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"b/\344\270\200\345\271\264\347\272\247\351\242\230\351\233\206/\344\270\200\345\271\264\347\272\247\344\270\212/\344\270\200\345\271\264\347\272\247\344\270\212\347\254\254\344\270\200\345\215\225\345\205\2035\344\273\245\345\206\205\346\225\260\347\232\204\350\256\244\350\257\206\345\222\214\345\212\240\343\200\201\345\207\217\346\263\225.json" @@ -0,0 +1,7798 @@ +[ + { + "id": "1", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "某饮品店今天上午接到了10份外卖订单,(),还有几份没有完成。笑笑列出算式\"10-5=5\"来解决这个问题,你知道横线上应该填什么吗。( )", + "options": [ + "A. 其中5份是橙汁", + "B. 下午又接到了5份", + "C. 已经完成了5份" + ], + "answer": "C", + "solution": "【分析】根据题意可知:求能用10-5=5算式解决这个问题,题干已经给出了接到的订单数量,问题是还有几份没有完成。则有总数量,有剩余的数量,则可提出已完成的数量即可.\n【详解】A。其中5份是橙汁,和题干问题没有关系,不符合题意。B。下午又接到了5份,和问题没有关系,题意上午接到10份,下午接到5份,则问题应该是一个多少份,用加法计算。C。已经完成了5份,题意已经有了接到的订单数,已经完成的数量,求还有几份没有完成的数量。用减法计算,用接到的订单数减去已经完成的数量即可求出还有几份没有完成。列式为:10-5=5,符合题意。故答案为:C", + "knowledge_points": [ + "10的加减法", + "\"提问题\"\"填条件\"问题" + ], + "source": "2025一年级上·全国·专题练习" + }, + { + "id": "2", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.65, + "question": "小明和哥哥有同样多的钱,去了超市后,小明剩3元,哥哥剩4元,谁花掉的钱多。( )", + "options": [ + "A. 小明", + "B. 哥哥", + "C. 同样多" + ], + "answer": "A", + "solution": "【分析】根据题意可知:求谁花的钱多,即同样的钱数,剩余的越少即花的则越多。则将剩余的钱数进行比较,选择数小的即可.\n【详解】3 < 4,则小明花掉的钱多。故答案为: A", + "knowledge_points": [ + "5以内数的比大小" + ], + "source": "2025一年级上·全国·专题练习" + }, + { + "id": "3", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.65, + "question": "小灰兔采的蘑菇不到15朵,给了小白兔3朵,它最多还剩( )朵蘑菇。", + "options": [ + "A. 12", + "B. 11", + "C. 10" + ], + "answer": "B", + "solution": "【分析】要解决这个问题,我们需要先确定小灰兔最多有多少朵蘑菇,再计算给小白兔3朵后最多还剩多少朵。因为小灰兔采的蘑菇不到15朵,所以小灰兔最多有14朵蘑菇。给了小白兔3朵后,还剩的蘑菇数量为14-3=11(朵).\n【详解】由题意可知:小灰兔最多有14朵蘑菇。14-3=11(朵)小灰兔最多还剩11朵蘑菇。故答案为:B", + "knowledge_points": [ + "不退位减法(20以内)" + ], + "source": "2025一年级上·全国·专题练习" + }, + { + "id": "4", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "左边的盒子里能放6块蛋糕,右边的盒子里大约能放几块蛋糕呢。( )\n![](images/Pasted%20image%2020260310203527.png)", + "options": [ + "A. 3块", + "B. 12块", + "C. 20块" + ], + "answer": "B", + "solution": "【分析】一般情况下,写字的手是右手,对应的方向是右边,不写字的手是左手,对应的方向是左边。左边盒子里能放6块蛋糕,右边盒子里大约能放2个6块,由此解答.\n【详解】6+6=12(块)右边的盒子里大约能放12块蛋糕。故答案为:B", + "knowledge_points": [ + "7,6加几的进位加法", + "左,右位置" + ], + "source": "25-26一年级上·全国·课后作业" + }, + { + "id": "5", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.94, + "question": "如图,有5只蚂蚁要进两个洞,每个洞进的蚂蚁会同样多吗。( )\n![](images/Pasted%20image%2020260310203613.png)", + "options": [ + "A. 会", + "B. 不会" + ], + "answer": "B", + "solution": "【分析】根据5的分合即可解答.\n【详解】5可以分成1和4,2和3,0和5。据此可得出每个洞进的数量不一样多。故答案为:B", + "knowledge_points": [ + "5以内数的分与合(组成)" + ], + "source": "25-26一年级上·福建莆田·月考" + }, + { + "id": "6", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "根据图意,以下选项正确的是( ).\n![](images/Pasted%20image%2020260310203620.png)", + "options": [ + "A. 共有4只动物", + "B. 狗比猫少1只", + "C. 猫比狗少1只" + ], + "answer": "B", + "solution": "【分析】比较物体多少时,可以用一一对应的方法,将物体一一对应后,有剩余的物体多,没有剩余的物体少,用减法计算出少的数量即可,将两种动物的数量相加即可计算出总数量.\n【详解】由分析得:\n![](images/Pasted%20image%2020260310203643.png)\n小猫有3只,小狗有2只。一一对应后,小猫有剩余,数量多,小狗没有剩余,数量少。A。3+2=5(只),一共有5只动物,原题说法错误;B。3-2=1(只),狗比猫少1只,原题说法正确;C。小猫比小狗多,原题说法错误。则说法正确的是狗比猫少1只。故答案为:B", + "knowledge_points": [ + "比较物体多少", + "5以内数的加法", + "5以内数的减法" + ], + "source": "25-26一年级上·陕西西安·月考" + }, + { + "id": "7", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "一盒巧克力的块数比9多比15少,3个3个地数正好数完。这盒巧克力有( )块。", + "options": [ + "A. 11", + "B. 12", + "C. 14" + ], + "answer": "B", + "solution": "【分析】确定巧克力块数的范围:比9多,比15少,所以可能是10,11,12,13,14.3个3个地数,在上述的数中找出符合条件的数即可.\n【详解】比9多,比15少,所以可能是10,11,12,13,14.3个3个地数:3,6,9,12,15。在10到14之间,只有12能3个3个地正好数完。因此,这盒巧克力有12块。故答案为:B", + "knowledge_points": [ + "20以内数的比大小" + ], + "source": "2025一年级上·全国·专题练习" + }, + { + "id": "8", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "先摆一个正方体,再在正方体的左边摆一个圆柱体,最后在圆柱体的上面摆一个长方体。下面摆法正确的是( )。", + "options": [ + "A. ![](images/Pasted%20image%2020260310203755.png)", + "B. ![](images/Pasted%20image%2020260310203802.png)", + "C. ![](images/Pasted%20image%2020260310203812.png)" + ], + "answer": "C", + "solution": "【分析】分清上下,左右,头为上,脚为下,写字的是右手,不写字的是左手。根据长方体是长长方方的;正方体是方方正正的,每个面都是正方形;圆柱上下是平平的面,且上下一样粗,侧面是曲面进行解答.\n【详解】A。正方体的左边是长方体,长方体上面是圆柱,不符合题意;B。正方体的右边是圆柱,不符合题意;C。正方体在右,其左边是圆柱,圆柱上面是长方体,符合题意。故答案为:C", + "knowledge_points": [ + "立体图形的拼搭", + "左,右位置", + "上,下位置" + ], + "source": "2025一年级上·全国·专题练习" + }, + { + "id": "9", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "15+![](images/Pasted%20image%2020260310203826.png)<20,![](images/Pasted%20image%2020260310203829.png)里可以填的数有( )个。", + "options": [ + "A. 4", + "B. 5", + "C. 6" + ], + "answer": "B", + "solution": "【分析】\n先想15+![](images/Pasted%20image%2020260310203833.png)的结果要小于20。那我们可以先算20-15=5,这说明![](images/Pasted%20image%2020260310203837.png)里的数要比5小,找出比5小的自然数即可解答.\n【详解】找出比5小的自然数,有0,1,2,3,4,一共5个。因此15+![](images/Pasted%20image%2020260310203843.png)<20,![](images/Pasted%20image%2020260310203847.png)里可以填的数有5个.\n故答案为:B", + "knowledge_points": [ + "不进位加法(20以内)", + "不退位减法(20以内)", + "20以内数的比大小" + ], + "source": "2025一年级上·全国·专题练习" + }, + { + "id": "10", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.94, + "question": "圈一圈,填一填.\n(1)![](images/Pasted%20image%2020260310203908.png)从左边数,圈出4个.\n(2)![](images/Pasted%20image%2020260310203915.png)从左边数,圈出第4个.\n我发现(1)中圈了( )个,(2)中圈了( )个,4个和第4个表示的意思(相同 不相同)(圈出正确答案)。", + "options": [], + "answer": "见详解;见详解;4;1;见详解", + "solution": "【分析】一般情况下,写字的手是右手,对应的方向是右边,不写字的手是左手,对应的方向是左边。(1)从左数,圈出4个,即将![](images/Pasted%20image%2020260310203956.png)圈出来,共圈4个;(2)从左数,圈出第4个,即将![](images/Pasted%20image%2020260310204004.png)圈出来,只圈1个;圈出来的数量不同,则4个和第4个表示的意思不同.\n【详解】(1)从左边数,圈出4个.\n![](images/Pasted%20image%2020260310204026.png)(2)从左边数,圈出第4个.\n![](images/Pasted%20image%2020260310204032.png)我发现(1)中圈了4个,(2)中圈了1个,4个和第4个表示的意思(相同 ![](images/Pasted%20image%2020260310203923.png))。", + "knowledge_points": [ + "认识几和第几", + "左,右位置" + ], + "source": "25-26一年级上·山西长治·月考" + }, + { + "id": "11", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.65, + "question": "画爱心,写一写.\n![](images/Pasted%20image%2020260310204120.png)", + "options": [], + "answer": "见详解", + "solution": "【分析】本题根据数的分与合进行解答。第1题:2和1合起来就是3,左边画2个,右边画1个;第2题:5可以分成3和2,左边画3个,右边画2个;第3题:4可以分成1和3,左边画1个,右边画3个;或4可以分成2和2,左边画2个,右边画2个;或4可以分成3和1,左边画3个,右边画1个.\n【详解】由分析得:\n![](images/Pasted%20image%2020260310204141.png)", + "knowledge_points": [ + "5以内数的分与合(组成)" + ], + "source": "25-26一年级上·山西长治·月考" + }, + { + "id": "12", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.94, + "question": "比一比.\n![](images/Pasted%20image%2020260310204214.png)\n( )=( ),( )多,5( )3,( )少,2( )3", + "options": [], + "answer": "=;3;多;>;少;<", + "solution": "【分析】比较物体多少时,可以用一一对应的方法,将物体一一对应后,有剩余的物体多,没有剩余的物体少;若都没有剩余,则同样多。依次数出每种车的数量再比较大小即可,5以内数大小关系为5>4>3>2>1;1<2<3<4<5,由此比较.\n【详解】![](images/Pasted%20image%2020260310204251.png)\n![](images/Pasted%20image%2020260310204314.png)\n![](images/Pasted%20image%2020260310204331.png)\n![](images/Pasted%20image%2020260310204346.png)\n![](images/Pasted%20image%2020260310204402.png)", + "knowledge_points": [ + "比较物体多少", + "5以内数的比大小" + ], + "source": "25-26一年级上·山西长治·月考" + }, + { + "id": "13", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.65, + "question": "按顺序填数.\n![](images/Pasted%20image%2020260310204410.png)", + "options": [], + "answer": "2;4;5", + "solution": "【分析】由题可知,车厢号按照5以内数的正序排列,依次为1,2,3,4,5,由此解答.\n【详解】由分析得:\n![](images/Pasted%20image%2020260310204417.png)", + "knowledge_points": [ + "5以内数的排序" + ], + "source": "25-26一年级上·山西长治·月考" + }, + { + "id": "14", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.94, + "question": "下面是数字手指操,看一看,写一写.\n![](images/Pasted%20image%2020260310204424.png)", + "options": [], + "answer": "5;3;1;4;2", + "solution": "【分析】从左到右数出每只手伸出的手指数量,然后填在对应的方框里.\n【详解】第一只手伸出5手指;第二只手伸出3根手指;第三只手伸出1根手指;第四只手伸出4根手指,第五只手伸出2根手指。因此从左到右依次填写5,3,1,4,2.\n![](images/Pasted%20image%2020260310204448.png)", + "knowledge_points": [ + "1~5的认识和读写" + ], + "source": "25-26一年级上·山西长治·月考" + }, + { + "id": "15", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.94, + "question": "一共有( )个小朋友,其中有( )个男生,有( )个女生,再来( )个男生,就和女生人数同样多.\n![](images/Pasted%20image%2020260310204453.png)", + "options": [], + "answer": "5;2;3;1", + "solution": "【分析】数一数可知,一共有5个小朋友,有2个男生和3个女生。女生的人数-男生的人数=和女生人数相同时,男生要再来的人数.\n【详解】3-2=1(个)\n一共有5个小朋友,其中有2个男生,有3个女生,再来1个男生,就和女生人数同样多。", + "knowledge_points": [ + "5以内数的减法", + "1~5的认识和读写" + ], + "source": "25-26一年级上·山西长治·月考" + }, + { + "id": "16", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "在多的后面画\"√\".\n![](images/Pasted%20image%2020260310204500.png)", + "options": [], + "answer": "见详解", + "solution": "【分析】通过数一数棕熊和熊猫的个数,即可知谁多谁少.\n【详解】通过数一数可知:棕熊有6个,熊猫有4个,6>4,因此棕熊多.\n![](images/Pasted%20image%2020260310204545.png)", + "knowledge_points": [ + "数一数", + "7以内数的比大小" + ], + "source": "25-26一年级上·江西九江·期中" + }, + { + "id": "17", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.94, + "question": "看图写数.\n![](images/Pasted%20image%2020260310204558.png)", + "options": [], + "answer": "3;5;0;2", + "solution": "【分析】数清楚各个图上物品的数量,再将数字填写在田字格内即可。图一有3个桃子。图二有5个石榴。图三一个都没有,用0表示。图四有2个苹果.\n【详解】\n![](images/Pasted%20image%2020260310204614.png)", + "knowledge_points": [ + "1~5的认识和读写", + "0的认识和读写" + ], + "source": "25-26一年级上·广东广州·月考" + }, + { + "id": "18", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "按规律填数.\n(1)![](images/Pasted%20image%2020260310204621.png)\n(2)![](images/Pasted%20image%2020260310204626.png)", + "options": [], + "answer": "6;8;9;11;12;14;4;10;14;16;20", + "solution": "【分析】(1)后一个数比前一个数多1,数一数可知:5,6,7,8,9,10,11,12,13,14;(2)后一个数比前一个数多2,数一数可知:2,4,6,8,10,12,14,16,18,20.\n【详解】由分析可得:\n![](images/Pasted%20image%2020260310204642.png)", + "knowledge_points": [ + "20以内数的排序", + "整数排列的规律" + ], + "source": "2025一年级上·全国·专题练习" + }, + { + "id": "19", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.94, + "question": "看图写数。![](images/Pasted%20image%2020260310204650.png)", + "options": [], + "answer": "5;7;9", + "solution": "【分析】根据题意,一个一个地数,数到几就有几个●,填写对应的数即可.\n【详解】由分析得:图1:有5个●;图2:有7个●;图3:有9个●;![](images/Pasted%20image%2020260310204700.png)", + "knowledge_points": [ + "数一数", + "1~5的认识和读写", + "6,7的认识和读写", + "8,9的认识和读写" + ], + "source": "25-26一年级上·云南曲靖·月考" + }, + { + "id": "20", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.94, + "question": "在大的下面画\"√\".\n![](images/Pasted%20image%2020260310204719.png)", + "options": [], + "answer": "见详解", + "solution": "【分析】通过观察可知,右边的明显比左边的大,所以在右边的下面画\"√\".\n【详解】\n根据分析:![](images/Pasted%20image%2020260310204725.png)", + "knowledge_points": [ + "比较物体大小" + ], + "source": "25-26一年级上·云南曲靖·月考" + }, + { + "id": "21", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.94, + "question": "在多的后面画\"√\".\n![](images/Pasted%20image%2020260310204735.png)", + "options": [], + "answer": "见详解", + "solution": "【分析】先数出两个图形中的点数,再比较大小即可,5以内数从大到小关系为5>4>3>2>1,由此比较.\n【详解】左边的图形有3个点;右边的图形有5个点。因为5>3,所以在右边图形的括号里画\"√\".\n![](images/Pasted%20image%2020260310204750.png)", + "knowledge_points": [ + "比较物体多少", + "1~5的认识和读写" + ], + "source": "25-26一年级上·云南曲靖·月考" + }, + { + "id": "22", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.94, + "question": "在高的下面画\"√\".\n![](images/Pasted%20image%2020260310204800.png)", + "options": [], + "answer": "见详解", + "solution": "【分析】比较高矮时要在同一水平面比较,通过观察可知,左边的高度明显高于右边的高度.\n【详解】\n由分析可知:![](images/Pasted%20image%2020260310204820.png)", + "knowledge_points": [ + "比高矮" + ], + "source": "25-26一年级上·云南曲靖·月考" + }, + { + "id": "23", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "做一做,想一想,圈一圈.\n![](images/Pasted%20image%2020260310204835.png)", + "options": [], + "answer": "见详解", + "solution": "【分析】一般情况下,写字的手是右手,不写字的手是左手。据此分一分.\n【详解】由题意分析得:![](images/Pasted%20image%2020260310204842.png)", + "knowledge_points": [ + "左,右位置" + ], + "source": "25-26一年级上·广东广州·月考" + }, + { + "id": "24", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "根据下图的摆放位置圈一圈.\n![](images/Pasted%20image%2020260310204855.png)\n(1)乒乓球在毽子的(左 右)边.\n(2)排球在足球的(左 右)边.\n(3)毽子在足球的(上 下)面.\n(4)跳绳在排球的(上 下)面.\n(5)羽毛球在乒乓球的下面,在排球的右边,它应该放在(①②③)。", + "options": [], + "answer": "右;左;上;下;③", + "solution": "【分析】一般情况下,写字的这只手是右手,右手所指的这边是右边,另一只手所指的这边是左边。头顶所指的这面是上面,脚底所指的这面是下面。据此解决即可.\n【详解】由题意分析得:(1)乒乓球在毽子的(右)边。(2)排球在足球的(左)边。(3)毽子在足球的(上)面。(4)跳绳在排球的(下)面。(5)羽毛球在乒乓球的下面,在排球的右边,它应该放在(③)。", + "knowledge_points": [ + "左,右位置", + "上,下位置" + ], + "source": "25-26一年级上·广东广州·月考" + }, + { + "id": "25", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "在括号里填上\">\"\"<\"或\"=\".\n13-10( )6\n4+8( )12\n15-3( )11\n6+5( )4+7\n18( )9+7\n19-7( )10\n9-5( )7\n17-4( )6+8", + "options": [], + "answer": "<;=;>;=;>;>;<;<", + "solution": "【分析】分别计算出各算式的答案,然后再比较大小即可.\n100以内数的比较大小:①两位数大于一位数;②两位数与两位数比较大小,先比较十位上的数,十位上大的数就大,十位上相同的,就比较个位上的数,个位上大的数就大.\n【详解】13-10=3,3<6,则13-10<6;4+8=12;15-3=12,12>11,15-3>11;6+5=11,4+7=11,11=11,则6+5=4+7;9+7=16,18>16,则18>9+7;19-7=12,12>10,则19-7>10;9-5=4,4<7,则9-5<7;17-4=13,6+8=14,13<14,则17-4<6+8。", + "knowledge_points": [ + "7,6加几的进位加法", + "5~2加几的进位加法", + "不退位减法(20以内)" + ], + "source": "2025一年级上·全国·专题练习" + }, + { + "id": "26", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.94, + "question": "在( )里填上合适的数.\n( )-6=3 ( )+3=10 4+( )=7\n( )+8=18 10-( )=5 2+( )=14\n( )+6=15 ( )-7=12 19-( )=10", + "options": [], + "answer": "9;7;3;10;5;12;9;19;9", + "solution": "【分析】根据被减数=差+减数,加数=和-另一个加数,减数=被减数-差即可解答.\n【详解】3+6=9,则9-6=3;10-3=7,则7+3=10;7-4=3,则4+3=7;18-8=10,则10+8=18;10-5=5,14-2=12,则2+12=14;15-6=9,则9+6=15;12+7=19,19-7=12;19-10=9,则19-9=10。", + "knowledge_points": [ + "不进位加法(20以内)", + "不退位减法(20以内)" + ], + "source": "2025一年级上·全国·专题练习" + }, + { + "id": "27", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "在括号里填上\"+\"或\"-\".\n9( )4( )7=12\n8( )2( )3=13\n6( )1( )4=1\n5( )7( )2=10\n9( )4( )3=8\n1( )7( )4=4", + "options": [], + "answer": "-;+;+;+;-;-;+;-;-;+;+;-", + "solution": "【分析】①9可以分成4和5,5和7可以合成12,则9-4+7=12;②8和2可以合成10,10和3可以合成13,则8+2+3=13;③6可以分成5和1,5可以分成4和1,则6-1-4=1;④5和7可以合成12,12可以分成2和10,则5+7-2=10;⑤9可以分成4和5,5和3可以合成8,则9-4+3=8;⑥1和7可以合成8,8可以分成4和4,则1+7-4=4.\n【详解】9(-)4(+)7=12\n8(+)2(+)3=13\n6(-)1(-)4=1\n5(+)7(-)2=10\n9(-)4(+)3=8\n1(+)7(-)4=4", + "knowledge_points": [ + "加减混合运算(10以内)", + "5~2加几的进位加法", + "加减混合运算(20以内)" + ], + "source": "2025一年级上·全国·专题练习" + }, + { + "id": "28", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "在计数器上拨珠子表示出11,左边的\"1\"比右边的\"1\"多( )。", + "options": [], + "answer": "9", + "solution": "【分析】计数器十位上有几个珠子,就表示几个十,个位上有几个珠子,就表示几个一。11中左边的1表示1个十,右边的1表示1个一。1个十表示10,1个一表示1.\n【详解】10 - 1 = 9 (个),则在计数器上拨珠子表示出11,左边的\"1\"比右边的\"1\"多 9。", + "knowledge_points": [ + "20以内数的组成" + ], + "source": "2025一年级上·全国·专题练习" + }, + { + "id": "29", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "在短的后面画\"√\".\n![](images/Pasted%20image%2020260310205334.png)", + "options": [], + "answer": "见详解", + "solution": "【分析】图中物体的一端对齐,则另一端离对齐的一端越远就越长,离对齐的一端越近就越短,由此解答.\n【详解】由分析可知:\n![](images/Pasted%20image%2020260310205340.png)", + "knowledge_points": [ + "比长短" + ], + "source": "25-26一年级上·广东广州·月考" + }, + { + "id": "30", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "看数圈一圈.\n![](images/Pasted%20image%2020260310205350.png)", + "options": [], + "answer": "见详解", + "solution": "【分析】看数字数出相应数量的蔬菜或水果,用笔圈起来即可.\n【详解】由题意分析得:\n![](images/Pasted%20image%2020260310205400.png)", + "knowledge_points": [ + "数一数", + "1~5的认识和读写" + ], + "source": "25-26一年级上·广东广州·月考" + }, + { + "id": "31", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.65, + "question": "在正确答案前面的\"框\"里画\"√\",在\"( )\"里填数.\n![](images/Pasted%20image%2020260310205414.png)\n(1)第二个小女孩的前面是谁。\n![](images/Pasted%20image%2020260310205429.png)\n(2)![](images/Pasted%20image%2020260310205448.png)在![](images/Pasted%20image%2020260310205456.png)的(()前面 ()后面)\n(3)![](images/Pasted%20image%2020260310205506.png)正好紧跟在谁的后面。\n![](images/Pasted%20image%2020260310205512.png)\n(4)![](images/Pasted%20image%2020260310205518.png)的前面有( )人。", + "options": [], + "answer": "见详解;见详解;见详解;4", + "solution": "【分析】(1)(2)(3)脸所对的这面是前面,背所对的这面是后面;据此解决即可.\n(4)![](images/Pasted%20image%2020260310205541.png)的前面有:![](images/Pasted%20image%2020260310205547.png),数一数可知有4人.\n【详解】\n(1)\n![](images/Pasted%20image%2020260310205616.png)\n(2)![](images/Pasted%20image%2020260310205630.png)\n(3)\n![](images/Pasted%20image%2020260310205646.png)(4)4。", + "knowledge_points": [ + "数一数", + "前,后位置" + ], + "source": "25-26一年级上·广东广州·月考" + }, + { + "id": "32", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "填一填.\n![](images/Pasted%20image%2020260310205721.png)", + "options": [], + "answer": "2;1;5;3", + "solution": "【分析】5可以分成3和2;3可以分成2和1;4和1合成5;4可以分成1和3;据此填空.\n【详解】由分析可知:\n![](images/Pasted%20image%2020260310205729.png)", + "knowledge_points": [ + "5以内数的分与合(组成)" + ], + "source": "25-26一年级上·广东广州·月考" + }, + { + "id": "33", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.65, + "question": "用2颗珠子在计数器上拨数,这个数可能是( ),也有可能是( ),还可能是( ),请你在下面的计数器上把这三个数按从大到小的顺序画一画.\n![](images/Pasted%20image%2020260310205737.png)", + "options": [], + "answer": "2;11;20;见详解", + "solution": "【分析】用2颗珠子在计数器上拨数,把这2颗珠子都放在个位上,那么这个数是2;把2颗珠子十位上放一个,个位上放一个,那么这个数是11;把2颗珠子都放在十位上,那么这个数是20。对应在计数器上按从大到小的顺序画出这三个数即可.\n【详解】用2颗珠子在计数器上拨数,并对应在计数器上按从大到小的顺序画出。把2颗珠子都放在十位上,那么这个数是20;![](images/Pasted%20image%2020260310205743.png)把2颗珠子十位上放一个,个位上放一个,那么这个数是11;![](images/Pasted%20image%2020260310205748.png)把这2颗珠子都放在个位上,那么这个数是2;![](images/Pasted%20image%2020260310205753.png)", + "knowledge_points": [ + "20以内数的组成" + ], + "source": "25-26一年级上·全国·课后作业" + }, + { + "id": "34", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.94, + "question": "按顺序写数.\n![](images/Pasted%20image%2020260310205825.png)", + "options": [], + "answer": "见详解", + "solution": "【分析】根据5以内的顺序,0,1,2,3,4,5,填写在数尺上即可.\n【详解】如图:\n![](images/Pasted%20image%2020260310205833.png)", + "knowledge_points": [ + "5以内数的排序" + ], + "source": "25-26一年级上·陕西西安·月考" + }, + { + "id": "35", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.65, + "question": "套圈.\n![](images/Pasted%20image%2020260310205843.png)\n(1)上面一共有( )缸鱼.\n(2)从右边数,第( )缸鱼和第( )缸鱼合起来有6条.\n(3)从左边数,优优套中第4缸鱼,在它的下面画\"○\".\n(4)天天套中右边的2缸鱼,把它们圈起来。", + "options": [], + "answer": "8;2;6;见详解;见详解", + "solution": "【分析】(1)数一数可知,一共有8缸鱼;(2)从右边数,第2缸有4条,第6缸有2条,4+2=6;或第3缸有1条,第5缸有5条,1+5=6;(3)(4)按要求圈画.\n【详解】(1)上面一共有8缸鱼。(2)从右边数,第2缸鱼和第6缸鱼合起来有6条(或第3缸和第5缸合起来有6条)。(3)![](images/Pasted%20image%2020260310205925.png)(4)![](images/Pasted%20image%2020260310205934.png)", + "knowledge_points": [ + "6的加减法", + "认识几和第几", + "左,右位置" + ], + "source": "25-26一年级上·江西九江·期中" + }, + { + "id": "36", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "![](images/Pasted%20image%2020260310205953.png)\n一共有( )个数,其中最大的数是( ),最小的数是( )。从左边数第4个数是( ),从右边数第3个数是( )。", + "options": [], + "answer": "9;20;9;16;17", + "solution": "【分析】将这几个数数一数,由此可得一共有多少个数,然后再将这几个数进行比较大小,从而可得最大和最小的数分别是多少;再从左边数或者右边数出第几个数是几即可,由此解答。整数比较大小的方法,位数多的数大于位数少的数;位数相同的数,从最高位比起,最高位上大的数就大,最高位上相同的,就比较下一位,以此类推。一般情况下,写字的手是右手,右手所指的这边是右边,另一只手所指的这边是左边.\n【详解】20>19>18>17>16>14>12>11>9\n一共有9个数,其中最大的数是20,最小的数是9。从左边数第4个数是16,从右边数第3个数是17。", + "knowledge_points": [ + "数一数", + "20以内数的排序", + "左,右位置", + "20以内数的比大小" + ], + "source": "25-26一年级上·全国·单元测试" + }, + { + "id": "37", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.94, + "question": "数一数,写一写.\n![](images/Pasted%20image%2020260310210008.png)", + "options": [], + "answer": "4;2;3;5", + "solution": "【分析】依次数出每组物品的数量,填写在对应的田字格里即可。图1:有4个梨;图2:有2只猫;图3:有3只小兔;图4:有5个草莓.\n【详解】填写如下:\n![](images/Pasted%20image%2020260310210020.png)", + "knowledge_points": [ + "数一数", + "1~5的认识和读写" + ], + "source": "25-26一年级上·陕西西安·月考" + }, + { + "id": "38", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.94, + "question": "把直尺上的数字补充完整.\n![](images/Pasted%20image%2020260310210027.png)\n(1)我发现,数字( )可以表示起点.\n(2)和2相邻的两个数是( )和( )。", + "options": [], + "answer": "0;3;5;0;1;3", + "solution": "【分析】(1)根据5以内数排序即可解答。0,1,2,3,4,5.\n直尺的最左侧通常标记为0,作为起点,按照数字从小到大的顺序依次填入即可.\n(2)观察直尺上的数,求和2相邻的两个数是即它前面的1个数和后面的1个数即可.\n【详解】由分析可得:\n![](images/Pasted%20image%2020260310210040.png)\n(1)我发现,数字(0)可以表示起点。(2)和2相邻的两个数是(1)和(3)。", + "knowledge_points": [ + "5以内数的排序", + "相邻的数" + ], + "source": "25-26一年级上·福建莆田·月考" + }, + { + "id": "39", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "数一数,填一填.\n![](images/Pasted%20image%2020260310210051.png)\n(1)从左边数,第1盆开了( )朵花,第( )盆开了1朵花,第5盆开了( )朵花.\n(2)从右边数,第3盆开了( )朵花。", + "options": [], + "answer": "4;4;3;5", + "solution": "【分析】(1)一般情况下,写字的手是右手也就是右边,不写字的手是左手也就是左边。从左数,第1盆开了4朵花,第2盆开了2朵花,第3盆开了5朵花,第4盆开了1朵花,第5盆开了3朵花;(2)从右数,第1盆开了3朵花,第2盆开了1朵花,第3盆开了5朵花,第4盆开了2朵花,第5盆开了4朵花.\n【详解】(1)从左边数,第1盆开了4朵花,第4盆开了1朵花,第5盆开了3朵花。(2)从右边数,第3盆开了5朵花。", + "knowledge_points": [ + "认识几和第几", + "左,右位置" + ], + "source": "25-26一年级上·陕西西安·月考" + }, + { + "id": "40", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.94, + "question": "在括号里填上\"+\"或\"-\".\n![](images/Pasted%20image%2020260310210107.png)\n3( )2=5\n4( )1=5\n3( )1=4\n4( )1=3", + "options": [], + "answer": "+;+;+;-", + "solution": "【分析】根据整数加减法的计算法则及数的分与合进行解答。第1题:3和2合起来就是5,填写\"+\";第2题:4和1合起来就是5,填写\"+\";第3题:3和1合起来就是4,填写\"+\";第4题:4可以分成1和3,填写\"-\".\n【详解】填写如下: 3+2=5,4+1=5,3+1=4,4-1=3", + "knowledge_points": [ + "5以内数的加法", + "5以内数的减法", + "5以内数的分与合(组成)" + ], + "source": "25-26一年级上·陕西西安·月考" + }, + { + "id": "41", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "填一填。(图中的小正方体可以拆下来,重新拼)\n![](images/Pasted%20image%2020260310210135.png)", + "options": [], + "answer": "6;2", + "solution": "【分析】底层能看到有5个小正方体,上层有1个小正方体,共有5+1=6个。要拼成最小的大正方体,需要8个小正方体(2行,2列,2层,一个一个数总共8个),已有6个小正方体,所以至少还需要的用总需要的减去已有的数量,即可解答.\n【详解】5+1=6(个)8-6=2(个)\n![](images/Pasted%20image%2020260310210146.png)", + "knowledge_points": [ + "立体图形的拼搭" + ], + "source": "2025一年级上·全国·专题练习" + }, + { + "id": "42", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "数一数,下面图形各由多少个正方体组成。\n![](images/Pasted%20image%2020260310210154.png)", + "options": [], + "answer": "6;4;5;8;7;10", + "solution": "【分析】根据题意,分别数出每组中正方体的个数,需要注意的是,上层的每一正方体下面都有一个对应的正方体.\n【详解】图1:从上往下第一层有2个,第二层有4个,一共有2+4=6(个);图2:从上往下第一层有1个,第二层有3个,一共有1+3=4(个);图3:从上往下第一层有1个,第二层有4个,一共有1+4=5(个);图4:从上往下第一层有4个,第二层有4个,一共有4+4=8(个);图5:从上往下第一层有1个,第二层有2个,第三层有4个,一共有1+2+4=7(个);图6:从上往下第一层有1个,第二层有3个,第三层有6个,一共有1+3+6=10(个).\n![](images/Pasted%20image%2020260310210219.png)", + "knowledge_points": [ + "6的加减法", + "数正方体的个数", + "8,9的加减法", + "连加,连减(10以内)" + ], + "source": "2025一年级上·全国·专题练习" + }, + { + "id": "43", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "按规律填数.\n![](images/Pasted%20image%2020260310210226.png)", + "options": [], + "answer": "14;12;3;12", + "solution": "【分析】观察第一行数字可知:18和16相差2,所以这列数字从左往右依次减少2;观察第二行数字可知:6和9之间相差3,所以这列数字从左往右依次增加3.\n【详解】16-2=14,14-2=12,6-3=3,9+3=12\n![](images/Pasted%20image%2020260310210246.png)", + "knowledge_points": [ + "9加几的进位加法", + "整数排列的规律", + "不退位减法(20以内)" + ], + "source": "2025一年级上·全国·专题练习" + }, + { + "id": "44", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "一个数是由7个一和1个十组成的,这个数是( ),它前面一个数是( ),后面的第三个数是( )。", + "options": [], + "answer": "17;16;20", + "solution": "【分析】7个一表示个位是7,1个十表示十位是1,所以这个数是17;它前面一个数就是比它小1;后面的第三个数就是比它大3,据此解答.\n【详解】17-1=16;17+3=20;一个数是由7个一和1个十组成的,这个数是17,它前面一个数是16,后面的第三个数是20。", + "knowledge_points": [ + "20以内数的组成", + "不进位加法(20以内)" + ], + "source": "2025一年级上·全国·专题练习" + }, + { + "id": "45", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.94, + "question": "一个数,十位上是1,个位上的数字比十位上的数字大7,这个数是( )。", + "options": [], + "answer": "18", + "solution": "【分析】十位数是几就是几十,十位数字为1,个位上的数字比十位上的数字大7,个位数字为(1+7),据此可写出这个两位数.\n【详解】个位数字1+7=8,十位数字为1,所以这个两位数为:10+8=18。", + "knowledge_points": [ + "20以内数的组成" + ], + "source": "2025一年级上·全国·专题练习" + }, + { + "id": "46", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.94, + "question": "看图写数,并读一读.\n![](images/Pasted%20image%2020260310210404.png)( ) ( ) ( )\n读作:( ) 读作:( ) 读作:( )", + "options": [], + "answer": "12;15;16;十二;十五;十六", + "solution": "【分析】数清楚图上有几个星星,即可得出此数。计数器十位上有几个珠子,就表示几个十,个位上有几个珠子,就表示几个一,据此数清楚各个数位上珠子的数量,即可得出答案。一捆小棒表示10,一根小棒表示1,数清楚小棒的数量,即可得出此数。十位上是几就读作几十,个位上是几就读作几,据此即可读出各数.\n【详解】![](images/Pasted%20image%2020260310210434.png)", + "knowledge_points": [ + "11~20的认识和读写" + ], + "source": "2025一年级上·全国·专题练习" + }, + { + "id": "47", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.94, + "question": "每种玩具各有多少.\n![](images/Pasted%20image%2020260310210449.png)", + "options": [], + "answer": "12;17;16", + "solution": "【分析】用一(1)班小汽车的辆数加上一(2)班小汽车的辆数,即可求出一共有多少辆小汽车;用一(1)班小飞机的架数加上一(2)班小飞机的架数,即可求出一共有多少架小飞机;用一(1)班玩具熊的只数加上一(2)班玩具熊的只数,即可求出一共有多少只玩具熊.\n【详解】小汽车:7+5=12(辆)小飞机:8+9=17(架)玩具熊:9+7=16(只)填表如下:![](images/Pasted%20image%2020260310210507.png)", + "knowledge_points": [ + "图文问题", + "8加几的进位加法", + "7,6加几的进位加法", + "9加几的进位加法" + ], + "source": "25-26一年级上·全国·单元测试" + }, + { + "id": "48", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "排序题", + "difficulty": 0.65, + "question": "把下面卡片上的算式按得数从小到大的顺序排一排。(填算式)\n![](images/Pasted%20image%2020260310210520.png)( )<( )<( )<( )", + "options": [], + "answer": "4+7<5+7<9+6<8+8", + "solution": "【分析】先算出算式的得数,然后比较得数大小。20以内的数从小到大排列是:0<1<2<3<4<5<6<7<8<9<10<11<12<13<14<15<16<17<18<19<20,据此比较大小,最后把算式按从小到大的顺序排列,即可解答.\n【详解】4+7=11;8+8=16;9+6=15;5+7=12。11<12<15<16,故4+7<5+7<9+6<8+8", + "knowledge_points": [ + "8加几的进位加法", + "9加几的进位加法", + "5~2加几的进位加法" + ], + "source": "25-26一年级上·全国·单元测试" + }, + { + "id": "49", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "判断题", + "difficulty": 0.85, + "question": "最大的一位数和最小的两位数的和是11。( )", + "options": [], + "answer": "×", + "solution": "【分析】最大的一位数是9,最小的两位数是10,它们的和应为9+10=19,而非11.\n【详解】由分析可知:9+10=19最大的一位数和最小的两位数的和是19,而不是11。原题说法错误。故答案为: ×", + "knowledge_points": [ + "不进位加法(20以内)" + ], + "source": "2025一年级上·全国·专题练习" + }, + { + "id": "50", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "判断题", + "difficulty": 0.65, + "question": "从10开始倒着数,第5个数是5。( )", + "options": [], + "answer": "×", + "solution": "【分析】从10开始倒着数,依次为10,9,8,7,6,第5个数应为6,而非5.\n【详解】从10开始倒着数,第1个数是10,第2个数是9,第3个数是8,第4个数是7,第5个数是6。因此,题目中\"第5个数是5\"的说法错误。故答案为: ×", + "knowledge_points": [ + "10以内数的排序" + ], + "source": "2025一年级上·全国·专题练习" + }, + { + "id": "51", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "计算题", + "difficulty": 0.94, + "question": "看图列式计算.\n![](images/Pasted%20image%2020260310210559.png)", + "options": [], + "answer": "3-2=1", + "solution": "【分析】原有3只小鸟,用虚线框起来2只表示去掉2只,则原有的数量-去掉的数量=还剩的数量.\n【详解】3-2=1(只)还剩1只小鸟。", + "knowledge_points": [ + "图文问题", + "5以内数的减法" + ], + "source": "25-26一年级上·山西长治·月考" + }, + { + "id": "52", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "计算题", + "difficulty": 0.94, + "question": "计算乐园.\n![](images/Pasted%20image%2020260310210611.png)", + "options": [], + "answer": "1;4;3;4;2;0", + "solution": "【分析】第一组:分别用1加上右边的各数,所得的结果填写在对应的方框里;第二组:分别用5减去右边的各数,所得的结果填写在对应的方框里.\n【详解】1+0=1;1+3=4;1+2=3;5-1=4;5-3=2;5-5=0\n![](images/Pasted%20image%2020260310210623.png)", + "knowledge_points": [ + "5以内数的加法", + "5以内数的减法", + "有关0的加减法" + ], + "source": "25-26一年级上·山西长治·月考" + }, + { + "id": "53", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式计算.\n![](images/Pasted%20image%2020260310210634.png)", + "options": [], + "answer": "5-1=4", + "solution": "【分析】由图可知,一共有5块西瓜,吃掉了1块,则西瓜的总数量-吃掉的数量=还剩的数量.\n【详解】5-1=4(块)还剩4块西瓜。", + "knowledge_points": [ + "图文问题", + "5以内数的减法" + ], + "source": "25-26一年级上·山西长治·月考" + }, + { + "id": "54", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "计算题", + "difficulty": 0.94, + "question": "看图讲故事,填算式.\n![](images/Pasted%20image%2020260310210644.png)", + "options": [], + "answer": "5-2=4-1", + "solution": "【分析】根据图片可知:左边猴子原有5个桃子,吃了2个,还剩几个;右边猴子原有4个桃子,吃了1个后和左边猴子的数量同样多,则我们可以分别求出两只猴子各剩余的数量,然后进行比较是否同样多。用原有的数量-吃了的数量=还剩的数量.\n【详解】5-2=3(个)4-1=3(个)3=3则5-2=4-1。", + "knowledge_points": [ + "5以内数的减法" + ], + "source": "25-26一年级上·福建莆田·月考" + }, + { + "id": "55", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "计算题", + "difficulty": 0.94, + "question": "看图列式计算.\n![](images/Pasted%20image%2020260310210658.png)", + "options": [], + "answer": "5-2=3", + "solution": "【分析】由图可知,5个点减去2个点,求还剩几个,用减法列式计算.\n【详解】5-2=3", + "knowledge_points": [ + "图文问题", + "5以内数的减法" + ], + "source": "25-26一年级上·云南曲靖·月考" + }, + { + "id": "56", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "计算题", + "difficulty": 0.94, + "question": "看图列式计算.\n![](images/Pasted%20image%2020260310210707.png)\n![](images/Pasted%20image%2020260310210718.png)", + "options": [], + "answer": "3+2=5", + "solution": "【分析】先数出左右两边图形里的点数,把它们相加,即可解答.\n【详解】左边图形里的点数是3;右边图形里的点数是2.3+2=5", + "knowledge_points": [ + "5以内数的加法" + ], + "source": "25-26一年级上·云南曲靖·月考" + }, + { + "id": "57", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式计算.\n![](images/Pasted%20image%2020260310210724.png)", + "options": [], + "answer": "2+2=4", + "solution": "【分析】由图可知,有2只母鸡,2只公鸡,则母鸡的数量+公鸡的数量=鸡的总数量.\n【详解】2+2=4(只)一共有4只鸡。", + "knowledge_points": [ + "图文问题", + "5以内数的加法" + ], + "source": "25-26一年级上·山西长治·月考" + }, + { + "id": "58", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式计算.\n![](images/Pasted%20image%2020260310210735.png)", + "options": [], + "answer": "3+2=5或2+3=5;5-3=2或5-2=3", + "solution": "【分析】用左边小狗的只数加上右边小狗的只数,即可求出小狗的总只数,或者用右边小狗的只数加上左边小狗的只数,即可求出小狗的总只数;用小狗的总只数减去左边小狗的只数,即可求出右边小狗的只数,或者用小狗的总只数减去右边小狗的只数,即可求出左边小狗的只数.\n【详解】3+2=5(只)或2+3=5(只)一共有5只小狗。5-3=2(只)右边有2只小狗。或5-2=3(只)左边有3只小狗。", + "knowledge_points": [ + "图文问题", + "5以内数的加法", + "5以内数的减法" + ], + "source": "25-26一年级上·江西九江·期中" + }, + { + "id": "59", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "计算题", + "difficulty": 0.65, + "question": "看图列式计算.\n![](images/Pasted%20image%2020260310210758.png)", + "options": [], + "answer": "8-4+2=6", + "solution": "【分析】根据图片可知:一共有8只鸽子,飞走了4只后,又飞来了2只,现在有多少只。用共有的数量减去飞走的数量,再加上又飞来的数量即可求出现在有的数量.\n【详解】8-4+2=6(只)则现在有6只。", + "knowledge_points": [ + "加减混合运算(10以内)" + ], + "source": "25-26一年级上·江西九江·期中" + }, + { + "id": "60", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "计算题", + "difficulty": 0.65, + "question": "看图列式计算.\n![](images/Pasted%20image%2020260310210839.png)", + "options": [], + "answer": "7+2=9", + "solution": "【分析】观察图片可知:盘中有7个桃子,外面有2个桃子,一共多少个桃子。用盘中的数量加上外面的数量即可.\n【详解】7+2=9(个)则一共有9个。", + "knowledge_points": [ + "8,9的加减法" + ], + "source": "25-26一年级上·江西九江·期中" + }, + { + "id": "61", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "计算题", + "difficulty": 0.94, + "question": "算一算,填一填.\n![](images/Pasted%20image%2020260310210859.png)", + "options": [], + "answer": "8;4;1;3;0;10;2;8;5;4", + "solution": "【分析】从左到右依次按照运算符号进行计算即可.\n【详解】(1)5+3=8,8-4=4,4-3=1,1+2=3,3-3=0。则填空如下:![](images/Pasted%20image%2020260310210910.png)\n(2)6+4=10,10-8=2,2+6=8,8-3=5,5-1=4.\n则填空如下:![](images/Pasted%20image%2020260310210919.png)", + "knowledge_points": [ + "10的加减法", + "8,9的加减法", + "5以内数的减法" + ], + "source": "25-26一年级上·江西九江·期中" + }, + { + "id": "62", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "计算题", + "difficulty": 0.65, + "question": "画\"园\"表示下列算式的意思.\n![](images/Pasted%20image%2020260310210945.png)", + "options": [], + "answer": "7;2", + "solution": "【分析】3+4表示3和4相加,则可以先画3个○,再画4个○,然后数一数一共的个数,即为3+4的和;6-4表示从6里面减去4,则可以先画6个○,然后在6个○中圈住4个,数一数剩下的数量,即为6-4的差.\n【详解】由分析可得:![](images/Pasted%20image%2020260310211033.png)", + "knowledge_points": [ + "6的加减法", + "7的加减法" + ], + "source": "25-26一年级上·江西九江·期中" + }, + { + "id": "63", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式计算.\n![](images/Pasted%20image%2020260310211042.png)", + "options": [], + "answer": "19-4=15", + "solution": "【分析】根据图片可知:一共有19只青蛙,右边有4只,左边有几只。用共有的数量减去右边的数量即可.\n【详解】19-4=15(只)\n则左边有15只。", + "knowledge_points": [ + "不退位减法(20以内)" + ], + "source": "25-26一年级上·全国·单元测试" + }, + { + "id": "64", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "计算题", + "difficulty": 0.85, + "question": "![](images/Pasted%20image%2020260310211052.png)", + "options": [], + "answer": "3+1=5-1", + "solution": "【分析】小女孩原来有3个苹果,又摘了1个,则原来的数量+又摘的数量=现在的数量;小男孩原来有5个苹果,吃了1个苹果,则原来的数量-吃了的数量=现在的数量。现在他们苹果的数量同样多,由此可以列出等式.\n【详解】由分析得:3+1=4(个)小女孩现在有4个苹果。5-1=4(个)小男孩现在有4个苹果.\n则3+1=5-1", + "knowledge_points": [ + "5以内数的加法", + "5以内数的减法" + ], + "source": "25-26一年级上·陕西西安·月考" + }, + { + "id": "65", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式计算.\n![](images/Pasted%20image%2020260310211108.png)", + "options": [], + "answer": "8+4=12", + "solution": "【分析】根据图片可知:求一共的数量,用左边的数量加右边的数量即可.\n【详解】8+4=12(个)则一共有12个。", + "knowledge_points": [ + "8加几的进位加法" + ], + "source": "2025一年级上·全国·专题练习" + }, + { + "id": "66", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "计算题", + "difficulty": 0.85, + "question": "列算式.\n![](images/Pasted%20image%2020260310211118.png)", + "options": [], + "answer": "4;3;1", + "solution": "【分析】还剩的桃子数量=一共的数量-吃掉的数量;据此列式解决.\n【详解】由分析可知:4-3=1", + "knowledge_points": [ + "图文问题", + "5以内数的减法" + ], + "source": "25-26一年级上·广东广州·月考" + }, + { + "id": "67", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "计算题", + "difficulty": 0.85, + "question": "列算式.\n![](images/Pasted%20image%2020260310211130.png)", + "options": [], + "answer": "5;3;2", + "solution": "【分析】用一共的鱼数量减去吃掉的数量,求出差,就是还剩的数量.\n【详解】由分析可知:5-3=2", + "knowledge_points": [ + "图文问题", + "5以内数的减法" + ], + "source": "25-26一年级上·广东广州·月考" + }, + { + "id": "68", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "计算题", + "difficulty": 0.85, + "question": "列算式.\n![](images/Pasted%20image%2020260310211143.png)", + "options": [], + "answer": "2;1;3", + "solution": "【分析】一共的刺猬数量=左边的数量+右边的数量;据此列式解决.\n【详解】由分析可知:2+1=3", + "knowledge_points": [ + "图文问题", + "5以内数的加法" + ], + "source": "25-26一年级上·广东广州·月考" + }, + { + "id": "69", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "计算题", + "difficulty": 0.85, + "question": "列算式.\n![](images/Pasted%20image%2020260310211152.png)", + "options": [], + "answer": "5;4;1", + "solution": "【分析】还剩的足球数量=一共的足球数量-圈出来的足球数量;据此解决.\n【详解】由分析可知:5-4=1", + "knowledge_points": [ + "5以内数的减法" + ], + "source": "25-26一年级上·广东广州·月考" + }, + { + "id": "70", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "计算题", + "difficulty": 0.85, + "question": "列算式.\n![](images/Pasted%20image%2020260310211202.png)", + "options": [], + "answer": "3;1;4", + "solution": "【分析】一共的小鸡数量=原来的数量+又来的数量;据此列式解决.\n【详解】由分析可知:\n3+1=4", + "knowledge_points": [ + "图文问题", + "5以内数的加法" + ], + "source": "25-26一年级上·广东广州·月考" + }, + { + "id": "71", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "计算题", + "difficulty": 0.85, + "question": "列算式.\n![](images/Pasted%20image%2020260310211209.png)", + "options": [], + "answer": "2;3;5", + "solution": "【分析】一共的羽毛球数量=左边的数量+右边的数量;据此列式解决.\n【详解】由分析可知:2+3=5", + "knowledge_points": [ + "图文问题", + "5以内数的加法" + ], + "source": "25-26一年级上·广东广州·月考" + }, + { + "id": "72", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "计算题", + "difficulty": 0.94, + "question": "看图讲故事,填算式.\n![](images/Pasted%20image%2020260310211220.png)", + "options": [], + "answer": "2+2=3+1", + "solution": "【分析】根据图片可知:左边兔子原有2个胡萝卜,又拔了2个,一共有几个;右边兔子原有1个胡萝卜,又拔了3个后和左边兔子的数量同样多,则我们可以分别求出两只兔子各拔的数量,然后进行比较是否同样多。用原有的数量+又拔的数量=共拔的数量.\n【详解】2+2=4(个)3+1=4(个)4=4则2+2=3+1。", + "knowledge_points": [ + "5以内数的加法" + ], + "source": "25-26一年级上·福建莆田·月考" + }, + { + "id": "73", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "计算题", + "difficulty": 0.94, + "question": "看图列式计算.\n![](images/Pasted%20image%2020260310211236.png)", + "options": [], + "answer": "2+3=5", + "solution": "【分析】根据题意可知,左边有2只蚂蚁,右边有3只蚂蚁,合起来是5只蚂蚁,列加法算式是:2+3=5(只).\n【详解】2+3=5(只)", + "knowledge_points": [ + "5以内数的加法" + ], + "source": "25-26一年级上·陕西西安·月考" + }, + { + "id": "74", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "计算题", + "difficulty": 0.94, + "question": "看图列式计算.\n![](images/Pasted%20image%2020260310211248.png)", + "options": [], + "answer": "3;4-2=2;4-4=0", + "solution": "【分析】图1:原有4根,摘掉了1根,则原有的数量-摘掉的数量=还剩的数量;图2:原有4根,摘掉了2根,则原有的数量-摘掉的数量=还剩的数量;图3:原有4根,摘掉了4根,则原有的数量-摘掉的数量=还剩的数量.\n【详解】图1:4-1=3(根)还剩3根。图2:4-2=2(根)还剩2根。图3:4-4=0(根)还剩0根。", + "knowledge_points": [ + "图文问题", + "5以内数的减法", + "有关0的加减法" + ], + "source": "25-26一年级上·陕西西安·月考" + }, + { + "id": "75", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "计算题", + "difficulty": 0.94, + "question": "我会算.\n3+2= 5-1= 4-2= 2-1=\n3-1= 2+0= 3-3= 3-2=\n5+0= 4-1= 2+2= 5-5=", + "options": [], + "answer": "5;4;2;1;2;2;0;1;5;3;4;0", + "solution": "【分析】按5以内加减法法则逐题计算.\n【详解】3+2=5;5-1=4;4-2=2;2-1=1;3-1=2;2+0=2;3-3=0;3-2=1;5+0=5;4-1=3;2+2=4;5-5=0", + "knowledge_points": [ + "5以内数的加法", + "5以内数的减法", + "有关0的加减法" + ], + "source": "25-26一年级上·陕西西安·月考" + }, + { + "id": "76", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "计算题", + "difficulty": 0.94, + "question": "看图列式计算.\n![](images/Pasted%20image%2020260310211341.png)", + "options": [], + "answer": "3+0=3", + "solution": "【分析】左边篮子里有3个菠萝,右边篮子里没有菠萝,也就是0个,则左边的数量+右边的数量=菠萝的总数量.\n【详解】3+0=3(个)一共有3个菠萝。", + "knowledge_points": [ + "图文问题", + "有关0的加减法" + ], + "source": "25-26一年级上·陕西西安·月考" + }, + { + "id": "77", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式计算.\n![](images/Pasted%20image%2020260310211349.png)", + "options": [], + "answer": "14+3=17", + "solution": "【分析】用左边苹果的个数加上右边苹果的个数,即可求出苹果的总个数.\n【详解】14+3=17(个)一共有17个苹果。", + "knowledge_points": [ + "图文问题", + "不进位加法(20以内)" + ], + "source": "2025一年级上·全国·专题练习" + }, + { + "id": "78", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式计算.\n![](images/Pasted%20image%2020260310211356.png)", + "options": [], + "answer": "6+5=11", + "solution": "【分析】观察题图可知,左边有6支笔,右边有5支笔,求一共有多少支笔,用加法计算,左边的数量加右边的数量即可.\n【详解】根据分析可得:6+5=11(支)因此,一共有11支笔。", + "knowledge_points": [ + "图文问题", + "7,6加几的进位加法" + ], + "source": "25-26一年级上·全国·单元测试" + }, + { + "id": "79", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "连线题", + "difficulty": 0.65, + "question": "把数量同样多的物品用线连起来.\n![](images/Pasted%20image%2020260310211431.png)", + "options": [], + "answer": "见详解", + "solution": "【分析】数一数各物体的数量,然后把数量一样的进行连线即可.\n【详解】由分析可得:\n![](images/Pasted%20image%2020260310211443.png)", + "knowledge_points": [ + "比较物体多少", + "数一数" + ], + "source": "25-26一年级上·江西九江·期中" + }, + { + "id": "80", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "作图题", + "difficulty": 0.94, + "question": "画月亮,月亮比星星多.\n![](images/Pasted%20image%2020260310211509.png)", + "options": [], + "answer": "见详解", + "solution": "【分析】题中有4个星星,要画月亮比星星多,比4大的数有5,6,7。可以画5个月亮.\n【详解】由分析得:画月亮,月亮比星星多![](images/Pasted%20image%2020260310211609.png)\n(答案不唯一)", + "knowledge_points": [ + "9以内数的比大小" + ], + "source": "25-26一年级上·山西长治·月考" + }, + { + "id": "81", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "作图题", + "difficulty": 0.94, + "question": "画△,△和笑脸同样多.\n![](images/Pasted%20image%2020260310211623.png)", + "options": [], + "answer": "见详解", + "solution": "【分析】\n数出笑脸的数量,有3个笑脸。因为△和笑脸同样多,所以△有3个.\n【详解】由分析得:![](images/Pasted%20image%2020260310211640.png)", + "knowledge_points": [ + "比较物体多少", + "数一数", + "1~5的认识和读写" + ], + "source": "25-26一年级上·山西长治·月考" + }, + { + "id": "82", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "作图题", + "difficulty": 0.65, + "question": "在横线上画三角形,比苹果多.\n![](images/Pasted%20image%2020260310211827.png)", + "options": [], + "answer": "见详解", + "solution": "【分析】\n根据题意可知:先数出苹果的数量,求画三角形比苹果多,然后画三角形比苹果多1个即可.\n【详解】由分析可得:苹果:6个则画三角形如下:\n![](images/Pasted%20image%2020260310211918.png)(答案不唯一)", + "knowledge_points": [ + "数一数" + ], + "source": "25-26一年级上·江西九江·期中" + }, + { + "id": "83", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "作图题", + "difficulty": 0.85, + "question": "画出接下来的5颗珠子.\n![](images/Pasted%20image%2020260310211932.png)", + "options": [], + "answer": "见详解", + "solution": "【分析】通过观察,白珠子和黑珠子的排列规律是:1白1黑,2白1黑,3白1黑,黑珠子数量不变,白珠子每次增加1个,故接下来珠子的排列是4白1黑;据此画一画.\n【详解】由分析可得:\n![](images/Pasted%20image%2020260310211938.png)", + "knowledge_points": [ + "数一数", + "1~5的认识和读写", + "图形的变化规律" + ], + "source": "25-26一年级上·全国·周测" + }, + { + "id": "84", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "作图题", + "difficulty": 0.94, + "question": "按规律涂色.\n![](images/Pasted%20image%2020260310211948.png)", + "options": [], + "answer": "见详解", + "solution": "【分析】这组图形的颜色按照红色,蓝色为一组,重复排列,由此可知,后面应涂蓝色.\n【详解】由分析作图如下:\n![](images/Pasted%20image%2020260310213827.png)", + "knowledge_points": [ + "图形的变化规律" + ], + "source": "25-26一年级上·云南曲靖·月考" + }, + { + "id": "85", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "作图题", + "difficulty": 0.85, + "question": "涂一涂,比一比.\n![](images/Pasted%20image%2020260310212258.png)", + "options": [], + "answer": "见详解", + "solution": "【分析】数一数可知,苹果有3个;①要求梨比苹果多,4>3,5>3,则梨应该涂多与3个,则可以涂4个或5个;②要求香蕉和苹果同样多,3=3,则桃子应该涂3个;据此解答即可.\n【详解】![](images/Pasted%20image%2020260310212437.png)", + "knowledge_points": [ + "5以内数的比大小" + ], + "source": "25-26一年级上·广东广州·月考" + }, + { + "id": "86", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "作图题", + "difficulty": 0.94, + "question": "照样子涂一涂,填一填.\n![](images/Pasted%20image%2020260310212458.png)", + "options": [], + "answer": "见详解", + "solution": "【分析】5可以分成3和2,5可以分成2和3,5可以分成4和1,5可以分成1和4,据此填上数字,并根据填的数把三角形涂上即可.\n【详解】如图:\n![](images/Pasted%20image%2020260310212518.png)", + "knowledge_points": [ + "5以内数的分与合(组成)" + ], + "source": "25-26一年级上·陕西西安·月考" + }, + { + "id": "87", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.94, + "question": "有( )个小朋友打乒乓球,有( )个小朋友跳绳,有( )个小朋友踢毽子.\n![](images/Pasted%20image%2020260310212531.png)\n(1)打乒乓球和跳绳的小朋友一共有多少个。![](images/Pasted%20image%2020260310212539.png)\n(2)再来几个小朋友跳绳就和踢毽子的同样多。![](images/Pasted%20image%2020260310212542.png)", + "options": [], + "answer": "2;1;5;2+1=3;3个;5-1=4;4个", + "solution": "【分析】由图可知,打乒乓球的有2人,跳绳的有1人,踢毽子的有5人。(1)根据加法的意义,打乒乓球的人数+跳绳的人数=打乒乓球和跳绳的总人数;(2)根据减法的意义,踢毽子的人数-跳绳的人数=和踢毽子的人数同样多时,跳绳要再来的人数.\n【详解】有2个小朋友打乒乓球,有1个小朋友跳绳,有5个小朋友踢毽子。(1)2+1=3(个)\n答:打乒乓球和跳绳的小朋友一共有3个。(2)5-1=4(个)答:再来4个小朋友跳绳就和踢毽子的同样多。", + "knowledge_points": [ + "5以内数的加法", + "5以内数的减法" + ], + "source": "25-26一年级上·山西长治·月考" + }, + { + "id": "88", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "一共有多少个鸡腿。\n![](images/Pasted%20image%2020260310212609.png)", + "options": [], + "answer": "3+2=5;5个", + "solution": "【分析】由图可知,一个盘子里有3个鸡腿,另一个盘子里有2个鸡腿,则将两个盘子里鸡腿的数量相加就是总数量.\n【详解】3+2=5(个)答:一共有5个鸡腿。", + "knowledge_points": [ + "图文问题", + "5以内数的加法" + ], + "source": "25-26一年级上·山西长治·月考" + }, + { + "id": "89", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "每人一串糖葫芦,还差几串。\n![](images/Pasted%20image%2020260310212620.png)", + "options": [], + "answer": "3-2=1;1串", + "solution": "【分析】根据题意,有3个小朋友,也就是需要3串糖葫芦,现在有2串糖葫芦,则需要的数量-现在有的数量=还差的数量.\n【详解】3-2=1(串)答:还差1串。", + "knowledge_points": [ + "图文问题", + "5以内数的减法" + ], + "source": "25-26一年级上·山西长治·月考" + }, + { + "id": "90", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "一共有几个足球。\n![](images/Pasted%20image%2020260310212635.png)", + "options": [], + "answer": "2+2=4;4个", + "solution": "【分析】用小朋友脚下足球的个数加上球门里面足球的个数,即可求出一共有几个足球.\n【详解】2+2=4(个)答:一共有4个足球。", + "knowledge_points": [ + "图文问题", + "5以内数的加法" + ], + "source": "25-26一年级上·江西九江·期中" + }, + { + "id": "91", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.65, + "question": "一只乌鸦口渴了,到处找水喝。它看到了一个装水的瓶子.\n![](images/Pasted%20image%2020260310212653.png)", + "options": [], + "answer": "10颗;5+5=10", + "solution": "【分析】根据题意可知:同样多为数量一样,则求一共放进去的数量,用放进去的数量加上又放进去的数量即可.\n【详解】5+5=10(颗)答:乌鸦一共放入10颗石头。", + "knowledge_points": [ + "10的加减法" + ], + "source": "25-26一年级上·江西九江·期中" + }, + { + "id": "92", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.65, + "question": "把下图中的水果分给小朋友们,如果每人1个,还有5个小朋友没分到,一共有多少个小朋友。\n![](images/Pasted%20image%2020260310212705.png)", + "options": [], + "answer": "13个;5+3+5=13", + "solution": "【分析】根据题意可知,先求出苹果和梨一共的数量,然后再加上没有分到的小朋友的数量,即可求出一共小朋友的数量.\n【详解】5+3+5=13(个)答:一共有13个小朋友。", + "knowledge_points": [ + "连加(20以内)" + ], + "source": "2025一年级上·全国·专题练习" + }, + { + "id": "93", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "![](images/Pasted%20image%2020260310212733.png)", + "options": [], + "answer": "14只;10+4=14", + "solution": "【分析】根据题意可知:求一共兔子的数量,用胡萝卜的数量加上还差的数量即可.\n【详解】10+4=14(只)答:灵灵家一共养了14只兔子。", + "knowledge_points": [ + "不进位加法(20以内)" + ], + "source": "2025一年级上·全国·专题练习" + }, + { + "id": "94", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.65, + "question": "小兔子收了19棵白菜,送给妈妈6棵,送给弟弟3棵,还剩多少棵白菜。\n![](images/Pasted%20image%2020260310212805.png)", + "options": [], + "answer": "19-6-3=10;10棵", + "solution": "【分析】要求小白兔还剩下多少棵白菜,根据减法的意义,用小白兔收的白菜的数量减去送给妈妈和送给弟弟的棵数,即可得出答案.\n【详解】19-6-3=13-3=10(棵)\n答:还剩10棵白菜。", + "knowledge_points": [ + "不进位,不退位连加,连减(20以内)" + ], + "source": "25-26一年级上·全国·单元测试" + }, + { + "id": "95", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "17只蚂蚁去觅食.\n![](images/Pasted%20image%2020260310212831.png)\n蚂蚁灰灰后面还有多少只蚂蚁。\n![](images/Pasted%20image%2020260310212839.png)", + "options": [], + "answer": "17-5=12;12只", + "solution": "【分析】用蚂蚁的总数量(17只)减去灰灰的排序(排在第5),求出差,就是蚂蚁灰灰后面还有多少只蚂蚁.\n【详解】17-5=12(只)答:蚂蚁灰灰后面还有12只蚂蚁。", + "knowledge_points": [ + "不退位减法(20以内)" + ], + "source": "25-26一年级上·全国·单元测试" + }, + { + "id": "96", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.65, + "question": "天天的书缺少了多少页。\n![](images/Pasted%20image%2020260310212854.png)", + "options": [], + "answer": "18-10+1=9;9页", + "solution": "【分析】用结束页18减去开始页10,再加上第10页这一页,因为第10页还是存在的,即可求出天天的书缺少了几页.\n【详解】18-10+1=8+1=9(页)\n答:天天的书缺少了9页。", + "knowledge_points": [ + "图文问题", + "加减混合运算(20以内)" + ], + "source": "2025一年级上·全国·专题练习" + }, + { + "id": "97", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "同学们站成一队做操,小明的前面有10人,后面有6人,这一队共有多少人。\n![](images/Pasted%20image%2020260310212910.png)", + "options": [], + "answer": "10+6+1=17", + "solution": "【分析】小明前面有10人,后面有6人,小明前面的人数加上他后面的人数,再加上小明,即可求出这一队共有多少人.\n【详解】10+6+1=16+1=17(人)\n答:这一队共有17人。", + "knowledge_points": [ + "不进位,不退位连加,连减(20以内)" + ], + "source": "2025一年级上·全国·专题练习" + }, + { + "id": "98", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.65, + "question": "![](images/Pasted%20image%2020260310212920.png)\n(1)画图思考:请在上图中用○画出拿走的表格.\n(2)原来有多少块饼干。\n![](images/Pasted%20image%2020260310212939.png)", + "options": [], + "answer": "![](images/Pasted%20image%2020260310212950.png);6+8=14", + "solution": "【分析】(1)在原有饼干图中,用○画出6块拿走的饼干;(2)用已知拿走的饼干数加上剩下的饼干数,即可求出原来有多少块饼干.\n【详解】\n(1)![](images/Pasted%20image%2020260310212954.png)(2)6+8=14(块)\n答:原来有14块饼干。", + "knowledge_points": [ + "图文问题", + "7,6加几的进位加法" + ], + "source": "25-26一年级上·全国·单元测试" + }, + { + "id": "99", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "有14位家长参加家长会,每人坐一把椅子,还差多少把。\n![](images/Pasted%20image%2020260310213003.png)", + "options": [], + "answer": "14-4=10;10把", + "solution": "【分析】已知14位家长需要14把椅子,现在已经有4把,要求还差多少把,根据减法的意义,用14-4进行解答即可.\n【详解】14-4=10(把)答:还差10把。", + "knowledge_points": [ + "图文问题", + "不退位减法(20以内)" + ], + "source": "25-26一年级上·全国·单元测试" + }, + { + "id": "100", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "小刚有9支铅笔,小红的铅笔支数和小刚的同样多,他们一共有多少支铅笔。\n![](images/Pasted%20image%2020260310213018.png)", + "options": [], + "answer": "9+9=18", + "solution": "【分析】小刚有9支铅笔,小红的铅笔支数和小刚同样多,所以小红也有9支铅笔。将他们的铅笔支数相加,即可求出他们一共有多少支铅笔.\n【详解】9+9=18(支)答:他们一共有18支铅笔。", + "knowledge_points": [ + "\"一样多\"问题", + "9加几的进位加法" + ], + "source": "25-26一年级上·全国·单元测试" + }, + { + "id": "101", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.94, + "question": "小朋友的数量可以用下面图( )表示.\n\n![](images/Pasted%20image%2020260310214405.png)", + "options": [ + "A. ![](images/Pasted%20image%2020260310214413.png)", + "B. ![](images/Pasted%20image%2020260310214419.png)", + "C. ![](images/Pasted%20image%2020260310214426.png)" + ], + "answer": "B", + "solution": "【分析】根据题意,有几个小朋友就要画几个○,由此数出小朋友的人数和○的数量,比较即可.\n【详解】有5个小朋友;A。有4个○,4<5,不符合题意;B。有5个○,5=5,符合题意;C。有3个○,3<5,不符合题意。则小朋友的数量可以用![](images/Pasted%20image%2020260310214419.png)来表示。故答案为:B", + "knowledge_points": [ + "5以内数的比大小", + "数一数" + ], + "source": "25-26一年级上·河北邢台·月考" + }, + { + "id": "102", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "在计算4+1=□时,下面的想法中,错误的是( )。", + "options": [ + "A. ![](images/Pasted%20image%2020260310214441.png)", + "B. 4后面接着数1个数", + "C. ![](images/Pasted%20image%2020260310214448.png)" + ], + "answer": "C", + "solution": "【分析】4+1表示4和1的和,也可以表示在4的基础上又多了1个,由此分析即可.\n【详解】A。表示4和1合起来就是5,可以用4+1来计算;B。4后面接着数1个数就是在4的基础上又多了1个,可以用4+1来计算;C。表示5可以分成3和2,可以用5-3来计算。则错误的是C。故答案为:C", + "knowledge_points": [ + "5以内数的加法", + "5以内数的减法", + "5以内数的分与合(组成)" + ], + "source": "25-26一年级上·河北邢台·月考" + }, + { + "id": "103", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.94, + "question": "4-![](images/Pasted%20image%2020260310214622.png)>1,![](images/Pasted%20image%2020260310214625.png)中不可以填( )。", + "options": [ + "A. 1", + "B. 2", + "C. 3" + ], + "answer": "C", + "solution": "【分析】根据题意,依次将各数代入到算式中,计算出结果和1比较大小即可,5以内数从大到小关系为5>4>3>2>1,由此比较.\n【详解】A。4-1=3;3>1,可以填1;B。4-2=2;2>1,可以填2;C。4-3=1;1=1,不可以填3。则4-![](images/Pasted%20image%2020260310214725.png)>1,![](images/Pasted%20image%2020260310214727.png)中不可以填3。故答案为:C", + "knowledge_points": [ + "5以内数的比大小", + "5以内数的减法" + ], + "source": "25-26一年级上·陕西西安·阶段练习" + }, + { + "id": "104", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.94, + "question": "比1大比4小的数是( )。", + "options": [ + "A. 5", + "B. 1", + "C. 2" + ], + "answer": "C", + "solution": "【分析】求比1大比4小的数,也就是求在1和4之间的数,根据5以内数排序,0,1,2,3,4,5,即可解答.\n【详解】由分析可得:比1大比4小的数是2,3。故答案为:C", + "knowledge_points": [ + "5以内数的排序" + ], + "source": "25-26一年级上·福建莆田·阶段练习" + }, + { + "id": "105", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.94, + "question": "如图,每只小兔吃一根萝卜,选哪一堆萝卜正合适。( )\n\n![](images/Pasted%20image%2020260310214803.png)", + "options": [ + "A. ![](images/Pasted%20image%2020260310214809.png)", + "B. ![](images/Pasted%20image%2020260310214815.png)", + "C. ![](images/Pasted%20image%2020260310214820.png)" + ], + "answer": "B", + "solution": "【分析】根据题意可知:先数一数兔子的数量,然后再数一数各选项中胡萝卜的数量,选择和兔子数量一样的即可.\n【详解】兔子:5只A。![](images/Pasted%20image%2020260310214840.png)3个,5>3,则不符合题意。B。![](images/Pasted%20image%2020260310214834.png)5个,5=5,符合题意。C。![](images/Pasted%20image%2020260310214827.png)2个,5>2,不符合题意。故答案为:B", + "knowledge_points": [ + "5以内数的比大小", + "比较物体多少", + "数一数" + ], + "source": "25-26一年级上·福建莆田·阶段练习" + }, + { + "id": "106", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "下面选项中,正确的是( )。", + "options": [ + "A. 4<5", + "B. 2=3", + "C. 0>1" + ], + "answer": "A", + "solution": "【分析】5以内数大小关系为5>4>3>2>1>0;0<1<2<3<4<5,由此比较解答.\n【详解】A。4<5,原结果正确;B。2<3,原结果错误;C。0<1,原结果错误。则正确的是4<5。故答案为:A", + "knowledge_points": [ + "0的认识和读写", + "5以内数的比大小" + ], + "source": "25-26一年级上·陕西咸阳·阶段练习" + }, + { + "id": "107", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.94, + "question": "下面能表示下图含义的是( )\n\n![](images/Pasted%20image%2020260310214918.png)", + "options": [ + "A. 4-1=3(只)", + "B. 3+1=4(只)", + "C. 3-1=2(只)" + ], + "answer": "A", + "solution": "【分析】根据题图可知,荷叶上有4只青蛙,离开了1只,还剩下多少只青蛙,用减法计算,荷叶上原有青蛙的只数减去离开的只数,即可解答.\n【详解】根据分析可得:4-1=3(只)荷叶上还剩下3只青蛙。下图含义是4-1=3(只)\n![](images/Pasted%20image%2020260310214931.png)故答案为:A", + "knowledge_points": [ + "5以内数的减法", + "图文问题" + ], + "source": "25-26一年级上·河南周口·阶段练习" + }, + { + "id": "108", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.94, + "question": "![](images/Pasted%20image%2020260310214941.png)把这些蛋糕分给两个孩子,他们分到的能同样多吗。( )", + "options": [ + "A. 能", + "B. 不能", + "C. 无法确定" + ], + "answer": "A", + "solution": "【分析】可以用分一分的方法,在分蛋糕的时候,使得两个孩子分的蛋糕一样多,如果两个孩子分的蛋糕不一样多,则把这些蛋糕分给两个孩子,他们分到的不能同样多.\n【详解】一共有4个蛋糕,要分给两个孩子。我们可以一个一个地分,先给第一个孩子1个,再给第二个孩子1个;接着再给第一个孩子1个,再给第二个孩子1个。这样分完后,每个孩子都有2个蛋糕,所以他们分到的能同样多。故答案为:A", + "knowledge_points": [ + "1~5的认识和读写", + "图文问题" + ], + "source": "25-26一年级上·青海果洛·阶段练习" + }, + { + "id": "109", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "下面算式( )能正确表达图片内容.\n\n![](images/Pasted%20image%2020260310214951.png)", + "options": [ + "A. 4-1", + "B. 4+1", + "C. 5-1" + ], + "answer": "C", + "solution": "【分析】根据题图,原有5个苹果,吃了1个,求还剩几个苹果;用苹果的总个数减去吃的个数,就是还剩下苹果的个数,据此解答.\n【详解】由分析可得:5-1能正确表达图片内容。故答案为:C", + "knowledge_points": [ + "5以内数的加法", + "5以内数的减法", + "图文问题" + ], + "source": "25-26一年级上·青海果洛·阶段练习" + }, + { + "id": "110", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.94, + "question": "图中每人吃一根香蕉,下面刚好合适的一堆是( ).\n\n![](images/Pasted%20image%2020260310215117.png)", + "options": [ + "A. ![](images/Pasted%20image%2020260310215134.png)", + "B. ![](images/Pasted%20image%2020260310215147.png)", + "C. ![](images/Pasted%20image%2020260310215154.png)", + "D. ![](images/Pasted%20image%2020260310215200.png)" + ], + "answer": "C", + "solution": "【分析】根据题意,数一数图中的人数,香蕉个数和人数一致的,即是刚好合适的一堆;据此解答.\n【详解】由分析可得:图中共有4人,下面刚好合适的一堆是![](images/Pasted%20image%2020260310215206.png).\n\n故答案为:C", + "knowledge_points": [ + "5以内数的比大小", + "数一数" + ], + "source": "25-26一年级上·广东东莞·阶段练习" + }, + { + "id": "111", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "从右边数,把第3个圈起来,下面圈法正确的是( )。", + "options": [ + "A. ![](images/Pasted%20image%2020260310215227.png)", + "B. ![](images/Pasted%20image%2020260310215233.png)", + "C. ![](images/Pasted%20image%2020260310215238.png)" + ], + "answer": "C", + "solution": "【分析】一般情况下,写字的手是右手也就是右边,不写字的手是左手也就是左边。从右边数的第3个,只圈这一个,由此解答.\n【详解】A。圈起来的是从右边数的3个,不符合题意;B。圈起来的是从右边数的第4个,不符合题意;C。圈起来的是从右边数的第3个,符合题意。则圈法正确的是![](images/Pasted%20image%2020260310215243.png).\n\n故答案为:C", + "knowledge_points": [ + "认识几和第几", + "左,右位置" + ], + "source": "25-26一年级上·陕西西安·阶段练习" + }, + { + "id": "112", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.94, + "question": "数一数,图中一共有( )个玉米.\n\n![](images/Pasted%20image%2020260310215255.png)", + "options": [ + "A. 2", + "B. 3", + "C. 4" + ], + "answer": "B", + "solution": "【分析】先数一数图片中玉米的数量,有3个玉米,再对应选项去选择.\n【详解】数一数,图片中玉米的数量是3个。故答案为:B", + "knowledge_points": [ + "1~5的认识和读写", + "数一数" + ], + "source": "25-26一年级上·陕西西安·阶段练习" + }, + { + "id": "113", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "东东和3个小朋友去游乐场,他们要买( )张票。", + "options": [ + "A. 3", + "B. 4", + "C. 5" + ], + "answer": "B", + "solution": "【分析】根据题意,有几人就需要买几张票,则总人数=东东+另外3个小朋友,由此解答.\n【详解】1+3=4(人)则他们要买4张票。故答案为:B", + "knowledge_points": [ + "5以内数的加法" + ], + "source": "25-26一年级上·河北邢台·阶段练习" + }, + { + "id": "114", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.94, + "question": "□<4,□里不可以填( )。", + "options": [ + "A. 3", + "B. 2", + "C. 5" + ], + "answer": "C", + "solution": "【分析】5以内数从小到大关系为1<2<3<4<5,由此比较即可解答.\n【详解】A。3<4,可以填3;B。2<4,可以填2;C。5>4,不可以填5;则□<4,□里不可以填5。故答案为:C", + "knowledge_points": [ + "5以内数的比大小" + ], + "source": "25-26一年级上·河北邢台·阶段练习" + }, + { + "id": "115", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.94, + "question": "![](images/Pasted%20image%2020260310215401.png)", + "options": [], + "answer": "5;4;3;5>4;4>3", + "solution": "【分析】依次数出每种动物的数量再比较大小,5以内数从大到小关系为5>4>3>2>1,由此比较.\n【详解】由分析得:5只鸡,4只鸟,3只狗。5只鸡>4只鸟,4只鸟>3只狗。", + "knowledge_points": [ + "5以内数的比大小", + "数一数" + ], + "source": "25-26一年级上·新疆省直辖县级单位·月考" + }, + { + "id": "116", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.94, + "question": "填一填。![](images/Pasted%20image%2020260310215511.png)", + "options": [], + "answer": "2;4;3;3;4;2;5;1", + "solution": "【分析】第一组:用左侧的各数与1相加,得出的结果填写在对应的方框内;第二组:用5减去右侧的各数,得出的结果填写在对应的方框内.\n【详解】1+1=2;2+1=3;3+1=4;4+1=5;5-1=4;5-2=3;5-3=2;5-4=1\n\n![](images/Pasted%20image%2020260310215534.png)", + "knowledge_points": [ + "5以内数的加法", + "5以内数的减法" + ], + "source": "25-26一年级上·新疆省直辖县级单位·月考" + }, + { + "id": "117", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.94, + "question": "看图写数。![](images/Pasted%20image%2020260310215541.png)", + "options": [], + "answer": "4;0;5;2", + "solution": "【分析】依次数出每组物体的数量,填写对应的数字即可。图1:有4个南瓜;图2:什么都没有,也就是0;图3:有5个碗;图4:有2只小鸡.\n【详解】填写如下:\n\n![](images/Pasted%20image%2020260310215558.png)", + "knowledge_points": [ + "0的认识和读写", + "1~5的认识和读写", + "数一数" + ], + "source": "25-26一年级上·新疆省直辖县级单位·月考" + }, + { + "id": "118", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.94, + "question": "照样子,填一填.\n\n![](images/Pasted%20image%2020260310215607.png)", + "options": [], + "answer": "5;4;4;2;5;2;4;5;2;4;2;5", + "solution": "【分析】5以内数大小关系为:5>4>3>2>1;1<2<3<4<5,由此填写即可.\n【详解】由分析填写如下:\n\n![](images/Pasted%20image%2020260310215618.png)", + "knowledge_points": [ + "5以内数的比大小" + ], + "source": "25-26一年级上·河北邢台·月考" + }, + { + "id": "119", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.94, + "question": "分一分.\n\n![](images/Pasted%20image%2020260310215624.png)", + "options": [], + "answer": "4;2;5;2", + "solution": "【分析】根据题意,5可以分成1和4,4可以分成2和2,3和2可以合成5,3可以分成1和2,据此填空.\n【详解】\n根据分析:![](images/Pasted%20image%2020260310215632.png)", + "knowledge_points": [ + "5以内数的分与合(组成)" + ], + "source": "25-26一年级上·新疆省直辖县级单位·月考" + }, + { + "id": "120", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.94, + "question": "看图写数.\n\n![](images/Pasted%20image%2020260310215638.png)", + "options": [], + "answer": "5;4;1;3", + "solution": "【分析】根据题意,分别数一数各物体有多少,把数字填入相对应的方格中即可.\n【详解】\n\n![](images/Pasted%20image%2020260310215644.png)", + "knowledge_points": [ + "1~5的认识和读写", + "数一数" + ], + "source": "25-26一年级上·山东济宁·月考" + }, + { + "id": "121", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "在□里填数字.\n\n![](images/Pasted%20image%2020260310215650.png)", + "options": [], + "answer": "3;4;3;1;1", + "solution": "【分析】由数的分与合可知:4可以分成1和3,2和2合成4,5可以分成3和2,2可以分成1和1,5可以分成1和4,据此填空即可.\n【详解】由分析填写如下:\n\n![](images/Pasted%20image%2020260310215657.png)", + "knowledge_points": [ + "5以内数的分与合(组成)" + ], + "source": "25-26一年级上·河北邢台·月考" + }, + { + "id": "122", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "算一算.\n\n![](images/Pasted%20image%2020260310215704.png)", + "options": [], + "answer": "见详解", + "solution": "【分析】本题根据数的分与合填写即可.\n第1题:3可以分成2和1;5可以分成3和2;1和3合起来就是4;第2题:5可以分成4和1;4可以分成1和3;5可以分成3和2;3可以分成2和1;2可以分成1和1.\n【详解】填写如下:\n\n![](images/Pasted%20image%2020260310215722.png)", + "knowledge_points": [ + "5以内数的分与合(组成)" + ], + "source": "25-26一年级上·河北邯郸·月考" + }, + { + "id": "123", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.94, + "question": "数一数,写一写.\n\n![](images/Pasted%20image%2020260310215730.png)", + "options": [], + "answer": "5;3;2;0", + "solution": "【分析】依次数出每组的数量,将对应的数字写在下面的格子中即可。图1:有5个梨;图2:有3个梨;图3:有2个梨;图4:什么都没有,也就是0.\n【详解】填写如下:![](images/Pasted%20image%2020260310215744.png)", + "knowledge_points": [ + "0的认识和读写", + "1~5的认识和读写", + "数一数" + ], + "source": "25-26一年级上·山东菏泽·月考" + }, + { + "id": "124", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "看图填空.\n\n![](images/Pasted%20image%2020260310215758.png)\n\n(1)一共有( )个水果.\n\n(2)从左边数,苹果排在第( ).\n\n(3)从右边数,香蕉排在第( ),梨排在第( ).\n\n(4)如果小明把香蕉吃掉了,还剩( )个水果。这时,从右边数,( )排在第1。", + "options": [], + "answer": "5;3;1;4;4;西瓜", + "solution": "【分析】(1)数一数可知,一共有5个水果;(2)一般情况下,写字的手是右手也就是右边,不写字的手是左手也就是左边。从左也就是从桃子开始数,桃子排第1,梨排第2,苹果排第3,西瓜排第4,香蕉排第5;(3)从右也就是从香蕉开始数,香蕉排第1,西瓜排第2,苹果排第3,梨排第4,桃子排第5;(4)小明把香蕉吃掉了,也就是吃了1个水果,则水果的总数量-吃掉的数量=还剩的数量;此时从右边数,第1个是西瓜.\n【详解】(1)一共有5个水果。(2)从左边数,苹果排在第3。(3)从右边数,香蕉排在第1,梨排在第4。(4)5-1=4(个)如果小明把香蕉吃掉了,还剩4个水果。这时,从右边数,西瓜排在第1。", + "knowledge_points": [ + "认识几和第几", + "左,右位置", + "5以内数的减法" + ], + "source": "25-26一年级上·山东菏泽·月考" + }, + { + "id": "125", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "![](images/Pasted%20image%2020260310215904.png)\n\n(1)一共有( )只动物.\n\n(2)从左往右数,猴子排第( );从右往左数,猴子排第( ).\n\n(3)羊的前面有( )只动物,后面有( )只动物.\n\n(4)圈出大象后面所有的动物,并在它后面第2只动物的上面画○。", + "options": [], + "answer": "5;4;2;1;3;见详解", + "solution": "【分析】(1)按照顺序数一数,即可得出一共有5只动物;(2)分清楚左右,找到猴子的位置可知,从左往右数,猴子排第4;从右往左数,猴子排第2;(3)分清楚前后,找到山羊的位置可知,山羊前面有1只动物,后面有3只动物;(4)找到大象的位置,并结合题干要求,圈出它后面的所有动物,它后面的第2只动物是乌龟,并在乌龟上面画上○即可.\n【详解】(1)一共有5只动物。(2)从左往右数,猴子排第4;从右往左数,猴子排第2\n(3)羊的前面有1只动物,后面有3只动物。(4)圈出大象后面所有的动物,并在它后面第2只动物的上面画○,如下图:\n\n![](images/Pasted%20image%2020260310220007.png)", + "knowledge_points": [ + "认识几和第几", + "左,右位置", + "数一数", + "前,后位置" + ], + "source": "25-26一年级上·广东广州·月考" + }, + { + "id": "126", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.94, + "question": "比一比,在括号里填上\">\"\"<\"或\"=\".\n\n5( )4\n3( )2\n1( )2", + "options": [], + "answer": ">;>;<", + "solution": "【分析】5以内数大小关系为:5>4>3>2>1;1<2<3<4<5,由此比较.\n【详解】由分析得:5>4;3>2;1<2", + "knowledge_points": [ + "5以内数的比大小" + ], + "source": "25-26一年级上·广东广州·阶段练习" + }, + { + "id": "127", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "在( )里填上\">\"或\"<\".\n\n5( )3\n3( )4\n1( )2\n4( )2", + "options": [], + "answer": ">;<;<;>", + "solution": "【分析】5以内数大小关系为5>4>3>2>1;1<2<3<4<5,由此比较.\n【详解】由分析得:5>3;3<4;1<2;4>2", + "knowledge_points": [ + "5以内数的比大小" + ], + "source": "25-26一年级上·山西长治·阶段练习" + }, + { + "id": "128", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.94, + "question": "梨+苹果=5,苹果+苹果=4,梨=( ),苹果=( )。", + "options": [], + "answer": "3;2", + "solution": "【分析】根据苹果+苹果=4可知:2+2=4,则苹果=2,把苹果的数值代入梨+苹果=5中,然后根据加数=和-另一个加数即可求出梨的数值.\n【详解】由分析可得:苹果+苹果=4,2+2=4,则苹果=2。把苹果=2代入梨+苹果=5中,则梨+2=5,则梨=5-2=3,即梨=3。则梨+苹果=5,苹果+苹果=4,梨=(3),苹果=(2)。", + "knowledge_points": [ + "5以内数的加法", + "5以内数的减法" + ], + "source": "25-26一年级上·福建莆田·阶段练习" + }, + { + "id": "129", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.94, + "question": "与4相邻的两个数是( )和( )。", + "options": [], + "answer": "3;5", + "solution": "【分析】5以内数从小到大顺序为:1,2,3,4,5,与4相邻的数是它前一个数和它后一个数,由此解答.\n【详解】由分析得:与4相邻的两个数是3和5。", + "knowledge_points": [ + "5以内数的排序" + ], + "source": "25-26一年级上·江西九江·期中" + }, + { + "id": "130", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.94, + "question": "在方框填上合适的数.\n\n![](images/Pasted%20image%2020260310220236.png)", + "options": [], + "answer": "1;4;1", + "solution": "【分析】根据5以内数的分合即可解答.\n2可以分成1和1;3和1可以合成4;3可以分成2和1.\n【详解】由分析可得:\n\n![](images/Pasted%20image%2020260310220243.png)", + "knowledge_points": [ + "5以内数的分与合(组成)" + ], + "source": "25-26一年级上·福建莆田·阶段练习" + }, + { + "id": "131", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.94, + "question": "看图写数.\n\n![](images/Pasted%20image%2020260310220248.png)", + "options": [], + "answer": "1;5;3;4;0", + "solution": "【分析】分别数一数各物体的数量,一个物体也没有用\"0\"表示,然后填写在相对应的空格里.\n【详解】由分析可得:\n\n![](images/Pasted%20image%2020260310220254.png)", + "knowledge_points": [ + "1~5的认识和读写" + ], + "source": "25-26一年级上·福建莆田·阶段练习" + }, + { + "id": "132", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.94, + "question": "![](images/Pasted%20image%2020260310220300.png)\n\n(1)照片中一共有( )个人.\n\n(2)从左边数,![](images/Pasted%20image%2020260310220313.png)排第( ),![](images/Pasted%20image%2020260310220319.png)排第( ).\n\n(3)从右边数,![](images/Pasted%20image%2020260310220326.png)排第4。(圈一圈)", + "options": [], + "answer": "5;2;5;见详解", + "solution": "【分析】由题意可知:(1)数一数即可知照片中一共有的人数;(2)从左边数,![](images/Pasted%20image%2020260310220313.png)排第( 2 ),![](images/Pasted%20image%2020260310220319.png)排第( 5 )。(3)从右往左数,排第4的是![](images/Pasted%20image%2020260310220437.png)。据此解答.\n【详解】由分析可得:\n(1)照片中一共有5个人。(2)从左边数,![](images/Pasted%20image%2020260310220313.png)排第( 2 ),![](images/Pasted%20image%2020260310220319.png)排第( 5 ).\n(3)从右边数,(![](images/Pasted%20image%2020260310220455.png))排第4。", + "knowledge_points": [ + "认识几和第几", + "左,右位置", + "1~5的认识和读写", + "数一数" + ], + "source": "25-26一年级上·陕西延安·阶段练习" + }, + { + "id": "133", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.94, + "question": "分与合.\n\n![](images/Pasted%20image%2020260310220512.png)", + "options": [], + "answer": "3;1;5;2;1", + "solution": "【分析】根据数的分与合:4能分成1和3,2能分成1和1,2和3组成5,3能分成1和2,5能分成1和4;据此填数.\n【详解】由分析可得:\n\n![](images/Pasted%20image%2020260310220519.png)", + "knowledge_points": [ + "5以内数的分与合(组成)" + ], + "source": "25-26一年级上·陕西延安·阶段练习" + }, + { + "id": "134", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.94, + "question": "给小动物们编上序号.\n\n![](images/Pasted%20image%2020260310220525.png)", + "options": [], + "answer": "1;2;4;5", + "solution": "【分析】根据图片结合日常可知,日常数数从左数起。然后一个一个数即可.\n【详解】由分析可得:\n\n![](images/Pasted%20image%2020260310220545.png)", + "knowledge_points": [ + "5以内数的排序" + ], + "source": "25-26一年级上·河南周口·阶段练习" + }, + { + "id": "135", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.94, + "question": "盘子里各有几个桃子,写一写.\n\n![](images/Pasted%20image%2020260310220557.png)", + "options": [], + "answer": "见详解", + "solution": "【分析】从左到右,依次数一数盘子里有几个桃子,数出的数填在下面的方格里.\n【详解】从左到右,第一个盘子有2个桃子;第二个盘子有4个桃子;第三个盘子有1个桃子;第四个盘子有3个桃子;第五个盘子有5个桃子.\n\n![](images/Pasted%20image%2020260310220609.png)", + "knowledge_points": [ + "1~5的认识和读写", + "图文问题" + ], + "source": "25-26一年级上·河北邢台·阶段练习" + }, + { + "id": "136", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.65, + "question": "看图写数.\n\n![](images/Pasted%20image%2020260310220620.png)", + "options": [], + "answer": "3;5;4;2", + "solution": "【分析】分别数一数各物体的数量,填写在相对应的田字格中.\n【详解】由分析可得:\n\n![](images/Pasted%20image%2020260310220632.png)", + "knowledge_points": [ + "1~5的认识和读写" + ], + "source": "25-26一年级上·河南周口·阶段练习" + }, + { + "id": "137", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.94, + "question": "分一分,合一合.\n\n![](images/Pasted%20image%2020260310220638.png)", + "options": [], + "answer": "3;4;2;3;4", + "solution": "【分析】根据数的分与合完成填空即可,5可以分成2和3,2和2合成4,3可以分成1和2,4可以分成1和3,5可以分成1和4.\n【详解】根据分析可得:\n\n![](images/Pasted%20image%2020260310220646.png)", + "knowledge_points": [ + "5以内数的分与合(组成)" + ], + "source": "25-26一年级上·河南周口·阶段练习" + }, + { + "id": "138", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "![](images/Pasted%20image%2020260310220723.png)\n\n猫比鱼多( ),鱼比猫少( )。", + "options": [], + "answer": "1;1", + "solution": "【分析】比较两种物体的多或少时,可以用一一对应的方法。当两种物体一一对应后,其中一种物体有剩余,有剩余的那种物体多,没有剩余的那种物体少。剩余的数量即谁比谁多的数量或者谁比谁少的数量.\n【详解】由分析可得:\n猫比鱼多( 1 ),鱼比猫少( 1 )。", + "knowledge_points": [ + "5以内数的比大小", + "比较物体多少" + ], + "source": "25-26一年级上·河南周口·阶段练习" + }, + { + "id": "139", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.65, + "question": "每只兔子吃一根萝卜,哪一堆萝卜正合适。画\"√\".\n\n![](images/Pasted%20image%2020260310220844.png)", + "options": [], + "answer": "见详解", + "solution": "【分析】数量正合适,也就是数量相等。由此数出兔子的只数和萝卜的数量比较即可。由图可知,有3只兔子,第一堆有5根萝卜,第二堆有3根萝卜。兔子的只数等于萝卜的数量,即3=3,据此解答.\n【详解】根据分析:3=3<5\n\n![](images/Pasted%20image%2020260310220911.png)", + "knowledge_points": [ + "5以内数的比大小", + "比较物体多少", + "数一数" + ], + "source": "25-26一年级上·河北邢台·阶段练习" + }, + { + "id": "140", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "遮住的是第( )个和第( )个雪人,遮住了( )个,一共有( )个雪人.\n\n![](images/Pasted%20image%2020260310220918.png)", + "options": [], + "answer": "2;3;2;5", + "solution": "【分析】由图可知:从第1个到第5个依次为:第1个,第2个,第3个,第4个,第5个,一共有5个,遮住的是第2个和第3个,由此解答.\n【详解】遮住的是第2个和第3个雪人,遮住了2个,一共有5个雪人。", + "knowledge_points": [ + "认识几和第几", + "图文问题", + "数一数" + ], + "source": "25-26一年级上·河北邢台·阶段练习" + }, + { + "id": "141", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.94, + "question": "按顺序填一填.\n\n(1)![](images/Pasted%20image%2020260310220925.png)\n\n(2)![](images/Pasted%20image%2020260310220931.png)", + "options": [], + "answer": "4;3;1;0;2;4", + "solution": "【分析】(1)按照5以内数的倒序填写,依次为5,4,3,2,1;(2)按照5以内数的正序填写,依次为0,1,2,3,4,5.\n【详解】(1)![](images/Pasted%20image%2020260310220940.png)\n\n(2)![](images/Pasted%20image%2020260310220947.png)", + "knowledge_points": [ + "5以内数的排序", + "0的认识和读写" + ], + "source": "25-26一年级上·广东东莞·阶段练习" + }, + { + "id": "142", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.94, + "question": "写数.\n\n![](images/Pasted%20image%2020260310220952.png)", + "options": [], + "answer": "4;3;1;5;2", + "solution": "【分析】依次数出各物品的数量,然后将数量写在对应的田字格内即可.\n【详解】图1:有4个桃子;图2:有3只蜜蜂;图3:有1个西瓜;图4:有5根香蕉;图5:有2只瓢虫.\n\n![](images/Pasted%20image%2020260310221017.png)", + "knowledge_points": [ + "1~5的认识和读写", + "数一数" + ], + "source": "25-26一年级上·广东东莞·阶段练习" + }, + { + "id": "143", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "照样子,数一数,写一写.\n\n![](images/Pasted%20image%2020260310221023.png)", + "options": [], + "answer": "5;3;2;4", + "solution": "【分析】分别数一数各物品的个数,然后把数量填写在对应的格子中即可.\n【详解】数一数可知,依次有:1个;5个;3个;2个;4个.\n\n![](images/Pasted%20image%2020260310221030.png)", + "knowledge_points": [ + "1~5的认识和读写", + "数一数" + ], + "source": "25-26一年级上·广东东莞·阶段练习" + }, + { + "id": "144", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.94, + "question": "每只兔子吃1根胡萝卜,哪一堆正合适。画\"√\".\n\n![](images/Pasted%20image%2020260310221038.png)", + "options": [], + "answer": "见详解", + "solution": "【分析】根据题意,数量正合适,也就是数量相等。由此数出小兔的只数和胡萝卜的数量比较即可.\n【详解】数一数可知,有4只小兔,第一堆有3根胡萝卜,第二堆有4根胡萝卜,第三堆有5根胡萝卜。3<4=4<5\n填写如下:![](images/Pasted%20image%2020260310221056.png)", + "knowledge_points": [ + "1~5的认识和读写", + "5以内数的比大小", + "图文问题", + "数一数" + ], + "source": "25-26一年级上·广东东莞·阶段练习" + }, + { + "id": "145", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "鸡蛋能放得下吗。\n\n![](images/Pasted%20image%2020260310221108.png)", + "options": [], + "answer": "4<5;不能", + "solution": "【分析】由图数出蛋托和鸡蛋的数量比较大小,若蛋托的数量大于或等于鸡蛋的数量放得下,小于则放不下.\n【详解】数一数可知:蛋托有4个;鸡蛋有5个;4<5,则不能放下.\n\n![](images/Pasted%20image%2020260310221117.png)", + "knowledge_points": [ + "5以内数的比大小", + "数一数" + ], + "source": "25-26一年级上·广东东莞·阶段练习" + }, + { + "id": "146", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.94, + "question": "数一数,写一写.\n\n![](images/Pasted%20image%2020260310221128.png)", + "options": [], + "answer": "1;3;5;4;2", + "solution": "【分析】由题意可知:分别数一数各图形,把数字填到下面相应的日子格中;据此解答.\n【详解】由分析可得:\n图1:1个;图2:3个;图3:5个;图4:4个;图5:2个;![](images/Pasted%20image%2020260310221342.png)", + "knowledge_points": [ + "1~5的认识和读写", + "数一数" + ], + "source": "25-26一年级上·甘肃张掖·阶段练习" + }, + { + "id": "147", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "![](images/Pasted%20image%2020260310221348.png)\n\n(1)从左边数,马排第( );从右边数,马排第( ).\n\n(2)狗的前面有( )只动物,后面有( )只动物.\n\n(3)从右边数,圈出第3只动物。", + "options": [], + "answer": "4;2;1;3;见详解", + "solution": "【分析】(1)一般情况下,写字的手是右手也就是右边,不写字的手是左手也就是左边。从左也就是从小刺猬开始数,小刺猬排第1,小狗排第2,小羊排第3,小马排第4,犀牛排第5;(2)面为前,尾巴对的位置为后。狗的前面是小刺猬,后面是小羊,小马和犀牛;(3)从右也就是从犀牛开始数,第3只是小羊,圈起来即可.\n【详解】\n(1)从左边数,马排第4;从右边数,马排第2。(2)狗的前面有1只动物,后面有3只动物。(3)从右边数,圈出第3只动物.\n\n![](images/Pasted%20image%2020260310221432.png)", + "knowledge_points": [ + "认识几和第几", + "左,右位置", + "前,后位置" + ], + "source": "25-26一年级上·甘肃张掖·阶段练习" + }, + { + "id": "148", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.65, + "question": "分与合.\n\n![](images/Pasted%20image%2020260310221453.png)", + "options": [], + "answer": "1;3;2;4;4", + "solution": "【分析】根据数的分与合:2能分成1和1,2和1组成3,5能分成3和2,3和1组成4,2和2组成4;据此解答.\n【详解】由分析可得:\n\n![](images/Pasted%20image%2020260310221500.png)", + "knowledge_points": [ + "5以内数的分与合(组成)" + ], + "source": "25-26一年级上·甘肃张掖·阶段练习" + }, + { + "id": "149", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.65, + "question": "先数一数,再认真写一写.\n\n![](images/Pasted%20image%2020260310221535.png)", + "options": [], + "answer": "2;4;3;5", + "solution": "【分析】根据图片信息内容,分别数出物体数量,对应填入数字即可.\n【详解】先对应数一数,再填写数字.\n\n![](images/Pasted%20image%2020260310221541.png)", + "knowledge_points": [ + "1~5的认识和读写", + "数一数" + ], + "source": "25-26一年级上·陕西西安·阶段练习" + }, + { + "id": "150", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "看图填空.\n\n![](images/Pasted%20image%2020260310221547.png)\n\n(1)一共有( )只猫.\n\n(2)![](images/Pasted%20image%2020260310221552.png)是从右边数的第( )只.\n\n(3)把右边的3只猫圈出来.\n\n(4)从左边数的第2只猫跑走了,还剩( )只猫。", + "options": [], + "answer": "5;2;见详解;4", + "solution": "【分析】(1)数一数可知,一共有5只猫;(2)一般情况下写字的手是右手也就是右边,不写字的手是左手也就是左边,从右开始数,![](images/Pasted%20image%2020260310221620.png)是第2只;(3)右边的3只是![](images/Pasted%20image%2020260310221641.png),圈起来即可;(4)从左边数的第2只猫跑走了,也就是跑了1只,则用总数量-跑了的数量=还剩的数量.\n【详解】(1)一共有5只猫。(2)是从右边数的第2只。(3)把右边的3只猫圈出来.\n\n![](images/Pasted%20image%2020260310221648.png)(4)5-1=4(只)从左边数的第2只猫跑走了,还剩4只猫。", + "knowledge_points": [ + "认识几和第几", + "左,右位置", + "5以内数的减法" + ], + "source": "25-26一年级上·广东东莞·阶段练习" + }, + { + "id": "151", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "看图在框里填数.\n\n![](images/Pasted%20image%2020260310221702.png)", + "options": [], + "answer": "见详解", + "solution": "【分析】依次数出每种物品的数量,再根据数的分与合填写即可。图1:分别有2颗糖果,1颗糖果,一共有3颗糖果,即2和1合起来就是3;图2:分别有3个草莓,1个草莓,一共有4个草莓,即3和1合起来就是4;图3:分别有2只蝴蝶,3只蝴蝶,一共有5只蝴蝶,即2和3合起来就是5.\n【详解】填写如下:\n\n![](images/Pasted%20image%2020260310221715.png)", + "knowledge_points": [ + "5以内数的分与合(组成)" + ], + "source": "25-26一年级上·陕西西安·阶段练习" + }, + { + "id": "152", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "2+2=( ),读作( )加( )等于( );4-1=( ),读作( )减( )等于( )。", + "options": [], + "answer": "4;2;2;4;3;4;1;3", + "solution": "【分析】根据题意,熟练掌握5以内的加减法,正确的读出加减法的算式。在加法算式中\"+\"是加号,读作加。在减法算式中\"-\"是减号,读作减.\"=\"是等于号,读作等于,按照算式中各数的位置依次读出。据此解答.\n【详解】根据分析:2+2=(4),读作(2)加(2)等于(4);4-1=(3),读作(4)减(1)等于(3)。", + "knowledge_points": [ + "5以内数的加法", + "5以内数的减法" + ], + "source": "25-26一年级上·河南周口·阶段练习" + }, + { + "id": "153", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.94, + "question": "分一分,合一合.\n\n![](images/Pasted%20image%2020260310221737.png)", + "options": [], + "answer": "5;3;3;2", + "solution": "【分析】根据5以内整数的合与分,结合题干要求进行解答即可。2和3可以合成5;4可以分成1和3;5可以分成2和3;4可以分成2和2.\n【详解】![](images/Pasted%20image%2020260310221754.png)", + "knowledge_points": [ + "5以内数的分与合(组成)" + ], + "source": "25-26一年级上·辽宁鞍山·阶段练习" + }, + { + "id": "154", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "数一数,写一写.\n\n![](images/Pasted%20image%2020260310221803.png)", + "options": [], + "answer": "4;3;2;1;5;0", + "solution": "【分析】依次数出每组物品的数量,写出对应的数字即可。图1:有4块西瓜;图2:有3个包子;图3:有2颗草莓;图4:有1个菠萝;图5:有5个桃子;图6:什么都没有,也就是0.\n【详解】填写如下:\n\n![](images/Pasted%20image%2020260310221817.png)", + "knowledge_points": [ + "0的认识和读写", + "1~5的认识和读写", + "数一数" + ], + "source": "25-26一年级上·河北邢台·阶段练习" + }, + { + "id": "155", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.94, + "question": "写出一个比3大的数是 。", + "options": [], + "answer": "4", + "solution": "【分析】5以内数从大到小关系为5>4>3>2>1,比3大的数,可填写4.\n【详解】由分析得:写出一个比3大的数是4。(答案不唯一)", + "knowledge_points": [ + "5以内数的比大小" + ], + "source": "25-26一年级上·河北邢台·阶段练习" + }, + { + "id": "156", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.94, + "question": "2+2=( ),读作( )加( )等于( )。", + "options": [], + "answer": "4;2;2;4", + "solution": "【分析】计算可知,结果是4,加法算式从左往右读,数字不变,\"+\"读作加,\"=\"读作等于.\n【详解】2+2=4,读作2加2等于4。", + "knowledge_points": [ + "5以内数的加法" + ], + "source": "25-26一年级上·河北邢台·阶段练习" + }, + { + "id": "157", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.94, + "question": "羊圈里只有一只羊,用数字 ()表示。", + "options": [], + "answer": "1", + "solution": "【分析】题目描述羊圈里有一只羊,根据对数的认识,数量\"一\"对应的数字是1,由此解答.\n【详解】由分析得:\n羊圈里只有一只羊,用数字1表示。", + "knowledge_points": [ + "1~5的认识和读写" + ], + "source": "25-26一年级上·河北邢台·阶段练习" + }, + { + "id": "158", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "计算题", + "difficulty": 0.94, + "question": "看图列算式.\n\n![](images/Pasted%20image%2020260310221908.png)", + "options": [], + "answer": "4-3=1", + "solution": "【分析】由图可知,有4条鱼,小猫吃掉3条,用原来有的数量减去小猫吃掉的数量,即可求出还剩几条,用减法列式计算.\n【详解】4-3=1(条)还剩1条。", + "knowledge_points": [ + "5以内数的减法", + "图文问题" + ], + "source": "25-26一年级上·新疆省直辖县级单位·月考" + }, + { + "id": "159", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "计算题", + "difficulty": 0.94, + "question": "看图列算式.\n\n![](images/Pasted%20image%2020260310221916.png)", + "options": [], + "answer": "3-3=0(个)", + "solution": "【分析】由图可知,原来有3个气球,飞走3个,用原来的数量减去飞走的数量,即可求出现在还剩几个。用减法列式计算.\n【详解】3-3=0(个)现在还剩0个。", + "knowledge_points": [ + "图文问题", + "有关0的加减法" + ], + "source": "25-26一年级上·新疆省直辖县级单位·月考" + }, + { + "id": "160", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "计算题", + "difficulty": 0.94, + "question": "看图列算式.\n\n![](images/Pasted%20image%2020260310221929.png)", + "options": [], + "answer": "4+1=5(个)", + "solution": "【分析】由图可知,有4个人在踢足球,又来1个人,用原来的数量加上又来的数量,即可求出现在的人数,用加法列式计算.\n【详解】4+1=5(个)现在有5个。", + "knowledge_points": [ + "5以内数的加法", + "图文问题" + ], + "source": "25-26一年级上·新疆省直辖县级单位·月考" + }, + { + "id": "161", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "计算题", + "difficulty": 0.94, + "question": "看图列算式.\n\n![](images/Pasted%20image%2020260310221938.png)", + "options": [], + "answer": "4-2=2", + "solution": "【分析】共有4只青蛙,左边有2只,右边有2只。则总数量-一边的数量=另一边的数量.\n【详解】由分析得:4-2=2(只)", + "knowledge_points": [ + "5以内数的减法", + "图文问题" + ], + "source": "25-26一年级上·新疆省直辖县级单位·月考" + }, + { + "id": "162", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "计算题", + "difficulty": 0.65, + "question": "看图列算式.\n\n![](images/Pasted%20image%2020260310221950.png)", + "options": [], + "answer": "5-3=2", + "solution": "【分析】根据图片信息,一共有5棵白菜,去掉了3棵,可以求出剩下有几棵。用全部的数量减去去掉的数量,列式计算即可.\n【详解】5-3=2还剩下2棵。", + "knowledge_points": [ + "5以内数的减法", + "图文问题" + ], + "source": "25-26一年级上·新疆省直辖县级单位·月考" + }, + { + "id": "163", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "计算题", + "difficulty": 0.94, + "question": "看图列算式.\n\n![](images/Pasted%20image%2020260310222000.png)", + "options": [], + "answer": "2+2=4", + "solution": "【分析】桌子上原有2个瓶子,狐狸又拿来了2个,则原有的数量+又拿来的数量=现在的数量.\n【详解】2+2=4(个)现在有4个瓶子。", + "knowledge_points": [ + "5以内数的加法", + "图文问题" + ], + "source": "25-26一年级上·新疆省直辖县级单位·月考" + }, + { + "id": "164", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "计算题", + "difficulty": 0.94, + "question": "看图列算式.\n\n![](images/Pasted%20image%2020260310222011.png)", + "options": [], + "answer": "5-1=4(个)", + "solution": "【分析】由图可知,一共有5个鸡腿,小狗叼走1个,用总的数量减去叼走的数量,即可求出还剩几个,用减法列式计算.\n【详解】5-1=4(个)还剩4个。", + "knowledge_points": [ + "5以内数的减法", + "图文问题" + ], + "source": "25-26一年级上·新疆省直辖县级单位·月考" + }, + { + "id": "165", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "计算题", + "difficulty": 0.94, + "question": "看图列式.\n\n![](images/Pasted%20image%2020260310222021.png)", + "options": [], + "answer": "4-3=1", + "solution": "【分析】由图可知,一共有4个桃子,右边有3个,求左边有几个,用减法计算,即总数量-右边的数量=左边的数量.\n【详解】4-3=1(个)\n左边有1个桃子。", + "knowledge_points": [ + "5以内数的减法" + ], + "source": "25-26一年级上·山东济宁·月考" + }, + { + "id": "166", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "计算题", + "difficulty": 0.94, + "question": "看图列式计算.\n\n![](images/Pasted%20image%2020260310222027.png)", + "options": [], + "answer": "3+1=4", + "solution": "【分析】原有3人在玩跳绳,又来了1人,则原来的人数+又来的人数=现在的人数.\n【详解】3+1=4(人)现在有4人。", + "knowledge_points": [ + "5以内数的加法" + ], + "source": "25-26一年级上·河北邢台·月考" + }, + { + "id": "167", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "计算题", + "difficulty": 0.94, + "question": "看图列式.\n\n![](images/Pasted%20image%2020260310222037.png)", + "options": [], + "answer": "4+1=5", + "solution": "【分析】左边有4个萝卜,右边有1个萝卜,则左边的数量+右边的数量=萝卜的总数量.\n【详解】4+1=5(个)一共有5个萝卜。", + "knowledge_points": [ + "5以内数的加法" + ], + "source": "25-26一年级上·山东济宁·月考" + }, + { + "id": "168", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "计算题", + "difficulty": 0.94, + "question": "看图列式.\n\n![](images/Pasted%20image%2020260310222045.png)", + "options": [], + "answer": "5-2=3", + "solution": "【分析】一共有5个,外边有2个,求盒子里有几个,用减法计算,即总数量-外边的数量=盒子里的数量.\n【详解】5-2=3(个)盒子里有3个。", + "knowledge_points": [ + "5以内数的减法" + ], + "source": "25-26一年级上·山东济宁·月考" + }, + { + "id": "169", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "计算题", + "difficulty": 0.94, + "question": "照样子画一画,算一算.\n\n![](images/Pasted%20image%2020260310222056.png)", + "options": [], + "answer": "见详解;4;5", + "solution": "【分析】根据题图,2+1=3,图和算式相对应,左边画了2个△,右边画了1个△,一共画了3个△,也就是结果是3;图2:3+1,左边画3个△,右边画1个△,一共画了几个△结果就是几;图3:2+3,左边画2个△,右边画3个△,一共画了几个△结果就是几.\n【详解】由分析得:![](images/Pasted%20image%2020260310222157.png)", + "knowledge_points": [ + "5以内数的加法" + ], + "source": "25-26一年级上·河北邢台·月考" + }, + { + "id": "170", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "计算题", + "difficulty": 0.94, + "question": "看图列式计算.\n\n![](images/Pasted%20image%2020260310222221.png)", + "options": [], + "answer": "2+2=4", + "solution": "【分析】左边有2台风扇,右边有2台风扇,则左边的数量+右边的数量=总数量.\n【详解】2+2=4(台)一共有4台风扇。", + "knowledge_points": [ + "5以内数的加法" + ], + "source": "25-26一年级上·河北邢台·月考" + }, + { + "id": "171", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "计算题", + "difficulty": 0.94, + "question": "列式计算.\n\n我们一起玩吧!\n![](images/Pasted%20image%2020260310222231.png)", + "options": [], + "answer": "1+2=3", + "solution": "【分析】左边有1只小鹿,右边有2只小鹿,则左边的数量+右边的数量=总数量.\n【详解】1+2=3(只)一共有3只小鹿。", + "knowledge_points": [ + "5以内数的加法" + ], + "source": "25-26一年级上·山东菏泽·月考" + }, + { + "id": "172", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "计算题", + "difficulty": 0.94, + "question": "看图列式。![](images/Pasted%20image%2020260310222241.png)", + "options": [], + "answer": "5-2=3", + "solution": "【分析】根据图片可知:一共有5支,左边有2支,右边文具盒中有几支。用共有的数量减去左边的数量即可.\n【详解】5-2=3(支)\n\n则文具盒中有3支。", + "knowledge_points": [ + "5以内数的减法" + ], + "source": "25-26一年级上·福建莆田·阶段练习" + }, + { + "id": "173", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "计算题", + "difficulty": 0.94, + "question": "看图列式。![](images/Pasted%20image%2020260310222249.png)", + "options": [], + "answer": "3+0=3", + "solution": "【分析】根据图片可知:左边盘子中3个桃子,右边盘子中0个桃子,一共多少个桃子。用左边的数量加右边的数量即可.\n【详解】3+0=3(个)一共3个桃子。", + "knowledge_points": [ + "有关0的加减法" + ], + "source": "25-26一年级上·福建莆田·阶段练习" + }, + { + "id": "174", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "计算题", + "difficulty": 0.94, + "question": "看图列式计算。![](images/Pasted%20image%2020260310222257.png)", + "options": [], + "answer": "2+3=5", + "solution": "【分析】根据题图可知,左边有2条小鱼,右边有3条小鱼,求一共有几条小鱼,用加法计算,左边小鱼的数量加右边小鱼的数量,即可解答.\n【详解】根据分析可得:2+3=5(条)因此,一共有5条小鱼。", + "knowledge_points": [ + "5以内数的加法", + "图文问题" + ], + "source": "25-26一年级上·山西忻州·期中" + }, + { + "id": "175", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "计算题", + "difficulty": 0.94, + "question": "看图列式计算。![](images/Pasted%20image%2020260310222308.png)", + "options": [], + "answer": "3+2=5(个)", + "solution": "【分析】左边有3个苹果,右边有2个苹果,将两边的苹果数量相加,即可求出一共有多少个苹果.\n【详解】3+2=5(个)\n\n因此一共有5个苹果。", + "knowledge_points": [ + "5以内数的加法", + "图文问题" + ], + "source": "25-26一年级上·河南周口·阶段练习" + }, + { + "id": "176", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式计算.\n\n![](images/Pasted%20image%2020260310222315.png)", + "options": [], + "answer": "2+1=3", + "solution": "【分析】根据图片可知:左边有2只熊猫,右边有1只熊猫,一共多少只。用左边的数量加上右边的数量即可.\n【详解】2+1=3(只)则一共有3只。", + "knowledge_points": [ + "5以内数的加法" + ], + "source": "25-26一年级上·河南周口·阶段练习" + }, + { + "id": "177", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "计算题", + "difficulty": 0.94, + "question": "看图填算式,再说一说算式表示的意思.\n\n![](images/Pasted%20image%2020260310222323.png)", + "options": [], + "answer": "5-2=3", + "solution": "【分析】从图中可知,原来有5个苹果,去掉2个,还剩下3个苹果,用减法计算.\n【详解】5-2=3(个)因此还剩下3个苹果。", + "knowledge_points": [ + "5以内数的减法", + "图文问题" + ], + "source": "25-26一年级上·广东东莞·阶段练习" + }, + { + "id": "178", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "计算题", + "difficulty": 0.94, + "question": "看图列式计算。![](images/Pasted%20image%2020260310222335.png)", + "options": [], + "answer": "2-2=0", + "solution": "【分析】由题图可知:原来有2条鱼,猫吃了2条,求现在还有几条,用原来鱼的条数减去吃了的即可;据此解答.\n【详解】由分析可得:2-2=0(条)现在还有0条。", + "knowledge_points": [ + "图文问题", + "有关0的加减法" + ], + "source": "25-26一年级上·甘肃张掖·阶段练习" + }, + { + "id": "179", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "计算题", + "difficulty": 0.94, + "question": "看图列式计算。![](images/Pasted%20image%2020260310222346.png)", + "options": [], + "answer": "1+3=4", + "solution": "【分析】由题图可知:左边有1只猫,右边有3只,求一共有多少只,把左右两边猫的只数相加即可;据此解答.\n【详解】由分析可得:1+3=4(只)一共有4只。", + "knowledge_points": [ + "5以内数的加法", + "图文问题" + ], + "source": "25-26一年级上·甘肃张掖·阶段练习" + }, + { + "id": "180", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "计算题", + "difficulty": 0.94, + "question": "看图列式计算.\n\n![](images/Pasted%20image%2020260310222358.png)\n\n5-( )=( )", + "options": [], + "answer": "2;3", + "solution": "【分析】从图上可得:原先有5只蜜蜂,有虚线圈起来2只,则表示蜜蜂数量减少2,要求还剩多少只蜜蜂,根据减法的意义,用5-2进行解答即可.\n【详解】5-2=3(只)还剩3只蜜蜂。", + "knowledge_points": [ + "5以内数的减法", + "图文问题" + ], + "source": "25-26一年级上·辽宁鞍山·阶段练习" + }, + { + "id": "181", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "作图题", + "difficulty": 0.94, + "question": "把得数是5的苹果圈起来.\n\n![](images/Pasted%20image%2020260310222414.png)", + "options": [], + "answer": "见详解", + "solution": "【分析】根据题意,依次计算出各算式的结果,再把得数是5的圈起来即可.\n【详解】4+1=5;1+2=3;3+2=5;2+1=3;1+3=4;2+2=4;2+3=5;1+1=2\n\n![](images/Pasted%20image%2020260310222420.png)", + "knowledge_points": [ + "5以内数的加法" + ], + "source": "25-26一年级上·河北邢台·月考" + }, + { + "id": "182", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "作图题", + "difficulty": 0.85, + "question": "看图圈一圈.\n\n![](images/Pasted%20image%2020260310222426.png)\n\n(1)老师站在丽丽的( )边,丽丽用( )手敲鼓.\n\n(2)丽丽的后面有( )个小朋友,圈出丽丽后面的第2个小朋友。", + "options": [], + "answer": "右;左;3;见详解", + "solution": "【分析】(1)一般情况下,写字的手是右手也就是右边,不写字的手是左手也就是左边。由此可知,老师在丽丽右边,丽丽用左手敲鼓;(2)面为前,背为后。数一数可知,丽丽后面有3个小朋友,丽丽后面的第2个小朋友是![](images/Pasted%20image%2020260310222439.png),圈出来即可.\n【详解】\n(1)老师站在丽丽的右边,丽丽用左手敲鼓。(2)丽丽的后面有3个小朋友,圈出丽丽后面的第2个小朋友.\n\n![](images/Pasted%20image%2020260310222513.png)", + "knowledge_points": [ + "认识几和第几", + "左,右位置", + "前,后位置" + ], + "source": "25-26一年级上·广东东莞·阶段练习" + }, + { + "id": "183", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.94, + "question": "舞狮常在重大活动中表演,象征着喜庆和吉祥.\n\n![](images/Pasted%20image%2020260310222537.png)\n\n(1)卡车遮住了( )只狮子.\n\n(2)这5只狮子每只配一个绣球,准备下面这些绣球够吗。在正确答案后面的□里画\"√\".\n\n![](images/Pasted%20image%2020260310222548.png)", + "options": [], + "answer": "2;不够;见详解", + "solution": "【分析】根据题意,能看见的是狮子有3只,一共有5只,可用总数减去看见的,即可得出卡车遮挡了几只;数一数绣球一共有4个,而狮子一共有5只,且每只狮子都要配一个绣球,绣球的数量小于狮子的数量,所以不够.\n【详解】(1)5-3=2(只)答:卡车遮住了2只狮子。(2)4<5,5只狮子每只配一个绣球,4个绣球不够。答:不够√。", + "knowledge_points": [ + "比较物体多少", + "5以内数的减法", + "数一数" + ], + "source": "25-26一年级上·河北邢台·月考" + }, + { + "id": "184", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "张老师用火柴棒搭成了一个算式5-2=2。当然这个算式是错的,请聪明的你移动一根火柴棒使算式成立.\n\n![](images/Pasted%20image%2020260310222603.png)", + "options": [], + "answer": "5-3=2或5-2=3", + "solution": "【分析】根据题意,可以如图中这样移动![](images/Pasted%20image%2020260310222610.png),算式是5-3=2。或者如图中这样移动![](images/Pasted%20image%2020260310222616.png),算式是5-2=3。据此解答.\n【详解】根据分析:\n![](images/Pasted%20image%2020260310222638.png)可以按照图中标出的方法移动一根火柴,使算式成立,5-3=2或者5-2=3。", + "knowledge_points": [ + "移动火柴棒", + "5以内数的减法" + ], + "source": "25-26一年级上·全国·周测" + }, + { + "id": "185", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.65, + "question": "三个同样的杯子中各放入一些同样大小的石子,想一想没有放石子之前,哪个杯子里的水最少。\n\n![](images/Pasted%20image%2020260310222646.png)", + "options": [], + "answer": "3号杯子", + "solution": "【分析】三个同样的杯子中各放入一些同样大小的石子,1号杯子里放入了2个石子,2号杯子里放入了2个石子,3号杯子里放入了3个石子;放石子后1号杯子水最多,2号和3号杯子水一样多;但3号杯子里石子数量大于2号杯子,所以,在没有放石子之前,3号杯子里的水最少.\n【详解】1号杯子和2号杯子里的石子一样多,拿掉石子后,1号杯子里的水多。2号杯子和3号杯子现在的水面一样高,但3号杯子里石子多,所以3号杯子里的水最少。答:3号杯子里的水最少。", + "knowledge_points": [ + "比较液体多少" + ], + "source": "25-26一年级上·辽宁·周测" + }, + { + "id": "186", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "绕口令\"。树上掉下小桃子,桃子打着小猴子,猴子吃掉小桃子.\"\n\n![](images/Pasted%20image%2020260310222655.png)\n\n(1)从右边数,第4个盘子里有( )个桃子.\n\n(2)从左边数,第4个盘子里有( )个桃子.\n\n(3)小猴要吃4个桃子,哪两盘的桃子合起来正好4个。(用算式表示)\n\n![](images/Pasted%20image%2020260310222703.png)", + "options": [], + "answer": "3;4;1+3=4;第1盘和第2盘", + "solution": "【分析】(1)一般情况下,写字的手是右手,即右边,不写字的手是左手,即左边。从右边数,第1盘有5个;第2盘有4个;第3盘有2个;第4盘有3个;第5盘有1个;(2)从左边数,第1盘有1个;第2盘有3个;第3盘有2个;第4盘有4个;第5盘有5个;(3)1和3合起来就是4,用加法计算即可.\n【详解】(1)从右边数,第4个盘子里有3个桃子。(2)从左边数,第4个盘子里有4个桃子。(3)1+3=4(个)答:从左边数的第1盘和第2盘的桃子合起来正好4个。", + "knowledge_points": [ + "认识几和第几", + "左,右位置", + "5以内数的加法" + ], + "source": "25-26一年级上·河北邯郸·月考" + }, + { + "id": "187", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.94, + "question": "树上有5只小鸟,飞走了2只。树上还剩几只小鸟。\n\n列式计算:\n\n答:树上还剩( )只小鸟。", + "options": [], + "answer": "5-2=3(只);3;3只", + "solution": "【分析】根据减法的意义,树上原有小鸟的数量-飞走的数量=还剩的数量.\n【详解】列式计算:5-2=3(只)答:树上还剩3只小鸟。", + "knowledge_points": [ + "5以内数的减法" + ], + "source": "25-26一年级上·云南曲靖·阶段练习" + }, + { + "id": "188", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "小朋友们排成一排,从左往右数,小明排在第4个;从右往左数,他排在第2个,那么这一排一共有( )个小朋友。试着画一画吧!", + "options": [], + "answer": "5个", + "solution": "【分析】一般情况下写字的手的一边是右边,和右相对的就是左边;分清楚左边,然后用画⚪代替,则从左数一个一个数着画,画4个⚪,把第4个⚪给涂色,表示小明,则分清楚右边,从右数,一个一个数,数到涂红色的⚪是2,然后数一数这一列有多少个⚪,即有多少个小朋友.\n【详解】由分析画图如下:\n\n![](images/Pasted%20image%2020260310222735.png)\n\n则一共有5个小朋友。", + "knowledge_points": [ + "认识几和第几", + "左,右位置" + ], + "source": "25-26一年级上·福建莆田·阶段练习" + }, + { + "id": "189", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.94, + "question": "一共有5个草莓,吃了1个,还剩几个。\n\n![](images/Pasted%20image%2020260310222741.png)", + "options": [], + "answer": "5-1=4;4个", + "solution": "【分析】根据题意可知,草莓的总数量减去吃的数量,等于还剩下的数量,据此解答.\n【详解】根据分析可得:\n\n5-1=4(个)\n\n答:还剩下4个草莓。", + "knowledge_points": [ + "5以内数的减法" + ], + "source": "25-26一年级上·山西忻州·期中" + }, + { + "id": "190", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.94, + "question": "凤冠是我国古代的一种饰物。小云购买了下面一盒凤冠冰箱贴,一共有()个。送给小雪,小风,小兰各一个,送出去()个,还剩下()个。![](images/Pasted%20image%2020260310222801.png)", + "options": [], + "answer": "3;3;0;3-3=0", + "solution": "【分析】由题意可知:数一数即可知凤冠冰箱贴的个数;送给小雪,小风,小兰这3个人各一个,共送出去了3个,用共有的凤冠冰箱贴的个数减去送出去的个数,即是还剩的个数;据此解答.\n【详解】由分析可得:凤冠是我国古代的一种饰物。小云购买了下面一盒凤冠冰箱贴,一共有3个。送给小雪,小风,小兰各一个,送出去3个,还剩下0个。3-3=0(个)答:还剩下0个。", + "knowledge_points": [ + "图文问题", + "有关0的加减法", + "数一数" + ], + "source": "25-26一年级上·陕西延安·阶段练习" + }, + { + "id": "191", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "有()个小朋友,有()本书,每个小朋友发1本,还差()本。![](images/Pasted%20image%2020260310222834.png)", + "options": [], + "answer": "5;3;2;5-3=2", + "solution": "【分析】数一数即可知小朋友的个数和本子数,用小朋友的个数减去本子数,即是还差的本数;据此解答.\n【详解】由分析可得:有5个小朋友,有3本书,每个小朋友发1本,还差2本。5-3=2(本)答:还差2本。", + "knowledge_points": [ + "5以内数的减法", + "图文问题", + "数一数" + ], + "source": "25-26一年级上·河南周口·阶段练习" + }, + { + "id": "192", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.94, + "question": "按要求做题.\n\n![](images/Pasted%20image%2020260310222853.png)\n\n(1)一共有( )只小猫.\n\n(2)把左边的3只小猫圈起来.\n\n(3)从右边数,给第2只小猫涂上颜色。", + "options": [], + "answer": "5;见详解;见详解", + "solution": "【分析】(1)一个一个地数一数,最后数到几,就有几只小猫。(2)一般情况下,写字的是右手,右手那边是右边,则另一边是左边,从左边数,数出3只小猫,把数出来的小猫圈起来。(3)从右边数,一个一个地数,数到第2只小猫,给它涂上颜色即可.\n【详解】(1)一共有5只小猫。(2)把左边的3只小猫圈起来。如图:\n\n![](images/Pasted%20image%2020260310222913.png)\n\n(3)从右边数,给第2只小猫涂上颜色。如图:\n\n![](images/Pasted%20image%2020260310222927.png)", + "knowledge_points": [ + "认识几和第几", + "左,右位置", + "1~5的认识和读写", + "数一数" + ], + "source": "25-26一年级上·河南周口·阶段练习" + }, + { + "id": "193", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.94, + "question": "糖画:以勺为笔,以糖为墨的人间甜味.\n\n![](images/Pasted%20image%2020260310222937.png)\n\n王爷爷再做( )个,就和刘爷爷的同样多.\n\n用算式表示:![](images/Pasted%20image%2020260310222943.png)", + "options": [], + "answer": "2;4-2=2;2个", + "solution": "【分析】由图可知,刘爷爷做了4个,王爷爷做了2个,王爷爷要想和刘爷爷的同样多,也就是要做4个,则用要做的数量-已经做的数量=还要做的数量.\n【详解】由分析得:王爷爷再做2个,就和刘爷爷的同样多。用算式表示:4-2=2(个)答:王爷爷再做2个,就和刘爷爷的同样多。", + "knowledge_points": [ + "\"一样多\"问题", + "5以内数的减法", + "图文问题" + ], + "source": "25-26一年级上·广东东莞·阶段练习" + }, + { + "id": "194", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.94, + "question": "看图填算式,再说一说算式表示的意思。![](images/Pasted%20image%2020260310223000.png)", + "options": [], + "answer": "4-1=3;树上原来有4只小鸟减去飞走的1只,还剩下3只小鸟。", + "solution": "【分析】根据题图可知,树上原来有4只小鸟,飞走了1只,求还剩下几只小鸟,用减法计算,树上原来小鸟的数量减去飞走的数量,即可解答.\n【详解】根据分析可得:4-1=3(只)\n算式表示的意思:树上原来有4只小鸟减去飞走的1只,还剩下3只小鸟。", + "knowledge_points": [ + "5以内数的减法", + "图文问题" + ], + "source": "25-26一年级上·广东东莞·阶段练习" + }, + { + "id": "195", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.65, + "question": "看图填算式,再说一说算式表示的意思。![](images/Pasted%20image%2020260310223016.png)", + "options": [], + "answer": "3+1=4;见详解", + "solution": "【分析】根据题图可知,原来有3辆车,又开来了1辆,求现在一共有多少辆车,用原来车的数量加上又开来车的数量即可.\n【详解】根据分析可得:3+1=4(辆)\n算式的意思是:原来有3辆车加上又开来的1辆,现在一共有4辆车。", + "knowledge_points": [ + "5以内数的加法", + "图文问题" + ], + "source": "25-26一年级上·广东东莞·阶段练习" + }, + { + "id": "196", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.94, + "question": "根据图中的数学故事,把算式补充完整。![](images/Pasted%20image%2020260310223026.png)", + "options": [], + "answer": "4-2=2;2个", + "solution": "【分析】根据题意,用风车的总数量-拿走的数量=还剩的数量.\n【详解】4-2=2(个)答:还剩2个。", + "knowledge_points": [ + "5以内数的减法", + "图文问题" + ], + "source": "25-26一年级上·广东东莞·阶段练习" + }, + { + "id": "197", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.65, + "question": "根据图中的数学故事,把算式补充完整。![](images/Pasted%20image%2020260310223035.png)", + "options": [], + "answer": "4+1=5;5人", + "solution": "【分析】根据题意,原有4人读书,又来了1人,则原来的人数+又来的人数=现在的人数.\n【详解】4+1=5(人)答:一共有5人。", + "knowledge_points": [ + "5以内数的加法", + "图文问题" + ], + "source": "25-26一年级上·广东东莞·阶段练习" + }, + { + "id": "198", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.65, + "question": "3只熊猫在吃竹子,2只熊猫在玩皮球,一共有几只熊猫。![](images/Pasted%20image%2020260310223045.png)", + "options": [], + "answer": "3+2=5;5只", + "solution": "【分析】由题意可知:把在吃竹子的熊猫和玩皮球的熊猫只数相加,即是一共有熊猫的只数;据此解答.\n【详解】由分析可得:3+2=5(只)答:一共有5只熊猫。", + "knowledge_points": [ + "5以内数的加法" + ], + "source": "25-26一年级上·甘肃张掖·阶段练习" + }, + { + "id": "199", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "乐乐和红红去掰向日葵,两人有同样多的向日葵需要掰,下面是他们掰了一些后剩下的向日葵.\n\n![](images/Pasted%20image%2020260310223058.png)\n\n(1)在掰得多的小朋友下面的框里画\"√\".\n\n(2)红红再掰几棵向日葵就和乐乐掰掉的一样多了。(用算式表示)\n![](images/Pasted%20image%2020260310223108.png)", + "options": [], + "answer": "见详解;3-2=1;1棵", + "solution": "【分析】(1)因为两人原本要掰的向日葵同样多,剩下的越少,掰掉的就越多。红红剩下3棵,乐乐剩下2棵,所以乐乐掰得多,在乐乐下面的□里画\"√\".\n(2)红红剩下3棵,乐乐剩下2棵,乐乐掰掉的比红红多3-2=1棵,所以红红再掰1棵向日葵就和乐乐掰掉的一样多了.\n【详解】(1)由分析得:\n\n![](images/Pasted%20image%2020260310223120.png)(2)3-2=1(棵)\n答:红红再掰1棵向日葵就和乐乐掰掉的一样多了。", + "knowledge_points": [ + "\"一样多\"问题", + "5以内数的减法", + "图文问题" + ], + "source": "25-26一年级上·青海果洛·阶段练习" + }, + { + "id": "200", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.94, + "question": "![](images/Pasted%20image%2020260310223137.png)\n\n荷叶上还剩下多少只青蛙。![](images/Pasted%20image%2020260310223144.png)", + "options": [], + "answer": "5-2=3;3只", + "solution": "【分析】用青蛙的总只数减去跳离荷叶的青蛙只数,即可求出荷叶上还剩下多少只青蛙.\n【详解】5-2=3(只)\n答:荷叶上还剩下3只青蛙。", + "knowledge_points": [ + "5以内数的减法", + "图文问题" + ], + "source": "25-26一年级上·青海果洛·阶段练习" + }, + { + "id": "201", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.94, + "question": "![](images/Pasted%20image%2020260310223943.png)\n如果从左边数的第2只小鸟飞走了,还剩下( )只小鸟。", + "options": [ + "A. 1", + "B. 2", + "C. 3" + ], + "answer": "C", + "solution": "【分析】数一数可知,共有4只小鸟,从左边数的第2只小鸟飞走了,就是飞走了1只小鸟;根据题图,用小鸟的总只数减去飞走小鸟的只数,即可求出还剩下几只小鸟.\n【详解】4-1=3(只)如果从左边数的第2只小鸟飞走了,还剩下3只小鸟。故答案为:C", + "knowledge_points": [ + "5以内数的减法" + ], + "source": "24-25 一年级上·河南驻马店·期中" + }, + { + "id": "202", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "鱼缸里一条鱼也没有,用数字(    )表示。", + "options": [ + "A. 0", + "B. 1", + "C. 10" + ], + "answer": "A", + "solution": "【分析】根据题意,鱼缸里一条鱼也没有,用数字表示就是\"0\",数字\"0\"表示\"没有\"的意思,据此解答.\n【详解】根据分析可得:鱼缸里一条鱼也没有,用数字0表示。故答案为:A", + "knowledge_points": [ + "0的认识和读写" + ], + "source": "24-25 一年级上·陕西延安·期中" + }, + { + "id": "203", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "一个盒里有2支笔,另一个盒里没有笔,两个盒里共有几支笔。算式(    )。", + "options": [ + "A. 2+2=4", + "B. 2+0=2", + "C. 4-2=2" + ], + "answer": "B", + "solution": "【分析】另一个盒里没有笔,用\"0\"表示。把两个盒里笔的支数加起来,即可求出两个盒里共有几支笔,据此列式选择即可.\n【详解】由分析得:2+0=2(支)求两个盒里共有几支笔,列式为2+0=2。故答案为:B", + "knowledge_points": [ + "有关0的加减法", + "0的认识和读写" + ], + "source": "24-25 一年级上·河南驻马店·期中" + }, + { + "id": "204", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.94, + "question": "有3个苹果,有2个桃,苹果和桃的个数比较,可以用下面(    )表示。", + "options": [ + "A. 3<2", + "B. 3>2", + "C. 3=2" + ], + "answer": "B", + "solution": "【分析】根据5以内数大小关系为:1<2<3<4<5,据此比较大小,题目要求比较苹果和桃的个数:苹果有3个,桃有2个,我们需要找出正确表示两者数量关系的选项.\n【详解】A。3<2:表示3小于2,错误,因为3大于2。B。3>2:表示3大于2,正确,苹果的数量多于桃的数量。C。3=2:表示3等于2,错误,因为两者数量不相等。有3个苹果,有2个桃,苹果和桃的个数比较,可以用下面3>2表示。故答案为:B", + "knowledge_points": [ + "5以内数的比大小" + ], + "source": "24-25 一年级上·河南驻马店·期中" + }, + { + "id": "205", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "5个1组成(    )。", + "options": [ + "A. 1", + "B. 4", + "C. 5" + ], + "answer": "C", + "solution": "【分析】1个1是1,2个1是2,3个1是3,4个1是4,5个1是5,据此解答.\n【详解】由分析可知:5个1组成5。故答案为:C", + "knowledge_points": [ + "5以内数的分与合(组成)" + ], + "source": "25-26 一年级上·湖南永州·开学考试" + }, + { + "id": "206", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.65, + "question": "与5-4得数相同的是(    )。", + "options": [ + "A. 4-1", + "B. 4-3", + "C. 2+2" + ], + "answer": "B", + "solution": "【分析】根据题意可知:分别求出各算式的答案,然后比较选择答案一样的即可.\n【详解】5-4=1。A。4-1=3,3>1,则不符合题意。B。4-3=1,1=1,则符合题意。C。2+2=4,4>1,则不符合题意。故答案为:B", + "knowledge_points": [ + "5以内数的减法" + ], + "source": "25-26 一年级上·河南周口·阶段练习" + }, + { + "id": "207", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.94, + "question": "与3相邻的两个数分别是(    )。", + "options": [ + "A. 2,4", + "B. 2,3", + "C. 3,4" + ], + "answer": "A", + "solution": "【分析】1~5各数正着数的顺序是:1,2,3,4,5,据此可知3的前一个数是2,后一个数是4,就是与3相邻的两个数.\n【详解】根据分析可得:与3相邻的两个数分别是2和4。故答案为:A", + "knowledge_points": [ + "5以内数的排序" + ], + "source": "25-26 一年级上·河南周口·阶段练习" + }, + { + "id": "208", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.65, + "question": "下面图(    )能用算式3+2=5表示。", + "options": [ + "A. ![](images/Pasted%20image%2020260310224114.png)", + "B. ![](images/Pasted%20image%2020260310224122.png)", + "C. ![](images/Pasted%20image%2020260310224128.png)" + ], + "answer": "A", + "solution": "【分析】3+2=5表示把3个和2个合起来,得到总数量5,据此逐一分析三个选项,找到正确答案.\n【详解】A。左边有3个,右边有2个,一共有5个,可以用算式3+2=5表示,符合题意;B。一共有5个○,划去3个○,还剩下2个○,用算式5-3=2表示,不符合题意;C。左边有2个茄子,右边有1个茄子,一共有3个茄子,用算式2+1=3表示,不符合题意;故答案为:A", + "knowledge_points": [ + "5以内数的加法", + "5以内数的减法", + "图文问题" + ], + "source": "24-25 一年级上·甘肃临夏·期中" + }, + { + "id": "209", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "下面的算式中,(    )的计算结果是3。", + "options": [ + "A. 4-2", + "B. 5-2", + "C. 1+3" + ], + "answer": "B", + "solution": "【分析】根据题意,分别计算出各个选项的得数,找出计算结果等于3的算式,即可解答.\n【详解】A。4-2:4减去2等于2,不等于3。B。5-2:5减去2等于3,等于3。C。1+3:1加上3等于4,不等于3。只有5-2的计算结果是3。故答案为:B", + "knowledge_points": [ + "5以内数的加法", + "5以内数的减法" + ], + "source": "24-25 一年级上·甘肃临夏·期中" + }, + { + "id": "210", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "小丽扎了3朵红花,又扎了2朵黄花,一共扎了(    )朵花。", + "options": [ + "A. 1", + "B. 2", + "C. 5" + ], + "answer": "C", + "solution": "【分析】根据题意,用扎红花的数量加上扎黄花的数量,即可求出一共扎了多少朵花,用加法列式计算.\n【详解】3+2=5(朵)一共扎了5朵花。故答案为:C", + "knowledge_points": [ + "5以内数的加法" + ], + "source": "25-26 一年级上·湖南永州·开学考试" + }, + { + "id": "211", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.65, + "question": "在计算4-1=□时,下面想法中错误的是(    )。", + "options": [ + "A. ![](images/Pasted%20image%2020260310224257.png)", + "B. ![](images/Pasted%20image%2020260310224304.png)", + "C. 4的前一个数字是3" + ], + "answer": "A", + "solution": "【分析】4-1表示求4与1的差是多少,还表示在4的基础上又少了1个,据此逐一分析三个选项,找出想法中错误的答案.\n【详解】A。表示4和1可以组成5,所以4+1=5,想法错误,符合题意;B。表示4可以分成3和1,所以4-1=3,想法正确,不符合题意;C。表示从4开始,往前接着数1个数,就是在4的基础上,又少了1个数,就是3,想法正确,不符合题意;故答案为:A", + "knowledge_points": [ + "5以内数的加法", + "5以内数的减法" + ], + "source": "25-26 一年级上·青海果洛·阶段练习" + }, + { + "id": "212", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.94, + "question": "乐乐排队买饮料,他前面有2人,从前面数乐乐是第(    )名。", + "options": [ + "A. 2", + "B. 3", + "C. 4" + ], + "answer": "B", + "solution": "【分析】根据题意,乐乐前面有2人,可以通过画图表示出乐乐的位置,![](images/Pasted%20image%2020260310224322.png),从前面数乐乐是第3名。据此解答.\n【详解】根据分析:\n![](images/Pasted%20image%2020260310224326.png)从前面数乐乐是第3名。故答案为:B", + "knowledge_points": [ + "认识几和第几" + ], + "source": "25-26 一年级上·青海果洛·阶段练习" + }, + { + "id": "213", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.94, + "question": "2<5读作(    )。", + "options": [ + "A. 2大于5", + "B. 2小于5", + "C. 2等于5" + ], + "answer": "B", + "solution": "【分析】比较数的大小时,\"=\"是等号,读作等于;\">\"是大于号,读作大于;\"<\"是小于号,读作小于,由此解答.\n【详解】由分析得:2<5读作2小于5。故答案为:B", + "knowledge_points": [ + "5以内数的比大小" + ], + "source": "25-26 一年级上·陕西西安·阶段练习" + }, + { + "id": "214", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "下面算式中得数最大的是(    )。", + "options": [ + "A. 5-1", + "B. 4-2", + "C. 1+4" + ], + "answer": "C", + "solution": "【分析】先计算出各选项算式的结果,再比较大小,选出得数最大的即可.\n【详解】A。5-1=4;B。4-2=2;C。1+4=5。5>4>2,因此得数最大的是1+4。故答案为:C", + "knowledge_points": [ + "5以内数的加法", + "5以内数的减法", + "5以内数的比大小" + ], + "source": "25-26 一年级上·河北邢台·阶段练习" + }, + { + "id": "215", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.94, + "question": "3+2=(    )。", + "options": [ + "A. 5", + "B. 1", + "C. 3" + ], + "answer": "A", + "solution": "【分析】5可以分成3和2,所以3+2=5,据此选答案.\n【详解】3+2=5。故答案为:A", + "knowledge_points": [ + "5以内数的加法", + "5以内数的分与合(组成)" + ], + "source": "25-26 一年级上·湖南永州·开学考试" + }, + { + "id": "216", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.94, + "question": "比较大小:5-1(    )1+3。", + "options": [ + "A. >", + "B. <", + "C. =" + ], + "answer": "C", + "solution": "【分析】先算出括号左右两边算式的结果,再根据1<2<3<4<5比较大小即可.\n【详解】5-1=4,1+3=4,4=4,所以5-1=1+3。故答案为:C", + "knowledge_points": [ + "5以内数的加法", + "5以内数的减法", + "5以内数的比大小" + ], + "source": "25-26 一年级上·湖南永州·开学考试" + }, + { + "id": "217", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.94, + "question": "4减3得多少。算式是(    )。", + "options": [ + "A. 4+3", + "B. 4-3", + "C. 3-4" + ], + "answer": "B", + "solution": "【分析】求一个数减另一个数等于几,两个数字的位置不变,中间写\"-\";求一个数加一个数等于几,中间写\"+\".\n【详解】A。4+3表示4加3得多少,不符合题意;B。4-3表示4减3得多少,符合题意;C。3-4表示3减4得多少,不符合题意。4减3得多少。算式是4-3。故答案为:B", + "knowledge_points": [ + "5以内数的减法" + ], + "source": "25-26 一年级上·湖南永州·开学考试" + }, + { + "id": "218", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.94, + "question": "姐姐今年4岁,比妹妹大3岁,妹妹今年(    )岁。", + "options": [ + "A. 7", + "B. 3", + "C. 1" + ], + "answer": "C", + "solution": "【分析】根据题意,用姐姐的岁数减去3,即可求出妹妹今年几岁。据此选择.\n【详解】4-3=1(岁)妹妹今年1岁。故答案为:C", + "knowledge_points": [ + "5以内数的减法" + ], + "source": "25-26 一年级上·湖南永州·开学考试" + }, + { + "id": "219", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "2+3(    )4-1。", + "options": [ + "A. =", + "B. >", + "C. <" + ], + "answer": "B", + "solution": "【分析】根据5以内数的加减法计算方法计算出算式的结果,再比较即可.\n【详解】2+3=5;4-1=3;5>3,则2+3>4-1。故答案为:B", + "knowledge_points": [ + "5以内数的加法", + "5以内数的减法", + "5以内数的比大小" + ], + "source": "25-26 一年级上·湖南永州·开学考试" + }, + { + "id": "220", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.94, + "question": "4-3=(    )。", + "options": [ + "A. 4", + "B. 3", + "C. 1" + ], + "answer": "C", + "solution": "【分析】想:(1)+3=4,所以4-3=1;据此选答案.\n【详解】4-3=1。故答案为:C", + "knowledge_points": [ + "5以内数的减法" + ], + "source": "25-26 一年级上·湖南永州·开学考试" + }, + { + "id": "221", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "5减4得多少。算式是(    )。", + "options": [ + "A. 5+4", + "B. 4-5", + "C. 5-4" + ], + "answer": "C", + "solution": "【分析】求一个数减另一个数等于几,两个数字的位置不变,中间写\"-\";求一个数加一个数等于几,中间写\"+\".\n【详解】A。5+4表示5加4得多少,不符合题意;B。4-5表示4减5得多少,不符合题意;C。5-4表示5减4得多少,符合题意。则5减4得多少。算式是5-4。故答案为:C", + "knowledge_points": [ + "5以内数的加法", + "5以内数的减法" + ], + "source": "25-26 一年级上·湖南永州·开学考试" + }, + { + "id": "222", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "3只鸡,又来了2只,一共有(    )只鸡。", + "options": [ + "A. 3", + "B. 4", + "C. 5" + ], + "answer": "C", + "solution": "【分析】由题意可知:用原来的母鸡数加上又来的只数,即是一共有的只数;据此解答.\n【详解】由分析可得:3+2=5(只)一共有5只。故答案为:C", + "knowledge_points": [ + "5以内数的加法" + ], + "source": "25-26 一年级上·湖南永州·开学考试" + }, + { + "id": "223", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "五星红旗上有(    )颗五角星。", + "options": [ + "A. 4", + "B. 5", + "C. 6" + ], + "answer": "B", + "solution": "【分析】由题意可知:一面五星红旗上有4颗小五角星包围着1颗大五角星,把小五角星的个数和大五角星的个数相加,即是五星红旗上五角星的个数;据此解答.\n【详解】由分析可得:4+1=5(颗)五星红旗上有5颗五角星。故答案为:B", + "knowledge_points": [ + "数一数", + "5以内数的加法", + "图文问题" + ], + "source": "25-26 一年级上·河北·课后作业" + }, + { + "id": "224", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "丽丽带了5个苹果和同学们分享,现在有两个相同的盘子,将苹果放入盘子,有(    )种放法。", + "options": [ + "A. 3", + "B. 4", + "C. 5" + ], + "answer": "A", + "solution": "【分析】把5个苹果放在两个相同的盘子里,实际上就是两个数加起来的和是5,根据5=0+5=1+4=2+3,解答即可.\n【详解】由分析得:可以一个盘子不放,另一个盘子放5个;一个盘子放1个,另一个盘子放4个;一个盘子放2个,另一个盘子放3个;因此共有3种放法。故答案为:A", + "knowledge_points": [ + "5以内数的加法", + "有关0的加减法" + ], + "source": "25-26 一年级上·全国·单元测试" + }, + { + "id": "225", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "哥哥有2块糖果,妹妹有2块糖果,合起来是(    )糖果。", + "options": [ + "A. 4块", + "B. 2块", + "C. 1块" + ], + "answer": "A", + "solution": "【分析】合起来是多少,就是求两个数的和。把哥哥的糖果块数和妹妹的糖果块数加在一起即可.\n【详解】2+2=4(块)合起来是4块糖果。故答案为:A", + "knowledge_points": [ + "5以内数的加法" + ], + "source": "24-25 一年级上·山东·课后作业" + }, + { + "id": "226", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "小猫钓了3条鱼,猫姐姐钓了5条鱼,猫姐姐给小猫(    )条后,它俩就一样多。", + "options": [ + "A. 1", + "B. 2", + "C. 3" + ], + "answer": "A", + "solution": "【分析】先用减法求出猫姐姐比小猫多钓了多少条鱼,然后把多钓的鱼平均分成2份,把其中的一份给小猫后,它俩就一样多.\n【详解】5-3=2(条)2可以分成1和1,则,猫姐姐给小猫1条后,它俩就一样多。故答案为:A", + "knowledge_points": [ + "5以内数的减法", + "5以内数的分与合(组成)" + ], + "source": "24-25 一年级上·河南商丘·期末" + }, + { + "id": "227", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.94, + "question": "一个物体都没有用(    )表示。", + "options": [ + "A. 0", + "B. 1", + "C. 2" + ], + "answer": "A", + "solution": "【分析】一个也没有用0表示,牢记数字的写法即可.\n【详解】一个物体都没有用0表示。故答案为:A", + "knowledge_points": [ + "0的认识和读写" + ], + "source": "24-25 一年级上·河南商丘·期末" + }, + { + "id": "228", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.65, + "question": "任何一个数字(    ),这个数字的大小不变。", + "options": [ + "A. 减去0", + "B. 加上1", + "C. 减去1", + "D. 加上2" + ], + "answer": "A", + "solution": "【分析】0加上任何数都得原数,任何数减去0还是原数.\n【详解】任何一个数字减去0,如1,1-0=1这个数字的大小不变。故答案为:A", + "knowledge_points": [ + "有关0的加减法" + ], + "source": "24-25 一年级上·浙江温州·期末" + }, + { + "id": "229", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "算式\"5-3=2\"中的\"3\"表示(    )。", + "options": [ + "A. 被减数", + "B. 减数", + "C. 差", + "D. 和" + ], + "answer": "B", + "solution": "【分析】在减法算式中,减号前面的数是被减数,减号后面的数是减数,结果是差,被减数-减数=差.\n【详解】算式\"5-3=2\"中的\"3\"表示减数。故答案为:B", + "knowledge_points": [ + "5以内数的减法" + ], + "source": "24-25 一年级上·浙江温州·期末" + }, + { + "id": "230", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.94, + "question": "我可以由两个相同的数合成,我是(    )。", + "options": [ + "A. 1", + "B. 3", + "C. 4" + ], + "answer": "C", + "solution": "【分析】熟练掌握5以内数的分与合,1可以分成1和0,0和1;3能分成1和2,2和1;4能分成1和3,2和2,3和1,据此解答.\n【详解】根据分析可得:A。1+0=1,0+1=1,没有两个相同的数相加,答案不正确;B。1+2=3,2+1=3,没有两个相同的数相加,答案不正确;C。1+3=4,2+2=4,3+1=4,其中2和2相加等于4,答案正确。我可以由两个相同的数合成,我是4。故答案为:C", + "knowledge_points": [ + "5以内数的减法", + "5以内数的分与合(组成)" + ], + "source": "24-25 一年级上·湖南怀化·期末" + }, + { + "id": "231", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "妈妈用榨汁机榨了5杯橙汁,她喝了1杯。如果列出算式5-1=4(杯),那么所求的问题是(    )。", + "options": [ + "A. 一共有几杯橙汁", + "B. 喝了几杯橙汁", + "C. 还剩几杯橙汁" + ], + "answer": "C", + "solution": "【分析】由题可知,榨了5杯橙汁,喝了1杯,所以在算式5-1=4中,总的橙汁是5杯,喝的橙汁是1杯,所以算出的4应该是剩下了几杯橙汁.\n【详解】A。一共有几杯橙汁;题目中已经给出榨了5杯橙汁,不需要计算,答案不正确;B。喝了几杯橙汁;题目中已经给出喝了1杯,不需要计算,答案不正确;C。还剩几杯橙汁;总的橙汁的数量减去喝了橙汁的数量,等于还剩下几杯橙汁,列出算式是5-1=4(杯);答案正确。故答案为:C", + "knowledge_points": [ + "5以内数的减法", + "\"提问题\"\"填条件\"问题" + ], + "source": "24-25 一年级上·辽宁鞍山·期中" + }, + { + "id": "232", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.94, + "question": "在(    )里填上适当的数.\n0,1,2,(        ),(        ),5。", + "options": [], + "answer": "3;4", + "solution": "【分析】观察可知,后面的数比前面的数多1,根据5以内数的排列顺序0,1,2,3,4,5填空即可.\n【详解】根据分析:0,1,2,3,4,5。", + "knowledge_points": [ + "5以内数的排序" + ], + "source": "25-26 一年级上·山东济宁·阶段练习" + }, + { + "id": "233", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.94, + "question": "在括号里填上\"+\"或\"-\".\n2(      )1=3    4(      )3=1    5(      )0=5    2(      )2=0", + "options": [], + "answer": "+;-;+或-;-", + "solution": "【分析】根据加减法的计算法则解答即可。2加上1就得3,填写\"+\";4减去3就得1,填写\"-\";5加上0还得5;5减去0还得5,填写\"+\"或\"-\";2减去2就得0,填写\"-\".\n【详解】填写如下:2+1=3;4-3=1;5+0=5或5-0=5;2-2=0", + "knowledge_points": [ + "5以内数的加法", + "5以内数的减法", + "有关0的加减法" + ], + "source": "25-26 一年级上·山东菏泽·阶段练习" + }, + { + "id": "234", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.94, + "question": "3>2读作:(        ),5=5读作:(        )。", + "options": [], + "answer": "3大于2;5等于5", + "solution": "【分析】数字直接读出来,\">\"读作\"大于\",\"=\"读作\"等于\",按照从左到右的顺序读出数字和符号,即可解答.\n【详解】3>2读作:3大于2,5=5读作:5等于5。", + "knowledge_points": [ + "5以内数的比大小" + ], + "source": "25-26 一年级上·河南周口·阶段练习" + }, + { + "id": "235", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.94, + "question": "分一分,合一合.\n![](images/Pasted%20image%2020260310224639.png)", + "options": [], + "answer": "2;5;3;1;4", + "solution": "【分析】根据3可以分成1和2;2和3合成5;4可以分成1和3;5可以分成1和4,2和3,3和2,4和1,任意选一组即可.\n【详解】根据分析可得:\n![](images/Pasted%20image%2020260310224645.png)\n(最后一题答案不唯一)", + "knowledge_points": [ + "5以内数的分与合(组成)" + ], + "source": "25-26 一年级上·广东东莞·阶段练习" + }, + { + "id": "236", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.94, + "question": "![](images/Pasted%20image%2020260310224657.png)\n5个去掉(        )个,还剩(        )个。", + "options": [], + "answer": "2;3", + "solution": "【分析】根据题图,共有5个○,虚线圈起来2个,就是去掉2个,求还剩几个,用○的总个数减去圈起来的个数即可.\n【详解】5-2=3(个)5个去掉2个,还剩3个。", + "knowledge_points": [ + "5以内数的减法", + "图文问题" + ], + "source": "24-25 一年级上·河北衡水·期中" + }, + { + "id": "237", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.94, + "question": "在括号里填上\"+\"或\"-\"\n4(      )0=4   5(      )2=3    3(      )2=5    4(      )3=1", + "options": [], + "answer": "+或-;-;+;-", + "solution": "【分析】根据分与合熟练掌握5以内数的加减法。任何数和0相加减都等于任何数。4-0=4或4+0=4.5可以分成2和3,5-2=3.3和2合成5,3+2=5.4可以分成3和1,4-3=1。据此解答.\n【详解】根据分析:4(-)0=4或4(+)0=4;5(-)2=3;3(+)2=5;4(-)3=1", + "knowledge_points": [ + "5以内数的加法", + "5以内数的减法", + "有关0的加减法" + ], + "source": "25-26 一年级上·青海果洛·阶段练习" + }, + { + "id": "238", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.65, + "question": "![](images/Pasted%20image%2020260310224726.png)\n(1)树挡住了(    )只小狗。从左边数,被树挡住的是第(    )只和第(    )只小狗.\n(2)从右边数,被树挡住的是第(    )只和第(    )只小狗。一共有(    )只小狗.\n(3)圈出最右边的两只小狗.\n(4)无论从哪边开始数,第(    )只小狗的顺序没有发生变化。", + "options": [], + "answer": "2;2;3;3;4;5;见详解;3", + "solution": "【分析】(1)从左边数,说话的小狗排第4,它左边能看到1只小狗,所以树挡住了4-1-1=2只小狗。从左边数,被树挡住的是第2只和第3只小狗。(2)从右边数,最右边的小狗是第1只,然后依次往左数,被树挡住的是第3只和第4只小狗。一共有4+1=5只小狗。(3)圈出从右数第1只和第2只小狗(即图中最右边的两只小狗)。(4)一共有5只小狗,无论从哪边开始数,第3只小狗的顺序没有发生变化.\n【详解】(1)4-1-1=2(只)从左边数,被树挡住的是第2只和第3只小狗。(2)4+1=5(只)从右边数,被树挡住的是第3只和第4只小狗。一共有5只小狗。(3)![](images/Pasted%20image%2020260310224749.png)\n(4)无论从哪边开始数,第3只小狗的顺序没有发生变化。", + "knowledge_points": [ + "数一数", + "图文问题", + "左,右位置", + "认识几和第几" + ], + "source": "25-26 一年级上·青海果洛·阶段练习" + }, + { + "id": "239", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "在(    )里填上\">\"\"<\"或\"=\".\n1(        )2         3(        )3             4(        )1              2(        )5", + "options": [], + "answer": "<;=;>;<", + "solution": "【分析】根据5以内数排序:5>4>3>2>1>0,即可比较5以内数大小;据此解答.\n【详解】由分析可得:1<2         3=3             4>1              2<5", + "knowledge_points": [ + "5以内数的排序", + "5以内数的比大小" + ], + "source": "25-26 一年级上·甘肃张掖·阶段练习" + }, + { + "id": "240", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "在(    )里填\"+\"或\"-\",使等式成立.\n3(        )1=2               0(        )1=1               1(        )1=2               4(        )4=0", + "options": [], + "answer": "-;+;+;-", + "solution": "【分析】根据整数加减法的计算法则选择合适的运算符号进行填空,可以先观察算式,如果等号右面的数比前面的两个数都大填\"+\",如果等号右边的数比左边最大的数小填\"-\"。一般情况下,加法会让得数多或不变,减法运算会让得数变少或不变,据此解答.\n【详解】由分析可得:3-1=2               0+1=1               1+1=2               4-4=0", + "knowledge_points": [ + "5以内数的加法", + "5以内数的减法", + "有关0的加减法" + ], + "source": "25-26 一年级上·广东东莞·阶段练习" + }, + { + "id": "241", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.94, + "question": "按顺序写数时,3和5中间的数是(      );比1小的数是(      )。", + "options": [], + "answer": "4;0", + "solution": "【分析】按顺序从3写到5,依次为3,4,5,也就是3和5中间的数是4;5以内数从大到小关系为5>4>3>2>1>0,也就是小于1的数是0.\n【详解】由分析得:\n按顺序写数时,3和5中间的数是4;比1小的数是0。", + "knowledge_points": [ + "5以内数的排序", + "5以内数的比大小", + "0的认识和读写" + ], + "source": "25-26 一年级上·河北邢台·阶段练习" + }, + { + "id": "242", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "每种图案代表数字几。\n菠萝+梨=5              菠萝-梨=1\n菠萝=(        )梨=(        )。", + "options": [], + "answer": "3;2", + "solution": "【分析】3和2组成5,3分成2和1,则菠萝=3,梨=2.\n【详解】据分析可知:3+2=5,3-2=1所以菠萝=3,梨=2。", + "knowledge_points": [ + "5以内数的加法", + "5以内数的减法", + "5以内数的分与合(组成)" + ], + "source": "25-26 一年级上·贵州黔南·阶段练习" + }, + { + "id": "243", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.65, + "question": "![](images/Pasted%20image%2020260310225605.png)\n(1)一共有(    )个图形,从左数月亮排第(    ).\n(2)◯左面有(    )个图形,△右面有(    )个图形.\n(3)在从左边数第4个图形下面画\"√\".\n(4)把右边5个图形圈起来。", + "options": [], + "answer": "10;6;4;3;见详解;见详解", + "solution": "【分析】(1)一个一个地数一数可知,一共有10个图形;一般情况下,写字的手是右手也就是右边,不写字的手是左手也就是左边;据此从左数一数,月亮排第6;(2)一般情况下,写字的手是右手也就是右边,不写字的手是左手也就是左边;以◯为参照物,数出它左面有4个图形,以△为参照物,数出它右面有3个图形;(3)从左边数六边形排第1,正方体排第4,在正方体下面画\"√\"即可;(4)从右边一个一个地数出5个图形,把它们圈起来即可.\n【详解】\n(1)一共有10个图形,从左数月亮排第6.\n(2)◯左面有4个图形,△右面有3个图形.\n(3)![](images/Pasted%20image%2020260310225704.png)\n(4)![](images/Pasted%20image%2020260310225721.png)。", + "knowledge_points": [ + "数一数", + "左,右位置", + "认识几和第几" + ], + "source": "24-25 一年级上·江西吉安·期中" + }, + { + "id": "244", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "我有(        )只手,平时我用(        )手拿铅笔写字。", + "options": [], + "answer": "2;右", + "solution": "【分析】左手和右手共2只手,平时一般用右手写字;据此解答.\n【详解】由分析可得:\n我有2只手,平时我用右手拿铅笔写字。", + "knowledge_points": [ + "1~5的认识和读写", + "左,右位置" + ], + "source": "24-25 一年级上·河南焦作·期中" + }, + { + "id": "245", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "填一填.\n![](images/Pasted%20image%2020260310225730.png)", + "options": [], + "answer": "1;3;4;4", + "solution": "【分析】根据5以内数的分与合填空。2可以分成1和1;2和1可以合成3;5可以分成1和4;2和2可以合成4.\n【详解】\n根据分析:![](images/Pasted%20image%2020260310225738.png)", + "knowledge_points": [ + "5以内数的分与合(组成)" + ], + "source": "25-26 一年级上·陕西延安·阶段练习" + }, + { + "id": "246", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.65, + "question": "5比(        )多2个;4比(        )少1个。", + "options": [], + "answer": "3;5", + "solution": "【分析】求5比几多2,用减法列式计算;求4比几少1,用加法列式计算.\n【详解】5-2=3,4+1=5,5比3多2个;4比5少1个。", + "knowledge_points": [ + "5以内数的加法", + "5以内数的减法" + ], + "source": "25-26 一年级上·湖南永州·开学考试" + }, + { + "id": "247", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "3比(      )少2,5比(      )多3。", + "options": [], + "answer": "5;2", + "solution": "【分析】求3比几少2,用3加2计算;求5比几多3,用5减3计算.\n【详解】3+2=5,5-3=2,3比5少2,5比2多3。", + "knowledge_points": [ + "5以内数的加法", + "5以内数的减法", + "谁比谁多/少几的问题" + ], + "source": "25-26 一年级上·湖南永州·开学考试" + }, + { + "id": "248", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "数一数,下面有(        )只小鸟.\n![](images/Pasted%20image%2020260310225811.png)", + "options": [], + "answer": "4", + "solution": "【分析】观察题图,一个一个地数一数,最后数到几,就有几只小鸟,据此解答.\n【详解】数一数,下面有4只小鸟。", + "knowledge_points": [ + "数一数", + "1~5的认识和读写" + ], + "source": "25-26 一年级上·黑龙江鹤岗·开学考试" + }, + { + "id": "249", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "数一数,下面有(        )朵花.\n![](images/Pasted%20image%2020260310225828.png)", + "options": [], + "answer": "3", + "solution": "【分析】从1开始,一个一个地数,最后数到几,就有几朵花,据此解答.\n【详解】数一数,下面有3朵花。", + "knowledge_points": [ + "数一数", + "1~5的认识和读写" + ], + "source": "25-26 一年级上·黑龙江鹤岗·开学考试" + }, + { + "id": "250", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.94, + "question": "数一数,下面有(        )个苹果.\n![](images/Pasted%20image%2020260310225842.png)", + "options": [], + "answer": "5", + "solution": "【分析】根据题图,一个一个地数一数,最后数到几,就有几个苹果,据此解答.\n【详解】数一数,下面有5个苹果。", + "knowledge_points": [ + "数一数", + "1~5的认识和读写" + ], + "source": "25-26 一年级上·黑龙江鹤岗·开学考试" + }, + { + "id": "251", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.65, + "question": "![](images/Pasted%20image%2020260310225851.png)\n(1)从前往后数,小鹿排在第(      )个,它后面有(      )只小动物.\n(2)从后往前数,小狗排第(      )个,它前面有(      )只小动物。", + "options": [], + "answer": "4;5;5;4", + "solution": "【分析】(1)从前往后数,数出小鹿排在第几,再数出小鹿后面有几只动物即可解答;(2)从后往前数。数出小狗排在第几,再数出小狗前面有几只动物即可解答.\n【详解】(1)根据分析可得:从前往后数,小鹿排在第4个,它后面有5只小动物。(2)根据分析可得:从后往前数,小狗排第5个,它前面有4只小动物。", + "knowledge_points": [ + "认识几和第几" + ], + "source": "25-26 一年级上·全国·课后作业" + }, + { + "id": "252", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "看图写数.\n![](images/Pasted%20image%2020260310225911.png)", + "options": [], + "answer": "1;2;2;3;2;2", + "solution": "【分析】根据给出的图片,观察图中每一组物品的分法,分别把上方总数写在中间方框,再根据图示的左右分组把它们拆分成两个数,填在下面的两个方框即可.\n【详解】![](images/Pasted%20image%2020260310230751.png)", + "knowledge_points": [ + "1~5的认识和读写", + "5以内数的分与合(组成)" + ], + "source": "25-26 一年级上·全国·课后作业" + }, + { + "id": "253", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "一根绳子剪1次有2段,剪2次有(        )段。", + "options": [], + "answer": "3", + "solution": "【分析】由题意可知:绳子剪的次数加1,即是剪的段数;据此解答.\n【详解】由分析可得:\n2+1=3(段)\n一根绳子剪1次有2段,剪2次有3段。", + "knowledge_points": [ + "5以内数的加法" + ], + "source": "25-26 一年级上·全国·课后作业" + }, + { + "id": "254", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "欢欢爬楼梯,爬了3层,她可能是从(      )楼爬到(      )楼,也可能是从(      )楼爬到(      )楼。", + "options": [], + "answer": "1;4;2;5", + "solution": "【分析】由题意可知:用开始的楼数加上爬的层数,即是爬到的楼数;如果从1楼开始爬,爬了3层,爬到了1+3=4(楼);如果从2楼开始爬,爬了3层,爬到了2+3=5(楼);据此可解.\n【详解】由分析可得:欢欢爬楼梯,爬了3层,她可能是从1楼爬到4楼,也可能是从2楼爬到5楼。(答案不唯一)", + "knowledge_points": [ + "5以内数的加法" + ], + "source": "25-26 一年级上·全国·课后作业" + }, + { + "id": "255", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "乐乐从2楼爬到5楼,他爬了(        )层楼。", + "options": [], + "answer": "3", + "solution": "【分析】由分析可得:把两个楼数相减,即是爬的层数;据此解答.\n【详解】由分析可得:5-2=3(层)乐乐从2楼爬到5楼,他爬了3层楼。", + "knowledge_points": [ + "5以内数的减法" + ], + "source": "25-26 一年级上·全国·课后作业" + }, + { + "id": "256", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "从1楼到2楼要爬(        )层楼,从1楼到3楼要爬(        )层楼。从1楼爬了4层楼,就到了(        )楼。", + "options": [], + "answer": "1;2;5", + "solution": "【分析】由题意可知:两个楼层数相减,即是要爬的层数;用楼数加上爬的层数,即是到的楼层数;从1楼到2楼要爬2-1层楼,从1楼到3楼要爬3-1层楼。从1楼爬了4层楼,就到了1+4楼。据此可解.\n【详解】2-1=1(层)3-1=2(层)1+4=5(楼)\n从1楼到2楼要爬1层楼,从1楼到3楼要爬2层楼。从1楼爬了4层楼,就到了5楼。", + "knowledge_points": [ + "5以内数的加法", + "5以内数的减法" + ], + "source": "25-26 一年级上·全国·课后作业" + }, + { + "id": "257", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.65, + "question": "按照下图这样,将5根短绳连在一起,要打(        )个结.\n![](images/Pasted%20image%2020260310230906.png)", + "options": [], + "answer": "4", + "solution": "【分析】根据题意,将2根短绳连在一起,要打1个结;将3根短绳连在一起,要打2个结;将4根短绳连在一起,要打3个结;将5根短绳连在一起,要打4个结;打结的个数比短绳的根数少1;据此解答.\n【详解】5-1=4(个)将5根短绳连在一起,要打4个结。", + "knowledge_points": [ + "5以内数的减法" + ], + "source": "25-26 一年级上·全国·课后作业" + }, + { + "id": "258", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "小明家在2楼4室,门牌上写着204;小芳家在3楼5室,门牌上写着(      )。我发现:数字(      )可以用来占位。", + "options": [], + "answer": "305;0", + "solution": "【分析】小明家在2楼4室,门牌是204。这表示:第一个数字是楼层号2,后两个数字是房间号(4室,但写成04以保持两位数)。同样小芳家在3楼5室,楼层号是3,房间号是5,需要写成05,0可用来占位,确保门牌号的格式统一.\n【详解】根据分析可得:小明家在2楼4室,门牌上写着204;小芳家在3楼5室,门牌上写着305。我发现:数字0可以用来占位。", + "knowledge_points": [ + "0的认识和读写" + ], + "source": "25-26 一年级上·全国·课后作业" + }, + { + "id": "259", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "小朋友排队,从前往后数,小明排在第4个。从后往前数,他排在第2个,一共有(        )人排队。", + "options": [], + "answer": "5", + "solution": "【分析】根据题意,从后往前数,他排在第2个,表示小明的后面有1个小朋友;从前往后数,小明排在第4个。说明从前往后数到小明共4人,再加上小明后面的1人,一共有5人排队.\n【详解】2-1=1(人)4+1=5(人)小朋友排队,从前往后数,小明排在第4个。从后往前数,他排在第2个,一共有5人排队。", + "knowledge_points": [ + "前,后位置", + "5以内数的加法", + "认识几和第几" + ], + "source": "25-26 一年级上·全国·课后作业" + }, + { + "id": "260", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.65, + "question": "白兔和黑兔一共有5只,猜一猜,黑兔最多有(      )只。", + "options": [], + "answer": "4", + "solution": "【分析】白兔最少1只,这时黑兔最多,用总数量减白兔最少的只数即可.\n【详解】5-1=4(只)黑兔最多有4只。", + "knowledge_points": [ + "5以内数的减法" + ], + "source": "25-26 一年级上·全国·课后作业" + }, + { + "id": "261", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "![](images/Pasted%20image%2020260310230940.png)\n大树挡住了(        )辆车。挡住的是第(        )辆和第(        )辆。", + "options": [], + "answer": "2;2;3", + "solution": "【分析】通过观察,数汽车是从右往左数,在第1辆和第4辆之间,挡住了第2辆和第3辆,这2辆车;据此可解.\n【详解】由分析可得:大树挡住了2辆车。挡住的是第2辆和第3辆。", + "knowledge_points": [ + "图文问题", + "认识几和第几" + ], + "source": "25-26 一年级上·全国·课后作业" + }, + { + "id": "262", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "填一填.\n![](images/Pasted%20image%2020260310231141.png)", + "options": [], + "answer": "3;2;3;4;1", + "solution": "【分析】根据5以内数的组成:2和3组成5,2和2组成4,1和2组成3,1和4组成5,3和1组成4;据此可填数.\n【详解】由分析可得:\n![](images/Pasted%20image%2020260310231147.png)", + "knowledge_points": [ + "5以内数的分与合(组成)" + ], + "source": "24-25 一年级上·全国·课后作业" + }, + { + "id": "263", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "填一填.\n![](images/Pasted%20image%2020260310231152.png)\n3+1=(        )", + "options": [], + "answer": "4", + "solution": "【分析】左边有3只小青蛙,右边有1只小青蛙,一共有4只小青蛙,因此3+1=4.\n【详解】由分析得:\n3+1=(4)", + "knowledge_points": [ + "5以内数的加法" + ], + "source": "25-26 一年级上·全国·课后作业" + }, + { + "id": "264", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "在下面的框里填上合适的数.\n![](images/Pasted%20image%2020260310231202.png)", + "options": [], + "answer": "2;1;4;1", + "solution": "【分析】5可以分成3和2.2可以分成1和1.3和1可以合成4.3可以分成2和1。据此填空.\n【详解】如图:\n![](images/Pasted%20image%2020260310231208.png)", + "knowledge_points": [ + "5以内数的分与合(组成)" + ], + "source": "25-26 一年级上·全国·课后作业" + }, + { + "id": "265", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "小平家距离学校2千米,一次他上学走了1千米后想起来忘记带铅笔盒,返回家中取。这次他到学校的路程是( )千米。", + "options": [], + "answer": "4", + "solution": "【分析】据题意可知,小平走了1千米后又返回家里,再从家去学校,等于他第一次去的时候走了1千米,回家又走了1千米,再从家到学校走了2千米,把它们相加即可求出这次他到学校的路程,据此解答.\n【详解】根据分析可得:1+1=2(千米)2+2=4(千米)这次他到学校的路程是4千米。", + "knowledge_points": [ + "5以内数的加法" + ], + "source": "24-25 一年级上·浙江温州·期末" + }, + { + "id": "266", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "一双筷子有(      )根,我国国旗上有(      )颗五角星。", + "options": [], + "answer": "2;5", + "solution": "【分析】数一数即可求解。一个一个地数,最后数到几就是几.\n【详解】一双筷子有2根,我国国旗上有5颗五角星。", + "knowledge_points": [ + "数一数", + "1~5的认识和读写" + ], + "source": "24-25 一年级上·青海果洛·阶段练习" + }, + { + "id": "267", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "计算题", + "difficulty": 0.94, + "question": "看图列式计算。![](images/Pasted%20image%2020260310231252.png)", + "options": [], + "answer": "4-1=3", + "solution": "【分析】由题图可知:原来有4颗花生,拿走了1颗,求还剩多少颗,用原来的花生颗数减去拿走的即可;据此解答.\n【详解】由分析可得:4-1=3(颗)还剩3颗。", + "knowledge_points": [ + "5以内数的减法", + "图文问题" + ], + "source": "24-25 一年级上·河北秦皇岛·期中" + }, + { + "id": "268", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "计算题", + "difficulty": 0.65, + "question": "看图列式计算。![](images/Pasted%20image%2020260310231305.png)", + "options": [], + "answer": "4-2=2", + "solution": "【分析】\n用刺猬的总只数减去划掉刺猬的只数,即可求出还剩几只刺猬.\n【详解】4-2=2(只)\n还剩2只刺猬。", + "knowledge_points": [ + "5以内数的减法", + "图文问题" + ], + "source": "24-25 一年级上·陕西延安·期中" + }, + { + "id": "269", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "计算题", + "difficulty": 0.94, + "question": "我会看图列式计算。![](images/Pasted%20image%2020260310231324.png)", + "options": [], + "answer": "2+3=5", + "solution": "【分析】观察题图可知,左边有2只蜜蜂,右边有3只蜜蜂,求一共有多少只蜜蜂,用加法计算,左边蜜蜂的只数加上右边蜜蜂的只数,等于蜜蜂的总只数.\n【详解】2+3=5(只)因此,一共有5只蜜蜂。", + "knowledge_points": [ + "5以内数的加法", + "图文问题" + ], + "source": "24-25 一年级上·甘肃临夏·期中" + }, + { + "id": "270", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式计算。![](images/Pasted%20image%2020260310231335.png)", + "options": [], + "answer": "5-2=3(个)", + "solution": "【分析】由图可知,一共5个△,划去2个△,求现在还剩几个。用原来的数量减去划去的数量,即可求出现在还剩的数量。用减法列式计算.\n【详解】5-2=3(个)现在还剩3个。", + "knowledge_points": [ + "5以内数的减法", + "图文问题" + ], + "source": "25-26 一年级上·湖南永州·开学考试" + }, + { + "id": "271", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式计算。![](images/Pasted%20image%2020260310231345.png)", + "options": [], + "answer": "1+4=5", + "solution": "【分析】\n左边篮球的个数加上右边篮球的个数,就是一共有几个篮球.\n【详解】1+4=5\n一共有5个篮球。", + "knowledge_points": [ + "5以内数的加法", + "图文问题" + ], + "source": "25-26 一年级上·陕西延安·阶段练习" + }, + { + "id": "272", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "计算题", + "difficulty": 0.65, + "question": "看图说一说图的意思,再计算。![](images/Pasted%20image%2020260310231410.png)", + "options": [], + "answer": "原来有3只鸽子,又飞来2只,一共有多少只;3+2=5", + "solution": "【分析】根据题图,原来有3只鸽子,又飞来2只,求一共有多少只。用原来的数量+又飞来的数量=一共的数量。据此解答.\n【详解】原来有3只鸽子,又飞来2只,一共有多少只。3+2=5(只)一共有5只。", + "knowledge_points": [ + "5以内数的加法", + "图文问题" + ], + "source": "24-25 一年级上·广东东莞·期中" + }, + { + "id": "273", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "计算题", + "difficulty": 0.94, + "question": "看图先说一说图表示的意思,再列式计算。![](images/Pasted%20image%2020260310231438.png)", + "options": [], + "answer": "原有3只燕子,飞走2只,还剩下多少只。3-2=1", + "solution": "【分析】根据题图,原有3只燕子,飞走2只,还剩下多少只。用原有的只数-飞走的只数=还剩的只数。即可解答.\n【详解】根据分析:原有3只燕子,飞走2只,还剩下多少只。3-2=1(只)还剩下1只。", + "knowledge_points": [ + "5以内数的减法", + "图文问题" + ], + "source": "24-25 一年级上·广东东莞·期中" + }, + { + "id": "274", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "计算题", + "difficulty": 0.65, + "question": "看图先说一说图表示的意思,再列式计算。![](images/Pasted%20image%2020260310231505.png)", + "options": [], + "answer": "原来有4个西瓜,小猴又拿来1个西瓜,一共有几个西瓜。4+1=5", + "solution": "【分析】根据题图,原来有4个西瓜,小猴又拿来1个西瓜,求一共有几个西瓜,用加法计算,用原来的数量+小猴又拿来的数量=一共的数量。据此解答\n【详解】根据分析:原来有4个西瓜,小猴又拿来1个西瓜,一共有几个西瓜。4+1=5(个)一共有5个西瓜。", + "knowledge_points": [ + "5以内数的加法", + "图文问题" + ], + "source": "24-25 一年级上·广东东莞·期中" + }, + { + "id": "275", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "计算题", + "difficulty": 0.94, + "question": "看图写算式。![](images/Pasted%20image%2020260310231536.png)", + "options": [], + "answer": "5;2;3", + "solution": "【分析】根据题图可知,一共有5只燕子,飞走了2只,求还剩下的只数,用减法计算,燕子的总只数减去飞走的只数,等于还剩下的只数.\n【详解】根据分析可得:![](images/Pasted%20image%2020260310231712.png)因此,还剩下3只燕子。", + "knowledge_points": [ + "5以内数的减法", + "图文问题" + ], + "source": "24-25 一年级上·湖北武汉·期中" + }, + { + "id": "276", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式并计算。![](images/Pasted%20image%2020260310231727.png)", + "options": [], + "answer": "2;1", + "solution": "【分析】池塘里原有3只天鹅,飞走了2只,求还剩几只,用减法计算,即原有的数量-飞走的数量=还剩的数量.\n【详解】3-2=1(只)还剩1只。", + "knowledge_points": [ + "5以内数的减法", + "图文问题" + ], + "source": "25-26 一年级上·全国·课后作业" + }, + { + "id": "277", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式并计算。![](images/Pasted%20image%2020260310231737.png)", + "options": [], + "answer": "5-2=3", + "solution": "【分析】原来有5个萝卜,用虚线框起来了2个表示去掉2个,则用原来的数量-去掉的数量=还剩的数量.\n【详解】5-2=3(个)还剩3个。", + "knowledge_points": [ + "5以内数的减法", + "图文问题" + ], + "source": "25-26 一年级上·全国·课后作业" + }, + { + "id": "278", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "计算题", + "difficulty": 0.85, + "question": "![](images/Pasted%20image%2020260310231808.png)", + "options": [], + "answer": "4;1", + "solution": "【分析】由题意可知:原来有5个麦穗,拿走了4个,求还剩多少个,用原来的个数减去拿走的即可;据此解答.\n【详解】由分析可得:5-4=1还剩1个。", + "knowledge_points": [ + "5以内数的减法" + ], + "source": "24-25 一年级上·全国·课后作业" + }, + { + "id": "279", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式计算。![](images/Pasted%20image%2020260310231821.png)", + "options": [], + "answer": "2+2=4", + "solution": "【分析】根据题图,用左边○的个数加上右边○的个数,即可求出一共有几个○,据此解答.\n【详解】2+2=4,一共有4个○。", + "knowledge_points": [ + "5以内数的加法", + "图文问题" + ], + "source": "25-26 一年级上·全国·单元测试" + }, + { + "id": "280", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式计算。![](images/Pasted%20image%2020260310231828.png)", + "options": [], + "answer": "1+4=5", + "solution": "【分析】由图意可知:左边有1只蜜蜂,右边有4只,求一共多少只蜜蜂,用左边的蜜蜂只数加上右边的即可;据此解答.\n【详解】由分析可得:1+4=5(只)一共5只蜜蜂。", + "knowledge_points": [ + "5以内数的加法", + "图文问题" + ], + "source": "25-26 一年级上·全国·课后作业" + }, + { + "id": "281", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式计算.