小小)+5(好朋友)=6(人),再用总数30除以人数6，即可得到平均每人分到的数量.\n【详解】1+5=6(人),30÷6=5(朵),平均每人分到5朵。故答案为:A",
+        "knowledge_points":  [
+                                 "6的加减法",
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·重庆秀山·期末"
+    },
+    {
+        "id":  "106",
+        "unit":  "第二单元 表内除法1",
+        "question_type":  "选择题",
+        "difficulty":  0.94,
+        "question":  "把10颗糖平均分成5份，下面分法正确的一组是( )。",
+        "options":  [
+                        "A. ![](images/8902ba1b5d55139782be9be19e9144376e1f92f8e94da585bcf34ec6e8d16a3f.jpg)",
+                        "B. ![](images/e91e80608e91ff95b5264b86ddbf72f27fbabeef385521a1f5a90e22a8559a3a.jpg)",
+                        "C. ![](images/164857.png)"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】根据题意，平均分就是把一些物品分成若干份，每份分得同样多。据此解答.\n【详解】根据分析:A分成了2份，不符合题意;B。每份分得不是同样多，不符合题意;C。是平均分成5份，每份都是2颗，符合题意。故答案为:C",
+        "knowledge_points":  [
+                                 "整数平均分的意义及应用"
+                             ],
+        "source":  "24-25 二年级下·河南郑州·期中"
+    },
+    {
+        "id":  "107",
+        "unit":  "第二单元 表内除法1",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "下面问题可以用算式15÷3来解决的是( )。",
+        "options":  [
+                        "A. 每本笔记本5元,15元可以买几本笔记本。",
+                        "B. 有15本笔记本，送出3本，还剩几本。",
+                        "C. 买3本笔记本，一共花了15元，每本笔记本多少钱。"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】根据除法的意义,\u002715÷3\u0027可以表达15分成3份，每份有多少个，也可以表达15按照每个3个为1份，一共可以分成几份。找出选项中能表达相似意思，且可以列出相同算式的即可解答.\n【详解】A。每本5元,15元可以买几本。代表15里面有几个5，应列式为15÷5=3;B。送出3本后剩余本数，代表15去掉3后剩余几，应列式为15-3=12;C。3本15元，求每本价格，代表15分成3份，每份是多少，列式为15÷3=5。故答案为:C",
+        "knowledge_points":  [
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·重庆·期末"
+    },
+    {
+        "id":  "108",
+        "unit":  "第二单元 表内除法1",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "明明想买6条毛巾，买第( )种最便宜。",
+        "options":  [
+                        "A. ![](images/e56cc67ce55377d0895ca259a70aca812c437cc9329a69df46b0dc579299348c.jpg)",
+                        "B. ![](images/b27b4c160bdc2f9eee7ad26f4a39e009c935add31b4f907118f114a689fbd1e7.jpg)",
+                        "C. ![](images/5286816f87142f3ffdf72902f578529a95da1d60e07ca7f75c578ef07a67614f.jpg)"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】根据题意，前两个选项分别用要买毛巾的总数量除以每组毛巾的数量，就是要买的组数，再将每组的钱数相加就是总钱数，最后一个选项用要买毛巾的数量和每条毛巾的钱数相乘，计算出总钱数，比较钱数的多少即可解答.\n【详解】A。6÷3=2(组);20+20=40(元);B。6÷2=3(组);14+14+14=42(元);C。6×8=48(元);40\u003c42\u003c48，买A最便宜。故答案为:A",
+        "knowledge_points":  [
+                                 "100以内数的比大小",
+                                 "100以内数的连加运算",
+                                 "8的乘法口诀及应用",
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·内蒙古赤峰·期末"
+    },
+    {
+        "id":  "109",
+        "unit":  "第二单元 表内除法1",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "在校\"三好学生\"投票中，统计时用画\"正\"字记录，圆圆得25票，她得了( )个\"正\"字。",
+        "options":  [
+                        "A. 3",
+                        "B. 5",
+                        "C. 6"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】\"正\"字记录法是统计中最常用的一种方法，一个\"正\"字有5画，代表5票。圆圆的总票数除以5，求出商即为她所得\"正\"字的个数。据此解答.\n【详解】25÷5=5(个),故答案为:B",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "24-25二年级下·河北邢台·期中"
+    },
+    {
+        "id":  "110",
+        "unit":  "第二单元 表内除法1",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "将6个△平均分成3份，正确的分法是( )。",
+        "options":  [
+                        "A. ![](images/a331efb9160bf56b34100b771ae5fdea3fd828fea549ca876104fdf3932af605.jpg)",
+                        "B. ![](images/05fccc5fa5bbe86e80eae0bcce752fbb721ee9b56947a6a6fbb6e78357ebc3e3.jpg)",
+                        "C. ![](images/8fb3da611a9be794127c881d7c803d58ad1cf701b4a685bf65441e9b19a124bc.jpg)"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】在分物体时，每份分得同样多，就是平均分，据此解答.\n【详解】由分析可得:A。分成3份，每份的数量相同，是平均分;B。每份的数量不相同，一份1个，一份2个，一份3个，不是平均分;C。分成2份，每份的数量相同，是平均分，但不符合题意。故答案为:A",
+        "knowledge_points":  [
+                                 "整数平均分的意义及应用"
+                             ],
+        "source":  "24-25 二年级下·江西赣州·期末"
+    },
+    {
+        "id":  "111",
+        "unit":  "第二单元 表内除法1",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "下列口诀中，可以用来计算8÷4的是( )。",
+        "options":  [
+                        "A. 四八三十二",
+                        "B. 四四十六",
+                        "C. 二四得八"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】依据9以内的乘法口诀进行选择.\n【详解】计算8÷4用到的乘法口诀是：二四得八。故答案为:C",
+        "knowledge_points":  [
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "24-25二年级下·浙江温州·期末"
+    },
+    {
+        "id":  "112",
+        "unit":  "第二单元 表内除法1",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "下面几种说法，不能用\"18÷3=6\"表示的是( )。",
+        "options":  [
+                        "A. 把18朵花平均分成3份，每份是几朵。",
+                        "B. 每个鱼缸里养6条金鱼,3个鱼缸一共养了几条金鱼。",
+                        "C. 18个粽子，每3个放一盘，能放几盘。"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】乘法算式中，两个乘数表示每份的数量和份数，积表示总数。除法算式中，被除数表示总数，除数表示平均分成的份数，商表示每份的数量;或者被除数表示总数，除数表示每份的数量，商表示平均分成的份数。逐项分析.\n【详解】A。用\"18÷3=6\"计算;B。用\"6×3\"计算;C。用\"18÷3=6\"计算。不能用\"18÷3=6\"表示的是：每个鱼缸里养6条金鱼,3个鱼缸一共养了几条金鱼。故答案为:B",
+        "knowledge_points":  [
+                                 "6的乘法口诀及应用",
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·广西柳州·期末"
+    },
+    {
+        "id":  "113",
+        "unit":  "第二单元 表内除法1",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "下面可以用20÷4解决的数学问题有( )。①有20本故事书，分给4个同学，每人分2本，还剩几本。②每个面包4元，买20个面包需要多少钱。③有20个灯泡，每个灯座装4个灯泡，可以装几个灯座。",
+        "options":  [
+                        "A. ①③",
+                        "B. ②③",
+                        "C. ①②③",
+                        "D. ③"
+                    ],
+        "answer":  "D",
+        "solution":  "【分析】根据除法的意义,20÷4=5表示把20平均分成4份，求每份是几(每份是5),还可以表示把20每4个一份，求分成了几份(分成了5份);根据除法的意义，逐项分析每个问题，找出能用除法的意义解决的问题;据此解答.\n【详解】①用4个同学乘每人分的2本，就是4个人共分的本数，用总数20本减去分走的本数，就是还剩的本数;列算式为:20-4×2=20-8=12(本),不是除法的意义;故和题意不相符;②根据题意,20个4相加才能算出买20个面包需要的钱数，用乘法或连加计算，不属于除法的意义;故和题意不相符;③根据除法的意义，用20个灯泡除以每个灯座装的4个，就是可以装的灯座数，算式是:20÷4=5(个),可以装5个灯座;故和题意相符。可以用20÷4解决的数学问题有③;故答案选:D",
+        "knowledge_points":  [
+                                 "整数平均分的意义及应用",
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "23-24 二年级下·广东揭阳·期末"
+    },
+    {
+        "id":  "114",
+        "unit":  "第二单元 表内除法1",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "12个同学排成2队，其中一队有4人，另一个队有几人。正确的算式是( )。",
+        "options":  [
+                        "A. 12-4",
+                        "B. 12÷2",
+                        "C. 12÷4"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】根据题意，用总人数-其中一队的人数=另一队的人数，据此解答.\n【详解】12-4=8(人),另一队有8人。故答案为:A",
+        "knowledge_points":  [
+                                 "不退位减法(20以内)",
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "24-25 一年级下·广西柳州·期末"
+    },
+    {
+        "id":  "115",
+        "unit":  "第二单元 表内除法1",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "一盒药共有24片，每天吃3次，每次吃2片，这盒药可以吃( )天。",
+        "options":  [
+                        "A. 6",
+                        "B. 4",
+                        "C. 2"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】先计算每天消耗的药片数，再用总片数除以每天消耗量，得出天数.\n【详解】2×3=6(片),24÷6=4(天),这盒药可以吃4天。故答案为:B",
+        "knowledge_points":  [
+                                 "3的乘法口诀及应用",
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·山东济南·期中"
+    },
+    {
+        "id":  "116",
+        "unit":  "第二单元 表内除法1",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "可以用15÷5=3表示的是( )。",
+        "options":  [
+                        "A. 15里面有几个3",
+                        "B. 15里边有几个5",
+                        "C. 把15平均分成3分，每份是5"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】根据除法的意义,15÷5=3可以表示两种含义:①将15平均分成5份，每份是3;②求15里面包含多少个5.\n【详解】A。15里面有几个3，对应的算式应为15÷3=5，与题目中的15÷5=3不符，此选项错误。B。15里面有几个5，对应的算式为15÷5=3，此选项正确。C。把15平均分成3份，每份是5，对应的算式应为15÷3=5，与题目中的15÷5=3不符，此选项错误。可以用15÷5=3表示的是15里边有几个5。故答案为:B",
+        "knowledge_points":  [
+                                 "整数平均分的意义及应用",
+                                 "除法的初步认识",
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·山东济南·期中"
+    },
+    {
+        "id":  "117",
+        "unit":  "第二单元 表内除法1",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "下面能用算式20÷4解决的数学问题是( )。",
+        "options":  [
+                        "A. 有20本故事书，分给4人，每人1本，还剩几本。",
+                        "B. 有20块糖果，每袋装4块，可以装几袋。",
+                        "C. 面包每个4元，买20个面包需要多少钱。"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】根据除法的意义,20÷4=5表示把20平均分成4份，求每份是几(每份是5),还可以表示把20每4个分成一份，求分成了几份(分成了5份);根据除法的意义，逐项分析每个选项，找出能用除法算式来解决的问题，即可解答.\n【详解】A。有20本故事书，分给4人，每人1本，共分4本，剩余本数为20-4=16(本),需用减法计算，此选项错误;B。有20块糖果，每袋装4块，求装袋数即求20÷4=5(袋),需要用除法计算，此选项正确;C。每个面包4元，买20个面包，每个面包的钱数乘购买面包的个数，等于需要多少钱，需用乘法计算，此选项错误。故答案为:B",
+        "knowledge_points":  [
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·湖北武汉·期末"
+    },
+    {
+        "id":  "118",
+        "unit":  "第二单元 表内除法1",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "24÷6和下面哪个算式的商不相等。( )",
+        "options":  [
+                        "A. 24÷4",
+                        "B. 12÷3",
+                        "C. 8÷2"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】根据表内除法口诀，先算出24÷6的商，再算出各个选项的得数，再进行解答即可.\n【详解】24÷6=4,A。24÷4=6,B。12÷3=4,C。8÷2=4，所以24÷6和24÷4的商不相等。故答案为:A",
+        "knowledge_points":  [
+                                 "用2~5的乘法口诀求商",
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "24-25二年级下·山东日照·期中"
+    },
+    {
+        "id":  "119",
+        "unit":  "第二单元 表内除法1",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "算式\"18÷3=6\"可以解决的问题是( )。",
+        "options":  [
+                        "A. 18米绳子，剪去3米，还剩多少米",
+                        "B. 小红剪了18朵纸花，小敏剪了3朵纸花，他们俩一共剪了多少朵纸花",
+                        "C. 把18块西瓜平均分给3个小朋友，每人分几块"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】算式\"18÷3=6\"可以表示平均分或求每份的数量，逐一分析选项中的每一个情境，找到符合把18分成3份求每份是多少，或把18按每份3个来分，能分成几份的情况，即可解答.\n【详解】A。18米绳子，剪去3米，还剩多少米;属于减法问题，不涉平均分或求每份的数量，不能用除法，不符合题意;B。小红剪了18朵纸花，小敏剪了3朵纸花，他们俩一共剪了多少朵纸花;求总数，属于加法问题，不涉及平均分或求每份的数量，不能用除法，不符合题意;C。把18块西瓜平均分给3个小朋友，求每人分几块;这需要用除法解决，因为是将18平均分成3份，列式为:18÷3=6(块),符合题意。故答案为:C",
+        "knowledge_points":  [
+                                 "整数平均分的意义及应用",
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·山东日照·期中"
+    },
+    {
+        "id":  "120",
+        "unit":  "第二单元 表内除法1",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "二(1)班有36人，每组6人，可以分成( )组。",
+        "options":  [
+                        "A. 5",
+                        "B. 6",
+                        "C. 7"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】求可以分成几组，也就是求36里面有几个6，用除法计算，即总人数/每组的人数=可以分成的组数.\n【详解】36÷6=6(组),二(1)班有36人，每组6人，可以分成6组。故答案为:B",
+        "knowledge_points":  [
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·湖南湘潭·期中"
+    },
+    {
+        "id":  "121",
+        "unit":  "第二单元 表内除法1",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "24朵花，每4朵插在一个花瓶里，一共需要几个花瓶。列式为( )。",
+        "options":  [
+                        "A. 24÷4=6(个)",
+                        "B. 24÷4=3(朵)",
+                        "C. 24÷3=4(朵)"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】要求需要几个花瓶，即求24里面有几个4，根据除法的意义，用24÷4进行解答即可.\n【详解】24÷4=6(个),所以一共需要6个花瓶。故答案为:A",
+        "knowledge_points":  [
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "23-24二年级下·湖南常德·期中"
+    },
+    {
+        "id":  "122",
+        "unit":  "第二单元 表内除法1",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "下列数学问题中,( )可以用12÷2=6来解决。",
+        "options":  [
+                        "A. 有12个苹果，拿走了2个，还剩几个。",
+                        "B. 有12个苹果，放到两个盘子里，一个盘子放2个，另一个盘子放几个。",
+                        "C. 有12个苹果，放在2个盘子里，每个盘子放几个。",
+                        "D. 有12个苹果，每个盘子放2个，可以放在几个盘子里。"
+                    ],
+        "answer":  "D",
+        "solution":  "【分析】除法算式为：被除数/除数=商，可以表示把被除数平均分成除数的份数，商是每份的数;也可以表示被除数里有商个数的除数，由此解答.\n【详解】A。求还剩几个，用减法计算，列式为12-2=10(个),不符合题意;B。求另一个盘子放的数量，用减法计算，列式为12-2=10(个),不符合题意;C。没有说明是不是平均放在2个盘子里，则每个盘子里放的数量不一定，不能用除法计算，不符合题意;D。求可以放在几个盘子里，用除法计算，列式为12÷2=6(个),符合题意。则可以用12÷2=6来解决的是有12个苹果，每个盘子放2个，可以放在几个盘子里。故答案为:D",
+        "knowledge_points":  [
+                                 "整数平均分的意义及应用",
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "23-24二年级下·福建龙岩·期末"
+    },
+    {
+        "id":  "123",
+        "unit":  "第二单元 表内除法1",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "关于算式18÷3=6，下列说法正确的是( )。",
+        "options":  [
+                        "A. 18除3等于6",
+                        "B. 18里面有6个3",
+                        "C. 除数是18，被除数是3，商是6",
+                        "D. 把18分成3份，每份是6个"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】被除数/除数=商，读除法算式时，依次从左往右读,\u0027/\u0027读作除以,\u0027=\u0027读作等于，数字直接读出来。除法算式中，被除数表示总数，除数表示平均分成的份数，商表示每份的数量;或者被除数表示总数，除数表示每份的数量，商表示平均分成的份数。逐项分析.\n【详解】A。读作18除以3等于6，原题说法错误。B。18里面有6个3，原题说法正确。C。被除数是18，除数是3，商是6，原题说法错误。D。把18平均分成3份，每份才是6个，原题说法错误。说法正确的是:18里面有6个3。故答案为:B",
+        "knowledge_points":  [
+                                 "整数平均分的意义及应用",
+                                 "除法的初步认识",
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "23-24 二年级下·福建龙岩·期末"
+    },
+    {
+        "id":  "124",
+        "unit":  "第二单元 表内除法1",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "24÷4表示把24平均分成4份，求每份是多少，也可以表示( )。",
+        "options":  [
+                        "A. 24里面有几个4",
+                        "B. 4个24相加是多少",
+                        "C. 24比4多多少"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】除法算式中，被除数表示总数，除数表示平均分成的份数，商表示每份的数量;或者被除数表示总数，除数表示每份的数量，商表示平均分成的份数。列出每项的算式即可求解.\n【详解】A。用24÷4计算;B。用4×24计算;C。用24-4计算。24÷4表示把24平均分成4份，求每份是多少，也可以表示24里面有几个4。故答案为:A",
+        "knowledge_points":  [
+                                 "整数平均分的意义及应用",
+                                 "除法的初步认识"
+                             ],
+        "source":  "24-25 二年级下·黑龙江佳木斯·期中"
+    },
+    {
+        "id":  "125",
+        "unit":  "第二单元 表内除法1",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "被除数除以除数，商是1，被除数与除数关系是( )。",
+        "options":  [
+                        "A. 除数\u003c被除数",
+                        "B. 除数=被除数",
+                        "C. 除数\u003e被除数"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】除法算式为被除数/除数=商，由此可举例写出商为1的算式，即可解答.\n【详解】5÷5=1;2÷2=1，则被除数除以除数，商是1，被除数与除数关系是除数=被除数。故答案为:B",
+        "knowledge_points":  [
+                                 "除法的初步认识",
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·贵州铜仁·期中"
+    },
+    {
+        "id":  "126",
+        "unit":  "第二单元 表内除法1",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "有20个苹果，每4个装一袋，可以装几袋。用( )法计算。",
+        "options":  [
+                        "A. 加",
+                        "B. 乘",
+                        "C. 除"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】求可以装几袋，也就是求20里面有几个4，用除法计算，即苹果的总数量/每袋装的数量=可以装的袋数.\n【详解】20÷4=5(袋),可以装5袋。用除法计算。故答案为:C",
+        "knowledge_points":  [
+                                 "除法的初步认识",
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "24-25二年级下·黑龙江佳木斯·期中"
+    },
+    {
+        "id":  "127",
+        "unit":  "第二单元 表内除法1",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "下面表达不正确的是( )。",
+        "options":  [
+                        "A. 8+8和8÷8表示的意思不相同。",
+                        "B. 把10分成2份，每份是5。",
+                        "C. 28÷4=7表示28里面有7个4。"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】加法算式表示一个数与另一个数的和，除法算式表示把被除数平均分成除数的份数，商是每份的数;还可以表示被除数里有商个数的除数.\n【详解】A。8+8表示2个8相加的和;8÷8表示把8平均分成8份，每份是1，两个算式表示的意思不相同，原说法正确;B。把10平均分成2份，每份是5，题中未说平均分，则每份的数不一定是5，原说法错误;C。28÷4=7表示28里面有7个4，原说法正确。则表述不正确的是把10分成2份，每份是5。故答案为:B",
+        "knowledge_points":  [
+                                 "整数平均分的意义及应用",
+                                 "除法的初步认识"
+                             ],
+        "source":  "24-25 二年级下·重庆渝中·期中"
+    },
+    {
+        "id":  "128",
+        "unit":  "第二单元 表内除法1",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "算式\"12÷3\"可以解决的问题是( )。",
+        "options":  [
+                        "A. 12米长的绳子剪去3米，还剩下多少米。",
+                        "B. 姐姐做了12朵红花，弟弟做了3朵，姐弟一共做了多少朵。",
+                        "C. 老师把12根小棒平均分给3个小朋友，每个小朋友分到多少根。"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】\"12÷3\"的运算意义核心是平均分配或求每份的数量，逐一分析选项中的每一个情境，找到符合把12分成3份求每份是多少，或把12按每份3个来分能分成几份的情况，即可解答.\n【详解】A。剪去3米，属于减法问题，不涉及平均分配，不能用除法，不符合题意;B。求总数，属于加法问题，不涉及分成几份，不能用除法，不符合题意;C。将12根小棒平均分成3份，属于除法问题，可列出算式12÷3，符合题意。故答案为:C",
+        "knowledge_points":  [
+                                 "整数平均分的意义及应用"
+                             ],
+        "source":  "23-24 二年级下·福建福州·期末"
+    },
+    {
+        "id":  "129",
+        "unit":  "第二单元 表内除法1",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "△*(☆-3)=21,△+△+△=9，则☆=( ),△=( )。",
+        "options":  [
+                        "A. 10;3",
+                        "B. 7;4",
+                        "C. 4;7",
+                        "D. 3;8"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】△+△+△=9，表示3个相同的数相加等于9,9÷3=3，可知△=3;再把△=3代入△*(☆-3)=21中，即可算出☆表示的数.\n【详解】9÷3=3，故△=3。把△=3代入△*(☆-3)=21中，得3×(☆-3)=21，所以☆-3=7,☆=10。即☆=10,△=3。故答案为:A",
+        "knowledge_points":  [
+                                 "7的乘法口诀及应用",
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "23-24 二年级下·福建龙岩·期末"
+    },
+    {
+        "id":  "130",
+        "unit":  "第二单元 表内除法1",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "除法算式中，除数是5，轩轩把除号看成了减号，结果是20，正确的商是( )。",
+        "options":  [
+                        "A. 6",
+                        "B. 4",
+                        "C. 5"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】根据题意，先用错误的结果和5相加，计算出被减数，也就是正确算式的被除数，再用被除数除以5即可解答.\n【详解】被除数:20+5=25，商:25÷5=5，正确的商是5。故答案为:C",
+        "knowledge_points":  [
+                                 "整十数加，减一位数",
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "23-24 二年级下·内蒙古鄂尔多斯·期中"
+    },
+    {
+        "id":  "131",
+        "unit":  "第二单元 表内除法1",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "明明5分钟做了25道题，红红4分钟做了24道题，丽丽3分钟做了12道题,( )做得最快。",
+        "options":  [
+                        "A. 明明",
+                        "B. 红红",
+                        "C. 丽丽"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】根据题意，分别用每人做题的数量除以做题用的时间，计算出每分钟做题的数量，再比较大小即可解答.\n【详解】明明:25÷5=5(道),红红:24÷4=6(道),丽丽:12÷3=4(道),6\u003e5\u003e4，则红红做得最快。故答案为:B",
+        "knowledge_points":  [
+                                 "用2~5的乘法口诀求商",
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "23-24二年级下·内蒙古鄂尔多斯·期中"
+    },
+    {
+        "id":  "132",
+        "unit":  "第二单元 表内除法1",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "12÷3=( ),读作( ),表示把12平均分成( )份，每份是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "4;12除以3等于4;3;4",
+        "solution":  "【分析】根据乘法口诀求商时，口诀中后一个数作被除数，前面两个数一个数作除数，另一个数作商。读除法算式时，依次从左往右读,\u0027/\u0027读作除以,\u0027=\u0027读作等于，数字直接读出来。在除法算式里，表示把被除数平均分成除数的份数，每份是商.\n【详解】根据分析可得:12÷3=4，读作12除以3等于4，表示把12平均分成3份，每份是4。",
+        "knowledge_points":  [
+                                 "整数平均分的意义及应用",
+                                 "除法的初步认识",
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·黑龙江佳木斯·期末"
+    },
+    {
+        "id":  "133",
+        "unit":  "第二单元 表内除法1",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "有24个桃子，每盘放6个，需要( )个盘子。如果平均分给4个小朋友，每个小朋友分得( )个。",
+        "options":  [
+
+                    ],
+        "answer":  "4;6",
+        "solution":  "【分析】根据除法的意义，桃子的总数/每盘放的桃子数量=需要的盘子数量，桃子的总数量/小朋友的人数=每个小朋友可以分到的数量，列出算式算出答案即可解答.\n【详解】24÷6=4(个),24÷4=6(个),所以，有24个桃子，每盘放6个，需要4个盘子。如果平均分给4个小朋友，每个小朋友分得6个。",
+        "knowledge_points":  [
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "24-25二年级下·黑龙江佳木斯·期末"
+    },
+    {
+        "id":  "134",
+        "unit":  "第二单元 表内除法1",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "一道除法算式，被除数是30，除数是5，商是( ),这个算式读作( )。",
+        "options":  [
+
+                    ],
+        "answer":  "6;30除以5等于6",
+        "solution":  "【分析】在除法算式中，被除数/除数=商，除法算式从左往右读，数字直接读出,\u0027/\u0027读作除以,\u0027=\u0027读作等于;据此解答.\n【详解】30÷5=6，一道除法算式，被除数是30，除数是5，商是6，这个算式读作30除以5等于6。",
+        "knowledge_points":  [
+                                 "除法的初步认识",
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·贵州铜仁·期末"
+    },
+    {
+        "id":  "135",
+        "unit":  "第二单元 表内除法1",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "计算12÷2=( )时，想乘法口诀( ),商是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "6;二六十二;6",
+        "solution":  "【分析】计算12÷2时，根据除法的意义，可以想2乘几等于12，对应的乘法口诀是\u0027二六十二\u0027,因此商是6，据此解答即可.\n【详解】根据乘法口诀\u0027二六十二\u0027可知:12÷2=6，所以商是6。",
+        "knowledge_points":  [
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·广东汕尾·期末"
+    },
+    {
+        "id":  "136",
+        "unit":  "第二单元 表内除法1",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "妈妈的手机锁屏密码是由□□□□△△组成的一个六位数，满足以下数量关系:□+□+□+□=24,△+△=6。妈妈的手机锁屏密码是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "666633",
+        "solution":  "【分析】由题意可知：先分别算出□和△所表示的数，即能算出妈妈手机锁屏密码;□+□+□+□=24,4个□是24,24÷4=6,□是6;△+△=6,2个△是6,6÷2=3,△是3;【详解】□□□□△△组成的六位数是:666633，妈妈的手机锁屏密码是666633。",
+        "knowledge_points":  [
+                                 "用2~5的乘法口诀求商",
+                                 "用6的乘法口诀求商",
+                                 "乘，除法的意义和各部分间的关系"
+                             ],
+        "source":  "24-25 二年级下·福建莆田·期末"
+    },
+    {
+        "id":  "137",
+        "unit":  "第二单元 表内除法1",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "如图,1个苹果和( )个草莓同样重.\n![](images/7bbe9d1c2a69afd334d0e72c11c51dd21cea0b401f498e51ce0436c84b42ee4e.jpg)",
+        "options":  [
+
+                    ],
+        "answer":  "3",
+        "solution":  "【分析】由图可知，天平保持水平，说明天平两边一样重，即3个苹果=9个草莓，求1个苹果和几个草莓同样重，就是求9里面有几个3，用除法计算即可.\n【详解】9÷3=3(个),1个苹果和3个草莓同样重。",
+        "knowledge_points":  [
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·山西长治·期中"
+    },
+    {
+        "id":  "138",
+        "unit":  "第二单元 表内除法1",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "18÷3=6，读作( ),其中18是( ),3是( ),6是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "18除以3等于6;被除数;除数;商",
+        "solution":  "【分析】在除法算式中，被除数/除数=商，除法算式从左往右读，数字直接读出,\u0027/\u0027读作除以,\u0027=\u0027读作等于;\u0027/\u0027前面的数是被除数,\u0027/\u0027后面的数是除数,\u0027=\u0027后面的数是商.\n【详解】18÷3=6，读作18除以3等于6，其中18是被除数,3是除数,6是商。",
+        "knowledge_points":  [
+                                 "除法的初步认识"
+                             ],
+        "source":  "24-25 二年级下·黑龙江佳木斯·期中"
+    },
+    {
+        "id":  "139",
+        "unit":  "第二单元 表内除法1",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "24÷6=( ),表示把24平均分成( )份，每份是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "4;6;4",
+        "solution":  "【分析】根据口诀四六二十四，及除法的平均分进行填空即可.\n【详解】24÷6=4，表示把24平均分成6份，每份是4。",
+        "knowledge_points":  [
+                                 "整数平均分的意义及应用",
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·湖南长沙·期末"
+    },
+    {
+        "id":  "140",
+        "unit":  "第二单元 表内除法1",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "15÷3=5，可以表示把15平均分成( )份，每份是( );也可以表示15里面有( )个( )。",
+        "options":  [
+
+                    ],
+        "answer":  "3;5;5;3",
+        "solution":  "【分析】根据除法的意义，把一个数平均分成若干份，求其中的一份是多少;求一个数里面有几个另一个数，都用除法计算，据此解答.\n【详解】15÷3=5，可以表示把15平均分成3份，每份是5;也可以表示15里面有5个3。",
+        "knowledge_points":  [
+                                 "整数平均分的意义及应用"
+                             ],
+        "source":  "24-25 二年级下·四川乐山·期末"
+    },
+    {
+        "id":  "141",
+        "unit":  "第二单元 表内除法1",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "12朵花，平均放在6个瓶子里，每瓶放( )朵;如果每瓶放4朵，需要( )个瓶子。",
+        "options":  [
+
+                    ],
+        "answer":  "2;3",
+        "solution":  "【分析】要求将12朵花平均放在6个瓶子里，每瓶放几朵，即求12里面有几个6，根据除法的意义，用12÷6进行解答即可。若每瓶放4朵，需要几个瓶子，即求12里面有几个4，根据除法的意义，用12÷4进行解答即可.\n【详解】12÷6=2(朵),所以每瓶放2朵。12÷4=3(个),所以需要3个瓶子。",
+        "knowledge_points":  [
+                                 "用2~5的乘法口诀求商",
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·河南郑州·期中"
+    },
+    {
+        "id":  "142",
+        "unit":  "第二单元 表内除法1",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "一只青蛙4条腿,2只眼睛,1张嘴。10只青蛙( )张嘴;( )只青蛙24条腿;6只青蛙( )只眼睛。",
+        "options":  [
+
+                    ],
+        "answer":  "10;6;12",
+        "solution":  "【分析】一只青蛙1张嘴，几只青蛙就有几张嘴;一只青蛙4条腿，求几只青蛙24条腿，就是求24里面有几个4，用除法列式解决;1只青蛙2只眼睛，求6只青蛙几只眼睛，就是6个2的和是多少，用乘法列式解决.\n【详解】24÷4=6(只),2×6=12(只),一只青蛙4条腿2只眼睛1张嘴,10只青蛙10张嘴;6只青蛙24条腿;6只青蛙12只眼睛。",
+        "knowledge_points":  [
+                                 "6的乘法口诀及应用",
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·山西长治·期中"
+    },
+    {
+        "id":  "143",
+        "unit":  "第二单元 表内除法1",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在括号里填上\u0027+\u0027,\u0027-\u0027,\u0027*\u0027或\u0027/\u0027。8( )2=625( )5=306( )6=19( )9=81",
+        "options":  [
+
+                    ],
+        "answer":  "-;+;/;*",
+        "solution":  "【分析】根据整数加减法计算法则，表内乘法口诀及表内除法来解决此题。8可以分成2和6，用减法计算;25和5合起来是30，用加法计算;根据乘法口诀一六得六可知，用除法计算;根据乘法口诀九九八十一可知，用乘法计算.\n【详解】8-2=6,25+5=30,6÷6=1,9×9=81。",
+        "knowledge_points":  [
+                                 "一位数与两位数的进位加法",
+                                 "9的乘法口诀及应用",
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·浙江杭州·期中"
+    },
+    {
+        "id":  "144",
+        "unit":  "第二单元 表内除法1",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "在括号里填上合适的数。24÷( )=4 ( )×6=1835-29=( )÷( )",
+        "options":  [
+
+                    ],
+        "answer":  "6;3;6;1",
+        "solution":  "【分析】乘法算式中两个乘数是口诀中的前两个数，积是口诀中的后一个数，写算式时两个乘数可互换位置。根据乘法口诀求商时，口诀中的后一个数作为被除数，前面两个数一个作除数另一个作商。减法计算时，相同数位对齐，从个位减起，哪一位不够减就向前一位借1当十，和本位上的数合并在一起，再减.\n【详解】四六二十四，则24÷6=4。三六十八，则3×6=18.35-29=6,6÷1=6，则35-29=6÷1。",
+        "knowledge_points":  [
+                                 "两位数与两位数的退位减法",
+                                 "6的乘法口诀及应用",
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·湖北襄阳·期中"
+    },
+    {
+        "id":  "145",
+        "unit":  "第二单元 表内除法1",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "有一堆书，平均分给4名同学，或者平均分给6名同学，都正好分完。这堆书最少有( )本。",
+        "options":  [
+
+                    ],
+        "answer":  "12",
+        "solution":  "【分析】平均分给4名同学，或者平均分给6名同学，都正好分完，即这堆书最少的本数即为4和6的最小的倍数，据此解答即可.\n【详解】4的倍数有4,8,12。6的倍数有6,12,18。12÷4=3(本),12÷6=2(本),所以这堆书最少有12本。",
+        "knowledge_points":  [
+                                 "用2~5的乘法口诀求商",
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·湖北武汉·期中"
+    },
+    {
+        "id":  "146",
+        "unit":  "第二单元 表内除法1",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "每3根小棒摆一个三角形，用18根小棒能摆( )个独立的三角形。",
+        "options":  [
+
+                    ],
+        "answer":  "6",
+        "solution":  "【分析】求可以摆几个独立的三角形，也就是求18里面有几个3，用除法计算，即小棒的总数量/摆一个三角形用小棒的数量=可以摆三角形的数量.\n【详解】18÷3=6(个),每3根小棒摆一个三角形，用18根小棒能摆6个独立的三角形。",
+        "knowledge_points":  [
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "24-25二年级下·河北邯郸·期中"
+    },
+    {
+        "id":  "147",
+        "unit":  "第二单元 表内除法1",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "把18颗糖平均分给3个小朋友，每人分到( )颗，算式是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "6;18÷3=6(颗)",
+        "solution":  "【分析】把一个数平均分成若干份，求每一份是多少，用除法列式解决;则用糖的总数量/小朋友的数量=每人分到的糖数量.\n【详解】18÷3=6(颗),即把18颗糖平均分给3个小朋友，每人分到6颗，算式是18÷3=6(颗)。",
+        "knowledge_points":  [
+                                 "整数平均分的意义及应用",
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·湖南湘潭·期中"
+    },
+    {
+        "id":  "148",
+        "unit":  "第二单元 表内除法1",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "35÷5=7，这个算式读作( ),表示把( )平均分成( )份，每份是( ),其中35在除法算式中叫( ),5在除法算式中叫( )。",
+        "options":  [
+
+                    ],
+        "answer":  "35除以5等于7;35;5;7;被除数;除数",
+        "solution":  "【分析】除法算式从左往右读，数字直接读出,\u0027/\u0027读作除以,\u0027=\u0027读作等于;除法算式中,\u0027/\u0027前面的数是被除数,\u0027/\u0027后面的数是除数,\u0027=\u0027后面的数是商;除法算式表示把被除数平均分成除数的份数，商是每份的数.\n【详解】35÷5=7，这个算式读作35除以5等于7，表示把35平均分成5份，每份是7，其中35在除法算式中叫被除数,5在除法算式中叫除数。",
+        "knowledge_points":  [
+                                 "除法的初步认识"
+                             ],
+        "source":  "24-25二年级下·湖北武汉·期中"
+    },
+    {
+        "id":  "149",
+        "unit":  "第二单元 表内除法1",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "8÷2=4读作( ),其中被除数是( ),除数是( ),商是( ),用到的乘法口诀是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "8除以2等于4;8;2;4;二四得八",
+        "solution":  "【分析】从左往右按照顺序读出算式，数字直接读出来,\u0027/\u0027读作\u0027除以\u0027,\u0027=\u0027读作\u0027等于\u0027,除号前面的数叫被除数，除号后面的数叫除数，结果叫商，根据乘法口诀求商时，口诀中后一个数作被除数，前面两个数一个数作除数，另一个数作商，用的口诀是二四得八.\n【详解】根据分析可得:8÷2=4读作8除以2等于4，其中被除数是8，除数是2，商是4，用到的乘法口诀是二四得八。",
+        "knowledge_points":  [
+                                 "除法的初步认识",
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "23-24 二年级下·河南信阳·期末"
+    },
+    {
+        "id":  "150",
+        "unit":  "第二单元 表内除法1",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "把18个苹果平均分给6个小朋友，每人分( )个，算式是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "3;18÷6=3(个)",
+        "solution":  "【分析】把一个数平均分成几份，求每份的数，用除法计算，即苹果的总数量/平均分的人数=每人分苹果的个数.\n【详解】把18个苹果平均分给6个小朋友，每人分3个，算式是18÷6=3(个)。",
+        "knowledge_points":  [
+                                 "整数平均分的意义及应用",
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "24-25 一年级下·湖南岳阳·期中"
+    },
+    {
+        "id":  "151",
+        "unit":  "第二单元 表内除法1",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "妈妈买了一些苹果，个数比20个多，比30个少。若全家每天吃5个正好吃完，则妈妈一共买了( )个苹果，共吃了( )天。",
+        "options":  [
+
+                    ],
+        "answer":  "25;5",
+        "solution":  "【分析】找出5的乘法口诀中积在20到30之间的算式，这个积就是妈妈买的苹果个数。用总数除以每天吃的个数即可求出共吃了多少天.\n【详解】五五二十五,20\u003c25\u003c30,25÷5=5(天),妈妈一共买了25个苹果，共吃了5天。",
+        "knowledge_points":  [
+                                 "5的乘法口诀及应用",
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·内蒙古赤峰·期末"
+    },
+    {
+        "id":  "152",
+        "unit":  "第二单元 表内除法1",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "如果☆+☆+☆+☆=20，那么☆=( )。",
+        "options":  [
+
+                    ],
+        "answer":  "5",
+        "solution":  "【分析】从题干可知:4个☆的和是20，要求每个☆表示多少，根据除法的意义，用20÷4进行解答即可.\n【详解】20÷4=5，如果☆+☆+☆+☆=20，那么☆=5。",
+        "knowledge_points":  [
+                                 "同数连加的应用",
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "23-24二年级下·河北邢台·期中"
+    },
+    {
+        "id":  "153",
+        "unit":  "第二单元 表内除法1",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在算式12÷3=( )中,( )是被除数,3是( ),商是( )。想口诀( )可以求出商。",
+        "options":  [
+
+                    ],
+        "answer":  "4;12;除数;4;三四十二",
+        "solution":  "【分析】除法算式为：被除数/除数=商。根据乘法口诀计算除法算式时，口诀中的后一个数是被除数，前两个数分别为除数和商.\n【详解】在算式12÷3=4中,12是被除数,3是除数，商是4。想口诀三四十二可以求出商。",
+        "knowledge_points":  [
+                                 "除法的初步认识",
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "23-24 二年级下·内蒙古通辽·期中"
+    },
+    {
+        "id":  "154",
+        "unit":  "第二单元 表内除法1",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "27÷3=9，读作:( ),表示把27平均分成( )份，每份是( );还表示27里面有( )个( )。",
+        "options":  [
+
+                    ],
+        "answer":  "27除以3等于9;3;9;9;3",
+        "solution":  "【分析】读除法算式时，依次从左往右读,\u0027/\u0027读作除以,\u0027=\u0027读作等于，数字直接读出来;表示把被除数平均分成除数的份数，每份是商，还可以表示被除数里面有商个除数，据此解答.\n【详解】27÷3=9，读作:27除以3等于9，表示把27平均分成3份，每份是9;还表示27里面有9个3。",
+        "knowledge_points":  [
+                                 "整数平均分的意义及应用",
+                                 "除法的初步认识"
+                             ],
+        "source":  "24-25 二年级下·山东日照·期中"
+    },
+    {
+        "id":  "155",
+        "unit":  "第二单元 表内除法1",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "算式12÷3=4读作( ),算式中被除数是( ),除数是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "12除以3等于4;12;3",
+        "solution":  "【分析】除法算式读作：几除以几等于几;在除法算式中，除号前面的数是被除数，除号后面的数是除数，等号后面的数是商。据此解答即可.\n【详解】算式12÷3=4读作12除以3等于4，算式中被除数是12，除数是3。",
+        "knowledge_points":  [
+                                 "除法的初步认识"
+                             ],
+        "source":  "23-24 二年级下·广东广州·期末"
+    },
+    {
+        "id":  "156",
+        "unit":  "第二单元 表内除法1",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "算式10除以5等于2写作( ),其中被除数是( ),除数是( ),商是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "10÷5=2;10;5;2",
+        "solution":  "【分析】除法算式写出来是：被除数/除数=商。其中除号前面的是被除数，除号后面的是除数，计算出的结果是商，据此解答.\n【详解】由分析可得：算式10除以5等于2写作10÷5=2，其中被除数是10，除数是5，商是2。",
+        "knowledge_points":  [
+                                 "除法的初步认识"
+                             ],
+        "source":  "23-24 二年级下·重庆丰都·期末"
+    },
+    {
+        "id":  "157",
+        "unit":  "第二单元 表内除法1",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "63÷9=7表示把( )平均分成( )份，每份是( );还表示( )里面有( )个( )。",
+        "options":  [
+
+                    ],
+        "answer":  "63;9;7;63;7;9",
+        "solution":  "【分析】除法算式：第一种含义(平均分),把一个总数平均分成几份，求每份是多少。第二种含义(包含除),求一个数里面包含几个另一个数。据此解答.\n【详解】由分析可得：根据除法算式的第一种含义,63÷9=7表示把63平均分成9份，每份是7;根据除法算式的第二种含义,63÷9=7表示63里面有7个9;63÷9=7表示把63平均分成9份，每份是7;还表示63里面有7个9。",
+        "knowledge_points":  [
+                                 "整数平均分的意义及应用",
+                                 "除法的初步认识"
+                             ],
+        "source":  "23-24 二年级下·福建龙岩·期末"
+    },
+    {
+        "id":  "158",
+        "unit":  "第二单元 表内除法1",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "一道除法题，除数是6，小明把被除数的十位数字和个位数字看颠倒了，结果除得的商是7。这道题正确的商是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "4",
+        "solution":  "【分析】根据题意，先用错误的商和除数相乘，求出错误的被除数，再通过颠倒数字得到正确的被除数，再用正确的被除数除以6得出正确的商.\n【详解】错误的被除数:7×6=42，正确的被除数:24，正确的商:24÷6=4，一道除法题，除数是6，小明把被除数的十位数字和个位数字看颠倒了，结果除得的商是7。这道题正确的商是4。",
+        "knowledge_points":  [
+                                 "7的乘法口诀及应用",
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "23-24 二年级下·浙江台州·期末"
+    },
+    {
+        "id":  "159",
+        "unit":  "第二单元 表内除法1",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "集市上每把艾草2元钱，奶奶拿12元钱可以买多少把艾草。解决这个问题时，列式是( ),算式读作( )。",
+        "options":  [
+
+                    ],
+        "answer":  "12÷2=6(把);12除以2等于6",
+        "solution":  "【分析】根据题意可知，奶奶带的钱数除以每把艾草的钱数，等于可以买多少把艾草，据此列式即可;读除法算式时，依次从左往右读,\u0027/\u0027读作除以,\u0027=\u0027读作等于，数字直接读出来.\n【详解】根据分析可得：集市上每把艾草2元钱，奶奶拿12元钱可以买多少把艾草。解决这个问题时，列式是12÷2=6(把),算式读作12除以2等于6。",
+        "knowledge_points":  [
+                                 "除法的初步认识",
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "23-24 二年级下·山西晋中·期末"
+    },
+    {
+        "id":  "160",
+        "unit":  "第二单元 表内除法1",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在下面的括号中填上\u0027+\u0027,\u0027-\u0027,\u0027*\u0027或\u0027/\u0027。3( )4=129( )6=39( )3=336( )4=40",
+        "options":  [
+
+                    ],
+        "answer":  "*;-;/;+",
+        "solution":  "【分析】等号右边的数大于等号左边的数，考虑填\u0027+\u0027或\u0027*\u0027;等号右边的数小于等号左边的数，考虑填\u0027-\u0027或\u0027/\u0027,根据整数加减法的计算法则，表内乘法口诀及表内除法进行验证填空即可.\n【详解】3( )4=12，等号右边的数大于等号左边的数，考虑填\u0027+\u0027或\u0027*\u0027,3×4=12，因此括号里填\u0027*\u0027,即3(*)4=12;9( )6=3，等号右边的数小于等号左边的数，考虑填\u0027-\u0027或\u0027/\u0027,9-6=3，因此括号里填\u0027-\u0027,即9(-)6=3;9( )3=3，等号右边的数小于等号左边的数，考虑填\u0027-\u0027或\u0027/\u0027,9÷3=3，因此括号里填\u0027/\u0027,即9(/)3=3;36( )4=40，等号右边的数大于等号左边的数，考虑填\u0027+\u0027或\u0027*\u0027,36+4=40，因此括号里填\u0027+\u0027,即36(+)4=40。",
+        "knowledge_points":  [
+                                 "8,9的加减法",
+                                 "一位数与两位数的进位加法",
+                                 "4的乘法口诀及应用",
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "23-24二年级下·河北张家口·期中"
+    },
+    {
+        "id":  "161",
+        "unit":  "第二单元 表内除法1",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "猜猜我是谁。16÷( )=4 ( )-56=2719+( )=57",
+        "options":  [
+
+                    ],
+        "answer":  "4;83;38",
+        "solution":  "【分析】根据\u0027除数=被除数/商\u0027,\u0027被减数=差+减数\u0027,\u0027一个加数=和-另一个加数\u0027计算填空即可.\n【详解】16÷4=4，所以16÷(4)=4;27+56=83，所以(83)-56=27;57-19=38，所以19+(38)=57。",
+        "knowledge_points":  [
+                                 "两位数与两位数的进位加法",
+                                 "两位数与两位数的退位减法",
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "23-24二年级下·内蒙古鄂尔多斯·期中"
+    },
+    {
+        "id":  "162",
+        "unit":  "第二单元 表内除法1",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "在算式63÷9=7中,9是被除数。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】根据除法算式\u0027被除数/除数=商\u0027的定义，被除数是除号前面的数，除数是除号后面的数.\n【详解】在算式63÷9=7中,9是除数，原题说法错误。故答案为: ×",
+        "knowledge_points":  [
+                                 "除法的初步认识"
+                             ],
+        "source":  "24-25 二年级下·甘肃临夏·期中"
+    },
+    {
+        "id":  "163",
+        "unit":  "第二单元 表内除法1",
+        "question_type":  "判断题",
+        "difficulty":  0.65,
+        "question":  "24÷4=6，这道算式表示把24分成4份，每份是6。( )",
+        "options":  [
+
+                    ],
+        "answer":  "√",
+        "solution":  "【分析】24÷4=6表示把24平均分成4份，每份是6;题目中虽然没有写\"平均\"二字，但\"每份是6\"已经说明4份同样多，所以说法正确.\n【详解】24÷4=6，这道算式表示把24分成4份，每份是6。原说法正确。故答案为:√",
+        "knowledge_points":  [
+                                 "除法的初步认识"
+                             ],
+        "source":  "24-25 二年级下·四川德阳·期末"
+    },
+    {
+        "id":  "164",
+        "unit":  "第二单元 表内除法1",
+        "question_type":  "判断题",
+        "difficulty":  0.65,
+        "question":  "一根绳子长20米，对折以后再对折，每段长10米。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】根据题意可知，一段绳子被连续对折2次，第一次对折绳子被平均分成2段，第二次对折绳子会被平均分成4段。根据除法的意义，绳子的总长度/平均分成的段数=每段的长度，由此列式计算出每段的长度即可解答.\n【详解】20÷4=5(米),所以，一根绳子长20米，对折以后再对折，每段长5米。原说法错误。故答案为: ×",
+        "knowledge_points":  [
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·贵州黔东南·期末"
+    },
+    {
+        "id":  "165",
+        "unit":  "第二单元 表内除法1",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "把25个苹果放在5个盘子里，每个盘子一定正好有5个。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】把25个苹果放在5个盘子里，若每个盘子一定正好有5个，必须满足平均分配的条件。题目未明确说明是\u0027平均分\u0027,因此可能存在不同的分配方式，导致每个盘子的数量不一定为5个.\n【详解】根据除法的意义,25÷5=5，但只有在平均分的情况下，每个盘子才会有5个苹果。若未规定平均分配，例如：一个盘子放6个，另一个放4个，其余3个各放5个，总数仍为25，但并非每个盘子都是5个。因此原题说法错误。故答案为: ×",
+        "knowledge_points":  [
+                                 "整数平均分的意义及应用",
+                                 "除法的初步认识",
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·甘肃兰州·期末"
+    },
+    {
+        "id":  "166",
+        "unit":  "第二单元 表内除法1",
+        "question_type":  "判断题",
+        "difficulty":  0.65,
+        "question":  "除数是8，被除数是4，商是2。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】根据除法算式\u0027被除数/除数=商\u0027,题目中除数是8，被除数是4，算算商是否等于2即可解决.\n【详解】被除数是4，除数是8，列式为4÷8,4比8小不够除，商要小于1，而非题目中的2。原题说法错误。故答案为: ×",
+        "knowledge_points":  [
+                                 "除法的初步认识"
+                             ],
+        "source":  "24-25二年级下·陕西延安·期末"
+    },
+    {
+        "id":  "167",
+        "unit":  "第二单元 表内除法1",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "把20个苹果放在5个盘子里，每个盘子只能放4个。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】题目中未说明\u0027平均分\u0027,因此每个盘子不一定只能放4个苹果;可能存在不同的分配方式，只要总数为20即可;据此解答.\n【详解】根据分析：例如：一个盘子放3个，另一个放5个，其余各放4个，总数为3+5+4+4+4=20(个);所以把20个苹果平均放在5个盘子里，每个盘子只能放4个这个说法错误。故答案为: ×",
+        "knowledge_points":  [
+                                 "整数平均分的意义及应用",
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·甘肃天水·期末"
+    },
+    {
+        "id":  "168",
+        "unit":  "第二单元 表内除法1",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "把20个篮球分给4个班，每个班都能分得5个。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】由题意可知：把20个篮球分给4个班，可能是平均分也可能不是平均分，如果是平均分每班都能分5个，如果不是平均分，每班不一定都能分5个;据此判断.\n【详解】由分析可得：把20个篮球分给4个班，每个班不一定都能分得5个。故答案为: ×",
+        "knowledge_points":  [
+                                 "整数平均分的意义及应用"
+                             ],
+        "source":  "24-25 二年级下·山东济宁·期末"
+    },
+    {
+        "id":  "169",
+        "unit":  "第二单元 表内除法1",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "计算8÷4时，用到的口诀是\u0027四八三十二\u0027。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】除法算式为被除数/除数=商，根据口诀计算除法算式时，口诀中的后一个数是被除数，前两个数分别为除数和商，由此解答.\n【详解】计算8÷4时，用到的口诀是\u0027二四得八\u0027。原题说法错误。故答案为: ×",
+        "knowledge_points":  [
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·湖北黄冈·期末"
+    },
+    {
+        "id":  "170",
+        "unit":  "第二单元 表内除法1",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "算式15÷3=5中,15是除数。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】根据除法算式各部分名称的定义，被除数/除数=商。在算式15÷3=5中,15位于除号前面，是被除数;3位于除号后面，是除数。因此，题目中\u002715是除数\u0027的表述错误.\n【详解】在除法算式15÷3=5中，被除数是15，除数是3，商是5。题目将15错误地判断为除数，而实际除数是3。原题说法错误。故答案为: ×",
+        "knowledge_points":  [
+                                 "除法的初步认识"
+                             ],
+        "source":  "24-25 二年级下·陕西延安·期末"
+    },
+    {
+        "id":  "171",
+        "unit":  "第二单元 表内除法1",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "15里面有1个5。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】判断15里面有几个5，需要用除法计算，即15除以5，根据计算结果判断题目说法是否正确.\n【详解】15÷5=3，因此,15里面有3个5，而不是1个5。题目说法错误。故答案为: ×",
+        "knowledge_points":  [
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·河南三门峡·期末"
+    },
+    {
+        "id":  "172",
+        "unit":  "第二单元 表内除法1",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "每一句乘法口诀都能写出两个不一样的除法算式。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】乘法口诀中，当两个乘数相同时，只能写出一个除法算式;当两个乘数不同时，可以写出两个不同的除法算式。因此，并非每一句口诀都能写出两个不同的除法算式.\n【详解】例如，口诀\u0027三三得九\u0027对应的乘法算式是3×3=9，对应的除法算式只有9÷3=3，无法写出另一个不同的除法算式。而口诀\u0027二三得六\u0027对应的除法算式是6÷2=3和6÷3=2，可以写出两个不同的除法算式。所以，每一句乘法口诀不一定都能写出两个不一样的除法算式。故答案为: ×",
+        "knowledge_points":  [
+                                 "3的乘法口诀及应用",
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·河南三门峡·期末"
+    },
+    {
+        "id":  "173",
+        "unit":  "第二单元 表内除法1",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "10÷5=2和10÷2=5，这两个除法算式表示的意义相同。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】除法的意义有两种:①平均分，即把总数平均分成若干份，求每份的数量;②包含除，即求总数里包含多少个另一个数。题目中的两个算式虽然使用同一个乘法口诀，但具体意义不同.\n【详解】10÷5=2表示将10平均分成5份，每份是2，或10里包含2个5;而10÷2=5表示将10平均分成2份，每份是5，或10里包含5个2。两者的分法或包含关系不同，因此意义不相同。原题说法错误。故答案为: ×",
+        "knowledge_points":  [
+                                 "除法的初步认识",
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·湖南岳阳·期末"
+    },
+    {
+        "id":  "174",
+        "unit":  "第二单元 表内除法1",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "把20块巧克力平均分给5个同学，每个同学一定会分得4块。( )",
+        "options":  [
+
+                    ],
+        "answer":  "√",
+        "solution":  "【分析】根据平均分的定义，将总数均分给若干份，每份的数量等于总数除以份数，据此解答.\n【详解】20÷5=4(块),每个同学一定会分得4块。原题说法正确。故答案为:√",
+        "knowledge_points":  [
+                                 "整数平均分的意义及应用",
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "24-25二年级下·湖北·期中"
+    },
+    {
+        "id":  "175",
+        "unit":  "第二单元 表内除法1",
+        "question_type":  "判断题",
+        "difficulty":  0.65,
+        "question":  "一根16米长的绳子，对折2次后，每段绳子长8米。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】对折两次将绳子平均分成4段，每段长度为总长度除以段数，据此解答即可.\n【详解】对折一次平均分成2段，对折两次平均分成4段。16÷4=4(米),一根16米长的绳子，对折2次后，每段绳子长4米。原题说法错误。故答案为: ×",
+        "knowledge_points":  [
+                                 "图形的折叠问题",
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "22-23 二年级下·新疆乌鲁木齐·期末"
+    },
+    {
+        "id":  "176",
+        "unit":  "第二单元 表内除法1",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "56根玉米分给7只小猴，每只小猴一定分到8根。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】在分物体时，每份分得同样多是平均分。题中未说明平均分，则每只小猴分到的数量不一定是8根，例如:1只小猴分到9根，另一只分到7根，其余5只各分8根，由此解答.\n【详解】56根玉米分给7只小猴，每只小猴不一定分到8根。原题说法错误。故答案为: ×",
+        "knowledge_points":  [
+                                 "整数平均分的意义及应用"
+                             ],
+        "source":  "23-24二年级下·浙江台州·期末"
+    },
+    {
+        "id":  "177",
+        "unit":  "第二单元 表内除法1",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "一道除法算式中，被除数和除数都是3，商是0。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】根据题意及根据乘法口诀求商的方法进行解答，被除数/除数=商，一三得三,3÷3=1.\n【详解】根据分析：一道除法算式中，被除数和除数都是3，商是1。原题说法错误。故答案为: ×",
+        "knowledge_points":  [
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "23-24 二年级下·湖北省直辖县级单位·期末"
+    },
+    {
+        "id":  "178",
+        "unit":  "第二单元 表内除法1",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "把30颗糖果平均分给5个小朋友，每个小朋友都能分到6颗糖果。( )",
+        "options":  [
+
+                    ],
+        "answer":  "√",
+        "solution":  "【分析】把一个数平均分成若干份，求每份是多少，用除法列式解决。即，把30颗糖果平均分给5个小朋友，求每个小朋友能分到几颗糖果，用30÷5进行解答即可.\n【详解】30÷5=6(颗),即，把30颗糖果平均分给5个小朋友，每个小朋友都能分到6颗糖果。说法正确。故答案为:√",
+        "knowledge_points":  [
+                                 "整数平均分的意义及应用",
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "23-24 二年级下·湖北省直辖县级单位·期末"
+    },
+    {
+        "id":  "179",
+        "unit":  "第二单元 表内除法1",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "王老师把35个苹果分给5个小朋友，每个小朋友得7个。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】这道题考查平均分的概念，只有在平均分的情况下，才能用总数除以份数得到每份的数量，即只有在平均分的情况下，把35个苹果分给5个小朋友，每个小朋友才得7个.\n【详解】题目中说王老师把35个苹果分给5个小朋友，但是并没有明确说明是平均分，所以每个小朋友得到的苹果个数不一定是7个，原题说法错误。故答案为: ×",
+        "knowledge_points":  [
+                                 "整数平均分的意义及应用"
+                             ],
+        "source":  "23-24 二年级下·河北张家口·期中"
+    },
+    {
+        "id":  "180",
+        "unit":  "第二单元 表内除法1",
+        "question_type":  "判断题",
+        "difficulty":  0.94,
+        "question":  "8÷2读作8除2。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】除法算式读作：几除以几等于几，据此解答即可.\n【详解】8÷2读作8除以2。原题说法错误。故答案为: ×",
+        "knowledge_points":  [
+                                 "除法的初步认识",
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "23-24 二年级下·河北张家口·期中"
+    },
+    {
+        "id":  "181",
+        "unit":  "第二单元 表内除法1",
+        "question_type":  "判断题",
+        "difficulty":  0.65,
+        "question":  "有24本故事书，分给二年级的4个班，每班一定都分到6本。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】平均分：把一些物品分成几份，每份分得同样多，叫平均分。把24本故事书平均分给4个班，求每个班分到几本，即求24里面有几个4，根据除法的意义，用24÷4进行解答即可.\n【详解】24÷4=6(本),所以有24本故事书，平均分给二年级的4个班，每班一定都分到6本。原题缺少\u0027平均分\u0027的条件，所以说法错误。故答案为: ×",
+        "knowledge_points":  [
+                                 "整数平均分的意义及应用",
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "23-24 二年级下·黑龙江佳木斯·期末"
+    },
+    {
+        "id":  "182",
+        "unit":  "第二单元 表内除法1",
+        "question_type":  "计算题",
+        "difficulty":  0.65,
+        "question":  "看图列式计算.\n![](images/aa595b5d96277a961bbc46d45ef162b0ea438ed3449acb8b832b3960185d5108.jpg)",
+        "options":  [
+
+                    ],
+        "answer":  "36÷6=6(厘米)",
+        "solution":  "【分析】由图意可知：把36厘米长的一段图形，平均分成6份，求每份是多少厘米，用36除以份数即可;据此解答.\n【详解】36÷6=6(厘米),每份是6厘米。",
+        "knowledge_points":  [
+                                 "图文问题",
+                                 "整数平均分的意义及应用",
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·陕西延安·期末"
+    },
+    {
+        "id":  "183",
+        "unit":  "第二单元 表内除法1",
+        "question_type":  "计算题",
+        "difficulty":  0.85,
+        "question":  "看图列式计算.\n![](images/381a4c65e21916021648101a229fdd217e78c81c60d6fb5a97a465e5e1f8dc37.jpg)",
+        "options":  [
+
+                    ],
+        "answer":  "18÷3=6",
+        "solution":  "【分析】由图意可知：有18块西瓜，平均放到3个盘子里，求每盘能放的块数，用西瓜的总块数除以盘子数即可;据此解答.\n【详解】18÷3=6(块),每盘能放6块。",
+        "knowledge_points":  [
+                                 "图文问题",
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·山西长治·期中"
+    },
+    {
+        "id":  "184",
+        "unit":  "第二单元 表内除法1",
+        "question_type":  "计算题",
+        "difficulty":  0.85,
+        "question":  "我会列式计算.\n![](images/2f73e15966c06e81a24005fc4394b783e37e6f649c8df0968185aa6b6f0a6adb.jpg)",
+        "options":  [
+
+                    ],
+        "answer":  "12÷3=4",
+        "solution":  "【分析】由图可知，把12根香蕉平均放在3个篮子里，求每个篮子里放的数量，用除法计算，即香蕉的总数量/平均放的篮数=每个篮子放香蕉的数量.\n【详解】12÷3=4(根),每个篮子放4根香蕉。",
+        "knowledge_points":  [
+                                 "图文问题",
+                                 "整数平均分的意义及应用",
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·山东日照·期中"
+    },
+    {
+        "id":  "185",
+        "unit":  "第二单元 表内除法1",
+        "question_type":  "计算题",
+        "difficulty":  0.85,
+        "question":  "15颗五角星，平均分成3份，每份是几颗。",
+        "options":  [
+
+                    ],
+        "answer":  "15÷3=5(颗)",
+        "solution":  "【分析】根据整数平均分的意义可知，五角星的总数量/平均分成的份数=每份的数量.\n【详解】15÷3=5(颗),15颗五角星，平均分成3份，每份是5颗。",
+        "knowledge_points":  [
+                                 "整数平均分的意义及应用",
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·河北邯郸·期中"
+    },
+    {
+        "id":  "186",
+        "unit":  "第二单元 表内除法1",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "同学们要折45颗星星，已经折了27颗。剩下的由王刚，李亮，周明继续折，他们平均每人要再折多少颗。",
+        "options":  [
+
+                    ],
+        "answer":  "6颗",
+        "solution":  "【分析】已知一共要折45颗星星，已经折了27颗，相减即可得出还缺多少颗，再除以3即可得出平均每人折多少颗.\n【详解】45-27=18(颗),18÷3=6(颗),答：他们平均每人要再折6颗。",
+        "knowledge_points":  [
+                                 "两位数与两位数的退位减法",
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "24-25二年级下·湖南衡阳·期末"
+    },
+    {
+        "id":  "187",
+        "unit":  "第二单元 表内除法1",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "学校买来48个足球，平均分给6个班，每班分到几个。",
+        "options":  [
+
+                    ],
+        "answer":  "8个",
+        "solution":  "【分析】用足球的总个数除以平均分给的班级数，即可求出每班分到几个，据此解答.\n【详解】48÷6=8(个),答：每班分到8个。",
+        "knowledge_points":  [
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·湖南长沙·期末"
+    },
+    {
+        "id":  "188",
+        "unit":  "第二单元 表内除法1",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "4个小朋友相约去甜品坊制作巧克力曲奇饼干，甜品坊师傅将24块巧克力平均分给他们，每人分到多少块。",
+        "options":  [
+
+                    ],
+        "answer":  "6块",
+        "solution":  "【分析】将24块巧克力平均分给4个小朋友，用总块数除以人数即可求出每人分到的块数.\n【详解】24÷4=6(块),答：每人分到6块。",
+        "knowledge_points":  [
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "24-25二年级下·广西河池·期末"
+    },
+    {
+        "id":  "189",
+        "unit":  "第二单元 表内除法1",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "一根绳子长30米，把它截成同样长的几段，一共截了5次，每段长多少米。",
+        "options":  [
+
+                    ],
+        "answer":  "5米",
+        "solution":  "【分析】截5次可将绳子分成6段，总长度30米除以段数6即可求出每段长度.\n【详解】5+1=6(段),30÷6=5(米),答：每段长5米。",
+        "knowledge_points":  [
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·山东济南·期中"
+    },
+    {
+        "id":  "190",
+        "unit":  "第二单元 表内除法1",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "一根长12米的绳子，对折一次，再对折一次，它此时的长度是几米。",
+        "options":  [
+
+                    ],
+        "answer":  "3米",
+        "solution":  "【分析】绳子对折两次，可以分成4段，根据除法的意义，用12÷4即可得出它此时的长度是几米.\n【详解】12÷4=3(米),答：它此时的长度是3米。",
+        "knowledge_points":  [
+                                 "图形的折叠问题",
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·山东济南·期中"
+    },
+    {
+        "id":  "191",
+        "unit":  "第二单元 表内除法1",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "超市大促销。袜子原来每双8元。原来买3双的钱，现在可以买4双袜子。现在每双袜子多少钱。",
+        "options":  [
+
+                    ],
+        "answer":  "6元",
+        "solution":  "【分析】已知原来一双袜子8元，原来买3双袜子的总钱数等于现在买4双袜子的总钱数。先根据原价算出总钱数，再用总钱数除以现在的购买数量，即可求出现价.\n【详解】原来买3双袜子的总钱数:8×3=24(元),现在24元可以买4双袜子，现价每双为:24÷4=6(元),答：现在每双袜子6元钱。",
+        "knowledge_points":  [
+                                 "8的乘法口诀及应用",
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "24-25二年级下·浙江嘉兴·期末"
+    },
+    {
+        "id":  "192",
+        "unit":  "第二单元 表内除法1",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "芳芳买来20支花，每5支扎一束，可以扎几束。",
+        "options":  [
+
+                    ],
+        "answer":  "4束",
+        "solution":  "【分析】用花的总朵数除以扎一束需要的朵数即可求出可以扎几束.\n【详解】20÷5=4(束),答：可以扎4束。",
+        "knowledge_points":  [
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·河北邢台·期中"
+    },
+    {
+        "id":  "193",
+        "unit":  "第二单元 表内除法1",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "王老师带30元，买6元一支的钢笔，最多能买几支。",
+        "options":  [
+
+                    ],
+        "answer":  "5支",
+        "solution":  "【分析】根据题意可知，王老师带的钱数除以每支钢笔的钱数，等于最多能买几支，据此解答.\n【详解】30÷6=5(支),答：最多能买5支。",
+        "knowledge_points":  [
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·湖南岳阳·期中"
+    },
+    {
+        "id":  "194",
+        "unit":  "第二单元 表内除法1",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "妈妈买了24个苹果，每6个装一盘，可以装几盘。",
+        "options":  [
+
+                    ],
+        "answer":  "4盘",
+        "solution":  "【分析】求可以装几盘，也就是24里面有几个6，用除法计算，即苹果的总数量/每盘装的数量=可以装的盘数.\n【详解】24÷6=4(盘),答：可以装4盘。",
+        "knowledge_points":  [
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "24-25二年级下·黑龙江佳木斯·期中"
+    },
+    {
+        "id":  "195",
+        "unit":  "第二单元 表内除法1",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "学校体育室买了30个排球，每6个装一箱，可以装多少箱。",
+        "options":  [
+
+                    ],
+        "answer":  "5箱",
+        "solution":  "【分析】根据题意可知，学校体育室排球的总数量除以每箱的个数，等于可以装多少箱，据此解答.\n【详解】30÷6=5(箱),答：可以装5箱。",
+        "knowledge_points":  [
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "24-25二年级下·贵州黔西·期中"
+    },
+    {
+        "id":  "196",
+        "unit":  "第二单元 表内除法1",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "三(2)班42人租船游玩，每条船限坐6人，租7条船够吗。如果不够，至少需要几条。",
+        "options":  [
+
+                    ],
+        "answer":  "够",
+        "solution":  "【分析】根据题意，用三(2)班的人数除以每条船限坐的人数，求出实际租船的条数，然后用实际租船的条数与7条比较，即可解答.\n【详解】42÷6=7(条),答：租7条船够。",
+        "knowledge_points":  [
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "24-25 三年级下·湖南岳阳·期中"
+    },
+    {
+        "id":  "197",
+        "unit":  "第二单元 表内除法1",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "一根绳子长24米，对折两次后，每段绳子有多长。",
+        "options":  [
+
+                    ],
+        "answer":  "6米",
+        "solution":  "【分析】根据题意可知，一根绳子对折一次，被平均分成2段，对折两次，被平均分成4段;绳子的总长度除以平均分的段数，等于每段绳子的长度，据此解答.\n【详解】2×2=4(段),24÷4=6(米),答：每段绳子长6米。",
+        "knowledge_points":  [
+                                 "2的乘法口诀及应用",
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "23-24 二年级下·内蒙古鄂尔多斯·期中"
+    },
+    {
+        "id":  "198",
+        "unit":  "第二单元 表内除法1",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "有20个气球，平均分给5人，每人分几个。如果每人分4个，能分给几人。",
+        "options":  [
+
+                    ],
+        "answer":  "4个;5人",
+        "solution":  "【分析】根据除法的意义可知，气球的总个数除以平均分给的人数，等于每人分的个数;气球的总个数除以每人分的个数，等于能分给的人数，据此解答.\n【详解】20÷5=4(个),20÷4=5(人),答：平均分给5人，每人分4个;如果每人分4个，能分给5人。",
+        "knowledge_points":  [
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·湖南·期中"
+    },
+    {
+        "id":  "199",
+        "unit":  "第二单元 表内除法1",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "一根彩带长24米，对折以后，再对折，每段长多少米。",
+        "options":  [
+
+                    ],
+        "answer":  "6米",
+        "solution":  "【分析】把这根彩带对折2次后被平均分成4段，根据平均分除法的意义，用这根彩带的长度除以段数，用24÷4即可得出答案.\n【详解】24÷4=6(米),答：每段长6米。",
+        "knowledge_points":  [
+                                 "图形的折叠问题",
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "23-24 二年级下·河北邢台·期中"
+    },
+    {
+        "id":  "200",
+        "unit":  "第二单元 表内除法1",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "二(1)班同学一共做了24只风筝，每个班分6只风筝，可以分给几个班。",
+        "options":  [
+
+                    ],
+        "answer":  "4个",
+        "solution":  "【分析】用风筝的总数除以每个班分到的数量，求出商，就是可以分的班级数.\n【详解】24÷6=4(个),答：可以分给4个班。",
+        "knowledge_points":  [
+                                 "整数平均分的意义及应用",
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "23-24二年级下·湖南常德·期中"
+    },
+    {
+        "id":  "201",
+        "unit":  "第二单元 表内除法2",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "一堆南瓜比20个多，比30个少，平均分成几份，分得的份数和每份的个数同样多，这堆南瓜有( )个。",
+        "options":  [
+                        "A. 25",
+                        "B. 22",
+                        "C. 36"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】根据题意，总数量/平均分的份数=每份的数量，也就是除数和商相同，先比较各选项与20,30的大小关系，找到比20大，比30小的数，再根据乘法口诀，找到符合题意的数即可.\n【详解】A。20\u003c25\u003c30，根据口诀五五二十五可知,25÷5=5(个),符合题意;B。20\u003c22\u003c30，乘法口诀中没有两个相同数的积是22，不符合题意;C。20\u003c30\u003c36，不符合题意。则这堆南瓜有25个。故答案为:A",
+        "knowledge_points":  [
+                                 "100以内数的比大小",
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "23-24 二年级下·内蒙古鄂尔多斯·期中"
+    },
+    {
+        "id":  "202",
+        "unit":  "第二单元 表内除法2",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "如图所示，一个西瓜的质量相当于( )个苹果的质量.\n![](images/9f852ad8687763e58ad0cad1652a1214346f65174c56afad451da00adf759c8e.jpg)",
+        "options":  [
+                        "A. 5",
+                        "B. 6",
+                        "C. 8"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】由图可知,1个西瓜的质量=3个菠萝的质量,2个菠萝的质量=4个苹果的质量。则根据除法的意义,4个苹果的质量/2个菠萝的数量=每个菠萝代表的苹果质量。再根据乘法的意义，每个菠萝代表的苹果质量*3个菠萝的数量=3个菠萝代表的苹果质量，由此可知一个西瓜代表的苹果质量.\n【详解】4÷2=2，所以，每个菠萝的质量代表2个苹果的质量。3×2=6，所以,3个菠萝的质量代表6个苹果的质量，即一个西瓜的质量相当于6个苹果的质量。故答案为:B",
+        "knowledge_points":  [
+                                 "图文问题",
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "23-24二年级下·河北邢台·期末"
+    },
+    {
+        "id":  "203",
+        "unit":  "第二单元 表内除法2",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "用\u0027二四得八\u0027不能解决的算式是( )。",
+        "options":  [
+                        "A. 8÷2",
+                        "B. 4×2",
+                        "C. 8÷4",
+                        "D. 8-4"
+                    ],
+        "answer":  "D",
+        "solution":  "【分析】乘法算式中两个乘数是口诀中的前两个数，积是口诀中的后一个数，写算式时两个乘数可互换位置。根据乘法口诀求商时，口诀中的后一个数作为被除数，前面两个数一个作除数另一个作商.\n【详解】A。8÷2用\u0027二四得八\u0027解决;B。4×2用\u0027二四得八\u0027解决;C。8÷4用\u0027二四得八\u0027解决;D。8-4是减法算式不能用乘法口诀解决。用\u0027二四得八\u0027不能解决的算式是8-4。故答案为:D",
+        "knowledge_points":  [
+                                 "8,9的加减法",
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "24-25 一年级下·湖南岳阳·期中"
+    },
+    {
+        "id":  "204",
+        "unit":  "第二单元 表内除法2",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "把8块糖平均分给4个小朋友，正确的分法是( )。",
+        "options":  [
+                        "A. ○○○○｜○○○○",
+                        "B. ○○｜○○｜○○｜○○",
+                        "C. ○○○｜○○○｜○○"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】用8除以4即可求出每个小朋友分得的个数.\n【详解】8÷4=2(个),A。每个小朋友4个，不符合;B。每个小朋友2个，符合;C。不是平均分，不符合。正确的分法是B。故答案为:B",
+        "knowledge_points":  [
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·湖南岳阳·期中"
+    },
+    {
+        "id":  "205",
+        "unit":  "第二单元 表内除法2",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "15÷3和25÷5这两个算式的结果( )。",
+        "options":  [
+                        "A. 相等",
+                        "B. 不相等",
+                        "C. 无法确定"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】根据5的乘法口诀求商，计算出这两个算式的结果，再判断是否相等。据此解答.\n【详解】15÷3=5,25÷5=5，所以说这两个算式的结果相等。故答案为:A",
+        "knowledge_points":  [
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "23-24 二年级下·河北邯郸·期末"
+    },
+    {
+        "id":  "206",
+        "unit":  "第二单元 表内除法2",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "把12朵花平均分成3份，哪种分法是正确的。( )",
+        "options":  [
+                        "A. 🌸🌸🌸🌸🌸🌸 🌸🌸🌸🌸🌸🌸",
+                        "B. 🌸🌸🌸🌸 🌸🌸🌸🌸 🌸🌸🌸🌸",
+                        "C. 🌸🌸🌸 🌸🌸🌸🌸 🌸🌸🌸🌸"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】用总朵数除以份数即可求出每份的数量.\n【详解】12÷3=4(朵),A。平均分成了2份，不正确;B。平均分成了3份，正确;C。平均分成了4份，不正确。故答案为:B",
+        "knowledge_points":  [
+                                 "整数平均分的意义及应用",
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "23-24二年级下·福建莆田·期末"
+    },
+    {
+        "id":  "207",
+        "unit":  "第二单元 表内除法2",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "1支铅笔5角钱，小明有3元，能买( )支铅笔。",
+        "options":  [
+                        "A. 5",
+                        "B. 6",
+                        "C. 7"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】据题意，一支铅笔5角钱，小明有3元，首先要将元换算为角,1元等于10角，换算出3元等于多少，在用总的钱数除以每支铅笔的钱数即可得出可以买几支.\n【详解】1元=10角,3元=30角,30÷5=6(支),所以3元可以买6支铅笔。故答案为:B",
+        "knowledge_points":  [
+                                 "用6的乘法口诀求商",
+                                 "元，角，分的认识及换算",
+                                 "十元以下人民币的认识与计算"
+                             ],
+        "source":  "24-25 二年级下·湖南岳阳·期中"
+    },
+    {
+        "id":  "208",
+        "unit":  "第二单元 表内除法2",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "下面算式中，商是6的是( )。",
+        "options":  [
+                        "A. 18÷3",
+                        "B. 2×3",
+                        "C. 24÷6"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】据题意，找出商是6的算式，首先商是除法算式的运算结果，排除不是除法的算式，再将剩余的除法算式进行计算即可得出答案.\n【详解】A。计算18÷3=6，商是6，符合题意;B。计算2×3=6，该算式不是除法算式，结果不是商，而是积，不符合题意;C。计算24÷6=4，商是4，不符合题意。故答案为:A",
+        "knowledge_points":  [
+                                 "3的乘法口诀及应用",
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·湖南岳阳·期中"
+    },
+    {
+        "id":  "209",
+        "unit":  "第二单元 表内除法2",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "下面三种书中，价格最贵的一种是( )。",
+        "options":  [
+                        "A. 5本15元",
+                        "B. 12元3本",
+                        "C. 一本5元"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】用总价除以数量算出各自的单价，然后比较，单价越高越贵.\n【详解】A。15÷5=3(元);B。12÷3=4(元);C。5÷1=5(元);3\u003c4\u003c5，价格最贵的一种是：一本5元。故答案为:C",
+        "knowledge_points":  [
+                                 "经济问题",
+                                 "5以内数的比大小",
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "23-24二年级下·浙江舟山·期末"
+    },
+    {
+        "id":  "210",
+        "unit":  "第二单元 表内除法2",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "在一道除法算式中，被除数和除数都是6，商是( )。",
+        "options":  [
+                        "A. 12",
+                        "B. 1",
+                        "C. 0",
+                        "D. 36"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】被除数/除数=商，据此计算。根据乘法口诀求商时，口诀中后面一个数作被除数，前面两个数一个数作除数另一个数作商.\n【详解】6÷6=1，在一道除法算式里，被除数和除数都是6，商是1。故答案为:B",
+        "knowledge_points":  [
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "23-24二年级下·福建龙岩·期末"
+    },
+    {
+        "id":  "211",
+        "unit":  "第二单元 表内除法2",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "计算□÷6=6，用到的口诀是( )。",
+        "options":  [
+                        "A. 一六得六",
+                        "B. 二六十二",
+                        "C. 六六三十六"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】根据被除数/除数=商，可知除数×商=被除数，利用表内乘法，找出计算6×6的口诀即可求解.\n【详解】计算6×6的口诀为六六三十六，所以36÷6=6。故答案为:C",
+        "knowledge_points":  [
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "23-24二年级下·浙江·期末"
+    },
+    {
+        "id":  "212",
+        "unit":  "第二单元 表内除法2",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "求30里面有几个6，下列方法不正确的是( )。",
+        "options":  [
+                        "A. 30-6=24",
+                        "B. 30÷6=5",
+                        "C. (五)六三十",
+                        "D. 30-6-6-6-6-6=0"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】求一个数里面有几个另一个数，用这个数/另一个数计算;或者用这个数依次减去另一个数，直到结果为0，减了几次就是有几个;或者几个6的和是30，也就是30里面有几个6，根据乘法口诀解答.\n【详解】A。30-6=24，表示从30里面减去6还剩24，方法不正确;B。30÷6=5,30里面有5个6，方法正确;C。(五)六三十，也就是5个6的和是30，方法正确;D。30-6-6-6-6-6=0，也就是30里面有5个6，方法正确。所以方法不正确的是30-6=24。故答案为:A",
+        "knowledge_points":  [
+                                 "一位数与两位数的退位减法",
+                                 "100以内数的连减运算",
+                                 "6的乘法口诀及应用",
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "23-24 二年级下·福建龙岩·期末"
+    },
+    {
+        "id":  "213",
+        "unit":  "第二单元 表内除法2",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "下面的分法不能用12÷3表示的是( )。",
+        "options":  [
+                        "A. ![](images/602290de07584a7f1495d42c9a1433c9b42b2a9eb9f733a972ff259ed2384bb4.jpg)",
+                        "B. ![](images/df25a0ffdabefba9c057993988a317a88587de3af97220e48b4eda5c4ada36e9.jpg)",
+                        "C. ![](images/319df8d3288e7a94c197fab4bc6f71292256916e4d1f3efcd1f9b9a2cc139392.jpg)"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】把一个数平均分成若干份，求每一份是多少用除法计算;求一个数里面有几个另一个数用除法计算。据此解答.\n【详解】A。是把全部物体平均分成3份，求每份是多少，用除法计算:12÷3=4;B。是计算12里面有几个3的问题，用除法计算:12÷3=4;C。四个方框里面的物体不一样多，没有平均分，不能用除法计算。故答案为:C",
+        "knowledge_points":  [
+                                 "整数平均分的意义及应用"
+                             ],
+        "source":  "23-24 二年级下·湖北黄石·期末"
+    },
+    {
+        "id":  "214",
+        "unit":  "第二单元 表内除法2",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "计算3÷3，用的口诀是( )。",
+        "options":  [
+                        "A. 三三得九",
+                        "B. 一三得三",
+                        "C. 二三得六"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】根据乘法口诀求商时，口诀中的后一个数作为被除数，前面两个数一个作除数另一个作商.\n【详解】计算3÷3，用的口诀是：一三得三。故答案为:B",
+        "knowledge_points":  [
+                                 "3的乘法口诀及应用"
+                             ],
+        "source":  "23-24二年级下·重庆永川·期末"
+    },
+    {
+        "id":  "215",
+        "unit":  "第二单元 表内除法2",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "下面属于平均分的是( )。",
+        "options":  [
+                        "A. ",
+                        "B. ",
+                        "C. ",
+                        "D. ![](images/e24dbcf1060597d28a0477fba21fb425.png)"
+                    ],
+        "answer":  "D",
+        "solution":  "【分析】平均分的意思是指在分物体的时候，要使每一份得到的数相等，据此解答即可.\n【详解】A。分成了3份，但不是每一份数量都相等，不是平均分;B。分成了4份，每一份数量都不相等，不是平均分;C。分成了4份，每一份数量都不相等，不是平均分;D。平均分成了4份，每份是3个，是平均分。故答案为:D",
+        "knowledge_points":  [
+                                 "整数平均分的意义及应用"
+                             ],
+        "source":  "23-24 二年级下·福建龙岩·期末"
+    },
+    {
+        "id":  "216",
+        "unit":  "第二单元 表内除法2",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "在竞选班长的投票活动中，用画\u0027正\u0027字记录投票结果，小丹获得了30票，她得到了( )个\u0027正\u0027字。",
+        "options":  [
+                        "A. 4",
+                        "B. 5",
+                        "C. 6"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】根据题意，一个\u0027正\u0027字有5笔，表示5票，小丹获得了30票，根据除法的意义，用30÷5即可求出小丹得到了几个\u0027正\u0027字.\n【详解】30÷5=6(个),小丹获得了30票，她得到了6个\u0027正\u0027字。故答案为:C",
+        "knowledge_points":  [
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "24-25二年级下·福建福州·期中"
+    },
+    {
+        "id":  "217",
+        "unit":  "第二单元 表内除法2",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "小一罐糖果，比20颗多，比30颗少。如果平均分成的份数和每份的颗数一样多，那么一共有( )颗糖果。",
+        "options":  [
+                        "A. 24",
+                        "B. 25",
+                        "C. 28"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】根据表内口诀\u0027五五二十五\u0027可知25÷5=5，且20\u003c25\u003c30，也就是25颗糖果平均分成的5份，每份是5颗，平均分成的份数和每份的颗数一样多，据此解决.\n【详解】20\u003c25\u003c30,25÷5=5(颗),即小一罐糖果，比20颗多，比30颗少。如果平均分成的份数和每份的颗数一样多，那么一共有25颗糖果。故答案为:B",
+        "knowledge_points":  [
+                                 "100以内数的比大小",
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "24-25二年级下·福建福州·期中"
+    },
+    {
+        "id":  "218",
+        "unit":  "第二单元 表内除法2",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "下面哪种分法是平均分。( )",
+        "options":  [
+                        "A. ○○○ ○○○○",
+                        "B. △△△ △△△",
+                        "C. ☆☆☆☆ ☆☆☆"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】在分物体时，每份分得同样多，是平均分，由此解答.\n【详解】A。分成了两份，一份是3个，一份是4个，每份数量不同，不是平均分;B。分成了两份，每份都是3个，是平均分;C。分成了两份，一份是4个，一份是3个，每份数量不同，不是平均分。则△△△ △△△是平均分。故答案为:B",
+        "knowledge_points":  [
+                                 "整数平均分的意义及应用"
+                             ],
+        "source":  "24-25 二年级下·湖南湘潭·期中"
+    },
+    {
+        "id":  "219",
+        "unit":  "第二单元 表内除法2",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "有18根萝卜，小兔每次抱走6根，需要( )次才能抱完。",
+        "options":  [
+                        "A. 2",
+                        "B. 3",
+                        "C. 4"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】求需要几次才能抱完，也就是求18里面有几个6，用除法计算，即萝卜的总数量/每次抱走的数量=抱的次数.\n【详解】18÷6=3(次),有18根萝卜，小兔每次抱走6根，需要3次才能抱完。故答案为:B",
+        "knowledge_points":  [
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "24-25二年级下·贵州黔西·期中"
+    },
+    {
+        "id":  "220",
+        "unit":  "第二单元 表内除法2",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "有20名同学乘车去博物馆参观，刚好坐满5辆车，平均每辆车坐( )。",
+        "options":  [
+                        "A. 5人",
+                        "B. 4人",
+                        "C. 3人"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】根据除法的意义，总人数/坐满车的数量=平均每辆车坐的人数.\n【详解】20÷5=4(人),平均每辆车坐4人。故答案为:B",
+        "knowledge_points":  [
+                                 "整数平均分的意义及应用",
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "24-25二年级下·陕西延安·期中"
+    },
+    {
+        "id":  "221",
+        "unit":  "第二单元 表内除法2",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "12个苹果，每3个一份，可以分成几份。正确的算式是( )。",
+        "options":  [
+                        "A. 12-3",
+                        "B. 12÷3",
+                        "C. 12×3"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】12个苹果，每3个一份，求可以分成几份，用除法计算，用苹果的个数除以每份的个数，即可求出可以分成几份，列式为12÷3，据此解答.\n【详解】12个苹果，每3个一份，可以分成几份。正确的算式是12÷3。故答案为:B",
+        "knowledge_points":  [
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "24-25二年级下·黑龙江佳木斯·期中"
+    },
+    {
+        "id":  "222",
+        "unit":  "第二单元 表内除法2",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "下面算式中，商是6的是( )。",
+        "options":  [
+                        "A. 30÷5",
+                        "B. 12÷3",
+                        "C. 24÷8"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】根据被除数/除数=商，分别求出3道题的商各是多少，据此选择答案.\n【详解】A。30÷5=6，符合题意;B。12÷3=4，不符合题意;C。24÷8=3，不符合题意。故答案为:A",
+        "knowledge_points":  [
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·黑龙江佳木斯·期中"
+    },
+    {
+        "id":  "223",
+        "unit":  "第二单元 表内除法2",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "12个苹果，每4个装一袋，可以装几袋。列式正确的是( )。",
+        "options":  [
+                        "A. 12÷3=4(袋)",
+                        "B. 12÷4=3(袋)",
+                        "C. 4×3=12(袋)"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】根据题意,12个苹果，每4个装一袋，求可以装几袋，用除法计算，用苹果的总个数除以每袋装的个数，就是可以装的袋数，据此解答.\n【详解】A。12÷3=4(袋),表示12个苹果，每3个装一袋，可以装4袋，不符合题意;B。12÷4=3(袋),表示12个苹果，每4个装一袋，可以装3袋，符合题意;C。4×3=12(袋),与题意无关，不符合题意。故答案为:B",
+        "knowledge_points":  [
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "24-25二年级下·黑龙江佳木斯·期中"
+    },
+    {
+        "id":  "224",
+        "unit":  "第二单元 表内除法2",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "5只小白兔要把15根萝卜一次运回家，平均每只小白兔运( )根萝卜。",
+        "options":  [
+                        "A. 5",
+                        "B. 4",
+                        "C. 3"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】根据除法的意义，用总萝卜数除以小白兔的只数，就是每只兔运的萝卜数，据此解答.\n【详解】15÷5=3(根),5只小白兔要把15根萝卜一次运回家，平均每只小白兔运3根萝卜。故答案为:C",
+        "knowledge_points":  [
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·河北邯郸·期中"
+    },
+    {
+        "id":  "225",
+        "unit":  "第二单元 表内除法2",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "妈妈用20元钱买5元钱一盒的牙膏，可以买( )盒。",
+        "options":  [
+                        "A. 3",
+                        "B. 4",
+                        "C. 5"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】根据题意，妈妈用20元钱买5元钱一盒的牙膏，求可以买几盒，用除法计算，用总钱数除以一盒牙膏的钱数，即可解答.\n【详解】20÷5=4(盒),可以买4盒。故答案为:B",
+        "knowledge_points":  [
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "24-25二年级下·河北邯郸·期中"
+    },
+    {
+        "id":  "226",
+        "unit":  "第二单元 表内除法2",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "下面的( )是根据4×6=24写出的除法算式。",
+        "options":  [
+                        "A. 24÷3=8",
+                        "B. 24÷8=3",
+                        "C. 24÷6=4"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】根据因数=积/另一个因数，结合题干要求将数据代入，即可得出答案.\n【详解】根据4×6=24可以写出的除法算式有:24÷4=6,24÷6=4。故答案为:C",
+        "knowledge_points":  [
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·河北邯郸·期中"
+    },
+    {
+        "id":  "227",
+        "unit":  "第二单元 表内除法2",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "12个苹果，每4个装一袋，可以装几袋。列式正确的是( )。",
+        "options":  [
+                        "A. 12-4",
+                        "B. 12÷4",
+                        "C. 12×4"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】用苹果的总个数除以每袋装的苹果个数，即可求出\u002712个苹果，每4个装一袋，求可以装几袋\u0027,列式为:12÷4，据此解答.\n【详解】12个苹果，每4个装一袋，可以装几袋。列式正确的是12÷4。故答案为:B",
+        "knowledge_points":  [
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "24-25二年级下·黑龙江佳木斯·期中"
+    },
+    {
+        "id":  "228",
+        "unit":  "第二单元 表内除法2",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "把8个桃子分给2个小朋友，一个小朋友分得5个，另一个小朋友分几个桃子。列式为( )。",
+        "options":  [
+                        "A. 8÷2",
+                        "B. 2+5",
+                        "C. 8-5"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】根据减法的意义，桃子的总数量-一个小朋友分得的数量=另一个小朋友分得的数量.\n【详解】A。8÷2表示把8个桃子平均分给2个小朋友，得数是每个小朋友分到的数量，与题意不符;B。2+5表示一部分是2个，另一部分是5个，合起来是总数量，与题意不符;C。8-5计算出的是另一个小朋友分到桃子的数量，与题意相符。则列式应为8-5。故答案为:C",
+        "knowledge_points":  [
+                                 "8,9的加减法",
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·河北邯郸·期中"
+    },
+    {
+        "id":  "229",
+        "unit":  "第二单元 表内除法2",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "小红要看一本24页的课外书，计划每天看4页，几天能看完。列式为( )。",
+        "options":  [
+                        "A. 24-4",
+                        "B. 24÷4",
+                        "C. 24+4"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】求几天能看完，也就是求24里面有几个4，用除法计算，即总页数/每天看的页数=看的天数.\n【详解】A。24-4：这是减法,24减4等于20，表示看完4页后还剩多少页，不符合题意;B。24÷4：这是除法,24除以4等于6，表示6天能看完，符合题意;C。24+4：这是加法,24加4等于28，没有实际意义，不符合题意。则正确的列式为24÷4。故答案为:B",
+        "knowledge_points":  [
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "24-25二年级下·河北邯郸·期中"
+    },
+    {
+        "id":  "230",
+        "unit":  "第二单元 表内除法2",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "关于\u002754÷9=6\u0027这个算式的意义，下面第( )种说法是不正确的。",
+        "options":  [
+                        "A. 表示\u00279和6相乘的积是54\u0027",
+                        "B. 表示\u002754里面有6个9\u0027",
+                        "C. 表示\u0027把54平均分成9份，每份是6\u0027"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】除法算式为：被除数/除数=商，可以表示把被除数平均分成除数的份数，商是每份的数，也可以表示被除数里有商个数的除数.\n【详解】A。9和6相乘的积是54，列式为9×6=54;B。54里面有6个9，列式为54÷9=6;C。把54平均分成9份，每份是6，列式为54÷9=6。则关于\u002754÷9=6\u0027这个算式的意义，说法不正确的是表示\u00279和6相乘的积是54\u0027。故答案为:A",
+        "knowledge_points":  [
+                                 "除法的初步认识"
+                             ],
+        "source":  "24-25二年级下·福建龙岩·期中"
+    },
+    {
+        "id":  "231",
+        "unit":  "第二单元 表内除法2",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "在下面的算式中，商是5的算式是( )。",
+        "options":  [
+                        "A. 10-5",
+                        "B. 10÷2",
+                        "C. 5×1"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】由题意可知：此道题要的是商5的算式，只有除法的得数才能成为商，因此必须是得5的除法算式，据此解答.\n【详解】A。10-5=5，虽然得5，但不是除法算式，不符合;B。10÷2=5，是得5的除法算式，符合;C。5×1=5，虽然得5，但不是除法算式，不符合。故答案为:B",
+        "knowledge_points":  [
+                                 "10的加减法",
+                                 "5的乘法口诀及应用",
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "24-25二年级下·河南南阳·期中"
+    },
+    {
+        "id":  "232",
+        "unit":  "第二单元 表内除法2",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "24÷4=6，不能表示( )。",
+        "options":  [
+                        "A. 把24平均分成6份，每份是4",
+                        "B. 24里面有4个6",
+                        "C. 把24平均分成4份，每份是6"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】除法算式中，被除数表示总数，除数表示平均分成的份数，商表示每份的数量;或者被除数表示总数，除数表示每份的数量，商表示平均分成的份数;或者表示被除数里面有商个除数.\n【详解】A。由分析得,24÷4=6，可以表示每份是4，把24平均分成6份，原说法正确。B。由分析得,24÷4=6，可以表示24里面有6个4，原说法错误。C。由分析得,24÷4=6，可以表示把24平均分成4份，每份是6，原说法正确。故答案为:B",
+        "knowledge_points":  [
+                                 "整数平均分的意义及应用",
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·黑龙江佳木斯·期中"
+    },
+    {
+        "id":  "233",
+        "unit":  "第二单元 表内除法2",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "老师要把6个鸡蛋分给3位同学,( )最合理。",
+        "options":  [
+                        "A. 大的多分，小的少分",
+                        "B. 小的多分，大的少分",
+                        "C. 平均分"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】由题意可知，最合理最公平的分法就是：每位同学分得同样多，也就是平均分，据此可解.\n【详解】老师要把6个鸡蛋分给3位同学，平均分最合理。故答案为:C",
+        "knowledge_points":  [
+                                 "整数平均分的意义及应用"
+                             ],
+        "source":  "24-25二年级下·河北邯郸·期中"
+    },
+    {
+        "id":  "234",
+        "unit":  "第二单元 表内除法2",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "爸爸花了8元钱买了2个同样的杯子，再买1个同样的杯子，要付( )钱。",
+        "options":  [
+                        "A. 2元",
+                        "B. 4元",
+                        "C. 3元"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】要求每个杯子多少钱，根据除法的意义，用8÷2即可得出答案.\n【详解】8÷2=4(元),所以爸爸再买1个同样的杯子，要付4元钱。故答案为:B",
+        "knowledge_points":  [
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "24-25二年级下·河北邯郸·期中"
+    },
+    {
+        "id":  "235",
+        "unit":  "第二单元 表内除法2",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "妈妈用20元钱买4元钱一盒的牙膏，可以买( )盒。",
+        "options":  [
+                        "A. 16",
+                        "B. 4",
+                        "C. 5"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】用20元钱除以每盒牙膏的价钱，即可求出20元钱可以买几盒，据此解答即可.\n【详解】20÷4=5(盒),20元钱买4元钱一盒的牙膏，可以买5盒。故答案为:C",
+        "knowledge_points":  [
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "24-25二年级下·河北邯郸·期中"
+    },
+    {
+        "id":  "236",
+        "unit":  "第二单元 表内除法2",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "分蛋糕。把下面这些蛋糕按要求分一分，填一填.\n![](images/4204dc75c0d71d7c238dd60e2c86c871180566395eaad2b0455afa291fcd318c.jpg)\n(1)这些蛋糕每2个装一盒，可以装( )盒.\n(2)蛋糕还可以( )个装一盒，也能平均分。",
+        "options":  [
+
+                    ],
+        "answer":  "6;3,4,6",
+        "solution":  "【分析】(1)根据题意可知一共有12个蛋糕，利用蛋糕的总数/每个盒子里的蛋糕数量=可以装的盒数，算出答案即可解。(2)需要平均分说明每个盒子里的蛋糕数量要一致，根据表内除法，被除数为12时，对应的口诀有\u0027二六十二\u0027\u0027三四十二\u0027。由此可知12个蛋糕，无论是2个,3个,4个,6个中的哪一种，都可以平均分.\n【详解】(1)12÷2=6(盒),这些蛋糕每2个装一盒，可以装(6)盒。(2)12÷3=4(盒),12÷4=3(盒),12÷6=2(盒),除去第一小问2个蛋糕装一盒的方式外，还可以3个,4个,6个装一盒，也能平均分。蛋糕还可以(3,4,6)个装一盒，也能平均分。",
+        "knowledge_points":  [
+                                 "整数平均分的意义及应用",
+                                 "用2~5的乘法口诀求商",
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "23-24 二年级下·福建龙岩·期末"
+    },
+    {
+        "id":  "237",
+        "unit":  "第二单元 表内除法2",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "12=○+○+○+○,○= ( )。",
+        "options":  [
+
+                    ],
+        "answer":  "3",
+        "solution":  "【分析】从题干可知:4个○的和是12，要求○表示多少，根据除法的意义，用12÷4进行解答即可.\n【详解】12÷4=3，所以○=3。",
+        "knowledge_points":  [
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "23-24 二年级下·河北邯郸·期末"
+    },
+    {
+        "id":  "238",
+        "unit":  "第二单元 表内除法2",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "要把一根粗细均匀的木头锯成3段需要12分钟，照这样计算，要把这根木头锯成5段需要 ( )分钟。",
+        "options":  [
+
+                    ],
+        "answer":  "24",
+        "solution":  "【分析】由题意可知：一根木头锯成3段需要锯2次，也就是锯2次用了12分钟，每锯一次需要的时间为:12÷2=6(分钟);要把这根木头锯成5段，需要锯4次，据此解答.\n【详解】3-1=2(次),12÷2=6(分钟),5-1=4(次),6×4=24(分钟),要把一根粗细均匀的木头锯成3段需要12分钟，照这样计算，要把这根木头锯成5段需要24分钟。",
+        "knowledge_points":  [
+                                 "6的乘法口诀及应用",
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "23-24 二年级下·福建龙岩·期末"
+    },
+    {
+        "id":  "239",
+        "unit":  "第二单元 表内除法2",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "9个3是( );9里面有( )个3。",
+        "options":  [
+
+                    ],
+        "answer":  "27;3",
+        "solution":  "【分析】求几个相同加数的和可以用乘法计算，求一个数里有几个另一个数用除法计算;9个3是多少应该用乘法计算。9里面有几个3应该用除法计算。据此解答.\n【详解】9×3=27;9÷3=3;9个3是27;9里面有3个3。",
+        "knowledge_points":  [
+                                 "9的乘法口诀及应用",
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "23-24 二年级下·湖南岳阳·期末"
+    },
+    {
+        "id":  "240",
+        "unit":  "第二单元 表内除法2",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "6个朋友相约去甜品坊制作巧克力曲奇饼干，甜品坊师傅将30块巧克力平均分给他们，每人分到( )块。",
+        "options":  [
+
+                    ],
+        "answer":  "5",
+        "solution":  "【分析】用巧克力的总块数除以平均分给的人数，即可求出每人分到多少块.\n【详解】30÷6=5(块),每人分到5块巧克力。",
+        "knowledge_points":  [
+                                 "整数平均分的意义及应用",
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "23-24二年级下·福建龙岩·期末"
+    },
+    {
+        "id":  "241",
+        "unit":  "第二单元 表内除法2",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "10只小青蛙，平均跳到2片荷叶上，每片荷叶上有( )只;10只小青蛙，跳到2片荷叶上，一片荷叶上有3只，另一片荷叶上有( )只。",
+        "options":  [
+
+                    ],
+        "answer":  "5;7",
+        "solution":  "【分析】由题意可知：把一个数平均分成若干份，求每份是多少用除法计算。用青蛙的总数减去一片叶子上的青蛙数就可以算出另一片叶子上的青蛙数。据此解答.\n【详解】10÷2=5(只),10-3=7(只),10只小青蛙，平均跳到2片荷叶上，每片荷叶上有5只;10只小青蛙，跳到2片荷叶上，一片荷叶上有3只，另一片荷叶上有7只。",
+        "knowledge_points":  [
+                                 "10的加减法",
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "23-24 二年级下·湖南岳阳·期末"
+    },
+    {
+        "id":  "242",
+        "unit":  "第二单元 表内除法2",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "一共有( )个桃，平均分成了( )份，每份( )个.\n![](images/4c988d613a68f3ca29ac8e897cbd20b673df3572167998fc1c1e6f53284199f9.jpg)\n![](images/4c988d613a68f3ca29ac8e897cbd20b673df3572167998fc1c1e6f53284199f9.jpg)\n![](images/4c988d613a68f3ca29ac8e897cbd20b673df3572167998fc1c1e6f53284199f9.jpg)",
+        "options":  [
+
+                    ],
+        "answer":  "18;3;6",
+        "solution":  "【分析】观察题图，数一数可知一共有18个桃子，平均分成了3份，每份有6个，即桃子的总数量除以平均分成的份数，等于每份有多少个，据此解答.\n【详解】18÷3=6(个),共有18个桃，平均分成了3份，每份6个。",
+        "knowledge_points":  [
+                                 "整数平均分的意义及应用",
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "23-24 二年级下·河南信阳·期末"
+    },
+    {
+        "id":  "243",
+        "unit":  "第二单元 表内除法2",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "先在上图中用平均分的方法圈一圈，上图中一共有( )片树叶，每( )片圈一份，平均分成了( )份.\n![](images/8529411a8c62deb9f86f745474250c868c696bd6593e3cd51fce4ea36b5302cd.jpg)",
+        "options":  [
+
+                    ],
+        "answer":  "12;2;6",
+        "solution":  "【分析】数一数可知，一共有12片树叶。在分物体时，每份分得一样多是平均分。只要保证结果是平均分即可，可以每2片树叶圈一个圈，圈了几个圈就能分成几份.\n【详解】上图中一共有12片树叶，每2片圈一份，平均分成了6份。(分法不唯一)",
+        "knowledge_points":  [
+                                 "整数平均分的意义及应用"
+                             ],
+        "source":  "23-24二年级下·重庆丰都·期末"
+    },
+    {
+        "id":  "244",
+        "unit":  "第二单元 表内除法2",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "用15块木块摆5个相同的长方体，每个长方体用( )块木块;如果每个长方体用3块木块，可以摆( )个。",
+        "options":  [
+
+                    ],
+        "answer":  "3;5",
+        "solution":  "【分析】根据除法的意义可知，木块的总数量/长方体的个数=每个长方体需要的木块，木块的总数量/每个长方体需要的木块=长方体的个数，列出算式算出答案即可解答.\n【详解】15÷5=3(块),15÷3=5(个),所以，用15块木块摆5个相同的长方体，每个长方体用3块木块;如果每个长方体用3块木块，可以摆5个。",
+        "knowledge_points":  [
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "23-24 二年级下·重庆大渡口·期末"
+    },
+    {
+        "id":  "245",
+        "unit":  "第二单元 表内除法2",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "有15个△,每3个分一份，可以分( )份。",
+        "options":  [
+
+                    ],
+        "answer":  "5",
+        "solution":  "【分析】求可以分成几份，也就是求15里面有几个3，用除法计算，即总数量/每份的数量=可以分成的份数.\n【详解】15÷3=5(份),有15个△,每3个分一份，可以分5份。",
+        "knowledge_points":  [
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "23-24 二年级下·天津河东·期末"
+    },
+    {
+        "id":  "246",
+        "unit":  "第二单元 表内除法2",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "20÷5=( ),想:( )五二十，商是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "4;四;4",
+        "solution":  "【分析】根据乘法口诀\u0027四五二十\u0027,可知5×4=20，乘法算式中的积20是除法算式中的被除数，一个乘数5作为除数，那么另一个乘数4就是商.\n【详解】20÷5=4，想：四五二十，商是4。",
+        "knowledge_points":  [
+                                 "除法的初步认识",
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "23-24 二年级下·河南信阳·期末"
+    },
+    {
+        "id":  "247",
+        "unit":  "第二单元 表内除法2",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "这些樱桃每4个一份，可以分成( )份。如果平均分成2份，每份( )个.\n![](images/6687679db6b61e79bfba5c0faf07bb28cc044ad9a570e4a2546fd2231cf5bd42.jpg)",
+        "options":  [
+
+                    ],
+        "answer":  "3;6",
+        "solution":  "【分析】从题干可知：一共有12个樱桃，要求这些樱桃每4个一份，可以分成几份，即求12里面有几个4，根据除法的意义，用12÷4进行解答即可。把一个数平均分成几份，求每份是多少，用除法计算，则把12个樱桃平均分成2份，求每份有几个，用12÷2进行解答即可.\n【详解】12÷4=3(份),12÷2=6(个),即这些樱桃每4个一份，可以分成3份。如果平均分成2份，每份6个。",
+        "knowledge_points":  [
+                                 "用2~5的乘法口诀求商",
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "24-25二年级下·山东济宁·期末"
+    },
+    {
+        "id":  "248",
+        "unit":  "第二单元 表内除法2",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "被除数是10，除数是5，商是( ),列出的除法算式为( ),运用的乘法口诀是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "2;10÷5=2;二五一十",
+        "solution":  "【分析】除法算式为：被除数/除数=商，根据乘法口诀计算除法算式时，口诀中的后一个数是被除数，前两个数分别为除数和商，由此解答.\n【详解】被除数是10，除数是5，商是2，列出的除法算式为10÷5=2，运用的乘法口诀是二五一十。",
+        "knowledge_points":  [
+                                 "5的乘法口诀及应用",
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·陕西延安·期中"
+    },
+    {
+        "id":  "249",
+        "unit":  "第二单元 表内除法2",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "把18个苹果平均分给6个小朋友，每个小朋友分( )个，用除法算式表示是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "3;18÷6=3(个)",
+        "solution":  "【分析】根据整数平均分的意义可知，苹果的总数量/平均分的人数=每人分到苹果的数量.\n【详解】把18个苹果平均分给6个小朋友，每个小朋友分3个，用除法算式表示是18÷6=3(个)。",
+        "knowledge_points":  [
+                                 "整数平均分的意义及应用",
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "24-25二年级下·黑龙江佳木斯·期中"
+    },
+    {
+        "id":  "250",
+        "unit":  "第二单元 表内除法2",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "把15分成5份，每份是3。( )",
+        "options":  [
+
+                    ],
+        "answer":  "√",
+        "solution":  "【分析】\"把15分成5份，每份是3\"已经直接说明分成5份后每份都是3，因此这个说法是正确的.\n【详解】因为5份中每份都是3，所以一共是3×5=15，题目说法正确。故答案为:√",
+        "knowledge_points":  [
+                                 "整数平均分的意义及应用",
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·黑龙江佳木斯·期中"
+    },
+    {
+        "id":  "251",
+        "unit":  "第二单元 表内除法2",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "有( )个□，每( )个一组，分成了( )组。",
+        "options":  [
+
+                    ],
+        "answer":  "12;4;3",
+        "solution":  "【分析】由题意可知：根据平均分的意义，共12个□，每4个一组，分成3组，据此可解。\n【详解】有12个□，每4个一组，分成了3组。",
+        "knowledge_points":  [
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·河北邯郸·期中"
+    },
+    {
+        "id":  "252",
+        "unit":  "第二单元 表内除法2",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "12里面有( )个4。",
+        "options":  [
+
+                    ],
+        "answer":  "3",
+        "solution":  "【分析】求一个数里面有几个另一个数，用这个数÷另一个数计算。\n【详解】12÷4=3，12里面有3个4。",
+        "knowledge_points":  [
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·河北邯郸·期中"
+    },
+    {
+        "id":  "253",
+        "unit":  "第二单元 表内除法2",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在括号里填上合适的运算符号（+、-、×或÷）。\n18( )6=12  14( )2=16  6( )6=1  15( )3=5\n12( )2=6  4( )4=16  5( )2=3  16( )4=4\n6( )4=10  2( )2=1  6( )5=30  9( )3=3",
+        "options":  [
+
+                    ],
+        "answer":  "-;+;÷;÷;÷;×;-;÷;+;÷;×;÷",
+        "solution":  "【分析】根据被减数-减数=差，被除数÷除数=商，因数×因数=积，加数+加数=和，结合题干数据进行解答即可。\n【详解】18-6=12，所以括号内填“-”；14+2=16，所以括号内填“+”；6÷6=1，所以括号内填“÷”；15÷3=5，所以括号内填“÷”；12÷2=6，所以括号内填“÷”；4×4=16，所以括号内填“×”；5-2=3，所以括号内填“-”；16÷4=4，所以括号内填“÷”；6+4=10，所以括号内填“+”；2÷2=1，所以括号内填“÷”；6×5=30，所以括号内填“×”；9÷3=3，所以括号内填“÷”。",
+        "knowledge_points":  [
+                                 "不退位减法(20以内)",
+                                 "6的乘法口诀及应用",
+                                 "用2~5的乘法口诀求商",
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·河北邯郸·期中"
+    },
+    {
+        "id":  "254",
+        "unit":  "第二单元 表内除法2",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "每3根小棒摆一个三角形，用18根小棒可以摆( )个独立的三角形。",
+        "options":  [
+
+                    ],
+        "answer":  "6",
+        "solution":  "【分析】根据题意，每3根小棒摆一个三角形，18根小棒可以摆多少个独立的三角形，就是求18里面有几个3，用除法计算，据此解答。\n【详解】18÷3=6（个），所以用18根小棒可以摆6个独立的三角形。",
+        "knowledge_points":  [
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·河北邯郸·期中"
+    },
+    {
+        "id":  "255",
+        "unit":  "第二单元 表内除法2",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "24里面有( )个4。",
+        "options":  [
+
+                    ],
+        "answer":  "6",
+        "solution":  "【分析】求一个数里面有几个相同的数，用除法列式解决。\n【详解】24÷4=6，即24里面有6个4。",
+        "knowledge_points":  [
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·河北邯郸·期中"
+    },
+    {
+        "id":  "256",
+        "unit":  "第二单元 表内除法2",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "把12平均分成3份，每份是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "4",
+        "solution":  "【分析】由题意可知：根据平均分的意义，用12除以3，得数4就是每份数，据此可解。\n【详解】12÷3=4，把12平均分成3份，每份是4。",
+        "knowledge_points":  [
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·河北邯郸·期中"
+    },
+    {
+        "id":  "257",
+        "unit":  "第二单元 表内除法2",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "24÷6=( )，24÷4=( )，它们求商时都用同一句口诀：( )。",
+        "options":  [
+
+                    ],
+        "answer":  "4;6;四六二十四",
+        "solution":  "【分析】在除法算式里，除号前面的数叫被除数，后面的数叫除数，最后的结果叫商。根据乘法口诀求商时，口诀中后一个数作被除数，前面两个数一个作除数，另一个作商。计算24÷6=( )，24÷4=( )时，需要想“6乘几等于24，4乘几等于24”，对应的乘法口诀是：四六二十四。\n【详解】24÷6=4，24÷4=6，它们求商时都用同一句口诀：四六二十四。",
+        "knowledge_points":  [
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·陕西渭南·期中"
+    },
+    {
+        "id":  "258",
+        "unit":  "第二单元 表内除法2",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在算式15÷5=3中，被除数是( )，商是( )，表示把( )平均分成( )份，每份是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "15;3;15;5;3",
+        "solution":  "【分析】除法算式为：被除数÷除数=商，除法算式表示把被除数平均分成除数的份数，商是每份的数。\n【详解】在算式15÷5=3中，被除数是15，商是3，表示把15平均分成5份，每份是3。",
+        "knowledge_points":  [
+                                 "整数平均分的意义及应用",
+                                 "除法的初步认识"
+                             ],
+        "source":  "24-25 二年级下·贵州黔西·期中"
+    },
+    {
+        "id":  "259",
+        "unit":  "第二单元 表内除法2",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "把下面的减法算式改写成除法算式。\n(1)8-2-2-2-2=0 → 8÷2=( )。\n(2)30-5-5-5-5-5-5=0 → 30÷( )=( )。",
+        "options":  [
+
+                    ],
+        "answer":  "4;5;6",
+        "solution":  "【分析】(1)从8里面连续减去4个2，结果是0，也就是8里面包含了4个2。求一个数里面有几个另一个数，用这个数÷另一个数=所求的个数；(2)从30里面连续减去6个5，结果为0，也就是30里面包含6个5，用30除以5计算即可。\n【详解】(1)8-2-2-2-2=0 → 8÷2=4。(2)30-5-5-5-5-5-5=0 → 30÷5=6。",
+        "knowledge_points":  [
+                                 "除法的初步认识",
+                                 "用2~5的乘法口诀求商",
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "24-25二年级下·福建龙岩·期末"
+    },
+    {
+        "id":  "260",
+        "unit":  "第二单元 表内除法2",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "□+□+□+□=16，☆+☆+☆=6，□×☆=( )。",
+        "options":  [
+
+                    ],
+        "answer":  "8",
+        "solution":  "【分析】由“□+□+□+□=16”可知4个□相加是16，因此用16÷4可以求出一个□代表的数；由“☆+☆+☆=6”可知3个☆相加是6，因此用6÷3可以求出一个☆代表的数，用求出的□代表的数乘求出的☆代表的数，填空即可。\n【详解】16÷4=4，6÷3=2，4×2=8，因此□×☆=8。",
+        "knowledge_points":  [
+                                 "4的乘法口诀及应用",
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·山东济南·期中"
+    },
+    {
+        "id":  "261",
+        "unit":  "第二单元 表内除法2",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "把20本图书平均分给4个小朋友，每个小朋友分( )本。",
+        "options":  [
+
+                    ],
+        "answer":  "5",
+        "solution":  "【分析】把一个数平均分成几份，求每份的数，用除法计算，即图书的总数量÷平均分的小朋友人数=每个小朋友分得图书的数量。\n【详解】20÷4=5（本），把20本图书平均分给4个小朋友，每个小朋友分5本。",
+        "knowledge_points":  [
+                                 "整数平均分的意义及应用",
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·山东临沂·期末"
+    },
+    {
+        "id":  "262",
+        "unit":  "第二单元 表内除法2",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "63÷7=9表示把( )平均分成( )份，每份是( )；还表示( )里面有( )个7。",
+        "options":  [
+
+                    ],
+        "answer":  "63;7;9;63;9",
+        "solution":  "【分析】除法算式为：被除数÷除数=商。除法算式表示把被除数平均分成除数的份数，商是每份的数；也可以表示被除数里有商个数的除数。\n【详解】63÷7=9表示把63平均分成7份，每份是9；还表示63里面有9个7。",
+        "knowledge_points":  [
+                                 "整数平均分的意义及应用",
+                                 "除法的初步认识"
+                             ],
+        "source":  "24-25 二年级下·山东临沂·期中"
+    },
+    {
+        "id":  "263",
+        "unit":  "第二单元 表内除法2",
+        "question_type":  "填空题",
+        "difficulty":  0.94,
+        "question":  "计算24÷4和24÷6时，都可以用口诀( )来计算。",
+        "options":  [
+
+                    ],
+        "answer":  "四六二十四",
+        "solution":  "【分析】根据6的乘法口诀“四六二十四”，结合题干要求进行解答即可。\n【详解】计算24÷4和24÷6时，都可以用口诀“四六二十四”来计算。",
+        "knowledge_points":  [
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·黑龙江佳木斯·期中"
+    },
+    {
+        "id":  "264",
+        "unit":  "第二单元 表内除法2",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "把12个苹果平均分成3份，每份是( )个；12里面有( )个4。",
+        "options":  [
+
+                    ],
+        "answer":  "4;3",
+        "solution":  "【分析】把12个苹果平均分成3份，要求每份有多少个，根据除法的意义，用12÷3进行解答即可。要求12里面有几个4，根据除法的意义，用12÷4进行解答即可。\n【详解】12÷3=4（个），所以每份是4个。12÷4=3，所以12里面有3个4。",
+        "knowledge_points":  [
+                                 "整数平均分的意义及应用",
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·黑龙江佳木斯·期中"
+    },
+    {
+        "id":  "265",
+        "unit":  "第二单元 表内除法2",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "12÷3=( )，读作( )，想口诀( )可以求出商。",
+        "options":  [
+
+                    ],
+        "answer":  "4;12除以3等于4;三四十二",
+        "solution":  "【分析】计算12÷3的商时，根据口诀“三四十二”来解答；除法算式为：被除数÷除数=商，除法算式从左往右读，数字直接读出，“÷”读作除以，“=”读作等于，据此解答。\n【详解】12÷3=4，读作12除以3等于4，想口诀三四十二可以求出商。",
+        "knowledge_points":  [
+                                 "除法的初步认识",
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·黑龙江佳木斯·期中"
+    },
+    {
+        "id":  "266",
+        "unit":  "第二单元 表内除法2",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "20÷4=( )，表示把( )平均分成( )份，每份是( )。还可以表示( )里面有( )个( )。",
+        "options":  [
+
+                    ],
+        "answer":  "5;20;4;5;20;5;4",
+        "solution":  "【分析】根据口诀四五二十可知，结果是5。除法算式为：被除数÷除数=商，表示把被除数平均分成除数的份数，商是每份的数；也可以表示被除数里有商个数的除数。\n【详解】20÷4=5，表示把20平均分成4份，每份是5。还可以表示20里面有5个4。",
+        "knowledge_points":  [
+                                 "整数平均分的意义及应用",
+                                 "除法的初步认识",
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·河北邯郸·期中"
+    },
+    {
+        "id":  "267",
+        "unit":  "第二单元 表内除法2",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "10÷5=2读作：( )。其中( )是被除数，( )是除数，( )是商。",
+        "options":  [
+
+                    ],
+        "answer":  "10除以5等于2;10;5;2",
+        "solution":  "【分析】根据除法的初步认识，写出相应的读作；根据除法各部分名称，除号前面的是被除数，后面是除数，得数就是商，据此解答。\n【详解】10÷5=2读作：10除以5等于2。其中10是被除数，5是除数，2是商。",
+        "knowledge_points":  [
+                                 "除法的初步认识",
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·河北邯郸·期中"
+    },
+    {
+        "id":  "268",
+        "unit":  "第二单元 表内除法2",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "把12块糖平均分成3份，每份一定是4块。( )",
+        "options":  [
+
+                    ],
+        "answer":  "√",
+        "solution":  "【分析】在分物体时，每份分得同样多是平均分，用总数量÷平均分的份数=每份的数量，由此解答。\n【详解】12÷3=4（块），把12块糖平均分成3份，每份一定是4块。原题说法正确。故答案为：√",
+        "knowledge_points":  [
+                                 "整数平均分的意义及应用",
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "23-24 二年级下·山东临沂·期末"
+    },
+    {
+        "id":  "269",
+        "unit":  "第二单元 表内除法2",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "把12个苹果分给4人，每人一定分到3个。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】平均分指在分物体时，尽可能地分完且每份得到的数量一样多。把12个苹果平均分给4人，每人一定分3个；若不是平均分，则每人分到的数量不一定是3个，可能是一人分3个，一人分4个，一人分2个，一人分3个。由此解答。\n【详解】把12个苹果分给4人，每人不一定分到3个，原题说法错误。故答案为：×",
+        "knowledge_points":  [
+                                 "整数平均分的意义及应用"
+                             ],
+        "source":  "22-23 二年级下·贵州遵义·期中"
+    },
+    {
+        "id":  "270",
+        "unit":  "第二单元 表内除法2",
+        "question_type":  "判断题",
+        "difficulty":  0.94,
+        "question":  "在算式32÷8=4中，32是被除数，8是商。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】根据被除数÷除数=商，据此结合题干可知：在算式32÷8=4中，32是被除数，8是除数，4是商，据此解答即可。\n【详解】在算式32÷8=4中，32是被除数，8是除数。原题说法错误。故答案为：×",
+        "knowledge_points":  [
+                                 "除法的初步认识"
+                             ],
+        "source":  "24-25 二年级下·湖南长沙·期末"
+    },
+    {
+        "id":  "271",
+        "unit":  "第二单元 表内除法2",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "计算24÷6和24÷4时，用的乘法口诀不同。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】根据乘法口诀“四六二十四”可以写出除法算式有24÷6=4，24÷4=6，据此解决即可。\n【详解】计算24÷6和24÷4时，用同一句乘法口诀“四六二十四”可得出结果，所以原题说法错误。故答案为：×",
+        "knowledge_points":  [
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·湖南长沙·期末"
+    },
+    {
+        "id":  "272",
+        "unit":  "第二单元 表内除法2",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "计算5×6和30÷5都要用到口诀“五六三十”。( )",
+        "options":  [
+
+                    ],
+        "answer":  "√",
+        "solution":  "【分析】根据表内乘法可知，计算5×6的口诀为五六三十。根据表内除法可知，计算30÷5的口诀为五六三十。由此解答即可。\n【详解】计算5×6和30÷5都要用到口诀“五六三十”，说法正确。故答案为：√",
+        "knowledge_points":  [
+                                 "6的乘法口诀及应用",
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "23-24 二年级下·湖北襄阳·期末"
+    },
+    {
+        "id":  "273",
+        "unit":  "第二单元 表内除法2",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "24颗糖分给6个小朋友，每个小朋友一定分到4颗糖。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】平均分的时候每份分得的数量一样多，不是平均分则不一定一样多。\n【详解】题中没有说明是平均分，所以每个小朋友不一定分到4颗糖。原题说法错误。故答案为：×",
+        "knowledge_points":  [
+                                 "整数平均分的意义及应用",
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "23-24 二年级下·湖北襄阳·期末"
+    },
+    {
+        "id":  "274",
+        "unit":  "第二单元 表内除法2",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "把8个萝卜分给2只小兔，每只小兔一定是分得4个。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】平均分的时候每份分得的数量一样多，不是平均分则不一定。\n【详解】把8个萝卜分给2只小兔，不是平均分，所以可以分别是3个和5个，每只小兔不一定分得4个。原题说法错误。故答案为：×",
+        "knowledge_points":  [
+                                 "整数平均分的意义及应用",
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "23-24二年级下·湖北黄石·期末"
+    },
+    {
+        "id":  "275",
+        "unit":  "第二单元 表内除法2",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "把20条鱼放进5个鱼缸里，每个鱼缸里一定放了4条。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】分物体时，每份分得同样多是平均分。金鱼的总数量除以平均分鱼缸的数量，等于每个鱼缸里金鱼的数量。而题目中未说明平均放，因此每个鱼缸的数量不一定，据此解答。\n【详解】20÷5=4（条），把20条鱼平均放进5个鱼缸里，每个鱼缸里一定放了4条。而题干中没有说平均放在5个鱼缸里，则每个鱼缸不一定是4条，原题说法错误。故答案为：×",
+        "knowledge_points":  [
+                                 "整数平均分的意义及应用",
+                                 "除法的初步认识",
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "23-24 二年级下·河南信阳·期末"
+    },
+    {
+        "id":  "276",
+        "unit":  "第二单元 表内除法2",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "把15个苹果分成3份，每份一定是5个。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】分物体时，每份分得同样多是平均分。总数量÷平均分的份数=每份的数量。题目未说明平均分，因此每份的数量不一定。例如，1份分3个，1份分5个，1份分7个，由此解答。\n【详解】15÷3=5（个），把15个苹果平均分成3份时，每份一定是5个。题干中没有说平均分，则每份的数量不一定是5个。原题说法错误。故答案为：×",
+        "knowledge_points":  [
+                                 "整数平均分的意义及应用",
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "23-24 二年级下·甘肃天水·期末"
+    },
+    {
+        "id":  "277",
+        "unit":  "第二单元 表内除法2",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "把36个桃子分成4堆，每堆一定是9个。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】平均分指在分物体时，尽可能地分完且每份得到的数量一样多。把36个桃子平均分成4堆时，每堆一定是9个；但若不是平均分，则每堆不一定是9个；如：一堆是8个，一堆是9个，一堆是9个，一堆是10个，据此判断即可。\n【详解】把36个桃子分成4堆，每堆不一定是9个。原题说法错误。故答案为：×",
+        "knowledge_points":  [
+                                 "整数平均分的意义及应用"
+                             ],
+        "source":  "20-21 二年级下·湖北荆门·期末"
+    },
+    {
+        "id":  "278",
+        "unit":  "第二单元 表内除法2",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "42÷6=7，表示42里面有6个7。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】42÷6=7，可以把42平均分成6份，每份是7，则42里有7个6。\n【详解】42÷6=7，表示42里面有7个6，则原题说法错误。故答案为：×",
+        "knowledge_points":  [
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·湖南湘潭·期中"
+    },
+    {
+        "id":  "279",
+        "unit":  "第二单元 表内除法2",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "24÷3=8，3是除数，24是被除数，8是商。( )",
+        "options":  [
+
+                    ],
+        "answer":  "√",
+        "solution":  "【分析】除法算式为：被除数÷除数=商，由此找出各部分对应的数即可。\n【详解】24÷3=8，3是除数，24是被除数，8是商，原题说法正确。故答案为：√",
+        "knowledge_points":  [
+                                 "除法的初步认识"
+                             ],
+        "source":  "24-25 二年级下·新疆喀什·期中"
+    },
+    {
+        "id":  "280",
+        "unit":  "第二单元 表内除法2",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "计算3×5和15÷3时，用的是同一句乘法口诀。( )",
+        "options":  [
+
+                    ],
+        "answer":  "√",
+        "solution":  "【分析】乘法算式为：乘数×乘数=积，除法算式为：被除数÷除数=商。根据口诀写乘法算式时，口诀中的前两个数是乘数，可互换位置，后一个数是积；根据口诀写除法算式时，口诀中的后一个数是被除数，前两个数可分别为除数和商，据此解答。\n【详解】根据口诀“三五十五”，可以写出两道乘法算式和两道除法算式：3×5=15，5×3=15，15÷3=5，15÷5=3，所以计算3×5和15÷3时，用的是同一句乘法口诀，说法正确。故答案为：√",
+        "knowledge_points":  [
+                                 "5的乘法口诀及应用",
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "24-25二年级下·黑龙江佳木斯·期中"
+    },
+    {
+        "id":  "281",
+        "unit":  "第二单元 表内除法2",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "24÷6=4，表示把24平均分成6份，每份是4。( )",
+        "options":  [
+
+                    ],
+        "answer":  "√",
+        "solution":  "【分析】除法算式为：被除数÷除数=商，可以表示把被除数平均分成除数的份数，商是每份的数，由此解答。\n【详解】24÷6=4，表示把24平均分成6份，每份是4。原题说法正确。故答案为：√",
+        "knowledge_points":  [
+                                 "整数平均分的意义及应用",
+                                 "除法的初步认识",
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·黑龙江佳木斯·期中"
+    },
+    {
+        "id":  "282",
+        "unit":  "第二单元 表内除法2",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "5÷5的商比2÷2的商大。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】根据题意，依次计算出各算式的商，再比较大小即可解答。\n【详解】5÷5=1，2÷2=1，1=1，则5÷5的商和2÷2的商一样大。原题说法错误。故答案为：×",
+        "knowledge_points":  [
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·河北邯郸·期中"
+    },
+    {
+        "id":  "283",
+        "unit":  "第二单元 表内除法2",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "6除以6的商是6。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】除法算式为：被除数÷除数=商，由此代入计算即可。\n【详解】6÷6=1，6除以6的商是1，原题说法错误。故答案为：×",
+        "knowledge_points":  [
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·河北邯郸·期中"
+    },
+    {
+        "id":  "284",
+        "unit":  "第二单元 表内除法2",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "计算2×2和4÷2时，用到的乘法口诀不相同。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】由题意可知：计算2×2用到的口诀是二二得四；计算4÷2做除法想乘法口诀，也是二二得四，所以用到的口诀相同，据此解答。\n【详解】计算2×2和4÷2时，用到的乘法口诀相同，原说法错误。故答案为：×",
+        "knowledge_points":  [
+                                 "2的乘法口诀及应用",
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·河北邯郸·期中"
+    },
+    {
+        "id":  "285",
+        "unit":  "第二单元 表内除法2",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "10里面有5个2。( )",
+        "options":  [
+
+                    ],
+        "answer":  "√",
+        "solution":  "【分析】求一个数里面有几个另一个数，用这个数÷另一个数计算。\n【详解】10÷2=5，10里面有5个2，原题说法正确。故答案为：√",
+        "knowledge_points":  [
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·河北邯郸·期中"
+    },
+    {
+        "id":  "286",
+        "unit":  "第二单元 表内除法2",
+        "question_type":  "计算题",
+        "difficulty":  0.85,
+        "question":  "除数是5，被除数是10，商是几。",
+        "options":  [
+
+                    ],
+        "answer":  "2",
+        "solution":  "【分析】根据被除数÷除数=商，将数据代入，结合5的乘法口诀进行解答即可。\n【详解】10÷5=2，所以商是2。",
+        "knowledge_points":  [
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·河北邯郸·期中"
+    },
+    {
+        "id":  "287",
+        "unit":  "第二单元 表内除法2",
+        "question_type":  "计算题",
+        "difficulty":  0.85,
+        "question":  "12里面有几个2。",
+        "options":  [
+
+                    ],
+        "answer":  "6个",
+        "solution":  "【分析】求12里面有几个2，符合除法的意义，应该用除法计算。据此解答。\n【详解】12÷2=6，答：12里面有6个2。",
+        "knowledge_points":  [
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "24-25二年级下·河北邯郸·期中"
+    },
+    {
+        "id":  "288",
+        "unit":  "第二单元 表内除法2",
+        "question_type":  "计算题",
+        "difficulty":  0.85,
+        "question":  "24个苹果，每6个一份，可以分成几份。",
+        "options":  [
+
+                    ],
+        "answer":  "4份",
+        "solution":  "【分析】要求24个苹果，每6个一份，可以分成几份，即求24里面有几个6，根据除法的意义，用24÷6进行解答即可。\n【详解】24÷6=4（份），答：可以分成4份。",
+        "knowledge_points":  [
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·河北邯郸·期中"
+    },
+    {
+        "id":  "289",
+        "unit":  "第二单元 表内除法2",
+        "question_type":  "计算题",
+        "difficulty":  0.85,
+        "question":  "口算。\n36÷6= 20÷5= 12÷3= 8÷4= 5×6= 16÷4=\n6÷3= 8×5= 24÷4= 18÷3= 7×9= 4÷1=",
+        "options":  [
+
+                    ],
+        "answer":  "6;4;4;2;30;4;2;40;6;6;63;4",
+        "solution":  "【分析】直接根据乘法口诀和除法计算口算即可。\n【详解】36÷6=6，20÷5=4，12÷3=4，8÷4=2，5×6=30，16÷4=4，6÷3=2，8×5=40，24÷4=6，18÷3=6，7×9=63，4÷1=4。",
+        "knowledge_points":  [
+                                 "8的乘法口诀及应用",
+                                 "9的乘法口诀及应用",
+                                 "用2~5的乘法口诀求商",
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "24-25二年级下·河北邯郸·期中"
+    },
+    {
+        "id":  "290",
+        "unit":  "第二单元 表内除法2",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "有24本练习本.\n(1)如果平均分给6人，每人分到几本。\n(2)如果每人分到4本，可以分给几人。",
+        "options":  [
+
+                    ],
+        "answer":  "4本;6人",
+        "solution":  "【分析】(1)用练习本的本数除以平均分给的人数，即可求出每人分到几本。(2)用练习本的本数除以每人分到的本数，即可求出可以分给几人。\n【详解】(1)24÷6=4（本），答：每人分到4本。(2)24÷4=6（人），答：可以分给6人。",
+        "knowledge_points":  [
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "23-24 二年级下·河南信阳·期末"
+    },
+    {
+        "id":  "291",
+        "unit":  "第二单元 表内除法2",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "一本书有24页，小红每天看4页，她几天能看完。",
+        "options":  [
+
+                    ],
+        "answer":  "6天",
+        "solution":  "【分析】一本书有24页，小红每天看4页，要求她几天能看完，即求24里面有几个4，根据除法的意义，用24÷4进行解答即可。\n【详解】24÷4=6（天），答：她6天能看完。",
+        "knowledge_points":  [
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "24-25二年级下·山东济宁·期末"
+    },
+    {
+        "id":  "292",
+        "unit":  "第二单元 表内除法2",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "钢笔原来8元一支，现在优惠促销,3支18元，现在每支多少元。现在每支比原来便宜多少元。",
+        "options":  [
+
+                    ],
+        "answer":  "6元;2元",
+        "solution":  "【分析】根据题意，用现在买3支钢笔花的钱数除以买的数量，求出每支钢笔的钱数，再用原来每支的钱数减去现在每支的钱数，即是便宜的钱数。\n【详解】18÷3=6（元），8-6=2（元），答：现在每支6元，现在每支比原来便宜2元。",
+        "knowledge_points":  [
+                                 "8,9的加减法",
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·山东临沂·期末"
+    },
+    {
+        "id":  "293",
+        "unit":  "第二单元 表内除法2",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "小华买了3块卡通手表花了18元，你知道一块卡通手表多少元钱吗。",
+        "options":  [
+
+                    ],
+        "answer":  "6元",
+        "solution":  "【分析】根据除法的意义，买卡通手表花的总钱数÷买卡通手表的数量=每块卡通手表的钱数。\n【详解】18÷3=6（元），答：一块卡通手表6元钱。",
+        "knowledge_points":  [
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "24-25二年级下·河北邯郸·期中"
+    },
+    {
+        "id":  "294",
+        "unit":  "第二单元 表内除法2",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "有20个气球，平均分给5个小朋友，每个小朋友分几个。",
+        "options":  [
+
+                    ],
+        "answer":  "4个",
+        "solution":  "【分析】用气球的总个数除以平均分给的小朋友人数，即可求出每个小朋友分几个。\n【详解】20÷5=4（个），答：每个小朋友分4个。",
+        "knowledge_points":  [
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "24-25二年级下·黑龙江佳木斯·期中"
+    },
+    {
+        "id":  "295",
+        "unit":  "第二单元 表内除法2",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "3只小白兔一天吃了6个萝卜，平均每只小白兔一天吃几个萝卜。",
+        "options":  [
+
+                    ],
+        "answer":  "2个",
+        "solution":  "【分析】要求平均每只小白兔一天吃几个萝卜，即求6里面有几个3，根据除法的意义，用6÷3进行解答即可。\n【详解】6÷3=2（个），答：平均每只小白兔一天吃2个萝卜。",
+        "knowledge_points":  [
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·河北邯郸·期中"
+    },
+    {
+        "id":  "296",
+        "unit":  "第二单元 表内除法2",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "有30个羽毛球.\n(1)平均装到5个筒中，每筒装几个。\n(2)每筒装6个，可以装几筒。",
+        "options":  [
+
+                    ],
+        "answer":  "6个;5筒",
+        "solution":  "【分析】(1)根据除法的意义，羽毛球的总数量÷平均装的筒数=每筒装的数量；(2)根据除法的意义，羽毛球的总数量÷每筒装的数量=可以装的筒数。\n【详解】(1)30÷5=6（个），答：每筒装6个。(2)30÷6=5（筒），答：可以装5筒。",
+        "knowledge_points":  [
+                                 "用2~5的乘法口诀求商",
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "24-25二年级下·河北邯郸·期中"
+    },
+    {
+        "id":  "297",
+        "unit":  "第二单元 表内除法2",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "有20个气球，平均分给4个小朋友，每个小朋友分得几个气球。",
+        "options":  [
+
+                    ],
+        "answer":  "5个",
+        "solution":  "【分析】由题意可知：根据除法的意义，把20个气球平均分给4个小朋友，需要把20平均分成4份，应该用除法计算。据此解答。\n【详解】20÷4=5（个），答：每个小朋友分得5个气球。",
+        "knowledge_points":  [
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·黑龙江佳木斯·期中"
+    },
+    {
+        "id":  "298",
+        "unit":  "第二单元 表内除法2",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "一本故事书有36页，小明每天看6页，几天可以看完。",
+        "options":  [
+
+                    ],
+        "answer":  "6天",
+        "solution":  "【分析】用故事书的总页数除以每天看的页数，即可求出几天可以看完。\n【详解】36÷6=6（天），答：6天可以看完。",
+        "knowledge_points":  [
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·黑龙江佳木斯·期中"
+    },
+    {
+        "id":  "299",
+        "unit":  "第二单元 表内除法2",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "二(1)班第一小组5名同学要编25个花篮。平均每名同学编几个花篮。",
+        "options":  [
+
+                    ],
+        "answer":  "5个",
+        "solution":  "【分析】根据除法的意义，要编花篮的总数量÷同学的人数=每名同学要编花篮的数量。\n【详解】25÷5=5（个），答：平均每名同学要编5个花篮。",
+        "knowledge_points":  [
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·河北邯郸·期中"
+    },
+    {
+        "id":  "300",
+        "unit":  "第二单元 表内除法2",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "有24支钢笔，平均分给6人，每人分几支。",
+        "options":  [
+
+                    ],
+        "answer":  "4支",
+        "solution":  "【分析】求每人分几支，也就是把24平均分成6份，每份是多少，用除法计算，即钢笔的总数量÷平均分的人数=每人分的数量。\n【详解】24÷6=4（支），答：每人分4支。",
+        "knowledge_points":  [
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·河北邯郸·期中"
+    },
+    {
+        "id":  "301",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "不可以用15÷3表示的是( )。",
+        "options":  [
+                        "15平均分成3份",
+                        "15除以5",
+                        "15里面有几个3"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】根据除法的意义，15÷3表示的是把15平均分成3份，也表示把15每3个一份，求分成了几份，也就是15里面有几个3；据此解答。\n【详解】A。15平均分成3份，可以用15÷3表示；B。15除以5，不可以用15÷3表示；C。15里面有几个3，可以用15÷3表示。故答案为：B",
+        "knowledge_points":  [
+                                 "整数平均分的意义及应用",
+                                 "除法的初步认识",
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·陕西渭南·期中"
+    },
+    {
+        "id":  "302",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "下面第( )种分法是平均分。\n![](images/170844.png)",
+        "options":  [
+                        "A",
+                        "B",
+                        "C"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】在分物体时，每份分得同样多，就是平均分，据此解答。\n【详解】A。每份的数量不相同，一份3个，一份1个，不是平均分；B。每份的数量不相同，一份3个，一份2个，不是平均分；C。分成2份，每份的数量相同，是平均分。故答案为：C",
+        "knowledge_points":  [
+                                 "整数平均分的意义及应用"
+                             ],
+        "source":  "24-25二年级下·湖南长沙·期中"
+    },
+    {
+        "id":  "303",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "把12根小棒平均分给3个小朋友，正确的分法是( )。\n![](images/170918.png)",
+        "options":  [
+                        "A",
+                        "B",
+                        "C"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】根据除法的意义，12根小棒被平均分给3个小朋友，求每个小朋友分到的小棒数即可，据此解答。\n【详解】12÷3=4（根），12根小棒被平均分给3个小朋友，每个小朋友分4根。A。表示分给3个小朋友，每个小朋友分别分3、4、5根小棒，不是平均分，错误；B。表示分给4个小朋友，每个小朋友分3根小棒，错误；C。表示分给3个小朋友，每个小朋友分4根小棒，正确。故答案为：C",
+        "knowledge_points":  [
+                                 "整数平均分的意义及应用"
+                             ],
+        "source":  "24-25 二年级下·福建莆田·期中"
+    },
+    {
+        "id":  "304",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "![](images/ab88f1735087f71fcf84646dc5513776320a3dbd40c61114a0126068a3d63011.jpg) ÷5=![](images/ce6655ee8f9690f75716722cfceccfabcfd8eef535da8c5de953fbd9651ccfcb.jpg) ÷6，( )表示的数大。",
+        "options":  [
+                        "![](images/ab88f1735087f71fcf84646dc5513776320a3dbd40c61114a0126068a3d63011.jpg)",
+                        "![](images/ce6655ee8f9690f75716722cfceccfabcfd8eef535da8c5de953fbd9651ccfcb.jpg)",
+                        "无法确定"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】根据题意，两个算式的商相同。可令它们的商都等于1，根据除数×商=被除数，计算出左图和右图分别表示的数，再比较大小即可解答。\n【详解】左图÷5=1，则左图表示5；右图÷6=1，则右图表示6。5\u003c6，所以右图表示的数大。故答案为：B",
+        "knowledge_points":  [
+                                 "用2~5的乘法口诀求商",
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·辽宁鞍山·期中"
+    },
+    {
+        "id":  "305",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "要把18个鲜花饼装进盒子里，每个盒子装6个，需要几个盒子。下面的思考过程错误的是( )。",
+        "options":  [
+                        "盒数123总个数61218",
+                        "(三)六十八18÷3=6",
+                        "![](images/b0a7f9156299868651ebc40f9022db3fb17003b903b32b72a8d6f52cfc0e7964.jpg)"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】求需要几个盒子，也就是18里面有几个6。可以用几个6的和是18，或者从18里面连续减去几个6结果是0，或者用18除以6来计算。\n【详解】A。1盒可以装6个，2盒可以装12个，3盒可以装18个，需要3个盒子，也就是18里面有3个6，思考过程正确；B。18÷3=6表示18里面有6个3，思考过程错误；C。从18里面连续减了3次6结果是0，也就是18里面有3个6，思考过程正确。则思考过程错误的是B。故答案为：B",
+        "knowledge_points":  [
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·辽宁鞍山·期中"
+    },
+    {
+        "id":  "306",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "下面图( )中的物品不是平均分。",
+        "options":  [
+                        "①",
+                        "②",
+                        "③"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】在分物体时，每份分得同样多，是平均分，由此解答。\n【详解】①分成了2份，每份都是4个，是平均分；②分成了3份，一份是1个，一份是2个，一份是3个，每份的数量不同，不是平均分；③分成了3份，每份都是2个，是平均分。则②中的物品不是平均分。故答案为：B",
+        "knowledge_points":  [
+                                 "整数平均分的意义及应用"
+                             ],
+        "source":  "24-25 二年级下·辽宁鞍山·期中"
+    },
+    {
+        "id":  "307",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "12只蜻蜓飞到2朵荷花上，一朵上有4只，另一朵荷花上有几只蜻蜓。列式正确的是( )。",
+        "options":  [
+                        "12÷2",
+                        "12-4",
+                        "12÷4"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】用蜻蜓的总数减其中一朵荷花上的只数即可得出另一朵荷花上的只数。\n【详解】12只蜻蜓飞到2朵荷花上，一朵上有4只，另一朵荷花上有几只蜻蜓。列式正确的是12-4。故答案为：B",
+        "knowledge_points":  [
+                                 "十几减5~2的退位减法",
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "24-25二年级下·河南南阳·期中"
+    },
+    {
+        "id":  "308",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "如图，求减了几个\"6\"，列式正确的是( )。",
+        "options":  [
+                        "24÷6",
+                        "24÷4",
+                        "24-6"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】根据题意，求减了几个“6”，也就是求24里面有几个6，用24除以6计算。\n【详解】A。24÷6=4，表示24里面有4个6，符合题意；B。24÷4=6，表示24里面有6个4，不符合题意；C。24-6=18，表示24减去6得18，不符合题意。则求减了几个“6”，列式正确的是24÷6。故答案为：A",
+        "knowledge_points":  [
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·青海果洛·期中"
+    },
+    {
+        "id":  "309",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "现有18个梨，每6个放一盘，能放几盘呢。正确的列式应该是( )。",
+        "options":  [
+                        "18-6",
+                        "18÷6",
+                        "18×6"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】求能放几盘，也就是求18里面有几个6，用除法计算，即梨的总数量÷每盘放的数量=可以放的盘数。\n【详解】18÷6=3（盘），能放3盘。则正确的列式应该是18÷6。故答案为：B",
+        "knowledge_points":  [
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "24-25二年级下·黑龙江佳木斯·期中"
+    },
+    {
+        "id":  "310",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "猴妈妈有一堆桃子，数量比20个多，比40个少，已知分给小猴的份数和每份的个数同样多，这堆桃子可能有( )个。",
+        "options":  [
+                        "20",
+                        "26",
+                        "36",
+                        "40"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】根据题意，桃子的总数量÷平均分的小猴数量=每个小猴分到的数量，也就是除数和商相同。先比较各选项与20、40的大小关系，找到比20大比40小的数，再根据乘法口诀，找到符合题意的数即可。\n【详解】A。20=20\u003c40，不符合题意；B。20\u003c26\u003c40，乘法口诀中没有两个相同数的积是26，不符合题意；C。20\u003c36\u003c40，根据口诀六六三十六可知，36÷6=6（个），符合题意；D。20\u003c40=40，不符合题意。则这堆桃子可能有36个。故答案为：C",
+        "knowledge_points":  [
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·福建龙岩·期中"
+    },
+    {
+        "id":  "311",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "把24本书分给阳阳和他的3个伙伴，平均每人分到( )本书。",
+        "options":  [
+                        "9",
+                        "8",
+                        "7",
+                        "6"
+                    ],
+        "answer":  "D",
+        "solution":  "【分析】根据题意，先用加法计算出一共要分给几个人，再用书的总数量÷平均分的人数=每人分到书的数量。\n【详解】1+3=4（人），24÷4=6（本），把24本书分给阳阳和他的3个伙伴，平均每人分到6本书。故答案为：D",
+        "knowledge_points":  [
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "24-25二年级下·福建龙岩·期中"
+    },
+    {
+        "id":  "312",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "下面不可以用12÷3解决的是( )。",
+        "options":  [
+                        "![](images/1f07169e0462d76c3c9b047653e5da845f9d2d333551721f687d459acad5fdf3.jpg)",
+                        "![](images/f861a5bbb582a27a5adc1290a86e016666e62d70db1575d768b5e790be92cac7.jpg)",
+                        "![](images/976a31a561fd298fb28d78b592d206f5c1e35322035c5cd5c26c66efc4b5273d.jpg)"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】12÷3可以表示把12平均分成3份，每份是多少，也可以表示一共有12个，每份是3个，可以分成几份，由此解答。\n【详解】A。12个○，分成了3份，一份是3个，一份是4个，一份是5个，每份的数量不同，不能用除法计算；B。一共有12个萝卜，每盘是3个，可以放4盘，列式为12÷3=4；C。一共有12支蜡笔，每份是3个，分成了4份，列式为12÷3=4。则不可以用12÷3解决的是A。故答案为：A",
+        "knowledge_points":  [
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·青海果洛·期中"
+    },
+    {
+        "id":  "313",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "星期天，明明一家人吃饭，明明准备了10根筷子，明明家一共有( )人吃饭。",
+        "options":  [
+                        "2",
+                        "5",
+                        "7"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】根据生活实际情况，一双筷子需要2根。求吃饭一共有几个人，利用整数除法的意义，求出10里面有几个2，用除法解答即可。\n【详解】10÷2=5（人），由此可知，明明家一共有5人吃饭。故答案为：B",
+        "knowledge_points":  [
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "24-25二年级下·贵州六盘水·期中"
+    },
+    {
+        "id":  "314",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "求18里面有几个3，列式为( )。",
+        "options":  [
+                        "18-3=15",
+                        "18÷6=3",
+                        "18÷3=6"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】要求18里面有几个3，根据除法的意义，用18÷3进行解答即可。\n【详解】18÷3=6，所以18里面有6个3。故答案为：C",
+        "knowledge_points":  [
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·河北唐山·期中"
+    },
+    {
+        "id":  "315",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "下面三种袜子的质量是一样的，买哪一种最便宜。( )",
+        "options":  [
+                        "![](images/6005ae6be384e3aa12923e3146625094aa545309317f605136ef188cc18d1113.jpg) 12元",
+                        "![](images/368a468ba2d757af4c0845beaaefd8c0f546583a4f4793d755a9d2894e5452e0.jpg) 15元",
+                        "![](images/73b7165679e9d0ea12d06752b080b5e2c02dc90bfa0387a06c27361b74ce4f12.jpg)"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】要想知道三种质量一样的袜子哪一种最便宜，需要分别算出这三种袜子每双袜子的价钱，价钱最少的最便宜。\n【详解】A。12÷2=6（元）；B。15÷3=5（元）；C。30÷5=6（元）；5\u003c6，第二种袜子最便宜。故答案为：B",
+        "knowledge_points":  [
+                                 "用2~5的乘法口诀求商",
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "24-25二年级下·重庆九龙坡·期中"
+    },
+    {
+        "id":  "316",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "下列选项中可以用18÷2表示的是( )。",
+        "options":  [
+                        "把18分成2份",
+                        "把18平均分成6份",
+                        "18里面有几个2"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】除法有两种，一种是平均分，将总数平均分成若干份，求每份的数量；另一种是包含除，求总数中包含多少个另一个数。题目要求找出可以用算式18÷2表示的选项，逐项分析各个选项，找出正确答案即可。\n【详解】A。把18分成2份未说明“平均分”，无法确定每份是否相等，因此不能用18÷2表示；B。18被平均分成6份，算式应为18÷6=3，与18÷2不符；C。求18里有多少个2，包含除，对应算式18÷2=9，可以用18÷2表示。综上，正确答案是C。故答案为：C",
+        "knowledge_points":  [
+                                 "整数平均分的意义及应用",
+                                 "除法的初步认识"
+                             ],
+        "source":  "24-25 二年级下·河南南阳·期中"
+    },
+    {
+        "id":  "317",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "有20个○能摆成几个□。列式正确的是( )。",
+        "options":  [
+                        "20÷4=5",
+                        "25÷5=4",
+                        "4×5=20"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】由图可知，摆1个□需要用4个小方块，求20个小方块可以摆几个□，用除法计算，即小方块的总数量÷摆1个□用小方块的数量=可以摆□的个数。\n【详解】20÷4=5（个），有20个○能摆成5个□。列式正确的是20÷4=5。故答案为：A",
+        "knowledge_points":  [
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "24-25二年级下·河南南阳·期中"
+    },
+    {
+        "id":  "318",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "16颗糖果，平均分给4个小朋友，正确的选项是( )。",
+        "options":  [
+                        "![](images/432e66f6440d2fdef3075cd1aa83e82be24663de0769228a940fdaa26d10f5db.jpg)",
+                        "![](images/cc4cd54c9cca4242a13cb758827552413c517df72b116415379ba22d06132d81.jpg)",
+                        "![](images/ce581357b4206ff4aa2981516ae70858a17bfbbfbb6f385689b13cc54751343c.jpg)"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】分物体时，每份分得同样多，是平均分。由此分析各选项所表示的意义即可解答。\n【详解】A。把12颗糖果平均分成了3份，每份是4颗，不符合题意；B。把16颗糖果平均分成了4份，每份是4颗，符合题意；C。把12颗糖果平均分成了4份，每份是3颗，不符合题意。则16颗糖果，平均分给4个小朋友，正确的选项是B。故答案为：B",
+        "knowledge_points":  [
+                                 "整数平均分的意义及应用"
+                             ],
+        "source":  "24-25 二年级下·河南南阳·期中"
+    },
+    {
+        "id":  "319",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "下面的算式中，商值最小的是( )。",
+        "options":  [
+                        "12÷2",
+                        "24÷6",
+                        "18÷3"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】根据除法的意义，被除数÷除数=商，将每个选项的商计算出来，再比较大小即可解答。\n【详解】A。12÷2=6；B。24÷6=4；C。18÷3=6；6=6\u003e4，故答案为：B",
+        "knowledge_points":  [
+                                 "9以内数的比大小",
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·黑龙江佳木斯·期中"
+    },
+    {
+        "id":  "320",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "把16个苹果平均分，每人至少分到2个，且没有剩余，有( )种分法。",
+        "options":  [
+                        "1",
+                        "2",
+                        "3",
+                        "4"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】每份分得同样多，叫平均分。根据题意，把16个苹果平均分，每人至少分到2个，且没有剩余，需找出所有符合条件的分法，并把它们全写出来，数一数有几种即可解答。\n【详解】每人分2个，可以分给8人；每人分4个，可以分给4人；每人分8个，可以分给2人；数一数，有3种分法。故答案为：C",
+        "knowledge_points":  [
+                                 "整数平均分的意义及应用"
+                             ],
+        "source":  "24-25二年级下·福建龙岩·期中"
+    },
+    {
+        "id":  "321",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "四个小朋友画图表示算式“6÷3=2”的含义，正确的有( )人。\n![](images/56f8f879a9a9c2abef0ef0ab8c131efbac1d73fa328f98343c33fa86488fb946.jpg) ![](images/f90a624760a451bb46c8f417d57cee54e2dffe9e47a4210f97b38a329236da70.jpg) ![](images/755bc27ae3594afb6fe24cfa6f3c3b5e560925dff592cc47e33ffa6609c6b45a.jpg) ![](images/ca041fd9ff5f6f2f20425924f7c9efc671270b9d84b2ecea2423a8853f0d0d49.jpg)",
+        "options":  [
+                        "4",
+                        "3",
+                        "2",
+                        "1"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】除法算式中，被除数表示总数，除数表示平均分成的份数，商表示每份的数量；或者被除数表示总数，除数表示每份的数量，商表示平均分成的份数。逐项分析。\n【详解】A。表示将6个心分成3份，求每份几个，正确；B。表示一共6个，平均每份3个，求分成了几份，正确；C。表示将6个心平均分成3份，求每份几个，正确；D。表示一共6个，平均每份2个，求分成了几份，用6÷2，不正确。正确的有3人。故答案为：B",
+        "knowledge_points":  [
+                                 "除法的初步认识"
+                             ],
+        "source":  "24-25二年级下·福建龙岩·期中"
+    },
+    {
+        "id":  "322",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "不可以用算式“15÷3”解决的问题是( )。",
+        "options":  [
+                        "被除数是15，除数是3，商是几",
+                        "15里面有几个3",
+                        "把15平均分成3份，每份是几",
+                        "15朵花,5朵扎一束，可以扎几束"
+                    ],
+        "answer":  "D",
+        "solution":  "【分析】被除数÷除数=商。除法算式中，被除数表示总数，除数表示平均分成的份数，商表示每份的数量；或者被除数表示总数，除数表示每份的数量，商表示平均分成的份数。逐项分析。\n【详解】A。被除数是15，除数是3，求商，用算式“15÷3”解决，商是5；B。求15里面有几个3，用算式“15÷3”解决，即15里面有5个3；C。把15平均分成3份，求每份是多少，用算式“15÷3”解决，每份是5；D。15朵花，5朵扎一束，求可以扎几束，用算式“15÷5”解决，可以扎3束。不可以用算式“15÷3”解决的问题是：15朵花，5朵扎一束，可以扎几束。故答案为：D",
+        "knowledge_points":  [
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·福建龙岩·期中"
+    },
+    {
+        "id":  "323",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "12个青团,4个装一盒，可以装几盒。四位同学的做法中，错误的是( )。",
+        "options":  [
+                        "12÷4=3(盒)可以装3盒。",
+                        "12-4-4-4=0可以装3盒。",
+                        "![](images/171820.png)"
+                    ],
+        "answer":  "D",
+        "solution":  "【分析】除法算式中，被除数表示总数，除数表示平均分成的份数，商表示每份的数量；或者被除数表示总数，除数表示每份的数量，商表示平均分成的份数。除法可以表示一个数中有几个另一个数。逐项分析。\n【详解】A。总数除以每盒的个数，正确；B。表示12中有3个4，正确；C。4个圈一份，圈了3份，正确；D。表示每份3个，即每盒3个，不正确。四位同学的做法中，错误的是D。故答案为：D",
+        "knowledge_points":  [
+                                 "除法的初步认识",
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·福建龙岩·期中"
+    },
+    {
+        "id":  "324",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "下面四种分法中，第( )种是平均分.\n![](images/171809.png)",
+        "options":  [
+                        "A",
+                        "B",
+                        "C",
+                        "D"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】在分物体的时候，每份分得同样多，叫平均分，由此解答。\n【详解】A。分成了3份，分别有1个、2个、3个，每份数量不一样，不是平均分；B。分成了2份，分别有4个、2个，每份数量不一样，不是平均分；C。分成了2份，每份都是3个，每份数量相同，是平均分；D。分成了2份，分别有5个、1个，每份数量不一样，不是平均分。故答案为：C",
+        "knowledge_points":  [
+                                 "整数平均分的意义及应用"
+                             ],
+        "source":  "24-25 二年级下·福建龙岩·期中"
+    },
+    {
+        "id":  "325",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "在18÷3算式中读作( )。",
+        "options":  [
+                        "18除3",
+                        "18除以3",
+                        "3除以18",
+                        "8除3"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】读除法算式时，依次从左往右读，“÷”读作除以，“=”读作等于，数字直接读出来。\n【详解】在18÷3算式中读作18除以3。故答案为：B",
+        "knowledge_points":  [
+                                 "除法的初步认识"
+                             ],
+        "source":  "24-25 二年级下·湖南怀化·期中"
+    },
+    {
+        "id":  "326",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "一根绳子长16米，对折后再对折，每段长( )米。",
+        "options":  [
+                        "4",
+                        "8",
+                        "16",
+                        "2"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】根据题意，对折1次分成了同样长的2段，对折2次分成了同样长的2×2段，先用乘法计算出一共分成了多少段，再用总长度÷段数=每段的长度，由此解答。\n【详解】2×2=4（段），16÷4=4（米），一根绳子长16米，对折后再对折，每段长4米。故答案为：A",
+        "knowledge_points":  [
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·福建龙岩·期中"
+    },
+    {
+        "id":  "327",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "二(2)班“数学小达人”投票中，统计时用画“正”字记录，亮亮得了30票，他得了( )个“正”字。",
+        "options":  [
+                        "3",
+                        "5",
+                        "6"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】由题意可知，根据除法的意义，一个“正”字是5画，也就是5票，看30票里有几个5票，就得几个“正”字，由此可解。\n【详解】30÷5=6（个），所以二(2)班“数学小达人”投票中，统计时用画“正”字记录，亮亮得了30票，他得了6个“正”字。故答案为：C",
+        "knowledge_points":  [
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "24-25二年级下·贵州六盘水·期中"
+    },
+    {
+        "id":  "328",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "一件上衣需要用5个纽扣，30个纽扣可以配( )件上衣。",
+        "options":  [
+                        "5",
+                        "10",
+                        "6"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】已知一件上衣需要用5个纽扣，要求30个纽扣可以配几件上衣，根据除法的意义，用30÷5进行解答即可。\n【详解】30÷5=6（件），所以30个纽扣可以配6件上衣。故答案为：C",
+        "knowledge_points":  [
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "24-25二年级下·山东临沂·期中"
+    },
+    {
+        "id":  "329",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "把12个◇平均分成3份，下面的分法正确的是( )。",
+        "options":  [
+                        "![](images/23fcc6fb53692d43029f1865d8c59b989259f5a77f1ed949a2e2887fc4a557b4.jpg)",
+                        "![](images/acc3bca390d903eb19e647dda3aa8747686248ff3b3d9b1f00e33471dd643fab.jpg)",
+                        "![](images/e0085613ed34d4ad7503f576a189e5378b14cbece7e8b601528c82c0a5292fa4.jpg)"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】把一个数平均分成若干份，求每份是多少，用除法列式解决。12÷3=4（个），即把12个◇平均分成3份，每份是4个。\n【详解】A。这里只有11个◇，不符合题意；B。这里只有9个◇，不符合题意；C。这里有12个◇，且是平均分成3份，每份是4个，符合题意。故答案为：C",
+        "knowledge_points":  [
+                                 "整数平均分的意义及应用",
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·江西宜春·期中"
+    },
+    {
+        "id":  "330",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "王师傅说：“我每天加工5把椅子。”李师傅说：“我4天加工16把椅子。”他们谁做得快些。( )",
+        "options":  [
+                        "王师傅",
+                        "李师傅",
+                        "一样快"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】用李师傅做的总把数除以做的天数得出每天做的把数，然后将两人每天做的把数作比较，把数越多做得越快。\n【详解】16÷4=4（把），5\u003e4，王师傅做得快些。故答案为：A",
+        "knowledge_points":  [
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·河北沧州·期中"
+    },
+    {
+        "id":  "331",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "“一共有8个○，每2个一份，可以分成4份”这句话可以用算式( )表示，也可以用图( )表示。",
+        "options":  [
+                        "②③",
+                        "①③",
+                        "②④",
+                        "①④"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】根据题意可知，一共有8个○，每2个一份，可以分成4份，就是求8里面有几个2，用除法列式计算。即用算式8÷2=4表示；画图时，就是把8个○，每2个圈一下，圈了4次，即图③表示，据此解答。\n【详解】“一共有8个○，每2个一份，可以分成4份”这句话可以用算式②表示，也可以用图③表示。A。②③，对应的算式为8÷2=4，对应的图为③，答案正确；B。①③，对应的算式为8÷4=2，对应的图为③，答案错误；C。②④，对应的算式为8÷2=4，对应的图为④，答案错误；D。①④，对应的算式为8÷4=2，对应的图为④，答案错误。故答案为：A",
+        "knowledge_points":  [
+                                 "除法的初步认识",
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·浙江宁波·期中"
+    },
+    {
+        "id":  "332",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "下列说法中正确的是( )。",
+        "options":  [
+                        "把30颗糖分给5个小朋友，每个小朋友一定分到6颗糖。",
+                        "从24里面连续减6，减4次结果为0。",
+                        "任何一句乘法口诀都可以写出两个不同的除法算式。"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】只说了分给5个小朋友，没有说平均分，所以不一定能用除法计算，结果也就不一定了。先算24里面有几个6，再用几减4，如果最后得0说法就正确，如果不得0就不正确；举例说明说法是否正确。\n【详解】A。结果不一定是6颗，说法不正确；B。24÷6=4，4-4=0，说法正确；C。例如：三三得九这句口诀，只能写出9÷3=3这一道除法算式，所以说法不正确。故答案为：B",
+        "knowledge_points":  [
+                                 "整数平均分的意义及应用",
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "24-25二年级下·重庆九龙坡·期中"
+    },
+    {
+        "id":  "333",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "下面哪个问题可以用12÷2解决。( )",
+        "options":  [
+                        "12个苹果，吃了2个，还剩几个。",
+                        "12元买2支笔，每支多少钱。",
+                        "每堆2个西瓜,12个能放几堆。",
+                        "B和C都可以"
+                    ],
+        "answer":  "D",
+        "solution":  "【分析】根据各选项所给的条件，逐一分析，即可知哪个问题可以用12÷2解决。\n【详解】A。“12个苹果，吃了2个，还剩几个。”列式为12-2，不能用12÷2解决；B。“12元买2支笔，每支多少钱。”列式为12÷2，可以用12÷2解决；C。“每堆2个西瓜，12个能放几堆。”列式为12÷2，可以用12÷2解决；D。通过以上分析，B和C都可以用12÷2来解决。故答案为：D",
+        "knowledge_points":  [
+                                 "除法的初步认识"
+                             ],
+        "source":  "24-25 二年级下·湖南长沙·期中"
+    },
+    {
+        "id":  "334",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "下面哪种分法是平均分。( )",
+        "options":  [
+                        "把8块糖分给2人，一人3块，一人5块",
+                        "把10个草莓分到2个盘子，每盘5个",
+                        "把12本书分给3个班，每班4本",
+                        "B和C都是"
+                    ],
+        "answer":  "D",
+        "solution":  "【分析】把一些物品分成几份，每份分得同样多，这样的分法叫平均分。据此解决即可。\n\n【详解】A。把8块糖分给2人，一人3块，一人5块，每人分得不一样多，这样的分法不是平均分；B。把10个草莓分到2个盘子，每盘都是5个，每盘分得同样多，这样的分法是平均分；C。把12本书分给3个班，每班4本，每班分得一样多，这样的分法是平均分；D.B和C的分法都是平均分。故答案为：D",
+        "knowledge_points":  [
+                                 "整数平均分的意义及应用"
+                             ],
+        "source":  "24-25二年级下·湖南长沙·期中"
+    },
+    {
+        "id":  "335",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "小红的妈妈买了一些苹果，每个小朋友分到3个苹果，正好分完。题目中需要补充哪个信息才能求出“一共有多少个小朋友”。( )",
+        "options":  [
+                        "每个苹果2元钱",
+                        "妈妈一共买了15个苹果",
+                        "小朋友们都喜欢吃苹果",
+                        "小红家有5个小朋友"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】逐一分析所给选项，看补充哪个信息可以求出“一共有多少个小朋友”。\n\n【详解】A。“每个苹果2元钱”，每个小朋友分到3个苹果，用每个苹果的价钱乘每个小朋友分到的苹果个数，可以求出每个小朋友分的苹果一共多少钱，不符合题意；B。“妈妈一共买了15个苹果”，每个小朋友分到3个苹果，用苹果的个数除以每个小朋友分到的苹果个数，可以求出一共有多少个小朋友，符合题意；C。“小朋友们都喜欢吃苹果”，此条件在解题中没有任何作用，不符合题意；D。“小红家有5个小朋友”，每个小朋友分到3个苹果，用人数乘每个小朋友分到的苹果个数，可以求出妈妈一共买了多少个苹果，不符合题意。故答案为：B",
+        "knowledge_points":  [
+                                 "\"提问题\"\"填条件\"问题",
+                                 "5的乘法口诀及应用",
+                                 "3的乘法口诀及应用",
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·广东广州·期中"
+    },
+    {
+        "id":  "336",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "下面各算式，除数最大的是( )。",
+        "options":  [
+                        "24÷3=8",
+                        "18÷9=2",
+                        "63÷7=9"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】除法算式为被除数÷除数=商，由此找出各算式的除数比较大小即可。\n\n【详解】A.24÷3=8，除数是3；B.18÷9=2，除数是9；C.63÷7=9，除数是7；9\u003e7\u003e3，除数最大的是18÷9=2。故答案为：B",
+        "knowledge_points":  [
+                                 "9以内数的比大小",
+                                 "除法的初步认识"
+                             ],
+        "source":  "24-25 二年级下·广东东莞·期中"
+    },
+    {
+        "id":  "337",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "甲、乙、丙三家超市卖同一款毛巾，甲超市12元3条，乙超市10元2条，丙超市25元5条，小丽想买一条毛巾（都可以单卖），去( )超市买划算。",
+        "options":  [
+                        "甲",
+                        "乙",
+                        "丙"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】用总价钱除以对应毛巾的总数量，求出商，就是对应每条毛巾的钱数，然后比较大小，即可解决。\n\n【详解】12÷3=4（元），10÷2=5（元），25÷5=5（元），4\u003c5，即去甲超市买划算。故答案为：A",
+        "knowledge_points":  [
+                                 "5以内数的比大小",
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·山东济宁·期末"
+    },
+    {
+        "id":  "338",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "根据乘法口诀“二六十二”，可以写出两道乘法算式分别是( )和( )；也可以写出两道除法算式分别是( )和( )。",
+        "options":  [
+
+                    ],
+        "answer":  "2×6=12;6×2=12;12÷2=6;12÷6=2",
+        "solution":  "【分析】写出乘法算式：口诀的前半句“二六”分别是乘法里的两个乘数，口诀得数“十二”就是积；写出除法算式：口诀的得数“十二”是被除数，前半句“二六”分别是除数和商；据此可解。\n\n【详解】根据乘法口诀“二六十二”，可以写出两道乘法算式分别是2×6=12和6×2=12；也可以写出两道除法算式分别是12÷2=6和12÷6=2。",
+        "knowledge_points":  [
+                                 "6的乘法口诀及应用",
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·河北邯郸·期中"
+    },
+    {
+        "id":  "339",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "4÷4=( )，用到的乘法口诀是( )，商是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "1;一四得四;1",
+        "solution":  "【分析】除法算式为：被除数÷除数=商，根据乘法口诀计算除法算式时，口诀中的后一个数是被除数，前两个数分别为除数和商。\n\n【详解】4÷4=1，用到的乘法口诀是一四得四，商是1。",
+        "knowledge_points":  [
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·河北邯郸·期中"
+    },
+    {
+        "id":  "340",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "18÷3=6读作：( )，除数是( )，商是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "18除以3等于6;3;6",
+        "solution":  "【分析】被除数÷除数=商。在除法算式中，除号前面的是被除数，除号后面的是除数，等号后面的是商。\n\n【详解】18÷3=6读作：18除以3等于6，除数是3，商是6。",
+        "knowledge_points":  [
+                                 "除法的初步认识",
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·河北邯郸·期中"
+    },
+    {
+        "id":  "341",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "18个○，每3个一份，可以分成( )份。",
+        "options":  [
+
+                    ],
+        "answer":  "6",
+        "solution":  "【分析】根据除法的意义，总数÷每份数=份数，据此解答。\n\n【详解】18是总数，3是每份数，求份数：18÷3=6（份），18个○，每3个一份，可以分成6份。",
+        "knowledge_points":  [
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "24-25二年级下·山东济南·期中"
+    },
+    {
+        "id":  "342",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "12÷( )=3，( )÷4=5。",
+        "options":  [
+
+                    ],
+        "answer":  "4;20",
+        "solution":  "【分析】除法算式为：被除数÷除数=商，计算除法算式时，可根据对应的乘法口诀进行解答。口诀中的后一个数是被除数，前两个数分别为除数和商。第1题根据乘法口诀三四十二进行解答；第2题根据乘法口诀四五二十进行解答。\n\n【详解】12÷4=3，20÷4=5。",
+        "knowledge_points":  [
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·黑龙江佳木斯·期中"
+    },
+    {
+        "id":  "343",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "把15个苹果平均分成5份，每份是( )个，列式为( )。",
+        "options":  [
+
+                    ],
+        "answer":  "3;15÷5=3（个）",
+        "solution":  "【分析】把一个数平均分成几份，求每份的数量，用除法计算，即苹果的总数量÷平均分成的份数=每份苹果的数量。\n\n【详解】把15个苹果平均分成5份，每份是3个，列式为15÷5=3（个）。",
+        "knowledge_points":  [
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·黑龙江佳木斯·期中"
+    },
+    {
+        "id":  "344",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "用12根小棒，如果摆成独立的□，可以摆( )个；如果摆成独立的△，可以摆( )个。",
+        "options":  [
+
+                    ],
+        "answer":  "3;4",
+        "solution":  "【分析】根据除法的意义，求一个数里面有几个另一个数用除法计算，据此解答。\n\n【详解】由题意可知：摆成独立的□，就是求12里面有几个4，即12÷4=3；如果摆成独立的△，就是求12里面有几个3，即12÷3=4。所以用12根小棒，如果摆成独立的□，可以摆3个；如果摆成独立的△，可以摆4个。",
+        "knowledge_points":  [
+                                 "用2~5的乘法口诀求商",
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·湖南怀化·期中"
+    },
+    {
+        "id":  "345",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "用20根小棒可以摆( )个独立的□，可以摆( )个独立的☆。",
+        "options":  [
+
+                    ],
+        "answer":  "5;4",
+        "solution":  "【分析】一个独立的□需要使用4根小棒，根据除法的意义计算20里面有多少个4，即可解答。一个独立的☆需要使用5根小棒，根据除法的意义计算20里面有多少个5，即可解答。\n\n【详解】20÷4=5（个），20÷5=4（个），所以用20根小棒可以摆5个独立的□，可以摆4个独立的☆。",
+        "knowledge_points":  [
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·内蒙古通辽·期中"
+    },
+    {
+        "id":  "346",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "20个□，每4个分为一份，可以分成( )份，对应的算式为( )。",
+        "options":  [
+
+                    ],
+        "answer":  "5;20÷4=5（份）",
+        "solution":  "【分析】求可以分几份，也就是求20里面有几个4，用除法计算，即总数量÷每份的数量=可以分的份数。\n\n【详解】20个□，每4个分为一份，可以分成5份，对应的算式为20÷4=5（份）。",
+        "knowledge_points":  [
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·黑龙江佳木斯·期中"
+    },
+    {
+        "id":  "347",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "计算24÷4时，所依据的乘法口诀为( )，得出的商是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "四六二十四;6",
+        "solution":  "【分析】除法算式为：被除数÷除数=商，根据乘法口诀计算除法算式时，口诀中的后一个数是被除数，前两个数分别为除数和商。\n\n【详解】计算24÷4时，所依据的乘法口诀为四六二十四，得出的商是6。",
+        "knowledge_points":  [
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·黑龙江佳木斯·期中"
+    },
+    {
+        "id":  "348",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "上图可表示：一共有( )个苹果，每( )个一份，平均分成了( )份，用算式表示( )。",
+        "options":  [
+
+                    ],
+        "answer":  "12;3;4;12÷3=4（份）",
+        "solution":  "【分析】由图可知，一共有12个苹果，每3个为一份，平均分成了4份，即总数量÷每份的数量=平均分成的份数。\n\n【详解】上图可表示：一共有12个苹果，每3个一份，平均分成了4份，用算式表示12÷3=4（份）。",
+        "knowledge_points":  [
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·贵州铜仁·期中"
+    },
+    {
+        "id":  "349",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "24÷4=( )，表示把( )平均分成( )份，每份是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "6;24;4;6",
+        "solution":  "【分析】根据乘法口诀四六二十四可知，结果是6。除法算式为被除数÷除数=商，表示把被除数平均分成除数的份数，商是每份的数。\n\n【详解】24÷4=6，表示把24平均分成4份，每份是6。",
+        "knowledge_points":  [
+                                 "整数平均分的意义及应用",
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·广西河池·期中"
+    },
+    {
+        "id":  "350",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "被除数是30，除数是5，商是( )，列式为( )。",
+        "options":  [
+
+                    ],
+        "answer":  "6;30÷5=6",
+        "solution":  "【分析】被除数÷除数=商，根据乘法口诀求商时，口诀中的后一个数作为被除数，前面两个数一个作除数，另一个作商。\n\n【详解】被除数是30，除数是5，商是6，列式为30÷5=6。",
+        "knowledge_points":  [
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·内蒙古通辽·期中"
+    },
+    {
+        "id":  "351",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "有20个桃子，每只小猴分4个，可以分给( )只小猴。",
+        "options":  [
+
+                    ],
+        "answer":  "5",
+        "solution":  "【分析】求可以分给几只小猴，也就是求20里面有几个4，用除法计算，即桃子的总数量÷每只小猴分的数量=可以分的小猴数量。\n\n【详解】20÷4=5(只)，有20个桃子，每只小猴分4个，可以分给5只小猴。",
+        "knowledge_points":  [
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·内蒙古通辽·期中"
+    },
+    {
+        "id":  "352",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "一袋饼干有30块，每次从袋中拿出5块,( )次可以拿完。",
+        "options":  [
+
+                    ],
+        "answer":  "6",
+        "solution":  "【分析】根据题意，就是求30里面有几个5，用除法计算。\n\n【详解】30÷5=6(次),一袋饼干有30块，每次从袋中拿出5块,6次可以拿完。",
+        "knowledge_points":  [
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·重庆渝中·期中"
+    },
+    {
+        "id":  "353",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "○+○+○+○=8,□÷○=8,□=( ),○=( )。",