\n![](images/Pasted%20image%2020260310231845.png)", + "options": [], + "answer": "2+2=4", + "solution": "【分析】由图意可知:左边有2个杯子,右边也有2个杯子,求一共多少个杯子,用左边的杯子数加上右边的即可;据此解答.\n【详解】由分析可得:2+2=4(个)一共4个杯子。", + "knowledge_points": [ + "5以内数的加法", + "图文问题" + ], + "source": "25-26 一年级上·全国·单元测试" + }, + { + "id": "282", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式计算。![](images/Pasted%20image%2020260310231855.png)", + "options": [], + "answer": "3+2=5", + "solution": "【分析】已知原本鱼缸里面有3条鱼,又倒进来2条鱼,要求现在鱼缸里面有多少条鱼,根据加法的意义,用3+2进行解答即可.\n【详解】3+2=5(条)所以现在鱼缸里面有5条鱼。", + "knowledge_points": [ + "5以内数的加法", + "图文问题" + ], + "source": "25-26 一年级上·全国·课后作业" + }, + { + "id": "283", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式计算。![](images/Pasted%20image%2020260310231903.png)", + "options": [], + "answer": "4;1;3", + "solution": "【分析】由题图可知:原来有4个苹果,小刺猬拿走了1个,求现在还剩几个,用原来的苹果数减去拿走的即可;据此解答.\n【详解】由分析可得:4-1=3现在还剩3个。", + "knowledge_points": [ + "5以内数的减法", + "图文问题" + ], + "source": "25-26 一年级上·全国·课后作业" + }, + { + "id": "284", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式计算。![](images/Pasted%20image%2020260310231929.png)", + "options": [], + "answer": "5;4;1", + "solution": "【分析】一共有5个五角星,用虚线框起来4个表示去掉4个,则用总数量-去掉的数量=还剩的数量.\n【详解】由分析得:5-4=1(个)还剩1个。", + "knowledge_points": [ + "5以内数的减法", + "图文问题" + ], + "source": "25-26 一年级上·全国·课后作业" + }, + { + "id": "285", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式计算。![](images/Pasted%20image%2020260310231943.png)", + "options": [], + "answer": "4;2;2", + "solution": "【分析】用原来的4个减划掉的2个即可求出还剩的个数.\n【详解】4-2=2还剩2个。", + "knowledge_points": [ + "5以内数的减法", + "图文问题" + ], + "source": "25-26 一年级上·全国·课后作业" + }, + { + "id": "286", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式计算.\n![](images/Pasted%20image%2020260310231951.png)", + "options": [], + "answer": "2+3=5", + "solution": "【分析】用左边蜻蜓的只数加上右边蜻蜓的只数,即可求出蜻蜓的总只数.\n【详解】2+3=5(只)一共有5只蜻蜓。", + "knowledge_points": [ + "5以内数的加法", + "图文问题" + ], + "source": "25-26 一年级上·全国·单元测试" + }, + { + "id": "287", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式计算。![](images/Pasted%20image%2020260310232002.png)", + "options": [], + "answer": "2+2=4", + "solution": "【分析】根据题意,左边萝卜的数量加上右边萝卜的数量,就是萝卜的总数量,据此解答.\n【详解】根据分析可得:2+2=4一共有4个萝卜。", + "knowledge_points": [ + "5以内数的加法" + ], + "source": "24-25 一年级下·河南驻马店·期中" + }, + { + "id": "288", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式计算。![](images/Pasted%20image%2020260310232015.png)", + "options": [], + "answer": "4;1", + "solution": "【分析】用原来的4支减去圈走的1支即可求出还剩几支.\n【详解】4-1=3(支)还剩3支铅笔。", + "knowledge_points": [ + "5以内数的减法", + "图文问题" + ], + "source": "24-25 一年级下·河南驻马店·期中" + }, + { + "id": "289", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.65, + "question": "一共有多少只小鸟。\n![](images/Pasted%20image%2020260310232033.png)", + "options": [], + "answer": "5只", + "solution": "【分析】根据图可知,树上原来有2只小鸟,又飞来3只,求一共有多少只小鸟,用加法计算,原来小鸟的数量加又飞来小鸟的数量,即可解答.\n【详解】根据分析可得:2+3=5(只)答:一共有5只小鸟。", + "knowledge_points": [ + "5以内数的加法", + "图文问题" + ], + "source": "24-25 一年级上·湖南岳阳·期中" + }, + { + "id": "290", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "![](images/Pasted%20image%2020260310232045.png)\n荷叶上还剩下多少只青蛙。![](images/Pasted%20image%2020260310232054.png)", + "options": [], + "answer": "5-2=3;3只", + "solution": "【分析】从图上可得:荷叶上原本有5只青蛙,跳入水里2只,要求荷叶上还剩下多少只青蛙,根据减法的意义,用5-2进行计算即可.\n【详解】5-2=3(只)答:荷叶上还剩下3只青蛙。", + "knowledge_points": [ + "5以内数的减法", + "图文问题" + ], + "source": "25-26 一年级上·贵州黔南·阶段练习" + }, + { + "id": "291", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "小河里有4条鱼,游走了1条,还剩几条。", + "options": [], + "answer": "3条", + "solution": "【分析】根据题意可知,用小河里原有鱼的条数减去游的条数,即可求出还剩几条鱼.\n【详解】4-1=3(条)答:还剩下3条鱼。", + "knowledge_points": [ + "5以内数的减法" + ], + "source": "24-25 一年级上·辽宁抚顺·期中" + }, + { + "id": "292", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.94, + "question": "差几个杯子。![](images/Pasted%20image%2020260310232254.png)", + "options": [], + "answer": "5-4=1;1个", + "solution": "【分析】如图,用图中的人数减去杯子的个数,即可计算出还差几个杯子.\n【详解】5-4=1(个)答:差1个杯子。", + "knowledge_points": [ + "5以内数的减法", + "图文问题" + ], + "source": "24-25 一年级上·广东东莞·期中" + }, + { + "id": "293", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "原有5只小鸭,游走1只,还剩几只。", + "options": [], + "answer": "4只", + "solution": "【分析】用原有的只数减去游走的只数,可求出还剩几只.\n【详解】5-1=4(只)答:还剩4只。", + "knowledge_points": [ + "5以内数的减法" + ], + "source": "24-25 一年级上·江西南昌·期中" + }, + { + "id": "294", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "小芳有5个气球,小丽有3个气球,小芳比小丽多几个气球。", + "options": [], + "answer": "2个", + "solution": "【分析】根据题意,用小芳的气球数量减去小丽的气球数量,求出差,就是小芳比小丽多几个气球。用减法列式计算.\n【详解】5-3=2(个)答:小芳比小丽多2个气球。", + "knowledge_points": [ + "5以内数的减法" + ], + "source": "25-26 一年级上·湖南永州·开学考试" + }, + { + "id": "295", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "白兔有5只,比灰兔多2只,灰兔有多少只。", + "options": [], + "answer": "3只", + "solution": "【分析】根据题意,用白兔的数量减去2,即可求出灰兔有多少只,用减法列式计算.\n【详解】5-2=3(只)答:灰兔有3只。", + "knowledge_points": [ + "5以内数的减法" + ], + "source": "25-26 一年级上·湖南永州·开学考试" + }, + { + "id": "296", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "池塘里原来有4只鸭子,游走了1只,还剩几只。", + "options": [], + "answer": "3只", + "solution": "【分析】根据减法的意义,池塘里原有鸭子的数量-游走的数量=还剩的数量.\n【详解】4-1=3(只)答:还剩3只。", + "knowledge_points": [ + "5以内数的减法" + ], + "source": "25-26 一年级上·广东汕头·开学考试" + }, + { + "id": "297", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "妈妈拿夹子晾衣服,2个夹子可以晾1件衣服,3个夹子可以晾2件衣服,4个夹子可以晾3件衣服,妈妈有5个夹子,她一共可以晾多少件衣服。", + "options": [], + "answer": "4件", + "solution": "【分析】根据2个夹子可以晾1件衣服,3个夹子可以晾2件衣服,4个夹子可以晾3件衣服,可得:晾衣服的件数比夹子数少1,即5个夹子可以晾4件衣服,据此解答.\n【详解】5-1=4(件)答:她一共可以晾4件衣服。", + "knowledge_points": [ + "5以内数的减法" + ], + "source": "25-26 一年级上·全国·课后作业" + }, + { + "id": "298", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.65, + "question": "在一次跑步比赛中,宁宁的前面有2人,后面有2人,一共有多少人参加跑步比赛。宁宁要想排名第一,必须超过多少人。", + "options": [], + "answer": "5人;2人", + "solution": "【分析】根据题意可得,宁宁前面的人数+宁宁后面的人数=除宁宁以外的人数,除宁宁以外的人数+宁宁=参加跑步的人数,由此列出算式算出答案即可知参加跑步比赛的人数。宁宁要成为第一名,就需要超过宁宁前面的人,找出宁宁前面的人数即可解答.\n【详解】2+2=4(人)4+1=5(人)宁宁前面有2人,所以宁宁要排第一,需要超过2人。答:一共有5人参加跑步比赛,宁宁要得第一必须超过2人。", + "knowledge_points": [ + "5以内数的加法" + ], + "source": "25-26 一年级上·全国·课后作业" + }, + { + "id": "299", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.65, + "question": "晚上小华在灯下写作业,突然停电。小华去拉了两下开关,这时爸爸回来后,又到小华的房间拉了三下开关。等来电后,小华房间的灯是亮的还是不亮的。", + "options": [], + "answer": "不亮", + "solution": "【分析】根据题意,灯原来是亮的,拉1下开关灯不亮,拉2下开关灯亮,拉3下开关灯不亮,拉4下开关灯亮,拉5下开关灯不亮,拉6下开关灯亮。由此用加法计算出小华和爸爸一共拉了几下,即可得知灯是否是亮的.\n【详解】2+3=5(下)拉5下开关灯不亮。答:等来电后,小华房间的灯是不亮的。", + "knowledge_points": [ + "5以内数的加法" + ], + "source": "25-26 一年级上·全国·课后作业" + }, + { + "id": "300", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "小华和爸爸妈妈为植树节义务植树,小华植了2棵,爸爸植了5棵,妈妈比爸爸少植2棵.\n(1)妈妈植树多少棵。\n(2)小华比爸爸少植树多少棵。", + "options": [], + "answer": "3棵;3棵", + "solution": "【分析】(1)根据减法的意义,用爸爸植树的棵数减去妈妈比爸爸少植的棵数,即可计算出妈妈植树多少棵;(2)用爸爸植树的棵数减去小华植树的棵数,即可计算出小华比爸爸少植树多少棵.\n【详解】(1)5-2=3(棵)答:妈妈植树3棵。(2)5-2=3(棵)答:小华比爸爸少植树3棵。", + "knowledge_points": [ + "5以内数的减法" + ], + "source": "24-25 一年级上·浙江温州·期末" + }, + { + "id": "301", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "小明和小丽有同样多的糖,送给爷爷后,小明还剩3颗,小丽还剩5颗,谁送给爷爷的糖多。", + "options": [ + "A. 小丽", + "B. 小明", + "C. 小丽" + ], + "answer": "B", + "solution": "【分析】根据题意可知,小明和小丽有同样多的糖,剩下多的就是送给爷爷的少,剩下少的就是送给爷爷的多,据此解答.\n【详解】3<5小明剩下的少,送给爷爷的就多,小丽剩下的多,送给爷爷的就少。故答案为:B", + "knowledge_points": [ + "比较物体多少" + ], + "source": "24-25一年级上·四川广元·期末" + }, + { + "id": "302", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "在算式\"◎-5=3\"中,下面说法正确的是( )。", + "options": [ + "A. ◎是被减数", + "B. ◎比5少3", + "C. 5比◎多3" + ], + "answer": "A", + "solution": "【分析】在减法算式中,\"-\"前面的数是被减数,后面的数是减数,等号后面的数是差,即被减数-减数=差;逐项分析选项中的答案即可.\n【详解】A。根据分析可知,◎是被减数,说法正确;B。根据题意可知,◎比5多3,而答案中说◎比5少3,故说法不正确;C。根据题意可知,◎比5多3,而答案中说5比◎多3,故说法不正确。故答案为:A", + "knowledge_points": [ + "加,减法的意义和各部分间的关系" + ], + "source": "24-25一年级上·湖北随州·期末" + }, + { + "id": "303", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "今天是星期一有雨,运动会推迟4天再开,运动会星期( )开。", + "options": [ + "A. 星期五", + "B. 星期三", + "C. 星期四" + ], + "answer": "A", + "solution": "【分析】据题意,星期一这一天不算,再往后推迟4天,即1加4即可得出答案.\n【详解】据分析可得:1+4=5,所以是星期五开运动会。故答案为:A", + "knowledge_points": [ + "5以内数的加法" + ], + "source": "24-25一年级上·河南漯河·期末" + }, + { + "id": "304", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "小白兔有2个哥哥和2个姐姐,兔妈妈有( )个兔宝宝。", + "options": [ + "A. 5", + "B. 7", + "C. 6" + ], + "answer": "A", + "solution": "【分析】首先算出来小白兔的哥哥和姐姐一共多少个,用加法计算,然后再把得数加上小白兔,就可以算出兔妈妈一共有多少个宝宝。据此解答.\n【详解】2+2=4(个)4+1=5(个)所以兔妈妈有5个兔宝宝。故答案为:A", + "knowledge_points": [ + "5以内数的加法" + ], + "source": "24-25一年级上·河南三门峡·期中" + }, + { + "id": "305", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.65, + "question": "比4小的数有( )个。", + "options": [ + "A. 3", + "B. 4", + "C. 5" + ], + "answer": "B", + "solution": "【分析】根据5以内从小到大的排列顺序0<1<2<3<4<5,解答即可.\n【详解】比4小的数有0,1,2,3,共4个数。所以比4小的数有4个。故答案为:B", + "knowledge_points": [ + "5以内数的排序" + ], + "source": "24-25一年级上·河南驻马店·期中" + }, + { + "id": "306", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "11月5日是星期二,再过3天是中小学生运动会,中小学生运动会在( )开。", + "options": [ + "A. 星期四", + "B. 星期五", + "C. 星期六" + ], + "answer": "B", + "solution": "【分析】从星期二开始,一天一天地往后数3天,即可知道再过3天是星期几.\n【详解】由题意分析得:星期二,星期三,星期四,星期五;即,11月5日是星期二,再过3天是中小学生运动会,中小学生运动会在星期五开。故答案为:B", + "knowledge_points": [ + "数一数" + ], + "source": "24-25一年级上·河北秦皇岛·期末" + }, + { + "id": "307", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "与1+3的和相等的算式是( )。", + "options": [ + "A. 2+2", + "B. 0+3", + "C. 5-2" + ], + "answer": "A", + "solution": "【分析】根据整数加减法的计算法则,依次计算出各算式的结果,再找到与1+3得数相同的即可.\n【详解】1+3=4;A。2+2=4;符合题意;B。0+3=3;不符合题意;C。5-2=3,不符合题意。与1+3的和相等的算式是2+2。故答案为:A", + "knowledge_points": [ + "有关0的加减法", + "5以内数的加法", + "5以内数的减法" + ], + "source": "24-25一年级上·山东菏泽·期中" + }, + { + "id": "308", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "一个物体都没有用( )表示。", + "options": [ + "A. 0", + "B. 1", + "C. 2", + "D. 3" + ], + "answer": "A", + "solution": "【分析】表示物体的个数用0,1,2,3,4,5,。来表示;其中0表示一个物体也没有;据此解决.\n【详解】由分析可得:一个物体都没有用\"0\"表示。故答案为:A", + "knowledge_points": [ + "0的认识和读写" + ], + "source": "24-25一年级上·河南南阳·期中" + }, + { + "id": "309", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "5个小朋友排一队唱歌,从左往右数,小红排第4个;从右往左数,小红排第( )个。", + "options": [ + "A. 4", + "B. 3", + "C. 2", + "D. 1" + ], + "answer": "C", + "solution": "【分析】根据题意,先求出小红右边的人数,再根据从右往左数小红第几=小红右边的人数+1(小红自己),即可解答.\n【详解】5-4=1(人)1+1=2(人)则小红排第(2)个。故答案为:C", + "knowledge_points": [ + "认识几和第几", + "5以内数的加法", + "5以内数的减法" + ], + "source": "24-25一年级上·河南南阳·期中" + }, + { + "id": "310", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "比1大比4小的数有( )个。", + "options": [ + "A. 2", + "B. 3", + "C. 4", + "D. 5" + ], + "answer": "A", + "solution": "【分析】根据题意,熟练掌握5以内数的大小比较,0<1<2<3<4<5,据此解答.\n【详解】比1大比4小的数有:2,3,共有2个。故答案为:A", + "knowledge_points": [ + "5以内数的比大小" + ], + "source": "24-25一年级上·河南南阳·期中" + }, + { + "id": "311", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.65, + "question": "5只青蛙跳上两片荷叶,两片荷叶上的青蛙只数能同样多吗。( )", + "options": [ + "A. 能", + "B. 不能", + "C. 不确定" + ], + "answer": "B", + "solution": "【分析】看看5是否可以分成两个相同的数,5可以分为0和5,1和4,2和3,每组中的两个数都不相同,因此两片荷叶上的青蛙只数不能同样多.\n【详解】由分析可知,5只青蛙跳上两片荷叶,两片荷叶上的青蛙只数不能同样多。故答案为:B", + "knowledge_points": [ + "5以内数的分与合(组成)" + ], + "source": "24-25一年级上·河南南阳·期中" + }, + { + "id": "312", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.65, + "question": "从1,2,4,5这四个数中选3个数写一道减法算式,正确的是( )。", + "options": [ + "A. 3-2=1", + "B. 1+4=5", + "C. 5-1=4" + ], + "answer": "C", + "solution": "【分析】根据题意\"选3个数\"以及\"减法算式\",分析各个算式是否符合题意.\n【详解】A。3-2=1,只选取了2个数,不符合题意B。1+4=5,是一道加法算式,不符合题意C。5-1=4,从1,2,4,5这四个数中选了3个数,并且是一道正确的减法算式,符合题意;故答案为:C", + "knowledge_points": [ + "5以内数的减法" + ], + "source": "24-25一年级上·河南南阳·期中" + }, + { + "id": "313", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "下列算式与5-2得数相同的是( )。", + "options": [ + "A. 2+3", + "B. 4-1", + "C. 1+3" + ], + "answer": "B", + "solution": "【分析】根据5以内整数的加减法运算,先算出5-2的得数,再算出各个算式的得数,据此解答即可.\n【详解】5-2=3A。2+3=5,不符合题意;B。4-1=3,与5-2=3的得数相同C。1+3=4,不符合题意。故答案为:B", + "knowledge_points": [ + "5以内数的加法", + "5以内数的减法" + ], + "source": "24-25一年级上·全国·单元测试" + }, + { + "id": "314", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "小利有3支笔,给了小美1支,小利还有几支笔。下面列式正确的是( )。", + "options": [ + "A. 3+1=4", + "B. 3-1=2", + "C. 3-2=1" + ], + "answer": "B", + "solution": "【分析】根据题意,给了小美1支,也就是去掉了1支,求剩下的数量,用减法计算,原有的数量-给小美的数量=剩下的数量.\n【详解】A。3+1=4表示又增加了1支,与题意不符;B。3-1=2表示给了小美1支后还剩2支,与题意相符C。3-2=1表示去掉了2支,与题意不符。所以列式正确的是3-1=2。故答案为:B", + "knowledge_points": [ + "5以内数的加法", + "5以内数的减法" + ], + "source": "24-25一年级上·贵州铜仁·期中" + }, + { + "id": "315", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.65, + "question": "王老师带一年级的4个小朋友去动物园,每人需要买1张门票,买( )张门票合适。", + "options": [ + "A. 2", + "B. 5", + "C. 4" + ], + "answer": "B", + "solution": "【分析】一共多少人就需要买多少张门票,将老师和小朋友的人数相加即可求出需要买几张门票.\n【详解】1+4=5(张)买5张门票合适。故答案为:B", + "knowledge_points": [ + "5以内数的加法" + ], + "source": "24-25一年级上·内蒙古通辽·期中" + }, + { + "id": "316", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.65, + "question": "在计算3+2=□时,下面的想法错误的是( )。", + "options": [ + "A. 3后面接着数2个数", + "B. ![](images/Pasted%20image%2020260310235909.png)", + "C. ![](images/Pasted%20image%2020260310235915.png)" + ], + "answer": "C", + "solution": "【分析】3+2表示3和2的和,也可以表示在3的基础上又多了2个。逐项分析即可.\n【详解】A。3后面接着数2个数就是在3的基础上又多了2个,可以用来计算3+2.\nB。表示3和2合起来是5,可以用来计算3+2.\nC。可以用来计算2+1.\n在计算3+2=□时,下面的想法错误的是![](images/Pasted%20image%2020260310235931.png)。故答案为:C", + "knowledge_points": [ + "5以内数的分与合(组成)", + "5以内数的加法" + ], + "source": "24-25一年级上·河南南阳·期中" + }, + { + "id": "317", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.65, + "question": "与算式5-3得数相等的算式是( )。", + "options": [ + "A. 4-3", + "B. 1+3", + "C. 0+2" + ], + "answer": "C", + "solution": "【分析】5可以分成3和2,4可以分成3和1,0和2可以合成2;根据5以内加减法的计算方法,分别计算出5-3和各选项算式的得数,再比较它们的得数解答即可.\n【详解】5-3=2A。4-3=1,不符合题意;B。1+3=4,不符合题意;C。0+2=2,符合题意。故答案为:C", + "knowledge_points": [ + "有关0的加减法", + "5以内数的加法", + "5以内数的减法" + ], + "source": "24-25一年级上·广西贺州·期中" + }, + { + "id": "318", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "妈妈给红红和东东各5个糖果,谁剩下的糖果多。\n![](images/Pasted%20image%2020260311001434.png)", + "options": [ + "A. 无法判断", + "B. 东东", + "C. 红红" + ], + "answer": "C", + "solution": "【分析】据题意,红红和东东各5个糖果,已知红红吃了2颗,东东吃了3颗,用总的糖果数量减去吃了的糖果数量,即可得出剩下的糖果数量。\n【详解】据分析可得:红红:5-2=3(颗);东东:5-3=2(颗)。红红还剩3颗糖果,东东还剩2颗糖果,所以红红剩下的糖果数量比东东的多。故答案为:C", + "knowledge_points": [ + "5以内数的减法" + ], + "source": "24-25一年级上·广东韶关·期中" + }, + { + "id": "319", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "与2+2的得数不相等的算式是( )。", + "options": [ + "A. 4+0", + "B. 4-0", + "C. 1+2" + ], + "answer": "C", + "solution": "【分析】2+2=4,依次计算出各选项的结果,选择得数不是4的即可.\n【详解】A。4+0=4,得数是4;B。4-0=4,得数是4;C。1+2=3,得数不是4。与2+2的得数不相等的算式是1+2。故答案为:C", + "knowledge_points": [ + "有关0的加减法", + "5以内数的加法" + ], + "source": "24-25一年级上·陕西汉中·期中" + }, + { + "id": "320", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "\"3-2=1\"读作( )。", + "options": [ + "A. 3加2等于1", + "B. 3等于2减1", + "C. 3减2等于1" + ], + "answer": "C", + "solution": "【分析】减法算式从左往右读,数字是几就读几,\"-\"读作减,\"=\"读作等于,由此解答.\n【详解】由分析可知,\"3-2=1\"读作3减2等于1。故答案为:C", + "knowledge_points": [ + "5以内数的减法" + ], + "source": "24-25一年级上·陕西汉中·期中" + }, + { + "id": "321", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "与5相邻的数是( )。", + "options": [ + "A. 6和7", + "B. 3和4", + "C. 4和6" + ], + "answer": "C", + "solution": "【分析】10以内数从小到大为:1,2,3,4,5,6,7,8,9,10。与5相邻的数也就是它两侧的数,由此解答.\n【详解】由分析可知,与5相邻的两个数是4和6。故答案为:C", + "knowledge_points": [ + "10以内数的排序" + ], + "source": "20-21一年级上·贵州黔南·期中" + }, + { + "id": "322", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "直尺上的刻度是从0开始,说明0可以表示( )。", + "options": [ + "A. 起点", + "B. 分界线", + "C. 没有" + ], + "answer": "A", + "solution": "【分析】直尺上的刻度从0开始,0可以表示测量的起点。\n【详解】直尺上的刻度从0开始,这一设计意味着0不仅代表了测量的起始点,而且象征着一种起点或开始的概念。在数学、测量和工程等多个领域中,0被广泛用作起始标记,表明测量的起点或某个过程的开始。因此,直尺上的0刻度线不仅是一个物理上的起点,也是数学和测量学中起点概念的体现。故答案为:A", + "knowledge_points": [ + "0的认识和读写" + ], + "source": "24-25一年级上·全国·单元测试" + }, + { + "id": "323", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "下面的算式不正确的是( )。", + "options": [ + "A. 0+5=5", + "B. 0-5=5", + "C. 5+0=5" + ], + "answer": "B", + "solution": "【分析】根据10以内加减法的运算法则计算,即可找到符合题意的答案.\n【详解】A。0+5=5,计算正确;B。0-5不够减,所以原题计算错误;C。5+0=5,计算正确;即,算式不正确的是(0-5=5)。故答案为:B", + "knowledge_points": [ + "有关0的加减法" + ], + "source": "24-25一年级上·辽宁·课后作业" + }, + { + "id": "324", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "草地上原来有5只兔子,后来跑了2只,现在草地上还有几只兔子。列式计算为( )。", + "options": [ + "A. 5-3=2", + "B. 5-2=3", + "C. 3+2=5" + ], + "answer": "B", + "solution": "【分析】用草地上原来有兔子的只数,减去跑了的只数,即可计算出现在草地上还有几只兔子.\n【详解】由题意分析得:草地上原来有5只兔子,后来跑了2只,现在草地上还有几只兔子。列式计算为(5-2=3)。故答案为:B", + "knowledge_points": [ + "5以内数的减法" + ], + "source": "24-25一年级上·辽宁·课后作业" + }, + { + "id": "325", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "与4-0得数不同的算式是( )。", + "options": [ + "A. 1+3", + "B. 5-1", + "C. 2-2" + ], + "answer": "C", + "solution": "【分析】依次计算出4-0和各选项算式的结果,选择得数不同的即可.\n【详解】4-0=4A。1+3=4;B。5-1=4;C。2-2=0。与4-0得数不同的算式是2-2。故答案为:C", + "knowledge_points": [ + "5以内数的加法", + "5以内数的减法" + ], + "source": "24-25一年级上·辽宁·课后作业" + }, + { + "id": "326", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "比3多2,比4多1的数是( )。", + "options": [ + "A. 5", + "B. 4", + "C. 3" + ], + "answer": "A", + "solution": "【分析】求比一个数多几的数是多少,用加法列式计算即可.\n【详解】3+2=5;4+1=5即,比3多2,比4多1的数是5。故答案为:A", + "knowledge_points": [ + "5以内数的加法" + ], + "source": "19-20一年级上·全国·期中" + }, + { + "id": "327", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "与4+2的结果相等的算式是( )。", + "options": [ + "A. 2+3", + "B. 1+1", + "C. 3+3" + ], + "answer": "C", + "solution": "【分析】分别计算出4+2和各个选项算式的结果,再找出结果相等的算式即可求解.\n【详解】4+2=6A。2+3=5;B。1+1=2;C。3+3=6。与4+2的结果相等的算式是3+3.\n故答案为:C", + "knowledge_points": [ + "6的加减法", + "5以内数的加法" + ], + "source": "24-25一年级上·江苏·课后作业" + }, + { + "id": "328", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "妈妈买了5个苹果,小刚吃了2个,还剩( )苹果。", + "options": [ + "A. 3个", + "B. 6个", + "C. 7个" + ], + "answer": "A", + "solution": "【分析】根据减法的意义,用买的数量减去吃了的数量,即可求出还剩多少个.\n【详解】5-2=3(个)还剩3个苹果。故答案为:A", + "knowledge_points": [ + "5以内数的减法" + ], + "source": "24-25一年级上·辽宁·课后作业" + }, + { + "id": "329", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "在4>□中,填在方框里的数,下列正确的选择是( )。", + "options": [ + "A. 3", + "B. 4", + "C. 5" + ], + "answer": "A", + "solution": "【分析】1到5从小到大排序:1,2,3,4,5;据此比较大小,即可解决.\n【详解】A。4>3;B。4=4;C。4<5;即,在4>□中,填在方框里的数,正确的选择是3.\n故答案为:A", + "knowledge_points": [ + "5以内数的比大小" + ], + "source": "24-25一年级上·江苏·课后作业" + }, + { + "id": "330", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "在5和3中间的数是( )。", + "options": [ + "A. 1", + "B. 4", + "C. 2" + ], + "answer": "B", + "solution": "【分析】按照1,2,3,4,5的顺序,即可知道在5和3中间的数是4;据此解决.\n【详解】由题意分析得:1,2,3,4,5,即,在5和3中间的数是4。故答案为:B", + "knowledge_points": [ + "5以内数的排序" + ], + "source": "24-25一年级上·江苏·课后作业" + }, + { + "id": "331", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "在算式5-1=4中,( )是减数。", + "options": [ + "A. 5", + "B. 1", + "C. 4" + ], + "answer": "B", + "solution": "【分析】在算式5-1=4中,接着减号后面的这个数是减数,据此即可解答.\n【详解】由题意分析得:在算式5-1=4中,1是减数。故答案为:B", + "knowledge_points": [ + "5以内数的减法" + ], + "source": "24-25一年级上·江苏·课后作业" + }, + { + "id": "332", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "小红比小华高5厘米,小力比小红矮3厘米,他们三人( )最矮。", + "options": [ + "A. 小华", + "B. 小红", + "C. 小力" + ], + "answer": "A", + "solution": "【分析】因为小红比小华高5厘米,小力比小红矮3厘米,则小华比小力矮(5-3)厘米,据此即可解答.\n【详解】5-3=2(厘米)所以他们三人小华最矮。故答案为:A.", + "knowledge_points": [ + "5以内数的减法" + ], + "source": "24-25一年级上·江苏·课后作业" + }, + { + "id": "333", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "一个数比4小,比2大,这个数可能是( )。", + "options": [ + "A. 3", + "B. 4", + "C. 5" + ], + "answer": "A", + "solution": "【分析】5以内数从小到大为1<2<3<4<5,由此比较选择即可.\n【详解】A。2<3<4,符合题意;B。2<4=4,不符合题意;C。2<4<5,不符合题意。这个数可能是3。故答案为:A", + "knowledge_points": [ + "5以内数的比大小" + ], + "source": "24-25一年级上·山东·课后作业" + }, + { + "id": "334", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "萌萌有3块蛋糕,明明有3块,3( )3。", + "options": [ + "A. >", + "B. <", + "C. =" + ], + "answer": "C", + "solution": "【分析】萌萌和明明的蛋糕数量都是3块,数量相同,用等号表示.\n【详解】萌萌有3块蛋糕,明明有3块,3=3。故答案为:C", + "knowledge_points": [ + "5以内数的比大小" + ], + "source": "24-25一年级上·山东·课后作业" + }, + { + "id": "335", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.65, + "question": "有关0的说法,错误的是( )。", + "options": [ + "A. 0只能表示\"没有\"", + "B. 0可以用来\"占位\"", + "C. 0可以表示\"分界\"", + "D. 0可以表示\"起点\"" + ], + "answer": "A", + "solution": "【分析】0可以表示什么都没有,在数位顺序表中写数,哪个数位上没有数,可以用0占位;0可以表示正负数的分界点;0可以表示刻度的起点,据此解答.\n【详解】A。0不仅只表示一个也没有,错误;B。0可以用来占位,正确;C。0可以表示正负数的分界点,正确;D。0可以表示刻度的起点。正确。故答案为:A.", + "knowledge_points": [ + "0的认识和读写" + ], + "source": "24-25一年级上·江苏·课前预习" + }, + { + "id": "336", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "佳佳左手拿了4个气球,右手拿了1个气球,佳佳手里一共拿了( )个气球。", + "options": [], + "answer": "5", + "solution": "【分析】根据推移,要求佳佳手里气球的总数,需要把左手拿的气球数量和右手拿的气球数量合并起来,用加法计算.\n【详解】4+1=5(个)佳佳左手拿了4个气球,右手拿了1个气球,佳佳手里一共拿了5个气球。", + "knowledge_points": [ + "5以内数的加法" + ], + "source": "24-25一年级上·陕西延安·期末" + }, + { + "id": "337", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "原定星期二开会,因雨推迟2天再开,应该星期 开会。", + "options": [], + "answer": "四", + "solution": "【分析】从星期二往后数2天即可,用加法计算.\n【详解】2+2=4原定星期二开会,因雨推迟2天再开,应该星期四开会。", + "knowledge_points": [ + "5以内数的加法" + ], + "source": "24-25一年级上·河北邯郸·期末" + }, + { + "id": "338", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "今天是星期一,因有雨,原计划今天召开的运动会将推迟3天召开,运动会将在星期( )召开。", + "options": [], + "answer": "四", + "solution": "【分析】从星期一开始,一天一天地往后数3天,即可知道3天后是星期几;据此解决.\n【详解】由题意分析得:星期一,星期二,星期三,星期四,即,今天是星期一,因有雨,原计划今天召开的运动会将推迟3天召开,运动会将在星期四召开。", + "knowledge_points": [ + "数一数" + ], + "source": "2024一年级上·全国·专题练习" + }, + { + "id": "339", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "与3相邻的数是( )和( )。", + "options": [], + "answer": "2;4", + "solution": "【分析】5以内数从小到大顺序为:1,2,3,4,5,与3相邻的数是它两侧的数,由此解答.\n【详解】与3相邻的数是2和4。", + "knowledge_points": [ + "5以内数的排序" + ], + "source": "24-25一年级上·河北保定·期中" + }, + { + "id": "340", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "一辆三轮车有( )个轮子,一双筷子有( )根,一只小狗有( )条腿,你的右手有( )根手指头。", + "options": [], + "answer": "3;2;4;5", + "solution": "【分析】根据生活经验数一数可知:图1:三轮车有3个轮子;图2:一双筷子有2根;图3:一只小狗有4条腿;图4:右手上有5根手指。![](images/Pasted%20image%2020260311000304.png)\n【详解】一辆三轮车有3个轮子,一双筷子有2根,一只小狗有4条腿,你的右手有5根手指头。", + "knowledge_points": [ + "数一数", + "1~5的认识和读写" + ], + "source": "24-25一年级上·湖南邵阳·期中" + }, + { + "id": "341", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "分一分,合一合.\n![](images/Pasted%20image%2020260311000312.png)", + "options": [], + "answer": "5;1;1;2;2;1;1", + "solution": "【分析】本题根据数的分与合解答。2和3合起来就是5;5可以分成4和1;3可以分成1和2;4可以分成1和3;4可以分成2和2;4可以分成3和1,0和4,填写任意一组即可;2可以分成1和1,0和2.\n【详解】填写如下:![](images/Pasted%20image%2020260311000431.png)", + "knowledge_points": [ + "5以内数的分与合(组成)" + ], + "source": "24-25一年级上·山东济宁·期中" + }, + { + "id": "342", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "两个同样的数相减得( )。", + "options": [], + "answer": "0", + "solution": "【分析】减法算式为被减数-减数=差,两个同样的数相减,也就是被减数和减数相同,由此可举例解答.\n【详解】两个同样的数相减得0。例如3-3=0。", + "knowledge_points": [ + "有关0的加减法" + ], + "source": "24-25一年级上·河南三门峡·期中" + }, + { + "id": "343", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.65, + "question": "在5,1,2,4,0中,( )最大,( )最小。从左数,数字\"1\"排在这一行的第( )位;数字\"0\"排在这一行的第( )位。", + "options": [], + "answer": "5;0;2;5", + "solution": "【分析】5以内数大小关系为:0<1<2<3<4<5,据此找出所给数中的最大数和最小数;从左数,也就是从5开始数,数出数字\"1\"排在这一行的第2位;数字\"0\"排在这一行的第5位,据此解答即可.\n【详解】0<1<2<4<5所以在5,1,2,4,0中,5最大,0最小。从左数,数字\"1\"排在这一行的第2位;数字\"0\"排在这一行的第5位。", + "knowledge_points": [ + "左,右位置", + "数一数", + "5以内数的比大小" + ], + "source": "24-25一年级上·全国·课后作业" + }, + { + "id": "344", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "按规律写数:( ),1,( ),3,4,( )。", + "options": [], + "answer": "0;2;5", + "solution": "【分析】根据对5以内数的认识可知,数字的排列顺序从小到大为:0,1,2,3,4,5,找到相应的数字填空即可.\n【详解】按规律写数:0,1,2,3,4,5。", + "knowledge_points": [ + "5以内数的排序" + ], + "source": "24-25一年级上·全国·课后作业" + }, + { + "id": "345", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "一个都没有,用( )表示。", + "options": [], + "answer": "0", + "solution": "【分析】一个都没有就是0,用0表示.\n【详解】一个都没有就是零,用0表示。例如:![](images/Pasted%20image%2020260311000449.png)原来有3只小鸟,飞走了3只,现在一只也没有,也就是0只。", + "knowledge_points": [ + "0的认识和读写" + ], + "source": "24-25一年级上·湖南娄底·期中" + }, + { + "id": "346", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "三轮车有( )个轮子,小猫有( )条腿,一双筷子有( )根。", + "options": [], + "answer": "3;4;2", + "solution": "【分析】数一数即可,一个一个地数,数到几就是几。如图:![](images/Pasted%20image%2020260311000506.png)\n【详解】三轮车有3个轮子,小猫有4条腿,一双筷子有2根。", + "knowledge_points": [ + "数一数", + "1~5的认识和读写" + ], + "source": "24-25一年级上·河南郑州·期中" + }, + { + "id": "347", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.94, + "question": "\">\"读作( ),\"<\"读作( ),\"=\"读作( )。", + "options": [], + "answer": "大于;小于;等于", + "solution": "【分析】认识大于、小于、等于三种符号的读法.\n【详解】\">\"读作大于,\"<\"读作小于,\"=\"读作等于.\n例如:2>1读作:2大于1,1<2读作:1小于2,1=1读作:1等于1。", + "knowledge_points": [ + "5以内数的比大小" + ], + "source": "24-25一年级上·河南商丘·期中" + }, + { + "id": "348", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.65, + "question": "5比3多( ),2比4少( )。", + "options": [], + "answer": "2;2", + "solution": "【分析】求一个数比另一个数多多少用减法计算;求一个数比另一个数少多少用减法计算.\n【详解】5-3=2;4-2=2;5比3多2,2比4少2。", + "knowledge_points": [ + "5以内数的减法" + ], + "source": "24-25一年级上·河南商丘·期中" + }, + { + "id": "349", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "5-5=( ),两个同样的数相减得( )。", + "options": [], + "answer": "0;0", + "solution": "【分析】5-5表示从5里面去掉5,结果是0.5和5同样大,则两个同样大的数相减结果是0.\n【详解】5-5=0,两个同样的数相减得0。", + "knowledge_points": [ + "有关0的加减法" + ], + "source": "24-25一年级上·广东汕头·期中" + }, + { + "id": "350", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "比3多1的数是( ),比5少2的数是( )。", + "options": [], + "answer": "4;3", + "solution": "【分析】求比一个数多几的数是多少,用这个数+多的数计算;求比一个数少几的数是多少,用这个数-少的数计算.\n【详解】3+1=4;5-2=3比3多1的数是4,比5少2的数是3。", + "knowledge_points": [ + "5以内数的加法", + "5以内数的减法" + ], + "source": "24-25一年级上·吉林白山·期中" + }, + { + "id": "351", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "4添上1是( );5去掉1是( );和4相邻的两个数是( )和( );2和4中间的数是( )。", + "options": [], + "answer": "5;4;3;5;3", + "solution": "【分析】4添上1是几,就是4加上1等于几;5去掉1是几,就是5减去1等于几;一个一个地数一数,即可知道和4相邻的两个数分别是几,以及可知2和4的中间的数是几;据此解决.\n【详解】4+1=5;5-1=4;一个一个地数一数:1,2,3,4,5;即,4添上1是5;5去掉1是4;和4相邻的两个数是3和5;2和4中间的数是3。", + "knowledge_points": [ + "5以内数的加法", + "5以内数的减法", + "5以内数的排序" + ], + "source": "24-25一年级上·湖南岳阳·期中" + }, + { + "id": "352", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.65, + "question": "把5枝花插在两个花瓶里,有( )种插法。", + "options": [], + "answer": "4", + "solution": "【分析】根据5的分与合,5可以分成1和4,2和3,3和2,4和1这4种情况进行插花.\n【详解】把5枝花插在两个花瓶里,有4种插法。", + "knowledge_points": [ + "5以内数的分与合(组成)" + ], + "source": "24-25一年级上·全国·单元测试" + }, + { + "id": "353", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "( )添上1后是5。", + "options": [], + "answer": "4", + "solution": "【分析】求几添上1后是5,就是求几加1等于5,用5减1,求出差,就是要求的数.\n【详解】5-1=4即,4添上1后是5。", + "knowledge_points": [ + "5以内数的减法" + ], + "source": "24-25一年级上·江苏·单元测试" + }, + { + "id": "354", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "一个数与它本身相加的和是4,这个数是( )。", + "options": [], + "answer": "2", + "solution": "【分析】4可以分成2和2,则,2+2=4,据此解决.\n【详解】由题意分析得:2+2=4一个数与它本身相加的和是4,这个数是2。", + "knowledge_points": [ + "5以内数的分与合(组成)", + "5以内数的加法" + ], + "source": "24-25一年级上·山东·课后作业" + }, + { + "id": "355", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "一个也没有用( )来表示。一个星期有( )天。", + "options": [], + "answer": "0;7", + "solution": "【分析】0表示一个也没有,一周有7天,据此解答.\n【详解】由分析可得:一个也没有用0来表示。一个星期有7天.", + "knowledge_points": [ + "0的认识和读写", + "6,7的认识和读写" + ], + "source": "24-25一年级上·江苏·课后作业" + }, + { + "id": "356", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "在0,3,2,1,4,5中,小于1的数是( )。", + "options": [], + "answer": "0", + "solution": "【分析】按照整数大小比较的方法,排在后面的数比排在前面的数大即可得出答案.\n【详解】按照从小到大排列:0<1<2<3<4<5在0,3,2,1,4,5中,小于1的数是0。", + "knowledge_points": [ + "5以内数的比大小" + ], + "source": "24-25一年级上·辽宁·课后作业" + }, + { + "id": "357", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "判断题", + "difficulty": 0.85, + "question": "第5和5表示的含义一样。", + "options": [], + "answer": "×", + "solution": "【分析】第几表示排的顺序,几表示数量的多少,意义是不相同的.\n【详解】由分析可得:第5和5表示的含义不一样,则原题说法错误。故答案为: ×", + "knowledge_points": [ + "认识几和第几", + "1~5的认识和读写" + ], + "source": "24-25一年级上·湖北孝感·期中" + }, + { + "id": "358", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "判断题", + "difficulty": 0.85, + "question": "4只能分成2和2。", + "options": [], + "answer": "×", + "solution": "【分析】根据数的分与合,4可以分成0和4,1和3,2和2,据此解答.\n【详解】4可以分成2和2,但不是只能分成2和2。原题说法错误。故答案为: ×", + "knowledge_points": [ + "5以内数的分与合(组成)" + ], + "source": "24-25一年级上·贵州铜仁·期中" + }, + { + "id": "359", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "判断题", + "difficulty": 0.85, + "question": "2-2=0读作:2加2等于0。", + "options": [], + "answer": "×", + "solution": "【分析】读减法算式时,依次从左往右读,\"-\"读作减,\"=\"读作等于,数字直接读出来.\n【详解】2-2=0读作:2减2等于0。原题说法错误。故答案为: ×", + "knowledge_points": [ + "有关0的加减法", + "5以内数的减法" + ], + "source": "24-25一年级上·贵州铜仁·期中" + }, + { + "id": "360", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "判断题", + "difficulty": 0.85, + "question": "姐姐比妹妹大5岁,也就是妹妹比姐姐小5岁。", + "options": [], + "answer": "√", + "solution": "【分析】一个数比另一个数大几,也就是另一个数比这个数小几,由此解答.\n【详解】由分析可知,姐姐比妹妹大5岁,也就是妹妹比姐姐小5岁。原题说法正确。故答案为:√", + "knowledge_points": [ + "比较物体大小", + "5以内数的比大小" + ], + "source": "24-25一年级上·全国·单元测试" + }, + { + "id": "361", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "判断题", + "difficulty": 0.65, + "question": "树上有5只小鸟,一声枪响,树上还剩4只小鸟。", + "options": [], + "answer": "×", + "solution": "【分析】树上有5只小鸟,一声枪响,树上的小鸟都惊飞了,所以树上没有小鸟了,据此解答.\n【详解】树上最后应该没有小鸟了,此说法错误。故答案为: ×", + "knowledge_points": [ + "5以内数的减法" + ], + "source": "24-25一年级上·江苏·单元测试" + }, + { + "id": "362", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "判断题", + "difficulty": 0.85, + "question": "比4大1的数是3,比4小1的数是5。", + "options": [], + "answer": "×", + "solution": "【分析】求比一个数大几的数是多少,用加法计算;求比一个数小几的数是多少,用减法计算.\n【详解】4+1=5;4-1=3即,比4大1的数是5,比4小1的数是3;原说法错误。故答案为: ×", + "knowledge_points": [ + "5以内数的加法", + "5以内数的减法" + ], + "source": "24-25一年级上·江苏·单元测试" + }, + { + "id": "363", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "判断题", + "difficulty": 0.85, + "question": "比4小的数只有1。", + "options": [], + "answer": "×", + "solution": "【分析】5以内数从小到大为:0<1<2<3<4<5,由此找出比4小的数即可.\n【详解】由分析可知,比4小的数有0,1,2,3,原题说法错误。故答案为: ×", + "knowledge_points": [ + "5以内数的比大小" + ], + "source": "24-25一年级上·全国·单元测试" + }, + { + "id": "364", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "判断题", + "difficulty": 0.85, + "question": "3只小猫在河边钓鱼,钓的鱼的条数和它们的只数同样多,鱼有3条。", + "options": [], + "answer": "√", + "solution": "【分析】根据题意,鱼的数量和小猫的数量同样多,即数量都是3,由此解答.\n【详解】3=3;3只小猫在河边钓鱼,钓的鱼的条数和它们的只数同样多,鱼有3条。原题说法正确。故答案为:√", + "knowledge_points": [ + "5以内数的比大小" + ], + "source": "24-25一年级上·山东·课后作业" + }, + { + "id": "365", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "判断题", + "difficulty": 0.85, + "question": "冰箱里有5瓶牛奶,2个面包,牛奶比面包多。", + "options": [], + "answer": "√", + "solution": "【分析】根据题意,比较牛奶和面包的数量即可。5以内数从小到大为1<2<3<4<5,由此比较.\n【详解】5>2冰箱里有5瓶牛奶,2个面包,牛奶比面包多。原题说法正确。故答案为:√", + "knowledge_points": [ + "5以内数的比大小" + ], + "source": "24-25一年级上·山东·课后作业" + }, + { + "id": "366", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "判断题", + "difficulty": 0.85, + "question": "小萌画了3个五角星,依依画的比小萌少,依依画了4个。", + "options": [], + "answer": "×", + "solution": "【分析】小萌画了3个五角星,依依画的比小萌少,也就是依依画的数量比3个要少(画了2个或1个);3<4,而题中说依依画了4个的说法是错误的;据此解决.\n【详解】由题意分析得:3<4即,小萌画了3个五角星,依依画的比小萌少,依依画了4个;此说法错误。故答案为: ×", + "knowledge_points": [ + "5以内数的比大小" + ], + "source": "24-25一年级上·山东·课后作业" + }, + { + "id": "367", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "判断题", + "difficulty": 0.85, + "question": "院子里有3只小狗,小灵有4根骨头,每只小狗啃一根,不够。", + "options": [], + "answer": "×", + "solution": "【分析】根据题意,比较小狗和骨头的数量,骨头的数量大于或等于小狗的数量就够,小于就不够。5以内数从小到大为1<2<3<4<5,由此比较.\n【详解】4>3,骨头数量大于小狗数量。每只小狗啃一根,够。原题说法错误。故答案为: ×", + "knowledge_points": [ + "5以内数的比大小" + ], + "source": "24-25一年级上·山东·课后作业" + }, + { + "id": "368", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "判断题", + "difficulty": 0.85, + "question": "桌子上有5个苹果,4个梨,苹果比梨多。", + "options": [], + "answer": "√", + "solution": "【分析】5以内数从小到大为1<2<3<4<5,由此比较.\n【详解】5>4苹果比梨多,原题说法正确。故答案为:√", + "knowledge_points": [ + "5以内数的比大小" + ], + "source": "24-25一年级上·山东·课后作业" + }, + { + "id": "369", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图填空。![](images/Pasted%20image%2020260311000726.png)", + "options": [], + "answer": "1+3=4", + "solution": "【分析】左右两边的数量相加即可求出一共有多少个.\n【详解】1+3=4", + "knowledge_points": [ + "图文问题", + "5以内数的加法" + ], + "source": "24-25一年级上·河南周口·期末" + }, + { + "id": "370", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式计算。![](images/Pasted%20image%2020260311000736.png)", + "options": [], + "answer": "2+3=5", + "solution": "【分析】把左边的蜻蜓数量与右边的数量加起来,求出和,就是蜻蜓的总数量.\n【详解】由题意分析得:2+3=5", + "knowledge_points": [ + "图文问题", + "5以内数的加法" + ], + "source": "24-25一年级上·河南周口·期末" + }, + { + "id": "371", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式并计算。![](images/Pasted%20image%2020260311000746.png)", + "options": [], + "answer": "2+2=4", + "solution": "【分析】左右两边的数量相加即可求出一共有多少条.\n【详解】2+2=4(条)\n一共有4条鱼。", + "knowledge_points": [ + "图文问题", + "5以内数的加法" + ], + "source": "24-25一年级上·陕西西安·期末" + }, + { + "id": "372", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式并计算。![](images/Pasted%20image%2020260311000752.png)", + "options": [], + "answer": "3+1=4", + "solution": "【分析】由图意可知,左边有3个苹果,右边有1个苹果,求一共有几个苹果,用加法列式计算即可.\n【详解】由题意分析得:\n3+1=4(个)", + "knowledge_points": [ + "图文问题", + "5以内数的加法" + ], + "source": "24-25一年级上·全国·假期作业" + }, + { + "id": "373", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式计算。![](images/Pasted%20image%2020260311000805.png)", + "options": [], + "answer": "3+2=5", + "solution": "【分析】左右两边的个数相加即可求出一共有多少个.\n【详解】3+2=5(个)一共有5个苹果。", + "knowledge_points": [ + "图文问题", + "5以内数的加法" + ], + "source": "24-25一年级上·河南周口·期中" + }, + { + "id": "374", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式计算。![](images/Pasted%20image%2020260311000822.png)", + "options": [], + "answer": "3+1=4", + "solution": "【分析】左边3只,右边1只,左右两边相加即可求出一共有多少只.\n【详解】3+1=4(只)", + "knowledge_points": [ + "图文问题", + "5以内数的加法" + ], + "source": "24-25一年级上·福建福州·期中" + }, + { + "id": "375", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式计算。![](images/Pasted%20image%2020260311000831.png)", + "options": [], + "answer": "1+2=3", + "solution": "【分析】由图可知,左边有1个冰淇淋,右边有2个冰淇淋,求一共有几个冰淇淋,根据加法的意义,用左边冰淇淋的数量加上右边冰淇淋的数量即可.\n【详解】1+2=3(个)所以一共有3个冰淇淋。", + "knowledge_points": [ + "图文问题", + "5以内数的加法" + ], + "source": "24-25一年级上·河南驻马店·期中" + }, + { + "id": "376", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图写算式。![](images/Pasted%20image%2020260311000840.png)", + "options": [], + "answer": "5-2=3", + "solution": "【分析】根据图片可知:一共有5只燕子,飞走了2只,还剩几只。用共有的只数减去飞走的数量即可.\n【详解】5-2=3(只)则还剩3只。", + "knowledge_points": [ + "图文问题", + "5以内数的减法" + ], + "source": "24-25一年级上·甘肃平凉·期中" + }, + { + "id": "377", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式计算。![](images/Pasted%20image%2020260311000848.png)", + "options": [], + "answer": "2+3=5", + "solution": "【分析】左边2只小狗,右边3只,左右两边相加即可求出一共有多少只.\n【详解】2+3=5(只)", + "knowledge_points": [ + "图文问题", + "5以内数的加法" + ], + "source": "2024一年级上·全国·专题练习" + }, + { + "id": "378", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式并计算。![](images/Pasted%20image%2020260311000854.png)", + "options": [], + "answer": "3+1=4", + "solution": "【分析】由图可知,左边有3个足球,右边有1个足球,求一共有多少个足球,根据加法的意义,用左边足球的数量加上右边足球的数量即可.\n【详解】3+1=4(个)\n所以一共有4个足球。", + "knowledge_points": [ + "图文问题", + "5以内数的加法" + ], + "source": "24-25一年级上·陕西汉中·期中" + }, + { + "id": "379", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式计算。![](images/Pasted%20image%2020260311000901.png)", + "options": [], + "answer": "2+3=5", + "solution": "【分析】左边2条,右边3条,左右两边相加即可求出一共多少条.\n【详解】2+3=5(条)", + "knowledge_points": [ + "图文问题", + "5以内数的加法" + ], + "source": "24-25一年级上·河北保定·期中" + }, + { + "id": "380", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式计算。![](images/Pasted%20image%2020260311000910.png)", + "options": [], + "answer": "3+2=5", + "solution": "【分析】由图可知,原来荷叶上有3只青蛙,又来了2只,求一共有多少只青蛙,根据加法的意义,用荷叶上原来有的青蛙的数量加上又来的青蛙的数量即可.\n【详解】3+2=5(只)所以一共有5只青蛙。", + "knowledge_points": [ + "图文问题", + "5以内数的加法" + ], + "source": "24-25一年级上·湖北黄冈·期中" + }, + { + "id": "381", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式计算。![](images/Pasted%20image%2020260311000925.png)", + "options": [], + "answer": "2;5", + "solution": "【分析】原有3只小鸟,又飞来了2只,求现在一共有几只小鸟,用加法计算,即原有的数量+又飞来的数量=现在一共的数量.\n【详解】3+2=5(只)现在一共有5只小鸟。", + "knowledge_points": [ + "图文问题", + "5以内数的加法" + ], + "source": "24-25一年级上·全国·课后作业" + }, + { + "id": "382", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式。![](images/Pasted%20image%2020260311000936.png)", + "options": [], + "answer": "2+1=3", + "solution": "【分析】左边有2只熊猫,右边有1只熊猫,求一共有几只熊猫,用加法计算,即左边的数量+右边的数量=总数量.\n【详解】2+1=3(只)\n一共有3只熊猫。", + "knowledge_points": [ + "图文问题", + "5以内数的加法" + ], + "source": "24-25一年级上·全国·单元测试" + }, + { + "id": "383", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式.\n![](images/Pasted%20image%2020260311000953.png)", + "options": [], + "answer": "4-1=3", + "solution": "【分析】一共有4个桃子,用虚线框起来1个表示去掉1个,求还剩几个桃子,用减法计算,即总数量-去掉的数量=还剩的数量.\n【详解】4-1=3(个)\n还剩3个桃子。", + "knowledge_points": [ + "图文问题", + "5以内数的减法" + ], + "source": "24-25一年级上·全国·单元测试" + }, + { + "id": "384", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式。![](images/Pasted%20image%2020260311001004.png)", + "options": [], + "answer": "3+2=5", + "solution": "【分析】左边3只,右边2只,左右两边相加即可求出一共多少只.\n【详解】3+2=5(只)一共5只。", + "knowledge_points": [ + "图文问题", + "5以内数的加法" + ], + "source": "24-25一年级上·广东江门·期中" + }, + { + "id": "385", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式计算。![](images/Pasted%20image%2020260311001013.png)", + "options": [], + "answer": "3+1=4", + "solution": "【分析】左边有3支铅笔,右边有1支铅笔,求一共有多少支铅笔,用加法计算,即左边的数量+右边的数量=总数量.\n【详解】3+1=4(支)一共有4支铅笔。", + "knowledge_points": [ + "图文问题", + "5以内数的加法" + ], + "source": "24-25一年级上·云南曲靖·期中" + }, + { + "id": "386", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式计算。![](images/Pasted%20image%2020260311001021.png)", + "options": [], + "answer": "4-2=2", + "solution": "【分析】根据图片可知:一共有4朵花,划去了2朵,还有几朵,用减法计算.\n【详解】4-2=2(朵)还有2朵花。", + "knowledge_points": [ + "5以内数的减法", + "图文问题" + ], + "source": "24-25一年级上·河南郑州·期中" + }, + { + "id": "387", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "小红有5支铅笔,小明有3支铅笔,小明添上( )支铅笔就和小红一样多.\n![](images/Pasted%20image%2020260311001039.png)", + "options": [], + "answer": "2", + "solution": "【分析】小明的铅笔要和小红一样多,需要再添上的支数=小红有铅笔的支数-小明有铅笔的支数.\n【详解】5-3=2(支)答:小明添上2支铅笔就和小红一样多。", + "knowledge_points": [ + "5以内数的减法", + "\"一样多\"问题" + ], + "source": "24-25一年级上·浙江杭州·期中" + }, + { + "id": "388", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "树上原来有5个梨,摘了3个,还剩几个。\n![](images/Pasted%20image%2020260311001048.png)", + "options": [], + "answer": "5-3=2;2个", + "solution": "【分析】求还剩几个,用减法计算,即梨的总数量-摘了的数量=还剩的数量.\n【详解】5-3=2(个)答:还剩2个。", + "knowledge_points": [ + "5以内数的减法" + ], + "source": "24-25一年级上·山东济宁·期中" + }, + { + "id": "389", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "张明和他的4个小伙伴排成一排练投球,从前面数,张明排第4,他的后面还有几个小伙伴。", + "options": [], + "answer": "1个", + "solution": "【分析】根据题意,先用加法计算出一共有几个人,再用总人数减去从前面排到张明的人数,就是张明后面的人数.\n【详解】1+4=5(个)5-4=1(个)答:他的后面还有1个小伙伴。", + "knowledge_points": [ + "5以内数的加法", + "5以内数的减法" + ], + "source": "24-25一年级上·全国·单元测试" + }, + { + "id": "390", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "小猫抓老鼠,猫哥哥抓了2只老鼠,猫弟弟抓了3只老鼠,它们一共抓了多少只老鼠。", + "options": [], + "answer": "5只", + "solution": "【分析】求一共抓了几只老鼠,用加法计算,即猫哥哥抓的数量+猫弟弟抓的数量=它们一共抓的数量.\n【详解】2+3=5(只)答:它们一共抓了5只老鼠。", + "knowledge_points": [ + "5以内数的加法" + ], + "source": "24-25一年级上·河南商丘·期中" + }, + { + "id": "391", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "车上原来有3人,又上车1人,车上现在有几人。", + "options": [], + "answer": "4人", + "solution": "【分析】根据题意可知,车上有3人,又上车1人,相加即可得出车上现在有几人.\n【详解】根据分析可得:3+1=4(人)答:车上现在有4人。", + "knowledge_points": [ + "5以内数的加法" + ], + "source": "24-25一年级上·河南商丘·期中" + }, + { + "id": "392", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "树上有5只小鸟,飞走了4只,还剩几只。", + "options": [], + "answer": "1只", + "solution": "【分析】用原有的只数减飞走的只数即可求出还剩几只.\n【详解】5-4=1(只)答:还剩1只。", + "knowledge_points": [ + "5以内数的减法" + ], + "source": "24-25一年级上·河南商丘·期中" + }, + { + "id": "393", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "一共有( )把,拿走了( )把,墙角还剩( )把。![](images/Pasted%20image%2020260311001123.png)", + "options": [], + "answer": "5;1;4;5-1=4;4把", + "solution": "【分析】由图可知,一共有5把铁锹,拿走了1把,墙角还剩4把,列算式时,用总数量-拿走的数量=还剩的数量.\n【详解】一共有5把,拿走了1把,墙角还剩4把。5-1=4(把)答:墙角还剩4把。", + "knowledge_points": [ + "图文问题", + "5以内数的减法" + ], + "source": "24-25一年级上·山东菏泽·期中" + }, + { + "id": "394", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "有五个皮球,小平拿走了五个,还剩多少个。", + "options": [], + "answer": "0个", + "solution": "【分析】用原有皮球的个数减去小平拿走的个数,求出差,就是还剩的个数.\n【详解】由题意分析得:5-5=0(个)答:还剩0个。", + "knowledge_points": [ + "5以内数的减法" + ], + "source": "24-25一年级上·辽宁·课后作业" + }, + { + "id": "395", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "小芳去图书馆借书,图书馆有4本故事书,被小芳借走了4本,图书馆还剩多少故事书。", + "options": [], + "answer": "0本", + "solution": "【分析】用图书馆原有故事书的本数减去小芳借走的本数,求出差,就是还剩故事书的本数.\n【详解】4-4=0(本)答:图书馆还剩0本故事书。", + "knowledge_points": [ + "5以内数的减法" + ], + "source": "24-25一年级上·辽宁·课后作业" + }, + { + "id": "396", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "小明的笔有三根,老师奖励了小明两根,小明有多少根笔。", + "options": [], + "answer": "5根", + "solution": "【分析】用小明原有笔的数量加上老师奖励笔的数量,就是小明现有笔的数量,根据题中所给的数据进行计算即可.\n【详解】3+2=5(根)答:小明有5根笔。", + "knowledge_points": [ + "5以内数的加法" + ], + "source": "24-25一年级上·辽宁·课后作业" + }, + { + "id": "397", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "荷叶上有4只青蛙,跳入水里3只,现在荷叶上还有多少只青蛙。", + "options": [], + "answer": "1只", + "solution": "【分析】用荷叶上原有青蛙的只数减去跳入水中的只数,即可计算出现在荷叶上还有多少只青蛙.\n【详解】4-3=1(只)答:现在荷叶上还有1只青蛙。", + "knowledge_points": [ + "5以内数的减法" + ], + "source": "24-25一年级上·辽宁·课后作业" + }, + { + "id": "398", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "姐姐有2颗糖,妹妹和姐姐一样多。姐姐和妹妹一共有多少颗糖。", + "options": [], + "answer": "4颗", + "solution": "【分析】根据题意,姐姐有2颗糖,妹妹和姐姐一样多,也有2颗糖,求总数量,根据加法的意义,将姐姐糖的数量和妹妹糖的数量相加即可.\n【详解】2+2=4(颗)答:姐姐和妹妹一共有4颗糖。", + "knowledge_points": [ + "5以内数的加法" + ], + "source": "24-25一年级上·山东·课后作业" + }, + { + "id": "399", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "植树节植树。小丽种了3棵树,小华种了2棵,两人一共种了多少棵树。", + "options": [], + "answer": "5棵", + "solution": "【分析】根据加法的意义,小丽种的数量+小华种的数量=两人一共种的数量.\n【详解】3+2=5(棵)答:两人一共种了5棵树。", + "knowledge_points": [ + "5以内数的加法" + ], + "source": "24-25一年级上·山东·课后作业" + }, + { + "id": "400", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "停车场原来有2辆汽车,又开来了3辆,现在一共有多少辆汽车。", + "options": [], + "answer": "5辆", + "solution": "【分析】现在的汽车数量=原来的汽车数量+又开来的汽车数量,据此列式解决即可.\n【详解】2+3=5(辆)答:现在一共有5辆汽车。", + "knowledge_points": [ + "5以内数的加法" + ], + "source": "24-25一年级上·江苏·课前预习" + }, + { + "id": "401", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "计算5-2时,下面计算方法错误的是( )。", + "options": [ + "A. 5可以分成2和3,5-2=3", + "B. 画出5个◯,去掉2个◯,还剩3个◯", + "C. 从5倒着数,5,4,还剩4", + "D. 想3+2=5,5-2=3" + ], + "answer": "C", + "solution": "【分析】计算5-2时,可以根据5的分与合计算;也可以采用画图的方式计算;或者根据几和2相加得5计算;或者从5倒着数2个数,数到几结果就是几.\n【详解】A。5可以分成2和3,即5-2=3,方法正确;B。![](images/Pasted%20image%2020260311002025.png),即5-2=3,方法正确;C。从5倒着数,4,3,还剩3,原方法错误;D。3+2=5,则5-2=3,方法正确。所以计算方法错误的是从5倒着数,5,4,还剩4。故答案为:C", + "knowledge_points": [ + "5以内数的减法" + ], + "source": "24-25一年级上·福建龙岩·期中" + }, + { + "id": "402", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "青青有4支勾线笔,给了弟弟1支后,她还有( )支勾线笔。", + "options": [ + "A. 5", + "B. 4", + "C. 3" + ], + "answer": "C", + "solution": "【分析】用青青原有勾线笔的支数减去送给弟弟的支数,即可计算出她还有多少支勾线笔.\n【详解】由题意分析得:4-1=3(支)即,她还有3支勾线笔。故答案为:C", + "knowledge_points": [ + "5以内数的减法" + ], + "source": "24-25一年级上·辽宁·课前预习" + }, + { + "id": "403", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.65, + "question": "下面关于\"0\"的说法错误的是( )。", + "options": [ + "A. 0可以表示\"没有\"", + "B. 0可以表示\"终点\"", + "C. 0可以用来\"占位\"", + "D. 0可以表示\"分界\"" + ], + "answer": "B", + "solution": "【分析】根据\"0\"的认识知识可知,0可以表示\"没有\",0可以用来\"占位\",0可以表示\"分界\",据此解答即可.\n【详解】A。0可以表示\"没有\",说法正确,不符合题意;B。0可以表示\"起点\",所以原选项说法错误,符合题意;C。0可以用来\"占位\",说法正确,不符合题意;D。0可以表示\"分界\",说法正确,不符合题意。故答案为:B", + "knowledge_points": [ + "有关0的加减法" + ], + "source": "24-25一年级上·辽宁·课前预习" + }, + { + "id": "404", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "妈妈买了5根香蕉,被爸爸吃掉2根,请问还剩下几根香蕉呢。请你选一选吧( )", + "options": [ + "A. 2", + "B. 3", + "C. 4" + ], + "answer": "B", + "solution": "【分析】用妈妈买来香蕉的总数量减去爸爸吃掉的数量,求出差,即可解决.\n【详解】5-2=3(根)即,还剩下3根香蕉。故答案为:B", + "knowledge_points": [ + "5以内数的减法" + ], + "source": "23-24一年级下·全国·课前预习" + }, + { + "id": "405", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "花布上本来有5颗星星,被小狮子弄丢了一块,请你想一想,丢了的那块花布上有几颗星星呢。( )\n\n![](images/Pasted%20image%2020260311002550.png)", + "options": [ + "A. 2", + "B. 3", + "C. 4" + ], + "answer": "A", + "solution": "【分析】用星星的总数量减去没丢的这块花布上的星星数量,求出差,即可解决.\n【详解】5-3=2(颗)即,丢了的那块花布上有2颗星星。故答案为:A", + "knowledge_points": [ + "5以内数的减法" + ], + "source": "23-24一年级下·全国·课前预习" + }, + { + "id": "406", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "![](images/Pasted%20image%2020260311002609.png),从右数,![](images/Pasted%20image%2020260311002616.png)排( )。", + "options": [ + "A. 第1", + "B. 第5", + "C. 第3" + ], + "answer": "B", + "solution": "【分析】一般情况下写字的手的一边是右边,和右相对的就是左边。从右边数就是从妈妈开始数,爸爸排第5,据此解答.\n【详解】由题意分析得:![](images/Pasted%20image%2020260311002609.png),从右数,![](images/Pasted%20image%2020260311002616.png)排第5。故答案为:B", + "knowledge_points": [ + "左,右位置", + "认识几和第几" + ], + "source": "23-24一年级下·全国·课前预习" + }, + { + "id": "407", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "图中盘子中的数可以表示为( ).\n\n![](images/Pasted%20image%2020260311002653.png)", + "options": [ + "A. 0", + "B. 1", + "C. 2" + ], + "answer": "A", + "solution": "【分析】根据0的意义,0既可以表示\"什么也没有\",又可以表示\"起点\"。图中盘子里什么也没有,所以用数字0表示.\n【详解】由题意分析得:图中盘子中的数可以表示为0。故答案为:A", + "knowledge_points": [ + "0的认识和读写" + ], + "source": "23-24一年级下·全国·课前预习" + }, + { + "id": "408", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "5只小鸟飞进两个鸟笼里,两个鸟笼里鸟的数量( )一样多。", + "options": [ + "A. 能", + "B. 不能", + "C. 不能确定" + ], + "answer": "B", + "solution": "【分析】5可以分成1和4,也可以2和3;故,5只小鸟飞进两个鸟笼里,两个鸟笼里鸟的数量分别是1只和4只,或2只和3只;也就是两个鸟笼里鸟的数量不能一样多.\n【详解】由题意分析得:5只小鸟飞进两个鸟笼里,两个鸟笼里鸟的数量不能一样多。故答案为:B", + "knowledge_points": [ + "5以内数的分与合(组成)" + ], + "source": "22-23一年级上·新疆喀什·期末" + }, + { + "id": "409", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "下列哪一组数,可以列出一道加法算式。( )", + "options": [ + "A. 5,2,1", + "B. 2,7,1", + "C. 5,2,7" + ], + "answer": "C", + "solution": "【分析】用较小的两个数相加,看看得数是否是最大的那个数,是就可以,不是就不可以.\n【详解】A。1+2=3,不是,不可以;B。2+1=3,不是,不可以;C。5+2=7,是,可以。用5,2,7可以列出一道加法算式。故答案为:C", + "knowledge_points": [ + "5以内数的加法", + "7的加减法" + ], + "source": "23-24一年级上·河南三门峡·期末" + }, + { + "id": "410", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "李老师给小丽和佳佳每人8颗糖。小丽吃了4颗,佳佳吃了3颗,剩下的糖果是( )。", + "options": [ + "A. 小丽比佳佳多", + "B. 佳佳比小丽多", + "C. 小丽和佳佳一样多" + ], + "answer": "B", + "solution": "【分析】两人同样多的糖果,吃了越多,剩下的越少,吃了越少,剩下的越多;据此解决.\n【详解】由题意分析得:4>3即,小丽吃了的糖果比佳佳多;故,剩下的糖果是佳佳比小丽多。故答案为:B", + "knowledge_points": [ + "5以内数的比大小" + ], + "source": "23-24一年级上·山东菏泽·期末" + }, + { + "id": "411", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "数一数,下图中有( )个小正方体.\n\n![](images/Pasted%20image%2020260311002812.png)", + "options": [ + "A. 4", + "B. 5", + "C. 6" + ], + "answer": "B", + "solution": "【分析】题中上层有2个小正方体,下层有3个小正方体,上层的数量+下层的数量=总数量.\n【详解】2+3=5(个)下图中有5个小正方体。![](images/Pasted%20image%2020260311002816.png)故答案为:B", + "knowledge_points": [ + "5以内数的加法" + ], + "source": "23-24一年级上·广西桂林·期末" + }, + { + "id": "412", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "4不能分成( )。", + "options": [ + "A. 1和3", + "B. 2和2", + "C. 2和3" + ], + "answer": "C", + "solution": "【分析】4能分成1和3,也能分成2和2,4不能再分成其它的;据此解决.\n【详解】A。4能分成1和3;B。4能分成2和2;C。4不能分成2和3;故答案为:C", + "knowledge_points": [ + "5以内数的分与合(组成)" + ], + "source": "23-24一年级上·贵州黔西·期末" + }, + { + "id": "413", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "2与3的和是( )。", + "options": [ + "A. 6", + "B. 5", + "C. 1" + ], + "answer": "B", + "solution": "【分析】求两个数的和,用加法列式计算.\n【详解】2+3=5故,2与3的和是5。故答案为:B", + "knowledge_points": [ + "5以内数的加法" + ], + "source": "23-24二年级上·吉林长春·期末" + }, + { + "id": "414", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.94, + "question": "( )比3多2。", + "options": [ + "A. 1", + "B. 5", + "C. 6" + ], + "answer": "B", + "solution": "【分析】根据加法的意义,求比3多2的数是多少,用3加2计算.\n【详解】3+2=5,5比3多2。故答案为:B", + "knowledge_points": [ + "5以内数的加法" + ], + "source": "23-24一年级上·河南周口·期末" + }, + { + "id": "415", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "7个小朋友站成一排,从左往右数小华是第5个,从右往左数小华是( )。", + "options": [ + "A. 第5个", + "B. 第2个", + "C. 第3个" + ], + "answer": "C", + "solution": "【分析】根据题意,先求出小华右边的人数,再根据从右往左数小华第几=小华右边的人数+1(小华),即可解答.\n【详解】7-5=2(人)2+1=3(人)所以从右往左数小华是第3个。故答案为:C", + "knowledge_points": [ + "5以内数的加法", + "7的加减法" + ], + "source": "22-23一年级上·甘肃天水·期末" + }, + { + "id": "416", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "我可以由两个相同的数合成,我可以是( )。", + "options": [ + "A. 5", + "B. 6", + "C. 7" + ], + "answer": "B", + "solution": "【分析】熟练掌握10以内数的分与合,5可以分成1和4,2和3,3和2,4和1;6可以分成1和5,2和4,3和3,4和2,5和1;7可以分成1和6,2和5,3和4,4和3,5和2,6和1,据此解答.\n【详解】根据分析:我可以由两个相同的数合成,我可以是(6)。故答案为:B", + "knowledge_points": [ + "6,7的分与合(组成)", + "5以内数的分与合(组成)" + ], + "source": "23-24一年级上·河南南阳·期中" + }, + { + "id": "417", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "游乐场售票处一共有5个人在排队买票,小明排在第5,这两个5表示的意思( )。", + "options": [ + "A. 一样", + "B. 不一样" + ], + "answer": "B", + "solution": "【分析】前面的5说的是一共有5个人,后面的5说的是第5人,表示的是1个人,所以意思不一样.\n【详解】游乐场售票处一共有5个人在排队买票,小明排在第5,这两个5表示的意思不一样。故答案为:B", + "knowledge_points": [ + "1~5的认识和读写", + "认识几和第几" + ], + "source": "23-24一年级上·河南南阳·期中" + }, + { + "id": "418", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "比1大比4小的数有( )个。", + "options": [ + "A. 2", + "B. 3", + "C. 4" + ], + "answer": "A", + "solution": "【分析】比1大比4小的数有2和3,据此解答.\n【详解】比1大比4小的数有2个。故答案为:A", + "knowledge_points": [ + "5以内数的比大小" + ], + "source": "23-24一年级上·甘肃陇南·期中" + }, + { + "id": "419", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "和4相邻的数是( )。", + "options": [ + "A. 1和3", + "B. 2和3", + "C. 3和5" + ], + "answer": "C", + "solution": "【分析】5以内数的从小到大顺序为:1,2,3,4,5。由此找到结果.\n【详解】A。1和3是2的相邻数;B。2和3相邻;C。3和5是4的相邻数。和4相邻的数是3和5。故答案为:C", + "knowledge_points": [ + "5以内数的排序" + ], + "source": "23-24一年级上·甘肃陇南·期中" + }, + { + "id": "420", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.94, + "question": "老猎人在林子里开了一枪,鸟惊飞了,树上还有( )只鸟。", + "options": [ + "A. 0", + "B. 4", + "C. 3", + "D. 5" + ], + "answer": "A", + "solution": "【分析】鸟惊飞了,树上没有鸟了,用数字0表示,即可解答.\n【详解】鸟惊飞了,树上有0只鸟。故答案为:A", + "knowledge_points": [ + "0的认识和读写" + ], + "source": "2023一年级上·辽宁·专题练习" + }, + { + "id": "421", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.94, + "question": "2+2的计算结果是( )。", + "options": [ + "A. 3", + "B. 5", + "C. 4" + ], + "answer": "C", + "solution": "【分析】根据加数+加数=和,结合10以内加法运算进行解答即可.\n【详解】2+2=4,所以2+2的计算结果是4。故答案为:C", + "knowledge_points": [ + "5以内数的加法" + ], + "source": "2023一年级上·辽宁·专题练习" + }, + { + "id": "422", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.94, + "question": "\"5○5=0\",在○里应填的运算符号是( )。", + "options": [ + "A. +", + "B. -", + "C. ![](images/Pasted%20image%2020260311005002.png)" + ], + "answer": "B", + "solution": "【分析】根据10以内加法的运算法则选择合适的运算符号进行填空即可.\n【详解】5-5=0,所以○里应填的运算符号是\"-\"。故答案为:B", + "knowledge_points": [ + "5以内数的减法" + ], + "source": "23-24一年级上·四川·课后作业" + }, + { + "id": "423", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.94, + "question": "0和任何数相乘都( ),任何数减0都( )。", + "options": [ + "A. 得0;得任何数", + "B. 得任何数;得0", + "C. 得1;得0", + "D. 无法确定结果" + ], + "answer": "A", + "solution": "【分析】根据0在乘法和减法中的特性,直接即可求解.\n【详解】0和任何数相乘都得0,任何数减0都得任何数。故答案为:A", + "knowledge_points": [ + "有关0的加减法" + ], + "source": "21-22三年级上·辽宁抚顺·期末" + }, + { + "id": "424", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.94, + "question": "一个都没有写作( )。", + "options": [ + "A. 10", + "B. 1", + "C. 0" + ], + "answer": "C", + "solution": "【分析】一个都没有就是零,写作\"0\",据此解答.\n【详解】一个都没有写作0。故答案为:C", + "knowledge_points": [ + "0的认识和读写" + ], + "source": "23-24一年级上·山东·单元测试" + }, + { + "id": "425", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "分一分,合一合.\n\n![](images/Pasted%20image%2020260311003245.png)", + "options": [], + "answer": "2;1;4;2", + "solution": "【分析】5可以分成3和2;3可以分成2和1;1和3合成4;4可以分成2和2;据此解决.\n【详解】由题意分析得:\n\n![](images/Pasted%20image%2020260311003252.png)", + "knowledge_points": [ + "5以内数的分与合(组成)" + ], + "source": "24-25一年级上·全国·单元测试" + }, + { + "id": "426", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "3里面有( )个一。", + "options": [], + "answer": "3", + "solution": "【分析】几个一就是几,例如:2个一是2,1个一是1,3个一是3;据此解答.\n【详解】由分析可知,3里面有3个一。", + "knowledge_points": [ + "20以内数的组成" + ], + "source": "24-25一年级上·河南郑州·期中" + }, + { + "id": "427", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "在方框里填上合适的数.\n\n![](images/Pasted%20image%2020260311003258.png)", + "options": [], + "answer": "5;3;2;4", + "solution": "【分析】根据数的分与合填写即可.\n2和3合起来就是5;2和1合起来就是3;4可以分成2和2;5可以分成1和4,由此解答.\n【详解】由分析填写如下:\n\n![](images/Pasted%20image%2020260311003306.png)", + "knowledge_points": [ + "5以内数的分与合(组成)" + ], + "source": "2024一年级上·全国·专题练习" + }, + { + "id": "428", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.94, + "question": "填一填.\n\n![](images/Pasted%20image%2020260311003312.png)\n\n(1)如果小熊猫排第1,那么小松鼠排第( ),小马排第( ).\n\n(2)如果小乌龟排第1,那么小松鼠排第( ),小马排第( )。", + "options": [], + "answer": "3;4;3;2", + "solution": "【分析】根据题意可知,有两种情况,分别是小熊猫排第一和小乌龟排第一,那就是分别从左右两个方向进行数数,小熊猫排第一是从左往右数,小乌龟排第一是从右往左数。按照方向数一数即可得出答案.\n【详解】(1)小熊猫排第1,从小熊猫开始数,小松鼠排第3,小马排第4;(2)小乌龟排第1,从小乌龟开始数,小松鼠排第3,小马排第2.", + "knowledge_points": [ + "认识几和第几", + "左,右位置", + "数一数" + ], + "source": "24-25一年级上·全国·课后作业" + }, + { + "id": "429", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "3的前一个数是( ),4的后一个数是( )。", + "options": [], + "answer": "2;5", + "solution": "【分析】根据5以内整数的排序,结合题干要求进行解答即可.\n【详解】3的前一个数是2,4的后一个数是5。", + "knowledge_points": [ + "5以内数的排序" + ], + "source": "24-25一年级上·全国·课后作业" + }, + { + "id": "430", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.94, + "question": "4后面的一个数是( );2前面的一个数是( )。", + "options": [], + "answer": "5;1", + "solution": "【分析】根据题意可知,我们按照数字从1往后的顺序进行数数,4后面的数字就是比4大一个数的数字,2前面的数就是比2小一个数的数字,再根据题干即可得出答案.\n【详解】4后面的一个数是5;2前面的一个数是1.", + "knowledge_points": [ + "5以内数的排序" + ], + "source": "24-25一年级上·全国·课后作业" + }, + { + "id": "431", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "在括号里填上合适的数.\n\n( )+2=4\n3-( )=1\n( )+3=4+1", + "options": [], + "answer": "2;2;2", + "solution": "【分析】在加,减法算式中缺少数时,可以用数的分与合来解决.\n□+2=4想4可以分成2和几,4可以分成2和2,所以□里填2;3-□=1想3可以分成几和1,3可以分成2和1,所以□里填2;□+3=4+1计算4+1=5,再想5可以分成3和几,5可以分成3和2,所以□里填2.\n【详解】根据分析可知:2+2=4,所以括号内填2.3-2=1,所以括号内填2.2+3=4+1,所以括号内填2。", + "knowledge_points": [ + "5以内数的加法", + "5以内数的减法" + ], + "source": "24-25一年级上·全国·课后作业" + }, + { + "id": "432", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.65, + "question": "把0,1,2,3,5,6这六个数分别填在下面的□里,使算式成立,每个数只能用一次.\n\n( )+( )=( )+( )=( )-( )", + "options": [], + "answer": "0;5;2;3;6;1", + "solution": "【分析】根据题意,前两个算式是加法,后一个算式是减法,它们的结果相等。这六个数是连续的数,加法可用一个较小的数和一个较大的数相加;减法可用一个较大的数减一个较小的数,由此解答.\n【详解】由分析填写如下:0+5=2+3=6-1", + "knowledge_points": [ + "6的加减法", + "5以内数的加法" + ], + "source": "24-25一年级上·江苏·单元测试" + }, + { + "id": "433", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.65, + "question": "若△+△=8,○-△=3,则○=( ),△=( )。", + "options": [], + "answer": "7;4", + "solution": "【分析】根据第一个算式2个三角形相加得到8,可知一个三角形表示4。根据第二个算式圆-4=3,用3加上三角形表示的4即可求出圆表示的数.\n【详解】△+△=8,则△=4;○-△=3,则○=3+4=7。", + "knowledge_points": [ + "5以内数的加法", + "7的加减法" + ], + "source": "24-25一年级上·江苏·单元测试" + }, + { + "id": "434", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "你知道下面的图形代表几吗。\n\n菱形+爱心=5 爱心+爱心=4\n\n菱形=( ) 爱心=( )", + "options": [], + "answer": "3;2", + "solution": "【分析】已知爱心+爱心=4,根据数的组成,4能分成2和2,所以爱心=2;已知菱形+爱心=5,又知爱心=2,根据数的组成,5能分成2和3,所以菱形=3.\n【详解】由分析可得:菱形+爱心=5 爱心+爱心=4\n\n菱形=( 3 ) 爱心=( 2 )", + "knowledge_points": [ + "5以内数的加法", + "5以内数的减法" + ], + "source": "23-24一年级上·山东·课后作业" + }, + { + "id": "435", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "![](images/Pasted%20image%2020260311003644.png)里有( )个苹果。", + "options": [], + "answer": "0", + "solution": "【分析】盘子里一个苹果也没有,用0表示.\n【详解】![](images/Pasted%20image%2020260311003647.png)里有0个苹果。", + "knowledge_points": [ + "0的认识和读写" + ], + "source": "24-25一年级上·江苏·课前预习" + }, + { + "id": "436", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.65, + "question": "乐乐第一天看了3页书,第二天和第一天看的同样多。乐乐两天一共看了( )页书。", + "options": [], + "answer": "6", + "solution": "【分析】第二天和第一天看的同样多,表示第二天也看了3页。把乐乐两天看的页数相加,即可计算出乐乐两天一共看了多少页书.\n【详解】3+3=6(页),乐乐两天一共看了6页书。", + "knowledge_points": [ + "6的加减法" + ], + "source": "24-25一年级上·辽宁·课前预习" + }, + { + "id": "437", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.65, + "question": "0可以表示( ),可以表示( ),也可以表示( ),还可以表示( )。", + "options": [], + "answer": "一个物体也没有;编号;分界限;起点", + "solution": "【分析】根据0的意义和特性进行解答即可.\n【详解】由题意分析得:0可以表示一个物体也没有,可以表示编号,也可以表示分界限,还可以表示起点。(如下图)\n\n![](images/Pasted%20image%2020260311003711.png)", + "knowledge_points": [ + "0的认识和读写" + ], + "source": "24-25一年级上·辽宁·课前预习" + }, + { + "id": "438", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "小学阶段很多地方用过0,写出两个你对数字0的认识:( ),( )。", + "options": [], + "answer": "0表示没有;0表示起点", + "solution": "【分析】0可以表示一个物体也没有,可以表示编号,也可以表示分界限,还可以表示起点等;据此解决.\n【详解】由题意分析得:小学阶段很多地方用过0,写出两个你对数字0的认识:0表示没有,0是表示起点。(答案不唯一)", + "knowledge_points": [ + "0的认识和读写" + ], + "source": "24-25一年级上·辽宁·课前预习" + }, + { + "id": "439", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "小红和小军同读一本故事书,小红读了4页,小军读了5页。( )剩的多。", + "options": [], + "answer": "小红", + "solution": "【分析】读同一本故事书,说明书的页数是一样的,读的页数越多,剩下的页数就越少,反之,读的页数越少,剩下的页数越多.\n【详解】由题意分析得:4<5,也就是小红读的页数越少,剩下的页数越多。即,小红和小军同读一本故事书,小红读了4页,小军读了5页。小红剩的多。", + "knowledge_points": [ + "5以内数的比大小" + ], + "source": "22-23一年级上·山东济南·期末" + }, + { + "id": "440", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "一共有5条小鱼在池塘里,游走2条,现在有( )条。", + "options": [], + "answer": "3", + "solution": "【分析】用原来的5条减去游走的2条,差就是剩下的条数.\n【详解】5-2=3(条)现在有3条。", + "knowledge_points": [ + "5以内数的减法" + ], + "source": "23-24一年级上·河南驻马店·期末" + }, + { + "id": "441", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "小雪比小云大2岁,小美比小云小3岁,小雪和小美相差( )岁。", + "options": [], + "answer": "5", + "solution": "【分析】根据题意可知,小雪比小云大2岁,小云比小美大3岁,小雪比小云和小美都大,因此小雪比小云大的岁数加上小云比小美大的岁数,就是小雪和小美相差的岁数.\n【详解】2+3=5(岁)小雪比小云大2岁,小美比小云小3岁,小雪和小美相差5岁。", + "knowledge_points": [ + "5以内数的加法" + ], + "source": "23-24二年级上·贵州铜仁·期末" + }, + { + "id": "442", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "小红有7朵花,小丽有3朵花,小红比小丽多( )朵花。小红给小丽( )朵后,两人同样多。", + "options": [], + "answer": "4;2", + "solution": "【分析】求一个数比另一个数多多少,用这个数减另一个数即可;计算出多出来的数量后,再把多出来的数量分成两个相同的数,即将多出来的分出来一半后,两人就一样多了.\n【详解】7-3=4(朵);4可以分成2和2;此时小红有7-2=5(朵);小丽有3+2=5(朵),5=5.\n小红有7朵花,小丽有3朵花,小红比小丽多4朵花。小红给小丽2朵后,两人同样多。", + "knowledge_points": [ + "5以内数的加法", + "7的加减法" + ], + "source": "23-24一年级上·浙江台州·期末" + }, + { + "id": "443", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "两个加数都是6,和是( );被减数和减数都是8,差是( )。", + "options": [], + "answer": "12;0", + "solution": "【分析】加数+加数=和,用6加6即可。被减数-减数=差,用8减去8即可求解.\n【详解】6+6=12,8-8=0\n两个加数都是6,和是12;被减数和减数都是8,差是0。", + "knowledge_points": [ + "8,9的加减法", + "有关0的加减法", + "7,6加几的进位加法" + ], + "source": "23-24一年级上·山东烟台·期末" + }, + { + "id": "444", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "今天是这个月的2号,因为有雨,所以运动会准备3天后再举办。推迟后,运动会在这个月的( )号举办。", + "options": [], + "answer": "5", + "solution": "【分析】根据题意,用原定的时间+推迟的天数=再举办的时间。由此解答.\n【详解】2+3=5(号)推迟后,运动会在这个月的5号举办。", + "knowledge_points": [ + "5以内数的加法" + ], + "source": "23-24一年级上·河南周口·期末" + }, + { + "id": "445", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.65, + "question": "盘子里没有苹果。用数字( )表示。", + "options": [], + "answer": "0", + "solution": "【分析】一个物体也没有,用0表示,据此解答即可.\n【详解】由分析知,盘子里没有苹果,用数字0表示。", + "knowledge_points": [ + "0的认识和读写" + ], + "source": "21-22一年级上·湖北荆门·期末" + }, + { + "id": "446", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "5比( )多1;( )比0多3;2比4少( )。", + "options": [], + "answer": "4;3;2", + "solution": "【分析】一个数比另一个数多几,求另一个数,用减法计算;求比一个数多几的数是多少,用加法计算;一个数比另一个数少几,用减法计算.\n【详解】5-1=4;0+3=3;4-2=2\n5比4多1;3比0多3;2比4少2。", + "knowledge_points": [ + "5以内数的加法", + "5以内数的减法" + ], + "source": "23-24一年级上·福建厦门·期中" + }, + { + "id": "447", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "比5大2的数是( ),5前面的一个数是( )。", + "options": [], + "answer": "7;4", + "solution": "【分析】用5加2即可求出比5大2的数。5前面的一个数比5小1,据此计算.\n【详解】5+2=7,5-1=4,比5大2的数是7,5前面的一个数是4。", + "knowledge_points": [ + "5以内数的减法", + "7的加减法" + ], + "source": "23-24一年级上·浙江杭州·期中" + }, + { + "id": "448", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "5>□,□里可以填( )个数,最大能填( )。", + "options": [], + "answer": "5;4", + "solution": "【分析】0到5,从小到大排序:0,1,2,3,4,5;据此解决.\n【详解】由题意分析得:5>4>3>2>1>0,故,5>□,□里可以填5个数,最大能填4。", + "knowledge_points": [ + "5以内数的比大小" + ], + "source": "23-24一年级上·河南平顶山·期中" + }, + { + "id": "449", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "5和( )合成7,( )和3合成5,9可以分成3和( ),还能分成4和( )。", + "options": [], + "answer": "2;2;6;5", + "solution": "【分析】5和2合成7,2和3合成5,3和6合成9,4和5合成9,据此解答.\n【详解】5和2合成7,2和3合成5,9可以分成3和6,还能分成4和5。", + "knowledge_points": [ + "8,9的分与合(组成)", + "6,7的分与合(组成)", + "5以内数的分与合(组成)" + ], + "source": "23-24一年级上·河南平顶山·期中" + }, + { + "id": "450", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "比2多3的数是( ),1比4少( ),在3和5中间的数是( )。", + "options": [], + "answer": "5;3;4", + "solution": "【分析】已知一个数比另一个数多多少,求一个数是几,用加法列式计算。求一个数比另一个数少多少,用减法列式计算。在3和5中间的数,就是比3大,且比5小的数.\n【详解】由题意分析得:2+3=5,4-1=3,3<4<5故,比2多3的数是5,1比4少3,在3和5中间的数是4。", + "knowledge_points": [ + "5以内数的比大小", + "5以内数的加法", + "5以内数的减法" + ], + "source": "23-24一年级上·山东菏泽·期中" + }, + { + "id": "451", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "比3大2的数是( ),比6小3的数是( )。", + "options": [], + "answer": "5;3", + "solution": "【分析】要求比3大2的数是多少,根据加法的意义,用3+2,解答即可.\n要求比6小3的数是多少,根据减法的意义,用6-3,解答即可.\n【详解】3+2=5,所以比3大2的数是5.6-3=3,所以比6小3的数是3。", + "knowledge_points": [ + "6的加减法", + "5以内数的加法" + ], + "source": "23-24一年级上·湖南郴州·期中" + }, + { + "id": "452", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "4前面的一个数是( ),后面的一个数是( )。", + "options": [], + "answer": "3;5", + "solution": "【分析】数一数即可解决此题。1,2,3,4,5;即,4前面的一个数是3,后面的一个数是5.\n【详解】由题意分析得:4前面的一个数是3,后面的一个数是5。", + "knowledge_points": [ + "数一数" + ], + "source": "20-21一年级上·四川·单元测试" + }, + { + "id": "453", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "在括号里填上\"+\"或者\"-\".\n\n4( )5=9\n6( )3=3\n6( )0=6", + "options": [], + "answer": "+;-;+", + "solution": "【分析】4和5相加得9;6和3相差3,用减法计算;6加0或者减0得数都是6,据此填空.\n【详解】4+5=9,6-3=3,6+0=6或者6-0=6", + "knowledge_points": [ + "6的加减法", + "8,9的加减法", + "有关0的加减法" + ], + "source": "23-24一年级上·山东德州·期中" + }, + { + "id": "454", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "最小的一位数是( ),5与最小的一位数相差( )。", + "options": [], + "answer": "1;4", + "solution": "【分析】根据对数的认识可知,最小的一位数是1,5与最小的一位数相差多少,用减法计算.\n【详解】5-1=4最小的一位数是1,5与最小的一位数相差4.", + "knowledge_points": [ + "5以内数的减法" + ], + "source": "22-23一年级上·贵州黔西·期中" + }, + { + "id": "455", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "三轮车有( )个轮子,一双筷子有( )根,五线谱上有( )根线,我国国旗上有( )颗五角星。", + "options": [], + "answer": "3;2;5;5", + "solution": "【分析】根据生活实际及数字的写法填写即可.\n【详解】三轮车有3个轮子,一双筷子有2根,五线谱上有5根线,我国国旗上有5颗五角星.", + "knowledge_points": [ + "1~5的认识和读写" + ], + "source": "22-23一年级上·贵州黔西·期中" + }, + { + "id": "456", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "小明家住在4楼,小明从1楼走到4楼,走了( )层。", + "options": [], + "answer": "3", + "solution": "【分析】1楼到2楼要走一层;2楼到3楼要走一层;3楼到4楼要走一层。走的层数比所在的楼层数少1,据此解答.\n【详解】4-1=3(层)走了3层.", + "knowledge_points": [ + "5以内数的减法" + ], + "source": "22-23一年级上·贵州黔西·期中" + }, + { + "id": "457", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "2和4中间的数是( ),比4多1的数是( )。", + "options": [], + "answer": "3;5", + "solution": "【分析】根据5以内数的排序:1,2,3,4,5。可知2和4中间的数是3,求比4多1的数是几,用加法计算.\n【详解】4+1=5,2和4中间的数是3,比4多1的数是5.", + "knowledge_points": [ + "5以内数的排序", + "5以内数的加法" + ], + "source": "22-23一年级上·贵州黔西·期中" + }, + { + "id": "458", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "5比3多( ),1比5少( )。", + "options": [], + "answer": "2;4", + "solution": "【分析】求5比3多多少,用5减3进行计算;求1比5少多少,用5减1进行计算.\n【详解】5-3=2;5-1=4,5比3多2,1比5少4.", + "knowledge_points": [ + "5以内数的减法" + ], + "source": "22-23一年级上·贵州黔西·期中" + }, + { + "id": "459", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "猴子一个桃子也没摘到,可以用( )表示。", + "options": [], + "answer": "0", + "solution": "【分析】由题意可知,0有两种含义,表示没有和起点,猴子一个桃子也没摘到,可以用0来表示,据此解答即可.\n【详解】猴子一个桃子也没摘到,可以用(0)表示.", + "knowledge_points": [ + "0的认识和读写" + ], + "source": "22-23一年级上·河南周口·期中" + }, + { + "id": "460", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "和3相邻的两个数是( )和( );2前面一个数是( ),后面一个数是( )。", + "options": [], + "answer": "2;4;1;3", + "solution": "【分析】由题意可知,3的相邻数字分别是3的前一个数字和3的后一个数字,那么3的相邻数字是2和4;2前面一个数字比2小1,应是1;2后面的一个数字比2大1,应是3,据此解答即可.\n【详解】和3相邻的两个数是(2)和(4);2前面一个数是(1),后面一个数是(3).", + "knowledge_points": [ + "5以内数的排序" + ], + "source": "23-24一年级上·吉林四平·期中" + }, + { + "id": "461", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "比大小,填\">\"\"<\"或\"=\".\n\n5( )3\n2( )2\n4( )0\n5-1( )4", + "options": [], + "answer": ">;=;>;=", + "solution": "【分析】5以内的数从小到大是0,1,2,3,4,5,据此填空,算式计算出结果再比较.\n【详解】5>3;2=2;4>0;5-1=4", + "knowledge_points": [ + "5以内数的比大小", + "5以内数的减法" + ], + "source": "22-23一年级上·浙江温州·期中" + }, + { + "id": "462", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "在括号里填上\"+\"或\"-\".\n\n9( )5=4\n6( )2=8\n4( )4=0", + "options": [], + "answer": "-;+;-", + "solution": "【分析】如果等号右边的数比左边的第1个数小,就填减号;如果等号右边的数比等号左边的两个数都大,就填加号.\n【详解】由分析得:9-5=4;6+2=8;4-4=0", + "knowledge_points": [ + "8,9的加减法", + "有关0的加减法", + "5以内数的减法" + ], + "source": "22-23一年级上·江西赣州·期中" + }, + { + "id": "463", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "比5小的数有( )。", + "options": [], + "answer": "0;1;2;3;4", + "solution": "【分析】数字按0,1,2,3,4,5的顺序排列,据此解答.\n【详解】比5小的数有0,1,2,3,4.", + "knowledge_points": [ + "5以内数的比大小" + ], + "source": "22-23一年级上·重庆·期中" + }, + { + "id": "464", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "1-5里有( )个数,其中( )最大,( )最小。", + "options": [], + "answer": "5;5;1", + "solution": "【分析】数一数即可知道1-5一共有几个数,且1-5从小到大排列:1,2,3,4,5;据此解决.\n【详解】由题意分析得:1-5里有5个数,其中5最大,1最小.", + "knowledge_points": [ + "5以内数的比大小" + ], + "source": "22-23一年级上·贵州铜仁·期中" + }, + { + "id": "465", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.94, + "question": "括号里填几。\n\n( )-2=1\n2+( )=3\n1+( )=5", + "options": [], + "answer": "3;1;4", + "solution": "【分析】根据5以内整数加减法运算进行解答即可.\n【详解】3-2=1,所以括号内填3.2+1=3,所以括号内填1.1+4=5,所以括号内填4.", + "knowledge_points": [ + "5以内数的加法", + "5以内数的减法" + ], + "source": "23-24一年级上·浙江·期中" + }, + { + "id": "466", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "1和3,2和2可以合成4;1和4,2和( )可以合成5;1和5,2和( ),3和3可以合成6。", + "options": [], + "answer": "3;4", + "solution": "【分析】2和3可以合成5,2和4可以合成6,据此解答.\n【详解】1和3,2和2可以合成4;1和4,2和3可以合成5;1和5,2和4,3和3可以合成6.", + "knowledge_points": [ + "6,7的分与合(组成)", + "5以内数的分与合(组成)" + ], + "source": "23-24一年级上·上海·期中" + }, + { + "id": "467", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "与4相邻的数是( )和( )。比5小又比2大的数是( )和( )。", + "options": [], + "answer": "3;5;3;4", + "solution": "【分析】与4相邻的数为比4小1的数和比4大1的数;比5小的数有4,3,2,1,0;比2大的数有3,4,5。从中找到比5小又比2大的数是3和4.\n【详解】4-1=3;4+1=5,与4相邻的数是3和5。比5小又比2大的数是3和4.", + "knowledge_points": [ + "5以内数的比大小", + "5以内数的加法", + "5以内数的减法" + ], + "source": "23-24一年级上·辽宁·期中" + }, + { + "id": "468", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.65, + "question": "7个小朋友排成一队做操,从前往后数,小方排在第5个,小方前面有( )人,后面有( )人。", + "options": [], + "answer": "4;2", + "solution": "【分析】从前往后数,小方排在第5个;用5减去1,求出差,就是小方前面的人数。7个小朋友排成一队做操,从前往后数,小方排在第5个;用7减去5,求出差,就是小方后面的人数.\n【详解】5-1=4(人)7-5=2(人)小方前面有4人,后面有2人.", + "knowledge_points": [ + "5以内数的减法", + "7的加减法" + ], + "source": "23-24一年级上·江苏·期中" + }, + { + "id": "469", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "在2和7两个数中,( )离5近一些。", + "options": [], + "answer": "7", + "solution": "【分析】由题意可知,2和7这两个数,谁距离5更近一些,只要算出这两个数分别与5的差,差越小,距离就更近,5-2=3,7-5=2,2和3相比较,2更小,所以7离5近一些,据此解答即可.\n【详解】由分析可得:5-2=3,7-5=2因此在2和7两个数中,( 7 )离5近一些.", + "knowledge_points": [ + "5以内数的减法", + "7的加减法" + ], + "source": "23-24一年级上·四川·期中" + }, + { + "id": "470", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.65, + "question": "聪聪和明明看同一本故事书,聪聪还剩5页没看,明明还剩3页没看。( )看的页数多,多( )页。", + "options": [], + "answer": "明明;2", + "solution": "【分析】看同一本故事书,剩下没看的页数越少,表示看的页数就越多;反之,剩下没看的页数越多,表示看的页数就越少。两人没看的页数差,也是两人已看的页数差。据此解决.\n【详解】3<5,5-3=2(页)明明看的页数多,多2页.", + "knowledge_points": [ + "5以内数的比大小", + "5以内数的减法" + ], + "source": "23-24一年级上·河北·课后作业" + }, + { + "id": "471", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "把4个白色的围棋子分成两堆,你有( )种不同的分法。", + "options": [], + "answer": "2", + "solution": "【分析】根据\"4可以分成1和3及分成2和2\"来解决此题.\n【详解】4个白色的围棋子分成两堆,可以分成:1个一堆和3个一堆;也可分成2个一堆和2个一堆;故,有2种不同的分法.", + "knowledge_points": [ + "5以内数的分与合(组成)" + ], + "source": "23-24一年级上·辽宁·课后作业" + }, + { + "id": "472", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "0表示一个也没有,从一些物体中减去相同的数量,还剩( )个。", + "options": [], + "answer": "0", + "solution": "【分析】0表示一个也没有,从一些物体中减去相同的数量,结果为0.\n【详解】由题意分析得:0表示一个也没有,从一些物体中减去相同的数量,还剩0个。例如:有5个苹果,小朋友们吃了5个,还剩下多少个。5-5=0(个)所以还剩下0个。", + "knowledge_points": [ + "有关0的加减法", + "5以内数的减法" + ], + "source": "23-24一年级上·辽宁·课后作业" + }, + { + "id": "473", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "与4相邻的两个数分别是( )和( )。", + "options": [], + "answer": "3;5", + "solution": "【分析】由题意可知,相邻的两个数,左边的数比右边的数少1,右边的数比左边的数多1,据此解答即可.\n【详解】由分析可得:4-1=3,4+1=5\n所以与4相邻的两个数分别是( 3 )和( 5 ).", + "knowledge_points": [ + "5以内数的加法", + "5以内数的减法" + ], + "source": "18-19一年级上·全国·课后作业" + }, + { + "id": "474", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "5可以分成1和( );4可以分成2和( );( )和1合成3;2可以分成( )和( )。", + "options": [], + "answer": "4;2;2;1;1", + "solution": "【分析】5可以分成1和4,也可以分成2和3;4可以分成1和3,也可以分成2和2;2和1合成3;2可以分成1和1;据此填空.\n【详解】由题意分析得:5可以分成1和4;4可以分成2和2;2和1合成3;2可以分成1和1.", + "knowledge_points": [ + "5以内数的分与合(组成)" + ], + "source": "23-24一年级上·浙江·单元测试" + }, + { + "id": "475", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.4, + "question": "把一根绳子两头对在一起,再在对折好的绳子中间剪一刀。这时,绳子被剪成( )段。", + "options": [], + "answer": "3", + "solution": "【分析】根据题意,把一根绳子两头对在一起,即把绳子对折1次,再在对折好的绳子中间剪一刀;可用纸条代替绳子剪一剪,可以知道被剪成3段,其中有1段比较长,有2段短的是一样长的.\n【详解】依题意:1+2=3(段)所以,绳子被剪成3段.", + "knowledge_points": [ + "5以内数的加法" + ], + "source": "22-23一年级下·辽宁·单元测试" + }, + { + "id": "476", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "东东有5个气球,不小心飞走了2个,东东现在还有( )个气球。", + "options": [], + "answer": "3", + "solution": "【分析】用气球的总数量减去飞走的数量,求出差,即可知道东东现在还有几个气球.\n【详解】5-2=3(个)故,东东有5个气球,不小心飞走了2个,东东现在还有3个气球.", + "knowledge_points": [ + "5以内数的减法" + ], + "source": "23-24一年级上·上海·课后作业" + }, + { + "id": "477", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "判断题", + "difficulty": 0.85, + "question": "在数轴上的0表示起点。( )", + "options": [], + "answer": "√", + "solution": "【分析】根据对数的认识可知,0表示没有。如图:直尺上的0和数轴上的0都表示起点。由此解答.\n【详解】由分析可知,在数轴上的0表示起点。原题说法正确。故答案为:√", + "knowledge_points": [ + "0的认识和读写" + ], + "source": "23-24一年级上·四川宜宾·期末" + }, + { + "id": "478", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "判断题", + "difficulty": 0.65, + "question": "两个数的和不一定比这两个数都大。( )", + "options": [], + "answer": "√", + "solution": "【分析】能举出例子说明和可以不大于两个加数,例如0参与加法时,和等于另一个加数,据此解答.\n【详解】例如:2+0=2,2=2,和并没有比两个数都大。所以两个数的和不一定比这两个数都大,原说法正确。故答案为:√", + "knowledge_points": [ + "有关0的加减法" + ], + "source": "23-24三年级上·浙江杭州·期中" + }, + { + "id": "479", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "判断题", + "difficulty": 0.65, + "question": "差一定小于被减数。( )", + "options": [], + "answer": "×", + "solution": "【分析】4-0=4,差与被减数相等,所以差不一定小于被减数,据此即可解答.\n【详解】根据分析可知,差不一定小于被减数,原说法错误。故答案为: ×", + "knowledge_points": [ + "有关0的加减法" + ], + "source": "23-24三年级上·河南周口·期中" + }, + { + "id": "480", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "判断题", + "difficulty": 0.65, + "question": "4只能分成1和3。( )", + "options": [], + "answer": "×", + "solution": "【分析】根据数的分与合,4除了可以分为1和3,还可以分为2和2,3和1,由此解答.\n【详解】由分析可知:4可以分为1和3,还可以分为2和2,3和1,原题说法错误。故答案为: ×", + "knowledge_points": [ + "5以内数的分与合(组成)" + ], + "source": "23-24一年级上·广东阳江·期中" + }, + { + "id": "481", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "判断题", + "difficulty": 0.85, + "question": "在加法算式里,两个加数一定都小于它们的和。( )", + "options": [], + "answer": "×", + "solution": "【分析】能举出反面例子即该说法错误,例如0加上任何数都等于那个数本身,据此解答.\n【详解】例如:2+0=2,2=2\n所以两个加数一定都小于它们的和是错误的。故答案为: ×。", + "knowledge_points": [ + "有关0的加减法" + ], + "source": "21-22三年级上·贵州黔西·期中" + }, + { + "id": "482", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "判断题", + "difficulty": 0.85, + "question": "因为〇+☆=□,所以☆-□=〇。( )", + "options": [], + "answer": "×", + "solution": "【分析】加数+加数=和,可转换为和-加数=另一个加数,由此解答.\n【详解】题中〇和☆都是加数,□是和,所以减法算式应为□-〇=☆或□-☆=〇。如1+2=3,则减法算式为3-1=2,3-2=1。原题说法错误。故答案为: ×", + "knowledge_points": [ + "5以内数的加法", + "5以内数的减法" + ], + "source": "22-23一年级上·江苏南通·期末" + }, + { + "id": "483", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "判断题", + "difficulty": 0.85, + "question": "在生活中,有许多地方用到\"0\"。( )", + "options": [], + "answer": "√", + "solution": "【分析】此题主要考查了0的认识,生活中,有许多地方用到\"0\",据此判断\n【详解】在生活中,有许多地方用到\"0\",比如一个苹果也没有了,可以用0来表示,等等。此题说法正确。故答案为:√", + "knowledge_points": [ + "0的认识和读写" + ], + "source": "2023一年级上·辽宁·专题练习" + }, + { + "id": "484", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "判断题", + "difficulty": 0.85, + "question": "4比5少1。( )", + "options": [], + "answer": "√", + "solution": "【分析】根据求一个数比另一个数少几,用减法计算,用5减去4,求出它们的差,即可判断.\n【详解】5-4=1所以,4比5少1,原题说法正确。故答案为:√", + "knowledge_points": [ + "5以内数的减法" + ], + "source": "2023一年级上·辽宁·专题练习" + }, + { + "id": "485", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "计算题", + "difficulty": 0.85, + "question": "我会看图列式计算.\n\n![](images/Pasted%20image%2020260311004526.png)", + "options": [], + "answer": "5-2=3", + "solution": "【分析】根据题意可知,原有5只燕子,飞走了2只,求还有几只燕子,用原来的数量减去飞走的数量,求出差,就是还剩的数量.\n【详解】由题意分析得:5-2=3(只)", + "knowledge_points": [ + "图文问题", + "5以内数的减法" + ], + "source": "24-25一年级上·全国·假期作业" + }, + { + "id": "486", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图写算式.\n\n![](images/Pasted%20image%2020260311004536.png)", + "options": [], + "answer": "4+1=5", + "solution": "【分析】左边4个,右边1个,左右两边相加即可求出一共有多少个.\n【详解】4+1=5", + "knowledge_points": [ + "图文问题", + "5以内数的加法" + ], + "source": "24-25一年级上·河南郑州·期中" + }, + { + "id": "487", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "计算题", + "difficulty": 0.65, + "question": "看图列式.\n\n![](images/Pasted%20image%2020260311004547.png)", + "options": [], + "answer": "3+1=4", + "solution": "【分析】原有3只小鸟,又飞来了1只,求现在一共有几只小鸟,用加法计算,即原有的数量+又飞来的数量=现在一共的数量.\n【详解】3+1=4(只)现在一共有4只小鸟。", + "knowledge_points": [ + "图文问题", + "5以内数的加法" + ], + "source": "24-25一年级上·内蒙古通辽·期中" + }, + { + "id": "488", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式计算.\n\n![](images/Pasted%20image%2020260311004555.png)", + "options": [], + "answer": "0+5=5", + "solution": "【分析】左边盘子里没有苹果,也就是0个,右边盘子里有5个苹果,求一共有多少个苹果,用加法计算,即左边的数量+右边的数量=总数量.\n【详解】0+5=5(个)一共有5个苹果。", + "knowledge_points": [ + "图文问题", + "有关0的加减法" + ], + "source": "24-25一年级上·云南曲靖·期中" + }, + { + "id": "489", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "计算题", + "difficulty": 0.65, + "question": "看图列式计算.\n\n![](images/Pasted%20image%2020260311004603.png)", + "options": [], + "answer": "4-0=4", + "solution": "【分析】由图可知,原本盘子里一个梨也没有,用0表示,后来盘子里有4个梨,求拿来了几个梨,根据减法的意义,用后来盘子里梨的数量减去原来盘子里梨的数量即可.\n【详解】4-0=4(个)所以拿来了4个梨。", + "knowledge_points": [ + "图文问题", + "有关0的加减法" + ], + "source": "24-25一年级上·河南开封·期中" + }, + { + "id": "490", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式计算.\n\n![](images/Pasted%20image%2020260311004613.png)", + "options": [], + "answer": "5-3=2", + "solution": "【分析】图中一共有5个萝卜,用虚线框起来3个表示去掉3个,求还剩多少个萝卜,用总数量减去去掉的数量,计算即可.\n【详解】5-3=2(个)还剩2个萝卜。", + "knowledge_points": [ + "图文问题", + "5以内数的减法" + ], + "source": "24-25一年级上·全国·课后作业" + }, + { + "id": "491", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "一共有5个萝卜,小兔子拿走了2个,还剩几个萝卜。\n\n![](images/Pasted%20image%2020260311004628.png)", + "options": [], + "answer": "5-2=3;3个", + "solution": "【分析】求还剩几个萝卜,用减法计算,即萝卜的总数量-拿走的数量=还剩的数量.\n【详解】5-2=3(个)答:还剩3个萝卜。", + "knowledge_points": [ + "图文问题", + "5以内数的减法" + ], + "source": "24-25一年级上·山西长治·期中" + }, + { + "id": "492", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.65, + "question": "粉笔盒里原来有4支粉笔,张老师用了3支,粉笔盒里还剩几支粉笔。", + "options": [], + "answer": "1支", + "solution": "【分析】用粉笔盒里原来有粉笔的支数,减去张老师用的支数,即可计算出粉笔盒里还剩几支粉笔.\n【详解】4-3=1(支)答:粉笔盒里还剩1支粉笔。", + "knowledge_points": [ + "5以内数的减法" + ], + "source": "24-25一年级上·辽宁·课前预习" + }, + { + "id": "493", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "小红和小兰玩拍皮球游戏,小红拍了2下,小兰和小红拍的一样多,小红和小兰一共拍了几下。", + "options": [], + "answer": "4下", + "solution": "【分析】小红拍了2下,小兰和小红拍的一样多,说明小兰也拍了2下,然后根据整数加法的意义,用2加上2求出和,即可解决.\n【详解】2+2=4(下)答:小红和小兰一共拍了4下。", + "knowledge_points": [ + "5以内数的加法" + ], + "source": "24-25一年级上·辽宁·课前预习" + }, + { + "id": "494", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "湖里原来有2只天鹅,又飞来了1只,湖里现在有几只天鹅。", + "options": [], + "answer": "3只", + "solution": "【分析】用湖里原有天鹅的只数加上又飞来的只数,即可计算出湖里现在有几只天鹅.\n【详解】2+1=3(只)答:湖里现在有3只天鹅。", + "knowledge_points": [ + "5以内数的加法" + ], + "source": "24-25一年级上·辽宁·课前预习" + }, + { + "id": "495", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.65, + "question": "在四则运算中,如果有0或1参与运算,有哪些特殊情况。", + "options": [], + "answer": "见详解", + "solution": "【分析】0和1参与四则运算时,结果往往保持不变或变为0,分情况说明即可。\n【详解】(1)任何运算乘0,得到的结果为0。比如:5×0=0。(2)任何运算除以1,得到的结果保持不变。比如:6÷1=6。(3)任何运算乘1,得到的结果保持不变。比如:6×1=6。(4)任何运算加0,得到的结果保持不变。比如:6+0=6。(5)任何运算减0,得到的结果保持不变。比如:6-0=6", + "knowledge_points": [ + "有关0的加减法" + ], + "source": "23-24六年级下·全国·随堂练习" + }, + { + "id": "496", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "小强看一本书,第一天看了3页,第二天看了4页,第一天比第二天少看多少页。", + "options": [], + "answer": "1页", + "solution": "【分析】第二天看的页数-第一天看的页数=第一天比第二天少看的页数.\n【详解】4-3=1(页)答:第一天比第二天少看1页。", + "knowledge_points": [ + "5以内数的减法" + ], + "source": "23-24一年级上·山东潍坊·期中" + }, + { + "id": "497", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "小红和小明帮老奶奶搬花,小红搬了2盆花,小明搬了2盆花,小红和小明一共搬了几盆花。", + "options": [], + "answer": "4盆", + "solution": "【分析】求小红和小明一共搬了几盆花,就是求两个数的和,用加法列式计算解决.\n【详解】2+2=4(盆)答:小红和小明一共搬了4盆花.", + "knowledge_points": [ + "5以内数的加法" + ], + "source": "23-24一年级上·河北·课后作业" + }, + { + "id": "498", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "植树节男生种了2棵树,女生种了3棵树,一共种了多少棵树。", + "options": [], + "answer": "5棵", + "solution": "【分析】把男生种的棵树与女生种的棵树加起来,求出和,即可解决此题.\n【详解】2+3=5(棵)答:一共种了5棵树.", + "knowledge_points": [ + "5以内数的加法" + ], + "source": "23-24一年级上·河北·课后作业" + }, + { + "id": "499", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "小明早上吃2个包子,妈妈吃的包子比小明多1个,爸爸吃的比妈妈又多1个,妈妈和爸爸分别吃多少个包子。", + "options": [], + "answer": "3个;4个", + "solution": "【分析】已知一个数比另一个数多多少,求一个数是几,用加法列式计算.\n【详解】2+1=3(个)3+1=4(个)答:妈妈和爸爸分别吃3个和4个包子.", + "knowledge_points": [ + "5以内数的加法" + ], + "source": "23-24一年级上·河北·课后作业" + }, + { + "id": "500", + "unit": "第一单元5以内数的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "小明吃了2个苹果,爸爸吃了3个苹果,他们一共吃了多少个。\n\n答:他们一共吃了( )个。", + "options": [], + "answer": "5个;5", + "solution": "【分析】根据题意求一共吃了多少个,用加法计算,用小明吃的数量加上爸爸吃的数量即可.\n【详解】2+3=5(个)答:他们一共吃了5个.", + "knowledge_points": [ + "5以内数的加法" + ], + "source": "22-23二年级上·四川·课后作业" + } +] diff --git "a/\344\270\200\345\271\264\347\272\247\351\242\230\351\233\206/\344\270\200\345\271\264\347\272\247\344\270\212/\344\270\200\345\271\264\347\272\247\344\270\212\347\254\254\344\270\211\345\215\225\345\205\203\350\256\244\350\257\206\347\253\213\344\275\223\345\233\276\345\275\242.json" "b/\344\270\200\345\271\264\347\272\247\351\242\230\351\233\206/\344\270\200\345\271\264\347\272\247\344\270\212/\344\270\200\345\271\264\347\272\247\344\270\212\347\254\254\344\270\211\345\215\225\345\205\203\350\256\244\350\257\206\347\253\213\344\275\223\345\233\276\345\275\242.json" new file mode 100644 index 0000000000000000000000000000000000000000..fec4f60d3aa8e02d88d79b7779e00efdb12f4c8c --- /dev/null +++ "b/\344\270\200\345\271\264\347\272\247\351\242\230\351\233\206/\344\270\200\345\271\264\347\272\247\344\270\212/\344\270\200\345\271\264\347\272\247\344\270\212\347\254\254\344\270\211\345\215\225\345\205\203\350\256\244\350\257\206\347\253\213\344\275\223\345\233\276\345\275\242.json" @@ -0,0 +1,8476 @@ +[ + { + "id": "1", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "下面三组积木,放得最稳的是 ( )。", + "options": [ + "A. ![](images/01259c265f08aaa25ea56f00895ea30b110717724a517e95081f1b524de4c421.jpg)", + "B. ![](images/8f0f79020df79300020c7e7fed92ec59c3054030614611ee5463f088dc670b17.jpg)", + "C. ![](images/759d619c5705c3e9a09f04099f43e9cc546de3aaf9628927dd010a8c9e59f5cb.jpg)" + ], + "answer": "B", + "solution": "【分析】长方体是长长方方的有平平的面;正方体是正正方方的有平平的面;圆柱上下是平平的面且上下一样粗;球没有平面可以任意方向滚动。平平的面在下面,且两个图形之间的接触面也是平平的,这样搭出来的是最稳的,由此解答.\n【详解】A。 下面是圆柱,平平的面与地面接触,不易滚动,上面是球,可随意滚动,不稳定;B. 下面是长方体,不易滚动;上面是正方体,不易滚动,整体稳定;C. 下面是正方体,不易滚动;上面是圆柱,平放易滚动,不稳定。则放得最稳的是B![](images/66adf7826ae46e877443878143eec29dd24b7cd371b84f47276b61f4eea2f34b.jpg),故答案为: B", + "knowledge_points": [ + "组合图形的稳定性" + ], + "source": "25-26 一年级上·江西九江·期中" + }, + { + "id": "2", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.94, + "question": "小明摸到的是 ( )。 ![](images/bed951acb42386605bda2c3772a40af9.png)", + "options": [ + "A. 长方体", + "B. 正方体", + "C. 圆柱" + ], + "answer": "B", + "solution": "【分析】根据对立体图形的认识可知:长方体是长长方方的有平平的面;正方体是正正方方的有平平的面;圆柱上下是平平的面且上下一样粗,由此选择.\n【详解】A。 是长方体,有不同大小的面,不符合题意;B. 是正方体,每个面都相同,符合题意;C. 是圆柱,有平平的面和曲面,不符合题意。则小明摸到的是B。故答案为: B", + "knowledge_points": [ + "立体图形的认识及分类" + ], + "source": "25-26 一年级上·江西九江·期中" + }, + { + "id": "3", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.94, + "question": "下面的 ( ) 最不容易滚动。", + "options": [ + "A. ![](images/4f7bdf4fa1d4863b22c49c800233a8ec849af0d04cad5d0da5019057468a32ce.jpg)", + "B. ![](images/ca2b425dab73b7184afee1efbc220938a697290334a868596030602d0232a6b7.jpg)", + "C. ![](images/ba95887481eda25b2f74061c25fda8aa07d731bde06bdb028cc82dc50339b20d.jpg)" + ], + "answer": "C", + "solution": "【分析】长方体是长长方方的;正方体是方方正正的,每个面都是正方形;圆柱上下是平平的面,且上下一样粗,侧面是曲面;球是圆圆的,没有平面,可以任意方向滚动;根据立体图形的特征来解决此题.\n【详解】A。 是圆柱,当曲面着地时,易滚动,当上下平平的面着地时,不易滚动;B. 是球,可以任意方向滚动;C. 是长方体,长长方方的,最不容易滚动。故答案为: C", + "knowledge_points": [ + "立体图形的认识及分类" + ], + "source": "24-25 一年级上·河南驻马店·期中" + }, + { + "id": "4", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.94, + "question": "下面最容易滚动的物体是 ( )。", + "options": [ + "A. 长方体", + "B. 球", + "C. 正方体" + ], + "answer": "B", + "solution": "【分析】长方体是长长方方的,有平平的面;正方体是正正方方的,有平平的面;球没有平面可以向任意方向滚动;据此逐一分析三个选项,找出最容易滚动的物体.\n【详解】A。长方体有平平的面,和地面接触时不易滚动,不符合题意;B. 球没有平面可以向任意方向滚动,容易滚动,符合题意;C. 正方体有平平的面,和地面接触时不易滚动,不符合题意。故答案为: B", + "knowledge_points": [ + "立体图形的认识及分类" + ], + "source": "24-25 一年级上·河南商丘·期末" + }, + { + "id": "5", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "用下面的图形搭一搭,要想搭得最牢固,不应该先放()。", + "options": [ + "A. ![](images/b019ab59139964a125d89ccec612f01d6000dbedb2978c37c16f10f6dbe18f78.jpg)", + "B. ![](images/86c30d2ae72abac7b99a1ef725ac980d51695ffaa99752d69dd57407ae648d74.jpg)", + "C. ![](images/be743c9cc4bf7881119e0e0a25824ca56c4e3c8444ecf11d0faafc98c49e6d87.jpg)" + ], + "answer": "C", + "solution": "【分析】长方体是长长方方的有平平的面,不易滚动;圆柱上下是平平的面且上下一样粗,可以立起来,放倒易滚动;球没有平面可以任意方向滚动。要想搭得最牢固,则不应该先放易滚动的图形,由此解答.\n【详解】A。不易滚动,稳定,可以先放;B. 立起来不易滚动,稳定,可以先放;C. 可随意滚动,不稳定,不可以先放。则要想搭得最牢固,不应该先放![](images/a85c679cb46743b70e9ee80c851ef0bbd32839acb883e33bc9ce0f1879d15ce3.jpg)。故答案为: C", + "knowledge_points": [ + "组合图形的稳定性" + ], + "source": "2025 一年级上·全国·专题练习" + }, + { + "id": "6", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "![](images/bdd546b1a909f7a87dd28866cba570103ab27df8990ac8709a659e564922770b.jpg)与下面图形( ) 能拼成一个长方体。", + "options": [ + "A. ![](images/cc0584b244ad9e579f3051b9d7aa27ab8727d75f7864dee95fa94ba0dcc7d466.jpg)", + "B. ![](images/3f73d70ccc515d54750825051925a47afca5becf78283760e68eb40f6294ed6c.jpg)", + "C. ![](images/946705825ec09a3ac61612927082881187eaef6e427771339a7e3159282f85cd.jpg)" + ], + "answer": "C", + "solution": "【分析】观察题目给出的图形,它是由两个小正方体并排组成的长方体,把它平放在右边,即可拼成一个长方体。据此解答.\n【详解】根据分析可得:![](images/1678b83ee1fe34d54723f6a429c411f795744ff750436cda7e512dd84baab37b.jpg)与下面图形![](images/adc5ffadef69e4f58eff13ca9a6c22818dd50ef128cb1d69d7a22011b56acf04.jpg)能拼成一个长方体。故答案为: C", + "knowledge_points": [ + "立体图形的拼搭" + ], + "source": "25-26 一年级上·全国·单元测试" + }, + { + "id": "7", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "下面的图中,滚得最快的是 ( )。", + "options": [ + "A. ![](images/00cc3868d3baefc75cb10d03f5bf899f7bebf159365944bda2c0b5c1f24f47a0.jpg)", + "B. ![](images/bcb538bba7b6f295f265f2f123efa96d40f64697c6c86156988bcdd0402cd4ce.jpg)", + "C. ![](images/9c5c7f47396db366384ac708e8148671bc4bb27ceb13450bfafe7617ca049c49.jpg)" + ], + "answer": "B", + "solution": "【分析】长方体是长长方方的,有平平的面;正方体是方方正正的,每个面都是正方形;圆柱上下是平平的面且上下一样粗,侧面是曲面;据此逐一分析三个选项,找出滚得最快的图形.\n【详解】A。长方体有平平的面,和地面接触时不易滚动,不符合题意;B. 圆柱体横放时,用圆滚滚的面和地面接触时,容易滚动,符合题意;C. 正方体有平平的面,和地面接触时不易滚动,不符合题意;故答案为: B", + "knowledge_points": [ + "组合图形的稳定性" + ], + "source": "25-26 一年级上·全国·单元测试" + }, + { + "id": "8", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "在斜坡上,哪个图形滚得最快。()。 ![](images/1d71043aef1fb6b57895c5a46a127f32.png)", + "options": [ + "A. 长方体", + "B. 球", + "C. 正方体", + "D. 圆柱" + ], + "answer": "B", + "solution": "【分析】长方体是长长方方的;正方体是方方正正的,每个面都是正方形;圆柱是上下平平的面且上下一样粗,侧面是曲面;球是圆圆的,没有平面,可以任意方向滚动;据此解答.\n【详解】在斜面上滚动时,球与地面的接触面最小,滚动最平稳,因此会滚得最快。故答案为: B", + "knowledge_points": [ + "立体图形的认识及分类" + ], + "source": "25-26 一年级上·全国·课后作业" + }, + { + "id": "9", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "下面哪个形状是圆柱体。 ( )", + "options": [ + "A. ![](images/6a82e56f46e95ca2c66adf67eb7ee1119835d054c1885d35016a8bd95235633a.jpg)", + "B. ![](images/8219bd06931a7d3bbfc0977130a1ca37eec3d60fd565a7e7b08bdb9de2046bdd.jpg)", + "C. ![](images/c6527556ba6f24e8c92467cfca8df9bfe8cbaaae2b177ddbc221b5d2c8d287fd.jpg)" + ], + "answer": "C", + "solution": "【分析】长方体是长长方方的有平平的面;正方体是正正方方的有平平的面,每面都一样;圆柱上下是圆,是平面且上下一样粗;中间是不是平面;球没有平面可以任意方向滚动.\n【详解】A。 正方体,不符合题意;B. 长方体,不符合题意;C. 圆柱,符合题意。故答案为: C", + "knowledge_points": [ + "立体图形的认识及分类" + ], + "source": "24-25 一年级下·湖南岳阳·期中" + }, + { + "id": "10", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "![](images/5740bc4f7eed4f25d4b871d0122e01db317c286d5bc00236b28948691bf40997.jpg)左图一共有()个 正方体", + "options": [ + "A. 5", + "B. 6", + "C. 7", + "D. 8" + ], + "answer": "D", + "solution": "【分析】从上往下数,第一层 4 个,第二层 4 个,把数的数量相加即可求出一共的数量.\n【详解】 4 + 4 = 8 (个),则 左图一共有(8)个 。故答案为: D", + "knowledge_points": [ + "8,9 的加减法", + "立体图形的拼搭" + ], + "source": "24-25 一年级上·福建龙岩·期末" + }, + { + "id": "11", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "下面 ( ) 是用 4 个正方体 拼成的。", + "options": [ + "A. ![](images/5ba3188dd6a595c82e0e56ea470b90b5788caf9dbec37474f34b0f1b59c6cbbe.jpg)", + "B. ![](images/a8db6257acd7e3e7a60b2b73998e21c17fc9e69520473f4050e1dbf51977a01e.jpg)", + "C. ![](images/5ec01afec76f54c6ce8c4b6216336f5b3cb2b459d816b180fc3de2036d853c82.jpg)" + ], + "answer": "C", + "solution": "【分析】逐项分析数出三个选项中小正方体的数量,对照三个答案选出由 4 个正方体拼成的即可.\n【详解】A。有5个小正方体拼成,不符合;B. 有 8 个小正方体拼成,不符合;C. 恰好由 4 个小正方体拼成,符合。即 是用4个 拼成的。故答案为: C", + "knowledge_points": [ + "数正方体的个数" + ], + "source": "24-25 一年级上·山东济南·期末" + }, + { + "id": "12", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "可以立起来,还可以滚动的图形是 ( )。", + "options": [ + "A. ![](images/38da2e4638d92650139a740d0b4ae89cc863d10e1f15d1a708051147c4b56c03.jpg)", + "B. ![](images/627938ad0fbba5e36fa75916b554348360c5235083054b128fa8225a6b1ef0fe.jpg)", + "C. ![](images/822be9593a7f4118aa285ea28e37d2be42396289cf9b5b651e2a034c0662e752.jpg)" + ], + "answer": "A", + "solution": "【分析】长方体是长长方方的;正方体是方方正正的,每个面都是正方形;圆柱上下是平平的面,且上下一样粗,侧面是曲面;根据立体图形的特征来解决此题.\n【详解】A。![](images/38da2e4638d92650139a740d0b4ae89cc863d10e1f15d1a708051147c4b56c03.jpg) 是圆柱,平平的面着地时,可以立起来,侧面可以滚动,所以它是 \"可以立起来,还可以滚动\" 的图形,答案正确;B. ![](images/627938ad0fbba5e36fa75916b554348360c5235083054b128fa8225a6b1ef0fe.jpg)是正方体,不论哪个面着地时,都不可以滚动,可以立起来,答案不正确;C. ![](images/822be9593a7f4118aa285ea28e37d2be42396289cf9b5b651e2a034c0662e752.jpg) 是长方体,不论哪个面着地时,都不可以滚动,可以立起来,答案不正确。故答案为: A", + "knowledge_points": [ + "立体图形的认识及分类" + ], + "source": "24-25 一年级上·山东济南·期末" + }, + { + "id": "13", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "给![](images/3309559f5c20c860f7731ce3dcce9d50d946f0c48655321d548317c04312c9a5.jpg)每个面涂上不同的颜色,至少需要()种颜色。", + "options": [ + "A. 2", + "B. 4", + "C. 6" + ], + "answer": "C", + "solution": "【分析】根据题意可知:正方体有 6 个面,每个面都相等。据此解答.\n【详解】由分析可得:给![](images/3309559f5c20c860f7731ce3dcce9d50d946f0c48655321d548317c04312c9a5.jpg) 每个面涂上不同的颜色,至少需要 (6) 种颜色。故答案为:C", + "knowledge_points": [ + "正方体的特征", + "立体图形的认识及分类" + ], + "source": "24-25 一年级上·河南三门峡·期末" + }, + { + "id": "14", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "下面最容易滚动的是 ( )。", + "options": [ + "A. 圆柱", + "B. 长方体", + "C. 球" + ], + "answer": "C", + "solution": "【分析】长方体是长长方方的有平平的面;正方体是正正方方的有平平的面,每面都相等;圆柱上下是圆且上下一样粗;球没有平面可以任意方向滚动.\n【详解】A。 圆柱,上下是圆,是平面,不易滚动,中间是曲面,易滚动,整体较易滚动,(看怎么放)。B。 长方体,都是平面,不易滚动,不符合题意。 C. 球,没有平面可以任意方向滚动,符合题意。故答案为: C", + "knowledge_points": [ + "立体图形的认识及分类" + ], + "source": "24-25 一年级上·四川乐山·期末" + }, + { + "id": "15", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "下面 ( ) 滚动得最快。", + "options": [ + "A. ![](images/5715505cc38e333f9210671d5361b7c9b8da4c0681a17a1870bd1120468752c0.jpg)", + "B. ![](images/85ad0813bc6b6837a2e0b78d9d6ce4faf53aeb7f85eb5b7e93f5801ed29090de.jpg)", + "C. ![](images/d3129e5b4bdeff8a8eb881928a86e6ef372f33d29d14df41d72441d6127e8500.jpg)" + ], + "answer": "C", + "solution": "【分析】越弯曲的面越容易滚动,越平整的面越不容易滚动.\n【详解】A。都是平平的面,不容易滚动;B. 都是平平的面,不容易滚动;C. 侧面是弯曲的,容易滚动。![](images/ee9e94ba4477a3cf905c1d484435599df9eccf8b39523ae7f42bb72cbdb94dd6.jpg)滚动得最快。故答案为: C", + "knowledge_points": [ + "立体图形的认识及分类" + ], + "source": "24-25 一年级上·河南商丘·期末" + }, + { + "id": "16", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "数一数,下图是由 ( ) 个小正方体搭成的。![](images/e420187346f87cf6db2bdf9c21639cfc63982ed3c7a5a717e4b435887fe66308.jpg)", + "options": [ + "A. 4", + "B. 5", + "C. 6" + ], + "answer": "B", + "solution": "【分析】从上往下数,上层 1 个,下层 4 个,把两层数出的数量相加即可.\n【详解】 1 + 4 = 5 (个),图形是由 5 个小正方体搭成的。故答案为: B", + "knowledge_points": [ + "立体图形的拼搭", + "5以内数的加法" + ], + "source": "24-25 一年级上·云南玉溪·期末" + }, + { + "id": "17", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "拼成一个大正方体,至少需要()个小正方体。", + "options": [ + "A. 8", + "B. 5", + "C. 4" + ], + "answer": "A", + "solution": "【分析】正方体是正正方方的有平平的面,每条边的长度一样.\n【详解】拼成一个大正方体,至少需要下面4个小正方体,上面4个小正方体。4 + 4 = 8(个),至少需要 8 个小正方体。故答案为: A", + "knowledge_points": [ + "长方体的认识及特征", + "立体图形的认识及分类" + ], + "source": "18-19 一年级上·全国·期末" + }, + { + "id": "18", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "![](images/486b6171f58ce41852f1514200e4f53851fa64187809274a95b51dfe421d5473.jpg)和( ) 可以拼成![](images/c82e49b4d8e2cc8ee9779c9a29d878501cd7e04e8773b1891d4124cf0de4d099.jpg) ![](images/7d12b4cccb84ff91facbcf80d648957f.png)", + "options": [ + + ], + "answer": "C", + "solution": "【分析】![](images/496cc61ab6fc4ebe1425bfd21271edc31d5f72161df37731c7ac07a3d95f3853.jpg)有6个正方体拼成,![](images/5cf72e134cccd0f39892a5e33db030b8e516822564f180ad45bbe90c1b25c3f6.jpg)有 10 个正方体拼成;![](images/683ebd2c35b652c820f80bf5a37d2d0e551fb42f87ce40b3a3fb893739916cba.jpg)要拼成![](images/b8607bbc20ea345846a8a33cdefd4c8c5faf7d5f9394cc5b0bca364288c9127e.jpg),还差4个正方体;据此解答.\n【详解】由题意分析可得:![](images/486b6171f58ce41852f1514200e4f53851fa64187809274a95b51dfe421d5473.jpg)可以和![](images/5a7854d8c4c86e42e0ee6a555ef63a553184378137d348c4c3321d263fbf95b7.jpg)拼成![](images/054f9328d2ae5788c8fa90fe6a8637eadfbf87b54e42828c09578f41aa626262.jpg)故答案为: C", + "knowledge_points": [ + "立体图形的拼搭" + ], + "source": "24-25 一年级上·湖北黄石·期末" + }, + { + "id": "19", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "下面 ( ) 堆物体放得最稳。", + "options": [ + "A. ![](images/59db82f37e89dba933f5aad2b0a74c1e6b4c7f70b78d7234e4c012724a008214.jpg)", + "B. ![](images/82f538be7ce09806eef52abb7b119f7ee62a9a7bcd528c7fdeb020c631523986.jpg)", + "C. ![](images/b92fd12eae146dcd5421fff48cedf1dd0c81cd71e8e2ea60ed70b6b7a293934d.jpg)" + ], + "answer": "C", + "solution": "【分析】长方体是长长方方的有平平的面,不易滚动;正方体是正正方方的有平平的面,不易滚动;圆柱上下是平平的面且上下一样粗,可以立起来,放倒易滚动;球没有平面可以任意方向滚动,由此找出整体不易滚动的,也就是最稳定的.\n【详解】A。下边是长方体,不易滚动,上边是球可随意滚动,不稳定;B. 下边是圆柱,放倒易滚动,上边无论放什么都不稳定;C. 下边是正方体和长方体,都不易滚动,上边圆柱立起来也不易滚动,所以整体稳定;放得最稳的是![](images/398c758e4cce6782ab474c47167eb3f106535b73044fda5901abe9acd120c70c.jpg)故答案为: C", + "knowledge_points": [ + "组合图形的稳定性", + "立体图形的认识及分类" + ], + "source": "24-25 一年级上·浙江宁波·期末" + }, + { + "id": "20", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "下面图形中,用最少数量的正方体拼成的是 ( )。", + "options": [ + "A. ![](images/0904db94255911ce827782e7a562d341b26c3a6eb14023ff2dac00061471bf18.jpg)", + "B. ![](images/7a3a9a097a9f076dec7af5c936e1e90d14bb53361046e9e1f13f72e51e133bb9.jpg)", + "C. ![](images/f943af52d040569494769319d28df80d84cb15c3bf36fec8412bb1923968afa6.jpg)" + ], + "answer": "C", + "solution": "【分析】根据题意,依次数出每个选项中正方体的数量再比较大小,选择数量最少的即可,5以内数从大到小关系为 5 \u003e 4 \u003e 3 \u003e 2 \u003e 1,要注意的是,每上层一个正方体的下边都对应着一个正方体.\n【详解】A。第一排有2个,第二排有3个,一共有 2 + 3 = 5 (个);B. 上层有 1 个,中间有 1 个,下层有 3 个,一共有 1 + 1 + 3 = 5 (个);C. 上层有 1 个,下层有 3 个,一共有 1 + 3 = 4 (个);5 = 5 \u003e 4\n用最少数量的![](images/468918961c688e50dd746e3e6418ee11c146f151f4ddf7d4063275f69366b2b5.jpg)拼成的是![](images/6920e59db2701e9454289e2001ad57da5407af453d439e64b39a75d59109eb5a.jpg)故答案为: C", + "knowledge_points": [ + "5 以内数的比大小", + "数正方体的个数", + "5 以内数的加法", + "连加", + "连减(10 以内)" + ], + "source": "24-25 一年级上·浙江宁波·期末" + }, + { + "id": "21", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "下面这些图形中,最难搭高的是()。", + "options": [ + "A. ![](images/a26e04ad9c883be7d67e6460165c38f3a7089dfd0bec5a9ac7ee1bfa4537bc0d.jpg)", + "B. ![](images/6e834812a0c18feef3944a873832ad9b62c82185d18ff7ec9aad6fa120f855c6.jpg)", + "C. ![](images/719e5ed0638ff174305019038b3fa0fd3ddda7f4f40c8f46b74afd7fa33bedd8.jpg)" + ], + "answer": "C", + "solution": "【分析】长方体是长长方方的有平平的面;正方体是正正方方的有平平的面,每面都相等;圆柱上下是圆且上下一样粗;球没有平面可以任意方向滚动\n【详解】A。 长方体是平面,则不易滚动,则不符合题意;B。![](images/874c71cfa8bf067007ddbbe22f6013b80348c3deb92c899df922661b3af6bb24.jpg)长方体是平面,则不易滚动,则不符合题意;C。![](images/51f8c1e65a018ffd6dbab542a461952cebe3ba18adf656bebbb49c9cb64b6e91.jpg)球没有平面可以任意方向滚动,则符合题意。故答案为 C", + "knowledge_points": [ + "立体图形的拼搭", + "立体图形的认识及分类" + ], + "source": "24-25 一年级上·湖南娄底·期末" + }, + { + "id": "22", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "下面的图形中,小正方体个数最多的是 ( )。", + "options": [ + "A. ![](images/c9eee29470a808f973edc09f3bdb064fca483ecebcdba726009a3839b0420fb3.jpg)", + "B. ![](images/0c379c99b7b2b255e2b7a2eb4e3bdc15c75c0739914c82b193cc0a2e615afb9b.jpg)", + "C. ![](images/2e740cb195b2ef4a43fde3ba4b13bee1bfcfcaaa242ee4d485902d67f2a0aa0a.jpg)" + ], + "answer": "C", + "solution": "【分析】根据题意,依次数出每个选项中正方体的个数,再比较大小即可,要注意的是,上层的每一个正方体下边都有对应的一个正方体。10以内数从大到小关系为: 10 \u003e 9 \u003e 8 \u003e 7 \u003e 6 \u003e 5 \u003e 4 \u003e 3 \u003e 2 \u003e 1,由此比较.\n【详解】A。上层有2个,下层有4个,一共有 2 + 4 = 6(个);B. 上层有 2 个,下层有 5 个,一共有 2 + 5 = 7 (个);C. 上层有 4 个,下层有 6个,一共有 4 + 6 = 10 (个);10 \u003e 7 \u003e 6;则小正方体个数最多的是![](images/d138d164c270dc666a7cf963309c3a50eeb375920db69339392983c2e27b23b3.jpg)故答案为: C", + "knowledge_points": [ + "10 以内数的比大小", + "数正方体的个数", + "7 的加减法", + "10 的加减法" + ], + "source": "24-25 一年级上·河南郑州·期末" + }, + { + "id": "23", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.65, + "question": "下面的物体中,哪一个最容易滚动。()", + "options": [ + "A. ![](images/a207a573cf193cf4d1620de973517c6664def5329a4b78b708c9b2cc26ca9d02.jpg)", + "B. ![](images/bfbb667de4c3277ad1fc305edf302309248ae4c319262cf1471e47e87723bfc4.jpg)", + "C. ![](images/3105e48721d31130394a90753cdc3731805b510354a23d65680e42815e4a756d.jpg)" + ], + "answer": "C", + "solution": "【分析】圆柱只有侧面可以滚动;正方体方方正正的不能滚动;球可以任意滚动.\n【详解】根据分析可知,![](images/493e4aab91e67727b6bf02125092132a7e470ea236c5473b0dc2ef4924387e20.jpg)最容易滚动。故答案为: C", + "knowledge_points": [ + "立体图形的认识及分类" + ], + "source": "24-25 一年级上·四川广元·期末" + }, + { + "id": "24", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.65, + "question": "下图中再添 ( ) 个小正方体就能成为一个大正方体。![](images/f8cdf8154f42871f3266891e6c373ef8017274f6e5ed8083bf2a42f636d4f4c5.jpg)", + "options": [ + "A. 4", + "B. 5", + "C. 6" + ], + "answer": "A", + "solution": "【分析】要成为一个大正方体,至少需要 8 个小正方体(上面 4 个,下面 4 个),现在已经有 4 个,用 8 减 4 即可求解.\n【详解】 8 - 4 = 4 (个),再添 4 个小正方体就能成为一个大正方体。故答案为: A", + "knowledge_points": [ + "立体图形的拼搭", + "数正方体的个数" + ], + "source": "24-25 一年级上·湖北孝感·期末" + }, + { + "id": "25", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "下面第()组组合起来搭得最稳。", + "options": [ + "A. ![](images/9dd4b9a027e79ba8a7d9e5a642686a05c88da6a2745bcc73490df7e46d2f6f81.jpg)", + "B. ![](images/f70a3e8a17347ba62f9b4f4cb92717571f2700f10e551d5f3a448b14b04beaa5.jpg)", + "C. ![](images/f855717696eb2e47cf3a755d6fb336006ba4f66ece6fae5d82370cc511c19354.jpg)" + ], + "answer": "A", + "solution": "【分析】长方体是长长方方的有平平的面,可以直立起来,但不易滚动;正方体是正正方方的有平平的面,可以直立起来,但不易滚动;圆柱上下是平平的面且上下一样粗,侧面是曲面,既可以直立起来,也可以滚动;球是圆圆的,没有平平的面,可以任意方向滚动的,但不可以直立起来;根据立体图形的特征来解决此题.\n【详解】A。![](images/696f3389d59093b9143d8d8d136236d10a46799395c8e8eafeb2fefff26138fd.jpg),此图长方体平平的面与地面接触,且长方体与正方体的接触面都是平平的,这样组合起来搭得最稳 B. ![](images/0431fbd91bc6b03f4fab92ec0b09972a695ffffd1387e3484c0b10ca7c06754f.jpg),此图的下面是球与地面接触,球没有平平的面,可以任意方向滚动,这样组合起来搭不稳。C。 ![](images/48111dcfa7dab88516145125f13132ab42e0d4c525a623060e3b96fc86fabe05.jpg),此图的下面是圆柱的曲面与地面接触,曲面易滚动,这样组合起来搭不稳。即![](images/696f3389d59093b9143d8d8d136236d10a46799395c8e8eafeb2fefff26138fd.jpg)这组合起来搭得最稳。故答案为: A", + "knowledge_points": [ + "立体图形的认识及分类" + ], + "source": "24-25 一年级上·福建福州·期末" + }, + { + "id": "26", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "下面物品 ( ) 的形状是圆柱。", + "options": [ + "A. ![](images/a0e0adc5db5d2360355f848c73222301082e72f522814201c6227cc8d22c9038.jpg)", + "B. ![](images/dec657c0d7489bd3faaaf4e58de1ca1bd2bec35a0a39e02987bcab82f8470aab.jpg)", + "C. ![](images/e07ce3bb170ed8bc3e188dc94e904b0751337e34d40ccb88957dc5332bb59516.jpg)" + ], + "answer": "B", + "solution": "【分析】长方体是长长方方的有平平的面;正方体是正正方方的有平平的面;圆柱上下是平平的面且上下一样粗,侧面是曲面;球是圆圆的,没有平面,可以任意方向滚动的;根据立体图形的特征来解决此题.\n【详解】由题意分析得:A. 是一个球,不符合圆柱特征;B. ,该物体符合圆柱的特征;C. 鼓中间比上下都粗,不符合圆柱特征;即,形状是圆柱。故答案为: B", + "knowledge_points": [ + "立体图形的认识及分类" + ], + "source": "24-25 一年级上·湖北襄阳·期末" + }, + { + "id": "27", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "可以滚动,还可以立起来的图形是()。", + "options": [ + "A. ![](images/d7630bf4231afb03716c08b4be8cc192ca3a0dbf76ce8cf0c3eb6e5f5c1e2f56.jpg)", + "B. ![](images/2e41cd48fc63d87c1564d268bbab540829115dae07ccbf00881b42fdfea41e5f.jpg)", + "C. ![](images/e19e3704c6063abedf74a1390992d88cf49859b03a4e4f72922bc39282e4e1dd.jpg)" + ], + "answer": "A", + "solution": "【分析】圆柱上下是平平的面且上下一样粗,侧面是曲面,既可以滚动,也可以立起来;长方体是长长方方的,有平平的面,可以直立,但不易滚动;球是圆圆的,没有平面,可以任意方向滚动的,但不可以直立起来;根据立体图形的特性来解决此题.\n【详解】A。 既可以滚动,也可以立起来;B. 既可以直立,但不易滚动;C. 可以任意方向滚动的,但不可以直立起来;故答案为: A", + "knowledge_points": [ + "立体图形的认识及分类" + ], + "source": "24-25 一年级上·广东梅州·期末" + }, + { + "id": "28", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "图 ( ) , 在斜坡上落得最快。", + "options": [ + "A. ![](images/5666ff5b4a50005d26ea9d7761a52136ae6cf2622276f32a3ceccb0d53a34427.jpg)", + "B. ![](images/37db3033ea5f32a8765c19217830cdbad8d138c77abd52222215abc29976beed.jpg)", + "C. ![](images/5ba4d22e829cfc70505f61162575e6dbca8be45f6132a140955d9210b0090308.jpg)" + ], + "answer": "B", + "solution": "【分析】长方体:长长方方的,有平平的面;正方体:是四四方方的,有平平的面;圆柱:是直直的,光滑的,上下一样粗,两头是圆的,平平的;球体:圆圆的,表面光滑;长方体和正方体不易滚动,圆柱体和球体易滚动,球体表面都是光滑的,所以它比圆柱体更容易滚动.\n【详解】球体的表面是光滑的,所以球体在斜坡上落得最快。故答案为: B", + "knowledge_points": [ + "立体图形的认识及分类" + ], + "source": "24-25 一年级上·广东汕头·期末" + }, + { + "id": "29", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "![](images/ef56b938d.jpg)左图中有()个正方体", + "options": [ + "A. 5", + "B. 6", + "C. 8" + ], + "answer": "B", + "solution": "【分析】按照顺序数一数即可知有几个正方体(要注意隐藏看不到的正方体),由上到下:第一层有 3 个正方体,第二层有 3 个正方体,一共有 6 个.\n【详解】由分析可知:![](images/b30efa6dd39047f7790f98e1eae5c438012d7fe4f76c3f12b3e0e42912632550.jpg)有6个![](images/8fbce923404d81fac225170fd3766c892fcc81fc9e6b5746a28dc3b89a86585f.jpg)故答案为: B", + "knowledge_points": [ + "数正方体的个数" + ], + "source": "24-25 一年级上·广东汕头·期末" + }, + { + "id": "30", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.65, + "question": "下面既能滚动,又能立起来的是 ( )。", + "options": [ + "A. 正方体", + "B. 圆柱", + "C. 球" + ], + "answer": "B", + "solution": "【分析】正方体不能滚动,圆柱既能滚动又能立起来,球能滚动不能立起来,据此得出结论即可.\n【详解】A。选项正方体不能滚动,不符合题意;B. 选项圆柱既能滚动又能立起来,符合题意;C. 选项球能滚动不能立起来,不符合题意;故答案为: B", + "knowledge_points": [ + "立体图形的认识及分类" + ], + "source": "24-25 一年级上·河北邯郸·期末" + }, + { + "id": "31", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "既可以滚动,也可以立起来的图形是 ( )。", + "options": [ + "A. ![](images/6cc3e1c581843881f6cc24bec8fbd27c54e38c45cce652f0bd173655f6a7fa31.jpg)", + "B. ![](images/5323659004a8049007c0ac1a18c418d00d702a5426450c4848829d16fb11b2db.jpg)", + "C. ![](images/ba3770d2d1b9edd9bc256122fc423f5b9b3c693f5fdaedcf289134b100135f93.jpg)" + ], + "answer": "A", + "solution": "【分析】圆柱上下是平平的面且上下一样粗,侧面是曲面,既可以直立起来,也可以滚动;长方体是长长方方的有平平的面,可以直立起来,但不易滚动;球是圆圆的,没有平面,可以任意方向滚动的,但不可以直立起来;根据立体图形的特征来解决此题.\n【详解】A。 ![](images/6cc3e1c581843881f6cc24bec8fbd27c54e38c45cce652f0bd173655f6a7fa31.jpg) 圆柱既可以直立起来,也可以滚动;B。![](images/5323659004a8049007c0ac1a18c418d00d702a5426450c4848829d16fb11b2db.jpg) ,长方体可以直立起来,但不易滚动;C。![](images/ba3770d2d1b9edd9bc256122fc423f5b9b3c693f5fdaedcf289134b100135f93.jpg),球可以任意方向滚动的,但不可以直立起来;即,既可以滚动,也可以立起来的图形是![](images/6cc3e1c581843881f6cc24bec8fbd27c54e38c45cce652f0bd173655f6a7fa31.jpg),故答案为: A", + "knowledge_points": [ + "立体图形的认识及分类" + ], + "source": "24-25 一年级上·河南漯河·期末" + }, + { + "id": "32", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "下面物体中,滚得最快的是 ( )。", + "options": [ + "A. ![](images/8921bdc548cfeee1aef59757fbb8207b871c2af8c51090ae989b3517bc0c3e6a.jpg)", + "B. ![](images/1e76e5eb56714300b5ca66f5703e66d99065c442dc464f7431f337aa79d8d94b.jpg)", + "C. ![](images/9c18d73f1fafb2d967eb41af45edeac6fb6b85e3d3c5eb4d1dcfff380980fdda.jpg)", + "D. ![](images/8ec4d7603438307a66fc31ceee8110e2dd8108fc5c834e7a5f97fa4a3abdf830.jpg)" + ], + "answer": "B", + "solution": "【分析】长方体是长长方方的,有平平的面,不易滚动;圆柱上下是平平的面且上下一样粗,放倒可以滚动;球没有平面,可以任意方向滚动。根据每个立体图形的特征选择即可.\n【详解】由分析可知:A。![](images/8921bdc548cfeee1aef59757fbb8207b871c2af8c51090ae989b3517bc0c3e6a.jpg) 是长方体,不易滚动,不符合题意;B. ![](images/1e76e5eb56714300b5ca66f5703e66d99065c442dc464f7431f337aa79d8d94b.jpg) 是球,可以任意方向滚动,滚得最快,符合题意;C. ![](images/9c18d73f1fafb2d967eb41af45edeac6fb6b85e3d3c5eb4d1dcfff380980fdda.jpg) 是圆柱,放倒可以滚动,不符合题意;D。![](images/8ec4d7603438307a66fc31ceee8110e2dd8108fc5c834e7a5f97fa4a3abdf830.jpg) 是长方体,不易滚动,不符合题意。故答案为: B", + "knowledge_points": [ + "立体图形的认识及分类" + ], + "source": "24-25 一年级上·辽宁鞍山·期末" + }, + { + "id": "33", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.65, + "question": "下面 ( ) 号组合图形能放稳。", + "options": [ + "A. ![](images/ce5b9877c847be155f16c9ad94da7ebd877aeed83cbb44c279d0eb861ed49411.jpg)", + "B. ![](images/ff6d3f4b5081a553370581d0321d0222633e39f5697b7ccd874cffe49fd4b8b9.jpg)", + "C. ![](images/cfb0774b9ae14f7a90c03b7eb6f9e8a59a416cb5efe8e91c9fca8997101f0f2c.jpg)" + ], + "answer": "B", + "solution": "【分析】圆柱:由 2 个平平的面和 1 个曲面围成,可以向一个方向滚动。球:由1个曲面围成,可以任意滚动。圆锥:由 1 个平平的面和 1 个曲面围成,且是一头是尖尖的。长方体:由 6 个平平的面围成,且是长长的,不易滚动。平平的面放在下面,且两个图形平平的面叠在一起最稳定。尖尖的一头在下面或曲面放在平平的面的上面,这样的放在一起不稳定.\n【详解】A。![](images/3660d2008fa6e06306d1cfc1d826d6c39a9b3d1120342b68f80d2e65fdb4c3fb.jpg)圆锥尖尖的一头在下面,不稳定;B。![](images/ba9ca6cf113d5cbafaf60f73528e0deed517044ad0f7c5a2cf2f1353b93ac5b9.jpg)圆柱平平的面放在下面,且上下两个图形平平的面叠在一起,最稳定;C。![](images/6087418f90f91deacb4ecbae68d225f7e554a2bd1b1c1ebf616bbaecc4a9549b.jpg)尖尖的一头在下面,不稳定![](images/8f66650e67dee4c594a53dae245c6b454f0d97dcf00b352ad4ccc6d4adf2d9ec.jpg)组合图形能放稳。故答案为: B", + "knowledge_points": [ + "组合图形的稳定性", + "立体图形的认识及分类" + ], + "source": "24-25 一年级上·山东济宁·期末" + }, + { + "id": "34", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "先放 2 个正方体,再在 2 个正方体上面放 1 个长方体,然后在长方体上面放 2 个圆柱。搭的正确的是 ( )。", + "options": [ + "A. ![](images/f92e7904c535d57e819cc4a19860e4ed92850105b39eb61397de2d92e5172c4f.jpg)", + "B. ![](images/bc6cbf7a971eeeca15e254c088f1563c372b392de53a528cf885fcc911b4b276.jpg)", + "C. ![](images/0c11e3dd7be9e6b0efe9858b96349b9e2e6204875d0410ff66cdf1c1a1129408.jpg)" + ], + "answer": "B", + "solution": "【分析】长方体是长长方方的有平平的面;正方体是正正方方的有平平的面;圆柱上下是平平的面且上下一样粗,侧面是曲面;球是圆圆的,没有平面,可以任意方向滚动的;根据立体图形的特征依次分析每一个选项,即可解决.\n【详解】A。 此图是先放2个正方体,再在2个正方体上面各放1个圆柱,然后在2个圆柱上面放1个长方体。B。 此图是先放 2 个正方体,再在 2 个正方体上面放 1 个长方体,然后在长方体上面放 2 个圆柱。C。![](images/ede04a416d5b2b6138b6d5e12f6d968a7fb51c24c08fdbf76355752ecb9328d0.jpg),此图是先放1个长方体,再在长方体上面放 2 个正方体,然后在 2 个正方体上面各放 1 个圆柱。故答案为: B", + "knowledge_points": [ + "立体图形的认识及分类" + ], + "source": "24-25 一年级上·陕西西安·期末" + }, + { + "id": "35", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.65, + "question": "下列积木中,搭得又高又稳的一组是 ( )。", + "options": [ + "A. ![](images/f61be64de3aece22fb0fff5787ed0b543d5b6e21564bc214165351a827572cad.jpg)", + "B. ![](images/ac77f0b952230175a6b37f88fed4174e375a842f0990c999a38d458b746cca12.jpg)", + "C. ![](images/398c758e4cce6782ab474c47167eb3f106535b73044fda5901abe9acd120c70c.jpg)" + ], + "answer": "B", + "solution": "【分析】长方体是长长方方的,有 6 个平平的面,且相对的两个面大小一样(特殊情况下有四个面相同);圆柱上下是圆且上下一样粗。根据特征逐项分析.\n【详解】A。长方体和圆柱都是横着放的,不太高;B. 长方体和圆柱都是竖着放,是最高的状态,接触面都是平的,比较稳;C. 长方体横着放的,不太高。搭得又高又稳的一组是![](images/fce415ac8e1bb25369bf41ec8fc1d358bf7bf1e7904ee2642fc6c503889ce7b9.jpg)故答案为: B", + "knowledge_points": [ + "组合图形的稳定性" + ], + "source": "24-25 一年级上·陕西西安·期末" + }, + { + "id": "36", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.94, + "question": "数一数,下面的立体图形中有几块积木。\n![](images/2bab209fbec302fe142dd2676a38b9db4ead0cb672d9e452ed5625a56f3f8faf.jpg)\n![](images/a667a9bfd29e0acae60672d70ef9548375f4705fe7604e04cebbd14e3511cdb8.jpg)\n( )块( )块", + "options": [ + + ], + "answer": "7;8", + "solution": "【分析】根据题图,先数一数,图一,上层有 3 块,下层有 4 块,用上层的数量 + 下层的数量 = 总数量。图二,上层有 3 块,下层有 5 块,用上层的数量 + 下层的数量 = 总数量.\n【详解】根据分析:3 + 4 = 7 (个)![](images/e6a8c7dd2a804b10bb5c468eec017c607dd736dcad007f51cf7f1a17bf21aa25.jpg)(7) 块;3 + 5 = 8 (个)![](images/7ee5e3dcd60d459153f0645dac861d30f6eaab920b35ce9dd612f6eff859c0be.jpg)(8) 块", + "knowledge_points": [ + "数正方体的个数", + "数一数" + ], + "source": "25-26 一年级上·全国·周测" + }, + { + "id": "37", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "这个大正方体是用( )个( )体拼成的,用( )个( )体可以拼成。", + "options": [ + + ], + "answer": "2;长方;8;正方", + "solution": "【分析】根据题图,长方体:长长方方的,有 6 个平平的面,相对的面一样大。正方体:正正方方的,有 6 个平平的面,都相等。![](images/bcf9542a462d5755cccfc6849cce255839efc10d0d1b9d5e31e20e0a713f9dec.jpg)这是一个正方体,所以6个面都相等。![](images/4afba3153d865762c2668ce5c9442aaa131a3383b5589eb6d0ec8dc22d4f9f0c.jpg)如图侧面的大小 = 1 + 2 = 4 + 5,这个正方体是由两个长方体组成。![](images/fa495d69a438536fb0e03fb58480da48b4d31f4f649baf7b9a75935e58629ef9.jpg)通过数一数小正方体的数量,上层有 4 个,下层有 4 个,上层的数量 + 下层的数量 = 一共的数量, 4 + 4 = 8 (个).\n【详解】 4 + 4 = 8 (个)![](images/9fab36a896aa04f17fecc39d8124653b8798133c34b09d813fd71be4c76686e9.jpg)这个大正方体是用(2)个(长方)体拼成的,用(8) 个(正方)体可以拼成![](images/ba80e8cb4ed8d27ddfaed8f740c4894e8452c45dfb76cdee8077b5de740ab212.jpg)", + "knowledge_points": [ + "立体图形的拼搭", + "数正方体的个数", + "立体图形的认识及分类" + ], + "source": "25-26 一年级上·全国·周测" + }, + { + "id": "38", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "数一数,填一填。 ![](images/1a7bc2741c93d2a4ec659844cc5557e30a6cbfdf659ff1451f32f3745e1e1e01.jpg) 长方体有( )个,正方体有( )个,圆柱有( )个,球有( )个。", + "options": [ + + ], + "answer": "6;4;4;3", + "solution": "【分析】长方体是长长方方的,有平平的面;正方体是方方正正的,有平平的面;圆柱上下是圆形的平平的面且上下一样粗;球没有平面,可以任意方向滚动。根据立体图形的特征数一数即可.\n【详解】由分析得: ![](images/a5c3a0fac4635cb2f88428c37f41c79dc1307d0d7d7c37dae0be6d9b18ec9624.jpg) 长方体有 (6) 个,正方体有 (4) 个,圆柱有 (4) 个,球有 (3) 个。", + "knowledge_points": [ + "立体图形的认识及分类" + ], + "source": "25-26 一年级上·江西九江·期中" + }, + { + "id": "39", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.94, + "question": "数一数,填一填。 ![](images/6e5f0c0a283c0c829d259ae1d9df0f4213f028074349d59242416cc9e4aeb172.jpg) 正方体有( )个,长方体有( )个,圆柱有( )个,球有( )个。", + "options": [ + + ], + "answer": "3;4;2;3", + "solution": "【分析】长方体是长长方方的有平平的面;正方体是正正方方的有平平的面;圆柱上下是平平的面且上下一样粗;球没有平面可以任意方向滚动,由此数出各图形的数量即可.\n【详解】由分析得:正方体有3个,长方体有4个,圆柱有2个,球有3个。", + "knowledge_points": [ + "立体图形的认识及分类" + ], + "source": "25-26 一年级上·河北·课后作业" + }, + { + "id": "40", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.94, + "question": "数一数,填一填。 ![](images/8ed1ba1df075a9f77c93e4f9a399064191e639eea8bfe1e6d675707084fbe49e.jpg)()个正方体 ![](images/ed5d23e22f60f62f52f4e5bbefa0383a400ccbe7c1d42e8fdc261e06098422a8.jpg) ()个正方体", + "options": [ + + ], + "answer": "7;8", + "solution": "【分析】图 1:从下往上数,第一层有 4 个正方体,第二层有 3 个正方体,把两层的数量相加即可求出一共有的数量;图2:从下往上数,第一层有5个正方体,第二层有2个正方体,第三层有1个正方体,把三层的数量相加即可求出一共有的数量;【详解】 4 + 3 = 7 (个);5 + 2 + 1 = 8 (个) 则填空如下:![](images/8ed1ba1df075a9f77c93e4f9a399064191e639eea8bfe1e6d675707084fbe49e.jpg)(7)个正方体;![](images/ed5d23e22f60f62f52f4e5bbefa0383a400ccbe7c1d42e8fdc261e06098422a8.jpg)(8) 个正方体", + "knowledge_points": [ + "数正方体的个数", + "数一数" + ], + "source": "25-26 一年级上·全国·课后作业" + }, + { + "id": "41", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.65, + "question": "填空。 ![](images/e4646613f11694093dfe446473a92a2a563dd7a07f9d837fd28ab44c82ed83f7.jpg)![](images/657c64f8126a693847ebb11b42408bc7fd50eaa92105f40f340b76c2f101ce29.jpg)![](images/ae9650d09b6ebcb25576f8aaf13dc2acd48d7201a0e0ae862630339aa439210f.jpg)![](images/0e82b7b5ac88524af97d5a42672b14412921d67687db4f2da6f664157819576b.jpg)![](images/b5f1f3643e79b923a91f78a552db73cd2390101761d2ebbfc6c507264cbc4925.jpg)![](images/cc3b0b1b85d63691c9f4b6b55c6c9161a14d6c8a497cfb116f4c076d9bc1f0c6.jpg)![](images/91d7f33066a9bdd1972b6c0f7fe7b65b9068d4e0784d2840e098c316337ec652.jpg) (1)一共有( )个正方体。 \n(2)从左边数,第( )个是球,第( )个和第( )个是圆柱。 \n(3)从右边数,第()个和第()个是长方体。", + "options": [ + + ], + "answer": "2;4;2;3;1;3", + "solution": "【分析】长方体是长长方方的;正方体是方方正正的,每个面都是正方形;圆柱是上下是平平的面且上下一样粗,侧面是曲面;球是圆圆的,没有平面,可以任意方向滚动。(1) 根据正方体的特征,数一数这列一共有多少正方体即可。 (2) 一般情况下写字的手的一边是右边,和右相对的就是左边分清楚左右,然后从左边开始数,数到球是几就是第几,数到圆柱是几和几就是第几和第几。 (3) 一般情况下写字的手的一边是右边,和右相对的就是左边分清楚左右,然后从右边开始数,数到长方体是几和几就是第几和第几.\n【详解】(1)一共有2个正方体。(2) 从左边数,第 (4) 个是球,第 (2) 个和第 (3) 个是圆柱。 (3) 从右边数,第 (1) 个和第 (3) 个是长方体。", + "knowledge_points": [ + "认识几和第几", + "左,右位置", + "数正方体的个数", + "立体图形的认识及分类" + ], + "source": "25-26 一年级上·全国·单元测试" + }, + { + "id": "42", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.94, + "question": "数一数。 ![](images/ab1ddcec68cf6b5041200b33484428fe.png)", + "options": [ + + ], + "answer": "2;3;4;2", + "solution": "【分析】长方体是长长方方的;正方体是方方正正的,每个面都是方方正正的;圆柱上下是圆圆的平平的面,且上下一样粗,侧面是曲面;球是圆圆的,没有平面,可以任意方向滚动;根据立体图形的特征来数一数,填一填。据此解答.\n【详解】由分析可得: ![](images/f2b3e87082486e4df4ed60e9c68c1f346f985b0b537cc6d3d40f58735188b221.jpg)", + "knowledge_points": [ + "数一数", + "立体图形的认识及分类" + ], + "source": "2025 一年级上·全国·专题练习" + }, + { + "id": "43", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.65, + "question": "要拼成一个大正方体,下面的图形至少还需要几个正方体。 ![](images/f31e7f8ee4ffaae2699645f5a959a347.png)", + "options": [ + + ], + "answer": "7;8", + "solution": "【分析】正方体是方方正正的,有平平的面。要拼成大正方体,则至少有 3 层,每层有 9 个,由此数出每层缺少的数量,相加即可.\n【详解】图1:第一层缺少7个,第二层和第三层不缺;图2:第一层缺少6个;第二层缺少1个;第三层缺少1个;6 + 1 + 1 = 8 (个)。![](images/f4509b6416e55c4283c5502310c7de7639fa8afad20d5e4cf1dcf7fd5a95d27e.jpg)还需要7个。![](images/8e88af180184a29f67d318141c5c1560b522189955e8f6f9555bb76eaef9ad98.jpg) 还需要8个。", + "knowledge_points": [ + "立体图形的拼搭", + "连加", + "连减(10以内)" + ], + "source": "2025 一年级上·全国·专题练习" + }, + { + "id": "44", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "数一数,填一填。 ![](images/f576073e4fb8dda5f11e3655ff059f49079ffbe68c8a1593b8984fdf598c8f40.jpg) \u003ctable\u003e\u003ctr\u003e\u003ctd\u003e球\u003c/td\u003e\u003ctd\u003e圆柱\u003c/td\u003e\u003ctd\u003e正方体\u003c/td\u003e\u003ctd\u003e长方体\u003c/td\u003e\u003c/tr\u003e\u003ctr\u003e\u003ctd\u003e()个\u003c/td\u003e\u003ctd\u003e()个\u003c/td\u003e\u003ctd\u003e()个\u003c/td\u003e\u003ctd\u003e()个\u003c/td\u003e\u003c/tr\u003e\u003c/table\u003e", + "options": [ + + ], + "answer": "2;7;1;2", + "solution": "【分析】长方体是长长方方的有平平的面;正方体是正正方方的有平平的面;圆柱上下是平平的面且上下一样粗;球没有平面可以任意方向滚动,由此数出图形的数量即可.\n【详解】根据分析可得: \u003ctable\u003e\u003ctr\u003e\u003ctd\u003e球\u003c/td\u003e\u003ctd\u003e圆柱\u003c/td\u003e\u003ctd\u003e正方体\u003c/td\u003e\u003ctd\u003e长方体\u003c/td\u003e\u003c/tr\u003e\u003ctr\u003e\u003ctd\u003e2个\u003c/td\u003e\u003ctd\u003e7个\u003c/td\u003e\u003ctd\u003e1个\u003c/td\u003e\u003ctd\u003e2个\u003c/td\u003e\u003c/tr\u003e\u003c/table\u003e", + "knowledge_points": [ + "立体图形的认识及分类" + ], + "source": "25-26 一年级上·全国·单元测试" + }, + { + "id": "45", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "下面的图形中,各有多少个正方体。 ![](images/172ce82c3ca13a29e6d00b5e23597393.png)", + "options": [ + + ], + "answer": "6;8;9", + "solution": "【分析】数清楚每个图形是由几个小正方体组成,再结合题干要求进行解答即可。第一个图形:从上往下数:第一层有 1 个小正方体,第二层有 2 个小正方体,第三层有 3 个小正方体,一共有 6 个小正方体。第二个图形:从上往下数:第一层有 1 个小正方体,第二层有 2 个小正方体,第三层有 5 个小正方体,一共有 8 个小正方体。第三个图形:从上往下数:第一层有 1 个小正方体,第二层有 2 个小正方体,第三层有 6 个小正方体,一共有 9 个小正方体.\n【详解】根据分析可得: ![](images/de47ddfd4450451e74f6cb08f527c40ed49fa8d1f6f9ce35caf1b753f957c2de.jpg) 6个;![](images/6abe1ab947792aa691a9f108736d86cb68ec5983d06017bb81e9ea4f3ec61369.jpg) 8个;![](images/9c8849a70fd96708a26eb38e01ccbd4ecaaabbf722534b48d034ec87580daccd.jpg) 9个", + "knowledge_points": [ + "立体图形的拼搭", + "数正方体的个数", + "立体图形的认识及分类" + ], + "source": "25-26 一年级上·全国·单元测试" + }, + { + "id": "46", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "数一数,填一填。 ![](images/540e341a859d2823b6e820313c960431.png)", + "options": [ + + ], + "answer": "2;2;2;2", + "solution": "【分析】长方体是长长方方的;正方体是方方正正的,每个面都是正方形;圆柱上下是平平的面,且上下一样粗,侧面是曲面;球是圆圆的,没有平面,可以任意方向滚动;根据立体图形的特征,数一数完成填空;在数图形的个数时,应该从 1 开始按顺序数,数到最后一个是几,这些图形就有几个.\n【详解】数一数填空:![](images/992da78d0687515f18b50a3df1927f4f.jpg)", + "knowledge_points": [ + "立体图形的认识及分类" + ], + "source": "25-26 一年级上·全国·单元测试" + }, + { + "id": "47", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "数一数,填一填。 ![](images/263bc1e20806d30f669fd219d4fa4cba.png)", + "options": [ + + ], + "answer": "6;4;4;2", + "solution": "【分析】长方体是长长方方的有平平的面,正方体是正正方方的有平平的面,圆柱上下是平平的面且上下一样粗,球没有平面可以向任意方向滚动,据此数一数填空即可.\n【详解】 ![](images/caf43568403f4a90716c6f73bdbe1ef3.png)", + "knowledge_points": [ + "数一数", + "立体图形的认识及分类" + ], + "source": "25-26 一年级上·全国·单元测试" + }, + { + "id": "48", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.65, + "question": "下图是小猴子搭的积木,数一数,一共用了( )个长方体。 ![](images/955941b961f602cfb2a746a9f0a2e4ed6dccf8a68f2963b623fc0c6f2ec17d50.jpg)", + "options": [ + + ], + "answer": "8", + "solution": "【分析】长方体:长长方方的,有平平的面;根据题意,数题目中的长方体,按照一定的顺序,一层一层的数,从上面开始数,第一层有 1 个,第二层有 2 个,第三层有 3 个,最后一层有 2 个,然后再把每一层的数量相加即可.\n【详解】 1 + 2 + 3 + 2= 3 + 3 + 2 = 6 + 2 = 8 (个) ,一共用了 8 个长方体。", + "knowledge_points": [ + "立体图形的认识及分类", + "连加", + "连减(10以内)" + ], + "source": "25-26 一年级上·全国·课后作业" + }, + { + "id": "49", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "数一数。 ![](images/d67a1a492caedd19119e144b4effa712.png)", + "options": [ + + ], + "answer": "5;9;7", + "solution": "【分析】正方体是正正方方的,每个面都是平平的且都一样;根据正方体的特征分别数一数每层的数量,再把每层的数量相加,即可解决.\n【详解】由题意分析得:第一个图:上层有 2 个,下层有 3 个, 2 + 3 = 5 (个),一共有 5 个;第二个图:从上往下,第一层有 1 个,第二层有 1 个,第三层有 2 个,第四层有 5 个, 1 + 1 + 2 + 5 = 9 (个),一共有 9 个;第三个图:上层有 2 个,下层有 5 个, 2 + 5 = 7 (个),一共有 7 个;![](images/ad7bedad05476c921e462ea49e20fe39d65fcbb2426c739bbcfcf7b1b92f13e3.jpg) 5个![](images/1b80a727e8e2cdf9ee66aa9ba60fb9b3a32251fcffcb2cc4effda2251c34cc65.jpg) 9个![](images/7d6b62e950963590e09d1470a5c3a7007437e9f97e28d08735c52119bb7c6988.jpg) 7个", + "knowledge_points": [ + "数正方体的个数", + "立体图形的认识及分类" + ], + "source": "24-25 一年级下·河南漯河·期末" + }, + { + "id": "50", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.65, + "question": "用一个 ![](images/2caf9344cfe0659da02593ef701dbf7d660cd85bf238ffc2240b0e03a45e05f6.jpg) 做一个正方体,数字\"6\"的对面的数字是( )。", + "options": [ + + ], + "answer": "1", + "solution": "【分析】根据正方体的展开图\"相对不相邻\"可知,1和6相对,4和3相对,2和5相对,由此解答.\n【详解】由分析得:正方体中数字 \"6\"的对面的数字是 1。", + "knowledge_points": [ + "正方体的展开图", + "立体图形的认识及分类" + ], + "source": "24-25 一年级下·广东珠海·期中" + }, + { + "id": "51", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "我会数。 ![](images/10ef558fd4998c095eaefb1a6b6da9ab.png)", + "options": [ + + ], + "answer": "4;1;2;4", + "solution": "【分析】长方体是长长方方的,有 6 个平平的面,且相对的两个面大小一样(特殊情况下有四个面相同);正方体是正正方方的有平平的面;圆柱上下是圆且上下一样粗;球没有平面可以任意方向滚动。数一数.\n【详解】 ![](images/dcb91739e2cfd267f0756612955426399f28853442101eb43da8c636dbd0e358.jpg)", + "knowledge_points": [ + "立体图形的认识及分类" + ], + "source": "24-25 一年级上·湖南株洲·期末" + }, + { + "id": "52", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "数一数,填一填。 ![](images/6d812bca0cdd23b4df1cb6e7af3adc9505afd26d15bb6026f93b30c7f00e8ab7.jpg) 长方体有( )个,正方体有( )个,圆柱体有( )个,球有( )个。", + "options": [ + + ], + "answer": "4;3;3;2", + "solution": "【分析】长方体是长长方方的有平平的面;正方体是正正方方的有平平的面,每面都一样;圆柱上下是圆,是平面且上下一样粗;中间不是平面;球没有平面可以任意方向滚动.\n【详解】由分析可得:![](images/4df096fd556085c8f5e76311bfe3f7a8eaa46c2a896310043fee43f238ce207f.jpg)长方体有(4)个,正方体有(3)个,圆柱体有(3)个,球有(2)个。", + "knowledge_points": [ + "立体图形的认识及分类" + ], + "source": "24-25 一年级上·河南周口·期末" + }, + { + "id": "53", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "数一数。![](images/96d15618132ddba3df628e99dfc5576f.png)", + "options": [ + + ], + "answer": "5;4;5;2", + "solution": "【分析】长方体是长长方方的;正方体是方方正正的,每个面都是正方形;圆柱上下是平平的面,且上下一样粗,侧面是曲面;球是圆圆的,没有平面,可以任意方向滚动;根据立体图形的特征,数一数即可完成填空.\n【详解】根据分析可得: ![](images/445fca0e2a2d21ef7f3f86a239572151.png)", + "knowledge_points": [ + "立体图形的认识及分类" + ], + "source": "24-25 一年级上·甘肃平凉·期末" + }, + { + "id": "54", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "我会数。 ![](images/ad2b030f575004731013f9a9f0e696a869cb3a1222a40337b7af478188ed7063.jpg) 长方体有( )个,正方体有( )个,圆柱体有( )个,球体有( )个。", + "options": [ + + ], + "answer": "6;4;4;3", + "solution": "【分析】长方体是长长方方的,有 6 个平平的面,且相对的两个面大小一样(特殊情况下有四个面相同);正方体是正正方方的有平平的面;圆柱上下是圆且上下一样粗;球没有平面可以任意方向滚动。数一数.\n【详解】 ![](images/4cde99fb39652a8689755d3e582169f97e3ec7752b72912322f2b5fa98b90c8a.jpg)长方体有6个,正方体有4个,圆柱体有4个,球体有3个。", + "knowledge_points": [ + "立体图形的认识及分类" + ], + "source": "24-25 一年级上·湖北黄冈·期末" + }, + { + "id": "55", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "数一数。 ![](images/bfdb6b2e38e6866de6292d2e34f20fea08836530268f258974958d448628fdb4.jpg) 长方体有( )个,正方体有( )个,圆柱体有( )个,球体有( )个。", + "options": [ + + ], + "answer": "5;3;2;6", + "solution": "【分析】长方体是长长方方的,有 6 个平平的面,且相对的两个面大小一样(特殊情况下有四个面相同);正方体是正正方方的有平平的面;圆柱上下是圆且上下一样粗;球没有平面可以任意方向滚动。数一数.\n【详解】![](images/967ff1590399f1bd545da663ba2900cf.png)", + "knowledge_points": [ + "立体图形的认识及分类" + ], + "source": "24-25 一年级上·河南商丘·期末" + }, + { + "id": "56", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "![](images/image-20251202221733854.png) 从左边数,第( )个是球,第( )个也是球,两个球之间有( )个图形。", + "options": [ + + ], + "answer": "3;8;4", + "solution": "【分析】一般情况下写字的手的一边是右边,和右相对的就是左边。球没有平面可以任意方向滚动,圆圆的.\n【详解】 ![](images/677999fe0235a48ddb4a1c5a71fa3f04880d5998a1eb2e89c1b196d394cc008b.jpg) 从左边数,第3个是球,第8个也是球,两个球之间有4个图形。", + "knowledge_points": [ + "左,右位置", + "立体图形的认识及分类" + ], + "source": "24-25 一年级上·湖北荆州·期末" + }, + { + "id": "57", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "数一数。 ![](images/0e77c169247b522d935d8a6e2d090d8cd107cfd9558c4d74edf4af39ed9f7b2c.jpg) 长方体( )个,正方体( )个,圆柱( )个,球体 ( )个。", + "options": [ + + ], + "answer": "5;3;5;2", + "solution": "【分析】长方体是长长方方的;正方体是方方正正的,每个面都是正方形;圆柱是上下是平平的面且上下一样粗,\n侧面是曲面;球是圆圆的,没有平面,可以任意方向滚动;根据立体图形的特征,数一数各个图形的数量填空即可.\n【详解】根据分析可得: ![](images/9544271d8ed2696edee452be98c56e6cf55c2bf4544d6d1086d1a028f31e05bf.jpg) 长方体5个,正方体3个,圆柱5个,球体2个。", + "knowledge_points": [ + "立体图形的认识及分类" + ], + "source": "24-25 一年级上·湖南怀化·期末" + }, + { + "id": "58", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "![](images/429214bf65cb834047c62ee5a9008fe2b8934c228df4086aca1e6872f0888819.jpg) (1)一共有( )个立体图形。 \n(2)长方体有( )个,圆柱有( )个。 \n(3)从右边数,圆柱是第( )个。", + "options": [ + + ], + "answer": "9;3;3;3", + "solution": "【分析】(1)数一数这一列立体图形的总数量。(2) 根据图形的特征数一数各物体的数量。长方体是长长方方的有平平的面;正方体是正正方方的有平平的面,每面都相等;圆柱上下是圆且上下一样粗;球没有平面可以任意方向滚动。(3) 然后根据一般写字的手为右手,即右边,与之相反的是左手,即左边,则从右边数,一个一个数,数到圆柱体,是几就是第几个.\n【详解】(1)一共有9个立体图形。(2) 长方体有 3 个,圆柱有 3 个。(3)从右边数,圆柱是第3个。", + "knowledge_points": [ + "左,右位置", + "立体图形的认识及分类" + ], + "source": "24-25 一年级上·福建龙岩·期末" + }, + { + "id": "59", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.65, + "question": "数一数,填一填。 ![](images/ef99c169af7f0f0bdc32e339298f81ac9bb01db5ae7087c7f587bb9476787de1.jpg) \u003ctable\u003e\u003ctr\u003e\u003ctd\u003e正方体\u003c/td\u003e\u003ctd\u003e圆柱\u003c/td\u003e\u003ctd\u003e长方体\u003c/td\u003e\u003ctd\u003e球\u003c/td\u003e\u003c/tr\u003e\u003ctr\u003e\u003ctd\u003e()个\u003c/td\u003e\u003ctd\u003e()个\u003c/td\u003e\u003ctd\u003e()个\u003c/td\u003e\u003ctd\u003e()个\u003c/td\u003e\u003c/tr\u003e\u003c/table\u003e", + "options": [ + + ], + "answer": "4;3;4;5", + "solution": "【分析】长方体:长长方方的,有平平的面;正方体:是四四方方的,有平平的面;圆柱:是直直的,上下一样粗,两头是圆的,平平的;球体:圆圆的,表面光滑;根据立体图形的特征,数一数即可.\n【详解】填写如下: ![](images/9288b5fb99df16e386b17ecc3fdec41783f6a84204fa3fd5780e850da7399c3d.jpg) \u003ctable\u003e\u003ctr\u003e\u003ctd\u003e正方体\u003c/td\u003e\u003ctd\u003e圆柱\u003c/td\u003e\u003ctd\u003e长方体\u003c/td\u003e\u003ctd\u003e球\u003c/td\u003e\u003c/tr\u003e\u003ctr\u003e\u003ctd\u003e(4)个\u003c/td\u003e\u003ctd\u003e(3)个\u003c/td\u003e\u003ctd\u003e(4)个\u003c/td\u003e\u003ctd\u003e(5)个\u003c/td\u003e\u003c/tr\u003e\u003c/table\u003e", + "knowledge_points": [ + "立体图形的认识及分类" + ], + "source": "24-25 一年级上·湖北武汉·期末" + }, + { + "id": "60", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.65, + "question": "![](images/d6a88e369c24b4733a6930bd67516ba4.png) (1)从右边数,第5个是( ),第( )个是球。 \n(2)图中有( )个圆柱和( )个长方体。 \n(3)球的左边有( )个图形,球的右边有( )个图形。", + "options": [ + + ], + "answer": "正方体;3;3;2;4;2", + "solution": "【分析】根据长方体,正方体,球,圆柱的特征:长方体:长长方方 6 个平平的面,相对两面一个样(特殊情况下 4 个面一样);正方体:正正方方 6 个平平的面,每个面都一样;球:能向四面八方滚动。圆柱:上下圆圆一个样,可以朝一个方向滚动。通常写字的手的一边是右边,与右相对的是左边。依据对立体图形长方体,正方体,圆柱,球的认识,分清左右数一数,再填空;【详解】(1)从右边数,第5个是正方体,第3个是球。(2) 图中有 3 个圆柱和 2 个长方体。 (3) 球的左边有 4 个图形,球的右边有 2 个图形。", + "knowledge_points": [ + "认识几和第几", + "左,右位置", + "数一数", + "立体图形的认识及分类" + ], + "source": "24-25 一年级上·广东揭阳·期末" + }, + { + "id": "61", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "![](images/443c33bdef0dd1475e290685f75068b6.png)有( )个正方体,至少再增加( )个正方体就可以拼成一个大正方体。", + "options": [ + + ], + "answer": "5;3", + "solution": "【分析】下面一层 4 个,上面一层 1 个,共 5 个。拼成一个大正方体至少需要 8 个小正方体,用 8 减已有的 5 个即可求出还需要至少多少个.\n【详解】 8 - 5 = 3 (个)则有(5)个,至少再增加(3)个就可以拼成一个大正方体。", + "knowledge_points": [ + "立体图形的拼搭", + "数正方体的个数" + ], + "source": "21-22 一年级上·湖北武汉·期末" + }, + { + "id": "62", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "![](images/49f08b1087e1143fafbb0a264ec0d95910d16850328390158dbdd27e053710cb.jpg) (1) 一共有()个图形。 \n(2) 圆柱有 ( ) 个,长方体有 ( ) 个。 \n(3) 从右边数,第 ( ) 个是球。 \n(4) 把左边的 3 个图形圈起来。", + "options": [ + + ], + "answer": "7;2;3;3;见详解", + "solution": "【分析】(1)数一数即可知道一共有几个图形。(2) 长方体是长长方方的有平平的面;正方体是正正方方的有平平的面;圆柱上下是平平的面且上下一样粗,侧面是曲面;球是圆圆的,没有平面,可以任意方向滚动的;根据立体图形的特征来数一数即可。(3) 找到右边,然后数出球是排在第几个即可。 (4) 左边的 3 个图形是:圆柱,正方体,长方体 .\n【详解】 ![](images/1fd986e9ce6f1198df0749663f9030c3.png) (1) 一共有 7 个图形。(2) 圆柱有 2 个,长方体有 3 个。 (3) 从右边数,第 3 个是球。 (4) 把左边的 3 个图形圈起来,见上图。", + "knowledge_points": [ + "左,右位置", + "9以内数的排序", + "数一数", + "立体图形的认识及分类" + ], + "source": "24-25 一年级上·浙江嘉兴·期末" + }, + { + "id": "63", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "数一数,各有多少个图形。 ![](images/24347f7c7d87508d4e3b5866cd44e128a1a8d95bfbc0b707a1f687d68e037c38.jpg) 长方体( )个,正方体 ( )个,球体 ( )个,圆柱体 ( )个。", + "options": [ + + ], + "answer": "4;1;2;4", + "solution": "【分析】长方体是长长方方的有平平的面;正方体是正正方方的有平平的面;圆柱上下是平平的面且上下一样粗,侧面是曲面;球是圆圆的,没有平面,可以任意方向滚动的;根据立体图形的特征来解决此题.\n【详解】由题意分析得: ![](images/31b56826140f07d871b50f7fcea6a2b5ef44cb896979a5853c3ee562aa8fa70f.jpg)", + "knowledge_points": [ + "立体图形的认识及分类" + ], + "source": "24-25 一年级上·广东揭阳·期末" + }, + { + "id": "64", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "数一数,填一填。 ![](images/5cdc5053da1405da445113968ec59579da1b7d7bf89dacf550a1ce1d30546a09.jpg) 圆柱体( )个,正方体 ( )个,长方体 ( )个,球体 ( )个。", + "options": [ + + ], + "answer": "6;2;4;2", + "solution": "【分析】正方体:有 6 个面,每个面都由正方形组成;长方体:有 6 个面,每个面都由长方形或相对的一组正方形组成;圆柱:上下两个面为大小相同的圆形,有一个曲面叫侧面;球:球是生活中最常见的图形之一,例如篮球,足球都是球,球是由一个面所围成的几何体。据此解答即可.\n【详解】![](images/4fe9f9396121b2a900e6c1cd74d24156.png)", + "knowledge_points": [ + "立体图形的认识及分类" + ], + "source": "24-25 一年级上·福建三明·期末" + }, + { + "id": "65", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "数一数,填一填。 ![](images/b6c1f4cb536d6648d8467b3b47245fcad62e8d0ce5b4f57a0d8297dd875605b3.jpg) 球有( )个,长方体有( )个,正方体有( )个,圆柱有( )个。", + "options": [ + + ], + "answer": "2;4;1;2", + "solution": "【分析】长方体是长长方方的有平平的面;正方体是正正方方的有平平的面;圆柱上下是平平的面且上下一样粗,侧面是曲面;球是圆圆的,没有平面,可以任意方向滚动的;根据立体图形的特征来解决此题.\n【详解】由题意分析得: ![](images/1b556a47ffb8d12fd18d6561b46ba313e2049a20ab09d732b887d13bf21b99e7.jpg)球有 2 个,长方体有 4 个,正方体有 1 个,圆柱有 2 个。", + "knowledge_points": [ + "立体图形的认识及分类" + ], + "source": "24-25 一年级上·辽宁鞍山·期末" + }, + { + "id": "66", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "数一数。正方体有( )个,长方体有( )个,圆柱有( )个,球有( )个。 ![](images/a1e454bbfef6711bf4626ba263372245a0ad9a7530d00fa60da3a733c6ae742a.jpg)", + "options": [ + + ], + "answer": "5;2;3;2", + "solution": "【分析】长方体是长长方方的有平平的面;正方体是正正方方的有平平的面;圆柱上下是平平的面且上下一样粗,侧面是曲面;球是圆圆的,没有平面,可以任意方向滚动的;根据立体图形的特征数一数,即可解决此题.\n【详解】由题意分析得:数一数。正方体有 5 个,长方体有 2 个,圆柱有 3 个,球有 2 个。 ![](images/a8987fe98e5f50e959ee5a52acf89bdf0f3f5856f429e4d66458fa76fb7eb66e.jpg)", + "knowledge_points": [ + "立体图形的认识及分类" + ], + "source": "24-25 一年级上·河南周口·期末" + }, + { + "id": "67", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "我会分类和整理。 ![](images/953f52a59b119781f91b219e1aaf8dbcad0b186ff2aa6b7e5bd2449c762daf18.jpg) 球有( )个,长方体有( )个,正方体有( )个,圆柱体有( )个。", + "options": [ + + ], + "answer": "6;1;3;6", + "solution": "【分析】球是圆圆的,没有平面,可以任意方向滚动;长方体是长长方方的;正方体是方方正正的,每个面都是正方形;圆柱是上下是平平的面且上下一样粗,侧面是曲面;根据立体图形的特征来解决此题.\n【详解】根据分析可得:球有 6 个,长方体有 1 个,正方体有 3 个,圆柱体有 6 个。", + "knowledge_points": [ + "数一数", + "立体图形的认识及分类" + ], + "source": "24-25 一年级上·福建漳州·期末" + }, + { + "id": "68", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "正方体有( )个,长方体有( )个,球有( )个,圆柱有( )个。 ![](images/522be67fc77f49b2987a82556b0bf26cdbf7e2c4b66741bb7ff1438287a213da.jpg)", + "options": [ + + ], + "answer": "3;4;3;2", + "solution": "【分析】长方体是长长方方的,有 6 个平平的面,且相对的两个面大小一样(特殊情况下有四个面相同);正方体是正正方方的有平平的面;圆柱上下是圆且上下一样粗;球没有平面可以任意方向滚动。据此数一数.\n【详解】正方体有 3 个,长方体有 4 个,球有 3 个,圆柱有 2 个。", + "knowledge_points": [ + "立体图形的认识及分类" + ], + "source": "24-25 一年级上·广东梅州·期末" + }, + { + "id": "69", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "数一数,填一填。 ![](images/ff7745a640ffb8c288eebe2ca1d9e45fc5d65aa3225b09b7c0c124d9568a7f67.jpg) 正方体( )个,长方体 ( )个,球( )个,圆柱 ( )个。", + "options": [ + + ], + "answer": "2;1;3;4", + "solution": "【分析】长方体是长长方方的,有 6 个平平的面,且相对的两个面大小一样(特殊情况下有四个面相同);正方体是正正方方的有平平的面;圆柱上下是圆且上下一样粗;球没有平面可以任意方向滚动。据此数一数.\n【详解】 ![](images/e102704bf8a14526c6f1e6af2828617c637a898ee5516214ab371ff248bc40cc.jpg) 正方体2个,长方体 1个,球3个,圆柱4个", + "knowledge_points": [ + "立体图形的认识及分类" + ], + "source": "24-25 一年级上·河北张家口·期末" + }, + { + "id": "70", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.65, + "question": "![](images/6193d849dc7d5882cb17ea22fc70f215.png)是( )体,至少用( )个同样大的小![](images/6193d849dc7d5882cb17ea22fc70f215.png) 可以拼一个大正方体。", + "options": [ + + ], + "answer": "正方;8", + "solution": "【分析】根据正方体的特点,我们可以看到上边的图形,有六个面,每个面都是平平的,且每个面都是正方形,所以它是正方体。我们可以通过摆一摆,画一画的方法看出来,至少用 8 个同样大小的小正方体可以拼成一个大正方体。据此解答.\n【详解】通过观察可以知道 ![](images/6193d849dc7d5882cb17ea22fc70f215.png)是一个正方体,我们还可以通过摆一摆,画一画的方法,得出一个大正方体,如图![](images/0de61fca890e6f14b4f83457074e157e.png) , 再仔细数一数小正方体的数量可知。![](images/6193d849dc7d5882cb17ea22fc70f215.png)是正方体,至少用(8)个同样大的小![](images/6193d849dc7d5882cb17ea22fc70f215.png)可以拼一个大正方体。", + "knowledge_points": [ + "正方体的特征" + ], + "source": "24-25 一年级上·广西柳州·期末" + }, + { + "id": "71", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "数一数。 ![](images/276ca2ee575bf1b6eda489305cc83196171a6d4c38e6fd7c0314b48ca09ed815.jpg) 长方体( )个;球( )个;圆柱( )个;正方体( )个", + "options": [ + + ], + "answer": "3;2;3;4", + "solution": "【分析】长方体是长长方方的;球是圆圆的,没有平面,可以任意方向滚动;圆柱是上下是平平的面且上下一样粗,侧面是曲面;正方体是方方正正的,每个面都是正方形;根据立体图形的特征来解决此题.\n【详解】由题意分析可得:长方体3个 球2个 圆柱3个 正方体4个。", + "knowledge_points": [ + "立体图形的认识及分类" + ], + "source": "24-25 一年级上·湖南岳阳·期末" + }, + { + "id": "72", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "数一数。 ![](images/bec91e267eafa3ae4ffde858feaa03a61748e4510a0c9baf075361ec7bce47fa.jpg) 长方体有( )个,球 有( )个,圆柱有( )个,正方体有( )个 。", + "options": [ + + ], + "answer": "3;1;5;4", + "solution": "【分析】长方体是长长方方的有平平的面;正方体是正正方方的有平平的面;圆柱上下是平平的面且上下一样粗;球没有平面可以任意方向滚动,由此数出各图形的数量即可.\n【详解】由分析得:长方体有3个,球有1个,圆柱有5个,正方体有4个。", + "knowledge_points": [ + "立体图形的认识及分类" + ], + "source": "24-25 一年级上·新疆喀什·期末" + }, + { + "id": "73", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "数一数。填一填。 ![](images/a9d243f35d0c6f29afebfcc171f0ed7197c5c9bb3e1db0cc2682f6795bbda2c3.jpg) 长方体有( )个,正方体 有( )个,球有( )个,圆柱有( )个 。", + "options": [ + + ], + "answer": "4;1;2;4", + "solution": "【分析】长方体是长长方方的有平平的面;正方体是正正方方的有平平的面;圆柱上下是平平的面且上下一样粗,侧面是曲面;球是圆圆的,没有平面,可以任意方向滚动的;根据立体图形的特征来解决此题.\n【详解】由题意分析得:长方体4个,正方体1个,球2个,圆柱4个。", + "knowledge_points": [ + "立体图形的认识及分类" + ], + "source": "24-25 一年级上·陕西榆林·期末" + }, + { + "id": "74", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "数一数。 ![](images/1d0acd194af4824b48473f45e18f0a3373efe4e16a476d4d3c786be79f925146.jpg) ( )个长方体 ( )个正方体 ( )个圆柱 ( )个球", + "options": [ + + ], + "answer": "3;2;5;1", + "solution": "【分析】长方体是长长方方的,有 6 个平平的面,且相对的两个面大小一样(特殊情况下有四个面相同);正方体是正正方方的有平平的面;圆柱上下是圆且上下一样粗;球没有平面可以任意方向滚动。据此数一数.\n【详解】![](images/d6fcf714c9367b56306e0f1ee31691533ac3e6f908e9e184113f5a8205a78552.jpg)3个长方体,2个正方体,5个圆柱,1个球。", + "knowledge_points": [ + "立体图形的认识及分类" + ], + "source": "24-25 一年级上·甘肃嘉峪关·期末" + }, + { + "id": "75", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "![](images/6418841c9f98c1574e1dea6f5573ef61.png) (1) 从左边数,正方体排第 ( );从右边数,正方体排第 ( ) 。 \n(2) 从左边数,把第6个物体圈起来;从右边数,把第3个物体涂成红色。", + "options": [ + + ], + "answer": "1;8;见详解", + "solution": "【分析】一般情况下,写字的手是右手,右手所指的这边是右边,另一只手所指的这边是左边;据此分清左右边。长方体是长长方方的有平平的面;正方体是正正方方的有平平的面;圆柱上下是平平的面且上下一样粗,侧面是曲面;球是圆圆的,没有平面,可以任意方向滚动的。(1) 分清左右并找出正方体,然后按要求数一数,即可解决。 (2) 分清左右按要求数一数,并圈出来和涂上红色,即可解决.\n【详解】由题意分析得:(1) 从左边数,正方体排第 1;从右边数,正方体排第 8 。(2)![](images/16438d078a536ada5131ee69784665948bab11fc6b2d26843d122c8617b6b437.jpg)", + "knowledge_points": [ + "认识几和第几", + "左,右位置", + "数一数", + "立体图形的认识及分类" + ], + "source": "24-25 一年级上·湖南常德·期末" + }, + { + "id": "76", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.65, + "question": "数一数,填一填。 ![](images/64140154cb0fb3c251186c813706b348.png)", + "options": [ + + ], + "answer": "4;3;4;4", + "solution": "【分析】根据长方体,正方体,球,圆柱的特征:长方体:长长方方 6 个平平的面,相对两面一个样(特殊情况下 4 个面一样);正方体:正正方方 6 个平平的面,每个面都一样;球:能向四面八方滚动。圆柱:上下圆圆一个样,可以朝一个方向滚动。据此数一数每个图形的个数.\n【详解】根据分析: \u003ctable\u003e\u003ctr\u003e\u003ctd\u003e长方体\u003c/td\u003e\u003ctd\u003e4\u003c/td\u003e\u003ctd\u003e球\u003c/td\u003e\u003ctd\u003e3\u003c/td\u003e\u003c/tr\u003e\u003ctr\u003e\u003ctd\u003e正方体\u003c/td\u003e\u003ctd\u003e4\u003c/td\u003e\u003ctd\u003e圆柱\u003c/td\u003e\u003ctd\u003e4\u003c/td\u003e\u003c/tr\u003e\u003c/table\u003e", + "knowledge_points": [ + "数一数", + "立体图形的认识及分类" + ], + "source": "24-25 一年级上·山东济宁·期末" + }, + { + "id": "77", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "数一数,填一填。 ![](images/57c782dd2ebbbab3da0842682df5c0fefd13593a12fdce55de5b10e155a160e3.jpg) \u003ctable\u003e\u003ctr\u003e\u003ctd\u003e长方体\u003c/td\u003e\u003ctd\u003e()个\u003c/td\u003e\u003c/tr\u003e\u003ctr\u003e\u003ctd\u003e正方体\u003c/td\u003e\u003ctd\u003e()个\u003c/td\u003e\u003c/tr\u003e\u003ctr\u003e\u003ctd\u003e圆柱\u003c/td\u003e\u003ctd\u003e()个\u003c/td\u003e\u003c/tr\u003e\u003ctr\u003e\u003ctd\u003e球\u003c/td\u003e\u003ctd\u003e()个\u003c/td\u003e\u003c/tr\u003e\u003c/table\u003e", + "options": [ + + ], + "answer": "6;3;4;3", + "solution": "【分析】长方体是长长方方的;正方体是方方正正的,每个面都是正方形;圆柱上下是平平的面,且上下一样粗,侧面是曲面;球是圆圆的,没有平面,可以任意方向滚动;根据立体图形的特征来解决此题.\n【详解】由分析可得: \u003ctable\u003e\u003ctr\u003e\u003ctd\u003e长方体\u003c/td\u003e\u003ctd\u003e(6)个\u003c/td\u003e\u003c/tr\u003e\u003ctr\u003e\u003ctd\u003e正方体\u003c/td\u003e\u003ctd\u003e(3)个\u003c/td\u003e\u003c/tr\u003e\u003ctr\u003e\u003ctd\u003e圆柱\u003c/td\u003e\u003ctd\u003e(4)个\u003c/td\u003e\u003c/tr\u003e\u003ctr\u003e\u003ctd\u003e球\u003c/td\u003e\u003ctd\u003e(3)个\u003c/td\u003e\u003c/tr\u003e\u003c/table\u003e", + "knowledge_points": [ + "立体图形的认识及分类" + ], + "source": "24-25 一年级上·甘肃兰州·期末" + }, + { + "id": "78", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "我会数。 ![](images/28344ddc83d4b2282fcf95b79e740ee2408c35f6f2ee955c297d2dcc2fae6445.jpg) 长方体有( )个,正方体有( )个,圆柱有( )个,球有( )个。", + "options": [ + + ], + "answer": "5;5;4;3", + "solution": "【分析】长方体是长长方方的有平平的面;正方体是正正方方的有平平的面,每面都相等;圆柱上下是圆且上下一样粗;球没有平面可以任意方向滚动;据此数一数即可.\n【详解】长方体有 5 个,正方体有 5 个,圆柱有 4 个,球有 3 个。", + "knowledge_points": [ + "数一数", + "立体图形的认识及分类" + ], + "source": "24-25 一年级上·甘肃平凉·期末" + }, + { + "id": "79", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.65, + "question": "数一数,填一填。 ![](images/cd89d0ec7a5e3d0ad7d56282d8f6012bd67ac638e0dfe8f4556431c1940cfe34.jpg) ![](images/2283f539a706198641a6a34993943267d2429b1c2211a36ae09081ff7051bc25.jpg) \u003ctable\u003e\u003ctr\u003e\u003ctd\u003e长方体\u003c/td\u003e\u003ctd\u003e正方体\u003c/td\u003e\u003ctd\u003e圆柱\u003c/td\u003e\u003ctd\u003e球\u003c/td\u003e\u003c/tr\u003e\u003ctr\u003e\u003ctd\u003e\u003c/td\u003e\u003ctd\u003e\u003c/td\u003e\u003ctd\u003e\u003c/td\u003e\u003ctd\u003e\u003c/td\u003e\u003c/tr\u003e\u003c/table\u003e", + "options": [ + + ], + "answer": "3;4;3;2", + "solution": "【分析】长方体是长长方方的,有 6 个平平的面,且相对的两个面大小一样(特殊情况下有四个面相同);正方体是正正方方的有平平的面;圆柱上下是圆且上下一样粗;球没有平面可以任意方向滚动。据此数一数.\n【详解】![](images/3d0e56b254c6d1acf8a07c69d176ba58a2d86f7b849f5f07c7714eab4115264e.jpg)![](images/c5c69b7021ed4c51786d42714ec99be8e3e8c37b6b3eed9e521a8a36b6649577.jpg) \u003ctable\u003e\u003ctr\u003e\u003ctd\u003e长方体\u003c/td\u003e\u003ctd\u003e正方体\u003c/td\u003e\u003ctd\u003e圆柱\u003c/td\u003e\u003ctd\u003e球\u003c/td\u003e\u003c/tr\u003e\u003ctr\u003e\u003ctd\u003e3\u003c/td\u003e\u003ctd\u003e4\u003c/td\u003e\u003ctd\u003e3\u003c/td\u003e\u003ctd\u003e2\u003c/td\u003e\u003c/tr\u003e\u003c/table\u003e", + "knowledge_points": [ + "立体图形的认识及分类" + ], + "source": "24-25 一年级上·广东汕头·期末" + }, + { + "id": "80", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.65, + "question": "数一数,填一填。 ![](images/04a21c333117a1969e6160a405d17d3206c85e2c7ae5a4689409d0ed13939c7b.jpg) \u003ctable\u003e\u003ctr\u003e\u003ctd\u003e长方体\u003c/td\u003e\u003ctd\u003e()个\u003c/td\u003e\u003c/tr\u003e\u003ctr\u003e\u003ctd\u003e正方体\u003c/td\u003e\u003ctd\u003e()个\u003c/td\u003e\u003c/tr\u003e\u003ctr\u003e\u003ctd\u003e球\u003c/td\u003e\u003ctd\u003e()个\u003c/td\u003e\u003c/tr\u003e\u003ctr\u003e\u003ctd\u003e圆柱\u003c/td\u003e\u003ctd\u003e()个\u003c/td\u003e\u003c/tr\u003e\u003c/table\u003e", + "options": [ + + ], + "answer": "4;1;2;4", + "solution": "【分析】首先要分别分析出图片中各个物体的特征:长方体有 6 个平平的面,长长的方方的;正方体四四方方的,有 6 个平平的面,每个面的大小都一样;圆柱直直的,上下一样粗,两端是两个大小一样的,圆圆的,平平的圆面,把圆柱横放在桌子上能滚动,立在桌子上就不能滚动;球是圆圆的,表面是曲面,把球放在桌子上能向任意方向滚动。根据每个物体的特征分别数一数图中各个物体的个数即可.\n【详解】填空如下: \u003ctable\u003e\u003ctr\u003e\u003ctd\u003e长方体\u003c/td\u003e\u003ctd\u003e4个\u003c/td\u003e\u003c/tr\u003e\u003ctr\u003e\u003ctd\u003e正方体\u003c/td\u003e\u003ctd\u003e1个\u003c/td\u003e\u003c/tr\u003e\u003ctr\u003e\u003ctd\u003e球\u003c/td\u003e\u003ctd\u003e2个\u003c/td\u003e\u003c/tr\u003e\u003ctr\u003e\u003ctd\u003e圆柱\u003c/td\u003e\u003ctd\u003e4个\u003c/td\u003e\u003c/tr\u003e\u003c/table\u003e", + "knowledge_points": [ + "数一数", + "立体图形的认识及分类" + ], + "source": "24-25 一年级上·陕西榆林·期末" + }, + { + "id": "81", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "数一数,算一算。 ![](images/c7c78d2dbba9740d3e25a50ce733507620fe947919f9535d211ccd80eb01029c.jpg) (1)长方体有( )个,正方体有( )个,圆柱有( )个,球有( )个。 \n(2)长方体和圆柱一共有( )个。 \n(3)拿走 2 个球后,还剩( )个球。", + "options": [ + + ], + "answer": "3;2;3;3;6;1", + "solution": "【分析】(1)长方体是长长方方的有平平的面;正方体是正正方方的有平平的面;圆柱上下是平平的面且上下一样粗;球没有平面可以任意方向滚动,由此数出各图形的数量即可;(2) 根据加法的意义,长方体的数量 + 圆柱的数量 = 长方体和圆柱一共的数量;(3) 根据减法的意义,球的总数量 - 拿走的数量 = 还剩的数量.\n【详解】(1)长方体有 3 个,正方体有 2 个,圆柱有 3 个,球有 3 个。(2) 3 + 3 = 6 (个)长方体和圆柱一共有 6 个。(3) 3 - 2 = 1 (个) 拿走 2 个球后,还剩 1 个球。", + "knowledge_points": [ + "6 的加减法", + "5 以内数的减法", + "立体图形的认识及分类" + ], + "source": "24-25 一年级上·甘肃陇南·期末" + }, + { + "id": "82", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.65, + "question": "数一数,填一填。 ![](images/32dccd7b9cc6004246632e59308e7ba0637851578d1d7d0fcb083ac56671b373.jpg) 球有( )个,长方体有( )个,正方体有( )个,圆柱有( )个。", + "options": [ + + ], + "answer": "3;3;2;3", + "solution": "【分析】根据长方体,正方体,球,圆柱的特征,长方体:长长方方6个平平的面,相对两面一个样(特殊情况下四个面一样);正方体:正正方方6个平平的面,每个面都一样;球:球没有平面,能向四面八方滚动。圆柱:上下是平平的面,上下圆圆一个样,可以朝一个方向滚动.\n【详解】根据分析,数一数每个图形的个数,球有3个,长方体有3个,正方体有2个,圆柱有3个。", + "knowledge_points": [ + "立体图形的认识及分类" + ], + "source": "24-25 一年级上·吉林长春·期末" + }, + { + "id": "83", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "![](images/d3b41234108bcf3a62b34b7d7c2da870c09fcfa12c06e8af1519f2ac40d5f909.jpg) 长方体( )个;正方体( )个;圆柱( )个;球( )个。", + "options": [ + + ], + "answer": "4;3;3;4", + "solution": "【分析】长方体是长长方方的有平平的面;正方体是正正方方的有平平的面;圆柱上下是平平的面且上下一样粗;球没有平面可以任意方向滚动,由此数出各图形的数量即可.\n【详解】由分析得:长方体 4 个;正方体 3 个;圆柱 3 个;球 4 个。", + "knowledge_points": [ + "立体图形的认识及分类" + ], + "source": "24-25 一年级上·青海西宁·期末" + }, + { + "id": "84", + "unit": "第三单元 认识立体图形", + "question_type": "判断题", + "difficulty": 0.85, + "question": "正方体有 6 个面,每个面都是正方形。()![](images/53bcddc202ab818b386e1e8fef399886d6e4dabd7f0e7d60e2c58b6364a9e1bb.jpg)", + "options": [ + + ], + "answer": "√", + "solution": "【分析】正方体是方方正正的,有 6 个完全一样的面,每个面都是正方形;据此判断.\n【详解】正方体有 6 个面,每个面都是正方形,原题说法正确。故答案为: √", + "knowledge_points": [ + "立体图形的认识及分类" + ], + "source": "25-26 一年级上·黑龙江·开学考试" + }, + { + "id": "85", + "unit": "第三单元 认识立体图形", + "question_type": "判断题", + "difficulty": 0.85, + "question": "![](images/b5696d860047e20905a54a9a89f2173377e17e30c2e6d3777b509b9769b17c92.jpg)图中有3个小正方体。()", + "options": [ + + ], + "answer": "×", + "solution": "【分析】下面3个,上面1个,一共4个,据此解答.\n【详解】![](images/80a135b138f981b4d100e1970e7df9236be35a1e357fb2c86b3e63e840f23e3a.jpg)图中有 4 个小正方体。原题说法错误。故答案为: ×", + "knowledge_points": [ + "数正方体的个数" + ], + "source": "18-19 一年级上·全国·期末" + }, + { + "id": "86", + "unit": "第三单元 认识立体图形", + "question_type": "判断题", + "difficulty": 0.85, + "question": "可以滚动的物体都是球体。( )", + "options": [ + + ], + "answer": "×", + "solution": "【分析】根据我们学过的立体图形可知,长方体是长长方方的有平平的面;正方体是正正方方的有平平的面;圆柱上下是平平的面且上下一样粗,可以立起来,放倒易滚动;球没有平面可以任意方向滚动,由此解答.\n【详解】由分析可知:球可以随意滚动,圆柱放倒易滚动,则可以滚动的物体不都是球体,原题说法错误。故答案为: ×", + "knowledge_points": [ + "立体图形的认识及分类" + ], + "source": "24-25 一年级上·湖北恩施·期末" + }, + { + "id": "87", + "unit": "第三单元 认识立体图形", + "question_type": "判断题", + "difficulty": 0.85, + "question": "用 4 个 ![](images/502908cd2ded9ac08b8b21587e92f20a672c7ad6efd65507ff0208f2a0b0703c.jpg)可以拼成 ![](images/8acd779ec2f644a8aaa7dc28982daeb1.png)。( )", + "options": [ + + ], + "answer": "√", + "solution": "【分析】![](images/8acd779ec2f644a8aaa7dc28982daeb1.png)上层有1个![](images/502908cd2ded9ac08b8b21587e92f20a672c7ad6efd65507ff0208f2a0b0703c.jpg),下层有3个![](images/502908cd2ded9ac08b8b21587e92f20a672c7ad6efd65507ff0208f2a0b0703c.jpg) ,合起来一共有4个![](images/502908cd2ded9ac08b8b21587e92f20a672c7ad6efd65507ff0208f2a0b0703c.jpg);据此判断即可.\n【详解】由分析可知:用 4 个![](images/502908cd2ded9ac08b8b21587e92f20a672c7ad6efd65507ff0208f2a0b0703c.jpg)可以拼成![](images/8acd779ec2f644a8aaa7dc28982daeb1.png) 。此说法正确。故答案为: √", + "knowledge_points": [ + "立体图形的拼搭", + "数正方体的个数" + ], + "source": "24-25 一年级上·河南商丘·期末" + }, + { + "id": "88", + "unit": "第三单元 认识立体图形", + "question_type": "判断题", + "difficulty": 0.85, + "question": "足球,皮球都是圆形的。( )", + "options": [ + + ], + "answer": "√", + "solution": "【分析】足球![](images/7b9262957947909b8d1e0e7cede22e2bced8f3066bd733de1c3c8f194ae1dda2.jpg),皮球![](images/f5c50d2a6f3372ace7fc462e4b7b8874b7d0244ba89eb1b2aa6bd635fda81f9d.jpg),观察可知,它们都是圆圆的,是圆形的.\n【详解】足球,皮球都是圆形的。原题说法正确。故答案为: √", + "knowledge_points": [ + "立体图形的认识及分类" + ], + "source": "24-25 一年级上·黑龙江绥化·期末" + }, + { + "id": "89", + "unit": "第三单元 认识立体图形", + "question_type": "判断题", + "difficulty": 0.85, + "question": "正方体比球滚得快。( )", + "options": [ + + ], + "answer": "×", + "solution": "【分析】正方体是方方正正的,有 6 个平平的面,不易滚动。球没有平面可任意滚动,由此解答.\n【详解】由分析可知,正方体比球滚得慢,原题说法错误。故答案为: ×", + "knowledge_points": [ + "立体图形的认识及分类" + ], + "source": "24-25 一年级下·河南许昌·开学考试" + }, + { + "id": "90", + "unit": "第三单元 认识立体图形", + "question_type": "判断题", + "difficulty": 0.85, + "question": "魔方是长方体。( )", + "options": [ + + ], + "answer": "×", + "solution": "【分析】长方体是长长方方的有平平的面;正方体是正正方方的有平平的面;由此结合生活经验进行解答.\n【详解】如图为魔方,是方方正正的,是正方体,原题说法错误。![](images/b4b17d99712bec99cf9e40d0fa73a015.png)故答案为: ×", + "knowledge_points": [ + "立体图形的认识及分类" + ], + "source": "24-25 一年级上·湖南株洲·期末" + }, + { + "id": "91", + "unit": "第三单元 认识立体图形", + "question_type": "判断题", + "difficulty": 0.65, + "question": "长方体和正方体都有六个平平的面。( )", + "options": [ + + ], + "answer": "√", + "solution": "【分析】像礼品盒一样长长方方的是长方体,像魔方一样正正方方的,有 6 个一样的面是正方体,长方体和正方体都有 6 个平平的面,据此得出结论即可.\n【详解】根据分析知:长方体和正方体都有六个平平的面,说法正确。故答案为: √", + "knowledge_points": [ + "立体图形的认识及分类" + ], + "source": "24-25 一年级上·甘肃天水·期末" + }, + { + "id": "92", + "unit": "第三单元 认识立体图形", + "question_type": "判断题", + "difficulty": 0.65, + "question": "2个![](images/10800c9af9a58a89548bd806b32cdf5c.png)可以搭成 1 个大长方体。( )", + "options": [ + + ], + "answer": "√", + "solution": "【分析】根据题意图形是长长方方的有平平的面,是长方体;如图![](images/da1e8a954b951af42c4de45cdd41241e57beb48b5f681c8d6ef48febc6f911c3.jpg)拼成的是长长方方的有平平的面,是长方体.\n【详解】根据分析, 2 个![](images/10800c9af9a58a89548bd806b32cdf5c.png)可以搭成 1 个大长方体。原题说法正确。故答案为: √", + "knowledge_points": [ + "立体图形的拼搭", + "立体图形的认识及分类" + ], + "source": "24-25 一年级上·山东菏泽·期末" + }, + { + "id": "93", + "unit": "第三单元 认识立体图形", + "question_type": "判断题", + "difficulty": 0.85, + "question": "正方体都一样大。( )", + "options": [ + + ], + "answer": "×", + "solution": "【分析】根据正方体的特点:正方体:有 6 个面,每个面都由正方形组成;正方形有大有小,所以正方体的大小也都不一样.\n【详解】例如: ![](images/627938ad0fbba5e36fa75916b554348360c5235083054b128fa8225a6b1ef0fe.jpg)和![](images/502908cd2ded9ac08b8b21587e92f20a672c7ad6efd65507ff0208f2a0b0703c.jpg)这两个正方体的大小不一样。原题说法错误。故答案为: ×", + "knowledge_points": [ + "立体图形的认识及分类" + ], + "source": "24-25 一年级上·山东菏泽·期末" + }, + { + "id": "94", + "unit": "第三单元 认识立体图形", + "question_type": "判断题", + "difficulty": 0.85, + "question": "用4个相同的小正方体能拼成一个长方体。()", + "options": [ + + ], + "answer": "√", + "solution": "【分析】长方体是长长方方的有平平的面;正方体是正正方方的有平平的面。把 4 个相同的小正方体并排在一起就可以拼成一个长方体(如下图).\n【详解】由题意分析得:用 4 个相同的小正方体能拼成一个长方体。此说法正确。故答案为: √ ![](images/07b19b454aa9cde83360f61768a40aeb318a751231a6430b393b4f37fb512ad7.jpg)", + "knowledge_points": [ + "正方体的特征", + "长方体的认识及特征" + ], + "source": "24-25 一年级上·吉林·期末" + }, + { + "id": "95", + "unit": "第三单元 认识立体图形", + "question_type": "作图题", + "difficulty": 0.85, + "question": "![](images/018d7600a3d6490ddd76b83fde12bbaf9691eba14c153a50bfe5f06825493d16.jpg) (1) 一共有()个圆柱。 \n(2) 从右边起,第 ( ) 个和第 ( ) 个是正方体。 \n(3) 把从左边数的第 2 个图形圈起来;把从右边数的第 3 个图形涂上颜色。", + "options": [ + + ], + "answer": "2;3;7;见详解", + "solution": "【分析】(1)长方体是长长方方的有平平的面;正方体是正正方方的有平平的面,每面都相等;圆柱上下是圆且上下一样粗;球没有平面可以任意方向滚动,则根据圆柱的特征数一数圆柱的个数即可。(2) 一般写字的是右手,即右边,与之相反的是左手即左边,然后从右边数,一个一个数,数到正方体是几和几就是第几和第几。 (3) 一般写字的是右手,即右边,与之相反的是左手即左边,然后从左边数,数到 2,把 2 这个图形给圈起来即可,从右边数数到 3,把 3 这个图形涂色即可.\n【详解】(1)一共有(2)个圆柱。(2) 从右边起,第 (3) 个和第 (7) 个是正方体。 (3) 由分析可得: ![](images/43981ed3502cbd0759d3be88026f3cc119ae55aed913ca7c978356b5e694171f.jpg)", + "knowledge_points": [ + "左,右位置", + "数一数", + "立体图形的认识及分类" + ], + "source": "24-25 一年级上·湖南娄底·期末" + }, + { + "id": "96", + "unit": "第三单元 认识立体图形", + "question_type": "作图题", + "difficulty": 0.85, + "question": "![](images/e34c3b555cc0271f44bddf8eef2915f8821076d1012bef7004d79590746116eb.jpg) (1) 图中长方体有()个,正方体有()个,它们一共有()个.\n(2) 把图中最容易滚动的图形圈出来,有 ( ) 个;在可以立起来,也可以滚动的图形下面打\"√\"有 ( ) 个。", + "options": [ + + ], + "answer": "4;4;8;2;2", + "solution": "【分析】(1)长方体是长长方方的;正方体是方方正正的,每个面都是正方形;根据长方体和正方体的特征,结合图示数一数填空即可。(2) 球是圆圆的,没有平面,可以任意方向滚动;圆柱是上下是平平的面且上下一样粗,侧面是曲面,可以立起来,也可以滚动;结合图示数数填空即可,并在圆柱的下面画\"√\".\n【详解】(1)图中长方体有4个,正方体有4个,它们一共有 8 个。(2) 把图中最容易滚动的图形圈出来,有 2 个;在可以立起来,也可以滚动的图形下面打\"√\"有 2 个。作图如下: ![](images/443d26f3a794ecbd1a7247d4823e13b602ab889a6286eb2a09eb3fb1432e8217.jpg)", + "knowledge_points": [ + "立体图形的认识及分类" + ], + "source": "24-25 一年级上·重庆九龙坡·期末" + }, + { + "id": "97", + "unit": "第三单元 认识立体图形", + "question_type": "解答题", + "difficulty": 0.65, + "question": "下图中最少再堆几个小正方体,正好堆成一个大正方体。 ![](images/67e0bff14aeb374499c8498d1b2466fe791adc5e0acf42f427ba60b8dd03ab32.jpg)", + "options": [ + + ], + "answer": "11个", + "solution": "【分析】观察题图可知,要堆成 3×3×3 的大正方体,每层应有 9 个小正方体。分别数出各层已有数量,用每层应有数量减去已有数量,再把各层缺少的数量相加即可.\n【详解】底层已有 9 个,中间层已有 5 个,还缺 9 - 5 = 4 (个);顶层已有 2 个,还缺 9 - 2 = 7 (个);一共还需 4 + 7 = 11 (个).答:最少再堆 11 个小正方体,正好堆成一个大正方体。", + "knowledge_points": [ + "数正方体的个数" + ], + "source": "25-26 一年级上·全国·周测" + }, + { + "id": "98", + "unit": "第三单元 认识立体图形", + "question_type": "解答题", + "difficulty": 0.85, + "question": "用 4 个相同的![](images/22aa86373a61007c7d1c4f8d76c4e196865bba592458c227ee4191cda916a995.jpg),你能拼出哪几种不同的长方体。", + "options": [ + + ], + "answer": "见详解", + "solution": "【分析】①一字排列时,因为小长方体有 3 种不同的面,所以分别让不同的面互相贴合,即能拼出 3 种不同的长方体;②分两层排列,一层 2 个,也能拼出 3 种不同的长方体;由此即可解答.\n【详解】由分析可得: ![](images/e56314c497523030ba82b6e2400e7541.png)", + "knowledge_points": [ + "立体图形的拼搭", + "长方体的认识及特征" + ], + "source": "25-26 一年级上·全国·随堂练习" + }, + { + "id": "99", + "unit": "第三单元 认识立体图形", + "question_type": "解答题", + "difficulty": 0.85, + "question": "数一数,下图由几个正方体组成。 ![](images/77c8a541b741bf76db3650069b48d34208a5e82eabc76038f951c774baa7ba90.jpg)", + "options": [ + + ], + "answer": "8个", + "solution": "【分析】按列数小正方体(每列高度即该列正方体个数),再把各列数量相加,即可求出总数.\n【详解】各列高度分别为 1、1、2、3、1,1 + 1 + 2 + 3 + 1 = 8 (个).答:图片是由 8 个正方体组成的。", + "knowledge_points": [ + "立体图形的拼搭", + "数正方体的个数" + ], + "source": "25-26 一年级上·全国·课后作业" + }, + { + "id": "100", + "unit": "第三单元 认识立体图形", + "question_type": "解答题", + "difficulty": 0.65, + "question": "数一数,下图中由几个正方体组成。 ![](images/b8d3b3111f852a42b1226568a5a8bd9af0e63527066fe190b3aa5148e4f905a9.jpg)", + "options": [ + + ], + "answer": "10个", + "solution": "【分析】观察该图可知,最上层有 4 个正方体,底层共有 6 个正方体。根据加法的意义,最上层的正方体数量 + 底层的正方体数量 = 正方体的总数量,由此列出算式即可解答.\n【详解】 4 + 6 = 10 (个)答:图中由 10 个正方体组成。", + "knowledge_points": [ + "数正方体的个数" + ], + "source": "25-26 一年级上·全国·课后作业" + }, + { + "id": "101", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "用 10 个小正方体正好可以拼出下面的()和()。 ![](images/7a81d8fe9aadeba94a389182dfcf9b48.png)", + "options": [ + "A. ①③", + "B. ①②", + "C. ②③" + ], + "answer": "A", + "solution": "【分析】数一数分别有多少个,再看看哪两个数合起来是 10 即可.\n【详解】①有 5 个,②有 4 个,③有 5 个。5 + 5 = 10 (个),用 10 个小正方体正好可以拼出下面的①和③.故答案为: A", + "knowledge_points": [ + "数正方体的个数", + "10 的加减法" + ], + "source": "25-26 一年级上·江西九江·期中" + }, + { + "id": "102", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "下面搭得最不稳的是 ( )。 ![](images/be997b01ddaf7c67e5c63cab748168c3.png)", + "options": [ + + ], + "answer": "B", + "solution": "【分析】长方体是长长方方的,有 6 个平平的面,且相对的两个面大小一样(特殊情况下有四个面相同);正方体是正正方方的有平平的面;圆柱上下是圆且上下一样粗;球没有平面可以任意方向滚动。根据它们的特征分析.\n【详解】A。![](images/1ab6eb4e1c1651f1e7c32e05c066b778e2dab895cf10436baa938211815ffc50.jpg)球会滚动,不稳;B。![](images/40622a1f9e093185aa280a5586a68587b901aac1aa94b230b56524003ed45d6d.jpg)球和圆柱的侧面都会滚动,非常不稳;C。![](images/7dae9a10b7759333849bf85f4817ad83fc9d706aa455a393eca1397ff66ad86a.jpg)相互接触的面都是平平的,比较稳定。搭得最不稳的是![](images/81545da4bae2d9d02d453408873aa5cc090ad27d93853a5cd8b0d1218230bff5.jpg)。故答案为: B", + "knowledge_points": [ + "组合图形的稳定性" + ], + "source": "25-26 一年级上·江西九江·期中" + }, + { + "id": "103", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "![](images/959cf95ae1170dfacfee7530ff2b0ee7bd4fb413799cab3e559afef0203a7e4a.jpg)中有()个![](images/d04fce40142507a94068250ab753d8aaca79db6ff9550572b2491b8a002a307e.jpg)", + "options": [ + "A. 3", + "B. 4", + "C. 5" + ], + "answer": "B", + "solution": "【分析】数一数可知:上层有 1 个小正方体,下层有 3 个小正方体,合起来一共有 4 个。据此解答.\n【详解】 1 + 3 = 4 (个)![](images/e6aa11984acdc5949575489b2ff78b951e6adcd366328fa70e0e4b7f2b3b7f60.jpg)中有 4 个![](images/80482a4f6a100a136daaa3941e40491cd608cefacdc93c17cecc8293df3297b3.jpg)故答案为: B", + "knowledge_points": [ + "数一数", + "立体图形的拼搭" + ], + "source": "25-26 一年级上·江西九江·期中" + }, + { + "id": "104", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "下面()不是用 5 个相同的小正方体拼成的。 ![](images/cc98150608eae6ecbb28b377e83347c2.png)", + "options": [ + + ], + "answer": "C", + "solution": "【分析】根据正方体(正方体是正正方方的有平平的面)的特征,分别数一数各有几个,然后找出符合题意的,即可解决.\n【详解】A。![](images/cfe43f089e542d1d7c3016bb6ed7f9f514b29c3bf7a88e2a52156e4dd32c0d2c.jpg), 此图用 5 个![](images/41fdfc95420bce277b79211fa165cb33ff9e129c5a7a6c73337c472a9e07ca7f.jpg)拼成的。B。![](images/262c54917594da4d373b15fafc72838aa6a9ea69e1c23ae5f86c9878028b267c.jpg),此图用 5 个![](images/41fdfc95420bce277b79211fa165cb33ff9e129c5a7a6c73337c472a9e07ca7f.jpg)拼成的。C。![](images/26d0ad3f6e75e443fc59deda0a8e6a82fe0884999c9f1db33d8f3282dbe45dfe.jpg),此图用 4 个拼成的。故答案为: C", + "knowledge_points": [ + "数正方体的个数" + ], + "source": "25-26 一年级上·江西九江·期中" + }, + { + "id": "105", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "下面的图形, ( )是用 5 个相同的正方体拼成的。 ![](images/70d3cce4c1ec09f009d5e777f20e2b15.png)", + "options": [ + + ], + "answer": "B", + "solution": "【分析】根据题意,分别数出每组图形中正方体的数量,选择总数量是 5 个的即可。要注意的是,上层的每一个图形下边都有对应的一个图形.\n【详解】A。上层有1个,下层有3个,一共有 1 + 3 = 4 (个),不符合题意;B. 上层有 1 个,下层有 4 个,一共有 1 + 4 = 5 (个), 符合题意;C. 上层有 1 个,下层有 5 个,一共有 1 + 5 = 6 (个), 不符合题意。![](images/d82338c02555db07d3416b25712d4a2a7bda4c0939eb5f8818d932a408628441.jpg)是用5个相同的正方体拼成的。故答案为: B", + "knowledge_points": [ + "5以内数的加法", + "6的加减法", + "数正方体的个数" + ], + "source": "25-26 一年级上·江西九江·期中" + }, + { + "id": "106", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "壮壮摸到的是()。 ![](images/b47fefb86e4b11a60bbb20656b1e88b7.png)", + "options": [ + + ], + "answer": "B", + "solution": "【分析】长方体是长长方方的有平平的面,相对的面相同;正方体是正正方方的有平平的面,每个面相同;圆柱上下是平平的面且上下一样粗,侧面是曲面;根据立体图形的特征来解决此题.\n【详解】A。![](images/ef41361b3bfa5ddbc1e0590b42cef9bd8bcec31217681a48733909d777fd323a.jpg),这是长方体,高高的,相对的面相同;B. ![](images/3ae153d581ace641cc67c9ee935ee39d7378857df186fbb6be9883530e6f659b.jpg),这是正方体,矮矮的,每个面都相同;C. ![](images/22d656cc190f940070bdd371651866ae.png) ,这是圆柱,有 2 个平平的面和 1 个曲面;即,壮壮摸到的是![](images/3ae153d581ace641cc67c9ee935ee39d7378857df186fbb6be9883530e6f659b.jpg) 。故答案为: B", + "knowledge_points": [ + "立体图形的认识及分类" + ], + "source": "25-26 一年级上·江西九江·期中" + }, + { + "id": "107", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "下面不易滚动的物体是 ( )。 ![](images/fb999822fa5cd60855dc98fb40d96067.png)", + "options": [ + + ], + "answer": "C", + "solution": "【分析】长方体是长长方方的有平平的面,但不易滚动;圆柱上下是平平的面且上下一样粗,侧面是曲面,可以滚动;球是圆圆的,没有平面,可以任意方向滚动的;根据立体图形的特征来解决此题.\n【详解】 A。这是圆柱,沿着侧面可以滚动;B。![](images/9b491878652fcb90b05fd488188ab477d95d194bc00030dbd946d1d803891ac8.jpg)这是球,可以任意方向滚动;C。![](images/c69d80a507838b3c5cd5a29fa7124f9fe450ffce484694b2be84cbb1d693ae7d.jpg)这是长方体,不易滚动;即,不易滚动的物体是![](images/e3c302d87e0e60cf9f39ffd870db1b0b4642bb78cb2991386cb0132c423c0fe0.jpg)故答案为: C", + "knowledge_points": [ + "立体图形的认识及分类" + ], + "source": "25-26 一年级上·江西九江·期中" + }, + { + "id": "108", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.65, + "question": "下面积木中, ( )搭得最稳。 ![](images/53b6e44ce11dffab275c004c72c6928d.png)", + "options": [ + + ], + "answer": "C", + "solution": "【分析】圆柱可以向一个方向滚动,球能向四面八方滚动,长方体和正方体有平平的面不易滚动,据此解答.\n【详解】A。积木下面是球,球能向四面八方滚动,搭得最不稳;B. 积木下面是圆柱,圆柱可以向一个方向滚动,搭得不稳;C. 积木下面是长方体,长方体有平平的面不易滚动,搭得最稳,故答案为: C", + "knowledge_points": [ + "立体图形的认识及分类" + ], + "source": "25-26 一年级上·江西九江·期中" + }, + { + "id": "109", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "哪堆搭得最稳。 ( ) ![](images/519fdcb3a5827682084fa5d3aa16cab9.png)", + "options": [ + + ], + "answer": "B", + "solution": "【分析】长方体是长长方方的有平平的面,不易滚动;正方体是正正方方的有平平的面,不易滚动;圆柱上下是平平的面且上下一样粗侧面是曲面,既可以直立起来,也可以滚动;球是圆圆的,没有平面,可以任意方向滚动的;根据立体图形的特征来解决此题.\n【详解】A。 ,圆柱在下长方体在上,且圆柱的曲面与平平的面搭在一起,这样搭起来不稳;B. 正方体和长方体每个面都是平平的,搭在一起最稳;C. , 球没有平平的面,易滚动,与长方体搭起来不稳。故答案为: B", + "knowledge_points": [ + "立体图形的切拼(长方体,正方体的体积)", + "立体图形的认识及分类" + ], + "source": "25-26 一年级上·江西九江·期中" + }, + { + "id": "110", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "下面图形中,哪个图既可以直立起来,也可以滚动。 ( ) ![](images/510129e242827fb72c6887c200d324fb.png)", + "options": [ + + ], + "answer": "A", + "solution": "【分析】正方体是正正方方的有平平的面,可以直立起来,\n但不易滚动;圆柱上下是平平的面且上下一样粗,侧面是曲面,既可以直立起来,也可以滚动;球是圆圆的,没有平面,可以任意方向滚动的,但不可以直立起来;根据立体图形的特征来解决此题.\n【详解】A。圆柱,既可以直立起来,也可以滚动;B。正方体可以直立起来,但不易滚动;C. 球易滚动,但不可以直立起来;即,圆柱既可以直立起来,也可以滚动。故答案为: A", + "knowledge_points": [ + "立体图形的认识及分类" + ], + "source": "25-26 一年级上·江西九江·期中" + }, + { + "id": "111", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "下列说法正确的是 ( )。", + "options": [ + "A. ![](images/5fa13eb48f4d5eb543635a044e1d933fba48443693270a43a596a1c37db69be4.jpg)是圆柱", + "B. 至少用 4 个![](images/30d1e6371466498ba2e17e78857e22d15841dcb8bc3fbdef1c313e69468c21c2.jpg)可以拼成一个大正方体", + "C. 数学课本的形状是长方体" + ], + "answer": "C", + "solution": "【分析】长方体是长长方方的有平平的面;正方体是正正方方的有平平的面每面都相等;圆柱上下是圆且上下一样粗;球没有平面可以任意方向滚动.\n【详解】A。 是圆柱,上下粗细不一样,则不是圆柱,不符合题意。 B. 至少用 4 个 可以拼成一个大正方体, 4 个可以拼成一个长方体,则不符合题意。 C. 数学课本的形状是长方体,课本是长长方方的有平平的面,符合题意。故答案为: C", + "knowledge_points": [ + "立体图形的认识及分类" + ], + "source": "25-26 一年级上·江西九江·期中" + }, + { + "id": "112", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "搭下面的积木,没有用到的图形是()。 ![](images/662383c5bd7c068608d3736c4fb39cb6d5c44f0c6a27ffe44f5368b9c391b672.jpg)", + "options": [ + "A. 圆柱", + "B. 球", + "C. 长方体" + ], + "answer": "B", + "solution": "【分析】正方体:有 6 个面,每个面都由正方形组成;长方体:有 6 个面,每个面都由长方形或相对的一组正方形组成;圆柱:上下两个面为大小相同的圆形,有一个曲面叫侧面;球:球是生活中最常见的图形之一,例如篮球,足球都是球,球是由一个面所围成的几何体.\n【详解】从图上可得:搭这个积木用到了 1 个正方体,1 个长方体,2 个圆柱。没有用到球。 故答案为: B", + "knowledge_points": [ + "立体图形的认识及分类" + ], + "source": "25-26 一年级上·江西九江·期中" + }, + { + "id": "113", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "下面图形中, ( )物体可以滚动的。", + "options": [ + "A. 正方体", + "B. 圆柱", + "C. 长方体" + ], + "answer": "B", + "solution": "【分析】长方体是长长方方的有平平的面;正方体是正正方方的有平平的面;圆柱上下是平平的面且上下一样粗,平平的面与地面接触不易滚动,弯弯的面与地面接触易滚动,由此解答.\n【详解】A。正方体不可以滚动;B. 圆柱可以立起来,也可以滚动;C. 长方体不可以滚动。所以圆柱可以滚动。故答案为: B", + "knowledge_points": [ + "立体图形的认识及分类" + ], + "source": "25-26 一年级上·江西九江·期中" + }, + { + "id": "114", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.65, + "question": "先摆一个正方体,在正方体的左边摆一个圆柱,右边摆一个球,再在圆柱的上边摆一个长方体,摆法正确的是 ( )。 ![](images/84c3e184486a60d078f5d9c2a31bff65.png)", + "options": [ + + ], + "answer": "A", + "solution": "【分析】长方体是长长方方的,有 6 个平平的面,且相对的两个面大小一样(特殊情况下有四个面相同);正方体是正正方方的有平平的面;圆柱上下是圆且上下一样粗;球没有平面可以任意方向滚动。据此摆一摆,逐项分析.\n【详解】A。![](images/075e744181e1e6b383b69b40c67bb7ee89bb2e574b4bb18fb8b5c0099f59df66.jpg)摆法正确;B。![](images/1ac237e16619ddd3e90385eea21d2c7824076626736ae6f11e3ed6c1a8e817bb.jpg)没有圆柱,不正确;C。![](images/4a1c831e1ea9fd4c6f6d21add886ebe17fcb12cde5a2d380db90b68e0f03b548.jpg)正方体左边不是圆柱,右边不是球,不正确。故答案为: A", + "knowledge_points": [ + "立体图形的拼搭" + ], + "source": "25-26 一年级上·江西九江·期中" + }, + { + "id": "115", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.65, + "question": "( ) 组图形能放稳。", + "options": [ + "A. ![](images/7d331309038190373221dcbf9755cebae547003a4926c504ee84bbe1b146b0e4.jpg)", + "B. ![](images/2d904fbb15ea705c6514efe0f920beec3e2cf1476ce0271cf94f2189c6518f03.jpg)", + "C. ![](images/87b1880f12bf6c0035509b41941c66d4facbb5fc1700af9c7ac610c5395e4fd4.jpg)" + ], + "answer": "C", + "solution": "【分析】长方体是长长方方的,有 6 个平平的面,且相对的两个面大小一样(特殊情况下有四个面相同);正方体是正正方方的有平平的面;圆柱上下是圆且上下一样粗;球没有平面可以任意方向滚动.\n接触的面越平则越不容易滚动,也就越稳.\n【详解】A。观察可知,有圆柱容易滚动,不稳;B. 有球,容易滚动,不稳;C. 相互接触的面都是平平的,能放稳。![](images/5b0e9ad719f30c2f5d4b13bcf9a4a687f593d93573d4e157aa953f906988b211.jpg)能放稳。故答案为: C", + "knowledge_points": [ + "组合图形的稳定性" + ], + "source": "25-26 一年级上·江西九江·期中" + }, + { + "id": "116", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.65, + "question": "用 8 个相同的正方体, ( ) 拼出一个正方体。", + "options": [ + "A. 可以", + "B. 不可以", + "C. 无法确定" + ], + "answer": "A", + "solution": "【分析】拼一拼,如图: ![](images/987792d1f06913c57a6a3ac814deff7a6d4c57a2b10c60affa7e071cf575241d.jpg) 一共有 8 个小正方体,拼成的图形还是一个正方体.\n【详解】由分析可知,用 8 个相同的正方体,可以拼出一个正方体。故答案为: A", + "knowledge_points": [ + "数正方体的个数", + "立体图形的认识及分类", + "立体图形的拼搭" + ], + "source": "25-26 一年级上·江西九江·期中" + }, + { + "id": "117", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "不可以滚动的图形是 ( )。", + "options": [ + "A. 长方体", + "B. 圆柱", + "C. 球" + ], + "answer": "A", + "solution": "【分析】长方体是长长方方的有平平的面;圆柱上下是平平的面且上下一样粗,平平的面与地面接触不易滚动,弯弯的面与地面接触易滚动;球没有平面可以任意方向滚动,由此解答.\n【详解】A。长方体不可以滚动;B. 圆柱可以立起来,也可以滚动;C. 球可以滚动。则不可以滚动的图形是长方体。故答案为: A", + "knowledge_points": [ + "立体图形的认识及分类" + ], + "source": "25-26 一年级上·江西九江·期中" + }, + { + "id": "118", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.65, + "question": "两个 ( ) 不能拼成一个长方体。", + "options": [ + "A. 长方体", + "B. 正方体", + "C. 圆柱" + ], + "answer": "C", + "solution": "【分析】长方体是长长方方的,有 6 个平平的面,且相对的两个面大小一样(特殊情况下有四个面相同);正方体是正正方方的有平平的面;圆柱上下是圆且上下一样粗。据此拼一拼.\n【详解】A。![](images/daabdae5f1afd53cc7a23b0df6fc8e212ca46bfd1e11d736e2d278c2260c9d87.jpg)两个长方体能拼成一个长方体。B。![](images/d983d27e0438f80caa4a3dede3394f7e68ce86d4b5ecff741f66f670211c2a92.jpg)两个正方体能拼成一个长方体。C。 两个圆柱不能拼成一个长方体。故答案为: C", + "knowledge_points": [ + "立体图形的拼搭" + ], + "source": "25-26 一年级上·江西九江·期中" + }, + { + "id": "119", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "下图的积木中,没用到的图形是 ( )。 ![](images/f554d3b800d2a7655fb0b3abcd7084f91062815f7c8008ae6d681b6b4281e4eb.jpg)", + "options": [ + "A. 圆柱", + "B. 球", + "C. 正方体", + "D. 长方体" + ], + "answer": "B", + "solution": "【分析】长方体是长长方方的有平平的面;正方体是正正方方的有平平的面;圆柱上下是平平的面且上下一样粗;球没有平面可以任意方向滚动,由此解答.\n【详解】A。图形的下边有圆柱;B. 图形中没有球;C. 图形的上边有正方体;D. 图形的中间和上边有长方体。所以没用到的图形是球。故答案为: B", + "knowledge_points": [ + "立体图形的认识及分类" + ], + "source": "25-26 一年级上·江西九江·期中" + }, + { + "id": "120", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.65, + "question": "哪个图形能放稳。()", + "options": [ + "A. ![](images/af15d4373d9085c40575c68fe5adcd9f31f7aba3982754e4ca92aa752025bb96.jpg)", + "B. ![](images/66705dc5540487cb2197bc201163d6b18853052eaf6424ba6168345996c30d6b.jpg)", + "C. ![](images/2b869168163d880c45761806709898c49929861a81a8e8479fd80ed82e1b66e9.jpg)" + ], + "answer": "B", + "solution": "【分析】长方体是长长方方的,有 6 个平平的面,且相对的两个面大小一样(特殊情况下有四个面相同);正方体是正正方方的有平平的面;圆柱上下是圆且上下一样粗;球没有平面可以任意方向滚动。有平平的面就能放稳,不是平平的面的不容易放稳,据此观察.\n【详解】A。下面和中间的不是平平的面,不能放稳;B. 三个都是用的平平的面,能放稳;C. 下面不是用的平平的面,不能放稳。![](images/2b0cd0b694c6a514471071ecab94bee538a9873d44b2821b27559018eaee9ff0.jpg)能放稳。故答案为: B", + "knowledge_points": [ + "组合图形的稳定性" + ], + "source": "25-26 一年级上·江西九江·期中" + }, + { + "id": "121", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "这个![](images/e7d478feb526ea817138c8fd9ce4cde0.png)图形是由()个 ![](images/f39484a5644c09212d92001339d0d7af4704c5944d2ec5d0326e5c2ac1f7836d.jpg)组成的。", + "options": [ + "A. 5", + "B. 6", + "C. 7" + ], + "answer": "B", + "solution": "【分析】根据图片从上往下数,上面有 1 个,下面有 5 个,然后将数的个数合在一起即可.\n【详解】 1 + 5 = 6 (个)则是由 6 个 ![](images/f39484a5644c09212d92001339d0d7af4704c5944d2ec5d0326e5c2ac1f7836d.jpg) 组成的。故答案为: B", + "knowledge_points": [ + "立体图形的认识", + "6 的加减法" + ], + "source": "25-26 一年级上·江西九江·期中" + }, + { + "id": "122", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "下面哪堆物体最难堆。()", + "options": [ + "A. ![](images/2a4eb62fb1c2a99337143b84a2b1952faddddee228f78f92468a473dd9d4948d.jpg)", + "B. ![](images/81450ed9b31d4f32682e9077a1a9e4e75fa11a8eb6f730a40d3a08a065938e1a.jpg)", + "C. ![](images/7c105bc9421b0f1befc330e02321bcad94a3a3766e15a40a7777d08666740a71.jpg)" + ], + "answer": "C", + "solution": "【分析】长方体是长长方方的有平平的面,圆柱上下是平平的面且上下一样粗,球没有平面可以任意方向滚动。由此找出容易滚动的就是最难堆的.\n【详解】A。这是一组长方体,不易滚动,容易堆;B. 这是一组圆柱,平平的面放在地上不易滚动,容易堆;C. 这是一组球,可随意滚动,不容易堆。所以最难堆的是![](images/7c105bc9421b0f1befc330e02321bcad94a3a3766e15a40a7777d08666740a71.jpg) ,故答案为: C", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "25-26 一年级上·江西九江·期中" + }, + { + "id": "123", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "哪组积木最稳定。()", + "options": [ + "A. ![](images/e1ecd818a2836c70e60cc4a3adf6d918b176aa637f4500c29f964b9e34743f83.jpg)", + "B. ![](images/3cf366c1dd85b30922bbb022b4a3de326bb3dfac86c6db09902dfca4f0ec6848.jpg)", + "C. ![](images/35b406725cf7bb29e72f7887bb255c53b336173e74ce99192de6a299b75d46a0.jpg)" + ], + "answer": "A", + "solution": "【分析】长方体是长长方方的有平平的面,圆柱上下是平平的面且上下一样粗,球没有平面可以任意方向滚动。由此找出组合的图中最稳定的即可.\n【详解】A。下边是长方体,不易滚动,圆柱平平的面和长方体接触不易滚动,稳定;B. 下边的物体是尖尖的,不稳定,上边是球,可随意滚动,整体都不稳定;C. 下边是球,可随意滚动,长方体放在上边不稳定.\n所以![](images/7c536ce98727210c6aee992c63179d4b2df17e790e495b5180750e53eb9ee11d.jpg)最稳定。故答案为: A", + "knowledge_points": [ + "组合图形的稳定性" + ], + "source": "25-26 一年级上·江西九江·期中" + }, + { + "id": "124", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.65, + "question": "下面物体中,容易滚动的是 ( )。", + "options": [ + "A. ![](images/b52d8083ed6a293ede59a8e82f8846e748b98ce8d8536ce551dcedd6928f2137.jpg)", + "B. ![](images/88b601d14e03634408f4ab5c61783ba2c792dca1877744e9bde36cb095b098c8.jpg)", + "C. ![](images/5de651a2af4871400e391747593952c9bbec65d74d25e2fac25252035f45d84b.jpg)" + ], + "answer": "B", + "solution": "【分析】根据长方体,正方体,圆柱的特征,长方体和正方体都是平面围成的立体图形,长方体和正方体不易滚动,圆柱是由曲面围成的立体图形,所以最容易滚动的是圆柱,据此解答.\n【详解】容易滚动的是圆柱。故答案为: B", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "25-26 一年级上·江西九江·期中" + }, + { + "id": "125", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "如图,圆柱的上面和下面都是 ( )。 ![](images/acf36dcfd8fc515aee1f1593bde61052.png)", + "options": [ + "A. ![](images/2789ef4eb0f7704875357e3d292c742038ad543c597f426386a40c25471b6d69.jpg)", + "B. ![](images/d9313816a82bf08dbbabc68381d15edaffc79a5252abf7540c1e02585cfcc571.jpg)", + "C. ![](images/3c1f1299b3cbe2a1e4ac44f453e14a512e424e3ab4735d559d3aa89ddc27d38a.jpg)" + ], + "answer": "C", + "solution": "【分析】圆柱:上下两个面为大小相同的圆形,有一个曲面叫侧面,据此解答即可.\n【详解】根据分析可知:圆柱的上面和下面都是![](images/9d9b45e6defc6d4d85399c2a0bb82e52889efdb93a8e3723674d08b99e9d83fe.jpg),故答案为: C", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "25-26 一年级上·江西九江·期中" + }, + { + "id": "126", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "用 4 个![](images/f39484a5644c09212d92001339d0d7af4704c5944d2ec5d0326e5c2ac1f7836d.jpg)正方体可以拼成的是()。", + "options": [ + "A. ![](images/acf36dcfd8fc515aee1f1593bde61052.png)", + "B. ![](images/1a6a4039bfb6fe7ab943b89aac8c7a5f.png)", + "C. ![](images/1a6a4039bfb6fe7ab943b89aac8c7a5f1.png)" + ], + "answer": "B", + "solution": "【分析】分别数一数拼成的各个图形分别有几个小正方体,找出用 4 个可以拼成的图形即可.\n【详解】![](images/1a6a4039bfb6fe7ab943b89aac8c7a5f.png)故答案为: B", + "knowledge_points": [ + "正方体的特征" + ], + "source": "25-26 一年级上·江西九江·期中" + }, + { + "id": "127", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.65, + "question": "从下面物体()的表面不能找到长方形。", + "options": [ + "A. ![](images/9515a48bd742f5b1e937246d29ebd934f536ea0fe22bcb64d91d587021e87fa3.jpg)", + "B. ![](images/5e2c757f651f8dfba69079d673060c3d6d5ecefe62c2d8a592ed25eaec4b4119.jpg)", + "C. ![](images/8b4d4a2c74d425863958ff061ffb79b34157b07b1fe5ab0326cdd0be403e872b.jpg)" + ], + "answer": "B", + "solution": "【分析】依据对立体图形长方体,正方体,圆柱,球的认识选择.\n【详解】A。电冰箱是长方体,有6个面是长方形,错误;B。球的表面是曲面,没有长方形,正确;C. 盒子是长方体,有 6 个面是长方形,错误。故答案为: B", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "25-26 一年级上·江西九江·期中" + }, + { + "id": "128", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.65, + "question": "下面三枚图章, ( ) 可以印出 ○ 。", + "options": [ + "A. ![](images/0364bc9bd678a3994a8e3809f0e3e10ac858c732ae8d4a02613ada7c471a0fb2.jpg)", + "B. ![](images/be0274959a4edd095a068e8b6520d231394c85bf22a54cb8a48fc33c8145f115.jpg)", + "C. ![](images/551d60ee593997779200e4c7153d96889a264ab447b0e7ae8778c693005fb404.jpg)" + ], + "answer": "C", + "solution": "【分析】立体图形的认识\n长方体:由 6 个长方形的面围成(特殊的由 2 个正方形和 4 个长方形围成), 用长方体不能印出圆形;正三棱柱:由 2 个三角形和 3 个长方形围成,用正三棱柱不能印出圆形 。圆柱:由 2 个圆和 1 个曲面围成,用圆柱能印出圆形.\n【详解】A。长方体不能印出圆形,错误;B。正三棱柱不能印出圆形,错误;C. 圆柱能印出圆形,正确。 故答案为: C", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "25-26 一年级上·江西九江·期中" + }, + { + "id": "129", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "小乐想画一个圆形,可以用下面的物体 ( ) 画出来。", + "options": [ + "A. ![](images/0763162f9673b827e7f3359b3a8e8ffa210e26dae574ca6b8cc680cb35521364.jpg)", + "B. ![](images/3e66b119182aa8f5fd6112633cb0f89b57bbc076de88844f1f6f8d45492646a6.jpg)", + "C. ![](images/a75a27ad13ca63dd3f9d7244f32c9d350679365ed14114e4a6a75b21ea60eb8a.jpg)" + ], + "answer": "A", + "solution": "【分析】本题考查圆柱,球,长方体的认识。圆柱的上下面都是圆,用圆柱可以画出圆;球圆圆的,表面是曲面,球可以滚动,用球不能画出圆;长方体有6个面,它的面是长方形,可能有正方形,不能画出圆.\n【详解】A,圆柱的上下面都是圆,用圆柱可以画出圆;B,球圆圆的,表面是曲面,球可以滚动,用球不能画出圆。 C,长方体有棱有角,不能画出圆。故答案为: A", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "25-26 一年级上·江西九江·期中" + }, + { + "id": "130", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.65, + "question": "最难堆起来的是 ( )。 ![](images/4edbb5139ac673f9325c12e887a29050.png)", + "options": [ + + ], + "answer": "A", + "solution": "【分析】长方体是长长方方的有平平的面,正方体是正正方方的有平平的面,圆柱上下是平平的面且上下一样粗,球没有平面可以任意方向滚动。由此解答.\n【详解】A。下边是球,可随意滚动,很难堆起来;B. 下边是长方体,不易滚动,容易堆起来;C. 下边是圆柱,平平的面与地面接触,不易滚动,上边是球,可随意滚动,比较难堆起来;D. 下边是圆柱,平平的面与地面接触,不易滚动,上边是正方体,不易滚动,容易堆起来.\n最难堆起来的是![](images/4f4dd7853075289f81213d91ca6809e7475be3cf031c31020f755e2dc372d83c.jpg),故答案为: A", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "25-26 一年级上·江西九江·期中" + }, + { + "id": "131", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.65, + "question": "关于下面的图形,表述正确的是 ( )。 ![](images/b20b63a6e8a009902dcca0e31ff3a68c9336b903b74b2a3dc4ecad24248bed0a.jpg)", + "options": [ + "A. 上层有 2 个小正方体,下层有 4 个小正方体", + "B. 上层有 2 个小正方体,下层有 5 个小正方体", + "C. 上层有 2 个小正方体,下层有 6 个小正方体" + ], + "answer": "A", + "solution": "【分析】上层有 2 个小正方体,下层有 4 个小正方体,合起来一共有 6 个小正方体,据此得出结论即可.\n【详解】根据分析知:上层有 2 个小正方体,下层有 4 个小正方体,故答案为: A", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "25-26 一年级上·江西九江·期中" + }, + { + "id": "132", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "下面图形不会滚动的是 ( )。", + "options": [ + "A. ![](images/2feb64c5756d9f87d79da847e8e3111cc563ddfa4fa88bbe5e39939298f6f33f.jpg)", + "B. ![](images/f39484a5644c09212d92001339d0d7af4704c5944d2ec5d0326e5c2ac1f7836d.jpg)", + "C. ![](images/bbb4539750aeb5755af7683196a7636ea6c11e0cac5b7f40dda0f47fdb29c0f2.jpg)" + ], + "answer": "B", + "solution": "【分析】正方体是正正方方的有平平的面;圆柱上下是平平的面且上下一样粗;球没有平面可以任意方向滚动。由此选择.\n【详解】A。球可以随意滚动;B. 正方体的面是平的,不易滚动;C. 圆柱放倒易滚动。不会滚动的是![](images/697eaa29f4a5a69dec968a799cf76859e7e838e06aeafa34b6b3f91cf282d327.jpg),故答案为: B", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "25-26 一年级上·江西九江·期中" + }, + { + "id": "133", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.65, + "question": "如图中有 ( ) 个长方体。 ![](images/fdfe7db7aac3380ee8664774a44ab9942bb1044e92f7d77bf4bb56fe9928b686.jpg)", + "options": [ + "A. 3", + "B. 4", + "C. 6" + ], + "answer": "C", + "solution": "【分析】长方体是长长方方的,有 6 个平平的面。由此数出单独的长方体的数量和组合成的长方体的数量,相加即可.\n【详解】单独的小长方体有 3 个;2 个小长方体组成的大长方体有 2 个;3 个小长方体组成的大长方体有 1 个,一共有 3 + 2 + 1 = 6(个).\n图中有 6 个长方体。![](images/29983689f3ad0e56ad3c162c700f4574f74b553b46dc19b936c4e2f2d85dd770.jpg),故答案为: C", + "knowledge_points": [ + "立体图形的认识", + "连加,连减(10以内)" + ], + "source": "25-26 一年级上·江西九江·期中" + }, + { + "id": "134", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "篮球是 ( )。", + "options": [ + "A. 圆柱", + "B. 球", + "C. 圆" + ], + "answer": "B", + "solution": "【分析】篮球没有任何平面,可以任意方向滚动,根据对立体图形的认识可知,篮球是球.\n【详解】由分析可知,篮球是球。故答案为: B", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "25-26 一年级上·江西九江·期中" + }, + { + "id": "135", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "数一数,图中一共有 ( ) 个小正方体。 ![](images/89db2cf55682647cbdf294d8933919207c1714cd5e1755d996d85a0292a49311.jpg)", + "options": [ + "A. 6", + "B. 7", + "C. 8" + ], + "answer": "A", + "solution": "【分析】正方体是正正方方的有平平的面。图中上层有 2 个小正方体,下层有 4 个小正方体,相加即可求出一共有多少个小正方体.\n【详解】 2 + 4 = 6 (个),图中一共有 6 个小正方体。故答案为: A", + "knowledge_points": [ + "立体图形的认识", + "7 的加减法" + ], + "source": "25-26 一年级上·江西九江·期中" + }, + { + "id": "136", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "下面最难堆放的是哪一个。() ![](images/e66d7a27ea83ad6a63a80e57f368b4e1.png)", + "options": [ + + ], + "answer": "B", + "solution": "【分析】根据对立体图形的认识,找到易滚动的就是最难堆的.\n【详解】A。长方体是长长方方的有平平的面,不易滚动,容易堆在一起;B. 球没有平面可以任意方向滚动的,最难堆在一起;C. 圆柱上下是平平的面,且上下一样粗,两个平平的面也容易堆在一起。最难堆放的是![](images/5bd800934e1a45f07415480143d6d28c894dcfe50fdfd0c1347b2ed45c064014.jpg)故答案为: B", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "25-26 一年级上·江西九江·期中" + }, + { + "id": "137", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "哪一个物体的形状是长方体。 ( ) ![](images/112f92016a0f6d94720eda07fdd21a18.png)", + "options": [ + + ], + "answer": "B", + "solution": "【分析】长方体是长长方方的有平平的面;正方体是正正方方的有平平的面;圆柱上下是平平的面且上下一样粗;球没有平面可以任意方向滚动,由此解答.\n【详解】A。![](images/c1c7a36b84038ba09fdce6a0ff82f0e7ddb792c6919755ce1291c6f2e35834ee.jpg)的形状是球形;B。![](images/9406ae0281b0a8488f358cce3e25f67c923cd23882d033e41412f8a08d02daf9.jpg)的形状是长方体;C。![](images/db2afa8637465cb8fd667097d0dcb2c3521d698cae7a579b1f923dea749da449.jpg)杯身的形状是圆柱。![](images/dde990ee292dd8ffdc71681105a61cf41a62a4f73b6886714a09be1c6760fdee.jpg)的形状是长方体。故答案为: B", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "25-26 一年级上·江西九江·期中" + }, + { + "id": "138", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "![](images/68ad49d164fae148118b80a9396b070b597bdce7aca9da1f6456113e149fb4cd.jpg)数一数,左图中共有( )个小正方体。", + "options": [ + "A. 5", + "B. 6", + "C. 7" + ], + "answer": "C", + "solution": "【分析】正方体是方方正正的,有平平的面。图中上层有 1 个,中间有 2 个,下层有 4 个,相加计算出总数量即可.\n【详解】 1 + 2 + 4 = 7 (个),图中共有 7 个小正方体。故答案为: C", + "knowledge_points": [ + "立体图形的认识", + "连加,连减(10以内)" + ], + "source": "25-26 一年级上·江西九江·期中" + }, + { + "id": "139", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "下面搭成的图形中,能放稳的是 ( )。", + "options": [ + "A. ![](images/c0c0506fa625d336fb9fe688a30a2452ed46b4c3bb285dd2fb0d8bf33edaa561.jpg)", + "B. ![](images/4973baa5cb0fbe6dfae0179fbcf1bf7541d4ee1d894515047e10ce77a0b611ae.jpg)", + "C. ![](images/bfce8c70733ea948845a2b8572ba618e39ddd37c7ce8bad23cf24f549eb4657d.jpg)" + ], + "answer": "A", + "solution": "【分析】图形平平的面与地面接触,以及两个图形平平的面接在一起,搭成的图形就可以放稳;曲面与地面接触(或是曲面与平平的面接在一起),搭成的图形不能放稳。长方体是长长方方的有平平的面;正方体是正正方方的有平平的面;圆柱上下是圆(圆是平平的面),侧面是曲面,且上下一样粗;球没有平面可以任意方向滚动的.\n【详解】A。![](images/c0c0506fa625d336fb9fe688a30a2452ed46b4c3bb285dd2fb0d8bf33edaa561.jpg) ,这两个图形都是由平平的面组成,这种搭法可以放稳;B。![](images/4973baa5cb0fbe6dfae0179fbcf1bf7541d4ee1d894515047e10ce77a0b611ae.jpg) , 下面的图形是曲面与地面接触,这种搭法不可以放稳;C。![](images/bfce8c70733ea948845a2b8572ba618e39ddd37c7ce8bad23cf24f549eb4657d.jpg) , 下面的图形是曲面与地面接触,这种搭法不可以放稳;故答案为: A", + "knowledge_points": [ + "组合图形的稳定性" + ], + "source": "25-26 一年级上·江西九江·期中" + }, + { + "id": "140", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "在长方体的右边摆一个正方体,在长方体的上面摆一个圆柱。下面哪种摆法是正确的。() ![](images/55bc38be245656200164d7c97c424d9bdbfb80561b933e11357d470c2af0e9b7.jpg) ![](images/0225b74f35c5720a72da509e32a7060fa86feee02b93eab3aa6fa5eb50a5a0e0.jpg) ![](images/5686f8166c43ac18262d2869e6f675d0c165d1534d9209fb317908c61a83e06e.jpg)", + "options": [ + "A. ![](images/55bc38be245656200164d7c97c424d9bdbfb80561b933e11357d470c2af0e9b7.jpg)", + "B. ![](images/0225b74f35c5720a72da509e32a7060fa86feee02b93eab3aa6fa5eb50a5a0e0.jpg)", + "C. ![](images/5686f8166c43ac18262d2869e6f675d0c165d1534d9209fb317908c61a83e06e.jpg)" + ], + "answer": "C", + "solution": "【分析】根据题意分清上下左右,写字的手为右,另一边为左;圆柱能像柱子一样立着,还能滚动,是直直的,上下一样粗细,两头都是圆圆的平平的面;长方体:长长的方方的,有 6 个平平的面;正方体:正正的方方的,有 6 个平平的面都相等。据此解答.\n【详解】根据分析:A. 长方体的下面摆的正方体和圆柱,不符合题意;B. 长方体的左面摆的正方体,上面摆的圆柱,不符合题意;C。![](images/458fb4110a00e0882ab5ac5f319f6b2e5b2d71faaabbb5c64f0f2ef290f8c9a2.jpg)长方体的右面摆的正方体,上面摆的圆柱,符合题意。故答案为: C", + "knowledge_points": [ + "立体图形的认识", + "上,下位置,左,右位置" + ], + "source": "25-26 一年级上·江西九江·期中" + }, + { + "id": "141", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "下面()是用4个![](images/8a93a443dc4a358ef9b80520ccea4c0f018e23ce8eefa504393eee2574a81719.jpg)拼成的。", + "options": [ + "A. ![](images/df5839c0a51e34735d05e97abc9a4f914ae6938983a20ed7acd2b7f38496fe2e.jpg)", + "B. ![](images/e3db3398e122c802ed2f9b50c439fa9f0fd4d66fc507d95dbd27780d7ab38e5e.jpg)", + "C. ![](images/6d04d4129918867352a8b4067b2b860baea08cf0da8b95cc91afdee2fc584707.jpg)" + ], + "answer": "B", + "solution": "【分析】数一数每个图中小正方体的个数即可求解.\n【详解】 A。![](images/c328c6e8af7828d2f8e5d7b684114c163669b0ae3b77ed234bec20dea9d23a8a.jpg)中有5个;B。![](images/af998f90421b9748f649fef972406fe6360c38b0c3100e311184e921a9fe11a4.jpg)中有 4 个![](images/6c2c025165abc96d5ad7b6b14352b6b75985d4a993ba5066efaebc68a9138cf3.jpg);C。![](images/4a28df2fee2f83e86ebfb2a749b9e0abc8875b2c31c0b4c208da6f04d2026421.jpg)中有3个![](images/983d348c0539fe6d3bc0a6c1baad117f150cdc9545504af7a48b819aacd7e0b4.jpg);![](images/ad6378cd19dff111a65d4c4011884c82af9a5e6ea4aec82aadf0445a1e22af29.jpg)是用 4 个![](images/62c5af6e2a45da70bbf0af8d5a0e557a03f1ca4e2fd41315bd0904739be1a7d0.jpg)拼成的。故答案为: B", + "knowledge_points": [ + "立体图形的认识", + "数一数" + ], + "source": "25-26 一年级上·江西九江·期中" + }, + { + "id": "142", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.65, + "question": "小丽闭着眼睛摸同一个物体,第一次摸到一个平的面,第二次摸到一个弯的面,这个物体可能是 ( )。", + "options": [ + "A. ![](images/5d0369b7724041c94831fe3d5562227e54e12c566e683caf8ffc014f4f3d4ceb.jpg)", + "B. ![](images/83da51a933594ff703502bf5d41f161577ebbf0e99c70072c471fa941f13ab85.jpg)", + "C. ![](images/54c79b08c8804d94e97e4b77b7dc391f56cef69f974908a9f0c58969ad2abc31.jpg)", + "D. ![](images/c0e7a81506799509fa08e07097f1c0a2f85effe50f4c762175526cdbeec76696.jpg)" + ], + "answer": "C", + "solution": "【分析】长方体是长长方方的,有平平的面;正方体是正正方方的,有平平的面;球没有平面,可以任意方向滚动;圆柱上下面为大小相同的圆形,有一个曲面叫侧面。根据立体图形的特征判断即可.\n【详解】由分析可知:长方体、正方体不可能有弯的面;球不可能有平的面。因此同一个物体,第一次摸到一个平的面,第二次摸到一个弯的面,这个物体可能是圆柱。故答案为: C", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "25-26 一年级上·江西九江·期中" + }, + { + "id": "143", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "汪汪队举行堆高比赛,毛毛想要获胜,不能选哪种积木。 ( )", + "options": [ + "A. ![](images/0d23c0aeb4daa7111e7021bc2aab69622a0c5da9008e240099e5781e8bdd1316.jpg)", + "B. ![](images/6044f7bf8b6fb1a672bc17aa1cc320f91900679eeb9926e6ab1196677f3a35d2.jpg)", + "C. ![](images/748c61bfd1764863dbc8e0bb0a75dcd55b95171b4685a63098ca1583c4eae230.jpg)" + ], + "answer": "B", + "solution": "【分析】长方体是长长方方的有平平的面,正方体是正正方方的有平平的面,圆柱上下是圆且上下一样粗,球没有平面可以任意方向滚动的。要用不易滚动的才容易获胜。因此他不能选易滚动的立体图形.\n【详解】A。正方体,不易滚动;B. 球,易滚动;C. 长方体,不易滚动。所以想要获胜,不能选球。故答案为: B", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "25-26 一年级上·江西九江·期中" + }, + { + "id": "144", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "![](images/de6a8d7d593a80639a84da85609aae3128f940ccc5ab56a7a39dcd6601a29a73.jpg)是用( ) 个小正方体拼成的。", + "options": [ + "A. 5", + "B. 6", + "C. 7" + ], + "answer": "B", + "solution": "【分析】正方体是正正方方的有平平的面。上层有 1 个,下层有 5 个,相加计算即可.\n【详解】 1+5=6(个)![](images/fa62135e43613f491d84106003725d0b013ba8165d9534c6e1ccdecb023883b4.jpg)是用 6 个小正方体拼成的。故答案为: B", + "knowledge_points": [ + "立体图形的认识", + "6 的加减法" + ], + "source": "25-26 一年级上·江西九江·期中" + }, + { + "id": "145", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "用()个![](images/cc71e582cfdbab8c69b8976f7e5a0d224eca20419e1b2debb5703226b30ce8d8.jpg)可以拼成一个![](images/2ae37f23eca9ae68d416e8f8b3683fae46c2b80310d482262033da234deecd4b.jpg)。", + "options": [ + "A. 3 个", + "B. 4 个", + "C. 5 个", + "D. 6 个" + ], + "answer": "B", + "solution": "【分析】从图上可得:![](images/b78c1c11d444cbe64f1c58d66fb4715a820056edec0dc3cb76c2468226317298.jpg)第一层有2个![](images/cc71e582cfdbab8c69b8976f7e5a0d224eca20419e1b2debb5703226b30ce8d8.jpg),第二层有2个![](images/cc71e582cfdbab8c69b8976f7e5a0d224eca20419e1b2debb5703226b30ce8d8.jpg),合起来一共有4个,据此解答即可.\n【详解】根据分析可知:用 (4) 个![](images/cc71e582cfdbab8c69b8976f7e5a0d224eca20419e1b2debb5703226b30ce8d8.jpg)可以拼成一个![](images/b78c1c11d444cbe64f1c58d66fb4715a820056edec0dc3cb76c2468226317298.jpg)故答案为: B", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "25-26 一年级上·江西九江·期中" + }, + { + "id": "146", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "下列立体图形中,在桌面上放不稳的是 ( )。", + "options": [ + "A. 球", + "B. 正方体", + "C. 长方体" + ], + "answer": "A", + "solution": "【分析】根据立体图形的认识可知,长方体,正方体,球中,球不是一个面和桌子接触的,故球最容易滚下来。由此解答.\n【详解】由分析可知:长方体,正方体,球中,在桌面上放不稳的是球;故答案为: A", + "knowledge_points": [ + "组合图形的稳定性" + ], + "source": "25-26 一年级上·江西九江·期中" + }, + { + "id": "147", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "在地面上最不容易站稳的是()。", + "options": [ + "A. 长方体", + "B. 正方体", + "C. 球" + ], + "answer": "C", + "solution": "【分析】长方体是长长方方的有平平的面;正方体是正正方方的有平平的面;球没有平面可以任意方向滚动。据此判断.\n【详解】A。长方体的面是平的,可以站稳;B. 正方体的面是平的,可以站稳;C. 球没有平面,不容易站稳。在地面上最不容易站稳的是球。故答案为: C", + "knowledge_points": [ + "组合图形的稳定性", + "长方体的认识及特征", + "正方体的特征" + ], + "source": "25-26 一年级上·江西九江·期中" + }, + { + "id": "148", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "下面既能滚动,又能立起来的是()。", + "options": [ + "A. ![](images/99c5a520dec1516edb3fb93acfd9d5cf8fc387ad97bbae6463313b9f8864ecd6.jpg)", + "B. ![](images/c861291c3514dca6f43108aa0249cf5884a81b1b7424abbc1e4613f93eea49e0.jpg)", + "C. ![](images/4367eaabfabbc62512a9351c2850dcf18d68e72be3a22ba3f44118975b62296c.jpg)" + ], + "answer": "A", + "solution": "【分析】长方体是长长方方的只有平平的面,不能滚动,只能立起来。圆柱由两个平平的面(圆)和一个曲面围成,既能滚动,又能立起来。球只有曲面围成,没有平面,只能滚动,不能立起来。根据立体图形的特征来解决此题即可.\n【详解】A。![](images/4eaef58309601dc128c49a989425e9b97ff99ebee337e504eb2781899d0a5d73.jpg)这是圆柱,既能滚动,又能立起来。B。![](images/0abc8ec88a336829ffa0cc07ca5c6eeaa2ad73943efef3bc5229d18ce7fee0dc.jpg)这是长方体,不能滚动,只能立起来。C。![](images/19da7aff04aac029f8d770d5d23e1d3aa98a79470be04b0baa150b8eb7c1fa3d.jpg)这是球,只能滚动,不能立起来。故,既能滚动,又能立起来的是![](images/4eaef58309601dc128c49a989425e9b97ff99ebee337e504eb2781899d0a5d73.jpg),故答案为:A", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "25-26 一年级上·江西九江·期中" + }, + { + "id": "149", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "数一数,填一填。 ![](images/bd9a78f3f7abdebdca360b4a48087eb2f1dc595da5609f9a1fe2705641b712dc.jpg)\n\u003ctable\u003e\u003ctr\u003e\u003ctd\u003e长方体\u003c/td\u003e\u003ctd\u003e( ) 个\u003c/td\u003e\u003c/tr\u003e\u003ctr\u003e\u003ctd\u003e正方体\u003c/td\u003e\u003ctd\u003e( ) 个\u003c/td\u003e\u003c/tr\u003e\u003ctr\u003e\u003ctd\u003e球\u003c/td\u003e\u003ctd\u003e( ) 个\u003c/td\u003e\u003c/tr\u003e\u003ctr\u003e\u003ctd\u003e圆柱\u003c/td\u003e\u003ctd\u003e( ) 个\u003c/td\u003e\u003c/tr\u003e\u003ctr\u003e\u003c/table\u003e", + "options": [ + + ], + "answer": "3;5;2;2", + "solution": "【分析】正方体:有 6 个面,每个面都由正方形组成;长方体:有 6 个面,每个面都由长方形或相对的一组正方形组成;圆柱:上下两个面为大小相同的圆形,有一个曲面叫侧面;球:球是生活中最常见的图形之一,例如篮球,足球都是球,球是由一个面所围成的几何体。据此解答即可.\n【详解】 \u003ctable\u003e\u003ctr\u003e\u003ctd\u003e长方体\u003c/td\u003e\u003ctd\u003e(3) 个\u003c/td\u003e\u003c/tr\u003e\u003ctr\u003e\u003ctd\u003e正方体\u003c/td\u003e\u003ctd\u003e(5) 个\u003c/td\u003e\u003c/tr\u003e\u003ctr\u003e\u003ctd\u003e球\u003c/td\u003e\u003ctd\u003e(2) 个\u003c/td\u003e\u003c/tr\u003e\u003ctr\u003e\u003ctd\u003e圆柱\u003c/td\u003e\u003ctd\u003e(2) 个\u003c/td\u003e\u003c/tr\u003e\u003ctr\u003e\u003c/table\u003e", + "knowledge_points": [ + "立体图形的认识及分类" + ], + "source": "25-26 一年级上·江西九江·期中" + }, + { + "id": "150", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "数一数,填一填。 ![](images/d1a25cccba2ff033316c53454fa3755df4e96686158c16ca82c0325d05f627ba.jpg) \u003ctable\u003e\u003ctr\u003e\u003ctd\u003e长方体\u003c/td\u003e\u003ctd\u003e正方体\u003c/td\u003e\u003ctd\u003e圆柱\u003c/td\u003e\u003ctd\u003e球\u003c/td\u003e\u003c/tr\u003e\u003ctr\u003e\u003ctd\u003e()个\u003c/td\u003e\u003ctd\u003e()个\u003c/td\u003e\u003ctd\u003e()个\u003c/td\u003e\u003ctd\u003e()个\u003c/td\u003e\u003c/tr\u003e\u003c/table\u003e", + "options": [ + + ], + "answer": "2;2;6;2", + "solution": "【分析】长方体是长长方方的有平平的面;正方体是正正方方的有平平的面;圆柱上下是平平的面且上下一样粗,并且上下是圆;球没有平面可以任意方向滚动。由此数出各图形的数量即可.\n【详解】根据分析填表如下: \u003ctable\u003e\u003ctr\u003e\u003ctd\u003e长方体\u003c/td\u003e\u003ctd\u003e正方体\u003c/td\u003e\u003ctd\u003e圆柱\u003c/td\u003e\u003ctd\u003e球\u003c/td\u003e\u003c/tr\u003e\u003ctr\u003e\u003ctd\u003e(2)个\u003c/td\u003e\u003ctd\u003e(2)个\u003c/td\u003e\u003ctd\u003e(6)个\u003c/td\u003e\u003ctd\u003e(2)个\u003c/td\u003e\u003c/tr\u003e\u003c/table\u003e", + "knowledge_points": [ + "数一数", + "立体图形的认识及分类" + ], + "source": "25-26 一年级上·江西九江·期中" + }, + { + "id": "151", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "数一数。 ![](images/5ab7376f2a945fc1618f8ba64f05bb010a98bb04dc930a0eb1a1c28c06f662c4.jpg) 长方体( )个,正方体( )个,球( )个,圆柱( )个。", + "options": [ + + ], + "answer": "4;2;3;4", + "solution": "【分析】长方体是长长方方的有平平的面;正方体是正正方方的有平平的面;圆柱上下是平平的面且上下一样粗;球没有平面可以任意方向滚动,由此数出各图形的数量即可.\n【详解】由分析填写如下:长方体4个,正方体2个,球3个,圆柱4个", + "knowledge_points": [ + "立体图形的认识及分类" + ], + "source": "25-26 一年级上·江西九江·期中" + }, + { + "id": "152", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "数一数,填一填。 ![](images/09352e4e2ed1dca993f51747d5e84788b3e369c9618a5d103ef3eb3c5c19c8e1.jpg) \u003ctable\u003e\u003ctr\u003e\u003ctd\u003e长方体\u003c/td\u003e\u003ctd\u003e()个\u003c/td\u003e\u003c/tr\u003e\u003ctr\u003e\u003ctd\u003e正方体\u003c/td\u003e\u003ctd\u003e()个\u003c/td\u003e\u003c/tr\u003e\u003ctr\u003e\u003ctd\u003e圆柱\u003c/td\u003e\u003ctd\u003e()个\u003c/td\u003e\u003c/tr\u003e\u003ctr\u003e\u003ctd\u003e球\u003c/td\u003e\u003ctd\u003e()个\u003c/td\u003e\u003c/tr\u003e\u003c/table\u003e", + "options": [ + + ], + "answer": "6;4;4;3", + "solution": "【分析】长方体是长长方方的,有 6 个平平的面,且相对的两个面大小一样(特殊情况下有四个面相同);正方体是正正方方的有平平的面;圆柱上下是圆且上下一样粗;球没有平面可以任意方向滚动。据此数一数.\n【详解】 ![](images/ec95e5ca7a68ca0b731765d684b785013a8e6896ec2954388b6af04841a4f4e5.jpg) \u003ctable\u003e\u003ctr\u003e\u003ctd\u003e长方体\u003c/td\u003e\u003ctd\u003e6个\u003c/td\u003e\u003c/tr\u003e\u003ctr\u003e\u003ctd\u003e正方体\u003c/td\u003e\u003ctd\u003e4个\u003c/td\u003e\u003c/tr\u003e\u003ctr\u003e\u003ctd\u003e圆柱\u003c/td\u003e\u003ctd\u003e4个\u003c/td\u003e\u003c/tr\u003e\u003ctr\u003e\u003ctd\u003e球\u003c/td\u003e\u003ctd\u003e3个\u003c/td\u003e\u003c/tr\u003e\u003c/table\u003e", + "knowledge_points": [ + "立体图形的认识及分类" + ], + "source": "25-26 一年级上·江西九江·期中" + }, + { + "id": "153", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "看图填空。 ![](images/f83ad6409dc584b8037566fcb22e19fde95f1bc185b4ade212d562610756b606.jpg) 长方体有( )个,圆柱有( )个,正方体有( )个,球有( )个。", + "options": [ + + ], + "answer": "3;4;2;3", + "solution": "【分析】长方体是长长方方的,有 6 个平平的面,且相对的两个面大小一样(特殊情况下有四个面相同);正方体是正正方方的有平平的面;圆柱上下是圆且上下一样粗;球没有平面可以任意方向滚动。据此数一数.\n【详解】 ![](images/f83ad6409dc584b8037566fcb22e19fde95f1bc185b4ade212d562610756b606.jpg) 长方体3个,圆柱有4个,正方体有2个,球有3个。", + "knowledge_points": [ + "立体图形的认识及分类" + ], + "source": "25-26 一年级上·江西九江·期中" + }, + { + "id": "154", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "在圆柱,正方体和球中, ( )可以立起来,还可以滚动;( )能向四面八方滚动;( )有6个平平的面。", + "options": [ + + ], + "answer": "圆柱;球;正方体", + "solution": "【分析】长方体是长长方方的有 6 个平平的面,可以直立起来,但不易滚动;圆柱上下是平平的面且上下一样粗,侧面是曲面,既可以直立起来,也可以滚动;球是圆圆的,没有平面,可以任意方向滚动的,但不可以直立起来;根据立体图形的特征来解决此题.\n【详解】由题意分析得:在圆柱,正方体和球中,圆柱可以立起来,还可以滚动;球能向四面八方滚动;正方体有 6 个平平的面。", + "knowledge_points": [ + "立体图形的认识及分类" + ], + "source": "25-26 一年级上·江西九江·期中" + }, + { + "id": "155", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "数一数,填一填。 ![](images/1a7c8e1ce261d8e0b25a31e4bdf9d01b01e8145c51fce805829a3c6d0efc2dec.jpg) 长方体有( )个;正方体有( )个;球有( )个;圆柱有( )个。", + "options": [ + + ], + "answer": "4;1;2;4", + "solution": "【分析】长方体是长长方方的有平平的面;正方体是正正方方的有平平的面;圆柱上下是平平的面且上下一样粗,侧面是曲面;球是圆圆的,没有平面,可以任意方向滚动的;根据立体图形的特征来解决此题.\n【详解】由题意分析得:长方体有 4 个;正方体有1个;球有2个;圆柱有4个。", + "knowledge_points": [ + "立体图形的认识及分类" + ], + "source": "25-26 一年级上·江西九江·期中" + }, + { + "id": "156", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "长方体( )个,正方体( )个,圆柱( )个,球( )个。 ![](images/6c9edff2c06a01f8dce5112e2deb0745fab14b43c69987bd7c1db6ee7bfa6a4f.jpg)", + "options": [ + + ], + "answer": "3;5;4;2", + "solution": "【分析】长方体是长长方方的有平平的面;正方体是正正方方的有平平的面;圆柱上下是平平的面且上下一样粗,侧面是曲面;球是圆圆的,没有平面,可以任意方向滚动的;根据立体图形的特征来解决此题.\n【详解】由图可得:长方体3个,正方体5个,圆柱4个,球2个。", + "knowledge_points": [ + "立体图形的认识及分类" + ], + "source": "25-26 一年级上·江西九江·期中" + }, + { + "id": "157", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.65, + "question": "长方体有( )个,球有( )个,圆柱有( )个,正方体有( )个,球比长方体少( )个。 ![](images/df4d5d97dbc11fbc07e2f2ed215bf638d629eee38e30640a8fe2052fa060e5b9.jpg)", + "options": [ + + ], + "answer": "6;5;5;2;1", + "solution": "【分析】长方体是长长方方的有平平的面;正方体是正正方方的有平平的面;圆柱上下是圆且上下一样粗;球没有平面可以任意方向滚动的;根据立体图形的特征,先按照顺序数一数,再填空即可。求一个数比另一个数少多少,用减法列式解决.\n【详解】 6 -5 = 1(个) 长方体有6个,球有5个,圆柱有5个,正方体有2个,球比长方体少1个。", + "knowledge_points": [ + "6 的加减法", + "立体图形的认识及分类" + ], + "source": "25-26 一年级上·江西九江·期中" + }, + { + "id": "158", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.65, + "question": "数一数,下面各图中的小正方体分别有几个。 ![](images/987792d1f06913c57a6a3ac814deff7a6d4c57a2b10c60affa7e071cf575241d.jpg)有( )个。![](images/9d126fd4464750401a6e6a5d67880a23.png) 有( )个。", + "options": [ + + ], + "answer": "8;6", + "solution": "【分析】第一幅图是 2×2×2 的大正方体,共 8 个小正方体;第二幅图上层 1 个,下层 5 个,相加即可.\n【详解】第一幅图一共有 2×2×2 = 8 (个);第二幅图,上层有 1 个,下层有 5 个,一共有: 1 + 5 = 6 (个)。", + "knowledge_points": [ + "数正方体的个数" + ], + "source": "25-26 一年级上·江西九江·期中" + }, + { + "id": "159", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "数一数。(把各种图形数一数,再填在括号里) ![](images/87551a347b32969b4bcddf5836ca3c45f92bf8415d0bc60ab270053e27430bc4.jpg) 长方体( )个,正方体 ( )个,球 ( )个,圆柱 ( )个。", + "options": [ + + ], + "answer": "4;1;2;4", + "solution": "【分析】长方体是长长方方的有平平的面;正方体是正正方方的有平平的面;圆柱上下是平平的面且上下一样粗;球没有平面可以任意方向滚动,由此数出各图形的数量即可.\n【详解】 长方体4个,正方体1个,球2个,圆柱4个。", + "knowledge_points": [ + "立体图形的认识及分类" + ], + "source": "25-26 一年级上·江西九江·期中" + }, + { + "id": "160", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.65, + "question": "数一数,填一填。 ![](images/17d9df9c96b40ab5bee0c0fc9bdba20ee05f88876a990e496d9ff7d516c3c562.jpg) 长方体有( )个,正方体有( )个,球有( )个,圆柱有( )个。", + "options": [ + + ], + "answer": "4;1;2;4", + "solution": "【分析】长方体:长长方方的,有平平的面;正方体:是四四方方的,有平平的面;圆柱:是直直的,上下一样粗,两头是圆的,平平的;球体:圆圆的,表面光滑;根据立体图形的特征,数一数即可.\n【详解】长方体有 4 个,正方体有 1 个,球有 2 个,圆柱4 个。", + "knowledge_points": [ + "立体图形的认识及分类" + ], + "source": "25-26 一年级上·江西九江·期中" + }, + { + "id": "161", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "数一数,填一填。 ![](images/58ecfaaf82f4461ff962fa3d212089e2b31befec4405fe625fd5c16139d0b86a.jpg) 长方体有( )个,正方体有( )个,球有( )个,圆柱有( )个。", + "options": [ + + ], + "answer": "5;3;2;4", + "solution": "【分析】长方体是长长方方的有平平的面;正方体是正正方方的有平平的面;圆柱上下是圆且上下一样粗;球没有平面可以任意方向滚动。据此数一数.\n【详解】由分析可得:长方体有 (5) 个,正方体有 (3) 个,球有 (2)个,圆柱有 (4) 个。", + "knowledge_points": [ + "立体图形的认识及分类" + ], + "source": "25-26 一年级上·江西九江·期中" + }, + { + "id": "162", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.65, + "question": "数一数,填一填。 ![](images/e3cd4e81d3b1407273c0f5946b9da564df56b524ba8f72d5f8c788f38735a08d.jpg) 其中,长方体有( )个,正方体有( )个,球有( )个,圆柱有( )个。", + "options": [ + + ], + "answer": "4;1;2;4", + "solution": "【分析】首先要分别分析出图片中各个物体的特征:长方体有 6 个平平的面,长长的方方的;正方体四四方方的,有 6 个平平的面,每个面的大小都一样;圆柱直直的,上下一样粗,两端是两个大小一样的,圆圆的,平平的圆面,把圆柱横放在桌子上能滚动,立在桌子上就不能滚动;球是圆圆的,表面是曲面,把球放在桌子上能向任意方向滚动。根据每个物体的特征分别数一数图中各个物体的个数即可.\n【详解】 数出 长方体有4个,正方体有1个,球有2个,圆柱有4个。", + "knowledge_points": [ + "立体图形的认识", + "数一数" + ], + "source": "25-26 一年级上·江西九江·期中" + }, + { + "id": "163", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "长方体有( )个面,相对的两个面大小( )。", + "options": [ + + ], + "answer": "6;一样", + "solution": "【分析】长方体是长长方方的,有 6 个平平的面,且相对的两个面大小一样(特殊情况下有四个面相同).\n【详解】长方体有6个面,相对的两个面大小一样。![](images/e33425784c916f9384c4ea159917426f.png)", + "knowledge_points": [ + "长方体的认识及特征" + ], + "source": "25-26 一年级上·江西九江·期中" + }, + { + "id": "164", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "谁的小眼睛最亮。 ![](images/7b72e4ad13009f181dbb231e57525d6a58b8da9310f0ab09d335473ec123a650.jpg) 长方体( )个 正方体( )个 球( )个 圆柱( )个 ", + "options": [ + + ], + "answer": "4;1;2;4", + "solution": "【分析】长方体是长长方方的有平平的面;正方体是正正方方的有平平的面;圆柱上下是平平的面且上下一样粗;球没有平面可以任意方向滚动,由此数出各图形的数量即可.\n【详解】由分析填写如下: ![](images/399f3a05e7e70a839dbf100af779874a9b1085a623129ba2a038bdc638043f5d.jpg) 长方体4个 正方体1个 球2个 圆柱4个 ", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "25-26 一年级上·江西九江·期中" + }, + { + "id": "165", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "看谁数得准。 ![](images/39a88f9afc55ec8fe7326d911fdb534929c02857483b7fae390decdd9d5d8ba6.jpg) ( )个球 ( )个长方体 ( )个圆柱 ( )个正方体", + "options": [ + + ], + "answer": "5;4;3;1", + "solution": "【分析】长方体是长长方方的有平平的面;正方体是正正方方的有平平的面;圆柱上下是平平的面且上下一样粗;球没有平面可以任意方向滚动,由此数出每种图形的数量即可.\n【详解】由分析填写如下: ![](images/39d5fd1d8d3c4a0b48a960f373f20800d89a25a4dc3f3c72383521b8bd5253f6.jpg) 5个球4个长方体3个圆柱1个正方体", + "knowledge_points": [ + "立体图形的认识及分类" + ], + "source": "25-26 一年级上·江西九江·期中" + }, + { + "id": "166", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "数一数。 ![](images/332dd89c0ae73f6f639226d800b254d2181c1f37680c139c59deb975fd88ceac.jpg) 圆柱有( )个。 长方体有( )个。正方体 有( )个。球有( )个。", + "options": [ + + ], + "answer": "4;4;1;2", + "solution": "【分析】长方体是长长方方的有平平的面;正方体是正正方方的有平平的面;圆柱上下是圆且上下一样粗;球没有平面可以任意方向滚动的;根据立体图形的特征,先数一数,再填空即可.\n【详解】由题意分析得:圆柱有4个。 长方体有4个。 正方体有1个。球有2个。", + "knowledge_points": [ + "立体图形的认识及分类" + ], + "source": "25-26 一年级上·江西九江·期中" + }, + { + "id": "167", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "数一数,填一填。 ![](images/edf0cc3761cca9c469c2c1b226c75b7ac6fa8d1c78915f2d381fcf478e1b2622.jpg) \u003ctable\u003e\u003ctr\u003e\u003ctd\u003e球\u003c/td\u003e\u003ctd\u003e正方体\u003c/td\u003e\u003ctd\u003e长方体\u003c/td\u003e\u003ctd\u003e圆柱\u003c/td\u003e\u003c/tr\u003e\u003ctr\u003e\u003ctd\u003e()个\u003c/td\u003e\u003ctd\u003e()个\u003c/td\u003e\u003ctd\u003e()个\u003c/td\u003e\u003ctd\u003e()个\u003c/td\u003e\u003c/tr\u003e\u003c/table\u003e", + "options": [ + + ], + "answer": "2;2;3;2", + "solution": "【分析】长方体是长长方方的有平平的面;正方体是正正方方的有平平的面;圆柱上下是平平的面且上下一样粗;球没有平面可以任意方向滚动,由此数出各图形的数量即可.\n【详解】由分析填写如下: \u003ctable\u003e\u003ctr\u003e\u003ctd\u003e球\u003c/td\u003e\u003ctd\u003e正方体\u003c/td\u003e\u003ctd\u003e长方体\u003c/td\u003e\u003ctd\u003e圆柱\u003c/td\u003e\u003c/tr\u003e\u003ctr\u003e\u003ctd\u003e2个\u003c/td\u003e\u003ctd\u003e2个\u003c/td\u003e\u003ctd\u003e3个\u003c/td\u003e\u003ctd\u003e2个\u003c/td\u003e\u003c/tr\u003e\u003c/table\u003e", + "knowledge_points": [ + "立体图形的认识及分类" + ], + "source": "25-26 一年级上·江西九江·期中" + }, + { + "id": "168", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.65, + "question": "请你数一数。(不包括组合体) ![](images/59cbb093a5b8fa3df83ab942f0ef8aba159e5753e5f036d6f2b2ba2c45718527.jpg)![](images/a1af5936e9fd5da9f143a5c486ae2ce34dd63e0af1a00e18dd28062615fbcb5d.jpg)( )个长方体 ( )个正方体", + "options": [ + + ], + "answer": "3;4", + "solution": "【分析】长方体有 6 个平平的面,长长的方方的;正方体四四方方的,有 6 个平平的面,每个面的大小都一样。据此数出长方体和正方体的数量即可.\n【详解】图一:数出长方体有 3 个;图二:上层有 1 个正方体,下层有 3 个正方体,一共有 1 + 3 = 4 (个)正方体。 填空如下: ![](images/890ca7bebda0dd550bb977ebbef682fa.png)", + "knowledge_points": [ + "数正方体的个数", + "立体图形的认识及分类" + ], + "source": "25-26 一年级上·江西九江·期中" + }, + { + "id": "169", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "数一数,填一填。 ![](images/04bf2652cc868416bfce74047e0c8cfcafb0ca5d4ef9081256040e5522002406.jpg) \u003ctable\u003e\u003ctr\u003e\u003ctd\u003e长方体\u003c/td\u003e\u003ctd\u003e正方体\u003c/td\u003e\u003ctd\u003e圆柱\u003c/td\u003e\u003ctd\u003e球\u003c/td\u003e\u003c/tr\u003e\u003ctr\u003e\u003ctd\u003e()个\u003c/td\u003e\u003ctd\u003e()个\u003c/td\u003e\u003ctd\u003e()个\u003c/td\u003e\u003ctd\u003e()个\u003c/td\u003e\u003c/tr\u003e\u003c/table\u003e", + "options": [ + + ], + "answer": "4;3;4;2", + "solution": "【分析】长方体是长长方方的有平平的面;正方体是正正方方的有平平的面;圆柱上下是圆且上下一样粗;球没有平面可以任意方向滚动的;根据立体图形的特征,先数一数,再填空即可.\n【详解】由题意分析得: \u003ctable\u003e\u003ctr\u003e\u003ctd\u003e长方体\u003c/td\u003e\u003ctd\u003e正方体\u003c/td\u003e\u003ctd\u003e圆柱\u003c/td\u003e\u003ctd\u003e球\u003c/td\u003e\u003c/tr\u003e\u003ctr\u003e\u003ctd\u003e4个\u003c/td\u003e\u003ctd\u003e3个\u003c/td\u003e\u003ctd\u003e4个\u003c/td\u003e\u003ctd\u003e2个\u003c/td\u003e\u003c/tr\u003e\u003c/table\u003e", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "25-26 一年级上·江西九江·期中" + }, + { + "id": "170", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.65, + "question": "数一数。 ![](images/4e79931de21d25319c56ec4fa79ae0c6.png) ![](images/977863bf8915ea1b5242041d9268b9cc76cf8641384d2470b2af32197058d7e0.jpg) ![](images/0f92c062c9d47345276615f2d551f7028a9812630dd8a7a4d9a36e0ee97687bf.jpg) ![](images/df08300ebdee11e9cf3c67b831b9d66e16f9a79786ca24e65c987f4db106ccf7.jpg) \u003ctable\u003e\u003ctr\u003e\u003ctd\u003e正方体\u003c/td\u003e\u003ctd\u003e长方体\u003c/td\u003e\u003ctd\u003e圆柱\u003c/td\u003e\u003ctd\u003e球\u003c/td\u003e\u003c/tr\u003e\u003ctr\u003e\u003ctd\u003e()个\u003c/td\u003e\u003ctd\u003e()个\u003c/td\u003e\u003ctd\u003e()个\u003c/td\u003e\u003ctd\u003e()个\u003c/td\u003e\u003c/tr\u003e\u003c/table\u003e", + "options": [ + + ], + "answer": "正方体4个;长方体2个;圆柱2个;球4个", + "solution": "【分析】首先要分别分析出图片中各个物体的特征:长方体有 6 个平平的面,长长的方方的;正方体四四方方的,有 6 个平平的面,每个面的大小都一样;圆柱直直的,上下一样粗,两端是两个大小一样的,圆圆的,平平的圆面,把圆柱横放在桌子上能滚动,立在桌子上就不能滚动;球是圆圆的,表面是曲面,把球放在桌子上能向任意方向滚动。根据每个物体的特征分别数一数图中各个物体的个数即可.\n【详解】由分析可得: \u003ctable\u003e\u003ctr\u003e\u003ctd\u003e正方体\u003c/td\u003e\u003ctd\u003e(4)个\u003c/td\u003e\u003ctd\u003e长方体\u003c/td\u003e\u003ctd\u003e(2)个\u003c/td\u003e\u003ctd\u003e圆柱\u003c/td\u003e\u003ctd\u003e(2)个\u003c/td\u003e\u003ctd\u003e球\u003c/td\u003e\u003ctd\u003e(4)个\u003c/td\u003e\u003c/tr\u003e\u003c/table\u003e", + "knowledge_points": [ + "立体图形的认识", + "数一数" + ], + "source": "25-26 一年级上·江西九江·期中" + }, + { + "id": "171", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "数一数,填一填。 ![](images/8272ebbddec5ba902bca887b52ef322de7a7913ebbbe27470136048b1b5a7204.jpg) 正方体有( )个,长方体有( )个,球有( )个,圆柱有( )个。", + "options": [ + + ], + "answer": "1;4;4;3", + "solution": "【分析】正方体是正正方方的有平平的面;长方体是长长方方的有平平的面;球没有平面可以任意方向滚动;圆柱上下是平平的面且上下一样粗。由此数出各图形的数量即可.\n【详解】 ![](images/5b647cc93dade93eb30f6f1c0b54203617f1e998d2c25ea4a90bbd626b7c1b66.jpg) 正方体有 1 个,长方体有 4 个,球有 4 个,圆柱有 3 个。", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "25-26 一年级上·江西九江·期中" + }, + { + "id": "172", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.65, + "question": "数一数。 ![](images/b87c7630c8551cc5494c90b7a84efecee1e3846931410989b551ce4bb3477109.jpg) ![](images/5cebb92fc35e6c4749dba94c0ff868fd6958f2a5cf96b3c84e032ed293884885.jpg) ![](images/57ba1cb96998fd676eb1541ba0945992eab64948993b32e23de693237a2b3522.jpg)", + "options": [ + + ], + "answer": "5;4;2;2", + "solution": "【分析】长方体是长长的,由 6 个长方形的面围成;圆柱由 1 个曲面和 2 个圆形围成;球是圆圆的,由 1 个曲面围成;正方体正正方方的,由 6 个正方形的围成;根据立体图形的特征,分别数一数各有几个即可.\n【详解】由题意分析得:长方体5个,圆柱4个,球2个,正方体2个。", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "25-26 一年级上·江西九江·期中" + }, + { + "id": "173", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "数一数。 ![](images/63ab8a48760c2bb29f5142b61be77ca19f4f5759c8f67374843bf5bf0916ea90.jpg) 正方体 ( )个,长方体( )个,圆柱( )个,球( )个。", + "options": [ + + ], + "answer": "4;5;4;3", + "solution": "【分析】正方体是正正方方的有平平的面;长方体是长长方方的有平平的面;圆柱上下是平平的面且上下一样粗;球没有平面可以任意方向滚动,由此数出各图形的数量即可.\n【详解】 ![](images/268fc231020059f79c2387e22db744b217b9e412d32875a487c2adf36f8a0a51.jpg)", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "25-26 一年级上·江西九江·期中" + }, + { + "id": "174", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.65, + "question": "数一数,填一填。 ![](images/72989c71aaae2b91d8ec7aebb24c101f71cc8f8e41368410dfd70037adc06a79.jpg) \u003ctable\u003e\u003ctr\u003e\u003ctd\u003e正方体\u003c/td\u003e\u003ctd\u003e()个\u003c/td\u003e\u003c/tr\u003e\u003ctr\u003e\u003ctd\u003e长方体\u003c/td\u003e\u003ctd\u003e()个\u003c/td\u003e\u003c/tr\u003e\u003ctr\u003e\u003ctd\u003e圆柱\u003c/td\u003e\u003ctd\u003e()个\u003c/td\u003e\u003c/tr\u003e\u003ctr\u003e\u003ctd\u003e球\u003c/td\u003e\u003ctd\u003e()个\u003c/td\u003e\u003c/tr\u003e\u003c/table\u003e", + "options": [ + + ], + "answer": "7;4;3;4", + "solution": "【分析】长方体是长长方方的,有平平的面;正方体是正正方方的,有平平的面,且6个面完全相同;球没有平面,可以任意方向滚动;圆柱上下是圆且上下一般粗;根据立体图形的特征,先数一数,再填空即可.\n【详解】由分析可知: \u003ctable\u003e\u003ctr\u003e\u003ctd\u003e正方体\u003c/td\u003e\u003ctd\u003e(7)个\u003c/td\u003e\u003c/tr\u003e\u003ctr\u003e\u003ctd\u003e长方体\u003c/td\u003e\u003ctd\u003e(4)个\u003c/td\u003e\u003c/tr\u003e\u003ctr\u003e\u003ctd\u003e圆柱\u003c/td\u003e\u003ctd\u003e(3)个\u003c/td\u003e\u003c/tr\u003e\u003ctr\u003e\u003ctd\u003e球\u003c/td\u003e\u003ctd\u003e(4)个\u003c/td\u003e\u003c/tr\u003e\u003c/table\u003e", + "knowledge_points": [ + "1~5 的认识和读写", + "立体图形的认识", + "6,7 的认识和读写" + ], + "source": "25-26 一年级上·江西九江·期中" + }, + { + "id": "175", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "数一数。 ![](images/2362332947f8093bf6fa25e867cf785b9650200cfb30b9f76ea2b16e3205772c.jpg) 长方体( )个,球( )个,圆柱( )个,正方体( )个。", + "options": [ + + ], + "answer": "4;3;3;3", + "solution": "【分析】根据立体图形的特征,先数一数,再填空即可。长方体是长长方方的有平平的面;正方体是正正方方的有平平的面;圆柱上下是圆且上下一样粗;球没有平面可以任意方向滚动的.\n【详解】由题意分析得: ![](images/a9a043c6a12af759039ef5b98451e3059051f9ee6675f57508c0b4201859ca54.jpg)", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "25-26 一年级上·江西九江·期中" + }, + { + "id": "176", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "数一数,填一填。 ![](images/0e825fa9b643f17d176f6efe950967baf5db2c7e87aa3a4ad738f3ff9b1d5ade.jpg) 长方体( )个,正方体 ( )个,圆柱 ( )个,球( )个。", + "options": [ + + ], + "answer": "2;5;1;2", + "solution": "【分析】长方体是长长方方的,有 6 个平平的面,且相对的两个面大小一样(特殊情况下有四个面相同);正方体是正正方方的有平平的面;圆柱上下是圆且上下一样粗;球没有平面可以任意方向滚动,据此数一数.\n【详解】 ![](images/ab55a2f17eaf52db4abfc2d9b3c58e2100519755003314076f36ac1bf40acc0f.jpg)", + "knowledge_points": [ + "立体图形的认识", + "数一数" + ], + "source": "25-26 一年级上·江西九江·期中" + }, + { + "id": "177", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "下图中一共有( )个 ![](images/697eaa29f4a5a69dec968a799cf76859e7e838e06aeafa34b6b3f91cf282d327.jpg) 。 ![](images/f275766e7bb5086e9ac4d6e1081eb2add746a04e1dba856025123c46c1e182a2.jpg)", + "options": [ + + ], + "answer": "6", + "solution": "【分析】由图可知从上往下第一层有 1 个小正方体,第二层有 1 个小正方体,第三层有 4 个小正方体 (注意第二层下面对应着有一个小正方体), 加在一起即为一共有多少个小正方体.\n【详解】 1 + 1 + 4 = 6(个)图中一共有 6 个 。", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "25-26 一年级上·江西九江·期中" + }, + { + "id": "178", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "数一数,填一填。 ![](images/671a273da2ef5b7a064dae93dc5dd3ab436213027dac04439ed79485beac130a.jpg) 圆柱有( )个,正方体有( )个,球有( )个,长方体有( )个。", + "options": [ + + ], + "answer": "2;2;3;5", + "solution": "【分析】圆柱上下是平平的面且上下一样粗;正方体是正正方方的,有平平的面;球没有平面,可以任意方向滚动;长方体是长长方方的,有平平的面。由此数出各图形的数量填空即可.\n【详解】由分析可知:圆柱有 2 个,正方体有 2 个,球有 3 个,长方体有 5 个。", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "25-26 一年级上·江西九江·期中" + }, + { + "id": "179", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.65, + "question": "如图的物体是由( )个小正方体搭成的。 ![](images/3d9edf65782533ddd2e2644b0264538cac2182175e66413b3e867e0b37300723.jpg)", + "options": [ + + ], + "answer": "8", + "solution": "【分析】该物体下层有 5 个小正方体,上层有 3 个小正方体,相加即可求出总数.\n【详解】 5 + 3 = 8 (个),该物体是由 8 个小正方体搭成的。", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "25-26 一年级上·江西九江·期中" + }, + { + "id": "180", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "数一数,填一填。 ![](images/c1ba11d631fdd89d4b6966f1b6355437636fdb6cfcca4a500ab1fe47bcc8ecdd.jpg) ( )个 正方体, ( )个圆柱 , ( )个长方体 , ( )个球 。", + "options": [ + + ], + "answer": "2;3;4;2", + "solution": "【分析】长方体是长长方方的有平平的面;正方体是正正方方的有平平的面;圆柱上下是平平的面且上下一样粗;球没有平面可以任意方向滚动。由此数出各图形的数量填空即可.\n【详解】由分析填写如下: ![](images/13c1c841a08553fe90945f890ceac1ec7efa2f05cf9cd9e0fa5d8ee4f2ddb5eb.jpg) 2个正方体 ,3个圆柱 ,4个长方体 ,2个球 。", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "25-26 一年级上·江西九江·期中" + }, + { + "id": "181", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "数一数。 ![](images/30c2d8f545e82707661686ecc92360e3ed6e65d5e74a864e97276b0b16e2604f.jpg) 长方体有( )个,正方体有( )个,球有( )个,圆柱有( )个。", + "options": [ + + ], + "answer": "3;2;2;1", + "solution": "【分析】长方体是长长方方的,有 6 个平平的面,且相对的两个面大小一样(特殊情况下有四个面相同);正方体是正正方方的有平平的面;圆柱上下是圆且上下一样粗;球没有平面可以任意方向滚动。据此数一数.\n【详解】 长方体有3个,正方体有2个,球有2个,圆柱有 1 个。", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "25-26 一年级上·江西九江·期中" + }, + { + "id": "182", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "数一数。 ![](images/4c1c1fc3c144518a9e75fd3bfb324d961a65fc5bc5c6b00ef3bd484d0d802a0e.jpg) 长方体有( )个,正方体有( )个,圆柱有( )个,球有( )个。", + "options": [ + + ], + "answer": "5;3;2;2", + "solution": "【分析】长方体是长长方方的有平平的面;正方体是正正方方的有平平的面;圆柱上下是平平的面且上下一样粗;球没有平面可以任意方向滚动。由此数出各图形的数量填空即可.\n【详解】由分析填写如下: ![](images/fc3ba727262c7c00ece186a658b38dd36cd1d722c2b27dafea605a50637e95db.jpg) 长方体有 5 个,正方体有 3 个,圆柱有 2 个,球有 2 个。", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "25-26 一年级上·江西九江·期中" + }, + { + "id": "183", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.65, + "question": "数一数,填一填。 ![](images/e3dbc027aca17ddea28b7eb438142dce9bae05c8d866be99fc8ca9982738d92e.jpg) 长方体( )个,正方体( )个,圆柱( )个,球( )个。", + "options": [ + + ], + "answer": "4;1;3;4", + "solution": "【分析】长方体的特点:有六个面,相对的两个面相同;正方体的特点:有六个面,六个面都相同;圆柱的特点:直直的,有一个曲面,上下两个面都是圆;球的特点:圆圆的,能滚动,据此解答.\n【详解】填空如下:长方体(4) 个,正方体(1) 个,圆柱(3) 个,球(4) 个", + "knowledge_points": [ + "立体图形的认识", + "长方体的认识及特征", + "圆柱的认识及特征", + "正方体的特征" + ], + "source": "25-26 一年级上·江西九江·期中" + }, + { + "id": "184", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "小熊请客。 ![](images/5ecec5317983f65de021020d89544b60857562aeea3c11b5ae4aee5f4dc70ec0.jpg) \u003ctable\u003e\u003ctr\u003e\u003ctd\u003e长方体\u003c/td\u003e\u003ctd\u003e()个\u003c/td\u003e\u003c/tr\u003e\u003ctr\u003e\u003ctd\u003e正方体\u003c/td\u003e\u003ctd\u003e()个\u003c/td\u003e\u003c/tr\u003e\u003ctr\u003e\u003ctd\u003e圆柱\u003c/td\u003e\u003ctd\u003e()个\u003c/td\u003e\u003c/tr\u003e\u003ctr\u003e\u003ctd\u003e球\u003c/td\u003e\u003ctd\u003e()个\u003c/td\u003e\u003c/tr\u003e\u003c/table\u003e", + "options": [ + + ], + "answer": "1;2;4;3", + "solution": "【分析】长方体是长长方方的有平平的面;正方体是正正方方的有平平的面;圆柱上下是平平的面且上下一样粗;球没有平面可以任意方向滚动的。由此数出各图形的数量填空即可.\n【详解】由分析填写如下: ![](images/91c87308248d6185d3041b6b3ba7edf71a278284b769dd4b717dc5e7fbd02582.jpg) \u003ctable\u003e\u003ctr\u003e\u003ctd\u003e长方体\u003c/td\u003e\u003ctd\u003e1个\u003c/td\u003e\u003c/tr\u003e\u003ctr\u003e\u003ctd\u003e正方体\u003c/td\u003e\u003ctd\u003e2个\u003c/td\u003e\u003c/tr\u003e\u003ctr\u003e\u003ctd\u003e圆柱\u003c/td\u003e\u003ctd\u003e4个\u003c/td\u003e\u003c/tr\u003e\u003ctr\u003e\u003ctd\u003e球\u003c/td\u003e\u003ctd\u003e3个\u003c/td\u003e\u003c/tr\u003e\u003c/table\u003e", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "25-26 一年级上·江西九江·期中" + }, + { + "id": "185", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "长方体和正方体都有( )个面。", + "options": [ + + ], + "answer": "6", + "solution": "【分析】长方体是长长方方的有平平的面;正方体是正正方方的有平平的面。如图为正方体和长方体。都有 6 个面,由此解答.\n【详解】由分析可知,长方体和正方体都有6个面。", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "25-26 一年级上·江西九江·期中" + }, + { + "id": "186", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.65, + "question": "用小正方体拼一个大正方体,最少要( )个一样的小正方体。", + "options": [ + + ], + "answer": "8", + "solution": "【分析】用小正方体拼一个大正方体,用最少小正方体的拼法,一层摆2行,一行摆2个,一层就需要 (2 + 2 = 4) 个,摆这样的2层,一共需要 (4 + 4 = 8) 个(如下图);据此解决.\n【详解】 2 + 2 = 4(个) 4 + 4 = 8 (个) 即,用小正方体拼一个大正方体,最少要 8 个一样的小正方体。", + "knowledge_points": [ + "正方体的特征" + ], + "source": "25-26 一年级上·江西九江·期中" + }, + { + "id": "187", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "数一数,填一填。 ![](images/348720b237c365640036ef6c331fa936662dbd798dbc12834639ff89ebafa8c6.jpg) 正方体有( )个 长方体有( )个 圆柱有( )个 球有( )个", + "options": [ + + ], + "answer": "0;5;3;2", + "solution": "【分析】长方体是长长方方的有平平的面;正方体是正正方方的有平平的面;圆柱上下是圆且上下一样粗;球没有平面可以任意方向滚动.\n【详解】 ![](images/571846c46f2f2d6760077961d1d35f79c2d903b27fe52d15c88752cb5d27a99e.jpg) 正方体有0个,长方体有5个,圆柱有 3 个,球有 2 个。", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "25-26 一年级上·江西九江·期中" + }, + { + "id": "188", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "![](images/2f0ae238bb13ec3366d7a535ba5dfbc671c6b0b3197186013e976abd390750a0.jpg) 长方体有( )个;正方体有( )个;圆柱有( )个;球有( )个。", + "options": [ + + ], + "answer": "4;1;4;2", + "solution": "【分析】长方体是长长方方的有平平的面;正方体是正正方方的有平平的面;圆柱上下是圆且上下一样粗;球没有平面可以任意方向滚动,由此数出各图形的数量填空即可.\n【详解】由分析可知: ![](images/aa8381a32407446e595ba9e869ba53115c53a38cbbf9eaebbefa5e3627ec5f2d.jpg) 长方体有 4 个;正方体有 1 个;圆柱有 4 个;球有 2 个。", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "25-26 一年级上·江西九江·期中" + }, + { + "id": "189", + "unit": "第三单元 认识立体图形", + "question_type": "解答题", + "difficulty": 0.85, + "question": "搭积木。要拼成一个大正方体,下图至少还需要再摆上( )个 ![](images/8bbbf64d23054792560d779d38f99454f0656005421a8fcf46f11263b9c2154f.jpg)。 ![](images/9918b214db2227e6622c382a8cecd8192a5e55294e10b6062012af6705fb8731.jpg)", + "options": [ + + ], + "answer": "2", + "solution": "【分析】正方体是正正方方的有平平的面。由题意作图如下:需要添上 2 个 ![](images/8bbbf64d23054792560d779d38f99454f0656005421a8fcf46f11263b9c2154f.jpg)。![](images/d3586606f0967608569850fc79bc3c8b10ac0d9e7caa3828c261903d5935d127.jpg)\n【详解】由分析得:要拼成一个大正方体,下图至少还需要再摆上 2 个 ![](images/8bbbf64d23054792560d779d38f99454f0656005421a8fcf46f11263b9c2154f.jpg)。", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "25-26 一年级上·江西九江·期中" + }, + { + "id": "190", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.65, + "question": "数立体图形。 ![](images/2180457c4b211fb46e39d8c128a3a2ef5b60b45d380ec014d72089c61cd5f4c6.jpg) 正方体( )个,长方体 ( )个,圆柱( )个,球( )个。", + "options": [ + + ], + "answer": "2;3;3;4", + "solution": "【分析】长方体是长长方方的有平平的面;正方体是正正方方的有平平的面;圆柱上下是圆且上下一样粗;球没有平面可以任意方向滚动;由此根据长方体,正方体,圆柱以及球的特征,通过数一数的方法,进行解答即可.\n【详解】 ![](images/08787ffc889b8e885f0ee682f15a25dda23915079b143618a247b3e109cfced8.jpg) 正方体(2) 个,长方体(3) 个,圆柱(3) 个,球(4) 个。", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "25-26 一年级上·江西九江·期中" + }, + { + "id": "191", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "数一数,填一填。 ![](images/5a92c6540e585d9a29b15c69261edae21c4018e049daa2580c7faf34bff160c0.jpg) 正方体有( )个,长方体有( )个,圆柱有( )个,球有( )个。", + "options": [ + + ], + "answer": "2;1;6;4", + "solution": "【分析】长方体是长长方方的有平平的面;正方体是正正方方的有平平的面;圆柱上下是圆且上下一样粗;球没有平面可以任意方向滚动的。由此数出各图形的数量填空即可.\n【详解】 ![](images/a8418f6d722145f58195da388a2f7c076591d9c3ccc6e46ad28e9525191ab9b3.jpg) 正方体有 2 个,长方体有 1 个,圆柱有 6 个,球有 4 个。", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "25-26 一年级上·江西九江·期中" + }, + { + "id": "192", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "最少用( )块同样的小正方体![](images/8bbbf64d23054792560d779d38f99454f0656005421a8fcf46f11263b9c2154f.jpg)才能摆成一个更大的正方体。", + "options": [ + + ], + "answer": "8", + "solution": "【分析】正方体是方方正正的,有平平的面,每个面都同样大。要想拼成一个大的正方体,如图:下面一层需要 4 块小正方体,上面一层需要 4 块小正方体。由此解答.\n【详解】 4 + 4 = 8 (块) 最少用 8 块同样的 ![](images/8bbbf64d23054792560d779d38f99454f0656005421a8fcf46f11263b9c2154f.jpg)才能摆成一个更大的正方体。", + "knowledge_points": [ + "8,9 的加减法", + "立体图形的认识" + ], + "source": "25-26 一年级上·江西九江·期中" + }, + { + "id": "193", + "unit": "第三单元 认识立体图形", + "question_type": "判断题", + "difficulty": 0.85, + "question": "乒乓球是一个圆柱。", + "options": [ + + ], + "answer": "×", + "solution": "【分析】圆柱上下是平平的面且上下一样粗;球没有平面可以任意方向滚动,由此解答.\n【详解】乒乓球是圆滚滚的,没有平平的面,是球,原题说法错误。故答案为: ×", + "knowledge_points": [ + "立体图形的认识及分类" + ], + "source": "25-26 一年级上·江西九江·期中" + }, + { + "id": "194", + "unit": "第三单元 认识立体图形", + "question_type": "判断题", + "difficulty": 0.85, + "question": "数学书是一个长方体。", + "options": [ + + ], + "answer": "√", + "solution": "【分析】如图:长方体是长长方方的有平平的面,由此判断即可.\n【详解】由分析可知,数学书是一个长方体,原题说法正确。", + "knowledge_points": [ + "立体图形的认识及分类" + ], + "source": "25-26 一年级上·江西九江·期中" + }, + { + "id": "195", + "unit": "第三单元 认识立体图形", + "question_type": "判断题", + "difficulty": 0.85, + "question": "牙膏盒子是正方体。", + "options": [ + + ], + "answer": "×", + "solution": "【分析】长方体是长长方方的有平平的面,如![](images/61dee729e97a0ddabf29263e976cf41a9d9aae9c975a25d42c2d3e2359bec2e4.jpg);正方体是正正方方的有平平的面,如![](images/c72ce62e83a11afb3250b8388b9807f3a9214fc63c66e6a5ee6c6e9d3ab640c1.jpg)等。由此判断即可.\n【详解】由分析可知,牙膏盒子是长长方方的,是长方体,原题说法错误。故答案为: ×", + "knowledge_points": [ + "立体图形的认识及分类" + ], + "source": "25-26 一年级上·江西九江·期中" + }, + { + "id": "196", + "unit": "第三单元 认识立体图形", + "question_type": "判断题", + "difficulty": 0.94, + "question": "在我们搭积木的时候,我发现球是可以任意滚动的。", + "options": [ + + ], + "answer": "√", + "solution": "【分析】根据球的特点可知,球是圆圆的,表面是曲面,把球放在桌子上能向任意方向滚动。据此解答.\n【详解】根据分析可知:在我们搭积木的时候,我发现球是可以任意滚动的。故答案为: √", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "25-26 一年级上·江西九江·期中" + }, + { + "id": "197", + "unit": "第三单元 认识立体图形", + "question_type": "判断题", + "difficulty": 0.85, + "question": "一张长方形纸可以做成一个圆筒。", + "options": [ + + ], + "answer": "√", + "solution": "【分析】圆柱沿着高剪开,侧面展开图是一个长方形,则,把一张长方形纸的两条短边(或长边)接在一起,就可以做成一个圆筒.\n【详解】由题意分析得:一张长方形纸可以做成一个圆筒。此说法正确。故答案为: √", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "25-26 一年级上·江西九江·期中" + }, + { + "id": "198", + "unit": "第三单元 认识立体图形", + "question_type": "解答题", + "difficulty": 0.65, + "question": "要拼成一个较大的正方体,至少需要几个完全相同的小正方体。", + "options": [ + + ], + "answer": "8个", + "solution": "【分析】正方体是正正方方的有平平的面,每一面大小一样,可以作图求解.\n【详解】如图: ![](images/1a89ad6f622bc92b122a6788bf9eaed0eebb8ecd776545feb199255be249db34.jpg) 4 + 4 = 8 (个) 答:至少需要 8 个完全相同的小正方体。", + "knowledge_points": [ + "数正方体的个数", + "立体图形的拼搭" + ], + "source": "25-26 一年级上·江西九江·期中" + }, + { + "id": "199", + "unit": "第三单元 认识立体图形", + "question_type": "解答题", + "difficulty": 0.65, + "question": "下图中共有多少个小正方体。 ![](images/eceaeaf0da8234f0ee49eed3ab9319e4511d5b5b9a15ae9ab680c1dd7d0061bf.jpg)", + "options": [ + + ], + "answer": "9个", + "solution": "【分析】从下往上数,第一层有 5 个,第二层有 3 个,第三层有 1 个,将它们相加即可求解.\n【详解】 5 + 3 + 1 = 9 (个)答:图中共有 9 个小正方体。", + "knowledge_points": [ + "连加,连减(10以内)", + "数正方体的个数" + ], + "source": "25-26 一年级上·江西九江·期中" + }, + { + "id": "200", + "unit": "第三单元 认识立体图形", + "question_type": "解答题", + "difficulty": 0.85, + "question": "数一数,填一填。 ![](images/ea4902421a08373be04d656def5d451b0c5fbad220146c644626a6676eaf4028.jpg) \u003ctable\u003e\u003ctr\u003e\u003ctd\u003e长方体\u003c/td\u003e\u003ctd\u003e正方体\u003c/td\u003e\u003ctd\u003e圆柱\u003c/td\u003e\u003ctd\u003e球\u003c/td\u003e\u003c/tr\u003e\u003ctr\u003e\u003ctd\u003e()个\u003c/td\u003e\u003ctd\u003e()个\u003c/td\u003e\u003ctd\u003e()个\u003c/td\u003e\u003ctd\u003e()个\u003c/td\u003e\u003c/tr\u003e\u003c/table\u003e", + "options": [ + + ], + "answer": "3;4;6;5", + "solution": "【分析】长方体是长长方方的有平平的面;正方体是正正方方的有平平的面;圆柱上下是平平的面且上下一样粗;球没有平面可以任意方向滚动的。由此数出各图形的数量填空即可.\n【详解】由分析填写如下: ![](images/f998d73646ecfea58260ed7f6c85d758ac2865a35f5bb00886c7dd35298511b0.jpg) \u003ctable\u003e\u003ctr\u003e\u003ctd\u003e长方体\u003c/td\u003e\u003ctd\u003e3个\u003c/td\u003e\u003ctd\u003e正方体\u003c/td\u003e\u003ctd\u003e4个\u003c/td\u003e\u003ctd\u003e圆柱\u003c/td\u003e\u003ctd\u003e6个\u003c/td\u003e\u003ctd\u003e球\u003c/td\u003e\u003ctd\u003e5个\u003c/td\u003e\u003c/tr\u003e\u003c/table\u003e", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "25-26 一年级上·江西九江·期中" + }, + { + "id": "201", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.65, + "question": "如图![](images/1d3c0fb15edd2bacd5f9bc40041cd61c955725e22d7c2ae1b5a4234f2164c4ae.jpg)是( ) 形状的。", + "options": [ + "A. 长方体", + "B. 圆柱体", + "C. 球" + ], + "answer": "A", + "solution": "【分析】根据立体图形的特征进行识别即可.\n【详解】![](images/91a0de2d9a5ae33c22a7e4e609dfad67a6898f46103770388b4f324c44b34d09.jpg)是长方体形状的。故答案为: A", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "23-24 一年级上·河北保定·期末" + }, + { + "id": "202", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "下面摆得最稳的一组是()。", + "options": [ + "A. ![](images/3313999da3d2cc4597e69042d2180b1c86db2e4882744c490f666fe7f5856fd3.jpg)", + "B. ![](images/3ee9cf93a9140ba1b6c82798a3a56b639f487165ec727ca56687567fbddf3d93.jpg)", + "C. ![](images/8cd4a53666f4403acdccb0d1f72e97d78ab47c8345d569f434f32d67abefec13.jpg)" + ], + "answer": "B", + "solution": "【分析】长方体是长长方方的有平平的面;正方体是正正方方的有平平的面;圆柱上下是圆且上下一样粗;球没有平面可以任意方向滚动的。由此找出组合的图中是不易滚动的立体图形的即可.\n【详解】A。下边是球,可随意滚动,不稳定;B. 下边是长方体,不易滚动;上边是竖起来的圆柱,也不易滚动,稳定;C. 下边是正方体,不易滚动,上边是球可随意滚动,不稳定。摆得最稳的一组是![](images/fb9b78b3562c7472aa8764676ce47c04065bcd898c343c4095e837b60e1be06b.jpg)故答案为: B", + "knowledge_points": [ + "组合图形的稳定性" + ], + "source": "23-24一年级上·广西桂林·期末" + }, + { + "id": "203", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "下面第 ( ) 组图形能放稳。", + "options": [ + "A. ![](images/f72921bbd9e8c8025c3935b6922eaa6d1717efaa384c850f370905df9326fd33.jpg)", + "B. ![](images/21ac57ebe38bf9d49ae87f905cea77ce1468fc297ce3db60ddda3404d6353870.jpg)", + "C. ![](images/98d130ba0a68b6555dbbb17840475849acc83d606428b42bf6ee99d03078862f.jpg)" + ], + "answer": "C", + "solution": "【分析】长方体是长长方方的有平平的面;圆柱上下是圆且上下一样粗;球没有平面可以任意方向滚动.\n【详解】A。 下面是尖的,不能稳放;B. 下面是球,会滚动,不能稳放;C. 下面是长方体,长方体是平平的面,能稳放。能放稳的是![](images/b5bec5604bae3b1dcd4d0c09eff1b204de8dae7bb8af91ee3938839b0121c175.jpg)。故答案为: C", + "knowledge_points": [ + "组合图形的稳定性" + ], + "source": "23-24 一年级上·山东聊城·期末" + }, + { + "id": "204", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "两个同样大的正方体魔方能拼成一个 ( )。", + "options": [ + "A. 正方体", + "B. 长方体", + "C. 圆柱" + ], + "answer": "B", + "solution": "【分析】正方体是正正方方的有平平的面,两个正方体能拼成如图的图形,由此选择。![](images/59eda4c8fb574ce5a93b39e19507af172f7308eae4d38e31275d33ccdbb42e02.jpg)或![](images/73b52c64dad57ceaa39e9fe0fd728b661cd504720d858efc7bc6ef3b707b64fd.jpg)\n【详解】A。拼成的图形不是正正方方的,不是正方体;B. 长方体是长长方方的有平平的面,拼成的图形是长方体;C. 圆柱上下是圆且上下一样粗,拼成的图形不是圆柱。两个同样大的正方体魔方能拼成一个长方体。故答案为: B", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "23-24 一年级上·浙江台州·期末" + }, + { + "id": "205", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.65, + "question": "至少用 ( ) 个小正方体可以搭出一个大的正方体。", + "options": [ + "A. 4", + "B. 8", + "C. 9" + ], + "answer": "B", + "solution": "【分析】根据正方体 12 条棱都相等的特点,用小正方体搭一个稍大的正方体,这样搭:一层摆 4 个小正方体 (这一层摆 2 行,一行摆 2 个), 搭 2 层这样的即可.\n【详解】由题意分析得:4 + 4 = 8 (个)至少用 8 个小正方体可以搭出一个大的正方体。故答案为: B", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "20-21 一年级上·四川·单元测试" + }, + { + "id": "206", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "下面各组拼搭起来的图形中,无法站稳的是 ( )。", + "options": [ + "A. ![](images/f0587e8142cb5a3871b56a56533f66c4491f18cd873a01134eefd0583fa0ecbb.jpg)", + "B. ![](images/b1c0eaaf105035f9b5ff53ab9d0874577062820dc4bbb217ba7f74d354a2d99b.jpg)", + "C. ![](images/54fca95b3ef4f5c752b0f2d5913a86dd35ef8e705ccdbbd2dd60aa0389b0764d.jpg)" + ], + "answer": "C", + "solution": "【分析】长方体是长长方方的有平平的面,正方体是正正方方的有平平的面,圆柱上下是圆且上下一样粗,球没有平面可以任意方向滚动的。由此找出组合的图中下边易滚动的立体图形的即可.\n【详解】A。下边平放的是长方体,不易滚动,可以站稳;B. 下边平放的都是长方体,不易滚动,可以站稳;C. 下边放的是球,可随意滚动,不能站稳。各组拼搭起来的图形中,无法站稳的是![](images/19bb31abcb9e41a813890c2bcad71192d2b23331bd045613d44471923c5e8e77.jpg)故答案为: C", + "knowledge_points": [ + "组合图形的稳定性" + ], + "source": "22-23 一年级上·福建福州·期末" + }, + { + "id": "207", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "搭积木时,不能把 ( ) 形状的积木放在最下面。", + "options": [ + "A. 正方体", + "B. 圆柱", + "C. 球" + ], + "answer": "C", + "solution": "【分析】长方体是长长方方的有平平的面,不易滚动;正方体是正正方方的有平平的面,不易滚动;球没有平面可以任意方向滚动的。据此解决.\n【详解】由题意分析得:搭积木时,不能把球形状的积木放在最下面,球形状的积木放在最下面容易滚动。故答案为: C", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "23-24 一年级上·贵州铜仁·期末" + }, + { + "id": "208", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.65, + "question": "要将下图的图形拼成一个大正方体,至少还需要 ( ) 个小正方体。 ![](images/1d245f3bf0268e9e94cec40b7c80fff67a307ac0e88f3bc38546c563a921e9da.jpg)", + "options": [ + "A. 5", + "B. 7", + "C. 8" + ], + "answer": "C", + "solution": "【分析】正方体为正正方方的,有平平的面,6个面都相等。可知,如果要补全的话,则每个面最少都是3个小正方体.\n如图:上面需要补 6 个,侧面需要补 2 个,合起来要补 6 + 2 = 8(个)。![](images/b0f1aa7d46c1534fa65918f424c24ccfc92e78316dde472bc997123eb84058ec.jpg)\n【详解】由分析可知,要将下图的图形拼成一个大正方体,至少还需要 8 个小正方体。![](images/1d245f3bf0268e9e94cec40b7c80fff67a307ac0e88f3bc38546c563a921e9da.jpg)故答案为: C", + "knowledge_points": [ + "8,9 的加减法", + "立体图形的认识" + ], + "source": "23-24一年级上·湖北黄石·期末" + }, + { + "id": "209", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "下面能站稳的图形是 ( )。", + "options": [ + "A. ![](images/5eef037236d2e45e87ffc97b5a1d438924c1e528583e70b83c604153b0ecc39c.jpg)", + "B. ![](images/ccee65f378d5d648c68b4979114694c0255b073a18ce54faaba4935587141c58.jpg)", + "C. ![](images/acbe5f61ad8872eb44cda752eda7c523c11a371029bd529afce45bd36724d4ba.jpg)" + ], + "answer": "B", + "solution": "【分析】只有物体的接触面是平面时,才能保持平衡,才能站稳,由此分析.\n【详解】A。 下边图形与地面接触的部分只有一个尖,不能站稳;B. 下边图形是长长方方的,有平平的面,是长方体,可以站稳;C. 下边图形是球,球没有平面可以任意方向滚动,不能站稳。故答案为: B", + "knowledge_points": [ + "组合图形的稳定性" + ], + "source": "23-24 一年级上·山东滨州·期末" + }, + { + "id": "210", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "如图是由 ( ) 个小正方体拼成的。 ![](images/2ad0059406e4c8604799d00bb16aeec4018e66822fb8c69126faa953e84ae559.jpg)", + "options": [ + "A. 6", + "B. 5", + "C. 7" + ], + "answer": "A", + "solution": "【分析】根据图示,左列有 4 个小正方体,右列有 2 个小正方体,合起来一共有 6 个小正方体;据此解答即可.\n【详解】由题意分析得:![](images/2ad0059406e4c8604799d00bb16aeec4018e66822fb8c69126faa953e84ae559.jpg)是由 6 个小正方体拼成的。故答案为: A", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "23-24 一年级上·山东潍坊·期末" + }, + { + "id": "211", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "下面图形可以滚动的是 ( )。", + "options": [ + "A. ![](images/affc2bcc0dbabb356964bfbcbd8aaf10d52c5e9c63846b2ab687873c51943968.jpg)", + "B. ![](images/14867e69a8c465ce34e35f6aea34c4ac5b1a9b22559ed02f415cfe2b444bb1f3.jpg)", + "C. ![](images/dc2cbee87274b50192555fff434f7090d6f552ec3299027b3db6b7f695757968.jpg)" + ], + "answer": "C", + "solution": "【分析】圆柱:由上下两个大小相同的圆形和一个曲面构成,可以立着,也可以滚动;长方体:由6个长方形围成(特殊的由2个正方形和4个长方形围成),不能滚动;正方体:由6个完全相同的正方形围成,不能滚动。据此解答即可.\n【详解】由分析可知:![](images/0c7c46c462c825f90e293581a6d7a38e7bc46ac069afdc7cb4ce31e7d1d647cb.jpg)是可以滚动的。故答案为: C", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "23-24 一年级上·山东潍坊·期末" + }, + { + "id": "212", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.65, + "question": "观察同一个立体图形,奇思看到的形状是圆形,妙想看到的形状是长方体。这个立体图形是 ( )。", + "options": [ + "A. 球", + "B. 圆柱", + "C. 长方体" + ], + "answer": "B", + "solution": "【分析】球是曲面图形,长方体的面是长方形或正方形,圆柱从上面看是圆形,从前面和侧面看是长方形.\n【详解】由以上分析可知:观察同一个立体图形,奇思看到的形状是圆形,妙想看到的形状是长方形,这个立体图形是圆柱。故答案为: B", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "23-24 三年级上·陕西宝鸡·期末" + }, + { + "id": "213", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "既能立起来又能滚动的立体图形是()。", + "options": [ + "A. 长方体", + "B. 正方体", + "C. 圆柱", + "D. 球" + ], + "answer": "C", + "solution": "【分析】只含有平平的面的立体图形不能滚动但可以立起来;只含有曲面的立体图形可以滚动但不能立起来。既含有平平的面又含有曲面的立体图形,既能立起来又能滚动。根据立体图形的特征来解决此题即可.\n【详解】由题意分析得:\nA。 长方体是长长方方的只有平平的面,不能滚动但可以立起来;B. 正方体是正正方方的只有平平的面,不能滚动但可以立起来;C. 圆柱上下是平平的面,侧面是曲面,既能立起来又能滚动;D. 球没有平面只有一个曲面,可以滚动但不能立起来;即,既能立起来又能滚动的立体图形是圆柱。故答案为: C", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "23-24一年级上·福建龙岩·期末" + }, + { + "id": "214", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "既能滚动又能平放,上下一样粗的是 ( )。", + "options": [ + "A. ![](images/5788479ce46f26913245e52c1bc41dc5bdf878f92bd3ba81621ac014a85ba418.jpg)", + "B. ![](images/0336b8b0a7b3c0001233c2b341a16afca86727c27fa333925a874117e6146386.jpg)", + "C. ![](images/274bef95c003976dd7c97bd5e89f3cfb9bb30b9bab9a22c449f1524423b57123.jpg)" + ], + "answer": "B", + "solution": "【分析】长方体是长长方方的有平平的面,不能滚动但能放平,上下一样粗;圆柱上下是平平的面,侧面是曲面,既能滚动又能平放,且上下一样粗;球是由曲面围成,不能放平,但可以任意方向滚动,且上下不一样粗;根据立体图形的特征来解决此题.\n【详解】A。![](images/5788479ce46f26913245e52c1bc41dc5bdf878f92bd3ba81621ac014a85ba418.jpg) , 这是长方体,能放平但不能滚动,上下一样粗,不符合题意;B。![](images/0336b8b0a7b3c0001233c2b341a16afca86727c27fa333925a874117e6146386.jpg), 这是圆柱,既能滚动又能平放,上下一样粗,符合题意;C。![](images/274bef95c003976dd7c97bd5e89f3cfb9bb30b9bab9a22c449f1524423b57123.jpg) , 这是球,但不能放平,可以任意方向滚动,且上下不一样粗,不符合题意;故,既能滚动又能平放,上下一样粗的是![](images/0336b8b0a7b3c0001233c2b341a16afca86727c27fa333925a874117e6146386.jpg) 故答案为: B", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "23-24一年级上·四川广元·期末" + }, + { + "id": "215", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.65, + "question": "下图中有 ( ) 个小正方体。 ![](images/cc35b9c6479a73b68b24b32ef9956bc7f05b59ca44d6e999dd1a26fb14b6aa64.jpg)", + "options": [ + "A. 3", + "B. 5", + "C. 4" + ], + "answer": "B", + "solution": "【分析】按照顺序,数清楚每层小正方体的数量,即可得出答案。注意上层的小正方体的下层肯定对应着一个小正方体.\n【详解】从图上可得:第一层有 4 个小正方体,第二层有 1 个小正方体,合起来一共有 5 个小正方体。故答案为: B", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "23-24 一年级上·四川广元·期末" + }, + { + "id": "216", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "用两块正方体可以拼成一个什么图形。 ( )", + "options": [ + "A. 长方体", + "B. 正方体", + "C. 圆柱" + ], + "answer": "A", + "solution": "【分析】正方体:有 6 个面,每个面都由正方形组成;长方体:有 6 个面,每个面都由长方形或相对的一组正方形组成;圆柱:上下两个面为大小相同的圆形,有一个曲面叫侧面,据此解答即可.\n【详解】根据分析可知:用两块正方体可以拼成一个长方体。故答案为: A", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "23-24 一年级上·湖北荆州·期末" + }, + { + "id": "217", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "![](images/7f9ec685ff05326307c6012dbf40b4b989970289f1025ddd8a626a88740c3a06.jpg) 可以和()拼成![](images/2514aa46d5891fb38d37c00403be4d19a9621e363974fb3cd525e47b73bda517.jpg)", + "options": [ + + ], + "answer": "B", + "solution": "【分析】在![](images/7f9ec685ff05326307c6012dbf40b4b989970289f1025ddd8a626a88740c3a06.jpg)的上面再摆 1 个小正方体,并与已有 3 个拼成 2×2 的一层,再摆第二层,就能拼成由 8 个小正方体组成的大正方体。据此选择.\n【详解】由题意分析得:应选 B 图。故答案为: B", + "knowledge_points": [ + "立体图形的切拼" + ], + "source": "23-24一年级上·福建福州·期末" + }, + { + "id": "218", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "![](images/ae7d7873a6c82620cefc26964b5117d978d64510cd273864200d0dbe94b1f8cf.jpg)要拼成一个大正方体,左边的图形至少还需要()个正方体。", + "options": [ + "A. 3", + "B. 6", + "C. 9" + ], + "answer": "A", + "solution": "【分析】根据题意可知:要拼成一个大正方体,每层都要铺满,也就是上下3层小正方体数量要相等,先分别数数这3层各有多少个,第一层有9个小正方体,第二层9个,第三层6个,求至少还需要几个。用第一层有的数量减去第三层有的数量即可.\n【详解】 9-6= 3(个) 所以左边的图形至少还需要 (3) 个正方体故答案为: A", + "knowledge_points": [ + "8,9 的加减法", + "立体图形的认识" + ], + "source": "23-24一年级上·湖北随州·期末" + }, + { + "id": "219", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "小丽闭着眼睛摸同一个物体,第一次摸到一个平的面,第二次摸到一个弯的面,这个物体可能是 ( )。", + "options": [ + "A. ![](images/68f4d9201292a2c850eb81880d95b58bf877710d3b4d074967a1f48418f50f93.jpg)", + "B. ![](images/40423539abefa030d19a880f102a33d6e9093c1ef3637680b58fd54635a1c269.jpg)", + "C. ![](images/d272ccec2d43874ec3a3516bf3efdc8313380d15fabc30e051e0b1e79dd3a0d4.jpg)" + ], + "answer": "C", + "solution": "【分析】正方体:有 6 个面,每个面都由正方形组成;圆柱:上下两个面为大小相同的圆形,有一个曲面叫侧面;球:球是生活中最常见的图形之一,例如篮球,足球都是球,球是由一个面所围成的几何体。据此进行解答即可.\n【详解】A。正方体6个面都是平面,不符合题意;B. 球都是曲面,没有平面,不符合题意;C. 圆柱有 2 个平面,一个曲面,所以符合小丽摸到的物体的状态。故答案为: C.", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "23-24 一年级上·山西晋中·期末" + }, + { + "id": "220", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "用下面的积木拼搭汽车时,用()做轮子合适。", + "options": [ + "A. ![](images/5514c5a4a5635fda021328471cb12135b9584b220808a769bafe5a6f7db4b83d.jpg)", + "B. ![](images/c70d45d582eaee83fa1418c2ebaf080321e5d15e440083bbe2c373329b22b49b.jpg)", + "C. ![](images/325b55608734b2bd6c4eae5b45e2b71d337da885b26eda29c855aa0586697f08.jpg)" + ], + "answer": "A", + "solution": "【分析】长方体是长长方方的有平平的面,不易滚动;正方体是正正方方的有平平的面,不易滚动;圆柱上下是圆且上下一样粗,且有一个曲面,曲面在下,易滚动;据此解决.\n【详解】由题意分析得:用![](images/27f1b7393e2fc1401c19cc7a09ce869ca8707562faf8a7fecfa66361c3e5e631.jpg)做轮子合适。故答案为: A", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "23-24一年级上·湖南长沙·期末" + }, + { + "id": "221", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "如图,图形中有 ( ) 个正方体。", + "options": [ + "A. 7", + "B. 6", + "C. 5" + ], + "answer": "B", + "solution": "【分析】从图上可得:第一行有 5 个正方体,第二行有 1 个正方体,合起来一共有 6 个正方体,据此解答即可.\n【详解】根据分析可知:5 + 1 = 6 (个) 图形中有 6 个正方体。故答案为: B", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "23-24一年级上·广东深圳·期末" + }, + { + "id": "222", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "容易滚动的物体是 ( )。", + "options": [ + "A. ![](images/6e8bc4ae5da4c908f9852f5ab2ca025739a54e8bdf39c5692a737fcc9f9a7534.jpg)", + "B. ![](images/0fb1bc5c50684cea0adff29cd20fc8a92c8acc445cdad68e6bacbdb5f697548d.jpg)", + "C. ![](images/648b551b7e610dc992e9fa570d7b0bd896ff20e65d43f9cc729399cc16b59098.jpg)" + ], + "answer": "B", + "solution": "【分析】长方体是长长方方的有平平的面,不易滚动;正方体是正正方方的有平平的面,不易滚动;球没有平面可以任意方向滚动的。由此解答.\n【详解】A。![](images/6e8bc4ae5da4c908f9852f5ab2ca025739a54e8bdf39c5692a737fcc9f9a7534.jpg)是长方体,不易滚动;B. ![](images/0fb1bc5c50684cea0adff29cd20fc8a92c8acc445cdad68e6bacbdb5f697548d.jpg)是球,易滚动;C。![](images/648b551b7e610dc992e9fa570d7b0bd896ff20e65d43f9cc729399cc16b59098.jpg) 是正方体,不易滚动。容易滚动的物体是球。故答案为: B", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "22-23一年级上·新疆克孜勒苏·期末" + }, + { + "id": "223", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "下面立体图形中,最容易滚动的是 ( )。", + "options": [ + "A. 正方体", + "B. 圆柱", + "C. 球" + ], + "answer": "C", + "solution": "【分析】正方体:有 6 个面,每个面都是方方正正的;圆柱:上下两个面为大小相同的圆形,有一个曲面叫侧面;球:球是生活中最常见的图形之一,例如篮球,足球都是球,球是由一个面所围成的立体图形。据此解答.\n【详解】由分析可知:立体图形中,最容易滚动的是球;故答案为: C", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "22-23 一年级上·甘肃天水·期末" + }, + { + "id": "224", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "下面的物体是球的是 ( )。", + "options": [ + "A. ![](images/4baea8d55d871d6e0795f296ae79f1b622fa6ca73f6b508c82369e3788ad3747.jpg)", + "B. ![](images/f4b0ec97d7bb863e55c57cdd0599dedd9981442283b62d0972f73b8362ed2f18.jpg)", + "C. ![](images/0c5c18fe670d69dbf7836170edc9e55fa2da305dfbef2502efe5636d3d761812.jpg)" + ], + "answer": "A", + "solution": "【分析】长方体是长长方方的有平平的面;正方体是正正方方的有平平的面;圆柱上下是圆且上下一样粗;球没有平面可以任意方向滚动的;据此解决.\n【详解】A。![](images/51d0e5a3b41b1e867f340cfdff1b4ef4e4345ccac399718c8f0ad4626e427b20.jpg), 这是球;B。![](images/f56b30eded61955a6ac02b272417c1814c1ae6cbfba8732eda6eaf9c8a452c1c.jpg), 这是正方体;C。![](images/04b80048355cd33129abd6fbd47fb019dfc0badf64f9388185306ebeec6ae2a1.jpg),这是长方体。故答案为: A", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "22-23一年级上·浙江金华·期末" + }, + { + "id": "225", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "下面是正方体的是 ( )。", + "options": [ + "A. ![](images/23712fdd231ebcbb92ee806faeb266e7878b82575042a5b017ffcb9c67f3f91d.jpg)", + "B. ![](images/5438d0bd40d90b4ab36bc50c7bb87c25b11e318d59d5ff865d25981475619cb1.jpg)", + "C. ![](images/6a8f316268f410b476afca3bb2f7dab7f561d8dade614407b337638f226bdd7e.jpg)" + ], + "answer": "B", + "solution": "【分析】依次分析各选项的图形,根据正正方方的有平平的面,找到正方体即可.\n【详解】A。长长方方的有平平的面,是长方体;B. 正正方方的有平平的面,是正方体;C. 上下是圆且上下一样粗,是圆柱。题中是正方体的是 B。故答案为: B", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "21-22 一年级上·广西钦州·期末" + }, + { + "id": "226", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.65, + "question": "先摆一个长方体,在长方体的上面分别摆一个正方体,圆柱和球,圆柱在球的左边,正方体在球的右边。()", + "options": [ + "A. ![](images/5957acae9591d9414dd86dd60ba6369f22e9057f5355c46eb7c45ddf5efcfa3d.jpg)", + "B. ![](images/49c6622c0d40678fa3b4735c8ef6c5bec57f6ea829f2897f780c82780af83297.jpg)", + "C. ![](images/f9b7cbf67171720f8d22ce75aba073b02c50c537654f5231d9f3bad417aa46bb.jpg)" + ], + "answer": "A", + "solution": "【分析】长方体:长长方方的,有 6 个长方形的面,特殊情况下有 2 个对面是正方形;正方体:方方正正的, 6 个面是同样大小的正方形;圆柱:上下两个面是同样大小的圆,侧面是曲面;球,表面是曲面,易滚动。由题意可知,长方体在最下边。左手的方向是左边,右手的方向是右边。球在中间,左边是圆柱,右边是正方体。由此解答.\n【详解】由分析可知,摆出的组合图形是 A。故答案为:A", + "knowledge_points": [ + "左,右位置", + "立体图形的认识" + ], + "source": "23-24 一年级上·河南洛阳·期中" + }, + { + "id": "227", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "长方体在圆柱的下面,摆法正确的是 ( )。", + "options": [ + "A. ![](images/c8ee5895b5c9c091f97312ba4d47b677c966f994d8e7f94aaad5313aa81cf7af.jpg)", + "B. ![](images/5c9df7baf39276378d76f6d4c98facc3a934b5cdf29e62dcecaa06212cd15020.jpg)", + "C. ![](images/fc5dcdcbe6db3afc2ee2777a7d4c158ed137a487854ff60de2ff10b9e633d893.jpg)" + ], + "answer": "B", + "solution": "【分析】长方体:由 6 个平平的面围成,且相对的面是完全一样。圆柱:由 2 个平平的面和 1 个曲面围成。球:由 1 个曲面围成.\n【详解】A。![](images/9b2241299fd4ff078f766d925f49f1474a6a90cf1d858a5f5502837898a89ea2.jpg)圆柱在长方体的下面,不符合题意;B。![](images/1470512b42c8e194ef012a96a4046879fb2fa35e2daea06977e4c1b6d38c0ae2.jpg),长方体在圆柱的下面,符合题意;C。![](images/05e15dbe4dedd4b9b0b4b68f473617ea24e0d6609300e656e26530fbe062c233.jpg),长方体在球的下面,不符合题意。故答案为: B", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "23-24 一年级上·山东菏泽·期中" + }, + { + "id": "228", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "![](images/9b55103ff844f2bb12774c3c24160e28ae8a46dc19fb18b4aacafe30ef017e8b.jpg)这个图形至少还要用()个,才能拼成一个大正方体。", + "options": [ + "A. 1", + "B. 2", + "C. 3" + ], + "answer": "B", + "solution": "【分析】由题意可知,用 8 个小正方体能拼成一个大正方体,图中的图形用了 6 个小正方体,还差 2 个小正方体就能拼成一个大正方体了,据此解答即可.\n【详解】这个图形至少还要用(2)个,才能拼成一个大正方体。故答案为:B", + "knowledge_points": [ + "立体图形的认识", + "立体图形的切拼" + ], + "source": "23-24一年级上·河南南阳·期中" + }, + { + "id": "229", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.65, + "question": "至少要再放( )个小正方体才能拼成一个大正方体。 ![](images/d9aa088692d40b488402c3625d9bfadeb230610f94a1ab100989c2cd39c81fd0.jpg)", + "options": [ + "A. 3", + "B. 4", + "C. 5", + "D. 6" + ], + "answer": "B", + "solution": "【分析】至少要 8 个小正方体才能拼成一个大正方体,![](images/d9aa088692d40b488402c3625d9bfadeb230610f94a1ab100989c2cd39c81fd0.jpg)有 4 个小正方体,用 8 减 4 即可求解.\n【详解】 8 - 4 = 4 (个),所以至少要再放 4 个小正方体才能拼成一个大正方体。故答案为: B", + "knowledge_points": [ + "8,9 的加减法", + "立体图形的认识" + ], + "source": "23-24一年级上·湖北省直辖县级单位·期中" + }, + { + "id": "230", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "我们的数学课本的形状是 ( )。", + "options": [ + "A. 长方形", + "B. 正方体", + "C. 长方体" + ], + "answer": "C", + "solution": "【分析】课本有 6 个面,对面相等,是立体图形。根据对立体图形的认识可知,长方体是长长方方的,有 6 个面,对面相等。由此选择.\n【详解】由分析可知,我们的数学课本的形状是长方体。故答案为: C", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "23-24 一年级上·甘肃陇南·期中" + }, + { + "id": "231", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "篮球和足球都是 ( )。", + "options": [ + "A. 正方体", + "B. 圆柱", + "C. 球体" + ], + "answer": "C", + "solution": "【分析】可以通过观察,手摸可以知道,圆柱能像柱子一样立着,还能滚动,是直直的,上下一样粗细,两头都是圆圆的平平的面.\n正方体:正正的方方的,有 6 个平平的面都相等。球是圆圆的容易滚动。据此解答\n【详解】篮球和足球都是球。故答案为: C", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "23-24 一年级上·甘肃陇南·期中" + }, + { + "id": "232", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.65, + "question": "下面的物体中,可以立起来,还可以滚动的是 ( )。", + "options": [ + "A. ![](images/893ddab7f373e0fde8f62d1ad6c37a3ef16fa5bbd3d513c2d8c8d3a732e98a6c.jpg)", + "B. ![](images/832210736e42e555f4507235b11ef3b5d38949720ef589fab7e2ac784240099a.jpg)", + "C. ![](images/0fa66d7d94848503d72b62d0ce56bbb9db759dc1d403538acfa5d71d486d2fd3.jpg)" + ], + "answer": "B", + "solution": "【分析】圆柱:由 1 个曲面和 2 个平平的面围成。正方体的六个面都是相同的正方形。球:由 1 个曲面围成.\n【详解】A。正方体可以立起来不可以滚动;B. 圆柱可以立起来还可以滚动;C. 球不可以立起来可以滚动。 可以立起来,还可以滚动的是![](images/832210736e42e555f4507235b11ef3b5d38949720ef589fab7e2ac784240099a.jpg),故答案为: B", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "23-24 一年级上·辽宁鞍山·期中" + }, + { + "id": "233", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.65, + "question": "下列搭成的图形中, ( ) 搭的最稳。", + "options": [ + "A. ![](images/c25fc286e29e91b79a9cabf10e78f18a724f766b963842e2162c7554e58db792.jpg)", + "B. ![](images/4840f55b32d22552b6557b68507be7cf4645245746239049a15518f95b389c09.jpg)", + "C. ![](images/5aad02107578d6d270a6967346f734d565d6fc31cf84a179a931217318c3829f.jpg)" + ], + "answer": "C", + "solution": "【分析】圆柱:由 1 个曲面和 2 个平面围成;球:由 1 个曲面围成;长方体:由六个长方形(特殊情况有两个相对的面是正方形)围成;正方体:由六个相同的正方形围成,根据各图形的特征找出正确的选项.\n【详解】A。正方体上面是球,球会滚动,不够稳;B. 长方体下面是圆柱,圆柱的侧面着地,会滚动,不够稳;C. 下面是长方体,上面是圆柱,圆柱的底面挨着长方体,此图形最稳。搭成的图形中,![](images/c8293dae4e1f68fc8321e5a1505af8f5a60b0839c72c5a4ca1fccadf4ca0589a.jpg)搭的最稳。故答案为: C", + "knowledge_points": [ + "组合图形的稳定性", + "立体图形的切拼" + ], + "source": "23-24 一年级上·辽宁鞍山·期中" + }, + { + "id": "234", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "下面组合图中,能放稳的是 ( )。 ![](images/67eedef6c407594bedee1573c3f9dfe4.png)", + "options": [ + "A", + "B", + "C" + ], + "answer": "A", + "solution": "【分析】长方体是长长方方的,不易滚动;正方体是四四方方的,不易滚动;圆柱的侧面是曲面,平放易滚动;球是圆圆的,可随意滚动。据此解答即可.\n【详解】A。这个图形下边是长方体,不易滚动,能放稳;B。这个图形下边是球,易滚动,不能放稳;C. 这个图形下边是圆柱,易滚动,不能放稳。组合图中,能放稳的是 A。故答案为: A", + "knowledge_points": [ + "组合图形的稳定性" + ], + "source": "22-23 一年级上·福建福州·期中" + }, + { + "id": "235", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "圆柱的上,下两个面 ( )。", + "options": [ + "A. 一样大", + "B. 不一样大" + ], + "answer": "A", + "solution": "【分析】圆柱:上下两个面为大小相同的圆形,有一个曲面叫侧面,据此解答.\n【详解】圆柱的上,下两个面都是大小相同的圆形。故答案为: A", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "22-23一年级上·贵州黔西·期中" + }, + { + "id": "236", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "如图中一共有( )个正方体。 ![](images/cc35b9c6479a73b68b24b32ef9956bc7f05b59ca44d6e999dd1a26fb14b6aa64.jpg)", + "options": [ + "A. 5", + "B. 4", + "C. 6" + ], + "answer": "A", + "solution": "【分析】由题意可知,从这个图形的下面开始数,第一层有 4 个正方体,第二层有 1 个正方体,合起来一共有 5 个正方体,列式为 4 + 1 = 5 (个), 据此解答即可.\n【详解】 4 + 1 = 5 (个)![](images/cc35b9c6479a73b68b24b32ef9956bc7f05b59ca44d6e999dd1a26fb14b6aa64.jpg)如图一共有 5 个正方体。故答案为: A", + "knowledge_points": [ + "正方体的特征", + "5以内数的加法", + "数一数" + ], + "source": "20-21 一年级上·湖南衡阳·期中" + }, + { + "id": "237", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "能放稳的是 ( )。 ![](images/ea69082b75a36724252f75af116079c8.png)", + "options": [ + "A", + "B", + "C", + "D" + ], + "answer": "D", + "solution": "【分析】要想放稳,下边应该放平平的面的物体,由此选择即可.\n【详解】A。图形中尖尖的角在下边,不能放稳;B. 下边是球,球能随意滚动,不能放稳;C. 下边是圆柱,曲面易滚动,不能放稳;D. 下边是长方体,有宽宽的,平平的面,不易滚动,能放稳。所以能放稳的是 D。故答案为: D", + "knowledge_points": [ + "组合图形的稳定性" + ], + "source": "23-24一年级上·福建龙岩·期中" + }, + { + "id": "238", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "![](images/d826fc91b6ee7f25c7f57aeb52946323e2691b0971ef56afa0b111b29470d38b.jpg) ( )个正方体,( )个长方体,( )个圆柱,( )个球。", + "options": [ + + ], + "answer": "3;2;3;4", + "solution": "【分析】长方体是长长方方的有平平的面;正方体是正正方方的有平平的面;圆柱上下是圆且上下一样粗;球没有平面可以任意方向滚动的。由此找出各图形的数量填空即可.\n【详解】![](images/4cd1f21ed294a91a95e94bebb3fb705b0ce25c9bc8a507bf3969a643e104c0cf.jpg)\n3个正方体,2个长方体,3个圆柱,4个球。", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "23-24一年级上·吉林白城·期末" + }, + { + "id": "239", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.65, + "question": "正方体有( )个;长方体有( )个;圆柱有( )个;球有( )个;正方体比圆柱少( )个;长方体比球多( )个。 ![](images/317fd9dacb5418406520a4c77ded6e30b4a823fbb53eb670adbbe0a4080db77f.jpg)", + "options": [ + + ], + "answer": "3;4;5;3;2;1", + "solution": "【分析】根据正方体,球,长方体,圆柱的特征进行分类识别,再数出相应的数量即可,再根据题意加减即可.\n【详解】根据图中所示, 5 - 3 = 2 , 4 - 3 = 1 正方体有(3)个;长方体有(4)个;圆柱有(5)个;球有(3)个;正方体比圆柱少(2)个;长方体比球多(1)个.", + "knowledge_points": [ + "立体图形的认识", + "5以内数的减法" + ], + "source": "23-24 一年级上·河北保定·期末" + }, + { + "id": "240", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "![](images/85d88e5109b6e2b174e9551af0c5729dee8b36ff61ff1703447c85bf10861035.jpg) \u003ctable\u003e\u003ctr\u003e\u003ctd\u003e圆柱\u003c/td\u003e\u003ctd\u003e长方体\u003c/td\u003e\u003ctd\u003e正方体\u003c/td\u003e\u003ctd\u003e球\u003c/td\u003e\u003c/tr\u003e\u003ctr\u003e\u003ctd\u003e()个\u003c/td\u003e\u003ctd\u003e()个\u003c/td\u003e\u003ctd\u003e()个\u003c/td\u003e\u003ctd\u003e()个\u003c/td\u003e\u003c/tr\u003e\u003c/table\u003e", + "options": [ + + ], + "answer": "4;5;5;2", + "solution": "【分析】圆柱的特征是直直的,上下有两个相同的圆。长方体的特征是有6个面,对着的两个面相同。正方体的特征是有6个面,每个面都相同。球的特征是由曲面组成的,是圆圆的.\n【详解】根据图上所示,故填空如下: \u003ctable\u003e\u003ctr\u003e\u003ctd\u003e圆柱\u003c/td\u003e\u003ctd\u003e长方体\u003c/td\u003e\u003ctd\u003e正方体\u003c/td\u003e\u003ctd\u003e球\u003c/td\u003e\u003c/tr\u003e\u003ctr\u003e\u003ctd\u003e4个\u003c/td\u003e\u003ctd\u003e5个\u003c/td\u003e\u003ctd\u003e5个\u003c/td\u003e\u003ctd\u003e2个\u003c/td\u003e\u003c/tr\u003e\u003c/table\u003e", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "23-24一年级上·福建厦门·期末" + }, + { + "id": "241", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "填一填。 ![](images/a4d92770fd6b1f76cb53d89bb126486e2a3aa55eaadb91a37396fbe33036e512.jpg) 长方体有( )个,正方体有( )个,圆柱有( )个,球有( )个。", + "options": [ + + ], + "answer": "5;4;4;2", + "solution": "【分析】长方体是长长方方的有平平的面;正方体是正正方方的有平平的面;圆柱上下是圆且上下一样粗;球没有平面可以任意方向滚动,由此数出各图形的数量填空即可.\n【详解】由分析得: ![](images/81138741b16c2b4b18d62ff7766ad8b3117416480918ab835fa0b816898456e4.jpg) 长方体有5个,正方体有4个,圆柱有4个,球有2个。", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "23-24 一年级上·河南漯河·期末" + }, + { + "id": "242", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "长方体有( )个,正方体有( )个,圆柱有( )个,球有( )个。 ![](images/ffa6e40f92274221469b55ee6d982bcc03ccece581b91572b16179d931805465.jpg)", + "options": [ + + ], + "answer": "3;2;2;3", + "solution": "【分析】长方体:有 6 个面,每个面都由长方形或相对的一组正方形组成;正方体:有 6 个面,每个面都由正方形组成;圆柱:上下两个面为大小相同的圆形,有一个曲面叫侧面;球:球是生活中最常见的图形之一,例如篮球,足球都是球,球是由一个面所围成的几何体。据此数出.\n【详解】由分析可知:长方体有 3 个,正方体有 2 个,圆柱有 2 个,球有 3 个.\n![](images/bc349f59aff2fce8e03bca7755aa05a9aee19451c2fec363d04fac27eee76fe2.jpg)", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "23-24 一年级上·山东潍坊·期末" + }, + { + "id": "243", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "数一数。 ![](images/775d1b338f673c6f6b09d54af9baed224c4d7cbbb2d27b3ec41064ef66e639b0.jpg) 长方体有( )个,正方体有( )个,圆柱有( )个,球有( )个。", + "options": [ + + ], + "answer": "3;3;4;1", + "solution": "【分析】长方体是长长方方的有平平的面;正方体是正正方方的有平平的面;圆柱上下是圆且上下一样粗;球没有平面可以任意方向滚动。由此数出各图形的数量填空即可.\n【详解】由分析得:![](images/176a88da308e9d3a90381de57a6df8eaa652f3e66911a4bd3f6202516144c8b8.jpg)长方体有 3 个,正方体有 3 个,圆柱有 4 个,球有 1 个。", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "23-24一年级上·山东潍坊·期末" + }, + { + "id": "244", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "数一数,再填空。 ![](images/84de374c605ec79c336d2fe14c844ef480933a94054589201269972b8f95451c.jpg) 长方体有( )个,正方体有( )个,圆柱有( )个,球有( )个。", + "options": [ + + ], + "answer": "3;2;2;1", + "solution": "【分析】长方体是长长方方的有平平的面;正方体是正正方方的有平平的面;圆柱上下是圆且上下一样粗;球没有平面可以任意方向滚动。据此数一数.\n【详解】长方体有3个,正方体有2个,圆柱有2个,球有1个。", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "23-24 一年级上·广东广州·期末" + }, + { + "id": "245", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "我会数.\n![](images/2e664847044fdda842661900426d3ff1fd8a0cb73b17bc52229016c0078f1687.jpg) 长方体有()个;正方体有()个;圆柱有()个;球有()个。", + "options": [ + + ], + "answer": "5;2;4;3", + "solution": "【分析】长方体是长长方方的有平平的面;正方体是正正方方的有平平的面;圆柱上下是圆且上下一样粗;球没有平面可以任意方向滚动.\n【详解】长方体有5个;正方体有2个;圆柱有4个;球有3个。", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "23-24 一年级上·江苏盐城·期末" + }, + { + "id": "246", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "数一数,填一填。 ![](images/e76e95b6a2057f09b6a554ef4bcb539a3122e151ef803489218133d7abc37810.jpg) 长方体有( )个;正方体有( )个;圆柱有( )个;球有( )个;长方体比正方体多( )个。", + "options": [ + + ], + "answer": "5;2;3;6;3", + "solution": "【分析】长方体是长长方方的有平平的面;正方体是正正方方的有平平的面;圆柱上下是圆且上下一样粗;球没有平面可以任意方向滚动的;根据立体图形的特征,先数一数,再填空即可。求一个数比另一个数多多少,用减法列式计算.\n【详解】由题意分析得:5-2=3(个) ![](images/78ed011f783965e513b15b11f8e9a30cd12dfb6914f65cbd1b5b72d01e6ece75.jpg)", + "knowledge_points": [ + "立体图形的认识", + "5以内数的减法" + ], + "source": "23-24 一年级上·河南南阳·期末" + }, + { + "id": "247", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "数一数。 ![](images/19de0ce1e1123cf53e7b8e2ca98351e3eab6117a336307a976959121cf89373d.jpg)", + "options": [ + + ], + "answer": "4;4;3;4", + "solution": "【分析】长方体是长长方方的有平平的面;正方体是正正方方的有平平的面;圆柱上下是圆且上下一样粗;球没有平面可以任意方向滚动。![](images/854e7f7850ab7804f5f3a91dad164f6573ad09bbd5bad6856cd6d4e482e9453c.jpg)\n【详解】(由图数得)长方体 4 个,正方体 4 个,圆柱 3 个,球 4 个。", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "23-24一年级上·湖南株洲·期末" + }, + { + "id": "248", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "数一数。 ![](images/2b6ff6cbc8e1397fa64268730d6c20e6be78748ea222eeb8c2120def369992c8.jpg) 长方体( )个,正方体( )个,圆柱( )个,球( )个。", + "options": [ + + ], + "answer": "4;2;5;6", + "solution": "【分析】长方体是长长方方的有平平的面;正方体是正正方方的有平平的面;圆柱上下是圆且上下一样粗;球没有平面可以任意方向滚动的;根据立体图形的特征,先数一数,再填空即可.\n【详解】由题意分析得:长方体4个,正方体2个,圆柱5个,球6个。", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "23-24 一年级上·河南南阳·期末" + }, + { + "id": "249", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "填空。 ![](images/9e37d07b3679e6407db5b58f3fe26fdb4fd031f40146a7de65c5f85ed9626d8b.jpg) 长方体( )个;正方体 ( )个;圆柱( )个;球( )个。", + "options": [ + + ], + "answer": "5;2;6;3", + "solution": "【分析】长方体是长长方方的有平平的面;正方体是正正方方的有平平的面;圆柱上下是圆且上下一样粗;球没有平面可以任意方向滚动。由此数出各图形的数量填写即可.\n【详解】由分析填写如下:![](images/824ef274395ecb7a399ace0a8a3224384ac0a488a2d01008bd2dd930366e565b.jpg)长方体5个;正方体2个;圆柱6个;球3个。", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "23-24 一年级上·江西赣州·期末" + }, + { + "id": "250", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "![](images/28f11bebe7d0eb44e5f6e9a085de145c43efbd7c41f832e6147b0d075ee29c5d.jpg) 长方体有( )个;正方体有( )个;圆柱有( )个;球有( )个。", + "options": [ + + ], + "answer": "5;4;4;2", + "solution": "【分析】长方体是长长方方的有平平的面;正方体是正正方方的有平平的面;圆柱上下是圆且上下一样粗;球没有平面可以任意方向滚动。由此数出各图形的数量填空即可.\n【详解】由分析得: ![](images/244c578f1e93ce66cab3c5a88a71660a87f547329643ddefeb88ed1f1b946698.jpg) 长方体有5个;正方体有4个;圆柱有4个;球有2个。", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "23-24一年级上·河南漯河·期末" + }, + { + "id": "251", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "数一数,填一填。 ![](images/f17355fb96b62a794236bbfeea87723db5e6625c6ae455884cda54ab1f82abd9.jpg) (1) 长方体有( )个。 (2)圆柱比球多( )个。", + "options": [ + + ], + "answer": "4;1", + "solution": "【分析】(1)根据长方体是长长方方的有平平的面,正方体是正正方方的有平平的面,圆柱上下是圆且上下一样粗,球没有平面可以任意方向滚动的特征进行分类识别,再数出相应的数量即可。(2) 先分别数出圆柱和球的个数,然后用减法计算多的个数即可.\n【详解】 (1)长方体有 4 个。 (2)圆柱有3个,球有 2个。3-2=1(个),所以圆柱比球多1个。", + "knowledge_points": [ + "立体图形的认识", + "5以内数的减法" + ], + "source": "23-24一年级上·四川成都·期末" + }, + { + "id": "252", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.65, + "question": "我会数。 ![](images/e7ab177c6599c368073f944ea26bdd781351fee6409bd9260255644d4bca5535.jpg) 长方体有( )个,正方体有( )个,球有( )个,圆柱有( )个。", + "options": [ + + ], + "answer": "5;3;4;6", + "solution": "【分析】长方体是长长方方的,有平平的面;正方体是正正方方的,有 6 个相同的面;圆柱上下是圆圆的面,且上下一样粗;球是圆圆的,可以任意滚动。据此判断图形并数出数量即可.\n【详解】根据分析知:长方体有 5 个,正方体有 3 个,球有 4 个,圆柱有 6 个。", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "23-24 一年级上·福建龙岩·期末" + }, + { + "id": "253", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "认真数,仔细填。 ![](images/4d7f68974b3ad9a97445f82ee131a9600ca37e20dddd78b47e3701294702be2e.jpg) \u003ctable\u003e\u003ctr\u003e\u003ctd\u003e长方体\u003c/td\u003e\u003ctd\u003e正方体\u003c/td\u003e\u003ctd\u003e球\u003c/td\u003e\u003ctd\u003e圆柱\u003c/td\u003e\u003c/tr\u003e\u003ctr\u003e\u003ctd\u003e()个\u003c/td\u003e\u003ctd\u003e()个\u003c/td\u003e\u003ctd\u003e()个\u003c/td\u003e\u003ctd\u003e()个\u003c/td\u003e\u003c/tr\u003e\u003c/table\u003e", + "options": [ + + ], + "answer": "4;4;3;3", + "solution": "【分析】长方体是长长方方的有平平的面;正方体是正正方方的有平平的面;圆柱上下是圆且上下一样粗;球没有平面可以任意方向滚动的;根据立体图形的特征,先数一数,再填空即可.\n【详解】由题意分析得: \u003ctable\u003e\u003ctr\u003e\u003ctd\u003e长方体\u003c/td\u003e\u003ctd\u003e正方体\u003c/td\u003e\u003ctd\u003e球\u003c/td\u003e\u003ctd\u003e圆柱\u003c/td\u003e\u003c/tr\u003e\u003ctr\u003e\u003ctd\u003e4个\u003c/td\u003e\u003ctd\u003e4个\u003c/td\u003e\u003ctd\u003e3个\u003c/td\u003e\u003ctd\u003e3个\u003c/td\u003e\u003c/tr\u003e\u003c/table\u003e", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "23-24一年级上·河北邯郸·期末" + }, + { + "id": "254", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "数一数,填一填。 ![](images/8ec3e598fe30407a94c684ec4c11d1045d0a77a923e5d35df2327d7faa7599f1.jpg) \u003ctable\u003e\u003ctr\u003e\u003ctd\u003e长方体\u003c/td\u003e\u003ctd\u003e()个\u003c/td\u003e\u003c/tr\u003e\u003ctr\u003e\u003ctd\u003e正方体\u003c/td\u003e\u003ctd\u003e()个\u003c/td\u003e\u003c/tr\u003e\u003ctr\u003e\u003ctd\u003e球\u003c/td\u003e\u003ctd\u003e()个\u003c/td\u003e\u003c/tr\u003e\u003ctr\u003e\u003ctd\u003e圆柱\u003c/td\u003e\u003ctd\u003e()个\u003c/td\u003e\u003c/tr\u003e\u003c/table\u003e", + "options": [ + + ], + "answer": "2;4;4;7", + "solution": "【分析】长方体是长长方方的有平平的面;正方体是正正方方的有平平的面;圆柱上下是圆且上下一样粗;球没有平面可以任意方向滚动的;根据立体图形的特征,先数一数,再填空即可.\n【详解】由题意分析得: \u003ctable\u003e\u003ctr\u003e\u003ctd\u003e长方体\u003c/td\u003e\u003ctd\u003e2个\u003c/td\u003e\u003c/tr\u003e\u003ctr\u003e\u003ctd\u003e正方体\u003c/td\u003e\u003ctd\u003e4个\u003c/td\u003e\u003c/tr\u003e\u003ctr\u003e\u003ctd\u003e球\u003c/td\u003e\u003ctd\u003e4个\u003c/td\u003e\u003c/tr\u003e\u003ctr\u003e\u003ctd\u003e圆柱\u003c/td\u003e\u003ctd\u003e7个\u003c/td\u003e\u003c/tr\u003e\u003c/table\u003e", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "23-24 一年级上·江西赣州·期末" + }, + { + "id": "255", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "数一数。 ![](images/32b9efead7b935b12632aeb02a41c54a39be11391805c9f0278747fbcbcd4e23.jpg) 长方体( )个,正方体( )个,圆柱( )个,球( )个。", + "options": [ + + ], + "answer": "5;1;3;6", + "solution": "【分析】长方体是长长方方的有平平的面;正方体是正正方方的有平平的面;圆柱上下是圆且上下一样粗;球没有平面可以任意方向滚动的;根据立体图形的特征,先数一数,再填空即可.\n【详解】由题意分析得:长方体 5 个,正方体 1 个,圆柱 3 个,球 6 个。", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "23-24 一年级上·重庆九龙坡·期末" + }, + { + "id": "256", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.65, + "question": "数一数。 ![](images/35d23fbc68df87482c74b43f601a44b3a8585cb6d0437d248bdfa5ea97af00ea.jpg) 正方体( )个,长方体( )个,圆柱( )个,球( )个。", + "options": [ + + ], + "answer": "4;6;4;3", + "solution": "【分析】正方体是正正方方的,有 6 个同样的平平的面;长方体是长长方方的,有平平的面;圆柱上下两个面是圆圆的,且上下一样粗;球是圆圆的可以任意滚动。据此判断图形并数出数量即可.\n【详解】根据分析知:正方体4个,长方体6个,圆柱4个,球3个。", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "23-24一年级上·河北保定·期末" + }, + { + "id": "257", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "数一数,填一填。 ![](images/fca0b64704d96807df326e929ddd323c41a9ab1e31aaba4ca3fe047dbd19a916.jpg) 长方体( )个,圆柱( )个,正方体( )个,球( )个。", + "options": [ + + ], + "answer": "5;3;2;6", + "solution": "【分析】长方体是长长方方的有平平的面;正方体是正正方方的有平平的面;圆柱上下是圆且上下一样粗;球没有平面可以任意方向滚动的;根据立体图形的特征,先数一数,再填空即可.\n【详解】由题意分析得:长方体5个,圆柱3个,正方体2个,球6个。", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "23-24 一年级上·广东广州·期末" + }, + { + "id": "258", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "数一数,填一填。 ![](images/845ddfafec82a361674a21d533ae0deb500013d81021ba16c9c17c3d826253f0.jpg) \u003ctable\u003e\u003ctr\u003e\u003ctd\u003e长方体\u003c/td\u003e\u003ctd\u003e正方体\u003c/td\u003e\u003ctd\u003e圆柱\u003c/td\u003e\u003ctd\u003e球\u003c/td\u003e\u003c/tr\u003e\u003ctr\u003e\u003ctd\u003e()个\u003c/td\u003e\u003ctd\u003e()个\u003c/td\u003e\u003ctd\u003e()个\u003c/td\u003e\u003ctd\u003e()个\u003c/td\u003e\u003c/tr\u003e\u003c/table\u003e", + "options": [ + + ], + "answer": "4;1;2;2", + "solution": "【分析】长方体是长长方方的有平平的面;正方体是正正方方的有平平的面,每个面大小都一样;圆柱上下是圆且上下一样粗;球没有平面可以任意方向滚动,由此数出各图形数量填空即可.\n【详解】由分析得: ![](images/0d20688959785b7a0eff1dccad90446851e5ca491ded4798a538d9674d2ca31d.jpg) \u003ctable\u003e\u003ctr\u003e\u003ctd\u003e长方体\u003c/td\u003e\u003ctd\u003e正方体\u003c/td\u003e\u003ctd\u003e圆柱\u003c/td\u003e\u003ctd\u003e球\u003c/td\u003e\u003c/tr\u003e\u003ctr\u003e\u003ctd\u003e4个\u003c/td\u003e\u003ctd\u003e1个\u003c/td\u003e\u003ctd\u003e2个\u003c/td\u003e\u003ctd\u003e2个\u003c/td\u003e\u003c/tr\u003e\u003c/table\u003e", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "23-24 二年级上·河南郑州·期末" + }, + { + "id": "259", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "数一数,填一填。 ![](images/8f84edebfae699b09dde38f6b7d20fca9e733e020872d4656e191831c677ce73.jpg) 长方体有( )个,正方体有( )个,圆柱有( )个,球有( )个。", + "options": [ + + ], + "answer": "3;2;2;2", + "solution": "【分析】长方体是长长方方的有平平的面;正方体是正正方方的有平平的面;圆柱上下是圆且上下一样粗;球没有平面可以任意方向滚动的;根据立体图形的特征,先数一数,再填空即可.\n【详解】由题意分析得:长方体有 3 个,正方体有 2 个,圆柱有 2 个,球有 2 个。", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "23-24一年级上·湖南长沙·期末" + }, + { + "id": "260", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.65, + "question": "数一数,填一填。 ![](images/4b9a6a4cc55c7d30309b714d52140380c7c5be768f7d55eaf52b94c3c852c43c.jpg) 长方体有( )个,正方体有( )个,圆柱有( )个,球有( )个。", + "options": [ + + ], + "answer": "6;4;4;3", + "solution": "【分析】根据长方体,正方体,圆柱体,球的特征,长方体是长长方方的,有 6 个平平的面,面有大有小;正方体是四四方方的,有 6 个平平的面,每个面的大小都一样;圆柱是直直的,上下一样粗,上下面是圆圆的,平平的;球是圆圆的。据此解答.\n【详解】![](images/e2be7f6bd74712cea164d6546af22ee5249783d66ed3da0f3b7694c1bb91b68a.jpg)\n图中长方体有 6 个,正方体有 4 个,圆柱有 4 个,球有 3 个.", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "23-24 一年级上·浙江温州·期末" + }, + { + "id": "261", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "![](images/1cadea176173ff2cf3fd13e49520ae849bd05832dcaec690902ad311ed378294.jpg) ( )个正方体;( )个球;( )个长方体;( )个圆柱。", + "options": [ + + ], + "answer": "2;3;2;6", + "solution": "【分析】根据立体图形的特征分别数一数各有几个,即可解答。长方体是长长方方的有平平的面;正方体是正正方方的有平平的面;圆柱上下是圆且上下一样粗;球没有平面可以任意方向滚动的.\n【详解】由题意分析得:2 个正方体;3 个球;2 个长方体;6 个圆柱。", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "23-24一年级上·青海果洛·期末" + }, + { + "id": "262", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "图中正方体有( )个,长方体有()个,圆柱有()个,球有()个,下面几种图形中,最容易滚动的是()。 ![](images/4698c87d301569774c3b91cce4b7d8c331bd5e8bc140eb8c0bdda3214c096a4b.jpg)", + "options": [ + + ], + "answer": "2;3;3;2;球", + "solution": "【分析】长方体是长长方方的有平平的面;正方体是正正方方的有平平的面;圆柱上下是圆且上下一样粗;球没有平面可以任意方向滚动.\n【详解】图中正方体有2个,长方体有3个,圆柱有3个,球有 2 个,下面几种图形中,最容易滚动的是球。", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "23-24 一年级上·河南周口·期末" + }, + { + "id": "263", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "各有多少个。 ![](images/20fdf05d65d87340c265f21b45b8d720adc7f809a824547aa534550a7756ecbb.jpg) 长方体( )个,正方体( )个,球 ( )个,圆柱( )个。", + "options": [ + + ], + "answer": "4;1;2;4", + "solution": "【分析】长方体是长长方方的有平平的面;正方体是正正方方的有平平的面;圆柱上下是圆且上下一样粗;球没有平面可以任意方向滚动的;根据立体图形的特征,先数一数,再填空即可.\n【详解】由题意分析得:长方体4个,正方体1个,球2个,圆柱4个。", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "23-24 一年级上·广东湛江·期末" + }, + { + "id": "264", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.65, + "question": "摆一个大正方体至少要用( )个同样的小正方体。", + "options": [ + + ], + "answer": "8", + "solution": "【分析】一行摆 2 个同样的小正方体,并排摆 2 行这样的,摆一层就需要 4 个这样的小正方体;接着第二层按照第一层的摆法,又需要 4 个这样的小正方体;故, 8 个同样的小正方体就可以摆出一个大正方体。(如下图)![](images/0ddc5deb71eba5abe424deef749efba10ab3587c17d90fe165e4522cef9f6963.jpg)\n【详解】 4 + 4 = 8 (个),故,摆一个大正方体至少要用 8 个同样的小正方体。", + "knowledge_points": [ + "8,9 的加减法", + "立体图形的认识" + ], + "source": "20-21 一年级上·山西晋中·期末" + }, + { + "id": "265", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "认识图形。 ![](images/66dc00c238d4ce6cc5bc21b268693723d8aed510ee299177152f806f4dd90487.jpg)( )个 正方体。", + "options": [ + + ], + "answer": "5", + "solution": "【分析】根据正方体的特征数一数即可知道一共有几个正方体 .\n【详解】由题意分析得:![](images/96adfcff701420651c9e1e85f19ba89a2738ba3e2b92f864a8bb8552483a43aa.jpg)5 个正方体。", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "23-24 一年级上·广东广州·期末" + }, + { + "id": "266", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "认识图形。![](images/540396bcfb1d95f6cc81b60c61577caa4353558d035e816206595b2ec6d6c825.jpg) ( )个正方体 , ( )个圆柱 , ( )个长方体 , ( )个球 。", + "options": [ + + ], + "answer": "4;3;3;2", + "solution": "【分析】长方体:有 6 个面,每个面都由长方形或相对的一组正方形组成;正方体:有 6 个面,每个面都由正方形组成;圆柱:上下两个面为大小相同的圆形,有一个曲面叫侧面;球是生活中最常见的图形之一,例如篮球,足球都是球,球是由一个面所围成的几何体。据此解答.\n【详解】由分析可知: ![](images/dc782406011a8b8cdea788045e2518a67604a6e20a6d7ba4b63a41811c05670e.jpg) 4个正方体 ,3个 圆柱,3个长方体 ,2个球 。", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "23-24 一年级上·广东广州·期末" + }, + { + "id": "267", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "数一数,填一填。 ![](images/b413fbe3e0475735ac8c75b3410487338106e869256016578f99cd2dfd459b05.jpg) 长方体有( )个,正方体有( )个,圆柱有( )个,球有( )个。", + "options": [ + + ], + "answer": "2;5;1;2", + "solution": "【分析】长方体是长长方方的有平平的面;正方体是正正方方的有平平的面;圆柱上下是圆且上下一样粗;球没有平面可以任意方向滚动的;根据立体图形的特征,先数一数,再填空即可.\n【详解】由题意分析得:长方体有2个,正方体有5个,圆柱有1个,球有2个。", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "23-24一年级上·新疆喀什·期末" + }, + { + "id": "268", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "数一数。 ![](images/f7257d30c378c1eef118487b60582a6b00705a0bace7a7dcf1b2507319e32da6.jpg) \u003ctable\u003e\u003ctr\u003e\u003ctd\u003e长方体\u003c/td\u003e\u003ctd\u003e正方体\u003c/td\u003e\u003ctd\u003e圆柱\u003c/td\u003e\u003c/tr\u003e\u003ctr\u003e\u003ctd\u003e()个\u003c/td\u003e\u003ctd\u003e()个\u003c/td\u003e\u003ctd\u003e()个\u003c/td\u003e\u003c/tr\u003e\u003c/table\u003e", + "options": [ + + ], + "answer": "2;2;3", + "solution": "【分析】长方体是长长方方的有平平的面;正方体是正正方方的有平平的面;圆柱上下是圆且上下一样粗;根据立体图形的特征,先数一数,再填空即可.\n【详解】由题意分析得: \u003ctable\u003e\u003ctr\u003e\u003ctd\u003e长方体\u003c/td\u003e\u003ctd\u003e正方体\u003c/td\u003e\u003ctd\u003e圆柱\u003c/td\u003e\u003c/tr\u003e\u003ctr\u003e\u003ctd\u003e2个\u003c/td\u003e\u003ctd\u003e2个\u003c/td\u003e\u003ctd\u003e3个\u003c/td\u003e\u003c/tr\u003e\u003c/table\u003e", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "23-24 一年级上·江苏淮安·期末" + }, + { + "id": "269", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "数一数。 ![](images/e37978491d2a34b982dc6e97529f7667af453d86a0a3abefb80881a78f62d3cf.jpg) 长方体( )个,正方体( )个,圆柱( )个,球( )个。", + "options": [ + + ], + "answer": "3;5;2;2", + "solution": "【分析】长方体是长长方方的有平平的面;正方体是正正方方的有平平的面;圆柱上下是圆且上下一样粗;球没有平面可以任意方向滚动。由此数出各图形的数量填空即可.\n【详解】由分析填写如下: ![](images/d5a93a0d40aa3c244fbb5e13962135e41163729defa1759666354afc54728e4b.jpg) 长方体3个,正方体5个,圆柱2个,球2个。", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "23-24 一年级上·山东烟台·期末" + }, + { + "id": "270", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "数一数。 ![](images/1964b6cf03bcc7c15c80144fb08dd7612138d25184be7f0107b0f2e0cb05f208.jpg) \u003ctable\u003e\u003ctr\u003e\u003ctd\u003e长方体\u003c/td\u003e\u003ctd\u003e()个\u003c/td\u003e\u003c/tr\u003e\u003ctr\u003e\u003ctd\u003e正方体\u003c/td\u003e\u003ctd\u003e()个\u003c/td\u003e\u003c/tr\u003e\u003ctr\u003e\u003ctd\u003e圆柱\u003c/td\u003e\u003ctd\u003e()个\u003c/td\u003e\u003c/tr\u003e\u003ctr\u003e\u003ctd\u003e球\u003c/td\u003e\u003ctd\u003e()个\u003c/td\u003e\u003c/tr\u003e\u003c/table\u003e", + "options": [ + + ], + "answer": "3;2;2;4", + "solution": "【分析】首先要分别分析出图片中各个物体的特征:长方体有 6 个平平的面,长长的方方的,面有大有小;正方体四四方方的,有 6 个平平的面,每个面的大小都一样;圆柱直直的,上下一样粗,两端是两个大小一样的,圆圆的,平平的圆面,把圆柱横放在桌子上能滚动,立在桌子上就不能滚动;球是圆圆的,表面是曲面,把球放在桌子上能向任意方向滚动。根据每个物体的特征分别数一数图中各个物体的个数即可.