+        "options":  [
+
+                    ],
+        "answer":  "16;2",
+        "solution":  "【分析】根据乘法口诀求商时，口诀中的后一个数作为被除数，前面两个数一个作除数另一个作商。有4个○相加会等于8，根据2~6的乘法口诀即可解答。再将算得的○代入第二个算式中，根据除法的意义解答即可。\n\n【详解】4×2=8，所以2+2+2+2=8，则○=2;□÷2=8，所以16÷2=8，则□=16。",
+        "knowledge_points":  [
+                                 "用2~5的乘法口诀求商",
+                                 "用7~9的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·福建莆田·期中"
+    },
+    {
+        "id":  "354",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "▲、★代表不同的数，如果▲-★-★-★-★-★=0，那么▲÷★=( )。",
+        "options":  [
+
+                    ],
+        "answer":  "5",
+        "solution":  "【分析】因为▲连续减去5个★等于0，所以▲里面有5个★，据此结合题干要求解答即可。\n\n【详解】据分析可知：▲里面有5个★，所以▲÷★=5。",
+        "knowledge_points":  [
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·山东临沂·期中"
+    },
+    {
+        "id":  "355",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "30÷5=( ),该算式读作( ),其中30被称作( ),5是( ),得出的商是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "6;30除以5等于6;被除数;除数;6",
+        "solution":  "【分析】除法算式为被除数÷除数=商。除法算式从左往右读，数字不变，“÷”读作除以，“=”读作等于。根据乘法口诀“五六三十”可知，结果是6。\n\n【详解】30÷5=6，该算式读作30除以5等于6，其中30被称作被除数，5是除数，得出的商是6。",
+        "knowledge_points":  [
+                                 "除法的初步认识",
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·黑龙江佳木斯·期中"
+    },
+    {
+        "id":  "356",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "18里面包含( )个3，同时,( )个5相加的和为30。",
+        "options":  [
+
+                    ],
+        "answer":  "6;6",
+        "solution":  "【分析】求一个数里面有几个另一个数，用这个数÷另一个数计算；求多少个5相加的和是30，用30除以5计算。\n\n【详解】18÷3=6，30÷5=6，18里面包含6个3，同时，6个5相加的和为30。",
+        "knowledge_points":  [
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·黑龙江佳木斯·期中"
+    },
+    {
+        "id":  "357",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "若把18颗糖果平均分给6个小朋友，每个小朋友能分到( )颗，对应的列式为( )。",
+        "options":  [
+
+                    ],
+        "answer":  "3;18÷6=3(颗)",
+        "solution":  "【分析】根据题意，把一个数平均分成几份，求每份是多少，用除法计算，即糖果的总数量÷平均分的人数=每人分到糖果的数量。\n\n【详解】若把18颗糖果平均分给6个小朋友，每个小朋友能分到3颗，对应的列式为18÷6=3(颗)。",
+        "knowledge_points":  [
+                                 "整数平均分的意义及应用",
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·黑龙江佳木斯·期中"
+    },
+    {
+        "id":  "358",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "☆-○-○-○-○=0,(☆和○都不为0),☆÷○=( )。",
+        "options":  [
+
+                    ],
+        "answer":  "4",
+        "solution":  "【分析】由题意可知☆-○-○-○-○=0，即4个○等于☆,那么☆=4○,因此用4个○去替换算式☆÷○中的☆,所以☆÷○就变成了4○÷○,4○÷○=4，所以☆÷○=4。\n\n【详解】由分析可知:☆-○-○-○-○=0,(☆和○都不为0),☆÷○=4。",
+        "knowledge_points":  [
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·贵州铜仁·期中"
+    },
+    {
+        "id":  "359",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在括号里填上合适的运算符号（+、-、×或÷）。\n24( )6=18  18( )6=3  81( )9=90  7( )7=49",
+        "options":  [
+
+                    ],
+        "answer":  "-;÷;+;×",
+        "solution":  "【分析】根据每个算式左右两边的结果，选择合适的运算符号填空即可。\n\n【详解】24-6=18，18÷6=3，81+9=90，7×7=49。",
+        "knowledge_points":  [
+                                 "一位数与两位数的进位加法",
+                                 "一位数与两位数的退位减法",
+                                 "7的乘法口诀及应用",
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·内蒙古通辽·期中"
+    },
+    {
+        "id":  "360",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "把18个苹果平均分成6份，每份( )个苹果。",
+        "options":  [
+
+                    ],
+        "answer":  "3",
+        "solution":  "【分析】用苹果总数除以平均分成的份数即可求出每份的个数。\n\n【详解】18÷6=3(个),把18个苹果平均分成6份，每份3个苹果。",
+        "knowledge_points":  [
+                                 "整数平均分的意义及应用",
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·内蒙古通辽·期中"
+    },
+    {
+        "id":  "361",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "西西摘了30颗草莓，打算和爸爸，妈妈，还有她的2个小伙伴一起分享，平均每人吃( )颗草莓，又增加爷爷一个，平均每人吃( )颗草莓。",
+        "options":  [
+
+                    ],
+        "answer":  "6;5",
+        "solution":  "【分析】用加法算出总人数，用总颗数除以总人数即可求出平均每人吃多少颗草莓，据此即可解答。\n\n【详解】1+1+1+2=5(人),30÷5=6(颗),5+1=6(人),30÷6=5(颗),西西摘了30颗草莓，打算和爸爸，妈妈，还有她的2个小伙伴一起分享，平均每人吃6颗草莓，又增加爷爷一个，平均每人吃5颗草莓。",
+        "knowledge_points":  [
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "24-25二年级下·湖南怀化·期中"
+    },
+    {
+        "id":  "362",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "上图中，一共有( )个☆,每( )个分成一份，一共分成了( )份。",
+        "options":  [
+
+                    ],
+        "answer":  "9;3;3",
+        "solution":  "【分析】由图可知，一共有9个草莓，每份是3个，则总数量÷每份的数量=分成的份数。\n\n【详解】9÷3=3(份)，上图中，一共有9个☆，每3个分成一份，一共分成了3份。",
+        "knowledge_points":  [
+                                 "除法的初步认识",
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·陕西渭南·期中"
+    },
+    {
+        "id":  "363",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "16个小朋友玩碰碰车。每2人坐一辆，需要( )辆。每辆车9元,70元够吗。( )(填\"够\"或\"不够\")。",
+        "options":  [
+
+                    ],
+        "answer":  "8;不够",
+        "solution":  "【分析】用小朋友的人数除以一辆车坐的人数即可求出需要的辆数。用需要的辆数乘每辆的钱数算出总钱数，然后和70元作比较，大于70元则不够，小于或等于70元则够。\n\n【详解】16÷2=8(辆),8×9=72(元),72\u003e70，不够。16个小朋友玩碰碰车。每2人坐一辆，需要8辆。每辆车9元,70元不够。",
+        "knowledge_points":  [
+                                 "100以内数的比大小",
+                                 "9的乘法口诀及应用",
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "24-25二年级下·河北沧州·期中"
+    },
+    {
+        "id":  "364",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "20米长的绳子剪成5米长的绳子，可以剪成( )段，需要剪( )次;36米长的绳子剪成6米长的绳子，可以剪成( )段，需要剪( )次。我发现：剪的次数要比剪成的段数( )。",
+        "options":  [
+
+                    ],
+        "answer":  "4;3;6;5;少1",
+        "solution":  "【分析】根据题意可知，用绳子的总长度除以每段绳子的长度，等于可以剪成的段数，因为最后剪一次，可以把绳子剪成了2段，所以剪的次数要比段数少1，故用段数减1即可求出剪的次数;通过两次计算可发现，剪的次数要比剪成的段数少1，据此解答。\n\n【详解】20÷5=4(段),4-1=3(次),36÷6=6(段),6-1=5(次),3比4少1,5比6少1.20米长的绳子剪成5米长的绳子，可以剪成4段，需要剪3次;36米长的绳子剪成6米长的绳子，可以剪成6段，需要剪5次。我发现：剪的次数要比剪成的段数少1。",
+        "knowledge_points":  [
+                                 "用2~5的乘法口诀求商",
+                                 "用6的乘法口诀求商",
+                                 "植树问题(两端都不栽)"
+                             ],
+        "source":  "24-25二年级下·浙江宁波·期中"
+    },
+    {
+        "id":  "365",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在括号里填上“+”“-”“×”或“÷”。\n10( )2=5  18( )6=24  7( )2=14  30( )5=25",
+        "options":  [
+
+                    ],
+        "answer":  "÷;+;×;-",
+        "solution":  "【分析】根据整数加减法的计算法则，表内乘法口诀及表内除法进行解答。\n\n【详解】根据乘法口诀“二五一十”可知：10÷2=5；18和6合起来是24，即18+6=24；根据乘法口诀“二七十四”可知：7×2=14；30可以分成5和25，即30-5=25。",
+        "knowledge_points":  [
+                                 "一位数与两位数的进位加法",
+                                 "一位数与两位数的退位减法",
+                                 "7的乘法口诀及应用",
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·浙江温州·期中"
+    },
+    {
+        "id":  "366",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "请在括号里填上合适的数。\n2×( )=16  ( )×4=28  25÷( )=5",
+        "options":  [
+
+                    ],
+        "answer":  "8;7;5",
+        "solution":  "【分析】根据表内乘法口诀，解答即可。\n\n【详解】(1)根据口诀“二八十六”可得：2×8=16，故括号里填8；(2)根据口诀“四七二十八”可得：7×4=28，故括号里填7；(3)根据口诀“五五二十五”可得：5×5=25，25÷5=5，故括号里填5。",
+        "knowledge_points":  [
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·广东广州·期中"
+    },
+    {
+        "id":  "367",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "有24根小棒，每4根摆一个□，可以摆( )个□，列式计算是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "6;24÷4=6",
+        "solution":  "【分析】用小棒的根数除以摆一个□用的根数，即可求出可以摆几个□。\n\n【详解】24÷4=6（个），有24根小棒，每4根摆一个□，可以摆6个□，列式计算是24÷4=6。",
+        "knowledge_points":  [
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·广东广州·期中"
+    },
+    {
+        "id":  "368",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在括号里填“+”“-”“×”或“÷”。\n8( )2=18( )3  18( )3=2( )3",
+        "options":  [
+
+                    ],
+        "answer":  "-;÷;÷;×",
+        "solution":  "【分析】第一个算式，左边的式子8( )2，如果用乘法，8×2=16；如果用加法，8+2=10；如果用减法，8-2=6；如果用除法，8÷2=4。右边的18( )3，如果用除法，18÷3=6。发现左边8-2=6，右边18÷3=6，所以8-2=18÷3。第二个算式，左边18( )3，如果用除法，18÷3=6；如果用乘法，18×3结果较大，不考虑；如果用加法，18+3=21；如果用减法，18-3=15。右边的2( )3，如果用乘法，2×3=6。发现左边18÷3=6，右边2×3=6，所以18÷3=2×3。\n\n【详解】8(-)2=18(÷)3，18(÷)3=2(×)3。",
+        "knowledge_points":  [
+                                 "8,9的加减法",
+                                 "6的乘法口诀及应用",
+                                 "用2~5的乘法口诀求商",
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "24-25二年级下·湖南长沙·期中"
+    },
+    {
+        "id":  "369",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "计算6×5和30÷5都要用到的乘法口诀是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "五六三十",
+        "solution":  "【分析】根据6的乘法口诀解答,6×5=30，用到乘法口诀的是\"五六三十\";根据乘法口诀求商时，口诀中后面一个数作被除数，前面两个数一个数作除数另一个作商,30÷5=6，用到的乘法口诀是\"五六三十\"。\n\n【详解】因此，计算6×5和30÷5都要用到的乘法口诀是五六三十。",
+        "knowledge_points":  [
+                                 "6的乘法口诀及应用",
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·江西宜春·期中"
+    },
+    {
+        "id":  "370",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "36÷4=9读作( ),在这个算式中，商是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "36除以4等于9;9",
+        "solution":  "【分析】根据题意，算式36÷4=9，读作36除以4等于9；在除法算式中，被除数÷除数=商，由此可知，商是9。\n【详解】36÷4=9读作36除以4等于9，在这个算式中，商是9。",
+        "knowledge_points":  [
+                                 "除法的初步认识"
+                             ],
+        "source":  "24-25 二年级下·湖北武汉·期末"
+    },
+    {
+        "id":  "371",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "求15里面有几个5，除法算式：15÷3=5。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】求一个数里面有几个另一个数，用这个数÷另一个数计算。\n【详解】求15里面有几个5，除法算式：15÷5=3，原题说法错误。故答案为：×",
+        "knowledge_points":  [
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·河南南阳·期中"
+    },
+    {
+        "id":  "372",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "判断题",
+        "difficulty":  0.65,
+        "question":  "一根长30米的彩带，如果每6米剪成一段，需要剪5次。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】根据题意，用彩带的总长度除以每段的长度，计算出要剪的段数。剪成2段需1次，剪成3段需2次。也就是剪成的段数-1=剪的次数.\n【详解】30÷6=5(段),5-1=4(次),则一根长30米的彩带，如果每6米剪成一段，需要剪4次。原题说法错误。故答案为: ×",
+        "knowledge_points":  [
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·四川乐山·期中"
+    },
+    {
+        "id":  "373",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "计算2×6和12÷2用的是同一句乘法口诀。( )",
+        "options":  [
+
+                    ],
+        "answer":  "√",
+        "solution":  "【分析】根据口诀二六十二计算2×6=12，根据口诀二六十二计算12÷2=6，据此得出结论即可.\n【详解】计算2×6和12÷2都用口诀二六十二。故答案为:√",
+        "knowledge_points":  [
+                                 "6的乘法口诀及应用",
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·黑龙江佳木斯·期中"
+    },
+    {
+        "id":  "374",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "任何一句乘法口诀都可以写出两道不同的除法算式。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】据题意，任何一句乘法口诀都可以写出两道不同的除法算式，但是当乘法口诀中的两个因数相同时，能写出的除法算式就只有一个，举例说明据此即可得出答案.\n【详解】五五二十五，对应的除法算式就只有一个25÷5=5，所以任何一句乘法口诀都可以写出两道不同的除法算式是不正确的。故答案为: ×",
+        "knowledge_points":  [
+                                 "除法的初步认识"
+                             ],
+        "source":  "24-25 二年级下·吉林松原·期中"
+    },
+    {
+        "id":  "375",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "一个乒乓球3元钱，四个羽毛球12元钱，一个羽毛球比一个乒乓球贵。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】根据题意，先用四个羽毛球的钱数除以数量，计算出一个羽毛球的钱数，再和一个乒乓球的钱数比较大小即可解答.\n【详解】12÷4=3(元),3=3，则一个乒乓球3元钱，四个羽毛球12元钱，一个羽毛球和一个乒乓球的价格一样，原题说法错误。故答案为: ×",
+        "knowledge_points":  [
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·河南南阳·期中"
+    },
+    {
+        "id":  "376",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "15个○,每份5个，可以分成3份，列式为:15÷5=3。( )",
+        "options":  [
+
+                    ],
+        "answer":  "√",
+        "solution":  "【分析】求可以分成的份数，也就是求15里面有几个5，用除法计算，即总数量÷每份的数量=可以分成的份数。\n【详解】15个○，每份5个，可以分成3份，列式为：15÷5=3。原题说法正确。故答案为：√",
+        "knowledge_points":  [
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·河南南阳·期中"
+    },
+    {
+        "id":  "377",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "把20随意分成4份，每份必然是5。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】把一些物品分成几份，每份分得同样多，叫平均分。若把20平均分成4份，每份是5;但若把20不是平均分成4份，则每份不一定是5;如：一份是3，一份是4，一份是6，一份是7;据此判断即可.\n【详解】把20随意分成4份，每份不一定是5。原题说法错误。故答案为: ×",
+        "knowledge_points":  [
+                                 "整数平均分的意义及应用"
+                             ],
+        "source":  "24-25 二年级下·黑龙江佳木斯·期中"
+    },
+    {
+        "id":  "378",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "计算4×5和20÷5时，用同一句口诀。( )",
+        "options":  [
+
+                    ],
+        "answer":  "√",
+        "solution":  "【分析】乘法算式中两个乘数是口诀中的前两个数，积是口诀中的后一个数，写算式时两个乘数可互换位置。根据乘法口诀求商时，口诀中的后一个数作为被除数，前面两个数一个作除数另一个作商.\n【详解】计算4×5使用的口诀为四五二十;计算20÷5使用的口诀为四五二十。计算4×5和20÷5时，用同一句口诀。原题说法正确。故答案为:√",
+        "knowledge_points":  [
+                                 "5的乘法口诀及应用",
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·贵州铜仁·期中"
+    },
+    {
+        "id":  "379",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "如果□+□+□=15，△+△=6，那么□×△=10。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】除法算式中，被除数表示总数，除数表示平均分成的份数，商表示每份的数量；或者被除数表示总数，除数表示每份的数量，商表示平均分成的份数。据此算出□和△分别是多少，然后代入□×△计算。\n【详解】15÷3=5，□=5，6÷2=3，△=3，□×△=5×3=15。如果□+□+□=15，△+△=6，那么□×△=15。原题说法错误。故答案为：×",
+        "knowledge_points":  [
+                                 "6的加减法",
+                                 "5的乘法口诀及应用",
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "24-25二年级下·内蒙古通辽·期中"
+    },
+    {
+        "id":  "380",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "把15个苹果分成3份，每份是5个。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】除法表示把一个数平均分成若干份，求每份是多少。如果不是平均分不能用除法表示.\n【详解】把15个苹果平均分成3份，每份是5个，如果不是平均分，每份的个数不确定。原题说法错误。故答案为: ×",
+        "knowledge_points":  [
+                                 "整数平均分的意义及应用",
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "24-25二年级下·广东·期中"
+    },
+    {
+        "id":  "381",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "被除数是28，商是4，除数是7，这个除法算式是28÷4=7。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】除法算式为：被除数÷除数=商，由此将数字写在对应位置即可解答。\n【详解】被除数是28，商是4，除数是7，这个除法算式是28÷7=4，原题说法错误。故答案为：×",
+        "knowledge_points":  [
+                                 "除法的初步认识"
+                             ],
+        "source":  "24-25 二年级下·湖北省直辖县级单位·期中"
+    },
+    {
+        "id":  "382",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "把24个○分成6份，每份是4个。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】在分物体时，每份分得同样多，是平均分。把24个○平均分成6份，每份是4个。题干没有说平均分，可以这样分：一份是4个;一份是3个;一份是5个;一份是6个;一份是2个;一份是4个，由此解答.\n【详解】把24个○分成6份，每份不一定是4个。原题说法错误。故答案为: ×",
+        "knowledge_points":  [
+                                 "整数平均分的意义及应用"
+                             ],
+        "source":  "24-25 二年级下·湖北省直辖县级单位·期中"
+    },
+    {
+        "id":  "383",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "24÷☆=4,☆是6。( )",
+        "options":  [
+
+                    ],
+        "answer":  "√",
+        "solution":  "【分析】除法算式为被除数÷除数=商，求除数时，根据被除数÷商=除数计算。\n【详解】24÷4=6，则24÷6=4，24÷☆=4，☆是6。原题说法正确。故答案为：√",
+        "knowledge_points":  [
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·广东汕头·期中"
+    },
+    {
+        "id":  "384",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "被除数和除数都是2，那么商是1。( )",
+        "options":  [
+
+                    ],
+        "answer":  "√",
+        "solution":  "【分析】根据被除数÷除数=商，据此代入数值进行计算即可。\n【详解】因为2÷2=1，所以被除数和除数都是2，商是1。原题说法正确。故答案为：√",
+        "knowledge_points":  [
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·广东汕头·期中"
+    },
+    {
+        "id":  "385",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "判断题",
+        "difficulty":  0.65,
+        "question":  "一根绳子长12米，对折后再对折，每段长3米。( )",
+        "options":  [
+
+                    ],
+        "answer":  "√",
+        "solution":  "【分析】根据题意，对折一次分成了同样长的2段，对折两次分成了同样长的4段，用绳子的总长度÷段数=每段的长度。\n【详解】2×2=4(段)，12÷4=3(米)，一根绳子长12米，对折后再对折，每段长3米。原题说法正确。故答案为：√",
+        "knowledge_points":  [
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·广东汕头·期中"
+    },
+    {
+        "id":  "386",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "将6片树叶分成几份，这是平均分。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】平均分后每一份的数量是一样的，据此解答。\n【详解】将6片树叶分成几份，不一定是平均分。原题说法错误。故答案为：×",
+        "knowledge_points":  [
+                                 "整数平均分的意义及应用"
+                             ],
+        "source":  "24-25 二年级下·陕西渭南·期中"
+    },
+    {
+        "id":  "387",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "判断题",
+        "difficulty":  0.65,
+        "question":  "把20分成4份，每份一定是5。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】把一些物品分成几份，每份分得同样多，叫平均分。若把20平均分成4份，每份是5;但若把20不是平均分成4份，则每份不一定是5;如：一份是3，一份是4，一份是6，一份是7;据此判断即可.\n【详解】把20分成4份，每份一定是5。此说法错误。故答案为: ×",
+        "knowledge_points":  [
+                                 "整数平均分的意义及应用"
+                             ],
+        "source":  "24-25 二年级下·湖南长沙·期中"
+    },
+    {
+        "id":  "388",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "计算题",
+        "difficulty":  0.85,
+        "question":  "看图列式。",
+        "options":  [
+
+                    ],
+        "answer":  "30÷5=6(米)",
+        "solution":  "【分析】用总长除以段数即可求出每段的长度.\n【详解】30÷5=6(米),每段长6米。",
+        "knowledge_points":  [
+                                 "图文问题",
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "24-25二年级下·湖南岳阳·期中"
+    },
+    {
+        "id":  "389",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "计算题",
+        "difficulty":  0.85,
+        "question":  "被除数和除数都是6，商是多少。",
+        "options":  [
+
+                    ],
+        "answer":  "1",
+        "solution":  "【分析】除法算式为被除数÷除数=商，由此代入计算即可。\n【详解】6÷6=1，被除数和除数都是6，商是1。",
+        "knowledge_points":  [
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "24-25二年级下·贵州铜仁·期中"
+    },
+    {
+        "id":  "390",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "计算题",
+        "difficulty":  0.85,
+        "question":  "看谁算得都对.\n25÷5= 36÷6= 9×7= 5×8=\n43-9= 60-7= 90-15= 54-28=",
+        "options":  [
+
+                    ],
+        "answer":  "5;6;63;40;34;53;75;26",
+        "solution":  "【分析】按顺序逐一计算即可。\n【详解】本题考查除法、乘法口诀及减法的计算能力，按顺序逐一计算即可。25÷5=5，因为5×5=25；36÷6=6，因为6×6=36；9×7=63，根据乘法口诀“七九六十三”；5×8=40，根据乘法口诀“五八四十”；43-9=34，可以先算43-10=33，再加回1得到34；60-7=53，可以先算60-10=50，再加回3得到53；90-15=75，可以先算90-10=80，再减5得到75；54-28=26，可以先算54-20=34，再减8得到26。所以结果依次为：5，6，63，40，34，53，75，26。",
+        "knowledge_points":  [
+                                 "整十数加，减一位数",
+                                 "8的乘法口诀及应用",
+                                 "9的乘法口诀及应用",
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·山东菏泽·期中"
+    },
+    {
+        "id":  "391",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "有24个水壶，每6个装一箱，可以装几箱。",
+        "options":  [
+
+                    ],
+        "answer":  "4箱",
+        "solution":  "【分析】根据题意可知，水壶的总个数除以每箱装的个数，等于可以装几箱，据此解答.\n【详解】24÷6=4(箱),答：可以装4箱。",
+        "knowledge_points":  [
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·黑龙江佳木斯·期中"
+    },
+    {
+        "id":  "392",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "有24本练习册，如果平均分给6人，每人分到几本。",
+        "options":  [
+
+                    ],
+        "answer":  "4本",
+        "solution":  "【分析】根据除法的意义，练习册的总数量÷分到的人数=平均每个人分到的数量，算出答案即可求解。\n【详解】24÷6=4(本)，答：每人分到4本。",
+        "knowledge_points":  [
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·吉林松原·期中"
+    },
+    {
+        "id":  "393",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "有18位同学参与拔河比赛，每6个同学组成一组，总共可以分成几组。",
+        "options":  [
+
+                    ],
+        "answer":  "3组",
+        "solution":  "【分析】求可以分成几组，也就是求18里面有几个6，用除法计算，即总人数÷每组的人数=可以分成的组数。\n【详解】18÷6=3(组)，答：总共可以分成3组。",
+        "knowledge_points":  [
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "24-25二年级下·黑龙江佳木斯·期中"
+    },
+    {
+        "id":  "394",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "学校购置了24盆绿植，打算平均分配给4个班级，每个班级能分到几盆。",
+        "options":  [
+
+                    ],
+        "answer":  "6盆",
+        "solution":  "【分析】根据题意，求每个班级能分到几盆，用除法计算，用学校购置绿植的总盆数除以平均分配的班级数，即可解答.\n【详解】24÷4=6(盆),答：每个班级能分到6盆。",
+        "knowledge_points":  [
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·黑龙江佳木斯·期中"
+    },
+    {
+        "id":  "395",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "美术社团课上，同学们正分组制作树叶贴画。每组制作4份作品，共制作了24份作品，一共有多少组参加制作树叶贴画。",
+        "options":  [
+
+                    ],
+        "answer":  "6组",
+        "solution":  "【分析】求一共有多少组，也就是求24里面有几个4，用除法计算，即作品的总数量÷每组制作的数量=组数。\n【详解】24÷4=6(组)，答：一共有6组参加制作树叶贴画。",
+        "knowledge_points":  [
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·贵州铜仁·期中"
+    },
+    {
+        "id":  "396",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "小贵带着零花钱去购物，他在购物前先看了看商品标价签。\n(1)小贵带的零花钱全部用来买冰激凌，刚好可以买9盒，小贵带了多少元。\n(2)如果小贵把全部的零花钱用来买奶茶，可以买几杯。",
+        "options":  [
+
+                    ],
+        "answer":  "36元;6杯",
+        "solution":  "【分析】(1)根据乘法的意义，每盒冰激凌的钱数和买的盒数相乘，就是小贵带的钱数；(2)根据除法的意义，小贵的钱数除以每杯奶茶的钱数，结果就是可以买奶茶的杯数。\n【详解】(1)4×9=36（元），答：小贵带了36元。(2)36÷6=6（杯），答：可以买6杯。",
+        "knowledge_points":  [
+                                 "图文问题",
+                                 "9的乘法口诀及应用",
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "24-25二年级下·青海果洛·期中"
+    },
+    {
+        "id":  "397",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "明明和亮亮为了装饰教室，决定给窗户贴上窗花。明明3分钟剪了12朵花，亮亮4分钟剪了20朵花，谁剪得快。",
+        "options":  [
+
+                    ],
+        "answer":  "亮亮",
+        "solution":  "【分析】根据题意，分别用每人剪花的总数量除以用的时间，计算出每分钟剪的数量，再比较大小即可解答.\n【详解】明明:12÷3=4(朵),亮亮:20÷4=5(朵),4\u003c5，答：亮亮剪得快。",
+        "knowledge_points":  [
+                                 "5以内数的比大小",
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·重庆渝中·期中"
+    },
+    {
+        "id":  "398",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "面包原来8元一个，现在优惠促销，买5个面包30元，促销的面包每个多少钱。每个比原来便宜多少钱。",
+        "options":  [
+
+                    ],
+        "answer":  "6元;2元",
+        "solution":  "【分析】根据题意，用买5个面包的总钱数除以买的个数，求出促销时每个面包的钱数，再用原来每个面包的钱数和现在每个面包的钱数相减，就是便宜的钱数.\n【详解】30÷5=6(元),8-6=2(元),答：促销的面包每个6元钱，每个比原来便宜2元钱。",
+        "knowledge_points":  [
+                                 "8,9的加减法",
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "24-25二年级下·湖北省直辖县级单位·期中"
+    },
+    {
+        "id":  "399",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "12名同学做手工，每2名同学分成一组，可以分成几组。",
+        "options":  [
+
+                    ],
+        "answer":  "6组",
+        "solution":  "【分析】12名同学做手工，每2名同学分成一组，要求可以分成几组，根据除法的意义，用总的人数除以每组的人数，用12÷2解答即可.\n【详解】12÷2=6(组),答：可以分成6组。",
+        "knowledge_points":  [
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "23-24 二年级下·湖南怀化·期末"
+    },
+    {
+        "id":  "400",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "公园里有24棵柳树，每行种6棵，可以种几行。如果每行种4棵，需要种几行。",
+        "options":  [
+
+                    ],
+        "answer":  "4行;6行",
+        "solution":  "【分析】有24棵柳树，每行种6棵，求可以种几行，就是求24里面有几个6，用24÷6解决;有24棵柳树，每行种4棵，求可以种几行，就是求24里面有几个4，用24÷4解决.\n【详解】24÷6=4(行),24÷4=6(行),答：每行种6棵，可以种4行;如果每行种4棵，需要种6行。",
+        "knowledge_points":  [
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·湖南长沙·期末"
+    },
+    {
+        "id":  "401",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "王叔叔把一根12米长的木材锯了3次，平均每段木材长( )米。",
+        "options":  [
+                        "A. 3",
+                        "B. 4",
+                        "C. 9"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】木材本身就是一段，锯一次分成两段，锯两次分成三段，锯三次分成四段，再用总长度除以分成的四段即可得出平均每段的长度.\n【详解】12÷4=3(米),王叔叔把一根12米长的木材锯了3次，平均每段木材长3米。故答案为:A",
+        "knowledge_points":  [
+                                 "整数平均分的意义及应用",
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "24-25二年级下·湖南永州·阶段练习"
+    },
+    {
+        "id":  "402",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "李老师把12个桃子平均分给6个小朋友，下列算式正确的是( )。",
+        "options":  [
+                        "A. 12÷6=2",
+                        "B. 6×2=12",
+                        "C. 12-6=6"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】根据整数平均分的意义可知，桃子的总数量÷平均分的小朋友人数=每人分的数量。\n【详解】A。12÷6=2表示把12平均分成6份，每份是2个，符合题意；B。6×2=12表示6个2或2个6的和是12，不符合题意；C。12-6=6表示从12里面减去6个，还剩6个，不符合题意。则算式正确的是12÷6=2。故答案为：A",
+        "knowledge_points":  [
+                                 "整数平均分的意义及应用",
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·湖南永州·阶段练习"
+    },
+    {
+        "id":  "403",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "在下面除法算式中，商最大的是( )。",
+        "options":  [
+                        "A. 2÷2",
+                        "B. 12÷6",
+                        "C. 1÷1"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】求出各算式的商再进行比较即可。\n【详解】A。2÷2=1；B。12÷6=2；C。1÷1=1。2\u003e1，商最大的是12÷6。故答案为：B",
+        "knowledge_points":  [
+                                 "用2~5的乘法口诀求商",
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·湖南永州·阶段练习"
+    },
+    {
+        "id":  "404",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "一只蜗牛爬10米深的井，白天爬4米，晚上下滑2米,( )天爬出来。",
+        "options":  [
+                        "A. 3",
+                        "B. 4",
+                        "C. 5",
+                        "D. 6"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】10-4=6(米),当它最后一天爬出井口不用下滑2米，所以最后一天再爬4米，就可爬出井口;因白天爬4米，晚上下滑2米，实际前面每天只爬4-2=2(米),最后用6除以2，求出商，再加上1，求出和，即可解决.\n【详解】10-4=6(米),4-2=2(米),6÷2=3(天),3+1=4(天),即到第4天爬出来。故答案为:B",
+        "knowledge_points":  [
+                                 "5以内数的加法",
+                                 "5以内数的减法",
+                                 "10的加减法",
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级上·浙江温州·期末"
+    },
+    {
+        "id":  "405",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "2只羊可以换6只兔子,1只兔子可以换3只小鸡,1只羊可以换( )只小鸡。",
+        "options":  [
+                        "A. 36",
+                        "B. 18",
+                        "C. 9",
+                        "D. 6"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】根据题意可知，先算出1只羊可以换几只兔子，兔子的只数除以羊的只数可得;题目中给出,1只兔子可以换3只小鸡，然后用刚才的结果乘3，即可求出1只羊可以换小鸡的数量，据此解答.\n【详解】6÷2=3(只),3×3=9(只),所以1只羊可以换9只小鸡。故答案为:C",
+        "knowledge_points":  [
+                                 "3的乘法口诀及应用",
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级上·浙江温州·期末"
+    },
+    {
+        "id":  "406",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "把8米长的绳子对折再对折，每段是( )米。",
+        "options":  [
+                        "A. 2",
+                        "B. 3",
+                        "C. 4"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】一根绳子对折再对折，是平均分成了4段，每段的长度=绳子的总长度÷绳子的段数。\n【详解】8÷4=2(米)，把8米长的绳子对折再对折，每段是2米。故答案为：A",
+        "knowledge_points":  [
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "23-24二年级下·浙江温州·期中"
+    },
+    {
+        "id":  "407",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "\"小荷才露尖尖角，早有蜻蜓立上头.\"若蜻蜓和荷花图片按照如下的顺序排列，共排了30幅图片，有( )幅荷花图片。![](images/173205.png)",
+        "options":  [
+                        "A. 18",
+                        "B. 15",
+                        "C. 12"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】2幅蜻蜓图片和3幅荷花图片为一组，先用除法求出30幅图片可以分成多少组，然后再乘3，求出积，就是荷花图片的数量.\n【详解】2+3=5(幅),30÷5=6(组),6×3=18(幅),即有18幅荷花图片。故答案为:A",
+        "knowledge_points":  [
+                                 "6的乘法口诀及应用",
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级上·湖南湘西·期末"
+    },
+    {
+        "id":  "408",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "小鸟换新家,9只小鸟住一间房子,27只小鸟需要几间房子。下面的思考过程,( )是错误的。",
+        "options":  [
+                        "A. ![](images/eadd9bff95165d2ff9e671f3d51108968a46f43bb29e7559835a0edb6cb438d6.jpg)",
+                        "B. ![](images/b3659cf7871164ff80205ff990e4cecff9074e0ea66c6f3477d913baf515f780.jpg)",
+                        "C. ![](images/173758.png)"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】9只小鸟住一间房子，要求27只小鸟要准备几间房子，就是求27里面有几个9，或者是求几个9是27，可据此确定思考过程是否正确.\n【详解】A。运用点子图，有9个框表示9间房子，每个框里有3个点表示3只小鸟住一间房子，共计27个点;用点子图表示的是27里面9个3，并没有表示出27里面有几个9;故思考过程是错误的。B。运用数射线，从27开始跳，每次跳9格，跳了3次，跳到0;能够表示出27里面有3个9;故思考过程是正确的。C。运用表格，从1个9计算到3个9，能够表示出3个9是27;故思考过程是正确的。故答案为:A",
+        "knowledge_points":  [
+                                 "除法的初步认识"
+                             ],
+        "source":  "24-25 二年级上·河南商丘·期末"
+    },
+    {
+        "id":  "409",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "如果○÷△=□，那么下列算式正确的是( )。",
+        "options":  [
+                        "A. ○×□=△",
+                        "B. ○×△=□",
+                        "C. ○÷□=△"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】被除数÷除数=商，被除数÷商=除数，商×除数=被除数，除数×商=被除数，据此解答。\n【详解】A。○×□=△，应为△×□=○，原算式错误。B。○×△=□，应为□×△=○，原算式错误。C。○÷□=△，原算式正确。算式正确的是○÷□=△。故答案为：C",
+        "knowledge_points":  [
+                                 "乘，除法的意义和各部分间的关系"
+                             ],
+        "source":  "24-25 二年级上·河南周口·期末"
+    },
+    {
+        "id":  "410",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "把16个五角星平均分为4份，每份是( )个。",
+        "options":  [
+                        "A. 4",
+                        "B. 3",
+                        "C. 2"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】把16个五角星平均分成4份，求每份是多少个，用除法计算，即总数量÷平均分成的份数=每份的数量。\n【详解】16÷4=4(个)，则每份是4个。故答案为：A",
+        "knowledge_points":  [
+                                 "整数平均分的意义及应用",
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "24-25二年级下·全国·假期作业"
+    },
+    {
+        "id":  "411",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "小红有6颗糖果，分给2个小伙伴，平均每人( )颗。",
+        "options":  [
+                        "A. 2",
+                        "B. 3",
+                        "C. 4"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】求平均每人分几颗，就是把6平均分成2份，求每份是多少，用除法计算.\n【详解】6÷2=3(颗),平均每人3颗。故答案为:B",
+        "knowledge_points":  [
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·全国·假期作业"
+    },
+    {
+        "id":  "412",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "首届中小学生艺术展演读书活动成果展示在陕州区拉开帷幕。选送节目《双面燕洵》中，器乐组表演共12人，将男生、女生平均分成2组，男生、女生各有几人。下面列式正确的是( )。",
+        "options":  [
+                        "A. 12+2",
+                        "B. 12÷2",
+                        "C. 12-2"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】从题干可知：将男生、女生平均分成2组，要求男生、女生各有几人，根据除法的意义，用12÷2进行解答即可。\n【详解】12÷2=6(人)，所以男生、女生各有6人。故答案为：B",
+        "knowledge_points":  [
+                                 "整数平均分的意义及应用"
+                             ],
+        "source":  "23-24 二年级下·河南三门峡·期末"
+    },
+    {
+        "id":  "413",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "21本书，平均分给3个小组，每个小组分几本。就是求( )。",
+        "options":  [
+                        "A. 21里面有几个3。",
+                        "B. 3个21相加是多少。",
+                        "C. 把21平均分成3份，每份是多少。"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】除法算式中，被除数表示总数，除数表示平均分成的份数，商表示每份的数量;或者被除数表示总数，除数表示每份的数量，商表示平均分成的份数。据此分析.\n【详解】A。21里面有几个3。是求21可以分成几个3，不符合;B。3个21相加是多少。是求21加21加21的和，不符合;C。把21平均分成3份，每份是多少。符合题意。21本书，平均分给3个小组，每个小组分几本。就是求：把21平均分成3份，每份是多少。故答案为:C",
+        "knowledge_points":  [
+                                 "整数平均分的意义及应用"
+                             ],
+        "source":  "24-25 二年级上·河南周口·期末"
+    },
+    {
+        "id":  "414",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "商是5的式子是( )。",
+        "options":  [
+                        "A. 10-5",
+                        "B. 5×1",
+                        "C. 5÷1"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】减法算式为：被减数-减数=差；乘法算式为：乘数×乘数=积；除法算式为：被除数÷除数=商，由此计算选择即可。\n【详解】A。10-5=5，差是5，不符合题意；B。5×1=5，积是5，不符合题意；C。5÷1=5，商是5，符合题意。所以商是5的式子是5÷1。故答案为：C",
+        "knowledge_points":  [
+                                 "10的加减法",
+                                 "5的乘法口诀及应用",
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级上·河南周口·期末"
+    },
+    {
+        "id":  "415",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "求8里面有几个2，正确的列式是( )。",
+        "options":  [
+                        "A. 8×2",
+                        "B. 8÷2",
+                        "C. 8-2"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】求一个数里面有几个另一个数用除法计算，用这个数除以另一个数即可.\n【详解】求8里面有几个2，正确的列式是8÷2。故答案为:B",
+        "knowledge_points":  [
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "23-24 二年级上·广东韶关·期末"
+    },
+    {
+        "id":  "416",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "选择题",
+        "difficulty":  0.4,
+        "question":  "2只猫2天抓了2只老鼠，那么在10天里抓10只老鼠，需要( )只猫。",
+        "options":  [
+                        "A. 10",
+                        "B. 5",
+                        "C. 2"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】根据2只猫2天抓了2只老鼠可以得出1只猫2天抓1只老鼠，10天里有5个2天，则1只猫10天抓1×5=5只老鼠，10只老鼠里面有几个5只，就需要几只猫。\n【详解】2÷2=1(只)，1×5=5(只)，二五一十，10里面有2个5，2只猫2天抓了2只老鼠，那么在10天里抓10只老鼠，需要2只猫。故答案为：C",
+        "knowledge_points":  [
+                                 "5的乘法口诀及应用",
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "23-24 二年级上·重庆丰都·期末"
+    },
+    {
+        "id":  "417",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "计算18÷6时，利用口诀( )来计算。",
+        "options":  [
+                        "A. 三六十八",
+                        "B. 三五十五",
+                        "C. 二八十六"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】利用乘法口诀计算除法算式时，口诀中的后一个数是被除数，前两个数可分别为除数和商，由此解答.\n【详解】计算18÷6时，利用口诀三六十八来计算。故答案为:A",
+        "knowledge_points":  [
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "23-24 二年级下·四川南充·期末"
+    },
+    {
+        "id":  "418",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "一道除法算式，除数和商相同，如果被除数是36，商是( )。",
+        "options":  [
+                        "A. 8",
+                        "B. 6",
+                        "C. 7"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】除法算式为被除数÷除数=商，除法算式中被除数是口诀中的后一个数，除数和商是口诀中的前两个数，根据乘法口诀，找出两个相同数的积是36的即可。\n【详解】根据乘法口诀六六三十六可知，6×6=36，即36÷6=6，商是6。故答案为：B",
+        "knowledge_points":  [
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "23-24二年级下·四川绵阳·期中"
+    },
+    {
+        "id":  "419",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "小刚有18张贴画，小林有10张贴画，小刚给小林( )张贴画后，他俩的贴画张数就同样多。",
+        "options":  [
+                        "A. 4",
+                        "B. 8",
+                        "C. 2"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】根据题意，用小刚减去小林的贴画数量，求出小刚比小林多的数量，再将多出的数量平均分成2份，即可求出小刚给小林几张贴画后，他俩的贴画张数就同样多.\n【详解】18-10=8(张),8÷2=4(张),小刚给小林4张贴画后，他俩的贴画张数就同样多。故答案为:A",
+        "knowledge_points":  [
+                                 "和差倍问题",
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "23-24 二年级下·四川乐山·期中"
+    },
+    {
+        "id":  "420",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "24人去划船，每条船坐6人，需要( )条船。",
+        "options":  [
+                        "A. 4",
+                        "B. 5",
+                        "C. 6"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】根据题意可知：求需要的船的数量，用共有的人数除以每条船上的人数即可.\n【详解】24÷6=4(条),则需要4条船。故答案为:A",
+        "knowledge_points":  [
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "23-24二年级上·重庆璧山·期末"
+    },
+    {
+        "id":  "421",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "下列算式中，商最大的是( )。",
+        "options":  [
+                        "A. 6÷1",
+                        "B. 8÷2",
+                        "C. 18÷6"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】根据题意，依次计算出各算式的结果再比较大小。10以内数从大到小关系为:10\u003e9\u003e8\u003e7\u003e6\u003e5\u003e4\u003e3\u003e2\u003e1，由此比较.\n【详解】A。6÷1=6;B。8÷2=4;C。18÷6=3;3\u003c4\u003c6，商最大的是6÷1。故答案为:A",
+        "knowledge_points":  [
+                                 "10以内数的比大小",
+                                 "用2~5的乘法口诀求商",
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级上·河南周口·期中"
+    },
+    {
+        "id":  "422",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "下面第( )个问题不可以用15÷3这个算式来解决。",
+        "options":  [
+                        "A. 15个苹果，每3个放一盘，可以放几盘。",
+                        "B. 15根跳绳，平均分给3个班，每班分几根跳绳。",
+                        "C. 15本书分给两个班,1班分了3本书,2班分了几本书。"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】除法算式中，被除数表示总数，除数表示平均分成的份数，商表示每份的数量;或者被除数表示总数，除数表示每份的数量，商表示平均分成的份数。已知总量和其中一部分的数量，用减法可以得出另一部分的数量.\n【详解】A。15个苹果，每3个放一盘，可以放几盘。用算式15÷3解决;B。15根跳绳，平均分给3个班，每班分几根跳绳。用算式15÷3解决;C。15本书分给两个班,1班分了3本书,2班分了几本书。用算式15-3解决。不可以用15÷3这个算式来解决的是:15本书分给两个班,1班分了3本书,2班分了几本书。故答案为:C",
+        "knowledge_points":  [
+                                 "不退位减法(20以内)",
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "24-25二年级上·北京平谷·期中"
+    },
+    {
+        "id":  "423",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "从20里连续减去4，要减( )次，结果才能变成0。",
+        "options":  [
+                        "A. 4",
+                        "B. 5",
+                        "C. 16"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】根据题意可知：求从20里连续减去4，要减( )次，结果才能变成0。也就是求20里面有几个4，用除法计算.\n【详解】20÷4=5，则要减5次，结果才能变成0。故答案为:B",
+        "knowledge_points":  [
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "24-25二年级上·河南郑州·期中"
+    },
+    {
+        "id":  "424",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "每束花4元，花店店庆，买3束花送1束花,12元可以买( )束。",
+        "options":  [
+                        "A. 5",
+                        "B. 3",
+                        "C. 4"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】根据题意，总钱数÷每束花的钱数=可以买的束数，若满3束，则再加上1束即可。\n【详解】12÷4=3(束)，3+1=4(束)，12元可以买4束。故答案为：C",
+        "knowledge_points":  [
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "23-24二年级下·河南南阳·期末"
+    },
+    {
+        "id":  "425",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "1个苹果和( )个草莓同样重。![](images/3ad5b35fb6f79f4677250a8043b0936a2c04ba01402396db19d4bbe3151b4275.jpg)",
+        "options":  [
+                        "A. 2",
+                        "B. 3",
+                        "C. 4"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】由图可知，天平保持水平，天平两边一样重，即3个苹果=9个草莓，求1个苹果和几个草莓同样重，就是求9里面有几个3，用除法计算即可.\n【详解】9÷3=3(个),所以1个苹果和3个草莓同样重。故答案为:B",
+        "knowledge_points":  [
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "23-24二年级下·河南南阳·期末"
+    },
+    {
+        "id":  "426",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "在计算3×6,18÷6和18÷3时，都可以用哪一句乘法口诀( )。",
+        "options":  [
+                        "A. 二六十二",
+                        "B. 三六十八",
+                        "C. 二九十八"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】计算3×6所用到的乘法口诀是：三六十八，计算18÷6和18÷3所用到的乘法口诀是：三六十八，据此选择正确答案.\n【详解】根据\"三六十八\"可知:3×6=18,18÷6=3,18÷3=6。故答案为:B",
+        "knowledge_points":  [
+                                 "6的乘法口诀及应用",
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "23-24 二年级下·贵州六盘水·期末"
+    },
+    {
+        "id":  "427",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "有20根萝卜，小兔每次抱走5根，需要( )次才能抱完。",
+        "options":  [
+                        "A. 4",
+                        "B. 3",
+                        "C. 2"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】用胡萝卜的总数量除以小兔每次抱走的数量，求出商，就是需要抱的次数.\n【详解】20÷5=4(次),即有20根萝卜，小兔每次抱走5根，需要4次才能抱完。故答案为:A",
+        "knowledge_points":  [
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "23-24 二年级下·河北廊坊·期末"
+    },
+    {
+        "id":  "428",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "下面的分法是平均分的是( )。",
+        "options":  [
+                        "A. △△△△△ △△△△ △△△",
+                        "B. △△△△ △△△△ △△ △△",
+                        "C. △△△ △△△ △△△ △△△"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】平均分的意思是指在分物体的时候，要使每一份得到的数相等，据此逐项分析即可.\n【详解】A。△△△△△ △△△△ △△△分成了3份，不是每份数量都相等，不是平均分;B。△△△△ △△△△ △△ △△分成了4份，不是每份数量都相等，不是平均分;C。△△△ △△△ △△△ △△△平均分成了4份，每份是3个。故答案为:C",
+        "knowledge_points":  [
+                                 "整数平均分的意义及应用"
+                             ],
+        "source":  "23-24 二年级上·安徽芜湖·期中"
+    },
+    {
+        "id":  "429",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在算式18÷6=3中，除数是( ),商是( ),计算时所用的口诀是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "6;3;三六十八",
+        "solution":  "【分析】在除法算式里，除号前面的数叫被除数，后面的数叫除数，最后的结果叫商。根据乘法口诀求商时，口诀中后一个数作被除数，前面两个数一个数作除数，另一个数作商。计算18÷6=3时，需要想\"6乘几等于18\"，对应的乘法口诀是三六十八.\n【详解】在算式18÷6=3中，除数是6，商是3，计算时所用的口诀是三六十八。",
+        "knowledge_points":  [
+                                 "除法的初步认识",
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·湖南永州·阶段练习"
+    },
+    {
+        "id":  "430",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "30÷6读作( ),商是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "30除以6;5",
+        "solution":  "【分析】根据整数的除法算式的读法进行解答，再根据6的乘法口诀求商即可,30÷6=5.\n【详解】30÷6读作30除以6，商是5。",
+        "knowledge_points":  [
+                                 "除法的初步认识",
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·湖南永州·阶段练习"
+    },
+    {
+        "id":  "431",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "6个8是( ),24里面有( )个6。",
+        "options":  [
+
+                    ],
+        "answer":  "48;4",
+        "solution":  "【分析】求几个几是多少，可以用乘法计算。求一个数里有几个几，用除法计算.\n【详解】6×8=48;24÷6=4，则6个8是48,24里面有4个6。",
+        "knowledge_points":  [
+                                 "8的乘法口诀及应用",
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·湖南永州·阶段练习"
+    },
+    {
+        "id":  "432",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "在括号里填上“+”“-”“×”或“÷”。\n3( )1=3  24( )6=4  6( )2=12  18( )3=6\n12( )2=6  9( )3=6  15( )5=20  4( )4=1",
+        "options":  [
+
+                    ],
+        "answer":  "×或÷;÷;×;÷;÷;-;+;÷",
+        "solution":  "【分析】根据整数加减法的计算法则，表内乘法口诀及表内除法进行解答。根据口诀“一三得三”可知，3×1=3；或3÷1=3；根据口诀“四六二十四”可知，24÷6=4；根据口诀“二六十二”可知，6×2=12；根据口诀“三六十八”可知，18÷3=6；根据口诀“二六十二”可知，12÷2=6；9可以分成3和6，即9-3=6；15和5合起来就是20，即15+5=20；根据口诀“一四得四”可知，4÷4=1。\n【详解】3×1=3或3÷1=3，24÷6=4，6×2=12，18÷3=6，12÷2=6，9-3=6，15+5=20，4÷4=1。",
+        "knowledge_points":  [
+                                 "8,9的加减法",
+                                 "6的乘法口诀及应用",
+                                 "用2~5的乘法口诀求商",
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·河北石家庄·阶段练习"
+    },
+    {
+        "id":  "433",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "8÷4=2读作( )，8是( )，4是( )，2是( )，计算时想：二( )得八，商是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "8除以4等于2;被除数;除数;商;四;2",
+        "solution":  "【分析】除法算式为被除数÷除数=商，除法算式从左往右读，数字是几就读几，“÷”读作除以，“=”读作等于；根据乘法口诀计算除法算式时，口诀中的后一个数是被除数，前两个数可分别为除数和商，由此解答。\n【详解】8÷4=2读作8除以4等于2，8是被除数，4是除数，2是商，计算时想：二四得八，商是2。",
+        "knowledge_points":  [
+                                 "除法的初步认识",
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·河北石家庄·阶段练习"
+    },
+    {
+        "id":  "434",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "12个▲，如果每3个分成一份，可以平均分成( )份，列式为( )。",
+        "options":  [
+
+                    ],
+        "answer":  "4;12÷3=4(份)",
+        "solution":  "【分析】求可以分成几份，也就是12里面有几个3，用除法计算，即总数量÷每份的数量=可以分成的份数。\n【详解】12个▲，如果每3个分成一份，可以平均分成4份，列式为12÷3=4(份)。",
+        "knowledge_points":  [
+                                 "除法的初步认识",
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·河北石家庄·阶段练习"
+    },
+    {
+        "id":  "435",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "28÷7=4，读作( ),被除数是( ),商是( )。表示把( )平均分成( )份，每份是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "28除以7等于4;28;4;28;7;4",
+        "solution":  "【分析】根据除法各部分名称读出算式即可，从左到右读，数字直接读出，“÷”读作除以，“=”读作等于，“÷”前面的数是被除数，“=”后面的数是商；除法算式可以表示把被除数平均分成除数的份数，商就是每份的数；据此解答即可。\n【详解】28÷7=4，读作28除以7等于4，被除数是28，商是4。表示把28平均分成7份，每份是4。",
+        "knowledge_points":  [
+                                 "整数平均分的意义及应用",
+                                 "除法的初步认识"
+                             ],
+        "source":  "23-24 二年级下·浙江温州·期中"
+    },
+    {
+        "id":  "436",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "6÷2=3读作:( )。",
+        "options":  [
+
+                    ],
+        "answer":  "6除以2等于3",
+        "solution":  "【分析】根据除法算式的读法，“÷”读作除以，“=”读作等于，每个数字按照数的读法读数来即可解答。\n【详解】6÷2=3读作：6除以2等于3。",
+        "knowledge_points":  [
+                                 "除法的初步认识"
+                             ],
+        "source":  "2025 二年级下·全国·专题练习"
+    },
+    {
+        "id":  "437",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "三（3）班的同学参加秋游。如果每个小组6人，可以分成6个小组；如果每个小组4人，可以分成( )个小组。",
+        "options":  [
+
+                    ],
+        "answer":  "9",
+        "solution":  "【分析】用每小组的人数×小组数即可求出总人数，然后再除以4，即为解题。\n【详解】6×6=36(人)，36÷4=9(个)，三（3）班的同学参加秋游。如果每个小组6人，可以分成6个小组；如果每个小组4人，可以分成9个小组。",
+        "knowledge_points":  [
+                                 "归总问题",
+                                 "6的乘法口诀及应用",
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "24-25 三年级上·广东广州·期末"
+    },
+    {
+        "id":  "438",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "比一比。在括号里填上“\u003e”“\u003c”或“=”。\n5×5( )5+5  15÷3( )20÷4  26+6( )4×9",
+        "options":  [
+
+                    ],
+        "answer":  "\u003e;=;\u003c",
+        "solution":  "【分析】先根据乘法口诀或整数加减法的计算法则，算出每一个算式的结果，然后比较大小即可。\n【详解】5×5=25，5+5=10，25\u003e10，故5×5\u003e5+5；15÷3=5，20÷4=5，故15÷3=20÷4；26+6=32，4×9=36，32\u003c36，故26+6\u003c4×9。",
+        "knowledge_points":  [
+                                 "100以内数的比大小",
+                                 "5的乘法口诀及应用",
+                                 "9的乘法口诀及应用",
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "23-24 二年级上·河北保定·期末"
+    },
+    {
+        "id":  "439",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "六一儿童节张老师去买了一些小礼品，比30个多，比40个少。平均分的份数和每份数同样多。张老师买了( )个小礼品。",
+        "options":  [
+
+                    ],
+        "answer":  "36",
+        "solution":  "【分析】乘法算式中，两个乘数表示每份的数量和份数，积表示总数。平均分的份数和每份数同样多，说明两个乘数一样，积是三十几，积就是买的小礼品个数.\n【详解】五五二十五，六六三十六，七七四十九。25\u003c30\u003c36\u003c40\u003c49，所以张老师买了36个小礼品。",
+        "knowledge_points":  [
+                                 "6的乘法口诀及应用",
+                                 "整数平均分的意义及应用"
+                             ],
+        "source":  "22-23 二年级下·四川乐山·期末"
+    },
+    {
+        "id":  "440",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "用口诀\"五五二十五\"可以写出一个乘法算式是( ),还可以写出一个除法算式是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "5×5=25;25÷5=5",
+        "solution":  "【分析】乘法算式中两个乘数是口诀中的前两个数，积是口诀中的后一个数，写算式时两个乘数可互换位置。根据乘法口诀求商时，口诀中后面一个数作被除数，前面两个数一个数作除数另一个数作商.\n【详解】用口诀\"五五二十五\"可以写出一个乘法算式是5×5=25，还可以写出一个除法算式是25÷5=5。",
+        "knowledge_points":  [
+                                 "5的乘法口诀及应用",
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "22-23 二年级下·四川南充·期末"
+    },
+    {
+        "id":  "441",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "32÷8=4，读作( )，表示把( )平均分成( )份，每份是( )，还可以表示32里面有( )个8。",
+        "options":  [
+
+                    ],
+        "answer":  "32除以8等于4;32;8;4;4",
+        "solution":  "【分析】除法算式从左往右读，数字是几就读几，“÷”读作除以，“=”读作等于。除法算式可以表示把被除数平均分成除数的份数，商就是每份的量；也可以表示被除数里有商个数的除数。\n【详解】32÷8=4，读作32除以8等于4，表示把32平均分成8份，每份是4，还可以表示32里面有4个8。",
+        "knowledge_points":  [
+                                 "整数平均分的意义及应用",
+                                 "除法的初步认识"
+                             ],
+        "source":  "23-24 二年级下·四川绵阳·期中"
+    },
+    {
+        "id":  "442",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "18个橘子，每盘装6个，可以装( )盘，算式是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "3;18÷6=3(盘)",
+        "solution":  "【分析】求可以装几盘，也就是求18里面有几个6，用除法计算，橘子的总数量÷每盘装的数量=可以装的盘数。\n【详解】18个橘子，每盘装6个，可以装3盘，算式是18÷6=3(盘)。",
+        "knowledge_points":  [
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "23-24 二年级下·四川乐山·期末"
+    },
+    {
+        "id":  "443",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "45÷9=5读作( ),可以表示45里面有( )个9。",
+        "options":  [
+
+                    ],
+        "answer":  "45除以9等于5;5",
+        "solution":  "【分析】除法算式从左往右读，数字是几就读几，“÷”读作除以，“=”读作等于。除法算式可以表示被除数里有商个数的除数。\n【详解】45÷9=5读作45除以9等于5，可以表示45里面有5个9。",
+        "knowledge_points":  [
+                                 "除法的初步认识"
+                             ],
+        "source":  "23-24 二年级下·四川乐山·期末"
+    },
+    {
+        "id":  "444",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "18÷3=( ),表示把( )平均分成( )份，每份是( ),还表示18里面有( )个( )。",
+        "options":  [
+
+                    ],
+        "answer":  "6;18;3;6;6;3",
+        "solution":  "【分析】两个数相除，根据乘法口诀即可求出商，它既可以表示一个数里面有几个相同的数;也可以表示把一个数平均分成若干份，求每份是多少;据此解决.\n【详解】18÷3=6，表示把18平均分成3份，每份是6，还表示18里面有6个3。",
+        "knowledge_points":  [
+                                 "整数平均分的意义及应用",
+                                 "除法的初步认识",
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级上·河南新乡·期中"
+    },
+    {
+        "id":  "445",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "有( )个○，每( )个分一份，可以分成( )份。",
+        "options":  [
+
+                    ],
+        "answer":  "10;2;5",
+        "solution":  "【分析】把一个数分成几份，已知其中的一份，即可求出可分成几份，用除法计算即可。根据题图可知：先数一数一共有的○的数量，然后2个是一份，求可以分成几份，用除法计算即可。\n【详解】○的数量：10个。10÷2=5(份)，则有10个○，每2个分一份，可以分成5份。",
+        "knowledge_points":  [
+                                 "除法的初步认识",
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级上·河南新乡·期中"
+    },
+    {
+        "id":  "446",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "15÷5=3，是把15平均分成( )份，每份是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "5;3",
+        "solution":  "【分析】根据平均分除法的意义，把一个数平均分成若干份，求一份是多少，用除法计算，被除数是15，除数是5，商是3，就是把15平均分成5份，每份是3.\n【详解】15÷5=3，是把15平均分成5份，每份是3。",
+        "knowledge_points":  [
+                                 "整数平均分的意义及应用",
+                                 "除法的初步认识",
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级上·广西贵港·期中"
+    },
+    {
+        "id":  "447",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "乘数4和乘数3的积是( ),被除数是36，除数是6，商是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "12;6",
+        "solution":  "【分析】乘法算式为：乘数×乘数=积；除法算式为：被除数÷除数=商，由此代入计算。\n【详解】4×3=12；36÷6=6，乘数4和乘数3的积是12，被除数是36，除数是6，商是6。",
+        "knowledge_points":  [
+                                 "4的乘法口诀及应用",
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "24-25二年级上·广西贵港·期中"
+    },
+    {
+        "id":  "448",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在( )里填上合适的数。\n24÷( )=4  3×( )=12  5×( )=25",
+        "options":  [
+
+                    ],
+        "answer":  "6;4;5",
+        "solution":  "【分析】被除数÷商=除数，积÷乘数=另一个乘数，据此计算。乘法算式中两个乘数是口诀中的前两个数，积是口诀中的后一个数，写算式时两个乘数可互换位置。根据乘法口诀求商时，口诀中后面一个数作被除数，前面两个数一个数作除数，另一个数作商。\n【详解】24÷4=6，所以24÷6=4；12÷3=4，所以3×4=12；25÷5=5，所以5×5=25。",
+        "knowledge_points":  [
+                                 "5的乘法口诀及应用",
+                                 "4的乘法口诀及应用",
+                                 "用2~5的乘法口诀求商",
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级上·广西贵港·期中"
+    },
+    {
+        "id":  "449",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "用12个小棒摆三角形，可以摆成( )个单独的三角形。",
+        "options":  [
+
+                    ],
+        "answer":  "4",
+        "solution":  "【分析】摆一个三角形需要3根小棒，用12个小棒能摆多少个三角形，也就是求12里面有几个3，用除法计算.\n【详解】12÷3=4(个),用12个小棒摆三角形，可以摆成4个单独的三角形。",
+        "knowledge_points":  [
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级上·河南周口·期中"
+    },
+    {
+        "id":  "450",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "一根8米的绳子，对折后再对折，每段绳子长( )米。",
+        "options":  [
+
+                    ],
+        "answer":  "2",
+        "solution":  "【分析】对折一次将这根绳子平均分成2份，对折两次将这根绳子平均分成4份，求每段的长度也就是把这根绳子平均分成4份，求每份是多少，用除法解答.\n【详解】8÷4=2(米),一根8米的绳子，对折后再对折，每段绳子长2米。",
+        "knowledge_points":  [
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "24-25 三年级上·湖北黄冈·期中"
+    },
+    {
+        "id":  "451",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "饼干原来8元1盒，现在促销，4盒24元。每盒比原来便宜( )元。",
+        "options":  [
+
+                    ],
+        "answer":  "2",
+        "solution":  "【分析】先根据整数除法的意义，用24除以4求出促销后1盒饼干的价钱，再根据减法的意义，用1盒饼干的原价减去求出的促销后的价钱即可求出每盒比原来便宜的钱数，据此解答即可。\n【详解】24÷4=6(元)，8-6=2(元)，所以饼干原来8元1盒，现在促销，4盒24元。每盒比原来便宜2元。",
+        "knowledge_points":  [
+                                 "8,9的加减法",
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "23-24 二年级下·河南南阳·期末"
+    },
+    {
+        "id":  "452",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在括号里填“\u003e”“\u003c”或“=”。\n6÷2( )4÷1  6×2( )3×4  10-5( )10÷5  18÷6( )12÷3",
+        "options":  [
+
+                    ],
+        "answer":  "\u003c;=;\u003e;\u003c",
+        "solution":  "【分析】分别计算出各算式的答案，然后再比较大小。比较两个整数的大小，位数多的数大；位数相同，从最高位看起，相同数位上的数大，那个数就大。\n【详解】6÷2=3，4÷1=4，3\u003c4，则6÷2\u003c4÷1；6×2=12，3×4=12，12=12，则6×2=3×4；10-5=5，10÷5=2，5\u003e2，则10-5\u003e10÷5；18÷6=3，12÷3=4，3\u003c4，则18÷6\u003c12÷3。",
+        "knowledge_points":  [
+                                 "4的乘法口诀及应用",
+                                 "6的乘法口诀及应用",
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "24-25二年级上·河南郑州·期中"
+    },
+    {
+        "id":  "453",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "把一根20厘米长的绳子剪成一样长的4段，每段长( )厘米。",
+        "options":  [
+
+                    ],
+        "answer":  "5",
+        "solution":  "【分析】根据题意,4段绳子一样长，总长度是20厘米，求每段的长度，用除法计算解答即可.\n【详解】20÷4=5(厘米),把一根20厘米长的绳子剪成一样长的4段，每段长5厘米。",
+        "knowledge_points":  [
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "23-24 二年级上·浙江杭州·期中"
+    },
+    {
+        "id":  "454",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在( )里填上合适的数。\n24÷( )=6  4×( )=12  1×( )=1",
+        "options":  [
+
+                    ],
+        "answer":  "4;3;1",
+        "solution":  "【分析】根据乘法口诀填空，乘法算式中两个乘数是口诀中的前两个数，积是口诀中的后一个数；用乘法口诀求除数，观察除法算式，根据乘法口诀想商乘几等于被除数，除数就是几，据此解答即可。\n【详解】24÷4=6，4×3=12，1×1=1。",
+        "knowledge_points":  [
+                                 "4的乘法口诀及应用",
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "22-23 二年级上·广西贵港·期中"
+    },
+    {
+        "id":  "455",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "在括号里填上“\u003e”“\u003c”或“=”。\n4×3( )16  6÷2( )4  2+2( )2×2  36÷6( )6  18÷6( )2  5×5( )4×6",
+        "options":  [
+
+                    ],
+        "answer":  "\u003c;\u003c;=;=;\u003e;\u003e",
+        "solution":  "【分析】比较数的大小，先看位数的多少，位数多的数就大；如果位数相同，从最高位开始比较，最高位上的数大则这个数大，最高位上的数相同，就比较下一位，依次类推。含有算式的大小比较，可以先计算出每个算式的结果，再比较大小。\n【详解】4×3=12，所以4×3\u003c16；6÷2=3，所以6÷2\u003c4；2+2=4，2×2=4，所以2+2=2×2；36÷6=6，所以36÷6=6；18÷6=3，所以18÷6\u003e2；5×5=25，4×6=24，所以5×5\u003e4×6。",
+        "knowledge_points":  [
+                                 "5以内数的加法",
+                                 "5的乘法口诀及应用",
+                                 "4的乘法口诀及应用",
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "23-24 二年级上·湖南邵阳·期中"
+    },
+    {
+        "id":  "456",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "6个♡，每3个一份，可以分成3份。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】求可以分成几份，也就是求6里面有几个3，用除法计算，即总数量÷每份的数量=可以分成的份数。\n【详解】6÷3=2(份)，6个♡，每3个一份，可以分成2份。原题说法错误。故答案为：×",
+        "knowledge_points":  [
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·山东济南·阶段练习"
+    },
+    {
+        "id":  "457",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "计算2×6与12÷4时，运用同一句乘法口诀。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】根据给出的算式，2×6可以使用二六十二的乘法口诀；12÷4的算式需要将除法转化为乘法，即思考4乘几等于12，对应的口诀是三四十二，根据两个算式对应的乘法口诀即可得出答案。\n【详解】2×6对应的乘法口诀是二六十二；12÷4对应的乘法口诀是三四十二。故答案为：×",
+        "knowledge_points":  [
+                                 "6的乘法口诀及应用",
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "24-25二年级下·山东济南·阶段练习"
+    },
+    {
+        "id":  "458",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "□÷3=5，□里填8。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】根据乘法口诀求商时，口诀中后面一个数作被除数，前面两个数一个数作除数，另一个数作商。\n【详解】想：三五十五，所以15÷3=5，□里填15。原题说法错误。故答案为：×",
+        "knowledge_points":  [
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·山东济南·阶段练习"
+    },
+    {
+        "id":  "459",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "被除数是6，除数是6，商也是6。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】除法算式为被除数÷除数=商，由此计算出商即可解答。\n【详解】6÷6=1，被除数是6，除数是6，商是1，原题说法错误。故答案为：×",
+        "knowledge_points":  [
+                                 "除法的初步认识",
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·山东济南·阶段练习"
+    },
+    {
+        "id":  "460",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "6只兔子吃18棵小草，平均每只兔子吃3棵小草。( )",
+        "options":  [
+
+                    ],
+        "answer":  "√",
+        "solution":  "【分析】根据题意可知：求每只兔子吃小草的数量，用共有小草的数量除以兔子的数量即可。\n【详解】18÷6=3(棵)，则平均每只兔子吃3棵小草。原题说法正确。故答案为：√",
+        "knowledge_points":  [
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·湖南永州·阶段练习"
+    },
+    {
+        "id":  "461",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "判断题",
+        "difficulty":  0.65,
+        "question":  "把15个苹果分给3个同学，每个同学分5个苹果。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】如果是平均分则每人分得同样多，每人得5个正确，但是题目没有说明是平均分，所以错误.\n【详解】把15个苹果平均分给3个同学，每个同学分5个苹果。所以原题说法错误。故答案为: ×",
+        "knowledge_points":  [
+                                 "整数平均分的意义及应用"
+                             ],
+        "source":  "24-25 二年级下·湖南永州·月考"
+    },
+    {
+        "id":  "462",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "把12个苹果装在两个盆里，每个盆里一定有6个苹果。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】把12个苹果装在两个盆里，如果是平均分的话，根据除法的意义可知,12÷2=6(个),每个盆里有6个苹果;但是题中没有说平均分，因此也可以有别的放法，如：一个放2个，另一个放10个;一个放5个，另一个放7个，由此解答.\n【详解】题干没有说平均分，则把12个苹果装在两个盆里，每个盆里不一定有6个苹果。原题说法错误。故答案为: ×",
+        "knowledge_points":  [
+                                 "整数平均分的意义及应用",
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "24-25二年级下·河北石家庄·阶段练习"
+    },
+    {
+        "id":  "463",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "一把剪刀6元,30元可以买6把这样的剪刀。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】根据除法的意义，总钱数÷每把剪刀的钱数=可以买的数量，代入计算即可解答。`n【详解】30÷6=5(把)，一把剪刀6元，30元可以买5把这样的剪刀，原题说法错误。故答案为：×",
+        "knowledge_points":  [
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "24-25二年级下·河北石家庄·阶段练习"
+    },
+    {
+        "id":  "464",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "计算12÷3和12÷4时，用同一句口诀。( )",
+        "options":  [
+
+                    ],
+        "answer":  "√",
+        "solution":  "【分析】根据乘法口诀计算除法算式时，口诀中的后一个数是被除数，前两个数可分别为除数和商，由此写出口诀即可解答.\n【详解】计算12÷3用到的口诀是三四十二;计算12÷4用到的口诀是三四十二，用的是同一句口诀，原题说法正确。故答案为:√",
+        "knowledge_points":  [
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·河北石家庄·阶段练习"
+    },
+    {
+        "id":  "465",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "算式10÷5=2读作:10除5等于2。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】读除法算式时，数字直接读出，“÷”读作除以，“=”读作等于。`n【详解】算式10÷5=2读作：10除以5等于2。则原题说法错误。故答案为：×",
+        "knowledge_points":  [
+                                 "除法的初步认识"
+                             ],
+        "source":  "24-25 二年级下·河北石家庄·阶段练习"
+    },
+    {
+        "id":  "466",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "根据每一道乘法算式都可以写出两道除法算式。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】根据\"3×3=9\"只能写出\"9÷3=3\"一道除法算式，据此解答.\n【详解】根据分析可知，根据每一道乘法算式都可以写出两道除法算式;原说法错误。故答案为: ×",
+        "knowledge_points":  [
+                                 "3的乘法口诀及应用",
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "2025 二年级下·全国·专题练习"
+    },
+    {
+        "id":  "467",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "在算式21÷3=7中，除数是21，被除数是3，商是7。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】根据“被除数÷除数=商”来找出各部分对应的数即可。`n【详解】在算式21÷3=7中，被除数是21，除数是3，商是7，原题说法错误。故答案为：×",
+        "knowledge_points":  [
+                                 "除法的初步认识"
+                             ],
+        "source":  "24-25 二年级上·广东揭阳·期末"
+    },
+    {
+        "id":  "468",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "一个数除以6，商是4，这个数是24。( )",
+        "options":  [
+
+                    ],
+        "answer":  "√",
+        "solution":  "【分析】除数是6，商是4，商×除数=被除数，据此计算.\n【详解】4×6=24，一个数除以6，商是4，这个数是24。原题说法正确。故答案为:√",
+        "knowledge_points":  [
+                                 "6的乘法口诀及应用",
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级上·河南周口·期末"
+    },
+    {
+        "id":  "469",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "把12颗糖分成3个等份，每份一定是4颗。( )",
+        "options":  [
+
+                    ],
+        "answer":  "√",
+        "solution":  "【分析】把12颗糖分成3个等份，也就是把12颗糖平均分成3份，求每份的数量，用除法计算.\n【详解】12÷3=4(颗),把12颗糖分成3个等份，每份一定是4颗。原题说法正确。故答案为:√",
+        "knowledge_points":  [
+                                 "整数平均分的意义及应用",
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "22-23 二年级下·四川乐山·期末"
+    },
+    {
+        "id":  "470",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "把12颗糖分成3个等份，每份一定是4颗。( )",
+        "options":  [
+
+                    ],
+        "answer":  "√",
+        "solution":  "【分析】把12颗糖分成3个等份，也就是把12颗糖平均分成3份，求每份的数量，用除法计算.\n【详解】12÷3=4(颗),把12颗糖分成3个等份，每份一定是4颗。原题说法正确。故答案为:√",
+        "knowledge_points":  [
+                                 "整数平均分的意义及应用",
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "22-23 二年级下·四川乐山·期末"
+    },
+    {
+        "id":  "471",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "4×3读作4乘3;8÷4读作8除以4。( )",
+        "options":  [
+
+                    ],
+        "answer":  "√",
+        "solution":  "【分析】读乘法算式时，依次从左往右读，数字直接读出来，“×”读作乘。读除法算式时，依次从左往右读，“÷”读作除以，数字直接读出来。`n【详解】4×3读作4乘3，8÷4读作8除以4。原题说法正确。故答案为：√",
+        "knowledge_points":  [
+                                 "初步认识乘法意义",
+                                 "除法的初步认识"
+                             ],
+        "source":  "24-25二年级上·河南新乡·期中"
+    },
+    {
+        "id":  "472",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "根据乘法口诀\"四四十六\"可以写出两道除法算式。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】两个乘数相同的乘法口诀只能写一道乘法算式或一道除法算式，据此判断.\n【详解】根据乘法口诀\"四四十六\"可以写出一道除法算式:16÷4=4，原题说法错误。故答案为: ×",
+        "knowledge_points":  [
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级上·河南新乡·期中"
+    },
+    {
+        "id":  "473",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "乘法口诀\"四四十六\"只可以列出一道除法算式。( )",
+        "options":  [
+
+                    ],
+        "answer":  "√",
+        "solution":  "【分析】根据题意，乘法口诀\"四四十六\"可以列出的乘法算式是:4×4=16，列出的除法算式是:16÷4=4，据此判断即可.\n【详解】乘法口诀\"四四十六\"只可以列出一道除法算式。原题说法正确。故答案为:√",
+        "knowledge_points":  [
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级上·河南周口·期末"
+    },
+    {
+        "id":  "474",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "小明，小新，小军和小华共有24颗糖，那么他们每人有6颗糖。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】四个人共有24颗糖，平均每人有的糖数=总数÷人数，即24÷4=6(颗)。题目中并没说明是平均分，所以原题说法错误。`n【详解】24÷4=6(颗)，小明、小新、小军和小华共有24颗糖，如果平均分的话，那么他们每人有6颗糖。题目中并没说明是平均分，所以原题说法错误。故答案为：×",
+        "knowledge_points":  [
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "24-25 四年级上·湖南邵阳·期中"
+    },
+    {
+        "id":  "475",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "在一个除法算式里，被除数是24，除数是6，商一定是3。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】被除数÷除数=商，根据乘法口诀求商时，口诀中后面一个数作被除数，前面两个数一个数作除数，另一个数作商。`n【详解】24÷6=4，在一个除法算式里，被除数是24，除数是6，商一定是4。原题说法错误。故答案为：×",
+        "knowledge_points":  [
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级上·河北保定·期中"
+    },
+    {
+        "id":  "476",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "把15个苹果分给5人，每人分得3个是平均分。( )",
+        "options":  [
+
+                    ],
+        "answer":  "√",
+        "solution":  "【分析】平均分，指在分物体的时候，要尽可能地分完，而且还要使每一份得到的数相等。据此解决即可.\n【详解】把15个苹果分给5人，每人分得3个，也就是每个人分得一样多，这是平均分;原题说法正确。故答案为:√",
+        "knowledge_points":  [
+                                 "整数平均分的意义及应用"
+                             ],
+        "source":  "23-24 二年级下·河北廊坊·期末"
+    },
+    {
+        "id":  "477",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "8÷4读作:8除以4。( )",
+        "options":  [
+
+                    ],
+        "answer":  "√",
+        "solution":  "【分析】读除法算式时，依次从左往右读，“÷”读作除以，数字直接读出来。`n【详解】8÷4读作：8除以4。原题说法正确。故答案为：√",
+        "knowledge_points":  [
+                                 "除法的初步认识"
+                             ],
+        "source":  "23-24二年级上·安徽芜湖·期中"
+    },
+    {
+        "id":  "478",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "15个气球可以平均分给5个小朋友。( )",
+        "options":  [
+
+                    ],
+        "answer":  "√",
+        "solution":  "【分析】把一个数平均分成几份，求每份是多少，用除法列式计算，然后结合乘法口诀，算出结果，即可解决.\n【详解】15÷5=3(个),即15个气球可以平均分给5个小朋友，每个小朋友分到3个;原说法正确。故答案为:√",
+        "knowledge_points":  [
+                                 "整数平均分的意义及应用",
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "23-24 二年级上·湖南邵阳·期中"
+    },
+    {
+        "id":  "479",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "计算6÷2与6×3，应用的乘法口诀相同。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】根据乘法口诀求商时，口诀中后面一个数作被除数，前面两个数一个数作除数另一个数作商;根据乘法口诀计算乘法算式结果时，乘法算式中两个乘数(可交换位置)是口诀中的前两个数，积是口诀中的后一个数;据此解答即可.\n【详解】计算6÷2应用乘法口诀\"二三得六\"，计算6×3应用乘法口诀\"三六十八\"，两个算式应用的乘法口诀不相同，原题说法错误。故答案为: ×",
+        "knowledge_points":  [
+                                 "6的乘法口诀及应用",
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "23-24 二年级上·湖南邵阳·期中"
+    },
+    {
+        "id":  "480",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "小丽阿姨扎了24朵红花，36朵黄花。红花每4朵扎一把，每把标价8元。黄花每6朵扎一把，每把标价9元。`n(1)1朵红花多少元？红花一共可以卖多少元？`n(2)黄花可以扎几把？一共可以卖多少元？",
+        "options":  [
+
+                    ],
+        "answer":  "2元;48元;6把;54元",
+        "solution":  "【分析】(1)根据除法的意义，每把红花的钱数÷每把红花的朵数=每朵红花的钱数；红花的总朵数÷每把的朵数=红花可以扎成的把数；每把红花的钱数×红花扎成的把数=红花可以卖的总钱数；(2)黄花的总朵数÷每把的朵数=可以扎成的把数；每把黄花的钱数×黄花扎成的把数=黄花可以卖的总钱数。`n【详解】(1)8÷4=2(元)，24÷4=6(把)，8×6=48(元)，答：1朵红花2元，红花一共可以卖48元。(2)36÷6=6(把)，9×6=54(元)，答：黄花可以扎6把，一共可以卖54元。",
+        "knowledge_points":  [
+                                 "8的乘法口诀及应用",
+                                 "9的乘法口诀及应用",
+                                 "用2~5的乘法口诀求商",
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "24-25二年级下·湖南永州·阶段练习"
+    },
+    {
+        "id":  "481",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "端午节，妈妈包了24个粽子，每盘装6个，一共要装多少盘。",
+        "options":  [
+
+                    ],
+        "answer":  "4盘",
+        "solution":  "【分析】求一共要装几盘，也就是求24里面有几个6，用除法计算，即粽子的总数量÷每盘装的数量=装的盘数。`n【详解】24÷6=4(盘)，答：一共要装4盘。",
+        "knowledge_points":  [
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·湖南永州·阶段练习"
+    },
+    {
+        "id":  "482",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "植树节快到了,3个小朋友要种12棵小树，平均每个小朋友要种几棵小树。",
+        "options":  [
+
+                    ],
+        "answer":  "4棵",
+        "solution":  "【分析】求每个小朋友种几棵，也就是求把12平均分成3份，每份是多少，用除法计算，即要种的总数量÷小朋友的人数=平均每人要种的数量。`n【详解】12÷3=4(棵)，答：平均每个小朋友要种4棵小树。",
+        "knowledge_points":  [
+                                 "整数平均分的意义及应用",
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "24-25二年级下·河北石家庄·阶段练习"
+    },
+    {
+        "id":  "483",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "教室里有15张桌子，每3张摆成一排，可以摆几排。",
+        "options":  [
+
+                    ],
+        "answer":  "5排",
+        "solution":  "【分析】求可以摆几排，也就是15里面有几个3，用除法计算，即桌子的总数量÷每排摆的数量=可以摆的排数。`n【详解】15÷3=5(排)，答：可以摆5排。",
+        "knowledge_points":  [
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·河北石家庄·阶段练习"
+    },
+    {
+        "id":  "484",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "妈妈买了6块橡皮，共花了12元，平均每块橡皮多少元。",
+        "options":  [
+
+                    ],
+        "answer":  "2元",
+        "solution":  "【分析】根据题意可知：用共花的钱除以买的数量即可求出每块的钱数.\n【详解】12÷6=2(元),答：平均每块橡皮2元。",
+        "knowledge_points":  [
+                                 "整数平均分的意义及应用",
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·河北石家庄·阶段练习"
+    },
+    {
+        "id":  "485",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "奇奇把20张魔法卡片分给青青和他的4个小伙伴，平均每人分到多少张魔法卡片。",
+        "options":  [
+
+                    ],
+        "answer":  "4张",
+        "solution":  "【分析】先算出要分的人数，用魔法卡片的数量除以要分的人数，等于平均每人分到的数量.\n【详解】4+1=5(人),20÷5=4(张),答：平均每人分到4张魔法卡片。",
+        "knowledge_points":  [
+                                 "5以内数的加法",
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "2025二年级下·全国·专题练习"
+    },
+    {
+        "id":  "486",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "6个乒乓球18元钱,3个羽毛球12元钱，哪种球比较便宜。每个球便宜多少钱。",
+        "options":  [
+
+                    ],
+        "answer":  "乒乓球;1元",
+        "solution":  "【分析】根据题意可知：先分别求出乒乓球的单价和羽毛球的单价。用6个乒乓球的钱数除以乒乓球的个数即可求出乒乓球的单价，用3个羽毛球的钱数除以羽毛球的个数即可求出羽毛球的单价。然后将单价进行比较，小的数则便宜，大的则贵，用大的数减去小的数即可求出每个球便宜的钱数.\n【详解】18÷6=3(元),12÷3=4(元),4\u003e3,4-3=1(元),答：乒乓球便宜，每个球便宜1元。",
+        "knowledge_points":  [
+                                 "经济问题",
+                                 "用2~5的乘法口诀求商",
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "2025 二年级下·全国·专题练习"
+    },
+    {
+        "id":  "487",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "一根木料长10米，要把它据成一些2米长的小段，每据一次要用4分钟，一共要用多少分钟。画一画，算一算。",
+        "options":  [
+
+                    ],
+        "answer":  "图见详解;16分钟",
+        "solution":  "【分析】根据题意可知：总长度除以每段的长度，等于可以锯成多少段，锯的次数等于锯的段数减1，锯的次数乘每锯一次用的时间，等于一共需要多少分钟，据此列式计算即可.\n【详解】10÷2=5(段),5-1=4(次),4×4=16(分钟),答：一共要用16分钟。",
+        "knowledge_points":  [
+                                 "4的乘法口诀及应用",
+                                 "用2~5的乘法口诀求商",
+                                 "植树问题(两端都不栽)"
+                             ],
+        "source":  "23-24 二年级下·浙江温州·期中"
+    },
+    {
+        "id":  "488",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "端午节到啦!王明家买来了25个粽子，每5个装一袋，可以装几袋。",
+        "options":  [
+
+                    ],
+        "answer":  "5袋",
+        "solution":  "【分析】粽子的总数量除以每袋装的数量，等于可以装几袋，据此解答.\n【详解】25÷5=5(袋),答：可以装5袋。",
+        "knowledge_points":  [
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "23-24二年级下·浙江温州·期末"
+    },
+    {
+        "id":  "489",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "一共有6枝花，每个花瓶里插2枝花，一共可以插多少个花瓶。",
+        "options":  [
+
+                    ],
+        "answer":  "3个",
+        "solution":  "【分析】由题意可知，用花的总数量除以每个花瓶插的花朵数即可解答.\n【详解】6÷2=3(个),答：一共可以插3个花瓶。",
+        "knowledge_points":  [
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "2025二年级下·全国·专题练习"
+    },
+    {
+        "id":  "490",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "把12张画片分给丽丽和她的2个同学，平均每人分几张。",
+        "options":  [
+
+                    ],
+        "answer":  "4张",
+        "solution":  "【分析】先算出一共要分给同学的数量，用画片的总数量除以要分同学的数量，等于平均每人分的数量.\n【详解】1+2=3(个),12÷3=4(张),答：平均每人分4张。",
+        "knowledge_points":  [
+                                 "5以内数的加法",
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "2025 二年级下·全国·专题练习"
+    },
+    {
+        "id":  "491",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "妈妈买了4袋面包，共有24个。`n(1)如果买8袋面包，一共有几个？`n(2)如果有42个面包，可以装成这样的几袋？",
+        "options":  [
+
+                    ],
+        "answer":  "48个;7袋",
+        "solution":  "【分析】(1)妈妈买了4袋面包，共有24个，据此根据除法的意义，用24除以4，先算出每袋里面包有几个，求买8袋面包一共有几个，用求出的每袋里面包的个数乘8，即可解答。(2)如果有42个面包，求可以装成这样的几袋，也就是求42个面包里面有几个每袋里面包的个数，即用42除以(1)小问里面求出的每袋里面包的个数，计算出结果即可解答。`n【详解】(1)24÷4=6(个)，6×8=48(个)，答：一共有48个。(2)42÷6=7(袋)，答：可以装成这样的7袋。",
+        "knowledge_points":  [
+                                 "8的乘法口诀及应用",
+                                 "用2~5的乘法口诀求商",
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "23-24 三年级上·河北保定·期末"
+    },
+    {
+        "id":  "492",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "过\"六一\"儿童节时，老师把16颗糖平均分给第一组的4个同学，每人分到多少颗糖。",
+        "options":  [
+
+                    ],
+        "answer":  "4颗",
+        "solution":  "【分析】用糖的总颗数除以人数即可求得每人分到多少颗糖.\n【详解】16÷4=4(颗),答：每人分到4颗糖。",
+        "knowledge_points":  [
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "22-23 二年级下·四川南充·期末"
+    },
+    {
+        "id":  "493",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "妈妈买了30枝花，每5枝插一个花瓶，需要多少个花瓶。",
+        "options":  [
+
+                    ],
+        "answer":  "6个",
+        "solution":  "【分析】求需要几个花瓶，也就是求30里面有几个5，用除法计算，即花的总枝数÷每个花瓶插的枝数=需要花瓶的数量。`n【详解】30÷5=6(个)，答：需要6个花瓶。",
+        "knowledge_points":  [
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级上·广西贵港·期中"
+    },
+    {
+        "id":  "494",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "学校买了30个排球，每5个装一箱，可以装多少箱。\n答：可以装( )箱。",
+        "options":  [
+
+                    ],
+        "answer":  "6;6箱",
+        "solution":  "【分析】求可以装几箱，也就是求30里面有几个5，用除法计算，总数量÷每箱装的数量=可以装的箱数。`n【详解】30÷5=6(箱)，答：可以装6箱。",
+        "knowledge_points":  [
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "23-24 二年级上·重庆云阳·期末"
+    },
+    {
+        "id":  "495",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "一本68页的故事书，乐乐已经看了32页，剩下的他想6天看完，需平均每天看多少页。",
+        "options":  [
+
+                    ],
+        "answer":  "6页",
+        "solution":  "【分析】先用一本故事书的总页数减去已看的页数，求出差，就是剩下的页数，再除以6天，求出商，即可解决.\n【详解】68-32=36(页),36÷6=6(页),答：需平均每天看6页。",
+        "knowledge_points":  [
+                                 "两位数与两位数的不退位减法",
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级上·河南周口·期中"
+    },
+    {
+        "id":  "496",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "学校图书室把76本《科技博览》分给三年级52本后，剩下的平均分给二年级4个班，二年级平均每班分得多少本。",
+        "options":  [
+
+                    ],
+        "answer":  "6本",
+        "solution":  "【分析】根据题意可知：先求出剩余的数量，用原有的数量减去分给三年级的数量。然后再除以平均分给二年级的班数即可求出每个班分几本.\n【详解】76-52=24(本),24÷4=6(本),答：二年级平均每班分得6本。",
+        "knowledge_points":  [
+                                 "两位数与两位数的不退位减法",
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级上·河南新乡·期中"
+    },
+    {
+        "id":  "497",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "有12个桃子，平均分给2只小猴，每只小猴能分几个桃子。",
+        "options":  [
+
+                    ],
+        "answer":  "6个",
+        "solution":  "【分析】根据题目意思，总数12个桃子被平均分给了2只小猴，这2只小猴最后手里的桃子数量是一样多的，列出除法算式然后计算即可。`n【详解】12÷2=6(个)，答：每只小猴能分6个桃子。",
+        "knowledge_points":  [
+                                 "图文问题",
+                                 "整数平均分的意义及应用",
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "24-25二年级上·山东济宁·期中"
+    },
+    {
+        "id":  "498",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "先选择合适的条件（把序号填在横线上），再列式计算。`n①每个班有6人参加拍球比赛；②跳绳每组4人；③每条跑道上有2人参加比赛`n(1)选( )，有3条跑道，一共有多少人参加比赛？`n(2)二年级参加拍球比赛的有30人，二年级有几个班？",
+        "options":  [
+
+                    ],
+        "answer":  "③;6人;①;5个",
+        "solution":  "【分析】(1)本题知道跑道数量，求一共有多少人参加比赛，则需知道跑道上人数。据此选择，然后根据每条跑道的人数乘跑道数即可。(2)本题知道拍球人数，求二年级有几个班，则需知道每班参加拍球的人数，据此选择。然后用参加拍球的人数除以每班参加人数。`n【详解】(1)选③，2×3=6(人)，答：一共有6人参加比赛。(2)选①，30÷6=5(个)，答：二年级有5个班。",
+        "knowledge_points":  [
+                                 "\"提问题\"\"填条件\"问题",
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级上·河南郑州·期中"
+    },
+    {
+        "id":  "499",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "一个保温杯30元，妈妈带的都是5元的人民币，买保温杯需要付几张。",
+        "options":  [
+
+                    ],
+        "answer":  "6张",
+        "solution":  "【分析】根据整数除法的意义，用保温杯的钱数除以5元即可求出买保温杯需要付5元人民币的张数，据此解答即可.\n【详解】30÷5=6(张),答：买保温杯需要付6张。",
+        "knowledge_points":  [
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "23-24 二年级下·河南濮阳·期末"
+    },
+    {
+        "id":  "500",
+        "unit":  "第二单元 表内除法",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "体育课上，同学们分成6个小组玩篮球。老师拿来了30个篮球，分给每个小组同样多，每个小组分得几个。",
+        "options":  [
+
+                    ],
+        "answer":  "30÷6=5;5个",
+        "solution":  "【分析】根据除法的意义，用篮球的总数量除以小组数量即可求出平均每个小组分得篮球的数量，据此解答即可.\n【详解】30÷6=5(个),答：每个小组分得5个。",
+        "knowledge_points":  [
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "23-24二年级上·广西贵港·期中"
+    }
+]
diff --git "a/\344\272\214\345\271\264\347\272\247\351\242\230\351\233\206/\344\272\214\345\271\264\347\272\247\344\270\213/\344\272\214\345\271\264\347\272\247\344\270\213\347\254\254\344\272\224\345\215\225\345\205\203\346\267\267\345\220\210\350\277\220\347\256\227.json" "b/\344\272\214\345\271\264\347\272\247\351\242\230\351\233\206/\344\272\214\345\271\264\347\272\247\344\270\213/\344\272\214\345\271\264\347\272\247\344\270\213\347\254\254\344\272\224\345\215\225\345\205\203\346\267\267\345\220\210\350\277\220\347\256\227.json"
new file mode 100644
index 0000000000000000000000000000000000000000..d62359f817024ec03eee614497f258530f15bf71
--- /dev/null
+++ "b/\344\272\214\345\271\264\347\272\247\351\242\230\351\233\206/\344\272\214\345\271\264\347\272\247\344\270\213/\344\272\214\345\271\264\347\272\247\344\270\213\347\254\254\344\272\224\345\215\225\345\205\203\346\267\267\345\220\210\350\277\220\347\256\227.json"
@@ -0,0 +1,8806 @@
+[
+    {
+        "id":  "1",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "学校打算购买一批文具，有下面4个条件，选择( )可以求出\"买笔记本一共花了多少元\"。",
+        "options":  [
+                        "②③④",
+                        "①②④",
+                        "①③④",
+                        "①②③"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】根据题意可知，要想求出\"买笔记本一共花了多少元\"，需要知道笔记本的数量和一个笔记本多少元;已知一个笔记本的价格，需要知道笔记本的数量;因为题中没有给出笔记本的数量，但条件③④中可以求出笔记本的数量，即笔记本的数量=订书机的数量+5;最后用笔记本的数量×笔记本的价格即可求出买笔记本的花费;据此解答。\n\n【详解】学校打算购买一批文具，选择②③④可以求出\"买笔记本一共花了多少元\"。故答案为:A",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算",
+                                 "\"提问题\"\"填条件\"问题"
+                             ],
+        "source":  "25-26三年级上·陕西安康·阶段练习"
+    },
+    {
+        "id":  "2",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "算式42-3×6的第二步应计算( )。",
+        "options":  [
+                        "3×6",
+                        "42-3",
+                        "42-18"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】计算42-3×6时，先算乘法，再算减法，所以第二步应计算42减3×6的积。\n\n【详解】42-3×6=42-18=24，算式42-3×6的第二步应计算42-18。故答案为:C",
+        "knowledge_points":  [
+                                 "乘加",
+                                 "乘减混合运算"
+                             ],
+        "source":  "25-26 三年级上·河北邢台·阶段练习"
+    },
+    {
+        "id":  "3",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "240加上60除以6的商，和是( )。",
+        "options":  [
+                        "250",
+                        "60",
+                        "50"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】根据题意,240加上60除以6的商，先用除法计算出60除以6的商，再用240加上商，列式计算即可。\n\n【详解】根据分析可知:240+60÷6=240+10=250,240加上60除以6的商，和是250。故答案为:A",
+        "knowledge_points":  [
+                                 "除加",
+                                 "除减混合运算"
+                             ],
+        "source":  "24-25三年级上·河南郑州·期中"
+    },
+    {
+        "id":  "4",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "下面选项中，先算加法的是( )。",
+        "options":  [
+                        "3×2+50",
+                        "56+(156-69)",
+                        "45÷9+3",
+                        "40÷(2+6)"
+                    ],
+        "answer":  "D",
+        "solution":  "【分析】做题要记\"先乘除后加减，有括号先算括号里\"的规则。\n\n【详解】A。3×2+50：有乘法和加法，得先算乘法，不是加法;B。56+(156-69):括号里是减法，所以先算括号里的减法，不是加法;C。45÷9+3：有除法和加法，先算除法，不是加法;D。40÷(2+6):括号里是加法，按规则先算括号里的，所以这个先算加法。故答案为:D",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算"
+                             ],
+        "source":  "25-26 三年级上·新疆和田·阶段练习"
+    },
+    {
+        "id":  "5",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "下面哪道题可以用算式(38-2)÷9来解决( )。",
+        "options":  [
+                        "有38颗糖，拿来2颗后，再平均分给9个小朋友，每个小朋友分到多少颗。",
+                        "有38颗糖，拿走2颗后，又拿来9颗，现在共有多少颗。",
+                        "有38颗糖，拿走2颗后，再平均分给9个小朋友，每个小朋友分到多少颗。"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】逐一分析以下各题，能和题目中算式一致的，即是可以解决的问题;A。用38颗糖加上拿来的2颗，再除以9个小朋友，即是每个小朋友分到的颗数;B。用38颗糖减去拿走2颗后，加上又拿来的9颗，即是现在共有的颗数;C。用38颗糖减去拿走2颗后，再除以9个小朋友，即是每个小朋友分到的颗数;据此解答。\n\n【详解】由分析可得:A。(38+2)÷9，和题目算式不一致，不符合题意;B。38-2+9，和题目算式不一致，不符合题意;C。(38-2)÷9，和题目算式一致，符合题意。故答案为:C",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算",
+                                 "用7~9的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·四川南充·期末"
+    },
+    {
+        "id":  "6",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "下面几个算式中，先算减法的是( )。",
+        "options":  [
+                        "72+12-8",
+                        "4×(8-3)",
+                        "72-56÷8",
+                        "40-5×8"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】根据整数四则混合运算的运算法则:1。若算式中只包含加减法或乘除法，应从左至右依次计算。2。若算式中同时包含乘除法和加减法，应先计算乘除法，再计算加减法。3。若有括号，应先计算小括号内的运算，再计算小括号外的运算。\n\n【详解】A。72+12-8的运算顺序是先计算加法，再计算减法，不符合题意;B。4×(8-3)的运算顺序是先计算小括号内的减法，再计算乘法，符合题意;C。72-56÷8的运算顺序是先计算除法，再计算减法，不符合题意;D。40-5×8的运算顺序是先计算乘法，再计算减法，不符合题意。计算时先算减法的是4×(8-3)。故答案为:B",
+        "knowledge_points":  [
+                                 "有括号的运算顺序",
+                                 "无括号的运算顺序",
+                                 "带有小括号的混合运算"
+                             ],
+        "source":  "24-25 二年级下·福建龙岩·期末"
+    },
+    {
+        "id":  "7",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "森林王国要召开运动会啦，进行开幕式队列表演的队伍每排有9只小动物，原来有6排，后来又增加了3排，现在进行队列表演的一共有多少只小动物。列式正确的是( )。",
+        "options":  [
+                        "6×9+3",
+                        "(6+3)×9",
+                        "6×(9+3)"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】因为原本只有6排，后面又增加了3排，则目前有6+3=9(排)的小动物在队列表演，已知每排有9只小动物，要求现在进行队列表演的一共有多少只小动物，即求9个9的和是多少，可用乘法计算，据此解答即可。\n\n【详解】(6+3)×9=9×9=81(只),所以现在进行队列表演的一共有81只小动物。故答案为:B",
+        "knowledge_points":  [
+                                 "表内乘加",
+                                 "乘减",
+                                 "带有小括号的混合运算"
+                             ],
+        "source":  "24-25 二年级下·四川成都·期末"
+    },
+    {
+        "id":  "8",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "有58个西瓜，上午卖出20个，下午卖出18个，还剩几个西瓜。聪聪这样想：\"先求出一共卖出几个，再求还剩几个.\"他列的算式是( )。",
+        "options":  [
+                        "58-(20+18)",
+                        "58-20+18",
+                        "58-20-18"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】根据题意，先求一共卖出几个，则将上午卖出的数量和下午卖出的数量相加即可;再求还剩几个，则用总数量减去一共卖出的数量，就是还剩的数量，由此解答。\n\n【详解】A。58-(20+18):先算20+18，即上午和下午共卖出了多少个，再算减法，即总数量减去一共卖出的数量，就是还剩的数量，与聪聪想法相符;B。58-20+18：用总数量减去上午卖出的数量，求出卖出20个后还剩多少个，再算加法，即又增加了18个西瓜，与聪聪想法不符;C。58-20-18：用西瓜的总数量减去上午卖出的数量，再减去下午卖出的数量，求出还剩的数量，与聪聪想法不符;则他列的算式是58-(20+18)。故答案为:A",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算",
+                                 "100以内数的加减混合运算"
+                             ],
+        "source":  "24-25二年级下·云南文山·期末"
+    },
+    {
+        "id":  "9",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "文具店有73支铅笔，上午卖了26支，下午卖了24支，还剩多少支。列式错误的是( )。",
+        "options":  [
+                        "73-26-24",
+                        "73-(26+24)",
+                        "73-(26-24)"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】根据题意，铅笔的总数量-上午卖出的数量-下午卖出的数量=还剩的数量;或者先用加法计算出上午和下午一共卖出的数量，再用总数量减去共卖出的数量，就是还剩的数量，由此解答。\n\n【详解】A。是用总数量-上午卖出的数量-下午卖出的数量=还剩的数量，列式正确;B。先计算出上午和下午一共卖出的数量，再用总数量减去共卖出的数量，计算出还剩的数量，列式正确;C。先计算出上午比下午多卖出的数量，再用总数量减去多的这部分数量，不能计算出还剩的数量，列式错误。则列式错误的是73-(26-24)。故答案为:C",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算",
+                                 "100以内数的连减运算"
+                             ],
+        "source":  "24-25 二年级下·广东肇庆·期中"
+    },
+    {
+        "id":  "10",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "把18-15=3,3×9=27合并成一道综合算式是( )。",
+        "options":  [
+                        "18-15×9",
+                        "3×9-18",
+                        "(18-15)×9"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】混合运算的运算顺序：如果只有加减法或只有乘除法，按照从左到右的顺序计算;如果既有加减法又有乘除法，要先算乘除法，再算加减法;如果有括号，要先算括号里面的，再算括号外面的。第一个算式18-15=3的结果是3，是第二个算式3×9=27中的第一个乘数，所以将3用18-15替换，为保证先算减法，需要加上小括号，得到综合算式为:(18-15)×9=27。\n\n【详解】由分析可知：把18-15=3,3×9=27合并成一道综合算式是(18-15)×9=27。故答案为:C",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算"
+                             ],
+        "source":  "24-25二年级下·山东菏泽·期末"
+    },
+    {
+        "id":  "11",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "用\"(44-16)÷4\"能解决的问题是( )。",
+        "options":  [
+                        "男，女生共44人，其中女生16人，将男生平均分成4组，每组几人",
+                        "元元带了44元，用16元买了4本画册，每本画册多少元",
+                        "16元可以买4本画册，航航带了44元，买一本画册后还剩多少元"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】(44-16)÷4表示先用减法求出还剩的，再把还剩的平均分4份，求每份是多少，先算减法，再算除法;据此逐一分析各选项，找出正确答案即可。\n\n【详解】A。先用男，女生的总人数减去女生的人数，算出男生的人数，再用男生的人数除以平均分成的组数，即可求出每组几人，列式为:(44-16)÷4，先算减法，再算除法，符合题意;B。求每本画册多少元，用4本画册的钱数16元除以买画册的本数4，即可解答，列式为:16÷4，不符合题意;C。先求买一本画册的钱，用除法计算，再求还剩多少元，用航航带的总钱数减去买一本画册的钱即可解答，列式为:44-16÷4，先算除法，再算减法，不符合题意。故答案为:A",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算",
+                                 "除加",
+                                 "除减混合运算",
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "24-25二年级下·湖北武汉·期末"
+    },
+    {
+        "id":  "12",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "下列算式中，与75-30-15的计算结果相同的是( )。",
+        "options":  [
+                        "75-(30-15)",
+                        "75-(30+15)",
+                        "75-30+15"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】分别求出各算式的答案，然后进行比较，选择答案相同的即可。同级运算按照从左到右的顺序依次计算，有小括号的先算小括号中的，再算小括号外的。\n\n【详解】75-30-15=45-15=30;A。75-(30-15)=75-15=60，60大于30，则不符合题意;B。75-(30+15)=75-45=30，30=30，符合题意;C。75-30+15=45+15=60，60大于30，则不符合题意。故答案为:B",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算",
+                                 "100以内数的加减混合运算"
+                             ],
+        "source":  "24-25 二年级下·湖北武汉·期末"
+    },
+    {
+        "id":  "13",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "从42中连续减去7，减( )次才能得到7。",
+        "options":  [
+                        "5",
+                        "6",
+                        "7"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】从42中连续减去7，减几次能得到7，则减去的数是42-7=35，再求35里面有几个7即可解答。\n\n【详解】(42-7)÷7=35÷7=5(次),从42中连续减去7，减5次才能得到7。故答案为:A",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算"
+                             ],
+        "source":  "24-25 二年级下·湖北武汉·期末"
+    },
+    {
+        "id":  "14",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "水果店运来杨梅12篮，每篮3千克，还剩多少千克杨梅。如果列式为\"(12-5)×3\"，那么横线上应补充的信息是( )。",
+        "options":  [
+                        "又运来5千克杨梅",
+                        "卖出5千克杨梅",
+                        "卖出5篮杨梅",
+                        "又运来5篮杨梅"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】本题考查对应题中数量关系的理解，需要根据算式逐一分析各选项所补充的条件，找到符合题意的即可。\n\n【详解】已知运来杨梅12篮，每篮3千克，算式为(12-5)×3。其中12是原来的篮数,12-5表示剩下的篮数，再乘每篮的3千克，得到剩下杨梅的总重量。A。又运来5千克杨梅，这里的5是用来描述重量的数量，而算式中是12-5(篮数的运算),不符合题意;B。卖出5千克杨梅，这里的5是用来描述重量的数量，算式中是对篮数的运算，不符合题意;C。卖出5篮杨梅，原来有12篮，卖出5篮后，剩下12-5篮，再乘每篮3千克，得到剩下的重量，与算式(12-5)×3相符，符合题意;D。又运来5篮杨梅，那么篮数应该是12+5，而不是12-5，不符合题意。故答案为:C",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算",
+                                 "\"提问题\"\"填条件\"问题"
+                             ],
+        "source":  "24-25 二年级下·福建厦门·期末"
+    },
+    {
+        "id":  "15",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "班级图书角中的书的数量在30-40本之间，平均分给5个小组，还剩3本;平均分给7个小组，也剩3本，这些书一共有( )本。",
+        "options":  [
+                        "37",
+                        "38",
+                        "35"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】因为平均分给5个小组还剩3本，平均分给7个小组也剩3本，这就意味着，如果我们从这些书里先拿出3本，那么剩下的书的数量，正好能整整齐齐地分给5个小组，也能整整齐齐地分给7个小组(也就是剩下的书,5个小组分的话，每个小组得到的本数一样多;7个小组分的话，每个小组得到的本数也一样多)。那我们就先找能既让5个小组分着一样多，又让7个小组分着一样多的数。从乘法口诀里想，\"五七三十五\"，所以35本是能让5个小组和7个小组都分匀的数量。然后，再把之前拿出去的3本加回来，这些书一共有35+3=38(本)。\n\n【详解】5×7+3=35+3=38(本),这些书一共有38本。故答案为:B",
+        "knowledge_points":  [
+                                 "乘加",
+                                 "乘减混合运算"
+                             ],
+        "source":  "24-25 二年级下·浙江杭州·期末"
+    },
+    {
+        "id":  "16",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "公交车上原来有42人，第一站下车14人，第二站下车16人，现在车上还剩多少人。列式42-(14+16),划线部分表示的是( )。",
+        "options":  [
+                        "剩下的人数",
+                        "下车的人数",
+                        "下车14人后还剩下的人数"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】第一站下车14人，第二站下车16人，用(14+16)表示下车的人数;据此找出正确的答案即可。\n\n【详解】A.\"剩下的人数\"用算式42-(14+16)表示;B.\"下车的人数\"用算式14+16表示;C.\"下车14人后还剩下的人数\"用算式42-14表示;公交车上原来有42人，第一站下车14人，第二站下车16人，现在车上还剩多少人。列式42-(14+16),划线部分表示的是(下车的人数)。故答案为:B",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算"
+                             ],
+        "source":  "24-25 二年级下·浙江杭州·期末"
+    },
+    {
+        "id":  "17",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "下面算式中，先算乘法的是( )。",
+        "options":  [
+                        "24÷3×2",
+                        "(7+2)×3",
+                        "54-4×9"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】四则混合运算的运算法则:①在没有括号的算式里，如果只有加减法或者只有乘除法，要从左往右依次计算。②在没有括号的算式里，如果既有乘除法又有加减法，要先算乘除法，再算加减法。③在有括号的算式里，要先算括号里面的，再算括号外面的。逐项分析各个选项，找出先算乘法的选项即可。\n\n【详解】A。24÷3×2：从左往右的顺序计算，先算除法，再算乘法，此选项错误;B。(7+2)×3：要先算括号里面的加法，再算括号外面的乘法，此选项错误;C。54-4×9：先算乘法，再算减法，此选项正确。先算乘法的是54-4×9。故答案为:C",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算",
+                                 "乘加",
+                                 "乘减混合运算",
+                                 "表内乘除混合运算"
+                             ],
+        "source":  "24-25 二年级下·湖北黄冈·期末"
+    },
+    {
+        "id":  "18",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "二1班的5组同学，每人要为交警叔叔准备一张贺卡，每组有8人，还有多少张贺卡没做完。若列式为5×8-28，那么横线上填的条件是( )。",
+        "options":  [
+                        "二1班一共有28人。",
+                        "已经有28名同学制作完成。",
+                        "做好节日贺卡的，比没做好的多28张。"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】根据题意,5×8-28先算出总人数就是一共需要准备的贺卡数量,28表示已经做好的数量，最后算减法求的是还没有做的数量，据此解答。\n\n【详解】根据分析:5×8-28=40-28=12(张),先用乘法算出需要准备的数量，再用减法算出还需要准备的数量。二1班的5组同学，每人要为交警叔叔准备一张贺卡，每组有8人，还有多少张贺卡没做完。若列式为5×8-28，那么横线上填的条件是(已经有28名同学制作完成)。故答案为:B",
+        "knowledge_points":  [
+                                 "乘加",
+                                 "乘减混合运算",
+                                 "\"提问题\"\"填条件\"问题"
+                             ],
+        "source":  "24-25 二年级下·山东济宁·期中"
+    },
+    {
+        "id":  "19",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "下面三个算式中去掉括号后运算顺序不变的是( )。",
+        "options":  [
+                        "(45-13)÷8",
+                        "9×(36-27)",
+                        "(25+12)-23"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】只有加减法或只有乘除法的混合运算，从左往右计算。既有加减法又有乘除法的混合运算，先算乘除法，再算加减法。有小括号的混合运算，先算小括号里面的，再算小括号外面的。据此逐项分析括号去掉前后的运算顺序是否改变。\n\n【详解】A。(45-13)÷8先算括号内的减法，再算括号外的除法;去掉括号后,45-13÷8先算除法，再算减法。B。9×(36-27)先算括号内的减法，再算括号外的乘法;去掉括号后,9×36-27先算乘法，再算减法。C。(25+12)-23先算括号内的加法，再算括号外的减法;去掉括号后,25+12-23先算加法，再算减法。去掉括号后运算顺序不变的是(25+12)-23。故答案为:C",
+        "knowledge_points":  [
+                                 "无括号的运算顺序",
+                                 "带有小括号的混合运算"
+                             ],
+        "source":  "24-25 二年级下·湖北孝感·期末"
+    },
+    {
+        "id":  "20",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "中国是茶文化的发源地。一套茶具有1个茶壶和6个茶杯，每个茶杯6元，每个茶壶20元，一套茶具( )元。",
+        "options":  [
+
+                    ],
+        "answer":  "56",
+        "solution":  "【分析】根据题意，先用每个茶杯的钱数和茶杯的个数相乘，计算出6个茶杯的钱数，再和1个茶壶的钱数相加，即可计算出一套茶具的总钱数。6×6+20=36+20=56(元)，中国是茶文化的发源地。一套茶具有1个茶壶和6个茶杯，每个茶杯6元，每个茶壶20元，一套茶具56元。\n\n【详解】6个茶杯的钱数:6×6=36(元);再加上1个茶壶的钱数:36+20=56(元)。所以，一套茶具56元。",
+        "knowledge_points":  [
+                                 "6的乘法口诀及应用",
+                                 "表内乘加",
+                                 "乘减"
+                             ],
+        "source":  "25-26 二年级上·全国·单元测试"
+    },
+    {
+        "id":  "21",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "学校腰鼓队有17个男生和28个女生。每9个同学站成一排，可以站( )排。",
+        "options":  [
+
+                    ],
+        "answer":  "5",
+        "solution":  "【分析】先计算腰鼓队总人数，再用总人数除以每排的人数，即可求得可以站多少排。(17+28)÷9=45÷9=5(排)，所以可以站5排。\n\n【详解】腰鼓队一共有:17+28=45(个);每9个同学站成一排:45÷9=5(排)。所以，可以站5排。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算"
+                             ],
+        "source":  "24-25 三年级上·陕西宝鸡·期中"
+    },
+    {
+        "id":  "22",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在计算36-24÷3时先算( )法，再算( )法，最后的计算结果是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "除;减;28",
+        "solution":  "【分析】在没有括号的算式里，如果只有加减法或者只有乘除法，都要从左往右按顺序计算。在没有括号的算式里，既有乘除法，又有加减法的要先算乘除法，再算加减法，算式里有括号要先算括号里的，再算括号外的计算。36-24÷3=36-8=28，所以在计算36-24÷3时先算除法，再算减法，最后的计算结果是28。\n\n【详解】算式36-24÷3里，既有减法，又有除法。按照运算顺序，要先算除法:24÷3=8;再算减法:36-8=28。所以，先算除法，再算减法，最后结果是28。",
+        "knowledge_points":  [
+                                 "无括号的运算顺序",
+                                 "除加",
+                                 "除减混合运算"
+                             ],
+        "source":  "25-26三年级上·陕西汉中·阶段练习"
+    },
+    {
+        "id":  "23",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "计算50-8×3时，应该先算( )法，再算( )法，最后结果是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "乘;减;26",
+        "solution":  "【分析】在没有括号的算式里，如果只有加减法或者只有乘除法，都要从左往右按顺序计算。在没有括号的算式里，既有乘除法，又有加减法的要先算乘除法，再算加减法。50-8×3=50-24=26，计算50-8×3时，应该先算乘法，再算减法，最后结果是26。\n\n【详解】算式50-8×3里，既有减法，又有乘法。按照运算顺序，要先算乘法:8×3=24;再算减法:50-24=26。所以，先算乘法，再算减法，最后结果是26。",
+        "knowledge_points":  [
+                                 "乘加",
+                                 "乘减混合运算"
+                             ],
+        "source":  "24-25三年级上·陕西咸阳·期中"
+    },
+    {
+        "id":  "24",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "红红买下面的体育用品，一共花了16元，有( )种可能的购买方法。\n![](images/8d490fd8fc4ac4552db29d43a9d5787c.png)",
+        "options":  [
+
+                    ],
+        "answer":  "2",
+        "solution":  "【分析】根据题意，已知1个羽毛球6元，1个乒乓球4元，红红买下面的体育用品一共花了16元，尝试用不同的方法购买，如：买4个乒乓球;买2个羽毛球和1个乒乓球;以此答题即可。\n\n【详解】根据分析可知:4×4=16(元)，买4个乒乓球;6×2+4=12+4=16(元)，买2个羽毛球和1个乒乓球。红红买下面的体育用品一共花了16元，有2种可能的购买方法。",
+        "knowledge_points":  [
+                                 "乘加",
+                                 "乘减混合运算"
+                             ],
+        "source":  "24-25三年级上·陕西咸阳·期中"
+    },
+    {
+        "id":  "25",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "灯笼又称\"彩灯\"，是一种古老的传统工艺品。李师傅第一天做了26个灯笼，第二天做了19个灯笼，李师傅这两天做的灯笼够做( )个如图的灯笼串。\n![](images/de2967c7a67b8a46075ad5aa919f008304f84962dedd5bd84fd8e0c9bb04da54.jpg)",
+        "options":  [
+
+                    ],
+        "answer":  "9",
+        "solution":  "【分析】先用加法求出这两天一共做了几个灯笼，然后除以每个灯笼串需要的灯笼个数(5个)，求出商，就是可以做几个这样的灯笼串。\n\n【详解】(26+19)÷5=45÷5=9(个)，李师傅这两天做的灯笼够做9个如图的灯笼串。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算"
+                             ],
+        "source":  "24-25 二年级下·湖北省直辖县级单位·期末"
+    },
+    {
+        "id":  "26",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "王阿姨买了1束月季花和5束小雏菊，一共花了58元。一束月季花18元，求一束小雏菊多少元，列式是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "(58-18)÷5",
+        "solution":  "【分析】王阿姨买花总共花了58元，其中1束月季花18元。先算出小雏菊的总钱数:58元减去月季花的18元，剩下40元是5束小雏菊的钱。因为小雏菊数量相同，所以用总钱数除以束数，就能得到每束的价格。\n\n【详解】算小雏菊的总钱数:58-18=40(元);算每束小雏菊的钱:40÷5=8(元)。所以综合算式是:(58-18)÷5=8(元)，求一束小雏菊多少元，列式是(58-18)÷5。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算"
+                             ],
+        "source":  "25-26 三年级上·新疆和田·阶段练习"
+    },
+    {
+        "id":  "27",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "趣味运动会上，同学们分组进行游戏。每组成员由3名女生、5名男生组成，40名同学刚好全部分到各组。参与游戏的男生有( )名，女生有( )名。",
+        "options":  [
+
+                    ],
+        "answer":  "25;15",
+        "solution":  "【分析】每组有3名女生和5名男生，那么每组一共有3+5=8名同学。总共有40名同学，所以一共分的组数为40÷8=5组。每组有5名男生，一共有5组，所以男生人数为5×5=25名。每组有3名女生，一共有5组，所以女生人数为3×5=15名。\n\n【详解】40÷(3+5)=40÷8=5(组);5×5=25(名);3×5=15(名)。参与游戏的男生有25名，女生有15名。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算"
+                             ],
+        "source":  "24-25 六年级上·吉林白城·期中"
+    },
+    {
+        "id":  "28",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "把24÷6=4,24+4=28这两道算式合并成一道综合算式为( )。",
+        "options":  [
+
+                    ],
+        "answer":  "24+24÷6=28",
+        "solution":  "【分析】观察两个算式，把第二个算式中的4换成第一个算式24÷6;根据运算顺序，先算除法再算加法，因此不需要添加括号，直接合并即可。\n\n【详解】由分析可得：得到综合算式:24+24÷6=24+4=28，把24÷6=4,24+4=28这两道算式合并成一道综合算式为24+24÷6=28。",
+        "knowledge_points":  [
+                                 "除加",
+                                 "除减混合运算",
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·湖北恩施·期末"
+    },
+    {
+        "id":  "29",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "一本故事书52页，看了16页后，剩下的4天看完，平均每天看( )页，列综合算式是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "9;(52-16)÷4=9(页)",
+        "solution":  "【分析】用总的页数减去看了的页数，先算出还剩多少页没看，再根据除法的意义，用剩下的页数除以看的天数，即可得出平均每天看多少页。\n\n【详解】(52-16)÷4=36÷4=9(页)，所以平均每天看9页。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算"
+                             ],
+        "source":  "24-25 二年级下·福建龙岩·期末"
+    },
+    {
+        "id":  "30",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在计算65-5×9时，应先算( )法;计算54÷(43-34)时，应先算( )法，再算( )法。",
+        "options":  [
+
+                    ],
+        "answer":  "乘;减;除",
+        "solution":  "【分析】根据整数混合运算法则：同级运算，按照从左往右的顺序依次计算即可;不同级运算，先算乘除，再算加减;有小括号的运算，先算小括号内的算式，再算括号外的计算，据此解答即可。\n\n【详解】在计算65-5×9时，应先算(乘)法;计算54÷(43-34)时，应先算(减)法，再算(除)法。",
+        "knowledge_points":  [
+                                 "有括号的运算顺序",
+                                 "无括号的运算顺序"
+                             ],
+        "source":  "24-25 二年级下·山东菏泽·期末"
+    },
+    {
+        "id":  "31",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "把36-15=21,21÷7=3合并成一个综合算式是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "(36-15)÷7=3",
+        "solution":  "【分析】分析算式的关系，算式21÷7=3中的21是由算式36-15=21得来的，因此列综合算式时，把算式21÷7=3中的21换成(36-15)并加上小括号即可。\n\n【详解】由分析可知：把36-15=21,21÷7=3合并成一个综合算式是(36-15)÷7=3。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算"
+                             ],
+        "source":  "24-25 二年级下·贵州铜仁·期末"
+    },
+    {
+        "id":  "32",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "聪聪从1楼到2楼用了12秒，他家住在5楼，从1楼到他家需要( )秒。",
+        "options":  [
+
+                    ],
+        "answer":  "48",
+        "solution":  "【分析】从1楼到2楼一共走了2-1=1层楼梯，用了12秒，也就是走一层楼梯需要12秒，从1楼到5楼需要走5-1=4层楼梯，则从1楼到5楼需要的时间是4个12秒，然后用连加求出4个12是多少，即可解决。\n\n【详解】2-1=1(层)，由此可知，走一层楼梯需要12秒;5-1=4(层)，12+12+12+12=48(秒)。即聪聪从1楼到2楼用了12秒，他家住在5楼，从1楼到他家需要48秒。",
+        "knowledge_points":  [
+                                 "植树问题(两端都不栽)",
+                                 "100以内数的连加运算"
+                             ],
+        "source":  "24-25 二年级下·贵州铜仁·期末"
+    },
+    {
+        "id":  "33",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在计算48÷(93-85)时，应先算( )法，再算( )法，结果是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "减;除;6",
+        "solution":  "【分析】根据整数混合运算法则：同级运算，按照从左往右的顺序依次计算即可;不同级运算，先算乘除，再算加减;有小括号的运算，先算小括号内的算式，再算括号外的计算，据此解答即可。\n\n【详解】据分析可知：计算48÷(93-85)时，先算括号内的减法，再算除法。48÷(93-85)=48÷8=6，所以结果是6。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算",
+                                 "除加",
+                                 "除减混合运算"
+                             ],
+        "source":  "24-25 二年级下·贵州铜仁·期末"
+    },
+    {
+        "id":  "34",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "小明在计算\"8+□÷8\"时，弄错了运算顺序，先算加法后算除法了，结果得数是6，正确的得数应该是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "13",
+        "solution":  "【分析】将错就错，用6乘8求出8+□的和，再减8求出□是多少，再按正确运算顺序计算即可。\n\n【详解】6×8-8=48-8=40，所以□表示的数是40;8+40÷8=8+5=13，所以正确的得数应该是13。",
+        "knowledge_points":  [
+                                 "表内乘加",
+                                 "乘减",
+                                 "除加",
+                                 "除减混合运算"
+                             ],
+        "source":  "24-25二年级下·四川成都·期末"
+    },
+    {
+        "id":  "35",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "计算36÷(4+5)时，我们要先算( )法，再算( )法，如果去掉小括号后，计算结果( )(填\"变大\"\"变小\"或\"不变\")。",
+        "options":  [
+
+                    ],
+        "answer":  "加;除;变大",
+        "solution":  "【分析】根据四则混合运算顺序，有小括号时先算括号内的加法，再算括号外的除法;去掉小括号后，按从左到右的顺序计算，先算除法再算加法;据此计算出结果，再看变化情况。\n\n【详解】36÷(4+5)=36÷9=4，36÷4+5=9+5=14，原结果为4，去掉小括号后结果为14，故计算结果变大。因此，计算36÷(4+5)时，我们要先算加法，再算除法，如果去掉小括号后，计算结果变大。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算",
+                                 "除加",
+                                 "除减混合运算"
+                             ],
+        "source":  "24-25 二年级下·云南文山·期末"
+    },
+    {
+        "id":  "36",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "被除数是72，除数是2×4，列成综合算式是( )，商是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "72÷(2×4);9",
+        "solution":  "【分析】在除法算式中，被除数÷除数=商，题目中被除数是72，除数是\"2×4\"。根据运算顺序，小括号内的算式优先计算，需要把\"2×4\"加上小括号，才能保证优先计算。接着用被除数72除以这个结果，求出商。\n\n【详解】72÷(2×4)=72÷8=9，被除数是72，除数是2×4，列成综合算式是72÷(2×4)，商是9。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算"
+                             ],
+        "source":  "24-25二年级下·云南文山·期末"
+    },
+    {
+        "id":  "37",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "中国是茶的故乡，发于神农，兴于唐朝，盛于宋代，普及于明清之时。米米买了4盒花茶，每盒花茶装有9包，把这些花茶平均分给6个人，每人分( )包。",
+        "options":  [
+
+                    ],
+        "answer":  "6",
+        "solution":  "【分析】首先根据每盒茶叶的包数×盒数=茶叶的总包数，求出这些茶叶的总包数;再根据除法的意义，用茶叶的总包数除以人数，即可求解。\n\n【详解】4×9÷6=36÷6=6(包)，米米买了4盒花茶，每盒花茶装有9包，把这些花茶平均分给6个人，每人分6包。",
+        "knowledge_points":  [
+                                 "表内乘除混合运算"
+                             ],
+        "source":  "24-25 二年级下·湖北省直辖县级单位·期末"
+    },
+    {
+        "id":  "38",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "小马虎在算35-□÷5时，先算减法，后算除法，最后的结果是5，正确的结果应该是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "33",
+        "solution":  "【分析】在没有括号的算式里，如果既有乘，除法，又有加，减法，要先算乘，除法，再算加，减法，正确的运算顺序为先算除法，再算减法。小马虎先算减法，后算除法，则用得到的结果先和5相乘，求出35-□的结果，再用35减去这个结果得到□代表的数，再根据正确的运算顺序计算即可。\n\n【详解】由分析得:5×5=25;35-25=10，即□=10;35-10÷5=35-2=33，小马虎在算35-□÷5时，先算减法，后算除法，最后的结果是5，正确的结果应该是33。",
+        "knowledge_points":  [
+                                 "除加",
+                                 "除减混合运算"
+                             ],
+        "source":  "24-25 二年级下·湖北恩施·期末"
+    },
+    {
+        "id":  "39",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "在计算18-6÷3时，应先算( )法，再算( )法。",
+        "options":  [
+
+                    ],
+        "answer":  "除;减",
+        "solution":  "【分析】根据四则运算顺序，加减法属于一级运算，乘除法属于二级运算;加减乘除混合运算，先算乘除，后算加减。据此解答即可。\n\n【详解】减法和除法混合，先算除法，再算减法。因此在计算18-6÷3时，应先算除法，再算减法。",
+        "knowledge_points":  [
+                                 "除加",
+                                 "除减混合运算"
+                             ],
+        "source":  "25-26 三年级上·黑龙江佳木斯·开学考试"
+    },
+    {
+        "id":  "40",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "计算40+25-5，应先算( )法，再算( )法，结果是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "加;减;60",
+        "solution":  "【分析】在没有括号的算式里，只有加、减法或只有乘、除法，要从左往右计算，由此解答。\n\n【详解】40+25-5=65-5=60，计算40+25-5，应先算加法，再算减法，结果是60。",
+        "knowledge_points":  [
+                                 "无括号的运算顺序",
+                                 "100以内数的加减混合运算"
+                             ],
+        "source":  "24-25二年级下·广东肇庆·期中"
+    },
+    {
+        "id":  "41",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "小马虎在计算\"2+□×5\"时弄错了运算顺序，先算加法再算乘法了，得数是30，正确的得数应该是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "22",
+        "solution":  "【分析】用先计算出的得数30除以5，再减去2求出方框里的数是几，再根据运算顺序，先计算乘法再计算加法。\n\n【详解】30÷5-2=6-2=4，2+4×5=2+20=22，即正确的得数应该是22。",
+        "knowledge_points":  [
+                                 "表内乘加",
+                                 "乘减",
+                                 "除加",
+                                 "除减混合运算"
+                             ],
+        "source":  "24-25 二年级下·福建厦门·期末"
+    },
+    {
+        "id":  "42",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "把3+2=5,40÷5=8，写成综合算式是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "40÷(3+2)=8",
+        "solution":  "【分析】根据题意可知，先算的是3+2=5，后算的是除法，列综合算式时,3+2要小括号且作除数,40作被除数，商是8。由此可写成40÷(3+2)=8。\n\n【详解】由题意分析得：把3+2=5,40÷5=8，写成综合算式是40÷(3+2)=8。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算"
+                             ],
+        "source":  "24-25 二年级下·浙江杭州·期末"
+    },
+    {
+        "id":  "43",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "小马虎在计算25+( )÷5时，先算的加法，后算的除法，最后结果是8。请你帮助小马虎算出正确的结果是( ),以及算式中括号内的数字是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "28;15",
+        "solution":  "【分析】根据题意可知:25+( )÷5时，先算的加法，后算的除法，最后结果是8。即25+()÷5=8，然后根据被除数=商×除数可求出25+()的和，然后根据和-加数=另一个加数，即可求出()内的数。然后根据正确的运算方法计算出正确的结果。有加减又有乘除的先计算乘除再计算加减。\n\n【详解】由分析可得:25+( )÷5=8，则25+( )=8×5=40，则()=40-25=15，即正确的算式为:25+15÷5,25+15÷5=25+3=28，则小马虎在计算25+( )÷5时，先算的加法，后算的除法，最后结果是8。请你帮助小马虎算出正确的结果是(28),以及算式中括号内的数字是(15)。",
+        "knowledge_points":  [
+                                 "除加",
+                                 "除减混合运算",
+                                 "8的乘法口诀及应用",
+                                 "两位数与两位数的退位减法"
+                             ],
+        "source":  "24-25 二年级下·云南昭通·期中"
+    },
+    {
+        "id":  "44",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "在计算28+45÷9时，应先算( )法，再算( )法。",
+        "options":  [
+
+                    ],
+        "answer":  "除;加",
+        "solution":  "【分析】在没有括号的混合算式中，先算乘除再算加减，据此得出结论即可。\n\n【详解】根据分析知：在计算28+45÷9时，应先算除法，再算加法。",
+        "knowledge_points":  [
+                                 "除加",
+                                 "除减混合运算"
+                             ],
+        "source":  "24-25 二年级下·云南昭通·期中"
+    },
+    {
+        "id":  "45",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "把8×6=48,73-48=25这两个算式改写成一个算式应该是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "73-8×6=25",
+        "solution":  "【分析】在有乘法和减法的混合算式中，先算乘法，再算减法。在算式8×6=48，73-48=25中，关联数字是48，也就是73减去8乘6的积，据此得出结论即可。\n\n【详解】73-8×6=73-48=25，把8×6=48，73-48=25这两个算式改写成一个算式应该是73-8×6=25。",
+        "knowledge_points":  [
+                                 "乘加",
+                                 "乘减混合运算"
+                             ],
+        "source":  "24-25 二年级下·云南昭通·期中"
+    },
+    {
+        "id":  "46",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "将55-48=7,7×8=( ),合并成一个综合算式( )。",
+        "options":  [
+
+                    ],
+        "answer":  "56;(55-48)×8=56",
+        "solution":  "【分析】根据题意，先计算出55减48的结果，再用这个结果和8相乘，最后的结果是两个数的积，综合算式中有减法和乘法，先算减法，再算乘法，用55-48代替7写在前面，要加小括号。\n\n【详解】7×8=56，(55-48)×8=7×8=56。将55-48=7，7×8=56，合并成一个综合算式是(55-48)×8=56。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算"
+                             ],
+        "source":  "24-25 二年级下·湖南张家界·期末"
+    },
+    {
+        "id":  "47",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "把算式42-36=6,54÷6=9合并成一个综合算式是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "54÷(42-36)=9",
+        "solution":  "【分析】根据题意，先计算出42减36的差，再用54除以这个差，最终的结果是两个数的商，综合算式中有减法和除法，先算减法，再算除法，用42-36代替6，要加小括号。\n\n【详解】由分析得:54÷(42-36)=54÷6=9，把算式42-36=6,54÷6=9合并成一个综合算式是54÷(42-36)=9。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算"
+                             ],
+        "source":  "24-25 二年级下·湖北黄冈·期末"
+    },
+    {
+        "id":  "48",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "判断题",
+        "difficulty":  0.65,
+        "question":  "小优看一本童话书，前5天一共看了25页，又用3天看了47页。这8天平均每天看多少页书。列式为:(25+47)÷8。( )",
+        "options":  [
+
+                    ],
+        "answer":  "√",
+        "solution":  "【分析】根据题意可知，将前5天和后3天看的页数加起来，计算出这8天看的总页数，再除以8计算出平均每天看多少页;据此解答。\n\n【详解】(25+47)÷8=72÷8=9(页)，所以小优看一本童话书，前5天一共看了25页，又用3天看了47页。这8天平均每天看多少页书，列式为:(25+47)÷8。故答案为:√",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算"
+                             ],
+        "source":  "25-26 三年级上·陕西安康·阶段练习"
+    },
+    {
+        "id":  "49",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "将14÷2=7,7+22=29这两个分步算式列成综合算式是14÷2+22=29。( )",
+        "options":  [
+
+                    ],
+        "answer":  "√",
+        "solution":  "【分析】将分步算式合并为综合算式时，需将第二个算式中的第一个数替换为对应的运算。此处第二个算式中的7由14÷2得到，直接代入即可。\n\n【详解】根据分步算式14÷2=7和7+22=29，第二个算式中的7是第一个算式的结果。将14÷2代入第二个算式中的7，得到综合算式14÷2+22。根据运算顺序，除法优先于加法，因此无需添加括号，计算结果为7+22=29。故综合算式14÷2+22=29正确。故答案为:√",
+        "knowledge_points":  [
+                                 "除加",
+                                 "除减混合运算"
+                             ],
+        "source":  "25-26 三年级上·陕西延安·阶段练习"
+    },
+    {
+        "id":  "50",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "把算式36-28=8和8×7=56写成综合算式是36-28×7。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】把算式36-28=8和8×7=56写成综合算式时，第2个算式中的8要换成36-28，计算时要先算减法，再算乘法，所以要加上小括号，即(36-28)×7，据此判断原题说法错误。\n\n【详解】把算式36-28=8和8×7=56写成综合算式是36-28×7，原题说法错误，正确的算式是:(36-28)×7。故答案为: ×",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算"
+                             ],
+        "source":  "24-25 二年级下·山东菏泽·期末"
+    },
+    {
+        "id":  "51",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "65-27-18与65-(27+28)的运算顺序不同，结果相同。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】在没有括号的算式里，只有加、减法或只有乘、除法，要从左往右计算;有括号的算式里，要先算括号里面的，再算括号外面的。由此计算出结果解答即可。\n\n【详解】65-27-18：从左往右计算，65-27-18=38-18=20;65-(27+28)：先算加法，再算减法，65-(27+28)=65-55=10。则65-27-18与65-(27+28)的运算顺序不同，结果也不同，原题说法错误。故答案为:×",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算",
+                                 "100以内数的连减运算"
+                             ],
+        "source":  "24-25 二年级下·山东菏泽·期末"
+    },
+    {
+        "id":  "52",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "判断题",
+        "difficulty":  0.65,
+        "question":  "72÷(39-30)的算式中，要先算除法。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】在有小括号的混合运算中，先算小括号里面的，再算小括号外的，也就是在72÷(39-30)的算式中，要先算减法，据此得出结论即可。\n\n【详解】72÷(39-30)的算式中，要先算小括号里面的减法。故答案为:×",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算"
+                             ],
+        "source":  "24-25 二年级下·云南昭通·期中"
+    },
+    {
+        "id":  "53",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "一盒药共有12片，每天吃3次，每次吃2片，这盒药可以吃2天。( )",
+        "options":  [
+
+                    ],
+        "answer":  "√",
+        "solution":  "【分析】根据题意，先用每天吃的次数和每次吃的片数相乘，求出每天吃的片数，再用总数量除以每天吃的片数，即可求出可以吃的天数。\n\n【详解】12÷(3×2)=12÷6=2(天)，这盒药可以吃2天。原题说法正确。故答案为:√",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算"
+                             ],
+        "source":  "24-25 二年级下·河南南阳·期中"
+    },
+    {
+        "id":  "54",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "72减去32的差除以8，得数是5。( )",
+        "options":  [
+
+                    ],
+        "answer":  "√",
+        "solution":  "【分析】根据题意，先用减法计算出72减去32的差，再用这个差除以8，最终的结果是两个数的商，先算减法，再算除法，列综合算式时减法要加小括号，由此计算即可解答。\n\n【详解】(72-32)÷8=40÷8=5，72减去32的差除以8，得数是5。原题说法正确。故答案为:√",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算"
+                             ],
+        "source":  "24-25 二年级下·广西玉林·期中"
+    },
+    {
+        "id":  "55",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "计算4×(8-3)时，应先算减法。( )",
+        "options":  [
+
+                    ],
+        "answer":  "√",
+        "solution":  "【分析】根据四则运算的规则，算式中有括号时，应先计算括号内的运算，再计算括号外的运算。因此，在计算4×(8-3)时，应先算括号内的减法，再算乘法。据此可判断。\n\n【详解】由分析可得：计算4×(8-3)时，应先算减法。故答案为:√",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算"
+                             ],
+        "source":  "24-25二年级下·山东济宁·期中"
+    },
+    {
+        "id":  "56",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "算式8×6÷6和8×(6÷6)的运算顺序不同，计算结果也不同。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】在没有括号的算式里，如果只有加减法或者只有乘除法，要从左往右依次计算。在没有括号的算式里，如果既有乘除法又有加减法，要先算乘除法，再算加减法。在有括号的算式里，要先算括号里面的，再算括号外面的。第一个算式按从左到右的顺序计算;第二个算式先算括号内的除法，再算乘法。需分别计算两个算式的结果，判断是否相同;据此解答。\n\n【详解】由分析可得:8×6÷6=48÷6=8,8×(6÷6)=8×1=8，算式8×6÷6和8×(6÷6)的运算顺序不同，计算结果相同。故答案为: ×",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算",
+                                 "表内乘除混合运算"
+                             ],
+        "source":  "24-25 二年级下·甘肃天水·期中"
+    },
+    {
+        "id":  "57",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "判断题",
+        "difficulty":  0.65,
+        "question":  "计算(77-42)÷7时，要先算42÷7。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】根据四则运算的规则，含有括号的算式应先计算括号内的，再计算括号外的。题目中(77-42)÷7的运算顺序应为先算括号内的减法，再算除法。\n\n【详解】在计算(77-42)÷7时，先算括号内的减法:77-42=35，再算除法:35÷7=5。原题说法错误。故答案为:×",
+        "knowledge_points":  [
+                                 "有括号的运算顺序",
+                                 "带有小括号的混合运算"
+                             ],
+        "source":  "24-25 二年级下·广西柳州·期中"
+    },
+    {
+        "id":  "58",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "63-12-15=63-(12+15)。( )",
+        "options":  [
+
+                    ],
+        "answer":  "√",
+        "solution":  "【分析】先计算出等号两边算式的结果，然后比较结果，即可判断对错。63-12-15按照从左往右的顺序计算;63-(12+15)按照先算小括号里面的，再算小括号外面的顺序计算。\n\n【详解】63-12-15=51-15=36，63-(12+15)=63-27=36，两边结果相等，即63-12-15=63-(12+15)。故答案为:√",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算",
+                                 "100以内数的连减运算"
+                             ],
+        "source":  "24-25二年级下·河北邯郸·期中"
+    },
+    {
+        "id":  "59",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "12÷3÷2和12÷(3×2)相比，运算顺序不同，结果一样。( )",
+        "options":  [
+
+                    ],
+        "answer":  "√",
+        "solution":  "【分析】在没有括号的算式里，只有加、减法或只有乘、除法，要从左往右计算;有括号的算式里，要先算括号里面的，再算括号外面的。由此解答。\n\n【详解】12÷3÷2=4÷2=2，12÷(3×2)=12÷6=2。12÷3÷2从左往右计算;12÷(3×2)先算乘法，再算除法，两个算式运算顺序不同，结果一样，原题说法正确。故答案为:√",
+        "knowledge_points":  [
+                                 "表内连乘",
+                                 "连除运算",
+                                 "带有小括号的混合运算",
+                                 "无括号的运算顺序",
+                                 "有括号的运算顺序"
+                             ],
+        "source":  "24-25二年级下·河南南阳·期中"
+    },
+    {
+        "id":  "60",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "计算题",
+        "difficulty":  0.85,
+        "question":  "直接写出得数。\n12+40÷8= 54÷9= 30-4×5= 48÷(9-3)=\n16+16÷2= 6×7-21= (21-15)×4= (22+42)÷8=",
+        "options":  [
+
+                    ],
+        "answer":  "17;6;10;8;24;21;24;8",
+        "solution":  "【分析】本题考查：混合运算顺序 乘除法口诀应用 含括号算式的计算 计算顺序要点：先算小括号里面的，再算乘除法3。最后算加减法\n\n【详解】12+40÷8，先算除法:40÷8=5，再算加法:12+5=17,54÷9=6,30-4×5，先算乘法:4×5=20，再算减法:30-20=10,48÷(9-3),先算括号:9-3=6，再算除法:48÷6=8,16+16÷2，先算除法:16÷2=8，再算加法:16+8=24,6×7-21，先算乘法:6×7=42，再算减法:42-21=21,(21-15)×4，先算括号:21-15=6，再算乘法:6×4=24,(22+42)÷8，先算括号:22+42=64，再算除法:64÷8=8",
+        "knowledge_points":  [
+                                 "用7~9的乘法口诀求商",
+                                 "乘加",
+                                 "乘减混合运算",
+                                 "除加",
+                                 "除减混合运算",
+                                 "带有小括号的混合运算"
+                             ],
+        "source":  "25-26 三年级上·陕西汉中·阶段练习"
+    },
+    {
+        "id":  "61",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "计算题",
+        "difficulty":  0.85,
+        "question":  "看图列式并计算。\n![](images/1024264a33fe0132415139ecacd0ec5a17798a28f2d2c62e7c5bcc595e09c0c4.jpg)",
+        "options":  [
+
+                    ],
+        "answer":  "3元",
+        "solution":  "【分析】由题意可知：笔记本4本共32元，那么每本的价钱=32÷4，而毛笔每支11元，求每支毛笔比每本笔记本多多少元，用每支毛笔的价钱减去每本笔记本的价钱即可，列式为11-32÷4。\n\n【详解】先求每本笔记本多少元:32÷4=8(元);再求每支毛笔比每本笔记本贵多少元:11-8=3(元)。列成综合算式是:11-32÷4=11-8=3(元)。答：每支毛笔比每本笔记本贵3元。",
+        "knowledge_points":  [
+                                 "除加",
+                                 "除减混合运算",
+                                 "图文问题"
+                             ],
+        "source":  "25-26三年级上·陕西延安·阶段练习"
+    },
+    {
+        "id":  "62",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "计算题",
+        "difficulty":  0.65,
+        "question":  "看图列式计算。\n![](images/c3f77d8110d1be422e745b19d7af1fdf1cf6075c83c58fa6b2868d677fe7bb64.jpg)",
+        "options":  [
+
+                    ],
+        "answer":  "38-3×5=23(元)",
+        "solution":  "【分析】图下面写着\"38元\"，表示所有东西加起来一共38元。上面有3个茶杯，每个标着\"5元\"，还有一个茶壶的价钱未知。我们要先算出3个茶杯一共多少钱，再用总钱数减去茶杯的钱，剩下的就是茶壶的钱了。\n\n【详解】38-3×5=38-15=23(元)。",
+        "knowledge_points":  [
+                                 "乘加",
+                                 "乘减混合运算",
+                                 "图文问题"
+                             ],
+        "source":  "25-26三年级上·新疆和田·阶段练习"
+    },
+    {
+        "id":  "63",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "计算题",
+        "difficulty":  0.85,
+        "question":  "看图列式计算。\n![](images/7dd97062005db99c58a6e828175df43b7f536f3590ad6a4bd77f4741492bd534.jpg)",
+        "options":  [
+
+                    ],
+        "answer":  "8×3+25=49(元)",
+        "solution":  "【分析】根据题图可知，每个杯子的钱数乘杯子的个数，等于这些杯子的总钱数，再加上一个茶壶的钱数，等于共需要的钱数。\n\n【详解】8×3+25=24+25=49(元)，因此，一共需要49元。",
+        "knowledge_points":  [
+                                 "乘加",
+                                 "乘减混合运算",
+                                 "图文问题"
+                             ],
+        "source":  "24-25二年级下·云南文山·期末"
+    },
+    {
+        "id":  "64",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "计算题",
+        "difficulty":  0.85,
+        "question":  "看图列式计算。\n![](images/db5d6ec5ff64c230fbfc0d9b13e1b07aae400c145f0def22d745911d8a4dccff.jpg)\n列式:()",
+        "options":  [
+
+                    ],
+        "answer":  "(74-20)÷6=9(元)",
+        "solution":  "【分析】从图上可得：用74-20先算出买6个粽子需要多少钱，再根据除法的意义，用6个粽子的总价钱除以6，即可得出每个粽子多少钱。\n\n【详解】(74-20)÷6=54÷6=9(元)，所以每个粽子9元。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算",
+                                 "除加",
+                                 "除减混合运算",
+                                 "图文问题"
+                             ],
+        "source":  "24-25 二年级下·福建龙岩·期末"
+    },
+    {
+        "id":  "65",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "计算题",
+        "difficulty":  0.85,
+        "question":  "看图列式计算.\n![](images/575b525b86e729c86db6bb6e26a55b494540d9d66947cbf22afa127f0907b5a6.jpg)",
+        "options":  [
+
+                    ],
+        "answer":  "62+7×5=97(元)",
+        "solution":  "【分析】从图上可得：一个羽毛球7元，根据乘法的意义，用7×5先算出买5个羽毛球需要多少钱，再加上一个足球的价钱，即可得出买1个足球和5个羽毛球一共需要多少钱。\n\n【详解】62+7×5=62+35=97(元)，所以买1个足球和5个羽毛球一共需要97元钱。",
+        "knowledge_points":  [
+                                 "乘加",
+                                 "乘减混合运算",
+                                 "图文问题"
+                             ],
+        "source":  "24-25 二年级下·贵州铜仁·期末"
+    },
+    {
+        "id":  "66",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "计算题",
+        "difficulty":  0.65,
+        "question":  "脱式计算.\n54-24÷690-(36-18) (25+15)÷5",
+        "options":  [
+
+                    ],
+        "answer":  "50;72;8",
+        "solution":  "【分析】在没有括号的算式里，只有加，减法或只有乘，除法，要从左往右计算;在没有括号的算式里，如果既有乘，除法，又有加，减法，要先算乘，除法，再算加，减法;有括号的算式里，要先算括号里面的，再算括号外面的。第1题：先算除法，再算减法;第2题：先算括号里的减法，再算括号外的减法;第3题：先算加法，再算除法。\n\n【详解】54-24÷6=54-4=50;90-(36-18)=90-18=72;(25+15)÷5=40÷5=8。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算",
+                                 "除加",
+                                 "除减混合运算"
+                             ],
+        "source":  "24-25二年级下·湖北黄冈·期末"
+    },
+    {
+        "id":  "67",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "计算题",
+        "difficulty":  0.85,
+        "question":  "看图列式计算.\n![](images/2e81b4060eb6f6024407204fa66ab0e54f2ee71ae5307b993a375f14dc8057df.jpg)",
+        "options":  [
+
+                    ],
+        "answer":  "(36-27)÷3=3(盘)",
+        "solution":  "【分析】先用○的总个数减去吃掉的个数，求出剩下的个数，再用剩下的个数除以每盘放的个数，即可求出剩下的可以放几盘。注意：因为要先算出剩下的个数，因此减法算式要用括号括起来。\n\n【详解】(36-27)÷3=9÷3=3(盘)，剩下的可以放3盘。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算",
+                                 "图文问题"
+                             ],
+        "source":  "24-25二年级下·山东菏泽·期中"
+    },
+    {
+        "id":  "68",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "计算题",
+        "difficulty":  0.85,
+        "question":  "看图列式计算.\n![](images/e9e464fd6cb095b9f82ffb46957413977fe70609c652b9f011570284c59b9cb3.jpg)",
+        "options":  [
+
+                    ],
+        "answer":  "2×4+16=24(元)",
+        "solution":  "【分析】一共需要的钱数=每瓶的价钱(2元)×瓶数(4瓶)+一箱的钱数(16元);据此列式解决。\n\n【详解】2×4+16=8+16=24(元)，一共需要24元。",
+        "knowledge_points":  [
+                                 "图文问题",
+                                 "表内乘加",
+                                 "乘减"
+                             ],
+        "source":  "24-25二年级下·山东菏泽·期中"
+    },
+    {
+        "id":  "69",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "计算题",
+        "difficulty":  0.65,
+        "question":  "看图列式我能行。\n![](images/48defa6f0b71363dc5b357a74ef9d7714bdeaf93d014833dd36f0be12464eea3.jpg)\n![](images/8818cd75c11251ad844f5cd9abe02bda6ccb77b921146570230d3037449da6bf.jpg)",
+        "options":  [
+
+                    ],
+        "answer":  "3×3+15=24(元)",
+        "solution":  "【分析】根据图片可知：求一共需要的钱数，先求出3个毽子需要的钱数，用毽子的价格乘数量即可，然后再加上左边杯子的价格即可求出一共需要的钱数。\n\n【详解】3×3+15=9+15=24(元)，则一共需要24元。",
+        "knowledge_points":  [
+                                 "表内乘加",
+                                 "乘减"
+                             ],
+        "source":  "24-25 二年级下·山东日照·期中"
+    },
+    {
+        "id":  "70",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "下面两辆载质量分别为6吨和4吨的货车可以用来运煤。如果每次运煤的车都能装满，那么怎样安排能恰好运完28吨煤。\n![](images/3c07fc3d6fc368dd58cbd8db045cc171be68e4c28ce127ad469d00ef266ba0c7.jpg)\n大货车：载质量6吨\n![](images/acc6765e41c1b6d690dfa1fb09e96f105834312157087826b37492f1978af5ec.jpg)\n小货车：载质量4吨",
+        "options":  [
+
+                    ],
+        "answer":  "可以安排6吨车跑4次，再安排4吨车跑1次;也可以安排6吨车跑2次，再安排4吨车跑4次。",
+        "solution":  "【分析】根据题意，因为每次都要装满，故需找6吨车与4吨车装载次数的整数组合，使总吨数为28。设计费不同的方案，如：将6吨车使用4次可运24吨，剩余4吨让4吨车运1次即可。该方案正好运完28吨煤，且每次都满载。也可用其他组合(如6吨车2次,4吨车4次)得到同样结果。以此答题即可。\n\n【详解】根据分析可知：可以安排6吨车跑4次，再安排4吨车跑1次。6×4+4=24+4=28(吨),可以安排6吨车跑2次，再安排4吨车跑4次。6×2+4×4=12+16=28(吨),答：可以安排6吨车跑4次，再安排4吨车跑1次，能恰好运完28吨煤。也可以安排6吨车跑2次，再安排4吨车跑4次，能恰好运完28吨煤。",
+        "knowledge_points":  [
+                                 "乘加，乘减混合运算"
+                             ],
+        "source":  "24-25 三年级上·广西柳州·期中"
+    },
+    {
+        "id":  "71",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "一批水泥用小车装载，要用5辆;用大车装载，只要4辆。已知每辆大车比每辆小车多装2吨，这批水泥共有多少吨。",
+        "options":  [
+
+                    ],
+        "answer":  "40吨",
+        "solution":  "【分析】根据题意，总水泥量不变。每辆大车比每辆小车多装2吨，4辆大车比4辆小车多装的总量为4×2=8(吨)。这8吨相当于少用1辆小车所减少的装载量，因此每辆小车装8吨，总吨数为5×8=40(吨)。\n\n【详解】(4×2)÷(5-4)=8÷1=8(吨)，一辆小车装8吨。5×8=40(吨)。答：这批水泥共有40吨。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算"
+                             ],
+        "source":  "24-25 三年级上·浙江宁波·期中"
+    },
+    {
+        "id":  "72",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "实验小学艺术节收集90幅绘画作品，36幅未获奖，每块展板可以展9幅获奖作品，需要几块展板。",
+        "options":  [
+
+                    ],
+        "answer":  "6块",
+        "solution":  "【分析】根据题意，用收集绘画作品幅数减去未获奖作品幅数，求出获奖作品的幅数，再用获奖作品的幅数除以每块展板可以展获奖作品的幅数，即可求出需要几块展板。\n\n【详解】(90-36)÷9=54÷9=6(块)。答：需要6块展板。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算"
+                             ],
+        "source":  "25-26 三年级上·海南省直辖县级单位·期中"
+    },
+    {
+        "id":  "73",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "在\"积分换礼物\"活动中，小明看中了一个铅笔盒。他刚好有5分和2分面值的积分卡各8张，有几种刚好换一个铅笔盒的方式。\n35积分可以兑换一个铅笔盒哟!\n![](images/0f6a7008e5fd28dc635560690cff6936985242a438cd560d2481206c78158ffd.jpg)",
+        "options":  [
+
+                    ],
+        "answer":  "2种",
+        "solution":  "【分析】根据题意，用5分和2分的面值分别乘它们的张数，算出5分和2分各有多少分。再相加。算出的积分刚好是35分即可。然后再看有几种换法。\n\n【详解】\n![](images/d307d9433d24fe69c9485848bb51d915774b197b4da15c1f8459de6a99859931.jpg)\n答：有2种兑换方式，第一种是7张面值5分的积分卡。第二种是5张面值5分的和5张面值2分的积分卡。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算",
+                                 "图文问题"
+                             ],
+        "source":  "24-25三年级上·湖北荆州·期中"
+    },
+    {
+        "id":  "74",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "二(1)班有8个小组，每个小组有9位小朋友，中午学校为每位小朋友订购一盒纯牛奶，已经订了48盒，还差多少盒纯牛奶。",
+        "options":  [
+
+                    ],
+        "answer":  "24盒",
+        "solution":  "【分析】根据\"每个小组的小朋友数量×小组数量\"求出总人数，每位小朋友订购一盒纯牛奶，即为总共需要订购的数量;再减去已经订了的牛奶数量，求出还差的纯牛奶盒数;据此列式解决。\n\n【详解】9×8=72(盒)，72-48=24(盒)。答：还差24盒纯牛奶。",
+        "knowledge_points":  [
+                                 "表内乘除法解决实际问题"
+                             ],
+        "source":  "24-25二年级下·贵州铜仁·期末"
+    },
+    {
+        "id":  "75",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "今年明明8岁，他爸爸44岁，再过5年，明明和爸爸一共有多少岁。",
+        "options":  [
+
+                    ],
+        "answer":  "62岁",
+        "solution":  "【分析】已知今年明明8岁，他爸爸44岁，再过5年，明明和他爸爸都要增加5岁，用明明的岁数加上他爸爸的岁数再加上明明和他爸爸再过5年增加的岁数，就是5年后明明和他爸爸的总岁数。据此解答即可。\n\n【详解】8+44+5×2=8+44+10=52+10=62(岁)。答：明明和爸爸一共有62岁。",
+        "knowledge_points":  [
+                                 "表内乘加，乘减",
+                                 "年龄问题"
+                             ],
+        "source":  "2025 三年级下·湖南永州·专题练习"
+    },
+    {
+        "id":  "76",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "奶奶准备编45个中国结，已经编了13个，剩下的要在4天内完成，剩下的奶奶平均每天编几个中国结才能完成。",
+        "options":  [
+
+                    ],
+        "answer":  "8个",
+        "solution":  "【分析】根据题意，先用准备编中国结的总数量减去已经编了的数量，计算出剩下要编的数量，再用剩下要编的数量除以要编的天数，即可求出平均每天要编的数量。\n\n【详解】(45-13)÷4=32÷4=8(个)。答：剩下的奶奶平均每天编8个中国结才能完成。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算"
+                             ],
+        "source":  "24-25 二年级下·山西阳泉·期末"
+    },
+    {
+        "id":  "77",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "乐乐在计算7×(6-□)时，把中间的减号不小心看成了加号，得到的结果是63，正确的得数是多少。",
+        "options":  [
+
+                    ],
+        "answer":  "21",
+        "solution":  "【分析】可以根据错误的计算，把中间的减号看成加号，结果是63;再根据乘法和除法互为逆运算的关系，得出括号内的和为9，计算出括号内的另一个数是3。再根据正确的运算计算出结果即可。\n\n【详解】63÷7-6=9-6=3，7×(6-3)=7×3=21。答：正确的得数是21。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算",
+                                 "乘加，乘减混合运算"
+                             ],
+        "source":  "24-25 二年级下·湖北省直辖县级单位·期末"
+    },
+    {
+        "id":  "78",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "一根绳子长36米，剪去同样长的4段后还剩8米，剪去的每段长几米。",
+        "options":  [
+
+                    ],
+        "answer":  "7米",
+        "solution":  "【分析】根据题意，先用绳子的总长度减去剩下的长度，计算出剪去的总长度，再用剪去的长度除以段数，就是每段的长度。\n\n【详解】(36-8)÷4=28÷4=7(米)。答：剪去的每段长7米。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算"
+                             ],
+        "source":  "24-25 二年级下·湖北恩施·期末"
+    },
+    {
+        "id":  "79",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "李老师买回4盒铅笔，每盒6支，如果改放成3盒，平均每盒放几支。",
+        "options":  [
+
+                    ],
+        "answer":  "8支",
+        "solution":  "【分析】根据题意，先用每盒铅笔的数量6支和买的盒数4盒相乘，求出一共买回多少支铅笔，再用铅笔的总数量除以要改成的盒数，即可求出平均每盒要放的数量。\n\n【详解】6×4÷3=24÷3=8(支)。答：平均每盒放8支。",
+        "knowledge_points":  [
+                                 "表内乘除混合运算"
+                             ],
+        "source":  "24-25 二年级下·湖北恩施·期末"
+    },
+    {
+        "id":  "80",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "(本题含图片)\n![](images/a65a58785140b8c93e09f055b1a35e2e.png)\n(1)小月买了8个转笔刀和一个书包，她付100元钱，够吗。\n(2)小月有50元钱，买一个书包后，剩下的钱能买多少个文具盒。",
+        "options":  [
+
+                    ],
+        "answer":  "够;3个",
+        "solution":  "【分析】(1)用乘法算出买8个转笔刀多少钱，再加上一个书包的钱，算出总钱数，与100元比较，若花的总钱数小于或等于100元，则够，反之则不够;(2)用50元减去买一个书包的钱，可以求出剩下的钱，再用剩下的钱除以一个文具盒的钱，即可求出剩下的钱能买多少个文具盒。\n\n【详解】(1)8×7+35=56+35=91(元)，91元小于100元，答：她付100元钱，够。(2)(50-35)÷5=15÷5=3(个)，答：剩下的钱能买3个文具盒。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算",
+                                 "乘加，乘减混合运算",
+                                 "100以内数的比大小"
+                             ],
+        "source":  "24-25 二年级下·山东菏泽·期末"
+    },
+    {
+        "id":  "81",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "钢笔原来15元一支，现在优惠促销5支45元。现在比原来便宜多少元钱。",
+        "options":  [
+
+                    ],
+        "answer":  "6元",
+        "solution":  "【分析】先用除法算出优惠促销后，每支钢笔多少元，再用原来一支钢笔的钱减去优惠促销后每支钢笔的钱，即可求出现在比原来便宜多少元钱。\n\n【详解】15-45÷5=15-9=6(元)。答：现在比原来便宜6元钱。",
+        "knowledge_points":  [
+                                 "除加，除减混合运算"
+                             ],
+        "source":  "24-25 二年级下·山东菏泽·期末"
+    },
+    {
+        "id":  "82",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "有40盒粉笔，平均分给一年级的5个班。其中一(1)班原来有6盒粉笔，现在一(1)班有多少盒粉笔。",
+        "options":  [
+
+                    ],
+        "answer":  "14盒",
+        "solution":  "【分析】由题意可知：用粉笔的总盒数除以班数，即是每班能分的盒数，再加上一(1)班原来有粉笔的盒数，即是现在一(1)班有粉笔的盒数;据此解答。\n\n【详解】由分析可得:40÷5+6=8+6=14(盒),答：现在一(1)班有14盒粉笔。",
+        "knowledge_points":  [
+                                 "除加，除减混合运算",
+                                 "用7~9的乘法口诀求商",
+                                 "8加几的进位加法"
+                             ],
+        "source":  "24-25 二年级下·山东菏泽·期末"
+    },
+    {
+        "id":  "83",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "食堂买来70千克黄瓜，又买来3筐萝卜，每筐9千克，一共买来蔬菜多少千克。",
+        "options":  [
+
+                    ],
+        "answer":  "97千克",
+        "solution":  "【分析】根据乘法的意义，用9×3先算出3筐萝卜一共多少千克，再将黄瓜和萝卜的千克数相加，即可得出一共买来蔬菜多少千克。\n\n【详解】70+9×3=70+27=97(千克)。答：一共买来蔬菜97千克。",
+        "knowledge_points":  [
+                                 "乘加，乘减混合运算"
+                             ],
+        "source":  "24-25 二年级下·广东江门·期末"
+    },
+    {
+        "id":  "84",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "同学们要栽72棵树，已经栽了7行，每行8棵，还要栽多少棵。\n答：还要栽( )棵。",
+        "options":  [
+
+                    ],
+        "answer":  "16",
+        "solution":  "【分析】根据乘法的意义，用8×7先算出已经栽了多少棵树，再用要栽的总棵数减去已经栽了的棵数，即得出还要栽多少棵。\n\n【详解】72-8×7=72-56=16(棵)。答：还要栽16棵。",
+        "knowledge_points":  [
+                                 "乘加，乘减混合运算"
+                             ],
+        "source":  "24-25 二年级下·广东江门·期末"
+    },
+    {
+        "id":  "85",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "学校开联欢会，要搬10张桌子，每个老师搬一张，两个同学抬一张。现在有3个老师，还要多少个同学才能一次搬完。\n答：还要( )个同学才能一次搬完。",
+        "options":  [
+
+                    ],
+        "answer":  "14",
+        "solution":  "【分析】由题意可知：用要搬的桌子数减去3个老师要搬的3张桌子，剩余的桌子数和2相乘，即是还要的同学的个数;据此解答。\n\n【详解】由分析可得:2×(10-3)=2×7=14(个),答：还要14个同学才能一次搬完。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算",
+                                 "7的乘法口诀及应用",
+                                 "10的加减法"
+                             ],
+        "source":  "24-25 二年级下·四川凉山·期末"
+    },
+    {
+        "id":  "86",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "一本故事书有90页，丽丽平均每天看8页，看了9天，还剩多少页没看。\n答：还剩( )页没看。",
+        "options":  [
+
+                    ],
+        "answer":  "18",
+        "solution":  "【分析】由题意可知：用每天看的页数乘看的天数，即是已经看的页数，用故事书的总页数减去已经看的页数，即是还剩的没看的页数;据此解答。\n\n【详解】由分析可得:90-8×9=90-72=18(页),答：还剩18页没看。",
+        "knowledge_points":  [
+                                 "乘加，乘减混合运算",
+                                 "9的乘法口诀及应用"
+                             ],
+        "source":  "24-25 二年级下·四川凉山·期末"
+    },
+    {
+        "id":  "87",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "文具店里一支钢笔要12元，比一本笔记本贵7元，妈妈要买8本笔记本，一共需要多少钱。\n答：一共需要( )元。",
+        "options":  [
+
+                    ],
+        "answer":  "40",
+        "solution":  "【分析】根据题意可知：先求出笔记本的价格，用钢笔的价格减去比一本笔记本贵的钱数即可;然后用一本笔记本的价格乘买笔记本的数量，即可求出买8本笔记本一共需要花的钱数。\n\n【详解】(12-7)×8=5×8=40(元)。答：一共需要40元。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算"
+                             ],
+        "source":  "24-25 二年级下·四川凉山·期末"
+    },
+    {
+        "id":  "88",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "原来每条毛巾15元，五一节优惠，买5条才45元，现在每条毛巾比原来便宜多少钱。\n答：现在每条毛巾比原来便宜( )元。",
+        "options":  [
+
+                    ],
+        "answer":  "6",
+        "solution":  "【分析】由题意可知：用45除以5，即是优惠后现在每条毛巾的价钱，用原来每条毛巾的价钱减去现在每条毛巾的价钱，即是现在每条毛巾比原来便宜的钱数;据此解答。\n\n【详解】由分析可得:15-45÷5=15-9=6(元),答：现在每条毛巾比原来便宜6元钱。",
+        "knowledge_points":  [
+                                 "除加，除减混合运算",
+                                 "用7~9的乘法口诀求商",
+                                 "十几减9的退位减法"
+                             ],
+        "source":  "24-25 二年级下·四川凉山·期末"
+    },
+    {
+        "id":  "89",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "合唱队有4组学生，每组9人，如果这些学生每排站6人，一共可以站几排。\n答：一共可以站( )排。",
+        "options":  [
+
+                    ],
+        "answer":  "6",
+        "solution":  "【分析】根据乘法的意义，用4×9先算出合唱队一共有多少人，再用合唱队的总人数除以每排站的人数，即可得出共可以站几排。\n\n【详解】4×9÷6=36÷6=6(排)。答：一共可以站6排。",
+        "knowledge_points":  [
+                                 "表内乘除混合运算"
+                             ],
+        "source":  "24-25二年级下·四川凉山·期末"
+    },
+    {
+        "id":  "90",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "同学们去公园划船，每条船限乘4人，租了9条船还有6个空位，划船的同学一共有多少人。",
+        "options":  [
+
+                    ],
+        "answer":  "30人",
+        "solution":  "【分析】根据题意可知，用每条船限乘的人数乘9条船，再减去空位，即可求出划船的同学人数;据此解答。\n\n【详解】4×9-6=36-6=30(人)。答：划船的同学一共有30人。",
+        "knowledge_points":  [
+                                 "乘加，乘减混合运算"
+                             ],
+        "source":  "25-26 三年级上·黑龙江佳木斯·开学考试"
+    },
+    {
+        "id":  "91",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "云云参加了学校举办的\"读书伴我成长\"活动。她选了一本98页的书，坚持每晚读9页，7天后她还有多少页没有读。",
+        "options":  [
+
+                    ],
+        "answer":  "35页",
+        "solution":  "【分析】已知，云云选的这本书一共有98页，每晚读9页,7天后她还有多少页没读，也就是读了7天，用每天读的页数乘读的天数，即可得出一共读了多少页，再用这本书的总页数98页减去读的页数即可得出剩多少页没有读。\n\n【详解】据分析可得:98-9×7=98-63=35(页),答:7天后她还有35页没有读。",
+        "knowledge_points":  [
+                                 "两位数与两位数的不退位减法",
+                                 "9的乘法口诀及应用",
+                                 "乘加，乘减混合运算"
+                             ],
+        "source":  "24-25 二年级下·广东肇庆·期中"
+    },
+    {
+        "id":  "92",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "一本故事书有50页，小华看了8页之后，剩下的要6天看完，平均每天要看多少页。",
+        "options":  [
+
+                    ],
+        "answer":  "7页",
+        "solution":  "【分析】用故事书的总页数减去小华看的页数，求出剩下的页数，再除以看的天数，即可求出平均每天要看多少页。\n\n【详解】(50-8)÷6=42÷6=7(页)。答：平均每天要看7页。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算"
+                             ],
+        "source":  "24-25二年级下·江西九江·期末"
+    },
+    {
+        "id":  "93",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "某花店一共进了90个花盆，第一周卖了27个，第二周卖了36个。现在还剩多少个。",
+        "options":  [
+
+                    ],
+        "answer":  "27个",
+        "solution":  "【分析】总共花盆数量减去第一周卖了的数量，再减去第二周卖了的数量，就是还剩下的数量，据此列式计算即可。\n\n【详解】90-27-36=63-36=27(个)。答：现在还剩下27个。",
+        "knowledge_points":  [
+                                 "100以内数的连减运算"
+                             ],
+        "source":  "24-25 二年级下·云南昭通·期中"
+    },
+    {
+        "id":  "94",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "王叔叔买来白兔24只，灰兔11只，一个笼子里可以装5只兔子。他一共需要准备多少个笼子。请你帮他算一算。",
+        "options":  [
+
+                    ],
+        "answer":  "7个",
+        "solution":  "【分析】先用买来的白兔只数加上买来的灰兔只数，求出总只数，再用总只数除以每个笼子里装的兔子只数，即可求出一共需要准备多少个笼子。注意：因为需要先计算兔子的总只数，因此加法计算要用括号括起来。\n\n【详解】(24+11)÷5=35÷5=7(个)。答：他一共需要准备7个笼子。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算"
+                             ],
+        "source":  "24-25 二年级下·云南昭通·期中"
+    },
+    {
+        "id":  "95",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "小兔灰灰说：我拔了6个萝卜，小兔蓝蓝说：爸爸，妈妈和我都拔了9个萝卜，问小兔一家一共拔了多少个萝卜。",
+        "options":  [
+
+                    ],
+        "answer":  "33个",
+        "solution":  "【分析】由题意可知，有3只兔子每只各拔了9个萝卜，先用乘法求出3个9的和是多少，然后加上另一只兔子拔的数量(6个)，求出和，就是一共拔了多少个萝卜。\n\n【详解】9×3+6=27+6=33(个)。答：小兔一家一共拔了33个萝卜。",
+        "knowledge_points":  [
+                                 "表内乘加，乘减"
+                             ],
+        "source":  "24-25 二年级下·云南昭通·期中"
+    },
+    {
+        "id":  "96",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "同学们要栽90棵树，已经栽了7行，每行6棵，还剩多少棵树没栽。",
+        "options":  [
+
+                    ],
+        "answer":  "48棵",
+        "solution":  "【分析】由题意可知：用每行的棵数乘行数，即是已经栽的棵数，用要栽的棵数减去已经栽的棵数，即是还剩的没有栽的棵数;据此解答。\n\n【详解】由分析可得:90-6×7=90-42=48(棵),答：还剩48棵树没栽。",
+        "knowledge_points":  [
+                                 "乘加，乘减混合运算",
+                                 "6的乘法口诀及应用",
+                                 "两位数与两位数的退位减法"
+                             ],
+        "source":  "24-25 二年级下·江西赣州·期末"
+    },
+    {
+        "id":  "97",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "校园篮球赛分为上半场和下半场，201班和202班进行比赛。上半场201班获得25分，下半场两个班得分同样多，最终比分如下图所示，上半场202班获得了几分。\n![](images/c465b6f880dc6dd19637efca5315d77266d0e2e46f6e8de89de19832fab664e4.jpg)",
+        "options":  [
+
+                    ],
+        "answer":  "19分",
+        "solution":  "【分析】根据题意可知，201班最终得54分，上半场得25分，用201班最终得分减去上半场得分，等于201班下半场得分。由于下半场两个班得分同样多，也等于202班下半场得分，再用202班最终得分减去202班下半场得分，即可求出上半场202班获得了几分，据此解答。\n\n【详解】48-(54-25)=48-29=19(分)。答：上半场202班获得了19分。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算"
+                             ],
+        "source":  "24-25二年级下·浙江杭州·期末"
+    },
+    {
+        "id":  "98",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "妈妈带了50元去商场给小贝买了一双鞋子，剩余的钱还能买几双袜子。\n![](images/99fd47ea904672141fb373d628c98c35.png)",
+        "options":  [
+
+                    ],
+        "answer":  "3双",
+        "solution":  "【分析】由题意可知：用妈妈带的钱减去一双鞋子的钱，是剩余的钱，再除以一双袜子的钱，即是剩余的钱还能买的袜子数;据此解答。\n\n【详解】由分析可得:(50-23)÷9=27÷9=3(双),答：剩余的钱还能买3双袜子。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算",
+                                 "用7~9的乘法口诀求商",
+                                 "两位数与两位数的退位减法"
+                             ],
+        "source":  "24-25二年级下·山东菏泽·期中"
+    },
+    {
+        "id":  "99",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "松鼠妈妈分松果.\n![](images/dc03ac0f1eb322d1f6945b1cb74f3232b6d33cef2e82b3a7169265396c1430e5.jpg)\n(1)一共有( )个松果，平均分给3只小松鼠，每只小松鼠分到( )个。\n列式:\n(2)如果松鼠妈妈又拿来18个松果，一起平均分给9只小松鼠，那么每只小松鼠分到( )个.\n列式:",
+        "options":  [
+
+                    ],
+        "answer":  "18;6;18÷3=6;4;(18+18)÷9=4",
+        "solution":  "【分析】(1)通过数一数可知一共有18个松果，用松果的个数除以平均分给的小松鼠只数，即可求出每只小松鼠分到几个。(2)先用原来松果的个数加上松鼠妈妈又拿来的松果个数，求出松果的总个数，再用松果的总个数除以平均分给的小松鼠只数，即可求出每只小松鼠分到几个。\n\n【详解】(1)一共有(18)个松果，平均分给3只小松鼠，每只小松鼠分到(6)个。列式:18÷3=6(个),答：一共有18个松果，平均分给3只小松鼠，每只小松鼠分到6个。(2)(18+18)÷9=36÷9=4(个),答：如果松鼠妈妈又拿来18个松果，一起平均分给9只小松鼠，那么每只小松鼠分到4个。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算",
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·山西晋中·期中"
+    },
+    {
+        "id":  "100",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "吉吉家买了8箱牛奶，每箱6瓶，现在还剩多少瓶。下面的信息中选一个填在横线上，再列式解答。",
+        "options":  [
+                        "①喝掉3瓶",
+                        "②又买来3瓶",
+                        "③每瓶3元"
+                    ],
+        "answer":  "①;45瓶",
+        "solution":  "【分析】要解决\"现在还剩多少瓶\"这个问题，我们需要明确\"剩余数量=原有数量-减少的数量\"。条件①意味着牛奶的数量减少了，能够通过原有数量减去喝掉的数量得到剩余的数量;条件②买来意味着牛奶的数量增加了，不能求出还剩多少瓶;条件③是关于价格的信息，与牛奶的剩余数量没有直接关系，无法计算剩余瓶数，因此我们需要选择①才能计算出剩余瓶数。先用每箱牛奶的瓶数乘购买的箱数，求出购买的总瓶数，再用总瓶数减去喝掉的瓶数，即可求出现在还剩多少瓶。\n\n【详解】选择条件①。8×6-3=48-3=45(瓶),答：现在还剩下45瓶。",
+        "knowledge_points":  [
+                                 "乘加，乘减混合运算",
+                                 "\"提问题\"\"填条件\"问题"
+                             ],
+        "source":  "24-25二年级下·浙江湖州·期末"
+    },
+    {
+        "id":  "101",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "面包师傅制作了61个面包，上午卖出23个，下午卖出24个，还剩几个。小明是这样想的：先求出一共卖掉几个，再求还剩几个。根据他的想法列出的算式是( )。",
+        "options":  [
+                        "61-23-24",
+                        "61-23+24",
+                        "61-(23+24)"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】小明的想法是先求出一共卖掉了几个，用加法计算，再算还剩几个，用减法计算，用总数-(上午卖出的数量+下午卖出的数量)=剩余的数量，据此解答。\n\n【详解】根据分析:A。61-23-24，先求上午卖出后还剩的数量，再求还剩的数量，不符合小明的想法。B。61-23+24，不符合题意。C。61-(23+24),先求出一共卖掉几个，再求还剩的数量。符合小明的想法。故答案为:C",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算",
+                                 "100以内数的连减运算"
+                             ],
+        "source":  "24-25二年级下·山东济宁·期中"
+    },
+    {
+        "id":  "102",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "下面的算式中,( )的运算顺序是先算减法，再算除法。",
+        "options":  [
+                        "48÷(15-7)",
+                        "48-27÷3",
+                        "64÷8-6"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】四则混合运算的运算法则:(1)在没有括号的算式里，如果只有加减法或者只有乘除法，要从左往右依次计算;(2)在没有括号的算式里，如果既有乘除法又有加减法，要先算乘除法，再算加减法;(3)在有括号的算式里，要先算括号里面的，再算括号外面的;据此解答。\n\n【详解】A。48÷(15-7),先算括号里面的减法，再算括号外面的除法;B。48-27÷3，先算除法，再算减法;C。64÷8-6，先算除法，再算减法;故答案为:A",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算",
+                                 "除加",
+                                 "除减混合运算"
+                             ],
+        "source":  "24-25 二年级下·海南省直辖县级单位·期末"
+    },
+    {
+        "id":  "103",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "工程队修一条40米长的路，第一天修了9米，第二天修的长度和第一天一样。还剩多少米没修。下面算式不正确的是( )。",
+        "options":  [
+                        "40-9-9",
+                        "40-9+9",
+                        "40-(9+9)",
+                        "40-9×2"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】根据题意，求还剩多少米没修，可以用一条路的全长-第一天修的米数-第二天修的米数=还剩多少米没修;也可以用一条路的全长-(第一天修的米数+第二天修的米数)=还剩多少米没修;据此分析每个选项，选出不正确的算式，据此解答。\n\n【详解】A。40-9-9，表示用一条路的全长减去第一天修的米数，再减去第二天修的米数，可以求出还剩多少米没修，算式正确，不符合题意;B。40-9+9，表示用一条路的全长减去第一天修的米数，再加上第二天修的米数，不能求出还剩多少米没修，算式错误，符合题意;C。40-(9+9),表示用一条路的全长减去第一天与第二天修的米数之和，可以求出还剩多少米没修，算式正确，不符合题意;D。40-9×2，表示用一条路的全长减去第一天与第二天修的米数之和，可以求出还剩多少米没修，算式正确，不符合题意;故答案为:B",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算",
+                                 "乘加",
+                                 "乘减混合运算",
+                                 "100以内数的加减混合运算",
+                                 "100以内数的连减运算"
+                             ],
+        "source":  "24-25 二年级下·浙江台州·期末"
+    },
+    {
+        "id":  "104",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "从18里面连续减去( )个3得3。",
+        "options":  [
+                        "4",
+                        "5",
+                        "6",
+                        "7"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】根据题意可知，从18里面连续减去几个3得3，先用18减去最后得数的3，然后再除以3，即可解答。\n\n【详解】(18-3)÷3=15÷3=5(个),从18里面连续减去5个3得3。故答案为:B",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算"
+                             ],
+        "source":  "24-25 二年级下·浙江台州·期末"
+    },
+    {
+        "id":  "105",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "水果店运来35箱苹果，每箱9千克，还剩多少千克。如果列式为(35-30)×9，那么横线上需要填的信息是( )。",
+        "options":  [
+                        "卖了30箱苹果",
+                        "又运来30箱苹果",