\n【详解】根据图中每个物体的特征,分别数出每个物体的个数如下: ![](images/54a44b0cd4d730507475f992abe023e2e5c3e8872af213ae7fd1d2be3e436abd.jpg) \u003ctable\u003e\u003ctr\u003e\u003ctd\u003e长方体\u003c/td\u003e\u003ctd\u003e3个\u003c/td\u003e\u003c/tr\u003e\u003ctr\u003e\u003ctd\u003e正方体\u003c/td\u003e\u003ctd\u003e2个\u003c/td\u003e\u003c/tr\u003e\u003ctr\u003e\u003ctd\u003e圆柱\u003c/td\u003e\u003ctd\u003e2个\u003c/td\u003e\u003c/tr\u003e\u003ctr\u003e\u003ctd\u003e球\u003c/td\u003e\u003ctd\u003e4个\u003c/td\u003e\u003c/tr\u003e\u003c/table\u003e", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "23-24 一年级上·浙江温州·期末" + }, + { + "id": "271", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.65, + "question": "我们来数一数吧! ![](images/e7e6cebe590430e80f562f460454744b5635a0808792afcc111aba9125cc5ada.jpg) 圆柱有( )个,球有( )个,正方体有( )个,长方体有( )个。", + "options": [ + + ], + "answer": "3;3;3;4", + "solution": "【分析】根据长方体是长长方方的有平平的面,正方体是正正方方的有平平的面,圆柱上下是圆且上下一样粗,球没有平面可以任意方向滚动的特征进行分类识别,再数出相应的数量即可。据此解答即可.\n【详解】 ![](images/d05600057e533ca9b6e1420d67a8edc11f2f788078cdcec89271f60ca3932204.jpg) 圆柱有(3)个,球有(3)个,正方体有(3)个,长方体有(4)个。", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "23-24 一年级上·浙江温州·期末" + }, + { + "id": "272", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "下面图形中, ( )是长方体,( )是正方体,( )是圆柱,( )是球。 ![](images/9d2dde651468c2a671a450f3ad00b783856a8991d74018bb03ab7cd3e8dfdba7.jpg)![](images/a0ab3f69ee2b1c5eda27276e925ad808cc2d328310047cc24a2d636aba6c03bb.jpg)![](images/18acc83a814f14e6873027a3f6581ce03bbd4c93dc2e32f7d36c80586d0e2e68.jpg)![](images/3a237c22f5d069461d02193bb471de502b4184f5e5243bfefa915637a42bb236.jpg)", + "options": [ + + ], + "answer": "②;④;①;③", + "solution": "【分析】长方体是长长方方的有平平的面;正方体是正正方方的有平平的面;圆柱上下是圆且上下一样粗;球没有平面可以任意方向滚动的;据此填空.\n【详解】由题意分析得:图形中, ②是长方体, ④是正方体, ①是圆柱, ③是球。", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "23-24 一年级上·陕西商洛·期末" + }, + { + "id": "273", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "认一认,数一数。 ![](images/0c892e0d0c08f4dbd1f57de62e0163a6e01ab9c6fcba91c75a78a8d96b0a6538.jpg) 长方体有( )个;正方体有( )个;球有( )个;圆柱有( )个。", + "options": [ + + ], + "answer": "3;3;1;4", + "solution": "【分析】长方体是长长方方的有平平的面;正方体是正正方方的有平平的面;圆柱上下是圆且上下一样粗;球没有平面可以任意方向滚动,由此数出各图形数量填写即可.\n【详解】由分析得: ![](images/9d64d37c254d4e89b9d55e12b36a5753c014c833460b9d11f89a63aec2a53f7e.jpg) 长方体有3个;正方体有3个;球有1个;圆柱有4个。", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "23-24 一年级上·黑龙江大兴安岭地·期末" + }, + { + "id": "274", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "要拼成一个大正方体,下图至少还需要( )个![](images/5438d0bd40d90b4ab36bc50c7bb87c25b11e318d59d5ff865d25981475619cb1.jpg) 。 ![](images/50e8910a304c589f000e4e20551da1a3e3049989dd3710fdfe4fa99fab08b856.jpg)", + "options": [ + + ], + "answer": "3", + "solution": "【分析】拼成 2×2×2 的大正方体一共需要 8 个小正方体。图中已有 5 个小正方体,用 8 减 5 即可.\n【详解】 8 - 5 = 3 (个),所以至少还需要 3 个小正方体。", + "knowledge_points": [ + "立体图形的认识", + "正方体的特征", + "5以内数的减法" + ], + "source": "23-24 一年级上·甘肃庆阳·期末" + }, + { + "id": "275", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "一共有( )个图形,其中有( )个正方体, ( )个圆柱,长方体( )个。 ![](images/861f453a1b43ebf0d75c6c80cf744da23b0434fa220626973234c654ec0c5f6c.jpg)", + "options": [ + + ], + "answer": "10;3;3;2", + "solution": "【分析】数一数可知,一共有 10 个图形。长方体是长长方方的有平平的面;正方体是正正方方的有平平的面;圆柱上下是圆且上下一样粗;球没有平面可以任意方向滚动,由此数出各图形的数量填空即可.\n【详解】一共有 10 个图形,其中有 3 个正方体, 3 个圆柱,长方体 2 个。 ![](images/94d614526882256c917d08aa5ba28f801bfbbe7c695a844d403fd111eb84fa2a.jpg)", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "22-23一年级上·山西忻州·期末" + }, + { + "id": "276", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "数一数,填一填。 ![](images/095b218beca011a1e1406a2523b55290011665a7201a7c0a1854e0ab0064f20a.jpg) 长方体有( )个,正方体有( )个,球有( )个,圆柱有( )个。", + "options": [ + + ], + "answer": "3;5;2;2", + "solution": "【分析】长方体是长长方方的有平平的面;正方体是正正方方的有平平的面;圆柱上下是圆且上下一样粗;球没有平面可以任意方向滚动,由此数出各图形的数量填空即可.\n【详解】 ![](images/63bf4c98f54f59b397dcb34ef5bf51861d9e0b8d883d7b3ef3c4bcce4092e3dc.jpg) 长方体有 3 个,正方体有 5 个,球有 2 个,圆柱有 2 个。", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "22-23一年级上·山东临沂·期末" + }, + { + "id": "277", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "数一数,填一填。 ![](images/55770e6fab361b236799b38bc77c8488decffc9da502d2e3c3045261d5cf797c.jpg) 正方体有( )个;长方体有( )个;球有( )个;圆柱有( )个。", + "options": [ + + ], + "answer": "2;5;6;4", + "solution": "【分析】图中正方体的每个面都是一样大小的正方形;长方体是4个面是长方形,其他两个面是正方形;圆柱体上下两个面是圆形,侧面是曲面;球体的整个表面都是曲面。根据每个物体的形状不同分别数出各有几个即可.\n【详解】可以数出图中正方体有2个,长方体有5个,球有6个,圆柱有4个。", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "22-23一年级上·四川达州·期末" + }, + { + "id": "278", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "数一数。 ![](images/a91ed43644e9de72a328d2420141291f48ed3b98f07725e991211187e10b41c2.jpg) ( )个 长方体,( )个正方体 ,( )个圆柱 ,( )个球 。", + "options": [ + + ], + "answer": "3;3;4;2", + "solution": "【分析】长方体是长长方方的有平平的面;正方体是正正方方的有平平的面;圆柱上下是圆且上下一样粗;球没有平面可以任意方向滚动的。根据立体图形的特征,先数一数,再填空即可.\n【详解】由题意分析得:3个长方体 ,3个正方体 ,4个圆柱,2个球 。", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "22-23一年级上·福建宁德·期末" + }, + { + "id": "279", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "数一数,填一填。 ![](images/5d2215e2da8728b8d60e052ddfee3f9e2708b67d60e22770cd35a08e0b6fcd4d.jpg) 球有( )个,正方体有( )个,长方体有( )个。", + "options": [ + + ], + "answer": "2;2;6", + "solution": "【分析】长方体是长长方方的有平平的面;正方体是正正方方的有平平的面;球没有平面可以任意方向滚动,由此数出各图形的数量填空即可.\n【详解】 ![](images/f171b22cc4c83a3ce975ecd2f3c557d44049cd41f85fe375a15e600fe8a16f0e.jpg) 球有2个,正方体有2个,长方体有 6 个。", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "22-23一年级上·湖南株洲·期末" + }, + { + "id": "280", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "数一数。 ![](images/8da5e75d0a6ae2b7680a0c632f366b6503fa33bc86e819830f8da727a68e8d8e.jpg) (1)长方体有()个。 \n(2)正方体有()个。 \n(3)圆柱有()个。 \n(4)球有()个。", + "options": [ + + ], + "answer": "5;1;4;1", + "solution": "【分析】(1)长方体是长长方方的有平平的面,由此数出数量即可;(2) 正方体是正正方方的有平平的面,由此数出数量即可;(3) 圆柱上下是圆且上下一样粗,由此数出数量即可;(4) 球没有平面可以任意方向滚动,由此数出数量即可.\n【详解】 (1) 长方体有 5 个。(2) 正方体有 1 个。 (3) 圆柱有 4 个。 (4) 球有 1 个。", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "22-23一年级上·浙江宁波·期末" + }, + { + "id": "281", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "数一数,填一填。 ![](images/998027201a35d329820886ac1312ddec11d0d0c1c7efff7328cee9cf3284b8aa.jpg) 正方体有( )个。圆柱有( )个。圆柱和球一共有( )个。圆柱比长方体多( )个。", + "options": [ + + ], + "answer": "5;6;10;1", + "solution": "【分析】长方体是长长方方的有平平的面;正方体是正正方方的有平平的面;圆柱上下是圆且上下一样粗;球没有平面可以任意方向滚动。由此数出各图形的数量为正方体有 5 个;圆柱有 6 个;球有 4 个;长方体有 5 个。圆柱和球的数量 = 圆柱的数量 + 球的数量;圆柱比长方体多的数量 = 圆柱的数量 - 长方体的数量,代入计算即可.\n【详解】 ![](images/d0a4658d62306b398bbc127ee06688a624f6648b614beed818d60222020a092c.jpg) 正方体有5个。圆柱有6个。6+4=10(个);6-5=1(个)圆柱和球一共有 10 个。圆柱比长方体多 1 个。", + "knowledge_points": [ + "6 的加减法", + "10 的加减法", + "立体图形的认识" + ], + "source": "22-23一年级上·浙江杭州·期末" + }, + { + "id": "282", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "数一数。 ![](images/21bf853af3d5e6df820f1376bed4fa45003d781921573868ff5a13e78f52c3a6.jpg) 长方体( )个,正方体( )个,圆柱( )个,球( )个。", + "options": [ + + ], + "answer": "4;3;3;2", + "solution": "【分析】长方体是长长方方的有平平的面,正方体是正正方方的有平平的面,圆柱上下是圆且上下一样粗,球没有平面可以任意方向滚动,由此可数出各图形数量.\n【详解】 ![](images/15b2c98533b94185944adb0425d9a11e29779501bd678258cba8172932d104b4.jpg) 长方体4个,正方体3个,圆柱3个,球2个。", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "22-23一年级上·江苏扬州·期末" + }, + { + "id": "283", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "数一数,填一填。 ![](images/68339482e21e6a94e5800faa7b12b4307398efb479ece1f9270570b93ce7669b.jpg) 长方体有( )个,正方体有( )个,圆柱有( )个,球有( )个。", + "options": [ + + ], + "answer": "3;2;3;2", + "solution": "【分析】长方体是长长方方的有平平的面;正方体是正正方方的有平平的面;圆柱上下是圆且上下一样粗;球没有平面可以任意方向滚动。由此数出各图形的数量填空即可.\n【详解】 ![](images/fad6b4b0b01dfe59e318900a615e7e84cbf48aec1e99aa6dce708fac560900bc.jpg) 长方体有 3 个,正方体有 2 个,圆柱有 3 个,球有 2 个。", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "20-21一年级上·河南开封·期末" + }, + { + "id": "284", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "下面图形中有( )个长方体,( )个正方体,( )个圆柱,( )个球。 ![](images/6bf72072c495b97ae2eb10db6b3f8f72b54037e22bc3824aff5e5da799c50361.jpg)", + "options": [ + + ], + "answer": "2;2;3;1", + "solution": "【分析】长方体是长长方方的有平平的面,正方体是正正方方的有平平的面,圆柱上下是圆且上下一样粗,球没有平面可以任意方向滚动的,根据立体图形的特征,先数一数,再填空即可.\n【详解】由题意分析得:图形中有 2 个长方体, 2 个正方体, 3 个圆柱, 1 个球。", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "21-22 一年级上·浙江·期末" + }, + { + "id": "285", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "数一数。 ![](images/12c543c2d89f2e38d2734693a3a47073f8211345d29b25cc296cae1202575541.jpg) 长方体( )个,正方体( )个,圆柱( )个,球( )个。", + "options": [ + + ], + "answer": "3;4;3;2", + "solution": "【分析】长方体:由 6 个平平的面围成,且相对的面一样;正方体:由 6 个平平的面围成,且 6 个面都一样;圆柱:由2个平平的面和1个曲面围成;球:由1个曲面围成.\n【详解】由题意分析得:长方体3个,正方体4个,圆柱3个,球2个。", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "23-24 一年级上·河南漯河·期中" + }, + { + "id": "286", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.65, + "question": "数一数。 ![](images/2d04d1a6c11ccd86d10fbe8ed837b79b79193e842ce6ab41068d2f875d10c79c.jpg) 长方体( )个,正方体( )个,圆柱( )个,球( )个。", + "options": [ + + ], + "answer": "3;2;4;2", + "solution": "【分析】长方体是长长方方的,有平平的面,正方体是正正方方的,有平平的面,圆柱上下是两个圆,而且上下一样粗,球是圆圆的没有平平的面,据此数出各种图形的数量即可.\n【详解】根据分析知:长方体有 3 个,正方体有 2 个,圆柱有 4 个,球有 2 个。", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "23-24 一年级上·山西大同·期中" + }, + { + "id": "287", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.65, + "question": "数一数,填一填。 ![](images/b97a8c4a958168263e85077c5058d0ab4849f3162a129a301b4e927ebf8b794f.jpg) \u003ctable\u003e\u003ctr\u003e\u003ctd\u003e长方体\u003c/td\u003e\u003ctd\u003e正方体\u003c/td\u003e\u003ctd\u003e圆柱\u003c/td\u003e\u003ctd\u003e球\u003c/td\u003e\u003c/tr\u003e\u003ctr\u003e\u003ctd\u003e()个\u003c/td\u003e\u003ctd\u003e()个\u003c/td\u003e\u003ctd\u003e()个\u003c/td\u003e\u003ctd\u003e()个\u003c/td\u003e\u003c/tr\u003e\u003c/table\u003e", + "options": [ + + ], + "answer": "4;1;4;2", + "solution": "【分析】长方体是长长的方方的有平平的面,正方体是正正方方的有平平的面,圆柱上下有两个圆且上下一样粗,球是圆的可以任意方向滚动,根据立体图形的特征,通过数一数的方法,即可解答.\n【详解】根据分析可知:长方体有 4 个,正方体有 1 个,圆柱有 4 个,球有 2 个。", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "23-24一年级上·河南南阳·期中" + }, + { + "id": "288", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.65, + "question": "数一数。 ![](images/8a00df1e3b0f68f39f0f0d2e906e5638d3a22b93da6825383cf0196e4352166a.jpg) (1) 正方体有( )个;长方体有( )个。圆柱有( ) 个;球有( )个。 \n(2) 球和圆柱一共有( )个。 \n(3) 长方体比正方体多( )个,球比圆柱少( )个。", + "options": [ + + ], + "answer": "1;3;4;3;7;2;1", + "solution": "【分析】(1)分别数出长方体,正方体,圆柱和球的数量即可,注意长方体和正方体的区别。(2) 根据球和圆柱的数量相加得出结论即可。 (3) 求谁比谁多,谁比谁少多少的问题,用减法解决即可.\n【详解】(1)正方体有 1 个,长方体有 3 个,圆柱有 4 个,球有 3 个。(2) 3 + 4 = 7 (个)故球和圆柱一共7个。(3) 3-1=2(个) 4-3=1(个)\n故长方体比正方体多 2 个,球比圆柱少 1 个。", + "knowledge_points": [ + "立体图形的认识", + "5以内数的减法", + "7 的加减法" + ], + "source": "23-24一年级上·山东菏泽·期中" + }, + { + "id": "289", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "数一数。 ![](images/e17afdc183de392a9542bf1bf440583e9e1f0fff647649011fe30de923487186.jpg) 长方体有( )个;正方体有( )个;圆柱有( )个;球有( )个。", + "options": [ + + ], + "answer": "5;4;6;5", + "solution": "【分析】长方体:长长方方的,有 6 个面,每个面都是长方形,特殊情况下有 2 个相对的面是正方形;正方体:方方正正的, 6 个面是相同大小的正方形;圆柱:上下两个面是相同的圆形,侧面是曲面,较易滚动;球:圆圆的,可随意滚动。由此数出各图形的数量即可.\n【详解】 ![](images/6845df7eb3a560dbed65cb6092ac8bac249582344da6c6c8a66b2b0978848297.jpg) 长方体 5 个,正方体 4 个,圆柱 6 个,球 5 个。", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "22-23一年级上·江苏南通·期末" + }, + { + "id": "290", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "看图填空。 ![](images/10cc8c1d96f7c233a17beed34764d1a50b4711b91c135d3c4dc7395d07218c11.jpg) (1)长方体有( )个,正方体有( )个,圆柱有( )个,球有( )个。 \n(2)圆柱比正方体多( )个,正方体比球少( )个。", + "options": [ + + ], + "answer": "3;1;3;2;2;1", + "solution": "【分析】(1)长方体是长长方方的,有 6 个面,对面相等;正方体是方方正正的,6 个面是大小相等的正方形;圆柱上下两个面是大小相同的圆,侧面是曲面;球是圆圆的,可随意滚动。由此数出各图形填空即可。(2) 圆柱的数量-正方体的数量 = 圆柱比正方体多的数量;球的数量-正方体的数量 = 正方体比球少的数量.\n【详解】(1)长方体有 3 个,正方体有 1 个,圆柱有 3 个,球有 2 个。(2) 3 - 1 = 2 (个);2 - 1 = 1 (个)圆柱比正方体多2个,正方体比球少1个.", + "knowledge_points": [ + "立体图形的认识", + "5以内数的减法" + ], + "source": "23-24一年级上·辽宁鞍山·期中" + }, + { + "id": "291", + "unit": "第三单元 认识立体图形", + "question_type": "判断题", + "difficulty": 0.65, + "question": "正方体比长方体大。", + "options": [ + + ], + "answer": "×", + "solution": "【分析】根据实际情况可知,判断正方体和长方体的大小,要考虑正方体的棱长和长方体的长,宽和高,不能直接就说谁大,谁小,据此解答即可.\n【详解】正方体可能比长方体大,也可能比长方体小,原题说法错误。故答案为: ×", + "knowledge_points": [ + "长方体的认识及特征" + ], + "source": "23-24 一年级上·河北保定·期末" + }, + { + "id": "292", + "unit": "第三单元 认识立体图形", + "question_type": "判断题", + "difficulty": 0.85, + "question": "8 个同样的小正方体可以拼成一个长方体。", + "options": [ + + ], + "answer": "√", + "solution": "【分析】根据正方体和长方体的特征可知, 8 个同样的正方体可以拼成一个长方体。如:排成一行或排成两行是都可以拼成一个长方体;据此判断即可.\n【详解】由分析可知: 8 个同样的小正方体可以拼成一个长方体,说法正确;故答案为: √", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "23-24 一年级上·河南南阳·期末" + }, + { + "id": "293", + "unit": "第三单元 认识立体图形", + "question_type": "判断题", + "difficulty": 0.85, + "question": "图形![](images/520ca50b70ca012f451bda328e1518c5fe40c3a2683debe72447774333abad13.jpg)是由5个正方体拼成的。", + "options": [ + + ], + "answer": "×", + "solution": "【分析】图形下层有 4 个正方体,上层有 5 个正方体,一共有 4 + 5 = 9 (个)正方体.\n【详解】由分析可知,图形是由 9 个正方体拼成的。原题说法错误。故答案为: ×", + "knowledge_points": [ + "立体图形的认识", + "连加,连减(10以内)" + ], + "source": "22-23一年级上·云南玉溪·期末" + }, + { + "id": "294", + "unit": "第三单元 认识立体图形", + "question_type": "判断题", + "difficulty": 0.65, + "question": "圆球比正方体滚得慢。", + "options": [ + + ], + "answer": "×", + "solution": "【分析】圆球是曲面,正方体没有曲面,不易滚动,据此判断.\n【详解】圆球是曲面,容易滚动,正方体没有曲面,不易滚动,所以圆球比正方体滚动得快。原题说法错误。故答案为: ×", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "23-24一年级上·湖南怀化·期末" + }, + { + "id": "295", + "unit": "第三单元 认识立体图形", + "question_type": "判断题", + "difficulty": 0.85, + "question": "正方体,长方体,圆柱和球都是平面图形。", + "options": [ + + ], + "answer": "×", + "solution": "【分析】根据图形的认识,所有点不在同一个面上的图形是立体图形;由此解答即可.\n【详解】由分析可知:正方体,长方体,圆柱和球他们都是立体图形;故答案为: ×", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "22-23一年级上·甘肃庆阳·期末" + }, + { + "id": "296", + "unit": "第三单元 认识立体图形", + "question_type": "判断题", + "difficulty": 0.85, + "question": "![](images/45810a77b1dc4113c69d937636ff55c7dfe0c72bb2d43fadf803e472a1d4125a.jpg)从上面和下面看到的形状是相同的。", + "options": [ + + ], + "answer": "√", + "solution": "【分析】![](images/73ca6613e9236d32bb456344788ebae01fa4447e229cb6e0111a1f856921a981.jpg)从上面和下面看到的形状是两个完全相同的圆形,据此得出结论即可.\n【详解】根据分析知,原题干说法正确。故答案为: √", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "20-21 二年级上·安徽蚌埠·期末" + }, + { + "id": "297", + "unit": "第三单元 认识立体图形", + "question_type": "判断题", + "difficulty": 0.85, + "question": "长方体比球难滚动。", + "options": [ + + ], + "answer": "√", + "solution": "【分析】根据立体图形特征进行解答即可。球:由 1 个曲面围成。由六个长方形(特殊情况有两个相对的面是正方形)围成的立体图形叫长方体.\n【详解】长方体比球难滚动,原题说法正确。故答案为: √", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "23-24一年级上·河北邢台·期中" + }, + { + "id": "298", + "unit": "第三单元 认识立体图形", + "question_type": "判断题", + "difficulty": 0.85, + "question": "最容易滚动的是球体。", + "options": [ + + ], + "answer": "√", + "solution": "【分析】由曲面围成的物体最容易滚动,由平平的面围成的物体不易滚动。球体由一个曲面围成,所以容易滚动.\n【详解】由题意分析得:最容易滚动的是球体;此说法正确。故答案为: √", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "23-24 一年级上·河南三门峡·期中" + }, + { + "id": "299", + "unit": "第三单元 认识立体图形", + "question_type": "解答题", + "difficulty": 0.65, + "question": "![](images/c19765891994be7f8ddd5236a1d03af6.png) (1) 上面一共有()种立体图形,数量最多的立体图形是()。 \n(2) 球从左起排第 ( ),从右数排 ( )。 \n(3) 把正方体涂成红色,长方体涂成黑色。", + "options": [ + + ], + "answer": "4;圆柱;4;4;按图示涂色", + "solution": "【分析】长方体:有 6 个面,每个面都由长方形或相对的一组正方形组成;正方体:有 6 个面,每个面都由正方形组成;圆柱:上下两个面为大小相同的圆形,有一个曲面叫侧面;球:球是生活中最常见的图形之一,例如篮球,足球都是球,球是由一个面所围成的几何体。(1) 根据立体图形的认识可知上面有长方体,正方体,圆柱,球 4 种立体图形,其中最多的是圆柱,共有 4 个;(2) 从前开始即从左开始,所以从球左起排第 4,从后面开始即从右起,所以球从右起排第 4;(3) 根据立体图形的认识,将长方体和正方体按要求涂色即可.\n【详解】(1)上面一共有 4 种立体图形,数量最多的立体图形是圆柱。(2) 球从左起排第 4,从右数排 4 。(3)\n![](images/2a72f24684c4b4e62065bd6d728f1fa9.png)", + "knowledge_points": [ + "左,右位置", + "立体图形的认识" + ], + "source": "22-23一年级上·甘肃庆阳·期末" + }, + { + "id": "300", + "unit": "第三单元 认识立体图形", + "question_type": "解答题", + "difficulty": 0.85, + "question": "一共有()个图形,从左边数排在第 ( ) , 有 ( ) 个,从左边数把第三个图形圈起来。 ![](images/6bad1805dc914443084edef26dcd3d53.png)", + "options": [ + + ], + "answer": "10;10;4", + "solution": "【分析】先数数这一列的图形有多少个;分清左右,从左边开始数,数到圆柱是 10,则圆柱排在第 10;数一数球的个数,数出几个就是几个;分清左右,从左边开始数,数到3,把该图形圈起来.\n【详解】由分析可得:一共有(10)个图形,从左边数圆柱排在第(10),球有(4)个;从左边数把第三个图形圈起来如下: ![](images/9ca0f08cc00ca7526b4c02dde3c75f01fe5c452397151cf6421b689db4e51af3.jpg)", + "knowledge_points": [ + "左,右位置", + "数一数", + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "23-24一年级上·河南周口·期末" + }, + { + "id": "301", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "我家的椅子坏了,垫 ( ) 比较稳。 ![](images/45509b534f9a20448f477abe04bacb57.png)", + "options": [ + "A", + "B", + "C" + ], + "answer": "C", + "solution": "【分析】圆柱和球都有曲面,这两种物体都是容易滚动的,因此包含这两个物体的都是不稳定的.\n【详解】A 下面是圆柱的侧面,易滚动,不稳;B 下面是球,易滚动,不稳;C 两个图形接触的面都是平平的,比较稳定。故答案为: C", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "23-24一年级上·山东·课后作业" + }, + { + "id": "302", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "下面图形 ( ) 搭得最稳。", + "options": [ + "A. ![](images/a165f8f78b271bb168465832f29627e28fcfc020692ac4a09749324bd30e3341.jpg)", + "B. ![](images/5608fc1bd2826717e4560ffbb2b7dfefb7bd3e9723c621d98ccb9a70c25b5023.jpg)", + "C. ![](images/057a4171f76190cca50a7b2646446c52463a60051c0982706e3031edbb90c43d.jpg)" + ], + "answer": "B", + "solution": "【分析】圆柱的侧面和球都是曲面物体,不稳,正方体和长方体每个面都是长方形或正方形,比较稳.\n【详解】A。下面是圆柱,不稳,不符合题意;B. 下面是长方体,稳当,符合题意;C. 下面是球,不稳,不符合题意。故答案为: B", + "knowledge_points": [ + "组合图形的稳定性" + ], + "source": "23-24 一年级上·山东·课后作业" + }, + { + "id": "303", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "下列物品中不是球的是 ( )。", + "options": [ + "A. 羽毛球", + "B. 足球", + "C. 皮球" + ], + "answer": "A", + "solution": "【分析】球:由 1 个曲面围成的封闭图形。结合生活经验来完成此题即可.\n【详解】由题意分析得:羽毛球不是球。故答案为: A", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "23-24 一年级上·辽宁·课后作业" + }, + { + "id": "304", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "谁滚得最快。 ( )", + "options": [ + "A. ![](images/6a872269a6017bb94a1f70b2f58c1c9b8feacc13e023fd0770cd4b35a05d290e.jpg)", + "B. ![](images/c625d729883903d6e79b6e6bb78dfa09412fd2f0dc5b1ea7c2790ec828ad0009.jpg)", + "C. ![](images/038de1bcd5d1fc1f13ab9dbcbc31acb72302667f1bb5f704a6e7dd7fb2e88d0b.jpg)" + ], + "answer": "C", + "solution": "【分析】平平的面不能滚动;曲面可以滚动。正方体:由 6 个平平的面围成,所以正方体是不能滚动的。圆柱:由 2 个平平的面和 1 个曲面围成,当平平的放在下面时,圆柱是不能滚动的。球:由 1 个曲面围成,所以球是滚得最快的.\n【详解】由题意分析得:![](images/0e6a173444e5f2eef4c3c6edae335aa586470dc38ed24c88be1f6ffa37ec4d7c.jpg)滚的最快。故答案为: C", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "23-24 一年级上·辽宁·课后作业" + }, + { + "id": "305", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "下面三组积木放得最稳的是 ( )。", + "options": [ + "A. ![](images/2c4abde97955525e8fd2d306e7df648ae093938032e1b139dd04943336606eb7.jpg)", + "B. ![](images/436772536d9a5a278b57e27e646d8863fbd00de0e354c114d34dd266e3038ecf.jpg)", + "C. ![](images/c6d33135bb97c8044f0ef84b67e6858d0cf31452dfb9c13ce3bc7004fc2caaad.jpg)" + ], + "answer": "B", + "solution": "【分析】圆柱:由2个平平的面和1个曲面围成。球:由1个曲面围成。圆锥:由 1 个平平的面和 1 个曲面围成,且是一头是尖尖的。长方体:由 6 个平平的面围成,且是长长的。平平的面放在下面,且两个图形平平的面叠在一起最稳定。尖尖的一头在下面或曲面放在平平的面的上面,这样的放在一起不稳定.\n【详解】A。![](images/b99f3f3ca7a76f82f300b794499afe17391920064a79c4b43b7aeee27f83d3f3.jpg),球的曲面放在平平的面上,不稳定;B。![](images/c6096a7df14e11608229bc2b31bb8ea77cc417e9b952c9fcb017ddf720a90697.jpg) 圆柱平平的面放在下面,且圆柱和圆锥两个平行的面叠在一起,最稳定;C。![](images/9c47784f9444ecf563a4542ab65ce57d5cb19a8d099335f15e91fe965c31ea5d.jpg),圆锥尖尖的一头在下面;不稳定;故答案为: B", + "knowledge_points": [ + "组合图形的稳定性" + ], + "source": "23-24一年级上·辽宁·课后作业" + }, + { + "id": "306", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.65, + "question": "下面的圆柱有( )个。 ![](images/45aa2fc200fc5cc50fd9c32a74a1e417dd7cc7dce9a983c4fd0c47f4a52256e4.jpg)", + "options": [ + "A. 3", + "B. 4", + "C. 5" + ], + "answer": "B", + "solution": "【分析】根据圆柱的主要特征:上下两个完全相同的圆,侧面是一个曲面进行选择即可.\n【详解】从左面起,第 1 个、第 5 个、第 6 个、第 7 个都是圆柱,因此一共有 4 个圆柱。故答案为: B", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "23-24一年级上·上海·单元测试" + }, + { + "id": "307", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "下面的物体是长方体的是 ( )。", + "options": [ + "A. ![](images/ce9db23996fd10ea11b078fe2ae613ffae2b9daf211e514323432937f4b74e6a.jpg)", + "B. ![](images/eda1fd2998050486d312fedcc3e79ba5647e7d1973757b404fff317aa23a3cdb.jpg)", + "C. ![](images/231a98a0021dc8c609e58bfd5aa9901548cb185f13fc3b573be2392e0833a36e.jpg)" + ], + "answer": "C", + "solution": "【分析】弄清楚每种立体图形的特征,然后找出长方体即可.\n【详解】A。是球体;B. 是正方体;C. 是长方体。故答案为: C", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "23-24 一年级上·上海·单元测试" + }, + { + "id": "308", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.65, + "question": "可以向任意方向滚动的是 ( )。", + "options": [ + "A. ![](images/0c479d4ee03897dbb0adf4b88a160ba6a57b4436e1d581d50bde2bb89fa37787.jpg)", + "B. ![](images/27cd48925b62db06a98830d8401777ab5e00d9d70e08dae95a99cdd99ef206cd.jpg)", + "C. ![](images/fe24371654249269f4eb896ba1624574409c60e7031ad7e934fc4347ef42e605.jpg)" + ], + "answer": "C", + "solution": "【分析】球体,由一个曲面围成,曲面最容易滚动。长方体,正方体由六个平平的面围成,平平的面最难滚动.\n【详解】长方体,正方体不可以向任意方向滚动,球体可以向任意方向滚动。故答案为: C", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "23-24 一年级上·浙江·单元测试" + }, + { + "id": "309", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.65, + "question": "请同学们认真观察并数一数,图中一共有( )个小正方体。 ![](images/bde18aad791b85f7a42445ad7e0aec3e6ddb52500240801be6d80c4050a26d11.jpg)", + "options": [ + "A. 6", + "B. 9", + "C. 10" + ], + "answer": "C", + "solution": "【分析】此立体图形一共有 3 层,第 3 层有 1 个小正方体,第 2 层有 3 个小正方体,第 1 层有 6 个小正方体,依此计算出小正方体的总个数即可.\n【详解】1 + 3 + 6 = 10 (个),图中一共有 10 个小正方体。故答案为: C", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "20-21 四年级下·山东济宁·期末" + }, + { + "id": "310", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "谁搭的积木不稳 ( )。", + "options": [ + "A. ![](images/188584faaa89b4ed1bcb6bc155cc4545fe8c76507b5052e5a75df5f984350924.jpg)", + "B. ![](images/c7e40f85279e1da38d59dcc6801ccfc0b8127d3a7877b30098e75f9782672f6b.jpg)", + "C. ![](images/0794471ed5f532bedf174b7b5e8d74410c948eb6d6766b01c490e0041076b32b.jpg)" + ], + "answer": "A", + "solution": "【分析】根据生活中的经验,圆柱侧面接触地面容易滚动,圆柱的底面不容易滚动,长方体不容易滚动,据此解答即可.\n【详解】由分析可得:第一个图与地面接触的为圆柱的侧面,圆柱容易滚动,所以 A 最不稳定。故答案为: A", + "knowledge_points": [ + "圆柱的认识及特征", + "组合图形的稳定性" + ], + "source": "19-20一年级上·北京西城·期末" + }, + { + "id": "311", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.65, + "question": "乒乓球的形状是 ( )。", + "options": [ + "A. 圆柱体", + "B. 球体", + "C. 长方体" + ], + "answer": "B", + "solution": "【分析】乒乓球它是立体的,乒乓球在正常的状态下,不管是从哪一个方向都可以转动,而且乒乓球也具备球体的外形特征,也就是说乒乓球无论是从哪一个方向看,都是球体.\n【详解】根据我们对立体图形的认识,乒乓球的形状是球体。故答案为: B", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "21-22 一年级下·北京·单元测试" + }, + { + "id": "312", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.65, + "question": "如图所示能搭稳的图形是( )。", + "options": [ + "A. ![](images/45386c8edca28edc458d5b8b262c6f596a8503983954b680abf8f7de8d59d4d4.jpg)", + "B. ![](images/59a08b494a508b8344061468b72f6c56c0ff4ca7ad5e0c73fefc35d8f8842be0.jpg)", + "C. ![](images/0cdc220b47b98e3aee877fbd177eafbb34353f6763249f8941de7847052d89ea.jpg)" + ], + "answer": "C", + "solution": "【分析】正方体的每个面都有正方形组成,长方体,正方体的稳定性好;圆柱:上下两个面为大小相同的圆形,有一个曲面叫侧面,侧面易滚动;球:球是生活中最常见的图形之一,例如篮球,足球都是球,球是由一个面所围成的几何体,滚动速度快。据此特性选择.\n【详解】根据正方体,圆柱及球的特性可知,圆柱,球体易滚动。A。![](images/e379bfda8da1dcbb5ef13c653edd5de8b36af8b2892cf8d4faa6b375219f06da.jpg), 不能搭稳;B。![](images/c515b31113b4cdd15d75305fde378f3cd3f2966632998e792b22ae79b4434cb4.jpg), 不能搭稳;C。![](images/bbd68f322ef9111706bc4ca7805152aab51d419ca6ac3c39c8fef11646a2b717.jpg),能搭稳。故答案为: C", + "knowledge_points": [ + "组合图形的稳定性" + ], + "source": "21-22一年级下·北京·单元测试" + }, + { + "id": "313", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "物体的面能画出![](images/4f289a173b342bb9f05bb895b61ab2465967859154536bc71569038c1805a4f7.jpg)的是()。", + "options": [ + "A. ![](images/830620c1ffe353dea50e7d6116e8c003ef171a954599851dd7a3f59e387e5477.jpg)", + "B. ![](images/9f3957647916bcf5b1d146a18a3dc3c6820c50237aa73a079726c32776ae2dfb.jpg)", + "C. ![](images/fcfdd546f4c78f16e427730456d15998b4596948247cbc7b5c934db583f447c8.jpg)" + ], + "answer": "B", + "solution": "【分析】正方体:由6个正方形的面围成。长方体:由 6 个长方形的面围成。圆柱:由2个圆形和一个曲面围成.\n【详解】由题意分析得:\n物体的面能画出![](images/4f289a173b342bb9f05bb895b61ab2465967859154536bc71569038c1805a4f7.jpg)的是![](images/9f3957647916bcf5b1d146a18a3dc3c6820c50237aa73a079726c32776ae2dfb.jpg)故答案为: B", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "20-21 一年级下·陕西西安·期中" + }, + { + "id": "314", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "下列选项中的立体图形,表面没有曲面的是 ( )。", + "options": [ + "A. ![](images/18bdacb28669f1c4aafab3d6ba7b98307cdb71f32a51e8da44f449dc1c573afc.jpg)", + "B. ![](images/e4b44097d848d1545ade30f82b9d874a08bb2001452f96cb34801ffd02fd2b44.jpg)", + "C. ![](images/5dd9829ac5d61e030e0c2bfd416b1507c023960375c1050a42a75fdc7633f381.jpg)", + "D. ![](images/529402937aa6cb9586830c9dbb533f62a0539c1173f71f6ca532dccab81e4b59.jpg)" + ], + "answer": "D", + "solution": "【分析】根据四种几何体的形状分别进行分析即可.\n【详解】A。球有一个曲面,故此选项错误;B. 圆柱有一个曲面,故此选项错误;C. 圆锥有一个曲面,故此选项错误;D. 长方体没有曲面,故此选项正确。故答案为: D", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "22-23六年级上·黑龙江哈尔滨·期末" + }, + { + "id": "315", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.4, + "question": "下面()的展开图是 ( )。![](images/29aa727196f5296243aba3db259d8b225462c566954bb2c9ed4de5d7ad1648a2.jpg)", + "options": [ + "A. ![](images/0e7fcd7fc77c788eb39124c505e0e2c8ae91b0a9111624b6c24c6b8413c389ed.jpg)", + "B. ![](images/8478c9708e1427964f7e12aa0c0d64ad844578ffc88cb23c8679ccfd057eb4d6.jpg)", + "C. ![](images/1889961465f7bfc7fb98a1cd25ef019ee69fa1850d7aaf4569df4e9f053e9e1f.jpg)" + ], + "answer": "A", + "solution": "【分析】从图上可得:这个图形是由 4 个三角形拼接围成的立体图形,结合选项的展开图进行选择即可.\n【详解】![](images/41c85db2060d4809bfa627804eb6e4521dac1d6fa81cb69139c249e21a9041cb.jpg)故答案为: A", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "22-23 一年级下·北京·单元测试" + }, + { + "id": "316", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.65, + "question": "用物体()可能画出正方形。", + "options": [ + "A. ![](images/57e80132c4ce999dc6f874d9efd4c745c4cdd7b1a9ec357ed74760fb238ac4b4.jpg)", + "B. ![](images/786e7ab03e7737f6a831e71eedce0f8a46126a7269a0a2d346c7d9e21872d8e2.jpg)", + "C. ![](images/b2df8f760253f615e3b3b4fe543bfa01188039a01aba000903c997c489a0c320.jpg)" + ], + "answer": "B", + "solution": "【分析】正方体每个面都有正方形组成;长方体每个面都由长方形或相对的一组正方形组成;圆柱上下两个面为大小相同的圆形,有一个曲面叫侧面;据此解答.\n【详解】由分析可得:用正方体可以画出正方形。故答案为: B", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "22-23一年级下·四川·单元测试" + }, + { + "id": "317", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "用哪个物体可以画出下面的图形, ( )。![](images/b9ab09b2292e6fc39fed2cc5fe8dfc3d469d174e93647f12dd3730cb2f3e56fc.jpg)", + "options": [ + "A. ![](images/62bf89144d94c0be3bb2bd8e4ed5c8bc40b90cf97b35c16cb79780de1491396d.jpg)", + "B. ![](images/8df9feccb30db02f1253721c6fc4caacdbf02dafe20c773fc9134a9f8304bd97.jpg)", + "C. ![](images/9534732bbe073d1ae4ea29e34168dfd0f07132b16bd67e9c00bf2c6995e810a8.jpg)" + ], + "answer": "B", + "solution": "【分析】根据立体图形的面的特征来完成此题.\n【详解】A。这个长方体由6个长方形的面组成,用这个长方体不能画出正方形;B. 正方体由 6 个正方形的面组成,用正方体可以画出正方形;C. 圆锥由一个圆和一个曲面组成,用圆锥不能画出正方形。故答案为: B", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "22-23一年级下·辽宁·单元测试" + }, + { + "id": "318", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.65, + "question": "下图是由( )个正方体组成的。 ![](images/377c59b1adcea4220578bd4571b6479cd0f67e87af4902d84e0074e792dc3dce.jpg)", + "options": [ + "A. 7", + "B. 6", + "C. 5" + ], + "answer": "A", + "solution": "【分析】分层数,先数出下层的个数,再加上上层的个数,注意隐藏的不要漏数.\n【详解】由题意分析得:图中是由 7 个正方体组成的。故答案为: A", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "22-23一年级上·河北衡水·期末" + }, + { + "id": "319", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.65, + "question": "汽车没安轮子,该选哪个图形做轮子?( )。 ![](images/bb8041bdb065c4bac02dedcc0f2ac9d3.png)", + "options": [ + "A", + "B", + "C" + ], + "answer": "C", + "solution": "【分析】根据图形的特征来选择答案。正方体和三棱柱的面都是平平的面,若用正方体或三棱柱做成的轮子,滚动起来不平稳;而圆柱有一个面是曲面,若用圆柱做成的轮子,沿着曲面滚动比较平稳.\n【详解】由题意分析得:汽车没有安轮子,应该选圆柱做轮子。故答案为: C", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "22-23一年级上·辽宁·课后作业" + }, + { + "id": "320", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "下面的图形中,最难滚动的是 ( )。", + "options": [ + "A. ![](images/14600fa3b5e6cf4cf91192a7acef0d54c80d83467991fb3212a0feb33a900f40.jpg)", + "B. ![](images/fb613807d72391130374e9299796a88a38268fc4038b35cf02326fdeb5ad29ce.jpg)", + "C. ![](images/6a71ff0f75d09d69f1ac2585a019c042192c0b373d904229bd66abc47a190c04.jpg)" + ], + "answer": "B", + "solution": "【分析】球体,由一个曲面围成,曲面最容易滚动。长方体,由六个平平的面围成,平平的面最难滚动。圆柱,由一个曲面和两个平平的面围成,曲面这一面容易滚动.\n【详解】由题意分析得:在这三个图形中,最难滚动的是长方体。故答案为: B", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "22-23一年级上·河北邯郸·期末" + }, + { + "id": "321", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "搭的最稳的是 ( )。", + "options": [ + "A. ![](images/8f8f0dbae083a8e222e24ebd1df33be9b0617bc1aa9a5bdd8845ce2b0939bb2c.jpg)", + "B. ![](images/f39a16dabc737151a778e37e3c7af7210cc67efb80b193522749121e4076a4ab.jpg)", + "C. ![](images/20af0bce39c15090879ac5956f3841174718f1c12a055cce9139883fd72bff70.jpg)" + ], + "answer": "A", + "solution": "【分析】长方体,由 6 个平平的面组成,长方体平平的面放在地面上很稳。圆柱,由 1 个曲面和 2 个平平的面组成,圆柱的曲面放在下面,不太稳定。球,由 1 个曲面组成,球放在下面,不稳定.\n【详解】由题意分析得:![](images/65b9d43386da550fda0b67c956c16ce92fb2e1b74c980c425ebf2739a1bb41ae.jpg),这个搭的最稳。故答案为: A", + "knowledge_points": [ + "组合图形的稳定性" + ], + "source": "20-21 一年级上·福建南平·期末" + }, + { + "id": "322", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.65, + "question": "下面哪个搭得最稳。( )", + "options": [ + "A. ![](images/63c1e93383addc904bbba6fb19bfe9b1fa60a57b6a0ee0550745a7b1471528a6.jpg)", + "B. ![](images/42e25710d9e9c7ed618330a5729ecd2ebf51a62f264462050621bc18c01a7706.jpg)", + "C. ![](images/0de279d72c85e5e48ac0aecab1a23cb65eedab9143facc4ad771772aaa5c478e.jpg)" + ], + "answer": "C", + "solution": "【分析】圆柱有一个曲面和两个平面组成,圆柱曲面放在下面不稳定。球有一个曲面组成,球放在下面不稳定。长方体有 6 个平的面组成,长方体放在下面最稳。据此选择.\n【详解】由题意分析得:![](images/ef5fda154d7b71cf0c65f3b70585ce9c0b692e0ef5f79e46d40f2b28543db6f4.jpg),这个最稳。故答案为: C", + "knowledge_points": [ + "组合图形的稳定性" + ], + "source": "20-21一年级上·江苏苏州·期末" + }, + { + "id": "323", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.65, + "question": "下图中, ( ) 最容易滚动。", + "options": [ + "A. ![](images/a252ef52bcb3cb4eb6d90dd4bba63a04e004174f8c93ba8dc347bb8ced2096f7.jpg)", + "B. ![](images/848c2ab1fb7bb2f625fdf9e55e6e48022e63cb148d0dff2bf76616d6bcffea76.jpg)", + "C. ![](images/39c42d94b63f027a0e161f2dd768034a3c0acba53dd253b16ef54e6a46a98f27.jpg)", + "D. ![](images/01e9ad80b1d1244bb1101c7fff42150e4ea4a4dd9ad9f3a3e2d03b256e60fd9.jpg)" + ], + "answer": "B", + "solution": "【分析】长方体由六个平平的面组成,不容易滚动;正方体由六个平平的面组成,不容易滚动;圆柱由两个相对的平平的面和一个曲面组成,比较容易滚动;球由一个曲面组成,最容易滚动;据此选择.\n【详解】由题意分析得:![](images/cc04d049d9b733cd3f6dbd0550a5329d1c898ca86e22f9586e0ca0fa4b36845.jpg)最容易滚动。故答案为: B", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "20-21 一年级上·辽宁大连·期末" + }, + { + "id": "324", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "用一张长方形的纸,折一折,卷一卷,下面哪个物体不可能出现。( )", + "options": [ + "A. ![](images/d84e6f92dde5fd609e24622fc9f58d057e536bff7305b14169784aebd2b110bd.jpg)", + "B. ![](images/8b907ff51d9daf0745967d14a794dd51e99d608c9dff3bafe051dc8438bea735.jpg)", + "C. ![](images/d56a78a049e825b6ae8499af718f357c5dc9f654fc66d91c8a4335a2cce6bed1.jpg)" + ], + "answer": "C", + "solution": "【分析】用一张长方形纸,可能卷成一个圆筒(即没有上、下底的圆柱),也可折成一个方筒(即没有上、下底的长方体),不可能折成或卷成球.\n【详解】用一张长方形的纸,折一折,卷一卷,不可能出现球。故答案为: C", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "20-21一年级上·江苏泰州·期末" + }, + { + "id": "325", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.65, + "question": "数一数,![](images/2d43757e5be61f166dd6fe930109c2e51fdf744d9e723c24b4e20f155b2487db.jpg)里有多少个小正方体。( )", + "options": [ + "A. 3 个", + "B. 4 个", + "C. 5 个" + ], + "answer": "A", + "solution": "【分析】根据图形,上面一层有 1 个,下面一层有 2 个,合起来一共有 3 个小正方体,由此解答.\n【详解】由分析可知:1 + 2 = 3 (个),故答案为: A", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "22-23一年级上·江苏徐州·期中" + }, + { + "id": "326", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "物体表面没有圆的是( )。 ![](images/39f04f7c51d2cdc4adf60e45b764b4ef.png)", + "options": [ + "A", + "B", + "C" + ], + "answer": "A", + "solution": "【分析】分别判断出三个选项分别是什么图形,再进行判断.\n【详解】A。是长方体,物体表面没有圆;B. 是圆柱体,物体表面有圆;C. 是圆锥体,物体表面有圆。故答案为: A", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "20-21 一年级下·四川甘孜·期末" + }, + { + "id": "327", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.65, + "question": "从立体图形的一个面看到的是一个长方形,它可能是( )。 ![](images/dfa0ee9c340dae08684c7f9edc6fc340.png)", + "options": [ + "A. ①或②", + "B. ②或③", + "C. ①或③" + ], + "answer": "A", + "solution": "【分析】观察可知,图①是长方体,从它的一个面可能看到的是一个长方形;图②是长方体,从它的一个面可能看到的是一个长方形;图③是球体,无论从哪个面都不可能看到一个长方形.\n【详解】根据分析可知,从立体图形的一个面看到的是一个长方形,它可能是①或②。故答案为: A", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "22-23二年级上·全国·期末" + }, + { + "id": "328", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.65, + "question": "图( )是用 4 个相同的小正方体拼成的。", + "options": [ + "A. ![](images/b15d7cf2324c7e762839af7a8286aa42daca027e883331c3c8a2b55aca675b02.jpg)", + "B. ![](images/651101b090e74c4af00a665873d6c09e4c9c6c4a4f69a566e671b7ad0ca8ef8e.jpg)", + "C. ![](images/e58502afb97b7d12a5cb15bc7581dd7c15771240ec12567048e3b28880eff2c3.jpg)" + ], + "answer": "C", + "solution": "【分析】将每个选项的立体图形用几个正方体拼成的算出来即可解答.\n【详解】A,该图是用5个正方体拼成的,故该选项错误;B,该图是用3个正方体拼成的,故该选项错误;C,该图是用4个正方体拼成的,故该选项正确。故答案为: C", + "knowledge_points": [ + "立体图形的切拼", + "立体图形的认识" + ], + "source": "22-23 一年级上·全国·课后作业" + }, + { + "id": "329", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.65, + "question": "( ) 可以立起来,放倒后很容易滚动。", + "options": [ + "A. 长方体", + "B. 圆柱体", + "C. 球" + ], + "answer": "B", + "solution": "【分析】根据对长方体,圆柱体,球的认识进行分析即可.\n【详解】长方体可以立起来,放倒后也不容易滚动;球不论怎么放都容易滚动;圆柱体可以立起来,放倒后很容易滚动。故答案为: B", + "knowledge_points": [ + "长方体的认识及特征", + "圆柱的认识及特征", + "立体图形的认识" + ], + "source": "22-23 一年级上·全国·课后作业" + }, + { + "id": "330", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "下面图形是圆柱的是 ( )。", + "options": [ + "A. ![](images/790327d514fd378ae28d41a77e8f14ad3ffa6d2384836e6d0608629a03dc1e5d.jpg)", + "B. ![](images/b749e91e62e80498d0f4561017c39176a37546d62d11c16061d324132a61d85a.jpg)", + "C. ![](images/8673f1d99595a4d8ac3f8bebce8424586100cd20e672cd14d60c474a1c3d8982.jpg)" + ], + "answer": "B", + "solution": "【分析】长方体是立体图形:是长长方方的,有平平的面;圆柱是立体图形:是直直的,上下一样粗细,两头是圆的,平平的;据此解答.\n【详解】A。是平面图形,梯形;B. 圆柱;C. 长方体。故答案为: B", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "21-22 一年级下·湖北黄冈·期末" + }, + { + "id": "331", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "下面的( )号图形是这个长方体的后面。 ![](images/b7dbbd3701f698464161b61eee9c4a2f2b8150a6481398b83e9ccca8e704863c.jpg)", + "options": [ + "A. ![](images/45ef5383bfaed7ecc7cef733a11e89712969214c37c28877e4984b53cd0a0c92.jpg)", + "B. ![](images/2328f399a979c4c22884e3c459bf2afc37c93ffbcc4fe2e9e6515de8089c8f4c.jpg)", + "C. ![](images/9dbd669a0b1c88508113e4644639815db025827ea1ae1dbe6a8a80d1b8443d95.jpg)" + ], + "answer": "C", + "solution": "【分析】观察图形可知,从正面看到的图形是长方形,据此解答即可.\n【详解】A。 图形是这个图形的左面和右面,不符合题意;B. 图形是这个图形的上面和下面,不符合题意;C. 图形是这个图形的前面和后面,符合题意。故答案为: C", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "2022一年级下·江苏·专题练习" + }, + { + "id": "332", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.65, + "question": "下面第 ( ) 个图形可以立起来,还可以滚动。 ![](images/aaeb317524fed76b2a4778115002f8ee.png)", + "options": [ + "A", + "B", + "C" + ], + "answer": "C", + "solution": "【分析】根据立体图形的特征,把各个选项进行分析,据此选择.\n【详解】\nA。![](images/3127247cb1731b2a324177347e1a8d2523d70e4a7c6e6be6b372bd90b87db58f.jpg)是球,可以滚动,但难以立住;B。![](images/01b1d802e024360e991d51cade8984180ecbd328f7873283dbe3a33e67845e25.jpg)是长方体,不可以滚动,但可以立住;C。![](images/eba99134a0efd595647177891b494453898c7fcd2eaca410227ed45863ffd277.jpg)是圆柱,既可以滚动,又可以立起来。故答案为: C", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "21-22 一年级上·湖北黄冈·期末" + }, + { + "id": "333", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "数一数,填一填.\n![](images/a99d2d365f426762307edda36386f51bdd2cabbf3d2ff26b8f7d552c3b86dd35.jpg)\n长方体有( )个,圆柱有( )个,正方体有( )个,球有( )个。", + "options": [ + + ], + "answer": "3;3;6;4", + "solution": "【分析】球:表面是曲面,易滚动;圆柱:上下两个面是圆,侧面是曲面,平放易滚动;长方体:长长方方的,6个面都是长方形,特殊情况下可能有两个相对的面是正方形,不易滚动;正方体:6个面是完全相等的正方形,不易滚动。由此数一数即可.\n【详解】由分析填写如下:\n![](images/d850651c2a5ef7c965ea00f5e854efb723555cce7d8c822ac52a2e3f936e976c.jpg)\n长方体有 3 个,圆柱有 3 个,正方体有 6 个,球有 4 个。", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "23-24一年级上·河北·期中" + }, + { + "id": "334", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "数一数,填一填.\n![](images/c392e34b33d81739dce50a7c293de08ceebccee4e58caf81d39a516f21776b81.jpg)\n( )个正方体 , ( )个长方体 ( )个圆柱, ( )个球", + "options": [ + + ], + "answer": "2;2;6;2", + "solution": "【分析】球:表面是曲面,易滚动;圆柱:上下两个面是圆,侧面是曲面,平放易滚动;长方体:长长方方的,6个面都是长方形,特殊情况下可能有两个相对的面是正方形,不易滚动;正方体: 6 个面是完全相等的正方形,不易滚动。由此数一数即可.\n【详解】由分析填写如下:2 个正方体,2 个长方体,6 个圆柱,2 个球。", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "23-24一年级上·四川·期中" + }, + { + "id": "335", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "要想把积木搭得又稳又高,一般把( )和( )搭在下面,把( )和( )搭在上面。", + "options": [ + + ], + "answer": "正方体;长方体;球;圆柱", + "solution": "【分析】根据对立体图形的认识可知:长方体:长长方方的,有平平的面,不易滚动;正方体:正正方方的,每个面都相同,不易滚动;圆柱:直直的,上下一样粗,上下两个面是圆的,平放易滚动;球:表面是曲面,易滚动。摆放时不易滚动的放在下面,易滚动的放在上面.\n【详解】由分析可知:要想把积木搭得又稳又高,一般把正方体和长方体搭在下面,把球和圆柱搭在上面.", + "knowledge_points": [ + "组合图形的稳定性" + ], + "source": "22-23 一年级上·全国·课前预习" + }, + { + "id": "336", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "长方体和正方体不易( ), 圆柱和球易( )。", + "options": [ + + ], + "answer": "滚动;滚动", + "solution": "【分析】长方体是长长方方的,有平平的面,不易滚动;正方体是方方正正的,有大小相同的面,不易滚动;圆柱是直直的,上下一样粗,上下两个面是平平的,侧面是曲面,平放易滚动;球表面是曲面,易滚动.\n【详解】由分析可知,长方体和正方体不易滚动,圆柱和球易滚动.", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "22-23 一年级上·全国·课前预习" + }, + { + "id": "337", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "长长方方的,有平平的面,这样的立体图形是( );四四方方的,有平平的面,这样的立体图形是( );直直的,上下一样粗,上下两个面平平的,侧面是曲面,这样的立体图形是( );表面是曲面,这样的立体图形是( )。", + "options": [ + + ], + "answer": "长方体;正方体;圆柱;球", + "solution": "【分析】由题意可知,长方体是长长方方的,有平平的面,相对的面大小相等;正方体是四四方方的,有平平的面,每个面的大小都相等;圆柱是直直的,上下一样粗,上下两个面是平的,侧面是曲面;球的表面是曲面,容易滚动,据此解答即可.\n【详解】长长方方的,有平平的面,这样的立体图形是(长方体);四四方方的,有平平的面,这样的立体图形是(正方体);直直的,上下一样粗,上下两个面平平的,侧面是曲面,这样的立体图形是(圆柱);表面是曲面,这样的立体图形是(球).", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "22-23 一年级上·全国·课前预习" + }, + { + "id": "338", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "数一数,填一填.\n![](images/f21e8ea9622f9a4766f21b7dcb114c3fc63860388c936b120adf2c6ffbcc9305.jpg)\n\u003ctable\u003e\u003ctr\u003e\u003ctd\u003e图形\u003c/td\u003e\u003ctd\u003e长方体\u003c/td\u003e\u003ctd\u003e正方体\u003c/td\u003e\u003ctd\u003e圆柱\u003c/td\u003e\u003ctd\u003e球\u003c/td\u003e\u003c/tr\u003e\u003ctr\u003e\u003ctd\u003e个数(个)\u003c/td\u003e\u003ctd\u003e\u003c/td\u003e\u003ctd\u003e\u003c/td\u003e\u003ctd\u003e\u003c/td\u003e\u003ctd\u003e\u003c/td\u003e\u003c/tr\u003e\u003c/table\u003e", + "options": [ + + ], + "answer": "5;3;6;4", + "solution": "【分析】长方体:由 6 个平平的面围成,且相对的面一样。正方体:由 6 个平平的面围成,且 6 个面都一样。圆柱:由2个平平的面和1个曲面围成。球:由1个曲面围成.\n【详解】由题意分析得:\n\u003ctable\u003e\u003ctr\u003e\u003ctd\u003e图形\u003c/td\u003e\u003ctd\u003e长方体\u003c/td\u003e\u003ctd\u003e正方体\u003c/td\u003e\u003ctd\u003e圆柱\u003c/td\u003e\u003ctd\u003e球\u003c/td\u003e\u003c/tr\u003e\u003ctr\u003e\u003ctd\u003e个数(个)\u003c/td\u003e\u003ctd\u003e5\u003c/td\u003e\u003ctd\u003e3\u003c/td\u003e\u003ctd\u003e6\u003c/td\u003e\u003ctd\u003e4\u003c/td\u003e\u003c/tr\u003e\u003c/table\u003e", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "23-24一年级上·河北·课后作业" + }, + { + "id": "339", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "数一数,填一填.\n![](images/d014ab7cff9e68030f01d009bdf74fe4.png)\n\u003ctable\u003e\u003ctr\u003e\u003ctd\u003e长方体\u003c/td\u003e\u003ctd\u003e正方体\u003c/td\u003e\u003ctd\u003e圆柱\u003c/td\u003e\u003ctd\u003e球\u003c/td\u003e\u003c/tr\u003e\u003ctr\u003e\u003ctd\u003e()个\u003c/td\u003e\u003ctd\u003e()个\u003c/td\u003e\u003ctd\u003e()个\u003c/td\u003e\u003ctd\u003e()个\u003c/td\u003e\u003c/tr\u003e\u003c/table\u003e", + "options": [ + + ], + "answer": "5;2;5;3", + "solution": "【分析】根据立体图形的不同特征,分别数一数各有几个,然后填空即可。圆柱:由2个平平的面和1个曲面围成。球:由 1 个曲面围成。长方体:由 6 个平平的面围成,且是长长的。正方体:由6个平平的面围成,且每个面都是正方形.\n【详解】由题意分析得:\n\u003ctable\u003e\u003ctr\u003e\u003ctd\u003e长方体\u003c/td\u003e\u003ctd\u003e正方体\u003c/td\u003e\u003ctd\u003e圆柱\u003c/td\u003e\u003ctd\u003e球\u003c/td\u003e\u003c/tr\u003e\u003ctr\u003e\u003ctd\u003e5个\u003c/td\u003e\u003ctd\u003e2个\u003c/td\u003e\u003ctd\u003e5个\u003c/td\u003e\u003ctd\u003e3个\u003c/td\u003e\u003c/tr\u003e\u003c/table\u003e", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "23-24一年级上·辽宁·课后作业" + }, + { + "id": "340", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "![](images/edb726076077c90d91883ca717745e0297bffbfd9ac7b25130cbfc86417a4241.jpg)\n\u003ctable\u003e\u003ctr\u003e\u003ctd\u003e()个\u003c/td\u003e\u003ctd\u003e()个\u003c/td\u003e\u003ctd\u003e()个\u003c/td\u003e\u003ctd\u003e()个\u003c/td\u003e\u003c/tr\u003e\u003c/table\u003e", + "options": [ + + ], + "answer": "3;3;3;3", + "solution": "【分析】根据立体图形的不同特征,分别数一数各有几个,然后填空即可.\n圆柱:由 2 个平平的面和 1 个曲面围成。球:由 1 个曲面围成。长方体:由 6 个平平的面围成,且是长长的。正方体:由 6 个平平的面围成,且每个面都一样.\n【详解】由题意分析得:\n\u003ctable\u003e\u003ctr\u003e\u003ctd\u003e长方体\u003c/td\u003e\u003ctd\u003e正方体\u003c/td\u003e\u003ctd\u003e球\u003c/td\u003e\u003ctd\u003e圆柱\u003c/td\u003e\u003c/tr\u003e\u003ctr\u003e\u003ctd\u003e3个\u003c/td\u003e\u003ctd\u003e3个\u003c/td\u003e\u003ctd\u003e3个\u003c/td\u003e\u003ctd\u003e3个\u003c/td\u003e\u003c/tr\u003e\u003c/table\u003e", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "23-24 一年级上·辽宁·课后作业" + }, + { + "id": "341", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "数一数,填一填.\n![](images/fe585a1b13b5afde564be76cad6e323dcab54b9540c1c344852c2506f1c4b645.jpg)\n\u003ctable\u003e\u003ctr\u003e\u003ctd\u003e长方体\u003c/td\u003e\u003ctd\u003e正方体\u003c/td\u003e\u003ctd\u003e圆柱\u003c/td\u003e\u003ctd\u003e球\u003c/td\u003e\u003c/tr\u003e\u003ctr\u003e\u003ctd\u003e()个\u003c/td\u003e\u003ctd\u003e()个\u003c/td\u003e\u003ctd\u003e()个\u003c/td\u003e\u003ctd\u003e()个\u003c/td\u003e\u003c/tr\u003e\u003c/table\u003e", + "options": [ + + ], + "answer": "5;3;2;2", + "solution": "【分析】根据立体图形的不同特征,分别数一数各有几个,然后填空即可.\n圆柱:由2个平平的面和1个曲面围成。球:由1个曲面围成。长方体:由 6 个平平的面围成,且是长长的。正方体:由 6 个平平的面围成,且每个面都一样.\n【详解】由题意分析得:\n\u003ctable\u003e\u003ctr\u003e\u003ctd\u003e长方体\u003c/td\u003e\u003ctd\u003e正方体\u003c/td\u003e\u003ctd\u003e圆柱\u003c/td\u003e\u003ctd\u003e球\u003c/td\u003e\u003c/tr\u003e\u003ctr\u003e\u003ctd\u003e5个\u003c/td\u003e\u003ctd\u003e3个\u003c/td\u003e\u003ctd\u003e2个\u003c/td\u003e\u003ctd\u003e2个\u003c/td\u003e\u003c/tr\u003e\u003c/table\u003e", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "23-24一年级上·辽宁·课后作业" + }, + { + "id": "342", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "比一比,填一填.\n![](images/3ec783de128959e12e047858bcbc22bdc29a627874144f0069781079ba3b8329.jpg)\n圆柱比正方体多( )个,长方体比球少( )个。", + "options": [ + + ], + "answer": "1;1", + "solution": "【分析】先按照圆柱,正方体,长方体,球特征分别数一数各有几个;再用减法求出两数差,即可解决此题.\n【详解】由题意分析得:圆柱有 3 个;正方体有 2 个;长方体有 3 个;球有 4 个;3 - 2 = 1 (个),4 - 3 = 1 (个);所以圆柱比正方体多 1 个,长方体比球少 1 个。", + "knowledge_points": [ + "5以内数的减法", + "立体图形的认识" + ], + "source": "21-22一年级上·广东湛江·期末" + }, + { + "id": "343", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.65, + "question": "数一数,填一填.\n![](images/ae35e41ca88fa51b641c49560b6feaeab9eb6cce24c3e2ca0d07776eeb91c58d.jpg)\n\u003ctable\u003e\u003ctr\u003e\u003ctd\u003e长方体\u003c/td\u003e\u003ctd\u003e()个\u003c/td\u003e\u003c/tr\u003e\u003ctr\u003e\u003ctd\u003e正方体\u003c/td\u003e\u003ctd\u003e()个\u003c/td\u003e\u003c/tr\u003e\u003ctr\u003e\u003ctd\u003e圆柱\u003c/td\u003e\u003ctd\u003e()个\u003c/td\u003e\u003c/tr\u003e\u003ctr\u003e\u003ctd\u003e球\u003c/td\u003e\u003ctd\u003e()个\u003c/td\u003e\u003c/tr\u003e\u003c/table\u003e", + "options": [ + + ], + "answer": "3;1;2;0", + "solution": "【分析】球的表面是曲面,球可以朝四周任意一个方向滚动;圆柱的特征:圆柱上下两个底面是完全相等的两个圆,侧面是曲面,将圆柱放倒,可以滚动;正方体的特征:6个面是完全相等的正方形;长方体的特征:6个面都是长方形,特殊情况下可能有两个相对的面是正方形,数一数各种图形的数量.\n【详解】数一数可知:\n\u003ctable\u003e\u003ctr\u003e\u003ctd\u003e长方体\u003c/td\u003e\u003ctd\u003e3个\u003c/td\u003e\u003c/tr\u003e\u003ctr\u003e\u003ctd\u003e正方体\u003c/td\u003e\u003ctd\u003e1个\u003c/td\u003e\u003c/tr\u003e\u003ctr\u003e\u003ctd\u003e圆柱\u003c/td\u003e\u003ctd\u003e2个\u003c/td\u003e\u003c/tr\u003e\u003ctr\u003e\u003ctd\u003e球\u003c/td\u003e\u003ctd\u003e0个\u003c/td\u003e\u003c/tr\u003e\u003c/table\u003e", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "23-24一年级上·上海·单元测试" + }, + { + "id": "344", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.65, + "question": "数一数.\n![](images/d48fbe2093e341610fd295cb84d37a038f988abbfe2f6d7c65a3b10bc99f9fdd.jpg)\n长方体()个,正方体()个,圆柱()个,球()个", + "options": [ + + ], + "answer": "4;1;4;2", + "solution": "【分析】球的表面是曲面,球可以朝四周任意一个方向滚动;圆柱的特征:圆柱上下两个底面是完全相等的两个圆,侧面是曲面,将圆柱放倒,可以滚动;正方体的特征: 6 个面是完全相等的正方形;长方体的特征:6个面都是长方形,特殊情况下可能有两个相对的面是正方形,数一数各种图形的数量.\n【详解】数一数可知,长方体4个,正方体1个,圆柱4个,球2个.", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "18-19一年级上·辽宁·单元测试" + }, + { + "id": "345", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.65, + "question": "数一数.\n![](images/c316e2f134b3e880e02c954095e50578d60e5e28dfe18d47a781ec4686e32e9d.jpg)\n长方体()个,正方体()个,球()个,圆柱()个", + "options": [ + + ], + "answer": "1;3;8;6", + "solution": "【分析】圆:圆形是绕一点旋转一周围成的图形,它是一个曲线图形;圆柱的特征:圆柱上下两个底面是完全相等的两个圆,侧面是曲面,将圆柱放倒,可以滚动;正方体的特征:6个面是完全相等的正方形;长方体的特征:6个面都是长方形,特殊情况下可能有两个相对的面是正方形,数一数各种图形的数量.\n【详解】数一数可知,长方体1个,正方体3个,球8个,圆柱6个.", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "23-24一年级上·上海·单元测试" + }, + { + "id": "346", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.65, + "question": "数一数,填一填.\n![](images/2dbb0ac2362b52fdee2396fac39ea5b11657169119d71977baca9e5bd71cbdd8.jpg)\n\u003ctable\u003e\u003ctr\u003e\u003ctd\u003e正方体\u003c/td\u003e\u003ctd\u003e圆柱\u003c/td\u003e\u003ctd\u003e长方体\u003c/td\u003e\u003ctd\u003e球\u003c/td\u003e\u003c/tr\u003e\u003ctr\u003e\u003ctd\u003e()个\u003c/td\u003e\u003ctd\u003e()个\u003c/td\u003e\u003ctd\u003e()个\u003c/td\u003e\u003ctd\u003e()个\u003c/td\u003e\u003c/tr\u003e\u003c/table\u003e", + "options": [ + + ], + "answer": "2;3;3;4", + "solution": "【分析】正方体的主要特征:6个正方形组成的几何体;圆柱的主要特征:上下两个完全相同的圆,侧面是一个曲面;长方体的主要特征: 6 个长方形组成 (或相对的一组正方形组成) 的几何体;球的主要特征:从正面看,从左面看,从上面看,都是一个圆;依此进行分类即可.\n【详解】根据分析,填空如下:\n\u003ctable\u003e\u003ctr\u003e\u003ctd\u003e正方体\u003c/td\u003e\u003ctd\u003e圆柱\u003c/td\u003e\u003ctd\u003e长方体\u003c/td\u003e\u003ctd\u003e球\u003c/td\u003e\u003c/tr\u003e\u003ctr\u003e\u003ctd\u003e2个\u003c/td\u003e\u003ctd\u003e3个\u003c/td\u003e\u003ctd\u003e3个\u003c/td\u003e\u003ctd\u003e4个\u003c/td\u003e\u003c/tr\u003e\u003c/table\u003e", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "23-24一年级上·上海·单元测试" + }, + { + "id": "347", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.65, + "question": "认识图形.\n![](images/ca3afd93787417705c10c38b707f10a170096d8218cd060067889e7f48abc175.jpg)\n长方体有()个;正方体有()个;圆柱体有()个;球有()个。", + "options": [ + + ], + "answer": "长方体有①,④;正方体有③,⑧;圆柱体有②,⑥,⑨;球有⑤,⑦", + "solution": "【分析】长方体的主要特征:6个长方形组成(或相对的一组正方形组成)的几何体;正方体的主要特征:6个正方形组成的几何体;圆柱的主要特征:上下两个完全相同的圆,侧面是一个曲面;球的主要特征:从正面看,从左面看,从上面看,都是一个圆;依此进行分类即可.\n【详解】根据分析,填空如下:长方体有①,④;正方体有③,⑧;圆柱体有②,⑥,⑨;球有⑤,⑦.", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "23-24一年级上·上海·单元测试" + }, + { + "id": "348", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.65, + "question": "数一数,填一填.\n![](images/d4cf1877d2f6690b4d3598aa872606edbfb1a8e67e14a247f9927b3cc3dbdfd1.jpg)\n长方体( )个,正方体( )个,球( )个,圆柱( )个。", + "options": [ + + ], + "answer": "4;1;2;4", + "solution": "【分析】球体的特征:球的表面是曲面,球可以朝四周任意一个方向滚动;圆柱的特征:圆柱上下两个底面是完全相等的两个圆,侧面是曲面,将圆柱放倒,可以滚动;正方体的特征:6个面是完全相等的正方形;长方体的特征: 6 个面都是长方形,特殊情况下可能有两个相对的面是正方形.\n【详解】长方体4个,正方体1个,球2个,圆柱4个.", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "23-24一年级上·上海·单元测试" + }, + { + "id": "349", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.65, + "question": "数一数,填一填.\n![](images/af849ee5788444908faa91495c9adae788e3558f16a28cb7abc1bf49c627774d.jpg)\n长方体有( )个,正方体有( )个,球有( )个,圆柱有( )个。", + "options": [ + + ], + "answer": "3;2;2;1", + "solution": "【分析】球体的特征:球的表面是曲面,球可以朝四周任意一个方向滚动;圆柱的特征:圆柱上下两个底面是完全相等的两个圆,侧面是曲面,将圆柱放倒,可以滚动;正方体的特征:6个面是完全相等的正方形;长方体的特征:6个面都是长方形,特殊情况下可能有两个相对的面是正方形.\n【详解】长方体有3个,正方体有2个,球有2个,圆柱有1个.", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "23-24 一年级上·山东·单元测试" + }, + { + "id": "350", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "看图填空:\n![](images/7e8cf3492e63e855740f98d3fe8e7e0a6a33c9766e7beff91d063f377472d226.jpg)\n\u003ctable\u003e\u003ctr\u003e\u003ctd\u003e长方体\u003c/td\u003e\u003ctd\u003e()个\u003c/td\u003e\u003c/tr\u003e\u003ctr\u003e\u003ctd\u003e正方体\u003c/td\u003e\u003ctd\u003e()个\u003c/td\u003e\u003c/tr\u003e\u003ctr\u003e\u003ctd\u003e圆柱\u003c/td\u003e\u003ctd\u003e()个\u003c/td\u003e\u003c/tr\u003e\u003ctr\u003e\u003ctd\u003e球\u003c/td\u003e\u003ctd\u003e()个\u003c/td\u003e\u003c/tr\u003e\u003c/table\u003e", + "options": [ + + ], + "answer": "5;4;4;3", + "solution": "【分析】由图可得,长方体有 5 个,正方体有 4 个,圆柱有 4 个,球有 3 个,据此填空即可.\n【详解】\n\u003ctable\u003e\u003ctr\u003e\u003ctd\u003e长方体\u003c/td\u003e\u003ctd\u003e5 个\u003c/td\u003e\u003c/tr\u003e\u003ctr\u003e\u003ctd\u003e正方体\u003c/td\u003e\u003ctd\u003e4 个\u003c/td\u003e\u003c/tr\u003e\u003ctr\u003e\u003ctd\u003e圆柱\u003c/td\u003e\u003ctd\u003e4 个\u003c/td\u003e\u003c/tr\u003e\u003ctr\u003e\u003ctd\u003e球\u003c/td\u003e\u003ctd\u003e3 个\u003c/td\u003e\u003c/tr\u003e\u003c/table\u003e", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "23-24 一年级上·河北·单元测试" + }, + { + "id": "351", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "下图中共有长方体( )个,正方体( )个;圆柱( )个,球( )个.\n![](images/7facf8214065ec3fabfe8dc06970bfaaaec9e146ca22658048066f3d8ef06109.jpg)", + "options": [ + + ], + "answer": "2;2;3;3", + "solution": "【分析】由题意可得,图中共有 2 个长方体, 2 个正方体, 3 个圆柱, 3 个球,据此填空即可.\n【详解】根据分析可得,下图中共有长方体 2 个,正方体 2 个;圆柱 3 个,球 3 个.", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "23-24 一年级上·河北·单元测试" + }, + { + "id": "352", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "![](images/ec82cf870ef54310e7f80705325ec09d80ce65918ebfcfbdccb347d9be0ad011.jpg)![](images/f14be84b77a236d3feb9c75677d0c668172a09509f0ace7614721bb130cba098.jpg)\n三位同学搭积木,共用了( )个长方体,( )个正方体,( )个圆柱,( )个球。", + "options": [ + + ], + "answer": "7;6;2;1", + "solution": "【分析】弄清楚长方体,正方体,球和圆柱的特征,依次数出每种图形的个数即可。长方体由 6 个长方形的面围成(特殊的由 2 个正方形和 4 个长方形的面围成)。正方体由6个正方形的面围成。球由1个曲面围成。圆柱由2个圆和1个曲面围成.\n【详解】由题意分析得:三位同学搭积木,共用了 7 个长方体, 6 个正方体, 2 个圆柱, 1 个球.", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "23-24 一年级上·辽宁·单元测试" + }, + { + "id": "353", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "( )是长方体, ( )是球体.\n![](images/2488f3ae8e28fddc5ed8ef1de5c65a00e3863b811925f9295cd21e9da7e8254d.jpg)", + "options": [ + + ], + "answer": "④是长方体,①是球体", + "solution": "【分析】长方体由 6 个长方形的面围成(特殊的由 2 个正方形和 4 个长方形的面围成)。球由 1 个曲面围成.\n【详解】由题意分析得:④ 是长方体, ①是球体.", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "23-24 一年级上·江苏·单元测试" + }, + { + "id": "354", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "数一数,填一填.\n![](images/20f96ba0acd7eabb417750c4420eda803bbc384e3448307741178853195ab64a.jpg)\n\u003ctable\u003e\u003ctr\u003e\u003ctd\u003e长方体\u003c/td\u003e\u003ctd\u003e()个\u003c/td\u003e\u003c/tr\u003e\u003ctr\u003e\u003ctd\u003e正方体\u003c/td\u003e\u003ctd\u003e()个\u003c/td\u003e\u003c/tr\u003e\u003ctr\u003e\u003ctd\u003e圆柱\u003c/td\u003e\u003ctd\u003e()个\u003c/td\u003e\u003c/tr\u003e\u003ctr\u003e\u003ctd\u003e球\u003c/td\u003e\u003ctd\u003e()个\u003c/td\u003e\u003c/tr\u003e\u003c/table\u003e", + "options": [ + + ], + "answer": "5;2;6;3", + "solution": "【分析】弄清楚长方体,正方体,球和圆柱的特征,依次数出每种图形的个数即可。长方体由 6 个长方形的面围成(特殊的由 2 个正方形和 4 个长方形的面围成)。正方体由6个正方形的面围成。球由1个曲面围成。圆柱由 2 个圆和 1 个曲面围成.\n【详解】由题意分析得:\n\u003ctable\u003e\u003ctr\u003e\u003ctd\u003e长方体\u003c/td\u003e\u003ctd\u003e5 个\u003c/td\u003e\u003c/tr\u003e\u003ctr\u003e\u003ctd\u003e正方体\u003c/td\u003e\u003ctd\u003e2 个\u003c/td\u003e\u003c/tr\u003e\u003ctr\u003e\u003ctd\u003e圆柱\u003c/td\u003e\u003ctd\u003e6 个\u003c/td\u003e\u003c/tr\u003e\u003ctr\u003e\u003ctd\u003e球\u003c/td\u003e\u003ctd\u003e3个\u003c/td\u003e\u003c/tr\u003e\u003c/table\u003e", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "23-24一年级上·江苏·单元测试" + }, + { + "id": "355", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "数一数.\n![](images/17e2d8d62a14daee5c482c3c2550df87103a50c44a09c97898e5fc5d47d68223.jpg)\n\u003ctable\u003e\u003ctr\u003e\u003ctd\u003e正方体\u003c/td\u003e\u003ctd\u003e长方体\u003c/td\u003e\u003ctd\u003e球\u003c/td\u003e\u003ctd\u003e圆柱\u003c/td\u003e\u003c/tr\u003e\u003ctr\u003e\u003ctd\u003e()个\u003c/td\u003e\u003ctd\u003e()个\u003c/td\u003e\u003ctd\u003e()个\u003c/td\u003e\u003ctd\u003e()个\u003c/td\u003e\u003c/tr\u003e\u003c/table\u003e", + "options": [ + + ], + "answer": "2;3;1;3", + "solution": "【分析】观察每个图形的特征,根据正方体,长方体,球体,圆柱体的特征确定各种物体的个数即可。球由 1 个曲面围成;圆柱由2个圆和1个曲面围成;正方体由6个正方形的面围成;长方体由 6 个长方形的面围成(特殊的由 2 个正方形和 4 个长方形的面围成).\n【详解】由题意分析得:\n\u003ctable\u003e\u003ctr\u003e\u003ctd\u003e正方体\u003c/td\u003e\u003ctd\u003e长方体\u003c/td\u003e\u003ctd\u003e球\u003c/td\u003e\u003ctd\u003e圆柱\u003c/td\u003e\u003c/tr\u003e\u003ctr\u003e\u003ctd\u003e2个\u003c/td\u003e\u003ctd\u003e3个\u003c/td\u003e\u003ctd\u003e1个\u003c/td\u003e\u003ctd\u003e3个\u003c/td\u003e\u003c/tr\u003e\u003c/table\u003e", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "23-24一年级上·江苏·单元测试" + }, + { + "id": "356", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "请你仔细观察下面物体并回答问题。![](images/68a979f24954d96fc04e1cccfa7dab57.png)\n( )是长方体, ( )是正方体, ( )是圆柱体, ( )是球。", + "options": [ + + ], + "answer": "④⑤⑦是长方体,③是正方体,①⑥⑧⑩是圆柱体,②⑨是球", + "solution": "【分析】长方体有 6 个面,一般都是长方形;正方体的 6 个面都是一模一样的正方形;圆柱体是由两个圆形平面和一个曲面围成;球是由曲面构成,可以滚动。据此作答.\n【详解】由立体图形的分类及识别可知: ④⑤⑦是长方体;③是正方体;①⑥⑧⑩是圆柱体;②⑨是球.", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "23-24一年级上·上海·单元测试" + }, + { + "id": "357", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "数一数,填一填.\n![](images/39caeaa456b0d8fc34639d9067160bc0.png)\n长方体( )个,正方体( )个,圆柱( )个,球( )个。", + "options": [ + + ], + "answer": "4;4;2;2", + "solution": "【分析】根据球,圆柱,正方体及长方体的特征分别数一数各有几个,再填空即可。球由 1 个曲面围成;圆柱由 2 个圆和 1 个曲面围成;正方体由 6 个正方形的面围成;长方体由 6 个长方形的面围成(特殊的由 2 个正方形的面和 4 个长方形的面围成).\n【详解】由题意分析得:长方体4个,正方体4个,圆柱2个,球2个.", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "23-24一年级上·江苏·单元测试" + }, + { + "id": "358", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "你认识的图形中, ( )最容易滚动。", + "options": [ + + ], + "answer": "球", + "solution": "【分析】在认识的立体图形中,球是由一个曲面围成,而只有曲面围成的图形是最容易滚动的.\n【详解】由题意分析得:认识的图形中,球最容易滚动.", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "23-24 一年级上·全国·单元测试" + }, + { + "id": "359", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "文具盒通常可看作( )体。", + "options": [ + + ], + "answer": "长方体", + "solution": "【分析】长方体的特征:有 6 个面,且相对的面相等,据此解答.\n【详解】根据生活经验可知:文具盒的形状为长方体;所以文具盒通常可看作长方体.", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "23-24 一年级上·全国·单元测试" + }, + { + "id": "360", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.65, + "question": "数一数,填一填.\n![](images/8e0e50edbf879e8165bc5b1f8376f5b755bf0fbe46830f99703c98cd8a6159e4.jpg)\n长方体有( )个,正方体有( )个,圆柱有( )个,球有( )个。", + "options": [ + + ], + "answer": "2;3;3;2", + "solution": "【分析】正方体:有 6 个面,每个面都由正方形组成;长方体:有 6 个面,每个面都由长方形或相对的一组正方形组成;圆柱:上下两个面为大小相同的圆形,有一个曲面叫侧面;球:球是生活中最常见的图形之一,例如篮球,足球都是球,球是由一个面所围成的几何体。据此解答即可.\n【详解】\n![](images/8e0e50edbf879e8165bc5b1f8376f5b755bf0fbe46830f99703c98cd8a6159e4.jpg)\n长方体有(2)个,正方体有(3)个,圆柱有(3)个,球有(2)个.", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "22-23一年级上·四川·课后作业" + }, + { + "id": "361", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "数一数.\n![](images/f19c3e16410c63f7a6046c47676fadd1.png)\n( )个长方体 ,( )个圆柱 ,( )个正方体 ,( )个球 。", + "options": [ + + ], + "answer": "4;4;3;2", + "solution": "【分析】按照立体图形的特征分别数一数各有几个,再填空即可。长方体:由六个长方形的面围成 (特殊的有两个正方形的面和四个长方形的面围成);正方体:由六个正方形的面围成;圆柱:由两个圆和一个曲面围成;球:由一个曲面围成.\n【详解】由题意分析得:长方体4个,圆柱4个,正方体3个,球2个。", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "22-23一年级上·山西吕梁·期末" + }, + { + "id": "362", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "认识图形.\n![](images/1ed05c0ebd3dc690b82f7f45ee2321b34463af7db0721e3dab37c14710eb8aae.jpg)\n\u003ctable\u003e\u003ctr\u003e\u003ctd\u003e长方体\u003c/td\u003e\u003ctd\u003e()个\u003c/td\u003e\u003c/tr\u003e\u003ctr\u003e\u003ctd\u003e正方体\u003c/td\u003e\u003ctd\u003e()个\u003c/td\u003e\u003c/tr\u003e\u003ctr\u003e\u003ctd\u003e球\u003c/td\u003e\u003ctd\u003e()个\u003c/td\u003e\u003c/tr\u003e\u003ctr\u003e\u003ctd\u003e圆柱\u003c/td\u003e\u003ctd\u003e()个\u003c/td\u003e\u003c/tr\u003e\u003c/table\u003e", + "options": [ + + ], + "answer": "4;3;2;2", + "solution": "【分析】根据长方体,正方体,球及圆柱的特征分别数一数各有几个,再填空即可。长方体:由六个长方形的面围成 (特殊的有两个正方形的面和四个长方形的面围成);正方体:由六个正方形的面围成;球:由一个曲面围成;圆柱:由两个圆和一个曲面围成.\n【详解】由题意分析得:\n\u003ctable\u003e\u003ctr\u003e\u003ctd\u003e长方体\u003c/td\u003e\u003ctd\u003e4个\u003c/td\u003e\u003c/tr\u003e\u003ctr\u003e\u003ctd\u003e正方体\u003c/td\u003e\u003ctd\u003e3个\u003c/td\u003e\u003c/tr\u003e\u003ctr\u003e\u003ctd\u003e球\u003c/td\u003e\u003ctd\u003e2个\u003c/td\u003e\u003c/tr\u003e\u003ctr\u003e\u003ctd\u003e圆柱\u003c/td\u003e\u003ctd\u003e2个\u003c/td\u003e\u003c/tr\u003e\u003c/table\u003e", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "22-23 一年级上·陕西延安·期末" + }, + { + "id": "363", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "数一数,填一填.\n![](images/0f16e9f05ff9e30a63f59aa3974acc8f6d273815c41d3baf0dc9bbac23a812e4.jpg)\n![](images/bb391a8b0178ed081242bfe2cd8e68e6a3b43fb7bcba579774c62984ff421b87.jpg)", + "options": [ + + ], + "answer": "5;2;8;1", + "solution": "【分析】根据长方体,正方形,圆柱及球的特征分别数一数各有几个,再填空即可。长方体:由 6 个长方形的面围成 (特殊的由 2 个正方形的面和 4 个长方形的面围成)。正方形:由 6 个正方形的面围成。圆柱:由 2 个平面(圆)和 1 个曲面围成。球:由 1 个曲面围成.\n【详解】由题意分析得:长方体5个,正方体2个,圆柱8个,球1个.", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "22-23一年级上·湖南岳阳·期末" + }, + { + "id": "364", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "找一找,填一填.\n![](images/e51d17124bf5ea29a61a34cc221d002f050bd9e7d64cf96d72b9762b64df6a0e.jpg)\n正方体有( )个,长方体有( )个,圆柱有( )个,球有( )个。", + "options": [ + + ], + "answer": "3;4;2;3", + "solution": "【分析】根据长方体,正方体,圆柱及球的特征,分别数一数各有几个,再填空即可.\n【详解】由题意分析得:正方体有3个,长方体有4个,圆柱有2个,球有3个.", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "20-21一年级上·四川甘孜·期末" + }, + { + "id": "365", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.65, + "question": "数一数,填一填,画一画.\n![](images/92340529d0abeeee780f78c7c4a3d8a11818d120d8a39c83b8d0d8fcda8d91dc.jpg)\n\u003ctable\u003e\u003ctr\u003e\u003ctd\u003e正方体\u003c/td\u003e\u003ctd\u003e长方体\u003c/td\u003e\u003ctd\u003e圆柱\u003c/td\u003e\u003ctd\u003e球\u003c/td\u003e\u003c/tr\u003e\u003ctr\u003e\u003ctd\u003e()个\u003c/td\u003e\u003ctd\u003e()个\u003c/td\u003e\u003ctd\u003e()个\u003c/td\u003e\u003ctd\u003e()个\u003c/td\u003e\u003c/tr\u003e\u003c/table\u003e", + "options": [ + + ], + "answer": "2;4;5;4", + "solution": "【分析】数一数可知:图中有 2 个正方体, 4 个长方体, 5 个圆柱, 4 个球,据此填空.\n【详解】\n\u003ctable\u003e\u003ctr\u003e\u003ctd\u003e正方体\u003c/td\u003e\u003ctd\u003e长方体\u003c/td\u003e\u003ctd\u003e圆柱\u003c/td\u003e\u003ctd\u003e球\u003c/td\u003e\u003c/tr\u003e\u003ctr\u003e\u003ctd\u003e2\u003c/td\u003e\u003ctd\u003e4\u003c/td\u003e\u003ctd\u003e5\u003c/td\u003e\u003ctd\u003e4\u003c/td\u003e\u003c/tr\u003e\u003c/table\u003e", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "22-23 一年级上·广东江门·期末" + }, + { + "id": "366", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "数一数填空.\n![](images/1ad38b2e783ed9b1c46d6ee2b0896322d60af1ef9757dbd1083800cc3e95219a.jpg)\n球( )个;正方体( )个;圆柱( )个;长方体( )个。", + "options": [ + + ], + "answer": "6;2;4;4", + "solution": "【分析】根据圆柱,正方体,长方体,圆柱的特征,分别数一数各有几个,再填空即可.\n【详解】由题意分析得:球6个;正方体 2个;圆柱 4个;长方体 4个.", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "21-22一年级上·河北张家口·期末" + }, + { + "id": "367", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "生活中微波炉的形状是( ).\n![](images/b55a9197ecda284c5c54c9733b80af3ab1168bb21f877862746c4bbb66942373.jpg)", + "options": [ + + ], + "answer": "长方体", + "solution": "【分析】长方体:由 6 个长方形的面围成,且相对的面完全一样;据此解答.\n【详解】由题意分析得:生活中微波炉的形状是长方体.", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "21-22 一年级上·河北张家口·期末" + }, + { + "id": "368", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "![](images/7607f029f59b5b94e16ef66eec0e830b31cba03d3aedbfc09e4e99df3ff058fd.jpg)\n(1)正方体有( )个,长方体有( )个,圆柱有( )个,球有( )个。 \n(2)( )的个数最多,( )的个数最少。", + "options": [ + + ], + "answer": "3;3;4;2;圆柱;球", + "solution": "【分析】(1)根据正方体,长方体,圆柱及球的特征分别数一数各有几个,再填空即可。(2) 先比较各种图形个数的多少,再找出个数最多的和最少的图形.\n【详解】由题意分析得:(1) 正方体有 3 个,长方体有 3 个,圆柱有 4 个,球有 2 个。(2) 4 \u003e 3 = 3 \u003e 2,圆柱的个数最多,球的个数最少。", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "21-22一年级上·陕西渭南·期末" + }, + { + "id": "369", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "数一数,填一填.\n![](images/f27f0c8720dbefcc6fbc996b59b4b4142914a37cf65fe49efb7da86682e239aa.jpg)\n\u003ctable\u003e\u003ctr\u003e\u003ctd\u003e形状\u003c/td\u003e\u003ctd\u003e长方体\u003c/td\u003e\u003ctd\u003e正方体\u003c/td\u003e\u003ctd\u003e圆柱\u003c/td\u003e\u003ctd\u003e球\u003c/td\u003e\u003c/tr\u003e\u003ctr\u003e\u003ctd\u003e个数\u003c/td\u003e\u003ctd\u003e()\u003c/td\u003e\u003ctd\u003e()\u003c/td\u003e\u003ctd\u003e()\u003c/td\u003e\u003ctd\u003e()\u003c/td\u003e\u003c/tr\u003e\u003c/table\u003e", + "options": [ + + ], + "answer": "2;4;3;3", + "solution": "【分析】根据长方体,正方体,圆柱及球的特征分别数一数各有几个,再填空.\n【详解】\n\u003ctable\u003e\u003ctr\u003e\u003ctd\u003e形状\u003c/td\u003e\u003ctd\u003e长方体\u003c/td\u003e\u003ctd\u003e正方体\u003c/td\u003e\u003ctd\u003e圆柱\u003c/td\u003e\u003ctd\u003e球\u003c/td\u003e\u003c/tr\u003e\u003ctr\u003e\u003ctd\u003e个数\u003c/td\u003e\u003ctd\u003e2\u003c/td\u003e\u003ctd\u003e4\u003c/td\u003e\u003ctd\u003e3\u003c/td\u003e\u003ctd\u003e3\u003c/td\u003e\u003c/tr\u003e\u003c/table\u003e", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "20-21 一年级上·安徽宿州·期末" + }, + { + "id": "370", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "![](images/6fc35d82f80323662724cc8b2c95ce1c05ae8ff73aab30c02a8b3964ce7229f7.jpg)\n\u003ctable\u003e\u003ctr\u003e\u003ctd\u003e正方体\u003c/td\u003e\u003ctd\u003e()个\u003c/td\u003e\u003c/tr\u003e\u003ctr\u003e\u003ctd\u003e球\u003c/td\u003e\u003ctd\u003e()个\u003c/td\u003e\u003c/tr\u003e\u003ctr\u003e\u003ctd\u003e圆柱\u003c/td\u003e\u003ctd\u003e()个\u003c/td\u003e\u003c/tr\u003e\u003ctr\u003e\u003ctd\u003e长方体\u003c/td\u003e\u003ctd\u003e()个\u003c/td\u003e\u003c/tr\u003e\u003c/table\u003e", + "options": [ + + ], + "answer": "2;3;2;2", + "solution": "【分析】根据球,长方体,圆柱,正方体的特征进行分类识别,再数出相应的数量,据此解答.\n【详解】由题意分析得:\n\u003ctable\u003e\u003ctr\u003e\u003ctd\u003e正方体\u003c/td\u003e\u003ctd\u003e2个\u003c/td\u003e\u003c/tr\u003e\u003ctr\u003e\u003ctd\u003e球\u003c/td\u003e\u003ctd\u003e3个\u003c/td\u003e\u003c/tr\u003e\u003ctr\u003e\u003ctd\u003e圆柱\u003c/td\u003e\u003ctd\u003e2个\u003c/td\u003e\u003c/tr\u003e\u003ctr\u003e\u003ctd\u003e长方体\u003c/td\u003e\u003ctd\u003e2个\u003c/td\u003e\u003c/tr\u003e\u003c/table\u003e", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "21-22 一年级上·陕西汉中·期末" + }, + { + "id": "371", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "数一数各种图形分别有几个,填在括号里.\n![](images/21370b955d4c251fb8c2e0db1bad3484b4756aa1ae4d96fa671f029fd6d38bba.jpg)\n\u003ctable\u003e\u003ctr\u003e\u003ctd\u003e正方体\u003c/td\u003e\u003ctd\u003e()个\u003c/td\u003e\u003c/tr\u003e\u003ctr\u003e\u003ctd\u003e长方体\u003c/td\u003e\u003ctd\u003e()个\u003c/td\u003e\u003c/tr\u003e\u003ctr\u003e\u003ctd\u003e圆柱\u003c/td\u003e\u003ctd\u003e()个\u003c/td\u003e\u003c/tr\u003e\u003ctr\u003e\u003ctd\u003e球\u003c/td\u003e\u003ctd\u003e()个\u003c/td\u003e\u003c/tr\u003e\u003c/table\u003e", + "options": [ + + ], + "answer": "3;2;3;2", + "solution": "【分析】按照正方体,长方体,圆柱及球的特征来数一数,各有几个,再填空即可.\n【详解】由题意分析得:\n\u003ctable\u003e\u003ctr\u003e\u003ctd\u003e正方体\u003c/td\u003e\u003ctd\u003e3个\u003c/td\u003e\u003c/tr\u003e\u003ctr\u003e\u003ctd\u003e长方体\u003c/td\u003e\u003ctd\u003e2个\u003c/td\u003e\u003c/tr\u003e\u003ctr\u003e\u003ctd\u003e圆柱\u003c/td\u003e\u003ctd\u003e3个\u003c/td\u003e\u003c/tr\u003e\u003ctr\u003e\u003ctd\u003e球\u003c/td\u003e\u003ctd\u003e2个\u003c/td\u003e\u003c/tr\u003e\u003c/table\u003e", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "21-22一年级上·江苏无锡·期末" + }, + { + "id": "372", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "数一数.\n![](images/8bd67e26251866d9b4e190b1621b71850f266115c51738fc52bb73bef2dc812e.jpg)\n\u003ctable\u003e\u003ctr\u003e\u003ctd\u003e长方体\u003c/td\u003e\u003ctd\u003e正方体\u003c/td\u003e\u003ctd\u003e圆柱\u003c/td\u003e\u003ctd\u003e球\u003c/td\u003e\u003c/tr\u003e\u003ctr\u003e\u003ctd\u003e()个\u003c/td\u003e\u003ctd\u003e()个\u003c/td\u003e\u003ctd\u003e()个\u003c/td\u003e\u003ctd\u003e()个\u003c/td\u003e\u003c/tr\u003e\u003c/table\u003e", + "options": [ + + ], + "answer": "3;1;4;2", + "solution": "【分析】根据长方体,正方体,圆柱及球的特征来数一数,各有几个,再填空即可.\n【详解】由题意分析得:\n\u003ctable\u003e\u003ctr\u003e\u003ctd\u003e长方体\u003c/td\u003e\u003ctd\u003e正方体\u003c/td\u003e\u003ctd\u003e圆柱\u003c/td\u003e\u003ctd\u003e球\u003c/td\u003e\u003c/tr\u003e\u003ctr\u003e\u003ctd\u003e3个\u003c/td\u003e\u003ctd\u003e1个\u003c/td\u003e\u003ctd\u003e4个\u003c/td\u003e\u003ctd\u003e2个\u003c/td\u003e\u003c/tr\u003e\u003c/table\u003e", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "21-22一年级上·江苏常州·期末" + }, + { + "id": "373", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "找一找,填一填.\n![](images/fada509f6724c54f10fc440c7f4daa10b382dfd82c9da7666087eca540d6fc7b.jpg)\n\u003ctable\u003e\u003ctr\u003e\u003ctd\u003e长方体\u003c/td\u003e\u003ctd\u003e()个\u003c/td\u003e\u003c/tr\u003e\u003ctr\u003e\u003ctd\u003e圆柱\u003c/td\u003e\u003ctd\u003e()个\u003c/td\u003e\u003c/tr\u003e\u003ctr\u003e\u003ctd\u003e正方体\u003c/td\u003e\u003ctd\u003e()个\u003c/td\u003e\u003c/tr\u003e\u003ctr\u003e\u003ctd\u003e球\u003c/td\u003e\u003ctd\u003e()个\u003c/td\u003e\u003c/tr\u003e\u003c/table\u003e", + "options": [ + + ], + "answer": "3;5;1;5", + "solution": "【分析】根据长方体,圆柱,正方体及球的特征来分别数一数各有几个,然后再填空即可.\n【详解】由题意分析得:\n\u003ctable\u003e\u003ctr\u003e\u003ctd\u003e长方体\u003c/td\u003e\u003ctd\u003e3个\u003c/td\u003e\u003c/tr\u003e\u003ctr\u003e\u003ctd\u003e圆柱\u003c/td\u003e\u003ctd\u003e5个\u003c/td\u003e\u003c/tr\u003e\u003ctr\u003e\u003ctd\u003e正方体\u003c/td\u003e\u003ctd\u003e1个\u003c/td\u003e\u003c/tr\u003e\u003ctr\u003e\u003ctd\u003e球\u003c/td\u003e\u003ctd\u003e5个\u003c/td\u003e\u003c/tr\u003e\u003c/table\u003e", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "22-23一年级上·江苏连云港·期末" + }, + { + "id": "374", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "数一数,填一填,画一画.\n![](images/65e53ff6d921db2e0fdad02dbd1a5ab18a5d939252337e6a715eb2d2ab2fa68b.jpg)\n\u003ctable\u003e\u003ctr\u003e\u003ctd\u003e长方体\u003c/td\u003e\u003ctd\u003e圆柱\u003c/td\u003e\u003ctd\u003e正方体\u003c/td\u003e\u003ctd\u003e球\u003c/td\u003e\u003c/tr\u003e\u003ctr\u003e\u003ctd\u003e()个\u003c/td\u003e\u003ctd\u003e()个\u003c/td\u003e\u003ctd\u003e()个\u003c/td\u003e\u003ctd\u003e()个\u003c/td\u003e\u003c/tr\u003e\u003c/table\u003e", + "options": [ + + ], + "answer": "5;3;2;6", + "solution": "【分析】先按照长方体,圆柱,正方体及球的特征来数一数,再填空即可.\n【详解】由题意分析得:长方体有 5 个,圆柱有 3 个,正方体有 2 个,球有 6 个。", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "21-22一年级上·江苏淮安·期末" + }, + { + "id": "375", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "数一数,填一填.\n![](images/50d63067711367bc949fb0970dd8eb2fe4d2e4b6fb848a4da5cf35aa65a11b93.jpg)\n长方体()个,正方体()个,球()个,圆柱()个。", + "options": [ + + ], + "answer": "4;1;2;4", + "solution": "【分析】先按照长方体,正方体,球及圆柱的特征分别数一数各有几个,再填空即可.\n【详解】由题意分析得:长方体4个,正方体1个,球2个,圆柱4个.", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "17-18一年级上·山东青岛·单元测试" + }, + { + "id": "376", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "数一数.\n![](images/313541cfceea4f88ae0b5b52ff332916f6af5cbef79d505d30d631a13a0fdff4.jpg)\n\u003ctable\u003e\u003ctr\u003e\u003ctd\u003e图形\u003c/td\u003e\u003ctd\u003e长方体\u003c/td\u003e\u003ctd\u003e正方体\u003c/td\u003e\u003ctd\u003e圆柱\u003c/td\u003e\u003c/tr\u003e\u003ctr\u003e\u003ctd\u003e个数\u003c/td\u003e\u003ctd\u003e()个\u003c/td\u003e\u003ctd\u003e()个\u003c/td\u003e\u003ctd\u003e()个\u003c/td\u003e\u003c/tr\u003e\u003c/table\u003e", + "options": [ + + ], + "answer": "4;2;3", + "solution": "【分析】按照长方体,正方体及圆柱的特征分别数一数,再填空即可.\n【详解】\n\u003ctable\u003e\u003ctr\u003e\u003ctd\u003e图形\u003c/td\u003e\u003ctd\u003e长方体\u003c/td\u003e\u003ctd\u003e正方体\u003c/td\u003e\u003ctd\u003e圆柱\u003c/td\u003e\u003c/tr\u003e\u003ctr\u003e\u003ctd\u003e个数\u003c/td\u003e\u003ctd\u003e4个\u003c/td\u003e\u003ctd\u003e2个\u003c/td\u003e\u003ctd\u003e3个\u003c/td\u003e\u003c/tr\u003e\u003c/table\u003e", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "20-21 一年级上·江苏南通·期末" + }, + { + "id": "377", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.65, + "question": "长方体有( )个面,圆柱的上下两个面都是( )形。", + "options": [ + + ], + "answer": "6;圆", + "solution": "【分析】长方体有6个面;圆柱:上下两个面为大小相同的圆形,有一个曲面叫侧面。据此解答.\n【详解】长方体有 6 个面,圆柱的上下两个面都是圆。", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "20-21 一年级上·江西吉安·期末" + }, + { + "id": "378", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.65, + "question": "下图有( )个正方体.\n![](images/7892bfb54338ab7047e09db851cbf36f93d028422e729e61d996e52f07b1c084.jpg)", + "options": [ + + ], + "answer": "10", + "solution": "【分析】从下往上,第一层有 6 个,第二层有 3 个,第三层有 1 个,将它们加起来即可求解.\n【详解】6 + 3 + 1 = 10 (个),所以有 10 个正方体.", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "21-22 二年级上·上海浦东新·期末" + }, + { + "id": "379", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.65, + "question": "在括号里分别填上每个图形的个数.\n![](images/f17e6f204632a072ff2586ac3da53c7aa9f4f90000fcb971b178265ae05ad010.jpg)\n长方体( )个,正方体( )个,球( )个,圆柱( )个。", + "options": [ + + ], + "answer": "4;1;2;4", + "solution": "【分析】对照对常见立体图形的认识按一定的次序辨别图形,计数时可以采取数一个划去一个的方法来计数,这样不重复不遗漏.\n【详解】长方体有 4 个;正方体有 1 个;球有 2 个;圆柱有4个.", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "21-22一年级上·甘肃酒泉·期末" + }, + { + "id": "380", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "长方体有( )个,圆柱有( )个,正方体有( )个,球有( )个.\n![](images/13043fea13114a21ad5e7702500271b913afbcd4153a545f0491fd25f3de06e0.jpg)", + "options": [ + + ], + "answer": "2;3;2;3", + "solution": "【分析】立体图形的特征:\n长方体:由六个长方形的面围成 (特殊的有两个正方形的面和四个长方形的面围成);正方体:由六个正方形的面围成;圆柱:由两个圆和一个曲面围成;球体:由一个曲面围成;据此解答.\n【详解】由题意得:长方体有 2 个,圆柱有 3 个,正方体有 2 个,球有 3 个.", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "22-23 一年级上·辽宁·期末" + }, + { + "id": "381", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "找一找,数一数.\n![](images/eed89e560aead47c61b35c8ad01340851d10f8815ecb21563b10706a190c299c.jpg)\n圆柱( )个,球( )个,正方体( )个,长方体( )个。", + "options": [ + + ], + "answer": "3;3;3;4", + "solution": "【分析】按照立体图形的特征来完成此题.\n长方体:由六个长方形的面围成 (特殊的有两个正方形的面和四个长方形的面围成);正方体:由六个正方形的面围成;圆柱:由两个圆和一个曲面围成;球体:由一个曲面围成.\n【详解】根据题意数一数可得:圆柱 (3) 个,球 (3) 个,正方体 (3) 个,长方体 (4)个.", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "22-23一年级上·江苏·期末" + }, + { + "id": "382", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.65, + "question": "数一数\n![](images/e8d20b9ee85c892c2fca704e345cf639769a66b712a4c64dd480d04077003bf1.jpg)\n正方体 ( )个,长方体( )个,球( )个,圆柱( )个。", + "options": [ + + ], + "answer": "4;5;5;3", + "solution": "【分析】根据正方体的特征:四四方方有 6 个面,6 个面都相等,摸起来有些地方平平的,有些地方尖尖,不能自由滚动;长方体的特征:长长方方的,有6个面,有些面大,有些面小,摸起来有些地方平平的,有些地方尖尖,不能自由滚动;球的特征:外表圆圆滑滑的,能自由滚动;圆柱体特征:直直的,上下一样粗细,站着不能滚动,躺着能滚动,两头摸起来是平平的,有些地方圆圆的。据此解答.\n【详解】正方体 (4) 个,长方体 (5) 个,球 (5) 个,圆柱 (3) 个.", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "22-23一年级上·全国·期末" + }, + { + "id": "383", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "数一数.\n![](images/3b347144a0e672eb2f85a47e5102cc7aa8c9c6fcd333878d01d10828751b9161.jpg)\n( )个正方体 ,( )个 长方体,( )个圆柱 ,( )个球。", + "options": [ + + ], + "answer": "5;6;2;3", + "solution": "【分析】根据立体图形的特征来完成此题。长方体:由六个长方形的面围成 (特殊的有两个正方形的面和四个长方形的面围成);正方体:由六个正方形的面围成;圆柱:由两个圆和一个曲面围成;球体:由一个曲面围成.\n【详解】由题意可得:\n![](images/98f9ed14742edd5f5e9a5b49dc68d43d605ac060deacf1e3171301ee3f992362.jpg)\n5个正方体 ,6个长方体 ,2个圆柱 ,3个球 .", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "22-23一年级上·江苏宿迁·期中" + }, + { + "id": "384", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.65, + "question": "数一数.\n![](images/2251928f8a370ef7ccceca22d5dfb33dca8e09226c40edade421de6b7b07c01e.jpg)\n长方体有( )个,正方体有( )个,圆柱有( )个,球有( )个", + "options": [ + + ], + "answer": "4;1;4;2", + "solution": "【分析】长方体:有 6 个面,每个面都由长方形或相对的一组正方形组成;正方体:有 6 个面,每个面都由正方形组成;圆柱:上下两个面为大小相同的圆形,有一个曲面叫侧面;球:球是生活中最常见的图形之一,例如篮球,足球都是球,球是由一个面所围成的几何体。据此数一数填空即可.\n【详解】\n![](images/be1e5e6a0530c50d61f718b706bde830aab3f91890312b5df74c136ba4954d53.jpg)\n长方体有4个,正方体有1个,圆柱有4个,球有2个", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "21-22一年级上·陕西安康·期末" + }, + { + "id": "385", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "乒乓球是( )体。", + "options": [ + + ], + "answer": "球", + "solution": "【分析】乒乓球是立体的,乒乓球在正常的状态下,不管是从哪一个方向都可以转动,而且乒乓球也具备球体的外形特征,也就是说乒乓球无论是从哪一个方向看,都是球体.\n【详解】根据我们对立体图形的认识,乒乓球的形状是球体.", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "21-22 一年级上·山东·单元测试" + }, + { + "id": "386", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.65, + "question": "![](images/8deeb0c7d8c9364a80f1fa51d7daeb010dcaed1da787c26a23f1f661da918fe0.jpg)\n圆柱有( ),长方体有( )。", + "options": [ + + ], + "answer": "①②⑧;③⑤", + "solution": "【分析】长方体:是长长方方的,有平平的面;圆柱:是直直的,上下一样粗细,两头是圆的,平平的:据此观察图形找出图形.\n【详解】圆柱有三个,分别是:①②⑧,长方体有两个,分别是:③⑤.", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "22-23 一年级上·全国·期中" + }, + { + "id": "387", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.65, + "question": "数一数.\n![](images/image-20251206144855372.png)\n长方体有( )个,正方体有( )个,圆柱有( )个,球有( )个。", + "options": [ + + ], + "answer": "2;2;3;1", + "solution": "【分析】长方体四四方方,有平平的面;正方体四四方方,6 个面完全相同;圆柱上下两个面是圆,侧面是曲面,平放易滚动;球表面是曲面,易滚动。依此分类并计数.\n【详解】根据分析:长方体有 2 个,正方体有 2 个,圆柱有 3 个,球有 1 个。", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "21-22一年级上·湖北孝感·期末" + }, + { + "id": "388", + "unit": "第三单元 认识立体图形", + "question_type": "判断题", + "difficulty": 0.65, + "question": "只有球能滚动,圆柱不能滚动。( )", + "options": [ + + ], + "answer": "×", + "solution": "【分析】球由一个曲面组成,最容易滚动;圆柱由两个相对的平平的面和一个曲面组成,比较容易滚动;据此判断.\n【详解】根据分析可知,球能滚动,圆柱也能滚动。故答案为: ×", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "23-24 一年级上·上海·单元测试" + }, + { + "id": "389", + "unit": "第三单元 认识立体图形", + "question_type": "判断题", + "difficulty": 0.85, + "question": "电冰箱是长方体。( )", + "options": [ + + ], + "answer": "√", + "solution": "【分析】根据长方体是长长方方的,有平平的面,无法滚动判断可知.\n【详解】根据分析可知,电冰箱是长方体,原题说法正确。故答案为: √", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "22-23 一年级上·四川·单元测试" + }, + { + "id": "390", + "unit": "第三单元 认识立体图形", + "question_type": "判断题", + "difficulty": 0.85, + "question": "球上有许多平平的面。( )", + "options": [ + + ], + "answer": "×", + "solution": "【分析】球是由一个曲面围成的;据此判断.\n【详解】由题意分析得:球上有许多平平的面;此说法错误。故答案为: ×", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "21-22 一年级下·河北·单元测试" + }, + { + "id": "391", + "unit": "第三单元 认识立体图形", + "question_type": "判断题", + "difficulty": 0.65, + "question": "乒乓球,篮球,排球都是球体。( )", + "options": [ + + ], + "answer": "√", + "solution": "【分析】球是由一个面所围成的几何体,到定点距离相等的几何体.\n【详解】根据分析可得,乒乓球,篮球,排球都是球体。故答案为: √", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "21-22 一年级下·北京·单元测试" + }, + { + "id": "392", + "unit": "第三单元 认识立体图形", + "question_type": "判断题", + "difficulty": 0.85, + "question": "数学课本是长方形。( )", + "options": [ + + ], + "answer": "×", + "solution": "【分析】长方体有 8 个顶点, 6 个面,每个面都由长方形或相对的一组正方形组成,据此特征判断.\n【详解】据分析可知:数学课本是一个长方体。所以原题说法错误。故答案为: ×", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "22-23 二年级下·山东·单元测试" + }, + { + "id": "393", + "unit": "第三单元 认识立体图形", + "question_type": "判断题", + "difficulty": 0.85, + "question": "![](images/9d705d42289dcf449edbb1e5b907ba5cd5bf84481dbc477355a76bf2fd723ff5.jpg)不容易滚动。( )", + "options": [ + + ], + "answer": "√", + "solution": "【分析】正方体由 6 个平平的面组成,每个面都是正方形,不易滚动;据此判断.\n【详解】由题意分析得:图中正方体不易滚动,此说法正确。故答案为: √", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "21-22一年级上·河北张家口·期末" + }, + { + "id": "394", + "unit": "第三单元 认识立体图形", + "question_type": "判断题", + "difficulty": 0.65, + "question": "在长方体,正方体,圆柱,球中,圆柱最容易滚动。( )", + "options": [ + + ], + "answer": "×", + "solution": "【分析】正方体:6个面,每个面都由正方形组成;长方体: 6 个面,每个面都由长方形或相对的一组正方形组成;圆柱:上下两个面为大小相同的圆形,有一个曲面叫侧面;球:是生活中最常见的图形之一,例如篮球,足球都是球,据此特征判断.\n【详解】在长方体,正方体,圆柱,球中,球最容易滚动。原题说法错误。故答案为: ×", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "20-21 一年级上·湖北十堰·期末" + }, + { + "id": "395", + "unit": "第三单元 认识立体图形", + "question_type": "判断题", + "difficulty": 0.85, + "question": "![](images/e4ef38af8930499f8f6615d92bde7a9ed6988c864a87a3cb15f29bdd008c996c.jpg)它不是一个球体。()", + "options": [ + + ], + "answer": "√", + "solution": "【分析】握在手里感觉圆溜溜的,鼓鼓的,滑滑的,容易滚动。据此判断.\n【详解】![](images/1da4c649be7929b77ddc29572e3a7675c9d5d85a3e2f11663575a71791aedb78.jpg)不是一个球体,说法正确。故答案为: √", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "20-21 一年级上·江西吉安·期末" + }, + { + "id": "396", + "unit": "第三单元 认识立体图形", + "question_type": "判断题", + "difficulty": 0.85, + "question": "![](images/9ed868e5b546656ba98e7ad518b158e0862217db0eb861cc8fad69c560086702.jpg)这是一个篮球,可以滚动。()", + "options": [ + + ], + "answer": "√", + "solution": "【分析】根据图片判断,并根据球的特点做题.\n【详解】图片是个篮球,而且可以滚动,原题说法正确。故答案为:√.", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "22-23一年级上·辽宁·单元测试" + }, + { + "id": "397", + "unit": "第三单元 认识立体图形", + "question_type": "判断题", + "difficulty": 0.94, + "question": "搭积木时,球最容易滚动。( )", + "options": [ + + ], + "answer": "√", + "solution": "【分析】球是由曲面围成的立体图形,所以最容易滚动。据此进行判断即可.\n【详解】立体图形中球最容易滚动,可联系学生生活实际理解,平常打球都应该见过球最容易滚动。所以搭积木时,球最容易滚动。故答案为: √ .", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "21-22 一年级上·山东·单元测试" + }, + { + "id": "398", + "unit": "第三单元 认识立体图形", + "question_type": "解答题", + "difficulty": 0.85, + "question": "单凭一个面能不能确定是什么物体。", + "options": [ + + ], + "answer": "不能", + "solution": "【分析】比如正方体的六个面都是正方形,看到的其中一个面是正方形;在长方体中,也可能有两个面是正方形,如果看到的是长方体中的正方形这一面,以此来判断它是正方体就是错误的,据此解答即可.\n【详解】由分析可得:答:单凭一个面不能确定是什么物体,因为这个立体图形可能是正方体,也可能是一个面是正方形的长方体.", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "22-23二年级上·全国·随堂练习" + }, + { + "id": "399", + "unit": "第三单元 认识立体图形", + "question_type": "解答题", + "difficulty": 0.85, + "question": "一个面是正方形,请猜一猜它可能是我们学过的哪个立体图形。", + "options": [ + + ], + "answer": "长方体,正方体", + "solution": "【分析】由题意可知,正方体的 6 个面都是正方形,长方体也有 6 个面,这 6 个面一般都是长方形,但也有特殊的情况,就是 4 个面为长方形,另外 2 个面为正方形,据此解答即可.\n【详解】由分析可得:答:一个面是正方形,有可能是我们学过的长方体或者正方体.", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "22-23 二年级上·全国·随堂练习" + }, + { + "id": "400", + "unit": "第三单元 认识立体图形", + "question_type": "解答题", + "difficulty": 0.65, + "question": "![](images/7772c6519f8a550c61a36460555caff89266f30f41d0a8cbadd855f1092745d9.jpg)\n长方体( )个,正方体( )个,圆柱( )个,球( )个。", + "options": [ + + ], + "answer": "1;3;6;7", + "solution": "【分析】根据图片数出对应立体图形的个数即可.\n【详解】由图可知:长方体有 1 个,正方体有 3 个,圆柱有 6 个,球有 7 个.", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "22-23一年级上·全国·课后作业" + }, + { + "id": "401", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "下面几组图形中,能站稳的是哪组。 ( )", + "options": [ + "A. ![](images/9fb46e013cde7fc5ef1763ed99864fffd1255f1a9b943dd84bd22df0a23bf188.jpg)", + "B. ![](images/cc0ef1b7203fab702d91922e780ddb90b4b672160e6f1813f8fe44d3eb977d57.jpg)", + "C. ![](images/1550a05cc0ca36e2cdd964b72a1354cf6e3d72a09d9be8cc6fb9542d92a1be74.jpg)" + ], + "answer": "B", + "solution": "【分析】长方体,正方体具有稳定性,球体不具有稳定性,圆柱平时也不稳定。据此选择即可.\n【详解】由分析可知:B 项的下面是一个正方体,则 B 项的图形较稳定。故答案为: B", + "knowledge_points": [ + "组合图形的稳定性" + ], + "source": "21-22 一年级上·福建宁德·期末" + }, + { + "id": "402", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.65, + "question": "用下面 ( ) 立体图形能方便画出圆。", + "options": [ + "A. ![](images/9fc233ebd906d964c957e8770ff6355d2e66b8fc486dcffec3a5942ce98cfa09.jpg)", + "B. ![](images/a316da17b6b8a49349eb938952b56caef8e47635053d566bc27cd8dda1dc92d9.jpg)", + "C. ![](images/fe9559e5841d518948d6901daa4beb02f73ad12d14652db3fbb98691975c7e00.jpg)" + ], + "answer": "A", + "solution": "【分析】圆柱上下两个面是圆,可以用底面描出圆;正方体、长方体的面是正方形或长方形.\n【详解】圆柱的底面是圆,能方便画出圆。故答案为: A", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "20-21 一年级下·宁夏银川·期末" + }, + { + "id": "403", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.65, + "question": "用 4 个小正方体可以拼成( )号图形。", + "options": [ + "A. ![](images/3b47aa65b308c4771db298630ae20f79d69101ca3fc1dce24051cfff9ebfa6d5.jpg)", + "B. ![](images/163e8819458c45b91ec4334a3db3bea0fc720e8992f7dbde3be10790a23d74f5.jpg)", + "C. ![](images/03c354306577b52294ca9f7db2b647cec293527b6d092bdfa239dd0acda6d229.jpg)" + ], + "answer": "A", + "solution": "【分析】分层数各选项中的小正方体个数,找出正好由 4 个小正方体拼成的图形.\n【详解】选项 A:下层 3 个 + 上层 1 个,共 4 个;选项 B:下层 3 个 + 上层 2 个,共 5 个;选项 C:至少有 6 个。故答案为: A", + "knowledge_points": [ + "立体图形的切拼", + "立体图形的认识" + ], + "source": "21-22一年级上·河北张家口·期末" + }, + { + "id": "404", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "选择叠起来最稳的物体。( ) ![](images/a9e82ce3388fa01b97ea33a47d126aee.png)", + "options": [ + "A", + "B", + "C", + "D" + ], + "answer": "D", + "solution": "【分析】粗细均匀且每个面都是平面的立体图形叠起来最稳.\n【详解】A。![](images/64b7aafefe5aef3ba2e35ab7b23fd270f6afe595f328e70ad28203eacf1f8ee1.jpg), 此图由 1 个曲面和 2 个平平的面(圆) 围成,图形粗细不均匀,把这样的图形叠起来,则不太稳。B。![](images/f09d538e58c8a0f0b90565b0d6a5d13e48606771be3ccb771367ff7b3689c469.jpg),此图由1个曲面和2个平平的面(圆)围成,若是把这样的图形叠起来,按此情况(![](images/f09d538e58c8a0f0b90565b0d6a5d13e48606771be3ccb771367ff7b3689c469.jpg))叠起来,则不太稳。C。![](images/542afd70c5ad0b730582804edd799a308d9b8592752c05168745635040b6488c.jpg), 此图由 1 个曲面和 1 个平平的面 (圆) 围成,图形粗细不均匀,把这样的图形叠起来,则不太稳。D。![](images/d83572014e3c1e5338e1cadb2ed07549e7a68023d8f9a9b25dd69199ee7c9f1c.jpg), 此图由 6 个平平的面 (6 个长方形) 围成,图形粗细均匀,把这样的图形叠起来,最稳。故答案为: D", + "knowledge_points": [ + "组合图形的稳定性" + ], + "source": "23-24 一年级上·浙江·单元测试" + }, + { + "id": "405", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.65, + "question": "要拼成一个大正方体,下面的图形至少还要 ( ) 个 正方体。![](images/20325c0ca5cbd65452302dbd150aabbe0c46a903a18de86121391426c348c2a2.jpg)", + "options": [ + "A. 7", + "B. 6", + "C. 5" + ], + "answer": "A", + "solution": "【分析】要拼成边长为 3 的大正方体,共需 3×3×3=27 个小正方体;用现有个数作差即可.\n【详解】大正方体需 27 个,图中现有 20 个,27 - 20 = 7 (个)。故答案为: A", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "20-21 一年级上·浙江宁波·期末" + }, + { + "id": "406", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.65, + "question": "![](images/a8662352674d269570d820fc06a8fc20221ab6ade578f79c810972bfae0870bb.jpg)有( )个正方体。", + "options": [ + "A. 7", + "B. 8", + "C. 9" + ], + "answer": "A", + "solution": "【分析】根据组合图形的计数即可解答.\n【详解】分层数一数,图中共有 7 个正方体。故答案为: A", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "21-22 一年级上·四川南充·期末" + }, + { + "id": "407", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.65, + "question": "下面四个物体,哪个物体滚得最快。( )", + "options": [ + "A. 球", + "B. 正方体", + "C. 长方体", + "D. 圆柱" + ], + "answer": "A", + "solution": "【分析】正方体:有 8 个顶点, 6 个面,每个面面积相等(或每个面都是正方形);长方体:有 8 个顶点, 6 个面,每个面都由长方形或相对的一组正方形组成;圆柱:上下两个面为大小相同的圆,有一个曲面叫侧面;球:球是生活中最常见的图形之一,例如篮球,足球都是球,球是由一个面所围成的几何体。据此特征可知球和圆柱易滚动,球最快.\n【详解】下面四个物体,球滚得最快。故答案为: A", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "21-22 一年级上·福建宁德·期末" + }, + { + "id": "408", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.65, + "question": "下列图形是圆柱体的是 ( )。", + "options": [ + "A. ![](images/7227dc84f2ddacb6bf4b53df3f1a079377b1c3f78af9f8898f9c7ad18e209315.jpg)", + "B. ![](images/790cf778d1d7efe8daf18eac2f3f08b3a9abf48ac1b20a70b3e9acdbe1e2c265.jpg)", + "C. ![](images/cd2730ea9ea47c49095fea4014741eb132823e925df4cf4d518416be21dcf4b6.jpg)" + ], + "answer": "C", + "solution": "【分析】圆柱体有两个完全相同的圆形底面,侧面是曲面.\n【详解】选项 A、B 不符合圆柱体特征;选项 C 上下两个面是圆,侧面是曲面,是圆柱体。故答案为: C", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "20-21一年级上·湖南张家界·期末" + }, + { + "id": "409", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.65, + "question": "它方方正正的,有 6 个同样大小的面,它是( )。", + "options": [ + "A. 正方体", + "B. 球", + "C. 圆柱", + "D. 长方体" + ], + "answer": "A", + "solution": "【分析】 正方体方方正正的;圆柱长长的,圆圆的,可以滚;球圆圆的,滚的最快;长方体长长的,滚不动;据此解答.\n【详解】它方方正正的,有 6 个同样大小的面,它是正方体 。故答案为: A", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "20-21一年级上·福建漳州·期末" + }, + { + "id": "410", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.65, + "question": "哪组站得稳。( )", + "options": [ + "A. ![](images/e9e097897429c5e992c7d1e5aaffa22d956e3e1898115673130f49b0da48e0a6.jpg)", + "B. ![](images/8943930c6935deba4956bc6e17ad06395238cfaa2ec77696a9fcbc2ddc0ec4be.jpg)", + "C. ![](images/327cc5296df16fce8749dde27b614c9c2b0034f8d9e2dc4f78087eae547abd8b.jpg)" + ], + "answer": "B", + "solution": "【分析】图形稳定的关键是下面用平平的面支撑,上面尽量不用易滚动的图形.\n【详解】B 项下面为正方体,接触面平平的,站得最稳。故答案为: B", + "knowledge_points": [ + "组合图形的稳定性" + ], + "source": "20-21一年级上·四川德阳·期末" + }, + { + "id": "411", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "6 个正方体能拼成一个大的正方体吗。( )", + "options": [ + "A. 不能", + "B. 能" + ], + "answer": "A", + "solution": "【分析】拼成完整的大正方体需要 2×2×2=8 个或 3×3×3=27 个等完全立方数个正方体.\n【详解】6 个正方体无法拼成一个完整的大正方体。故答案为: A", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "20-21一年级上·四川德阳·期末" + }, + { + "id": "412", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "我们要画一个圆形,可以借用下面图形( )。", + "options": [ + "A. ![](images/2bbb883949e27e21123c9adb1b38c81eb5965f8965835fef89c773a108bccc9f.jpg)", + "B. ![](images/65426ae4e5a2541a070522f0eedb34e4bcaf7a0f413f43c5651da60edfaec691.jpg)", + "C. ![](images/a852f2117ef9df197de76501966054262e7c9a07d260e03ee1e47067500065ac.jpg)" + ], + "answer": "C", + "solution": "【分析】含有圆形面的立体图形,可以用其底面描出圆.\n【详解】圆柱(或圆锥)的底面是圆,可以方便地画出圆形;长方体、正方体的面是长方形或正方形。故答案为: C", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "20-21 二年级上·湖北襄阳·期末" + }, + { + "id": "413", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.65, + "question": "下面( )组积木站得稳。", + "options": [ + "A", + "B", + "C" + ], + "answer": "C", + "solution": "【分析】长方体是长长方方的,面都是平的,不易滚动,站的最稳;圆柱上下是圆且上下一样粗,上下平平的面不易滚动,侧面是曲面容易滚动;球没有平面可以任意方向滚动;根据立方体图形的特征解决此题即可.\n【详解】A。![](images/8ae80b38e4651b03847d675e9b322aae5d5accf7f4f3accb8251918021b875e3.jpg)左图的球易滚动,搭不稳,不符合题意;B。![](images/ee3bb8e6b5d37bf6626494efa65d4a285d7b05d92d6f6ca3691f7c207ff06ce0.jpg)左图的球易滚动,搭不稳,不符合题意;C。![](images/b9c3a50d0fbfac5ec01a475a398cdbc1f578852759ab48119a2698df6856d794.jpg)左图长方体与地面接触面及长方体和圆柱之间的接触面都是平平的面,不易滚动,搭得稳,符合题意。故答案为: C", + "knowledge_points": [ + "组合图形的稳定性" + ], + "source": "20-21 一年级上·浙江杭州·期中" + }, + { + "id": "414", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.65, + "question": "下面拼法,哪种最稳。( )", + "options": [ + "A. ![](images/78be60527f6873a061a3a947c8f04330b1fb8ea4f548beeb7bfec31ddaf10eb4.jpg)", + "B. ![](images/6a7e967a59050749ce7b7374756879cc749425be45ae358241c1fa418d7d870f.jpg)", + "C. ![](images/9f2ef8b868c3f026766e4e0d1824c50706930319d7690d56601ac7f758467860.jpg)" + ], + "answer": "C", + "solution": "【分析】要搭得比较稳定,就要把面比较平且比较大的图形放在下面;长方体、正方体在下面搭得比较稳定,圆柱竖着放才能平稳;球容易滚动,不能放在下面.\n【详解】由分析可知,C 项最稳。故答案为: C", + "knowledge_points": [ + "组合图形的稳定性" + ], + "source": "21-22 一年级上·河南濮阳·期末" + }, + { + "id": "415", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.65, + "question": "下面图形中,用( )能在纸上画出圆形。 ![](images/ebfd334249f6c448426958d8571ff641.png)", + "options": [ + "A. ①", + "B. ②", + "C. ③", + "D. ④" + ], + "answer": "C", + "solution": "【分析】①六个面都是长方形,所以不能画出圆;②六个面都是正方形,所以不能画出圆;③上下两个面是圆,所以可以画出圆;④每个面都是三角形,所以不能画出圆;据此解答即可.\n【详解】①六个面都是长方形,所以不能画出圆;② 六个面都是正方形,所以不能画出圆;③上下两个面是圆,所以可以画出圆;④ 每个面都是三角形,所以不能画出圆。故答案为: C", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "20-21 一年级下·广东清远·期末" + }, + { + "id": "416", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.65, + "question": "有两个面是圆的物体是( )。", + "options": [ + "A. ![](images/16e3e44fa0cbd4239611515b3da817d3142c1c336e5587336b791f7422948ce8.jpg)", + "B. ![](images/585099c1f2079c5ae23bfae368f3d67aac8e22d94f5a43b93a454dc8403edc8f.jpg)", + "C. ![](images/d1cb993c584a8472d93fa1cffb24ed9ff4956b2a9cb761f1112295a6606e42d3.jpg)" + ], + "answer": "A", + "solution": "【分析】圆柱上下两个底面是圆形.\n【详解】A 是圆柱,有两个圆面;B 是长方体,面是长方形或正方形;C 是三棱柱,面是三角形和长方形。故答案为: A", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "20-21一年级下·河南鹤壁·期中" + }, + { + "id": "417", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.65, + "question": "下面 ( ) 物体可以画出正方形。", + "options": [ + "A. ![](images/c2cb042ad4bb8dd04b750492b63c87be54ea6a5fdde4445d9c125bc8e645241f.jpg)", + "B. ![](images/c7094367e58c9120cbdc6aadd4c8584d67bfa52f8bc8c7504e9411468fb72da5.jpg)", + "C. ![](images/f6306bf6a93d23c02298619944be563ee0469bdac8750a0e67396414e59e6468.jpg)" + ], + "answer": "B", + "solution": "【分析】正方体的每个面都是正方形,沿一个面描边可以画出正方形;球只能画出圆.\n【详解】A 是长方体,主要面是长方形;B 是正方体,每个面都是正方形,能画出正方形;C 是球,只能画出圆。故答案为: B", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "20-21 一年级下·福建莆田·期末" + }, + { + "id": "418", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "每个面都是长方形的物体是( )。", + "options": [ + "A. ![](images/347c4f7e46d97245abbad7e4beb05e077f80317055b0b08aa32c26d9799f0f21.jpg)", + "B. ![](images/6d1a4e8785da561ffee9d1acf101229a39826b41f4325fe02860495015945db8.jpg)", + "C. ![](images/f0d20c845876bfba7555056a31d63e5cf2b36979265892c02f270ab273052e37.jpg)" + ], + "answer": "B", + "solution": "【分析】长方体 6 个面都是长方形;圆柱有圆形底面;三棱柱有三角形面.\n【详解】A 是圆柱,有圆形底面;B 是长方体,6 个面都是长方形;C 是三棱柱,有三角形面。故答案为: B", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "21-22一年级下·湖北省直辖县级单位·单元测试" + }, + { + "id": "419", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.65, + "question": "下面图形中,可以画出圆的图形是( )。", + "options": [ + "A. ![](images/31f21ce1dfb4bf98d7cb945bd1ba02fa98900cc8cea0e39c9a51f6fd73ae8bf7.jpg)", + "B. ![](images/18bb1b52f5abc9756744ab31ca29f320c6ba227475e687983753a249307c75b2.jpg)", + "C. ![](images/aadc1dc85337f10703e42d464ba1302feb76ec20a1610c5c0a08ff091f68cbf1.jpg)", + "D. ![](images/ad02fff66391eabfbaffde0e36ff0c2d82ecfd159d49076352beb30da9bca873.jpg)" + ], + "answer": "C", + "solution": "【分析】可逐项分析,确定每个立体图形能够画出的平面图形,再做选择.\n【详解】A。正方体能够画出正方形;B. 长方体,能够画出长方形或正方形;C. 圆柱,能够画出圆;D. 长方体,能够画出长方形或正方形。故答案为: C", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "20-21 一年级上·内蒙古呼伦贝尔·期末" + }, + { + "id": "420", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.65, + "question": "搭积木时,下面最适合做轮子的是哪个物体。( )", + "options": [ + "A. ![](images/34b18edef14b110fb7817fbd8881eca5f2e531d90121a08ab381acfa36ecdd43.jpg)", + "B. ![](images/22317655eae4dc68393eb04b4320efe8b01ddd70eafc72a374fca325992fc0d2.jpg)", + "C. ![](images/b2b73ea749ee8123de74a636c1f2795dcae93ea58d75b9d65fab6b9c2751f98e.jpg)" + ], + "answer": "C", + "solution": "【分析】由题可知,三个选项中的立体图形分别是长方体,正方体,圆柱体,选择易滚动的立体图形最适合做轮子,据此解答即可.\n【详解】A。长方体:不易滚动,不适合做轮子。B。 正方体:不易滚动,不适合做轮子。 C. 圆柱体:易滚动,适合做轮子。故答案为: C", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "20-21 一年级上·江苏盐城·期末" + }, + { + "id": "421", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.65, + "question": "下面()不是同一类的。", + "options": [ + "A. ![](images/8330f50c4926cf1b39c65c533f89833e3dee3b0e2e4c9aa39a4efeb51d4a41d2.jpg)", + "B. ![](images/a5b086c12d3c59b51d93ff5d362616747dd8261f3491bc31dd9a50fec02e5dd5.jpg)", + "C. ![](images/6ac69ff4e5b889518e616c72c88fc4cd9d2786bf6357188fdfc8ad3eb42f7a05.jpg)", + "D. ![](images/c9012749bf5fa66a844b77f522f50277d0d6d6f864a2ac4e0607da3a228ce3e0.jpg)" + ], + "answer": "C", + "solution": "【分析】A、B、D 都是立体图形,C 是平面图形长方形.\n【详解】A 圆柱、B 长方体、D 正方体都是立体图形;C 是长方形,属于平面图形,不是同一类。故答案为: C", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "21-22一年级上·吉林·期末" + }, + { + "id": "422", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "![](images/7bbd9c36ef4fb29d119fb20ab0443ac718153f20cc049ec168496146525d6d95.jpg)左图由多少个正方体拼成。( )", + "options": [ + "A. 8 个", + "B. 7 个", + "C. 6 个" + ], + "answer": "A", + "solution": "【分析】分层计数,注意被遮挡的小正方体不要漏数.\n【详解】分层数一数,共有 8 个小正方体。故答案为: A", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "20-21 一年级上·四川绵阳·期末" + }, + { + "id": "423", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "能任意滚动的是 ( )。", + "options": [ + "A. 长方体", + "B. 正方体", + "C. 球" + ], + "answer": "C", + "solution": "【分析】球只有一个曲面,可以向任意方向滚动;长方体和正方体有平平的面,不易滚动.\n【详解】球能任意滚动;长方体和正方体不易滚动。故答案为: C", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "21-22 一年级上·湖南怀化·期中" + }, + { + "id": "424", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "可以滚动还可以立起来的是( )。", + "options": [ + "A. ![](images/2a5d2c7b6520ee482671f112d0e20dfb375a8470a9a96c34db0756135dd27d2e.jpg)", + "B. ![](images/83e3785e233680e47b5d6a484999af6047d689753f0d131a6f07d1bd0a38dd68.jpg)", + "C. ![](images/1ff05fefaed1919465ed4a18e0dfd09147c6a59001567d9b0f70817500c18bee.jpg)" + ], + "answer": "C", + "solution": "【分析】根据对长方体,圆柱体,正方体的认识进行分析即可.\n【详解】长方体和正方体可以立起来,放倒后也不容易滚动;圆柱体可以立起来,放倒后很容易滚动。故答案为: C", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "21-22一年级上·辽宁·单元测试" + }, + { + "id": "425", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "是圆柱的是 ( )。", + "options": [ + "A. ![](images/a1051cd4f4610638d0cb1412b138e9bac9b3ade4623b3f339dd65889c03ed698.jpg)", + "B. ![](images/38b1683ae1f076203b497f6e147d38d793695c2bed819e3f4a460318838ab91.jpg)", + "C. ![](images/ed55267361885599b2683177721fdfdefdb344b8075d6ab5be4eea48cbaaa526.jpg)" + ], + "answer": "B", + "solution": "【分析】圆柱上下两个面是圆形,侧面是曲面.\n【详解】选项 B 上下两个面是圆,侧面是曲面,是圆柱。故答案为: B", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "21-22 一年级上·辽宁·单元测试" + }, + { + "id": "426", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "把一个圆柱锯 2 次,可以锯成()个圆柱。", + "options": [ + "A. 2", + "B. 3", + "C. 4" + ], + "answer": "B", + "solution": "【分析】圆柱:能像柱子一样立着,还能滚动,是直直的,上下一样粗细,两头都是圆圆的平平的面。生活中,![](images/53fce59877eb2b5a82a9c28573b9a055d2f442fb1dc6da56ca160ebb152e4fd6.jpg)这些物体都是圆柱。把一个圆柱锯 2 次,可以这样锯,如图:![](images/096d255bd88849c212eb6148afa5656bdf98f5cfe84e627849bee771366048dc.jpg)\n【详解】由分析可得,把一个圆柱锯 2 次,可以锯成 3 个圆柱。故答案为: B", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "21-22 一年级上·辽宁·单元测试" + }, + { + "id": "427", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "下面物体既可以滚动,又可以稳定地搭一搭的是 ( )。", + "options": [ + "A. ![](images/a761799c38b1d3ad34914a1b8b8f98a8ecfe5894a8e3a8917e7e31c97f19115d.jpg)", + "B. ![](images/01785be4b72a68f9bc0a8ba7d04544761e27670c9b97ce06481abd0722379dd2.jpg)", + "C. ![](images/4b6b99afcaa9f8a0b7b3a57991e321573ac380f2c3faa6c30aaae857b785a2d3.jpg)" + ], + "answer": "B", + "solution": "【分析】圆柱侧面可以滚动,两端的圆面是平平的,可以稳定搭放.\n【详解】圆柱既可以滚动,又能用平平的底面放稳;球易滚动但不易放稳;长方体不易滚动。故答案为: B", + "knowledge_points": [ + "组合图形的稳定性" + ], + "source": "21-22 一年级上·辽宁·单元测试" + }, + { + "id": "428", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.94, + "question": "下面物体是圆柱的是 ( )。", + "options": [ + "A. ![](images/4253edf644547f8e6d3241af0a157f415be821731ed50a6e9cf324dba15d5dd6.jpg)", + "B. ![](images/7a01eea85ba2c67b393fd44dad7144fb2bc72bc0e55d272085b3d104d7b2ce97.jpg)", + "C. ![](images/8d25d1bf1372b3563cfaafa36ad2b02b7363b1ef528de7eeeb4405e57717cd9b.jpg)" + ], + "answer": "B", + "solution": "【分析】圆柱有两个大小相同的圆形底面和一个曲面侧面.\n【详解】选项 B 符合圆柱的特征。故答案为: B", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "21-22 一年级上·河北·期中" + }, + { + "id": "429", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.65, + "question": "能放稳的是 ( )。", + "options": [ + "A. ![](images/2a0b820ae0b427c58b408a22cba57f9e4170e1771a67abc9c9ca20f5689e1d29.jpg)", + "B. ![](images/c9e1be1da0d1ea1428b606964de93d4cd7e67b6f859ec847cbe4d7fccb18a0c5.jpg)", + "C. ![](images/7ddfeb6a8eff7b915408b457a2465145245142d3f13c911029e4573f71e5d5b7.jpg)" + ], + "answer": "A", + "solution": "【分析】长方体能放稳,圆柱体的侧面和球体的任意面都不能稳定的放在平面上,有滚动的可能;据此解答.\n【详解】根据分析:A. 是长方体在下面,能放稳;B. 是球体在下面,不能放稳;C. 是圆柱体的侧面在下面,不能放稳。故答案为: A", + "knowledge_points": [ + "组合图形的稳定性" + ], + "source": "20-21 一年级上·吉林松原·期中" + }, + { + "id": "430", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "能放稳的是 ( )。", + "options": [ + "A. ![](images/0181c9b1c550d65d1ec7813d9cd0186ebe34af50a573578aed8a6c205fca75ab.jpg)", + "B. ![](images/a50944159de451e9e037e1117dae59d81be283800731228d5fba721fb37a5cdc.jpg)", + "C. ![](images/2097d63d4b61191944f9f808e9d0a07e33492a429bbd026cfd73b4727cea2688.jpg)", + "D. ![](images/d640b2b0b48d3ce8b27d0304eaa38a3b1b4255ae40722272387669415b244cd8.jpg)" + ], + "answer": "A", + "solution": "【分析】长方体有平平的面,放在下面最稳;球和圆柱的侧面是曲面,不易放稳.\n【详解】选项 A 是长方体,能放稳;球和圆柱侧面在下面都不稳。故答案为: A", + "knowledge_points": [ + "组合图形的稳定性" + ], + "source": "21-22 一年级上·全国·期中" + }, + { + "id": "431", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "能滚动又能放稳的是 ( )。", + "options": [ + "A. ![](images/8719faf419f38ab49db561ac5a323f588c35d4df7ce078a6eaee4cd1d714fc30.jpg)", + "B. ![](images/a1181132f230bc5fde7abf206a457755f237c155638fd5140ee7ce4466259137.jpg)", + "C. ![](images/2ca5ec8a0206e48f3d335263e2d1f78a2eb3e758fea41b9db20f893857045eb1.jpg)" + ], + "answer": "C", + "solution": "【分析】圆柱侧面可以滚动,两端的圆面可以平稳放置.\n【详解】圆柱既能滚动又能放稳;球只能滚动;长方体不易滚动。故答案为: C", + "knowledge_points": [ + "组合图形的稳定性" + ], + "source": "21-22 一年级上·江苏·单元测试" + }, + { + "id": "432", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "数学课本的形状是 ( )。", + "options": [ + "A. 长方体", + "B. 正方体", + "C. 圆柱" + ], + "answer": "A", + "solution": "【分析】数学课本有 6 个面,相对的面形状相同,是长长方方的.\n【详解】数学课本的形状是长方体。故答案为: A", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "21-22 一年级上·江苏·单元测试" + }, + { + "id": "433", + "unit": "第三单元 认识立体图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "在长方体的上面放一个球,下面摆放正确的是 ( )。", + "options": [ + "A. ![](images/29965de504bf9a29daf32f5fe14c0c90d5c2190639e8dc122f467c60dbdbbd1f.jpg)", + "B. ![](images/408fbb4a1c2d788fee2ab0244196e891787814144ec9c23e06573918becbd1e5.jpg)", + "C. ![](images/fa061cf65d8b1133c875e7ac8ca7d711cdc99db33a5b7f814abf183d23f09d76.jpg)" + ], + "answer": "A", + "solution": "【分析】球放在长方体上面,接触面是平平的,可以搭稳.\n【详解】球应放在长方体上面,且与长方体的平面接触;选项 A 摆放正确。故答案为: A", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "21-22 一年级上·全国·单元测试" + }, + { + "id": "434", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "数一数.\n![](images/3fae7a3440e490fe3fde7fca62b983b3fa598dbcd4992fd69d3edc99cd2e186f.jpg)\n\n 长方体有( )个;正方体有( )个,球有( )个。", + "options": [ + + ], + "answer": "4;1;2", + "solution": "【分析】根据长方体,正方体及球的特征,分别数一数各有几个,再填空即可.\n【详解】长方体有 4 个,正方体有 1 个,球有 2 个。", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "21-22 一年级上·江苏徐州·期末" + }, + { + "id": "435", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "数一数下面图中的图形.\n![](images/d219591d25f1020c254df1dc6fbc0371d92bd6cb86899fe440b4b85f33f9208c.jpg)\n\n 球有( )个;圆柱有( )个;正方体有( )个;长方体有( )个。", + "options": [ + + ], + "answer": "4;3;4;5", + "solution": "【分析】球:表面是曲面,易滚动;圆柱:上下两个面是圆,侧面是曲面;长方体:长长方方的,不易滚动;正方体: 6 个面是完全相等的正方形,不易滚动.\n【详解】球有 4 个,圆柱有 3 个,正方体有 4 个,长方体有 5 个。", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "20-21 一年级上·重庆黔江·期末" + }, + { + "id": "436", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "数一数,填一填.\n![](images/b4d9a56f12c008d519b590450291ec0b265ff0d1d9b0fc2e237b7cabe91e1cb2.jpg)\n\n( )个长方体;( )个球;( )个正方体;( )个圆柱。", + "options": [ + + ], + "answer": "2;3;5;6", + "solution": "【分析】球:表面是曲面,易滚动;圆柱:上下两个面是圆,侧面是曲面;长方体:长长方方的,不易滚动;正方体: 6 个面是完全相等的正方形,不易滚动.\n【详解】2 个长方体,3 个球,5 个正方体,6 个圆柱。", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "20-21一年级上·湖南岳阳·期末" + }, + { + "id": "437", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "数一数.\n![](images/1219e3a63a48a5e5fd92bd40fe0a9d6558ba56ec69ff131ba3d037dc4d5d55e7.jpg)\n\n 正方体有( )个,长方体有( )个,球有( )个,圆柱有( )个。", + "options": [ + + ], + "answer": "4;4;3;6", + "solution": "【分析】根据长方体,正方体,圆柱及球的特征分别数一数各有几个,再填空即可.\n【详解】由题意分析得:正方体有 4 个,长方体有 4 个,球有 3 个,圆柱有 6 个.", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "22-23一年级上·河北保定·期末" + }, + { + "id": "438", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "数一数,填一填.\n![](images/436dbb1c47a2dce8531aa8b7366d61f12a5503e6f1c3f26004b744425b3e7565.jpg)\n\n\u003ctable\u003e\u003ctr\u003e\u003ctd\u003e长方体\u003c/td\u003e\u003ctd\u003e正方体\u003c/td\u003e\u003c/tr\u003e\u003ctr\u003e\u003ctd\u003e()个\u003c/td\u003e\u003ctd\u003e()个\u003c/td\u003e\u003c/tr\u003e\u003ctr\u003e\u003ctd\u003e圆柱\u003c/td\u003e\u003ctd\u003e球\u003c/td\u003e\u003c/tr\u003e\u003ctr\u003e\u003ctd\u003e()个\u003c/td\u003e\u003ctd\u003e()个\u003c/td\u003e\u003c/tr\u003e\u003c/table\u003e", + "options": [ + + ], + "answer": "5;4;5;4", + "solution": "【分析】根据长方体,正方体,圆柱及球的特征,分别数一数各有几个,再填空即可.\n【详解】由题意分析得:\n\u003ctable\u003e\u003ctr\u003e\u003ctd\u003e长方体\u003c/td\u003e\u003ctd\u003e正方体\u003c/td\u003e\u003c/tr\u003e\u003ctr\u003e\u003ctd\u003e5个\u003c/td\u003e\u003ctd\u003e4个\u003c/td\u003e\u003c/tr\u003e\u003ctr\u003e\u003ctd\u003e圆柱\u003c/td\u003e\u003ctd\u003e球\u003c/td\u003e\u003c/tr\u003e\u003ctr\u003e\u003ctd\u003e5个\u003c/td\u003e\u003ctd\u003e4个\u003c/td\u003e\u003c/tr\u003e\u003c/table\u003e", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "20-21 一年级上·福建泉州·期末" + }, + { + "id": "439", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "看图填表.\n![](images/684d38c946dd69ddacc5ac31037ed4cee905b2cda95d4e516b643a379b48f6ce.jpg)\n\n\u003ctable\u003e\u003ctr\u003e\u003ctd\u003e长方体\u003c/td\u003e\u003ctd\u003e()个\u003c/td\u003e\u003c/tr\u003e\u003ctr\u003e\u003ctd\u003e正方体\u003c/td\u003e\u003ctd\u003e()个\u003c/td\u003e\u003c/tr\u003e\u003ctr\u003e\u003ctd\u003e圆柱\u003c/td\u003e\u003ctd\u003e()个\u003c/td\u003e\u003c/tr\u003e\u003ctr\u003e\u003ctd\u003e球\u003c/td\u003e\u003ctd\u003e()个\u003c/td\u003e\u003c/tr\u003e\u003c/table\u003e", + "options": [ + + ], + "answer": "5;3;3;2", + "solution": "【分析】先根据长方体,正方体,球和圆柱的特征,识别并数出个数,然后完成填空.\n【详解】由题意分析得:\n\u003ctable\u003e\u003ctr\u003e\u003ctd\u003e长方体\u003c/td\u003e\u003ctd\u003e5个\u003c/td\u003e\u003c/tr\u003e\u003ctr\u003e\u003ctd\u003e正方体\u003c/td\u003e\u003ctd\u003e3个\u003c/td\u003e\u003c/tr\u003e\u003ctr\u003e\u003ctd\u003e圆柱\u003c/td\u003e\u003ctd\u003e3个\u003c/td\u003e\u003c/tr\u003e\u003ctr\u003e\u003ctd\u003e球\u003c/td\u003e\u003ctd\u003e2个\u003c/td\u003e\u003c/tr\u003e\u003c/table\u003e", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "20-21 一年级上·江苏徐州·期末" + }, + { + "id": "440", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "球有( )个,正方体有( )个,圆柱有( )个,长方体有( )个.\n![](images/feed97752fb0e0f674fab120b572883160da80dd7998ec85fd51250c42483479.jpg)", + "options": [ + + ], + "answer": "3;2;2;3", + "solution": "【分析】依据对常见立体图形的认识从左向右辨别图形,计数时可以采取数一个划去一个的方法来计数,这样不重复不遗漏.\n【详解】球有 3 个;正方体有 2 个;圆柱有 2 个;长方体有 3 个.", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "20-21 一年级上·江苏徐州·期末" + }, + { + "id": "441", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "球有( )个,圆柱有( )个,正方体有( )个,长方体有( )个.\n![](images/b0b2ae193eef4c18fc73babf045ed2b8f851698c90d59557c0e61425ea51d7dc.jpg)", + "options": [ + + ], + "answer": "2;5;3;4", + "solution": "【分析】根据球,圆柱,正方体及长方体的特征分别数一数各有几个.\n【详解】球有 2 个,圆柱有 5 个,正方体有 3 个,长方体有 4 个。", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "23-24 一年级上·江苏·单元测试" + }, + { + "id": "442", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.65, + "question": "看图,填一填.\n![](images/0fff438ec24f17625cd42b6acc1b07e916220a31a9a169325986ea1cd5ae6bea.jpg)\n\n\u003ctable\u003e\u003ctr\u003e\u003ctd\u003e正方体\u003c/td\u003e\u003ctd\u003e长方体\u003c/td\u003e\u003ctd\u003e圆柱\u003c/td\u003e\u003ctd\u003e球\u003c/td\u003e\u003c/tr\u003e\u003ctr\u003e\u003ctd\u003e()个\u003c/td\u003e\u003ctd\u003e()个\u003c/td\u003e\u003ctd\u003e()个\u003c/td\u003e\u003ctd\u003e()个\u003c/td\u003e\u003c/tr\u003e\u003c/table\u003e", + "options": [ + + ], + "answer": "3;4;2;3", + "solution": "【分析】按正方体、长方体、圆柱、球的特征分类计数.\n【详解】正方体有 3 个,长方体有 4 个,圆柱有 2 个,球有 3 个。", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "20-21 一年级上·辽宁本溪·期末" + }, + { + "id": "443", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "数一数,填一填.\n![](images/b677b58cc6f90fc5ec890472363f0e72fcba4eaf9449bbcb7457c7b9fc7acab1.jpg)\n\n 长方体有( )个,正方体有( )个,圆柱有( )个,球有( )个。", + "options": [ + + ], + "answer": "3;1;2;2", + "solution": "【分析】按立体图形特征分类计数.\n【详解】长方体有 3 个,正方体有 1 个,圆柱有 2 个,球有 2 个。", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "20-21一年级上·浙江宁波·期末" + }, + { + "id": "444", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.65, + "question": "数一数,填一填.\n![](images/bc54233233aef604e084b0fecd2e110d12b025d054838efcfd36d149991de8c6.jpg)\n\n (1)正方体有( )个,长方体有( )个。 \n (2)圆柱有( )个,球有( )个。", + "options": [ + + ], + "answer": "2;3;2;2", + "solution": "【分析】按正方体、长方体、圆柱、球的特征分类计数.\n【详解】正方体有 2 个,长方体有 3 个,圆柱有 2 个,球有 2 个。", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "21-22一年级上·甘肃平凉·期中" + }, + { + "id": "445", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.65, + "question": "\n![](images/4ceefb2d37224eed5910cff018e638e42cfa3b703df51065e3d6eb1e9648182c.jpg)\n\n长方体有( )个,正方体有( )个,圆柱有( )个,球有( )个。", + "options": [ + + ], + "answer": "3;2;2;2", + "solution": "【分析】按立体图形特征分类计数.\n【详解】长方体有 3 个,正方体有 2 个,圆柱有 2 个,球有 2 个。", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "21-22 一年级上·湖北十堰·期中" + }, + { + "id": "446", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.65, + "question": "数一数,下面图形中有正方体( )个,球( )个,长方体( )个,圆柱( )个。\n![](images/71052ad0772e30c8ca7118624e758a7b4553060b8043ccad34899f1898ca9817.jpg)", + "options": [ + + ], + "answer": "5;2;3;2", + "solution": "【分析】根据圆柱,长方体,正方体及球的特征分类计数.\n【详解】5 个正方体,2 个球,3 个长方体,2 个圆柱。", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "20-21一年级上·四川内江·期末" + }, + { + "id": "447", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.65, + "question": "如图中有( )个长方体, ( )个正方体, ( )个圆柱, ( )个球.\n![](images/b5f273659ccf14815e21373fb2a3bb30b79c9b9ebd5587add6dedb1fae9eb6ca.jpg)", + "options": [ + + ], + "answer": "4;1;2;2", + "solution": "【分析】根据立体图形的分类及特征即可解答.\n【详解】图中有 4 个长方体, 1 个正方体, 2 个圆柱, 2 个球.", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "20-21 一年级上·河南漯河·期末" + }, + { + "id": "448", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.65, + "question": "数一数.\n![](images/a80831a2d2e3cb7d2fb5466625e901d274161eea06b14d79795c307dd3356370.jpg)\n\n\u003ctable\u003e\u003ctr\u003e\u003ctd\u003e正方体\u003c/td\u003e\u003ctd\u003e长方体\u003c/td\u003e\u003ctd\u003e球\u003c/td\u003e\u003ctd\u003e圆柱\u003c/td\u003e\u003c/tr\u003e\u003ctr\u003e\u003ctd\u003e()个\u003c/td\u003e\u003ctd\u003e()个\u003c/td\u003e\u003ctd\u003e()个\u003c/td\u003e\u003ctd\u003e()个\u003c/td\u003e\u003c/tr\u003e\u003c/table\u003e", + "options": [ + + ], + "answer": "4;2;2;3", + "solution": "【分析】按正方体、长方体、球、圆柱的顺序分类计数.\n【详解】正方体有 4 个,长方体有 2 个,球有 2 个,圆柱有 3 个。", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "20-21 一年级上·安徽安庆·期末" + }, + { + "id": "449", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "![](images/4a11f59f3152262316d025ccf4095278cf6b6b1a26d14900da53c348b30f907c.jpg)\n( )个正方体,( )个圆柱,( )个长方体,( )个球", + "options": [ + + ], + "answer": "5;3;2;2", + "solution": "【分析】按正方体、圆柱、长方体、球的顺序分类计数.\n【详解】正方体有 5 个,圆柱有 3 个,长方体有 2 个,球有 2 个。", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "21-22 一年级上·河南周口·期末" + }, + { + "id": "450", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.65, + "question": "我会数.\n![](images/2576e15603926f910256ef00b5a6f54234821af0651d673ab6ff62f00bf0e282.jpg)\n\n( )个正方体 ,( )个长方体 , ( )个圆柱,( )个球", + "options": [ + + ], + "answer": "4;3;3;2", + "solution": "【分析】按正方体、长方体、圆柱、球的顺序分类计数.\n【详解】正方体有 4 个,长方体有 3 个,圆柱有 3 个,球有 2 个。", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "20-21 一年级上·安徽六安·期末" + }, + { + "id": "451", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.65, + "question": "数一数,填一填.\n![](images/b7e2cf33ce5edffc308c6c439f5329f76fd619526c3adc47a1a9da4b67c43880.jpg)\n\n长方体有( )个;正方体有( )个;圆柱有( )个;球有( )个。", + "options": [ + + ], + "answer": "2;2;5;3", + "solution": "【分析】按立体图形特征分类计数.\n【详解】长方体有 2 个,正方体有 2 个,圆柱有 5 个,球有 3 个。", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "20-21 一年级上·安徽淮南·期末" + }, + { + "id": "452", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.65, + "question": "数一数.\n![](images/bed496246b4806a5979f20895530d95b.png)\n\n有( )个圆柱,有( )个长方体,有( )个正方体", + "options": [ + + ], + "answer": "3;3;5", + "solution": "【分析】按照长方体,正方体及圆柱的特征分别数一数各有几个,再填空即可.\n【详解】圆柱有 3 个,长方体有 3 个,正方体有 5 个。", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "20-21 一年级上·河南焦作·期末" + }, + { + "id": "453", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.65, + "question": "数一数,填一填.\n![](images/271c8e1291db9360fa0c7bda1c93a732fe5bd197f4298f1f2669cf743261a2e9.jpg)\n\n 圆柱有( )个;长方体有( )个;球有( )个;正方体有( )个。", + "options": [ + + ], + "answer": "8;3;7;3", + "solution": "【分析】按立体图形特征分类计数.\n【详解】圆柱有 8 个,长方体有 3 个,球有 7 个,正方体有 3 个。", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "20-21 一年级上·广东韶关·期末" + }, + { + "id": "454", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.65, + "question": "长方体有( )个,正方体有( )个,圆柱有( )个,球有( )个.\n![](images/f34168284dee6d0675b84fe0db48391e383d06cc854efa9edf3f75e21a635760.jpg)", + "options": [ + + ], + "answer": "3;2;2;2", + "solution": "【分析】按立体图形特征分类计数.\n【详解】长方体有 3 个,正方体有 2 个,圆柱有 2 个,球有 2 个。", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "21-22 一年级上·河南濮阳·期末" + }, + { + "id": "455", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.65, + "question": "给长方体的每个面上写一个不同的数字,需要( )个数字。", + "options": [ + + ], + "answer": "6", + "solution": "【分析】长方体有 6 个面,每个面写不同数字需要 6 个数字.\n【详解】长方体有 6 个面,所以需要 6 个数字。", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "21-22 一年级下·山东·课后作业" + }, + { + "id": "456", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.65, + "question": "下图是欢欢在科学小社团搭建的一幅作品,找找图中你认识的图形.\n![](images/9cb032c3697f7f540fe76f302ce96fe0f62c687b96e0a7e79e3b8381e77bdbb8.jpg)\n\n图中有( )个长方体,有( )个球,有( )个正方体,有( )个圆柱。个数最多的图形是( ),个数最少的图形是( )。", + "options": [ + + ], + "answer": "3;1;2;2;长方体;球", + "solution": "【分析】根据立体图形的不同特征,分别数一数各有几个,然后填空即可。长方体:由 6 个平平的面围成,且是长长的;球:由 1 个曲面围成;正方体:由 6 个平平的面围成,且每个面都是正方形;圆柱:由2个平平的面和1个曲面围成;据此再判断哪个图形个数最多和最少.\n【详解】由分析可得:图中有 3 个长方体,有 1 个球,有 2 个正方体,有 2 个圆柱。3 \u003e 2 \u003e 1,所以个数最多的图形是长方体,个数最少的图形是球.", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "21-22 一年级上·山西忻州·期末" + }, + { + "id": "457", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.65, + "question": "数一数,填一填.\n![](images/5d7c28ea0d5712c7d09aa4905307950cbad2253f56b4207632bff6c59bd72cb4.jpg)\n\n正方体有( )个;长方体有( )个;圆柱有( )个;球有( )个。", + "options": [ + + ], + "answer": "1;3;5;4", + "solution": "【分析】正方体、长方体、圆柱、球的特征各不相同,依次数出个数即可.\n【详解】正方体有 1 个,长方体有 3 个,圆柱有 5 个,球有 4 个。", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "21-22 一年级下·山东临沂·开学考试" + }, + { + "id": "458", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "数一数,填一填.\n![](images/d7158544781556adfddba25edecfa189043f7bf544485ada3219f93dacbc0477.jpg)\n\n正方体有( )个,长方体有( )个,圆柱有( )个,球有( )个。", + "options": [ + + ], + "answer": "3;6;4;3", + "solution": "【分析】根据立体图形的特点,数清楚图片上各种图形的数量,即可得出答案.\n【详解】由分析可得:正方体有 3 个,长方体有 6 个,圆柱有 4 个,球有 3 个.", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "21-22一年级上·广东韶关·期末" + }, + { + "id": "459", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.65, + "question": "正方体有( )个,长方体有( )个,圆柱有( )个,球有( )个.\n![](images/04c3cc14c1884ca6cfd6def39b761344f7c30f0996a195852fdbb1c862324343.jpg)", + "options": [ + + ], + "answer": "2;2;4;2", + "solution": "【分析】按立体图形特征分类计数.\n【详解】正方体有 2 个,长方体有 2 个,圆柱有 4 个,球有 2 个。", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "20-21 一年级上·广东惠州·期末" + }, + { + "id": "460", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "认立体图形.\n![](images/605c353d686637ddbfdc8b5b4d4ad3f889399f1998b06b4c7575251e295fad36.jpg)\n\n长方体有( )个;圆柱有( )个;正方体有( )个;球有( )个。", + "options": [ + + ], + "answer": "3;3;4;2", + "solution": "【分析】按立体图形特征分类计数.\n【详解】长方体有 3 个,圆柱有 3 个,正方体有 4 个,球有 2 个。", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "21-22 一年级上·广东佛山·期末" + }, + { + "id": "461", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.65, + "question": "两个完全一样的正方体,能拼成一个( )体。", + "options": [ + + ], + "answer": "长方", + "solution": "【分析】两个相同的正方体并排拼在一起,形成的长方体比原来更长.\n【详解】两个完全一样的正方体可以拼成一个长方体。", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "20-21 一年级上·广东汕头·期末" + }, + { + "id": "462", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.4, + "question": "下图要拼出一个大正方体,至少还需要( )个正方体.\n![](images/3cf317be588786b8e8b71f0d8c0a48e1cdb6f2e668d97979425a4d1ee560719c.jpg)", + "options": [ + + ], + "answer": "9", + "solution": "【分析】拼成 3×3×3 的大正方体共需 27 个小正方体,减去图中已有个数即为还需个数.\n【详解】大正方体需 27 个,图中现有 18 个,27 - 18 = 9 (个),至少还需要 9 个正方体。", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "20-21 一年级上·广东东莞·期末" + }, + { + "id": "463", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.65, + "question": "数一数.\n![](images/9286290348cc273e71aa0122cb32cfb1ed1f9402343268e63fe425a1db5acfc7.jpg)\n\n长方体( )个,正方体( )个,圆柱( )个,球 ( )个。", + "options": [ + + ], + "answer": "4;2;3;2", + "solution": "【分析】按立体图形特征分类计数.\n【详解】长方体有 4 个,正方体有 2 个,圆柱有 3 个,球有 2 个。", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "20-21 一年级上·广东东莞·期末" + }, + { + "id": "464", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "数一数,填一填.\n![](images/06d3626d05f3c629890b5cba16fb0ad9a002867e1d9e30b050cd5c4312876fee.jpg)\n![](images/0b9396b56995cb92369cec51e07975843f334063aa09345793f2eb4c3e475e0b.jpg)\n\n\u003ctable\u003e\u003ctr\u003e\u003ctd\u003e长方体\u003c/td\u003e\u003ctd\u003e()个\u003c/td\u003e\u003c/tr\u003e\u003ctr\u003e\u003ctd\u003e正方体\u003c/td\u003e\u003ctd\u003e()个\u003c/td\u003e\u003c/tr\u003e\u003ctr\u003e\u003ctd\u003e圆柱\u003c/td\u003e\u003ctd\u003e()个\u003c/td\u003e\u003c/tr\u003e\u003ctr\u003e\u003ctd\u003e球\u003c/td\u003e\u003ctd\u003e()个\u003c/td\u003e\u003c/tr\u003e\u003c/table\u003e", + "options": [ + + ], + "answer": "1;6;1;2", + "solution": "【分析】按立体图形特征分类计数.\n【详解】长方体有 1 个,正方体有 6 个,圆柱有 1 个,球有 2 个。", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "20-21一年级上·湖北武汉·期末" + }, + { + "id": "465", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "数一数,填一填.\n![](images/00de2fcf892b4687083bf8ad49a66ff76347b6ea89ea62954ba6f57cf5e2eaf5.jpg)\n\n圆柱有( )个;长方体有( )个;球有( )个;正方体有( )个", + "options": [ + + ], + "answer": "8;3;7;3", + "solution": "【分析】按立体图形特征分类计数.\n【详解】圆柱有 8 个,长方体有 3 个,球有 7 个,正方体有 3 个。", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "20-21一年级上·广东韶关·期末" + }, + { + "id": "466", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "分一分,数一数.\n![](images/54d2a4e5d15b9df560639c493a3128043552fd4da0b87890eb0a87ede121ee12.jpg)\n\n长方体有( )个;正方体有( )个;球有( )个;圆柱有( )个", + "options": [ + + ], + "answer": "4;1;2;4", + "solution": "【分析】按立体图形特征分类计数.\n【详解】长方体有 4 个,正方体有 1 个,球有 2 个,圆柱有 4 个。", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "20-21一年级上·山西忻州·期末" + }, + { + "id": "467", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.65, + "question": "数一数,填一填.\n![](images/eedec64e914390078d794f4af435b9a3.png)\n\n长方体有( )个,正方体有( )个,圆柱有( )个,球有( )个。", + "options": [ + + ], + "answer": "5;2;6;3", + "solution": "【分析】按立体图形特征分类计数.\n【详解】长方体有 5 个,正方体有 2 个,圆柱有 6 个,球有 3 个。", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "20-21 一年级上·河北石家庄·期末" + }, + { + "id": "468", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.65, + "question": "看图数一数,填一填.\n![](images/22f0c5763ab0b02f5ee73f4fa954fa46b16fece12204e9cb8149726a91acb31b.jpg)\n\n正方体有( )个;球有( )个;圆柱有( )个;长方体有( )个。", + "options": [ + + ], + "answer": "1;2;4;4", + "solution": "【分析】按立体图形特征分类计数.\n【详解】正方体有 1 个,球有 2 个,圆柱有 4 个,长方体有 4 个。", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "21-22 一年级上·河北张家口·期末" + }, + { + "id": "469", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "数图形.\n![](images/b780f0f4994616d1f2e86acc3ae788357ea9e52658dd069bf82b8724e22609bd.jpg)\n\n\u003ctable\u003e\u003ctr\u003e\u003ctd\u003e长方体\u003c/td\u003e\u003ctd\u003e正方体\u003c/td\u003e\u003ctd\u003e圆柱\u003c/td\u003e\u003ctd\u003e球\u003c/td\u003e\u003c/tr\u003e\u003ctr\u003e\u003ctd\u003e()个\u003c/td\u003e\u003ctd\u003e()个\u003c/td\u003e\u003ctd\u003e()个\u003c/td\u003e\u003ctd\u003e()个\u003c/td\u003e\u003c/tr\u003e\u003c/table\u003e", + "options": [ + + ], + "answer": "3;3;2;3", + "solution": "【分析】按立体图形特征分类计数.\n【详解】长方体有 3 个,正方体有 3 个,圆柱有 2 个,球有 3 个。", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "20-21 一年级上·湖北随州·期末" + }, + { + "id": "470", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "我会数.\n![](images/d83c504d8cca2bc1b9462e4dff4b1c105d4f76dcec5c7a1f2990e61fefd73dff.jpg)\n\n\u003ctable\u003e\u003ctr\u003e\u003ctd\u003e正方体\u003c/td\u003e\u003ctd\u003e()个\u003c/td\u003e\u003c/tr\u003e\u003ctr\u003e\u003ctd\u003e长方体\u003c/td\u003e\u003ctd\u003e()个\u003c/td\u003e\u003c/tr\u003e\u003ctr\u003e\u003ctd\u003e球\u003c/td\u003e\u003ctd\u003e()个\u003c/td\u003e\u003c/tr\u003e\u003ctr\u003e\u003ctd\u003e圆柱\u003c/td\u003e\u003ctd\u003e()个\u003c/td\u003e\u003c/tr\u003e\u003c/table\u003e", + "options": [ + + ], + "answer": "2;5;2;4", + "solution": "【分析】根据立体图形的特征,正确识别并数出各图形的个数.\n【详解】由题意分析得:\n\u003ctable\u003e\u003ctr\u003e\u003ctd\u003e正方体\u003c/td\u003e\u003ctd\u003e2个\u003c/td\u003e\u003c/tr\u003e\u003ctr\u003e\u003ctd\u003e长方体\u003c/td\u003e\u003ctd\u003e5个\u003c/td\u003e\u003c/tr\u003e\u003ctr\u003e\u003ctd\u003e球\u003c/td\u003e\u003ctd\u003e2个\u003c/td\u003e\u003c/tr\u003e\u003ctr\u003e\u003ctd\u003e圆柱\u003c/td\u003e\u003ctd\u003e4个\u003c/td\u003e\u003c/tr\u003e\u003c/table\u003e", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "21-22 一年级上·江苏盐城·期末" + }, + { + "id": "471", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.65, + "question": "数一数,填一填.\n![](images/49baf76b6052adf6de6f466e72cbabc2744e507266b28246f66cddfa6402690b.jpg)\n\n长方体有( )个,正方体有( )个,圆柱有( )个,球有( )个。", + "options": [ + + ], + "answer": "3;2;2;2", + "solution": "【分析】按立体图形特征分类计数.\n【详解】长方体有 3 个,正方体有 2 个,圆柱有 2 个,球有 2 个。", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "20-21一年级上·湖北黄冈·期末" + }, + { + "id": "472", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "我会数.\n![](images/70c906d0c2fba4d62b8b96c404f7e62e29050c499b86a6ef21fa268900f3674f.jpg)\n\n长方体有( )个,圆柱有( )个,球有( )个,正方体有( )个。", + "options": [ + + ], + "answer": "2;5;3;2", + "solution": "【分析】按立体图形特征分类计数.\n【详解】长方体有 2 个,圆柱有 5 个,球有 3 个,正方体有 2 个。", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "21-22 一年级上·甘肃平凉·期末" + }, + { + "id": "473", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.65, + "question": "数一数.\n![](images/1311e7732fa6aedd53e698df5a0025009c6e21717a27c1cc9a62e3b324b11a9b.jpg)\n\n\u003ctable\u003e\u003ctr\u003e\u003ctd\u003e正方体\u003c/td\u003e\u003ctd\u003e长方体\u003c/td\u003e\u003ctd\u003e圆柱\u003c/td\u003e\u003ctd\u003e球\u003c/td\u003e\u003c/tr\u003e\u003ctr\u003e\u003ctd\u003e()个\u003c/td\u003e\u003ctd\u003e()个\u003c/td\u003e\u003ctd\u003e()个\u003c/td\u003e\u003ctd\u003e()个\u003c/td\u003e\u003c/tr\u003e\u003c/table\u003e", + "options": [ + + ], + "answer": "1;3;4;3", + "solution": "【分析】按立体图形特征分类计数.\n【详解】正方体有 1 个,长方体有 3 个,圆柱有 4 个,球有 3 个。", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "21-22 一年级上·广东汕尾·期末" + }, + { + "id": "474", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "火眼金睛,我会数.\n![](images/68f9ba145d2e91191ea0d34c213bdb0dbbb5dd0f334871a96cae3c621df8cb54.jpg)\n\n\u003ctable\u003e\u003ctr\u003e\u003ctd\u003e正方体\u003c/td\u003e\u003ctd\u003e球\u003c/td\u003e\u003ctd\u003e圆柱\u003c/td\u003e\u003ctd\u003e长方体\u003c/td\u003e\u003c/tr\u003e\u003ctr\u003e\u003ctd\u003e()个\u003c/td\u003e\u003ctd\u003e()个\u003c/td\u003e\u003ctd\u003e()个\u003c/td\u003e\u003ctd\u003e()个\u003c/td\u003e\u003c/tr\u003e\u003c/table\u003e", + "options": [ + + ], + "answer": "5;8;8;1", + "solution": "【分析】根据正方体,长方体,圆柱体,球的特征,数出对应数量填在表格中即可.\n【详解】通过分类数一数,得出:\n\u003ctable\u003e\u003ctr\u003e\u003ctd\u003e正方体\u003c/td\u003e\u003ctd\u003e球\u003c/td\u003e\u003ctd\u003e圆柱\u003c/td\u003e\u003ctd\u003e长方体\u003c/td\u003e\u003c/tr\u003e\u003ctr\u003e\u003ctd\u003e(5)个\u003c/td\u003e\u003ctd\u003e(8)个\u003c/td\u003e\u003ctd\u003e(8)个\u003c/td\u003e\u003ctd\u003e(1)个\u003c/td\u003e\u003c/tr\u003e\u003c/table\u003e", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "20-21 一年级上·江苏盐城·期末" + }, + { + "id": "475", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "数一数,填一填.\n![](images/5fc474672807590c8e10a1cc7838885059f7a546173856a51fe8fba63b60bb84.jpg)\n\n正方体有( )个,长方体有( )个,圆柱有( )个,球有( )个。", + "options": [ + + ], + "answer": "2;4;1;4", + "solution": "【分析】按立体图形特征分类计数.\n【详解】正方体有 2 个,长方体有 4 个,圆柱有 1 个,球有 4 个。", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "21-22一年级上·甘肃定西·期末" + }, + { + "id": "476", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "数一数,填一填.\n![](images/01ed49a0f08441b3516244b731db0c4ae248c581726689e5cbc0217f16f473ba.jpg)\n\n长方体有( )个,正方体有( )个,圆柱有( )个。", + "options": [ + + ], + "answer": "6;4;3", + "solution": "【分析】按立体图形特征分类计数.\n【详解】长方体有 6 个,正方体有 4 个,圆柱有 3 个。", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "20-21 一年级上·湖北咸宁·期末" + }, + { + "id": "477", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "数一数.\n![](images/711719fbeb43e1fa2bb529801663bda0637ddb6e73c10910b8a317e4e248945b.jpg)\n\n()个正方体 ,()个圆柱 ,()个 长方体,()个球。", + "options": [ + + ], + "answer": "4;5;1;2", + "solution": "【分析】按立体图形特征分类计数.\n【详解】正方体有 4 个,圆柱有 5 个,长方体有 1 个,球有 2 个。", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "21-22一年级上·河北邯郸·期末" + }, + { + "id": "478", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "数一数,填一填.\n![](images/d81f52b8e41c057f5b2146b869d4dce439805c9acab860c779c7552ccfafa55b.jpg)\n\n正方体有( )个,长方体有( )个,球有( )个。", + "options": [ + + ], + "answer": "2;3;1", + "solution": "【分析】按立体图形特征分类计数.\n【详解】正方体有 2 个,长方体有 3 个,球有 1 个。", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "21-22 一年级上·江苏苏州·期中" + }, + { + "id": "479", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "数一数,填一填.\n![](images/4f730ede7db25d1b99ffb153420bad9673ac1c446e6632de341c444c00217ec0.jpg)\n\n\u003ctable\u003e\u003ctr\u003e\u003ctd\u003e长方体\u003c/td\u003e\u003ctd\u003e()个\u003c/td\u003e\u003c/tr\u003e\u003ctr\u003e\u003ctd\u003e正方体\u003c/td\u003e\u003ctd\u003e()个\u003c/td\u003e\u003c/tr\u003e\u003ctr\u003e\u003ctd\u003e圆柱\u003c/td\u003e\u003ctd\u003e()个\u003c/td\u003e\u003c/tr\u003e\u003ctr\u003e\u003ctd\u003e球\u003c/td\u003e\u003ctd\u003e()个\u003c/td\u003e\u003c/tr\u003e\u003c/table\u003e", + "options": [ + + ], + "answer": "3;4;2;3", + "solution": "【分析】按立体图形特征分类计数.\n【详解】长方体有 3 个,正方体有 4 个,圆柱有 2 个,球有 3 个。", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "20-21一年级上·江苏盐城·期末" + }, + { + "id": "480", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "看图填空.\n![](images/9832bcb0cf64eca4c36a753f0c974e046a5d4363b70cb61f6950b05758a49863.jpg)\n\n()个正方体,()个球 ,()个长方体 ,()个 圆柱 。", + "options": [ + + ], + "answer": "4;3;6;4", + "solution": "【分析】按立体图形特征分类计数.\n【详解】正方体有 4 个,球有 3 个,长方体有 6 个,圆柱有 4 个。", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "20-21 一年级上·辽宁朝阳·期末" + }, + { + "id": "481", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "数一数.\n![](images/5f318de7173fb5950b15fa052698f0e1e672669254674f56cda853f3ec045d1e.jpg)\n![](images/fa4dcbe9287a6deb2434d3933e1edf17d0b1930c412c7f254291d44a0a6735ee.jpg)\n\n 长方体有( )个,圆柱有( )个,正方体有( )个。", + "options": [ + + ], + "answer": "5;2;1", + "solution": "【分析】按立体图形特征分类计数.\n【详解】长方体有 5 个,圆柱有 2 个,正方体有 1 个。", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "21-22一年级上·广东深圳·期末" + }, + { + "id": "482", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "数一数.\n![](images/7b7ac64505926592d8136e0c1714c57bd980f1c6aefce7271b7a8c1e07bd82e3.jpg)\n\n( )个正方体 ,( )个 圆柱,( )个 长方体,( )个球。", + "options": [ + + ], + "answer": "4;2;4;1", + "solution": "【分析】按立体图形特征分类计数.\n【详解】正方体有 4 个,圆柱有 2 个,长方体有 4 个,球有 1 个。", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "21-22一年级上·黑龙江大兴安岭地·期末" + }, + { + "id": "483", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "我会数.\n![](images/d035692e726d0d612cf88ac3b7057447.png)\n\n长方体有( )个,圆柱有( )个,正方体有( )个。", + "options": [ + + ], + "answer": "3;5;4", + "solution": "【分析】按立体图形特征分类计数.\n【详解】长方体有 3 个,圆柱有 5 个,正方体有 4 个。", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "21-22 一年级上·广西河池·期中" + }, + { + "id": "484", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": " 数一数.\n![](images/f1ec13c72858fdfec044d0ea0155cdade4a3141adf63aa0c1b09e5047761204a.jpg)\n\n 球有( )个,正方体有( )个,长方体有( )个,圆柱有( )个。", + "options": [ + + ], + "answer": "4;2;3;2", + "solution": "【分析】按立体图形特征分类计数.\n【详解】球有 4 个,正方体有 2 个,长方体有 3 个,圆柱有 2 个。", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "21-22 一年级上·福建龙岩·期中" + }, + { + "id": "485", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.65, + "question": "数一数,填一填.\n
长方体正方体圆柱球
()个()个()个()个
", + "options": [ + + ], + "answer": "2;2;6;7", + "solution": "【分析】按立体图形特征分类计数.\n【详解】长方体有 2 个,正方体有 2 个,圆柱有 6 个,球有 7 个。", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "21-22 一年级上·辽宁·单元测试" + }, + { + "id": "486", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "数一数,填一填.\n![](images/7e12536cdd95d74adc0c775faac4ded0162b57f939a46ded62d499392acc502b.jpg)\n\n(1) 填一填.\n\u003ctable\u003e\u003ctr\u003e\u003ctd\u003e正方体\u003c/td\u003e\u003ctd\u003e长方体\u003c/td\u003e\u003ctd\u003e圆柱\u003c/td\u003e\u003ctd\u003e球\u003c/td\u003e\u003ctr\u003e\u003ctd\u003e()个\u003c/td\u003e\u003ctd\u003e()个\u003c/td\u003e\u003ctd\u003e()个\u003c/td\u003e\u003ctd\u003e()个\u003c/td\u003e\u003c/tr\u003e\u003c/table\u003e\n (2) ( )的个数最多, ( )的个数最少。", + "options": [ + + ], + "answer": "3;4;2;3;长方体;圆柱", + "solution": "【分析】按正方体、长方体、圆柱、球的特征分类计数,再比较多少.\n【详解】(1) 正方体 3 个,长方体 4 个,圆柱 2 个,球 3 个。(2) 长方体 4 个最多,圆柱 2 个最少。", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "21-22一年级上·辽宁·单元测试" + }, + { + "id": "487", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": " 认识图形.\n![](images/a7eaeb498ffd53c3e9d6901cb6404217dc537b51053e2873fa7dbaae87511608.jpg)\n\n\u003ctable\u003e\u003ctr\u003e\u003ctd\u003e长方体\u003c/td\u003e\u003ctd\u003e正方体\u003c/td\u003e\u003ctd\u003e圆柱\u003c/td\u003e\u003ctd\u003e球\u003c/td\u003e\u003c/tr\u003e\u003ctr\u003e\u003ctd\u003e()个\u003c/td\u003e\u003ctd\u003e()个\u003c/td\u003e\u003ctd\u003e()个\u003c/td\u003e\u003ctd\u003e()个\u003c/td\u003e\u003c/tr\u003e\u003c/table\u003e", + "options": [ + + ], + "answer": "4;2;4;3", + "solution": "【分析】按立体图形特征分类计数.\n【详解】长方体有 4 个,正方体有 2 个,圆柱有 4 个,球有 3 个。", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "21-22 一年级上·河南焦作·期中" + }, + { + "id": "488", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "\n![](images/dd5e0398f427f2dd4cf3b412b7f06a1e11068cb2560c9ced69c3dd3436bd78b3.jpg)\n\n\u003ctable\u003e\u003ctr\u003e\u003ctd\u003e正方体\u003c/td\u003e\u003ctd\u003e()个\u003c/td\u003e\u003c/tr\u003e\u003ctr\u003e\u003ctd\u003e长方体\u003c/td\u003e\u003ctd\u003e()个\u003c/td\u003e\u003c/tr\u003e\u003ctr\u003e\u003ctd\u003e圆柱\u003c/td\u003e\u003ctd\u003e()个\u003c/td\u003e\u003c/tr\u003e\u003ctr\u003e\u003ctd\u003e球\u003c/td\u003e\u003ctd\u003e()个\u003c/td\u003e\u003c/tr\u003e\u003c/table\u003e", + "options": [ + + ], + "answer": "4;5;4;3", + "solution": "【分析】按立体图形特征分类计数.\n【详解】正方体有 4 个,长方体有 5 个,圆柱有 4 个,球有 3 个。", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "21-22 一年级上·江苏淮安·期中" + }, + { + "id": "489", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "我会数一数,填一填.\n![](images/4889151d7278f31c608e328138b938dc69b66fee9605a632889ccf2624d6a89b.jpg)\n\n\u003ctable\u003e\u003ctr\u003e\u003ctd\u003e圆柱\u003c/td\u003e\u003ctd\u003e()个\u003c/td\u003e\u003c/tr\u003e\u003ctr\u003e\u003ctd\u003e长方体\u003c/td\u003e\u003ctd\u003e()个\u003c/td\u003e\u003c/tr\u003e\u003ctr\u003e\u003ctd\u003e正方体\u003c/td\u003e\u003ctd\u003e()个\u003c/td\u003e\u003c/tr\u003e\u003ctr\u003e\u003ctd\u003e球\u003c/td\u003e\u003ctd\u003e()个\u003c/td\u003e\u003c/tr\u003e\u003c/table\u003e", + "options": [ + + ], + "answer": "4;6;4;5", + "solution": "【分析】按立体图形特征分类计数.\n【详解】圆柱有 4 个,长方体有 6 个,正方体有 4 个,球有 5 个。", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "21-22 一年级上·湖北省直辖县级单位·期中" + }, + { + "id": "490", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "数一数,填一填.\n![](images/0edf8eb5ca03013ddbf06e48bf07875f21f124290e668ae67be05e20b63753a5.jpg)\n\n\u003ctable\u003e\u003ctr\u003e\u003ctd\u003e长方体\u003c/td\u003e\u003ctd\u003e正方体\u003c/td\u003e\u003ctd\u003e圆柱\u003c/td\u003e\u003ctd\u003e球\u003c/td\u003e\u003c/tr\u003e\u003ctr\u003e\u003ctd\u003e()个\u003c/td\u003e\u003ctd\u003e()个\u003c/td\u003e\u003ctd\u003e()个\u003c/td\u003e\u003ctd\u003e()个\u003c/td\u003e\u003c/tr\u003e\u003c/table\u003e", + "options": [ + + ], + "answer": "5;4;4;3", + "solution": "【分析】按立体图形特征分类计数.\n【详解】长方体有 5 个,正方体有 4 个,圆柱有 4 个,球有 3 个。", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "21-22一年级上·江苏·期末" + }, + { + "id": "491", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "数一数,填一填.\n![](images/25056a509db58ce57b9d30fc65dd31cfd7bc7af459a926d5abf5d459ab2083c4.jpg)\n\n\u003ctable\u003e\u003ctr\u003e\u003ctd\u003e长方体\u003c/td\u003e\u003ctd\u003e正方体\u003c/td\u003e\u003ctd\u003e圆柱\u003c/td\u003e\u003ctd\u003e球\u003c/td\u003e\u003c/tr\u003e\u003ctr\u003e\u003ctd\u003e()个\u003c/td\u003e\u003ctd\u003e()个\u003c/td\u003e\u003ctd\u003e()个\u003c/td\u003e\u003ctd\u003e()个\u003c/td\u003e\u003c/tr\u003e\u003c/table\u003e", + "options": [ + + ], + "answer": "2;3;4;2", + "solution": "【分析】按立体图形特征分类计数.\n【详解】长方体有 2 个,正方体有 3 个,圆柱有 4 个,球有 2 个。", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "21-22一年级上·辽宁·期末" + }, + { + "id": "492", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "数一数.\n![](images/388442ea63704add7ecda2f8d904178f0f94e68aecd4fd8eda77c5c73b0b7a43.jpg)\n\n 圆柱有( )个,正方体有( )个,球有( )个,长方体有( )个。", + "options": [ + + ], + "answer": "5;1;2;2", + "solution": "【分析】按立体图形特征分类计数.\n【详解】圆柱有 5 个,正方体有 1 个,球有 2 个,长方体有 2 个。", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "21-22 一年级上·全国·期中" + }, + { + "id": "493", + "unit": "第三单元 认识立体图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "数一数,填一填.\n![](images/b46dbe61b5b8f19a53f691333fa9ebe4.png)\n\n长方体有( )个,正方体有( )个,圆柱有( )个,球有( )个。", + "options": [ + + ], + "answer": "3;3;7;4", + "solution": "【分析】按立体图形特征分类计数.\n【详解】长方体有 3 个,正方体有 3 个,圆柱有 7 个,球有 4 个。", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "21-22 一年级上·河北·期中" + }, + { + "id": "494", + "unit": "第三单元 认识立体图形", + "question_type": "判断题", + "difficulty": 0.85, + "question": "冰箱是一个长方体。( )", + "options": [ + + ], + "answer": "√", + "solution": "【分析】长方体: 6 个面,每个面都由长方形或相对的一组正方形组成;据此解答.\n【详解】由分析可得:冰箱是一个长方体。故答案为: √", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "21-22 一年级上·河北张家口·期末" + }, + { + "id": "495", + "unit": "第三单元 认识立体图形", + "question_type": "判断题", + "difficulty": 0.85, + "question": "![](images/a0b1309280da5638cdd529123817ef1e1d1dd04b5edf072776fd6407b1a73710.jpg)![](images/4a0dc8257f76210da9e713751647039793759443a465a69269166246706e8997.jpg)都是圆圆的。()", + "options": [ + + ], + "answer": "√", + "solution": "【分析】根据生活实际情况可知,篮球和足球都是圆圆的.\n【详解】由题意分析得:![](images/4fbf7ef486026b797a9a2e97bf9d11973939e4178432bf1c86019c23f8bb9816.jpg)![](images/e047a44cbf8e811c123d438896a228c9a5369da97c416654768593267846bff7.jpg)都是圆圆的。此说法正确。故答案为: √", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "23-24一年级上·辽宁·单元测试" + }, + { + "id": "496", + "unit": "第三单元 认识立体图形", + "question_type": "判断题", + "difficulty": 0.85, + "question": "我们用的语文书和数学书都是正方体。( )", + "options": [ + + ], + "answer": "×", + "solution": "【分析】根据长方体和正方体的特征可知,我们用的语文书和数学书都是长方体。据此判断即可.\n【详解】由分析可知:\n我们用的语文书和数学书都是长方体。所以原题干说法错误。故答案为: ×", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "21-22 一年级上·贵州铜仁·期末" + }, + { + "id": "497", + "unit": "第三单元 认识立体图形", + "question_type": "判断题", + "difficulty": 0.65, + "question": "如图![](images/32190da83b7eb5b21923e9bf12efccd772bb5e535e79bda47593e63d719ed669.jpg)是由4个正方体拼成的。( )", + "options": [ + + ], + "answer": "×", + "solution": "【分析】观察图形,一共两层,注意被遮挡的小正方体不要漏数.\n【详解】图形有两层,上面一层有 1 个,下面一层有 4 个。1 + 4 = 5 (个),不是 4 个,原题说法错误。故答案为: ×", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "20-21一年级上·河南安阳·期中" + }, + { + "id": "498", + "unit": "第三单元 认识立体图形", + "question_type": "判断题", + "difficulty": 0.85, + "question": "粉笔盒是长方体。( )", + "options": [ + + ], + "answer": "√", + "solution": "【分析】粉笔盒有 6 个面,每个面都是长方形.\n【详解】粉笔盒符合长方体的特征,原题说法正确。故答案为: √", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "20-21 一年级上·河南郑州·期末" + }, + { + "id": "499", + "unit": "第三单元 认识立体图形", + "question_type": "判断题", + "difficulty": 0.85, + "question": "圆柱比长方体更容易滚动。( )", + "options": [ + + ], + "answer": "√", + "solution": "【分析】圆柱侧面是曲面易滚动,长方体有平平的面不易滚动.\n【详解】圆柱比长方体更容易滚动,原题说法正确。故答案为: √", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "20-21 一年级上·湖北十堰·期末" + }, + { + "id": "500", + "unit": "第三单元 认识立体图形", + "question_type": "判断题", + "difficulty": 0.94, + "question": "篮球和乒乓球都是球。( )", + "options": [ + + ], + "answer": "√", + "solution": "【分析】篮球和乒乓球都是圆圆的,可以向任意方向滚动.\n【详解】篮球和乒乓球都是球,原题说法正确。故答案为: √", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "21-22 一年级上·湖南怀化·期中" + } +] \ No newline at end of file diff --git "a/\344\270\200\345\271\264\347\272\247\351\242\230\351\233\206/\344\270\200\345\271\264\347\272\247\344\270\212/\344\270\200\345\271\264\347\272\247\344\270\212\347\254\254\344\272\214\345\215\225\345\205\2036-10\347\232\204\350\256\244\350\257\206\345\222\214\345\212\240\343\200\201\345\207\217\346\263\225.json" "b/\344\270\200\345\271\264\347\272\247\351\242\230\351\233\206/\344\270\200\345\271\264\347\272\247\344\270\212/\344\270\200\345\271\264\347\272\247\344\270\212\347\254\254\344\272\214\345\215\225\345\205\2036-10\347\232\204\350\256\244\350\257\206\345\222\214\345\212\240\343\200\201\345\207\217\346\263\225.json" new file mode 100644 index 0000000000000000000000000000000000000000..5a4262e97e03ecf4e3e364409b9047306f373a80 --- /dev/null +++ "b/\344\270\200\345\271\264\347\272\247\351\242\230\351\233\206/\344\270\200\345\271\264\347\272\247\344\270\212/\344\270\200\345\271\264\347\272\247\344\270\212\347\254\254\344\272\214\345\215\225\345\205\2036-10\347\232\204\350\256\244\350\257\206\345\222\214\345\212\240\343\200\201\345\207\217\346\263\225.json" @@ -0,0 +1,6896 @@ +[ + { + "id": "1", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.65, + "question": "妈妈买的月饼中, 有 4 个豆沙馅, 够每人一个吗? ( )\n\n![](images/a960b039a28aa0f9c85dc00b98864592dd2778c4554ca56bec2a8b2705aa3a8e.jpg)", + "options": [ + "A. 够", + "B. 不够", + "C. 不能确定" + ], + "answer": "B", + "solution": "【分析】根据题意,数出人数再和月饼的数量比较大小,人数大于月饼的数量不够,小于或等于月饼的数量够.\n【详解】由分析得:有 6 个人,6 \u003e 4,人数比月饼的数量多.则不够每人一个.故答案为: B", + "knowledge_points": [ + "9 以内数的比大小", + "数一数" + ], + "source": "25-26 一年级上·江西九江·期中" + }, + { + "id": "2", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.94, + "question": "排队购票, 小文的前面有 4 人, 后面也有 4 人, 这队一共有 ( ) 人.", + "options": [ + "A. 8", + "B. 9", + "C. 10" + ], + "answer": "B", + "solution": "【分析】根据题意,用小文前面的人数加上小文后面的人数再加上小文自己 1 人,即可求出这队一共有多少人.\n【详解】4 + 4 + 1 = 9 (人);这队一共有 9 人.故答案为: B", + "knowledge_points": [ + "连加,连减(10以内)", + "前,后位置" + ], + "source": "25-26 一年级上·广东东莞·期中" + }, + { + "id": "3", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "下面算式中与 4 + 4 的得数相等的是 ( ).", + "options": [ + "A. 5 + 5", + "B. 7 + 2", + "C. 10 - 2" + ], + "answer": "C", + "solution": "【分析】先算出每个选项的结果,再和 4 + 4 的结果对比.\n【详解】4 + 4 = 8;A. 5 + 5 = 10 , 不符合题意;B. 7 + 2 = 9 , 不符合题意;C. 10 - 2 = 8 ,符合题意.因此算式中与 4 + 4 的得数相等的是 10 - 2 .故答案为: C", + "knowledge_points": [ + "8,9 的加减法", + "10 的加减法" + ], + "source": "25-26 一年级上·广东东莞·期中" + }, + { + "id": "4", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "王奶奶家养了 10 只鸡和 6 只鸭, 卖出了 2 只鸡, 还剩 ( ) 只鸡.", + "options": [ + "A. 8", + "B. 6", + "C. 4" + ], + "answer": "A", + "solution": "【分析】王奶奶家养了 10 只鸡, 卖出了 2 只鸡, 用王奶奶家养鸡的总只数减去卖出鸡的只数, 即可求出还剩下鸡的只数.\n【详解】10 - 2 = 8 (只);因此还剩下 8 只鸡.故答案为: A", + "knowledge_points": [ + "10 的加减法" + ], + "source": "25-26 一年级上·广东东莞·期中" + }, + { + "id": "5", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "4 后面第 6 个数是().", + "options": [ + "A. 10", + "B. 9", + "C. 8" + ], + "answer": "A", + "solution": "【分析】10以内数从小到大顺序为:1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 由此找到 4 后面第 6 个数即可.\n【详解】A.10是4后面的第6个数,符合题意.B. 9是4后面的第5个数,不符合题意.C. 8 是 4 后面的第 4 个数, 不符合题意.则 4 后面第 6 个数是 10 .故答案为: A", + "knowledge_points": [ + "10以内数的排序" + ], + "source": "2025 一年级上·全国·专题练习" + }, + { + "id": "6", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "小明有 6 支彩笔, 小红的彩笔比小明多 3 支, 小红有 ( ) 支彩笔.", + "options": [ + "A. 3", + "B. 9", + "C. 6" + ], + "answer": "B", + "solution": "【分析】根据题意, 小明彩笔的数量 + 小红比小明多的数量 = 小红彩笔的数量.\n【详解】6 + 3 = 9 (支);小红有 9 支彩笔.故答案为: B", + "knowledge_points": [ + "8,9 的加减法" + ], + "source": "25-26 一年级上·广东深圳·月考" + }, + { + "id": "7", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.94, + "question": "8 ○ 9 , ○ 里面应该填 ( ).", + "options": [ + "A. \u003e", + "B. \u003c", + "C. =" + ], + "answer": "B", + "solution": "【分析】9 以内数的大小比较: 0 \u003c 1 \u003c 2 \u003c 3 \u003c 4 \u003c 5 \u003c 6 \u003c 7 \u003c 8 \u003c 9 , 据此解答.\n【详解】由分析得:8 \u003c 9 , 所以 ○ 里面应该填 \u003c .故答案为: B", + "knowledge_points": [ + "9 以内数的比大小" + ], + "source": "25-26 一年级上·河北邢台·期中" + }, + { + "id": "8", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.94, + "question": "一共有 6 颗糖果, 月月吃了 2 颗, 还剩几颗? 正确的列式是 ( ).", + "options": [ + "A. 6 - 4 = 2 (颗)", + "B. 6 + 2 = 8 (颗)", + "C. 6 - 2 = 4 (颗)" + ], + "answer": "C", + "solution": "【分析】根据题意,需要用总数减去吃掉的数量,等于还剩下的糖果数量,据此解答.\n【详解】根据分析可得:6 - 2 = 4 (颗);因此,还剩下 4 颗糖果.一共有 6 颗糖果, 月月吃了 2 颗, 还剩几颗? 正确的列式是 6 - 2 = 4 (颗).故答案为: C", + "knowledge_points": [ + "6 的加减法" + ], + "source": "25-26 一年级上·河北邢台·期中" + }, + { + "id": "9", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "妈妈买了 2 盒月饼,每盒 4 个, 一共买了 ( ) 个月饼.", + "options": [ + "A. 2", + "B. 4", + "C. 8" + ], + "answer": "C", + "solution": "【分析】根据题意,买了 2 盒月饼,每盒有 4 个,求月饼的总数量,用加法计算,即一盒月饼的数量 + 另一盒月饼的数量 = 月饼的总数量.\n【详解】4 + 4 = 8 (个);一共买了 8 个月饼.故答案为: C", + "knowledge_points": [ + "8,9 的加减法" + ], + "source": "25-26 一年级上·江西九江·期中" + }, + { + "id": "10", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "5 后面第 4 个数是( ).", + "options": [ + "A. 8", + "B. 9", + "C. 10" + ], + "answer": "B", + "solution": "【分析】10以内数从小到大顺序为:1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 由此找到 5 后面的第 4 个数即可.\n【详解】由分析得:A. 8是5后面的第3个数,不符合题意;B. 9是5后面的第4个数,符合题意;C. 10 是 5 后面的第 5 个数, 不符合题意.则 5 后面第 4 个数是 9 .故答案为: B", + "knowledge_points": [ + "10以内数的排序" + ], + "source": "25-26 一年级上·江西九江·期中" + }, + { + "id": "11", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "从 0 数到 6 , 一共数了 ( ) 个数.", + "options": [ + "A. 6", + "B. 7", + "C. 8" + ], + "answer": "B", + "solution": "【分析】从 0 数到 6 , 包括 0 和 6 , 依次为0, 1, 2, 3, 4, 5, 6, 数出数字的个数即可.\n【详解】由分析得:从 0 数到 6 , 一共数了 7 个数.故答案为: B", + "knowledge_points": [ + "9 以内数的排序", + "数一数" + ], + "source": "25-26 一年级上·江西九江·期中" + }, + { + "id": "12", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.94, + "question": "数字2和数字6之间有()个数.", + "options": [ + "A. 5", + "B. 3", + "C. 4" + ], + "answer": "B", + "solution": "【分析】根据10以内数的排列顺序0,1,2,3,4,5,6,7,8,9,10,数一数 2,3,4,5,6,即可知道数字 2 和数字 6 之间有 3 个数.\n【详解】由分析可知, 数字 2 和数字 6 之间有 3 个数.故答案为: B", + "knowledge_points": [ + "10以内数的排序" + ], + "source": "25-26一年级上·河南周口·阶段练习" + }, + { + "id": "13", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "如果 2 + □ \u003c 8 那么 □ 里填几?()", + "options": [ + "A. 6", + "B. 比 6 小的数", + "C. 比 6 大的数" + ], + "answer": "B", + "solution": "【分析】把 \"\u003c\" 看成 \"=\" , 8 可以分成 2 和 6 , 所以 2 + 6 = 8 , 此时 □ 等于 6 , 如果 2 + □ \u003c 8 , 则 □ 的数必须是比 6 小的数, 据此解答.\n【详解】根据分析可得:如果 2 + □ \u003c 8 , 那么 □ 里填比 6 小的数.故答案为: B", + "knowledge_points": [ + "8,9 的加减法", + "9 以内数的比大小" + ], + "source": "24-25一年级上·河南驻马店·期中" + }, + { + "id": "14", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.94, + "question": "左边盘里有6个桔子,右边盘里有4个桔子,如果左边盘里的桔子个数不变,再往右边盘子里放()个桔子,这样两个盘里桔子就同样多了.", + "options": [ + "A. 2", + "B. 3", + "C. 4" + ], + "answer": "A", + "solution": "【分析】用左边盘里的桔子个数减去右边盘里的桔子个数,即可求出再往右边盘子里放几个桔子,两个盘里的桔子就同样多.\n【详解】6 - 4 = 2 (个);左边盘里有 6 个桔子, 右边盘里有 4 个桔子, 如果左边盘里的桔子个数不变, 再往右边盘子里放 2 个桔子, 这样两个盘里桔子就同样多了.故答案为: A", + "knowledge_points": [ + "6 的加减法", + "\"一样多\"问题" + ], + "source": "24-25一年级上·河南驻马店·期中" + }, + { + "id": "15", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "小明有 9 支铅笔,弄丢了 3 支, △? 算式 9 - 3 = 6 (支) 解决的问题是 ( ).", + "options": [ + "A. 还剩多少本书?", + "B. 还剩多少支铅笔?", + "C. 一共有多少支?" + ], + "answer": "B", + "solution": "【分析】根据题意可知: 9 - 3 = 6 , 用减法计算, 则 9 为题干中给出的总铅笔数, 3 为弄丢的数量, 用 9-3 表示的是用总数量减去弄丢的数量即为还剩的数量.\n【详解】A.还剩多少本书?题干中未给出和书本相关的条件,则不符合题意. B. 还剩多少支铅笔? 用小明有的数量减去弄丢的数量, 符合题意. C. 一共有多少支? 求一共的数量, 一般用加法计算, 不符合题意.故答案为: B", + "knowledge_points": [ + "\"提问题\"\"填条件\"问题", + "8,9的加减法" + ], + "source": "24-25 一年级上·浙江温州·期中" + }, + { + "id": "16", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.94, + "question": "桌子上有 5 块牛奶糖, 有 4 块水果糖, 一共有多少块糖? 算式 ( ) 块.", + "options": [ + "A. 5 + 4 = 9", + "B. 4 + 1 = 5", + "C. 9 - 5 = 4" + ], + "answer": "A", + "solution": "【分析】根据题意可知, 牛奶糖的块数加水果糖的块数,等于一共有多少块糖, 据此解答.\n【详解】根据分析可得:桌子上有 5 块牛奶糖, 有 4 块水果糖, 一共有多少块糖? 算式 5 + 4 = 9 (块).故答案为: A", + "knowledge_points": [ + "8,9 的加减法" + ], + "source": "24-25 一年级上·河南驻马店·期中" + }, + { + "id": "17", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "下面关于 10 的说法中, 不正确的是 ( ).", + "options": [ + "A. 9 添上 1", + "B. 一双手", + "C. 比 7 少 3" + ], + "answer": "C", + "solution": "【分析】逐一分析各选项,找出不正确的即可.\n【详解】A. \"9 添上 1\"的意思是 9 加 1, 即 9 + 1 = 10 , 因此关于 10 的说法正确;B. 一只手有 5 根手指, 一双手就是有 5 + 5 = 10 (根) 手指,因此关于 10 的说法正确;C. \"比 7 少 3 \" 的意思是用 7 减 3 , 即 7 - 3 = 4 , 因此关于 10 的说法不正确.故答案为: C", + "knowledge_points": [ + "7 的加减法", + "10 的加减法" + ], + "source": "24-25 一年级上·浙江温州·期中" + }, + { + "id": "18", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.94, + "question": "小丽认为: 6 和 8 中间的数是 ( ).", + "options": [ + "A. 7", + "B. 8", + "C. 9" + ], + "answer": "A", + "solution": "【分析】9 以内数从小到大顺序为:0,1,2,3,4,5,6,7,8,9,据此找出6和8中间的数即可.\n【详解】根据 9 以内数从小到大的顺序可知, 6 和 8 中间的数是 7 .故答案为: A", + "knowledge_points": [ + "9 以内数的排序" + ], + "source": "24-25 一年级上·河南驻马店·期中" + }, + { + "id": "19", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.94, + "question": "李奶奶种了两行小树,一行有 4 棵,另一行有 5 棵,一共种了多少棵?列式是().", + "options": [ + "A. 5×4", + "B. 5×2", + "C. 4 + 5" + ], + "answer": "C", + "solution": "【分析】根据题意, 将第一行和第二行小树的棵数相加即可求出两行一共有多少棵小树, 列式 4 + 5 = 9 (棵), 据此选择即可.\n【详解】根据分析可知: 李奶奶种了两行小树, 一行有 4 棵,另一行有 5 棵, 一共种了多少棵? 列式是 4 + 5 .故答案为: C", + "knowledge_points": [ + "8,9 的加减法" + ], + "source": "25-26 二年级上·河北邢台·阶段练习" + }, + { + "id": "20", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.94, + "question": "根据\"有 6 只小鸡,2 只母鸡\"这两个信息,可以解决下面的问题().", + "options": [ + "A. 一共几只鸡?", + "B. 草丛里藏了几只小鸡?", + "C. 草丛里藏了几只母鸡?" + ], + "answer": "A", + "solution": "【分析】根据题意, 知道小鸡的数量, 知道母鸡的数量,可以用加法计算出一共有多少只鸡, 由此解答.\n【详解】A.求一共有几只鸡,用小鸡的数量加母鸡的数量,即 6 + 2 = 8 (只),可以解决这个问题;B. 求草丛里藏了几只小鸡, 就要知道草丛外小鸡的数量,题干中没有对应的信息,所以不能解决这个问题;C. 求草丛里藏了几只母鸡, 就要知道草丛外母鸡的数量,题干中没有对应的信息,所以不能解决这个问题;可以解决的问题是一共有几只鸡?故答案为: A", + "knowledge_points": [ + "\"提问题\"\"填条件\"问题", + "8,9的加减法" + ], + "source": "25-26 一年级上·全国·期中" + }, + { + "id": "21", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.94, + "question": "一盒饼干有9块,丽丽吃了1块,丽丽的朋友们吃了7块.他们一共吃了多少块? ( ).", + "options": [ + "A. 1 块", + "B. 8块", + "C. 9块" + ], + "answer": "B", + "solution": "【分析】根据题意可知,丽丽吃的块数加朋友们吃的块数,等于他们一共吃了多少块,据此解答.\n【详解】根据分析可得:1 + 7 = 8 (块);因此,他们一共吃了8块.故答案为: B", + "knowledge_points": [ + "8,9 的加减法" + ], + "source": "24-25 一年级上·河南驻马店·期中" + }, + { + "id": "22", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.94, + "question": "下面哪道算式的得数最小? ( ).", + "options": [ + "A. 8 + 0", + "B. 8 - 0", + "C. 8 - 8" + ], + "answer": "C", + "solution": "【分析】根据题意,可逐项计算,求出结果后比较大小,9以内数从小到大的顺序: 0 \u003c 1 \u003c 2 \u003c 3 \u003c 4 \u003c 5 \u003c 6 \u003c 7 \u003c 8 \u003c 9 ,据此比较.\n【详解】A. 8 + 0 = 8;B. 8 - 0 = 8;C. 8 - 8 = 0;8 = 8 \u003e 0;因此,8-8 的得数最小.故答案为: C", + "knowledge_points": [ + "有关 0 的加减法", + "9 以内数的比大小" + ], + "source": "24-25 一年级上·河南驻马店·期中" + }, + { + "id": "23", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.94, + "question": "小红有 10 个苹果,小丽有 6 个苹果, 小丽再拿 ( ) 个苹果就和小红的同样多.", + "options": [ + "A. 6", + "B. 4", + "C. 5" + ], + "answer": "B", + "solution": "【分析】用小红的苹果个数减去小丽的苹果个数, 即可求出小丽再拿几个苹果就和小红的同样多.\n【详解】10 - 6 = 4 (个);小红有 10 个苹果, 小丽有 6 个苹果, 小丽再拿 4 个苹果就和小红的同样多.故答案为: B", + "knowledge_points": [ + "10 的加减法" + ], + "source": "24-25 一年级上·浙江温州·期中" + }, + { + "id": "24", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.94, + "question": "妈妈买了 6 包奶,笑笑喝了 2 包, 如果列出算式 6 - 2 = 4 , 那么所求的问题是 ( ).", + "options": [ + "A. 一共买了几包奶", + "B. 喝了几包奶", + "C. 还剩几包奶" + ], + "answer": "C", + "solution": "【分析】根据题意, 算式 6 - 2 = 4 表示用妈妈买奶的总包数减去笑笑喝奶的包数, 即可求出还剩几包奶, 据此逐一分析三个选项, 找出正确答案.\n【详解】A. 一共买了几包奶, 是题中的已知条件, 妈妈买了 6 包奶, 不是所求的问题, 不符合题意;B. 喝了几包奶, 是题中的已知条件, 笑笑喝了 2 包, 不是所求的问题, 不符合题意;C. 还剩几包奶, 用妈妈买奶的总包数减去笑笑喝奶的包数,即可求出还剩几包奶,是所求的问题,符合题意.故答案为: C", + "knowledge_points": [ + "\"提问题\"\"填条件\"问题", + "6的加减法" + ], + "source": "24-25 一年级上·河南商丘·期中" + }, + { + "id": "25", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.94, + "question": "草地上有5只小白兔,有4只小灰兔,有7只小黑兔.只数最少的是().", + "options": [ + "A. 小白兔", + "B. 小灰兔", + "C. 小黑兔" + ], + "answer": "B", + "solution": "【分析】9 以内数从小到大顺序为: 0 \u003c 1 \u003c 2 \u003c 3 \u003c 4 \u003c 5 \u003c 6 \u003c 7 \u003c 8 \u003c 9 , 据此比较三种兔子只数的多少, 找出只数最少的选项即可.\n【详解】7 \u003e 5 \u003e 4;草地上有 5 只小白兔, 有 4 只小灰兔, 有 7 只小黑兔.只数最少的是小灰兔.故答案为: B", + "knowledge_points": [ + "9以内数的比大小" + ], + "source": "24-25一年级上·河南驻马店·期中" + }, + { + "id": "26", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.94, + "question": "在下面的数中,()是最大的.", + "options": [ + "A. 6", + "B. 9", + "C. 8" + ], + "answer": "B", + "solution": "【分析】9 以内数从小到大顺序为: 0 \u003c 1 \u003c 2 \u003c 3 \u003c 4 \u003c 5 \u003c 6 \u003c 7 \u003c 8 \u003c 9 , 据此找出最大的数即可.\n【详解】比较选项中三个数的大小: 6 \u003c 8 \u003c 9.9 是最大的数.故答案为: B", + "knowledge_points": [ + "9以内数的比大小" + ], + "source": "24-25一年级上·河南驻马店·期中" + }, + { + "id": "27", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.94, + "question": "下面哪个问题可以用 4 + 2 解决? ( )", + "options": [ + "A. 第一小组有 4 个同学, 男生有 2 人, 女生有几人?", + "B. 有 4 支铅笔, 拿走 2 支, 还剩多少支?", + "C. 原来有 4 个苹果, 又买来 2 个, 现在一共有多少个苹果?" + ], + "answer": "C", + "solution": "【分析】根据题意可知,第一小组学生的总人数减去男生的人数,等于女生的人数;原有铅笔的支数减去拿走的支数,等于还剩下的支数;原有苹果的个数加上又买来的个数,等于现在苹果的总个数.逐项分析各个选项,找出可以用 4 + 2 解决的问题即可.\n【详解】A.第一小组有4个同学,男生有2人,女生有几人?根据分析可列式为: 4 - 2 = 2 (人),不能用 4 + 2 解决.B. 有 4 支铅笔, 拿走 2 支, 还剩多少支? 根据分析可列式为: 4 - 2 = 2 (支), 不能用 4 + 2 解决.C. 原来有 4 个苹果, 又买来 2 个, 现在一共有多少个苹果?根据分析可列式为: 4 + 2 = 6 (个).原来有 4 个苹果, 又买来 2 个, 现在一共有多少个苹果? 可以用 4 + 2 解决.故答案为: C", + "knowledge_points": [ + "6 的加减法", + "5 以内数的减法" + ], + "source": "24-25 一年级上·河南驻马店·期中" + }, + { + "id": "28", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.65, + "question": "8 可以分成 ( ).", + "options": [ + "A. 2 和 5", + "B. 1 和 7", + "C. 6和3" + ], + "answer": "B", + "solution": "【分析】根据 8 的分与合解答此题, 8 可以分成 1 和 7, 2 和 6, 3 和 5, 4 和 4, 逐项分析各个选项, 找出正确答案即可.\n【详解】A.2和5,7可以分成2和5,选项错误;B. 1 和 7, 8 可以分成 1 和 7, 选项正确;C. 6 和 3, 9 可以分成 6 和 3, 选项错误.故答案为: B", + "knowledge_points": [ + "6,7 的分与合(组成)", + "8,9 的分与合(组成)" + ], + "source": "24-25 一年级上·陕西延安·期中" + }, + { + "id": "29", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.94, + "question": "7\u003c □ , □ 里可以填 ( ).", + "options": [ + "A. 6", + "B. 7", + "C. 8" + ], + "answer": "C", + "solution": "【分析】由题意可知:7 小于这个数,这个数比 7 大,比 7 大的数有:8,9 等;据此可选择.\n【详解】由分析可得:7\u003c □ , □ 里可以填 8.故答案为: C", + "knowledge_points": [ + "10以内数的比大小" + ], + "source": "24-25 一年级上·陕西延安·期中" + }, + { + "id": "30", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.94, + "question": "6 的前一个数是( ),后一个数是( );7和9的中间的数是( ),与5相邻的两个数是( )和( ).", + "options": [ + + ], + "answer": "5;7;8;4;6", + "solution": "【分析】9 以内数从小到大顺序为:1,2,3,4,5,6,7,8,9;根据每个数所在的位置解答即可.\n【详解】6 的前一个数是 5 , 后一个数是 7;7 和 9 的中间的数是 8 , 与 5 相邻的两个数是 4 和 6 .", + "knowledge_points": [ + "9以内数的排序" + ], + "source": "25-26 一年级上·新疆喀什·期中" + }, + { + "id": "31", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "把一些课外书分给张明和李飞,如果张明分得6本,李飞就分得4本;如果张明分得3本,那么李飞会得到( )本.", + "options": [ + + ], + "answer": "7", + "solution": "【分析】根据题意,张明分得6本,李飞就分得4本,先用加法算出总共有多少本书,然后用书的总数减去分给张明3本,即可求出李飞会得到多少本书.\n【详解】6 + 4 = 10 (本);10 - 3 = 7 (本),因此李飞会得到7本书.", + "knowledge_points": [ + "10 的加减法" + ], + "source": "25-26一年级上·全国·周测" + }, + { + "id": "32", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "从 1 开始数, 第 8 个数是( );从 10 开始倒着数,第 4 个数是( ).", + "options": [ + + ], + "answer": "8;7", + "solution": "【分析】从 1 开始数,依次为1, 2, 3, 4, 5, 6, 7, 8, 9, 10...从 10 开始倒着数,依次为 10, 9, 8, 7, 6, 5, 4, 3, 2, 1, 0, 由此找到对应的数.\n【详解】由分析得:从 1 开始数, 第 8 个数是 8;从 10 开始倒着数, 第 4 个数是 7.", + "knowledge_points": [ + "10以内数的排序", + "认识几和第几" + ], + "source": "25-26 一年级上·广东深圳·月考" + }, + { + "id": "33", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "填一填数的分与合.\n(1)8 可以分成 3 和 ( ),也可以分成 ( )和 4.\n(2)9 能分成( )和 4 , 7 和( )合起来是 10 .", + "options": [ + + ], + "answer": "5;4;5;3", + "solution": "【分析】(1)根据 8 的分解填写:8 可以分成 1 和 7;8 可以分成 2 和 6;8 可以分成 3 和 5;8 可以分成 4 和 4;8 可以分成 5 和 3;8 可以分成 6 和 2;8 可以分成 7 和 1;(2) 根据 9 的分解填写: 9 可以分成 1 和 8;9 可以分成 2 和 7;9 可以分成 3 和 6;9 可以分成 4 和 5;9 可以分成 5 和 4;9 可以分成 6 和 3;9 可以分成 7 和 2;9 可以分成 8 和1;根据 10 的组成填写:1 和 9 合起来就是 10;2 和 8 合起来就是 10;3 和 7 合起来就是 10;4 和 6 合起来就是 10;5 和 5 合起来就是 10;6 和 4 合起来就是 10;7 和 3 合起来就是 10;8 和 2 合起来就是 10;9 和 1 合起来就是 10.\n【详解】(1)8 可以分成 3 和 5,也可以分成 4 和 4.(2) 9 能分成 5 和 4, 7 和 3 合起来是 10.", + "knowledge_points": [ + "10 的分与合(组成)", + "8,9的分与合(组成)" + ], + "source": "25-26 一年级上·广东深圳·月考" + }, + { + "id": "34", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.94, + "question": "在□里填上合适的数.\n\n![](images/112931.png)", + "options": [ + + ], + "answer": "5;7;4;4;5;5;4;3", + "solution": "【分析】根据数的分与合进行解答.7 可以分为 2 和 5;10 可以分为 3 和 7;6 可以分为 2 和 4;8 可以分为 4 和 4;10 可以分为 5 和 5;7 可以分为 2 和 5;9 可以分为 5 和 4;6 和 3 合起来是 9 .\n【详解】由分析可知:![](images/114213.png)", + "knowledge_points": [ + "6,7 的分与合(组成)", + "10 的分与合(组成)", + "8,9 的分与合 (组成)" + ], + "source": "25-26 一年级上·河北邯郸·月考" + }, + { + "id": "35", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.94, + "question": "在括号内填上\"\u003e\" \"\u003c\"或\"=\".\n2 ( ) 4\n5 ( ) 4\n3 ( ) 3\n0 ( ) 1", + "options": [ + + ], + "answer": "\u003c;\u003e;=;\u003c", + "solution": "【分析】根据 10 以内数的排列顺序比较大小, 排在后面的数比前面的数大.\n【详解】根据分析可知:2 \u003c 4;5 \u003e 4;3 = 3;0 \u003c 1", + "knowledge_points": [ + "10以内数的比大小" + ], + "source": "25-26 一年级上·广东广州·月考" + }, + { + "id": "36", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.94, + "question": "比 7 大比 10 小的数有( ).", + "options": [ + + ], + "answer": "8,9", + "solution": "【分析】10以内数从大到小关系为: 10 \u003e 9 \u003e 8 \u003e 7 \u003e 6 \u003e 5\u003e 4 \u003e 3 \u003e 2 \u003e 1 ,由此找到大于7小于10的数即可.\n【详解】由分析得:比7大比10小的数有8,9.", + "knowledge_points": [ + "10以内数的比大小" + ], + "source": "25-26 一年级上·江西九江·期中" + }, + { + "id": "37", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.94, + "question": "与 6 相邻的两个数是( )和( );9 减 1 等于( ).", + "options": [ + + ], + "answer": "5;7;8", + "solution": "【分析】与一个数相邻的两个数分别是比它小 1 和比它大 1 的数, 用 6 减 1 , 6 加 1 , 即可求出 6 相邻的两个数, 求 9 减 1 是多少, 也就是比 9 少 1 的数, 据此解答.\n【详解】6 - 1 = 5;6 + 1 = 7;9 - 1 = 8;因此,与 6 相邻的两个数是 5 和 7;9 减 1 等于 8.", + "knowledge_points": [ + "8,9 的加减法", + "6 的加减法", + "7 的加减法" + ], + "source": "25-26 一年级上·河北邢台·期中" + }, + { + "id": "38", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.65, + "question": "在4,3,0,8,9,5中,最大的数是( ),最小的数是(),大于5的数有( )个.", + "options": [ + + ], + "answer": "9;0;2", + "solution": "【分析】9 以内数从大到小关系为 9 \u003e 8 \u003e 7 \u003e 6 \u003e 5 \u003e 4 \u003e 3 \u003e 2 \u003e1 \u003e 0 , 由此比较数字, 找到最大的数, 最小的数, 以及比 5 大的数即可.\n【详解】由分析得:9 \u003e 8 \u003e 5 \u003e 4 \u003e 3 \u003e 0,在 4,3,0,8,9,5 中,最大的数是 9,最小的数是 0,大于 5 的数有 2 个.", + "knowledge_points": [ + "9 以内数的比大小" + ], + "source": "25-26 一年级上·江西九江·期中" + }, + { + "id": "39", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "在括号里填上\"+\"或\"-\".\n4 ( ) 4 = 0\n5 = 7 ( ) 2\n0 ( ) 7 = 7\n9 ( ) 3 = 6", + "options": [ + + ], + "answer": "-;-;+;-", + "solution": "【分析】根据整数加减法的计算法则,通过数的分与合判断括号内应填\"+\"或\"-\".\n第1题:4减去4就得0,填写\"-\";第2题:7可以分成2和5,填写\"-\";第3题:0加上7就得7,填写\"+\";第4题:9可以分成3和6,填写\"-\".\n【详解】由分析填写如下:4 - 4 = 0;5 = 7 - 2;0 + 7 = 7;9 - 3 = 6", + "knowledge_points": [ + "8,9 的加减法", + "有关 0 的加减法", + "7 的加减法", + "8,9 的分与合 (组成)" + ], + "source": "25-26一年级上·江西九江·期中" + }, + { + "id": "40", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.94, + "question": "在5,2,4,7,8,1中,最小的数字是( ),最大的数字是( ).把这些数按从大到小的顺序排列( ).", + "options": [ + + ], + "answer": "1;8;8\u003e7\u003e5\u003e4\u003e2\u003e1", + "solution": "【分析】根据 10 以内大小关系比较进行解答, 10 以内数从小到大为: 0 \u003c 1 \u003c 2 \u003c 3 \u003c 4 \u003c 5 \u003c 6 \u003c 7 \u003c 8 \u003c 9 \u003c 10 .\n【详解】由分析得:8 \u003e 7 \u003e 5 \u003e 4 \u003e 2 \u003e 1;所以在 5,2,4,7,8,1 最小的数字是 1 , 最大的数字是 8 .把这些数按从大到小的顺序排列 8 \u003e 7 \u003e 5 \u003e 4 \u003e 2 \u003e 1 .", + "knowledge_points": [ + "10以内数的比大小", + "10以内数的排序" + ], + "source": "25-26 一年级上·河南周口·阶段练习" + }, + { + "id": "41", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.94, + "question": "在括号里填 \"\u003e\" \"\u003c\" 或 \"=\".\n5 ( ) 7\n7 ( ) 4\n4 ( ) 6\n2 ( ) 2", + "options": [ + + ], + "answer": "\u003c;\u003e;\u003c;=", + "solution": "【分析】根据7以内数比较大小即可.7 \u003e 6 \u003e 5 \u003e 4 \u003e 3 \u003e 2 \u003e 1 \u003e 0\n【详解】5 \u003c 7;7 \u003e 4;4 \u003c 6;2 = 2", + "knowledge_points": [ + "7 以内数的比大小" + ], + "source": "25-26 一年级上·河南周口·阶段练习" + }, + { + "id": "42", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.65, + "question": "10,9,8,3,0,5,2,7,这里共有( )个数,其中最大的数是( ),最小的数是( ),把这些数从小到大排列起来( ).", + "options": [ + + ], + "answer": "8;10;0;0 \u003c 2 \u003c 3 \u003c 5 \u003c 7 \u003c 8 \u003c 9 \u003c 10", + "solution": "【分析】10,9,8,3,0,5,2,7中,数一数一共有8个数;其中最大的数是10,最小的数是0;再比较大小,按照从小到大排列即可.\n【详解】10,9,8,3,0,5,2,7,这里共有8个数,其中最大的数是 10 , 最小的数是 0 , 把这些数从小到大排列起来 0\u003c2\u003c3\u003c5\u003c7\u003c8\u003c9\u003c10 .", + "knowledge_points": [ + "10以内数的比大小", + "数一数" + ], + "source": "25-26 一年级上·河北邯郸·阶段练习" + }, + { + "id": "43", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.94, + "question": "10 个一是( ),6 个一组成的数是( ).", + "options": [ + + ], + "answer": "10;6", + "solution": "【分析】因为 1 个一是 1 , 所以 10 个一就是 10 , 6 个一组成的数就是 6 , 据此解答.\n【详解】由分析得:10 个一是 10, 6 个一组成的数是 6.", + "knowledge_points": [ + "10 的认识和读写", + "6,7 的认识和读写" + ], + "source": "25-26 一年级上·河北邯郸·阶段练习" + }, + { + "id": "44", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.65, + "question": "比 4 少 1 的数是( ),比 8 多 2 的数是( ).", + "options": [ + + ], + "answer": "3;10", + "solution": "【分析】比 4 少 1 的数, 也就是 4 - 1 = 3;比 8 多 2 的数,也就是 8 + 2 = 10 .\n【详解】比4少1的数是3,比8多2的数是 10.", + "knowledge_points": [ + "8,9 的加减法", + "5 以内数的减法" + ], + "source": "25-26 一年级上·河北邯郸·阶段练习" + }, + { + "id": "45", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "把 7 只小鸡关进 2 个鸡笼里(每个笼子里都有鸡),每个鸡笼关进的鸡(会,不会)同样多.", + "options": [ + + ], + "answer": "不会", + "solution": "【分析】根据 7 的分与合, 7 可以分成 1 和 6, 2 和 5, 3 和 4, 所以 7 不能分成同样多.\n【详解】7 可以分成 1 和 6, 2 和 5, 3 和 4, 所以把 7 只小鸡关进 2 个鸡笼里(每个笼子里都有鸡),每个鸡笼关进的鸡不会同样多.", + "knowledge_points": [ + "6,7 的分与合(组成)" + ], + "source": "24-25 一年级上·广东东莞·期中" + }, + { + "id": "46", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.94, + "question": "在括号里填上 \"+\" 或 \"-\".\n3 ( ) 1 = 4\n2 ( ) 0 = 2\n7 ( ) 1 = 8", + "options": [ + + ], + "answer": "+;+;+", + "solution": "【分析】等号右边的数大于左边括号前面的数则填 \"+\",等号右边的数小于左边括号前面的数则填 \"-\".任何数加减 0 都等于它本身.\n【详解】由分析可知: 3 + 1 = 4;2 + 0 = 2 (答案不唯一);7 + 1 = 8", + "knowledge_points": [ + "8,9 的加减法", + "有关 0 的加减法", + "5 以内数的加法" + ], + "source": "25-26 一年级上·全国·期中" + }, + { + "id": "47", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.94, + "question": "在括号里填上 \"\u003e\" \"\u003c\" 或 \"=\".\n4 + 3 ( ) 3 + 3\n5 + 4 ( ) 0 + 8\n6 - 3 ( ) 6 - 2", + "options": [ + + ], + "answer": "\u003e;\u003e;\u003c", + "solution": "【分析】根据题意,先计算出两边算式的结果,再比较大小.\n【详解】4 + 3 = 7, 3 + 3 = 6, 7 \u003e 6 ,则 4 + 3 \u003e 3 + 3;5 + 4 = 9, 0 + 8 = 8, 9 \u003e 8 ,则 5 + 4 \u003e 0 + 8;6 - 3 = 3, 6 - 2 = 4, 3 \u003c 4 ,则 6 - 3 \u003c 6 - 2", + "knowledge_points": [ + "8,9 的加减法", + "6 的加减法", + "10 以内数的比大小", + "7 的加减法" + ], + "source": "25-26 一年级上·全国·期中" + }, + { + "id": "48", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.94, + "question": "体育课上, 同学们排成一队.小刚前面有 3 人, 后面有 4 人.这队一共有( )人.", + "options": [ + + ], + "answer": "8", + "solution": "【分析】根据题意可知, 小刚前面的人数加他后面的人数,再加上小刚自己, 等于这队的总人数, 据此解答.\n【详解】根据分析可得:3 + 4 + 1 = 8 (人),体育课上,同学们排成一队.小刚前面有 3 人,后面有 4 人.这队一共有 8 人.", + "knowledge_points": [ + "连加,连减(10以内)" + ], + "source": "24-25 一年级上·河南驻马店·期中" + }, + { + "id": "49", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.94, + "question": "在括号里填上 \"+\" 或 \"-\".\n2 ( ) 2 = 4\n3 ( ) 2 = 1\n3 ( ) 1 = 5 ( ) 1", + "options": [ + + ], + "answer": "+;-;+;-", + "solution": "【分析】根据整数加减法的计算法则选择合适的运算符号进行填空,可以先观察算式,如果等号右面的数比等号左边的两个数都大填\"+\",如果等号右边的数比等号左边最大的数小填\"-\".一般情况下,加法会让得数多或不变,减法运算会让得数变少或不变,据此解答.\n【详解】2( ) 2 = 4 ,等号右面的数是4,比等号左边的两个数都大,填\"+\",故 2 + 2 = 4;3( ) 2 = 1 ,等号右边的数是1,比等号左边最大的数3还要小,填\"-\",故 3 - 2 = 1;3 ( ) 1 = 5 ( ) 1, 左边: 3 + 1 = 4;3 - 1 = 2;右边: 5 + 1 = 6 , 5 - 1 = 4;左边填加号得 4 , 右边填减号也得 4 , 两边相等, 故 3 + 1 = 5 - 1 .", + "knowledge_points": [ + "6 的加减法", + "5 以内数的加法", + "5 以内数的减法" + ], + "source": "25-26 一年级上·河南南阳·阶段练习" + }, + { + "id": "50", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "在括号里填上合适的数.\n9 - ( ) = 5\n7 + ( ) = 7\n2 + ( ) = 10\n( ) - 5 = 1", + "options": [ + + ], + "answer": "4;0;8;6", + "solution": "【分析】想:(4) +5 = 9 ,所以 9 - 4 = 5;7 可以分成 7 和 0 , 所以 7 + 0 = 7;10 可以分成 2 和 8, 所以 2 + 8 = 10;想: 1 + 5 = 6 , 所以 6 - 5 = 1 .\n【详解】9 - 4 = 5;7 + 0 = 7;2 + 8 = 10;6 - 5 = 1", + "knowledge_points": [ + "8,9 的加减法", + "10 的分与合(组成)", + "10 的加减法", + "8,9 的分与合(组成)" + ], + "source": "24-25一年级上·陕西延安·期中" + }, + { + "id": "51", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "判断题", + "difficulty": 0.65, + "question": "爸爸买来 10 个桔子,我和妹妹每人吃 2 个, 还剩下 8 个桔子.( )", + "options": [ + + ], + "answer": "×", + "solution": "【分析】一共 10 个桔子, 两人各吃 2 个, 共吃掉:2 + 2 = 4 (个),那么剩下的桔子数量为: 10 - 4 = 6 (个),所以题目中还剩 8 个是错误的.\n【详解】求剩下几个桔子,用桔子总数减去吃掉的桔子数量即可:10 - 4 = 6 (个).故答案为: ×", + "knowledge_points": [ + "10 的加减法" + ], + "source": "25-26 一年级上·广东东莞·期中" + }, + { + "id": "52", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "判断题", + "difficulty": 0.85, + "question": "9 可以分成 6 和 3,也可以分成 2 和 7,还可以分成 4 和 5.()", + "options": [ + + ], + "answer": "√", + "solution": "【分析】根据9的分解知识,判断给出的分解组合是否正确.\n【详解】6 + 3 = 9 ,所以9可以分成6和3;2 + 7 = 9 , 所以 9 可以分成 2 和 7;4 + 5 = 9 , 所以 9 可以分成 4 和 5.题目中列举的三种分解方式均符合 9 的分解规则, 因此说法正确.故答案为: √", + "knowledge_points": [ + "8,9 的分与合 (组成)" + ], + "source": "25-26 一年级上·广东东莞·期中" + }, + { + "id": "53", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "判断题", + "difficulty": 0.94, + "question": "按从小到大的顺序,7后面一个数是8, 7的前面一共有6个数.( )", + "options": [ + + ], + "answer": "×", + "solution": "【分析】按从小到大的顺序, 7 之后紧接着的数就是 8 .题目中 \"7 的前面一共有 6 个数\" 是否正确, 需考虑数的范围.根据教材, 学生已学过 0 , 因此 7 前面的数包括 0 至 6 , 共 7 个, 而非 6 个.\n【详解】由分析得:按从小到大的顺序,7 后面的一个数是 8(正确).但 7 前面的数应为 0,1,2,3,4,5,6,共 7 个数,而非 6 个.因此题目中的说法错误.故答案为: ×", + "knowledge_points": [ + "8,9 的认识和读写", + "10 以内数的排序", + "6,7 的认识和读写" + ], + "source": "25-26 一年级上·广东东莞·期中" + }, + { + "id": "54", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "判断题", + "difficulty": 0.85, + "question": "妈妈买 10 个鸡蛋,8 个鸭蛋, 送给爷爷 4 个鸡蛋, 还剩 4 个鸭蛋.( )", + "options": [ + + ], + "answer": "×", + "solution": "【分析】分别分析鸡蛋和鸭蛋的数量变化,即可解答.原有鸡蛋:10个,送给爷爷后减少:4个,剩余鸡蛋: 10 - 4 = 6 (个).原有鸭蛋:8个,题目未提及赠送鸭蛋,因此鸭蛋数量不变,仍为8个.\n【详解】剩余鸡蛋: 10 - 4 = 6 (个);鸭蛋数量不变,仍为8个.题目中描述 \"还剩 4 个鸭蛋\" 与实际情况不符, 因此判断为错误.故答案为: ×", + "knowledge_points": [ + "10 的认识和读写", + "10 的加减法" + ], + "source": "25-26 一年级上·广东东莞·期中" + }, + { + "id": "55", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "判断题", + "difficulty": 0.94, + "question": "5 + 4 = 9, 4 + 5 = 9, 这体现了加法交换律.( )", + "options": [ + + ], + "answer": "√", + "solution": "【分析】根据题意,5加4和4加5,加数5和4的位置被交换了,但是和都是9,所以加数交换和不变,是加法的交换律.\n【详解】5 + 4 = 9, 4 + 5 = 9 , 这体现了加法交换律是正确的.故答案为: √", + "knowledge_points": [ + "8,9 的加减法", + "整数加法交换律" + ], + "source": "25-26 一年级上·广东深圳·月考" + }, + { + "id": "56", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "判断题", + "difficulty": 0.85, + "question": "10 - 3 = 7, 7 + 3 = 10, 这两道算式的得数相关联.( )", + "options": [ + + ], + "answer": "√", + "solution": "【分析】根据题意,第一个算式为 10 减去 3 得到 7,第二个算式为 7 加上 3 得到 10,也就是一个数减去另一个数后,再加上相同的数,又得到了原来的数,即它们的得数是相关联的.\n【详解】由分析得:10 - 3 = 7, 7 + 3 = 10 , 这两道算式的得数相关联.原题说法正确.故答案为: √", + "knowledge_points": [ + "10 的加减法" + ], + "source": "25-26 一年级上·广东深圳·月考" + }, + { + "id": "57", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "判断题", + "difficulty": 0.94, + "question": "从 0 数到 9 有 10 个数.( )", + "options": [ + + ], + "answer": "√", + "solution": "【分析】从 0 数到 9 , 需要包含 0 和 9 在内的所有整数的个数.根据数数的规则, 起始数和结束数都应被计入总数.\n【详解】从0开始数,依次为0,1,2,3,4,5,6,7,8,9,共10个数.题目说法正确.故答案为: √", + "knowledge_points": [ + "数一数" + ], + "source": "25-26 一年级上·河南周口·阶段练习" + }, + { + "id": "58", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "判断题", + "difficulty": 0.94, + "question": "与5相邻的数只有4.( )", + "options": [ + + ], + "answer": "×", + "solution": "【分析】根据9以内排列顺序0,1,2,3,4,5,6,7,8,9;5 的前一个数是 4 ,后一个数是 6 ,因此与 5 相邻的数有两个.\n【详解】由分析可知: 与 5 相邻的数有 2 个, 前面是 4 , 后面是 6 .原题说法错误.故答案为: ×", + "knowledge_points": [ + "9以内数的排序", + "相邻的数" + ], + "source": "25-26一年级上·河南周口·阶段练习" + }, + { + "id": "59", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "判断题", + "difficulty": 0.94, + "question": "6 后面的一个数比 6 小.( )", + "options": [ + + ], + "answer": "×", + "solution": "【分析】根据 10 以内数从小到大的排列顺序,0,1,2,3,4,5,6,7,8,9,10,相邻两个数后一个数比前一个数大 1, 6 后面的数是 7, 7 比 6 大.\n【详解】由分析可知, 6 后面的数是 7, 7 比 6 大. 原题说法错误.故答案为: ×", + "knowledge_points": [ + "10以内数的比大小", + "10以内数的排序" + ], + "source": "25-26 一年级上·河南周口·阶段练习" + }, + { + "id": "60", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式.\n\n![](images/b6b9b30694d06b4bad51e13230d20553bc309d06b1099b343e0235cae3cc1cd4.jpg)\n\n□ ○ □ = □ (棵)", + "options": [ + + ], + "answer": "5 + 2 = 7 (棵)", + "solution": "【分析】用左边菜的棵数加上右边菜的棵数,即可求出菜的总棵数.\n【详解】5 + 2 = 7 (棵);一共有 7 棵菜.", + "knowledge_points": [ + "7 的加减法", + "图文问题" + ], + "source": "25-26 一年级上·新疆喀什·期中" + }, + { + "id": "61", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式.\n\n![](images/2cf3b58753e2278edbae3d81f15e102d7e8607b8fcdc7dd06f7c504744f81097.jpg)\n\n□ ○ □ = □ (个)", + "options": [ + + ], + "answer": "4 + 3 = 7 (个)", + "solution": "【分析】用左边桃子的个数加上右边桃子的个数, 即可求出桃子的总个数.\n【详解】4 + 3 = 7 (个);一共有 7 个桃子.", + "knowledge_points": [ + "7 的加减法", + "图文问题" + ], + "source": "25-26 一年级上·新疆喀什·期中" + }, + { + "id": "62", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "计算题", + "difficulty": 0.85, + "question": "列式计算.\n\n![](images/4a2adca6ea0e6b5c28ada0dfd469eba9f1e90049e7a19714b01adc6b0f624a87.jpg)\n\n□ ○ □ = □ (个)", + "options": [ + + ], + "answer": "5 + 4 = 9 (个)", + "solution": "【分析】根据题图,数一数左边有 5 个,右边有 4 个,用左边的数量 + 右边的数量 = 总数量.据此解答.\n【详解】根据分析:5 + 4 = 9 (个);一共有 9 个.", + "knowledge_points": [ + "8,9 的加减法", + "图文问题" + ], + "source": "25-26 二年级上·山东菏泽·月考" + }, + { + "id": "63", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式计算.\n\n![](images/9837625c70e8329423dfa937befce5ffdfa9ed33a3cf5c77b367393e5f0971a0.jpg)\n\n□ ○ □ = □ (个)", + "options": [ + + ], + "answer": "10 - 3 = 7 (个)", + "solution": "【分析】用梨的总个数减去右边梨的个数, 即可求出左边篮子里梨的个数.\n【详解】10 - 3 = 7 (个);左边篮子里有 7 个梨.", + "knowledge_points": [ + "10 的加减法", + "图文问题" + ], + "source": "25-26 一年级上·江西九江·期中" + }, + { + "id": "64", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式计算.\n\n![](images/1a3750af763bf78360710a5d0fed58680a5ee8f82769c5f52a9a63cb101e7120.jpg)\n\n□ ○ □ = □ (只)", + "options": [ + + ], + "answer": "3 + 3 = 6 (只)", + "solution": "【分析】根据题图可知,左边有 3 只蝴蝶,右边也有 3 只蝴蝶,求一共有多少只,用加法计算,左边蝴蝶的数量加右边蝴蝶的数量即可解答.\n【详解】根据分析可得:3 + 3 = 6 (只);因此,一共有 6 只蝴蝶.", + "knowledge_points": [ + "6 的加减法", + "图文问题" + ], + "source": "25-26 一年级上·河北邢台·期中" + }, + { + "id": "65", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式计算.\n\n![](images/8d6013d1ef49fd637a4ecd6f04686befee3546bd97b21231b621dd80f350d68f.jpg)\n\n□ ○ □ = □ (个)", + "options": [ + + ], + "answer": "7 - 4 = 3 (个)", + "solution": "【分析】由图可知, 总共有 7 个鸡蛋, 右边有 4 个鸡蛋, 要求左边篮子里的数量, 就用总数减去右边的数量, 即可解答.\n【详解】7 - 4 = 3 (个);因此左边篮子里有 3 个鸡蛋.", + "knowledge_points": [ + "7 的加减法", + "图文问题" + ], + "source": "25-26 一年级上·河北邢台·期中" + }, + { + "id": "66", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "计算题", + "difficulty": 0.94, + "question": "看图列式计算.\n\n![](images/61f0296bd634ef0437e818e84d03bc20dca6c184c2b0496e00d186477ded8203.jpg)\n\n□ ○ □ = □ (根)", + "options": [ + + ], + "answer": "2 + 2 + 4 = 8 (根)", + "solution": "【分析】根据题图可知,左边有 2 根小棒,中间有 2 根小棒,右边有 4 根小棒,求一共有多少根,用加法计算,左边小棒的数量加中间小棒的数量,再加右边小棒的数量,即可解答.\n【详解】根据分析可得:2 + 2 + 4 = 8 (根);因此,一共有 8 根小棒.", + "knowledge_points": [ + "连加,连减(10以内)", + "图文问题" + ], + "source": "25-26 一年级上·山西忻州·期中" + }, + { + "id": "67", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "计算题", + "difficulty": 0.94, + "question": "看图列式计算.\n\n![](images/942807a8c860ffb5ac083506ac7bf5833c6d99a7843edbed5f87209610df46d1.jpg)\n\n□ ○ □ = □ (支)", + "options": [ + + ], + "answer": "10 - 5 = 5 (支)", + "solution": "【分析】根据题图可知, 一共有 10 支铅笔, 文具盒外面有 5 支, 求文具盒里有几支, 用减法计算, 铅笔的总数量减去文具盒外边的数量, 即可解答.\n【详解】根据分析可得:![](images/60748400113682012afc18e317550c96b87a1ac8ee54a7f78ad7a8b835eba61b.jpg)\n10 - 5 = 5 (支),因此,文具盒里有5支铅笔.", + "knowledge_points": [ + "10 的加减法", + "图文问题" + ], + "source": "25-26 一年级上·山西忻州·期中" + }, + { + "id": "68", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "计算题", + "difficulty": 0.94, + "question": "看图列式计算.\n\n![](images/7f6f4cfd6798bb341d6d94076864710b711eb6080d4acbaf88e15a9a4b66589c.jpg)\n\n□ ○ □ = □ (只)", + "options": [ + + ], + "answer": "3 + 3 = 6 (只)", + "solution": "【分析】根据题图可知,一堆有 3 只小鸡,另一堆也有 3 只小鸡, 求一共有多少只, 用加法计算, 一堆的数量加上另一堆的数量即可.\n【详解】根据分析可得:3 + 3 = 6 (只);因此,一共有 6 只小鸡.", + "knowledge_points": [ + "6 的加减法", + "图文问题" + ], + "source": "25-26 一年级上·山西忻州·期中" + }, + { + "id": "69", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "计算题", + "difficulty": 0.94, + "question": "看图列式计算.\n\n![](images/1d791ffa3fc5abea152a99d02df597492b197d92118c61f4fc5ef2efce4b0cd5.jpg)\n\n□ ○ □ ○ □ = □ (条)", + "options": [ + + ], + "answer": "4 + 2 + 1 = 7 (条)", + "solution": "【分析】根据题图可知, 左边有 4 条小鱼, 中间有 2 条小鱼,右边有 1 条小鱼, 把它们相加, 即可求出一共有多少条小鱼.\n【详解】根据分析可得:4 + 2 + 1 = 7 (条);因此,一共有7条小鱼.", + "knowledge_points": [ + "连加,连减(10以内)", + "图文问题" + ], + "source": "2025 一年级上·全国·专题练习" + }, + { + "id": "70", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "计算题", + "difficulty": 0.94, + "question": "看图写算式.\n\n![](images/b4361d041c9912e8ad76370afe12d0a56f56d887d1484bf6f5c0414d18e7a13f.jpg)\n\n□ ○ □ = □ (个)", + "options": [ + + ], + "answer": "3 + 3 = 6 (个)", + "solution": "【分析】左边水果的个数加上右边水果的个数,就是一共有几个水果.\n【详解】3 + 3 = 6 (个);一共有 6 个水果.", + "knowledge_points": [ + "6 的加减法", + "图文问题" + ], + "source": "24-25 一年级上·河南·期中" + }, + { + "id": "71", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "计算题", + "difficulty": 0.94, + "question": "看图写算式.\n\n![](images/ac5c911ad6561cf9316ebd1d99e1a91bb746382cd6afeaef0010a7d21629e09b.jpg)\n\n□ ○ □ = □ (只)", + "options": [ + + ], + "answer": "3 + 4 = 7 (只)", + "solution": "【分析】根据题图,数一数可知,左边有 3 只鸡,右边有 4 只鸡,求一共有多少只鸡,用加法计算,左边的数量加右边的数量即可.\n【详解】根据分析可得:\n\n![](images/940688fb24b3a64a096c559655a7ce56a112280d8005028719cc3eb7393ee3bf.jpg)\n\n3 + 4 = 7 (只);因此,一共有 7 只鸡.", + "knowledge_points": [ + "7 的加减法", + "图文问题" + ], + "source": "24-25 一年级上·河南·期中" + }, + { + "id": "72", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.65, + "question": "小白鸭有9条鱼,小灰鸭有10条鱼,鸭妈妈又买来5条鱼,怎样分,两只小鸭才有同样多的鱼?", + "options": [ + + ], + "answer": "小白鸭分到3条鱼;小灰鸭分到2条鱼", + "solution": "【分析】把鸭妈妈又买来的鱼分成两部分,第一部分分给小白鸭,补足小灰鸭比小白鸭多的数量,第二部分分成相同的两份,分别分给小白鸭和小灰鸭,据此解答.\n【详解】10 - 9 = 1 (条),5 - 1 = 4 (条),2 + 2 = 4 (条),小白鸭分到鱼的数量是: 1 + 2 = 3 (条),小灰鸭分到鱼的数量是: 5 - 3 = 2 (条);答: 小白鸭分到 3 条鱼;小灰鸭分到 2 条鱼.", + "knowledge_points": [ + "10 的加减法", + "5 以内数的加法", + "5 以内数的减法" + ], + "source": "25-26一年级上·全国·周测" + }, + { + "id": "73", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.65, + "question": "解决生活中的数学问题.\n\n![](images/8ab9f52cbc0bab86421a52d37d67d262b89c0e209fcc2db92ff7e3ac283242d7.jpg)\n\n□ ○ □ = □ (个)", + "options": [ + + ], + "answer": "8 个;3 + 5 = 8", + "solution": "【分析】由图可知, 左边有 3 个毽子, 右边有 5 个毽子, 求毽子的总个数, 用加法计算, 即可解答.\n【详解】3 + 5 = 8 (个),答: 一共有 8 个毽子.", + "knowledge_points": [ + "8,9 的加减法", + "图文问题" + ], + "source": "25-26 一年级上·广东东莞·期中" + }, + { + "id": "74", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.65, + "question": "解决生活中的数学问题.\n\n![](images/2d01048cc9c383ae6889ce1a8e55781db1756d1f4e40949228a2f3165bba2bae.jpg)\n\n□ ○ □ = □ (根)", + "options": [ + + ], + "answer": "5 根;9 - 4 = 5", + "solution": "【分析】由图可知, 总共有 9 根玉米, 左边有 4 根玉米, 求右边篮子里玉米的数量, 用玉米的总数减去左边玉米的数量, 即可解答.\n【详解】9 - 4 = 5 (根),答: 右边篮子里有 5 根玉米.", + "knowledge_points": [ + "8,9 的加减法", + "图文问题" + ], + "source": "25-26 一年级上·广东东莞·期中" + }, + { + "id": "75", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.94, + "question": "房子里原来有 9 只小鸟.\n\n![](images/8e1607f0101aff1df1f9e40c9933275cf9b7d5896f5dd77a262e1ea20334639c.jpg)\n\n房子里还剩几只小鸟?\n\n□ ○ □ = □ (只)", + "options": [ + + ], + "answer": "4 只;9 - 5 = 4", + "solution": "【分析】根据题意,房子里原有 9 只小鸟,飞走了 5 只,求房子里还剩小鸟的只数,用房子里面原有小鸟的只数减去飞走的只数,即可解答.\n【详解】9 - 5 = 4 (只),答: 房子里还剩 4 只小鸟.", + "knowledge_points": [ + "8,9 的加减法", + "图文问题" + ], + "source": "25-26 一年级上·广东东莞·期中" + }, + { + "id": "76", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.94, + "question": "妈妈买来 10 个苹果.\n\n![](images/8f8878945034c0be8ef5bf3568faaee317849179bacf5e7071fe2afe73bf49be.jpg)\n\n妈妈让我拿4个送给奶奶.还剩下多少个苹果?\n\n□ ○ □ = □ (个)", + "options": [ + + ], + "answer": "6 个;10 - 4 = 6", + "solution": "【分析】根据题意,用苹果的总数减去拿走的数量,即可求出还剩下多少个.用减法列式计算.\n【详解】10 - 4 = 6 (个);答: 还剩下 6 个苹果.", + "knowledge_points": [ + "10 的加减法", + "图文问题" + ], + "source": "25-26 一年级上·广东东莞·期中" + }, + { + "id": "77", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.94, + "question": "我会解决问题.左边有()颗,右边有()颗,一共有几颗?\n\n![](images/977f702c6981a12ae6f72295fdd9812eaa4ee16ad5432779d1e97d4b7453336e.jpg)\n\n□ ○ □ = □ (颗)", + "options": [ + + ], + "answer": "5;3;8 颗;5 + 3 = 8", + "solution": "【分析】根据题图数一数可知,左边有 5 颗樱桃,右边有 3 颗樱桃,求一共有多少颗,用加法计算,左边樱桃的数量加右边樱桃的数量,即可解答.\n【详解】左边有 5 颗, 右边有 3 颗, 一共有几颗?5 + 3 = 8 (颗);答: 一共有 8 颗.", + "knowledge_points": [ + "左,右位置", + "8,9的加减法", + "图文问题" + ], + "source": "25-26 一年级上·新疆喀什·期中" + }, + { + "id": "78", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.65, + "question": "把一些课外书分给乐乐和美美,如果乐乐分得5本,美美就分得4本;如果乐乐分得3本,美美就能分得多少本?", + "options": [ + + ], + "answer": "6本", + "solution": "【分析】把一些课外书分给乐乐和美美,如果乐乐分得5本,美美就分得4本,这些课外书一共有 5 + 4 = 9 本.如果乐乐分得3本,美美就能分得多少本,用总本数减乐乐分得的本数即可, 9 - 3 = 6 本.\n【详解】总本数: 5 + 4 = 9 (本),美美分得的本数: 9 - 3 = 6 (本),答: 如果乐乐分得 3 本, 美美就能分得 6 本.", + "knowledge_points": [ + "9以内加减法实际应用" + ], + "source": "25-26 一年级上·全国·课后作业" + }, + { + "id": "79", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.65, + "question": "两根同样长的蜡烛,第一根燃烧了7厘米,第二根燃烧了4厘米,哪一根剩下的长,长多少厘米?", + "options": [ + + ], + "answer": "第二根,3厘米", + "solution": "【分析】两根同样长的蜡烛,第一根燃烧了 7 厘米,第二根燃烧了 4 厘米,哪一根剩下的长,同一个数减去的数越小,那么这个数越大,所以第二根剩下的长;长多少厘米,用第一根燃烧的长度减第二根燃烧的长度即可, 7 - 4 = 3 (厘米).\n【详解】两根同样长的蜡烛,第一根燃烧了 7 厘米,第二根燃烧了 4 厘米,因为 4 \u003c 7 ,所以第二根剩下的长;7 - 4 = 3 (厘米)答: 第二根剩下的长, 长 3 厘米.", + "knowledge_points": [ + "7的加减法" + ], + "source": "25-26一年级上·全国·课后作业" + }, + { + "id": "80", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.65, + "question": "一根18米长的绳子,第一次剪去了6米,第二次剪去了2米.这根绳子短了多少米?", + "options": [ + + ], + "answer": "8米", + "solution": "【分析】一根 18 米长的绳子, 第一次剪去了 6 米, 第二次剪去了 2 米, 问这根绳子短了多少米.用第一次剪去的长度 +第二次剪去的长度 = 这根绳子短的长度, 即 6 + 2 = 8 米.\n【详解】6 + 2 = 8 (米);答: 这根绳子短了 8 米.", + "knowledge_points": [ + "8,9 的加减法" + ], + "source": "25-26一年级上·全国·课后作业" + }, + { + "id": "81", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "李老师和8个小朋友玩\u0027老鹰捉小鸡\u0027的游戏,已经捉住了5只\u0027小鸡\u0027,还有几只\u0027小鸡\u0027没有被捉住?", + "options": [ + + ], + "answer": "2只", + "solution": "【分析】根据题意,先用加法计算出老师和小朋友一共有多少人,也就是游戏的总只数.游戏中有 1 只\u0027老鹰\u0027,1 只\u0027母鸡\u0027,则总只数减\u0027老鹰\u0027的只数减\u0027母鸡\u0027的只数减被捉住的\u0027小鸡\u0027只数 = 没被捉住的\u0027小鸡\u0027只数.\n【详解】1 + 8 = 9(只),9 - 1 - 1 - 5 = 2 (只),答: 还有 2 只 \u0027小鸡\u0027 没有被捉住.", + "knowledge_points": [ + "8,9 的加减法", + "连加,连减(10以内)" + ], + "source": "25-26一年级上·全国·课后作业" + }, + { + "id": "82", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "9 个小朋友玩\u0027老鹰捉小鸡\u0027的游戏,已经捉住了 3 只\u0027小鸡\u0027,还有几个小朋友在做游戏?", + "options": [ + + ], + "answer": "6 个", + "solution": "【分析】根据题意,做游戏的总人数减去被捉住的人数,也就是退出的人数,即可计算出还在做游戏的人数.\n【详解】9 - 3 = 6 (个);答: 还有 6 个小朋友在做游戏.", + "knowledge_points": [ + "8,9 的加减法" + ], + "source": "25-26 一年级上·全国·课后作业" + }, + { + "id": "83", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.94, + "question": "王奶奶家养了 3 只鸡和 2 只兔,鸡脚和兔脚比,哪个多?", + "options": [ + + ], + "answer": "兔脚", + "solution": "【分析】1 只鸡有 2 只脚, 2 个 2 个地数, 即可算出 3 只鸡有几只脚;1 只兔有 4 只脚, 4 个 4 个地数, 即可算出 2 只兔有几只脚.\n【详解】2 + 2 + 2 = 4 + 2 = 6 (只),3只鸡有6只脚.4 + 4 = 8 (只),2 只兔有 8 只脚.6 \u003c 8;答: 鸡脚和兔脚比, 兔脚多.", + "knowledge_points": [ + "8,9 的加减法", + "6 的加减法" + ], + "source": "25-26 一年级上·全国·周测" + }, + { + "id": "84", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "东东和其他参加演讲比赛的每个同学都握了一次手,一共握了8次手,参加演讲比赛的一共有多少个同学?", + "options": [ + + ], + "answer": "9 个", + "solution": "【分析】东东和 1 个人握手算 1 次, 和 2 个人握手算 2 次... ...握了 8 次手, 说明其他参赛的同学有 8 人, 再加上东东自己, 即可解答.\n【详解】8 + 1 = 9 (个);答: 参加演讲比赛的一共有 9 个同学.", + "knowledge_points": [ + "8,9 的加减法" + ], + "source": "25-26 一年级上·全国·周测" + }, + { + "id": "85", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "小朋友们排队,从前面数小明排第5,从后面数小明排第4,这一队一共有多少个小朋友?", + "options": [ + + ], + "answer": "8个", + "solution": "【分析】根据题意, 从前往后数到小明有 5 人, 从后往前数到小明有 4 人, 则从前往后数到小明的人数 + 从后往前数到小明的人数 -1 (重复数了一次小明) = 总人数.\n【详解】5 + 4 - 1 = 8 (个);答: 这一队一共有 8 个小朋友.", + "knowledge_points": [ + "加减混合运算(10以内)" + ], + "source": "25-26一年级上·广东深圳·月考" + }, + { + "id": "86", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.65, + "question": "左边有 3 个苹果,右边有 6 个苹果, 一共有多少个苹果?\n\n( ) + ( ) = ( ) (个)", + "options": [ + + ], + "answer": "9个;3;6;9", + "solution": "【分析】根据题意,左边苹果的数量和右边苹果的数量相加,即可计算出苹果的总数量.\n【详解】由分析得:3 + 6 = 9 (个)或 6 + 3 = 9 (个);答: 一共有 9 个苹果.", + "knowledge_points": [ + "8,9 的加减法" + ], + "source": "25-26 一年级上·广东深圳·月考" + }, + { + "id": "87", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.94, + "question": "有7个小朋友在做游戏,走了3个.还剩几个小朋友?列式计算:答:还剩()个小朋友.", + "options": [ + + ], + "answer": "4 个;7 - 3 = 4;4", + "solution": "【分析】根据减法的意义,做游戏的总人数减走了的人数 =还剩的人数.\n【详解】列式计算: 7 - 3 = 4 (个);答:还剩 4 个小朋友.", + "knowledge_points": [ + "7 的加减法" + ], + "source": "25-26一年级上·云南曲靖·阶段练习" + }, + { + "id": "88", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.94, + "question": "鱼缸里有 6 条金鱼, 又放进去 2 条.现在鱼缸里有几条金鱼?列式计算:答:现在鱼缸里有()条金鱼.", + "options": [ + + ], + "answer": "8条;6 + 2 = 8;8", + "solution": "【分析】根据题意, 用鱼缸里原来金鱼的数量加上又放进去的数量, 即可求出现在鱼缸里鱼的数量.用加法列式计算.\n【详解】6 + 2 = 8 (条);答: 现在鱼缸里有 8 条金鱼.", + "knowledge_points": [ + "8,9 的加减法" + ], + "source": "25-26 一年级上·云南曲靖·阶段练习" + }, + { + "id": "89", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.94, + "question": "小红有 4 支铅笔, 小兰有 3 支铅笔.她们一共有几支铅笔?\n\n列式计算:答:她们一共有()支铅笔.", + "options": [ + + ], + "answer": "7支;4 + 3 = 7;7", + "solution": "【分析】根据题意, 小红有 4 支铅笔, 小兰有 3 支铅笔, 求她们一共有几支铅笔, 用加法计算.\n【详解】4 + 3 = 7 (支);答: 她们一共有 7 支铅笔.", + "knowledge_points": [ + "7 的加减法" + ], + "source": "25-26 一年级上·云南曲靖·阶段练习" + }, + { + "id": "90", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.94, + "question": "兔妈妈和兔宝宝一共吃了多少根胡萝卜?\n\n![](images/b9a0c5c5ab8e5a0a7918724c8bd3d7a2320c39b43104b98ba92fdbfd7800f673.jpg)\n\n\n![](images/06114a2a220ac26f27e842de16996ec604988a2ce9b6db6abeb834a360898e7c.jpg)\n\n\n![](images/653d0aadfffe6a6cc02ed7631bcf20c5d3aca64dbc7bbc4abe9d856613c5cdda.jpg)\n\n\n□ ○ □ = □ (根)", + "options": [ + + ], + "answer": "8根;3 + 5 = 8", + "solution": "【分析】根据题意可知, 兔宝宝吃的根数加兔妈妈吃的根数, 等于兔妈妈和兔宝宝一共吃了多少根胡萝卜, 据此解答.\n【详解】根据分析可得:3 + 5 = 8 (根)\n\n答: 兔妈妈和兔宝宝一共吃了 8 根胡萝卜.", + "knowledge_points": [ + "8,9 的加减法", + "图文问题" + ], + "source": "25-26一年级上·河北邢台·期中" + }, + { + "id": "91", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.94, + "question": "茉莉蛋糕房早上共做出8块,还剩多少块?\n\n![](images/7a5919fbd2272583020e353eee7365e3add039f752961a5a3ee5cb428753721b.jpg)\n\n\n□ ○ □ = □ (块)", + "options": [ + + ], + "answer": "3 块;8 - 5 = 3", + "solution": "【分析】根据题意可知,蛋糕房早上做出蛋糕的数量减去顾客买走的数量,等于还剩下的数量,据此解答.\n【详解】根据分析可得:8 - 5 = 3 (块);答: 还剩下 3 块.", + "knowledge_points": [ + "8,9 的加减法", + "图文问题" + ], + "source": "25-26 一年级上·河北邢台·期中" + }, + { + "id": "92", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.94, + "question": "六一儿童节,乐乐折了10只纸鹤,送给朋友4只,他还剩几只?\n\n□ ○ □ = □ (只)", + "options": [ + + ], + "answer": "6 只;10 - 4 = 6", + "solution": "【分析】根据题意可知:求还剩的数量,用乐乐折的数量减去送给朋友的数量即可.\n【详解】10 - 4 = 6 (只);答: 他还剩 6 只.", + "knowledge_points": [ + "10 的加减法" + ], + "source": "25-26一年级上·全国·课后作业" + }, + { + "id": "93", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.65, + "question": "小朋友拍皮球,第一次拍了4下,第二次和第一次拍的一样多.两次一共拍了多少下?", + "options": [ + + ], + "answer": "8下", + "solution": "【分析】第一次拍了 4 下, 第二次和第一次拍的一样多, 则第二次也拍了 4 下, 用第一次拍的数量加上第二次拍的数量,即可求出两次一共拍了多少下.\n【详解】4 + 4 = 8 (下);答: 两次一共拍了 8 下.", + "knowledge_points": [ + "8,9 的加减法" + ], + "source": "24-25一年级上·辽宁抚顺·期中" + }, + { + "id": "94", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.94, + "question": "要做8朵小红花,小玲做了2朵,小丽做了3朵,还要再做几朵才能完成任务?", + "options": [ + + ], + "answer": "3 朵", + "solution": "【分析】根据题意可知, 需要小红花的总数量减去小玲做的数量, 再减去小丽做的数量, 等于还要再做几朵才能完成任务, 据此解答.\n【详解】根据分析可得:8 - 2 - 3 = 3 (朵)\n\n答: 还要再做 3 朵才能完成任务.", + "knowledge_points": [ + "连加,连减(10以内)" + ], + "source": "24-25一年级上·河南驻马店·期中" + }, + { + "id": "95", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.94, + "question": "小汽车里原来有 5 人, 下去 4 人, 又上来 3 人, 现在车里有多少人?", + "options": [ + + ], + "answer": "4人", + "solution": "【分析】用小汽车里原来有的人数减去下去的人数,再加上又上来的人数,就是现在车里有多少人.\n【详解】5 - 4 + 3 = 4 (人)\n\n答: 现在车里有 4 人.", + "knowledge_points": [ + "加减混合运算(10以内)" + ], + "source": "24-25 一年级上·河南驻马店·期中" + }, + { + "id": "96", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.94, + "question": "有9块西瓜,小力吃了1块,现在还剩多少块西瓜?\n\n□ ○ □ = □ (块)", + "options": [ + + ], + "answer": "8 块;9 - 1 = 8", + "solution": "【分析】用西瓜的总块数减去小力吃的块数, 就是现在还剩多少块西瓜.\n【详解】9 - 1 = 8 (块);答: 现在还剩 8 块西瓜.", + "knowledge_points": [ + "8,9 的加减法" + ], + "source": "24-25一年级上·河南驻马店·期中" + }, + { + "id": "97", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "操场上有7个同学在跳绳,其中男生有3人,女生有多少人?\n\n□ ○ □ = □ (个)", + "options": [ + + ], + "answer": "4 个;7 - 3 = 4", + "solution": "【分析】由题意可知: 用操场上在跳绳的人数减去男生的人数, 即是女生的人数;据此解答.\n【详解】由分析可得:7 - 3 = 4 (个);答: 女生有 4 人.", + "knowledge_points": [ + "7 的加减法" + ], + "source": "24-25一年级上·河南驻马店·期中" + }, + { + "id": "98", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.94, + "question": "白色的球和蓝色的球一共有8个,蓝色的球有2个,白色的球有多少个?\n\n□ ○ □ = □ (个)", + "options": [ + + ], + "answer": "6 个;8 - 2 = 6", + "solution": "【分析】用白色的球和蓝色的球的总个数减去蓝色的球的个数, 就是白色的球有多少个.\n【详解】8 - 2 = 6 (个);答: 白色的球有 6 个.", + "knowledge_points": [ + "8,9 的加减法", + "9 以内加减法实际应用" + ], + "source": "24-25一年级上·河南驻马店·期中" + }, + { + "id": "99", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.94, + "question": "鱼缸里有 6 条红金鱼和 4 条黑金鱼, 一共有多少条金鱼?\n\n□ ○ □ = □ (条)", + "options": [ + + ], + "answer": "10 条;6 + 4 = 10", + "solution": "【分析】根据题意可知, 鱼缸里红金鱼的条数加黑金鱼的条数, 等于一共有多少条金鱼, 据此解答.\n【详解】根据分析可得:6 + 4 = 10 (条);答: 一共有 10 条金鱼.", + "knowledge_points": [ + "10 的加减法" + ], + "source": "24-25 一年级上·河南驻马店·期中" + }, + { + "id": "100", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.94, + "question": "猫妈妈钓了 5 条鱼, 小猫钓了 3 条鱼, 它们一共钓了多少条鱼?\n\n□ ○ □ = □ (条)", + "options": [ + + ], + "answer": "8条;5 + 3 = 8", + "solution": "【分析】用猫妈妈钓鱼的条数加上小猫钓鱼的条数, 就是它们一共钓了多少条鱼.\n【详解】5 + 3 = 8 (条);答: 它们一共钓了 8 条鱼.", + "knowledge_points": [ + "8,9 的加减法", + "9 以内加减法实际应用" + ], + "source": "24-25 一年级上·河南驻马店·期中" + }, + { + "id": "101", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.94, + "question": "下面算式中, 得数等于 5 的是 ( ).", + "options": [ + "A. 4 - 1", + "B. 4 + 1", + "C. 5 + 1", + "D. 5 - 1" + ], + "answer": "B", + "solution": "【分析】根据题意,分别算出各个选项的结果的多少,找出得数等于5的算式即可.\n【详解】A. 4 - 1 = 3 ,得数不等于5,不符合题意;B. 4 + 1 = 5 , 得数等于 5 , 符合题意;C. 5 + 1 = 6 , 得数不等于 5 , 不符合题意;D. 5 - 1 = 4 , 得数不等于 5 , 不符合题意;故答案为: B", + "knowledge_points": [ + "5以内数的加法", + "5以内数的减法", + "6的加减法" + ], + "source": "24-25 一年级上·广东湛江·期中" + }, + { + "id": "102", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "小丽有 3 个苹果, 和下面哪一堆合起来是 6 个苹果? ( )", + "options": [ + "A. ![](images/141021.png)", + "B. ![](images/wps1.jpg)", + "C. ![](images/wps2.jpg)" + ], + "answer": "C", + "solution": "【分析】根据题意可知, 合起来苹果的总个数减去小丽现有苹果的个数, 等于需要加上苹果的个数, 据此解答.\n【详解】6 - 3 = 3 (个)需要再加上 3 个苹果, 总数才是 6 个.因此,小丽有 3 个苹果,和![](images/wps2.jpg)合起来是 6 个苹果,故答案为:C", + "knowledge_points": [ + "6 的加减法" + ], + "source": "24-25 一年级上·甘肃临夏·期中" + }, + { + "id": "103", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.65, + "question": "白花和红花共有 6 朵, 红花比白花多 2 朵, 红花有 ( ) 朵.", + "options": [ + "A. 8", + "B. 4", + "C. 2" + ], + "answer": "B", + "solution": "【分析】已知红花比白花多 2 朵, 我们可以先从总数中减去红花比白花多的 2 朵, 此时剩下花的数量中红花和白花的数量是相等的, 即剩下 6 - 2 = 4 (朵).因为剩下的 4 朵花中红花和白花数量相等,所以将这 4 朵花分成两份一样多的,其中一份就是白花的数量,4 - 2 = 2(朵);已知红花比白花多 2 朵, 白花有 2 朵, 那么红花的数量为: 2 + 2 = 4 (朵), 所以红花有 4 朵.\n【详解】6 - 2 = 4 (朵),4 - 2 = 2 (朵),2 + 2 = 4 (朵),红花有 4 朵.故答案为: B", + "knowledge_points": [ + "5以内数的加法", + "6的加减法" + ], + "source": "25-26 一年级上·湖南永州·开学考试" + }, + { + "id": "104", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "比较大小: 6-3 ( ) 2 + 1 .", + "options": [ + "A. \u003e", + "B. \u003c", + "C. =" + ], + "answer": "C", + "solution": "【分析】分别计算出两边算式的答案,然后再比较.\n【详解】6 - 3 = 3, 2 + 1 = 3,3 = 3,则 6 - 3 (=) 2 + 1 .故答案为: C", + "knowledge_points": [ + "5 以内数的加法", + "6 的加减法" + ], + "source": "25-26 一年级上·湖南永州·开学考试" + }, + { + "id": "105", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "4 + 5 = ( ).", + "options": [ + "A. 5", + "B. 9", + "C. 4" + ], + "answer": "B", + "solution": "【分析】由题意可知: 4 和 5 组成 9 , 故 4 和 5 相加等于 9;据此可解.\n【详解】由分析可得:4 + 5 = 9,故答案为: B", + "knowledge_points": [ + "8,9 的加减法", + "8,9 的分与合(组成)" + ], + "source": "25-26 一年级上·湖南永州·开学考试" + }, + { + "id": "106", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "8 个 1 组成 ( ).", + "options": [ + "A. 7", + "B. 8", + "C. 9" + ], + "answer": "B", + "solution": "【分析】8 个 1 组成的数, 也就是将 8 个 1 加起来, 由此计算解答.\n【详解】1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 = 8,则 8 个 1 组成 8 .故答案为: B", + "knowledge_points": [ + "连加,连减(10以内)" + ], + "source": "25-26 一年级上·湖南永州·开学考试" + }, + { + "id": "107", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "小明有 10 本书,小红有6本书,小明给小红()本书,两人的书就同样多.", + "options": [ + "A. 2", + "B. 3", + "C. 4" + ], + "answer": "A", + "solution": "【分析】根据题意可知:用小明有的数量减去小红有的数量求两人相差的数量,然后把两人相差的数量分成相等的两部分,给其中一部分即可.\n【详解】10 - 6 = 4 (本),4 = 2 + 2,则小明给小红 2 本书, 两人的书就同样多.故答案为: A", + "knowledge_points": [ + "移多补少问题", + "10 的加减法" + ], + "source": "25-26 二年级上·黑龙江佳木斯·开学考试" + }, + { + "id": "108", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.94, + "question": "3 和 4 的和是 ( ).", + "options": [ + "A. 7", + "B. 12", + "C. 16" + ], + "answer": "A", + "solution": "【分析】求两个数的和,用加法计算,由此解答.\n【详解】3 + 4 = 7,则 3 和 4 的和是 7,故答案为: A", + "knowledge_points": [ + "7 的加减法" + ], + "source": "2025 二年级上·全国·专题练习" + }, + { + "id": "109", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "今年, 小明 5 岁,小天 7 岁.3 年后, 两人相差 ( ) 岁.", + "options": [ + "A. 2", + "B. 3", + "C. 5" + ], + "answer": "A", + "solution": "【分析】根据年龄差不变可知, 今年两人相差几岁, 3 年后还是相差几岁, 则用今年小天的年龄-今年小明的年龄,计算即可.\n【详解】7 - 5 = 2 (岁),3年后,两人相差2岁.故答案为: A", + "knowledge_points": [ + "7 的加减法" + ], + "source": "25-26 一年级上·广东汕头·开学考试" + }, + { + "id": "110", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "与( )相邻的两个数是7和9.", + "options": [ + "A. 6", + "B. 8", + "C. 10" + ], + "answer": "B", + "solution": "【分析】10以内数从小到大的顺序为,1, 2, 3, 4, 5, 6, 7, 8, 9, 10.由此找到符合题意的数即可.\n【详解】由 10 以内数从小到大的顺序可知: 与 8 相邻的两个数是 7 和 9.故答案为: B", + "knowledge_points": [ + "10以内数的排序" + ], + "source": "25-26 一年级上·广东汕头·开学考试" + }, + { + "id": "111", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "从 2 数到 9 , 一共数了()个数.", + "options": [ + "A. 2", + "B. 7", + "C. 8" + ], + "answer": "C", + "solution": "【分析】根据 10 以内数的顺序,从 2 数到 9(包括 2 和 9),数出数字的个数即可.\n【详解】由分析得:从 2 数到 9 , 依次为 2, 3, 4, 5, 6, 7, 8, 9, 一共数了 8 个数.故答案为: C", + "knowledge_points": [ + "10以内数的排序", + "数一数" + ], + "source": "25-26 一年级上·广东汕头·开学考试" + }, + { + "id": "112", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "图中要解决的问题是().\n\n![](images/d23a7f2f248a7457de521c88eb0827a8ab8b79df58d700b7d12c30fe31894911.jpg)", + "options": [ + "A. 房子里有多少只小鸟", + "B. 右边有多少只小鸟", + "C. 一共有多少只小鸟" + ], + "answer": "A", + "solution": "【分析】由题图可知: 已知共有 10 只鸟, 右边有 3 只, 用总只数减右边的小鸟只数, 能求出左边房子里有多少只小鸟;据此可选择.\n【详解】由分析可得:图中要解决的问题是房子里有多少只小鸟.故答案为: A", + "knowledge_points": [ + "图文问题", + "10 的加减法" + ], + "source": "2025 一年级上·全国·专题练习" + }, + { + "id": "113", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "和 5 相邻的两个数是 ( ).", + "options": [ + "A. 3和4", + "B. 6和7", + "C. 4和6" + ], + "answer": "C", + "solution": "【分析】求相邻的两个数, 就是求出比其少 1 和多 1 的数,即减 1 和加 1.\n【详解】5 - 1 = 4, 5 + 1 = 6 .则和 5 相邻的两个数是 4 和 6.故答案为: C", + "knowledge_points": [ + "5 以内数的减法", + "相邻的数", + "6 的加减法", + "10 以 内数的排序" + ], + "source": "25-26 一年级上·全国·课后作业" + }, + { + "id": "114", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.65, + "question": "下面的数中, 比 7 小的数是 ( ).", + "options": [ + "A. 9", + "B. 5", + "C. 7", + "D. 8" + ], + "answer": "B", + "solution": "【分析】根据 10 以内数的大小, 逐个分析每个选项和 7 之间的大小关系, 找出比 7 更小的选项即可解答.\n【详解】A. 9比7更大,不符合题意;B. 5 比 7 更小, 符合题意;C. 7 和 7 相等, 不符合题意;D. 8 比 7 更大, 不符合题意.故答案为: B", + "knowledge_points": [ + "10 以内数的比大小" + ], + "source": "25-26 一年级上·全国·课后作业" + }, + { + "id": "115", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "如果 9 - □ \u003e 5 , □ 表示的是哪些数?()", + "options": [ + "A. 4", + "B. 比 4 大的数", + "C. 比 4 小的数" + ], + "answer": "C", + "solution": "【分析】根据题意, 9 - □ \u003e 5 , 把 9 - □ 看作一个整体, ( ) \u003e 5 , 括号里可以填 6,7,8....把这些数作为 9 - □ 的差, 据此解答.\n【详解】根据分析:9 - □ = 6, 9 - 6 = 3, □ = 3.9 - □ = 7, 9 - 7 = 2, □ = 2 . 9 - □ = 8, 9 - 8 = 1, □ = 1 .□ 里填写的数是 3,2,1...,都比 4 小.如果 9 - □ \u003e 5 , □ 表示的是比 4 小的数.故答案为: C", + "knowledge_points": [ + "8,9 的加减法", + "10 以内数的比大小" + ], + "source": "25-26 一年级上·全国·课后作业" + }, + { + "id": "116", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "6 + □ \u003c 9 , □ 里最大能填几? ( )", + "options": [ + "A. 4", + "B. 3", + "C. 2" + ], + "answer": "C", + "solution": "【分析】10 以内数从小到大关系为 1 \u003c 2 \u003c 3 \u003c 4 \u003c 5 \u003c 6 \u003c 7\u003c 8 \u003c 9 \u003c 10 , 由此将各数代入到算式中计算出结果再和 9 比较大小即可.\n【详解】A. 6 + 4 = 10;10 \u003e 9 ,不符合题意;B. 6 + 3 = 9;9 = 9 , 不符合题意;C. 6 + 2 = 8;8 \u003c 9 , 符合题意.则 6 + □ \u003c 9 ,□里最大能填2.故答案为: C", + "knowledge_points": [ + "8,9 的加减法", + "10 以内数的比大小", + "10 的加减法" + ], + "source": "25-26 一年级上·全国·课后作业" + }, + { + "id": "117", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "与 7 - 2 + 4 相等的算式是哪个? ( )", + "options": [ + "A. 8 - 0 + 1", + "B. 8 - 0 - 1", + "C. 9 - 1 + 0" + ], + "answer": "A", + "solution": "【分析】根据题意,依次计算出各算式的结果,选择与 7 - 2 + 4 结果相等的即可.只有加减法的混合运算,从左往右计算.\n【详解】7 - 2 + 4 = 9;A. 8 - 0 + 1 = 9 , 符合题意;B. 8 - 0 - 1 = 7 , 不符合题意;C. 9 - 1 + 0 = 8 , 不符合题意.则与 7 - 2 + 4 相等的算式是 8 - 0 + 1 .故答案为:A", + "knowledge_points": [ + "连加,连减(10以内)", + "加减混合运算(10以内)" + ], + "source": "25-26 一年级上·全国·课后作业" + }, + { + "id": "118", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "8 - 4 = 10- ( ) ,括号里填 ( ) ?", + "options": [ + "A. 5", + "B. 6", + "C. 7" + ], + "answer": "B", + "solution": "【分析】先求出 8 - 4 的差, 作为 10 - () 的差, 然后根据被减数-差 = 减数即可求出 ( ) 中的数.\n【详解】8 - 4 = 4;10 - 4 = 6;则 8 - 4 = 10 - ( ),括号里填 6 .故答案为: B", + "knowledge_points": [ + "8,9 的加减法", + "10 的加减法" + ], + "source": "25-26 一年级上·全国·课后作业" + }, + { + "id": "119", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.94, + "question": "与 6 相邻的数是( )和( );10的前面一个数是( ).", + "options": [ + + ], + "answer": "5;7;9", + "solution": "【分析】10以内数的排序为:0,1,2,3,4,5,6,7,8,9,10,据此找出与 6 相邻的两个数,及 10 前面的一个数;据此解答.\n【详解】由分析可得:与 6 相邻的数是 5 和 7;10 的前面一个数是 9.", + "knowledge_points": [ + "相邻的数", + "10以内数的排序" + ], + "source": "24-25 一年级上·江西吉安·期中" + }, + { + "id": "120", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.94, + "question": "在0, 4, 5, 6, 9, 8, 2 中, 小于 4 的数有( ), 大于 6 的数有( ),大于4小于8的数有( ).", + "options": [ + + ], + "answer": "0,2;8,9;5,6", + "solution": "【分析】根据 10 以内数的排列顺序比较大小, 排在后面的数比前面的数大.\n【详解】在 0, 4, 5, 6, 9, 8, 2 中, 大小排列为: 0 \u003c 2 \u003c 4 \u003c 5 \u003c 6 \u003c 8 \u003c 9 .因此,小于 4 的数有 0,2,大于 6 的数有 8,9,大于 4 小于 8 的数有 5,6.", + "knowledge_points": [ + "9 以内数的比大小" + ], + "source": "24-25 一年级上·河南新乡·期中" + }, + { + "id": "121", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "在横线上填上\"\u003e\",\"\u003c\"或\"=\".\n\n8 ( ) 9\n5 + 3 ( ) 8\n8 - 1 ( ) 6\n7 ( ) 4\n9 - 2 ( ) 6\n4 + 5 ( ) 9", + "options": [ + + ], + "answer": "\u003c;=;\u003e;\u003e;\u003e;=", + "solution": "【分析】9 以内的数由小到大依次是 0,1,2,3,4,5,6,7,8,9;有算式的,先计算,再按整数的先后顺序进行大小比较.\n【详解】8 \u003c 9;5 + 3 = 8, 8 = 8 , 因此 5 + 3 = 8;8 - 1 = 7, 7 \u003e 6 , 因此 8 - 1 \u003e 6;7 \u003e 4;9 - 2 = 7, 7 \u003e 6 , 因此 9 - 2 \u003e 6;4 + 5 = 9, 9 = 9 ,因此 4 + 5 = 9 .", + "knowledge_points": [ + "8,9 的加减法", + "9 以内数的比大小" + ], + "source": "24-25 一年级上·广东东莞·期中" + }, + { + "id": "122", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.94, + "question": "分一分, 合一合.\n\n![](images/142531.png)", + "options": [ + + ], + "answer": "见详解", + "solution": "【分析】根据题意,熟练掌握 10 以内数的分与合进行解答即可.8 可以分成 3 和 5,7 可以分成 2 和 5,3 和 6 合成 9, 6 可以分成 1 和 5, 6 可以分成 2 和 4, 6 可以分成 3 和 3, 6 可以分成 4 和 2, 6 可以分成 5 和 1, 6 可以分成 0 和 6, 6 可以分成 6 和 0 .据此解答.\n【详解】根据分析:\n\n![](images/efcfc5e3dab02ddbefe340581ab0887d91ff66564d421221051a220eddb87299.jpg)\n\n(最后一题答案不唯一)", + "knowledge_points": [ + "6,7 的分与合(组成)", + "8,9 的分与合(组成)" + ], + "source": "24-25一年级上·广东东莞·期中" + }, + { + "id": "123", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "7 前面的一个数是( );与 9 相邻的数是( )和( ).", + "options": [ + + ], + "answer": "6;8;10", + "solution": "【分析】10以内数的正序排列规律:0,1,2,3,4,5,6,7,8,9,10;根据排序可知,7前面的一个数是 6,9 的前一个数是 8,后一个数是 10,据此解答.\n【详解】根据分析可得:7前面的一个数是6;与9相邻的数是8和10.", + "knowledge_points": [ + "10以内数的排序" + ], + "source": "24-25 一年级上·甘肃临夏·期中" + }, + { + "id": "124", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "在括号里填上\"\u003e\",\"\u003c\"或\"=\".\n\n5 ( ) 4\n2 + 3 ( ) 5\n7 ( ) 6 + 3\n2 ( ) 6 + 4\n10 ( ) 9\n9 - 6 ( ) 2\n8 - 5 ( ) 3\n0 + 8 ( ) 9 + 0", + "options": [ + + ], + "answer": "\u003e;=;\u003c;\u003c;\u003e;=;\u003c", + "solution": "【分析】根据整数加减法的计算法则,依次计算出各算式的结果再比较大小.10以内数从大到小关系为: 10 \u003e 9 \u003e 8\u003e7\u003e6\u003e5\u003e4\u003e3\u003e2\u003e1\u003e0 , 由此比较.\n【详解】5 \u003e 4;2 + 3 = 5, 5 = 5 , 故 2 + 3 = 5.6 + 3 = 9, 7 \u003c 9 ,故 7 \u003c 6 + 3.6 + 4 = 10, 2 \u003c 10 ,故 2 \u003c 6 + 4.10 \u003e 9;9 - 6 = 3, 3 \u003e 2 ,故 9 - 6 \u003e 2.8 - 5 = 3, 3 = 3 ,故 8 - 5 = 3.0 + 8 = 8, 9 + 0 = 9, 8 \u003c 9 ,故 0 + 8 \u003c 9 + 0 .", + "knowledge_points": [ + "8,9 的加减法", + "5 以内数的加法", + "10 以内数的比大小", + "10 的加减法" + ], + "source": "24-25 一年级上·甘肃临夏·期中" + }, + { + "id": "125", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "( ) 里填几?\n\n1 + ( ) = 53 + ( ) = 85 + ( ) = 7\n2 + ( ) = 94 + ( ) = 67 + ( ) = 8", + "options": [ + + ], + "answer": "4;5;2;7;2;1", + "solution": "【分析】左侧两个数相加的结果是等号右侧的数,则用等号右侧的数减去等号左边的一个已知数, 即可计算出应填写的数.\n【详解】5 - 1 = 4 ,则 1 + 4 = 5;8 - 3 = 5 , 则 3 + 5 = 8;7 - 5 = 2 , 则 5 + 2 = 7;9 - 2 = 7 , 则 2 + 7 = 9;6 - 4 = 2 , 则 4 + 2 = 6;8 - 7 = 1 , 则 7 + 1 = 8 .", + "knowledge_points": [ + "8,9 的加减法", + "5 以内数的加法", + "7 的加减法" + ], + "source": "24-25 一年级上·甘肃嘉峪关·期中" + }, + { + "id": "126", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.94, + "question": "最小的一位数与最大的一位数的和是( ),差是( ).", + "options": [ + + ], + "answer": "10;8", + "solution": "【分析】根据题意可知: 最小的一位数是 1 , 最大的一位数是 9 , 则将两数进行相加求出和, 将两数进行相减求出差即可.\n【详解】1 + 9 = 10;9 - 1 = 8;则最小的一位数与最大的一位数的和是 10 , 差是 8 .", + "knowledge_points": [ + "8,9 的加减法", + "10 的加减法" + ], + "source": "25-26 二年级上·黑龙江佳木斯·开学考试" + }, + { + "id": "127", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "6 前面一个数是 ( ),7 后面一个数是 ( ).", + "options": [ + + ], + "answer": "5;8", + "solution": "【分析】在数的顺序中,数是连续排列的,例如:1,2,3,4,5,6,7,8,9等,即可得出6前面的数字和7后面的数字.\n【详解】6前面的一个数是5,7后面的一个数是8.", + "knowledge_points": [ + "10以内数的排序" + ], + "source": "25-26 一年级上·湖南永州·开学考试" + }, + { + "id": "128", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "5 比 4 多( );3 比 6 少( ).", + "options": [ + + ], + "answer": "1;3", + "solution": "【分析】由题意可知: 求谁比谁多多少或少多少, 都用减法计算;据此解答.\n【详解】由分析可得:5 - 4 = 1;6 - 3 = 3;5 比 4 多 1;3 比 6 少 3.", + "knowledge_points": [ + "5 以内数的减法", + "6 的加减法", + "谁比谁多/少几的问题" + ], + "source": "25-26 一年级上·湖南永州·开学考试" + }, + { + "id": "129", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "6 个一是( );4 和 3 组成( ).", + "options": [ + + ], + "answer": "6;7", + "solution": "【分析】根据题意可得:6个一可以表示6个1相加,4和3组成几可以表示两个数字相加的结果,计算填入括号即可.\n【详解】1 + 1 + 1 + 1 + 1 + 1 = 6;4 + 3 = 7,所以,6个一是6;4和3组成7.", + "knowledge_points": [ + "6 的加减法", + "7 的加减法" + ], + "source": "25-26 一年级上·湖南永州·开学考试" + }, + { + "id": "130", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "9 的前面一个数是( ),后面一个数是( ).", + "options": [ + + ], + "answer": "8;10", + "solution": "【分析】10以内数的正序排列规律:0,1,2,3,4,5,6,7,8,9,10;据此解答.\n【详解】根据排序可得:9 的前面一个数是 8 , 后面一个数是 10.", + "knowledge_points": [ + "10以内数的排序" + ], + "source": "25-26 一年级上·黑龙江佳木斯·开学考试" + }, + { + "id": "131", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.65, + "question": "10 个小朋友排成一队,从前面数,豆豆排第 3,从后面数,多多排第 4,豆豆和多多之间隔着( )个人.", + "options": [ + + ], + "answer": "3", + "solution": "【分析】1 个○表示 1 个小朋友, 根据题意画图如下:\n\n![](images/cb6344cd5f62692f70b7564c812a84c68ae4635987742d358f2f1e2ccd989c4e.jpg)\n\n用总人数减去豆豆和他前面的人数,再减去多多和他后面的人数,即可求出豆豆和多多之间隔着几个人.\n【详解】10 - 3 - 4 = 3 (人);10 个小朋友排成一队,从前面数,豆豆排第 3,从后面数,多多排第 4,豆豆和多多之间隔着 3 个人.", + "knowledge_points": [ + "连加,连减(10以内)", + "认识几和第几" + ], + "source": "25-26 一年级上·全国·周测" + }, + { + "id": "132", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.65, + "question": "丁丁花了6元买了两样同样的玩具,笑笑花了4元买了一样玩具,( )买一样玩具花的钱多,多花了( )元.", + "options": [ + + ], + "answer": "笑笑;1", + "solution": "【分析】根据题意,丁丁花6元买了两样同样的玩具,也就是把6分成同样的两个数,这个数就是一样玩具的价格,再和笑笑买一样玩具花的钱数比较大小即可,两种玩具的价格相减就是多花的钱数.\n【详解】由分析得:6 = 3 + 3 , 即丁丁买一样玩具花了 3 元;3 \u003c 4;4 - 3 = 1 (元),丁丁花了 6 元买了两样同样的玩具, 笑笑花了 4 元买了一样玩具, 笑笑买一样玩具花的钱多, 多花了 1 元.", + "knowledge_points": [ + "5以内数的减法", + "6的加减法", + "5以内数的比大小" + ], + "source": "25-26一年级上·全国·周测" + }, + { + "id": "133", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "明明花 8 元买了两本同样的练习本, 乐乐花 6 元买了一本练习本, ( )买的练习本贵,每本贵了( )元.", + "options": [ + + ], + "answer": "乐乐;2", + "solution": "【分析】根据题意,明明花 8 元买了两本同样的练习本,两个练习本的单价相同,想 4 + 4 = 8 ,一本 4 元.比较明明和乐乐买练习本的单价,即可知道谁买的练习本贵,用两本练习本的单价作差,即可算出贵的钱数,据此解答.\n【详解】根据分析:4 + 4 = 8(元) 6 - 4 = 2(元);4 \u003c 6;明明花 8 元买了两本同样的练习本, 乐乐花 6 元买了一本练习本, (乐乐) 买的练习本贵, 每本贵了 (2) 元.", + "knowledge_points": [ + "8,9 的加减法", + "6 的加减法" + ], + "source": "25-26 一年级上·全国·课后作业" + }, + { + "id": "134", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "明明端来了一盘![](images/d9b16ad8366daf22a73c1a2b65ebbecbaa10671e0acc2ccd574db42f3fb2b389.jpg),如果每位客人拿2个,正好够分,家里来了( )位客人.", + "options": [ + + ], + "answer": "5", + "solution": "【分析】根据题意可知用盘中的数量减去每位客人拿的数量,一直减到减为0,然后数一数减了几次即为几位客人.\n【详解】10 - 2 = 8 (个);8 - 2 = 6(个);6 - 2 = 4(个);4 - 2 = 2(个);2 - 2 = 0(个);减了 5 次.则明明端来了一盘![](images/c56a20e4296482ed6bb407ccb2ed253bc1faabbf001ebacbf2fc63646670bbb9.jpg),如果每位客人拿2个,正好够分,家里来了(5)位客人.", + "knowledge_points": [ + "8,9 的加减法", + "5 以内数的减法", + "6 的加减法", + "10 的加减法" + ], + "source": "25-26 一年级上·全国·课后作业" + }, + { + "id": "135", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "红红有 8 个苹果,\n\n明明有 2 个苹果, 红红给明明( )个苹果, 两人的苹果就一样多了.", + "options": [ + + ], + "answer": "3", + "solution": "【分析】根据题意可知:用红红有的数量减去明明有的数量求出红红比明明多的数量,然后把多的数量分成相等的两部分,将其中一部分给明明即可.\n【详解】8 - 2 = 6 (个),6 = 3 + 3,则红红给明明(3)个苹果,两人的苹果就一样多了.", + "knowledge_points": [ + "8,9 的加减法", + "6 的加减法" + ], + "source": "25-26 一年级上·全国·课后作业" + }, + { + "id": "136", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.65, + "question": "天天和 6 个小朋友排队,从前面数,天天排第4,天天后面有( )人.", + "options": [ + + ], + "answer": "3", + "solution": "【分析】由题意可知: 6 个小朋友和天天这 1 人共 7 人;用 7 人减去前面带天天在内的 4 个人, 即是天天后面的人数;据此解答.\n【详解】由分析可得:6 + 1 = 7 (人),7 - 4 = 3 (人),天天和 6 个小朋友排队, 从前面数, 天天排第 4 , 天天后面有 3 人.", + "knowledge_points": [ + "认识几和第几", + "7的加减法", + "前,后位置" + ], + "source": "25-26 一年级上·全国·课后作业" + }, + { + "id": "137", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.65, + "question": "10 个小朋友手拉手围成一圈玩游戏, 每相邻两个小朋友之间放一块手绢, 一共要( )块手绢.", + "options": [ + + ], + "answer": "10", + "solution": "【分析】根据题意,要想知道需要手帕的数量,也就是 10 个小朋友之间有几个间隔,可作图数出间隔数即可.\n【详解】由分析得:○表示小朋友.一共有 10 个间隔.\n\n![](images/a694222fea13644fb034ce315680cb2869eeb8df1424d69ecb83fd53186443af.jpg)\n\n则 10 个小朋友手拉手围成一圈玩游戏, 每相邻两个小朋友之间放一块手绢, 一共要 10 块手绢.", + "knowledge_points": [ + "10 的认识和读写", + "数一数" + ], + "source": "25-26 一年级上·全国·课后作业" + }, + { + "id": "138", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.65, + "question": "小明和小红各有 8 块糖, 小明吃了一些后, 还剩 2 块, 小红吃了一些后, 还剩 3 块.( )吃得多.", + "options": [ + + ], + "answer": "小明", + "solution": "【分析】根据减法的意义,糖果的总数量-剩余的糖果数量 = 吃掉的糖果数量,由此列出算式算出答案即可知小明和小红各自吃的糖果数量.再比较小明和小红各自吃的糖果数量,找出吃得多的人即可解答.\n【详解】小明: 8 - 2 = 6 (块);小红: 8 - 3 = 5 (块);6块 \u003e 5块,答: 小明吃得多.", + "knowledge_points": [ + "8,9 的加减法", + "10 以内数的比大小" + ], + "source": "25-26 一年级上·全国·课后作业" + }, + { + "id": "139", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "两棵树上共有 8 只小鸟,有 3 只小鸟从第一棵树上飞到第二棵树上, 现在两棵树上一共有( )只小鸟.", + "options": [ + + ], + "answer": "8", + "solution": "【分析】根据题意可知,两棵树上共有8只小鸟,有3只小鸟从第一棵树上飞到第二棵树上,用小鸟的总只数减去从第一棵树上飞走的只数,再加上飞到第二棵树上的只数,即可求出现在两棵树上一共有几只小鸟.\n【详解】8 - 3 + 3 = 8 (只);现在两棵树上一共有8只小鸟.", + "knowledge_points": [ + "加减混合运算(10以内)" + ], + "source": "25-26 一年级上·江苏·课后作业" + }, + { + "id": "140", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.65, + "question": "把 2, 3, 5, 6 填入下面的算式中,使等式成立.( )-( )+( )=( )", + "options": [ + + ], + "answer": "5;2;3;6", + "solution": "【分析】只有加减法的混合运算,从左往右计算.也就是前两个数的结果和第三个数相加,等于右边的数.我们可以尝试将数字填入算式中,只要等式成立即可.\n【详解】由分析得:5 可以分成 2 和 3, 3 和 3 合起来就是 6, 即 5 - 2 + 3 = 6 .(答案不唯一)", + "knowledge_points": [ + "加减混合运算 (10 以内)" + ], + "source": "25-26 一年级上·全国·课后作业" + }, + { + "id": "141", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.65, + "question": "把 3, 4, 5, 6 填入下面的算式中,使等式成立.\n\n( )+( )-( )=( )", + "options": [ + + ], + "answer": "3;6;4;5", + "solution": "【分析】只有加减法的混合运算,从左往右计算.也就是前两个数的结果再减去第三个数,等于右边的数.可以把数字分成和相等的两组,用一组数的和减去另一组中的一个数, 等于另一组中的另一个数.3 和 6 的和是 9, 4 和 5 的和也是 9 , 由此解答.\n【详解】由分析得:3 + 6 = 9;4 + 5 = 9;即 3 + 6 - 4 = 5 (答案不唯一)", + "knowledge_points": [ + "加减混合运算 (10 以内)" + ], + "source": "25-26 一年级上·全国·课后作业" + }, + { + "id": "142", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "明明和其他参加朗诵比赛的每个同学都握了一次手,一共握了6次手,参加朗诵比赛的一共有( )个同学.", + "options": [ + + ], + "answer": "7", + "solution": "【分析】根据题意,明明和其他每个同学都握了一次手,一共握了 6 次手, 也就是和他握手的有 6 人, 则用和他握手的人数 + 明明自己 = 参加比赛的总人数.\n【详解】6 + 1 = 7 (个)明明和其他参加朗诵比赛的每个同学都握了一次手,一共握了6次手,参加朗诵比赛的一共有7个同学.", + "knowledge_points": [ + "7 的加减法" + ], + "source": "25-26 一年级上·全国·课后作业" + }, + { + "id": "143", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "丁丁和明明参加射击比赛,射中两枪,两次射中环数的得分不同.\n\n![](images/31c330cfa9863aeb7a2a82cf8532e2b84c4a259722b7f4f4b910913b94708625.jpg),明明得了7分,他可能射中了( )分和( )分,也可能射中了( )分和( )分.", + "options": [ + + ], + "answer": "2;5;3;4", + "solution": "【分析】根据题意,两次射中环数的得分不同,总分是7分,也就是两个数相加的和是7,根据2和5合起来是7,3和4合起来是7,即可解答.\n【详解】2 + 5 = 7 (分);3 + 4 = 7 (分);明明得了7分,他可能射中了2分和5分,也可能射中了3分和4分.", + "knowledge_points": [ + "7 的加减法" + ], + "source": "25-26 一年级上·全国·课后作业" + }, + { + "id": "144", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.65, + "question": "把 2, 3, 4, 5 这四个数分别填入下面的括号里,每个数只能用一次,使等式成立.\n\n( ) + ( ) - ( ) = ( )", + "options": [ + + ], + "answer": "2;5;4;3", + "solution": "【分析】通过尝试不同的数字组合,使等式两边的结果相等.\n【详解】1.尝试第一种组合:把 2 放在第一个括号, 5 放在第二个括号, 4 放在第三个括号, 3 放在第四个括号, 得到 2 + 5 - 4 = 3 , 等式成立.2. 尝试第二种组合:把 3 放在第一个括号, 4 放在第二个括号, 5 放在第三个括号, 2 放在第四个括号, 得到 3 + 4 - 5 = 2 , 等式成立.(答案不唯一)", + "knowledge_points": [ + "加减混合运算(10以内)" + ], + "source": "25-26 一年级上·全国·课后作业" + }, + { + "id": "145", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.65, + "question": "把5,6,7,8这四个数分别填入下面的括号里,每个数只能用一次,使等式成立.\n( )-( )=( )-( )", + "options": [ + + ], + "answer": "8;7;6;5", + "solution": "【分析】要使等式成立, 也就是两个算式的结果相等.观察数字可知, 5 和 6 相差 1, 7 和 8 相差 1;5 和 7 相差 2, 6 和 8 相差 2, 由此解答.\n【详解】由分析得: 8 - 7 = 6 - 5 或 8 - 6 = 7 - 5 .(答案不唯一)", + "knowledge_points": [ + "8,9 的加减法", + "6 的加减法", + "7 的加减法" + ], + "source": "25-26一年级上·全国·课后作业" + }, + { + "id": "146", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.65, + "question": "填一填.\n\n5 + ( ) = 8\n6 + ( ) = 10\n7 + ( ) = 8\n3 + ( ) = 9", + "options": [ + + ], + "answer": "3;4;1;6", + "solution": "【分析】等号左侧的两个数相加等于等号右侧的数, 则用等号右侧的数减去等号左侧的一个数, 等于左侧的另一个数.\n【详解】8 - 5 = 3 ,则 5 + 3 = 810 - 6 = 4 , 则 6 + 4 = 10;8 - 7 = 1 , 则 7 + 1 = 8;9 - 3 = 6 , 则 3 + 6 = 9 .", + "knowledge_points": [ + "8,9 的加减法", + "10 的加减法" + ], + "source": "25-26 一年级上·全国·课后作业" + }, + { + "id": "147", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式计算.\n\n![](images/fdc816bb92414c29fc45dd5344c770d5eef90497e0db29195ccace536fbae843.jpg)\n\n□ ○ □ ○ □ = □ (个)", + "options": [ + + ], + "answer": "5 + 2 + 2 = 9 (个)", + "solution": "【分析】从图上可得: 左边有 5 个胡萝卜, 中间有 2 个胡萝卜, 右边有 2 个胡萝卜, 要求一共有多少个胡萝卜, 根据加法的意义, 用 5 + 2 + 2 进行解答即可.\n【详解】5 + 2 + 2 = 7 + 2 = 9 (个),一共有 9 个胡萝卜.", + "knowledge_points": [ + "连加,连减(10以内)", + "图文问题" + ], + "source": "24-25 一年级上·河南商丘·期中" + }, + { + "id": "148", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式.\n\n![](images/35e84d16e84471932ae1029b719f605483f11d8990bcbf84b06111cfcf2dfb09.jpg)\n\n□ ○ □ = □ (只)", + "options": [ + + ], + "answer": "2 + 6 = 8 (只)", + "solution": "【分析】观察题图可知,左边有 2 只小鸟,右边有 6 只小鸟,求一共有多少只小鸟,用加法计算,即可解答.\n【详解】2 + 6 = 8 (只),因此,一共有 8 只小鸟.", + "knowledge_points": [ + "8,9 的加减法", + "图文问题" + ], + "source": "25-26 一年级上·黑龙江鹤岗·开学考试" + }, + { + "id": "149", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "计算题", + "difficulty": 0.65, + "question": "看图列式计算.\n\n![](images/38d88a177bc936d59814aab3168f0cc8de00a15e5583d9a30cbde07b4855acab.jpg)\n\n□ ○ □ = □ (本)", + "options": [ + + ], + "answer": "8 - 5 = 3 (本)", + "solution": "【分析】根据减法的意义,本子的总数量-左边本子的数量 = 右边本子的数量,由此列出算式算出答案即可解答.\n【详解】8 - 5 = 3 (本)", + "knowledge_points": [ + "8,9 的加减法", + "图文问题" + ], + "source": "25-26 一年级上·全国·课后作业" + }, + { + "id": "150", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.65, + "question": "请写出用 10 - 4 = 6 解决的一个数学问题.", + "options": [ + + ], + "answer": "有 10 个苹果, 吃了 4 个, 还剩几个? (答案不唯一)", + "solution": "【分析】根据题干的数学信息,结合学过的减法知识提出问题并解答即可.本题答案不唯一,例如:有 10 个苹果,吃了 4 个,还剩几个?\n【详解】有 10 个苹果, 吃了 4 个, 还剩几个?10 - 4 = 6 (个);答: 还剩 6 个.(答案不唯一)", + "knowledge_points": [ + "\"提问题\"\"填条件\"问题", + "10的加减法" + ], + "source": "24-25 一年级上·河南商丘·期中" + }, + { + "id": "151", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "家里原有 6 个梨,吃了 4 个后, 妈妈又买来 5 个.现在家里有多少个梨?", + "options": [ + + ], + "answer": "7 个", + "solution": "【分析】根据题意,吃了的数量要减去,又买来的数量要加上,即原有梨的数量-吃了的数量 + 又买来的数量 = 现在的数量.\n【详解】6 - 4 + 5 = 7 (个);答: 现在家里有 7 个梨.", + "knowledge_points": [ + "加减混合运算(10以内)" + ], + "source": "24-25 一年级上·江西南昌·期中" + }, + { + "id": "152", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.94, + "question": "白兔有 5 只, 灰兔有 4 只.白兔和灰兔一共有多少只?", + "options": [ + + ], + "answer": "9 只", + "solution": "【分析】用白兔的只数加上灰兔的只数,即可求出白兔和灰兔一共有多少只.\n【详解】5 + 4 = 9 (只);答: 白兔和灰兔一共有 9 只.", + "knowledge_points": [ + "8,9 的加减法" + ], + "source": "24-25 一年级上·江西南昌·期中" + }, + { + "id": "153", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.65, + "question": "一群小朋友排成一排,小明排在队伍中,他前面有3人,后面有4人,这一排小朋友共有多少人?", + "options": [ + + ], + "answer": "8人", + "solution": "【分析】根据题意,用小明前面的人数加上后面的人数,再加上他自己,即可得到这一排的总人数.\n【详解】3 + 4 + 1 = 8 (人)答: 这一排小朋友共有 8 人.", + "knowledge_points": [ + "连加,连减(10以内)", + "前,后位置" + ], + "source": "25-26一年级上·湖南永州·开学考试" + }, + { + "id": "154", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "河里有 4 只鸭子,后来走了2只,又来了3只.现在河里有多少只鸭子?", + "options": [ + + ], + "answer": "5只", + "solution": "【分析】根据题意,用河里原来鸭子的数量减去后来走的数量再加上又来的数量,即可求出现在河里有多少只鸭子.据此解答.\n【详解】4 - 2 + 3 = 5 (只)答: 现在河里有 5 只鸭子.", + "knowledge_points": [ + "加减混合运算(10以内)" + ], + "source": "25-26 一年级上·湖南永州·开学考试" + }, + { + "id": "155", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "奶奶养了 6 只母鸡, 2 只公鸡, 奶奶一共养了几只鸡?", + "options": [ + + ], + "answer": "8只", + "solution": "【分析】根据题意,用母鸡的数量加上公鸡的数量,即可求出一共养了几只鸡.用加法列式计算.\n【详解】6 + 2 = 8 (只)答: 奶奶一共养了 8 只鸡.", + "knowledge_points": [ + "8,9 的加减法" + ], + "source": "25-26 一年级上·湖南永州·开学考试" + }, + { + "id": "156", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "一群小朋友排成一排,小丽排在中间,她前面有2人,后面有3人,这一排小朋友共有多少人?", + "options": [ + + ], + "answer": "6人", + "solution": "【分析】要计算这一排小朋友的总人数,需要把小丽前面的人数,小丽后面的人数以及小丽自己加起来,即可解答.\n【详解】2 + 3 + 1= 5 + 1 = 6 (人);答: 这一排小朋友共有 6 人.", + "knowledge_points": [ + "连加,连减(10以内)" + ], + "source": "25-26一年级上·湖南永州·开学考试" + }, + { + "id": "157", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.94, + "question": "母鸡和小鸡共有 8 只, 小鸡有 5 只, 母鸡有几只?", + "options": [ + + ], + "answer": "3只", + "solution": "【分析】用母鸡和小鸡共有的只数减去小鸡的只数, 即可求出母鸡有几只.\n【详解】8 - 5 = 3 (只);答: 母鸡有 3 只.", + "knowledge_points": [ + "8,9 的加减法" + ], + "source": "25-26 一年级上·湖南永州·开学考试" + }, + { + "id": "158", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "一共有多少个苹果?\n\n![](images/760767df760638787c947dbce81fc27a2bdfa8c42f879ade5307df1a5cb7993e.jpg)\n\n□ ○ □ = □ (个)\n答: 一共有 ( ) 个苹果.", + "options": [ + + ], + "answer": "9 个;6 + 3 = 9 (个);9", + "solution": "【分析】观察题图可知,左边有 6 个苹果,右边有 3 个苹果,求一共有多少个苹果,用加法计算.左边苹果的个数 + 右边苹果的个数 = 苹果的总个数.\n【详解】6 + 3 = 9 (个)答: 一共有 9 个苹果.", + "knowledge_points": [ + "8,9 的加减法", + "图文问题" + ], + "source": "25-26一年级上·黑龙江鹤岗·开学考试" + }, + { + "id": "159", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "停车场原本停了7辆车,先开走1辆,又开走3辆,停车场现在还剩几辆车?", + "options": [ + + ], + "answer": "3辆", + "solution": "【分析】用停车场原本停车的辆数减去先开走的辆数,再减去又开走的辆数,即可求出停车场现在还剩几辆车.\n【详解】7 - 1 - 3= 6 - 3 = 3 (辆);答:停车场现在还剩3辆车.", + "knowledge_points": [ + "连加,连减(10以内)" + ], + "source": "25-26一年级上·黑龙江佳木斯·开学考试" + }, + { + "id": "160", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.94, + "question": "妈妈买了一些苹果, 小明吃了一半后, 还剩下 5 个, 妈妈买了多少个苹果?", + "options": [ + + ], + "answer": "10 个", + "solution": "【分析】根据题意可知, 小明吃了一半, 还剩一半, 也就是吃了的是 5 个, 剩下的是 5 个, 则将吃了的和剩下的数量相加, 就是妈妈买来苹果的总数量.\n【详解】5 + 5 = 10 (个);答: 妈妈买了 10 个苹果.", + "knowledge_points": [ + "10 的加减法" + ], + "source": "25-26 二年级上·黑龙江佳木斯·开学考试" + }, + { + "id": "161", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "天气预报, 今天哈尔滨的最低气温是零下6摄氏度,新疆的最低气温是0摄氏度.你觉得哪个地方更暖和一点?", + "options": [ + + ], + "answer": "新疆", + "solution": "【分析】根据生活经验可知, 温度计上以 0 为界.0 上面的温度称为零上几摄氏度(温度单位), 0 下面的温度称为零下几摄氏度(温度单位), 越往下温度越低.由此解答.\n【详解】由分析可知:新疆的最低气温是 0 摄氏度, 而哈尔滨的最低气温是零下 6 摄氏度, 说明比 0 摄氏度的温度要低, 也就是更冷一些.答:新疆更暖和一点.", + "knowledge_points": [ + "0 的认识和读写", + "6,7 的认识和读写" + ], + "source": "25-26 一年级上·全国·周测" + }, + { + "id": "162", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "在一次长跑比赛中,小明的前面有3个人,后面有2个人,一共有多少人参加跑步比赛?小明想要排名第一,必须超过多少个人?", + "options": [ + + ], + "answer": "6人;3个", + "solution": "【分析】根据加法的意义,小明前面的人数+小明自己+小明后面的人数 = 总人数;小明要想排第一,则需要把排在他前面的人都超过,也就是超过 3 个人,由此解答.\n【详解】3 + 1 + 2 = 6 (人);答: 一共有 6 人参加跑步比赛, 小明要想排名第一, 必须超过 3 个人.", + "knowledge_points": [ + "连加,连减(10以内)" + ], + "source": "25-26一年级上·全国·周测" + }, + { + "id": "163", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "妈妈采了 5 个蘑菇,小丽采了 3 个蘑菇,妈妈和小丽一共采了几个蘑菇?", + "options": [ + + ], + "answer": "8个", + "solution": "【分析】根据加法的意义,妈妈采蘑菇的数量 + 小丽采蘑菇的数量 = 她们采蘑菇的总数量.\n【详解】5 + 3 = 8 (个);答: 妈妈和小丽一共采了 8 个.\n\n![](images/046753e93032c268357605e247082e47a569210503533c417db648f9167addd8.jpg)", + "knowledge_points": [ + "8,9 的加减法" + ], + "source": "25-26 一年级上·湖南永州·开学考试" + }, + { + "id": "164", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "花枝上有 8 只![](images/3299a7453f2a1810a00516e825e8eea9c8fa525fb4eedd62d80ceb9c440bd9ec.jpg),飞走了2只,还剩下几只?", + "options": [ + + ], + "answer": "6只", + "solution": "【分析】根据减法的意义,花枝上原有蜜蜂的数量-飞走的数量 = 还剩的数量.\n【详解】8 - 2 = 6 (只);答: 还剩下 6 只.\n\n![](images/b1037b9c04f3164e319ec90a06f9aac4b84e12c1498263e87064b3ba3954d94e.jpg)", + "knowledge_points": [ + "8,9 的加减法" + ], + "source": "25-26 一年级上·湖南永州·开学考试" + }, + { + "id": "165", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "小红排队买冰淇淋,她前面有2个人,后面有5个人,这一排一共有多少人在排队?", + "options": [ + + ], + "answer": "8 人", + "solution": "【分析】根据题意可知, 小红前面的人数加上她后面的人数, 再加上小红自己, 等于这一排一共有多少人在排队,据此解答.\n【详解】2 + 5 + 1 = 8 (人);答: 这一排一共有 8 人在排队.", + "knowledge_points": [ + "连加,连减(10以内)" + ], + "source": "25-26一年级上·黑龙江佳木斯·开学考试" + }, + { + "id": "166", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "小明有3颗糖,妈妈又给他买了4颗,小明现在一共有几颗糖?", + "options": [ + + ], + "answer": "7 颗", + "solution": "【分析】用小明原有糖的颗数 + 妈妈又给他买的颗数 = 小明现在一共有几颗糖,据此解答.\n【详解】3 + 4 = 7 (颗)答: 小明现在一共有 7 颗糖.", + "knowledge_points": [ + "7 的加减法" + ], + "source": "25-26一年级上·黑龙江佳木斯·开学考试" + }, + { + "id": "167", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "小朋友们排队, 小明前面有 3 人, 后面有 4 人, 这一队一共有多少人?\n\n□ ○ □ ○ □ = □ (人)\n\n答: 这一队一共有 ( ) 人.", + "options": [ + + ], + "answer": "8 人;3 + 4 + 1 = 8 (人);8", + "solution": "【分析】根据题意可知, 小明前面的人数加上他后面的人数, 再加上小明自己, 等于这一队一共有多少人.\n【详解】3 + 4 + 1 = 8 (人)答: 这一队一共有 8 人.", + "knowledge_points": [ + "连加,连减(10以内)" + ], + "source": "25-26 一年级上·黑龙江鹤岗·开学考试" + }, + { + "id": "168", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "小猴子摘了 6 个桃子, 吃了 2 个, 又摘了 3 个, 现在有几个桃子?\n\n□ ○ □ ○ □ = □ (个)\n\n答:现在有()个桃子.", + "options": [ + + ], + "answer": "7 个;6 - 2 + 3 = 7 (个);7", + "solution": "【分析】根据题意可知, 小猴摘了桃子的个数-吃了的个数+又摘了的个数 = 现在桃子的个数, 据此解答.\n【详解】6 - 2 + 3 = 7 (个);答: 现在有 7 个桃子.", + "knowledge_points": [ + "加减混合运算(10以内)" + ], + "source": "25-26 一年级上·黑龙江鹤岗·开学考试" + }, + { + "id": "169", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "树上原来有 10 只小鸟, 飞走了 4 只, 又飞来了 2 只, 现在树上有几只小鸟?\n\n□ ○ □ ○ □ = □ (只)\n\n答:现在树上有()只小鸟.", + "options": [ + + ], + "answer": "8 只;10 - 4 + 2 = 8 (只);8", + "solution": "【分析】根据题意可知, 树上原来小鸟的只数-飞走的只数 + 又飞来的只数 = 现在树上小鸟的只数;据此解答.\n【详解】根据分析可得:10 - 4 + 2 = 8 (只);答: 现在树上有 8 只小鸟.", + "knowledge_points": [ + "加减混合运算(10以内)" + ], + "source": "25-26 一年级上·黑龙江鹤岗·开学考试" + }, + { + "id": "170", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "小红有 8 朵花, 送给小丽 3 朵, 还剩几朵?\n□ ○ □ = □ (朵) \n答: 还剩 ( ) 朵花.", + "options": [ + + ], + "answer": "5 朵;8 - 3 = 5 (朵);5", + "solution": "【分析】根据题意可知, 小红现有花朵的数量减去送给小丽的数量, 等于还剩几朵, 据此解答.\n【详解】8 - 3 = 5 (朵)答: 还剩 5 朵花.", + "knowledge_points": [ + "8,9 的加减法" + ], + "source": "25-26 一年级上·黑龙江鹤岗·开学考试" + }, + { + "id": "171", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.65, + "question": "小朋友排队上体育课,天天排在队伍中.从前往后数,天天排在第6个;从后往前数,天天排在第4个,这一队共有多少人?", + "options": [ + + ], + "answer": "9人", + "solution": "【分析】根据题意,如图\n\n![](images/69fa0bf6c0fc946331f0cb7ec5f51e70e36f9df790fdcbfbf01680ba57e117f5.jpg)\n\n从前往后数, 天天排在第 6 个;从后往前数, 天天排在第 4 个, 天天被数了 2 次. 6 + 4 = 10 , 再减去天天被多数的 1 次, 就是这排队伍的人数.据此解答.\n【详解】根据分析:6 + 4 - 1 = 9 (人),答: 这一队共有 9 人.", + "knowledge_points": [ + "加减混合运算(10以内)", + "排队问题" + ], + "source": "25-26 一年级上·全国·周测" + }, + { + "id": "172", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.65, + "question": "小白兔有 6 个胡萝卜, 它拿 1 个胡萝卜给小黑兔后, 两只小兔的胡萝卜就同样多, 原来小黑兔有几个胡萝卜?", + "options": [ + + ], + "answer": "4 个", + "solution": "【分析】根据减法的意义, 小白兔的胡萝卜数量-拿给小黑兔的胡萝卜数量 = 当前小白兔的胡萝卜数量;当前小白兔的胡萝卜数量和当前小黑兔的胡萝卜数量相等,则当前小黑兔的胡萝卜数量-收到的胡萝卜数量 = 原来小黑兔的胡萝卜数量, 由此列出算式算出答案即可解答.\n【详解】6 - 1 = 5 (个),5 - 1 = 4 (个);答:原来小黑兔有 4 个胡萝卜.", + "knowledge_points": [ + "5以内数的减法", + "6的加减法" + ], + "source": "25-26 一年级上·全国·课后作业" + }, + { + "id": "173", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "故事书共100页,小强第一天看了 6 页, 第二天看了 4 页, 两天一共看了多少页?", + "options": [ + + ], + "answer": "10页", + "solution": "【分析】根据加法的意义,小强第一天看的页数 + 第二天看的页数 = 两天一共看的页数.\n【详解】6 + 4 = 10 (页)答:两天一共看了 10 页.", + "knowledge_points": [ + "10 的加减法" + ], + "source": "25-26 一年级上·全国·课后作业" + }, + { + "id": "174", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "树上原来有 16 只小鸟, 第一次飞走了 5 只, 第二次飞走了 4 只, 现在比原来少了多少只小鸟?", + "options": [ + + ], + "answer": "9只", + "solution": "【分析】根据题意,现在比原来少的数量也就是一共飞走的数量,则用第一次飞走的数量和第二次飞走的数量相加,计算即可.\n【详解】5 + 4 = 9 (只)答: 现在比原来少了 9 只小鸟.", + "knowledge_points": [ + "8,9 的加减法" + ], + "source": "25-26 一年级上·全国·课后作业" + }, + { + "id": "175", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.65, + "question": "一道减法算式, 减数减少了 2 , 差怎样变化?", + "options": [ + + ], + "answer": "差增加 2", + "solution": "【分析】减法算式为被减数-减数 = 差,可以举例解答,如原算式为 10 - 4 = 6 , 则计算出减数变化后的差, 即可解答.\n【详解】由分析得:原算式为 10 - 4 = 6;减数减少 2 , 即现在的减数为 4 - 2 = 2;现在的差为 10 - 2 = 8,8 \u003e 6,8 - 6 = 2;答: 差增加 2.", + "knowledge_points": [ + "8,9 的加减法", + "10 的加减法" + ], + "source": "25-26 一年级上·全国·课后作业" + }, + { + "id": "176", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.65, + "question": "一道减法算式, 被减数减少了 3 , 差怎样变化?", + "options": [ + + ], + "answer": "差减少 3", + "solution": "【分析】减法算式为被减数-减数 = 差, 可以举例解答,如原算式为 10 - 5 = 5 , 则计算出被减数减少后的差, 即可解答.\n【详解】例如:原算式为 10 - 5 = 5,被减数减少 3 , 即 10 - 3 = 7,现在的差为: 7 - 5 = 2,2 \u003c 5 , 现在的差比原来的差小.5 - 2 = 3;答: 差减少 3 .", + "knowledge_points": [ + "和与差的变化规律", + "7 的加减法", + "10 的加减法" + ], + "source": "25-26 一年级上·全国·课后作业" + }, + { + "id": "177", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "一道加法算式, 两个加数同时增加了 5 , 和增加了多少?", + "options": [ + + ], + "answer": "和增加 10", + "solution": "【分析】根据题意,我们先假设一个算式是 2 + 3 = 5 ,两个加数都增加了 5,算式变成 7 + 8 = 15 ,和从 5 变成了 15,也增加了 10.\n【详解】由分析可得:\n\n原加法算式: 2 + 3 = 5 , 两个加数都增加了 5 , 算式变成: 7 + 8 = 15 , 和的变化是: 15 - 5 = 10 .答: 和增加了 10 .", + "knowledge_points": [ + "和与差的变化规律", + "加减混合运算(10以内)", + "加减混合运算(20以内)" + ], + "source": "25-26 一年级上·全国·课后作业" + }, + { + "id": "178", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "一道加法算式, 一个加数减少了 3 , 和怎样变化?", + "options": [ + + ], + "answer": "和减少 3", + "solution": "【分析】根据题意, 我们先假设一个算式是 2 + 5 = 7 , 如果一个加数减少了 3 , 加数 5 减少了 3 , 算式变成 2 + 2 = 4 , 和从 7 变成了 4 , 减少了 3 .\n【详解】根据分析可得:原加法算式: 2 + 5 = 7 , 加数 5 减少了 3 变成 2 , 算式变为 2 + 2 = 4 , 和的变化是: 7 - 4 = 3 .答: 和减少了 3 .", + "knowledge_points": [ + "和与差的变化规律", + "加减混合运算(10以内)" + ], + "source": "25-26 一年级上·全国·课后作业" + }, + { + "id": "179", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.65, + "question": "一道加法算式, 一个加数增加了 4 , 和怎样变化?", + "options": [ + + ], + "answer": "和增加了 4", + "solution": "【分析】根据题意, 我们先假设一个算式是 2 + 3 = 5 , 如果一个加数增加了 4 , 算式变成 6 + 3 = 9 , 加数 2 增加了 4 , 和从 5 变成了 9 , 也增加了 4 .\n【详解】例如: 2 + 3 = 5;2 + 4 = 6;6 + 3 = 9;9 - 5 = 4;答: 和增加了 4 .", + "knowledge_points": [ + "8,9 的加减法", + "和与差的变化规律" + ], + "source": "25-26 一年级上·全国·课后作业" + }, + { + "id": "180", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "有 9 只兔子, 要坐成一排照相,如果让兔妈妈坐在正中间,兔妈妈应该坐在第几个座位上?", + "options": [ + + ], + "answer": "第 5 个", + "solution": "【分析】从 9 只兔子中把兔妈妈这 1 只减去, 是剩余的兔子数, 找出剩余兔子数的一半, 即是兔妈妈前面或后面的兔子只数, 用兔妈妈前面的兔子只数加上兔妈妈这 1 只, 即是兔妈妈应该坐的座位数;据此解答.\n【详解】由分析可得:9 - 1 = 8 (只),8 - 4 = 4 (只),4 + 1 = 5 (个);答: 兔妈妈应该坐在第 5 个座位上.", + "knowledge_points": [ + "8,9 的加减法", + "5 以内数的加法" + ], + "source": "25-26 一年级上·全国·课后作业" + }, + { + "id": "181", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.65, + "question": "两条同样长的彩带,红彩带用去了3米,绿彩带用去了7米.哪一条彩带剩下的长?长多少米?", + "options": [ + + ], + "answer": "红彩带;4米", + "solution": "【分析】根据题意,假设两条同样长的彩带都是 9 米,用彩带的长度-用去的长度 = 剩下的长度,分别算出两条彩带各剩下几米,再比较大小,即可知道哪一条彩带剩下的长;用减法可以算出长多少米;据此解答.\n【详解】假设两条同样长的彩带都是 9 米,9 - 3 = 6 (米);9 - 7 = 2 (米),6 \u003e 2,答:红彩带剩下的长.6 - 2 = 4 (米),答: 长 4 米.", + "knowledge_points": [ + "7 以内数的比大小", + "6 的加减法", + "9 以内加减法实际应用" + ], + "source": "25-26 一年级上·全国·课后作业" + }, + { + "id": "182", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "小动物们举行运动会,老虎排队去参加,从前数老虎排第2,从后数老虎排第 4,这一队一共有多少只小动物?", + "options": [ + + ], + "answer": "5 只", + "solution": "【分析】根据题意可知, 老虎从前数排第 2 , 所以老虎前面有 1 只小动物, 老虎从后数排第 4 , 所以老虎后面有 3 只小动物, 可用加法计算, 老虎前面的 1 只加上后面的 3 只再加上老虎即可得出答案.\n【详解】2 - 1 = 1 (只),4 - 1 = 3 (只),1 + 3 + 1 = 5 (只);答: 这一队一共有 5 只小动物.", + "knowledge_points": [ + "连加,连减(10以内)", + "5以内数的加法", + "前,后位置" + ], + "source": "25-26 一年级上·全国·课后作业" + }, + { + "id": "183", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "小动物们排成一排做操, 小猴的前面有 3 只小动物, 它的后面也有 3 只小动物,这一排一共有几只小动物呢?", + "options": [ + + ], + "answer": "7 只", + "solution": "【分析】根据题意可知:求一共有的数量,用小猴前面的数量加后面的数量再加上小猴自己 1 只即可.\n【详解】3 + 3 + 1 = 7 (只),答: 这一排一共有 7 只小动物.", + "knowledge_points": [ + "连加,连减(10以内)" + ], + "source": "25-26 一年级上·全国·课后作业" + }, + { + "id": "184", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "10 只小动物排一队,小猫的前面有 5 只小动物, 排在小猫后面的小动物有几只?", + "options": [ + + ], + "answer": "4 只", + "solution": "【分析】根据题意, 用这一队的动物总数-小猫前面的动物数量-小猫本身 = 排在小猫后面的小动物的数量, 据此解答.\n【详解】根据分析:10 - 5 - 1 = 4 (只);答: 排在小猫后面的小动物有 4 只.", + "knowledge_points": [ + "连加,连减(10以内)", + "排队问题", + "前,后位置" + ], + "source": "25-26 一年级上·全国·课后作业" + }, + { + "id": "185", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "学校走廊里有一排盆栽花,从左往右数,杜鹃花是第4盆,从右往左数,这盆杜鹃花是第5盆.这一排一共有多少盆盆栽花?", + "options": [ + + ], + "answer": "8盆", + "solution": "【分析】根据题意可知:杜鹃花的前面有 3 盆,后面有 4 盆,则求这一排有多少盆?用杜鹃花前面的数量加其后面的数量再加上杜鹃花自己这 1 盆即可.\n【详解】3 + 4 + 1 = 8 (盆),答: 这一排一共有 8 盆盆栽花.", + "knowledge_points": [ + "连加,连减(10以内)" + ], + "source": "25-26 一年级上·全国·课后作业" + }, + { + "id": "186", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "瞧!乐乐又来了,他和小伙伴们在玩游戏呢!做游戏时,乐乐从左边数起排在第5个,从右边数起排在第6个,这一排一共有多少个小朋友呢?", + "options": [ + + ], + "answer": "10 个", + "solution": "【分析】根据题意, 乐乐从左边数起排在第 5 个, 所以乐乐左边有 4 人, 乐乐从右边数起排在第 6 个, 说明乐乐右边有5人,再加上乐乐本人,就是这一队的总人数,据此解答.\n【详解】根据分析:4 + 5 + 1 = 10 (个)\n答: 这一排一共有 10 个小朋友.", + "knowledge_points": [ + "左,右位置", + "连加,连减(10以内)", + "排队问题" + ], + "source": "25-26 一年级上·全国·课后作业" + }, + { + "id": "187", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.65, + "question": "把 10 个桃子放在 3 个盘子里,每个盘子里桃子的个数各不相同,你能试着分一分吗?", + "options": [ + + ], + "answer": "能;见详解", + "solution": "【分析】根据题意, 把 10 个桃子放在 3 个盘子里, 每个盘子里桃子的个数各不相同, 也就是把 10 分成几, 几和几,据此解答.\n【详解】由分析可得:第一种分法:第 1 个盘子放 1 个桃子,第 2 个盘子放 2 个桃子,第3个盘子放7个桃子;第二种分法:第 1 个盘子放 1 个桃子,第 2 个盘子放 3 个桃子,第 3 个盘子放 6 个桃子;第三种分法:第 1 个盘子放 1 个桃子,第 2 个盘子放 4 个桃子,第 3 个盘子放 5 个桃子;第四种分法:第 1 个盘子放 2 个桃子,第 2 个盘子放 3 个桃子,第 3 个盘子放 5 个桃子.", + "knowledge_points": [ + "10 的分与合 (组成)" + ], + "source": "25-26 一年级上·全国·课后作业" + }, + { + "id": "188", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.65, + "question": "乐乐有 6 块巧克力, 欢欢有 5 块巧克力, 妈妈又买来 3 块巧克力, 怎样分才能让两人的巧克力块数同样多?", + "options": [ + + ], + "answer": "欢欢;2 块;乐乐;1 块", + "solution": "【分析】欢欢比乐乐少 1 块,先给欢欢 1 块,剩下的分成相同的两份,一人一份即可.\n【详解】6 - 5 = 1 (块),还剩: 3 - 1 = 2 (块),1 + 1 = 2 (块)一人再分 1 块.则欢欢分了 1 + 1 = 2 (块),乐乐分了 1 块.答: 给欢欢 2 块, 乐乐 1 块.", + "knowledge_points": [ + "5 以内数的加法", + "5 以内数的减法", + "6 的加减法", + "移多补少问题" + ], + "source": "25-26 一年级上·全国·课后作业" + }, + { + "id": "189", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "乐乐有 7 块巧克力,欢欢有5块巧克力,妈妈又买来2块巧克力,怎样分才能让两人的巧克力块数同样多?", + "options": [ + + ], + "answer": "买来的 2 块巧克力都给欢欢", + "solution": "【分析】已知乐乐有 7 块巧克力, 欢欢有 5 块巧克力, 欢欢比乐乐少 2 块, 妈妈又买来 2 块, 正好可以弥补欢欢比乐乐少的 2 块, 两个人就一样多了.\n【详解】5 + 2 = 7 (块),7 = 7,答: 妈妈又买来的 2 块巧克力都给欢欢.", + "knowledge_points": [ + "10以内数的比大小", + "7的加减法" + ], + "source": "25-26 一年级上·全国·课后作业" + }, + { + "id": "190", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.65, + "question": "小白兔有 3 个萝卜,小黑兔有5个萝卜,兔妈妈又买来2个萝卜,怎样分才能让两只小兔的萝卜个数同样多?", + "options": [ + + ], + "answer": "分给小白兔 2 个;分给小黑兔 0 个", + "solution": "【分析】先计算萝卜总数,再求每只小兔需要分的数量(分成相同的两份), 最后根据原有数量确定需要分得的数量.\n【详解】3 + 5 + 2= 8 + 2 = 10 (个),5 + 5 = 10 (个),每只小兔需要有 5 个萝卜.小白兔: 5 - 3 = 2 (个),小黑兔: 5 - 5 = 0 (个)答: 分给小白兔 2 个萝卜, 分给小黑兔 0 个萝卜.", + "knowledge_points": [ + "连加,连减(10以内)", + "5以内数的减法" + ], + "source": "25-26 一年级上·全国·课后作业" + }, + { + "id": "191", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "9个小朋友做运球游戏.第1个小朋友把球从操场东边运到西边,第2个小朋友接着把球从西边运到东边,第3个小朋友又接着运下去...最后球在东边还是西边?", + "options": [ + + ], + "answer": "西边", + "solution": "【分析】根据题意, 一共有 9 个小朋友, 第 1 个小朋友把球从操场东边运到西边, 此时球在西边.第 2 个小朋友把球从西边运到东边,此时球在东边.第3个小朋友把球从操场东边运到西边,此时球在西边...,也就是第1,3,5,7,9个小朋友把球从操场东边运到西边,第2,4,6,8个小朋友把球从西边运到东边,最后一个小朋友是第9个,所以最后球在西边.据此解答.\n【详解】根据分析:第1,3,5,7,9个小朋友把球从操场东边运到西边,第 2,4,6,8 个小朋友把球从西边运到东边,所以最后球在西边.", + "knowledge_points": [ + "8,9 的认识和读写", + "周期问题", + "认识几和第几" + ], + "source": "25-26 一年级上·全国·课后作业" + }, + { + "id": "192", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.65, + "question": "时钟敲了 3 下, 正好2秒钟敲完.如果时钟敲7下,你知道几秒可以敲完?", + "options": [ + + ], + "answer": "6秒", + "solution": "【分析】根据题意,当时钟敲3下时,实际上有2个时间间隔(从第一下到第二下,第二下到第三下),总用时为 2 秒,也就是每个间隔是 1 秒钟,即间隔数 +1 = 敲的次数,敲的次数 -1 = 间隔数(秒数).\n【详解】7 - 1 = 6 (秒),答: 6 秒可以敲完.", + "knowledge_points": [ + "7 的加减法" + ], + "source": "25-26 一年级上·全国·课后作业" + }, + { + "id": "193", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.65, + "question": "新年快到了,教室里挂了一排红灯笼,共有 10 个,每 2 个红灯笼之间放 1 个黄灯笼,一共有多少个黄灯笼?", + "options": [ + + ], + "answer": "9 个", + "solution": "【分析】根据题意,每 2 个红灯笼之间放 1 个黄灯笼,则 3 个红灯笼之间放 2 个黄灯笼,4 个红灯笼之间放 3 个黄灯笼...,黄灯笼的个数比红灯笼的个数少 1,红灯笼共有 10 个,减去 1 个,就是黄灯笼的个数,据此解答.\n【详解】10 - 1 = 9 (个);答: 一共有 9 个黄灯笼.", + "knowledge_points": [ + "10 的加减法" + ], + "source": "25-26 一年级上·全国·课后作业" + }, + { + "id": "194", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.65, + "question": "从 4 数到 9 , 一共数了几个数?", + "options": [ + + ], + "answer": "6 个", + "solution": "【分析】根据题意, 从数到的数字减去开始数的数字, 由于 4 也数了, 相当于多减了一个数, 则再加 1 是总个数.\n【详解】9 - 4 + 1 = 6 (个);答: 一共数了 6 个数.", + "knowledge_points": [ + "加减混合运算(10以内)" + ], + "source": "25-26 一年级上·全国·课后作业" + }, + { + "id": "195", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "李老师给宁宁一些气球,让他分给第1组和第2组,宁宁数了数,让老师再给他 1 个,这样两个小组就都有 4 个了,你知道李老师给了宁宁多少个吗?", + "options": [ + + ], + "answer": "7 个", + "solution": "【分析】根据题意,先用加法计算出两个小组都有 4 个时一共需要多少个气球,再用需要气球的总数量减去宁宁让李老师再给他的 1 个,就是原来李老师给宁宁的数量.\n【详解】4 + 4 = 8 (个),8 - 1 = 7 (个),答: 李老师给了宁宁 7 个", + "knowledge_points": [ + "8,9 的加减法" + ], + "source": "25-26 一年级上·全国·课后作业" + }, + { + "id": "196", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "一道加法算式, 一个加数增加 5 , 另一个加数减少 7 , 和怎样变化?", + "options": [ + + ], + "answer": "和减少 2", + "solution": "【分析】根据题意,我们先假设一个算式是 2 + 8 = 10 ,如果加数 2 增加了 5,加数 8 减少 7,算式变成 7 + 1 = 8 ,和从 10 变成了 8,减少了 2.\n【详解】根据分析可得:原加法算式: 2 + 8 = 10 , 一个加数增加 5 , 另一个加数减少 7, 算式变成: 7 + 1 = 8 , 和的变化是: 10 - 8 = 2 .答: 和减少了 2 .", + "knowledge_points": [ + "和与差的变化规律", + "加减混合运算(10以内)", + "加减混合运算 (20 以内)" + ], + "source": "25-26 一年级上·全国·课后作业" + }, + { + "id": "197", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.65, + "question": "一道减法算式, 被减数增加 3 , 减数减少 2 , 差怎样变化?", + "options": [ + + ], + "answer": "增加 5", + "solution": "【分析】减法算式为被减数-减数 = 差,可以举例解答, 如原算式为 7 - 2 = 5 , 则计算出被减数和减数变化后算式的差,即可解答.\n【详解】例如:原算式为 7 - 2 = 5,被减数增加 3 , 即 7 + 3 = 10,减数减少 2 , 即 2 - 2 = 0,现在的差为 10 - 0 = 10;10 \u003e 5 , 比原来的差要大.10 - 5 = 5;答: 差增加 5 .", + "knowledge_points": [ + "和与差的变化规律", + "7 的加减法", + "10 的加减法" + ], + "source": "25-26 一年级上·全国·课后作业" + }, + { + "id": "198", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.65, + "question": "一道减法算式,被减数和减数都减少了6,差怎样变化?", + "options": [ + + ], + "answer": "差不变", + "solution": "【分析】减法算式为被减数-减数 = 差, 可举例解答, 如原算式为 10 - 6 = 4 , 则计算出被减数和减数减少后算式的差, 即可解答.\n【详解】由分析得:原算式: 10 - 6 = 4;被减数减少 6 , 即 10 - 6 = 4;减数减少 6 , 即 6 - 6 = 0;现在的差为 4 - 0 = 4;4 = 4 , 和原来的差相同.答: 差不变.", + "knowledge_points": [ + "6 的加减法", + "10 的加减法" + ], + "source": "25-26 一年级上·全国·课后作业" + }, + { + "id": "199", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "瓜地里有 12 个西瓜,八戒先摘3个西瓜,然后又摘走了4个西瓜,最后又摘走了2个西瓜,八戒一共摘走了多少个西瓜?", + "options": [ + + ], + "answer": "9 个", + "solution": "【分析】根据题意, 用八戒先摘走的数量 + 又摘走的数量+最后又摘走的数量 = 八戒一共摘走的数量,据此解答.\n【详解】根据分析:3 + 4 + 2 = 9 (个)答: 八戒一共摘走了 9 个西瓜.", + "knowledge_points": [ + "连加,连减(10以内)" + ], + "source": "25-26 一年级上·全国·课后作业" + }, + { + "id": "200", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "10 块巧克力, 小明吃了几块后还剩下 4 块, 小明吃了几块巧克力?", + "options": [ + + ], + "answer": "6块", + "solution": "【分析】由题意可知: 用巧克力块数减去还剩的块数, 即是小明吃的巧克力块数;据此解答.\n【详解】由分析可得:10 - 4 = 6 (块)答: 小明吃了 6 块巧克力.", + "knowledge_points": [ + "10 的加减法" + ], + "source": "25-26 一年级上·全国·课后作业" + }, + { + "id": "201", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.65, + "question": "10个小朋友排队玩滑滑梯,乐乐前面有3个人,后面有()个人.", + "options": [ + "A. 4", + "B. 5", + "C. 6" + ], + "answer": "C", + "solution": "【分析】用 10 个小朋友减去乐乐前面的 3 个人, 再减去乐乐, 即可得到后面有几个人.\n【详解】 10 - 3 - 1 = 6 (人)所以,后面有 6 个人.故答案为: C", + "knowledge_points": [ + "连加,连减(10以内)", + "前,后位置" + ], + "source": "2025一年级上·全国·专题练习" + }, + { + "id": "202", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "8 根筷子是 ( ) 双.", + "options": [ + "A. 8", + "B. 10", + "C. 4" + ], + "answer": "C", + "solution": "【分析】根据生活经验可知, 每 2 根筷子为一双, 则可以用筷子的总根数依次减去每双筷子的根数, 减到最后的结果为 0 , 减了几次 2 , 就是几双.\n【详解】 8 - 2 = 6 (根),6 - 2 = 4 (根),4 - 2 = 2 (根),2 - 2 = 0 (根),减了 4 次 2 , 则 8 根筷子是 4 双.故答案为: C", + "knowledge_points": [ + "6的加减法", + "5以内数的减法", + "8,9的加减法" + ], + "source": "24-25一年级上·河南信阳·期末" + }, + { + "id": "203", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "和 1 相邻的两个数是 ( ).", + "options": [ + "A. 2 和 3", + "B. 1 和 2", + "C. 0 和 2" + ], + "answer": "C", + "solution": "【分析】10以内数的排序为0,1,2,3,4,5,6,7,8,9,10,根据排序可知1前一个数0,后一个数是2,据此解答.\n【详解】根据分析可得:和 1 相邻的两个数是 0 和 2.故答案为: C", + "knowledge_points": [ + "10以内数的排序" + ], + "source": "24-25 一年级上·广西玉林·期末" + }, + { + "id": "204", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.65, + "question": "要使 9 \u003e 5+□ , □ 里可以填 ( ) 个数.", + "options": [ + "A. 4", + "B. 3", + "C. 2" + ], + "answer": "A", + "solution": "【分析】 5 + □ 最大是 9 减 1 的得数, 最小是 5 加 0 的得数,用 9 减 1 的得数减 5 可以求出□里最大填几,据此解答.\n【详解】 9 - 1 = 8 , 8 - 5 = 3,可以填 0,1,2,3,共 4 个数.故答案为: A", + "knowledge_points": [ + "9 以内数的比大小", + "8,9 的加减法" + ], + "source": "24-25 一年级上·河南商丘·期末" + }, + { + "id": "205", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "下面关于 10 的说法,错误的是 ( ).", + "options": [ + "A. 0 - 9 是用一个数字表示的, 10 是用 1 和 0 两个数字来表示的.", + "B. 1 和 10 都有 \"1\", 两个 \"1\"表示的意义一样.", + "C. 9 添上 1 就是 10.", + "D. 10个一是 10." + ], + "answer": "B", + "solution": "【分析】10 表示一个一个地数一共数了 10 个.有几个数字就是几个数字表示.1 个十是 10,10 个一也是 10.逐项分析.\n【详解】A. 0 - 9 是用一个数字表示的, 10 是用 1 和 0 两个数字来表示的.10 表示一个一个地数一共数了 10 个.有几个数字就是几个数字表示.不符合题意.B. 1 和 10 都有 \"1\", 两个 \"1\"表示的意义一样.1 表示的 1 个 10 中的 1 表示 1 个十, 则意义不同, 符合题意. C. 9 添上 1 就是 10 . 9 + 1 = 10 , 不符合题意. D. 10 个一是 10.10 可以表示 1 个十, 也可以表示 10 个一,不符合题意.故答案为: B", + "knowledge_points": [ + "10 的认识和读写" + ], + "source": "24-25 一年级上·福建龙岩·期末" + }, + { + "id": "206", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.65, + "question": "小朋友排队做操, 笑笑前面有 3 人, 后面有 6 人, 这一队一共有 ( ) 人做操.", + "options": [ + "A. 8", + "B. 9", + "C. 10" + ], + "answer": "C", + "solution": "【分析】用笑笑前面的人数加后面的人数再加笑笑即可求出一共多少人.\n【详解】 3 + 6 + 1 = 10 (人);这一队一共有 10 人做操.故答案为: C", + "knowledge_points": [ + "连加,连减(10以内)" + ], + "source": "24-25 一年级上·河南周口·期末" + }, + { + "id": "207", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "笑笑折了 4 只小船,淘气折了 3 只小船, 共折了 ( ) 只小船.", + "options": [ + "A. 5", + "B. 1", + "C. 7" + ], + "answer": "C", + "solution": "【分析】用加法把两人折的小船数量加起来,求出和,就是两人共折的小船数量.\n【详解】由题意分析得:4 + 3 = 7 (只),笑笑折了 4 只小船, 淘气折了 3 只小船, 共折了 7 只小船.故答案为: C", + "knowledge_points": [ + "7 的加减法" + ], + "source": "24-25 一年级上·河南商丘·期末" + }, + { + "id": "208", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "小明左边有 3 人,右边有 4 人, 这一排一共有 ( ) 人.", + "options": [ + "A. 7", + "B. 8", + "C. 9" + ], + "answer": "B", + "solution": "【分析】根据加法的意义,小明左边的人数 + 小明自己 + 小明右边的人数 = 这一排的总人数.\n【详解】 3 + 1 + 4 = 8 (人),这一排一共有 8 人.故答案为: B", + "knowledge_points": [ + "连加,连减(10以内)" + ], + "source": "24-25 一年级下·新疆喀什·开学考试" + }, + { + "id": "209", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "与 8-3 得数相同的是().", + "options": [ + "A. 9 - 4", + "B. 7 - 3", + "C. 8 - 2" + ], + "answer": "A", + "solution": "【分析】先求出各算式的答案,然后选择相同的即可.\n【详解】 8 - 3 = 5,A. 9 - 4 = 5, 5 = 5 , 符合题意. B. 7 - 3 = 4, 4 \u003c 5 , 则不符合题意.C. 8 - 2 = 6, 6 \u003e 5 , 则不符合题意.故答案为: A", + "knowledge_points": [ + "7 的加减法", + "8,9 的加减法" + ], + "source": "24-25一年级下·新疆喀什·开学考试" + }, + { + "id": "210", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": " 5 + 3 的结果比 9 ( ).", + "options": [ + "A. 大", + "B. 小", + "C. 相等" + ], + "answer": "B", + "solution": "【分析】先算出 5 加 3 的结果,然后和 9 作比较.\n【详解】 5 + 3 = 8,8 \u003c 9,5 + 3 的结果比 9 小.故答案为: B", + "knowledge_points": [ + "9 以内数的比大小", + "8,9 的加减法" + ], + "source": "24-25 一年级下·新疆喀什·开学考试" + }, + { + "id": "211", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "下面计算结果等于 8 的是 ( ).", + "options": [ + "A. 2 + 7", + "B. 3 + 5", + "C. 9 - 2" + ], + "answer": "B", + "solution": "【分析】根据选项中给出的算式,计算出每个算式的结果,看哪一个等于 8 即可得出答案.\n【详解】A. 2 + 7 = 9 , 结果是 9 , 不符合题意;B. 3 + 5 = 8 , 结果是 8 , 符合题意;C. 9 - 2 = 7 , 结果是 7 , 不符合题意.故答案为: B", + "knowledge_points": [ + "8,9 的加减法" + ], + "source": "24-25 一年级下·新疆喀什·开学考试" + }, + { + "id": "212", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "被减数是 9 , 减数是 4 , 差是 ( ).", + "options": [ + "A. 13", + "B. 0", + "C. 5" + ], + "answer": "C", + "solution": "【分析】被减数-减数 = 差,据此直接计算.\n【详解】 9 - 4 = 5,差是 5 ,故答案为: C", + "knowledge_points": [ + "8,9 的加减法" + ], + "source": "24-25 一年级上·湖南邵阳·期中" + }, + { + "id": "213", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "比大小: 3 + 4 ○ 8, ○ 里应该填什么? ( )", + "options": [ + "A. \u003e", + "B. =", + "C. \u003c" + ], + "answer": "C", + "solution": "【分析】计算出算是的答案,然后和 8 比较即可.\n【详解】 3 + 4 = 7,7 \u003c 8,故答案为: C", + "knowledge_points": [ + "9 以内数的比大小", + "7 的加减法" + ], + "source": "24-25 一年级上·河南新乡·期末" + }, + { + "id": "214", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "和\"8-3\"得数相等的算式是().", + "options": [ + "A. 9 - 4", + "B. 7 + 2", + "C. 6 - 2" + ], + "answer": "A", + "solution": "【分析】算出 8 - 3 的得数和各选项中算式的得数即可求解.\n【详解】 8 - 3 = 5,A. 9 - 4 = 5,B. 7 + 2 = 9,C. 6 - 2 = 4和 \"8-3\"得数相等的算式是 \"9-4\".故答案为: A", + "knowledge_points": [ + "6 的加减法", + "7 的加减法", + "8,9 的加减法" + ], + "source": "24-25一年级上·河南周口·期末" + }, + { + "id": "215", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "下面的算式中, 减数是 6 的算式是 ( ).", + "options": [ + "A. 6 + 3 = 9", + "B. 9 - 6 = 3", + "C. 9 - 3 = 6" + ], + "answer": "B", + "solution": "【分析】减法算式为被减数-减数 = 差,加法算式为加数 + 加数 = 和,由此找出减数是 6 的即可.\n【详解】A. 6 + 3 = 9, 6 是一个加数,不符合题意;B. 9 - 6 = 3, 6 是减数,符合题意;C. 9 - 3 = 6, 6 是差,不符合题意.则减数是 6 的算式是 9 - 6 = 3 .故答案为: B", + "knowledge_points": [ + "8,9 的加减法" + ], + "source": "24-25 一年级上·福建福州·期末" + }, + { + "id": "216", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "彩娃家住在8层,福娃家比他家低2层,福娃家住()层.", + "options": [ + "A. 2", + "B. 6", + "C. 10" + ], + "answer": "B", + "solution": "【分析】根据题意可知, 彩娃家住在 8 层, 福娃家比他家低 2 层, 即比 8 层少 2 层;用彩娃家的楼层数减去福娃家比他家低的层数, 即可求出福娃家住几层, 据此解答.\n【详解】根据分析可得:8 - 2 = 6 (层),彩娃家住在 8 层,福娃家比他家低 2 层,福娃家住 6 层.故答案为: B", + "knowledge_points": [ + "8,9 的加减法" + ], + "source": "24-25 一年级上·河南南阳·期末" + }, + { + "id": "217", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.94, + "question": "下面算式中, 与 10 -3 得数相等的是 ( ).", + "options": [ + "A. 8 - 2", + "B. 7 - 0", + "C. 9 - 3" + ], + "answer": "B", + "solution": "【分析】先计算出 10 - 3 = 7 , 再分别算出各个选项的结果,找到和 10 - 3 结果相同的选项即可, 据此解答.\n【详解】A. 8 - 2 = 6 ,不等于7,答案不正确;B. 7 - 0 = 7 , 等于 7, 答案正确;C. 9 - 3 = 6 , 不等于 7, 答案不正确;故答案为: B", + "knowledge_points": [ + "7 的加减法", + "10 的加减法", + "8,9 的加减法" + ], + "source": "24-25 一年级上·湖南湘西·期末" + }, + { + "id": "218", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "8 的相邻数是 ( ).", + "options": [ + "A. 9和10", + "B. 7 和 9", + "C. 6和7" + ], + "answer": "B", + "solution": "【分析】根据题意可知:求一个数的相邻的两个数,就是求比这个数小 1 和大 1 的数,即用这个数减 1 和加 1.\n【详解】 8 - 1 = 7,8 + 1 = 9,则 8 的相邻数是 7 和 9.故答案为: B", + "knowledge_points": [ + "10以内数的排序", + "8,9的加减法" + ], + "source": "24-25 一年级上·黑龙江绥化·期末" + }, + { + "id": "219", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "9 个小朋友排成一排,排在小可前面的有 5 人, 排在小可后面的有 ( ) 人.", + "options": [ + "A. 3", + "B. 4", + "C. 5" + ], + "answer": "A", + "solution": "【分析】根据题意, 9 个小朋友排成一排, 排在小可前面的有 5 人, 这 5 人中不包含小可, 说明小可排在第六位, 用总人数减去小可前面的 5 人, 求出差, 再减去小可本人, 就可以求出排在小可后面的人数.\n【详解】 9 - 5 = 4 (人),4 - 1 = 3 (人),排在小可后面的有 3 人.故答案为: A", + "knowledge_points": [ + "前,后位置", + "8,9 的加减法" + ], + "source": "24-25 一年级上·湖南湘西·期末" + }, + { + "id": "220", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.65, + "question": "一共有 10 个女生,老师让相邻两个女生之间站一个男生,一共可以站进()个男生.", + "options": [ + "A. 8", + "B. 9", + "C. 10" + ], + "answer": "B", + "solution": "【分析】相当于有 10 减 1 个间隔, 每个间隔中一个男生,用女生人数减 1 即可求出站的男生人数.\n【详解】 10 - 1 = 9 (个),一共可以站进 9 个男生.故答案为: B", + "knowledge_points": [ + "10 的加减法", + "植树问题(两端都栽)" + ], + "source": "24-25 一年级下·广东潮州·阶段练习" + }, + { + "id": "221", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "小华从头开始看一本书,第一天看了3页,第二天看了6页,第三天接着看,小华应该从第()页看起.", + "options": [ + "A. 10", + "B. 6", + "C. 9" + ], + "answer": "A", + "solution": "【分析】根据题意,先用加法计算出第一天和第二天一共看了几页,第三天开始看的页数应为前两天看的总页数的后一页,则再加 1 即可.\n【详解】 3 + 6 + 1 = 10 (页),第三天小华应该从第 10 页看起.故答案为: A", + "knowledge_points": [ + "连加,连减(10以内)" + ], + "source": "24-25一年级上·贵州黔东南·期末" + }, + { + "id": "222", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "与9相邻的两个数是().", + "options": [ + "A. 7 和 8", + "B. 8和10", + "C. 10和11" + ], + "answer": "B", + "solution": "【分析】与一个数相邻的两个数, 指的是比它小 1 和大 1 的数.9 的前一个数是: 9 - 1 = 8 , 9 的后一个数是, 9 + 1 = 10 , 因此, 与 9 相邻的两个数是 8 和 10 , 找出正确答案即可.\n【详解】根据分析可知,与 9 相邻的两个数是 8 和 10.故答案为: B", + "knowledge_points": [ + "10 的加减法", + "8,9 的加减法" + ], + "source": "24-25一年级上·安徽黄山·期末" + }, + { + "id": "223", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "比 2 大, 比 9 小的数有 ( ) 个.", + "options": [ + "A. 7", + "B. 6", + "C. 8" + ], + "answer": "B", + "solution": "【分析】9 以内数从大到小关系为: 9 \u003e 8 \u003e 7 \u003e 6 \u003e 5 \u003e 4 \u003e 3 \u003e2 \u003e 1 , 由此找出比 2 大, 比 9 小的数, 数出个数即可.\n【详解】由分析可知,比2大,比9小的数有3,4,5,6,7,8,共6个.故答案为:B", + "knowledge_points": [ + "9 以内数的比大小" + ], + "source": "24-25 一年级上·安徽黄山·期末" + }, + { + "id": "224", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "小红前面有5个人,后面有2个人,这列队伍一共有()人.", + "options": [ + "A. 3", + "B. 7", + "C. 8", + "D. 9" + ], + "answer": "C", + "solution": "【分析】根据加法的意义,小红前面的人数 + 小红自己 + 小红后面的人数 = 总人数.\n【详解】 5 + 1 + 2 = 8 (人),这列队伍一共有 8 人.故答案为: C", + "knowledge_points": [ + "连加,连减(10以内)" + ], + "source": "24-25一年级上·浙江温州·期末" + }, + { + "id": "225", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "小明吃掉2颗糖,再吃掉 1 颗糖, 现在还剩 5 颗糖.小明原来有 ( ) 颗糖.", + "options": [ + "A. 8", + "B. 2", + "C. 4", + "D. 6" + ], + "answer": "A", + "solution": "【分析】根据加法的意义,先吃掉的数量 + 再吃掉的数量 + 还剩的数量 = 原来糖果的数量.\n【详解】 2 + 1 + 5 = 8 (颗),小明原来有 8 颗糖.故答案为: A", + "knowledge_points": [ + "连加,连减(10以内)" + ], + "source": "24-25一年级上·浙江温州·期末" + }, + { + "id": "226", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "无论是从前往后数,还是从后往前数,华华都排在第5个,这个队伍一共有()人.", + "options": [ + "A. 9", + "B. 10", + "C. 11" + ], + "answer": "A", + "solution": "【分析】根据题意可知,华华都排在第5个,华华前面有4个人,后面也有4个人,用华华前面的人数加上后面的人数,再加上华华就等于这个队伍一共有多少人.\n【详解】根据分析可得:4 + 4 + 1 = 9 (人),这个队伍一共有 9 人.故答案为: A", + "knowledge_points": [ + "连加,连减(10以内)" + ], + "source": "24-25 一年级上·四川广元·期末" + }, + { + "id": "227", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "欢欢和乐乐有同样多的饼干,欢欢吃了6块,乐乐吃了4块,()剩下的饼干多.", + "options": [ + "A. 欢欢", + "B. 乐乐", + "C. 同样多" + ], + "answer": "B", + "solution": "【分析】根据题意,欢欢和乐乐原有的饼干数量相同,要比较剩下的数量,则比较吃了的数量即可.吃了的数量多,剩下的数量少;吃了的数量少,剩下的数量多.7以内数从大到小关系为: 7 \u003e 6 \u003e 5 \u003e 4 \u003e 3 \u003e 2 \u003e 1 ,由此比较.\n【详解】 6 \u003e 4,欢欢吃了的饼干数量多,剩下的饼干数量少;乐乐吃了的饼干数量少,剩下的饼干数量多.故答案为: B", + "knowledge_points": [ + "7 以内数的比大小" + ], + "source": "24-25 一年级上·河南郑州·期末" + }, + { + "id": "228", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.65, + "question": "红绳子长 8 米, 蓝绳子长 9 米, 都剪去同样长的一段, 剩下的绳子 ( ).", + "options": [ + "A. 蓝绳子长", + "B. 红绳子长", + "C. 一样长" + ], + "answer": "A", + "solution": "【分析】根据两根绳子,都减去相同的一段,原来绳子长的,剩下的绳子长,据此解答即可.\n【详解】红绳子 8 米, 蓝绳子长 9 米, 都减去同样长的一段,原来蓝绳子比较长, 所以剩下的绳子, 蓝绳子长.故答案为:A", + "knowledge_points": [ + "10以内数的比大小" + ], + "source": "24-25 一年级上·湖北黄石·期末" + }, + { + "id": "229", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "下列各数中, 最大的一项是 ( ).", + "options": [ + "A. 2", + "B. 5", + "C. 4", + "D. 6" + ], + "answer": "D", + "solution": "【分析】1 到 7 从小到大的排序: 1\u003c2\u003c3\u003c4\u003c5\u003c6\u003c7 ,据此比较.\n【详解】 2 \u003c 4 \u003c 5 \u003c 6,故答案为: D", + "knowledge_points": [ + "7 以内数的比大小" + ], + "source": "24-25 一年级上·浙江温州·期末" + }, + { + "id": "230", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "在括号里填上合适的数.\n\n4 + ( ) = 7\n( ) - 3 = 3\n( ) + 2 \u003e 5\n7 - ( ) \u003c 4", + "options": [ + + ], + "answer": "3;6;4;4", + "solution": "【分析】根据加减法的关系,加数+加数 = 和,和-加数 = 加数,被减数-减数 = 差,差+减数 = 被减数,据此解答第一和第二小题.把大于号或小于号看作等号,根据加减法的关系,求出加数或减数,括号里需要填写的数要大于求出的这个加数或减数, 据此解答第三和第四小题.\n【详解】根据分析:7 - 4 = 3, 4 + (3) = 7 , 3 + 3 = 6, (6) - 3 = 3 ,(1) +2 = 5, 5 - 2 = 3, 3 + 1 = 4, (4) +2 \u003e 5 (答案不唯一) 7- ( ) =4, 7-4=3, 3+1=4, 7- (4) \u003c4 (答案不唯一)", + "knowledge_points": [ + "6 的加减法", + "7 的加减法" + ], + "source": "25-26 一年级上·全国·课后作业" + }, + { + "id": "231", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "8 名男生站成一排,相邻男生之间插入 1 名女生, 则女生有( )名.如果这 8 名男生围成一圈, 相邻男生之间插入 1 名女生, 则女生有( )名.", + "options": [ + + ], + "answer": "7;8", + "solution": "【分析】根据题意, 可以通过图示进行解答, 蓝色代表男生, 红色代表女生.8 名男生站成一排, 相邻男生之间插入1名女生,如图:\n![](images/d24fba59eee8f35b7416a53eef299e143a445cbec5ca79f1651ad9abe1d01cdf.jpg)\n女生有 7 名.如果这 8 名男生围成一圈, 相邻男生之间插入1名女生,如图:\n![](images/557a040c39716e71b4230456daf12c1e1cccadb76e58eedcdabc24e0a4d2a88f.jpg), 女生有 8 名,据此解答.\n【详解】根据分析:8名男生站成一排,相邻男生之间插入1名女生,则女生有(7) 名.如果这 8 名男生围成一圈, 相邻男生之间插入 1 名女生, 则女生有 (8) 名.", + "knowledge_points": [ + "8,9 的认识和读写", + "植树问题(两端都不栽)", + "封闭图形上的植树问题" + ], + "source": "25-26 一年级上·全国·课后作业" + }, + { + "id": "232", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "与 5 相邻的数是( )和( ),6 后面的第三个数是( ).", + "options": [ + + ], + "answer": "4;6;9", + "solution": "【分析】由题意可知:与 5 相邻的数是: 5 前面的一个数和它后面的一个数;接着 6 向后数 3 个数: 第一个数是 7, 第二个数是 8, 第三个数是 9;据此解答.\n【详解】由分析可得:与 5 相邻的数是 4 和 6, 6 后面的第三个数是 9.", + "knowledge_points": [ + "8,9 的认识和读写", + "认识几和第几", + "相邻的数", + "数一数" + ], + "source": "2025一年级上·全国·专题练习" + }, + { + "id": "233", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.65, + "question": "在括号里填上 \"\u003e\" \"\u003c\" 或 \"=\" .\n\n4 + 3 ( ) 8\n9 - 6 ( ) 4\n8 + 0 ( ) 10 - 0\n4 + 3 - 7 ( ) 5\n5 + 3 - 1 ( ) 7\n6 + 2 ( ) 8 - 2", + "options": [ + + ], + "answer": "\u003c;\u003c;\u003c;=;\u003e", + "solution": "【分析】先算出括号左右两边各个算式的结果,再比较数的大小;10以内数从小到大依次是: 0 \u003c 1 \u003c 2 \u003c 3 \u003c 4 \u003c 5 \u003c 6 \u003c 7 \u003c 8 \u003c 9 \u003c 10 .\n【详解】 4 + 3 = 7, 7 \u003c 8 ,所以 4 + 3 \u003c 8;9 - 6 = 3, 3 \u003c 4 ,所 以9 - 6 \u003c 4;8 + 0 = 8, 10 - 0 = 10, 8 \u003c 10 ,8 + 0 \u003c 10 - 0;4 + 3 - 7 = 7 - 7 = 0, 0 \u003c 5 , 所 以4 + 3 - 7 \u003c 5;5 + 3 - 1 = 8 - 1 = 7, 7 = 7, 所 以5 + 3 - 1 = 7;6 + 2 = 8, 8 - 2 = 6, 8 \u003e 6 ,所 以6 + 2 \u003e 8 - 2 .", + "knowledge_points": [ + "加减混合运算(10以内)", + "有关0的加减法", + "7的加减法", + "8,9的加减法" + ], + "source": "25-26 一年级上·全国·课后作业" + }, + { + "id": "234", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "在括号里填上合适的数.\n\n9 - ( ) = 4\n( ) + 4 = 8\n( ) + 5 = 7\n2 + ( ) = 6\n6 - ( ) = 2\n( ) + 2 = 5\n( ) + 3 = 4\n4 + 3 = ( )", + "options": [ + + ], + "answer": "5;4;2;4;4;3;1;7", + "solution": "【分析】 9 - () = 4 和 6 - () = 2 根据 \"减数 = 被减数-差\" 计算即可;4 + 3 = () 直接计算即可;其它的根据 \"一个加数 = 和 - 另一个加数\" 计算即可.\n【详解】 9 - 4 = 5 , 所以 9 - (5) = 4;8 - 4 = 4, 所 以(4) + 4 = 8;7 - 5 = 2, 所 以 (2) + 5 = 7;6 - 2 = 4, 所 以2 + (4) = 6;6 - 2 = 4, 所 以6 - (4) = 2;5 - 2 = 3 , 所 以 (3) + 2 = 5;4 - 3 = 1 , 所以 (1) +3 = 4;4 + 3 = (7) .", + "knowledge_points": [ + "6 的加减法", + "5 以内数的减法", + "7 的加减法", + "8,9 的加减法" + ], + "source": "25-26 一年级上·全国·课后作业" + }, + { + "id": "235", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.65, + "question": "在 ( ) 里填上合适的数.\n\n2 + ( ) = 66 - ( ) = 67 - ( ) = 4 ( ) - 2 = 5", + "options": [ + + ], + "answer": "4;0;3;7", + "solution": "【分析】根据被减数-减数 = 差,被减数-差 = 减数,差 + 减数 = 被减数, 算出括号里应该填的数即可解答.\n【详解】 6 - 2 = 4 ,所以 2 + 4 = 6 ,则括号内填4;6 - 6 = 0 , 所以 6 - 0 = 6 , 则括号内填 0;7 - 4 = 3 , 所以 7 - 3 = 4 , 则括号内填 3;5 + 2 = 7 , 所以 7 - 2 = 5 , 则括号内填 7 .", + "knowledge_points": [ + "6 的加减法", + "7 的加减法" + ], + "source": "25-26 一年级上·全国·课后作业" + }, + { + "id": "236", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "想一想, 填一填.\n\n![](images/5ce8a9016b82fca7a368c5db6d084375e4ef30f9cf7cde92580a3cbef2d6b112.jpg)\n\n( ) + ( ) = ( )\n( )-( )=( )", + "options": [ + + ], + "answer": "2;3;5;5;3;2", + "solution": "【分析】由题意可知: 左边有 2 个球, 右边有 3 个球, 左边球的个数加右边的个数, 即是球一共的个数;用一共的个数减去一边的个数, 即是另一边的个数;据此列算式.\n【详解】由分析可得:2 + 3 = 5 (算式不唯一),5 - 3 = 2 (算式不唯一)", + "knowledge_points": [ + "图文问题", + "7的加减法" + ], + "source": "25-26 一年级上·全国·课后作业" + }, + { + "id": "237", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "在括号里填上合适的数.\n\n3 + ( ) = 9\n( ) - 2 = 6\n( ) + 4 = 10\n9 - ( ) = 2\n5 + ( ) = 10\n( ) - 1 = 7", + "options": [ + + ], + "answer": "6;8;6;7;5;8", + "solution": "【分析】根据数的组成,依次填空即可.\n【详解】9 可以分成 3 和 6, 所以 3 + (6) = 9;8 可以分成 2 和 6, 所以 (8) -2 = 6;10 可以分成 4 和 6, 所以 (6) +4 = 10;9 可以分成 2 和 7, 所以 9 - (7) = 2;10 可以分成 5 和 5 , 所以 5 + (5) = 10;8 可以分成 1 和 7, 所以 (8) -1 = 7 .", + "knowledge_points": [ + "10 的加减法", + "8,9 的加减法" + ], + "source": "25-26 一年级上·全国·课后作业" + }, + { + "id": "238", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "看图填一填.\n\n![](images/b92b2d8542a6e449a33ff087c0cd8ea59f5d810010a8362ed054bf5259bb2155.jpg)", + "options": [ + + ], + "answer": "1;5;5;1", + "solution": "【分析】由图可知, 一共有 6 个 △ , 分成了两部分, 一部分是 1 个, 另一部分是 5 个, 也就是 6 可以分成 1 和 5, 6 可以分成 5 和 1.\n【详解】由分析填写如下:![](images/190955.png)", + "knowledge_points": [ + "6,7 的分与合(组成)" + ], + "source": "25-26 一年级上·全国·课后作业" + }, + { + "id": "239", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "看图填一填.\n\n![](images/191555.png)", + "options": [ + + ], + "answer": "见详解", + "solution": "【分析】根据题意可知, 共有 7 个圆圈, 左边有 2 个, 右边有 5 个, 即 7 可以分成 2 和 5, 7 也可以分成 5 和 2 , 据此解答.\n【详解】填写如下:\n\n![](images/1ade9f54d751fa1c05cf435d8390017f9a8605d82725f2a7adc8bd4e9a08de8a.jpg)", + "knowledge_points": [ + "6,7 的分与合(组成)" + ], + "source": "25-26 一年级上·全国·课后作业" + }, + { + "id": "240", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "在括号里填入合适的数.\n\n( ) + 2 = 9\n( ) + 6 = 10\n( ) - 4 = 3\n10 - 8 = ( ) + 2\n3 + ( ) = 9\n( ) + 1 = 8", + "options": [ + + ], + "answer": "7;4;7;0;6;7", + "solution": "【分析】由题意可知: 根据数的组成, 即可算出所填的数;据此解答.\n【详解】由分析可得:( ) + 2 = 9: 7 和 2 组成 9 , 故 7 + 2 = 9;( ) + 6 = 10: 4 和 6 组成 10 , 故 4 + 6 = 10;( ) - 4 = 3: 7 能分成 4 和 3, 故 7 - 4 = 3;10 - 8 = ( ) + 2: 10 能分成 8 和 2, 10 - 8 = 2, 0 和 2 组成 2, 故 10 - 8 = 0 + 2;3 + ( ) = 9: 3 和 6 组成 9, 故 3 + 6 = 9;( ) + 1 = 8: 7 和 1 组成 8, 故 7 + 1 = 8.", + "knowledge_points": [ + "有关 0 的加减法", + "7 的加减法", + "10 的加减法", + "8,9 的加减法" + ], + "source": "25-26 一年级上·全国·课后作业" + }, + { + "id": "241", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "在括号里填上\"\u003e\",\"\u003c\"或\"=\".\n\n3 ( ) 6\n3 ( ) 3\n7 ( ) 1\n4 ( ) 6\n6 ( ) 4\n0 ( ) 1\n5 ( ) 4\n2 ( ) 0", + "options": [ + + ], + "answer": "\u003c;=;\u003e;\u003c;\u003e;\u003c;\u003e;\u003e", + "solution": "【分析】由题意可知: 7 以内数的大小关系为: 7 \u003e 6 \u003e 5 \u003e 4 \u003e 3 \u003e 2 \u003e 1 \u003e 0;据此可比较大小.\n【详解】由分析可得:3 \u003c 6;3 = 3;7 \u003e 1;4 \u003c 6;6 \u003e 4;0 \u003c 1;5 \u003e 4;2 \u003e 0", + "knowledge_points": [ + "7以内数的比大小" + ], + "source": "25-26一年级上·全国·课后作业" + }, + { + "id": "242", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.65, + "question": "在同一个算式的 ( )里填上相同的数.\n4 + ( ) = 10 - ( ) 9 - ( ) = 1 + ( )", + "options": [ + + ], + "answer": "3;3;4;4", + "solution": "【分析】根据 10 以内整数的加减法进行计算, 只要等号两边的算式得数和括号内填的数都一样即可.\n【详解】4+3=7,10-3=7,所以4+3=10-3,括号内都填3.9-4=5,1+4=5,所以9-4=1+4,括号内都填4.", + "knowledge_points": [ + "5以内数的加法", + "7的加减法", + "10的加减法", + "8,9 的加减法" + ], + "source": "25-26 一年级上·全国·课后作业" + }, + { + "id": "243", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.65, + "question": "从前往后数, 小红排在第 5 位, 从后往前数, 小红排在第 2 位, 请问这一排一共有( )位小朋友.", + "options": [ + + ], + "answer": "6", + "solution": "【分析】从前往后数,小红排在第 5 位,说明到小红这里有 5 个人,从后往前数,小红排在第 2 位,说明小红的后面只有 1 位小朋友,据此根据加法的意义,用 5 + 1 进行解答即可.\n【详解】根据分析可知: 5 + 1 = 6 (位),所以这一排一共有 6 位小朋友.", + "knowledge_points": [ + "6 的加减法", + "认识几和第几" + ], + "source": "25-26 一年级上·全国·课后作业" + }, + { + "id": "244", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.65, + "question": "在()里填上\"+\"或\"-\".\n\n10 ( ) 4 ( ) 3 = 3\n8 ( ) 1 ( ) 3 = 10\n1 ( ) 2 ( ) 4 = 7\n3 ( ) 5 ( ) 2 = 6", + "options": [ + + ], + "answer": "-;-;-;+;+;+;+;-", + "solution": "【分析】根据 10 以内加减法的计算法则选择合适的运算符号即可,要想使两个数的计算结果变大,就让这两个数相加;要想使两个数的计算结果变小,就让这两个数相减.\n【详解】由分析得:10 - 4 - 3 = 3;8 - 1 + 3 = 10;1 + 2 + 4 = 7;3 + 5 - 2 = 6", + "knowledge_points": [ + "加减混合运算(10以内)", + "连加,连减(10以内)" + ], + "source": "25-26 一年级上·全国·课后作业" + }, + { + "id": "245", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.65, + "question": "交换数字卡片( )和( )的位置,两边卡片上的数字相加的得数就相等了.\n\n![](images/193850.png)", + "options": [ + + ], + "answer": "5;6", + "solution": "【分析】由题意可知:左边数字卡片上的数相加等于8,右边的相加等于 10 , 右边比左边大 2, 2 的一半是 1 , 找出右边比左边大 1 的数, 交换即可.据此解答.\n【详解】左边数字 6 比数字 5 大 1 , 交换数字卡片 5 和 6;左边三个数相加 2 + 6 + 1 = 9;右边三个数相加 5 + 0 + 4 = 9;得数相等.交换数字卡片 5 和 6 的位置, 两边卡片上的数字相加的得数就相等了.", + "knowledge_points": [ + "9 以内数的比大小", + "连加,连减(10 以内)" + ], + "source": "25-26 一年级上·全国·课后作业" + }, + { + "id": "246", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "在()里填上\"\u003e\",\"\u003c\"或\"=\".\n\n2 + 3 + 2 ( ) 7\n1 + 6 - 4 ( ) 4\n9 - 7 + 5 ( ) 5\n4 + 6 - 2 ( ) 10\n5 + 4 - 3 ( ) 3\n6 + 4 - 3 ( ) 7", + "options": [ + + ], + "answer": "=;\u003c;\u003e;\u003c;\u003e;=", + "solution": "【分析】根据题意,依次计算出各算式的结果再比较大小,只有加减法的混合运算,从左往右计算.10以内数从大到小关系为: 10 \u003e 9 \u003e 8 \u003e 7 \u003e 6 \u003e 5 \u003e 4 \u003e 3 \u003e 2 \u003e 1 \u003e 0 ,由此比较.\n【详解】 2 + 3 + 2 = 71 + 6 - 4 = 3;3 \u003c 4 , 则 1 + 6 - 4 \u003c 4;9 - 7 + 5 = 7;7 \u003e 5 , 则 9 - 7 + 5 \u003e 5;4 + 6 - 2 = 8;8\u003c 10 , 则 4 + 6 - 2 \u003c 10;5 + 4 - 3 = 6;6 \u003e 3 , 则 5 + 4 - 3 \u003e 3;6 + 4 - 3 = 7 .", + "knowledge_points": [ + "加减混合运算(10以内)", + "10以内数的比大小" + ], + "source": "25-26一年级上·全国·课后作业" + }, + { + "id": "247", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "在 ( ) 里填上合适的数.\n\n( ) + 5 = 9\n10 - ( ) = 6\n3 + ( ) = 7\n( ) - 2 = 7\n8 + ( ) = 10\n9 - ( ) = 6", + "options": [ + + ], + "answer": "4;4;4;9;2;3", + "solution": "【分析】根据 9 可以分成 4 和 5 , 得出 4 + 5 = 9;同理计算第 3,第 5 小题.想 (4) +6 = 10 , 所以 10 - 4 = 6;同理计算第 4,第 6 小题.\n【详解】9 可以分成 4 和 5,所以 4 + 5 = 9;想 (4) +6 = 10 , 所以 10 - 4 = 6;7 可以分成 3 和 4 , 所以 3 + 4 = 7;想 (2) +7 = 9 , 所以 9 - 2 = 7;10 可以分成 8 和 2, 所以 8 + 2 = 10;想 (3) +6 = 9 , 所以 9 - 3 = 6 .", + "knowledge_points": [ + "7 的加减法", + "10 的加减法", + "8,9 的加减法" + ], + "source": "25-26 一年级上·全国·课后作业" + }, + { + "id": "248", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "从0数到10,一共数了( )个数.", + "options": [ + + ], + "answer": "11", + "solution": "【分析】10以内数的排序:0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 数一数一共多少个.\n【详解】从 0 数到 10, 一共数了 11 个数.", + "knowledge_points": [ + "10以内数的排序" + ], + "source": "24-25一年级下·新疆喀什·开学考试" + }, + { + "id": "249", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "原定周二比赛, 推迟 2 天举行, 比赛将在周( )举行.", + "options": [ + + ], + "answer": "四", + "solution": "【分析】每周都有 7 天,按照周一,周二,周三,周四,周五,周六,周日的顺序排列,也就是按照1, 2, 3, 4, 5, 6, 7 的顺序排列, 由此数出 2 后边的第二个数是几, 就是周几举行比赛.\n【详解】2后边第一个数是3,第二个数是4.则原定周二比赛,推迟2天举行,比赛将在周四举行.", + "knowledge_points": [ + "10以内数的排序" + ], + "source": "24-25 一年级上·湖南益阳·期末" + }, + { + "id": "250", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.65, + "question": "小朋友们排队参加跳绳比赛, 小乐排第 2 , 小宇排第 8 , 小乐和小宇之间有( )个小朋友.", + "options": [ + + ], + "answer": "5", + "solution": "【分析】根据题意可知, 小宇的排名减去小乐的排名, 再减去 1 , 即可求出他们之间有多少个小朋友, 据此解答.\n【详解】根据分析可得:8 - 2 - 1 = 5 (个),小朋友们排队参加跳绳比赛, 小乐排第 2 , 小宇排第 8 , 小乐和小宇之间有 5 个小朋友.", + "knowledge_points": [ + "连加,连减(10以内)" + ], + "source": "24-25 一年级上·山东济南·期末" + }, + { + "id": "251", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "要使 10 \u003e 5+□ , □ 里最大填( ).", + "options": [ + + ], + "answer": "4", + "solution": "【分析】根据题意,先计算出等于 10 时,填写的数是多少,要想 10 大于右边的算式,则口里最大能填写的数是比求出的结果小 1 的数,用减法计算.\n【详解】 10 = 5+ ( ),即 10 - 5 = 5 .要使 10 \u003e 5 + □ ,则 5 - 1 = 4 ,□ 里最大填 4 .", + "knowledge_points": [ + "10以内数的比大小", + "5以内数的减法", + "10的加减法" + ], + "source": "24-25 一年级上·河南商丘·期末" + }, + { + "id": "252", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "10 个苹果分装在两个盘子里, 这两个盘子里可能有( )个和( )个.", + "options": [ + + ], + "answer": "5;5", + "solution": "【分析】根据 10 得分合即可解答.10 可以分成 5 和 5, 4 和 6, 3 和 7, 2 和 8, 1 和 9, 任意选一组数填写即可.\n【详解】10 个苹果分装在两个盘子里, 这两个盘子里可能有 (5) 个和 (5) 个.(答案不唯一)", + "knowledge_points": [ + "10 的分与合 (组成)" + ], + "source": "24-25 一年级上·福建龙岩·期末" + }, + { + "id": "253", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "从星期三到星期六,一共放了( )天假.", + "options": [ + + ], + "answer": "4", + "solution": "【分析】每周都有 7 天,按照星期一,星期二,星期三,星期四,星期五,星期六,星期日依次排列,也就是按照1, 2, 3, 4, 5, 6, 7 的顺序排列,从星期三到星期六,也就是从 3 数到 6,有几个数就是几天.\n【详解】由分析得:从 3 数到 6 , 依次为 3, 4, 5, 6 , 共 4 个数, 则从星期三到星期六, 一共放了 4 天假.", + "knowledge_points": [ + "10以内数的排序" + ], + "source": "24-25 一年级上·广东潮州·期末" + }, + { + "id": "254", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "小朋友排队, 从前往后数, 小明是第 5 , 从后往前数, 小明是第 4 , 这队一共有( )人.", + "options": [ + + ], + "answer": "8", + "solution": "【分析】用5加4,小明被加了两次,再减去1即可求解.\n【详解】 5 + 4 - 1 = 8 (人),这队一共有 8 人.", + "knowledge_points": [ + "加减混合运算 (10 以内)" + ], + "source": "24-25 一年级上·山东临沂·期末" + }, + { + "id": "255", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "小明和小华读同一本故事书, 小明读了 8 页, 小华读了 9 页, ( )剩下的多.", + "options": [ + + ], + "answer": "小明", + "solution": "【分析】根据题意,他们看的书相同,也就是总页数相同,要比较剩下页数的多少,则比较读了的页数即可,读了的页数多,剩下的页数少,读了的页数少,剩下的页数多.10 以内数从大到小关系为 10 \u003e 9 \u003e 8 \u003e 7 \u003e 6 \u003e 5 \u003e 4 \u003e 3 \u003e 2 \u003e 1\u003e0 , 由此比较.\n【详解】 9 \u003e 8,小华读的页数多,小明读的页数少.则小华剩下的少,小明剩下的多.", + "knowledge_points": [ + "10以内数的比大小" + ], + "source": "24-25 一年级下·江西吉安·阶段练习" + }, + { + "id": "256", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "笑笑喜欢包饺子,笑笑和妈妈共包了9个饺子,笑笑包了4个,妈妈包了( )个饺子.", + "options": [ + + ], + "answer": "5", + "solution": "【分析】用笑笑和妈妈共包的饺子数量减去笑笑包的数量,求出差, 就是妈妈包了多少个饺子.\n【详解】 9 - 4 = 5 (个),即,妈妈包了 5 个饺子.", + "knowledge_points": [ + "8,9 的加减法" + ], + "source": "24-25 一年级上·河南商丘·期末" + }, + { + "id": "257", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "4 + 5 = 3+ ( ) = ( ) + 7 = 8 + ( ) = 5 + ( ).", + "options": [ + + ], + "answer": "6;2;1;4", + "solution": "【分析】先算出 4 + 5 的结果, 然后用 \"和-一个加数 = 另一个加数\" 求出其它算式的结果, 据此解答.\n【详解】根据分析可得:4 + 5 = 9, 9 - 3 = 6, 9 - 7 = 2, 9 - 8 = 1, 9 - 5 = 4;故: 4 + 5 = 3 + 6 = 2 + 7 = 8 + 1 = 5 + 4", + "knowledge_points": [ + "6的加减法", + "7的加减法", + "8,9的加减法" + ], + "source": "24-25 一年级上·河南商丘·期末" + }, + { + "id": "258", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "今天是文文7岁生日,妈妈已经帮他插了2根蜡烛,还要再插( )根蜡烛.", + "options": [ + + ], + "answer": "5", + "solution": "【分析】根据题意,文文7岁生日,也就是需要插7根蜡烛,则用需要插蜡烛的总数量-已经插了的数量 = 还要再插的数量.\n【详解】 7 - 2 = 5 (根),今天是文文 7 岁生日, 妈妈已经帮他插了 2 根蜡烛, 还要再插 5 根蜡烛.", + "knowledge_points": [ + "7 的加减法" + ], + "source": "24-25一年级下·新疆喀什·开学考试" + }, + { + "id": "259", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "有 10 个同学排队,小明前面有 5 人, 后面有( )人.", + "options": [ + + ], + "answer": "4", + "solution": "【分析】根据减法的意义,排队的总人数-小明前面的人数-小明自己=小明后面的人数.\n【详解】 10 - 5 - 1 = 4 (人),有 10 个同学排队, 小明前面有 5 人, 后面有 4 人.", + "knowledge_points": [ + "连加,连减(10以内)" + ], + "source": "24-25 一年级上·湖南湘西·期末" + }, + { + "id": "260", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "10 个小朋友排队做操,小明前面有4个小朋友,小明后面有( )个小朋友.", + "options": [ + + ], + "answer": "5", + "solution": "【分析】根据题意可知:用共有的小朋友人数减去小明前面的人数,再减去小明自己即可求出小明后面有的小朋友数量.\n【详解】 10 - 4 - 1 = 5 (个),则小明后面有 5 个小朋友.", + "knowledge_points": [ + "连加,连减(10以内)" + ], + "source": "24-25 一年级上·河南新乡·期末" + }, + { + "id": "261", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.65, + "question": "2025 年腊月二十三是星期三, 再过 3 天就是彩娃的生日, 彩娃的生日是星期( ).", + "options": [ + + ], + "answer": "六", + "solution": "【分析】根据题意,用星期数加天数即可求出彩娃的生日是星期几.\n【详解】 3 + 3 = 6,2025年腊月二十三是星期三,再过3天就是彩娃的生日,彩娃的生日是星期六.", + "knowledge_points": [ + "6 的加减法" + ], + "source": "24-25 一年级上·河南南阳·期末" + }, + { + "id": "262", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.65, + "question": "一九一九好朋友,四六四六一起走, 你来猜猜我是谁, 五五凑成一双手.( )(请把你想到的数字填在括号里)", + "options": [ + + ], + "answer": "10", + "solution": "【分析】根据题意, 每句儿歌中都隐含了数字组合相加的结果:一九好朋友: 1 + 9 = 10;四六一起走: 4 + 6 = 10;五五凑成一双手: 5 + 5 = 10 (一双手有10根手指)\n【详解】根据分析可得:这个数字是:10", + "knowledge_points": [ + "10 的分与合(组成)", + "10 的加减法" + ], + "source": "24-25 一年级上·河南三门峡·期末" + }, + { + "id": "263", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.65, + "question": "小华看一本故事书,第一天看了 3 页, 第二天看了 6 页, 第三天要从第( )页看起.", + "options": [ + + ], + "answer": "10", + "solution": "【分析】先算出前两天一共看了多少页,第三天要从前两天看的总页数的下一页看起,即用前两天看的总页数 +1 ,即为第三天要从第几页看起.\n【详解】 3 + 6 + 1= 9 + 1= 10 (页),第三天要从第 10 页看起.", + "knowledge_points": [ + "连加,连减(10以内)" + ], + "source": "24-25 一年级上·河南商丘·期末" + }, + { + "id": "264", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "判断题", + "difficulty": 0.85, + "question": "把 10 只![](images/e341be9d58d51dd8dddf67a1b0c80eb80ebe33359be59ae4bb75aff0508ed861.jpg)关进2个笼子里,每个笼子能关进同样多的![](images/1316f156647cc882a0545d44afd9751275a90cb3f9ed3aa4c33b621e93b3e008.jpg)吗?在正确答案后面画\"√\".(能□,不能□)", + "options": [ + + ], + "answer": "√", + "solution": "【分析】根据题意, 一共有 10 只兔子, 有 2 个笼子, 把 10 只兔子分成相同多的两部分, 装入笼子, 10 可以分成 5 和 5 , 每个笼子可装 5 只兔子.\n【详解】10 可以分成 5 和 5;把 10 只![](images/99544f03ee29b8e16cddc01489dd47592931c23fee4ac6d5b6b05c877128a850.jpg)关进 2 个笼子里,每个笼子能关进同样多的![](images/efc6083465dfad7669e8bec06e3dc96fee2c7904beab362c2d8b24cca1af3209.jpg)吗?在正确答案后面画\"√\".(能 √,不能).故答案为: √", + "knowledge_points": [ + "10 的分与合 (组成)" + ], + "source": "24-25 一年级上·广东东莞·期中" + }, + { + "id": "265", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.65, + "question": "比大小.