+                        "每箱苹果30元"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】题目需要求还剩下的重量，结合算式(35-30)×9可知，\"35-30\"代表的应该是剩余的苹果箱数，剩余的苹果箱数×每箱苹果的重量=剩余的苹果重量。由此可知，横线内的信息应该是从35箱去掉了30箱，找出能够表达此含义的选项即可解答。\n\n【详解】A。卖了30箱苹果，是35-30，符合题意;B。又运来30箱苹果，是35+30，不符合题意;C。每箱苹果30元，无法体现从35中去掉30，不符合题意。故答案为:A",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算",
+                                 "\"提问题\"\"填条件\"问题"
+                             ],
+        "source":  "24-25二年级下·浙江台州·期末"
+    },
+    {
+        "id":  "106",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "用\"(60-4)÷7\"不能解决的问题是( )。",
+        "options":  [
+                        "小文带了60元，买了7瓶果汁，找回4元，每瓶果汁多少元。",
+                        "小轩看一本60页的故事书看了7天，还剩4页没看完。小轩平均每天看多少页。",
+                        "小新买了7支水彩笔，每支4元，付了60元，找回多少钱。"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】根据题意，依次分析各选项解答即可。A。用总钱数减去找回的钱数，计算出买果汁一共花了多少钱，再除以买果汁的瓶数，就是每瓶果汁的钱数;B。用故事书的总页数减去剩下没看的页数，计算出看了的页数，再除以看的天数，就是每天看的页数;C。先用每支水彩笔的钱数和买的数量相乘，计算出一共花了多少钱，再用总钱数减去花了的钱数，就是应找回的钱数。\n\n【详解】A。(60-4)÷7=56÷7=8(元),每瓶果汁8元。能用\"(60-4)÷7\"解决，不符合题意;B。(60-4)÷7=56÷7=8(页),小轩平均每天看8页。能用\"(60-4)÷7\"解决，不符合题意;C。60-4×7=60-28=32(元),找回32元。不能用\"(60-4)÷7\"解决，符合题意。则用\"(60-4)÷7\"不能解决的问题是小新买了7支水彩笔，每支4元，付了60元，找回多少钱。故答案为:C",
+        "knowledge_points":  [
+                                 "乘加",
+                                 "乘减混合运算",
+                                 "带有小括号的混合运算"
+                             ],
+        "source":  "24-25 二年级下·山东临沂·期中"
+    },
+    {
+        "id":  "107",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "小华有50元钱，买文具盒花了25元，买尺子花了6元，还剩多少钱。下面列式错误的是( )。",
+        "options":  [
+                        "50-25-6",
+                        "50-(25-6)",
+                        "50-(25+6)"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】根据题意，用小华的钱数-买文具盒花的钱数-买尺子花的钱数=还剩的钱数;或者先用加法计算出买文具盒和尺子一共花了多少钱，再用小华的钱数减去一共花的钱数，即可计算出还剩的钱数。\n\n【详解】A。50-25-6是用小华的钱数-买文具盒花的钱数-买尺子花的钱数，计算出的是剩下的钱数，算式正确;B。50-(25-6):25-6计算出的是买文具盒比买尺子多花的钱数，用总钱数减去这部分钱数，不能计算出剩下的钱数，算式错误;C。50-(25+6)先计算出买两样物品一共花的钱数，再用总钱数减去一共花的钱数，计算出的是剩下的钱数，算式正确。则列式错误的是50-(25-6)。故答案为:B",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算",
+                                 "100以内数的连减运算"
+                             ],
+        "source":  "24-25 二年级下·江西九江·期中"
+    },
+    {
+        "id":  "108",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "下面算式哪个先算加法( )。",
+        "options":  [
+                        "24+6×3",
+                        "25-17+60",
+                        "36÷(4+5)"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】在没有括号的算式里，只有加，减法或只有乘，除法，要从左往右计算;在没有括号的算式里，如果既有乘，除法，又有加，减法，要先算乘，除法，再算加，减法;有括号的算式里，要先算括号里面的，再算括号外面的。由此解答。\n\n【详解】A。24+6×3先算乘法，再算加法，不符合题意;B。25-17+60从左往右计算，也就是先算减法，再算加法，不符合题意;C。36÷(4+5)先算加法，再算除法，符合题意。则先算加法的算式是36÷(4+5)。故答案为:C",
+        "knowledge_points":  [
+                                 "有括号的运算顺序",
+                                 "无括号的运算顺序",
+                                 "带有小括号的混合运算",
+                                 "乘加",
+                                 "乘减混合运算"
+                             ],
+        "source":  "24-25二年级下·江西九江·期中"
+    },
+    {
+        "id":  "109",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "算式7×(5+2)和7×5+2的得数相差( )。",
+        "options":  [
+                        "12",
+                        "13",
+                        "15"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】混合运算的运算顺序：如果只有加减法或只有乘除法，按照从左到右的顺序计算;如果既有加减法又有乘除法，要先算乘除法，再算加减法;如果有括号，要先算括号里面的，再算括号外面的。7×(5+2)先算括号里面的加法，再算括号外面的乘法;7×5+2先算乘法，再算加法。分别计算出各算式的结果，再相减即可求出得数相差几。\n\n【详解】7×(5+2)=7×7=49,7×5+2=35+2=37,49-37=12，得数相差12。故答案为:A",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算",
+                                 "乘加",
+                                 "乘减混合运算",
+                                 "两位数与两位数的不退位减法"
+                             ],
+        "source":  "24-25二年级下·山西晋中·期中"
+    },
+    {
+        "id":  "110",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "下面算式去掉小括号结果不变的是( )。",
+        "options":  [
+                        "(45+11)÷8",
+                        "57-(5×7)",
+                        "(46-34)÷6"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】混合运算的运算顺序：如果只有加减法或只有乘除法，按照从左到右的顺序计算;如果既有加减法又有乘除法，要先算乘除法，再算加减法;如果有括号，要先算括号里面的，再算括号外面的。据此判断去掉小括号前后的运算顺序是否一致，如果一致，则结果不变;如果不一致，则结果改变。\n\n【详解】A。(45+11)÷8，去掉小括号前先算加法，再算除法，去掉后先算除法，再算加法，去掉小括号前后运算顺序不同，所以结果改变;B。57-(5×7),去掉小括号前先算乘法，再算减法，去掉后先算乘法，再算减法，去掉小括号前后运算顺序相同，所以结果不变;C。(46-34)÷6，去掉小括号前先算减法，再算除法，去掉后先算除法，再算减法，去掉小括号前后运算顺序不同，所以结果改变。因此，去掉小括号结果不变的是57-(5×7)。故答案为:B",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算",
+                                 "除加",
+                                 "除减混合运算",
+                                 "乘加",
+                                 "乘减混合运算"
+                             ],
+        "source":  "24-25 二年级下·山西晋中·期末"
+    },
+    {
+        "id":  "111",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "同学们要栽65棵树，已经栽了6行，每行8棵。还要栽多少棵。解决这个问题，要先算( )。",
+        "options":  [
+                        "还剩几行",
+                        "已经栽了几棵",
+                        "还要栽几棵"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】先用每行栽的棵数乘栽的行数，求出已经栽了多少棵，再用要栽的棵数减去已经栽的棵数，即可求出还要栽多少棵。因此，要解决这个问题，要先算已经栽了几棵。\n\n【详解】由分析可知:65-8×6=65-48=17(棵),还要栽17棵。因此，解决\"还要栽多少棵\"这个问题，要先算已经栽了几棵。故答案为:B",
+        "knowledge_points":  [
+                                 "乘加",
+                                 "乘减混合运算"
+                             ],
+        "source":  "24-25二年级下·山西晋中·期中"
+    },
+    {
+        "id":  "112",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "一本笔记本8元钱，豆豆付给售货员100元钱，找回52元，豆豆买了多少本笔记本。列式为(100-52)÷8，说明要先算( )。",
+        "options":  [
+                        "找回来了多少钱",
+                        "6本笔记本多少钱",
+                        "买笔记本花了多少钱"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】根据题意，豆豆付了100元，找回52元，说明买笔记本实际花费了100-52=48(元)。每本笔记本8元，所以数量为48÷8=6(本)。列式(100-52)÷8中，括号内的运算优先计算，即先算买笔记本的总花费。\n\n【详解】(100-52)÷8=48÷8=6(本),列式为(100-52)÷8，说明要先算：买笔记本花了多少钱。故答案为:C",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算",
+                                 "经济问题"
+                             ],
+        "source":  "24-25 二年级下·山东临沂·期中"
+    },
+    {
+        "id":  "113",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "下列算式中，去掉小括号不影响计算结果的是( )。",
+        "options":  [
+                        "(24+32)÷8",
+                        "79-(81÷9)",
+                        "63÷(3×3)"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】在没有括号的算式里，只有加，减法或只有乘，除法，要从左往右计算;在没有括号的算式里，如果既有乘，除法又有加，减法，要先算乘，除法，再算加，减法;有括号的算式里，要先算括号里面的，再算括号外面的。小括号去掉后，运算顺序不发生改变，得数也不会发生改变，由此解答。\n\n【详解】A。(24+32)÷8先算加法，再算除法，去掉小括号后先算除法，再算加法，运算顺序改变，结果改变，不符合题意;B。79-(81÷9)先算除法，再算减法，去掉小括号后先算除法，再算减法，运算顺序不变，结果不变，符合题意;C。63÷(3×3)先算乘法，再算除法，去掉小括号后先算除法，再算乘法，运算顺序改变，结果改变，不符合题意。则去掉小括号不影响计算结果的是79-(81÷9)。故答案为:B",
+        "knowledge_points":  [
+                                 "有括号的运算顺序",
+                                 "无括号的运算顺序",
+                                 "带有小括号的混合运算"
+                             ],
+        "source":  "24-25二年级下·山东临沂·期中"
+    },
+    {
+        "id":  "114",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "小刚买了3盒铅笔，每盒8支，小红买了15支铅笔。小刚比小红多买了( )支。",
+        "options":  [
+                        "24",
+                        "9",
+                        "4"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】用铅笔的盒数乘每盒的价格，先计算小刚买的铅笔总数，再减去小红买的支数即可求解。\n\n【详解】8×3-15=24-15=9(支),小刚比小红多买了9支。故答案为:B",
+        "knowledge_points":  [
+                                 "乘加",
+                                 "乘减混合运算"
+                             ],
+        "source":  "24-25 二年级下·山东济宁·期中"
+    },
+    {
+        "id":  "115",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "与6×8+6结果相同的算式是( )。",
+        "options":  [
+                        "6×9",
+                        "7×6",
+                        "6×7"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】根据题意，依次计算出各算式的结果，找出与6×8+6得数相同的即可。在没有括号的算式里，如果既有乘、除法，又有加、减法，要先算乘、除法，再算加、减法。\n\n【详解】6×8+6=48+6=54;A。6×9=54，结果相同，符合题意;B。7×6=42，结果不同，不符合题意;C。6×7=42，结果不同，不符合题意。则与6×8+6结果相同的算式是6×9。故答案为:A",
+        "knowledge_points":  [
+                                 "乘加",
+                                 "乘减混合运算",
+                                 "9的乘法口诀及应用"
+                             ],
+        "source":  "24-25 二年级下·湖北孝感·期末"
+    },
+    {
+        "id":  "116",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "下面算式中，先算加法的是( )。",
+        "options":  [
+                        "3+5×2",
+                        "(3+5)×2",
+                        "8-3+5"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】在没有括号的算式里，如果只有加减法或者只有乘除法，要从左往右依次计算。在没有括号的算式里，如果既有乘除法又有加减法，要先算乘除法，再算加减法。在有括号的算式里，要先算括号里面的，再算括号外面的。A。3+5×2：先算乘法，再算加法，不符合题意;B。(3+5)×2：先算括号里面的加法，再算括号外面的乘法，符合题意;C。8-3+5：先算减法，再算加法，不符合题意。据此可选择。\n\n【详解】由分析可得：下面算式中，先算加法的是(3+5)×2。故答案为:B",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算",
+                                 "乘加",
+                                 "乘减混合运算",
+                                 "加减混合运算(20以内)"
+                             ],
+        "source":  "24-25 二年级下·湖北孝感·期中"
+    },
+    {
+        "id":  "117",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "有40个苹果，吃了8个，剩下的每8个放在一个盘子里，要用多少个盘子。正确列式是( )。",
+        "options":  [
+                        "40÷8-8",
+                        "40-8÷8",
+                        "(40-8)÷8"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】根据题意，先用苹果的总数量减去吃了的数量，求出剩下的数量，再用剩下的数量除以每盘放的数量，即可求出需要盘子的数量，综合算式中有减法和除法，先算减法，再算除法，减法要加小括号。\n\n【详解】(40-8)÷8=32÷8=4(个)，要用4个盘子。正确列式是(40-8)÷8。故答案为:C",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算"
+                             ],
+        "source":  "24-25二年级下·河南信阳·期中"
+    },
+    {
+        "id":  "118",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "除数是\"2+4\"，被除数是42，商是多少。列式为( )。",
+        "options":  [
+                        "42÷(2+4)",
+                        "42÷2+4",
+                        "42÷6"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】根据题意，除数是\"2+4\"，需先计算2+4的和，再用被除数42除以这个和。根据\"被除数/除数=商\"来列式。列算式时，除数(2+4)要加小括号。\n\n【详解】被除数是42，除数是(2+4),列式为42÷(2+4)。A。42÷(2+4),正确体现除数，先算加法，符合题意;B。42÷2+4，先算除法后算加法，结果错误;C。42÷6，虽然结果正确，但未按题目要求列式，排除。故答案为:A",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算"
+                             ],
+        "source":  "24-25 二年级下·湖北黄冈·期中"
+    },
+    {
+        "id":  "119",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "下列算式中，去掉小括号不会影响计算结果的是( )。",
+        "options":  [
+                        "(45-20)÷5",
+                        "9×(5+2)",
+                        "30-(2×5)"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】只有加减法或只有乘除法的混合运算，从左往右计算。既有加减法又有乘除法的混合运算，先算乘除法，再算加减法。有小括号的混合运算，先算小括号里面的，再算小括号外面的。判断去掉小括号是否影响计算结果，需验证运算顺序是否改变。若去掉后运算顺序不变，则结果不变。\n\n【详解】A。(45-20)÷5先算括号内45-20=25，再25÷5=5。去掉括号后:45-20÷5=45-4=41，结果改变。此选项错误。B。9×(5+2)先算括号内5+2=7，再9×7=63。去掉括号后:9×5+2=45+2=47，结果改变。此选项错误。C。30-(2×5)先算括号内2×5=10，再30-10=20。去掉括号后:30-2×5=30-10=20，结果不变。此选项正确。故答案为:C",
+        "knowledge_points":  [
+                                 "无括号的运算顺序",
+                                 "带有小括号的混合运算"
+                             ],
+        "source":  "24-25二年级下·湖北黄冈·期中"
+    },
+    {
+        "id":  "120",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "二(1)班的小红和爸爸、妈妈一起去公园玩，公园门票价格如下：成人票6元/人，学生票2元/人，20元买3个人的票，( )。",
+        "options":  [
+                        "够",
+                        "不够",
+                        "无法确定"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】根据题意，需要买2张成人票和1张学生票，则每张成人票的钱数和买的数量相乘，求出买成人票需要的钱数，再和1张学生票的钱数相加，求出一共需要的钱数，再和20元比较大小。需要的钱数大于20元不够，小于或等于20元够。\n\n【详解】6×2+2=12+2=14(元)，14小于20，则20元买3个人的票，够。故答案为:A",
+        "knowledge_points":  [
+                                 "乘加",
+                                 "乘减混合运算",
+                                 "20以内数的比大小"
+                             ],
+        "source":  "24-25 二年级下·河南南阳·期中"
+    },
+    {
+        "id":  "121",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "儿童乐园原来每张门票12元，六一儿童节举行优惠活动,3张27元。现在每张比原来便宜多少元。正确的列式是( )。",
+        "options":  [
+                        "12+27÷3",
+                        "12-27÷3",
+                        "(27-12)÷3"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】根据题意，用原来每张门票的钱数减去现在每张门票的钱数，即可求出便宜的钱数，其中现在每张门票的钱数用优惠后买3张的钱数除以买的张数，由此解答。\n\n【详解】由分析得:12-27÷3=12-9=3(元),现在每张比原来便宜3元。则正确的列式为12-27÷3。故答案为:B",
+        "knowledge_points":  [
+                                 "除加",
+                                 "除减混合运算"
+                             ],
+        "source":  "24-25二年级下·河北邯郸·期中"
+    },
+    {
+        "id":  "122",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "水果店一共运来90盒草莓，上午卖了35盒，下午卖了26盒。聪聪列出算式\"35+26\"所求的问题是( )。",
+        "options":  [
+                        "还剩多少盒草莓。",
+                        "上午卖完后还剩多少盒草莓。",
+                        "上午和下午一共卖了多少盒草莓。"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】求两部分的和，用加法计算，即上午卖出的数量+下午卖出的数量=一共卖出的数量，由此解答。\n\n【详解】A。求还剩的数量，列式为90-35-26，不符合题意;B。求上午卖完后还剩的数量，列式为90-35，不符合题意;C。求上午和下午一共卖出的数量，列式为35+26，符合题意。则聪聪列出算式\"35+26\"所求的问题是上午和下午一共卖了多少盒草莓。故答案为:C",
+        "knowledge_points":  [
+                                 "100以内数的连减运算",
+                                 "两位数与两位数的退位减法",
+                                 "两位数与两位数的进位加法",
+                                 "\"提问题\"\"填条件\"问题"
+                             ],
+        "source":  "24-25 二年级下·河南漯河·期中"
+    },
+    {
+        "id":  "123",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "下列算式去掉小括号不改变运算顺序的是( )。",
+        "options":  [
+                        "(3+5)×9",
+                        "24+(6÷3)",
+                        "(60-15)÷5"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】整数混合运算中，同级运算时，从左到右依次计算;两级运算时，先算乘除，后算加减;有括号时，先算括号里面的，再算括号外面的。据此逐项分析。\n\n【详解】A。原式先算括号内加法，再乘9;去掉括号后变为3+5×9，先乘后加，顺序改变。B。原式先算括号内除法，再相加;去掉括号后变为24+6÷3，仍先算除法再加法，顺序未变。C。原式先算括号内减法，再除以5;去掉括号后变为60-15÷5，先除后减，顺序改变。去掉小括号不改变运算顺序的是24+(6÷3)。故答案为:B",
+        "knowledge_points":  [
+                                 "无括号的运算顺序",
+                                 "带有小括号的混合运算"
+                             ],
+        "source":  "24-25 二年级下·河南南阳·期中"
+    },
+    {
+        "id":  "124",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "鼓楼门票9元一张，小维买了4张门票，付了40元，应找回多少钱。正确算式是( )。",
+        "options":  [
+                        "40-4×9",
+                        "4×9-40",
+                        "(40-4)×9"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】根据题意可知，一张门票的钱数乘购买门票的张数，等于一共需要多少钱，再用付的钱数减去购买门票需要的钱数，等于应找回多少钱，据此解答。\n\n【详解】根据分析可得：鼓楼门票9元一张，小维买了4张门票，付了40元，应找回多少钱。正确算式是40-4×9。故答案为:A",
+        "knowledge_points":  [
+                                 "乘加",
+                                 "乘减混合运算"
+                             ],
+        "source":  "24-25 二年级下·广西柳州·期中"
+    },
+    {
+        "id":  "125",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "把1+5=6和48÷6=8合并成综合算式是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "48÷(1+5)=8",
+        "solution":  "【分析】四则混合运算的运算法则:①在没有括号的算式里，如果只有加减法或者只有乘除法，要从左往右依次计算。②在没有括号的算式里，如果既有乘除法又有加减法，要先算乘除法，再算加减法。③在有括号的算式里，要先算括号里面的，再算括号外面的。分步算式的最后一步是除法，分别找出被除数和除数，被除数是48，除数是6，由1+5得到，要加上小括号，综合算式是48÷(1+5)=8。\n\n【详解】根据分析：把1+5=6和48÷6=8合并成综合算式是48÷(1+5)=8。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算"
+                             ],
+        "source":  "24-25 二年级下·浙江杭州·期末"
+    },
+    {
+        "id":  "126",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "在计算36+18÷6时，要先算( )法，再算( )法;如果添括号改变运算顺序，计算的结果是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "除;加;9",
+        "solution":  "【分析】在没有括号的算式里，如果既有乘除法，又有加减法，要先算乘除法，再算加减法;有括号的算式里，要先算括号里面的，再算括号外面的。原算式先算除法，再算加法，要改变运算顺序，也就是先算加法，再算除法，应在加法外边加小括号。\n\n【详解】(36+18)÷6=54÷6=9，在计算36+18÷6时，要先算除法，再算加法;如果添括号改变运算顺序，计算的结果是9。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算",
+                                 "除加",
+                                 "除减混合运算"
+                             ],
+        "source":  "24-25 二年级下·浙江台州·期末"
+    },
+    {
+        "id":  "127",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "从63里连续减去9，减( )次还剩9。",
+        "options":  [
+
+                    ],
+        "answer":  "6",
+        "solution":  "【分析】先用63减去9，求出差，再除以9，求出商，就表示从63里面连续减去9，减几次还剩9。\n\n【详解】(63-9)÷9=54÷9=6，即从63里连续减去9，减6次还剩9。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算",
+                                 "用7~9的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·山东菏泽·期末"
+    },
+    {
+        "id":  "128",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "将\"72-23=49,49÷7=7\"合并成一道综合算式是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "(72-23)÷7=7",
+        "solution":  "【分析】根据题意，先计算出72减23的差，再用这个差除以7，最终的结果是两个数的商。综合算式中有减法和除法，先算减法，再算除法。用72-23代替49写在除号前面，要加小括号。\n\n【详解】(72-23)÷7=49÷7=7，将\"72-23=49,49÷7=7\"合并成一道综合算式是(72-23)÷7=7。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算",
+                                 "用7~9的乘法口诀求商",
+                                 "两位数与两位数的退位减法"
+                             ],
+        "source":  "24-25 二年级下·山东临沂·期中"
+    },
+    {
+        "id":  "129",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "计算48+12÷3，先算( )法，再算( )法，结果是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "除;加;52",
+        "solution":  "【分析】在没有括号的算式里，如果既有乘、除法，又有加、减法，要先算乘、除法，再算加、减法，由此解答。\n\n【详解】48+12÷3=48+4=52，计算48+12÷3，先算除法，再算加法，结果是52。",
+        "knowledge_points":  [
+                                 "除加",
+                                 "除减混合运算"
+                             ],
+        "source":  "24-25 二年级下·山东临沂·期中"
+    },
+    {
+        "id":  "130",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "被除数是50与6的和，除数是7，求商是多少，列综合算式为( )。",
+        "options":  [
+
+                    ],
+        "answer":  "(50+6)÷7=8",
+        "solution":  "【分析】除法算式为被除数÷除数=商。即先计算出50与6的和，再用这个和除以7，求出商即可，综合算式中有加法和除法，先算加法再除法，加法要加小括号。\n\n【详解】(50+6)÷7=56÷7=8，被除数是50与6的和，除数是7，求商是多少，列综合算式为(50+6)÷7=8。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算"
+                             ],
+        "source":  "24-25 二年级下·山东临沂·期中"
+    },
+    {
+        "id":  "131",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "小虎在计算8+□÷8时，算错了运算顺序，先算加法再算除法结果是7，正确结果是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "14",
+        "solution":  "【分析】在没有括号的算式里，如果既有乘，除法，又有加，减法，要先算乘，除法，再算加，减法，正确的运算顺序为先算除法，再算加法。小虎运算顺序算错了，也就是先算加法，再算除法，则用错误的结果和8相乘，求出8+□的结果，再用这个结果减去8，计算出□代表的数，再根据正确的顺序计算结果即可。\n\n【详解】由分析得:7×8=56;56-8=48，即□是48.8+48÷8=8+6=14，小虎在计算8+□÷8时，算错了运算顺序，先算加法再除法结果是7，正确结果是14。",
+        "knowledge_points":  [
+                                 "除加",
+                                 "除减混合运算"
+                             ],
+        "source":  "24-25 二年级下·福建厦门·期末"
+    },
+    {
+        "id":  "132",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "把\"51-45=6,42÷6=7\"合并成综合算式:( )。",
+        "options":  [
+
+                    ],
+        "answer":  "42÷(51-45)=7",
+        "solution":  "【分析】根据题意，先计算出51减45的差，再用42除以这个差，最终的结果是两个数的商。综合算式中有减法和除法，先算减法，再算除法。42写在前，51-45代替6写在后，要加小括号。\n\n【详解】42÷(51-45)=42÷6=7，把\"51-45=6,42÷6=7\"合并成综合算式:42÷(51-45)=7。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算"
+                             ],
+        "source":  "24-25 二年级下·浙江台州·期末"
+    },
+    {
+        "id":  "133",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在计算8+2×3时，要先算( )法，然后算( )法。如果要改变运算顺序，先算加法再算乘法，算式应变为( )。",
+        "options":  [
+
+                    ],
+        "answer":  "乘;加;(8+2)×3",
+        "solution":  "【分析】在没有括号的算式里，如果既有乘，除法，又有加，减法，要先算乘，除法，再算加，减法;有括号的算式里，要先算括号里面的，再算括号外面的，由此解答。\n\n【详解】在计算8+2×3时，要先算乘法，然后算加法。如果要改变运算顺序，先算加法再算乘法，算式应变为(8+2)×3。",
+        "knowledge_points":  [
+                                 "无括号的运算顺序",
+                                 "带有小括号的混合运算",
+                                 "乘加",
+                                 "乘减混合运算"
+                             ],
+        "source":  "24-25 二年级下·江西赣州·期末"
+    },
+    {
+        "id":  "134",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "计算18+36÷9时，先算( )法;要想先算加法，需要把算式改为( )。",
+        "options":  [
+
+                    ],
+        "answer":  "除;(18+36)÷9",
+        "solution":  "【分析】在没有括号的算式里，只有加，减法或只有乘，除法，要从左往右计算;在没有括号的算式里，如果既有乘，除法，又有加，减法，要先算乘，除法，再算加，减法;有括号的算式里，要先算括号里面的，再算括号外面的。由此解答。\n\n【详解】计算18+36÷9时，先算除法;要想先算加法，需要把算式改为(18+36)÷9。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算",
+                                 "除加",
+                                 "除减混合运算"
+                             ],
+        "source":  "24-25 二年级下·河南郑州·期中"
+    },
+    {
+        "id":  "135",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "小红看书，从第一页看起，每天看5页，看了9天，第10天应从第( )页看起。",
+        "options":  [
+
+                    ],
+        "answer":  "46",
+        "solution":  "【分析】先用每天看的页数乘看的天数，求出小红9天共看的页数，再加1即为第10天开始看的页码。\n\n【详解】5×9+1=45+1=46(页)，第10天应从第46页看起。",
+        "knowledge_points":  [
+                                 "乘加",
+                                 "乘减混合运算"
+                             ],
+        "source":  "24-25 二年级下·甘肃兰州·期末"
+    },
+    {
+        "id":  "136",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "二年级三个班去植树，三个班共植95棵，二(1)班植树29棵，二(2)班植树32棵，二(3)班植树( )棵。",
+        "options":  [
+
+                    ],
+        "answer":  "34",
+        "solution":  "【分析】先用二(1)班植树棵数加上二(2)班植树棵数，求出二(1)班和二(2)班植树总棵数，再用三个班植树总棵数减去二(1)班和二(2)班植树总棵数，即可求出二(3)班植树多少棵。因为要先算二(1)班和二(2)班植树总棵数，所以加法算式要加上小括号。\n\n【详解】95-(29+32)=95-61=34(棵)，二(3)班植树34棵。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算"
+                             ],
+        "source":  "24-25 二年级下·山东济宁·期中"
+    },
+    {
+        "id":  "137",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "工厂里有19位男工人,17位女工人，每4人一个生产小组，一共可分为( )个生产小组。",
+        "options":  [
+
+                    ],
+        "answer":  "9",
+        "solution":  "【分析】根据题意，男工人的人数加女工人的人数，等于共有多少人，再用总人数除以每组人数，结果即为可分成的组数。\n\n【详解】根据分析可得:(19+17)÷4=36÷4=9(个),因此，一共可以分成9个生产小组。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算"
+                             ],
+        "source":  "24-25二年级下·山东济宁·期中"
+    },
+    {
+        "id":  "138",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "把45÷5=9和85-9=76合并成综合算式是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "85-45÷5=76",
+        "solution":  "【分析】根据题意，整数的混合运算，有括号的先算括号里面的。没有括号的同级运算，从左往右依次计算，两级运算，先算乘除后算加减。把45÷5=9和85-9=76合并成综合算式，先算除法，再算减法，用85减去45与5的商，求差是多少。列式即可解答。\n\n【详解】根据分析：把45÷5=9和85-9=76合并成综合算式是85-45÷5=76。",
+        "knowledge_points":  [
+                                 "除加",
+                                 "除减混合运算"
+                             ],
+        "source":  "24-25 二年级下·山西长治·期中"
+    },
+    {
+        "id":  "139",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "计算40-12÷4时，先算( )法，再算( )法。如果要改变运算顺序先算减法，列式是( ),结果是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "除;减;(40-12)÷4;7",
+        "solution":  "【分析】整数的混合运算，有括号的先算括号里面的。没有括号的同级运算，从左往右依次计算，两级运算，先算乘除后算加减。40-12÷4，先算除法12÷4=3，再算减法40-3=37。如果要改变运算顺序先算减法，需要添加括号，把40-12用括号括起来。(40-12)÷4，先算括号里面的减法40-12=28，再算除法28÷4=7，据此解答。\n\n【详解】根据分析：计算40-12÷4时，先算(除)法，再算(减)法。如果要改变运算顺序先算减法，列式是(40-12)÷4，结果是(7)。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算",
+                                 "除加",
+                                 "除减混合运算"
+                             ],
+        "source":  "24-25 二年级下·山西长治·期中"
+    },
+    {
+        "id":  "140",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "在括号里填上\">\"\"<\"或\"=\"。\n2×6( )18  48÷6( )48÷8  63÷7( )9\n63( )8×8  24÷3×2( )4  8( )28÷(7-3)",
+        "options":  [
+
+                    ],
+        "answer":  "<;>;=;<;>;>",
+        "solution":  "【分析】根据题意，依次计算出各算式的结果再比较大小。在没有括号的算式里，只有加、减法或只有乘、除法，要从左往右计算;有括号的算式里，要先算括号里面的，再算括号外面的。\n\n【详解】2×6=12，12<18，则2×6<18;48÷6=8，48÷8=6，8>6，则48÷6>48÷8;63÷7=9，则63÷7=9;8×8=64，63<64，则63<8×8;24÷3×2=8×2=16，16>4，则24÷3×2>4;28÷(7-3)=28÷4=7，8>7，则8>28÷(7-3)。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算",
+                                 "表内乘除混合运算",
+                                 "用7~9的乘法口诀求商",
+                                 "100以内数的比大小"
+                             ],
+        "source":  "24-25 二年级下·山东临沂·期中"
+    },
+    {
+        "id":  "141",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "月月在计算\"5+□×6\"时弄错了运算顺序，先算加法后算乘法了，结果得数是36。正确的得数应该是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "11",
+        "solution":  "【分析】根据错误的运算顺序，得(5+□)×6=36，先算出□是多少，然后代入正确的算式计算即可。\n\n【详解】36÷6=6，则5+□=6，□=1。代入正确运算:5+1×6=5+6=11，正确的得数应该是11。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算",
+                                 "乘加",
+                                 "乘减混合运算"
+                             ],
+        "source":  "24-25二年级下·江西九江·期中"
+    },
+    {
+        "id":  "142",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在括号里填上\">\"\"<\"或\"=\"。\n40÷5( )5  24÷6( )24÷4  12÷(3×2)( )12÷6",
+        "options":  [
+
+                    ],
+        "answer":  ">;<;=",
+        "solution":  "【分析】由题意可知：有算式的先计算出得数，再比较大小;据此解答。\n\n【详解】40÷5=8，8>5，故40÷5>5;24÷6=4，24÷4=6，4<6，故24÷6<24÷4;12÷(3×2)=12÷6=2，12÷6=2，2=2，故12÷(3×2)=12÷6。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算",
+                                 "用7~9的乘法口诀求商",
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "24-25二年级下·山东菏泽·期中"
+    },
+    {
+        "id":  "143",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "将12+15=27和27÷9=3合并成一道综合算式为( )。",
+        "options":  [
+
+                    ],
+        "answer":  "(12+15)÷9=3",
+        "solution":  "【分析】通过观察，可以把27÷9=3中的被除数27，用算式12+15代替;因先算加法再算除法，故加法部分加上小括号;据此解答。\n\n【详解】由分析可得：将12+15=27和27÷9=3合并成一道综合算式为(12+15)÷9=3。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算",
+                                 "用7~9的乘法口诀求商",
+                                 "两位数与两位数的不进位加法"
+                             ],
+        "source":  "24-25二年级下·山东菏泽·期中"
+    },
+    {
+        "id":  "144",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在56-49÷7中，应先算( )法，再算( )法，结果是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "除;减;49",
+        "solution":  "【分析】在没有括号的算式里，如果只有加减法或者只有乘除法，要从左往右依次计算。在没有括号的算式里，如果既有乘除法又有加减法，要先算乘除法，再算加减法。在有括号的算式里，要先算括号里面的，再算括号外面的。56-49÷7：先算除法，再算减法;据此解答。\n\n【详解】由分析可得:56-49÷7=56-7=49，在56-49÷7中，应先算除法，再算减法，结果是49。",
+        "knowledge_points":  [
+                                 "除加，除减混合运算"
+                             ],
+        "source":  "24-25 二年级下·山东菏泽·期中"
+    },
+    {
+        "id":  "145",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "计算(27-18)÷9时，应先算( )法，最后的结果是( );如果去掉括号，应先算( )法，最后的结果是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "减;1;除;25",
+        "solution":  "【分析】混合运算的运算顺序：如果只有加减法或只有乘除法，按照从左到右的顺序计算;如果既有加减法又有乘除法，要先算乘除法，再算加减法;如果有括号，要先算括号里面的，再算括号外面的。(27-18)÷9要先算括号里面的减法，再算括号外面的除法;去掉括号，就变成了27-18÷9，此时要先算除法，再算减法。\n\n【详解】(27-18)÷9=9÷9=1，27-18÷9=27-2=25。计算(27-18)÷9时，应先算减法，最后的结果是1;如果去掉括号，应先算除法，最后的结果是25。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算",
+                                 "除加",
+                                 "除减混合运算"
+                             ],
+        "source":  "24-25 二年级下·山西晋中·期中"
+    },
+    {
+        "id":  "146",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "王奶奶端午节包了44个豆沙粽和28个肉粽，现在要把这些粽子每8个装一袋，可以装( )袋。",
+        "options":  [
+
+                    ],
+        "answer":  "9",
+        "solution":  "【分析】根据题意，先用豆沙粽的数量和肉粽的数量相加，计算出粽子的总数量，再用粽子的总数量除以每袋装的数量，就是可以装的袋数。\n\n【详解】(44+28)÷8=72÷8=9(袋)，王奶奶端午节包了44个豆沙粽和28个肉粽，现在要把这些粽子每8个装一袋，可以装9袋。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算"
+                             ],
+        "source":  "24-25 二年级下·山东临沂·期中"
+    },
+    {
+        "id":  "147",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "计算15-3×4时，先算( )法，再算( )法，结果是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "乘;减;3",
+        "solution":  "【分析】在没有括号的算式里，如果既有乘、除法，又有加、减法，要先算乘、除法，再算加、减法，由此解答。\n\n【详解】15-3×4=15-12=3，计算15-3×4时，先算乘法，再算减法，结果是3。",
+        "knowledge_points":  [
+                                 "无括号的运算顺序",
+                                 "乘加",
+                                 "乘减混合运算"
+                             ],
+        "source":  "24-25 二年级下·山东临沂·期中"
+    },
+    {
+        "id":  "148",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "合唱队有男生12人，女生16人，每4人一组，可以分成( )组。列式:( )。",
+        "options":  [
+
+                    ],
+        "answer":  "7;(12+16)÷4=7",
+        "solution":  "【分析】先利用加法将男生的人数和女生的人数进行相加，由此得到班级的总人数。再利用除法，用班级的总人数÷每组的人数，即可算出可以分成多少组。由此列出一个综合算式即可解答。\n\n【详解】(12+16)÷4=28÷4=7(组)，所以，可以分成7组，列式为(12+16)÷4=7。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算"
+                             ],
+        "source":  "24-25 二年级下·湖北孝感·期中"
+    },
+    {
+        "id":  "149",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "计算6×7-12时，先算( ),再算( ),结果是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "乘法;减法;30",
+        "solution":  "【分析】混合运算的运算顺序：如果只有加减法或只有乘除法，按照从左到右的顺序计算;如果既有加减法又有乘除法，要先算乘除法，再算加减法;如果有括号，要先算括号里面的，再算括号外面的。据此判断运算顺序并计算即可。\n\n【详解】由分析可知：计算6×7-12时，要先算乘法，再算减法。6×7-12=42-12=30，计算6×7-12时，先算(乘法),再算(减法),结果是(30)。",
+        "knowledge_points":  [
+                                 "乘加",
+                                 "乘减混合运算"
+                             ],
+        "source":  "24-25 二年级下·湖北孝感·期中"
+    },
+    {
+        "id":  "150",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "小马虎计算\"24+( )÷8\"时，弄错了运算顺序，先算了加法后算除法，结果得数是8，正确得数应该是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "29",
+        "solution":  "【分析】先根据错误的运算顺序求出括号中的数是几，再把这个数代入正确的运算顺序，计算出正确的结果，据此解答。\n\n【详解】把()看成□,计算如下:(24+□)÷8=8,24+□=8×8,24+□=64,□=64-24,□=40。将□=40代入原式，按正确顺序计算:24+40÷8=24+5=29，正确得数应该是29。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算",
+                                 "除加",
+                                 "除减混合运算"
+                             ],
+        "source":  "24-25 二年级下·湖北黄冈·期中"
+    },
+    {
+        "id":  "151",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "8加上48除以8的商，和是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "14",
+        "solution":  "【分析】先计算48除以8的商，再用8加上这个商，求和的结果，列出一个综合算式即可解答。\n\n【详解】48÷8=6，8+6=14，所以，和是14。",
+        "knowledge_points":  [
+                                 "除加",
+                                 "除减混合运算"
+                             ],
+        "source":  "24-25 二年级下·湖北黄冈·期中"
+    },
+    {
+        "id":  "152",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "把算式42÷6=7,54-7=47合并成一个综合算式( )。",
+        "options":  [
+
+                    ],
+        "answer":  "54-42÷6=47",
+        "solution":  "【分析】首先观察两个算式，第一个算式42÷6=7的结果7被第二个算式54-7=47作为减数使用。合并时需将第一个算式代入第二个算式中的7的位置。由于除法优先级高于减法，直接替换即可，无需添加括号。\n\n【详解】将42÷6=7代入54-7=47中，得到综合算式:54-42÷6=54-7=47，因此，合并后的综合算式为54-42÷6=47。",
+        "knowledge_points":  [
+                                 "除加",
+                                 "除减混合运算"
+                             ],
+        "source":  "24-25 二年级下·湖北黄冈·期中"
+    },
+    {
+        "id":  "153",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "要使4×(△-5)=28,△应该是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "12",
+        "solution":  "【分析】有括号的算式里，要先算括号里面的，再算括号外面的。题中算式先算减法，再算乘法，也就是△-5的差和4相乘，积是28，则先用28除以4，求出△-5的差，再根据减数+差=被减数，计算出△代表的数。\n\n【详解】由分析得:28÷4=7，即△-5=7;5+7=12。要使4×(△-5)=28,△应该是12。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算",
+                                 "用7~9的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·湖北黄冈·期中"
+    },
+    {
+        "id":  "154",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "18+27=45,54-45=9，把这两道算式改写成一道综合算式是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "54-(18+27)=9",
+        "solution":  "【分析】根据题意，先计算出18加27的和，再用54减去这个和，最终的结果是两个数的差，综合算式中有加法和减法，先算加法，再算减法。把54写在前,18+27代替45写在后，要加小括号。\n\n【详解】由分析得:18+27=45,54-45=9，把这两道算式改写成一道综合算式是54-(18+27)=9。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算"
+                             ],
+        "source":  "24-25 二年级下·湖南衡阳·期中"
+    },
+    {
+        "id":  "155",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "在括号里填上\">\"\"<\"或\"=\"。\n35÷7( )20÷4  48÷6( )48÷8  32÷8( )8  7÷7×9( )9÷9×7",
+        "options":  [
+
+                    ],
+        "answer":  "=;>;<;>",
+        "solution":  "【分析】含有算式的大小比较，可以先计算出每个算式的结果，再比较大小，即可解答。\n\n【详解】35÷7=5，20÷4=5，5和5相等，所以35÷7=20÷4；48÷6=8，48÷8=6，8>6，所以48÷6>48÷8；32÷8=4，4<8，所以32÷8<8；7÷7×9=1×9=9，9÷9×7=1×7=7，9>7，所以7÷7×9>9÷9×7。",
+        "knowledge_points":  [
+                                 "表内乘除混合运算",
+                                 "用7~9的乘法口诀求商",
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·山西长治·期中"
+    },
+    {
+        "id":  "156",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "小马虎在计算\"30-□÷6\"时弄错了运算顺序，先算减法后算除法，结果得数是3。正确的得数是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "28",
+        "solution":  "【分析】按照错误的计算顺序可知，先用3乘6算出积18，然后用30减去18，以此算出□代表的数。算出□代表的数后，根据先计算除法，再计算减法计算出正确的得数即可解答。\n\n【详解】根据错误的运算顺序可得:3×6=18,30-18=12，即□=12。正确的得数:30-12÷6=30-2=28，正确的得数是28。",
+        "knowledge_points":  [
+                                 "两位数与两位数的退位减法",
+                                 "6的乘法口诀及应用",
+                                 "除加",
+                                 "除减混合运算"
+                             ],
+        "source":  "24-25 二年级下·河南南阳·期中"
+    },
+    {
+        "id":  "157",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "27+18÷9的结果是( ),如果要改变它的运算顺序，那新的算式为( ),结果是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "29;(27+18)÷9;5",
+        "solution":  "【分析】根据四则运算规则，27+18÷9应先算除法，再算加法。要改变运算顺序，需添加括号使加法先算，再算除法。\n\n【详解】27+18÷9=27+2=29，(27+18)÷9=45÷9=5，所以27+18÷9的结果是29，如果要改变它的运算顺序，那新的算式为(27+18)÷9，结果是5。",
+        "knowledge_points":  [
+                                 "除加",
+                                 "除减混合运算",
+                                 "带有小括号的混合运算"
+                             ],
+        "source":  "24-25 二年级下·河南南阳·期中"
+    },
+    {
+        "id":  "158",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "计算15+25÷5时，先算( )法，再算( )法，结果是( ),如果改变运算顺序，改变后的算式是( ),结果是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "除;加;20;(15+25)÷5;8",
+        "solution":  "【分析】在没有括号的算式里，只有加、减法或只有乘、除法，要从左往右计算；在没有括号的算式里，如果既有乘、除法，又有加、减法，要先算乘、除法，再算加、减法；有括号的算式里，要先算括号里面的，再算括号外面的。则原算式先算除法，再算加法。要想改变运算顺序，也就是先算加法，再算除法，则加法外边要加小括号。\n\n【详解】15+25÷5=15+5=20，(15+25)÷5=40÷5=8，所以计算15+25÷5时，先算除法，再算加法，结果是20；如果改变运算顺序，改变后的算式是(15+25)÷5，结果是8。",
+        "knowledge_points":  [
+                                 "有括号的运算顺序",
+                                 "无括号的运算顺序",
+                                 "带有小括号的混合运算",
+                                 "除加",
+                                 "除减混合运算"
+                             ],
+        "source":  "24-25 二年级下·河南南阳·期中"
+    },
+    {
+        "id":  "159",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "把20张卡片平均分给小明和他的4个好朋友，每个人分( )张。",
+        "options":  [
+
+                    ],
+        "answer":  "4",
+        "solution":  "【分析】由题意可知：小明和他的4个好朋友共:1+4=5(人),用卡片的总张数除以人数，即是每个人分的张数;据此解答。\n\n【详解】由分析可得:20÷(1+4)=20÷5=4(张),把20张卡片平均分给小明和他的4个好朋友，每个人分4张。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算",
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·河南周口·期中"
+    },
+    {
+        "id":  "160",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "计算35-25÷5时，要先算( )法，后算( )法。",
+        "options":  [
+
+                    ],
+        "answer":  "除;减",
+        "solution":  "【分析】整数四则混合运算，如果有括号先算小括号里面的，再算括号外面的;如果没有括号，先算乘除，再算加减;只含有同一级运算，按照从左到右的顺序计算。\n\n【详解】据分析可知：计算35-25÷5时，要先算除法，后算减法。",
+        "knowledge_points":  [
+                                 "除加",
+                                 "除减混合运算"
+                             ],
+        "source":  "24-25二年级下·湖北武汉·期中"
+    },
+    {
+        "id":  "161",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "计算43+(13-6)时，应先算( )法，再算( )法，结果是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "减;加;50",
+        "solution":  "【分析】整数四则混合运算，如果有括号先算小括号里面的，再算括号外面的；如果没有括号，先算乘除，再算加减；只含有同一级运算，按照从左到右的顺序计算。\n\n【详解】43+(13-6)=43+7=50，所以计算43+(13-6)时，应先算减法，再算加法，结果是50。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算",
+                                 "100以内数的加减混合运算"
+                             ],
+        "source":  "24-25 二年级下·新疆阿克苏·期末"
+    },
+    {
+        "id":  "162",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "计算题",
+        "difficulty":  0.85,
+        "question":  "计算下面各题。\n27+18+2  27+3×7  42+(42-35)",
+        "options":  [
+
+                    ],
+        "answer":  "47;48;49",
+        "solution":  "【分析】四则混合运算的运算法则：(1)在没有括号的算式里，如果只有加减法或者只有乘除法，要从左往右依次计算；(2)在没有括号的算式里，如果既有乘除法又有加减法，要先算乘除法，再算加减法；(3)在有括号的算式里，要先算括号里面的，再算括号外面的。第1题从左往右依次计算，先算加法，再算加法；第2题先算乘法，再算加法；第3题先算括号里面的减法，再算括号外面的加法。\n\n【详解】27+18+2=45+2=47；27+3×7=27+21=48；42+(42-35)=42+7=49。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算",
+                                 "乘加",
+                                 "乘减混合运算",
+                                 "100以内数的连加运算"
+                             ],
+        "source":  "24-25 二年级下·浙江湖州·期末"
+    },
+    {
+        "id":  "163",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "计算题",
+        "difficulty":  0.85,
+        "question":  "脱式计算。\n(1)50-(25+16)  (2)42+15÷3  (3)48÷8×9  (4)9×(26-19)",
+        "options":  [
+
+                    ],
+        "answer":  "9;47;54;63",
+        "solution":  "【分析】在没有括号的算式里，如果只有加减法或者只有乘除法，要从左往右依次计算。在没有括号的算式里，如果既有乘除法又有加减法，要先算乘除法，再算加减法。在有括号的算式里，要先算括号里面的，再算括号外面的。(1)先算括号里面的，再算括号外面的;(2)先算除法，再算加法;(3)从左往右依次计算;(4)先算括号里面的，再算括号外面的。\n\n【详解】由分析可得:(1)50-(25+16)=50-41=9;(2)42+15÷3=42+5=47;(3)48÷8×9=6×9=54;(4)9×(26-19)=9×7=63。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算",
+                                 "除加",
+                                 "除减混合运算",
+                                 "表内乘除混合运算"
+                             ],
+        "source":  "24-25 二年级下·山东菏泽·期中"
+    },
+    {
+        "id":  "164",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "计算题",
+        "difficulty":  0.85,
+        "question":  "脱式计算。\n6×9+37  68-(18+16)  (83-35)÷8  43-9×3",
+        "options":  [
+
+                    ],
+        "answer":  "91;34;6;16",
+        "solution":  "【分析】6×9+37先算乘法，再算加法;68-(18+16)先算小括号里面的加法，再算小括号外面的减法;(83-35)÷8先算小括号里面的减法，再算小括号外面的除法;43-9×3先算乘法，再算减法;据此解答。\n\n【详解】6×9+37=54+37=91;68-(18+16)=68-34=34;(83-35)÷8=48÷8=6;43-9×3=43-27=16。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算",
+                                 "乘加",
+                                 "乘减混合运算"
+                             ],
+        "source":  "24-25 二年级下·山西长治·期中"
+    },
+    {
+        "id":  "165",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "计算题",
+        "difficulty":  0.65,
+        "question":  "脱式计算。\n63-34+26  42÷7×5  3+3×8  54÷(7+2)",
+        "options":  [
+
+                    ],
+        "answer":  "55;30;27;6",
+        "solution":  "【分析】在没有括号的算式里，只有加，减法或只有乘，除法，要从左往右计算;在没有括号的算式里，如果既有乘，除法，又有加，减法，要先算乘，除法，再算加，减法;有括号的算式里，要先算括号里面的，再算括号外面的。第1题：从左往右计算;第2题：从左往右计算;第3题：先算乘法，再算加法;第4题：先算加法，再算除法。\n\n【详解】63-34+26=29+26=55;42÷7×5=6×5=30;3+3×8=3+24=27;54÷(7+2)=54÷9=6。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算",
+                                 "乘加",
+                                 "乘减混合运算",
+                                 "表内乘除混合运算"
+                             ],
+        "source":  "24-25 二年级下·山东临沂·期中"
+    },
+    {
+        "id":  "166",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "计算题",
+        "difficulty":  0.65,
+        "question":  "计算。\n2×9÷3  65-30÷5  76-(28+19)  72÷8÷3",
+        "options":  [
+
+                    ],
+        "answer":  "6;59;29;3",
+        "solution":  "【分析】四则混合运算的运算法则：在没有括号的算式里，如果只有加减法或者只有乘除法，要从左往右依次计算；在没有括号的算式里，如果既有乘除法又有加减法，要先算乘除法，再算加减法；在有括号的算式里，要先算括号里面的，再算括号外面的。第1题先算乘法，再算除法；第2题先算除法，再算减法；第3题先算括号里面的加法，再算括号外面的减法；第4题从左往右依次计算。\n\n【详解】2×9÷3=18÷3=6；65-30÷5=65-6=59；76-(28+19)=76-47=29；72÷8÷3=9÷3=3。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算",
+                                 "除加",
+                                 "除减混合运算",
+                                 "表内乘除混合运算",
+                                 "表内连乘",
+                                 "连除运算"
+                             ],
+        "source":  "24-25 二年级下·河南南阳·期中"
+    },
+    {
+        "id":  "167",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "计算题",
+        "difficulty":  0.65,
+        "question":  "按运算顺序计算。\n6+3×9  (42+14)÷7  35+21÷7\n65-30÷5  45÷(3×3)  72÷8÷3",
+        "options":  [
+
+                    ],
+        "answer":  "33;8;38;59;5;3",
+        "solution":  "【分析】在没有括号的算式里，只有加、减法或只有乘、除法，要从左往右计算；在没有括号的算式里，如果既有乘、除法，又有加、减法，要先算乘、除法，再算加、减法；有括号的算式里，要先算括号里面的，再算括号外面的。第一行第1题先算乘法，再算加法；第2题先算加法，再算除法；第3题先算除法，再算加法。第二行第1题先算除法，再算减法；第2题先算括号里面的乘法，再算括号外面的除法；第3题从左往右计算。\n\n【详解】6+3×9=6+27=33；(42+14)÷7=56÷7=8；35+21÷7=35+3=38；65-30÷5=65-6=59；45÷(3×3)=45÷9=5；72÷8÷3=9÷3=3。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算",
+                                 "除加",
+                                 "除减混合运算",
+                                 "乘加",
+                                 "乘减混合运算",
+                                 "表内连乘",
+                                 "连除运算"
+                             ],
+        "source":  "24-25二年级下·湖南衡阳·期中"
+    },
+    {
+        "id":  "168",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "计算题",
+        "difficulty":  0.65,
+        "question":  "按运算顺序计算。\n56-(30+12)  60+40÷8  (25-18)×8",
+        "options":  [
+
+                    ],
+        "answer":  "14;65;56",
+        "solution":  "【分析】在没有括号的算式里，只有加，减法或只有乘，除法，要从左往右计算;在没有括号的算式里，如果既有乘，除法，又有加，减法，要先算乘，除法，再算加，减法;有括号的算式里，要先算括号里面的，再算括号外面的。第1题：先算加法，再算减法;第2题先算除法，再算加法;第3题先算减法，再算乘法。\n\n【详解】56-(30+12)=56-42=14;60+40÷8=60+5=65;(25-18)×8=7×8=56。",
+        "knowledge_points":  [
+                                 "除加",
+                                 "除减混合运算",
+                                 "带有小括号的混合运算"
+                             ],
+        "source":  "24-25 二年级下·广西玉林·期中"
+    },
+    {
+        "id":  "169",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "计算题",
+        "difficulty":  0.65,
+        "question":  "列综合算式并计算结果。\n被除数是15与3的差，除数是4，商是多少。",
+        "options":  [
+
+                    ],
+        "answer":  "(15-3)÷4=3",
+        "solution":  "【分析】根据题意，被除数/除数=商,15与3的差除以4，则计算减法的时候需要加上小括号，最后计算除法，据此列式后求出商即可。\n\n【详解】(15-3)÷4=12÷4=3，商是3。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算"
+                             ],
+        "source":  "24-25 二年级下·河南南阳·期中"
+    },
+    {
+        "id":  "170",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "有一袋糖果，分给9个同学，每人5块，还剩35块。这袋糖果原来有多少块。\n答：这袋糖果原来有( )块。",
+        "options":  [
+
+                    ],
+        "answer":  "80",
+        "solution":  "【分析】根据题意，每人分到的数量和分的人数相乘，求出分出糖果的数量，再加上剩下的数量，就是原来糖果的数量。\n\n【详解】5×9+35=45+35=80(块)，答：这袋糖果原来有80块。",
+        "knowledge_points":  [
+                                 "乘加",
+                                 "乘减混合运算"
+                             ],
+        "source":  "24-25 二年级下·广东潮州·期末"
+    },
+    {
+        "id":  "171",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "一本60页的故事书，小丁每天看9页，已经看了24页，剩下的还要看几天。",
+        "options":  [
+
+                    ],
+        "answer":  "4天",
+        "solution":  "【分析】根据题意，先用故事书的总页数减去已经看了的页数，计算出剩下的页数，再用剩下的页数除以每天看的页数，即可求出还要看的天数。\n\n【详解】(60-24)÷9=36÷9=4(天)，答：剩下的还要看4天。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算"
+                             ],
+        "source":  "24-25 二年级下·浙江台州·期末"
+    },
+    {
+        "id":  "172",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "小灵和她的7个同学一起折了56朵花，平均每人折了多少朵花。",
+        "options":  [
+
+                    ],
+        "answer":  "7朵",
+        "solution":  "【分析】根据题意，小灵加上她的7个同学，先求出一共有多少人，再用一起折花的朵数除以总人数，求出平均每人折了多少朵花。\n\n【详解】56÷(1+7)=56÷8=7(朵)，答：平均每人折了7朵花。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算"
+                             ],
+        "source":  "24-25 二年级下·浙江台州·期末"
+    },
+    {
+        "id":  "173",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "超市要将52个菠萝装到箱子里，大箱限装8个，小箱限装6个，怎么装才能把菠萝正好装完。",
+        "options":  [
+
+                    ],
+        "answer":  "用2个大箱和6个小箱，或者用5个大箱和2个小箱",
+        "solution":  "【分析】根据题意，只要大箱和小箱里装菠萝的总数量是52个即可。用大箱装菠萝的数量×大箱的个数+小箱装菠萝的数量×小箱的个数=菠萝的总数量，计算即可。\n\n【详解】8×2+6×6=16+36=52(个);或8×5+6×2=40+12=52(个);答：可以用2个大箱和6个小箱，或者用5个大箱和2个小箱能把菠萝正好装完。",
+        "knowledge_points":  [
+                                 "乘加",
+                                 "乘减混合运算"
+                             ],
+        "source":  "24-25 二年级下·福建厦门·期末"
+    },
+    {
+        "id":  "174",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "养殖场白兔有20只，灰兔有12只。如果把这些兔子放在4间兔舍里，平均每间兔舍放几只兔子。",
+        "options":  [
+
+                    ],
+        "answer":  "8只",
+        "solution":  "【分析】根据题意，先用加法计算出白兔和灰兔一共有多少只，再用兔子的总数量除以兔舍的数量，即可求出每间兔舍里兔子的数量。\n\n【详解】(20+12)÷4=32÷4=8(只)，答：平均每间兔舍放8只兔子。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算"
+                             ],
+        "source":  "24-25 二年级下·江西赣州·期末"
+    },
+    {
+        "id":  "175",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "二年级共有50人，参加绘画小组的有20人，剩下的同学参加舞蹈小组，舞蹈小组每组6人，可以分成几组。",
+        "options":  [
+
+                    ],
+        "answer":  "5组",
+        "solution":  "【分析】由题意可知：用二年级共有的人数减去参加绘画小组的人数，即是剩下参加舞蹈小组的人数，再除以舞蹈小组每组的人数，即是可以分成的组数;据此解答。\n\n【详解】由分析可得:(50-20)÷6=30÷6=5(组),答：可以分成5组。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算",
+                                 "用6的乘法口诀求商",
+                                 "整十数之间的加减法"
+                             ],
+        "source":  "24-25 二年级下·湖北孝感·期末"
+    },
+    {
+        "id":  "176",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "\"夏九九\"是以夏至那一天为起点，每九天为一个九，每年9个九，一共81天。\"夏九九\"已经过了18天，还剩几个星期。",
+        "options":  [
+
+                    ],
+        "answer":  "9个星期",
+        "solution":  "【分析】根据题意，先用总天数减去已经过去的天数，计算出还剩多少天，再用剩下的天数除以每个星期的天数(7天)，商就是剩余的星期数。\n\n【详解】(81-18)÷7=63÷7=9，答：还剩9个星期。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算"
+                             ],
+        "source":  "24-25 二年级下·浙江台州·期末"
+    },
+    {
+        "id":  "177",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "某小区新建了一幢楼房，一共6层，每层可以住8户。现已搬进了35户，还有多少户没有搬。",
+        "options":  [
+
+                    ],
+        "answer":  "13户",
+        "solution":  "【分析】先根据乘法的意义，层数×每层可以住的户数=总共可以住的户数，再根据减法的意义，总共可以住的户数-已经搬进去的户数=剩余未搬的户数，由此列出一个综合算式并算出答案即可解答。\n\n【详解】6×8=48(户)，48-35=13(户)，答：还有13户没有搬。",
+        "knowledge_points":  [
+                                 "乘加",
+                                 "乘减混合运算",
+                                 "表内乘除法解决实际问题"
+                             ],
+        "source":  "24-25 二年级下·湖北孝感·期末"
+    },
+    {
+        "id":  "178",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "小新买草莓花了多少钱。\n![](images/65c26917b9e486b96ae4a8589e6ac2d9.png)",
+        "options":  [
+
+                    ],
+        "answer":  "36元",
+        "solution":  "【分析】根据题意，先用小红买草莓花的钱数除以她买草莓的质量，求出每千克草莓的钱数，再和小新买的质量相乘，就是小新花的钱数。\n\n【详解】30÷5×6=6×6=36(元)，答：小新买草莓花了36元。",
+        "knowledge_points":  [
+                                 "图文问题",
+                                 "表内乘除混合运算"
+                             ],
+        "source":  "24-25 二年级下·江西赣州·期末"
+    },
+    {
+        "id":  "179",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "![](images/0f5a61d710d8b66aed19d35c3259e776.png)\n(1)王阿姨用50元，购买9支玫瑰花后，应找回多少钱。\n(2)王阿姨购买3支向日葵的钱，正好可以买6支康乃馨，一支康乃馨多少钱。",
+        "options":  [
+
+                    ],
+        "answer":  "5元;4元",
+        "solution":  "【分析】(1)先用每支玫瑰花的价钱乘购买的支数，求出9支玫瑰花的价钱，再用50元钱减去9支玫瑰花的价钱，即可求出应找回多少钱。(2)先用每支向日葵的价钱乘购买的支数，求出3支向日葵的价钱，再用3支向日葵的价钱(即6支康乃馨的价钱)除以购买的康乃馨的支数，即可求出一支康乃馨多少钱。\n\n【详解】(1)50-5×9=50-45=5(元),答：应找回5元钱。(2)8×3÷6=24÷6=4(元),答：一支康乃馨4元钱。",
+        "knowledge_points":  [
+                                 "表内乘除混合运算",
+                                 "乘加",
+                                 "乘减混合运算"
+                             ],
+        "source":  "24-25 二年级下·山东济宁·期中"
+    },
+    {
+        "id":  "180",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "面包店师傅一共烤了6盘面包，其中5盘每盘9个，还有1盘8个。面包店师傅一共烤了多少个面包。\n答：面包店师傅一共烤了( )个面包。",
+        "options":  [
+
+                    ],
+        "answer":  "53",
+        "solution":  "【分析】题目中给出6盘面包，其中5盘每盘9个，还有1盘8个。需要计算面包总数量，先用乘法求5个9的和，然后再加上8，求出和就是面包的总数量。\n\n【详解】9×5+8=45+8=53(个)，答：面包店师傅一共烤了53个面包。",
+        "knowledge_points":  [
+                                 "表内乘加",
+                                 "乘减"
+                             ],
+        "source":  "24-25二年级下·四川成都·期中"
+    },
+    {
+        "id":  "181",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "学校合唱队参加表演，如果每行站8人，可以站成3行，如果站成4行，每行站多少人。",
+        "options":  [
+
+                    ],
+        "answer":  "6人",
+        "solution":  "【分析】由题意可知：用每行站的人数乘3行，即是合唱队参加表演的总人数;用总人数除以4行，即是每行站的人数;据此解答。\n\n【详解】由分析可得:8×3÷4=24÷4=6(人),答：每行站6人。",
+        "knowledge_points":  [
+                                 "表内乘除混合运算",
+                                 "用6的乘法口诀求商",
+                                 "8的乘法口诀及应用"
+                             ],
+        "source":  "24-25 二年级下·山东菏泽·期中"
+    },
+    {
+        "id":  "182",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "一辆公交车上原来有29人，到少年宫站后下去14人，上来9人。现在公交车上有多少人。",
+        "options":  [
+
+                    ],
+        "answer":  "24人",
+        "solution":  "【分析】由题意可知：用公交车上原来的人数减去到少年宫站下去的人数，再加上上来的人数，即是现在公交车上有的人数;据此解答。\n\n【详解】由分析可得:29-14+9=15+9=24(人),答：现在公交车上有24人。",
+        "knowledge_points":  [
+                                 "100以内数的加减混合运算",
+                                 "一位数与两位数的进位加法",
+                                 "两位数与两位数的不退位减法"
+                             ],
+        "source":  "24-25 二年级下·山东菏泽·期中"
+    },
+    {
+        "id":  "183",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "李大伯要做45个竹篮子，已经做好了10个。剩下的要7天做完，平均每天要做多少个。",
+        "options":  [
+
+                    ],
+        "answer":  "5个",
+        "solution":  "【分析】由题意可知：用李大伯要做的竹篮子数减去已经做好的，即是剩下还要做的竹篮子数;用剩下的竹篮子数除以天数，即是平均每天需要做的竹篮子数;据此解答。\n\n【详解】由分析可得:(45-10)÷7=35÷7=5(个),答：平均每天要做5个。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算",
+                                 "用7~9的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·山东济宁·期中"
+    },
+    {
+        "id":  "184",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "器材室里有6盒乒乓球，每盒有8个，张老师拿走了18个，还剩几个乒乓球。",
+        "options":  [
+
+                    ],
+        "answer":  "30个",
+        "solution":  "【分析】由题意可知：用乒乓球每盒的个数乘盒数，再减去张老师拿走的个数，即是还剩乒乓球的个数;据此解答。\n\n【详解】由分析可得:8×6-18=48-18=30(个),答：还剩30个乒乓球。",
+        "knowledge_points":  [
+                                 "乘加",
+                                 "乘减混合运算",
+                                 "8的乘法口诀及应用",
+                                 "两位数与两位数的不退位减法"
+                             ],
+        "source":  "24-25 二年级下·山东济宁·期中"
+    },
+    {
+        "id":  "185",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "军军去商店买了1支钢笔和1个书包，一共付了50元，售货员阿姨找给军军2元。如果买1个书包的钱正好可以买7支钢笔，那么1个书包和1支钢笔分别是多少元。",
+        "options":  [
+
+                    ],
+        "answer":  "42元;6元",
+        "solution":  "【分析】根据题意，先用付出的钱数-找回的钱数=一共花的钱数。1个书包的钱数可以买7支钢笔，把书包换成钢笔，即7支钢笔加上原来的1支钢笔，也就是一共花的钱数可以买8支钢笔。用一共花的钱数除以可以买钢笔的总数量，就是每支钢笔的钱数，再用总钱数-1支钢笔的钱数=1个书包的钱数。\n\n【详解】50-2=48(元),48÷(7+1)=48÷8=6(元),48-6=42(元),答:1个书包42元,1支钢笔6元。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算"
+                             ],
+        "source":  "24-25 二年级下·山东临沂·期中"
+    },
+    {
+        "id":  "186",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "李老师准备买5本笔记本奖励学生，这种笔记本6元一本，现在购买6本及以上每本优惠1元，你认为李老师怎么买更优惠。请用算式说明理由。",
+        "options":  [
+
+                    ],
+        "answer":  "买6本更优惠;算式见详解",
+        "solution":  "【分析】根据题意，分别计算出买5本和买6本各需要多少钱，再比较钱数的大小选择更优惠的方案即可。买5本时：每本的钱数×本数=总钱数;买6本时：先计算出优惠后每本的钱数，再和买的本数相乘，求出总钱数。\n\n【详解】买5本:6×5=30(元);买6本:(6-1)×6=5×6=30(元);两种方案总费用均为30元，但购买6本可多获得1本笔记本。答：李老师买6本更优惠。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算",
+                                 "6的乘法口诀及应用"
+                             ],
+        "source":  "24-25 二年级下·湖北黄冈·期中"
+    },
+    {
+        "id":  "187",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "周日包子店包了56个肉包子和38个豆沙包子，上午卖了79个包子，还剩多少个包子。",
+        "options":  [
+
+                    ],
+        "answer":  "15个",
+        "solution":  "【分析】根据题意，先用肉包子的数量和豆沙包子的数量相加，计算出一共包了多少个包子，再减去上午卖出的数量，即可求出还剩的数量。\n\n【详解】56+38-79=94-79=15(个)，答：还剩15个包子。",
+        "knowledge_points":  [
+                                 "100以内数的加减混合运算"
+                             ],
+        "source":  "24-25 二年级下·湖北黄冈·期中"
+    },
+    {
+        "id":  "188",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "把30颗糖平均分给红红和她的5个朋友，每人分多少颗。",
+        "options":  [
+
+                    ],
+        "answer":  "5颗",
+        "solution":  "【分析】根据题意，先用加法计算出总人数，再用糖的总数量除以平均分的总人数，即可求出每人应分的数量。\n\n【详解】30÷(1+5)=30÷6=5(颗)，答：每人分5颗。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算"
+                             ],
+        "source":  "24-25 二年级下·湖北黄冈·期中"
+    },
+    {
+        "id":  "189",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "音乐兴趣小组6人一组正好可以分成4组，如果要改成3人一组，那么能分成几组。",
+        "options":  [
+
+                    ],
+        "answer":  "8组",
+        "solution":  "【分析】根据题意，先用原来每组的人数和组数相乘，求出总人数，再用总人数除以改后每组的人数，即可求出改后能分成的组数。\n\n【详解】6×4÷3=24÷3=8(组)，答：能分成8组。",
+        "knowledge_points":  [
+                                 "表内乘除混合运算"
+                             ],
+        "source":  "24-25二年级下·湖北黄冈·期中"
+    },
+    {
+        "id":  "190",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "丁丁在计算\"4+□×9\"时，弄错了运算顺序，先算加法后算乘法了，结果得数是63。正确的得数应该是多少。",
+        "options":  [
+
+                    ],
+        "answer":  "31",
+        "solution":  "【分析】根据错误的运算顺序，先求出方框中的数(用63除以9，求出商，再减去4，求出差就是方框中的数),再代入原式按正确顺序计算。\n\n【详解】63÷9-4=7-4=3，因此,□=3。按正确顺序计算原式:4+3×9=4+27=31，答：正确的得数应该是31。",
+        "knowledge_points":  [
+                                 "表内乘加",
+                                 "乘减",
+                                 "除加",
+                                 "除减混合运算",
+                                 "用7~9的乘法口诀求商"
+                             ],
+        "source":  "24-25二年级下·河北邯郸·期中"
+    },
+    {
+        "id":  "191",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "二(2)班图书角有12本童话书,16本科技书，平均分给4个小组，每个小组分多少本书。",
+        "options":  [
+
+                    ],
+        "answer":  "7本",
+        "solution":  "【分析】由题意可知：把童话书和科技书的本数相加，即是书的总本数，用书的总本数除以组数，即是每个小组分的本数;据此解答。\n\n【详解】由分析可得:(12+16)÷4=28÷4=7(本),答：每个小组分7本书。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算",
+                                 "用7~9的乘法口诀求商",
+                                 "两位数与两位数的不进位加法"
+                             ],
+        "source":  "24-25 二年级下·河北邯郸·期中"
+    },
+    {
+        "id":  "192",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "小华和爸爸、妈妈、爷爷、奶奶一起去海洋公园玩，海洋公园门票如右图所示。成人票：9元/人，儿童票：5元/人。用40元钱买5个人的票够吗。",
+        "options":  [
+
+                    ],
+        "answer":  "不够",
+        "solution":  "【分析】根据题意，他们需要买4张成人票和1张儿童票。则先用每张成人票的钱数和要买的张数相乘，求出买成人票花的钱数，再和1张儿童票的钱数相加，计算出一共需要花的钱数，最后和40元比较大小，需要的钱数大于40元不够，小于或等于40元够。\n\n【详解】9×4+5=36+5=41(元)，41 > 40，答：用40元钱买5个人的票不够。",
+        "knowledge_points":  [
+                                 "乘加",
+                                 "乘减混合运算",
+                                 "100以内数的比大小"
+                             ],
+        "source":  "24-25 二年级下·湖南衡阳·期中"
+    },
+    {
+        "id":  "193",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "二(1)班有男生22人，女生20人，平均分成6组做科学实验，每组有多少人。",
+        "options":  [
+
+                    ],
+        "answer":  "7人",
+        "solution":  "【分析】根据题意，先将男生和女生的人数相加，计算出总人数，再用总人数除以平均分的组数，即可求出每组的人数。\n\n【详解】(22+20)÷6=42÷6=7(人)，答：每组有7人。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算"
+                             ],
+        "source":  "24-25 二年级下·湖南衡阳·期中"
+    },
+    {
+        "id":  "194",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "人脸识别系统使社区变得越来越\"智慧\"。民主社区计划给8个小区安装人脸识别系统，每个小区安装9套，已经安装了56套，还剩多少套没有安装。",
+        "options":  [
+
+                    ],
+        "answer":  "16套",
+        "solution":  "【分析】用小区数量乘每个小区安装的套数，计算出一共需要安装的套数，再减去已安装的套数，得到剩余套数。\n\n【详解】9×8-56=72-56=16(套)，答：还剩下16套没有安装。",
+        "knowledge_points":  [
+                                 "乘加",
+                                 "乘减混合运算"
+                             ],
+        "source":  "24-25 二年级下·河南南阳·期中"
+    },
+    {
+        "id":  "195",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "比赛前，王老师为二(1)班同学在面包房预定了90个面包，已经取回了36个。剩下的平均装成9袋，每袋装几个。",
+        "options":  [
+
+                    ],
+        "answer":  "6个",
+        "solution":  "【分析】由题意可知：用预定的面包数减去已经取回的，是剩下的，再除以袋数，即是每袋装的个数;据此解答。\n\n【详解】由分析可得:(90-36)÷9=54÷9=6(个),答：每袋装6个。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算",
+                                 "用7~9的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·河南漯河·期中"
+    },
+    {
+        "id":  "196",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "比赛期间，二(1)班买了9提椰子水，每提6瓶，喝了27瓶，还剩多少瓶。",
+        "options":  [
+
+                    ],
+        "answer":  "27瓶",
+        "solution":  "【分析】由题意可知：用每提的瓶数乘提数，即是共买的椰子水瓶数，减去喝了的瓶数，即是还剩的瓶数;据此解答。\n\n【详解】由分析可得:9×6-27=54-27=27(瓶),答：还剩27瓶。",
+        "knowledge_points":  [
+                                 "乘加",
+                                 "乘减混合运算",
+                                 "9的乘法口诀及应用",
+                                 "两位数与两位数的退位减法"
+                             ],
+        "source":  "24-25 二年级下·河南漯河·期中"
+    },
+    {
+        "id":  "197",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "运动会的开幕式上，各班学生排队进场。二(1)班男生有17人，女生有19人，如果每队9人，可以排成几队。",
+        "options":  [
+
+                    ],
+        "answer":  "4队",
+        "solution":  "【分析】根据题意，先用加法计算出男生和女生一共有多少人，再用总人数除以每队的人数，即可求出排成的队数。\n\n【详解】(17+19)÷9=36÷9=4(队),答：可以排成4队。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算"
+                             ],
+        "source":  "24-25二年级下·河南漯河·期中"
+    },
+    {
+        "id":  "198",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "二(1)班有26名男同学，19名女同学。如果每9名同学分成一个学习小组，全班可以分成几个学习小组。",
+        "options":  [
+
+                    ],
+        "answer":  "5个",
+        "solution":  "【分析】根据题意，先用加法计算出男同学和女同学一共有多少人，再用总人数除以每个学习小组的人数，商就是可以分成的组数。\n\n【详解】(26+19)÷9=45÷9=5(个)，答：全班可以分成5个学习小组。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算"
+                             ],
+        "source":  "24-25 二年级下·河南南阳·期中"
+    },
+    {
+        "id":  "199",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "某水果店一共进了60个苹果，上午卖了25个，下午卖了16个，还剩多少个。(用两种方法解答)",
+        "options":  [
+
+                    ],
+        "answer":  "19个",
+        "solution":  "【分析】方法一：用进的苹果的总个数分别减去上午卖的个数和下午卖的个数，即可求出还剩多少个。方法二：先用上午卖的个数加上下午卖的个数，求出一共卖的个数，再用进的苹果总个数减去一共卖的个数，即可求出还剩多少个。因为要先求一共卖的个数，因此加法算式用括号括起来。\n\n【详解】方法一:60-25-16=35-16=19(个);方法二:60-(25+16)=60-41=19(个);答：还剩19个。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算",
+                                 "100以内数的连减运算"
+                             ],
+        "source":  "24-25 二年级下·河南南阳·期中"
+    },
+    {
+        "id":  "200",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "二(1)班有男生22人，女生20人，每6人为一个合作学习小组，一共可以分成多少个合作学习小组。",
+        "options":  [
+
+                    ],
+        "answer":  "7个",
+        "solution":  "【分析】根据题意，先用加法计算出男生和女生一共有多少人，再用总人数除以每个学习小组的人数，商就是可以分成的学习小组数量。\n\n【详解】(22+20)÷6=42÷6=7(个),答：一共可以分成7个合作学习小组。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算"
+                             ],
+        "source":  "24-25 二年级下·湖北武汉·期中"
+    },
+    {
+        "id":  "201",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "把55-20=35和35÷7=5合并成一个综合算式是( )。",
+        "options":  [
+                        "55-20÷7",
+                        "55-35÷7",
+                        "(55-20)÷7"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】将两个算式合并时，需先计算减法再算除法。根据运算顺序，减法需加括号以确保优先计算。原式55-20=35的结果35需作为被除数，即(55-20)÷7=5。\n\n【详解】A。55-20÷7中未加括号导致先算除法，再算减法，不符合题意;B。55-35÷7中的35未替换为原式结果，不符合题意;C。(55-20)÷7中加括号先算减法，再算除法，符合题意。即，把55-20=35和35÷7=5合并列成一个综合算式是(55-20)÷7。故答案为:C",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算"
+                             ],
+        "source":  "24-25二年级下·陕西延安·期末"
+    },
+    {
+        "id":  "202",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "丽丽在计算\"3+( )×8\"时弄错了运算顺序，先算加法后乘法，结果得数是64，正确的得数应该是( )。",
+        "options":  [
+                        "33",
+                        "43",
+                        "23"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】根据题意，先用64除以8，求出3+( )的和，再减去3，求出( )表示的数，最后按照先算乘法，再算加法的运算顺序，求出正确结果即可解答。\n\n【详解】64÷8-3=8-3=5,3+5×8=3+40=43，丽丽在计算\"3+( )×8\"时弄错了运算顺序，先算加法后算乘法，结果得数是64，正确的得数应该是43。故答案为:B",
+        "knowledge_points":  [
+                                 "除加",
+                                 "除减混合运算",
+                                 "乘加",
+                                 "乘减混合运算"
+                             ],
+        "source":  "24-25 二年级下·湖北黄石·期末"
+    },
+    {
+        "id":  "203",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "把\"12-5=7,28÷7=4\"合并成一个综合算式，正确的是( )。",
+        "options":  [
+                        "12-5÷7",
+                        "28÷7-5",
+                        "28÷(12-5)"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】将第二个算式中的7替换为第一个算式12-5，最终的结果是求两个数的商，综合算式中有除法和减法，要保证先算减法，再算除法，减法要加小括号，逐项分析各个选项，找出正确答案即可解答。\n\n【详解】A。12-5÷7，先算除法，再算减法，不符合题意;B。28÷7-5，先算除法，再算减法，不符合题意;C。28÷(12-5),先算减法，再算除法，符合题意。把\"12-5=7,28÷7=4\"合并成一个综合算式，正确的是28÷(12-5)。故答案为:C",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算"
+                             ],
+        "source":  "24-25二年级下·湖北武汉·期末"
+    },
+    {
+        "id":  "204",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "文具店新进了7盒铅笔，每盒8支。求还剩多少支。如果列式(7-5)×8，那么横线上需要填的信息是( )。",
+        "options":  [
+                        "卖出5支",
+                        "卖出5盒",
+                        "又进了5盒"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】根据题意，算式(7-5)×8,7表示新进的铅笔盒数,8表示每盒的支数，每盒的支数和剩下的盒数相乘是剩下的支数，也就是7-5的结果表示还剩的盒数，由此解答。\n\n【详解】由分析可知:7-5=2(盒),铅笔的盒数还剩2盒，只有卖出了5盒符合题意。横线上需要填的正确信息是卖出了5盒。故答案为:B",
+        "knowledge_points":  [
+                                 "\"提问题\"\"填条件\"问题",
+                                 "带有小括号的混合运算"
+                             ],
+        "source":  "24-25二年级下·湖北襄阳·期末"
+    },
+    {
+        "id":  "205",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "把12÷3=4,16+4=20，合并成一个综合算式是( )。",
+        "options":  [
+                        "20-16=4",
+                        "3×4=12",
+                        "16+12÷3=20"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】根据题意，先算除法，再算加法，用16加上12除以3的商，据此解答。\n\n【详解】根据分析:16+12÷3=16+4=20，所以把12÷3=4,16+4=20，合并成一个综合算式是:16+12÷3=20;故答案为:C",
+        "knowledge_points":  [
+                                 "除加",
+                                 "除减混合运算"
+                             ],
+        "source":  "24-25 二年级下·河北邢台·期末"
+    },
+    {
+        "id":  "206",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "在没有括号的算式里，有乘法和加法的计算顺序是( )。",
+        "options":  [
+                        "先算乘法再算加法",
+                        "一定是从左往右算",
+                        "不管按什么顺序算结果不变"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】在没有括号的算式里，只有加减法或只有乘除法的混合运算，从左往右计算;在没有括号的算式里，既有加减法又有乘除法的混合运算，先算乘除法，再算加减法。\n\n【详解】由分析可知：在没有括号的算式里，有乘法和加法的计算顺序是(先算乘法再算加法)。故答案为:A",
+        "knowledge_points":  [
+                                 "无括号的运算顺序"
+                             ],
+        "source":  "24-25 二年级下·云南昭通·期末"
+    },
+    {
+        "id":  "207",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "飞飞原来有40元，买童话书花了22元，买钢笔花了15元。飞飞现在还剩多少钱。下面列式中，错误的是( )。",
+        "options":  [
+                        "40-22-15",
+                        "40-(22+15)",
+                        "40-22+15"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】由题意可知：方法一：用飞飞原来的钱数，减去买童话书花的钱数，再减去买钢笔花的钱数，即是飞飞现在还剩的钱数;方法二：可以先把买童话书和买钢笔花的钱数相加，算出共花了多少钱，再用飞飞原来的钱数减去一共花的钱数，即是飞飞现在还剩的钱数;据此解答。\n\n【详解】由分析可得：方法一:40-22-15=18-15=3(元);方法二:40-(22+15)=40-37=3(元);答：飞飞现在还剩3元钱。AB答案都正确,C错误;故答案为:C",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算",
+                                 "100以内数的连减运算"
+                             ],
+        "source":  "24-25 二年级下·重庆梁平·期末"
+    },
+    {
+        "id":  "208",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "马小虎在计算(80-56)/☐时，漏掉了括号，最后得73，这道算式正确的得数是( )。",
+        "options":  [
+                        "8",
+                        "6",
+                        "3"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】由题意得，马小虎在计算(80-56)/☐时，漏掉了括号，最后得73，即80-56÷□=73。可以先用80减去73算出56÷□的结果，然后再用56除以前面的结果算出□的值。最后再将□的值代入算式(80-56)/☐即可算出正确的结果。\n\n【详解】80-73=7,56÷7=8，即□的值是8。(80-56)÷8=24÷8=3，即正确的得数是3。故答案为:C",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算",
+                                 "除加",
+                                 "除减混合运算"
+                             ],
+        "source":  "24-25三年级下·湖南怀化·期末"
+    },
+    {
+        "id":  "209",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "下面算式中，先算加法的是( )。",
+        "options":  [
+                        "50-12+33",
+                        "4+7×3",
+                        "64÷(2+6)"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】根据四则混合运算的运算法则：在没有括号的算式里，如果只有加减法或者只有乘除法，要从左往右依次计算;在没有括号的算式里，如果既有乘除法又有加减法，要先算乘除法，再算加减法;在有括号的算式里，要先算括号里面的，再算括号外面的，逐个判断每个选项即可解答。\n\n【详解】A。计算该算式时，从左往右依次进行计算:50-12+33=38+33=71，最后算加法，不符合题意;B。计算该算式时，先算乘法再算加法:4+7×3=4+21=25，最后算加法，不符合题意;C。计算该算式时，先算括号内的加法再算括号外的除法:64÷(2+6)=64÷8=8，先算加法，符合题意。故答案为:C",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算",
+                                 "乘加",
+                                 "乘减混合运算",
+                                 "100以内数的加减混合运算"
+                             ],
+        "source":  "24-25二年级下·甘肃庆阳·期末"
+    },
+    {
+        "id":  "210",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "下面算式中，先算加法的是( )。",
+        "options":  [
+                        "18÷(2+4)",
+                        "24-8+6",
+                        "4×6+3"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】混合运算的运算顺序：如果只有加减法或只有乘除法，按照从左到右的顺序计算;如果既有加减法又有乘除法，要先算乘除法，再算加减法;如果有括号，要先算括号里面的，再算括号外面的。据此判断运算顺序，选择即可。\n\n【详解】A。18÷(2+4)先算括号里面的加法，再算括号外面的除法，符合题意;B。24-8+6先算减法，再算加法，不符合题意;C。4×6+3先算乘法，再算加法，不符合题意。故答案为:A",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算",
+                                 "乘加",
+                                 "乘减混合运算",
+                                 "100以内数的加减混合运算"
+                             ],
+        "source":  "24-25 二年级下·山东济宁·期末"
+    },
+    {
+        "id":  "211",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "56中连续减9，减( )次后结果为2。",
+        "options":  [
+                        "8",
+                        "7",
+                        "6",
+                        "4"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】根据题意，求56连续减去几次9结果是2，也就是几个9的和再加上2是56，先用56减去2，再用所得的结果除以9，由此解答。\n\n【详解】根据分析可得:(56-2)÷9=54÷9=6，因此,56中连续减9，减6次后结果为2。故答案为:C.",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算"
+                             ],
+        "source":  "24-25二年级下·浙江绍兴·期末"
+    },
+    {
+        "id":  "212",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "小红家原来有25只鸭子，又买来15只。将这些鸭子平均放在5个笼子里，每个笼子里放几只。下面列式正确的是( )。",
+        "options":  [
+                        "(25-15)×5",
+                        "25-15÷5",
+                        "(25+15)÷5"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】由题意可知：用小红家原有的鸭子数，加上又买来的只数，是现在的鸭子数;现在的鸭子数除以笼子的个数，即是每个笼子里放的鸭子数;根据分析列出算式，找出正确答案;据此解答。\n\n【详解】由分析可得:(25+15)÷5=40÷5=8(只),每个笼子里放8只;故答案为:C",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算"
+                             ],
+        "source":  "24-25 二年级下·重庆秀山·期末"
+    },
+    {
+        "id":  "213",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "算式(8+12)÷4和8+12÷4相比较( )。",
+        "options":  [
+                        "运算顺序不同，结果相同",
+                        "运算顺序相同，结果相同",
+                        "运算顺序不同，结果不同"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】根据四则运算的规则，第一个算式有括号，先算括号内的加法，再算除法;第二个算式没有括号，先算除法，再算加法。运算顺序不同，结果也不同。\n\n【详解】(8+12)÷4=20÷4=5,8+12÷4=8+3=11，所以运算顺序不同，结果也不同。故答案为:C",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算",
+                                 "除加",
+                                 "除减混合运算",
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "24-25二年级下·重庆·期末"
+    },
+    {
+        "id":  "214",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "下列问题中，不能用\"24÷(2×4)\"解决的是( )。",
+        "options":  [
+                        "东东弟弟学会走路了，在围栏里走了4个来回，共走了24米，这个围栏有多长。",
+                        "每套《百科知识》绘本有2本，王老师买4套共花了24元。每本多少元。",
+                        "花样跳绳组有24名学生，每名学生需要发2根跳绳，每根跳绳4元，买这些跳绳需要花多少钱。"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】A。已知4个来回共24米，先用2乘4算出4个来回相当于8个围栏的长度，然后用24米除以8，即是这个围栏的长度;B。已知4套共24元，每套2本;先用每套的本数乘套数，求出一共有多少本，再用24元除以总本数，求出每本多少钱;C。24名学生，每人2根跳绳，每根4元，先用24×2求出需买跳绳的数量，再乘每根跳绳的价钱，即可求出买这些跳绳需花的钱数。\n\n【详解】A。求围栏的长度，列式为:24÷(2×4),不符合题意;B。求每本的钱数，列式为:24÷(2×4),不符合题意;C。求出买这些跳绳需花的钱数，列式为:24×2×4，不能用\"24÷(2×4)\"解决问题，符合题意。故答案为:C",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算"
+                             ],
+        "source":  "24-25 二年级下·江西赣州·期末"
+    },
+    {
+        "id":  "215",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "\"赵海原来有100元钱，买一本故事书花了34元，买一支钢笔花了22元。赵海现在还剩下多少钱。\"有一位同学是这样想的：先求买一本故事书和一支钢笔一共要多少元，再求还剩下多少元。下面的算式中跟这位同学的想法相同的是( )。",
+        "options":  [
+                        "100-34-22",
+                        "100-(34+22)",
+                        "100-34+22"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】根据题意可知：还剩下的钱数=赵海原有的钱数-(买故事书花的钱数+买钢笔花的钱数)。\n\n【详解】由分析可得：列式是100-(34+22)。故答案为:B",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算"
+                             ],
+        "source":  "24-25 二年级下·浙江温州·期末"
+    },
+    {
+        "id":  "216",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "下面的问题中，不能用(40-4)÷9解决的是( )。",
+        "options":  [
+                        "一本书40页，小明已经看了4页，剩下的每天看9页，还要几天才能看完。",
+                        "兰兰买了9本日记本，每本4元，付了40元，应找回多少元。",
+                        "小军买了9瓶酸奶，付给售货员40元，找回4元，每瓶多少元。"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】A。先用书的总页数减去已经看的页数，求出剩下的页数，再用剩下的页数除以每天看的页数，即可求出还要几天才能看完;B。先用每本日记本的价钱乘购买的本数，求出买日记本花的钱，再用付的钱数减去买日记本花的钱数，即可求出应找回多少元;C。先用付的钱数减去找回的钱数，求出买酸奶花的钱数，再用买酸奶花的钱数除以购买的瓶数，即可求出每瓶多少元。\n\n【详解】A。列式为:(40-4)÷9，因此可以用(40-4)÷9解决;B。列式为:40-4×9，不能用(40-4)÷9解决;C。列式为:(40-4)÷9，因此可以用(40-4)÷9解决。故答案为:B",
+        "knowledge_points":  [
+                                 "乘加",
+                                 "乘减混合运算",
+                                 "带有小括号的混合运算",
+                                 "解决多步计算的实际问题"
+                             ],
+        "source":  "24-25 二年级下·浙江温州·期末"
+    },
+    {
+        "id":  "217",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "一本笔记本8元，小红买了3本，小芳买了5本，两人一共花了多少钱。列式正确的是( )。",
+        "options":  [
+                        "8×3×5",
+                        "8×5-8×3",
+                        "8×(3+5)"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】由题意得，一本笔记本8元，小红买了3本，小芳买了5本，两人一共花了多少钱，可以先用加法算出他们一共买了多少本笔记本，然后再乘上8即可算出两人一共花了多少钱。列式为:(3+5)×8。\n\n【详解】由分析得，求两人一共花了多少钱，列式为:(3+5)×8。故答案为:C",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算"
+                             ],
+        "source":  "24-25 三年级下·天津津南·期末"
+    },
+    {
+        "id":  "218",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "下列算式中，先算加法的是( )。",
+        "options":  [
+                        "25-12+48",
+                        "9×(4+3)",
+                        "27+3×7"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】整数混合运算中，同级运算时，从左到右依次计算;两级运算时，先算乘除，后算加减;有括号时，先算括号里面的，再算括号外面的。逐项分析。\n\n【详解】A。先算减法再算加法，不符合。B。先算加法再算乘法，符合。C。先算乘法再算加法，不符合。先算加法的是9×(4+3)。故答案为:B",
+        "knowledge_points":  [
+                                 "100以内数的加减混合运算",
+                                 "乘加",
+                                 "乘减混合运算",
+                                 "带有小括号的混合运算"
+                             ],
+        "source":  "24-25 二年级下·山东济南·期中"
+    },
+    {
+        "id":  "219",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "计算(32-16)÷8时，应先算( )法，最后的结果是( );如果去掉括号，应先算( )法，最后的结果是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "减;2;除;30",
+        "solution":  "【分析】根据四则运算顺序,(32-16)÷8，有括号时先算括号内的减法，再算括号外的除法;32-16÷8，去掉括号后，需先算除法，再算减法。\n\n【详解】(32-16)÷8=16÷8=2,32-16÷8=32-2=30，即，计算(32-16)÷8时，应先算减法，最后的结果是2;如果去掉括号，应先算除法，最后的结果是30。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算",
+                                 "除加",
+                                 "除减混合运算"
+                             ],
+        "source":  "24-25 二年级下·陕西延安·期末"
+    },
+    {
+        "id":  "220",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "一本故事书，小明每天看5页，看了9天，还剩28页，这本书共有( )页。",
+        "options":  [
+
+                    ],
+        "answer":  "73",
+        "solution":  "【分析】根据题意可知：用看的天数乘每天看的数量然后再加上剩余的页数。9×5+28=45+28=73(页),则这本书共有73页。",
+        "knowledge_points":  [
+                                 "乘加",
+                                 "乘减混合运算"
+                             ],
+        "source":  "24-25 二年级下·云南红河·期末"
+    },
+    {
+        "id":  "221",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "小玲把16颗糖果平均分给她和她的3个好朋友，每个分得( )颗糖果。",
+        "options":  [
+
+                    ],
+        "answer":  "4",
+        "solution":  "【分析】由题意可知：用16颗糖果数除以小玲和她3个好朋友共4人，即可得出每个分得的糖果数;据此解答。\n\n【详解】由分析可得:16÷(3+1)=16÷4=4(颗),小玲把16颗糖果平均分给她和她的3个好朋友，每个分得4颗糖果。",
+        "knowledge_points":  [
+                                 "整数平均分的意义及应用",
+                                 "用2~5的乘法口诀求商",
+                                 "带有小括号的混合运算"
+                             ],
+        "source":  "24-25 二年级下·云南红河·期末"
+    },
+    {
+        "id":  "222",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "根据42-34=8,72÷8=9，列出综合算式是:( )。",
+        "options":  [
+
+                    ],
+        "answer":  "72÷(42-34)=9",
+        "solution":  "【分析】将两个分步算式合并成一个综合算式时，需要找到第二个算式中的哪个数是由第一个算式得到的，并用第一个算式代替这个数;本题中第二个算式中的8是由42-34得到的，因此将72÷8中的8替换为42-34即可;这道题先算减法，再算除法，所以要添加小括号。\n\n【详解】由分析可得:72÷(42-34)=72÷8=9，根据42-34=8,72÷8=9，列出综合算式是:72÷(42-34)=9。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算"
+                             ],
+        "source":  "24-25 二年级下·云南红河·期末"
+    },
+    {
+        "id":  "223",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "小华和小东一共有50枚邮票，小东比小华少10枚，小东有邮票( )枚。",
+        "options":  [
+
+                    ],
+        "answer":  "20",
+        "solution":  "【分析】本题属于和差问题：已知大小两个数的和与它们的差，求大，小两个数的问题。已知两人的邮票总数为50枚，小东比小华少10枚。根据和差解答方法：小数=(和-差)÷2，可直接求出小东的邮票数量。\n\n【详解】小华和小东一共有50枚邮票，即和为50，小东比小华少10枚，即差为10;(50-10)÷2=40÷2=20(枚),所以小东有邮票20枚。",
+        "knowledge_points":  [
+                                 "和差倍问题"
+                             ],
+        "source":  "24-25 四年级上·湖南邵阳·期末"
+    },
+    {
+        "id":  "224",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "你能用5,6,9三个数算出24吗。请列出综合算式:( )。",
+        "options":  [
+
+                    ],
+        "answer":  "(9-5)×6=24 或6×(9-5)=24",
+        "solution":  "【分析】根据题意，考虑如何用5,6,9通过运算得到24。观察到6与4相乘，可得24，而9减去5，正好等于4，因此将两者结合即可。\n\n【详解】根据分析可知:9-5=4,4×6=24,(9-5)×6=4×6=24，你能用5,6,9三个数算出24吗。请列出综合算式:(9-5)×6=24。(答案不唯一)",
+        "knowledge_points":  [
+                                 "24点",
+                                 "带有小括号的混合运算"
+                             ],
+        "source":  "24-25 三年级下·河南洛阳·期末"
+    },
+    {
+        "id":  "225",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "把\"95-23=72,72÷9=8\"合并成一个综合算式是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "(95-23)÷9=8",
+        "solution":  "【分析】观察两个算式，\"72\"可以由95-23得到，则用95-23代替72÷9=8中的\"72\"。代替后的算式从左往右依次是减法，除法，需要保证运算结果不变，则95-23需要添加小括号，即可满足先算括号内的减法，再算括号外的除法，由此即可解答。\n\n【详解】根据分析可得:(95-23)÷9=72÷9=8，即(95-23)÷9=8。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算"
+                             ],
+        "source":  "24-25 二年级下·浙江温州·期末"
+    },
+    {
+        "id":  "226",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "把36÷9=4,18+4=22合并成一个综合算式( )。",
+        "options":  [
+
+                    ],
+        "answer":  "18+36÷9=22",
+        "solution":  "【分析】将两个分步算式合并成一个综合算式时，需要找到第二个算式中的哪个数是由第一个算式得到的，并用第一个算式代替这个数。第二个算式中的4是由36÷9得到的，因此将18+4中的4替换为36÷9即可。由于除法运算的优先级高于加法，所以不需要添加括号。\n\n【详解】18+36÷9=18+4=22，把36÷9=4,18+4=22合并成一个综合算式18+36÷9=22。",
+        "knowledge_points":  [
+                                 "除加",
+                                 "除减混合运算"
+                             ],
+        "source":  "24-25 二年级下·河南郑州·期中"
+    },
+    {
+        "id":  "227",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "在括号里填上\"<\"\">\"或\"=\"。\n40÷8( )49÷7  54÷9( )24÷4  (4+5)×8( )4+5×8",
+        "options":  [
+
+                    ],
+        "answer":  "<;=;>",
+        "solution":  "【分析】有算式的大小比较，可以先计算出每个算式的结果，再比较大小。第1、2题直接计算出结果再比较；第3题左侧算式先算加法再算乘法，右侧算式先算乘法再算加法，计算出结果再比较。\n\n【详解】40÷8=5，49÷7=7，5<7，则40÷8<49÷7；54÷9=6，24÷4=6，6=6，则54÷9=24÷4；(4+5)×8=9×8=72，4+5×8=4+40=44，72>44，则(4+5)×8>4+5×8。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算",
+                                 "乘加",
+                                 "乘减混合运算",
+                                 "用7~9的乘法口诀求商",
+                                 "100以内数的比大小"
+                             ],
+        "source":  "24-25 二年级下·浙江杭州·期中"
+    },
+    {
+        "id":  "228",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "计算6×(5+4)时，先算( )法，再算( )法，结果是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "加;乘;54",
+        "solution":  "【分析】根据题意，整数四则混合运算中，有括号的先算括号里面，没有括号的先算乘除后算加减，据此解答。\n\n【详解】根据分析:6×(5+4)=6×9=54，计算6×(5+4)时，先算(加)法，再算(乘)法，结果是(54)。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算"
+                             ],
+        "source":  "24-25 二年级下·湖北襄阳·期末"
+    },
+    {
+        "id":  "229",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "计算16+20÷4时，应先算( )法，再算( )法。如果要改变运算顺序，添上括号后的算式是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "除;加;(16+20)÷4",
+        "solution":  "【分析】根据整数混合运算法则：有乘除又有加减的，先算乘除，再算加减；同级运算按照从左到右的顺序依次计算；有小括号的，先算小括号里面的，再算小括号外面的。\n\n【详解】由分析可得：计算16+20÷4时，应先算除法，再算加法。如果要改变运算顺序，添上括号后的算式是(16+20)÷4。",
+        "knowledge_points":  [
+                                 "除加",
+                                 "除减混合运算",
+                                 "带有小括号的混合运算"
+                             ],
+        "source":  "24-25 二年级下·湖北武汉·期末"
+    },
+    {
+        "id":  "230",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "壮壮在计算\"32-□÷4\"时弄错了运算顺序，先算减法后除法，得数是4，正确的得数是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "28",
+        "solution":  "【分析】根据题意，先用错误的得数和4相乘，求出32-□的差，再用32减去这个差，得出□代表的数，代入到算式中，先算除法，再算减法，计算出结果即可。\n\n【详解】4×4=16;32-16=16，即□=16,32-16÷4=32-4=28，壮壮在计算\"32-□÷4\"时弄错了运算顺序，先算减法后除法，得数是4，正确的得数是28。",
+        "knowledge_points":  [
+                                 "除加",
+                                 "除减混合运算"
+                             ],
+        "source":  "24-25 二年级下·湖北武汉·期末"
+    },
+    {
+        "id":  "231",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "小马虎在计算\"28+□÷4\"时，弄错了运算顺序，先算加法后除法了，结果得数是9，正确的得数应该是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "30",
+        "solution":  "【分析】根据题意，先用错误的得数和4相乘，求出28+□的和，再用这个和减去28，求出□代表的数。代入到算式中，先算除法，再算加法，计算出结果即可。\n\n【详解】9×4=36,36-28=8，则□=8;28+8÷4=28+2=30，小马虎在计算\"28+□÷4\"时，弄错了运算顺序，先算加法后除法了，结果得数是9，正确的得数应该是30。",
+        "knowledge_points":  [
+                                 "除加",
+                                 "除减混合运算"
+                             ],
+        "source":  "24-25 二年级下·浙江杭州·期中"
+    },
+    {
+        "id":  "232",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "小马虎在计算\"26-□÷2\"时弄错了运算顺序，先算了减法，后算除法，结果得数是8，正确的得数是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "21",
+        "solution":  "【分析】先按照错误的计算顺序，用26减去已经算得的得数乘2的积，以此算出□代表的数。算出□代表的数后，根据先计算除法，再减法计算出正确的得数即可解答。\n\n【详解】根据分析可得：错误运算为(26-□)÷2=8，则:26-8×2=26-16=10,□代表10。正确运算为:26-10÷2=26-5=21，所以，正确的得数是21。",
+        "knowledge_points":  [
+                                 "除加",
+                                 "除减混合运算",
+                                 "乘加",
+                                 "乘减混合运算"
+                             ],
+        "source":  "24-25 二年级下·贵州铜仁·期末"
+    },
+    {
+        "id":  "233",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "聪聪在计算\"6+□×3\"时弄错了运算顺序，先算加法再算乘法，运算结果是27，正确的得数是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "15",
+        "solution":  "【分析】先根据错误的运算顺序和结果求出□里的数，再按照正确的运算顺序计算出正确的得数。\n\n【详解】因为弄错运算顺序后是(6+□)×3=27，所以先算27÷3=9，这就是6+□的结果；再算9-6=3，所以□里的数是3。把□里的数3代入原式6+□×3，得到6+3×3；根据正确的运算顺序，先算乘法3×3=9，再算加法6+9=15。因此，正确的得数是15。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算",
+                                 "乘加",
+                                 "乘减混合运算"
+                             ],
+        "source":  "24-25二年级下·湖北随州·期末"
+    },
+    {
+        "id":  "234",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "一桶油连桶重15千克，倒出一半后连桶重8千克，桶重( )千克，油重( )千克。",
+        "options":  [
+
+                    ],
+        "answer":  "1;14",
+        "solution":  "【分析】由题意可知：用一桶油连桶的重量减去倒出一半油后连桶的重量，即是半桶油的重量，半桶油的重量乘2是一桶油的重量;一桶油连桶的重量，减去一桶油的重量，即可求出桶的重量;据此列式计算即可。\n\n【详解】由题意可知：一桶油的重量:(15-8)×2=7×2=14(千克),桶重:15-14=1(千克),桶油连桶重15千克，倒出一半后连桶重8千克，桶重1千克，油重14千克。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算",
+                                 "7的乘法口诀及应用",
+                                 "不退位减法(20以内)",
+                                 "倒推问题"
+                             ],
+        "source":  "24-25二年级下·湖南长沙·期末"
+    },
+    {
+        "id":  "235",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "把7×5=35,68-35=33这两个算式改写成一个综合算式应该是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "68-7×5=33",
+        "solution":  "【分析】观察题干给出的两个算式，用\"7×5\"代替\"68-35=33\"中的\"35\"。原来两个算式是先算乘法，后算减法，代替后的算式计算顺序也符合该顺序，故不需要添加小括号，直接写出代替后的综合算式即可。\n\n【详解】根据分析可得:68-7×5=68-35=33，所以，把7×5=35,68-35=33这两个算式改写成一个综合算式应该是68-7×5=33。",
+        "knowledge_points":  [
+                                 "乘加",
+                                 "乘减混合运算"
+                             ],
+        "source":  "24-25 二年级下·云南昭通·期末"
+    },
+    {
+        "id":  "236",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "一道算式中，被除数是63，除数是12-3，这道算式是( ),最终的计算结果是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "63÷(12-3);7",
+        "solution":  "【分析】根据\"被除数/除数=商\"，代入公式计算即可。题目中除数是12-3，因此需先计算减法，即除数为12-3=9。算式是63÷9=7，因需要保留原表达式，则12-3在完整的算式中需要加小括号。\n\n【详解】63÷(12-3)=63÷9=7，道算式中，被除数是63，除数是12-3，这道算式是63÷(12-3),最终的计算结果是7。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算",
+                                 "用7~9的乘法口诀求商"
+                             ],
+        "source":  "24-25二年级下·甘肃庆阳·期末"
+    },
+    {
+        "id":  "237",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "小明在计算\"4+□÷4\"时弄错了计算顺序，先算了加法，再算除法，结果是9，正确的得数应该是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "12",
+        "solution":  "【分析】根据题意，先用错误的结果9与4相乘，求出4+□的和，再用这个和减去4，计算出方框里的数；代入到算式中，先算除法，再算加法，计算出正确的结果即可。\n\n【详解】9×4=36，36-4=32，所以□=32；4+32÷4=4+8=12，即正确的得数应该是12。",
+        "knowledge_points":  [
+                                 "除加",
+                                 "除减混合运算",
+                                 "9的乘法口诀及应用",
+                                 "两位数与一位数的减法(不退位)"
+                             ],
+        "source":  "24-25 二年级下·山东菏泽·期末"
+    },
+    {
+        "id":  "238",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "把4×4=16和24-16=8合并成综合算式是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "24-4×4=8",
+        "solution":  "【分析】将两个分步算式合并成一个综合算式时，需要找到第二个算式中的哪个数是由第一个算式得到的，并用第一个算式代替这个数。本题中第二个算式中的16是由4×4得到的，因此将24-16中的16替换为4×4即可;这道题先算乘法，再算减法，所以不需要添加括号。\n\n【详解】把4×4=16和24-16=8合并成综合算式是:24-4×4=8。",
+        "knowledge_points":  [
+                                 "乘加",
+                                 "乘减混合运算"
+                             ],
+        "source":  "24-25 二年级下·重庆·期末"
+    },
+    {
+        "id":  "239",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "把\"54÷6=9,28-9=19\"这两个算式合并成一个综合算式是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "28-54÷6=19",
+        "solution":  "【分析】将两个分步算式合并成一个综合算式时，需要找到第二个算式中的哪个数是由第一个算式得到的，并用第一个算式代替这个数;本题中第二个算式中的9是由54÷6得到的，因此将28-9中的9替换为54÷6即可。这道题先算除法，再算减法，所以不需要添加括号。28-54÷6=28-9=19，把\"54÷6=9,28-9=19\"这两个算式合并成一个综合算式是28-54÷6=19。",
+        "knowledge_points":  [
+                                 "除加",
+                                 "除减混合运算"
+                             ],
+        "source":  "24-25二年级下·浙江温州·期末"
+    },
+    {
+        "id":  "240",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "王叔叔家要挖总长60米的水沟，已经挖了12米。剩下的要用6天挖完，平均每天要挖( )米。",
+        "options":  [
+
+                    ],
+        "answer":  "8",
+        "solution":  "【分析】由题意可知：用王叔叔家要挖水沟的米数，减去已经挖了的米数，即是剩下的米数，用剩下的米数除以挖完的天数，即是平均每天要挖的米数;据此解答。\n\n【详解】(60-12)÷6=48÷6=8(米),王叔叔家要挖总长60米的水沟，已经挖了12米。剩下的要用6天挖完，平均每天要挖8米。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算"
+                             ],
+        "source":  "24-25 二年级下·浙江温州·期末"
+    },
+    {
+        "id":  "241",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "同学们一共要种65棵树，已经种了17棵，剩下的平均分给6个小组种，每个小组还要种( )棵。",
+        "options":  [
+
+                    ],
+        "answer":  "8",
+        "solution":  "【分析】由题意可知：用同学们一共要种树的棵数，减去已经种了的棵数，即是剩下的棵数;用剩下棵数除以小组数，即是每个小组还要种的棵数;据此解答。\n\n【详解】由分析可得:(65-17)÷6=48÷6=8(棵),同学们一共要种65棵树，已经种了17棵，剩下的平均分给6个小组种，每个小组还要种8棵。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算"
+                             ],
+        "source":  "24-25 二年级下·浙江温州·期末"
+    },
+    {
+        "id":  "242",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "联欢会上，智能机器人排成方阵进行灯光表演。每行有9个机器人，有这样的9行。为突出视觉效果，编程师让最外层的机器人举起一盏红色指示灯，这场表演至少需要准备( )盏红色指示灯。",
+        "options":  [
+
+                    ],
+        "answer":  "32",
+        "solution":  "【分析】由题意得，机器人排成9×9的方阵，最外层机器人分布在外层的四条边上，直接用9乘4可以算出最外层机器人的个数。但这样计算四个角上的机器人会被重复计算，直接用前面的得数减去4即可算出最外层机器人的数量，也就是需要准备红色指示灯的数量。9×4-4=36-4=32(盏),故至少需要准备32盏红色指示灯。",
+        "knowledge_points":  [
+                                 "方阵问题",
+                                 "乘加",
+                                 "乘减混合运算"
+                             ],
+        "source":  "24-25 四年级下·北京顺义·期末"
+    },
+    {
+        "id":  "243",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "小马虎在计算\"24+□÷4\"时，弄错了运算顺序，先算加法后再算除法了，结果得数是8。正确的得数应该是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "26",
+        "solution":  "【分析】根据题意，弄错了运算顺序的算式是(24+□)÷4=8，先用错误的得数和4相乘，求出24+□的和，再用这个和减去24，求出□代表的数。把□代表的数代入到正确的算式24+□÷4中，先算除法，再算加法，计算出正确的得数即可。\n\n【详解】根据分析可得:8×4-24=32-24=8,24+8÷4=24+2=26，正确的得数应该是26。",
+        "knowledge_points":  [
+                                 "除加",
+                                 "除减混合运算",
+                                 "乘加",
+                                 "乘减混合运算"
+                             ],
+        "source":  "24-25 二年级下·重庆秀山·期末"
+    },
+    {
+        "id":  "244",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "把算式24-18=6和48÷6=8合并成一个综合算式是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "48÷(24-18)=8",
+        "solution":  "【分析】整数混合运算中，同级运算时，从左到右依次计算;两级运算时，先算乘除，后算加减;有括号时，先算括号里面的，再算括号外面的。本题先算减法再算除法，需要给减法加上小括号。\n\n【详解】48÷(24-18)=48÷6=8，把算式24-18=6和48÷6=8合并成一个综合算式是48÷(24-18)=8。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算"
+                             ],
+        "source":  "24-25 二年级下·重庆秀山·期末"
+    },
+    {
+        "id":  "245",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "箱子里有一些梨，小刚取走总数的一半多1个，小明取走余下的一半多1个，这时箱子里还剩1个梨。箱子里原有( )个梨.\n![](images/ac29fd9b77bf813db08c11eb2fa83d53efaf5c6b48edf2a01cf425f96f92e8a5.jpg)",
+        "options":  [
+
+                    ],
+        "answer":  "10",
+        "solution":  "【分析】小明取走余下的一半多1个，那么1个加1个就是小明没取走时的一半，所以，小明取走一些梨后，箱子里剩下的梨的个数是(1+1)×2=2×2=4个，而4个加1个是原来梨的一半，所以，原来梨的个数是(4+1)×2=5×2=10个。\n\n【详解】(1+1)×2=2×2=4,(4+1)×2=5×2=10(个),即箱子里有一些梨，小刚取走总数的一半多1个，小明取走余下的一半多1个，这时箱子里还剩1个梨。箱子里原有10个。",
+        "knowledge_points":  [
+                                 "倒推问题"
+                             ],
+        "source":  "24-25 三年级下·山东济南·期末"
+    },
+    {
+        "id":  "246",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "猴妈妈摘回65个桃子，它先把2个给自己留下，然后把剩下的桃子平均分给它的9个孩子，平均每个孩子分得( )个。",
+        "options":  [
+
+                    ],
+        "answer":  "7",
+        "solution":  "【分析】猴妈妈摘了65个桃子，先留下2个，剩下的桃子数量为65-2=63个;将63个桃子平均分给9个孩子，每个孩子分得的数量为63÷9=7个;据此列综合算式解决即可。\n\n【详解】(65-2)÷9=63÷9=7(个),答：平均每个孩子分得7个。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算"
+                             ],
+        "source":  "24-25 二年级下·湖北黄石·期末"
+    },
+    {
+        "id":  "247",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "计算91-(18+27)时，应先算( )法，再算( )法，结果是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "加;减;46",
+        "solution":  "【分析】整数混合运算中，同级运算时，从左到右依次计算;两级运算时，先算乘除，后算加减;有括号时，先算括号里面的，再算括号外面的。据此解答。\n\n【详解】91-(18+27)=91-45=46，计算91-(18+27)时，应先算加法，再算减法，结果是46。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算"
+                             ],
+        "source":  "24-25 二年级下·山东菏泽·期中"
+    },
+    {
+        "id":  "248",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "把37-13=24和24÷8=3合并成一道综合算式是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "(37-13)÷8=3",
+        "solution":  "【分析】根据题意，先算减法37-13=24，再算除法24÷8=3，不是同级运算，先算减法要添加小括号，据此解答。\n\n【详解】根据分析：先算减法，再算除法。把37-13=24和24÷8=3合并成一道综合算式是:(37-13)÷8=3。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算"
+                             ],
+        "source":  "24-25 二年级下·内蒙古赤峰·期中"
+    },
+    {
+        "id":  "249",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "算式82-19-21和82-(19+21)的运算结果相同。( )",
+        "options":  [
+
+                    ],
+        "answer":  "√",
+        "solution":  "【分析】只有加减法的混合运算，从左往右计算;含有小括号的混合运算，先算小括号里面的，再算小括号外面的。算式1：从左往右计算;算式2：先算小括号里面的，再算小括号外面的。按照运算顺序算出结果，然后作比较，即可作出判断。\n\n【详解】由分析可得:82-19-21=63-21=42,82-(19+21)=82-40=42,42=42，算式82-19-21和82-(19+21)的运算结果相同。故答案为:√",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算",
+                                 "100以内数的连减运算"
+                             ],
+        "source":  "24-25 二年级下·山东济宁·期末"
+    },
+    {
+        "id":  "250",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "商店里共有6盒墨水，每盒里有8瓶，卖了20瓶，还剩28瓶。( )",
+        "options":  [
+
+                    ],
+        "answer":  "√",
+        "solution":  "【分析】根据题目描述，先用6乘上8计算出总瓶数，再减去卖出的数量，验证剩余数量是否正确即可。\n\n【详解】6×8-20=48-20=28(瓶),因此，还剩下28瓶，与题目中所给的28瓶一致;故答案为:√",
+        "knowledge_points":  [
+                                 "乘加",
+                                 "乘减混合运算"
+                             ],
+        "source":  "24-25 四年级下·湖北黄冈·期末"
+    },
+    {
+        "id":  "251",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "两步计算一般都按照从左到右的顺序，如9+6÷3。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】四则混合运算的顺序：一个算式里，如果只有加减法或者只有乘除法，按照从左到右的顺序依次计算;如果既有加减法，又有乘除法，先算乘除法，再算加减法;如果有括号，先算括号里面的。\n\n【详解】计算时9+6÷3，先算除法，再算加法，原题\"两步计算一般都按照从左到右的顺序\"的说法错误。故答案为: ×",
+        "knowledge_points":  [
+                                 "有括号的运算顺序",
+                                 "除加",
+                                 "除减混合运算"
+                             ],
+        "source":  "24-25二年级下·浙江台州·期末"
+    },
+    {
+        "id":  "252",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "计算(12+18)÷6时，要先算加法。( )",
+        "options":  [
+
+                    ],
+        "answer":  "√",
+        "solution":  "【分析】混合运算的运算顺序：如果只有加减法或只有乘除法，按照从左到右的顺序计算;如果既有加减法又有乘除法，要先算乘除法，再算加减法;如果有括号，要先算括号里面的，再算括号外面的。由此解答。\n\n【详解】由分析可知：计算(12+18)÷6时，按照运算顺序，先算括号内的加法，再算括号外面的除法。原题说法正确。故答案为:√",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算"
+                             ],
+        "source":  "24-25 二年级下·黑龙江佳木斯·期末"
+    },
+    {
+        "id":  "253",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "5×2+6和5×(2+6)的结果相同。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】四则混合运算的运算法则:①在没有括号的算式里，如果只有加减法或者只有乘除法，要从左往右依次计算。②在没有括号的算式里，如果既有乘除法又有加减法，要先算乘除法，再算加减法。③在有括号的算式里，要先算括号里面的，再算括号外面的。5×2+6，先算乘法，再算加法;5×(2+6)先算括号里面的加法，再算括号外面的乘法。分别计算两个算式的得数，比较结果是否相同，即可解答。\n\n【详解】5×2+6=10+6=16,5×(2+6)=5×8=40,5×2+6和5×(2+6),两个算式的结果不同。原题说法错误。故答案为: ×",
+        "knowledge_points":  [
+                                 "表内乘加",
+                                 "乘减",
+                                 "带有小括号的混合运算"
+                             ],
+        "source":  "24-25 二年级下·内蒙古呼伦贝尔·期末"
+    },
+    {
+        "id":  "254",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "判断题",
+        "difficulty":  0.65,
+        "question":  "在没有括号的混合运算中，一定要先算乘除法，后算加减法。( )",
+        "options":  [
+
+                    ],
+        "answer":  "√",
+        "solution":  "【分析】在没有括号的混合运算中，如果既有乘除法，又有加减法，要先算乘除法，后算加减法；如果只有同级运算，则按从左到右的顺序计算。\n\n【详解】在四则混合运算中，若算式没有括号，且同时含有加、减、乘、除运算时，运算顺序为：先算乘除法，后算加减法。若只有同级运算(如只有加减或只有乘除)，则需从左往右依次计算。题干中明确提到\"混合运算\"，即包含不同级运算，因此需先算乘除法，后算加减法。例如：计算8+3×2时，应先算3×2=6，再算8+6=14。题干所述规则正确。故答案为:√",
+        "knowledge_points":  [
+                                 "无括号的运算顺序"
+                             ],
+        "source":  "24-25 二年级下·广东汕尾·期末"
+    },
+    {
+        "id":  "255",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "小猴子爬8米高的树，每次爬4米后都会下滑2米，小猴子要爬4次才能爬上树顶。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】小猴子最后一次爬到树顶就不会下滑了。先求出最后一次爬之前还剩多少米，再用每次实际向上爬的米数去除，最后再加上最后一次即可。\n\n【详解】(8-4)÷(4-2)+1=4÷2+1=2+1=3(次)，小猴子要爬3次才能爬上树顶，所以原题说法错误。故答案为: ×",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算"
+                             ],
+        "source":  "24-25 二年级下·四川乐山·期末"
+    },
+    {
+        "id":  "256",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "计算30÷5×2时，可以先算乘法，再算除法。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】根据四则混合运算的法则，在没有括号的算式里，如果只有加减法或者只有乘除法，要从左往右依次计算，据此判断。\n\n【详解】由分析可得：计算30÷5×2时，题中没有括号，只有乘除法，要从左往右依次计算。原题说法错误。故答案为: ×",
+        "knowledge_points":  [
+                                 "无括号的运算顺序"
+                             ],
+        "source":  "24-25 二年级下·四川乐山·期末"
+    },
+    {
+        "id":  "257",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "计算30+(25-5)时，先算减法，再算加法。( )",
+        "options":  [
+
+                    ],
+        "answer":  "√",
+        "solution":  "【分析】根据整数混合运算法则：有小括号的，先算小括号中的再算小括号外的。\n\n【详解】由分析可得：计算30+(25-5)时，先算减法，再算加法，原题说法正确。故答案为:√",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算",
+                                 "100以内数的加减混合运算"
+                             ],
+        "source":  "24-25一年级下·河南安阳·期末"
+    },
+    {
+        "id":  "258",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "计算题",
+        "difficulty":  0.85,
+        "question":  "我会计算。想一想每道题先算什么，再算什么。\n63÷7+91  8×(36-29)  51-36÷9",
+        "options":  [
+
+                    ],
+        "answer":  "100;56;47",
+        "solution":  "【分析】整数四则混合运算，如果有括号先算小括号里面的，再算括号外面的;如果没有括号，先算乘除，再算加减;只含有同一级运算，按照从左到右的顺序计算。(1)先算除法，再算加法。(2)先算括号内的减法，再算乘法。(3)先算除法，再算减法。\n\n【详解】63÷7+91=9+91=100;8×(36-29)=8×7=56;51-36÷9=51-4=47。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算",
+                                 "除加",
+                                 "除减混合运算"
+                             ],
+        "source":  "24-25 二年级下·广东佛山·期末"
+    },
+    {
+        "id":  "259",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "计算题",
+        "difficulty":  0.65,
+        "question":  "在自己练习本上列式计算。\n18+(72-56)  8×6+21  54-48÷8",
+        "options":  [
+
+                    ],
+        "answer":  "34;69;48",
+        "solution":  "【分析】混合运算的运算顺序：如果只有加减法或只有乘除法，按照从左到右的顺序计算;如果既有加减法又有乘除法，要先算乘除法，再算加减法;如果有括号，要先算括号里面的，再算括号外面的。18+(72-56)先算括号里面的减法，再算括号外面的加法;8×6+21先算乘法，再算加法;54-48÷8先算除法，再算减法。\n\n【详解】18+(72-56)=18+16=34;8×6+21=48+21=69;54-48÷8=54-6=48。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算",
+                                 "除加",
+                                 "除减混合运算",
+                                 "乘加",
+                                 "乘减混合运算"
+                             ],
+        "source":  "24-25 二年级下·湖南长沙·期末"
+    },
+    {
+        "id":  "260",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "计算题",
+        "difficulty":  0.85,
+        "question":  "看图列式.\n![](images/881a40b2e850734cc21d342a7bf8e7e198e2ff85ee89c7ad822ec93358d9f03d.jpg)",
+        "options":  [
+
+                    ],
+        "answer":  "36÷4×6=54(元)",
+        "solution":  "【分析】根据题图可知,4个一共36元，用36元除以4，等于一个多少钱，每个的钱数乘6，等于6个一共多少钱，据此解答。\n\n【详解】根据分析可得:36÷4×6=9×6=54(元),因此,6个一共54元。",
+        "knowledge_points":  [
+                                 "表内乘除混合运算",
+                                 "图文问题"
+                             ],
+        "source":  "24-25 二年级下·湖北襄阳·期中"
+    },
+    {
+        "id":  "261",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "计算题",
+        "difficulty":  0.65,
+        "question":  "我可以用递等式计算.\n(1)72÷(45-37) (2)32÷4+52 (3)68+10÷5",
+        "options":  [
+
+                    ],
+        "answer":  "9;60;70",
+        "solution":  "【分析】在没有括号的算式里，只有加，减法或只有乘，除法，要从左往右计算;在没有括号的算式里，如果既有乘，除法，又有加，减法，要先算乘，除法，再算加，减法;有括号的算式里，要先算括号里面的，再算括号外面的。(1)72÷(45-37)先算减法，再算除法;(2)32÷4+52先算除法，再算加法;(3)68+10÷5先算除法，再算加法。\n\n【详解】(1)72÷(45-37)=72÷8=9;(2)32÷4+52=8+52=60;(3)68+10÷5=68+2=70。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算",
+                                 "除加",
+                                 "除减混合运算"
+                             ],
+        "source":  "24-25 二年级下·广东广州·期末"
+    },
+    {
+        "id":  "262",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "计算题",
+        "difficulty":  0.85,
+        "question":  "脱式计算。\n64+22-30  64-40÷8  14÷(83-76)",
+        "options":  [
+
+                    ],
+        "answer":  "56;59;2",
+        "solution":  "【分析】(1)从左往右依次计算，先算加法，再算减法;(2)先算除法，再算减法;(3)先算括号内的减法，再算除法。\n\n【详解】64+22-30=86-30=56;64-40÷8=64-5=59;14÷(83-76)=14÷7=2。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算",
+                                 "除加",
+                                 "除减混合运算",
+                                 "100以内数的加减混合运算"
+                             ],
+        "source":  "24-25 二年级下·福建福州·期末"
+    },
+    {
+        "id":  "263",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "计算题",
+        "difficulty":  0.65,
+        "question":  "先用横线画出先算的部分，再计算.\n91-(19+22) (65-56)×475+15÷3",
+        "options":  [
+
+                    ],
+        "answer":  "50;36;80",
+        "solution":  "【分析】在没有括号的算式里，只有加，减法或只有乘，除法，要从左往右计算;在没有括号的算式里，如果既有乘，除法，又有加，减法，要先算乘，除法，再算加，减法;有括号的算式里，要先算括号里面的，再算括号外面的。第1题先算加法，再算减法;第2题先算减法，再算乘法;第3题先算除法，再算加法。\n\n【详解】91-(19+22)=91-41=50;(65-56)×4=9×4=36;75+15÷3=75+5=80。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算",
+                                 "除加",
+                                 "除减混合运算"
+                             ],
+        "source":  "24-25 二年级下·广西柳州·期末"
+    },
+    {
+        "id":  "264",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "计算题",
+        "difficulty":  0.85,
+        "question":  "脱式计算。\n4×9-24  54-29+36  81÷(4+5)",
+        "options":  [
+
+                    ],
+        "answer":  "12;61;9",
+        "solution":  "【分析】第1题：先算乘法，再算减法;第2题：从左往右依次计算，先算减法，再算加法;第3题：先算括号里面的加法，再算括号外面的除法。\n\n【详解】4×9-24=36-24=12;54-29+36=25+36=61;81÷(4+5)=81÷9=9。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算",
+                                 "乘加",
+                                 "乘减混合运算",
+                                 "100以内数的加减混合运算"
+                             ],
+        "source":  "23-24 二年级下·福建龙岩·期末"
+    },
+    {
+        "id":  "265",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "一袋糖果有80颗，小明吃了65颗，剩下的他每天吃3颗，他还可以吃几天。",
+        "options":  [
+
+                    ],
+        "answer":  "5天",
+        "solution":  "【分析】首先计算剩下的糖果数量，用共有的数量减去小明吃的数量即可;再用剩下的数量除以每天吃的数量，得到天数。\n\n【详解】(80-65)÷3=15÷3=5(天),答：他还可以吃5天。",
+        "knowledge_points":  [
+                                 "除加",
+                                 "除减混合运算"
+                             ],
+        "source":  "24-25 二年级下·云南红河·期末"
+    },
+    {
+        "id":  "266",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "二(1)班买回25本童话书和15本寓言故事书。把这些书平均分给5个小组，每个小组分到多少本书。",
+        "options":  [
+
+                    ],
+        "answer":  "8本",
+        "solution":  "【分析】根据题意，先用加法计算出一共买回多少本书，再用书的总数量除以平均分的小组数，就是每个小组分到书的数量。\n\n【详解】(25+15)÷5=40÷5=8(本),答：每个小组分到8本书。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算"
+                             ],
+        "source":  "24-25 二年级下·山东临沂·期末"
+    },
+    {
+        "id":  "267",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "大犀山动物园每张门票12元，假期开展优惠活动,5张门票45元。优惠后每张门票比原来便宜多少钱。",
+        "options":  [
+
+                    ],
+        "answer":  "3元",
+        "solution":  "【分析】先用除法算出开展优惠活动后，每张门票的价格，再用原来每张门票的钱减去开展优惠活动后每张门票的钱，即可求出优惠后每张门票比原来便宜多少钱。\n\n【详解】12-45÷5=12-9=3(元),答：优惠后每张门票比原来便宜3元钱。",
+        "knowledge_points":  [
+                                 "除加",
+                                 "除减混合运算"
+                             ],
+        "source":  "24-25二年级下·贵州铜仁·期末"
+    },
+    {
+        "id":  "268",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "昭通市实验小学二年级一班54名师生租车去春游，租了6辆车，每辆车上正好有1名老师，平均每辆车上有几名学生。",
+        "options":  [
+
+                    ],
+        "answer":  "8名",
+        "solution":  "【分析】用春游总人数除以租车的数量，求出商就是每辆车上的人数，再减去1，求出差，就是每辆车上的学生人数。\n\n【详解】54÷6-1=9-1=8(名),答：平均每辆车上有8名学生。",
+        "knowledge_points":  [
+                                 "除加",
+                                 "除减混合运算"
+                             ],
+        "source":  "24-25 二年级下·云南昭通·期末"
+    },
+    {
+        "id":  "269",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "城市书房里上午有35人，中午走了16人，下午又来了28人，城市书房里下午有多少人。",
+        "options":  [
+
+                    ],
+        "answer":  "47人",
+        "solution":  "【分析】根据题意，用书房上午有的人数-中午走了的人数+下午又来了的人数=城市书房里下午有的人数，据此解答。\n\n【详解】根据分析:35-16+28=19+28=47(人),答：城市书房里下午有47人。",
+        "knowledge_points":  [
+                                 "100以内数的加减混合运算"
+                             ],
+        "source":  "24-25 二年级下·湖南衡阳·期末"
+    },
+    {
+        "id":  "270",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "妈妈买1千克苹果花了12元，买3千克香蕉花了15元，每千克香蕉比苹果便宜多少元。",
+        "options":  [
+
+                    ],
+        "answer":  "7元",
+        "solution":  "【分析】要求每千克香蕉比苹果便宜多少元，需先分别求出苹果和香蕉的单价，已知苹果的价格是12元每千克，香蕉单价为15元3千克，可用除法计算，再用苹果单价减去香蕉单价。\n\n【详解】12-(15÷3)=12-5=7(元),答：每千克香蕉比苹果便宜7元。",
+        "knowledge_points":  [
+                                 "除加",
+                                 "除减混合运算",
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·山东济宁·期末"
+    },
+    {
+        "id":  "271",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "一本故事书有64页，小明看了7天，还有15页没看过，他平均每天能看多少页。",
+        "options":  [
+
+                    ],
+        "answer":  "7页",
+        "solution":  "【分析】先计算小明7天共看的页数，即总页数减去未看的页数，再用7天共看的页数除以天数，得到平均每天看的页数。\n\n【详解】(64-15)÷7=49÷7=7(页),答：他平均每天能看7页。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算"
+                             ],
+        "source":  "24-25 二年级下·浙江绍兴·期末"
+    },
+    {
+        "id":  "272",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "二(1)班有男生22人，女生26人，每6人一组参加课外实践活动，可以分成几个小组。",
+        "options":  [
+
+                    ],
+        "answer":  "8组",
+        "solution":  "【分析】根据题意可知，二(1)班男生的人数加上女生的人数，等于一共有多少人参加课外实践活动，再用参加课外实践活动总人数除以每组人数，等于可以分成几个小组，据此解答。\n\n【详解】根据分析可得:(22+26)÷6=48÷6=8(组),答：可以分成8个小组。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算"
+                             ],
+        "source":  "24-25 二年级下·浙江绍兴·期末"
+    },
+    {
+        "id":  "273",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "二年级8个班，每个班选9人参加大合唱，三年级的参赛人员比二年级多6人，三年级有多少人参加大合唱。",
+        "options":  [
+
+                    ],
+        "answer":  "78人",
+        "solution":  "【分析】先用二年级每个班选的参加大合唱的人数乘班数，求出二年级参加大合唱的人数，再用二年级参加大合唱的人数加上三年级比二年级多的人数，即可求出三年级有多少人参加大合唱。\n\n【详解】9×8+6=72+6=78(人),答：三年级有78人参加大合唱。",
+        "knowledge_points":  [
+                                 "乘加",
+                                 "乘减混合运算"
+                             ],
+        "source":  "24-25 二年级下·湖南长沙·期末"
+    },
+    {
+        "id":  "274",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "一本故事书，小兰已经看了36页。剩下的用8天看完，她平均每天要看7页，这本故事书一共有多少页。",
+        "options":  [
+
+                    ],
+        "answer":  "92页",
+        "solution":  "【分析】根据题意可知：用每天看的页数乘剩余需看的天数，再加上已经看的页数即可求出一共的页数。\n\n【详解】7×8+36=56+36=92(页),答：这本故事书一共有92页。",
+        "knowledge_points":  [
+                                 "乘加",
+                                 "乘减混合运算"
+                             ],
+        "source":  "24-25 二年级下·广东东莞·期末"
+    },
+    {
+        "id":  "275",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "丽丽拿30元去买快餐。A套餐:8元/份 B套餐:6元/份(1)可以买几份B套餐。(2)她先买了一份B套餐，剩余的钱能买几份A套餐。",
+        "options":  [
+
+                    ],
+        "answer":  "5份;3份",
+        "solution":  "【分析】(1)求30元能买几份B套餐，用总钱数除以每份B套餐的价钱，即30÷6;(2)先用减法计算买1份B套餐后的剩余钱数，再用除法求剩余钱数能买几份A套餐，即(30-6)÷8。\n\n【详解】(1)30÷6=5(份),答：可以买5份B套餐。(2)(30-6)÷8=24÷8=3(份),答：剩余的钱能买3份A套餐。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算",
+                                 "用7~9的乘法口诀求商",
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "24-25二年级下·广东东莞·期末"
+    },
+    {
+        "id":  "276",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "永辉超市卖了9袋面粉，每袋面粉7千克，还剩34千克，永辉超市原来有多少千克面粉。",
+        "options":  [
+
+                    ],
+        "answer":  "97千克",
+        "solution":  "【分析】根据题意，卖出9袋，每袋7千克，每袋面粉的千克数乘卖出面粉的袋数，等于卖出了多少千克，再用卖出的千克数加上剩余的千克数，等于原来面粉的总重量，据此解答。\n\n【详解】根据分析可得:7×9+34=63+34=97(千克),答：永辉超市原来有97千克面粉。",
+        "knowledge_points":  [
+                                 "乘加",
+                                 "乘减混合运算"
+                             ],
+        "source":  "24-25 二年级下·重庆秀山·期末"
+    },
+    {
+        "id":  "277",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "这本故事书剩下的要多少天看完。这本故事书有80页，已看32页。剩下的平均每天看8页。",
+        "options":  [
+
+                    ],
+        "answer":  "6天",
+        "solution":  "【分析】根据题意，先用书的总页数减去已经看了的页数，计算出剩下没看的页数，再用没看的页数除以每天看的页数，就是要看的天数。\n\n【详解】(80-32)÷8=48÷8=6(天),答：这本故事书剩下的要6天看完。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算"
+                             ],
+        "source":  "24-25 二年级下·河南周口·期末"
+    },
+    {
+        "id":  "278",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "二(1)班有男生25人，女生23人，平均分成6组做科学实验，每组有多少人。",
+        "options":  [
+
+                    ],
+        "answer":  "8人",
+        "solution":  "【分析】要求每组的人数，需先求出总人数，再平均分成6组。总人数为男生25人加女生23人，即25+23=48(人)。将48人平均分成6组，用48除以6即可求解。\n\n【详解】(25+23)÷6=48÷6=8(人),答：每组有8人。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算"
+                             ],
+        "source":  "24-25 二年级下·江西上饶·期末"
+    },
+    {
+        "id":  "279",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "三(1)班有男生24人，女生18人，每6人一组做游戏，一共能分几个小组。",
+        "options":  [
+
+                    ],
+        "answer":  "7个",
+        "solution":  "【分析】根据题意，先把男生和女生的人数相加求出总人数，然后再除以6即可求出一共能分几个小组。\n\n【详解】(24+18)÷6=42÷6=7(个),答：一共能分7个小组。",
+        "knowledge_points":  [
+                                 "除加",
+                                 "除减混合运算",
+                                 "用7~9的乘法口诀求商",
+                                 "两位数与两位数的进位加法"
+                             ],
+        "source":  "24-25 二年级下·湖南长沙·期末"
+    },
+    {
+        "id":  "280",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "超市文具盒原来11元一个，现在举行五一促销活动，买4个文具盒36元，现在每个比原来便宜多少钱。",
+        "options":  [
+
+                    ],
+        "answer":  "2元",
+        "solution":  "【分析】根据题意，先用除法求出促销活动时一个文具盒多少元，再用原来一个文具盒的钱减去促销活动时一个文具盒的钱，即可求出现在每个文具盒比原来便宜多少钱。\n\n【详解】11-36÷4=11-9=2(元),答：现在每个比原来便宜2元钱。",
+        "knowledge_points":  [
+                                 "除加",
+                                 "除减混合运算"
+                             ],
+        "source":  "24-25二年级下·江西赣州·期末"
+    },
+    {
+        "id":  "281",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "购物。![](images/47ff91f32e293ad8672ec7022babee3a.png)\n(1)32元可以买几个汉堡。\n(2)小明买了3包薯条，付给售货员30元，应找回多少钱。\n(3)你还能提出其他数学问题并解答吗。",
+        "options":  [
+
+                    ],
+        "answer":  "4个;3元;9元可以买几瓶可乐;3瓶",
+        "solution":  "【分析】(1)用买汉堡的钱数除以每个汉堡的钱数，等于可以买几个汉堡，据此解答;(2)每包薯条的钱数乘小明买薯条的包数，等于他购买薯条花的钱数，再用付给售货员的钱数减去买薯条花的钱数，等于应找回多少钱;(3)买可乐的钱数除以每瓶可乐的钱数，等于可以买几瓶可乐，据此解答。\n\n【详解】(1)32÷8=4(个),答:32元可以买4个汉堡。(2)30-3×9=30-27=3(元),答：应找回3元。(3)提出问题:9元可以买几瓶可乐。(提出问题和答案不唯一)9÷3=3(瓶),答:9元可以买3瓶可乐。",
+        "knowledge_points":  [
+                                 "乘加",
+                                 "乘减混合运算",
+                                 "用7~9的乘法口诀求商",
+                                 "用2~5的乘法口诀求商",
+                                 "\"提问题\"\"填条件\"问题"
+                             ],
+        "source":  "24-25 二年级下·湖南·期中"
+    },
+    {
+        "id":  "282",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "options":  [
+
+                    ],
+        "question":  "![](images/2d8bcb1f54c87a06d84836e187c453ce.png)\n(1)购买5架玩具飞机和一个玩具机器人需要多少钱。\n(2)购买8辆玩具小汽车，50元够吗。\n(3)你还能提出其他数学问题并解答吗。",
+        "answer":  "61元;够;购买一架玩具飞机和一辆玩具小汽车需要多少钱;13元",
+        "solution":  "【分析】(1)根据乘法的意义，用7×5先算出买5架玩具飞机需要多少元，再加上一个玩具机器人的价钱，即可得出答案。(2)根据乘法的意义，用6×8先算出买8辆玩具小汽车需要多少元，再跟50元进行比较，若大于50，则不够，若小于50，则够，据此解答即可。(3)根据题干数学信息，结合学过的数学知识，提出问题并解答即可。本小题答案不唯一，例如：购买一架玩具飞机和一辆玩具小汽车需要多少钱。\n\n【详解】(1)7×5+26=35+26=61(元)，答：购买5架玩具飞机和一个玩具机器人需要61元钱。(2)6×8=48(元)，48<50，答：50元够买8辆玩具小汽车。(3)问题：购买一架玩具飞机和一辆玩具小汽车需要多少钱。6+7=13(元)，答：购买一架玩具飞机和一辆玩具小汽车需要13元。(本题答案不唯一)",
+        "knowledge_points":  [
+                                 "乘加",
+                                 "乘减混合运算",
+                                 "8的乘法口诀及应用",
+                                 "\"提问题\"\"填条件\"问题"
+                             ],
+        "source":  "24-25 二年级下·贵州铜仁·期末"
+    },
+    {
+        "id":  "283",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "二年级召开家长会，同学们准备了35把单人椅和8把双人椅。邀请50名家长，座位够吗。",
+        "options":  [
+
+                    ],
+        "answer":  "够",
+        "solution":  "【分析】先根据乘法的意义，双人椅的数量×一把双人椅的座位数=双人椅可以坐的人数，算出双人椅可以坐的人数。再根据加法的意义，单人椅可以坐的人数+双人椅可以坐的人数=一共可以坐的人数，由此列出一个综合算式，并算出答案。算出的答案如果大于或等于50，则座位够，反之，则不够。\n\n【详解】8×2+35=16+35=51(位)，因为51 > 50，所以座位够。答：座位够。",
+        "knowledge_points":  [
+                                 "乘加",
+                                 "乘减混合运算"
+                             ],
+        "source":  "24-25 二年级下·湖南长沙·期末"
+    },
+    {
+        "id":  "284",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "李奶奶家养了40只公鸡和16只母鸡，每8只鸡放进一个笼子里，需要多少个笼子。",
+        "options":  [
+
+                    ],
+        "answer":  "7个",
+        "solution":  "【分析】先根据公鸡的数量+母鸡的数量=两种鸡的数量，算出两种鸡的总数。再根据两种鸡的总数/每个笼子里鸡的数量=需要的笼子个数，列出一个综合算式并算出答案即可解答。\n\n【详解】(40+16)÷8=56÷8=7(个),答：需要7个笼子。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算"
+                             ],
+        "source":  "24-25 二年级下·浙江温州·期末"
+    },
+    {
+        "id":  "285",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "在进行队列操比赛时，原来是每列站9人，站了4列。老师觉得队列太长，就改为6列，现在每列站几人。",
+        "options":  [
+
+                    ],
+        "answer":  "6人",
+        "solution":  "【分析】根据题意可知：先求出总人数，然后用总人数除以列数即可求出每列站的人数。即现在平均每列站的人数=原来每列站的人数×原来站的列数/现在站的列数。\n\n【详解】9×4÷6=36÷6=6(人),答：现在每列站6人。",
+        "knowledge_points":  [
+                                 "除加",
+                                 "除减混合运算"
+                             ],
+        "source":  "24-25 二年级下·浙江温州·期末"
+    },
+    {
+        "id":  "286",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "![](images/b8be08a439bc78a5324871a190cf03fd.png)\n(1)买6个杯子需要多少元。\n(2)27元买了3条毛巾，一条毛巾多少钱。\n(3)小明有20元钱，买2支牙刷和一条毛巾后，还剩多少元。",
+        "options":  [
+
+                    ],
+        "answer":  "54元;9元;3元",
+        "solution":  "【分析】由题意可知:(1)根据乘法的意义，用一个杯子的价钱乘6，即是买6个杯子需要的钱数;(2)根据除法的意义，用27元除以毛巾的条数，即是一条毛巾的钱数;(3)用1支牙刷的钱乘2，再加一条毛巾的钱，即是买2支牙刷和一条毛巾一共的钱;用小明有的钱数减去买2支牙刷和一条毛巾的钱，即是还剩的钱;【详解】由分析可得:(1)9×6=54(元),答：买6个杯子需要54元。(2)27÷3=9(元),答：一条毛巾9元钱。(3)20-(4×2+9)=20-(8+9)=20-17=3(元),答：还剩3元。",
+        "knowledge_points":  [
+                                 "表内乘加",
+                                 "乘减",
+                                 "用7~9的乘法口诀求商",
+                                 "9的乘法口诀及应用",
+                                 "图文问题"
+                             ],
+        "source":  "24-25 二年级下·山东临沂·期末"
+    },
+    {
+        "id":  "287",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "一根跳绳原价9元，因商店优惠活动，现在每根跳绳6元，原来买4根的钱，现在可以买几根。",
+        "options":  [
+
+                    ],
+        "answer":  "6根",
+        "solution":  "【分析】根据题意，用原价×原来买的数量/现价=现在可以买的根数，据此解答。\n\n【详解】9×4÷6=36÷6=6(根),答：现在可以买6根。",
+        "knowledge_points":  [
+                                 "表内乘除法解决实际问题",
+                                 "表内乘除混合运算"
+                             ],
+        "source":  "24-25 二年级下·山东临沂·期末"
+    },
+    {
+        "id":  "288",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "学校买了2箱牛奶，每箱6瓶，平均分给3个班，每个班分得多少瓶。",
+        "options":  [
+
+                    ],
+        "answer":  "4瓶",
+        "solution":  "【分析】根据题意，先求牛奶的总瓶数，已知学校买了2箱牛奶，每箱有6瓶，要求牛奶的总瓶数，就是求2个6是多少，用乘法计算;再将总瓶数平均分给各个班级，从而得到每个班级分得的瓶数。也就是要把12瓶牛奶平均分给3个班，就是把12平均分成3份，求每份是多少，用除法计算。由此列式。\n\n【详解】6×2÷3=12÷3=4(瓶),答：每个班分得4瓶。",
+        "knowledge_points":  [
+                                 "表内乘除混合运算",
+                                 "表内乘除法解决实际问题"
+                             ],
+        "source":  "24-25 二年级下·四川乐山·期末"
+    },
+    {
+        "id":  "289",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "面包店搞活动，原价：每个面包12元，优惠价:3个27元，优惠后，每个面包比原价便宜多少钱。",
+        "options":  [
+
+                    ],
+        "answer":  "3元",
+        "solution":  "【分析】先计算优惠后每个面包的价格，再用原价减去优惠后的价格，即可得到每个面包比原价便宜多少钱。\n\n【详解】27÷3=9(元),12-9=3(元),答：优惠后，每个面包比原价便宜3元钱。",
+        "knowledge_points":  [
+                                 "表内乘除法解决实际问题",
+                                 "除加",
+                                 "除减混合运算"
+                             ],
+        "source":  "24-25 二年级下·湖南长沙·期末"
+    },
+    {
+        "id":  "290",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "二(1)班为运动员买来了12千克苹果和9千克桔子，准备把这些水果装进3个箱子里，平均每箱要装多少千克。",
+        "options":  [
+
+                    ],
+        "answer":  "7千克",
+        "solution":  "【分析】根据题意，先用加法计算出苹果和桔子的总重量，再用总重量除以要装的箱子数量，即可求出平均每箱装的重量。\n\n【详解】(12+9)÷3=21÷3=7(千克),答：平均每箱要装7千克。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算"
+                             ],
+        "source":  "24-25 二年级下·河北邢台·期末"
+    },
+    {
+        "id":  "291",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "小刚有45元，买一个跳绳用了9元，如果用剩下的钱买6元一个的魔方，可以买多少个。\n答：可以买( )个。",
+        "options":  [
+
+                    ],
+        "answer":  "6",
+        "solution":  "【分析】用45-9先算出小刚买跳绳后剩下的钱，再用剩下的钱除以每个魔方的价格，即可求出可以买的魔方个数。\n\n【详解】(45-9)÷6=36÷6=6(个),答：可以买6个。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算",
+                                 "除加",
+                                 "除减混合运算"
+                             ],
+        "source":  "24-25二年级下·广东广州·期末"
+    },
+    {
+        "id":  "292",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "购物。![](images/b574ee1cd41b1d49be675f1000bf5ceb.png)\n(1)36元可以买几个皮球。\n(2)哥哥买了4根跳绳和一副乒乓球拍，一共花了多少元。\n(3)小红买了8个羽毛球，付了50元，应找回多少元。",
+        "options":  [
+
+                    ],
+        "answer":  "6个;45元;34元",
+        "solution":  "【分析】根据题意,(1)一个皮球6元，问36元可以买几个皮球，就是求36里面有几个6，用除法计算;(2)跳绳每根5元，乒乓球拍每副25元，求买4根跳绳和一副乒乓球拍多少钱，一共的钱数=每根跳绳的单价×数量+一副乒乓球拍的价格;(3)用付的钱数-每个羽毛球的单价×数量=应找回的钱数，据此解答。\n\n【详解】(1)36÷6=6(个),答:36元可以买6个皮球。(2)5×4+25=20+25=45(元),答：一共花了45元。(3)50-8×2=50-16=34(元),答：应找回34元。",
+        "knowledge_points":  [
+                                 "乘加",
+                                 "乘减混合运算",
+                                 "用6的乘法口诀求商",
+                                 "两位数与整十数的加法"
+                             ],
+        "source":  "24-25 二年级下·山东济宁·期末"
+    },
+    {
+        "id":  "293",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "妈妈带着小明坐10路车去黄石玩，车上原来有29人，到西塞站后下去14人，又上来9人。现在公交车上有多少人。",
+        "options":  [
+
+                    ],
+        "answer":  "24人",
+        "solution":  "【分析】用车上原来的人数减下去的14人，再加上又上来的9人即可求解。\n\n【详解】29-14+9=15+9=24(人),答：现在公交车上有24人。",
+        "knowledge_points":  [
+                                 "100以内数的加减混合运算"
+                             ],
+        "source":  "23-24 二年级下·湖北黄石·期末"
+    },
+    {
+        "id":  "294",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "博物馆最近运回了100个机器人模型，送给光明小学26个，希望小学37个，博物馆还剩多少个机器人模型。",
+        "options":  [
+
+                    ],
+        "answer":  "37个",
+        "solution":  "【分析】由题意可知：把送给光明小学和希望小学的机器人模型数加起来，就是两个学校一共送的机器人模型数，再用总共运回的模型数减去送给两个学校的模型数，就是博物馆还剩的机器人模型数；据此解答。\n\n【详解】由分析可得：100-(26+37)=100-63=37(个)，答：博物馆还剩37个机器人模型。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算",
+                                 "两、三位数的连续退位减法"
+                             ],
+        "source":  "23-24 二年级下·湖北黄冈·期末"
+    },
+    {
+        "id":  "295",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "图书馆有8台自助借还书机。一天系统显示一共借出了97本书，其中33本是人工通道借出的，剩下的平均通过每台自助借还书机借出了多少本书。",
+        "options":  [
+
+                    ],
+        "answer":  "8本",
+        "solution":  "【分析】根据减法的意义，用97-33先算出用自助借还书机一共借出多少本，再用借出的书本数量除以自助借还书机的数量，即可得出平均通过每台自助借还书机借出了多少本书。\n\n【详解】(97-33)÷8=64÷8=8(本),答：剩下的平均通过每台自助借还书机借出了8本书。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算",
+                                 "除加",
+                                 "除减混合运算"
+                             ],
+        "source":  "24-25 二年级下·重庆·期末"
+    },
+    {
+        "id":  "296",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "《九章算术》是我国古代的数学专著，共分为九章，其中第二章\"粟米\"有46个例题。亮亮已经做了6个例题，剩下的5天做完，平均每天做几个例题。",
+        "options":  [
+
+                    ],
+        "answer":  "8个",
+        "solution":  "【分析】首先计算剩下的例题数量，用总例题数减去已做的例题数，得到剩下的例题数。然后将剩下的例题数除以剩下要做的天数，求出商，即可解决。\n\n【详解】(46-6)÷5=40÷5=8(个),答：平均每天做8个例题。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算"
+                             ],
+        "source":  "24-25 二年级下·湖北黄石·期末"
+    },
+    {
+        "id":  "297",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "王阿姨给小明买了一套衣服，付了100元，应找回多少钱。\n![](images/052648f680c9a16192a18a2df765ae0a.png)",
+        "options":  [
+
+                    ],
+        "answer":  "27元",
+        "solution":  "【分析】根据题意，用付的总钱数-上衣的价格-裤子的价格=应找回的钱数，据此解答。\n\n【详解】100-38-35=62-35=27(元),答：应找回27元。",
+        "knowledge_points":  [
+                                 "100以内数的连减运算",
+                                 "经济问题"
+                             ],
+        "source":  "24-25 二年级下·河南周口·期末"
+    },
+    {
+        "id":  "298",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "兔妈妈拔了60根胡萝卜，留出了15根准备以后吃，剩下的胡萝卜分给她的9个孩子，平均每个孩子分得几根。",
+        "options":  [
+
+                    ],
+        "answer":  "5根",
+        "solution":  "【分析】根据减法的意义，用60-15先算出还剩下多少根萝卜，再根据除法的意义，用剩下的萝卜数量除以9，即可得出平均每个孩子分得几根。\n\n【详解】(60-15)÷9=45÷9=5(根),答：平均每个孩子分得5根。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算"
+                             ],
+        "source":  "24-25 二年级下·山东济南·期中"
+    },
+    {
+        "id":  "299",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "一家4口去科技馆，乘地铁每人5元，乘出租车需要45元，乘地铁比乘出租车节省多少钱。",
+        "options":  [
+
+                    ],
+        "answer":  "25元",
+        "solution":  "【分析】根据乘法的意义，用4×5先算出4个人乘坐地铁一共需要多少钱，再用乘出租车的花的钱减去乘地铁花的钱，即可得出答案。\n\n【详解】45-4×5=45-20=25(元),答：乘地铁比乘出租车节省25元钱。",
+        "knowledge_points":  [
+                                 "乘加",
+                                 "乘减混合运算"
+                             ],
+        "source":  "24-25二年级下·河南郑州·期中"
+    },
+    {
+        "id":  "300",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "手工小组做纸扇花，女生做了28朵，男生做了14朵，将这些纸扇花平均分给7个班，每班分得几朵。",
+        "options":  [
+
+                    ],
+        "answer":  "6朵",
+        "solution":  "【分析】先算出女生和男生一共做了多少朵纸扇花，再根据除法的意义，用总的纸扇花数量除以班级数量，即可得出每班分得几朵，据此解答即可。\n\n【详解】(28+14)÷7=42÷7=6(朵),答：每班分得6朵。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算",
+                                 "除加",
+                                 "除减混合运算"
+                             ],
+        "source":  "24-25 二年级下·河南郑州·期中"
+    },
+    {
+        "id":  "301",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "琳琳的3个好朋友到她家玩。琳琳妈妈拿出24块糖平均分给琳琳和她的好朋友，平均每人分到( )块。",
+        "options":  [
+                        "6",
+                        "8",
+                        "9"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】先用加法确定总人数，再用总糖数除以人数得出每人分到的数量。\n\n【详解】24÷(1+3)=24÷4=6(块),平均每人分到6块。故答案为:A",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算",
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "24-25二年级下·河南许昌·期中"
+    },
+    {
+        "id":  "302",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "下面说法错误的是( )。",
+        "options":  [
+                        "把36个苹果平均分装在4个盘里，每盘装9个。",
+                          "算式27÷3÷3与算式27÷(3×3)的计算结果相同。",
+                        "18+27÷9和(18+27)÷9的运算顺序相同。"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】根据除法的意义和整数四则混合运算的法则，逐分析各个选项，找出说法错误的答案即可。\n\n【详解】A。把36个苹果平均分装在4个盘里，每盘装9个，说法正确;B。27÷3/3=9÷3=3,27÷(3×3)=27÷9=3，两个算式的计算结果相同，说法正确;C。18+27÷9这道题先算除法，再算加法,(18+27)÷9这道题先算括号里面的加法，再算括号外面的除法，运算顺序不相同，说法错误;故答案为:C",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算",
+                                 "除加",
+                                 "除减混合运算",
+                                 "表内连乘",
+                                 "连除运算",
+                                 "用7~9的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·广西玉林·期中"
+    },
+    {
+        "id":  "303",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "在博白各家美食街里18元可以买6个龙潭虾公籺，买3个这样的龙潭虾公籺需要多少钱。( )",
+        "options":  [
+                        "6×3",
+                        "18÷6×3",
+                        "18÷3×6"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】根据题意，先用花的钱数18元除以可以买的数量6个，求出每个的钱数，再和要买的数量相乘，就是需要的总钱数。\n\n【详解】由分析得:18÷6×3=3×3=9(元),买3个这样的龙潭虾公籺需要9元。正确的算式为18÷6×3。故答案为:B",
+        "knowledge_points":  [
+                                 "表内乘除混合运算"
+                             ],
+        "source":  "24-25 二年级下·广西玉林·期中"
+    },
+    {
+        "id":  "304",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "下面算式如果要求先算除法,( )必须添加小括号。",
+        "options":  [
+                        "24÷4+34",
+                        "25×8÷2",
+                        "57-81÷9"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】在没有括号的算式里，只有加，减法或只有乘，除法，要从左往右计算;在没有括号的算式里，如果既有乘，除法，又有加，减法，要先算乘，除法，再算加，减法;有括号的算式里，要先算括号里面的，再算括号外面的。由此解答。\n\n【详解】A。24÷4+34先算除法，再算加法，要想先算除法，不用添加小括号，不符合题意;B。25×8÷2先算乘法，再算除法，要想先算除法，必须添加小括号为25×(8÷2),符合题意;C。57-81÷9先算除法，再算减法，要想先算除法，不用添加小括号，不符合题意。则如果要求先算除法,25×8÷2必须添加小括号。故答案为:B",
+        "knowledge_points":  [
+                                 "有括号的运算顺序",
+                                 "无括号的运算顺序",
+                                 "除加",
+                                 "除减混合运算"
+                             ],
+        "source":  "24-25 二年级下·福建福州·期中"
+    },
+    {
+        "id":  "305",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "二(1)班的同学准备在\"天空农场\"种向日葵，需要栽8行，每行栽9棵，还剩多少棵没有栽。列式为8×9-7，横线上应填( )。",
+        "options":  [
+                        "已经栽了7行",
+                        "已经栽了7棵",
+                        "还剩7行没栽"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】由题意可知：用需要栽的行数乘每行栽的棵数，即8×9是一共要栽树的总棵树，要想算出还剩多少棵树没有栽，条件中缺少已经栽树的棵数;故从选项中找出已经栽树的棵树即可;据此可解。\n\n【详解】由分析可得：二(1)班的同学准备在\"天空农场\"种向日葵，需要栽8行，每行栽9棵，还剩多少棵没有栽。列式为8×9-7，横线上应填已经栽了7棵树。故答案为:B",
+        "knowledge_points":  [
+                                 "表内乘加",
+                                 "乘减",
+                                 "乘加",
+                                 "乘减混合运算"
+                             ],
+        "source":  "24-25二年级下·湖南邵阳·期中"
+    },
+    {
+        "id":  "306",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "皮皮和奇奇看同一本书。皮皮3天看完这本书，他第一天看了12页，后两天一共看了18页。奇奇平均每天看5页，他用几天能看完这本书。解决这个问题的正确算式是( )。",
+        "options":  [
+                        "18÷6×3",
+                        "(12+18)÷3",
+                        "(12+18)÷5"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】由题意可知：把皮皮第一天看的页数和后两天看的相加，即是这本书的页数，再除以奇奇每天看的页数，即是奇奇能看的天数;据此解答。\n\n【详解】由分析可得:(12+18)÷5=30÷5=6(天),他用6天能看完这本书。故答案为:C",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算",
+                                 "用6的乘法口诀求商",
+                                 "两位数与两位数的进位加法"
+                             ],
+        "source":  "24-25 二年级下·湖南邵阳·期中"
+    },
+    {
+        "id":  "307",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "下面算式中，小括号去掉后，得数不变的是( )。",
+        "options":  [
+                        "76-(12+25)",
+                        "(12-5)×3",
+                        "(72-18)+9"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】在没有括号的算式里，如果只有加减法或者只有乘除法，要从左往右依次计算。在没有括号的算式里，如果既有乘除法又有加减法，要先算乘除法，再算加减法。在有括号的算式里，要先算括号里面的，再算括号外面的。由题意可知：小括号去掉后，运算顺序不发生改变，得数也不会发生改变;A。76-(12+25):先算小括号里面的加法，去掉小括号后，先算减法;不符合题意;B。(12-5)×3：先算小括号里面的减法，去掉小括号后，先算乘法;不符合题意;C。(72-18)+9：先算小括号里面的减法，去掉小括号后，先算减法;符合题意;据此可选。\n\n【详解】由分析可得：下面算式中，小括号去掉后，得数不变的是(72-18)+9。故答案为:C",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算",
+                                 "乘加",
+                                 "乘减混合运算",
+                                   "两、三位数的加减混合运算"
+                             ],
+        "source":  "24-25 二年级下·湖南邵阳·期中"
+    },
+    {
+        "id":  "308",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "与\"86-36-24\"的结果不相等的算式是( )。",
+        "options":  [
+                        "86-24-36",
+                        "86-(36+24)",
+                        "86-(36-24)"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】整数混合运算中，同级运算时，从左到右依次计算;两级运算时，先算乘除，后算加减;有括号时，先算括号里面的，再算括号外面的。算出各算式的结果再作对比即可。\n\n【详解】86-36-24=50-24=26;86-24-36=62-36=26;86-(36+24)=86-60=26;86-(36-24)=86-12=74;与\"86-36-24\"的结果不相等的算式是86-(36-24)。故答案为:C",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算",
+                                 "100以内数的加减混合运算",
+                                 "100以内数的连减运算"
+                             ],
+        "source":  "24-25二年级下·湖南邵阳·期中"
+    },
+    {
+        "id":  "309",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "选择题",
+        "difficulty":  0.94,
+        "question":  "下列说法正确的是( )。",
+        "options":  [
+                        "把20本练习本分给4个同学，每个同学一定分得5本。",
+                        "计算10-6÷1与(10-6)÷1，这两个算式的运算顺序不同，计算结果相同。",
+                        "统计数据时必须用写\"正\"字的方法。"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】根据题意，分析各选项，找出符合题意的即可。A。把一个整体平均分成几份，用除法计算。20÷4=5(本),本选项没说是平均分，所以不一定每份都相等。B。分别计算出两个算式的结果，然后再比较结果的大小，第1个算式是除减运算，先算除法再算减法，第2个算式是带有小括号的，先算小括号里的减法，再算除法。C。统计数据时可以用多种符号来表示数量的多少，不一定必须用正字来表示。\n\n【详解】A。把20本练习本平均分给4个同学，每个同学分得5本，原选项没说是平均分，说法错误。B。10-6÷1=10-6=4,(10-6)÷1=4÷1=4，两个算式的结果相同，运算顺序不同，原选项说法正确。C。统计数据时可以用√,*,△,☆。表示数量的多少，不一定必须用写\"正\"字，原选项说法错误。故答案为:B",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算",
+                                 "整数平均分的意义及应用",
+                                 "数据的搜集与整理"
+                             ],
+        "source":  "24-25 二年级下·福建莆田·期中"
+    },
+    {
+        "id":  "310",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "57连续减8，减( )次后，得数是1。",
+        "options":  [
+                        "6",
+                        "7",
+                        "8"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】要求57连续减8多少次后得1，即求57减去多少个8等于1。先计算总减少量:57-1=56，再用56÷8即可求解。(57-1)÷8=56÷8=7,57连续减8，减7次后，得数是1。故答案为:B",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算",
+                                 "用7~9的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·广东云浮·期中"
+    },
+    {
+        "id":  "311",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "下面说法正确的是( )。",
+        "options":  [
+                        "③和④",
+                        "②和④",
+                        "①和④",
+                        "①和②"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】在除法算式中，被除数/除数=商，当被除数和除数都是6时，商是6÷6=1，因此①的说法不正确;混合运算的运算顺序：如果只有加减法或只有乘除法，按照从左到右的顺序计算;如果既有加减法又有乘除法，要先算乘除法，再算加减法;如果有括号，要先算括号里面的，再算括号外面的。计算6+3×5时，先算乘法，再算加法，因此②的说法不正确;一个图形沿着一条直线对折后，直线两旁的部分能够完全重合，这样的图形就叫做轴对称图形。平行四边形不管沿着哪条直线对折，直线两旁的部分都不能完全重合，所以平行四边形不是轴对称图形，因此③的说法正确;根据乘法口诀求商时，口诀中的后一个数为被除数，前两个数一个作除数，一个作商。计算27÷9=。时，可以想(三)九二十七，商是3，因此④的说法正确。\n\n【详解】由分析可知：说法正确的是③和④。故答案为:A",
+        "knowledge_points":  [
+                                 "乘加",
+                                 "乘减混合运算",
+                                 "用7~9的乘法口诀求商",
+                                 "用6的乘法口诀求商",
+                                 "轴对称的认识及辨认"
+                             ],
+        "source":  "24-25 二年级下·福建龙岩·期中"
+    },
+    {
+        "id":  "312",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "下列算式中，能按从左往右的顺序计算的是( )。",
+        "options":  [
+                        "42+3×8",
+                        "65-28+19",
+                        "48÷(9-3)",
+                        "36+18÷9"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】在没有括号的算式里，只有加，减法或只有乘，除法，要从左往右计算;在没有括号的算式里，如果既有乘，除法，又有加，减法，要先算乘，除法，再算加，减法;有括号的算式里，要先算括号里面的，再算括号外面的。由此解答。\n\n【详解】A。42+3×8=42+24=66，先算乘法，再算加法，不符合题意;B。65-28+19=37+19=56，从左往右计算，符合题意;C。48÷(9-3)=48÷6=8，先算减法，再算除法，不符合题意;D。36+18÷9=36+2=38，先算除法，再算加法，不符合题意。则能按从左往右的顺序计算的是65-28+19。故答案为:B",
+        "knowledge_points":  [
+                                 "100以内数的加减混合运算",
+                                 "乘加",
+                                 "乘减混合运算",
+                                 "除加",
+                                 "除减混合运算",
+                                 "带有小括号的混合运算"
+                             ],
+        "source":  "24-25 二年级下·福建龙岩·期中"
+    },
+    {
+        "id":  "313",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "每排种8棵白菜，可以种9排，还剩多少棵白菜没种。如果列式为9×8-5，那么横线上应补充的信息是( )。",
+        "options":  [
+                        "已经种了5排",
+                        "已经种了5棵",
+                        "还剩5排没种",
+                        "一共种了5排"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】根据题意可知，每排白菜的棵数乘可以种的排数，等于白菜的总棵数，算式9×8表示白菜的总棵数，如果列式为9×8-5，问题是：还剩下多少棵白菜没种，需要补充的条件为：已经种的棵数，逐项分析各个选项，找出正确答案，即可解答。\n\n【详解】A。已种5排，总棵数:9×8=72(棵),算式应为72-5×8，列式并非是9×8-5，不符合题意;B。已种5棵，算式为9×8-5，符合题意;C。剩5排未种，算式应为5×8=40(棵),不符合题意;D。共种5排，算式同A,不符合题意。每排种8棵白菜，可以种9排，还剩多少棵白菜没种。如果列式为9×8-5，那么横线上应补充的信息是已经种了5棵。故答案为:B",
+        "knowledge_points":  [
+                                 "\"提问题\"\"填条件\"问题",
+                                 "表内乘加",
+                                 "乘减"
+                             ],
+        "source":  "24-25 二年级下·福建龙岩·期中"
+    },
+    {
+        "id":  "314",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "王师傅用56分钟把一根木料锯成了8段，平均每锯一次需要( )分钟。",
+        "options":  [
+                        "7",
+                        "8",
+                        "48"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】由题意可知：把一根木料锯成了8段，只需锯8-1次，用总时间除以锯的次数，即是平均锯一次需要的时间。据此解答。\n\n【详解】由分析可得:56÷(8-1)=56÷7=8(分钟),平均每锯一次需要8分钟。故答案为:B",
+        "knowledge_points":  [
+                                 "植树问题(两端都不栽)",
+                                 "带有小括号的混合运算",
+                                 "用7~9的乘法口诀求商"
+                             ],
+        "source":  "24-25二年级下·河南许昌·期中"
+    },
+    {
+        "id":  "315",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "把30-22=8,8×4=32这两个算式合并成一个综合算式是( )。",
+        "options":  [
+                        "30-22×4",
+                        "(30-22)×4",
+                        "8×4-30"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】同级运算，从左往右依次运算，两级运算，先算乘除，后算加减;有括号的，先算小括号里面的;因为要先算减法，再算乘法，需要用小括号改变运算顺序。故，这两个算式合并成一个综合算式时，减法运算要添上小括号，则有(30-22)×4。\n\n【详解】由分析可知：把30-22=8,8×4=32这两个算式合并成一个综合算式是(30-22)×4。故答案为:B",
+        "knowledge_points":  [
+                                 "有括号的运算顺序",
+                                 "带有小括号的混合运算"
+                             ],
+        "source":  "24-25 二年级下·黑龙江佳木斯·期末"
+    },
+    {
+        "id":  "316",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "笑笑做手工花，每天做7朵，做了9天，还少21朵，笑笑需要做多少朵手工花。解答时要先求( )。",
+        "options":  [
+                        "剩下的朵数",
+                        "一共要做的朵数",
+                        "已经做的朵数"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】根据题意，要求笑笑需要做多少朵手工花，分两步解答;先算出笑笑9天做了几朵手工花，再加上还要做的朵数，即可求出笑笑一共需要做多少朵手工花。\n\n【详解】由分析可得：笑笑做手工花，每天做7朵，做了9天，还少21朵，笑笑需要做多少朵手工花。解答时要先求笑笑9天已经做的朵数。故答案为:C",
+        "knowledge_points":  [
+                                 "乘加",
+                                 "乘减混合运算"
+                             ],
+        "source":  "24-25 二年级下·山东济南·期末"
+    },
+    {
+        "id":  "317",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "下列算式中，去掉括号不改变计算结果的是( )。",
+        "options":  [
+                        "36+(27÷9)",
+                        "53-(33-17)",
+                        "(66-6)÷6"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】根据四则混合运算的运算法则，逐一分析三个选项，选出去掉括号不改变计算结果的即可。(1)在没有括号的算式里，如果只有加减法或者只有乘除法，要从左往右依次计算;(2)在没有括号的算式里，如果既有乘除法又有加减法，要先算乘除法，再算加减法;(3)在有括号的算式里，要先算括号里面的，再算括号外面的。\n\n【详解】A。36+(27÷9),先算除法，再算加法，去掉括号之后变成36+27÷9，还是先算除法，再算加法，运算顺序不变，结果也不变;B。53-(33-17),先算小括号里面的减法，再算括号外面的减法，去掉括号之后变成53-33-17，是按照从左到右的顺序计算，所以运算顺序变了，结果也变了;C。(66-6)÷6，先算小括号里面的减法，再算除法，去掉括号之后变成66-6÷6，先算除法，再算减法，所以运算顺序变了，结果也变了;故答案为:A",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算",
+                                 "除加",
+                                 "除减混合运算"
+                             ],
+        "source":  "24-25 二年级下·福建福州·期中"
+    },
+    {
+        "id":  "318",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "把42-36=6,18÷6=3这两个算式合并成一个综合算式正确的是( )。",
+        "options":  [
+                        "42-36÷6",
+                        "18÷(42-36)",
+                        "42-18÷6"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】将第二个算式中6替换成第一个算式42-36，最终结果是求两个数的商，综合算式中有除法和减法，要保证先算减法，再算除法，减法要加上小括号，逐项分析各个选项，找出正确答案即可解答。\n\n【详解】A。42-36÷6，先算除法，再算减法，不符合题意;B。18÷(42-36),先算减法，再算除法，符合题意;C。42-18÷6，先算除法，再算减法，不符合题意;把42-36=6,18÷6=3这两个算式合并成一个综合算式正确的是18÷(42-36)=3。故答案为:B",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算"
+                             ],
+        "source":  "24-25 二年级下·浙江台州·期末"
+    },
+    {
+        "id":  "319",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "黄河路公交车上原来有47人，下车24人，上车16人，现在车上有几人。正确的算式为( )。",
+        "options":  [
+                        "47-24-16",
+                        "47+24-16",
+                        "47-(24-16)"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】由题意可知，现在车上的人数=黄河路公交车上原来的人数-下车的人数+又上车的人数或者也可以用\"抵消\"的方法理解：把\"下车24人\"和\"上车16人\"放在一起看，相当于先下车24人，其中有16人其实等于没走(抵消了),真正离开的只有24-16=8(人),所以现在车上的人数，就相当于原来的47人，减去\"真正离开的8人\"，也就是47-(24-16)。\n\n【详解】由分析可知：求现在车上有几人，列式为:47-24+16或47-(24-16)。故答案为:C",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算",
+                                 "100以内数的加减混合运算"
+                             ],
+        "source":  "24-25 二年级下·浙江台州·期末"
+    },
+    {
+        "id":  "320",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "下面算式中，先算减法的是( )。",
+        "options":  [
+                        "45+26-13",
+                        "99-81÷9",
+                        "(11-7)×4"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】四则混合运算的运算法则:①在没有括号的算式里，如果只有加减法或者只有乘除法，要从左往右依次计算。②在没有括号的算式里，如果既有乘除法又有加减法，要先算乘除法，再算加减法。③在有括号的算式里，要先算括号里面的，再算括号外面的。据此分析各个算式的运算顺序，看哪个算式先算减法即可解答。\n\n【详解】A。计算45+26-13时，从左往右依次计算，先算加法，后算减法;B。计算99-81÷9时，先算除法，后算减法;C。计算(11-7)×4时，先算括号里的减法，再算括号外的乘法。故答案为:C",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算",
+                                 "除加",
+                                 "除减混合运算",
+                                 "100以内数的加减混合运算"
+                             ],
+        "source":  "24-25 二年级下·湖北武汉·期末"
+    },
+    {
+        "id":  "321",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "对下列算式的计算步骤判断不正确的是( )。",
+        "options":  [
+                        "①先算乘法，再算减法",
+                        "②先算除法，再算乘法",
+                        "③先算除法，再算减法"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】既有减法又有乘法的混合运算，先算乘法，再算减法;只有乘除法的混合运算，从左往右计算;含有小括号的混合运算，先算小括号里面的，再算小括号外面的。\n\n【详解】A。42-7×5先算乘法，再算减法，原计算步骤正确;B。56÷8×9先算除法，再算乘法，原计算步骤正确;C。(42-24)÷3先算减法，再算除法，原计算步骤不正确;故答案为:C",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算",
+                                 "无括号的运算顺序"
+                             ],
+        "source":  "24-25二年级下·陕西渭南·期末"
+    },
+    {
+        "id":  "322",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "计算(72-18)÷9时，应先算( )法，再算( )法。",
+        "options":  [
+
+                    ],
+        "answer":  "减 除",
+        "solution":  "【分析】在没有括号的算式里，只有加，减法或只有乘，除法，要从左往右计算;在没有括号的算式里，如果既有乘，除法，又有加，减法，要先算乘，除法，再算加，减法;有括号的算式里，要先算括号里面的，再算括号外面的。由此解答。\n\n【详解】由分析得：计算(72-18)÷9时，应先算减法，再算除法。",
+        "knowledge_points":  [
+                                 "有括号的运算顺序",
+                                 "带有小括号的混合运算"
+                             ],
+        "source":  "24-25二年级下·河北廊坊·期中"
+    },
+    {
+        "id":  "323",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "把52-44=8,56÷8=7合并成一个综合算式是( );被除数是48，除数是41-33，列出的综合算式是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "56÷(52-44)=748÷(41-33)=6",
+        "solution":  "【分析】根据题意，先计算出52减44的差，再用56除以这个差，最终的结果是两个数的商，综合算式中有减法和除法，先算减法，再算除法,56写在前,52-44代替8写在后，要加小括号;除法算式为：被除数/除数=商，除数是41减33的差，综合算式中有减法和除法，先算减法，再算除法,48写在前,41-33加上小括号写在后。\n\n【详解】41-33=8;48÷8=6，把52-44=8,56÷8=7合并成一个综合算式是56÷(52-44)=7;被除数是48，除数是41-33，列出的综合算式是48÷(41-33)=6。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算"
+                             ],
+        "source":  "24-25 二年级下·河南许昌·期中"
+    },
+    {
+        "id":  "324",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "在括号里填上合适的数.\n48÷6=( )÷254/( )=45-394×2=32÷( )",
+        "options":  [
+
+                    ],
+        "answer":  "1694",
+        "solution":  "【分析】48÷6=( )÷2先计算出等号左边48÷6的结果，再根据\"被除数=除数×商\"计算出括号里的数，列式为48÷6×2;54÷( )=45-39先计算出等号右边45-39的结果，再根据\"除数=被除数/商\"计算出括号里的数，列式为54÷(45-39);4×2=32÷( )先计算出等号左边4×2的结果，再根据\"除数=被除数/商\"计算出括号里的数，列式为32÷(4×2)。\n\n【详解】48÷6=( )÷2括号里的数为:48÷6×2=8×2=16，即48÷6=(16)÷2;54÷( )=45-39括号里的数为:54÷(45-39)=54÷6=9，即54÷(9)=45-39;4×2=32÷( )括号里的数为:32÷(4×2)=32÷8=4，即4×2=32÷(4)。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算",
+                                 "表内乘除混合运算"
+                             ],
+        "source":  "24-25 二年级下·广西玉林·期中"
+    },
+    {
+        "id":  "325",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "把52-44=8,56÷8=7合并成一个综合算式是( );被除数是48，除数是41-33，列出的综合算式是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "56÷(52-44)=748÷(41-33)=6",
+        "solution":  "【分析】根据题意，先计算出52减44的差，再用56除以这个差，最终的结果是两个数的商，综合算式中有减法和除法，先算减法，再算除法,56写在前,52-44代替8写在后，要加小括号;除法算式为：被除数/除数=商，除数是41减33的差，综合算式中有减法和除法，先算减法，再算除法,48写在前,41-33加上小括号写在后。\n\n【详解】41-33=8;48÷8=6，把52-44=8,56÷8=7合并成一个综合算式是56÷(52-44)=7;被除数是48，除数是41-33，列出的综合算式是48÷(41-33)=6。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算"
+                             ],
+        "source":  "24-25二年级下·河南许昌·期中"
+    },
+    {
+        "id":  "326",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "莉莉在计算5+□*7时，弄错了顺序，先算了加法，得到的结果是63，这道算式的正确结果是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "33",
+        "solution":  "【分析】根据题意,63÷7=9，所以5+□=9,9-5=4，即□=4，再计算出5+4×7的结果即可解答。\n\n【详解】5+4×7=5+28=33，莉莉在计算5+□*7时，弄错了顺序，先算了加法，得到的结果是63，这道算式的正确结果是33。",
+        "knowledge_points":  [
+                                 "无括号的运算顺序",
+                                 "乘加",
+                                 "乘减混合运算"
+                             ],
+        "source":  "24-25二年级下·甘肃天水·期末"
+    },
+    {
+        "id":  "327",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "把12+15=27和27÷9=3合并成一个综合算式是( )。把13-6=7,63-7=56合并成一个综合算式为( )。",
+        "options":  [
+
+                    ],
+        "answer":  "(12+15)÷9=3;63-(13-6)=56",
+        "solution":  "【分析】观察题目：由12+15=27可知，可以用12+15替换27÷9=3中的27，再根据整数四则混合运算的顺序，保证运算结果不变需要把12+15加上小括号，最后写出综合算式即可。由13-6=7可知，可以用13-6替换63-7=56中的7，再根据整数四则混合运算的顺序，保证运算结果不变需要把13-6加上小括号，最后写出综合算式即可。\n\n【详解】由分析可得：把12+15=27和27÷9=3合并成一个综合算式是(12+15)÷9=3。把13-6=7,63-7=56合并成一个综合算式为63-(13-6)=56。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算",
+                                 "用7~9的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·甘肃天水·期末"
+    },
+    {
+        "id":  "328",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "把7×9=63和70-63=7合并成一道综合算式( )。",
+        "options":  [
+
+                    ],
+        "answer":  "70-7×9=7",
+        "solution":  "【分析】根据题意，先计算出7乘9的积，再用70减去这个积，最后的结果是两个数的差，综合算式中，先算乘法，再算减法，把70写在前面，用7×9代替63写在后面。\n\n【详解】由分析得：把7×9=63和70-63=7合并成一道综合算式70-7×9=7。",
+        "knowledge_points":  [
+                                 "乘加",
+                                 "乘减混合运算"
+                             ],
+        "source":  "24-25二年级下·湖南邵阳·期中"
+    },
+    {
+        "id":  "329",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "被减数是80，减数是42-27列成一道综合算式应该是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "80-(42-27)=65",
+        "solution":  "【分析】根据题意，被减数是80，减数是42-27的差，需要将这两个数合并成一个综合算式。由于减数部分本身是一个减法运算，需先计算42-27，因此需要用小括号确保运算顺序正确。\n\n【详解】80-(42-27)=80-15=65，被减数是80，减数是42-27列成一道综合算式应该是80-(42-27)=65。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算"
+                             ],