\n\n10 - 2 - 6 ( ) 8 + 2 - 5\n7 + 2 + 1 ( ) 8 - 4 + 3", + "options": [ + + ], + "answer": "\u003c;\u003e", + "solution": "【分析】计算出各算式的答案,然后再进行比较大小;连减,连加或加减混合的算式,从左往右计算即可;10以内数的大小关系: 0 \u003c 1 \u003c 2 \u003c 3 \u003c 4 \u003c 5 \u003c 6 \u003c 7 \u003c 8 \u003c 9 \u003c 10 , 10 \u003e 9 \u003e 8 \u003e 7 \u003e 6 \u003e 5 \u003e 4 \u003e 3 \u003e 2 \u003e 1 \u003e 0;据此解答.\n【详解】根据分析:10 - 2 - 6 = 2, 8 + 2 - 5 = 5, 2 \u003c 5, 则10 - 2 - 6 \u003c 8 + 2 -5;7 + 2 + 1 = 10, 8 - 4 + 3 = 7, 10 \u003e 7, 则7 + 2 + 1 \u003e 8 - 4 +3.", + "knowledge_points": [ + "加减混合运算(10以内)", + "10以内数的比大小", + "连加,连减(10以内)" + ], + "source": "24-25 一年级下·广东梅州·开学考试" + }, + { + "id": "266", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "填一填.\n\n( ) + 2 = 8\n6 - ( ) = 6\n( ) - 4 = 4", + "options": [ + + ], + "answer": "6;0;8", + "solution": "【分析】根据加数 = 和 - 另一加数, 减数 = 被减数-差,被减数 = 差 + 减数即可解答.\n【详解】 8 - 2 = 6 , 则 6 + 2 = 8;6 - 6 = 0 , 则 6 - 0 = 6;4 + 4 = 8 , 则 8 - 4 = 4 .", + "knowledge_points": [ + "6 的加减法", + "8,9 的加减法" + ], + "source": "24-25一年级下·广东梅州·开学考试" + }, + { + "id": "267", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "10 个小朋友排成一列做操, 从前往后数, 小海是第 5 个;从后往前数, 小海是第( )个.", + "options": [ + + ], + "answer": "6", + "solution": "【分析】已知小朋友有 10 个排成一列, 可以画 10 个圈代表小朋友, 从前往后数到第五个标记小海的位置, 在从后往前数一数即可得出小海是第几个.\n【详解】![](images/18467fbc2a3ebabfe2762b5a541673275e76f888d906aa8c8b4412ea84d4f924.jpg)\n10 个小朋友排成一列做操,从前往后数,小海是第 5 个;从后往前数,小海是第 6 个.", + "knowledge_points": [ + "10以内数的排序" + ], + "source": "24-25 一年级上·贵州铜仁·期末" + }, + { + "id": "268", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.65, + "question": "折扇是南京著名的传统手工艺制品之一,爸爸出差回来给小梦带了一把金陵折扇,扇面上有9个民间故事,相邻两个故事之间有一幅插画,这把折扇上一共有( )幅插画.", + "options": [ + + ], + "answer": "8", + "solution": "【分析】根据题意,故事的数量比插画的数量多1,用故事的数量减 1 即可求出插画的数量.\n【详解】 9 - 1 = 8 (幅),这把折扇上一共有 8 幅插画.", + "knowledge_points": [ + "8,9 的加减法" + ], + "source": "24-25一年级下·全国·单元测试" + }, + { + "id": "269", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "在横线内填入\"\u003e\" \"\u003c\"或\"=\".\n\n6 ( ) 9\n9 - 3 ( ) 2 + 7\n2 + 7 ( ) 3 + 5", + "options": [ + + ], + "answer": "=;\u003e", + "solution": "【分析】根据整数加减法的计算法则计算出算式的结果, 再比较大小即可.9 以内数从大到小关系为: 9 \u003e 8 \u003e 7 \u003e 6\u003e 5 \u003e 4 \u003e 3 \u003e 2 \u003e 1 , 由此比较.\n【详解】 6 = 9 - 3;2 + 7 = 9;3 + 5 = 8;9 \u003e 8, 则2 + 7 \u003e 3 + 5 .", + "knowledge_points": [ + "9 以内数的比大小", + "8,9 的加减法" + ], + "source": "24-25 一年级上·浙江温州·期末" + }, + { + "id": "270", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "9 可以分成 5 和( ), ( )和 3 合起来是 10.", + "options": [ + + ], + "answer": "4;7", + "solution": "【分析】9 可以分成 0 和 9,1 和 8,2 和 7,3 和 6,4 和 5;0 和 10,1 和 9,2 和 8,3 和 7,4 和 6,5 和 5 合起来是 10,据此填空.\n【详解】9 可以分成 5 和 4, 7 和 3 合起来是 10 .", + "knowledge_points": [ + "10 的分与合(组成)", + "8,9 的分与合(组成)" + ], + "source": "25-26 一年级上·江西九江·期中" + }, + { + "id": "271", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.65, + "question": "小明今年 6 岁, 小强今年 4 岁.当 5 年后, 小明比小强大( )岁.", + "options": [ + + ], + "answer": "2", + "solution": "【分析】依据题意可知, 用减法列式计算出, 今年小明比小强大多少岁, 两人的年龄差不随着时间的变化而变化,由此解答本题.\n【详解】根据分析可得:6 - 4 = 2 (岁),当5年后,小明比小强大2岁.", + "knowledge_points": [ + "6 的加减法" + ], + "source": "25-26 一年级上·江西九江·期中" + }, + { + "id": "272", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "在括号里填上\"+\"或\"-\".\n\n2 ( ) 2 = 4\n3 ( ) 2 = 1\n4 ( ) 1 = 3\n5 ( ) 4 = 1\n6 ( ) 2 = 4\n7 ( ) 1 = 6", + "options": [ + + ], + "answer": "+;-;-;-;-;-", + "solution": "【分析】根据整数加减法的计算法则及数的分与合进行解答.加法运算会让得数变多或不变,减法运算会让得数变少或不变.2 和 2 合起来就是 4 , 即 2 + 2 = 4;3 可以分成 2 和 1, 即 3 - 2 = 1;4 可以分成 1 和 3 , 即 4 - 1 = 3;5 可以分成 4 和 1 , 即 5 - 4 = 1;6 可以分成 2 和 4 , 即 6 - 2 = 4;7 可以分成 1 和 6 , 即 7 - 1 = 6 .\n【详解】 2 + 2 = 4;3 - 2 = 1;4 - 1 = 3;5 - 4 = 1;6 - 2 = 4;7 - 1 = 6", + "knowledge_points": [ + "6 的加减法", + "5 以内数的加法", + "5 以内数的减法", + "7 的加减法" + ], + "source": "25-26 一年级上·江西九江·期中" + }, + { + "id": "273", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "在 ( ) 里填上合适的数.\n\n( ) + 3 = 5\n2 + ( ) = 9\n10 - ( ) = 4\n2 + ( ) \u003e 7", + "options": [ + + ], + "answer": "2;7;6;6", + "solution": "【分析】第 1, 2 题根据和-一个加数 = 另一个加数计算;第 3 题根据被减数 - 差 = 减数计算;,比7大的数有8, 9, 10... 可使结果为 8 , 根据第4题左侧算式的结果大于7即可和-一个加数 = 另一个加数计算.\n【详解】 5 - 3 = 2 ,则 2 + 3 = 5;9 - 2 = 7 , 则 2 + 7 = 9;10 - 4 = 6 , 则 10 - 6 = 4;2+ () =8, 8-2=6, 则 2 + 6 \u003e 7 . (答案不唯一)", + "knowledge_points": [ + "10以内数的比大小", + "5以内数的减法", + "10的加减法", + "8,9的加减法" + ], + "source": "25-26 一年级上·江西九江·期中" + }, + { + "id": "274", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "判断题", + "difficulty": 0.85, + "question": "\"9 个\" 和 \"第 9 个\"的意义完全相同.( )", + "options": [ + + ], + "answer": "×", + "solution": "【分析】第几只有 1 个,几个可以表示 1 个或者多个.\n【详解】\"9个\"和\"第9个\"的意义不相同.原题说法错误.故答案为: ×", + "knowledge_points": [ + "认识几和第几" + ], + "source": "25-26 一年级上·江西九江·期中" + }, + { + "id": "275", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "判断题", + "difficulty": 0.85, + "question": "丽丽读书, 从第 2 页读到第 8 页, 她一共读了 7 页.( )", + "options": [ + + ], + "answer": "√", + "solution": "【分析】根据题意, 从 2 数到 8 (包括 2 和 8), 数了几个数, 就是读了几页.\n【详解】从 2 数到 8 , 依次为 2, 3, 4, 5, 6, 7, 8, 数了 7 个数.丽丽读书, 从第 2 页读到第 8 页, 她一共读了 7 页.原题说法正确.故答案为:√", + "knowledge_points": [ + "10以内数的排序" + ], + "source": "25-26 一年级上·江西九江·期中" + }, + { + "id": "276", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "判断题", + "difficulty": 0.85, + "question": "比 5 大比 8 小的数只有 7.( )", + "options": [ + + ], + "answer": "×", + "solution": "【分析】10 以内数的大小关系为: 0 \u003c 1 \u003c 2 \u003c 3 \u003c 4 \u003c 5 \u003c 6\u003c 7 \u003c 8 \u003c 9 \u003c 10 .\n【详解】比 5 大比 8 小的数有 6,7.原题说法错误.故答案为: ×", + "knowledge_points": [ + "9 以内数的比大小" + ], + "source": "25-26 一年级上·江西九江·期中" + }, + { + "id": "277", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "判断题", + "difficulty": 0.85, + "question": "比 5 大 3 的数是 2.", + "options": [ + + ], + "answer": "×", + "solution": "【分析】求比一个数大几的数是多少,用这个数加大的数计算.\n【详解】 5 + 3 = 8,比 5 大 3 的数是 8 , 原题说法错误.故答案为: ×", + "knowledge_points": [ + "8,9 的加减法" + ], + "source": "25-26 一年级上·江西九江·期中" + }, + { + "id": "278", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "计算题", + "difficulty": 0.85, + "question": "计算.\n6 + 3 - 4 = ( ) 8 + 2 - 5 = ( ) 3 + 3 + 3 = ( )\n8 - 6 - 2 = ( ) 10 - 6 + 5 = ( ) 9 - 2 - 2 = ( )", + "options": [ + + ], + "answer": "5;5;9;0;9;5", + "solution": "[解析]6 + 3 - 4 = 9 - 4 = 5;8 + 2 - 5 = 10 - 5 = 5;3 + 3 + 3 = 6 + 3 = 9;8 - 6 - 2 = 2 - 2 = 0;10 - 6 + 5 = 4 + 5 = 9;9 - 2 - 2 = 7 - 2 = 5.", + "knowledge_points": [ + "加减混合运算(10以内)", + "连加,连减(10以内)", + "10的加减法", + "8,9的加减法" + ], + "source": "25-26 一年级上·江西九江·期中" + }, + { + "id": "279", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式计算.\n![](images/78b6edf3529f825a5e0a182f4b998afd4f252de95edb8caacd806fae226dadc1.jpg)\n□ ○ □ = □(个)", + "options": [ + + ], + "answer": "5 + 4 = 9 (个)", + "solution": "【分析】一共的西瓜数量 = 左边的数量 + 右边的数量;据此列式解决.\n【详解】 5 + 4 = 9 (个),一共有 9 个西瓜.", + "knowledge_points": [ + "图文问题", + "10 的加减法" + ], + "source": "25-26 一年级上·江西九江·期中" + }, + { + "id": "280", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式计算.\n![](images/66e409054643368d1cf1df8389d3e52e90125f0fbd012f065e87a8cfc1c4f79c.jpg)\n□ ○ □ = □(只)", + "options": [ + + ], + "answer": "4 + 3 = 7 (只)", + "solution": "【分析】一共的兔子数量 = 左边的数量 + 右边的数量;据此列式解决.\n【详解】 4 + 3 = 7 (只),一共有 7 只兔子.", + "knowledge_points": [ + "图文问题", + "7 的加减法" + ], + "source": "25-26 一年级上·江西九江·期中" + }, + { + "id": "281", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图写算式.\n![](images/d3d02a72d7119fc7dc754aa320ff617746e2baeda21d7a99084e031725191474.jpg)\n□ ○ □ = □(条)", + "options": [ + + ], + "answer": "9 - 5 = 4 (条)", + "solution": "【分析】一共有 9 条小鱼, 左边有 5 条, 求右边鱼缸里有几条, 用减法计算, 即总数量-左边的数量 = 右边的数量.\n【详解】 9 - 5 = 4 (条),右边鱼缸里有 4 条.", + "knowledge_points": [ + "图文问题", + "8,9 的加减法" + ], + "source": "25-26 一年级上·江西九江·期中" + }, + { + "id": "282", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式计算.\n![](images/c12d47ac788495dbecbb084e0de5d47596e01f1e80b6cfe35d9d286913b7dd54.jpg)\n□ ○ □ = □(只)", + "options": [ + + ], + "answer": "3 + 2 + 1 = 6 (只)", + "solution": "【分析】从图上可得:左边有3只小鸡,中间有2只小鸡,右边有 1 只小鸡, 要求一共有多少只小鸡, 根据加法的意义,用 3 + 2 + 1 进行解答即可.\n【详解】 3 + 2 + 1 = 5 + 1 = 6 (只),所以现在一共有 6 只小鸡.", + "knowledge_points": [ + "连加,连减(10以内)", + "图文问题" + ], + "source": "25-26 一年级上·江西九江·期中" + }, + { + "id": "283", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式计算.\n![](images/a2b69e2737987fd84223cbedacdeb13880985aad7d60c558ee4a9d859013195f.jpg)\n□ ○ □ = □(个)", + "options": [ + + ], + "answer": "9 - 3 = 6 (个)", + "solution": "【分析】从图上可得: 一共有 9 个星星, 划去 3 个表示星星数量减少 3 个, 求现在有多少个星星, 用减法计算.\n【详解】 9 - 3 = 6 (个),所以现在有 6 个星星.", + "knowledge_points": [ + "加减混合运算(10以内)", + "图文问题" + ], + "source": "25-26 一年级上·江西九江·期中" + }, + { + "id": "284", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式.\n![](images/ab2bfa06a9e63b3998df96557069141b2d084394deb900d259d5f1e4f45185fd.jpg)\n□ ○ □ = □(个)", + "options": [ + + ], + "answer": "4 + 6 = 10 (个)", + "solution": "【分析】左边有 4 个![](images/202740.png) , 右边有 6 个 ![](images/202740.png) , 求一共有多少个, 用加法计算, 即左边的数量 + 右边的数量 = 总数量.\n【详解】 4 + 6 = 10 (个),一共有 10 个.", + "knowledge_points": [ + "图文问题", + "8,9 的加减法" + ], + "source": "25-26 一年级上·江西九江·期中" + }, + { + "id": "285", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "计算题", + "difficulty": 0.85, + "question": "直接写出得数.\n2 + 2 = ( ) 10 - 1 = ( ) 4 + 4 = ( ) 3 - 0 = ( )\n2 + 8 = ( ) 2 + 7 + 1 = ( ) 3 + 5 - 6 = ( ) 10 - 7 - 3 = ( )", + "options": [ + + ], + "answer": "4;9;8;3;10;10;2;0", + "solution": "[解析]2 + 2 = 4;10 - 1 = 9;4 + 4 = 8;3 - 0 = 3;2 + 8 = 10;2 + 7 + 1 = 9 + 1 = 10;3 + 5 - 6 = 8 - 6 = 2;10 - 7 - 3 = 3 - 3 = 0", + "knowledge_points": [ + "加减混合运算(10以内)", + "连加,连减(10以内)", + "10的加减法", + "8,9的加减法" + ], + "source": "25-26 一年级上·江西九江·期中" + }, + { + "id": "286", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式.\n![](images/ecd4bd9f21247e819165f5dcf060db66d7a04c6587e336fc117cbd7df0325610.jpg)\n□ ○ □ = □(个)", + "options": [ + + ], + "answer": "5 + 4 = 9 (个)", + "solution": "【分析】左边有 5 个蘑菇, 右边有 4 个, 求一共有几个蘑菇,用加法计算, 即左边的数量 + 右边的数量 = 总数量.\n【详解】 5 + 4 = 9 (个),一共有 9 个蘑菇.", + "knowledge_points": [ + "图文问题", + "8,9 的加减法" + ], + "source": "25-26 一年级上·江西九江·期中" + }, + { + "id": "287", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.65, + "question": "9 名女同学围成一个圆圈, 隔 3 名女同学插进 2 名男同学, 一共插进多少名男同学?", + "options": [ + + ], + "answer": "6名", + "solution": "【分析】根据题意,可以通过画图来表示,红色表示女生,蓝色表示男生,9名女同学围成一个圆圈,隔3名女同学插进2名男同学,如图:\n![](images/6ba57c0f693b5381ff2d3eec886b24943155b62a6a1f549921d6626001e00b00.jpg)\n求插进多少名男生,用 2 + 2 + 2 = 6 (名),据此解答.\n【详解】 2 + 2 = 4 (名),4 + 2 = 6 (名),答: 一共插进 6 名男同学.", + "knowledge_points": [ + "6 的加减法", + "封闭图形上的植树问题" + ], + "source": "25-26 一年级上·江西九江·期中" + }, + { + "id": "288", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.65, + "question": "小刚和小组里的每个同学都合照一次相,一共照了9次.小组里一共有多少人?", + "options": [ + + ], + "answer": "10人", + "solution": "【分析】根据题意, 小刚和小组里的每个同学都合照一次相, 2人时需要拍照 1 次, 3人时需要拍照 2 次, 4人时需要拍照 3 次, 5人时需要拍照 4 次..., 人数 -1= 拍照次数, 拍照次数 +1= 人数, 据此解答.\n【详解】 9 + 1 = 10 (人),答: 小组里一共有 10 人.", + "knowledge_points": [ + "10 的加减法" + ], + "source": "25-26 一年级上·江西九江·期中" + }, + { + "id": "289", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.65, + "question": "学校运动会, 有 4 支队伍参加比赛.每队都要和另外 3 支队伍进行比赛, 一共需要进行几场比赛?", + "options": [ + + ], + "answer": "6场", + "solution": "【分析】根据题意,可以通过画图表示4支队伍之间的比赛情况,如图:![](images/617976024a4a897b3ee4d4e0e536f3a1291499d6d6d6a85096099fc1fc4b88a1.jpg), 第一队分别和其余的三队比赛,需要赛 3 场,第二队和其余的两队比赛,需要赛 2 场,最后两队赛 1 场,分别把这些比赛的场次相加,据此解答.\n【详解】 3 + 2 = 5 (场),5 + 1 = 6 (场),答: 一共需要进行 6 场比赛.", + "knowledge_points": [ + "6的加减法", + "比赛问题" + ], + "source": "25-26 一年级上·江西九江·期中" + }, + { + "id": "290", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.65, + "question": "小红,小美和小兵 3 个好朋友,互相赠送照片,他们一共要送出多少张照片?", + "options": [ + + ], + "answer": "6 张", + "solution": "【分析】3 个小朋友相互送照片, 每个人都需要送 2 张给另外两个人, 则根据加法的意义, 小红送的照片数量 + 小美送的照片数量 + 小兵送的照片数量 = 一共送的照片总数量,由此列出算式算出答案即可解答.\n【详解】 2 + 2 + 2 = 4 + 2= 6 (张),答: 他们一共要送出 6 张照片.", + "knowledge_points": [ + "6 的加减法" + ], + "source": "25-26 一年级上·江西九江·期中" + }, + { + "id": "291", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.65, + "question": "晚上小南准备打开台灯写作业,顽皮的小南把灯开了关,关了开.共按了 7 下,猜一猜,这时台灯是亮还是不亮?", + "options": [ + + ], + "answer": "亮", + "solution": "【分析】根据题意,台灯的开关每按一次,状态就会改变一次(开变关,关变开).从题目可知,小南准备写作业时灯是关着的(初始状态为关).按开关灯的变化规律为:开,关,开,关...也就是单数(1,3,5,7)是开,双数(2,4,6)是关,由此解答.\n【详解】由分析得:按1下:开(亮);按2下:关(灭);按3下:开(亮);按4下:关(灭);按5下:开(亮);按6下:关(灭);按7下:开(亮).答:这时台灯是亮的.", + "knowledge_points": [ + "6,7 的认识和读写", + "间隔问题" + ], + "source": "25-26 一年级上·江西九江·期中" + }, + { + "id": "292", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.65, + "question": "把7个桃子放在3个盘子里,每个盘子里桃子的个数各不相同,你能试着分一分吗?", + "options": [ + + ], + "answer": "1 个;2 个;4 个", + "solution": "【分析】根据题意,把 7 分成 3 个不同的数即可,据此解答.\n【详解】7 可以分成 1 和 2 和 4.答: 3 个盘子里分别放 1 个,2 个,4 个.", + "knowledge_points": [ + "6,7 的分与合(组成)" + ], + "source": "25-26 一年级上·江西九江·期中" + }, + { + "id": "293", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "小白兔拿了 10 个红萝卜, 小灰兔拿了 4 个红萝卜, 问: 小灰兔再拿多少个红萝卜, 它们两个拿的就一样多?\n□ ○ □ = □(个)", + "options": [ + + ], + "answer": "6 个;10 - 4 = 6", + "solution": "【分析】由题意可知: 用小白兔拿的红萝卜数减去小灰兔拿的红萝卜数, 即是小灰兔再拿的个数;据此解答.\n【详解】由分析可得:10 - 4 = 6 (个),答: 小灰兔再拿 6 个红萝卜, 它们两个拿的就一样多.", + "knowledge_points": [ + "10 的加减法" + ], + "source": "25-26 一年级上·江西九江·期中" + }, + { + "id": "294", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "一共要栽10棵树,再栽6棵树正好栽完,已经栽了多少棵树?\n□ ○ □ = □(棵)", + "options": [ + + ], + "answer": "4棵;10 - 6 = 4", + "solution": "【分析】由题意可知: 用一共要栽树的棵数, 减去再栽树的棵数, 即是已经栽的树的棵数;据此解答.\n【详解】 10 - 6 = 4 (棵)答: 已经栽了 4 棵树.", + "knowledge_points": [ + "10 的加减法" + ], + "source": "25-26 一年级上·江西九江·期中" + }, + { + "id": "295", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "同学们去科技馆参观,去了两组,一组有3人,另一组有5人,一共去了多少人?", + "options": [ + + ], + "answer": "8人", + "solution": "【分析】求一共去了多少人, 就是把这两组的人数合起来,用加法计算, 由此列式解答.\n【详解】 3 + 5 = 8 (人),答: 一共去了 8 人.", + "knowledge_points": [ + "8,9 的加减法" + ], + "source": "25-26 一年级上·江西九江·期中" + }, + { + "id": "296", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "8 个烧卖, 放在 2 个蒸笼里.一个蒸笼放 6 个, 另一个蒸笼放几个?", + "options": [ + + ], + "answer": "2个", + "solution": "【分析】由题意可知: 用烧麦的总个数减去一个蒸笼里的个数, 即是另一个蒸笼放的个数;据此解答.\n【详解】由分析可得:8 - 6 = 2 (个),答: 另一个蒸笼放 2 个.", + "knowledge_points": [ + "8,9 的加减法" + ], + "source": "25-26 一年级上·江西九江·期中" + }, + { + "id": "297", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "7 人玩捉迷藏游戏,游戏规则是:由一人捉住6人,现在已经捉住了3人,还有几人没有捉住?\n□ ○ □ = □(人)", + "options": [ + + ], + "answer": "3人;6 - 3 = 3", + "solution": "【分析】从题干可知:7人玩捉迷藏,由1人捉6人,已知已经捉住3人,要求还有几人没有捉住,根据减法的意义,用6-3进行解答即可.\n【详解】 6 - 3 = 3 (人)答: 还有 3 人没有捉住.", + "knowledge_points": [ + "6 的加减法", + "含有多余条件的实际问题" + ], + "source": "25-26 一年级上·江西九江·期中" + }, + { + "id": "298", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.65, + "question": "一队女生有10名,老师要求在2名女生中间插进1名男生,可插进多少名男生?", + "options": [ + + ], + "answer": "9名", + "solution": "【分析】2名女生中间插进1名男生,则男生人数比女生人数少1,用女生人数减1即可求解.\n【详解】 10 - 1 = 9 (名),答: 可插进 9 名男生.", + "knowledge_points": [ + "10 的加减法" + ], + "source": "25-26 一年级上·江西九江·期中" + }, + { + "id": "299", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "学校举行拔河比赛,第一队有 8 人,第二队有 6 人,要使比赛公平,第二队应再加几人?\n□ ○ □ = □(人)", + "options": [ + + ], + "answer": "2人;8 - 6 = 2", + "solution": "【分析】用第一队的人数减去第二队的人数,求出差,就是第二队应再加几人.\n【详解】 8 - 6 = 2 (人),答: 第二队应再加 2 人.", + "knowledge_points": [ + "8,9 的加减法" + ], + "source": "25-26 一年级上·江西九江·期中" + }, + { + "id": "300", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "丽丽折了 5 只千纸鹤, 欢欢折了 2 只, 乐乐折了 3 只千纸鹤, 丽丽和乐乐一共折了几只千纸鹤?", + "options": [ + + ], + "answer": "8只", + "solution": "【分析】根据题意可知:用丽丽折的数量加上乐乐折的数量即可求出丽丽和乐乐一共折的数量.\n【详解】 5 + 3 = 8 (只),答: 丽丽和乐乐一共折了 8 只千纸鹤.", + "knowledge_points": [ + "8,9 的加减法" + ], + "source": "25-26 一年级上·江西九江·期中" + }, + { + "id": "301", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.65, + "question": "小雨和小方有同样多的故事书, 他们的故事书合起来超过 6 本但不到 10 本, 他们可能一共有 ( ) 本故事书.", + "options": [ + "A. 6", + "B. 8", + "C. 10" + ], + "answer": "B", + "solution": "【分析】根据题意,两个相同的数相加,和大于6并且小于10,这个和就是故事书的本数.\n【详解】 4 + 4 = 8 (本);6 \u003c 8 \u003c 10;他们可能一共有 8 本故事书.故答案为: B", + "knowledge_points": [ + "8,9 的加减法", + "10 以内数的比大小" + ], + "source": "24-25 一年级上·福建三明·期中" + }, + { + "id": "302", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "妈妈买了 8 个桃子,我和姐姐吃了 2 个,?根据信息可以解决的问题是().", + "options": [ + "A. 一共有多少个桃子?", + "B. 一共吃了多少个桃子?", + "C. 还剩多少个桃子?" + ], + "answer": "C", + "solution": "【分析】根据题意,妈妈买来桃子的总数量-我和姐姐吃了的数量 = 还剩的数量,由此解答.\n【详解】A.一共有8个桃子,不需要解答;B. 一共吃了 2 个桃子, 不需要解答;C. 8 - 2 = 6 (个), 还剩 6 个桃子.则根据信息可以解决的问题是还剩多少个桃子.故答案为: C", + "knowledge_points": [ + "\"提问题\"\"填条件\"问题", + "8,9的加减法" + ], + "source": "24-25 一年级上·福建三明·期中" + }, + { + "id": "303", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "妈妈买了两盒蛋糕,一共 10 个.下面图 ( ) 不是妈妈买的.", + "options": [ + "A. ![](images/559910eb7a82e383f46b440fe1f423a06cb8aae5d3b3ee5fc8c8867618710533.jpg)", + "B. ![](images/5e8d9cac33cf9becce01e753bf353ef58c3ce12f525a4b20b2cc6e5257a18690.jpg)", + "C. ![](images/f38a3329f024a5b5d4295bea73f8b3294ed1793ebbd5233b2c0cf96ba5102383.jpg)" + ], + "answer": "A", + "solution": "【分析】根据题意, 将每两盒的数量相加, 求出结果为 10 个的两盒是妈妈买的, 剩余的一盒不是妈妈买的.\n【详解】第一盒和第二盒: 2 + 4 = 6 (个), 不符合题意;第一盒和第三盒: 2 + 6 = 8 (个), 不符合题意;第二盒和第三盒: 4 + 6 = 10 (个), 符合题意.所以妈妈买的是第二盒和第三盒,没有买第一盒,也就是\n![](images/ae399474989610d90dcd3b231f4666eed8a13359d57ceefb877563977448baca.jpg)\n故答案为: A", + "knowledge_points": [ + "图文问题", + "6 的加减法", + "10 的加减法", + "8,9 的加减法" + ], + "source": "24-25 一年级上·福建三明·期中" + }, + { + "id": "304", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "8 个小朋友打扫卫生,有5把![](images/81d0a1e66496849a1ea4eebae2d2502d2c9becc9d45efbb743825ae2f823bbbb.jpg),还差()把.", + "options": [ + "A. 3", + "B. 5", + "C. 6" + ], + "answer": "A", + "solution": "【分析】用小朋友的数量减去已有的扫把数量,求出差,就是还差的扫把数量.\n【详解】 8 - 5 = 3 (把),即, 8 个小朋友打扫卫生, 有 5 把\n![](images/db3afd5430f752121112a4dd9320bf9310c232b145f0296a330be40450d93e62.jpg)\n,还差3把.故答案为: A", + "knowledge_points": [ + "8,9 的加减法" + ], + "source": "24-25 一年级上·湖北随州·期末" + }, + { + "id": "305", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.65, + "question": "如果 △ -2 =□-5, 那么().", + "options": [ + "A. △ \u003c □ ", + "B. △ = □ ", + "C. △ \u003e □" + ], + "answer": "A", + "solution": "【分析】此题可以用赋值法解答.假设 △ 是 3 , 算出这时 □ 表示多少, 然后比较它们的大小.\n【详解】假设 △ = 3 , 则 △ - 2 = 3 - 2 = 1 , 1 + 5 = 6 , 则 □ = 6 ,\n6 \u003e 3,所以 □ \u003e △ , 或 △ \u003c □ .故答案为: A", + "knowledge_points": [ + "6 的加减法", + "加,减法的意义和各部分间的关系", + "5 以内数的减法" + ], + "source": "24-25一年级上·福建厦门·期末" + }, + { + "id": "306", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "□ \u003e 6, □ 里最小能填().", + "options": [ + "A. 5", + "B. 7", + "C. 9" + ], + "answer": "B", + "solution": "【分析】1 到 10, 从小到大排序:1,2,3,4,5,6,7,8,9,10;由此可知,比 6 大且是最小的数是 7;据此解决即可.\n【详解】由题意分析得:□ \u003e6 ,□ 里最小能填 7.故答案为: B", + "knowledge_points": [ + "10以内数的比大小" + ], + "source": "24-25 一年级上·福建厦门·期末" + }, + { + "id": "307", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.65, + "question": "明明和丽丽有同样多的糖, 明明吃了 5 块, 丽丽吃了 7 块, 谁剩下的多? ( )", + "options": [ + "A. 明明", + "B. 丽丽", + "C. 同样多" + ], + "answer": "A", + "solution": "【分析】明明和丽丽有同样多的糖,吃的越多剩下的越少,比较谁吃的少谁就剩的多,据此得出结论即可.\n【详解】 5\u003c7,即明明剩下的多.故答案为: A", + "knowledge_points": [ + "10以内数的比大小" + ], + "source": "24-25 一年级上·河北邯郸·期末" + }, + { + "id": "308", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "从 4 数到 10 , 共数 ( ) 个数.", + "options": [ + "A. 6", + "B. 7", + "C. 8" + ], + "answer": "B", + "solution": "【分析】10以内数的排序:0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10.据此数一数.\n【详解】从 4 数到 10 ,有 4,5,6,7,8,9,10,共数 7个数.故答案为: B", + "knowledge_points": [ + "10以内数的排序" + ], + "source": "24-25 一年级上·河北邯郸·期末" + }, + { + "id": "309", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "妈妈买了 10 个苹果,小明吃了 3 个,还剩下几个苹果?()", + "options": [ + "A. 7 个", + "B. 6个", + "C. 8个" + ], + "answer": "A", + "solution": "【分析】根据题意可知:用妈妈买的数量减去小明吃的数量即可.\n【详解】 10 - 3 = 7 (个),则还剩下 7 个苹果.故答案为: A", + "knowledge_points": [ + "10 的加减法" + ], + "source": "24-25 一年级上·湖北武汉·期末" + }, + { + "id": "310", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "小明有 3 颗糖,小红又给了他 4 颗,小明现在一共有几颗糖?()", + "options": [ + "A. 6 颗", + "B. 7 颗", + "C. 8 颗" + ], + "answer": "B", + "solution": "【分析】把小明原有的糖数量与小红给他的数量加起来,求出和, 就是一共的数量.\n【详解】 3 + 4 = 7 (颗),即 小明有 3 颗糖, 小红又给了他 4 颗, 小明现在一共有 7 颗糖.故答案为: B", + "knowledge_points": [ + "7 的加减法" + ], + "source": "24-25 一年级上·湖北武汉·期末" + }, + { + "id": "311", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.65, + "question": "在计数器上, 从右边起第二位是 ( ).", + "options": [ + "A. 十位", + "B. 个位", + "C. 十" + ], + "answer": "A", + "solution": "【详解】在计数器上,从右边起,第一位是个位,第二位是十位(如图).\n![](images/7977087d6ebaca08f90981bc4c4db34d3164a156546a608f544f6a6caaecb637.jpg)\n故答案为: A", + "knowledge_points": [ + "整数的数级,数位和计数单位的认识" + ], + "source": "24-25 一年级上·吉林四平·期末" + }, + { + "id": "312", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "比 6 小又比 3 大的数是 ( ).", + "options": [ + "A. 4和5", + "B. 2和3", + "C. 5和7" + ], + "answer": "A", + "solution": "【分析】1 到 9, 从小到大排序:1,2,3,4,5,6,7,8,9;据此找出比 6 小又比 3 大的数即可.\n【详解】由题意分析得:A. 3 \u003c 4 \u003c 5 \u003c 6;B. 2 \u003c 3 \u003c 6;C. 3 \u003c 5 \u003c 6 \u003c 7;即比 6 小又比 3 大的数是 4 和 5.故答案为: A", + "knowledge_points": [ + "9 以内数的比大小" + ], + "source": "24-25 一年级上·河南驻马店·期中" + }, + { + "id": "313", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.65, + "question": "与9相邻的两个数是().", + "options": [ + "A. 7 和 8", + "B. 8 和 10", + "C. 9和10" + ], + "answer": "B", + "solution": "【分析】根据 10 以内的排序1,2,3,4,5,6,7,8,9,10,与 9 相邻的两个数是 9 前面和 9 后面的数,据此解答.\n【详解】9 前面是 8,9 后面是 10 .所以与 9 相邻的两个数是 8 和 10.故答案为: B", + "knowledge_points": [ + "10以内数的排序" + ], + "source": "24-25一年级上·河南驻马店·期中" + }, + { + "id": "314", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "大于6小于8的数是().", + "options": [ + "A. 5", + "B. 6", + "C. 7" + ], + "answer": "C", + "solution": "【分析】9以内数从小到大排序:0, 1, 2, 3, 4, 5, 6, 7, 8, 9;据此解决即可.\n【详解】A. 5 \u003c 6 \u003c 8;B. 6 = 6, 6 \u003c 8;C. 6 \u003c 7 \u003c 8;即大于 6 小于 8 的数是 7.故答案为: C", + "knowledge_points": [ + "9 以内数的比大小" + ], + "source": "24-25一年级上·河南濮阳·期中" + }, + { + "id": "315", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "河里有 10 条鱼, 第一次游走 4 条, 第二次游走 5 条, 一共游走 ( ) 条.", + "options": [ + "A. 4", + "B. 5", + "C. 9" + ], + "answer": "C", + "solution": "【分析】用第一次游走的数量加上第二次游走的数量,就能求出来一共游走的数量,用加法计算,据此解答.\n【详解】根据分析:4 + 5 = 9 (条);所以,一共游走9条.故答案为: C.", + "knowledge_points": [ + "8,9 的加减法" + ], + "source": "24-25 一年级上·浙江杭州·期中" + }, + { + "id": "316", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.65, + "question": "有7根香蕉,分给5个小朋友,每个小朋友都有香蕉吃,如果只有一个小朋友拿的香蕉最多,这个小朋友有()根香蕉.(建议画一画)", + "options": [ + "A. 1", + "B. 2", + "C. 3" + ], + "answer": "C", + "solution": "【分析】要使这个小朋友的香蕉最多, 则其余 4 个小朋友各分 1 根, 剩余的都分给他.\n【详解】7 - 1 - 1 - 1 - 1 = 3 (根),这个小朋友有 3 根香蕉.故答案为: C", + "knowledge_points": [ + "连加,连减(10以内)" + ], + "source": "24-25一年级上·浙江杭州·期中" + }, + { + "id": "317", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "□\u003e6, □ 里最小填 ( ).", + "options": [ + "A. 6", + "B. 7", + "C. 8" + ], + "answer": "B", + "solution": "【分析】9 以内数的大小关系为: 0 \u003c 1 \u003c 2 \u003c 3 \u003c 4 \u003c 5 \u003c 6 \u003c 7\u003c 8 \u003c 9 , 所以大于 6 的数中, 最小的是 7.\n【详解】\u003e6,□ 里最小填7.故答案为: B", + "knowledge_points": [ + "9 以内数的比大小" + ], + "source": "24-25一年级上·福建漳州·期中" + }, + { + "id": "318", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "原来有9根黄瓜,先吃了3根,又吃了4根,还剩()根.", + "options": [ + "A. 2", + "B. 3", + "C. 4" + ], + "answer": "A", + "solution": "【分析】要求还剩多少根黄瓜,根据减法的意义,用黄瓜的数量减去吃了的黄瓜数量,即可得出答案.\n【详解】 9 - 3 - 4= 6 - 4= 2 (根),所以,还剩2根.故答案为:A", + "knowledge_points": [ + "连加,连减(10以内)" + ], + "source": "24-25一年级上·河北秦皇岛·期末" + }, + { + "id": "319", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "同学们排队买票,小红排第8,小红前面有()个小朋友.", + "options": [ + "A. 7", + "B. 8", + "C. 6" + ], + "answer": "A", + "solution": "【分析】小红前面的人数不包括小红,所以用 8 - 1 即可得出小红前面有几个小朋友.\n【详解】 8 - 1 = 7 (个),所以小红前面有 7 个小朋友.故答案为: A", + "knowledge_points": [ + "数一数", + "8,9 的加减法" + ], + "source": "24-25 一年级上·广西柳州·期末" + }, + { + "id": "320", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "下面的数量关系不可以表示 \" 4 + 3 = 7 \" 的是图 ( ).", + "options": [ + "A. ![](images/211552.png)", + "B. ![](images/dbc246e29e34ec08a6023c39e47c4bc8a42dd8ff62b5e1955fd87bce0e0296d4.jpg)", + "C. ![](images/f0f1f17b293d086ceaa7a21b0ded3448b7488b7e8a73256d384972d10cabd6dc.jpg)" + ], + "answer": "A", + "solution": "【分析】根据整数加法的意义,对各个选项进行分析,即可得出答案.\n【详解】A.图中共 6 只小鸟, 不能表示 4 + 3 = 7 (如 4 + 2 = 6);B. 左边有 4 个圆柱, 右边有 3 个, 用 4 + 3 = 7 (个);C. 左边有 4 个蛋糕, 右边有 3 个, 用 4 + 3 = 7 (个).故答案为: A", + "knowledge_points": [ + "6 的加减法", + "7 的加减法" + ], + "source": "24-25 一年级上·山东菏泽·期中" + }, + { + "id": "321", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "小朋友排队做操, 小林排在第 3 , 小云排在第 8 , 小林和小云之间有( )个小朋友.", + "options": [ + + ], + "answer": "4", + "solution": "【分析】根据题意可知: 从 3 数到 8 , 然后数一数 3 和 8 之间有几个人.\n【详解】3,4,5,6,7,8.则小林和小云之间有 4 人.", + "knowledge_points": [ + "9 以内数的排序", + "数一数" + ], + "source": "24-25 一年级上·湖北省直辖县级单位·期末" + }, + { + "id": "322", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "在括号里填上合适的数.\n\n6 - ( ) = 5\n( ) + 2 = 9\n10 + ( ) = 10\n3 + 2 = ( ) - 3", + "options": [ + + ], + "answer": "1;7;0;8", + "solution": "【分析】根据减数 = 被减数-差, 加数 = 和 - 另一个加数,被减数 = 差 + 减数, 计算出结果即可解答.\n【详解】 6 - 5 = 1 ,则 6 - 1 = 5;9 - 2 = 7 , 则 7 + 2 = 9;10 - 10 = 0 , 则 10 + 0 = 10;3 + 2 = 5, 5 + 3 = 8 ,则 3 + 2 = 8 - 3 .", + "knowledge_points": [ + "6 的加减法", + "10 的加减法", + "8,9 的加减法" + ], + "source": "24-25一年级上·广东揭阳·期末" + }, + { + "id": "323", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.65, + "question": "在括号里填上\"+\"或\"-\".\n\n9 ( ) 1 = 10\n5 ( ) 3 = 2\n8 ( ) 5 = 3\n6 ( ) 3 = 9", + "options": [ + + ], + "answer": "+;-;-;+", + "solution": "【分析】依据 10 以内数的组成与分成, 10 以内加减法, 分别计算.\n【详解】 9 + 1 = 10;5 - 3 = 2;8 - 5 = 3;6 + 3 = 9", + "knowledge_points": [ + "10的加减法", + "8,9的加减法", + "5以内数的减法" + ], + "source": "24-25一年级上·广东揭阳·期末" + }, + { + "id": "324", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "在括号里填上\"\u003e\",\"\u003c\"或\"=\".\n\n1 + 6 ( ) 8\n3 ( ) 7 - 4\n5 + 3 ( ) 7\n8 + 2 ( ) 10\n9 - 2 ( ) 6\n6 + 2 ( ) 9", + "options": [ + + ], + "answer": "\u003c;=;\u003e;=;\u003e;\u003c", + "solution": "【分析】根据整数加减法的计算法则,依次计算出各算式的结果再比较大小.10 以内数从大到小关系为: 10 \u003e 9 \u003e 8\u003e7\u003e6\u003e5\u003e4\u003e3\u003e2\u003e1 , 由此比较.\n【详解】 1 + 6 = 7;7 \u003c 8 ,则 1 + 6 \u003c 8;3 = 7 - 4;5 + 3 = 8;8 \u003e 7 , 则 5 + 3 \u003e 7;8 + 2 = 10;9 - 2 = 7;7 \u003e 6 , 则 9 - 2 \u003e 6;6 + 2 = 8;8 \u003c 9 , 则 6 + 2 \u003c 9 .", + "knowledge_points": [ + "7 的加减法", + "10 的加减法", + "8,9 的加减法", + "10 以内数的比大小" + ], + "source": "24-25一年级上·广东揭阳·期末" + }, + { + "id": "325", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.65, + "question": "在括号里填上合适的数.\n\n5 + ( ) = 10\n( ) - 2 = 4\n( ) + 6 = 9\n2 + ( ) = 8\n( ) - 8 = 1\n7 + ( ) = 7 - ( )", + "options": [ + + ], + "answer": "5;6;3;6;9;0;0", + "solution": "【分析】根据5和5合起来是10,6可以分成2和4,3和6,合起来是 9, 2 和 6 合起来是 8, 9 可以分成 8 和 1, 一个数加上 0 和这个数减去 0 的结果相等, 据此得出结论即可.\n【详解】根据分析知:\n5 + 5 = 10;6 - 2 = 4;3 + 6 = 9;\n2 + 6 = 8;9 - 8 = 1;7 + 0 = 7 - 0", + "knowledge_points": [ + "有关 0 的加减法", + "10 的加减法", + "8,9 的加减法" + ], + "source": "24-25 一年级上·广东揭阳·期末" + }, + { + "id": "326", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.65, + "question": "在括号里填上\"\u003e\" \"\u003c\"或\"=\".\n\n8 - 2 ( ) 6 + 2\n10 ( ) 6 + 3\n5 + 2 ( ) 4 + 3\n8 - 7 ( ) 6", + "options": [ + + ], + "answer": "\u003c;\u003e;=;\u003c", + "solution": "【分析】整数的大小比较:比较数的大小,先看位数的多少,位数多的数就大;位数相同,从高位开始比较,高位上的数大则这个数大,高位上的数相同,就比较下一位.含有算式的,可以先计算出算式的结果,再比较大小.\n【详解】 8 - 2 = 6, 6 + 2 = 8, 6 \u003c 8 ,所以 8 - 2 \u003c 6 + 2;6 + 3 = 9, 10 \u003e 9 ,所以 10 \u003e 6 + 3;5 + 2 = 7, 4 + 3 = 7, 7 = 7 ,所以 5 + 2 = 4 + 3;8 - 7 = 1, 1 \u003c 6 ,所以 8 - 7 \u003c 6 .", + "knowledge_points": [ + "7 的加减法", + "8,9 的加减法", + "10 以内数的比大小" + ], + "source": "24-25 一年级上·广东揭阳·期末" + }, + { + "id": "327", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.65, + "question": "比 9 大 1 的数是( ), 比 9 小 3 的数是( ).", + "options": [ + + ], + "answer": "10;6", + "solution": "【分析】求比 9 大 1 的数用加法计算, 求比 9 小 3 的数是几,用减法计算, 据此解答即可.\n【详解】 9 + 1 = 10,9 - 3 = 6,故: 比 9 大 1 的数是 10 , 比 9 小 3 的数是 6 .", + "knowledge_points": [ + "10 的加减法", + "8,9 的加减法" + ], + "source": "24-25 一年级上·广东揭阳·期末" + }, + { + "id": "328", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "8 比 6 多( ), ( )比 5 多 2 .", + "options": [ + + ], + "answer": "2;7", + "solution": "【分析】求一个数比一个数多多少,用减法列式计算;求比一个数多几的数是多少,用加法列式计算.\n【详解】 8 - 6 = 2,5 + 2 = 7,即8比6多2,7比5多2.", + "knowledge_points": [ + "7 的加减法", + "8,9 的加减法" + ], + "source": "24-25 一年级上·福建福州·期末" + }, + { + "id": "329", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "下边的图形有( )个小正方体.\n\n![](images/12230e712ab490f51c17976ec3677dac5691a2cb71ac37beaa9528d6b93b8fe9.jpg)", + "options": [ + + ], + "answer": "5", + "solution": "【分析】根据图示可知, 此立体图形可分为 2 层, 第一层有 4 个小正方体, 第二层有 1 个小正方体, 计算小正方体的总个数即可.\n【详解】 4 + 1 = 5 (个);下边的图形有 5 个小正方体.\n![](images/0b5f4b3a8d18ed7f8603520481eb74bfd79dbd62d79cb92b94e3ad91dcb730c2.jpg)", + "knowledge_points": [ + "6 的加减法", + "数一数" + ], + "source": "24-25 一年级上·湖北省直辖县级单位·期末" + }, + { + "id": "330", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "老师给 9 个 \"数学之星\" 每人发一朵小红花, 还多出 1 朵小红花, 老师一共有 ( )朵小红花.", + "options": [ + + ], + "answer": "10", + "solution": "【分析】把老师发给小朋友的小红花数量与还多出的小红花数量加起来,求出和,即可解决.\n【详解】 9 + 1 = 10 (朵),即老师给 9 个 \"数学之星\" 每人发一朵小红花, 还多出 1 朵小红花, 老师一共有 10 朵小红花.", + "knowledge_points": [ + "10 的加减法" + ], + "source": "24-25 一年级上·湖北随州·期末" + }, + { + "id": "331", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "在括号里填上\"\u003e\" \"\u003c\"或\"=\"或填上适当的数.\n\n7 ( ) 6\n6 ( ) 9\n4 ( ) 7\n8 ( ) 3\n5 ( ) 8\n4 \u003c ( )\n2 + 5 ( ) 6\n3 + 5 ( ) 10 - 2", + "options": [ + + ], + "answer": "\u003e;\u003c;\u003c;\u003c;6;\u003e;=", + "solution": "【分析】根据整数加减法的计算法则,依次计算出各个算式的结果再比较大小.10 以内的数从大到小的关系为: 10 \u003e 9 \u003e 8 \u003e 7 \u003e 6 \u003e 5 \u003e 4 \u003e 3 \u003e 2 \u003e 1 \u003e 0 ,由此比较.\n【详解】 (1) 7 \u003e 6;(2) 6 \u003c 9;(3) 4 \u003c 7;(4) 8 \u003e 3;(5) 5 \u003c 8;(6) 4 \u003c 6;(答案不唯一) (7) 左边: 2 + 5 = 7 , 右边: 6, 7 \u003e 6 , 故 2 + 5 \u003e 6;(8) 左边: 3 + 5 = 8 , 右边: 10 - 2 = 8, 8 = 8 , 故 3 + 5 = 10 - 2 .", + "knowledge_points": [ + "7 的加减法", + "10 的加减法", + "8,9 的加减法", + "10 以内数的比大小" + ], + "source": "24-25 一年级上·广东梅州·期末" + }, + { + "id": "332", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.65, + "question": "在括号里最大填几.\n\n( ) + 4 \u003c 9\n7 - ( ) \u003e 4\n10 - ( ) \u003e 5\n( ) + 2 \u003c 7", + "options": [ + + ], + "answer": "4;2;4;4", + "solution": "【分析】把大于,小于号看作等号,算出另一个数,然后用另一个数减 1 即可得出所求的数.\n【详解】 9 - 4 = 5, 5 - 1 = 4 ,则 4 + 4 \u003c 9;7 - 4 = 3, 3 - 1 = 2 , 则 7 - 2 \u003e 4;10 - 5 = 5, 5 - 1 = 4 , 则 10 - 4 \u003e 5;7 - 2 = 5, 5 - 1 = 4 , 则 4 + 2 \u003c 7 .", + "knowledge_points": [ + "7 的加减法", + "10 的加减法", + "8,9 的加减法", + "不等式填数问题", + "9 以内数的比大小" + ], + "source": "24-25一年级上·浙江杭州·期中" + }, + { + "id": "333", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "10 枚棋子, 1 个 1个的数要数( )次;2个2个的数要数( )次.", + "options": [ + + ], + "answer": "10;5", + "solution": "【分析】从 1 开始, 1 个 1 个地数, 一直数到 10 , 即可知道要数几次.从 2 开始, 2 个 2 个地数, 一直数到 10, 即可知道要数几次.\n【详解】由题意分析得:1,2,3,4,5,6,7,8,9,10;2,4,6,8,10;即10枚棋子,1个1个的数要数10次;2个2个的数要数5次.", + "knowledge_points": [ + "数一数" + ], + "source": "24-25 一年级上·河南南阳·期末" + }, + { + "id": "334", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.65, + "question": "小朋友排队, 小明排第 4 , 小芳排第 8 , 小明和小芳之间有( )人.", + "options": [ + + ], + "answer": "3", + "solution": "【分析】用小芳排的位置数减去小明排的位置数,再减去小明 1 人即可.\n【详解】 8 - 4 - 1 = 3 (人)或 8 - 1 - 4 = 3 (人),小朋友排队,小明排第4,小芳排第8,小明和小芳之间有3人.", + "knowledge_points": [ + "连加,连减(10以内)", + "两个数之间有几个数" + ], + "source": "24-25 一年级上·湖南岳阳·期末" + }, + { + "id": "335", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "亮亮读一本书, 从第 5 页读到第 10 页, 他一共读了( )页.", + "options": [ + + ], + "answer": "6", + "solution": "【分析】从 5 开始, 一个一个地数, 一直数到 10, 看看数了几个数, 就知道他一共读了几页.\n【详解】由题意分析得:5, 6, 7, 8, 9, 10;即亮亮读一本书, 从第 5 页读到第 10 页, 他一共读了 6 页.", + "knowledge_points": [ + "数一数" + ], + "source": "24-25 一年级上·湖南常德·期末" + }, + { + "id": "336", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "10比2多( ), 3比9少( ).", + "options": [ + + ], + "answer": "8;6", + "solution": "【分析】一个数比另一个数多几或少几,用减法计算,大数减去小数即可算出结果,据此解答.\n【详解】根据分析可得:(1) 10 - 2 = 8 , 所以 10 比 2 多 8;(2) 9 - 3 = 6 , 所以 3 比 9 少 6.", + "knowledge_points": [ + "10 的加减法", + "8,9 的加减法" + ], + "source": "24-25一年级上·云南玉溪·期末" + }, + { + "id": "337", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "清明节, 学校从星期四到星期六放假, 共放假( )天.今天是星期五, 再过 3 天就是禾禾的生日, 他的生日是星期( ).", + "options": [ + + ], + "answer": "3;一", + "solution": "【分析】每周都有 7 天,按照星期一,星期二,星期三,星期四,星期五,星期六和星期日依次循环,也就是按照 1, 2, 3, 4, 5, 6, 7 的顺序重复排列,从星期四到星期六,也就是从 4 数到 6,分别是 4, 5, 6,共 3 个数,即放假 3 天;星期五后面第一天是星期六,第二天是星期日,第三天是星期一,由此解答.\n【详解】清明节,学校从星期四到星期六放假,共放假3天.今天是星期五,再过 3 天就是禾禾的生日,他的生日是星期一.", + "knowledge_points": [ + "9 以内数的排序", + "数一数" + ], + "source": "24-25 一年级上·甘肃陇南·期末" + }, + { + "id": "338", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "小明看一本故事书,第一天看了 4 页, 第二天和第一天看的同样多, 第三天应从第( )页开始看.", + "options": [ + + ], + "answer": "9", + "solution": "【分析】因为第二天和第一天看的同样多,所以第二天也看了 4 页,要求第三天要从第几页开始看,即先求出前面两天一共看了多少页,再加上 1 页,就是第三天开始看的页码.\n【详解】 4 + 4 + 1 = 9 (页),所以,第三天应从第9页开始看.", + "knowledge_points": [ + "连加,连减(10以内)" + ], + "source": "24-25 一年级上·河南驻马店·期中" + }, + { + "id": "339", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "5前面第2个数是( ),5后面第3个数是( ).", + "options": [ + + ], + "answer": "3;8", + "solution": "【分析】从 1 到 10 , 一个一个地数, 即可找出 5 前面第 2 个数是几, 及 5 后面第 3 个数是几.\n【详解】由题意分析得:1, 2, 3, 4, 5, 6, 7, 8, 9, 10;即,5前面第2个数是3,5后面第3个数是8.", + "knowledge_points": [ + "10以内数的排序" + ], + "source": "24-25 一年级上·河南驻马店·期中" + }, + { + "id": "340", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "( )比 5 多 3;7 比 2 多( ).", + "options": [ + + ], + "answer": "8;5", + "solution": "【分析】求比一个数多几的数是多少,用加法计算;求一个数比另一个数多几,用减法计算.\n【详解】 5 + 3 = 8;7 - 2 = 5;即,8比5多3;7比2多5.", + "knowledge_points": [ + "7 的加减法", + "8,9 的加减法" + ], + "source": "24-25 一年级上·河南驻马店·期中" + }, + { + "id": "341", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.65, + "question": "姐姐有 9 颗糖, 妹妹有 3 颗糖, 姐姐给妹妹( )颗糖, 姐姐和妹妹的糖就一样多, 现在她俩各有( )颗糖.", + "options": [ + + ], + "answer": "3;6", + "solution": "【分析】要使姐姐和妹妹的糖一样多,姐姐给妹妹的颗数 = 姐姐比妹妹糖多的颗数的一半;用姐姐原来的数量减姐姐比妹妹糖多的颗数的一半即可求出现在的颗数.\n【详解】 9 - 3 = 6 (颗),3 + 3 = 6 (颗),姐姐有 9 颗糖, 妹妹有 3 颗糖, 姐姐给妹妹 3 颗糖, 姐姐和妹妹的糖就一样多.9 - 3 = 6 (颗),现在她俩各有 6 颗糖.", + "knowledge_points": [ + "6 的加减法", + "8,9 的加减法" + ], + "source": "24-25 一年级上·浙江杭州·期中" + }, + { + "id": "342", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "妈妈买了 10 个苹果,姐姐吃了2个,妹妹吃了4个,一共吃掉了( )个苹果,还剩下( )个苹果.", + "options": [ + + ], + "answer": "6;4", + "solution": "【分析】要想求一共吃掉苹果的个数,姐姐吃的个数加妹妹吃的个数即可;如果求还剩下苹果的个数, 拿着妈妈买苹果的总个数减去一共吃掉的个数即可.据此解答.\n【详解】根据分析:2 + 4 = 6 (个);10 - 6 = 4 (个).所以,妈妈买了 10 苹果,姐姐吃了 2 个,妹妹吃了 4 个,一共吃掉了 (6) 个苹果, 还剩下 (4) 个苹果.", + "knowledge_points": [ + "6 的加减法", + "10 的加减法" + ], + "source": "24-25 一年级上·浙江杭州·期中" + }, + { + "id": "343", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.65, + "question": "比 10 小的数有( )个, 比 6 大比 9 小的数有( )个.", + "options": [ + + ], + "answer": "10;2", + "solution": "【分析】依据 10 以内数的排序 10 \u003e 9 \u003e 8 \u003e 7 \u003e 6 \u003e 5 \u003e 4 \u003e 3 \u003e2 \u003e 1 \u003e 0 , 填空即可.\n【详解】比 10 小的数有 9,8,7,6,5,4,3,2,1,0;共 10 个数.比6大比9小的数有7,8共2个数.比10小的数有10个;比6大比9小的数有2个数.", + "knowledge_points": [ + "10以内数的比大小" + ], + "source": "24-25 一年级上·浙江杭州·期中" + }, + { + "id": "344", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "比 5 大 2 的数是( ), 10 比 4 大( ).", + "options": [ + + ], + "answer": "7;6", + "solution": "【分析】求比一个数大几的数的多少,用加法计算;求一个数比另一个数大几,用减法计算.据此解答.\n【详解】 5 + 2 = 7,10 - 4 = 6,所以,比 5 大 2 的数是 7,10 比 4 大 6.", + "knowledge_points": [ + "7 的加减法", + "10 的加减法" + ], + "source": "24-25 一年级上·浙江杭州·期中" + }, + { + "id": "345", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "与 6 相邻的两个数是( )和( ), 9 前面第 2 个数是( ).", + "options": [ + + ], + "answer": "5;7;7", + "solution": "【分析】依据 10 以内数的排序填空.9 以内数的排序: 0, 1, 2, 3, 4, 5, 6, 7, 8, 9 .\n【详解】与 6 相邻的两个数是 5 和 7.9 前面第 2 个数是 7.", + "knowledge_points": [ + "9以内数的排序" + ], + "source": "24-25 一年级上·浙江杭州·期中" + }, + { + "id": "346", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "8 和 10 中间的数是( ).比7少2的数是( ).", + "options": [ + + ], + "answer": "9;5", + "solution": "【分析】一个一个地数, 即可知道 8 和 10 中间的数是几;求比一个数少几的数是多少, 用减法列式计算.\n【详解】由题意分析得:8,9,10 , 7 - 2 = 5,即, 8 和 10 中间的数是 9.比 7 少 2 的数是 5.", + "knowledge_points": [ + "7 的加减法", + "10 以内数的排序" + ], + "source": "24-25 一年级上·山东日照·期中" + }, + { + "id": "347", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "判断题", + "difficulty": 0.85, + "question": "如果 8 - □ = 7 - 4 ,那么 □ 里应该填 3.( )", + "options": [ + + ], + "answer": "×", + "solution": "【分析】根据题意可知: 先计算 7 - 4 的差, 然后根据被减数-差 = 减数即可求出 □ 的答案.\n【详解】 7 - 4 = 3;8 - 5 = 3,则□里应该填5,原题说法错误.故答案为: ×", + "knowledge_points": [ + "7 的加减法", + "8,9 的加减法" + ], + "source": "24-25 一年级上·陕西延安·期末" + }, + { + "id": "348", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "判断题", + "difficulty": 0.85, + "question": "有 6 个小朋友, 李阿姨拿了 5 块糖, 每个小朋友分 1 块糖, 刚好够.( )", + "options": [ + + ], + "answer": "×", + "solution": "【分析】根据题意,先判断糖的数量与小朋友人数是否一样,也就是比较糖的总数和小朋友的总人数,若两者相等,每个小朋友才能刚好分 1 块糖.\n【详解】已知有 6 个小朋友, 而李阿姨只拿了 5 块糖.因为 6 \u003e 5 , 即小朋友的人数比糖的数量多.所以有 6 个小朋友, 李阿姨拿了 5 块糖, 每个小朋友分 1 块糖, 糖是不够的.故答案为: ×", + "knowledge_points": [ + "7 以内数的比大小" + ], + "source": "24-25 一年级上·陕西延安·期末" + }, + { + "id": "349", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "判断题", + "difficulty": 0.85, + "question": "与 9 相邻数是 8 和7.()", + "options": [ + + ], + "answer": "×", + "solution": "【分析】根据 10 以内的数排列顺序, 可以找出与 9 相邻的两个数, 顺序为: 0,1,2,3,4,5,6,7,8,9,10;可以清楚的看出来 9 的左边是 8 , 右边是 10;据此解答.\n【详解】根据分析可得:与 9 相邻的数是 8 和 10,所以原说法错误.故答案为: ×", + "knowledge_points": [ + "10以内数的排序" + ], + "source": "24-25 一年级上·湖南岳阳·期末" + }, + { + "id": "350", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "判断题", + "difficulty": 0.65, + "question": "10比8多2, 8比10少2.( )", + "options": [ + + ], + "answer": "√", + "solution": "【分析】求一个数比另一个数多(少)多少,用减法列式计算.\n【详解】 10 - 8 = 2,即,10比8多2,8比10少2.此说法正确.故答案为: √", + "knowledge_points": [ + "10 的加减法" + ], + "source": "24-25 一年级上·吉林·期末" + }, + { + "id": "351", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "判断题", + "difficulty": 0.85, + "question": "在算式 3 + 6 = 9 中, 3 和 6 是加数, 9 是和.( )", + "options": [ + + ], + "answer": "√", + "solution": "【分析】根据\"加数+加数 = 和\"来解决此题即可.\n【详解】由题意分析得:在算式 3 + 6 = 9 中, 3 和 6 是加数, 9 是和.此说法正确.故答案为: √", + "knowledge_points": [ + "8,9 的加减法" + ], + "source": "24-25 一年级上·河北秦皇岛·期末" + }, + { + "id": "352", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式计算.\n![](images/f049c73e75c3a58f67f3e5401d7fba395669100a521813171c3d1ebe6b26c7d0.jpg)\n□ ○ □ ○ □ = □ (个)", + "options": [ + + ], + "answer": "4 + 3 + 1 = 8 (个)", + "solution": "【分析】左边的数量加上中间的数量,再加上右边的数量,等于一共有多少个.\n【详解】 4 + 3 + 1 = 8 (个);一共有 8 个.", + "knowledge_points": [ + "连加,连减(10以内)" + ], + "source": "24-25一年级上·湖北省直辖县级单位·期末" + }, + { + "id": "353", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图写算式.\n![](images/74ff098576fdb4766bf966198d93949c119189a2535df9293fc5096e13ea3760.jpg)\n□ ○ □ = □ (颗)", + "options": [ + + ], + "answer": "9 - 3 = 6 (颗)", + "solution": "【分析】用 ![](images/223617.png) 的总颗数减去右边的颗数, 求出差, 就是左边的颗数.\n【详解】由题意分析得:9 - 3 = 6 (颗)", + "knowledge_points": [ + "图文问题", + "8,9 的加减法" + ], + "source": "24-25 一年级上·福建福州·期末" + }, + { + "id": "354", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式.\n![](images/4a920747b70561578bbc82cfce4cecf3da5d92aba9addc5516369237cd9d650b.jpg)\n□ ○ □ = □ (个)", + "options": [ + + ], + "answer": "6 + 3 = 9 (个)", + "solution": "【分析】左右两边的个数相加即可求出一共有多少个.\n【详解】 6 + 3 = 9 (个)", + "knowledge_points": [ + "图文问题", + "8,9 的加减法" + ], + "source": "24-25 一年级上·江西赣州·期末" + }, + { + "id": "355", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式计算.\n![](images/e990da85cebf70f96529875938172496b8a5d5e78a16f02cd8a218a8a9e80049.jpg)\n□ ○ □ = □ (个)", + "options": [ + + ], + "answer": "5 + 2 = 7 (个)", + "solution": "【分析】左边有 5 个西红柿, 右边有 2 个, 求一共有几个西红柿, 用加法计算, 即左边的数量 + 右边的数量 = 总数量.\n【详解】 5 + 2 = 7 (个);一共有 7 个西红柿.", + "knowledge_points": [ + "图文问题", + "7 的加减法" + ], + "source": "24-25 一年级上·甘肃天水·期末" + }, + { + "id": "356", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式计算.\n![](images/ef8bb68c10e5d6338fd754eec1a30847ca004bbb57fbb81243c5b81a62017a05.jpg)\n□ ○ □ ○ □ = □ (个)", + "options": [ + + ], + "answer": "2 + 3 + 3 = 8 (个)", + "solution": "【分析】由图可知, 要求一共有多少个草莓, 用左边的个数加上中间的个数, 再加上右边的个数;据此解答.\n【详解】由分析可得:2 + 3 + 3 = 8 (个);一共有 8 个.", + "knowledge_points": [ + "图文问题", + "连加,连减(10以内)" + ], + "source": "24-25 一年级上·甘肃兰州·期末" + }, + { + "id": "357", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式并计算.\n![](images/632eaf2fdf5366027eda40e94983b329c14d7480646130f75886777cf37987f9.jpg)\n□ ○ □ = □ (个)", + "options": [ + + ], + "answer": "6 + 2 = 8 (个)", + "solution": "【分析】根据图片可知:左边有 6 个柠檬,右边有 2 个,一共有多少个?用左边的数量加右边的数量即可.\n【详解】 6 + 2 = 8 (个),则一共有 8 个.", + "knowledge_points": [ + "8,9 的加减法" + ], + "source": "24-25 一年级上·陕西榆林·期末" + }, + { + "id": "358", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式计算.\n![](images/dd6edb4e10b6803ea976eb9491444774635f617036568a43c45c6b00e6440984.jpg)\n□ ○ □ ○ □ = □ (个)", + "options": [ + + ], + "answer": "3 + 2 + 3 = 8 (个)", + "solution": "【分析】左边有 3 个球, 中间有 2 个球, 右边有 3 个球, 求一共有几个球, 用加法计算, 即左边的数量 + 中间的数量 + 右边的数量 = 总数量.\n【详解】 3 + 2 + 3 = 8 (个)\n一共有 8 个球.", + "knowledge_points": [ + "图文问题", + "连加,连减(10以内)" + ], + "source": "24-25 一年级上·云南玉溪·期末" + }, + { + "id": "359", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式计算.\n![](images/b1eca4377e3aa4c1c6e3aed3ac641fcdcc21d62541a84c296d83e0ef5fa48358.jpg)\n□ ○ □ = □ (枝)", + "options": [ + + ], + "answer": "5 + 3 = 8 (枝)", + "solution": "【分析】左边有 5 枝花,右边有 3 枝花,求一共有几枝花,用加法计算,即左边的数量 + 右边的数量 = 总数量.\n【详解】 5 + 3 = 8 (枝);一共有 8 枝花.", + "knowledge_points": [ + "图文问题", + "8,9 的加减法" + ], + "source": "24-25 一年级上·云南玉溪·期末" + }, + { + "id": "360", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式计算.\n![](images/88a1f0b88851f2129680c43dc2fbc9370d85f994e7c278f773c3d90a359920ff.jpg)\n□ ○ □ ○ □ = □ (只)", + "options": [ + + ], + "answer": "5 + 3 + 1 = 9 (只)", + "solution": "【分析】将左边,中间,右边的数量相加即可求出一共多少只.\n【详解】 5 + 3 + 1 = 9 (只)", + "knowledge_points": [ + "图文问题", + "连加,连减(10以内)" + ], + "source": "24-25 一年级上·广东汕头·期末" + }, + { + "id": "361", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式.\n![](images/39d1a3f9b6c7487fccd3150bc76bd9fc2a509748bc158c54a10b6ff5c1ca3dff.jpg)\n□ ○ □ = □ (只)", + "options": [ + + ], + "answer": "5 + 2 = 7 (只)", + "solution": "【分析】左右两边的数量相加即可求出一共有多少只.\n【详解】 5 + 2 = 7 (只)", + "knowledge_points": [ + "图文问题", + "7 的加减法" + ], + "source": "24-25 一年级上·广东江门·期末" + }, + { + "id": "362", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式并计算.\n![](images/9e7a0944c1b9feaca16428e7b026f0b80033e35e8b7d22116e844cf1a5ba9984.jpg)\n□ ○ □ = □ (个)", + "options": [ + + ], + "answer": "6 + 2 = 8 (个)", + "solution": "【分析】把左边的个数与右边的个数加起来,求出和,就是一共的个数.\n【详解】由题意分析得:6 + 2 = 8 (个),一共有 8 个.", + "knowledge_points": [ + "图文问题", + "8,9 的加减法" + ], + "source": "24-25 一年级上·陕西榆林·期末" + }, + { + "id": "363", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式计算.\n![](images/10323eb4ee3ae62f4c2468fad88d465716248f61ec678878d69ac190833ea503.jpg)\n□ ○ □ ○ □ = □ (个)", + "options": [ + + ], + "answer": "2 + 3 + 4 = 9 (个)", + "solution": "【分析】将左边,中间,右边的桃子个数相加,即可求出一共多少个桃子.\n【详解】 2 + 3 + 4 = 9 (个);一共有 9 个桃子.", + "knowledge_points": [ + "图文问题", + "连加,连减(10以内)" + ], + "source": "24-25 一年级上·青海西宁·期末" + }, + { + "id": "364", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式计算.\n![](images/5614699aace50ced0b3f25b4c1102ea55ac51d43f48a2f09372d50f3f5b0f6d3.jpg)\n□ ○ □ = □ (个)", + "options": [ + + ], + "answer": "3 + 3 = 6 (个)", + "solution": "【分析】左右两边的个数相加即可求出一共有多少个.\n【详解】 3 + 3 = 6 (个)", + "knowledge_points": [ + "图文问题", + "6 的加减法" + ], + "source": "24-25 一年级上·青海西宁·期末" + }, + { + "id": "365", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式并计算.\n![](images/465031e0eedf52c94bfd2a4d86ee60a7bf82a59218f70b4ad90050c9b9d78c0d.jpg)\n□ ○ □ = □ ○ □", + "options": [ + + ], + "answer": "6 + 4 = 3 + 7", + "solution": "【分析】把左边这只猫原来钓的鱼数量与又钓了的数量加起来, 求出和, 就是左边这只猫一共钓了的数量, 即, 6 + 4 = 10 (条).\n把右边这只猫原来钓的鱼数量与又钓了的数量加起来,求出和,就是右边这只猫一共钓了的数量,即, 3 + 7 = 10 (条).\n最后两只猫钓的鱼数量同样多,故, 6 + 4 = 3 + 7 .\n【详解】由题意分析得:6 + 4 = 10 (条),3 + 7 = 10 (条),即, 6 + 4 = 3 + 7 .", + "knowledge_points": [ + "图文问题", + "10 的加减法" + ], + "source": "24-25 一年级上·吉林·期末" + }, + { + "id": "366", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式计算.\n![](images/cd14ce06bc016c1358d3d704931333f7bac5cf56221fdf545569adf072869ae8.jpg)\n□ ○ □ ○ □ = □ (个)", + "options": [ + + ], + "answer": "4 + 3 + 2 = 9 (个)", + "solution": "【分析】将左边,中间,右边的个数相加即可求出一共多少个.\n【详解】 4 + 3 + 2 = 9 (个);一共有 9 个.", + "knowledge_points": [ + "图文问题", + "连加,连减(10以内)" + ], + "source": "24-25 一年级上·黑龙江齐齐哈尔·期末" + }, + { + "id": "367", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式计算.\n![](images/c5e599775264b4d572ff2a28ad309e58170097ec38753d631782688fc689ee89.jpg)", + "options": [ + + ], + "answer": "3 + 4 + 3 = 10 (杯)", + "solution": "【分析】先把第一个盘子和第二个盘子的数量相加,再加上第三个盘子的数量,就能列式计算,据此解答.\n【详解】根据分析:3 + 4 + 3 = 10 (杯),所以一共有 10 杯.", + "knowledge_points": [ + "图文问题", + "连加,连减(10以内)", + "10的加减法" + ], + "source": "24-25 一年级上·内蒙古呼伦贝尔·期末" + }, + { + "id": "368", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式计算.\n![](images/1d2f8facf93104e24e4e53d5f839e6b1f2c754ee473ef3a491670fb378be1f22.jpg)\n□ ○ □ ○ □ = □ (个)", + "options": [ + + ], + "answer": "4 + 3 + 2 = 9 (个)", + "solution": "【分析】将左边,中间,右边的数量相加即可求出一共多少个.\n【详解】 4 + 3 + 2 = 9 (个)", + "knowledge_points": [ + "图文问题", + "连加,连减(10以内)" + ], + "source": "24-25 一年级上·安徽芜湖·期末" + }, + { + "id": "369", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "计算题", + "difficulty": 0.85, + "question": "我会看图列式.\n![](images/89b735948147ceec21cc1ee76e09c8656de06915166217d91a6fe16dfdf052e1.jpg)\n□ ○ □ ○ □ = □ (个)", + "options": [ + + ], + "answer": "3 + 4 + 2 = 9 (个)", + "solution": "【分析】观察图可知, 第一个盘子里有 3 个, 第二个盘子里有 4 个, 第三个盘子里有 2 个, 求一共有多少个苹果, 用加法计算即可.\n【详解】根据分析可列式:3 + 4 + 2 = 9 (个),所以一共有 9 个苹果.", + "knowledge_points": [ + "图文问题", + "连加,连减(10以内)" + ], + "source": "24-25 一年级上·吉林四平·期末" + }, + { + "id": "370", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "计算题", + "difficulty": 0.85, + "question": "我会看图列式.\n![](images/38cb69e2572b2b157e37de35b598922b6b05af9200d5edf531afb10f2df5b5e3.jpg)", + "options": [ + + ], + "answer": "2 + 7 = 9 (只)", + "solution": "【分析】看图可知, 左边有 2 只小鹿, 房子里有 7 只, 求一共有多少只小鹿, 用加法计算, 据此解答.\n【详解】根据分析可知:2 + 7 = 9 (只),所以,一共有 9 只小鹿.", + "knowledge_points": [ + "图文问题", + "8,9的加减法" + ], + "source": "24-25 一年级上·吉林四平·期末" + }, + { + "id": "371", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "计算题", + "difficulty": 0.85, + "question": "我会看图列式.\n![](images/6163181560b5aa20354fd900da8a5437561c6154affa883eff040f9c92facd8d.jpg)", + "options": [ + + ], + "answer": "10 - 5 = 5 (个)", + "solution": "【分析】观察图可知,一共有10个球,右边有5个,求左边盒子里装了多少个,用减法计算,据此解答.\n【详解】根据分析可列式:10 - 5 = 5 (个),所以,左边盒子里有 5 个球.", + "knowledge_points": [ + "图文问题", + "10 的加减法" + ], + "source": "24-25 一年级上·吉林四平·期末" + }, + { + "id": "372", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式.\n![](images/6bad3db98d5dcde4dc60e4a0cb2ebb649f069692a9fc43f4b2c216466d8052b6.jpg)", + "options": [ + + ], + "answer": "6 + 2 = 8 (只)", + "solution": "【分析】根据图片:左边有 6 只小熊,右边有 2 只小熊,求一共有多少只小熊;用左边的数量加上右边的数量,求出和即可.\n【详解】由题意分析得:6 + 2 = 8 (只)", + "knowledge_points": [ + "图文问题", + "8,9 的加减法" + ], + "source": "24-25 一年级上·全国·假期作业" + }, + { + "id": "373", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列算式.\n![](images/5c89ab9ab41c21ce20bc7b8afc41a931a7000ee81120a4cbe8d0b2c24d2d5da0.jpg)", + "options": [ + + ], + "answer": "4 + 1 + 3 = 8 (个)", + "solution": "【分析】左边有 4 个, 中间有 1 个, 右边有 3 个, 求一共有多少个, 把三部分相加, 求出和即可解答.\n【详解】由题意分析得: 4 + 1 + 3 = 5 + 3 = 8 (个)", + "knowledge_points": [ + "图文问题", + "连加,连减(10以内)" + ], + "source": "24-25 一年级上·全国·假期作业" + }, + { + "id": "374", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式计算.\n![](images/8602aced98972aa6c2ea89edccbd27d99758d5a6609917246ea07ce18211d75e.jpg)", + "options": [ + + ], + "answer": "7 - 3 = 4 (个)", + "solution": "【分析】用梨的总数量减去左边的数量,求出差,就是右边箱子里的梨数量.\n【详解】由题意分析得:7 - 3 = 4 (个),右边箱子里有 4 个梨.", + "knowledge_points": [ + "图文问题", + "7 的加减法" + ], + "source": "24-25 一年级上·河南濮阳·期中" + }, + { + "id": "375", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式计算.\n![](images/02cbe2654ed5557d681aaf37b893716e98c5ef46a348c93c55ccab3390f9c1e0.jpg)", + "options": [ + + ], + "answer": "4 + 4 = 8 (条)", + "solution": "【分析】把左边的毛巾数量与右边的数量加起来,求出和,就是毛巾的总数量.\n【详解】由题意分析得:4 + 4 = 8 (条)", + "knowledge_points": [ + "图文问题", + "8,9 的加减法" + ], + "source": "24-25 一年级上·河南濮阳·期中" + }, + { + "id": "376", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "计算题", + "difficulty": 0.65, + "question": "看图列式.\n![](images/54e0f6d765d57d80c015d48fb269bb566d3e4a001b628288805e1198ea8897ab.jpg)", + "options": [ + + ], + "answer": "2 + 4 = 6 (个)", + "solution": "【分析】根据题意: 左边 2 个, 右边 4 个, 用加法求出一共有多少个草莓.\n【详解】 2 + 4 = 6 (个)", + "knowledge_points": [ + "图文问题", + "6的加减法" + ], + "source": "24-25一年级上·广西贵港·期中" + }, + { + "id": "377", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.65, + "question": "欢欢还要做几道口算题?\n![](images/cf5f1ef162167a2eabe799d7d83bb2f3d7eece2b55f3a3c1270a16af8e1cc222.jpg)\n![](images/c5028a99345ce147332f38aa46f2a8f97813e64bbc9f71ed6b1ccde538a2130d.jpg)", + "options": [ + + ], + "answer": "3 道", + "solution": "【分析】根据题意,用老师布置的数量减去已经做的数量,即可求出欢欢还要做几道口算题.据此解答.\n【详解】 10 - 7 = 3 (道);答: 欢欢还要做 3 道口算题.", + "knowledge_points": [ + "图文问题", + "10 的加减法" + ], + "source": "24-25 一年级上·河北邯郸·期中" + }, + { + "id": "378", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.65, + "question": "它俩一共捡了多少个松果?\n![](images/8b682f17312d13395d525cdceab5282c536c874ae287c1dc528bfd9a6ebac98e.jpg)", + "options": [ + + ], + "answer": "9 个", + "solution": "【分析】根据题意, 将两只松鼠捡的个数相加, 即可求出它俩一共捡了多少个松果.据此解答.\n【详解】 5 + 4 = 9 (个);答: 它俩一共捡了 9 个松果.", + "knowledge_points": [ + "图文问题", + "8,9 的加减法" + ], + "source": "24-25一年级上·河北邯郸·期中" + }, + { + "id": "379", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "一共有几条鱼?\n![](images/fb5ebb7322a783306b1ff353311e2ad4d09faf65451c7436be3b757208e279b9.jpg)", + "options": [ + + ], + "answer": "10条", + "solution": "【分析】用已经吃的条数加上还剩的条数, 即可计算出一共有几条鱼.\n【详解】 6 + 4 = 10 (条);答: 一共有 10 条鱼.", + "knowledge_points": [ + "图文问题", + "10 的加减法" + ], + "source": "24-25 一年级上·重庆九龙坡·期末" + }, + { + "id": "380", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "小芳家有 3 只白兔和 4 只灰兔,白兔和灰兔一共有多少只?", + "options": [ + + ], + "answer": "7 只;3 + 4 = 7", + "solution": "【分析】用白兔的只数加上灰兔的只数,求出和,就是白兔和灰兔一共的数量.\n【详解】 3 + 4 = 7 (只);答: 白兔和灰兔一共有 7 只.", + "knowledge_points": [ + "7 的加减法" + ], + "source": "24-25 一年级上·河南周口·期末" + }, + { + "id": "381", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "妈妈买了 9 块蛋糕,明明吃了些,还剩下5块,明明吃了几块?", + "options": [ + + ], + "answer": "4块;9 - 5 = 4", + "solution": "【分析】用妈妈买的9块减去还剩的5块即可求出吃了几块.\n【详解】 9 - 5 = 4 (块);答: 明明吃了 4 块.", + "knowledge_points": [ + "8,9 的加减法" + ], + "source": "24-25 一年级上·河北唐山·期末" + }, + { + "id": "382", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "草地上原有 8 只猴子,跑走了5只,又跑来了4只,现在草地上有多少只猴子?", + "options": [ + + ], + "answer": "7 只;8 - 5 + 4 = 7", + "solution": "【分析】根据题意, 跑走的数量要减去, 又跑来的数量要加上, 即现在猴子的数量 = 原有的数量 - 跑走的数量 + 又跑来的数量, 由此解答.\n【详解】 8 - 5 + 4 = 7 (只);答: 现在草地上有 7 只猴子.", + "knowledge_points": [ + "加减混合运算 (10 以内)" + ], + "source": "24-25一年级上·甘肃嘉峪关·期末" + }, + { + "id": "383", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "小华有 7 块橡皮,送给弟弟 3 块, 还剩多少块橡皮?", + "options": [ + + ], + "answer": "4 块;7 - 3 = 4", + "solution": "【分析】求还剩几块橡皮,用减法计算,即橡皮的总数量 - 送给弟弟的数量 = 还剩的数量.\n【详解】 7 - 3 = 4 (块);答: 还剩 4 块橡皮.", + "knowledge_points": [ + "7 的加减法" + ], + "source": "24-25 一年级上·甘肃嘉峪关·期末" + }, + { + "id": "384", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "原来树上有8只鸟,飞走了3只,又飞来了2只,现在树上一共有多少只小鸟?", + "options": [ + + ], + "answer": "7只;8 - 3 + 2 = 7", + "solution": "【分析】根据题意, 飞走的数量要减去, 又飞来的数量要加上, 即现在的数量 = 原来的数量 - 飞走的数量 + 又飞来的数量, 由此解答.\n【详解】 8 - 3 + 2 = 7 (只);答: 现在树上一共有 7 只小鸟.", + "knowledge_points": [ + "加减混合运算(10以内)" + ], + "source": "24-25一年级上·云南玉溪·期末" + }, + { + "id": "385", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.65, + "question": "原来房子里有4只小鸡,走出去了3只,又走进来了5只,现在房子里一共有多少只小鸡?", + "options": [ + + ], + "answer": "6 只;4 - 3 + 5 = 6", + "solution": "【分析】根据加,减法的意义,用原来房子里有小鸡的总数量减去走出去小鸡的数量,再加上又走进来小鸡的数量即可求出现在房子里一共有的小鸡的数量,据此解答即可.\n【详解】 4 - 3 + 5 = 6 (只);答: 现在房子里一共有 6 只小鸡.", + "knowledge_points": [ + "加减混合运算(10以内)" + ], + "source": "24-25一年级上·陕西榆林·期末" + }, + { + "id": "386", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "自习室原有 8 人,有 3 人离开, 又来了 5 人.自习室现在有多少人?", + "options": [ + + ], + "answer": "10人;8 - 3 + 5 = 10", + "solution": "【分析】根据题意,离开的人数要减去,又来的人数要加上,即原有的人数 - 离开的人数 + 又来的人数 = 现在的人数.\n【详解】 8 - 3 + 5 = 10 (人);答: 自习室现在有 10 人.", + "knowledge_points": [ + "加减混合运算 (10 以内)" + ], + "source": "24-25 一年级上·青海西宁·期末" + }, + { + "id": "387", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "家里原有 7 个面包,吃了 2 个, 家里还剩几个?", + "options": [ + + ], + "answer": "5 个", + "solution": "【分析】求还剩几个,用减法计算,即原有的数量 - 吃了的数量 = 还剩的数量.\n【详解】 7 - 2 = 5 (个);答: 家里还剩 5 个.", + "knowledge_points": [ + "7 的加减法" + ], + "source": "24-25一年级上·青海西宁·期末" + }, + { + "id": "388", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "还剩多少条?\n![](images/d2fbdff291c9b860e98bf10a3491ab7189ae1797b7f392ccddc0c06172a8fbdb.jpg)", + "options": [ + + ], + "answer": "4条;9 - 5 = 4", + "solution": "【分析】根据题意可知, 用总数量减去吃的数量, 就等于还剩下鱼的数量, 据此解答.\n【详解】根据分析可列式:\n9 - 5 = 4 (条)\n答: 还剩下 4 条.", + "knowledge_points": [ + "图文问题", + "8,9 的加减法" + ], + "source": "24-25 一年级上·吉林四平·期末" + }, + { + "id": "389", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.65, + "question": "他们一共吃了多少颗杏子?\n![](images/387302b0933bf176a57a13e182974ae0035ee3878637f25369610d31aec36547.jpg)", + "options": [ + + ], + "answer": "9颗;3 + 6 = 9", + "solution": "【分析】根据题意, 把男孩吃的数量和女孩吃的数量相加即可求出他们一共吃了多少颗杏子.\n【详解】 3 + 6 = 9 (颗),答: 他们一共吃了 9 颗杏子.", + "knowledge_points": [ + "图文问题", + "8,9 的加减法" + ], + "source": "24-25一年级上·吉林四平·期末" + }, + { + "id": "390", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "还剩 ( ) 根.\n![](images/aa7453b0cdfc070cbc94ded87711c47eff1dacc6b03ecb313a990c6fd476ab2a.jpg)", + "options": [ + + ], + "answer": "2根;10 - 8 = 2", + "solution": "【分析】一共有 10 根, 有 8 个人, 每人一根也就是需要 8 根, 则用总数量 - 需要的数量 = 还剩的数量.\n【详解】还剩 2 根.10 - 8 = 2 (根);答: 还剩 2 根.", + "knowledge_points": [ + "图文问题", + "10 的加减法" + ], + "source": "24-25 一年级上·河北唐山·期末" + }, + { + "id": "391", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.94, + "question": "超市里的 7 号电池有一板装 4 节的, 也有一板装 6 节的, 两种包装的电池各买一板, 一共是多少节电池?", + "options": [ + + ], + "answer": "10节", + "solution": "【分析】求一共有几节电池,用加法计算,即一板电池的数量 4 节 + 另一板电池的数量 6 节 = 一共的数量.\n【详解】 4 + 6 = 10 (节);答: 一共是 10 节电池.", + "knowledge_points": [ + "10 的加减法" + ], + "source": "23-24 二年级上·河北保定·期末" + }, + { + "id": "392", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.65, + "question": "公交车上原来有6人,到站后有5人下车,又上来3人.公交车上现在有多少人?", + "options": [ + + ], + "answer": "4人;6 - 5 + 3 = 4", + "solution": "【分析】用原来的人数减去下车的人数,再加上又上来的人数即可求出公交车上现在有多少人.\n【详解】 6 - 5 + 3 = 4 (人);答: 公交车上现在有 4 人.", + "knowledge_points": [ + "加减混合运算(10以内)" + ], + "source": "24-25一年级上·河南周口·期中" + }, + { + "id": "393", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "原来有 9 个鸡蛋,吃掉了 6 个.还剩多少个鸡蛋?", + "options": [ + + ], + "answer": "3 个;9 - 6 = 3", + "solution": "【分析】根据减法的意义,原来鸡蛋的数量减吃掉的数量 = 还剩的数量.\n【详解】 9 - 6 = 3 (个);答: 还剩 3 个鸡蛋.", + "knowledge_points": [ + "8,9 的加减法" + ], + "source": "24-25 一年级上·河南周口·期中" + }, + { + "id": "394", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.65, + "question": "明明有 2 支铅笔,妈妈又给了他7支,他借给丽丽4支.现在明明有几支铅笔?", + "options": [ + + ], + "answer": "5支", + "solution": "【分析】明明原有的铅笔支数加上妈妈买给他的铅笔支数,减去借给丽丽的支数即是现在的铅笔支数.\n【详解】 2 + 7 - 4 = 5 (支),答: 现在明明有 5 支铅笔.", + "knowledge_points": [ + "加减混合运算(10以内)" + ], + "source": "24-25 一年级上·广西玉林·期中" + }, + { + "id": "395", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "树上有9只小鸟,飞走了5只,还剩几只小鸟?\n![](images/f0aef87e4864bd661bce8fd3548772f2c7a07647cedbc0e6d5956f509b5765d8.jpg)", + "options": [ + + ], + "answer": "4只", + "solution": "【分析】如图,树上原有 9 只鸟,减去飞走的 5 只,即可计算出还剩几只鸟.\n【详解】 9 - 5 = 4 (只),答: 还剩 4 只小鸟.", + "knowledge_points": [ + "图文问题", + "8,9 的加减法" + ], + "source": "24-25一年级上·河南驻马店·期中" + }, + { + "id": "396", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "一共有9只小兔,房子外面有3只,房子里面有几只?\n![](images/6420bec8cdc69fb4b2bcfce67e64ef2a2f1980a54a3aa08f3aa1658a5a8c82dc.jpg)\n![](images/edfb944e600278ceb7198649902d3f3e3966d83bed5402a18ef33953d2c56d5f.jpg)", + "options": [ + + ], + "answer": "6只", + "solution": "【分析】如图,用兔子的总数减去房子外面的只数,即可计算出房子里面有几只.\n【详解】 9 - 3 = 6 (只);答: 房子里面有 6 只.", + "knowledge_points": [ + "图文问题", + "8,9 的加减法" + ], + "source": "24-25一年级上·河南驻马店·期中" + }, + { + "id": "397", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "两只小猴在吃桃子.它们一共吃了几个桃子?\n![](images/34f7c5b0fbf50c8b03348e7dcacaedbd93190b38747366ece20b73103ceb5516.jpg)\n![](images/15be1ad12066d6fb1872c1f8fddf0148ba5f21257e4997f2660640f38b33f452.jpg)", + "options": [ + + ], + "answer": "8个", + "solution": "【分析】由题意可知, 两只小猴各吃了 4 个桃子, 用加法把两只小猴吃的桃子数量相加, 求出和即可解答.\n【详解】 4 + 4 = 8 (个);答: 它们一共吃了 8 个桃子.", + "knowledge_points": [ + "图文问题", + "8,9的加减法" + ], + "source": "24-25一年级上·河南驻马店·期中" + }, + { + "id": "398", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "泥塑是一种用黏土塑制成各种形象的古老民间手工艺术.小方买了8个泥塑娃娃,送给小东2个泥塑娃娃,小方现在还剩多少个泥塑娃娃?", + "options": [ + + ], + "answer": "6 个", + "solution": "【分析】用小方买的总个数减送给小东的个数即可求出小方现在还剩多少个泥塑娃娃.\n【详解】 8 - 2 = 6 (个);答: 小方现在还剩 6 个泥塑娃娃.", + "knowledge_points": [ + "8,9 的加减法" + ], + "source": "24-25一年级上·河南濮阳·期中" + }, + { + "id": "399", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "妈妈买回10个苹果,吃了一些后, 剩下6个, 吃了多少个苹果?", + "options": [ + + ], + "answer": "4 个", + "solution": "【分析】用买回的个数减去剩下的个数, 即可求出吃了多少个苹果.\n【详解】 10 - 6 = 4 (个);答: 吃了 4 个苹果.", + "knowledge_points": [ + "10 的加减法" + ], + "source": "24-25一年级上·河北邯郸·期中" + }, + { + "id": "400", + "unit": "第二单元 6-10的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.65, + "question": "小河水呀哗啦啦,一行小鸭水上划.其中有只小花鸭, 伸长脖子叫嘎嘎.顺着数呀它第三,倒着一数它第六.多少小鸭水上划,算对心里乐开花.一共有多少只小鸭?", + "options": [ + + ], + "answer": "8只", + "solution": "【分析】顺着数小花鸭排第 3,倒着数小花鸭排第 6,这样小花鸭就数了 2 次;则先把 3 和 6 加起来,求出和,再减去 1(小花鸭多数了 1 次),求出差,就表示小鸭的总数量.\n【详解】 3 + 6 - 1 = 9 - 1 = 8 (只);答: 一共有 8 只小鸭.", + "knowledge_points": [ + "加减混合运算 (10 以内)" + ], + "source": "24-25一年级上·河南濮阳·期中" + } +] \ No newline at end of file diff --git "a/\344\270\200\345\271\264\347\272\247\351\242\230\351\233\206/\344\270\200\345\271\264\347\272\247\344\270\212/\344\270\200\345\271\264\347\272\247\344\270\212\347\254\254\344\272\224\345\215\225\345\205\20320\344\273\245\345\206\205\347\232\204\350\277\233\344\275\215\345\212\240\346\263\225.json" "b/\344\270\200\345\271\264\347\272\247\351\242\230\351\233\206/\344\270\200\345\271\264\347\272\247\344\270\212/\344\270\200\345\271\264\347\272\247\344\270\212\347\254\254\344\272\224\345\215\225\345\205\20320\344\273\245\345\206\205\347\232\204\350\277\233\344\275\215\345\212\240\346\263\225.json" new file mode 100644 index 0000000000000000000000000000000000000000..27d4fe36eb56f374b1e5c82a1e8693eddcab5b73 --- /dev/null +++ "b/\344\270\200\345\271\264\347\272\247\351\242\230\351\233\206/\344\270\200\345\271\264\347\272\247\344\270\212/\344\270\200\345\271\264\347\272\247\344\270\212\347\254\254\344\272\224\345\215\225\345\205\20320\344\273\245\345\206\205\347\232\204\350\277\233\344\275\215\345\212\240\346\263\225.json" @@ -0,0 +1,7839 @@ +[ + { + "id": "1", + "unit": "第五单元20以内的进位加法1", + "question_type": "选择题", + "difficulty": 0.65, + "question": "从9开始3个3个地数,12 和 18 中间的数是( )。", + "options": [ + "A. 14", + "B. 15", + "C. 16" + ], + "answer": "B", + "solution": "【分析】从9开始3个3个地数,也就是后一个数比前一个数多3,从9开始,依次加3,计算出结果,选择12和18之间的数即可.\n【详解】 9 + 3 = 12;~ 12 + 3 = 15;~ 15 + 3 = 18 这组数字为9,12,15,18。 则12和18之间的数是 15故答案为:B", + "knowledge_points": [ + "9 加几的进位加法", + "不进位加法(20 以内)" + ], + "source": "24-25一年级上·湖南湘西·期末" + }, + { + "id": "2", + "unit": "第五单元20以内的进位加法1", + "question_type": "选择题", + "difficulty": 0.85, + "question": "算式得数最大的是( )。", + "options": [ + "A. 4+9", + "B. 19-4", + "C. 12+2" + ], + "answer": "B", + "solution": "【分析】算出各算式的得数,然后比较得数大小。20 以内的数从小到大排列是: 1 < 2 < 3 < 4 < 5 < 6 < 7 < 8 <9 < 10 < 11<12<13<14<15<16<17<18<19<20.\n【详解】A。 4 + 9 = 13 B。19-4=15 C. 12 + 2 = 1413<14<15 算式得数最大的是19-4。故答案为:B", + "knowledge_points": [ + "9 加几的进位加法", + "5 ∼ 2 加几的进位加法", + "20 以内数的比大小", + "不退位减法(20 以内)" + ], + "source": "24-25 一年级下·广东揭阳·阶段练习" + }, + { + "id": "3", + "unit": "第五单元20以内的进位加法1", + "question_type": "选择题", + "difficulty": 0.85, + "question": "体育课上,一班的同学领走了8个足球后,还剩7个足球,原来一共有多少个足球。正确的算式是( )。", + "options": [ + "A. 8-7", + "B. 8+7", + "C. 15-8" + ], + "answer": "B", + "solution": "【分析】用领走的个数加还剩的个数即可求出原来一共多 少个.\n【详解】体育课上,一班的同学领走了8个足球后,还剩7个足球,原来一共有多少个足球。正确的算式是8+7或7+8。故答案为:B", + "knowledge_points": [ + "8加几的进位加法", + "7,6加几的进位加法" + ], + "source": "24-25 一年级上·云南保山·期末" + }, + { + "id": "4", + "unit": "第五单元20以内的进位加法1", + "question_type": "选择题", + "difficulty": 0.65, + "question": "能用算式\"9+7\"解决的是第( )。", + "options": [ + "A. 小丽有 9 本书,看过了 7 本。还有几本书没有看。", + "B. 小丽已经看了 7 本书,还有 9 本书没有看。小丽要看几本书。", + "C. 小丽有 9 本故事书,7 本漫画书。再买几本漫画书就和故事书同样多。" + ], + "answer": "B", + "solution": "【分析】加法算式表示两个数的和,减法算式表示两个数的差,由此分析解答.\n【详解】A。求还没看的数量,用书的总数量-看过的数量计算,即 9-7,不符合题意;B。求要看的总数量,用还没看的数量+已经看了的数量,即 9 + 7,符合题意;C。根据减法的意义,故事书的数量-漫画书的数量 =和故事书同样多时,要再买漫画书的数量,即9-7,不符合题意;则能用算式\"9+7\"解决的是小丽已经看了7本书,还有9本书没有看。小丽要看几本书。故答案为:B", + "knowledge_points": [ + "8,9的加减法", + "9加几的进位加法" + ], + "source": "24-25 一年级下·江西吉安·阶段练习" + }, + { + "id": "5", + "unit": "第五单元20以内的进位加法1", + "question_type": "选择题", + "difficulty": 0.85, + "question": "4+( )<12,()里不可能填( )。", + "options": [ + "A. 8", + "B. 3", + "C. 5" + ], + "answer": "A", + "solution": "【分析】用4和每个选项的数相加,哪个和等于或大于 12,就选哪个.\n【详解】A。 4 + 8 = 12 , 12 = 12,因此括号里不可能填 8,符合题意;B. 4 + 3 = 7 , 7 < 12,因此括号里可能填 3,不符合题意;C. 4 + 5 = 9 , 9 < 12,因此括号里可能填 5,不符合题意。 故答案为:A", + "knowledge_points": [ + "8,9 的加减法", + "5 ∼ 2 加几的进位加法", + "7 的加减法", + "20以内数的比大小" + ], + "source": "24-25 一年级上·山东济南·期末" + }, + { + "id": "6", + "unit": "第五单元20以内的进位加法1", + "question_type": "选择题", + "difficulty": 0.65, + "question": "下面可以用算式\"9-2-3\"来解决的是( )。", + "options": [ + "A. 爸爸要贴 9 副春联,已经贴了 2 副,还剩几副没有贴。", + "B. 彩娃盘子里有9个饺子,先吃了2个,又吃了3个,盘子里还有几个饺子。", + "C. 彩娃和爸爸一起买年货,买了 9 种,还有 3 种没有买,原来需要买几种年货。" + ], + "answer": "B", + "solution": "【分析】求两者之间的差用减法计算。求两者之和用加法计算。逐项分析.\n【详解】A。用 9-2 解决;B。用算式\"9-2-3\"来解决;C。用 9+3 解决。可以用算式\"9-2-3\"来解决的是:彩娃盘子里有9个饺子,先吃了 2 个,又吃了 3 个,盘子里还有几个饺子。故答案为:B", + "knowledge_points": [ + "9加几的进位加法", + "5 ∼ 2 加几的进位加法", + "连加,连减(10 以内)" + ], + "source": "24-25 一年级上·河南南阳·期末" + }, + { + "id": "7", + "unit": "第五单元20以内的进位加法1", + "question_type": "选择题", + "difficulty": 0.85, + "question": "7+□ >11,□里最小可以填( )。", + "options": [ + "A. 4", + "B. 5", + "C. 6" + ], + "answer": "B", + "solution": "【分析】根据题意可知,因为 7 + 4 = 11,所以 7 加上比 4 大的数,和都比 11 大,题目中 里求最小填几,找到比 4 大的数中最小的数填空即可.\n【详解】根据分析可得:7 + 4 = 11,比4大的数有:5,6,7,8,。其中最小的是5, 7 + 5 = 12 > 11,所以□ 里最小可以填 5 。故答案为:B", + "knowledge_points": [ + "7,6加几的进位加法", + "20以内数的比大小" + ], + "source": "24-25一年级上·湖南湘西·期末" + }, + { + "id": "8", + "unit": "第五单元20以内的进位加法1", + "question_type": "选择题", + "difficulty": 0.85, + "question": "与 8 + 6 得数相同的算式是( )。", + "options": [ + "A. 8+9", + "B. 6+7", + "C. 9+5" + ], + "answer": "C", + "solution": "【分析】算出各算式的得数,然后找出得数相同的算式即可.\n【详解】 8 + 6 = 14 A. 8 + 9 = 17 B。6+7=13 C。9+5=14 与 8 + 6 得数相同的算式是 9 + 5。故答案为:C", + "knowledge_points": [ + "9 加几的进位加法", + "5 ∼ 2 加几的进位加法", + "7,6加几的进位加法" + ], + "source": "24-25 一年级下·河南周口·阶段练习" + }, + { + "id": "9", + "unit": "第五单元20以内的进位加法1", + "question_type": "选择题", + "difficulty": 0.85, + "question": "下面算式的结果和 5+9相等的是( )。", + "options": [ + "A. 4+10", + "B. 16-3", + "C. 8+7" + ], + "answer": "A", + "solution": "【分析】算出各算式的结果然后作对比.\n【详解】 5 + 9 = 14 A. 4 + 10 = 14,相等;B. 16 - 3 = 13,不相等;C. 8 + 7 = 15,不相等。算式的结果和 5+9 相等的是 4 + 10 故答案为:A", + "knowledge_points": [ + "5 ∼ 2 加几的进位加法", + "8 加几的进位加法", + "不进位加法(20以内)", + "不退位减法(20以内)" + ], + "source": "24-25 一年级上·安徽黄山·期末" + }, + { + "id": "10", + "unit": "第五单元20以内的进位加法1", + "question_type": "选择题", + "difficulty": 0.65, + "question": "差是 13 的算式是()。", + "options": [ + "A. 11+2", + "B. 7+6", + "C. 14-1" + ], + "answer": "C", + "solution": "【分析】减法算式为被减数-减数 = 差,加法算式为加数+加数 = 和,由此计算选择差是13的算式即可.\n【详解】A。 11 + 2 = 13,和是13,不符合题意;B. 7 + 6 = 13,和是13,不符合题意;C. 14 - 1 = 13,差是 13,符合题意。差是 13 的算式是 14 - 1 = 13 ext 故答案为:C", + "knowledge_points": [ + "7,6 加几的进位加法", + "不进位加法(20 以内)", + "不退位减法(20 以内)" + ], + "source": "24-25 一年级上·浙江宁波·期末" + }, + { + "id": "11", + "unit": "第五单元20以内的进位加法1", + "question_type": "选择题", + "difficulty": 0.85, + "question": "下面算式得数与8+5 不相同的是( )。", + "options": [ + "A. 5+8", + "B. 7+6", + "C. 2+10" + ], + "answer": "C", + "solution": "【分析】根据整数加减法的计算法则,算出每个算式的得数,然后找出得数不同的算式即可.\n【详解】 8 + 5 = 13 A. 5 + 8 = 13;B. 7 + 6 = 13;C. 2 + 10 = 12;即,得数与 8 + 5 不相同的算式是 2 + 10 。 故答案为:C", + "knowledge_points": [ + "5 ∼ 2 加几的进位加法", + "8 加几的进位加法", + "7,6加几的进位加法", + "不进位加法(20以内)" + ], + "source": "24-25一年级上·河南郑州·期末" + }, + { + "id": "12", + "unit": "第五单元20以内的进位加法1", + "question_type": "选择题", + "difficulty": 0.65, + "question": "下列算式中得数最大的那个是( )。", + "options": [ + "A. 5+9", + "B. 14-1", + "C. 8+4" + ], + "answer": "A", + "solution": "【分析】根据整数加减法的计算法则,依次计算出各算式的结果再比较大小。20 以内数从大到小关系为: 20 { > } 19 { > } 18>17>16>15>14>13>12>11>10>9>8>7>6>5>4 { > } 3 { > } 2 { > } 1 { > } 0,由此比较.\n【详解】A。 5 + 9 = 14 B. 14 - 1 = 13 。;C. 8 + 4 = 12;14>13>12 则得数最大的是 5 + 9 。故答案为:A", + "knowledge_points": [ + "5 ∼ 2 加几的进位加法", + "8 加几的进位加法", + "20 以内数的比大小", + "不退位减法(20以内)" + ], + "source": "24-25 一年级上·浙江宁波·期末" + }, + { + "id": "13", + "unit": "第五单元20以内的进位加法1", + "question_type": "选择题", + "difficulty": 0.85, + "question": "计算9+5时,可以这样计算: 9 + 1 = 10 , 10 + 4 = 14,下面与这种计算方法相同的是( )。", + "options": [ + "A. 10+5-1", + "B. ![](images/3be521d6eaf67efa1ff65c11fc2841177902c2799c0c63309f7150eab478c853.jpg)", + "C. ![](images/d0b63c515bc31ce5cded161217daa92b8e66dfe7345b1989f08574874e2bbe9d.jpg)" + ], + "answer": "C", + "solution": "【分析】根据题意,逐项分析各个算式,找出正确答案即可解答.\n【详解】A。把9看成10,先算 10 + 5 = 15,再把多算的1减去, 15 - 1 = 14,与原题的计算方法不相同,答案不正确;B。把 9 分成 5 和 4,先算 5 + 5 = 10,再算 10 + 4 = 14,与原题的计算方法不相同,答案不正确;C。左边9个圆圈加上右边的1个圆圈,再加上剩下的4个圆圈,可以这样计算: 9 + 1 = 10 , 10 + 4 = 14,与原题的计算方法相同,答案正确;故答案为:C", + "knowledge_points": [ + "9加几的进位加法" + ], + "source": "24-25一年级上·四川广元·期末" + }, + { + "id": "14", + "unit": "第五单元20以内的进位加法1", + "question_type": "选择题", + "difficulty": 0.85, + "question": "下面的 3 盒面包中有 2 盒是小明的,小明最少有( )个面包.\n\n![](images/abf4f27e4d40ae8d5e709ce655d4aaa5.jpg)", + "options": [ + "A. 17", + "B. 14", + "C. 12" + ], + "answer": "B", + "solution": "【分析】通过观察图片可知,三盒面包的数量分别是6个,8 个,9 个,小明有 2 盒,最少有多少个,将数量比较少的两盒相加,算出他有多少个面包即可.\n【详解】根据分析可得:6 + 8 = 14 (个)小明最少有 14 个。故答案为:B", + "knowledge_points": [ + "8加几的进位加法" + ], + "source": "24-25 一年级上·湖北襄阳·期末" + }, + { + "id": "15", + "unit": "第五单元20以内的进位加法1", + "question_type": "填空题", + "difficulty": 0.85, + "question": "计算 8+5 可以这样想:先将 5 分成( )和( ),再用 8 加上( )得 10,最后再与( )相加,结果是( )。", + "options": [], + "answer": "2;3;2;3;13", + "solution": "【分析】根据\"凑十法\"可以先将5分成2和3,然后用8加上 2 等于 10,然后再与 3 相加,即结果 10 + 3 = 13,则 8+5=13.\n【详解】由分析可得:计算 8+5 可以这样想:先将 5 分成(2)和(3),再用 8加上(2)得 10,最后再与(3)相加,结果是(13)。", + "knowledge_points": [ + "8加几的进位加法" + ], + "source": "24-25 一年级上·广东潮州·期末" + }, + { + "id": "16", + "unit": "第五单元20以内的进位加法1", + "question_type": "填空题", + "difficulty": 0.85, + "question": "计算 9 + 6 时,我们可以把 6 分成( )和( ),先算( ) + ( ) = ( ) , 再算( )+( )=( )。", + "options": [], + "answer": "1;5;9;1;10;10;5;15", + "solution": "【分析】20以内的进位加法计算时,可以用凑十法计算,即将其中一个加数分成两部分,一部分与另一个加数凑成十,十再加上剩下的另一部分就是十几.\n【详解】计算9+6时,我们可以把6分成1和5,先算 9 +1 = 10,再算 10 + 5 = 15 。", + "knowledge_points": [ + "9加几的进位加法" + ], + "source": "24-25 一年级下·新疆喀什·开学考试" + }, + { + "id": "17", + "unit": "第五单元20以内的进位加法1", + "question_type": "填空题", + "difficulty": 0.65, + "question": "学校合唱比赛时,丽丽和其他成员站成一排,丽丽的左边有 6 人,右边有 7 人,这一排有( )人。", + "options": [], + "answer": "14", + "solution": "【分析】用丽丽左边的人数加右边的人数,再加丽丽即可求解.\n【详解】 6 + 7 + 1 = 14 (人)这一排有14人。", + "knowledge_points": [ + "左,右位置", + "连加(20 以内)" + ], + "source": "24-25 一年级上·湖北荆州·期末" + }, + { + "id": "18", + "unit": "第五单元20以内的进位加法1", + "question_type": "填空题", + "difficulty": 0.65, + "question": "两个加数都是 8,和是( ),它后面第 4 个数是( )。", + "options": [], + "answer": "16;20", + "solution": "【分析】加法算式为加数+加数 = 和,由此代入计算;根据20以内数的顺序,一个一个地往后数,找出它后面的第4 个数即可.\n【详解】 8 + 8 = 1616后面的第一个数是17,第二个数是18,第三个数是19,第四个数是 200 两个加数都是 8,和是 16,它后面第 4 个数是 20 ", + "knowledge_points": [ + "8 加几的进位加法", + "20 以内数的排序" + ], + "source": "24-25 一年级上·河南周口·期末" + }, + { + "id": "19", + "unit": "第五单元20以内的进位加法1", + "question_type": "填空题", + "difficulty": 0.65, + "question": "在( )里填上合适的数.\n\n\n( ) + 9 = 1714 - ( ) = 48 + ( ) = 14\n\n\n\n19 - ( ) = 10 ( ) - 3 = 4 \n", + "options": [], + "answer": "8;10;6;9;7", + "solution": "【分析】第 1,3 题根据凑十法计算,即将已知的一个加数凑成十,10再加几就是十几;第 2,4 题根据被减数-差 = 减数计算;第 5 题根据减数+差 = 被减数计算.\n【详解】9 和 1 合起来就是 10,再加上 7 就是 17,即 8+9= 17;14 - 4 = 10;则 14 - 10 = 4;8 和 2 合起来就是 10,再加上 4 就是 14,即 8 + 6 = 1419 - 10 = 9,则 19 - 9 = 10;3 + 4 = 7。", + "knowledge_points": [ + "9加几的进位加法", + "8加几的进位加法", + "10的加减法", + "不退位减法(20 以内)" + ], + "source": "24-25 一年级上·山西晋中·期末" + }, + { + "id": "20", + "unit": "第五单元20以内的进位加法1", + "question_type": "填空题", + "difficulty": 0.65, + "question": "小朋友排队放学,小方前面有 8 人,后面有 6 人,这一队一共有( )人。", + "options": [], + "answer": "15", + "solution": "【分析】用小方前面的人数加后面的人数再加小方即可求出一共多少人.\n【详解】 8 + 6 + 1 = 15 (人)这一队一共有15人。", + "knowledge_points": [ + "前,后位置", + "连加(20以内)" + ], + "source": "24-25一年级上·云南保山·期末" + }, + { + "id": "21", + "unit": "第五单元20以内的进位加法1", + "question_type": "填空题", + "difficulty": 0.65, + "question": "8 加 5 的和是( ),这个数再加上( )个一是 20。", + "options": [], + "answer": "13;7", + "solution": "【分析】加数+加数 = 和,8和5都是加数,直接计算即可。一个一个的数,往后面数几个到20就需要加上几个一.\n【详解】 8 + 5 = 138 加 5 的和是 13,这个数再加上 7 个一是 20", + "knowledge_points": [ + "5 ∼ 2 加几的进位加法", + "8加几的进位加法", + "20以内数的排序" + ], + "source": "24-25 一年级上·河南周口·期末" + }, + { + "id": "22", + "unit": "第五单元20以内的进位加法1", + "question_type": "填空题", + "difficulty": 0.65, + "question": "同学们排队站成一列,从前面数,小红排第4,从后面数,小红排第7,这一列一共有( )人。", + "options": [], + "answer": "10", + "solution": "【分析】根据题意,从前数到小红有4人,从后数到小红有7人,都数了小红,也就是多数了1次,则用从前数到小红的人数+从后数到小红的人数-1(重复计算的小红) = 总人数.\n【详解】 4 + 7 - 1 = 10 (人)同学们排队站成一列,从前面数,小红排第4,从后面数,小红排第 7,这一列一共有 10 人。", + "knowledge_points": [ + "加减混合运算(20 以内)" + ], + "source": "24-25一年级上·山东济南·期末" + }, + { + "id": "23", + "unit": "第五单元20以内的进位加法1", + "question_type": "填空题", + "difficulty": 0.65, + "question": "小朋友排队,从前往后数,小红是第 3 人,从后往前数,小红是第 8 人,这一队一共有( )人。", + "options": [], + "answer": "10", + "solution": "【分析】根据题意,从前往后和从后往前都数了小红,多数了1次小红,则用从前往后数到小红的人数+从后往前数到小红的人数- 1 = 总人数.\n【详解】 3 + 8 - 1 = 10 (人)小朋友排队,从前往后数,小红是第3人,从后往前数,小红是第 8 人,这一队一共有 10 人。", + "knowledge_points": [ + "加减混合运算(20 以内)" + ], + "source": "24-25 一年级上·山东济宁·期末" + }, + { + "id": "24", + "unit": "第五单元20以内的进位加法1", + "question_type": "填空题", + "difficulty": 0.65, + "question": "比 8 多 7 的数是(),( )比 14 少 4。", + "options": [], + "answer": "15;10", + "solution": "【分析】求比一个数多几的数用加法计算。求比一个数少多少的数用减法计算.\n【详解】 8 + 7 = 1514 - 4 = 10 比 8 多 7 的数是 15,10 比 14 少 4。", + "knowledge_points": [ + "8 加几的进位加法", + "不退位减法(20 以内)" + ], + "source": "24-25 一年级上·河南南阳·期末" + }, + { + "id": "25", + "unit": "第五单元20以内的进位加法1", + "question_type": "填空题", + "difficulty": 0.85, + "question": "被减数是 20,减数是 10,差是( );两个相同的数相加的和是14,这两个数都是( )。", + "options": [], + "answer": "10;7", + "solution": "【分析】根据\"被减数-减数 = 差\",代入计算即可;两个相同加数的和是14,和超过了10,因为5和5合起来是10,所以从加数为6开始计算,看哪两个相同的数相加为14 即可.\n【详解】 20 - 10 = 107+7=14 被减数是 20,减数是 10,差是 10;两个相同的数相加的和是 14,这两个数都是 7。", + "knowledge_points": [ + "7,6 加几的进位加法", + "不退位减法(20 以内)" + ], + "source": "24-25 一年级上·湖北襄阳·期末" + }, + { + "id": "26", + "unit": "第五单元20以内的进位加法1", + "question_type": "填空题", + "difficulty": 0.65, + "question": "括号里最大可以填几。\n\n\n9 + ( ) < 1519 - ( ) > 1012 + ( ) < 17\n", + "options": [], + "answer": "5;8;4", + "solution": "【分析】第1题:比15小的数有14,13,12。其中最大的是 14,则左侧结果为 14 时填写的数最大,根据凑十法计算;第2题:比10大的数有11,12,13。要想填写的数最大,则左侧算式的结果应为比10大的数中最小的数11,根据被减数-差 = 减数计算;第3题:比17小的数有16,15,14。其中最大的是16,则左侧结果为16时填写的数最大,根据和-一个加数 = 另一个加数计算.\n【详解】9和1合起来就是10,再加上4就是14,即 9 + 5 <15,括号里最大能填 5;19 - ~ ( ) ~ = 11 , 19 - 11 = 8,则 19 - 8 > 10,括号里最大能填 8;12 + ( ) \\ = 16 , 16 - 12 = 4,则 12 + 4 < 17,括号里最大能填 4 \n, 。", + "knowledge_points": [ + "9 加几的进位加法", + "20 以内数的比大小", + "不退位减法(20 以内)" + ], + "source": "24-25 一年级上·贵州黔东南·期末" + }, + { + "id": "27", + "unit": "第五单元20以内的进位加法1", + "question_type": "填空题", + "difficulty": 0.85, + "question": "在括号里填上 \">\"\"<\"或 ''=''.\n\n11( )1214( )5+87+6( )13", + "options": [], + "answer": "<;>;=", + "solution": "【分析】有算式先算出算式的得数,再根据 20 以内整数比较大小的方法进行比较即可.\n【详解】 11 < 125 + 8 = 13 , 14 > 13,所以 14 > 5 + 87 + 6 = 13", + "knowledge_points": [ + "5 ∼ 2 加几的进位加法", + "7,6 加几的进位加法", + "20以内数的比大小" + ], + "source": "24-25一年级上·广西贵港·期末" + }, + { + "id": "28", + "unit": "第五单元20以内的进位加法1", + "question_type": "填空题", + "difficulty": 0.65, + "question": "在括号里填上 \">\"\"<\"或\"=\".\n\n7 + 9 ( ) 125 + 8 ( ) 15 - 210 - 4 ( ) 9 + 33 ( ) 14 - 109 + 1 ( ) 10 - 017 - 7 ( ) 6 + 3", + "options": [], + "answer": ">;=;<;<;=;>", + "solution": "【分析】根据整数加减法的计算法则,依次计算出各算式的结果再比较大小,20以内数从大到小关系为 20 { > } 19 { > } 18 >17>16>15>14>13>12>11>10>9>8>7>6>5>4{ > } 3 { > } 2 { > } 1 { > } 0,由此比较.\n【详解】 7 + 9 = 16;16 > 12,则 7 + 9 > 12;5 + 8 = 13;~ 15 - 2 = 13;~ 13 = 135 + 8 = 1313 = 13,则 5 + 8 = 15 - 2;10 - 4 = 6;\\ 9 + 3 = 12;\\ 6 < 129 + 3 = 126 < 12,则 10 - 4 < 9 + 3;;14-10=4;3 { < } 4,则 3 { < } 14 - 10;;9 + 1 = 10;\\ 10 - 0 = 10;\\ 10 = 109 + 1 = 1010 = 10,则 9 + 1 = 10 - 0;17 - 7 = 10;6 + 3 = 9;10 { > } 9,则 17 - 7 > 6 + 3 。", + "knowledge_points": [ + "5 ∼ 2 加几的进位加法", + "7,6 加几的进位加法", + "20以内数的比大小", + "不退位减法(20 以内)" + ], + "source": "24-25一年级上·湖北孝感·期末" + }, + { + "id": "29", + "unit": "第五单元20以内的进位加法1", + "question_type": "填空题", + "difficulty": 0.65, + "question": "亮亮在排队等公交车,他前面有 6 个人,后面有 7 人,一共有( )人在等公交车。", + "options": [], + "answer": "14", + "solution": "【分析】用亮亮前面的人数加后面的人数再加亮亮即可求出一共多少人.\n【详解】 6 + 7 + 1 = 14 (人)一共有 14 人在等公交车。", + "knowledge_points": [ + "前,后位置", + "连加(20 以内)" + ], + "source": "24-25 一年级上·安徽黄山·期末" + }, + { + "id": "30", + "unit": "第五单元20以内的进位加法1", + "question_type": "填空题", + "difficulty": 0.85, + "question": "两个加数都是8,和是( );被减数是 16,减数是 6,差是( )。", + "options": [], + "answer": "16;10", + "solution": "【分析】加数+加数 = 和,被减数-减数 = 差,据此列式计算.\n【详解】 8 + 8 = 1616 - 6 = 10两个加数都是 8,和是 16;被减数是 16,减数是 6,差是10。", + "knowledge_points": [ + "8加几的进位加法", + "不退位减法(20以内)" + ], + "source": "24-25 一年级上·江西赣州·期末" + }, + { + "id": "31", + "unit": "第五单元20以内的进位加法1", + "question_type": "填空题", + "difficulty": 0.65, + "question": "在括号里填上\">\"\"<\"或\"=\".\n\n5+9( )151 个十和 5 个一( )203+9( )5+8\n\n6+8( )1617-7( )96+3( )19-10", + "options": [], + "answer": "<;<;<;<;>;=", + "solution": "【分析】根据题意,依次计算出各算式的结果或写出各数再比较大小。20 以内数从大到小关系为: 20 > 19 > 18 > 17 >16>15>14>13>12>11>10>9>8>7>6>5>4>3>2 { > } 1 { > } 0,由此比较.\n【详解】 5 + 9 = 14;14 < 15,则 5 + 9 { < } 15;1 个十是 10,5 个一是 5,合起来是 15;15 { < } 20,则 1 个十\n和 5 个一<20;3 + 9 = 12;\\ 5 + 8 = 13;\\ 12 < 1312 < 13,则 3 + 9 < 5 + 8;6 + 8 = 14;14<16,则 6 + 8 { < } 16 ;17 - 7 = 10;10 { > } 9,则 17 - 7 > 9;6 + 3 = 9;19 - 10 = 9;9 = 9,则 6 + 3 = 19 - 10 ", + "knowledge_points": [ + "20 以内数的组成", + "5 ∼ 2 加几的进位加法", + "20 以内数的比大小", + "不退位减法(20以内)" + ], + "source": "24-25 一年级上·江西赣州·期末" + }, + { + "id": "32", + "unit": "第五单元20以内的进位加法1", + "question_type": "填空题", + "difficulty": 0.65, + "question": "在( )里填上合适的数.\n\n5 + ( ) = 1310 - ( ) = 34 + ( ) = 9\n\n9 + ( ) = 144 + ( ) = 14 ( ) + 9 = 13", + "options": [], + "answer": "8;7;5;5;10;4", + "solution": "【分析】第1,4,6题根据凑十法解答,即将其中一个加数凑成10,10再加几就是十几;第2题根据被减数-差 = 减数计算;第 3,5 题根据和-一个加数 = 另一个加数计算。 \n【详解】5 和 5 合起来就是 10,再加上 3 就是 13,即 5+8= 13;10 - 3 = 7,则 10 - 7 = 3;9 - 4 = 5,则 4 + 5 = 9;9 和 1 合起来就是 10,再加上 4 就是 14,即 9 + 5 = 14;14 - 4 = 10,则 4 + 10 = 14;9 和 1 合起来就是 10,再加上 3 就是 13,即 4 + 9 = 13 。", + "knowledge_points": [ + "9 加几的进位加法", + "5 ∼ 2 加几的进位加法", + "10 的加减法", + "不退位减法(20以内)" + ], + "source": "24-25一年级上·甘肃陇南·期末" + }, + { + "id": "33", + "unit": "第五单元20以内的进位加法1", + "question_type": "填空题", + "difficulty": 0.65, + "question": "被减数是 17,减数是 2,差是( );两个相同数的和是 16,这个数是( )。", + "options": [], + "answer": "15;8", + "solution": "【分析】减法算式为被减数-减数 = 差;两个相同数的和是16,根据8和8合起来就是16即可解答.\n【详解】 17 - 2 = 15;8 + 8 = 16 被减数是 17,减数是 2,差是 15;两个相同数的和是 16,这个数是 8 。", + "knowledge_points": [ + "8加几的进位加法", + "不退位减法(20以内)" + ], + "source": "24-25 一年级上·贵州铜仁·期末" + }, + { + "id": "34", + "unit": "第五单元20以内的进位加法1", + "question_type": "填空题", + "difficulty": 0.85, + "question": "有 8 名女生站成一排,老师让每相邻两名女生之间站一名男生,一共可以站( )名男生。现在一共有( )名学生。", + "options": [], + "answer": "7;15", + "solution": "【分析】(1)根据题意可知:在2女生之间,站1名男生,在3名女生之间,可以站2名男生,在4名女生之间,可以站3名男生,即有多少名男生,男生的数量比其少1,则图中有7名男生,即 8 - 1 = 7 (名) .\n(2)由(1)求出男生的人数加上女生的人数即可求出共有的人数即可.\n【详解】 8 - 1 = 7 (名)7 + 8 = 15 (名)则一共可以站 7 名男生。现在一共有 15 名学生。", + "knowledge_points": [ + "8,9 的加减法", + "7,6 加几的进位加法" + ], + "source": "24-25 一年级下·全国·期中" + }, + { + "id": "35", + "unit": "第五单元20以内的进位加法1", + "question_type": "填空题", + "difficulty": 0.65, + "question": "比 19 少 9 的数是(),比 5 多 9 的数是( )。", + "options": [], + "answer": "10;14", + "solution": "【分析】求比一个数少几的数是多少,用这个数-少的数计算;求比一个数多几的数是多少,用这个数+多的数计算.\n【详解】 19 - 9 = 105 + 9 = 14 比19少9的数是10,比5多9的数是 14", + "knowledge_points": [ + "5 ∼ 2 加几的进位加法", + "不退位减法(20 以内)" + ], + "source": "24-25 一年级上·江西赣州·期末" + }, + { + "id": "36", + "unit": "第五单元20以内的进位加法1", + "question_type": "填空题", + "difficulty": 0.85, + "question": "被减数是 16,减数是 3,差是( );两个加数都是 8,和是( )。", + "options": [], + "answer": "13;16", + "solution": "【分析】已知,被减数是 16,减数是 3,根据被减数-减数= 差,即可计算出差是多少;已知两个加数都是8,根据加数+加数 = 和,即可计算出和是多少.\n【详解】16-3=13;8 + 8 = 16 被减数是16,减数是3,差是13;两个加数都是8,和是16。", + "knowledge_points": [ + "两位数与一位数的减法(不退位)", + "8加几的进位加法" + ], + "source": "24-25 一年级上·福建龙岩·期末" + }, + { + "id": "37", + "unit": "第五单元20以内的进位加法1", + "question_type": "填空题", + "difficulty": 0.85, + "question": "我排队买包子,前面有 9 人,后面有 7 人,一共有( )人。", + "options": [], + "answer": "17", + "solution": "【分析】先把我前面的人数与后面的人数加起来,求出和,再加上 1,求出和就是一共的人数.\n【详解】 9 + 7 + 1 = 17 (人)即,我排队买包子,前面有 9 人,后面有 7 人,一共有 17人。", + "knowledge_points": [ + "连加(20 以内)" + ], + "source": "24-25 一年级上·河北沧州·期末" + }, + { + "id": "38", + "unit": "第五单元20以内的进位加法1", + "question_type": "填空题", + "difficulty": 0.85, + "question": "为了鼓励同学们好好学习,张老师带了男同学,女同学各 8 人去电影院,那么一共需要买( )张电影票。", + "options": [], + "answer": "17", + "solution": "【分析】用男同学的人数加上女同学的人数再加上 1,即可求出一共需要买多少张电影票.\n【详解】 8 + 8 + 1 = 17 (张)一共需要买17张电影票。", + "knowledge_points": [ + "连加(20 以内)" + ], + "source": "24-25 一年级上·浙江温州·期末" + }, + { + "id": "39", + "unit": "第五单元20以内的进位加法1", + "question_type": "填空题", + "difficulty": 0.65, + "question": "校园里有一行树,共 13 棵,每两棵松树之间有一棵柳树。校园里一共有( )棵柳树。", + "options": [], + "answer": "6", + "solution": "【分析】根据题意,每两棵松树之间有一棵柳树,也就是柳树的数量是松树的间隔数,即松树的数量- 1 = 柳树的数量。也就是两个相邻数的和是13,其中较大的数是松树的数量,较小的数是柳树的数量,由此解答.\n【详解】 13 = 1 + 12 = 2 + 11 = 3 + 10 = 4 + 9 = 5 + 8 = 6 + 7,其中只有6和7符合题意。所以校园里一共有 7 棵松树,有 6 棵柳树。", + "knowledge_points": [ + "5 ∼ 2 加几的进位加法", + "7,6 加几的进位加法", + "不进位加法(20 以内)" + ], + "source": "24-25 一年级上·浙江温州·期末" + }, + { + "id": "40", + "unit": "第五单元20以内的进位加法1", + "question_type": "填空题", + "difficulty": 0.65, + "question": "有两个数字都有相邻数 6,那么这两个数的和是( )。", + "options": [], + "answer": "12", + "solution": "【分析】有两个数字都有相邻数6,则这两个数分别是6前一个数 5,6 后一个数 7,把 5 和 7 相加即可求出它们的和是多少,据此解答即可.\n【详解】根据分析可得:7 + 5 = 12这两个数的和是 12 。", + "knowledge_points": [ + "7,6 加几的进位加法" + ], + "source": "24-25 一年级上·浙江温州·期末" + }, + { + "id": "41", + "unit": "第五单元20以内的进位加法1", + "question_type": "填空题", + "difficulty": 0.85, + "question": "小朋友们排队做早操,小花前面有 9 个人,后面有 4 个人,这一队一共有( )人。", + "options": [], + "answer": "14", + "solution": "【分析】根据题意可知:用小花前面的人数加后面的人数再加小花 1 人。即可求出这一队一共有的人数.\n【详解】 9 + 4 + 1 = 14 (人)则这一队一共有14人。", + "knowledge_points": [ + "连加(20 以内)" + ], + "source": "24-25一年级上·河南周口·期末" + }, + { + "id": "42", + "unit": "第五单元20以内的进位加法1", + "question_type": "填空题", + "difficulty": 0.85, + "question": "两个加数都是9,和是( );被减数是 16,减数是 10,差是( )。", + "options": [], + "answer": "18;6", + "solution": "【分析】根据加数+加数 = 和,被减数-减数 = 差,即可解答.\n【详解】 9 + 9 = 1816 - 10 = 6 两个加数都是 9,和是 18;被减数是 16,减数是 10,差是6。", + "knowledge_points": [ + "9加几的进位加法", + "不退位减法(20以内)" + ], + "source": "24-25一年级上·湖北武汉·期末" + }, + { + "id": "43", + "unit": "第五单元20以内的进位加法1", + "question_type": "填空题", + "difficulty": 0.85, + "question": "比 9 多 7 的数是(),18 比( )多 10,比 6 少 2 的数是( )。", + "options": [], + "answer": "16;8;4", + "solution": "【分析】比一个数多几的数是多少,用加法计算;一个数比另一个数多几,求另一个数是多少,用减法计算;比一个数少几的数是多少,用减法计算.\n【详解】 9 + 7 = 1618 - 10 = 86 - 2 = 4 比 9 多 7 的数是 16,18 比 8 多 10,比 6 少 2 的数是 4 ", + "knowledge_points": [ + "9 加几的进位加法", + "6 的加减法", + "不退位减法(20 以内)" + ], + "source": "24-25 一年级上·四川广元·期末" + }, + { + "id": "44", + "unit": "第五单元20以内的进位加法1", + "question_type": "填空题", + "difficulty": 0.85, + "question": "同学们排队放学,小芳前面有 7 人,后面有 6 人,这一队一共有( )人。", + "options": [], + "answer": "14", + "solution": "【分析】小芳前面的人数加上后面的人数,再加上小芳本人,等于这队的总人数,据此解答.\n【详解】由分析可得:7 + 6 + 1 = 14 (人) 这队一共有14人。", + "knowledge_points": [ + "7,6 加几的进位加法", + "连加(20 以内)" + ], + "source": "24-25 一年级上·甘肃兰州·期末" + }, + { + "id": "45", + "unit": "第五单元20以内的进位加法1", + "question_type": "填空题", + "difficulty": 0.85, + "question": "8 加 7 的和是( ),这个数再加上( )个一是 20。", + "options": [], + "answer": "15;5", + "solution": "【分析】8 加 7 的和是多少,用加法计算,即 8 + 7 = 15;15是1个十和5个一组成,5个一再加上5个一可以再组成1 个十,合起来是 20。据此完成填空即可.\n【详解】由题意分析得:8 + 7 = 15 即8 加 7 的和是 15,这个数再加上 5 个一是 20。", + "knowledge_points": [ + "20以内数的组成", + "8加几的进位加法" + ], + "source": "24-25 一年级上·山东菏泽·期末" + }, + { + "id": "46", + "unit": "第五单元20以内的进位加法1", + "question_type": "填空题", + "difficulty": 0.65, + "question": "两个加数都是 7,和是( )。被减数 16,减数是 6,差是( )。", + "options": [], + "answer": "14;10", + "solution": "【分析】在加法算式中,加数 + 加数 = 和;在减法算式中,被减数-减数 = 差.\n【详解】 7 + 7 = 14 , 16 - 6 = 10,所以两个加数都是7,和是 14 被减数16,减数是6,差是 10。", + "knowledge_points": [ + "7,6 加几的进位加法", + "不退位减法(20 以内)" + ], + "source": "24-25 一年级上·广东汕头·期末" + }, + { + "id": "47", + "unit": "第五单元20以内的进位加法1", + "question_type": "填空题", + "difficulty": 0.85, + "question": "比 18 少 5 的数是();比 9 多 4 的数是( )。", + "options": [], + "answer": "13;13", + "solution": "【分析】求比一个数少多少,用减法计算;求比另一个数多多少,用加法计算。据此解答即可.\n【详解】 18 - 5 = 139 + 4 = 13 比18少5的数是13;比9多4的数是 13。", + "knowledge_points": [ + "9 加几的进位加法", + "不退位减法(20 以内)" + ], + "source": "24-25 一年级上·广东汕头·期末" + }, + { + "id": "48", + "unit": "第五单元20以内的进位加法1", + "question_type": "填空题", + "difficulty": 0.85, + "question": "7+□>13,□里最小能填( )。", + "options": [], + "answer": "7", + "solution": "【分析】比 13 大的数有 14,15,16。其中最小的是 14,只要左侧的计算结果为 14 即可得出答案.\n【详解】7 和 3 合起来就是 10,10 再加上 4 就是 14,则 7+7=14.7 + □ > 13 ,□里最小应填 7。", + "knowledge_points": [ + "7,6加几的进位加法", + "20以内数的比大小" + ], + "source": "24-25 一年级上·湖北黄石·期末" + }, + { + "id": "49", + "unit": "第五单元20以内的进位加法1", + "question_type": "填空题", + "difficulty": 0.65, + "question": "两个加数分别是 4和 8,和是( );被减数是 16,减数是 5,差是( )。", + "options": [], + "answer": "12;11", + "solution": "【分析】根据加数+加数 = 和,被减数-减数 = 差,代入数据计算即可.\n【详解】 4 + 8 = 12 , 16 - 5 = 11 故两个加数分别是4和8,和是12;被减数是16,减数是5,差是 11 。", + "knowledge_points": [ + "5 ∼ 2 加几的进位加法", + "不退位减法(20以内)" + ], + "source": "24-25 一年级上·湖南怀化·期末" + }, + { + "id": "50", + "unit": "第五单元20以内的进位加法1", + "question_type": "填空题", + "difficulty": 0.85, + "question": "被减数是 16,减数是 3,差是( );9 与 6 的和是( )。", + "options": [], + "answer": "13;15", + "solution": "【分析】被减数-减数 = 差,加数+加数 = 和,据此列式计算.\n【详解】 16 - 3 = 139 + 6 = 15 被减数是 16,减数是 3,差是 13;9 与 6 的和是 15", + "knowledge_points": [ + "9 加几的进位加法", + "7,6 加几的进位加法", + "不退位减法(20 以内)" + ], + "source": "24-25 一年级上·河北邯郸·期末" + }, + { + "id": "51", + "unit": "第五单元20以内的进位加法1", + "question_type": "判断题", + "difficulty": 0.85, + "question": "在括号里填上\">\"\"<\"或\"=\".\n\n12( )13-34+8( )6+62 个十( )208+7( )6+10", + "options": [], + "answer": ">;=;=;<", + "solution": "【分析】先根据整数加减法计算法则,计算出每个算式的结果,再比较大小即可.\n【详解】(1)左边:12,右边: 13 - 3 = 10,因为 12 > 10,所以 12 > 13 - 3;(2)左边: 4 + 8 = 12,右边: 6 + 6 = 12,因为 12 = 12,所以 4 + 8 = 6 + 6;(3)左边:2 个十是 20,右边:20,因为 20 = 20,所以 2个十 = 20;(4)左边: 8 + 7 = 15,右边: 6 + 10 = 16 , 15 { < } 16,所以 8+ 7 < 6 + 10。", + "knowledge_points": [ + "8 加几的进位加法", + "7,6 加几的进位加法", + "不进位加法(20 以内)", + "不退位减法(20 以内)" + ], + "source": "24-25一年级上·河北唐山·期末" + }, + { + "id": "52", + "unit": "第五单元20以内的进位加法1", + "question_type": "判断题", + "difficulty": 0.65, + "question": "在括号里填上\">\"\"<\"或\"=\".\n\n\n0 + 5 ( ) 412 ( ) 8 + 615 - 4 ( ) 1 + 104 + 9 ( ) 15 - 5\n", + "options": [], + "answer": ">;<;=;>", + "solution": "【分析】根据整数加减法的计算法则,依次计算出各算式的结果再比较大小。20 以内数从大到小关系为: 20 { > } 19 { > } 18>17>16>15>14>13>12>11>10>9>8>7>6>5>4 { > } 3 { > } 2 { > } 1,由此比较.\n【详解】 0 + 5 = 5;\\ 5 { > } 4,则 0 + 5 > 4;8 + 6 = 14;12 < 14,则 12 < 8 + 6;15 - 4 = 11;1 + 10 = 11;11 = 11,则 15 - 4 = 1 + 10;4 + 9 = 13;15 - 5 = 10;13 > 10,则 4 + 9 > 15 - 5。", + "knowledge_points": [ + "5 ∼ 2 加几的进位加法", + "8加几的进位加法", + "20以内数的比大小", + "不退位减法(20 以内)" + ], + "source": "24-25一年级上·河北秦皇岛·期末" + }, + { + "id": "53", + "unit": "第五单元20以内的进位加法1", + "question_type": "判断题", + "difficulty": 0.85, + "question": "在括号里填上\">\"\"<\"或\"=\".\n\n\n10 - 5 ( ) 613 + 2 ( ) 146 + 9 ( ) 1517 - 6 ( ) 12\n", + "options": [], + "answer": "<;>;=;<", + "solution": "【分析】整数的大小比较:比较数的大小,先看位数的多少,位数多的数就大;位数相同,从高位开始比较,高位上的数大则这个数大,高位上的数相同,就比较下一位。含有算式的,可以先计算出算式的结果,再比较大小.\n【详解】 10 - 5 = 5,所以 10 - 5 { < } 6; 13 + 2 = 15,所 以 13 + 2 > 14;\n 6 + 9 = 15 \n 17 - 6 = 11,所 以 17 - 6 < 12。", + "knowledge_points": [ + "10 的加减法", + "7,6 加几的进位加法", + "20 以内数的比大小", + "不退位减法(20 以内)" + ], + "source": "24-25一年级上·湖南常德·期末" + }, + { + "id": "54", + "unit": "第五单元20以内的进位加法1", + "question_type": "判断题", + "difficulty": 0.65, + "question": "一个加数是 8,另一个加数是 6,和是 15。( )", + "options": [], + "answer": "×", + "solution": "【分析】根据加数+加数 = 和即可解答.\n【详解】 8 + 6 = 14 则一个加数是8,另一个加数是6,和是 14 原题说法错误。故答案为: ×", + "knowledge_points": [ + "8加几的进位加法" + ], + "source": "24-25 一年级上·黑龙江绥化·期末" + }, + { + "id": "55", + "unit": "第五单元20以内的进位加法1", + "question_type": "判断题", + "difficulty": 0.85, + "question": "如果 8 ○ 9 = 17,那么 ○ 里应该填\"+\"。( )", + "options": [], + "answer": "√", + "solution": "【分析】根据题意,看填上\"+\"能否使算式成立。这里需要将运算符号代入式子进行计算,看结果是否符合算式右边的数。即可解答.\n【详解】 8 + 9 = 17 所以如果 8 ○ 9 = 17,那么 ○ 里应该填\"+\"。原题说法正确;故答案为:√", + "knowledge_points": [ + "8加几的进位加法" + ], + "source": "24-25 一年级上·陕西延安·期末" + }, + { + "id": "56", + "unit": "第五单元20以内的进位加法1", + "question_type": "判断题", + "difficulty": 0.85, + "question": "马路上有 2 排花,一排 6 盆,一排 7 盆,共 42 盆。( )", + "options": [], + "answer": "×", + "solution": "【分析】马路上有 2 排花,一排 6 盆,一排 7 盆,求一共有多少盆,就是求两个数的和,用加法列式解决.\n【详解】 6 + 7 = 13 (盆)即,马路上有2排花,一排6盆,一排7盆,共13盆。原题说法错误。故答案为: ×", + "knowledge_points": [ + "7,6加几的进位加法" + ], + "source": "24-25 二年级上·四川南充·期末" + }, + { + "id": "57", + "unit": "第五单元20以内的进位加法1", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式计算.\n\n![](images/764913672772c3b7861b7cd16b7efee47b56bbf9be363ff4f1d49ce14163a97f.jpg)\n\n□ ○ □ = □(朵)", + "options": [], + "answer": "7 + 5 = 12", + "solution": "【分析】根据题意可知,左边花朵的数量加上右边花朵的数量,等于一共有多少朵花,据此解答.\n【详解】根据分析可得:7 + 5 = 12 (朵)一共有12朵花。", + "knowledge_points": [ + "图文问题", + "7,6 加几的进位加法" + ], + "source": "24-25 一年级上·浙江嘉兴·期末" + }, + { + "id": "58", + "unit": "第五单元20以内的进位加法1", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式计算.\n\n![](images/646bf0616cd3d676714f0c3f93e5a6e19b1316fa2064cefa8b679668ce8749c4.jpg)\n\n□ ○ □ = □(个)", + "options": [], + "answer": "5 + 8 = 13", + "solution": "【分析】从图上可得:左边有5个苹果,右边有8个苹果,要求一共有多少个苹果,根据加法的意义,用5+8进行解答即可.\n【详解】 5 + 8 = 13 (个)", + "knowledge_points": [ + "图文问题", + "5 ∼ 2 加几的进位加法" + ], + "source": "24-25 一年级下·全国·课后作业" + }, + { + "id": "59", + "unit": "第五单元20以内的进位加法1", + "question_type": "计算题", + "difficulty": 0.65, + "question": "看图列式计算.\n\n![](images/57d9c8039e2fe37f36f000ccfe106e5832ec8cf8178f64362a963b7f27b81f9d.jpg)\n\n□ ○ □ = □(本)", + "options": [], + "answer": "3 + 8 = 11", + "solution": "【分析】从图上可得:左边有3本书,右边书包里面有8本书,要求一共有多少本,根据加法的意义,用 3 + 8 进行解答即可.\n【详解】 3 + 8 = 11 (本)那么一共有 11 本书。", + "knowledge_points": [ + "图文问题", + "5 ∼ 2 加几的进位加法" + ], + "source": "24-25 一年级下·全国·课后作业" + }, + { + "id": "60", + "unit": "第五单元20以内的进位加法1", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式计算.\n\n![](images/cf8b10e2fe29aba94f4381b311f49ea95f94d471b6ade704405c48223ad1f04a.jpg)\n\n□ ○ □ ○ □ = □(个)", + "options": [], + "answer": "5 + 4 + 6 = 15", + "solution": "【分析】用左边的 5 个加中间的 4 个,再加上右边的 6 个即可求出一共多少个.\n【详解】 5 + 4 + 6 = 15 (个)一共有 15 个。", + "knowledge_points": [ + "图文问题", + "连加(20 以内)" + ], + "source": "24-25 一年级上·浙江温州·期末" + }, + { + "id": "61", + "unit": "第五单元20以内的进位加法1", + "question_type": "计算题", + "difficulty": 0.65, + "question": "看图列式计算.\n\n![](images/21829aaf967c8fd65269652305008f985858cba97945f9bd525f7b69d0f682b2.jpg)\n\n□ ○ □ = □(个)", + "options": [], + "answer": "9 + 4 = 13", + "solution": "【分析】左边有9个苹果,右边有4个苹果,求一共有几个苹果,用加法计算,即左边的数量+右边的数量 = 总数量.\n【详解】 9 + 4 = 13 (个)一共有 13 个苹果。", + "knowledge_points": [ + "图文问题", + "9 加几的进位加法" + ], + "source": "24-25 一年级下·全国·单元测试" + }, + { + "id": "62", + "unit": "第五单元20以内的进位加法1", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图写算式.\n\n![](images/cb862fa274948a9003a451ff21757d30388541058856091ca837c7f2b0619046.jpg)\n\n□ ○ □ = □(个)", + "options": [], + "answer": "4 + 8 = 12", + "solution": "【分析】把左边的方块数量与右边的数量加起来,求出和,就是一共的方块数量.\n【详解】由题意分析得:4 + 8 = 12 (个)", + "knowledge_points": [ + "图文问题", + "5 ∼ 2 加几的进位加法" + ], + "source": "24-25 一年级上·湖北随州·期末" + }, + { + "id": "63", + "unit": "第五单元20以内的进位加法1", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式.\n\n![](images/d6fb67ac250d27b44daeb9e03ba8d44dd3701096f9c39fff392ff5ddc8d3cdee.jpg)\n\n□ ○ □ = □(个)", + "options": [], + "answer": "5 + 9 = 14", + "solution": "【分析】根据图片可知:用左边的数量加右边的数量即可求出一共的数量.\n【详解】 5 + 9 = 14 (个)", + "knowledge_points": [ + "5 ∼ 2 加几的进位加法" + ], + "source": "24-25 一年级上·河南郑州·期末" + }, + { + "id": "64", + "unit": "第五单元20以内的进位加法1", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式计算.\n\n![](images/94782a3a5b2b47fcce718aebc06636374acbba89ccbc238237cd999133ab49e6.jpg)\n\n□ ○ □ = □(个)", + "options": [], + "answer": "3 + 9 = 12", + "solution": "【分析】左右两边的个数相加即可求出一共有多少个.\n【详解】 3 + 9 = 12 (个)", + "knowledge_points": [ + "图文问题", + "9 加几的进位加法", + "5 ∼ 2 加几的进位加法" + ], + "source": "24-25 一年级上·陕西延安·期末" + }, + { + "id": "65", + "unit": "第五单元20以内的进位加法1", + "question_type": "计算题", + "difficulty": 0.65, + "question": "看图列式计算.\n\n![](images/7fa8c95284c7216fe09a8c7aeab026daad9a66258566a6ade1b21d1bb07496f6.jpg)\n\n□ ○ □ = □(个)", + "options": [], + "answer": "8 + 4 = 12", + "solution": "【分析】根据图意,求一共有多少,用左边的 8 块加上右边的 4 块,即可解答.\n【详解】 8 + 4 = 12 (块)", + "knowledge_points": [ + "图文问题", + "8 加几的进位加法" + ], + "source": "24-25 一年级上·浙江嘉兴·期末" + }, + { + "id": "66", + "unit": "第五单元20以内的进位加法1", + "question_type": "计算题", + "difficulty": 0.65, + "question": "看图列式.\n\n![](images/b7cb3727369a65085022bb8478021a5dd6d44a1b5a6ab79ed929fae0297ffbe3.jpg)\n\n□ ○ □ = □(个)", + "options": [], + "answer": "5 + 9 = 14", + "solution": "【分析】左边的足球加上右边的足球即可求出一共有多少个足球.\n【详解】 5 + 9 = 14 (个)", + "knowledge_points": [ + "图文问题", + "9 加几的进位加法", + "5 ∼ 2 加几的进位加法" + ], + "source": "24-25 一年级上·四川广元·期末" + }, + { + "id": "67", + "unit": "第五单元20以内的进位加法1", + "question_type": "计算题", + "difficulty": 0.85, + "question": "我会列式计算.\n\n![](images/a1d30e712aad279ececf7d8203b3dd41bbfea428e54874d58fbe230378c8464f.jpg)\n\n□ ○ □ = □(个)", + "options": [], + "answer": "8 + 6 = 14", + "solution": "【分析】如图,左边有 8 个三角形,右边有 6 个,求一共有多少个,用加法计算.\n【详解】 8 + 6 = 14 (个)一共有 14 个三角形。", + "knowledge_points": [ + "图文问题", + "8加几的进位加法" + ], + "source": "24-25 一年级上·重庆九龙坡·期末" + }, + { + "id": "68", + "unit": "第五单元20以内的进位加法1", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式计算.\n\n![](images/cd6bb52c90b600fe8230a2d048be30a04b4b8c80feceec8f743ff0dc47843d0c.jpg)\n\n□ ○ □ = □(个)", + "options": [], + "answer": "8 + 4 = 12", + "solution": "【分析】从图上可得:左边有8个草莓,右边有4个草莓,要求一共有多少个草莓,将左右两边的草莓数量相加,即可得出答案.\n【详解】 8 + 4 = 12 (个)", + "knowledge_points": [ + "图文问题", + "8 加几的进位加法" + ], + "source": "24-25 一年级上·福建三明·期末" + }, + { + "id": "69", + "unit": "第五单元20以内的进位加法1", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式计算.\n\n![](images/3e7307bdc028d5be0b80655481a35ed325859e522e61dc8599f08af1f98d2c0a.jpg)\n\n□ ○ □ = □(个)", + "options": [], + "answer": "9 + 6 = 15", + "solution": "【分析】蜂窝里面有9只蜜蜂,外面有6只蜜蜂,求一共有多少只蜜蜂,用加法计算,用蜂窝里面的只数加上蜂窝外面的只数.\n【详解】 9 + 6 = 15 (只)一共有15只蜜蜂。", + "knowledge_points": [ + "图文问题", + "9 加几的进位加法" + ], + "source": "24-25 一年级上·江西抚州·期末" + }, + { + "id": "70", + "unit": "第五单元20以内的进位加法1", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式计算.\n\n![](images/7fef2b4107dc40a831a36191640368210776d508d4ff424ea75742c1e5d5f95d.jpg)\n\n□ ○ □ = □(个)", + "options": [], + "answer": "9 + 6 = 15", + "solution": "【分析】已知左边有9个桃子,右边有6个桃子,要求一共有多少个桃子,根据加法的意义,用 9 + 6 进行解答即可.\n【详解】 9 + 6 = 15 (个)", + "knowledge_points": [ + "图文问题", + "9加几的进位加法" + ], + "source": "24-25 一年级上·湖北黄石·期末" + }, + { + "id": "71", + "unit": "第五单元20以内的进位加法1", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式.\n\n![](images/507c5841c47e1b5261c0b9f27a4924e77380757a790cfb56af125b975ccb30ed.jpg)\n\n□ ○ □ = □(只)", + "options": [], + "answer": "9 + 6 = 15", + "solution": "【分析】左右两边的只数相加即可求出一共有多少只.\n【详解】 9 + 6 = 15 (只)", + "knowledge_points": [ + "图文问题", + "9 加几的进位加法" + ], + "source": "24-25 一年级上·湖北襄阳·期末" + }, + { + "id": "72", + "unit": "第五单元20以内的进位加法1", + "question_type": "解答题", + "difficulty": 0.85, + "question": "图书角的连环画被借走了9本,还剩6本,原来有多少本。\n\n□ ○ □ = □(本)", + "options": [], + "answer": "9 + 6 = 15", + "solution": "【分析】用借走的本数加还剩的本数即可求出原来的本数.\n【详解】 9 + 6 = 15 (本)答:原来有 15 本。", + "knowledge_points": [ + "9 加几的进位加法", + "7,6 加几的进位加法" + ], + "source": "24-25 一年级上·浙江温州·期末" + }, + { + "id": "73", + "unit": "第五单元20以内的进位加法1", + "question_type": "解答题", + "difficulty": 0.85, + "question": "在天鹅湖的湖面上,原有8只白天鹅,又飞来7只黑天鹅,现在湖面上一共有多少只天鹅。\n\n□ ○ □ = □(只)", + "options": [], + "answer": "8 + 7 = 15;15 只", + "solution": "【分析】根据题意可知,原有白天鹅的数量加上又飞来黑天鹅的数量,等于现在湖面上一共有多少只天鹅.\n【详解】根据分析可得: 8 + 7 = 15 (只) 答:现在湖面上一共有 15 只天鹅。", + "knowledge_points": [ + "8加几的进位加法" + ], + "source": "24-25 一年级上·河南三门峡·期末" + }, + { + "id": "74", + "unit": "第五单元20以内的进位加法1", + "question_type": "解答题", + "difficulty": 0.85, + "question": "彩娃亮亮参加汤圆制作比赛,已经制作了 8 个,还剩下 6 个没有制作,原来要制作多少个汤圆。", + "options": [], + "answer": "14 个", + "solution": "【分析】根据题意可知,已制作的汤圆加上未制作的汤圆,等于原来要制作多少个汤圆,据此解答.\n【详解】根据题意可得: 8 + 6 = 14 (个) 答:原来要制作14个汤圆。", + "knowledge_points": [ + "8加几的进位加法" + ], + "source": "24-25 一年级上·河南南阳·期末" + }, + { + "id": "75", + "unit": "第五单元20以内的进位加法1", + "question_type": "解答题", + "difficulty": 0.65, + "question": "小兰有 9 个果冻,小东的果冻和她的同样多,两人共有多少个果冻。\n\n□ ○ □ ○ □ = □(个)", + "options": [], + "answer": "9 + 9 = 18", + "solution": "【分析】小东的果冻和小兰的同样多,所以小东也有9个,将他们的个数相加即可求解.\n【详解】 9 + 9 = 18 (个) 答:两人共有18个果冻。", + "knowledge_points": [ + "9加几的进位加法" + ], + "source": "24-25 一年级上·山东济宁·期末" + }, + { + "id": "76", + "unit": "第五单元20以内的进位加法1", + "question_type": "解答题", + "difficulty": 0.85, + "question": "小明和小亮看书,小明看了9页,小亮和小明看的同样多,小明和小亮一共看了多少页。", + "options": [], + "answer": "18页", + "solution": "【分析】小亮和小明看的同样多,所以小亮也看了9页,将两个人看的页数相加即可求出一共看了多少页.\n【详解】 9 + 9 = 18 (页) 答:小明和小亮一共看了 18 页。", + "knowledge_points": [ + "9 加几的进位加法" + ], + "source": "24-25 一年级下·河南周口·阶段练习" + }, + { + "id": "77", + "unit": "第五单元20以内的进位加法1", + "question_type": "解答题", + "difficulty": 0.85, + "question": "荷叶上有 17 只青蛙,第一次跳进水里6只,第二次跳进水里9只,两次一共跳进水里多少只青蛙。", + "options": [], + "answer": "15 只", + "solution": "【分析】用第一次跳进水里的只数加上第二次跳进水里的只数,即可求出两次一共跳进水里多少只青蛙.\n【详解】 6 + 9 = 15 (只) 答:两次一共跳进水里15只青蛙。", + "knowledge_points": [ + "7,6加几的进位加法" + ], + "source": "24-25 一年级下·河南周口·阶段练习" + }, + { + "id": "78", + "unit": "第五单元20以内的进位加法1", + "question_type": "解答题", + "difficulty": 0.85, + "question": "书店卖出 9 本科技书,还剩下 7 本,书店原来有多少本科技书。\n\n答:书店原来有( )本科技书。", + "options": [], + "answer": "16;16 本", + "solution": "【分析】用卖出的数量加还剩下的数量即可求出原来的数量.\n【详解】 9 + 7 = 16 (本) 答:书店原来有16本科技书。", + "knowledge_points": [ + "9 加几的进位加法", + "7,6 加几的进位加法" + ], + "source": "24-25 一年级下·广东潮州·阶段练习" + }, + { + "id": "79", + "unit": "第五单元20以内的进位加法1", + "question_type": "解答题", + "difficulty": 0.85, + "question": "有两排桌子,一排5张,另一排6张。一共有多少张桌子。", + "options": [], + "answer": "11 张", + "solution": "【分析】根据加法的意义,一排桌子的数量+另一排桌子的数量 = 桌子的总数量.\n【详解】 5 + 6 = 11 (张) 答:一共有 11 张桌子。", + "knowledge_points": [ + "5 ∼ 2 加几的进位加法" + ], + "source": "24-25二年级上·贵州黔南·期末" + }, + { + "id": "80", + "unit": "第五单元20以内的进位加法1", + "question_type": "解答题", + "difficulty": 0.85, + "question": "树上原有 8 只鸟,飞来了 5 只,又飞走了 3 只,现在共有多少只鸟。\n\n□ ○ □ ○ □ = □(只)\n\n口答:现在共有 只鸟。", + "options": [], + "answer": "8 + 5 - 3 = 10", + "solution": "【分析】先把树上原来的鸟数量与又飞来的数量加起来,求出和,再减去又飞走的数量,求出差,就是现在共有的鸟数量.\n【详解】8+5-3= 13-3 = 10 (只) 口答:现在共有 10 只鸟。", + "knowledge_points": [ + "加减混合运算(20以内)" + ], + "source": "24-25 一年级上·湖北随州·期末" + }, + { + "id": "81", + "unit": "第五单元20以内的进位加法1", + "question_type": "解答题", + "difficulty": 0.85, + "question": "原来一共有多少人。\n\n![](images/e22616c18960cdad2dc05259d984d68d9c9e9e4f5a6864a02350fb51ce2d5995.jpg)\n\n□ ○ □ = □(人)答:原来一共有 人。", + "options": [], + "answer": "11 人;5 + 6 = 11;11", + "solution": "【分析】根据题意可知:用外面的人数加已经进去的人数即可求出原来一共的人数.\n【详解】 5 + 6 = 11 (人)答:原来一共有 11 人。", + "knowledge_points": [ + "5 ∼ 2 加几的进位加法" + ], + "source": "24-25 一年级上·湖北省直辖县级单位·期末" + }, + { + "id": "82", + "unit": "第五单元20以内的进位加法1", + "question_type": "解答题", + "difficulty": 0.85, + "question": "原来一共有多少个。\n\n![](images/8c12f493252effefe87245dda4dc9275af0204f50ecb2dfdefa6ba23f6612506.jpg)", + "options": [], + "answer": "7 + 6= 13", + "solution": "【分析】根据题意可知:求原来的数量。用吃的数量加还剩的数量即可.\n【详解】 7 + 6 = 13 (个)答:原来一共13个。", + "knowledge_points": [ + "7,6 加几的进位加法" + ], + "source": "24-25 一年级上·湖北省直辖县级单位·期末" + }, + { + "id": "83", + "unit": "第五单元20以内的进位加法1", + "question_type": "解答题", + "difficulty": 0.85, + "question": "一共多少颗草莓。\n\n![](images/832a8ed9f8549fd4eb8d029ea8be2812daf315e54bf5021c1d99be6b270d51c8.jpg)", + "options": [], + "answer": "9 + 6 + 4 = 19", + "solution": "【分析】先把左边的草莓数量与中间的数量加起来,求出和,再加上右边的数量,求出和,就是一共的草莓数量.\n【详解】9+6+4= 15 + 4= 19(颗)答:一共19颗草莓。", + "knowledge_points": [ + "图文问题", + "连加(20以内)" + ], + "source": "24-25 一年级上·湖南娄底·期末" + }, + { + "id": "84", + "unit": "第五单元20以内的进位加法1", + "question_type": "解答题", + "difficulty": 0.85, + "question": "原来有多少块西瓜。\n\n![](images/e375cb0717a3df13c117eddffb2538d14b7459b67cd9dc5d8eeb188e0c3f85c9.jpg)\n\n□ ○ □ = □(块)", + "options": [], + "answer": "9 + 4 = 13", + "solution": "【分析】把吃了的西瓜数量与还剩的数量加起来,求出和,就是原来的西瓜数量.\n【详解】 9 + 4 = 13 (块)答:原来有13块西瓜。", + "knowledge_points": [ + "9 加几的进位加法" + ], + "source": "24-25 一年级上·河南郑州·期末" + }, + { + "id": "85", + "unit": "第五单元20以内的进位加法1", + "question_type": "解答题", + "difficulty": 0.65, + "question": "临近新年,书法班的王老师给学生写对联,上午写了 6 副对联,下午写了 9 副对联,王老师一共写了多少副对联。\n\n![](images/8b9305d1790d99f2667e7aa2dbda3545d371b3f8024970c18f984a5f5d67feb7.jpg)\n\n□ ○ □ = □(副)", + "options": [], + "answer": "6 + 9 = 15", + "solution": "【分析】根据题意,要求王老师一天总共写的对联数,只需将上午写的对联数量与下午写的对联数量相加即可解答.\n【详解】 6 + 9 = 15 (副)答:王老师一共写了15副对联。", + "knowledge_points": [ + "7,6加几的进位加法" + ], + "source": "24-25 一年级上·陕西延安·期末" + }, + { + "id": "86", + "unit": "第五单元20以内的进位加法1", + "question_type": "解答题", + "difficulty": 0.65, + "question": "看图解答.\n\n![](images/28eebb85d56e16cea821f43982ae9c536fc998782f9b7f3ae6ba42d4dab0dee4.jpg)\n\n![](images/ed39d837c08cc4a67a8c11274e35b525700927979f6a12aa38e800965dc99ea4.jpg)\n\n□ ○ □ = □(个)", + "options": [], + "answer": "7 + 6 = 13", + "solution": "【分析】送给妈妈的个数加上还剩的个数即可得到原有的个数.\n【详解】 7 + 6 = 13 (个)答:小白兔原来有 13 个蘑菇。", + "knowledge_points": [ + "图文问题", + "7,6加几的进位加法" + ], + "source": "24-25 一年级上·四川广元·期末" + }, + { + "id": "87", + "unit": "第五单元20以内的进位加法1", + "question_type": "解答题", + "difficulty": 0.65, + "question": "原来有多少个鸡蛋。\n\n![](images/52b664092e35f969a579e62c2b62166b0fdfd2960b4d7d9fa5c1f24cd2f25c20.jpg)\n\n□ ○ □ = □(个)", + "options": [], + "answer": "8 + 6 = 14", + "solution": "【分析】吃了的数量加上还剩的数量即可得到原来的数量.\n【详解】 8 + 6 = 14 (个)答:原来有14个鸡蛋。", + "knowledge_points": [ + "图文问题", + "8加几的进位加法" + ], + "source": "24-25 一年级上·河南郑州·期末" + }, + { + "id": "88", + "unit": "第五单元20以内的进位加法1", + "question_type": "解答题", + "difficulty": 0.65, + "question": "他们一共有多少朵小红花。\n\n![](images/8cb7944e9a9a35f56f7a518129947f1fb40b4ec00390a557b9ba79d1cc39a0f3.jpg)\n\n□ ○ □ = □(朵)", + "options": [], + "answer": "9 + 5 = 14", + "solution": "【分析】左边小朋友有9朵小红花,右边小朋友有5朵小红花,求一共有多少朵小红花。用加法计算,据此解答.\n【详解】 9 + 5 = 14 (朵)答:他们一共有14朵小红花。", + "knowledge_points": [ + "图文问题", + "9加几的进位加法" + ], + "source": "24-25一年级上·全国·期末" + }, + { + "id": "89", + "unit": "第五单元20以内的进位加法1", + "question_type": "解答题", + "difficulty": 0.85, + "question": "同学们站成一队做操,小明的前面有9人,后面有6人,这一队一共有多少人。\n\n□ ○ □ = □(人)", + "options": [], + "answer": "9 + 6 + 1 = 16", + "solution": "【分析】小明前面的人数加上他后面的人数,再加上小明等于这一队的总人数.\n【详解】 9 + 6 + 1 = 16 (人)答:这一队一共有16人。", + "knowledge_points": [ + "连加(20 以内)" + ], + "source": "24-25一年级上·湖北黄石·期末" + }, + { + "id": "90", + "unit": "第五单元20以内的进位加法1", + "question_type": "解答题", + "difficulty": 0.85, + "question": "树上原来有19个苹果,第一次摘下8个,第二次摘下6个,两次一共摘下多少个。\n\n□ ○ □ = □(个)", + "options": [], + "answer": "8 + 6 = 14;14", + "solution": "【分析】第一次摘苹果的数量加上第二次摘的数量,等于两次一共摘苹果的数量.\n【详解】 8 + 6 = 14 (个)答:两次一共摘了 14 个。", + "knowledge_points": [ + "8 加几的进位加法" + ], + "source": "24-25一年级上·湖北黄石·期末" + }, + { + "id": "91", + "unit": "第五单元20以内的进位加法1", + "question_type": "解答题", + "difficulty": 0.65, + "question": "原来一共有多少只蝴蝶。\n\n![](images/1d39138fbfbdc2f9a1e112de5a6603075719b682f6da457eb8dc6a527483ab4b.jpg)\n\n已经飞走了 8 只 □ ○ □ = □(只)", + "options": [], + "answer": "6 + 8 = 14", + "solution": "【分析】用剩下的6只加上飞走的8只即可求出原来的只数.\n【详解】 6 + 8 = 14 (只)答:原来一共有 14 只蝴蝶。", + "knowledge_points": [ + "图文问题", + "7,6加几的进位加法" + ], + "source": "24-25 一年级上·江西赣州·期末" + }, + { + "id": "92", + "unit": "第五单元20以内的进位加法1", + "question_type": "解答题", + "difficulty": 0.85, + "question": "除夕乐乐一家包饺子,乐乐包了 9 个饺子,姐姐和乐乐包的一样多,乐乐和姐姐一共包了多少个饺子。\n\n□ ○ □ = □(个)", + "options": [], + "answer": "9 + 9 = 18", + "solution": "【分析】乐乐包了9个饺子,姐姐和乐乐包的一样多,说明姐姐也是包了9个饺子;用加法把她们俩包的饺子数量加起来,求出和,就是一共的数量.\n【详解】 9 + 9 = 18 (个)答:乐乐和姐姐一共包了18个饺子。", + "knowledge_points": [ + "9 加几的进位加法" + ], + "source": "24-25 一年级上·河南驻马店·期末" + }, + { + "id": "93", + "unit": "第五单元20以内的进位加法1", + "question_type": "解答题", + "difficulty": 0.85, + "question": "树上有 6 只鸟,树下有 8 只鸟,一共有多少只鸟。\n\n□ ○ □ = □(只)", + "options": [], + "answer": "6+8=14", + "solution": "【分析】把树上的鸟数量与树下的数量加起来,求出和,就是一共的鸟数量.\n【详解】 6 + 8 = 14 (只)答:一共有14只鸟。", + "knowledge_points": [ + "7,6加几的进位加法" + ], + "source": "24-25一年级上·河南驻马店·期末" + }, + { + "id": "94", + "unit": "第五单元20以内的进位加法1", + "question_type": "解答题", + "difficulty": 0.85, + "question": "车上原来有9个快递,现在有多少个快递。\n\n![](images/29c31ef5753716e2f943b463c79a7f6578a27516967336e86b542c303f7a8465.jpg)", + "options": [], + "answer": "9 - 5 + 8 = 12", + "solution": "【分析】送出去5个表示快递数量减少5个,收到8个表示快递数量增加8个,要求现在有多少个快递,用原来的快递数量减去送出去的快递数量,再加上收到的快递数量,即9- 5 + 8=4 + 8 = 12 (个) ,据此解答即可.\n答:现在有 12 个快递。", + "knowledge_points": [ + "加减混合运算(20 以内)" + ], + "source": "24-25一年级上·湖北黄石·期末" + }, + { + "id": "95", + "unit": "第五单元20以内的进位加法1", + "question_type": "解答题", + "difficulty": 0.85, + "question": "学做家务,做最美小学生。原来要洗多少个盘子。\n\n![](images/06691c2bc5a5683cff8996291533ddad00065aa1625974080e643b4181ccb0b6.jpg)", + "options": [], + "answer": "6 + 5 = 11", + "solution": "【分析】要求要洗多少个盘子,根据加法的意义,将已经洗的盘子数量和还没洗的盘子数量相加,即可得出答案.\n【详解】 6 + 5 = 11 (个) 答:原来要洗11个盘子。", + "knowledge_points": [ + "7,6加几的进位加法" + ], + "source": "24-25一年级上·湖北黄石·期末" + }, + { + "id": "96", + "unit": "第五单元20以内的进位加法1", + "question_type": "解答题", + "difficulty": 0.85, + "question": "一(1)班教室原来有19人,出去10人,又进来5人,现在一(1)班教室有多少人。", + "options": [], + "answer": "14 人", + "solution": "【分析】用班级原来的人数减去出去的人数,求出差,再加上又进来的人数,求出和,即可解决.\n【详解】19-10+5= 9 + 5 = 14 (人) 答:现在一(1)班教室有14人。", + "knowledge_points": [ + "加减混合运算(20以内)" + ], + "source": "24-25一年级上·甘肃天水·期末" + }, + { + "id": "97", + "unit": "第五单元20以内的进位加法1", + "question_type": "解答题", + "difficulty": 0.85, + "question": "草地上有 6 只小鸡,先跑来 3 只,又跑来 4 只,草地上一共有几只小鸡。", + "options": [], + "answer": "13 只", + "solution": "【分析】用草地原有的小鸡数量加上先跑来的数量,求出和,再加上又跑来的数量,求出和,就是一共的小鸡数量.\n【详解】6+3+4= 9 + 4 = 13 (只)答:草地上一共有 13 只小鸡。", + "knowledge_points": [ + "连加(20 以内)" + ], + "source": "24-25 一年级上·甘肃天水·期末" + }, + { + "id": "98", + "unit": "第五单元20以内的进位加法1", + "question_type": "解答题", + "difficulty": 0.65, + "question": "兔妈妈运走了 9 棵白菜,还剩下 9 棵,兔妈妈一共收了多少棵白菜。", + "options": [], + "answer": "18", + "solution": "【分析】运走的白菜的数量+剩下的白菜数量 = 一共收的白菜数量,据此得出结论即可.\n【详解】 9 + 9 = 18 (棵)答:一共收了18棵白菜。", + "knowledge_points": [ + "9 加几的进位加法" + ], + "source": "24-25 一年级上·甘肃天水·期末" + }, + { + "id": "99", + "unit": "第五单元20以内的进位加法1", + "question_type": "解答题", + "difficulty": 0.65, + "question": "她俩一共有多少个苹果。\n小红:我有9个苹果 小丽:我跟你同样多", + "options": [], + "answer": "18 个", + "solution": "【分析】由题意可知小红和小丽有同样多的苹果,也就是小丽也有9个苹果,把她们两个有的苹果个数加在一起,即可求出她俩一共有多少个苹果.\n【详解】 9 + 9 = 18 (个)答:她俩一共有18个苹果。", + "knowledge_points": [ + "9加几的进位加法" + ], + "source": "24-25一年级上·贵州黔东南·期末" + }, + { + "id": "100", + "unit": "第五单元20以内的进位加法1", + "question_type": "解答题", + "difficulty": 0.85, + "question": "奶奶养了 7 只白兔,5只灰兔,奶奶一共养了多少只兔。", + "options": [], + "answer": "7 + 5 = 12", + "solution": "【分析】用白兔的只数加灰兔的只数即可求出总只数.\n【详解】 7 + 5 = 12 (只)答:奶奶一共养了12只兔。", + "knowledge_points": [ + "5 ∼ 2 加几的进位加法", + "7,6加几的进位加法" + ], + "source": "24-25 一年级上·湖南怀化·期末" + }, + { + "id": "101", + "unit": "第五单元20以内的进位加法", + "question_type": "选择题", + "difficulty": 0.65, + "question": "六一儿童节这天,小兰和她的3位好朋友每人都收到了5张贺卡,她们一共收到了( )张贺卡。", + "options": [ + "A. 8", + "B. 15", + "C. 20" + ], + "answer": "C", + "solution": "【分析】根据题意,小兰和她的3位好朋友每人都收到了5张贺卡,一共是四个人,每人5张,4个5相加就是她们一共收到的数量,据此解答.\n【详解】根据分析:5 + 5 + 5 + 5 = 20 (张) 她们一共收到20张。故答案为:C", + "knowledge_points": [ + "连加(20 以内)" + ], + "source": "24-25一年级下·山东济宁·期末" + }, + { + "id": "102", + "unit": "第五单元20以内的进位加法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "淘气有两盒果冻,一共有 15 个,下面的三盒果冻中( )不是淘气的。", + "options": [ + "A. ![](images/371c01ca241d4a04178aa9ee2f3df1e504c92ba1c0c5f50fefe83133d654c437.jpg)", + "B. ![](images/22732365ac6b2a947de4d57ec61ff53dd87a7f6b491a001b52f4e0fa88970175.jpg)", + "C. ![](images/9ba77256e1f77c074be4eb8131753e4cbc44e07cff06b594e883833b5bc38d6d.jpg)" + ], + "answer": "A", + "solution": "【分析】根据整数加减法的计算法则,找出两个盒里的果冻数量之和等于15个,就是淘气的果冻,剩下的另一盒就不是淘气的.\n【详解】 9 + 6 = 15(个)即,淘气有两盒果冻,一共有15个,三盒果冻中,4个的那盒果冻不是淘气的。故答案为:A", + "knowledge_points": [ + "9加几的进位加法" + ], + "source": "24-25 一年级上·河南驻马店·期末" + }, + { + "id": "103", + "unit": "第五单元20以内的进位加法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "下面算式中,得数最大的是( )。", + "options": [ + "A. 9+6", + "B. 7+5", + "C. 8+9" + ], + "answer": "C", + "solution": "【分析】将每个选项式子的结果计算出来,再进行比较即可.\n【详解】 9 + 6 = 15,7 + 5 = 12,8 + 9 = 17,17 > 15 > 12,所以得数最大的算式是 8 + 9。故答案为:C", + "knowledge_points": [ + "9 加几的进位加法", + "8 加几的进位加法", + "7,6 加几的进位加法", + "20 以内数的比大小" + ], + "source": "24-25 一年级上·河南驻马店·期末" + }, + { + "id": "104", + "unit": "第五单元20以内的进位加法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "同学们排成一队做早操,小明前面有4人,后面有7人,这一队一共有多少人。列式正确的是( )。", + "options": [ + "A. 4+7", + "B. 4+7-1", + "C. 4+7+1" + ], + "answer": "C", + "solution": "【分析】先把小明前面的人数与后面的人数加起来,求出和,再加上1(小明自己),求出和,就是这一队一共有多少人;据此解决即可.\n【详解】由题意分析得:同学们排成一队做早操,小明前面有4人,后面有7人,这一队一共有多少人。列式正确的是(4+7+1)。故答案为:C", + "knowledge_points": [ + "连加(20以内)" + ], + "source": "24-25一年级上·福建厦门·期末" + }, + { + "id": "105", + "unit": "第五单元20以内的进位加法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "两个加数都是 8,和是( )。", + "options": [ + "A. 10", + "B. 16", + "C. 18" + ], + "answer": "B", + "solution": "【分析】加数+加数=和,据此列式计算.\n【详解】 8 + 8 = 16,和是16。故答案为:B", + "knowledge_points": [ + "8 加几的进位加法" + ], + "source": "24-25 一年级上·河北邯郸·期末" + }, + { + "id": "106", + "unit": "第五单元20以内的进位加法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "一道算式,第一个数是9,小明把加号看成了减号,算出的得数是3,正确的得数是( )。", + "options": [ + "A. 6", + "B. 12", + "C. 15" + ], + "answer": "C", + "solution": "【分析】先根据\"减数=被减数-差\"来求出原算式的第二个数,然后根据\"加数+加数=和\"来求出正确的得数.\n【详解】 9 - 3 = 6,9 + 6 = 15。即,一道算式,第一个数是9,小明把加号看成了减号,算出的得数是3,正确的得数是15。故答案为:C", + "knowledge_points": [ + "8,9 的加减法", + "9 加几的进位加法", + "错中求解问题(加减法)" + ], + "source": "24-25 一年级上·河南周口·期末" + }, + { + "id": "107", + "unit": "第五单元20以内的进位加法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "与8相邻的两个数的和是( )。", + "options": [ + "A. 15", + "B. 16", + "C. 17" + ], + "answer": "B", + "solution": "【分析】用8减1和8加1的方法找到与8相邻的两个数,再把它们相加即可算出结果.\n【详解】8 - 1 = 7,8 + 1 = 9,7 + 9 = 16,所以与8相邻的两个数的和是16。故答案为:B", + "knowledge_points": [ + "9 加几的进位加法", + "10 以内数的排序" + ], + "source": "24-25一年级上·河南周口·期末" + }, + { + "id": "108", + "unit": "第五单元20以内的进位加法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "两个加数都是 9,和是( )。", + "options": [ + "A. 9", + "B. 18", + "C. 0" + ], + "answer": "B", + "solution": "【分析】根据\"加数+加数=和\"及整数加减法的计算法则来解决此题.\n【详解】 9 + 9 = 18,即两个加数都是9,和是18。故答案为:B", + "knowledge_points": [ + "9加几的进位加法" + ], + "source": "24-25 一年级上·辽宁鞍山·期末" + }, + { + "id": "109", + "unit": "第五单元20以内的进位加法", + "question_type": "选择题", + "difficulty": 0.65, + "question": "9+□<13,□里最大填( )。", + "options": [ + "A. 4", + "B. 5", + "C. 3" + ], + "answer": "C", + "solution": "【分析】要使方框里面的数最大,则算式的和要最大,小于13的最大的数是12,所以 9 + □ = 12 即可得出答案.\n【详解】小于13的最大的数是12,9 + 3 = 12,所以方框内最大填3。故答案为:C", + "knowledge_points": [ + "9 加几的进位加法", + "20 以内数的比大小" + ], + "source": "24-25一年级上·内蒙古通辽·期末" + }, + { + "id": "110", + "unit": "第五单元20以内的进位加法", + "question_type": "选择题", + "difficulty": 0.65, + "question": "□+8>16,□里最小填( )。", + "options": [ + "A. 8", + "B. 9", + "C. 10" + ], + "answer": "B", + "solution": "【分析】根据题意,依次将选项中的数代入到算式中,计算出结果再和16比较大小,选择得数大于16且最小的即可。20 以内数从大到小关系为:20 > 19 > 18 > 17 > 16 > 15 > 14>13 > 12 > 11 > 10 > 9 > 8 > 7 > 6 > 5 > 4 > 3 > 2 > 1,由此比较.\n【详解】A。8 + 8 = 16,16=16,不符合题意;B。9 + 8 = 17,17>16;C。10+8=18,18>16;18 > 17 > 16,则□+8>16,□里最小填9。故答案为:B", + "knowledge_points": [ + "9 加几的进位加法", + "8 加几的进位加法", + "20 以内数的比大小", + "不进位加法(20以内)" + ], + "source": "24-25 一年级上·山东济南·期末" + }, + { + "id": "111", + "unit": "第五单元20以内的进位加法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "在下面的算式中,得数最大的是( )。", + "options": [ + "A. 4+8", + "B. 16-6", + "C. 8+3" + ], + "answer": "A", + "solution": "【分析】算出各算式的得数,然后比较得数大小。20以内的数从小到大排列是:1<2<3<4<5<6<7<8<9<10<11<12<13<14<15<16<17<18<19<20.\n【详解】A。4 + 8 = 12;B。16-6=10;C。8+3=11;10<11<12,得数最大的是 4 + 8。故答案为:A", + "knowledge_points": [ + "5∼2 加几的进位加法", + "8 加几的进位加法", + "20 以内数的比大小", + "不退位减法(20 以内)" + ], + "source": "24-25 一年级上·山东济南·期末" + }, + { + "id": "112", + "unit": "第五单元20以内的进位加法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "得数与19-5不相等的是( )。", + "options": [ + "A. 7+7", + "B. 8+6", + "C. 7+6" + ], + "answer": "C", + "solution": "【分析】先根据整数加减法的计算法则,算出每一个算式的得数,然后找出得数不相等的式子即可.\n【详解】19 - 5 = 14。A。7 + 7 = 14;B。8 + 6 = 14;C。7 + 6 = 13。即,得数与19-5不相等的是 7 + 6。故答案为:C", + "knowledge_points": [ + "8 加几的进位加法", + "7,6 加几的进位加法", + "不退位减法(20 以内)" + ], + "source": "24-25一年级上·河北秦皇岛·期末" + }, + { + "id": "113", + "unit": "第五单元20以内的进位加法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "壮壮在计算一道\"9加几\"的算式时,先算 9+1=10,再算 10+6=16,这道加法算式是( )。", + "options": [ + "A. 9+6", + "B. 9+7", + "C. 9+8" + ], + "answer": "B", + "solution": "【分析】根据\"凑十法\",逐项分析,找出正确答案即可。凑十法就是:两个数相加时,把其中的一个加数分成两个数,使分成的数与另一个加数的和正好是10,这就是凑十法.\n【详解】A。计算 9 + 6 时,把6分成1和5,先算 9 + 1 = 10,再算 10 + 5 = 15;B。计算 9 + 7 时,把7分成1和6,先算 9 + 1 = 10,再算 10 + 6 = 16;C。计算 9 + 8 时,把8分成1和7,先算 9 + 1 = 10,再算 10 + 7 = 17。即,这道加法算式是 9 + 7。故答案为:B", + "knowledge_points": [ + "9 加几的进位加法" + ], + "source": "24-25 一年级上·全国·课后作业" + }, + { + "id": "114", + "unit": "第五单元20以内的进位加法", + "question_type": "选择题", + "difficulty": 0.65, + "question": "淘淘看一本书,第一天看了6页,第二天看了7页,他第三天应该从第( )页看起。", + "options": [ + "A. 12", + "B. 13", + "C. 14" + ], + "answer": "C", + "solution": "【分析】根据题意,第三天开始看的页数应为前两天看的总页数的后一页,则先用第一天看的页数+第二天看的页数,求出两天一共看了多少页,再加上1,就是第三天开始看的页数.\n【详解】6 + 7 + 1 = 14(页),他第三天应该从第14页看起。故答案为:C", + "knowledge_points": [ + "连加(20 以内)" + ], + "source": "24-25 一年级上·全国·课后作业" + }, + { + "id": "115", + "unit": "第五单元20以内的进位加法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "万老师拿来 18 根跳绳,一组借走 8 根,二组借走 4 根。两组一共借走多少根。下面解答正确的是( )。", + "options": [ + "A. 18-8-4=6(根)", + "B. 8-4=4(根)", + "C. 8+4=12(根)" + ], + "answer": "C", + "solution": "【分析】求一共借走了几根,用加法计算,即一组借走的数量+二组借走的数量=一共借走的数量,由此解答.\n【详解】A。18 - 8 - 4 = 6(根),表示一组和二组借走后,还剩几根,不符合题意;B。8 - 4 = 4(根),表示一组比二组多借走几根,不符合题意;C。8 + 4 = 12(根),表示两组一共借走了多少根,符合题意。所以解答正确的是 8 + 4 = 12(根)。故答案为:C", + "knowledge_points": [ + "8,9 的加减法", + "8 加几的进位加法", + "不进位,不退位连加,连减(20 以内)" + ], + "source": "24-25 一年级上·全国·课后作业" + }, + { + "id": "116", + "unit": "第五单元20以内的进位加法", + "question_type": "选择题", + "difficulty": 0.65, + "question": "6+□<13,□里最大可以填( )。", + "options": [ + "A. 6", + "B. 7", + "C. 9" + ], + "answer": "A", + "solution": "【分析】根据题意,依次将选项中的数代入到算式中,计算出结果再和13比较大小,选择得数小于13且最大的即可。20 以内数从大到小关系为:20 > 19 > 18 > 17 > 16 > 15 > 14> 13 > 12 > 11 > 10 > 9 > 8 > 7 > 6 > 5 > 4 > 3 > 2 > 1,由此比较.\n【详解】A。6+6=12,12<13,符合题意;B。6 + 7 = 13,13=13,不符合题意;C。6+9=15,15>13,不符合题意。6+□<13,□里最大可以填6。故答案为:A", + "knowledge_points": [ + "7,6加几的进位加法", + "20以内数的比大小" + ], + "source": "24-25 一年级上·全国·课后作业" + }, + { + "id": "117", + "unit": "第五单元20以内的进位加法", + "question_type": "选择题", + "difficulty": 0.65, + "question": "下面算式中,得数小于 15 的是( )。", + "options": [ + "A. 8+7", + "B. 9+4", + "C. 8+8" + ], + "answer": "B", + "solution": "【分析】根据题意,依次计算出各算式的结果再和15比较大小,选择得数小于15的即可。20以内数从大到小关系为:20 > 19 > 18 > 17 > 16 > 15 > 14 > 13 > 12 > 11 > 10 > 9 > 8 > 7>6 > 5 > 4 > 3 > 2 > 1 > 0,由此比较.\n【详解】A。8+7=15,15=15,不符合题意;B。9+4=13,13<15,符合题意;C。8+8=16,16>15,不符合题意。得数小于15的是 9 + 4。故答案为:B", + "knowledge_points": [ + "9 加几的进位加法", + "8 加几的进位加法", + "20 以内数的比大小" + ], + "source": "24-25 一年级上·全国·课后作业" + }, + { + "id": "118", + "unit": "第五单元20以内的进位加法", + "question_type": "选择题", + "difficulty": 0.65, + "question": "校园里有两排松树,一排有5棵,另一排有6棵。一共有( )棵松树。", + "options": [ + "A. 10", + "B. 30", + "C. 11" + ], + "answer": "C", + "solution": "【分析】两排松树的数量相加就是一共的松树的数量,据此计算得出结论即可.\n【详解】5 + 6 = 11(棵),即一共有11棵松树。故答案为:C", + "knowledge_points": [ + "5∼2 加几的进位加法" + ], + "source": "23-24二年级上·福建福州·期末" + }, + { + "id": "119", + "unit": "第五单元20以内的进位加法", + "question_type": "选择题", + "difficulty": 0.65, + "question": "与 6+8 的得数相等的算式是( )。", + "options": [ + "A. 10-6", + "B. 8-6", + "C. 7+7" + ], + "answer": "C", + "solution": "【分析】根据整数加减法的计算法则,依次计算出各算式的结果,找出与 6+8 得数相同的即可.\n【详解】6 + 8 = 14。A。10 - 6 = 4,不符合题意;B。8 - 6 = 2,不符合题意;C。7 + 7 = 14,符合题意。与 6+8 的得数相等的算式是 7 + 7。故答案为:C", + "knowledge_points": [ + "8,9 的加减法", + "10 的加减法", + "7,6 加几的进位加法" + ], + "source": "2024 一年级上·全国·专题练习" + }, + { + "id": "120", + "unit": "第五单元20以内的进位加法", + "question_type": "选择题", + "difficulty": 0.65, + "question": "( )的得数最小。", + "options": [ + "A. 8-1", + "B. 2+10", + "C. 8+5" + ], + "answer": "A", + "solution": "【分析】根据整数加减法的计算法则,依次计算出各算式的结果再比较大小,20 以内数从小到大关系为:0 < 1 < 2 <3 < 4 < 5 < 6 < 7 < 8 < 9 < 10 < 11 < 12 < 13 < 14 < 15 < 16 < 17< 18 < 19 < 20,由此比较.\n【详解】A。8 - 1 = 7;B。2 + 10 = 12;C。8 + 5 = 13;7<12<13,则8-1的得数最小。故答案为:A", + "knowledge_points": [ + "8,9 的加减法", + "8 加几的进位加法", + "20 以内数的比大小", + "不进位加法(20 以内)" + ], + "source": "2024 一年级上·全国·专题练习" + }, + { + "id": "121", + "unit": "第五单元20以内的进位加法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "如果 8+□>12,那么□里应填( )。", + "options": [ + "A. 4", + "B. 比4大的数", + "C. 比 4 小的数" + ], + "answer": "B", + "solution": "【分析】根据题意,先计算出等于12时,填写的数是多少。算式实际的结果比12大,也就是应填的数要比求出的数大。由此解答.\n【详解】8 + □ = 12.8和2合起来就是10,再加上2就是12,即 8 + 4 = 12。要使 8 + □ > 12,那么□里应填比4大的数。故答案为:B", + "knowledge_points": [ + "8 加几的进位加法", + "20 以内数的比大小" + ], + "source": "24-25 一年级上·全国·单元测试" + }, + { + "id": "122", + "unit": "第五单元20以内的进位加法", + "question_type": "选择题", + "difficulty": 0.65, + "question": "同学们排队去动物园,阳阳前面有 6 人,后面有 9 人,一共有( )人去动物园。", + "options": [ + "A. 14", + "B. 15", + "C. 16" + ], + "answer": "C", + "solution": "【分析】用阳阳前面的人数加阳阳后面的人数再加阳阳即可算出一共有多少人去动物园.\n【详解】6 + 9 + 1 = 16(人),一共有16人去动物园。故答案为:C", + "knowledge_points": [ + "连加(20以内)" + ], + "source": "24-25 一年级上·全国·单元测试" + }, + { + "id": "123", + "unit": "第五单元20以内的进位加法", + "question_type": "选择题", + "difficulty": 0.65, + "question": "下面算式中,得数最大的是( )。", + "options": [ + "A. 7+8", + "B. 9+9", + "C. 8+6", + "D. 7+5" + ], + "answer": "B", + "solution": "【分析】将每个选项式子的结果计算出来,再进行比较即可.\n【详解】7 + 8 = 15,9 + 9 = 18,8+6=14,7+5=12,18 > 15 > 14 > 12,所以 9 + 9 的得数最大。故答案为:B", + "knowledge_points": [ + "9加几的进位加法", + "8加几的进位加法", + "7,6加几的进位加法", + "20 以内数的比大小" + ], + "source": "24-25 一年级上·全国·课后作业" + }, + { + "id": "124", + "unit": "第五单元20以内的进位加法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "如果□+□=18,△-□=2,那么□=( ),△=( )。", + "options": [], + "answer": "9;11", + "solution": "【分析】根据题意,□+□=18,即两个相同的数相加等于18,因为 9 + 9 = 18,则□=9;把△-□=2中的□换成9,再根据被减数=差+减数,即可求出△等于多少,据此解答.\n【详解】□+□=18,9 + 9 = 18,即□=9。把△-□=2中的□换成9,即 △-9 = 2,△ = 9 + 2 = 11。因此,如果□+□=18,△-□=2,那么□=9,△=11。", + "knowledge_points": [ + "9加几的进位加法" + ], + "source": "24-25 一年级下·湖北随州·期末" + }, + { + "id": "125", + "unit": "第五单元20以内的进位加法", + "question_type": "填空题", + "difficulty": 0.65, + "question": "如果 ☆+7=18,△+☆=20,那么☆=( ),△=( )。", + "options": [], + "answer": "11;9", + "solution": "【分析】先看看哪个数和7相加得18,则☆就是那个数。然后将☆的值代入△+☆=20,看看哪个数和☆的值相加得20,△就是那个数.\n【详解】11 + 7 = 18,所以☆=11。△+☆=20,即 △+11=20,9 + 11 = 20,所以△=9。如果 ☆+7=18,△+☆=20,那么☆=11,△=9。", + "knowledge_points": [ + "9 加几的进位加法", + "不进位加法(20 以内)" + ], + "source": "24-25 一年级上·贵州黔东南·期末" + }, + { + "id": "126", + "unit": "第五单元20以内的进位加法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "8+6+6=20,先把( )和( )相加得( ),再加上( ),得数是20。", + "options": [], + "answer": "8;6;14;6", + "solution": "【分析】同级运算时,从左到右依次计算。交换加数的位置,和不变,也可以先加6和6.\n【详解】8 + 6 + 6 = 20,先把8和6相加得14,再加上6,得数是20。", + "knowledge_points": [ + "连加(20以内)" + ], + "source": "24-25 一年级下·河南许昌·开学考试" + }, + { + "id": "127", + "unit": "第五单元20以内的进位加法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "今天早上晶晶吃了 8 个水饺,还剩 6 个水饺。妈妈一共为晶晶准备了( )个水饺;晶晶再吃( )个就刚好吃了 10 个。", + "options": [], + "answer": "14;2", + "solution": "【分析】把吃了的水饺数量与还剩的数量加起来,求出和,就是一共的水饺数量;用10个减去吃了的水饺数量,求出差,就是再吃的水饺数量.\n【详解】8 + 6 = 14(个),10 - 8 = 2(个)。即,今天早上晶晶吃了8个水饺,还剩6个水饺。妈妈一共为晶晶准备了14个水饺;晶晶再吃2个就刚好吃了10个。", + "knowledge_points": [ + "8 加几的进位加法", + "10 的加减法" + ], + "source": "24-25 一年级上·河南周口·期末" + }, + { + "id": "128", + "unit": "第五单元20以内的进位加法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "一根绳子对折后,长 8 米,这根绳子展开后长( )米。", + "options": [], + "answer": "16", + "solution": "【分析】根据题意可知,一根绳子对折后,再展开是两个长度一样的绳子,一段是8米,2段是两个8相加;据此列式解答即可.\n【详解】根据分析可得:8 + 8 = 16(米),所以这根绳子展开后长16米。", + "knowledge_points": [ + "8 加几的进位加法" + ], + "source": "24-25 一年级上·河南周口·期末" + }, + { + "id": "129", + "unit": "第五单元20以内的进位加法", + "question_type": "填空题", + "difficulty": 0.65, + "question": "小朋友排队,从前往后数,小红是第5人,从后往前数,小红是第8人,这一队一共有( )人。", + "options": [], + "answer": "12", + "solution": "【分析】从前往后数,小红是第5人,说明数到小红这里有5个人;从后往前数,小红是第8人,说明数到小红这里有8个人;这样数,小红被数了2次。先求5与8的和,再减去1(小红被多数了1次),即可求出这一队一共有多少人.\n【详解】5 + 8 - 1 = 12,即,这一队一共有12人。", + "knowledge_points": [ + "加减混合运算(20以内)" + ], + "source": "24-25 一年级上·内蒙古通辽·期末" + }, + { + "id": "130", + "unit": "第五单元20以内的进位加法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "7 加 9 的和是( ),这个数再加上( )个一是 20。", + "options": [], + "answer": "16;4", + "solution": "【分析】7 加 9 的和是多少,用加法计算,和是16;16是1个十和6个一组成,6个一再加上4个一可以再组成1个十,合起来是20。即可完成填空.\n【详解】由分析可得:7 + 9 = 16,所以,7加9的和是16,这个数再加上4个一是20。", + "knowledge_points": [ + "9 加几的进位加法", + "20 以内数的组成" + ], + "source": "24-25 一年级上·甘肃兰州·期末" + }, + { + "id": "131", + "unit": "第五单元20以内的进位加法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "一个加数是7,另一个加数是 8,和是( );被减数是 17,减数是 7,差是( )。", + "options": [], + "answer": "15;10", + "solution": "【分析】根据\"加数+加数=和;被减数-减数=差\"即可解答.\n【详解】7 + 8 = 15,17 - 7 = 10。则一个加数是7,另一个加数是8,和是15;被减数是17,减数是7,差是10。", + "knowledge_points": [ + "7,6 加几的进位加法", + "不退位减法(20 以内)" + ], + "source": "24-25一年级上·甘肃平凉·期末" + }, + { + "id": "132", + "unit": "第五单元20以内的进位加法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "两个加数都是 9,和是( );被减数是 10,减数是 4,差是( )。", + "options": [], + "answer": "18;6", + "solution": "【分析】根据加数+加数=和,被减数-减数=差即可解答.\n【详解】9 + 9 = 18,10 - 4 = 6。则两个加数都是9,和是18;被减数是10,减数是4,差是6。", + "knowledge_points": [ + "9 加几的进位加法", + "10 的加减法" + ], + "source": "24-25 一年级上·山东济宁·期末" + }, + { + "id": "133", + "unit": "第五单元20以内的进位加法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "一个加数是6,另一个加数是5,和是( )。", + "options": [], + "answer": "11", + "solution": "【分析】根据\"加数+加数=和\",计算出结果即可.\n【详解】根据分析可得:6 + 5 = 11,一个加数是6,另一个加数是5,和是11。", + "knowledge_points": [ + "7,6加几的进位加法" + ], + "source": "24-25一年级上·云南玉溪·期末" + }, + { + "id": "134", + "unit": "第五单元20以内的进位加法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "在括号里填上合适的数.\n\n\n9 + ( ) = 1418 - ( ) = 12 ( ) + 7 = 15\n", + "options": [], + "answer": "5;6;8", + "solution": "【分析】我们可以根据数的分与合完成此题,14可以分成9和5;18可以分成6和12;15可以分成8和7,据此完成题目.\n【详解】14分成9和5,所以 9 + ( 5 ) = 14;18 分成 6 和 12,所以 18 - ( 6 ) = 12;15 分成 8 和 7,所以 (8)+7=15。", + "knowledge_points": [ + "9 加几的进位加法", + "8 加几的进位加法", + "不退位减法(20 以内)" + ], + "source": "24-25 一年级上·广西柳州·期末" + }, + { + "id": "135", + "unit": "第五单元20以内的进位加法", + "question_type": "填空题", + "difficulty": 0.65, + "question": "算一算.\n![](images/996555d056aa1b069edb03724544fb7411b6a66a99c5d0b088f420f6c28ce018.jpg)\n\n□ ○ □ = □(个)", + "options": [], + "answer": "7+6=13", + "solution": "【分析】左边有7个苹果,右边有6个苹果,列算式应为左边的数量+右边的数量=总数量;根据凑十法进行计算,7和3合起来就是10,再加上3就是13,即左边的7个和右边的3个圈在一起.\n【详解】7 + 6 = 13(个)答:一共有13个苹果。", + "knowledge_points": [ + "7,6 加几的进位加法" + ], + "source": "24-25 一年级上·全国·课后作业" + }, + { + "id": "136", + "unit": "第五单元20以内的进位加法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "在括号里填上\">\"\"<\"或\"=\".\n\n9+5( )1516-4( )1014-2( )7+6", + "options": [], + "answer": "<;>;<", + "solution": "【分析】先计算出每个算式的结果,然后比较大小即可.\n【详解】9 + 5 = 14,故 9 + 5 < 15;16 - 4 = 12,故 16 - 4 > 10;14 - 2 = 12,7 + 6 = 13,故 14 - 2 < 7 + 6。", + "knowledge_points": [ + "9 加几的进位加法", + "7,6 加几的进位加法", + "20以内数的比大小", + "不退位减法(20以内)" + ], + "source": "2024 一年级上·全国·专题练习" + }, + { + "id": "137", + "unit": "第五单元20以内的进位加法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "在括号里填上\"+\"或\"-\".\n\n3( )5=810( )4=68( )5=13", + "options": [], + "answer": "+;-;+", + "solution": "【分析】根据整数加减法的计算法则及数的分与合进行解答。3 和 5 合起来就是 8,即 3+5=8;10 可以分成 4 和 6,即 10-4=6;8 和 2 合起来就是 10,再加上 3 就是 13,即 8+5=13.\n【详解】3 + 5 = 8,10 - 4 = 6,8 + 5 = 13。", + "knowledge_points": [ + "8,9 的加减法", + "8 加几的进位加法", + "10 的加减法" + ], + "source": "2024一年级上·全国·专题练习" + }, + { + "id": "138", + "unit": "第五单元20以内的进位加法", + "question_type": "填空题", + "difficulty": 0.65, + "question": "在括号里填上合适的数.\n\n\n4 + ( ) = 98 - ( ) = 210 + ( ) = 13\n\n\n\n( ) + 5 = 11 ( ) - 4 = 107 + ( ) = 15\n", + "options": [], + "answer": "5;6;3;6;14;8", + "solution": "【分析】根据加数+加数=和,被减数-减数=差,结合10以内整数的加减法运算,进行解答即可.\n【详解】9 - 4 = 5,所以括号内填5;8 - 2 = 6,所以括号内填6;13 - 10 = 3,所以括号内填3;6 + 5 = 11,所以括号内填6;10 + 4 = 14,所以括号内填14;7 + 8 = 15,所以括号内填8。", + "knowledge_points": [ + "8,9 的加减法", + "7,6 加几的进位加法", + "不进位加法(20 以内)", + "不退位减法(20 以内)" + ], + "source": "24-25 一年级上·全国·期末" + }, + { + "id": "139", + "unit": "第五单元20以内的进位加法", + "question_type": "填空题", + "difficulty": 0.65, + "question": "一个加数是 5,另一个加数是 7,算式是( ),和是( )。", + "options": [], + "answer": "5+7=12;12", + "solution": "【分析】加法算式为:加数+加数=和,由此代入计算即可.\n【详解】一个加数是5,另一个加数是7,算式是 5 + 7 = 12,和是12。", + "knowledge_points": [ + "5∼2 加几的进位加法" + ], + "source": "24-25 一年级上·全国·课后作业" + }, + { + "id": "140", + "unit": "第五单元20以内的进位加法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "两个加数都是 9,和是( );被减数是 19,减数是 3,差是( )。", + "options": [], + "answer": "18;16", + "solution": "【分析】根据\"加数+加数=和,被减数-减数=差\"及整数加减法的计算法则来解决此题.\n【详解】9 + 9 = 18,19 - 3 = 16。即两个加数都是9,和是18;被减数是19,减数是3,差是16。", + "knowledge_points": [ + "9 加几的进位加法", + "不退位减法(20 以内)" + ], + "source": "24-25 一年级上·全国·期末" + }, + { + "id": "141", + "unit": "第五单元20以内的进位加法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "括号下面藏着几。填一填.\n\n8+( )=13 ( )+6=127+( )=148+5=( )+7", + "options": [], + "answer": "5;6;7;6", + "solution": "【分析】据题意,已知一个加数和和,可用和减去已知的加数即可得出另一个加数;也可用凑十法进行计算,例如:8 加 2 等于 10,10 加 3 等于 13,2 加 3 等于 5,可以求出 8加5等于13,可依次求出其它算式.\n【详解】8 + 5 = 13;6 + 6 = 12;7+7=14;8+5=6+7。", + "knowledge_points": [ + "8加几的进位加法", + "7,6加几的进位加法" + ], + "source": "24-25 一年级上·全国·单元测试" + }, + { + "id": "142", + "unit": "第五单元20以内的进位加法", + "question_type": "填空题", + "difficulty": 0.65, + "question": "在括号里填上最小的数.\n\n13<( )+514<9+( )", + "options": [], + "answer": "9;6", + "solution": "【分析】第1题:比13大的数有14,15,16。其中最小的是14,右侧算式的结果为14即可;第2题:比14大的数有15,16,17。其中最小的是15,右侧算式的结果为15即可。根据凑十法进行解答.\n【详解】5 和 5 合起来就是10,再加上4就是14,即13<9+5=14,括号里最小能填9;9和1合起来就是10,再加上5就是15,即14<9+6=15,括号里最小能填6。", + "knowledge_points": [ + "9 加几的进位加法", + "5∼2 加几的进位加法", + "20 以内数的比大小" + ], + "source": "24-25一年级上·全国·课后作业" + }, + { + "id": "143", + "unit": "第五单元20以内的进位加法", + "question_type": "填空题", + "difficulty": 0.65, + "question": "同学们站成一队,从前数,兰兰排第 8,从后数,兰兰排第 5,这一队一共有( )个同学。", + "options": [], + "answer": "12", + "solution": "【分析】由题可知,从前数,兰兰排第8,说明兰兰前面有7个同学,从后数,兰兰排第5,说明兰兰后面有4个同学,求这一队一共有几个同学,根据加法的意义,用兰兰前面同学的数量加上兰兰后面的同学的数量,再加上兰兰自己即可.\n【详解】7 + 4 + 1 = 12(个),所以这一队一共有12个同学。", + "knowledge_points": [ + "连加(20 以内)" + ], + "source": "24-25一年级上·全国·单元测试" + }, + { + "id": "144", + "unit": "第五单元20以内的进位加法", + "question_type": "填空题", + "difficulty": 0.65, + "question": "小月在做加法计算时,把其中一个加数6误抄成了9,算出的结果是14,正确的结果是( )。", + "options": [], + "answer": "11", + "solution": "【分析】根据题意,先用错误的加数和错误的和,计算出另一个加数是几,根据凑十法计算。