+        "source":  "24-25 二年级下·福建莆田·期中"
+    },
+    {
+        "id":  "330",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "计算40-4×6时，要先算( )法，再算( )法。",
+        "options":  [
+
+                    ],
+        "answer":  "乘;减",
+        "solution":  "【分析】在没有括号的算式里，只有加，减法或只有乘，除法，都要从左往右按顺序计算;如果既有乘，除法，又有加，减法，要先算乘，除法，后算加，减法。\n\n【详解】计算40-4×6时要先算乘法，再算减法。",
+        "knowledge_points":  [
+                                 "乘加",
+                                 "乘减混合运算"
+                             ],
+        "source":  "24-25 二年级下·福建莆田·期中"
+    },
+    {
+        "id":  "331",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在计算8×(4+5)时，先算( )法，最后的结果是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "加;72",
+        "solution":  "【分析】在有括号的算式里，要先算括号里面的，再算括号外面的，据此解答。\n\n【详解】由分析可得:8×(4+5)=8×9=72，在计算8×(4+5)时，先算加法，最后的结果是72。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算"
+                             ],
+        "source":  "24-25二年级下·福建漳州·期中"
+    },
+    {
+        "id":  "332",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "东东在计算\"5+( )×9\"时弄错了顺序，先算加法后算乘法得数是72，正确的得数应该是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "3;32",
+        "solution":  "【分析】根据错误的运算顺序，先算加法后算乘法，得到72。由此可逆推出括号中的数，再代入括号中的数，按正确运算顺序计算即可。\n\n【详解】(5+□)×9=72,5+□=72÷9=8，因此括号里的数为:8-5=3。把3代入，按正确顺序计算:5+3×9=5+27=32，正确的得数是32。因此，东东在计算\"5+(3)×9\"时弄错了顺序，先算加法后算乘法得数是72，正确的得数应该是(32)。",
+        "knowledge_points":  [
+                                 "乘加",
+                                 "乘减混合运算"
+                             ],
+        "source":  "24-25 二年级下·福建莆田·期中"
+    },
+    {
+        "id":  "333",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "34与56的和比29多( ),21比5个9少( )。",
+        "options":  [
+
+                    ],
+        "answer":  "61;24",
+        "solution":  "【分析】第一空：先计算34与56的和，再减去29，得到多的部分。第二空：先计算5个9的和，再减去21，得到少的部分。\n\n【详解】34+56-29=90-29=61,5×9-21=45-21=24,34与56的和比29多61,21比5个9少24。",
+        "knowledge_points":  [
+                                 "乘加",
+                                 "乘减混合运算",
+                                 "100以内数的加减混合运算",
+                                 "两位数与两位数的退位减法"
+                             ],
+        "source":  "24-25二年级下·福建莆田·期中"
+    },
+    {
+        "id":  "334",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "32加上16的和再除以8。结果是多少。列综合算式是( )。计算时，应先算( )法，再算( )法。",
+        "options":  [
+
+                    ],
+        "answer":  "(32+16)÷8=6;加;除",
+        "solution":  "【分析】根据题意，先算32与16的和，再用这个和除以8。列综合算式时，加法需要加上括号以保证优先运算，因此算式为(32+16)÷8。计算时，先算括号内的加法，再算括号外的除法。\n\n【详解】由分析可知：32加上16的和再除以8，列综合算式是(32+16)÷8=6。计算时，应先算加法，再算除法。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算"
+                             ],
+        "source":  "24-25二年级下·福建莆田·期中"
+    },
+    {
+        "id":  "335",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "计算8×3÷4时，先算( )法，再算( )法，结果是( )。计算36÷(7+2)时，先算( )法，再算( )法，结果是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "乘;除;6;加;除;4",
+        "solution":  "【分析】混合运算的运算顺序：如果只有加减法或只有乘除法，按照从左到右的顺序计算;如果既有加减法又有乘除法，要先算乘除法，再算加减法;如果有括号，要先算括号里面的，再算括号外面的。8×3÷4按照从左到右的顺序，先算乘法8×3=24，再算除法24÷4=6;36÷(7+2)先算括号里面的加法7+2=9，再算括号外面的除法36÷9=4。\n\n【详解】由分析得：计算8×3÷4时，先算(乘)法，再算(除)法，结果是(6)。计算36÷(7+2)时，先算(加)法，再算(除)法，结果是(4)。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算",
+                                 "表内乘除混合运算"
+                             ],
+        "source":  "24-25 二年级下·福建福州·期中"
+    },
+    {
+        "id":  "336",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "6×3+5的结果是( ),如果要改变运算顺序，先算加法再算乘法，这个算式应是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "23;6×(3+5)",
+        "solution":  "【分析】在没有括号的算式里，如果只有加减法或者只有乘除法，要从左往右依次计算。在没有括号的算式里，如果既有乘除法又有加减法，要先算乘除法，再算加减法。在有括号的算式里，要先算括号里面的，再算括号外面的。6×3+5：先算乘法，再算加法;如果要改变运算顺序，先算加法再算乘法，这个算式中的加法加上小括号;据此解答。\n\n【详解】由分析可得:6×3+5=18+5=23,6×(3+5)=6×8=48,6×3+5的结果是23，如果要改变运算顺序，先算加法再算乘法，这个算式应是6×(3+5)。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算",
+                                 "乘加",
+                                 "乘减混合运算"
+                             ],
+        "source":  "24-25 二年级下·福建龙岩·期中"
+    },
+    {
+        "id":  "337",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在(45-30)÷5中，先算( )法，再算( )法。",
+        "options":  [
+
+                    ],
+        "answer":  "减;除",
+        "solution":  "【分析】根据四则混合运算的运算法则，在有括号的算式里，要先算括号里面的，再算括号外面的;据此解答。\n\n【详解】由分析可得：在(45-30)÷5中，先算减法，再算除法。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算"
+                             ],
+        "source":  "23-24二年级下·云南昭通·期末"
+    },
+    {
+        "id":  "338",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "小东在计算\"6+□×4\"时弄错了运算顺序，先算加法后算乘法了，得数是36，正确的得数应该是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "18",
+        "solution":  "【分析】本题采取逆推的方法，后算的乘法，即6+□的和是一个因数,4是另一个因数，积是36，根据乘法算式各部分的关系可以求出6+□的值，进而可以求出□的值;再把□的值代入算式，按照正确的运算顺序求出正确的结果。\n\n【详解】根据题意，小东先算加法后算乘法，得数为36，可列式:(6+□)×4=36，所以6+□=36÷4=9,□=9-6=3。将□=3代入原式，按正确顺序(先乘后加)计算:6+3×4=6+12=18。",
+        "knowledge_points":  [
+                                 "乘加",
+                                 "乘减混合运算"
+                             ],
+        "source":  "24-25 二年级下·广西玉林·期中"
+    },
+    {
+        "id":  "339",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "把44-12=32,32÷4=8合并成一个综合算式是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "(44-12)÷4=8",
+        "solution":  "【分析】根据运算顺序，先算括号内的减法，再算除法。将第二个算式中的32替换为44-12，并添加括号确保运算顺序正确。\n\n【详解】将44-12=32和32÷4=8合并成一个综合算式时，需用44-12代替32，得到(44-12)÷4。(44-12)÷4=32÷4=8，即综合算式为(44-12)÷4=8。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算"
+                             ],
+        "source":  "24-25 二年级下·湖北黄冈·期末"
+    },
+    {
+        "id":  "340",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "有6个小朋友进行1分钟跳绳比赛，成绩如下:\n![](images/224954.png)\n(1)跳得最多的小朋友是( ),跳得最少的小朋友是( ).\n(2)如果小乐想超过小慧，他至少再跳( )个。",
+        "options":  [
+
+                    ],
+        "answer":  "小明;小乐;16",
+        "solution":  "【分析】根据题意，(1)把这些数按照从大到小的顺序排列，最大的就是跳得最多的，最少的就是跳得最少的。165 > 156 > 137 > 109 > 93 > 78。(2)用小慧跳的数量-小乐跳的数量+1=小乐想超过小慧至少需要再跳的数量，据此解答。\n\n【详解】(1)跳得最多的小朋友是小明，跳得最少的小朋友是小乐。(2)93-78+1=16(个)，如果小乐想超过小慧，他至少再跳16个。",
+        "knowledge_points":  [
+                                 "100以内数的加减混合运算",
+                                 "两位数与两位数的退位减法",
+                                 "1000以内数的比大小"
+                             ],
+        "source":  "24-25 二年级下·湖北随州·期末"
+    },
+    {
+        "id":  "341",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "24+16÷8的结果是( );如果要改变它的运算顺序，那新的算式是( ),结果是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "26;(24+16)÷8;5",
+        "solution":  "【分析】四则混合运算的运算法则：在没有括号的算式里，如果只有加减法或者只有乘除法，要从左往右依次计算;在没有括号的算式里，如果既有乘除法又有加减法，要先算乘除法，再算加减法;在有括号的算式里，要先算括号里面的，再算括号外面的。计算24+16÷8时，先算除法，再算加法;如果要改变运算顺序，就要使用小括号。24+16÷8=24+2=26,(24+16)÷8=40÷8=5，所以,24+16÷8的结果是26;如果要改变它的运算顺序，那新的算式是(24+16)÷8，结果是5。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算",
+                                 "除加",
+                                 "除减混合运算"
+                             ],
+        "source":  "24-25二年级下·广东潮州·期末"
+    },
+    {
+        "id":  "342",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "一本故事书，小米看了一个星期，每天看6页，还剩46页没看。这本故事书一共有( )页。",
+        "options":  [
+
+                    ],
+        "answer":  "88",
+        "solution":  "【分析】先根据乘法的意义，小米看的天数×平均每天看的页数=一个星期看的书的页数，再根据加法的意义，一个星期看的书的页数+还剩下没有看的页数=这本书的总页数，由此列出算式算出答案即可解答。\n\n【详解】7×6+46=42+46=88(页)，所以，这本故事书一共有88页。",
+        "knowledge_points":  [
+                                 "乘加",
+                                 "乘减混合运算"
+                             ],
+        "source":  "24-25 二年级下·广东潮州·期末"
+    },
+    {
+        "id":  "343",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "草莓糖有18颗，奶酥糖有12颗，总共有( )颗糖。要是平均分给6个小朋友，每人能分到( )颗糖，综合算式是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "30;5;(18+12)÷6",
+        "solution":  "【分析】用草莓糖的颗数加上奶酥糖的颗数，即可求出总共有多少颗;用糖果的总数除以6，即可求出每人能分到多少颗;列综合算式时，先算加法，再算除法，需要在加法算式上添加小括号;据此解答。\n\n【详解】18+12=30(颗),30÷6=5(颗),综合算式:(18+12)÷6，草莓糖有18颗，奶酥糖有12颗，总共有30颗糖。要是平均分给6个小朋友，每人能分到5颗糖，综合算式是(18+12)÷6。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算",
+                                 "用6的乘法口诀求商",
+                                 "整数平均分的意义及应用"
+                             ],
+        "source":  "24-25 二年级下·福建福州·期末"
+    },
+    {
+        "id":  "344",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "计算14+21÷7时，应先算( )法，再算( )法;计算(14+21)÷7时，应先算( )法，后算( )法。",
+        "options":  [
+
+                    ],
+        "answer":  "除;加;加;除",
+        "solution":  "【分析】在没有括号的算式里，如果只有加减法或者只有乘除法，要从左往右依次计算。在没有括号的算式里，如果既有乘除法又有加减法，要先算乘除法，再算加减法。在有括号的算式里，要先算括号里面的，再算括号外面的。14+21÷7：先算除法，再算加法;(14+21)÷7：先算括号里面的，再算括号外面的;据此可解。\n\n【详解】由分析可得：计算14+21÷7时，应先算除法，再算加法;计算(14+21)÷7时，应先算加法，后算除法。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算",
+                                 "除加",
+                                 "除减混合运算"
+                             ],
+        "source":  "24-25 二年级下·甘肃天水·期末"
+    },
+    {
+        "id":  "345",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "乐乐，安安买了相同的笔，乐乐买了8支，安安买了5支，乐乐比安安多花了12元，每支笔( )元。",
+        "options":  [
+
+                    ],
+        "answer":  "4",
+        "solution":  "【分析】根据题意，乐乐买了8支，安安买了5支，乐乐比安安多买了8-5=3(支),多花了12元，然后再根据整数除法的意义，用3支总的价钱除以笔的支数，即可得出每支笔的价钱，据此解答即可。\n\n【详解】12÷(8-5)=12÷3=4(元),因此，每支笔4元。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算"
+                             ],
+        "source":  "24-25 二年级下·福建福州·期末"
+    },
+    {
+        "id":  "346",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "23+7=30,30÷6=5，列综合算式是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "(23+7)÷6=5",
+        "solution":  "【分析】从题干可知：先算出23+7的和，再用它们的和30除以6，据此列式。因为加法和除法不是同级运算，所以要在加法外面加上一个小括号。据此解答即可。(23+7)÷6=30÷6=5，所以23+7=30,30÷6=5，列综合算式是(23+7)÷6=5。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算",
+                                 "除加",
+                                 "除减混合运算"
+                             ],
+        "source":  "24-25 二年级下·内蒙古赤峰·期末"
+    },
+    {
+        "id":  "347",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "聪聪在计算52-□÷3时，把\"÷\"错看成了\"+\"，得出的结果是37，那么正确的结果是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "46",
+        "solution":  "【分析】把\"÷\"错看成\"+\"后，原算式就变成了52-□+3。根据错误的结果先求出□里的数，再按正确运算顺序求出原算式的结果。\n\n【详解】52-□+3=37，所以55-□=37，□=18。正确的算式是52-18÷3=52-6=46，所以正确的结果是46。",
+        "knowledge_points":  [
+                                 "除加",
+                                 "除减混合运算"
+                             ],
+        "source":  "24-25 二年级下·内蒙古赤峰·期末"
+    },
+    {
+        "id":  "348",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "朵朵计算36+45-9时，应先算( )法，再算( )法。如果她想先算减法，你有什么好办法。列式是( ),结果是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "加;减;36+(45-9);72",
+        "solution":  "【分析】四则混合运算的运算法则：在没有括号的算式里，如果只有加减法或者只有乘除法，要从左往右依次计算;在没有括号的算式里，如果既有乘除法又有加减法，要先算乘除法，再算加减法;在有括号的算式里，要先算括号里面的，再算括号外面的。\n\n【详解】根据分析可得：计算36+45-9时，应先算加法，再算减法。如果想先算减法，则需要将\"45-9\"用小括号括起来，列式是36+(45-9)。36+(45-9)=36+36=72，所以，计算36+45-9时，应先算加法，再算减法。如果她想先算减法，列式是36+(45-9),结果是72。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算",
+                                 "100以内数的加减混合运算"
+                             ],
+        "source":  "24-25 二年级下·吉林四平·期末"
+    },
+    {
+        "id":  "349",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "把42-34=8,8×7=56合并成综合算式是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "(42-34)×7=56",
+        "solution":  "【分析】先计算42减34的差，再用这个差乘7，得到结果56。因此需要将减法用括号括起来，确保运算顺序正确，由此即可求解。\n\n【详解】根据分析可得:(42-34)×7=8×7=56，综合算式为:(42-34)×7=56，把42-34=8,8×7=56合并成综合算式是(42-34)×7=56。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算"
+                             ],
+        "source":  "24-25 二年级下·贵州黔东南·期末"
+    },
+    {
+        "id":  "350",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "把算式42÷6=7,22-16=6合并成一道综合算式是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "42÷(22-16)=7",
+        "solution":  "【分析】根据题意，需要将两个算式合并成一个综合算式：首先观察第二个算式22-16=6的结果是第一个算式中的除数6，因此需要用22-16替换第一个算式中的6;综合算式中有减法和除法，先算减法，再算除法，需把减法加上小括号。据此可解。42÷(22-16)=42÷6=7，把算式42÷6=7,22-16=6合并成一道综合算式是42÷(22-16)=7。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算",
+                                 "用7~9的乘法口诀求商",
+                                 "两位数与两位数的退位减法"
+                             ],
+        "source":  "24-25 二年级下·辽宁鞍山·期末"
+    },
+    {
+        "id":  "351",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "小明和他的5个小朋友一起夹了32颗珠子，其他同学夹得同样多，小明比其他同学多夹了2颗，小明夹了( )颗。",
+        "options":  [
+
+                    ],
+        "answer":  "7",
+        "solution":  "【分析】小明夹的颗数=其他同学平均每人夹的颗数+2颗，其中，其他同学平均每人夹的颗数=(夹的总颗数-2颗)÷夹珠子的总人数(6人)；据此解答。\n\n【详解】1+5=6(人)，(32-2)÷6=30÷6=5(颗)，5+2=7(颗)，即小明夹了7颗。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算"
+                             ],
+        "source":  "24-25二年级下·浙江台州·期末"
+    },
+    {
+        "id":  "352",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "把4×7=28,92-28=64合并成一个综合算式是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "92-4×7=64",
+        "solution":  "【分析】先观察两个算式的关系，4×7的结果28被代入到第二个算式中作为减数。根据运算顺序，乘法优先于减法，因此直接替换即可，无需添加括号。\n\n【详解】由分析可知：将4×7=28代入92-28=64中，替换28得到92-4×7=92-28=64，所以把4×7=28，92-28=64合并成一个综合算式是92-4×7=64。",
+        "knowledge_points":  [
+                                 "乘加",
+                                 "乘减混合运算"
+                             ],
+        "source":  "24-25 二年级下·内蒙古呼伦贝尔·期末"
+    },
+    {
+        "id":  "353",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "把2+4=6和54÷6=9合并成一个算式是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "54÷(2+4)=9",
+        "solution":  "【分析】先用\"2+4\"代替\"54÷6=9\"中的\"6\"，再根据算式的计算顺序，单独的算式是先算加法，再算除法，所以代替后的算式需要给\"2+4\"加上小括号，才能保证计算顺序和结果都不发生改变。\n\n【详解】根据分析可得:54÷(2+4)=54÷6=9，所以，把2+4=6和54÷6=9合并成一个算式是54÷(2+4)=9。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算"
+                             ],
+        "source":  "24-25 二年级下·河北张家口·期末"
+    },
+    {
+        "id":  "354",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "把5×6=30和50-30=20合成一个综合算式是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "50-5×6=20",
+        "solution":  "【分析】将两个分步算式合并成一个综合算式时，需要找到第二个算式中的哪个数是由第一个算式得到的，并用第一个算式代替这个数。本题中第二个算式中的30是由5×6得到的，因此将50-30=20中的30替换为5×6即可;这道题先算乘法，再算减法，所以不需要添加括号，据此写出综合算式。\n\n【详解】根据分析可得：把5×6=30和50-30=20合成一个综合算式是50-5×6=20。",
+        "knowledge_points":  [
+                                 "乘加",
+                                 "乘减混合运算"
+                             ],
+        "source":  "24-25 二年级下·湖南株洲·期末"
+    },
+    {
+        "id":  "355",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "计算18÷3×2=18÷6=3。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】根据运算顺序，在没有括号的算式里，只有加，减法或只有乘，除法，要从左往右计算，由此解答。\n\n【详解】由分析得:18÷3×2=6×2=12，原题计算错误。故答案为: ×",
+        "knowledge_points":  [
+                                 "表内乘除混合运算"
+                             ],
+        "source":  "24-25 二年级下·广西玉林·期中"
+    },
+    {
+        "id":  "356",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "36-8÷4=34。( )",
+        "options":  [
+
+                    ],
+        "answer":  "√",
+        "solution":  "【分析】整数混合运算中，同级运算时，从左到右依次计算;两级运算时，先算乘除，后算加减。题目中应先计算8÷4，再计算36减去所得结果。\n\n【详解】36-8÷4=36-2=34，则36-8÷4=34，原题说法正确。故答案为:√",
+        "knowledge_points":  [
+                                 "除加",
+                                 "除减混合运算"
+                             ],
+        "source":  "24-25 二年级下·河北廊坊·期中"
+    },
+    {
+        "id":  "357",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "计算4×(18-9)时，先算乘法。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】在没有括号的算式里，只有加，减法或只有乘，除法，要从左往右计算;在没有括号的算式里，如果既有乘，除法，又有加，减法，要先算乘，除法，再算加，减法;有括号的算式里，要先算括号里面的，再算括号外面的。由此解答。\n\n【详解】由分析可知：计算4×(18-9)时，先算减法，再算乘法，原题说法错误。故答案为: ×",
+        "knowledge_points":  [
+                                 "有括号的运算顺序",
+                                 "带有小括号的混合运算"
+                             ],
+        "source":  "24-25 二年级下·广西·期中"
+    },
+    {
+        "id":  "358",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "小括号不能改变算式的运算顺序。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】在四则运算中，小括号的作用是改变运算顺序，使其内部的运算优先进行。例如，算式3+4×2的运算顺序是先乘后加，结果为11;而加上小括号后的算式(3+4)×2，运算顺序变为先加后乘，结果为14。由此可见，小括号能够改变原算式的运算顺序;据此可解。\n\n【详解】由分析可得：小括号能改变算式的运算顺序。故答案为: ×",
+        "knowledge_points":  [
+                                 "有括号的运算顺序",
+                                 "带有小括号的混合运算"
+                             ],
+        "source":  "24-25 二年级下·甘肃临夏·期中"
+    },
+    {
+        "id":  "359",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "计算3+27÷9的运算顺序是从左往右。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】混合运算的运算顺序：如果只有加减法或只有乘除法，按照从左到右的顺序计算;如果既有加减法又有乘除法，要先算乘除法，再算加减法;如果有括号，要先算括号里面的，再算括号外面的。题目中的算式3+27÷9包含除法和加法，应先计算除法，再计算加法，而不是从左往右依次计算。\n\n【详解】由分析可知：计算3+27÷9时，应先算除法部分:27÷9=3，再算加法部分:3+3=6。因此，运算顺序不是从左往右，而是先算除法后算加法。原题说法错误。故答案为: ×",
+        "knowledge_points":  [
+                                 "除加",
+                                 "除减混合运算"
+                             ],
+        "source":  "24-25 二年级下·甘肃临夏·期中"
+    },
+    {
+        "id":  "360",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "6+8×7与(6+8)×7都要先算乘法。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】在没有括号的算式里，如果只有加减法或者只有乘除法，要从左往右依次计算。在没有括号的算式里，如果既有乘除法又有加减法，要先算乘除法，再算加减法。在有括号的算式里，要先算括号里面的，再算括号外面的。6+8×7：先算乘法，再算加法;(6+8)×7：先算括号里面的加法，再算括号外面的乘法;据此可解。\n\n【详解】由分析可得:6+8×7与(6+8)×7不是都要先算乘法。题干说法错误。故答案为: ×",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算",
+                                 "乘加",
+                                 "乘减混合运算"
+                             ],
+        "source":  "24-25 二年级下·四川德阳·期末"
+    },
+    {
+        "id":  "361",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "计算35-(23-15)时，先算23-15。( )",
+        "options":  [
+
+                    ],
+        "answer":  "√",
+        "solution":  "【分析】根据四则混合运算的运算规则，在有括号的算式里，要先算括号里面的，再算括号外面的;计算35-(23-15)时，要先算括号里面的23-15，再算括号外面的减法。\n\n【详解】由分析可得：计算35-(23-15)时，要先算23-15，原题说法正确。故答案为:√",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算"
+                             ],
+        "source":  "24-25 二年级下·四川德阳·期末"
+    },
+    {
+        "id":  "362",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "计算题",
+        "difficulty":  0.85,
+        "question":  "脱式计算。\n83-39+17  (77-47)÷5  24+12÷6",
+        "options":  [
+
+                    ],
+        "answer":  "61;6;26",
+        "solution":  "【分析】在没有括号的算式里，如果只有加减法或者只有乘除法，要从左往右依次计算。在没有括号的算式里，如果既有乘除法又有加减法，要先算乘除法，再算加减法。在有括号的算式里，要先算括号里面的，再算括号外面的。第1题：从左往右依次计算;第2题：先算括号里面的，再算括号外面的;第3题：先算除法，再算加法。据此解答。\n\n【详解】由分析可得:83-39+17=44+17=61;(77-47)÷5=30÷5=6;24+12÷6=24+2=26。",
+        "knowledge_points":  [
+                                 "100以内数的加减混合运算",
+                                 "除加",
+                                 "除减混合运算",
+                                 "带有小括号的混合运算"
+                             ],
+        "source":  "24-25 二年级下·福建莆田·期中"
+    },
+    {
+        "id":  "363",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "计算题",
+        "difficulty":  0.65,
+        "question":  "70减去6的差，再除以8，商是多少。",
+        "options":  [
+
+                    ],
+        "answer":  "8",
+        "solution":  "【分析】根据题意，先用减法计算出70与6的差，再用这个差除以8，最终的结果是两个数的商，综合算式中有减法和除法，要保证先算减法，再算除法，需要把减法加小括号。(70-6)÷8=64÷8=8,70减去6的差，再除以8，商是8。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算"
+                             ],
+        "source":  "24-25 二年级下·江西抚州·期末"
+    },
+    {
+        "id":  "364",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "计算题",
+        "difficulty":  0.85,
+        "question":  "计算下面各题。\n18+27÷9  4×6÷3  54÷(22-13)",
+        "options":  [
+
+                    ],
+        "answer":  "21;8;6",
+        "solution":  "【分析】(1)先算除法，再算加法;(2)从左往右先算乘法，再算除法;(3)先算括号内的减法，再算除法。\n\n【详解】18+27÷9=18+3=21;4×6÷3=24÷3=8;54÷(22-13)=54÷9=6。",
+        "knowledge_points":  [
+                                 "表内乘除混合运算",
+                                 "除加",
+                                 "除减混合运算",
+                                 "带有小括号的混合运算"
+                             ],
+        "source":  "24-25 二年级下·陕西渭南·期末"
+    },
+    {
+        "id":  "365",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "一辆玩具小汽车24元，买4个布娃娃一共花了32元，一辆玩具小汽车比一个布娃娃贵多少元。\n口答：一辆玩具小汽车比一个布娃娃贵( )元。",
+        "options":  [
+
+                    ],
+        "answer":  "16",
+        "solution":  "【分析】先用4个布娃娃的价钱除以4，求出一个布娃娃的价钱，再用一辆玩具小汽车的价钱减去一个布娃娃的价钱，即可求出一辆玩具小汽车比一个布娃娃贵多少元。24-32÷4=24-8=16(元),答：一辆玩具小汽车比一个布娃娃贵16元。",
+        "knowledge_points":  [
+                                 "除加",
+                                 "除减混合运算"
+                             ],
+        "source":  "24-25二年级下·甘肃临夏·期中"
+    },
+    {
+        "id":  "366",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "宴石山是博白有名的旅游景点，为保护宴石山摩崖石刻周边环境，志愿者计划种植56棵松树。第一天种了8排，每排5棵，第二天还需种多少棵。",
+        "options":  [
+
+                    ],
+        "answer":  "16棵",
+        "solution":  "【分析】由题意可知：用排数乘每排的棵数，即是第一天种树的棵数;用总棵数减去第一天种的棵数，即是第二天需要种的棵数。据此解答。\n\n【详解】由分析可得:56-8×5=56-40=16(棵),答：第二天还需种16棵。",
+        "knowledge_points":  [
+                                 "乘加",
+                                 "乘减混合运算",
+                                 "8的乘法口诀及应用",
+                                 "两位数与整十数的减法"
+                             ],
+        "source":  "24-25 二年级下·广西玉林·期中"
+    },
+    {
+        "id":  "367",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "学校食堂面包房里一共要烤95个面包，已经烤了47个。如果每次能烤8个，剩下的还要烤几次。",
+        "options":  [
+
+                    ],
+        "answer":  "6次",
+        "solution":  "【分析】根据题意，先用要烤的总数量减去已经烤了的数量，计算出剩下没烤的数量。再用没烤的数量除以每次烤的数量，即可求出要烤的次数。\n\n【详解】(95-47)÷8=48÷8=6(次),答：剩下的还要烤6次。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算"
+                             ],
+        "source":  "24-25 二年级下·广西玉林·期中"
+    },
+    {
+        "id":  "368",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "博白公园动物园饲养小组有8个兔笼，每个笼子装4只，后来又买来6只，现在一共有多少只兔子。",
+        "options":  [
+
+                    ],
+        "answer":  "38只",
+        "solution":  "【分析】先用每个笼子装的兔子只数乘兔笼的个数，求出原来兔子的只数，再加上又买来的兔子只数，即可求出现在一共有多少只兔子。8×4+6=32+6=38(只),答：现在一共有38只兔子。",
+        "knowledge_points":  [
+                                 "乘加",
+                                 "乘减混合运算"
+                             ],
+        "source":  "24-25 二年级下·广西玉林·期中"
+    },
+    {
+        "id":  "369",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "博白县是芒编大县，那林镇芒编厂用56米藤条编筐，每个筐用7米，已编5个筐，剩余藤条还能编几个筐。",
+        "options":  [
+
+                    ],
+        "answer":  "3个",
+        "solution":  "【分析】先用编一个筐用的藤条米数乘已经编的筐的个数，求出已经用的藤条米数，再用藤条的总米数减去已经用的藤条米数，求出剩余藤条的米数，最后用剩余藤条的米数除以编一个筐用的米数，即可求出剩余藤条还能编几个筐。\n\n【详解】56-7×5=56-35=21(米),21÷7=3(个),答：剩余藤条还能编3个筐。",
+        "knowledge_points":  [
+                                 "乘加",
+                                 "乘减混合运算",
+                                 "用7~9的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·广西玉林·期中"
+    },
+    {
+        "id":  "370",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "4月23日是\"世界读书日\"。新华书店原来每本15元的图书，在这一天\"买5本只需45元\"，每本比原来便宜了多少元。",
+        "options":  [
+
+                    ],
+        "answer":  "6元",
+        "solution":  "【分析】先计算现在每本的单价，再用原价减去现价得到每本便宜的钱数。\n\n【详解】15-45÷5=15-9=6(元),答：每本比原来便宜了6元。",
+        "knowledge_points":  [
+                                 "除加",
+                                 "除减混合运算",
+                                 "经济问题"
+                             ],
+        "source":  "24-25 二年级下·甘肃天水·期中"
+    },
+    {
+        "id":  "371",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "一瓶钙片有85片，吃掉49片后，剩下的钙片每天吃4片，剩下的还可以吃几天。",
+        "options":  [
+
+                    ],
+        "answer":  "9天",
+        "solution":  "【分析】首先计算剩下的钙片数量，再用剩下的数量除以每天吃的数量，得到可以吃的天数。(85-49)÷4=36÷4=9(天),答：剩下的还可以吃9天。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算"
+                             ],
+        "source":  "24-25二年级下·甘肃天水·期中"
+    },
+    {
+        "id":  "372",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "王老师为了奖励学习进步的同学，买了9支同样的钢笔，付了100元，找回19元，每支钢笔多少钱。",
+        "options":  [
+
+                    ],
+        "answer":  "9元",
+        "solution":  "【分析】根据题意，先用付出的钱数减去找回的钱数，计算出一共花了多少钱，再用花了的钱数除以买钢笔的数量，就是每支钢笔的钱数。\n\n【详解】(100-19)÷9=81÷9=9(元),答：每支钢笔9元钱。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算"
+                             ],
+        "source":  "24-25 二年级下·湖南邵阳·期中"
+    },
+    {
+        "id":  "373",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "爷爷家原来养了25只小鸡，又买来23只。把这些小鸡装进6个笼子里，平均每个笼子里装几只小鸡。",
+        "options":  [
+
+                    ],
+        "answer":  "8只",
+        "solution":  "【分析】根据题意，先用原来养小鸡的数量加上又买来的数量，计算出一共有多少只小鸡，再用小鸡的总数量除以笼子的数量，即可求出平均每个笼子装小鸡的数量。(25+23)÷6=48÷6=8(只),答：平均每个笼子里装8只小鸡。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算"
+                             ],
+        "source":  "24-25 二年级下·湖南邵阳·期中"
+    },
+    {
+        "id":  "374",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "一根绳子长30米，剪了5次(绳子不折叠)后分成长度相等的若干段。每段长多少米。",
+        "options":  [
+
+                    ],
+        "answer":  "5米",
+        "solution":  "【分析】由题意可知：剪了5次能剪5+1段，用绳子的总长除以段数，即是每段的长;据此解答。\n\n【详解】由分析可得:30÷(5+1)=30÷6=5(米),答：每段长5米。",
+        "knowledge_points":  [
+                                 "植树问题(两端都栽)",
+                                 "带有小括号的混合运算",
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "24-25二年级下·福建莆田·期中"
+    },
+    {
+        "id":  "375",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "二(1)班男生有28人，女生有26人，每6人组成一个学习小组，能组成几个学习小组。",
+        "options":  [
+
+                    ],
+        "answer":  "9个",
+        "solution":  "【分析】先用男生人数加女生人数，求二(1)班的总人数，再用总人数除以每个学习小组的人数，即可求出能组成几个学习小组。为保证先算加法，加法要加上括号。(28+26)÷6=54÷6=9(个),答：能组成9个学习小组。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算"
+                             ],
+        "source":  "24-25 二年级下·福建莆田·期中"
+    },
+    {
+        "id":  "376",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "一盒铅笔9元，一块橡皮3元，小明想买5盒铅笔和1块橡皮，带50元钱够吗。",
+        "options":  [
+
+                    ],
+        "answer":  "够",
+        "solution":  "【分析】先用一盒铅笔的价钱乘买的铅笔的盒数，求出5盒铅笔的价钱，再用5盒铅笔的价钱加上1块橡皮的价钱，求出5盒铅笔和1块橡皮的总价钱，最后再和50元比较，如果5盒铅笔和1块橡皮的总价钱比50少或等于50，就够;如果5盒铅笔和1块橡皮的总价钱比50多，就不够。9×5+3=45+3=48(元),48\u003c50，答：带50元钱够。",
+        "knowledge_points":  [
+                                 "表内乘加",
+                                 "乘减",
+                                 "100以内数的比大小"
+                             ],
+        "source":  "24-25 二年级下·福建福州·期中"
+    },
+    {
+        "id":  "377",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "同学们排队做操，每行站9人，站了4行，还多3人，一共有多少人做操。",
+        "options":  [
+
+                    ],
+        "answer":  "39人",
+        "solution":  "【分析】已知每行站9人，站了4行，根据乘法的意义，用9×4先算出4行有多少人，再加上多出的3人，即可得出共有多少人做操。9×4+3=36+3=39(人),答：一共有39人做操。",
+        "knowledge_points":  [
+                                 "乘加",
+                                 "乘减混合运算"
+                             ],
+        "source":  "24-25 二年级下·广东汕尾·期末"
+    },
+    {
+        "id":  "378",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "某学校在落实课后服务后，鼓励学生参加兴趣班，参加绘画班的有25人，参加音乐班的有20人，这些人平均分成9组，每组有几人。",
+        "options":  [
+
+                    ],
+        "answer":  "5人",
+        "solution":  "【分析】先把参加绘画班和音乐班的人数加起来，求出总人数，再用总人数除以平均分成的组数，即可求出每组有几人。因为要先算总人数，因此加法算式用括号括起来。(25+20)÷9=45÷9=5(人),答：这些人平均分成9组，每组有5人。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算"
+                             ],
+        "source":  "24-25 二年级下·山东济宁·期末"
+    },
+    {
+        "id":  "379",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "小明买铅笔用了2元，买练习本用了11元，他带了20元钱，还剩下多少元。",
+        "options":  [
+
+                    ],
+        "answer":  "7元",
+        "solution":  "【分析】根据题意，先算出买铅笔和练习本一共花了多少元，再用带的总钱数减去花的钱，即可求出还剩下多少元钱。20-(2+11)=20-13=7(元),答：还剩下7元。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算"
+                             ],
+        "source":  "24-25 二年级下·四川德阳·期末"
+    },
+    {
+        "id":  "380",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "一种跳绳，每根8元，二(1)班原来有9根，李老师又花56元买了一些这样的跳绳，现在这种跳绳有多少根。",
+        "options":  [
+
+                    ],
+        "answer":  "16根",
+        "solution":  "【分析】用李老师又花的56元钱除以每根跳绳8元，算出李老师又买了几根跳绳，再加上原来的跳绳根数，即可求出现在这种跳绳共有多少根。56÷8+9=7+9=16(根),答：现在这种跳绳有16根。",
+        "knowledge_points":  [
+                                 "除加",
+                                 "除减混合运算"
+                             ],
+        "source":  "24-25 二年级下·山东济南·期末"
+    },
+    {
+        "id":  "381",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "女生有21人，男生有24人。排队做操时，如果每9人站一排，可以站几排。",
+        "options":  [
+
+                    ],
+        "answer":  "5排",
+        "solution":  "【分析】先根据加法的意义算出男生和女生的总人数，再根据除法的意义，用男生和女生的总人数除以每排站的人数，由此可以列出一个综合算式,(女生人数+男生人数)/平均每排的人数=可以站的排数。\n\n【详解】(21+24)÷9=45÷9=5(排),答：可以站5排。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算"
+                             ],
+        "source":  "24-25 二年级下·广东潮州·期末"
+    },
+    {
+        "id":  "382",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "王老师把一些糖果平均分给6位小朋友，每人分得5颗糖果，还剩下2颗，如果把这些糖果平均分给4位小朋友，每位小朋友分得多少颗糖果。",
+        "options":  [
+
+                    ],
+        "answer":  "8颗",
+        "solution":  "【分析】根据题意，用每人分到的糖数乘小朋友的人数6，再加上剩下的2颗，即可算出这些糖一共的颗数;再用这些糖的总颗数除以小朋友的人数4，即可算出每人可以分到的糖的颗数。据此解答。\n\n【详解】由分析可得:5×6+2=30+2=32(颗),32÷4=8(颗),答：每位小朋友分得8颗糖果。",
+        "knowledge_points":  [
+                                 "表内乘加",
+                                 "乘减",
+                                 "用7~9的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·福建福州·期末"
+    },
+    {
+        "id":  "383",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "超市促销活动，可乐原来3元一瓶，现在买3送2,27元能买到几瓶。",
+        "options":  [
+
+                    ],
+        "answer":  "15瓶",
+        "solution":  "【分析】根据题意，用27÷3=9瓶，得出原来27元可以买9瓶，超市搞促销活动时买3送2，就是每购买3瓶再额外送2瓶，也就是可以得到5瓶，再用9÷3=3组，得出可以买3组买3送2，最后用乘法求出一共买的瓶数。27÷3×(3+2)=9÷3×(3+2)=3×5=15(瓶),答:27元能买到15瓶。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算"
+                             ],
+        "source":  "24-25 二年级下·山东济南·期末"
+    },
+    {
+        "id":  "384",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "超市运进54箱饮料，卖了4天后还剩18箱，平均每天卖多少箱。",
+        "options":  [
+
+                    ],
+        "answer":  "9箱",
+        "solution":  "【分析】根据题意可知，超市运进饮料的箱数减去还剩下的箱数，等于4天卖出的箱数，再用它们的差除以卖的天数，等于平均每天卖多少箱。\n\n【详解】(54-18)÷4=36÷4=9(箱),答：平均每天卖9箱。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算"
+                             ],
+        "source":  "24-25 二年级下·黑龙江佳木斯·期末"
+    },
+    {
+        "id":  "385",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "二(1)班有男生22人，女生20人，每6人一组参加劳动，可以分几组。",
+        "options":  [
+
+                    ],
+        "answer":  "7组",
+        "solution":  "【分析】根据题意，二(1)班男生的人数加女生的人数，等于二(1)班的总人数，总人数除以每组的人数，等于可以分成的组数，据此解答。(22+20)÷6=42÷6=7(组),答：可以分7组。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算"
+                             ],
+        "source":  "24-25 二年级下·黑龙江佳木斯·期末"
+    },
+    {
+        "id":  "386",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "每年5月的第二个星期日是母亲节。鲜花店上午卖出康乃馨8束，每束6元，下午卖了36元。鲜花店这一天一共卖了多少元。\n答：鲜花店这一天一共卖了( )元。",
+        "options":  [
+
+                    ],
+        "answer":  "84",
+        "solution":  "【分析】用上午卖出的康乃馨数量乘每束的价钱算出上午卖出的钱数，然后加上下午卖出的钱数即可求解。8×6+36=48+36=84(元),答：鲜花店这一天一共卖了84元。",
+        "knowledge_points":  [
+                                 "乘加",
+                                 "乘减混合运算",
+                                 "经济问题"
+                             ],
+        "source":  "24-25 二年级下·山东济宁·期末"
+    },
+    {
+        "id":  "387",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "蛋糕原来每个8元，现在开展\"3个21元\"的优惠促销活动，现在买3个蛋糕，每个比原来便宜多少元。",
+        "options":  [
+
+                    ],
+        "answer":  "1元",
+        "solution":  "【分析】由题意可知：用21除以3，算出的得数是现在每个蛋糕的钱数;用原来每个蛋糕的钱数减去现在每个蛋糕的钱数，即是每个比原来便宜的钱数;据此解答。\n\n【详解】由分析可得:8-21÷3=8-7=1(元),答：每个比原来便宜1元。",
+        "knowledge_points":  [
+                                 "除加",
+                                 "除减混合运算",
+                                 "用7~9的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·甘肃天水·期末"
+    },
+    {
+        "id":  "388",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "一条路长96米，修路队已经修了60米，剩下的计划4小时修完。平均每小时修几米。",
+        "options":  [
+
+                    ],
+        "answer":  "9米",
+        "solution":  "【分析】由题意可知：用一条路的总长减去已经修好的米数，即是剩下的米数，再除以修的小时数，即是平均每小时修的米数;据此解答。\n\n【详解】由分析可得:(96-60)÷4=36÷4=9(米),答：平均每小时修9米。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算",
+                                 "除加",
+                                 "除减混合运算",
+                                 "用7~9的乘法口诀求商",
+                                 "两位数与整十数的减法"
+                             ],
+        "source":  "24-25 二年级下·甘肃天水·期末"
+    },
+    {
+        "id":  "389",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "二(1)班组织学生乘车去三坊七巷游玩。其中女生18人，男生27人，需要多少辆中巴车？中巴车限乘9人。",
+        "options":  [
+
+                    ],
+        "answer":  "5辆",
+        "solution":  "【分析】由题意可知：把男女生的人数相加，算出乘车的总人数；用总人数除以中巴车限乘人数，即是需要中巴车的辆数；据此解答。\n\n【详解】(18+27)÷9=45÷9=5(辆)，答：需要5辆中巴车。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算",
+                                 "用7~9的乘法口诀求商",
+                                 "两位数与两位数的进位加法"
+                             ],
+        "source":  "24-25 二年级下·福建福州·期末"
+    },
+    {
+        "id":  "390",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "小区运来月季花，每行摆8盆可摆3行。若每行摆6盆，能摆几行。",
+        "options":  [
+
+                    ],
+        "answer":  "4行",
+        "solution":  "【分析】根据题意可知，每行摆的盆数乘摆的行数，等于月季花的总盆数。小区运来的月季花总盆数不变，现在每行摆6盆，用月季花的总盆数再除以每行摆的6盆，等于能摆几行，据此解答。\n\n【详解】8×3÷6=24÷6=4(行)，答：若每行摆6盆，能摆4行。",
+        "knowledge_points":  [
+                                 "表内乘除混合运算"
+                             ],
+        "source":  "24-25 二年级下·黑龙江佳木斯·期末"
+    },
+    {
+        "id":  "391",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "小马虎在做减法时，把被减数个位上的3看成了8，结果得45。正确的差是多少。",
+        "options":  [
+
+                    ],
+        "answer":  "40",
+        "solution":  "【分析】被减数个位上的3看成了8，则被减数多5，结果也就多5，用得到的结果减去5即可求出正确的差。\n\n【详解】45-(8-3)=45-5=40，答：正确的差是40。",
+        "knowledge_points":  [
+                                 "错中求解问题(加减法)"
+                             ],
+        "source":  "24-25 二年级下·黑龙江佳木斯·期末"
+    },
+    {
+        "id":  "392",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "妈妈买了30个鸡蛋，第一天吃了6个，第二天吃了剩下的一半，还剩下多少个鸡蛋。",
+        "options":  [
+
+                    ],
+        "answer":  "12个",
+        "solution":  "【分析】根据题意可知，妈妈买鸡蛋的个数减去第一天吃的个数，等于第一天后剩下的个数。第二天吃了剩下的一半，那么还剩下的也是这一半，所以用剩下的个数除以2，等于还剩下多少个鸡蛋，据此解答。\n\n【详解】根据分析可得：(30-6)÷2=24÷2=12(个)，答：还剩下12个鸡蛋。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算"
+                             ],
+        "source":  "24-25 二年级下·黑龙江佳木斯·期末"
+    },
+    {
+        "id":  "393",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "二年级一班有45人，二班比一班多8人，两个班一共有多少人。",
+        "options":  [
+
+                    ],
+        "answer":  "98人",
+        "solution":  "【分析】用一班的人数加二班比一班多的人数算出二班的人数，然后将两个班的人数相加即可求解。45+8+45=53+45=98(人),答：两个班一共有98人。",
+        "knowledge_points":  [
+                                 "100以内数的连加运算"
+                             ],
+        "source":  "24-25 二年级下·黑龙江佳木斯·期末"
+    },
+    {
+        "id":  "394",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "小明用35元买了4本笔记本，每本笔记本7元，他还剩多少钱。",
+        "options":  [
+
+                    ],
+        "answer":  "7元",
+        "solution":  "【分析】用买的笔记本的数量乘每本的价钱算出买笔记本花的钱数，然后用35元减去买笔记本花的钱数即可求解。35-4×7=35-28=7(元),答：他还剩7元钱。",
+        "knowledge_points":  [
+                                 "乘加",
+                                 "乘减混合运算",
+                                 "经济问题"
+                             ],
+        "source":  "24-25 二年级下·黑龙江佳木斯·期末"
+    },
+    {
+        "id":  "395",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "李叔叔和王叔叔都是外卖骑手，下面是他们今天的接单量，李叔叔说\"我上午接了16单，我们下午接的单同样多.\"王叔叔上午接了多少单。\n| 王叔叔 | 李叔叔 |\n| ------ | ------ |\n| 42单 | 48单 |",
+        "options":  [
+
+                    ],
+        "answer":  "10单",
+        "solution":  "【分析】根据题意，方法一，用李叔叔接单的总数减去李叔叔上午接单的数量即可求出李叔叔下午接单的数量，王叔叔和李叔叔下午接的单同样多，用王叔叔接单的总数减去下午接单的数量即可求出王叔叔上午接单的数量。方法二，王叔叔和李叔叔下午接的单同样多，李叔叔接单总量大于王叔叔接单总量，李叔叔上午接单量大于王叔叔上午接单量，用李叔叔上午接单量减去李叔叔比王叔叔多的总量，即可求出王叔叔上午接了多少单，据此解答。\n\n【详解】方法一:42-(48-16)=42-32=10(单);方法二:16-(48-42)=16-6=10(单);答：王叔叔上午接了10单。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算",
+                                 "100以内数的加减混合运算",
+                                 "图文问题"
+                             ],
+        "source":  "24-25 二年级下·内蒙古赤峰·期末"
+    },
+    {
+        "id":  "396",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "学校买来30本科技书,24本故事书，把这些书平均分给6个年级，每个年级分到多少本书。",
+        "options":  [
+
+                    ],
+        "answer":  "9本",
+        "solution":  "【分析】首先将科技书和故事书的总本数相加，得到总共有多少本书，然后将总本数平均分给6个年级，用除法计算每个年级分到的书本数量，由此列出一个综合算式即可解答。\n\n【详解】(30+24)÷6=54÷6=9(本),答：每个年级分到9本书。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算"
+                             ],
+        "source":  "24-25 二年级下·广东汕头·期末"
+    },
+    {
+        "id":  "397",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "六一儿童节，妈妈带文文去玩具店买礼物。\n![](images/9f50fe2eca43fd2c3411bb500d1b4e6a.png)\n(1)买一辆小汽车的钱正好可以买4个布娃娃，每个布娃娃多少钱。\n(2)文文买了3辆小火车和1个皮球，一共花了多少钱。",
+        "options":  [
+
+                    ],
+        "answer":  "9元;26元",
+        "solution":  "【分析】(1)用一辆小汽车的价钱除以4，求出商，就是每个布娃娃的价钱。(2)先用1辆小火车的价钱乘3求出3辆小火车多少钱，然后加上一个皮球的价钱，即可求出一共花了多少钱。\n\n【详解】(1)36÷4=9(元),答：每个布娃娃9元钱。(2)7×3+5=21+5=26(元),答：一共花了26元钱。",
+        "knowledge_points":  [
+                                 "乘加",
+                                 "乘减混合运算",
+                                 "用7~9的乘法口诀求商",
+                                 "经济问题",
+                                 "图文问题"
+                             ],
+        "source":  "24-25 二年级下·广东江门·期末"
+    },
+    {
+        "id":  "398",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "体育器材室有红皮球26个，有蓝皮球37个，把这些皮球平均分给7个班，每班可以分到几个皮球。",
+        "options":  [
+
+                    ],
+        "answer":  "9个",
+        "solution":  "【分析】先根据加法的意义，红皮球的数量+蓝皮球的数量=皮球的总数量，算出皮球总的数量。再根据除法的意义，皮球的总数量/班级的总数量=每个班平均分到的皮球数量，由此按照先算加法，再算除法的顺序，列出一个综合算式即可解答。\n\n【详解】(26+37)÷7=63÷7=9(个),答：每班可以分到9个皮球。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算"
+                             ],
+        "source":  "24-25 二年级下·河北张家口·期末"
+    },
+    {
+        "id":  "399",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "学校原来有16个篮球，又买来9个篮球。李老师想把这些篮球放在5个球筐里，平均每个球筐放几个篮球。",
+        "options":  [
+
+                    ],
+        "answer":  "5个",
+        "solution":  "【分析】根据题意，先将原来篮球的数量和又买来的数量相加，计算出现在一共有多少个篮球，再用篮球的总数量除以球筐的数量，即可计算出平均每个球筐放篮球的数量。(16+9)÷5=25÷5=5(个),答：平均每个球筐放5个篮球。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算"
+                             ],
+        "source":  "24-25 二年级下·内蒙古通辽·期末"
+    },
+    {
+        "id":  "400",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "爸爸买了一套茶几，其中一个茶壶50元,6个杯子一共42元，一个茶壶比一个杯子贵多少元。",
+        "options":  [
+
+                    ],
+        "answer":  "43元",
+        "solution":  "【分析】要求一个茶壶比一个杯子贵的金额，需先用杯子的总价除以杯子的数量，求出一个杯子的价格，再用一个茶壶价格减去一个杯子的价格，求出差即可解决。\n\n【详解】50-42÷6=50-7=43(元),口答：一个茶壶比一个杯子贵43元。",
+        "knowledge_points":  [
+                                 "经济问题",
+                                 "除加",
+                                 "除减混合运算"
+                             ],
+        "source":  "24-25 二年级下·陕西延安·期末"
+    },
+    {
+        "id":  "401",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "将56÷7=8,39-8=31合并成一道综合算式，应是( )。",
+        "options":  [
+                        "56÷7-39",
+                        "39-56÷7",
+                        "56÷7+39-8"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】观察发现算式39-8=31中的\"8\"是由算式56÷7=8得来的，那么将减数\"8\"替换为56÷7即可，算式中有除法和减法，先算除法，再算减法，逐项分析各个选项，找出正确答案即可解答。\n\n【详解】A。56÷7-39，先算56÷7=8，再算8减39，不够减，不符合题意;B。39-56÷7，根据运算顺序，先算56÷7=8，再算39-8=31，符合题意;C。56÷7+39-8，先算56÷7=8，再算8+39=47，最后47-8=39，结果是39，而正确答案为31，不符合题意;即，将56÷7=8,39-8=31合并成一道综合算式，应是(39-56÷7)。故答案为:B",
+        "knowledge_points":  [
+                                 "除加",
+                                 "除减混合运算"
+                             ],
+        "source":  "24-25二年级下·广西柳州·期末"
+    },
+    {
+        "id":  "402",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "估一估，下列算式中得数最大的是( )。",
+        "options":  [
+                        "45-14+18",
+                        "45-(14+18)",
+                        "45-14-18"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】找出得数和被减数的大小关系，然后比较即可。\n\n【详解】A。45减去14后又加了18，则得数比45大。B。45一共减去了14和18的和，得数比45小。C。45减去14后又减去18，得数比45小。比45大的数一定大于比45小的数。所以得数最大的是45-14+18。故答案为:A",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算",
+                                 "100以内数的加减混合运算",
+                                 "100以内数的连减运算",
+                                 "100以内数的比大小"
+                             ],
+        "source":  "24-25 二年级下·浙江杭州·期中"
+    },
+    {
+        "id":  "403",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "下面的算式与16÷8×2的计算结果一样的是( )。",
+        "options":  [
+                        "2×3+2",
+                        "(25+7)÷8",
+                        "16-32÷4"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】根据整数混合运算法则：同级运算，按照从左往右的顺序依次计算即可;不同级运算，先算乘除，再算加减;有小括号的运算，先算小括号内的算式，再算括号外的计算。据此算出16÷8×2的结果，再算出各个选项的得数，即可得出答案。\n\n【详解】16÷8×2=2×2=4;2×3+2=6+2=8;(25+7)÷8=32÷8=4;16-32÷4=16-8=8;与16÷8×2的计算结果一样的是(25+7)÷8。故答案为:B",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算",
+                                 "除加",
+                                 "除减混合运算",
+                                 "乘加",
+                                 "乘减混合运算"
+                             ],
+        "source":  "23-24 二年级下·湖南常德·期中"
+    },
+    {
+        "id":  "404",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "下面算式中，与24÷(6÷2)的计算结果相同的是( )。",
+        "options":  [
+                        "24÷6/2",
+                        "24÷6×2",
+                        "24÷(6-2)"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】整数混合运算中，同级运算时，从左到右依次计算；两级运算时，先算乘除，后算加减；有括号时，先算括号里面的，再算括号外面的。算出各算式的结果再作对比即可求解。\n\n【详解】24÷(6÷2)=24÷3=8；24÷6÷2=4÷2=2；24÷6×2=4×2=8；24÷(6-2)=24÷4=6；与24÷(6÷2)的计算结果相同的是24÷6×2。故答案为:B",
+        "knowledge_points":  [
+                                 "表内连乘",
+                                 "连除运算",
+                                 "表内乘除混合运算",
+                                 "带有小括号的混合运算"
+                             ],
+        "source":  "24-25 二年级下·山东日照·期中"
+    },
+    {
+        "id":  "405",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "从42里面连续减去6，减( )次后还剩6。",
+        "options":  [
+                        "5",
+                        "6",
+                        "7",
+                        "8"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】根据题意，从42里面连续减去6，求减去几次后还剩6，也就是求减去的数里面有几个6;所以可以根据被减数-差=减数，先用42减剩下的6，得到减去的数，再用减去的数除以6，即得到减的次数;再根据四则运算顺序计算;据此解答。\n\n【详解】根据分析可得:(42-6)÷6=36÷6=6，从42里面连续减去6，减6次后还剩6。故答案为:B",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算",
+                                 "用7~9的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·辽宁鞍山·期中"
+    },
+    {
+        "id":  "406",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "94-(22+48)=3×( )。",
+        "options":  [
+                        "8",
+                        "7",
+                        "6"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】根据整数加减法运算，先算出94-(22+48)的得数，再根据除法的意义，用算式得数除以3，即可得出括号内的数。\n\n【详解】94-(22+48)=94-70=24,24÷3=8，所以94-(22+48)=3×8。故答案为:A",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算",
+                                 "用7~9的乘法口诀求商"
+                             ],
+        "source":  "23-24二年级下·河北邯郸·期末"
+    },
+    {
+        "id":  "407",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "计算8+4×3时，应先算( )。",
+        "options":  [
+                        "8+4",
+                        "4×3",
+                        "8+3"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】根据整数混合运算法则：同级运算，按照从左往右的顺序依次计算即可;不同级运算，先算乘除，再算加减;有小括号的运算，先算小括号内的算式，再算括号外的计算，据此解答即可。\n\n【详解】据分析可知：计算8+4×3时，应先算乘法，再算加法。即先算4×3。故答案为:B",
+        "knowledge_points":  [
+                                 "乘加",
+                                 "乘减混合运算"
+                             ],
+        "source":  "24-25二年级下·山东日照·期中"
+    },
+    {
+        "id":  "408",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "超市促销：牛奶买3箱送1箱。王阿姨需要12箱，最少买( )箱。",
+        "options":  [
+                        "9",
+                        "10",
+                        "12"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】牛奶买3箱送1箱就是买(3+1)箱的钱只需要花买3箱牛奶的钱，王阿姨需要12箱,12÷(3+1)=3(组),3×3=9(箱),即最少买9箱即可。\n\n【详解】根据分析可得:12÷(3+1)=12÷4=3(组),3×3=9(箱),最少买9箱。故答案为:A",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算",
+                                 "3的乘法口诀及应用"
+                             ],
+        "source":  "24-25 三年级下·湖南·期中"
+    },
+    {
+        "id":  "409",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "下面的算式，不能省去括号的是( )。",
+        "options":  [
+                        "45-(6÷3)",
+                        "(27+36)÷7",
+                        "37+(20÷5)"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】根据题意，不能省去括号，也就是去掉括号后会改变运算顺序。在没有括号的算式里，只有加，减法或只有乘，除法，要从左往右计算;在没有括号的算式里，如果既有乘，除法，又有加，减法，要先算乘，除法，再算加，减法;有括号的算式里，要先算括号里面的，再算括号外面的。由此解答。\n\n【详解】A。45-(6÷3):先算除法，再算减法;去掉括号后45-6÷3：先算除法，再算减法，运算顺序相同，不符合题意;B。(27+36)÷7：先算加法，再算除法;去掉括号后27+36÷7：先算除法，再算加法，运算顺序不同，符合题意;C。37+(20÷5):先算除法，再算加法;去掉括号后37+20÷5：先算除法，再算加法，运算顺序相同，不符合题意。则不能省去括号的是(27+36)÷7。故答案为:B",
+        "knowledge_points":  [
+                                 "除加",
+                                 "除减混合运算",
+                                 "带有小括号的混合运算",
+                                 "无括号的运算顺序",
+                                 "有括号的运算顺序"
+                             ],
+        "source":  "23-24 二年级下·河南许昌·期末"
+    },
+    {
+        "id":  "410",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "妈妈用20个沙琪玛招待客人，如果给每位客人分6个，还剩2个，来了( )位客人。",
+        "options":  [
+                        "1",
+                        "2",
+                        "3"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】根据题意，先用沙琪玛的总数量减去剩下的数量，求出一共分给客人多少个沙琪玛，再除以分给每位客人的数量，就是分的人数。\n\n【详解】(20-2)÷6=18÷6=3(位),则来了3位客人。故答案为:C",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算"
+                             ],
+        "source":  "23-24 二年级下·河南许昌·期末"
+    },
+    {
+        "id":  "411",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "同学们要搬走100套课桌椅，男生搬走48套，女生搬走34套，计算还剩几套没搬走的正确列式是( )。",
+        "options":  [
+                        "100+48+37",
+                        "100-48+34",
+                        "100-(48+34)"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】可以用总数连续减去两次搬走的数量;还可以先算出搬走的数量，然后用总数减去搬走的数量，逐项分析。\n\n【详解】A。原式是连加计算，应该是连减，不对;B。应该是连减，不对;C。先算出搬走的数量，然后用总数减去搬走的数量，正确。同学们要搬走100套课桌椅，男生搬走48套，女生搬走34套，计算还剩几套没搬走的正确列式是:100-(48+34)。故答案为:C",
+        "knowledge_points":  [
+                                 "100以内数的连减运算",
+                                 "带有小括号的混合运算"
+                             ],
+        "source":  "24-25 二年级下·河南漯河·期末"
+    },
+    {
+        "id":  "412",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "把15-9=6和24÷6=4合并成一个综合算式是( )。",
+        "options":  [
+                        "24÷(15-9)",
+                        "24÷15-9",
+                        "15-9÷24"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】观察可知，第二个算式中的6可以用第一个算式代替，第一个算式是减法，有减有除，先算减法时，减法要用小括号括起来，这样就组成了一个综合算式，据此解答。\n\n【详解】把15-9=6和24÷6=4合并成一个综合算式，正确的是24÷(15-9)。故答案为:A",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算"
+                             ],
+        "source":  "23-24 二年级下·湖南长沙·期末"
+    },
+    {
+        "id":  "413",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "文文在计算2+□×9时，弄错了运算顺序，先算加法后算乘法，结果得数是72，这道算式的正确结果是( )。",
+        "options":  [
+                        "36",
+                        "38",
+                        "56"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】根据题意，先用错误的得数除以9，计算出2+□的和，再用这个和减去2得出□里的数，再代入到算式中，先算乘法，再算加法，计算出正确的结果即可。\n\n【详解】72÷9=8;8-2=6，则□是6;2+6×9=2+54=56，这道算式的正确结果是56。故答案为:C",
+        "knowledge_points":  [
+                                 "乘加",
+                                 "乘减混合运算"
+                             ],
+        "source":  "24-25 二年级下·陕西渭南·期中"
+    },
+    {
+        "id":  "414",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "民建小学二年级9个班进行踢毽子比赛，二年级参加比赛的一共有多少人。根据算式(3+5)×9可知，横线上补充的信息是( )。",
+        "options":  [
+                        "每班选出3队参赛，每队5名同学",
+                        "二(3)班派出5名同学参加",
+                        "每班选出3名男生和5名女生参加"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】根据题意，知道参加比赛的班级数，要想求一共有多少人，则还需要知道的条件是每个班参加的人数，3+5计算出的是每个班的人数，也就是两部分人数的和，由此解答。\n\n【详解】A。每班选出3队参赛，每队5名同学，应该用每队的人数和队数相乘，求出每班的人数，不符合题意；B。只有二(3)班的人数，不能计算出二年级参加比赛的总人数，不符合题意；C。男生的人数+女生的人数=每个班参加比赛的人数，也就是(3+5)×9能计算出二年级参加比赛的总人数，符合题意。则横线上补充的信息是每班选出3名男生和5名女生参加。故答案为:C",
+        "knowledge_points":  [
+                                 "\"提问题\"\"填条件\"问题",
+                                 "带有小括号的混合运算"
+                             ],
+        "source":  "24-25 二年级下·四川乐山·期中"
+    },
+    {
+        "id":  "415",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "下面各题中，与16÷4÷2结果一样的算式是( )。",
+        "options":  [
+                        "16÷4×2",
+                        "16÷2×4",
+                        "16÷(4×2)"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】整数混合运算中，同级运算时，从左到右依次计算；两级运算时，先算乘除，后算加减；有括号时，先算括号里面的，再算括号外面的。算出各算式的结果即可求解。\n\n【详解】16÷4÷2=4÷2=2；16÷4×2=4×2=8；16÷2×4=8×4=32；C。16÷(4×2)=16÷8=2；与16÷4÷2结果一样的算式是16÷(4×2)。故答案为:C",
+        "knowledge_points":  [
+                                 "表内连乘",
+                                 "连除运算",
+                                 "表内乘除混合运算",
+                                 "带有小括号的混合运算"
+                             ],
+        "source":  "23-24 二年级下·浙江台州·期末"
+    },
+    {
+        "id":  "416",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "把算式42÷6=7,32-26=6合并成一道综合算式是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "42÷(32-26)=7",
+        "solution":  "【分析】根据题意，需要将两个算式合并成一个综合算式。首先观察第二个算式32-26=6的结果是第一个算式中的除数6，因此需要用32-26替换第一个算式中的6。综合算式中有减法和除法，先算减法，再算除法，减法要加小括号。\n\n【详解】把算式42÷6=7,32-26=6合并成一道综合算式是42÷(32-26)=7。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算"
+                             ],
+        "source":  "24-25 二年级下·浙江嘉兴·期末"
+    },
+    {
+        "id":  "417",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "从54里面减去6，连续减( )次后得数是6。",
+        "options":  [
+
+                    ],
+        "answer":  "8",
+        "solution":  "【分析】根据题意，先用54减去最后的得数6，计算出共需要减去多少，再用需要减去的数除以每次减的数，就是要减的次数。\n\n【详解】(54-6)÷6=48÷6=8，从54里面减去6，连续减8次后得数是6。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算"
+                             ],
+        "source":  "24-25 二年级下·浙江嘉兴·期末"
+    },
+    {
+        "id":  "418",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "34-26=8,6×8=48，把这两个算式合并成一个综合算式是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "6×(34-26)=48",
+        "solution":  "【分析】要将这两个算式合并成一个综合算式，第二个算式中8替换成第一算式。但8是由34减26得到的，因此在综合算式中，必须把34减26加上小括号，这样才能保证先算减法，再将它们的差乘6，算出最终的结果，据此解答。\n\n【详解】根据分析可得:6×(34-26)=6×8=48,34-26=8,6×8=48，把这两个算式合并成一个综合算式是6×(34-26)=48。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算"
+                             ],
+        "source":  "24-25 二年级下·山西晋中·期末"
+    },
+    {
+        "id":  "419",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "42比3个6的和多( ),70减去30的差，再除以5得( )。",
+        "options":  [
+
+                    ],
+        "answer":  "24;8",
+        "solution":  "【分析】求42比3个6的和多几，先根据求几个几是多少，用乘法计算，先求出3个6是多少，再用42减去所得的积即可;求70减去30的差，再除以5得几，先用减法求出70与30的差，再用所得的差除以5即可。\n\n【详解】42-3×6=42-18=24;(70-30)÷5=40÷5=8,42比3个6的和多24,70减去30的差，再除以5得8。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算",
+                                 "乘加",
+                                 "乘减混合运算"
+                             ],
+        "source":  "24-25 二年级下·内蒙古赤峰·期中"
+    },
+    {
+        "id":  "420",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "计算21+35÷7时，应先算( )法，再算( )法，结果是( )。要想先算加法，需要把算式改为( )。",
+        "options":  [
+
+                    ],
+        "answer":  "除;加;26;(21+35)÷7",
+        "solution":  "【分析】四则混合运算的运算法则：在没有括号的算式里，如果只有加减法或者只有乘除法，要从左往右依次计算;在没有括号的算式里，如果既有乘除法又有加减法，要先算乘除法，再算加减法;在有括号的算式里，要先算括号里面的，再算括号外面的。\n\n【详解】根据分析可知，计算21+35÷7时，应先算除法，再算加法:21+35÷7=21+5=26，算得的结果是26。想要先算加法，需要把算式改为(21+35)÷7。所以，计算21+35÷7时，应先算除法，再算加法，结果是26。要想先算加法，需要把算式改为(21+35)÷7。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算"
+                             ],
+        "source":  "23-24 二年级下·湖南常德·期中"
+    },
+    {
+        "id":  "421",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "乐乐计算\"3+△*7\"时弄错了计算顺序，先算加法后算乘法，得数是56，正确的结果是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "38",
+        "solution":  "【分析】先按照错误的顺序逻辑，用56除以7算出答案后减去3，得到△代表的数。将算式还原补齐后，再按照先乘法，后加法的顺序算出正确答案即可解答。\n\n【详解】56÷7=8,8-3=5，即△代表的数是5，原算式为3+5×7.3+5×7=3+35=38，所以，正确的结果是38。",
+        "knowledge_points":  [
+                                 "表内乘加",
+                                 "乘减"
+                             ],
+        "source":  "23-24二年级下·重庆大渡口·期末"
+    },
+    {
+        "id":  "422",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "把32÷4=8,12+8=20合并成一个综合算式是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "12+32÷4=20",
+        "solution":  "【分析】此题是先算除法32÷4的商，再算12与这个商的和，根据运算顺序列出综合算式即可。\n\n【详解】由题意分析得：把32÷4=8,12+8=20合并成一个综合算式是:12+32÷4=20。",
+        "knowledge_points":  [
+                                 "表内乘加",
+                                 "乘减"
+                             ],
+        "source":  "22-23 二年级下·新疆乌鲁木齐·期中"
+    },
+    {
+        "id":  "423",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "老师拿出17颗小红花，每人奖励2颗，还剩余1颗，老师奖给了( )个小朋友。",
+        "options":  [
+
+                    ],
+        "answer":  "8",
+        "solution":  "【分析】已知总共有17颗小红花，每人奖2颗后剩余1颗，说明实际奖励的小红花数量为17-1=16颗。根据除法的意义，用实际奖励的总数除以每人奖励的数量，即可求出小朋友的人数。\n\n【详解】(17-1)÷2=16÷2=8(个),因此，老师奖给了8个小朋友。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算"
+                             ],
+        "source":  "22-23 二年级下·新疆乌鲁木齐·期末"
+    },
+    {
+        "id":  "424",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "27比5个5的和多( ),60减4的差，除以8得( )。",
+        "options":  [
+
+                    ],
+        "answer":  "2;7",
+        "solution":  "【分析】由题意可知：用乘法算出5个5的和，再用27减去5个5的和即可，列出综合算式;用60减4算出差，再用差除以8，列出综合算式时，先算减法，故减法运算要加小括号。据此计算。\n\n【详解】由分析可得:27-5×5=27-25=2;(60-4)÷8=56÷8=7，即,27比5个5的和多2,60减4的差，除以8得7。",
+        "knowledge_points":  [
+                                 "乘加",
+                                 "乘减混合运算",
+                                 "带有小括号的混合运算"
+                             ],
+        "source":  "22-23 二年级下·新疆乌鲁木齐·期末"
+    },
+    {
+        "id":  "425",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "彩塑也称泥塑，是雕塑艺术之一。奇奇和妈妈买了6个泥塑，每个9元，付给售货员100元，应找回( )元。",
+        "options":  [
+
+                    ],
+        "answer":  "46",
+        "solution":  "【分析】根据乘法的意义，用6×9先算出买6个泥塑一共需要多少钱，再用付给售货员的100元减去买6个泥塑用的钱，即可得出应找回多少元。100-6×9=100-54=46(元),所以应找回46元。",
+        "knowledge_points":  [
+                                 "乘加",
+                                 "乘减混合运算"
+                             ],
+        "source":  "24-25 二年级下·广西玉林·期末"
+    },
+    {
+        "id":  "426",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "把45-18=27和27÷3=9合并成一道综合算式为( )。",
+        "options":  [
+
+                    ],
+        "answer":  "(45-18)÷3=9",
+        "solution":  "【分析】从题干可知：先算出45-18=27，再用减法的差27除以3，得出商是9。因为除法和减法不是同级运算，根据整数混合运算，要在减法的运算外面加上括号，据此列式即可。(45-18)÷3=27÷3=9，所以把45-18=27和27÷3=9合并成一道综合算式为(45-18)÷3=9。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算"
+                             ],
+        "source":  "24-25 二年级下·广西玉林·期末"
+    },
+    {
+        "id":  "427",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "28÷7×7的运算顺序是先算( ),再算( )。",
+        "options":  [
+
+                    ],
+        "answer":  "除法;乘法",
+        "solution":  "【分析】根据整数混合运算法则：同级运算，按照从左往右的顺序依次计算即可;不同级运算，先算乘除，再算加减;有小括号的运算，先算小括号内的算式，再算括号外的计算，据此解答即可。因为乘法和除法是同级运算，且没有括号，则按照顺序从左往右依次计算即可。\n\n【详解】28÷7×7=4×7=28,28÷7×7的运算顺序是先算除法，再算乘法。(或先算28÷7，再算4×7)",
+        "knowledge_points":  [
+                                 "表内乘除混合运算"
+                             ],
+        "source":  "22-23二年级下·新疆乌鲁木齐·期末"
+    },
+    {
+        "id":  "428",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "小梅在计算\"3+□*4\"时弄错了运算顺序，先算加法后算乘法了，结果得数是36，正确的得数是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "27",
+        "solution":  "【分析】根据题意，先用错误的结果除以4，求出3+□的和，再减去3计算出□代表的数;代入到算式中，先算乘法，再算加法计算出结果即可。\n\n【详解】36÷4-3=9-3=6,□为6;3+6×4=3+24=27，小梅在计算\"3+□*4\"时弄错了运算顺序，先算加法后算乘法了，结果得数是36，正确的得数是27。",
+        "knowledge_points":  [
+                                 "乘加",
+                                 "乘减混合运算",
+                                 "除加",
+                                 "除减混合运算"
+                             ],
+        "source":  "24-25 二年级下·山东济南·期中"
+    },
+    {
+        "id":  "429",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "小梅在计算\"3+□*4\"时弄错了运算顺序，先算加法后算乘法了，结果得数是36，正确的得数是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "27",
+        "solution":  "【分析】根据题意，先用错误的结果除以4，求出3+□的和，再根据和-一个加数=另一个加数，计算出□代表的数，代入到算式中，先算乘法，再算加法，计算出结果即可。\n\n【详解】36÷4=9,9-3=6,□=63+6×4=3+24=27，小梅在计算\"3+□*4\"时弄错了运算顺序，先算加法后算乘法了，结果得数是36，正确的得数是27。",
+        "knowledge_points":  [
+                                 "乘加",
+                                 "乘减混合运算"
+                             ],
+        "source":  "24-25 二年级下·甘肃庆阳·期中"
+    },
+    {
+        "id":  "430",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "小丽在计算\"6+□*4\"时弄错了运算顺序，她从左往右计算后得数是32，这道题正确的结果应该是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "14",
+        "solution":  "【分析】由题意可知：先按错误的顺序和结果计算，算出□里的数，再用正确的顺序计算出正确结果;据此解答。\n\n【详解】由分析可得：按错误运算顺序和结果算6+□*4=32，先算加法6+2=8，再算8×4=32，得出□里填2;再按正确顺序计算：先算乘法再算加法;6+2×4=6+8=14，这道题正确的结果应该是14。",
+        "knowledge_points":  [
+                                 "乘加",
+                                 "乘减混合运算"
+                             ],
+        "source":  "23-24 二年级下·福建龙岩·期末"
+    },
+    {
+        "id":  "431",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "48-48÷8，要先算( ),再算( )。",
+        "options":  [
+
+                    ],
+        "answer":  "除法;减法",
+        "solution":  "【分析】在没有括号的算式里，如果只有加减法或者只有乘除法，要从左往右依次计算，如果既有乘除法又有加减法，要先算乘除法，再算加减法。据此解答。\n\n【详解】由分析可得:48-48÷8，要先算除法，再算减法。",
+        "knowledge_points":  [
+                                 "除加",
+                                 "除减混合运算"
+                             ],
+        "source":  "23-24 二年级下·河南许昌·期末"
+    },
+    {
+        "id":  "432",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "计算63÷(32-25)时，应先算( )法，再算( )法，结果是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "减;除;9",
+        "solution":  "【分析】根据数学运算顺序规则，在有小括号的算式里，要先算小括号里面的，再算小括号外面的，依此填空并计算出结果。\n\n【详解】63÷(32-25)=63÷7=9，因此，计算63÷(32-25)时，应先算减法，再算除法，结果是9。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算"
+                             ],
+        "source":  "24-25二年级下·山东日照·期中"
+    },
+    {
+        "id":  "433",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "把35-8=27和27÷9=3合并成一个综合算式为( )。",
+        "options":  [
+
+                    ],
+        "answer":  "(35-8)÷9=3",
+        "solution":  "【分析】根据题意，先计算出35减8的差，再用这个差除以9，最终的结果是两个数的商，综合算式中有减法和除法，先算减法，再算除法，用35-8代替27写在前边，要加小括号。\n\n【详解】由分析得：把35-8=27和27÷9=3合并成一个综合算式为(35-8)÷9=3。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算"
+                             ],
+        "source":  "23-24 二年级下·河南信阳·期末"
+    },
+    {
+        "id":  "434",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "计算36+45÷9时，先算( )法，再算( )法。如果要改变计算顺序，列式是( ),结果是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "除;加;(36+45)÷9;9",
+        "solution":  "【分析】整数四则混合运算，如果有括号先算小括号里面的，再算括号外面的;如果没有括号，先算乘除，再算加减;只含有同一级运算，按照从左到右的顺序计算。据此解答即可。\n\n【详解】计算36+45÷9时，先算除法，再算加法。如果要改变计算顺序，则先算加法36+45，则需要加个括号，则列式为:(36+45)÷9。(36+45)÷9=81÷9=9，所以结果为9。",
+        "knowledge_points":  [
+                                 "除加",
+                                 "除减混合运算",
+                                 "带有小括号的混合运算"
+                             ],
+        "source":  "24-25 二年级下·山东临沂·期中"
+    },
+    {
+        "id":  "435",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "爱心饼屋的一种蛋糕原来9元一个，现在优惠促销，一次买3个24元。现在每个比原来便宜( )元。",
+        "options":  [
+
+                    ],
+        "answer":  "1",
+        "solution":  "【分析】用24除以3算出现在每个的价钱，用原来一个的价钱减现在每个的价钱即可求解。\n\n【详解】9-24÷3=9-8=1(元),现在每个比原来便宜1元。",
+        "knowledge_points":  [
+                                 "除加",
+                                 "除减混合运算"
+                             ],
+        "source":  "24-25二年级下·山东临沂·期中"
+    },
+    {
+        "id":  "436",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "2×6+5的运算顺序是先算( )法，再算( )法。一个算式如果有小括号，先算( )的，后算( )的。",
+        "options":  [
+
+                    ],
+        "answer":  "乘;加;小括号里面;小括号外面",
+        "solution":  "【分析】在没有括号的算式里，只有加，减法或只有乘，除法，要从左往右计算;在没有括号的算式里，如果既有乘，除法，又有加，减法，要先算乘，除法，再算加，减法;有括号的算式里，要先算括号里面的，再算括号外面的。由此解答。\n\n【详解】2×6+5的运算顺序是先算乘法，再算加法。一个算式如果有小括号，先算小括号里面的，后算小括号外面的。",
+        "knowledge_points":  [
+                                 "乘加",
+                                 "乘减混合运算",
+                                 "无括号的运算顺序",
+                                 "有括号的运算顺序"
+                             ],
+        "source":  "23-24二年级下·山东菏泽·期末"
+    },
+    {
+        "id":  "437",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "方方在计算\"28+□÷7\"时弄错了运算顺序，先算了加法，后算了除法，结果是8。正确的得数应该是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "32",
+        "solution":  "【分析】根据题意，先用错误的结果和7相乘，求出28+□的和，再用这个和减去28得出□代表的数，再按正确顺序计算即可。\n\n【详解】8×7=56，56-28=28，所以□是28。28+28÷7=28+4=32，方方在计算\"28+□÷7\"时弄错了运算顺序，先算了加法，后算了除法，结果是8。正确的得数应该是32。",
+        "knowledge_points":  [
+                                 "除加",
+                                 "除减混合运算"
+                             ],
+        "source":  "24-25二年级下·湖北省直辖县级单位·期中"
+    },
+    {
+        "id":  "438",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "同学们要栽65棵树，已经栽了6行，每行8棵。还要栽( )棵才能完成任务。",
+        "options":  [
+
+                    ],
+        "answer":  "17",
+        "solution":  "【分析】由题意可知：栽的行数×每行的棵数=已经栽了的棵数，一共要栽的棵数-已经栽的棵数=还要栽的棵数。据此解答。\n\n【详解】由分析可得:65-6×8=65-48=17(棵),还要栽17棵才能完成任务。",
+        "knowledge_points":  [
+                                 "乘加",
+                                 "乘减混合运算"
+                             ],
+        "source":  "23-24二年级下·河北唐山·期末"
+    },
+    {
+        "id":  "439",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "计算26-15÷5时，第一步要先算( );计算32÷(1+7)时，第一步要先算( )。",
+        "options":  [
+
+                    ],
+        "answer":  "除法;加法",
+        "solution":  "【分析】根据整数混合运算法则：同级运算，按照从左往右的顺序依次计算即可;不同级运算，先算乘除，再算加减;有小括号的运算，先算小括号内的算式，再算括号外的计算，据此解答即可。\n\n【详解】据分析可知：计算26-15÷5时，第一步要先算除法;计算32÷(1+7)时，第一步要先算加法。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算",
+                                 "除加",
+                                 "除减混合运算"
+                             ],
+        "source":  "23-24 二年级下·湖南益阳·期末"
+    },
+    {
+        "id":  "440",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "在计算24+16÷8时，按从左至右的顺序计算，最后结果是5。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】根据题意，在四则混合运算中，运算顺序应遵循\"先乘除，后加减\"。24+16÷8先算除法再算加法。据此解答。\n\n【详解】根据分析24+16÷8=24+2=26，先算除法，再算加法。原题说法错误。故答案为: ×",
+        "knowledge_points":  [
+                                 "除加",
+                                 "除减混合运算"
+                             ],
+        "source":  "24-25 二年级下·湖北襄阳·期中"
+    },
+    {
+        "id":  "441",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "52-36÷4=4。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】根据四则运算的规则，应先计算除法，再计算减法。原式中的36÷4应先算，得到9，再用52减去9，结果为43，不等于4。\n\n【详解】52-36÷4=52-9=43，因为43≠4，所以原式说法错误。故答案为: ×",
+        "knowledge_points":  [
+                                 "除加",
+                                 "除减混合运算"
+                             ],
+        "source":  "22-23 二年级下·新疆乌鲁木齐·期末"
+    },
+    {
+        "id":  "442",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "判断题",
+        "difficulty":  0.65,
+        "question":  "14-8÷4的运算顺序是先算减法。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】根据四则运算的规则，在没有括号的算式里，既有加减法又有乘除法，应先进行乘除运算，再进行加减运算。据此解答。\n\n【详解】由分析可得:14-8÷4(先算除法再算减法)14-8÷4=14-2=12，故答案为: ×",
+        "knowledge_points":  [
+                                 "除加",
+                                 "除减混合运算"
+                             ],
+        "source":  "22-23 二年级下·新疆乌鲁木齐·期末"
+    },
+    {
+        "id":  "443",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "计算(42-7)÷6时，应先算减法，再算除法。( )",
+        "options":  [
+
+                    ],
+        "answer":  "√",
+        "solution":  "【分析】在有小括号的混合运算中，应先算括号内的，再算括号外的;据此解答。\n\n【详解】计算(42-7)÷6时，根据运算顺序，先算括号内的42-7，得到35，再算35÷6。因此，应先算减法，再算除法。故答案为:√",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算"
+                             ],
+        "source":  "24-25 二年级下·内蒙古赤峰·期中"
+    },
+    {
+        "id":  "444",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "2×6-3和2×(6-3)的运算顺序和计算结果都不一样。( )",
+        "options":  [
+
+                    ],
+        "answer":  "√",
+        "solution":  "【分析】在整数混合运算中，运算顺序不同会导致计算结果不同。第一个算式没有括号，先算乘法再算减法;第二个算式有括号，先算括号内的减法再算乘法。根据运算顺序，计算结果判断即可。\n\n【详解】2×6-3的运算顺序：先算乘法:2×6=12，再算减法:12-3=9;2×(6-3)的运算顺序：先算括号内的减法:6-3=3，再算乘法:2×3=6;两个算式的运算顺序不同，计算结果分别为9和6，结果也不同。因此，原题说法正确。故答案为:√",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算",
+                                 "乘加",
+                                 "乘减混合运算"
+                             ],
+        "source":  "24-25 二年级下·山东日照·期末"
+    },
+    {
+        "id":  "445",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "判断题",
+        "difficulty":  0.65,
+        "question":  "40-30÷5=10÷5=2。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】在没有括号的算式里，如果既有乘，除法，又有加，减法，要先算乘，除法，再算加，减法，由此解答。\n\n【详解】由分析得：题中算式先算除法，再算减法。40-30÷5=40-6=34，原题计算错误。故答案为: ×",
+        "knowledge_points":  [
+                                 "除加",
+                                 "除减混合运算"
+                             ],
+        "source":  "24-25 二年级下·河南周口·期末"
+    },
+    {
+        "id":  "446",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "判断题",
+        "difficulty":  0.65,
+        "question":  "5×8÷5×8=40÷40=1。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】在没有括号的算式里，只有加，减法或只有乘，除法，要从左往右计算，由此解答。\n\n【详解】由分析得:5×8÷5×8=40÷5×8=8×8=64，原题计算错误。故答案为: ×",
+        "knowledge_points":  [
+                                 "表内乘除混合运算"
+                             ],
+        "source":  "24-25 二年级下·山东济宁·期末"
+    },
+    {
+        "id":  "447",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "6×8÷6和29+18-12的运算顺序是相同的。( )",
+        "options":  [
+
+                    ],
+        "answer":  "√",
+        "solution":  "【分析】在没有括号的算式里，只有加，减法或只有乘，除法，要从左往右计算，由此解答。\n\n【详解】由分析得:6×8÷6从左往右计算;29+18-12从左往右计算;也就是6×8÷6和29+18-12的运算顺序是相同的，原题说法正确。故答案为:√",
+        "knowledge_points":  [
+                                 "无括号的运算顺序",
+                                 "表内乘除混合运算",
+                                 "100以内数的加减混合运算"
+                             ],
+        "source":  "23-24 二年级下·甘肃天水·期末"
+    },
+    {
+        "id":  "448",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "计算题",
+        "difficulty":  0.65,
+        "question":  "递等式计算。\n18+27÷9  (36-29)×9  42÷(2×3)",
+        "options":  [
+
+                    ],
+        "answer":  "21;63;7",
+        "solution":  "【分析】在没有括号的算式里，如果只有加减法或者只有乘除法，要从左往右依次计算。在没有括号的算式里，如果既有乘除法又有加减法，要先算乘除法，再算加减法。在有括号的算式里，要先算括号里面的，再算括号外面的。据此解答。\n\n【详解】由分析可得：算式一：先算除法再算加法;18+27÷9=18+3=21;算式二：先算括号里面的，再算括号外面的;(36-29)×9=7×9=63;算式三：先算括号里面的，再算括号外面的;42÷(2×3)=42÷6=7。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算",
+                                 "除加",
+                                 "除减混合运算"
+                             ],
+        "source":  "24-25 二年级下·河北邢台·期末"
+    },
+    {
+        "id":  "449",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "计算题",
+        "difficulty":  0.65,
+        "question":  "看图列综合算式并计算.\n![](images/041c756a89da26e590cbd850b33a1c905ae3ac7435c68f460e37a2dce741af4d.jpg)",
+        "options":  [
+
+                    ],
+        "answer":  "28+3×2=34(元)",
+        "solution":  "【分析】用右边物品的数量乘每个的价钱，然后加上左边物品的价钱即可求出一共多少钱。\n\n【详解】28+3×2=28+6=34(元),一共34元。",
+        "knowledge_points":  [
+                                 "乘加",
+                                 "乘减混合运算",
+                                 "图文问题"
+                             ],
+        "source":  "24-25 二年级下·湖北武汉·期中"
+    },
+    {
+        "id":  "450",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "计算题",
+        "difficulty":  0.65,
+        "question":  "看图列综合算式并计算.\n![](images/5f9a20eb1df91fdf538485203a416d3c6af5c854306a5d7697234da153d446cb.jpg)",
+        "options":  [
+
+                    ],
+        "answer":  "28+2×3=34(元)",
+        "solution":  "【分析】根据题意，先用每个乒乓球的钱数和数量相乘，求出3个乒乓球的钱数，再和乒乓球拍的钱数相加，就是总钱数。\n\n【详解】28+2×3=28+6=34(元),一共34元。",
+        "knowledge_points":  [
+                                 "图文问题",
+                                 "乘加",
+                                 "乘减混合运算"
+                             ],
+        "source":  "24-25 二年级下·湖北武汉·期中"
+    },
+    {
+        "id":  "451",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "计算题",
+        "difficulty":  0.65,
+        "question":  "递等式计算。\n27÷3×7\n18+36÷9\n42÷(33-27)",
+        "options":  [
+
+                    ],
+        "answer":  "63;22;7",
+        "solution":  "【分析】在没有括号的算式里，只有加，减法或只有乘，除法，要从左往右计算;在没有括号的算式里，如果既有乘，除法，又有加，减法，要先算乘，除法，再算加，减法;有括号的算式里，要先算括号里面的，再算括号外面的。第1题：从左往右计算;第2题：先算除法，再算加法;第3题：先算减法，再算除法。\n\n【详解】27÷3×7=9×7=63;18+36÷9=18+4=22;42÷(33-27)=42÷6=7。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算",
+                                 "除加",
+                                 "除减混合运算",
+                                 "表内乘除混合运算"
+                             ],
+        "source":  "23-24 二年级下·浙江舟山·期末"
+    },
+    {
+        "id":  "452",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "计算题",
+        "difficulty":  0.65,
+        "question":  "按运算顺序计算下面各题。\n67-45+28\n33+36÷4\n32÷4×9\n49÷(26-19)",
+        "options":  [
+
+                    ],
+        "answer":  "50;42;72;7",
+        "solution":  "【分析】整数混合运算中，同级运算时，从左到右依次计算;两级运算时，先算乘除，后算加减;有括号时，先算括号里面的，再算括号外面的。(1)从左到右依次计算;(2)先算除法再算加法;(3)从左到右依次计算;(4)先算减法再除法。\n\n【详解】67-45+28=22+28=50;33+36÷4=33+9=42;32÷4×9=8×9=72;49÷(26-19)=49÷7=7。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算",
+                                 "除加",
+                                 "除减混合运算",
+                                 "表内乘除混合运算",
+                                 "100以内数的加减混合运算"
+                             ],
+        "source":  "23-24 二年级下·广东揭阳·期末"
+    },
+    {
+        "id":  "453",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "计算题",
+        "difficulty":  0.65,
+        "question":  "看图列式计算.\n![](images/03fa344dd65d529585be4e29a8a67a96c77800ff6d86db7c9b21a46f1581bbe5.jpg)",
+        "options":  [
+
+                    ],
+        "answer":  "48-4×9=12(个)",
+        "solution":  "【分析】苹果和梨一共有48个，每袋梨装9个，先用乘法求出4袋这样的梨一共有几个，然后用苹果和梨的一共数量减去梨一共的数量，求出差，就是苹果的数量。\n\n【详解】由题意分析得:48-4×9=48-36=12(个),所以苹果有12个。",
+        "knowledge_points":  [
+                                 "图文问题",
+                                 "表内乘加",
+                                 "乘减"
+                             ],
+        "source":  "23-24 二年级下·广东东莞·期末"
+    },
+    {
+        "id":  "454",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "计算题",
+        "difficulty":  0.85,
+        "question":  "看图列式我能行.\n![](images/6ffa636dd281091bb317767c239dd29294b36b7146ae886641b7065b474b2d5b.jpg)\n![](images/8e12a983f360433c577dea644c97c5c4390fec63efc04569fa1419389677472d.jpg)",
+        "options":  [
+
+                    ],
+        "answer":  "3×3+15=24",
+        "solution":  "【分析】用右边物品的数量乘单价算出右边物品一共多少钱，然后加上左边的15元即可求出左右两边物品一共多少钱。\n\n【详解】3×3+15=9+15=24(元),一共有24元。",
+        "knowledge_points":  [
+                                 "乘加",
+                                 "乘减混合运算",
+                                 "经济问题",
+                                 "图文问题"
+                             ],
+        "source":  "24-25二年级下·山东日照·期中"
+    },
+    {
+        "id":  "455",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "计算题",
+        "difficulty":  0.85,
+        "question":  "看图列综合算式并计算.\n![](images/06592b96dfbd81ea544aa2af4222fa92.png)",
+        "options":  [
+
+                    ],
+        "answer":  "(72-36)÷6=6(元)",
+        "solution":  "【分析】从图上可得：一辆汽车和6支钢笔一共72元，要求每支钢笔多少元，根据减法的意义，用72-36先算出6支钢笔一共多少元，再用6支钢笔的总价钱除以6即可得出答案。\n\n【详解】(72-36)÷6=36÷6=6(元),所以每支钢笔6元。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算",
+                                 "图文问题"
+                             ],
+        "source":  "24-25 二年级下·湖北武汉·期中"
+    },
+    {
+        "id":  "456",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "计算题",
+        "difficulty":  0.65,
+        "question":  "看图列式计算.\n![](images/202025.png)",
+        "options":  [
+
+                    ],
+        "answer":  "(54-30)÷3=8(元)",
+        "solution":  "【分析】根据题意，用篮球和足球的总钱数减去篮球的钱数，计算出3个足球的钱数，再除以足球的数量，就是每个足球的钱数。\n\n【详解】(54-30)÷3=24÷3=8(元),每个足球8元。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算",
+                                 "图文问题"
+                             ],
+        "source":  "23-24 二年级下·湖南长沙·期末"
+    },
+    {
+        "id":  "457",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "计算题",
+        "difficulty":  0.65,
+        "question":  "看图列综合算式解答.\n![](images/3e329d31c019761777d593eadc681756715833b0db3f6f9327da3bce1c08b67a.jpg)",
+        "options":  [
+
+                    ],
+        "answer":  "70千克",
+        "solution":  "【分析】用右边的袋数乘每袋的重量，然后和左边的46千克相加即可求出一共多少千克。\n\n【详解】46+4×6=46+24=70(千克),一共70千克。",
+        "knowledge_points":  [
+                                 "图文问题",
+                                 "乘加",
+                                 "乘减混合运算"
+                             ],
+        "source":  "23-24 二年级下·福建福州·期末"
+    },
+    {
+        "id":  "458",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "红红和她的5个好朋友折千纸鹤，每人折了9只，她们一共折了多少只千纸鹤。",
+        "options":  [
+
+                    ],
+        "answer":  "54只",
+        "solution":  "【分析】根据题意，先用加法计算出一共有多少人，再用人数和每人折的数量相乘，计算出折的总数量即可。\n\n【详解】(1+5)×9=6×9=54(只),答：她们一共折了54只千纸鹤。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算"
+                             ],
+        "source":  "24-25 二年级下·浙江嘉兴·期末"
+    },
+    {
+        "id":  "459",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "小松鼠一共采了17个松果。他们一天要吃8个松果，还要采多少个才够他们吃4天。",
+        "options":  [
+
+                    ],
+        "answer":  "15个",
+        "solution":  "【分析】用每天吃松果的数量乘吃的天数求出一共要采松果的总数量，再减去已经采松果的数量，即可求出还要采松果的数量。\n\n【详解】8×4-17=32-17=15(个),答：还要采15个才够他们吃4天。",
+        "knowledge_points":  [
+                                 "乘加",
+                                 "乘减混合运算"
+                             ],
+        "source":  "24-25 二年级下·浙江嘉兴·期末"
+    },
+    {
+        "id":  "460",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "学校门口摆4行月季花，每行3盆，又摆了16盆牵牛花。月季花和牵牛花一共摆了多少盆。",
+        "options":  [
+
+                    ],
+        "answer":  "28盆",
+        "solution":  "【分析】根据乘法的意义，用4×3先求出月季花的盆数，再加上牵牛花的盆数，即可得出月季花和牵牛花一共摆了多少盆。\n\n【详解】4×3+16=12+16=28(盆),答：月季花和牵牛花一共有28盆。",
+        "knowledge_points":  [
+                                 "乘加",
+                                 "乘减混合运算"
+                             ],
+        "source":  "25-26 二年级·全国·假期作业"
+    },
+    {
+        "id":  "461",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "小丽和她的5个好朋友去动物园玩，网上团购的门票一共30元，每张门票多少元钱。",
+        "options":  [
+
+                    ],
+        "answer":  "5元",
+        "solution":  "【分析】根据题意，用总钱数/总人数=每张门票的价格，总人数=小丽+她的5个朋友，据此解答。\n\n【详解】根据分析:30÷(1+5)=30÷6=5(元),答：每张门票5元。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算",
+                                 "用6的乘法口诀求商",
+                                 "经济问题"
+                             ],
+        "source":  "24-25 二年级下·内蒙古赤峰·期中"
+    },
+    {
+        "id":  "462",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "红红和7个小朋友一起去游乐园，一共付了56元门票，每张门票多少钱。",
+        "options":  [
+
+                    ],
+        "answer":  "7元",
+        "solution":  "【分析】红红和7个小朋友一共是8人，总费用56元，求每张门票的价格，用总费用除以总人数即可。\n\n【详解】56÷(1+7)=56÷8=7(元),答：每张门票7元钱。",
+        "knowledge_points":  [
+                                 "经济问题",
+                                 "带有小括号的混合运算"
+                             ],
+        "source":  "24-25 二年级下·湖北武汉·期末"
+    },
+    {
+        "id":  "463",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "美化校园--种植花卉。第一组领了35株牡丹花，第二组领了37株玫瑰花，如果每排栽9株，一共可以栽多少排。",
+        "options":  [
+
+                    ],
+        "answer":  "8排",
+        "solution":  "【分析】首先将两组领取的花卉数量相加，得到总株数，再用总株数除以每排栽种的株数，即可求得一共可以栽多少排，据此解答。\n\n【详解】根据分析可得:(35+37)÷9=72÷9=8(排),答：一共可以栽8排。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算"
+                             ],
+        "source":  "24-25二年级下·山西晋中·期末"
+    },
+    {
+        "id":  "464",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "神舟十九号成功发射，我国航天事业再创新高。未来小学举办航天主题征文活动。现将筛选出的18篇征文贴在校园长廊左右两面墙的展板上让大家投票，每面墙有3个展板，平均每个展板上贴几篇。",
+        "options":  [
+
+                    ],
+        "answer":  "3篇",
+        "solution":  "【分析】先用每面墙展板的个数乘2，求出两面墙展板的总个数，再用征文的篇数除以展板的总个数，即可求出平均每个展板上贴几篇。\n\n【详解】18÷(3×2)=18÷6=3(篇),答：平均每个展板上贴3篇。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算"
+                             ],
+        "source":  "24-25 二年级下·湖北武汉·期末"
+    },
+    {
+        "id":  "465",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "小刚带了50元钱，买了一个22元的文具盒，剩下的钱正好可以买4本同样的笔记本。每本笔记本多少钱。",
+        "options":  [
+
+                    ],
+        "answer":  "7元",
+        "solution":  "【分析】根据题意，用带的钱数-一个文具盒的钱数=剩下的钱数，剩下的钱数/笔记本的数量=每本笔记本的价格，据此解答。\n\n【详解】根据分析:(50-22)÷4=28÷4=7(元),答：每本笔记本7元。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算"
+                             ],
+        "source":  "24-25二年级下·河南新乡·期末"
+    },
+    {
+        "id":  "466",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "水果店原来有86千克苹果，卖出去48千克后，又运来了35千克。现在店里有多少千克苹果。",
+        "options":  [
+
+                    ],
+        "answer":  "73千克",
+        "solution":  "【分析】根据题意，用原来的数量-卖出的数量+运来的数量=现在的数量，据此解答。\n\n【详解】根据分析:86-48+35=38+35=73(千克),答：现在店里有73千克苹果。",
+        "knowledge_points":  [
+                                 "100以内数的加减混合运算"
+                             ],
+        "source":  "24-25二年级下·河南新乡·期末"
+    },
+    {
+        "id":  "467",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "奇奇和他的5个好朋友一起在游乐园坐小火车，共花了30元，平均每个小朋友花了多少元钱。",
+        "options":  [
+
+                    ],
+        "answer":  "5元",
+        "solution":  "【分析】先用加法算出总人数，最后用一共花的钱数除以总人数即可求出平均每个小朋友花了多少元钱。\n\n【详解】30÷(1+5)=30÷6=5(元),答：平均每个小朋友花了5元钱。",
+        "knowledge_points":  [
+                                 "经济问题",
+                                 "带有小括号的混合运算"
+                             ],
+        "source":  "23-24 二年级下·湖南长沙·期末"
+    },
+    {
+        "id":  "468",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "一场篮球赛分为上半场和下半场，二(1)班上半场得了24分，全场总分是42分。二(2)班的全场总分是38分，下半场两个班的得分一样多。二(2)班上半场得了多少分。\n答：二(2)班上半场得了( )分。",
+        "options":  [
+
+                    ],
+        "answer":  "20",
+        "solution":  "【分析】由题意可知：用二(1)班全场总分减去上半场得的分数，就等于下半场的分数;由于下半场两个班的得分一样多，用二(2)班的全场总分减去下半场的得分，就等于上半场得分。列综合算式，应先算二(1)下半场得分，才能算出二(2)班上半场得分，故把二(1)下半场得分的算式用小括号括起来;据此解答。\n\n【详解】由分析可得:38-(42-24)=38-18=20(分),答：二(2)班上半场得了20分。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算",
+                                 "两位数与两位数的退位减法",
+                                 "两位数与两位数的不退位减法"
+                             ],
+        "source":  "23-24 二年级下·浙江嘉兴·期末"
+    },
+    {
+        "id":  "469",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "蛋糕店上午做了85个蛋糕，卖了47个，下午又做了26个蛋糕。现在蛋糕店有多少个蛋糕。",
+        "options":  [
+
+                    ],
+        "answer":  "64个",
+        "solution":  "【分析】用上午做的个数减卖了的个数，再加上又做了的个数即可求出现在蛋糕店有多少个蛋糕。\n\n【详解】85-47+26=38+26=64(个),答：现在蛋糕店有64个蛋糕。",
+        "knowledge_points":  [
+                                 "100以内数的加减混合运算"
+                             ],
+        "source":  "23-24二年级下·河北邢台·期中"
+    },
+    {
+        "id":  "470",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "二(1)班同学折了红花和黄花共42朵，其中红花有24朵。二(2)班同学两种颜色的花共折了38朵，且两个班折的黄花朵数相同。二(2)班折了多少朵红花。",
+        "options":  [
+
+                    ],
+        "answer":  "20朵",
+        "solution":  "【分析】根据题意，先用二(1)班折花的总数量减去折红花的数量，计算出二(1)班折了多少朵黄花，也就是二(2)班折了多少朵黄花。再用二(2)班折花的总数量减去折黄花的数量，就是二(2)班折红花的数量。\n\n【详解】38-(42-24)=38-18=20(朵),答：二(2)班折了20朵红花。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算"
+                             ],
+        "source":  "24-25 二年级下·河南周口·期末"
+    },
+    {
+        "id":  "471",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "我们一共要90个面包，已经烤了36个\n![](images/79889cc8f196f36b1eb2ddbae7871f1ea9f66144275193cba8f72c4663ce7d88.jpg)\n(1)已经烤了多少次。\n(2)一共要烤多少次。",
+        "options":  [
+
+                    ],
+        "answer":  "4次;10次",
+        "solution":  "【分析】(1)每次烤9个，求36个面包要烤几次，就是求36里面有几个9，用除法列式解决。(2)用一共要烤的面包数量先减去已经烤好的数量，求出差，再除以每次烤的数量，求出商，最后加上已经烤了的次数，求出和就是一共要烤几次。\n\n【详解】(1)36÷9=4(次),答：已经烤了4次。(2)(90-36)÷9=54÷9=6(次),6+4=10(次),答：一共要烤10次。",
+        "knowledge_points":  [
+                                 "用7~9的乘法口诀求商",
+                                 "带有小括号的混合运算"
+                             ],
+        "source":  "22-23 二年级下·新疆乌鲁木齐·期中"
+    },
+    {
+        "id":  "472",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "妈妈买了15个红苹果和17个青苹果，每个盘子里放8个。一共放了多少盘。",
+        "options":  [
+
+                    ],
+        "answer":  "4盘",
+        "solution":  "【分析】先算出红苹果和青苹果一共有多少个，再除以每个盘子放的苹果数量，据此即可得出放了多少盘。\n\n【详解】(15+17)÷8=32÷8=4(盘),答：一共放了4盘。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算"
+                             ],
+        "source":  "22-23二年级下·新疆乌鲁木齐·期中"
+    },
+    {
+        "id":  "473",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "有5捆铅笔，每捆8支，用了36支，还剩多少支。",
+        "options":  [
+
+                    ],
+        "answer":  "4支",
+        "solution":  "【分析】已知有5捆铅笔，每捆8支，根据乘法的意义，用5×8先算出一共有多少支铅笔，再减去用了的铅笔数量，据此即可得出还剩多少支。\n\n【详解】5×8-36=40-36=4(支),答：还剩4支。",
+        "knowledge_points":  [
+                                 "乘加",
+                                 "乘减混合运算"
+                             ],
+        "source":  "22-23 二年级下·新疆乌鲁木齐·期中"
+    },
+    {
+        "id":  "474",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "商店3个杯子12元，妈妈想买6个，应付多少钱。",
+        "options":  [
+
+                    ],
+        "answer":  "24元",
+        "solution":  "【分析】已知3个杯子的总价为12元，要求买6个杯子的应付金额。先用12除以3求出每个杯子的单价，再用每个杯子的单价乘6，求出买6个杯子应付多少钱。\n\n【详解】12÷3×6=4×6=24(元),答：应付24元钱。",
+        "knowledge_points":  [
+                                 "表内乘除法解决实际问题"
+                             ],
+        "source":  "22-23 二年级下·新疆乌鲁木齐·期中"
+    },
+    {
+        "id":  "475",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "暑假，七七经过周密的计划与准备，跟着探险队踏上了\"探险之旅\"。探险队在路上找到一本书，七七想每天看9页,4天刚好看完。明明也想看这本书，他如果每天看6页，需要几天才能看完。",
+        "options":  [
+
+                    ],
+        "answer":  "6天",
+        "solution":  "【分析】根据乘法的意义，用9×4先算出这本书一共有多少页，再用总的页数除以每天看的6页，据此即可得出需要几天能看完。\n\n【详解】9×4÷6=36÷6=6(天),答：他如果每天看6页，需要6天才能看完。",
+        "knowledge_points":  [
+                                 "表内乘除法解决实际问题",
+                                 "表内乘除混合运算"
+                             ],
+        "source":  "24-25 二年级下·广西玉林·期末"
+    },
+    {
+        "id":  "476",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "学校购进80箱粉笔，学校仓库备用留下26箱，剩下的分给六个年级，每个年级平均能分多少箱。",
+        "options":  [
+
+                    ],
+        "answer":  "9箱",
+        "solution":  "【分析】先用减法计算剩下的粉笔箱数，再用剩下的粉笔箱数除以年级数即可求出每个年级分得的箱数。\n\n【详解】(80-26)÷6=54÷6=9(箱),答：每个年级平均能分9箱。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算"
+                             ],
+        "source":  "24-25 二年级下·山东菏泽·期末"
+    },
+    {
+        "id":  "477",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "星期天，二(1)班的18名同学和二(2)班的24名同学去大唐芙蓉园做志愿者。如果把他们平均分成7组，那么每组有多少名同学。",
+        "options":  [
+
+                    ],
+        "answer":  "6名",
+        "solution":  "【分析】先算出两个班级的总人数，再用两个班级的总人数除以需要分成的组数，即可求解每组平均需要多少人。\n\n【详解】(18+24)÷7=42÷7=6(名),答：每组有6名同学。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算"
+                             ],
+        "source":  "24-25 二年级下·山东济南·期末"
+    },
+    {
+        "id":  "478",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "学校买来18本连环画和36本科幻小说，如果把这些书平均分给6个班，每个班分得几本书。",
+        "options":  [
+
+                    ],
+        "answer":  "9本",
+        "solution":  "【分析】先用买来的连环画的本数加上科幻小说的本数，求出买来的连环画和科幻小说的总本数，再用买来的连环画和科幻小说的总本数除以平均分给的班数，即可求出每个班分得几本书。\n\n【详解】(18+36)÷6=54÷6=9(本),答：每个班分得9本书。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算"
+                             ],
+        "source":  "23-24 二年级下·天津河东·期末"
+    },
+    {
+        "id":  "479",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "二(4)班有25名女同学参加活动，参加活动的男同学比女同学少6名。二(4)班一共有多少名同学参加活动。",
+        "options":  [
+
+                    ],
+        "answer":  "44名",
+        "solution":  "【分析】根据题意，先用女同学的人数减去男同学比女同学少的人数，计算出男同学的人数，再和女同学的人数相加，就是总人数。\n\n【详解】25+(25-6)=25+19=44(名),答：二(4)班一共有44名同学参加活动。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算"
+                             ],
+        "source":  "24-25 二年级下·湖北武汉·期中"
+    },
+    {
+        "id":  "480",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "要修一条长50米的路，已经修好了23米，剩下的要用3天修完，平均每天修多少米。\n口答：平均每天修( )米。",
+        "options":  [
+
+                    ],
+        "answer":  "9",
+        "solution":  "【分析】根据题意，用一条路的总长度减去已经修好的长度，求出剩下要修的米长度，再除以要修的天数，即可求出平均每天修多少米，据此解答。\n\n【详解】由分析可得:(50-23)÷3=27÷3=9(米),答：平均每天修9米。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算"
+                             ],
+        "source":  "23-24二年级下·天津河北·期末"
+    },
+    {
+        "id":  "481",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "![](images/15dd8a7241b6535f860c67d9ae175728.png)\n\n全班同学可以分成几个小组。\n口答：全班同学可以分成( )个小组。",
+        "options":  [
+
+                    ],
+        "answer":  "7",
+        "solution":  "【分析】先用男生人数加上女生人数，求出全班人数，再用全班人数除以每个小组的人数，即可求出全班同学可以分成几个小组。\n\n【详解】(30+26)÷8=56÷8=7(个),答：全班同学可以分成7个小组。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算"
+                             ],
+        "source":  "23-24 二年级下·河南漯河·期末"
+    },
+    {
+        "id":  "482",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "要修78米长的路，已经修了43米，剩下的要5天修完。平均每天修多少米。",
+        "options":  [
+
+                    ],
+        "answer":  "7米",
+        "solution":  "【分析】根据题意，先用要修的长度减去已经修了的长度，计算出还剩多少没有修，再用没修的长度除以要修的天数，就是平均每天修的长度。\n\n【详解】(78-43)÷5=35÷5=7(米),答：平均每天修7米。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算"
+                             ],
+        "source":  "24-25二年级下·山东临沂·期末"
+    },
+    {
+        "id":  "483",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "小华看一本85页的故事书，已经看了36页，剩下的要在一星期(7天)看完，平均每天要看多少页。",
+        "options":  [
+
+                    ],
+        "answer":  "7页",
+        "solution":  "【分析】根据题意，先用书的总页数减去已经看了的页数，计算出还剩多少页，再用剩下的页数除以要看的天数，就是平均每天要看的页数。\n\n【详解】(85-36)÷7=49÷7=7(页),答：平均每天要看7页。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算"
+                             ],
+        "source":  "23-24 二年级下·河南许昌·期末"
+    },
+    {
+        "id":  "484",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "同学们进行古诗文背诵，有6个小组参加，每个小组有8名同学，其中有4个小组的同学已经背完了，还有多少名同学没有背完。",
+        "options":  [
+
+                    ],
+        "answer":  "16名",
+        "solution":  "【分析】根据题意，先用总的组数减去已经背完的组数，求出没背完的组数，再和每组的人数相乘，就是没背完的人数。\n\n【详解】(6-4)×8=2×8=16(名),答：还有16名同学没有背完。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算"
+                             ],
+        "source":  "24-25 二年级下·河南漯河·期末"
+    },
+    {
+        "id":  "485",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "同学们搬砖，第一组搬了40块，第二组搬了30块，还要再搬多少块才能达到100块。",
+        "options":  [
+
+                    ],
+        "answer":  "30块",
+        "solution":  "【分析】根据题意，先将第一组搬的数量和第二组搬的数量相加，计算出两组已经搬了多少块砖，再用要搬的总数量减去已经搬了的数量就是还要再搬的数量。\n\n【详解】100-(40+30)=100-70=30(块),答：还要再搬30块才能达到100块。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算"
+                             ],
+        "source":  "24-25 二年级下·河南漯河·期末"
+    },
+    {
+        "id":  "486",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "小灰兔拔了34个萝卜，小白兔拔了30个萝卜。\n(1)这些萝卜每8个装一袋，可以装几袋。\n(2)他们吃了26个，还剩多少个萝卜。",
+        "options":  [
+
+                    ],
+        "answer":  "8袋;38个",
+        "solution":  "【分析】(1)小灰兔拔萝卜的个数加上小白兔拔萝卜的个数，等于它们一共拔了多少个萝卜，用萝卜的总个数除以每袋装的个数，等于可以装几袋;(2)小灰兔拔萝卜的个数加上小白兔拔萝卜的个数，等于它们一共拔了多少个萝卜，用萝卜的总个数减去吃了的个数，等于还剩多少个萝卜。\n\n【详解】(1)(34+30)÷8=64÷8=8(袋),答：可以装8袋。(2)34+30-26=64-26=38(个),答：还剩38个萝卜。",
+        "knowledge_points":  [
+                                 "100以内数的加减混合运算",
+                                 "带有小括号的混合运算"
+                             ],
+        "source":  "24-25 二年级下·山东日照·期中"
+    },
+    {
+        "id":  "487",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "同学们去公园划船，每条船限坐4人，租了7条船，还有3个空位，一共有多少同学去划船。",
+        "options":  [
+
+                    ],
+        "answer":  "25个",
+        "solution":  "【分析】根据题意可知，每条船限坐的人数乘租船的条数，减去还有空位的个数，等于一共有多少同学去划船，据此解答。\n\n【详解】根据分析可得:4×7-3=28-3=25(个),答：一共有25同学去划船。",
+        "knowledge_points":  [
+                                 "乘加",
+                                 "乘减混合运算"
+                             ],
+        "source":  "24-25 二年级下·湖南邵阳·期中"
+    },
+    {
+        "id":  "488",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "学校腰鼓队有17个男生和28个女生，每9同学站成一排，可以站几排。",
+        "options":  [
+
+                    ],
+        "answer":  "5排",
+        "solution":  "【分析】将男生人数和女生人数相加算出总人数，然后除以一排的人数即可求解。\n\n【详解】(17+28)÷9=45÷9=5(排),答：可以站5排。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算"
+                             ],
+        "source":  "23-24二年级下·福建龙岩·期末"
+    },
+    {
+        "id":  "489",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "同学们进行诗会。有6个小组参加，每个小组有8名同学，其中有2个小组的同学表演完了，还有多少名同学没有表演。",
+        "options":  [
+
+                    ],
+        "answer":  "32名",
+        "solution":  "【分析】用一共的小组数减表演完的小组数，求出还剩的小组数，最后用还剩的小组数乘每个小组的人数即可求出还有多少名同学没有表演。\n\n【详解】(6-2)×8=4×8=32(名),答：还有32名同学没有表演。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算"
+                             ],
+        "source":  "23-24 二年级下·河南信阳·期末"
+    },
+    {
+        "id":  "490",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "周末，二(1)班的同学们参加社区志愿活动，分成9个小组，每个小组4人。如果每辆出租车可以乘坐6名同学，需要几辆出租车。",
+        "options":  [
+
+                    ],
+        "answer":  "6辆",
+        "solution":  "【分析】根据题意，先用每个小组的人数和分成的组数相乘，求出一共有多少人，再用总人数除以每辆出租车坐的人数，就是需要出租车的数量。\n\n【详解】4×9÷6=36÷6=6(辆),答：需要6辆出租车。",
+        "knowledge_points":  [
+                                 "表内乘除混合运算"
+                             ],
+        "source":  "24-25 二年级下·山东日照·期中"
+    },
+    {
+        "id":  "491",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "同学们要栽65棵树，已经栽了4行，每行8棵。还要栽多少棵。",
+        "options":  [
+
+                    ],
+        "answer":  "33棵",
+        "solution":  "【分析】已知，同学们已经栽了4行，每行8棵，即每行的棵数乘行数即可得出已经栽了多少棵，再用总棵数减去已经栽的棵数，得到还要栽的棵数。\n\n【详解】65-8×4=65-32=33(棵),答：还要栽33棵。",
+        "knowledge_points":  [
+                                 "8的乘法口诀及应用",
+                                 "乘加",
+                                 "乘减混合运算"
+                             ],
+        "source":  "23-24二年级下·浙江台州·期末"
+    },
+    {
+        "id":  "492",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "手工组男生17人，女生19人，每4人一组，一共可以分几组。",
+        "options":  [
+
+                    ],
+        "answer":  "9组",
+        "solution":  "【分析】由题意可知：男生人数+女生人数=手工组总人数,4人一组可以分几组，是求手工组里面有几个4应该用除法计算。据此解答。\n\n【详解】由分析可得:(17+19)÷4=36÷4=9(组),答：一共可以分9组。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算"
+                             ],
+        "source":  "23-24 二年级下·甘肃天水·期末"
+    },
+    {
+        "id":  "493",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "同学们要种56棵树，已经种了2行，每行9棵，还要种多少棵树。",
+        "options":  [
+
+                    ],
+        "answer":  "38棵",
+        "solution":  "【分析】根据题意，先用种的行数和每行的棵树相乘，求出已经种了多少棵，再用要种的总数量减去已经种了的数量，就是还要种的数量。\n\n【详解】56-2×9=56-18=38(棵),答：还要种38棵树。",
+        "knowledge_points":  [
+                                 "乘加",
+                                 "乘减混合运算"
+                             ],
+        "source":  "23-24 二年级下·甘肃天水·期末"
+    },
+    {
+        "id":  "494",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "72米长的彩带，剪了8次，平均每段长多少米。",
+        "options":  [
+
+                    ],
+        "answer":  "8米",
+        "solution":  "【分析】根据题意可知，将彩带剪了8次，表示把彩带平均分成8+1=9(段),要求每段有多长，用彩带总长度/段数=平均每段的长度，据此列式解答。\n\n【详解】72÷(8+1)=72÷9=8(米),答：平均每段长8米。",
+        "knowledge_points":  [
+                                 "除加",
+                                 "除减混合运算",
+                                 "带有小括号的混合运算"
+                             ],
+        "source":  "23-24 二年级下·湖北省直辖县级单位·期末"
+    },
+    {
+        "id":  "495",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "饲养小组有7个兔笼子，每个笼子装5只兔子，后来又买来5只，一共有多少只兔子。",
+        "options":  [
+
+                    ],
+        "answer":  "40只",
+        "solution":  "【分析】根据题意可知，每个笼子装兔子的只数乘笼子的个数，再加上又买来的只数，等于一共有多少只兔子，据此解答。\n\n【详解】根据分析可得:5×7+5=35+5=40(只),答：一共有40只兔子。",
+        "knowledge_points":  [
+                                 "乘加",
+                                 "乘减混合运算"
+                             ],
+        "source":  "24-25 二年级下·湖南·期中"
+    },
+    {
+        "id":  "496",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "沿河县城区某小学有一间会议室，安装了单人椅80把，双人椅9把，这间会议室一共能坐多少人。",
+        "options":  [
+
+                    ],
+        "answer":  "98人",
+        "solution":  "【分析】要求一共能坐多少人，根据乘法的意义，用2×9先算出9把双人椅可以坐多少人，再加上80把单人椅坐的人数，即可得出答案。\n\n【详解】2×9+80=18+80=98(人),答：这间会议室一共能坐98人。",
+        "knowledge_points":  [
+                                 "乘加",
+                                 "乘减混合运算"
+                             ],
+        "source":  "24-25二年级下·贵州铜仁·期末"
+    },
+    {
+        "id":  "497",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "有一袋糖果，分给9个同学，每人6颗，还剩38颗。这袋糖果原来有多少颗。",
+        "options":  [
+
+                    ],
+        "answer":  "92颗",
+        "solution":  "【分析】根据题意，分给9个同学每人6颗糖果，用乘法计算分出的数量，再加上剩下的38颗，即可求出原来的总颗数。据此解答。\n\n【详解】9×6+38=54+38=92(颗),答：这袋糖果原来有92颗。",
+        "knowledge_points":  [
+                                 "表内乘加",
+                                 "乘减"
+                             ],
+        "source":  "23-24 二年级下·浙江嘉兴·期末"
+    },
+    {
+        "id":  "498",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "端午节前，妈妈包了40个粽子，送给奶奶10个，剩下的平均装在5个保鲜盒里，每个保鲜盒里装几个。",
+        "options":  [
+
+                    ],
+        "answer":  "6个",
+        "solution":  "【分析】根据题意，先用粽子的总数量减去送给奶奶的数量，计算出还剩多少个粽子，再除以平均装的保鲜盒数量，就是每个保鲜盒装粽子的数量。\n\n【详解】(40-10)÷5=30÷5=6(个),答：每个保鲜盒里装6个。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算"
+                             ],
+        "source":  "23-24 二年级下·山西晋中·期末"
+    },
+    {
+        "id":  "499",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "学校买来24本故事书,30本科技书。如果把这些书平均分给6个班，每个班可以分到多少本书。",
+        "options":  [
+
+                    ],
+        "answer":  "9本",
+        "solution":  "【分析】根据题意，学校买来24本故事书和30本科技书，需要将两种书的总数平均分给6个班。先用加法求出两种书的总本数，再用总本数除以班级数，即可得到每个班分到的本数。\n\n【详解】(24+30)÷6=54÷6=9(本),答：每个班可以分到9本书。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算"
+                             ],
+        "source":  "23-24 二年级下·浙江台州·期末"
+    },
+    {
+        "id":  "500",
+        "unit":  "第五单元 混合运算",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "阅览室新购进26本故事书,14本画册。把这些书平均分给二年级5个班，每个班分得多少本。",
+        "options":  [
+
+                    ],
+        "answer":  "8本",
+        "solution":  "【分析】根据加法的意义，将故事书和画册的数量相加即可得出一共有多少本书。再用总的书本数量除以5，即可得出平均每个班能分得多少本。\n\n【详解】(26+14)÷5=40÷5=8(本),答：每个班得8本。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算"
+                             ],
+        "source":  "23-24 二年级下·湖南岳阳·期末"
+    }
+]
diff --git "a/\344\272\214\345\271\264\347\272\247\351\242\230\351\233\206/\344\272\214\345\271\264\347\272\247\344\270\213/\344\272\214\345\271\264\347\272\247\344\270\213\347\254\254\345\205\253\345\215\225\345\205\203\345\205\213\345\222\214\345\215\203\345\205\213.json" "b/\344\272\214\345\271\264\347\272\247\351\242\230\351\233\206/\344\272\214\345\271\264\347\272\247\344\270\213/\344\272\214\345\271\264\347\272\247\344\270\213\347\254\254\345\205\253\345\215\225\345\205\203\345\205\213\345\222\214\345\215\203\345\205\213.json"
new file mode 100644
index 0000000000000000000000000000000000000000..692ec03869c715330683f2556952c78185a07357
--- /dev/null
+++ "b/\344\272\214\345\271\264\347\272\247\351\242\230\351\233\206/\344\272\214\345\271\264\347\272\247\344\270\213/\344\272\214\345\271\264\347\272\247\344\270\213\347\254\254\345\205\253\345\215\225\345\205\203\345\205\213\345\222\214\345\215\203\345\205\213.json"
@@ -0,0 +1,8205 @@
+[
+    {
+        "id":  "1",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "如图，杯子里装的饮料重( )克.\n![](images/5f7ebb0b6f3572e79732d665f877846a.png)",
+        "options":  [
+                        "A. 200",
+                        "B. 300",
+                        "C. 500"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】根据图中所示，读出空杯的重量和倒满饮料后它的重量，用倒满饮料的杯子重量减去空杯重量就是饮料的重量。\n\n【详解】500-200=300(克),所以杯子里装的饮料重300克。故答案为:B",
+        "knowledge_points":  [
+                                 "整百数，几百几十数的加减法口算，克的认识"
+                             ],
+        "source":  "24-25 三年级上·河南安阳·期中"
+    },
+    {
+        "id":  "2",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "6个苹果大约重1( )。",
+        "options":  [
+                        "A. 吨",
+                        "B. 克",
+                        "C. 千克"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】根据情景选择合适的计量单位，要注意联系生活实际，计量单位和数据的大小，灵活的选择。\n\n【详解】A。吨,1吨大约为一货车沙子的重量，则计量6个苹果的重量不合适;B。克,1克大约为一枚硬币的重量，计量一个苹果的重量用\"克\"作单位比较合适。C。千克,1千克大约为两瓶矿泉水的重量，计量6个苹果的重量用\"千克\"作单位比较合适。故答案为:C",
+        "knowledge_points":  [
+                                 "克的认识，千克的认识，吨的认识，质量单位的选择"
+                             ],
+        "source":  "24-25二年级下·山东菏泽·期末"
+    },
+    {
+        "id":  "3",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "如图，一个苹果重400克，一个西瓜重( )克.\n![](images/57f258f6b3e710396a588195a45c1311.png)",
+        "options":  [
+                        "A. 2000",
+                        "B. 4000",
+                        "C. 400"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】天平平衡说明两边的物体一样重。图1：把5个苹果的重量相加，即是一个菠萝的重量;图2：把两个菠萝的重量相加，即是一个西瓜的重量;据此解答。\n\n【详解】由分析可得:400+400+400+400+400=2000(克),2000+2000=4000(克),一个苹果重400克，一个西瓜重4000克。故答案为:B",
+        "knowledge_points":  [
+                                 "整百数，几百几十数的加减法口算，克的认识"
+                             ],
+        "source":  "24-25二年级下·四川成都·期末"
+    },
+    {
+        "id":  "4",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "下列说法错误的是( )。",
+        "options":  [
+                        "A. 把15个苹果分给3个人，每人得5个",
+                        "B. 2千克铁和2000克棉花一样重",
+                        "C. 6005读数时只要读一个零"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】平均分指在分物体时，尽可能地分完且每份得到的数量一样多。1千克=1000克，比较物体的轻重时，只比较物体本身的重量，与材质无关。读一个四位数，从高位往低位读，千位上的数读作几千，百位上的数读作几百，十位上的数读作几十，个位上的数读作几，中间的一个0或连续两个0，都只读一个\"零\"，末尾的0不用读。据此分析每一个选项即可。\n\n【详解】A。把15个苹果平均分给3个人，每人得5个，但当不是平均分时，每人分得不一定是5个，如：一人分4个，一人分5个，一人分6个;原说法错误;B。1千克=1000克,2千克=2000克，则2千克铁和2000克棉花一样重，说法正确;C。6005读作：六千零五，读数时只要读一个零，说法正确;故答案为:A",
+        "knowledge_points":  [
+                                 "万以内数的读，写法，整数平均分的意义及应用，克，千克之间的换算与比较"
+                             ],
+        "source":  "24-25二年级下·浙江杭州·期末"
+    },
+    {
+        "id":  "5",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "一袋冰糖重500克,( )袋这样的冰糖重2千克。",
+        "options":  [
+                        "A. 4",
+                        "B. 2",
+                        "C. 6"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】2个500是1000,2个1000是2000，也就是4个500是2000;则4个500克是2000克，即2千克(1千克=1000克);据此解决即可。\n\n【详解】500克+500克=1000克,1000克+1000克=2000克,2千克=2000克，即，一袋冰糖重500克,4袋这样的冰糖重2千克。故答案为:A",
+        "knowledge_points":  [
+                                 "整百数，几百几十数的加减法口算，克，千克之间的换算与比较"
+                             ],
+        "source":  "24-25二年级下·青海果洛·期末"
+    },
+    {
+        "id":  "6",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "一台电视机重10千克，它的包装物重6000克，它们一共重( )千克。",
+        "options":  [
+                        "A. 16",
+                        "B. 601",
+                        "C. 6010"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】题目中电视机的重量是10千克，包装物的重量是6000克，将单位统一为千克后再相加，求出和就是一共重多少千克。1千克=1000克。\n\n【详解】6000克=6千克,10+6=16(千克),即，它们一共重(16)千克。故答案为:A",
+        "knowledge_points":  [
+                                 "克，千克之间的换算与比较"
+                             ],
+        "source":  "24-25 二年级下·湖北孝感·期末"
+    },
+    {
+        "id":  "7",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "一个苹果重200克,( )个这样的苹果重1千克。",
+        "options":  [
+                        "A. 5",
+                        "B. 50",
+                        "C. 500"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】先单位换算1千克=1000克，几个200克加起来是1000克，则几个这样的苹果重1千克。\n\n【详解】1千克=1000克,200+200+200+200+200=1000(克),5个200克加起来是1000克，因此5个这样的苹果重1千克。故答案为:A",
+        "knowledge_points":  [
+                                 "整百数，几百几十数的加减法口算，克，千克之间的换算与比较"
+                             ],
+        "source":  "24-25 二年级下·浙江杭州·期末"
+    },
+    {
+        "id":  "8",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "下面三个质量中，最轻的是( )。",
+        "options":  [
+                        "A. 4018克",
+                        "B. 4100克",
+                        "C. 4千克"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】根据1千克=1000克统一单位，再按照整数比较大小的方法比较即可。比较时，位数多的数就大，位数相同比较最高位，最高位大的数就大，最高位相同比较下一位，直到比较出结果为止。\n\n【详解】4千克=4000克,4000克\u003c4018克\u003c4100克，则4千克\u003c4018克\u003c4100克，最轻的是4千克。故答案为:C",
+        "knowledge_points":  [
+                                 "万以内数的大小比较，克，千克之间的换算与比较"
+                             ],
+        "source":  "24-25 二年级下·广东潮州·期末"
+    },
+    {
+        "id":  "9",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "下面的物品中,( )的质量约是1千克。",
+        "options":  [
+                        "A. 10个鸡蛋",
+                        "B. 2个西瓜",
+                        "C. 4个苹果",
+                        "D. 10颗荔枝"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】根据对生活经验，重量单位的认识可知;1枚1分的硬币大约重1克,1瓶矿泉水大约重500克,2瓶矿泉水大约重1千克;逐项分析各个选项，找出质量大约是1千克的选项即可。\n\n【详解】A。10个鸡蛋:1个普通鸡蛋的质量约为50克,10个鸡蛋的总质量是500克,1千克=1000克,500克与1000克相差较大，不符合题意;B。2个西瓜：一个中等西瓜的质量通常为4-5千克,2个西瓜的总质量约8-10千克，远大于1千克，不符合题意;C。4个苹果：一个中等苹果的质量约为200克,4个苹果的总质量大约800克,1千克=1000克,800克接近1000克，符合题意;D。10颗荔枝：一颗普通荔枝的质量约为20克,10颗荔枝的总质量大约200克,1千克=1000克,200克与1000克相差较大，不符合题意。故答案为:C",
+        "knowledge_points":  [
+                                 "克的认识，千克的认识"
+                             ],
+        "source":  "24-25 二年级下·浙江湖州·期末"
+    },
+    {
+        "id":  "10",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "一个潮州柑大约重200( )。",
+        "options":  [
+                        "A. 千克",
+                        "B. 克",
+                        "C. 厘米"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】根据对生活经验，质量单位和数据大小的认识可知;1枚1分的硬币约重1克，所以，要计量一个潮州柑的重量用\"克\"作单位比较合适;据此解答。\n\n【详解】一个潮州柑大约重200克。故答案为:B",
+        "knowledge_points":  [
+                                 "克的认识，质量单位的选择"
+                             ],
+        "source":  "24-25 二年级下·广东潮州·期末"
+    },
+    {
+        "id":  "11",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "500克芒果售价5元，妈妈用20元能买( )千克的芒果。",
+        "options":  [
+                        "A. 2000",
+                        "B. 4",
+                        "C. 2"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】由题意可知:500克芒果售价5元,1000克芒果售价5元+5元=10元;20元可以买1000克+1000克=2000克，根据1千克=1000克,2000克=2千克，故20元能买2千克的芒果。\n\n【详解】由分析可得：妈妈用20元能买2千克的芒果。故答案为:C",
+        "knowledge_points":  [
+                                 "整百数，几百几十数的加减法口算，十元以上人民币的认识与计算，克，千克之间的换算与比较"
+                             ],
+        "source":  "24-25 二年级下·福建福州·期末"
+    },
+    {
+        "id":  "12",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "黄河是世界上含沙量最大的河流,5千克500克黄沙和5050克棉花比较( )。",
+        "options":  [
+                        "A. 黄沙重",
+                        "B. 一样重",
+                        "C. 棉花重"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】根据1千克=1000克，把单位统一为克后，再比较轻重，据此解答。\n\n【详解】1千克=1000克,5千克=5000克,5千克500克=5000克+500克=5500克,5500克\u003e5050克，黄河是世界上含沙量最大的河流,5千克500克黄沙和5050克棉花比较，黄沙重。故答案为:A",
+        "knowledge_points":  [
+                                 "克的认识，千克的认识，克，千克之间的换算与比较"
+                             ],
+        "source":  "24-25 二年级下·浙江台州·期末"
+    },
+    {
+        "id":  "13",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "一件物品加上400克是600克，这件物品重( )。",
+        "options":  [
+                        "A. 1千克",
+                        "B. 200克",
+                        "C. 2000克"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】由题意可知：用600克减去加上的400克，即是这件物品的重量;据此解答。\n\n【详解】由分析可得:600-400=200(克),这件物品重200克。故答案为:B",
+        "knowledge_points":  [
+                                 "整百数，几百几十数的加减法口算，克的认识"
+                             ],
+        "source":  "24-25 二年级下·吉林四平·期末"
+    },
+    {
+        "id":  "14",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "一个鸡蛋重30( );一袋洗衣粉重1( )。",
+        "options":  [
+
+                    ],
+        "answer":  "克或g;千克或kg",
+        "solution":  "【分析】计量较轻的物品，常用\"克\"作单位;计量较重的物品，常用\"千克\"作单位;1克大约1枚2分硬币重量,1千克大约2瓶500毫升矿泉水的重量，结合数据，根据题意和生活实际选取合适的单位即可。\n\n【详解】一个鸡蛋重30克;一袋洗衣粉重1千克。",
+        "knowledge_points":  [
+                                 "克的认识，千克的认识，质量单位的选择"
+                             ],
+        "source":  "24-25三年级上·海南省直辖县级单位·期中"
+    },
+    {
+        "id":  "15",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在下面的括号里填上\"千克\"或\"克\".\n![](images/ff81a3d4d425c7d6088001e7faed5a92.png)\n\n5( ) 5( ) 500( )",
+        "options":  [
+
+                    ],
+        "answer":  "千克;克;克",
+        "solution":  "【分析】称一般物体有多重，常用千克作单位。两包盐的重量是1千克，千克用字母\"kg\"表示。所以计量一个西瓜的重量一般用千克作单位。称比较轻的物体，通常用克作单位。1枚2分的硬币大约重1克，所以计量一支铅笔的重量和一个足球的重量用\"克\"作单位比较合适。\n\n【详解】根据生活经验，单位填写如下所示：西瓜5千克 笔5克 足球500克",
+        "knowledge_points":  [
+                                 "克的认识，千克的认识，质量单位的选择"
+                             ],
+        "source":  "24-25 三年级上·河南南阳·期中"
+    },
+    {
+        "id":  "16",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在( )里填上适当的单位名称.\n壮壮身高约1( ),体重已达到22( )。在学校举行运动会这天早上，他吃了一个重约40( )的包子和一根长约18( )的油条，喝了一杯200毫升牛奶，精神饱满地去参加运动会了。",
+        "options":  [
+
+                    ],
+        "answer":  "米或m;千克或kg;克或g;厘米或cm",
+        "solution":  "【分析】根据对生活经验，长度单位，重量单位和数据大小的认识可知;二年级学生双臂展开的长度大约是1米，所以计量壮壮的身高用\"米\"作单位比较合适;2袋食盐约重1千克，所以计量壮壮的体重用\"千克\"作单位比较合适;1枚1分的硬币约重1克，所以，要计量一个包子的重量用\"克\"作单位比较合适;1厘米大约是食指的宽度，所以计量一根油条的长度用\"厘米\"作单位比较合适。\n\n【详解】壮壮身高约1米，体重已达到22千克。在学校举行运动会这天早上，他吃了一个重约40克的包子和一根长约18厘米的油条，喝了一杯200毫升牛奶，精神饱满地去参加运动会了。",
+        "knowledge_points":  [
+                                 "克的认识，千克的认识，质量单位的选择，长度单位的选择"
+                             ],
+        "source":  "24-25二年级下·湖北省直辖县级单位·期末"
+    },
+    {
+        "id":  "17",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "在括号里填上\"\u003e\"\"\u003c\"或\"=\".\n10个一百( )9992300克( )3千克\n1890( )1900 (4+5)×6( )4+5×6",
+        "options":  [
+
+                    ],
+        "answer":  "\u003e;\u003c;\u003c;\u003e",
+        "solution":  "【分析】比较数的大小时，位数多的数就大，位数相同比较最高位，最高位大的数就大，最高位相同比较下一位，直到比较出结果为止。(4+5)×6=9×6=54,4+5×6=4+30=34,54\u003e34，则(4+5)×6\u003e4+5×6。",
+        "knowledge_points":  [
+                                 "万以内数的大小比较，带有小括号的混合运算，克，千克之间的换算与比较"
+                             ],
+        "source":  "24-25 二年级下·云南文山·期末"
+    },
+    {
+        "id":  "18",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "用\"克\"或\"千克\"填空.\n周末，我跟爸爸妈妈一起来到外婆家，外婆家的果园里有许多水果，我摘了一个苹果，大约重200( ),5个这样的就重1( )。",
+        "options":  [
+
+                    ],
+        "answer":  "克;千克",
+        "solution":  "【分析】根据生活经验，对质量单位和数据大小的认识可知：计量比较轻的物体，常用克作单位,2个曲别针约重1克，计量比较重的物体，常用千克作单位,2袋白砂糖约重1千克。所以一个苹果的重量大约为200克;5个苹果的重量约为5个200克，相加计算出总重量，根据1千克=1000克换算单位即可。\n\n【详解】200+200+200+200+200=1000(克),1000克=1千克，周末，我跟爸爸妈妈一起来到外婆家，外婆家的果园里有许多水果，我摘了一个苹果，大约重200克,5个这样的苹果就重1千克。",
+        "knowledge_points":  [
+                                 "克，千克之间的换算与比较，质量单位的选择"
+                             ],
+        "source":  "24-25二年级下·云南文山·期末"
+    },
+    {
+        "id":  "19",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "一个鸡蛋大约重65( ),一个二年级的学生体重约28( )。",
+        "options":  [
+
+                    ],
+        "answer":  "克或g;千克或kg",
+        "solution":  "【分析】根据生活经验以及对质量单位和数据大小的认识,1张普通的A4纸大约重1克，所以计量一个鸡蛋的质量用\"克\"做单位比较合适;1瓶矿泉水大约重500克,2瓶矿泉水大约重1千克，所以计量一个二年级学生的体重用\"千克\"做单位比较合适。\n\n【详解】根据分析可知：一个鸡蛋大约重65克(或g),一个二年级的学生体重约28千克(或kg)。",
+        "knowledge_points":  [
+                                 "克的认识，千克的认识"
+                             ],
+        "source":  "24-25 二年级下·福建龙岩·期末"
+    },
+    {
+        "id":  "20",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在括号里填上\"\u003c\"\"\u003e\"或\"=\".\n8231( )79685999克( )6千克 36÷4( )42/(7-1)\n1002( )8988千克( )8000克 8+12÷4( )4×6-5",
+        "options":  [
+
+                    ],
+        "answer":  "\u003e;\u003c;\u003e;\u003e;=;\u003c",
+        "solution":  "【分析】比较大小方法:①位数多的数大于位数少的数;②位数相同的，先比较最高位上的数，最高位上大的，数就大，最高位数相同的，就比较下一位，以此类推。有算式的先算出得数再进行比较，单位不统一的先统一单位再进行比较;【详解】由分析可得：千位数字8\u003e7，故8231\u003e7968;6千克=6000克,5999克\u003c6000克，故5999克\u003c6千克;36÷4=9,7-1=6,42÷6=7,9\u003e7，故36÷4\u003e42÷(7-1);四位数\u003e三位数，故1002\u003e898;8千克=8000克,8000克=8000克，故8千克=8000克;12÷4=3,8+3=11;4×6=24,24-5=19,11\u003c19，故8+12÷4\u003c4×6-5。",
+        "knowledge_points":  [
+                                 "万以内数的大小比较，乘加，乘减混合运算，带有小括号的混合运算，克，千克之间的换算与比较"
+                             ],
+        "source":  "24-25 二年级下·甘肃庆阳·期末"
+    },
+    {
+        "id":  "21",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "3000克=( )千克 9000克+2千克=( )千克\n3千克-600克=( )克 6300克+700克=( )千克",
+        "options":  [
+
+                    ],
+        "answer":  "3;11;2400;7",
+        "solution":  "【分析】根据1千克=1000克,1000克=1千克，进行单位的换算，将单位统一后，再进行计算。\n\n【详解】1000克=1千克,3000克=3千克;1000克=1千克,9000克+2千克=9千克+2千克=11千克，所以9000克+2千克=11千克;1千克=1000克,3千克-600克=3000克-600克=2400克，所以3千克-600克=2400克;1000克=1千克,6300克+700克=7000克=7千克，所以6300克+700克=7千克。",
+        "knowledge_points":  [
+                                 "克，千克之间的换算与比较"
+                             ],
+        "source":  "24-25 二年级下·山东菏泽·期末"
+    },
+    {
+        "id":  "22",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在括号里填上\"\u003e\"\"\u003c\"\"=\".\n6080( )60086千克( )6000克 48÷8( )7\n999( )10003500克( )3千克 1700-800( )899",
+        "options":  [
+
+                    ],
+        "answer":  "\u003e;=;\u003c;\u003c;\u003e;\u003e",
+        "solution":  "【分析】万以内数的大小比较方法：先看位数，位数多的大于位数少的;位数相同，先比较最高位上的数，最高位上的数大的那个数就大;如果最高位上的数相同，再比较下一位上的数，以此类推，直到比较出大小。根据1千克=1000克，先将单位统一，再进行比较大小即可。有算式先算出算式的得数，再进行比较大小即可。\n\n【详解】6080\u003e6008;6千克=6000克;48÷8=6,6\u003c7，所以48÷8\u003c7;999\u003c1000;3千克=3000克,3500克\u003e3000克，所以3500克\u003e3千克;1700-800=900,900\u003e899，所以1700-800\u003e899。",
+        "knowledge_points":  [
+                                 "万以内数的大小比较，用7~9的乘法口诀求商，克，千克之间的换算与比较"
+                             ],
+        "source":  "24-25 二年级下·广东潮州·期末"
+    },
+    {
+        "id":  "23",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在括号里填上合适的单位.\n一只鹅重4( )。 一个苹果重125( )。",
+        "options":  [
+
+                    ],
+        "answer":  "千克或kg;克或g",
+        "solution":  "【分析】根据生活常识和对不同重量单位的认识来选择合适的单位。计量比较轻的物体，常用\"克\"作单位，计量比较重的物体，常用\"千克\"作单位。2个曲别针约重1克，所以计量一个苹果的重量用\"克\"作单位比较合适;2小袋食盐重1千克，所以计量一只鹅的重量用\"千克\"作单位比较合适;据此解答。\n\n【详解】由分析可得：一只鹅重4千克。一个苹果重125克。",
+        "knowledge_points":  [
+                                 "克的认识，千克的认识，质量单位的选择"
+                             ],
+        "source":  "24-25 二年级下·广东潮州·期末"
+    },
+    {
+        "id":  "24",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在( )填上\"\u003e\"\"\u003c\"或\"=\".\n9090( )999055-23-18( )55-(23-18) 3500克( )3千克",
+        "options":  [
+
+                    ],
+        "answer":  "\u003c;\u003c;\u003e",
+        "solution":  "【分析】万以内数的大小比较方法：先看位数，位数多的大于位数少的;位数相同，先比较最高位上的数，最高位上的数大的那个数就大;如果最高位上的数相同，再比较下一位上的数，以此类推，直到比较出大小。有算式先算出算式的得数，再进行比较大小。根据1千克=1000克，先将单位统一，再进行比较大小。\n\n【详解】9090\u003c9990;55-23-18=32-18=14,55-(23-18)=55-5=50,14\u003c50，所以55-23-18\u003c55-(23-18);3千克=3000克,3500克\u003e3000克，所以3500克\u003e3千克。",
+        "knowledge_points":  [
+                                 "万以内数的大小比较,100以内数的连减运算，带有小括号的混合运算，克，千克之间的换算与比较"
+                             ],
+        "source":  "24-25 二年级下·广东汕头·期末"
+    },
+    {
+        "id":  "25",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在括号里填上\"\u003e\"\"\u003c\"或\"=\".\n3005克( )3千克 3时( )180分 50厘米( )5米",
+        "options":  [
+
+                    ],
+        "answer":  "\u003e;=;\u003c",
+        "solution":  "【分析】当单位不统一时，先换算成统一单位，再进行比较。注意不同单位之间的换算方法。1千克=1000克,1时=60分,1米=100厘米。\n\n【详解】1千克=1000克,3千克=3000克，故,3005克\u003e3千克;1时=60分，故,3时=180分;1米=100厘米,5米=500厘米，故,50厘米\u003c5米。",
+        "knowledge_points":  [
+                                 "时，分的认识及换算，克，千克之间的换算与比较，厘米和米之间的进率与换算"
+                             ],
+        "source":  "24-25 二年级下·贵州铜仁·期末"
+    },
+    {
+        "id":  "26",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在括号里填上\"\u003e\"\"\u003c\"或\"=\".\n6003( )603036÷6( )42/71000克( )10千克 1500( )900",
+        "options":  [
+
+                    ],
+        "answer":  "\u003c;=;\u003c;\u003e",
+        "solution":  "【分析】万以内数的大小比较方法：先看位数，位数多的大于位数少的;位数相同，先比较最高位上的数，最高位上的数大的那个数就大;如果最高位上的数相同，再比较下一位上的数，以此类推，直到比较出大小。有算式先算出算式的得数，再进行比较大小即可。1千克=1000克，先将单位统一，再进行比较大小即可。\n\n【详解】6003\u003c6030;36÷6=6,42÷7=6，所以36÷6=42÷7;1000克=1千克,1千克\u003c10千克，所以1000克\u003c10千克;1500\u003e900。",
+        "knowledge_points":  [
+                                 "万以内数的大小比较，用7~9的乘法口诀求商，克，千克之间的换算与比较"
+                             ],
+        "source":  "24-25二年级下·广东江门·期末"
+    },
+    {
+        "id":  "27",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "在括号里填上\"\u003e\"\"\u003c\"或\"=\".\n8056( )8065489( )3601000克( )1000千克 5千克( )50克 3+18÷3( )54/61000( )10个一千",
+        "options":  [
+
+                    ],
+        "answer":  "\u003c;\u003e;\u003c;\u003e;=;\u003c",
+        "solution":  "【分析】万以内数的大小比较方法：先看位数，位数多的数大于位数少的;位数相同，先比较最高位，最高位上的数大的那个数就大;如果最高位上的数相同，再比较下一位，以此类推，直到比较出大小。根据1千克=1000克，先将单位统一，再进行比较大小即可。有算式先算出算式的得数，再进行比较大小即可。\n\n【详解】8056\u003c8065;489\u003e360;1000克=1千克,1千克\u003c1000千克，所以1000克\u003c1000千克;5千克=5000克,5000克\u003e50克，所以5千克\u003e50克;3+18÷3=3+6=9,54÷6=9，所以3+18÷3=54÷6;10个一千是10000,1000\u003c10000，所以1000\u003c10个一千。",
+        "knowledge_points":  [
+                                 "万以内数的组成，万以内数的大小比较，用7~9的乘法口诀求商，克，千克之间的换算与比较"
+                             ],
+        "source":  "24-25 二年级下·四川凉山·期末"
+    },
+    {
+        "id":  "28",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在( )里填上合适的单位.\n字典厚约4( );一个西瓜重约5( );桥长约100( );手机重约180( )。",
+        "options":  [
+
+                    ],
+        "answer":  "厘米或cm;千克或kg;米或m;克或g",
+        "solution":  "【分析】根据生活经验以及对长度单位和数据大小的认识，量比较短的物体的长度，通常用厘米作单位。食指的宽大约是1厘米，所以计量一本字典的厚度用\"厘米\"作单位比较合适。量比较长的物体，通常用米作单位。二年级学生双臂展开的长度大约是1米，所以计量桥的长度用\"米\"作单位比较合适。根据生活经验以及对质量单位和数据大小的认识,1张普通的A4纸大约重1克，所以计量一部手机的质量用\"克\"作单位比较合适;1瓶矿泉水大约重500克,2瓶矿泉水大约重1千克，所以计量西瓜的质量用\"千克\"作单位比较合适。\n\n【详解】字典厚约4厘米(或cm);一个西瓜重约5千克(或kg);桥长约100米(或m);手机重约180克(或g)。",
+        "knowledge_points":  [
+                                 "千克的认识，质量单位的选择，厘米的认识，长度单位的选择"
+                             ],
+        "source":  "24-25 二年级下·四川凉山·期末"
+    },
+    {
+        "id":  "29",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "1千克=( )克 3000克=( )千克\n在括号里填上合适的单位。一个鸡蛋大约重50( ) 一头牛大约重500( )。",
+        "options":  [
+
+                    ],
+        "answer":  "1000;3 克或g;千克或kg",
+        "solution":  "【分析】(1)(2)根据克和千克的进率是1000即可解答。(3)(4)计量物体的重量填质量单位，\"克\"一般是计量比较轻的物体;\"千克\"一般是计量比较重的物体;据此解答即可。\n\n【详解】1千克=1000克 3000克=3千克;一个鸡蛋大约重50克;一头牛大约重500千克。",
+        "knowledge_points":  [
+                                 "克，千克之间的换算与比较，质量单位的选择"
+                             ],
+        "source":  "25-26 三年级上·黑龙江佳木斯·开学考试"
+    },
+    {
+        "id":  "30",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在括号里填上合适的质量单位.\n一个苹果约重200( );一头牛约重300( )。",
+        "options":  [
+
+                    ],
+        "answer":  "克或g;千克或kg",
+        "solution":  "【分析】常见的质量单位有克和千克，克通常用于较轻物体的计量，千克用于较重物体的计量。一个苹果相对来说是比较轻的物体，在质量单位中，\"克\"是用于计量较轻物品的单位，所以一个苹果约重200克。一头牛是比较重的大型动物，\"千克\"是用于计量较重物品的单位，所以一头牛约重300千克。\n\n【详解】一个苹果约重200克;一头牛约重300千克。",
+        "knowledge_points":  [
+                                 "克的认识，千克的认识"
+                             ],
+        "source":  "25-26 三年级上·黑龙江佳木斯·开学考试"
+    },
+    {
+        "id":  "31",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "填合适的质量单位.\n一个苹果重200( ) 一只母鸡重3( )\n一袋大米重10( ) 一个铅笔盒重300( )",
+        "options":  [
+
+                    ],
+        "answer":  "克或g;千克或kg;千克或kg;克或g",
+        "solution":  "【分析】根据情景选择合适的计量单位，要注意联系生活实际，计量单位和数据的大小，灵活的选择。1克大约为一枚硬币的重量，计量一个苹果的重量，一个铅笔盒的重量用\"克\"作单位比较合适。1千克大约为两瓶矿泉水的重量，计量一只母鸡的重量，一袋大米用\"千克\"作单位比较合适。\n\n【详解】一个苹果重200(克);一只母鸡重3(千克);一袋大米重10(千克);一个铅笔盒重300(克)。",
+        "knowledge_points":  [
+                                 "克的认识，千克的认识，质量单位的选择"
+                             ],
+        "source":  "24-25 二年级下·山东菏泽·期末"
+    },
+    {
+        "id":  "32",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在括号里填上合适的质量单位或数.\n(1)一只孔雀重3967( ),约重( )千克.\n(2)世界上现存最大的鸟是鸵鸟。一只成年鸵鸟大约重130( ),一个鸵鸟蛋就大约重1500( )。",
+        "options":  [
+
+                    ],
+        "answer":  "克或g;4;千克或kg;克或g",
+        "solution":  "【分析】根据生活经验，对质量单位和数据大小的认识可知:(1)2个曲别针约重1克，所以一只孔雀的重量，用克作单位比较合适，然后把孔雀的重量看成与之接近的整百数或整百整十数，再根据1000克=1千克变换单位即可;(2)2袋白砂糖约重1千克，所以一只成年鸵鸟的重量，用千克作单位比较合适;2个曲别针约重1克，一个鸵鸟蛋的重量用克作单位比较合适。\n\n【详解】(1)3967克可以看成4000克,1000克=1千克,4000克=4千克;一只孔雀重3967克，约重4千克。(2)世界上现存最大的鸟是鸵鸟。一只成年鸵鸟大约重130千克，一个鸵鸟蛋就大约重1500克。",
+        "knowledge_points":  [
+                                 "克的认识，千克的认识，克，千克之间的换算与比较，质量单位的选择"
+                             ],
+        "source":  "24-25二年级下·湖北武汉·期末"
+    },
+    {
+        "id":  "33",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在括号里填上\"\u003e\"\"\u003c\"或\"=\".\n850-600( )850-602000( )19个百\n4千克( )700克 4+5×4( )(5+4)×4",
+        "options":  [
+
+                    ],
+        "answer":  "\u003c;\u003e;\u003e;\u003c",
+        "solution":  "【分析】算式之间比较大小，可以先计算出结果再进行比较，数量之间比较大小，先统一单位，再比较大小。1千克=1000克。\n\n【详解】850-600=250,850-60=790，故,850-600\u003c850-60;19个百就是1900，故,2000\u003e19个百;4千克=4000克，故,4千克\u003e700克;4+5×4=4+20=24,(5+4)×4=9×4=36，故,4+5×4\u003c(5+4)×4。",
+        "knowledge_points":  [
+                                 "万以内数的大小比较，整百数，几百几十数的加减法口算，带有小括号的混合运算，克，千克之间的换算与比较"
+                             ],
+        "source":  "24-25 二年级下·浙江杭州·期末"
+    },
+    {
+        "id":  "34",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "小明是一名二年级的学生，他的身高约125( ),体重约30( ),他早上吃了一个重约60( )的鸡蛋。",
+        "options":  [
+
+                    ],
+        "answer":  "厘米或cm;千克或kg;克或g",
+        "solution":  "【分析】根据生活经验和实际数据相结合可知：食指的宽度约1厘米，则计量小明的身高用\"厘米\"作单位;1克大约为一枚硬币的重量，计量一个鸡蛋的重量用\"克\"作单位比较合适。1千克大约为两瓶矿泉水的重量，计量小明体重用\"千克\"作单位比较合适。\n\n【详解】由分析可得：小明是一名二年级的学生，他的身高约125(厘米),体重约30(千克),他早上吃了一个重约60(克)的鸡蛋。",
+        "knowledge_points":  [
+                                 "千克的认识，质量单位的选择，米的认识，长度单位的选择"
+                             ],
+        "source":  "24-25 二年级下·浙江杭州·期末"
+    },
+    {
+        "id":  "35",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "奇奇同学的体重约是25，一个梨约重200 。",
+        "options":  [
+
+                    ],
+        "answer":  "千克;克",
+        "solution":  "【分析】根据生活经验，对质量单位和数据大小的认识可知：计量比较轻的物体，常用克作单位,2个曲别针约重1克，所以一个梨的重量，用克作单位比较合适;计量比较重的物体，常用千克作单位,2袋白砂糖约重1千克，所以奇奇同学的体重用千克作单位比较合适。\n\n【详解】奇奇同学的体重约是25千克，一个梨约重200克。",
+        "knowledge_points":  [
+                                 "克的认识，千克的认识，质量单位的选择"
+                             ],
+        "source":  "24-25 二年级下·江西九江·期末"
+    },
+    {
+        "id":  "36",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "一个鸡蛋约重50( ) 二年级的小贵约重36( ) 一袋大米重5( )",
+        "options":  [
+
+                    ],
+        "answer":  "克或g;千克或kg;千克或kg",
+        "solution":  "【分析】计量比较轻的物体重量用\"克\"作单位，如一粒花生米重量大约是1克。计量比较重的物体重量用\"千克\"作单位，如2袋食盐重量是1千克。\n\n【详解】一个鸡蛋比较轻，用\"克\"作单位比较合适，因此一个鸡蛋约重50(克);二年级的小贵比较重，用\"千克\"作单位比较合适，因此二年级的小贵约重36(千克);一袋大米比较重，用\"千克\"作单位比较合适，因此一袋大米重5(千克)。",
+        "knowledge_points":  [
+                                 "质量单位的选择"
+                             ],
+        "source":  "24-25 二年级下·青海果洛·期末"
+    },
+    {
+        "id":  "37",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "兰兰体重26( );身高131( );一个月饼重180( )。",
+        "options":  [
+
+                    ],
+        "answer":  "千克或kg;厘米或cm;克或g",
+        "solution":  "【分析】根据生活经验，对长度单位，质量单位和数据大小的认识可知，一分钱的硬币重约1克，所以，计量一个月饼重用\"克\"作单位比较合适;两袋500克的盐是1千克，所以，计量一个人的体重用\"千克\"作单位比较合适;食指宽大约是1厘米，所以，计量一个人的身高用\"厘米\"作单位比较合适。\n\n【详解】由题意分析得：兰兰体重26千克;身高131厘米;一个月饼重180克。",
+        "knowledge_points":  [
+                                 "质量单位的选择，长度单位的选择"
+                             ],
+        "source":  "24-25二年级下·江西赣州·期末"
+    },
+    {
+        "id":  "38",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "9个猕猴桃约重1千克,37个猕猴桃约重( )千克。",
+        "options":  [
+
+                    ],
+        "answer":  "4",
+        "solution":  "【分析】根据题意，用除法计算出37里面有几个9，就是大约有几千克。\n\n【详解】37÷9=4。1，也就是37里面大约有4个9。则9个猕猴桃约重1千克,37个猕猴桃约重4千克。",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算，千克的认识"
+                             ],
+        "source":  "24-25 二年级下·湖南张家界·期末"
+    },
+    {
+        "id":  "39",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "一只兔子重2( ) 两个回形针重1( )\n小明体重是30( ) 一盒酸奶重240( )",
+        "options":  [
+
+                    ],
+        "answer":  "千克或kg;克或g;千克或kg;克或g",
+        "solution":  "【分析】根据生活经验，对质量单位和数据大小的认识可知，一分钱的硬币重约1克，所以，计量两个回形针重和计量一盒酸奶重用\"克\"作单位比较合适;两袋500克的盐是1千克，所以，计量一只兔子重和计量小明体重用\"千克\"作单位比较合适。\n\n【详解】由分析可知：一只兔子重2千克;两个回形针重1克;小明体重是30千克;一盒酸奶重240克。",
+        "knowledge_points":  [
+                                 "质量单位的选择"
+                             ],
+        "source":  "24-25 二年级下·湖南张家界·期末"
+    },
+    {
+        "id":  "40",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "军军身高138( );体重32( );一个鸡蛋重约48( )。",
+        "options":  [
+
+                    ],
+        "answer":  "厘米或cm;千克或kg;克或g",
+        "solution":  "【分析】根据生活经验，对长度单位，质量单位和数据大小的认知填单位：食指宽大约是1厘米，所以军军的身高用厘米作单位比较合适;计量比较轻的物体，常用克作单位,2个曲别针约重1克，所以一个鸡蛋的重量用克作单位比较合适;计量比较重的物体，常用千克作单位,2袋白砂糖约重1千克，所以军军的体重用千克作单位比较合适。\n\n【详解】军军身高138厘米;体重32千克;一个鸡蛋重约48克。",
+        "knowledge_points":  [
+                                 "克的认识，千克的认识，质量单位的选择，长度单位的选择"
+                             ],
+        "source":  "24-25 二年级下·江西赣州·期末"
+    },
+    {
+        "id":  "41",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "一个西瓜重3000( )。 一只羊重50( )。 一个鸡蛋重50( )。",
+        "options":  [
+
+                    ],
+        "answer":  "克;千克;克",
+        "solution":  "【分析】根据实际情境生活经验及数据的大小选择合适的单位，一粒花生米的质量大约是1克，两包食用盐的质量大约是1千克。一个西瓜重结合数据3000用克作单位;一只羊重结合数据50用千克作单位，一个鸡蛋重结合数据50用克作单位。据此解答。\n\n【详解】根据分析：一个西瓜重3000(克)。一只羊重50(千克)。一个鸡蛋重50(克)。",
+        "knowledge_points":  [
+                                 "克的认识，千克的认识，质量单位的选择"
+                             ],
+        "source":  "24-25二年级下·海南省直辖县级单位·期末"
+    },
+    {
+        "id":  "42",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "一头猪约重160( ) 一个鸡蛋约重55( )\n一瓶食用油约重5( ) 一支铅笔约长18( )",
+        "options":  [
+
+                    ],
+        "answer":  "千克或kg;克或g;千克或kg;厘米或cm",
+        "solution":  "【分析】计量比较轻的物体重量用\"克\"作单位，如一粒花生米重量大约是1克。计量比较重的物体重量用\"千克\"作单位，如2袋食盐重量是1千克。量比较短的物体的长度，通常用厘米作单位，食指的宽度大约是1厘米。\n\n【详解】一头猪比较重，用\"千克\"作单位比较合适，因此一头猪约重160千克;一个鸡蛋的重量比较轻，用\"克\"作单位比较合适，因此一个鸡蛋约重55克;一瓶食用油比较重，用\"千克\"作单位比较合适，因此一瓶食用油约重5千克;铅笔比较短，大约是18个食指的宽度，用\"厘米\"作单位比较合适，因此一支铅笔约长18厘米。",
+        "knowledge_points":  [
+                                 "质量单位的选择，长度单位的选择"
+                             ],
+        "source":  "24-25 二年级下·浙江湖州·期末"
+    },
+    {
+        "id":  "43",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "买8个猕猴桃约重500克,32个猕猴桃约重( )千克。",
+        "options":  [
+
+                    ],
+        "answer":  "2",
+        "solution":  "【分析】根据题意，先用除法计算出32里面有几个8，也就是大约有几组500克，相加计算出总重量约是多少克，根据1千克=1000克换算单位即可。\n\n【详解】32÷8=4(组),500克+500克+500克+500克=2000克,2000克=2千克，买8个猕猴桃约重500克,32个猕猴桃约重2千克。",
+        "knowledge_points":  [
+                                 "整百数，几百几十数的加减法口算，克，千克之间的换算与比较"
+                             ],
+        "source":  "24-25 二年级下·福建厦门·期末"
+    },
+    {
+        "id":  "44",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "(1)一只蜂鸟的体重约是2( ).\n(2)一袋面粉大约重20( ).\n(3)小亮的体重是27( ),他的数学课本重170( )。",
+        "options":  [
+
+                    ],
+        "answer":  "克或g 千克或kg 千克或kg;克或g",
+        "solution":  "【分析】根据生活经验，对质量单位和数据大小的认识可知：计量比较轻的物体，常用克作单位,2个曲别针约重1克，所以蜂鸟的体重，数学课本的重量用克作单位比较合适;计量比较重的物体，常用千克作单位,2袋白砂糖约重1千克，所以面粉的重量，小亮的体重用千克作单位比较合适。\n\n【详解】(1)一只蜂鸟的体重约是2克(g)。(2)一袋面粉大约重20千克(kg)。(3)小亮的体重是27千克(kg),他的数学课本重170克(g)。",
+        "knowledge_points":  [
+                                 "质量单位的选择"
+                             ],
+        "source":  "24-25 二年级下·江西赣州·期末"
+    },
+    {
+        "id":  "45",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "在括号里填上\"\u003e\"\"\u003c\"或\"\".\n456( )4652358( )2385 (16+24)÷8( )16+24÷8\n700克+300克( )1千克 1500克( )2千克",
+        "options":  [
+
+                    ],
+        "answer":  "\u003c;\u003c;\u003c;=;\u003c",
+        "solution":  "【分析】比较大小方法:①位数多的数大于位数少的数;②位数相同的，先比较最高位上的数，最高位上大的，数就大，最高位数相同的，就比较下一位，以此类推。在没有括号的算式里，如果只有加减法或者只有乘除法，要从左往右依次计算。在没有括号的算式里，如果既有乘除法又有加减法，要先算乘除法，再算加减法。在有括号的算式里，要先算括号里面的，再算括号外面的。有算式的先算出得数再进行比较，单位不统一的先统一单位再进行比较;据此解答。\n\n【详解】由分析可得:456( )465：百位数字相等，十位数字5\u003c6，故456\u003c465;2358( )2385：千位和百位数字相等，十位数字5\u003c8，故2358\u003c2385;(16+24)÷8=40÷8=5,16+24÷8=16+3=19,5\u003c19，故(16+24)÷8\u003c16+24÷8;700克+300克=1000克,1000克=1千克,1千克=1千克，故700克+300克=1千克;2千克=2000克,1500克\u003c2000克，故1500克\u003c2千克。",
+        "knowledge_points":  [
+                                 "万以内数的大小比较，除加，除减混合运算，带有小括号的混合运算，克，千克之间的换算与比较"
+                             ],
+        "source":  "24-25 二年级下·湖北孝感·期末"
+    },
+    {
+        "id":  "46",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "学校操场跑一圈是400( ),小明的体重是30( )。",
+        "options":  [
+
+                    ],
+        "answer":  "米或m;千克或kg",
+        "solution":  "【分析】根据对生活经验，长度单位，重量单位和数据大小的认识可知：测量较高(或较长)物体的长度时，一般选择用\"米\"作单位。计量比较轻的物体，常用\"克\"作单位，计量比较重的物体，常用\"千克\"作单位。二年级学生双臂展开的长度大约是1米，所以计量学校操场跑一圈的长度用\"米\"作单位比较合适;2小袋食盐重1千克，所以计量小明的体重用\"千克\"作单位比较合适;据此解答。\n\n【详解】由分析可得：学校操场跑一圈是400米，小明的体重是30千克。",
+        "knowledge_points":  [
+                                 "千克的认识，质量单位的选择，长度单位的选择"
+                             ],
+        "source":  "24-25二年级下·河南郑州·期末"
+    },
+    {
+        "id":  "47",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "超市的杨梅每500克要8元，王阿姨买了一箱3千克的杨梅，要付( )元。",
+        "options":  [
+
+                    ],
+        "answer":  "48",
+        "solution":  "【分析】根据1千克=1000克，先计算出3千克里面有几个500克，再和每500克的钱数相乘，就是要付的钱数。\n\n【详解】3千克=3000克,500克+500克+500克+500克+500克+500克=3000克，即3000克里面有6个500克。8×6=48(元),超市的杨梅每500克要8元，王阿姨买了一箱3千克的杨梅，要付48元。",
+        "knowledge_points":  [
+                                 "克，千克之间的换算与比较"
+                             ],
+        "source":  "24-25 二年级下·浙江台州·期末"
+    },
+    {
+        "id":  "48",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "8000克( )8千克 4千克( )1000克\n6666克( )6千克 500克+300克( )2千克\n3574( )35474300( )3300+1000",
+        "options":  [
+
+                    ],
+        "answer":  "=;\u003e;\u003e;\u003c;\u003e;=",
+        "solution":  "【分析】1千克=1000克，根据进率统一单位再进行比较;含有算式的题目，先计算出算式的结果再进行比较;整数比较大小方法:①位数多的数大于位数少的数;②位数相同的，先比较最高位上的数，最高位上大的，数就大，最高位数相同的，就比较下一位，以此类推。据此解答。\n\n【详解】8千克=8000克,8000克=8000克，故8000克=8千克;4千克=4000克,4000克\u003e1000克，故4千克\u003e1000克;6千克=6000克,6666克\u003e6000克，故6666克\u003e6千克;500克+300克=800克,2千克=2000克,800克\u003c2000克，故500克+300克\u003c2千克;都是四位数，千位和百位相同，十位7\u003e4，故3574\u003e3547;3300+1000=4300,4300=4300，故4300=3300+1000。",
+        "knowledge_points":  [
+                                 "万以内数的大小比较，克，千克之间的换算与比较"
+                             ],
+        "source":  "24-25 二年级下·甘肃兰州·期末"
+    },
+    {
+        "id":  "49",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "一袋盐重500( ) 一个西瓜约重4( )",
+        "options":  [
+
+                    ],
+        "answer":  "克或g;千克或kg",
+        "solution":  "【分析】根据生活经验，对质量单位和数据大小的认识可知：计量比较轻的物体，常用克作单位,2个曲别针约重1克，所以一袋盐的重量用克作单位比较合适;计量比较重的物体，常用千克作单位,2袋白砂糖约重1千克，所以一个西瓜的重量用千克作单位比较合适。\n\n【详解】由分析得：一袋盐重500克(g);一个西瓜约重4千克(kg)。",
+        "knowledge_points":  [
+                                 "质量单位的选择"
+                             ],
+        "source":  "24-25 二年级下·新疆阿克苏·期末"
+    },
+    {
+        "id":  "50",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "一袋面粉重10( ),一个鸡蛋重50( )。(填\"克\"或\"千克\")",
+        "options":  [
+
+                    ],
+        "answer":  "千克;克",
+        "solution":  "【分析】根据生活经验以及对质量单位和数据大小的认识,1瓶矿泉水大约重500克,2瓶矿泉水大约重1千克，所以计量一袋面粉的质量用\"千克\"做单位比较合适。1张普通的A4纸大约重1克，所以计量一个鸡蛋的质量用\"克\"做单位比较合适。\n\n【详解】据分析可知：一袋面粉重10千克，一个鸡蛋重50克。",
+        "knowledge_points":  [
+                                 "克的认识，千克的认识"
+                             ],
+        "source":  "24-25 二年级下·湖南岳阳·期中"
+    },
+    {
+        "id":  "51",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "葡萄每千克8元，小美买了几串葡萄，重3998克，她大约要付( )元。",
+        "options":  [
+
+                    ],
+        "answer":  "32",
+        "solution":  "【分析】根据题意，先将小美买的葡萄的重量看成与之接近的整克数，再根据1千克=1000克换算单位，最后和每千克葡萄的钱数相乘即可。\n\n【详解】3998克≈4000克,4000克=4千克,8×4=32(元),所以她大约要付32元。",
+        "knowledge_points":  [
+                                 "万以内数的估计,8的乘法口诀及应用，克，千克之间的换算与比较"
+                             ],
+        "source":  "23-24 二年级下·云南昭通·期末"
+    },
+    {
+        "id":  "52",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在括号里填上\"\u003e\"\"\u003c\"或\"=\".\n3058( )30856千克( )666克 3000( )30个百",
+        "options":  [
+
+                    ],
+        "answer":  "\u003c;\u003e;=",
+        "solution":  "【分析】比较数的大小时，位数多的数就大，位数相同比较最高位，最高位大的数就大，最高位相同比较下一位，直到比较出结果为止。第1题：直接比较;第2题：根据1千克=1000克统一单位再比较;第3题：根据数的组成，几个百就是几百，几十个百就是几千，写出数字再比较。\n\n【详解】3058和3085位数相同，千位相同，百位相同，十位5\u003c8，则3058\u003c3085;6千克=6000克,6000克\u003e666克，则6千克\u003e666克;30个百是3000，则3000=30个百。",
+        "knowledge_points":  [
+                                 "万以内数的组成，万以内数的大小比较，克，千克之间的换算与比较"
+                             ],
+        "source":  "23-24二年级下·云南昭通·期末"
+    },
+    {
+        "id":  "53",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在括号里填上\"克\"或\"千克\".\n一袋大米重25( ) 一根香蕉约重200( )",
+        "options":  [
+
+                    ],
+        "answer":  "千克;克",
+        "solution":  "【分析】计量比较重的物品，通常用千克作单位,2袋白砂糖重1千克，所以一袋大米的重量用千克作单位比较合适。计量比较轻的物品，通常用克作单位,2个曲别针约重1克，所以一根香蕉的重量用克作单位比较合适。\n\n【详解】一袋大米重25千克;一根香蕉约重200克。",
+        "knowledge_points":  [
+                                 "克的认识，千克的认识，质量单位的选择"
+                             ],
+        "source":  "23-24二年级下·云南昭通·期末"
+    },
+    {
+        "id":  "54",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "一瓶醋500克,2瓶醋有( )克，也就是( )千克。",
+        "options":  [
+
+                    ],
+        "answer":  "1000;1",
+        "solution":  "【分析】一瓶醋大约重500克,2瓶醋的重量是2个500克,500加500即可知道2瓶的质量，再将单位化为千克,1千克=1000克。\n\n【详解】500+500=1000(克),1000克=1千克，一瓶醋500克,2瓶醋有1000克，也就是1千克。",
+        "knowledge_points":  [
+                                 "整百数，几百几十数的加减法口算，克，千克之间的换算与比较"
+                             ],
+        "source":  "24-25 二年级下·广西贵港·期中"
+    },
+    {
+        "id":  "55",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在括号里填上合适的质量单位.\n二年级的乐乐很注意饮食健康，他每天吃一个重约150( )的苹果，吃300( )的青菜，他现在的体重是28( )。他不费力就能提起来一桶重5( )的食用油。",
+        "options":  [
+
+                    ],
+        "answer":  "克或g;克或g;千克或kg;千克或kg",
+        "solution":  "【分析】计量比较轻的物体重量用\"克\"作单位，如一粒花生米重量大约是1克。计量比较重的物体重量用\"千克\"作单位，如2袋食盐重量是1千克。\n\n【详解】苹果和吃的青菜比较轻，因此苹果和吃的青菜的重量用\"克\"作单位比较合适;乐乐的体重和食用油比较重，因此乐乐的体重和食用油的重量用\"千克\"作单位比较合适。二年级的乐乐很注意饮食健康，他每天吃一个重约150(克)的苹果，吃300(克)的青菜，他现在的体重是28(千克)。他不费力就能提起来一桶重5(千克)的食用油。",
+        "knowledge_points":  [
+                                 "质量单位的选择"
+                             ],
+        "source":  "24-25 二年级下·山东济宁·期末"
+    },
+    {
+        "id":  "56",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "一颗鸡蛋约重50( ),一袋大米重25( )。",
+        "options":  [
+
+                    ],
+        "answer":  "克或g;千克或kg",
+        "solution":  "【分析】根据情景选择合适的计量单位，要注意联系生活实际，计量单位和数据的大小，灵活的选择。1克大约为一枚硬币的重量，计量一个鸡蛋的重量用\"克\"作单位比较合适。1千克大约为两瓶矿泉水的重量，计量一袋大米重量用\"千克\"作单位比较合适。\n\n【详解】一颗鸡蛋约重50(克),一袋大米重25(千克)。",
+        "knowledge_points":  [
+                                 "克的认识，千克的认识，质量单位的选择"
+                             ],
+        "source":  "24-25 二年级下·黑龙江佳木斯·期末"
+    },
+    {
+        "id":  "57",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "8个鸡蛋大约重500克，估一估:16个鸡蛋大约重( )克。",
+        "options":  [
+
+                    ],
+        "answer":  "1000",
+        "solution":  "【分析】根据题意，先用除法计算出16里面有几个8，也就是16个鸡蛋里有几个500克，再相加计算出总重量即可。\n\n【详解】16÷8=2,16个鸡蛋的重量大约是2个500克的和，即500+500=1000(克),8个鸡蛋大约重500克，估一估:16个鸡蛋大约重1000克。",
+        "knowledge_points":  [
+                                 "整百数，几百几十数的加减法口算，克的认识"
+                             ],
+        "source":  "24-25 二年级下·湖北随州·期末"
+    },
+    {
+        "id":  "58",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "妈妈很重视聪聪的营养搭配：安排他每天吃一个50( )的鸡蛋，喝一袋重250( )的牛奶，吃一个150( )的苹果。他的体重已有30( )。",
+        "options":  [
+
+                    ],
+        "answer":  "克或g;克或g;克或g;千克或kg",
+        "solution":  "【分析】根据生活经验，对质量单位和数据大小的认识可知：计量比较轻的物体，常用克作单位,2个曲别针约重1克，所以一个鸡蛋的重量，一袋牛奶的重量，一个苹果的重量用克作单位比较合适;计量比较重的物体，常用千克作单位,2袋白砂糖约重1千克，所以聪聪的体重用千克作单位比较合适。\n\n【详解】妈妈很重视聪聪的营养搭配：安排他每天吃一个50克(g)的鸡蛋，喝一袋重250克(g)的牛奶，吃一个150克(g)的苹果。他的体重已有30千克(kg)。",
+        "knowledge_points":  [
+                                 "质量单位的选择"
+                             ],
+        "source":  "24-25 二年级下·湖北随州·期末"
+    },
+    {
+        "id":  "59",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在括号里面填\"\u003e\"\"\u003c\"或\"=\".\n10000( )99995099克( )9千克 49÷7( )32/4\n7667( )76761千克( )400克+600克 72-48÷6( )(72-48)÷6",
+        "options":  [
+
+                    ],
+        "answer":  "\u003e;\u003c;\u003c;\u003c;=;\u003e",
+        "solution":  "【分析】比较大小方法:①位数多的数大于位数少的数;②位数相同的，先比较最高位上的数，最高位上大的，数就大，最高位数相同的，就比较下一位，以此类推。有算式的先算出得数再进行比较，单位不统一的先统一单位再进行比较;据此解答。\n\n【详解】由分析可得:10000( )9999：五位数\u003e四位数，故10000\u003e9999;5099克( )9千克:9千克=9000克,5099\u003c9000，故5099克\u003c9千克;49÷7=7,32÷4=8,7\u003c8，故49÷7\u003c32÷4;7667( )7676：千位百位数字相等，十位数字6\u003c7，故7667\u003c7676;1千克( )400克+600克:400克+600克=1000克=1千克,1千克=1千克，故1千克=400克+600克;72-48÷6=72-8=64,(72-48)÷6=24÷6=4,64\u003e4，故72-48÷6\u003e(72-48)÷6。",
+        "knowledge_points":  [
+                                 "万以内数的大小比较，除加，除减混合运算，带有小括号的混合运算，克，千克之间的换算与比较"
+                             ],
+        "source":  "24-25 二年级下·福建福州·期末"
+    },
+    {
+        "id":  "60",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "2000克( )2千克 1001( )99935÷7( )6",
+        "options":  [
+
+                    ],
+        "answer":  "=;\u003e;\u003c",
+        "solution":  "【分析】整数比较大小：先看位数的多少，位数多的数大;位数相同，从最高位比起，最高位上的数大这个数就大，若最高位上的数相同，就比较下一位，依次类推，直到比出大小。单位不统一的，先根据1千克=1000克，统一单位之后再比较大小;有算式的，先计算出各算式的结果再比较大小。\n\n【详解】2千克=2000克,2000克=2000克，所以2000克=2千克;1001\u003e999;35÷7=5,5\u003c6，所以35÷7\u003c6。",
+        "knowledge_points":  [
+                                 "万以内数的大小比较，用7~9的乘法口诀求商，克，千克之间的换算与比较"
+                             ],
+        "source":  "24-25 二年级下·黑龙江佳木斯·期末"
+    },
+    {
+        "id":  "61",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在( )里填上\"\u003e\"\"\u003c\"或\"=\".\n6889( )68984900克( )5千克 24÷3/2( )24÷(3×2)",
+        "options":  [
+
+                    ],
+        "answer":  "\u003c;\u003c;=",
+        "solution":  "【分析】整数比较大小：先看位数的多少，位数多的数大;位数相同，从最高位比起，最高位上的数大这个数就大，若最高位上的数相同，就比较下一位，依次类推，直到比出大小。有算式的，先计算出各算式的结果，再比较大小;单位不统一的，先根据1千克=1000克，统一单位以后再比较大小。\n\n【详解】6889\u003c6898;5千克=5000克,4900克\u003c5000克，所以4900克\u003c5千克;24÷3/2=8÷2=4,24÷(3×2)=24÷6=4,4=4，所以24÷3/2=24÷(3×2)。",
+        "knowledge_points":  [
+                                 "万以内数的大小比较，表内连乘，连除运算，带有小括号的混合运算，克，千克之间的换算与比较"
+                             ],
+        "source":  "24-25 二年级下·山东济宁·期末"
+    },
+    {
+        "id":  "62",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在括号里填上合适的单位名称.\n小明体重约是20( )。 一个鸡蛋约重60( )。 一只兔子约重3( )。 一只铅笔长约18( )。",
+        "options":  [
+
+                    ],
+        "answer":  "千克或kg;克或g;千克或kg;厘米/cm",
+        "solution":  "【分析】根据生活常识和对不同重量单位和长度单位的认识来选择合适的单位。计量比较轻的物体，常用\"克\"作单位，计量比较重的物体，常用\"千克\"作单位。测量较矮(或较短)物体的长度时，一般选择用\"厘米\"作单位。2小袋食盐重1千克，所以计量小明体重，一只兔子约重用\"千克\"作单位比较合适;2个曲别针约重1克，所以计量一个鸡蛋约重用\"克\"作单位比较合适;1厘米大约是食指的宽度，所以计量一只铅笔长用\"厘米\"作单位比较合适;据此解答。\n\n【详解】由分析可得：小明体重约是20千克。一个鸡蛋约重60克。一只兔子约重3千克。一只铅笔长约18厘米。",
+        "knowledge_points":  [
+                                 "质量单位的选择，长度单位的选择"
+                             ],
+        "source":  "24-25 二年级下·山东济宁·期末"
+    },
+    {
+        "id":  "63",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在括号里填上\"\u003e\"\"\u003c\"或\"=\".\n5千克( )5000克 6700( )6070400+500( )1700-700",
+        "options":  [
+
+                    ],
+        "answer":  "=;\u003e;\u003c",
+        "solution":  "【分析】根据1千克=1000克，先将单位统一，再进行比较大小即可。有算式先算出算式的得数，根据整数比较大小的方法：比较两个整数的大小，要先看它们的位数，如果位数不同，位数多的数就大;如果位数相同，则从高位开始比较，相同数位上的数大的那个数就大。\n\n【详解】5千克=5000克;6700\u003e6070;400+500=900,1700-700=1000,900\u003c1000，所以400+500\u003c1700-700。",
+        "knowledge_points":  [
+                                 "万以内数的大小比较，整百数，几百几十数的加减法口算，克，千克之间的换算与比较"
+                             ],
+        "source":  "24-25 二年级下·甘肃天水·期末"
+    },
+    {
+        "id":  "64",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "在括号里填\"\u003e\"\"\u003c\"或\"=\".\n6889( )68984900克( )5千克\n10000( )99996×3+6( )12÷2+18",
+        "options":  [
+
+                    ],
+        "answer":  "\u003c;\u003c;\u003e;=",
+        "solution":  "【分析】万以内数比较大小的方法：比较数的大小，先看位数的多少，位数多的数就大;如果位数相同，从最高位开始比较，最高位上的数大则这个数大，最高位上的数相同，就比较下一位，依次类推。含有算式的大小比较，可以先计算出每个算式的结果，再比较大小;单位不同的可以根据1千克=1000克，统一单位后再比较大小，即可解答。\n\n【详解】6889和6898的千位和百位上的数相同，十位上8\u003c9，所以6889\u003c6898;5千克=5000克,4900和5000千位上4\u003c5，则4900\u003c5000，所以4900克\u003c5千克;6×3+6=18+6=24,12÷2+18=6+18=24,24和24相等，所以6×3+6=12÷2+18。",
+        "knowledge_points":  [
+                                 "万以内数的大小比较，乘加，乘减混合运算，除加，除减混合运算，克，千克之间的换算与比较"
+                             ],
+        "source":  "24-25 二年级下·黑龙江佳木斯·期末"
+    },
+    {
+        "id":  "65",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "小明的体重是30( ),他每天喝一袋250( )的牛奶，吃一个约60( )的鸡蛋，背着重约2( )的书包上学。(填\"克\"或\"千克\")",
+        "options":  [
+
+                    ],
+        "answer":  "千克;克;克;千克",
+        "solution":  "【分析】根据生活经验，对质量单位的认识可知,1枚回形针的重量大约是1克，两瓶矿泉水重量大约是1千克，据此进行解答即可。\n\n【详解】小明的重量远重于30枚回形针，所以小明的体重用\"千克\"作为单位更合适;一袋牛奶的重量比两瓶矿泉水的重量更轻，结合单位前面的数据250，所以一袋牛奶的重量用\"克\"作为单位更合适;一个鸡蛋的重量比两瓶矿泉水的重量更轻，结合单位前面的数据60，所以一个鸡蛋的重量用\"克\"作为单位更合适;书包的重量比两瓶矿泉水的重量重，结合单位前面的数据2，所以书包的重量用\"千克\"作为单位更合适。综上可得：小明的体重是30千克，他每天喝一袋250克的牛奶，吃一个约60克的鸡蛋，背着重约2千克的书包上学。",
+        "knowledge_points":  [
+                                 "克的认识，千克的认识，质量单位的选择"
+                             ],
+        "source":  "24-25 二年级下·黑龙江佳木斯·期末"
+    },
+    {
+        "id":  "66",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在括号里填上合适的单位：一个苹果约重200( ),小明身高1( )25( )。",
+        "options":  [
+
+                    ],
+        "answer":  "克或g;米或m;厘米或cm",
+        "solution":  "【分析】1克大约为一枚硬币的重量，计量一个苹果的重量用\"克\"作单位比较合适。大拇指的指甲长度大约1厘米，小学生两臂伸开的长度大约1米。小朋友的身高一般是一百多厘米,100厘米=1米，也就是大约1米几十厘米。\n\n【详解】一个苹果约重200克，小明身高1米25厘米。",
+        "knowledge_points":  [
+                                 "质量单位的选择，长度单位的选择"
+                             ],
+        "source":  "24-25 二年级下·黑龙江佳木斯·期末"
+    },
+    {
+        "id":  "67",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在括号里填上合适的质量单位.\n(1)一块橡皮重20( )。 (2)一袋面粉重25( ).\n(3)一块面包重70( )。 (4)一只小鱼重12( )。",
+        "options":  [
+
+                    ],
+        "answer":  "克或g 千克或kg 克或g 克或g",