再用两个加数相加就是正确的和.\n【详解】9 + ( ) = 14,9 和 1 合起来就是10,再加上4就是14,即 9 + 5 = 14,另一个加数是5;6 + 5 = 11,正确的结果是11。", + "knowledge_points": [ + "9加几的进位加法", + "7,6加几的进位加法" + ], + "source": "24-25 一年级上·全国·单元测试" + }, + { + "id": "145", + "unit": "第五单元20以内的进位加法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "陈老师和王老师要带着 9 名同学去看科技展,一共需要买( )张门票。", + "options": [], + "answer": "11", + "solution": "【分析】一共有几人就需要买几张票,先计算出老师需要的数量,再和同学需要的数量相加即可.\n【详解】1 + 1 = 2(张),2 + 9 = 11(张)。陈老师和王老师要带着9名同学去看科技展,一共需要买11张门票。", + "knowledge_points": [ + "5∼2 加几的进位加法" + ], + "source": "24-25 一年级上·全国·单元测试" + }, + { + "id": "146", + "unit": "第五单元20以内的进位加法", + "question_type": "填空题", + "difficulty": 0.65, + "question": "在括号里填上\">\"\"<\"或\"=\".\n\n\n5 + 7 ( ) 9 + 79 + 8 ( ) 8 + 4\n\n\n\n2 + 9 ( ) 11 + 43 + 8 ( ) 9 + 5\n", + "options": [], + "answer": "<;>;<;<", + "solution": "【分析】根据整数加减法的计算法则,依次计算出各算式的结果再比较大小。20 以内数从大到小的关系为:20 > 19 > 18 > 17 > 16 > 15 > 14 > 13 > 12 > 11 > 10 > 9 > 8 > 7 > 6 > 5 > 4 > 3 > 2 > 1,由此比较.\n【详解】5 + 7 = 12,9 + 7 = 16,12<16,则 5+7<9+7;9 + 8 = 17,8+4=12,17>12,则 9+8>8+4;2 + 9 = 11,11 + 4 = 15,11<15,则 2+9<11+4;3+8=11,9+5=14,11<14,则 3+8<9+5。", + "knowledge_points": [ + "9 加几的进位加法", + "5∼2 加几的进位加法", + "8 加几的进位加法", + "20以内数的比大小" + ], + "source": "24-25 一年级上·全国·课后作业" + }, + { + "id": "147", + "unit": "第五单元20以内的进位加法", + "question_type": "填空题", + "difficulty": 0.4, + "question": "一个牧羊人去放羊,第一个月他发现少了 9 只羊,第二个月又发现少了 6 只羊,正当他着急的时候,突然发现羊群中有一只披着羊皮的狼,两个月一共少了( )只羊。", + "options": [], + "answer": "16", + "solution": "【分析】由题意可知,第一个月少了9只羊,第二个月少了6只羊,羊群中有一只披着羊皮的狼,说明还有1只羊也被吃掉了,用9加6再加1即可求出两个月一共少了多少只羊。理清题目中所有数量之间的关系,注意隐藏条件.\n【详解】9 + 6 + 1 = 16(只),两个月一共少了16只羊。", + "knowledge_points": [ + "连加(20以内)" + ], + "source": "24-25一年级上·全国·课后作业" + }, + { + "id": "148", + "unit": "第五单元20以内的进位加法", + "question_type": "填空题", + "difficulty": 0.65, + "question": "某校军训的学生进行列队表演,排列了一个7行7列的正方形队列。如果每去掉一行同时增加一列,当仅剩下一行时,这一行的人数为( )人。", + "options": [], + "answer": "13", + "solution": "【分析】如果每去掉一行同时增加一列,当仅剩下一行时,就是去掉了6行,增加6列,也就是剩下的一列增加6个人.\n【详解】7 - 1 = 6(人),7 + 6 = 13(人),这一行的人数为13人。", + "knowledge_points": [ + "7,6 加几的进位加法" + ], + "source": "2007 四年级·全国·竞赛" + }, + { + "id": "149", + "unit": "第五单元20以内的进位加法", + "question_type": "填空题", + "difficulty": 0.65, + "question": "想一想,填一填.\n\n\n7 + ( ) = 105 + 8 = ( ) + 710 - ( ) > 7\n\n\n\n( ) + 4 = 14 ( ) + 8 = 159 + ( ) = 18\n", + "options": [], + "answer": "3;6;2;10;7;9", + "solution": "【分析】10 可以分成7和3;有算式的先算出算式结果,13可以分成7和6;10-0=10,10-1=9,10-2=8,都大于7;14 可以分成4和10;15 可以分成8和7;18 可以分成9和9.\n【详解】7 + 3 = 10;5 + 8 = 13,13可以分成7和6,所以 5+8=6+7;10 - 0 = 10,10 - 1 = 9,10 - 2 = 8,10-0>7,10-1>7,10-2>7;14可以分成4和10,10 + 4 = 14;15可以分成8和7,7 + 8 = 15;18可以分成9和9,9 + 9 = 18。", + "knowledge_points": [ + "9 加几的进位加法", + "5∼2 加几的进位加法", + "10 的加减法" + ], + "source": "22-23一年级上·江苏盐城·期末" + }, + { + "id": "150", + "unit": "第五单元20以内的进位加法", + "question_type": "判断题", + "difficulty": 0.85, + "question": "4+7<10。( )", + "options": [], + "answer": "×", + "solution": "【分析】先计算出 4+7 的答案,然后和10作比较。比较时,位数多的数就大;位数相同比较最高位,最高位大的数就大;最高位相同比较下一位,直到比较出结果为止.\n【详解】4 + 7 = 11,11>10,则 4+7<10 这一说法错误。故答案为: ×", + "knowledge_points": [ + "5∼2 加几的进位加法", + "20以内数的比大小" + ], + "source": "24-25 一年级上·陕西延安·期末" + }, + { + "id": "151", + "unit": "第五单元20以内的进位加法", + "question_type": "判断题", + "difficulty": 0.85, + "question": "按顺序,1,3,5,7,9,( )。括号里填11。( )", + "options": [], + "answer": "√", + "solution": "【分析】观察题干可知:1和3相差2,3和5相差2,5和7 相差2,7和9相差2,所以这列数字从左往右依次增加2,据此解答即可.\n【详解】9 + 2 = 11,所以这列数字为:1,3,5,7,9,11。题干说法正确。故答案为:√", + "knowledge_points": [ + "整数排列的规律" + ], + "source": "24-25 一年级上·山东菏泽·期末" + }, + { + "id": "152", + "unit": "第五单元20以内的进位加法", + "question_type": "判断题", + "difficulty": 0.85, + "question": "大门两旁各摆了 9盆花,一共摆了19盆花。( )", + "options": [], + "answer": "×", + "solution": "【分析】据题意,大门两旁各摆了9盆花,即有两个9盆花,相加即可得出共多少盆花.\n【详解】据题意:9 + 9 = 18(盆),而题目中是一共摆了19盆花,与正确答案不符。故答案为: ×", + "knowledge_points": [ + "9加几的进位加法" + ], + "source": "24-25 一年级上·全国·单元测试" + }, + { + "id": "153", + "unit": "第五单元20以内的进位加法", + "question_type": "判断题", + "difficulty": 0.85, + "question": "9+3=8+□,□里应填4。( )", + "options": [], + "answer": "√", + "solution": "【分析】先计算出左侧算式的结果,再根据凑十法计算出方框里应填的数即可.\n【详解】9 + 3 = 12;8 + □ = 12,8 和 2 合起来就是10,再加上2就是12,即 8 + 4 = 12,□里应填4。原题说法正确。故答案为:√", + "knowledge_points": [ + "9 加几的进位加法", + "8 加几的进位加法" + ], + "source": "24-25 一年级上·全国·单元测试" + }, + { + "id": "154", + "unit": "第五单元20以内的进位加法", + "question_type": "判断题", + "difficulty": 0.94, + "question": "9 和 3 相加的和是12。( )", + "options": [], + "answer": "√", + "solution": "【分析】求两个数的和是多少,用加法列式计算;由此计算后再判断即可.\n【详解】由题意分析得:9 + 3 = 12,即9和3相加的和是12。原题说法正确。故答案为:√", + "knowledge_points": [ + "9加几的进位加法" + ], + "source": "22-23 二年级上·江苏盐城·期末" + }, + { + "id": "155", + "unit": "第五单元20以内的进位加法", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式计算.\n![](images/11a4188f116dcfe9707367cc411692980e2aec3adbb217bd2f5d071b03a46e19.jpg)", + "options": [], + "answer": "9+7=16", + "solution": "【分析】把剩下的樱桃数量与吃了的数量加起来,求出和就是原来的数量.\n【详解】由题意分析得:9 + 7 = 16(个)。", + "knowledge_points": [ + "9 加几的进位加法", + "图文问题" + ], + "source": "24-25 一年级上·全国·假期作业" + }, + { + "id": "156", + "unit": "第五单元20以内的进位加法", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式计算.\n![](images/58e00892c34bcb5d08f90796901284cc697528eda4ec7cc6778db0231244f87e.jpg)\n\n□ ○ □ = □", + "options": [], + "answer": "8+7=15", + "solution": "【分析】把左边的萝卜数量与右边的数量加起来,求出和,就是一共的数量.\n【详解】由题意分析得:8 + 7 = 15(根),一共有15根。", + "knowledge_points": [ + "图文问题", + "8 加几的进位加法" + ], + "source": "24-25 一年级上·河南驻马店·期末" + }, + { + "id": "157", + "unit": "第五单元20以内的进位加法", + "question_type": "计算题", + "difficulty": 0.65, + "question": "看图列式计算.\n![](images/429fcb1891bb3e8d9064b3ddcefd342a30d7e3e43f84cdd830c95ab22f9841a0.jpg)\n\n□ ○ □ = □", + "options": [], + "answer": "6+5=11", + "solution": "【分析】左边的蜜蜂数量+右边的蜜蜂数量=蜜蜂的总数量,据此列式计算即可.\n【详解】6 + 5 = 11。", + "knowledge_points": [ + "图文问题", + "7,6 加几的进位加法" + ], + "source": "24-25 一年级上·甘肃天水·期末" + }, + { + "id": "158", + "unit": "第五单元20以内的进位加法", + "question_type": "计算题", + "difficulty": 0.65, + "question": "看图列式计算.\n![](images/e969deca9ec159134d9f8cc2642b29f6c23c70d723b327572b13fb9b14aa22a7.jpg)\n\n□ ○ □ = □", + "options": [], + "answer": "6+5=11 或 5+6=11", + "solution": "【分析】根据题意,左边书包有6本,右边有5本,求一共有多少本。把左,右两边的数量相加即可求出一共有多少本.\n【详解】6 + 5 = 11(本)或 5 + 6 = 11(本),一共11本。", + "knowledge_points": [ + "图文问题", + "7,6加几的进位加法" + ], + "source": "24-25 一年级上·广东汕头·期末" + }, + { + "id": "159", + "unit": "第五单元20以内的进位加法", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列算式.\n![](images/5ca8f6726529b9e9399ef510f6e93c89e849be1783528aca62ca6d4fa8f435a7.jpg)\n□ ○ □ ○ □= □(个)", + "options": [], + "answer": "2 + 4 + 7 = 13", + "solution": "【分析】将左边,中间,右边的个数相加即可求出一共多少个.\n【详解】2 + 4 + 7 = 13(个)", + "knowledge_points": [ + "图文问题", + "连加(20 以内)" + ], + "source": "24-25 一年级上·湖南常德·期末" + }, + { + "id": "160", + "unit": "第五单元20以内的进位加法", + "question_type": "计算题", + "difficulty": 0.65, + "question": "看图列算式.\n![](images/08e9a8efc4b2432905dd0f23f91e3f9a127aa7f040b058f2c95ab3d2c4eb4f55.jpg)\n□ ○ □ ○ □ = □(条)", + "options": [], + "answer": "3 + 6 + 2 = 11", + "solution": "【分析】根据题意,第一组有3条,第二组有6条,第三组有2条,求一共有多少条。把三组的条数相加即可求出一共多少条,据此列式计算.\n【详解】3 + 6 + 2 = 11(条)(列式不唯一)一共11条。", + "knowledge_points": [ + "连加(20以内)" + ], + "source": "24-25 一年级上·湖南常德·期末" + }, + { + "id": "161", + "unit": "第五单元20以内的进位加法", + "question_type": "计算题", + "difficulty": 0.65, + "question": "看图列式.\n![](images/2e1e382f55c4f44e4e88cb39d4aaaaafc00352c9d9eb67e10188bbeaf8170422.jpg)\n□ ○ □ ○ □ = □(只)", + "options": [], + "answer": "4 + 4 + 3 = 11", + "solution": "【分析】由图可知,第一组有4只,第二组有4只,第三组有3只,求一共有多少只,把3组的数量相加即可求出一共有多少只.\n【详解】4 + 4 + 3 = 11(只)一共11只。", + "knowledge_points": [ + "图文问题", + "连加(20 以内)" + ], + "source": "24-25 一年级上·广东阳江·期末" + }, + { + "id": "162", + "unit": "第五单元20以内的进位加法", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式计算.\n![](images/d9cadbaed0b58a915b12f55a762725a1d9351c3c4cef2bfaefb2c9666eb0f45f.jpg)\n□ ○ □ ○ □ = □(只)", + "options": [], + "answer": "8 + 6 = 14", + "solution": "【分析】大括号下面的问号是求总和,数出左边有6只,右边有8只,将左边的数量加上右边的数量即可.\n【详解】8 + 6 = 14(只)一共有14只。", + "knowledge_points": [ + "8 加几的进位加法" + ], + "source": "24-25 一年级上·湖北武汉·期末" + }, + { + "id": "163", + "unit": "第五单元20以内的进位加法", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图写算式.\n![](images/0dce8afa82b01552f847849a7b1d6925d26eecac50385d6ab37a25bf087af730.jpg)\n□ ○ □ = □(只)", + "options": [], + "answer": "5 + 6 = 11", + "solution": "【分析】把鸡的数量与鸭数量加起来,求出和,就是一共的数量.\n【详解】由题意分析得:5 + 6 = 11(只)一共有11只动物。", + "knowledge_points": [ + "5∼2 加几的进位加法" + ], + "source": "24-25一年级上·山东菏泽·期末" + }, + { + "id": "164", + "unit": "第五单元20以内的进位加法", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式并计算.\n![](images/d2ebe9ca47305a7ccfbfbb7610df006171eda7520990c2304dabd157c0436f7c.jpg)\n□ ○ □ ○ □ = □(只)", + "options": [], + "answer": "4 + 2 + 5 = 11", + "solution": "【分析】根据图片可知:左边有4只松鼠,中间有2只松鼠,右边有5只松鼠,现在一共多少只。用左边的数量加上中间的数量再加上右边的数量.\n【详解】4 + 2 + 5 = 11(只)一共有11只。", + "knowledge_points": [ + "连加(20 以内)" + ], + "source": "24-25一年级上·陕西榆林·期末" + }, + { + "id": "165", + "unit": "第五单元20以内的进位加法", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式计算.\n![](images/1ece1f4bd9483b1bf9fa24d9f0a55026a12b0ead1971422f97bc7fe109fd01d5.jpg)\n□ ○ □ = □(只)", + "options": [], + "answer": "7 + 6 = 13", + "solution": "【分析】左边有7只小鸭,右边有6只小鸭,求一共有几只小鸭,用加法计算,即左边的数量+右边的数量=总数量.\n【详解】7 + 6 = 13(只)一共有13只小鸭。", + "knowledge_points": [ + "图文问题", + "7,6加几的进位加法" + ], + "source": "24-25一年级上·山东济南·期末" + }, + { + "id": "166", + "unit": "第五单元20以内的进位加法", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列算式.\n![](images/8bb35c48f0220d91db9617ab2cced98c15fb616097678c2e8bdc568ecad09e06.jpg)\n□ ○ □ = □(只)", + "options": [], + "answer": "8 + 6 = 14", + "solution": "【分析】左右两边的数量相加即可求出一共有多少个.\n【详解】8 + 6 = 14(个)一共14个。", + "knowledge_points": [ + "图文问题", + "8 加几的进位加法", + "7,6 加几的进位加法" + ], + "source": "24-25 一年级上·河北秦皇岛·期末" + }, + { + "id": "167", + "unit": "第五单元20以内的进位加法", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列算式.\n![](images/98ee106936f87b3c31d674fdcee17f77d5165778499aaf68284b6c206aae6f59.jpg)\n□ ○ □ = □(只)", + "options": [], + "answer": "8 + 6 = 14", + "solution": "【分析】左边有8个梨,右边有6个梨,求一共有多少个梨,用加法计算,即左边的数量+右边的数量=总数量.\n【详解】8 + 6 = 14(个)一共有14个梨。", + "knowledge_points": [ + "图文问题", + "8 加几的进位加法" + ], + "source": "24-25 一年级上·河北唐山·期末" + }, + { + "id": "168", + "unit": "第五单元20以内的进位加法", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式计算.\n![](images/dd1545050042a49599bb9a44d0277895b9496df4607ab46f738f5f7f9df7d960.jpg)\n□ ○ □ = □(颗)", + "options": [], + "answer": "5 + 8 = 13", + "solution": "【分析】把左,右两边的棒棒糖的数量加起来,结果就是总数量.\n【详解】由题意分析得:5 + 8 = 13(颗)", + "knowledge_points": [ + "图文问题", + "5∼2 加几的进位加法" + ], + "source": "24-25 一年级上·全国·假期作业" + }, + { + "id": "169", + "unit": "第五单元20以内的进位加法", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式计算.\n![](images/2d798a5cd44b9453e0d11c2a20281e56104a92eb66de1d98e5181536bf50f085.jpg)\n□ ○ □ = □(只)", + "options": [], + "answer": "9 + 4 = 13", + "solution": "【分析】根据图片可知:左边有9支粉笔,右边4支,问一共有多少支。用左边的数量加右边的数量即可.\n【详解】9 + 4 = 13(支)", + "knowledge_points": [ + "9 加几的进位加法" + ], + "source": "24-25 一年级上·全国·单元测试" + }, + { + "id": "170", + "unit": "第五单元20以内的进位加法", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式计算.\n![](images/8972f46b5aa892184e9816159cf68af2f2e42e845bd66c88571861d3da56b314.jpg)\n□ ○ □ = □(只)", + "options": [], + "answer": "9 + 5 = 14", + "solution": "【分析】把左边的梨数量与右边的梨数量加起来,求出和,就是梨的总数量.\n【详解】由题意分析得:9 + 5 = 14(个)一共有14个梨。", + "knowledge_points": [ + "9加几的进位加法", + "图文问题" + ], + "source": "2024 一年级上·全国·专题练习" + }, + { + "id": "171", + "unit": "第五单元20以内的进位加法", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式计算.\n![](images/9599eae4721a2046333b29579621d1316dc707e2aae863a84319fd690d675191.jpg)\n□ ○ □ = □(个)", + "options": [], + "answer": "6 + 9 = 15", + "solution": "【分析】由图可知,左边有6个足球,右边筐里有9个足球,求一共有几个足球,根据加法的意义,用左边足球的数量加上右边筐里的足球的数量即可.\n【详解】6 + 9 = 15(个)所以一共有15个足球。", + "knowledge_points": [ + "图文问题", + "7,6 加几的进位加法" + ], + "source": "24-25 一年级上·全国·课后作业" + }, + { + "id": "172", + "unit": "第五单元20以内的进位加法", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式计算.\n![](images/f487837a17da4d88beffc47c0e671dae0f9e63414c0d2251f1619994fc9d504f.jpg)\n![](images/a907dd164d85cdf95575b73f286829c8eb9a238c971671fdcb55381b110fa3a5.jpg)\n□ ○ □ = □(个)", + "options": [], + "answer": "9 + 6 = 15", + "solution": "【分析】左边有9个球,右边有6个,求一共有几个球,用加法计算,即左边的数量+右边的数量=总数量.\n【详解】9 + 6 = 15(个)一共有15个球。", + "knowledge_points": [ + "9 加几的进位加法", + "图文问题" + ], + "source": "24-25 一年级上·全国·单元测试" + }, + { + "id": "173", + "unit": "第五单元20以内的进位加法", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式计算.\n![](images/eae25ce995dbcb3ff7f741ca9699180d9b512cc3a11e2f85629192a91b869f9f.jpg)\n□ ○ □ = □(颗)", + "options": [], + "answer": "7 + 8 = 15", + "solution": "【分析】左边有7颗糖果,右边有8颗糖果,求一共有几颗糖果,用加法计算,即左边的数量+右边的数量=总数量.\n【详解】7 + 8 = 15(颗)一共有15颗糖果。", + "knowledge_points": [ + "图文问题", + "7,6 加几的进位加法" + ], + "source": "24-25 一年级上·全国·单元测试" + }, + { + "id": "174", + "unit": "第五单元20以内的进位加法", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式计算.\n![](images/ad98f4819512fc2b956f651d269f90baf6b1a464f66e25c2b91bcfa0d67b1f72.jpg)\n□ ○ □ = □(个)", + "options": [], + "answer": "2 + 9 = 11", + "solution": "【分析】左边2个,右边9个,左右两边相加即可求出一共有多少个.\n【详解】2 + 9 = 11(个)即有11个苹果。", + "knowledge_points": [ + "9 加几的进位加法", + "图文问题", + "5∼2 加几的进位加法" + ], + "source": "24-25 一年级上·全国·单元测试" + }, + { + "id": "175", + "unit": "第五单元20以内的进位加法", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式计算.\n![](images/4d9ba8910e8df004a70675a55ae2612b7dcb6e6b98ec00813bc3537a2432e287.jpg)\n□ ○ □ = □(只)", + "options": [], + "answer": "9 + 4 = 13", + "solution": "【分析】把左边房子里的兔子数量与右边的数量加起来,求出和,就是兔子的总数量.\n【详解】由题意分析得:9 + 4 = 13(只)一共有13只兔子。", + "knowledge_points": [ + "9加几的进位加法", + "图文问题" + ], + "source": "24-25 一年级上·全国·期末" + }, + { + "id": "176", + "unit": "第五单元20以内的进位加法", + "question_type": "计算题", + "difficulty": 0.65, + "question": "看图列式计算.\n![](images/29a94a57f0fe8e18c2d91fc253f4b746355fb6d0de0cf7decbd93a7d866207cf.jpg)\n□ ○ □ = □(瓶)", + "options": [], + "answer": "8 + 6 = 14", + "solution": "【分析】左边8瓶,右边6瓶,左右两边相加即可求出一共有多少瓶.\n【详解】8 + 6 = 14(瓶)", + "knowledge_points": [ + "图文问题", + "8 加几的进位加法", + "7,6 加几的进位加法" + ], + "source": "24-25 一年级上·全国·课后作业" + }, + { + "id": "177", + "unit": "第五单元20以内的进位加法", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式计算.\n![](images/ebcfe7f035f4bd6382d24aa791ee7df0a0d769087ba25b77fe8c95b14773b404.jpg)\n□ ○ □ = □(只)", + "options": [], + "answer": "7 + 6 = 13", + "solution": "【分析】左边有7只小青蛙,右边有6只小青蛙,求一共有多少只小青蛙,用加法计算,即左边的数量+右边的数量=总数量.\n【详解】7 + 6 = 13(只)一共有13只小青蛙。", + "knowledge_points": [ + "图文问题", + "7,6加几的进位加法" + ], + "source": "24-25 一年级上·全国·课后作业" + }, + { + "id": "178", + "unit": "第五单元20以内的进位加法", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式计算.\n![](images/e72e868a40a9ef5732659976dec988adc5b18dbf952dc1a4f5bd30cf57c048be.jpg)\n□ ○ □ = □(朵)", + "options": [], + "answer": "8 + 3 = 11", + "solution": "【分析】左边有8朵花,右边有3朵花,求一共有几朵花,用加法计算,即左边的数量+右边的数量=总数量.\n【详解】8 + 3 = 11(朵)一共有11朵花。", + "knowledge_points": [ + "图文问题", + "8加几的进位加法" + ], + "source": "24-25 一年级上·全国·课后作业" + }, + { + "id": "179", + "unit": "第五单元20以内的进位加法", + "question_type": "计算题", + "difficulty": 0.65, + "question": "看图列式.\n![](images/b4bd7af0682689472510cc6d3fbb54773e09c9d464c318c41f65cd391a4fba42.jpg)\n□ ○ □ = □()(瓶)", + "options": [], + "answer": "9 + 3 = 12", + "solution": "【分析】左边有9瓶,右边有3瓶,左右两边相加即可求出共有多少瓶.\n【详解】9 + 3 = 12(瓶)", + "knowledge_points": [ + "9 加几的进位加法", + "图文问题" + ], + "source": "24-25 一年级上·全国·课后作业" + }, + { + "id": "180", + "unit": "第五单元20以内的进位加法", + "question_type": "计算题", + "difficulty": 0.65, + "question": "看图列式计算.\n![](images/94bf3c98a92b12c3b41ef8df6eb88068300fa8d426762f4d1d079184df196f7d.jpg)\n□ ○ □ = □(支)", + "options": [], + "answer": "6 + 8 = 14", + "solution": "【分析】由图可知,左边盒子里有6支铅笔,右边有8支铅笔,求一共有几支铅笔,根据加法的意义,用左边盒子里铅笔的数量加上右边铅笔的数量即可.\n【详解】6 + 8 = 14(支)所以一共有14支铅笔。", + "knowledge_points": [ + "图文问题", + "7,6 加几的进位加法" + ], + "source": "2024 一年级上·全国·单元测试" + }, + { + "id": "181", + "unit": "第五单元20以内的进位加法", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式计算.\n![](images/6b801f5dd6e1b10e87b001ccde6aa1decf36e4e5b7f8ccdc8012e4a9e5a291cc.jpg)\n□ ○ □ = □(只)", + "options": [], + "answer": "9 + 6 = 15", + "solution": "【分析】左边9只蜜蜂,右边6只蜜蜂,左右两边相加即可求出一共有多少只蜜蜂.\n【详解】9 + 6 = 15(只)一共有15只蜜蜂。", + "knowledge_points": [ + "9 加几的进位加法", + "图文问题", + "7,6 加几的进位加法" + ], + "source": "24-25 一年级上·全国·期末" + }, + { + "id": "182", + "unit": "第五单元20以内的进位加法", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式计算.\n![](images/3e532754458f2a78246c36e731a8b5ef773e0d36a505603579548c07e315ca03.jpg)\n□ ○ □ = □(个)", + "options": [], + "answer": "4 + 8 = 12", + "solution": "【分析】左边4个,右边8个,左右两边相加即可求出一共有多少个.\n【详解】4 + 8 = 12(个)", + "knowledge_points": [ + "图文问题", + "5∼2 加几的进位加法", + "8 加几的进位加法" + ], + "source": "24-25 一年级上·全国·课后作业" + }, + { + "id": "183", + "unit": "第五单元20以内的进位加法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "一共吃了多少个萝卜。\n兔子1:我吃了6个萝卜。 兔子2:我吃了5个萝卜。 兔子3:我吃了4个萝卜.\n□ ○ □ ○ □= □(个)", + "options": [], + "answer": "6 + 5 + 4 = 15", + "solution": "【分析】用加法把三只兔子吃了的萝卜数量加起来,求出和,就是一共吃了的萝卜数量.\n【详解】6+5+4 = 11 + 4 = 15(个)答:一共吃了15个萝卜。", + "knowledge_points": [ + "连加(20以内)" + ], + "source": "24-25 一年级上·河南驻马店·期末" + }, + { + "id": "184", + "unit": "第五单元20以内的进位加法", + "question_type": "解答题", + "difficulty": 0.65, + "question": "小明吃了 9 个饺子,碗里还有 6 个饺子,他原来有多少个饺子。\n□ ○ □ = □(个)", + "options": [], + "answer": "9 + 6 = 15", + "solution": "【分析】根据题意,用吃了的饺子数量加上还剩的饺子数量,即可求出原来有多个饺子。据此解答.\n【详解】9 + 6 = 15(个)答:他原来有15个饺子。", + "knowledge_points": [ + "9加几的进位加法" + ], + "source": "24-25 一年级上·广东阳江·期末" + }, + { + "id": "185", + "unit": "第五单元20以内的进位加法", + "question_type": "解答题", + "difficulty": 0.65, + "question": "一(1)班有 7 根跳绳,一(2)班有 8 根跳绳,这两个班一共有多少根跳绳。\n□ ○ □ = □(根)", + "options": [], + "answer": "7 + 8 = 15", + "solution": "【分析】求两个班一共有几根跳绳,用加法计算,即一(1)班跳绳的数量+一(2)班跳绳的数量=两个班跳绳的总数量.\n【详解】7 + 8 = 15(根)答:这两个班一共有15根跳绳。", + "knowledge_points": [ + "7,6 加几的进位加法" + ], + "source": "24-25 一年级上·甘肃天水·期末" + }, + { + "id": "186", + "unit": "第五单元20以内的进位加法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "班级图书角有一些绘本,同学们借走了9本,还剩下7本,图书角原来有多少本绘本。\n□ ○ □ = □(本)", + "options": [], + "answer": "9 + 7 = 16", + "solution": "【分析】用借走的数量加上还剩下的数量,就能算出原来的数量,据此解答.\n【详解】9 + 7 = 16(本)答:图书角原来有16本绘本。", + "knowledge_points": [ + "9加几的进位加法" + ], + "source": "24-25一年级上·河北唐山·期末" + }, + { + "id": "187", + "unit": "第五单元20以内的进位加法", + "question_type": "解答题", + "difficulty": 0.65, + "question": "小玲家有 8 只白兔和 7 只灰兔。小玲家一共有多少只兔子。\n□ ○ □ = □(只)", + "options": [], + "answer": "8 + 7 = 15", + "solution": "【分析】求一共有多少只兔子,用加法计算,即白兔的数量+灰兔的数量=兔子的总数量.\n【详解】8 + 7 = 15(只)答:小玲家一共有15只兔子。", + "knowledge_points": [ + "8 加几的进位加法" + ], + "source": "24-25 一年级上·甘肃嘉峪关·期末" + }, + { + "id": "188", + "unit": "第五单元20以内的进位加法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "原来有多少块西瓜。\n![](images/746119a135fc0f8a766aab67f6051146f11d9aa8d0370a09ccefd041312ade7d.jpg)吃了 6 块,还剩 5 块。", + "options": [], + "answer": "6 + 5 = 11", + "solution": "【分析】把吃了的西瓜数量与还剩的数量加起来,求出和,就是原来的数量.\n【详解】6 + 5 = 11(块)答:原来有11块西瓜。", + "knowledge_points": [ + "7,6加几的进位加法" + ], + "source": "24-25一年级上·山东临沂·期末" + }, + { + "id": "189", + "unit": "第五单元20以内的进位加法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "小丽有7枚风景邮票和9枚动物邮票。小丽的风景邮票和动物邮票共有多少枚。", + "options": [], + "answer": "16 枚", + "solution": "【分析】用小丽的风景邮票数量和动物邮票数量相加即可求解.\n【详解】7 + 9 = 16(枚)答:小丽的风景邮票和动物邮票共有16枚。", + "knowledge_points": [ + "9加几的进位加法", + "7,6加几的进位加法" + ], + "source": "24-25一年级上·青海西宁·期末" + }, + { + "id": "190", + "unit": "第五单元20以内的进位加法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "地里原来一共有多少个萝卜。\n![](images/860de55307afa8d28c7fbdd2c166edaffaa5f99ece8d239fc4b3471589f11efe.jpg)\n□ ○ □ = □(个)", + "options": [], + "answer": "6 + 6 = 12", + "solution": "【分析】根据加法的意义,拔了的数量+还剩的数量=原来地里的数量,由此解答.\n【详解】6 + 6 = 12(个)答:地里原来一共有12个萝卜。", + "knowledge_points": [ + "图文问题", + "7,6 加几的进位加法" + ], + "source": "24-25 一年级上·全国·课后作业" + }, + { + "id": "191", + "unit": "第五单元20以内的进位加法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "小红和伙伴们租了两条船,一条坐了 8 人,另一条坐了 6 人,一共有多少人。", + "options": [], + "answer": "14 人", + "solution": "【分析】求一共有多少人,用加法计算,即一条船坐的人数+另一条船坐的人数=总人数.\n【详解】8 + 6 = 14(人)答:一共有14人。", + "knowledge_points": [ + "8加几的进位加法" + ], + "source": "23-24二年级上·河南安阳·期末" + }, + { + "id": "192", + "unit": "第五单元20以内的进位加法", + "question_type": "解答题", + "difficulty": 0.94, + "question": "花店进了一些康乃馨,一个花瓶里装 5 枝,另一个花瓶里装 6 枝。一共有多少枝康乃馨。", + "options": [], + "answer": "11 枝", + "solution": "【分析】求一共有多少枝,用加法计算,即一个花瓶里装的枝数+另一个花瓶里装的枝数=一共的枝数.\n【详解】5 + 6 = 11(枝)答:一共有11枝康乃馨。", + "knowledge_points": [ + "5∼2 加几的进位加法" + ], + "source": "24-25二年级上·河南驻马店·期中" + }, + { + "id": "193", + "unit": "第五单元20以内的进位加法", + "question_type": "解答题", + "difficulty": 0.65, + "question": "动物园里小动物比赛吃水果,小猴子已经吃了8个桃子,还剩下4个没吃,小猴一共要吃多少个桃子。\n□ ○ □ = □(个)", + "options": [], + "answer": "8 + 4 = 12(个)", + "solution": "【分析】根据题意可知:用小猴吃的数量加上没有吃的数量即可求出一共要吃的数量.\n【详解】8 + 4 = 12(个)答:小猴一共要吃12个桃子。", + "knowledge_points": [ + "8加几的进位加法" + ], + "source": "2024一年级上·全国·专题练习" + }, + { + "id": "194", + "unit": "第五单元20以内的进位加法", + "question_type": "解答题", + "difficulty": 0.65, + "question": "妈妈买来一些苹果,第一天吃了总数的一半,第二天吃了剩下苹果的一半,最后剩下 3 个,妈妈一共买了多少个苹果。\n![](images/9d687e0d68cc2c3bf0ed05f2860be4ee1d664c2dc463ff0ea3c8d0c29b9aac61.jpg)", + "options": [], + "answer": "12 个", + "solution": "【分析】可以运用画图法来解决。从图中可以看出,剩下的3个是苹果总数一半的一半,也就是2个3的和是苹果的一半,再将两个一半的数量相加,就是苹果的总数量.\n【详解】苹果的一半:3 + 3 = 6(个);苹果的总数量:6 + 6 = 12(个)。答:妈妈一共买了12个苹果。", + "knowledge_points": [ + "6 的加减法", + "7,6 加几的进位加法" + ], + "source": "24-25 一年级上·全国·课后作业" + }, + { + "id": "195", + "unit": "第五单元20以内的进位加法", + "question_type": "解答题", + "difficulty": 0.4, + "question": "从前面数小红排第 8,从后面数小红排第 6。这一队一共有多少人。", + "options": [], + "answer": "13 人", + "solution": "【分析】用8加6,小红被加了两次,再减去1即可求出这一队一共有多少人.\n【详解】8 + 6 - 1 = 13(人)答:这一队一共有13人。", + "knowledge_points": [ + "左,右位置", + "加减混合运算(20 以内)" + ], + "source": "24-25 一年级上·江苏·单元测试" + }, + { + "id": "196", + "unit": "第五单元20以内的进位加法", + "question_type": "解答题", + "difficulty": 0.65, + "question": "一共有多少个足球。\n![](images/9c9b1baf6d7b9545c37d7e7f12991e97d3eb4abd78206d62ba17c1d1e1ecc27a.jpg)\n□ ○ □ = □", + "options": [], + "answer": "9 + 6 =15", + "solution": "【分析】左边9个,右边6个,左右两边相加即可求出一共有多少个.\n【详解】9 + 6 = 15(个)答:一共有15个足球。", + "knowledge_points": [ + "9 加几的进位加法", + "图文问题" + ], + "source": "24-25 一年级上·全国·课后作业" + }, + { + "id": "197", + "unit": "第五单元20以内的进位加法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "停车场原来停着 9辆小汽车,一小时后,又开进来8辆车,现在停车场里有多少辆车。\n□ ○ □ = □(辆)", + "options": [], + "answer": "9 + 8 = 17", + "solution": "【分析】原来有9辆小汽车,又开来了8辆车,求现在有多少辆车,用加法计算。用原来的数量加又开进来的数量即可.\n【详解】9 + 8 = 17(辆)答:现在停车场里有17辆车。", + "knowledge_points": [ + "9加几的进位加法" + ], + "source": "24-25 一年级上·全国·单元测试" + }, + { + "id": "198", + "unit": "第五单元20以内的进位加法", + "question_type": "解答题", + "difficulty": 0.65, + "question": "小朋友们玩\"老鹰捉小鸡\"的游戏,抓住了 8 人,还有 6 人没有被抓住。一共有多少个小朋友在玩游戏。", + "options": [], + "answer": "16 个", + "solution": "【分析】在做游戏的人数=抓住的人数+没有被抓住的人数+\"老鹰\"的人数+\"母鸡\"1人.\n【详解】8 + 6 + 1 + 1 = 16(个)答:一共有16个小朋友在玩游戏。", + "knowledge_points": [ + "连加(20以内)" + ], + "source": "24-25 一年级上·江苏·单元测试" + }, + { + "id": "199", + "unit": "第五单元20以内的进位加法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "一共有多少盒牛奶。\n![](images\\27960daefdb2d6f60227bcac4f629a4e.jpg)", + "options": [], + "answer": "9 + 9 = 18", + "solution": "【分析】左边有9盒牛奶,右边有9盒牛奶,求一共有多少盒牛奶,用加法计算,即左边的数量+右边的数量=总数量.\n【详解】9 + 9 = 18(盒)答:一共有18盒牛奶。", + "knowledge_points": [ + "9加几的进位加法", + "图文问题" + ], + "source": "24-25一年级上·全国·课后作业" + }, + { + "id": "200", + "unit": "第五单元20以内的进位加法", + "question_type": "解答题", + "difficulty": 0.65, + "question": "妈妈种了两盆花,一盆有6棵,另一盆有5棵,妈妈一共种了多少棵花。", + "options": [], + "answer": "11棵", + "solution": "【分析】把两盆花的棵数相加,即可计算出妈妈一共种了多少棵花。本题解题关键是根据加法的意义,列式计算,熟练掌握20以内加法的计算方法.\n【详解】6 + 5 = 11(棵)答:妈妈一共种了11棵花。", + "knowledge_points": [ + "5∼2 加几的进位加法", + "7,6加几的进位加法" + ], + "source": "23-24 二年级上·山东济宁·期中" + }, + { + "id": "201", + "unit": "第五单元20以内的进位加法", + "question_type": "选择题", + "difficulty": 0.65, + "question": "幼儿园大班有 17 人,每人一个球,选下面哪两袋比较合适。( )", + "options": [ + "A. ![](images/2819f609b173b399dca9bf1313bb9768428a8f6a4fa38069fc7cae646deb1324.jpg)", + "B. ![](images/bf1d6b80bba89b6d67e85d14ac61657b1ee044b90afa5f4526f0594c373f4a0d.jpg)", + "C. ![](images/5fa83bb9bb143605ecbd97dccec60f595b81474ec27cfad961344b0daca5e8ed.jpg)" + ], + "answer": "AB", + "solution": "【分析】先数出每袋的个数,选择的两袋加起来要大于或等于17,才能满足每人一个球.\n【详解】A。这袋有6个球 B。这袋有8个球 C。这袋有9个球,8 + 9 = 17(个),故答案为:AB。", + "knowledge_points": [ + "8加几的进位加法" + ], + "source": "22-23 一年级上·江苏盐城·期末" + }, + { + "id": "202", + "unit": "第五单元20以内的进位加法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "小朋友排队做操,小丽后面有5个人,从前往后数,小丽在第6个,这一队一共有( )个小朋友。", + "options": [ + "A. 12", + "B. 11", + "C. 13" + ], + "answer": "B", + "solution": "【分析】从前往后数,小丽在第6个,说明从前数到小丽这里一共有6人,再加上后面的5人,就是这一队一共的人数.\n【详解】6 + 5 = 11(人),即这一队一共有11个小朋友。故答案为:B.", + "knowledge_points": [ + "7,6加几的进位加法" + ], + "source": "22-23 一年级下·江苏淮安·开学考试" + }, + { + "id": "203", + "unit": "第五单元20以内的进位加法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "妈妈买了两盒共 12 只袜子,她买的是第( )款袜子。", + "options": [ + "A. 每盒 12 双", + "B. 每盒 6 双", + "C. 每盒 3 双" + ], + "answer": "C", + "solution": "【分析】根据题意可知:一双袜子是两只,两盒是 12 只,则一盒是 6 只,然后用 6 减 2,减完,数一数减了几次,就是有几双.\n【详解】6 + 6 = 12(只),6 - 2 = 4(只),4 - 2 = 2(只),2 - 2 = 0(只),减了3次,则有3双。故答案为:C.", + "knowledge_points": [ + "5以内数的减法", + "7,6加几的进位加法", + "6的加减法" + ], + "source": "23-24 一年级下·广东潮州·期末" + }, + { + "id": "204", + "unit": "第五单元20以内的进位加法", + "question_type": "选择题", + "difficulty": 0.65, + "question": "小力在做一道减法算式时,把减数6看成了9,算出的得数是8。原来正确的得数为( )。", + "options": [ + "A. 17", + "B. 15", + "C. 11", + "D. 5" + ], + "answer": "C", + "solution": "【分析】根据题意,用错误的减数+错误的差,计算出正确的被减数。再用正确的被减数-正确的减数,计算即可.\n【详解】9 + 8 = 17;17-6=11,正确的得数是11。故答案为:C.", + "knowledge_points": [ + "不退位减法(20 以内)", + "9加几的进位加法", + "错中求解问题(加减法)" + ], + "source": "23-24一年级下·福建龙岩·期末" + }, + { + "id": "205", + "unit": "第五单元20以内的进位加法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "妈妈买回一些苹果,小兰吃了 5 个,还剩 9 个,妈妈买回( )个。", + "options": [ + "A. 4", + "B. 14", + "C. 7" + ], + "answer": "B", + "solution": "【分析】要求妈妈买回多少个苹果,根据加法的意义,用小兰吃了的苹果数量加上剩下的苹果数量即可得出答案.\n【详解】5 + 9 = 14(个),所以妈妈买回14个苹果。故答案为:B.", + "knowledge_points": [ + "5~2加几的进位加法" + ], + "source": "23-24 一年级下·河南南阳·期末" + }, + { + "id": "206", + "unit": "第五单元20以内的进位加法", + "question_type": "选择题", + "difficulty": 0.65, + "question": "把12个苹果放在两个盘子里,有( )放法。", + "options": [ + "A. 6", + "B. 7", + "C. 12", + "D. 11" + ], + "answer": "B", + "solution": "【分析】分别可以放 0 个和 12 个,1 个和 11 个,2 个和 10 个,3 个和 9 个,4 个和 8 个,5 个和 7 个,6 个和 6 个,共有7种不同的放法,据此解答.\n【详解】把 12 个苹果放在两个盘子里,有 7 种不同的放法。故答案为:B.", + "knowledge_points": [ + "9加几的进位加法", + "5~2加几的进位加法", + "7,6加几的进位加法", + "8加几的进位加法" + ], + "source": "22-23一年级下·山东聊城·期末" + }, + { + "id": "207", + "unit": "第五单元20以内的进位加法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "如果一次只能端两盘,那么一次最多能端几个梨。( )\n![](images/3c768b39451d038affa3f3dd5c1fc37a.jpg)", + "options": [ + "A. 12 个", + "B. 13 个", + "C. 14 个" + ], + "answer": "C", + "solution": "【分析】根据题意,先比较每盘中梨数量的多少,再找到数量多的两盘相加即可求出最多能端的数量.\n【详解】3<5<9,5 + 9 = 14(个),一次最多能端 14 个梨。故答案为:C.", + "knowledge_points": [ + "5~2加几的进位加法", + "10以内数的比大小" + ], + "source": "23-24 一年级上·福建泉州·期末" + }, + { + "id": "208", + "unit": "第五单元20以内的进位加法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "下面算式中,( )的得数最小。", + "options": [ + "A. 5+6", + "B. 5+7", + "C. 5+8" + ], + "answer": "A", + "solution": "【分析】依次计算出各算式的结果再比较大小。20 以内数从小到大为:0<1<2<3<4<5<6<7<8<9<10<11<12<13<14<15<16<17<18<19<20,由此比较.\n【详解】A:5 + 6 = 11;B:5 + 7 = 12;C:5 + 8 = 13,11<12<13,所以 5+6 的得数最小。故答案为:A.", + "knowledge_points": [ + "20以内数的比大小", + "5~2加几的进位加法" + ], + "source": "23-24 一年级上·河北廊坊·期末" + }, + { + "id": "209", + "unit": "第五单元20以内的进位加法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "计算 8 + 5 = 时,思考错误的是( )。", + "options": [ + "A. 先计算 8 + 2 = 10,再算 10 + 3 = 13", + "B. 先计算 5 + 5 = 10,再算 10 + 8 = 18", + "C. 先计算 5 + 5 = 10,再算 10 + 3 = 13" + ], + "answer": "B", + "solution": "【分析】题中算式为进位加法的计算。可以用凑十法,将大数凑成十,或将小数凑成十,由此分析各选项解答即可.\n【详解】A:先算 8 + 2 = 10,再算 10 + 3 = 13,是把 5 分成了 2 和 3,把 8 先凑成 10 再计算,思考正确;B:先算 5 + 5 = 10,再算 10 + 8 = 18,是把 8 分成 5 和 3,把 5 凑成 10 后应该再将剩下的 3 加上,而不是加 8,思考错误;C:先算 5 + 5 = 10,再算 10 + 3 = 13,是把 8 分成 5 和 3,把 5 凑成 10 后再加 3,思考正确。故思考错误的是 B。答案为:B.", + "knowledge_points": [ + "8加几的进位加法" + ], + "source": "23-24一年级上·河南·期末" + }, + { + "id": "210", + "unit": "第五单元20以内的进位加法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "小明有6个桃,小林的桃与小明的同样多,他们共有( )个桃。", + "options": [ + "A. 12", + "B. 8", + "C. 6" + ], + "answer": "A", + "solution": "【分析】小林的桃与小明的同样多,所以小林也有 6 个桃,用 6 加 6 即可求出他们共有多少桃.\n【详解】6 + 6 = 12(个),因此他们共有12个桃。故答案为:A.", + "knowledge_points": [ + "7,6加几的进位加法" + ], + "source": "23-24一年级上·河南驻马店·期末" + }, + { + "id": "211", + "unit": "第五单元20以内的进位加法", + "question_type": "选择题", + "difficulty": 0.65, + "question": "与8+6相等的算式是( )。", + "options": [ + "A. 7+6", + "B. 9+5", + "C. 8+7" + ], + "answer": "B", + "solution": "【分析】8 + 6 = 14,分别计算各选项算式的结果进行比较.\n【详解】7 + 6 = 13,9 + 5 = 14,8 + 7 = 15,可知 8 + 6 = 9 + 5 = 14。故答案为:B.", + "knowledge_points": [ + "9加几的进位加法", + "7,6加几的进位加法", + "8加几的进位加法" + ], + "source": "23-24一年级上·河南三门峡·期末" + }, + { + "id": "212", + "unit": "第五单元20以内的进位加法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "小红吃了 8 个饺子,还剩 5 个,原来有( )个饺子。", + "options": [ + "A. 3", + "B. 13", + "C. 15" + ], + "answer": "B", + "solution": "【分析】根据加法的意义,吃了的数量 + 还剩的数量 = 原来的数量,由此解答.\n【详解】8 + 5 = 13(个),原来有13个饺子。故答案为:B.", + "knowledge_points": [ + "8加几的进位加法" + ], + "source": "23-24 一年级上·山东菏泽·期末" + }, + { + "id": "213", + "unit": "第五单元20以内的进位加法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "飞飞,鹿鹿,华华各有10块糖,下列说法正确的是( )。", + "options": [ + "A. 飞飞说:\"我左手有5块糖,右手有6块糖.\"", + "B. 鹿鹿说:\"我左手有 4 块糖,右手有 6 块糖.\"", + "C. 华华说:\"我吃了 2 块糖,还剩 7 块糖没吃.\"" + ], + "answer": "B", + "solution": "【分析】根据题意,他们手里的数量相加为10,或者吃了的和剩下的相加为 10,才是正确的,由此解答.\n【详解】A:5 + 6 = 11(块),不符合题意;B:4 + 6 = 10(块),符合题意;C:2 + 7 = 9(块),不符合题意。只有鹿鹿的说法正确。故答案为:B.", + "knowledge_points": [ + "8,9的加减法", + "5~2加几的进位加法", + "10的加减法" + ], + "source": "23-24 一年级上·山东青岛·期末" + }, + { + "id": "214", + "unit": "第五单元20以内的进位加法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "有( )个篮球可以投进篮筐。", + "options": [ + "A. 4 个", + "B. 3 个", + "C. 2 个" + ], + "answer": "B", + "solution": "【分析】依次计算出各算式的结果,找到得数为12的有几个即可.\n【详解】4 + 8 = 12,3 + 9 = 12,9 + 6 = 15,5 + 6 = 11,7 + 5 = 12,4 + 7 = 11,结果为 12 的有 3 个,所以有 3 个篮球可以投进篮筐。故答案为:B.", + "knowledge_points": [ + "9加几的进位加法", + "5~2加几的进位加法", + "7,6加几的进位加法" + ], + "source": "23-24 一年级上·浙江台州·期末" + }, + { + "id": "215", + "unit": "第五单元20以内的进位加法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "我们领走了 9 本书,还剩下 5 本,原来有( )本。", + "options": [ + "A. 4", + "B. 13", + "C. 14" + ], + "answer": "C", + "solution": "【分析】根据题意可知:求原来有多少本书。用领走的数量加上剩下的数量即可.\n【详解】9 + 5 = 14(本),所以原来有14本。故答案为:C.", + "knowledge_points": [ + "9加几的进位加法" + ], + "source": "23-24 一年级上·湖北黄冈·期末" + }, + { + "id": "216", + "unit": "第五单元20以内的进位加法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "一个加数是 8,另一个加数是 6,和是( )。", + "options": [ + "A. 2", + "B. 12", + "C. 14" + ], + "answer": "C", + "solution": "【分析】根据\"加数+加数=和\"来解决即可.\n【详解】8 + 6 = 14,即一个加数是8,另一个加数是6,和是14。故答案为:C.", + "knowledge_points": [ + "8加几的进位加法" + ], + "source": "23-24 一年级上·贵州铜仁·期末" + }, + { + "id": "217", + "unit": "第五单元20以内的进位加法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "( )算式得数最小。", + "options": [ + "A. 6+6", + "B. 4+7", + "C. 5-1" + ], + "answer": "C", + "solution": "【分析】分别计算出每个算式的得数,然后根据20以内数的大小关系比较即可求解.\n【详解】A:6 + 6 = 12;B:4 + 7 = 11;C:5-1 = 4,12>11>4,算式 5-1 得数最小。故答案为:C.", + "knowledge_points": [ + "20以内数的比大小", + "5以内数的减法", + "5~2加几的进位加法", + "7,6加几的进位加法" + ], + "source": "23-24一年级上·内蒙古通辽·期末" + }, + { + "id": "218", + "unit": "第五单元20以内的进位加法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "龙龙用\"凑十法\"计算 7 加几的题目时,先算 7 + 3 = 10,再算 10 + 4 = 14,龙龙计算的这道题是( )。", + "options": [ + "A. 7+4", + "B. 4+3", + "C. 7+7", + "D. 10+7" + ], + "answer": "C", + "solution": "【分析】先算出每个算式的结果,然后找出结果是14,且其中一个加数是7的算式,即可解决.\n【详解】A:7 + 4 = 11,可以先算 7 + 3 = 10,再算 10 + 1 = 11;B:4 + 3 = 7;C:7 + 7 = 14,可以先算 7 + 3 = 10,再算 10 + 4 = 14;D:10 + 7 = 17。即龙龙计算的题是 7 + 7。故答案为:C.", + "knowledge_points": [ + "7,6加几的进位加法" + ], + "source": "23-24 一年级上·福建龙岩·期末" + }, + { + "id": "219", + "unit": "第五单元20以内的进位加法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "可可踢毽子,第一次踢了 9 下,第二次踢了 8 下,两次一共踢了( )下。", + "options": [ + "A. 18", + "B. 17", + "C. 16" + ], + "answer": "B", + "solution": "【分析】把两次踢的数量加起来,求出和,即可解决.\n【详解】9 + 8 = 17(下),即两次一共踢了17下。故答案为:B.", + "knowledge_points": [ + "9加几的进位加法" + ], + "source": "23-24一年级上·贵州黔西·期末" + }, + { + "id": "220", + "unit": "第五单元20以内的进位加法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "两个加数都是 9,那么和是( )。", + "options": [ + "A. 9", + "B. 18", + "C. 0" + ], + "answer": "B", + "solution": "【分析】根据\"加数+加数=和\"列式计算.\n【详解】9 + 9 = 18,即两个加数都是 9,那么和是18。故答案为:B.", + "knowledge_points": [ + "9加几的进位加法" + ], + "source": "23-24 一年级上·河北保定·期末" + }, + { + "id": "221", + "unit": "第五单元20以内的进位加法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "同学们排队做操,从左边数小红排第 5,从右边数小红排第 7,一共有( )人。", + "options": [ + "A. 10", + "B. 11", + "C. 12" + ], + "answer": "B", + "solution": "【分析】从左边数小红排第5,从右边数小红排第7,这样数,小红数了2次,计算时要减掉1次。先把5和7加起来,求出和,再减去1,求出差,即可解决此题.\n【详解】5+7-1 = 12-1 = 11(人),即一共有11人。故答案为:B.", + "knowledge_points": [ + "加减混合运算(20以内)" + ], + "source": "23-24一年级上·甘肃陇南·期末" + }, + { + "id": "222", + "unit": "第五单元20以内的进位加法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "一个加数是 5,另一个加数是 6,求和是多少的算式是( )。", + "options": [ + "A. 5+6", + "B. 6-5", + "C. 5+5" + ], + "answer": "A", + "solution": "【分析】根据加法各部分关系,加数 + 加数 = 和,由此列出算式.\n【详解】一个加数是 5,另一个加数是 6,求和是多少的算式是 5 + 6。故答案为:A.", + "knowledge_points": [ + "5~2加几的进位加法" + ], + "source": "22-23 一年级上·新疆克孜勒苏·期末" + }, + { + "id": "223", + "unit": "第五单元20以内的进位加法", + "question_type": "填空题", + "difficulty": 0.65, + "question": "在括号里填\">\"\"<\"或\"=\".\n9( )1315( )8+67+4( )5+610-4( )9-4", + "options": [], + "answer": "<;>;=;>", + "solution": "【分析】根据整数加减法的计算法则,依次计算出各算式的结果再比较大小。20以内数从小到大为:1<2<3<4<5<6<7<8<9<10<11<12<13<14<15<16<17<18<19<20,由此比较.\n【详解】9<13;8 + 6 = 14,15>14,则 15>8 + 6;7 + 4 = 11,5 + 6 = 11,11 = 11,则 7 + 4 = 5 + 6;10-4 = 6,9-4 = 5,6>5,则 10-4>9-4。", + "knowledge_points": [ + "20以内数的比大小", + "5~2加几的进位加法", + "10的加减法", + "7,6加几的进位加法" + ], + "source": "23-24一年级上·江苏盐城·期末" + }, + { + "id": "224", + "unit": "第五单元20以内的进位加法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "两个数都是 7,它俩的和是( ),差是( )。", + "options": [], + "answer": "140", + "solution": "【分析】两个数相加的结果叫和;两个数相减的结果叫差。结合整数加减法的计算法则,算出结果即可.\n【详解】7 + 7 = 14,7 - 7 = 0,即两个数都是 7,它俩的和是14,差是0。", + "knowledge_points": [ + "7的加减法", + "7,6加几的进位加法" + ], + "source": "22-23 一年级上·山东德州·期末" + }, + { + "id": "225", + "unit": "第五单元20以内的进位加法", + "question_type": "填空题", + "difficulty": 0.65, + "question": "两个加数都是 7,和是( );被减数和减数都是 5,差是( )。", + "options": [], + "answer": "14;0", + "solution": "【分析】根据\"加数+加数=和\"\"被减数-减数=差\",计算得出结论即可.\n【详解】7+7=14,5 - 5 = 0,故两个加数都是 7,和是14;被减数和减数都是 5,差是0。", + "knowledge_points": [ + "5以内数的减法", + "7,6加几的进位加法" + ], + "source": "22-23 一年级上·河南驻马店·期末" + }, + { + "id": "226", + "unit": "第五单元20以内的进位加法", + "question_type": "填空题", + "difficulty": 0.65, + "question": "在括号里填上\">\"\"<\"或\"=\".\n7 + 5 ( ) 139 - 9 ( ) 187 + 1 ( ) 18 - 1017 ( ) 8 + 84 + 8 ( ) 8 + 417 - 5 ( ) 12 + 5", + "options": [], + "answer": "<;<;=;>;=;<", + "solution": "【分析】依次计算出各算式的结果再比较大小。20以内数从小到大为:0<1<2<3<4<5<6<7<8<9<10<11<12<13<14<15<16<17<18<19<20,由此比较.\n【详解】7 + 5 = 12,12<13,则 7 + 5<13;9 - 9 = 0,0<18,则 9 - 9<18;7 + 1 = 8,18 - 10 = 8,8=8,则 7 + 1 = 18 - 10;8 + 8 = 16,17>16,则 17>8 + 8;4 + 8 = 12,8 + 4 = 12,12=12,则 4 + 8 = 8 + 4;17 - 5 = 12,12 + 5 = 17,12<17,则 17 - 5<12 + 5。", + "knowledge_points": [ + "20以内数的比大小", + "不退位减法(20以内)", + "5~2加几的进位加法", + "7,6加几的进位加法" + ], + "source": "23-24 一年级上·山东临沂·期末" + }, + { + "id": "227", + "unit": "第五单元20以内的进位加法", + "question_type": "填空题", + "difficulty": 0.65, + "question": "\"读书破万卷,下笔如有神.\"贝贝读一本书,打开后左右两边的页数和是13,她打开的是第( )页和第( )页。", + "options": [], + "answer": "6;7", + "solution": "【分析】根据题意,两边的页数之和是13,也就是两个相邻数的和是13。两个相邻数之间相差1,即2个相同数的和再加1是13。因为两个相同数的和超过了10,5和5合起来是10,所以加数从6开始计算,由此解答.\n【详解】6 + 6 + 1 = 13(页),也就是 6 + 7 = 13(页),她打开的是第 6 页和第 7 页。", + "knowledge_points": [ + "7,6加几的进位加法" + ], + "source": "23-24 一年级上·山西忻州·期末" + }, + { + "id": "228", + "unit": "第五单元20以内的进位加法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "在括号里填上合适的数.\n5 + 7 = 4 + ( ) ( ) + 0 = 10 - 19 - ( ) = 3 + 2", + "options": [], + "answer": "8;9;4", + "solution": "【分析】第1题:5 + 7 = 12,根据凑十法,4和6合起来是10,再加2是12,即 4 + 8 = 12;第2题:10 - 1 = 9,( ) + 0 = 9,可看成 9 - 0 = 9;第3题:3 + 2 = 5,9 - ( ) = 5,可看成 9 - 5 = 4。", + "knowledge_points": [ + "8,9的加减法", + "5~2加几的进位加法", + "10的加减法" + ], + "source": "23-24一年级上·湖南邵阳·期末" + }, + { + "id": "229", + "unit": "第五单元20以内的进位加法", + "question_type": "填空题", + "difficulty": 0.65, + "question": "明明在看一本故事书,打开书后,两边的页码加起来正好是 17,他正在看第( )页和第( )页。", + "options": [], + "answer": "8;9", + "solution": "【分析】计算一下哪两个相邻的数加起来是17.\n【详解】8 + 9 = 17,所以他正在看第 8 页和第 9 页。", + "knowledge_points": [ + "9加几的进位加法", + "8加几的进位加法" + ], + "source": "23-24一年级上·福建厦门·期末" + }, + { + "id": "230", + "unit": "第五单元20以内的进位加法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "两个加数都是最大的一位数,它们的和是( )。", + "options": [], + "answer": "18", + "solution": "【分析】最大的一位数是9,用9加9即可求解.\n【详解】9 + 9 = 18,两个加数都是最大的一位数,它们的和是18。", + "knowledge_points": [ + "9加几的进位加法" + ], + "source": "23-24 一年级上·浙江台州·期末" + }, + { + "id": "231", + "unit": "第五单元20以内的进位加法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "一个加数是 6,另一个加数是 9,和是( )。", + "options": [], + "answer": "15", + "solution": "【分析】根据\"加数+加数=和\"来解决此题.\n【详解】6 + 9 = 15,即一个加数是 6,另一个加数是 9,和是15。", + "knowledge_points": [ + "7,6加几的进位加法" + ], + "source": "23-24 一年级上·河南南阳·期末" + }, + { + "id": "232", + "unit": "第五单元20以内的进位加法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "在括号里面填出合适的数.\n4 + ( ) = 12 ( ) - 5 = 98 + ( ) = 17", + "options": [], + "answer": "8;14;9", + "solution": "【分析】第1题:根据凑十法,4和6合起来是10,再加2是12,即 4 + 8 = 12;第2题:根据\"被减数-减数=差\",可转化为\"减数+差=被减数\",即 5 + 9 = 14;第3题:根据凑十法,8和2合起来是10,再加7是17,即 8 + 9 = 17。", + "knowledge_points": [ + "5~2加几的进位加法", + "8加几的进位加法" + ], + "source": "23-24一年级上·贵州遵义·期末" + }, + { + "id": "233", + "unit": "第五单元20以内的进位加法", + "question_type": "填空题", + "difficulty": 0.65, + "question": "12 支铅笔,放在两个笔筒里,要使两个笔筒里的笔一样多,可以每个笔筒放( )支。", + "options": [], + "answer": "6", + "solution": "【分析】12 支铅笔,放在两个笔筒里,要使两个笔筒里的笔一样多,找到两个相同的数的和是 12 即可.\n【详解】6 + 6 = 12,12 支铅笔,放在两个笔筒里,要使两个笔筒里的笔一样多,可以每个笔筒放 6 支。", + "knowledge_points": [ + "7,6加几的进位加法" + ], + "source": "23-24 一年级上·江苏淮安·期末" + }, + { + "id": "234", + "unit": "第五单元20以内的进位加法", + "question_type": "填空题", + "difficulty": 0.65, + "question": "8 + 3 = 11 这个算式中,( )和( )是加数,和是( )。", + "options": [], + "answer": "8;3;11", + "solution": "【分析】根据加法的意义,求两个数和的运算用加法,可得加数+加数=和,在 8 + 3 = 11 这个算式中,8 和 3 是加数,和是 11.\n【详解】根据\"加数+加数=和\"可知:在 8 + 3 = 11 这个算式中,8 和 3 是加数,和是 11。", + "knowledge_points": [ + "8加几的进位加法" + ], + "source": "22-23 一年级上·重庆沙坪坝·期末" + }, + { + "id": "235", + "unit": "第五单元20以内的进位加法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "一个加数是8,另一个加数是 7,和是( )。", + "options": [], + "answer": "15", + "solution": "【分析】根据\"加数+加数=和\"及整数加减法的计算法则来解决.\n【详解】8 + 7 = 15,故一个加数是 8,另一个加数是 7,和是15。", + "knowledge_points": [ + "8加几的进位加法" + ], + "source": "23-24一年级上·河南周口·期末" + }, + { + "id": "236", + "unit": "第五单元20以内的进位加法", + "question_type": "判断题", + "difficulty": 0.65, + "question": "飞走了 8 只小鸟,剩下的和飞走的同样多,原来有 18 只小鸟。( )", + "options": [], + "answer": "×", + "solution": "【分析】飞走 8 只小鸟,剩下的和飞走的小鸟同样多也是 8 只,剩下的加上飞走的就是原来的小鸟数量,据此计算得出结论即可.\n【详解】8 + 8 = 16(只),即原来有 16 只小鸟,而不是 18 只小鸟,原说法错误。故答案为: ×。", + "knowledge_points": [ + "8加几的进位加法" + ], + "source": "23-24 一年级上·湖南怀化·期末" + }, + { + "id": "237", + "unit": "第五单元20以内的进位加法", + "question_type": "判断题", + "difficulty": 0.85, + "question": "4 + 9 = 5 + 7 。( )", + "options": [], + "answer": "×", + "solution": "【分析】先计算出算式的结果再比较大小即可。20 以内数从小到大为:0<1<2<3<4<5<6<7<8<9<10<11<12<13<14<15<16<17<18<19<20,由此比较.\n【详解】4 + 9 = 13,5 + 7 = 12,13>12,则 4 + 9>5 + 7,原题说法错误。故答案为: ×。", + "knowledge_points": [ + "20以内数的比大小", + "5~2加几的进位加法" + ], + "source": "23-24一年级上·河北保定·期末" + }, + { + "id": "238", + "unit": "第五单元20以内的进位加法", + "question_type": "判断题", + "difficulty": 0.85, + "question": "大树的左边有5只小羊,右边有 7 只小羊,大树的左,右两边一共有 12 只小羊。( )", + "options": [], + "answer": "√", + "solution": "【分析】先把大树的左,右两边的羊数量加起来,求出和,就是大树的左,右两边一共有几只小羊,然后判断对错即可.\n【详解】5 + 7 = 12(只),即大树的左边有 5 只小羊,右边有 7 只小羊,大树的左,右两边一共有 12 只小羊;此说法正确。故答案为:√。", + "knowledge_points": [ + "5~2加几的进位加法" + ], + "source": "23-24一年级上·陕西商洛·期末" + }, + { + "id": "239", + "unit": "第五单元20以内的进位加法", + "question_type": "计算题", + "difficulty": 0.65, + "question": "看图列式计算.\n![](images/8ae8894ff255534d08225cb7beef1a9970436c0fbc62d806ed1ec13f84ee5789.jpg)\n□ ○ □ = □(个)", + "options": [], + "answer": "6 + 6 = 12", + "solution": "【分析】求一共有多少颗草莓,左边有 6 颗草莓,右边有 6 颗草莓,相加计算即可解答.\n【详解】6 + 6 = 12(颗)。", + "knowledge_points": [ + "7,6加几的进位加法" + ], + "source": "23-24 一年级上·新疆喀什·期末" + }, + { + "id": "240", + "unit": "第五单元20以内的进位加法", + "question_type": "计算题", + "difficulty": 0.65, + "question": "看图列式计算.\n![](images/7248230a5a50caf9eb207eacaf5bd82811bb60fb7a2ef8cc22f94da5ca10f9f9.jpg)\n□ ○ □ = □(个)", + "options": [], + "answer": "5 + 7 = 12", + "solution": "【分析】左边蝴蝶的数量加右边蝴蝶的数量就是总数.\n【详解】左边 5 只,右边 7 只,5 + 7 = 12(只)。", + "knowledge_points": [ + "5~2加几的进位加法" + ], + "source": "23-24 一年级上·吉林白城·期末" + }, + { + "id": "241", + "unit": "第五单元20以内的进位加法", + "question_type": "计算题", + "difficulty": 0.65, + "question": "看图列式.\n![](images/1504edf4e0c535d82c1955ecf1d268aef65b0e8c78e967bd00c293f8760816a3.jpg)\n□ ○ □ = □(个)", + "options": [], + "answer": "9 + 4 = 13", + "solution": "【分析】根据图意,求一共的数量,用加法计算,将两份上的数量相加即可.\n【详解】9 + 4 = 13(个)。", + "knowledge_points": [ + "图文问题", + "9加几的进位加法" + ], + "source": "23-24 一年级上·山东济宁·期末" + }, + { + "id": "242", + "unit": "第五单元20以内的进位加法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "树上原来有 19 只小鸟,先飞走了9只,又飞走了5只。两次一共飞走了多少只小鸟。\n□ ○ □ = □(只)", + "options": [], + "answer": "9 + 5 = 14", + "solution": "【分析】根据加法的意义,先飞走的数量+又飞走的数量=两次一共飞走的数量,由此解答.\n【详解】9 + 5 = 14(只)。答:两次一共飞走了 14 只小鸟。", + "knowledge_points": [ + "9加几的进位加法" + ], + "source": "23-24 一年级上·江苏盐城·期末" + }, + { + "id": "243", + "unit": "第五单元20以内的进位加法", + "question_type": "解答题", + "difficulty": 0.65, + "question": "小朋友排队做操,小明前面有 9 人,后面有 8 人,这一排小朋友一共有多少人。", + "options": [], + "answer": "18人", + "solution": "【分析】用小明前面的人加上后面的人,再加上他自己,即可得到这一排的总人数.\n【详解】9 + 8 = 17(人),17 + 1 = 18(人)。答:这一排小朋友一共有 18 人。", + "knowledge_points": [ + "9加几的进位加法" + ], + "source": "22-23 一年级上·江苏盐城·期末" + }, + { + "id": "244", + "unit": "第五单元20以内的进位加法", + "question_type": "解答题", + "difficulty": 0.65, + "question": "男同学种了7棵树,女同学种了9棵,一共种了多少棵树。\n□ ○ □ = □(棵)", + "options": [], + "answer": "7 + 9 = 16", + "solution": "【分析】用男同学种的棵数加上女同学种的棵数即可.\n【详解】7 + 9 = 16(棵)。答:一共种了 16 棵树。", + "knowledge_points": [ + "9加几的进位加法" + ], + "source": "22-23一年级上·江苏盐城·期末" + }, + { + "id": "245", + "unit": "第五单元20以内的进位加法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "树上原来有 13 只鸟,第一次飞走了6只,第二次飞走了7只。两次一共飞走多少只鸟。", + "options": [], + "answer": "13 只", + "solution": "【分析】根据题意可知:求两次一共飞走的只数。用第一次飞走的只数加上第二次飞走的只数即可.\n【详解】6 + 7 = 13(只)。答:两次一共飞走 13 只鸟。", + "knowledge_points": [ + "7,6加几的进位加法" + ], + "source": "23-24 一年级下·河北张家口·期末" + }, + { + "id": "246", + "unit": "第五单元20以内的进位加法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "书架上有一些故事书,借走了5本后,还剩8本,书架上原来有多少本故事书。\n□ ○ □ = □(本)", + "options": [], + "answer": "5 + 8 = 13", + "solution": "【分析】根据加法的意义,借走的数量+还剩的数量=原来的数量,代入数据计算即可.\n【详解】5 + 8 = 13(本)。答:书架上原来有 13 本故事书。", + "knowledge_points": [ + "5~2加几的进位加法" + ], + "source": "23-24 一年级下·广东东莞·期末" + }, + { + "id": "247", + "unit": "第五单元20以内的进位加法", + "question_type": "解答题", + "difficulty": 0.65, + "question": "一盒糖,小明和小红一共吃了 9 个,还剩下 7 个。这盒糖原来有多少个。\n□ ○ □ = □(个)", + "options": [], + "answer": "9 + 7 = 16", + "solution": "【分析】这题的关键词是\"原来\",指的是还没有吃之前的个数。用吃了的个数加上剩下的个数即可求出原来有几个.\n【详解】吃了 9 个,还剩下 7 个,9 + 7 = 16(个)。答:这盒糖原来有 16 个。", + "knowledge_points": [ + "9加几的进位加法" + ], + "source": "22-23 一年级上·湖北荆州·期末" + }, + { + "id": "248", + "unit": "第五单元20以内的进位加法", + "question_type": "解答题", + "difficulty": 0.65, + "question": "李老师发了 8 个本,还有 6 个本,一共有多少个本。\n□ ○ □ = □(本)", + "options": [], + "answer": "14本", + "solution": "【分析】根据题意可知,已经发的本数+李老师手里的本数=李老师一共要发的本数,据此列式解答.\n【详解】8 + 6 = 14(本)。答:李老师一共要发 14 本书。", + "knowledge_points": [ + "8加几的进位加法" + ], + "source": "22-23 一年级上·山西忻州·期末" + }, + { + "id": "249", + "unit": "第五单元20以内的进位加法", + "question_type": "解答题", + "difficulty": 0.65, + "question": "丽丽有 8 元钱,买一本故事书还差4元,这本故事书多少钱。\n□ ○ □ = □(元)", + "options": [], + "answer": "8 + 4 = 12", + "solution": "【分析】原有的钱数加还差的钱数就是故事书的钱数,据此列式解答即可.\n【详解】8 + 4 = 12(元)。答:这本故事书 12 元。", + "knowledge_points": [ + "8加几的进位加法" + ], + "source": "22-23 一年级上·山西忻州·期末" + }, + { + "id": "250", + "unit": "第五单元20以内的进位加法", + "question_type": "解答题", + "difficulty": 0.65, + "question": "小丽摘了7个南瓜,小强摘了6个南瓜,他们一共摘了多少个南瓜。\n□ ○ □ = □(个)", + "options": [], + "answer": "7 + 6 = 13", + "solution": "【分析】小丽摘的南瓜数量加小强摘的南瓜数量就是他们共摘的南瓜数量,据此列式解答即可.\n【详解】7 + 6 = 13(个)。答:他们一共摘了 13 个南瓜。", + "knowledge_points": [ + "7,6加几的进位加法" + ], + "source": "22-23一年级上·河南驻马店·期末" + }, + { + "id": "251", + "unit": "第五单元20以内的进位加法", + "question_type": "解答题", + "difficulty": 0.65, + "question": "同学们到游乐场去玩,女生 8 人,男生 6 人,大家都进场需要买多少张门票。\n□ ○ □ = □(张)", + "options": [], + "answer": "8 + 6 = 14", + "solution": "【分析】女生人数加男生人数就是需要买门票的数量,据此列式解答即可.\n【详解】8 + 6 = 14(张)。答:大家都进场需要买 14 张门票。", + "knowledge_points": [ + "8加几的进位加法" + ], + "source": "22-23 一年级上·河南驻马店·期末" + }, + { + "id": "252", + "unit": "第五单元20以内的进位加法", + "question_type": "解答题", + "difficulty": 0.65, + "question": "妈妈买来一袋糖,分给我和弟弟每人7块,正好分完,这袋糖共有多少块。\n□ ○ □ = □(块)", + "options": [], + "answer": "7+7=14", + "solution": "【分析】我分到的糖的数量加弟弟分到的糖的数量就是这袋糖总共的数量,据此列式解答即可.\n【详解】7 + 7 = 14(块)。答:这袋糖共有 14 块。", + "knowledge_points": [ + "7,6加几的进位加法" + ], + "source": "22-23 一年级上·河南驻马店·期末" + }, + { + "id": "253", + "unit": "第五单元20以内的进位加法", + "question_type": "解答题", + "difficulty": 0.65, + "question": "有一袋枣,小明第一次吃了 9 个,第二次吃了 6 个,他两次共吃了多少个枣。\n□ ○ □ = □(个)", + "options": [], + "answer": "9 + 6 = 15", + "solution": "【分析】小明第一次吃的枣的个数加第二次吃的枣的个数就是他两次共吃的枣的个数,据此列式解答即可.\n【详解】9 + 6 = 15(个)。答:他两次共吃了 15 个枣。", + "knowledge_points": [ + "9加几的进位加法" + ], + "source": "22-23 一年级上·河南驻马店·期末" + }, + { + "id": "254", + "unit": "第五单元20以内的进位加法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "鱼缸中有红金鱼5条,黑金鱼8条,鱼缸中一共有多少条金鱼。", + "options": [], + "answer": "13 条", + "solution": "【分析】用红金鱼的条数加黑金鱼的条数即可求出鱼缸中共有多少条金鱼.\n【详解】5 + 8 = 13(条)。答:鱼缸中一共有 13 条金鱼。", + "knowledge_points": [ + "5~2加几的进位加法" + ], + "source": "22-23 一年级下·甘肃庆阳·阶段练习" + }, + { + "id": "255", + "unit": "第五单元20以内的进位加法", + "question_type": "解答题", + "difficulty": 0.65, + "question": "合唱队里有男生6人,女生5人。合唱队里一共有多少人。\n□ ○ □ = □(人)", + "options": [], + "answer": "6 + 5 = 11", + "solution": "【分析】男生人数加女生人数就是合唱队的总人数,据此列式解答即可.\n【详解】6 + 5 = 11(人)。答:合唱队里一共有 11 人。", + "knowledge_points": [ + "7,6加几的进位加法" + ], + "source": "22-23一年级下·吉林白城·开学考试" + }, + { + "id": "256", + "unit": "第五单元20以内的进位加法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "书架上有一些故事书,借走了 3 本后,还剩 9 本,书架上原来有多少本故事书。\n□ ○ □ = □(本)", + "options": [], + "answer": "9 + 3 = 12", + "solution": "【分析】把还剩的故事书数量与借走的数量加起来,求出和,即可解决.\n【详解】9 + 3 = 12(本)。答:书架上原来有 12 本故事书。", + "knowledge_points": [ + "9加几的进位加法" + ], + "source": "23-24一年级下·福建泉州·期末" + }, + { + "id": "257", + "unit": "第五单元20以内的进位加法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "超市卖出 8 个文具盒后,箱子里还有 8 个,超市原来有多少个文具盒。", + "options": [], + "answer": "16 个", + "solution": "【分析】用超市卖出的个数加箱子里还有的个数即可求出超市原来有多少个文具盒.\n【详解】8 + 8 = 16(个)。答:超市原来有 16 个文具盒。", + "knowledge_points": [ + "8加几的进位加法" + ], + "source": "23-24 一年级下·河南驻马店·期中" + }, + { + "id": "258", + "unit": "第五单元20以内的进位加法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "小力要做 8 架飞机,小红要做 9 架飞机,他们一共要做多少架飞机。\n□ ○ □ = □(架)", + "options": [], + "answer": "8 + 9 = 17", + "solution": "【分析】用小力要做的数量加小红要做的数量即可求出他们一共要做多少架飞机.\n【详解】8 + 9 = 17(架)。答:他们一共要做 17 架飞机。", + "knowledge_points": [ + "9加几的进位加法", + "8加几的进位加法" + ], + "source": "23-24 一年级下·广西梧州·期中" + }, + { + "id": "259", + "unit": "第五单元20以内的进位加法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "一年级(3)班买了8 个足球和 9 个篮球,一共买了多少个球。", + "options": [], + "answer": "17 个", + "solution": "【分析】用买的足球个数加篮球个数即可求出一共买了多少个球.\n【详解】8 + 9 = 17(个)。答:一共买了 17 个球。", + "knowledge_points": [ + "9加几的进位加法", + "8加几的进位加法" + ], + "source": "23-24 一年级下·广东惠州·期中" + }, + { + "id": "260", + "unit": "第五单元20以内的进位加法", + "question_type": "解答题", + "difficulty": 0.65, + "question": "春春和小雨一起画画,小雨画了 9 朵,春春画了 8 朵,他们一共画了几朵。\n□ ○ □ = □(朵)", + "options": [], + "answer": "9 + 8 = 17", + "solution": "【分析】小雨画的朵数加春春画的朵数就是他们一共画的朵数,据此得出结论即可.\n【详解】9 + 8 = 17(朵)。答:他们一共画了 17 朵。", + "knowledge_points": [ + "9加几的进位加法" + ], + "source": "23-24一年级下·河南三门峡·期中" + }, + { + "id": "261", + "unit": "第五单元20以内的进位加法", + "question_type": "解答题", + "difficulty": 0.65, + "question": "小红跳了8下,小华比小红多跳5下,小华跳了多少下。\n□ ○ □ = □(下)", + "options": [], + "answer": "8 + 5 = 13(下)", + "solution": "【分析】小红跳的数量加上小华比小红多跳的数量就是小华跳的数量,据此得出结论即可.\n【详解】8 + 5 = 13(下)。答:小华跳了 13 下。", + "knowledge_points": [ + "8加几的进位加法" + ], + "source": "23-24一年级下·甘肃定西·期中" + }, + { + "id": "262", + "unit": "第五单元20以内的进位加法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "树上第一次飞走了 8 只小鸟,第二次飞走的和第一次同样多。两次一共飞走了多少只小鸟。", + "options": [], + "answer": "16 只", + "solution": "【分析】根据题意,第二次飞走的和第一次同样多,也是 8 只,求一共飞走几只,根据加法的意义,将两次飞走的数量相加即可.\n【详解】8 + 8 = 16(只)。答:两次一共飞走了 16 只小鸟。", + "knowledge_points": [ + "8加几的进位加法" + ], + "source": "23-24 一年级上·山东济南·期末" + }, + { + "id": "263", + "unit": "第五单元20以内的进位加法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "小青说:我得了 9 朵小红花。小兰说:小青得的小红花朵数是我的一半。小兰得了多少朵小红花。", + "options": [], + "answer": "18 朵", + "solution": "【分析】根据题意,小青得了 9 朵小红花,小青得的小红花朵数是小兰的一半,求小兰得了多少朵小红花,用小青得的朵数 + 9 = 小兰得的朵数,据此解答.\n【详解】9 + 9 = 18(朵)。答:小兰得了 18 朵。", + "knowledge_points": [ + "9加几的进位加法" + ], + "source": "23-24 一年级上·河南周口·期末" + }, + { + "id": "264", + "unit": "第五单元20以内的进位加法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "小明吃了 4 块糖,还剩下 8 块,原来有多少块糖。", + "options": [], + "answer": "12 块", + "solution": "【分析】求原来有多少块糖,根据加法的意义,用吃了的数量+还剩下的数量,计算即可.\n【详解】4 + 8 = 12(块)。答:原来有 12 块糖。", + "knowledge_points": [ + "5~2加几的进位加法" + ], + "source": "23-24 一年级上·山东临沂·期末" + }, + { + "id": "265", + "unit": "第五单元20以内的进位加法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "停车场开走了5辆车,还剩下7辆,原来有多少辆车。", + "options": [], + "answer": "12 辆", + "solution": "【分析】求原来有多少辆,根据加法的意义,用开走的数量+还剩下的数量,计算即可.\n【详解】5 + 7 = 12(辆)。答:原来有 12 辆车。", + "knowledge_points": [ + "5~2加几的进位加法" + ], + "source": "23-24一年级上·河南南阳·期末" + }, + { + "id": "266", + "unit": "第五单元20以内的进位加法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "瓶子里有 9 个红珠子和 6 个蓝珠子,一共有多少个珠子。", + "options": [], + "answer": "15 个", + "solution": "【分析】求一共有多少个珠子,根据加法的意义,用红珠子的数量+蓝珠子的数量,计算即可.\n【详解】9 + 6 = 15(个)。答:一共有 15 个珠子。", + "knowledge_points": [ + "9加几的进位加法" + ], + "source": "23-24 一年级上·河南驻马店·期末" + }, + { + "id": "267", + "unit": "第五单元20以内的进位加法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "一年级(1)班男生有 9 人,女生有 7 人,问一年级(1)班一共有多少人。\n□ ○ □ = □(人)", + "options": [], + "answer": "9 + 7 = 16(人)", + "solution": "【分析】一年级(1)班一共的学生人数=一年级(1)班的男生人数+一年级(1)班的女生人数.\n【详解】9 + 7 = 16(人)。答:一年级(1)班一共有 16 人。", + "knowledge_points": [ + "9加几的进位加法", + "7,6加几的进位加法" + ], + "source": "23-24 一年级上·江苏宿迁·期末" + }, + { + "id": "268", + "unit": "第五单元20以内的进位加法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "树上原来有 7 只鸟,又飞来了 5 只,现在一共有多少只小鸟。\n□ ○ □ = □(只)", + "options": [], + "answer": "7 + 5 = 12(只)", + "solution": "【分析】现在有小鸟的只数=树上原来有小鸟的只数+又飞来的只数.\n【详解】7 + 5 = 12(只)。答:现在一共有 12 只小鸟。", + "knowledge_points": [ + "7,6加几的进位加法" + ], + "source": "23-24 一年级上·江苏宿迁·期末" + }, + { + "id": "269", + "unit": "第五单元20以内的进位加法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "红红做手抄报,她画了一排共 9 朵小红花做装饰,又在相邻两朵小红花之间画了 1 朵小黄花。请你帮她算一算,她一共画了多少朵花。", + "options": [], + "answer": "17 朵", + "solution": "【分析】根据题意,每两朵花之间有 1 个间隔,9 朵花之间有 9-1 个间隔,也就是黄花的数量,再将红花和黄花数量相加即可.\n【详解】9 - 1 = 8(朵),9 + 8 = 17(朵)。答:她一共画了 17 朵花。", + "knowledge_points": [ + "8,9的加减法", + "9加几的进位加法", + "相邻的数" + ], + "source": "23-24 一年级上·全国·课后作业" + }, + { + "id": "270", + "unit": "第五单元20以内的进位加法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "小明和同学去划船,租了 2 条船,一条坐 5 人,另一条坐 7 人,一共有多少人。", + "options": [], + "answer": "12 人", + "solution": "【分析】将两条船上分别坐的人数相加即可.\n【详解】5 + 7 = 12(人)。答:一共有 12 人。", + "knowledge_points": [ + "5~2加几的进位加法", + "7,6加几的进位加法" + ], + "source": "23-24 二年级上·重庆大渡口·期末" + }, + { + "id": "271", + "unit": "第五单元20以内的进位加法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "有 2 行路队,一行有 6 人,另一行有 5 人,一共有多少人。", + "options": [], + "answer": "11 人", + "solution": "【分析】求一共有多少人,根据加法的意义,用一行的人数加上另一行的人数计算即可.\n【详解】6 + 5 = 11(人)。答:一共有 11 人。", + "knowledge_points": [ + "7,6加几的进位加法" + ], + "source": "23-24 二年级上·贵州遵义·期末" + }, + { + "id": "272", + "unit": "第五单元20以内的进位加法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "小兔第一次运走 9 根胡萝卜,第二次运走的和第一次同样多。两次一共运走多少根胡萝卜。\n□ ○ □ = □(根)", + "options": [], + "answer": "9 + 9 = 18", + "solution": "【分析】第二次运走的和第一次同样多,所以第二次也运走了 9 根,用 9 加 9 即可求解.\n【详解】9 + 9 = 18(根)。答:两次一共运走 18 根胡萝卜。", + "knowledge_points": [ + "9加几的进位加法" + ], + "source": "23-24 一年级上·江苏宿迁·期末" + }, + { + "id": "273", + "unit": "第五单元20以内的进位加法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "明明看了 9 本书,丽丽看的书和明明同样多,两人一共看了多少本书。\n□ ○ □ = □(本)", + "options": [], + "answer": "18 本", + "solution": "【分析】根据题意可知:明明看了 9 本书,丽丽看的书和明明同样多,则丽丽也看了 9 本,用加法计算两人一共看的本数.\n【详解】9 + 9 = 18(本)。答:两人一共看了 18 本书。", + "knowledge_points": [ + "9加几的进位加法" + ], + "source": "23-24 一年级上·山东济宁·期末" + }, + { + "id": "274", + "unit": "第五单元20以内的进位加法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "游走 7 条金鱼,还有 8 条金鱼,原来一共有多少条金鱼。\n□ ○ □ = □(条)", + "options": [], + "answer": "7 + 8 = 15", + "solution": "【分析】把游走的金鱼数量与还有的数量加起来,求出和,就是原来的金鱼数量.\n【详解】7 + 8 = 15(条)。答:原来一共有 15 条金鱼。", + "knowledge_points": [ + "7,6加几的进位加法" + ], + "source": "23-24 一年级上·山东菏泽·期末" + }, + { + "id": "275", + "unit": "第五单元20以内的进位加法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "小明吃了 7 个水饺,还剩下 8 个,原来有多少个水饺。\n□ ○ □ = □(个)", + "options": [], + "answer": "7 + 8 = 15", + "solution": "【分析】把吃了的水饺数量与还剩的数量加起来,求出和,就是原来的水饺数量.\n【详解】7 + 8 = 15(个)。答:原来有 15 个水饺。", + "knowledge_points": [ + "7,6加几的进位加法" + ], + "source": "23-24 一年级上·福建厦门·期末" + }, + { + "id": "276", + "unit": "第五单元20以内的进位加法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "花样跳绳社团的小朋友分成 4 个小组练习跳绳,第一组有 9 人,第二组人数和第一组同样多。两个小组一共有多少人。\n□ ○ □ = □(人)", + "options": [], + "answer": "9 + 9 = 18", + "solution": "【分析】第二组人数和第一组同样多,说明第二组也是 9 人,用 9 加 9 即可求出两组一共的人数.\n【详解】9 + 9 = 18(人)。答:两个小组一共有 18 人。", + "knowledge_points": [ + "9加几的进位加法" + ], + "source": "23-24 一年级上·山东济宁·期末" + }, + { + "id": "277", + "unit": "第五单元20以内的进位加法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "强强吃了 7 个草莓,小明吃了 6 个,他们两人一共吃了多少个。", + "options": [], + "answer": "13 个", + "solution": "【分析】根据加法的意义,用强强吃的数量加上小明吃的数量等于一共吃的数量.\n【详解】7 + 6 = 13(个)。答:他们两人一共吃了 13 个。", + "knowledge_points": [ + "7,6加几的进位加法" + ], + "source": "23-24 一年级上·山东潍坊·期末" + }, + { + "id": "278", + "unit": "第五单元20以内的进位加法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "小猫吃了 7 条鱼,还剩 8 条,小猫原来有多少条鱼。\n□ ○ □ = □(条)", + "options": [], + "answer": "7 + 8 = 15", + "solution": "【分析】用小猫吃了的条数加还剩的条数即可求出原来的条数.\n【详解】7 + 8 = 15(条)。答:小猫原来有 15 条鱼。", + "knowledge_points": [ + "7,6加几的进位加法", + "8加几的进位加法" + ], + "source": "23-24 一年级上·山东济宁·期末" + }, + { + "id": "279", + "unit": "第五单元20以内的进位加法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "花丛中有 19 只蝴蝶,第一次飞走了 9 只,第二次飞走了 7 只,两次一共飞走了多少只蝴蝶。", + "options": [], + "answer": "16 只", + "solution": "【分析】根据题意,第一次飞走的数量加上第二次飞走的数量,等于两次一共飞走的数量.\n【详解】9 + 7 = 16(只)。答:两次一共飞走了 16 只蝴蝶。", + "knowledge_points": [ + "9加几的进位加法" + ], + "source": "23-24 一年级上·浙江台州·期末" + }, + { + "id": "280", + "unit": "第五单元20以内的进位加法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "妈妈去菜场买了 8 根玉米,奶奶也买了同样多的玉米,奶奶和妈妈一共买了多少根玉米。\n□ ○ □ = □(根)", + "options": [], + "answer": "8 + 8 = 16", + "solution": "【分析】奶奶也买了同样多的玉米,说明奶奶也买了 8 根,用 8 加 8 即可求解.\n【详解】8 + 8 = 16(根)。答:奶奶和妈妈一共买了 16 根玉米。", + "knowledge_points": [ + "8加几的进位加法" + ], + "source": "23-24 一年级上·浙江台州·期末" + }, + { + "id": "281", + "unit": "第五单元20以内的进位加法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "已经有 8 人来了,还有 4 人没来。一共要来多少人。\n□ ○ □ = □(人)", + "options": [], + "answer": "8 + 4 = 12(人)", + "solution": "【分析】求一共要来多少人,根据加法的意义,用已经来的人数加上还没来的人数即可.\n【详解】8 + 4 = 12(人)。答:一共要来 12 人。", + "knowledge_points": [ + "8加几的进位加法" + ], + "source": "22-23 一年级上·江苏南京·期末" + }, + { + "id": "282", + "unit": "第五单元20以内的进位加法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "小明说:\"我采了 6 朵野花.\"小怀说:\"我采的和小明一样多.\"他们一共采了多少朵野花。\n□ ○ □ = □(朵)", + "options": [], + "answer": "6 + 6 = 12(朵)", + "solution": "【分析】根据题意可知,小怀和小明采的同样多,也是 6 朵。求一共采了多少朵,将他们采的数量相加即可.\n【详解】6 + 6 = 12(朵)。答:他们一共采了 12 朵野花。", + "knowledge_points": [ + "7,6加几的进位加法" + ], + "source": "22-23 一年级上·江苏南京·期末" + }, + { + "id": "283", + "unit": "第五单元20以内的进位加法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "妈妈剪了 8 朵红花,小花剪的红花和妈妈的同样多,她们一共剪了多少朵红花。\n□ ○ □ = □(朵)", + "options": [], + "answer": "8 + 8 = 16", + "solution": "【分析】用加法把妈妈剪的红花数量与小花剪的红花数量加起来,求出和,就是红花的总数量。妈妈剪了 8 朵红花,小花剪的红花和妈妈的同样多,也就是小花也是剪了 8 朵红花.\n【详解】8 + 8 = 16(朵)。答:她们一共剪了 16 朵红花。", + "knowledge_points": [ + "8加几的进位加法" + ], + "source": "23-24 一年级上·河南南阳·期末" + }, + { + "id": "284", + "unit": "第五单元20以内的进位加法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "妈妈买了一些鸡蛋,吃了 6 个,还有 9 个,原来有几个鸡蛋。\n□ ○ □ = □(个)", + "options": [], + "answer": "6 + 9 = 15", + "solution": "【分析】把吃了的鸡蛋数量与还剩的数量加起来,求出和,就是原来的鸡蛋数量.\n【详解】6 + 9 = 15(个)。答:原来有 15 个鸡蛋。", + "knowledge_points": [ + "7,6加几的进位加法" + ], + "source": "23-24 一年级上·河南南阳·期末" + }, + { + "id": "285", + "unit": "第五单元20以内的进位加法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "飞走了 8 只鸟,还剩下 5 只,树上原来有几只鸟。\n□ ○ □ = □(只)", + "options": [], + "answer": "8 + 5 = 13", + "solution": "【分析】用飞走的只数加上剩下的只数即可求出原来的只数.\n【详解】8 + 5 = 13(只)。答:树上原来有 13 只鸟。", + "knowledge_points": [ + "5~2加几的进位加法", + "8加几的进位加法" + ], + "source": "23-24 一年级上·内蒙古通辽·期末" + }, + { + "id": "286", + "unit": "第五单元20以内的进位加法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "文文有 6 张卡片,丽丽的卡片数和文文同样多,她们一共有多少张卡片。\n□ ○ □ = □(张)", + "options": [], + "answer": "6 + 6 = 12", + "solution": "【分析】求一共有多少张卡片,就是求两个数的和,用加法列式计算。文文有 6 张卡片,丽丽的卡片数和文文同样多,则丽丽也有 6 张卡片.\n【详解】6 + 6 = 12(张)。答:她们一共有 12 张卡片。", + "knowledge_points": [ + "7,6加几的进位加法" + ], + "source": "23-24 一年级上·山东德州·期末" + }, + { + "id": "287", + "unit": "第五单元20以内的进位加法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "小猴子下山摘桃子,摘了 6 个,还剩 8 个,原来有多少个。\n□ ○ □ = □(个)", + "options": [], + "answer": "6 + 8 = 14", + "solution": "【分析】已知小猴摘了 6 个桃子,还剩 8 个,要求原来有多少个桃子,根据加法的意义,将摘了的桃子数量和剩下的桃子数量相加即可.\n【详解】6 + 8 = 14(个)。答:原来有 14 个。", + "knowledge_points": [ + "7,6加几的进位加法" + ], + "source": "23-24 一年级上·四川广元·期末" + }, + { + "id": "288", + "unit": "第五单元20以内的进位加法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "树上先飞走 8 只小鸟,又飞走 4 只,两次飞走多少只小鸟。\n□ ○ □ = □(只)", + "options": [], + "answer": "8 + 4 = 12", + "solution": "【分析】要求两次飞走了多少只小鸟,根据加法的意义,将两次飞走的鸟的数量相加,即可得出答案.\n【详解】8 + 4 = 12(只)。答:两次飞走 12 只小鸟。", + "knowledge_points": [ + "8加几的进位加法" + ], + "source": "23-24 一年级上·四川广元·期末" + }, + { + "id": "289", + "unit": "第五单元20以内的进位加法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "两组同学跑步,一组 5 人,另一组 6 人,一共有多少人。", + "options": [], + "answer": "11 人", + "solution": "【分析】求一共有多少人,就是求两个数的和,用加法列式计算.\n【详解】5 + 6 = 11(人)。答:一共有 11 人。", + "knowledge_points": [ + "5~2加几的进位加法" + ], + "source": "23-24 二年级上·广东广州·期末" + }, + { + "id": "290", + "unit": "第五单元20以内的进位加法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "小力家里有 17 个苹果,第一天吃掉 7 个,第二天吃掉 5 个,两天一共吃掉多少个。", + "options": [], + "answer": "12 个", + "solution": "【分析】要求小力家两天一共吃掉多少个苹果,根据加法的意义,将第一天和第二天吃掉的苹果数量相加即可.\n【详解】7 + 5 = 12(个)。答:两天一共吃掉 12 个。", + "knowledge_points": [ + "7,6加几的进位加法" + ], + "source": "23-24 一年级上·安徽芜湖·期末" + }, + { + "id": "291", + "unit": "第五单元20以内的进位加法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "车上原来有 9 人,到站后又有 6 人上车,现在车上有多少人。", + "options": [], + "answer": "15 人", + "solution": "【分析】已知车上原来有 9 人,后来又上来 6 人,用车上原有的人数加上又上车的人数,即可求出现在车上有多少人.\n【详解】9 + 6 = 15(人)。答:现在车上有 15 人。", + "knowledge_points": [ + "9加几的进位加法" + ], + "source": "23-24 一年级上·山东潍坊·期末" + }, + { + "id": "292", + "unit": "第五单元20以内的进位加法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "树上有 15 只小鸟,第一次飞走了 9 只,第二次飞走 2 只。树上一共少了几只小鸟。\n□ ○ □ = □(只)", + "options": [], + "answer": "9 + 2 = 11", + "solution": "【分析】把第一次飞走的鸟数量与第二次飞走的数量加起来,求出和,就是树上一共少了的鸟数量.\n【详解】9 + 2 = 11(只)。答:树上一共少了 11 只小鸟。", + "knowledge_points": [ + "9加几的进位加法" + ], + "source": "22-23 一年级上·山东德州·期末" + }, + { + "id": "293", + "unit": "第五单元20以内的进位加法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "公共汽车上有 6 人下车,现在车上还有 8 人,车上原来有几人。\n□ ○ □ = □(人)", + "options": [], + "answer": "6 + 8 = 14", + "solution": "【分析】把下车的人数与现在车上还有的人数加起来,求出和,就是车上原来的人数.\n【详解】6 + 8 = 14(人)。答:车上原来有 14 人。", + "knowledge_points": [ + "7,6加几的进位加法" + ], + "source": "22-23 一年级上·山东德州·期末" + }, + { + "id": "294", + "unit": "第五单元20以内的进位加法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "一本图画书,我昨天看了 6 页,今天看了 9 页,两天看了多少页。\n□ ○ □ = □(页)", + "options": [], + "answer": "6 + 9 = 15", + "solution": "【分析】求两天一共看了多少页,根据加法的意义,将两天看的数量相加即可.\n【详解】6 + 9 = 15(页)。答:两天看了 15 页。", + "knowledge_points": [ + "7,6加几的进位加法" + ], + "source": "22-23 一年级上·山东德州·期末" + }, + { + "id": "295", + "unit": "第五单元20以内的进位加法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "妈妈买了一些桃子,吃了 8 个,还剩下 7 个,妈妈买了多少个桃子。\n□ ○ □ = □(个)", + "options": [], + "answer": "8 + 7 = 15", + "solution": "【分析】已知妈妈吃了 8 个桃子,还剩下 7 个,要求妈妈买了多少个桃子,根据加法的意义,用 8 + 7 列式解答即可.\n【详解】8 + 7 = 15(个)。答:妈妈买了 15 个桃子。", + "knowledge_points": [ + "8加几的进位加法" + ], + "source": "23-24 一年级上·湖北襄阳·期末" + }, + { + "id": "296", + "unit": "第五单元20以内的进位加法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "同学们在马路两边各栽了 6 棵小树,一共栽了多少棵小树。\n□ ○ □ = □(棵)", + "options": [], + "answer": "6 + 6 = 12", + "solution": "【分析】把马路两边栽的小树数量加起来,求出和,即可解决此题。马路两边各栽了 6 棵小树,也就是一边栽 6 棵,另一边也栽 6 棵.\n【详解】6 + 6 = 12(棵)。答:一共栽了 12 棵小树。", + "knowledge_points": [ + "7,6加几的进位加法" + ], + "source": "23-24 一年级上·湖北襄阳·期末" + }, + { + "id": "297", + "unit": "第五单元20以内的进位加法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "妈妈买了 15 块巧克力,小明第一天吃了 5 块巧克力,第二天吃了 7 块巧克力。小明一共吃了多少块巧克力。\n□ ○ □ = □(块)", + "options": [], + "answer": "5 + 7 = 12(块)", + "solution": "【分析】把两天吃了的巧克力数量加起来,求出和,就是一共吃了的巧克力数量.\n【详解】5 + 7 = 12(块)。答:小明一共吃了 12 块巧克力。", + "knowledge_points": [ + "5~2加几的进位加法" + ], + "source": "23-24 一年级上·江苏淮安·期末" + }, + { + "id": "298", + "unit": "第五单元20以内的进位加法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "一本故事书,我昨天看了 9 页,今天看了 6 页,两天一共看了多少页。\n□ ○ □ = □(页)", + "options": [], + "answer": "9 + 6 = 15", + "solution": "【分析】根据加法的意义,求一共看的页数,将两天看的相加即可解答.\n【详解】9 + 6 = 15(页)。答:两天一共看了 15 页。", + "knowledge_points": [ + "9加几的进位加法" + ], + "source": "23-24 一年级上·新疆喀什·期末" + }, + { + "id": "299", + "unit": "第五单元20以内的进位加法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "小猴子从树上摘了 9 个桃子,树上还有 6 个桃子没摘,原来树上一共有多少个桃子。", + "options": [], + "answer": "15 个", + "solution": "【分析】求原来树上一共有多少个桃子,根据加法的意义,用摘了的数量加上还没摘的数量即可.\n【详解】9 + 6 = 15(个)。答:原来树上一共有 15 个桃子。", + "knowledge_points": [ + "9加几的进位加法" + ], + "source": "23-24 一年级上·山东烟台·期末" + }, + { + "id": "300", + "unit": "第五单元20以内的进位加法", + "question_type": "解答题", + "difficulty": 0.4, + "question": "工人要把一根木头锯成 3 段,每锯一次需要 6 分,锯完这根木头要多少分。\n□ ○ □ = □(分)", + "options": [], + "answer": "6 + 6 = 12", + "solution": "【分析】根据生活实际,把一根木头锯成 3 段,需要锯 2 次,每一次 6 分钟,2 次即 2 个 6 分钟,用加法计算.\n【详解】6 + 6 = 12(分)。答:锯完这根木头要 12 分。", + "knowledge_points": [ + "7,6加几的进位加法" + ], + "source": "23-24 一年级上·河南周口·期末" + }, + { + "id": "301", + "unit": " 第五单元20以内的进位加法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "班上的同学有的7岁,有的8岁。同桌的两个小朋友的年龄相加,最大是( )岁,最小是( )岁。", + "options": [ + "A. 16;15", + "B. 15;14", + "C. 16;14" + ], + "answer": "C", + "solution": "【分析】如果同桌的两个小朋友的年龄都是8岁,加起来的和就是最大的年龄和;如果同桌的两个小朋友的年龄都是7岁,加起来的和就是最小的年龄和;据此解决.\n【详解】 8 + 8 =16 (岁)7 + 7 =14 (岁)故,最大是16岁,最小是14岁。故答案为:C", + "knowledge_points": [ + "8加几的进位加法", + "7,6加几的进位加法" + ], + "source": "23-24一年级上·河南周口·期末" + }, + { + "id": "302", + "unit": " 第五单元20以内的进位加法", + "question_type": "选择题", + "difficulty": 0.65, + "question": "计算 8+7 时,先把 7分成( )。", + "options": [ + "A. 3 和 4", + "B. 2 和 5", + "C. 1 和 6" + ], + "answer": "B", + "solution": "【分析】用凑十法计算8+7时,把7分成2和5,先计算8+2得10,再算10+5得15,据此得出结论即可.\n【详解】根据分析知,计算8+7时,先把7分成2和5。故答案为:B", + "knowledge_points": [ + "8加几的进位加法" + ], + "source": "23-24 一年级上·吉林四平·期末" + }, + { + "id": "303", + "unit": " 第五单元20以内的进位加法", + "question_type": "选择题", + "difficulty": 0.65, + "question": "一根木料长2米,木匠用去 8 分米后,剩下的比用去的长( )。", + "options": [ + "A. 4厘米", + "B. 12厘米", + "C. 4分米", + "D. 12分米" + ], + "answer": "C", + "solution": "【分析】根据 1 米 = 10 分米,2 米 = 20 分米,用 20 分米减去8分米,求出剩下的长度,再用剩下的长度减去用去的长度,即可求出剩下的比用去的长多少分米.\n【详解】1米 = 10 分米,2 米 = 20 分米,20 - 8 = 12(分米),12 - 8 = 4(分米)。一根木料长2米,木匠用去8分米后,剩下的比用去的长4分米。故答案为:C", + "knowledge_points": [ + "减法表(20以内)" + ], + "source": "23-24三年级上·江西赣州·期中" + }, + { + "id": "304", + "unit": " 第五单元20以内的进位加法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "有2人在分桃子,一人分得 5 个,另一人分得 7 个,一共有( )个桃子。", + "options": [ + "A. 35", + "B. 14", + "C. 12" + ], + "answer": "C", + "solution": "【分析】一共分得的数量,用两人分别分得的数量5个和7个相加计算即可.\n【详解】 5 + 7 =12 (个)一共有12个桃子。故答案为:C", + "knowledge_points": [ + "5∼2加几的进位加法" + ], + "source": "22-23二年级上·贵州铜仁·期末" + }, + { + "id": "305", + "unit": " 第五单元20以内的进位加法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "计算8+7,下列算法错误的是( )。", + "options": [ + "A. 8 + 2 = 10 ,10+5=15", + "B. 10 + 7 = 17 ,17-2=15", + "C. 10 + 7 = 17 ,17 + 2 = 19" + ], + "answer": "C", + "solution": "【分析】逐项分析,找出错误的答案即可.\n【详解】A。先把 7 分成 2 和 5,然后计算 8 加 2 等于 10,再加上剩下的 5,结果就是 15;所以,8 + 2 = 10,10 + 5 = 15 是正确的计算方法;B。先把8与2凑成10,然后计算10加7等于17,再减去多加的 2,结果就是 15;所以,10 + 7 = 17,17 - 2 = 15 是正确的计算方法;C。先把8与2凑成10,然后计算10加7等于17,再减去多加的2,而不是加上多加的2;所以,10 + 7 = 17,17+2 = 19 是错误的计算方法。故答案为:C", + "knowledge_points": [ + "8加几的进位加法" + ], + "source": "22-23一年级上·浙江金华·期末" + }, + { + "id": "306", + "unit": " 第五单元20以内的进位加法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "小红有 8 支铅笔,小明的铅笔和小红同样多,两人一共有( )支铅笔。", + "options": [ + "A. 15", + "B. 14", + "C. 16" + ], + "answer": "C", + "solution": "【分析】小明和小红铅笔的数量一样多,即小明也有 8 支铅笔,将两人铅笔的数量相加即可求出总数量.\n【详解】 8 + 8 =16 (支)两人一共有16支铅笔。故答案为:C.", + "knowledge_points": [ + "8 加几的进位加法" + ], + "source": "23-24 一年级上·上海·期中" + }, + { + "id": "307", + "unit": " 第五单元20以内的进位加法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "一个数比9多4,这个数是( )。", + "options": [ + "A. 19", + "B. 7", + "C. 13" + ], + "answer": "C", + "solution": "【分析】已知一个数比另一个数多多少,求一个数是几,用加法计算.\n【详解】 9 + 4 =13 故,一个数比9多4,这个数是13。故答案为:C", + "knowledge_points": [ + "9加几的进位加法" + ], + "source": "23-24一年级上·辽宁·课后作业" + }, + { + "id": "308", + "unit": " 第五单元20以内的进位加法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "9 + 5 = ( )。", + "options": [ + "A. 14", + "B. 15", + "C. 95" + ], + "answer": "A", + "solution": "【分析】先根据20以内进位加法的计算方法算出 9 + 5 的结果,再选出正确答案即可.\n【详解】 9 + 5 =14;故答案为:A", + "knowledge_points": [ + "9加几的进位加法" + ], + "source": "23-24 一年级上·浙江·单元测试" + }, + { + "id": "309", + "unit": " 第五单元20以内的进位加法", + "question_type": "选择题", + "difficulty": 0.94, + "question": "5 + 6 = ( )。", + "options": [ + "A. 13", + "B. 11", + "C. 56" + ], + "answer": "B", + "solution": "【分析】先根据20以内进位加法的计算方法算出 5 + 6 的结果,再选出正确答案即可.\n【详解】 5 + 6 =11;故答案为:B", + "knowledge_points": [ + "7,6 加几的进位加法" + ], + "source": "23-24 一年级上·浙江·单元测试" + }, + { + "id": "310", + "unit": " 第五单元20以内的进位加法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "8 + 9 = ( )。", + "options": [ + "A. 12", + "B. 15", + "C. 17" + ], + "answer": "C", + "solution": "【分析】先根据20以内进位加法的计算方法算出 8 + 9 的结果,再选出正确答案即可.\n【详解】 8 + 9=17;故答案为:C", + "knowledge_points": [ + "9加几的进位加法" + ], + "source": "23-24 一年级上·浙江·单元测试" + }, + { + "id": "311", + "unit": " 第五单元20以内的进位加法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "下面的算式正确的是( )。 ![](images/1518952eda6f76048893e202a544c161d61cf77357a4ee0d00e883b47b96d1d2.jpg) ![](images/cce701d9360e57f7e3557e1e00eaaa86d0b12296978d1804af57ad0b18f4f2c1.jpg)", + "options": [ + "A. 9-8=1", + "B. 9-1=8", + "C. 9+8=17" + ], + "answer": "C", + "solution": "【分析】左边有9个篮球,右边有8个篮球,求一共有几个篮球可以用加法计算;【详解】 9 + 8 =17 (个);故答案为:C", + "knowledge_points": [ + "9加几的进位加法" + ], + "source": "23-24 一年级上·浙江·单元测试" + }, + { + "id": "312", + "unit": " 第五单元20以内的进位加法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "一个加数是 9,另一个加数是 6,和是( )。", + "options": [ + "A. 12", + "B. 13", + "C. 15" + ], + "answer": "C", + "solution": "【分析】加数+加数 = 和,据此解答即可。本题主要考查20以内进位加法的计算,熟练掌握即可.\n【详解】 9 + 6 =15;故答案为:C", + "knowledge_points": [ + "9加几的进位加法" + ], + "source": "23-24 一年级上·浙江·单元测试" + }, + { + "id": "313", + "unit": " 第五单元20以内的进位加法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "与 5 + 8 结果相等的算式是( )。", + "options": [ + "A. 9+4", + "B. 7+7", + "C. 6+9" + ], + "answer": "A", + "solution": "【分析】先把题目中5+8的算式算出来,再把选项中的3个算式结果算出来,据此解答即可;【详解】 5 + 8=13;A. 9 + 4 =13 ,13 = 13,符合条件;B. 7 + 7= 14 ,14 > 13,不符合条件;C. 6 + 9 =15 ,15 > 13,不符合条件;故答案为:A", + "knowledge_points": [ + "9 加几的进位加法", + "8 加几的进位加法", + "7,6 加几的进位加法" + ], + "source": "23-24一年级上·河北·单元测试" + }, + { + "id": "314", + "unit": " 第五单元20以内的进位加法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "弟弟剪了 5 个![](images/119b27fee116cbcffe449f59861cf18109b0e6723223760c41b880a551332fbb.jpg)姐姐剪了 9 个,他们一共剪了( )个。", + "options": [ + "A. 14", + "B. 4", + "C. 13" + ], + "answer": "A", + "solution": "【分析】求他们一共剪了多少个,就是求两个数的和,用加法列式解答.\n【详解】 5 + 9=14 (个)即,弟弟剪了 5 个,姐姐剪了 9 个,他们一共剪了 14 个。故答案为:A.", + "knowledge_points": [ + "5∼2加几的进位加法" + ], + "source": "23-24 一年级上·河北·单元测试" + }, + { + "id": "315", + "unit": " 第五单元20以内的进位加法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "小明有3元零花钱,奶奶又给了8元,小明现在有( )元零花钱。", + "options": [ + "A. 11", + "B. 12", + "C. 13" + ], + "answer": "A", + "solution": "【分析】用小明原来的零花钱数量加上奶奶又给的零花钱数量,求出和,即可解决.\n【详解】 3 + 8= 11 (元)即,小明有 3 元零花钱,奶奶又给了 8 元,小明现在有 11元零花钱。故答案为:A", + "knowledge_points": [ + "5∼2加几的进位加法" + ], + "source": "23-24一年级上·河北·单元测试" + }, + { + "id": "316", + "unit": " 第五单元20以内的进位加法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "一盒乒乓球有 6 个,两盒同样的乒乓球有多少个。正确的列式计算是()。", + "options": [ + "A. 6 + 6 =12(个)", + "B. 6 + 2 =8(个)", + "C. 12 - 6 = 6(个)" + ], + "answer": "A", + "solution": "【分析】一盒乒乓球有 6 个,求两盒同样的乒乓球有多少个,就是求6加6的和等于多少,用加法列式计算.\n【详解】由题意分析得:一盒乒乓球有6个,两盒同样的乒乓球有多少个。正确的列式计算是 6 + 6 =12(个)。故答案为:A", + "knowledge_points": [ + "7,6 加几的进位加法" + ], + "source": "23-24 一年级上·河北·单元测试" + }, + { + "id": "317", + "unit": " 第五单元20以内的进位加法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "有 2 排小树,一排有 6 棵,一排有 7 棵,一共有多少棵。列式为:( )", + "options": [ + "A. 2+6", + "B. 2+7", + "C. 6+7" + ], + "answer": "C", + "solution": "【分析】求一共有多少棵树,就是求两排树一共有多少棵,用加法列式计算.\n【详解】由题意分析得:有 2 排小树,一排有 6 棵,一排有 7 棵,一共有多少棵。列式为:6+7。故答案为:C", + "knowledge_points": [ + "7,6 加几的进位加法" + ], + "source": "23-24 一年级上·河北·单元测试" + }, + { + "id": "318", + "unit": " 第五单元20以内的进位加法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "正确答案是:6+9=( )。", + "options": [ + "A. 14", + "B. 15" + ], + "answer": "B", + "solution": "【分析】把6看成1与5的和,用1加9等于10,然后再加上 5,一共就是 15,据此解答.\n【详解】 6 + 9 =15 故答案为:B", + "knowledge_points": [ + "9加几的进位加法" + ], + "source": "22-23一年级上·四川·单元测试" + }, + { + "id": "319", + "unit": " 第五单元20以内的进位加法", + "question_type": "选择题", + "difficulty": 0.65, + "question": "一共用了( )块积木。红色黄色的各用了7块。", + "options": [ + "A. 13", + "B. 14", + "C. 15" + ], + "answer": "B", + "solution": "【分析】根据题意,求一共用了多少块,将红色的块数和黄色的块数相加即可解答.\n【详解】 7 + 7 =14 (块)所以一共用了 14 块积木。故答案为:B", + "knowledge_points": [ + "7,6加几的进位加法" + ], + "source": "22-23 一年级上·四川·课后作业" + }, + { + "id": "320", + "unit": " 第五单元20以内的进位加法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "小猫和小狗共剩下( )盆花没浇。 ![](images/0bd6f494f9b97f476eb721387c28bb655ddfbe97c31b37222011a54196a50de4.jpg)", + "options": [ + "A. 10", + "B. 11", + "C. 12" + ], + "answer": "C", + "solution": "【分析】根据题意,将小猫剩下的数量和小狗剩下的数量相加即可.\n【详解】 7 + 5 =12 (盆)小猫和小狗共剩下 12 盆花没浇。故答案为:C\n[点睛]本题解答时要注意浇了的数量和要浇的数量是干扰条件。", + "knowledge_points": [ + "7,6加几的进位加法" + ], + "source": "22-23 一年级上·四川·课后作业" + }, + { + "id": "321", + "unit": " 第五单元20以内的进位加法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "小猫一共要浇( )盆花。浇了5盆,还剩7盆没浇。", + "options": [ + "A. 10", + "B. 11", + "C. 12" + ], + "answer": "C", + "solution": "【分析】根据图片信息可知:要求一共浇了多少盆花,用加法计算,用小猫浇过的数量加上还未浇的数量即可.\n【详解】 5 + 7 =12 (盆)所以小猫一共要浇 12 盆花。故答案为:C\n[点睛]主要考查20以内数的进位加法应用,要熟练掌握。", + "knowledge_points": [ + "7,6加几的进位加法" + ], + "source": "22-23一年级上·四川·课后作业" + }, + { + "id": "322", + "unit": " 第五单元20以内的进位加法", + "question_type": "选择题", + "difficulty": 0.65, + "question": "一共要做( )道数学题。 ![](images/986235f54a683a875ca420cc900811319558fc92edcb965b01dd475d68f2df8f.jpg)", + "options": [ + "A. 10", + "B. 11", + "C. 12" + ], + "answer": "B", + "solution": "【分析】根据题意,已经做了5道,还剩下6道没有做,要求总题数,用已经做的题数+剩下的题数即可解答.\n【详解】 5 + 6=11 (道)所以一共要做 11 道数学题。故答案为:B", + "knowledge_points": [ + "5∼2加几的进位加法" + ], + "source": "22-23一年级上·四川·课后作业" + }, + { + "id": "323", + "unit": " 第五单元20以内的进位加法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "妈妈一共买来( )个苹果。 ![](images/f1b70befaf631eddaf1d161963adacc9ccd6166d6ed1a2db858ad2cb01c58aba.jpg)", + "options": [ + "A. 11", + "B. 12", + "C. 13" + ], + "answer": "A", + "solution": "【分析】根据题意:我吃了3个后还剩8个,问妈妈一共买来多少个苹果。用加法计算,用还剩的数量加上吃掉的数量即可.\n【详解】 8 + 3 =11 (个)所以妈妈一共买来 11 个苹果。故答案为:A", + "knowledge_points": [ + "8加几的进位加法" + ], + "source": "22-23 一年级上·四川·课后作业" + }, + { + "id": "324", + "unit": " 第五单元20以内的进位加法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "一共有( )只小鸟。 ![](images/94ae6c6350a8e9e634b788350862a2a333d2d2785832f61a93795892da41e35c.jpg)", + "options": [ + "A. 12", + "B. 13", + "C. 14" + ], + "answer": "B", + "solution": "【分析】根据图片可知,树桩上原有5只小鸟,又飞来了8只,问一共又多少只小鸟。用加法计算,用原来有的小鸟数量加上又飞来的数量即可.\n【详解】 5 + 8 =13 (只)所以一共有13只小鸟。故答案为:B.", + "knowledge_points": [ + "8加几的进位加法" + ], + "source": "22-23 一年级上·四川·课后作业" + }, + { + "id": "325", + "unit": " 第五单元20以内的进位加法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "原来有6名小朋友在跳绳,又跑来了 7 名小朋友,现在共有( )名小朋友。", + "options": [ + "A. 12", + "B. 13", + "C. 14", + "D. 15" + ], + "answer": "B", + "solution": "【分析】根据题意:求现在共有多少名小朋友,用加法计算,用原来有的小朋友数量加上又来的数量即可.\n【详解】 6 + 7=13 (名)所以现在共有13名小朋友。故答案为:B", + "knowledge_points": [ + "7,6加几的进位加法" + ], + "source": "22-23一年级上·四川·课后作业" + }, + { + "id": "326", + "unit": " 第五单元20以内的进位加法", + "question_type": "选择题", + "difficulty": 0.65, + "question": "两只小猫吃了 6 条鱼,还剩9条,一共有( )条鱼。", + "options": [ + "A. 13", + "B. 15", + "C. 17" + ], + "answer": "B", + "solution": "【分析】根据题意,要求一共有多少条鱼,用剩下的条数加上已经吃的条数,即可解答.\n【详解】 9 + 6=15 (条)一共有15条鱼。故答案为:B.", + "knowledge_points": [ + "9 加几的进位加法" + ], + "source": "22-23 一年级上·四川·课后作业" + }, + { + "id": "327", + "unit": " 第五单元20以内的进位加法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "张老师购回两盒钢笔作奖品,一盒 9 支,另一盒 8 支,一共有( )支钢笔。", + "options": [ + "A. 17", + "B. 72", + "C. 36" + ], + "answer": "A", + "solution": "【分析】根据题意。老师一共购回两盒钢笔,一盒9支,另盒8支,问一共有多少支。用加法计算,把两盒各有的支数相加即可.\n【详解】 9 + 8=17 (支)所以一共有17支。故答案为:A.", + "knowledge_points": [ + "9加几的进位加法" + ], + "source": "22-23二年级上·四川·课后作业" + }, + { + "id": "328", + "unit": " 第五单元20以内的进位加法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "6 + 9 = ( )。", + "options": [ + "A. 17", + "B. 15", + "C. 9", + "D. 6" + ], + "answer": "B", + "solution": "【分析】本题考查20以内进位加法的计算方法,熟练掌握计算方法,根据数的分与合,将其中一个加数进行正确的拆分是解答关键。根据20以内进位加法的计算方法,将6分为1和5,先计算 1 + 9 = 10,再计算 10 + 5 = 15,所以 6 + 9 = 15,由此解答.\n【详解】由分析可知:6 分为 1 和 5,1 + 9 =10,10 + 5 = 15,所以 6 + 9 = 15。故答案为:B", + "knowledge_points": [ + "7,6 加几的进位加法" + ], + "source": "22-23 一年级上·四川·课后作业" + }, + { + "id": "329", + "unit": " 第五单元20以内的进位加法", + "question_type": "选择题", + "difficulty": 0.65, + "question": "一共剪了( )个窗花。 ![](images/009779774dc9ffcaff7e34f937dfaf83.jpg)", + "options": [ + "A. 19", + "B. 18", + "C. 17" + ], + "answer": "B", + "solution": "【分析】根据题意:男生剪了9个窗花,女生剪的和男生一样多,也就是9个,问一共剪了多少个窗花。用加法计算,用男生剪的数量加上女生剪的数量即可.\n【详解】 9 + 9 = 18 (个)所以一共剪了 18 个窗花。故答案为:B.", + "knowledge_points": [ + "9 加几的进位加法" + ], + "source": "22-23一年级上·四川·课后作业" + }, + { + "id": "330", + "unit": " 第五单元20以内的进位加法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "两只小猫一共钓了( )条鱼。 ![](images/391a897c22e322dc9d0560410f2d20fa1386570d9a6519845c5690c5515fa285.jpg)", + "options": [ + "A. 14", + "B. 15", + "C. 16" + ], + "answer": "B", + "solution": "【分析】将两只猫钓的鱼的数量相加即可得出它们一共钓了多少条鱼.\n【详解】 9 + 6 =15 (条)所以两只小猫一共钓了15条鱼。故答案为:B", + "knowledge_points": [ + "9 加几的进位加法" + ], + "source": "22-23 一年级上·四川·课后作业" + }, + { + "id": "331", + "unit": " 第五单元20以内的进位加法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "根据下图,可以列出算式( )。 ![](images/314174f78cc0340e7ae35f9220f00666.jpg)", + "options": [ + "A. 9 + 6 = 16", + "B. 9 + 7 = 16", + "C. 9 + 6 =15" + ], + "answer": "C", + "solution": "【分析】根据图片:左边有9面红旗,右边有6面红旗,问共有多少面。用左边的数量加上右边的数量即可.\n【详解】 9 + 6 =15 (面)故答案为:C\n[点睛]主要考查看图列算式及9加几的进位加法,计算要正确。", + "knowledge_points": [ + "9 加几的进位加法" + ], + "source": "22-23一年级上·四川·课后作业" + }, + { + "id": "332", + "unit": " 第五单元20以内的进位加法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "根据图片,所列式子正确的是( )。 ![](images/a7c10b943de195c17bc6213ab1c9e69d.jpg)", + "options": [ + "A. 9+5= 14", + "B. 9 + 6 =15", + "C. 9 + 7 = 16" + ], + "answer": "B", + "solution": "【分析】根据图片:左边有9个桃子,右边有6个桃子,问共有多少个桃子。用左边的数量加上右边的数量即可.\n【详解】 9 + 6=15 (个)故答案为:B.", + "knowledge_points": [ + "9加几的进位加法" + ], + "source": "22-23 一年级上·四川·课后作业" + }, + { + "id": "333", + "unit": " 第五单元20以内的进位加法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "算一算,可以用算式( )表示西瓜的个数。 ![](images/c3d2e06eccc9376be614f24cdc25541a.jpg)", + "options": [ + "A. 9+4=13", + "B. 9+6=15", + "C. 8+6=14" + ], + "answer": "B", + "solution": "【分析】从图上可得:左边有9个西瓜,右边有6个西瓜,要求一共有多少个西瓜,根据整数加法的意义,列式解答即可.\n【详解】 9 + 6 =15 (个)所以,有 15 个西瓜。故答案为:B.", + "knowledge_points": [ + "9加几的进位加法" + ], + "source": "22-23 一年级上·四川·课后作业" + }, + { + "id": "334", + "unit": " 第五单元20以内的进位加法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "在新一届少儿电视节目主持人大赛中,一(1)班同学给⽉亮姐姐投了 9 票,给绿泡泡投了 3 票,一(1)班同学给这两位主持人共投了( )票。", + "options": [ + "A. 11", + "B. 12", + "C. 13" + ], + "answer": "B", + "solution": "【分析】根据题意:一(1)班同学给⽉亮姐姐投了 9 票,给绿泡泡投了3票,问共给这两位主持人投了多少票。用加法计算,把投给⽉亮姐姐的票数加上给绿泡泡投的票数即可.\n【详解】 9 + 3 =12 (票)所以一(1)班同学给这两位主持人共投了 12 票。故答案为:B.", + "knowledge_points": [ + "9加几的进位加法" + ], + "source": "22-23一年级上·四川·课后作业" + }, + { + "id": "335", + "unit": " 第五单元20以内的进位加法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "小明有 7 张邮票,小强有 9 张邮票,他们一共有( )张邮票。", + "options": [ + "A. 15", + "B. 16", + "C. 17" + ], + "answer": "B", + "solution": "【分析】根据题意可知:小明有7张邮票,小强有9张邮票,问他们一共有多少张邮票。用加法计算,用小明有的数量加上小强有的数量即可.\n【详解】 7 + 9 =16 (张)所以他们一共有 16 张邮票。故答案为:B.", + "knowledge_points": [ + "7,6加几的进位加法" + ], + "source": "22-23一年级上·四川·课后作业" + }, + { + "id": "336", + "unit": " 第五单元20以内的进位加法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "树上原来有 9 只鸟,又飞来了 4 只,现在共有( )只鸟。", + "options": [ + "A. 13", + "B. 14", + "C. 15" + ], + "answer": "A", + "solution": "【分析】树上原来有9只鸟,又飞来了4只,现在共有多少只鸟。用加法计算,用原来有的数量加又飞来的数量即可.\n【详解】 9 + 4 =13 (只)所以现在共有13只鸟。故答案为:A.", + "knowledge_points": [ + "9加几的进位加法" + ], + "source": "22-23一年级上·四川·课后作业" + }, + { + "id": "337", + "unit": " 第五单元20以内的进位加法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "小朋友们做红旗,一班做了9面,二班和一班一样多,两个班一共做了()面红旗.\n![](images/6ba01e015c0d9075887de4cd68376976b6c53515b49e556f69d91bdea9f08101.jpg)", + "options": [ + "A. 9", + "B. 18", + "C. 27" + ], + "answer": "B", + "solution": "【分析】从图上可得:二班和一班一样多,所以二班也做了9面红旗,要求两个班一共做了多少面红旗,根据加法的意义,列式解答即可.\n【详解】 9 + 9 = 18 (面)所以,两个班一共做了18面红旗。故答案为:B", + "knowledge_points": [ + "9 加几的进位加法" + ], + "source": "22-23一年级上·四川·课后作业" + }, + { + "id": "338", + "unit": " 第五单元20以内的进位加法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "依据下图,再画()个三角形就满 16 个了.\n![](images/a299143dfd8084d045641f990ce3dc2c05f49d93233200b21ba0bdbba99f9657.jpg)", + "options": [ + "A. 6", + "B. 7", + "C. 8" + ], + "answer": "B", + "solution": "【分析】从图上可得:已经有9个三角形,根据9加几的加法运算进行解答即可.\n【详解】 9 + 7 =16,所以再画7个三角形就满16个了。故答案为:B", + "knowledge_points": [ + "9 加几的进位加法" + ], + "source": "22-23一年级上·四川·课后作业" + }, + { + "id": "339", + "unit": " 第五单元20以内的进位加法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "一个加数是7,另一个加数是 9,和是( )。", + "options": [ + "A. 16", + "B. 17", + "C. 18" + ], + "answer": "A", + "solution": "【分析】根据加数+加数 = 和,将数据代入即可得出答案.\n【详解】 9 + 7 =16,所以和是 16 故答案为:A.", + "knowledge_points": [ + "9加几的进位加法" + ], + "source": "22-23一年级上·四川·课后作业" + }, + { + "id": "340", + "unit": " 第五单元20以内的进位加法", + "question_type": "选择题", + "difficulty": 0.65, + "question": "5+( )<14,括号里可以填的数有( )个。", + "options": [ + "A. 8", + "B. 9", + "C. 10" + ], + "answer": "B", + "solution": "【分析】先分别计算出 5 加 0,1,2,3,。,9 的和,再找出和小于 14 的算式,数一数有几个,即可解决此题.\n【详解】 5 + 0 =5 , 5 + 1 =6 , 5 + 2 =7 , 5 + 3 =8 , 5 + 4 = 9,5 + 5= 10 , 5 + 6 =11 , 5 + 7= 12 , 5 + 8 =13 , 5 + 9 =14 则, 5 + \\ ( ) \\ < 14,括号里可以填的数有 0,1,2,3,。,8,共 9 个。故答案为:B.", + "knowledge_points": [ + "8,9的加减法", + "5~ 2 加几的进位加法", + "10的加减法", + "20 以内数的比大小" + ], + "source": "22-23一年级下·上海·单元测试" + }, + { + "id": "341", + "unit": " 第五单元20以内的进位加法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "树上有一些鸟,第一次飞走4只,第二次飞走7只,两次一共飞走了( )只鸟。", + "options": [ + "A. 11", + "B. 10", + "C. 3" + ], + "answer": "A", + "solution": "【分析】把两次飞走的鸟数量加起来,求出和,即可解决此题.\n【详解】 4 + 7 =11 (只)故答案为:A.", + "knowledge_points": [ + "5 ~ 2 加几的进位加法" + ], + "source": "22-23一年级上·江苏泰州·期末" + }, + { + "id": "342", + "unit": " 第五单元20以内的进位加法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "一年级有 5 个班,二年级有 6 个班,三年级有 7 个班。一,二年级共有几个班。选择正确的算式( )。", + "options": [ + "A. 7+5", + "B. 5+6", + "C. 7+6" + ], + "answer": "B", + "solution": "【分析】把一年级的班级数和二年级的班级数加起来,结果就是一,二年级共有几个班;据此选择即可.\n【详解】由题意分析得:年级有5个班,二年级有6个班,三年级有7个班。一,二年级共有几个班。列式为:5+6。故答案为:B.", + "knowledge_points": [ + "5 ~ 2 加几的进位加法" + ], + "source": "22-23一年级上·江苏扬州·期末" + }, + { + "id": "343", + "unit": " 第五单元20以内的进位加法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "原来有 7 只猴子,又跑来了 6 只,现在有( )只。", + "options": [ + "A. 1", + "B. 12", + "C. 13" + ], + "answer": "C", + "solution": "【分析】把原来的猴子数量和又跑来的数量加起来,结果就是现在的数量.\n【详解】 7 + 6 =13 (只)故答案为:C.", + "knowledge_points": [ + "7,6 加几的进位加法" + ], + "source": "22-23一年级上·江苏徐州·期末" + }, + { + "id": "344", + "unit": " 第五单元20以内的进位加法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "王守给了季飞8张贴纸,两人的贴纸数量就一样多了,原来两人的贴纸相差()张。", + "options": [], + "answer": "16", + "solution": "【分析】把一个数比另一个数多出的数量平均分成2份,把其中的 1 份分给小的数后,两个数就会一样多。故,王守给了季飞 8 张贴纸,两人的贴纸数量就一样多,就说明王守的贴纸数量比季飞多了(8+8)张;据此解决.\n【详解】 8 + 8 =16 (张)故,王守给了季飞 8 张贴纸,两人的贴纸数量就一样多了,原来两人的贴纸相差16张。", + "knowledge_points": [ + "8加几的进位加法" + ], + "source": "23-24一年级上·河南周口·期末" + }, + { + "id": "345", + "unit": " 第五单元20以内的进位加法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "计算 9 + 4 时,我是这样想的:可以先算 9 加( ),再加( ),得数是( )。", + "options": [], + "answer": "13;13", + "solution": "【分析】用凑十法来解决此题,9和1凑成 。10 计算 9 + 4 时,先把4分成1和3,然后先计算 9 + 110,再计算 10 + 3 =13,即, 9 + 4 = 13\n【详解】由题意分析得:计算 9 + 4 时,我是这样想的:可以先算9加1,再加3,得数是 13 。", + "knowledge_points": [ + "9加几的进位加法" + ], + "source": "22-23一年级上·福建宁德·期末" + }, + { + "id": "346", + "unit": " 第五单元20以内的进位加法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "用\"凑十法\"计算 9+ 6 = ( ( )时,应先算( )+( )=( ),再算( )+()=( )。", + "options": [], + "answer": "15;9;1;10;10;5;15", + "solution": "【分析】根据凑十法,将其中一个加数拆出一个和另一个加数相加是10的数字,再用10加上拆分后剩下的数即可。在计算 9 + 6 时,使用凑十法,要把6分成1和5,先算 9 + 1= 10,再用 10 + 5= 15,所以 9 + 6 = 15 .\n【详解】先把6分成1和5, 9 + 1 =10 , 10 + 5= 15;所以用\"凑十法\"计算 9 + 6 等于几时,应先算 9 + 1 =10,再算 10 + 5 =15 。", + "knowledge_points": [ + "9 加几的进位加法" + ], + "source": "22-23一年级上·山东淄博·期末" + }, + { + "id": "347", + "unit": " 第五单元20以内的进位加法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "减数和差都是7,被减数是( )。", + "options": [], + "answer": "14", + "solution": "【分析】根据被减数-减数 = 差,可转换为减数+差 = 被减数,代入计算即可.\n【详解】 7 + 7 =14减数和差都是 7,被减数是 14", + "knowledge_points": [ + "7,6 加几的进位加法" + ], + "source": "22-23一年级上·浙江杭州·期末" + }, + { + "id": "348", + "unit": " 第五单元20以内的进位加法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "我们教室里原来有8盆花,小朋友们又拿来了 5 盆,现在共有( )盆花。", + "options": [], + "answer": "13", + "solution": "【分析】把原来的花的数量与又拿来的数量加起来,求出和,就是现在的花的数量.\n【详解】 8 + 5 =13 (盆)故,现在共有13盆花。", + "knowledge_points": [ + "8加几的进位加法" + ], + "source": "22-23一年级上·浙江杭州·期末" + }, + { + "id": "349", + "unit": " 第五单元20以内的进位加法", + "question_type": "填空题", + "difficulty": 0.65, + "question": "在括号里填上合适的数字。 4 + ( ) = 12 ( ) + 6 = 1310 - 2 = 4 + ( ) 9 + 5 = ( ) + 8", + "options": [], + "answer": "8;7;4;6", + "solution": "【分析】第 1 题:根据凑十法, 4 + 6 =10 , 10 + 2=12,则4 + 8 =12;;第 2 题:根据凑十法, 6 + 4=10;10 + 3 =13,则 6 + 7 = 13;第 3 题: 10 - 28;~ 84 + ~ ( ) ,即 8 - 4 =4;第 4 题: 9 + 5= 14 ;根据凑十法, 8 + 2 =10;10 + 4 = 14,则 8 + 6 =14 \n【详解】由分析得: 4 + 8 = 12;7 + 6 = 13;10 - 2 = 4 + 4;9 + 5 = 6 + 8 ", + "knowledge_points": [ + "8,9 的加减法", + "9 加几的进位加法", + "5~ 2 加几的进位加法", + "7,6 加几的进位加法" + ], + "source": "22-23一年级上·江苏苏州·期末" + }, + { + "id": "350", + "unit": " 第五单元20以内的进位加法", + "question_type": "填空题", + "difficulty": 0.65, + "question": "把3,5,7,9填在括号里,每个数只能填一次, ( ) + ( ) = ( ) + ( ) 。", + "options": [], + "answer": "3;9;5;7", + "solution": "【分析】根据大数凑小数的原则,先计算 3 + 9 =12,再计算 5 + 7 =12,据此得出结论即可.\n【详解】由分析知,3 + 9 = 5 + 7", + "knowledge_points": [ + "9加几的进位加法", + "7,6加几的进位加法" + ], + "source": "21-22一年级上·湖北武汉·期末" + }, + { + "id": "351", + "unit": " 第五单元20以内的进位加法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "☆-3=5, ○+☆=12 ☆=( ),○=( )。", + "options": [], + "answer": "8;4", + "solution": "【分析】被减数-减数 = 差,可转换为被减数 = 减数+差,即 ☆ = 5 + 3 = 8;可得出 ○+ 8 = 12,根据 4 + 8 =12,可知○ 为 4 .\n【详解】由分析得:☆-3=5, ○+☆=12 , ☆= 8 , ○ = 4。", + "knowledge_points": [ + "8,9 的加减法", + "5~ 2 加几的进位加法" + ], + "source": "22-23一年级上·江苏南通·期末" + }, + { + "id": "352", + "unit": " 第五单元20以内的进位加法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "有 2 行小树,一行 5棵,另一行有 6 棵,一共有( )棵。", + "options": [], + "answer": "11", + "solution": "【分析】根据题意可知,求一共有几棵数。把两行的各自有的数量相加即可.\n【详解】 5 + 6= 11 (棵)所以一共有(11)棵。", + "knowledge_points": [ + "5 ~ 2 加几的进位加法" + ], + "source": "22-23二年级上·河南周口·期中" + }, + { + "id": "353", + "unit": " 第五单元20以内的进位加法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "同学们排队,8 个男生站成一排,每两个男生之间站一个女生,有( )个女生,这一排共有( )人。", + "options": [], + "answer": "3;11", + "solution": "【分析】由题意可知,用 ○来表示男生,用△来表示女生,如图所示:○○△○○△○○△○○,这一排一共有3个女生,再加上男生的 8 人,这一排一共有 11 人,列式为 8+3= 11 (人),据此解答即可.\n【详解】 8 + 3= 11 (人)同学们排队,8个男生站成一排,每两个男生之间站一个女生,有(3)个女生,这一排共有(11)人。", + "knowledge_points": [ + "8加几的进位加法" + ], + "source": "22-23一年级下·浙江绍兴·期末" + }, + { + "id": "354", + "unit": " 第五单元20以内的进位加法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "算 8 + 6 时,可以把6 分成( )和( ),8 和( )凑成 10,再加( ),所以 8+6=( )。", + "options": [], + "answer": "2;4;2;4;1;4", + "solution": "【分析】计算 20 以内数的进位加法,可以用\"凑十法\"来做。故,算 8 + 6 时,先把 6 分成 2 和 4,然后 8 和 2 凑成 10,10+ 4 =14,故, 8 + 6 =14 .\n【详解】由题意分析得:算 8 + 6 时,可以把 6 分成 2 和 4,8 和 2 凑成 10,再加 4,所以 8 + 6=14 。", + "knowledge_points": [ + "8 加几的进位加法" + ], + "source": "23-24一年级上·河北·课后作业" + }, + { + "id": "355", + "unit": " 第五单元20以内的进位加法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "妈妈给贝贝买了 9支笔,阿姨又送给贝贝 8 支笔,贝贝一共有( )支笔。", + "options": [], + "answer": "17", + "solution": "【分析】把妈妈买的笔数量与阿姨买的数量加起来,求出和,就是贝贝一共有几支笔.\n【详解】 9 + 8 =17 (支)故,贝贝一共有17支笔。", + "knowledge_points": [ + "9 加几的进位加法" + ], + "source": "23-24一年级上·辽宁·课后作业" + }, + { + "id": "356", + "unit": " 第五单元20以内的进位加法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "填上\">\"\"<\"或 \"=\" \"。 3 + 8 ( ) 124 + 7 ( ) 1915 ( ) 4 + 94 + 1 ( ) 9+6", + "options": [], + "answer": "<;<;>;<", + "solution": "【分析】先将括号左右两边的算式算出来后比大小;比较两个整数的大小,首先看位数,若不同,数位多的整数大;若相同,从高位比起,相同数位上的数大的那个整数就大.\n【详解】 3 + 8 =11,所以 3 + 8 { < } 124 + 7= 11,所以 4 + 7 < 194 + 9= 13,所以 { 15 > 4 + 9 } 4 + 1 =5 , 9 + 6 =15,所以 4 + 1 { < } 9 + 6\n[点睛]本题主要考查20以内加法计算和20以内比大小,熟练掌握即可。", + "knowledge_points": [ + "9 加几的进位加法", + "5~ 2 加几的进位加法", + "8 加几的进位加法", + "7,6加几的进位加法" + ], + "source": "23-24一年级上·辽宁·课后作业" + }, + { + "id": "357", + "unit": " 第五单元20以内的进位加法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "树上停了一些小鸟,第一次飞走了 7 只,第二次飞走了 9 只,最后还剩下 4 只,树上的小鸟比原来少了( )只。", + "options": [], + "answer": "16", + "solution": "【分析】把第一次飞走的数量和第二次飞走的数量加起来,求出和,即可解决此题.\n【详解】 7 + 9 =16 (只)故,树上的小鸟比原来少了16只。", + "knowledge_points": [ + "7,6 加几的进位加法" + ], + "source": "23-24一年级上·上海·单元测试" + }, + { + "id": "358", + "unit": " 第五单元20以内的进位加法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "减数是 8,差是 4,被减数是( )。", + "options": [], + "answer": "12", + "solution": "【分析】被减数-减数 = 差,被减数 = 减数+差,据此解答.\n【详解】 8 + 4 =12;所以,减数是 8,差是 4,被减数是 12。", + "knowledge_points": [ + "8 加几的进位加法" + ], + "source": "23-24一年级上·上海·单元测试" + }, + { + "id": "359", + "unit": " 第五单元20以内的进位加法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "树上有 16 只鸟,第一次飞走 6 只,第二次飞走 5 只,两次共飞走了( )只。", + "options": [], + "answer": "11", + "solution": "【分析】把两次飞走的鸟数量加起来,求出和,即可解决此题.\n【详解】 6 + 5= 11 (只)故,两次共飞走了 11 只。", + "knowledge_points": [ + "5 ~ 2 加几的进位加法" + ], + "source": "23-24一年级上·辽宁·单元测试" + }, + { + "id": "360", + "unit": " 第五单元20以内的进位加法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "小灰兔拔了 9 个萝卜,再拔 6 个就和小白兔的一样多了,小白兔拔了( )个萝卜。", + "options": [], + "answer": "15", + "solution": "【分析】小灰兔拔了9个萝卜,再拔6个就和小白兔的一样多,也就是小白兔拔的萝卜比小灰兔多6个,用加法列式计算.\n【详解】 9 + 6=15 (个)故,小灰兔拔了9个萝卜,再拔6个就和小白兔的一样多,小白兔拔了15个萝卜。", + "knowledge_points": [ + "9 加几的进位加法" + ], + "source": "23-24一年级上·辽宁·单元测试" + }, + { + "id": "361", + "unit": " 第五单元20以内的进位加法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "一根长20分米的彩带,第一次用去5分米,第二次用去8分米,现在比原来短了( )分米。", + "options": [], + "answer": "13", + "solution": "【分析】两次用去的长度和,就是现在比原来短了的长度.\n【详解】 5 + 8 =13 (分米)故,现在比原来短了 13 分米。", + "knowledge_points": [ + "5 ~ 2 加几的进位加法" + ], + "source": "23-24一年级上·辽宁·单元测试" + }, + { + "id": "362", + "unit": " 第五单元20以内的进位加法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "一年级一班同学的年龄有的是7岁,有的是8岁。他们每人都有同桌,每对同学的年龄相加,总和最大是( )岁,最小是( )岁。", + "options": [], + "answer": "1614", + "solution": "【分析】两个8岁的相加,总和是最大的;两个7岁的相加,总和是最小的.\n【详解】由题意分析得:8 + 8 = 16 (岁) 7 + 7 = 14 (岁) 故,总和最大是16岁,最小是14岁。", + "knowledge_points": [ + "8加几的进位加法", + "7,6加几的进位加法" + ], + "source": "23-24一年级上·辽宁·单元测试" + }, + { + "id": "363", + "unit": " 第五单元20以内的进位加法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "小明向灾区小朋友捐了9个文具盒,小立捐了8个文具盒。两人一共捐了()个文具盒。", + "options": [], + "answer": "17", + "solution": "【分析】把小明捐的文具盒数量和小立捐的文具盒数量加起来,求出和,即可解决.\n【详解】 9 + 8=17 (个)故,两人一共捐了 17 个文具盒。", + "knowledge_points": [ + "9 加几的进位加法" + ], + "source": "23-24一年级上·辽宁·单元测试" + }, + { + "id": "364", + "unit": " 第五单元20以内的进位加法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "5 与 6 的和,列式是( )。", + "options": [], + "answer": "5 + 6=11", + "solution": "【分析】根据题意知:和即加法,则求5与6的和,用加法列式可为: 5 + 6 = 11 .\n【详解】由分析可得:5 与 6 的和,列式是5 + 6 =11 。", + "knowledge_points": [ + "5 ~ 2 加几的进位加法", + "7,6加几的进位加法" + ], + "source": "22-23二年级上·四川·课后作业" + }, + { + "id": "365", + "unit": " 第五单元20以内的进位加法", + "question_type": "填空题", + "difficulty": 0.65, + "question": "一个加数是 7,和是16,另一个加数是( )。", + "options": [], + "answer": "9", + "solution": "【分析】根据加数+加数 = 和,将数据代入,即可得出答案.\n【详解】 9 + 7 =16,所以另一个加数是9。", + "knowledge_points": [ + "9加几的进位加法" + ], + "source": "22-23一年级上·四川·课后作业" + }, + { + "id": "366", + "unit": " 第五单元20以内的进位加法", + "question_type": "填空题", + "difficulty": 0.65, + "question": "芳芳读一本18页的故事书,读了一周正好读完它的一半,还剩( )页没有读。", + "options": [], + "answer": "9", + "solution": "【分析】读了一周正好读完它的一半,说明读完的页数和没有读的页数一样多,故,找出两个相同的数的和是18的数,即可解决此题.\n【详解】由题意分析得:9 + 9= 18,即,18 的一半是 9;故,芳芳读一本18页的故事书,读了一周正好读完它的半,还剩9页没有读。", + "knowledge_points": [ + "9 加几的进位加法" + ], + "source": "22-23一年级下·江苏·单元测试" + }, + { + "id": "367", + "unit": " 第五单元20以内的进位加法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "在括号里填上\">\"\"<\"或\"=\"。 10 () 95 + 8 () 9 + 50 + 7 () 7 - 0", + "options": [], + "answer": ">;<;=", + "solution": "【分析】先计算出相应算式的结果,再按照整数比较大小的方法进行比较即可.\n【详解】由题意分析得: 10 > 9;5 + 8 = 13, 9 + 5 = 14,故,5 + 8 < 9 + 5;0 + 7 = 7, 7 - 0 = 7,故, 0 + 7 = 7 - 0 。 ", + "knowledge_points": [ + "9 加几的进位加法", + "5~2 加几的进位加法", + "7 的加减法", + "20 以内数的比大小" + ], + "source": "23-24一年级上·山西太原·期末" + }, + { + "id": "368", + "unit": " 第五单元20以内的进位加法", + "question_type": "判断题", + "difficulty": 0.65, + "question": "有 3 个数 4,3,9,任选其中 2 个数求和,得数有 6 种可能。( )", + "options": [], + "answer": "×", + "solution": "【分析】分别计算出每种可能即可求解.\n【详解】 4 + 3 =73 + 9 = 124 + 9 = 13 得数有 3 种可能。原题说法错误。 故答案为: ×", + "knowledge_points": [ + "9 加几的进位加法", + "5~2 加几的进位加法", + "7 的加减法" + ], + "source": "22-23二年级上·湖南张家界·期末" + }, + { + "id": "369", + "unit": " 第五单元20以内的进位加法", + "question_type": "判断题", + "difficulty": 0.65, + "question": "从 3,4,8 这三个数中,任意选取其中 2 个求和,得数有 3 种可能。( )", + "options": [], + "answer": "√", + "solution": "【分析】从 3,4,8 这三个数中,任意选取其中 2 个求和,将每种结果列出来即可求解.\n【详解】 3 + 4 =74 + 8 = 123 + 8 = 11 得数有3种可能。原题说法正确。 故答案为:√", + "knowledge_points": [ + "5 ~ 2 加几的进位加法", + "8加几的进位加法", + "7的加减法" + ], + "source": "23-24二年级上·甘肃武威·期中" + }, + { + "id": "370", + "unit": " 第五单元20以内的进位加法", + "question_type": "判断题", + "difficulty": 0.85, + "question": "与 8 相邻的两个数之和为 16。( )", + "options": [], + "answer": "√", + "solution": "【分析】由题意可知,与8相邻的数字分别是7和9,这两个数的和是 7 + 916,据此解答即可.\n【详解】由分析可得: 7 + 9 = 16 因此与8相邻的两个数之和为16。 故答案为:√", + "knowledge_points": [ + "9加几的进位加法" + ], + "source": "19-20 一年级上·全国·期末" + }, + { + "id": "371", + "unit": " 第五单元20以内的进位加法", + "question_type": "判断题", + "difficulty": 0.85, + "question": "校园两旁各栽了 8棵树,一共栽了 16 棵树。( )", + "options": [], + "answer": "√", + "solution": "【分析】两旁各栽了8棵,用8加8即可求出一共栽了多少棵树.\n【详解】 8 + 8= 16 (棵)一共栽了16棵树。故答案为:√", + "knowledge_points": [ + "8加几的进位加法" + ], + "source": "23-24 二年级上·四川·单元测试" + }, + { + "id": "372", + "unit": " 第五单元20以内的进位加法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "小白兔第一天拔了6根萝卜,第二天又拔了 8 根萝卜,一共拔多少根萝卜。 □ ○ □ = □(根)", + "options": [], + "answer": "6 + 8 =14", + "solution": "【分析】已知小白兔第一天拔了6根萝卜,第二天又拔了8根萝卜,要求两天一共拔了多少根萝卜,将两天拔的萝卜数量相加,即 6 + 8,据此解答即可.\n【详解】 6 + 8= 14 (根)答:一共拔了14根萝卜。", + "knowledge_points": [ + "7,6加几的进位加法" + ], + "source": "23-24一年级上·甘肃定西·期末" + }, + { + "id": "373", + "unit": " 第五单元20以内的进位加法", + "question_type": "解答题", + "difficulty": 0.65, + "question": "小兔送给妈妈8个萝卜后,还剩下6个,小兔原来有多少个萝卜。", + "options": [], + "answer": "14个", + "solution": "【分析】根据题意,要求原来的个数,用送给妈妈的个数加上剩下的个数,即可解答.\n【详解】 8 + 6 =14 (个)答:小兔原来有 14 个萝卜。", + "knowledge_points": [ + "8 加几的进位加法" + ], + "source": "22-23一年级上·甘肃天水·期末" + }, + { + "id": "374", + "unit": " 第五单元20以内的进位加法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "一根绳子长 18 米,第一次用去 8 米,第二次用去的和第一次同样长。两次一共用去多少米。", + "options": [], + "answer": "16 米", + "solution": "【分析】把第一次用去的长度和第二次用去的长度加起来,求出和,就是两次一共用去的长度。第一次用去8米,第二次用去的和第一次同样长,即,第二次也用去 8 米.\n【详解】 8 + 8=16 (米)答:两次一共用去 16 米。", + "knowledge_points": [ + "8 加几的进位加法" + ], + "source": "22-23 一年级上·福建宁德·期末" + }, + { + "id": "375", + "unit": " 第五单元20以内的进位加法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "猫妈妈钓了 8 条鱼,猫爸爸和她钓的同样多,那么它们一共钓了多少条鱼。", + "options": [], + "answer": "16 条", + "solution": "【分析】根据题意,猫爸爸和猫妈妈钓的同样多,也是8条,它们一共钓的数量,相加计算即可.\n【详解】 8 + 8 =16 (条)答:它们一共钓了16条鱼。", + "knowledge_points": [ + "8加几的进位加法" + ], + "source": "22-23 一年级上·山东淄博·期末" + }, + { + "id": "376", + "unit": " 第五单元20以内的进位加法", + "question_type": "解答题", + "difficulty": 0.65, + "question": "小红折了 7 朵纸花,小亮折的和小红同样多,他们一共折了多少朵纸花。 □ ○ □ = □(朵)", + "options": [], + "answer": "7+7=14", + "solution": "【分析】小亮和小红折的纸花同样多,都是 7 朵,用加法求他们一共折了几朵即可.\n【详解】 7 + 7 =14 (朵)答:他们一共折了 14 朵纸花。", + "knowledge_points": [ + "7,6 加几的进位加法" + ], + "source": "22-23 一年级上·江苏苏州·期末" + }, + { + "id": "377", + "unit": " 第五单元20以内的进位加法", + "question_type": "解答题", + "difficulty": 0.65, + "question": "有 9 个,又买来 7 个,现在有多少个 。 □ ○ □ = □(个)", + "options": [], + "answer": "9+7=16", + "solution": "【分析】现有的苹果数量加上又买来的苹果数量就是现在的苹果数量。据此列式解答即可.\n【详解】 9 + 716 (个)答:现在有 16 个苹果。", + "knowledge_points": [ + "9加几的进位加法" + ], + "source": "22-23 一年级上·江苏苏州·期末" + }, + { + "id": "378", + "unit": " 第五单元20以内的进位加法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "乐乐做了 8 朵纸花,红红做的和他同样多。他们俩一共做了多少朵纸花。 □ ○ □ = □=(朵)", + "options": [], + "answer": "8+8=16", + "solution": "【分析】乐乐做了8朵纸花,红红做的和他同样多,也就是红红做了 8 朵纸花;用加法把两人做的花数量加起来,求出和,即可解决此题.\n【详解】 8 + 8 =16 (朵)答:他们俩一共做了 16 朵纸花。", + "knowledge_points": [ + "8 加几的进位加法" + ], + "source": "22-23 一年级上·江苏淮安·期末" + }, + { + "id": "379", + "unit": " 第五单元20以内的进位加法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "一年一班图书角原有8本漫画书,同学们又捐了7本。现在图书角共有多少本漫画书。", + "options": [], + "answer": "15本", + "solution": "【分析】现在图书角共有漫画书的本数 = 图书角原有漫画书的本数+同学们又捐的本数.\n【详解】 8 + 7 =15 (本)答:现在图书角共有15本漫画书。", + "knowledge_points": [ + "8 加几的进位加法" + ], + "source": "20-21一年级上·黑龙江鹤岗·期末" + }, + { + "id": "380", + "unit": " 第五单元20以内的进位加法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "小华吃了 3 个面包,还有9个,原来有多少个面包。", + "options": [], + "answer": "12 个", + "solution": "【分析】原来的面包数量 = 吃了的数量 + 还剩的数量,代入计算即可.\n【详解】 3 + 9 =12 (个)答:原来有12个面包。", + "knowledge_points": [ + "5 ~ 2 加几的进位加法" + ], + "source": "21-22 一年级上·广东清远·期末" + }, + { + "id": "381", + "unit": " 第五单元20以内的进位加法", + "question_type": "解答题", + "difficulty": 0.94, + "question": "小兰今年 6 岁,再过 9 年,小兰多少岁。", + "options": [], + "answer": "15 岁", + "solution": "【分析】已知小兰今年 6 岁,要求再过 9 年小兰多少岁,根据加法的意义,用 6+9,列式解答即可.\n【详解】 6 + 9=15 (岁)答:再过9年,小兰15岁。", + "knowledge_points": [ + "9 加几的进位加法" + ], + "source": "20-21 一年级上·河北石家庄·期末" + }, + { + "id": "382", + "unit": " 第五单元20以内的进位加法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "花店卖了 8 盆仙人球,还剩 9 盆,花店原来有多少盆仙人球。", + "options": [], + "answer": "17 盆", + "solution": "【分析】卖了的数量+还剩的数量 = 原来的数量,代入计算即可.\n【详解】 8 + 9= 17 (盆)答:花店原来有 17 盆仙人球。", + "knowledge_points": [ + "8加几的进位加法" + ], + "source": "20-21 一年级上·河北石家庄·期末" + }, + { + "id": "383", + "unit": " 第五单元20以内的进位加法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "4个男同学从图书馆借走7本书,2个女同学借走4本书,他们一共借走多少本书。 □ ○ □ = □ (本)", + "options": [], + "answer": "7 + 4 =11", + "solution": "【分析】把男同学借走的书数量和女同学借走的书数量加起来,求出和,就是一共借走的书的数量.\n【详解】由题意分析得:7 + 4=11 (本)答:他们一共借走11本书。", + "knowledge_points": [ + "7,6加几的进位加法" + ], + "source": "20-21一年级上·河北张家口·期末" + }, + { + "id": "384", + "unit": " 第五单元20以内的进位加法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "马路两边种树,一边种了 8 棵,一边种了 9 棵,两边一共种了多少棵。", + "options": [], + "answer": "17棵", + "solution": "【分析】将两边的棵数相加即可求出一共种了多少棵.\n【详解】 8 + 9=17 (棵)答:两边一共种了 17 棵。", + "knowledge_points": [ + "8加几的进位加法" + ], + "source": "23-24 二年级上·四川·期中" + }, + { + "id": "385", + "unit": " 第五单元20以内的进位加法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "草地上有 6 只公鸡,9只母鸡,8只黄色的,7只花色的。草地上一共有多少只鸡。", + "options": [], + "answer": "15 只", + "solution": "【分析】由题意可知,草地上有6只公鸡,9只母鸡,问题是一共有多少只鸡,用加法计算即可.\n【详解】 6 + 9 =15 (只)答:草地上一共有15只鸡。", + "knowledge_points": [ + "9加几的进位加法" + ], + "source": "22-23 一年级上·全国·随堂练习" + }, + { + "id": "386", + "unit": " 第五单元20以内的进位加法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "小朋友们一起做小花,做了 9 朵红花,7 朵黄花。小朋友们一共做了多少朵花。", + "options": [], + "answer": "16 朵", + "solution": "【分析】由题意可知,小朋友们一起做小花,做了9朵红花,7朵黄花,问题是一共做了多少朵花,用红花的朵数加上黄花的朵数即可解决问题.\n【详解】由分析可得:9 + 7 = 16 (朵) 答:小朋友们一共做了 16 朵花。", + "knowledge_points": [ + "9加几的进位加法" + ], + "source": "22-23 一年级上·全国·随堂练习" + }, + { + "id": "387", + "unit": " 第五单元20以内的进位加法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "东东第一天看了 9页书,第二天看了6页,两天一共看了多少页。", + "options": [], + "answer": "15 页", + "solution": "【分析】把第一天看的页数与第二天看的页数加起来,求出和,就是两天一共看了的页数.\n【详解】 9 + 6 =15 (页)答:两天一共看了15页。", + "knowledge_points": [ + "9加几的进位加法" + ], + "source": "23-24 一年级上·辽宁·课后作业" + }, + { + "id": "388", + "unit": " 第五单元20以内的进位加法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "停车场原有9辆车,又开来了 8 辆,停车场现在有多少辆车。", + "options": [], + "answer": "17 辆", + "solution": "【分析】把停车场原有车的数量与又开来的数量加起来,求出和,就是停车场现在车的数量.\n【详解】 9 + 8 =17 (辆)答:停车场现在有 17 辆车。", + "knowledge_points": [ + "9 加几的进位加法" + ], + "source": "23-24一年级上·辽宁·课后作业" + }, + { + "id": "389", + "unit": " 第五单元20以内的进位加法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "淘气有 8 张画片,笑笑又给他了3张,淘气现在有多少张画片。", + "options": [], + "answer": "11 张", + "solution": "【分析】淘气有8张画片,笑笑又给他了3张,求淘气现在有多少张画片用加法计算.\n【详解】 8 + 3 =11 (张)答:淘气现在有 11 张画片。", + "knowledge_points": [ + "8加几的进位加法" + ], + "source": "23-24 一年级上·辽宁·课后作业" + }, + { + "id": "390", + "unit": " 第五单元20以内的进位加法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "手工课上,红红折了8只千纸鹤,明明折了6只千纸鹤,两人一共折了多少只千纸鹤。", + "options": [], + "answer": "14 只", + "solution": "【分析】红红折了8只千纸鹤,明明折了6只千纸鹤,求两人一共折了多少只千纸鹤用加法计算.\n【详解】 8 + 6 =14 (只)答:两人一共折了14只千纸鹤。", + "knowledge_points": [ + "8加几的进位加法" + ], + "source": "23-24 一年级上·辽宁·课后作业" + }, + { + "id": "391", + "unit": " 第五单元20以内的进位加法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "汽车到站下去了 9 个人,现在车上有8个人,车上原来有几个人。", + "options": [], + "answer": "17 人", + "solution": "【分析】把汽车到站下去的人数和现在车上的人数加起来,求出和,即可解决此题.\n【详解】 9 + 8 =17 (人)答:车上原来有17个人。", + "knowledge_points": [ + "9 加几的进位加法" + ], + "source": "23-24 一年级上·上海·单元测试" + }, + { + "id": "392", + "unit": " 第五单元20以内的进位加法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "国美电器某门店卖出了 9 台电冰箱,还剩 9 台。原来商店有多少台电冰箱。", + "options": [], + "answer": "18 台", + "solution": "【分析】把卖出去的冰箱和剩下的冰箱加起来,求出和,即可解决此题.\n【详解】 9 + 9 = 18 (台)答:原来商店有 18 台电冰箱。", + "knowledge_points": [ + "9 加几的进位加法" + ], + "source": "23-24 一年级上·上海·单元测试" + }, + { + "id": "393", + "unit": " 第五单元20以内的进位加法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "桌上有4支铅笔,7支水笔,2 块橡皮。一共有几支笔。", + "options": [], + "answer": "11 支", + "solution": "【分析】把铅笔,水笔的数量加起来,求出和,即可解决此题.\n【详解】 4 + 7= 11(支)答:一共有 11 支笔。", + "knowledge_points": [ + "5 ~ 2 加几的进位加法" + ], + "source": "23-24一年级上·上海·单元测试" + }, + { + "id": "394", + "unit": " 第五单元20以内的进位加法", + "question_type": "解答题", + "difficulty": 0.65, + "question": "校门口摆了两行花,一行 6 盆,另一行 5 盆,一共多少盆。", + "options": [], + "answer": "11盆", + "solution": "【分析】根据加法的意义可知,计算两行花的总盆数,用加法计算,依此解答.\n【详解】 6 + 5 =11 (盆)答:一共有11盆。", + "knowledge_points": [ + "7,6加几的进位加法" + ], + "source": "22-23 一年级下·上海·单元测试" + }, + { + "id": "395", + "unit": " 第五单元20以内的进位加法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "一班有 6 个组,二班有 8 个组,一共有几个组。", + "options": [], + "answer": "14 个", + "solution": "【分析】一共的组数 = 一班的组数+二班的组数.\n【详解】 6 + 8= 14 (个)答:一共有14个组。", + "knowledge_points": [ + "7,6 加几的进位加法" + ], + "source": "23-24 二年级上·山东·单元测试" + }, + { + "id": "396", + "unit": " 第五单元20以内的进位加法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "一根绳子长20米,第一次剪去6米,第二次剪去5米,这根绳子比原来短了几米。", + "options": [], + "answer": "11 米", + "solution": "【分析】两次一共剪掉的绳子长度就是这根绳子比原来短的长度;故,用加法把两次剪掉的绳子长度加起来,求出和,即可解决此题.\n【详解】 6 + 5 =11(米) 答:这根绳子比原来短了 11 米。", + "knowledge_points": [ + "7,6加几的进位加法" + ], + "source": "23-24二年级上·上海·单元测试" + }, + { + "id": "397", + "unit": " 第五单元20以内的进位加法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "植树节里,三(2)班第一小组 6 个小朋友栽了 8 棵小树,第二小组 7 个小朋友栽了 9 棵小树。两个小组一共栽了几棵小树。", + "options": [], + "answer": "17 棵", + "solution": "【分析】求两个小组一共栽了几棵小树,就是求两个数的和,用加法列式计算.\n【详解】 8 + 9 =17 (棵)答:两个小组一共栽了 17 棵小树。", + "knowledge_points": [ + "8加几的进位加法" + ], + "source": "23-24 一年级上·河北·单元测试" + }, + { + "id": "398", + "unit": " 第五单元20以内的进位加法", + "question_type": "解答题", + "difficulty": 0.65, + "question": "小猫钓了 8 条大鱼和 6 条小鱼,小猫一共钓了几条鱼。", + "options": [], + "answer": "14 条", + "solution": "【分析】将小猫钓的大鱼和小鱼的数量相加,即可得出答案.\n【详解】 8 + 6=14 (条)答:小猫一共钓了14条鱼。", + "knowledge_points": [ + "8加几的进位加法" + ], + "source": "22-23 一年级上·四川·单元测试" + }, + { + "id": "399", + "unit": " 第五单元20以内的进位加法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "奶奶买了 9 个苹果,爷爷也买了同样多的苹果。两人一共买了多少个苹果。", + "options": [], + "answer": "18 个", + "solution": "【分析】求两个人一共买了多少个苹果,就是求两个数的和是多少,用加法计算。奶奶买了9个苹果,爷爷也买了同样多的苹果,说明爷爷也 是买了 9 个苹果.\n【详解】 9 + 9 = 18 (个)答:两人一共买了18个苹果。", + "knowledge_points": [ + "9加几的进位加法" + ], + "source": "21-22 一年级上·广东河源·期末" + }, + { + "id": "400", + "unit": " 第五单元20以内的进位加法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "玲玲和兰兰各有6个苹果,他们一共有几个苹果。", + "options": [], + "answer": "12个", + "solution": "【分析】求一共有几个苹果,就是求两个数的和,用加法列式解答.\n【详解】 6 + 6 =12 (个)答:他们一共有12个苹果。", + "knowledge_points": [ + "7,6 加几的进位加法" + ], + "source": "20-21一年级上·浙江金华·期末" + }, + { + "id": "401", + "unit": " 第五单元20以内的进位加法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "安安排队做操,她前面有 6 人,后面有 9 人,她所在的这一队一共排了()人。", + "options": [ + "A. 15", + "B. 16", + "C. 17" + ], + "answer": "B", + "solution": "【分析】根据题意,求这一队的总人数,用加法计算,即安安前面的人数+安安+安安后面的人数 = 这一队的总人数.\n【详解】 6 + 1 + 9 = 16 (人)她所在的这一队一共排了16人。故答案为:B", + "knowledge_points": [ + "连加(20以内)" + ], + "source": "2025 一年级上·全国·专题练习" + }, + { + "id": "402", + "unit": " 第五单元20以内的进位加法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "如果 △ + 6 = 10 + ○ ,那么( )代表的数字大一些。", + "options": [ + "A. △", + "B. ○", + "C. 无法确定" + ], + "answer": "A", + "solution": "【分析】由题可知,两个算式的结果相同,则一个加数越大,另一个加数就越小,由此比较已知加数的大小即可,也可以假设算式的结果,计算出△和 ○ 代表的数,比较即可.\n【详解】由分析得:已知的加数 6 < 10,则另一个加数 △ > ○。假设算式的结果为 15.6 和 4 合起来就是 10,10 再加上 5 就是 15,即 9 + 6 =15;10 + 5 =15;9 > 5,即△>○。则△代表的数字大一些。故答案为:A", + "knowledge_points": [ + "10 以内数的比大小", + "不进位加法(20 以内)", + "9加几的进位加法" + ], + "source": "2025 一年级上·全国·专题练习" + }, + { + "id": "403", + "unit": " 第五单元20以内的进位加法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "有一袋苹果,吃了一 半后,还剩 8 个,这袋苹果原来有( )个。", + "options": [ + "A. 8", + "B. 12", + "C. 16" + ], + "answer": "C", + "solution": "【分析】由题可知,一袋苹果,吃了一半,剩下的是另一半,是8个,则吃了的也是8个,吃了的数量+剩下的数量= 原来的数量.\n【详解】 8 + 8 =16 (个)这袋苹果原来有16个。故答案为:C", + "knowledge_points": [ + "8加几的进位加法" + ], + "source": "2025一年级上·全国·专题练习" + }, + { + "id": "404", + "unit": " 第五单元20以内的进位加法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "在算 9 + 6 =。 时,应先算( )。", + "options": [ + "A. 8+1", + "B. 1+4", + "C. 9+1" + ], + "answer": "C", + "solution": "【分析】根据凑十法,将其中一个加数拆出一个和另一个加数相加是10的数字,再用10加上拆分后剩下的数即可。在计算9+6时,使用凑十法,要把6分成1和5,先算9加1的和,再用这个和加上剩下的5即可.\n【详解】由分析得:先把6分成1和5, 9 + 1 =10 , 10 + 5 =15 即在算 9 + 6 =。 时,应先算 9 + 1 = 10 。故答案为:C", + "knowledge_points": [ + "9加几的进位加法" + ], + "source": "2025 一年级上·全国·专题练习" + }, + { + "id": "405", + "unit": " 第五单元20以内的进位加法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "下面的算式中,得数比 9 + 7 大的是( )。", + "options": [ + "A. 8+8", + "B. 19-7", + "C. 10+7" + ], + "answer": "C", + "solution": "【分析】根据 20 以内整数加减法运算,先算出各个算式的得数,再比较大小即可得出答案.\n【详解】 9 + 7 =16 A。8+8=16, 16 =16 B. 19 - 7 = 12 , 12 < 16 C. 10 + 7 = 17 ,17>16 故答案为:C", + "knowledge_points": [ + "不退位减法(20以内)", + "8加几的进位加法", + "9加几的进位加法", + "20 以内数的比大小" + ], + "source": "2025一年级上·全国·专题练习" + }, + { + "id": "406", + "unit": " 第五单元20以内的进位加法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "排队时,林林前面有7人,后面有9人,这一排一共有( )人。", + "options": [ + "A. 16", + "B. 18", + "C. 17" + ], + "answer": "C", + "solution": "【分析】用林林前面的人数加上林林自己,再加上林林后面的人数,就是这一排一共有的人数,据此解答.\n【详解】 7 + 1 =8 (人) 8 + 9 = 17 (人) 排队时,林林前面有 7 人,后面有 9 人,这一排一共有 17人。故答案为:C", + "knowledge_points": [ + "8 加几的进位加法" + ], + "source": "24-25一年级下·广东揭阳·期末" + }, + { + "id": "407", + "unit": " 第五单元20以内的进位加法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "下面的问题不可以用8 + 6 解决的是( )。", + "options": [ + "A. 鱼缸里有 8 条黑鱼,6 条鲤鱼,鱼缸里一共有多少条鱼。", + "B. 车上原来有 8 人,又上来 6 人,车上现在有多少人。", + "C. 盘子里有 8 个苹果,爸爸吃了 6 个,盘子里还剩下几个苹果。" + ], + "answer": "C", + "solution": "【分析】由题意可知:分析下面各项,并列式计算,和题目中算式不一致的,即是不可以用 8+6 解决的问题。A。把8条黑鱼和6条鲤鱼相加,即是鱼缸里一共有鱼的条数;B。用车上原来有的人数加上又上来的人数,即是车上现在有的人数;C。用盘子里原来有的苹果数减去爸爸吃了的个数,即是盘子里还剩下苹果的个数;据此列式计算.\n【详解】A。 8 + 6 =14 (条),和题目一致,不符合题意;B. 8 + 6 =14 (人),和题目一致,不符合题意;C. 8 - 6 =2 (个),和题目不一致,符合题意。故答案为:C", + "knowledge_points": [ + "8加几的进位加法", + "8,9的加减法" + ], + "source": "24-25 一年级下·宁夏银川·期末" + }, + { + "id": "408", + "unit": " 第五单元20以内的进位加法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "把 12 个苹果分成两堆,下面哪种分法相等。( )", + "options": [ + "A. 8 和 4", + "B. 6 和 6", + "C. 5 和 7" + ], + "answer": "B", + "solution": "【分析】找出两堆数量相加的和等于12,且两堆数量相等的分法即可.\n【详解】A。 8 + 4 =12 ,8 和 4 不相等,一堆 8 个,另一堆 4个的分法不是平均分;B. 6 + 6 =12 ,6 和 6 相等,一堆 6 个,另一堆 6 个的分法是平均分;C. 5 + 7 =12 ,5和7不相等,一堆5个,另一堆7个的分法不是平均分。故答案为:B", + "knowledge_points": [ + "5 ∼ 2 加几的进位加法", + "8 加几的进位加法", + "7,6加几的进位加法" + ], + "source": "24-25 一年级下·黑龙江佳木斯·期末" + }, + { + "id": "409", + "unit": " 第五单元20以内的进位加法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "小红有 7 朵花,小丽比小红多 6 朵,小丽有( )朵花。", + "options": [ + "A. 12", + "B. 13", + "C. 14" + ], + "answer": "B", + "solution": "【分析】已知一个数比另一个数多多少,求一个数是多少,用加法列式解决;即用小红的花数量加上小丽比小红多的数量,求出和,就是小丽的花数量.\n【详解】 7 + 6 =13 (朵)即,小红有7朵花,小丽比小红多6朵,小丽有(13)朵花。故答案为:B", + "knowledge_points": [ + "谁比谁多/少几的问题", + "7,6加几的进位加法" + ], + "source": "24-25 一年级下·黑龙江佳木斯·期末" + }, + { + "id": "410", + "unit": " 第五单元20以内的进位加法", + "question_type": "选择题", + "difficulty": 0.65, + "question": "姐姐有16本书,妹妹有 8 本书,姐姐给妹妹 4 本后,( )。", + "options": [ + "A. 两人的书同样多", + "B. 姐姐的书多", + "C. 妹妹的书多" + ], + "answer": "A", + "solution": "【分析】算出姐姐给妹妹 4 本后各自的本数,然后比较即可求解。给出去用减法计算,收到书的用加法计算.\n【详解】 16 - 4 = 12 (本) 8 + 4 = 12 (本) 12 = 12 姐姐有16本书,妹妹有8本书,姐姐给妹妹4本后,两人的书同样多。故答案为:A", + "knowledge_points": [ + "5 ∼ 2 加几的进位加法", + "不退位减法(20 以内)", + "8 加几的进位加法" + ], + "source": "24-25二年级下·河南周口·期末" + }, + { + "id": "411", + "unit": " 第五单元20以内的进位加法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "有 2 盒钢笔,一盒 5 支,一盒 6 支,两盒一共有( )支钢笔。", + "options": [ + "A. 30", + "B. 12", + "C. 11" + ], + "answer": "C", + "solution": "【分析】把两盒钢笔的支数加在一起,即可求出两盒一共有多少支钢笔.\n【详解】 5 + 6 =11 (支) 两盒一共有11支钢笔。 故答案为:C", + "knowledge_points": [ + "5 ∼ 2 加几的进位加法" + ], + "source": "23-24 二年级上·新疆乌鲁木齐·期末" + }, + { + "id": "412", + "unit": " 第五单元20以内的进位加法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "体育课上笑笑和妙想一起踢毽子,笑笑踢了9下,妙想踢了7下,她们一共踢了( )下。", + "options": [ + "A. 2", + "B. 16", + "C. 17" + ], + "answer": "B", + "solution": "【分析】要求笑笑和妙想一共踢了多少下,根据加法的意义,将她们跳的下数相加,用 9+7 进行解答即可.\n【详解】 9 + 7 =16 (下)所以她们一共踢了16下。故答案为:B", + "knowledge_points": [ + "9加几的进位加法", + "7,6加几的进位加法" + ], + "source": "24-25一年级下·安徽芜湖·期中" + }, + { + "id": "413", + "unit": " 第五单元20以内的进位加法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "小明的书包里有8本书,妈妈又放了 5 本,现在有多少本书。( )", + "options": [ + "A. 12", + "B. 13", + "C. 14" + ], + "answer": "B", + "solution": "【分析】根据题意可知,小明书包里原有书本的数量加上妈妈又放进去的数量,等于现在有多少本书,据此解答.\n【详解】根据分析可得:8 + 5 =13 (本) 所以,小明的书包里现在有 13 本书。故答案为:B", + "knowledge_points": [ + "8加几的进位加法" + ], + "source": "24-25一年级下·湖南岳阳·期中" + }, + { + "id": "414", + "unit": " 第五单元20以内的进位加法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "□+5=13,□里能填( )。", + "options": [ + "A. 7", + "B. 8", + "C. 18" + ], + "answer": "B", + "solution": "【分析】题目要求找到方框中的数,使得等式成立:□+5= 13 。先想一想哪个数和已知加数相加等于10,然后再用这个数加上和的个位上的数,即可得□里的数.\n【详解】根据分析可得; 5 + 5 = 105 + 3 = 8 即, 8 + 5 =13,所以,□ + 5 =13 ,□里能填 8。故答案为:B", + "knowledge_points": [ + "8 加几的进位加法", + "8,9 的加减法", + "10 的加减法" + ], + "source": "24-25一年级上·山东济南·期末" + }, + { + "id": "415", + "unit": " 第五单元20以内的进位加法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "下面算式中,得数最大的是( )。", + "options": [ + "A. 7+8", + "B. 5+6", + "C. 8+9" + ], + "answer": "C", + "solution": "【分析】分别计算各选项的得数,加法时,可以用\"凑十法\"等方法计算,把得数比较大小,找出最大即可。20以内数从小到大为: 0 < 1 < 2 < 3 < 4 < 5 < 6 < 7 < 8 < 9 < 10 < 11<12<13<14<15<16<17<18<19<20,由此比较即可.\n【详解】A。 7 + 8 =15 B。5+6=11 C。8+9=1717>15>1117 是最大的数,因此得数最大的是选项C。 故答案为:C", + "knowledge_points": [ + "5 ∼ 2 加几的进位加法", + "8 加几的进位加法", + "7,6加几的进位加法" + ], + "source": "24-25 一年级上·河南周口·期末" + }, + { + "id": "416", + "unit": " 第五单元20以内的进位加法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "美术组有男生 7 人,女生有 9 人,一共有( )人。", + "options": [ + "A. 2", + "B. 10", + "C. 16" + ], + "answer": "C", + "solution": "【分析】根据题意可知,男生的人数加上女生的人数,等于美术组一共有多少人,据此解答.\n【详解】根据分析可得: 7 + 9 =16 (人) 美术组一共有16人。 故答案为:C", + "knowledge_points": [ + "7,6加几的进位加法" + ], + "source": "24-25一年级上·山东济南·期末" + }, + { + "id": "417", + "unit": " 第五单元20以内的进位加法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "有2组同学正在拍皮球,一组有 5 人,另一组有 6 人,一共有( )人拍皮球。", + "options": [ + "A. 11", + "B. 8", + "C. 7" + ], + "answer": "A", + "solution": "【分析】据题意,一组有 5 人,另一组有 6 人,相加即可得出一共有几人.\n【详解】据分析可得 5 + 6 =11 (人),所以一共有 11 人拍皮球。故答案为:A", + "knowledge_points": [ + "7,6加几的进位加法" + ], + "source": "24-25一年级下·新疆喀什·开学考试" + }, + { + "id": "418", + "unit": " 第五单元20以内的进位加法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "在 3,6,9,15这四个数中,选三个数写出算式,下面列式不正确的是()。", + "options": [ + "A. 3+6=9", + "B. 6+9=15", + "C. 15-3=12" + ], + "answer": "C", + "solution": "【分析】检查算式计算是否正确,并且是否都是3,6,9,15这四个数中的数.\n【详解】A。 3 + 6 =9,正确;B. 6 + 9 =15,正确;C。没有数字12,不符合。列式不正确的是 15 - 3 = 12 mathrm o故答案为:C", + "knowledge_points": [ + "不退位减法(20 以内)", + "8,9 的加减法", + "9 加几的进位加法", + "7,6 加几的进位加法" + ], + "source": "24-25 一年级下·新疆喀什·开学考试" + }, + { + "id": "419", + "unit": " 第五单元20以内的进位加法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "得数大于 16 的算式是( )。", + "options": [ + "A. 7+5", + "B. 6+9", + "C. 5+12" + ], + "answer": "C", + "solution": "【分析】根据题意可知,题目要求找出得数大于16的算式,用\"凑十法\"或掌握的其它方法,逐一计算各选项,找出正确答案即可.\n【详解】A。7+5:7 加 5 等于 12, 12 < 16,不符合条件。 B。6+9:6加9等于15, 15 { < } 16,不符合条件。 C。5+12:5 加 12 等于 17, 17 > 16,符合条件。故答案为:C", + "knowledge_points": [ + "不进位加法(20 以内)", + "7,6 加几的进位加法" + ], + "source": "24-25 一年级下·江西吉安·阶段练习" + }, + { + "id": "420", + "unit": " 第五单元20以内的进位加法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "书架上有绘本和科普书共 18 本,拿走科普书的一半后,还剩 10 本书,科普书原来有( )本。", + "options": [], + "answer": "16", + "solution": "【分析】根据题意可知:可以先求出拿走科普书的一半是多少。用共有的数量减去还剩的数量即可, 18 - 10 = 8(本);然后理解一半是多少,即把两部分分得一样多,取其中一部分为一半。则科普书原来有2个8本,则把2个8相加即可求出科普书原来的数量.\n【详解】 18 - 10 = 8 (本) 8 + 8 = 16 (本) 则科普书原来有16本。", + "knowledge_points": [ + "不退位减法(20 以内)", + "8 加几的进位加法" + ], + "source": "25-26一年级上·全国·课后作业" + }, + { + "id": "421", + "unit": " 第五单元20以内的进位加法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "学校有一些篮球,一(1)班拿走了3个,一(2)班拿走了6个,两个班拿走的是总数的一半,学校一共有( )个篮球。", + "options": [], + "answer": "18", + "solution": "【分析】根据题意可知:先求出两个半一共拿走的数量,用一(1)班拿走的数量加上一(2)班拿走的数量即可,然后根据两个班拿走的是总数的一半,即可知道一共拿走的总数和剩余的是数量是一样多的,则把一共拿走的数量加剩余的数量即可求出学校一共的数量.\n【详解】 3 + 6 =9 (个) 9 + 9 = 18 (个) 则学校一共有(18)个篮球。", + "knowledge_points": [ + "9加几的进位加法", + "10的加减法" + ], + "source": "25-26 一年级上·全国·课后作业" + }, + { + "id": "422", + "unit": " 第五单元20以内的进位加法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "一些梨,乐乐吃掉了一半,爸爸又吃掉剩下的一半,还剩 4 个。一共有( )个梨。", + "options": [], + "answer": "16", + "solution": "【分析】根据题意可知,爸爸吃掉剩下的一半后剩4个,说明爸爸吃之前梨的数量,即4加4,等于8个,这8个正好是乐乐吃掉一半后剩下的梨,说明原来梨的数量,即8加8,等于16个,据此解答.\n【详解】根据分析可得: 4 + 4 = 8 (个) 8 + 8 = 16 (个) 些梨,乐乐吃掉了一半,爸爸又吃掉剩下的一半,还剩4个。一共有 16 个梨。", + "knowledge_points": [ + "8 加几的进位加法", + "8,9 的加减法" + ], + "source": "25-26一年级上·全国·课后作业" + }, + { + "id": "423", + "unit": " 第五单元20以内的进位加法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "笑笑今年9岁,哥哥比她大 4 岁,4 年后,哥哥和她相差( )岁。", + "options": [], + "answer": "4", + "solution": "【分析】根据年龄差不变可知,今年哥哥比笑笑大几岁,4年后还是大几岁。也可以计算出今年哥哥的年龄,4年后笑笑和哥哥的年龄,相减即可计算出结果.\n【详解】哥哥今年: 9 + 4 =13 (岁) 4 年后笑笑: 9 + 4 =13 (岁) 4年后哥哥: 13 + 4 = 17 (岁)17 - 13 = 4 (岁) 笑笑今年 9 岁,哥哥比她大 4 岁,4 年后,哥哥和她相差 4岁。", + "knowledge_points": [ + "不进位加法(20 以内)", + "不退位减法(20 以内)", + "9 加几的进位加法" + ], + "source": "25-26一年级上·全国·课后作业" + }, + { + "id": "424", + "unit": " 第五单元20以内的进位加法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "在括号里填上\"+\"或\"-\"。 9 ( ) 3 = 129 ( ) 5 > 109 ( ) 1 = 12 ( ) 2", + "options": [], + "answer": "+;+;+;-", + "solution": "【分析】结合整数加减法的计算法则及整数比较大小的方法来解决此题即可.\n【详解】 9 + 3 =12; 9 + 5 = 14, 14 > 10,故, 9 + 5 > 10;9 + 1 = 10, 12 - 2 = 10,故 , 9 + 1 = 12 - 2 。", + "knowledge_points": [ + "不退位减法(20 以内)", + "9 加几的进位加法", + "10的加减法", + "20 以内数的比大小" + ], + "source": "25-26一年级上·全国·课后作业" + }, + { + "id": "425", + "unit": " 第五单元20以内的进位加法", + "question_type": "填空题", + "difficulty": 0.94, + "question": "一个书架有两层,一层有 5 本书,一层有 6 本书,一共有( )本书。", + "options": [], + "answer": "11", + "solution": "【分析】根据题意,将两层书架上书的数量相加,即可计算出书的总数量.\n【详解】 5 + 6 =11 (本)一个书架有两层,一层有 5 本书,一层有 6 本书,一共有11 本书。", + "knowledge_points": [ + "5 ∼ 2 加几的进位加法" + ], + "source": "25-26 二年级上·陕西延安·阶段练习" + }, + { + "id": "426", + "unit": " 第五单元20以内的进位加法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "比一比。 5 + 7 ( ) 7 + 59 + 5 ( ) 8 + 64 + 8 ( ) 8 + 5", + "options": [], + "answer": "=;=;<", + "solution": "【分析】根据题意,依次计算出各算式的结果再比较大小,20 以内数从大到小关系为 20 > 19 > 18 > 17 > 16 > 15 > 14 > 13 > 12 > 11 > 10 > 9 > 8 > 7 > 6 > 5 > 4 > 3 > 2 > 1 > 0,由此比较.\n【详解】 5 + 7 = 12;~ 7 + 5 = 12;~ 12 = 1212 =12,则 5 + 7 =7 + 5; 9 + 5 = 14;~ 8 + 6 = 14;~ 14 = 1414 =14,则 9 + 5 =8 + 6;4 + 8 = 12;~ 8 + 5 = 13 。;12 < 13,则 4 + 8 { < } 8 + 5 phantom 。 +", + "knowledge_points": [ + "5 ∼ 2 加几的进位加法", + "8 加几的进位加法", + "7,6加几的进位加法", + "20以内数的比大小" + ], + "source": "25-26 一年级上·全国·课后作业" + }, + { + "id": "427", + "unit": " 第五单元20以内的进位加法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "7 + ( ) =169 + ()=12 ( )+3=116 + ( ) = 138 + ( ) = 15 ( ) + 4 = 14", + "options": [], + "answer": "9;3;8;7;7;10", + "solution": "【分析】根据\"加数+加数 = 和,和-一个加数 = 另一个加数\"据此计算.\n【详解】 16 - 7 = 9,则 7 + 9 =1612 - 9 = 3,则 9 + 3 =1211 - 3 = 8,则 8 + 3 =1113 - 6 =7,则 6 + 7 =1315 - 8 = 7,则 8 + 7 =1514 - 4 = 10,则 10 + 4 = 14", + "knowledge_points": [ + "8 加几的进位加法", + "9 加几的进位加法", + "7,6 加几的进位加法" + ], + "source": "25-26 一年级上·全国·课后作业" + }, + { + "id": "428", + "unit": " 第五单元20以内的进位加法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "在括号里填上\">\"\"<\"或 \"=\" 。 13( )4+83+9( )147+6( )12 \n11( )5+76+5( )123+8( )11", + "options": [], + "answer": ">;<;>;<;<;=", + "solution": "【分析】先计算每个算式的结果,再与另一边的数比较大小。据此解答.\n【详解】由分析可得:4 + 8 = 12, 13 > 12, 13 > 4 + 8;\n 3 + 9 = 12, 12 < 14, 3 + 9 < 14;\n 7 + 6 = 13, 13 > 12, 7 + 6 > 12;\n 5 + 7 = 12, 11 < 12, 11 < 5 + 7;6 + 5 = 11, 11 < 12, 6 + 5 < 12;\n 3 + 8 = 11, 11 = 11, 3 + 8 = 11 \n ", + "knowledge_points": [ + "5 ∼ 2 加几的进位加法", + "7,6 加几的进位加法", + "20以内数的比大小" + ], + "source": "25-26 一年级上·全国·课后作业" + }, + { + "id": "429", + "unit": " 第五单元20以内的进位加法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "找规律填数:3,6,9,( ),15,( )。", + "options": [], + "answer": "12;18", + "solution": "【分析】由题可知:6 - 3 =3;~ 9 - 6 =3,也就是后一个数比前一个数多3,则用前一个数 + 3 = 后一个数.\n【详解】9+3=12;15+3=18 找规律填数:3,6,9,12,15,18。", + "knowledge_points": [ + "整数排列的规律", + "不进位加法(20 以内)", + "9 加几的进位加法" + ], + "source": "25-26 二年级上·黑龙江佳木斯·开学考试" + }, + { + "id": "430", + "unit": " 第五单元20以内的进位加法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "在括号里填上\">\"\"<\"或 '' = '' 。 11( )139+4( )1215-3( )10", + "options": [], + "answer": "<;>;>", + "solution": "【分析】根据题意,依次计算出各算式的结果再比较大小,20 以内数从大到小关系为 20 > 19 > 18 > 17 > 16 > 15 > 14 > 13 > 12 > 11 > 10 > 9 > 8 > 7 > 6 > 5 > 4 > 3 > 2 > 1 > 0,由此比较.\n【详解】 11 < 139 + 4 =13;13>12,则 9 + 4 > 12;15-3=12;12 > 10,则 15 - 3 { > } 10 ", + "knowledge_points": [ + "不退位减法(20 以内)", + "9 加几的进位加法", + "20以内数的比大小" + ], + "source": "25-26二年级上·黑龙江佳木斯·开学考试" + }, + { + "id": "431", + "unit": " 第五单元20以内的进位加法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "在( )里填上\">\"\"<\"或 ''='' 。 2+9( )157+6( )138+10-5( )12\n8 + 7 () 167 + 5 () 118 - 4 + 9 () 16", + "options": [], + "answer": "<;=;>;<;>;<", + "solution": "【分析】先算出括号左边各算式的结果,再根据 20 { > } 19 { > } 18>17>16>15>14>13>12>11>10>9> 8>7>6>5>4 { > } 3 { > } 2 { > } 1 { > } 0 的顺序比较大小即可.\n【详解】 2 + 9 =11 , 11 < 15,所以 2 + 9 < 15;7 + 6 =13 , 13 =13,所以 7 + 6 =13;8 + 10 - 5 = 13 , 13 > 12,所以 8 + 10 - 5 > 12;8 + 7 =15 , 15 { < } 16,所以 8 + 7 { < } 16;7 + 5 =12 , 12 > 11,所以 7 + 5 > 11;8 - 4 + 9 = 13 , 13 { < } 16,所以 8 - 4 + 9 < 16 ", + "knowledge_points": [ + "5 ∼ 2 加几的进位加法", + "加减混合运算(20以内)8 加几的进位加法", + "7,6 加几的进位加法" + ], + "source": "2025 一年级上·全国·专题练习" + }, + { + "id": "432", + "unit": " 第五单元20以内的进位加法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "同学们排队做操,明明前面有 6 人,后面有 8 人,这一排一共有( )人。", + "options": [], + "answer": "15", + "solution": "【分析】根据题意,明明前面的人数+明明后面的人数+明明 = 这一排的总人数.\n【详解】 6 + 8 + 1 = 15 (人)同学们排队做操,明明前面有6人,后面有8人,这一排一共有 15 人。", + "knowledge_points": [ + "连加(20以内)" + ], + "source": "24-25一年级下·黑龙江佳木斯·期末" + }, + { + "id": "433", + "unit": " 第五单元20以内的进位加法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "爸爸沿圆形花坛一周种了 9 棵月季花,又在相邻两棵月季之间各种了 1 棵百合,月季和百合一共种了( )棵。", + "options": [], + "answer": "18", + "solution": "【分析】在封闭的圆形路径上,月季花的数量等于间隔数,每个间隔种1棵百合,因此百合的数量与月季数量相同。月季的棵数加上百合的颗数,等于月季和百合一共种了多少棵,据此解答.\n【详解】根据分析可得:9 + 9 =18 (棵)因此,爸爸沿圆形花坛一周种了9棵月季花,又在相邻两棵月季之间各种了 1 棵百合,月季和百合一共种了 18 棵。", + "knowledge_points": [ + "9加几的进位加法" + ], + "source": "24-25 一年级下·贵州黔东南·期末" + }, + { + "id": "434", + "unit": " 第五单元20以内的进位加法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "小丽领走了 9 本书,还剩 4 本,原来有( )本书。", + "options": [], + "answer": "13", + "solution": "【分析】根据加法的意义,小丽领走书的数量+还剩的数量 = 原来有书的数量.\n【详解】 9 + 4 =13 (本)小丽领走了 9 本书,还剩 4 本,原来有 13 本书。", + "knowledge_points": [ + "9加几的进位加法" + ], + "source": "24-25 一年级下·福建三明·期末" + }, + { + "id": "435", + "unit": " 第五单元20以内的进位加法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "小明从前往后数排第 8,从后往前数排第 9,这个队伍共有( )人。", + "options": [], + "answer": "16", + "solution": "【分析】根据题意,从前往后数到小明有8人,从后往前数到小明有9人,则用从前往后数到小明的人数+从后往前数到小明的人数-1(重复数了一次小明) = 总人数.\n【详解】 8 + 9 - 1 = 16 (人)小明从前往后数排第 8,从后往前数排第 9,这个队伍共有16 人。", + "knowledge_points": [ + "加减混合运算(20 以内)" + ], + "source": "24-25一年级下·广东佛山·期末" + }, + { + "id": "436", + "unit": " 第五单元20以内的进位加法", + "question_type": "填空题", + "difficulty": 0.65, + "question": "按规律填数: 3,6,9,( ),15。", + "options": [], + "answer": "12", + "solution": "【分析】由题意分析可知,相邻的两个数,后一个数比前一个数多 3;据此解决即可.\n【详解】 3 + 3 =6 , 6 + 3 =9 ,9+3=12,12+3=15;即,按规律填数:3,6,9,12,15。", + "knowledge_points": [ + "整数排列的规律" + ], + "source": "24-25 一年级下·湖南株洲·期中" + }, + { + "id": "437", + "unit": " 第五单元20以内的进位加法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "一个加数是8,另一个加数是5,和是( ),被减数是 17,减数是 5,差是()。", + "options": [], + "answer": "13;12", + "solution": "【分析】根据\"加数+加数 = 和,被减数-减数 = 差\",列式计算后填空即可.\n【详解】根据分析列式计算: 8 + 5 = 13;17 - 5 = 12 一个加数是8,另一个加数是5,和是13,被减数是17,减数是 5,差是 12。", + "knowledge_points": [ + "不退位减法(20 以内)", + "8 加几的进位加法" + ], + "source": "24-25一年级上·河南南阳·期末" + }, + { + "id": "438", + "unit": " 第五单元20以内的进位加法", + "question_type": "填空题", + "difficulty": 0.65, + "question": "比 15 多 1 的数是(),9 比( )少 4。", + "options": [], + "answer": "16;13", + "solution": "【分析】求比 15 多 1 的数,用 15 加 1 计算;求 9 比几少4,用9加4计算.\n【详解】 15 + 1 = 16;\\ 9 + 4 = 13 比 15 多 1 的数是 16,9 比 13 少 4 phantom 。", + "knowledge_points": [ + "不进位加法(20 以内)", + "9 加几的进位加法" + ], + "source": "24-25 一年级上·湖南湘西·期末" + }, + { + "id": "439", + "unit": " 第五单元20以内的进位加法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "小朋友排队购票,小明前面有 8 人,后面有 4 人,一共有( )人。", + "options": [], + "answer": "13", + "solution": "【分析】根据题意可知:用小明前面的人数加上后面的人数,再加上小明自己 1 人即可求出一共的人数.\n【详解】 8 + 4 + 1 = 13 (人)则一共有 13 人。", + "knowledge_points": [ + "连加(20以内)" + ], + "source": "24-25 一年级上·福建龙岩·期末" + }, + { + "id": "440", + "unit": " 第五单元20以内的进位加法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "小朋友站队,从左往右数,小明排第 6,从右往左数,小明排第 9,这一队共有( )人。", + "options": [], + "answer": "14", + "solution": "【分析】根据题意可知,从左数小明排第 6,说明他左边有5人;从右数小明排第9,说明他右边有8人。小明左边的人数加右边的人数,再加上小明自己,等于这一队共有多少人,据此解答.\n【详解】根据分析可得: 5 + 8 = 13 (人) 13 + 1 = 14 (人) 这一队共有 14 人。", + "knowledge_points": [ + "左,右位置", + "5 ~ 2 加几的进位加法", + "认识几和第几", + "不进位加法(20以内)" + ], + "source": "24-25一年级上·山东济南·期末" + }, + { + "id": "441", + "unit": " 第五单元20以内的进位加法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "两个加数分别是 5和 9,和是( ),差是( )。", + "options": [], + "answer": "14;4", + "solution": "【分析】根据\"加数+加数 = 和,被减数-减数 = 差\"完成此题.\n【详解】 5 + 9 =149 - 5 = 4 两个加数分别是 5 和 9,和是 14,差是 4 phantom 。", + "knowledge_points": [ + "5 ∼ 2 加几的进位加法", + "8,9 的加减法" + ], + "source": "24-25 一年级上·河南周口·期末" + }, + { + "id": "442", + "unit": " 第五单元20以内的进位加法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "两个加数都是 8,它们的和是( ),被减数是 13,减数的 10,差是( )。", + "options": [], + "answer": "16;3", + "solution": "【分析】加数+加数 = 和,被减数-减数 = 差,直接列式计算即可.\n【详解】 8 + 8 =1613 - 10 = 3 两个加数都是8,它们的和是16,被减数是13,减数的10,差是3。", + "knowledge_points": [ + "不退位减法(20以内)", + "8加几的进位加法" + ], + "source": "24-25 一年级上·湖北黄冈·期末" + }, + { + "id": "443", + "unit": " 第五单元20以内的进位加法", + "question_type": "填空题", + "difficulty": 0.65, + "question": "比 5 多 9 的数是(),( )比 7 多 11。", + "options": [], + "answer": "14;18", + "solution": "【分析】求比一个数多几的数是多少,用这个数+多的数计算.\n【详解】 5 + 9 = 14;\\ 7 + 11 = 18 比 5 多 9 的数是 14,18 比 7 多 11。", + "knowledge_points": [ + "5 ∼ 2 加几的进位加法", + "不进位加法(20 以内)" + ], + "source": "24-25 一年级上·广东潮州·期末" + }, + { + "id": "444", + "unit": " 第五单元20以内的进位加法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "计算 9 + 6 = dot iota 。 时,可以这样算,先算 9 + ( ) = 10,再算 10 + () = ( ) ", + "options": [], + "answer": "1;5;15", + "solution": "【分析】计算9+6时,可以用凑十法,即凑大数,分小数,凑成十,加剩数。也就是把6分成1和5,9和1合起来就是10,再加上5就是 15 \n【详解】计算 9 + 6 =。 时,可以这样算,先算 9 + 1 =10,再算 10 + 5 =15 。", + "knowledge_points": [ + "9加几的进位加法" + ], + "source": "24-25一年级上·河南周口·期末" + }, + { + "id": "445", + "unit": " 第五单元20以内的进位加法", + "question_type": "判断题", + "difficulty": 0.85, + "question": "8 + 7 =7 + 8 。( )", + "options": [], + "answer": "√", + "solution": "【分析】根据题意,分别计算出等号两边算式的结果,左边的数+右边的数 = 右边的数+左边的数,结果不变,据此解答.\n【详解】 8 + 7 =15 , 7 + 8 =15,和相等, 8 + 7 =7 + 8 故答案为:√", + "knowledge_points": [ + "8加几的进位加法", + "7,6加几的进位加法" + ], + "source": "24-25 一年级下·河南南阳·期末" + }, + { + "id": "446", + "unit": " 第五单元20以内的进位加法", + "question_type": "判断题", + "difficulty": 0.85, + "question": "两个数的和是12,那么这两个数的差可能是 0。( )", + "options": [], + "answer": "√", + "solution": "【分析】两个数的和为12,有多种情况,当这两个数相等,也就是 6 + 6 =12 时,两个数均为 6,和为 12 且差为 0;说明两个数的差可能是0,据此解答.\n【详解】由分析可得:两个数的和是12,那么这两个数的差可能是0,原题说法正确。故答案为:√", + "knowledge_points": [ + "6的加减法" + ], + "source": "24-25一年级下·河南许昌·期中" + }, + { + "id": "447", + "unit": " 第五单元20以内的进位加法", + "question_type": "判断题", + "difficulty": 0.85, + "question": "7 + 8 = 15 。