+        "solution":  "【分析】根据生活经验，对质量单位和数据大小的认识可知：计量比较轻的物体，常用克作单位,2个曲别针约重1克，所以计量橡皮的重量，面包的重量，小鱼的重量用克作单位比较合适;计量比较重的物体，常用千克作单位,2袋白砂糖约重1千克，所以计量面粉的重量用千克作单位比较合适。\n\n【详解】一块橡皮重20克;一袋面粉重25千克;一块面包重70克;一只小鱼重12克。",
+        "knowledge_points":  [
+                                 "克的认识，千克的认识，质量单位的选择"
+                             ],
+        "source":  "24-25二年级下·内蒙古赤峰·期末"
+    },
+    {
+        "id":  "68",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "在括号里填上\"\u003e\"\"\u003c\"或\"=\".\n32千克( )3200克 1800克-700克( )1千克 5000克( )5千克\n1100-400( )7006901( )96015400( )540",
+        "options":  [
+
+                    ],
+        "answer":  "\u003e;\u003e;=;=;\u003c;\u003e",
+        "solution":  "【分析】先统一单位或计算数值，再比较大小。注意单位换算:1千克=1000克。整数比较时，位数多的数大;位数相同则从最高位开始逐位比较。\n\n【详解】3200克=3千克200克,3千克200克\u003c4千克，故,32千克\u003e3200克;1800克-700克=1100克,1千克=1000克,1100克\u003e1000克，故,1800克-700克\u003e1千克;1000克=1千克，故,5000克=5千克;1100-400=700;都是四位数，最高位6\u003c9，故,6901\u003c9601;5400是四位数,540是三位数，位数多的数更大，故,5400\u003e540。",
+        "knowledge_points":  [
+                                 "万以内数的大小比较，整百数，几百几十数的加减法口算，克，千克之间的换算与比较"
+                             ],
+        "source":  "24-25 二年级下·甘肃天水·期末"
+    },
+    {
+        "id":  "69",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "两袋食用盐重1000( ),小华的体重是23( )。",
+        "options":  [
+
+                    ],
+        "answer":  "克或g;千克或kg",
+        "solution":  "【分析】根据生活常识和对不同重量单位的认识来选择合适的单位。计量比较轻的物体，常用\"克\"作单位，计量比较重的物体，常用\"千克\"作单位。2个曲别针约重1克，所以计量两袋食用盐重用\"克\"作单位比较合适;2小袋食盐重1千克，所以计量小华的体重用\"千克\"作单位比较合适;据此可解。\n\n【详解】由分析可得：两袋食用盐重1000克，小华的体重是23千克。",
+        "knowledge_points":  [
+                                 "克的认识，千克的认识，质量单位的选择"
+                             ],
+        "source":  "24-25 二年级下·甘肃天水·期末"
+    },
+    {
+        "id":  "70",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "4千克=( )克 6千克-1000克=( )千克",
+        "options":  [
+
+                    ],
+        "answer":  "4000;5",
+        "solution":  "【分析】根据克和千克之间的换算:1千克=1000克，将单位进行统一后再进行解答即可。\n\n【详解】1千克=1000克，所以4千克=4000克;1千克=1000克，则6-1=5，所以6千克-1000克=5千克。",
+        "knowledge_points":  [
+                                 "克，千克之间的换算与比较"
+                             ],
+        "source":  "24-25 二年级下·吉林四平·期末"
+    },
+    {
+        "id":  "71",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "妈妈买了12个桃子，平均4个重1千克，那么这些桃子重( )千克;每500克桃子2元，妈妈共花了( )元钱。",
+        "options":  [
+
+                    ],
+        "answer":  "3;12",
+        "solution":  "【分析】根据克和千克之间的换算可知,1千克=1000克。根据除法的意义，桃子的总数/每份4个桃子=可以分成的份数，列出算式算出12里面有几份4个桃子。再根据加法的意义，可以分成的份数×一份桃子的重量=全部桃子的重量，列出算式算出答案即可知道12个桃子的重量。不断用桃子的总重量-500克桃子的重量，一直减到剩余的桃子的重量为0时，数出一共减了几个500克桃子的重量，就是500克桃子为一份的份数。再根据乘法的意义，一份500克桃子的价格*500克桃子为一份的份数=全部桃子的总价格，由此列出算式算出答案。\n\n【详解】12÷4=3(份),3×1=3(千克),3千克=3000克,3000-500=2500(克),2500-500=2000(克),2000-500=1500(克),1500-500=1000(克),1000-500=500(克),500-500=0(克),数出一共减去了6个500克，所以3千克里面有6个500克。2×6=12(元),所以，妈妈买了12个桃子，平均4个重1千克，那么这些桃子重3千克;每500克桃子2元，妈妈共花了12元钱。",
+        "knowledge_points":  [
+                                 "整百数，几百几十数的加减法口算,6的乘法口诀及应用，用2~5的乘法口诀求商，克，千克之间的换算与比较"
+                             ],
+        "source":  "24-25 二年级下·辽宁鞍山·期末"
+    },
+    {
+        "id":  "72",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "判断题",
+        "difficulty":  0.65,
+        "question":  "1000克的棉花糖与1千克的棒棒糖同样重。( )",
+        "options":  [
+
+                    ],
+        "answer":  "√",
+        "solution":  "【分析】比较1000克与1千克的质量是否相等，需将单位统一后进行判断。根据质量单位换算,1千克=1000克，因此两者质量相同。\n\n【详解】根据分析可知:1千克=1000克,1000克的棉花糖与1千克的棒棒糖同样重。原题说法正确。故答案为:√",
+        "knowledge_points":  [
+                                 "克，千克之间的换算与比较"
+                             ],
+        "source":  "24-25三年级上·广东汕头·期中"
+    },
+    {
+        "id":  "73",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "1千克的铁比1000克纸重。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】比较1千克和1000克的重量，需先统一单位。1千克=1000克，因此两者的质量相等。\n\n【详解】1千克=1000克，铁和纸的质量均为1000克，所以它们的重量相等。故答案为: ×",
+        "knowledge_points":  [
+                                 "克，千克之间的换算与比较"
+                             ],
+        "source":  "24-25 三年级上·云南楚雄·期中"
+    },
+    {
+        "id":  "74",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "1千克鸭毛和1千克水一样重。( )",
+        "options":  [
+
+                    ],
+        "answer":  "√",
+        "solution":  "【分析】比较两个物体的质量是否相等，需依据它们的实际重量。题目中明确给出1千克鸭毛和1千克水，两者的质量均为1千克，因此重量相同。\n\n【详解】根据质量的定义,1千克的物体无论种类，体积如何，其质量均为1千克。题目中1千克鸭毛和1千克水的质量相等，因此它们的重量相同。故答案为:√",
+        "knowledge_points":  [
+                                 "千克的认识"
+                             ],
+        "source":  "24-25三年级上·河北唐山·期中"
+    },
+    {
+        "id":  "75",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "一本书的质量大约为250千克。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】称一般物体有多重，常用千克作单位。两包盐的重量是1千克，千克用字母\"kg\"表示。称比较轻的物体，通常用克作单位。1枚1分的硬币大约重1克，所以计量本书的重量用\"克\"作单位比较合适。据此判断。\n\n【详解】根据生活实际，一本书的质量大约为250克，如果是250千克，显然不符合实际。因此，题目中的说法错误。故答案为: ×",
+        "knowledge_points":  [
+                                 "克的认识，千克的认识，质量单位的选择"
+                             ],
+        "source":  "24-25 三年级上·河南南阳·期中"
+    },
+    {
+        "id":  "76",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "判断题",
+        "difficulty":  0.94,
+        "question":  "因为111\u003e1，所以111克\u003e1千克。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】比较物体的重量时，需先统一单位。1千克=1000克，因此111克与1千克比较时，应将1千克转化为1000克，再比较数值大小。\n\n【详解】1千克=1000克,111克与1000克相比,111\u003c1000，所以111克\u003c1千克，则原题说法错误。故答案为: ×",
+        "knowledge_points":  [
+                                 "克，千克之间的换算与比较"
+                             ],
+        "source":  "24-25 二年级下·山东菏泽·期末"
+    },
+    {
+        "id":  "77",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "1kg水泥和1000g的白灰一样重。( )",
+        "options":  [
+
+                    ],
+        "answer":  "√",
+        "solution":  "【分析】比较1kg和1000g是否相等，需统一单位。1kg=1000g,因此无论物质种类，质量相等即重量相同。\n\n【详解】1kg=1000g,水泥和白灰的质量均为1kg(或1000g),因此它们的重量相等。原题说法正确。故答案为:√",
+        "knowledge_points":  [
+                                 "千克的认识，克，千克之间的换算与比较"
+                             ],
+        "source":  "24-25 二年级下·广东汕头·期末"
+    },
+    {
+        "id":  "78",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "小明读二年级，他的体重是250克。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】根据生活常识和对不同重量单位的认识来选择合适的单位。计量比较轻的物体，常用\"克\"作单位，计量比较重的物体，常用\"千克\"作单位。2小袋食盐重1千克，所以计量小明的体重用\"千克\"作单位比较合适;据此解答。\n\n【详解】小明读二年级，他的体重是25千克。原题说法错误。故答案为: ×",
+        "knowledge_points":  [
+                                 "克的认识，千克的认识，质量单位的选择"
+                             ],
+        "source":  "24-25 二年级下·湖北省直辖县级单位·期末"
+    },
+    {
+        "id":  "79",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "2000克铁比2千克木头重。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】比较物体的质量时，需先统一单位。根据1千克=1000克，将2千克转换为2000克，再与2000克铁比较。\n\n【详解】2千克=2000克,2000克铁与2000克木头的质量相等，因此\"2000克铁比2千克木头重\"是错误的。故答案为: ×",
+        "knowledge_points":  [
+                                 "克，千克之间的换算与比较"
+                             ],
+        "source":  "24-25 二年级下·湖北·期末"
+    },
+    {
+        "id":  "80",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "4800克\u003e3千克。( )",
+        "options":  [
+
+                    ],
+        "answer":  "√",
+        "solution":  "【分析】根据重量单位之间的进率:1千克=1000克，进行单位换算，再进行比较，即可进行判断;据此解答。\n\n【详解】由分析可得:3千克=3000克,4800克\u003e3000克,4800克\u003e3千克。故答案为:√",
+        "knowledge_points":  [
+                                 "万以内数的大小比较，克，千克之间的换算与比较"
+                             ],
+        "source":  "24-25 二年级下·山东菏泽·期末"
+    },
+    {
+        "id":  "81",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "5kg的沙子和5kg的棉花一样重。( )",
+        "options":  [
+
+                    ],
+        "answer":  "√",
+        "solution":  "【分析】比较物体的重量时，只比较物体本身的重量，与物体本身的材质无关。\n\n【详解】5kg=5kg,故,5kg的沙子和5kg的棉花一样重，此说法正确。故答案为:√",
+        "knowledge_points":  [
+                                 "千克的认识，克，千克之间的换算与比较"
+                             ],
+        "source":  "24-25 二年级下·江西赣州·期末"
+    },
+    {
+        "id":  "82",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "2千克铁比2000克纸重得多。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】比较两个物体的重量时，先统一单位，再进行比较。1千克=1000克，因此2千克=2000克，两者重量相等。\n\n【详解】根据分析可得:2千克铁与2000克纸一样重。题目中\"重得多\"的说法错误。故答案为: ×",
+        "knowledge_points":  [
+                                 "克，千克之间的换算与比较"
+                             ],
+        "source":  "24-25二年级下·湖北黄冈·期末"
+    },
+    {
+        "id":  "83",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "用天平称量物体时，一般用千克作单位。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】根据生活经验，对质量单位和数据大小的认识可知：比较轻的物体常用天平来称，计量比较轻的物体，常用克作单位;比较重的物体常用台秤或体重秤来称，计量比较重的物体，常用千克作单位。由此解答。\n\n【详解】由分析可知：用天平称量物体时，一般用克作单位。原题说法错误。故答案为: ×",
+        "knowledge_points":  [
+                                 "克的认识，千克的认识"
+                             ],
+        "source":  "24-25 二年级下·安徽淮南·期末"
+    },
+    {
+        "id":  "84",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "一枚2分硬币约重1克,20枚这样的硬币约重10克。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】由题意可知：一枚2分硬币约重1克,10枚这样的硬币约重10克,20枚这样的硬币约重20克。据此可判断。\n\n【详解】由分析可得：一枚2分硬币约重1克,20枚这样的硬币约重20克。故答案为: ×",
+        "knowledge_points":  [
+                                 "克的认识"
+                             ],
+        "source":  "24-25 二年级下·河南郑州·期末"
+    },
+    {
+        "id":  "85",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "判断题",
+        "difficulty":  0.65,
+        "question":  "1千克棉花比1千克西瓜轻。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】根据题意，比较物体的轻重应依据质量，而题干中棉花和西瓜的质量均为1千克，因此它们的重量相等。以此判断即可。\n\n【详解】根据分析可知:1千克棉花和1千克西瓜的质量相同，因此重量相等。原题说法错误。故答案为: ×",
+        "knowledge_points":  [
+                                 "千克的认识"
+                             ],
+        "source":  "24-25 三年级下·广东汕头·期末"
+    },
+    {
+        "id":  "86",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "5kg的沙子比5kg的棉花重。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】比较物体的轻重应依据质量，和材质无关。题中沙子和棉花的质量均为5kg,因此它们的重量相等，由此解答。\n\n【详解】由分析可知:5kg的沙子和5kg的棉花的质量相同，因此一样重。原题说法错误。故答案为: ×",
+        "knowledge_points":  [
+                                 "千克的认识"
+                             ],
+        "source":  "24-25 二年级下·江西赣州·期末"
+    },
+    {
+        "id":  "87",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "妈妈买了2千克葡萄，花了多少元钱。\n![](images/6d1a6ae127a776a69f22809e96d7d9e5.png)",
+        "options":  [
+
+                    ],
+        "answer":  "36元",
+        "solution":  "【分析】1千克=1000克，也就是1千克等于2个500克,2千克=2000克，也就是2千克等于4个500克;每500克葡萄9元，每500克葡萄的价钱乘4，等于妈妈花的钱。\n\n【详解】每500克葡萄9元,2千克=2000克,2千克相当于4份500克。9×4=36(元),答：妈妈买了2千克葡萄共需36元。",
+        "knowledge_points":  [
+                                 "9的乘法口诀及应用，克的认识，千克的认识，克，千克之间的换算与比较"
+                             ],
+        "source":  "24-25 二年级下·山西阳泉·期末"
+    },
+    {
+        "id":  "88",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "想一想，要买1千克花生，可以怎样买。需要多少元。\n![](images/612811cba43a97f5ed9b2797cfdcadf1.png)",
+        "options":  [
+
+                    ],
+        "answer":  "可以买2袋300克1袋400克;28元",
+        "solution":  "【分析】根据题意可知：将1千克换成克,1千克=1000克，然后把这两种花生的克重相加是其等于1000克的，据此可直到如何怎么买，然后把买的价格相加即可求出需要多少钱。\n\n【详解】400+300=700(克),700+300=1000(克),1000克=1千克,10+9+9=19+9=28(元),答：可以买2袋300克1袋400克需要28元。",
+        "knowledge_points":  [
+                                 "整百数，几百几十数的加减法口算，克，千克之间的换算与比较"
+                             ],
+        "source":  "24-25二年级下·云南文山·期末"
+    },
+    {
+        "id":  "89",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "超市新进一批水果，价格如下:\n\n| 水果 | 苹果 | 梨 | 鲜枣 | 柿子 | 柚子 |\n| ---- | --------- | --------- | --------- | --------- | --------- |\n| 价格 | 6元/500克 | 4元/500克 | 3元/500克 | 8元/500克 | 5元/500克 |\n\n(1)买3千克柿子和1000克梨，一共要多少钱。\n(2)你能提出其他数学问题并解答吗。",
+        "options":  [
+
+                    ],
+        "answer":  "56元;买2千克苹果需要多少钱。(答案不唯一)24元",
+        "solution":  "【分析】(1)根据题意，先统一换算单位,1千克=1000克,1千克有2个500克,3千克是6个500克;用8乘6，可求出买3千克柿子的价钱，用4乘2可求出买1000克梨的价钱，再把买柿子的价钱和梨的价钱相加即可求出一共要多少钱。(2)提问题符合题意即可，答案不唯一，可提出\"买2千克苹果需要多少钱。\"2千克里有4个500克，用6乘4可求出买2千克苹果的价钱。\n\n【详解】由分析可得:(1)3千克里有6个500克,1000克有2个500克,8×6=48(元),4×2=8(元),48+8=56(元),答：一共要56元钱。(2)买2千克苹果需要多少钱。(答案不唯一)2千克里有4个500克,6×4=24(元),答：买2千克苹果需要24元钱。",
+        "knowledge_points":  [
+                                 "\"提问题\"\"填条件\"问题，克，千克之间的换算与比较"
+                             ],
+        "source":  "24-25 二年级下·福建龙岩·期末"
+    },
+    {
+        "id":  "90",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "周末，妈妈带着米琦去\"果缤纷\"购买水果，价格如右图:\n价格表\n\n| 价格表 | |\n| ------ | ---------- |\n| 杨梅 | 500克/8元 |\n| 火龙果 | 1千克/6元 |\n| 蓝莓 | 500克/12元 |\n| 杨桃 | 500克/7元 |\n\n(1)妈妈想买3千克杨桃,500克蓝莓和1500克杨梅一共要付多少钱。\n(2)米琦不喜欢吃杨桃，她想把妈妈买杨桃的钱用来买火龙果，能买多少千克。\n(3)你能提出其他数学问题并解答吗。",
+        "options":  [
+
+                    ],
+        "answer":  "78元;7千克;买5千克火龙果需要多少钱。30元(答案不唯一)",
+        "solution":  "【分析】(1)1千克=1000克=500克+500克，也就是1000克里面有2个500克，即,1千克里面有2个500克。再结合题意，先分别算出3千克杨桃多少钱和1500克杨梅多少钱，最后用加法求出3千克杨桃,500克蓝莓和1500克杨梅一共要付多少钱。(2)能买到的火龙果重量=买杨桃的钱/每千克火龙果的价钱;(3)根据已知条件提出数学问题，合理即可，答案不唯一。如：买5千克火龙果需要多少钱。用乘法列式解决。\n\n【详解】(1)1千克里面有2个500克，则3千克里面有6个500克。7×6=42(元);1000克里面有2个500克，则1500克里面有3个500克,8×3=24(元),42+12+24=78(元),答：一共要付78元。(2)42÷6=7(千克),答：能买7千克。(3)买5千克火龙果需要多少钱。6×5=30(元),答：买5千克火龙果需要30元。",
+        "knowledge_points":  [
+                                 "经济问题，\"提问题\"\"填条件\"问题,8的乘法口诀及应用，克，千克之间的换算与比较"
+                             ],
+        "source":  "24-25 二年级下·贵州铜仁·期末"
+    },
+    {
+        "id":  "91",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "超市原有大米800千克，第一天卖出200千克，第二天进货500千克，现在超市有大米多少千克。\n答：现在超市有大米( )千克。",
+        "options":  [
+
+                    ],
+        "answer":  "1100千克;1100",
+        "solution":  "【分析】用原有的大米重量减去卖出去的重量，求出差，再加上进货的重量，求出和，就是现在超市已有的大米重量。\n\n【详解】800-200=600(千克),600+500=1100(千克),答：现在超市有大米1100千克。",
+        "knowledge_points":  [
+                                 "整百数，几百几十数的加减法口算，千克的认识"
+                             ],
+        "source":  "24-25 二年级下·广东江门·期末"
+    },
+    {
+        "id":  "92",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "苹果和荔枝的价格如下表。妈妈买了1千克苹果和500克荔枝，共花了多少元。\n\n| 水果 | 价格 |\n| ---- | --------- |\n| 苹果 | 6元/500克 |\n| 荔枝 | 8元/500克 |",
+        "options":  [
+
+                    ],
+        "answer":  "20元",
+        "solution":  "【分析】1千克=1000克=500克+500克,1千克里面有2个500克，先算出妈妈买1千克苹果花了多少元，再加上500克荔枝的钱，即可求出共花了多少元。\n\n【详解】1千克=1000克=500克+500克,6×2+8=12+8=20(元),答：共花了20元。",
+        "knowledge_points":  [
+                                 "乘加，乘减混合运算，克，千克之间的换算与比较"
+                             ],
+        "source":  "24-25 二年级下·四川成都·期末"
+    },
+    {
+        "id":  "93",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "用一个杯子向一个空瓶中倒果汁。如果倒进去2杯果汁，那么连瓶共重400克;如果倒进去3杯果汁，那么连瓶共重500克。一杯果汁(不包括杯子)和一个空瓶各重多少克。",
+        "options":  [
+
+                    ],
+        "answer":  "果汁100克，空瓶200克",
+        "solution":  "【分析】根据题意，两种情况相比，多倒进1杯果汁，倒进3杯果汁比倒进2杯果汁增加了100克，这100克是多出来的1杯果汁的质量。果汁:500-400=100(克),从而可求出1杯果汁重100克,2杯果汁重200克，进而可求出一个空瓶重400-200=200(克)。\n\n【详解】由分析可得：果汁:500-400=100(克),空瓶:400-200=200(克),答：一杯果汁重100克，一个空瓶重200克。",
+        "knowledge_points":  [
+                                 "和差倍问题，整百数，几百几十数的加减法口算，克的认识"
+                             ],
+        "source":  "25-26二年级上·全国·周测"
+    },
+    {
+        "id":  "94",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "一大型水果超市上午卖了3000千克苹果，下午卖了4000千克苹果。下午比上午多卖多少千克。上午和下午共卖出多少千克。",
+        "options":  [
+
+                    ],
+        "answer":  "1000千克;7000千克",
+        "solution":  "【分析】由题意可知：把上午和下午卖出苹果的千克数相减，即是下午比上午多卖出的千克数;把上午和下午卖出苹果的千克数相加，即是上午和下午共卖出的千克数;据此解答。\n\n【详解】由分析可得:4000-3000=1000(千克),4000+3000=7000(千克),答：下午比上午多卖1000千克，上午和下午共卖出7000千克。",
+        "knowledge_points":  [
+                                 "整百数，几百几十数的加减法口算，千克的认识"
+                             ],
+        "source":  "24-25 二年级下·山东菏泽·期末"
+    },
+    {
+        "id":  "95",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "买1千克苹果和2千克香蕉，一共需要多少元。\n\n| 水果 | 价格 |\n| ---- | --------- |\n| 苹果 | 7元/500克 |\n| 西瓜 | 3元/500克 |\n| 香蕉 | 4元/500克 |",
+        "options":  [
+
+                    ],
+        "answer":  "30元",
+        "solution":  "【分析】根据题意，先计算出1千克里面有几个500克，然后和每500克苹果的钱数相乘，求出买苹果需要的钱数;计算出2千克里面有几个500克，再和每500克香蕉的钱数相乘，计算出买香蕉需要的钱数，将两部分钱数相加，就是需要的总钱数。\n\n【详解】1千克=1000克,500克+500克=1000克,1千克里面有2个500克。7×2=14(元),2千克=2000克,500克+500克+500克+500克=2000克,2千克里面有4个500克。4×4=16(元),14+16=30(元),答：一共需要30元。",
+        "knowledge_points":  [
+                                 "克，千克之间的换算与比较"
+                             ],
+        "source":  "24-25 二年级下·湖北黄冈·期末"
+    },
+    {
+        "id":  "96",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "妈妈购买4袋花生，每袋500克，妈妈一共买了多少千克花生。",
+        "options":  [
+
+                    ],
+        "answer":  "2千克",
+        "solution":  "【分析】根据题意，将每袋花生的重量相加，计算出总重量，再根据1千克=1000克换算单位即可。\n\n【详解】500+500+500+500=2000(克),2000克=2千克，答：妈妈一共买了2千克花生。",
+        "knowledge_points":  [
+                                 "整百数，几百几十数的加减法口算，克，千克之间的换算与比较"
+                             ],
+        "source":  "24-25 二年级下·安徽淮南·期末"
+    },
+    {
+        "id":  "97",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "一箱梨连箱子重2千克，卖了一半后重1100克，箱子重多少克。梨净重多少克。",
+        "options":  [
+
+                    ],
+        "answer":  "200克;1800克",
+        "solution":  "【分析】根据题意，先进行单位换算，根据1千克=1000克，把2千克换算成2000克，一箱梨连箱子的总质量减卖了一半后剩余的质量，等于卖出一半梨的质量;卖出一半梨的质量加卖出一半梨的质量，等于梨的净重;一箱梨连箱子的总质量减梨的净重量，等于箱子的质量。\n\n【详解】2千克=2000克,2000-1100=900(克),900+900=1800(克),2000-1800=200(克),答：箱子重200克，梨净重1800克。",
+        "knowledge_points":  [
+                                 "整百数，几百几十数的加减法口算，克的认识，千克的认识，克，千克之间的换算与比较"
+                             ],
+        "source":  "24-25 二年级下·浙江杭州·期末"
+    },
+    {
+        "id":  "98",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "暑假到了，小天去看望奶奶，给奶奶买了4千克水果，有苹果，菠萝，香蕉，其中菠萝重500克，香蕉重1500克，小天给奶奶买了多少千克的苹果。",
+        "options":  [
+
+                    ],
+        "answer":  "2千克",
+        "solution":  "【分析】用小天买的水果重量减去菠萝和香蕉的重量和，即是苹果的重量;计算前先根据进率1千克=1000克，统一单位后再计算;据此解答。\n\n【详解】由分析可得:500+1500=2000(克),2000克=2千克,4-2=2(千克),答：小天给奶奶买了2千克的苹果。(计算方法不唯一)",
+        "knowledge_points":  [
+                                 "整百数，几百几十数的加减法口算，克，千克之间的换算与比较"
+                             ],
+        "source":  "24-25二年级下·山东济宁·期末"
+    },
+    {
+        "id":  "99",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "下表为长江码头某超市部分零食的价格表.\n\n| 名称 | 小鱼干 | 小虾干 | 海苔卷 |\n| ---- | -------- | -------- | -------- |\n| 价格 | 9元/500g | 8元/500g | 4元/500g |\n\n丽丽买了2千克小鱼干和1千克海苔卷，一共花了多少元。",
+        "options":  [
+
+                    ],
+        "answer":  "44元",
+        "solution":  "【分析】2千克=2000克,2000克里面有4个500克;1千克=1000克,1000克里面有2个500克。丽丽买了2千克小鱼干和1千克海苔卷，每500克小鱼干的钱数乘4，等于买2千克小鱼干花了多少钱;每500克海苔卷的钱数乘2，等于买1千克海苔卷的钱数，把2千克小鱼干和1千克海苔卷的钱数相加，等于一共花了多少元。\n\n【详解】2千克=2000克,2000克里面有4个500克;9×4=36(元),1千克=1000克,1000克里面有2个500克;4×2=8(元),36+8=44(元),答：一共花了44元。",
+        "knowledge_points":  [
+                                 "一位数与两位数的进位加法,4的乘法口诀及应用,9的乘法口诀及应用，克，千克之间的换算与比较"
+                             ],
+        "source":  "24-25 二年级下·浙江台州·期末"
+    },
+    {
+        "id":  "100",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "有两块蔬菜地，今年分别收白菜2100千克和青菜3200千克。一块西瓜地，今年收西瓜5500千克.\n(1)两块菜地一共收了多少千克蔬菜。\n(2)西瓜比蔬菜多收多少千克。\n(3)你还能提出数学问题并解答吗。",
+        "options":  [
+
+                    ],
+        "answer":  "5300千克;200千克;白菜比青菜少收多少千克。(答案不唯一)1100千克",
+        "solution":  "【分析】由题意可知:(1)把两块菜地的白菜和青菜的千克数相加，即是一共收的蔬菜的千克数;(2)用西瓜重量减去蔬菜重量，即是西瓜比蔬菜多收的千克数;(3)可以提减法的问题，比如：白菜比青菜少收多少千克。用青菜的重量减去白菜的重量即可;据此解答。\n\n【详解】由分析可得:(1)2100+3200=5300(千克),答：两块菜地一共收了5300千克蔬菜。(2)5500-5300=200(千克),答：西瓜比蔬菜多收200千克。(3)问题：白菜比青菜少收多少千克。(答案不唯一)3200-2100=1100(千克),答：白菜比青菜少收1100千克。",
+        "knowledge_points":  [
+                                 "\"提问题\"\"填条件\"问题，谁比谁多/少几的问题，整百数，几百几十数的加减法口算，千克的认识"
+                             ],
+        "source":  "24-25 二年级下·贵州黔东南·期末"
+    },
+    {
+        "id":  "101",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "6千克棉花和6000克铁比较,( )。",
+        "options":  [
+                        "A. 棉花重",
+                        "B. 铁重",
+                        "C. 一样重"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】比较物体的重量时，需先将单位统一(1千克=1000克)。将6千克转换为克后与6000克进行比较，即可得出答案。\n\n【详解】6千克=6000克，即,6千克的棉花重量也就是6000克。因此,6千克棉花和6000克铁比较，一样重。故答案为:C",
+        "knowledge_points":  [
+                                 "克，千克之间的换算与比较"
+                             ],
+        "source":  "24-25二年级下·广东汕头·期末"
+    },
+    {
+        "id":  "102",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "一只小猫大约重( )。",
+        "options":  [
+                        "A. 3千克",
+                        "B. 30千克",
+                        "C. 3克"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】计量比较轻的物体，常用克作单位,2个曲别针约重1克;计量比较重的物体，常用千克作单位,2小袋食盐重1千克;注意联系生活实际，计量单位和数据的大小逐项分析各个选项，找出正确答案，即可解答。\n\n【详解】A。3千克：合理。一只健康的小猫重量通常在1至3千克左右，成年猫重约4至5千克。B。30千克：不合理。30千克相当于6至7岁儿童的体重，而小猫是小型动物，不可能这么重。C。3克：不合理。3克非常轻，大约等于3枚硬币的重量，小猫的体重远大于3克。一只小猫大约重3千克。故答案为:A",
+        "knowledge_points":  [
+                                 "克的认识，千克的认识，质量的估计"
+                             ],
+        "source":  "24-25二年级下·广东江门·期末"
+    },
+    {
+        "id":  "103",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "9000克比10千克( )。",
+        "options":  [
+                        "A. 多1千克",
+                        "B. 少1千克",
+                        "C. 多8990克"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】比较9000克与10千克的大小，需统一单位后计算差值;1千克=1000克。\n\n【详解】1000克=1千克，故,9000克=9千克;10-9=1(千克),即,9000克比10千克(少1千克)。故答案为:B",
+        "knowledge_points":  [
+                                 "克，千克之间的换算与比较"
+                             ],
+        "source":  "24-25 二年级下·广西玉林·期末"
+    },
+    {
+        "id":  "104",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "一只猫重5千克，一盘鸡蛋重2000克，一只猫比一盘鸡蛋重( )克。",
+        "options":  [
+                        "A. 3",
+                        "B. 300",
+                        "C. 3000"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】根据1千克=1000克，统一单位，再用一只猫的重量减去一盘鸡蛋的重量，即可求出一只猫比一盘鸡蛋重多少克。\n\n【详解】1千克=1000克,5千克=5000克,5000-2000=3000(克),一只猫比一盘鸡蛋重3000克。故答案为:C",
+        "knowledge_points":  [
+                                 "克，千克之间的换算与比较，整百数，几百几十数的加减法口算"
+                             ],
+        "source":  "24-25 二年级下·陕西渭南·期末"
+    },
+    {
+        "id":  "105",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "下面的说法中，正确的是( )。",
+        "options":  [
+                        "A. 999比最小的四位数小10",
+                        "B. 1袋1千克的瓜子和2袋500克的糖一样重",
+                        "C. 230和350两个数中的\"3\"表示的意义相同"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】根据比较数的大小，先看位数的多少，位数多的数就大;如果位数相同，从最高位开始比较，最高位上的数大则这个数大，最高位上的数相同，就比较下一位，依次类推，可知最小的四位数为1000，计算其和999之间的差距即可;利用加法，算出两袋糖的总重量为1000克，再结合1千克=1000克，用一袋瓜子的总重量和两袋糖的总重量进行对比即可;根据百位上是几就有几个百，十位上是几就有几个十，个位上是几就有几个一即可解答。\n\n【详解】A。1000和999相差1，则选项错误;B。2袋糖总重量为1000克,1袋瓜子和2袋糖的重量都是1千克，则选项正确;C。230中十位上是3，代表有3个十,350中百位上是3，代表有3个百，两者的意义不同，则选项错误。故答案为:B",
+        "knowledge_points":  [
+                                 "克，千克之间的换算与比较，万以内数的大小比较,1000以内数的组成"
+                             ],
+        "source":  "24-25二年级下·河北唐山·期末"
+    },
+    {
+        "id":  "106",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "下面正确的是( )。",
+        "options":  [
+                        "A. 235克\u003e253克",
+                        "B. 2米\u003e9分米",
+                        "C. 5时\u003c50分"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】比较数的大小，先看位数的多少，位数多的数就大;如果位数相同，从最高位开始比较，最高位上的数大则这个数大，最高位上的数相同，就比较下一位，依次类推。单位不同的，根据1米=10分米,1时=60分进行单位换算，统一单位后在进行比较大小即可解答。\n\n【详解】A。235和253的百位上相同，十位上3\u003c5，所以235\u003c253，则235克\u003c253克，选项错误;B。2米=20分米,20和9前者的位数更多，所以20\u003e9，则2米\u003e9分米，选项正确;C。5时=300分,300和50前者的位数更多，所以300\u003e50，则5时\u003e50分，选项错误。故答案为:B",
+        "knowledge_points":  [
+                                 "毫米，厘米，分米，米之间的进率与换算，时，分的认识及换算,1000以内数的比大小"
+                             ],
+        "source":  "24-25 二年级下·河北唐山·期末"
+    },
+    {
+        "id":  "107",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "比1克轻的物体有( )。",
+        "options":  [
+                        "A. 一根头发",
+                        "B. 一个鸡蛋",
+                        "C. 一部手机"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】计量比较轻的物体的重量，一般用\"克\"作单位。生活中，一个2分的硬币约重1克，根据生活经验，用各选项的物体和一个2分硬币作比较，找出比1克轻的物体即可。\n\n【详解】A。一根头发比一个2分硬币轻很多，所以一根头发比1克轻，符合题意;B。一个鸡蛋比一个2分硬币重很多，所以一个鸡蛋比1克重，不符合题意;C。一部手机比一个2分硬币重很多，所以一部手机比1克重，不符合题意。故答案为:A",
+        "knowledge_points":  [
+                                 "克的认识"
+                             ],
+        "source":  "24-25 二年级下·广东佛山·期末"
+    },
+    {
+        "id":  "108",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "下面说法错误的是( )。",
+        "options":  [
+                        "A. 然然的体重大约是50克。",
+                        "B. 2000克羽毛和2千克铁一样重。",
+                        "C. 一粒花生米约重1克。"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】根据质量单位的实际应用对选项进行分析，需要进行单位换算的先进行换算。\n\n【详解】A。然然的体重大约是50克，根据常识，一包食盐的重量是500克，人的体重应以千克为单位，说法错误;B。2000克羽毛和2千克铁一样重,2000克=2千克，质量相等，因此一样重，说法正确;C。一粒花生米约重1克，花生米重量较轻,1克符合实际，说法正确。故答案为:A",
+        "knowledge_points":  [
+                                 "克的认识，千克的认识，克，千克之间的换算与比较"
+                             ],
+        "source":  "24-25二年级下·河南三门峡·期末"
+    },
+    {
+        "id":  "109",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "称10粒黄豆的质量一般用( )。",
+        "options":  [
+                        "A. ![](images/31169544fc8aec46b63d4850eaa869219097506880c11dc4926d960a09fa71ef.jpg)",
+                        "B. ![](images/a46d8fb22b3c70384ffb629cf73ceb5144427518d8d390d311361aa8986be456.jpg)",
+                        "C. ![](images/3179ece100649f415f72698cfc890df22c250c24ff6ad16604686951d22896d6.jpg)"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】根据生活经验，对质量单位和数据大小的认识可知：计量比较轻的物体，常用克作单位,2个曲别针约重1克,10粒黄豆的质量较轻，一般用克作单位，由此选择合适的答案即可。\n\n【详解】A。弹簧秤常用来称比较重的物品，称用\"千克\"作单位的物品多一些，不符合题意。B。天平秤常用来称比较轻的物品，称用\"克\"作单位的物品多一些，符合题意;C。磅秤常用来称比较重的物品，称用\"千克\"作单位的物品多一些，不符合题意。则称10粒黄豆的质量一般用B。故答案为:B",
+        "knowledge_points":  [
+                                 "千克的认识，克的认识"
+                             ],
+        "source":  "24-25 二年级下·湖北武汉·期末"
+    },
+    {
+        "id":  "110",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "一盒巧克力重250克,4盒这样的巧克力重( )。",
+        "options":  [
+                        "A. 100克",
+                        "B. 1千克",
+                        "C. 10千克"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】一盒巧克力重250克,4盒这样的巧克力也就是4个250克相加，然后根据1000克=1千克换算单位，得出结论即可。\n\n【详解】250+250+250+250=500+250+250=750+250=1000(克),1000克=1千克，即一盒巧克力重250克,4盒这样的巧克力重1千克。故答案为:B",
+        "knowledge_points":  [
+                                 "克，千克之间的换算与比较"
+                             ],
+        "source":  "24-25 二年级下·山东济宁·期末"
+    },
+    {
+        "id":  "111",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "下面物品中，质量最接近1克的是( )。",
+        "options":  [
+                        "A. 1个鸡蛋",
+                        "B. 1粒花生米",
+                        "C. 1块橡皮",
+                        "D. 1包盐"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】根据生活经验，对质量单位和数据大小的认识可知：计量比较轻的物体，常用克作单位,2个曲别针约重1克，由此选择即可。\n\n【详解】A。1个鸡蛋：普通鸡蛋质量约为50克，远大于1克;答案不正确。B。1粒花生米：单粒花生米与2个曲别针质量差不多，接近1克;答案正确。C。1块橡皮：普通橡皮质量约为10克，明显大于1克;答案不正确。D。1包盐：家庭用盐通常为500克，远大于1克;答案不正确。故答案为:B",
+        "knowledge_points":  [
+                                 "克的认识"
+                             ],
+        "source":  "24-25 二年级下·浙江绍兴·期末"
+    },
+    {
+        "id":  "112",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "1000克石头和1千克棉花比较,( )。",
+        "options":  [
+                        "A. 一样重",
+                        "B. 石头重",
+                        "C. 棉花重"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】比较物体之间的轻重，与物体本身的材质无关，与本身的重量有关;根据1千克=1000克，将单位统一后，比较大小即可。\n\n【详解】1千克=1000克,1000克=1000克，所以1000克石头和1千克棉花比较，一样重。故答案为:A",
+        "knowledge_points":  [
+                                 "克，千克之间的换算与比较"
+                             ],
+        "source":  "24-25 二年级下·湖北襄阳·期末"
+    },
+    {
+        "id":  "113",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "1000克棉花和1千克铁相比较，下列说法正确的是( )。",
+        "options":  [
+                        "A. 棉花更重",
+                        "B. 铁更重",
+                        "C. 两者同样重"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】根据1千克=1000克，将单位换算统一，再比较大小，数大的则重，数小的则轻。\n\n【详解】1千克=1000克,1000克=1000克;则1000克棉花和1千克铁同样重。故答案为:C",
+        "knowledge_points":  [
+                                 "克，千克之间的换算与比较"
+                             ],
+        "source":  "24-25 二年级下·浙江温州·期末"
+    },
+    {
+        "id":  "114",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "下面说法错误的是( )。",
+        "options":  [
+                        "A. 比最大的三位数多1的是1000",
+                        "B. 在算盘上，一颗下珠表示5，一颗上珠表示1",
+                        "C. 2千克棉花和2千克铁一样重"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】由题意可知：逐项分析下面各项，找出错误的说法即可。(1)最大的三位数是999,999+1=1000，比最大的三位数多1的是1000。(2)在算盘上，一颗下珠表示1，一颗上珠表示5。(3)棉花和铁的重量相等，都重2千克。\n\n【详解】由分析可得:A。比最大的三位数多1的是1000：最大的三位数是999,999+1=1000，说法正确;B。在算盘上，一颗下珠表示5，一颗上珠表示1：在算盘上，一颗下珠表示1，一颗上珠表示5，说法错误;C。2千克棉花和2千克铁一样重：无论是什么物品只要是2千克都是一样重的，说法正确;故答案为:B",
+        "knowledge_points":  [
+                                 "千克的认识，数万以内的数，算盘的认识与使用"
+                             ],
+        "source":  "24-25 二年级下·福建福州·期末"
+    },
+    {
+        "id":  "115",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "一个小菠萝重208克,( )个这样的小菠萝大约重1千克。",
+        "options":  [
+                        "A. 6",
+                        "B. 5",
+                        "C. 4",
+                        "D. 3"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】根据题意，将每个小菠萝的重量看成与之接近的整百数，再相加直到结果为1千克，可得出小菠萝的数量。根据1千克=1000克统一单位。\n\n【详解】1千克=1000克;208接近200;200+200+200+200+200=1000(克);则一个小菠萝重208克,5个这样的小菠萝大约重1千克。故答案为:B",
+        "knowledge_points":  [
+                                 "克，千克之间的换算与比较,1000以内数的估计"
+                             ],
+        "source":  "23-24二年级下·广东东莞·期末"
+    },
+    {
+        "id":  "116",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "比较1千克的铁和1000克的棉花,( )。",
+        "options":  [
+                        "A. 1000克的棉花重",
+                        "B. 1千克的铁重",
+                        "C. 两者一样重"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】根据1千克=1000克先进行单位换算，再进行比较即可。\n\n【详解】1千克=1000克，所以1千克的铁和1000克的棉花一样重。故答案为:C",
+        "knowledge_points":  [
+                                 "克，千克之间的换算与比较"
+                             ],
+        "source":  "24-25 二年级下·浙江温州·期末"
+    },
+    {
+        "id":  "117",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "如果4个大小差不多的梨共重1000克，妈妈买了12个这样的梨，这些梨大约重( )千克。",
+        "options":  [
+                        "A. 12",
+                        "B. 3000",
+                        "C. 3"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】用12除以4求出12里面有几个4，有几个4大约就有几个1000克，据此计算。1000克=1千克，最后换算成千克作单位。\n\n【详解】12÷4=3(份),1000+1000+1000=3000(克),3000克=3千克，这些梨大约重3千克。故答案为:C",
+        "knowledge_points":  [
+                                 "克，千克之间的换算与比较，用2~5的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·浙江嘉兴·期末"
+    },
+    {
+        "id":  "118",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "一袋安溪铁观音重500克,4袋安溪铁观音重( )千克。",
+        "options":  [
+                        "A. 2",
+                        "B. 20",
+                        "C. 2000"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】由题意可知：把4袋铁观音的重量相加，算出的和再变单位为千克，即可算出4袋安溪铁观音的重量;据此解答。\n\n【详解】500+500+500+500=2000(克),2000克=2千克,4袋安溪铁观音重2千克。故答案为:A",
+        "knowledge_points":  [
+                                 "整百数，几百几十数的加减法口算，克，千克之间的换算与比较"
+                             ],
+        "source":  "24-25 二年级下·福建福州·期末"
+    },
+    {
+        "id":  "119",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "在括号中填上合适的质量单位.\n(1)一个鸡蛋约重50( )。 (2)一个西瓜约重4( )。 (3)小明的体重约重30( )。 (4)一枚一元硬币约重6( )。",
+        "options":  [
+
+                    ],
+        "answer":  "克或g;千克或kg 千克或kg 克或g",
+        "solution":  "【分析】根据生活经验和实际数据相结合可知:1克大约为一枚硬币的重量，计量一个鸡蛋的重量，硬币的重量用\"克\"作单位比较合适。1千克大约为两瓶矿泉水的重量，计量一个西瓜的重量，小明的体重用\"千克\"作单位比较合适。\n\n【详解】(1)一个鸡蛋约重50(克)。(2)一个西瓜约重4(千克)。(3)小明的体重约重30(千克)。(4)一枚一元硬币约重6(克)。",
+        "knowledge_points":  [
+                                 "克的认识，千克的认识，质量单位的选择"
+                             ],
+        "source":  "24-25 二年级下·辽宁鞍山·期末"
+    },
+    {
+        "id":  "120",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "在横线上填上合适的数或单位.\n5000克=( )千克 8千克=( )克 2000克+400千克=( )千克\n5千克-300克=( )克 小明身高130( ),体重30( )\n一个鸡蛋约重50( ) 一头猪重约150( )",
+        "options":  [
+
+                    ],
+        "answer":  "5;8000;402;4700;厘米或cm;千克或kg;克或g;千克或kg",
+        "solution":  "【分析】1千克=1000克，据此换算单位后再相加减;根据生活经验，对长度单位，质量单位和数据大小的认识来解决此题。食指宽大约是1厘米，所以，小明身高用\"厘米\"作单位比较合适。表示较重的物体时，一般用\"千克\"作单位;表示较轻的物体时，一般用\"克\"作单位;小明的体重及一头猪重属于比较重的，故，表示小明的体重及一头猪重用\"千克\"作单位比较合适;一个鸡蛋的重量属于比较轻的，故，表示一个鸡蛋的重量用\"克\"作单位比较合适。\n\n【详解】1000克=1千克，故,5000克=5千克;1千克=1000克，故,8千克=8000克;2000克+400千克=2千克+400千克=402千克;5千克-300克=5000克-300克=4700克;小明身高130厘米，体重30千克;一个鸡蛋约重50克;一头猪约重150千克。",
+        "knowledge_points":  [
+                                 "克，千克之间的换算与比较，质量单位的选择，长度单位的选择"
+                             ],
+        "source":  "24-25二年级下·浙江台州·期末"
+    },
+    {
+        "id":  "121",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "在括号里填上\"\u003e\"\"\u003c\"或\"=\".\n6000克( )6千克 400+600( )10000\n1500-700( )22007050克( )7500克\n360+30( )390300+400( )70",
+        "options":  [
+
+                    ],
+        "answer":  "=;\u003c;\u003c;\u003c;=;\u003e",
+        "solution":  "【分析】万以内数比较大小的方法：比较数的大小，先看位数的多少，位数多的数就大;如果位数相同，从最高位开始比较，最高位上的数大则这个数大，最高位上的数相同，就比较下一位，依次类推。含有算式的大小比较，可以先计算出每个算式的结果，再比较大小;单位不同的可以根据1千克=1000克，统一单位后再比较大小，即可解答。\n\n【详解】6000克=6千克,6千克和6千克相等，所以6000克=6千克;400+600=1000,1000和10000前者的位数更少，则1000\u003c10000，所以400+600\u003c10000;1500-700=800,800和2200前者的位数更少，则800\u003c2200，所以1500-700\u003c2200;7050和7500的千位上相同，百位上0\u003c5，所以7050克\u003c7500克;360+30=390,390和390相等，所以360+30=390;300+400=700,700和70前者的位数更多，则700\u003e70，所以300+400\u003e70。",
+        "knowledge_points":  [
+                                 "万以内数的大小比较，整百数，几百几十数的加减法口算，克，千克之间的换算与比较"
+                             ],
+        "source":  "24-25 二年级下·广东汕头·期末"
+    },
+    {
+        "id":  "122",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "在括号里填上\"\u003e\"\"\u003c\"或\"=\".\n1890( )19805千克40克( )540克 1万( )10个1千",
+        "options":  [
+
+                    ],
+        "answer":  "\u003c;\u003e;=",
+        "solution":  "【分析】整数比较大小方法:①位数多的数大于位数少的数;②位数相同的，先比较最高位上的数，最高位上大的，数就大，最高位数相同的，就比较下一位，以此类推。第1题：根据整数比较大小的方法直接比较大小;第2题：根据1千克=1000克，单位变换统一后再根据整数比较大小的方法比较大小;第3题:1万即10000;1个1千是1千,2个1千是2千。10个1千是10000。\n\n【详解】两数均为四位数，千位均为1，百位上8\u003c9，故1890\u003c1980;5千克=5000克,5千克40克=5000克+40克=5040克,5040克\u003e540克，故5千克40克\u003e540克;1万=10000;10个1千=10000,10000=10000，故1万=10个1千。",
+        "knowledge_points":  [
+                                 "万以内数的组成，万以内数的大小比较，克，千克之间的换算与比较"
+                             ],
+        "source":  "24-25二年级下·福建漳州·期末"
+    },
+    {
+        "id":  "123",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在( )里填上合适的质量单位.\n小明是一名小学生，他的体重是32( ),每天他都会喝一袋重250( )的牛奶。",
+        "options":  [
+
+                    ],
+        "answer":  "千克或kg;克或g",
+        "solution":  "【分析】根据情景选择合适的计量单位，要注意联系生活实际，计量单位和数据的大小，灵活的选择。1克大约为一枚硬币的重量，计量一袋牛奶的重量用\"克\"作单位比较合适。1千克大约为两瓶矿泉水的重量，计量小明的体重用\"千克\"作单位比较合适。\n\n【详解】小明是一名小学生，他的体重是32(千克),每天他都会喝一袋重250(克)的牛奶。",
+        "knowledge_points":  [
+                                 "克的认识，千克的认识，质量单位的选择"
+                             ],
+        "source":  "24-25 二年级下·内蒙古呼伦贝尔·期末"
+    },
+    {
+        "id":  "124",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "8000克=( )千克 7千克=( )克",
+        "options":  [
+
+                    ],
+        "answer":  "8;7000",
+        "solution":  "【分析】常见的质量单位有克，千克,1千克=1000克;把用千克作单位的数换算成用克作单位就是在数字后面加上3个0，并且把单位改写成克;把用克作单位的数换算成用千克作单位就是去掉数字后面的3个0，并且把单位改写成千克。\n\n【详解】8000克=8千克;7千克=7000克。",
+        "knowledge_points":  [
+                                 "克，千克之间的换算与比较"
+                             ],
+        "source":  "24-25 二年级下·云南昭通·期末"
+    },
+    {
+        "id":  "125",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在( )里填上合适的单位名称.\n一个苹果约重150( )。 小明的体重是32( )。 一袋洗衣粉重500( )。 一袋大米重10( )。",
+        "options":  [
+
+                    ],
+        "answer":  "克或g;千克或kg;克或g;千克或kg",
+        "solution":  "【分析】计量比较轻的物体重量用\"克\"作单位，如一粒花生米重量大约是1克。计量比较重的物体重量用\"千克\"作单位，如2袋食盐重量是1千克。\n\n【详解】一个苹果比较轻，用\"克\"作单位比较合适，因此一个苹果约重150(克)。小明的体重比较重，用\"千克\"作单位比较合适，因此小明的体重是32(千克)。一袋洗衣粉比较轻，用\"克\"作单位比较合适，因此一袋洗衣粉重500(克)。一袋大米比较重，用\"千克\"作单位比较合适，因此一袋大米重10(千克)。",
+        "knowledge_points":  [
+                                 "质量单位的选择"
+                             ],
+        "source":  "24-25 二年级下·黑龙江佳木斯·期末"
+    },
+    {
+        "id":  "126",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在( )里填\"\u003e\"\"\u003c\"或\"=\".\n4千克( )4400克 25-20( )25÷51001( )10109/3( )36÷6",
+        "options":  [
+
+                    ],
+        "answer":  "\u003c;=;\u003c;\u003c",
+        "solution":  "【分析】先统一单位或先计算出结果，然后比较大小即可。整数比较大小的方法，位数多的数大于位数少的数;位数相同的数，从最高位比起，最高位上大的数就大，最高位上相同的，就比较下一位，以此类推。\n\n【详解】4千克=4000克，故,4000克\u003c4400克;25-20=5,25÷5=5，故,25-20=25÷5;千位和百位相同(1和0),十位0\u003c1，故1001\u003c1010;9÷3=3,36÷6=6，故,9÷3\u003c36÷6。",
+        "knowledge_points":  [
+                                 "克，千克之间的换算与比较，用6的乘法口诀求商，用2~5的乘法口诀求商，万以内数的大小比较"
+                             ],
+        "source":  "24-25二年级下·湖南长沙·期末"
+    },
+    {
+        "id":  "127",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "在( )里填上合适的单位.\n一支铅笔重10( ) 小明体重是28( ) 一条鱼重2000( )",
+        "options":  [
+
+                    ],
+        "answer":  "克或g;千克或kg;克或g",
+        "solution":  "【分析】根据生活经验和对质量单位认识可知，一枚回形针重量大约是1克，两瓶矿泉水重量大约是1千克。\n\n【详解】一枚回形针重量大约是1克，所以计量铅笔的重量用\"克\"作单位比较合适，则一支铅笔重约10克;两瓶矿泉水重量大约是1千克，所以计量小明的重量用\"千克\"作单位比较合适，则小明的体重是28千克;一枚回形针重量大约是1克，所以计量鱼的重量用\"克\"作单位比较合适，则一条鱼重2000克。",
+        "knowledge_points":  [
+                                 "质量单位的选择"
+                             ],
+        "source":  "24-25二年级下·湖南长沙·期末"
+    },
+    {
+        "id":  "128",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在( )里填上合适的质量单位.\n1支冰淇淋约重100( ) 小明的体重是35( )\n1袋方便面重108( ) 一袋大米重50( )",
+        "options":  [
+
+                    ],
+        "answer":  "克或g;千克或kg;克或g;千克或kg",
+        "solution":  "【分析】根据情景选择合适的计量单位，要注意联系生活实际，计量单位和数据的大小，灵活的选择。1克大约为一枚硬币的重量，计量一支冰淇淋，方便面的重量用\"克\"作单位比较合适。1千克大约为两瓶矿泉水的重量，计量小明的体重，一袋大米的重量用\"千克\"作单位比较合适。\n\n【详解】1支冰淇淋约重100(克);小明的体重是35(千克);1袋方便面重108(克);一袋大米重50(千克)。",
+        "knowledge_points":  [
+                                 "质量单位的选择，千克的认识，克的认识"
+                             ],
+        "source":  "24-25二年级下·河北张家口·期末"
+    },
+    {
+        "id":  "129",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在括号里填上合适的单位.\n我是小亮，现在读二年级，身体健康，身高135( ),体重30( )。我喜欢吃水果，每天吃一个约重150( )的苹果，我的书包有点重，约4( ),但我还是很喜欢上学。",
+        "options":  [
+
+                    ],
+        "answer":  "厘米或cm;千克或kg;克或g;千克或kg",
+        "solution":  "【分析】根据对生活经验，长度单位，重量单位和数据大小的认识可知;1厘米大约是食指的宽度，所以计量小亮的身高用\"厘米\"作单位比较合适;1枚1分的硬币约重1克，所以，要计量一个苹果的重量用\"克\"作单位比较合适;1瓶矿泉水大约重500克,2瓶矿泉水大约重1千克，所以小亮的体重和书包的重量用\"千克\"作单位比较合适。\n\n【详解】根据分析可得：我是小亮，现在读二年级，身体健康，身高135厘米，体重30千克。我喜欢吃水果，每天吃一个约重150克的苹果，我的书包有点重，约4千克，但我还是很喜欢上学。",
+        "knowledge_points":  [
+                                 "长度单位的选择，质量单位的选择，千克的认识，克的认识"
+                             ],
+        "source":  "24-25 二年级下·湖南株洲·期末"
+    },
+    {
+        "id":  "130",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在括号里填上\"\u003e\"\"\u003c\"或\"=\".\n875( )78581÷9/9( )7×6-411千克50克( )150克\n1011( )110154-45( )19+21900+2100( )7000-6000",
+        "options":  [
+
+                    ],
+        "answer":  "\u003e;=;\u003e;\u003c;\u003c;\u003e",
+        "solution":  "【分析】比较数的大小需根据位数，单位转换及运算结果进行判断。整数比较大小的方法，位数多的数大于位数少的数;位数相同的数，从最高位比起，最高位上大的数就大，最高位相同的，就比较下一位，以此类推。1千克=1000克。\n\n【详解】比较百位:8\u003e7，故875\u003e785.81÷9/9=9÷9=1,7×6-41=42-41=1，故81÷9/9=7×6-41.1千克=1000克,1千克50克=1000克+50克=1050克，故1千克50克\u003e150克。比较百位:0\u003c1，故1011\u003c1101.54-45=9,19+21=40，故54-45\u003c19+21.900+2100=3000,7000-6000=1000，故900+2100\u003e7000-6000。",
+        "knowledge_points":  [
+                                 "克，千克之间的换算与比较，表内连乘，连除运算，整百数，几百几十数的加减法口算，万以内数的大小比较"
+                             ],
+        "source":  "24-25 二年级下·广西玉林·期末"
+    },
+    {
+        "id":  "131",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在括号里填上\"克\"或\"千克\".\n一根玉米约重300( )。 小丽的体重约是27( )。 一个西瓜约重3( )。 一个冰激凌重150( )。",
+        "options":  [
+
+                    ],
+        "answer":  "克;千克;千克;克",
+        "solution":  "【分析】根据生活实际，较轻物品用\"克\"，较重物品用\"千克\"。玉米和冰激凌较轻，用\"克\";人的体重和西瓜较重，用\"千克\"。\n\n【详解】由题意分析得：一根玉米约重300克。小丽的体重约是27千克。一个西瓜约重3千克。一个冰激凌重150克。",
+        "knowledge_points":  [
+                                 "质量单位的选择，千克的认识，克的认识"
+                             ],
+        "source":  "24-25 二年级下·广西玉林·期末"
+    },
+    {
+        "id":  "132",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "( )填写合适的单位.\n1头小牛约重40( ) 一支圆珠笔重约10( )\n欢欢体重28( ),身高128( )。",
+        "options":  [
+
+                    ],
+        "answer":  "千克或kg;克或g;千克或kg;厘米或cm",
+        "solution":  "【分析】根据生活经验，对长度单位，质量单位和数据大小的认识可知：计量比较重的物体，常用千克作单位,2袋白砂糖约重1千克，所以计量小牛的重量用千克作单位比较合适，计量欢欢的体重用千克作单位比较合适;计量比较轻的物体，常用克作单位,2个曲别针约重1克，所以计量一支圆珠笔的重量用克作单位比较合适;计量比较短的物体的长度，通常用厘米作单位，食指的宽大约是1厘米，所以计量欢欢的身高用厘米作单位比较合适。\n\n【详解】1头小牛约重40千克(kg);一支圆珠笔重约10克(g);欢欢体重28千克(kg),身高128厘米(cm)。",
+        "knowledge_points":  [
+                                 "质量单位的选择，长度单位的选择"
+                             ],
+        "source":  "24-25二年级下·内蒙古通辽·期末"
+    },
+    {
+        "id":  "133",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "一个桃子大约重200克,( )个这样的桃子大约重1千克。",
+        "options":  [
+
+                    ],
+        "answer":  "5",
+        "solution":  "【分析】1千克=1000克，因此1000克里面有几个200克，就有多少个这样的桃子大约重1千克。\n\n【详解】200+200+200+200+200=1000(克),1000克=1千克，则一个桃子大约重200克,5个这样的桃子大约重1千克。",
+        "knowledge_points":  [
+                                 "克，千克之间的换算与比较，整百数，几百几十数的加减法口算"
+                             ],
+        "source":  "17-18 三年级上·全国·月考"
+    },
+    {
+        "id":  "134",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "在括号里填上\"\u003e\"\"\u003c\"或\"=\".\n1001( )984123( )658752( )725\n5千克( )5000克 790克( )7千克 4千克( )3000克",
+        "options":  [
+
+                    ],
+        "answer":  "\u003e;\u003c;\u003e;=;\u003c;\u003e",
+        "solution":  "【分析】比较整数时，先看位数，位数多的数大;位数相同则从最高位开始逐位比较。单位不同的先统一单位再比较,1千克=1000克。\n\n【详解】1001\u003e984;123\u003c658;752\u003e725;1千克=1000克，故,5千克=5000克;7千克=7000克，故,790克\u003c7千克;4千克=4000克，故,4千克\u003e3000克。",
+        "knowledge_points":  [
+                                 "克，千克之间的换算与比较，万以内数的大小比较"
+                             ],
+        "source":  "24-25二年级下·陕西延安·期末"
+    },
+    {
+        "id":  "135",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "小月每天喝一盒250( )的牛奶，吃300( )的蔬菜，他现在的体重是30( ),身体棒棒，一次能提起一桶5( )的菜籽油。",
+        "options":  [
+
+                    ],
+        "answer":  "克或g;克或g;千克或kg;千克或kg",
+        "solution":  "【分析】根据生活常识和常用单位认识可知，一枚回形针重量大约是1克，两瓶矿泉水重量大约是1千克，由此进行判断即可解答。\n\n【详解】牛奶的重量应该用克作为单位更合适，更贴合生活实际，所以一盒牛奶为250克;蔬菜的重量应该用克作为单位更合适，更贴合生活实际，所以一天吃的蔬菜应为300克;小明的体重应该用千克作为单位更合适，更贴合生活实际，所以小明的体重应为30千克;菜籽油的重量应该用千克作为单位更合适，更贴合生活实际，所以一桶菜籽油的重量为5千克。则，小月每天喝一盒250克的牛奶，吃300克的蔬菜，他现在的体重是30千克，身体棒棒，一次能提起一桶5千克的菜籽油。",
+        "knowledge_points":  [
+                                 "质量单位的选择"
+                             ],
+        "source":  "24-25 二年级下·贵州铜仁·期末"
+    },
+    {
+        "id":  "136",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "一袋方便面重110( ),明明的体重是28( )。(填\"克\"或\"千克\")",
+        "options":  [
+
+                    ],
+        "answer":  "克;千克",
+        "solution":  "【分析】根据生活常识和对不同重量单位的认识来选择合适的单位。计量比较轻的物体，常用\"克\"作单位，计量比较重的物体，常用\"千克\"作单位。2个曲别针约重1克，所以计量一袋方便面重用\"克\"作单位比较合适;2小袋食盐重1千克，所以计量明明的体重用\"千克\"作单位比较合适;据此可解。\n\n【详解】由分析可得：一袋方便面重110克，明明的体重是28千克。",
+        "knowledge_points":  [
+                                 "克的认识，千克的认识，质量单位的选择"
+                             ],
+        "source":  "24-25 二年级下·陕西延安·期末"
+    },
+    {
+        "id":  "137",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在括号填上\"\u003e\"\"\u003c\"或\"=\".\n3千克( )2000克 1千克+500克( )2千克\n800克( )1千克 2千克-800克( )1500克",
+        "options":  [
+
+                    ],
+        "answer":  "\u003e;\u003c;\u003c;\u003c",
+        "solution":  "【分析】根据1千克=1000克，把千克变成克，统一单位后再比较。\n\n【详解】1千克=1000克,3千克=3000克，故:3千克\u003e2000克;1千克=1000克,2千克=2000克,1千克+500克=1000克+500克=1500克,1500克\u003c2000克，故:1千克+500克\u003c2千克;1千克=1000克,800克\u003c1000克，故:800克\u003c1千克;1千克=1000克,2千克=2000克,2千克-800克=2000克-800克=1200克,1200克\u003c1500克，故:2千克-800克\u003c1500克。",
+        "knowledge_points":  [
+                                 "克，千克之间的换算与比较"
+                             ],
+        "source":  "24-25 二年级下·贵州铜仁·期末"
+    },
+    {
+        "id":  "138",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "8个鸡蛋约重500克,( )个鸡蛋约重2千克。",
+        "options":  [
+
+                    ],
+        "answer":  "32",
+        "solution":  "【分析】已知8个鸡蛋约重500克，要求2千克对应的鸡蛋数量。先根据1千克=1000克统一单位,2千克=2000克。通过计算2000克里面有几个500克，得出2000克大约是由几份8个鸡蛋组成，由此可得鸡蛋的总数。\n\n【详解】根据分析可得:2千克=2000克,2000-500=1500(克),1500-500=1000(克),1000-500=500(克),500-500=0(克),可知2000里面有4个500，所以2000克大约由4份8个鸡蛋组成。1份鸡蛋是8个,4份鸡蛋是4×8=32(个)。所以,8个鸡蛋约重500克,32个鸡蛋约重2千克。",
+        "knowledge_points":  [
+                                 "整百数，几百几十数的加减法口算,8的乘法口诀及应用，克，千克之间的换算与比较"
+                             ],
+        "source":  "24-25 二年级下·贵州铜仁·期末"
+    },
+    {
+        "id":  "139",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "在( )里填上合适的单位.\n大家好，我是聪聪，今年上二年级，身高1( )35( )。体重30( )。我的一步长约50( )。我上午在学校的时间大约是4( ),一节课的时间是40( )。",
+        "options":  [
+
+                    ],
+        "answer":  "米或m;厘米或cm;千克或kg;厘米或cm;小时或h;分钟或min",
+        "solution":  "【分析】根据生活经验以及对长度单位和数据大小的认识，食指的宽大约是1厘米，计量聪聪的步长用\"厘米\"作单位比较合适。二年级学生双臂展开的长度大约是1米，所以计量聪聪的身高用\"米\"和\"厘米\"作单位比较合适。根据生活经验以及对质量单位和数据大小的认识,1瓶矿泉水大约重500克,2瓶矿泉水大约重1千克，所以计量聪聪的体重用\"千克\"做单位比较合适。1小时=60分钟,1分钟=60秒，一节课的标准时长为40分钟，所以在计量一节课的时间用\"分钟\"做单位。上午一般要上3-4节课，所以计量聪聪上午在学校的时间用\"小时\"作单位比较合适，据此结合实际情况判断即可。\n\n【详解】大家好，我是聪聪，今年上二年级，身高1米(或m)35厘米(或cm)。体重30千克(kg)。我的一步长约50厘米(或cm)。我上午在学校的时间大约是4小时(或h),一节课的时间是40分钟(或min)。",
+        "knowledge_points":  [
+                                 "长度单位的选择，质量单位的选择，时间单位的选择"
+                             ],
+        "source":  "24-25 二年级下·河北唐山·期末"
+    },
+    {
+        "id":  "140",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在括号里填上\"\u003e\"\"\u003c\"或\"=\".\n2307( )23705430( )4530 六千( )60001千克( )1010克",
+        "options":  [
+
+                    ],
+        "answer":  "\u003c;\u003e;=;\u003c",
+        "solution":  "【分析】四位数比较大小，千位上大的数就大，如果千位上的数字相同，百位上大的数就大，如果百位上的数字相同，十位上大的数就大，如果十位上的数字相同，个位上大的数就大。1千克=1000克，然后再比较大小。\n\n【详解】2307\u003c2370;5430\u003e4530;六千=6000;1千克=1000克，所以1千克\u003c1010克。",
+        "knowledge_points":  [
+                                 "克，千克之间的换算与比较，万以内数的大小比较"
+                             ],
+        "source":  "24-25 二年级下·广东佛山·期末"
+    },
+    {
+        "id":  "141",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "5千克=( )克 2000克=( )千克\n1310=1000+300+105061=( )+( )+( )",
+        "options":  [
+
+                    ],
+        "answer":  "5000;2;5000;60;1",
+        "solution":  "【分析】根据克与千克间的进率换算,1千克=1000克;5千克就是5个1000克,2000克就是2个1000克，据此换算;根据数的组成1310是由1个千,3个百,1个十,0个一组成，所以1310=1000+300+10;据此写出5061的组成,5061中5在千位表示5000,0在百位表示0,6在十位表示60,1在个位表示1，则5061=5000+60+1。\n\n【详解】5千克=5000克;2000克=2千克;1310=1000+300+10;5061=5000+60+1。",
+        "knowledge_points":  [
+                                 "克，千克之间的换算与比较，万以内数的组成"
+                             ],
+        "source":  "24-25 二年级下·甘肃庆阳·期末"
+    },
+    {
+        "id":  "142",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "8千克=( )克 ( )千克=6000克",
+        "options":  [
+
+                    ],
+        "answer":  "8000;6",
+        "solution":  "【分析】根据1千克=1000克，结合题干要求进行解答即可。\n\n【详解】据分析可知:8千克=8000克;6千克=6000克。",
+        "knowledge_points":  [
+                                 "克，千克之间的换算与比较"
+                             ],
+        "source":  "24-25 二年级下·广东汕尾·期末"
+    },
+    {
+        "id":  "143",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "一头牛的体重是499( );一颗草莓重25( )。",
+        "options":  [
+
+                    ],
+        "answer":  "千克或kg;克或g",
+        "solution":  "【分析】根据生活经验以及对质量单位和数据大小的认识,1张普通的A4纸大约重1克，所以计量一颗草莓的质量用\"克\"作单位比较合适;1瓶矿泉水大约重500克,2瓶矿泉水大约重1千克，所以一头牛的体重用\"千克\"作单位比较合适。\n\n【详解】据分析可知：一头牛的体重是499千克(或kg);一颗草莓重25克(或g)。",
+        "knowledge_points":  [
+                                 "克的认识，千克的认识，质量单位的选择"
+                             ],
+        "source":  "24-25 二年级下·广东汕尾·期末"
+    },
+    {
+        "id":  "144",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在括号填上合适的质量单位.\n图钉重1( ) 牛重550( ) 足球重430( ) 贝贝重32( )",
+        "options":  [
+
+                    ],
+        "answer":  "克或g;千克或kg;克或g;千克或kg",
+        "solution":  "【分析】计量比较轻的物体，常用克作单位,2个曲别针约重1克，所以计量图钉和足球的重量用\"克\"作单位比较合适;计量比较重的物体，常用千克作单位,2小袋食盐重1千克，所以计量一头牛和贝贝的重量用\"千克\"作单位比较合适;据此解答。\n\n【详解】由分析可得：图钉重1克;牛重550千克;足球重430克;贝贝重32千克。",
+        "knowledge_points":  [
+                                 "质量单位的选择，千克的认识，克的认识"
+                             ],
+        "source":  "24-25 二年级下·江西上饶·期末"
+    },
+    {
+        "id":  "145",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在括号填上\"\u003e\"\"\u003c\"或\"=\".\n3806( )368054÷9( )36/62199( )2919\n50-12+8( )50-(12+8) 800克( )1千克 3千克( )3000克",
+        "options":  [
+
+                    ],
+        "answer":  "\u003e;=;\u003c;\u003e;\u003c;=",
+        "solution":  "【分析】先算出每一个算式的结果或先统一单位，然后比较结果的大小，即可解决。整数比较大小的方法，位数多的数大于位数少的数;位数相同的数，从最高位比起，最高位上大的数就大，最高位上相同的，就比较下一位，以此类推。1千克=1000克。\n\n【详解】3806\u003e3680;54÷9=6,36÷6=6，故,54÷9=36÷6;2199\u003c2919;50-12+8=38+8=46,50-(12+8)=50-20=30，故,50-12+8\u003e50-(12+8);1千克=1000克，故,800克\u003c1千克;1千克=1000克，故,3千克=3000克。",
+        "knowledge_points":  [
+                                 "克，千克之间的换算与比较，带有小括号的混合运算，用7~9的乘法口诀求商，万以内数的大小比较"
+                             ],
+        "source":  "24-25 二年级下·河南南阳·期末"
+    },
+    {
+        "id":  "146",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "一袋洗衣液重500克，每袋售价7元,( )袋这样的洗衣液正好重1千克,35元能买( )袋这样的洗衣液。",
+        "options":  [
+
+                    ],
+        "answer":  "2;5",
+        "solution":  "【分析】由题意可知:1千克=1000克,2个500克重1000克，故2袋这样的洗衣液正好重1千克;用35除以每袋售价，即是能买洗衣液的袋数;据此解答。\n\n【详解】由分析可得:1千克=1000克,500+500=1000(克),2袋500克的洗衣液重1千克。35÷7=5(袋),能买5袋洗衣液。一袋洗衣液重500克，每袋售价7元,2袋这样的洗衣液正好重1千克,35元能买5袋这样的洗衣液。",
+        "knowledge_points":  [
+                                 "整百数，几百几十数的加减法口算，用7~9的乘法口诀求商，克，千克之间的换算与比较"
+                             ],
+        "source":  "24-25 二年级下·河南三门峡·期末"
+    },
+    {
+        "id":  "147",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在括号里填上\"\u003e\"\"\u003c\"或\"=\".\n2458( )24856千克( )5800克 4×2( )56÷7",
+        "options":  [
+
+                    ],
+        "answer":  "\u003c;\u003e;=",
+        "solution":  "【分析】①根据整数大小比较方法直接比较。②根据1千克=1000克将单位换算统一，然后在进行比较。③先计算出各算式的答案，然后在进行比较。整数比较大小：位数多的数大于位数少的数;位数相同的数，要从高位开始一级一级的往下比较。\n\n【详解】2458(\u003c)2485;6千克=6000克,6000克\u003e5800，则6千克(\u003e)5800克;4×2=8,56÷7=8,8=8，则4×2(=)56÷7。",
+        "knowledge_points":  [
+                                 "万以内数的大小比较，用7~9的乘法口诀求商，克，千克之间的换算与比较"
+                             ],
+        "source":  "24-25 二年级下·福建三明·期末"
+    },
+    {
+        "id":  "148",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在括号里填上合适的质量单位.\n1盒纯牛奶重250( ),4盒同样的纯牛奶重1( )。",
+        "options":  [
+
+                    ],
+        "answer":  "克或g;千克或kg",
+        "solution":  "【分析】根据情景，生活经验，以及对重量大小的认识可知：计量比较轻的物品常用\"克\"(g)作单位，计量比较重的物品常用\"千克\"(kg)作单位。\n\n【详解】1盒纯牛奶比较轻，计量1盒纯牛奶用\"克\"作单位合适，所以1盒纯牛奶重250克;4盒牛奶的质量要比1盒牛奶重，所以4盒同样的纯牛奶重1千克。",
+        "knowledge_points":  [
+                                 "克的认识，千克的认识，质量单位的选择"
+                             ],
+        "source":  "24-25 二年级下·福建三明·期末"
+    },
+    {
+        "id":  "149",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在下面括号里填上合适的单位.\n二年级的聪聪很注意饮食健康，他每天喝一袋250( )的牛奶，吃300( )的青菜，他现在的身高是132( ),体重是30( )。",
+        "options":  [
+
+                    ],
+        "answer":  "克或g;克或g;厘米或cm;千克或kg",
+        "solution":  "【分析】根据生活常识和对不同重量单位的认识来选择合适的单位。计量比较轻的物体，常用\"克\"作单位，计量比较重的物体，常用\"千克\"作单位。测量较矮(或较短)物体的长度时，一般选择用\"厘米\"作单位。2个曲别针约重1克，所以计量一袋奶和吃的青菜的重量用\"克\"作单位比较合适;2小袋食盐重1千克，所以计量聪聪体重用\"千克\"作单位比较合适;1厘米大约是食指的宽度，所以计量聪聪的身高用\"厘米\"作单位比较合适;【详解】由分析可得：二年级的聪聪很注意饮食健康，他每天喝一袋250克的牛奶，吃300克的青菜，他现在的身高是132厘米，体重是30千克。",
+        "knowledge_points":  [
+                                 "长度单位的选择，质量单位的选择"
+                             ],
+        "source":  "24-25 二年级下·福建莆田·期末"
+    },
+    {
+        "id":  "150",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在括号里填上合适的单位.\n一个西瓜重2( ) 一根香蕉重200( )\n一头猪重140( ) 一袋盐重500( )",
+        "options":  [
+
+                    ],
+        "answer":  "千克或kg;克或g;千克或kg;克或g",
+        "solution":  "【分析】根据实际情境生活经验及数据的大小选择合适的单位，一粒花生米的质量大约是1克，两包食用盐的质量大约是1千克。一个西瓜的质量结合数据2用千克作单位;一根香蕉的质量结合数据200用克作单位比较合适;一头猪的质量结合数据140用千克作单位比较合适;一袋盐的质量结合数据500用克作单位比较合适。据此解答。\n\n【详解】根据分析：一个西瓜重2(千克);一根香蕉重200(克);一头猪重140(千克);一袋盐重500(克)。",
+        "knowledge_points":  [
+                                 "克的认识，千克的认识，质量单位的选择"
+                             ],
+        "source":  "24-25 二年级下·湖南衡阳·期末"
+    },
+    {
+        "id":  "151",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "在括号里填上合适的单位.\n一本书约300( ) 一只羊约重40( )\n小明的体重约23( ) 小明身高136( )",
+        "options":  [
+
+                    ],
+        "answer":  "克或g;千克或kg;千克或kg;厘米/cm",
+        "solution":  "【分析】根据生活常识和对不同重量单位和长度单位的认识，来选择合适的单位。计量比较轻的物体，常用\"克\"作单位，计量比较重的物体，常用\"千克\"作单位。测量较高(或较长)物体的长度时，一般用\"米\"作单位。测量较矮(或较短)物体的长度时，一般用\"厘米\"作单位。2个曲别针约重1克，所以计量一本书的重量用\"克\"作单位比较合适;2小袋食盐重1千克，所以计量一只羊的重量和小明的体重用\"千克\"作单位比较合适;1厘米大约是食指的宽度，所以计量小明身高用\"厘米\"作单位比较合适;【详解】由分析可得：一本书约300克;一只羊约重40千克;小明的体重约23千克;小明身高136厘米。",
+        "knowledge_points":  [
+                                 "质量单位的选择，长度单位的选择"
+                             ],
+        "source":  "24-25二年级下·四川乐山·期末"
+    },
+    {
+        "id":  "152",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在( )里填合适的单位.\n一个鸡蛋约重50( );小明的体重是28( )。",
+        "options":  [
+
+                    ],
+        "answer":  "克或g;千克或kg",
+        "solution":  "【分析】根据生活经验以及对质量单位和数据大小的认识，一枚塑料纽扣的质量大约是1克，所以计量一个鸡蛋的质量用\"克\"作单位比较合适,1瓶矿泉水大约重500克,2瓶矿泉水大约重1千克，所以计量小明的体重用\"千克\"做单位比较合适。据此结合实际情况判断即可。\n\n【详解】一个鸡蛋约重50克(或g);小明的体重是28千克(或kg)。",
+        "knowledge_points":  [
+                                 "克的认识，千克的认识，质量单位的选择"
+                             ],
+        "source":  "24-25 二年级下·山东济宁·期末"
+    },
+    {
+        "id":  "153",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在括号里填\"\u003e\"\"\u003c\"或\"=\".\n42÷7( )36/61999克( )2千克",
+        "options":  [
+
+                    ],
+        "answer":  "=;\u003c",
+        "solution":  "【分析】根据表内乘法口诀，先算出各个除法算式的得数，再进行比较大小。1千克=1000克，先将单位统一，再进行比较大小即可。\n\n【详解】根据\"六七四十二\"\"六六三十六\"可知:42÷7=6,36÷6=6，所以42÷7=36÷6;2千克=2000克,1999克\u003c2000克，所以1999克\u003c2千克。",
+        "knowledge_points":  [
+                                 "用6的乘法口诀求商，用7~9的乘法口诀求商，克，千克之间的换算与比较"
+                             ],
+        "source":  "24-25 二年级下·山东济宁·期末"
+    },
+    {
+        "id":  "154",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在括号里填\"\u003e\"\"\u003c\"或\"=\".\n45÷9( )36/635+27( )7×9\n4千克( )500克 5个千2个一( )9个百9个十",
+        "options":  [
+
+                    ],
+        "answer":  "\u003c;\u003c;\u003e;\u003e",
+        "solution":  "【分析】①②先计算出各算式的答案然后再比较。③根据1千克=1000克，将单位换算统一然后再比较。④万以内整数的写法：从高级单位到低位依次写出各位上的数字，哪位上一个单位也没有，就在那位上写0，据此即可写出此数。位数多的数大于位数少的数;位数相同的数，要从高位开始一级一级的往下比较。\n\n【详解】45÷9=5,36÷6=6,5\u003c6，则45÷9\u003c36÷6;35+27=62,7×9=63,63\u003e62，则35+27\u003c7×9;4千克=4000克,4000\u003e500，则4千克\u003e500克;5个千2个一写作5002,9个百9个十写作990,5002\u003e990，则5个千2个一\u003e9个百9个十。",
+        "knowledge_points":  [
+                                 "万以内数的读，写法，用7~9的乘法口诀求商，克，千克之间的换算与比较"
+                             ],
+        "source":  "24-25 二年级下·山西长治·期末"
+    },
+    {
+        "id":  "155",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "在下面的括号里填上\"\u003e\"\"\u003c\"或\"=\".\n968克( )8千克 24÷3×2( )24÷(3×2)\n3000克( )3千克 83-18+2( )83-(18+2)",
+        "options":  [
+
+                    ],
+        "answer":  "\u003c;\u003e;=;\u003e",
+        "solution":  "【分析】比较数的大小时，位数多的数就大，位数相同比较最高位，最高位大的数就大，最高位相同就比较下一位，直到比出大小为止。(1)(3)题，根据1千克=1000克，把单位统一后再比较大小;(2)(4)题，根据四则混合运算的运算法则：在没有括号的算式里，如果只有加减法或者只有乘除法，要从左往右依次计算;在有括号的算式里，要先算括号里面的，再算括号外面的;分别计算出括号左右两边算式的结果，再比较大小。\n\n【详解】1千克=1000克,8千克=8000克，故:968克\u003c8000克;24÷3×2=8×2=16,24÷(3×2)=24÷6=4,16\u003e4，故:24÷3×2\u003e24÷(3×2);1千克=1000克,3千克=3000克，故:3000克=3千克;83-18+2=65+2=67,83-(18+2)=83-20=63,67\u003e63，故:83-18+2\u003e83-(18+2)。",
+        "knowledge_points":  [
+                                 "100以内数的加减混合运算，表内乘除混合运算，带有小括号的混合运算，克，千克之间的换算与比较"
+                             ],
+        "source":  "24-25 二年级下·广东东莞·期末"
+    },
+    {
+        "id":  "156",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "3000克=( )千克 6千克+2000克=( )千克",
+        "options":  [
+
+                    ],
+        "answer":  "3;8",
+        "solution":  "【分析】先根据\"1千克=1000克\"来换算单位，然后根据加法运算计算出结果即可。\n\n【详解】1000克=1千克，故,3000克=3千克;2000克=2千克,6千克+2千克=8千克，故,6千克+2000克=8千克。",
+        "knowledge_points":  [
+                                 "克，千克之间的换算与比较"
+                             ],
+        "source":  "24-25 二年级下·山东菏泽·期末"
+    },
+    {
+        "id":  "157",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在括号里填上合适的单位.\n一个鸡蛋重约50( )。 小明的体重是30( )。 一支铅笔长约16( ),重约10( )。",
+        "options":  [
+
+                    ],
+        "answer":  "克或g;千克或kg;厘米/cm;克或g",
+        "solution":  "【分析】根据生活常识和对不同重量单位，长度单位的认识来选择合适的单位。计量比较轻的物体，常用\"克\"作单位，计量比较重的物体，常用\"千克\"作单位。测量较矮(或较短)物体的长度时，一般选择用\"厘米\"作单位。测量较高(或较长)物体的长度时，一般用\"米\"作单位。2个曲别针约重1克，所以计量一个鸡蛋重，一支铅笔的重用\"克\"作单位比较合适;2小袋食盐重1千克，所以计量小明的体重用\"千克\"作单位比较合适;1厘米大约是食指的宽度，所以计量一支铅笔长\"厘米\"作单位比较合适;【详解】由分析可得：一个鸡蛋重约50克。小明的体重是30千克。一支铅笔长约16厘米，重约10克。",
+        "knowledge_points":  [
+                                 "质量单位的选择，长度单位的选择"
+                             ],
+        "source":  "24-25 二年级下·山东菏泽·期末"
+    },
+    {
+        "id":  "158",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "6千克=( )克 1400克-400克=( )千克",
+        "options":  [
+
+                    ],
+        "answer":  "6000;1",
+        "solution":  "【分析】本题考查质量单位的换算及简单计算。根据1千克=1000克进行单位转换，先将6千克转换为克，再计算1400克-400克的结果并转换为千克。\n\n【详解】1千克=1000克，故,6千克=6000克;1400克-400克=1000克,1000克=1千克，故,1400克-400克=1千克。",
+        "knowledge_points":  [
+                                 "整百数，几百几十数的加减法口算，克，千克之间的换算与比较"
+                             ],
+        "source":  "24-25 二年级下·浙江绍兴·期末"
+    },
+    {
+        "id":  "159",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "填上合适的单位.\n一盒酸奶重150( );一个西瓜重3( )。",
+        "options":  [
+
+                    ],
+        "answer":  "克或g;千克或kg",
+        "solution":  "【分析】根据生活经验，质量单位和数据大小的认识来解决此题。表示较重的物体时，一般用\"千克\"作单位;表示较轻的物体时，一般用\"克\"作单位。一盒酸奶的重量较轻，常用\"克\"作单位;一个西瓜的重量较重，常用\"千克\"作单位。\n\n【详解】由分析可知：一盒酸奶重150克;一个西瓜重3千克。",
+        "knowledge_points":  [
+                                 "克的认识，千克的认识，质量单位的选择"
+                             ],
+        "source":  "24-25 二年级下·浙江绍兴·期末"
+    },
+    {
+        "id":  "160",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在( )里填上适当的单位.\n一个梨重150( )。 小华的身高135( ),体重30( )。",
+        "options":  [
+
+                    ],
+        "answer":  "克或g;厘米/cm;千克或kg",
+        "solution":  "【分析】计量较轻的物体重量，通常用克作单位,1个鸡蛋大约50克，一个梨大约是3个鸡蛋的重量，结合数据150，计量一个梨的重量用克作单位比较合适;指甲盖的宽度大约是1厘米，结合数据135，计量小华的身高用厘米作单位比较合适;计量较重的物体重量，通常用千克作单位,2袋食盐的重量大约是1千克，结合数据30，计量小华的体重用千克作单位比较合适。\n\n【详解】一个梨重150(克)。小华的身高135(厘米),体重30(千克)。",
+        "knowledge_points":  [
+                                 "质量单位的选择，长度单位的选择"
+                             ],
+        "source":  "24-25 二年级下·湖南长沙·期末"
+    },
+    {
+        "id":  "161",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在( )里填上\"\u003e\"\"\u003c\"或\"=\".\n2300克( )3千克 5千克铁( )5千克鸡蛋 7千克( )6900克",
+        "options":  [
+
+                    ],
+        "answer":  "\u003c;=;\u003e",
+        "solution":  "【分析】整数比较大小：先看位数的多少，位数多的数大;位数相同，从最高位比起，最高位上的数大这个数就大，若最高位上的数相同，就比较下一位，依次类推，直到比出大小。单位不统一的，根据1千克=1000克统一单位之后再比较。\n\n【详解】3千克=3000克,2300克\u003c3000克，所以2300克\u003c3千克;5千克=5千克，所以5千克铁=5千克鸡蛋;7千克=7000克,7000克\u003e6900克，所以7千克\u003e6900克。",
+        "knowledge_points":  [
+                                 "万以内数的大小比较，克，千克之间的换算与比较"
+                             ],
+        "source":  "24-25 二年级下·湖南长沙·期末"
+    },
+    {
+        "id":  "162",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "在括号里填上\"\u003e\"\"\u003c\"或\"=\".\n3740( )3470729千克( )7000克 5+5×8( )51-18÷3",
+        "options":  [
+
+                    ],
+        "answer":  "\u003e;\u003e;=",
+        "solution":  "【分析】(1)比较数的大小时，位数多的数就大，位数相同比较最高位，最高位大的数就大，最高位相同就比较下一位，直到比出大小为止;(2)根据1000克=1千克，将单位统一后，再比较大小;(3)按照四则混合运算的运算法则：在没有括号的算式里，如果既有乘除法又有加减法，要先算乘除法，再算加减法;将括号左右两边算式的结果算出来，比较大小即可。\n\n【详解】两个数都是四位数，千位的数字一样，比较百位7\u003e4，所以3740\u003e3470;1000克=1千克,7000克=7千克,729千克\u003e7千克，所以729千克\u003e7000克;5+5×8=5+40=45,51-18÷3=51-6=45,45=45，所以5+5×8=51-18÷3。",
+        "knowledge_points":  [
+                                 "万以内数的大小比较，乘加，乘减混合运算，除加，除减混合运算，克，千克之间的换算与比较"
+                             ],
+        "source":  "24-25 二年级下·湖北襄阳·期末"
+    },
+    {
+        "id":  "163",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在( )里填上合适的单位.\n一把牙刷约重20( );一头山羊约重60( );教室的黑板长是2( )。",
+        "options":  [
+
+                    ],
+        "answer":  "克或g;千克或kg;米/m",
+        "solution":  "【分析】根据情景选择合适的计量单位，要注意联系生活实际，计量单位和数据的大小，灵活的选择。1克大约为一枚硬币的重量，计量一把牙刷的重量用\"克\"作单位比较合适。1千克大约为两瓶矿泉水的重量，计量一头山羊的重量用\"千克\"作单位比较合适。小学生两臂伸开的长度大约1米，计量黑板的长度用\"米\"作单位比较合适。\n\n【详解】一把牙刷约重20克;一头山羊约重60千克;教室的黑板长是2米。",
+        "knowledge_points":  [
+                                 "质量单位的选择，长度单位的选择"
+                             ],
+        "source":  "24-25 二年级下·重庆秀山·期末"
+    },
+    {
+        "id":  "164",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "在括号里填\"\u003e\"\"\u003c\"\"=\".\n66个十( )7个百 3千克( )980克\n24-12÷3( )(24-12)÷318/3÷2( )18/(3×2)",
+        "options":  [
+
+                    ],
+        "answer":  "\u003c;\u003e;\u003e;=",
+        "solution":  "【分析】单位换算与数值比较：将\"几个十\"和\"几个百\"转换为具体数值，统一质量单位后比较大小(1千克=1000克)。根据只有乘除法，从左往右计算;既有乘除法又有加减，先算乘除后算加减;有括号先算括号内的规则;计算左右两边的结果再比较。整数比较大小的方法，位数多的数大于位数少的数;位数相同的数，从最高位比起，最高位上大的数就大，位数相同的，就比较下一位，以此类推。\n\n【详解】66个十是660,7个百是700,660\u003c700，故,66个十\u003c7个百;3千克=3000克,3000克\u003e980克，故,3千克\u003e980克;24-12÷3=24-4=20,(24-12)÷3=12÷3=4，故,24-12÷3\u003e(24-12)÷3;18÷3/2=6÷2=3,18÷(3×2)=18÷6=3，故,18÷3/2=18÷(3×2)。",
+        "knowledge_points":  [
+                                 "1000以内数的比大小，除加，除减混合运算，带有小括号的混合运算，克，千克之间的换算与比较"
+                             ],
+        "source":  "24-25 二年级下·重庆秀山·期末"
+    },
+    {
+        "id":  "165",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "在括号里填上合适的单位.\n一袋大米约重20( )。 一支铅笔长18( )。 一颗鸡蛋约重60( )。 一个西瓜约重4000( )。",
+        "options":  [
+
+                    ],
+        "answer":  "千克或kg;厘米/cm;克或g;克或g",
+        "solution":  "【分析】根据生活经验，对长度单位，质量单位认识可知,1米大约为小学生双臂伸展开的长度;1分米大约手掌的宽度;1厘米大约指甲盖的宽度;两瓶矿泉水重量大约是1千克。\n\n【详解】两瓶矿泉水重量大约是1千克，所以用\"千克\"作为大米的单位更合适，即一袋大米约重20千克;1厘米大约指甲盖的宽度，所以用\"厘米\"作为铅笔的单位更合适，即一支铅笔长18厘米;两瓶矿泉水重量大约是1千克，所以用\"克\"作为鸡蛋的单位更合适，即一颗鸡蛋约重60克;两瓶矿泉水重量大约是1千克，所以用\"克\"作为西瓜的单位更合适，即一个西瓜约重4000克。",
+        "knowledge_points":  [
+                                 "长度单位的选择，质量单位的选择"
+                             ],
+        "source":  "24-25 二年级下·广西河池·期末"
+    },
+    {
+        "id":  "166",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在括号里填上合适的质量单位.\n小明是一名小学生，他的体重是32( ),每天他都会喝一袋重250( )的牛奶，吃一个约重60( )的鸡蛋和1个约重150( )的苹果，然后背着书包去上学。",
+        "options":  [
+
+                    ],
+        "answer":  "千克或kg;克或g;克或g;克或g",
+        "solution":  "【分析】计量比较重的物体，通常用千克作单位,2袋白砂糖约重1千克，所以小明的体重用千克作单位比较合适;计量比较轻的物体，通常用克作单位,2个曲别针约重1克，所以一袋牛奶的重量和一个鸡蛋的重量及一个苹果的重量用克作单位比较合适。\n\n【详解】由分析可知：小明是一名小学生，他的体重是32(千克),每天他都会喝一袋重250(克)的牛奶，吃一个约重60(克)的鸡蛋和1个约重150(克)的苹果，然后背着书包去上学。",
+        "knowledge_points":  [
+                                 "克的认识，千克的认识"
+                             ],
+        "source":  "24-25 二年级下·湖北黄石·期末"
+    },
+    {
+        "id":  "167",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "5000克=( )千克 9千克=( )克",
+        "options":  [
+
+                    ],
+        "answer":  "5;9000",
+        "solution":  "【分析】1000克=1千克，据此进行单位换算。\n\n【详解】5000克里面有5个1000克，即5个1千克，则5000克=5千克。9千克里面有9个1千克，即9个1000克，则9千克=9000克。",
+        "knowledge_points":  [
+                                 "克，千克之间的换算与比较"
+                             ],
+        "source":  "24-25 二年级下·重庆·期末"
+    },
+    {
+        "id":  "168",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "一枚1元硬币约重6( );一个西瓜约重5( )。一个足球约重500克,( )个同样的足球约重1千克。",
+        "options":  [
+
+                    ],
+        "answer":  "克或g;千克或kg;2",
+        "solution":  "【分析】根据生活常识和对不同重量单位的认识来选择合适的单位。计量比较轻的物体，常用\"克\"作单位，计量比较重的物体，常用\"千克\"作单位。2个曲别针约重1克，所以计量一枚1元硬币的重量用\"克\"作单位比较合适;2小袋食盐重1千克，所以计量一个西瓜的重量用\"千克\"作单位比较合适;把1千克统一单位为1000克，再看几个500克是1000克，就有几个同样的足球约重1千克;2个500克是1000克，所以2个同样的足球约重1千克。\n\n【详解】由分析可得：一枚1元硬币约重6克;一个西瓜约重5千克。一个足球约重500克,2个同样的足球约重1千克。",
+        "knowledge_points":  [
+                                 "质量单位的选择，克，千克之间的换算与比较"
+                             ],
+        "source":  "24-25 二年级下·山东临沂·期末"
+    },
+    {
+        "id":  "169",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "1千克=( )克;2千克-800克=( )克。",
+        "options":  [
+
+                    ],
+        "answer":  "1000;1200",
+        "solution":  "【分析】由题意可知:1千克=1000克，把千克变单位成克，统一单位后再计算。\n\n【详解】由分析可得:1千克=1000克;2千克-800克=2000克-800克=1200克。1千克=1000克;2千克-800克=1200克。",
+        "knowledge_points":  [
+                                 "克，千克之间的换算与比较"
+                             ],
+        "source":  "24-25 二年级下·湖南长沙·期末"
+    },
+    {
+        "id":  "170",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在括号里填上\"\u003e\"\"\u003c\"或\"=\".\n8091( )8029996( )12012千克( )2000克 48÷6( )48/8",
+        "options":  [
+
+                    ],
+        "answer":  "\u003e;\u003c;=;\u003e",
+        "solution":  "【分析】比较数的大小，先看位数，位数多的数大;位数相同则从高位逐位比较。单位不同需先统一单位，算式比较需先计算结果。\n\n【详解】两数均为四位数，千位，百位相同，十位9\u003e2，所以,8091\u003e8029;996是三位数,1201是四位数，四位数更大，所以,996\u003c1201;1千克=1000克,2千克=2000克，所以,2千克=2000克;48÷6=8,48÷8=6,8\u003e6，所以,48÷6\u003e48÷8。",
+        "knowledge_points":  [
+                                 "万以内数的大小比较，用7~9的乘法口诀求商，克，千克之间的换算与比较"
+                             ],
+        "source":  "24-25二年级下·江西赣州·期末"
+    },
+    {
+        "id":  "171",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在下面的括号里填上合适的单位.\n一枚1元硬币重约1( ) 一辆三轮车可以装货物200( )\n一根跳绳长约2( ) 1个苹果重200g,5个苹果大约重1( )",
+        "options":  [
+
+                    ],
+        "answer":  "克或g;千克或kg;米或m;千克或kg",
+        "solution":  "【分析】根据生活经验以及对质量单位和数据大小的认识,1张普通的A4纸大约重1克，所以计量一枚1元硬币的质量用\"克\"做单位比较合适;1瓶矿泉水大约重500克,2瓶矿泉水大约重1千克，所以计量一辆三轮车可以装货物的质量用\"千克\"做单位比较合适。计量5个苹果的质量用\"千克\"做单位比较合适。根据生活经验以及对长度单位和数据大小的认识，量比较长的物体，通常用米作单位。二年级学生双臂展开的长度大约是1米，所以计量一根跳绳的长度用\"米\"作单位比较合适。\n\n【详解】一枚1元硬币重约1克。一辆三轮车可以装货物200千克。一根跳绳长约2米。200×5=1000(克),1000克=1千克;1个苹果重200g,5个苹果大约重1千克。",
+        "knowledge_points":  [
+                                 "克的认识，千克的认识，质量单位的选择，长度单位的选择"
+                             ],
+        "source":  "24-25 二年级下·江西赣州·期末"
+    },
+    {
+        "id":  "172",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "1千克=( )克 8000克=( )千克",
+        "options":  [
+
+                    ],
+        "answer":  "1000;8",
+        "solution":  "【分析】根据\"1千克=1000克\"，换算单位后即可解答。\n\n【详解】1千克=1000克;1000克=1千克，故8000克=8千克。",
+        "knowledge_points":  [
+                                 "克，千克之间的换算与比较"
+                             ],
+        "source":  "24-25 二年级下·山东济宁·期末"
+    },
+    {
+        "id":  "173",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "填上合适的单位.\n张老师身高168( ),体重62( ),他在讲台桌前拿着2瓶约重1( )的矿泉水和一个约重150( )的苹果，开始了一节时长40( )的数学实验课。",
+        "options":  [
+
+                    ],
+        "answer":  "厘米/cm;千克或kg;千克或kg;克或g;分钟或min",
+        "solution":  "【分析】根据生活经验，对长度单位，质量单位，时间单位认识可知,1米大约为小学生双臂伸展开的长度;1分米大约手掌的宽度;1厘米大约指甲盖的宽度，两瓶矿泉水重量大约是1千克;一集电视剧的时长约为45分钟，一天为24小时。\n\n【详解】根据分析可知，张老师的体重用厘米更合适，体重用千克更合适，矿泉水的重量用千克更合适，苹果的重量用克更合适，实验课的时长用分钟更合适。所以，张老师身高168厘米，体重62千克，他在讲台桌前拿着2瓶约重1千克的矿泉水和一个约重150克的苹果，开始了一节时长40分钟的数学实验课。",
+        "knowledge_points":  [
+                                 "时间单位的选择，质量单位的选择，长度单位的选择"
+                             ],
+        "source":  "24-25二年级下·浙江温州·期末"
+    },
+    {
+        "id":  "174",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "7000克+2千克=( )千克 3千克-500克=( )克",
+        "options":  [
+
+                    ],
+        "answer":  "9;2500",
+        "solution":  "【分析】根据1千克=1000克，先把单位统一后再相加减。\n\n【详解】7000克+2千克=7千克+2千克=9千克，所以7000克+2千克=9千克;3千克-500克=3000克-500克=2500克，所以3千克-500克=2500克。",
+        "knowledge_points":  [
+                                 "克，千克之间的换算与比较"
+                             ],
+        "source":  "24-25 二年级下·浙江温州·期末"
+    },
+    {
+        "id":  "175",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "在横线上填合适的单位.\n一部手机约重200( );妈妈身高约163( );一袋大米约重5( )。",
+        "options":  [
+
+                    ],
+        "answer":  "克或g;厘米或cm;千克或kg",
+        "solution":  "【分析】根据生活经验，对长度单位，质量单位认识可知,1米大约为小学生双臂伸展开的长度;1分米大约手掌的宽度;1厘米大约指甲盖的宽度，两瓶矿泉水重量大约是1千克。\n\n【详解】两瓶矿泉水重量大约是1千克，手机质量比两瓶矿泉水重量要轻很多，所以计量手机的重量用\"克\"作单位比较合适，则一部手机约重200克;小学生双臂展开的长度大约是1米,1厘米大约指甲盖的宽度，由于前面数字比较大，所以计量妈妈的身高用\"厘米\"作单位比较合适，则妈妈身高约163厘米;两瓶矿泉水重量大约是1千克，所以计量大米的重量用\"千克\"作单位比较合适，则一袋大米约重5千克。",
+        "knowledge_points":  [
+                                 "质量单位的选择，长度单位的选择"
+                             ],
+        "source":  "24-25 二年级下·浙江温州·期末"
+    },
+    {
+        "id":  "176",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在括号里填合适的质量单位.\n(1)一小袋面粉重3( )。 (2)一枚月饼约重80( )。",
+        "options":  [
+
+                    ],
+        "answer":  "千克或kg 克或g",
+        "solution":  "【分析】根据情景选择合适的计量单位，要注意联系生活实际，计量单位和数据的大小，灵活的选择。1千克大约为两瓶矿泉水的重量，计量一小袋面粉的重量用\"千克\"作单位比较合适。1克大约为一枚硬币的重量，计量一枚月饼的重量用\"克\"作单位比较合适。\n\n【详解】(1)一小袋面粉重3千克。(2)一枚月饼约重80克。",
+        "knowledge_points":  [
+                                 "质量单位的选择，千克的认识，克的认识"
+                             ],
+        "source":  "24-25 二年级下·湖南岳阳·期末"
+    },
+    {
+        "id":  "177",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在( )里填上合适的单位.\n1只兔子约重1500( )。 小明家离学校很近，只有65( )。 小明的课桌高约70( )。 小明的体重约25( )。",
+        "options":  [
+
+                    ],
+        "answer":  "克或g;米或m;厘米或cm;千克或kg",
+        "solution":  "【分析】根据情景选择合适的计量单位，要注意联系生活实际，计量单位和数据的大小，灵活的选择。1克大约为一枚硬币的重量，计量兔子的重量用\"克\"作单位比较合适。小学生两臂伸展开的长度大约1米，计量家到学校的距离用\"米\"作单位比较合适。大拇指的指甲长度大约1厘米，计量课桌的高度用\"厘米\"作单位比较合适。1千克大约为两瓶矿泉水的重量，计量小朋友的体重用\"千克\"作单位比较合适。\n\n【详解】1只兔子约重1500克。小明家离学校很近，只有65米。小明的课桌高约70厘米。小明的体重约25千克。",
+        "knowledge_points":  [
+                                 "质量单位的选择，长度单位的选择"
+                             ],
+        "source":  "23-24 二年级下·浙江嘉兴·期末"
+    },
+    {
+        "id":  "178",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "王阿姨买了2500克西瓜，每500克西瓜2元，她花了( )元。",
+        "options":  [
+
+                    ],
+        "answer":  "10",
+        "solution":  "【分析】根据题意，先计算2500克里面有几个500克，每500克西瓜2元，再用2乘几，等于王阿姨花了多少元，即可解答。\n\n【详解】1个500克是500克,2个500克是1000克,3个500克是1500克,4个500克是2000克,5个500克是2500克，即2500克里面有5个500克;2×5=10(元),因此，王阿姨买了2500克西瓜，每500克西瓜2元，她花了10元。",
+        "knowledge_points":  [
+                                 "5的乘法口诀及应用，元，角，分的认识及换算，克的认识"
+                             ],
+        "source":  "24-25 二年级下·湖北武汉·期末"
+    },
+    {
+        "id":  "179",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在括号里填上合适的单位.\n一个鸡蛋约重60( ) 一个梨大约重250( )\n小明体重32( ) 200克+800克=1( )",
+        "options":  [
+
+                    ],
+        "answer":  "克或g;克或g;千克或kg;千克或kg",
+        "solution":  "【分析】据生活经验以及对质量单位和数据大小的认识,1张普通的A4纸大约重1克，所以计量一个鸡蛋和一个梨的质量用\"克\"做单位比较合适;1瓶矿泉水大约重500克,2瓶矿泉水大约重1千克，所以计量小明的体重用\"千克\"做单位比较合适。再根据1千克=1000克进行计算即可。\n\n【详解】据分析可知：一个鸡蛋约重60克(或g);一个梨大约重250克(或g);小明体重32千克(或kg);200克+800克=1000克,1000克=1千克，所以200克+800克=1千克。",
+        "knowledge_points":  [
+                                 "质量单位的选择，克，千克之间的换算与比较，千克的认识，克的认识"
+                             ],
+        "source":  "24-25 二年级下·福建福州·期末"
+    },
+    {
+        "id":  "180",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "在括号中填上\"\u003e\"\"\u003c\"或\"=\".\n3003( )3030987( )21431千克( )800克\n9000+900( )10个一千 16-12÷4( )(16-12)÷46000克( )3千克",
+        "options":  [
+
+                    ],
+        "answer":  "\u003c;\u003c;\u003e;\u003c;\u003e;\u003e",
+        "solution":  "【分析】万以内数比较大小的方法：位数不同时，位数多的那个数就大，位数相同时，从最高位比起，最高位上的数字大，那个数就大;如果最高位也相同，比下一位，直到比出大小为止;题中单位不统一的先变统一再比较;比较算式的大小，先算出算式得数，再根据得数比较大小;据此解答。\n\n【详解】3003( )3030：都是四位数，千位和百位数字相等，比较十位数字0\u003c3，故3003\u003c3030;987( )2143：三位数小于四位数，故987\u003c2143;1千克( )800克:1千克=1000克,1000克\u003e800克，故1千克\u003e800克;9000+900( )10个一千:9000+900=9900,10个一千是10000,9900\u003c10000，故9000+900\u003c10个一千;16-12÷4=16-3=13,(16-12)÷4=4÷4=1,13\u003e1，故16-12÷4\u003e(16-12)÷4;6000克( )3千克:3千克=3000克,6000克\u003e3000克，故6000克\u003e3千克。",
+        "knowledge_points":  [
+                                 "克，千克之间的换算与比较，带有小括号的混合运算，整百数，几百几十数的加减法口算，万以内数的大小比较"
+                             ],
+        "source":  "24-25二年级下·浙江温州·期末"
+    },
+    {
+        "id":  "181",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在( )里填上合适的单位.\n小胖体重40( ) 一个苹果约重300( )",
+        "options":  [
+
+                    ],
+        "answer":  "千克或kg;克或g",
+        "solution":  "【分析】根据情景选择合适的计量单位，要注意联系生活实际，计量单位和数据的大小，灵活的选择。1千克大约为两瓶矿泉水的重量，计量人的体重用\"千克\"作单位比较合适。1克大约为一枚硬币的重量，计量一个苹果的重量用\"克\"作单位比较合适。\n\n【详解】小胖体重40千克;一个苹果约重300克。",
+        "knowledge_points":  [
+                                 "克的认识，千克的认识，质量单位的选择"
+                             ],
+        "source":  "24-25 二年级下·山东菏泽·期末"
+    },
+    {
+        "id":  "182",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "一袋食盐500克,2袋这样的食盐重( )千克。",
+        "options":  [
+
+                    ],
+        "answer":  "1",
+        "solution":  "【分析】将2袋食盐的重量相加，然后换算成千克作单位,1000克=1千克，据此换算。\n\n【详解】500克+500克=1000克,1000克=1千克，一袋食盐500克,2袋这样的食盐重1千克。",
+        "knowledge_points":  [
+                                 "克，千克之间的换算与比较"
+                             ],
+        "source":  "19-20 三年级上·全国·单元测试"
+    },
+    {
+        "id":  "183",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "一个二年级小学生的体重约是35千克。( )",
+        "options":  [
+
+                    ],
+        "answer":  "√",
+        "solution":  "【分析】根据生活经验和实际数据相结合可知:1千克大约为两瓶矿泉水的重量，则二年级小学生的体重通常以\"千克\"为单位,35千克属于合理范围。\n\n【详解】千克是较大的质量单位，常用于表示人体体重。二年级小学生年龄约为7-8岁，体重一般在20-40千克之间,35千克符合实际生活经验，因此题干描述正确。故答案为:√",
+        "knowledge_points":  [
+                                 "质量单位的选择，千克的认识"
+                             ],
+        "source":  "20-21 三年级下·辽宁·单元测试"
+    },
+    {
+        "id":  "184",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "1千克油比1千克羽毛重。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】比较物体之间的轻重，与物体本身的材质无关，与本身的重量有关，油和羽毛重量都是1千克，所以二者一样重。\n\n【详解】由分析可得:1千克油和1千克羽毛同样重，原题说法错误。故答案为: ×",
+        "knowledge_points":  [
+                                 "千克的认识，克，千克之间的换算与比较"
+                             ],
+        "source":  "24-25 二年级下·云南红河·期末"
+    },
+    {
+        "id":  "185",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "1千克鸡蛋与2袋500克的糖一样重。( )",
+        "options":  [
+
+                    ],
+        "answer":  "√",
+        "solution":  "【分析】比较1千克鸡蛋与2袋500克糖的总重量是否相等。单位不统一的话，根据1千克=1000克，统一单位之后再比较。\n\n【详解】2袋糖的重量:500+500=1000(克),1000克=1千克，所以1千克鸡蛋与2袋500克的糖一样重。原题说法正确。故答案为:√",
+        "knowledge_points":  [
+                                 "整百数，几百几十数的加减法口算，克，千克之间的换算与比较"
+                             ],
+        "source":  "24-25 二年级下·山东济宁·期末"
+    },
+    {
+        "id":  "186",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "5千克棉花比3000克石头轻。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】比较物体的轻重需统一单位。根据1千克=1000克，将5千克统一成克，再和3000克比较，即可作出判定。\n\n【详解】由分析可得:1千克=1000克,5千克=5000克;5000克\u003e3000克,5千克棉花比3000克石头重。故答案为: ×",
+        "knowledge_points":  [
+                                 "克，千克之间的换算与比较"
+                             ],
+        "source":  "24-25 二年级下·贵州铜仁·期末"
+    },
+    {
+        "id":  "187",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "一瓶可乐重350千克。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】根据生活经验，对质量单位和数据大小的认识可知：计量比较轻的物体，常用克作单位,2个曲别针约重1克;计量比较重的物体，常用千克作单位,2袋白砂糖约重1千克;可乐的重量较轻，用克作单位比较合适，由此解答。\n\n【详解】由分析得：一瓶可乐应重350克，原题说法错误。故答案为: ×",
+        "knowledge_points":  [
+                                 "质量单位的选择，千克的认识，克的认识"
+                             ],
+        "source":  "24-25二年级下·湖北黄冈·期末"
+    },
+    {
+        "id":  "188",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "判断题",
+        "difficulty":  0.65,
+        "question":  "1个苹果重3千克。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】根据生活常识，一个普通苹果的重量通常在100克到300克之间，相当于约10个普通苹果的总重量，显然不符合实际情况。1千克=1000克。\n\n【详解】根据分析,1个苹果的重量通常在100克到300克之间。原题说法错误。故答案为: ×",
+        "knowledge_points":  [
+                                 "千克的认识，克的认识"
+                             ],
+        "source":  "24-25 二年级下·云南昭通·期末"
+    },
+    {
+        "id":  "189",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "一枚2分硬币约重1千克。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】计量比较轻的物体，常用\"克\"作单位，计量比较重的物体，常用\"千克\"作单位。2个曲别针约重1克，所以计量一枚2分硬币重量用\"克\"作单位比较合适;据此可判断。\n\n【详解】由分析可得：一枚2分硬币约重1克。故答案为: ×",
+        "knowledge_points":  [
+                                 "千克的认识，克的认识"
+                             ],
+        "source":  "24-25 二年级下·内蒙古呼伦贝尔·期末"
+    },
+    {
+        "id":  "190",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "二(1)班兰兰同学的体重是38克。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】根据生活常识，小学生的体重通常以\"千克\"为单位，而\"克\"是较小的质量单位。兰兰同学的体重38克不符合实际情况，因此判断为错误。\n\n【详解】克是较小的质量单位，通常用于较轻的物体，如一枚硬币约6克。小学生的体重一般在20千克至50千克之间,38克远低于正常范围，故题干中\"38克\"单位使用错误。故答案为: ×",
+        "knowledge_points":  [
+                                 "质量单位的选择"
+                             ],
+        "source":  "24-25二年级下·广东汕尾·期末"
+    },
+    {
+        "id":  "191",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "判断题",
+        "difficulty":  0.65,
+        "question":  "一袋1千克的糖果与2袋500克的瓜子一样重。( )",
+        "options":  [
+
+                    ],
+        "answer":  "√",
+        "solution":  "【分析】根据重量单位换算进行判断。物体的质量与材质无关,1千克=1000克,2袋500克的瓜子总重量为500+500=1000(克),与1千克的糖果重量相等。\n\n【详解】1千克的糖果重量为1000克,1袋瓜子500克,2袋瓜子的总重量为500+500=1000(克),原题说法正确。故答案为:√",
+        "knowledge_points":  [
+                                 "克，千克之间的换算与比较"
+                             ],
+        "source":  "24-25二年级下·河北承德·期末"
+    },
+    {
+        "id":  "192",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "2000克棉花比2千克钢铁轻。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】质量的大小和物体材质无关，先根据1千克=1000克，将不同单位统一，再进行比较。\n\n【详解】由分析可得:1千克=1000克，因此2千克=2000克。2000克棉花与2千克钢铁的重量相等。故答案为: ×",
+        "knowledge_points":  [
+                                 "克，千克之间的换算与比较"
+                             ],
+        "source":  "24-25 二年级下·四川乐山·期末"
+    },
+    {
+        "id":  "193",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "1千克的铁比1千克的棉花重。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】比较物体的轻重时，若单位相同，只需比较数值大小。题目中铁和棉花的重量均为1千克，重量相等，因此两者一样重。\n\n【详解】1千克的铁与1千克的棉花一样重。原题说法错误。故答案为: ×",
+        "knowledge_points":  [
+                                 "千克的认识"
+                             ],
+        "source":  "24-25 三年级上·内蒙古通辽·期中"
+    },
+    {
+        "id":  "194",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "判断题",
+        "difficulty":  0.94,
+        "question":  "比较轻的物品常用天平来称。( )",
+        "options":  [
+
+                    ],
+        "answer":  "√",
+        "solution":  "【详解】根据题意，天平是用于测量物体质量的工具，其原理是通过比较两边的重量来确定物体的质量。在小学阶段，天平通常量程较小，适合称量较轻的物品(如几克到几百克)。例如，在科学实验中，常用天平称量小石块，硬币等质量较小的物体。所以，比较轻的物品常用天平来称。原题说法正确。答案为:√",
+        "knowledge_points":  [
+                                 "克的认识，千克的认识"
+                             ],
+        "source":  "24-25 二年级下·山东菏泽·期末"
+    },
+    {
+        "id":  "195",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "1千克苹果比1000克棉花重。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】根据题意,1千克=1000克,1千克苹果和1000克棉花的质量相等。据此解答。\n\n【详解】根据分析:1千克=1000克,1千克苹果和1000克棉花一样重。原题说法错误。故答案为: ×",
+        "knowledge_points":  [
+                                 "克，千克之间的换算与比较"
+                             ],
+        "source":  "18-19 三年级下·辽宁沈阳·期末"
+    },
+    {
+        "id":  "196",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "妈妈买了3千克香蕉，每千克香蕉6元，又买了2千克苹果，每千克苹果5元，妈妈一共花了多少钱。",
+        "options":  [
+
+                    ],
+        "answer":  "28元",
+        "solution":  "【分析】根据乘法的意义，用每千克香蕉的价钱乘买的香蕉的质量，即可得出买香蕉花了多少钱。用每千克苹果的价钱乘买的苹果的质量，即可得出买苹果花了多少钱，再将买两种水果花的价钱相加，即可得出答案。\n\n【详解】6×3+5×2=18+10=28(元),答：妈妈一共花了28元钱。",
+        "knowledge_points":  [
+                                 "乘加，乘减混合运算"
+                             ],
+        "source":  "24-25二年级下·广东汕尾·期末"
+    },
+    {
+        "id":  "197",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "水果店原有500千克苹果，上午卖出300千克，下午又运来260千克苹果，现在水果店有多少千克苹果。",
+        "options":  [
+
+                    ],
+        "answer":  "460千克",
+        "solution":  "【分析】由题意得，水果店里有500千克苹果，上午卖出300千克，可以先用500减去300算出上午卖完后还剩多少千克苹果。下午又运进260千克苹果，那么直接用前面的得数加上260即可算出现在商店里有多少千克苹果。\n\n【详解】500-300+260=200+260=460(千克),答：现在水果店有460千克苹果。",
+        "knowledge_points":  [
+                                 "整百数，几百几十数的加减法口算，两，三位数的加减混合运算"
+                             ],
+        "source":  "24-25 二年级下·广东汕尾·期末"
+    },
+    {
+        "id":  "198",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "李叔叔周日钓到20千克鱼，其中有8千克草鱼，王叔叔钓到12千克鱼。把这些鱼平均放到8个筐里，每个筐里可放多少千克鱼。",
+        "options":  [
+
+                    ],
+        "answer":  "4千克",
+        "solution":  "【分析】先用李叔叔钓的鱼的重量加上王叔叔钓的鱼的重量，求出鱼的总重量，再用鱼的总重量除以筐的个数，即可求出每个筐里可放多少千克鱼。注意\"其中有8千克草鱼\"这个条件与解题无用。\n\n【详解】(20+12)÷8=32÷8=4(千克),答：每个筐里可放4千克鱼。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算，千克的认识，含有多余条件的实际问题"
+                             ],
+        "source":  "24-25 二年级下·山西长治·期末"
+    },
+    {
+        "id":  "199",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "下图是飘香水果店的水果标价牌.\n苹果:4元/500克 橘子:2元/500克 龙眼:7元/500克 山竹:16元/500克 榴莲:21元/500克\n(1)买500克山竹的钱可以买多少千克苹果。\n(2)妈妈买了1千克龙眼和500克山竹，一共要花多少钱。",
+        "options":  [
+
+                    ],
+        "answer":  "2千克;30元",
+        "solution":  "【分析】(1)根据题意可知：山竹是16元500克，苹果是4元500克，则可以求出16里面有几个4，也即是可以买几个500克，然后把这几个500相加即可，求买500克山竹的钱可以买苹果的克数，然后根据1千克=1000克将单位换算成千克即可。(2)根据题意：首先根据1千克=1000克将单位换算，然后求出1千克龙眼花的钱数，即用1000减500，求出有几个500，也就是求出有几个7，然后用乘法计算，求出1千克龙眼的价格，然后再加上500克山竹的价格。\n\n【详解】(1)16÷4=4,500+500+500+500=1000+500+500=1500+500=2000(克),2000克=2千克，答：买500克山竹的钱可以买2千克苹果。(2)1000-500=500(克),500-500=0(克),则1千克龙眼的价钱是2个7元，用乘法计算。2×7=14(元),14+16=30(元),答：一共要花30元。",
+        "knowledge_points":  [
+                                 "克，千克之间的换算与比较，整百数，几百几十数的加减法口算"
+                             ],
+        "source":  "23-24 二年级下·湖北荆州·期末"
+    },
+    {
+        "id":  "200",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "某水果店水果价格如下图。小东要买1500克葡萄和500克苹果，一共需要多少元。\n![](images/6b952726be93272a31c33a1b24b5cbef.png)",
+        "options":  [
+
+                    ],
+        "answer":  "35;35元",
+        "solution":  "【分析】根据题意，先算出1500克里面有几个500克，然后和每500克葡萄的钱数相乘，即可求出买葡萄的钱数，再加上每500克苹果的钱数，就可以求出一共需要多少元，据此解答。\n\n【详解】500克+500克+500克=1500克，即1500克里面有3个500克;9×3+8=27+8=35(元),答：一共需要35元钱。",
+        "knowledge_points":  [
+                                 "乘加，乘减混合运算，克的认识"
+                             ],
+        "source":  "24-25 二年级下·浙江温州·期末"
+    },
+    {
+        "id":  "201",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "一个盒子的质量是200克，在盒子里放入1800克的点心后，盒子和点心一共重( )。",
+        "options":  [
+                        "A. 1600克",
+                        "B. 1000克",
+                        "C. 2千克"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】用盒子的质量+点心的质量=盒子和点心一共的质量，再根据1000克=1千克换算单位即可。\n\n【详解】200+1800=2000(克),1000克=1千克,2000克=2千克，所以盒子和点心一共重2千克。故答案为:C",
+        "knowledge_points":  [
+                                 "克，千克之间的换算与比较，整百数，几百几十数的加减法口算"
+                             ],
+        "source":  "23-24二年级下·河南信阳·期末"
+    },
+    {
+        "id":  "202",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "一只鸵鸟约重( )。",
+        "options":  [
+                        "A. 100克",
+                        "B. 100千克",
+                        "C. 1000克"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】根据生活经验以及对质量单位和数据大小的认识,1瓶矿泉水大约重500克,2瓶矿泉水大约重1千克,1张普通的A4纸的质量大约重1克，据此结合实际情况进行解答即可。\n\n【详解】据分析可知：一只鸵鸟约重100千克。故答案为:B",
+        "knowledge_points":  [
+                                 "千克的认识，克的认识"
+                             ],
+        "source":  "23-24 二年级下·河北邯郸·期末"
+    },
+    {
+        "id":  "203",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "乌鸦喝水。第一次喝了一瓶水的一半，第二次喝了剩下半瓶水的一半，第三次喝了9克，正好全部喝完，这瓶水有( )克。",
+        "options":  [
+                        "A. 36",
+                        "B. 27",
+                        "C. 18"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】本题采用倒推法求解，从最后一次喝水情况往前推，第三次喝了9克后正好喝完，第二次喝完后剩下的水就是第三次喝的量。第二次喝了剩下半瓶水的一半后剩下9克，那么第二次喝完后剩下的水是第一次喝完后剩下的一半，所以第一次喝完后剩下9+9=18(克)。而第一次喝完后剩下的水又是整瓶水的一半，所以整瓶水有18+18=36(克),据此解答。\n\n【详解】9+9=18(克),18+18=36(克),这瓶水有36克。故答案为:A",
+        "knowledge_points":  [
+                                 "克的认识，两位数与两位数的进位加法,9加几的进位加法，倒推问题"
+                             ],
+        "source":  "23-24二年级下·浙江·期末"
+    },
+    {
+        "id":  "204",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "下面说法错误的是( )。",
+        "options":  [
+                        "A. 比最大的三位数多1的是1000",
+                        "B. 在算盘上，一个下珠表示5，一个上珠表示1",
+                        "C. 2千克棉花和2千克铁一样重",
+                        "D. \"8800\"中，两个\"8\"表示的意思不同"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】最大的三位数是999，往后数1个即可。算盘上一颗上珠表示5，一颗下珠表示1。单位一样的可以直接比较。整数中，从右到左分别是个位，十位，百位，千位。个位上是几表示几个一，十位上是几表示几个十，百位上是几表示几个百，千位上是几表示几个千。逐项分析。\n\n【详解】A。比最大的三位数多1的是1000，原题说法正确。B。在算盘上，一个下珠表示1，一个上珠表示5，原题说法错误。C。2千克=2千克,2千克棉花和2千克铁一样重，原题说法正确。D.\"8800\"中，两个\"8\"表示的意思不同，原题说法正确。故答案为:B",
+        "knowledge_points":  [
+                                 "克，千克之间的换算与比较，整数的数级，数位和计数单位的认识，万以内数的组成，算盘的认识与使用"
+                             ],
+        "source":  "23-24 二年级下·福建龙岩·期末"
+    },
+    {
+        "id":  "205",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "一支铅笔重10( )。",
+        "options":  [
+                        "A. 厘米",
+                        "B. 克",
+                        "C. 千克"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】根据生活经验，对长度单位，质量单位和数据大小的认识可知：量比较短的物体的长度，通常用厘米作单位，食指的宽大约是1厘米;计量比较轻的物体，常用克作单位,2个曲别针约重1克;计量比较重的物体，常用千克作单位,2袋白砂糖约重1千克;由此解答。\n\n【详解】A。厘米是长度单位，不能计量铅笔的重量，不符合题意;B。10克大约是1支铅笔的重量，符合题意;C。10千克大约为1袋大米的重量，不符合题意。则一支铅笔重10克。故答案为:B",
+        "knowledge_points":  [
+                                 "质量单位的选择，千克的认识，克的认识"
+                             ],
+        "source":  "23-24二年级下·河南许昌·期末"
+    },
+    {
+        "id":  "206",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "1千克棉花和1千克铁相比,( )。",
+        "options":  [
+                        "A. 棉花重",
+                        "B. 铁重",
+                        "C. 一样重"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】都是以千克作单位，直接比较即可。\n\n【详解】1千克=1千克,1千克棉花和1千克铁相比，一样重。故答案为:C",
+        "knowledge_points":  [
+                                 "千克的认识"
+                             ],
+        "source":  "24-25 二年级下·河南漯河·期末"
+    },
+    {
+        "id":  "207",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "一瓶水连瓶共重1千克，水重900克，瓶重( )。",
+        "options":  [
+                        "A. 1克",
+                        "B. 100克",
+                        "C. 100千克"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】根据题意，连瓶带水的总重量-水的重量=瓶的重量，根据1千克=1000克统一单位再计算。\n\n【详解】1千克=1000克,1000克-900克=100克，瓶重100克。故答案为:B",
+        "knowledge_points":  [
+                                 "克，千克之间的换算与比较"
+                             ],
+        "source":  "24-25 二年级下·河南周口·期末"
+    },
+    {
+        "id":  "208",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "买1千克苹果和500克桃子应付( )钱.\n\n| 苹果 | 3元/500克 |\n| ---- | --------- |\n| 梨 | 4元/500克 |\n| 桃子 | 8元/500克 |",
+        "options":  [
+                        "A. 14元",
+                        "B. 15元",
+                        "C. 19元"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】根据1千克=1000克，把买的苹果的重量换算成以\"克\"为单位的数，先计算1千克苹果应付的钱数，再加上500克桃子应付的钱数，即可求出买1千克苹果和500克桃子应付多少元钱，据此解答。\n\n【详解】1千克=1000克,500+500=1000(克),即1千克中有2个500克。3×2+8=6+8=14(元),因此，买1千克苹果和500克桃子应付14元钱。故答案为:A",
+        "knowledge_points":  [
+                                 "表内乘加，乘减，克，千克之间的换算与比较"
+                             ],
+        "source":  "23-24二年级下·浙江台州·期末"
+    },
+    {
+        "id":  "209",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "一袋大米重25千克,( )袋大米是100千克。",
+        "options":  [
+                        "A. 4",
+                        "B. 40",
+                        "C. 400"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】要求几袋大米是100千克，即求100里面有几个25，根据减法的意义，用100连续减去25，能减几次就表示几袋。据此解答即可。\n\n【详解】100-25=75(千克),75-25=50(千克),50-25=25(千克),25-25=0(千克),所以4袋大米是100千克。故答案为:A",
+        "knowledge_points":  [
+                                 "两位数与两位数的不退位减法，两位数与两位数的退位减法，千克的认识"
+                             ],
+        "source":  "23-24二年级下·湖北省直辖县级单位·期末"
+    },
+    {
+        "id":  "210",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "赞皇大枣是河北的特产，被誉为\"百果之首\"，\"天然维生素之王\"，含有丰富的营养价值。3箱大枣共重15千克，平均每箱重( )。",
+        "options":  [
+                        "A. 5克",
+                        "B. 5000克",
+                        "C. 5000千克"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】根据题意可知，大枣的总千克数除以大枣的箱数，等于每箱大枣多少千克，再根据1千克=1000克，换算单位后，找出正确答案即可。\n\n【详解】根据分析可得:15÷3=5(千克),5千克=5000克，因此,3箱大枣共重15千克，平均每箱重5000克。故答案为:B",
+        "knowledge_points":  [
+                                 "克，千克之间的换算与比较，用2~5的乘法口诀求商"
+                             ],
+        "source":  "23-24二年级下·河南濮阳·期末"
+    },
+    {
+        "id":  "211",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "一个梨约重( )。",
+        "options":  [
+                        "A. 8克",
+                        "B. 8千克",
+                        "C. 200克"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】根据生活经验，对质量单位和数据大小的认识可知：计量比较轻的物体，常用克作单位,2个曲别针约重1克，计量比较重的物体，常用千克作单位,2袋白砂糖约重1千克，由此解答。\n\n【详解】A。8克和一枚一元硬币的重量差不多，不符合题意;B。8千克相当于一袋大米的重量，不符合题意;C。200克符合一个梨的重量。则一个梨约重200克。故答案为:C",
+        "knowledge_points":  [
+                                 "质量的估计，千克的认识，克的认识"
+                             ],
+        "source":  "23-24二年级下·河北邯郸·期末"
+    },
+    {
+        "id":  "212",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "下边的秤最多能称( )重的物体.\n![](images/63d6a342db1965e787e0a667cd7ac5ac84e0dd25e4fb0b2a4c3e61be6f820b2b.jpg)",
+        "options":  [
+                        "A. 5克",
+                        "B. 5千克",
+                        "C. 500克",
+                        "D. 50千克"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】这台称的单位是\"千克\"，最大数值是5，表示这台秤最多能称5千克的物体。\n\n【详解】据分析得：下边的秤最多能称5千克的物体。故答案为:B",
+        "knowledge_points":  [
+                                 "克，千克之间的换算与比较，千克的认识，克的认识"
+                             ],
+        "source":  "23-24 二年级下·广东揭阳·期末"
+    },
+    {
+        "id":  "213",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "下列物品中,( )的质量用\"千克\"作单位比较合适。",
+        "options":  [
+                        "A. 一颗葡萄",
+                        "B. 一块面包",
+                        "C. 一桶水",
+                        "D. 一部手机"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】根据生活经验，对质量单位和数据大小的认识可知：计量比较轻的物体，常用克作单位,2个曲别针约重1克，计量比较重的物体，常用千克作单位,2袋白砂糖约重1千克，由此解答。\n\n【详解】A。一颗葡萄的质量较轻，用克作单位比较合适，不符合题意;B。一块面包的质量较轻，用克作单位比较合适，不符合题意;C。一桶水的质量较重，用千克作单位比较合适，符合题意;D。一部手机的质量较轻，用克作单位比较合适，不符合题意。则一桶水的质量用\"千克\"作单位比较合适。故答案为:C",
+        "knowledge_points":  [
+                                 "质量单位的选择，千克的认识，克的认识"
+                             ],
+        "source":  "23-24 二年级下·福建龙岩·期末"
+    },
+    {
+        "id":  "214",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "4箱苹果共重24千克，平均每箱重( )。",
+        "options":  [
+                        "A. 6000千克",
+                        "B. 6000克",
+                        "C. 600克"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】求平均每箱重多少克，就是求把24千克平均分成4份，每份是多少，先算24÷4=6(千克),再根据1千克=1000克，换算单位，即6千克=6000克，即可解答。\n\n【详解】24÷4=6(千克),6千克=6000克，平均每箱重6000克。故答案为:B",
+        "knowledge_points":  [
+                                 "克，千克之间的换算与比较"
+                             ],
+        "source":  "23-24 二年级下·浙江嘉兴·期末"
+    },
+    {
+        "id":  "215",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "适合用\"千克\"作单位的是( )。",
+        "options":  [
+                        "A. 爸爸的体重",
+                        "B. 一包海苔",
+                        "C. 一个鸡蛋"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】1千克大约为两瓶矿泉水的重量,1克大约为一枚硬币的重量，克用来形容较轻的物体质量，千克用来形容较重的物体质量。\n\n【详解】A。爸爸的体重较重，适合用\"千克\"作单位;B。一包海苔较轻，适合用\"克\"作单位;C。一个鸡蛋较轻，适合用\"克\"作单位。适合用\"千克\"作单位的是：爸爸的体重。故答案为:A",
+        "knowledge_points":  [
+                                 "质量单位的选择，千克的认识，克的认识"
+                             ],
+        "source":  "23-24 二年级下·河南南阳·期末"
+    },
+    {
+        "id":  "216",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "一个鸡蛋的质量约为( )。",
+        "options":  [
+                        "A. 500克",
+                        "B. 50克",
+                        "C. 50千克"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】计量比较轻的物体，常用克作单位,2个曲别针约重1克，计量比较重的物体，常用千克作单位,2小袋食盐重1千克。据此解答。\n\n【详解】由分析可得：一个鸡蛋属于比较轻的物体应该用克做单位，结合数据应该是50克。故答案为:B",
+        "knowledge_points":  [
+                                 "质量单位的选择，千克的认识，克的认识"
+                             ],
+        "source":  "23-24 二年级下·浙江·期末"
+    },
+    {
+        "id":  "217",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "一袋奶重200克,( )袋奶重1千克。",
+        "options":  [
+                        "A. 3",
+                        "B. 4",
+                        "C. 5"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】根据1千克=1000克，用1000-200算出答案后再减去200，减到答案为0时，数出一共减去了多少个200就代表有多少袋牛奶能重1千克。\n\n【详解】1000-200=800,800-200=600,600-200=400,400-200=200,200-200=0，数得一共减去了5个200，所以一袋奶重200克,5袋奶重1千克。故答案为:C",
+        "knowledge_points":  [
+                                 "克，千克之间的换算与比较，整百数，几百几十数的加减法口算"
+                             ],
+        "source":  "23-24 二年级下·河南漯河·期末"
+    },
+    {
+        "id":  "218",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "50千克的棉花和50千克的铁相比,( )。",
+        "options":  [
+                        "A. 50千克的棉花重",
+                        "B. 50千克的铁重",
+                        "C. 一样重",
+                        "D. 无法比较"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】比较物体的轻重，与什么样的物体无关，与物体本身的轻重有关。棉花和铁都是50千克，所以一样重。\n\n【详解】根据分析可得:50千克的棉花和50千克的铁相比，一样重。故答案为:C",
+        "knowledge_points":  [
+                                 "千克的认识"
+                             ],
+        "source":  "23-24 二年级下·福建龙岩·期末"
+    },
+    {
+        "id":  "219",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "小明的体重大约是( )。",
+        "options":  [
+                        "A. 20克",
+                        "B. 20千克",
+                        "C. 2千克"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】根据生活经验，对质量单位和数据大小的认识可知：计量比较轻的物体，常用克作单位,2个曲别针约重1克;计量比较重的物体，常用千克作单位,2袋白砂糖约重1千克;由此解答。\n\n【详解】A。20克大约为1颗杏子的重量，不符合题意;B。20千克符合小明的体重;C。2千克大约为1个哈密瓜的重量，不符合题意。则小明的体重大约是20千克。故答案为:B",
+        "knowledge_points":  [
+                                 "质量的估计"
+                             ],
+        "source":  "23-24二年级下·天津河东·期末"
+    },
+    {
+        "id":  "220",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "我可以填上合适的单位名称.\n一只成年鸵鸟约重130( ),它的一个蛋约重1500( )。",
+        "options":  [
+
+                    ],
+        "answer":  "千克或kg;克或g",
+        "solution":  "【分析】根据情景选择合适的计量单位，要注意联系生活实际，计量单位和数据的大小，灵活的选择。1千克大约为两瓶矿泉水的重量，计量一只成年鸵鸟的重量用\"千克\"作单位比较合适。1克大约为一枚硬币的重量，计量一个鸵鸟蛋的重量用\"克\"作单位比较合适。\n\n【详解】一只成年鸵鸟约重130千克，它的一个蛋约重1500克。",
+        "knowledge_points":  [
+                                 "克的认识，千克的认识，质量单位的选择"
+                             ],
+        "source":  "24-25 二年级下·广东广州·期末"
+    },
+    {
+        "id":  "221",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "填合适的单位:8个鸡蛋约重400( ),一只公鸡约重3( )。",
+        "options":  [
+
+                    ],
+        "answer":  "克或g;千克或kg",
+        "solution":  "【分析】根据情景选择合适的计量单位，要注意联系生活实际，计量单位和数据的大小，灵活的选择。1克大约为一枚硬币的重量，鸡蛋比较轻，计量8个鸡蛋的重量用\"克\"作单位比较合适。1千克大约为两瓶矿泉水的重量，公鸡较重，计量一只公鸡的重量用\"千克\"作单位比较合适。\n\n【详解】填合适的单位:8个鸡蛋约重400克，一只公鸡约重3千克。",
+        "knowledge_points":  [
+                                 "质量单位的选择，千克的认识，克的认识"
+                             ],
+        "source":  "24-25 二年级下·湖北武汉·期末"
+    },
+    {
+        "id":  "222",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "一个鸡蛋约重50克,( )个鸡蛋约重500克,( )个鸡蛋约重1千克。每500克鸡蛋6元，妈妈买3千克鸡蛋，需要( )元。",
+        "options":  [
+
+                    ],
+        "answer":  "10;20;36",
+        "solution":  "【分析】根据题意,1千克=1000克，求几个鸡蛋重500克，就是求500里面有几个50克,500克+500克=1000克=1千克,500克鸡蛋是6元,3千克鸡蛋多少钱，先求出3千克里面有几个500克，有几个500克就是有几个6元，据此解答。\n\n【详解】根据分析:10个50是500;1千克=1000克=500克+500克，一个500里面有10个50，两个500里面有20个50.3千克=3000克=500克+500克+500克+500克+500克+500克,3千克里面有6个500克,6×6=36(元),一个鸡蛋约重50克,(10)个鸡蛋约重500克,(20)个鸡蛋约重1千克。每500克鸡蛋6元，妈妈买3千克鸡蛋，需要(36)元。",
+        "knowledge_points":  [
+                                 "克，千克之间的换算与比较"
+                             ],
+        "source":  "24-25 二年级下·湖北武汉·期末"
+    },
+    {
+        "id":  "223",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在括号里填上\"\u003e\"\"\u003c\"或\"=\".\n4687( )487642克( )2千克 15÷3×6( )7\n982( )1001301千克( )320克 860-600( )860-60",
+        "options":  [
+
+                    ],
+        "answer":  "\u003c;\u003c;\u003e;\u003c;\u003e;\u003c",
+        "solution":  "【分析】根据1千克=1000克，把单位换算统一后再比较大小;含有算式，先计算出左右两边的结果，再比较大小;整数比较大小方法:①位数多的数大于位数少的数;②位数相同的，先比较最高位上的数，最高位上大的，数就大，最高位数相同的，就比较下一位，以此类推。\n\n【详解】比较两个四位数，千位相同，百位6\u003c8，故4687\u003c4876;1千克=1000克,2千克=2000克,42克\u003c2000克，故42克\u003c2千克;15÷3=5,5×6=30,30\u003e7，故15÷3×6\u003e7;982是三位数,1001是四位数，三位数小于四位数，故982\u003c1001;301千克\u003e1千克,1千克=1000克,1000克\u003e320克，故301千克\u003e320克;860-600=260,860-60=800,260\u003c800，故860-600\u003c860-60。",
+        "knowledge_points":  [
+                                 "克，千克之间的换算与比较，表内乘除混合运算，整百数，几百几十数的加减法口算，万以内数的大小比较"
+                             ],
+        "source":  "24-25 二年级下·山西晋中·期末"
+    },
+    {
+        "id":  "224",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在括号里填上适当的质量单位.\n一支铅笔重10( ) 一袋面粉重25( ) 一个鸡蛋重50( )",
+        "options":  [
+
+                    ],
+        "answer":  "克或g;千克或kg;克或g",
+        "solution":  "【分析】根据生活经验，对质量单位和数据大小的认识来解决此题。表示较重的物体时，一般用\"千克\"作单位;一袋面粉重属于比较重的，故，表示一袋面粉重用\"千克\"作单位比较合适。表示较轻的物体时，一般用\"克\"作单位;一支铅笔重和一个鸡蛋重属于比较轻的，故，表示一支铅笔重和一个鸡蛋重用\"克\"作单位比较合适。\n\n【详解】由题意分析得：一支铅笔重10克;一袋面粉重25千克;一个鸡蛋重50克。",
+        "knowledge_points":  [
+                                 "质量单位的选择"
+                             ],
+        "source":  "24-25二年级下·河南新乡·期末"
+    },
+    {
+        "id":  "225",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "![](images/741979071f71b11b6d0fd14ad0f0805f.png)\n\n1个鸭梨和( )个玻璃球同样重;1个蜜桃和( )个玻璃球同样重。一个鸭梨比1个蜜桃( )。(填\"重\"或\"轻\")",
+        "options":  [
+
+                    ],
+        "answer":  "9;7;重",
+        "solution":  "【分析】由图可知,1个鸭梨和9个玻璃球一样重;1个蜜桃和7个玻璃球一样重;每个玻璃球的重量是相同的，则比较玻璃球的数量，玻璃球越多，则这个物体越重。\n\n【详解】9\u003e7,1个鸭梨和9个玻璃球同样重;1个蜜桃和7个玻璃球同样重。一个鸭梨比1个蜜桃重。",
+        "knowledge_points":  [
+                                 "比轻重"
+                             ],
+        "source":  "24-25 二年级下·河北石家庄·期中"
+    },
+    {
+        "id":  "226",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在( )里填上合适的单位.\n一支铅笔长约18( )。 一棵大树高约10( )。 小明的体重约30( )。",
+        "options":  [
+
+                    ],
+        "answer":  "厘米或cm;米或m;千克或kg",
+        "solution":  "【分析】根据生活经验，对长度单位，质量单位认识可知,1米大约为小学生双臂伸展开的长度;1分米大约手掌的宽度;1厘米大约指甲盖的宽度，两瓶矿泉水重量大约是1千克。\n\n【详解】1厘米大约是指甲盖的宽度，所以计量铅笔的长度用\"厘米\"作单位比较合适，则一支铅笔长约18厘米;小学生双臂展开的长度大约是1米，所以计量大树的高度用\"米\"作单位比较合适，则一棵大树高约10米;两瓶矿泉水重量大约是1千克，所以计量小明的体重用\"千克\"作单位比较合适，则小明的体重约30千克。",
+        "knowledge_points":  [
+                                 "长度单位的选择，厘米的认识，质量单位的选择，千克的认识"
+                             ],
+        "source":  "24-25 二年级下·黑龙江佳木斯·期中"
+    },
+    {
+        "id":  "227",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "在括号里填上\"\u003e\"\"\u003c\"或\"=\".\n998( )1000300克( )2千克 7×5( )35÷7又63÷7×6( )64÷8×76千克( )5999克",
+        "options":  [
+
+                    ],
+        "answer":  "\u003c;\u003c;\u003e;\u003c;\u003e;\u003e",
+        "solution":  "【分析】整数的大小比较：比较数的大小，先看位数的多少，位数多的数就大;位数相同，从高位开始比较，高位上的数大则这个数大，高位上的数相同，就比较下一位。含有算式的，可以先计算出算式的结果，再比较大小;单位不统一时，先化成相同单位，再比较大小。1千克=1000克。\n\n【详解】998\u003c1000;2千克=2000克,300\u003c2000，则300克\u003c2千克;7×5=35,35÷7=5,35\u003e5，则7×5\u003e35÷7;63÷7×6=54,64÷8×7=56,54\u003c56，则63÷7×6\u003c64÷8×7;6千克=6000克,6000\u003e5999，则6千克\u003e5999克。",
+        "knowledge_points":  [
+                                 "克，千克之间的换算与比较，表内乘除混合运算,7的乘法口诀及应用，万以内数的大小比较"
+                             ],
+        "source":  "23-24 二年级下·河南漯河·期末"
+    },
+    {
+        "id":  "228",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "在括号里填上\"\u003e\"\"\u003c\"或\"=\".\n1100( )10016千克+30克( )6300克 7000克( )7千克\n4004( )44012÷3×4( )12÷4×363-9( )7",
+        "options":  [
+
+                    ],
+        "answer":  "\u003e;\u003c;=;\u003e;\u003e;\u003e",
+        "solution":  "【分析】比较数的大小时，位数多的数就大，位数相同比较最高位，最高位大的数就大，最高位相同比较下一位，直到比较出结果为止。第1,4题直接比较;第2,3题根据1千克=1000克统一单位再比较;第5,6题计算出结果再比较，只有乘除法的混合运算，从左往右计算。\n\n【详解】12÷3×4=4×4=16,12÷4×3=3×3=9,16\u003e9，则12÷3×4\u003e12÷4×3;63-9=54;54\u003e7，则63-9\u003e7。",
+        "knowledge_points":  [
+                                 "克，千克之间的换算与比较，表内乘除混合运算，万以内数的大小比较"
+                             ],
+        "source":  "23-24 二年级下·黑龙江佳木斯·期末"
+    },
+    {
+        "id":  "229",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "比一比。(填\"\u003e\"\"\u003c\"或\"=\")\n3500克( )4千克 5×8+5( )406×4÷3( )8",
+        "options":  [
+
+                    ],
+        "answer":  "\u003c;\u003e;=",
+        "solution":  "【分析】第1题，根据1千克=1000克，变换单位后再比较大小;第2题，第3题，根据混合运算的计算法则，先计算结果再比较大小，据此解答。\n\n【详解】4千克=4000克,3500克\u003c4000克，故3500克\u003c4千克;5×8=40,40+5=45,45\u003e40，故5×8+5\u003e40;6×4=24,24÷3=8,8=8，故6×4÷3=8。",
+        "knowledge_points":  [
+                                 "表内乘加，乘减，克，千克之间的换算与比较，表内乘除混合运算，万以内数的大小比较"
+                             ],
+        "source":  "24-25 二年级下·山西晋中·期末"
+    },
+    {
+        "id":  "230",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在括号里填上\"\u003e\"\"\u003c\"或\"=\".\n503( )3051000( )9996分米( )60厘米\n8分米( )8米 70千克( )700克 40秒( )1分",
+        "options":  [
+
+                    ],
+        "answer":  "\u003e;\u003e;=;\u003c;\u003e;\u003c",
+        "solution":  "【分析】整数的大小比较：比较数的大小，先看数位的多少，数位多的数就大;位数相同，从高位开始比较，高位上的数大则这个数大，高位上的数相同，就比较下一位，需要单位换算的先统一单位，再比较大小。\n\n【详解】百位上的数字5\u003e3，因此503大于305，所以503\u003e305.1000比999大1，因此1000\u003e999.1分米=10厘米，因此6分米=60厘米，两者相等，所以6分米=60厘米。1米=10分米，因此8米=80分米,8分米\u003c80分米，所以8分米\u003c8米。1千克=1000克，因此70千克=70000克,70000克\u003e700克，所以70千克\u003e700克。1分=60秒，因此40秒\u003c60秒，所以40秒\u003c1分。",
+        "knowledge_points":  [
+                                 "毫米，厘米，分米，米之间的进率与换算，克，千克之间的换算与比较，时，分，秒之间的换算与比较"
+                             ],
+        "source":  "23-24 二年级下·河北邢台·期末"
+    },
+    {
+        "id":  "231",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "在括号填上合适的单位.\n(1)旗杆高约13( )。 (2)一张数学试卷重约4( )。 (3)一袋大米重30( )。 (4)课桌高80( )。",
+        "options":  [
+
+                    ],
+        "answer":  "米或m 克或g 千克或kg 厘米或cm",
+        "solution":  "【分析】(1)(4)根据生活经验以及对长度单位和数据大小的认识，量比较短的物体的长度，通常用厘米作单位。食指的宽大约是1厘米，所以计量课桌的高度用\"厘米\"作单位比较合适。量比较长的物体，通常用米作单位。二年级学生双臂展开的长度大约是1米，所以计量旗杆高度用\"米\"作单位比较合适。(2)(3)根据生活经验以及对质量单位和数据大小的认识，量比较轻的物体的质量，通常用克作单位，一粒花生米的质量大约是1克，所以计量一张数学试卷的质量用\"克\"作单位。量比较重的物体的质量，通常用千克作单位。所以计量一袋大米的质量用\"千克\"作单位。\n\n【详解】(1)旗杆高约13米(或m);(2)一张数学试卷重约4克(或g);(3)一袋大米重30千克(或kg);(4)课桌高80厘米(或cm)。",
+        "knowledge_points":  [
+                                 "米的认识，厘米的认识，千克的认识，克的认识"
+                             ],
+        "source":  "23-24 二年级下·云南曲靖·期末"
+    },
+    {
+        "id":  "232",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在括号里填上合适的单位.\n一只鸡重2( )。 一支铅笔长18( )。",
+        "options":  [
+
+                    ],
+        "answer":  "千克或kg;厘米或cm",
+        "solution":  "【分析】计量比较重的物品，通常用\"千克\"作单位,2袋食盐重1千克，根据生活经验可知一只鸡的重量用千克作单位比较合适;大拇指指甲盖的宽度大约是1厘米，一支铅笔长大约18个大拇指指甲盖宽，因此一支铅笔长18厘米。\n\n【详解】一只鸡重2(千克)。一支铅笔长18(厘米)。",
+        "knowledge_points":  [
+                                 "长度单位的选择，厘米的认识，质量单位的选择，千克的认识"
+                             ],
+        "source":  "23-24二年级下·甘肃天水·期末"
+    },
+    {
+        "id":  "233",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "在括号里填上\"\u003e\"\"\u003c\"或\"=\".\n800克+300克( )1千克 1800克-900克( )1080克\n18÷3/2( )18÷(3×2) 7000+700+70( )7077",
+        "options":  [
+
+                    ],
+        "answer":  "\u003e;\u003c;=;\u003e",
+        "solution":  "【分析】比较数的大小时，位数多的数就大，位数相同比较最高位，最高位大的数就大，最高位相同比较下一位，直到比较出结果为止。第1,2题根据1千克=1000克统一单位再比较;第3题：左侧算式从左往右计算;右侧算式先算乘法，再算除法;计算出结果再比较;第4题：计算出结果再比较。\n\n【详解】800克+300克=1100克;1千克=1000克;1100克\u003e1000克，则800克+300克\u003e1千克;1800克-900克=900克;900克\u003c1080克，则1800克-900克\u003c1080克;18÷3/2=6÷2=3,18÷(3×2)=18÷6=3,3=3，则18÷3/2=18÷(3×2);7000+700+70=7770;7770\u003e7077，则7000+700+70\u003e7077。",
+        "knowledge_points":  [
+                                 "万以内数的大小比较，表内连乘，连除运算，带有小括号的混合运算，克，千克之间的换算与比较"
+                             ],
+        "source":  "23-24 二年级下·广东揭阳·期末"
+    },
+    {
+        "id":  "234",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "填上适当的单位.\n一个苹果大约是300( );一个西瓜大约是4( );王强的体重大约是35( );一只鸭子重2000( )。",
+        "options":  [
+
+                    ],
+        "answer":  "克或g;千克或kg;千克或kg;克或g",
+        "solution":  "【分析】根据生活经验，对质量单位和数据大小的认识可知：计量比较轻的物体，常用克作单位,2个曲别针约重1克，所以一个苹果大约重300克;一只鸭子重2000克;计量比较重的物体，常用千克作单位,2袋白砂糖约重1千克，所以一个西瓜约重4千克;王强体重约35千克。\n\n【详解】由分析得：一个苹果大约是300克(g);一个西瓜大约是4千克(kg);王强的体重大约是35千克(kg);一只鸭子重2000克(g)。",
+        "knowledge_points":  [
+                                 "质量单位的选择，千克的认识，克的认识"
+                             ],
+        "source":  "24-25 二年级下·河南漯河·期末"
+    },
+    {
+        "id":  "235",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "请在括号里填上合适的单位和数字.\n小明的身高是130( ),体重是30( ),他的水杯重500( ).\n400克+600克=( )千克 9000克-5千克=( )千克",
+        "options":  [
+
+                    ],
+        "answer":  "厘米或cm;千克或kg;克或g;1;4",
+        "solution":  "【分析】根据对生活经验，长度单位，重量单位和数据大小的认识可知;1厘米大约是食指的宽度，所以计量小明的身高用\"厘米\"作单位比较合适;2袋白糖约重1千克，所以计量小明的体重用\"千克\"作单位比较合适;1枚1分的硬币约重1克，所以计量水杯重用\"克\"作单位比较合适;根据1千克=1000克，统一单位后，结合题干要求进行解答。\n\n【详解】小明的身高是130厘米，体重是30千克，他的水杯重500克。400克+600克=1000克,1000克=1千克，故400克+600克=1千克;9000克-5千克=9千克-5千克=4千克，故9000克-5千克=4千克。",
+        "knowledge_points":  [
+                                 "长度单位的选择，质量单位的选择，克，千克之间的换算与比较，千克的认识"
+                             ],
+        "source":  "23-24二年级下·浙江台州·期末"
+    },
+    {
+        "id":  "236",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在括号里填上\"\u003e\"\"\u003c\"或\"=\".\n6200( )6202300克( )3千克 70-53( )70-35",
+        "options":  [
+
+                    ],
+        "answer":  "\u003c;\u003c;\u003c",
+        "solution":  "【分析】整数比较大小：先看位数的多少，位数多的数大;位数相同，从最高位比起，最高位上的数大这个数就大，若最高位上的数相同，就比较下一位，依次类推，直到比出大小。单位不统一的，根据\"1千克=1000克\"统一单位再比较大小;有算式的，先计算出结果再比较大小。\n\n【详解】6200\u003c6202;3千克=3000克,300克\u003c3000克，所以300克\u003c3千克;70-53=17,70-35=35,17\u003c35，所以70-53\u003c70-35。",
+        "knowledge_points":  [
+                                 "吨，千克之间的换算与比较，两位数与两位数的退位减法，万以内数的大小比较"
+                             ],
+        "source":  "23-24二年级下·天津河北·期末"
+    },
+    {
+        "id":  "237",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在括号里填上\"\u003e\"\"\u003c\"或\"=\".\n1800-700( )120048÷8( )36/64千克( )3900克",
+        "options":  [
+
+                    ],
+        "answer":  "\u003c;=;\u003e",
+        "solution":  "【分析】有算式先算出算式的得数，再进行比较大小即可。根据1千克=1000克，先将单位统一，再进行比较大小。万以内数的大小比较方法：先看位数，位数多的大于位数少的;位数相同，先比较最高位上的数，最高位上的数大的那个数就大;如果最高位上的数相同，再比较下一位上的数，以此类推，直到比较出大小。\n\n【详解】1800-700=1100,1100\u003c1200，所以1800-700\u003c1200;48÷8=6,36÷6=6，所以48÷8=36÷6;4千克=4000克,4000克\u003e3900克，所以4千克\u003e3900克。",
+        "knowledge_points":  [
+                                 "克，千克之间的换算与比较，用7~9的乘法口诀求商，整百数，几百几十数的加减法口算，万以内数的大小比较"
+                             ],
+        "source":  "24-25 二年级下·山东济宁·期末"
+    },
+    {
+        "id":  "238",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在括号里填上\"\u003c\"\"\u003e\"或\"=\".\n4701( )47108( )56÷83千克( )2900克 1千克( )200克+800克",
+        "options":  [
+
+                    ],
+        "answer":  "\u003c;\u003e;\u003e;=",
+        "solution":  "【分析】有算式先算出算式得数，再根据整数比较大小的方法：比较两个整数的大小，要先看它们的位数，如果位数不同，位数多的数就大;如果位数相同，则从高位开始比较，相同数位上的数大的那个数就大。根据1千克=1000克，将单位统一，再进行比较大小即可。\n\n【详解】4701\u003c4710;56÷8=7,8\u003e7，所以8\u003e56÷8;3千克=3000克,3000克\u003e2900克，所以3千克\u003e2900克;200克+800克=1000克,1000克=1千克，所以1千克=200克+800克。",
+        "knowledge_points":  [
+                                 "克，千克之间的换算与比较，用7~9的乘法口诀求商，万以内数的大小比较"
+                             ],
+        "source":  "23-24 二年级下·广东广州·期末"
+    },
+    {
+        "id":  "239",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在括号填上合适的单位.\n世界上最小的鸟是蜂鸟，大约重2( ),最大的鸟是鸵鸟，大约重150( )。",
+        "options":  [
+
+                    ],
+        "answer":  "克或g;千克或kg",
+        "solution":  "【分析】根据生活经验以及对质量单位和数据大小的认识,1张普通的A4纸的质量大约是1克，所以计量蜂鸟的质量用\"克\"做单位比较合适。1瓶矿泉水大约重500克,2瓶矿泉水大约重1千克，所以计量鸵鸟的质量用\"千克\"做单位比较合适。\n\n【详解】世界上最小的鸟是蜂鸟，大约重2克;最大的鸟是鸵鸟，大约重150千克。",
+        "knowledge_points":  [
+                                 "克的认识，千克的认识，质量单位的选择"
+                             ],
+        "source":  "22-23 二年级下·新疆乌鲁木齐·期末"
+    },
+    {
+        "id":  "240",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在括号里填上\"千克\"或\"克\".\n9岁的乐乐体重约30( ),早上，他吃了一个重约300( )的汉堡包，背着重约3( )的书包去上学。",
+        "options":  [
+
+                    ],
+        "answer":  "千克或kg;克或g;千克或kg",
+        "solution":  "【分析】根据生活经验以及对质量单位和数据大小的认识,1瓶矿泉水大约重500克,2瓶矿泉水大约重1千克，所以计量乐乐的体重和书包的质量用\"千克\"做单位比较合适;1张普通的A4纸大约是1克，所以计量一个汉堡包的质量用\"克\"做单位比较合适，据此结合实际情况判断即可。\n\n【详解】9岁的乐乐体重约30(千克),早上，他吃了一个重约300(克)的汉堡包，背着重约3(千克)的书包去上学。",
+        "knowledge_points":  [
+                                 "质量单位的选择，千克的认识，克的认识"
+                             ],
+        "source":  "24-25二年级下·广西玉林·期末"
+    },
+    {
+        "id":  "241",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "在括号里填上合适的数.\n苹果每千克8元，妈妈买了2970克苹果，大约要付( )元钱。",
+        "options":  [
+
+                    ],
+        "answer":  "24",
+        "solution":  "【分析】根据题意，先将妈妈买苹果的重量看成与之接近的整克数，再根据1千克=1000克换算单位，最后和每千克苹果的钱数相乘即可。\n\n【详解】2970克接近3000克,3000克=3千克,8×3=24(元),苹果每千克8元，妈妈买了2970克苹果，大约要付24元钱。",
+        "knowledge_points":  [
+                                 "克，千克之间的换算与比较，万以内数的估计"
+                             ],
+        "source":  "23-24 二年级下·浙江·期末"
+    },
+    {
+        "id":  "242",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "在括号里填上合适的数.\n公鸡每千克9元，买一只重2980克的公鸡大约要付( )元。",
+        "options":  [
+
+                    ],
+        "answer":  "27",
+        "solution":  "【分析】2980克接近3000克，根据\"1千克=1000克\"把3000克换算成3千克，公鸡每千克9元，然后用乘法求出3个9的和是多少，就是买这只公鸡大约要付的钱数。\n\n【详解】2980克接近3000克,3000克=3千克;9×3=27(元)即，公鸡每千克9元，买一只重2980克的公鸡大约要付27元。",
+        "knowledge_points":  [
+                                 "克，千克之间的换算与比较,9的乘法口诀及应用，万以内数的估计"
+                             ],
+        "source":  "23-24 二年级下·广东东莞·期末"
+    },
+    {
+        "id":  "243",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在括号里填上合适的数或单位.\n小东和妈妈去超市购物。小东买了一支画笔长20( ),妈妈买了一盒工克力重240( ),4个248克的苹果约重( )千克，一袋大米重10( )。",
+        "options":  [
+
+                    ],
+        "answer":  "厘米或cm;克或g;1 千克或kg",
+        "solution":  "【分析】根据情景选择合适的计量单位，要注意联系生活实际，计量单位和数据的大小，灵活的选择。大拇指的指甲长度大约1厘米，计量画笔的长度用\"厘米\"作单位比较合适。1克大约为一枚硬币的重量，计量一盒巧克力的重量用\"克\"作单位比较合适。248大约是250，将4个250相加，然后换算成千克作单位,1000克=1千克。1千克大约为两瓶矿泉水的重量，计量一袋大米的重量用\"千克\"作单位比较合适。\n\n【详解】250+250+250+250=1000(克),1000克=1千克，小东和妈妈去超市购物。小东买了一支画笔长20厘米，妈妈买了一盒工克力重240克,4个248克的苹果约重1千克，一袋大米重10千克。",
+        "knowledge_points":  [
+                                 "长度单位的选择，质量单位的选择"
+                             ],
+        "source":  "23-24 二年级下·福建莆田·期末"
+    },
+    {
+        "id":  "244",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在括号里填上合适的数或单位.\n依依非常喜欢小动物。她养了一只3( )的兔子，每天要吃200( )的兔粮。她还养了一只小猫，出生时体重只有80( ),现在已经长到2( )了。(填\"克\"或\"千克\")",
+        "options":  [
+
+                    ],
+        "answer":  "千克;克;克;千克",
+        "solution":  "【分析】根据生活经验，对质量单位和数据大小的认识可知：计量比较轻的物体，常用克作单位,2个曲别针约重1克，所以兔子每天吃兔粮的量用克作单位比较合适;小猫刚出生的重量用克作单位比较合适;计量比较重的物体，常用千克作单位,2袋白砂糖约重1千克，所以兔子的重量用千克作单位比较合适;小猫现在的重量用千克作单位比较合适。\n\n【详解】依依非常喜欢小动物。她养了一只3千克的兔子，每天要吃200克的兔粮。她还养了一只小猫，出生时体重只有80克，现在已经长到2千克了。",
+        "knowledge_points":  [
+                                 "质量单位的选择"
+                             ],
+        "source":  "23-24 二年级下·湖南长沙·期末"
+    },
+    {
+        "id":  "245",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "在括号里填上\"\u003e\"\"\u003c\"或\"=\".\n5003克( )5千克 10个一千( )一万 1300克+800克( )2千克",
+        "options":  [
+
+                    ],
+        "answer":  "\u003e;=;\u003e",
+        "solution":  "【分析】比较数的大小时，位数多的数就大，位数相同比较最高位，最高位相同比较下一位，直到比较出结果为止。第1,3题根据1千克=1000克统一单位再比较;第2题，几个千就是几千，几十个千就是几万，由此写出数字再比较。\n\n【详解】5千克=5000克;5003克\u003e5000克，则5003克\u003e5千克;10个一千是10000，一万即10000;10000=10000，则10个一千=一万;1300克+800克=2100克;2千克=2000克;2100克\u003e2000克，则1300克+800克\u003e2千克。",
+        "knowledge_points":  [
+                                 "克，千克之间的换算与比较，万以内数的大小比较，万以内数的组成"
+                             ],
+        "source":  "23-24 二年级下·湖南岳阳·期末"
+    },
+    {
+        "id":  "246",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "在括号里填上\"\u003e\"\"\u003c\"或\"=\".\n36个百( )3个千和6个百 6900克( )7千克 5500克-500克( )5千克",
+        "options":  [
+
+                    ],
+        "answer":  "=;\u003c;=",
+        "solution":  "【分析】几个千就是几千，几个百就是几百，几十个百是几千，据此组数。1000克=1千克，将单位统一后再比较。整数的大小比较：比较数的大小，先看位数的多少，位数多的数就大;位数相同，从高位开始比较，高位上的数大则这个数大，高位上的数相同，就比较下一位。\n\n【详解】36个百是3600,3个千和6个百是3600，则36个百=3个千和6个百。7千克=7000克,6900克\u003c7000克，则6900克\u003c7千克。5500克-500克=5000克=5千克，则5500克-500克=5千克。",
+        "knowledge_points":  [
+                                 "克，千克之间的换算与比较，万以内数的大小比较，万以内数的组成"
+                             ],
+        "source":  "23-24 二年级下·福建龙岩·期末"
+    },
+    {
+        "id":  "247",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在括号里填上适当的单位.\n一个火龙果重约500( ) 一个袋大米重约6( ) 小明身高120( )",
+        "options":  [
+
+                    ],
+        "answer":  "克或g;千克或kg;厘米/cm",
+        "solution":  "【分析】计量较轻物体的重量用\"克\"作单位，一粒花生米的重量大约是1克，因此计量火龙果的重量用\"克\"作单位比较合适;计量较重物体的重量用\"千克\"作单位，两包食盐的重量大约是1千克，因此计量一袋大米的重量用\"千克\"作单位比较合适;大拇指的宽度大约是1厘米，人的身高一般在一百多厘米，所以小明的身高用\"厘米\"作单位比较合适。\n\n【详解】由分析可知：一个火龙果重约500(克);一个袋大米重约6(千克);小明身高120(厘米)。",
+        "knowledge_points":  [
+                                 "长度单位的选择，质量单位的选择"
+                             ],
+        "source":  "23-24 二年级下·福建龙岩·期末"
+    },
+    {
+        "id":  "248",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "一枚2分硬币约重1克,4枚2分硬币约重( )克。",
+        "options":  [
+
+                    ],
+        "answer":  "4",
+        "solution":  "【分析】将每枚2分硬币的质量相加即可求解。\n\n【详解】1+1+1+1=4(克),一枚2分硬币约重1克,4枚2分硬币约重4克。",
+        "knowledge_points":  [
+                                 "克的认识"
+                             ],
+        "source":  "23-24 二年级下·河南许昌·期末"
+    },
+    {
+        "id":  "249",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "在括号填上\"\u003e\"\"\u003c\"或\"=\".\n8056( )80651000克( )1000千克 7×3( )7+7+7\n10000( )99995千克( )4900克 54÷6( )18/3+3",
+        "options":  [
+
+                    ],
+        "answer":  "\u003c;\u003c;=;\u003e;\u003e;=",
+        "solution":  "【分析】整数的大小比较：比较数的大小，先看位数的多少，位数多的数就大;位数相同，从高位开始比较，高位上的数大则这个数大，高位上的数相同，就比较下一位。含有算式的，可以先计算出算式的结果，再比较大小;1千克=1000克，单位不统一时，先化成相同单位，再比较大小。\n\n【详解】千位，百位相同，十位5\u003c6，故8056\u003c8065.1000克=1千克,1千克\u003c1000千克，故1000克\u003c1000千克。7×3=21,7+7+7=21，两边相等，故7×3=7+7+7.10000是五位数,9999是四位数，位数多的数更大，故10000\u003e9999.5千克=5000克,5000克\u003e4900克，故5千克\u003e4900克。54÷6=9,18÷3+3=6+3=9，两边结果相等，故54÷6=18÷3+3。",
+        "knowledge_points":  [
+                                 "克，千克之间的换算与比较，除加，除减混合运算，用7~9的乘法口诀求商，万以内数的大小比较"
+                             ],
+        "source":  "23-24 二年级下·浙江台州·期末"
+    },
+    {
+        "id":  "250",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "在( )里填上\"\u003e\"\"\u003c\"或\"=\".\n7千克( )7000克 50千克( )50克 (27÷9)千克( )3千克\n5970( )95704÷1( )356/8( )8",
+        "options":  [
+
+                    ],
+        "answer":  "=;\u003e;=;\u003c;\u003e;\u003c",
+        "solution":  "【分析】根据题意，先统一单位或先计算出结果，然后比较大小即可。1千克=1000克;整数比较大小方法：位数多的数大于位数少的数;位数相同的，先比较最高位上的数，最高位上大的，数就大，最高位数相同的，就比较下一位，以此类推;有算式的，先计算算式的结果，再进行答题即可。\n\n【详解】根据分析可知:1千克=1000克,7千克=7000克;50千克=50000克,50000克\u003e50克,50千克\u003e50克;27÷9=3,(27÷9)千克=3千克;5970\u003c9570;4÷1=4,4÷1\u003e3;56÷8=7,56÷8\u003c8。",
+        "knowledge_points":  [
+                                 "克，千克之间的换算与比较，用7~9的乘法口诀求商，万以内数的大小比较"
+                             ],
+        "source":  "23-24 二年级下·福建福州·期末"
+    },
+    {
+        "id":  "251",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在( )里填上合适的单位.\n一枚鸡蛋约重60( ) 一支铅笔长18( )\n一袋大米约重20( ) 一个西瓜约重3000( )",
+        "options":  [
+
+                    ],
+        "answer":  "克或g;厘米或cm;千克或kg;克或g",
+        "solution":  "【分析】根据生活经验，对长度单位，质量单位和数据大小的认识来解决此题。表示较轻的物体时，一般用\"克\"作单位;一枚鸡蛋的重量属于较轻的，故，表示一枚鸡蛋约重用\"克\"作单位比较合适。食指宽大约是1厘米，所以，一支铅笔长用\"厘米\"作单位比较合适。表示较重的物体时，一般用\"千克\"作单位;一袋大米的重量属于较重轻的，故，表示一袋大米约重用\"千克\"作单位比较合适。一个西瓜的重量属于较重的，若是用\"千克\"作单位，应该是：一个西瓜约重3千克，也就是一个西瓜约重3000克。\n\n【详解】由分析可知：一枚鸡蛋约重60克;一支铅笔长18厘米;一袋大米约重20千克;一个西瓜约重3000克。",
+        "knowledge_points":  [
+                                 "长度单位的选择，质量单位的选择，克，千克之间的换算与比较"
+                             ],
+        "source":  "23-24 二年级下·福建福州·期末"
+    },
+    {
+        "id":  "252",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "在括号里填上\"\u003e\"\"\u003c\"或\"=\".\n3×2( )30÷68000克-3000克( )5千克\n1800+400( )2600-600 (5+35)÷5( )5+35÷5",
+        "options":  [
+
+                    ],
+        "answer":  "\u003e;=;\u003e;\u003c",
+        "solution":  "【分析】万以内数的大小比较，数位多的数大，数位相同比较最高位，最高位大的数大，最高位相同比较下一位，下位大的数大,。,以此类推，直到比较出大小为止;括号两边有算式的，要先计算出算式的结果，然后再比较大小;单位不同的要统一单位后再比较大小,1千克=1000克，据此解答。\n\n【详解】3×2=6,30÷6=5,6\u003e5,3×2(\u003e)30÷6;8000克-3000克=5000克=5千克,8000克-3000克(=)5千克;1800+400=2200,2600-600=2000,2200\u003e2000,1800+400(\u003e)2600-600;(5+35)÷5=40÷5=8,5+35÷5=5+7=12,8\u003c12,(5+35)÷5(\u003c)5+35÷5。",
+        "knowledge_points":  [
+                                 "克，千克之间的换算与比较，带有小括号的混合运算，用6的乘法口诀求商,3的乘法口诀及应用"
+                             ],
+        "source":  "23-24 二年级下·湖北省直辖县级单位·期末"
+    },
+    {
+        "id":  "253",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在括号里填上合适的单位名称.\n一瓶矿泉水重500( ) 一节数学课时间为40( )\n爸爸的身高是180( ) 妈妈的体重约为50( )",
+        "options":  [
+
+                    ],
+        "answer":  "克或g;分钟或min;厘米或cm;千克或kg",
+        "solution":  "【分析】小学生拇指指甲盖的长度大约是1厘米，爸爸的身高结合数据180用厘米作单位比较合适;一粒花生米的质量大约是1克，一瓶矿泉水的重量结合数据500用克作单位比较合适;两包食用盐的质量大约是1千克，妈妈的体重结合数据50用千克作单位比较合适;1秒大约是眨一次眼的时间，一节数学课时间结合数据40用分钟作单位比较合适，据此解答。\n\n【详解】根据分析：一瓶矿泉水重500(克);一节数学课时间为40(分钟);爸爸的身高是180(厘米);妈妈的体重约为50(千克)。",
+        "knowledge_points":  [
+                                 "长度单位的选择，质量单位的选择，时间单位的选择"
+                             ],
+        "source":  "23-24 二年级下·湖北省直辖县级单位·期末"
+    },
+    {
+        "id":  "254",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "一个鸡蛋约重50( );一只鸭子约重5( )。",
+        "options":  [
+
+                    ],
+        "answer":  "克或g;千克或kg",
+        "solution":  "【分析】根据生活经验，对质量单位和数据大小的认识可知：计量比较轻的物体，常用克作单位,2个曲别针约重1克，所以一个鸡蛋的重量用克作单位比较合适;计量比较重的物体，常用千克作单位,2袋白砂糖约重1千克，所以一只鸭子的重量用千克作单位比较合适。\n\n【详解】由分析得：一个鸡蛋约重50克(g);一只鸭子约重5千克(kg)。",
+        "knowledge_points":  [
+                                 "质量单位的选择，千克的认识，克的认识"
+                             ],
+        "source":  "23-24 二年级下·山东菏泽·期末"
+    },
+    {
+        "id":  "255",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "一个大约是100( )(括号内填\"克\"或\"千克\"),( )个这样的粽子大约是1千克。",
+        "options":  [
+
+                    ],
+        "answer":  "克;10",
+        "solution":  "【分析】根据对生活经验，重量单位和数据大小的认识可知;1枚1分的硬币约重1克，所以，要计量一个重用\"克\"作单位比较合适;一百一百地数,1个100是100,2个100是200,3个100是300。10个100是1000，再根据1000克=1千克，变换单位解答即可。\n\n【详解】一个大约是100克,10个100是1000，即10个这样的是1000克,1000克=1千克。因此，一个大约是100克,10个这样的粽子大约是1千克。",
+        "knowledge_points":  [
+                                 "质量单位的选择，克，千克之间的换算与比较，千克的认识，克的认识"
+                             ],
+        "source":  "23-24 二年级下·山西晋中·期末"
+    },
+    {
+        "id":  "256",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在括号填上合适的质量单位.\n![](images/fba660450fd72fc104293eaae468e684.png)\n苹果 250( ) 猪 100( ) 儿童牙刷 20( ) 西瓜 4( )",
+        "options":  [
+
+                    ],
+        "answer":  "克或g;千克或kg;克或g;千克或kg",
+        "solution":  "【分析】根据情景选择合适的计量单位，要注意联系生活实际，计量单位和数据的大小，灵活的选择。1克大约为一枚硬币的重量,1千克大约为两瓶矿泉水的重量，较轻的物体用\"克\"作单位，如苹果，牙刷;较重的物体用\"千克\"作单位，如猪，西瓜。\n\n【详解】苹果250克;猪100千克;儿童牙刷20克;西瓜4千克。",
+        "knowledge_points":  [
+                                 "质量单位的选择，千克的认识，克的认识"
+                             ],
+        "source":  "23-24 二年级下·河南信阳·期末"
+    },
+    {
+        "id":  "257",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在括号里填上合适的质量单位.\n![](images/0a8d5c7fc850e186adede0f902eb2f80.png)\n1( ) 100( ) 365( ) 5( )",
+        "options":  [
+
+                    ],
+        "answer":  "克或g;克或g;克或g;千克或kg",
+        "solution":  "【分析】根据生活经验，对质量单位和数据大小的认识可知：计量比较轻的物体，常用克作单位,2个曲别针约重1克，所以1角硬币的重量，一包方便面的重量，一个足球的重量，用克作单位比较合适;计量比较重的物体，常用千克作单位,2袋白砂糖约重1千克，所以一个西瓜的重量用千克作单位比较合适。\n\n【详解】由分析得:1克;100克;365克;5千克。",
+        "knowledge_points":  [
+                                 "质量单位的选择，千克的认识，克的认识"
+                             ],
+        "source":  "23-24 二年级下·湖南岳阳·期末"
+    },
+    {
+        "id":  "258",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "6000克=( )千克 5千克=( )克\n1千克-400克=( )克 9600克=( )千克( )克",
+        "options":  [
+
+                    ],
+        "answer":  "6;5000;600;9;600",
+        "solution":  "【分析】根据1千克=1000克，结合题干要求进行解答。\n\n【详解】1千克=1000克，故6000克=6千克;1千克=1000克，故5千克=5000克;1千克-400克=1000克-400克=600克;9600克=9000克+600克=9千克+600克。",
+        "knowledge_points":  [
+                                 "整百数，几百几十数的加减法口算，克，千克之间的换算与比较"
+                             ],
+        "source":  "23-24 二年级下·江西萍乡·期末"
+    },
+    {
+        "id":  "259",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "生活中，我们常用( )和( )来表示物品的质量。1袋盐重500( ),( )袋盐重1千克。",
+        "options":  [
+
+                    ],
+        "answer":  "克或g;千克或kg;克或g;2",
+        "solution":  "【分析】根据生活经验，对质量单位和数据大小的认识可知：计量比较轻的物体，常用克作单位,2个曲别针约重1克，计量比较重的物体，常用千克作单位,2袋白砂糖约重1千克。将盐的重量相加，直到结果为1千克为止,1千克=1000克，由此解答。\n\n【详解】500克+500克=1000克;1000克=1千克;生活中，我们常用克和千克来表示物品的质量。1袋盐重500克,2袋盐重1千克。",
+        "knowledge_points":  [
+                                 "克，千克之间的换算与比较，千克的认识，克的认识"
+                             ],
+        "source":  "23-24 二年级下·湖南岳阳·期末"
+    },
+    {
+        "id":  "260",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "一瓶果汁重500克,( )瓶果汁是1千克。",
+        "options":  [
+
+                    ],
+        "answer":  "2",
+        "solution":  "【分析】根据题意，将每瓶果汁的重量相加，直到结果为1千克为止，根据1千克=1000克统一单位再计算。\n\n【详解】1千克=1000克,500+500=1000(克),一瓶果汁重500克,2瓶果汁是1千克。",
+        "knowledge_points":  [
+                                 "整百数，几百几十数的加减法口算，克，千克之间的换算与比较"
+                             ],
+        "source":  "23-24 二年级下·甘肃天水·期末"
+    },
+    {
+        "id":  "261",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "在括号里填上\"\u003e\"\"\u003c\"或\"=\".\n27( )3×7-163524( )35426千克( )6000克 54÷9/2( )32+9÷3( )161千克( )999克",
+        "options":  [
+
+                    ],
+        "answer":  "\u003e;\u003c;=;=;\u003c;\u003e",
+        "solution":  "【分析】有算式先算出算式的得数，根据整数比较大小的方法：比较两个整数的大小，要先看它们的位数，如果位数不同，位数多的数就大;如果位数相同，则从高位开始比较，相同数位上的数大的那个数就大。根据1千克=1000克进行单位换算，再进行比较大小即可。\n\n【详解】3×7-16=21-16=5,21\u003e5，所以27\u003e3×7-16;3524\u003c3542;6千克=6000克;54÷9/2=6÷2=3，所以54÷9/2=3;2+9÷3=2+3=5,5\u003c16，所以2+9÷3\u003c16;1千克=1000克,1000克\u003e999克，所以1千克\u003e999克。",
+        "knowledge_points":  [
+                                 "克，千克之间的换算与比较，乘加，乘减混合运算，表内连乘，连除运算，万以内数的大小比较"
+                             ],
+        "source":  "23-24 二年级下·河北邯郸·期末"
+    },
+    {
+        "id":  "262",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "下面的单位合适吗。合适的在括号里打\"√\"，不合适的在括号里改正过来.\n周末，小玲和妈妈去超市购物，她们买了一个重5000千克( )的西瓜，一袋20克( )的大米，还买了一支长18米( )的铅笔。",
+        "options":  [
+
+                    ],
+        "answer":  "克或g;千克或kg;厘米或cm",
+        "solution":  "【分析】根据生活经验，以及对质量单位，长度单位和数据大小的认识，可知:1克大约是1粒花生米的质量，结合数据5000，所以计量一个西瓜的质量应用\"克\"作单位;1千克大约是5个苹果的质量，所以计量一袋大米的质量用\"千克\"作单位;食指的宽大约是1厘米，二年级学生双臂展开的长度大约是1米，计量一支铅笔的长度应用\"厘米\"作单位，据此解答。\n\n【详解】据分析可知：周末，小玲和妈妈去超市购物，她们买了一个重5000千克(克)的西瓜，一袋20克(千克)的大米，还买了一支长18米(厘米)的铅笔。",
+        "knowledge_points":  [
+                                 "长度单位的选择，厘米的认识，质量单位的选择，千克的认识"
+                             ],
+        "source":  "23-24 二年级下·福建龙岩·期末"
+    },
+    {
+        "id":  "263",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "在括号填上\"\u003e\"\"\u003c\"或\"=\".\n1990( )16906000克( )6千克\n48÷6( )77200克( )7199克",
+        "options":  [
+
+                    ],
+        "answer":  "\u003e;=;\u003e;\u003e",
+        "solution":  "【分析】比较数的大小时，位数多的数就大，位数相同比较最高位，最高位大的数就大，最高位相同比较下一位，直到比较出结果为止。第1题直接比较;第2题根据1千克=1000克统一单位再比较;第3题计算出结果再比较;第4题单位相同，直接比较。\n\n【详解】1990和1690位数相同，千位相同，百位9\u003e6，则1990\u003e1690;6000克=6千克;48÷6=8;8\u003e7，则48÷6\u003e7;7200和7199位数相同，千位相同，百位2\u003e1，则7200克\u003e7199克。",
+        "knowledge_points":  [
+                                 "万以内数的大小比较，用7~9的乘法口诀求商，克，千克之间的换算与比较"
+                             ],
+        "source":  "24-25一年级下·山东临沂·期末"
+    },
+    {
+        "id":  "264",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "在括号里填\"\u003e\"\"\u003c\"或\"=\".\n2500克( )3千克 32÷4( )56/71600( )1060",
+        "options":  [
+
+                    ],
+        "answer":  "\u003c;=;\u003e",
+        "solution":  "【分析】整数的大小比较：比较数的大小，先看位数的多少，位数多的数就大;位数相同，从高位开始比较，高位上的数大则这个数大，高位上的数相同，就比较下一位。含有算式的，可以先计算出算式的结果，再比较大小;1千克=1000克，单位不统一时，先化成相同单位，再比较大小。\n\n【详解】3千克=3000克,2500\u003c3000，则2500克\u003c3千克;32÷4=8,56÷7=8，则32÷4=56÷7;千位一样，百位上6\u003e0,1600\u003e1060。",
+        "knowledge_points":  [
+                                 "克，千克之间的换算与比较，用7~9的乘法口诀求商，万以内数的大小比较"
+                             ],
+        "source":  "24-25一年级下·湖南岳阳·期中"
+    },
+    {
+        "id":  "265",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "2千克=( )克 3000克=( )千克 1小时15分=( )分",
+        "options":  [
+
+                    ],
+        "answer":  "2000;3;75",
+        "solution":  "【分析】根据:1千克=1000克,1小时=60分，进行解答。\n\n【详解】由分析可得:2千克里面有2个1千克，也就是2个1000克即2000克,2千克=2000克;3000克里面有3个1000克，也就是3个1千克即3千克，所以3000克=3千克;1小时=60分,60分+15分=75分，所以1小时15分=75分。2千克=2000克;3000克=3千克;1小时15分=75分。",
+        "knowledge_points":  [
+                                 "克，千克之间的换算与比较，时，分的认识及换算"
+                             ],
+        "source":  "24-25一年级下·湖南岳阳·期中"
+    },
+    {
+        "id":  "266",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在括号里填上合适的单位.\n一袋盐重400( )。 课桌的高度大约是70( )。 小明的体重是43( )。 吃一顿饭大约需要15( )。",
+        "options":  [
+
+                    ],
+        "answer":  "克或g;厘米或cm;千克或kg;分钟或min",
+        "solution":  "【分析】2个曲别针约重1克，所以计量一袋盐的重量用克作单位比较合适;1厘米大约是食指的宽度，所以计量课桌的高度用厘米作单位比较合适;2小袋食盐重1千克，所以计量小学生的体重用千克比较合适;1分钟大约能写20个字，所以计量吃一顿饭的时间用分钟作单位比较合适。\n\n【详解】有分析可得：食盐的重量不太重，一袋家用盐的重量一般在几百克左右(如常见的包装有250克,500克等),400克是合理的。课桌的高度一般在几十厘米范围内。标准课桌高度约为70厘米左右。如果用\"米\"，则70米太高(相当于20多层楼),不现实。小学生的体重通常有一定的重量。用千克比较合适,43千克对于一个小学生是合理的。吃饭的时间通常不会太长，用分钟做单位比较合适。一顿饭大约需要10-20分钟,15分钟是常见的时间。一袋盐重400克。课桌的高度大约是70厘米。小明的体重是43千克。吃一顿饭大约需要15分钟。",
+        "knowledge_points":  [
+                                 "长度单位的选择，质量单位的选择，时间单位的选择"
+                             ],
+        "source":  "23-24 二年级下·河北邢台·期末"
+    },
+    {
+        "id":  "267",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "如图，右边的筐里再添上( )千克橙子，就和左边的苹果一样重了.\n![](images/74a0024c40fde3098cf3f279a93ceeda.png)",
+        "options":  [
+
+                    ],
+        "answer":  "4",
+        "solution":  "【分析】根据题意，根据1千克=1000克，先把9000克变换成9千克，苹果的千克数减去橙子的千克数，等于右边的筐里再添上几千克，就和左边的苹果一样重了，据此解答。\n\n【详解】根据分析可得:9000克=9千克,9千克-5千克=4千克，因此，右边的筐里再添上4千克橙子，就和左边的苹果一样重了。",
+        "knowledge_points":  [
+                                 "克，千克之间的换算与比较"
+                             ],
+        "source":  "23-24 二年级下·福建龙岩·期末"
+    },
+    {
+        "id":  "268",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在括号里填上合适的质量单位.\n周末，妈妈带龙龙去超市买东西。她给龙龙买了一包重300( )的饼干，还买了5( )鸡蛋,1袋大米和6个苹果。",
+        "options":  [
+
+                    ],
+        "answer":  "克或g;千克或kg",
+        "solution":  "【分析】根据情景选择合适的计量单位，要注意联系生活实际，计量单位和数据的大小，灵活的选择。1克大约为一枚硬币的重量，计量饼干的重量用\"克\"作单位比较合适。1千克大约为两瓶矿泉水的重量，计量买的鸡蛋的重量用\"千克\"作单位比较合适。\n\n【详解】周末，妈妈带龙龙去超市买东西。她给龙龙买了一包重300克的饼干，还买了5千克鸡蛋,1袋大米和6个苹果。",
+        "knowledge_points":  [
+                                 "质量单位的选择，千克的认识，克的认识"
+                             ],
+        "source":  "23-24二年级下·广东揭阳·期末"
+    },
+    {
+        "id":  "269",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "填一填.\n( )克=5千克 4千克200克=( )克\n1千克-400克=( )克 8千克-( )千克=3000克",
+        "options":  [
+
+                    ],
+        "answer":  "5000;4200;600;5",
+        "solution":  "【分析】根据1千克=1000克进行灵活换算，据此结算。\n\n【详解】由分析可得:5000克=5千克;4千克=4000克,4000克+200克=4200克，所以4千克200克=4200克;1千克=1000克,1000克-400克=600克，所以1千克-400克=600克;3000克=3千克,8千克-3千克=5千克，所以8千克-5千克=3000克。",
+        "knowledge_points":  [
+                                 "克，千克之间的换算与比较，整百数，几百几十数的加减法口算"
+                             ],
+        "source":  "23-24 二年级下·浙江嘉兴·期末"
+    },
+    {
+        "id":  "270",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "8个鸡蛋重500克,65个鸡蛋大约重( )千克。",
+        "options":  [
+
+                    ],
+        "answer":  "4",
+        "solution":  "【分析】由题意可知：根据除法的意义，看65里有几个8，即65÷8，有几个8就重几个500克，把几个500克相加，得出的结果再根据1千克=1000克变成千克即可;据此解答。\n\n【详解】由分析可得:65÷8=8。1,65个鸡蛋里大约有8个8,65个鸡蛋大约重8个500克;把8个500克相加:500+500+500+500+500+500+500+500=4000(克),4000克=4千克,8个鸡蛋重500克,65个鸡蛋大约重4千克。",
+        "knowledge_points":  [
+                                 "克，千克之间的换算与比较,100以内有余数的除法计算"
+                             ],
+        "source":  "23-24 二年级下·广东东莞·期末"
+    },
+    {
+        "id":  "271",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在括号里填上\"\u003e\"\"\u003c\"或\"=\".\n1千克( )959克 8千克( )7990克 5600克( )6千克 4千克( )4000克",
+        "options":  [
+
+                    ],
+        "answer":  "\u003e;\u003e;\u003c;=",
+        "solution":  "【分析】根据1千克=1000克统一单位，再按照整数比较大小的方法比较即可。比较时，位数多的数就大，位数相同比较最高位，最高位大的数就大，最高位相同比较下一位，直到比较出结果为止。\n\n【详解】1千克=1000克;1000克\u003e959克，则1千克\u003e959克;8千克=8000克;8000克\u003e7990克，则8千克\u003e7990克;6千克=6000克;5600克\u003c6000克，则5600克\u003c6千克;4千克=4000克。",
+        "knowledge_points":  [
+                                 "万以内数的大小比较，克，千克之间的换算与比较"
+                             ],
+        "source":  "23-24 二年级下·福建龙岩·期末"
+    },
+    {
+        "id":  "272",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "在括号里填上\"\u003e\"\"\u003c\"或\"=\".\n72-8( )72÷81899( )19905千克( )5000克",
+        "options":  [
+
+                    ],
+        "answer":  "\u003e;\u003c;=",
+        "solution":  "【分析】比较数的大小时，位数多的数就大，位数相同比较最高位，最高位大的数就大，最高位相同比较下一位，直到比较出结果为止。第1题：计算出各算式的结果再比较;第2题：直接比较;第3题：根据1千克=1000克统一单位再比较。\n\n【详解】72-8=64,72÷8=9,64\u003e9，则72-8\u003e72÷8;1899和1990位数相同，千位相同，百位8\u003c9，则1899\u003c1990;5千克=5000克。",
+        "knowledge_points":  [
+                                 "克，千克之间的换算与比较，用7~9的乘法口诀求商，一位数与两位数的退位减法，万以内数的大小比较"
+                             ],
+        "source":  "23-24 二年级下·湖北襄阳·期末"
+    },
+    {
+        "id":  "273",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "在括号里填上合适的数或单位.\n7000克=( )千克 3千克=( )克\n4000克+5千克=( )千克 5千克-300克=( )克\n一个书包约重5( ) 一个鸡蛋约重60( )",
+        "options":  [
+
+                    ],
+        "answer":  "7;3000;9;4700;千克或kg;克或g",
+        "solution":  "【分析】1千克=1000克，再根据生活经验，对质量单位和数据大小的认识可知，一枚回形针大约重1克，两瓶矿泉水重量大约是1千克。由此作为判断基础，即可解答。\n\n【详解】7000克=7千克，所以括号内应填7;3千克=3000克，所以括号内应填3000;4000克=4千克,4+5=9千克，所以括号内应填9;5千克=5000克,5000-300=4700克，所以括号内应填4700;一个书包会比两瓶矿泉水更重，用千克做单位更合适，所以括号内应填千克;一个鸡蛋会比一枚回形针更重，但是比两瓶矿泉水更轻，用克做单位更合适，所以括号内应填克。",
+        "knowledge_points":  [
+                                 "质量单位的选择，克，千克之间的换算与比较"
+                             ],
+        "source":  "23-24 二年级下·浙江舟山·期末"
+    },
+    {
+        "id":  "274",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "在括号里填上合适的单位.\n爸爸的体重约75( ) 一节课40( )\n一个鸡蛋约重50( ) 一棵大树约高12( )",
+        "options":  [
+
+                    ],
+        "answer":  "千克或kg;分钟或min或分;克或g;米或m",
+        "solution":  "【分析】根据生活经验，对长度单位，质量单位，时间单位和数据大小的认识可知：计量比较重的物体，常用千克作单位,2袋白砂糖约重1千克，所以爸爸的体重用千克作单位比较合适;表示比较短的时间，常用分钟作单位，一分钟大约能写20个字，所以一节课的时间用分钟作单位比较合适;计量比较轻的物体，常用克作单位,2个曲别针约重1克，所以一个鸡蛋的重量用克作单位比较合适;测量较长的物体用米作单位，二年级学生双臂展开的长度大约是1米，所以大树的高度用米作单位比较合适。\n\n【详解】爸爸的体重约75千克(kg);一节课40分钟(min);一个鸡蛋约重50克(g);一棵大树约高12米(m)。",
+        "knowledge_points":  [
+                                 "长度单位的选择，质量单位的选择，时间单位的选择"
+                             ],
+        "source":  "23-24 二年级下·重庆大渡口·期末"
+    },
+    {
+        "id":  "275",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "一瓶墨水重200克,( )瓶墨水重是1千克。",
+        "options":  [
+
+                    ],
+        "answer":  "5",
+        "solution":  "【分析】根据1千克=1000克，首先把1千克换算成1000克，要求几瓶墨水是1000克，也就是求1000克里面有多少个200克，据此解答。\n\n【详解】根据分析可得:200克+200克+200克+200克+200克=1000克,1000克=1千克,5个200克重1千克。因此，一瓶墨水重200克,5瓶墨水重是1千克。",
+        "knowledge_points":  [
+                                 "克，千克之间的换算与比较，整百数，几百几十数的加减法口算"
+                             ],
+        "source":  "23-24 二年级下·河南信阳·期末"
+    },
+    {
+        "id":  "276",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在( )里填上质量单位\"克\"或\"千克\".\n一个梨重约150( )。 一只鸡重约3( )。 一袋碘盐重约500( )。 一头牛重约300( )。",
+        "options":  [
+
+                    ],
+        "answer":  "克;千克;克;千克",
+        "solution":  "【分析】计量比较轻的物体重量用\"克\"作单位，如一粒花生米重量大约是1克，计量比较重的物体重量用\"千克\"作单位，如一个西瓜重量大约是3千克。\n\n【详解】一个梨比较轻，用\"克\"作单位比较合适，因此一个梨重约150(克);一只鸡比较重，用\"千克\"作单位比较合适，因此一只鸡重约3(千克);一袋碘盐比较轻，用\"克\"作单位比较合适，因此一袋碘盐重约500(克);一头牛比较重，用\"千克\"作单位比较合适，因此一头牛重约300(千克)。",
+        "knowledge_points":  [
+                                 "质量单位的选择，千克的认识，克的认识"
+                             ],
+        "source":  "23-24二年级下·重庆永川·期末"
+    },
+    {
+        "id":  "277",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "在括号里填上合适的质量单位或数.\n(1)一个南瓜大约重4( ),一袋方便面净重100( ).\n(2)每4个苹果约重1千克，王奶奶摘了20个苹果，大约重( )千克.\n(3)2袋盐重1( ),那么这样的1袋盐重500( ).\n(4)6千克=( )克,800克+( )克=1千克。",
+        "options":  [
+
+                    ],
+        "answer":  "千克;克 5 千克;克 6000;200",
+        "solution":  "【分析】(1)1克大约为一枚硬币的重量，计量一袋方便面的重量用\"克\"作单位比较合适。1千克大约为两瓶矿泉水的重量，计量一个南瓜的重量用\"千克\"作单位比较合适。(2)每4个苹果约重1千克，用苹果的总数除以4，商是几就有几个1千克。(3)1千克大约为两瓶矿泉水的重量，计量2袋盐的重量用\"千克\"作单位比较合适。1千克=1000克=500克+500克，所以1袋盐重500克。(4)1千克=1000克，据此解答。\n\n【详解】(1)一个南瓜大约重4千克，一袋方便面净重100克。(2)20÷4=5(千克),每4个苹果约重1千克，王奶奶摘了20个苹果，大约重5千克。(3)1千克=1000克=500克+500克,2袋盐重1千克，那么这样的1袋盐重500克。(4)6千克就是6个1千克，即6个1000克，则6千克=6000克。1千克=1000克,1000-800=200，则800克+200克=1千克。",
+        "knowledge_points":  [
+                                 "克，千克之间的换算与比较"
+                             ],
+        "source":  "23-24 二年级下·天津和平·期末"
+    },
+    {
+        "id":  "278",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "3千克=( )克 5000克=( )千克",
+        "options":  [
+
+                    ],
+        "answer":  "3000;5",
+        "solution":  "【分析】1千克=1000克,3千克里面有3个1千克，也就是有3个1000克，是3000克;1000克=1千克,5000克里面有5个1000克，也就是有5个1千克，是5千克。\n\n【详解】3千克=3000克;5000克=5千克。",
+        "knowledge_points":  [
+                                 "克，千克之间的换算与比较"
+                             ],
+        "source":  "23-24 二年级下·天津河东·期末"
+    },
+    {
+        "id":  "279",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "填上合适的单位.\n一只苹果重200( ) 小明跑完60米用了15( )\n一袋大米重10( ) 一节课的时间是35( )",
+        "options":  [
+
+                    ],
+        "answer":  "克或g;秒或s;千克或kg;分钟或分或min",
+        "solution":  "【分析】根据生活经验，对时间单位，质量单位和数据大小的认识，来选择合适的质量单位或时间单位。1枚1分的硬币约重1克，所以计量一个苹果重用\"克\"作单位比较合适;1秒大约能眨一次眼，所以计量小明跑完60米的时间用\"秒\"作单位比较合适;2袋食用盐的重量大约是1千克，所以计量一袋大米重用\"千克\"作单位比较合适;1分钟大约能写20个字，所以计量一节课的时间用\"分钟\"作单位比较合适。\n\n【详解】根据分析可得：一只苹果重200克;小明跑完60米用了15秒;一袋大米重10千克;一节课的时间是35分钟。",
+        "knowledge_points":  [
+                                 "质量单位的选择，千克的认识，时间单位的选择，秒的认识"
+                             ],
+        "source":  "23-24 二年级下·上海松江·期末"
+    },
+    {
+        "id":  "280",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "排序题",
+        "difficulty":  0.85,
+        "question":  "按从大到小的顺序排一排.\n2400克 2040克 4千克 4002克\n( )\u003e( )\u003e( )\u003e( )。",
+        "options":  [
+
+                    ],
+        "answer":  "4002克;4千克;2400克;2040克",
+        "solution":  "【分析】根据题意，比较质量的大小，按从大到小的顺序排列。比较时，同单位的直接比较，不同单位的根据1千克=1000克统一单位后，再根据整数比较大小的方法比较。比较时，位数多的数就大，位数相同比较最高位，最高位大的数就大，最高位相同比较下一位，直到比较出结果为止。\n\n【详解】4千克=4000克;4002克\u003e4000克\u003e2400克\u003e2040克;则4002克\u003e4千克\u003e2400克\u003e2040克。",
+        "knowledge_points":  [
+                                 "克，千克之间的换算与比较，万以内数的大小比较"
+                             ],
+        "source":  "23-24 二年级下·湖南岳阳·期末"
+    },
+    {
+        "id":  "281",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "1枚2分硬币约重1克,9枚2分硬币约重18克。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】依据总重量=枚数×每枚重量，求出9枚2分硬币的重量，再与18克比较即可判断。\n\n【详解】1×9=9(克),9克!=18克，因此原题说法错误。故答案为: ×",
+        "knowledge_points":  [
+                                 "克的认识,9的乘法口诀及应用"
+                             ],
+        "source":  "24-25 二年级下·广西柳州·期末"
+    },
+    {
+        "id":  "282",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "1kg棉花比1000g洗衣粉轻。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】根据1kg=1000g统一单位后再比较即可，要注意，物品的质量与材质无关。\n\n【详解】1kg=1000g,则1kg棉花和1000g洗衣粉一样重，原题说法错误。故答案为: ×",
+        "knowledge_points":  [
+                                 "克，千克之间的换算与比较"
+                             ],
+        "source":  "24-25 二年级下·河南周口·期末"
+    },
+    {
+        "id":  "283",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "1千克铁和1000克棉花同样重。( )",
+        "options":  [
+
+                    ],
+        "answer":  "√",
+        "solution":  "【详解】1千克=1000克，所以1千克铁和1000克棉花的重量均为1000克，质量相同.\n\n【分析】根据质量单位的换算关系,1千克=1000克，因此1千克铁和1000克棉花的实际质量相等，与材质无关。原题说法正确。故答案为:√",
+        "knowledge_points":  [
+                                 "克，千克之间的换算与比较"
+                             ],
+        "source":  "23-24二年级下·新疆昌吉·期末"
+    },
+    {
+        "id":  "284",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "5克和5厘米一样大。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】5克是质量的单位，用于测量重量;5厘米是长度的单位，用于测量长短。它们是完全不同的量，重量和长度没有可比性，不能说\"一样大\"，据此解答。\n\n【详解】5克和5厘米是完全不同的量，不能比较它们的大小。因此,5克和5厘米一样大，这个说法是错误的。故答案为: ×",
+        "knowledge_points":  [
+                                 "厘米的认识，克的认识"
+                             ],
+        "source":  "23-24 二年级下·甘肃天水·期末"
+    },
+    {
+        "id":  "285",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "一只北京烤鸭的重量是1克。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】根据生活经验以及对质量单位和数据大小的认识,1瓶矿泉水大约重500克,2瓶矿泉水大约重1千克,1张普通的A4纸的质量大约是1克，据此结合实际情况判断即可。\n\n【详解】据分析可知：一只北京烤鸭的重量是1千克。原题说法错误。故答案为: ×",
+        "knowledge_points":  [
+                                 "千克的认识，克的认识"
+                             ],
+        "source":  "23-24 二年级下·湖南益阳·期末"
+    },
+    {
+        "id":  "286",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "小丽体重20克。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】根据生活经验，对质量单位和数据大小的认识可知：计量比较轻的物体，常用克作单位,2个曲别针约重1克，计量比较重的物体，常用千克作单位,2袋白砂糖约重1千克，由此判断即可。\n\n【详解】由分析得:20克大约是一块橡皮的重量，显然不符合小丽的体重，则小丽的体重应为20千克，原题说法错误。故答案为: ×",
+        "knowledge_points":  [
+                                 "质量单位的选择，千克的认识，克的认识"
+                             ],
+        "source":  "23-24 二年级下·山东菏泽·期末"
+    },
+    {
+        "id":  "287",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "10千克铁比10千克棉花重。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】比较物体之间的轻重，与物体本身的材质无关，与本身的重量有关，铁和棉花重量都是10千克，所以二者一样重。\n\n【详解】10千克铁和10千克棉花相比，一样重，所以原题说法错误。故答案为: ×",
+        "knowledge_points":  [
+                                 "千克的认识"
+                             ],
+        "source":  "23-24 二年级下·河北唐山·期末"
+    },
+    {
+        "id":  "288",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "一瓶奶茶重450千克。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】根据生活经验以及对质量单位和数据大小的认识,1瓶矿泉水大约重500克,2瓶矿泉水大约重1千克，据此结合实际情况判断即可。\n\n【详解】根据生活经验可知：一瓶奶茶重450克。原题说法错误。故答案为: ×",
+        "knowledge_points":  [
+                                 "千克的认识，克的认识"
+                             ],
+        "source":  "23-24 二年级下·黑龙江佳木斯·期末"
+    },
+    {
+        "id":  "289",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "判断题",
+        "difficulty":  0.65,
+        "question":  "4千克棉花和4000克铁同样重。( )",
+        "options":  [
+
+                    ],
+        "answer":  "√",
+        "solution":  "【分析】先根据\"1千克=1000克\"统一单位，然后比较大小即可;要注意，物品的质量与材质无关。\n\n【详解】1千克=1000克，故4千克=4000克;所以,4千克棉花和4000克铁同样重，说法正确。故答案为:√",
+        "knowledge_points":  [
+                                 "克，千克之间的换算与比较"
+                             ],
+        "source":  "23-24 二年级下·云南曲靖·期末"
+    },
+    {
+        "id":  "290",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "判断题",
+        "difficulty":  0.65,
+        "question":  "在生活中，人们还习惯用\"斤\"和\"两\"来表示物体有多重,1斤=500克。( )",
+        "options":  [
+
+                    ],
+        "answer":  "√",
+        "solution":  "【分析】在日常生活中，人们习惯用\"公斤\"，\"斤\"和\"两\"表示物体的重量:1千克=1公斤,1公斤=2斤,2斤=1000克，据此结合题干要求进行解答即可。\n\n【详解】据分析可知:2斤=1000克，所以1斤=500克。题干说法正确。故答案为:√",
+        "knowledge_points":  [
+                                 "克，千克之间的换算与比较，千克的认识，克的认识"
+                             ],
+        "source":  "23-24 二年级下·河北邯郸·期末"
+    },
+    {
+        "id":  "291",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "2袋盐重1000克。( )",
+        "options":  [
+
+                    ],
+        "answer":  "√",
+        "solution":  "【分析】根据生活经验可知:1袋盐重500克，所以2袋盐重1000克。据此解答即可。\n\n【详解】2袋盐重1000克。原题说法正确。故答案为:√",
+        "knowledge_points":  [
+                                 "克的认识"
+                             ],
+        "source":  "23-24 二年级下·河北邯郸·期末"
+    },
+    {
+        "id":  "292",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "1000克铁比1000克棉花重。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】从题干可知：铁与棉花都是1000克，所以它们的质量相同，据此解答即可。\n\n【详解】1000克=1000克，所以1000克铁跟1000克棉花一样重。原题说法错误。故答案为: ×",
+        "knowledge_points":  [
+                                 "克的认识"
+                             ],
+        "source":  "23-24 二年级下·河北邯郸·期末"
+    },
+    {
+        "id":  "293",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "一辆自行车重25克。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】计量比较轻的物体重量用\"克\"作单位，如一粒花生米重量大约是1克，计量比较重的物体重量用\"千克\"作单位，如一个西瓜重量大约是3千克。\n\n【详解】一辆自行车比较重，因此用\"千克\"作单位比较合适，所以一辆自行车重25千克，原题说法错误。故答案为: ×",
+        "knowledge_points":  [
+                                 "质量单位的选择，千克的认识，克的认识"
+                             ],
+        "source":  "23-24 二年级下·河南漯河·期末"
+    },
+    {
+        "id":  "294",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "计算题",
+        "difficulty":  0.85,
+        "question":  "看图列式计算.\n![](images/21e5a8c4e31cebe2a946c5d4f89ee71536a6510d11c5fec0324e25abb8eff7a5.jpg)\n![](images/2117ec8c99a69dd9f0703a9ab216404f588631f8f4c6ede2b385005e71fc1795.jpg)",
+        "options":  [
+
+                    ],
+        "answer":  "50-20=30",
+        "solution":  "【分析】根据题图可知，要想保持天平平衡，两边的重量相等，左边的重量减去右边的20克，等于右边●的重量，据此解答。\n\n【详解】根据分析可得:50-20=30(克),因此，右边的●重30克。",
+        "knowledge_points":  [
+                                 "克的认识，整十数之间的加减法，图文问题"
+                             ],
+        "source":  "24-25一年级下·河北张家口·期末"
+    },
+    {
+        "id":  "295",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "小狗比小鸡重多少千克。再来几只同样重的小鸡，跷跷板就平衡了。\n![](images/1673f4cba95224b8a03ffb8d2e570a1e00fe85b79711c321c03160e55d0fa26b.jpg)",
+        "options":  [
+
+                    ],
+        "answer":  "6千克;3只",
+        "solution":  "【分析】用小狗的重量减小鸡的重量即可求出小狗比小鸡重多少千克。用小狗比小鸡重的千克数除以一只小鸡的千克数即可求出再来几只同样重的小鸡，跷跷板就平衡了。\n\n【详解】8-2=6(千克),(8-2)÷2=6÷2=3(只),答：小狗比小鸡重6千克;再来3只同样重的小鸡，跷跷板就平衡了。",
+        "knowledge_points":  [
+                                 "千克的认识，带有小括号的混合运算，图文问题"
+                             ],
+        "source":  "24-25 二年级下·河北石家庄·期中"
+    },
+    {
+        "id":  "296",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "请你根据下边提供的信息提一个数学问题并解答。端午节快到了，给爸妈邮寄了1000克枣粽,300克的豆沙粽.\n![](images/7131de1b299750d47ae003551e6a9a2a8963442ae8be0bfb1811d522f6d92df1.jpg)",
+        "options":  [
+
+                    ],
+        "answer":  "一共寄了多少克粽子。;1300克(答案不唯一)1300克",
+        "solution":  "【分析】根据题意，结合给出的信息，可提出问题为：一共寄了多少克粽子。给爸妈寄枣粽的克数加上豆沙粽的克数，等于一共寄了多少克粽子，据此解答。\n\n【详解】根据分析可得：问题：一共寄了多少克粽子。(提问题和答案不唯一)1000+300=1300(克),答：一共寄了1300克粽子。",
+        "knowledge_points":  [
+                                 "克的认识，整百数，几百几十数的加减法口算，\"提问题\"\"填条件\"问题"
+                             ],
+        "source":  "23-24 二年级下·山西晋中·期末"
+    },
+    {
+        "id":  "297",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "一桶油连桶重29千克，吃了半桶油后，连桶重20千克。油桶里油重多少千克。油桶重多少千克。",
+        "options":  [
+
+                    ],
+        "answer":  "18千克;11千克",
+        "solution":  "【分析】根据题意，先用油连桶的重量减去用掉了一半油后油连桶的重量，求出一半油的重量。用一半油的重量乘2即可求出油的重量;初始油连桶的重量减去油的重量，就是桶的重量。\n\n【详解】油重:(29-20)×2=9×2=18(千克),桶重:29-18=11(千克),答：油桶里油重18千克，油桶重11千克。",
+        "knowledge_points":  [
+                                 "千克的认识，带有小括号的混合运算"
+                             ],
+        "source":  "24-25 二年级下·河南周口·期末"
+    },
+    {
+        "id":  "298",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "奶奶买了2千克的苹果，付给收银员50元后，应找回多少钱。\n\n| 水果 | 价格 |\n| ---- | --------- |\n| 苹果 | 7元/500克 |\n| 香蕉 | 3元/500克 |\n| 西瓜 | 4元/500克 |",
+        "options":  [
+
+                    ],
+        "answer":  "22元",
+        "solution":  "【分析】根据题意可知：先将单位统一,1千克=1000克，则2千克=2000克，然后根据500克苹果是7元，则求出2000克是多少钱，可用2000减去500，直到为0，减几个500就是有几个500，也就是有几个7元，用乘法计算就可求出2千克的苹果的价格，然后用付给收银员的钱数减去2千克的苹果的价格即可求出应找回的钱数。\n\n【详解】2千克=2000克,2000-500=1500(克),1500-500=1000(克),1000-500=500(克),500-500=0(克),则有4个500，即有4个7元。4×7=28(元),50-28=22(元),答：应找回22元钱。",
+        "knowledge_points":  [
+                                 "克，千克之间的换算与比较,7的乘法口诀及应用，整百数，几百几十数的加减法口算"
+                             ],
+        "source":  "23-24二年级下·福建龙岩·期末"
+    },
+    {
+        "id":  "299",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "购物.\n![](images/67a652ffe90276e64c29e44cb73bf296.png)\n(1)南瓜重多少千克。\n(2)冬瓜重多少千克。",
+        "options":  [
+
+                    ],
+        "answer":  "5千克;9千克",
+        "solution":  "【分析】由题意可知:(1)用西瓜的重量加上比西瓜多出的重量，等于南瓜的重量;(2)把西瓜和南瓜的重量相加，等于冬瓜的重量;据此解答。\n\n【详解】由分析可得:(1)4+1=5(千克),答：南瓜重5千克。(2)4+5=9(千克),答：冬瓜重9千克。",
+        "knowledge_points":  [
+                                 "千克的认识，图文问题"
+                             ],
+        "source":  "23-24 二年级下·河南许昌·期末"
+    },
+    {
+        "id":  "300",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "一桶油连桶共重20千克，用掉了一半油后连桶共重11千克。油重多少千克。",
+        "options":  [
+
+                    ],
+        "answer":  "18千克",
+        "solution":  "【分析】用油连桶的重量减用掉了一半油后油连桶的重量即可求出一半油的重量，用一半油的重量乘2即可求出油重多少千克。\n\n【详解】20-11=9(千克),9×2=18(千克),答：油重18千克。",
+        "knowledge_points":  [
+                                 "千克的认识,9的乘法口诀及应用，两位数与两位数的退位减法"
+                             ],
+        "source":  "24-25 二年级下·山东临沂·期中"
+    },
+    {
+        "id":  "301",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "小明的体重是( )。",
+        "options":  [
+                        "A. 35千克",
+                        "B. 350克",
+                        "C. 5千克"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】根据生活经验，对质量单位和数据大小的认识可知：计量比较轻的物体，常用克作单位,2个曲别针约重1克;计量比较重的物体，常用千克作单位,2袋白砂糖约重1千克;由此解答。\n\n【详解】A。35千克符合小明的体重;B。350克大约为一瓶饮料的重量，不符合题意;C。5千克大约为新生儿的体重，不符合题意。则小明的体重是35千克。故答案为:A",
+        "knowledge_points":  [
+                                 "克的认识，千克的认识，质量单位的选择"
+                             ],
+        "source":  "24-25 二年级下·山东济宁·期末"
+    },
+    {
+        "id":  "302",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "6千克的海绵和6千克的沙子比较,( )。",
+        "options":  [
+                        "A. 海绵重",
+                        "B. 沙子重",
+                        "C. 一样重"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】单位一样，直接比较数字即可。整数的大小比较：比较数的大小，先看位数的多少，位数多的数就大;位数相同，从高位开始比较，高位上的数大则这个数大，高位上的数相同，就比较下一位。\n\n【详解】6=6,6千克的海绵和6千克的沙子比较，一样重。故答案为:C",
+        "knowledge_points":  [
+                                 "千克的认识"
+                             ],
+        "source":  "23-24 二年级下·河北邢台·期中"
+    },
+    {
+        "id":  "303",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "( )的质量大约是1千克。",
+        "options":  [
+                        "A. 20个鸡蛋",
+                        "B. 1袋大米",
+                        "C. 1个橙子"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】根据情景，生活经验，以及对质量单位和数据大小的认识可知:1克大约是40粒大米重量,1千克=1000克,2袋盐大约重1千克，逐项分析后进行选择;据此解答。\n\n【详解】根据分析:A。20个鸡蛋的质量大约是1千克;B。1袋大米的质量大约是10千克;C。1个橙子的质量大约100克。故答案为:A",
+        "knowledge_points":  [
+                                 "克的认识，千克的认识，克，千克之间的换算与比较，质量的估计"
+                             ],
+        "source":  "24-25 三年级上·湖北随州·期末"
+    },
+    {
+        "id":  "304",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "2300克-300克=( )千克。",
+        "options":  [
+                        "A. 2000",
+                        "B. 200",
+                        "C. 2"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】先计算2300克-300克=2000克，再根据1千克=1000克进行单位换算，得出2000克=2千克即可。\n\n【详解】2300克-300克=2000克=2千克。故答案为:C",
+        "knowledge_points":  [
+                                 "克，千克之间的换算与比较"
+                             ],
+        "source":  "22-23 二年级下·四川凉山·期末"
+    },
+    {
+        "id":  "305",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "一个盒子的质量是200克，在盒子里放入800克的点心后，盒子和点心一共重( )。",
+        "options":  [
+                        "A. 600克",
+                        "B. 10000克",
+                        "C. 1千克"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】根据加法的意义，盒子的质量+点心的质量=盒子和点心一共的质量。根据1000克=1千克换算单位即可。\n\n【详解】200+800=1000(克),1000克=1千克，盒子和点心一共重1千克。故答案为:C",
+        "knowledge_points":  [
+                                 "整百数，几百几十数的加减法口算，克，千克之间的换算与比较"
+                             ],
+        "source":  "23-24二年级下·四川德阳·期末"
+    },
+    {
+        "id":  "306",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "5千克铁块和5000克棉花相比较，哪个重。( )",
+        "options":  [
+                        "A. 一样重",
+                        "B. 5000克棉花重",
+                        "C. 5千克铁块重"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】根据1千克=1000克，比较两个物体的轻重，比较他们的质量即可，跟物体的大小和材质没有关系;据此解答。\n\n【详解】根据分析可知,5千克中有5个1千克，也就是5个1000克为5000克，则5千克=5000克，所以5千克铁块和5000克棉花相比较，一样重。故答案为:A",
+        "knowledge_points":  [
+                                 "克，千克之间的换算与比较"
+                             ],
+        "source":  "24-25 三年级上·贵州六盘水·期中"
+    },
+    {
+        "id":  "307",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "下面最接近1千克的物品是( )。",
+        "options":  [
+                        "A. 一张桌子",
+                        "B. 一个乒乓球",
+                        "C. 两袋盐"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】1千克大约是两瓶矿泉水的重量，结合生活经验逐项估算物品的重量，找出最接近1千克的物品。\n\n【详解】A。通常一张桌子质量较大，远远超过1千克。例如，一张普通的木质餐桌质量可能在10千克以上，因为桌子的材质一般是木材或者金属，其结构复杂，体积也比较大，所以质量较重。B。一个乒乓球质量非常小。乒乓球是空心的塑料球体，质量大约在2.7克左右，和1千克相差甚远。C。在日常生活中，常见的食用盐一袋是500克左右，那么两袋盐的质量就是1000克，也就是1千克。故答案为:C",
+        "knowledge_points":  [
+                                 "克的认识，千克的认识，质量的估计"
+                             ],
+        "source":  "24-25 三年级上·海南省直辖县级单位·期中"
+    },
+    {
+        "id":  "308",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "1千克铁和1千克棉花( )重。",
+        "options":  [
+                        "A. 棉花",
+                        "B. 铁",
+                        "C. 一样",
+                        "D. 无法比较"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】物品的重量和材料无关，棉花和铁都重1千克，那就说明1千克棉花和1千克铁重量上是相同的。\n\n【详解】根据解析可知,1千克铁和1千克棉花一样重。故答案为:C",
+        "knowledge_points":  [
+                                 "千克的认识"
+                             ],
+        "source":  "24-25 三年级上·浙江杭州·期中"
+    },
+    {
+        "id":  "309",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "下面物品的重量,( )用\"克\"作单位比较合适。",
+        "options":  [
+                        "A. 一袋味精",
+                        "B. 一箱苹果",
+                        "C. 一袋面粉"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】常用的质量单位有克，千克。我们知道，两枚回形针大约重1克，两瓶矿泉水大约重1千克。据此分析。\n\n【详解】A。一袋味精较轻，它比两枚回形针要重一些，它比两瓶矿泉水要轻一些，所以一袋味精用\"克\"做单位比较合适。B。一箱苹果较重，它比两瓶矿泉水要重一些，所以一箱苹果用\"千克\"做单位比较合适。C。一袋面粉很重，它比两瓶矿泉水重很多，所以一袋面粉用\"千克\"做单位比较合适。故答案为:A",
+        "knowledge_points":  [
+                                 "克的认识，千克的认识"
+                             ],
+        "source":  "24-25三年级上·湖南邵阳·期中"
+    },
+    {
+        "id":  "310",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "买1千克苹果需要5元钱，现在有25元钱，可以买( )克苹果。",
+        "options":  [
+                        "A. 5",
+                        "B. 500",
+                        "C. 5000"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】买1千克苹果需要5元钱，则25元可以买25÷5=5(千克)苹果，然后根据1千克=1000克，换算成克作单位。\n\n【详解】25÷5=5(千克),5千克=5000克，买1千克苹果需要5元钱，现在有25元钱，可以买5000克苹果。故答案为:C",
+        "knowledge_points":  [
+                                 "用2~5的乘法口诀求商，克，千克之间的换算与比较"
+                             ],
+        "source":  "24-25 三年级上·湖南邵阳·期中"
+    },
+    {
+        "id":  "311",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "1枚一元硬币约重( )克。",
+        "options":  [
+                        "A. 3",
+                        "B. 10",
+                        "C. 6"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】根据生活经验以及对质量单位和数据大小的认识，可知：计量比较轻的物品的质量，通常用克作单位,10粒绿豆大约重1克，所以计量1枚一元硬币的重量用\"克\"作单位比较合适，约重6克;据此解答。\n\n【详解】3克的重量偏轻,10克的重量偏重，不符合实际情况，所以结合生活实际可知1枚一元硬币约重6克。故答案为:C",
+        "knowledge_points":  [
+                                 "克的认识，质量的估计"
+                             ],
+        "source":  "24-25 三年级上·河南洛阳·期中"
+    },
+    {
+        "id":  "312",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "一张卡片重20克,( )张这样的卡片重1千克。",
+        "options":  [
+                        "A. 5",
+                        "B. 50",
+                        "C. 500"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】1千克=1000克，一张卡片重20克，则50个20克是1000克，即50张这样的卡片重1千克;依此选择。\n\n【详解】1千克=1000克，因为一张卡片重20克,50个20克是1000克，也就是50张这样的卡片重1千克。故答案为:B",
+        "knowledge_points":  [
+                                 "克，千克之间的换算与比较"
+                             ],
+        "source":  "24-25 三年级上·湖南长沙·期中"
+    },
+    {
+        "id":  "313",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "测量一个人的腰围，用下面哪个工具比较合适。( )",
+        "options":  [
+                        "A. ![](images/8ddfc1f346e7318d564a3b023538ac13784d6a63bed380dbd30e0a17ecd3cdc8.jpg)",
+                        "B. ![](images/4bc448cd663c3736a7e5c06aaab271b05175d66bc1f4446ce4325fd0944e7970.jpg)",
+                        "C. ![](images/db2f23ab514a23ef29ff8913b657074b288a78710315c32e9a73ede0b7bda851.jpg)"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】根据生活经验可知，测量腰围也就是测量其长度，测量长度的工具包括直尺，卷尺等，通常用卷尺测量腰围，由此解答。\n\n【详解】A。用卷尺测量腰围比较合适;B。台秤用来称重量，不符合题意;C。直尺一般用来测量书本，桌子的长度，测量腰围不合适。所以测量一个人的腰围用A比较合适。故答案为:A",
+        "knowledge_points":  [
+                                 "长度的测量方法，千克的认识"
+                             ],
+        "source":  "24-25 二年级上·山东济南·期中"
+    },
+    {
+        "id":  "314",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "下列各物品中，比1克轻的是( )。",
+        "options":  [
+                        "A. 一块饼干",
+                        "B. 一块橡皮",
+                        "C. 一根羽毛"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】通过给出的物体，结合生活实际情况来判断各种物体的质量大约是多少，然后找出符合题意的即可。\n\n【详解】A。一块饼干大约重10克;B。一块橡皮大约重10克;C。一根羽毛重不到1克;即，比1克轻的是一根羽毛。故答案为:C",
+        "knowledge_points":  [
+                                 "克的认识"
+                             ],
+        "source":  "23-24 二年级下·河南濮阳·期末"
+    },
+    {
+        "id":  "315",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "下面物品中,( )比1克轻。",
+        "options":  [
+                        "A. 一个西瓜",
+                        "B. 一粒小米",
+                        "C. 一杯果汁"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】根据生活经验，数据的大小和对单位的认识可知，计量较轻的物体用\"克\"作单位;计量较重的物体用\"千克\"作单位。1千克=1000克。日常生活中一个西瓜大约有2千克;1克米大约有29至56粒;一杯果汁大约20克，据此判断即可。\n\n【详解】A。一个西瓜大约重2千克，比1克重，不符合题意;B。1克米大约有三四十粒，因此一粒米比1克轻;C。一杯果汁大约重20克，比1克重，不符合题意。故答案为:B",
+        "knowledge_points":  [
+                                 "克的认识，千克的认识，克，千克之间的换算与比较"
+                             ],
+        "source":  "23-24 二年级下·河北廊坊·期末"
+    },
+    {
+        "id":  "316",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "( )大约重1千克。",
+        "options":  [
+                        "A. 一头猪",
+                        "B. 一个大西瓜",
+                        "C. 2包食盐"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】常见的质量单位有克，千克等。根据生活经验以及对质量单位的认识,1千克=1000克,1克大约是一枚2分硬币的重量,1千克大约是一瓶一品鲜酱油的重量，可知2包食盐的重量大约是1千克，一头猪大约重几十甚至上百千克,1个大西瓜的重量大约是5千克。\n\n【详解】根据分析可知,2包食盐的重量大约是1千克，一头猪大约重几十甚至上百千克,1个大西瓜的重量大约是5千克。故答案为:C",
+        "knowledge_points":  [
+                                 "质量单位的选择"
+                             ],
+        "source":  "23-24 三年级上·山东菏泽·期中"
+    },
+    {
+        "id":  "317",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "测量比较短的物体长度，一般用( )作单位。",
+        "options":  [
+                        "A. 米",
+                        "B. 厘米",
+                        "C. 千克"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】结合实际可知，测量比较短的物体长度，一般用\"厘米\"作单位;测量比较长的物体长度，一般用\"米\"作单位。例如：一支铅笔长10厘米，课桌桌面长1米。克和千克是质量单位。\n\n【详解】A。测量比较长的物体长度，一般用\"米\"作单位;B。测量比较短的物体长度，一般用\"厘米\"作单位;C.\"千克\"是质量单位;故答案为:B",
+        "knowledge_points":  [
+                                 "千克的认识，厘米的认识，米的认识，长度单位的选择"
+                             ],
+        "source":  "23-24 二年级上·贵州铜仁·期中"
+    },
+    {
+        "id":  "318",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "500g香蕉9元钱,2kg香蕉要( )元钱。",
+        "options":  [
+                        "A. 18",
+                        "B. 36",
+                        "C. 45"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】根据题意可知:1kg=1000g先将单位换算统一，然后再进行计算,500g香蕉9元钱，则求2kg香蕉要多少钱。则2kg=2000g减去500g,看有多少个500g即有多少个9元。最后用乘法计算即可。\n\n【详解】2kg=2000g,2000-500=1500g,1500-500=1000g,1000-500=500g,500-500=0g,共减了4次，即有4个500，则有4个9，用4×9=36(元)。所以2kg香蕉要(36)元钱。故答案为:B",
+        "knowledge_points":  [
+                                 "整百数，几百几十数的加减法口算,9的乘法口诀及应用，千克的认识"
+                             ],
+        "source":  "23-24 二年级下·湖北恩施·期末"
+    },
+    {
+        "id":  "319",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "一袋500克,6袋( )千克。",
+        "options":  [
+                        "A. 3",
+                        "B. 30",
+                        "C. 300",
+                        "D. 3000"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】根据题意,6袋的重量也就是6个500克的和，用加法计算，再根据1千克=1000克换算单位即可。\n\n【详解】500+500+500+500+500+500=3000(克),3000克=3千克，一袋500克,6袋3千克。故答案为:A",
+        "knowledge_points":  [
+                                 "整百数，几百几十数的加减法口算，克，千克之间的换算与比较"
+                             ],
+        "source":  "23-24二年级下·福建漳州·期末"
+    },
+    {
+        "id":  "320",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "买500克梨要4元钱，买2千克梨要( )元。",
+        "options":  [
+                        "A. 14",
+                        "B. 16",
+                        "C. 18"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】根据1千克=1000克,500+500=1000，所以1千克里面有2个500克,2千克里面有4个500克，根据乘法的意义，用500克梨的价钱*4即可解答。\n\n【详解】2千克里面有4个500克。4×4=16(元),所以买2千克梨要16元。故答案为:B",
+        "knowledge_points":  [
+                                 "经济问题，克，千克之间的换算与比较"
+                             ],
+        "source":  "23-24 二年级下·河南商丘·期末"
+    },
+    {
+        "id":  "321",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "一个洗衣机的质量用( )作单位。",
+        "options":  [
+                        "A. 千克",
+                        "B. 克",
+                        "C. 厘米"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】一个洗衣机的质量应选用质量单位，常见的质量单位有克，千克，较轻物体的质量单位一般选择克，一般物体的质量单位选择千克。根据生活经验,1个U形针大约1克,3个苹果大约1千克，由此可知一个洗衣机的质量选择千克作单位比较合适。\n\n【详解】由分析可知：一个洗衣机的质量用千克作单位。故答案为:A",
+        "knowledge_points":  [
+                                 "质量单位的选择"
+                             ],
+        "source":  "23-24 二年级下·河北保定·期末"
+    },
+    {
+        "id":  "322",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "8个鸡蛋大约重500克，那么65个鸡蛋大约重( )千克。",
+        "options":  [
+                        "A. 4",
+                        "B. 3",
+                        "C. 2",
+                        "D. 1"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】根据题意，把8个鸡蛋看作1组，用鸡蛋的总数量65个除以每组的数量8个，求出大约有几组鸡蛋，也就是大约有几个500克，相加计算出总克数，根据1千克=1000克换算即可。\n\n【详解】65÷8=8(组)。1(个),大约有8个500克。500克+500克+500克+500克+500克+500克+500克+500克=4000克,4000克=4千克,65个鸡蛋大约重4千克。故答案为:A",
+        "knowledge_points":  [
+                                 "有余数除法的实际应用，克，千克之间的换算与比较"
+                             ],
+        "source":  "23-24 二年级下·福建漳州·期末"
+    },
+    {
+        "id":  "323",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "下面这则数学日记中，质量单位使用正确的是( )。",
+        "options":  [
+                        "A. ①",
+                        "B. ②",
+                        "C. ③",
+                        "D. ④"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】1千克大约为两瓶矿泉水的重量，计量人的体重和书包的重量用\"千克\"作单位比较合适。1克大约为一枚硬币的重量，计量酸奶的重量和鸡蛋的重量用\"克\"作单位比较合适。\n\n【详解】笑笑的体重①30千克。她喝了②150克的酸奶，吃了一个重约③60克的鸡蛋，然后背着约重④3千克的书包上学去。质量单位使用正确的是③。故答案为:C",
+        "knowledge_points":  [
+                                 "克的认识，千克的认识，质量单位的选择"
+                             ],
+        "source":  "23-24 二年级下·福建漳州·期末"
+    },
+    {
+        "id":  "324",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "6枚1角硬币大约重( )。",
+        "options":  [
+                        "A. 6米",
+                        "B. 6千克",
+                        "C. 6克"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】根据题意，括号里应该填质量单位。常用的质量单位有克和千克。我们知道，一枚回形针大约重1克，两瓶矿泉水大约重1千克。所以根据生活经验，对质量单位的认识可知，计量6枚1角硬币的重量用\"克\"作单位比较合适。\n\n【详解】A。米是长度单位，不是质量单位，不符合题意;B。6千克质量太大，不符合题意;C。6枚1角硬币大约重6克，符合题意。故答案为:C",
+        "knowledge_points":  [
+                                 "克的认识，千克的认识，质量的估计，米的认识"
+                             ],
+        "source":  "23-24 二年级下·福建福州·期末"
+    },
+    {
+        "id":  "325",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "一只鸭和两只鸡共重8千克，一只鸭重4000克，平均每只鸡重( )千克。",
+        "options":  [
+                        "A. 2",
+                        "B. 4",
+                        "C. 8"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】先用鸭和鸡的总重量减去一只鸭的重量(计算时，先统一单位),求出差，然后除以2，求出商，就是平均每只鸡的重量。注意1千克=1000克。\n\n【详解】4000克=4千克,(8-4)÷2=4÷2=2(千克),即，一只鸭和两只鸡共重8千克，一只鸭重4000克，平均每只鸡重2千克。故答案为:A",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算，克，千克之间的换算与比较"
+                             ],
+        "source":  "23-24 二年级下·河北邯郸·期末"
+    },
+    {
+        "id":  "326",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "1桶油连桶重15千克，用去一半油后，连桶称还重9千克。原来桶里装有( )千克油，桶重( )千克。",
+        "options":  [
+
+                    ],
+        "answer":  "12;3",
+        "solution":  "【分析】根据题意，先用油和桶的总重量减去用了一半油后，油和桶还剩的重量，计算出一半油的重量;一半油的重量+另一半油的重量=油的总重量;油和桶的总重量-油的重量=桶的重量。\n\n【详解】一半油的重量:15-9=6(千克),油的重量:6+6=12(千克),桶的重量:15-12=3(千克),1桶油连桶重15千克，用去一半油后，连桶称还重9千克。原来桶里装有12千克油，桶重3千克。",
+        "knowledge_points":  [
+                                 "千克的认识"
+                             ],
+        "source":  "24-25二年级下·湖北武汉·期中"
+    },
+    {
+        "id":  "327",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "2个曲别针约重2克,2000个曲别针约重( )克，也可以说约重( )千克。",
+        "options":  [
+
+                    ],
+        "answer":  "2000;2",
+        "solution":  "【分析】2000里面有几个2，即2000个曲别针就大约重几个2克，再根据1千克=1000克，把2000个曲别针质量换算成用千克作单位。\n\n【详解】2000里面有1000个2，所以2000个曲别针约重2000克。2000克=2千克，所以也可以说约重2千克。",
+        "knowledge_points":  [
+                                 "克的认识，千克的认识，克，千克之间的换算与比较"
+                             ],
+        "source":  "23-24 二年级下·河南信阳·期末"
+    },
+    {
+        "id":  "328",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "填\"\u003e\"\"\u003c\"或\"=\".\n6千克( )6000克 700克( )1千克\n9千克( )1100克 3千克( )2900克",
+        "options":  [
+
+                    ],
+        "answer":  "=;\u003c;\u003e;\u003e",
+        "solution":  "【分析】根据1千克=1000克统一单位，再根据整数比较大小的方法进行比较。比较时，位数多的数就大，位数相同比较最高位，最高位大的数就大，最高位相同，比较下一位，直到比较出结果为止。\n\n【详解】6千克=6000克;1千克=1000克;700克\u003c1000克，则700克\u003c1千克;9千克=9000克;9000克\u003e1100克，则9千克\u003e1100克;3千克=3000克;3000克\u003e2900克，则3千克\u003e2900克。",
+        "knowledge_points":  [
+                                 "万以内数的大小比较，克，千克之间的换算与比较"
+                             ],
+        "source":  "2025 二年级下·全国·专题练习"
+    },
+    {
+        "id":  "329",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在括号里填合适的单位.\n一支铅笔长15( )。 一袋面粉重2( )。",
+        "options":  [
+
+                    ],
+        "answer":  "厘米或cm;千克或kg",
+        "solution":  "【分析】根据生活经验，对长度单位，质量单位和数据大小的认识可知，食指宽大约是1厘米，所以，计量一支铅笔长用\"厘米\"作单位比较合适;两袋500克的盐是1千克，所以，计量一袋面粉重量用\"千克\"作单位比较合适。\n\n【详解】由分析可知：一支铅笔长15厘米。一袋面粉重2千克。",
+        "knowledge_points":  [
+                                 "质量单位的选择，长度单位的选择"
+                             ],
+        "source":  "24-25 二年级下·湖南岳阳·期中"
+    },
+    {
+        "id":  "330",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "在横线上填上合适的单位名称.\n乐乐是一名三年级学生，他的体重是27( ),身高是142( )。周末，他和妈妈一起来到附近的离家2000( )的山姆超市，购买了2袋500( )的汤圆。",
+        "options":  [
+
+                    ],
+        "answer":  "千克或kg;厘米或cm;米或m;克或g",
+        "solution":  "【分析】根据生活经验，对长度单位，质量单位和数据大小的认识可知:1枚2分硬币,1粒花生米,2颗黄豆的重量大约是1克;1袋食盐的重量是500克，两袋盐的质量是1千克，所以计量乐乐的体重用\"千克\"作单位比较合适，计量2袋汤圆的重量用\"克\"作单位比较合适。生活中食指宽大约1厘米，量比较短的物体，可以用\"厘米\"作单位，所以计量乐乐身高用\"厘米\"作单位比较合适。生活中长度大约是1米的物体有：成年人的一个步，成年人的一个手臂的长度;所以计量到家附近山姆超市的距离用\"米\"作单位比较合适。\n\n【详解】乐乐是一名三年级学生，他的体重是27千克，身高是142厘米。周末，他和妈妈一起来到附近的离家2000米的山姆超市，购买了2袋500克的汤圆。",
+        "knowledge_points":  [
+                                 "质量单位的选择，长度单位的选择"
+                             ],
+        "source":  "23-24 三年级上·江苏无锡·期末"
+    },
+    {
+        "id":  "331",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "在下面的( )里填上\"\u003e\"\"\u003c\"或\"=\".\n8906( )86908960克( )9千克\n95-(18+12)( )95-18-1263÷7/3( )63-7×3",
+        "options":  [
+
+                    ],
+        "answer":  "\u003e;\u003c;=;\u003c",
+        "solution":  "【分析】整数的大小比较：比较数的大小，先看位数的多少，位数多的数就大;位数相同，从高位开始比较，高位上的数大则这个数大，高位上的数相同，就比较下一位;含有算式的，可以先计算出算式的结果，再比较大小;1千克=1000克，单位不统一时，先化成相同单位，再比较大小。整数混合运算中，同级运算时，从左到右依次计算;两级运算时，先算乘除，后算加减;有括号时，先算括号里面的，再算括号外面的。\n\n【详解】8906\u003e8690;9千克=9000克，所以8960克\u003c9千克;95-(18+12)=95-30=65,95-18-12=65，所以95-(18+12)=95-18-12;63÷7/3=3,63-7×3=63-21=42，所以63÷7/3\u003c63-7×3。",
+        "knowledge_points":  [
+                                 "万以内数的大小比较，表内连乘，连除运算，带有小括号的混合运算，克，千克之间的换算与比较"
+                             ],
+        "source":  "22-23 二年级下·四川乐山·期末"
+    },
+    {
+        "id":  "332",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在括号里填上合适的质量单位.\n一块橡皮约重6( ) 一袋面粉重10( )\n一袋奶粉重900( ) 一袋盐重500( )",
+        "options":  [
+
+                    ],
+        "answer":  "克或g;千克或kg;克或g;克或g",
+        "solution":  "【分析】根据生活经验，对质量单位和数据大小的认识可知：计量比较轻的物体，常用克作单位,2个曲别针约重1克，所以计量橡皮的重量，奶粉的重量，盐的重量用克作单位比较合适;计量比较重的物体，常用千克作单位,2袋白砂糖约重1千克，所以计量面粉的重量用千克作单位比较合适。\n\n【详解】一块橡皮约重6克;一袋面粉重10千克;一袋奶粉重900克;一袋盐重500克。",
+        "knowledge_points":  [
+                                 "质量单位的选择"
+                             ],
+        "source":  "23-24二年级下·四川德阳·期末"
+    },
+    {
+        "id":  "333",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在括号里填\"\u003e\"\"\u003c\"或\"=\".\n7805( )78503400克( )4千克 10000( )99995千克( )5000克",
+        "options":  [
+
+                    ],
+        "answer":  "\u003c;\u003c;\u003e;=",
+        "solution":  "【分析】整数的大小比较：比较数的大小，先看数位的多少，数位多的数就大;数位相同，从高位开始比较，高位上的数大则这个数大，高位上的数相同，就比较下一位;单位之间的比较，先进行单位统一,1千克=1000克，在进行比较即可。\n\n【详解】7805\u003c7850;4千克=4000克，所以3400克\u003c4千克;10000\u003e9999;5千克=5000克。",
+        "knowledge_points":  [
+                                 "万以内数的大小比较，克，千克之间的换算与比较"
+                             ],
+        "source":  "22-23 二年级下·四川凉山·期末"
+    },
+    {
+        "id":  "334",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在括号里填上合适的单位.\n一个苹果约重200( ) 一只羊约重50( )\n小明同学身高125( ) 课间休息10( )",
+        "options":  [
+
+                    ],
+        "answer":  "克或g;千克或kg;厘米或cm;分钟或min",
+        "solution":  "【分析】根据生活常识和对重量单位，长度单位，时间单位的认识可知：如食指指甲盖的宽度大概是1厘米，计量小明同学身高125厘米比较合适;一粒黄豆的重量大约重1克，计量一个苹果约重200克比较合适;两袋盐的重量大概是1千克，计量一只羊重50千克比较合适;一分钟大约写十个大字，计量课间休息10分钟比较合适。\n\n【详解】一个苹果约重200克;一只羊约重50千克;小明同学身高125厘米;课间休息10分钟。",
+        "knowledge_points":  [
+                                 "时间单位的选择，质量单位的选择，长度单位的选择"
+                             ],
+        "source":  "22-23 二年级下·四川凉山·期末"
+    },
+    {
+        "id":  "335",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在括号里填上合适的单位名称.\n一袋糖重500( ) 一头羊约重60( ) 一根跳绳长2( )",
+        "options":  [
+
+                    ],
+        "answer":  "克或g;千克或kg;米或m",
+        "solution":  "【分析】联系生活实际，计量单位和数据的大小，灵活的选择。1克大约为一枚硬币的重量，计量一袋糖的重量用\"克\"作单位比较合适。1千克大约为两瓶矿泉水的重量，计量一头羊的重量用\"千克\"作单位比较合适。小学生两臂伸开的长度大约1米，计量一根跳绳的长度用\"米\"作单位比较合适。\n\n【详解】一袋糖重500克;一头羊约重60千克;一根跳绳长2米。",
+        "knowledge_points":  [
+                                 "质量单位的选择，长度单位的选择"
+                             ],
+        "source":  "22-23 二年级下·四川广元·期末"
+    },
+    {
+        "id":  "336",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "在括号里填上合适的数或单位.\n3千克=( )克 5千克400克=( )克 一个鸡蛋重约50( )\n一头牛重约350( ) 小明身高140( ) 一个书包价钱是60( )",
+        "options":  [
+
+                    ],
+        "answer":  "3000;5400;克或g;千克或kg;厘米或cm;元",
+        "solution":  "【分析】根据生活经验，对长度单位，质量单位，人民币单位和数据大小的认识可知：计量比较轻的物体，常用克作单位,2个曲别针约重1克，所以计量一个鸡蛋的重量用克作单位比较合适;计量比较重的物体，常用千克作单位,2袋白砂糖约重1千克，所以计量一头牛的重量用千克作单位比较合适;计量比较短的物体的长度，通常用厘米作单位，食指的宽大约是1厘米，所以计量小明的身高用厘米作单位比较合适;计量比较贵的物品的价格，常用元作单位，所以计量一个书包的价钱用元作单位比较合适;质量单位根据1千克=1000克进行换算。\n\n【详解】3千克=3000克;5千克400克=5000克+400克=5400克;一个鸡蛋重约50克;一头牛重约350千克;小明身高140厘米;一个书包价钱是60元。",
+        "knowledge_points":  [
+                                 "元，角，分的认识及换算，克，千克之间的换算与比较，质量单位的选择，长度单位的选择"
+                             ],
+        "source":  "22-23二年级下·四川乐山·期末"
+    },
+    {
+        "id":  "337",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "一袋洗衣粉重500克，每袋售价为7元,( )袋洗衣粉正好是1千克。28元可以买( )袋这样的洗衣粉。",
+        "options":  [
+
+                    ],
+        "answer":  "2;4",
+        "solution":  "【分析】根据1千克=1000克换算单位，连续加500克，直到和是1千克即可。根据除法的意义，总钱数/每袋洗衣粉的钱数=可以买洗衣粉的袋数。\n\n【详解】500克+500克=1000克=1千克;28÷7=4(袋);一袋洗衣粉重500克，每袋售价为7元,2袋洗衣粉正好是1千克。28元可以买4袋这样的洗衣粉。",
+        "knowledge_points":  [
+                                 "用7~9的乘法口诀求商，克，千克之间的换算与比较"
+                             ],
+        "source":  "22-23 二年级下·四川凉山·期末"
+    },
+    {
+        "id":  "338",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在括号里填上合适的质量单位.\n乐乐的体重约是30( ) 一个橘子约重150( )\n一个排球重约450( ) 一只熊猫约重120( )",
+        "options":  [
+
+                    ],
+        "answer":  "千克;克;克;千克",
+        "solution":  "【分析】1个2分钱的硬币约重1克,2袋食用盐约重1000克，计量比较轻的物体常用\"克\"(g)作单位，计量比较重的物体常用\"千克\"(kg)作单位,1千克=1000克。\n\n【详解】2袋食用盐约重1千克，计量体重用\"千克\"作单位比较合适，所以乐乐的体重约是30千克;1个2分钱的硬币约重1克，计量一个橘子用\"克\"作单位比较合适，所以一个橘子约重150克;1个2分钱的硬币约重1克，计量一个排球用\"克\"作单位比较合适，所以一个排球重约450克;2袋食用盐约重1千克，计量熊猫体重用\"千克\"作单位比较合适，所以一只熊猫约重120千克。",
+        "knowledge_points":  [
+                                 "克的认识，千克的认识"
+                             ],
+        "source":  "23-24 二年级下·四川乐山·期末"
+    },
+    {
+        "id":  "339",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在括号里填上合适的数.\n1000克=( )千克 7千克=( )克\n3000克+6000克=( )千克 10千克-5000克=( )千克",
+        "options":  [
+
+                    ],
+        "answer":  "1;7000;9;5",
+        "solution":  "【分析】(1)(2)根据1千克=1000克，低级单位克化高级单位千克除以进率1000，高级单位千克化低级单位克乘进率1000;(3)单位相同，直接计算，再把计算结果克数除以进率1000化成千克数;(4)把5000克除以进率1000化成5千克再计算。\n\n【详解】1000克=1千克;7千克=7000克;3000克=3千克,6000克=6千克,3千克+6千克=9千克，即3000克+6000克=9千克;5000克=5千克,10千克-5千克=5千克，即10千克-5000克=5千克。",
+        "knowledge_points":  [
+                                 "克，千克之间的换算与比较"
+                             ],
+        "source":  "24-25三年级上·湖南邵阳·期中"
+    },
+    {
+        "id":  "340",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "克可以用字母( )表示,1kg等于( )g。",
+        "options":  [
+
+                    ],
+        "answer":  "g;1000",
+        "solution":  "【分析】克，千克都属于常见的质量单位，千克用字母\"kg\"表示，克用字母\"g\"表示,1千克=1000克，据此解答。\n\n【详解】克可以用字母g表示,1kg等于1000g。",
+        "knowledge_points":  [
+                                 "克的认识，千克的认识，克，千克之间的换算与比较"
+                             ],
+        "source":  "24-25 三年级上·湖南邵阳·期中"
+    },
+    {
+        "id":  "341",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "我的身高是( ),我的体重是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "135厘米或135cm;25千克或25kg",
+        "solution":  "【分析】每个人都有自己的身高和体重，身高和体重的多少因人而异，本题答案不唯一，仅作参考。衡量身高一般用\"厘米(cm)\"表示，衡量体重一般用\"千克(kg)\"表示。三年级小学生的身高和体重一般在130厘米，体重一般在25千克。\n\n【详解】我的身高是135厘米，我的体重是25千克。(答案不唯一)",
+        "knowledge_points":  [
+                                 "质量单位的选择，长度单位的选择"
+                             ],
+        "source":  "24-25 三年级上·全国·单元测试"
+    },
+    {
+        "id":  "342",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在括号里填上合适的单位名称.\n乐乐9岁了，他的身高约130( ),体重约30( )。早上，他吃了一个重约100( )的肉夹馍，背着重约3( )的书包，高高兴兴地上学。",
+        "options":  [
+
+                    ],
+        "answer":  "厘米或cm;千克或kg;克或g;千克或kg",
+        "solution":  "【分析】根据生活经验，对长度单位，质量单位和数据大小的认识可知：量比较短的物体的长度，通常用厘米作单位，食指的宽大约是1厘米，所以结合数据130，乐乐的身高用厘米作单位比较合适;计量比较轻的物体，常用克作单位,2个曲别针约重1克，所以结合数据100，肉夹馍的重量用克作单位比较合适;计量比较重的物体，常用千克作单位,2袋白砂糖约重1千克，所以乐乐的体重，书包的重量用千克作单位比较合适。\n\n【详解】乐乐9岁了，他的身高约130厘米，体重约30千克。早上，他吃了一个重约100克的肉夹馍，背着重约3千克的书包，高高兴兴地上学。",
+        "knowledge_points":  [
+                                 "质量单位的选择，长度单位的选择"
+                             ],
+        "source":  "23-24 二年级下·河南南阳·期末"
+    },
+    {
+        "id":  "343",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在括号里填上\"克\"或\"千克\".\n二(1)班张萌萌的体重是28( ),上学期间他每天早上都要吃一个重约50( )的鸡蛋和一瓶250毫升的新鲜牛奶，然后背着约2( )重的书包去上学。",
+        "options":  [
+
+                    ],
+        "answer":  "千克;克;千克",
+        "solution":  "【分析】根据生活经验，对质量单位和数据大小的认识可知：计量比较重的物体，常用千克作单位,2袋白砂糖约重1千克，所以张萌萌的体重，书包的重量用千克作单位比较合适;计量比较轻的物体，常用克作单位,2个曲别针约重1克，所以鸡蛋的重量用克作单位比较合适。\n\n【详解】二(1)班张萌萌的体重是28千克，上学期间他每天早上都要吃一个重约50克的鸡蛋和一瓶250毫升的新鲜牛奶，然后背着约2千克重的书包去上学。",
+        "knowledge_points":  [
+                                 "质量单位的选择"
+                             ],
+        "source":  "23-24二年级下·贵州铜仁·期末"
+    },
+    {
+        "id":  "344",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "一盒纯牛奶重250克,4盒同样重的纯牛奶( )千克，因为1000克=( )千克。",
+        "options":  [
+
+                    ],
+        "answer":  "1;1",
+        "solution":  "【分析】将4盒牛奶的质量相加，再根据1千克=1000克结合题干要求进行解答即可。\n\n【详解】250+250+250+250=500+500=1000(克),1000克=1千克，所以4盒同样重的纯牛奶1千克，因为1000克=1千克。",
+        "knowledge_points":  [
+                                 "整百数，几百几十数的加减法口算，克，千克之间的换算与比较"
+                             ],
+        "source":  "23-24 二年级下·贵州六盘水·期末"
+    },
+    {
+        "id":  "345",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "在括号里填上\"\u003e\"\"\u003c\"或\"=\".\n878( )78773500克( )3千克 30÷6( )15/3",
+        "options":  [
+
+                    ],
+        "answer":  "\u003c;\u003e;=",
+        "solution":  "【分析】比较数的大小，先看位数的多少，位数多的数就大;如果位数相同，从最高位开始比较，最高位上的数大则这个数大，最高位上的数相同，就比较下一位，依次类推。单位不相同的两个数比较大小，先根据1千克=1000克，统一单位后再比较。含有算式的大小比较，可以先计算出每个算式的结果，再比较大小。\n\n【详解】878\u003c7877;3千克=3000克，所以3500克\u003e3千克;30÷6=5,15÷3=5，所以30÷6=15÷3。",
+        "knowledge_points":  [
+                                 "万以内数的大小比较，用2~5的乘法口诀求商，用6的乘法口诀求商，克，千克之间的换算与比较"
+                             ],
+        "source":  "23-24 二年级下·河南濮阳·期末"
+    },
+    {
+        "id":  "346",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "一只成年鸵鸟大约重130( ),它的蛋大约重1500( )。",
+        "options":  [
+
+                    ],
+        "answer":  "千克或kg;克或g",
+        "solution":  "【分析】根据题意，括号里应该填质量单位。常用的质量单位有克(g)和千克(kg)。我们知道，一枚回形针大约重1克，两瓶矿泉水大约重1千克。所以根据生活经验，对质量单位和数据大小的认识可知，计量一只成年鸵鸟的重量用\"千克\"作单位比较合适;计量鸵鸟蛋的重量用\"克\"作单位比较合适。\n\n【详解】一只成年鸵鸟大约重130千克，它的蛋大约重1500克。",
+        "knowledge_points":  [
+                                 "克的认识，千克的认识，质量单位的选择"
+                             ],
+        "source":  "23-24 二年级下·江西赣州·期末"
+    },
+    {
+        "id":  "347",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "一个橘子重120( )。小军的体重是23( )。",
+        "options":  [
+
+                    ],
+        "answer":  "克或g;千克或kg",
+        "solution":  "【分析】根据题意，括号里应该填质量单位。常用的质量单位有克(g)和千克(kg)。我们知道，一枚回形针大约重1克，两瓶矿泉水大约重1千克。所以根据生活经验，对质量单位和数据大小的认识可知，计量一个橘子的重量应该用\"克\"作单位比较合适;计量小军的体重应该用\"千克\"作单位比较合适。\n\n【详解】一个橘子重120克。小军的体重是23千克。",
+        "knowledge_points":  [
+                                 "克的认识，千克的认识，质量单位的选择"
+                             ],
+        "source":  "23-24 二年级下·河北廊坊·期末"
+    },
+    {
+        "id":  "348",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "一名三年级学生的体重是30( ),身高130( )。",
+        "options":  [
+
+                    ],
+        "answer":  "千克或kg;厘米或cm",
+        "solution":  "【分析】根据生活经验，对时间单位，面积单位，长度单位，质量单位，容积单位和数据大小的认识可知，计量比较重的物品，常用\"千克\"作单位。2袋盐重1千克，所以计量一名三年级学生的体重用\"千克\"作单位比较合适。量比较短的物体的长度，通常用厘米作单位。食指的宽大约是1厘米，所以计量一名三年级学生的身高用\"厘米\"作单位比较合适。\n\n【详解】一名三年级学生的体重是30千克，身高130厘米。",
+        "knowledge_points":  [
+                                 "质量单位的选择，长度单位的选择"
+                             ],
+        "source":  "24-25三年级上·广东东莞·期中"
+    },
+    {
+        "id":  "349",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "三年级小红的体重是32( ),身高是130( )。",
+        "options":  [
+
+                    ],
+        "answer":  "千克或kg;厘米或cm",
+        "solution":  "【分析】根据生活经验对重量单位，长度单位和数据大小的认识，称一般物体的重量用千克(kg)作单位，一只小狗的重量大约是10千克，所以小红的体重用\"千克\"作单位比较合适;计量较短的物体用厘米(cm)作单位，一把直尺大约是15厘米，但因为单位前面的数字是130所以小红的身高用\"厘米\"作单位比较合适。\n\n【详解】三年级小红的体重是32千克，身高是130厘米。",
+        "knowledge_points":  [
+                                 "质量单位的选择，长度单位的选择"
+                             ],
+        "source":  "23-24三年级上·河北保定·期中"
+    },
+    {
+        "id":  "350",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "三年级小君的体重是40( ),身高是135( )。",
+        "options":  [
+
+                    ],
+        "answer":  "千克或kg;厘米或cm",
+        "solution":  "【分析】1千克的重量大约相当于1立方分米水在室温中的重量，在生活中,1袋食盐的重量是500克，两袋盐的质量是1千克，所以计量三年级小君的体重用\"千克\"作单位比较合适。生活中食指宽大约1厘米，量比较短的物体，可以用\"厘米\"作单位，所以计量三年级小君的身高用\"厘米\"作单位比较合适。\n\n【详解】三年级小君的体重是40(千克),身高是135(厘米)。",
+        "knowledge_points":  [
+                                 "质量单位的选择，长度单位的选择"
+                             ],
+        "source":  "23-24 三年级上·河北邯郸·期中"
+    },
+    {
+        "id":  "351",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在括号里填上合适的单位.\n一包方便面重100( ) 小明的体重是26( )\n一个西瓜约重4( ) 一包薯片重50( )",
+        "options":  [
+
+                    ],
+        "answer":  "克或g;千克或kg;千克或kg;克或g",
+        "solution":  "【分析】根据生活经验，对质量单位和数据大小的认识可知：计量比较轻的物体，常用克作单位,2个曲别针约重1克，所以计量一包方便面的重量，一包薯片的重量用克作单位比较合适;计量比较重的物体，常用千克作单位,2袋白砂糖约重1千克，所以计量小明的体重，一个西瓜的重量用千克作单位比较合适。\n\n【详解】一包方便面重100克;小明的体重是26千克;一个西瓜约重4千克;一包薯片重50克。",
+        "knowledge_points":  [
+                                 "质量单位的选择"
+                             ],
+        "source":  "23-24 二年级下·山东济宁·期末"
+    },
+    {
+        "id":  "352",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在括号里填上\"\u003e\"\"\u003c\"或\"=\".\n5799( )5800600克( )6千克 5千克( )2500克\n36÷4+9( )36÷9+4600+500( )1000+100",
+        "options":  [
+
+                    ],
+        "answer":  "\u003c;\u003c;\u003e;\u003e;=",
+        "solution":  "【分析】先计算出每个算式的结果或先统一单位，然后比较大小即可。整数比较大小方法:①位数多的数大于位数少的数;②位数相同的，先比较最高位上的数，最高位上大的，数就大，最高位数相同的，就比较下一位，以此类推。1千克=1000克。\n\n【详解】5799\u003c5800;6千克=6000克，故,600克\u003c6千克;5千克=5000克，故,5千克\u003e2500克;36÷4+9=9+9=18,36÷9+4=4+4=8，故,36÷4+9\u003e36÷9+4;600+500=1100,1000+100=1100，故,600+500=1000+100。",
+        "knowledge_points":  [
+                                 "万以内数的大小比较，整百数，几百几十数的加减法口算，除加，除减混合运算，克，千克之间的换算与比较"
+                             ],
+        "source":  "23-24 二年级下·山西长治·期末"
+    },
+    {
+        "id":  "353",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "8000克=( )千克 5千克=( )克",
+        "options":  [
+
+                    ],
+        "answer":  "8;5000",
+        "solution":  "【分析】1000克=1千克，几千克就是几个1000克，据此解答。\n\n【详解】8000克=8千克;5千克=5000克。",
+        "knowledge_points":  [
+                                 "克，千克之间的换算与比较"
+                             ],
+        "source":  "23-24 二年级下·湖南衡阳·期末"
+    },
+    {
+        "id":  "354",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "在括号里填上\"\u003e\"\"\u003c\"或\"=\".\n32÷8( )27/916÷2( )1×8\n1593( )14854千克200克( )4500克",
+        "options":  [
+
+                    ],
+        "answer":  "\u003e;=;\u003e;\u003c",
+        "solution":  "【分析】比较数的大小时，位数多的数就大;位数相同比较最高位，最高位大的数就大;最高位相同比较下一位，直到比较出结果为止。第1,2题计算出各算式的结果再比较大小;第3题直接比较;第4题根据1千克=1000克统一单位再比较。\n\n【详解】32÷8=4;27÷9=3;4\u003e3，则32÷8\u003e27÷9;16÷2=8;1×8=8;8=8，则16÷2=1×8;1593\u003e1485;4千克200克=4200克;4200克\u003c4500克，则4千克200克\u003c4500克。",
+        "knowledge_points":  [
+                                 "万以内数的大小比较,8的乘法口诀及应用，用7~9的乘法口诀求商，克，千克之间的换算与比较"
+                             ],
+        "source":  "23-24 二年级下·湖南衡阳·期末"
+    },
+    {
+        "id":  "355",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在括号里填上合适的单位名称.\n一盒牙膏重180( ) 一袋大米重5( )\n一支铅笔长16( ) 刷一次牙大约需要2( )",
+        "options":  [
+
+                    ],
+        "answer":  "克或g;千克或kg;厘米或cm;分或分钟或min",
+        "solution":  "【分析】1克大约为一枚硬币的重量，计量一盒牙膏的重量用\"克\"作单位比较合适。1千克大约为两瓶矿泉水的重量，计量一袋大米的重量用\"千克\"作单位比较合适。大拇指的指甲长度大约1厘米，计量一支铅笔的长度用\"厘米\"作单位比较合适。削一个苹果的时间大约是1分钟，计量刷牙的时间用\"分\"作单位比较合适。\n\n【详解】一盒牙膏重180克;一袋大米重5千克;一支铅笔长16厘米;刷一次牙大约需要2分。",
+        "knowledge_points":  [
+                                 "时间单位的选择，质量单位的选择，长度单位的选择"
+                             ],
+        "source":  "23-24二年级下·湖北孝感·期末"
+    },
+    {
+        "id":  "356",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "一个西瓜约重4( ),2袋盐重1000( ),妈妈的身高是165( )。",
+        "options":  [
+
+                    ],
+        "answer":  "千克或kg;克或g;厘米或cm",
+        "solution":  "【分析】根据生活经验及结合给出的数据，来选择合适的计量单位。1袋盐重500克，则,2袋盐重1000克;2袋500克的盐重1千克，所以，要计量一个西瓜重用\"千克\"作单位比较合适;食指宽大约是1厘米，所以，计量妈妈身高用\"厘米\"作单位比较合适。\n\n【详解】由题意分析得：一个西瓜约重4千克,2袋盐重1000克，妈妈的身高是165厘米。",
+        "knowledge_points":  [
+                                 "质量单位的选择，长度单位的选择"
+                             ],
+        "source":  "23-24 二年级下·福建福州·期末"
+    },
+    {
+        "id":  "357",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在括号里填上合适的质量单位.\n一块橡皮约重6( ) 一个西瓜重4( )\n一只鸭重2999( )约3( ) 一桶奶粉重900( )",
+        "options":  [
+
+                    ],
+        "answer":  "克或g;千克或kg;克或g;千克或kg;克或g",
+        "solution":  "【分析】根据生活经验，对质量单位和数据大小的认识可知：计量比较轻的物体，常用克作单位,2个曲别针约重1克，所以橡皮的重量，奶粉的重量用克作单位比较合适;计量比较重的物体，常用千克作单位,2袋白砂糖约重1千克，所以西瓜的重量用千克作单位比较合适。鸭的重量应为2999克,2999接近3000，再根据1千克=1000克换算即可。\n\n【详解】2999克约3000克,3000克=3千克;一块橡皮约重6克;一个西瓜重4千克;一只鸭重2999克约3千克;一桶奶粉重900克。",
+        "knowledge_points":  [
+                                 "万以内数的估计，克，千克之间的换算与比较，质量单位的选择"
+                             ],
+        "source":  "23-24二年级下·湖北武汉·期末"
+    },
+    {
+        "id":  "358",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在括号里填上合适的单位或数.\n一头猪约重110( ) 一个鸡蛋重约50( )\n4000克=( )千克 3千克600克=( )克",
+        "options":  [
+
+                    ],
+        "answer":  "千克或kg;克或g;4;3600",
+        "solution":  "【分析】第一，二小题括号里应该填质量单位。常用的质量单位有克和千克。我们知道，一枚回形针大约重1克，两瓶矿泉水大约重1千克。所以根据生活经验，对质量单位和数据大小的认识可知，计量一头猪的重量用\"千克\"作单位比较合适;计量一个鸡蛋的重量用\"克\"作单位比较合适;第三，四小题根据1千克=1000克解答即可。\n\n【详解】一头猪约重110千克;一个鸡蛋重约50克;4000克=4千克;3千克600克=3000克+600克=3600克。",
+        "knowledge_points":  [
+                                 "克，千克之间的换算与比较，质量单位的选择"
+                             ],
+        "source":  "23-24 二年级下·湖南郴州·期末"
+    },
+    {
+        "id":  "359",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在( )里填上合适的质量单位：克，千克.\n一只鸵鸟大约重100( ) 一个鸡蛋大约重50( )",
+        "options":  [
+
+                    ],
+        "answer":  "千克;克",
+        "solution":  "【分析】根据生活经验，对质量单位和数据大小的认识可知：计量比较重的物体，常用千克作单位,2袋白砂糖约重1千克，所以鸵鸟的重量用千克作单位比较合适;计量比较轻的物体，常用克作单位,2个曲别针约重1克，所以鸡蛋的重量用克作单位比较合适。\n\n【详解】一只鸵鸟大约重100千克;一个鸡蛋大约重50克。",
+        "knowledge_points":  [
+                                 "质量单位的选择"
+                             ],
+        "source":  "23-24 二年级下·湖南衡阳·期末"
+    },
+    {
+        "id":  "360",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "1千克里面有( )个500克,6个500克是( )千克。",
+        "options":  [
+
+                    ],
+        "answer":  "2;3",
+        "solution":  "【分析】根据1千克=1000克换算单位。连续加500克，直到和是1千克即可;将6个500克相加，得出的结果换算为千克即可。\n\n【详解】500克+500克=1000克=1千克;500克+500克+500克+500克+500克+500克=3000克=3千克。1千克里面有2个500克,6个500克是3千克。",
+        "knowledge_points":  [
+                                 "克，千克之间的换算与比较"
+                             ],
+        "source":  "23-24 二年级下·河南三门峡·期末"
+    },
+    {
+        "id":  "361",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.94,
+        "question":  "比较轻的物品常用( )来称，用( )作单位。计量比较重的物品，常用( )作单位。",
+        "options":  [
+
+                    ],
+        "answer":  "天平;克或g;千克或kg",
+        "solution":  "【详解】比较轻的物品常用天平来称，用克作单位。计量比较重的物品，常用千克作单位。比如一支铅笔，我们会用克作为单位;儿童的体重，我们会用千克作为单位。",
+        "knowledge_points":  [
+                                 "克的认识，千克的认识"
+                             ],
+        "source":  "23-24 二年级下·河南三门峡·期末"
+    },
+    {
+        "id":  "362",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "每500克苹果需要6元，买1500克苹果需要( )元，买4千克苹果需要( )元。",
+        "options":  [
+
+                    ],
+        "answer":  "18;48",
+        "solution":  "【分析】1千克=1000克,1000克里面有2个500克。1500克里面有3个500克，每500克苹果需要6元，求买1500克苹果需要多少元，就是求3个6的和是多少，可以用乘法列式计算;4千克=4000克,4000克里面有8个500克，每500克苹果需要6元，求买4千克苹果需要多少元，就是求8个6的和是多少，可以用乘法列式计算。\n\n【详解】1500克里面有3个500克,3×6=18(元);4千克里面有8个500克,8×6=48(元),即，每500克苹果需要6元，买1500克苹果需要18元，买4千克苹果需要48元。",
+        "knowledge_points":  [
+                                 "6的乘法口诀及应用,8的乘法口诀及应用，克，千克之间的换算与比较"
+                             ],
+        "source":  "23-24二年级下·河北邯郸·期末"
+    },
+    {
+        "id":  "363",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "小明的身高是128( ),体重是36( ),他喜欢滑滑梯，滑滑梯的运动属于( )现象。",
+        "options":  [
+
+                    ],
+        "answer":  "厘米或cm;千克或kg;平移",
+        "solution":  "【分析】根据生活经验以及数据的大小，选择合适的计量单位。食指宽大约是1厘米，所以，计量一个人身高用\"厘米\"作单位比较合适;2包500克的盐重1千克，所以，要计量一个人体重用\"千克\"作单位比较合适;在平面内，一个图形绕着一个定点旋转一定的角度得到另一个图形的变化叫做旋转。在平面内，将一个图形上的所有点都按照某个方向作相同距离的移动，这样的图形运动叫平移。\n\n【详解】由题意分析得：小明的身高是128厘米，体重是36千克，他喜欢滑滑梯，滑滑梯的运动属于平移现象。",
+        "knowledge_points":  [
+                                 "平移与平移现象，质量单位的选择，长度单位的选择"
+                             ],
+        "source":  "23-24 二年级下·河北邯郸·期末"
+    },
+    {
+        "id":  "364",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在括号里填上合适的单位.\n一个梨子约重150( )。爸爸体重70( )。2袋食盐约重1( )。",
+        "options":  [
+
+                    ],
+        "answer":  "克或g;千克或kg;千克或kg",
+        "solution":  "【分析】根据生活经验，对质量单位和数据大小的认识可知：计量比较轻的物体，常用克作单位,2个曲别针约重1克，所以梨子的重量用克作单位比较合适;计量比较重的物体，常用千克作单位,2袋白砂糖重1千克，所以爸爸的体重和2袋食盐的重量用千克作单位比较合适。\n\n【详解】一个梨子约重150克。爸爸体重70千克。2袋食盐约重1千克。",
+        "knowledge_points":  [
+                                 "质量单位的选择"
+                             ],
+        "source":  "23-24二年级下·湖南衡阳·期末"
+    },
+    {
+        "id":  "365",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "填上合适的单位.\n一袋盐重500( ) 妈妈的身高是160( )\n一袋大米重25( ) 一个苹果约重200( )",
+        "options":  [
+
+                    ],
+        "answer":  "克或g;厘米或cm;千克或kg;克或g",
+        "solution":  "【分析】根据生活经验及结合给出的数据，来选择合适的质量单位或长度单位。由实际情况可知,1袋盐重500克,2袋盐重1千克，所以，要计量一袋大米重用\"千克\"作单位比较合适;1枚1分的硬币约重1克，所以，要计量一个苹果重用\"克\"作单位比较合适;食指宽大约是1厘米，所以，计量妈妈的身高用\"厘米\"作单位比较合适。\n\n【详解】由题意分析得：一袋盐重500克;妈妈的身高是160厘米;一袋大米重25千克;一个苹果约重200克。",
+        "knowledge_points":  [
+                                 "质量单位的选择，长度单位的选择"
+                             ],
+        "source":  "23-24 二年级下·山东临沂·期末"
+    },
+    {
+        "id":  "366",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在括号里填上合适的单位名称.\n一盒酸奶重120( ) 一本字典厚4( ) 一个西瓜重3( )",
+        "options":  [
+
+                    ],
+        "answer":  "克或g;厘米或cm;千克或kg",
+        "solution":  "【分析】根据生活经验，对长度单位，质量单位和数据大小的认识可知：计量比较轻的物体，常用克作单位,2个曲别针约重1克，所以酸奶的重量用克作单位比较合适;量比较短的物体的长度，通常用厘米作单位，食指的宽大约是1厘米，所以字典的厚度用厘米作单位比较合适;计量比较重的物体，常用千克作单位,2袋白砂糖重1千克，所以一个西瓜的重量用千克作单位比较合适。\n\n【详解】一盒酸奶重120克;一本字典厚4厘米;一个西瓜重3千克。",
+        "knowledge_points":  [
+                                 "质量单位的选择，长度单位的选择"
+                             ],
+        "source":  "23-24 二年级下·山东济宁·期末"
+    },
+    {
+        "id":  "367",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "计量一块香皂的质量用千克作单位更合适。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】根据生活经验以及对质量单位和数据大小的认识，量比较轻的物体的质量，通常用克作单位，如一粒花生米的质量大约是1克，量比较重的物体的质量，通常用千克作单位，如一个西瓜大约重3千克。据此解答即可。\n\n【详解】据分析可知：计量一块香皂的质量用克作单位更合适。原题说法错误。故答案为: ×",
+        "knowledge_points":  [
+                                 "克的认识，千克的认识，质量单位的选择"
+                             ],
+        "source":  "24-25二年级下·山东济宁·期末"
+    },
+    {
+        "id":  "368",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "5千克水和5000克蜂蜜一样重。( )",
+        "options":  [
+
+                    ],
+        "answer":  "√",
+        "solution":  "【分析】进行质量之间的比较时，和是水还是蜂蜜无关，根据质量单位千克和克之间的进率是1000,1千克=1000克，解答即可。\n\n【详解】根据分析:5千克=5000克，所以5千克水和5000克蜂蜜一样重。说法正确。故答案为:√",
+        "knowledge_points":  [
+                                 "克，千克之间的换算与比较"
+                             ],
+        "source":  "24-25 三年级上·贵州铜仁·期末"
+    },
+    {
+        "id":  "369",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "判断题",
+        "difficulty":  0.65,
+        "question":  "一名小学三年级学生的体重约35克。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】一名小学三年级学生的正常体重应在30千克左右，而35克仅相当于一个鸡蛋的重量，显然不符合实际。正确的单位应为\"千克\"。因此，题目中的说法是错误的。\n\n【详解】由分析可知，一名小学三年级学生的体重约35千克。所以题目说法错误。故答案为: ×",
+        "knowledge_points":  [
+                                 "克的认识，千克的认识，质量单位的选择"
+                             ],
+        "source":  "24-25 三年级上·湖北十堰·期末"
+    },
+    {
+        "id":  "370",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "判断题",
+        "difficulty":  0.65,
+        "question":  "2kg棉花比2kg铁轻。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】kg是质量单位，棉花和铁的重量都是2kg,所以2kg棉花与2kg铁一样重，据此解答即可。\n\n【详解】由分析可知,2kg棉花与2kg铁一样重，原说法错误。故答案为: ×",
+        "knowledge_points":  [
+                                 "千克的认识"
+                             ],
+        "source":  "24-25 三年级上·重庆大渡口·期末"
+    },
+    {
+        "id":  "371",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "一只小猫大约重3千克。( )",
+        "options":  [
+
+                    ],
+        "answer":  "√",
+        "solution":  "【分析】注意联系生活实际，计量单位和数据的大小，灵活的选择。1千克大约为两瓶矿泉水的重量，计量小猫的体重用\"千克\"作单位比较合适。\n\n【详解】一只小猫大约重3千克。原题说法正确。故答案为:√",
+        "knowledge_points":  [
+                                 "千克的认识"
+                             ],
+        "source":  "23-24 二年级下·河北邢台·期中"
+    },
+    {
+        "id":  "372",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "1000克糖比1千克棉花重。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】1千克=1000克，将单位统一后再进行比较。\n\n【详解】1000克=1千克,1000克糖和1千克棉花一样重。原题说法错误。故答案为: ×",
+        "knowledge_points":  [
+                                 "克，千克之间的换算与比较"
+                             ],
+        "source":  "22-23 二年级下·四川凉山·期末"
+    },
+    {
+        "id":  "373",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "一箱苹果的重量，一个成人的体重，一大袋大米的重量，通常用千克作单位。( )",
+        "options":  [
+
+                    ],
+        "answer":  "√",
+        "solution":  "【分析】1千克大约为两瓶矿泉水的重量，联系生活实际，灵活的选择。\n\n【详解】一箱苹果的重量，一个成人的体重，一大袋大米的重量，通常用千克作单位。原题说法正确。故答案为:√",
+        "knowledge_points":  [
+                                 "千克的认识，质量单位的选择"
+                             ],
+        "source":  "22-23 二年级下·四川南充·期末"
+    },
+    {
+        "id":  "374",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "5千克铁比5千克气球重。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】物体的质量和物体的材质无关。单位一致，直接比较即可判断。\n\n【详解】5千克=5千克,5千克铁和5千克气球一样重。原题说法错误。故答案为: ×",
+        "knowledge_points":  [
+                                 "千克的认识"
+                             ],
+        "source":  "22-23 二年级下·四川乐山·期末"
+    },
+    {
+        "id":  "375",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "判断题",
+        "difficulty":  0.65,
+        "question":  "800克钢比8千克棉花轻。( )",
+        "options":  [
+
+                    ],
+        "answer":  "√",
+        "solution":  "【分析】物体的质量和物体的材质无关,1千克=1000克，据此将棉花的质量换算成克，再与钢的质量比较大小，据此解答即可。\n\n【详解】8千克=8000克,800克\u003c8000克，所以800克钢比8千克棉花轻。原题说法正确。故答案为:√",
+        "knowledge_points":  [
+                                 "克的认识，千克的认识，克，千克之间的换算与比较"
+                             ],
+        "source":  "23-24二年级下·四川乐山·期末"
+    },
+    {
+        "id":  "376",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "1000g铁比1kg糖重。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】单位不一致，根据1kg=1000g,先化成统一的单位，再进行比较即可判断。\n\n【详解】1000g=1kg,1000g铁与1kg糖一样重，所以原题说法错误。故答案为: ×",
+        "knowledge_points":  [
+                                 "克，千克之间的换算与比较"
+                             ],
+        "source":  "23-24 三年级上·重庆云阳·期末"
+    },
+    {
+        "id":  "377",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "3千克棉花和3000克铁比较，铁比较重。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】物品的质量和物品的材料无关，根据质量单位的换算进率:1千克=1000克，把单位统一即可解答。\n\n【详解】3千克=3000克，因此3千克棉花和3000克铁一样重，所以题干说法是错误的。故答案为: ×",
+        "knowledge_points":  [
+                                 "克，千克之间的换算与比较"
+                             ],
+        "source":  "23-24三年级上·浙江宁波·期末"
+    },
+    {
+        "id":  "378",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "判断题",
+        "difficulty":  0.65,
+        "question":  "因为4\u003c400，所以4千克\u003c400克。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】1千克=1000克，则4千克就是4个1000克，依此将4千克化成克后再比较即可判断。\n\n【详解】4千克=4000克，所以4千克\u003e400克。故答案为: ×",
+        "knowledge_points":  [
+                                 "克，千克之间的换算与比较"
+                             ],
+        "source":  "24-25 三年级上·湖北十堰·期中"
+    },
+    {
+        "id":  "379",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "判断题",
+        "difficulty":  0.65,
+        "question":  "棉花又软又轻，所以1千克铁块要比1千克棉花更重一些。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】物体的质量和物体的材质无关，与物体重量有关，据此解答。\n\n【详解】由分析可得:1千克=1千克,1千克铁块和1千克棉花一样重，原题说法错误。故答案为: ×",
+        "knowledge_points":  [
+                                 "千克的认识"
+                             ],
+        "source":  "24-25三年级上·湖北襄阳·期中"
+    },
+    {
+        "id":  "380",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "妈妈的体重约5000克。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】根据生活经验，质量单位和数据大小的认识，可知妈妈的体重大约是50千克。1千克=1000克，据此将50千克换算成克。\n\n【详解】根据分析可知，妈妈的体重约50千克，即50000克。所以原题说法错误。故答案为: ×",
+        "knowledge_points":  [
+                                 "克的认识，千克的认识，克，千克之间的换算与比较"
+                             ],
+        "source":  "24-25 三年级上·广东茂名·期中"
+    },
+    {
+        "id":  "381",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "10颗黄豆大约重1克。( )",
+        "options":  [
+
+                    ],
+        "answer":  "√",
+        "solution":  "【分析】根据生活经验对质量单位和数据大小的认识，称比较轻的物体用克(g)作单位，一个苹果大约重70克，据此判断即可。\n\n【详解】10颗黄豆大约重1克。原题说法正确。故答案为:√",
+        "knowledge_points":  [
+                                 "克的认识，质量的估计"
+                             ],
+        "source":  "24-25 三年级上·河南洛阳·期中"
+    },
+    {
+        "id":  "382",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "判断题",
+        "difficulty":  0.65,
+        "question":  "李老师身高162厘米，体重55千克。( )",
+        "options":  [
+
+                    ],
+        "answer":  "√",
+        "solution":  "【分析】根据生活经验，以及对长度单位，质量单位和数据大小的认识，可知：计量比较短的物体的长度，可以用厘米作单位，食指的指甲盖的长度约是1厘米长，结合数据162，所以计量老师身高以厘米为单位比较合适;计量一般的物品的质量，通常用千克作单位,2袋食盐重1千克，结合数据55，所以计量李老师的体重以千克为单位比较合适;据此判断即可。\n\n【详解】由分析可知，李老师身高162厘米，体重55千克。原题说法正确。故答案为:√",
+        "knowledge_points":  [
+                                 "千克的认识，质量单位的选择，厘米的认识，长度单位的选择"
+                             ],
+        "source":  "24-25三年级上·广东肇庆·期中"
+    },
+    {
+        "id":  "383",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "判断题",
+        "difficulty":  0.65,
+        "question":  "1千克铁和1000克海绵一样重。( )",
+        "options":  [
+
+                    ],
+        "answer":  "√",
+        "solution":  "【分析】由\"1千克=1000克\"可知,1千克铁和1000克海绵是一样重;也就是物体轻重的比较与物体本身是什么材质无关，与物体本身的轻重有关。\n\n【详解】由题意分析得:1千克=1000克，则,1千克铁和1000克海绵一样重，此说法正确。故答案为:√",
+        "knowledge_points":  [
+                                 "克，千克之间的换算与比较"
+                             ],
+        "source":  "23-24二年级下·河南南阳·期末"
+    },
+    {
+        "id":  "384",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "3千克棉花糖比3000克红糖轻。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】根据1千克=1000克把单位统一后再比较即可。\n\n【详解】3千克=3000克，所以3千克棉花糖和3000克红糖一样重，原题说法错误。故答案为: ×",
+        "knowledge_points":  [
+                                 "克，千克之间的换算与比较"
+                             ],
+        "source":  "23-24 二年级下·贵州铜仁·期末"
+    },
+    {
+        "id":  "385",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "1千克铁比1000克面粉重。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】根据1千克=1000克统一单位后再比较即可。\n\n【详解】1千克=1000克，所以1千克铁和1000克面粉一样重，原题说法错误。故答案为: ×",
+        "knowledge_points":  [
+                                 "克，千克之间的换算与比较"
+                             ],
+        "source":  "23-24二年级下·河北廊坊·期末"
+    },
+    {
+        "id":  "386",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "一个苹果大约重50千克。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】根据生活经验对重量单位和数据大小的认识，称一般物体的重量用千克作单位;称比较轻的物体用克作单位，一个鸡蛋大约重80克，所以计量一个苹果的重量用\"克\"作单位比较合适。\n\n【详解】根据分析可知，一个苹果大约重50克。故答案为: ×",
+        "knowledge_points":  [
+                                 "质量单位的选择"
+                             ],
+        "source":  "23-24 三年级上·甘肃兰州·期中"
+    },
+    {
+        "id":  "387",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "数学课本长20克。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】数学课本的长度应该用长度单位，克是质量单位。长度单位:1米(m)大约为小学生双臂伸展开的长度;1厘米(cm)大约为指甲盖的宽度，根据生活经验和实际数据相结合，计量数学课本的长度应该用\"厘米\"作单位。\n\n【详解】由分析可得，数学课本长20厘米，原题说法错误。故答案为: ×",
+        "knowledge_points":  [
+                                 "克的认识，厘米的认识"
+                             ],
+        "source":  "23-24 二年级下·河南商丘·期末"
+    },
+    {
+        "id":  "388",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "一个鸡蛋重30千克。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】在计量单位的选择上，较小的物体如鸡蛋，通常使用\"克\"作为单位。较大的物体如人或大型动物，可能会使用\"千克\"或\"吨\"作为单位。1枚1分的硬币大约重1克,2袋盐重1千克,4只老虎大约重1吨，所以计量一个鸡蛋重量用\"克\"作单位比较合适。\n\n【详解】一个鸡蛋是较轻的物体，所以选择\"克\"为单位，一个鸡蛋重30克。故答案为: ×",
+        "knowledge_points":  [
+                                 "质量单位的选择"
+                             ],
+        "source":  "23-24 二年级下·河北保定·期末"
+    },
+    {
+        "id":  "389",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "2千克棉花和2千克铁，铁重些。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】比较两个物体重量的关系，无论物体的材质如何，只比较重量大小即可，由此解答。\n\n【详解】2千克=2千克,2千克棉花和2千克铁一样重，原题说法错误。故答案为: ×",
+        "knowledge_points":  [
+                                 "千克的认识"
+                             ],
+        "source":  "23-24 二年级下·湖南衡阳·期末"
+    },
+    {
+        "id":  "390",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "世界上现存最大的鸟是鸵鸟，它的一个蛋约有1500克。( )",
+        "options":  [
+
+                    ],
+        "answer":  "√",
+        "solution":  "【分析】注意联系生活实际，计量单位和数据的大小,1克大约为一枚硬币的重量，所以一个鸵鸟蛋大约1500克。\n\n【详解】世界上现存最大的鸟是鸵鸟，它的一个蛋约有1500克。原题说法正确。故答案为:√",
+        "knowledge_points":  [
+                                 "克的认识"
+                             ],
+        "source":  "23-24二年级下·河南三门峡·期末"
+    },
+    {
+        "id":  "391",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "爸爸买回8000克豆油，吃掉5千克后，又买回2000克菜籽油，还有多少千克油。",
+        "options":  [
+
+                    ],
+        "answer":  "5千克",
+        "solution":  "【分析】据题意，需要进行单位的换算，根据1千克=1000克，可知8000克=8千克,2000克=2千克，进行统一的单位后在进行计算;爸爸买回8千克豆油，吃掉了5千克，可用减法计算出还剩多少，又买回2千克，可用剩余的数量加上新买回来的即可得出还有多少千克油。\n\n【详解】8000克=8千克,2000克=2千克,8-5+2=3+2=5(千克),答：还有5千克油。",
+        "knowledge_points":  [
+                                 "克，千克之间的换算与比较"
+                             ],
+        "source":  "2025 二年级下·全国·专题练习"
+    },
+    {
+        "id":  "392",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "有5袋白糖，有3袋红糖，每袋糖重3千克，请问红糖一共比白糖少多少千克。",
+        "options":  [
+
+                    ],
+        "answer":  "6千克",
+        "solution":  "【分析】先用白糖的袋数减去红糖的袋数算出红糖比白糖少的袋数，最后用红糖比白糖少的袋数乘每袋糖的重量即可求解。\n\n【详解】5-3=2(袋),2×3=6(千克),答：红糖一共比白糖少6千克。",
+        "knowledge_points":  [
+                                 "3的乘法口诀及应用，千克的认识"
+                             ],
+        "source":  "23-24 二年级下·广东汕头·期中"
+    },
+    {
+        "id":  "393",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "露露抱着两个同样重的哈密瓜一起称体重，共重29千克。已知一个哈密瓜重2千克，露露的体重是多少千克。",
+        "options":  [
+
+                    ],
+        "answer":  "25千克",
+        "solution":  "【分析】用露露和两个哈密瓜一共的重量依次减去每个哈密瓜的重量即可求出露露的体重是多少千克。\n\n【详解】29-2-2=25(千克),答：露露的体重是25千克。",
+        "knowledge_points":  [
+                                 "100以内数的连减运算，千克的认识"
+                             ],
+        "source":  "23-24 二年级下·河北邢台·期中"
+    },
+    {
+        "id":  "394",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "食堂运来550千克大米，吃了250千克，现在又运来180千克，食堂现在有多少千克大米。",
+        "options":  [
+
+                    ],
+        "answer":  "480千克",
+        "solution":  "【分析】用食堂最开始运来的质量减去吃了的质量，再加上又运来的质量即可求出食堂现在有多少千克大米。\n\n【详解】550-250+180=300+180=480(千克),答：食堂现在有480千克大米。",
+        "knowledge_points":  [
+                                 "整百数，几百几十数的加减法口算，千克的认识"
+                             ],
+        "source":  "22-23 二年级下·四川凉山·期末"
+    },
+    {
+        "id":  "395",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "水果店早上运来90千克苹果，下午卖出去35千克，晚上卖了47千克。水果店还剩下多少千克苹果。",
+        "options":  [
+
+                    ],
+        "answer":  "8千克",
+        "solution":  "【分析】用运来的质量减下午卖出的质量，再减晚上卖出的质量，即可求出水果店还剩下多少千克苹果。\n\n【详解】90-35-47=8(千克),答：水果店还剩下8千克苹果。",
+        "knowledge_points":  [
+                                 "100以内数的连减运算，千克的认识"
+                             ],
+        "source":  "22-23 二年级下·四川乐山·期末"
+    },
+    {
+        "id":  "396",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "小方调查了每500克下面素菜的价格.\n\n| 素菜种类 | 胡萝卜 | 茄子 | 辣椒 | 西红柿 |\n| -------- | ------ | ------ | ---- | ------ |\n| 数量 | 2根 | 1个 | 4个 | 3个 |\n| 价格 | 8角 | 1元5角 | 9角 | 1元 |\n\n(1)买2千克西红柿有多少个。又要花多少钱呢。\n(2)你能根据表中信息，提一个问题并解答吗。",
+        "options":  [
+
+                    ],
+        "answer":  "12个;4元;买1千克胡萝卜要花多少钱。1元6角(答案不唯一)",
+        "solution":  "【分析】(1)1千克=1000克，则,2千克=2000克;1000克里面有2个500克，则,2000克里面有4个500克;而500克的西红柿有3个，且需要1元钱，故，求买2千克西红柿有多少个，就是求4个3的和是多少，可以用乘法列式解决;求买2千克西红柿要花多少钱，就是求4个1的和是多少，可以用乘法列式解决。(2)根据已知条件提出数学问题，答案不唯一，合理即可。\n\n【详解】(1)2千克=2000克;且2000克里面有4个500克;3×4=12(个),1×4=4(元),答：买2千克西红柿有12个;要花4元。(2)买1千克胡萝卜要花多少钱。1千克=1000克;且1000克里面有2个500克;2×8=16(角),16角=1元6角，答：买1千克胡萝卜要花1元6角。(答案不唯一)",
+        "knowledge_points":  [
+                                 "\"提问题\"\"填条件\"问题,4的乘法口诀及应用,8的乘法口诀及应用，克，千克之间的换算与比较"
+                             ],
+        "source":  "23-24 二年级下·江西赣州·期末"
+    },
+    {
+        "id":  "397",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "一袋白糖重500克，一瓶洗衣液重2千克。一瓶洗衣液比一袋白糖重多少克。",
+        "options":  [
+
+                    ],
+        "answer":  "1500克",
+        "solution":  "【分析】根据减法的意义，一瓶洗衣液的重量-一袋白糖的重量=一瓶洗衣液比一袋白糖重的重量，根据1千克=1000克统一单位再计算。\n\n【详解】2千克=2000克,2000-500=1500(克),答：一瓶洗衣液比一袋白糖重1500克。",
+        "knowledge_points":  [
+                                 "整百数，几百几十数的加减法口算，克，千克之间的换算与比较"
+                             ],
+        "source":  "23-24 二年级下·山东济宁·期末"
+    },
+    {
+        "id":  "398",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "普通水稻亩产400千克，袁隆平爷爷的杂交水稻亩产700千克，杂交水稻比普通水稻亩产多多少千克。",
+        "options":  [
+
+                    ],
+        "answer":  "300千克",
+        "solution":  "【分析】根据减法的意义，杂交水稻亩产量-普通水稻亩产量=杂交水稻比普通水稻亩产多的量。\n\n【详解】700-400=300(千克),答：杂交水稻比普通水稻亩产多300千克。",
+        "knowledge_points":  [
+                                 "整百数，几百几十数的加减法口算，千克的认识"
+                             ],
+        "source":  "23-24 二年级下·湖南衡阳·期末"
+    },
+    {
+        "id":  "399",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "以下是果太郎水果店部分水果的标价。妈妈买了500克香蕉和2千克桃，应付多少钱。\n\n| 水果 | 价格 |\n| ---- | --------- |\n| 桃 | 4元/500克 |\n| 香蕉 | 2元/500克 |",
+        "options":  [
+
+                    ],
+        "answer":  "18元",
+        "solution":  "【分析】根据题意，先计算出2千克里面有几个500克，再和每500克桃的价格相乘，求出2千克桃一共需要多少钱，再和500克香蕉的价格相加就是一共要付的钱数。\n\n【详解】1千克=1000克;2千克=2000克;500克+500克+500克+500克=2000克,2000克里有4个500克。4×4+2=16+2=18(元),答：应付18元钱。",
+        "knowledge_points":  [
+                                 "乘加，乘减混合运算，克，千克之间的换算与比较"
+                             ],
+        "source":  "23-24二年级下·湖北武汉·期末"
+    },
+    {
+        "id":  "400",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "超市里500克草莓售价3元，张阿姨买了3500克草莓，应付多少元。\n口答：应付( )元。",
+        "options":  [
+
+                    ],
+        "answer":  "21;21元",
+        "solution":  "【分析】根据题意，先计算出3500克里有几个500克，再和每500克的价格相乘，就是应付的钱数。\n\n【详解】500克+500克+500克+500克+500克+500克+500克=3500克,3500克里有7个500克。3×7=21(元),答：应付21元。",
+        "knowledge_points":  [
+                                 "7的乘法口诀及应用，克的认识"
+                             ],
+        "source":  "23-24 二年级下·河南三门峡·期末"
+    },
+    {
+        "id":  "401",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "下面物品中,( )的重量最接近1克。",
+        "options":  [
+                        "A. 1粒花生米",
+                        "B. 1罐可乐",
+                        "C. 1个鸡蛋"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】根据生活经验，对质量单位和数据大小的认识可知：计量比较轻的物体，常用克作单位,2个曲别针约重1克，由此选择即可。\n\n【详解】A。1粒花生米的重量接近1克;B。1罐可乐大约250克;C。1个鸡蛋大约60克;所以1粒花生米的重量最接近1克。故答案为:As",
+        "knowledge_points":  [
+                                 "克的认识，质量的估计"
+                             ],
+        "source":  "23-24二年级下·山东济宁·期末"
+    },
+    {
+        "id":  "402",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "6千克油和7000克棉花相比较( )。",
+        "options":  [
+                        "A. 油重",
+                        "B. 油轻",
+                        "C. 同样重"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】根据1千克=1000克统一单位后，再比较即可。物体的轻重与物体本身的材质无关，与物体本身轻重有关。\n\n【详解】7000克=7千克,6千克\u003c7千克,6千克油和7000克棉花相比较油轻。故答案为:B",
+        "knowledge_points":  [
+                                 "克，千克之间的换算与比较"
+                             ],
+        "source":  "23-24 二年级下·山东菏泽·期末"
+    },
+    {
+        "id":  "403",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "欢欢的爸爸的身高是180厘米，他的体重可能是( )。",
+        "options":  [
+                        "A. 10千克",
+                        "B. 75克",
+                        "C. 75千克"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】根据生活经验，对质量单位和数据大小的认识可知：计量比较轻的物体，常用克作单位,2个曲别针约重1克;计量比较重的物体，常用千克作单位,2袋白砂糖重1千克;所以计量爸爸的体重用千克作单位比较合适。由此选择即可。\n\n【详解】A。10千克大约是一袋大米的重量，不符合题意;B。75克大约是1个鸭蛋的重量，不符合题意;C。75千克符合爸爸的体重;所以他的体重可能是75千克。故答案为:C",
+        "knowledge_points":  [
+                                 "质量单位的选择，质量的估计"
+                             ],
+        "source":  "23-24二年级下·广东汕尾·期末"
+    },
+    {
+        "id":  "404",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "超市里西红柿每500克3元，胡萝卜每500克8角，妈妈买1千克西红柿和2500克胡萝卜要( )钱。",
+        "options":  [
+                        "A. 5元",
+                        "B. 5元4角",
+                        "C. 10元"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】根据题意，先计算出1千克和2500克里有几个500克，再分别和每500克的价格相乘，求出每种蔬菜的价格，再相加就是总价格。\n\n【详解】西红柿:1千克=1000克;500克+500克=1000克;1千克里有2个500克。3×2=6元;胡萝卜:500克+500克+500克+500克+500克=2500克;2500克里有5个500克。8×5=40(角);1元=10角;40角=4元;总价格:6元+4元=10元，妈妈买1千克西红柿和2500克胡萝卜要10元钱。故答案为:C",
+        "knowledge_points":  [
+                                 "克，千克之间的换算与比较，元，角，分的认识及换算,8的乘法口诀及应用"
+                             ],
+        "source":  "23-24 二年级下·河南南阳·期末"
+    },
+    {
+        "id":  "405",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "2个一元硬币大约重( )。",
+        "options":  [
+                        "A. 12克",
+                        "B. 12千克",
+                        "C. 12米"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】一般情况下，表示重量的单位有\"克\"，\"千克\"，表示长度的单位有\"米\"，\"厘米\"，此题考查根据情景选择合适的计量单位，要注意联系生活实际，计量单位和数据的大小，灵活的选择。\n\n【详解】A。1枚一元硬币大约重6克,2个一元硬币大约重12克;B。1千克大约为两瓶矿泉水的重量,12千克太重不合适;C.\"米\"是长度单位，不合适。所以2个一元硬币大约重12克。故答案为:A",
+        "knowledge_points":  [
+                                 "质量单位的选择，千克的认识，克的认识"
+                             ],
+        "source":  "23-24二年级下·江西吉安·期末"
+    },
+    {
+        "id":  "406",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "( )的质量约是100克。",
+        "options":  [
+                        "A. 一个苹果",
+                        "B. 一粒黄豆",
+                        "C. 一只鸡"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】根据生活经验，对质量单位和数据大小的认识可知：计量比较轻的物体，常用克作单位,2个曲别针约重1克，由此选择即可。\n\n【详解】A。一个苹果的质量大约为100克，符合题意;B。一粒黄豆的质量比100克轻得多，不符合题意;C。一只鸡的质量比100克多得多，不符合题意;所以一个苹果的质量约是100克。故答案为:A",
+        "knowledge_points":  [
+                                 "克的认识，质量的估计"
+                             ],
+        "source":  "23-24 二年级下·河北保定·期末"
+    },
+    {
+        "id":  "407",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "1000粒黄豆重约500克,2000粒黄豆约重( )。",
+        "options":  [
+                        "A. 500克",
+                        "B. 1千克",
+                        "C. 1000千克",
+                        "D. 5千克"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】根据克与千克之间的进率,1千克=1000克，将2000粒黄豆的重量估计出来，进行单位换算即可。\n\n【详解】1000粒黄豆重约500克,2000里面有2个1000,2个500是1000，则2000粒黄豆约重1000克,1000克=1千克。故答案为:B",
+        "knowledge_points":  [
+                                 "克，千克之间的换算与比较"
+                             ],
+        "source":  "23-24二年级下·福建龙岩·期末"
+    },
+    {
+        "id":  "408",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "1只鸡重2千克,1只猴重( )千克.\n![](images/87056e48c287c0a2b7916eec1a14de00.png)",
+        "options":  [
+                        "A. 8",
+                        "B. 10",
+                        "C. 12"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】根据题意可知，一只鸡的重量是2千克，一个天平上两只鸡和一只兔子的重量一样，可知一只兔子的重量是4千克。两只兔子的重量和一只猴子的重量一样，计算可以得出猴子的重量。\n\n【详解】2×2×2=4×2=8(千克),一只鸡重2千克,1只猴重8千克。故答案为:A",
+        "knowledge_points":  [
+                                 "千克的认识,2的乘法口诀及应用"
+                             ],
+        "source":  "23-24 二年级下·河北邢台·期末"
+    },
+    {
+        "id":  "409",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "王叔叔买了一盒碧螺春茶，茶叶与盒子共重1400克，盒子重200克。下面( )是他买的碧螺春茶。",
+        "options":  [
+                        "A. 净含量:1600克",
+                        "B. 净含量:12千克",
+                        "C. 净含量:1200克"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】根据减法的意义，茶叶与盒子的总重量-盒子的重量=茶叶净含量，由此解答。\n\n【详解】1400-200=1200(克),C净含量:1200克的是他买的碧螺春茶。故答案为:C",
+        "knowledge_points":  [
+                                 "克的认识"
+                             ],
+        "source":  "23-24二年级下·湖南湘西·期末"
+    },
+    {
+        "id":  "410",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "下列物体中( )的质量大约是1千克。",
+        "options":  [
+                        "A. 6个红富士苹果",
+                        "B. 两颗鸡蛋",
+                        "C. 200粒黄豆"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】计量比较轻的物品，常用克作单位，计量比较重的物体，用千克作单位，两袋盐重1000克，也可以说是重1千克。根据生活经验，对质量单位和数据大小的认识可知：两颗鸡蛋不如一袋盐重，不到1千克;黄豆比较轻,200粒黄豆也不如一袋盐重，不到1千克;6个红富士苹果和两袋盐差不多重，据此可以解答。\n\n【详解】A。两袋盐重1千克,6个红富士苹果和两袋盐差不多重，所以6个红富士苹果的质量大约是1千克。B。两颗鸡蛋不如一袋盐重，不到1千克。C。200粒黄豆也不如一袋盐重，不到1千克。故答案为:A",
+        "knowledge_points":  [
+                                 "千克的认识，克的认识"
+                             ],
+        "source":  "23-24 三年级下·内蒙古包头·期末"
+    },
+    {
+        "id":  "411",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "一桶油连桶重8千克，桶重400克，油重( )。",
+        "options":  [
+                        "A. 7千克600克",
+                        "B. 760克",
+                        "C. 8400克"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】根据减法的意义，油连桶的重量-桶的重量=油的重量，根据1千克=1000克换算计算。\n\n【详解】8千克=8000克,8000-400=7600克,7600克=7千克600克，油重7千克600克。故答案为:A",
+        "knowledge_points":  [
+                                 "克，千克之间的换算与比较，整百数，几百几十数的加减法口算"
+                             ],
+        "source":  "23-24 二年级下·广西柳州·期末"
+    },
+    {
+        "id":  "412",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "称一头牛的体重，用( )作单位。",
+        "options":  [
+                        "A. 米",
+                        "B. 克",
+                        "C. 千克"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】根据生活实际，结合质量的认识，计量比较重的物品，常用\"千克\"作单位。据此判断。\n\n【详解】称一头牛的体重，用千克作单位。故答案为:C",
+        "knowledge_points":  [
+                                 "质量单位的选择，千克的认识"
+                             ],
+        "source":  "23-24 二年级下·广东汕头·期末"
+    },
+    {
+        "id":  "413",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "下面是三件物品的质量，最重的是( )。",
+        "options":  [
+                        "A. 960克",
+                        "B. 1200克",
+                        "C. 2千克"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】根据1千克=1000克，先将单位统一，再进行比较大小即可得出答案。\n\n【详解】2千克=2000克,960克\u003c1200克\u003c2000克，所以三件物品中，质量最重的是2千克。故答案为:C",
+        "knowledge_points":  [
+                                 "克，千克之间的换算与比较，万以内数的大小比较"
+                             ],
+        "source":  "23-24二年级下·广东肇庆·期末"
+    },
+    {
+        "id":  "414",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "一个南瓜约重4千克,( )个南瓜约重8000克。",
+        "options":  [
+                        "A. 2000",
+                        "B. 4",
+                        "C. 2",
+                        "D. 7600"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】根据1千克=1000克，先将单位统一,8000克=8千克，一个南瓜约重4千克，求几个4千克的南瓜是8千克，用除法计算。\n\n【详解】8000克=8千克,8÷4=2(个),所以是2个南瓜约重8000克。故答案为:C",
+        "knowledge_points":  [
+                                 "克，千克之间的换算与比较"
+                             ],
+        "source":  "23-24二年级下·四川内江·期末"
+    },
+    {
+        "id":  "415",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "一只小猫大约重( )。",
+        "options":  [
+                        "A. 3千克",
+                        "B. 30千克",
+                        "C. 3克",
+                        "D. 30克"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】根据生活经验及给出的答案进行估计即可。2包500克的盐重1千克，所以，通过比较可知，一只小猫大约重3千克比较合适。\n\n【详解】由题意分析得：一只小猫大约重3千克。故答案为:A",
+        "knowledge_points":  [
+                                 "克的认识，千克的认识，质量的估计"
+                             ],
+        "source":  "23-24 二年级下·浙江宁波·期末"
+    },
+    {
+        "id":  "416",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "一个杯子里装满了一杯水，连杯子称一共800克。如倒掉半杯水，剩下的连杯子称一共( )。",
+        "options":  [
+                        "A. 大于400克",
+                        "B. 等于400克",
+                        "C. 小于400克"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】800克的一半是400克;800克是杯子与水的质量，去掉杯子质量后，水的质量小于800克，那么半杯水的质量就小于400克，所以剩下的半杯水与杯子的质量就一定大于400克;据此解决即可。\n\n【详解】由题意分析得：一个杯子里装满了一杯水，连杯子称一共800克。如倒掉半杯水，剩下的连杯子称一共大于400克。故答案为:A",
+        "knowledge_points":  [
+                                 "克的认识"
+                             ],
+        "source":  "23-24 二年级下·浙江台州·期末"
+    },
+    {
+        "id":  "417",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "2千克棉花和2千克铁相比( )。",
+        "options":  [
+                        "A. 铁重",
+                        "B. 棉花重",
+                        "C. 一样重",
+                        "D. 无法比较"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】比较棉花和铁的轻重，直接比较质量即可。\n\n【详解】2千克=2千克，也就是2千克棉花和2千克铁块比较一样重。故答案为:C",
+        "knowledge_points":  [
+                                 "千克的认识"
+                             ],
+        "source":  "23-24 二年级下·山东济南·期末"
+    },
+    {
+        "id":  "418",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "图中的梨共重( ).\n![](images/64d745d55f407acc2129f4c19b1bc500a06a1ebdd3c5bed80bddbb97b5de7fc7.jpg)",
+        "options":  [
+                        "A. 210克",
+                        "B. 300克",
+                        "C. 300千克"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】指针指向200和400中间，是指向300的，单位是\"克\"，表示的是300克。\n\n【详解】图中的梨共重300克。故答案为:B",
+        "knowledge_points":  [
+                                 "克的认识"
+                             ],
+        "source":  "23-24二年级下·四川绵阳·期末"
+    },
+    {
+        "id":  "419",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "下面的秤最多能称( )重的物品.\n![](images/42d785eb5789f9f8a8fd4034c2ef552ad765adcd1caed66fdb3b8db9a2a44df1.jpg)",
+        "options":  [
+                        "A. 9kg",
+                        "B. 10g",
+                        "C. 10kg"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】这秤是以\"kg\"为单位，秤上的最大值是10，故，这秤最多能称10kg重的物品。\n\n【详解】由题意分析得：下面的秤最多能称(10kg)重的物品。故答案为:C",
+        "knowledge_points":  [
+                                 "克的认识，千克的认识"
+                             ],
+        "source":  "23-24二年级下·海南省直辖县级单位·期末"
+    },
+    {
+        "id":  "420",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在括号里填上合适的单位.\n乐乐的身高是125( ),他的体重是30( ),每天在校学习的时间大约是6( )。",
+        "options":  [
+
+                    ],
+        "answer":  "厘米或cm;千克或kg;时或小时或h",
+        "solution":  "【分析】根据生活经验，对长度单位，质量单位，时间单位和数据大小的认识可知：量比较短的物体的长度，通常用厘米作单位，食指的宽大约是1厘米，所以乐乐的身高用厘米作单位比较合适;计量比较重的物体，常用千克作单位,2袋白砂糖重1千克，所以乐乐的体重用千克作单位比较合适;表示比较长的时间，常用时作单位，所以在校学习时间用时作单位比较合适。\n\n【详解】乐乐的身高是125厘米，他的体重是30千克，每天在校学习的时间大约是6时。",
+        "knowledge_points":  [
+                                 "长度单位的选择，质量单位的选择，时间单位的选择"
+                             ],
+        "source":  "23-24 二年级下·江西赣州·期末"
+    },
+    {
+        "id":  "421",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在括号里填上\"克\"或\"千克\".\n一个梨约重200( );一头猪约重200( )。",
+        "options":  [
+
+                    ],
+        "answer":  "克或g;千克或kg",
+        "solution":  "【分析】根据生活经验，对质量单位和数据大小的认识可知：计量比较轻的物体，常用克作单位,2个曲别针约重1克，所以一个梨的重量用克作单位比较合适;计量比较重的物体，常用千克作单位,2袋白砂糖约重1千克，所以一头猪的重量用千克作单位比较合适。\n\n【详解】一个梨约重200克;一头猪约重200千克。",
+        "knowledge_points":  [
+                                 "质量单位的选择"
+                             ],
+        "source":  "23-24 二年级下·广东江门·期末"
+    },
+    {
+        "id":  "422",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "1000克=( )千克 200克+800克=( )千克",
+        "options":  [
+
+                    ],
+        "answer":  "1;1",
+        "solution":  "【分析】相同单位的直接相加计算出结果，根据1千克=1000克换算即可。\n\n【详解】1000克=1千克;200克+800克=1000克=1千克。",
+        "knowledge_points":  [
+                                 "克，千克之间的换算与比较"
+                             ],
+        "source":  "23-24 二年级下·广东江门·期末"
+    },
+    {
+        "id":  "423",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在( )里填上合适的质量单位.\n(1)一只鹅重3967( ),约重4( ).\n(2)世界上现存最大的鸟是鸵鸟。一只成年鸵鸟大约重130( ),它的一个蛋就大约有1500( )重。",
+        "options":  [
+
+                    ],
+        "answer":  "克或g;千克或kg 千克或kg;克或g",
+        "solution":  "【分析】(1)根据我们日常生活经验，一个大西瓜的重量大约为4000克，一只鹅与一个西瓜的重量差不多，所以鹅的重量用克来表示,1000克=1千克，根据四舍五入即可知大约多重。(2)根据我们日常生活经验，一个成年人的体重大约是80千克，鸵鸟与人的体重比较接近，所以鸵鸟的体重用千克来表示;一个鸵鸟蛋的重量要比鸡蛋大得多，结合数据1500，鸵鸟蛋的重量用克作单位比较合适。\n\n【详解】(1)一只鹅重3967克，约重4千克。(2)世界上现存最大的鸟是鸵鸟。一只成年鸵鸟大约重130千克，它的一个蛋就大约有1500克重。",
+        "knowledge_points":  [
+                                 "质量单位的选择，千克的认识，克的认识"
+                             ],
+        "source":  "23-24二年级下·湖北武汉·期末"
+    },
+    {
+        "id":  "424",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "在括号里填上\"\u003e\"\"\u003c\"或\"=\".\n1001( )999990克( )9千克 28÷4( )45/5\n785( )87055千克( )5000克 40÷8( )54/9",
+        "options":  [
+
+                    ],
+        "answer":  "\u003e\u003c;\u003c;\u003c;\u003c;=;\u003c",
+        "solution":  "【分析】比较数的大小时，位数多的数就大;位数相同比较最高位，最高位大的数就大;最高位相同比较下一位，直到比较出结果为止。第1,4题直接比较;第2,5题根据1千克=1000克统一单位后再比较;第3,6题依次计算出各算式的结果后再比较。\n\n【详解】1001\u003e999;9千克=9000克,990克\u003c9000克，则990克\u003c9千克;28÷4=7;45÷5=9;7\u003c9，则28÷4\u003c45÷5;785\u003c8705;5千克=5000克;40÷8=5;54÷9=6;5\u003c6，则40÷8\u003c54÷9。",
+        "knowledge_points":  [
+                                 "克，千克之间的换算与比较，用7~9的乘法口诀求商，万以内数的大小比较"
+                             ],
+        "source":  "23-24二年级下·河北保定·期末"
+    },
+    {
+        "id":  "425",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在( )里填上合适的单位.\n一个鸭蛋约重70( )。一个西瓜约重5( ).\n一头羊约重80( )。教室长9( )。",
+        "options":  [
+
+                    ],
+        "answer":  "克或g;千克或kg;千克或kg;米/m",
+        "solution":  "【分析】根据生活经验，对长度单位，质量单位和数据大小的认识可知：计量比较轻的物体，常用克作单位,2个曲别针约重1克，所以鸭蛋的重量用克作单位比较合适;计量比较重的物体，常用千克作单位,2袋白砂糖重1千克，所以西瓜的重量，羊的重量用千克作单位比较合适;测量较长的物体用米作单位，二年级学生双臂展开的长度大约是1米，所以教室的长度用米作单位比较合适。\n\n【详解】一个鸭蛋约重70克。一个西瓜约重5千克。一头羊约重80千克。教室长9米。",
+        "knowledge_points":  [
+                                 "长度单位的选择，质量单位的选择"
+                             ],
+        "source":  "23-24二年级下·广东汕尾·期末"
+    },
+    {
+        "id":  "426",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "在括号里填上合适的单位.\n一袋盐重500( ) 小兰的体重是32( )\n两个苹果约重1( ) 小刚身高135( )",
+        "options":  [
+
+                    ],
+        "answer":  "克或g;千克或kg;千克或kg;厘米或cm",
+        "solution":  "【分析】根据生活经验，对质量单位和数据大小的认识可知:(1)称比较轻的物体，通常用\"克\"作单位。1枚1分的硬币大约重1克，所以计量一袋盐的重量，结合数据用\"克\"作单位比较合适;(2)计量比较重的物品，常用\"千克\"作单位。2袋盐重1千克，所以计量小兰的体重用\"千克\"作单位比较合适;(3)计量比较重的物品，常用\"千克\"作单位。2袋盐重1千克，所以计量两个苹果的重量，结合数据用\"千克\"作单位比较合适;(4)测量时通常用\"厘米\"作单位，食指的宽度约1厘米，所以计量小刚的身高，结合数据用\"厘米\"作单位比较合适。\n\n【详解】(1)一袋盐重500克;(2)小兰的体重是32千克;(3)两个苹果约重1千克;(4)小刚身高135厘米。",
+        "knowledge_points":  [
+                                 "长度单位的选择，质量单位的选择"
+                             ],
+        "source":  "23-24 二年级下·江西吉安·期末"
+    },
+    {
+        "id":  "427",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "3000克=( )千克 4千克=( )克\n5千克200克=( )克 3020克=( )千克( )克",
+        "options":  [
+
+                    ],
+        "answer":  "3;4000;5200;3;20",
+        "solution":  "【分析】据题意可知，是对重量单位的换算，已知1千克=1000克，根据题目要求进行计算即可。\n\n【详解】3000克=3千克;4千克=4000克;5千克200克=5200克;3020克=3千克20克。",
+        "knowledge_points":  [
+                                 "克，千克之间的换算与比较"
+                             ],
+        "source":  "23-24 二年级下·河南开封·期末"
+    },
+    {
+        "id":  "428",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在括号里填上合适的单位名称.\n一袋饼干重200( ) 妹妹的体重是18( )\n一块橡皮重30( ) 一个书包大约重1( )",
+        "options":  [
+
+                    ],
+        "answer":  "克或g;千克或kg;克或g;千克或kg",
+        "solution":  "【分析】根据生活经验，对质量单位和数据大小的认识可知：计量比较轻的物体，常用克作单位,2个曲别针约重1克，所以一袋饼干的重量，一块橡皮的重量用克作单位比较合适;计量比较重的物体，常用千克作单位,2袋白砂糖重1千克，所以妹妹的体重，一个书包的重量用千克作单位比较合适。\n\n【详解】一袋饼干重200克;妹妹的体重是18千克;一块橡皮重30克;一个书包大约重1千克。",
+        "knowledge_points":  [
+                                 "质量单位的选择"
+                             ],
+        "source":  "23-24 二年级下·河南开封·期末"
+    },
+    {
+        "id":  "429",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在括号里填上合适数或单位.\n一只狗约重10( ) 一个汤圆约重50( )\n5千克=( )克 9000克=( )千克",
+        "options":  [
+
+                    ],
+        "answer":  "千克或kg;克或g;5000;9",
+        "solution":  "【分析】第1题：计量比较重的物体，常用千克作单位,2袋白砂糖重1千克，所以小狗的重量用千克作单位比较合适;第2题：计量比较轻的物体，常用克作单位,2个曲别针约重1克，所以一个汤圆的重量用克作单位比较合适;第3,4题根据1千克=1000克换算即可。\n\n【详解】一只狗约重10千克;一个汤圆约重50克;5千克=5000克;9000克=9千克。",
+        "knowledge_points":  [
+                                 "质量单位的选择，克，千克之间的换算与比较"
+                             ],
+        "source":  "23-24 二年级下·湖南湘西·期末"
+    },
+    {
+        "id":  "430",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在括号里填上克或千克.\n根据《中国学龄儿童膳食指南(2022)》,6-10岁儿童一日水果推荐量是150-200( )。明明是个二年级的学生，体重是23( ),他今天吃了一个苹果150( ),一颗草莓25( )。",
+        "options":  [
+
+                    ],
+        "answer":  "克;千克;克;克",
+        "solution":  "【分析】根据生活经验，对质量单位和数据大小的认识可知：计量比较轻的物体，常用克作单位,2个曲别针约重1克，所以6-10岁儿童一日水果推荐量用克作单位比较合适;苹果和草莓的重量用克作单位比较合适;计量比较重的物体，常用千克作单位,2袋白砂糖重1千克，所以明明的体重用千克作单位比较合适。\n\n【详解】根据《中国学龄儿童膳食指南(2022)》,6-10岁儿童一日水果推荐量是150-200克。明明是个二年级的学生，体重是23千克，他今天吃了一个苹果150克，一颗草莓25克。",
+        "knowledge_points":  [
+                                 "质量单位的选择"
+                             ],
+        "source":  "23-24二年级下·福建龙岩·期末"
+    },
+    {
+        "id":  "431",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在括号填\"\u003e\"\"\u003c\"或\"=\".\n6910( )69012000克( )700千克\n1000-300( )70042÷7( )28/4",
+        "options":  [
+
+                    ],
+        "answer":  "\u003e;\u003c;=;\u003c",
+        "solution":  "【分析】先计算出每个算式的结果或先统一单位，然后比较大小即可。整数比较大小方法:①位数多的数大于位数少的数;②位数相同的，先比较最高位上的数，最高位上大的，数就大，最高位数相同的，就比较下一位，以此类推。1千克=1000克。\n\n【详解】6910\u003e6901;2000克=2千克，故,2000克\u003c700千克;1000-300=700;42÷7=6,28÷4=7，故,42÷7\u003c28÷4。",
+        "knowledge_points":  [
+                                 "克，千克之间的换算与比较，用7~9的乘法口诀求商，整百数，几百几十数的加减法口算，万以内数的大小比较"
+                             ],
+        "source":  "23-24二年级下·甘肃陇南·期末"
+    },
+    {
+        "id":  "432",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "一个苹果重( )克，一把香蕉重( )克.\n![](images/1353beb2ee9d1722f19a219b14570a58.png)",
+        "options":  [
+
+                    ],
+        "answer":  "200;400",
+        "solution":  "【分析】从左往右，由第二个天平可得一把香蕉重200+200=400(克);由第一个天平可得两个苹果的质量等于把香蕉的质量，即两个苹果重400克，也就是一个苹果重200克，据此解答即可。\n\n【详解】由分析可得，一个苹果重200克，一把香蕉重400克。",
+        "knowledge_points":  [
+                                 "整百数，几百几十数的加减法口算，等量代换，克的认识"
+                             ],
+        "source":  "23-24 二年级下·河北保定·期末"
+    },
+    {
+        "id":  "433",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "在括号里填上合适的单位.\n小丽的体重是24( )。 一小袋盐重500( )。 小明身高130( )。",
+        "options":  [
+
+                    ],
+        "answer":  "千克或kg 克或g 厘米或cm",
+        "solution":  "【分析】根据生活经验，对质量单位，长度单位和数据大小的认识可知,(1)计量比较重的物品，常用\"千克\"作单位。2袋盐重1千克，所以计量小丽的体重结合数据大小用\"千克\"作单位比较合适。(2)称比较轻的物体，通常用\"克\"作单位。1枚1分的硬币大约重1克，所以计量一小袋食盐的重量用\"克\"作单位比较合适。(3)测量物体长度时通常用\"厘米\"作单位，食指的宽大约是1厘米，所以小明的身高结合数据大小用\"厘米\"作单位比较合适。\n\n【详解】(1)小丽的体重是24千克;(2)一小袋盐重500克;(3)小明身高130厘米。",
+        "knowledge_points":  [
+                                 "长度单位的选择，质量单位的选择"
+                             ],
+        "source":  "23-24二年级下·湖南长沙·期末"
+    },
+    {
+        "id":  "434",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "4千克=( )克 3040克=( )千克( )克",
+        "options":  [
+
+                    ],
+        "answer":  "4000;3;40",
+        "solution":  "【分析】1千克=1000克,4千克就是4个1000克，就是4000克;3040克，把3000克换算成3千克,40克不变即可。\n\n【详解】4千克=4000克;3040克=3千克40克。",
+        "knowledge_points":  [
+                                 "克，千克之间的换算与比较"
+                             ],
+        "source":  "23-24 二年级下·河北石家庄·期末"
+    },
+    {
+        "id":  "435",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "超市里一袋洗衣粉重1( ),两袋盐重980( ),一盒蛋黄派重360( ),一袋大米重10( ),一桶花生油重5( )。",
+        "options":  [
+
+                    ],
+        "answer":  "千克或kg;克或g;克或g;千克或kg;千克或kg",
+        "solution":  "【分析】根据生活经验，对质量单位和数据大小的认识可知：计量比较轻的物体，常用克作单位,2个曲别针约重1克，所以两袋盐和一盒蛋黄派的重量用克作单位比较合适;计量比较重的物体，常用千克作单位,2袋白砂糖重1千克，所以一袋洗衣粉，一袋大米和一桶花生油的重量用千克作单位比较合适。\n\n【详解】超市里一袋洗衣粉重1千克，两袋盐重980克，一盒蛋黄派重360克，一袋大米重10千克，一桶花生油重5千克。",
+        "knowledge_points":  [
+                                 "质量单位的选择"
+                             ],
+        "source":  "23-24 二年级下·广西柳州·期末"
+    },
+    {
+        "id":  "436",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在括号里填上合适的单位.\n贝贝今年9岁，他的身高约135( ),体重约30( )。早上他吃了一个重约250( )的面包，背着重约3( )的书包。",
+        "options":  [
+
+                    ],
+        "answer":  "厘米或cm;千克或kg;克或g;千克或kg",
+        "solution":  "【分析】根据生活经验及结合给出的数据，来选择合适的计量单位。食指宽大约是1厘米，所以，计量一个孩子的身高用\"厘米\"作单位比较合适;2包500克的盐重1千克，所以，要计量一个人的体重和一个小学生的书包重量用\"千克\"做单位比较合适;1枚1分的硬币约重1克，所以，要计量一个面包的重量用\"克\"作单位比较合适。\n\n【详解】由题意分析得：贝贝今年9岁，他的身高约135厘米，体重约30千克。早上他吃了一个重约250克的面包，背着重约3千克的书包。",
+        "knowledge_points":  [
+                                 "质量单位的选择，长度单位的选择"
+                             ],
+        "source":  "23-24 二年级下·山东济宁·期末"
+    },
+    {
+        "id":  "437",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "3000克=( )千克 7千克=( )克 7020克=( )千克( )克",
+        "options":  [
+
+                    ],
+        "answer":  "3;7000;7;20",
+        "solution":  "【分析】(1)1000克=1千克,3000克就是3个1000克，即3千克;(2)1千克=1000克,7千克就是7个1000克，即7000克;(3)根据1000克=1千克，把7000克化成7千克,20克不变即可。\n\n【详解】3000克=3千克;7千克=7000克;7020克=7千克20克。",
+        "knowledge_points":  [
+                                 "克，千克之间的换算与比较"
+                             ],
+        "source":  "22-23 二年级下·江西吉安·期末"
+    },
+    {
+        "id":  "438",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "填上合适的质量单位.\n亮亮饮食很注意营养，每天喝250( )牛奶，吃一个35( )鸡蛋，身体很棒，他现在的体重有30( ),能随手拎起一桶重5( )的油。",
+        "options":  [
+
+                    ],
+        "answer":  "克或g;克或g;千克或kg;千克或kg",
+        "solution":  "【分析】根据生活经验，对质量单位和数据大小的认识可知：计量比较轻的物体，常用克作单位,2个曲别针约重1克，所以牛奶和鸡蛋的重量用克作单位比较合适;计量比较重的物体，常用千克作单位,2袋白砂糖重1千克，所以亮亮的体重和油的重量用千克作单位比较合适。\n\n【详解】亮亮饮食很注意营养，每天喝250克牛奶，吃一个35克鸡蛋，身体很棒，他现在的体重有30千克，能随手拎起一桶重5千克的油。",
+        "knowledge_points":  [
+                                 "质量单位的选择"
+                             ],
+        "source":  "22-23 二年级下·江西吉安·期末"
+    },
+    {
+        "id":  "439",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "小明早上喝了一袋质量250( )的牛奶，吃了一枚约重60( )的鸡蛋，然后背着重约3( )的书包去上学了。",
+        "options":  [
+
+                    ],
+        "answer":  "克或g;克或g;千克或kg",
+        "solution":  "【分析】根据生活经验，对质量单位和数据大小的认识可知,(1)称比较轻的物体，通常用克作单位。1枚1分的硬币大约重1克，所以计量一袋牛奶的重量用\"克\"作单位比较合适。(2)称比较轻的物体，通常用克作单位。1枚1分的硬币大约重1克，所以计量一枚鸡蛋的重量用\"克\"作单位比较合适。(3)计量比较重的物品，常用\"千克\"作单位。2袋盐重1千克，所以计量书包的重量用\"千克\"作单位比较合适。\n\n【详解】(1)一袋牛奶的质量250克;(2)一枚鸡蛋约重60克;(3)书包重约3千克;所以小明早上喝了一袋质量250克的牛奶，吃了一个约重60克的鸡蛋，然后背着重约3千克的书包去上学了。",
+        "knowledge_points":  [
+                                 "质量单位的选择"
+                             ],
+        "source":  "22-23 二年级下·四川绵阳·期末"
+    },
+    {
+        "id":  "440",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在括号里填上合适的质量单位.\n一头小牛约重40( )。 一支圆珠笔约重10( )。",
+        "options":  [
+
+                    ],
+        "answer":  "千克或kg;克或g",
+        "solution":  "【分析】根据生活经验，对质量单位和数据大小的认识可知：计量比较重的物体，常用千克作单位,2袋白砂糖重1千克，所以小牛的重量用千克作单位比较合适;计量比较轻的物体，常用克作单位,2个曲别针约重1克，所以圆珠笔的重量用克作单位比较合适。\n\n【详解】一头小牛约重40千克。一支圆珠笔约重10克。",
+        "knowledge_points":  [
+                                 "质量单位的选择"
+                             ],
+        "source":  "23-24 二年级下·吉林四平·期末"
+    },
+    {
+        "id":  "441",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在括号里填上合适的单位.\n我是亮亮，身高125( ),体重28( )。我每天早上会用10( )洗脸刷牙，系红领巾用20( )。早饭必有一个约重50( )的鸡蛋。然后背上约重3( )的书包去上学，我家离学校600( ),步行大约需要10( )。",
+        "options":  [
+
+                    ],
+        "answer":  "厘米或cm;千克或kg;分钟或min;秒或s 克或g;千克或kg;米或m;分钟或min",
+        "solution":  "【分析】根据生活经验对时间单位，长度单位，质量单位和数据大小的认识可知:1分米大约是一只粉笔的长度，所以计量亮亮的身高用\"厘米\"作单位比较合适;一个乒乓球的重量为3克，一千克相当于20个鸡蛋的重量，所以计量亮亮的体量，书包重量用\"千克\"作单位，计量一个鸡蛋的重量用\"克\"作单位;1分钟可以穿一件衣服,1眨眼1次大约是1秒，所以洗脸刷牙用\"分钟\"作单位比较合适;计量步行用\"分钟\"作单位比较合适;则计量系红领巾用秒作单位最合适;人走1大步是1米，所以计量家离学校的距离用\"米\"作单位比较合适。\n\n【详解】我是亮亮，身高125厘米，体重28千克。我每天早上会用10分钟洗脸刷牙，系红领巾用20秒。早饭必有一个约重50克的鸡蛋。然后背上约重3千克的书包去上学，我家离学校600米，步行大约需要10分钟。",
+        "knowledge_points":  [
+                                 "长度单位的选择，质量单位的选择，时间单位的选择"
+                             ],
+        "source":  "23-24 二年级下·河北唐山·期末"
+    },
+    {
+        "id":  "442",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "小强的体重是28( ),他的数学课本约重200( )。",
+        "options":  [
+
+                    ],
+        "answer":  "千克或kg;克或g",
+        "solution":  "【分析】根据生活经验，对质量单位和数据大小的认识可知，计量比较重的物品，常用\"千克\"作单位。2袋盐重1千克，所以计量小强的体重用\"千克\"作单位比较合适。称比较轻的物体，通常用克作单位。1枚1分的硬币大约重1克，所以计量数学课本的重量用\"克\"作单位比较合适。\n\n【详解】小强的体重是28千克，他的数学课本约重200克。",
+        "knowledge_points":  [
+                                 "质量单位的选择"
+                             ],
+        "source":  "23-24 二年级下·湖南常德·期末"
+    },
+    {
+        "id":  "443",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "A说：\"今天买500克的梨要花7元\",B说：\"我买3千克梨，要( )元。",
+        "options":  [
+
+                    ],
+        "answer":  "42",
+        "solution":  "【分析】先根据\"1千克=1000克\"把单位统一，然后再根据3千克=3000克，且3000=1000+1000+1000=500+500+500+500+500+500，由此可知3000里面有6个500，即3000克里面有6个500克，已知1个500克需要7元，则可以求出3千克(即3000克)梨需要付多少钱，用乘法计算，据此解答。\n\n【详解】3千克=3000克，据分析可知3000克里有6个500克。6×7=42(元),所以说：\"我买3千克梨，要42元.\"",
+        "knowledge_points":  [
+                                 "经济问题,7的乘法口诀及应用，克，千克之间的换算与比较"
+                             ],
+        "source":  "23-24 二年级下·湖北黄石·期末"
+    },
+    {
+        "id":  "444",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "在括号里填上合适的单位.\n(1)一只鸡重1998( ),约2( ).\n(2)小明身高136( ),体重29( ),他一天食盐的摄入量不超过6( )。",
+        "options":  [
+
+                    ],
+        "answer":  "克或g;千克或kg 厘米或cm;千克或kg;克或g",
+        "solution":  "【分析】根据生活经验，对长度单位，质量单位和数据大小的认识可知：计量比较轻的物体，常用克作单位,2个曲别针约重1克，结合数字1998，所以计量一只鸡的重量用克作单位比较合适。计量一天食盐的摄入量用克作单位比较合适;计量比较重的物体，常用千克作单位,2袋白砂糖重1千克，结合数字2，所以计量一只鸡的重量用千克作单位比较合适。计量小明的体重用千克作单位比较合适;量比较短的物体的长度，通常用厘米作单位，食指的宽大约是1厘米，所以计量小明身高用厘米作单位比较合适。\n\n【详解】(1)一只鸡重1998克，约2千克。(2)小明身高136厘米，体重29千克，他一天食盐的摄入量不超过6克。",
+        "knowledge_points":  [
+                                 "长度单位的选择，质量单位的选择，克，千克之间的换算与比较"
+                             ],
+        "source":  "23-24 二年级下·湖北黄石·期末"
+    },
+    {
+        "id":  "445",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "在括号填上合适的单位.\n一个汉堡包重280( ) 一个西瓜重6( )\n一头小牛约重30( ) 一管牙膏重100( )",
+        "options":  [
+
+                    ],
+        "answer":  "克或g;千克或kg;千克或kg;克或g",
+        "solution":  "【分析】根据题意，括号里应该填质量单位。常用的质量单位有克和千克。我们知道，一枚回形针大约重1克，两瓶矿泉水大约重1千克。所以根据生活经验，对质量单位和数据大小的认识可知，计量汉堡包的重量，一管牙膏的重量用\"克\"作单位比较合适;计量一个西瓜的重量，一头小牛的重量用\"千克\"作单位比较合适。\n\n【详解】由分析可得，一个汉堡包重280克;一个西瓜重6千克;一头小牛约重30千克;一管牙膏重100克。",
+        "knowledge_points":  [
+                                 "质量单位的选择，千克的认识，克的认识"
+                             ],
+        "source":  "23-24 二年级下·湖南常德·期末"
+    },
+    {
+        "id":  "446",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "在括号里填上\"\u003e\"\"\u003c\"或\"=\".\n3009( )30094千克( )4500克 21+9÷3( )21/3+9\n2800克( )3千克 900+2100( )700010个千( )100个百",
+        "options":  [
+
+                    ],
+        "answer":  "=;\u003c;\u003e;\u003c;\u003c;=",
+        "solution":  "【分析】比较数的大小时，位数多的数就大;位数相同比较最高位，最高位大的数就大;最高位相同比较下一位，直到比较出结果为止。第1题：直接比较;第2,4题：根据1千克=1000克统一单位后再比较;第3题：算式中有除法和加法，先算除法再算加法，计算出结果再比较;第5题：计算出左侧算式结果再比较;第6题：根据数的组成写出数字再比较。\n\n【详解】3009=3009;4千克=4000克;4000克\u003c4500克，则4千克\u003c4500克;21+9÷3=21+3=24,21÷3+9=7+9=16,24\u003e16，则21+9÷3\u003e21÷3+9;3千克=3000克;2800克\u003c3000克，则2800克\u003c3千克;900+2100=3000;3000\u003c7000，则900+2100\u003c7000;10个千是10000;100个百是10000;10000=10000，则10个千=100个百。",
+        "knowledge_points":  [
+                                 "克，千克之间的换算与比较，除加，除减混合运算，整百数，几百几十数的加减法口算，万以内数的大小比较"
+                             ],
+        "source":  "23-24 二年级下·山东济宁·期末"
+    },
+    {
+        "id":  "447",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "在括号里填上\"\u003e\"\"\u003c\"或\"=\".\n6910( )69012000克( )700千克 48÷6( )48/8",
+        "options":  [
+
+                    ],
+        "answer":  "\u003e;\u003c;\u003e",
+        "solution":  "【分析】整数的大小比较：比较数的大小，先看数位的多少，数位多的数就大;数位相同，从高位开始比较，高位上的数大则这个数大，高位上的数相同，就比较下一位。1000克=1千克，单位不统一时，先化成相同单位，再比较大小。含有算式的大小比较，可以先计算出每个算式的结果，再比较大小。\n\n【详解】6910\u003e6901;2000克=2千克，所以2000克\u003c700千克;48÷6=8,48÷8=6，所以48÷6\u003e48÷8。",
+        "knowledge_points":  [
+                                 "克，千克之间的换算与比较，用7~9的乘法口诀求商，万以内数的大小比较"
+                             ],
+        "source":  "22-23 二年级下·江西吉安·期末"
+    },
+    {
+        "id":  "448",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在括号填上合适单位.\n一袋食盐重500( ) 小明的体重38( )\n小红的身高132( ) 爸爸每天睡8( )",
+        "options":  [
+
+                    ],
+        "answer":  "克或g;千克或kg;厘米或cm;小时或h",
+        "solution":  "【分析】根据生活经验以及对质量单位和数据大小的认识，量比较轻的物体的质量，通常用克作单位，一粒花生米的质量大约是1克，所以计量一袋食盐的质量用\"克\"作单位。1千克=1000克，量比较重的物体的质量，通常用千克作单位。所以计量小明的体重用\"千克\"作单位。根据生活经验以及对长度单位和数据大小的认识，量比较短的物体的长度，通常用厘米作单位。食指的宽大约是1厘米，所以计量小红的身高用\"厘米\"作单位比较合适。根据生活经验可知:1小时=60分，一个人每天的睡眠时间不少于8小时，所以计量爸爸每天睡觉时间长度用\"小时\"作单位。\n\n【详解】一袋食盐重500克;小明的体重38千克;小红的身高132厘米;爸爸每天睡8小时。",
+        "knowledge_points":  [
+                                 "长度单位的选择，质量单位的选择，时间单位的选择"
+                             ],
+        "source":  "23-24 二年级下·贵州铜仁·期末"
+    },
+    {
+        "id":  "449",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "在括号里填上\"\u003e\"\"\u003c\"或\"=\".\n3565( )34651500克( )2千克 72-6×7( )5×6",
+        "options":  [
+
+                    ],
+        "answer":  "\u003e;\u003c;=",
+        "solution":  "【分析】比较数的大小时，位数多的数就大;位数相同比较最高位，最高位大的数就大;最高位相同比较下一位，直到比较出结果为止。第1题：直接比较;第2题：根据1千克=1000克统一单位后再比较;第3题：左侧算式先算乘法再算减法，右侧算式直接计算，再比较得数即可。\n\n【详解】3565\u003e3465;2千克=2000克;1500克\u003c2000克，则1500克\u003c2千克;72-6×7=72-42=30,5×6=30,30=30，则72-6×7=5×6。",
+        "knowledge_points":  [
+                                 "克，千克之间的换算与比较，乘加，乘减混合运算，万以内数的大小比较"
+                             ],
+        "source":  "22-23 二年级下·江西吉安·期末"
+    },
+    {
+        "id":  "450",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "填上合适的单位.\n一头牛重500( ) 一袋食用盐重500( )\n一只母鸡重约2( ) 一个苹果重约300( )",
+        "options":  [
+
+                    ],
+        "answer":  "千克或kg;克或g;千克或kg;克或g",
+        "solution":  "【分析】根据生活经验，对质量单位和数据大小的认识可知,(1)计量比较重的物品，常用\"千克\"作单位。2袋盐重1千克，所以计量一头牛的重量用\"千克\"作单位比较合适。(2)称比较轻的物体，通常用克作单位。1枚1分的硬币大约重1克，所以计量一袋食盐的重量用\"克\"作单位比较合适。(3)计量比较重的物品，常用\"千克\"作单位。2袋盐重1千克，所以计量一只母鸡重量用\"千克\"作单位比较合适。(4)称比较轻的物体，通常用克作单位。1枚1分的硬币大约重1克，所以计量一个苹果的重量用\"克\"作单位比较合适。\n\n【详解】(1)一头牛重500千克;(2)一袋食用盐重500克;(3)一只母鸡重约2千克;(4)一个苹果重约300克。",
+        "knowledge_points":  [
+                                 "质量单位的选择"
+                             ],
+        "source":  "22-23 二年级下·江西吉安·期末"
+    },
+    {
+        "id":  "451",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "在括号里填上\"\u003e\"\"\u003c\"或\"=\".\n8000克( )8千克 70( )8×8-91500-700( )800\n5千克( )5克 32-32÷8( )53300+400( )70",
+        "options":  [
+
+                    ],
+        "answer":  "=;\u003e;=;\u003e;\u003c;\u003e",
+        "solution":  "【分析】单位不统一，先统一单位，再比较大小,1千克=1000克;有算式的计算出各算式的结果再比较大小。比较大小时，数位多的数就大;数位相同比较最高位，最高位大的数就大;最高位相同比较下一位，直到比较出结果为止。\n\n【详解】8000克=8千克;8×8-9=64-9=55,70\u003e55，故70\u003e8×8-9;1500-700=800;5千克\u003e5克;32-32÷8=32-4=28,28\u003c53，故32-32÷8\u003c53;300+400=700,700\u003e70，故300+400\u003e70。",
+        "knowledge_points":  [
+                                 "克，千克之间的换算与比较，整百数，几百几十数的加减法口算，万以内数的大小比较"
+                             ],
+        "source":  "23-24 二年级下·广东汕头·期末"
+    },
+    {
+        "id":  "452",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "填上合适的单位名称：\"克\"或\"千克\".\n小明的体重是35( )。 一个桃子约重200( )。 一头猪约重200( )。 一个鸡蛋约重50( )。",
+        "options":  [
+
+                    ],
+        "answer":  "千克或kg;克或g;千克或kg;克或g",
+        "solution":  "【分析】根据实际生活经验以及题干中的具体数据来进行填空。2包500克的盐重1千克，所以，要计量小明的体重和一头猪重用\"千克\"做单位比较合适;1枚1分的硬币约重1克，所以，要计量一个桃子重和一个鸡蛋重用\"克\"作单位比较合适。\n\n【详解】由题意分析得：小明的体重是35千克。一个桃子约重200克。一头猪约重200千克。一个鸡蛋约重50克。",
+        "knowledge_points":  [
+                                 "质量单位的选择"
+                             ],
+        "source":  "23-24 二年级下·黑龙江双鸭山·期末"
+    },
+    {
+        "id":  "453",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "在括号里填上\"\u003e\"\"\u003c\"或\"=\".\n48-9×2( )6×8-183×9-16( )175千克( )4900克 2000克( )2千克 9687( )98764000+800+60( )4086",
+        "options":  [
+
+                    ],
+        "answer":  "=;\u003c;\u003e;=;\u003c;\u003e",
+        "solution":  "【分析】先计算出每个算式的结果或先统一单位，然后比较大小即可。整数比较大小方法:①位数多的数大于位数少的数;②位数相同的，先比较最高位上的数，最高位上大的，数就大，最高位相同的，就比较下一位，以此类推。1千克=1000克。\n\n【详解】48-9×2=48-18=30,6×8-18=48-18=30，故,48-9×2=6×8-18;3×9-16=27-16=11，故,3×9-16\u003c17;5千克=5000克，故,5千克\u003e4900克;1000克=1千克，故,2000克=2千克;9687\u003c9876;4000+800+60=4860，故,4000+800+60\u003e4086。",
+        "knowledge_points":  [
+                                 "表内乘加，乘减，克，千克之间的换算与比较，整百数，几百几十数的加减法口算，万以内数的大小比较"
+                             ],
+        "source":  "23-24 二年级下·黑龙江双鸭山·期末"
+    },
+    {
+        "id":  "454",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "括号里填上合适的单位名称.\n明明的体重是40( ),身高是134( );一只鸡重3( );一个西瓜约重4000( )。",
+        "options":  [
+
+                    ],
+        "answer":  "千克或kg;厘米或cm;千克或kg;克或g",
+        "solution":  "【分析】根据生活经验，对长度单位，质量单位和数据大小的认识可知，食指宽大约是1厘米，所以，计量一个人的身高用\"厘米\"作单位比较合适;2包500克的盐重1千克，所以，要计量一个人的体重和一只鸡的重量用\"千克\"作单位比较合适;1枚1分的硬币约重1克，所以，要计量一个西瓜重量用\"克\"作单位比较合适。\n\n【详解】由题意分析得：明明的体重是40千克，身高是134厘米;一只鸡重3千克;一个西瓜约重4000克。",
+        "knowledge_points":  [
+                                 "质量单位的选择，长度单位的选择"
+                             ],
+        "source":  "23-24 二年级下·江西吉安·期末"
+    },
+    {
+        "id":  "455",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在括号里填上合适的质量单位.\n一瓶洗衣液重500( ) 一个鸡蛋约重50( ) 小明重35( )",
+        "options":  [
+
+                    ],
+        "answer":  "克或g;克或g;千克或kg",
+        "solution":  "【分析】根据生活经验，对质量单位和数据大小的认识可知,2包500克的盐重1千克，所以，要计量小明的重量用\"千克\"作单位比较合适;1枚1分的硬币约重1克，所以，要计量一瓶洗衣液的重量及一个鸡蛋的重量用\"克\"作单位比较合适;据此解决。\n\n【详解】由题意分析得：一瓶洗衣液重500克;一个鸡蛋约重50克;小明重35千克。",
+        "knowledge_points":  [
+                                 "质量单位的选择"
+                             ],
+        "source":  "23-24 二年级下·甘肃陇南·期末"
+    },
+    {
+        "id":  "456",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "联系实际，在括号里填上适当的单位(\"克\"或\"千克\").\n明明很注意饮食营养，他每天喝一袋250( )的牛奶，吃300( )青菜，身体很棒。他现在的体重有30( ),一桶油5( ),他不费力就能提起来。",
+        "options":  [
+
+                    ],
+        "answer":  "克或g;克或g;千克或kg;千克或kg",
+        "solution":  "【分析】根据生活经验以及对质量单位和数据大小的认识，量比较轻的物体的质量通常用克作单位，量比较重的物体的质量通常用千克作单位。\n\n【详解】一袋牛奶重250克，吃300克青菜比较合适;明明的体重有30千克，一桶油重5千克。",
+        "knowledge_points":  [
+                                 "质量单位的选择"
+                             ],
+        "source":  "23-24 二年级下·四川内江·期末"
+    },
+    {
+        "id":  "457",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在括号里填入\"\u003e\"\"\u003c\"或\"=\".\n6×8( )5×93千克3克( )3300克 100个十( )10个百",
+        "options":  [
+
+                    ],
+        "answer":  "\u003e;\u003c;=",
+        "solution":  "【分析】第一小题，根据乘法口诀先计算出结果，再进行比较即可;第二小题，根据1千克=1000克，把3千克3克换成\"克\"作单位，再进行比较即可;第三小题，根据10个十是100,100个十是1000,10个百是1000来解答。\n\n【详解】6×8=48,5×9=45,48\u003e45，故,6×8\u003e5×9;3千克3克=3003克，故,3003克\u003c3300克;100个十是1000,10个百是1000，故,100个十=10个百。",
+        "knowledge_points":  [
+                                 "克，千克之间的换算与比较,9的乘法口诀及应用，万以内数的大小比较,1000以内数的组成"
+                             ],
+        "source":  "23-24二年级下·四川内江·期末"
+    },
+    {
+        "id":  "458",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在括号内填上适当的单位名称.\n圆圆今年9岁，他的身高约140( ),体重约40( )。为了保证他能茁壮成长，妈妈每天会给他准备一瓶重约250( )的牛奶和一个重约50( )的鸡蛋。",
+        "options":  [
+
+                    ],
+        "answer":  "厘米或cm;千克或kg;克或g;克或g",
+        "solution":  "【分析】根据生活经验，对长度单位，质量单位和数据大小的认识可知：测量比较短的物体的长度，通常用厘米作单位，食指的宽大约是1厘米，所以圆圆的身高用厘米作单位比较合适;计量比较重的物体，常用千克作单位,2袋白砂糖重1千克，所以圆圆的体重用千克作单位比较合适;计量比较轻的物体，常用克作单位,1个曲别针约重1克，所以牛奶和鸡蛋的重量用克作单位比较合适。\n\n【详解】圆圆今年9岁，他的身高约140厘米，体重约40千克。为了保证他能茁壮成长，妈妈每天会给他准备一瓶重约250克的牛奶和一个重约50克的鸡蛋。",
+        "knowledge_points":  [
+                                 "长度单位的选择，质量单位的选择"
+                             ],
+        "source":  "23-24 二年级下·四川南充·期末"
+    },
+    {
+        "id":  "459",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在括号填上合适的单位.\n阳阳身高130( ),体重32( )。他每天7( )起床，洗脸，刷牙共15( ),然后吃了一个50( )的鸡蛋和一些面包，就从家出发，要走500( )的路程才能到学校。",
+        "options":  [
+
+                    ],
+        "answer":  "厘米或cm;千克或kg;时或h;分钟或分或min;克或g;米或m",
+        "solution":  "【分析】要根据实际情况，结合数据的大小选择合适的计量单位。食指宽大约是1厘米，所以，计量一个人身高用\"厘米\"作单位比较合适;米尺的长度是1米，所以，计量从家到学校的距离用\"米\"作单位比较合适;表示某一时刻，选择\"几时几分几秒\"表示，如：每天7时起床;表示较短的时间时，一般选择\"分钟\"作单位，如：洗脸，刷牙共15分钟;2包500克的盐重1千克，所以，要计量一个人体重用\"千克\"作单位比较合适;1枚1分的硬币约重1克，所以，要计量一个人早餐重量用\"克\"作单位比较合适。\n\n【详解】由题意分析得：阳阳身高130厘米，体重32千克。他每天7时起床，洗脸，刷牙共15分钟，然后吃了一个50克的鸡蛋和一些面包，就从家出发，要走500米的路程才能到学校。",
+        "knowledge_points":  [
+                                 "长度单位的选择，质量单位的选择，时间单位的选择"
+                             ],
+        "source":  "23-24二年级下·浙江宁波·期末"
+    },
+    {
+        "id":  "460",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "在括号里填\"\u003e\"\"\u003c\"或\"=\".\n5千克( )4999克 5020( )5200 (18+36)÷9( )8",
+        "options":  [
+
+                    ],
+        "answer":  "\u003e;\u003c;\u003c",
+        "solution":  "【分析】计算出算式的结果或统一单位再比较。比较时，位数多的数就大;位数相同比较最高位，最高位大的数就大;最高位相同比较下一位，直到比较出结果为止。\n\n【详解】1千克=1000克;5千克=5000克,5000克\u003e4999克，则5千克\u003e4999克;5020\u003c5200;(18+36)÷9=54÷9=6,6\u003c8，则(18+36)÷9\u003c8。",
+        "knowledge_points":  [
+                                 "万以内数的大小比较，带有小括号的混合运算，克，千克之间的换算与比较"
+                             ],
+        "source":  "23-24 二年级下·山东菏泽·期末"
+    },
+    {
+        "id":  "461",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在括号里填上合适的单位名称.\n小华的体重是49( );两袋食盐重800( );青青的身高是120( )。",
+        "options":  [
+
+                    ],
+        "answer":  "千克或kg;克或g;厘米或cm",
+        "solution":  "【分析】根据生活经验，对长度单位，质量单位和数据大小的认识可知：计量比较重的物体，常用千克作单位,2袋白砂糖重1千克，所以小华的体重用千克作单位比较合适;计量比较轻的物体，常用克作单位,2个曲别针约重1克，所以两袋盐的重量用克作单位比较合适;量比较短的物体的长度，通常用厘米作单位，食指的宽大约是1厘米，所以青青的身高用厘米作单位比较合适。\n\n【详解】小华的体重是49千克;两袋食盐重800克;青青的身高是120厘米。",
+        "knowledge_points":  [
+                                 "长度单位的选择，质量单位的选择"
+                             ],
+        "source":  "23-24 二年级下·山东临沂·期末"
+    },
+    {
+        "id":  "462",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "每500克桔子6元，买1千克桔子要( )元。",
+        "options":  [
+
+                    ],
+        "answer":  "12",
+        "solution":  "【分析】判断出1千克里面有几个500克，就需要几个6元。\n\n【详解】1千克=1000克,500克+500克=1000克，也就是有2个500克。6+6=12(元),每500克桔子6元，买1千克桔子要12元。",
+        "knowledge_points":  [
+                                 "克，千克之间的换算与比较"
+                             ],
+        "source":  "23-24 二年级下·浙江台州·期末"
+    },
+    {
+        "id":  "463",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "( )克=6千克 5050克=( )千克( )克",
+        "options":  [
+
+                    ],
+        "answer":  "6000;5;50",
+        "solution":  "【分析】根据1千克=1000克换算即可。\n\n【详解】6000克=6千克;5050克=5000克+50克=5千克50克。",
+        "knowledge_points":  [
+                                 "克，千克之间的换算与比较"
+                             ],
+        "source":  "23-24 二年级下·浙江台州·期末"
+    },
+    {
+        "id":  "464",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "可可走20步约10米，走( )步约100米;一个苹果约重200克,( )个这样的苹果约重1千克。",
+        "options":  [
+
+                    ],
+        "answer":  "200;5",
+        "solution":  "【分析】第一空:100米里面有10个10米，所以走100米的步数就是10个20步,10个20步也就是200步;第二空:200克+200克+200克+200克+200克=1000克,1000克=1千克，所以5个这样的苹果约重1千克。\n\n【详解】由题意分析得：可可走20步约10米，走200步约100米;一个苹果约重200克,5个这样的苹果约重1千克。",
+        "knowledge_points":  [
+                                 "克，千克之间的换算与比较，整百数，几百几十数的加减法口算,1000以内数的组成"
+                             ],
+        "source":  "23-24 二年级下·浙江台州·期末"
+    },
+    {
+        "id":  "465",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "3千克=( )克 5000克=( )千克",
+        "options":  [
+
+                    ],
+        "answer":  "3000;5",
+        "solution":  "【分析】根据\"1千克=1000克\"来进行单位之间的换算即可。\n\n【详解】由题意分析得:3千克=3000克,5000克=5千克。",
+        "knowledge_points":  [
+                                 "克，千克之间的换算与比较"
+                             ],
+        "source":  "23-24 二年级下·浙江宁波·期末"
+    },
+    {
+        "id":  "466",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在括号里填上适当的单位名称.\n小强的体重是30( )。 一个苹果重200( )。",
+        "options":  [
+
+                    ],
+        "answer":  "千克或kg;克或g",
+        "solution":  "【分析】根据实际生活经验以及题干中的具体数据来进行填空。2包500克的盐重1千克，所以，要计量一个人的体重用\"千克\"作单位比较合适;1枚1分的硬币约重1克，所以，要计量一个苹果的重量用\"克\"作单位比较合适。\n\n【详解】由题意分析得：小强的体重是30千克。一个苹果重200克。",
+        "knowledge_points":  [
+                                 "质量单位的选择"
+                             ],
+        "source":  "23-24 二年级下·广东肇庆·期末"
+    },
+    {
+        "id":  "467",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "周末，乐乐与妈妈来到联华超市，乐乐先测了自己的身高140( ),体重35( );然后她们在超市里买了一袋15( )的大米，一罐500( )的麦片,2包重400( )的盐，还买了8个柿子约重1( )。",
+        "options":  [
+
+                    ],
+        "answer":  "厘米或cm;千克或kg;千克或kg;克或g;克或g;千克或kg",
+        "solution":  "【分析】常用的长度单位有米，分米，厘米等;常用的质量单位有千克和克等;要根据实际情况结合数据的大小选择合适的计量单位。大拇指的指甲长度大约1厘米，计量乐乐的身高用\"厘米\"作单位比较合适。1千克大约为两瓶矿泉水的重量，计量乐乐的体重，大米的重量,8个柿子的重量用\"千克\"作单位比较合适。1克大约为一枚硬币的重量，计量麦片的重量，盐的重量用\"克\"作单位比较合适。\n\n【详解】周末，乐乐与妈妈来到联华超市，乐乐先测了自己的身高140厘米，体重35千克;然后她们在超市里买了一袋15千克的大米，一罐500克的麦片,2包重400克的盐，还买了8个柿子约重1千克。",
+        "knowledge_points":  [
+                                 "长度单位的选择，质量单位的选择，千克的认识，克的认识"
+                             ],
+        "source":  "23-24二年级下·浙江杭州·期末"
+    },
+    {
+        "id":  "468",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "在括号里填上\"\u003e\"\"\u003c\"或\"=\".\n1023( )9995900克( )6千克 72÷9-3( )54×7+21( )45÷5×6",
+        "options":  [
+
+                    ],
+        "answer":  "\u003e;\u003c;=;\u003c",
+        "solution":  "【分析】整数的大小比较：比较数的大小，先看数位的多少，数位多的数就大;数位相同，从高位开始比较，高位上的数大则这个数大，高位上的数相同，就比较下一位。含有算式的大小比较，可以先计算出每个算式的结果，再比较大小;1千克=1000克，单位不统一时，先化成相同单位，再比较大小。整数混合运算中，同级运算时，从左到右依次计算;两级运算时，先算乘除，后算加减。\n\n【详解】1023\u003e999;6千克=6000克，所以5900克\u003c6千克;72÷9-3=8-3=5，即72÷9-3=5;4×7+21=28+21=49,45÷5×6=9×6=54，所以4×7+21\u003c45÷5×6。",
+        "knowledge_points":  [
+                                 "克，千克之间的换算与比较，除加，除减混合运算，乘加，乘减混合运算，万以内数的大小比较"
+                             ],
+        "source":  "23-24 二年级下·四川绵阳·期末"
+    },
+    {
+        "id":  "469",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "6根香蕉大约重1千克,18根香蕉大约重( )千克。",
+        "options":  [
+
+                    ],
+        "answer":  "3",
+        "solution":  "【分析】将6根香蕉看作一份，则一份是1千克。用18除以6求出有这样的几份，然后用份数乘一份的重量即可求解。\n\n【详解】18÷6=3(份),3×1=3(千克),18根香蕉大约重3千克。",
+        "knowledge_points":  [
+                                 "千克的认识，用6的乘法口诀求商,3的乘法口诀及应用"
+                             ],
+        "source":  "23-24 二年级下·四川绵阳·期末"
+    },
+    {
+        "id":  "470",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "8000克=( )千克 ( )千克=7000克",
+        "options":  [
+
+                    ],
+        "answer":  "8;7",
+        "solution":  "【分析】千克与克之间的进率是1000，即1千克=1000克，据此解答即可。\n\n【详解】由分析可知:8000克=8千克;7千克=7000克。",
+        "knowledge_points":  [
+                                 "克，千克之间的换算与比较"
+                             ],
+        "source":  "23-24 二年级下·辽宁鞍山·期末"
+    },
+    {
+        "id":  "471",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "在括号里填上\"\u003e\"\"\u003c\"或\"=\".\n1953( )19809990( )10000360+540( )900\n2500克( )3千克 10千克( )1000克 8千克-2500克( )5千克",
+        "options":  [
+
+                    ],
+        "answer":  "\u003c;\u003c;=;\u003c;\u003e;\u003e",
+        "solution":  "【分析】比较数的大小时，位数多的数就大;位数相同比较最高位，最高位大的数就大;最高位相同比较下一位，直到比较出结果为止。第1,2题直接比较;第3题计算出结果再比较;第4,5,6题先统一单位再计算比较。\n\n【详解】1953\u003c1980;9990\u003c10000;360+540=900;1千克=1000克;3千克=3000克;2500克\u003c3000克，则2500克\u003c3千克;10千克\u003e1千克，则10千克\u003e1000克;8000克-2500克=5500克;5500克\u003e5000克，则8千克-2500克\u003e5千克。",
+        "knowledge_points":  [
+                                 "万以内数的大小比较，整百数，几百几十数的加减法口算，克，千克之间的换算与比较"
+                             ],
+        "source":  "23-24二年级下·湖北孝感·期末"
+    },
+    {
+        "id":  "472",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "一个梨重100( ),一筐梨重20( )。",
+        "options":  [
+
+                    ],
+        "answer":  "克或g;千克或kg",
+        "solution":  "【分析】1克大约为一枚硬币的重量，计量一个梨的重量用\"克\"作单位比较合适。1千克大约为两瓶矿泉水的重量，计量一筐梨的重量用\"千克\"作单位比较合适。\n\n【详解】一个梨重100克，一筐梨重20千克。",
+        "knowledge_points":  [
+                                 "克的认识，千克的认识"
+                             ],
+        "source":  "23-24 二年级下·山东济宁·期末"
+    },
+    {
+        "id":  "473",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在括号里填上合适的长度或质量单位.\n(1)一支铅笔长约15( )。 (2)一颗草莓重约30( )。 (3)乐乐体重25( )。",
+        "options":  [
+
+                    ],
+        "answer":  "厘米或cm;克或g;千克或kg",
+        "solution":  "【分析】根据生活经验，对长度单位，质量单位和数据大小的认识可知:(1)量比较短的物体的长度，通常用厘米作单位，食指的宽大约是1厘米，所以铅笔的长度用厘米作单位比较合适;(2)计量比较轻的物体，常用克作单位,2个曲别针约重1克，所以一颗草莓的重量用克作单位比较合适;(3)计量比较重的物体，常用千克作单位,2袋白砂糖重1千克，所以乐乐体重用千克作单位比较合适。\n\n【详解】(1)一支铅笔长约15厘米。(2)一颗草莓重约30克。(3)乐乐体重25千克。",
+        "knowledge_points":  [
+                                 "长度单位的选择，质量单位的选择"
+                             ],
+        "source":  "23-24 二年级下·贵州黔西·期末"
+    },
+    {
+        "id":  "474",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在括号里填上合适的质量单位.\n![](images/c7b8f2a860e5bef89a272d326ace8c31.png)\n28( ) 3000( ) 180( ) 2( )",
+        "options":  [
+
+                    ],
+        "answer":  "千克或kg;克或g;克或g;千克或kg",
+        "solution":  "【分析】1千克大约为两瓶矿泉水的重量，根据生活实际结合数据可知，计量1辆自行车的重量,3颗白菜的重量用\"千克\"作单位比较合适;1克大约为一枚硬币的重量，根据生活实际结合数据可知，计量1只鹅的重量,1个苹果的重量用\"克\"作单位比较合适。\n\n【详解】28千克;3000克;180克;2千克。",
+        "knowledge_points":  [
+                                 "克的认识，千克的认识，质量单位的选择"
+                             ],
+        "source":  "23-24 二年级下·四川绵阳·期末"
+    },
+    {
+        "id":  "475",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "一枚1元的硬币约重2千克。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】根据生活经验，对质量单位和数据大小的认识可知：计量比较轻的物体，常用克作单位,2个曲别针约重1克;计量比较重的物体，常用千克作单位,2袋白砂糖约重1千克;由此判断。\n\n【详解】2千克大约是4袋白砂糖的重量，不符合1元硬币的重量。1元硬币较轻，用克作单位比较合适;一枚1元硬币大约重6克。原题说法错误。故答案为: ×",
+        "knowledge_points":  [
+                                 "质量的估计，质量单位的选择"
+                             ],
+        "source":  "23-24 二年级下·河南周口·期末"
+    },
+    {
+        "id":  "476",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "小明身高是132厘米，体重是25克。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】根据生活经验，对长度单位，质量单位和数据大小的认识可知：量比较短的物体的长度，通常用厘米作单位，食指的宽大约是1厘米，所以小明的身高结合数据132，用厘米作单位比较合适;计量比较轻的物体，常用克作单位,2个曲别针约重1克;计量比较重的物体，常用千克作单位,2袋白砂糖重1千克，所以小明的体重用千克作单位比较合适。由此解答。\n\n【详解】由分析可知，小明身高是132厘米，体重是25千克。原题说法错误。故答案为: ×",
+        "knowledge_points":  [
+                                 "长度单位的选择，质量单位的选择"
+                             ],
+        "source":  "23-24 二年级下·广东·期末"
+    },
+    {
+        "id":  "477",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "判断题",
+        "difficulty":  0.65,
+        "question":  "2000克的铁比2千克的棉花重。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】根据克与千克之间的进率,1千克=1000克，将单位进行统一，再进行比较。\n\n【详解】1千克=1000克，则2000克=2千克，所以2000克的铁与2千克的棉花一样重。故答案为: ×",
+        "knowledge_points":  [
+                                 "克，千克之间的换算与比较"
+                             ],
+        "source":  "23-24 二年级下·广东·期末"
+    },
+    {
+        "id":  "478",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "7千克铁与7千克棉花一样重。( )",
+        "options":  [
+
+                    ],
+        "answer":  "√",
+        "solution":  "【分析】我国有特定的计量单位斤，常用计量单位克(g),千克(kg),美国英国的磅等。根据7千克=7千克进行判断即可。\n\n【详解】由分析可得:7千克铁与7千克棉花一样重，原题说法正确。故答案为:√",
+        "knowledge_points":  [
+                                 "千克的认识"
+                             ],
+        "source":  "23-24 二年级下·湖北荆门·期末"
+    },
+    {
+        "id":  "479",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "4千克棉花加上4000克铁共重8千克。( )",
+        "options":  [
+
+                    ],
+        "answer":  "√",
+        "solution":  "【分析】求共重多少千克，用加法计算，即棉花的重量+铁的重量=总重量，根据1000克=1千克统一单位再计算。\n\n【详解】铁:4000克=4千克,4千克+4千克=8千克,4千克棉花加上4000克铁共重8千克。原题说法正确。故答案为:√",
+        "knowledge_points":  [
+                                 "克，千克之间的换算与比较"
+                             ],
+        "source":  "23-24 二年级下·山东济宁·期末"
+    },
+    {
+        "id":  "480",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "判断题",
+        "difficulty":  0.65,
+        "question":  "我们班的小星同学特别瘦，体重只有38克。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】根据生活经验，对质量单位和数据大小的认识可知，称比较轻的物体，通常用\"克\"作单位,1枚1分的硬币大约重1克;计量比较重的物品，常用\"千克\"作单位;2袋盐重1千克;计量小星同学的体重，结合数据38，应该用\"千克\"作为单位比较合适。\n\n【详解】我们班的小星同学特别瘦，体重只有38千克。故答案为: ×",
+        "knowledge_points":  [
+                                 "质量单位的选择"
+                             ],
+        "source":  "22-23二年级下·甘肃天水·期末"
+    },
+    {
+        "id":  "481",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "小丽妈妈买了一瓶大约500千克的洗手液。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】根据生活经验，对质量单位和数据大小的认识可知：计量比较轻的物体，常用克作单位,2个曲别针约重1克;计量比较重的物体，常用千克作单位,2袋白砂糖重1千克;洗手液的质量较轻，用克作单位比较合适。\n\n【详解】由分析可知，小丽妈妈买了一瓶大约500克的洗手液。原题说法错误。故答案为: ×",
+        "knowledge_points":  [
+                                 "质量单位的选择"
+                             ],
+        "source":  "23-24 二年级下·河北石家庄·期末"
+    },
+    {
+        "id":  "482",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "3千克的棉花比3000克的铁轻。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】比较两个物体重量的关系，无论物体的材质如何，只比较重量大小即可。根据1千克=1000克换算比较。\n\n【详解】3千克=3000克,3千克的棉花和3000克的铁比较，棉花和铁一样重。原题说法错误。故答案为: ×",
+        "knowledge_points":  [
+                                 "克，千克之间的换算与比较"
+                             ],
+        "source":  "23-24 二年级下·广西柳州·期末"
+    },
+    {
+        "id":  "483",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "判断题",
+        "difficulty":  0.65,
+        "question":  "6千克棉花和6千克铁比较,6千克铁更重。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】比较两个物体重量的关系，无论物体的材质如何，只比较重量大小即可。6千克=6千克，棉花和铁重量相同，据此解答。\n\n【详解】6千克=6千克,6千克棉花和6千克铁比较，棉花和铁一样重。原题说法错误。故答案为: ×",
+        "knowledge_points":  [
+                                 "千克的认识"
+                             ],
+        "source":  "22-23 二年级下·四川绵阳·期末"
+    },
+    {
+        "id":  "484",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "16个鸡蛋约重1000克，也就是1千克。( )",
+        "options":  [
+
+                    ],
+        "answer":  "√",
+        "solution":  "【分析】2个曲别针约重1克;2袋白砂糖约重1千克;再结合具体数据可确定,16个鸡蛋约重1000克;根据1000克=1千克换算解答即可。\n\n【详解】由分析可知:16个鸡蛋约重1000克，也就是1千克。原题说法正确。故答案为:√",
+        "knowledge_points":  [
+                                 "质量的估计，质量单位的选择，克，千克之间的换算与比较"
+                             ],
+        "source":  "23-24 二年级下·广东汕头·期末"
+    },
+    {
+        "id":  "485",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "判断题",
+        "difficulty":  0.65,
+        "question":  "一个西瓜的重量等于两个哈密瓜的重量，一个西瓜重4千克，一个哈密瓜重2千克。( )",
+        "options":  [
+
+                    ],
+        "answer":  "√",
+        "solution":  "【分析】已知一个西瓜的重量等于两个哈密瓜的重量，一个西瓜重4千克，那么两个哈密瓜重4千克，除以2即可求出一个哈密瓜重量，据此解答。\n\n【详解】4÷2=2(千克),原题说法正确。故答案为:√",
+        "knowledge_points":  [
+                                 "千克的认识，用2~5的乘法口诀求商"
+                             ],
+        "source":  "23-24 二年级下·河南南阳·期末"
+    },
+    {
+        "id":  "486",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "1千克沙子的重量大于1千克棉花的重量。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】物体的重量与物体的材质无关，据此解答即可。\n\n【详解】1千克沙子的重量等于1千克棉花的重量。原题说法错误。故答案为: ×",
+        "knowledge_points":  [
+                                 "千克的认识"
+                             ],
+        "source":  "22-23 二年级下·江西吉安·期末"
+    },
+    {
+        "id":  "487",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "一只小花猫重1千克，一只小花猪重890克，小花猪比小花猫重。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】先根据\"1千克=1000克\"来统一单位，然后比较大小，即可判断对错。\n\n【详解】1千克=1000克,1000克\u003e890克，即，一只小花猫重1千克，一只小花猪重890克，小花猫比小花猪重;原说法错误。故答案为: ×",
+        "knowledge_points":  [
+                                 "克，千克之间的换算与比较"
+                             ],
+        "source":  "23-24二年级下·贵州铜仁·期末"
+    },
+    {
+        "id":  "488",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "李明今年10岁，身高150厘米，体重40克。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】根据实际生活经验以及题干中的具体数据来进行判断即可。食指宽大约是1厘米，所以，李明今年10岁，身高150厘米是合理的;2包500克的盐重1千克,1枚1分的硬币约重1克，所以，李明今年10岁，体重40克是不合理的，而40千克比较合理。\n\n【详解】由题意分析得：李明今年10岁，身高150厘米，体重40千克;原说法错误。故答案为: ×",
+        "knowledge_points":  [
+                                 "厘米的认识，千克的认识，克的认识"
+                             ],
+        "source":  "23-24 二年级下·山东济宁·期末"
+    },
+    {
+        "id":  "489",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "判断题",
+        "difficulty":  0.65,
+        "question":  "4个桃重500克,8个桃大约重1千克。( )",
+        "options":  [
+
+                    ],
+        "answer":  "√",
+        "solution":  "【分析】4个桃重500克,8里面有2个4，所以8个桃的质量是2个500克的和，据此解答。\n\n【详解】500+500=1000(克),1000克=1千克,8个桃大约重1千克，原题干说法正确。故答案为:√",
+        "knowledge_points":  [
+                                 "克，千克之间的换算与比较，整百数，几百几十数的加减法口算"
+                             ],
+        "source":  "23-24 二年级下·甘肃天水·期末"
+    },
+    {
+        "id":  "490",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "2千克的铁与2千克的棉花比,2千克铁重。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】比较物体之间的轻重，与物体本身材质无关，与本身重量有关。铁和棉花都是2千克，所以二者是一样重的。\n\n【详解】由题意分析得:2千克的铁与2千克的棉花比，一样重。原题说法错误。故答案为: ×",
+        "knowledge_points":  [
+                                 "克，千克之间的换算与比较，千克的认识"
+                             ],
+        "source":  "23-24 二年级下·浙江宁波·期末"
+    },
+    {
+        "id":  "491",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "10克比10厘米大。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】克是表示物体质量的单位，厘米是表示物体长度的单位，不能进行比较。\n\n【详解】10克与10厘米不能进行比较。原题说法错误。故答案为: ×",
+        "knowledge_points":  [
+                                 "克的认识，厘米的认识"
+                             ],
+        "source":  "23-24 二年级下·甘肃平凉·期末"
+    },
+    {
+        "id":  "492",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "2千克的棉花和2000克的石头,2000克的石头更重。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】根据1千克=1000可将单位换算统一即可，再比较。\n\n【详解】2千克=2000克,2000克=2000克，则2千克的棉花和2000克的石头一样重，原题说法错误。故答案为: ×",
+        "knowledge_points":  [
+                                 "克，千克之间的换算与比较"
+                             ],
+        "source":  "23-24 二年级下·广西柳州·期末"
+    },
+    {
+        "id":  "493",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "王叔叔买了27个苹果，如果3个苹果约1千克，那么这些苹果大约有多少千克。",
+        "options":  [
+
+                    ],
+        "answer":  "9千克",
+        "solution":  "【分析】用27除以3求出27里有几个3，有几个3就有几个1千克，据此解答即可。\n\n【详解】27÷3×1=9×1=9(千克),答：这些苹果大约有9千克。",
+        "knowledge_points":  [
+                                 "表内乘除混合运算，千克的认识"
+                             ],
+        "source":  "23-24 二年级下·浙江温州·期末"
+    },
+    {
+        "id":  "494",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "我买1千克苹果和2千克桃子一共需要付多少钱。\n\n| 水果 | 价格 |\n| ---- | --------- |\n| 苹果 | 5元/500克 |\n| 桃子 | 3元/500克 |\n| 香蕉 | 5元/500克 |\n| 西瓜 | 2元/500克 |\n| 菠萝 | 4元/500克 |",
+        "options":  [
+
+                    ],
+        "answer":  "22元",
+        "solution":  "【分析】根据1千克=1000克=500克+500克，所以1千克等于2个500克,2千克等于4个500克，用苹果的价格*2即可求出买苹果花的钱数，用桃子的价格*4即可求出买桃子花的钱数，再根据加法的意义，用买苹果花的钱数加上买桃子花的钱数即可求出一共要付的钱数。\n\n【详解】5×2+3×4=10+12=22(元),答：我买1千克苹果和2千克桃子一共需要付22元。",
+        "knowledge_points":  [
+                                 "克，千克之间的换算与比较，乘加，乘减混合运算"
+                             ],
+        "source":  "23-24 二年级下·江西吉安·期末"
+    },
+    {
+        "id":  "495",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "某菜市场各种蔬菜的价格如下:\n\n| | 黄瓜 | 茄子 | 西红柿 | 白菜 |\n| ---- | ----- | ----- | ------ | ----- |\n| 质量 | 500克 | 500克 | 500克 | 500克 |\n| 价格 | 5元 | 3元 | 4元 | 2元 |\n\n(1)买1千克黄瓜和2000克白菜需要多少钱。\n(2)再提一个数学问题并解答。",
+        "options":  [
+
+                    ],
+        "answer":  "18元;买1千克茄子需要多少钱。6元(答案不唯一)",
+        "solution":  "【分析】(1)1千克=1000克,1千克是2个500克,2000克是4个500克，分别用乘法计算出1千克黄瓜的价格和2000克白菜的价格，相加就是总价格;(2)提出的问题符合题意即可。可提出，买1千克茄子需要多少钱。\n\n【详解】(1)1千克黄瓜:5×2=10(元),2000克白菜:2×4=8(元),10+8=18(元),答：买1千克黄瓜和2000克白菜需要18元。(2)买1千克茄子需要多少钱。(答案不唯一)3×2=6(元),答：买1千克茄子需要6元钱。",
+        "knowledge_points":  [
+                                 "克，千克之间的换算与比较,5的乘法口诀及应用，\"提问题\"\"填条件\"问题"
+                             ],
+        "source":  "23-24 二年级下·甘肃平凉·期末"
+    },
+    {
+        "id":  "496",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "下面是超市里的水果价格表.\n\n| 名称 | 价格 |\n| ---- | --------- |\n| 苹果 | 5元/500克 |\n| 梨 | 4元/500克 |\n| 桃 | 8元/500克 |\n| 菠萝 | 9元/500克 |\n\n(1)李阿姨买了1千克菠萝和500克梨，一共花了多少钱。\n(2)买500克桃的钱可以买多少千克梨。",
+        "options":  [
+
+                    ],
+        "answer":  "22元;1千克",
+        "solution":  "【分析】(1)1千克=1000克,1千克是2个500克,1千克菠萝的钱数也就是2个9元的和，用乘法计算，再和500克梨的钱数相加即可;(2)根据题意，用乘法计算出1千克梨需要多少钱，再用500克桃的钱数/1千克梨的价格=可以买梨的千克数。\n\n【详解】(1)9×2+4=18+4=22(元),答：一共花了22元钱。(2)8÷(4×2)=8÷8=1(千克),答：买500克桃的钱可以买1千克梨。",
+        "knowledge_points":  [
+                                 "乘加，乘减混合运算，带有小括号的混合运算，克，千克之间的换算与比较"
+                             ],
+        "source":  "23-24 二年级下·河北石家庄·期末"
+    },
+    {
+        "id":  "497",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "开心农场.\n\n| 蔬菜 | 黄瓜 | 西红柿 | 土豆 |\n| ---- | -------- | -------- | -------- |\n| 价格 | 3元500克 | 4元500克 | 3元500克 |\n\n(1)买2千克西红柿和500克土豆，一共应付多少钱。\n(2)奶奶有12元钱，最多可以买几千克黄瓜。\n(3)你还能提出其他数学问题并解决吗。",
+        "options":  [
+
+                    ],
+        "answer":  "19元;2千克;买3千克西红柿多少钱。24元(答案不唯一)",
+        "solution":  "【分析】(1)已知西红柿4元500克，根据2千克=2000克，看2000克里面有几个500克，就需要花几个4元，据此求出买西红柿花的钱，再加上500克土豆的钱，就是一共花的钱;(2)已知黄瓜3元500克，看12元里面包含几个3元，就买几个500克;据此解答;(3)根据表中信息提出合理的数学问题并解答即可。\n\n【详解】(1)2千克里面有4个500克。4×4+3=16+3=19(元),答：买2千克西红柿和500克土豆，一共应付19元钱。(2)12÷3=4,500+500+500+500=2000(克),2000克=2千克，答：最多可以买2千克黄瓜。(3)买3千克西红柿多少钱。(答案不唯一)3千克里面有6个500克。4×6=24(元),答：买3千克西红柿24元钱。",
+        "knowledge_points":  [
+                                 "6的乘法口诀及应用，克，千克之间的换算与比较，表内乘加，乘减，\"提问题\"\"填条件\"问题"
+                             ],
+        "source":  "23-24 二年级下·湖南常德·期末"
+    },
+    {
+        "id":  "498",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "李阿姨买了2千克的香蕉和500克的荔枝，一共花了多少元。\n\n| 水果 | 价格 |\n| ---- | ---------- |\n| 苹果 | 6元/500克 |\n| 香蕉 | 3元/500克 |\n| 荔枝 | 15元/500克 |",
+        "options":  [
+
+                    ],
+        "answer":  "27元",
+        "solution":  "【分析】根据1千克=1000克=500克+500克，所以2千克等于4个500克，用香蕉的单价*4即可求出买香蕉花的钱数，再加上买荔枝花的15元即可求出一共花的钱数。\n\n【详解】2千克=500克+500克+500克+500克,3×4+15=12+15=27(元),答：一共花了27元。",
+        "knowledge_points":  [
+                                 "克，千克之间的换算与比较，乘加，乘减混合运算，经济问题"
+                             ],
+        "source":  "23-24 二年级下·湖北黄石·期末"
+    },
+    {
+        "id":  "499",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "农场里3只羊的质量等于9只狗的质量,2只狗的质量等于5只公鸡的质量，已知1只公鸡重4千克，则一只羊重多少千克。",
+        "options":  [
+
+                    ],
+        "answer":  "30千克",
+        "solution":  "【分析】利用等量代换，已知1只公鸡重4千克，根据2只狗的质量等于5只公鸡的质量，可以先算出5只公鸡的质量是5×4=20(千克),即2只狗重20千克，从而算出1只狗重10千克;根据3只羊的质量等于9只狗的质量，可以算出9只狗重90千克，用90除以3即可求出1只羊的质量，据此作答。\n\n【详解】5只公鸡的质量:5×4=20(千克),2只狗的质量=5只公鸡的质量=20千克,1只狗的质量:20÷2=10(千克),9只狗的质量:9×10=90(千克),3只羊的质量=9只狗的质量=90千克,1只羊的质量:90÷3=30(千克),答：一只羊重30千克。",
+        "knowledge_points":  [
+                                 "等量代换"
+                             ],
+        "source":  "23-24三年级上·全国·课后作业"
+    },
+    {
+        "id":  "500",
+        "unit":  "第八单元 克和千克",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "幸福超市水果价目表如下.\n\n| 水果 | 苹果 | 梨子 | 香蕉 | 石榴 |\n| ---- | --------- | --------- | --------- | --------- |\n| 价格 | 4元/500克 | 3元/500克 | 2元/500克 | 7元/500克 |\n\n(1)买2千克苹果和500克石榴需要多少钱。\n(2)小新带了20元钱，买1500克香蕉和2千克梨子，够吗。",
+        "options":  [
+
+                    ],
+        "answer":  "23元;够",
+        "solution":  "【分析】(1)1千克=1000克,1千克是2个500克，所以2千克是4个500克，然后用苹果的单价乘数量得出苹果的总价，再加500克石榴的价钱即可;(2)1500克是3个500克，分别用乘法计算出1500克香蕉和2千克梨子的总价，再相加，最后用和与20元进行比较即可。\n\n【详解】(1)2千克是4个500克;4×4+7=16+7=23(元),答：买2千克苹果和500克石榴需要23元钱。(2)1500克是3个500克;2×3+3×4=6+12=18(元),18\u003c20，答：小新带了20元钱，够买1500克香蕉和2千克梨子。",
+        "knowledge_points":  [
+                                 "克，千克之间的换算与比较，表内乘加，乘减"
+                             ],
+        "source":  "23-24 二年级下·湖北黄冈·期末"
+    }
+]
\ No newline at end of file
diff --git "a/\344\272\214\345\271\264\347\272\247\351\242\230\351\233\206/\344\272\214\345\271\264\347\272\247\344\270\213/\344\272\214\345\271\264\347\272\247\344\270\213\347\254\254\345\205\255\345\215\225\345\205\203\346\234\211\344\275\231\346\225\260\347\232\204\351\231\244\346\263\225.json" "b/\344\272\214\345\271\264\347\272\247\351\242\230\351\233\206/\344\272\214\345\271\264\347\272\247\344\270\213/\344\272\214\345\271\264\347\272\247\344\270\213\347\254\254\345\205\255\345\215\225\345\205\203\346\234\211\344\275\231\346\225\260\347\232\204\351\231\244\346\263\225.json"
new file mode 100644
index 0000000000000000000000000000000000000000..b53311647e799fef49490c8ae75ae9eb7f65d1b6
--- /dev/null
+++ "b/\344\272\214\345\271\264\347\272\247\351\242\230\351\233\206/\344\272\214\345\271\264\347\272\247\344\270\213/\344\272\214\345\271\264\347\272\247\344\270\213\347\254\254\345\205\255\345\215\225\345\205\203\346\234\211\344\275\231\346\225\260\347\232\204\351\231\244\346\263\225.json"
@@ -0,0 +1,8768 @@
+[
+    {
+        "id":  "1",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "选择题",
+        "difficulty":  0.94,
+        "question":  "碳中和文具是指对可再生资源进行再生利用制作成的文具。将 36 支碳中和荧光笔装进盒子里,( ),每个盒子正好装满。",
+        "options":  [
+                        "A. 每 7 支装一盒",
+                        "B. 每 8 支装一盒",
+                        "C. 每 9 支装一盒"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】分别计算36支碳中和荧光笔按每个选项的数量装盒时，是否能正好装满，即判断36能否被各个选项中的数整除。若没有余数则能正好装满，若有余数则不能，这里用到除法运算中\"被除数 / 除数 = 商……余数\"的关系，重点是看余数是否为0。\n\n【详解】A. 36÷7=5(盒)……1(支),余下1支，答案错误。\nB. 36÷8=4(盒)……4(支),余下4支，答案错误。\nC. 36÷9=4(盒),每个盒子正好装满，答案正确。\n故答案为:C",
+        "knowledge_points":  [
+                                 "有余数除法的认识",
+                                 "用 7~9 的乘法口诀求商"
+                             ],
+        "source":  "25-26 二年级上·全国·单元测试"
+    },
+    {
+        "id":  "2",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "穿一条手链需要 8 颗珠子。青青有 30 颗珠子可以穿几条手链。还剩几颗珠子。下列竖式中虚线框中的\"3\"表示的意义，下列说法正确的是( ).\n![](images/d2d1740c2e2ae7212b03da1c68c186657abcee28ac2bdfe64ee02058b68cf7e1.jpg)",
+        "options":  [
+                        "A. 表示穿好了30条手链。",
+                        "B. 表示穿好了3条手链。",
+                        "C. 表示已经用了3颗珠子。"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】由题意可知：用30颗珠子除以一条手链需要的珠子数，求出的商是能穿的手链条数;竖式虚线框中的\"3\"在商的位置，故表示的意义是穿了3条手链;据此可选择。\n\n【详解】由分析可得：竖式中虚线框中的\"3\"表示的意义，说法正确的是表示穿好了3条手链。故答案为:B",
+        "knowledge_points":  [
+                                 "有余数除法的实际应用",
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "24-25 二年级下·四川南充·期末"
+    },
+    {
+        "id":  "3",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "如图,![](images/6a176987332faf0bf793bb4b353a903b.png)按照规律，它的下一个图形应该是( )。![](images/13c3c19aa1599ea2635048e71dfab76e.png)",
+        "options":  [
+
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】由图可知，第一个图形有1个圆点，第二个图形有3个圆点，第三个图形有5个圆点，第四个图形有7个圆点，即后一个图形比前一个图形多2个圆点。所以下一个图形应该有9个圆点且圆点呈\"V\"字形。据此解答。\n\n【详解】由分析得，下一个图形应该是有9个圆点的\"V\"字形图。故答案为:B",
+        "knowledge_points":  [
+                                 "图形的变化规律"
+                             ],
+        "source":  "24-25 三年级上·河南周口·期中"
+    },
+    {
+        "id":  "4",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "科学小组制作了28只蝴蝶标本，每个容器能放6只，至少需要( )个这样的容器。",
+        "options":  [
+                        "A. 4",
+                        "B. 5",
+                        "C. 6"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】问题是求至少需要几个这样的容器，可以先用除法求出可以装满几个这样的容器和剩余的蝴蝶标本只数，剩余的蝴蝶标本还需要1个容器来装，商再加1就是至少需要的容器个数。\n\n【详解】28÷6=4(个)……4(只)。剩余的4只蝴蝶标本还需要1个容器来装，所以至少要4+1=5(个)这样的容器。故答案为:B",
+        "knowledge_points":  [
+                                 "有余数除法的实际应用"
+                             ],
+        "source":  "24-25三年级上·河南周口·期中"
+    },
+    {
+        "id":  "5",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "下边竖式中遮住的数是( ).\n![](images/7abdeea08bd720df75ee0054def3d4428d517a1cb3eb479ca2e381188fa61e1e.jpg)",
+        "options":  [
+                        "A. 19",
+                        "B. 25",
+                        "C. 31"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】根据有余数除法各部分之间的关系：商×除数+余数=被除数，即可求出遮住的数;据此解答。\n\n【详解】由分析可得:7×4+3=28+3=31。下边竖式中遮住的数是31。故答案为:C",
+        "knowledge_points":  [
+                                 "表内乘加",
+                                 "乘减",
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "24-25二年级下·云南文山·期末"
+    },
+    {
+        "id":  "6",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "欢欢准备了 42 双手套，给每位环卫工人赠送8双手套。观察欢欢列的竖式，下列说法不正确的是( ).\n![](images/ee726352ecdbdecee2fcbb213b2a069da4d42294a8c9b3ee4a084f193fe1e4b1.jpg)",
+        "options":  [
+                        "A. 2表示剩下2双手套",
+                        "B. 5表示可以送给 5 位环卫工人",
+                        "C. 8 表示可以送给 8 位环卫工人"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】从题干可知:42表示欢欢准备的手套总数,8表示送给每位环卫工人的手套数量，用42÷8得出的商表示可以送给几位环卫工人，余数表示剩余的手套数量。\n\n【详解】据分析可知:A. 2表示剩下2双手套，说法正确;B. 5表示可以送给5位环卫工人，说法正确;C. 8表示每位环卫工人分得8双手套，不是可以送给8位环卫工人，说法错误。故答案为:C",
+        "knowledge_points":  [
+                                 "有余数除法的认识",
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "24-25 二年级下·广东江门·期末"
+    },
+    {
+        "id":  "7",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "○□□△△△○□□△△△。照这样排下去，第 37 个图形是( )。",
+        "options":  [
+                        "A. ○",
+                        "B. □",
+                        "C. △"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】根据图示，每组以1个圆形、2个正方形、3个三角形共6个图形循环，用除法计算出第37个图形的位置，有余数时，余数是几就是每组的第几个，没有余数则是一组中的最后一个，从而判断图形。\n\n【详解】由分析可得:1+2+3=6(个),37÷6=6(组)……1(个),则余数是1，为每组的第1个图形，是圆形。故答案为:A",
+        "knowledge_points":  [
+                                 "图形的变化规律",
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "24-25二年级下·湖北省直辖县级单位·期末"
+    },
+    {
+        "id":  "8",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "□÷6=5。□,被除数最大是( )。",
+        "options":  [
+                        "A. 31",
+                        "B. 39",
+                        "C. 35"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】在有余数的除法中，余数必须小于除数。已知除数是6，商是5，余数最大为5。根据被除数=除数×商+余数，计算被除数最大值。\n\n【详解】6-1=5,6×5+5=30+5=35。即，被除数最大是35。故答案为:C",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算",
+                                 "余数与除数的关系"
+                             ],
+        "source":  "24-25 二年级下·河北保定·期末"
+    },
+    {
+        "id":  "9",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "每件衣服要钉 4 个扣子，一共有 15 个扣子，最多可以钉几件衣服。三位同学的做法中，正确的是( )。",
+        "options":  [
+                        "A. 15÷4=2。7 小东：最多钉 2 件。",
+                        "B. ![](images/110520.png) 小西：最多钉3件。",
+                        "C. ![](images/110524.png) 小北：最多钉4件。"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】根据题意，用15个扣子除以每件衣服要钉4个扣子，即可求出可以钉几件，还剩几个，计算的结果用\"去尾法\"，逐项分析各个选项，找出正确答案即可。\n\n【详解】15÷4=3(件)……3(个),所以最多可以钉3件衣服。\nA. 15÷4=2(件)……7(个),余数比除数大，计算结果错误，小东的做法错误;B. 15个扣子，每4个钉1件，钉了3件后还剩3个，不能再钉1件，所以最多钉3件，小西的做法正确;C. 15个扣子，每4个钉1件，钉了3件后还剩3个，不能再钉1件，小北说最多钉4件，做法错误。故答案为:B",
+        "knowledge_points":  [
+                                 "有余数除法的实际应用",
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "24-25 二年级下·湖北恩施·期末"
+    },
+    {
+        "id":  "10",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "有 39 个皮球，至少再添( )个，才能平均分给7个班。",
+        "options":  [
+                        "A. 2",
+                        "B. 3",
+                        "C. 4",
+                        "D. 5"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】先用除法计算出商，也就是每个班能分几个小皮球，再用7减去余数计算出需要添的皮球数;据此解答。\n\n【详解】39÷7=5(个)……4(个),7-4=3(个),至少再添3个，才能平均分给7个班。故答案为:B",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算",
+                                 "有余数除法的实际应用"
+                             ],
+        "source":  "24-25 二年级下·福建龙岩·期末"
+    },
+    {
+        "id":  "11",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "一个数除以 7，如果有余数，那么余数最大是( )。",
+        "options":  [
+                        "A. 6",
+                        "B. 7",
+                        "C. 8"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】在有余数的除法中，余数一定要比除数小，最大的余数=除数-1，据此解答。\n\n【详解】7-1=6，一个数除以7，如果有余数，那么余数最大是6。故答案为:A",
+        "knowledge_points":  [
+                                 "余数与除数的关系"
+                             ],
+        "source":  "24-25 二年级下·山东菏泽·期末"
+    },
+    {
+        "id":  "12",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "有 14 个球，每 6 个装一盒，至少需要( )个盒子才能装完。",
+        "options":  [
+                        "A. 2",
+                        "B. 3",
+                        "C. 4"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】由题意可知：用球的总个数除以每盒的个数，求出的商是装满的盒子数，余数是剩余球的个数，还需一个盒子把剩余的球装进去，故需商+1个盒子;据此解答。\n\n【详解】由分析可得:14÷6=2(个)……2(个),2+1=3(个),至少需要3个盒子才能装完。故答案为:B",
+        "knowledge_points":  [
+                                 "有余数除法的实际应用",
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "24-25 二年级下·广东潮州·期末"
+    },
+    {
+        "id":  "13",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "用 13 根小棒搭△,上面的竖式中 4 的含义是( ).\n![](images/110544.png)",
+        "options":  [
+                        "A. 可以搭4个三角形",
+                        "B. 用去 4 根小棒",
+                        "C. 还剩4根小棒"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】在除法竖式中，被除数是13根小棒，除数是每个△需要的3根小棒，竖式中的商表示可以搭4个△。据此可选择。\n\n【详解】由分析可得：用13根小棒搭△,上面的竖式中4的含义是可以搭4个三角形。故答案为:A",
+        "knowledge_points":  [
+                                 "有余数除法的实际应用",
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "24-25 二年级下·广东汕头·期末"
+    },
+    {
+        "id":  "14",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "一个数除以 8，商和余数相等，被除数最大是( )。",
+        "options":  [
+                        "A. 57",
+                        "B. 63",
+                        "C. 81"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】要使被除数最大，则余数也应最大，在有余数的除法算式里，余数应比除数小，依此确定出最大的余数和商，被除数=商×除数+余数，当余数最大时，依此计算出被除数即可。\n\n【详解】除数是8，则余数最大是7，商也是7，则被除数为:7×8+7=56+7=63，所以被除数最大是63。故答案为:B",
+        "knowledge_points":  [
+                                 "表内乘加",
+                                 "乘减",
+                                 "余数与除数的关系"
+                             ],
+        "source":  "24-25 二年级下·广东江门·期末"
+    },
+    {
+        "id":  "15",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "把36个桃子平均分给 5 只猴子，每只猴子可以分到几个。还剩几个。下面的竖式中，\"35\"表示( ).\n![](images/110558.png)",
+        "options":  [
+                        "A. 剩下的桃子数量",
+                        "B. 分掉的桃子数量",
+                        "C. 每只猴子分到的桃子数量"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】有余数除法竖式计算：被除数写在除号下面，除数写在除号左边，商写在除号上面，对应数位上，商跟除数相乘结果写在被除数的下面，再计算出余数，余数必须比除数小。据此解答。35是商7和除数5相乘的结果，表示每只猴子分的7个桃子乘5只猴子，共分掉的桃子数;据此可选择。\n\n【详解】由分析可得：下面的竖式中，\"35\"表示分掉的桃子数量。故答案为:B",
+        "knowledge_points":  [
+                                 "有余数除法的实际应用",
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "24-25二年级下·四川凉山·期末"
+    },
+    {
+        "id":  "16",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "用 25 根小棒摆独立的，可以摆几个。还剩几根。下面竖式里的\"24\"表示( ).\n![](images/8e622cb644a2c2bb454679cdae729e53b42bf333585518f23989b21beccf2c3f.jpg)",
+        "options":  [
+                        "A. 还剩24根小棒",
+                        "B. 摆了24个",
+                        "C. 用了24根小棒"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】根据除法竖式的意义，竖式中的25是被除数，表示一共有25根小棒,4是除数，表示摆一个独立的用4根小棒,6是商，表示可以摆6个,1是余数，表示还剩小棒的根数,24是4和6的乘积，表示摆一个独立的用4根小棒，摆6个一共用了24根小棒，据此解答。\n\n【详解】A。 还剩24根小棒，根据分析可知，还剩1根小棒，不符合题意;B. 摆了24个，根据分析可知，摆了6个，不符合题意;C. 用了24根小棒,24是4和6的乘积，表示摆6个一共用了24根小棒，符合题意;竖式里的24表示用了24根小棒。故答案为:C",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算",
+                                 "有余数除法的实际应用"
+                             ],
+        "source":  "24-25 二年级下·四川成都·期末"
+    },
+    {
+        "id":  "17",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "运动会前，小明想帮老师把47名参加50米跑的学生分组，按每6人一组，可以分成几个小组。还剩几人。小明列出的竖式如下图，箭头所指的\"42\"表示( ).\n![](images/110614.png)",
+        "options":  [
+                        "A. 还剩下42名学生",
+                        "B. 6个小组一共42名学生",
+                        "C. 7个小组一共42名学生"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】根据被除数/除数=商。余数，据此结合题干要求进行解答即可。从题干可知:47表示报名参加50米跑的学生的人数,6表示每组的人数，所以7则表示分的组数,6×7=42(名),\"42\"表示7个小组一共42名学生,5则表示剩下的人数。据此解决即可。\n\n【详解】运动会前，小明想帮老师把47名参加50米跑的学生分组，按每6人一组，可以分成几个小组。还剩几人。小明列出的竖式如下图，箭头所指的\"42\"表示(7个小组一共42名学生)。故答案为:C",
+        "knowledge_points":  [
+                                 "有余数除法的实际应用"
+                             ],
+        "source":  "24-25二年级下·湖北省直辖县级单位·期末"
+    },
+    {
+        "id":  "18",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "小云按下图的规律穿珠子，第 30 个珠子是( ).\n![](images/4997736efef623ea3fd3154e2ed31dd559c0cd54dc4ac847e6d826fb3b180dc1.jpg)",
+        "options":  [
+                        "A. 黑珠",
+                        "B. 白珠",
+                        "C. ☆"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】观察题干可知：这串珠子是按照4个为一组的顺序排列，据此用30÷4得出第30个珠子是第几组第几个，即可得出答案。\n\n【详解】30÷4=7(组)。2(个),所以第30个珠子是第8组第2个，所以第30个珠子是☆。故答案为:C",
+        "knowledge_points":  [
+                                 "图形的变化规律",
+                                 "有余数除法的实际应用"
+                             ],
+        "source":  "24-25 二年级下·广东汕头·期末"
+    },
+    {
+        "id":  "19",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "○÷7=8。□,○最大能填( )。",
+        "options":  [
+                        "A. 56",
+                        "B. 63",
+                        "C. 62",
+                        "D. 6"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】根据余数比除数小，得出最大的余数是6，再根据除数乘商加余数等于被除数得出结论即可。\n\n【详解】最大的余数是6,7×8+6=56+6=62，即○最大能填62;故答案为:C",
+        "knowledge_points":  [
+                                 "余数与除数的关系",
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "24-25 二年级下·福建厦门·期末"
+    },
+    {
+        "id":  "20",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "选择题",
+        "difficulty":  0.94,
+        "question":  "淘气带了20元，买6元一个的冰激凌，根据算式20÷6=3(个)。2(元),可知最多能买几个冰激凌。( )",
+        "options":  [
+                        "A. 3",
+                        "B. 4",
+                        "C. 2"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】根据题意，用总钱数除以每个冰激凌的价钱，求出商和余数，商是最多能买冰激凌的个数，余数是还剩下的钱数，即可解决。\n\n【详解】根据算式20÷6=3(个)。2(元)可知，商是3，即是最多能买3个冰激凌，还剩下2元。故答案为:A",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算",
+                                 "有余数除法的实际应用"
+                             ],
+        "source":  "24-25 二年级下·江西九江·期末"
+    },
+    {
+        "id":  "21",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "一根绳子长 26 米，每5米剪一段，最多可以剪成( )段这样长度的绳子。",
+        "options":  [
+                        "A. 4",
+                        "B. 5",
+                        "C. 6"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】一根绳子的总米数除以每剪一段的米数，商就是最多可以剪成几段这样长度的绳子，余数是还剩的米数。\n\n【详解】26÷5=5(段)。1(米),最多可以剪成5段这样长度的绳子。故答案为:B",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算",
+                                 "有余数除法的实际应用"
+                             ],
+        "source":  "24-25 二年级下·陕西延安·期末"
+    },
+    {
+        "id":  "22",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "△□□◇√△◇√△□◇按这样的规律摆下去，第 27 个图形是( )。",
+        "options":  [
+                        "A. □",
+                        "B. ◇",
+                        "C. √"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】根据题意可知，这组图形按照△□◇√为一组重复排列，每组有4个图形，则用27除以每组图形的数量，若能除尽，则是这组的最后一个图形;若除不尽，则余数是几就是下一组的第几个图形。\n\n【详解】27÷4=6(组)。3(个),第27个图形是第7组的第3个，是◇。故答案为:B",
+        "knowledge_points":  [
+                                 "有余数除法的实际应用"
+                             ],
+        "source":  "24-25 二年级下·湖南张家界·期末"
+    },
+    {
+        "id":  "23",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "体育老师有 39 个皮球，最少拿走( )个，剩下的就能平均分给 7 个班了。",
+        "options":  [
+                        "A. 11",
+                        "B. 2",
+                        "C. 4"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】根据题意，用皮球的总数量/平均分的班级数=每个班分到皮球的数量。剩余皮球的数量，要想平均分给7个班，则至少要拿走的数量也就是剩余的数量。\n\n【详解】39÷7=5(个)。4(个),则最少拿走4个，剩下的就能平均分给7个班了。故答案为:C",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "24-25 二年级下·湖南张家界·期末"
+    },
+    {
+        "id":  "24",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "如果将中国代表团在巴黎奥运会上获得的所有金牌每 5 枚装一盒，那么正好能装完，这些金牌有( )枚。",
+        "options":  [
+                        "A. 40",
+                        "B. 44",
+                        "C. 48"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】用金牌总数除以每盒装的金牌数，求出结果，结果若没有余数，则表示正好能装完;结果若有余数，则表示不能正好装完。\n\n【详解】A。 40÷5=8(盒);B. 44÷5=8(盒)。4(枚);C. 48÷5=9(盒)。3(枚)。则，这些金牌有40枚。故答案为:A",
+        "knowledge_points":  [
+                                 "用7~9的乘法口诀求商",
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "24-25二年级下·湖南张家界·期末"
+    },
+    {
+        "id":  "25",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "把23个苹果平均分给4个小朋友，每人分得几个。还剩几个。竖式中的20表示( ).\n![](images/110638.png)",
+        "options":  [
+                        "A. 一共有20个苹果",
+                        "B. 分掉了20个苹果",
+                        "C. 还剩20个苹果"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】根据题意，苹果的总数量/平均分给小朋友的人数=每人分得的数量。还剩苹果的数量。用竖式计算时，除号下面是被除数即苹果的总数量;除号外边是除数即平均分给小朋友的人数;除号上面是商即每人分得的数量;被除数下面是除数和商的积，即分掉苹果的数量;最下边是余数即剩下苹果的数量，由此解答。\n\n【详解】A。 一共有20个苹果：根据题意可知，一共有23个苹果，不符合题意;B. 分掉了20个苹果:20是4×5的积，即分掉苹果的数量，符合题意;C. 还剩20个苹果：根据分析可知，还剩3个苹果，不符合题意。竖式中的20表示分掉了20个苹果。故答案为:B",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算",
+                                 "有余数除法的实际应用"
+                             ],
+        "source":  "24-25 二年级下·福建厦门·期末"
+    },
+    {
+        "id":  "26",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "李老师有 48 根小棒，下图的竖式是李老师分小棒的过程，箭头所指的数表示的含义正确的是( ).\n![](images/110738.png)",
+        "options":  [
+                        "A. 要分的45根小棒",
+                        "B. 还剩45根小棒",
+                        "C. 分走的45根小棒"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】用竖式计算48÷5时，个位上商9,5×9=45，表示：分走的45根小棒,48-45=5，表示还剩5根。据此解答即可。\n\n【详解】根据分析可知：箭头所指的数表示：分走的45根小棒。故答案为:C",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "24-25 二年级下·浙江杭州·期末"
+    },
+    {
+        "id":  "27",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "把26本方格本平均分给5个同学，如图竖式方框里的25表示的是( ).\n![](images/1dfe0339e7808a33f0c6c676f0610f8324291ba6157132abe9daff9be9a68fe3.jpg)",
+        "options":  [
+                        "A. 一共有25本",
+                        "B. 分掉25本",
+                        "C. 还剩25本"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】结合题意分析得:26÷5=5(本)。1(本),5×5=25(本),表示25本方格本平均分给5个同学，每人分到5本，分掉了25本，还剩下1本;据此解决。\n\n【详解】由题意分析得：把26本方格本平均分给5个同学，如图竖式方框里的25表示的是分掉25本。故答案为:B",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算",
+                                 "有余数除法的实际应用"
+                             ],
+        "source":  "24-25 二年级下·海南省直辖县级单位·期末"
+    },
+    {
+        "id":  "28",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "下面的竖式是贝贝用来计算27根小棒可以搭几个正方形的，竖式中的\"24\"表示的含义是( ).\n![](images/110748.png)",
+        "options":  [
+                        "A. 可以搭24个正方形",
+                        "B. 搭4个正方形要用24根小棒",
+                        "C. 还剩24根小棒",
+                        "D. 搭6个正方形要用24根小棒"
+                    ],
+        "answer":  "D",
+        "solution":  "【分析】由题可知，共有27根小棒，搭一个正方形需要4根小棒，求可以搭几个正方形，其实就是求27里面有几个4，用除法计算，即27÷4.27是被除数，它代表的是小棒的总根数,4是除数，它表示搭一个正方形需要4根小棒，商是6，它表示可以搭6个正方形。我们看竖式中的24，它是4×6的结果，因为搭一个正方形需要4根小棒，搭了6个，那么总共需要的小棒根数就是4×6=24(根),所以24表示搭6个正方形要用24根小棒。\n\n【详解】由分析得:4×6=24(根),所以24表示搭6个正方形要用24根小棒。故答案为:D",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "24-25 二年级下·浙江湖州·期末"
+    },
+    {
+        "id":  "29",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "图中的竖式是小明来计算\"18 根小棒最多可以搭几个正方形\"，竖式中的\"16\"表示的意思是( ).\n![](images/110758.png)",
+        "options":  [
+                        "A. 还剩16根小棒",
+                        "B. 搭了16个正方形",
+                        "C. 可以搭4个正方形",
+                        "D. 已经用了16根小棒"
+                    ],
+        "answer":  "D",
+        "solution":  "【分析】根据除法竖式的意义，竖式中的18是被除数，表示一共有18根小棒,4是除数，表示每个正方形用4根小棒,4是商，表示可以搭几个正方形,2是余数，表示还剩小棒的根数,16是4和4的乘积，表示每个正方形用4根小棒，搭4个正方形一共用了16根小棒，据此解答。\n\n【详解】由分析可得:A. 还剩16根小棒，由分析可知，余数是2，表示还剩2根小棒，不符合题意;B. 搭了16个正方形，由分析可知，商是4，表示搭了4个正方形，不符合题意;C. 可以搭4个正方形，与竖式中的\"16\"表示的意思无关，不符合题意;D. 已经用了16根小棒，符合题意。故答案为:D",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "24-25 二年级下·浙江台州·期末"
+    },
+    {
+        "id":  "30",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在一道有余数的除法算式里，余数是8，除数最小是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "9",
+        "solution":  "【分析】有余数的除法中，余数总比除数小，余数是8，除数最小是9。\n\n【详解】根据余数比除数小，在一道有余数的除法算式里，余数是8，除数最小是9。",
+        "knowledge_points":  [
+                                 "余数与除数的关系"
+                             ],
+        "source":  "24-25三年级上·山西临汾·期中"
+    },
+    {
+        "id":  "31",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "23 个苹果，平均分给5个小朋友，每个小朋友分( )个，还剩( )个。",
+        "options":  [
+
+                    ],
+        "answer":  "4;3",
+        "solution":  "【分析】根据题意，用苹果的总数量/平均分给的人数=每人分到苹果的数量。剩余苹果的数量。\n\n【详解】23÷5=4(个)……3(个)。23个苹果，平均分给5个小朋友，每个小朋友分4个，还剩3个。",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "24-25 二年级下·山西阳泉·期末"
+    },
+    {
+        "id":  "32",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "□÷6=7。□,余数最大是( ),被除数最大是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "5;47",
+        "solution":  "【分析】在有余数的除法中，余数一定要比除数小，最大的余数=除数-1，最小的余数是1，再根据被除数=商×除数+余数，求出被除数即可。\n\n【详解】6-1=5，余数最大是5;6×7+5=42+5=47。□÷6=7……□,余数最大是5，被除数最大是47。",
+        "knowledge_points":  [
+                                 "有余数的除法验算",
+                                 "100以内有余数的除法计算",
+                                 "余数与除数的关系"
+                             ],
+        "source":  "24-25 二年级下·湖北省直辖县级单位·期末"
+    },
+    {
+        "id":  "33",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "□÷8=5。△,在这个算式中，余数最大是( ),此时被除数是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "7;47",
+        "solution":  "【分析】有余数的除法算式为：被除数/除数=商……余数，其中余数一定小于除数，余数最大是比除数小1的数，根据除数×商+余数=被除数，计算即可。\n\n【详解】由分析得：余数最大:8-1=7;被除数:8×5+7=40+7=47。□÷8=5……△,在这个算式中，余数最大是7，此时被除数是47。",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算",
+                                 "余数与除数的关系"
+                             ],
+        "source":  "24-25 二年级下·云南文山·期末"
+    },
+    {
+        "id":  "34",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "有34个小球，每盒装6个，最多可装满5盒，还剩( )个，再添( )个小球可以再装满1盒。",
+        "options":  [
+
+                    ],
+        "answer":  "4;2",
+        "solution":  "【分析】根据题意，小球的总数量/每盒装的数量=可以装满的盒数。剩余的数量，要想再装满1盒，也就是剩下的数量要凑到6个，则用6减去剩下的数量即可。\n\n【详解】34÷6=5(盒)……4(个),6-4=2(个)。有34个小球，每盒装6个，最多可装满5盒，还剩4个，再添2个小球可以再装满1盒。",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "24-25 二年级下·四川南充·期末"
+    },
+    {
+        "id":  "35",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "□÷8=9。△中,△最大是( ),这时□是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "7;79",
+        "solution":  "【分析】在有余数除法中，余数一定比除数小，则求出△最大是几，即为余数最大的是几，即为比除数少1的数，用除数减1即可，然后根据被除数=商×除数+余数即可求出□的数值。\n\n【详解】8-1=7,9×8+7=72+7=79。则□÷8=9……△中,△最大是7,这时□是79。",
+        "knowledge_points":  [
+                                 "余数与除数的关系",
+                                 "100以内有余数的除法计算",
+                                 "表内乘加",
+                                 "乘减"
+                             ],
+        "source":  "24-25 二年级下·福建龙岩·期末"
+    },
+    {
+        "id":  "36",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "39里面最多有( )个7,43里面最多有( )个5。",
+        "options":  [
+
+                    ],
+        "answer":  "5;8",
+        "solution":  "【分析】要求39里面最多有几个7，根据除法的意义，用39÷7进行计算，商是几，就表示39里面最多有几个7。要求43里面最多有几个5，根据除法的意义，用43÷5进行计算，商是几，就表示43里面最多有几个5。\n\n【详解】39÷7=5……4，所以39里面最多有5个7;43÷5=8……3，所以43里面最多有8个5。",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "24-25 二年级下·福建龙岩·期末"
+    },
+    {
+        "id":  "37",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.94,
+        "question":  "44÷6=7。2中，除数是( ),被除数是( ),2是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "6;44;余数",
+        "solution":  "【分析】根据被除数/除数=商……余数即可解答。\n\n【详解】44÷6=7……2中，除数是6,被除数是44,2是余数。",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "24-25 二年级下·福建龙岩·期末"
+    },
+    {
+        "id":  "38",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "小优用彩色珠子给自己制作了一条手链，珠子的颜色按照\"红，黄，绿，黄，红，黄，绿，黄……\"的规律排列，第27颗珠子应该是( )颜色，第32颗珠子应该是( )颜色。",
+        "options":  [
+
+                    ],
+        "answer":  "绿;黄",
+        "solution":  "【分析】通过观察，珠子颜色排列规律是：红，黄，绿，黄四个颜色为一组，不断重复出现;用第27颗和第32颗珠子分别除以每组的珠子数，求出的余数是几，就数出每组中的第几个珠子，即可知道什么颜色;如果没有余数，数出一组中的最后一颗珠子，即可知道什么颜色。据此解答。\n\n【详解】由分析可得:27÷4=6(组)……3(个),第3颗珠子是绿色。32÷4=8(组),第4颗珠子是黄色。小优用彩色珠子给自己制作了一条手链，珠子的颜色按照\"红，黄，绿，黄，红，黄，绿，黄……\"的规律排列，第27颗珠子应该是绿颜色，第32颗珠子应该是黄颜色。",
+        "knowledge_points":  [
+                                 "周期问题",
+                                 "有余数除法的实际应用",
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "24-25 二年级下·广东潮州·期末"
+    },
+    {
+        "id":  "39",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "( )里最大能填几。\n( )×8\u003c6356\u003e9×( ) ( )×6\u003c36",
+        "options":  [
+
+                    ],
+        "answer":  "7;6;5",
+        "solution":  "【分析】根据有余数的除法，用积除以乘数，如果有余数，商就是需要填的数，即所得的数为最大数;如果没有余数，用所得的商-1，就是需要填写的数，据此解答。\n\n【详解】63÷8=7……7，最大填7，则7×8\u003c63;56÷9=6……2，最大填6，则56\u003e9×6;36÷6=6,6-1=5，最大填5，则5×6\u003c36。",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算",
+                                 "用7~9的乘法口诀求商",
+                                 "用6的乘法口诀求商",
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "24-25二年级下·广东汕头·期末"
+    },
+    {
+        "id":  "40",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在一道除法算式里，除数和商都是7，余数最大，被除数是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "55",
+        "solution":  "【分析】在有余数除法中，最大的余数=除数-1，被除数=商×除数+余数;据此即可解答。\n\n【详解】7-1=6,7×7+6=49+6=55。在一道除法算式里，除数和商都是7，余数最大，被除数是55。",
+        "knowledge_points":  [
+                                 "余数与除数的关系",
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "24-25 二年级下·贵州铜仁·期末"
+    },
+    {
+        "id":  "41",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "●●●○○●●●○○●●●○○。第49颗珠子是( )珠子。",
+        "options":  [
+
+                    ],
+        "answer":  "白",
+        "solution":  "【分析】这串珠子的排列是有规律的，即按\"●●●○○\"不断地重复出现，每5颗珠子为一个周期。先用除法算出49颗珠子形成了几个完整的周期，还剩几个，即49÷5=9(个)……4(颗),余数是4，表明第49颗是一个周期的第4颗珠子，即\"○\"。\n\n【详解】49÷5=9(个)……4(颗),则第49颗珠子是白珠子。",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算",
+                                 "周期问题"
+                             ],
+        "source":  "24-25 二年级下·贵州铜仁·期末"
+    },
+    {
+        "id":  "42",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "〇/6=2。☆,☆是符合条件的最大的数,☆是( ),〇是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "5;17",
+        "solution":  "【分析】在有余数的除法中，余数一定要比除数小，最大的余数=除数-1，最小的余数是1，再根据被除数=商×除数+余数，求出被除数即可。\n\n【详解】除数是6，则余数最大是5，即☆是5;6×2+5=12+5=17。〇/6=2……☆,☆是符合条件的最大的数,☆是5,〇是17。",
+        "knowledge_points":  [
+                                 "余数与除数的关系",
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "24-25 二年级下·四川成都·期末"
+    },
+    {
+        "id":  "43",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "有45块饼干，每个小朋友分7块，可以分给( )个小朋友，还剩( )块。",
+        "options":  [
+
+                    ],
+        "answer":  "6;3",
+        "solution":  "【分析】根据题意可知：用饼干的数量除以每个小朋友分的数量，求出商和余数，商为可分的小朋友数量，余数为还剩余的饼干数量。\n\n【详解】45÷7=6(个)……3(块)。则有45块饼干，每个小朋友分7块，可以分给6个小朋友，还剩3块。",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "24-25 一年级下·山东济宁·期末"
+    },
+    {
+        "id":  "44",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "( )里最大能填几。\n56÷( )\u003e7 ( )×7\u003c4855+12\u003e( )×9",
+        "options":  [
+
+                    ],
+        "answer":  "7;6;7",
+        "solution":  "【分析】56÷( )\u003e7，用56除以7，求出结果，结果若没有余数，用商减去1，就是最大能填的数;结果若有余数，商就是最大能填的数。( )×7\u003c48，用48除以7，求出结果，结果若没有余数，用商减去1，就是最大能填的数;结果若有余数，商就是最大能填的数。55+12\u003e( )×9，先算55+12=67，再用67除以9，按同样的方法求解。\n\n【详解】56÷7=8,8-1=7，故56÷7\u003e7;48÷7=6……6，故6×7\u003c48;55+12=67,67÷9=7……4，故55+12\u003e7×9。",
+        "knowledge_points":  [
+                                 "100以内数的比大小",
+                                 "用7~9的乘法口诀求商",
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "24-25 二年级下·湖北省直辖县级单位·期末"
+    },
+    {
+        "id":  "45",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "52颗山楂最多能穿( )串，再添上( )颗，又可以穿一串了。",
+        "options":  [
+
+                    ],
+        "answer":  "8;2",
+        "solution":  "【分析】用山楂的总颗数除以每串用的山楂颗数，商就是最多能穿几串，余数是还剩的山楂颗数，用每串用的山楂颗数减去余数，即可求出再添上几颗，又可以穿一串了。\n\n【详解】52÷6=8(串)……4(颗),6-4=2(颗)。52颗山楂最多能穿8串，再添上2颗，又可以穿一串了。",
+        "knowledge_points":  [
+                                 "有余数除法的实际应用",
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "24-25 二年级下·福建龙岩·期末"
+    },
+    {
+        "id":  "46",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "○○□□□○○□□□○○□□□。照样子摆下去，第24个图形是( ),第31个图形是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "□;○",
+        "solution":  "【分析】由题可知，这组图形按照○○□□□为一组重复排列，每组有5个图形，则分别用24和31除以每组图形的数量，若能除尽，则是这组的最后一个图形;若除不尽，则余数是几就是下一组的第几个图形。\n\n【详解】24÷5=4(组)……4(个),第24个图形是第5组的第4个，是□;31÷5=6(组)……1(个),第31个图形是第7组的第1个，是○。",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算",
+                                 "有余数除法的实际应用"
+                             ],
+        "source":  "24-25 二年级下·山东菏泽·期末"
+    },
+    {
+        "id":  "47",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "有37人租车去旅游，每辆车限乘6人，最少要租( )辆车。",
+        "options":  [
+
+                    ],
+        "answer":  "7",
+        "solution":  "【分析】根据题意可知：用旅游的人数除以每辆车可乘的人数，求出商和余数，商为要租的车数，余数为剩余的人数，剩余的人数也需要坐车，则用要租的车数再加1即可。\n\n【详解】37÷6=6(辆)……1(人),6+1=7(辆)。则最少要租7辆车。",
+        "knowledge_points":  [
+                                 "有余数除法的实际应用"
+                             ],
+        "source":  "24-25 二年级下·山东菏泽·期末"
+    },
+    {
+        "id":  "48",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "□÷7=3。△,被除数最大是( ),最小是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "27;22",
+        "solution":  "【分析】有余数的除法算式为：被除数/除数=商……余数，其中余数一定比除数小，且不为0。余数最大是比除数小1的数，此时被除数最大;余数最小是1，此时被除数最小。根据除数×商+余数=被除数，计算即可。\n\n【详解】余数最大:7-1=6，被除数最大:7×3+6=21+6=27;余数最小:1，被除数最小:7×3+1=21+1=22。□÷7=3……△,被除数最大是27，最小是22。",
+        "knowledge_points":  [
+                                 "余数与除数的关系",
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "24-25二年级下·山东菏泽·期末"
+    },
+    {
+        "id":  "49",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "17个△,每5个一份，可以分成( )份，还剩( )个。列式是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "3;2;17÷5=3(份)……2(个)",
+        "solution":  "【分析】通过分一分可知,17个△,每5个一份，可以分成3份，还剩2个;用△的个数除以每份△的个数，商为可以分成的份数，余数为剩余△的个数。\n\n【详解】由分析可知:17个△,每5个一份，可以分成3份，还剩2个。列式是17÷5=3(份)……2(个)。",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "24-25 二年级下·山东菏泽·期末"
+    },
+    {
+        "id":  "50",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "现有40个篮球，至少拿走( )个篮球，剩下的正好平均分给二年级6个班;至少拿来( )个篮球，合起来也正好平均分给二年级6个班。",
+        "options":  [
+
+                    ],
+        "answer":  "4;2",
+        "solution":  "【分析】有40个篮球，求至少拿走几个，剩下的能正好平均分给6个班，用总数量除以班级的数量，求得的余数就是至少要拿走的数量;求至少再拿来几个能正好平均分给6个班，用6减去余数即可，就是至少要再拿来的数量。\n\n【详解】40÷6=6(个)……4(个),6-4=2(个)。即，现有40个篮球，至少拿走4个篮球，剩下的正好平均分给二年级6个班;至少拿来2个篮球，合起来也正好平均分给二年级6个班。",
+        "knowledge_points":  [
+                                 "有余数除法的实际应用"
+                             ],
+        "source":  "24-25 二年级下·福建厦门·期末"
+    },
+    {
+        "id":  "51",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "有40个苹果，至少拿走( )个，剩下的正好平均分给6个同学;至少增加( )个，才能平均分给7个小朋友且刚好够分。",
+        "options":  [
+
+                    ],
+        "answer":  "4;2",
+        "solution":  "【分析】用苹果的总个数除以平均分给6个同学，商就是每个同学分几个，余数是还剩下的个数，也是至少拿走的个数;用苹果的总个数除以平均分给7个同学，商就是每个同学分几个，余数是还剩下的个数，用除数减去余数，就是至少增加的个数。\n\n【详解】40÷6=6(个)……4(个)，40÷7=5(个)……5(个)，7-5=2(个)。有40个苹果，至少拿走4个，剩下的正好平均分给6个同学;至少增加2个，才能平均分给7个小朋友且刚好够分。",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算",
+                                 "有余数除法的实际应用"
+                             ],
+        "source":  "24-25 二年级下·浙江杭州·期末"
+    },
+    {
+        "id":  "52",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "○÷△=8……5，△最小是( )，这时被除数是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "6;53",
+        "solution":  "【分析】有余数除法中，余数一定比除数小，该题中余数是5，则除数一定大于5，那么除数最小是5+1=6，然后根据被除数=商×除数+余数即可求得。\n\n【详解】5+1=6，8×6+5=48+5=53。则○÷△=8……5，△最小是6，这时被除数是53。",
+        "knowledge_points":  [
+                                 "余数与除数的关系",
+                                 "表内乘加",
+                                 "乘减"
+                             ],
+        "source":  "24-25 二年级下·浙江杭州·期末"
+    },
+    {
+        "id":  "53",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "△△□□△△□□△。照这样排下去，第18个图形是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "△",
+        "solution":  "【分析】图形按照△△□□的顺序循环排列，一组4个，用除法算出18个里面有这样的几组，若没有余数就是一组中的最后一个图形，若有余数，余数是几就是一组中的第几个图形。\n\n【详解】18÷4=4(组)……2(个)，第18个图形是△。",
+        "knowledge_points":  [
+                                 "图形的变化规律",
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "24-25二年级下·江西九江·期末"
+    },
+    {
+        "id":  "54",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在□÷8=7……□中，被除数最大是( )，最小是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "63;57",
+        "solution":  "【分析】在有余数除法中，余数要比除数小，除数是8，余数最大是7，最小是1;根据商×除数+最大的余数=最大的被除数，算出最大的被除数;根据商×除数+最小的余数=最小的被除数，算出最小的被除数;据此解答。\n\n【详解】由分析可得:7×8+7=56+7=63;7×8+1=56+1=57。在□÷8=7……□中，被除数最大是63，最小是57。",
+        "knowledge_points":  [
+                                 "余数与除数的关系",
+                                 "100以内有余数的除法计算",
+                                 "乘加",
+                                 "乘减混合运算"
+                             ],
+        "source":  "24-25 二年级下·陕西延安·期末"
+    },
+    {
+        "id":  "55",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "文艺晚会上，气球按照\"黄绿紫红红，黄绿紫红红……\"的规律排列。第28个是( )色，这时有( )个红气球。",
+        "options":  [
+
+                    ],
+        "answer":  "紫;10",
+        "solution":  "【分析】由题意可知：用28除以黄绿紫红红5个颜色一组的数，求出的商是能分的组数，余数是剩余的颜色数，余数是几，就从一组的颜色中数第几个，即是第28个气球的颜色;每组有2个红色气球，用每组红色气球数乘求出的组数，即是红气球的个数;据此解答。\n\n【详解】由分析可得:28÷5=5(组)……3(个)，第3个气球是紫色。2×5=10(个)。文艺晚会上，气球按照\"黄绿紫红红，黄绿紫红红……\"的规律排列。第28个是紫色，这时有10个红气球。",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算",
+                                 "有余数除法的实际应用",
+                                 "周期问题"
+                             ],
+        "source":  "24-25 二年级下·江西赣州·期末"
+    },
+    {
+        "id":  "56",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在★÷5=7……●中，●最大是( )，这时★等于( )。",
+        "options":  [
+
+                    ],
+        "answer":  "4;39",
+        "solution":  "【分析】在有余数除法中，余数要比除数小，除数是5，余数●最大是4，用商×除数+最大余数=被除数，即可算出被除数★等于几;据此解答。\n\n【详解】由分析可得:7×5+4=35+4=39。在★÷5=7……●中，●最大是4，这时★等于39。",
+        "knowledge_points":  [
+                                 "余数与除数的关系",
+                                 "100以内有余数的除法计算",
+                                 "乘加",
+                                 "乘减混合运算"
+                             ],
+        "source":  "24-25 二年级下·江西赣州·期末"
+    },
+    {
+        "id":  "57",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在算式□÷7=5……◇中，余数最大是( )，此时被除数是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "6;41",
+        "solution":  "【分析】在有余数除法中，最大的余数等于除数减1;被除数=商×除数+余数;据此解答即可。\n\n【详解】7-1=6，7×5+6=35+6=41。即，在算式□÷7=5……◇中，余数最大是6，此时被除数是41。",
+        "knowledge_points":  [
+                                 "余数与除数的关系",
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "24-25 二年级下·湖南张家界·期末"
+    },
+    {
+        "id":  "58",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "妈妈烤了一盘饼干，数量比20块多，比30块少。如果分给4个小朋友，每人分到一样多后还剩2块;如果分给5个小朋友，每人分到一样多后也剩2块，妈妈烤了( )块饼干。",
+        "options":  [
+
+                    ],
+        "answer":  "22",
+        "solution":  "【分析】根据题意可知，每人分到块数乘4，再加上2，刚好比20块多，比30块少，据此找出这些数为22块或26块;再用这两个数除以5，找出每人分到一样多后也剩下2块的数，即可解答。\n\n【详解】4×5+2=20+2=22(块);4×6+2=24+2=26(块)。妈妈烤了一盘饼干的块数可能是22块或26块。22÷5=4(块)……2(块)，22块比20块多，比30块少，每人分到4块后剩2块，符合题意;26÷5=5(块)……1(块)，26块比20块多，比30块少，每人分到5块后剩1块，不符合题意。因此，妈妈烤了22块。",
+        "knowledge_points":  [
+                                 "表内乘加",
+                                 "乘减",
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "24-25二年级下·湖北黄冈·期末"
+    },
+    {
+        "id":  "59",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "春光小学有40名学生去参加夏令营，每间房能住6人，至少要预约( )间房。",
+        "options":  [
+
+                    ],
+        "answer":  "7",
+        "solution":  "【分析】总人数是40人，每间房住6人，求至少需要的房间数。用除法计算，40除以6得到商6余4，即6间房住满后还剩4人，因此需要再加1间房，共7间。\n\n【详解】40÷6=6(间)……4(人)，6+1=7(间)。所以，至少要预约7间房。",
+        "knowledge_points":  [
+                                 "有余数除法的实际应用",
+                                 "100以内有余数的除法计算",
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·云南曲靖·期末"
+    },
+    {
+        "id":  "60",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "用一堆小棒摆六边形，如果有剩余，最多剩( )根小棒，最少剩( )根小棒。",
+        "options":  [
+
+                    ],
+        "answer":  "5;1",
+        "solution":  "【分析】根据题意，小棒的总数量÷摆一个六边形用小棒的数量=可以摆成的个数。剩余的小棒数量在有余数的除法算式里，余数一定小于除数，且不为0，余数最大是比除数小1的数，最小是1，由此解答。\n\n【详解】由分析得：摆一个六边形需要6根小棒。6-1=5(根)。用一堆小棒摆六边形，如果有剩余，最多剩5根小棒，最少剩1根小棒。",
+        "knowledge_points":  [
+                                 "余数与除数的关系"
+                             ],
+        "source":  "24-25 二年级下·云南曲靖·期末"
+    },
+    {
+        "id":  "61",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "21根小棒，每3根搭成一个独立的三角形，一共可以搭成( )个独立的三角形。如果25根小棒，最多可以搭成( )个独立的三角形。",
+        "options":  [
+
+                    ],
+        "answer":  "7;8",
+        "solution":  "【分析】根据除法的意义，小棒的总数量÷每个图形需要的小棒数量=可以拼成的图形数量，有余数的情况下，算出的商就是最多能拼成的图形数量。由此列出算式算出答案即可解答。\n\n【详解】21÷3=7(个);25÷3=8(个)……1(根)。所以，21根小棒，每3根搭成一个独立的三角形，一共可以搭成7个独立的三角形。如果25根小棒，最多可以搭成8个独立的三角形。",
+        "knowledge_points":  [
+                                 "用7~9的乘法口诀求商",
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "24-25 二年级下·湖北孝感·期末"
+    },
+    {
+        "id":  "62",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "文艺晚会上，气球按照\"红红黄绿紫，红红黄绿紫……\"的规律排列。第26个是( )色，这时有( )个红气球。",
+        "options":  [
+
+                    ],
+        "answer":  "红;11",
+        "solution":  "【分析】气球按照红红黄绿紫的顺序循环排列，一组5个。用除法算出26个里面有这样的几组，若没有余数就是一组中的最后一个图形，若有余数，余数是几就是一组中的第几个图形;求这时有几个红气球，用每组中红气球的个数×组数+余数，即可解答。\n\n【详解】26÷5=5(组)……1(个)，2×5+1=10+1=11(个)。文艺晚会上，气球按照\"红红黄绿紫，红红黄绿紫……\"的规律排列。第26个是红色，这时有11个红气球。",
+        "knowledge_points":  [
+                                 "有余数除法的实际应用",
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "24-25 二年级下·江西赣州·期末"
+    },
+    {
+        "id":  "63",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "在算式△÷6=4……□中，△里最大是( )，最小是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "29;25",
+        "solution":  "【分析】有余数的除法算式为：被除数÷除数=商……余数，其中余数一定小于除数且不为0，余数最大是比除数小1的数，此时被除数最大。余数最小是1，此时被除数最小，根据除数×商+余数=被除数，计算即可。\n\n【详解】余数最大:6-1=5，被除数最大:6×4+5=24+5=29;余数最小:1，被除数最小:6×4+1=24+1=25。在算式△÷6=4……□中，△里最大是29，最小是25。",
+        "knowledge_points":  [
+                                 "余数与除数的关系",
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "24-25 二年级下·福建厦门·期末"
+    },
+    {
+        "id":  "64",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "有26位来宾，每张沙发坐4位，至少需要6张这样的沙发。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】有26位来宾，每张沙发坐4位，用26除以4可算出至少需要几张这样的沙发，如果有余数则用商加1，据此解答。\n\n【详解】26÷4=6(张)。2(人),6+1=7(张)。至少需要7张这样的沙发。故答案为: ×",
+        "knowledge_points":  [
+                                 "有余数除法的实际应用"
+                             ],
+        "source":  "24-25 三年级上·河南周口·期中"
+    },
+    {
+        "id":  "65",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "余数可以和除数同样大。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】在有余数的除法中，余数必须比除数小。如果余数等于除数，说明商还可以再增加1，余数会变为0，因此余数不能和除数同样大。\n\n【详解】在除法算式里，余数必须小于除数。题目说法错误。故答案为: ×",
+        "knowledge_points":  [
+                                 "余数与除数的关系"
+                             ],
+        "source":  "24-25 二年级下·湖北省直辖县级单位·期末"
+    },
+    {
+        "id":  "66",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "36÷7=4……8计算错误。( )",
+        "options":  [
+
+                    ],
+        "answer":  "√",
+        "solution":  "【分析】根据有余数除法的规则，余数必须小于除数。题目中余数是8，除数是7，余数大于除数，因此计算错误。\n\n【详解】在算式36÷7=4……8中，除数是7，余数是8。根据余数必须比除数小的原则，余数8大于除数7，不符合要求。正确的计算应为:7×5=35,36-35=1，即36÷7=5……1。因此原题说法正确。故答案为:√",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算",
+                                 "余数与除数的关系"
+                             ],
+        "source":  "24-25 二年级下·广东汕头·期末"
+    },
+    {
+        "id":  "67",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "判断题",
+        "difficulty":  0.65,
+        "question":  "■▲▲★■▲▲★■▲▲★。照这样的规律摆下去，第25个图形应该是■。( )",
+        "options":  [
+
+                    ],
+        "answer":  "√",
+        "solution":  "【分析】观察题干可知：这列图形是按照■▲▲★的顺序依次排列，要求第25个图形是什么，根据除法的意义，用25÷4进行解答，即可得出第25个图形是第几组第几个。\n\n【详解】25÷4=6(组)。1(个),所以第25个图形是第7组第1个，所以第25个图形应该是■。原题说法正确。故答案为:√",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算",
+                                 "周期问题"
+                             ],
+        "source":  "24-25 二年级下·四川·期末"
+    },
+    {
+        "id":  "68",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "判断题",
+        "difficulty":  0.65,
+        "question":  "二(1)班有30-40人，如果每6人分成一组，还剩2人。二(1)班最多有38人。( )",
+        "options":  [
+
+                    ],
+        "answer":  "√",
+        "solution":  "【分析】根据题意，二(1)班的人数在30到40之间，用总人数/每6人分一组=可以分几组。2人，据此找出满足条件的最大数即可。\n\n【详解】32÷6=5(组)。2(人);38÷6=6(组)。2(人)。二(1)班有30-40人，如果每6人分成一组，还剩2人，二(1)班最多有38人，原题说法正确。故答案为:√",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算",
+                                 "有余数除法的实际应用"
+                             ],
+        "source":  "24-25 二年级下·湖北武汉·期末"
+    },
+    {
+        "id":  "69",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "判断题",
+        "difficulty":  0.65,
+        "question":  "35÷6=6……1。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】根据有余数除法的计算法则，被除数=商×除数+余数，且余数必须小于除数。题目中35÷6=6……1，6×6=36，36+1=37，不等于被除数35，因此错误。\n\n【详解】根据分析可得:35÷6=5……5。题目中的算式35÷6=6……1，计算错误。故答案为: ×",
+        "knowledge_points":  [
+                                 "有余数的除法验算",
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "24-25 二年级下·湖北武汉·期末"
+    },
+    {
+        "id":  "70",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "在△÷□=3……6中，除数最小是5。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】有余数的除法算式为：被除数÷除数=商……余数，其中除数一定大于余数，除数最小是比余数大1的数。\n\n【详解】6+1=7，则在△÷□=3……6中，除数最小是7，原题说法错误。故答案为: ×",
+        "knowledge_points":  [
+                                 "余数与除数的关系"
+                             ],
+        "source":  "24-25 二年级下·云南曲靖·期末"
+    },
+    {
+        "id":  "71",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "在有余数的除法中，除数必须比余数大。( )",
+        "options":  [
+
+                    ],
+        "answer":  "√",
+        "solution":  "【分析】在有余数的除法中，余数必须小于除数，即除数必须比余数大，这是除法运算的基本规则。\n\n【详解】根据有余数除法的定义，余数必须小于除数。因此，除数必须比余数大，否则余数不符合要求。例如：当除数是5时，余数只能是1,2,3,4，此时除数5比余数大。原题说法正确。故答案为:√",
+        "knowledge_points":  [
+                                 "余数与除数的关系"
+                             ],
+        "source":  "24-25二年级下·广西贵港·期中"
+    },
+    {
+        "id":  "72",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "计算题",
+        "difficulty":  0.65,
+        "question":  "用竖式计算。\n36÷4= 47÷9= 63÷7= 34÷5=",
+        "options":  [
+
+                    ],
+        "answer":  "9;5……2;9;6……4",
+        "solution":  "【分析】两位数除以一位数，十位比除数小，商写在个位，再把商与除数的积写在被除数下方，最后用被除数减商与除数的积，得出余数，且余数要小于除数。据此解答。\n\n【详解】36÷4=9;47÷9=5……2;63÷7=9;34÷5=6……4",
+        "knowledge_points":  [
+                                 "用7~9的乘法口诀求商",
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "25-26 三年级上·黑龙江佳木斯·开学考试"
+    },
+    {
+        "id":  "73",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "三(1)班32个同学去划船，每条船限坐6人，至少需要租几条船。",
+        "options":  [
+
+                    ],
+        "answer":  "6条",
+        "solution":  "【分析】用总人数/每条船限乘的人数即可计算出需要几条船，如果有余数，商再加1即可解题。\n\n【详解】32÷6=5(条)。2(个),5+1=6(条)。答：至少需要租6条船。",
+        "knowledge_points":  [
+                                 "两位数除以一位数的有余数除法"
+                             ],
+        "source":  "2025 三年级上·全国·专题练习"
+    },
+    {
+        "id":  "74",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "同学们排队体检，笑笑排在第50位。每次进入8名同学，笑笑第几次才能进去体检。",
+        "options":  [
+
+                    ],
+        "answer":  "7次",
+        "solution":  "【分析】根据题意，用总人数除以每次进的人数，若能除尽，则商是几就是笑笑第几次进去;若除不尽，剩余的人数也要按一组进去，则商+1即可求出笑笑第几次进去。\n\n【详解】50÷8=6(次)。2(人),6+1=7(次)。答：笑笑第7次才能进去体检。",
+        "knowledge_points":  [
+                                 "有余数除法的实际应用",
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "23-24 三年级上·贵州铜仁·期中"
+    },
+    {
+        "id":  "75",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "一批货物有56箱。大货车运了3次，剩下的由小货车来运，小货车至少还需要运几次才能全部运完。\n![](images/5c2dedfe0dc16726fcc717041783d5c3.png)",
+        "options":  [
+
+                    ],
+        "answer":  "8次",
+        "solution":  "【分析】先用乘法算出大货车运了3次，运了几箱，再用一批货物的总箱数减去运的箱数，可以求出剩下的箱数;最后用剩下的箱数除以小货车每次最多运的箱数，商就是小货车至少还需要运几次才能全部运完，若有余数，剩下的箱数还要再运1次，据此解答。\n\n【详解】56-9×3=56-27=29(箱),29÷4=7(次)。1(箱),7+1=8(次)。答：小货车至少还需要运8次才能全部运完。",
+        "knowledge_points":  [
+                                 "乘加",
+                                 "乘减混合运算",
+                                 "有余数除法的实际应用",
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "24-25 二年级下·湖北省直辖县级单位·期末"
+    },
+    {
+        "id":  "76",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "最多可以穿成完整的多少串。\n![](images/47e0bf6978a5f09ae73c9564ef65c7e5eccf9ba7b0b9536374a19a2c7ef19fb5.jpg)",
+        "options":  [
+
+                    ],
+        "answer":  "7串",
+        "solution":  "【分析】根据题意可知：用共有的数量除以一串4个，求出商和余数，商为可以串的串数，余数为剩余的红果，剩余的红果不能串成完整的串，则舍弃。\n\n【详解】30÷4=7(串)。2(个)。答：最多可以穿成完整的7串。",
+        "knowledge_points":  [
+                                 "有余数除法的实际应用",
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "24-25 一年级下·陕西榆林·期末"
+    },
+    {
+        "id":  "77",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "一本故事书共58页，小红每天看7页，她至少需要多少天才能全部看完。",
+        "options":  [
+
+                    ],
+        "answer":  "9天",
+        "solution":  "【分析】根据题意，用故事书的总页数除以每天看的页数，若能除尽，则商是要看的天数，若除不尽，剩余的页数也需要看1天，则商+1是需要看的天数。\n\n【详解】58÷7=8(天)。2(页),8+1=9(天)。答：她至少需要9天才能全部看完。",
+        "knowledge_points":  [
+                                 "有余数除法的实际应用"
+                             ],
+        "source":  "24-25 二年级下·湖北恩施·期末"
+    },
+    {
+        "id":  "78",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "32名游客要划船，如果都坐大船，至少需要几条。\n![](images/110819.png)",
+        "options":  [
+
+                    ],
+        "answer":  "6条",
+        "solution":  "【分析】由题意可知：用游客的总人数除以每条大船限乘的人数，求出的商即是坐满大船的条数，余数是剩下的人数，剩下的人需要再增加1条大船，因此总需要船数为商+1条。据此解答。\n\n【详解】由分析可得:32÷6=5(条)。2(人),5+1=6(条)。答：至少需要6条。",
+        "knowledge_points":  [
+                                 "有余数除法的实际应用",
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "24-25二年级下·甘肃庆阳·期末"
+    },
+    {
+        "id":  "79",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "学校买来56个足球。\n(1)装在7个箱子里，平均每箱装多少个。\n(2)装在9个箱子里，平均每箱装多少个。还剩多少个。",
+        "options":  [
+
+                    ],
+        "answer":  "8;6;2",
+        "solution":  "【分析】(1)用买来足球的总个数除以装的箱子数，即可求出平均每箱装多少个;(2)用买来足球的总个数除以装的箱子数，商就是平均每箱装多少个，余数就是还剩多少个。\n\n【详解】(1)56÷7=8(个)。答：平均每箱装8个。\n(2)56÷9=6(个)……2(个)。答：平均每箱装6个，还剩2个。",
+        "knowledge_points":  [
+                                 "用7~9的乘法口诀求商",
+                                 "100以内有余数的除法计算",
+                                 "有余数除法的实际应用"
+                             ],
+        "source":  "24-25 二年级下·山东菏泽·期末"
+    },
+    {
+        "id":  "80",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "端午节妈妈包了22个粽子，每4个绑成一串，最多可以绑成多少串。还剩多少个。答：最多绑成( )串，还剩下( )个。",
+        "options":  [
+
+                    ],
+        "answer":  "5;2",
+        "solution":  "【分析】由题意可知：用妈妈包的粽子数除以每串的个数，求出的商即是串数，余数是剩余的个数;据此解答。\n\n【详解】由分析可得:22÷4=5(串)……2(个)。答：最多可以绑成5串，还剩2个。",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算",
+                                 "有余数除法的实际应用"
+                             ],
+        "source":  "24-25 二年级下·广东潮州·期末"
+    },
+    {
+        "id":  "81",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "在人工智能展览会上，有一场无人机表演，主办方要把50架无人机运往会场，每8架装一箱，至少需要多少个箱子。",
+        "options":  [
+
+                    ],
+        "answer":  "7个",
+        "solution":  "【分析】要求至少需要多少个箱子，根据除法的意义，用50÷8进行解答即可，若没有余数，则商就是需要的箱子数量，若有余数，则表示剩余的无人机数量，还需要用1个箱子来装。\n\n【详解】50÷8=6(个)。2(架),6+1=7(个)。答：至少需要7个箱子。",
+        "knowledge_points":  [
+                                 "有余数除法的实际应用"
+                             ],
+        "source":  "24-25 二年级下·广东汕头·期末"
+    },
+    {
+        "id":  "82",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "森林里要举办盛大的动物派对啦!小动物们都要穿上漂亮的新衣服去参加。小兔子负责设计小伙伴们的服饰，它发现钉一件服饰需要5粒像宝石一样的小纽扣，盒子里还剩42粒纽扣，它最多能钉几件漂亮的服饰呢。",
+        "options":  [
+
+                    ],
+        "answer":  "8件",
+        "solution":  "【分析】用纽扣的总数除以每件衣服需要钉的纽扣数量，算出的商就是最多能钉的衣服件数，若有余数，余数则表示剩下的纽扣数量。\n\n【详解】42÷5=8(件)。2(颗)。答：它最多能钉8件漂亮的服饰。",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "24-25 二年级下·贵州铜仁·期末"
+    },
+    {
+        "id":  "83",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "一根铁丝长60厘米。工人师傅用8厘米长的铁丝做一个铁钩，这根铁丝一共可以做几个这样的铁钩。还剩下多少厘米。\n答：一共可以做( )个这样的铁钩，还剩下( )厘米。",
+        "options":  [
+
+                    ],
+        "answer":  "7;4",
+        "solution":  "【分析】要求60厘米长的铁丝可以做几个8厘米的铁钩，即求60里面有几个8，根据除法的意义，用60÷8进行解答即可。商就是可以做的铁钩数量，余数就是剩下的铁丝的长度。\n\n【详解】60÷8=7(个)……4(厘米)。答：一共可以做7个这样的铁钩，还剩下4厘米。",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算",
+                                 "有余数除法的实际应用"
+                             ],
+        "source":  "24-25 二年级下·广东江门·期末"
+    },
+    {
+        "id":  "84",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "文学社的同学们最近都在读同一本故事书。小红3天读了24页，剩下的如果每天读9页，正好再读7天读完。\n(1)这本故事书一共有多少页。\n(2)如果小玲每天都读9页，那么她至少需要多少天才能读完这本故事书。",
+        "options":  [
+
+                    ],
+        "answer":  "87页;10天",
+        "solution":  "【分析】(1)已知读了24页，剩下的如果每天读9页，正好再读7天读完，即求7个9的和是多少，根据乘法的意义，用9×7先算出还剩多少页没读，再加上已经读的24页，即可得出这本故事书一共有多少页。(2)用这本书的总页数除以9进行解答即可，若没有余数，则商是几就需要几天，若有余数，则还需要再加上1天，将剩下的页数读完。\n\n【详解】(1)9×7+24=63+24=87(页)。答：这本故事书一共有87页。(2)87÷9=9(天)……6(页)，9+1=10(天)。答：她至少需要10天才能读完这本故事书。",
+        "knowledge_points":  [
+                                 "有余数除法的实际应用",
+                                 "乘加",
+                                 "乘减混合运算"
+                             ],
+        "source":  "24-25 二年级下·四川成都·期末"
+    },
+    {
+        "id":  "85",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "松鼠妈妈有33个松果，平均分给6只小松鼠，每只小松鼠分几个。还剩几个。",
+        "options":  [
+
+                    ],
+        "answer":  "5个;3个",
+        "solution":  "【分析】用松鼠妈妈有的松果数，除以分给的小松鼠只数，求出的商即是每只小松鼠分的个数;余数是还剩的个数;据此解答。\n\n【详解】由分析可得:33÷6=5(个)……3(个)。答：每只小松鼠分5个，还剩3个。",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算",
+                                 "有余数除法的实际应用"
+                             ],
+        "source":  "24-25 二年级下·四川南充·期末"
+    },
+    {
+        "id":  "86",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "假期期间，华华和妈妈一起跟随旅行团去旅游。旅行团一共有25人，他们一起乘车去机场.\n(1)如果都坐大车，至少需要几辆车。如果都坐小车，至少需要几辆车。\n(2)如果大车，小车可以搭配乘车，请给出一种合理的乘车方案.\n![](images/92afc08c8ab722ac9397fa6477cdf832.png)",
+        "options":  [
+
+                    ],
+        "answer":  "4辆;7辆;可以安排3辆大车和1辆小车",
+        "solution":  "【分析】(1)根据题意可知：用共有的人数分别除以大车和小车各限乘的人数，求出商和余数，商为需要的辆数，余数为剩余的人数，剩余的人数也需要坐车，则需要的辆数再加1即可。(2)可以尝试不同数量的大车和小车，使乘坐的人数刚好满足或超过总人数即可(任选一种方案即可)。可以先安排大车，当25人都坐大车时，看需要多少辆，还剩多少人，再将剩余的人安排坐小车即可。\n\n【详解】(1)25÷7=3(辆)……4(人)，3+1=4(辆);25÷4=6(辆)……1(人)，6+1=7(辆)。答：都坐大车，至少需要4辆车;如果都坐小车，至少需要7辆车。(2)25÷7=3(辆)……4(人)。答：可以安排3辆大车和1辆小车。",
+        "knowledge_points":  [
+                                 "有余数除法的实际应用",
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "24-25 二年级下·山西阳泉·期末"
+    },
+    {
+        "id":  "87",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "妈妈买了15个苹果，吃了5个，剩下的苹果平均放在3个盘子里，每个盘子里放几个。还剩几个。",
+        "options":  [
+
+                    ],
+        "answer":  "3个;1个",
+        "solution":  "【分析】根据题意可知：用妈妈买的数量减去吃的数量求出剩下的数量，然后用剩下的数量除以盘子的个数，求出商和余数，商为每个盘子里放的数量，余数为还剩下的苹果数量。\n\n【详解】15-5=10(个)，10÷3=3(个)……1(个)。答：每个盘子里放3个，还剩1个。",
+        "knowledge_points":  [
+                                 "整数平均分的意义及应用",
+                                 "用2~5的乘法口诀求商",
+                                 "有余数除法的实际应用"
+                             ],
+        "source":  "25-26 二年级上·黑龙江鹤岗·开学考试"
+    },
+    {
+        "id":  "88",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "有38个苹果，每6个装一袋，可以装几袋。还剩几个。",
+        "options":  [
+
+                    ],
+        "answer":  "6袋;2个",
+        "solution":  "【分析】根据题意可知，38个苹果，每6个装一袋，求可以装几袋，就是求38里面有几个6，用除法计算;据此解答。\n\n【详解】38÷6=6(袋)……2(个)。答：可以装6袋，还剩下2个。",
+        "knowledge_points":  [
+                                 "有余数除法的实际应用"
+                             ],
+        "source":  "25-26 三年级上·黑龙江佳木斯·开学考试"
+    },
+    {
+        "id":  "89",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "同学们想去参观植物园，每张门票6元，50元最多能买几张票。",
+        "options":  [
+
+                    ],
+        "answer":  "8张",
+        "solution":  "【分析】根据题意可知：用钱数除以每张门票的钱数，求出商和余数，商为可买的票数，余数为剩余的钱数，剩余的钱数小于门票钱，则舍弃，据此即可解答。\n\n【详解】50÷6=8(张)……2(元)。答：最多买8张。",
+        "knowledge_points":  [
+                                 "有余数除法的实际应用"
+                             ],
+        "source":  "24-25二年级下·山东菏泽·期末"
+    },
+    {
+        "id":  "90",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "假期安全，从不玩水做起。为了提高同学们的安全意识，老师带领学生们到多媒体教室观看防溺水宣传片。多媒体教室一排最多坐8人，那么二(1)班38个学生最少需要坐几排。",
+        "options":  [
+
+                    ],
+        "answer":  "5排",
+        "solution":  "【分析】根据题意可知，二(1)班学生的总人数除以每排坐的人数，求出结果，若没有余数，商就是最少需要坐几排;若有余数，剩下的人还需要1排，用商加1即是最少需要坐几排。\n\n【详解】38÷8=4(排)……6(人)，4+1=5(排)。答：二(1)班38个学生最少需要坐5排。",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算",
+                                 "有余数除法的实际应用"
+                             ],
+        "source":  "24-25 二年级下·湖北武汉·期末"
+    },
+    {
+        "id":  "91",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "水果店装水果拼盘，现在有20个苹果,22个橘子,36个桃子，要求每个拼盘里面放4个苹果,3个橘子,6个桃子，那么这些水果最多可以放几个水果拼盘。",
+        "options":  [
+
+                    ],
+        "answer":  "5个",
+        "solution":  "【分析】用苹果的总数量除以每个拼盘里面放的苹果数量，求出结果，商表示苹果可以放满几个拼盘;用橘子的总数量除以每个拼盘里面放的橘子数量，求出结果，商表示橘子可以放满几个拼盘;用桃子的总数量除以每个拼盘里面放的桃子数量，求出结果，商表示桃子可以放满几个拼盘;然后比较3个商的大小，最小的商表示最多可以放几个水果拼盘。\n\n【详解】20÷4=5(个);22÷3=7(个)……1(个);36÷6=6(个)。因为5\u003c6\u003c7，所以这些水果最多可以放5个水果拼盘。",
+        "knowledge_points":  [
+                                 "用2~5的乘法口诀求商",
+                                 "用6的乘法口诀求商",
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "24-25 二年级下·浙江杭州·期末"
+    },
+    {
+        "id":  "92",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "面包店做了54个蛋黄酥。\n(1)每个纸盒可以装8个蛋黄酥，至少需要多少个盒子。\n(2)每个蛋黄酥8元，50元最多能买几个蛋黄酥。",
+        "options":  [
+
+                    ],
+        "answer":  "7;6",
+        "solution":  "【分析】(1)用蛋黄酥的总个数除以每个纸盒可以装蛋黄酥的个数，商就是至少需要多少个盒子，若有余数，剩下的蛋黄酥再装1个盒子;(2)用蛋黄酥的总钱数除以每个蛋黄酥的钱数，商就是最多能买几个蛋黄酥。\n\n【详解】(1)54÷8=6(个)……6(个)，6+1=7(个)。答：至少需要7个盒子。(2)50÷8=6(个)……2(元)。答：50元最多能买6个蛋黄酥。",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算",
+                                 "有余数除法的实际应用"
+                             ],
+        "source":  "24-25 二年级下·浙江杭州·期末"
+    },
+    {
+        "id":  "93",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "4名老师带着15名学生去划船，每条船限坐6人，至少要租几条船。",
+        "options":  [
+
+                    ],
+        "answer":  "4条",
+        "solution":  "【分析】用去划船的总人数除以每条船限坐的人数，商就是至少要租几条船，若有余数，余下的人还要再租1条船，据此解答。\n\n【详解】15+4=19(名)，19÷6=3(条)……1(人)，3+1=4(条)。答：至少要租4条船。",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算",
+                                 "有余数除法的实际应用"
+                             ],
+        "source":  "24-25 二年级下·江西九江·期末"
+    },
+    {
+        "id":  "94",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "一根长跳绳7米，用39米的绳子，最多可以做几根长跳绳。",
+        "options":  [
+
+                    ],
+        "answer":  "5根",
+        "solution":  "【分析】由题意可知：用绳子的总长除以一根跳绳的长度，求出的商即是最多可以做跳绳的根数;据此解答。\n\n【详解】由分析可得:39÷7=5(根)……4(米)。答：最多可以做5根长跳绳。",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算",
+                                 "有余数除法的实际应用"
+                             ],
+        "source":  "24-25 二年级下·江西赣州·期末"
+    },
+    {
+        "id":  "95",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "妈妈带了80元钱，去超市买了9元一个的粽子，能买几个，还剩多少元。",
+        "options":  [
+
+                    ],
+        "answer":  "8个;8元",
+        "solution":  "【分析】用妈妈带的总钱数除以一个粽子的钱数，求出商和余数，商表示能买几个，余数表示还剩的钱数。\n\n【详解】80÷9=8(个)……8(元)。答：能买8个，还剩8元。",
+        "knowledge_points":  [
+                                 "有余数除法的实际应用"
+                             ],
+        "source":  "24-25 二年级下·湖南张家界·期末"
+    },
+    {
+        "id":  "96",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "学校将要组织去琵琶洲进行研学活动，二年级二班学生有28人和老师有3人，租限坐4人的出租车，至少要租几辆车。",
+        "options":  [
+
+                    ],
+        "answer":  "8辆",
+        "solution":  "【分析】用总人数(学生人数加老师人数)除以每辆出租车限坐人数，求出结果，结果若没有余数，商就是至少要租的出租车数量;若有余数，商加1求出的和就是至少要租的出租车数量。\n\n【详解】28+3=31(人)，31÷4=7(辆)……3(人)，7+1=8(辆)。答：至少要租8辆。",
+        "knowledge_points":  [
+                                 "一位数与两位数的进位加法",
+                                 "100以内有余数的除法计算",
+                                 "有余数除法的实际应用"
+                             ],
+        "source":  "24-25 二年级下·湖南张家界·期末"
+    },
+    {
+        "id":  "97",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "二(1)班有男生25人，女生20人，全班一起去公园划船，每条船限坐6人，至少需要租几条船。",
+        "options":  [
+
+                    ],
+        "answer":  "8条",
+        "solution":  "【分析】根据题意可先用加法计算出这个班的总人数，然后用总人数除以每条船限乘的人数，得到的商就是坐满船的条数，余数表示剩下的人数，然后再用坐满船的条数加1条，即可得到需要船的条数，依此计算。\n\n【详解】25+20=45(人)，45÷6=7(条)……3(人)，7+1=8(条)。答：至少需要租8条船。",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算",
+                                 "有余数除法的实际应用"
+                             ],
+        "source":  "25-26 三年级上·黑龙江鹤岗·开学考试"
+    },
+    {
+        "id":  "98",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "明明借了一本75页的漫画书，每天看8页，他至少需要多少天才能全部看完呢。",
+        "options":  [
+
+                    ],
+        "answer":  "10天",
+        "solution":  "【分析】根据题意可知：用漫画书的页数除以每天看的页数，求出商和余数，商为需要的天数，余数为剩余的页数。剩余的页数也需要看完，则需要的天数再加上1。\n\n【详解】75÷8=9(天)……3(页)，9+1=10(天)。答：他至少需要10天才能全部看完。",
+        "knowledge_points":  [
+                                 "有余数除法的实际应用"
+                             ],
+        "source":  "24-25 二年级下·湖北黄冈·期末"
+    },
+    {
+        "id":  "99",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "一间房子最多住6只小兔，40只小兔至少需要住几间房子。",
+        "options":  [
+
+                    ],
+        "answer":  "7间",
+        "solution":  "【分析】根据题意，用小兔的总只数除以一间房子最多住小兔的只数，商就是需要住几间房子，若有余数，剩下的小兔还要再加1间房子，据此解答。\n\n【详解】40÷6=6(间)……4(只)，6+1=7(间)。答：40只小兔至少需要住7间房子。",
+        "knowledge_points":  [
+                                 "有余数除法的实际应用",
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "24-25二年级下·江西赣州·期末"
+    },
+    {
+        "id":  "100",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "许老师拿50元钱买跳绳，他最多可以买几根跳绳。还剩多少钱。\n![](images/8ee7a2591abe0ab6efa0fa82f4ef0ff906ea61a4f0ad28b6cf4c5b1e4115b0fa.jpg)",
+        "options":  [
+
+                    ],
+        "answer":  "6根;2元",
+        "solution":  "【分析】根据题意，许老师拿的钱数÷每根跳绳的钱数=可以买跳绳的数量，余数表示剩余的钱数。\n\n【详解】50÷8=6(根)……2(元)。答：他最多可以买6根跳绳，还剩2元钱。",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算",
+                                 "有余数除法的实际应用"
+                             ],
+        "source":  "24-25 二年级下·江西赣州·期末"
+    },
+    {
+        "id":  "101",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "有三种笔记本，价格最贵的是( )。",
+        "options":  [
+                        "A. 12元3本",
+                        "B. 4元一本",
+                        "C. 17元4本"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】平均每本笔记本的单价=总钱数÷买的本数，由此算出每本笔记本的单价，找出价格最贵的选项即可解答。\n\n【详解】A. 12÷3=4(元)，4元一本;B. 4元一本;C. 17÷4=4(元)……1(元)。由此可知，A和B选项的笔记本都是4元一本，C选项的笔记本比4元一本还贵一些。故答案为:C",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算",
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "24-25二年级下·浙江台州·期末"
+    },
+    {
+        "id":  "102",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "下面算式中余数是4的是( )。",
+        "options":  [
+                        "A. 27÷4",
+                        "B. 58÷7",
+                        "C. 40÷6"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】有余数的除法算式为：被除数÷除数=商……余数，依次计算出各算式的结果，找到余数是4的即可。\n\n【详解】A. 27÷4=6……3，余数是3，不符合题意;B. 58÷7=8……2，余数是2，不符合题意;C. 40÷6=6……4，余数是4，符合题意。则余数是4的算式是40÷6。故答案为:C",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "24-25 二年级下·广东潮州·期末"
+    },
+    {
+        "id":  "103",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "把40颗糖平均分给小朋友，每个小朋友分7颗。下面竖式中框出的部分所指的数表示( )。\n![](images/7a2737a3e3bdd7a22fb9b9e4471c265bee45c5b3f0669b2ded30ee106c575a78.jpg)",
+        "options":  [
+                        "A. 一共有35颗糖",
+                        "B. 分掉了35颗糖",
+                        "C. 还剩下35颗糖"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】有余数的除法的计算方法：一商，二乘，三减，四比。(1)商：即试商，想除数和几相乘最接近被除数且小于被除数，那么商就是几，写在被除数的个位的上面;(2)乘：把除数和商相乘，将得数写在被除数下面;(3)减：用被除数减去商与除数的乘积，所得的差写在横线的下面;(4)比：将余数与除数比一比，余数必须比除数小。由此判断每个位置的数代表的意义即可解答。\n\n【详解】用竖式计算40÷7时，个位上商5,5×7=35，表示：分掉了35颗糖。故答案为:B",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "24-25 二年级下·浙江台州·期末"
+    },
+    {
+        "id":  "104",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "□÷7=8……□，被除数最大是( )。",
+        "options":  [
+                        "A. 56",
+                        "B. 62",
+                        "C. 64",
+                        "D. 72"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】在有余数的除法中，余数最大=除数-1;余数最大时，被除数最大，此时，被除数=商×除数+余数。\n\n【详解】余数最大是:7-1=6，8×7+6=56+6=62。□÷7=8……□，被除数最大是62。故答案为:B",
+        "knowledge_points":  [
+                                 "余数与除数的关系",
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "24-25 二年级下·浙江湖州·期末"
+    },
+    {
+        "id":  "105",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "二(1)班准备了一些矿泉水免费分发给环卫工人，瓶数比30多，比45少，正好能平均分给6人，如果去掉一瓶，正好可以平均分给5人，这些矿泉水可能有( )瓶。",
+        "options":  [
+                        "A. 36",
+                        "B. 38",
+                        "C. 42"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】根据题意，矿泉水的总数量÷6，看能不能正好平均分给6人;去掉1瓶后，再用剩下的数量÷5，看能不能正好平均分给5人。逐项分析各个选项，找出正确答案即可。\n\n【详解】A. 36÷6=6(瓶)，正好能平均分给6人;36÷5=7(瓶)……1(瓶)，去掉1瓶，正好平均分给5人，符合题意。B. 38÷6=6(瓶)……2(瓶)，不能平均分给6人，不符合题意;38÷5=7(瓶)……3(瓶)，去掉1瓶后也不能正好平均分给5人。C. 42÷6=7(瓶)，正好平均分给6人;42÷5=8(瓶)……2(瓶)，去掉1瓶后不能正好平均分给5人，不符合题意。因此，这些矿泉水可能有36瓶。故答案为:A",
+        "knowledge_points":  [
+                                 "用6的乘法口诀求商",
+                                 "用7~9的乘法口诀求商",
+                                 "有余数除法的试商",
+                                 "有余数除法的实际应用"
+                             ],
+        "source":  "24-25二年级下·福建厦门·期末"
+    },
+    {
+        "id":  "106",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "○÷△=8……6，△最小是( )。",
+        "options":  [
+                        "A. 5",
+                        "B. 7",
+                        "C. 8"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】有余数的除法算式为：被除数÷除数=商……余数，其中余数一定小于除数，除数最小是比余数大1的数，由此解答。\n\n【详解】6+1=7，则○÷△=8……6，△最小是7。故答案为:B",
+        "knowledge_points":  [
+                                 "余数与除数的关系"
+                             ],
+        "source":  "24-25二年级下·江西赣州·期末"
+    },
+    {
+        "id":  "107",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "当余数是5时，除数最小是( )。",
+        "options":  [
+                        "A. 4",
+                        "B. 5",
+                        "C. 6"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】在除法运算中，余数必须小于除数，当余数是5时，除数必须大于5，除数最小是比5大1的数，据此解答。\n\n【详解】5+1=6，当余数是5时，除数最小是6。故答案为:C",
+        "knowledge_points":  [
+                                 "余数与除数的关系"
+                             ],
+        "source":  "24-25 二年级下·湖北孝感·期末"
+    },
+    {
+        "id":  "108",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "拼一个独立的正方形需要4根小棒，用27根小棒可以拼出几个独立的正方形。还剩几根小棒。下面竖式中的\"24\"表示的是( ).\n![](images/112152.png)",
+        "options":  [
+                        "A. 一共有24根小棒",
+                        "B. 拼了24个独立的正方形",
+                        "C. 拼6个独立的正方形用了24根小棒"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】根据除法竖式的意义，竖式中的27是被除数，表示一共有27根小棒，4是除数，表示每个独立的正方形需要4根小棒，6是商，表示可以拼出几个独立的正方形，3是余数，表示还剩几根小棒，24是4和6的乘积，表示拼出6个独立的正方形一共用了24根小棒，据此解答。\n\n【详解】A. 一共有24根小棒，由分析可知，被除数是27，表示一共有27根小棒，不符合题意;B. 拼了24个独立的正方形，由分析可知，商是6，表示拼了6个独立的正方形，不符合题意;C. 拼6个独立的正方形用了24根小棒，符合题意。故答案为:C",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算",
+                                 "有余数除法的实际应用"
+                             ],
+        "source":  "24-25 二年级下·河南郑州·期末"
+    },
+    {
+        "id":  "109",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "一堆橡皮的数量在20块和30块之间，把它们平均分给4个小朋友还剩下3块，这堆橡皮的数量可能是( )块。",
+        "options":  [
+                        "A. 23",
+                        "B. 27",
+                        "C. 23或27"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】先逐个判断选项中的数是否在20和30之间，再分别除以4，找出平均分给4个小朋友后还剩3块的数。因为橡皮的数量未确定，所以需要找出包含所有可能性的选项，据此即可解答。\n\n【详解】A. 23在20和30之间，23÷4=5……3，所以23块橡皮平均分给4个小朋友后还剩3块，但可能性未列全，不选;B. 27在20和30之间，27÷4=6……3，所以27块橡皮平均分给4个小朋友后还剩3块，但可能性未列全，不选;C. 根据前两个选项可知，橡皮的数量可以是23块或27块，列出了所有可能性，当选。故答案为:C",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "24-25二年级下·甘肃兰州·期末"
+    },
+    {
+        "id":  "110",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "有45根跳绳，至少再添( )根，才能平均分给6个班级。",
+        "options":  [
+                        "A. 2",
+                        "B. 3",
+                        "C. 4"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】根据题意可知，用跳绳的总根数除以平均分给班级的个数，求出结果，再用6减去余数，即最少再添多少根跳绳，才能平均分给6个班，据此解答。\n\n【详解】根据分析可得:45÷6=7(根)……3(根)，6-3=3(根)。因此，有45根跳绳，至少再添3根，才能平均分给6个班级。故答案为:B",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算",
+                                 "有余数除法的实际应用"
+                             ],
+        "source":  "24-25 二年级下·贵州黔东南·期末"
+    },
+    {
+        "id":  "111",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "月月有42元，她买下面的一种笔正好把钱花完，她买的是哪一种笔。( )。",
+        "options":  [
+                        "A. ![](images/d2e28e2947a0bf83dbc05dd4c692019f155d94ef661b637e72d1c36564eb5966.jpg) 每支7元",
+                        "B. ![](images/51ef473d18adfd6fab8e0d6c1726c0ae515ed670df218db808c5992da72a9cab.jpg) 每支8元",
+                        "C. ![](images/4f83184d14cb17b8af3c6b0156291798fad6fbec7a2c5ce66dcbdcb87b97ff85.jpg) 每支9元"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】用月月带的钱除以每支笔的价钱，哪个没有余数，就正好把钱花完，就选哪种笔。\n\n【详解】A. 42÷7=6(支)，正好把钱花完;B. 42÷8=5(支)……2(元)，还剩2元;C. 42÷9=4(支)……6(元)，还剩6元。买每支7元的笔正好把钱花完。故答案为:A",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算",
+                                 "用7~9的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·湖北孝感·期中"
+    },
+    {
+        "id":  "112",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "甜品店有32个面包，每( )个装一袋，正好装完。",
+        "options":  [
+                        "A. 4",
+                        "B. 6",
+                        "C. 9"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】根据除法的意义，用面包的总个数÷每袋装的个数=装的袋数，用32分别除以三个选项，看哪个选项正好能整除，没有余数，就是这个题的答案。\n\n【详解】A. 32÷4=8(袋)，每4个装一袋，正好装完，符合题意;B. 32÷6=5(袋)……2(个)，每6个装一袋，不能正好装完，不符合题意;C. 32÷9=3(袋)……5(个)，每9个装一袋，不能正好装完，不符合题意。故答案为:A",
+        "knowledge_points":  [
+                                 "用7~9的乘法口诀求商",
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "24-25 二年级下·河南周口·期中"
+    },
+    {
+        "id":  "113",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "用3根小棒可以摆一个△，19根小棒最多可以摆( )个这样的△。",
+        "options":  [
+                        "A. 5",
+                        "B. 6",
+                        "C. 7"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】由题意可知：用总根数除以摆一个△的根数，求出的商即是△的个数;据此解答。\n\n【详解】由分析可得:19÷3=6(个)……1(根)，19根小棒最多可以摆6个这样的△。故答案为:B",
+        "knowledge_points":  [
+                                 "有余数除法的实际应用",
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "24-25二年级下·广西贵港·期中"
+    },
+    {
+        "id":  "114",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "学校体检中，小瓦排在第21位，医生每次只让进去4名同学，小瓦第( )次才能轮到体检。",
+        "options":  [
+                        "A. 5",
+                        "B. 6",
+                        "C. 7"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】小瓦排在第21位，每次进4人，求他第几次被轮到。用除法计算21÷4，商为5，余1，说明前5次共进20人，剩下的第21位需在第6次进入。\n\n【详解】21÷4=5(次)……1(位)，5+1=6(次)。小瓦第6次才能轮到体检。故答案为:B",
+        "knowledge_points":  [
+                                 "有余数除法的实际应用"
+                             ],
+        "source":  "24-25 二年级下·广东云浮·期中"
+    },
+    {
+        "id":  "115",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "下面算式中，计算正确的是( )。",
+        "options":  [
+                        "A. 42÷6=6……6",
+                        "B. 48÷8=8",
+                        "C. 73÷9=8……1"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】有余数的除法中，余数必须比除数小。根据乘法口诀先求出商，再判断各算式是否正确即可。\n\n【详解】A. 42÷6=7，不是6……6;B. 48÷8=6，不是8;C. 73÷9=8……1，计算正确。故答案为:C",
+        "knowledge_points":  [
+                                 "用7~9的乘法口诀求商",
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "24-25 二年级下·广东云浮·期中"
+    },
+    {
+        "id":  "116",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "有一堆糖，将它平均分成9份，刚好全部分完。这堆糖可能有( )颗。",
+        "options":  [
+                        "A. 26",
+                        "B. 36",
+                        "C. 46"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】根据题意，有一堆糖，将它平均分成9份，刚好全部分完，说明用一堆糖的总数量除以9，商正好是整数，没有余数，分别用三个选项除以9，找出没有余数的那个答案即可。\n\n【详解】A。 26÷9=2。8，不能全部分完，不符合题意;B. 36÷9=4，刚好全部分完，符合题意;C. 46÷9=5。1，不能全部分完，不符合题意;有一堆糖，将它平均分成9份，刚好全部分完，这堆糖可能有36颗。故答案为:B",
+        "knowledge_points":  [
+                                 "用7~9的乘法口诀求商",
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "24-25 二年级下·福建漳州·期中"
+    },
+    {
+        "id":  "117",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "与47÷9的余数相等的式子是( )。",
+        "options":  [
+                        "A. 66÷8",
+                        "B. 17÷4",
+                        "C. 40÷6"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】计算出算式的结果再选择即可;笔算两位数除以位数时，要从最高位除起，除到被除数的哪一位，就把商写在那一位的上面。\n\n【详解】47÷9=5。2，余数为2;A. 66÷8=8。2，余数为2;B. 17÷4=4。1，余数为1;C. 40÷6=6。4，余数为4;综上所述，与47÷9的余数相等的式子是66÷8。故答案为:A",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "24-25二年级下·湖北黄冈·期末"
+    },
+    {
+        "id":  "118",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "王老师带36个同学去划船，每条船可以坐6个人，至少需要( )条船。",
+        "options":  [
+                        "A. 5",
+                        "B. 6",
+                        "C. 7"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】由题意可知：用同学的人数加王老师1人，即是去划船的总人数，用划船的总人数除以每条船可以坐的人数，算出的商即是坐满船的条数，余数是剩余的人数，剩余的人数还需1条船，故至少需要商+1条船;据此解答。\n\n【详解】由分析可得:(36+1)÷6=37÷6=6(条)。1(人),6+1=7(条)。至少需要7条船。故答案为:C",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算",
+                                 "有余数除法的实际应用",
+                                 "带有小括号的混合运算"
+                             ],
+        "source":  "24-25二年级下·山东济南·期末"
+    },
+    {
+        "id":  "119",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "乐乐有21元钱，一本笔记本4元，他最多能买几本这样的笔记本。关于竖式中圈起来的部分。下面说法正确的是( ).\n![](images/494f8ebc5385bcd63f7b8a00281be4bb32b94c27d8878a96c8febe38650ed2b9.jpg)",
+        "options":  [
+                        "A. 乐乐有20元",
+                        "B. 买4本笔记本花去20元",
+                        "C. 买5本笔记本花去20元"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】根据除法竖式的意义，竖式中的21是被除数，表示乐乐有21元钱,4是除数，表示一本笔记本4元,5是商，表示可以买几本笔记本,1是余数，表示乐乐还剩的钱数,20是4和5的乘积，表示一本笔记本4元，买了5本笔记本共花去20元，据此解答。\n\n【详解】由分析可得：竖式中圈起来的数20表示买5本笔记本花去20元。故答案为:C",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "24-25二年级下·山东济南·期末"
+    },
+    {
+        "id":  "120",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "一盒潮州酥饺售价8元，小亮有30元，最多买( )盒。",
+        "options":  [
+                        "A. 3",
+                        "B. 4",
+                        "C. 5"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】用小亮的总钱数除以平均每盒的单价，求出商和余数，商表示最多可以买的盒数，余数是还剩下的钱数。\n\n【详解】30÷8=3(盒)。6(元)。即，一盒潮州酥饺售价8元，小亮有30元，最多买3盒。故答案为:A",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算",
+                                 "有余数除法的实际应用"
+                             ],
+        "source":  "24-25二年级下·广东潮州·期末"
+    },
+    {
+        "id":  "121",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "一罐糖果有17颗，平均分给三个小朋友，下面竖式箭头所指的数表示的是( ).\n![](images/692dee2194468d0656a36c9b83c6aa8c8467b9b58c783bc4d37fb4cdd453944c.jpg)",
+        "options":  [
+                        "A. 要分的15颗糖果",
+                        "B. 分走了15颗糖果",
+                        "C. 还剩15颗糖果"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】根据除法竖式的意义，竖式中的17是被除数，表示一罐糖果有17颗,3是除数，表示要平均分给三个小朋友,5是商，表示每人分几颗,2是余数，表示还剩糖果的颗数,15是3和5的乘积，表示平均分给三个小朋友，每人分5颗，一共分走了15颗糖果，据此解答。\n\n【详解】由分析可得：竖式中箭头所指的数15表示的是分走了15颗糖果。故答案为:B",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "24-25二年级下·福建福州·期末"
+    },
+    {
+        "id":  "122",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "丽丽要把24件礼物平均装进几个相同的盒子里，且每个盒子都要装满，选( )项盒子刚好装完最合适。",
+        "options":  [
+                        "A. 每盒装5件",
+                        "B. 每盒装6件",
+                        "C. 每盒装7件"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】由题意可知：用24分别除以各项中每盒的件数，没有余数的即是最合适的;据此解答。\n\n【详解】由分析可得:A. 每盒装5件:24÷5=4(盒)。4(件),不符合题意;B. 每盒装6件:24÷6=4(盒),符合题意;C. 每盒装7件:24÷7=3(盒)。3(件),不符合题意。选每盒装6件刚好装完。故答案为:B",
+        "knowledge_points":  [
+                                 "用6的乘法口诀求商",
+                                 "100以内有余数的除法计算",
+                                 "有余数除法的实际应用"
+                             ],
+        "source":  "24-25 二年级下·山东济南·期末"
+    },
+    {
+        "id":  "123",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "下面的计算正确的是( )。",
+        "options":  [
+                        "A. 48÷6=7。6",
+                        "B. 35÷7=4。7",
+                        "C. 49÷7=7"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】在有余数的除法中，余数总比除数小;除法根据乘法口诀即可解答。\n\n【详解】A。 48÷6=7。6,6=6，余数和除数相等，则不符合题意。B。 35÷7=4。7,7=7，余数和除数相等，则不符合题意。C。 49÷7=7，运用七七四十九即可求出商，则符合题意。计算正确的是49÷7=7。故答案为:C",
+        "knowledge_points":  [
+                                 "用7~9的乘法口诀求商",
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "24-25 二年级下·黑龙江佳木斯·期末"
+    },
+    {
+        "id":  "124",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "用4个苹果,3个梨和2个橘子可以拼成一个果盘。现在有21个苹果,20个梨和15个橘子，最多可以拼成( )个果盘。",
+        "options":  [
+                        "A. 5",
+                        "B. 6",
+                        "C. 7"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】分别用每种水果的总数除以果盘里放的个数，找出商最小的，据此即可解答。\n\n【详解】21÷4=5(个)……1(个);20÷3=6(个)……2(个);15÷2=7(个)……1(个)。因为5\u003c6\u003c7，所以最多可以拼成5个果盘。故答案为:A",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "24-25 二年级下·甘肃天水·期末"
+    },
+    {
+        "id":  "125",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "按规律排列:△□○△□○。第26个是( )。",
+        "options":  [
+                        "A. △",
+                        "B. ○",
+                        "C. □"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】这组图形按照△□○的顺序循环排列，一组3个;用除法算出26个里面有这样的几组，若没有余数，就是这组中的最后一个图形，若有余数，余数是几就是下一组中的第几个图形。\n\n【详解】根据分析可得:26÷3=8(组)……2(个)，余数是2，就是第9组中的第2个图形，即□。按规律排列:△□○△□○。第26个是□。故答案为:C",
+        "knowledge_points":  [
+                                 "间隔问题",
+                                 "100以内有余数的除法计算",
+                                 "有余数除法的实际应用"
+                             ],
+        "source":  "24-25二年级下·黑龙江佳木斯·期末"
+    },
+    {
+        "id":  "126",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "□△○☆□△○☆□△○☆。按照样子排下去，第37个图形是( )。",
+        "options":  [
+                        "A. □",
+                        "B. △",
+                        "C. ○",
+                        "D. ☆"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】图形按\"□△○☆\"4个为一组循环排列。求第37个图形，用37除以4，求出商和余数，余数是几，第37个图形就对应一组中的第几个。\n\n【详解】37÷4=9(组)……1(个)，余数1对应一组中的第1个图形\"□\"，因此，第37个图形是□。故答案为:A",
+        "knowledge_points":  [
+                                 "周期问题",
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "24-25二年级下·广东揭阳·期末"
+    },
+    {
+        "id":  "127",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "按●●●○○●●●○○●●●○○的顺序排列，第19个图形是( )色，第28个图形是( )色。",
+        "options":  [
+
+                    ],
+        "answer":  "白;黑",
+        "solution":  "【分析】根据图示，每组以3个黑圆、2个白圆共5个图形排列。用除法计算出第19个图形和第28个图形的位置，有余数时余数是几就是每组的第几个，没有余数则是一组中的最后一个，从而判断颜色。\n\n【详解】由分析可得:3+2=5(个);19÷5=3(组)……4(个)，则余数是4，为每组的第4个图形，颜色是白;28÷5=5(组)……3(个)，则余数是3，为每组的第3个图形，颜色是黑。由此可知：按●●●○○●●●○○●●●○○的顺序排列，第19个图形是白色，第28个图形是黑色。",
+        "knowledge_points":  [
+                                 "周期问题",
+                                 "有余数除法的实际应用",
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "24-25 二年级下·湖北孝感·期末"
+    },
+    {
+        "id":  "128",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "有余数的除法算式□÷6=8……∆中，∆最大是( )，这时□是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "5;53",
+        "solution":  "【分析】在有余数的除法中，余数必须小于除数。已知除数是6，余数∆最大为6-1=5。再根据\"被除数=除数×商+余数\"计算对应的被除数。\n\n【详解】根据分析可得:∆最大是5;6×8+5=48+5=53。所以，∆最大是5，这时□是53。",
+        "knowledge_points":  [
+                                 "乘加",
+                                 "乘减混合运算",
+                                 "余数与除数的关系"
+                             ],
+        "source":  "24-25 二年级下·湖北孝感·期末"
+    },
+    {
+        "id":  "129",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "小新计算43÷7=5……8。如果你当小老师，你会告诉小新，除数应该( )余数(填\"大于\"或\"小于\")。正确的计算是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "大于;43÷7=6……1",
+        "solution":  "【分析】有余数的除法算式为：被除数÷除数=商……余数，可以表示把被除数平均分成除数的若干份，商是每份的数，余数是剩下的数。其中除数一定大于余数。由此计算解答。\n\n【详解】小新计算43÷7=5……8。如果你当小老师，你会告诉小新，除数应该大于余数。正确的计算是43÷7=6……1。",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算",
+                                 "余数与除数的关系"
+                             ],
+        "source":  "24-25 二年级下·江西赣州·期末"
+    },
+    {
+        "id":  "130",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "一条道路的一边插了一排彩旗，按照\"3面红旗，2面黄旗\"的规律排列。第39面彩旗是( )旗，在这39面彩旗中，有( )面是红旗。",
+        "options":  [
+
+                    ],
+        "answer":  "黄;24",
+        "solution":  "【分析】按照\"3面红旗，2面黄旗\"5面旗子为一组依次循环，用除法计算，商是循环的组数，余数是剩余的面数，如果没有余数，就是一组中的最后一面，如果有余数，余数是几就是一组中的第几面;在这39面彩旗中，红旗的面数=平均每组红旗的面数×循环的组数+剩余中的红旗面数。据此解答。\n\n【详解】根据分析:39÷(3+2)=39÷5=7(组)……4(面)，第39面彩旗是黄旗。7×3+3=21+3=24(面)。一条道路的一边插了一排彩旗，按照\"3面红旗，2面黄旗\"的规律排列。第39面彩旗是黄旗，在这39面彩旗中，有24面是红旗。",
+        "knowledge_points":  [
+                                 "有余数除法的实际应用",
+                                 "周期问题"
+                             ],
+        "source":  "24-25 二年级下·浙江杭州·期末"
+    },
+    {
+        "id":  "131",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "食堂需要给每个小朋友准备一双筷子和一个碗，有15根筷子和8个碗，可以分给( )个小朋友。",
+        "options":  [
+
+                    ],
+        "answer":  "7",
+        "solution":  "【分析】根据生活经验可知，每人需要1个碗和2根筷子。也就是8个碗可以分给8个人。用筷子的总数量除以每人需要的数量，商是最多可以分的人数，再比较碗和筷子分的人数，找出较小数，就是最终可以分的人数。\n\n【详解】15÷2=7(个)。1(根),7\u003c8。食堂需要给每个小朋友准备一双筷子和一个碗，有15根筷子和8个碗，可以分给7个小朋友。",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算",
+                                 "有余数除法的实际应用"
+                             ],
+        "source":  "24-25 二年级下·浙江台州·期末"
+    },
+    {
+        "id":  "132",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "按照下面的规律画图形:△△□□。第18个图形是( )，第26个图形是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "△;△",
+        "solution":  "【分析】这组图形按照△△□□为一组重复排列，每组有4个图形，则分别用18和26除以每组图形的数量，若能除尽，则是这组的最后一个图形，若除不尽，则余数是几就是下一组的第几个图形。\n\n【详解】18÷4=4(组)……2(个)，第18个图形是第5组的第2个，是△;26÷4=6(组)……2(个)，第26个图形是第7组的第2个，也是△。",
+        "knowledge_points":  [
+                                 "有余数除法的实际应用",
+                                 "周期问题"
+                             ],
+        "source":  "24-25 二年级下·浙江台州·期末"
+    },
+    {
+        "id":  "133",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "□÷△=8……8，△最小是( )，此时被除数是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "9;80",
+        "solution":  "【分析】在有余数的除法中，余数比除数小，除数最小=余数+1;此时，被除数=商×除数+余数。\n\n【详解】8+1=9;8×9+8=72+8=80。□÷△=8……8，△最小是9，此时被除数是80。",
+        "knowledge_points":  [
+                                 "余数与除数的关系",
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "24-25 二年级下·浙江台州·期末"
+    },
+    {
+        "id":  "134",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "△△○□★△△○□★△△○□★。从左往右数，第28个图形是( )，这28个图形中○有( )个。",
+        "options":  [
+
+                    ],
+        "answer":  "○;6",
+        "solution":  "【分析】这组图形是按照\"△△○□★\"5个图形为一组依次循环，用28除以5，余数是几，第28个图形就是一个循环中的第几个图形。这28个图形中○的个数=平均每组○的个数×组数+余下的○个数。\n\n【详解】28÷5=5(组)……3(个)，第28个图形是○。5×1+1=5+1=6(个)。这28个图形中○有6个。△△○□★△△○□★△△○□★。从左往右数，第28个图形是○，这28个图形中○有6个。",
+        "knowledge_points":  [
+                                 "表内乘加",
+                                 "乘减",
+                                 "有余数除法的实际应用"
+                             ],
+        "source":  "24-25 二年级下·浙江湖州·期末"
+    },
+    {
+        "id":  "135",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "把25朵花平均放在5个花瓶里，那么每个花瓶里放( )朵：如果平均放在4个花瓶里，那么每个花瓶里最多放( )朵，还剩( )朵。",
+        "options":  [
+
+                    ],
+        "answer":  "5;6;1",
+        "solution":  "【分析】据题意，花的总朵数除以瓶数即可得出每个花瓶放几朵花，每个花瓶最多放的朵数=花的总朵数÷放的瓶数，余数是还剩下的朵数。\n\n【详解】25÷5=5(朵);25÷4=6(朵)……1(朵)。所以，把25朵花平均放在5个花瓶里，那么每个花瓶里放5朵;如果平均放在4个花瓶里，那么每个花瓶里最多放6朵，还剩1朵。",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算",
+                                 "用6的乘法口诀求商",
+                                 "用2~5的乘法口诀求商",
+                                 "整数平均分的意义及应用"
+                             ],
+        "source":  "24-25 二年级下·浙江湖州·期末"
+    },
+    {
+        "id":  "136",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "王阿姨将50多个碗打包，每6个装一盒还余3个，每8个装一盒，还余1个，共( )个碗。",
+        "options":  [
+
+                    ],
+        "answer":  "57",
+        "solution":  "【分析】根据题意，王阿姨将50多个碗打包，每6个装一盒还余3个，可得碗的总个数=每6个装一盒×装的盒数+余下的个数。根据乘法口诀\"六八四十八\"、\"六九五十四\"可以得出装8盒、9盒时，碗的总个数是50多个;用这两个盒数分别求出碗的总个数，再分别除以8，哪个数的余数是1，哪个数就是正确答案，据此解答。\n\n【详解】根据乘法口诀\"六八四十八\"得出碗的总个数是:6×8+3=48+3=51(个);根据乘法口诀\"六九五十四\"得出碗的总个数是:6×9+3=54+3=57(个)。碗的总个数可能是51个或57个。用51个和57个分别除以8可得:51÷8=6(盒)……3(个)，57÷8=7(盒)……1(个)。只有碗的总个数是57个时，每8个装一盒，还余1个，所以57是正确答案。王阿姨将50多个碗打包，每6个装一盒还余3个，每8个装一盒，还余1个，共57个碗。",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算",
+                                 "有余数除法的实际应用",
+                                 "乘加",
+                                 "乘减混合运算"
+                             ],
+        "source":  "24-25 二年级下·福建厦门·期末"
+    },
+    {
+        "id":  "137",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "括号里最大填几。\n( )×7\u003c40  ( )×6\u003c43  ( )×4\u003c30  9×( )\u003c48  4×( )\u003c23  8×( )\u003c52",
+        "options":  [
+
+                    ],
+        "answer":  "5;7;7;5;5;6",
+        "solution":  "【分析】用小于号右边的数或大于号左边的数，除以左边或右边已知的一个数，如果正好能整除，则商减1是括号里最大能填的数，如果有余数，则商是最大能填的数。\n\n【详解】( )×7\u003c40，40÷7=5……5，故5×7\u003c40;( )×6\u003c43，43÷6=7……1，故7×6\u003c43;( )×4\u003c30，30÷4=7……2，故7×4\u003c30;9×( )\u003c48，48÷9=5……3，故9×5\u003c48;4×( )\u003c23，23÷4=5……3，故4×5\u003c23;8×( )\u003c52，52÷8=6……4，故8×6\u003c52。",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "25-26 二年级上·全国·课后作业"
+    },
+    {
+        "id":  "138",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "如果△÷☆=3……4，那么除数最小是( )，此时被除数是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "5;19",
+        "solution":  "【分析】在有余数除法中，余数要比除数小;余数是4，除数最小比4大1;根据被除数=商×除数+余数，即可求出被除数;据此解答。\n\n【详解】由分析可得：除数最小是:4+1=5;3×5+4=15+4=19。如果△÷☆=3……4，那么除数最小是5，此时被除数是19。",
+        "knowledge_points":  [
+                                 "余数与除数的关系",
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "24-25 二年级下·河南郑州·期末"
+    },
+    {
+        "id":  "139",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "△○☆☆△○☆☆△○☆☆△○。按这样的规律，第28个图形是( ),第38个图形是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "☆;○",
+        "solution":  "【分析】这组图形按照△○☆☆为一组重复排列，每组有4个图形，则分别用28,38除以每组图形的数量，若能整除，则是这组的最后一个图形，若除不尽，则余数是几就是下组的第几个图形。\n\n【详解】28÷4=7(组),第28个图形是第7组的最后一个，是☆;38÷4=9(组)。2(个),第38个图形是第10组的第2个，是○。",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算",
+                                 "有余数除法的实际应用",
+                                 "周期问题"
+                             ],
+        "source":  "24-25 二年级下·浙江台州·期末"
+    },
+    {
+        "id":  "140",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在有余数的除法算式△÷□=6……7中，□最小是( )，这时△是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "8;55",
+        "solution":  "【分析】有余数的除法算式为：被除数÷除数=商……余数，其中余数一定比除数小，除数最小是比余数大1的数，根据除数×商+余数=被除数，计算即可。\n\n【详解】7+1=8;8×6+7=48+7=55。在有余数的除法算式△÷□=6……7中，□最小是8，这时△是55。",
+        "knowledge_points":  [
+                                 "余数与除数的关系",
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "24-25 二年级下·浙江台州·期末"
+    },
+    {
+        "id":  "141",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "把8分米长的铁丝，如果每3分米剪成一段，可以剪成( )段，还剩( )分米。",
+        "options":  [
+
+                    ],
+        "answer":  "2;2",
+        "solution":  "【分析】已知铁丝总长8分米，每3分米剪成一段，求可以剪成的段数和剩余长度。根据除法意义，总长度/每段长度，商就是可以剪成的段数，余数就是还剩的长度。\n\n【详解】8÷3=2(段)。2(分米)。可以剪成2段，还剩2分米。",
+        "knowledge_points":  [
+                                 "有余数除法的实际应用",
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "24-25 二年级下·山东济南·期中"
+    },
+    {
+        "id":  "142",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "□□□☆☆□□□☆☆□□□☆☆。按这样的规律继续摆下去，第27个图形是( )，第34个图形是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "□;☆",
+        "solution":  "【分析】由题意可知：观察图形的排列规律是□□□☆☆5个图形为一组，不断地重复出现;用27、34分别除以每组图形的个数，求出的余数是几，就是一组里第几个图形;据此解答。\n\n【详解】由分析可得:27÷5=5(组)……2(个)，第2个图形是□;34÷5=6(组)……4(个)，第4个图形是☆。按这样的规律继续摆下去，第27个图形是□，第34个图形是☆。",
+        "knowledge_points":  [
+                                 "图形的变化规律",
+                                 "有余数除法的实际应用",
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "24-25二年级下·广东阳江·期末"
+    },
+    {
+        "id":  "143",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在\"□÷5=4……△\"中，△最大的是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "4",
+        "solution":  "【分析】在有余数除法中，余数要比除数小，且余数最大比除数小1;据此解答。\n\n【详解】余数最大:5-1=4。在\"□÷5=4……△\"中，△最大的是4。",
+        "knowledge_points":  [
+                                 "余数与除数的关系"
+                             ],
+        "source":  "24-25 二年级下·广东阳江·期末"
+    },
+    {
+        "id":  "144",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "有36颗草莓.\n(1)如果平均分成4份，每份有( )个.\n(2)如果每9颗草莓装一盒，可以装( )盒.\n(3)如果8颗草莓装一盒，最多可以装满( )盒，想全部装完的话，至少需要( )个盒子。",
+        "options":  [
+
+                    ],
+        "answer":  "9;4;4;5",
+        "solution":  "【分析】(1)把36颗草莓平均分成4份，要求每份有多少个，根据除法的意义，用36÷4进行解答即可。(2)把36颗草莓每9颗装一盒，要求可以装多少盒，根据除法的意义，用36÷9进行解答即可。(3)把36颗草莓每8颗装一盒，要求最多可以装多少盒，根据除法的意义，用36÷8进行解答即可。得出的商就是最多可以装的盒数，余数就是剩下的草莓数量。若要全部装完，则需要再用一个盒子装剩下的草莓。\n\n【详解】(1)36÷4=9(个)，所以每份有9个。(2)36÷9=4(盒)，所以可以装4盒。(3)36÷8=4(盒)……4(个)，所以最多可以装满4盒。4+1=5(盒)，所以想全部装完的话，至少需要5个盒子。",
+        "knowledge_points":  [
+                                 "有余数除法的实际应用",
+                                 "100以内有余数的除法计算",
+                                 "用7~9的乘法口诀求商"
+                             ],
+        "source":  "24-25二年级下·内蒙古赤峰·期末"
+    },
+    {
+        "id":  "145",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "二(1)班38名同学一起去阅览室看书，每5人共用一张桌子，至少需要( )张桌子。",
+        "options":  [
+
+                    ],
+        "answer":  "8",
+        "solution":  "【分析】用学生的总人数除以每张桌子共用的人数，商就是至少需要几张桌子，若有余数，剩下的学生也要再加一张桌子，据此解答。\n\n【详解】38÷5=7(张)……3(人)，7+1=8(张)。二(1)班38名同学一起去阅览室看书，每5人共用一张桌子，至少需要8张桌子。",
+        "knowledge_points":  [
+                                 "有余数除法的实际应用",
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "24-25 二年级下·浙江湖州·期末"
+    },
+    {
+        "id":  "146",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "四月份有30天，有( )个星期，还多( )天。",
+        "options":  [
+
+                    ],
+        "answer":  "4;2",
+        "solution":  "【分析】根据题意可知，用四月份的天数除以一周的天数，求出结果，商是有几个星期，余数是还多的天数，据此解答。\n\n【详解】根据分析可得:30÷7=4(个)……2(天)。答：四月份有4个星期，还多2天。",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算",
+                                 "有余数除法的实际应用"
+                             ],
+        "source":  "24-25 二年级下·甘肃兰州·期末"
+    },
+    {
+        "id":  "147",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在算式□÷5=9……△中，△最大是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "4",
+        "solution":  "【分析】有余数的除法算式为：被除数÷除数=商……余数，其中余数一定小于除数，余数最大是比除数小1的数。\n\n【详解】5-1=4。在算式□÷5=9……△中，△最大是4。",
+        "knowledge_points":  [
+                                 "余数与除数的关系"
+                             ],
+        "source":  "24-25 二年级下·新疆阿克苏·期末"
+    },
+    {
+        "id":  "148",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "有一袋糖果的数量在35~40之间，平均分给9个小朋友，还剩2颗，平均分给6个小朋友也还剩2颗，这袋糖果共有( )颗。",
+        "options":  [
+
+                    ],
+        "answer":  "38",
+        "solution":  "【分析】因为这些糖果平均分给9人还剩2颗，平均分给6个人也还剩2颗，所以这些糖果的数量应该是9和6的公倍数再加2颗。据此解答。\n\n【详解】9和6的公倍数有18、36、54。36在35~40之间，符合要求。36+2=38(颗)。所以这袋糖果共有38颗。",
+        "knowledge_points":  [
+                                 "9的乘法口诀及应用"
+                             ],
+        "source":  "23-24二年级下·云南昭通·期末"
+    },
+    {
+        "id":  "149",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "△÷□=4……5，□里最小是( )，此时被除数是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "6;29",
+        "solution":  "【分析】由题意可知：在有余数除法中，余数要比除数小;余数是5，除数最小是6;根据商×除数+余数=被除数，即可求出被除数;据此解答。\n\n【详解】由分析可得:4×6+5=24+5=29。△÷□=4……5，□里最小是6，此时被除数是29。",
+        "knowledge_points":  [
+                                 "有余数的除法验算",
+                                 "100以内有余数的除法计算",
+                                 "余数与除数的关系"
+                             ],
+        "source":  "23-24 二年级下·云南昭通·期末"
+    },
+    {
+        "id":  "150",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "○÷△=8……6，当△最小时，△=( )，○=( )。",
+        "options":  [
+
+                    ],
+        "answer":  "7;62",
+        "solution":  "【分析】余数与除数的关系是：余数要比除数小。余数是6，那么除数最小是7，再根据被除数=商×除数+余数计算出被除数即可。\n\n【详解】余数是6，除数最小是:6+1=7;8×7+6=56+6=62。○÷△=8……6，当△最小时，△=7，○=62。",
+        "knowledge_points":  [
+                                 "有余数的除法验算",
+                                 "余数与除数的关系"
+                             ],
+        "source":  "24-25二年级下·广西贵港·期中"
+    },
+    {
+        "id":  "151",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "二(1)班39名同学去研学旅行，每辆车限乘7人，至少要租( )辆车，会有( )个空座。",
+        "options":  [
+
+                    ],
+        "answer":  "6;3",
+        "solution":  "【分析】根据题意，用总人数除以每辆车限乘的人数，若能除尽，则商是要租车的数量;若除不尽，剩余的人数也需要租一辆车，则商+1是要租车的数量。用每辆车限乘的人数减去最后一辆车上的人数，就是空座数。\n\n【详解】39÷7=5(辆)……4(人)，5+1=6(辆)，7-4=3(个)。二(1)班39名同学去研学旅行，每辆车限乘7人，至少要租6辆车，会有3个空座。",
+        "knowledge_points":  [
+                                 "有余数除法的实际应用"
+                             ],
+        "source":  "24-25二年级下·广东云浮·期中"
+    },
+    {
+        "id":  "152",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "把8个足球平均分给3个班，每个班分到( )个，还剩( )个。",
+        "options":  [
+
+                    ],
+        "answer":  "2;2",
+        "solution":  "【分析】将8个足球平均分给3个班，用除法计算，商为每个班分到的个数，余数为剩下的个数。\n\n【详解】8÷3=2(个)……2(个)。每个班分到2个，还剩2个。",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算",
+                                 "有余数除法的实际应用"
+                             ],
+        "source":  "24-25 二年级下·广东云浮·期中"
+    },
+    {
+        "id":  "153",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "□÷8=7……☆，☆最大是( )，这时□是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "7;63",
+        "solution":  "【分析】在有余数的除法中，余数必须小于除数。已知除数是8，余数☆最大是7。被除数等于除数乘商加余数，即8×7+7，计算即可。\n\n【详解】8-1=7;8×7+7=56+7=63。□÷8=7……☆，☆最大是7，这时□是63。",
+        "knowledge_points":  [
+                                 "余数与除数的关系",
+                                 "100以内有余数的除法计算",
+                                 "有余数的除法验算"
+                             ],
+        "source":  "24-25 二年级下·广东云浮·期中"
+    },
+    {
+        "id":  "154",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "被除数是22，除数是4，商是( ),余数是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "5;2",
+        "solution":  "【分析】在有余数除法的算式中，余数一定比除数小，再根据22÷4的结果求出商和余数。\n\n【详解】22÷4=5……2。被除数是22，除数是4，商是5，余数是2。",
+        "knowledge_points":  [
+                                 "用2~5的乘法口诀求商",
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "24-25 二年级下·广东云浮·期中"
+    },
+    {
+        "id":  "155",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在括号里最大能填几。\n( )×5\u003c26  54÷9\u003e( )  85\u003e42+( )",
+        "options":  [
+
+                    ],
+        "answer":  "5;5;42",
+        "solution":  "【分析】根据题意：第1小题，用小于号右边的数除以左边已知的一个因数，如果正好能整除，则商减1是括号里最大能填的数，如果有余数，则商是最大能填的数;第2小题，先算54÷9的结果，再找比它小的最大整数;第3小题，用大于号左边的数减去右边的已知加数，则差减1是最大能填的数;据此解答。\n\n【详解】由分析可得:26÷5=5……1，所以( )里最大填5;54÷9=6，所以( )里最大填5;85-42=43，43-1=42，所以( )里最大填42。即5×5\u003c26，54÷9\u003e5，85\u003e42+42。",
+        "knowledge_points":  [
+                                 "100以内数的比大小",
+                                 "两位数与两位数的不退位减法",
+                                 "用7~9的乘法口诀求商",
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "24-25 二年级下·福建龙岩·期中"
+    },
+    {
+        "id":  "156",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "商是6，除数是9，余数是4，被除数是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "58",
+        "solution":  "【分析】根据\"被除数=商×除数+余数\"来计算即可。\n\n【详解】6×9+4=54+4=58。商是6，除数是9，余数是4，被除数是58。",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "24-25 二年级下·山东济宁·期末"
+    },
+    {
+        "id":  "157",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "有35米布，每4米做一条床单，最多可以做( )条床单。",
+        "options":  [
+
+                    ],
+        "answer":  "8",
+        "solution":  "【分析】根据题意可知：用共有的长度除以每条床单需用的长度，求出商和余数，余数不够再做一条床单，所以舍去余数，即可求出最多可以做的床单数量。\n\n【详解】35÷4=8(条)……3(米)。则有35米布，每4米做一条床单，最多可以做8条床单。",
+        "knowledge_points":  [
+                                 "有余数除法的实际应用"
+                             ],
+        "source":  "24-25 二年级下·湖北黄冈·期末"
+    },
+    {
+        "id":  "158",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "有23块糖，每6块装一盒，能装( )盒，还剩( )块。",
+        "options":  [
+
+                    ],
+        "answer":  "3;5",
+        "solution":  "【分析】根据100以内有余数的除法可知，糖的总数量÷每盒装的糖的数量=能够装的盒数，余数是剩余的糖的数量，由此列出算式算出答案即可。\n\n【详解】23÷6=3(盒)……5(块)。所以，有23块糖，每6块装一盒，能装3盒，还剩5块。",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算",
+                                 "有余数除法的实际应用"
+                             ],
+        "source":  "24-25 二年级下·黑龙江佳木斯·期末"
+    },
+    {
+        "id":  "159",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "13个桃子，每只猴子分3个桃子，可以分给几只小猴。列除法算式是:( )÷( )=( )(只)。( )个.\n![](images/28641aa5fdb389b5b2f8eeee343f5df4.png)",
+        "options":  [
+
+                    ],
+        "answer":  "13;3;4;1",
+        "solution":  "【分析】根据题意，用桃子的总数量除以每只小猴分桃子的数量，商就是可以分给小猴的数量，余数是剩余桃子的数量。\n\n【详解】由分析得：列除法算式是13÷3=4(只)……1(个)。则13个桃子可以分给4只小猴。",
+        "knowledge_points":  [
+                                 "有余数除法的认识",
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "24-25 二年级下·湖南·期末"
+    },
+    {
+        "id":  "160",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "乐乐有一些卡片，平均分给8个小朋友，每个人分到的卡片和剩下的卡片一样多，最多有( )张卡片。",
+        "options":  [
+
+                    ],
+        "answer":  "63",
+        "solution":  "【分析】根据余数一定要小于除数可知，卡片的总数量/小朋友的数量=每个小朋友分到的数量。剩余的卡片数量，其中余数是剩余卡片的数量，除数是小朋友的数量，则剩余卡片的数量一定要\u003c8，则剩余卡片的数量最大为7张。根据每个小朋友分到的数量×小朋友的数量+剩余卡片的数量=最多的卡片总数量，其中每个小朋友分到的数量和剩余卡片的数量都是7，小朋友的数量是8，由此列出算式算出答案即可解答。7×8+7=56+7=63(张)。所以，最多有63张卡片。",
+        "knowledge_points":  [
+                                 "余数与除数的关系",
+                                 "表内乘加",
+                                 "乘减"
+                             ],
+        "source":  "24-25 二年级下·山东济南·期末"
+    },
+    {
+        "id":  "161",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "△÷○=7……6，○内最小填( )，这时△里应填( )。",
+        "options":  [
+
+                    ],
+        "answer":  "7;55",
+        "solution":  "【分析】在有余数的除法中，余数一定要比除数小，最小的除数=余数+1，再根据被除数=商×除数+余数，求出被除数即可。\n\n【详解】6+1=7，○最小是7;7×7+6=49+6=55。△÷○=7……6，○内最小填7，这时△里应填55。",
+        "knowledge_points":  [
+                                 "余数与除数的关系",
+                                 "100以内有余数的除法计算",
+                                 "有余数的除法验算"
+                             ],
+        "source":  "24-25 二年级下·山东济南·期末"
+    },
+    {
+        "id":  "162",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "乐乐用18根小棒摆五边形，可以摆( )个，还剩( )根。笑笑也用一些小棒摆六边形，如果有剩余，最多剩( )根，最少剩( )根。",
+        "options":  [
+
+                    ],
+        "answer":  "3;3;5;1",
+        "solution":  "【分析】根据题意可知，乐乐摆一个五边形需要5根小棒，则小棒的总数÷每个图形需要的小棒数量=可以摆的图形个数，余数是剩余小棒的数量。笑笑摆六边形需要6根小棒，根据余数必须小于除数，可知笑笑剩余的数量必须小于6，大于0，由此进行解答即可。\n\n【详解】根据分析可得:18÷5=3(个)……3(根);笑笑剩余的根数最大为5，最小为1。所以，乐乐可以摆3个，还剩3根。笑笑如果有剩余，最多剩5根，最少剩1根。",
+        "knowledge_points":  [
+                                 "余数与除数的关系",
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "24-25 二年级下·山东济南·期末"
+    },
+    {
+        "id":  "163",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "体育课上，22个同学站成一排，按\"1，2，3\"的顺序依次重复报数。最后一个同学应该报( )。",
+        "options":  [
+
+                    ],
+        "answer":  "1",
+        "solution":  "【分析】根据题意，1，2，3作为一组依次重复出现，一组有3个数，用22除以一组的个数，如果结果没有余数，22就是一组中的最后一个;如果有余数，余数是几，22就是一组中的第几个，据此解答。\n\n【详解】根据分析:22÷3=7(组)……1(个)。体育课上，22个同学站成一排，按\"1，2，3\"的顺序依次重复报数。最后一个同学应该报1。",
+        "knowledge_points":  [
+                                 "有余数除法的实际应用"
+                             ],
+        "source":  "24-25 二年级下·湖北随州·期末"
+    },
+    {
+        "id":  "164",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "在□÷△=8……3中，△最小是( );当△是5时，□是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "4;43",
+        "solution":  "【分析】根据余数一定要小于除数，所以最小的除数=余数+1;在有余数的除法中，被除数=商×除数+余数，由此进行解答即可。\n\n【详解】3+1=4;8×5+3=40+3=43。所以，△最小是4;当△是5时，□是43。",
+        "knowledge_points":  [
+                                 "余数与除数的关系",
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "24-25 二年级下·广东潮州·期末"
+    },
+    {
+        "id":  "165",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "19颗玻璃球，每个瓶子里最多装4颗，可以装满 个瓶子。如果把它们全部装入瓶子里，至少需要 个瓶子。",
+        "options":  [
+
+                    ],
+        "answer":  "4;5",
+        "solution":  "【分析】由题意得，玻璃球的总颗数除以每个瓶子最多装的颗数，求出结果，商就是可以装满瓶子的个数;若有余数，剩下的还需一个瓶子，把商加1，即可得至少需要瓶子的个数。\n\n【详解】19÷4=4(个)。3(颗),4+1=5(个)。19颗玻璃球，每个瓶子里最多装4颗，可以装满4个瓶子。如果把它们全部装入瓶子里，至少需要5个瓶子。",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算",
+                                 "有余数除法的实际应用"
+                             ],
+        "source":  "24-25 二年级下·山东济南·期末"
+    },
+    {
+        "id":  "166",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "妈妈买了25朵花，每9朵扎成一束，最多能扎( )束。如果要多扎一束，应该再买( )朵花。",
+        "options":  [
+
+                    ],
+        "answer":  "2;2",
+        "solution":  "【分析】用妈妈买的花的朵数除以扎成一束的朵数，求出的商即是最多能扎的束数;余数是剩余的朵数，余数再加上几等于9，即用9减去余数，算出的得数，即是再买花朵数。据此解答。\n\n【详解】由分析可得:25÷9=2(束)。7(朵),9-7=2(朵)。妈妈买了25朵花，每9朵扎成一束，最多能扎2束。如果要多扎一束，应该再买2朵花。",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算",
+                                 "有余数除法的实际应用"
+                             ],
+        "source":  "24-25 二年级下·山东济宁·期末"
+    },
+    {
+        "id":  "167",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在口/7=5。口中，被除数最大是( ),被除数最小是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "41;36",
+        "solution":  "【分析】由题意可知：在有余数除法算式里，余数最大，被除数最大;余数最小，被除数最小。根据余数要比除数小，求出最大和最小的余数，最大的余数：除数-1，最小的余数是1，再根据商×除数+余数=被除数，算出最大的被除数和最小的被除数;据此解答。\n\n【详解】由分析可得：最大的余数是:7-1=6;最小的余数是1;最大的被除数:7×5+6=35+6=41;最小的被除数:7×5+1=35+1=36。在口/7=5。口中，被除数最大是41，被除数最小是36。",
+        "knowledge_points":  [
+                                 "余数与除数的关系",
+                                 "100以内有余数的除法计算",
+                                 "有余数的除法验算"
+                             ],
+        "source":  "24-25 二年级下·山东济宁·期末"
+    },
+    {
+        "id":  "168",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "文艺晚会上，气球按照\"红红黄绿紫，红红黄绿紫……\"的规律排列。第17个是( )色，第25个是( )色，第38个是( )色。",
+        "options":  [
+
+                    ],
+        "answer":  "红;紫;黄",
+        "solution":  "【分析】由题意可知：气球的排列规律是红红黄绿紫5个颜色为一组，不断地重复出现;分别用17、25、38这三个数除以一组的颜色数，得出的余数是几，就对应一组中的第几个颜色;如果没有余数，则是一组中最后一个颜色;据此解答。\n\n【详解】由分析可得:17÷5=3(组)……2(个);25÷5=5(组);38÷5=7(组)……3(个)。文艺晚会上，气球按照\"红红黄绿紫，红红黄绿紫……\"的规律排列。第17个是红色，第25个是紫色，第38个是黄色。",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算",
+                                 "周期问题"
+                             ],
+        "source":  "24-25 二年级下·甘肃天水·期末"
+    },
+    {
+        "id":  "169",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在□÷☆=4……5中，☆最小是( )，这时□是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "6;29",
+        "solution":  "【分析】根据在有余数的除法算式中，余数小于除数，余数是5，则除数最小比余数大1，即5+1=6，根据被除数=商×除数+余数进行计算即可。\n\n【详解】余数是5，除数最小是5+1=6;6×4+5=24+5=29。则在□÷☆=4……5中，☆最小是6，这时□是29。",
+        "knowledge_points":  [
+                                 "余数与除数的关系",
+                                 "有余数的除法验算"
+                             ],
+        "source":  "24-25 二年级下·福建福州·期末"
+    },
+    {
+        "id":  "170",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "王老师有21本故事书，平均分给4个小组，每个小组分( )本，还剩下( )本;王老师再买( )本，每个小组就正好分得6本。",
+        "options":  [
+
+                    ],
+        "answer":  "5;1;3",
+        "solution":  "【分析】用故事书的数量除以4，商就是每个小组分的本数，余数就是剩下的本数。用每个小组分得的数量乘4，求出故事书的总本书，用总本数减去21，即可求出王老师再买几本，每个小组就正好分得6本。\n\n【详解】21÷4=5(本)。1(本);4×6=24(本);24-21=3(本)。王老师有21本故事书，平均分给4个小组，每个小组分5本，还剩下1本;王老师再买3本，每个小组就正好分得6本。",
+        "knowledge_points":  [
+                                 "有余数除法的实际应用",
+                                 "100以内有余数的除法计算",
+                                 "6的乘法口诀及应用"
+                             ],
+        "source":  "24-25 二年级下·广东揭阳·期末"
+    },
+    {
+        "id":  "171",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "计算题",
+        "difficulty":  0.65,
+        "question":  "竖式计算。\n73÷8= 46÷6= 52÷7= 27÷3=",
+        "options":  [
+
+                    ],
+        "answer":  "9……1;7……4;7……3;9",
+        "solution":  "【分析】除法用竖式计算时，从最高位开始除起，若除不了，就用最高位和下一位合成一个数来除，直到能除以除数为止。若有余数，则余数一定比除数小。\n\n【详解】73÷8=9……1;46÷6=7……4;52÷7=7……3;27÷3=9。",
+        "knowledge_points":  [
+                                 "用7~9的乘法口诀求商",
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "24-25 二年级下·广东潮州·期末"
+    },
+    {
+        "id":  "172",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "计算题",
+        "difficulty":  0.85,
+        "question":  "计算下列各题，前两道题脱式计算。(带*的列竖式计算)\n48÷(32-26)  25+9×8  *37÷7",
+        "options":  [
+
+                    ],
+        "answer":  "8;97;5……2",
+        "solution":  "【分析】四则混合运算的运算法则:①在没有括号的算式里，如果只有加减法或者只有乘除法，要从左往右依次计算。②在没有括号的算式里，如果既有乘除法又有加减法，要先算乘除法，再算加减法。③在有括号的算式里，要先算括号里面的，再算括号外面的。第1题先算括号里面的减法，再算括号外面的除法。第2题先算乘法，再算加法。第3题列竖式计算有余数的除法。\n\n【详解】48÷(32-26)=48÷6=8;25+9×8=25+72=97;37÷7=5……2。",
+        "knowledge_points":  [
+                                 "带有小括号的混合运算",
+                                 "乘加",
+                                 "乘减混合运算",
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "24-25二年级下·海南省直辖县级单位·期末"
+    },
+    {
+        "id":  "173",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "计算题",
+        "difficulty":  0.65,
+        "question":  "用竖式计算。\n47÷7= 72÷8= 50÷6=",
+        "options":  [
+
+                    ],
+        "answer":  "6……5;9;8……2",
+        "solution":  "【分析】有余数除法的计算方法：想除数和几相乘最接近被除数并且小于被除数，那么商就是几，写在被除数个位的上面;把除数和商相乘，把结果写在被除数下面;用被除数减去商与除数的乘积，所得的差写在横线下面;将余数与除数比一比，余数必须比除数小。根据乘法口诀求商时，口诀中的后一个数为被除数，前两个数一个作除数，一个作商。\n\n【详解】47÷7=6……5;72÷8=9;50÷6=8……2。",
+        "knowledge_points":  [
+                                 "用7~9的乘法口诀求商",
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "24-25 二年级下·浙江湖州·期末"
+    },
+    {
+        "id":  "174",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "计算题",
+        "difficulty":  0.65,
+        "question":  "用竖式计算。\n18÷4= 51÷8= 60÷9=",
+        "options":  [
+
+                    ],
+        "answer":  "4……2;6……3;6……6",
+        "solution":  "【分析】除法用竖式计算时，从最高位开始除起，若除不了，就用最高位和下一位合成一个数来除，直到能除以除数为止。若有余数，则余数一定比除数小。\n\n【详解】18÷4=4……2;51÷8=6……3;60÷9=6……6。",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "24-25 二年级下·江西赣州·期末"
+    },
+    {
+        "id":  "175",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "计算题",
+        "difficulty":  0.65,
+        "question":  "列式计算.\n被除数是52，余数是4，商是6，除数是多少。",
+        "options":  [
+
+                    ],
+        "answer":  "8",
+        "solution":  "【分析】由题意可知：用被除数减去余数，再除以商，即是除数;据此解答。\n\n【详解】(52-4)÷6=48÷6=8。除数是8。",
+        "knowledge_points":  [
+                                 "一位数与两位数的退位减法",
+                                 "用7~9的乘法口诀求商",
+                                 "100以内有余数的除法计算",
+                                 "带有小括号的混合运算"
+                             ],
+        "source":  "24-25二年级下·黑龙江佳木斯·期末"
+    },
+    {
+        "id":  "176",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "计算题",
+        "difficulty":  0.65,
+        "question":  "用竖式计算。(带△的要验算)\n78÷9= △315+147= 53÷7= △986-178=",
+        "options":  [
+
+                    ],
+        "answer":  "8……6;462;7……4;808",
+        "solution":  "【分析】(1)(3)除法的计算方法：一商，二乘，三减，四比。一商：即试商，想除数和几相乘最接近被除数且小于被除数，那么商就是几，写在被除数的个位的上面;二乘：把除数和商相乘，将得数写在被除数下面;三减：用被除数减去商与除数的乘积，所得的差写在横线的下面;四比：将余数与除数比一比，余数必须比除数小。\n(2)竖式计算三位数加法时，相同数位对齐，从个位加起，任意一位相加满十就要向前一位进一，注意最后不要把进位漏掉。加法的验算方法是：和-一个加数=另一个加数。\n(4)竖式计算三位数减法时，相同数位对齐，从个位减起，哪一位不够减，就从前一位退一，本位数字加十再减。减法的验算方法是：差+减数=被减数。\n\n【详解】78÷9=8……6;△315+147=462;53÷7=7……4;△986-178=808。",
+        "knowledge_points":  [
+                                 "两位数除以一位数的有余数除法",
+                                 "两，三位数的一次退位减法",
+                                 "两，三位数的一次进位加法"
+                             ],
+        "source":  "24-25 二年级下·广东揭阳·期末"
+    },
+    {
+        "id":  "177",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "一批货物有51箱.\n![](images/f7977afbbc101886c8e129cd98bd17c1.png)\n(1)如果都用大货车运，至少要运多少次。\n(2)如果都用小货车运，可以装满几辆小货车。\n(3)如果大车和小车搭配，怎样安排正好能运完所有货物。",
+        "options":  [
+
+                    ],
+        "answer":  "6;8;1次大货车和7次小货车或3次大货车和4次小货车或5次大货车和1次小货车",
+        "solution":  "【分析】(1)用货物的总数量÷大货车每次运的数量，若能除尽，则商是要运的次数，若除不尽，剩余的箱数需要再运1次，则商+1是要运的次数;(2)用货物的总数量÷小货车每次运的数量，商是能装满小货车的数量;(3)两种车装的总数量为51箱即可，即大货车运的次数×每次大货车运的箱数+小货车运的次数×每次小货车运的箱数=51箱。\n\n【详解】(1)51÷9=5(次)……6(箱)，5+1=6(次)。答：至少要运6次。(2)51÷6=8(辆)……3(箱)。答：可以装满8辆小货车。(3)9×1+6×7=9+42=51(箱);9×3+6×4=27+24=51(箱);9×5+6×1=45+6=51(箱)。答：用1次大货车和7次小货车，或者用3次大货车和4次小货车，或者用5次大货车和1次小货车正好能运完所有货物。",
+        "knowledge_points":  [
+                                 "有余数除法的实际应用",
+                                 "乘加",
+                                 "乘减混合运算"
+                             ],
+        "source":  "24-25二年级下·浙江台州·期末"
+    },
+    {
+        "id":  "178",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "一个星期有7天，6月份有30天。\n(1)6月份有几个星期，还多几天。\n(2)2025年6月7日是星期六，2025年6月20日是星期( )。",
+        "options":  [
+
+                    ],
+        "answer":  "4;2;五",
+        "solution":  "【分析】(1)6月份有星期的个数=6月份的天数÷平均每个星期的天数，余数是还多的天数;(2)先计算两个日期之间的天数差，再除以7，如果没有余数，那么6月20日就是星期六;如果有余数，余数是几，就从星期六往后数几天，数到的那天即为目标日期对应的星期。\n\n【详解】(1)30÷7=4(个)……2(天)。答：6月份有4个星期，还多2天。(2)20-7=13(天)，13÷7=1(个)……6(天)。从星期六依次往后数6天：星期日、星期一、星期二、星期三、星期四、星期五。因此，2025年6月20日是星期五。",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算",
+                                 "有余数除法的实际应用"
+                             ],
+        "source":  "24-25 二年级下·浙江湖州·期末"
+    },
+    {
+        "id":  "179",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "安安家养了31只鸡，有两种鸡笼可用。大鸡笼最多可放6只鸡，小鸡笼最多可放4只鸡。\n(1)如果都放进大鸡笼，至少需要几个大鸡笼。\n(2)如果都放进小鸡笼，最多可以装满几个小鸡笼。",
+        "options":  [
+
+                    ],
+        "answer":  "6;7",
+        "solution":  "【分析】(1)至少需要大鸡笼的个数=要装鸡的总只数÷平均每个大鸡笼装的只数;如果有余数，大鸡笼的个数再加1个。(2)最多可以装满小鸡笼的个数=要装鸡的总只数÷平均每个小鸡笼装的只数，余数是还剩下的只数。\n\n【详解】(1)31÷6=5(个)……1(只)，5+1=6(个)。答：至少需要6个大鸡笼。(2)31÷4=7(个)……3(只)。答：最多可以装满7个小鸡笼。",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算",
+                                 "有余数除法的实际应用"
+                             ],
+        "source":  "24-25二年级下·浙江湖州·期末"
+    },
+    {
+        "id":  "180",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "王老师和36名学生租船，每条船坐6人，至少需要租几条船。他们一共交了42元，每条船的租金是多少钱。",
+        "options":  [
+
+                    ],
+        "answer":  "7条;6元",
+        "solution":  "【分析】根据题意，先用加法计算出一共有多少人，再用总人数除以每条船坐的人数，若能除尽，则商是需要船的数量;若除不尽，剩余的人数也需要1条船，则商加1是需要船的数量。根据除法的意义，总钱数÷租船的数量=每条船的租金。\n\n【详解】1+36=37(人)，37÷6=6(条)……1(人)，6+1=7(条)，42÷7=6(元)。答：至少需要租7条船;每条船的租金是6元钱。",
+        "knowledge_points":  [
+                                 "有余数除法的实际应用",
+                                 "用7~9的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·浙江台州·期末"
+    },
+    {
+        "id":  "181",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "把一些面包平均分成2份，每份有6个，还剩2个。如果把这些面包平均分成7份，每份有几个。",
+        "options":  [
+
+                    ],
+        "answer":  "2个",
+        "solution":  "【分析】先根据面包的份数×每份面包的个数+多余的面包数量=面包的总数量，列出算式算出面包的总数量。再根据面包的总数量÷面包的份数=每份面包的个数，算出把这些面包平均分成7份时，每份有几个面包。\n\n【详解】2×6+2=12+2=14(个)，14÷7=2(个)。答：每份有2个面包。",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算",
+                                 "乘加",
+                                 "乘减混合运算"
+                             ],
+        "source":  "24-25二年级下·福建厦门·期末"
+    },
+    {
+        "id":  "182",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "有30盆花，每次最多能搬7盆，至少要搬多少次才能搬完。",
+        "options":  [
+
+                    ],
+        "answer":  "5次",
+        "solution":  "【分析】用花的总盆数除以每次最多搬的盆数，求出商和余数，由于余下的还需要搬1次，因此用商加上1即可求出至少要搬的次数，据此解答。\n\n【详解】30÷7=4(次)……2(盆)，4+1=5(次)。答：至少要搬5次才能搬完。",
+        "knowledge_points":  [
+                                 "有余数除法的实际应用"
+                             ],
+        "source":  "24-25 二年级下·湖北孝感·期末"
+    },
+    {
+        "id":  "183",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "售票处：每条船最多坐6人。32个学生去划船，他们至少要租多少条船。",
+        "options":  [
+
+                    ],
+        "answer":  "6条",
+        "solution":  "【分析】总人数是32人，每条船最多坐6人。用总人数除以每条船的人数，求出结果，结果若有余数，则需多租1条船。\n\n【详解】32÷6=5(条)……2(人)，5+1=6(条)。答：他们至少要租6条船。",
+        "knowledge_points":  [
+                                 "有余数除法的实际应用",
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "24-25 二年级下·广东阳江·期末"
+    },
+    {
+        "id":  "184",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "兔妈妈有32个梨，每个兔宝宝分5个梨，可以分给几个兔宝宝。还剩几个梨。",
+        "options":  [
+
+                    ],
+        "answer":  "6个;2个",
+        "solution":  "【分析】本题属于有余数的除法应用，已知总数和每份数，求份数和余数。用总数32除以每份数5，商即为可分给的兔宝宝数量，余数为剩下的梨数量。\n\n【详解】32÷5=6(个)……2(个)。答：可以分给6个兔宝宝;还剩2个梨。",
+        "knowledge_points":  [
+                                 "有余数除法的实际应用"
+                             ],
+        "source":  "24-25 二年级下·广东阳江·期末"
+    },
+    {
+        "id":  "185",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "一本成语故事共40页。王明每天看7页，至少需要几天才能看完。",
+        "options":  [
+
+                    ],
+        "answer":  "6天",
+        "solution":  "【分析】需要计算40页的书每天看7页，至少需要几天看完。用总页数除以每天看的页数，若有余数则需再加1天。\n\n【详解】40÷7=5(天)……5(页)，余数为5页，表示5天后还剩5页未看，需再增加1天。总天数为5+1=6(天)。答：至少需要6天才能看完。",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算",
+                                 "有余数除法的实际应用"
+                             ],
+        "source":  "24-25二年级下·甘肃兰州·期末"
+    },
+    {
+        "id":  "186",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "李叔叔要运34个西瓜，每次最多能运8个。至少要运几次才能运完。\n口答：至少要运 次才能运完。",
+        "options":  [
+
+                    ],
+        "answer":  "5",
+        "solution":  "【分析】用西瓜的个数除以每次运的个数，如果没有余数，商即为至少要运几次才能运完;如果有余数，还要用商加1，才能求出至少要运几次才能运完，因为剩下的西瓜也需要再运一次。\n\n【详解】34÷8=4(次)……2(个)，4+1=5(次)。答：至少要运5次才能运完。",
+        "knowledge_points":  [
+                                 "有余数除法的实际应用"
+                             ],
+        "source":  "24-25 二年级下·新疆阿克苏·期末"
+    },
+    {
+        "id":  "187",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "每年的4月23日是\"世界读书日\"。这天书店卖的儿童读物每本6元。小芳带了50元，最多可以买多少本儿童读物。",
+        "options":  [
+
+                    ],
+        "answer":  "8本",
+        "solution":  "【分析】根据题意可知：用小芳带的钱除以儿童读物每本的单价，求出商和余数，商则为最多可买的数量，余数为剩余的钱数。\n\n【详解】50÷6=8(本)……2(元)。答：最多可以买8本儿童读物。",
+        "knowledge_points":  [
+                                 "有余数除法的实际应用"
+                             ],
+        "source":  "23-24 二年级下·云南昭通·期末"
+    },
+    {
+        "id":  "188",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "二年级师生46人去餐厅聚餐，餐厅的团购优惠有6人套餐和8人套餐.\n(1)如果都买6人套餐，至少需要买几份套餐。\n(2)如果都买8人套餐，至少需要买几份套餐。\n(3)如果6人套餐和8人套餐搭配买，请给出一种搭配方案。",
+        "options":  [
+
+                    ],
+        "answer":  "8;6;5份8人套餐和1份6人套餐",
+        "solution":  "【分析】(1)总人数除以每份套餐的人数(6人)，若能除尽，则商是要买的份数，若除不尽，剩余的人数需要再买一份，则商+1是要买套餐的数量;(2)总人数除以每份套餐的人数(8人)，若能除尽，则商是要买的份数，若除不尽，剩余的人数需要再买一份，则商+1是要买套餐的数量;(3)只要两种套餐的人数总和正好是46人即可。\n\n【详解】(1)46÷6=7(份)……4(人)，7+1=8(份)。答：至少需要8份套餐。(2)46÷8=5(份)……6(人)，5+1=6(份)。答：至少需要买6份套餐。(3)5×8+1×6=40+6=46(人)。答：可以买5份8人套餐和1份6人套餐。(答案不唯一)",
+        "knowledge_points":  [
+                                 "乘加",
+                                 "乘减混合运算",
+                                 "有余数除法的实际应用"
+                             ],
+        "source":  "24-25 二年级下·广东云浮·期中"
+    },
+    {
+        "id":  "189",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "有一根50米的绳子，每6米可以做一根长跳绳，最多可以做多少根长跳绳。",
+        "options":  [
+
+                    ],
+        "answer":  "8根",
+        "solution":  "【分析】根据题意，用总长度÷一根长跳绳的长度=可以做的根数，余数是剩余的米数，据此解答。\n\n【详解】根据分析:50÷6=8(根)……2(米)。答：最多可以做8根长跳绳。",
+        "knowledge_points":  [
+                                 "有余数除法的实际应用"
+                             ],
+        "source":  "24-25 二年级下·广东云浮·期中"
+    },
+    {
+        "id":  "190",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "学校体育器材室有30个乒乓球。\n(1)每5个装一盒，需要几个盒子。\n(2)装在7个盒子里，平均每盒装几个。还剩几个。",
+        "options":  [
+
+                    ],
+        "answer":  "6;4;2",
+        "solution":  "【分析】(1)用乒乓球的个数除以一盒装的个数，即可求出需要几个盒子。(2)用乒乓球的个数除以装的盒子个数，商即为平均每盒装几个，余数为剩下的个数。\n\n【详解】(1)30÷5=6(个)。答：每5个装一盒，需要6个盒子。(2)30÷7=4(个)……2(个)。答：装在7个盒子里，平均每盒装4个，还剩2个。",
+        "knowledge_points":  [
+                                 "用6的乘法口诀求商",
+                                 "100以内有余数的除法计算",
+                                 "有余数除法的实际应用"
+                             ],
+        "source":  "24-25 二年级下·山东济宁·期末"
+    },
+    {
+        "id":  "191",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "李叔叔要做56个灯笼，每天最多做9个，至少需要几天才能全部做完。\n![](images/bde0cc82780db1404fed51df31958d64d4291831035818121ee2739d42fb5490.jpg)",
+        "options":  [
+
+                    ],
+        "answer":  "7天",
+        "solution":  "【分析】根据题意，用要做灯笼的总数量除以每天最多做的数量，若能除尽，则商是要做的天数，若除不尽，剩余的灯笼还需要再做1天，则商+1是要做的天数。\n\n【详解】56÷9=6(天)……2(个)，6+1=7(天)。答：至少需要7天才能全部做完。",
+        "knowledge_points":  [
+                                 "有余数除法的实际应用"
+                             ],
+        "source":  "24-25 二年级下·湖北黄冈·期末"
+    },
+    {
+        "id":  "192",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "舞台前的花真漂亮!从左往右看是红、黄、紫、粉、红、黄、紫、粉……你知道第12盆是什么颜色吗?第27盆呢?",
+        "options":  [
+
+                    ],
+        "answer":  "粉色;紫色",
+        "solution":  "【分析】根据题意，这些花的颜色按照红、黄、紫、粉为一组重复排列，每组有4盆。则分别用12和27除以每组花的数量，若能除尽，则是这组的最后一盆的颜色;若除不尽，则余数是几就是下一组的第几盆的颜色。\n\n【详解】12÷4=3(组)，第12盆是第3组的最后一盆，是粉色;27÷4=6(组)……3(盆)，第27盆是第7组的第3盆，是紫色。答：第12盆是粉色，第27盆是紫色。",
+        "knowledge_points":  [
+                                 "有余数除法的实际应用"
+                             ],
+        "source":  "24-25二年级下·湖北黄冈·期末"
+    },
+    {
+        "id":  "193",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "有42名同学去看电影，每排座位坐5人，至少要坐几排。",
+        "options":  [
+
+                    ],
+        "answer":  "9排",
+        "solution":  "【分析】根据题意可知：用共有的学生人数除以每排坐的人数，求出商和余数，商为可坐的排数，余数是还剩余的人数，剩余的人数也需要坐，则用可坐的排数再加1即可。\n\n【详解】42÷5=8(排)……2(人)，8+1=9(排)。答：至少要坐9排。",
+        "knowledge_points":  [
+                                 "有余数除法的实际应用"
+                             ],
+        "source":  "24-25 二年级下·黑龙江佳木斯·期末"
+    },
+    {
+        "id":  "194",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "潮州韩江景色宜人，一个22人的旅游团前来乘船游玩。如果每条船限坐4人，至少需要租多少条船。",
+        "options":  [
+
+                    ],
+        "answer":  "6条",
+        "solution":  "【分析】由题意可知：用旅游团的总人数除以每条船限坐的人数，算出的商是坐满船的条数，余数是剩余的人数，剩余的人数还需1条船，故至少需要租商+1条船;据此解答。\n\n【详解】由分析可得:22÷4=5(条)……2(人)，5+1=6(条)。答：至少需要租6条船。",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算",
+                                 "有余数除法的实际应用"
+                             ],
+        "source":  "24-25二年级下·广东潮州·期末"
+    },
+    {
+        "id":  "195",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "福清三伏茶是一种流行于福建福清地区的传统养生茶饮，具有清热解暑、健脾利湿等功效。一杯三伏茶里面有金银花8克，甘草5克，荷叶6克。现有金银花48克、甘草28克、荷叶44克，这些材料可以泡几杯三伏茶?",
+        "options":  [
+
+                    ],
+        "answer":  "5",
+        "solution":  "【分析】分别用金银花、甘草和荷叶的总克数除以一杯三伏茶需要的对应克数，得到的商进行对比，最小的那个商，就是可以泡三伏茶的杯数。\n\n【详解】48÷8=6(杯);28÷5=5(杯)……3(克);44÷6=7(杯)……2(克)。因为5\u003c6\u003c7，所以这些材料可以泡5杯三伏茶。",
+        "knowledge_points":  [
+                                 "用7~9的乘法口诀求商",
+                                 "100以内有余数的除法计算",
+                                 "有余数除法的实际应用"
+                             ],
+        "source":  "24-25 二年级下·福建福州·期末"
+    },
+    {
+        "id":  "196",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "快板是一种传统说唱艺术，一副快板由七块竹板制作而成，其中包括两块大板和五块小板，大小竹板合称为\"七块板\"。李师傅一共准备了55块竹板，能制作几副快板。\n![](images/6836fd109a0c2b337a89686d762ec4ef341b582f6792b24eb9cb326744f43848.jpg)",
+        "options":  [
+
+                    ],
+        "answer":  "7副",
+        "solution":  "【分析】根据100以内有余数的除法的意义，用一共准备的竹板块数除以一副快板需要的竹板数量，商就是能制作快板的副数。\n\n【详解】55÷7=7(副)……6(块)。答：能制作7副快板。",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "24-25 二年级下·福建福州·期末"
+    },
+    {
+        "id":  "197",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "超市运来35个木瓜。\n(1)如果每6个木瓜装一筐，至少需要多少个筐。\n(2)如果每个木瓜的价格是7元，50元最多能买多少个木瓜。",
+        "options":  [
+
+                    ],
+        "answer":  "6;7",
+        "solution":  "【分析】由题意得(1)用运来的木瓜数除以一筐木瓜的数量，求出的商是装满木瓜的筐数，余数是剩余的木瓜数，剩余的木瓜还需1个筐子，故至少需要商+1个筐子;(2)用50元钱除以木瓜的价格，求出的商即是最多能买的木瓜数;据此解答。\n\n【详解】由分析可得:(1)35÷6=5(筐)……5(个)，5+1=6(筐)。答：至少需要6个筐。(2)50÷7=7(个)……1(元)。答：50元最多能买7个木瓜。",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算",
+                                 "有余数除法的实际应用"
+                             ],
+        "source":  "24-25二年级下·山东济南·期末"
+    },
+    {
+        "id":  "198",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "王老师买来50颗糖果，平均分给8位表现优秀的同学，每位同学分到多少颗。还剩多少颗。",
+        "options":  [
+
+                    ],
+        "answer":  "6颗;2颗",
+        "solution":  "【分析】根据题意，用糖果的总数量除以8，所得的商就是每位同学分到的颗数，余数就是剩下的颗数，据此解答。\n\n【详解】50÷8=6(颗)……2(颗)。答：每位同学分到6颗，还剩2颗。",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算",
+                                 "有余数除法的实际应用"
+                             ],
+        "source":  "24-25二年级下·山东济南·期末"
+    },
+    {
+        "id":  "199",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "端午节超市的鸡蛋有优惠活动，工作人员将50个鸡蛋装在包装盒里打折出售。每8个装一盒，最多可以装满几个包装盒。要准备几个包装盒才能全部装下。",
+        "options":  [
+
+                    ],
+        "answer":  "6个;7个",
+        "solution":  "【分析】用鸡蛋的总数除以一盒的个数，商就是最多可以装满的包装盒个数。还有剩余，需要全部装下，则还需要加1个包装盒，据此解答。\n\n【详解】50÷8=6(个)……2(个)，6+1=7(个)。答：最多可以装满6个包装盒，要准备7个包装盒才能全部装下。",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算",
+                                 "有余数除法的实际应用"
+                             ],
+        "source":  "24-25二年级下·山东济宁·期末"
+    },
+    {
+        "id":  "200",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "二(1)班41人去吃饭，方桌每桌6人，圆桌每桌8人。\n(1)若全坐圆桌，可坐满几张。剩几人。\n(2)若全坐方桌，至少需几张。",
+        "options":  [
+
+                    ],
+        "answer":  "5;1;7",
+        "solution":  "【分析】(1)根据100以内有余数的除法的意义，班级总人数÷每张圆桌可以坐的人数=可以坐满的圆桌数量，余数是剩余没有坐下的人数。(2)根据100以内有余数的除法的意义，班级总人数÷每张方桌可以坐的人数=可以坐满的方桌数量，剩余没有坐下的人数需要再加1张桌子。\n\n【详解】(1)41÷8=5(张)……1(人)。答：可坐满5张，剩1人。(2)41÷6=6(张)……5(人)，6+1=7(张)。答：至少需要7张。",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "24-25 二年级下·黑龙江佳木斯·期末"
+    },
+    {
+        "id":  "201",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "渔民李叔叔在江边捕获50多条草鱼，平均分装在9个箱子里运往全国各地，李叔叔用下图竖式解决，竖式中虚线方框里的数可能是( )条。\n![](images/026c82fb03a1851bb99652957ac1e6e59434cf9057fdc805ed49d69bdb3ddccd.jpg)",
+        "options":  [
+                        "A. 36",
+                        "B. 54",
+                        "C. 56"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】依据九的乘法口诀\u0027五九四十五\u0027\u0027六九五十四\u0027\u0027七九六十三\u0027可知，因为鱼是50多条，所以商可能是6，6×9=54，竖式中虚线方框里的数可能是54条。\n\n【详解】渔民李叔叔在江边捕获50多条草鱼，平均分装在9个箱子里运往全国各地，李叔叔用下图竖式解决，竖式中虚线方框里的数可能是54条。故答案为:B",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "24-25二年级下·浙江台州·期末"
+    },
+    {
+        "id":  "202",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "有27只兔子，如果每4只兔子住在一个笼子里，至少需要( )个笼子。",
+        "options":  [
+                        "A. 6",
+                        "B. 7",
+                        "C. 8"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】由题意可得：实际上是求27里面有几个4，根据除法的意义，用27÷4。若有余数，根据题意可知，余数表示剩余兔子的数量，所以此题应使用\u0027进一法\u0027保留整数。\n\n【详解】27÷4=6(个)……3(只)，6+1=7(个)。所以至少需要7个笼子。故答案为:B",
+        "knowledge_points":  [
+                                 "有余数除法的实际应用",
+                                 "有余数除法的试商"
+                             ],
+        "source":  "24-25 二年级下·云南红河·期末"
+    },
+    {
+        "id":  "203",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "按这样的顺序排下去，第35个箭头是( )。\n→↓←↑→↓←↑→↓←↑。",
+        "options":  [
+                        "A. →",
+                        "B. ↓",
+                        "C. ←"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】由题意可知：图形的规律是→↓←↑四个为一组，不断地重复出现;用35除以每组箭头的个数，求出的商是组数，余数是剩余的个数，剩余几个，对应每组中的第几个图形，即是第35个箭头;据此解答。\n\n【详解】由分析可得:35÷4=8(组)……3(个)，一组中第3个图形是←，即第35个箭头是←。故答案为:C",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算",
+                                 "图形的变化规律"
+                             ],
+        "source":  "24-25 二年级下·吉林四平·期末"
+    },
+    {
+        "id":  "204",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "在有余数的除法算式□÷3=□……□中，余数可能是( )。",
+        "options":  [
+                        "A. 1,2,3",
+                        "B. 0,1,2",
+                        "C. 1,2"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】在有余数的除法计算中，余数要比除数小，但不能是0，据此解答。\n\n【详解】除法算式□÷3=□……□中，除数是3，那么余数可能是1、2。故答案为:C",
+        "knowledge_points":  [
+                                 "余数与除数的关系"
+                             ],
+        "source":  "24-25二年级下·辽宁鞍山·期末"
+    },
+    {
+        "id":  "205",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "小红练习写字，她连续写\u0027宋韵黄岩\u0027，写到第30个字是( )。",
+        "options":  [
+                        "A. \u0027宋\u0027",
+                        "B. \u0027韵\u0027",
+                        "C. \u0027黄\u0027"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】按照\u0027宋韵黄岩\u00274个字为一组依次循环，用总字数除以循环的长度4，如果没有余数，则为循环中的最后一个字;如果有余数，余数是几，就是一个循环中的第几个字。\n\n【详解】30÷4=7(组)……2(个)，小红写到第30个字是\u0027韵\u0027。故答案为:B",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算",
+                                 "周期问题"
+                             ],
+        "source":  "24-25 二年级下·浙江台州·期末"
+    },
+    {
+        "id":  "206",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "△○□□△○□□△。照这样排下去，第30个图形是( )。",
+        "options":  [
+                        "A. △",
+                        "B. ○",
+                        "C. □"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】观察图形排列规律，发现每4个图形(△○□□)为一组循环出现。要求第30个图形，只需计算30除以4的余数，余数是几，就对应一组循环内的第几个图形。\n\n【详解】30÷4=7(组)……2(个)，余数为2，对应第2个图形○，因此第30个图形是○。故答案为:B",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算",
+                                 "周期问题"
+                             ],
+        "source":  "24-25 二年级下·广东汕头·期末"
+    },
+    {
+        "id":  "207",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "一条丝绸长38分米，做一条丝巾要用7分米。如图竖式中箭头所指的部分表示( )(分米是一种长度单位).\n![](images/69f6cf3cb44ea145d1c90c760fa122894ed362dbd445c25bc6d8cfb9e4ebb677.jpg)",
+        "options":  [
+                        "A. 用去35分米",
+                        "B. 总长度35分米",
+                        "C. 还剩35分米"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】有余数除法竖式计算：被除数写在除号下面，除数写在除号左边，商写在除号上面，对应数位上，商跟除数相乘结果写在被除数的下面，再计算出余数，余数必须比除数小。被除数38是丝绸的总长，除数7是做一条丝巾的长，竖式中\u002735\u0027是商5和除数7的乘积，表示做5条丝巾用去丝绸35分米;余数3是剩余的丝绸长;据此解答。\n\n【详解】由分析可得：竖式中箭头所指的部分表示用去丝绸35分米。故答案为:A",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "24-25 二年级下·湖北武汉·期末"
+    },
+    {
+        "id":  "208",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "☆☆△○△☆☆△○△☆☆△○△。像这样画下去，第42个图形是( )。",
+        "options":  [
+                        "A. ☆",
+                        "B. ○",
+                        "C. △"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】通过观察这组图形，可以发现是以\u0027☆☆△○△\u0027这五个图形为一组的规律重复出现，用图形的位置数除以5，看余数是几，就是一组中的第几个图形，没有余数就是一组中的最后一个。据此即可解答。\n\n【详解】42÷5=8(组)……2(个)，说明第42个图形应该是第9组中的第2个，即是☆。故答案为:A",
+        "knowledge_points":  [
+                                 "周期问题",
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "24-25 二年级下·河北张家口·期末"
+    },
+    {
+        "id":  "209",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "下面的数除以6，余数是3的是( )。",
+        "options":  [
+                        "A. 18",
+                        "B. 50",
+                        "C. 39"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】根据题意，找出除以6余数为3的数。每个选项分别除以6，计算余数是否为3即可。\n\n【详解】A. 18÷6=3，余数为0，不符合条件;B. 50÷6=8……2，余数为2，不符合条件;C. 39÷6=6……3，余数为3，符合条件。故答案为:C",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算",
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·广西玉林·期末"
+    },
+    {
+        "id":  "210",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "小琪做了21颗蓝色星星、30颗黄色星星和15颗红色星星，她用星星穿手串，每个手串需要4颗蓝色星星、5颗黄色星星和2颗红色星星，小琪可以穿成( )个这样的星星手串。",
+        "options":  [
+                        "A. 5",
+                        "B. 6",
+                        "C. 7"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】要确定小琪最多能穿多少个手串，用每种颜色星星总数分别除以每个手串需要对应颜色星星的个数，分别计算每种颜色星星能制作的手串数量，再取最小值。\n\n【详解】21÷4=5(个)……1(颗);30÷5=6(个);15÷2=7(个)……1(颗)。因为5\u003c6\u003c7，所以小琪最多可以穿成5个这样的星星手串。故答案为:A",
+        "knowledge_points":  [
+                                 "用6的乘法口诀求商",
+                                 "100以内有余数的除法计算",
+                                 "有余数除法的实际应用"
+                             ],
+        "source":  "24-25 二年级下·陕西渭南·期末"
+    },
+    {
+        "id":  "211",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "欢欢，乐乐和安安三个小朋友按顺序从1开始轮流报数，报出\u002718\u0027的是( )。",
+        "options":  [
+                        "A. 安安",
+                        "B. 乐乐",
+                        "C. 欢欢"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】三个小朋友按固定顺序循环报数，每轮3个数构成一个周期。通过计算目标数在周期中的余数，判断对应的是哪位小朋友。余数为1对应欢欢，余数为2对应乐乐，没有余数对应安安。\n\n【详解】18÷3=6(组)。所以，欢欢，乐乐和安安三个小朋友按顺序从1开始轮流报数，报出\u002718\u0027的是安安。故答案为:A",
+        "knowledge_points":  [
+                                 "周期问题",
+                                 "有余数除法的实际应用",
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·福建福州·期末"
+    },
+    {
+        "id":  "212",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "2025年的7月1日是星期二，那么7月30日是( )。",
+        "options":  [
+                        "A. 星期二",
+                        "B. 星期三",
+                        "C. 星期四"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】根据题意，先用减法计算出从7月1日到7月30日经过了多少天，每周有7天，则用经过的天数除以每周的天数，若能除尽，则是星期二，若除不尽，则余数是几就从星期二往后推几天。\n\n【详解】30-1=29(天)，29÷7=4(周)……1(天)，余数是1，则从星期二往后推1天是星期三，即7月30日是星期三。故答案为:B",
+        "knowledge_points":  [
+                                 "有余数除法的实际应用"
+                             ],
+        "source":  "24-25 二年级下·贵州铜仁·期末"
+    },
+    {
+        "id":  "213",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "把16颗糖平均分给3个小朋友，每个小朋友可以分到几颗。还剩几颗。下边竖式中箭头所指的部分表示的是( )。\n![](images/6d2751ef50bcbfa5cbd7721466957c69f2025ad13f2879a5a45a16942caa79c7.jpg)",
+        "options":  [
+                        "A. 分了15颗",
+                        "B. 剩下15颗",
+                        "C. 一共有15颗"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】箭头处的15表示3个小朋友每人分5颗，一共分了15颗。余数表示剩下的颗数，逐项分析即可。\n\n【详解】A. 分了15颗，原题说法正确。B. 剩下1颗，原题说法错误。C. 一共有16颗，原题说法错误。竖式中箭头所指的部分表示的是分了15颗。故答案为:A",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "24-25 二年级下·贵州铜仁·期末"
+    },
+    {
+        "id":  "214",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "每支铅笔8角钱，6元钱最多可以买( )支铅笔。",
+        "options":  [
+                        "A. 8",
+                        "B. 7",
+                        "C. 6"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】由题意可知：根据1元=10角，先统一单位，6元=60角;用60角除以每支铅笔的钱，求出的商即是最多可以买的铅笔支数;据此解答。\n\n【详解】由分析可得:60÷8=7(支)……4(角)。每支铅笔8角钱，6元钱最多可以买7支铅笔。故答案为:B",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算",
+                                 "有余数除法的实际应用",
+                                 "元，角，分的认识及换算"
+                             ],
+        "source":  "24-25 二年级下·重庆梁平·期末"
+    },
+    {
+        "id":  "215",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "○○☆☆△△○○☆☆△△。按这样排下去，第21个图形是( )。",
+        "options":  [
+                        "A. ○",
+                        "B. ☆",
+                        "C. △"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】由题意可知：图形的排列规律是○○☆☆△△6个图形为一组，不断地重复出现;用21除以每组的图形个数，求出的商是组数，余数是剩余的图形个数;剩余几个图形，对应一组中的第几个图形，即是正确答案;据此解答。\n\n【详解】由分析可得:21÷6=3(组)……3(个)，第三个图形是☆，所以第21个图形是☆。故答案为:B",
+        "knowledge_points":  [
+                                 "有余数除法的实际应用",
+                                 "100以内有余数的除法计算",
+                                 "间隔问题"
+                             ],
+        "source":  "24-25二年级下·广东云浮·期末"
+    },
+    {
+        "id":  "216",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "刘老师领了25本书，最少再领( )本就能平均分给6个小朋友。",
+        "options":  [
+                        "A. 1",
+                        "B. 5",
+                        "C. 3"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】要使25本书能平均分给6个小朋友，总书数必须是6的倍数。计算25除以6的余数，再用6减去余数，就是最少需再领的本数。\n\n【详解】25÷6=4(本)……1(本)，6-1=5(本)。最少再领5本就能平均分给6个小朋友。故答案为:B",
+        "knowledge_points":  [
+                                 "有余数除法的实际应用",
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "24-25 二年级下·天津静海·期末"
+    },
+    {
+        "id":  "217",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "下面算式中，余数是2的是( )。",
+        "options":  [
+                        "A. 16÷3",
+                        "B. 22÷4",
+                        "C. 34÷5"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】有余数除法的计算方法：想除数和几相乘最接近被除数并且小于被除数，那么商就是几，用被除数减去商与除数的乘积，所得的差就是余数，将余数与除数比一比，余数必须比除数小。分别计算出各选项的结果，选择余数是2的即可。\n\n【详解】A. 16÷3=5……1，不符合题意;B. 22÷4=5……2，符合题意;C. 34÷5=6……4，不符合题意。故答案为:B",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "24-25 二年级下·广东汕尾·期末"
+    },
+    {
+        "id":  "218",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "妈妈带了50元去买8元一支的钢笔，最多能买( )支。",
+        "options":  [
+                        "A. 6",
+                        "B. 7",
+                        "C. 8"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】由题意可知：用妈妈带的钱数除以一支钢笔的钱数，求出的商即是最多能买钢笔的支数;据此解答。\n\n【详解】由分析可得:50÷8=6(支)……2(元)。最多能买6支。故答案为:A",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算",
+                                 "有余数除法的实际应用"
+                             ],
+        "source":  "24-25 二年级下·广东汕尾·期末"
+    },
+    {
+        "id":  "219",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "下边的竖式是优优用来计算\u002719根小棒可以摆几个单独的三角形\u0027,竖式中\u002718\u0027表示的意思是( ).\n![](images/112436.png)",
+        "options":  [
+                        "A. 可以摆18个三角形",
+                        "B. 还剩18根小棒",
+                        "C. 用掉了18根小棒"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】计算有余数的除法时，先利用和除数有关的乘法口诀求商，想除数和几相乘的积最接近被除数，而且小于被除数，商就是几。再用商乘除数求出积，把积写在被除数的下面;最后用被除数减去商与除数的积求出余数。根据有余数除法的计算方法逐项分析。\n\n【详解】算式表示,19根小棒除以每个三角形用的3根小棒，想乘法3×6=18(根),可知摆6个三角形，用了18根小棒,19-18=1(根),还剩1根小棒。A。 可以摆6个三角形，原题说法错误。B。 还剩1根小棒，原题说法错误。C。 用掉了18根小棒，原题说法正确。故答案为:C",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算",
+                                 "有余数除法的认识"
+                             ],
+        "source":  "24-25 二年级下·江西上饶·期末"
+    },
+    {
+        "id":  "220",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "□□○○☆☆☆□□○○☆☆☆□□○○☆☆☆。按这样的规律摆下去，第27个图形是( )。",
+        "options":  [
+                        "A. □",
+                        "B. ○",
+                        "C. ☆"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】图形按□□○○☆☆☆的顺序循环排列，一组循环图形有7个，用27除以7，余数是几就是一组中的第几个，没有余数就是最后一个。即可解答。\n\n【详解】27÷7=3(组)……6(个)，余数是6，所以第27个图形是☆。故答案为:C",
+        "knowledge_points":  [
+                                 "周期问题",
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "24-25 二年级下·广东揭阳·期末"
+    },
+    {
+        "id":  "221",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "46名师生乘车外出春游，每7人乘坐一辆面包车，至少需要( )辆面包车。",
+        "options":  [
+                        "A. 6",
+                        "B. 7",
+                        "C. 8"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】由题意得，实际上是求46里面有几个7。根据题意，若有余数则表示剩余的人数，剩余人数还需要一辆车，所以此题应使用\u0027进一法\u0027保留整数。\n\n【详解】46÷7=6(辆)……4(人)，6+1=7(辆)。所以至少需要7辆面包车。故答案为:B",
+        "knowledge_points":  [
+                                 "有余数除法的实际应用",
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "24-25 二年级下·广东揭阳·期末"
+    },
+    {
+        "id":  "222",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "11个桃子，每盘放3个，可以放多少盘。用下面竖式计算，箭头所指的数表示的是( ).\n![](images/a6a63d34f9afd2646d0dc3a6d69b6585e9e6b7de268df8d9f035ea5beba97915.jpg)",
+        "options":  [
+                        "A. 放了9盘",
+                        "B. 每盘放9个",
+                        "C. 3盘放了9个桃子"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】题中说共有11个桃子，每盘放3个，求可以放多少盘，其实就是求11里面有几个3，用除法计算，即11÷3。11是被除数，它代表桃子的总数;3是除数，它表示每盘放3个;商是3，它表示可以放3盘。竖式中的9是3×3的结果，因为每盘放3个，放了3盘，那么总共分出去的桃子个数就是3×3=9(个)，所以9表示3盘放了9个桃子。\n\n【详解】由分析得:3×3=9(个)，所以9表示3盘放了9个桃子。故答案为:C",
+        "knowledge_points":  [
+                                 "有余数除法的实际应用",
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "24-25二年级下·河南南阳·期末"
+    },
+    {
+        "id":  "223",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "下面计算错误的是( )。",
+        "options":  [
+                        "A. 16÷5=3……1",
+                        "B. 62÷8=7……6",
+                        "C. 34÷7=4……5"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】有余数除法中，余数必须比除数小。分别判断各选项中的余数是否小于除数，就能知道哪个计算错误。\n\n【详解】A. 16÷5=3……1，余数1小于除数5，计算正确;B. 62÷8=7……6，余数6小于除数8，计算正确;C. 34÷7=4……5不对，因为34÷7应为4……6。故答案为:C",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "24-25 二年级下·河南南阳·期末"
+    },
+    {
+        "id":  "224",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "按△○☆◇△○☆◇△○☆◇。的规律排列，第26个图形是( )。",
+        "options":  [
+                        "A. △",
+                        "B. ○",
+                        "C. ☆"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】通过观察这组图形，可知是按照△○☆◇为一组重复出现的，每组有4个图形，求第26个图形是什么，用26除以4，若能除尽，则是这组的最后一个图形;若不能除尽，则余数是几就是下一组的第几个图形。\n\n【详解】26÷4=6(组)……2(个)，第26个图形是第7组的第2个，即第26个图形是○。故答案为:B",
+        "knowledge_points":  [
+                                 "图形的变化规律",
+                                 "有余数除法的实际应用",
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "24-25 二年级下·河南南阳·期末"
+    },
+    {
+        "id":  "225",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "八月份有31天，八月份有( )个星期还多( )天。",
+        "options":  [
+
+                    ],
+        "answer":  "4;3",
+        "solution":  "【分析】一个星期有7天，用8月份的总天数除以7，商就是星期数，余数就是多的天数。\n\n【详解】31÷7=4(个)……3(天)。八月份有31天，八月份有4个星期还多3天。",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算",
+                                 "有余数除法的实际应用"
+                             ],
+        "source":  "24-25 二年级下·广东揭阳·期末"
+    },
+    {
+        "id":  "226",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "在☆÷6=4……△中，△最大是( )，☆最小是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "5;25",
+        "solution":  "【分析】在有余数的除法算式☆÷6=4……△中，除数是6。因为余数一定小于除数，所以△最大只能是比6小1的数，即6-1=5;要使☆最小，余数△也应取最小值。由于余数大于0，所以△最小是1，根据\u0027被除数=商×除数+余数\u0027，此时商是4，除数是6，余数是1，那么☆最小为4×6+1。\n\n【详解】在☆÷6=4……△中，余数最大是6-1=5。要保证☆最小，那么余数也应取最小值1，4×6+1=24+1=25。在☆÷6=4……△中，△最大是5，☆最小是25。",
+        "knowledge_points":  [
+                                 "余数与除数的关系",
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "24-25 二年级下·内蒙古赤峰·期末"
+    },
+    {
+        "id":  "227",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "小芳有一串珠子，按1红2绿3黄的顺序排列，第51颗珠子是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "绿",
+        "solution":  "【分析】根据题意可知，每组以1红2绿3黄共6颗珠子循环，计算出第51颗珠子是第几组再多几颗，多出的几颗就是每组循环中的第几颗珠子，即可判断其颜色。\n\n【详解】由分析可得:1+2+3=6(颗);51÷6=8(组)……3(颗)，则余数是3，为每组的第3颗珠子，颜色是绿。由此可知，小芳有一串珠子，按1红2绿3黄的顺序排列，第51颗珠子是绿。",
+        "knowledge_points":  [
+                                 "有余数除法的实际应用",
+                                 "周期问题"
+                             ],
+        "source":  "24-25 二年级下·内蒙古赤峰·期末"
+    },
+    {
+        "id":  "228",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "禁渔期间，码头要挂上\u0027休渔旗\u0027，小江在码头按\u0027一黄二蓝三红\u0027为一组的规律挂旗，如果第1面旗子是黄色，第2面旗子是蓝色的。那么第18面旗是( )色的，第53面旗是( )色的。",
+        "options":  [
+
+                    ],
+        "answer":  "红;红",
+        "solution":  "【分析】根据题意可知，按照\u0027一黄二蓝三红\u00276面旗子为一组循环，求第几面旗是什么颜色，用第几除以6，若没有余数，则是这组中的最后一面旗;若有余数，余数是几就是下一组中的第几面，据此解答。\n\n【详解】1+2+3=6(面);18÷6=3(组)，第18面旗是第3组中最后一个，即红色;53÷6=8(组)……5(面)，第53面旗是第9组中第5个，即红色。因此，禁渔期间，码头要挂上\u0027休渔旗\u0027，小江在码头按\u0027一黄二蓝三红\u0027为一组的规律挂旗，如果第1面旗子是黄色，第2面旗子是蓝色的。那么第18面旗是红色的，第53面旗是红色的。",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算",
+                                 "有余数除法的实际应用",
+                                 "周期问题"
+                             ],
+        "source":  "24-25二年级下·浙江台州·期末"
+    },
+    {
+        "id":  "229",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "渔民李叔叔打捞了45条鱼，至少再打( )条鱼，就可以平均分给7家饭店：或者至少拿走( )条，剩下的也可以平均分给7家饭店。",
+        "options":  [
+
+                    ],
+        "answer":  "4;3",
+        "solution":  "【分析】由题意可知：用鱼的总数量÷饭店的数量，求得的余数加上几凑够7，即用7减去余数即可，就是至少要再打鱼的条数;求得的余数就是至少拿走鱼的条数，据此解答。\n\n【详解】由分析可得:45÷7=6(条)……3(条)，7-3=4(条)。渔民李叔叔打捞了45条鱼，至少再打4条鱼，就可以平均分给7家饭店;或者至少拿走3条，剩下的也可以平均分给7家饭店。",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算",
+                                 "有余数除法的实际应用"
+                             ],
+        "source":  "24-25二年级下·浙江台州·期末"
+    },
+    {
+        "id":  "230",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "若●÷6=9……◯，◯最大是( )，这时●是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "5;59",
+        "solution":  "【分析】在有余数的除法中，最大的余数=除数-1，再根据被除数=商×除数+余数，求出被除数即可。\n\n【详解】若●÷6=9……◯，◯最大是6-1=5;6×9+5=54+5=59。所以，若●÷6=9……◯，◯最大是5，这时●是59。",
+        "knowledge_points":  [
+                                 "余数与除数的关系",
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "24-25 二年级下·浙江台州·期末"
+    },
+    {
+        "id":  "231",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "妈妈准备用烤箱烤30个月饼，烤箱每次最多可以烤4个，她至少要烤( )次。",
+        "options":  [
+
+                    ],
+        "answer":  "8",
+        "solution":  "【分析】30里面有几个4，就说明最多烤4个的情况有几次，用除法计算。如果有余数，余下的月饼也需要再烤一次;据此解答。\n\n【详解】根据分析:30÷4=7(次)……2(个)，7+1=8(次)。所以妈妈准备用烤箱烤30个月饼，烤箱每次最多可以烤4个，她至少要烤8次。",
+        "knowledge_points":  [
+                                 "有余数除法的实际应用",
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "24-25三年级下·广西南宁·期末"
+    },
+    {
+        "id":  "232",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在□÷7=6……□中，余数最大是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "6",
+        "solution":  "【分析】在有余数的除法中，余数必须比除数小。除数是7，余数最大是6。\n\n【详解】由分析可知:7-1=6。即，在□÷7=6……□中，余数最大是6。",
+        "knowledge_points":  [
+                                 "余数与除数的关系"
+                             ],
+        "source":  "24-25 二年级下·甘肃天水·期末"
+    },
+    {
+        "id":  "233",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在( )÷7=9……( )中，被除数最大是( )，被除数最小是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "69;64",
+        "solution":  "【分析】在有余数的除法中，余数一定要比除数小，最大的余数=除数-1，最小的余数是1，再根据被除数=商×除数+余数，求出被除数即可。\n\n【详解】7-1=6，余数最大是6，最小是1;7×9+6=63+6=69，当余数是6时，被除数最大是69;7×9+1=63+1=64，当余数是1时，被除数最小是64。在( )÷7=9……( )中，被除数最大是69，被除数最小是64。",
+        "knowledge_points":  [
+                                 "余数与除数的关系",
+                                 "100以内有余数的除法计算",
+                                 "有余数的除法验算"
+                             ],
+        "source":  "24-25二年级下·贵州黔东南·期末"
+    },
+    {
+        "id":  "234",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "一个星期有7天，11月有30天，有( )个星期，还有( )天。",
+        "options":  [
+
+                    ],
+        "answer":  "4;2",
+        "solution":  "【分析】根据题意可知：用11月共有的天数除以一星期有的天数，求出商和余数，商为星期的数量，余数为剩余的天数。\n\n【详解】30÷7=4(个)……2(天)。则一个星期有7天，11月有30天，有4个星期，还有2天。",
+        "knowledge_points":  [
+                                 "有余数除法的实际应用"
+                             ],
+        "source":  "24-25 二年级下·辽宁鞍山·期末"
+    },
+    {
+        "id":  "235",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "☆÷9=□……△，△最大是( )，如果□是3，此时☆是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "8;35",
+        "solution":  "【分析】在☆÷9=□……△中，△是余数，余数要小于除数，最大的余数是比除数少1的数，所以用9-1求出最大余数是8。如果商是3，求此时被除数是多少，根据被除数=除数×商+余数即可解答。\n\n【详解】9-1=8;9×3+8=27+8=35。☆÷9=□……△，△最大是8，如果□是3，此时☆是35。",
+        "knowledge_points":  [
+                                 "余数与除数的关系",
+                                 "有余数的除法验算"
+                             ],
+        "source":  "24-25 二年级下·湖北武汉·期末"
+    },
+    {
+        "id":  "236",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在算式□÷4=6……□中，余数最大是( )，这时被除数是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "3;27",
+        "solution":  "【分析】有余数除法中，余数一定比除数小，该题中除数是4，则余数最大是比除数小1的数，即4-1=3，然后根据被除数=商×除数+余数即可求得。\n\n【详解】4-1=3;6×4+3=24+3=27。则在算式□÷4=6……□中，余数最大是3，这时被除数是27。",
+        "knowledge_points":  [
+                                 "余数与除数的关系",
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "24-25 二年级下·内蒙古呼伦贝尔·期末"
+    },
+    {
+        "id":  "237",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "学校买来26个梨，平均分给4个小朋友，每个小朋友分( )个，还剩( )个。",
+        "options":  [
+
+                    ],
+        "answer":  "6;2",
+        "solution":  "【分析】用买来的梨数量除以小朋友的数量，求出商和余数，商表示每个小朋友分得梨数量，余数表示还剩的数量。\n\n【详解】26÷4=6(个)……2(个)。即，学校买来26个梨，平均分给4个小朋友，每个小朋友分6个，还剩2个。",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算",
+                                 "有余数除法的实际应用"
+                             ],
+        "source":  "24-25 二年级下·云南昭通·期末"
+    },
+    {
+        "id":  "238",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "□÷7=5……☆，☆最大是( )，这时□是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "6;41",
+        "solution":  "【分析】在有余数的除法算式中，余数必须比除数小，并且不能是0。在□÷7=5……☆中，除数是7，因此余数☆最大是6;用\u0027除数×商+余数\u0027即可求出被除数的值。\n\n【详解】由分析可知：在□÷7=5……☆中，除数是7，余数最大是6;5×7+6=35+6=41。□÷7=5……☆，☆最大是6，这时□是41。",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算",
+                                 "余数与除数的关系"
+                             ],
+        "source":  "24-25 二年级下·黑龙江佳木斯·期末"
+    },
+    {
+        "id":  "239",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "60朵纸花，平均分给9个小朋友。每人分( )朵，还剩( )朵。",
+        "options":  [
+
+                    ],
+        "answer":  "6;6",
+        "solution":  "【分析】根据有余数除法的意义，纸花的总数÷小朋友的人数=每个小朋友可以分到的纸花数量，余数是剩余的纸花数量，列出算式算出答案即可。\n\n【详解】60÷9=6(朵)……6(朵)。所以，每人分6朵，还剩6朵。",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "24-25二年级下·湖南长沙·期末"
+    },
+    {
+        "id":  "240",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "在算式□÷5=8……△中，余数最大是( )，这时被除数是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "4;44",
+        "solution":  "【分析】根据余数必须比除数小，可知余数一定要小于5，找出△能够取的最大数。再根据商×除数+余数=被除数，列出算式算出被除数即可解答。\n\n【详解】根据分析可得:△最大可以为4;8×5+4=40+4=44。所以，在算式□÷5=8……△中，余数最大是4，这时被除数是44。",
+        "knowledge_points":  [
+                                 "乘加",
+                                 "乘减混合运算",
+                                 "余数与除数的关系"
+                             ],
+        "source":  "24-25 二年级下·河北张家口·期末"
+    },
+    {
+        "id":  "241",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "袋子里的糖果比20颗多比30颗少，每人分6颗，多1颗，袋子里的糖果有( )颗，再增加( )颗就可以再分一个人。",
+        "options":  [
+
+                    ],
+        "answer":  "25;5",
+        "solution":  "【分析】根据题意，糖果的总数量÷平均分的人数=6(颗)……1(颗)，也就是平均分的人数×6+1=糖果的总数量。根据6的乘法口诀，找出结果比20大比30小的数就是糖果的数量;最后用每人分到糖果的数量减去多的1颗，求出差，就是再增加几颗就可以再分一个人。\n\n【详解】3×6+1=18+1=19，19\u003c20，糖果有19颗，不符合题意;4×6+1=24+1=25，20\u003c25\u003c30，糖果有25颗，符合题意;5×6+1=30+1=31，31\u003e30，糖果有31颗，不符合题意;6-1=5(颗)。即，袋子里的糖果比20颗多比30颗少，每人分6颗，多1颗，袋子里的糖果有25颗，再增加5颗就可以再分一个人。",
+        "knowledge_points":  [
+                                 "100以内数的比大小",
+                                 "100以内有余数的除法计算",
+                                 "有余数除法的实际应用"
+                             ],
+        "source":  "24-25 二年级下·湖南株洲·期末"
+    },
+    {
+        "id":  "242",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "☆÷7=4……○，○最大是( )，这时☆是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "6;34",
+        "solution":  "【分析】根据余数要比除数小，除数是7，余数○最大比7小1;根据被除数=商×除数+余数，求出☆;据此解答。\n\n【详解】由分析可得:7-1=6，余数最大是6;7×4+6=28+6=34。☆÷7=4……○，○最大是6，这时☆是34。",
+        "knowledge_points":  [
+                                 "余数与除数的关系",
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "24-25 二年级下·湖南株洲·期末"
+    },
+    {
+        "id":  "243",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "下面是小云调查二(2)班全部同学出生季节的结果。\n![](images/3b91e26f8f3bb831d6a3643086d9f022483085a8d35663cbbd7195e2f012cca5.jpg)\n(1)把上面的调查结果填在表中。\n\n| 季节 | 春 | 夏 | 秋 | 冬 |\n| ---- | ---- | ---- | ---- | ---- |\n| 人数 | | | | |\n\n(2)二(2)班一共有( )名同学，其中在( )季出生的人数最多，在( )季出生的人数最少。\n(3)二(2)班全部同学参加\u0027报季节\u0027游戏，按\u0027春，夏，秋，冬，春，夏，秋，冬\u0027的顺序，每人报一个，最后一名同学报的是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "9;12;5;7;33;夏;秋;春",
+        "solution":  "【分析】(1)依次数出在每个季节出生的人数填表即可，\u0027正\u0027字的每一笔代表1人;(2)将每个季节出生的人数相加就是参与调查的总人数;比较每个季节出生的人数，找出出生人数最多的和最少的;(3)根据除法的意义，用总人数除以4，得出的商就是报\u0027春，夏，秋，冬\u0027的循环数，若没有余数，则最后一个人报的就是\u0027冬\u0027;若有余数，余数是几，则找出对应的季节即可。\n\n【详解】(1)把上面的调查结果填在表中。\n\n| 季节 | 春 | 夏 | 秋 | 冬 |\n| ---- | ---- | ---- | ---- | ---- |\n| 人数 | 9 | 12 | 5 | 7 |\n\n(2)9+12+5+7=21+5+7=26+7=33(名)。所以二(2)班一共有33名同学。12\u003e9\u003e7\u003e5，所以其中在夏季出生的人数最多，在秋季出生的人数最少。\n(3)33÷4=8(组)……1(人)。所以二(2)班全部同学参加\u0027报季节\u0027游戏，按\u0027春，夏，秋，冬，春，夏，秋，冬\u0027的顺序，每人报一个，最后一名同学报的是春。",
+        "knowledge_points":  [
+                                 "数据的搜集与整理",
+                                 "100以内数的连加运算",
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "24-25 二年级下·陕西渭南·期末"
+    },
+    {
+        "id":  "244",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "○÷7=5……□，□里最大填( )，这时○=( )。",
+        "options":  [
+
+                    ],
+        "answer":  "6;41",
+        "solution":  "【分析】在有余数的除法中，余数必须小于除数。已知除数是7，余数□最大为6。根据被除数=除数×商+余数，可求出○的值。\n\n【详解】7-1=6;7×5+6=35+6=41。即，○÷7=5……□，□里最大填6，这时○=41。",
+        "knowledge_points":  [
+                                 "余数与除数的关系",
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "24-25 二年级下·陕西延安·期末"
+    },
+    {
+        "id":  "245",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "在算式□÷6=○……○中，○最大是( )，此时□等于( )。",
+        "options":  [
+
+                    ],
+        "answer":  "5;35",
+        "solution":  "【分析】根据在有余数的除法中，余数一定要比除数小，当此时的除数为6时，余数要比6小，余数最大为5，由此即可解答。\n\n【详解】根据分析可得:○最大是5，则□÷6=5……5，5×6+5=30+5=35。则，被除数为35。所以，在算式□÷6=○……○中，○最大是5，此时□等于35。",
+        "knowledge_points":  [
+                                 "余数与除数的关系",
+                                 "乘加",
+                                 "乘减混合运算"
+                             ],
+        "source":  "24-25二年级下·贵州铜仁·期末"
+    },
+    {
+        "id":  "246",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "学校购买了43个篮球，至少再买( )个，正好可以平均分给7个班级。",
+        "options":  [
+
+                    ],
+        "answer":  "6",
+        "solution":  "【分析】根据题意，有43个篮球，求至少再买几个能正好平均分给7个班，用篮球的总数量÷平均分给班级的数量，求出结果，得的余数加上几凑够7，即用7减去余数即可，就是至少要再买篮球的数量;据此解答。\n\n【详解】根据分析可得:43÷7=6(个)……1(个)，7-1=6(个)。因此，学校计划购买43个篮球，至少再买6个，正好可以平均分给7个班级。",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算",
+                                 "有余数除法的实际应用"
+                             ],
+        "source":  "24-25 二年级下·重庆梁平·期末"
+    },
+    {
+        "id":  "247",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "一天晚上，明明和爸爸妈妈围坐在一张桌子旁包汤圆，他们一共包了20个汤圆，平均每人分得( )个，还剩( )个，如果每人吃8个，还要再包( )个。",
+        "options":  [
+
+                    ],
+        "answer":  "6;2;4",
+        "solution":  "【分析】根据100以内有余数除法的意义，汤圆的总数量÷总人数=每个人能平均分到的汤圆数量，余数是剩余的汤圆数量。根据乘法的意义，每个人要吃的汤圆数量×总人数=需要包的汤圆总数量，再根据需要包的汤圆总数量-现在已经包了的汤圆数量=还需要包的汤圆数量，由此列式解答。\n\n【详解】20÷3=6(个)……2(个);8×3-20=24-20=4(个)。所以，平均每人分得6个，还剩2个，如果每人吃8个，还要再包4个。",
+        "knowledge_points":  [
+                                 "表内乘加",
+                                 "乘减",
+                                 "100以内有余数的除法计算",
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·河北唐山·期末"
+    },
+    {
+        "id":  "248",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "☆÷8=3……□，□最大是( );△÷○=6……5，○最小是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "7;6",
+        "solution":  "【分析】由题意可知：在有余数除法中，余数要比除数小;余数最大是除数减1;除数最小是余数+1;当除数是8，余数最大是8-1=7;当余数是5，除数最小是5+1=6;据此可解。\n\n【详解】由分析可得:☆÷8=3……□，□最大是7;△÷○=6……5，○最小是6。",
+        "knowledge_points":  [
+                                 "余数与除数的关系"
+                             ],
+        "source":  "24-25 二年级下·河北唐山·期末"
+    },
+    {
+        "id":  "249",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "有25枝玫瑰花，每个花瓶插3枝，需要( )个花瓶，还剩( )枝花。",
+        "options":  [
+
+                    ],
+        "answer":  "8;1",
+        "solution":  "【分析】根据题意，玫瑰花的总枝数除以每个花瓶插的枝数，求出结果，商是需要花瓶的个数，余数是还剩下玫瑰花的枝数，据此解答。\n\n【详解】根据分析可得:25÷3=8(个)……1(枝)。因此，有25枝玫瑰花，每个花瓶插3枝，需要8个花瓶，还剩1枝花。",
+        "knowledge_points":  [
+                                 "有余数除法的实际应用",
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "24-25二年级下·广东云浮·期末"
+    },
+    {
+        "id":  "250",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "学校买了46盆花，至少拿走( )盆，才能正好平均分给7个班;至少再买( )盆，才能每班多分1盆。",
+        "options":  [
+
+                    ],
+        "answer":  "4;3",
+        "solution":  "【分析】根据题意，求至少拿走几盆才能正好平均分给7个班，用总数量除以班级的数量，求得的余数就是至少要拿走的盆数;求至少再买几盆才能每班多分1盆，也就是把余数凑成7，每班就能多1盆，用7减去余数计算即可。\n\n【详解】46÷7=6(盆)……4(盆);7-4=3(盆)。学校买了46盆花，至少拿走4盆，才能正好平均分给7个班;至少再买3盆，才能每班多分1盆。",
+        "knowledge_points":  [
+                                 "有余数除法的实际应用",
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "24-25 二年级下·天津河西·期末"
+    },
+    {
+        "id":  "251",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "如果○÷△=□……4，那么△代表的数最小是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "5",
+        "solution":  "【分析】根据有余数的除法算式为：被除数÷除数=商……余数，其中余数一定比除数小，除数最小是比余数大1的数。\n\n【详解】4+1=5。如果○÷△=□……4，那么△代表的数最小是5。",
+        "knowledge_points":  [
+                                 "余数与除数的关系"
+                             ],
+        "source":  "24-25 二年级下·天津河西·期末"
+    },
+    {
+        "id":  "252",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "一支铅笔的价格是8角，6元最多可以买( )支铅笔；有30只鸽子，每4只装1个笼子，装这些鸽子一共需要( )个笼子。",
+        "options":  [
+
+                    ],
+        "answer":  "7;8",
+        "solution":  "【分析】先根据1元=10角，把6元换算成60角，再用60角除以一支铅笔的价格，商即为最多可以买的铅笔支数，余数为剩下的钱；用鸽子的总只数除以1个笼子装的鸽子只数，如果没有余数，那么商即为需要的笼子个数，如果有余数，还要用商加1，因为剩下的鸽子虽然不能装满一个笼子，但是也需要用一个笼子去装。\n\n【详解】6元=60角；60÷8=7(支)……4(角)。一支铅笔的价格是8角，6元最多可以买(7)支铅笔。30÷4=7(个)……2(只)，7+1=8(个)。有30只鸽子，每4只装1个笼子，装这些鸽子一共需要(8)个笼子。",
+        "knowledge_points":  [
+                                 "元，角，分的认识及换算",
+                                 "有余数除法的实际应用",
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "24-25二年级下·天津静海·期末"
+    },
+    {
+        "id":  "253",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "□÷6=7……□，余数最大是( )，当余数最大时，被除数是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "5;47",
+        "solution":  "【分析】在有余数的除法计算中，最大的余数=除数-1，最小的余数是1；再根据被除数=商×除数+余数，求出对应的被除数，据此解答。\n\n【详解】□÷6=7……□，余数最大是6-1=5；6×7+5=42+5=47。□÷6=7……□，余数最大是5，当余数最大时，被除数是47。",
+        "knowledge_points":  [
+                                 "余数与除数的关系",
+                                 "100以内有余数的除法计算",
+                                 "有余数的除法验算"
+                             ],
+        "source":  "24-25 二年级下·广东汕尾·期末"
+    },
+    {
+        "id":  "254",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "40个苹果，平均分给6人，每人能分到( )个，还剩( )个。",
+        "options":  [
+
+                    ],
+        "answer":  "6;4",
+        "solution":  "【分析】用苹果的总个数除以平均分给的人数，求出商和余数，商就是每人能分到几个，余数就是还剩的个数，据此解答。\n\n【详解】40÷6=6(个)……4(个)。40个苹果，平均分给6人，每人能分到6个，还剩4个。",
+        "knowledge_points":  [
+                                 "有余数除法的实际应用",
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "24-25 二年级下·广东揭阳·期末"
+    },
+    {
+        "id":  "255",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "□÷4=5……△，当△最大时，□应该是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "23",
+        "solution":  "【分析】在有余数的除法中，余数最大=除数-1；此时，被除数=商×除数+余数。\n\n【详解】4-1=3，所以△最大是3；4×5+3=20+3=23。所以当△最大时，□应该是23。",
+        "knowledge_points":  [
+                                 "表内乘加",
+                                 "乘减",
+                                 "余数与除数的关系"
+                             ],
+        "source":  "24-25 二年级下·广东佛山·期末"
+    },
+    {
+        "id":  "256",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "8月有31天，即它有4个星期，还多3天。( )",
+        "options":  [
+
+                    ],
+        "answer":  "√",
+        "solution":  "【分析】根据题意，用8月份的总天数31除以每个星期的天数7，商就是8月有几个星期，余数是还多的天数。\n\n【详解】31÷7=4(个)……3(天)。8月有31天，即它有4个星期，还多3天，原题说法正确。故答案为:√",
+        "knowledge_points":  [
+                                 "有余数除法的实际应用",
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "24-25二年级下·广东潮州·期末"
+    },
+    {
+        "id":  "257",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "35÷6和50÷9的商相同，余数也相同。( )",
+        "options":  [
+
+                    ],
+        "answer":  "√",
+        "solution":  "【分析】分别计算出35÷6和50÷9的商和余数各是多少，再比较商和余数是否相同，据此解答。\n\n【详解】35÷6=5……5，商是5，余数是5；50÷9=5……5，商是5，余数是5。35÷6和50÷9的商相同，余数也相同，原题说法正确。故答案为:√",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "24-25 二年级下·广东揭阳·期末"
+    },
+    {
+        "id":  "258",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "判断题",
+        "difficulty":  0.65,
+        "question":  "在除法算式中余数不能比除数小。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】在有余数的除法中，余数必须比除数小，据此判断。\n\n【详解】在除法算式中，余数必须比除数小，这是除法的基本规则。例如，11÷2=5……1，余数1小于除数2。若余数等于或大于除数，则说明商需要调整，余数应重新计算。原题说法错误。故答案为:×",
+        "knowledge_points":  [
+                                 "余数与除数的关系"
+                             ],
+        "source":  "24-25二年级下·甘肃兰州·期末"
+    },
+    {
+        "id":  "259",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "判断题",
+        "difficulty":  0.65,
+        "question":  "1千克葡萄要8元钱，林阿姨现在有30元钱，最多可以买4千克葡萄。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】用现有的钱数(30元)除以每千克葡萄的钱数(8元)，求出商和余数，商表示买到的整千克数，余数表示不够买1千克葡萄的钱。\n\n【详解】30÷8=3(千克)……6(元)。也就是30元钱最多可以买3千克葡萄，不到4千克。1千克葡萄要8元钱，林阿姨现在有30元钱，最多可以买4千克葡萄，此说法错误。故答案为:×",
+        "knowledge_points":  [
+                                 "有余数除法的实际应用",
+                                 "100以内有余数的除法计算",
+                                 "经济问题"
+                             ],
+        "source":  "24-25二年级下·广东汕头·期末"
+    },
+    {
+        "id":  "260",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "判断题",
+        "difficulty":  0.65,
+        "question":  "□÷9=□……□，余数最大应该是7。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】根据有余数除法的定义，余数必须小于除数。除数是9，余数必须小于9，最大可以为8。\n\n【详解】根据分析可得:□÷9=□……□，余数最大应该是8。原说法错误。故答案为:×",
+        "knowledge_points":  [
+                                 "余数与除数的关系"
+                             ],
+        "source":  "24-25二年级下·广东汕头·期末"
+    },
+    {
+        "id":  "261",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "32÷4=7……4读作：三十二除以四等于七余四。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】有余数的除法中，余数必须比除数小。题目中除数是4，余数是4，余数等于除数，不符合要求，因此算式错误。\n\n【详解】由分析可知：在算式32÷4=7……4中，余数4等于除数4，不符合余数必须比除数小的规则。正确的应为:32÷4=8，读作：三十二除以四等于八。原题说法错误。故答案为:×",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算",
+                                 "余数与除数的关系",
+                                 "有余数除法的认识"
+                             ],
+        "source":  "24-25 二年级下·甘肃天水·期末"
+    },
+    {
+        "id":  "262",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "被除数=商×除数+余数。( )",
+        "options":  [
+
+                    ],
+        "answer":  "√",
+        "solution":  "【分析】除法是乘法的逆运算，可以运用乘法来验算除法：在有余数的除法中，先算出除数与商的积，再加上余数与被除数比较即可，据此可判断。\n\n【详解】由分析可得：被除数=商×除数+余数。比如，25÷6=4……1，6×4+1=24+1=25。故答案为:√",
+        "knowledge_points":  [
+                                 "乘，除法的意义和各部分间的关系",
+                                 "有余数的除法验算",
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "24-25 二年级下·甘肃天水·期末"
+    },
+    {
+        "id":  "263",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "判断题",
+        "difficulty":  0.65,
+        "question":  "29+4=7……3。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】本题考查加法运算的正确性。题目给出算式“29+4=7……3”，其中“……”表示余数，但加法运算不涉及余数，余数是除法中的概念，因此此算式明显是错误的。\n\n【详解】由分析可知：29+4=33，不应写成29+4=7……3。原题说法错误。故答案为:×",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "24-25 二年级下·陕西延安·期末"
+    },
+    {
+        "id":  "264",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "判断题",
+        "difficulty":  0.65,
+        "question":  "每个瓶子能装5千克油，有48千克油只能装满9瓶。( )",
+        "options":  [
+
+                    ],
+        "answer":  "√",
+        "solution":  "【分析】根据100内有余数的除法，48千克油能装满的瓶数=油的总质量÷平均每瓶能装的质量，余数是还剩下的质量。\n\n【详解】48÷5=9(瓶)……3(千克)。所以，每个瓶子能装5千克油，有48千克油只能装满9瓶的说法正确。故答案为:√",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "24-25 二年级下·浙江台州·期末"
+    },
+    {
+        "id":  "265",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "□÷7=3……□的余数可能是8。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】在有余数的除法中，余数必须小于除数，本题中除数是7，余数应小于7，所以余数不可能是8。\n\n【详解】□÷7=3……□的余数必须比7小，不可能是8，原题说法错误。故答案为:×",
+        "knowledge_points":  [
+                                 "余数与除数的关系"
+                             ],
+        "source":  "24-25 二年级下·广东江门·期末"
+    },
+    {
+        "id":  "266",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "50÷6=7……8。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】在有余数的除法中，余数必须比除数小。结合题干要求进行解答即可。\n\n【详解】根据对有余数除法的认识可知：余数要比除数小，题干中除数是6，余数是8，8\u003e6，余数大于除数，所以题干说法错误。故答案为:×",
+        "knowledge_points":  [
+                                 "余数与除数的关系"
+                             ],
+        "source":  "24-25 二年级下·陕西渭南·期末"
+    },
+    {
+        "id":  "267",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "在有余数的除法算式中，余数一定要大于除数。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】在有余数的除法中，余数必须小于除数，这是除法运算的基本规则。若余数等于或大于除数，说明商还可以继续增加，余数需要调整到小于除数的范围。\n\n【详解】由分析可知：在有余数的除法算式中，余数必须小于除数，原题说法错误。故答案为: ×",
+        "knowledge_points":  [
+                                 "余数与除数的关系"
+                             ],
+        "source":  "24-25 二年级下·广西玉林·期末"
+    },
+    {
+        "id":  "268",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "在有余数的除法算式中，除数是8，余数有7种可能。( )",
+        "options":  [
+
+                    ],
+        "answer":  "√",
+        "solution":  "【分析】在有余数的除法中，余数必须小于除数且大于0。除数是8时，余数可能是1、2、3、4、5、6、7，共7种情况。\n\n【详解】由分析可知：在有余数的除法算式中，除数是8，余数可能是1、2、3、4、5、6、7，共7种情况。原题说法正确。故答案为:√",
+        "knowledge_points":  [
+                                 "余数与除数的关系"
+                             ],
+        "source":  "24-25 二年级下·广西玉林·期末"
+    },
+    {
+        "id":  "269",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "判断题",
+        "difficulty":  0.65,
+        "question":  "因为8×4+5=37，所以37÷4=8……5。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】计算有余数除法时，余数比除数小。本题余数5大于除数4，得数不正确。\n\n【详解】因为余数要比除数小，所以37÷4不可能等于8……5。37÷4=9……1。原题说法错误。故答案为:×",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算",
+                                 "余数与除数的关系"
+                             ],
+        "source":  "24-25 二年级下·湖南株洲·期末"
+    },
+    {
+        "id":  "270",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "计算题",
+        "difficulty":  0.65,
+        "question":  "列竖式计算。\n55÷9= 31÷4= 50+6= 48÷6= 44÷5= 77+8=",
+        "options":  [
+
+                    ],
+        "answer":  "6……1;7……3;56;8;8……4;85",
+        "solution":  "【分析】用竖式计算除法的计算方法：一商，二乘，三减，四比。(1)商：即试商，想除数和几相乘最接近被除数且小于被除数，那么商就是几，写在被除数的个位的上面；(2)乘：把除数和商相乘，将得数写在被除数下面；(3)减：用被除数减去商与除数的乘积，所得的差写在横线的下面；(4)比：将余数与除数比一比，余数必须比除数小。根据100以内整数加减法运算，计算时要注意相同数位对齐，加法则从个位开始计算，满十则向前一位进1，据此解答即可。\n\n【详解】55÷9=6……1;31÷4=7……3;50+6=56;48÷6=8;44÷5=8……4;77+8=85。![](images/9f88778e61202adf117ebf0d610bccba.png)",
+        "knowledge_points":  [
+                                 "整十数加",
+                                 "减一位数",
+                                 "一位数与两位数的进位加法",
+                                 "用7~9的乘法口诀求商",
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "24-25 二年级下·辽宁鞍山·期末"
+    },
+    {
+        "id":  "271",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "计算题",
+        "difficulty":  0.85,
+        "question":  "列竖式计算。\n40÷8= 58÷6= 66÷9=",
+        "options":  [
+
+                    ],
+        "answer":  "5;9……4;7……3",
+        "solution":  "【分析】100以内数除法列竖式计算，用乘法口诀来试商，商要与被除数的个位对齐，若有余数，余数要小于除数。有余数的除法的计算方法：一商，二乘，三减，四比。(1)商：即试商，想除数和几相乘最接近被除数且小于被除数，那么商就是几，写在被除数的个位的上面；(2)乘：把除数和商相乘，将得数写在被除数下面；(3)减：用被除数减去商与除数的乘积，所得的差写在横线的下面；(4)比：将余数与除数比一比，余数必须比除数小。\n\n【详解】40÷8=5;58÷6=9……4;66÷9=7……3。![](images/d15cf592580750ed135c9907437a4538.png)",
+        "knowledge_points":  [
+                                 "用7~9的乘法口诀求商",
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "24-25 二年级下·浙江台州·期末"
+    },
+    {
+        "id":  "272",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "计算题",
+        "difficulty":  0.65,
+        "question":  "列竖式计算。\n33÷9= 48÷6= 55÷8=",
+        "options":  [
+
+                    ],
+        "answer":  "3……6;8;6……7",
+        "solution":  "【分析】除法用竖式计算时，从最高位开始除起，若除不了，那么就用最高位和下一位合成一个数来除，直到能除以除数为止；有余数的除法的计算方法：一商，二乘，三减，四比。(1)商：即试商，想除数和几相乘最接近被除数且小于被除数，那么商就是几，写在被除数的个位的上面；(2)乘：把除数和商相乘，将得数写在被除数下面；(3)减：用被除数减去商与除数的乘积，所得的差写在横线的下面；(4)比：将余数与除数比一比，余数必须比除数小。\n\n【详解】33÷9=3……6;48÷6=8;55÷8=6……7。![](images/3834409454e8c259ec2a6b73d08bb438.png)",
+        "knowledge_points":  [
+                                 "用7~9的乘法口诀求商",
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "24-25 二年级下·广东汕尾·期末"
+    },
+    {
+        "id":  "273",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "长江码头举办美味包子促销活动，4个鱼肉包子、5个虾肉包子、6个素包子装成一个礼盒，仓库共有鱼肉包子34个，虾肉包子36个，素包子45个，最多可以装多少个礼盒。",
+        "options":  [
+
+                    ],
+        "answer":  "7个",
+        "solution":  "【分析】由题意可知：用总数除以每盒所需的个数，求出的商分别是鱼肉包子、虾肉包子、素包子可以装的礼盒数，再作比较，最少的礼盒数就是最多可以装的礼盒数，据此解答。\n\n【详解】由分析可得:34÷4=8(盒)……2(个);36÷5=7(盒)……1(个);45÷6=7(盒)……3(个)。7\u003c8，所以最多可以装7个礼盒。",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算",
+                                 "有余数除法的实际应用"
+                             ],
+        "source":  "24-25二年级下·浙江台州·期末"
+    },
+    {
+        "id":  "274",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "老师把47本图画书平均分给6个同学，每个同学分到几本。还剩多少本。\n答：每个同学分到( )本，还剩( )本。",
+        "options":  [
+
+                    ],
+        "answer":  "7;5",
+        "solution":  "【分析】根据题意，图画书的总数量÷平均分的人数=每人分到的数量，余数表示剩余的数量。\n\n【详解】47÷6=7(本)……5(本)。答：每个同学分到7本，还剩5本。",
+        "knowledge_points":  [
+                                 "有余数除法的实际应用",
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "24-25 二年级下·湖北襄阳·期末"
+    },
+    {
+        "id":  "275",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "二年(1)班有38人乘车去春游，至少需要租几辆车。\n![](images/daee4885b707096afb9f071d51026e61.png)",
+        "options":  [
+
+                    ],
+        "answer":  "6辆",
+        "solution":  "【分析】根据100以内有余数的除法的意义，总人数÷每辆车最多能承载的人数=能坐满的车子的数量。剩余的人数需要再租一辆车，由此列出算式计算出答案即可。\n\n【详解】38÷7=5(辆)……3(人)，5+1=6(辆)。答：至少需要租6辆车。",
+        "knowledge_points":  [
+                                 "图文问题",
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "24-25 二年级下·广东揭阳·期末"
+    },
+    {
+        "id":  "276",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "六一儿童节二(1)班买来了52个文具盒作为奖品。每盒装8个文具盒，这些文具盒全部装完，至少需要准备几个盒子。",
+        "options":  [
+
+                    ],
+        "answer":  "7个",
+        "solution":  "【分析】用文具盒的总数量除以每盒可以装的数量，求出商和余数，商再加上1个盒子，就是至少需要的盒子的总数量，据此解答。\n\n【详解】52÷8=6(盒)……4(个)，6+1=7(盒)。答：至少需要准备7个盒子。",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算",
+                                 "有余数除法的实际应用"
+                             ],
+        "source":  "24-25 二年级下·贵州黔东南·期末"
+    },
+    {
+        "id":  "277",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "西红柿每千克6元，妈妈带了40元，可以买几千克西红柿，还剩几元。\n答：可以买( )千克西红柿，还剩( )元。",
+        "options":  [
+
+                    ],
+        "answer":  "6;4",
+        "solution":  "【分析】根据100以内有余数的除法，妈妈带的总金额÷每千克西红柿的单价=能够购买的西红柿数量，余数表示剩余的钱数，列出算式算出答案即可解答。\n\n【详解】40÷6=6(千克)……4(元)。答：可以买6千克西红柿，还剩4元。",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "24-25 二年级下·浙江台州·期末"
+    },
+    {
+        "id":  "278",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "一件上衣需要5粒纽扣，28粒纽扣最多可以钉几件上衣。",
+        "options":  [
+
+                    ],
+        "answer":  "5件",
+        "solution":  "【分析】本题属于有余数的除法应用题，用纽扣的总数量除以每件上衣需要的纽扣数量，求出商和余数，商即为答案。\n\n【详解】28÷5=5(件)……3(粒)。答：28粒纽扣最多可以钉5件上衣。",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算",
+                                 "有余数除法的实际应用"
+                             ],
+        "source":  "24-25二年级下·广东汕头·期末"
+    },
+    {
+        "id":  "279",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "快递站要配送38件大型快递，每辆快递三轮车最多只能装8件，至少需要几辆三轮车。",
+        "options":  [
+
+                    ],
+        "answer":  "5辆",
+        "solution":  "【分析】根据题意，总件数除以每辆三轮车最多装的件数，若有余数，剩余的件数也需要1辆三轮车，因此商需要加1。\n\n【详解】38÷8=4(辆)……6(件)，4+1=5(辆)。答：至少需要5辆三轮车。",
+        "knowledge_points":  [
+                                 "有余数除法的实际应用"
+                             ],
+        "source":  "24-25 二年级下·广东江门·期末"
+    },
+    {
+        "id":  "280",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "38个小朋友坐小火车，小火车里有两种车厢，动感车厢每节可以坐8人，动漫车厢每节可以坐6人。\n(1)如果全都坐动感车厢，那么至少需要几节车厢。\n(2)如果全都坐动漫车厢，那么最多可以坐满几节车厢。\n(3)动漫车厢和动感车厢搭配乘坐，怎样才能刚好坐下38个小朋友。",
+        "options":  [
+
+                    ],
+        "answer":  "5;6;4节动感车厢和1节动漫车厢",
+        "solution":  "【分析】(1)动感车厢每节可以坐8人，求38个小朋友至少需要几节车厢，根据表内除法的意义，用38÷8列式，计算要用“进一法”求结果。(2)动漫车厢每节可以坐6人，求38个小朋友最多可以坐满几节车厢，根据表内除法的意义，用38÷6列式，计算要用“去尾法”求结果。(3)动漫车厢和动感车厢搭配乘坐，求怎样才能刚好坐下38个小朋友，就看看几个8加几个6等于38，答案不唯一。\n\n【详解】(1)38÷8=4(节)……6(人)，4+1=5(节)。答：至少需要5节车厢。(2)38÷6=6(节)……2(人)。答：最多可以坐满6节车厢。(3)4×8+1×6=32+6=38(人)。答：可以坐4节动感车厢和1节动漫车厢，刚好坐下38个小朋友。(答案不唯一)。",
+        "knowledge_points":  [
+                                 "乘加",
+                                 "乘减混合运算",
+                                 "有余数除法的实际应用",
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "24-25二年级下·湖北武汉·期末"
+    },
+    {
+        "id":  "281",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "小明家装修房子，妈妈买来29米花布，准备自己做窗帘，计划每4米做一个窗帘，可做几个窗帘余几米布。",
+        "options":  [
+
+                    ],
+        "answer":  "7个;1米",
+        "solution":  "【分析】用买来的花布总长度除以每一个窗帘的长度，求出商和余数，商表示可做的窗帘数量，余数表示还剩几米布。\n\n【详解】29÷4=7(个)……1(米)。答：可做7个窗帘，余1米布。",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算",
+                                 "有余数除法的实际应用"
+                             ],
+        "source":  "24-25 二年级下·云南昭通·期末"
+    },
+    {
+        "id":  "282",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "学校在教学楼上挂一串彩灯，彩灯按红色，黄色，蓝色，绿色的顺序重复排列，你认为第42盏彩灯应该是什么颜色。",
+        "options":  [
+
+                    ],
+        "answer":  "黄色",
+        "solution":  "【分析】通过观察这组彩灯，可以发现是以“红色、黄色、蓝色、绿色”这四个颜色为一组的规律重复出现，用图形的位置数除以4，看余数是几，就是一组中的第几个图形，没有余数就是一组中的最后一个。据此即可解答。\n\n【详解】42÷4=10(组)……2(个)，说明第42盏彩灯应该是第11组中的第2个，即是黄色。答：第42盏彩灯应该是黄色。",
+        "knowledge_points":  [
+                                 "两位数除以一位数的有余数除法"
+                             ],
+        "source":  "24-25二年级下·湖南长沙·期末"
+    },
+    {
+        "id":  "283",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "学校准备将糖果装入礼盒送给同学们，如果一个礼盒里需要2块巧克力、3块水果糖和5块奶糖，这些糖最多可以装多少盒。\n![](images/e37244a7aacbf1df58104c2a807175047bea2f74ceb79134878b3643ba6cd9eb.jpg)",
+        "options":  [
+
+                    ],
+        "answer":  "4盒",
+        "solution":  "【分析】根据100内有余数的除法的意义，每个品类糖果的总数量÷盒子里该品类糖果需要装的块数=能装的盒子数量。分别算出巧克力、水果糖和奶糖能装的盒子数量，找到三种糖果中能装盒子数量最少的，就是这些糖最多能装礼盒的数量。\n\n【详解】巧克力:17÷2=8(盒)……1(块);水果糖:26÷3=8(盒)……2(块);奶糖:20÷5=4(盒)。所以，奶糖只能装4盒，则这些糖果最多能装4盒。答：这些糖最多可以装4盒。",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算",
+                                 "用2~5的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·河北张家口·期末"
+    },
+    {
+        "id":  "284",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "有36块小蛋糕，如果每人分5块，可以分给几个小朋友。还剩几块。",
+        "options":  [
+
+                    ],
+        "answer":  "7个;1块",
+        "solution":  "【分析】根据题意可知：用总数除以每人分的数量，求出商和余数，商为小朋友的数量，余数为剩下的块数。\n\n【详解】36÷5=7(个)……1(块)。答：可以分给7个小朋友，还剩1块。",
+        "knowledge_points":  [
+                                 "有余数除法的实际应用",
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "24-25 二年级下·河北张家口·期末"
+    },
+    {
+        "id":  "285",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "二(1)班一共有31人，至少需要租几条船。他们一共需要交租船费64元，每条船的租金是多少钱。\n![](images/f0e43a801d96e11b2887e19778d1ddf7.png)",
+        "options":  [
+
+                    ],
+        "answer":  "8条;8元",
+        "solution":  "【分析】用总人数除以每条船限乘人数，求出商和余数，再把商加1，求出和，就是至少需要几条船。用一共需要交租船费除以一共需要的船数量，求出商，就是每条船的租金。\n\n【详解】31÷4=7(条)……3(人)，7+1=8(条)，64÷8=8(元)。答：至少需要租8条船，每条船的租金是8元。",
+        "knowledge_points":  [
+                                 "经济问题",
+                                 "用7~9的乘法口诀求商",
+                                 "100以内有余数的除法计算",
+                                 "有余数除法的实际应用"
+                             ],
+        "source":  "24-25 二年级下·湖南株洲·期末"
+    },
+    {
+        "id":  "286",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "面塑俗称“捏面人”，是汉族民间传统艺术之一。把30个面塑作品装在盒子里，每个盒子装4个，至少需要几个盒子。",
+        "options":  [
+
+                    ],
+        "answer":  "8",
+        "solution":  "【分析】由题意得，实际上是求30里面有几个4，根据除法的意义，用30÷4进行计算即可。根据实际情况可知，若有余数，则此题应使用“进一法”保留整数。\n\n【详解】30÷4=7(个)……2(个)，7+1=8(个)。口答：至少需要8个盒子。",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算",
+                                 "有余数除法的实际应用"
+                             ],
+        "source":  "24-25 二年级下·陕西渭南·期末"
+    },
+    {
+        "id":  "287",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "花店购进58枝玫瑰花，每8枝扎成一束，最多能扎多少束。还剩几枝。\n口答：最多能扎( )束，还剩( )枝。",
+        "options":  [
+
+                    ],
+        "answer":  "7;2",
+        "solution":  "【分析】根据题意可知：用购进的花的数量除以一束花的数量求出商和余数，商为扎的束数，余数为还剩余的数量。\n\n【详解】58÷8=7(束)……2(枝)。口答：最多能扎7束，还剩2枝。",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算",
+                                 "有余数除法的实际应用"
+                             ],
+        "source":  "24-25 二年级下·陕西延安·期末"
+    },
+    {
+        "id":  "288",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "有39名同学坐观光车上山，每辆车限乘6人。至少需要几辆观光车。",
+        "options":  [
+
+                    ],
+        "answer":  "7辆",
+        "solution":  "【分析】由题意可知：用坐观光车上山的总人数除以每辆车限乘的人数，求出的商是坐满观光车的辆数，余数是剩余的人数，剩余的人还需一辆观光车，故至少需要商+1辆观光车，据此解答。\n\n【详解】由分析可得:39÷6=6(辆)……3(人)，6+1=7(辆)。答：至少需要7辆观光车。",
+        "knowledge_points":  [
+                                 "有余数除法的实际应用",
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "24-25二年级下·广东揭阳·期中"
+    },
+    {
+        "id":  "289",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "爷爷手机钱包里有38元，他准备在家族群中发6元一个的红包，最多能发几个。",
+        "options":  [
+
+                    ],
+        "answer":  "6个",
+        "solution":  "【分析】根据题意可知，用总金额除以每个红包的金额，求出结果，商是最多能发红包的数量，余数是还剩下的钱数，据此解答。\n\n【详解】38÷6=6(个)……2(元)。因为余下的2元不足以再发一个6元的红包，所以最多能发6个。答：最多能发6个。",
+        "knowledge_points":  [
+                                 "有余数除法的实际应用",
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "24-25 二年级下·广东揭阳·期中"
+    },
+    {
+        "id":  "290",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "学校买来30个篮球，每个班分4个，最多可以分给几个班。",
+        "options":  [
+
+                    ],
+        "answer":  "7个",
+        "solution":  "【分析】用篮球的总个数30除以每个班分篮球的个数4，商就是最多可以分给几个班，余数是剩下篮球的个数。\n\n【详解】30÷4=7(个)……2(个)。答：最多可以分给7个班。",
+        "knowledge_points":  [
+                                 "有余数除法的实际应用",
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "24-25二年级下·广东揭阳·期中"
+    },
+    {
+        "id":  "291",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "王老师把35根跳绳平均分给6个班，每班分几根，还剩几根。",
+        "options":  [
+
+                    ],
+        "answer":  "5根;5根",
+        "solution":  "【分析】根据题意可知：用总数除以班级数，求出商和余数，商为每班分得的根数，余数为剩下的根数。\n\n【详解】35÷6=5(根)……5(根)。答：每班分5根，还剩5根。",
+        "knowledge_points":  [
+                                 "有余数除法的实际应用",
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "24-25 二年级下·广东揭阳·期中"
+    },
+    {
+        "id":  "292",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "![](images/98b4fb8bb438d36bc764cc589f65cab6.png)\n(1)买6块毛巾，一共需要多少钱。(2)用50元可以买几个茶杯。还剩几元。(3)你还能提出其他用除法解决的数学问题并解答吗。",
+        "options":  [
+
+                    ],
+        "answer":  "30;5;5;32元可以买几双手套;4",
+        "solution":  "【分析】(1)用买的数量乘1块毛巾的价钱即可求解。(2)用总钱数除以1个茶杯的价钱，商就是可以买的茶杯个数，余数就是还剩的钱数。(3)合理即可，如：32元可以买几双手套。(答案不唯一)\n\n【详解】(1)6×5=30(元)。答：一共需要30元钱。(2)50÷9=5(个)……5(元)。答：用50元可以买5个茶杯，还剩5元。(3)32元可以买几双手套。(答案不唯一)32÷8=4(双)。答：32元可以买4双手套。",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算",
+                                 "提问题",
+                                 "填条件问题",
+                                 "经济问题",
+                                 "图文问题"
+                             ],
+        "source":  "24-25 二年级下·湖北武汉·期末"
+    },
+    {
+        "id":  "293",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "水果超市包装果篮，每2个猕猴桃、3个火龙果和5个橙子装成一个果篮，下面这些水果最多可以装多少个果篮。\n![](images/69f8ab12baf4626e4418672185234311.png)",
+        "options":  [
+
+                    ],
+        "answer":  "3个",
+        "solution":  "【分析】根据除法的意义，算出猕猴桃最多可以装几个果篮；再根据100内有余数的除法的意义，算出火龙果和橙子最多可以装几个果篮。因为果篮里三种水果都需要，则找出能装最少果篮的水果，该种水果能装的果篮数就是这三种水果能装的最多的果篮数。\n\n【详解】猕猴桃:10÷2=5(个);火龙果:20÷3=6(个)……2(个);橙子:18÷5=3(个)……3(个)。3\u003c5\u003c6。答：这些水果最多可以装3个果篮。",
+        "knowledge_points":  [
+                                 "用2~5的乘法口诀求商",
+                                 "用6的乘法口诀求商",
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "24-25 二年级下·贵州铜仁·期末"
+    },
+    {
+        "id":  "294",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "儿童节要到了，幼儿园老师要给小朋友们准备儿童节礼包。每个礼包中都有5支棒棒糖、3个果冻、2包薯片。下图中的物品最多可以包装成几个礼包。\n![](images/af88ccfa37e0c0459996adc14f44e12a.png)",
+        "options":  [
+
+                    ],
+        "answer":  "7个",
+        "solution":  "【分析】先用有余数的除法分别计算出棒棒糖按5支一组、果冻按3个一组和薯片按2包一组，各自最多可以分成几个礼包；再取包数最少的，作为最后的结果即可。\n\n【详解】44÷5=8(个)……4(支);25÷3=8(个)……1(个);14÷2=7(个)。8=8\u003e7。答：最多可以包装成7个礼包。",
+        "knowledge_points":  [
+                                 "有余数除法的实际应用"
+                             ],
+        "source":  "24-25 二年级下·河南南阳·期末"
+    },
+    {
+        "id":  "295",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "红富士苹果个大味甜，营养丰富，李爷爷摘了28箱红富士，每次运8箱，至少要运几次才能运回家。",
+        "options":  [
+
+                    ],
+        "answer":  "4次",
+        "solution":  "【分析】根据100内有余数的除法的意义，苹果的总箱数÷每次最多运的箱数=每次能运满箱数的次数。剩余的箱数需要再运一次，则至少要运的次数应为每次能运满箱数的次数+1，由此列出算式即可解答。\n\n【详解】28÷8=3(次)……4(箱)，3+1=4(次)。答：至少要运4次才能运回家。",
+        "knowledge_points":  [
+                                 "有余数除法的实际应用",
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "24-25二年级下·河北唐山·期末"
+    },
+    {
+        "id":  "296",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "丽丽准备了一盒共24块巧克力要和4位好朋友一起分享，平均每人分到几块，还剩几块。",
+        "options":  [
+
+                    ],
+        "answer":  "4块;4块",
+        "solution":  "【分析】丽丽和4位好朋友合起来一共5个人，根据除法的意义，用24÷5，得出的商就是平均每人分到巧克力块数，余数就是剩下的巧克力数量。\n\n【详解】4+1=5(人);24÷5=4(块)……4(块)。答：每人分到4块，还剩4块。",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "24-25 二年级下·河北唐山·期末"
+    },
+    {
+        "id":  "297",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "灯笼是一种古老的汉族传统工艺品。要做48个灯笼，李叔叔每天最多做5个，李叔叔至少要做多少天才能做完。",
+        "options":  [
+
+                    ],
+        "answer":  "10天",
+        "solution":  "【分析】求至少需要多少天才能做完，即求48里面有几个5，根据除法的意义，用48÷5算出结果，若有余数则表示剩余的灯笼数量，则还需要再一天将剩余的灯笼做完。所以考虑到实际情况，要用进一法取值。\n\n【详解】48÷5=9(天)……3(个)，9+1=10(天)。答：李叔叔至少要做10天才能做完。",
+        "knowledge_points":  [
+                                 "有余数除法的实际应用",
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "24-25 二年级下·甘肃庆阳·期末"
+    },
+    {
+        "id":  "298",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "二年级有54人去动物园春游。\n(1)每辆面包车限坐8人，至少需要租几辆面包车。\n(2)动物园门票每张7元，50元最多能买几张门票。",
+        "options":  [
+
+                    ],
+        "answer":  "7;7",
+        "solution":  "【分析】(1)用去动物园春游的总人数除以每辆面包车限坐的人数，即可求出需要租几辆面包车；若正好被整除，则商就是要租面包车的辆数；若有余数，则用面包车的辆数加1即可。(2)用总钱数除以每张门票的钱数，商就是最多能买几张门票，余数是还剩的钱数。\n\n【详解】(1)54÷8=6(辆)……6(人)，6+1=7(辆)。答：至少需要租7辆面包车。(2)50÷7=7(张)……1(元)。答：50元最多能买7张门票。",
+        "knowledge_points":  [
+                                 "经济问题",
+                                 "100以内有余数的除法计算",
+                                 "有余数除法的实际应用"
+                             ],
+        "source":  "24-25二年级下·广东汕尾·期末"
+    },
+    {
+        "id":  "299",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "体育运动场的一侧按照“3红2蓝1黄”的规律插了45面彩旗，请你算一算，一共有多少面红色的旗子。\n![](images/c3cf2c7fd87b3e99a2414cf133b269efa6c3219e85efc1d8e63b579f43c95eb2.jpg)",
+        "options":  [
+
+                    ],
+        "answer":  "24面",
+        "solution":  "【分析】根据题意，按照“3红2蓝1黄”的顺序插了45面彩旗，一个周期里有(3+2+1)面旗子；用除法计算出45里面有几个周期，还余下几，进而确定出余下的旗子是什么颜色；根据每个周期中三种颜色彩旗的数量列式计算，即可得到答案。\n\n【详解】3+2+1=6(面);45÷6=7(个)……3(面)，第8个周期的前3面都是红色的旗子。3×7+3=21+3=24(面)。答：一共有24面红色的旗子。",
+        "knowledge_points":  [
+                                 "乘加",
+                                 "乘减混合运算",
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "24-25 二年级下·河北邢台·期末"
+    },
+    {
+        "id":  "300",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "有60名同学去郊游，至少要租多少辆车。\n![](images/8fd601ded9552ca6a69e9d57917497ff.png)",
+        "options":  [
+
+                    ],
+        "answer":  "9辆",
+        "solution":  "【分析】用总人数除以每辆车限乘人数，商就是需要的辆数，如果有余数，需要再加1辆。\n\n【详解】60÷7=8(辆)……4(名)，8+1=9(辆)。答：至少要租9辆车。",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算",
+                                 "图文问题"
+                             ],
+        "source":  "24-25二年级下·湖北武汉·期末"
+    },
+    {
+        "id":  "301",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "有45只鸽子，如果每7只装在一个笼子里，需要( )个笼子才能装完。",
+        "options":  [
+                        "A. 8",
+                        "B. 7",
+                        "C. 6"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】由题意得，实际上是求45里面有几个7，求一个数里面有几个另一个数用除法。根据题意，此题应使用“进一法”保留整数。\n\n【详解】45÷7=6(个)……3(只)，6+1=7(个)。所以需要7个笼子才能装完。故答案为:B",
+        "knowledge_points":  [
+                                 "有余数除法的实际应用",
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "24-25二年级下·河北保定·期末"
+    },
+    {
+        "id":  "302",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "在◯÷6=4……☆中，☆最大是( )。",
+        "options":  [
+                        "A. 3",
+                        "B. 5",
+                        "C. 24"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】根据对有余数除法的认识可知：余数要比除数小，据此根据题干要求进行解答即可。\n\n【详解】因为余数要比除数小，小于6的最大的数是5，所以☆最大是5。故答案为:B",
+        "knowledge_points":  [
+                                 "余数与除数的关系"
+                             ],
+        "source":  "24-25 二年级下·福建三明·期末"
+    },
+    {
+        "id":  "303",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "静静用竖式计算\"13根小棒可以搭几个独立的正方形\"，竖式中的\"12\"表示的意思是( ).\n![](images/113357.png)",
+        "options":  [
+                        "A. 还剩12根小棒",
+                        "B. 一共有12根小棒",
+                        "C. 可以搭12个正方形",
+                        "D. 已经用了12根小棒"
+                    ],
+        "answer":  "D",
+        "solution":  "【分析】根据除法竖式的意义，竖式中的13表示一共有13根小棒，是被除数；4是除数，即一个正方形用小棒的根数；3是商，即可以搭成正方形的个数；1是余数，即还剩下小棒的数量；12是3和4的乘积，表示搭了3个正方形一共用了多少根小棒，据此解答。\n\n【详解】A. 还剩12根小棒，是错误的，应该是还剩1根小棒；B. 一共有12根小棒，是错误的，应该是一共有13根小棒；C. 可以搭12个正方形，是错误的，应该是可以搭3个正方形；D. 搭3个正方形已经用了12根小棒，是正确的。故答案为:D",
+        "knowledge_points":  [
+                                 "有余数除法的实际应用",
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "24-25二年级下·福建莆田·期末"
+    },
+    {
+        "id":  "304",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "选择题",
+        "difficulty":  0.94,
+        "question":  "甜品店有30个蛋挞，( )个装一盒，正好装完。",
+        "options":  [
+                        "A. 6",
+                        "B. 7",
+                        "C. 8",
+                        "D. 9"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】根据题意，用甜品店蛋挞的总个数除以每盒装的个数，若没有余数，正好装完；若有余数，则不能装完，逐项分析各个选项，找出正确答案即可。\n\n【详解】A. 30÷6=5(盒)，没有余数，正好装完；B. 30÷7=4(盒)……2(个)，有余数，不能装完；C. 30÷8=3(盒)……6(个)，有余数，不能装完；D. 30÷9=3(盒)……3(个)，有余数，不能装完。因此，甜品店有30个蛋挞，6个装一盒，正好装完。故答案为:A",
+        "knowledge_points":  [
+                                 "有余数除法的实际应用",
+                                 "100以内有余数的除法计算",
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·福建莆田·期末"
+    },
+    {
+        "id":  "305",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "☆☆●○☆☆●○☆☆●○。按这样的规律摆下去，第37个图形是( )。",
+        "options":  [
+                        "A. ○",
+                        "B. ●",
+                        "C. ☆"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】图形是按☆☆●○4个图形一组，即每4个图形为一个完整的重复单元，用总数除以4，余数为1，也就是第37个图形和第一个图形是一样的，据此得出结论即可。\n\n【详解】37÷4=9(组)……1(个)，即第37个图形和第1个图形一样是☆。故答案为:C",
+        "knowledge_points":  [
+                                 "有余数除法的实际应用"
+                             ],
+        "source":  "24-25二年级下·湖南衡阳·期末"
+    },
+    {
+        "id":  "306",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "○□□△△△○□□△△△。按照这样的规律排列，第27个图形应该是( )。",
+        "options":  [
+                        "A. ○",
+                        "B. □",
+                        "C. △"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】图形按○□□△△△的顺序重复排列，一组6个。用27除以6，余数是几就是一组中的第几个，没有余数就是最后一个。\n\n【详解】27÷6=4(组)……3(个)，第27个图形应该是□。故答案为:B",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算",
+                                 "图形的变化规律"
+                             ],
+        "source":  "24-25 二年级下·山东菏泽·期末"
+    },
+    {
+        "id":  "307",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "选择题",
+        "difficulty":  0.94,
+        "question":  "在算式□÷5=6……□中，余数可能是( )。",
+        "options":  [
+                        "A. 4",
+                        "B. 5",
+                        "C. 6",
+                        "D. 7"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】在有余数的除法中，余数必须小于除数。题目中除数是5，因此余数可能是1、2、3、4中的一个，逐项分析各个选项，找出正确答案即可解答。\n\n【详解】A. 4\u003c5，答案正确；B. 5=5，答案错误；C. 6\u003e5，答案错误；D. 7\u003e5，答案错误。故答案为:A",
+        "knowledge_points":  [
+                                 "余数与除数的关系"
+                             ],
+        "source":  "24-25 二年级下·广东东莞·期末"
+    },
+    {
+        "id":  "308",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "二年级有44名学生到游乐园划船游玩，每条船最多可以坐7人，至少需要租( )条船。",
+        "options":  [
+                        "A. 6",
+                        "B. 7",
+                        "C. 8"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】用学生的总人数除以每条船最多可以坐的人数，即可求出需要租船的数量；若正好被整除，则商就是需要租船的数量；若有余数，则用租船的数量加1即可。\n\n【详解】44÷7=6(条)……2(人)，6+1=7(条)。至少需要租7条船。故答案为:B",
+        "knowledge_points":  [
+                                 "有余数除法的实际应用",
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "24-25二年级下·湖北襄阳·期末"
+    },
+    {
+        "id":  "309",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "把20个香蕉平均分给6只小猴，有关下面竖式中各数表示的意义，说法正确的是( )。\n![](images/113412.png)",
+        "options":  [
+                        "A. 20表示一共有20只猴子",
+                        "B. 3表示平均分给3只猴子",
+                        "C. 18表示分掉了18个香蕉"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】根据题意可知，竖式中被除数20表示的是20个香蕉，除数6表示的是6只小猴，商3表示每只小猴分到3个香蕉，18是3和6的乘积，表示6只小猴一共分掉18个香蕉，2是余数，表示分掉18个后还剩余2个，据此可解。\n\n【详解】A. 20表示一共有20个香蕉，说法错误；B. 3表示每只小猴分到3个香蕉，说法错误；C. 18表示分掉了18个香蕉，说法正确。故答案为:C",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算",
+                                 "有余数除法的认识"
+                             ],
+        "source":  "24-25 二年级下·广西河池·期末"
+    },
+    {
+        "id":  "310",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "一共有17根小棒，平均分成3份，每份5根，还剩2根。下面竖式中箭头所指的数表示含义正确的是( )。\n![](images/113421.png)",
+        "options":  [
+                        "A. 要分的15根小棒",
+                        "B. 还剩15根小棒",
+                        "C. 分走的15根小棒"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】根据图示，竖式中15表示3乘5的积，即把17平均分成3份，每份是5根。17是要分小棒的根数，15表示共分走了15根小棒，2是还剩下的小棒根数，据此解答即可。\n\n【详解】A. 要分的小棒是17根，并非15根，答案错误；B. 还剩下的小棒是2根，并非15根，答案错误；C. 竖式中箭头所指是分走的15根小棒，答案正确。故答案为:C",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "24-25 二年级下·湖北黄石·期末"
+    },
+    {
+        "id":  "311",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "用一堆小棒摆。如果有剩余，可能会剩( )根。",
+        "options":  [
+                        "A. 1~5",
+                        "B. 1~6",
+                        "C. 1~7"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】根据题意，摆1个需要6根小棒。则小棒的总数量÷摆1个需要小棒的数量=可以摆的个数。剩余的小棒数量，也就是余数。有余数的除法算式中，余数一定小于除数且不为0，也就是余数要小于6且不为0，由此解答。\n\n【详解】由分析可知：比6小且不为0的数有5、4、3、2、1。则可能会剩1~5根。故答案为:A",
+        "knowledge_points":  [
+                                 "余数与除数的关系"
+                             ],
+        "source":  "24-25 二年级下·山西晋中·期末"
+    },
+    {
+        "id":  "312",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "下面除法算式中，余数是2的是( )。",
+        "options":  [
+                        "A. 32÷5",
+                        "B. 47÷6",
+                        "C. 60÷8"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】求商和余数，根据“被除数÷除数=商……余数”代入数值，进行解答即可。\n\n【详解】A. 32÷5=6……2，余数是2，符合题意；B. 47÷6=7……5，余数是5，不符合题意；C. 60÷8=7……4，余数是4，不符合题意。故答案为:A",
+        "knowledge_points":  [
+                                 "两位数除以一位数的有余数除法",
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "24-25 二年级下·湖南长沙·期末"
+    },
+    {
+        "id":  "313",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "10个小朋友去坐观光车，每部观光车最多坐4人。他们至少要租( )部观光车。",
+        "options":  [
+                        "A. 3",
+                        "B. 2",
+                        "C. 4"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】根据题意可知，用小朋友的总人数除以每部观光车最多坐的人数，求出结果。若没有余数，商就是至少要租观光车的数量；若有余数，剩下的人还需要1辆观光车，因此商再加1，就是至少要租观光车的数量，据此解答。\n\n【详解】10÷4=2(辆)……2(人)，2+1=3(辆)。10个小朋友去坐观光车，每部观光车最多坐4人，他们至少要租3部观光车。故答案为:A",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算",
+                                 "有余数除法的实际应用"
+                             ],
+        "source":  "24-25二年级下·江西赣州·期末"
+    },
+    {
+        "id":  "314",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "现有15枝玫瑰、26枝百合和28枝康乃馨。如果用3枝玫瑰、4枝百合和7枝康乃馨扎成一束花，这些花最多可以扎成( )。",
+        "options":  [
+                        "A. 4束",
+                        "B. 5束",
+                        "C. 6束"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】先用有余数的除法分别计算出玫瑰3枝一束、百合4枝一束和康乃馨7枝一束，各自最多可以分成几束；再取束数最少的，作为最后的结果即可。\n\n【详解】15÷3=5(束);26÷4=6(束)……2(枝);28÷7=4(束)。6\u003e5\u003e4，这些花最多可以扎成4束。故答案为:A",
+        "knowledge_points":  [
+                                 "用2~5的乘法口诀求商",
+                                 "用7~9的乘法口诀求商",
+                                 "有余数除法的实际应用"
+                             ],
+        "source":  "24-25 二年级下·浙江温州·期末"
+    },
+    {
+        "id":  "315",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "有17本书，每个小朋友分5本。分给了几个小朋友，还剩几本。下面竖式中箭头所指的部分表示的是( )。\n![](images/113432.png)",
+        "options":  [
+                        "A. 分给了15个小朋友",
+                        "B. 分掉了15本书",
+                        "C. 一共有15本书"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】竖式中的17表示书的总本数，5表示每个小朋友分的本数，3表示分给了几个小朋友，15表示一共分掉了几本书，2表示还剩下书的本数，据此选答案。\n\n【详解】竖式中的15表示3乘5的积，也就是每个小朋友分5本，分给了3个小朋友，一共分掉了15本书，据此选答案。故答案为:B",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算",
+                                 "有余数除法的实际应用"
+                             ],
+        "source":  "24-25二年级下·浙江温州·期末"
+    },
+    {
+        "id":  "316",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "小赵按照“□□△○□□△○□□△○……”的规律画了一排图形，第37个图形是( )。",
+        "options":  [
+                        "A. □",
+                        "B. △",
+                        "C. ○"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】图形按照□□△○的顺序循环排列，一组4个。用除法算出37个里面有这样的几组，若没有余数，就是一组中的最后一个图形；若有余数，余数是几就是一组中的第几个图形。\n\n【详解】37÷4=9(组)……1(个)，所以第37个图形是□。故答案为:A",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算",
+                                 "有余数除法的实际应用"
+                             ],
+        "source":  "24-25 二年级下·浙江温州·期末"
+    },
+    {
+        "id":  "317",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "小强用竖式计算\"13根小棒可以摆几个独立的三角形\"，竖式中的\"12\"表示( ).\n![](images/47fb61570058a883881d37228731cee3.png)",
+        "options":  [
+                        "A. 还剩几根小棒",
+                        "B. 原来一共有12根小棒",
+                        "C. 摆4个独立的三角形用去12根小棒"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】已知摆一个独立的三角形需要3根小棒，现在有13根小棒，用13除以3，商就是求能摆几个独立的三角形，余数就是剩下的小棒根数。在竖式计算中，商是4，它表示可以摆成4个独立的三角形。因为摆一个三角形需要3根小棒，那么摆4个三角形所用小棒的数量就是4×3=12(根)，所以竖式中的12就表示摆4个三角形用去12根小棒。\n\n【详解】A. “还剩几根小棒”应该是竖式中的余数1，不是12；B. 原来一共有13根小棒，不是12根；C. 摆一个三角形需要3根小棒，那么摆4个三角形所用小棒的数量就是4×3=12(根)，所以竖式中的12就表示摆4个三角形用去12根小棒。故答案为:C",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算",
+                                 "有余数除法的实际应用"
+                             ],
+        "source":  "24-25 二年级下·浙江温州·期末"
+    },
+    {
+        "id":  "318",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "把20个梨平均分给6只小猴，有关下面竖式中各数表示的意义，说法正确的是( )。\n![](images/113443.png)",
+        "options":  [
+                        "A. 3表示平均分给3只小猴",
+                        "B. 18表示分掉了18个梨",
+                        "C. 2表示每只小猴分到了2个梨"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】根据题意，商3表示每只小猴分到3个，18是3和6的乘积，表示6只小猴一共分掉18个，2是余数，表示分掉18个后还剩余2个，据此解答。\n\n【详解】根据分析：A. 3表示每只小猴分到3个，原选项说法错误；B. 18表示分掉了18个梨，说法正确；C. 2表示分掉18个后还剩2个，原选项说法错误。故答案为:B",
+        "knowledge_points":  [
+                                 "有余数除法的认识",
+                                 "有余数除法的实际应用"
+                             ],
+        "source":  "24-25 二年级下·山东临沂·期末"
+    },
+    {
+        "id":  "319",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "38位同学到公园划船，每条船最多坐6人。下图竖式箭头所指的部分表示的是( )。\n![](images/113452.png)",
+        "options":  [
+                        "A. 需要36条船",
+                        "B. 坐满6条船，还剩36人",
+                        "C. 6条船可以坐36人",
+                        "D. 一共有36人"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】箭头所指的36是6乘6得到的，也就是每条船最多坐的人数乘船的条数得来的，是指6条船一共可以坐的人数。总人数÷每条船最多坐的人数=需要船的条数，逐项分析即可。\n\n【详解】A. 需要6条船，原题说法错误；B. 坐满6条船，还剩2人，原题说法错误；C. 6条船可以坐36人，原题说法正确；D. 一共有38人，原题说法错误。38位同学到公园划船，每条船最多坐6人，下图竖式箭头所指的部分表示的是6条船可以坐36人。故答案为:C",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "23-24二年级下·福建龙岩·期末"
+    },
+    {
+        "id":  "320",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "如图中的果盘，19个苹果和16个梨最多可以拼成这样的( )盘。\n![](images/a6d651063032f00216d3f30798ce963438e2fbe8c47efb97490d310b46290fcf.jpg)",
+        "options":  [
+                        "A. 6",
+                        "B. 8",
+                        "C. 7",
+                        "D. 14"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】每盘有3个苹果和2个梨，先用除法分别算出各自可以拼的盘数，然后找出最小的那个盘数即可。\n\n【详解】19÷3=6(盘)……1(个);16÷2=8(盘)。6\u003c8，最多可以拼成这样的6盘。故答案为:A",
+        "knowledge_points":  [
+                                 "用7~9的乘法口诀求商",
+                                 "100以内有余数的除法计算",
+                                 "有余数除法的实际应用"
+                             ],
+        "source":  "23-24 二年级下·福建龙岩·期末"
+    },
+    {
+        "id":  "321",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "□◆☆△□◆☆△。按这样的顺序排列，第28个图形是( )。",
+        "options":  [
+                        "A. □",
+                        "B. ◆",
+                        "C. △"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】这组图形按照□◆☆△的顺序重复排列，4个图形为一组。用除法算出28里面有这样的几组，如果没有余数，结果就是最后一个图形；如果有余数，余数是几，结果就是一组中的第几个图形，据此解答。\n\n【详解】由分析可得:28÷4=7(组)，第28个图形是△。故答案为:C",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算",
+                                 "图形的变化规律"
+                             ],
+        "source":  "24-25 二年级下·湖北襄阳·期末"
+    },
+    {
+        "id":  "322",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "“六一”儿童节那天，学校举行“六一”游园活动，小朋友们用气球装扮教室。他们按“5红2蓝1黄”的颜色挂气球，一共挂了70个气球。最后一个气球是( )色。",
+        "options":  [
+                        "A. 红",
+                        "B. 蓝",
+                        "C. 黄"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】由题意可知：气球的排列规律是“5红2蓝1黄”，8个气球为一组，不断地重复出现；用气球的总个数除以每组气球的个数，求出的商是气球排列的组数，余数是剩余气球的个数；剩余几个气球就和一组中第几个气球对照，找出相应颜色，即是正确答案，据此解答。\n\n【详解】由分析可得:70÷8=8(组)……6(个)，剩余6个气球，一组中第6个气球是蓝色，即最后一个气球是蓝色。故答案为:B",
+        "knowledge_points":  [
+                                 "间隔问题",
+                                 "100以内有余数的除法计算",
+                                 "有余数除法的实际应用"
+                             ],
+        "source":  "24-25 二年级下·广西河池·期末"
+    },
+    {
+        "id":  "323",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "有50根小棒，每7根分一组，可以分成几组，还剩几根。列式为50÷7=7(组)……1(根)。观察下面的竖式，其中49表示( )。\n![](images/113504.png)",
+        "options":  [
+                        "A. 一共有49根小棒",
+                        "B. 已经分掉的49根小棒",
+                        "C. 剩下的49根小棒"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】在除法竖式中，被除数下方的数表示商与除数的乘积，即已经分掉的数量。50根小棒每7根分一组，分7组用掉49根，余下1根。\n\n【详解】A. 一共有50根小棒，原题说法错误；B. 已经分掉的49根小棒，原题说法正确；C. 剩下的是1根小棒，原题说法错误。49表示已经分掉的49根小棒。故答案为:B",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "24-25 二年级下·河北邢台·期末"
+    },
+    {
+        "id":  "324",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "算式□÷6=□……□，余数最大是( )。",
+        "options":  [
+                        "A. 3",
+                        "B. 4",
+                        "C. 5"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】有余数的除法算式为被除数÷除数=商……余数，其中余数一定小于除数，余数最大是比除数小1的数。\n\n【详解】6-1=5，则算式□÷6=□……□，余数最大是5。故答案为:C",
+        "knowledge_points":  [
+                                 "余数与除数的关系"
+                             ],
+        "source":  "24-25二年级下·广东广州·期末"
+    },
+    {
+        "id":  "325",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "有一串珠子，按下面的顺序依次排列，第24个珠子是( )。\n![](images/5dc1139feaf3045fc87ac3d50438170a26bafa2a823b4292928191e89e5accab.jpg)",
+        "options":  [
+                        "A. ○",
+                        "B. ●",
+                        "C. 网珠",
+                        "D. 斑点珠"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】珠子按○●●网珠斑点珠的顺序循环排列，一组5颗。用24除以每组的颗数，商就是共有的组数，余数是几就是一组中的第几颗，没有余数就是最后一颗。\n\n【详解】根据分析可得:24÷5=4(组)……4(个)，有这样4组，还余4个，一组中的第4个是网珠。因此，有一串珠子，按下面的顺序依次排列，第24个珠子是网珠。故答案为:C",
+        "knowledge_points":  [
+                                 "间隔问题",
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "23-24 二年级下·福建龙岩·期末"
+    },
+    {
+        "id":  "326",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "◯÷7=6……△中，下列说法正确的是( )。",
+        "options":  [
+                        "A. 余数可能是9",
+                        "B. 余数最大是6",
+                        "C. 余数最大是7",
+                        "D. 余数最小是0"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】余数比除数小，余数最大是除数减1。\n\n【详解】7-1=6。A. 9\u003e7，原题说法错误；B. 余数最大是6，原题说法正确；C. 余数不能是7，原题说法错误；D. 余数最小是1，原题说法错误。说法正确的是余数最大是6。故答案为:B",
+        "knowledge_points":  [
+                                 "余数与除数的关系"
+                             ],
+        "source":  "23-24 二年级下·福建龙岩·期末"
+    },
+    {
+        "id":  "327",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "有30根跳绳，至少拿走( )根，剩下的正好平均分给7个班;至少再买( )根，可以平均分给9个班。",
+        "options":  [
+
+                    ],
+        "answer":  "2;6",
+        "solution":  "【分析】用跳绳的总数量30根除以平均分班级数量7个，求出商和余数，余数就是至少拿走的跳绳数量；用跳绳的总数量30根除以平均分班级数量9个，求出商和余数，再用9减去余数，求出差就是至少再买的跳绳数量。\n\n【详解】30÷7=4……2；30÷9=3……3；9-3=6。即，有30根跳绳，至少拿走2根，剩下的正好平均分给7个班；至少再买6根，可以平均分给9个班。",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "24-25 二年级下·河南南阳·期末"
+    },
+    {
+        "id":  "328",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "下边的算式中，余数最大是( )。\n□÷7=□……□",
+        "options":  [
+
+                    ],
+        "answer":  "6",
+        "solution":  "【分析】在有余数的除法中，余数必须比除数小;除数是7，余数最大是比7小1的数。据此可解。\n\n【详解】由分析可得：下边的算式中，余数最大是6。",
+        "knowledge_points":  [
+                                 "余数与除数的关系"
+                             ],
+        "source":  "24-25二年级下·河南南阳·期末"
+    },
+    {
+        "id":  "329",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "小东今天练习写字，按下面的顺序重复写，第32个字是( )。\n黄河入海流黄河入海流黄河入海流黄河入。",
+        "options":  [
+
+                    ],
+        "answer":  "河",
+        "solution":  "【分析】观察可知，“黄河入海流”每5个字为一个周期长度循环，用总字数除以周期长度5，若余数为0，则为周期的最后一个字；若余数不为0，则余数是几就表示周期的第几个字。\n\n【详解】32÷5=6(组)……2(个)，余数是2，即表示第32个字是第7个周期的第2个字。小东今天练习写字，按下面的顺序重复写，第32个字是河。",
+        "knowledge_points":  [
+                                 "周期问题",
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "24-25二年级下·福建三明·期末"
+    },
+    {
+        "id":  "330",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "乐乐在练习书法时，把“白日依山尽”这几个字按顺序重复写，第29个字是( )；在这29个字中，( )字写得最少。",
+        "options":  [
+
+                    ],
+        "answer":  "山;尽",
+        "solution":  "【分析】“白日依山尽”5个字重复写，29÷5=5(遍)……4(个)，也就是写5遍“白日依山尽”，再写“白日依山”四个字，据此得出结论即可。\n\n【详解】29÷5=5(遍)……4(个)，即第29个字和第4个字相同是“山”，“尽”字写得最少。故乐乐在练习书法时，把“白日依山尽”这几个字按顺序重复写，第29个字是山；在这29个字中，尽字写得最少。",
+        "knowledge_points":  [
+                                 "有余数除法的实际应用"
+                             ],
+        "source":  "24-25 二年级下·福建莆田·期末"
+    },
+    {
+        "id":  "331",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "把15块糖平均分给5个小朋友，每人分( )块，若每人4块，可分给( )人，还剩( )块。",
+        "options":  [
+
+                    ],
+        "answer":  "3;3;3",
+        "solution":  "【分析】把一些物品平均分成若干份，每份分得同样多，则叫平均分。求每人分的数量，用总数除以分给的小朋友数量即可求出；求可以分给的小朋友数量及还剩的数量，用总数除以每人分的块数，求出商和余数，商为可以分得的人数，余数为剩余的块数。\n\n【详解】15÷5=3(块);15÷4=3(人)……3(块)。则把15块糖平均分给5个小朋友，每人分(3)块，若每人4块，可分给(3)人，还剩(3)块。",
+        "knowledge_points":  [
+                                 "有余数除法的实际应用"
+                             ],
+        "source":  "24-25 二年级下·山西长治·期末"
+    },
+    {
+        "id":  "332",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "由于突发洪水，有33人被困在海中的小岛上需要营救，每条船最多坐5人，至少要准备( )条船才能一次把所有人都救上岸。",
+        "options":  [
+
+                    ],
+        "answer":  "7",
+        "solution":  "【分析】根据题意，用总人数÷每条船最多能坐的人数=坐满船的数量。剩余的人数还需要再安排1条船，所以坐满船的数量+1=至少需要准备船的数量，据此解答。\n\n【详解】根据分析:33÷5=6(条)……3(人)，6+1=7(条)。由于突发洪水，有33人被困在海中的小岛上需要营救，每条船最多坐5人，至少要准备(7)条船才能一次把所有人都救上岸。",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算",
+                                 "有余数除法的实际应用"
+                             ],
+        "source":  "24-25 二年级下·山东菏泽·期末"
+    },
+    {
+        "id":  "333",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "把40支铅笔平均分给牛牛和他的5个好朋友，每个人可以分到( )支。",
+        "options":  [
+
+                    ],
+        "answer":  "6",
+        "solution":  "【分析】总人数：牛牛和他的5个好朋友，一共6人。铅笔总数：40支。平均分配时，40支铅笔除以6人，商是6，余数是4，所以每人分到6支铅笔，但会剩余4支铅笔。\n\n【详解】1+5=6(人);40÷6=6(支)……4(支)。把40支铅笔平均分给牛牛和他的5个好朋友，每个人可以分到6支。",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "24-25 二年级下·山东菏泽·期末"
+    },
+    {
+        "id":  "334",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "有22个苹果，这些苹果最少加上( )个，才能正好平均分给9个小朋友。去掉( )个，才能正好平均分给9个小朋友。",
+        "options":  [
+
+                    ],
+        "answer":  "5;4",
+        "solution":  "【分析】用苹果总数除以小朋友的人数，商是每个小朋友分得的个数，余数是还剩的个数，最后用人数减去余数即可求出至少需要添的个数。求去掉的个数时，直接用余数即可。\n\n【详解】22÷9=2(个)……4(个);9-4=5(个)。则有22个苹果，这些苹果最少加上(5)个，才能正好平均分给9个小朋友；去掉(4)个，才能正好平均分给9个小朋友。",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算",
+                                 "有余数除法的实际应用"
+                             ],
+        "source":  "24-25 二年级下·广东东莞·期末"
+    },
+    {
+        "id":  "335",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "亮亮在练习书法时，把“白日依山尽”这几个字按顺序重复写，第29个字是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "山",
+        "solution":  "【分析】“白日依山尽”共有5个字，按顺序重复写，每5个字为一个周期。求第29个字时，可用29除以5，余数即为该字在周期中的位置。若余数为0，则为第5个字；余数为1~4，则对应第1~4个字。\n\n【详解】29÷5=5(组)……4(个)，余数4对应周期中的第4个字“山”，也就是第29个字是山。",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算",
+                                 "有余数除法的实际应用",
+                                 "周期问题"
+                             ],
+        "source":  "24-25二年级下·广东东莞·期末"
+    },
+    {
+        "id":  "336",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "口★★○○口★★○○。按左边的规律排下去，第16个图形是( ),第27个图形是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "口;★",
+        "solution":  "【分析】这组图形按照口★★○○的顺序循环排列，一组5个；用除法算出16个和27个里面有这样的几组，若没有余数，就是一组中的最后一个图形，若有余数，余数是几就是一组中的第几个图形。\n\n【详解】16÷5=3(组)……1(个);27÷5=5(组)……2(个)。口★★○○口★★○○。按左边的规律排下去，第16个图形是口，第27个图形是★。",
+        "knowledge_points":  [
+                                 "图形的变化规律",
+                                 "有余数除法的实际应用",
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "24-25 二年级下·湖北襄阳·期末"
+    },
+    {
+        "id":  "337",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "按☆△□□☆△□□……的规律排列，第26个图形是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "△",
+        "solution":  "【分析】这组图形按照☆△□□的顺序循环排列，一组4个；用除法算出26个里面有这样的几组，若没有余数，就是一组中的最后一个图形，若有余数，余数是几就是一组中的第几个图形。\n\n【详解】由分析可得:26÷4=6(组)……2(个)。按☆△□□☆△□□……的规律排列，第26个图形是△。",
+        "knowledge_points":  [
+                                 "图形的变化规律",
+                                 "有余数除法的实际应用",
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "24-25 二年级下·湖北黄石·期末"
+    },
+    {
+        "id":  "338",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在算式□÷4=6……□中，余数最大时，这时被除数是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "27",
+        "solution":  "【分析】在有余数的除法计算中，最大的余数=除数-1，最小的余数是1；再根据被除数=商×除数+余数，求出对应的被除数，据此解答。\n\n【详解】根据分析可得：在算式□÷4=6……□中，余数最大是4-1=3，4×6+3=24+3=27。在算式□÷4=6……□中，余数最大时，这时被除数是27。",
+        "knowledge_points":  [
+                                 "有余数的除法验算",
+                                 "余数与除数的关系"
+                             ],
+        "source":  "24-25 二年级下·湖北黄石·期末"
+    },
+    {
+        "id":  "339",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "围棋是一种起源于我国的棋类游戏，深受人们的喜爱。下面是小军用棋子在棋盘上摆出的图案，照这样的规律摆下去，第38个棋子是( )色，第45个棋子是( )色。\n![](images/47970f63bcf81b0f65b6c5cbd4b191a733a718c2d10294e288b358a635b817e2.jpg)",
+        "options":  [
+
+                    ],
+        "answer":  "黑;黑",
+        "solution":  "【分析】棋子按2白3黑为一组重复排列，一组为5颗，用38和45分别除以5，余数是几就是一组中的第几颗，没有余数就是最后一颗。\n\n【详解】38÷5=7(组)……3(颗)，第38个棋子是黑色；45÷5=9(组)，没有余数，第45个棋子是黑色。",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "24-25 二年级下·山西晋中·期末"
+    },
+    {
+        "id":  "340",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "按照下面的规律摆图形，这样摆下去，第27个图形是( )。\n![](images/fc21bfb269cbbc29feb31d08dbf4a5e44d5d2158f53d805a83b12ffebe55217b.jpg)",
+        "options":  [
+
+                    ],
+        "answer":  "△",
+        "solution":  "【分析】由图意可知：图形的规律是□○△☆4个图形为一组，不断地重复出现；用第27个图形除以每组的4个图形，求出的商是组数，余数是剩余的图形数，余数是几就对应一组图形里的第几个图形，据此解答。\n\n【详解】由分析可得:27÷4=6(组)……3(个)，第3个图形是△；按照下面的规律摆图形，这样摆下去，第27个图形是△。",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算",
+                                 "有余数除法的实际应用",
+                                 "图形的变化规律"
+                             ],
+        "source":  "24-25 二年级下·江西赣州·期末"
+    },
+    {
+        "id":  "341",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在□÷5=6……★中，★最大是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "4",
+        "solution":  "【分析】在有余数的除法计算中，余数要小于除数，最大的余数=除数-1，最小的余数是1，据此解答。\n\n【详解】5-1=4。在□÷5=6……★中，★最大是4。",
+        "knowledge_points":  [
+                                 "余数与除数的关系"
+                             ],
+        "source":  "24-25 二年级下·江西赣州·期末"
+    },
+    {
+        "id":  "342",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "一共有24个苹果，如果每7个装一盘，可以装( )盘，还剩( )个。照这样，49个苹果可以装( )盘，算式是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "3;3;7;49÷7=7",
+        "solution":  "【分析】根据题意，用总的苹果数量÷每盘的数量=可以装的盘数，余数表示还剩的数量，据此解答。\n\n【详解】根据分析:24÷7=3(盘)……3(个);49÷7=7(盘)。共有24个苹果，如果每7个装一盘，可以装(3)盘，还剩(3)个。照这样，49个苹果可以装(7)盘，算式是(49÷7=7)。",
+        "knowledge_points":  [
+                                 "用7~9的乘法口诀求商",
+                                 "有余数除法的实际应用"
+                             ],
+        "source":  "24-25二年级下·湖南衡阳·期末"
+    },
+    {
+        "id":  "343",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "45个学生去划船，每条船最多坐8人。他们至少要租( )条船。",
+        "options":  [
+
+                    ],
+        "answer":  "6",
+        "solution":  "【分析】根据有余数除法的意义，学生的总人数÷每条船最多能坐的人数=坐满的船的数量。剩余学生的人数还需要再租一条船，则需要在坐满的船的数量上加1，列出算式算出答案即可解答。\n\n【详解】45÷8=5(条)……5(人)，5+1=6(条)。所以，他们至少要租6条船。",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "24-25 二年级下·湖南长沙·期末"
+    },
+    {
+        "id":  "344",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "一个数除以7，商是13，余数最大是( )，这时被除数是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "6;97",
+        "solution":  "【分析】在有余数的除法算式里，余数应比除数小，依此确定出最大的余数，被除数=商×除数+余数，当余数最大时，依此计算出被除数即可。\n\n【详解】除数是7，所以余数最大是6;被除数=商×除数+余数=13×7+6=91+6=97。这时被除数是97。",
+        "knowledge_points":  [
+                                 "有余数的除法验算",
+                                 "余数与除数的关系"
+                             ],
+        "source":  "24-25 三年级下·湖北十堰·期末"
+    },
+    {
+        "id":  "345",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "六一儿童节，二(2)班小朋友用彩旗装饰教室。他们按照“红红黄绿红红黄绿红红黄绿……”的规律将彩旗挂成一串。这串彩旗中的第31面是( )色的。",
+        "options":  [
+
+                    ],
+        "answer":  "黄",
+        "solution":  "【分析】根据题意，彩旗按照“红红黄绿”为一组重复排列，每组有4面，则用31除以每组彩旗的数量，若能除尽，则是这组的最后一面彩旗；若除不尽，则余数是几就是下一组的第几面彩旗。\n\n【详解】31÷4=7(组)……3(面)。这串彩旗中的第31面是第8组的第3面，是黄色的。",
+        "knowledge_points":  [
+                                 "有余数除法的实际应用"
+                             ],
+        "source":  "24-25 二年级下·浙江温州·期末"
+    },
+    {
+        "id":  "346",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "在有余数的除法算式☆÷6=9……△中，△最大是( )，这时☆是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "5;59",
+        "solution":  "【分析】在有余数除法中，余数要比除数小，因此余数最大=除数-1；此时，被除数=商×除数+余数，据此解答。\n\n【详解】由分析可得:6-1=5，余数最大是5;6×9+5=54+5=59，被除数是59。在有余数的除法算式☆÷6=9……△中，△最大是5，这时☆是59。",
+        "knowledge_points":  [
+                                 "余数与除数的关系",
+                                 "有余数的除法验算"
+                             ],
+        "source":  "24-25 二年级下·浙江温州·期末"
+    },
+    {
+        "id":  "347",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "有一列数:2,1,3,2,1,3,2,1,3。这列数第23个数是( ),从第一个数到第23个数的和是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "1;45",
+        "solution":  "【分析】这组数按照2、1、3的顺序循环排列，一组3个；用除法算出23个数里面有这样的几组，若没有余数就是组中的最后一个数，若有余数，余数是几就是一组中的第几个数；求从第一个数到第23个数的和时，用一组数的和×组数+剩余的数，即可解答。\n\n【详解】23÷3=7(组)……2(个);2+1+3=6，6×7+2+1=45。有一列数:2,1,3,2,1,3,2,1,3。这列数第23个数是1，从第一个数到第23个数的和是45。",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算",
+                                 "有余数除法的实际应用",
+                                 "整数排列的规律"
+                             ],
+        "source":  "24-25 二年级下·四川乐山·期末"
+    },
+    {
+        "id":  "348",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在算式□÷6=4……□中，余数最大是( )，这时被除数是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "5;29",
+        "solution":  "【分析】根据在有余数的除法中，余数总比除数小，即余数最大为除数-1。当余数最大时，被除数最大，进而根据“被除数=商×除数+余数”解答即可。\n\n【详解】除数是6，余数最大是:6-1=5;被除数是:4×6+5=24+5=29。所以，在算式□÷6=4……□中，余数最大是5，这时被除数是29。",
+        "knowledge_points":  [
+                                 "余数与除数的关系",
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "24-25 二年级下·四川乐山·期末"
+    },
+    {
+        "id":  "349",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "每3根小棒摆一个三角形，28根小棒最多可以摆( )个三角形，算式是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "9;28÷3=9(个)……1(根)",
+        "solution":  "【分析】根据题意，用小棒的总数量除以摆一个三角形用小棒的数量，商就是可以摆三角形的数量，若有余数，则余数是剩余小棒的数量。\n\n【详解】由分析得：每3根小棒摆一个三角形，28根小棒最多可以摆9个三角形，算式是28÷3=9(个)……1(根)。",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算",
+                                 "有余数除法的实际应用"
+                             ],
+        "source":  "24-25 二年级下·湖北襄阳·期末"
+    },
+    {
+        "id":  "350",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "▲÷7=6……★，★最大是( )，这时▲最大是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "6;48",
+        "solution":  "【分析】根据余数要比除数小，除数是7，余数★最大比7小1；根据被除数=商×除数+余数，求出▲，据此解答。\n\n【详解】由分析可得：余数最大是6;6×7+6=42+6=48。▲÷7=6……★，★最大是6，这时▲最大是48。",
+        "knowledge_points":  [
+                                 "有余数的除法验算",
+                                 "余数与除数的关系"
+                             ],
+        "source":  "21-22 二年级下·江苏连云港·期中"
+    },
+    {
+        "id":  "351",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "△△◯□△△◯□△△◯□。,按照这样的顺序排列，第26个图形是( ),这时△共有( )个,◯共有( )个。",
+        "options":  [
+
+                    ],
+        "answer":  "△;14;6",
+        "solution":  "【分析】由题意可知：图形的排列规律是:△△◯□4个为组，不断的重复出现;用26除以每组数，得出的商是组数，余数是图形剩余的个数;余数是几，最后一个图形就是△△◯□中的第几个图形。△共有的个数是商*2+剩余图形中△的个数;◯共有的个数就是商*1+剩余图形中◯的个数;据此解答。\n\n【详解】由分析可得:26÷4=6(组)。2(个),余数是2，第26个图形是一组中第2个图形△。6×2+2=12+2=14(个);6×1=6(个)。这时△共有14个,◯共有6个。△△◯□△△◯□△△◯□。,按照这样的顺序排列，第26个图形是△;这时△共有14个,◯共有6个。",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算",
+                                 "表内乘加，乘减",
+                                 "周期问题"
+                             ],
+        "source":  "24-25 二年级下·江西上饶·期末"
+    },
+    {
+        "id":  "352",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "在▲/★=5。7中,★最小是( ),这时▲是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "8;47",
+        "solution":  "【分析】根据100内有余数的除法可知，余数一定要比除数小，所以★一定要大于7。找出满足★大于7时,★可以取的最小值，再计算★*5+7，即可求得当★最小时,▲的值。\n\n【详解】根据分析可知,★最小是8.8×5+7=40+7=47。所以，在▲/★=5。7中,★最小是8，这时▲是47。",
+        "knowledge_points":  [
+                                 "余数与除数的关系",
+                                 "表内乘加，乘减"
+                             ],
+        "source":  "24-25 二年级下·江西上饶·期末"
+    },
+    {
+        "id":  "353",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "□☆△○○□☆△○○□☆△○○。按照这样继续画下去，第33个图形是( ),第40个图形是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "△;○",
+        "solution":  "【分析】观察图形排列的周期，每个周期为\"□☆△○○\"共5个图形。要确定第33个和第40个图形，需分别计算它们所在的周期位置。用总数除以周期长度，余数对应周期中的位置，若余数为0则对应最后一个图形。\n\n【详解】33÷5=6(组)。3(个),余数3对应周期中的第3个图形，即第33个图形是△。40÷5=8(组),余数为0，对应周期中的第5个图形，即第40个图形是○。",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算",
+                                 "周期问题"
+                             ],
+        "source":  "24-25 二年级下·湖北武汉·期末"
+    },
+    {
+        "id":  "354",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "□÷6=3。☆,余数最大是( ),此时被除数是( )。□÷☆=8。6，除数最小是( ),此时被除数是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "5;23;7;62",
+        "solution":  "【分析】(1)在有余数的除法中，余数必须小于除数。已知除数为6，余数最大为5。被除数=除数×商+余数，即6×3+5。(2)余数为6时，除数必须大于6，最小为7。被除数=除数×商+余数，即7×8+6。\n\n【详解】除数是6，余数最大为6-1=5，被除数:6×3+5=18+5=23。余数是6，除数最小为6+1=7，被除数:7×8+6=56+6=62。即,□÷6=3。☆,余数最大是5，此时被除数是23。□÷☆=8。6，除数最小是7，此时被除数是62。",
+        "knowledge_points":  [
+                                 "余数与除数的关系",
+                                 "有余数的除法验算"
+                             ],
+        "source":  "24-25 二年级下·湖北武汉·期末"
+    },
+    {
+        "id":  "355",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "□÷9=6。□,余数最大是( ),这时被除数是( );余数最小是( ),这时被除数是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "8;62;1;55",
+        "solution":  "【分析】有余数的除法算式为：被除数/除数=商。余数，其中余数一定比除数小且不为0。余数最大时，被除数最大，余数最大是比除数小1的数;余数最小为1，此时被除数最小，根据除数×商+余数=被除数，计算即可。\n\n【详解】余数最大:9-1=8;被除数最大:9×6+8=54+8=62;余数最小:1;被除数最小:9×6+1=54+1=55。□÷9=6。□,余数最大是8，这时被除数是62;余数最小是1，这时被除数是55。",
+        "knowledge_points":  [
+                                 "余数与除数的关系",
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "24-25 二年级下·福建福州·期末"
+    },
+    {
+        "id":  "356",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "54里面有( )个9;27里面最多有( )个8。",
+        "options":  [
+
+                    ],
+        "answer":  "6;3",
+        "solution":  "【分析】求一个数里面有多少个另一个数，用除法计算，商就是另一个数的个数。若有余数，则说明剩余部分不足以再组成一个完整的数。\n\n【详解】54÷9=6;27÷8=3。3.54里面有(6)个9;27里面最多有(3)个8。",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算",
+                                 "用7~9的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·重庆·期末"
+    },
+    {
+        "id":  "357",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在算式\"▲/7=3。■\"中,■最大是( ),此时▲等于( )。",
+        "options":  [
+
+                    ],
+        "answer":  "6;27",
+        "solution":  "【分析】在有余数除法中，余数要比除数小，余数■最大也要比除数7小，找出比7小的最大数即可;根据被除数=商×除数+余数，算出被除数▲即可;据此解答。\n\n【详解】由分析可得：比7小的数有:6,5,4,3,2,1，其中6最大，故■最大是6;3×7+6=21+6=27，故▲等于27。",
+        "knowledge_points":  [
+                                 "余数与除数的关系",
+                                 "有余数的除法验算",
+                                 "表内乘加，乘减"
+                             ],
+        "source":  "24-25 二年级下·浙江温州·期末"
+    },
+    {
+        "id":  "358",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "要做50个灯笼，每天最多可做8个，至少需要( )天才能完成。",
+        "options":  [
+
+                    ],
+        "answer":  "7",
+        "solution":  "【分析】用要做灯笼的总个数除以每天最多可做的个数，求出商和余数，然后用商加1，求出和，就是至少需要的天数。\n\n【详解】50÷8=6(天)。2(个),6+1=7(天)。即，要做50个灯笼，每天最多可做8个，至少需要7天才能完成。",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算",
+                                 "有余数除法的实际应用"
+                             ],
+        "source":  "23-24二年级下·河北邯郸·期末"
+    },
+    {
+        "id":  "359",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "糖果店有白巧克力51块，黑巧克力29块，如果现在用6块白巧克和4块黑巧克力装一盒，最多可以装( )盒。如果要装8盒，至少还差( )块黑巧克力。",
+        "options":  [
+
+                    ],
+        "answer":  "7;3",
+        "solution":  "【分析】分别用白，黑巧克力的总块数除以一盒需要的块数，商就是它们各自可以装的盒数，选择最小的那个商即可。用一盒需要黑巧克力的块数减装了7盒后剩余的块数即可求出还差多少块。\n\n【详解】51÷6=8(盒)。3(块);29÷4=7(盒)。1(块);7\u003c8，最多装7盒。4-1=3(块)。糖果店有白巧克力51块，黑巧克力29块，如果现在用6块白巧克和4块黑巧克力装一盒，最多可以装7盒。如果要装8盒，至少还差3块黑巧克力。",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算",
+                                 "有余数除法的实际应用"
+                             ],
+        "source":  "23-24 二年级下·河南信阳·期末"
+    },
+    {
+        "id":  "360",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "有47个苹果，最少拿出( )个，剩下的才能平均分给9个小朋友。",
+        "options":  [
+
+                    ],
+        "answer":  "2",
+        "solution":  "【分析】要使剩下的苹果能平均分给9个小朋友，剩下的苹果数必须是9的倍数。需要用47除以9，商表示每个小朋友平均分，最多能拿到的苹果个数，余数为剩下的无法再平均分给9个小朋友，因此余数即为最少需要拿出的苹果个数。\n\n【详解】47÷9=5(个)。2(个)。有47个苹果，最少拿出2个，剩下的才能平均分给9个小朋友。",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算",
+                                 "有余数除法的实际应用"
+                             ],
+        "source":  "23-24 二年级下·浙江嘉兴·期末"
+    },
+    {
+        "id":  "361",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "一串珠子按\"一黑二白三红\"的顺序排列，第24颗珠子的颜色是( ),这24颗珠子中共有( )颗白珠子。",
+        "options":  [
+
+                    ],
+        "answer":  "红;8",
+        "solution":  "【分析】根据题意可知，珠子按\"一黑二白三红\"顺序循环排列，一组6颗。用24除以每组的颗数，商就是一共有这样的几组，余数是几就是一组中的第几颗，没有余数就是最后一颗;用组数乘每组中白珠子的颗数，再加上余数中白珠子的颗数即可，求出一共有多少颗白珠子，据此解答。\n\n【详解】一黑二白三红的排列中，一组有6颗。24÷6=4(组),没有余数是一组中最后一颗，即红。2×4=8(颗)。因此，一串珠子按\"一黑二白三红\"的顺序排列，第24颗珠子的颜色是红，这24颗珠子中共有8颗白珠子。",
+        "knowledge_points":  [
+                                 "间隔问题",
+                                 "4的乘法口诀及应用",
+                                 "用6的乘法口诀求商"
+                             ],
+        "source":  "23-24 二年级下·河南濮阳·期末"
+    },
+    {
+        "id":  "362",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "( )÷7=3。6。",
+        "options":  [
+
+                    ],
+        "answer":  "27",
+        "solution":  "【分析】根据被除数/除数=商。余数，则求被除数，用商乘除数再加上余数即可。\n\n【详解】3×7=21,21+6=27。则27÷7=3。6。",
+        "knowledge_points":  [
+                                 "有余数的除法验算"
+                             ],
+        "source":  "23-24 二年级下·河北邯郸·期末"
+    },
+    {
+        "id":  "363",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "43个面包，每7个装一袋，最多可以装( )袋，还剩( )个面包。",
+        "options":  [
+
+                    ],
+        "answer":  "6;1",
+        "solution":  "【分析】用面包的个数除以每袋装的面包个数，商为最多装的袋数，余数为还剩的面包个数。\n\n【详解】43÷7=6(袋)。1(个)。最多可以装(6)袋，还剩(1)个面包。",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "23-24二年级下·天津河北·期末"
+    },
+    {
+        "id":  "364",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "判断题",
+        "difficulty":  0.65,
+        "question":  "38个小朋友坐船，每条船坐8人，至少要5条船才够坐。( )",
+        "options":  [
+
+                    ],
+        "answer":  "√",
+        "solution":  "【分析】根据题意，用坐船的总人数除以每条船上可坐的人数，如果没有余数，商即是船的条数;如果有余数，商再加1，即是至少需要船的条数。\n\n【详解】38÷8=4(条)。6(人),4+1=5(条)。所以,38个小朋友坐船，每条船坐8人，至少要5条船才够坐。原题说法正确。故答案为:√",
+        "knowledge_points":  [
+                                 "有余数除法的实际应用",
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "24-25 二年级下·广东佛山·期末"
+    },
+    {
+        "id":  "365",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "41÷5=8。1，可以用5×8+1=41检验计算结果是否正确。( )",
+        "options":  [
+
+                    ],
+        "answer":  "√",
+        "solution":  "【分析】在有余数的除法中，可以通过被除数=商×除数+余数来检验计算结果是否正确，据此判断。\n\n【详解】由分析可得:41÷5=8。1，验算时可以用:8×5+1=40+1=41.41÷5=8。1，可以用5×8+1=41检验计算结果是否正确。故答案为:√",
+        "knowledge_points":  [
+                                 "有余数的除法验算",
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "24-25 二年级下·河南三门峡·期末"
+    },
+    {
+        "id":  "366",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "判断题",
+        "difficulty":  0.65,
+        "question":  "在除法算式中，余数一定比商小。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】在除法算式中，余数的定义是必须小于除数，但余数与商的大小关系并不固定。通过举例验证，余数可能等于或大于商，因此原题说法错误。\n\n【详解】根据分析可知：在除法算式中，余数必须满足\"余数\u003c除数\"，但余数与商的大小没有必然联系。例如:15÷4=3。3，余数3等于商3;8÷5=1。3，余数3大于商1。上述例子中余数均不小于商，因此原题说法错误。故答案为: ×",
+        "knowledge_points":  [
+                                 "余数与除数的关系"
+                             ],
+        "source":  "24-25 三年级下·湖北孝感·期末"
+    },
+    {
+        "id":  "367",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "一个数除以7，余数可能是9。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】根据有余数除法的定义，余数必须小于除数。当除数是7时，余数必须小于7，据此解答。\n\n【详解】根据分析可知，余数必须小于7，而9大于7，所以一个数除以7，余数不可能是9，原题说法错误。故答案为: ×",
+        "knowledge_points":  [
+                                 "余数与除数的关系"
+                             ],
+        "source":  "24-25 三年级下·河南省直辖县级单位·期末"
+    },
+    {
+        "id":  "368",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "计算题",
+        "difficulty":  0.65,
+        "question":  "用竖式计算。\n25÷4= 56÷7= 32÷6= 63÷9=",
+        "options":  [
+
+                    ],
+        "answer":  "6……1;8;5……2;7",
+        "solution":  "【分析】有余数除法的计算方法：想除数和几相乘最接近被除数并且小于被除数，那么商就是几，写在被除数个位的上面;把除数和商相乘，把结果写在被除数下面;用被除数减去商与除数的乘积，所得的差写在横线下面;将余数与除数比一比，余数必须比除数小。根据乘法口诀求商时，口诀中的后一个数为被除数，前两个数一个作除数，一个作商。\n\n【详解】25÷4=6……1;56÷7=8;32÷6=5……2;63÷9=7。",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算",
+                                 "用7~9的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·河南三门峡·期末"
+    },
+    {
+        "id":  "369",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "计算题",
+        "difficulty":  0.65,
+        "question":  "列竖式计算。\n48÷8= 30÷4= 22÷7=",
+        "options":  [
+
+                    ],
+        "answer":  "6;7……2;3……1",
+        "solution":  "【分析】除法用竖式计算时，从最高位开始除起，若除不了，就用最高位和下一位合成一个数来除，直到能除以除数为止。若有余数，则余数一定比除数小。\n\n【详解】48÷8=6;30÷4=7……2;22÷7=3……1。",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算",
+                                 "用7~9的乘法口诀求商"
+                             ],
+        "source":  "24-25 二年级下·福建三明·期末"
+    },
+    {
+        "id":  "370",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "计算题",
+        "difficulty":  0.85,
+        "question":  "用竖式计算下面各题。\n29÷5= 56÷7= 70÷9=",
+        "options":  [
+
+                    ],
+        "answer":  "5……4;8;7……7",
+        "solution":  "【分析】对于每个算式，先找出最大整数商（使除数×商\u003c=被除数），然后从被除数中减去除数×商的积，得到余数。\n\n【详解】29÷5=5……4;56÷7=8;70÷9=7……7。",
+        "knowledge_points":  [
+                                 "两位数除以一位数的有余数除法",
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "24-25二年级下·四川乐山·期末"
+    },
+    {
+        "id":  "371",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "计算题",
+        "difficulty":  0.85,
+        "question":  "列竖式计算。\n54÷9= 31÷4= 50÷6=",
+        "options":  [
+
+                    ],
+        "answer":  "6;7……3;8……2",
+        "solution":  "【分析】100以内数除法列竖式计算，用乘法口诀来试商，商要与被除数的个位对齐，若有余数，余数要小于除数。有余数的除法的计算方法：一商，二乘，三减，四比。(1)商：即试商，想除数和几相乘最接近被除数且小于被除数，那么商就是几，写在被除数的个位的上面;(2)乘：把除数和商相乘，将得数写在被除数下面;(3)减：用被除数减去商与除数的乘积，所得的差写在横线的下面;(4)比：将余数与除数比一比，余数必须比除数小。\n\n【详解】54÷9=6;31÷4=7……3;50÷6=8……2。",
+        "knowledge_points":  [
+                                 "用7~9的乘法口诀求商",
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "24-25 二年级下·广东东莞·期末"
+    },
+    {
+        "id":  "372",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "计算题",
+        "difficulty":  0.85,
+        "question":  "用竖式计算。\n36÷9= 28÷5= 60÷8=",
+        "options":  [
+
+                    ],
+        "answer":  "4;5……3;7……4",
+        "solution":  "【分析】根据表内乘法口诀求商，用竖式计算，商直接和被除数的个位对齐。有余数的除法的计算方法：一商，二乘，三减，四比。(1)商：即试商，想除数和几相乘最接近被除数且小于被除数，那么商就是几，写在被除数的个位的上面;(2)乘：把除数和商相乘，将得数写在被除数下面;(3)减：用被除数减去商与除数的乘积，所得的差写在横线的下面;(4)比：将余数与除数比一比，余数必须比除数小。根据乘法口诀求商时，口诀中的后一个数作为被除数，前面两个数一个作除数，另一个作商。\n\n【详解】36÷9=4;28÷5=5……3;60÷8=7……4。",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "24-25 二年级下·湖北襄阳·期末"
+    },
+    {
+        "id":  "373",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "计算题",
+        "difficulty":  0.85,
+        "question":  "用竖式计算。\n45÷6= 70÷8= 52÷9=",
+        "options":  [
+
+                    ],
+        "answer":  "7……3;8……6;5……7",
+        "solution":  "【分析】有余数除法的计算方法：一商，二乘，三减，四比。(1)商：即试商，想除数和几相乘最接近被除数且小于被除数，那么商就是几，写在被除数的个位的上面;(2)乘：把除数和商相乘，把得数写在被除数下面;(3)减：用被除数减去商与除数的乘积，所得的差写在横线的下面;(4)比：将余数与除数比一比，余数必须比除数小。\n\n【详解】45÷6=7……3;70÷8=8……6;52÷9=5……7。",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "24-25 二年级下·重庆秀山·期末"
+    },
+    {
+        "id":  "374",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "\"六一\"儿童节，陈老师用一条长60分米的红丝带给小演员做头饰。每个头饰用7分米的红丝带，最多能做多少个头饰。",
+        "options":  [
+
+                    ],
+        "answer":  "8个",
+        "solution":  "【分析】红丝带的总长度除以每个头饰用的红丝带长度，得出能做的头饰数量，余下不够做一个头饰的红丝带长度，据此得出结论即可。\n\n【详解】60÷7=8(个)……4(分米)。答：最多能做8个头饰。",
+        "knowledge_points":  [
+                                 "有余数除法的实际应用"
+                             ],
+        "source":  "24-25 二年级下·河北保定·期末"
+    },
+    {
+        "id":  "375",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "小明用35根同样的小棒搭独立的正方形，最多可以搭几个。至少再添上几根这样的小棒，又可以搭一个正方形。",
+        "options":  [
+
+                    ],
+        "answer":  "8个;1根",
+        "solution":  "【分析】根据题意，用总数/每个正方形需要的数量=能搭成正方形的个数。剩余的数量，用每个正方形需要的数量-剩余的数量，就是至少再添的数量，据此解答。\n\n【详解】根据分析：35÷4=8(个)……3(根)，4-3=1(根)。答：最多可以搭8个，至少再添上1根这样的小棒，又可以搭一个正方形。",
+        "knowledge_points":  [
+                                 "有余数除法的实际应用"
+                             ],
+        "source":  "24-25二年级下·四川乐山·期末"
+    },
+    {
+        "id":  "376",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "王老师准备35个白珠子、28个红珠子和9个黄珠子，现要把这些珠子混装放在箱子里，要求一个箱子里只能放6个白珠子、4个红珠子和2个黄珠子，按此要求去混装，这些珠子最多能装在几个箱子里。",
+        "options":  [
+
+                    ],
+        "answer":  "4个",
+        "solution":  "【分析】要确定最多能装多少箱子，需分别计算每种珠子数除以每箱放的珠子数，求出的商是所能装的箱数;比较三种箱数，最小数就是这些珠子最多能装的箱子数。\n\n【详解】由分析可得：白珠子：35÷6=5(箱)……5(个);红珠子：28÷4=7(箱);黄珠子：9÷2=4(箱)……1(个)。7\u003e5\u003e4。答：这些珠子最多能装在4个箱子里。",
+        "knowledge_points":  [
+                                 "有余数除法的实际应用",
+                                 "100以内有余数的除法计算",
+                                 "用7~9的乘法口诀求商"
+                             ],
+        "source":  "24-25二年级下·山西长治·期末"
+    },
+    {
+        "id":  "377",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "两位老师带32名小朋友去乘船。\n(1)大船一条可坐6人，都坐大船至少要几条？\n(2)小船一条可坐4人，那么可以坐满几条小船？",
+        "options":  [
+
+                    ],
+        "answer":  "6条;8条",
+        "solution":  "【分析】(1)小朋友的人数加上老师的人数，等于一共有多少人，再用总人数除以一条大船可以坐的人数，求出结果，商是可以坐满几条大船，余数是还剩下多少人，剩下的人还需要坐1条大船，用商加1，即可求出都坐大船至少要几条，据此解答;(2)用总人数除以一条小船可以坐的人数，求出结果，商是可以坐满几条小船，余数是还剩下多少人，据此解答。\n\n【详解】(1)32+2=34(人)，34÷6=5(条)……4(人)，5+1=6(条)。答：都坐大船至少要6条。(2)32+2=34(人)，34÷4=8(条)……2(人)。答：可以坐满8条小船。",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算",
+                                 "有余数除法的实际应用"
+                             ],
+        "source":  "24-25 二年级下·浙江绍兴·期末"
+    },
+    {
+        "id":  "378",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "58个布娃娃，平均装在8个箱子里，每箱装几个？还剩几个？",
+        "options":  [
+
+                    ],
+        "answer":  "7个;2个",
+        "solution":  "【分析】将58个布娃娃平均分到8个箱子中，求每箱装的数量和剩余的数量，属于有余数的除法问题。用总数58除以箱子数8，商即为每箱装的数量，余数即为剩下的数量。\n\n【详解】58÷8=7(个)……2(个)。答：每箱装7个，还剩2个。",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "24-25 二年级下·湖南长沙·期末"
+    },
+    {
+        "id":  "379",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "丽丽按照\"我爱学数学我爱学数学我爱学数学……\"的规律写下去，第33个字是什么？",
+        "options":  [
+
+                    ],
+        "answer":  "学",
+        "solution":  "【分析】观察题目中的文字排列规律，发现\"我爱学数学\"这5个字为一个周期循环出现。要求第33个字是什么，用33除以5，商表示有几组这样的循环，余数是几，这一个循环中的第几个字就是要求的答案。\n\n【详解】33÷5=6(组)……3(个)。答：第33个字是学。",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算",
+                                 "有余数除法的实际应用",
+                                 "周期问题"
+                             ],
+        "source":  "24-25 二年级下·湖南长沙·期末"
+    },
+    {
+        "id":  "380",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "张师傅要做60个风筝，每天最多可以做7个。至少需要多少天才能做完。\n答：至少需要( )天才能做完。",
+        "options":  [
+
+                    ],
+        "answer":  "9天",
+        "solution":  "【分析】根据除法的意义，风筝的总数量/每天最多做的风筝数量=每天做满风筝需要的天数。剩余的风筝数量不满7个，但也需要单独用一天完成。所以每天做满风筝需要的天数+1，就是做完所有风筝最少需要的天数。由此列出算式算出答案即可解答。\n\n【详解】60÷7=8(天)……4(个)，8+1=9(天)。答：至少需要9天才能做完。",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算",
+                                 "有余数除法的实际应用"
+                             ],
+        "source":  "24-25 二年级下·重庆秀山·期末"
+    },
+    {
+        "id":  "381",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "张老师和何老师带着二年级60名同学去参加研学活动，至少需要租几辆车。\n![](images/7b5feffd075fff0cc5e1ffe56bbf9787.png)",
+        "options":  [
+
+                    ],
+        "answer":  "8辆",
+        "solution":  "【分析】先用加法算出总人数，然后用总人数除以每辆车的限乘人数，商就是需要的辆数，如果有余数，还需要加1辆。\n\n【详解】(2+60)÷8=62÷8=7(辆)……6(人)，7+1=8(辆)。答：至少需要租8辆车。",
+        "knowledge_points":  [
+                                 "图文问题",
+                                 "100以内有余数的除法计算",
+                                 "有余数除法的实际应用"
+                             ],
+        "source":  "24-25二年级下·广西河池·期末"
+    },
+    {
+        "id":  "382",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "将32只鸽子放进下面的鸽笼里。\n![](images/54955b52619c2a08ede8560e346d4fff.png)\n(1)如果都放进大笼里，至少要几个大鸽笼？\n(2)如果都放进小笼里，至少要几个小鸽笼？\n(3)大鸽笼和小鸽笼搭配，怎样能正好装下38只鸽子？",
+        "options":  [
+
+                    ],
+        "answer":  "5个;7个;5个大鸽笼和1个小鸽笼",
+        "solution":  "【分析】由题意可知：(1)用鸽子的总只数除以大笼放的鸽子数，得出的商是放的大笼数，余数是剩下的鸽子数，剩余的鸽子还需一个大笼来放，故至少需要商加1个大鸽笼;(2)用鸽子的总只数除以小笼放的鸽子数，得出的商是放的小笼数，余数是剩下的鸽子数，剩余的鸽子还需一个小笼来放，故至少需要商加1个小鸽笼;(3)用38只鸽子数除以大笼放的鸽子数，得出的商是放的大笼数，余数是剩下的鸽子数，剩余的鸽子正好可以放进1个小笼里。\n\n【详解】由分析可得：(1)32÷7=4(个)……4(只)，4+1=5(个)。答：至少要5个大鸽笼。(2)32÷5=6(个)……2(只)，6+1=7(个)。答：至少要7个小鸽笼。(3)38÷7=5(个)……3(只)。答：先用5个大鸽笼装，剩下的3只再用1个小鸽笼装，正好装下38只鸽子。",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算",
+                                 "有余数除法的实际应用"
+                             ],
+        "source":  "24-25 二年级下·山东菏泽·期末"
+    },
+    {
+        "id":  "383",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "李老师给孩子们准备了儿童节礼包。每个礼包中都有8支棒棒糖、4个果冻、2包薯片。下图中的物品最多可以包装成几个礼包？\n![](images/e1d9fc4db823af13d3267ed991abf055.png)",
+        "options":  [
+
+                    ],
+        "answer":  "6个",
+        "solution":  "【分析】由题意可知：分别算出棒棒糖、果冻、薯片最多可包装几个礼包，算出的得数进行比较，最小的那个数就是最多可以包装的礼包数，据此解答。\n\n【详解】棒棒糖：52÷8=6(个)……4(支)，最多能包装6个礼包。果冻：28÷4=7(个);薯片：14÷2=7(个)。7=7\u003e6。答：最多可以包装成6个礼包。",
+        "knowledge_points":  [
+                                 "用7~9的乘法口诀求商",
+                                 "100以内有余数的除法计算",
+                                 "有余数除法的实际应用"
+                             ],
+        "source":  "24-25二年级下·山西晋中·期末"
+    },
+    {
+        "id":  "384",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "二(1)班有32人，二(2)班有29人，去春游时每辆车坐9人，至少需要几辆车。",
+        "options":  [
+
+                    ],
+        "answer":  "7辆",
+        "solution":  "【分析】由题意可知：把二(1)班和二(2)班去的人数相加，算出一共去了多少人，再用去的总人数除以每辆车坐的人数，算出的商是坐满的车辆数，余数是剩余的人数，剩余的人数还需1辆车，故至少需要商+1辆车，据此解答。\n\n【详解】由题意可知：(32+29)÷9=61÷9=6(辆)……7(人)，6+1=7(辆)。答：至少需要7辆车。",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算",
+                                 "有余数除法的实际应用"
+                             ],
+        "source":  "24-25 二年级下·湖南长沙·期末"
+    },
+    {
+        "id":  "385",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "王老师带50元买6元一支的钢笔，最多能买几支。还剩多少元。",
+        "options":  [
+
+                    ],
+        "answer":  "8支;2元",
+        "solution":  "【分析】用王老师带的总钱数除以一支钢笔的钱数，商就是最多能买的支数，余数就是还剩的钱数。\n\n【详解】50÷6=8(支)。2(元)。答：最多能买8支，还剩2元。",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算",
+                                 "有余数除法的实际应用"
+                             ],
+        "source":  "24-25 二年级下·湖南长沙·期末"
+    },
+    {
+        "id":  "386",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "上杭永定土楼是世界上独一无二的民居建筑,2008年7月成功被列入《世界遗产名录》。二(1)班的同学到永定土楼参观，想买一些纪念品回去.\n![](images/7a66eecce2783e95678b2db69ea7743f.png)\n(1)东东有40元，最多可以买几个小号的土楼模型。\n(2)红红想买8个中号的土楼模型回去，还差5元。她一共有多少钱。\n(3)根据算式\"3×6+8\"结合上面的信息提出一个数学问题，再解答。数学问题:",
+        "options":  [
+
+                    ],
+        "answer":  "6个;59元;买3个小号土楼模型和一个中号土楼模型要多少钱。26元",
+        "solution":  "【分析】(1)东东的钱数除以一个小号土楼模型的钱数，等于最多可以买几个小号的土楼模型;(2)每个中号土楼模型乘红红想买的数量，减去还差的钱数，等于红红一共有多少钱;(3)根据算式\"3×6+8\"结合上面的信息可知，每个小号土楼模型是6元,6乘3，即3个小号土楼模型需要多少钱，每个中号土楼模型8元，则3×6+8，提出的数学问题是：买3个小号土楼模型和一个中号土楼模型要多少钱。根据给出的算式，求出答案即可。\n\n【详解】(1)40÷6=6(个)。4(元)。答：最多可以买6个小号的土楼模型。(2)8×8-5=64-5=59(元)。答：她一共有59元。(3)买3个小号土楼模型和一个中号土楼模型要多少钱。3×6+8=18+8=26(元)。答：买3个小号土楼模型和一个中号土楼模型要26元。",
+        "knowledge_points":  [
+                                 "\"提问题\"\"填条件\"问题",
+                                 "有余数除法的实际应用",
+                                 "乘加",
+                                 "乘减混合运算",
+                                 "表内乘加",
+                                 "乘减"
+                             ],
+        "source":  "23-24 二年级下·福建龙岩·期末"
+    },
+    {
+        "id":  "387",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "春天是一年中气候温暖，天气宜人的季节，适合户外活动。春游可以从大自然获得心灵启迪，使人心胸开阔。二年级3名老师带56名学生去春游，至少需要租几辆车。\n![](images/bc319da53d2184dd150c0478ac32e482.png)",
+        "options":  [
+
+                    ],
+        "answer":  "8辆",
+        "solution":  "【分析】根据题意可知：先求出一共去春游的人数，用老师的人数加学生的人数即可;然后用总人数除以每辆车限乘的人数求出商和余数，商是需要的车辆，余数为剩余的人数，剩余的人数也需要坐车，则需要的车辆数再加1即可。\n\n【详解】3+56=59(人),59÷8=7(辆)。3(人),7+1=8(辆)。答：至少需要租8辆车。",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算",
+                                 "有余数除法的实际应用"
+                             ],
+        "source":  "23-24 二年级下·福建龙岩·期末"
+    },
+    {
+        "id":  "388",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "水果店里有45千克苹果，每8千克苹果装一箱，可以装满几箱。还剩多少千克。",
+        "options":  [
+
+                    ],
+        "answer":  "5箱;5千克",
+        "solution":  "【分析】本题需要将45千克苹果按每8千克装一箱进行分配，属于整数除法问题。通过计算45除以8的商和余数，商即为装满的箱数，余数为剩余的苹果重量。\n\n【详解】45÷8=5(箱)。5(千克)。答：可以装满5箱，还剩5千克。",
+        "knowledge_points":  [
+                                 "用7~9的乘法口诀求商",
+                                 "有余数除法的实际应用"
+                             ],
+        "source":  "24-25 二年级下·山东临沂·期末"
+    },
+    {
+        "id":  "389",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "二(3)班38个同学参加研学活动酒店住宿，每个房间最多住6人。他们至少需要几间房。",
+        "options":  [
+
+                    ],
+        "answer":  "7间",
+        "solution":  "【分析】用参加研学的总人数除以每个房间最多住的人数，即可求出至少需要几间房;若正好被整除，则商就是需要房间的数量;若有余数，则商加1即是至少需要房间的数量。\n\n【详解】38÷6=6(间)。2(人),6+1=7(间)。答：他们至少需要7间房。",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算",
+                                 "有余数除法的实际应用"
+                             ],
+        "source":  "24-25 二年级下·四川乐山·期末"
+    },
+    {
+        "id":  "390",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "妈妈买了50个鸡蛋，每个包装盒最多装8个鸡蛋，至少要准备几个包装盒才能全部装下。",
+        "options":  [
+
+                    ],
+        "answer":  "7个",
+        "solution":  "【分析】先用鸡蛋总数50除以每盒8个，得到的商是可以装满的盒数，余数是剩余的鸡蛋。因为要全部装下，所以剩余的鸡蛋还需要1个盒子，装满的盒数加上1就是需要准备的包装盒数。\n\n【详解】50÷8=6(个)……2(个)，6+1=7(个)。答：至少要准备7个包装盒才能全部装下。",
+        "knowledge_points":  [
+                                 "有余数除法的实际应用"
+                             ],
+        "source":  "24-25 二年级下·湖北襄阳·期末"
+    },
+    {
+        "id":  "391",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "猫妈妈钓了20多条鱼，如果平均分给4只猫宝宝，多1条，如果平均分给6只猫宝宝，也还多1条，猫妈妈钓了多少条鱼。",
+        "options":  [
+
+                    ],
+        "answer":  "25条",
+        "solution":  "【分析】平均分给4只猫宝宝多1条，说明鱼的总数除以4，余数是1;平均分给6只猫宝宝多1条，说明鱼的总数除以6，余数也是1，用列举法找到符合条件的数，据此解答。\n\n【详解】(1)平均分给4只猫宝宝的情况：平均分给4只猫宝宝多1条，可表示为鱼的总数÷4=商……1。因为鱼有20多条，根据4的乘法口诀：4×5=20，此时鱼可能有20+1=21(条)，即21÷4=5(条)……1(条);4×6=24，此时鱼可能有24+1=25(条)，即25÷4=6(条)……1(条);4×7=28，此时鱼可能有28+1=29(条)，即29÷4=7(条)……1(条)。\n(2)平均分给6只猫宝宝的情况：平均分给6只猫宝宝多1条，可表示为鱼的总数÷6=商……1。因为鱼有20多条，根据6的乘法口诀：6×4=24，此时鱼可能有24+1=25(条)，即25÷6=4(条)……1(条)。\n同时满足平均分给4只猫宝宝多1条、平均分给6只猫宝宝多1条且在20多条的，只有25条。答：猫妈妈钓了25条鱼。",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算",
+                                 "有余数除法的实际应用"
+                             ],
+        "source":  "24-25 二年级下·湖南长沙·期末"
+    },
+    {
+        "id":  "392",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "参加二年级男子组100米比赛的有30名同学，现在要给他们分组，每组最多8人，至少要分成多少组。",
+        "options":  [
+
+                    ],
+        "answer":  "4组",
+        "solution":  "【分析】根据题意，用总人数/每组最多的人数=满人的组数。若有剩余人数，满人的组数加1即可解答。\n\n【详解】30÷8=3(组)……6(人)，3+1=4(组)。答：至少要分成4组。",
+        "knowledge_points":  [
+                                 "有余数除法的实际应用"
+                             ],
+        "source":  "24-25 二年级下·河北邢台·期末"
+    },
+    {
+        "id":  "393",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "为了让同学们了解航天方面的知识，学校购进了50本与航天相关的图书，如果把这些书平均分给二年级9个班，每个班最多能分到几本，还剩几本。",
+        "options":  [
+
+                    ],
+        "answer":  "5本;5本",
+        "solution":  "【分析】本题是将50本图书平均分给9个班，属于有余数的除法问题。根据除法的定义，总本数/班级数=每班分到的本数。余下的本数，余数必须小于除数。\n\n【详解】50÷9=5(本)。5(本)。答：每个班最多能分到5本，还剩5本。",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算",
+                                 "有余数除法的实际应用"
+                             ],
+        "source":  "24-25二年级下·江西上饶·期末"
+    },
+    {
+        "id":  "394",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "如果把4盆白月季、3盆红月季和2盆紫月季摆成一个圆形造型，这些花最多可以摆成几个这样的造型？\n\n| 白月季花 | 30盆 |\n| -------- | ---- |\n| 红月季花 | 28盆 |\n| 紫月季花 | 19盆 |",
+        "options":  [
+
+                    ],
+        "answer":  "7个",
+        "solution":  "【分析】由题意可知：用白月季花的盆数除以每组的盆数，求出的商即是白月季花能分的组数;用红月季花的盆数除以每组的盆数，求出的商即是红月季花能分的组数;用紫月季花的盆数除以每组的盆数，求出的商即是紫月季花能分的组数;把这三种月季花能分的组数按从小到大的顺序排列，找出最少的组数，即是这些花最多可以摆成的造型数，据此解答。\n\n【详解】由分析可得：30÷4=7(组)……2(盆);28÷3=9(组)……1(盆);19÷2=8(组)……1(盆);7\u003c8\u003c9。答：这些花最多可以摆成7个这样的造型。",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算",
+                                 "有余数除法的实际应用"
+                             ],
+        "source":  "24-25二年级下·江西上饶·期末"
+    },
+    {
+        "id":  "395",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "现有16枝玫瑰、25枝百合和32枝康乃馨。如果用3枝玫瑰、4枝百合和8枝康乃馨扎成一束花，这些花最多可以扎成多少束？",
+        "options":  [
+
+                    ],
+        "answer":  "4束",
+        "solution":  "【分析】先用有余数的除法分别计算出玫瑰3枝一束、百合4枝一束和康乃馨8枝一束，各自最多可以分成几束;再取束数最少的，作为最后的结果即可。\n\n【详解】16÷3=5(束)……1(枝);25÷4=6(束)……1(枝);32÷8=4(束);4\u003c5\u003c6。答：这些花最多可以扎成4束。",
+        "knowledge_points":  [
+                                 "有余数除法的实际应用"
+                             ],
+        "source":  "24-25 二年级下·湖北武汉·期末"
+    },
+    {
+        "id":  "396",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "仓库要运走56箱牛奶，每次能运9箱，至少要多少次才能运完。",
+        "options":  [
+
+                    ],
+        "answer":  "7次",
+        "solution":  "【分析】本题属于有余数的除法应用问题。已知总共有56箱牛奶，每次运9箱，求至少需要多少次才能运完。根据除法计算，56除以9得到商6余2，即运6次后还剩2箱，因此需要再加1次才能全部运完。\n\n【详解】56÷9=6(次)……2(箱)，余下的2箱需要再运1次，总次数为：6+1=7(次)。答：至少要7次才能运完。",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算",
+                                 "有余数除法的实际应用"
+                             ],
+        "source":  "24-25 二年级下·湖北黄石·期末"
+    },
+    {
+        "id":  "397",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "学校举行\"爱阅读\"的读书节活动，小芳准备阅读一本共有70页的科学书，每天看8页。小芳看完这本书至少需要多少天？",
+        "options":  [
+
+                    ],
+        "answer":  "9天",
+        "solution":  "【分析】由题意可知：用这本科学书的总页数除以每天看的页数，求出的商是看的天数，余数是剩余的页数，不管剩余几页，都需要再看一天，故看完这本书至少需要商加1天，据此解答。\n\n【详解】由分析可得：70÷8=8(天)……6(页)，8+1=9(天)。答：小芳看完这本书至少需要9天。",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算",
+                                 "有余数除法的实际应用"
+                             ],
+        "source":  "24-25二年级下·浙江温州·期末"
+    },
+    {
+        "id":  "398",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "一共38个圈，图一：![](images/a664840f1bceb2c86a4040ef0488cb1c8eaea924b3950d8640468c565756a4dc.jpg)\n(1)乐乐想做成图一，这些能做成几个？\n(2)乐乐想做8个图一，还差几个○？",
+        "options":  [
+
+                    ],
+        "answer":  "7个;2个",
+        "solution":  "【分析】(1)根据题意可知，做一个需要5个○，要求乐乐可以做成几个，用○的总数量/做成一个需要○的数量，商就是最多能做成的个数;(2)根据题意，先用做一个需要○的数量和要做8个的数量相乘，求出一共需要多少个○，再减去现有○的数量，就是还差的数量。\n\n【详解】(1)38÷5=7(个)……3(个)。答：这些能做成7个。(2)5×8-38=40-38=2(个)。答：还差2个○。",
+        "knowledge_points":  [
+                                 "有余数除法的实际应用",
+                                 "乘加",
+                                 "乘减混合运算"
+                             ],
+        "source":  "25-26三年级·全国·假期作业"
+    },
+    {
+        "id":  "399",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "有23个同学去春游。\n![](images/bc8c3be07e057d83193c379e8b157f8f.png)\n(1)如果都住大房，至少要几间大房？\n(2)如果大房和小房都住，并且每个房间都住满，可以怎样安排？",
+        "options":  [
+
+                    ],
+        "answer":  "6间;大房5间，小房1间",
+        "solution":  "【分析】(1)用总人数除以每间大房可以住的人数，商就是需要的房间数，如果有余数，则再加1间房。(2)用总人数除以每间大房可以住的人数，商就是需要的大房间数，然后根据余数进行调整，直到房间都住满即可。\n\n【详解】(1)23÷4=5(间)……3(人)，5+1=6(间)。答：至少要6间大房。(2)23÷4=5(间)……3(人)，剩下的3人正好住1间小房。答：可以安排大房5间，小房1间。",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算",
+                                 "有余数除法的实际应用"
+                             ],
+        "source":  "23-24 二年级下·河南信阳·期末"
+    },
+    {
+        "id":  "400",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "二(1)班一共有31人，至少需要租几条船。他们一共需要交租船费64元，每条船的租金是多少钱。\n![](images/b37a5721e22d44f2c26784a89873ac37.png)",
+        "options":  [
+
+                    ],
+        "answer":  "8条;8元",
+        "solution":  "【分析】根据有余数的除法的意义，班级总人数/每条船限乘人数=能坐满的船的数量。剩余的人数需要另外再租一条船才能全员上船，所以需要在能坐满的船的数量基础上加1，才是最少需要租船的数量。根据除法的意义，租船的总费用/租船的数量=每条船的租金，列出算式算出答案即可解答。\n\n【详解】31÷4=7(条)……3(人)，7+1=8(条);64÷8=8(元)。答：至少需要租8条船，每条船的租金是8元。",
+        "knowledge_points":  [
+                                 "用7~9的乘法口诀求商",
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "23-24 二年级下·山东临沂·期末"
+    },
+    {
+        "id":  "401",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "一条布带长25米，剪成每段长3米的布条做围巾，最多能做( )条围巾。",
+        "options":  [
+                        "A. 6",
+                        "B. 7",
+                        "C. 8",
+                        "D. 9"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】根据题意，用布带的总长度除以做每条围巾用的长度，商就是最多能做成围巾的数量。\n\n【详解】25÷3=8(条)……1(米)。最多能做8条围巾。故答案为:C",
+        "knowledge_points":  [
+                                 "有余数除法的实际应用"
+                             ],
+        "source":  "23-24 二年级下·广东东莞·期末"
+    },
+    {
+        "id":  "402",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "下面算式中，商最小的是( )。",
+        "options":  [
+                        "A. 54÷7=7……5",
+                        "B. 64÷8=8",
+                        "C. 27÷3=9",
+                        "D. 23÷8=2……7"
+                    ],
+        "answer":  "D",
+        "solution":  "【分析】除法算式为：被除数÷除数=商;有余数的除法算式为：被除数÷除数=商……余数，由此找出各算式的商比较大小即可。\n\n【详解】A. 商是7;B. 商是8;C. 商是9;D. 商是2;9\u003e8\u003e7\u003e2，则商最小的是23÷8=2……7。故答案为:D",
+        "knowledge_points":  [
+                                 "有余数除法的认识",
+                                 "除法的初步认识"
+                             ],
+        "source":  "23-24 二年级下·广东东莞·期末"
+    },
+    {
+        "id":  "403",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "有18个梨，平均放在4个盘子里，每个盘子里放几个，还剩几个。用下面的竖式计算，箭头所指的数表示的意思是( )。\n![](images/28ee21f0e31653c34fcceedbb58b9e8219977c7f8e4a6cad2551699517e0061b.jpg)",
+        "options":  [
+                        "A. 一共有16个梨",
+                        "B. 还剩下16个梨",
+                        "C. 4个盘子里一共放了16个梨",
+                        "D. 每盘有16个梨"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】根据题意，梨的总数量÷平均放的盘子数量=每盘放梨的数量，还剩梨的数量。用竖式计算时，除号里面是被除数，即梨的总数量;除号左边是除数，即平均放的盘子数量;除号上面是商，即每盘放的数量;被除数下面是除数和商的积，即4个盘子里一共放了多少个梨;最下边是余数，即剩下梨的数量，由此解答。\n\n【详解】A. 一共有18个梨，不符合题意;B. 还剩下2个梨，不符合题意;C. 4×4=16(个)，4个盘子里一共放了16个梨，符合题意;D. 每盘有4个梨，不符合题意。则箭头所指的数表示4个盘子里一共放了16个梨。故答案为:C",
+        "knowledge_points":  [
+                                 "有余数除法的实际应用",
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "23-24 二年级下·广东东莞·期末"
+    },
+    {
+        "id":  "404",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "☆□△○☆□△○☆□△○……按照上面这些图形的规律排下去，第29个图形应该是( )。",
+        "options":  [
+                        "A. ☆",
+                        "B. □",
+                        "C. △",
+                        "D. ○"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】由题意可知：通过观察图形的规律是按☆□△○的顺序，4个为一组不断重复出现;用29除以每组图形数，商是组数，余数是几就对应每组的第几个图形，即能找出正确答案，据此解答。\n\n【详解】由分析可得：29÷4=7(组)……1(个)，余数1对应每组的第一个图形是☆。故答案为:A",
+        "knowledge_points":  [
+                                 "周期问题",
+                                 "图形的变化规律",
+                                 "有余数除法的实际应用"
+                             ],
+        "source":  "24-25二年级下·山东菏泽·期末"
+    },
+    {
+        "id":  "405",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "除数和商都是8，余数是3，被除数是( )。",
+        "options":  [
+                        "A. 67",
+                        "B. 32",
+                        "C. 19"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】根据题意，被除数=商×除数+余数，据此解答。\n\n【详解】根据分析：8×8+3=64+3=67，被除数是67。故答案为:A",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算",
+                                 "有余数的除法验算"
+                             ],
+        "source":  "24-25 二年级下·河北邢台·期末"
+    },
+    {
+        "id":  "406",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "有17块糖，至少再添上( )块就可以平均分给4个小朋友。",
+        "options":  [
+                        "A. 1",
+                        "B. 2",
+                        "C. 3"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】根据题意可知，用总数除以小朋友的人数，即17÷4=4(块)……1(块)，得到每个小朋友平均分得4块，余1块，用小朋友人数减去余数，即4-1=3(块)，即可得到至少再添上3块就可以平均分给4个小朋友。\n\n【详解】17÷4=4(块)……1(块)，4-1=3(块)。至少再添上3块就可以平均分给4个小朋友。故答案为:C",
+        "knowledge_points":  [
+                                 "有余数除法的实际应用"
+                             ],
+        "source":  "24-25二年级下·内蒙古赤峰·期中"
+    },
+    {
+        "id":  "407",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "一盘炸黄花鱼有27条，至少减少( )条才能平均分给7人。",
+        "options":  [
+                        "A. 6",
+                        "B. 7",
+                        "C. 8"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】用总数除以平均分给的人数，余数是几就说明还剩几条，至少需要减少剩下的条数。\n\n【详解】27÷7=3(条)……6(条)，至少减少6条才能平均分给7人。故答案为:A",
+        "knowledge_points":  [
+                                 "有余数除法的实际应用",
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "24-25 二年级下·河北石家庄·期中"
+    },
+    {
+        "id":  "408",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "看下面的除法竖式，下列说法正确的是( )。\n![](images/113956.png)",
+        "options":  [
+                        "A. 5是被除数",
+                        "B. 45表示5乘9的积",
+                        "C. 9可以写在个位上，也可以写在十位上"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】根据题意，熟练掌握竖式计算。用竖式计算时，除数是一位数的除法从被除数的最高位除起，每次先用除数试除被除数的前一位数，如果它比除数小，再试除前两位数。除到被除数的哪一位，就把商写在那一位上面。每求出一位商，余下的数必须比除数小。逐个选项进行分析，即可解答。\n\n【详解】根据分析：A. 5是除数，原说法错误。B. 45表示5乘9的积，原说法正确。C. 9只能写在个位上，原说法错误。故答案为:B",
+        "knowledge_points":  [
+                                 "有余数除法的认识"
+                             ],
+        "source":  "24-25 二年级下·山东济宁·期末"
+    },
+    {
+        "id":  "409",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "用19元钱买3元一个的笔记本，下面竖式中\"6\"的含义是( )。\n![](images/114002.png)",
+        "options":  [
+                        "A. 可以买6个笔记本",
+                        "B. 用去了6元钱",
+                        "C. 还剩6元钱"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】根据有余数的除法，总金额÷笔记本的单价=能购买的笔记本数量，剩余的是钱数。其中总金额是被除数，笔记本的单价是除数，能购买的笔记本数量是商，剩余的金额是余数。结合竖式中各个位置代表的意义，即可解答。\n\n【详解】根据分析可知，6所在的位置是商，表示能够购买的笔记本数量。所以竖式中\"6\"的含义是可以买6个笔记本。故答案为:A",
+        "knowledge_points":  [
+                                 "有余数除法的认识"
+                             ],
+        "source":  "23-24二年级下·重庆大渡口·期末"
+    },
+    {
+        "id":  "410",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "◇○○△◇○○△◇○○△。按照这样的规律排下去，第23个图形是( )。",
+        "options":  [
+                        "A. ◇",
+                        "B. ○",
+                        "C. △"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】根据题意，这组图形按◇○○△的顺序排列，4个图形为一个周期。确定周期后，用总数量23除以周期，如果正好是整数个周期，结果为周期的最后一个;如果有余数，余数是几，结果就是下一个周期中的第几个图形，据此解答。\n\n【详解】23÷4=5(组)……3(个)，这组图形排了5个周期，余下3个图形，所以第23个图形是○。故答案为:B",
+        "knowledge_points":  [
+                                 "周期问题",
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "23-24二年级下·湖南长沙·期末"
+    },
+    {
+        "id":  "411",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "东东今天练习写毛笔字\"白日依山尽\"，按顺序重复写了几遍后，东东写完\"山\"字就停笔了。他可能一共写了( )个字。",
+        "options":  [
+                        "A. 25",
+                        "B. 24",
+                        "C. 23"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】\"山\"是这句话的第4个字，用各项中的数字除以这句话的字数，找出余数是4的即可。\n\n【详解】A. 25÷5=5(遍)，没有余数，不符合题意;B. 24÷5=4(遍)……4(个)，符合题意;C. 23÷5=4(遍)……3(个)，不符合题意。他可能一共写了24个字。故答案为:B",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "23-24二年级下·湖北荆州·期末"
+    },
+    {
+        "id":  "412",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "把一些糖果平均分给6个人。如果有剩余，可能剩( )颗。",
+        "options":  [
+                        "A. 12",
+                        "B. 7",
+                        "C. 6",
+                        "D. 4"
+                    ],
+        "answer":  "D",
+        "solution":  "【分析】有余数的除法算式为：被除数÷除数=商……余数，可以表示把被除数平均分成除数的份数，商是每份的数，余数是剩下的数，其中余数一定小于除数，也就是剩下糖果的数量一定小于平均分的人数，即小于6，由此解答。\n\n【详解】A. 12\u003e6，不符合题意;B. 7\u003e6，不符合题意;C. 6=6，不符合题意;D. 4\u003c6，符合题意。则可能剩4颗。故答案为:D",
+        "knowledge_points":  [
+                                 "余数与除数的关系"
+                             ],
+        "source":  "23-24 二年级下·广东东莞·期末"
+    },
+    {
+        "id":  "413",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "用一些小棒摆，如果有剩余，那么剩余的小棒根数有( )种可能。",
+        "options":  [
+                        "A. 4",
+                        "B. 5",
+                        "C. 6"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】根据在有余数的除法中，余数总比除数小，而这堆小棒的总数相当于被除数，摆一个六边形需要的6根小棒相当于除数，剩余的小棒数相当于余数。把剩下有几根小棒的情况写出来，数一数有几种，据此解答即可。\n\n【详解】用一些小棒摆，如果有剩余，那么剩余的小棒根数可能是1、2、3、4、5，共有5种可能。故答案为:B",
+        "knowledge_points":  [
+                                 "余数与除数的关系"
+                             ],
+        "source":  "23-24 二年级下·河南信阳·期末"
+    },
+    {
+        "id":  "414",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "按照下图串手链，第35颗是( )。\n![](images/8211ef28a113603b9d0cdba70e533d906084316de925306a47bbd76120a0658d.jpg)",
+        "options":  [
+                        "A. ●",
+                        "B. ○",
+                        "C. △"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】通过观察这组图形，可以发现这四个图形为一组，按规律重复出现。用图形的位置数除以4，看余数是几，就是一组中的第几个图形，没有余数就是组中的最后一个，据此即可解答。\n\n【详解】35÷4=8(组)……3(个)，说明第35颗是第9组中的第3颗，即是△。故答案为:C",
+        "knowledge_points":  [
+                                 "图形的变化规律",
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "23-24二年级下·重庆大渡口·期末"
+    },
+    {
+        "id":  "415",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "按照下面的规律摆，在前面38个图形中，○有( )个。\n☆☆○○○☆☆○○○……",
+        "options":  [
+                        "A. 24",
+                        "B. 22",
+                        "C. 21",
+                        "D. 15"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】图形按☆☆○○○的顺序循环排列，一组5个。38除以每组的个数，商就是有这样的几组，余数是剩下的个数，再数一数剩下的图形中有多少个○。用组数乘每组中○的个数，再加上余数中○的个数即可。\n\n【详解】根据分析可得：38÷5=7(组)……3(个)，有这样的7组，还剩下3个。每组中有3个○，剩下的3个图形中有1个○。7×3+1=21+1=22(个)。因此，在前面38个图形中，○有22个。故答案为:B",
+        "knowledge_points":  [
+                                 "图形的变化规律",
+                                 "乘加",
+                                 "乘减混合运算",
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "23-24 二年级下·广东东莞·期末"
+    },
+    {
+        "id":  "416",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "☆○▽■◎☆○▽■◎☆○▽■◎……按照上面这些图形的规律排下去，第39个图形应该是( )。",
+        "options":  [
+                        "A. ■",
+                        "B. ☆",
+                        "C. ○",
+                        "D. ▽"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】通过观察这组图形，可以发现是以\"☆○▽■◎\"这五个图形为一组的规律重复出现，用图形的位置数除以5，看余数是几，就是一组中的第几个图形，没有余数就是一组中的最后一个。据此即可解答。\n\n【详解】39÷5=7(组)……4(个)，说明第39个图形应该是第8组中的第4个，即是■。故答案为:A",
+        "knowledge_points":  [
+                                 "图形的变化规律",
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "23-24 二年级下·山东菏泽·期末"
+    },
+    {
+        "id":  "417",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "3位老师和19个学生坐船过河，每条船最多坐6人，至少要( )只船才能一次就把他们送到对岸。",
+        "options":  [
+                        "A. 3",
+                        "B. 4",
+                        "C. 5"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】求至少需要几只船才能一次就把他们送到对岸，根据\"总人数÷每只船最多乘坐的人数=所需船的只数\"进行解答。若有余数，则需要再多1只船把剩余的人送去对岸。\n\n【详解】(3+19)÷6=22÷6=3(只)……4(人)，3+1=4(只)。答：至少要4只船。故答案为:B",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算",
+                                 "有余数除法的实际应用"
+                             ],
+        "source":  "22-23 二年级下·新疆乌鲁木齐·期中"
+    },
+    {
+        "id":  "418",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "有18个苹果，平均分给5个小朋友。下面竖式中的15表示( )。\n![](images/114022.png)",
+        "options":  [
+                        "A. 每人分到15个苹果",
+                        "B. 还剩15个苹果",
+                        "C. 分掉了15个苹果"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】有余数除法竖式计算时，除号里面写被除数，除号左边写除数，商写在除号上面，商乘除数的结果写在被除数下面对应位置，然后计算余数，余数要比除数小，据此解答。\n\n【详解】由分析可得：15是商乘除数的结果，5×3=15(个)，表示分掉了15个苹果。故答案为:C",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "23-24 二年级下·浙江台州·期末"
+    },
+    {
+        "id":  "419",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "小明拿20元钱去买3元一支的笔，最多可以买几支。如图竖式中虚框所指的部分表示( )。\n![](images/d195db2875c45626811d9909d9aa7335d58952c9ff13eaadc199e862cbae6fcd.jpg)",
+        "options":  [
+                        "A. 共有18元钱",
+                        "B. 花掉18元钱",
+                        "C. 还剩18元"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】虚框中的18是3乘6得到的，即一支笔的价钱乘可以买的支数，所以18表示一共用了18元钱。\n\n【详解】小明拿20元钱去买3元一支的笔，最多可以买6支，还剩2元。虚框中的18为3×6=18(元)，所以竖式中虚框所指的部分表示花掉18元钱。故答案为:B",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "23-24 二年级下·河南信阳·期末"
+    },
+    {
+        "id":  "420",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "选择题",
+        "difficulty":  0.94,
+        "question":  "有13根小棒，每4根分一组，结果怎样。如图竖式中的12表示( )。\n![](images/114046.png)",
+        "options":  [
+                        "A. 还剩12根小棒",
+                        "B. 可以分成12组",
+                        "C. 分掉的12根小棒"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】根据除法竖式的意义，竖式中的13是一共有13根小棒，4是除数，即每4根分一组，3是商，即可以分3组，12是3和4的积，表示分掉的12根小棒，1是余数，表示还剩下小棒的根数，据此解答。\n\n【详解】A. 还剩12根小棒，是错误的，应该还剩下1根小棒;B. 可以分成12组，是错误的，应该可以分3组;C. 分掉的12根小棒，是正确的。故答案为:C",
+        "knowledge_points":  [
+                                 "有余数除法的实际应用",
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "23-24 二年级下·浙江嘉兴·期末"
+    },
+    {
+        "id":  "421",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "53位老师乘车外出学习，每辆车坐9人(司机除外)，能坐满几辆车，还剩几人。竖式中圈出的数表示( )。\n![](images/0c25724dbe4b45b14b1b3f96cad662765a7af3b531ed34d32273739f204bd1d0.jpg)",
+        "options":  [
+                        "A. 还剩下的45人",
+                        "B. 坐上车的45人",
+                        "C. 能坐满45辆车"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】根据题意可知，每辆车能坐9人，商是5，则表示坐满5辆车，5辆车可坐5×9=45(人)，据此解答即可。\n\n【详解】由分析知：竖式中圈出的数表示坐上车的45人。故答案为:B",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "23-24 二年级下·湖南长沙·期末"
+    },
+    {
+        "id":  "422",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "○÷6=6……△，○最大能填( )。",
+        "options":  [
+                        "A. 36",
+                        "B. 38",
+                        "C. 41",
+                        "D. 5"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】有余数的除法算式为：被除数÷除数=商……余数，其中余数一定小于除数。余数最大时，被除数最大，余数最大是比除数小1的数，根据除数×商+余数=被除数，计算即可。\n\n【详解】6-1=5;6×6+5=36+5=41。○÷6=6……△，○最大能填41。故答案为:C",
+        "knowledge_points":  [
+                                 "余数与除数的关系",
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "23-24 二年级下·福建龙岩·期末"
+    },
+    {
+        "id":  "423",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "根据下面图形的排列规律，猜一猜，第18个图形是( )。\n☆☆○△△☆☆○△△☆☆○△△……",
+        "options":  [
+                        "A. ☆",
+                        "B. ○",
+                        "C. △"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】这组图形按照☆☆○△△为一组重复排列，每组有5个图形。求第18个图形，则用18除以每组图形的数量，若能除尽，则是这组的最后一个图形;若除不尽，则余数是几就是下一组的第几个图形。\n\n【详解】18÷5=3(组)……3(个)，第18个图形是第4组的第3个，是○。故答案为:B",
+        "knowledge_points":  [
+                                 "有余数除法的实际应用",
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "23-24二年级下·江西九江·期末"
+    },
+    {
+        "id":  "424",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "一个数除以8，所得的余数最大是( )。",
+        "options":  [
+                        "A. 任何数",
+                        "B. 0",
+                        "C. 7",
+                        "D. 9"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】有余数的除法算式为：被除数÷除数=商……余数，其中余数一定小于除数且不为0，余数最大是比除数小1的数，由此解答。\n\n【详解】由分析得：8是除数，余数最大是8-1=7。则一个数除以8，所得的余数最大是7。故答案为:C",
+        "knowledge_points":  [
+                                 "余数与除数的关系"
+                             ],
+        "source":  "24-25 二年级下·河南周口·期末"
+    },
+    {
+        "id":  "425",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "王阿姨有18个红气球、36个黄气球、25个蓝气球。若用4个红气球、7个黄气球、3个蓝气球扎成一束，这些气球最多可以扎成( )束。",
+        "options":  [
+                        "A. 4",
+                        "B. 5",
+                        "C. 6"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】先用每种颜色的气球总数分别除以每一束需要的对应颜色的气球个数，即可求出红气球、黄气球、蓝气球分别够单独扎几束。然后取它们的最小值，即为这些气球最多可以扎成多少束。\n\n【详解】18÷4=4(束)……2(个);36÷7=5(束)……1(个);25÷3=8(束)……1(个);4\u003c5\u003c8。因此这些气球最多可以扎成4束。故答案为:A",
+        "knowledge_points":  [
+                                 "有余数除法的实际应用"
+                             ],
+        "source":  "23-24二年级下·湖南长沙·期末"
+    },
+    {
+        "id":  "426",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "一袋梨在20~30个之间。平均分给4人还剩1个，平均分给6人也剩1个，这袋梨有( )个。",
+        "options":  [
+                        "A. 24",
+                        "B. 25",
+                        "C. 26"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】根据题意，分别把每个选项中的数据代入进行计算，看看是否和题干相符，据此解答。\n\n【详解】A. 24÷4=6(个)，与题意不符。B. 25÷4=6(个)……1(个);25÷6=4(个)……1(个)，与题意相符。C. 26÷4=6(个)……2(个)，与题意不符。故答案为:B",
+        "knowledge_points":  [
+                                 "有余数除法的实际应用"
+                             ],
+        "source":  "23-24二年级下·浙江台州·期末"
+    },
+    {
+        "id":  "427",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "36只动物，每间房子最多可以住7只动物，至少要( )间房子。",
+        "options":  [
+                        "A. 4",
+                        "B. 5",
+                        "C. 6"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】根据题意，用动物的总数÷每间房子最多可以住7只动物=住满的房间数量。剩余的只数，因为有余数，需要多一间房子，据此解答。\n\n【详解】根据分析：36÷7=5(间)……1(只)，5+1=6(间)。至少要6间房子。故答案为:C",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算",
+                                 "有余数除法的实际应用"
+                             ],
+        "source":  "23-24 二年级下·甘肃天水·期末"
+    },
+    {
+        "id":  "428",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "二(1)班40名同学去秋游，每辆缆车可以坐6人，小明前面还有24人在排队，他最快可以坐第( )辆缆车。",
+        "options":  [
+                        "A. 4",
+                        "B. 5",
+                        "C. 6"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】根据题意可知，小明前面还有24人在排队，他前面的人数加上1，等于小明排在第几名。小明排的名次数除以每辆缆车可以坐的人数，求出结果，商是可以坐满的缆车数，余数表示还剩下几人，坐满的缆车数加上1，就是他最快可以坐第几辆缆车，据此解答。\n\n【详解】根据分析可得：24+1=25(人)，25÷6=4(辆)……1(人)，4+1=5(辆)。因此，他最快可以坐第5辆缆车。故答案为:B",
+        "knowledge_points":  [
+                                 "有余数除法的实际应用",
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "23-24二年级下·浙江嘉兴·期末"
+    },
+    {
+        "id":  "429",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "一个除法算式中，算得的余数是3，那么除数最小是( )。",
+        "options":  [
+                        "A. 2",
+                        "B. 4",
+                        "C. 3"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】在除法算式中，余数必须比除数小。已知余数是3，因此除数必须大于3，除数最小是:3+1=4。据此解答。\n\n【详解】根据余数的性质，余数必须小于除数。题目中余数为3，所以除数必须满足除数\u003e3。由分析可知，除数最小是4，对应选项B。故答案为:B",
+        "knowledge_points":  [
+                                 "余数与除数的关系"
+                             ],
+        "source":  "24-25三年级下·山东济南·期中"
+    },
+    {
+        "id":  "430",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "选择题",
+        "difficulty":  0.85,
+        "question":  "米米用小棒摆□，剩下的不够摆一个△，她可能有( )根小棒。",
+        "options":  [
+                        "A. 23",
+                        "B. 19",
+                        "C. 15"
+                    ],
+        "answer":  "C",
+        "solution":  "【分析】根据有余数除法的意义，用各个选项除以4，因为剩下的不够摆一个△，所以余数要小于3，据此解答即可。\n\n【详解】A. 23÷4=5……3，剩下的小棒刚好摆一个△，不符合题意;B. 19÷4=4……3，剩下的小棒刚好摆一个△，不符合题意;C. 15÷4=3……2，剩下的小棒不够摆一个△，符合题意。所以米米可能有15根小棒。故答案为:C",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "23-24 二年级下·湖北省直辖县级单位·期末"
+    },
+    {
+        "id":  "431",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "张老师有28个苹果，至少要添上( )个，才能正好平均分给6个小朋友。",
+        "options":  [
+                        "A. 4",
+                        "B. 2",
+                        "C. 3"
+                    ],
+        "answer":  "B",
+        "solution":  "【分析】用苹果总数除以小朋友的人数，商是每个小朋友分得的个数，余数是还剩的个数，最后用人数减去还剩的个数即可求出至少需要添的个数。\n\n【详解】28÷6=4(个)……4(个)，6-4=2(个)。至少要添上2个，才能正好平均分给6个小朋友。故答案为:B",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算",
+                                 "有余数除法的实际应用"
+                             ],
+        "source":  "24-25 二年级下·山东临沂·期中"
+    },
+    {
+        "id":  "432",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "选择题",
+        "difficulty":  0.65,
+        "question":  "算式54÷□=6……6的除数是( )。",
+        "options":  [
+                        "A. 8",
+                        "B. 9",
+                        "C. 7"
+                    ],
+        "answer":  "A",
+        "solution":  "【分析】由题意可知，把各项代入算一算，得数是6余6的就是正确答案，据此解答。\n\n【详解】由分析可得：A. 54÷8=6……6，符合题意;B. 54÷9=6，不符合题意;C. 54÷7=7……5，不符合题意。故答案为:A",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "23-24 二年级下·山东菏泽·期末"
+    },
+    {
+        "id":  "433",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "56里面有( )个7，30里面最多有( )个4。",
+        "options":  [
+
+                    ],
+        "answer":  "8;7",
+        "solution":  "【分析】求一个数里面有多少个另一个数，用除法计算。用56除以7即可。用30除以4，商是几则最多有几个4。\n\n【详解】56÷7=8;30÷4=7……2。56里面有8个7，30里面最多有7个4。",
+        "knowledge_points":  [
+                                 "用7~9的乘法口诀求商",
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "23-24 二年级下·浙江台州·期末"
+    },
+    {
+        "id":  "434",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在算式□÷7=5……△中，△最大是( )，这时□是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "6;41",
+        "solution":  "【分析】有余数的除法算式为：被除数÷除数=商……余数，其中余数一定比除数小，余数最大是比除数小1的数，根据除数×商+余数=被除数，计算即可。\n\n【详解】7-1=6;7×5+6=35+6=41。在算式□÷7=5……△中，△最大是6，这时□是41。",
+        "knowledge_points":  [
+                                 "余数与除数的关系",
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "23-24 二年级下·江西赣州·期末"
+    },
+    {
+        "id":  "435",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "☆÷8=3……△，余数最大是( )，当余数最大时，被除数是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "7;31",
+        "solution":  "【分析】有余数的除法算式为：被除数÷除数=商……余数，其中余数一定比除数小，余数最大是比除数小1的数，根据除数×商+余数=被除数，计算即可。\n\n【详解】8-1=7;8×3+7=24+7=31。☆÷8=3……△，余数最大是7，当余数最大时，被除数是31。",
+        "knowledge_points":  [
+                                 "余数与除数的关系",
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "24-25 二年级下·浙江嘉兴·期末"
+    },
+    {
+        "id":  "436",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在□÷5=□……□的算式中，余数最大是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "4",
+        "solution":  "【分析】余数小于除数，所以余数最大是除数减1。\n\n【详解】5-1=4。在□÷5=□……□的算式中，余数最大是4。",
+        "knowledge_points":  [
+                                 "余数与除数的关系"
+                             ],
+        "source":  "24-25 二年级下·山东菏泽·期末"
+    },
+    {
+        "id":  "437",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "一个数除以8商7有余数，余数最大是( ),这时被除数是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "7;63",
+        "solution":  "【分析】在有余数的除法中，余数必须小于除数。除数是8，余数最大是7。根据被除数=商×除数+余数，可求出被除数。\n\n【详解】余数最大为：8-1=7;被除数为：7×8+7=56+7=63。即，一个数除以8商7有余数，余数最大是7，这时被除数是63。",
+        "knowledge_points":  [
+                                 "有余数的除法验算",
+                                 "余数与除数的关系"
+                             ],
+        "source":  "24-25 二年级下·山东滨州·期末"
+    },
+    {
+        "id":  "438",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "有45个梨，最少拿走( )个，就使得6个小朋友分得一样多。",
+        "options":  [
+
+                    ],
+        "answer":  "3",
+        "solution":  "【分析】根据题意，用梨的总数量÷平均分的人数=每人分得的数量。剩余梨的数量，要想平均分给6个小朋友，至少要拿走的数量就是剩余的数量，由此解答。\n\n【详解】45÷6=7(个)……3(个)。有45个梨，最少拿走3个，就使得6个小朋友分得一样多。",
+        "knowledge_points":  [
+                                 "有余数除法的实际应用",
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "24-25 二年级下·浙江嘉兴·期末"
+    },
+    {
+        "id":  "439",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "用一堆小棒摆独立的六边形，如果有剩余，最多剩( )根，如果摆5个这样的正多边形后，还有剩余，那么这堆小棒最少有( )根。",
+        "options":  [
+
+                    ],
+        "answer":  "5;31",
+        "solution":  "【分析】有余数的除法算式为：被除数÷除数=商……余数，其中余数一定比除数小，且不为0。余数最大是比除数小1的数，最小是1。摆一个六边形需要6根小棒，则小棒的总数量÷摆一个六边形需要小棒的数量=可以摆六边形的个数。\n\n【详解】摆一个六边形需要6根小棒，所以如果有剩余，最多剩6-1=5(根)。如果摆5个这样的正多边形后，还有剩余，那么这堆小棒最少有6×5+1=31(根)。",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算",
+                                 "余数与除数的关系"
+                             ],
+        "source":  "23-24二年级下·河南信阳·期末"
+    },
+    {
+        "id":  "440",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "在算式□÷5=8……△中，△最大填( )，此时□等于( )。",
+        "options":  [
+
+                    ],
+        "answer":  "4;44",
+        "solution":  "【分析】有余数的除法算式为：被除数÷除数=商……余数，其中余数一定小于除数，余数最大是比除数小1的数，根据除数×商+余数=被除数，计算即可。\n\n【详解】5-1=4;5×8+4=40+4=44。在算式□÷5=8……△中，△最大填4，此时□等于44。",
+        "knowledge_points":  [
+                                 "余数与除数的关系",
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "23-24 二年级下·重庆大渡口·期末"
+    },
+    {
+        "id":  "441",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.94,
+        "question":  "计算有余数的除法时,( )必须比( )小。",
+        "options":  [
+
+                    ],
+        "answer":  "余数;除数",
+        "solution":  "【分析】有余数的除法的计算方法：一商，二乘，三减，四比。(1)商：即试商，想除数和几相乘最接近被除数且小于被除数，那么商就是几，写在被除数的个位的上面;(2)乘：把除数和商相乘，将得数写在被除数下面;(3)减：用被除数减去商与除数的乘积，所得的差写在横线的下面;(4)比：将余数与除数比一比，余数必须比除数小。\n\n【详解】计算有余数的除法时，余数必须比除数小。",
+        "knowledge_points":  [
+                                 "余数与除数的关系"
+                             ],
+        "source":  "23-24 二年级下·广东惠州·期末"
+    },
+    {
+        "id":  "442",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "下面算式中的△应换成什么数字，才能使方框中的余数最大。5△÷6=9……□，△=( )，□=( )。",
+        "options":  [
+
+                    ],
+        "answer":  "9;5",
+        "solution":  "【分析】有余数的除法算式为：被除数÷除数=商……余数，其中余数一定小于除数，余数最大是比除数小1的数，根据除数×商+余数=被除数，计算即可。\n\n【详解】6-1=5;6×9+5=54+5=59。则算式应为：59÷6=9……5，△=9，□=5。",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算",
+                                 "余数与除数的关系"
+                             ],
+        "source":  "23-24二年级下·河南信阳·期末"
+    },
+    {
+        "id":  "443",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "如果△÷5=4……( )，余数最大是( )，这时△=( )。",
+        "options":  [
+
+                    ],
+        "answer":  "4;24",
+        "solution":  "【分析】有余数的除法算式为：被除数÷除数=商……余数，其中余数一定小于除数，余数最大是比除数小1的数，根据除数×商+余数=被除数，计算即可。\n\n【详解】5×4+4=20+4=24。如果△÷5=4……( )，余数最大是4，这时△=24。",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算",
+                                 "余数与除数的关系"
+                             ],
+        "source":  "23-24 二年级下·重庆酉阳·期末"
+    },
+    {
+        "id":  "444",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "△÷□=6……3，□最小是( )，此时△是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "4;27",
+        "solution":  "【分析】余数小于除数，除数最小是余数加1，然后根据被除数=商×除数+余数计算出被除数。\n\n【详解】3+1=4;6×4+3=24+3=27。△÷□=6……3，□最小是4，此时△是27。",
+        "knowledge_points":  [
+                                 "有余数的除法验算",
+                                 "余数与除数的关系"
+                             ],
+        "source":  "24-25 二年级下·湖南岳阳·期中"
+    },
+    {
+        "id":  "445",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "在算式□÷7=5……○中，被除数最大是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "41",
+        "solution":  "【分析】商和除数已知，余数最大时被除数最大，余数最大是除数减1，然后根据被除数=商×除数+余数计算。\n\n【详解】7-1=6;5×7+6=35+6=41。在算式□÷7=5……○中，被除数最大是41。",
+        "knowledge_points":  [
+                                 "有余数的除法验算",
+                                 "余数与除数的关系"
+                             ],
+        "source":  "23-24 二年级下·浙江嘉兴·期末"
+    },
+    {
+        "id":  "446",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在算式□÷☆=5……5中，☆最小是( )，这时□是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "6;35",
+        "solution":  "【分析】有余数除法中，余数一定比除数小，该题中余数是5，则除数一定大于5，那么除数最小是5+1=6，然后根据被除数=商×除数+余数即可求得。\n\n【详解】由分析可得：5+1=6;5×6+5=30+5=35。则在算式□÷☆=5……5中，☆最小是6，这时□是35。",
+        "knowledge_points":  [
+                                 "表内乘加",
+                                 "乘减",
+                                 "有余数的除法验算",
+                                 "余数与除数的关系"
+                             ],
+        "source":  "23-24二年级下·福建福州·期末"
+    },
+    {
+        "id":  "447",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "袋里的糖果在20~30块之间，平均分给3人，剩2块，平均分给5人，剩下1块，袋里有( )块糖。",
+        "options":  [
+
+                    ],
+        "answer":  "26",
+        "solution":  "【分析】由题意可知：糖果在20~30块之间，说明这袋糖果有20多块;平均分给3人，剩2块，根据商×除数+余数=被除数，商只有是7、8、9时，糖果的总数才是20多块;用这三个商分别算出这袋糖果可能的总数;再用这三个可能的总数分别除以5，谁的余数是1，谁就是正确答案，据此解答。\n\n【详解】由分析可得：根据商×除数+余数=被除数，商分别是7、8、9时，除数是3，余数是2，可得：7×3+2=23(块);8×3+2=26(块);9×3+2=29(块)。这袋糖果可能是23块、26块或29块。用23、26、29分别除以5可得：23÷5=4(块)……3(块);26÷5=5(块)……1(块);29÷5=5(块)……4(块)。只有26块时，平均分给5人，才能剩下1块，所以袋里有26块糖。",
+        "knowledge_points":  [
+                                 "表内乘加",
+                                 "乘减",
+                                 "有余数除法的实际应用",
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "23-24二年级下·河北邯郸·期末"
+    },
+    {
+        "id":  "448",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "★÷7=2……○，○最大是( )，这时★是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "6;20",
+        "solution":  "【分析】根据余数和除数的关系可知：余数小于除数。小于7的最大的数是6，所以○最大是6，再根据被除数=商×除数+余数，将数据代入，即可得出答案。\n\n【详解】据分析可知：○最大是6;2×7+6=14+6=20。所以这时★是20。",
+        "knowledge_points":  [
+                                 "表内乘加",
+                                 "乘减",
+                                 "余数与除数的关系"
+                             ],
+        "source":  "23-24二年级下·广东广州·期末"
+    },
+    {
+        "id":  "449",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "六一节用气球装饰教室，按照红红黄绿红红黄绿红红黄绿。这样的规律排列，第18个气球是( )色，第27个气球是( )色。",
+        "options":  [
+
+                    ],
+        "answer":  "红;黄",
+        "solution":  "【分析】气球的排列规律是\"红、红、黄、绿\"，每4个一组重复循环。用18和27分别除以每组气球个数，算出按这样的规律排列了几组，再看余数，余数是几，就是这一组中的第几个气球。\n\n【详解】第18个气球：18÷4=4(组)……2(个)，余数为2，对应一组中的第2个气球，即红色。第27个气球：27÷4=6(组)……3(个)，余数为3，对应一组中的第3个气球，即黄色。因此，第18个气球是红色，第27个气球是黄色。",
+        "knowledge_points":  [
+                                 "周期问题",
+                                 "两位数除以一位数的有余数除法",
+                                 "有余数除法的实际应用"
+                             ],
+        "source":  "23-24二年级下·浙江·期末"
+    },
+    {
+        "id":  "450",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "42个小朋友坐船，每条船最多坐5人，至少要( )条船才能全部坐下。",
+        "options":  [
+
+                    ],
+        "answer":  "9",
+        "solution":  "【分析】根据题意，总人数除以每条船最多坐的人数，若能除尽，则商是需要船的数量;若除不尽，剩余的人数也需要1条船，则商+1是需要船的数量。\n\n【详解】42÷5=8(条)……2(人)，8+1=9(条)。42个小朋友坐船，每条船最多坐5人，至少要9条船才能全部坐下。",
+        "knowledge_points":  [
+                                 "有余数除法的实际应用"
+                             ],
+        "source":  "23-24二年级下·浙江·期末"
+    },
+    {
+        "id":  "451",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "△÷6=4……□，□里最大是( )；△÷□=8……6，△最小是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "5;62",
+        "solution":  "【分析】根据余数要比除数小可知，□表示的数要比6小，据此求出小于6的最大的数是多少，即得出答案。要求△最小是多少，则除数最小时，被除数最小。因为余数是6，所以大于6的最小的数是7，再根据被除数=商×除数+余数，据此解答即可。\n\n【详解】小于6的最大的数是5，所以□里最大是5。大于6的最小的数是7，8×7+6=56+6=62。所以△最小是62。",
+        "knowledge_points":  [
+                                 "余数与除数的关系",
+                                 "表内乘加",
+                                 "乘减"
+                             ],
+        "source":  "22-23 二年级下·新疆乌鲁木齐·期末"
+    },
+    {
+        "id":  "452",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "在有余数的除法里，余数( )除数。(填上\"\u003e\"\"\u003c\"或\"=\")",
+        "options":  [
+
+                    ],
+        "answer":  "\u003c",
+        "solution":  "【分析】根据有余数除法的认识，余数要比除数小，据此解答即可。\n\n【详解】据分析可知：在有余数的除法里，余数\u003c除数。",
+        "knowledge_points":  [
+                                 "余数与除数的关系"
+                             ],
+        "source":  "22-23 二年级下·新疆乌鲁木齐·期中"
+    },
+    {
+        "id":  "453",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "63里面有( )个9;53里面最多有( )个6。",
+        "options":  [
+
+                    ],
+        "answer":  "7;8",
+        "solution":  "【分析】要求63里面有几个9，根据除法的意义，用63÷9即可得出答案。要求53里面最多有几个6，根据除法的意义，用53÷6进行解答即可。\n\n【详解】63÷9=7，所以63里面有7个9。53÷6=8……5，所以53里面最多有8个6。",
+        "knowledge_points":  [
+                                 "用7~9的乘法口诀求商",
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "22-23 二年级下·新疆乌鲁木齐·期中"
+    },
+    {
+        "id":  "454",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "有21位游客去西湖划船，每条船限乘5人，至少需要租( )条船。",
+        "options":  [
+
+                    ],
+        "answer":  "5",
+        "solution":  "【分析】根据题意，用总人数除以每条船的人数，就是需要几条船。若有余下的人数，则需多租1条船。\n\n【详解】21÷5=4(条)……1(人)，4+1=5(条)。所以，至少需要租5条船。",
+        "knowledge_points":  [
+                                 "有余数除法的实际应用",
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "24-25 三年级下·福建福州·期中"
+    },
+    {
+        "id":  "455",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "56÷7=( ),58÷8=( ),这两道算式都是用口诀( )来计算的。",
+        "options":  [
+
+                    ],
+        "answer":  "8;7……2;七八五十六",
+        "solution":  "【分析】由题意可知：做除法算式，根据表内乘法口诀，想商和除数相乘等于被除数;做有余数除法时，想商和除数相乘的积最接近被除数而且小于被除数，据此解答。\n\n【详解】由分析可得：56÷7=8，7和8相乘等于56，用到的口诀是七八五十六;58÷8=7……2，7和8相乘得到的积最接近58而且小于58，用到的乘法口诀也是七八五十六。所以56÷7=8，58÷8=7……2，这两道算式都是用口诀七八五十六来计算的。",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算",
+                                 "用7~9的乘法口诀求商"
+                             ],
+        "source":  "22-23 二年级下·新疆乌鲁木齐·期中"
+    },
+    {
+        "id":  "456",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "按照图中的规律穿一串珠子，第31个珠子是白色的。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】根据图示可知，每5个珠子一循环，按2黑、3白的顺序排列，用31除以5计算出31个珠子是有几组零几个珠子，即可判断其颜色。\n\n【详解】31÷5=6(组)……1(个)，所以第31个珠子是第7组的第1个，是黑色。原题说法错误。故答案为:×",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "24-25二年级下·山东济宁·期末"
+    },
+    {
+        "id":  "457",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "○▲▲□○▲▲□○▲▲□○……按照这样的顺序排列，第35个图形是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "▲",
+        "solution":  "【分析】通过观察这组图形，可以发现是以\"○▲▲□\"这四个图形为一组的规律重复出现，用图形的位置数除以4，看余数是几，就是一组中的第几个图形，没有余数就是一组中的最后一个。据此即可解答。\n\n【详解】35÷4=8(组)……3(个)，说明第35个图形应该是第9组中的第3个，即是▲。",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算",
+                                 "间隔问题"
+                             ],
+        "source":  "23-24 二年级下·福建龙岩·期末"
+    },
+    {
+        "id":  "458",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "23÷6=3(条)……5(条)，这个算式表示有( )条小鱼，平均分给( )只小猫，每只小猫分到( )条，还剩( )条。",
+        "options":  [
+
+                    ],
+        "answer":  "23;6;3;5",
+        "solution":  "【分析】根据有余数的除法的意义，23÷6=3……5表示把23平均分成6份，每份可以分到3，还剩下5条无法平均分配，据此即可解答。\n\n【详解】根据分析可知，23÷6=3(条)……5(条)，这个算式表示有23条小鱼，平均分给6只小猫，每只小猫分到3条，还剩5条。",
+        "knowledge_points":  [
+                                 "有余数除法的实际应用",
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "23-24二年级下·天津河西·期末"
+    },
+    {
+        "id":  "459",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "括号里最大能填几。\n8×( )\u003c36\n54\u003e( )×8\n6×( )\u003c40",
+        "options":  [
+
+                    ],
+        "answer":  "4;6;6",
+        "solution":  "【分析】用比较的数除以已知的因数，如果有余数，所得的商就是要填的最大的数;如果没有余数，那么用所得的商减1，所得的差就是要填的最大的数。\n\n【详解】36÷8=4……4，有余数，故8×4\u003c36;54÷8=6……6，有余数，故54\u003e6×8;40÷6=6……4，有余数，故6×6\u003c40。",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "24-25二年级下·新疆喀什·期中"
+    },
+    {
+        "id":  "460",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "一串珠子，按3红2黄1白的顺序穿起来，第21颗珠子是( )色，第30颗珠子是( )色。",
+        "options":  [
+
+                    ],
+        "answer":  "红;白",
+        "solution":  "【分析】由题可知，每组有6颗珠子，求第21颗和第30颗珠子的颜色，分别用21和30除以每组珠子的数量，若能除尽，则是这组的最后一颗珠子的颜色;若除不尽，则余数是几就是下一组第几颗的颜色。\n\n【详解】3+2+1=6(颗);21÷6=3(组)……3(颗)，第21颗珠子是第4组的第3颗，是红色;30÷6=5(组)，第30颗珠子是第5组的最后一颗，是白色。",
+        "knowledge_points":  [
+                                 "间隔问题",
+                                 "有余数除法的实际应用"
+                             ],
+        "source":  "24-25 二年级下·广东揭阳·期中"
+    },
+    {
+        "id":  "461",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "被除数是46，除数是9，商是( ),余数是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "5;1",
+        "solution":  "【分析】被除数÷除数=商……余数。有余数的除法的计算方法：一商，二乘，三减，四比。(1)商：即试商，想除数和几相乘最接近被除数且小于被除数，那么商就是几，写在被除数的个位的上面;(2)乘：把除数和商相乘，将得数写在被除数下面;(3)减：用被除数减去商与除数的乘积，所得的差写在横线的下面;(4)比：将余数与除数比一比，余数必须比除数小。\n\n【详解】46÷9=5……1。被除数是46，除数是9，商是5，余数是1。",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "23-24 二年级下·重庆永川·期末"
+    },
+    {
+        "id":  "462",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "一本故事书8元,50元最多可以买( )本。",
+        "options":  [
+
+                    ],
+        "answer":  "6",
+        "solution":  "【分析】根据题意，已知一本故事书8元，用50除以8，求出商。如果有余数，由于书的数量必须是整数，且余下的钱不够再买一本，商就是最多可以买的本数，以此答题即可。\n\n【详解】根据分析可知：50÷8=6(本)……2(元)。一本故事书8元，50元最多可以买6本。",
+        "knowledge_points":  [
+                                 "有余数除法的实际应用",
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "23-24 三年级下·广东茂名·期末"
+    },
+    {
+        "id":  "463",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "○÷□=△……4，□最小是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "5",
+        "solution":  "【分析】根据余数和除数的关系：余数要比除数小，最小的除数要比余数大1，据此解答。\n\n【详解】由分析可得：余数4比除数小，除数最小也要比4大1，即4+1=5;○÷□=△……4，□最小是5。",
+        "knowledge_points":  [
+                                 "余数与除数的关系"
+                             ],
+        "source":  "23-24 二年级下·河南许昌·期末"
+    },
+    {
+        "id":  "464",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "有42块巧克力，至少拿出( )块，才能平均分给5个小朋友，每个小朋友可分得( )块。",
+        "options":  [
+
+                    ],
+        "answer":  "2;8",
+        "solution":  "【分析】根据题意，用巧克力的总数量除以平均分的人数，商是每人分得的数量，余数是剩下的数量，余数就是至少要拿出的数量，剩下的就能平均分且没有剩余。\n\n【详解】42÷5=8(块)……2(块)。有42块巧克力，至少拿出2块，才能平均分给5个小朋友，每个小朋友可分得8块。",
+        "knowledge_points":  [
+                                 "有余数除法的实际应用",
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "24-25二年级下·河南周口·期末"
+    },
+    {
+        "id":  "465",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "数学好玩数学好玩数学好玩……第20个字是( )，第34个字是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "玩;学",
+        "solution":  "【分析】根据题意，这组字按照\"数学好玩\"为一组重复排列，则分别用20和34除以每组字的数量，若能除尽，则是这组的最后一个字;若除不尽，则余数是几就是下一组的第几个字。\n\n【详解】20÷4=5(组)，第20个字是第5组的最后一个字，是玩;34÷4=8(组)……2(个)，第34个字是第9组的第2个字，是学。",
+        "knowledge_points":  [
+                                 "有余数除法的实际应用"
+                             ],
+        "source":  "23-24 二年级下·浙江台州·期末"
+    },
+    {
+        "id":  "466",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "△○□□△○□□△○□□。按照这样的规律接着画，第24个图形是( ),第34个图形是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "□;○",
+        "solution":  "【分析】这组图形按照△○□□为一组重复排列，则分别用24和34除以每组图形的数量，若能除尽，则是这组的最后一个图形;若除不尽，则余数是几就是下一组的第几个图形。\n\n【详解】24÷4=6(组)，第24个图形是第6组的最后一个，是□;34÷4=8(组)……2(个)，第34个图形是第9组的第2个，是○。",
+        "knowledge_points":  [
+                                 "有余数除法的实际应用"
+                             ],
+        "source":  "23-24 二年级下·浙江台州·期末"
+    },
+    {
+        "id":  "467",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "在算式□÷8=7……□中，余数最大是( )，这时被除数是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "7;63",
+        "solution":  "【分析】有余数的除法算式为：被除数÷除数=商……余数，其中余数一定比除数小，余数最大是比除数小1的数，根据除数×商+余数=被除数，计算即可。\n\n【详解】8-1=7;8×7+7=56+7=63。在算式□÷8=7……□中，余数最大是7，这时被除数是63。",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算",
+                                 "余数与除数的关系"
+                             ],
+        "source":  "23-24 二年级下·浙江台州·期末"
+    },
+    {
+        "id":  "468",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "一根长28米的绳子，每6米做一根跳绳，最多能做( )根这样的跳绳。",
+        "options":  [
+
+                    ],
+        "answer":  "4",
+        "solution":  "【分析】根据题意，用绳子的全长除以每根跳绳需要的米数，商即为最多能做的跳绳根数，余数不够再做一根，因此直接忽略不计。\n\n【详解】28÷6=4(根)……4(米)。最多能做4根这样的跳绳。",
+        "knowledge_points":  [
+                                 "有余数除法的实际应用",
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "23-24二年级下·浙江嘉兴·期末"
+    },
+    {
+        "id":  "469",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "在●●●○○●●●○○……中，第27个图形是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "●",
+        "solution":  "【分析】这组图形按照●●●○○为一组重复排列，每组有5个图形。求第27个图形，用27除以每组图形的数量，若能除尽，则是这组的最后一个图形;若除不尽，则余数是几就是下一组的第几个图形。\n\n【详解】27÷5=5(组)……2(个)，第27个图形是第6组的第2个，是●。",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "23-24二年级下·甘肃天水·期末"
+    },
+    {
+        "id":  "470",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "有26支笔、36本练习本、39本故事书，每个爱心书包装4支笔、7本练习本和5本故事书，这些学习用品最多可以装( )个这样的爱心书包。",
+        "options":  [
+
+                    ],
+        "answer":  "5",
+        "solution":  "【分析】分别用各个物品的总数除以每个爱心书包用到的数量，商就是各种物品可以装爱心书包的数量，找出商最小的那个即可。\n\n【详解】26÷4=6(个)……2(支);36÷7=5(个)……1(本);39÷5=7(个)……4(本);5\u003c6\u003c7。这些学习用品最多可以装5个这样的爱心书包。",
+        "knowledge_points":  [
+                                 "有余数除法的实际应用",
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "23-24二年级下·浙江嘉兴·期末"
+    },
+    {
+        "id":  "471",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "有15个足球，每筐最多装6个，至少要( )个筐才能装完。",
+        "options":  [
+
+                    ],
+        "answer":  "3",
+        "solution":  "【分析】用足球总数除以每筐最多装的个数，商就是需要的筐数，如果有余数，则还需要加1个筐。\n\n【详解】15÷6=2(个)……3(个)，2+1=3(个)。有15个足球，每筐最多装6个，至少要3个筐才能装完。",
+        "knowledge_points":  [
+                                 "有余数除法的实际应用"
+                             ],
+        "source":  "23-24 二年级下·浙江嘉兴·期末"
+    },
+    {
+        "id":  "472",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.85,
+        "question":  "□□□☆☆□□□☆☆。按左边的顺序排下去，第27个图形是( ),第34个图形是( )。",
+        "options":  [
+
+                    ],
+        "answer":  "□;☆",
+        "solution":  "【分析】图形按□□□☆☆顺序循环排列，一组5个，分别用27和34除以每组的个数，商是有这样的几组，余数是剩下几个图形，余数是几就是下一组中的第几个，没有余数就是这一组中最后一个。\n\n【详解】27÷5=5(组)……2(个)，余数2，即是第6组中的第2个位置，该位置是□，因此第27个图形是□。34÷5=6(组)……4(个)，余数4，即是第7组中的第4个位置，该位置是☆，因此第34个图形是☆。",
+        "knowledge_points":  [
+                                 "有余数除法的实际应用",
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "23-24 二年级下·江西萍乡·期末"
+    },
+    {
+        "id":  "473",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "节日期间广场上有一排彩旗，按照1面红旗、2面黄旗、3面绿旗的顺序排列。第31面彩旗是( )色，第45面彩旗是( )色。",
+        "options":  [
+
+                    ],
+        "answer":  "红;黄",
+        "solution":  "【分析】根据题意，彩旗是以\"红黄黄绿绿绿\"这6面彩旗为一组的规律重复出现，用彩旗的位置数除以6，看余数是几，就是一组中的第几个彩旗，没有余数就是一组中的最后一个。据此即可解答。\n\n【详解】31÷6=5(组)……1(个)，说明第31面彩旗是第6组中的第1面，即红旗。45÷6=7(组)……3(个)，说明第45面彩旗是第8组中的第3面，即黄旗。",
+        "knowledge_points":  [
+                                 "间隔问题",
+                                 "100以内有余数的除法计算",
+                                 "有余数除法的实际应用"
+                             ],
+        "source":  "23-24 二年级下·湖北省直辖县级单位·期末"
+    },
+    {
+        "id":  "474",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "填空题",
+        "difficulty":  0.65,
+        "question":  "在算式□÷7=5……□中，当余数最小时，被除数是( )；当余数最大时，被除数是( )，你发现了：除数( )余数。",
+        "options":  [
+
+                    ],
+        "answer":  "36;41;大于",
+        "solution":  "【分析】根据题意，在有余数的除法中，余数都比除数小。□÷7=5……□这题中，除数是7，余数是比7小且比0大的整数，余数可能是1、2、3、4、5、6，这些余数中最小的是1，最大的是6。被除数=商×除数+余数，据此解答。\n\n【详解】余数最小是1，被除数是：5×7+1=35+1=36;余数最大是6，被除数是：5×7+6=35+6=41。在算式□÷7=5……□中，当余数最小时，被除数是36;当余数最大时，被除数是41。你发现了：除数大于余数。",
+        "knowledge_points":  [
+                                 "余数与除数的关系",
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "23-24 二年级下·湖北省直辖县级单位·期末"
+    },
+    {
+        "id":  "475",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "可乐每瓶3元，20元最多可以买5瓶。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】根据题意，每瓶可乐3元，求20元最多可以买几瓶，即求20里面最多有几个3。用20除以3，商即为最多能买的瓶数。\n\n【详解】20÷3=6(瓶)……2(元)，则可乐每瓶3元，20元最多可以买6瓶。原题说法错误。故答案为:×",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "24-25 二年级下·江西上饶·期末"
+    },
+    {
+        "id":  "476",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "判断题",
+        "difficulty":  0.94,
+        "question":  "34里面最多有5个7。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】判断34里面最多有几个7，需要用34除以7，取商的整数部分。根据计算结果，确定题目中的说法是否正确。\n\n【详解】34÷7=4……6，34里面最多有4个7，而不是5个7。题目中的说法错误。故答案为:×",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "24-25 二年级下·山东滨州·期末"
+    },
+    {
+        "id":  "477",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "判断题",
+        "difficulty":  0.65,
+        "question":  "笑笑要买一张12元的哪吒画报，她每天存5元，至少要存3天。( )",
+        "options":  [
+
+                    ],
+        "answer":  "√",
+        "solution":  "【分析】由题意可知：用一张哪吒画报的钱除以每天存的钱，算出的商是需要存的天数，余数是剩余的钱数，不管剩余多少钱，都还需要多存一天，故至少存商加1天，据此解答。\n\n【详解】12÷5=2(天)……2(元)，2+1=3(天)。至少存3天。故答案为:√",
+        "knowledge_points":  [
+                                 "有余数除法的实际应用",
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "24-25 二年级下·广东揭阳·期中"
+    },
+    {
+        "id":  "478",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "判断题",
+        "difficulty":  0.85,
+        "question":  "( )×8\u003c56，括号里最大能填7。( )",
+        "options":  [
+
+                    ],
+        "answer":  "×",
+        "solution":  "【分析】用比较的数除以已知的因数，如果有余数，所得的商就是要填的最大的数;如果没有余数，那么用所得的商减1，所得的差就是要填的最大的数。\n\n【详解】56÷8=7，没有余数，所以7-1=6。故( )×8\u003c56，括号里最大能填6。原题说法错误。故答案为:×",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算",
+                                 "100以内数的比大小"
+                             ],
+        "source":  "24-25二年级下·山东济宁·期中"
+    },
+    {
+        "id":  "479",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "计算题",
+        "difficulty":  0.65,
+        "question":  "用竖式计算。\n32÷5= 71÷9= 44÷7=",
+        "options":  [
+
+                    ],
+        "answer":  "6……2;7……8;6……2",
+        "solution":  "【分析】除法用竖式计算时，从最高位开始除起，若除不了，就用最高位和下一位合成一个数来除，直到能除以除数为止。若有余数，则余数一定比除数小。\n\n【详解】32÷5=6……2;71÷9=7……8;44÷7=6……2。",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "24-25 二年级下·湖北武汉·期末"
+    },
+    {
+        "id":  "480",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "一群小朋友排队，按\"1 2 3 4 1 2 3 4\"报数，笑笑站在第30个，她报的应该是几？",
+        "options":  [
+
+                    ],
+        "answer":  "2",
+        "solution":  "【分析】按\"1 2 3 4\"循环报数，即每4个数为一个循环，所以用30除以4，看余数对应循环中的几就是该学生所报的数。\n\n【详解】30÷4=7……2，所以第30个是第8个循环的第2个。答：笑笑报的应该是2。",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算",
+                                 "有余数除法的实际应用"
+                             ],
+        "source":  "24-25 二年级下·浙江嘉兴·期末"
+    },
+    {
+        "id":  "481",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "包粽子是端午节的传统习俗，以粽叶包裹糯米及其他馅料，通过不同手法制作成多种形状，具有丰富的文化内涵和地域特色。妈妈现在要包50个粽子，她每天最多包8个，至少需要多少天才能完成。",
+        "options":  [
+
+                    ],
+        "answer":  "7天",
+        "solution":  "【分析】根据题意，用需要包的粽子总数÷每天包的数量=包满8个的天数。没包完的数量，有剩余需要加一天，据此解答。\n\n【详解】根据分析：50÷8=6(天)……2(个)，6+1=7(天)。答：至少要7天。",
+        "knowledge_points":  [
+                                 "有余数除法的实际应用"
+                             ],
+        "source":  "24-25二年级下·广东广州·期末"
+    },
+    {
+        "id":  "482",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "快板是一种传统说唱艺术，又称\"数来宝\"。做一副快板需要\"两长五短\"7块竹板。非遗工艺品店新进了一批竹板，最多可以做多少副快板。\n![](images/a2de2d0b7e3c2a87f6ba5f9616b71cbd3eaf8b96602910fe56e0731cd608947c.jpg)\n![](images/ded8becda57f1e0d6a85411729c495bf8da2d5f81068e12f48cad9bb6849fe0b.jpg)",
+        "options":  [
+
+                    ],
+        "answer":  "7副",
+        "solution":  "【分析】已知做一副快板需要2块长板，用长板的块数除以一副快板需要的长板块数，求出长板最多能做多少副快板;已知做一副快板需要5块短板，用短板的块数除以一副快板需要的短板块数，求出短板能做多少副快板。做快板时，长板和短板都得有，最多能制作的快板数量，取决于长板和短板分别可以制作数量中的最小值。\n\n【详解】15÷2=7(副)……1(块);42÷5=8(副)……2(块);7\u003c8。答：最多可以做7副快板。",
+        "knowledge_points":  [
+                                 "有余数除法的实际应用",
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "24-25 二年级下·湖北武汉·期末"
+    },
+    {
+        "id":  "483",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "这些草莓够吃几天。\n![](images/277b775facc5a9317c81976d2a545e659c123c5cf60823c375537bf4e7ae1cd8.jpg)",
+        "options":  [
+
+                    ],
+        "answer":  "7天",
+        "solution":  "【分析】根据题意，用草莓的总数量除以小刺猬每天吃的数量，商就是可以吃的天数。\n\n【详解】30÷4=7(天)……2(个)。答：这些草莓够吃7天。",
+        "knowledge_points":  [
+                                 "有余数除法的实际应用",
+                                 "100以内有余数的除法计算",
+                                 "图文问题"
+                             ],
+        "source":  "24-25 二年级下·河北石家庄·期中"
+    },
+    {
+        "id":  "484",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "26名同学去划船，每条船限乘4人，至少需要几条船。",
+        "options":  [
+
+                    ],
+        "answer":  "7条",
+        "solution":  "【分析】根据题意，用总人数除以每条船的限乘人数，若有余数，则需增加1条船，确保所有同学都能乘船。据此解答。\n\n【详解】根据分析：26÷4=6(条)……2(人)，6+1=7(条)。答：至少需要7条船。",
+        "knowledge_points":  [
+                                 "有余数除法的实际应用"
+                             ],
+        "source":  "24-25 二年级下·河南新乡·期末"
+    },
+    {
+        "id":  "485",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "购物。\n![](images/0e2b8eac005db3cd4ce722e786188d0689d8e01fd62bebfb6e4287e1f0f0bfff.jpg)\n![](images/d26ed3f72967cee7855c0161e9b18d03d1b686105ea86d87f9303de82f4905da.jpg)\n(1)20元能买几个柠檬？还剩多少元？\n(2)聪聪想买8个火龙果，他带了50元，够吗？",
+        "options":  [
+
+                    ],
+        "answer":  "6个;2元;够",
+        "solution":  "【分析】(1)根据题意，总钱数÷每个柠檬的钱数=可以买柠檬的数量，余数是剩余的钱数;(2)先用每个火龙果的钱数和要买的数量相乘，求出一共需要多少钱，再和聪聪带的钱数比较大小，需要的钱数大于带的钱数就不够，小于或等于带的钱数就够。\n\n【详解】(1)20÷3=6(个)……2(元)。答：20元能买6个柠檬，还剩2元。(2)6×8=48(元)，48\u003c50。答：他带了50元，够。",
+        "knowledge_points":  [
+                                 "100以内数的比大小",
+                                 "8的乘法口诀及应用",
+                                 "100以内有余数的除法计算",
+                                 "有余数除法的实际应用"
+                             ],
+        "source":  "24-25 二年级下·河北邢台·期中"
+    },
+    {
+        "id":  "486",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "有40人参加合唱比赛，如果每6人站一排，至少站几排才能全部站完。",
+        "options":  [
+
+                    ],
+        "answer":  "7排",
+        "solution":  "【分析】根据题意可知，合唱比赛的总人数除以每排站的人数，求出结果，商是可以站的排数，余数是还剩下的人数，剩下的人还需要站一排，站的排数加上1，等于至少站几排才能全部站完，据此解答。\n\n【详解】根据分析可得：40÷6=6(排)……4(人)，6+1=7(排)。答：至少站7排才能全部站完。",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算",
+                                 "有余数除法的实际应用"
+                             ],
+        "source":  "23-24二年级下·广西贵港·期末"
+    },
+    {
+        "id":  "487",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "有28只小动物去郊游划船，每条船坐6只，需要几条船。",
+        "options":  [
+
+                    ],
+        "answer":  "5条",
+        "solution":  "【分析】根据题意，用小动物的总数量除以每条船坐的数量，若能除尽，则商是需要船的数量;若除不尽，剩余的小动物也需要1条船，则商+1是需要船的数量。\n\n【详解】28÷6=4(条)……4(只)，4+1=5(条)。答：需要5条船。",
+        "knowledge_points":  [
+                                 "有余数除法的实际应用"
+                             ],
+        "source":  "23-24 二年级下·浙江·期末"
+    },
+    {
+        "id":  "488",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "宁宁有80元，打算买9元一瓶的牛奶，最多可以买几瓶。",
+        "options":  [
+
+                    ],
+        "answer":  "8瓶",
+        "solution":  "【分析】根据除法的意义，宁宁的钱数除以每瓶牛奶的钱数，商就是最多可以买牛奶的瓶数。\n\n【详解】80÷9=8(瓶)……8(元)。答：最多可以买8瓶。",
+        "knowledge_points":  [
+                                 "有余数除法的实际应用",
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "23-24二年级下·浙江舟山·期末"
+    },
+    {
+        "id":  "489",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "二(1)班有41名同学去公园划船。公园里有大小两种船供游客租用。如果都租小船，至少需要租几条船。\n![](images/9d626de47f9b9491bab8f890fd49d64c99d4bce7ae9aec8817d51b489200c786.jpg)",
+        "options":  [
+
+                    ],
+        "answer":  "7条",
+        "solution":  "【分析】用总人数除以每条小船可以坐的人数，商就是需要的条数，如果有余数，则再加1条小船。\n\n【详解】41÷6=6(条)……5(名)，6+1=7(条)。答：至少需要租7条船。",
+        "knowledge_points":  [
+                                 "有余数除法的实际应用",
+                                 "100以内有余数的除法计算",
+                                 "图文问题"
+                             ],
+        "source":  "23-24 二年级下·浙江台州·期末"
+    },
+    {
+        "id":  "490",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "第一小组用易拉罐做成垃圾分类收纳盒(如图)，一共收集了34个易拉罐，最多可以做多少个这样的收纳盒？\n![](images/9cba0cb3fb7e59488b250c5bb55870bce3fd4f06224ffa6e4f30476ef3fcaf44.jpg)",
+        "options":  [
+
+                    ],
+        "answer":  "8个",
+        "solution":  "【分析】由题意可知：用收集的易拉罐数除以做收纳盒需要的易拉罐数，得出的商是能做的收纳盒数，余数是剩余的易拉罐数，剩余的易拉罐不够再做一个收纳盒，故商就是最多能做的收纳盒数，据此解答。\n\n【详解】由分析可得：34÷4=8(个)……2(个)。答：最多能做8个这样的收纳盒。",
+        "knowledge_points":  [
+                                 "有余数除法的实际应用",
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "24-25 二年级下·山西晋中·期末"
+    },
+    {
+        "id":  "491",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "20米布料能做几件大衣。还剩几米布。\n![](images/859cb865e0e6586263533e9cb85d258cd611c532c41c42116b51f8faf036016b.jpg)",
+        "options":  [
+
+                    ],
+        "answer":  "6件;2米",
+        "solution":  "【分析】根据有余数的除法可知，布料总长度÷一件大衣需要的布料长度=可做大衣的件数，余数是剩余布料长度。列出算式算出答案即可解答。\n\n【详解】20÷3=6(件)……2(米)。答：一共可以做6件大衣，还剩2米布料。",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算",
+                                 "有余数除法的实际应用"
+                             ],
+        "source":  "23-24 二年级下·重庆大渡口·期末"
+    },
+    {
+        "id":  "492",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "二年一班35名同学去植物园参观，每辆电瓶车限乘8人，至少需要几辆电瓶车才能让所有同学去参观。",
+        "options":  [
+
+                    ],
+        "answer":  "5辆",
+        "solution":  "【分析】用总人数除以每辆电瓶车限乘的人数，商就是至少需要的电瓶车辆数，如果有余数，商再加1，即可解答。\n\n【详解】35÷8=4(辆)……3(名)，4+1=5(辆)。答：至少需要5辆电瓶车才能让所有同学去参观。",
+        "knowledge_points":  [
+                                 "有余数除法的实际应用",
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "23-24 二年级下·天津和平·期末"
+    },
+    {
+        "id":  "493",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "学校买来52盆菊花，平均分给二年级的7个班。每班可分到几盆。还剩几盆。",
+        "options":  [
+
+                    ],
+        "answer":  "7盆;3盆",
+        "solution":  "【分析】根据题意，用买来菊花的总盆数÷二年级的班级数=每个班可以分到的盆数，余数是还剩的盆数，据此解答。\n\n【详解】52÷7=7(盆)……3(盆)。答：每班可分到7盆，还剩3盆。",
+        "knowledge_points":  [
+                                 "有余数除法的实际应用"
+                             ],
+        "source":  "24-25二年级下·河南漯河·期末"
+    },
+    {
+        "id":  "494",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "解答题",
+        "difficulty":  0.85,
+        "question":  "有47个气球，每6个扎成一束，能扎成几束。还剩几个气球。",
+        "options":  [
+
+                    ],
+        "answer":  "7束;5个",
+        "solution":  "【分析】根据题意可知，气球的总个数除以每束扎的个数，求出结果，商是能扎的束数，余数是还剩下气球的个数，据此解答。\n\n【详解】根据分析可得：47÷6=7(束)……5(个)。答：能扎成7束，还剩5个气球。",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算",
+                                 "有余数除法的实际应用"
+                             ],
+        "source":  "24-25二年级下·湖南邵阳·期中"
+    },
+    {
+        "id":  "495",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "有27名同学坐车去参加跳绳比赛，每辆车坐5人，至少要租几辆车。",
+        "options":  [
+
+                    ],
+        "answer":  "6辆",
+        "solution":  "【分析】由题意可知：同学总数除以每辆车可坐人数，算出商和余数，商再加1即可，据此计算。\n\n【详解】由分析可得：27÷5=5(辆)……2(人)，5+1=6(辆)。答：至少要租6辆车。",
+        "knowledge_points":  [
+                                 "有余数除法的实际应用"
+                             ],
+        "source":  "23-24 二年级下·湖南长沙·期末"
+    },
+    {
+        "id":  "496",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "同学们玩丛林探险游戏，每辆小车可以坐6人，44人需要租几辆车？",
+        "options":  [
+
+                    ],
+        "answer":  "8辆",
+        "solution":  "【分析】总人数为44人，每辆小车坐6人，需要计算44除以6的结果，商就是需要的车辆数。若有剩余人数，则需再租1辆车。\n\n【详解】44÷6=7(辆)……2(人)，7+1=8(辆)。答：44人需要租8辆车。",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算",
+                                 "有余数除法的实际应用"
+                             ],
+        "source":  "23-24 二年级下·浙江台州·期末"
+    },
+    {
+        "id":  "497",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "春光小学二年级的38名学生去参观科技馆，至少要租几辆车才能保证每名都去参观。\n![](images/ad36e0d3139f0dbe30c943db0d8840a3.png)",
+        "options":  [
+
+                    ],
+        "answer":  "10辆",
+        "solution":  "【分析】用总人数除以每辆车的限乘人数，商就是需要的车辆数，如果有余数，则再加1辆车。\n\n【详解】38÷4=9(辆)……2(名)，9+1=10(辆)。答：至少要租10辆车才能保证每名都去参观。",
+        "knowledge_points":  [
+                                 "有余数除法的实际应用",
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "23-24 二年级下·浙江嘉兴·期末"
+    },
+    {
+        "id":  "498",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "\"六一\"儿童节，小胖挂气球，他按红、黄、绿、蓝的顺序排列，第35个气球是什么颜色的？",
+        "options":  [
+
+                    ],
+        "answer":  "绿色",
+        "solution":  "【分析】根据题意可知，每组有4个气球，用35除以每组气球的数量，若能除尽，则是这组的最后一个气球的颜色;若除不尽，则余数是几就是下一组的第几个气球的颜色，由此解答。\n\n【详解】35÷4=8(组)……3(个)，第35个气球是第9组的第3个。答：第35个气球是绿色的。",
+        "knowledge_points":  [
+                                 "100以内有余数的除法计算",
+                                 "有余数除法的实际应用"
+                             ],
+        "source":  "23-24 二年级下·甘肃天水·期末"
+    },
+    {
+        "id":  "499",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "30个学生去划船，每条船最多坐4人。他们至少要租多少条船。",
+        "options":  [
+
+                    ],
+        "answer":  "8条",
+        "solution":  "【分析】根据题意，总人数除以每条船坐的人数，若能除尽，则商是需要租船的数量;若除不尽，剩余的人数也需要1条船，则商+1是需要租船的数量。\n\n【详解】30÷4=7(条)……2(人)，7+1=8(条)。答：他们至少要租8条船。",
+        "knowledge_points":  [
+                                 "有余数除法的实际应用"
+                             ],
+        "source":  "23-24 二年级下·甘肃天水·期末"
+    },
+    {
+        "id":  "500",
+        "unit":  "第六单元 有余数的除法",
+        "question_type":  "解答题",
+        "difficulty":  0.65,
+        "question":  "某小学有48名同学参加户外露营活动。如果他们都住小帐篷，至少需要多少顶小帐篷。\n![](images/2f7ae99292f03e28e65dbce940a36107.png)",
+        "options":  [
+
+                    ],
+        "answer":  "10顶",
+        "solution":  "【分析】根据有余数的除法的意义，学生的总人数÷每个小帐篷能住的人数=能住满的帐篷数量。剩余人数不够再住满一个帐篷，要在能住满的帐篷数量上加1，算出来的就是所有人都住下需要的帐篷数量，由此解答即可。\n\n【详解】48÷5=9(顶)……3(人)，9+1=10(顶)。答：至少需要10顶小帐篷。",
+        "knowledge_points":  [
+                                 "有余数除法的实际应用",
+                                 "100以内有余数的除法计算"
+                             ],
+        "source":  "23-24二年级下·福建福州·期末"
+    }
+]
\ No newline at end of file