( )", + "options": [], + "answer": "√", + "solution": "【分析】20以内数的进位加法计算时,可以用凑十法,把个加数分成两部分,其中一部分与另一个加数凑成十,再用十加上剩下的那部分就是最终的结果.\n【详解】由分析得:把 8 分成 3 和 5,7 和 3 合起来就是 10,再加上 5 就是 15,即 7 + 8 =15,原题计算正确。故答案为:√", + "knowledge_points": [ + "7,6加几的进位加法" + ], + "source": "24-25 一年级下·河南许昌·期中" + }, + { + "id": "448", + "unit": " 第五单元20以内的进位加法", + "question_type": "判断题", + "difficulty": 0.85, + "question": "8 + 9 和 9 + 8 的计算结果一样。( )", + "options": [], + "answer": "√", + "solution": "【分析】根据加法可知,交换两个加数的位置,和不变.\n【详解】8+9和 9 + 8 的计算结果一样。原题说法正确。故答案为:√", + "knowledge_points": [ + "8加几的进位加法", + "9加几的进位加法" + ], + "source": "24-25一年级上·湖南株洲·期末" + }, + { + "id": "449", + "unit": " 第五单元20以内的进位加法", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图写算式。 ![](images/41ace1a546df56b495924a651b77ba28bd0ad721af73fedf8291d2f7449cee7c.jpg) □ ○ □ = □(个)", + "options": [], + "answer": "7+7=14", + "solution": "【分析】由图可知,左边有7个,右边有7个,将左右两边 的数量相加即可求出一共多少个.\n【详解】 7 + 7 =14 (个)一共 14 个。", + "knowledge_points": [ + "图文问题", + "7,6 加几的进位加法" + ], + "source": "25-26 一年级上·全国·课后作业" + }, + { + "id": "450", + "unit": " 第五单元20以内的进位加法", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图写算式。 ![](images/44721ce604a16a9fc6273046aa1112c297fe5196abaca9822b98d76f9c7466e3.jpg) □ ○ □ = □(支)", + "options": [], + "answer": "8+5=13", + "solution": "【分析】由图可知,左边有 8 支,右边有 5 支,将左右两边的数量相加即可求出一共多少支.\n【详解】 8 + 5 =13 (支)或 5 + 8 =13 (支) 一共 13 支。", + "knowledge_points": [ + "8 加几的进位加法", + "图文问题" + ], + "source": "25-26 一年级上·全国·课后作业" + }, + { + "id": "451", + "unit": " 第五单元20以内的进位加法", + "question_type": "计算题", + "difficulty": 0.94, + "question": "看图写算式。 ![](images/1c4333f50c37ab0b9b4b4b15d34c92338fccf10f97d67fcea812499cdeff6c9f.jpg) □ ○ □ = □(个)", + "options": [], + "answer": "8+4=12", + "solution": "【分析】左边有8个,右边有4个,大括号下面求的是总和,求一共有多少个用加法计算.\n【详解】 8 + 4 =12 (个)所以一共有 12 个。", + "knowledge_points": [ + "8加几的进位加法" + ], + "source": "25-26 一年级上·全国·课后作业" + }, + { + "id": "452", + "unit": " 第五单元20以内的进位加法", + "question_type": "计算题", + "difficulty": 0.94, + "question": "看图列式计算。 ![](images/b95afac6947114825170d7997c33aa34438e6542a0a429acad502b07795b09f6.jpg) □ ○ □ = □(个)", + "options": [], + "answer": "3+8=11", + "solution": "【分析】图中左边有3本书,右边书包里有8本书,要求一共有多少本书,用加法计算.\n【详解】 3 + 8 =11 (本)因此一共有11本书。", + "knowledge_points": [ + "5 ∼ 2 加几的进位加法", + "图文问题" + ], + "source": "25-26 一年级上·全国·课后作业" + }, + { + "id": "453", + "unit": " 第五单元20以内的进位加法", + "question_type": "计算题", + "difficulty": 0.94, + "question": "看图列式计算。 ![](images/472255ff09b6e0419329bfd68d93cd7ccc75c7b0b04abf41ffc88c5acd207935.jpg) □ ○ □ = □(个)", + "options": [], + "answer": "5+8=13", + "solution": "【分析】从图上可得:左边有5只虾,右边有8只虾,要求共有多少只虾,根据加法的意义,用 5+8 进行解答即可.\n【详解】 5 + 8 =13 (只)一共有 13 只虾。", + "knowledge_points": [ + "5 ∼ 2 加几的进位加法", + "图文问题" + ], + "source": "25-26 一年级上·全国·课后作业" + }, + { + "id": "454", + "unit": " 第五单元20以内的进位加法", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式计算。 ![](images/d6ffbcd420664f3614494b705e9dffa315f352ba501812c6c37d0cc85be0214b.jpg) □ ○ □ = □(个 )", + "options": [], + "answer": "3+9=12", + "solution": "【分析】左边有3个草莓,右边有9个草莓,求一共有多少个草莓,用加法计算,即左边的数量+右边的数量 = 总数量.\n【详解】 3 + 9 =12 (个)一共有 12 个草莓。", + "knowledge_points": [ + "5 ∼ 2 加几的进位加法", + "图文问题" + ], + "source": "25-26 一年级上·全国·课后作业" + }, + { + "id": "455", + "unit": " 第五单元20以内的进位加法", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式计算。 ![](images/cfb64aaf8bbb3d6df373e82b85510bcc24c02663331b6eaee49ee9626b20848a.jpg) □ ○ □ = □ (支)", + "options": [], + "answer": "4+9=13", + "solution": "【分析】从图上可得:左边有4支铅笔,右边有9支铅笔,要求一共有多少支铅笔,根据加法的意义,用4+9进行解答即可.\n【详解】 4 + 9 =13 (支)所以一共有13支铅笔。", + "knowledge_points": [ + "5 ∼ 2 加几的进位加法", + "图文问题" + ], + "source": "25-26 一年级上·全国·单元测试" + }, + { + "id": "456", + "unit": " 第五单元20以内的进位加法", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式计算。 ![](images/3c754ad3ad2a5cb6caa777b1abe7eaf27eeba67495562fe2e4571ce52cc29f52.jpg) □ ○ □ = □ (个)", + "options": [], + "answer": "8+5=13", + "solution": "【分析】根据图片可知:左边有8个冰淇淋,右边有5个,则一共有多少个。用左边的数量加右边的数量即可.\n【详解】 8 + 5 =13 (个)则一共有13个。", + "knowledge_points": [ + "8加几的进位加法", + "图文问题" + ], + "source": "25-26 一年级上·全国·单元测试" + }, + { + "id": "457", + "unit": " 第五单元20以内的进位加法", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式计算。 ![](images/a70751067f7a46c40a0017cc87abf3b2e4b7afc5af7af65f09f2ada4db4983a4.jpg) □ ○ □ = □(个)", + "options": [], + "answer": "9+6 =15", + "solution": "【分析】一共的苹果数量 = 左边的数量+右边的数量;据此列式解决.\n【详解】 9 + 6 =15 (个)一共有15个苹果。", + "knowledge_points": [ + "图文问题", + "9 加几的进位加法" + ], + "source": "25-26 一年级上·全国·课后作业" + }, + { + "id": "458", + "unit": " 第五单元20以内的进位加法", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式计算。 ![](images/53e8a694f6be568e1af85863711fc73e419b9472c0a45004747e392a1223d437.jpg) □ ○ □ = □(个)", + "options": [], + "answer": "5+8=13", + "solution": "【分析】左边有5只兔子,右边房子里有8只,求一共有多少只,用加法计算,即左边的数量+右边的数量 = 总数量.\n【详解】 5 + 8 =13 (只)一共有 13 只兔子。", + "knowledge_points": [ + "5 ∼ 2 加几的进位加法", + "图文问题" + ], + "source": "25-26 一年级上·全国·课后作业" + }, + { + "id": "459", + "unit": " 第五单元20以内的进位加法", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式计算。 ![](images/7da465933d82dc4b5c529640de2e4de56713a405d25b0ff7417155ce88b6cfd5.jpg) □ ○ □ = □(个)", + "options": [], + "answer": "7+4=11", + "solution": "【分析】左边有7个足球,右边有4个足球,求一共有多少个足球,用加法计算,即左边的数量+右边的数量 = 总数量.\n【详解】 7 + 4 =11 (个) 一共有11个足球。", + "knowledge_points": [ + "图文问题", + "7,6 加几的进位加法" + ], + "source": "25-26 一年级上·全国·课后作业" + }, + { + "id": "460", + "unit": " 第五单元20以内的进位加法", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式计算。 ![](images/4a7da8f5247499692c1a5abbb119e145b71a9a0d8b3d0be1bbcc940ec8140033.jpg) □ ○ □ = □(个)", + "options": [], + "answer": "7+4=11", + "solution": "【分析】由图可知,左边有 7 个,右边有 4 个,求一共有多 少个。用加法列式计算.\n【详解】 7 + 4 =11 (个)或 4 + 7 =11 (个)一共有11个。", + "knowledge_points": [ + "图文问题", + "7,6 加几的进位加法" + ], + "source": "24-25 一年级上·辽宁抚顺·期中" + }, + { + "id": "461", + "unit": " 第五单元20以内的进位加法", + "question_type": "计算题", + "difficulty": 0.94, + "question": "看图列式计算。 ![](images/38fd21e69a8ca2d0dcd1d9b39b698c73a93b2872d6dd8048b100cf7e8252d11e.jpg) □ ○ □ = □(个)", + "options": [], + "answer": "8+5=13", + "solution": "【分析】根据题图数一数可知,左边有8个苹果,右边有5个苹果,求一共有多少个苹果,用加法计算;左边苹果的个数+右边苹果的个数 = 苹果的总个数.\n【详解】 8 + 5 =13 (个)因此,一共有13个苹果。", + "knowledge_points": [ + "8 加几的进位加法", + "图文问题" + ], + "source": "2025 一年级上·全国·专题练习" + }, + { + "id": "462", + "unit": " 第五单元20以内的进位加法", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式计算。 ![](images/2e4eae5751a8446ece4d4abf03d28c07200fe1498904401c6423132adcdff8e5.jpg) □ ○ □ = □(个)", + "options": [], + "answer": "8+7=15", + "solution": "【分析】一共的南瓜数量 = 左边的数量+右边的数量;据此列式解决.\n【详解】 8 + 7 =15 (个)一共有 15 个南瓜。", + "knowledge_points": [ + "8 加几的进位加法", + "图文问题" + ], + "source": "25-26一年级上·全国·单元测试" + }, + { + "id": "463", + "unit": " 第五单元20以内的进位加法", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式计算。 ![](images/83c24be498389c6a0a6e4e320ae5c6208e9a860553962c82a3f2c896e88b5fd0.jpg) □ ○ □ = □(个)", + "options": [], + "answer": "6+8=14", + "solution": "【分析】由题意可知:左边有6个梨,右边有8个梨,求一共有多少个梨,把左边梨的个数加上右边的即可;据此解答.\n【详解】由分析可得: 6 + 8 = 14 (个) 一共有14个梨。", + "knowledge_points": [ + "图文问题", + "7,6加几的进位加法" + ], + "source": "25-26 一年级上·全国·单元测试" + }, + { + "id": "464", + "unit": " 第五单元20以内的进位加法", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式计算。 ![](images/286ddc7e6562d6d77b721b978ab3e492120d8ea49de14f510957a62a52f565f4.jpg) □ ○ □ = □(个)", + "options": [], + "answer": "9+3 =12", + "solution": "【分析】左边有9颗草莓,右边有3颗草莓,求一共有多少颗草莓,用加法计算,即左边的数量+右边的数量 = 总数量.\n【详解】 9 + 3 =12 (颗)一共有12颗草莓。", + "knowledge_points": [ + "图文问题", + "9 加几的进位加法" + ], + "source": "25-26 一年级上·全国·课后作业" + }, + { + "id": "465", + "unit": " 第五单元20以内的进位加法", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式计算。 ![](images/ee4c45bdc3159bca1edb3196907c899f2fed52319f85951f1bc469d6b117ac53.jpg) □ ○ □ = □(块)", + "options": [], + "answer": "9+5=14", + "solution": "【分析】左边有9块橡皮,右边有5块橡皮,求一共有多少块橡皮,用加法计算,即左边的数量+右边的数量 = 总数量.\n【详解】 9 + 5 =14 (块)一共有 14 块橡皮。", + "knowledge_points": [ + "图文问题", + "9加几的进位加法" + ], + "source": "25-26 一年级上·全国·课后作业" + }, + { + "id": "466", + "unit": " 第五单元20以内的进位加法", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式计算。 ![](images/2980260ec18bf16ef8b938789b9c5578cf7b81be83613635d016b8ca41524f8d.jpg) □ ○ □ = □(根)", + "options": [], + "answer": "9+3=12", + "solution": "【分析】观察图可知,篮子里有9根胡萝卜,篮子外还有3根,求一共有多少根;篮子里胡萝卜的根数+篮子外胡萝卜的根数 = 胡萝卜的总根数.\n【详解】 9 + 3 =12 (根)或 3 + 9 =12 (根)因此,一共有12根胡萝卜。", + "knowledge_points": [ + "图文问题", + "9 加几的进位加法" + ], + "source": "25-26 一年级上·全国·单元测试" + }, + { + "id": "467", + "unit": " 第五单元20以内的进位加法", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式计算。 ![](images/453801fcbf58810eb570580235328e919483c5b72d896616875b43f6c5f3d877.jpg) □ ○ □ = □(根)", + "options": [], + "answer": "9 + 3 =12", + "solution": "【分析】根据题图可知,筐子里萝卜的数量加上筐子外边萝卜的数量,等于一共有多少根萝卜,据此解答.\n【详解】根据分析可得:9 + 3 =12 (根) 因此,一共有12根萝卜。", + "knowledge_points": [ + "图文问题", + "9加几的进位加法" + ], + "source": "24-25 一年级下·广东揭阳·期中" + }, + { + "id": "468", + "unit": " 第五单元20以内的进位加法", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式计算。 ![](images/098b1dc57acd2189b34174459a79fc89ec4bf54e5149afd43a38fe658b3121dc.jpg) □ ○ □ = □(个)", + "options": [], + "answer": "2 + 11 = 13", + "solution": "【分析】左右两边的数量相加即可求出一共有多少个.\n【详解】 2 + 11 = 13 (个)一共有13个。", + "knowledge_points": [ + "不进位加法(20以内)", + "图文问题" + ], + "source": "24-25 一年级下·云南玉溪·期中" + }, + { + "id": "469", + "unit": " 第五单元20以内的进位加法", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式子。 ![](images/0e56a8f8e5e027b8cd936f83845bf25d07a4654d8588bcd97dff809077f678f3.jpg) □ ○ □ = □(条)", + "options": [], + "answer": "6 + 5 =11", + "solution": "【分析】左边有6条鱼,右边有5条鱼,求一共有多少条鱼,用加法计算,即左边的数量+右边的数量 = 总数量.\n【详解】 6 + 5 =11 (条)一共有11条鱼。", + "knowledge_points": [ + "7,6加几的进位加法" + ], + "source": "24-25 一年级下·河南许昌·期中" + }, + { + "id": "470", + "unit": " 第五单元20以内的进位加法", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式计算。 ![](images/81b40ebf6a73190a7f2d481071253bcfd3e7ece1a02d0d2be5bb20c14af861c4.jpg) □ ○ □ = □(个)", + "options": [], + "answer": "7+6 =13(个)", + "solution": "【分析】左边筐里有 7 个萝卜,右边有 6 个萝卜,求一共有多少个萝卜,用加法计算,即左边的数量+右边的数量=总数量.\n【详解】 7 + 6 =13 (个)一共有 13 个萝卜。", + "knowledge_points": [ + "图文问题", + "7,6 加几的进位加法" + ], + "source": "24-25一年级下·江西赣州·期中" + }, + { + "id": "471", + "unit": " 第五单元20以内的进位加法", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式计算。 ![](images/93f1805e159963a5df5234ca7cf758e12b622c873b3eaac93889338f0e3f2303.jpg) □ ○ □ = □(本)", + "options": [], + "answer": "9+6 =15", + "solution": "【分析】左边有9本书,右边有6本书,求一共有多少本,用加法计算,即左边的数量+右边的数量 = 总数量.\n【详解】 9 + 6 =15 (本)一共有 15 本。", + "knowledge_points": [ + "图文问题", + "9加几的进位加法" + ], + "source": "24-25 一年级下·山东济宁·期中" + }, + { + "id": "472", + "unit": " 第五单元20以内的进位加法", + "question_type": "计算题", + "difficulty": 0.85, + "question": "列算式。 ![](images/9bb4eeb701d2a5c0c2e693589d10a1313b68172e983f677d3103683c01b3bea5.jpg) □ ○ □ = □(支)", + "options": [], + "answer": "9+4 =13", + "solution": "【分析】根据图片可知:求一共的数量,用左边的数量加右边的数量即可.\n【详解】 9 + 4 =13 (支)则一共 13 支。", + "knowledge_points": [ + "9 加几的进位加法" + ], + "source": "24-25 一年级上·福建龙岩·期末" + }, + { + "id": "473", + "unit": " 第五单元20以内的进位加法", + "question_type": "计算题", + "difficulty": 0.65, + "question": "我会看图列式计算。 ![](images/8f5abf0e3b90a7a50448232e5714016010f0b2a19ea8000996c807275f30c625.jpg) □ ○ □ = □(根)", + "options": [], + "answer": "7+4=11", + "solution": "【分析】左边有7根胡萝卜,右边有4根,求一共有多少根,用加法计算,即左边的数量+右边的数量 = 总数量.\n【详解】 7 + 4 =11 (根)一共有11根胡萝卜。", + "knowledge_points": [ + "图文问题", + "7,6加几的进位加法" + ], + "source": "24-25 一年级上·湖南益阳·期末" + }, + { + "id": "474", + "unit": " 第五单元20以内的进位加法", + "question_type": "计算题", + "difficulty": 0.85, + "question": "直接写出得数。 7 - 7 = 10 + 6 = 14 - 3 = 19 - 9 + 7 = 15 + 3 = 5 + 9 = 8 + 8 = 6 + 8 - 3 =", + "options": [], + "answer": "0;16;11;17;18;14;16;11", + "solution": "【分析】本题考查20以内的加减法计算,涉及0的减法,10加几,不进位加法,不退位减法,进位加法以及加减混合运算。计算时需根据数字特点选择合适的方法:相同数相减得0;10加几直接得十几;不进位加法个位相加,十位不变;不退位减法个位相减,十位不变;进位加法用凑十法;加减混合按从左到右顺序计算.\n【详解】第一行计算:① 7 - 7 = 0相同的两个数相减,差为0。② 10 + 6 =1610加几就是十几,1个十和6个一合起来是16。③ 14 - 3 = 11 不退位减法:个位4 - 3 = 1,十位是1,结果为11。 ④ 19 - 9 + 7 = 17 加减混合,从左到右计算:先算 19 - 9 = 10(个位相同数相减得0)再算 10 + 7 = 17 第二行计算:⑤ 15 + 3 = 18 不进位加法:个位5 + 3 = 8,十位是1,结果为18。⑥ 5 + 9 = 14 进位加法,用凑十法:把5分成4和1,先算1 + 9 = 10,再算10 + 4 = 14。⑦ 8 + 8 = 16进位加法,用凑十法:把8分成6和2,先算2 + 8 = 10,再算10 + 6 = 16。⑧ 6 + 8 - 3 = 11 加减混合,从左到右计算:先算 6 + 8 = 14(凑十法:6分成4和2,2 + 8 = 10,10 + 4 = 14)再算 14 - 3 = 11。", + "knowledge_points": [ + "5 ∼ 2 加几的进位加法", + "不进位加法(20 以内)", + "不退位减法(20以内)", + "8加几的进位加法" + ], + "source": "24-25一年级上·河南周口·期末" + }, + { + "id": "475", + "unit": " 第五单元20以内的进位加法", + "question_type": "解答题", + "difficulty": 0.94, + "question": "小猴看到一辆观光列车(如下图),想数一数它有多少个轮子。小猴一个一个地数,一共数了 8 个轮子。小朋友,小猴数得对吗。 ![](images/15932c23d9916043c285069e330b5bbb8fc568c95a36eb5ff47f11d4cd30d151.jpg)", + "options": [], + "answer": "不对", + "solution": "【分析】小猴数得不对,它只看到了观光列车的一边,列车另一边的轮子虽然不能直接看到,但它的轮子个数和这边的同样多,也是8个,将两边的轮子数相加,即可求出这辆观光列车一共有多少个轮子.\n【详解】 8 + 8 =16 (个)答:小猴数得不对,这辆观光列车一共有16个轮子。", + "knowledge_points": [ + "8 加几的进位加法", + "图文问题", + "数一数" + ], + "source": "25-26 一年级上·全国·周测" + }, + { + "id": "476", + "unit": " 第五单元20以内的进位加法", + "question_type": "解答题", + "difficulty": 0.94, + "question": "学校举行登山活动,2 名体育老师带领6名男生和7名女生一起登山。参加登山的一共有多少人。", + "options": [], + "answer": "15人", + "solution": "【分析】体育老师有 2 人;男生有 6 人;女生有 7 人,把体育老师,男生,女生的人数相加,即可求出参加登山的一共有多少人.\n【详解】2+6+7 = 8 + 7 = 15 (人) 答:参加登山的一共有15人。", + "knowledge_points": [ + "连加(20 以内)", + "7,6 加几的进位加法" + ], + "source": "25-26 一年级上·全国·周测" + }, + { + "id": "477", + "unit": " 第五单元20以内的进位加法", + "question_type": "解答题", + "difficulty": 0.65, + "question": "小朋友吃饭,每人一个饭碗,两人一个菜碗,三人一个汤碗,一共需要11个碗,你知道有多少个小朋友吃饭吗。", + "options": [], + "answer": "6个", + "solution": "【分析】根据题意可知:每人一个饭碗,两人一个菜碗,三人一个汤碗,则人数为3,6,9,当有3个人时,两人1菜碗,则有一个人没有菜碗,当有 6 个人时,则有 6 个饭碗,两人一个菜碗时,则有3个菜碗,三人一个汤碗,则有2个汤碗,此时用饭碗的数量加菜碗的数量再加汤碗的数量求证是否是11个碗.\n【详解】由分析可得:当有6人时:饭碗:6个,菜碗:3个,汤碗:2个。总碗数:6 + 3 + 2=9 + 2=11(个)答:有 6 个小朋友吃饭。", + "knowledge_points": [ + "连加(20以内)", + "9加几的进位加法" + ], + "source": "25-26 一年级上·全国·课后作业" + }, + { + "id": "478", + "unit": " 第五单元20以内的进位加法", + "question_type": "解答题", + "difficulty": 0.65, + "question": "妈妈去超市买梨,买回来的梨不超过10个,如果两个两个地数少一个,如果三个三个的数也少一个,请你猜一猜妈妈买了几个梨。", + "options": [], + "answer": "5 个", + "solution": "【分析】根据题意,梨的总数量不超过10个,则用每次数 的数量相加,再减去少的数量,计算出总数量,再选择两 种数法总数量相同,且数量不超过10个的即可.\n【详解】由分析得:2 - 1 = 1 (个) 3 - 1 = 2 (个); 2 + 2 - 1 = 3 (个); 3 + 3 - 1 = 5 (个);2 + 2 + 2 - 1 = 5 (个);3 + 3 + 3 - 1 = 8 (个);2 + 2 + 2 + 2 - 1 = 7 (个);3 + 3 + 3 + 3 - 1 = 11 (个)。总数量不超过 10 个,且两种数法总数量相同的是 5 个。答:妈妈买了 5 个梨。", + "knowledge_points": [ + "加减混合运算(10 以内)", + "加减混合运算(20以内)" + ], + "source": "25-26 一年级上·全国·课后作业" + }, + { + "id": "479", + "unit": " 第五单元20以内的进位加法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "妈妈买来 15 个桃子,欢欢和乐乐各吃了6个,他俩一共吃了多少个桃子。", + "options": [], + "answer": "6 + 6 =12", + "solution": "【分析】根据题意,欢欢和乐乐都吃了6个桃子,则欢欢吃桃子的数量+乐乐吃桃子的数量 = 他俩一共吃桃子的数量.\n【详解】 6 + 6 =12 (个)答:他俩一共吃了 12 个桃子。", + "knowledge_points": [ + "7,6加几的进位加法" + ], + "source": "2025 一年级上·全国·专题练习" + }, + { + "id": "480", + "unit": " 第五单元20以内的进位加法", + "question_type": "解答题", + "difficulty": 0.65, + "question": "小红想搭图一 小明想搭图二,一共要用到几个 正方体。![](images\\46513ae32b2d6596c398231f5012f32f.jpg)", + "options": [], + "answer": "5+7 =12;12 个", + "solution": "【分析】由题可知,小红搭图一搭要用7个,则将他们要用 正方体的数量相加,即可计算出一共要用的数量.\n【详解】 5 + 7 =12 (个)答:一共要用到12个 。", + "knowledge_points": [ + "5 ∼ 2 加几的进位加法" + ], + "source": "2025 一年级上·全国·专题练习" + }, + { + "id": "481", + "unit": " 第五单元20以内的进位加法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "妈妈买了 8 个梨,又买了 7 个苹果,妈妈一共买了多少个水果。", + "options": [], + "answer": "15 个", + "solution": "【分析】根据加法的意义,妈妈买来梨的数量+又买来苹果的数量 = 买来水果的总数量.\n【详解】 8 + 7 =15 (个)答:妈妈一共买了15个水果。", + "knowledge_points": [ + "8加几的进位加法" + ], + "source": "25-26 一年级上·广东深圳·月考" + }, + { + "id": "482", + "unit": " 第五单元20以内的进位加法", + "question_type": "解答题", + "difficulty": 0.94, + "question": "佩奇和 2 个好朋友去植物园玩,门票6元一张,买门票要花多少钱。", + "options": [], + "answer": "18元", + "solution": "【分析】佩奇和2个好朋友一共3个人,所以需要买3张门票,根据加法的意义,用 6 + 6 + 6 进行解答即可.\n【详解】 6 + 6 + 6= 12 + 6 = 18 (元) 答:买门票要花 18 元钱。", + "knowledge_points": [ + "连加(20以内)" + ], + "source": "24-25 一年级下·江西赣州·期末" + }, + { + "id": "483", + "unit": " 第五单元20以内的进位加法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "希望小学一(1)班的小朋友排队放学,小军的前面有 8 个小朋友,后面有 6 个小朋友,这队一共有多少个小朋友。", + "options": [], + "answer": "15 个", + "solution": "【分析】根据加法的意义,小军前面的人数+小军自己+小军后面的人数 = 这队的总人数.\n【详解】 8 + 1 + 6 = 15 (个)答:这队一共有15个小朋友。", + "knowledge_points": [ + "排队问题", + "连加(20以内)" + ], + "source": "25-26 一年级上·全国·课后作业" + }, + { + "id": "484", + "unit": " 第五单元20以内的进位加法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "妈妈买了18 个橘子,第一天吃了 6 个,第二天吃了 7 个,两天一共吃了多少个橘子。", + "options": [], + "answer": "13 个", + "solution": "【分析】由题意可知:把第一天和第二天吃的橘子数相加,即是两天一共吃的橘子数;据此解答.\n【详解】由分析可得:6 + 7 = 13 (个) 答:两天一共吃了13个橘子。", + "knowledge_points": [ + "含有多余条件的实际问题", + "7,6 加几的进位加法" + ], + "source": "25-26 二年级上·黑龙江佳木斯·开学考试" + }, + { + "id": "485", + "unit": " 第五单元20以内的进位加法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "停车场原来有9辆车,又开来了5辆,现在停车场有多少辆车。", + "options": [], + "answer": "14 辆", + "solution": "【分析】根据加法的意义,停车场原有车的数量+又开来 的数量 = 现在的数量.\n【详解】 9 + 5 =14 (辆) 答:现在停车场有 14 辆车。", + "knowledge_points": [ + "9 加几的进位加法" + ], + "source": "25-26 二年级上·黑龙江佳木斯·开学考试" + }, + { + "id": "486", + "unit": " 第五单元20以内的进位加法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "同学们参加合唱比赛,站成两排,一排有 6 人,另一排有 5 人。一共有多少人参加合唱比赛。", + "options": [], + "answer": "11 人", + "solution": "【分析】用一排有的人数加上另一排有的人数,即可求出共有多少人参加合唱比赛.\n【详解】 6 + 5 =11 (人)答:一共有11人参加合唱比赛。", + "knowledge_points": [ + "7,6加几的进位加法" + ], + "source": "25-26 二年级上·全国·单元测试" + }, + { + "id": "487", + "unit": " 第五单元20以内的进位加法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "子强今年 5 岁,姐姐说:\"你的年龄加上一岁,正好是我年龄的一半.\"姐姐今年几岁。", + "options": [], + "answer": "12 岁", + "solution": "【分析】根据题意可知:先求出姐姐年龄的一半是多少,用子强的年龄加1即可。然后用一半的年龄再加一半即可求出姐姐的年龄。(把一个数分成相等两部分,拿其中一部分,则为一半。)\n【详解】 5 + 1 =6 (岁) 6 + 6 = 12 (岁) 答:姐姐今年12岁。", + "knowledge_points": [ + "5 以内数的分与合(组成)", + "7,6 加几的进位加法" + ], + "source": "25-26 一年级上·全国·课后作业" + }, + { + "id": "488", + "unit": " 第五单元20以内的进位加法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "小明和小兰今年都上一年级,小明今年 6 岁,小兰今年 7 岁。2 年后,小明和小兰一共多少岁。", + "options": [], + "answer": "17 岁", + "solution": "【分析】先求出 2 年后,小明和小兰分别是几岁,再用 2 年后小明的年龄加上 2 年后小兰的年龄,即可求出 2 年后,小明和小兰一共多少岁.\n【详解】 6 + 2 =8 (岁) 7 + 2 =9 (岁) 8 + 9 =17 (岁) 答:2年后,小明和小兰一共17岁。", + "knowledge_points": [ + "8 加几的进位加法", + "8,9 的加减法" + ], + "source": "25-26 一年级上·全国·课后作业" + }, + { + "id": "489", + "unit": " 第五单元20以内的进位加法", + "question_type": "解答题", + "difficulty": 0.65, + "question": "8名男同学进行排队,站成一排。如果隔 2 名男同学插入 3 名女同学,现在这一排一共有多少名同学。", + "options": [], + "answer": "17 名", + "solution": "【分析】根据题意,可以画图来解答问题。 ○ 表示男同学,☆表示女同学。有8名男同学,隔2名插入3名女同学,则男同学之间会有3个间隔,则女同学的人数也就是3个3相加,再和男同学的人数相加,就是总人数.\n○○ ○○ ○○ ○○☆☆☆ ☆☆☆ ☆☆☆\n【详解】由分析得:女同学: 3 + 3 + 3 = 9 (名)总人数: 8 + 9 =17 (名)答:现在这一排一共有17名同学。", + "knowledge_points": [ + "8 加几的进位加法", + "连加", + "连减(10 以内)" + ], + "source": "25-26一年级上·全国·课后作业" + }, + { + "id": "490", + "unit": " 第五单元20以内的进位加法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "有一个圆形花坛,沿着花坛放了 9 盆月季花,每两盆月季花中间放了一盆菊花,这个花坛周围有多少盆花。", + "options": [], + "answer": "18 盆", + "solution": "【分析】已知,花坛是圆形的,因此花的排列呈圆形,因为圆形排列,首尾是相接的,所以9盆月季花中间有9个间隙,可以放 9 盆菊花,相加即可得出一共多少盆花.\n【详解】 9 + 9 = 18 (盆)答:这个花坛周围有 18 盆花。", + "knowledge_points": [ + "9 加几的进位加法" + ], + "source": "25-26 一年级上·全国·课后作业" + }, + { + "id": "491", + "unit": " 第五单元20以内的进位加法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "妈妈买了一些 苹果,吃了 7 个,还剩 8 个,妈妈原来买了多少个苹果。", + "options": [], + "answer": "15 个", + "solution": "【分析】要求妈妈原来买了多少个苹果,根据加法的意义,将吃了的苹果数量和剩下的苹果数量相加,用7+8进行解\n答即可.\n【详解】 7 + 8 =15​ (个)答:妈妈原来买了 15 个苹果。", + "knowledge_points": [ + "7,6加几的进位加法" + ], + "source": "24-25一年级下·黑龙江佳木斯·期末" + }, + { + "id": "492", + "unit": " 第五单元20以内的进位加法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "某学校组织学生春游,一(2)班有 9 名女生报名参加,男生报名的人数与女生同样多,一(2)有多少名同学参加春游。□ ○ □ = □(名)", + "options": [], + "answer": "9 + 9 = 18", + "solution": "【分析】一(2)班有9名女生报名参加,男生报名的人数与女生同样多,也就是男生也有9名报名,求一(2)有多少名同学参加春游,就是求男生与女生的人数和,用加法列式解决.\n【详解】 9 + 9 = 18 (名)答:一(2)有 18 名同学参加春游。", + "knowledge_points": [ + "9加几的进位加法" + ], + "source": "24-25一年级下·湖南衡阳·期中" + }, + { + "id": "493", + "unit": " 第五单元20以内的进位加法", + "question_type": "解答题", + "difficulty": 0.65, + "question": "大家排队玩游戏,小明前面有 5 人,后面有 6 人,一共有多少人在排队。□ ○ □ = □(人)", + "options": [], + "answer": "5 + 6 + 1 = 12", + "solution": "【分析】用小明前面的人数加小明后面的人数再加小明自己即可求出一共有多少人在排队.\n【详解】 5 + 6 + 1 = 12 (人)答:一共有12人在排队。", + "knowledge_points": [ + "连加(20以内)", + "前,后位置" + ], + "source": "24-25 一年级下·贵州黔西·期中" + }, + { + "id": "494", + "unit": " 第五单元20以内的进位加法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "图书馆一共有35本书,第一天借走5本,第二天借走7本,这两天一共借走多少本书。", + "options": [], + "answer": "12本", + "solution": "【分析】根据加法的意义,第一天借走的数量+第二天借走的数量 = 两天一共借走的数量,与书的总数量无关.\n【详解】 5 + 7 =12 (本)答:这两天一共借走12本书。", + "knowledge_points": [ + "5 ∼ 2 加几的进位加法" + ], + "source": "24-25一年级下·安徽芜湖·期中" + }, + { + "id": "495", + "unit": " 第五单元20以内的进位加法", + "question_type": "解答题", + "difficulty": 0.65, + "question": "一共有多少支笔。 ![](images/baa38d1c925c4d77c62d7389e5e149684fc29b1891dbfcb79d6d9a46e53cdc28.jpg) □ ○ □ = □(支)", + "options": [], + "answer": "4+9=13", + "solution": "【分析】已知左边有4支笔,右边有9支笔,要求一共有多少支笔,根据加法的意义,用 4+9 进行解答即可.\n【详解】 4 + 9 =13 (支)答:一共有 13 支笔。", + "knowledge_points": [ + "5 ∼ 2 加几的进位加法", + "图文问题", + "9 加几的进位加法" + ], + "source": "24-25一年级下·广东韶关·期中" + }, + { + "id": "496", + "unit": " 第五单元20以内的进位加法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "妈妈买回一些苹果,全家吃了3天,共吃了9个,还剩5个苹果,妈妈买了几个 苹果。□ ○ □ = □(个)", + "options": [], + "answer": "9+5=14", + "solution": "【分析】根据加法的意义,吃了苹果的数量+还剩苹果的数量 = 妈妈买回苹果的总数量.\n【详解】 9 + 5 =14 (个)答:妈妈买了14个苹果。", + "knowledge_points": [ + "9加几的进位加法" + ], + "source": "24-25一年级下·福建福州·期中" + }, + { + "id": "497", + "unit": " 第五单元20以内的进位加法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "妈妈给小明买了一些蛋糕,他吃了 9 块,还剩 3 块,妈妈原来给小明买了多少 块蛋糕。□ ○ □ = □(块)", + "options": [], + "answer": "9+3=12", + "solution": "【分析】用小明吃了的块数加还剩的块数即可求出妈妈原来给小明买了多少块蛋糕.\n【详解】 9 + 3 =12 (块)答:妈妈原来给小明买了12块蛋糕。", + "knowledge_points": [ + "5 ∼ 2 加几的进位加法", + "9 加几的进位加法" + ], + "source": "24-25一年级上·山东临沂·期末" + }, + { + "id": "498", + "unit": " 第五单元20以内的进位加法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "小兔子拔萝卜,已经拔了7根萝卜,还剩下8根没有拔,原来有多少根萝卜。□ ○ □ = □(根)", + "options": [], + "answer": "7+8=15", + "solution": "【分析】用已经拔的根数加还没有拔的根数即可求出原来有多少根萝卜.\n【详解】 7 + 8 =15 (根)答:原来有15根萝卜。", + "knowledge_points": [ + "8 加几的进位加法", + "7,6 加几的进位加法" + ], + "source": "24-25 一年级上·河南周口·期末" + }, + { + "id": "499", + "unit": " 第五单元20以内的进位加法", + "question_type": "解答题", + "difficulty": 0.65, + "question": "同学们排队检查视力,笑笑前边有5人,后面有6人,一共有多少人排队检查视力。□ ○ □○ □ = □(名)", + "options": [], + "answer": "5+6+1=12", + "solution": "【分析】用笑笑前面的人数加后面的人数再加笑笑即可求出一共有多少人排队检查视力.\n【详解】 5 + 6 + 1 = 12 (人)答:一共有 12 人排队检查视力。", + "knowledge_points": [ + "连加(20以内)", + "前,后位置" + ], + "source": "24-25 一年级上·河南周口·期末" + }, + { + "id": "500", + "unit": " 第五单元20以内的进位加法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "树上原来有 17 只小鸟,先飞走了 10 只,后又有 5 只小鸟飞来这棵树上,现在这棵树上有多少只小鸟。□ ○ □○ □ = □ (只)", + "options": [], + "answer": "17-10+5 = 12", + "solution": "【分析】根据题意可知,树上原来小鸟的数量减去飞走的数量,再加上飞来的数量,等于现在这棵树上小鸟的数量,据此解答.\n【详解】根据分析可得:17 - 10 + 5 = 12 (只) 答:现在这棵树上有 12 只小鸟。", + "knowledge_points": [ + "加减混合运算(20 以内)" + ], + "source": "24-25 一年级上·广西玉林·期末" + } +] diff --git "a/\344\270\200\345\271\264\347\272\247\351\242\230\351\233\206/\344\270\200\345\271\264\347\272\247\344\270\212/\344\270\200\345\271\264\347\272\247\344\270\212\347\254\254\345\233\233\345\215\225\345\205\20311~20\347\232\204\302\267\350\256\244\350\257\206.json" "b/\344\270\200\345\271\264\347\272\247\351\242\230\351\233\206/\344\270\200\345\271\264\347\272\247\344\270\212/\344\270\200\345\271\264\347\272\247\344\270\212\347\254\254\345\233\233\345\215\225\345\205\20311~20\347\232\204\302\267\350\256\244\350\257\206.json" new file mode 100644 index 0000000000000000000000000000000000000000..f5a432c37aabbf04439e140baaf79ce866056c15 --- /dev/null +++ "b/\344\270\200\345\271\264\347\272\247\351\242\230\351\233\206/\344\270\200\345\271\264\347\272\247\344\270\212/\344\270\200\345\271\264\347\272\247\344\270\212\347\254\254\345\233\233\345\215\225\345\205\20311~20\347\232\204\302\267\350\256\244\350\257\206.json" @@ -0,0 +1,8573 @@ +[ + { + "id": "1", + "unit": "第二单元 11~20的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.65, + "question": "小娟,小云,小龙是好朋友,他们三人一起折星星,分别折了 15 颗,17 颗,20 颗。小娟说:\"我折的不是最少的.\" 小云说:\"我折的比小娟多.\" 小龙折了 ( ) 颗。", + "options": [ + "A. 20", + "B. 17", + "C. 15" + ], + "answer": "C", + "solution": "【分析】根据题目给出的信息可知,小娟折的星星不是最少的,则小娟不是最后一名,小云折的比小娟多,则小云是第一名,由此可知小龙应该是第三名。将折的星星数量由小到大进行排序,找出排在第三的星星数量,即可解答.\n【详解】15颗 \u003c 17颗 \u003c 20颗,排在第三的是 15 颗,则小龙折了 15 颗。故答案为: C", + "knowledge_points": [ + "20以内数的比大小" + ], + "source": "24-25 二年级下·江西赣州·期末" + }, + { + "id": "2", + "unit": "第二单元 11~20的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.65, + "question": "从13里减去( )个一得10。", + "options": [ + "A. 1", + "B. 3", + "C. 10" + ], + "answer": "B", + "solution": "【分析】用 \"13 - 10\" 算出的答案,答案是几就代表从 13 里减去几个一可以得到 10,由此进行解答即可.\n【详解】13 - 10 = 3,所以,从 13 里减去 3 个一得 10 。故答案为: B", + "knowledge_points": [ + "不退位减法 (20以内)" + ], + "source": "24-25 一年级下·河北张家口·期末" + }, + { + "id": "3", + "unit": "第二单元 11~20的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "在计数器上拨出数字 12,需要用到 ( ) 颗珠子。", + "options": [ + "A. 2", + "B. 3", + "C. 12" + ], + "answer": "B", + "solution": "【分析】在计数器上拨数字时,十位上的一个珠子表示 10,个位上的一个珠子表示 1。数字 12 由 1 个十和 2 个一组成,因此需要 1(十位)+ 2(个位)=3 颗珠子.\n【详解】由分析可知:数字 12 的十位是 1,需用 1 颗珠子;个位是 2,需用 2 颗珠子。总珠子数为 1 + 2 = 3 (颗);故答案为: B", + "knowledge_points": [ + "20以内数的组成" + ], + "source": "24-25 一年级下·河南三门峡·期末" + }, + { + "id": "4", + "unit": "第二单元 11~20的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "比 12 多 3 的数是 ( )。", + "options": [ + "A. 8", + "B. 9", + "C. 15", + "D. 16" + ], + "answer": "C", + "solution": "【分析】要求比 12 多 3 的数是多少,根据加法的意义,用 12 + 3 进行解答即可.\n【详解】12 + 3 = 15,所以比12多3的数是 15。故答案为: C", + "knowledge_points": [ + "不进位加法(20以内)" + ], + "source": "24-25 一年级下·广东湛江·期末" + }, + { + "id": "5", + "unit": "第二单元 11~20的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "一个数,个位上是 5,十位上是1,这个数是()。", + "options": [ + "A. 51", + "B. 15", + "C. 10", + "D. 6" + ], + "answer": "B", + "solution": "【分析】从右边起第一位是个位,第二位是十位,据此结合题干要求,即可得出此数.\n【详解】个位上是 5,十位上是 1,这个数是 15 。故答案为: B", + "knowledge_points": [ + "20以内数的组成" + ], + "source": "24-25 一年级下·广东湛江·期末" + }, + { + "id": "6", + "unit": "第二单元 11~20的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "下图中 ○ 与 □ 的数量关系列成算式是 \" 15 - 4 = 11 \",其中 \"4\"表示 ( ).\n\n![](images/ccfb195c7b9c89c08390067247bdf4011d73a3c4fbfd7ce01a3d5a0933c46ff7.jpg)", + "options": [ + "A. □ 比 ○ 多的个数", + "B. ○ 比 □ 多的个数", + "C. □ 的个数" + ], + "answer": "B", + "solution": "【分析】减法算式可以表示已知一个数比另一个数多多少,求另一个数是几;由题可知,有 15 个 ○ , ○ 比 □ 多 4 个 (或 □ 比 ○ 少 4 个), 15 - 4 = 11 中的 11 表示 □ 的个数;由此解答.\n【详解】A。 有图可知, □ 比 ○ 少,原说法错误;B. 有图可知, ○ 比 □ 多 4 个,原说法正确;C. 15 - 4 = 11 中的 11 表示 □ 的个数,原说法错误。所以算式是 \"15 - 4 = 11\",其中 \"4\" 表示 ○比□)多的个数)。故答案为: B", + "knowledge_points": [ + "图文问题", + "不退位减法(20以内)", + "谁比谁多/少几的问题" + ], + "source": "24-25 一年级下·福建莆田·期末" + }, + { + "id": "7", + "unit": "第二单元 11~20的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "小明有 15 支铅笔,送给小红 5 支,还剩 ( ) 支。", + "options": [ + "A. 10", + "B. 20", + "C. 5" + ], + "answer": "A", + "solution": "【分析】用小明的铅笔支数减去他送给小红的铅笔支数,即可求出还剩多少支铅笔,据此选择即可.\n【详解】15 - 5 = 10 (支),还剩 10 支铅笔。故答案为: A", + "knowledge_points": [ + "不退位减法 (20 以内)" + ], + "source": "24-25 一年级下·黑龙江佳木斯·期中" + }, + { + "id": "8", + "unit": "第二单元 11~20的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "下面数中,比 14 大,比 18 小的数是 ( )。", + "options": [ + "A. 13", + "B. 15", + "C. 19" + ], + "answer": "B", + "solution": "【分析】两位数的比较大小,当十位上的数相同时,个位上大的数就大;据此解决此题.\n【详解】A。 13 \u003c 14;B. 14 \u003c 15 \u003c 18;C. 19 \u003e 18;即,这些数中,比 14 大比 18 小的数是 15。故答案为: B", + "knowledge_points": [ + "20以内数的比大小" + ], + "source": "24-25 一年级下·湖南株洲·期中" + }, + { + "id": "9", + "unit": "第二单元 11~20的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "一个两位数,十位上是 1,个位上的数比十位上的数大 2,这个数是 ( )。", + "options": [ + "A. 12", + "B. 13", + "C. 14" + ], + "answer": "B", + "solution": "【分析】一个两位数,从右往左数,第一位是个位,第二位是十位;先找出各位上的数字分别是多少,然后组数即可.\n【详解】1 + 2 = 3,也就是个位上是3;则,一个两位数,十位上是 1,个位上的数比十位上的数大 2,这个数是 13。故答案为: B", + "knowledge_points": [ + "20以内数的组成" + ], + "source": "24-25 一年级上·湖南株洲·期中" + }, + { + "id": "10", + "unit": "第二单元 11~20的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "儿童乐园有 18 个小朋友,有 10 人在玩抓迷藏,已经被找到的有 6 人,还有几人没被找到。正确的算式是()。", + "options": [ + "A. 18 - 6 - 1", + "B. 10 - 6", + "C. 10 - 1 - 6" + ], + "answer": "B", + "solution": "【分析】根据题意可知,儿童乐园有 18 个小朋友,这个条件是多余的,不参加计算;玩抓迷藏的总人数减去已经被找到的人数,等于还有几个人没有被找到,据此解答.\n【详解】A。18-6-1:根据分析18个小朋友是多余条件,不用参加计算,答案不正确;B. 10 - 6:玩抓迷藏的 10 人- 被抓到的 6 人 = 没被抓到的人数,答案正确;C. 10 - 1 - 6:题目中没有出现 1,算式中减去 1,答案不正确。故答案为: B", + "knowledge_points": [ + "连加,连减(10以内)", + "连减(20以内)", + "10的加减法" + ], + "source": "24-25 一年级下·福建莆田·期中" + }, + { + "id": "11", + "unit": "第二单元 11~20的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.94, + "question": "小明前面有 5 人,后面有 5 人,这个队伍一共有 ( ) 人。", + "options": [ + "A. 10", + "B. 9", + "C. 11" + ], + "answer": "C", + "solution": "【分析】根据题意可知,小明前面的人数加上后面的人数,再加上小明自己,等于这个队伍一共有多少人,据此解答.\n【详解】根据分析可得:5 + 5 + 1 = 11(人),因此,这个队伍一共有 11 人。故答案为: C", + "knowledge_points": [ + "连加(20以内)", + "排队问题" + ], + "source": "24-25 一年级下·广东江门·期中" + }, + { + "id": "12", + "unit": "第二单元 11~20的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "关于算式 15 - 3 = 12,下面说法错误的是 ( )。", + "options": [ + "A. 15 是加数", + "B. 3是减数", + "C. 12 是差" + ], + "answer": "A", + "solution": "【分析】减法算式为被减数 - 减数 = 差,加法算式为加数+加数 = 和,由此解答.\n【详解】A。15是被减数,原说法错误;B. 3是减数,原说法正确;C. 12 是差,原说法正确。则说法错误的是 15 是加数。故答案为:A", + "knowledge_points": [ + "不退位减法 (20 以内)" + ], + "source": "24-25 一年级上·河南周口·期末" + }, + { + "id": "13", + "unit": "第二单元 11~20的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "我是数字宝宝,我有两个好邻居,它们分别是 9 和 11,我是 ( )。", + "options": [ + "A. 8", + "B. 10", + "C. 12" + ], + "answer": "B", + "solution": "【分析】根据题意,数字宝宝的\"好邻居\"指的是它的前一个数和后一个数(即相邻数)。20以内数的排序为:1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,据此解答.\n【详解】根据分析可得:10 的两个相邻数正好是 9 和 11。故答案为: B", + "knowledge_points": [ + "20以内数的排序" + ], + "source": "24-25 一年级上·山东济南·期末" + }, + { + "id": "14", + "unit": "第二单元 11~20的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "1个十和 8 个一合起来是 ( )。", + "options": [ + "A. 9", + "B. 18", + "C. 8" + ], + "answer": "B", + "solution": "【分析】几个十就是几十,几个一就是几,然后合起来组数即可.\n【详解】1个十是10,8个一是8,合起来是 18故答案为: B", + "knowledge_points": [ + "20以内数的组成" + ], + "source": "24-25 一年级上·广西玉林·期末" + }, + { + "id": "15", + "unit": "第二单元 11~20的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "在 11 和 17 中间有 ( ) 个数。", + "options": [ + "A. 6", + "B. 7", + "C. 5" + ], + "answer": "C", + "solution": "【分析】根据题意,按照20以内数的顺序,从11数到17,数出它们之间数字的数量即可,不包含 11 和 17.\n【详解】从 11 数到 17 为:11,12,13,14,15,16,17,则在 11 和 17 中间有 5 个数。故答案为: C", + "knowledge_points": [ + "20以内数的排序" + ], + "source": "24-25 一年级上·广西玉林·期末" + }, + { + "id": "16", + "unit": "第二单元 11~20的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "一个数,十位上是 1,个位上是 0,这个数是 ( )。", + "options": [ + "A. 1", + "B. 10", + "C. 11" + ], + "answer": "B", + "solution": "【分析】一个两位数,从右往左依次是个位,十位;十位上的数表示几个十,个位上的数表示几个一;十位是 1,表示 1 个十(即 10);个位是 0,表示 0 个一,合起来是 10,据此解答.\n【详解】根据分析可得:一个数,十位上是 1,个位上是 0,这个数是 10。故答案为: B", + "knowledge_points": [ + "20以内数的组成" + ], + "source": "24-25 一年级上·广西玉林·期末" + }, + { + "id": "17", + "unit": "第二单元 11~20的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "1 个十和 6 个一组成的数是 ( )", + "options": [ + "A. 61", + "B. 7", + "C. 16" + ], + "answer": "C", + "solution": "【分析】几个十就是几十,几个一就是几,合起来就是几十几,由此解答.\n【详解】1个十是10,6个一是6,组成的数是 16 。故答案为:C", + "knowledge_points": [ + "20以内数的组成" + ], + "source": "24-25 一年级下·新疆喀什·开学考试" + }, + { + "id": "18", + "unit": "第二单元 11~20的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "比14大,比18小的数有()个。", + "options": [ + "A. 3", + "B. 4", + "C. 5" + ], + "answer": "A", + "solution": "【分析】数一数可知,比14大,比18小的数有15,16,17,共3个.\n【详解】比 14 大,比 18 小的数有 3 个。故答案为: A", + "knowledge_points": [ + "20以内数的比大小", + "20以内数的排序" + ], + "source": "24-25一年级上·湖南株洲·期末" + }, + { + "id": "19", + "unit": "第二单元 11~20的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "18 个位上的 \"8\" 表示 8 个 ( )。", + "options": [ + "A. 一", + "B. 十", + "C. 八" + ], + "answer": "A", + "solution": "【分析】一个两位数,从右往左依次为个位,十位,十位上的数表示几个十,个位上的数表示几个一.\n【详解】18个位上的\"8\"表示8个一。故答案为:A", + "knowledge_points": [ + "20以内数的组成" + ], + "source": "24-25 一年级上·河南周口·期末" + }, + { + "id": "20", + "unit": "第二单元 11~20的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "计算 14 - 3,下面三个小朋友的做法中,正确的有 ( ).\n明明:先算 4 - 3 = 1,再算 10 + 1 = 11 .\n红红:我倒着数3个数,13,12,11,所以 14 - 3 = 11 .\n兰兰:因为 4 - 3 = 1,可知 14 - 3 = 11 。", + "options": [ + "A. 明明和红红", + "B. 明明和兰兰", + "C. 三人都对" + ], + "answer": "C", + "solution": "【分析】计算 14 - 3 时,可将 14 分成 10 和 4,先计算出 4 减 3 的结果,再用这个结果和 10 相加即可;或者用倒着数数的方法,数到几结果就是几;或者先计算个位的 4 先减去 3 得几,十位的结果不变,则整体的结果就是十几.\n【详解】明明:将 14 分成了 10 和 4,先算 4 - 3 = 1,再算 10 + 1 = 11;方法正确;红红:倒着数3个数,13,12,11,所以 14 - 3 = 11,方法正确;兰兰: 4 - 3 = 1,十位还是 1,则整体的结果就是 14 - 3 = 11,方法正确。则三人的方法都对。故答案为: C", + "knowledge_points": [ + "不退位减法(20以内)" + ], + "source": "24-25 一年级下·河南周口·阶段练习" + }, + { + "id": "21", + "unit": "第二单元 11~20的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.65, + "question": "下面 ( ) 最接近 19。", + "options": [ + "A. 17", + "B. 1个十和6个一", + "C. 2个十" + ], + "answer": "C", + "solution": "【分析】1 到 20,从小到大排序:1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20。几个十就是几十,几个一就是几。中间间隔的数越少则越接近.\n【详解】A。间隔1个数。B。 表示 16,中间间隔 2 个数。 C. 表示 20,中间间隔 0 个数。0 \u003c 1 \u003c 2,2个十最接近19。故答案为: C", + "knowledge_points": [ + "20以内数的组成", + "20以内数的排序" + ], + "source": "24-25 一年级上·浙江温州·期末" + }, + { + "id": "22", + "unit": "第二单元 11~20的认识和加、减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "从 1 数到 20, 14 后面第 2 个数是 ( )。", + "options": [ + "A. 12", + "B. 15", + "C. 16" + ], + "answer": "C", + "solution": "【分析】1 到 20,从小到大排序:1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20。据此数一数。求后面第几个数就数几下.\n【详解】从 1 数到 20, 14 后面第 2 个数是 16 。故答案为: C", + "knowledge_points": [ + "20以内数的排序" + ], + "source": "24-25 一年级下·广东揭阳·阶段练习" + }, + { + "id": "23", + "unit": "第二单元 11~20的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.65, + "question": "美术兴趣组的同学,昨天课间休息时有 8 名同学离开,一会儿, 5 名同学回到了组里,这时组里有 15 名同学。美术兴趣组有( )名同学。", + "options": [ + + ], + "answer": "18", + "solution": "【分析】本题可通过逆向推理解决;已知最后有 15 名同学,是在 5 名同学回来后的人数,因此回来前有 15 - 5 = 10(名) 同学;这 10 名同学是 8 名同学离开后剩下的,所以原来有 10 + 8 = 18 (名) 同学;据此可解.\n【详解】由分析可得:美术兴趣组的同学,昨天课间休息时有 8 名同学离开,一会儿, 5 名同学回到了组里,这时组里有 15 名同学。美术兴趣组有 18 名同学。", + "knowledge_points": [ + "不进位加法(20以内)", + "不退位减法(20以内)" + ], + "source": "24-25 一年级下·四川·期末" + }, + { + "id": "24", + "unit": "第二单元 11~20的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "按规律填数:3, 6, 9, 12, ( ), 18。", + "options": [ + + ], + "answer": "15", + "solution": "【分析】观察这组数可知,后一个数比前一个数大 3,遵循此规律进行计算并填空即可.\n【详解】 12 + 3 = 15,所以,这组数是3,6,9,12,15,18。", + "knowledge_points": [ + "整数排列的规律", + "不进位加法(20以内)" + ], + "source": "24-25 二年级下·黑龙江佳木斯·期末" + }, + { + "id": "25", + "unit": "第二单元 11~20的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.65, + "question": "小明有 18 颗糖,小红有 12 颗糖,小明给( )颗糖给小红,两人的糖就一样多。", + "options": [ + + ], + "answer": "3", + "solution": "【分析】根据题意,用 18 减去 12,求出小明比小红多的数量,然后再多的数量平均分成 2 份,其中一份给小红,这样两个人的糖果数量就相同.\n【详解】 18 - 12 = 6 (颗),6 平均分成两份,一份是 3 颗,此时小明和小红的糖果数量分别为:18 - 3 = 15 (颗);12 + 3 = 15 (颗),所以,小明有 18 颗糖,小红有 12 颗糖,小明给 3 颗糖给小红,两人的糖就一样多。", + "knowledge_points": [ + "不退位减法 (20以内)" + ], + "source": "24-25 一年级下·湖南长沙·期末" + }, + { + "id": "26", + "unit": "第二单元 11~20的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "按规律填数:1, 4, 7, 10, ( ), ( ), ( )。", + "options": [ + + ], + "answer": "13;16;19", + "solution": "【分析】这组数字依次变大。 4 - 1 = 3;7 - 4 = 3;10 - 7 = 3,也就是每后一个数比前一个数大 3,则前一个数 +3 = 后一个数.\n【详解】 10 + 3 = 13;13 + 3 = 16;16 + 3 = 19;按规律填数: 1, 4, 7, 10, 13, 16, 19。", + "knowledge_points": [ + "整数排列的规律", + "不进位加法(20以内)", + "10的加减法" + ], + "source": "24-25 二年级下·黑龙江佳木斯·期末" + }, + { + "id": "27", + "unit": "第二单元 11~20的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "一个一个地数,11后面第4个数是。( );11前面第4个数是( )。", + "options": [ + + ], + "answer": "15,7", + "solution": "【分析】一个一个的数,从 11 开始往后数,则往后数 4 个数,即 11,12,13,14,15,则 11 后面第 4 个数是 15。一个一个的数,从 11 开始往前数,往前数 4 个数,即11,10,9,8,7,则 11 前面第 4 个数是 7.\n【详解】由分析可得:一个一个地数,11后面第4个数是(15);11 前面第 4 个数是 (7)。", + "knowledge_points": [ + "20以内数的排序" + ], + "source": "24-25一年级下·河北石家庄·期中" + }, + { + "id": "28", + "unit": "第二单元 11~20的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.65, + "question": "文文有 13 块糖,送给小芳 3 块后,她还剩( )块。", + "options": [ + + ], + "answer": "10", + "solution": "【分析】根据题意可知,文文块糖的总块数减去送给小芳的块数,等于她还剩多少块,据此解答.\n【详解】根据分析可得:13 - 3 = 10 (块),因此,文文还剩下10块糖。", + "knowledge_points": [ + "不退位减法 (20以内)" + ], + "source": "24-25 一年级下·河北沧州·期中" + }, + { + "id": "29", + "unit": "第二单元 11~20的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "小李有 14 个香蕉,吃了 4 个,还剩( )个。", + "options": [ + + ], + "answer": "10", + "solution": "【分析】由题意可知:用原来的香蕉数减去吃了的,就是还剩的,据此解答.\n【详解】由分析可得:14 - 4 = 10 (个)小李有 14 个香蕉,吃了 4 个,还剩 10 个。", + "knowledge_points": [ + "不退位减法 (20以内)" + ], + "source": "24-25 一年级下·湖南长沙·期中" + }, + { + "id": "30", + "unit": "第二单元 11~20的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.65, + "question": "小红有 14 支铅笔,比小刚少 3 支,小刚有( )支。", + "options": [ + + ], + "answer": "17", + "solution": "【分析】用小红的铅笔支数加小红比小刚少的支数,即可求出小刚的支数.\n【详解】 14 + 3 = 17 (支),小刚有 17 支。", + "knowledge_points": [ + "不进位加法(20以内)" + ], + "source": "24-25 一年级下·湖南岳阳·期中" + }, + { + "id": "31", + "unit": "第二单元 11~20的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "从 1 数到 20, 15 前面一个数是( ), 后面第二个数是( )。", + "options": [ + + ], + "answer": "14,17", + "solution": "【分析】从1数到20依次为:1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,由此找出对应的数即可.\n【详解】由分析可得:从 1 数到 20,15 前面一个数是 14,后面第二个数是 17。", + "knowledge_points": [ + "20以内数的排序" + ], + "source": "24-25 一年级下·广东揭阳·期中" + }, + { + "id": "32", + "unit": "第二单元 11~20的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "小宇原来有 14 支笔,送给小丽 2 支后,他们就同样多了。小丽原来有( )支笔。", + "options": [ + + ], + "answer": "10", + "solution": "【分析】根据题意,先用小宇原有笔的数量减去给小丽的数量,计算出小宇现在有几支笔,也就是小丽现在有几支笔,再用小丽现在笔的数量减去小宇给她的数量,就是小丽原有笔的数量.\n【详解】 14 - 2 = 12 (支),12 - 2 = 10 (支),小宇原来有 14 支笔,送给小丽 2 支后,他们就同样多了。小丽原来有 10 支笔。", + "knowledge_points": [ + "不退位减法(20以内)", + "\"一样多\"问题" + ], + "source": "24-25 一年级下·江西吉安·期中" + }, + { + "id": "33", + "unit": "第二单元 11~20的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.4, + "question": "弟弟今年 3 岁,姐姐今年11岁,当弟弟和姐姐两人的年龄合起来是16岁时,姐姐( )岁,弟弟( )岁。", + "options": [ + + ], + "answer": "12;4", + "solution": "【分析】根据题意,先用加法计算出弟弟和姐姐今年的年龄和,再用 16 减去今年的年龄和,计算出两人增加的年龄和。弟弟长一岁,姐姐同样也长一岁,则将增加的年龄和\n分成同样多的两份,每一份就是两人增长的岁数,再和原来的年龄相加即可.\n【详解】今年两人的年龄和: 3 + 11 = 14(岁);两人增加的年龄和: 16 - 14 = 2 (岁);2 = 1 + 1,也就是每人增长 1 岁。弟弟: 3 + 1 = 4 (岁);姐姐: 11 + 1 = 12 (岁)。弟弟今年 3 岁,姐姐今年 11 岁,当弟弟和姐姐两人的年龄合起来是 16 岁时,姐姐 12 岁,弟弟 4 岁。", + "knowledge_points": [ + "年龄问题", + "不进位加法(20以内)", + "不退位减法 (20 以内)" + ], + "source": "24-25 一年级下·江西抚州·期中" + }, + { + "id": "34", + "unit": "第二单元 11~20的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "在 9,12,15,18 中,个位是 5 的数是( ), 十位是 1 的数有( )个。", + "options": [ + + ], + "answer": "15;3", + "solution": "【分析】20 以内数,从右往左数,第一位是个位,第二位是十位;据此解决即可。则,在 9,12,15,18 中,个位是 5 的数是 15,十位是 1 的数有:12,15,18,共 3 个;【详解】由分析可知:在 9,12,15,18 中,个位是 5 的数是 15,十位是 1 的数有 3 个。", + "knowledge_points": [ + "20以内数的组成" + ], + "source": "24-25 一年级下·湖南株洲·期中" + }, + { + "id": "35", + "unit": "第二单元 11~20的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "比 12 多 3 的数是( ), 比 17 少 4 的数是( )。", + "options": [ + + ], + "answer": "15;13", + "solution": "【分析】求比一个数多几的数是多少,用这个数十多的数计算;求比一个数少几的数是多少,用这个数一少的数计算.\n【详解】12 + 3 = 15;17 - 4 = 13,比 12 多 3 的数是 15,比 17 少 4 的数是 13。", + "knowledge_points": [ + "不进位加法(20以内)", + "不退位减法(20以内)", + "谁比谁多/少几的问题" + ], + "source": "24-25 一年级下·湖南株洲·期中" + }, + { + "id": "36", + "unit": "第二单元 11~20的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "7 个一和 1 个十组成的数是( ),它后面的第一个数是( )。", + "options": [ + + ], + "answer": "17;18", + "solution": "【分析】一个两位数,从右往左数,第一位是个位,第二位是十位。7个一是7,1个十是10,合起来是17。相邻的两个数相差1,后一个数比前一个数多1,前一个数比后一个数少1;据此解决.\n【详解】 17 + 1 = 18,7 个一和 1 个十组成的数是 17,它后面的第一个数是 18。", + "knowledge_points": [ + "20以内数的组成", + "不进位加法(20以内)" + ], + "source": "24-25 一年级下·河南信阳·期中" + }, + { + "id": "37", + "unit": "第二单元 11~20的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "找规律填数:3,6,9,( ),( )。", + "options": [ + + ], + "answer": "12;15", + "solution": "【分析】根据数据可知,规律为从左往右依次的多 3,据此解答.\n【详解】9 + 3 = 12;12 + 3 = 15,找规律填数: 3, 6, 9, 12, 15。", + "knowledge_points": [ + "整数排列的规律", + "不进位加法(20以内)" + ], + "source": "24-25 一年级下·湖南岳阳·期中" + }, + { + "id": "38", + "unit": "第二单元 11~20的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "乐乐和明明参加 1分钟口算比赛。乐乐还剩 12 道没完成,明明还剩 13 道没完成。()完成的口算多,多()道。", + "options": [ + + ], + "answer": "乐乐;1", + "solution": "【分析】口算比赛时,每人要完成的题目总数是一样多的。每人要完成的题目总数包含已经完成的和剩下没做的。剩下没做的越少,已经完成的就越多。乐乐还剩 12 道没做,明明还剩 13 道, 12 \u003c 13,乐乐剩下没做的比明明少,那么乐乐已经完成的就比明明多。用减法 13 - 12 = 1 (道),即可求出乐乐比明明多完成了 1 道.\n【详解】根据分析可得:乐乐和明明参加 1 分钟口算比赛。乐乐还剩 12 道没完成,明明还剩 13 道没完成。乐乐完成的口算多,多 1 道。", + "knowledge_points": [ + "20以内数的比大小", + "不退位减法(20以内)" + ], + "source": "24-25 一年级下·全国·课后作业" + }, + { + "id": "39", + "unit": "第二单元 11~20的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "2 个十是( ),读作( )。", + "options": [ + + ], + "answer": "20;二十", + "solution": "【分析】一个十是 10,则 2 个十是 20;读数时,从十位读起,十位上是几,就读几十,个位上是几,就读几,若末尾是 0,则不读.\n【详解】2 个十是(20),读作(二十)。", + "knowledge_points": [ + "20以内数的组成", + "11~20 的认识和读写" + ], + "source": "24-25 一年级上·福建龙岩·期末" + }, + { + "id": "40", + "unit": "第二单元 11~20的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "一个两位数,个位上是 2,十位上是 1,这个数是( )。", + "options": [ + + ], + "answer": "12", + "solution": "【分析】一个两位数,从右往左依次为个位,十位。个位上是几表示几个一,就在个位上写几,十位上是几表示几个十,就在十位上写几,据此解答.\n【详解】根据分析可得:一个两位数,个位上是 2,十位上是 1,这个数是 12 。", + "knowledge_points": [ + "20以内数的组成", + "11~20 的认识和读写" + ], + "source": "24-25 一年级上·山东临沂·期末" + }, + { + "id": "41", + "unit": "第二单元 11~20的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "3 个一和 1 个十合起来是( ),2 个十是( )。", + "options": [ + + ], + "answer": "13;20", + "solution": "【分析】根据数位的意义,几个十就是几十,几个一就是几,据此解答.\n【详解】3个一和1个十合起来是13,2个十是 20。", + "knowledge_points": [ + "20以内数的组成" + ], + "source": "24-25 一年级上·河南周口·期末" + }, + { + "id": "42", + "unit": "第二单元 11~20的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "20 前面的一个数是( ), 15 后面的一个数是( )。", + "options": [ + + ], + "answer": "19;16", + "solution": "【分析】1 到 20,从小到大排序:1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20。据此填空.\n【详解】20前面的一个数是19,15后面的一个数是 16 。", + "knowledge_points": [ + "20以内数的排序" + ], + "source": "24-25 一年级上·湖北黄冈·期末" + }, + { + "id": "43", + "unit": "第二单元 11~20的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "一个数由 1 个十和 3 个一组成,这个数是( )。与它相邻的两个数是( )和( )。", + "options": [ + + ], + "answer": "13;12;14", + "solution": "【分析】几个十就是几十,几个一就是几。一个数前面第一个数比它小 1,后面第一个数比它大 1 .\n【详解】一个数由 1 个十和 3 个一组成,这个数是 13。与它相邻的两个数是 12 和 14。", + "knowledge_points": [ + "20以内数的组成", + "20以内数的排序" + ], + "source": "24-25 一年级上·湖南株洲·期末" + }, + { + "id": "44", + "unit": "第二单元 11~20的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "由1个十和7个一组成的数据是( ),与他相邻的两个数据是( )和( )。", + "options": [ + + ], + "answer": "17;16;18", + "solution": "【分析】几个十就是几十,几个一就是几。1 到 20,从小到大排序:1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20.\n【详解】由 1 个十和 7 个一组成的数是 17,与他相邻的两个数是 16 和 18。", + "knowledge_points": [ + "20以内数的组成", + "20以内数的排序" + ], + "source": "24-25 一年级上·河南周口·期末" + }, + { + "id": "45", + "unit": "第二单元 11~20的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "小红今天看书从第 5 页看到 12 页,明天开始看 13 页,今天看了( )页。", + "options": [ + + ], + "answer": "8", + "solution": "【分析】从第 5 页看到 12 页,依次是5,6,7,8,9,10,11,12页,数一数即可.\n【详解】小红今天看书从第 5 页看到 12 页,明天开始看 13 页,今天看了 8 页。", + "knowledge_points": [ + "20以内数的排序" + ], + "source": "24-25 一年级上·湖南株洲·期末" + }, + { + "id": "46", + "unit": "第二单元 11~20的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "13 是由( )个十和( )个一组成的,这个数在( )和( )中间。", + "options": [ + + ], + "answer": "1;3;12;14", + "solution": "【分析】一个两位数,从右往左数,第一位是个位,个位上的数表示几个一;第二位是十位,十位上的数表示几个十。1 到 20,从小到大排序:1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20.\n【详解】13是由1个十和3个一组成的,这个数在12和14中间。", + "knowledge_points": [ + "20以内数的组成", + "20以内数的排序" + ], + "source": "24-25 一年级上·广西玉林·期末" + }, + { + "id": "47", + "unit": "第二单元 11~20的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "最大的一位数和最小的两位数的和是( );被减数是 17,减数是 3,差是( )。", + "options": [ + + ], + "answer": "19;14", + "solution": "【分析】根据\"加数 + 加数 = 和,被减数 - 减数 = 差\"及\"最大的一位数是 9 和最小的两位数是 10\"来解决此题.\n【详解】最大的一位数是9,最小的两位数是10.9 + 10 = 19被减数是 17,减数是 3.17 - 3 = 14,最大的一位数和最小的两位数的和是 19;被减数是 17,减数是 3,差是 14 。", + "knowledge_points": [ + "不进位加法(20以内)", + "不退位减法(20以内)" + ], + "source": "24-25 一年级上·山东临沂·期末" + }, + { + "id": "48", + "unit": "第二单元 11~20的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "1 个十和 3 个一组成( ),比 19 大 1 的数是( )。", + "options": [ + + ], + "answer": "13;20", + "solution": "【分析】几个十就是几十,几个一就是几,由此组数即可。比 19 大 1 的数,也就是数数时,19 后边的一个数,根据 20 以内数的顺序解答.\n【详解】20以内数的顺序:1,2,3。17,18,19,20.1个十是10,3个一是3,组成13,比19大1的数是20。", + "knowledge_points": [ + "20以内数的组成", + "20以内数的排序" + ], + "source": "24-25 一年级上·湖北恩施·期末" + }, + { + "id": "49", + "unit": "第二单元 11~20的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "小朋友们排队做游戏,小悦排第 10,小宇排第 18,小悦和小宇之间有( )人。", + "options": [ + + ], + "answer": "7", + "solution": "【分析】根据题意,可从 10 数到 18,它们之间有几个数字,也就是小悦和小宇之间有几人.\n【详解】从 10 数到 18 依次为: 10, 11, 12, 13, 14, 15, 16, 17, 18.10 和 18 之间有 7 个数字。则小朋友们排队做游戏,小悦排第 10,小宇排第 18,小悦和小宇之间有 7 人。", + "knowledge_points": [ + "20以内数的排序" + ], + "source": "24-25 一年级上·湖北恩施·期末" + }, + { + "id": "50", + "unit": "第二单元 11~20的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.65, + "question": "比 10 多 2 的数是( );比 16 少 6 的数是( );15 比( )多 4。", + "options": [ + + ], + "answer": "12;10;11", + "solution": "【分析】求比一个数多多少的数用加法计算。求比一个数少多少的数用减法计算。用 15 减 4 可以算出 15 比哪个数多 4.\n【详解】10 + 2 = 12;16 - 6 = 10;15 - 4 = 11,比 10 多 2 的数是 12;比 16 少 6 的数是 10;15 比 11 多 4。", + "knowledge_points": [ + "不进位加法(20以内)", + "不退位减法(20以内)" + ], + "source": "24-25 一年级上·湖北黄冈·期末" + }, + { + "id": "51", + "unit": "第二单元 11~20的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "7 个一和 1 个十合起来是( ),再添 2 个一是( )。", + "options": [ + + ], + "answer": "17;19", + "solution": "【分析】几个十就是几十,几个一就是几,合起来就是几十几,由此解答.\n【详解】7 个一是 7, 1 个十是 10,合起来是 17。再添上 2 个一,也就是 1 个十和 9 个一,是 19。", + "knowledge_points": [ + "20以内数的组成" + ], + "source": "24-25 一年级下·新疆喀什·开学考试" + }, + { + "id": "52", + "unit": "第二单元 11~20的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "加数是 5,另一个加数是 10,和是( )。", + "options": [ + + ], + "answer": "15", + "solution": "【分析】加数 + 加数 = 和,直接列式计算.\n【详解】 5 + 10 = 15,和是 15 。", + "knowledge_points": [ + "不进位加法(20以内)" + ], + "source": "24-25 一年级上·湖南株洲·期末" + }, + { + "id": "53", + "unit": "第二单元 11~20的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "按顺序填上合适的数.\n\n\u003ctable\u003e\u003ctr\u003e\u003ctd\u003e\u003c/td\u003e\u003ctd\u003e10\u003c/td\u003e\u003ctd\u003e\u003c/td\u003e\u003ctd\u003e\u003c/td\u003e\u003ctd\u003e13\u003c/td\u003e\u003ctd\u003e14\u003c/td\u003e\u003ctd\u003e\u003c/td\u003e\u003c/tr\u003e\u003c/table\u003e\n\n\u003ctable\u003e\u003ctr\u003e\u003ctd\u003e16\u003c/td\u003e\u003ctd\u003e\u003c/td\u003e\u003ctd\u003e12\u003c/td\u003e\u003ctd\u003e10\u003c/td\u003e\u003ctd\u003e\u003c/td\u003e\u003ctd\u003e\u003c/td\u003e\u003c/tr\u003e\u003c/table\u003e", + "options": [ + + ], + "answer": "9;11;12;15;14;8;6", + "solution": "【分析】第一组数字依次变大,每后一个数比前一个数大1,也就是从 9 开始,一个一个地正着数,依次为9, 10, 11, 12, 13, 14, 15;第二组数字依次变小,每后一个数比前一个数小 2,也就是从 16 开始,两个两个地倒着数,依次为16, 14, 12, 10, 8, 6.\n【详解】填写如下:\n\n\u003ctable\u003e\u003ctr\u003e\u003ctd\u003e9\u003c/td\u003e\u003ctd\u003e10\u003c/td\u003e\u003ctd\u003e11\u003c/td\u003e\u003ctd\u003e12\u003c/td\u003e\u003ctd\u003e13\u003c/td\u003e\u003ctd\u003e14\u003c/td\u003e\u003ctd\u003e15\u003c/td\u003e\u003c/tr\u003e\u003c/table\u003e\n\n\u003ctable\u003e\u003ctr\u003e\u003ctd\u003e16\u003c/td\u003e\u003ctd\u003e14\u003c/td\u003e\u003ctd\u003e12\u003c/td\u003e\u003ctd\u003e10\u003c/td\u003e\u003ctd\u003e8\u003c/td\u003e\u003ctd\u003e6\u003c/td\u003e\u003c/tr\u003e\u003c/table\u003e", + "knowledge_points": [ + "20以内数的排序" + ], + "source": "24-25 一年级上·湖北荆州·期末" + }, + { + "id": "54", + "unit": "第二单元 11~20的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "14 是( )位数,是由( )个十和( )个一组成的。", + "options": [ + + ], + "answer": "两;1;4", + "solution": "【分析】有几个数字就是几位数。一个两位数,从右往左数,第一位是个位,个位上的数表示几个一;第二位是十位,十位上的数表示几个十.\n【详解】14是两位数,是由1个十和4个一组成的。", + "knowledge_points": [ + "20以内数的组成" + ], + "source": "24-25 一年级上·湖北黄冈·期末" + }, + { + "id": "55", + "unit": "第二单元 11~20的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "14 个位上的 4 表示( ), 十位上的 1 表示( )。", + "options": [ + + ], + "answer": "4个一;1个十", + "solution": "【分析】一个两位数,从右往左依次为个位,十位。个位上是几表示几个一,十位上是几表示几个十,据此解答.\n【详解】根据分析可得:14个位上的4表示4个一,十位上的1表示1个十。", + "knowledge_points": [ + "20以内数的组成" + ], + "source": "24-25 一年级上·河南周口·期末" + }, + { + "id": "56", + "unit": "第二单元 11~20的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.65, + "question": "17 是由( )个十和 7 个( )组成的,再添上( )就是 2 个十。", + "options": [ + + ], + "answer": "1;一;3", + "solution": "【分析】一个两位数,从右往左数,第一位是个位,个位上的数表示几个一;第二位是十位,十位上的数表示几个十。2 个十是 20,再往后数几下到 20 就添上几.\n【详解】17是由1个十和7个一组成的,再添上3就是2个十。", + "knowledge_points": [ + "20 以内数的组成", + "11~20 的认识和读写" + ], + "source": "24-25 一年级下·江西吉安·阶段练习" + }, + { + "id": "57", + "unit": "第二单元 11~20的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "与 7 相邻的数是( )和( ),15和17都是与( )相邻的数,比10大比 13 小的数有( )()。", + "options": [ + + ], + "answer": "6;8;16;11;12", + "solution": "【分析】与 7 相邻的数:自然数中,比 7 小 1 的数是 6,比7大1的数是8,因此填6和8.15和17的中间数:15是16 的前一个数, 17 是 16 的后一个数,因此 15 和 17 都与 16相邻。比 10 大比 13 小的数:通过数数的方法可知,比 10大且比 13 小的数是 11 和 12.\n【详解】根据分析可得:与 7 相邻的数是 6 和 8, 15 和 17 都是与 16 相邻的数,比 10 大比 13 小的数有 11,12。", + "knowledge_points": [ + "20以内数的比大小", + "20以内数的排序" + ], + "source": "24-25 一年级下·江西吉安·阶段练习" + }, + { + "id": "58", + "unit": "第二单元 11~20的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "18,7,9,13,4,16上面这些数中,最小的是( ),最大的是( ),从右边数起,第3个数是( )。", + "options": [ + + ], + "answer": "4;18;13", + "solution": "【分析】20 以内数从大到小关系为 20 \u003e 19 \u003e 18 \u003e 17 \u003e 16\u003e 15 \u003e 14 \u003e 13 \u003e 12 \u003e 11 \u003e 10 \u003e 9 \u003e 8 \u003e 7 \u003e 6 \u003e 5 \u003e 4 \u003e 3 \u003e 2 \u003e 1\u003e0,由此比较找到最大的数和最小的数;一般情况下,写字的手是右手也就是右边,不写字的手是左手也就是左边,从右也就是从 16 开始数,第 3 个数是 13.\n【详解】 18 \u003e 16 \u003e 13 \u003e 9 \u003e 7 \u003e 4上面这些数中,最小的是 4,最大的是 18,从右边数起,第 3 个数是 13。", + "knowledge_points": [ + "左,右位置", + "20以内数的比大小", + "认识几和第几" + ], + "source": "24-25一年级下·江西吉安·阶段练习" + }, + { + "id": "59", + "unit": "第二单元 11~20的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "在9,18,0,10,3,20这些数中,最大的数是( ),最小的数是( ),最接近 10 的数是( )。", + "options": [ + + ], + "answer": "20;0;9", + "solution": "【分析】20以内数由小到大为:0,1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,通过 20 以内数的排序可知最大的数是几,最小的数是几,离 10 最近的数就是最接近 10 的数.\n【详解】由分析可知: 9,18,0,10,3,20 这些数中,最大的数是 20,最小的数是 0,最接近 10 的数是 9。", + "knowledge_points": [ + "20以内数的比大小", + "20以内数的排序" + ], + "source": "24-25 一年级上·湖南湘西·期末" + }, + { + "id": "60", + "unit": "第二单元 11~20的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "一个数由 9 个一和 1 个十组成,这个数是( ), 读作( ), 与它相邻的两个数是( )和( )。", + "options": [ + + ], + "answer": "19;十九;18;20", + "solution": "【分析】一个两位数,从右往左依次为个位,十位,十位上的数表示几个十,个位上的数表示几个一。写数时从高位写起,几个十就在十位写几,几个一就在个位写几,读数时,从高位读起,十位是几读作几十,个位是几读作几。与它相邻的数,是它两侧的数,根据20以内数的顺序解答.\n【详解】20以内数的顺序为:1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16, 17, 18, 19, 20。一个数由 9 个一和 1 个十组成,这个数是 19,读作十九,与它相邻的两个数是 18 和 20。", + "knowledge_points": [ + "20以内数的组成", + "11~20 的认识和读写", + "20以内数的排序" + ], + "source": "24-25 一年级上·湖南湘西·期末" + }, + { + "id": "61", + "unit": "第二单元 11~20的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "比 9 大,比 12 小的数有( ),共( )个;12后面的第3个数是( )。", + "options": [ + + ], + "answer": "10,11;2;15", + "solution": "【分析】20以内数由小到大为:0,1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,由 20 以内数的大小关系可知比 9大,比 12 小的数有 10 和 11,共 2 个;从 12 往后数 3 个数,对应的数字是 15.\n【详解】由分析得:比 9 大,比 12 小的数有 10,12,共 2 个;12 后面的第 3 个数是 15。", + "knowledge_points": [ + "20以内数的比大小", + "20以内数的排序" + ], + "source": "24-25 一年级上·湖南湘西·期末" + }, + { + "id": "62", + "unit": "第二单元 11~20的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "按顺序,填一填.\n(1)0, 3, 6, ( ), 12, ( ).\n\n(2)17, 15, ( ), 11, 9, 7, ( )。", + "options": [ + + ], + "answer": "9;15;13;5", + "solution": "【分析】(1)这组数字依次变大,每后一个数比前一个数大3,也就是从0开始,三个三个地正着数,依次为0,3,6,9,12,15;(2) 这组数字依次变小,每后一个数比前一个数小 2,也就是从 17 开始,两个两个地倒着数,依次为17, 15, 13, 11, 9, 7, 5.\n【详解】 (1) 0, 3, 6, 9, 12, 15。(2) 17, 15, 13, 11, 9, 7, 5。", + "knowledge_points": [ + "20以内数的排序" + ], + "source": "24-25一年级上·贵州黔南·期末" + }, + { + "id": "63", + "unit": "第二单元 11~20的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "在 6,9,12,5,18 中,最大的数是( ), 最小的数是( ), 最接近 10 的数是( )。", + "options": [ + + ], + "answer": "18;5;9", + "solution": "【分析】19 以内的数从小到大排列是: 1 \u003c 2 \u003c 3 \u003c 4 \u003c 5 \u003c 6 \u003c 7 \u003c 8 \u003c 9 \u003c 10 \u003c 11 \u003c 12 \u003c 13 \u003c 14 \u003c 15 \u003c 16 \u003c 17 \u003c 18 \u003c 19 。间隔的数字越少则越接近,据此解答.\n【详解】 5 \u003c 6 \u003c 9 \u003c 12 \u003c 18,在 6,9,12,5,18 中,最大的数是 18,最小的数是 5,最接近 10 的数是 9。", + "knowledge_points": [ + "20以内数的比大小", + "20以内数的排序" + ], + "source": "24-25一年级上·贵州黔南·期末" + }, + { + "id": "64", + "unit": "第二单元 11~20的认识和加、减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "16 的个位上是( ),表示( )个一,十位上是( ),表示()个十。与 16 相邻的两个数是( )和( )。", + "options": [ + + ], + "answer": "6;6;1;1;15;17", + "solution": "【分析】一个两位数,从右往左依次为个位,十位,十位是几表示几个十,个位是几表示几个一。与 16 相邻的数是比它小 1 的数,用它 -1,和比它大 1 的数,用它 +1,由此解答.\n【详解】 16 - 1 = 15;16 + 1 = 17,16 的个位上是 6,表示 6 个一,十位上是 1,表示 1 个十。与 16 相邻的两个数是 15 和 17 。", + "knowledge_points": [ + "20以内数的组成", + "不进位加法(20以内)", + "不退位减法(20以内)" + ], + "source": "24-25 一年级上·贵州黔南·期末" + }, + { + "id": "65", + "unit": "第二单元 11~20的认识和加、减法", + "question_type": "判断题", + "difficulty": 0.85, + "question": "从1数到20,有20个数。( )", + "options": [ + + ], + "answer": "√", + "solution": "【分析】从 1 数到 20,依次为1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,数出数字的个数即可解答.\n【详解】由分析得:从 1 数到 20,有 20 个数。原题说法正确。故答案为: √", + "knowledge_points": [ + "数一数", + "20以内数的排序" + ], + "source": "24-25一年级下·黑龙江佳木斯·期末" + }, + { + "id": "66", + "unit": "第二单元 11~20的认识和加、减法", + "question_type": "判断题", + "difficulty": 0.65, + "question": "有 13 人排成一队,从前往后数,小红排在第 3,从后往前数,小红一定排在第 11。( )", + "options": [ + + ], + "answer": "√", + "solution": "【分析】根据排队的位置关系,总人数为 13 人,从前往后数小红排第 3,则从后往前数的位置为总人数减去前数位置再加 1,即 13 - 3 + 1 = 11 .\n【详解】 13 - 3 + 1 = 11,即,有 13 人排成一队,从前往后数,小红排在第 3,从后往前数,小红一定排在第 11,结论正确。故答案为: √", + "knowledge_points": [ + "不进位,不退位加减混合运算(20以内)", + "排队问题" + ], + "source": "24-25 一年级下·河北邯郸·期末" + }, + { + "id": "67", + "unit": "第二单元 11~20的认识和加、减法", + "question_type": "判断题", + "difficulty": 0.85, + "question": "3 个一和 1 个十合起来是 13。( )", + "options": [ + + ], + "answer": "√", + "solution": "【分析】根据数的组成,3个一表示个位是3,1个十表示十位是1,合起来组成的数是13,据此解答.\n【详解】3个一和1个十合起来是 13。原题说法正确。故答案为: √", + "knowledge_points": [ + "20以内数的组成", + "11~20 的认识和读写" + ], + "source": "24-25 一年级下·河北邯郸·期末" + }, + { + "id": "68", + "unit": "第二单元 11~20的认识和加、减法", + "question_type": "判断题", + "difficulty": 0.85, + "question": "比 10 大比 16 小的数有 5 个。( )", + "options": [ + + ], + "answer": "√", + "solution": "【分析】两位数之间的比较大小,当十位上的数相同时,就比较个位上的数,个位上大的数就大;据此解决此题.\n【详解】 10 \u003c 11 \u003c 12 \u003c 13 \u003c 14 \u003c 15 \u003c 16,即,比 10 大比 16 小的数有 5 个。此说法正确。故答案为: √", + "knowledge_points": [ + "20以内数的比大小" + ], + "source": "24-25 一年级下·湖南株洲·期中" + }, + { + "id": "69", + "unit": "第二单元 11~20的认识和加、减法", + "question_type": "判断题", + "difficulty": 0.85, + "question": " 13 - 2 = 11 中, 13是减数,2 是被减数,11 是差。()", + "options": [ + + ], + "answer": "×", + "solution": "【分析】减法算式为被减数 - 减数 = 差,由此找出各部分对应的名称即可.\n【详解】由分析可知:13-2=11中,13是被减数,2是减数,11是差,原题说法错误。故答案为: ×", + "knowledge_points": [ + "不退位减法(20以内)" + ], + "source": "24-25一年级上·湖北恩施·期末" + }, + { + "id": "70", + "unit": "第二单元 11~20的认识和加、减法", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式计算.\n\n![](images/668dcbdb90b05dcfa9c7550491f156a67ac4b34d4030ca39b8724bbb451959eb.jpg)\n\n□ ○ □ = □(个)", + "options": [ + + ], + "answer": "17 - 5 = 12", + "solution": "【分析】由图意可知:共有 17 个羽毛球,左边有 5 个羽毛球球,求右边有多少个,用总个数减去左边的个数即可;据此解答.\n【详解】由分析可得:17 - 5 = 12 (个)右边有 12 个。", + "knowledge_points": [ + "图文问题", + "不退位减法(20以内)" + ], + "source": "25-26 一年级上·全国·单元测试" + }, + { + "id": "71", + "unit": "第二单元 11~20的认识和加、减法", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式计算.\n\n![](images/06216d901ada58105e3d5db825ec0af31bbbc816c7abf26c842e385dc47cba55.jpg)\n\n□ ○ □ = □(个)", + "options": [ + + ], + "answer": "10 + 7 = 17", + "solution": "【分析】由图意可知:左边有 10 个笑脸,右边有 7 个,求一共多少个,把左边的笑脸数加上右边的即可;据此解答.\n【详解】由分析可得:10 + 7 = 17 (个),一共有 17 个笑脸。", + "knowledge_points": [ + "图文问题", + "不进位加法(20以内)" + ], + "source": "25-26 一年级上·全国·单元测试" + }, + { + "id": "72", + "unit": "第二单元 11~20的认识和加、减法", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式计算.\n\n![](images/611092f3f4b049803a126417c7a67036c8c749a6dc37807af710857ef4f10e47.jpg)\n\n□ ○ □ = □(个)", + "options": [ + + ], + "answer": "17 - 5 = 12", + "solution": "【分析】用一共的 17 个减去左边的 5 个即可求出右边的个数.\n【详解】17 - 5 = 12(个),右边有 12 个。", + "knowledge_points": [ + "图文问题", + "不退位减法(20以内)" + ], + "source": "24-25 一年级下·福建龙岩·期末" + }, + { + "id": "73", + "unit": "第二单元 11~20的认识和加、减法", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式计算.\n\n![](images/49f38c7f8305d31896a80c8b930423047d4b09fbdb2c63b85678523e29056de7.jpg)\n\n□ ○ □ = □( )", + "options": [ + + ], + "answer": "19 - 4 = 15(只)", + "solution": "【分析】一共有 19 只小鸟,飞走了 4 只,求树上还剩几只,用减法计算,即总数量 - 飞走的数量 = 还剩的数量.\n【详解】19 - 4 = 15(只)树上还剩15只。", + "knowledge_points": [ + "图文问题", + "不退位减法(20以内)" + ], + "source": "24-25 一年级下·河南许昌·期中" + }, + { + "id": "74", + "unit": "第二单元 11~20的认识和加、减法", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式计算.\n\n![](images/5586d07bb0ad98340e53b23cf02f7b9da3712fa55d6b0a2d48ee5a5c03ebff4f.jpg)\n\n□ ○ □ = □(个)", + "options": [ + + ], + "answer": "14 - 2 = 12", + "solution": "【分析】一共有 14 个玉米,用虚线框起来 2 个表示去掉 2 个,求剩下的数量,用减法计算,即总数量 - 去掉的数量 = 还剩的数量.\n【详解】14 - 2 = 12(个),还剩 12 个玉米。", + "knowledge_points": [ + "图文问题", + "不退位减法(20以内)" + ], + "source": "24-25 一年级下·河北邢台·期中" + }, + { + "id": "75", + "unit": "第二单元 11~20的认识和加、减法", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式计算.\n\n![](images/399a6b7c01b83ad74d0235c7221e695d50079996b112ef38df46aa8d05be0f27.jpg)", + "options": [ + + ], + "answer": "15 - 3 = 12(支)", + "solution": "【分析】用一共的 15 支减去右边的 3 支即可求出左边的支数.\n【详解】15 - 3 = 12(支),左边有 12 支。", + "knowledge_points": [ + "图文问题", + "不退位减法(20以内)" + ], + "source": "24-25 一年级下·河南周口·期中" + }, + { + "id": "76", + "unit": "第二单元 11~20的认识和加、减法", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式计算.\n\n![](images/0b49f77a085e6e47f6f1c3ca28cfd222c9dd9e3b02f627957a4fc8bd4331b51c.jpg)\n\n□ ○ □ = □(个)", + "options": [ + + ], + "answer": "19 - 6 = 13", + "solution": "【分析】用一共的 19 个减去左边的 6 个即可求出右边的个数.\n【详解】19 - 6 = 13(个),右边有 13 个。", + "knowledge_points": [ + "图文问题", + "不退位减法(20以内)" + ], + "source": "24-25 一年级下·河北邢台·期中" + }, + { + "id": "77", + "unit": "第二单元 11~20的认识和加、减法", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式计算.\n\n![](images/84e5ade5fe78b6ff7bc1940ef3adb27dd4ca6fb361e23e0fe6828d9a57abc2e3.jpg)\n\n□ ○ □ = □(个)", + "options": [ + + ], + "answer": "2 + 11 = 13", + "solution": "【分析】用左边蘑菇的个数加上右边筐里蘑菇的个数,即可求出蘑菇的总个数.\n【详解】2 + 11 = 13(个),一共有 13 个蘑菇。", + "knowledge_points": [ + "图文问题", + "不进位加法(20以内)" + ], + "source": "24-25 一年级下·广东汕尾·期中" + }, + { + "id": "78", + "unit": "第二单元 11~20的认识和加、减法", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图写算式.\n\n![](images/3daa6accd4985713f0fce52404f267ba8bf06e18abab9fe629bbf6c920f8d88c.jpg)\n\n□ ○ □ = □(瓶)", + "options": [ + + ], + "answer": "9 + 10 = 19", + "solution": "【分析】总瓶数 = 左边的瓶数 + 右边的瓶数.\n【详解】9 + 10 = 19 (瓶),一共有 19 瓶。", + "knowledge_points": [ + "图文问题", + "不进位加法(20以内)" + ], + "source": "24-25 一年级下·广东揭阳·期中" + }, + { + "id": "79", + "unit": "第二单元 11~20的认识和加、减法", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式计算.\n\n![](images/58829f835384adef9ab4f65e07f8313564712ce1623383159420121108b54c4c.jpg)\n\n□ ○ □ = □(支)", + "options": [ + + ], + "answer": "2 + 17 = 19", + "solution": "【分析】用左边蘑菇的个数加上右边篮子里蘑菇的个数,即可求出一共有多少个蘑菇 .\n【详解】2 + 17 = 19(个),一共有 19 个蘑菇。", + "knowledge_points": [ + "图文问题", + "不进位加法(20以内)" + ], + "source": "24-25 一年级下·贵州六盘水·期中" + }, + { + "id": "80", + "unit": "第二单元 11~20的认识和加、减法", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式.\n\n![](images/屏幕截图%202025-12-01%20230331.jpg)\n\n□ ○ □ = □(支)", + "options": [ + + ], + "answer": "13 - 3 = 10", + "solution": "【分析】用一共的 13 支减去右边的 3 支即可求出左边的支数.\n【详解】13 - 3 = 10 (支),左边有 10 支。", + "knowledge_points": [ + "图文问题", + "不退位减法(20以内)" + ], + "source": "24-25 一年级下·河南周口·阶段练习" + }, + { + "id": "81", + "unit": "第二单元 11~20的认识和加、减法", + "question_type": "计算题", + "difficulty": 0.85, + "question": "列算式.\n\n![](images/e566a8e713f9d95f274421428a43ee52f18c08f841d3844686eb665939c2b11a.jpg)\n\n□ ○ □ = □(个)", + "options": [ + + ], + "answer": "16 - 5 = 11", + "solution": "【分析】用总共的个数减去右边的个数,即可求出左边盒子里的个数.\n【详解】16 - 5 = 11 (个),左边盒子里有 11 个。", + "knowledge_points": [ + "图文问题", + "不退位减法(20以内)" + ], + "source": "24-25 一年级上·福建龙岩·期末" + }, + { + "id": "82", + "unit": "第二单元 11~20的认识和加、减法", + "question_type": "计算题", + "difficulty": 0.85, + "question": "列式计算.\n\n![](images/c9d8e20f22545a5fe08ab3aa2b2b2212fcd7e0b769ae39965019f4a78c0a5f62.jpg)\n\n□ ○ □ = □(支)", + "options": [ + + ], + "answer": "18 - 4 = 14", + "solution": "【分析】根据题图可知,左边有 4 支铅笔,铅笔的总支数减去左边的支数,等于盒子里的支数,据此解答.\n【详解】根据分析可得:18 - 4 = 14 (支),盒子里有 14 支铅笔。", + "knowledge_points": [ + "图文问题", + "不退位减法(20以内)" + ], + "source": "24-25 一年级上·江西吉安·期末" + }, + { + "id": "83", + "unit": "第二单元 11~20的认识和加、减法", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式计算.\n\n![](images/e1202b23af0cc76da953b466ed52f45b462ec416ae811182b6b646b681161c4c.jpg)\n\n□ ○ □ = □(个)", + "options": [ + + ], + "answer": "10 + 5 = 15", + "solution": "【分析】左右两边相加即可求出一共有多少个.\n【详解】10 + 5 = 15 (个),一共有 15 个杯子。", + "knowledge_points": [ + "图文问题", + "不进位加法(20以内)" + ], + "source": "24-25 一年级上·湖南株洲·期末" + }, + { + "id": "84", + "unit": "第二单元 11~20的认识和加、减法", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式.\n\n![](images/dda0544efa3102f0be59b7a2d47cf41e350fa4dba51ab9fcdfdee32bc2a47ee4.jpg)\n\n□ ○ □ = □(根)", + "options": [ + + ], + "answer": "16 - 4 = 12", + "solution": "【分析】根据题图可知,总数量减去篮子外面的 4 根,等于篮子里的数量,据此解答.\n【详解】根据分析可得:16 - 4 = 12 (根),篮子里有 12 根。", + "knowledge_points": [ + "图文问题", + "不退位减法(20以内)" + ], + "source": "24-25 一年级上·山东济南·期末" + }, + { + "id": "85", + "unit": "第二单元 11~20的认识和加、减法", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式计算.\n\n![](images/0ecb764fb31e5187a6e77fdc33818a02d4e44b01c21a7ba59fc5356627b813bd.jpg)\n\n□ ○ □ = □(个)", + "options": [ + + ], + "answer": "16 - 6 = 10", + "solution": "【分析】用一共的个数减左边的个数即可求出右边的个数.\n【详解】16 - 6 = 10 (个),右边有 10 个。", + "knowledge_points": [ + "图文问题", + "不退位减法(20以内)" + ], + "source": "24-25 一年级上·甘肃平凉·期末" + }, + { + "id": "86", + "unit": "第二单元 11~20的认识和加、减法", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式计算.\n\n![](images/39e4fa5d332965d4ffe4354e68321f7191e5fe657b99b44206f6de1d89b993a2.jpg)\n\n□ ○ □ = □(支)", + "options": [ + + ], + "answer": "19 - 3 = 16", + "solution": "【分析】用一共的 19 支减去右边的 3 支即可求出左边的支数.\n【详解】19 - 3 = 16 (支)左边有 16 支。", + "knowledge_points": [ + "图文问题", + "不退位减法(20以内)" + ], + "source": "24-25 一年级上·湖南湘西·期末" + }, + { + "id": "87", + "unit": "第二单元 11~20的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.65, + "question": "公交车上原来有 12 人,第一站上来 3 人,下去 2 人;第二站又上来 4 人,现在公交车上有多少人。", + "options": [ + + ], + "answer": "17人", + "solution": "【分析】根据公交车上原来有的人数 + 上来的人数 - 下去的人数 = 第一站后公交车上的人数,列出算式算出答案即可知道第一站后公交车上一共有多少人。根据第一站后公交车上的人数 + 第二站上来的人数 = 第二站后公交车上的人数,列出算式算出答案即可求得现在公交车上的人数.\n【详解】12 + 3 - 2= 15 - 2 =13 (人);13 + 4 = 17 (人);答:现在公交车上有 17 人。", + "knowledge_points": [ + "不进位加法(20以内)", + "加减混合运算(20以内)" + ], + "source": "24-25 一年级下·黑龙江佳木斯·期末" + }, + { + "id": "88", + "unit": "第二单元 11~20的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.65, + "question": "一排同学排成一队去看动物标本。从排头数起,奇奇是第11人;从排尾数起,奇奇是第7人。问这队一共有多少同学。", + "options": [ + + ], + "answer": "17名", + "solution": "【分析】根据题意,从排头数到奇奇有 11 人,从排尾数到奇奇有 7 人,都数了奇奇,则从排头数到奇奇的人数 + 从排尾数到奇奇的人数 -1 (重复数的一次奇奇) = 总人数.\n【详解】11 + 7 - 1 = 17 (名),答:这队一共有 17 名同学。", + "knowledge_points": [ + "不进位加法(20以内)", + "加减混合运算(20以内)" + ], + "source": "24-25 一年级下·安徽芜湖·期中" + }, + { + "id": "89", + "unit": "第二单元 11~20的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.65, + "question": "停车场上原有 15 辆汽车,开走了 4 辆,又开进来 8 辆,现在有多少辆汽车。", + "options": [ + + ], + "answer": "19辆", + "solution": "【分析】用原来的数量减开走了的数量,再加又开进来的数量即可求出现在有多少辆汽车.\n【详解】15 - 4 + 8 = 11 + 8 = 19 (辆),答:现在有 19 辆汽车。", + "knowledge_points": [ + "加减混合运算(20以内)" + ], + "source": "24-25 一年级下·河北石家庄·期中" + }, + { + "id": "90", + "unit": "第二单元 11~20的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "树上的鸟先飞走 13 只,又飞走 6 只,两次飞走多少只鸟。", + "options": [ + + ], + "answer": "19只", + "solution": "【分析】题目要求两次飞走的鸟的总数,需将两次飞走的数量相加.\n【详解】13 + 6 = 19(只);答:两次飞走 19 只鸟。", + "knowledge_points": [ + "不进位加法 (20以内)" + ], + "source": "24-25 一年级下·湖北黄石·期中" + }, + { + "id": "91", + "unit": "第二单元 11~20的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.65, + "question": "小云和小宇共折了,15朵纸花,小宇折了4朵,其中有3朵红花,小云折了多少朵花。", + "options": [ + + ], + "answer": "11朵", + "solution": "【分析】由题意可知:用小云和小宇共折的纸花数减去小宇折的,等于小云折的。据此解答.\n【详解】由分析可得:15 - 4 = 11 (朵);答:小云折了 11 朵花。", + "knowledge_points": [ + "不退位减法 (20以内)" + ], + "source": "24-25 一年级下·湖北黄石·期中" + }, + { + "id": "92", + "unit": "第二单元 11~20的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.65, + "question": "小红有 13 朵鲜花,送给小明 3 朵,又送给小丽 2 朵,小红还剩多少朵。", + "options": [ + + ], + "answer": "8朵", + "solution": "【分析】根据题意,求小红还剩多少朵,用小红有鲜花的总朵数,减去送给小明的朵数,再减去又送给小丽的朵数,即可求出小红还剩的朵数,据此解答.\n【详解】由分析可得:13 - 3 - 2 = 10 - 2= 8 (朵);答:小红还剩 8 朵。", + "knowledge_points": [ + "连减 (20以内)" + ], + "source": "24-25 一年级下·河北承德·期中" + }, + { + "id": "93", + "unit": "第二单元 11~20的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.65, + "question": "明明和红红一起折了 19 个纸飞机,其中红色有 9 个,明明折了 6 个,红红折了多少个。", + "options": [ + + ], + "answer": "13个", + "solution": "【分析】根据减法的意义,明明和红红折纸飞机的总数量 - 明明折的数量 = 红红折的数量,与纸飞机的颜色无关.\n【详解】19 - 6 = 13 (个);答:红红折了 13 个。", + "knowledge_points": [ + "含有多余条件的实际问题", + "不退位减法(20以内)" + ], + "source": "24-25 一年级下·河南南阳·期中" + }, + { + "id": "94", + "unit": "第二单元 11~20的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "王老师要把 18 本书分给果果和东东,果果 6 本,东东几本。", + "options": [ + + ], + "answer": "12本", + "solution": "【分析】根据减法的意义,书的总数量 - 分给果果的数量 = 分给东东的数量.\n【详解】18 - 6 = 12 (本);答:东东 12 本。", + "knowledge_points": [ + "不退位减法 (20以内)" + ], + "source": "24-25 二年级下·辽宁鞍山·期中" + }, + { + "id": "95", + "unit": "第二单元 11~20的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.65, + "question": "一年级(1)班开展\"收集废电池,减少污染\"活动,全班一共收集了79节废电池。乐乐收集了多少节。\n\n![](images/屏幕截图%202025-12-02%20180446.jpg)\n\n□○□=□( )", + "options": [ + + ], + "answer": "13 - 3 = 10(节)", + "solution": "【分析】用丽丽收集的废电池节数减去乐乐比她少收集的节数,即可求出乐乐收集了多少节废电池。注意 \"全班一共收集了 79 节废电池\" 这个条件与解题无关.\n【详解】13 - 3 = 10(节);答:乐乐收集了 10 节。", + "knowledge_points": [ + "图文问题", + "不退位减法(20以内)" + ], + "source": "24-25一年级下·广东汕尾·期中" + }, + { + "id": "96", + "unit": "第二单元 11~20的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "小明有 18 本故事书,借给同学 5 本,还剩多少本。", + "options": [ + + ], + "answer": "13本", + "solution": "【分析】根据减法的意义,小明原有故事书的数量 - 借给同学的数量 = 还剩的数量.\n【详解】18 - 5 = 13 (本);答:还剩 13 本。", + "knowledge_points": [ + "不退位减法 (20 以内)" + ], + "source": "24-25 一年级下·湖南岳阳·期中" + }, + { + "id": "97", + "unit": "第二单元 11~20的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "一共有多少个羽毛球!\n\n![](images/屏幕截图%202025-12-02%20181000.jpg)\n\n□○□=○ (个)", + "options": [ + + ], + "answer": "10 + 5 = 15", + "solution": "【分析】左边一筒有 10 个羽毛球,右边有 5 个,求一共有多少个羽毛球,用加法计算,即左边的数量 + 右边的数量 = 总数量.\n【详解】10 + 5 = 15 (个);答:一共有 15 个!羽毛球。", + "knowledge_points": [ + "图文问题", + "不进位加法(20以内)" + ], + "source": "24-25一年级下·广东揭阳·期中" + }, + { + "id": "98", + "unit": "第二单元 11~20的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "公交车上原来有 12人,第一站上来5人,下去3人,现在公交车上有多少人。", + "options": [ + + ], + "answer": "14人", + "solution": "【分析】先用公交车上原来的人数加上第一站上来的人数,求出和,再减去下去的人数,求出差,即可解决.\n【详解】12 + 5 - 3= 17 - 3 = 14 (人);答:现在公交车上有 14 人。", + "knowledge_points": [ + "不进位,不退位加减混合运算 (20 以内)" + ], + "source": "24-25 一年级下·湖南株洲·期中" + }, + { + "id": "99", + "unit": "第二单元 11~20的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "一辆公交车上有乘客18人,到站后下车8人,又上车7人,现在车上有多少人。\n\n□○□○□=□(人)", + "options": [ + + ], + "answer": "18 - 8 + 7 = 17", + "solution": "【分析】用车上原来的人数减下车的人数,再加上上车的人数即可求解.\n【详解】18 - 8 + 7 = 17 (人);答:现在车上有 17 人。", + "knowledge_points": [ + "加减混合运算 (20 以内)" + ], + "source": "24-25一年级下·辽宁鞍山·阶段练习" + }, + { + "id": "100", + "unit": "第二单元 11~20的认识和加、减法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "原来有 15 个苹果,吃了 4 个,还剩多少个。\n\n□ ○ □ = □ (个)", + "options": [ + + ], + "answer": "15 - 4 = 11", + "solution": "【分析】用原来的个数减吃了的个数即可求出还剩多少个.\n【详解】15 - 4 = 11(个);答:还剩 11 个。", + "knowledge_points": [ + "不退位减法 (20以内)" + ], + "source": "24-25 一年级上·湖南湘西·期末" + }, + { + "id": "101", + "unit": "11~20的认识", + "question_type": "选择题", + "difficulty": 0.85, + "question": "爸爸计划星期一带明明去世界之窗游玩,因工作原因,爸爸推迟了4天,推迟后,爸爸是星期()带明明去世界之窗游玩的。", + "options": [ + "A. 四", + "B. 五", + "C. 六" + ], + "answer": "B", + "solution": "【分析】从星期一开始,一天一天往后数 4 天,即星期二,星期三,星期四,星期五,也就是从星期一推迟 4 天后是星期五。\n\n【详解】由分析可得:爸爸计划星期一带明明去世界之窗游玩,因工作原因,爸爸推迟了4天,推迟后,爸爸是星期五带明明去世界之窗游玩的。故答案为: B", + "knowledge_points": [ + "年,月,日时间的推算" + ], + "source": "25-26 一年级上·全国·单元测试" + }, + { + "id": "102", + "unit": "11~20的认识", + "question_type": "选择题", + "difficulty": 0.85, + "question": "从 8 数到 13,一共数了()个数。", + "options": [ + "A. 5", + "B. 6", + "C. 7" + ], + "answer": "B", + "solution": "【分析】要解决\"从 8 数到 13,一共数了多少个数\"的问题,我们可以依次列举出数的数字,再数个数。从 8 开始数,依次是 8,9,10,11,12,13。然后我们来数这些数字的个数,一共是 6 个。\n\n【详解】由分析可知:从 8 数到 13,一共数了 (6) 个数。故答案为: B", + "knowledge_points": [ + "数一数", + "20以内数的排序" + ], + "source": "25-26 一年级上·全国·单元测试" + }, + { + "id": "103", + "unit": "11~20的认识", + "question_type": "选择题", + "difficulty": 0.85, + "question": "个位上是 6,十位上是 1 的数是 ( )。", + "options": [ + "A. 61", + "B. 16", + "C. 6" + ], + "answer": "B", + "solution": "【分析】数位顺序从右往左依次为个位,十位,十位上的数表示几个十,个位上的数表示几个一;1个十就在十位上写1,6个一就在个位上写6,据此可选择。\n\n【详解】由分析可得:个位上是 6,十位上是 1 的数是 16 。故答案为: B", + "knowledge_points": [ + "11~20 的认识和读写", + "20以内数的组成" + ], + "source": "2025 一年级上·全国·专题练习" + }, + { + "id": "104", + "unit": "11~20的认识", + "question_type": "选择题", + "difficulty": 0.85, + "question": "老师带着 17 个小朋友乘车,乘()号车比较合适。", + "options": [ + "A. ![](images/屏幕截图%202025-12-04%20120620.jpg)(图a)", + "B. ![](images/屏幕截图%202025-12-04%20120638.jpg)\n(图b)", + "C. ![](images/屏幕截图%202025-12-04%20120654.jpg)\n(图c)" + ], + "answer": "B", + "solution": "【分析】老师和小朋友合起来一共 18 人,所以车能乘坐的人数要大于或者等于 18 人,据此解答即可。\n\n【详解】17 + 1 = 18(人),车的限乘人数要大于或者等于 18 人。A。 图a,限乘 16,16 \u003c 18,不符合题意;B. 图b,限乘 20 人 ,20 \u003e 18,符合题意;C。图c, 限乘 12 人 ,12 \u003c 18,不符合题意。故答案为: B", + "knowledge_points": [ + "不进位加法(20以内)", + "20以内数的比大小" + ], + "source": "2025 一年级上·全国·专题练习" + }, + { + "id": "105", + "unit": "11~20的认识", + "question_type": "选择题", + "difficulty": 0.85, + "question": "宁宁每天都会写 20 个毛笔字。现在他准备写第 15 个字,说明他已经写好了多少个毛笔字。 ( )", + "options": [ + "A. 16 个", + "B. 15个", + "C. 14个" + ], + "answer": "C", + "solution": "【分析】根据题意,宁宁准备写第 15 个字,说明第 15 个还没写,从第 1 个到第 15 个一共有 15 个字,减去 1 个(第 15 个字),就是已经写好的数量。\n\n【详解】15 - 1 = 14 (个),他已经写好了 14 个毛笔字。故答案为: C", + "knowledge_points": [ + "不退位减法(20以内)" + ], + "source": "25-26 一年级上·全国·课后作业" + }, + { + "id": "106", + "unit": "11~20的认识", + "question_type": "选择题", + "difficulty": 0.65, + "question": "下面哪个数最接近 8 +4 的结果。 ( )", + "options": [ + "A. 10", + "B. 13", + "C. 15" + ], + "answer": "B", + "solution": "【分析】哪个数最接近 8 + 4 的结果,先计算 8 + 4 = 12,再逐一对比选项与 12 的差即可。\n\n【详解】8 + 4 = 12,A. 12 - 10 = 2,B. 13 - 12 = 1,C. 15 - 12 = 3,综合对比, A 选项与 12 相差 2, B 选项与 12 相差 1, C 选项与 12 相差 3,所以 B 选项最接近 8 + 4 的结果。故答案为: B", + "knowledge_points": [ + "减法表(20以内)", + "20以内数的比大小" + ], + "source": "25-26 一年级上·全国·课后作业" + }, + { + "id": "107", + "unit": "11~20的认识", + "question_type": "选择题", + "difficulty": 0.94, + "question": "再过 2 天就是小明妈妈的生日,他妈妈的生日是星期().\n\n| 日期 | 星期 |\n|----------|--------|\n| 12月8日 | 星期二 |", + "options": [ + "A. 三", + "B. 四", + "C. 五" + ], + "answer": "B", + "solution": "【分析】根据生活经验可知,每个星期有 7 天,今天星期二,再过 2 天,则用 2 加上 2 计算即可。\n\n【详解】2 + 2 = 4,则他妈妈的生日是星期四。故答案为: B", + "knowledge_points": [ + "5以内数的加法" + ], + "source": "2025 一年级上·全国·专题练习" + }, + { + "id": "108", + "unit": "11~20的认识", + "question_type": "选择题", + "difficulty": 0.85, + "question": "小明昨天做了 18 道题,今天他要做的题比昨天多,他已经做了 10 道题,至少还需要做()道题。", + "options": [ + "A. 9", + "B. 8", + "C. 7" + ], + "answer": "A", + "solution": "【分析】根据题意,先用小明昨天做题的数量减去今天已经做的数量,计算出和昨天做的一样多时,还要做的数量,要想比昨天做的多,至少多做 1 道题,则用计算出的结果再加 1 即可。\n\n【详解】由分析得:18 - 10 = 8 (道),8 + 1 = 9 (道),他至少还需要做 9 道题。故答案为: A", + "knowledge_points": [ + "不退位减法(20以内)" + ], + "source": "2025 一年级上·全国·专题练习" + }, + { + "id": "109", + "unit": "11~20的认识", + "question_type": "选择题", + "difficulty": 0.94, + "question": "与 14 相邻的数是()。", + "options": [ + "A. 12 和 13", + "B. 13 和 14", + "C. 13 和 15" + ], + "answer": "C", + "solution": "【分析】20以内数由小至大顺序为:0,1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20;和 14 相邻的数是它前一个数和它后一个数,由此解答。\n\n【详解】由分析可知:与 14 相邻的数是 13 和 15。故答案为: C", + "knowledge_points": [ + "20以内数的排序" + ], + "source": "2025 一年级上·全国·专题练习" + }, + { + "id": "110", + "unit": "11~20的认识", + "question_type": "选择题", + "difficulty": 0.85, + "question": "被减数是 15,减数是 3,差是()。", + "options": [ + "A. 18", + "B. 12", + "C. 8" + ], + "answer": "B", + "solution": "【分析】减法算式为:被减数 - 减数 = 差,由此代入计算即可。\n\n【详解】 15 - 3 = 12,被减数是 15,减数是 3,差是 12 。故答案为: B", + "knowledge_points": [ + "不退位减法(20以内)" + ], + "source": "2025 一年级上·全国·专题练习" + }, + { + "id": "111", + "unit": "11~20的认识", + "question_type": "选择题", + "difficulty": 0.85, + "question": "13 比 ( ) 少 2。", + "options": [ + "A. 11", + "B. 15", + "C. 10" + ], + "answer": "B", + "solution": "【分析】13 比一个数少 2,也就是这个数比 13 多 2,则用 13 加 2 即可计算出这个数。\n\n【详解】由分析得:13 + 2 = 15,则 13 比 15 少 2。故答案为: B", + "knowledge_points": [ + "不进位加法(20以内)" + ], + "source": "25-26 一年级上·广东深圳·月考" + }, + { + "id": "112", + "unit": "11~20的认识", + "question_type": "选择题", + "difficulty": 0.85, + "question": "下面的数中,最接近 10 的是 ( )。", + "options": [ + "A. 8", + "B. 13", + "C. 11" + ], + "answer": "C", + "solution": "【分析】根据题意,依次用减法计算出各数与 10 之间的差值,差值越小越接近。\n\n【详解】A。10 - 8 = 2,差是 2;B。13 - 10 = 3,差是 3;C。11 - 10 = 1,差是1.1 \u003c 2 \u003c 3,则最接近 10 的是 11。故答案为: C", + "knowledge_points": [ + "5 以内数的比大小", + "不退位减法(20 以内)", + "10 的加减法" + ], + "source": "25-26 一年级上·广东深圳·月考" + }, + { + "id": "113", + "unit": "11~20的认识", + "question_type": "选择题", + "difficulty": 0.85, + "question": "关于15,下列说法不正确的是()。", + "options": [ + "A. 15 是由 1 个十和 5 个一组成的", + "B. 15 读作十五", + "C. 15 后面一个数是 14" + ], + "answer": "C", + "solution": "【分析】从右边起第一位是个位,个位上是几就表示几个一;第二位是十位,十位上是几就表示几个十;再根据 20 以内的组成和排序,结合题干要求进行解答即可。\n\n【详解】A。15是由1个十和5个一组成的,说法正确;B. 15 读作:十五,说法正确;C. 15 后面一个数是 16,原选项说法错误。故答案为: C", + "knowledge_points": [ + "11~20 的认识和读写", + "20以内数的组成", + "20以内数的排序" + ], + "source": "2024 一年级上·河北·专题练习" + }, + { + "id": "114", + "unit": "11~20的认识", + "question_type": "选择题", + "difficulty": 0.85, + "question": "比 8 大,比 12 小的数有 ( ) 个。", + "options": [ + "A. 3", + "B. 4", + "C. 5" + ], + "answer": "A", + "solution": "【分析】根据题意可知:根据 20 以内数的排序把 8 - 12 之间的数写出来,并数一数即可。\n\n【详解】8,9,10,11,12。则比 8 大,比 12 小的数有 3 个。故答案为:A", + "knowledge_points": [ + "20以内数的排序", + "20以内数的比大小" + ], + "source": "25-26 二年级上·黑龙江佳木斯·开学考试" + }, + { + "id": "115", + "unit": "11~20的认识", + "question_type": "选择题", + "difficulty": 0.85, + "question": "一个数,个位和十位上的数字都是 1,这个数是 ( )。", + "options": [ + "A. 10", + "B. 11", + "C. 12" + ], + "answer": "B", + "solution": "【分析】一个整数,从右往左依次为个位,十位。由此将数字写在对应数位上即可。\n\n【详解】由分析得:一个数,个位和十位上的数字都是 1,这个数是 11。故答案为: B", + "knowledge_points": [ + "11~20 的认识和读写", + "认识个位和十位", + "20 以内数的组成" + ], + "source": "25-26 二年级上·黑龙江佳木斯·开学考试" + }, + { + "id": "116", + "unit": "11~20的认识", + "question_type": "填空题", + "difficulty": 0.94, + "question": "按规律填数.\n\n(1)3, 6, 9, (), 15, ()。 (2)5, 10, 15, ( )。", + "options": [ + + ], + "answer": "12,18;20", + "solution": "【分析】根据题意,(1)通过观察这组数据,从 3 开始,3个 3 个地数。(2) 这组数据是从 5 开始, 5 个 5 个地数。据此解答。\n\n【详解】 (1) 3, 6, 9, (12), 15, (18)。(2) 5, 10, 15, (20)。", + "knowledge_points": [ + "整数排列的规律" + ], + "source": "25-26 一年级上·全国·周测" + }, + { + "id": "117", + "unit": "11~20的认识", + "question_type": "填空题", + "difficulty": 0.85, + "question": "在括号里填上\"\u003e\"\"\u003c\"或\"=\".\n\n13 + 5 () 19;18 - 10 ( ) 8;10 + 3 ( ) 14\n\n17 - 3 ( ) 10;4 + 10 ( ) 12;12 + 3 ( ) 15", + "options": [ + + ], + "answer": "\u003c;=;\u003c;\u003e;\u003e;=", + "solution": "【分析】整数比较大小:先看位数的多少,位数多的数大;位数相同,从最高位比起,最高位上的数大这个数就大,若最高位上的数相同,就比较下一位,依次类推,直到比出大小。有算式的,先计算出算式的结果,再比较大小。\n\n【详解】 13 + 5 = 18, 18 \u003c 19,因此 13 + 5 (\u003c ) 19;18- 10=8, 8=8,因此 18-10 (=) 8;10 + 3 = 13, 13 \u003c 14,因此 10 + 3 (\u003c) 14;17 - 3 = 14, 14 \u003e 10,因此 17 - 3 (\u003e ) 10;4 + 10 = 14, 14 \u003e 12,因此 4 + 10 (\u003e ) 12;12 + 3 = 15, 15 = 15,因此 12 + 3 (=) 15 。", + "knowledge_points": [ + "不进位加法(20以内)", + "不退位减法(20以内)", + "20以内数的比大小" + ], + "source": "25-26 一年级上·全国·单元测试" + }, + { + "id": "118", + "unit": "11~20的认识", + "question_type": "填空题", + "difficulty": 0.85, + "question": "找规律填空.\n\n(1)10,12,( ),16,( ),( )。 \n(2)20,19,( ),17,( ),15,( ),13,( ),11。", + "options": [ + + ], + "answer": "14;18;20;18;16;14;12", + "solution": "【分析】(1)该组规律为:数字从左到右依次加2。(2) 该组规律为:数字从左到右依次减 1。\n\n【详解】 (1) 由分析可得:10+2=12, 12+2=14, 14+2=16, 16+2=18, 18+2=20。则填空如下:10, 12, (14), 16, (18), (20)。(2) 20 - 1 = 19, 19 - 1 = 18, 18 - 1 = 17, 17 - 1 = 16, 16 - 1 = 15, 15 - 1 = 14, 14 - 1 = 13, 13 - 1 = 12, 12 - 1 = 11 。填空如下:20, 19, (18), 17, (16), 15, (14), 13,(12) , 11。", + "knowledge_points": [ + "不进位加法(20以内)", + "不退位减法(20以内)", + "整数排列的规律" + ], + "source": "25-26 一年级上·全国·单元测试" + }, + { + "id": "119", + "unit": "11~20的认识", + "question_type": "填空题", + "difficulty": 0.85, + "question": "在括号里填上合适的数.\n\n14 + ( ) = 17;10 + ( ) = 15;11 + ( ) = 16", + "options": [ + + ], + "answer": "3;5;5", + "solution": "【分析】根据 20 以内不进位加法运算,结合题干要求进行解答即可。\n\n【详解】14 + 3 = 17,所以括号内填 3.10 + 5 = 15,所以括号内填 5.11 + 5 = 16,所以括号内填 5 。", + "knowledge_points": [ + "不进位加法 (20以内)" + ], + "source": "25-26 一年级上·全国·单元测试" + }, + { + "id": "120", + "unit": "11~20的认识", + "question_type": "填空题", + "difficulty": 0.85, + "question": "16 是 12 后面第( )个数,是 18 前面第( )个数。", + "options": [ + + ], + "answer": "42", + "solution": "【分析】20 以内的数由小到大依次是 0,1,。,12,13,14,15,16,17,18,19,20,由此可知 16是 12 后面的第 4 个数,是 18 前面的第 2 个数。\n\n【详解】由分析可知:16 是 12 后面第 (4) 个数,是 18 前面第 (2) 个数。", + "knowledge_points": [ + "20以内数的排序" + ], + "source": "25-26 一年级上·全国·单元测试" + }, + { + "id": "121", + "unit": "11~20的认识", + "question_type": "填空题", + "difficulty": 0.85, + "question": "被减数是 14,减数是 10,差是( )。", + "options": [ + + ], + "answer": "4", + "solution": "【分析】减法算式中,被减数 - 减数 = 差,据此计算即可。\n\n【详解】14 - 10 = 4,被减数是 14,减数是 10,差是 (4)", + "knowledge_points": [ + "不退位减法 (20 以内)" + ], + "source": "25-26 一年级上·全国·单元测试" + }, + { + "id": "122", + "unit": "11~20的认识", + "question_type": "填空题", + "difficulty": 0.85, + "question": "在括号里填上\"\u003e\"或\"\u003c\"或\"=\".\n\n1 ( ) 15 - 10;10 ( ) 9;13 ( ) 16 - 3;6 ( ) 4 + 3\n\n9 + 1 ( ) 10;16 ( ) 8 + 10;20 ( ) 12;8 + 2 ( ) 9", + "options": [ + + ], + "answer": "\u003c;\u003e;=;\u003c;=;\u003c;\u003e", + "solution": "【分析】比较数的大小,先看位数的多少,位数多的数就大;位数相同,从最高位开始比较,最高位上的数大则这个数大,最高位上的数相同,就比较下一位,依次类推。含有算式的,先计算出各算式的结果,再比较大小。\n\n【详解】15 - 10 = 5,故,1 \u003c 15 - 10;10 \u003e 9;16 - 3 = 13,即, 13 = 16 - 3;4 + 3 = 7,故, 6 \u003c 4 + 3;9 + 1 = 10;8 + 10 = 18,故, 16 \u003c 8 + 10;20 \u003e 12;8 + 2 = 10,故,8 + 2 \u003e 9 。", + "knowledge_points": [ + "不进位加法(20以内)", + "不退位减法(20以内)", + "10的加减法", + "20以内数的比大小" + ], + "source": "2025 一年级上·全国·专题练习" + }, + { + "id": "123", + "unit": "11~20的认识", + "question_type": "填空题", + "difficulty": 0.65, + "question": "小朋友们排成一列向前走,芳芳排第10,明明排第14,芳芳和明明之间有( )个小朋友。", + "options": [ + + ], + "answer": "3", + "solution": "【分析】先用 14 减去 10,求出差里面还包含明明,再减去 1,求出差就是芳芳和明明之间有几个小朋友。\n\n【详解】 14 - 10 - 1= 4 - 1= 3 (个),芳芳和明明之间有 3 个小朋友。", + "knowledge_points": [ + "不进位,不退位连加,连减(20以内)" + ], + "source": "2025 一年级上·全国·专题练习" + }, + { + "id": "124", + "unit": "11~20的认识", + "question_type": "填空题", + "difficulty": 0.65, + "question": "小猴和小兔做游戏,数了一下共 20 只小动物。奇怪的是,从这 20 只小动物中任选2只,总有小猴,小猴有( )只。", + "options": [ + + ], + "answer": "19", + "solution": "【分析】根据题意,一共有 20 只小动物,每次任选 2 只都有小猴,也就是无论怎么选,都不能出现有 2 只小兔的情况,小兔的数量也就是少于 2 只,则小兔可能有 1 只或 0 只,而题干说小猴和小兔做游戏,也就是必须有小兔,则小兔有 1 只,剩下的都是小猴。\n\n【详解】由分析得:小兔有 1 只,剩余的都是小猴。红色的表示小兔,没涂颜色的表示小猴。![](images/6cf36dd1db5f0828662be1c4ff3020a872e23db246a2c2f4c11d769e269d9b94.jpg)则小猴有 19 只。", + "knowledge_points": [ + "11~20 的认识和读写" + ], + "source": "25-26 一年级上·全国·课后作业" + }, + { + "id": "125", + "unit": "11~20的认识", + "question_type": "填空题", + "difficulty": 0.85, + "question": "太极拳的李教练想和学号是 10~16 的小朋友一起上台表演,表演的一共有( )人。", + "options": [ + + ], + "answer": "8", + "solution": "【分析】根据题意,先按顺序数出学号是 10~16 的一共有多少小朋友,再将小朋友的人数与教练的人数相加,即可计算出总人数。\n\n【详解】由分析得:10~16 依次为: 10, 11, 12, 13, 14, 15, 16,共 7 个小朋友。7 + 1 = 8 (人),太极拳的李教练想和学号是 10~16 的小朋友一起上台表演,表演的一共有 8 人。", + "knowledge_points": [ + "8,9 的加减法", + "20 以内数的排序" + ], + "source": "25-26 一年级上·全国·课后作业" + }, + { + "id": "126", + "unit": "11~20的认识", + "question_type": "填空题", + "difficulty": 0.65, + "question": "丁丁在计数器上拨了 6 颗算珠表示一个数,这个数比 10 大,比 19 小,丁丁拨的数是( )。", + "options": [ + + ], + "answer": "15", + "solution": "【分析】20以内数从大到小关系为: 20 \u003e 19 \u003e 18 \u003e 17 \u003e 16 \u003e15 \u003e 14 \u003e 13 \u003e 12 \u003e 11 \u003e 10 \u003e 9 \u003e 8 \u003e 7 \u003e 6 \u003e 5 \u003e 4 \u003e 3 \u003e 2\u003e1,由此找到比 10 大比 19 小的数。用计数器表示数时,十位是几就拨几颗珠子,表示几个十,个位是几就拨几颗珠子,表示几个一,找到用 6 颗算珠拨出的数即可。\n\n【详解】由分析得:比10大比19小的数有:11, 12, 13, 14, 15, 16, 17, 18.11:十位拨 1 颗,个位拨 1 颗,一共拨 2 颗,不符合题意;12:十位拨 1 颗,个位拨 2 颗,一共拨 3 颗,不符合题意;13:十位拨 1 颗,个位拨 3 颗,一共拨 4 颗,不符合题意;14:十位拨 1 颗,个位拨 4 颗,一共拨 5 颗,不符合题意;15:十位拨 1 颗,个位拨 5 颗,一共拨 6 颗,符合题意;16:十位拨 1 颗,个位拨 6 颗,一共拨 7 颗,不符合题意;17:十位拨 1 颗,个位拨 7 颗,一共拨 8 颗,不符合题意;18:十位拨 1 颗,个位拨 8 颗,一共拨 9 颗,不符合题意。丁丁在计数器上拨了 6 颗算珠表示一个数,这个数比 10 大,比 19 小,丁丁拨的数是 15。", + "knowledge_points": [ + "20以内数的组成", + "20以内数的比大小" + ], + "source": "25-26 一年级上·全国·课后作业" + }, + { + "id": "127", + "unit": "11~20的认识", + "question_type": "填空题", + "difficulty": 0.65, + "question": "我的十位和个位上的数相同,且小于 20,我是( )。", + "options": [ + + ], + "answer": "11", + "solution": "【分析】十位和个位上的数相同,说明这个数是两位数;且小于 20,那这个数的范围在 10 至 19 之间,十位和个位的数相同,十位是 1,个位是 1,符合题意,那么这个数为 11。\n\n【详解】我的十位和个位上的数相同,且小于 20,我是 11。", + "knowledge_points": [ + "20以内数的组成" + ], + "source": "25-26 一年级上·全国·课后作业" + }, + { + "id": "128", + "unit": "11~20的认识", + "question_type": "填空题", + "difficulty": 0.94, + "question": "在括号里填上\"\u003e\"或\"\u003c\".\n\n10( )11;18( )15;20( )19", + "options": [ + + ], + "answer": "\u003c;\u003e;\u003e", + "solution": "【分析】20以内数由小至大关系为: 0 \u003c 1 \u003c 2 \u003c 3 \u003c 4 \u003c 5 \u003c 6 \u003c 7 \u003c 8 \u003c 9 \u003c 10 \u003c 11 \u003c 12 \u003c 13 \u003c 14 \u003c 15 \u003c 16 \u003c 17 \u003c 18 \u003c 19 \u003c 20;由大至小关系为: 20 \u003e 19 \u003e 18 \u003e 17 \u003e 16 \u003e 15 \u003e 14 \u003e 13 \u003e12 \u003e 11 \u003e 10 \u003e 9 \u003e 8 \u003e 7 \u003e 6 \u003e 5 \u003e 4 \u003e 3 \u003e 2 \u003e 1 \u003e 0,由此比较。\n\n【详解】由分析得:10 \u003c 11;18 \u003e 15;20 \u003e 19", + "knowledge_points": [ + "20以内数的比大小" + ], + "source": "25-26 一年级上·全国·课后作业" + }, + { + "id": "129", + "unit": "11~20的认识", + "question_type": "填空题", + "difficulty": 0.65, + "question": "我的个位上是 7,比十位上的数大 6,我是( )。", + "options": [ + + ], + "answer": "17", + "solution": "【分析】个位上是 7,比十位上的数大 6,那么十位上的数是 7 - 6 = 1,这个数是 17 。\n\n【详解】个位上是 7,比十位上的数大 6,那么十位上的数是:7 - 6 = 1,我的个位是 7,十位是 1,我是 17 。", + "knowledge_points": [ + "20以内数的组成" + ], + "source": "25-26 一年级上·全国·课后作业" + }, + { + "id": "130", + "unit": "11~20的认识", + "question_type": "填空题", + "difficulty": 0.94, + "question": "欣欣看一本书,第一天看了 10 页,第二天看了 3 页,第三天从第( )页开始看。", + "options": [ + + ], + "answer": "14", + "solution": "【分析】根据题意,先用第一天看的页数和第二天看的页数相加,计算出两天一共看的页数,第三天开始看的页数是前两天看的总页数的下一页,用计算出的结果再加 1 即可。\n\n【详解】 10 + 3 + 1 = 14 (页),欣欣看一本书,第一天看了 10 页,第二天看了 3 页,第三天从第 14 页开始看。", + "knowledge_points": [ + "不进位,不退位连加,连减(20以内)" + ], + "source": "25-26 一年级上·全国·课后作业" + }, + { + "id": "131", + "unit": "11~20的认识", + "question_type": "填空题", + "difficulty": 0.94, + "question": "我的十位上是 1,个位上是最大的一位数,我是( )。", + "options": [ + + ], + "answer": "19", + "solution": "【分析】一个整数,从右往左依次为个位,十位。最大的一位数是 9,将数字写在对应数位上即可。\n\n【详解】由分析得:我的十位上是 1,个位上是最大的一位数,我是 19。", + "knowledge_points": [ + "认识个位和十位", + "20以内数的组成" + ], + "source": "25-26 一年级上·全国·课后作业" + }, + { + "id": "132", + "unit": "11~20的认识", + "question_type": "填空题", + "difficulty": 0.94, + "question": "算一算,填一填.\n\n10 + ( ) = 12;5 + ( ) = 15;( ) + 6= 16\n\n3 + ( ) = 13;10 + ( ) = 20;( ) + 10 = 18", + "options": [ + + ], + "answer": "2;10;10;10;10;8", + "solution": "【分析】根据加数 + 加数 = 和,可转换为和 - 加数 = 另一个加数,代入计算即可。\n\n【详解】因为 12 - 10 = 2,所以 10 + 2 = 12;因为 15 - 5 = 10,所以 5 + 10 = 15;因为 16 - 6 = 10,所以 10 + 6 = 16;因为 13 - 3 = 10,所以 3 + 10 = 13;因为 20 - 10 = 10,所以 10 + 10 = 20;因为 18 - 10 = 8,所以 8 + 10 = 18 。", + "knowledge_points": [ + "不进位加法(20以内)", + "不退位减法(20以内)" + ], + "source": "25-26 一年级上·全国·课后作业" + }, + { + "id": "133", + "unit": "11~20的认识", + "question_type": "填空题", + "difficulty": 0.85, + "question": "在括号里填上合适的数.\n\n10 - ( ) = 10;7 + ( ) = 9;9 - ( ) = 3;9 - 5 + ( ) = 10;5 + 5 = ( ) + ( );( ) - ( ) = 3 + 3", + "options": [ + + ], + "answer": "0;2;6;6;2;8;16;10", + "solution": "【分析】第1,3题根据被减数 - 差 = 减数计算;第2题根据和 - 一个加数 = 另一个加数计算;第 4 题先计算出 9 - 5 的差,再根据和 - 一个加数 = 另一个加数计算;第 5 题先计算出左侧算式的结果,再写出和这个结果相同的加法算式即可;第 6 题先计算出右侧算式的结果,再写出和这个结果相同的减法算式即可。\n\n【详解】10 - 10 = 0,则 10 - 0 = 10;9 - 7 = 2,则 7 + 2 = 9;9 - 3 = 6,则 9 - 6 = 3;9 - 5 = 4;10 - 4 = 6,则 9 - 5 + 6 = 10;5 + 5 = 10;则 5 + 5 = 2 + 8 (答案不唯一);3 + 3 = 6;则 16 - 10 = 3 + 3(答案不唯一)。", + "knowledge_points": [ + "加减混合运算(10以内)", + "不退位减法(20以内)", + "10的加减法" + ], + "source": "2025 一年级上·全国·专题练习" + }, + { + "id": "134", + "unit": "11~20的认识", + "question_type": "填空题", + "difficulty": 0.85, + "question": "比 11 大 3 的数是( ), 比 18 小 5 的数是( )。", + "options": [ + + ], + "answer": "14;13", + "solution": "【分析】比11大3的数,用11加3计算;比18小5的数,用 18 减 5 计算。\n\n【详解】11 + 3 = 14;18 - 5 = 13;比 11 大 3 的数是 14,比 18 小 5 的数是 13。", + "knowledge_points": [ + "不进位加法(20以内)", + "不退位减法(20以内)" + ], + "source": "25-26 一年级上·广东深圳·月考" + }, + { + "id": "135", + "unit": "11~20的认识", + "question_type": "填空题", + "difficulty": 0.85, + "question": "在括号里填\"\u003e\"或\"\u003c\"或\"=\".\n\n12( )14;9( )19-10;8+2( )10", + "options": [ + + ], + "answer": "\u003c;=;=", + "solution": "【分析】根据题意,依次计算出各算式的结果再比较大小。20以内数从大到小关系为 20 \u003e 19 \u003e 18 \u003e 17 \u003e 16 \u003e 15 \u003e 14\u003e 13 \u003e 12 \u003e 11 \u003e 10 \u003e 9 \u003e 8 \u003e 7 \u003e 6 \u003e 5 \u003e 4 \u003e 3 \u003e 2 \u003e 1 \u003e 0,由此比较。\n\n【详解】12 \u003c 14;9 = 19 - 10;8 + 2 = 10。", + "knowledge_points": [ + "不退位减法(20以内)", + "10的加减法", + "20以内数的比大小" + ], + "source": "25-26 一年级上·广东深圳·月考" + }, + { + "id": "136", + "unit": "11~20的认识", + "question_type": "填空题", + "difficulty": 0.85, + "question": "小米昨天学了中国功夫的3个动作,今天又学了14个,明天应该从第( )个动作学起。", + "options": [ + + ], + "answer": "18", + "solution": "【分析】用昨天学中国功夫的动作个数加上今天又学的个数,可以求出一共学了几个动作,求明天应该从第几个动作学起,在一共学了几个动作的基础上,再加 1 即可。\n\n【详解】3 + 14 = 17(个) ,17 + 1 = 18(个),小米昨天学了中国功夫的 3 个动作,今天又学了 14 个,明天应该从第 18 个动作学起。", + "knowledge_points": [ + "不进位加法(20以内)" + ], + "source": "24-25 一年级上·江苏·单元测试" + }, + { + "id": "137", + "unit": "11~20的认识", + "question_type": "填空题", + "difficulty": 0.85, + "question": "1 个十和 4 个一合起来是( ),与 13 相邻的两个数是( )和( ),6 和 12 之间有( )个数。", + "options": [ + + ], + "answer": "14;12;14;5", + "solution": "【分析】1 个十是 10, 4 个一是 4,合起来是 14;与 13 相邻的两个数,即 13 前一个数 12 和后一个数 14;6 和 12 之间的数,从 7 开始数到 11,分别是 7,8,9,10,11,共 5 个数。\n\n【详解】根据分析可得:1个十和4个一合起来是14,与13相邻的两个数是12和14, 6 和 12 之间有 5 个数。", + "knowledge_points": [ + "20以内数的组成", + "20以内数的排序" + ], + "source": "25-26 一年级上·全国·课后作业" + }, + { + "id": "138", + "unit": "11~20的认识", + "question_type": "填空题", + "difficulty": 0.85, + "question": "在括号里填上\"\u003e\" \"\u003c\"或\"=\".\n\n11 + 2 ( ) 16;12 + 5 ( ) 17 - 5;16 - 6 ( ) 10 \n18 - 5 ( ) 13;11 + 7 ( ) 19;4 + 13 ( ) 16", + "options": [ + + ], + "answer": "\u003c;\u003e;=;\u003c;\u003e", + "solution": "【分析】先计算给出的算式得数,在进行数字之间的比较。\n\n【详解】11 + 2 = 13, 13 \u003c 16,所以 11 + 2 \u003c 16;12 + 5 = 17, 17 - 5 = 12, 17 \u003e 12,所 以 12 + 5 \u003e 17 - 5;16 - 6 = 10,所 以16 - 6 = 10;18 - 5 = 13,所 以 18 - 5 = 13;11 + 7 = 18, 18 \u003c 19,所 以11 + 7 \u003c 19;4 + 13 = 17, 17 \u003e 16, 4 + 13 \u003e 16 。", + "knowledge_points": [ + "不进位加法(20以内)", + "不退位减法(20以内)", + "20以内数的比大小" + ], + "source": "25-26 一年级上·全国·课后作业" + }, + { + "id": "139", + "unit": "11~20的认识", + "question_type": "填空题", + "difficulty": 0.85, + "question": "在括号里填上 \"\u003e\" \"\u003c\" 或 \"=\".\n\n4 + 13 ( ) 18;13 ( ) 16 - 3;10 + 7 ( ) 17 - 10\n\n19 - 5 ( ) 14;14 ( ) 19 - 6;16 - 10 ( ) 16 - 6", + "options": [ + + ], + "answer": "\u003c;=;\u003e;=;\u003e;\u003c", + "solution": "【分析】根据整数加减法的计算法则,依次计算出各算式的结果再比较大小。20以内数从大到小关系为: 20 \u003e 19\u003e 18 \u003e 17 \u003e 16 \u003e 15 \u003e 14 \u003e 13 \u003e 12 \u003e 11 \u003e 10 \u003e 9 \u003e 8 \u003e 7 \u003e 6 \u003e 5\u003e 4 \u003e 3 \u003e 2 \u003e 1 \u003e 0,由此比较。\n\n【详解】4 + 13 = 17,故,4 + 13 \u003c 1816 - 3 = 13,故,13 = 16 - 310 + 7 = 17,17 - 10 = 7,故,10 + 7 \u003e 17 - 1019 - 5 = 1419 - 6 = 13,故, 14 \u003e 19 - 6,16 - 10 = 6, 16 - 6 = 10,故, 16 - 10 \u003c 16 - 6 。", + "knowledge_points": [ + "不进位加法(20以内)", + "不退位减法(20以内)", + "20以内数的比大小" + ], + "source": "25-26 一年级上·全国·课后作业" + }, + { + "id": "140", + "unit": "11~20的认识", + "question_type": "解答题", + "difficulty": 0.65, + "question": "猫小花和猫小咪去钓鱼,根据下面的对话想一想,猫小花钓了( )条鱼.\n\n![](images/306e1aa85322e431f796e43ebdb77f05ebf39f9f5d70d25424871f071f6efc3b.jpg)", + "options": [ + + ], + "answer": "19", + "solution": "【分析】已知猫小咪钓了 18 条鱼,猫小花钓了不到 20 条鱼,但是比喵小咪的 18 条多,所以她钓的数量在 18 和 20 中间,根据 20 以内数字的顺序,即可得出 18 和 20 中间的数字是 19。\n\n【详解】据分析可得:18,19,20;所以,猫小花和猫小咪去钓鱼,根据下面的对话想一想,猫小花钓了 19 条鱼。", + "knowledge_points": [ + "20以内数的排序", + "20以内数的比大小" + ], + "source": "25-26 一年级上·全国·课后作业" + }, + { + "id": "141", + "unit": "11~20的认识", + "question_type": "填空题", + "difficulty": 0.85, + "question": "顺着数数:\n\n8,9,( ),( ),12,13.\n\n反着数数:21,20,( ),( ),17。", + "options": [ + + ], + "answer": "10;11;19;18", + "solution": "【分析】观察可知,顺着数数,根据 20 以内数的排列顺序,从 8 开始后面的数比前面的数大 1;反着数数:从 21 开始后面的数比前面的数小 1;据此填空。\n\n【详解】由分析可得:8,9,10,11,12,13.21,20,19,18,17。", + "knowledge_points": [ + "整数排列的规律", + "20以内数的排序" + ], + "source": "25-26 一年级上·湖南永州·开学考试" + }, + { + "id": "142", + "unit": "11~20的认识", + "question_type": "填空题", + "difficulty": 0.85, + "question": "11月9日是全国消防日,星海社区将进行为期三天的消防安全排查,到11月( )日结束。", + "options": [ + + ], + "answer": "11", + "solution": "【分析】根据题意,消防安全排查从11月9日开始,持续三天,第一天是9日,第二天是10日,第三天是11日。因此,结束日期是11月11日。\n\n【详解】根据分析可得:11月9日是全国消防日,星海社区将进行为期三天的消防安全排查,到11月11日结束。", + "knowledge_points": [ + "两个数之间有几个数" + ], + "source": "2025 一年级上·全国·专题练习" + }, + { + "id": "143", + "unit": "11~20的认识", + "question_type": "填空题", + "difficulty": 0.94, + "question": "被减数是18,减数是6,差是( )。", + "options": [ + + ], + "answer": "12", + "solution": "【分析】根据\"被减数 - 减数 = 差\"来解决此题。\n\n【详解】 18 - 6 = 12,被减数是 18,减数是 6,差是 12。", + "knowledge_points": [ + "不退位减法(20以内)" + ], + "source": "24-25 一年级上·河北·单元测试" + }, + { + "id": "144", + "unit": "11~20的认识", + "question_type": "填空题", + "difficulty": 0.65, + "question": "18 = 10+ ( );16= ( ) + 6;19 = ( ) + ( )", + "options": [ + + ], + "answer": "8;10;10;9", + "solution": "【分析】①②根据加数 = 和-另一个加数即可求出。③④根据 20 以内加法选择两数相加得 19 即可。\n\n【详解】18 - 10 = 8,则 18 = 10 + 8;16 - 6 = 10,则 16 = 10 + 6;19 = 10 + 9 。", + "knowledge_points": [ + "不进位加法(20以内)", + "不退位减法(20以内)" + ], + "source": "25-26 一年级上·江苏·课后作业" + }, + { + "id": "145", + "unit": "11~20的认识", + "question_type": "填空题", + "difficulty": 0.85, + "question": "7 + ( ) = 10;10 ( ) = 12;11 + ( ) = 13", + "options": [ + + ], + "answer": "3;2;2", + "solution": "【分析】一个加数 = 和 - 另一个加数,根据加减法各部分间的关系计算。\n\n【详解】10 - 7 = 3,故 7 + 3 = 10.12 - 10 = 2,故 10 + 2 = 12.13 - 11 = 2,故 11 + 2 = 13 。", + "knowledge_points": [ + "不进位加法(20以内)", + "不退位减法(20以内)", + "10的加减法" + ], + "source": "25-26 一年级上·全国·课后作业" + }, + { + "id": "146", + "unit": "11~20的认识", + "question_type": "填空题", + "difficulty": 0.85, + "question": "在括号里填上\"\u003e\" \"\u003c\"或\"=\".\n\n15( )16;9( )11;20( )19\n\n10+7( )14;19-5( )14;16-6( )12", + "options": [ + + ], + "answer": "\u003c;\u003c;\u003e;\u003e;=;\u003c", + "solution": "【分析】根据整数加减法的计算法则,依次计算出各算式的结果再比较大小。20 以内数从大到小关系为: 20 \u003e 19\u003e18 \u003e 17 \u003e 16 \u003e 15 \u003e 14 \u003e 13 \u003e 12 \u003e 11 \u003e 10 \u003e 9 \u003e 8 \u003e 7 \u003e 6 \u003e 5\u003e4 \u003e 3 \u003e 2 \u003e 1 \u003e 0,由此比较。\n\n【详解】15 \u003c 16;9 \u003c 11;20 \u003e 19;10 + 7 = 17, 17 \u003e 14,故 10 + 7 \u003e 14.19 - 5 = 14, 14 = 14,故 19 - 5 = 14.16 - 6 = 10, 10 \u003c 12,故 16 - 6 \u003c 12 。", + "knowledge_points": [ + "不进位加法(20以内)", + "不退位减法(20以内)", + "20以内数的比大小" + ], + "source": "25-26 一年级上·全国·课后作业" + }, + { + "id": "147", + "unit": "11~20的认识", + "question_type": "填空题", + "difficulty": 0.85, + "question": "与13相邻的两个数,较小的是( ), 较大的是( )。", + "options": [ + + ], + "answer": "12;14", + "solution": "【分析】20以内数由小至大的排列规律:0,1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20;根据规律找出与 13 相邻的两个数,较小的是 13 前一个数,较大的数是 13 后一个数,据此解答。\n\n【详解】因此,与 13 相邻的两个数中,较小的是 12,较大的是 14。", + "knowledge_points": [ + "20以内数的排序" + ], + "source": "25-26 二年级上·黑龙江佳木斯·开学考试" + }, + { + "id": "148", + "unit": "11~20的认识", + "question_type": "填空题", + "difficulty": 0.85, + "question": "写出和 15相邻的两个数,分别是( )和( )。", + "options": [ + + ], + "answer": "14;16", + "solution": "【分析】从 1 数到 20 依次为:1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15,16, 17, 18, 19, 20,据此找出对应的数即可。\n\n【详解】写出和 15 相邻的两个数,分别是 14 和 16。", + "knowledge_points": [ + "20以内数的排序" + ], + "source": "25-26 二年级上·黑龙江佳木斯·开学考试" + }, + { + "id": "149", + "unit": "11~20的认识", + "question_type": "填空题", + "difficulty": 0.85, + "question": "倒着数,补充完整:20,19,( ),17,( ),( ),14,( ),12。", + "options": [ + + ], + "answer": "18;16;15;13", + "solution": "【分析】从 20 倒着数到 1 依次为:20, 19, 18, 17, 16, 15, 14, 13, 12, 11, 10, 9, 8, 7, 6, 5, 4, 3, 2, 1,据此填空即可。\n\n【详解】倒着数,补充完整:20, 19, 18, 17, 16, 15, 14, 13, 12。", + "knowledge_points": [ + "20以内数的排序" + ], + "source": "25-26 二年级上·黑龙江佳木斯·开学考试" + }, + { + "id": "150", + "unit": "11~20的认识", + "question_type": "填空题", + "difficulty": 0.85, + "question": "在括号里填上 \"\u003e\" \"\u003c\" 或 \"=\".\n\n4( )6;8( )8;12( )10;3+2( )4;9-4( )6", + "options": [ + + ], + "answer": "\u003c;=;\u003e;\u003c", + "solution": "【分析】根据题意,有算式的依次计算出各算式的结果再比较大小。20 以内数从大到小关系为: 20 \u003e 19\u003e 18 \u003e 17 \u003e 16 \u003e 15 \u003e 14 \u003e 13 \u003e 12 \u003e 11 \u003e 10 \u003e 9 \u003e 8 \u003e 7 \u003e 6 \u003e 5\u003e 4 \u003e 3 \u003e 2 \u003e 1 \u003e 0,由此比较。\n\n【详解】4 \u003c 6;8 = 8;12 \u003e 10;3 + 2 = 5;5 \u003e 4,则3 + 2 \u003e 4;9 - 4 = 5;5 \u003c 6,则9 - 4 \u003c 6 。", + "knowledge_points": [ + "8,9 的加减法", + "5 以内数的加法", + "20 以内数的比大小" + ], + "source": "25-26 一年级上·全国·课后作业" + }, + { + "id": "151", + "unit": "11~20的认识", + "question_type": "填空题", + "difficulty": 0.85, + "question": "13 前面的第 4 个数是( )。", + "options": [ + + ], + "answer": "9", + "solution": "【分析】13前面的数是比它小的数。13前面第一个数是 12,第二个数是 11,第三个数是 10,第四个数是 9,由此解答。\n\n【详解】由分析得:13 前面的第 4 个数是 9。", + "knowledge_points": [ + "20以内数的排序" + ], + "source": "25-26 二年级上·黑龙江佳木斯·开学考试" + }, + { + "id": "152", + "unit": "11~20的认识", + "question_type": "填空题", + "difficulty": 0.85, + "question": "16 个男生站成一行,现在要在相邻的两个男生之间站一个女生,一共要( )个女生。", + "options": [ + + ], + "answer": "15", + "solution": "【分析】相邻两个男生之间站一个女生,则女生比男生少 1人,用男生人数减 1 即可求解。\n\n【详解】16 - 1 = 15 (个),则一共可以站进 15 个女生。", + "knowledge_points": [ + "不退位减法 (20以内)" + ], + "source": "24-25 一年级下·湖南怀化·期末" + }, + { + "id": "153", + "unit": "11~20的认识", + "question_type": "填空题", + "difficulty": 0.85, + "question": "十位上是 1,且小于 14 的数有( )个。", + "options": [ + + ], + "answer": "4", + "solution": "【分析】20 以内数从大到小关系为: 20 \u003e 19 \u003e 18 \u003e 17 \u003e 16 \u003e15 \u003e 14 \u003e 13 \u003e 12 \u003e 11 \u003e 10 \u003e 9 \u003e 8 \u003e 7 \u003e 6 \u003e 5 \u003e 4 \u003e 3 \u003e 2 \u003e 1 \u003e0,据此找出十位上是 1,且小于 14 的数。\n\n【详解】由分析可得:十位上是 1,且小于 14 的数有: 10, 11, 12, 13,共 4 个。", + "knowledge_points": [ + "20以内数的组成", + "20以内数的排序", + "20以内数的比大小" + ], + "source": "25-26 一年级上·全国·课后作业" + }, + { + "id": "154", + "unit": "11~20的认识", + "question_type": "判断题", + "difficulty": 0.65, + "question": "9 个一和 1 个十组成的数是 91。( )", + "options": [ + + ], + "answer": "×", + "solution": "【分析】一个整数,从右往左依次为个位,十位。十位是几表示几个十(几个十就是几十),个位是几表示几个一(几个一就是几)。\n\n【详解】由分析得:9 个一是 9, 1 个十是 10,合起来是 19,原题说法错误。故答案为: ×", + "knowledge_points": [ + "20以内数的组成" + ], + "source": "25-26 一年级上·广东深圳·月考" + }, + { + "id": "155", + "unit": "11~20的认识", + "question_type": "判断题", + "difficulty": 0.85, + "question": "15 读作 \"十五\",二十写作 \"2\"。( )", + "options": [ + + ], + "answer": "×", + "solution": "【分析】一个整数,从右往左依次为个位,十位。读数时,从高位读起,十位是几读作几十,个位是几读作几;写数时,从高位写起,几十就在十位写几,几就在个位写几,个位一个也没有,就写 0 占位。\n\n【详解】由分析得:15 读作 \"十五\",二十写作 \"20\",原题说法错误。故答案为: ×", + "knowledge_points": [ + "11~20 的认识和读写" + ], + "source": "25-26 一年级上·广东深圳·月考" + }, + { + "id": "156", + "unit": "11~20的认识", + "question_type": "计算题", + "difficulty": 0.65, + "question": "想一想,怎样简便怎样算.\n\n11 + 8 - 1 = 18 - 6 + 2 =\n16 + 2 - 6 = 13 - 2 + 7 =", + "options": [ + + ], + "answer": "18;14;12;18", + "solution": "【分析】第 1 题: 11 加上 8 再减去 1,与 11 先减去 1 再加上 8 结果相同;第2题:18减去6再加上2,可以理解为18先减去4再减去2,又加上了2,即18减去4;第3题:16加上2再减去6,与16先减去6再加上2结果相同;第 4 题: 13 先减去 2 再加上 7,可以理解为 13 先减去 2,再加上 2,再加上 5,即 13 加上 5 。\n\n【详解】由分析得:11 + 8 - 1 = 11 - 1 + 8 = 10 + 8 = 18;18 - 6 + 2 = 18 - 4 - 2 + 2 = 18 - 4 = 14;16 + 2 - 6 = 16 - 6 + 2 = 10 + 2 = 12;13 - 2 + 7 = 13 - 2 + 2 + 5 = 13 + 5 = 18", + "knowledge_points": [ + "不进位,不退位加减混合运算 (20 以内)" + ], + "source": "25-26 一年级上·全国·课后作业" + }, + { + "id": "157", + "unit": "11~20的认识", + "question_type": "计算题", + "difficulty": 0.94, + "question": "看图列式计算.\n\n![](images/00e3120e71834a9dbeaa16ebf4adfbf700ba733b75e1f76172c964cf356c7b97.jpg)\n\n□ ○ □ = □(个)", + "options": [ + + ], + "answer": "15 + 2 = 17", + "solution": "【分析】由图可知,左边筐子里有 15 个,右边有 2 个,求一共多少个,将左右两边的数量相加求和即可。\n\n【详解】 15 + 2 = 17(个),一共17个。", + "knowledge_points": [ + "图文问题", + "不进位加法(20以内)" + ], + "source": "25-26 一年级上·全国·课后作业" + }, + { + "id": "158", + "unit": "11~20的认识", + "question_type": "计算题", + "difficulty": 0.94, + "question": "看图列式计算.\n\n![](images/16beaa78a65bdd3312022b1ea60aab02605ef154652b0557f558a4468857e098.jpg)\n\n□ ○ □ = □(只)", + "options": [ + + ], + "answer": "19 - 5 = 14", + "solution": "【分析】根据图片可知:一共有 19 只乌龟,右边有 5 只,则左边有几只。 用共有的数量减去右边有的数量即可。\n\n【详解】19 - 5 = 14(只),则左边有 14 只。", + "knowledge_points": [ + "不退位减法 (20 以内)" + ], + "source": "25-26 一年级上·全国·单元测试" + }, + { + "id": "159", + "unit": "11~20的认识", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式计算.\n\n![](images/d67d1da6db04700b9e358f369c41e4166636b2ba470e1986714f6ccc0ab2283f.jpg)\n\n□ ○ □ = □(个)", + "options": [ + + ], + "answer": "17 - 6 = 11", + "solution": "【分析】一共有 17 个草莓,左边有 6 个,求右边筐里有几个,用减法计算,即总数量 - 左边的数量 = 右边的数量。\n\n【详解】17 - 6 = 11(个),右边筐里有 11 个草莓。", + "knowledge_points": [ + "图文问题", + "不退位减法(20以内)" + ], + "source": "25-26 一年级上·全国·单元测试" + }, + { + "id": "160", + "unit": "11~20的认识", + "question_type": "计算题", + "difficulty": 0.94, + "question": "看图列式计算.\n\n![](images/a2a8efa161535989cc63867e99ca2467dfdba36398a85e416862e0b6a1f45be5.jpg)\n\n□ ○ □ = □(个)", + "options": [ + + ], + "answer": "15 - 4 = 11", + "solution": "【分析】从图上可得:一共有 15 个乒乓球,已知右边有 4 个,要求左边盒子有多少个乒乓球,根据减法的意义,用 15 - 4 进行解答即可。\n\n【详解】15 - 4 = 11(个),左边盒子有 11 个乒乓球。", + "knowledge_points": [ + "图文问题", + "不退位减法(20以内)" + ], + "source": "25-26 一年级上·全国·课后作业" + }, + { + "id": "161", + "unit": "11~20的认识", + "question_type": "计算题", + "difficulty": 0.94, + "question": "看图列式计算.\n\n![](images/6818eb11a705496f93b57ee614c76037b3437b4db543d082aa2cb4a36123fee7.jpg)\n\n□ ○ □ = □(个)", + "options": [ + + ], + "answer": "4 + 10 = 14", + "solution": "【分析】由图可知,左边有 4 个,右边盒子里有 10 个,求一共多少个。将左右两边数量相加求和即可。\n\n【详解】 4 + 10 = 14 (个)或 10 + 4 = 14 (个)一共 14 个。", + "knowledge_points": [ + "图文问题", + "不进位加法(20以内)" + ], + "source": "25-26 一年级上·全国·单元测试" + }, + { + "id": "162", + "unit": "11~20的认识", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式计算.\n\n![](images/20132523.jpg) \n()○ () = ()(只)", + "options": [ + + ], + "answer": "15 - 4 = 11", + "solution": "【分析】由题意可知:共有 15 只猫,右边有 4 只,求左边房子里有多少只,用共有的只数减去右边的即可;据此解答。\n\n【详解】由分析可得:15 - 4 = 11 (只),左边房子里有 11 只。", + "knowledge_points": [ + "图文问题", + "不退位减法 (20以内)" + ], + "source": "24-25 一年级上·辽宁·期中" + }, + { + "id": "163", + "unit": "11~20的认识", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式计算.\n\n![](images/d6aece48528f5145350795ef337aa7305b0766781f020763c787141b34a39dd6.jpg)\n\n□ ○ □ = □(辆)", + "options": [ + + ], + "answer": "12 - 2 = 10", + "solution": "【分析】根据图片可知:用一共有的数量减去右边的数量,即可求出做左边盒中的数量。\n\n【详解】12 - 2 = 10(辆),则左边盒中有 10 辆。", + "knowledge_points": [ + "不退位减法 (20 以内)" + ], + "source": "25-26 一年级上·全国·课后作业" + }, + { + "id": "164", + "unit": "11~20的认识", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式计算.\n\n![](images/fe2c0956f5d8f861ce806abe2bebe979c8940043ff6c6e9dcc6455dd2d0da38b.jpg)\n\n□ ○ □ = □(支)", + "options": [ + + ], + "answer": "18 - 6 = 12", + "solution": "【分析】根据题图,用总数量 - 右边的数量 = 左边的数量,据此解答。\n\n【详解】18 - 6 = 12 (支),左边有 12 支。", + "knowledge_points": [ + "图文问题", + "不退位减法(20以内)" + ], + "source": "25-26 一年级上·全国·单元测试" + }, + { + "id": "165", + "unit": "11~20的认识", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式计算.\n\n![](images/e2560a66f685a1f40ae6a33f0831d8f8c3e2e3d48acd3f9326d550fac2d7a4ad.jpg)\n\n□ ○ □ = □(棵)", + "options": [ + + ], + "answer": "10 + 5 = 15", + "solution": "【分析】左边白菜的棵树加上右边白菜的棵树,就是一共有几棵白菜。\n\n【详解】10 + 5 = 15(棵),一共有 15 棵。", + "knowledge_points": [ + "图文问题", + "不进位加法(20以内)" + ], + "source": "25-26 一年级上·全国·单元测试" + }, + { + "id": "166", + "unit": "11~20的认识", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式计算.\n\n![](images/bd37709736c84115f03c5020b731b28a599b68a42cae579db9eb973a8297249c.jpg)\n\n□ ○ □ = □(支)", + "options": [ + + ], + "answer": "19 - 7 = 12", + "solution": "【分析】一共有 19 支铅笔,左边有 7 支,求右边有多少支,用减法计算,即总数量 - 左边的数量 = 右边的数量。\n\n【详解】19 - 7 = 12 (支),右边有 12 支。", + "knowledge_points": [ + "图文问题", + "不退位减法(20以内)" + ], + "source": "25-26 一年级上·全国·课后作业" + }, + { + "id": "167", + "unit": "11~20的认识", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式计算.\n\n![](images/44a3a1e57a35352af643af73bf8e752242b6fcae2d7dcb936a4d24835b72f8fa.jpg)\n\n□ ○ □ = □(个)", + "options": [ + + ], + "answer": "12 + 5 = 17", + "solution": "【分析】根据题图,数一数左边有 12 个,右边有 5 个,相加即可得出一共有多少个。\n\n【详解】据分析可得列式: 12 + 5 = 17 (个),所以,一共有 17 个。", + "knowledge_points": [ + "不进位加法 (20 以内)" + ], + "source": "25-26 一年级上·全国·课后作业" + }, + { + "id": "168", + "unit": "11~20的认识", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式计算.\n\n![](images/198c2ba48f261dd34ca5df9f60c83a69a450d4ddf910e5f5df160d587dbced8f.jpg)\n\n□ ○ □ = □(个)", + "options": [ + + ], + "answer": "14 - 3 = 11", + "solution": "【分析】用一共的个数减去右边的个数,即可求出左边的个数。\n\n【详解】14 - 3 = 11(个),左边有 11 个。", + "knowledge_points": [ + "图文问题", + "不退位减法(20以内)" + ], + "source": "2025 一年级上·全国·专题练习" + }, + { + "id": "169", + "unit": "11~20的认识", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式计算.\n\n![](images/4909e85d23063aaa0bd5960f212bddaaef4c3574edddffd9e19bf864a942a6c5.jpg)\n\n□ ○ □ = □(个)", + "options": [ + + ], + "answer": "18 - 6 = 12", + "solution": "【分析】根据题图,数一数可知,篮子外边有 6 个蘑菇,蘑菇的总个数减去篮子外边蘑菇的个数,等于篮子里蘑菇的个数;据此解答。\n\n【详解】 18 - 6 = 12 (个),因此,篮子里有 12 个蘑菇。", + "knowledge_points": [ + "图文问题", + "不退位减法(20以内)" + ], + "source": "2025 一年级上·全国·专题练习" + }, + { + "id": "170", + "unit": "11~20的认识", + "question_type": "计算题", + "difficulty": 0.94, + "question": "看图列式计算.\n\n![](images/b9e3d5ec1691d4043833e67193dca1ef5da188f929dedc7abd51048eec2f56c3.jpg)\n\n□ ○ □ = □(本)", + "options": [ + + ], + "answer": "14 - 4 = 10", + "solution": "【分析】根据题图可知,书本的总数量减去书包外面书本的数量,等于书包里书本的数量,据此解答。\n\n【详解】14 - 4 = 10(本),因此,书包里面有10本书。", + "knowledge_points": [ + "图文问题", + "不退位减法(20以内)" + ], + "source": "2025 一年级上·全国·专题练习" + }, + { + "id": "171", + "unit": "11~20的认识", + "question_type": "计算题", + "difficulty": 0.94, + "question": "10 + 4 =();11 + 4 =();13 + 5 =();14 - 10 =();15 - 4 =();18 - 5 =", + "options": [ + + ], + "answer": "14;15;18;4;11;13", + "solution": "【详解】略", + "knowledge_points": [ + "不进位加法(20以内)", + "不退位减法(20以内)" + ], + "source": "25-26 一年级上·全国·随堂练习" + }, + { + "id": "172", + "unit": "11~20的认识", + "question_type": "计算题", + "difficulty": 0.85, + "question": "7 + 3 + 5 =();6+4+9=();8 + 2 + 6 =();9 + 1 - 4 =();11 - 1 + 5 =();18 - 8 - 3 =", + "options": [ + + ], + "answer": "15;19;16;6;15;7", + "solution": "【详解】略", + "knowledge_points": [ + "不进位,不退位加减混合运算(20以内)", + "不进位,不退位连加,连减(20以内)" + ], + "source": "25-26 一年级上·全国·课后作业" + }, + { + "id": "173", + "unit": "11~20的认识", + "question_type": "解答题", + "difficulty": 0.85, + "question": "小朋友们排队去秋游,小明前面有11个人,从前往后数,他是第几个人。小红后面有17个人,从后往前数,她是第几个人。\n\n![](images/8e17812b3a6b7e71cd09333aa8e7998cd04721dc1b9e3df1524627eac6c7612c.jpg)", + "options": [ + + ], + "answer": "第12个;第18个", + "solution": "【分析】根据题意,可通过画图法表示,从图中可以看出\"小明前面有 11 个人\",从前往后数,数到小明是第 (11 + 1) 个人;\"小红后面有 17 个人\",从后往前数,数到小红是第 (17 + 1) 个人。\n\n【详解】11 + 1 = 12 (个),17 + 1 = 18 (个),答:从前往后数,小明是第 12 个人;从后往前数,小红是第 18 个人。", + "knowledge_points": [ + "认识几和第几", + "不进位加法(20以内)", + "前,后位置" + ], + "source": "25-26 一年级上·全国·周测" + }, + { + "id": "174", + "unit": "11~20的认识", + "question_type": "解答题", + "difficulty": 0.65, + "question": "小明和小亮买同一本书,小明缺 11 元,小亮缺 5 元。如果用他俩的钱合起来买这本书,钱正好。这本书的价钱是多少。他们各带了多少钱。", + "options": [ + + ], + "answer": "16 元。小明带了 5 元,小亮带了 11 元。", + "solution": "【分析】已知小明缺 11 元,小亮缺 5 元,且两人的钱合起来正好能买这本书。说明小明缺的钱正好是小亮带的钱,即小亮带了 11 元;同理,小亮缺的钱正好是小明带的钱,即小明带了 5 元。那么书的价钱就是两人带的钱之和,即可解答。\n\n【详解】由分析得:11 + 5 = 16 (元),答:这本书的价钱是 16 元。小明带了 5 元,小亮带了 11 元。", + "knowledge_points": [ + "不进位加法 (20以内)" + ], + "source": "25-26 一年级上·全国·周测" + }, + { + "id": "175", + "unit": "11~20的认识", + "question_type": "解答题", + "difficulty": 0.65, + "question": "一 (1) 班举行象棋比赛,共有 17 位同学参加,比赛采用淘汰制,每场比赛淘汰一位同学,要决出最后的冠军,一共要比赛多少场。", + "options": [ + + ], + "answer": "16场", + "solution": "【分析】在淘汰制比赛中,每进行一场比赛就会淘汰 1 名同学,最终要决出冠军,就需要计算出最终淘汰多少名同学,冠军只有 1 个,用总人数减去最后的一名同学,即可求出淘汰多少名同学,也就是进行多少场比赛。\n\n【详解】 17 - 1 = 16 (名),因为每场比赛淘汰 1 名同学,所以淘汰 16 名同学需要进行的比赛场数就是 16 场。答:一共要比赛16场。", + "knowledge_points": [ + "不退位减法 (20以内)" + ], + "source": "25-26 一年级上·全国·周测" + }, + { + "id": "176", + "unit": "11~20的认识", + "question_type": "解答题", + "difficulty": 0.94, + "question": "欢欢和 12 个好朋友去看电影,要买几张电影票。", + "options": [ + + ], + "answer": "13 张", + "solution": "【分析】根据题意,欢欢和12个好朋友,包括她自己和她的 12 个好朋友,所以总人数为欢欢 1 人加上 12 个好朋友,即 13 人,需要买 13 张票。\n\n【详解】12 + 1 = 13 (张),答:要买 13 张电影票。", + "knowledge_points": [ + "不进位加法 (20 以内)" + ], + "source": "25-26 一年级上·全国·周测" + }, + { + "id": "177", + "unit": "11~20的认识", + "question_type": "解答题", + "difficulty": 0.65, + "question": "妈妈买回来十几个苹果,小丽数了数发现,如果每天吃5个,几天后还剩下3个,妈妈可能买回来多少个苹果。", + "options": [ + + ], + "answer": "13 个或 18 个", + "solution": "【分析】根据题意,一共有十几个苹果,每天吃 5 个,几天后还剩 3 个。吃的天数不确定,则可以从第一天开始算起,用吃了的数量和剩下的数量相加,计算出总数量,再找到符合题意的即可。\n\n【详解】由分析得:第一天: 5 + 3 = 8 (个), 8 个不在十几个的范围里,不符合题意;第二天: 5 + 5 + 3 = 13 (个), 13 个在十几个的范围里,符合题意;第三天: 5 + 5 + 5 + 3 = 18 (个), 18 个在十几个的范围里,符合题意。答:妈妈可能买回来 13 个或 18 个苹果。", + "knowledge_points": [ + "8,9 的加减法", + "不进位,不退位连加,连减(20 以内)" + ], + "source": "25-26 一年级上·全国·课后作业" + }, + { + "id": "178", + "unit": "11~20的认识", + "question_type": "解答题", + "difficulty": 0.65, + "question": "17人玩捉迷藏游戏,已经找到了6人,还有多少人没有找到。", + "options": [ + + ], + "answer": "10人", + "solution": "【分析】根据生活经验可知,玩捉迷藏时,1人负责找,剩余的人负责藏,则总人数 - 负责找的人数 - 找到的人数 =没找到的人数。\n\n【详解】17 - 1 - 6 = 10 (人),答:还有 10 人没有找到。", + "knowledge_points": [ + "不进位,不退位连加,连减(20以内)" + ], + "source": "25-26 一年级上·全国·课后作业" + }, + { + "id": "179", + "unit": "11~20的认识", + "question_type": "解答题", + "difficulty": 0.94, + "question": "给这个小组每人发一本书,还需要多少本。\n\n![](images/edd46d83385417dd385935a39ae81e68c4a8add767e84d54b78f2357781fb2d6.jpg)\n\n□ ○ □ = □ (本)", + "options": [ + + ], + "answer": "10 本", + "solution": "【分析】根据题意,一共有 13 个同学,也就是需要 13 本,则需要的数量 - 拿来的数量 = 还需要的数量。\n\n【详解】13 - 3 = 10 (本),答:还需要 10 本。", + "knowledge_points": [ + "图文问题", + "不退位减法(20以内)" + ], + "source": "2025 一年级上·全国·专题练习" + }, + { + "id": "180", + "unit": "11~20的认识", + "question_type": "解答题", + "difficulty": 0.94, + "question": "他们一共栽了多少棵树。\n\n![](images/4541f5a06f9a11250e4c921ae96f4ded55953dedc674ed0aa0d9bf78b84cd66f.jpg)", + "options": [ + + ], + "answer": "17 棵", + "solution": "【分析】根据题意可知:把两个人栽的数量相加即可求出他们一共栽的数量。\n\n【详解】12 + 5 = 17 (棵),答:他们一共栽了 17 棵树。", + "knowledge_points": [ + "不进位加法 (20 以内)" + ], + "source": "25-26 一年级上·全国·课后作业" + }, + { + "id": "181", + "unit": "11~20的认识", + "question_type": "解答题", + "difficulty": 0.85, + "question": "美术社团将在2天后外出写生,那一天是几日。星期几。\n\n![](images/a143cc1c68edbe01882b798918ac01030ff7c7f3c3bb9bf9ac8ffcea7f266d8c.jpg)", + "options": [ + + ], + "answer": "15日;星期二", + "solution": "【分析】根据题意,用今天的日期 +2 天 = 2 天后的日期。一个星期是 7 天,从星期一到星期日,依次重复,今天是星期日, 1 天后是星期一, 2 天后是星期二。据此解答。\n\n【详解】13 + 2 = 15 (日),2天后是星期二,答:那一天是 11 月 15 日,星期二。", + "knowledge_points": [ + "不进位加法(20以内)", + "年,月,日时间的推算" + ], + "source": "25-26 一年级上·全国·单元测试" + }, + { + "id": "182", + "unit": "11~20的认识", + "question_type": "解答题", + "difficulty": 0.85, + "question": "足球社团的成员正在排队进入球场,这一排一共有多少人。\n\n![](images/89d9025770247c0ea7ce6605823b76a45d60ef4db31fed24307354ddc3cb592f.jpg)\n\n□ ○ □ = □(人)", + "options": [ + + ], + "answer": "16人", + "solution": "【分析】根据题图,9号小朋友是从前往后数的第12个,最右边的小朋友是从后往前数的第1个,从图中可以看出,9号小朋友的后面还有4人。用 12 + 4 就是这一排的总人数。据此解答。\n\n【详解】根据分析:12 + 4 = 16 (人),答:这一排一共有 16 人。", + "knowledge_points": [ + "图文问题", + "不进位加法(20以内)" + ], + "source": "24-25 一年级上·河北·单元测试" + }, + { + "id": "183", + "unit": "11~20的认识", + "question_type": "解答题", + "difficulty": 0.94, + "question": "茶艺社团的成员有16人,每人1套茶杯,还需要多少套茶杯。\n\n![](images/cfd6c00812ba54ca1875b2dbf3218c7a0e3af034558fd7dd81186675ad00f0b1.jpg)", + "options": [ + + ], + "answer": "6套", + "solution": "【分析】根据题图,用总人数 - 已经有的茶杯数量 = 还需要茶杯的数量。据此解答。\n\n【详解】根据分析:16 - 10 = 6 (套),答:还需要 6 套茶杯。", + "knowledge_points": [ + "图文问题", + "不退位减法(20以内)" + ], + "source": "24-25 一年级上·河北·单元测试" + }, + { + "id": "184", + "unit": "11~20的认识", + "question_type": "解答题", + "difficulty": 0.85, + "question": "它们一共钓了几条鱼。\n\n![](images/201325221.jpg)", + "options": [ + + ], + "answer": "17条", + "solution": "【分析】用加法把两只猫钓了的鱼数量加起来,求出和,就是它们一共钓了几条鱼。\n\n【详解】 10 + 7 = 17 (条),答:它们一共钓了 17 条鱼。", + "knowledge_points": [ + "不进位加法 (20 以内)" + ], + "source": "25-26 一年级上·全国·课后作业" + }, + { + "id": "185", + "unit": "11~20的认识", + "question_type": "解答题", + "difficulty": 0.85, + "question": "育英学校一年级一班图书角共有16本故事书,借走了3本,还剩下多少本故事书。", + "options": [ + + ], + "answer": "13本", + "solution": "【分析】还剩的故事书本数 = 图书角共有的本数 - 借走的本数;据此列式解决。\n\n【详解】16 - 3 = 13(本),答:还剩下13本故事书。", + "knowledge_points": [ + "不退位减法 (20以内)" + ], + "source": "25-26 一年级上·全国·课后作业" + }, + { + "id": "186", + "unit": "11~20的认识", + "question_type": "解答题", + "difficulty": 0.85, + "question": "美羊羊读一本书,她从第5页读到第16页,明天读第17页,一共读了多少页。", + "options": [ + + ], + "answer": "12页", + "solution": "【分析】已知她是从第 5 页开始读的,读到 16 页,明天读 17 页,说明她 16 页读完了。用最后读的页数减去开始的页数再加上最后读的这一页,即可得出答案,或者从 5 开始数,一直数到 16 也可得出答案。\n\n【详解】16 - 5 + 1= 11 + 1= 12 (页),答:一共读了 12 页。", + "knowledge_points": [ + "不进位加法(20以内)", + "不退位减法(20以内)", + "加减混合运算(20以内)" + ], + "source": "25-26 一年级上·全国·课后作业" + }, + { + "id": "187", + "unit": "11~20的认识", + "question_type": "解答题", + "difficulty": 0.85, + "question": "小红星期几还书。\n\n![](images/20132722.jpg)", + "options": [ + + ], + "answer": "星期五", + "solution": "【分析】根据题意,今天是星期二,3天后还书,接下来的3天分别是星期三,星期四,星期五,那么星期五还书。\n\n【详解】从星期二往后数3天是星期五。2 + 3 = 5,答:小红星期五还书。", + "knowledge_points": [ + "5以内数的加法", + "年,月,日时间的推算" + ], + "source": "25-26 一年级上·全国·课后作业" + }, + { + "id": "188", + "unit": "11~20的认识", + "question_type": "解答题", + "difficulty": 0.85, + "question": "你知道树后面有几只兔子吗。\n\n![](images/b1d7bcd8ea74f2c1977e8abd60f84e66588abc1ee1af13b7ac1efe66d6730cd9.jpg)\n\n![](images/bad30b83384d96fe481911f4dde7bb869b04c1f6fc5db1d387fd70ac24588cea.jpg)\n\n![](images/32572557b2470ce1d39a49cf8a980dba361973827eac7337a406f99359dd4c7a.jpg)", + "options": [ + + ], + "answer": "7 只", + "solution": "【分析】由图可知,![](images/bad30b83384d96fe481911f4dde7bb869b04c1f6fc5db1d387fd70ac24588cea.jpg)排第 10,也就是数到灰兔有10只兔子;![](images/32572557b2470ce1d39a49cf8a980dba361973827eac7337a406f99359dd4c7a.jpg)排第18,也就是数到白兔有18只兔子。则用数到白兔的兔子数量 - 数到灰兔的兔子数量-1(白兔)= 它们之间的兔子的数量,也就是后面兔子的数量。\n\n【详解】18 - 10 - 1 = 7(只),答:树后面有 7 只兔子。", + "knowledge_points": [ + "不进位,不退位连加,连减(20以内)" + ], + "source": "25-26 一年级上·全国·课后作业" + }, + { + "id": "189", + "unit": "11~20的认识", + "question_type": "解答题", + "difficulty": 0.65, + "question": "湖里有 12 只天鹅,又飞来5只。现在一共有多少只天鹅。", + "options": [ + + ], + "answer": "17 只", + "solution": "【分析】根据题意可知:用湖里有的数量加上又飞来的数量即可求出现在一共有的数量。\n\n【详解】12 + 5 = 17(只),答:现在一共有 17 只天鹅。", + "knowledge_points": [ + "不进位加法 (20 以内)" + ], + "source": "25-26 一年级上·江苏·课后作业" + }, + { + "id": "190", + "unit": "11~20的认识", + "question_type": "解答题", + "difficulty": 0.85, + "question": "小红有 16 朵花,小兰有 10 朵花,小红给小兰几朵,两人的花就一样多。", + "options": [ + + ], + "answer": "3 朵", + "solution": "【分析】根据题意,先用减法计算出小红比小兰多几朵花,再将多的数量分成同样多的两份,其中一份的数量给小兰,她们的花就一样多。\n\n【详解】16 - 10 = 6 (朵);6 = 3 + 3,即 16 - 3 = 13 (朵);10 + 3 = 13 (朵)答:小红给小兰 3 朵,两人的花就一样多。", + "knowledge_points": [ + "\"一样多\"问题", + "不退位减法(20以内)" + ], + "source": "25-26 二年级上·黑龙江佳木斯·开学考试" + }, + { + "id": "191", + "unit": "11~20的认识", + "question_type": "解答题", + "difficulty": 0.94, + "question": "公交车上原来有 16 个人,第一站下去 5 个人,第二站又下去 3 个人,现在公交车上还有多少人。", + "options": [ + + ], + "answer": "8人", + "solution": "【分析】根据题意可知:用原有的人数减去下去的人数再减去又下去的人数即可求出现在还有的人数。\n\n【详解】16 - 5 - 3 = 8(人),答:现在公交车还有 8 人。", + "knowledge_points": [ + "连减 (20以内)" + ], + "source": "25-26 二年级上·黑龙江佳木斯·开学考试" + }, + { + "id": "192", + "unit": "11~20的认识", + "question_type": "解答题", + "difficulty": 0.85, + "question": "体育课上,小朋友站成一排,一共11人。从前往后数小华站在第5个,从后往前数小勇站在第9个,小华和小勇之间一共有几人。\n\n![](images/377487c1e157dfdf2cbd107e0a4793beb59d4b4eff1e66f0553550b4c5a460e8.jpg)", + "options": [ + + ], + "answer": "1人", + "solution": "【分析】已知,小朋友共11个人,可用圆圈代替小朋友,分别数一数小华和小勇的位置,标记出来后,看一下两人之间的人数即可。\n\n【详解】根据上图,两人之间有 1 人。答:小华和小勇之间一共有 1 人。", + "knowledge_points": [ + "11~20 的认识和读写", + "数一数" + ], + "source": "25-26 一年级上·全国·课后作业" + }, + { + "id": "193", + "unit": "11~20的认识", + "question_type": "解答题", + "difficulty": 0.85, + "question": "乐乐和笑笑参加 100 米赛跑,乐乐用了 17 秒,笑笑用了 20 秒,谁跑得快。", + "options": [ + + ], + "answer": "乐乐", + "solution": "【分析】时间越短则跑的越快,然后将两人用时进行比较,选择用时短的那人即可。\n\n【详解】17秒 \u003c 20 秒,答:乐乐跑得快。", + "knowledge_points": [ + "20以内数的比大小", + "时间快慢的比较" + ], + "source": "25-26 一年级上·全国·课后作业" + }, + { + "id": "194", + "unit": "11~20的认识", + "question_type": "解答题", + "difficulty": 0.85, + "question": "姐姐和妹妹读同一本故事书,妹妹读了 13 页,姐姐读了 20 页。谁剩下的页数多,多多少页。", + "options": [ + + ], + "answer": "妹妹;7页", + "solution": "【分析】读的数量越少则剩余的越多,将两人读的数量进行比较,选择少的即可;然后用姐姐读的数量减去妹妹读的数量即可求出多的页数。\n\n【详解】13 \u003c 20,20 - 13 = 7 (页),答:妹妹剩下的页数多,多 7 页。", + "knowledge_points": [ + "不退位减法(20以内)", + "20以内数的比大小" + ], + "source": "25-26 一年级上·全国·课后作业" + }, + { + "id": "195", + "unit": "11~20的认识", + "question_type": "解答题", + "difficulty": 0.65, + "question": "班级的图书角有一些书,第一周小朋友们借走了图书的一半,第二周小朋友们借走了剩下的一半,图书角还剩下5本,原来图书角的书有多少本。", + "options": [ + + ], + "answer": "20 本", + "solution": "【分析】根据题意,第一周小朋友们借走了图书的一半,说明第二周小朋友们也借走了图书的一半,再根据第二周小朋友们借走了剩下图书的一半,图书角还剩下 5 本,用 5 + 5 = 10 (本)可以算出第二周小朋友们借走 10 本图书,再用 10 + 10 = 20 (本)可以算出原来图书角的书有多少本。\n\n【详解】5 + 5 = 10 (本),10 + 10 = 20 (本),答:原来图书角的书有 20 本。", + "knowledge_points": [ + "倒推问题", + "不进位加法(20以内)", + "10的加减法" + ], + "source": "25-26 一年级上·全国·课后作业" + }, + { + "id": "196", + "unit": "11~20的认识", + "question_type": "解答题", + "difficulty": 0.65, + "question": "小朋友们进行长跑比赛,从前往后数明明是第5个,他后面还有10个小朋友,参加长跑比赛的小朋友一共有多少个。", + "options": [ + + ], + "answer": "15 个", + "solution": "【分析】从前往后数,明明是第 5 个,说明他前面有 4 个小朋友,加上他自己共 5 个。后面还有 10 个小朋友,总人数为前面的 5 个加上后面的 10 个。\n\n【详解】5 + 10 = 15 (个),答:参加长跑比赛的小朋友一共有 15 个。", + "knowledge_points": [ + "不进位加法(20以内)", + "前,后位置" + ], + "source": "25-26 一年级上·全国·课后作业" + }, + { + "id": "197", + "unit": "11~20的认识", + "question_type": "解答题", + "difficulty": 0.85, + "question": "一辆公共汽车从东站开到西站,开一趟。若这辆公共汽车从东站出发,开了11趟之后,这辆公共汽车在东站还是西站。", + "options": [ + + ], + "answer": "西站", + "solution": "【分析】根据题意,一共开了 11 趟,第 1 趟从东站开到西站,此时这辆公共汽车在西站。第 2 趟从西站开到东站,此时这辆公共汽车在东站。第 3 趟从东站开到西站,此时这辆公共汽车在西站。也就是第 1,3,5,7,9,11 趟从东站开到西站,第 2,4,6,8,10 趟从西站开到东站,最后一趟是第 11 趟,所以最后这辆公共汽车在西站。据此解答。\n\n【详解】根据分析:第1,3,5,7,9,11趟从东站开到西站,第2,4,6,8,10趟从西站开到东站,最后一趟是第11趟,所以最后这辆公共汽车在西站。", + "knowledge_points": [ + "周期问题", + "11~20 的认识和读写", + "认识几和第几" + ], + "source": "25-26 一年级上·全国·课后作业" + }, + { + "id": "198", + "unit": "11~20的认识", + "question_type": "解答题", + "difficulty": 0.65, + "question": "小华周末在家看书,从第 7 页读到了第 18 页。他周末一共读了多少页。", + "options": [ + + ], + "answer": "12页", + "solution": "【分析】根据题意,用读到的页码减去开始读的页码,由于第 7 页也读了,相当于多减了 1 页,则再加上 1,就是读了的页数。\n\n【详解】18 - 7 + 1 = 12 (页)答:他周末一共读了 12 页。", + "knowledge_points": [ + "不进位,不退位加减混合运算 (20 以内)" + ], + "source": "25-26 一年级上·全国·课后作业" + }, + { + "id": "199", + "unit": "11~20的认识", + "question_type": "解答题", + "difficulty": 0.85, + "question": "妈妈买回来 10 个梨,爸爸也买回来了同样多的梨,两人一共买了多少个梨。", + "options": [ + + ], + "answer": "20个", + "solution": "【分析】妈妈买回来 10 个梨,爸爸也买回来了同样多的梨,也就是爸爸也买回来 10 个梨,用妈妈买梨的个数加上爸爸买梨的个数,即可求出两人一共买了多少个梨。\n\n【详解】10 + 10 = 20 (个),答:两人一共买了20个梨。", + "knowledge_points": [ + "不进位加法 (20 以内)" + ], + "source": "25-26 一年级上·全国·课后作业" + }, + { + "id": "200", + "unit": "11~20的认识", + "question_type": "解答题", + "difficulty": 0.85, + "question": "妈妈给哥哥和弟弟每个人都买了10颗糖果,哥哥给了弟弟5颗后,两人相差多少颗。", + "options": [ + + ], + "answer": "10颗", + "solution": "【分析】根据题意可知:先求出哥哥给了弟弟 5 颗后,每人都还有几颗糖,哥哥现有的数量用哥哥原有的数量减去 5,弟弟现有的数量用弟弟原有的数量加 5,然后用弟弟现有的数量减去哥哥现有的数量即可求出两人相差的数量。\n\n【详解】哥哥现有的数量: 10 - 5 = 5 (颗),弟弟现有的数量: 10 + 5 = 15 (颗),15 - 5 = 10 (颗),答:两人相差 10 颗。", + "knowledge_points": [ + "不进位加法(20以内)", + "不退位减法(20以内)", + "10的加减法" + ], + "source": "25-26 一年级上·全国·课后作业" + }, + { + "id": "201", + "unit": "第二单元 11~20的认识", + "question_type": "选择题", + "difficulty": 0.94, + "question": "在算式 16 - 6 = 10 中, 16 是 ( )。", + "options": [ + "A. 减数", + "B. 差", + "C. 被减数" + ], + "answer": "C", + "solution": "【分析】减法算式中,被减数 - 减数 = 差,据此解答.\n【详解】在算式 16 - 6 = 10 中,16 是被减数。故答案为: C", + "knowledge_points": [ + "加,减法的意义和各部分间的关系", + "不退位减法(20以内)" + ], + "source": "24-25 一年级上·河南周口·期末" + }, + { + "id": "202", + "unit": "第二单元 11~20的认识", + "question_type": "选择题", + "difficulty": 0.85, + "question": "13 和 18 这两个数,( ) 最接近 10 , ( ) 最接近 20 。", + "options": [ + "A. 13, 18", + "B. 18, 13" + ], + "answer": "A", + "solution": "【分析】1 到 20,从小到大排序:1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20。中间间隔的数越少则越接近.\n【详解】13 和 18 这两个数, 13 最接近 10 , 18 最接近 20 。故答案为: A", + "knowledge_points": [ + "20以内数的排序" + ], + "source": "24-25一年级上·河南周口·期末" + }, + { + "id": "203", + "unit": "第二单元 11~20的认识", + "question_type": "选择题", + "difficulty": 0.94, + "question": "比 15 大,比 19 小的数有 ( ) 个。", + "options": [ + "A. 5", + "B. 4", + "C. 3" + ], + "answer": "C", + "solution": "【分析】根据题意,符合条件的数必须是大于15且小于19的数。因此,依次列举这些数:16,17,18,共3个,据此解答.\n【详解】按照 20 以内数的顺序, 15,16,17,18,19,所以,比 15 大,比 19 小的数有 3 个。故答案:C", + "knowledge_points": [ + "20以内数的排序", + "20以内数的比大小" + ], + "source": "24-25 一年级上·山西晋中·期末" + }, + { + "id": "204", + "unit": "第二单元 11~20的认识", + "question_type": "选择题", + "difficulty": 0.85, + "question": "小朋友们排成一排做游戏,希希排在第15,点点排在第20,他们两人之间共有()。", + "options": [ + "A. 3人", + "B. 4人", + "C. 5人" + ], + "answer": "B", + "solution": "【分析】希希排在第 15,点点排在第 20,求他们两人之间共有几人;根据 20 以内数从小到大的顺序为:0,1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20。由此数出 15 和 20 之间有几个数即可.\n【详解】根据分析可知, 15 和 20 之间有 16, 17, 18, 19 共 4 个数,所以希希和点点两人之间共有 4 人。故答案为: B", + "knowledge_points": [ + "20以内数的排序" + ], + "source": "24-25一年级上·河南三门峡·期末" + }, + { + "id": "205", + "unit": "第二单元 11~20的认识", + "question_type": "选择题", + "difficulty": 0.85, + "question": "甜甜有一盒巧克力(如图)快要吃完了,可能还剩()块.\n![](images/屏幕截图%202025-12-02%20203023.jpg)", + "options": [ + "A. 2 块", + "B. 18 块", + "C. 20块" + ], + "answer": "A", + "solution": "【分析】快要吃完了,所以剩下的应该很少,找出比 20 块小,并且差得多的数即可;据此解答.\n【详解】根据分析:A. 2块比20块小,差得多;B. 18 块比 20 块小一些,则还剩很多;C. 20 块等于 20 块,说明还没吃;所以可能还剩2块。故答案为:A", + "knowledge_points": [ + "11~20 的认识和读写", + "20以内数的比大小" + ], + "source": "24-25一年级上·河南三门峡·期末" + }, + { + "id": "206", + "unit": "第二单元 11~20的认识", + "question_type": "选择题", + "difficulty": 0.85, + "question": "下面选项中最小的数是 ( )。", + "options": [ + "A. 个位上是 5 的数,十位上是 1 的数", + "B. 最大的一位数", + "C. 9 和 11 中间的数" + ], + "answer": "B", + "solution": "【分析】一个两位数从右往左数第一位是个位,个位是几,就表示几个一,第二位是十位,十位是几,就表示几个十。最大的一位数是 9;求 9 和 11 中间的数,根据 20 以内数的排序即可解答。1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20。然后把 3 个选项的数进行比较大小即可.\n【详解】A。个位上是5的数,十位上是1的数写作:15。B。最大的一位数是 9。C。9 和 11 中间的数是 10.9 \u003c 10 \u003c 15故答案为: B", + "knowledge_points": [ + "20以内数的组成", + "20以内数的排序", + "20以内数的比大小" + ], + "source": "24-25 一年级上·河南三门峡·期末" + }, + { + "id": "207", + "unit": "第二单元 11~20的认识", + "question_type": "选择题", + "difficulty": 0.85, + "question": "与12相邻的两个数是( )。", + "options": [ + "A. 10 和 11", + "B. 11 和 13", + "C. 13 和 14" + ], + "answer": "B", + "solution": "【分析】20以内数从小到大顺序为0,1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,与 12 相邻的数是它前边一个数和它后边一个数,由此解答.\n【详解】由分析可知:与 12 相邻的两个数是 11 和 13。故答案为: B", + "knowledge_points": [ + "20以内数的排序" + ], + "source": "24-25 一年级上·福建漳州·期末" + }, + { + "id": "208", + "unit": "第二单元 11~20的认识", + "question_type": "选择题", + "difficulty": 0.65, + "question": "下面的数, ( ) 与 10 相邻,又比 10 大。", + "options": [ + "A. 9", + "B. 11", + "C. 20" + ], + "answer": "B", + "solution": "【分析】20 以内的数从小到大排列是: 1 \u003c 2 \u003c 3 \u003c 4 \u003c 5 \u003c 6\u003c 7 \u003c 8 \u003c 9 \u003c 10 \u003c 11 \u003c 12 \u003c 13 \u003c 14 \u003c 15 \u003c 16 \u003c 17 \u003c 18 \u003c 19 \u003c 20,据此解答.\n【详解】A。 9 \u003c 10,不符合;B. 11 \u003e 10,相差 1,相邻,符合;C. 10 和 20 之间相差不止 1 个数,不相邻,不符合。11 与 10 相邻,又比 10 大。故答案为: B", + "knowledge_points": [ + "20以内数的排序", + "20以内数的比大小" + ], + "source": "24-25 一年级上·云南保山·期末" + }, + { + "id": "209", + "unit": "第二单元 11~20的认识", + "question_type": "选择题", + "difficulty": 0.85, + "question": "彩娃和福娃看同一本关于春节的故事书,彩娃看了14页,福娃看了16页,()剩下没看的页数多。", + "options": [ + "A. 彩娃", + "B. 福娃", + "C. 无法确定" + ], + "answer": "A", + "solution": "【分析】看同一本书,谁看的页数多,谁剩下没看的页数就少;谁看的页数少,谁剩下没看的页数就多.\n【详解】14 \u003c 16,彩娃看的页数少,因此彩娃剩下没看的页数多。故答案为: A", + "knowledge_points": [ + "20以内数的比大小" + ], + "source": "24-25一年级上·河南南阳·期末" + }, + { + "id": "210", + "unit": "第二单元 11~20的认识", + "question_type": "选择题", + "difficulty": 0.85, + "question": "13 和 17 之间的数有()个。", + "options": [ + "A. 1", + "B. 2", + "C. 3" + ], + "answer": "C", + "solution": "【分析】根据题意,按照20以内数的顺序,从13数到17,数出它们之间数字的个数即可,不包含 13 和 17.\n【详解】从 13 到 17 依次为: 13, 14, 15, 16, 17,则 13 和 17 之间的数有 3 个。故答案为: C", + "knowledge_points": [ + "20以内数的排序" + ], + "source": "24-25 一年级上·山东济南·期末" + }, + { + "id": "211", + "unit": "第二单元 11~20的认识", + "question_type": "选择题", + "difficulty": 0.85, + "question": "从 16 开始,一个一个的往前数,第三个数是 ( )。", + "options": [ + "A. 19", + "B. 18", + "C. 14" + ], + "answer": "C", + "solution": "【分析】1 到 20,从小到大排序:1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20.\n【详解】从 16 开始,一个一个的往前数,第三个数是 14 。故答案为: C", + "knowledge_points": [ + "20以内数的排序" + ], + "source": "24-25 一年级上·山东济南·期末" + }, + { + "id": "212", + "unit": "第二单元 11~20的认识", + "question_type": "选择题", + "difficulty": 0.85, + "question": "比 13 少 2 的数是 ( )。", + "options": [ + "A. 11", + "B. 15", + "C. 10" + ], + "answer": "A", + "solution": "【分析】求比一个数少几的数是多少,用这个数减去少的数计算,由此解答.\n【详解】 13 - 2 = 11,比13少2的数是11。故答案为:A", + "knowledge_points": [ + "不退位减法(20以内)" + ], + "source": "24-25 一年级上·山东济南·期末" + }, + { + "id": "213", + "unit": "第二单元 11~20的认识", + "question_type": "选择题", + "difficulty": 0.85, + "question": "在算式 \" 17 - 3 = 14 \" 中,减数是几。 ( )", + "options": [ + "A. 17", + "B. 3", + "C. 14" + ], + "answer": "B", + "solution": "【分析】减法算式为被减数 - 减数 = 差,由此找出各数字对应的名称即可解答.\n【详解】A。17是被减数,不符合题意;B. 3是减数,符合题意;C. 14 是差,不符合题意。故答案为: B", + "knowledge_points": [ + "不退位减法(20以内)" + ], + "source": "24-25 一年级上·山东济宁·期末" + }, + { + "id": "214", + "unit": "第二单元 11~20的认识", + "question_type": "选择题", + "difficulty": 0.85, + "question": "从8数到15,一共数了()个数。", + "options": [ + "A. 6", + "B. 7", + "C. 8" + ], + "answer": "C", + "solution": "【分析】从 8 数到 15,有8,9,10,11,12,13,14,15,共8个数.\n【详解】从 8 数到 15,一共数了 8 个数。故答案为: C", + "knowledge_points": [ + "20以内数的排序" + ], + "source": "22-23一年级上·云南玉溪·期末" + }, + { + "id": "215", + "unit": "第二单元 11~20的认识", + "question_type": "选择题", + "difficulty": 0.65, + "question": "一个数,个位上的数字比十位上的数字多 5,这个数可能是 ( )。", + "options": [ + "A. 18", + "B. 16", + "C. 14" + ], + "answer": "B", + "solution": "【分析】用个位上的数字减十位上的数字,找出得数是 5 的即可.\n【详解】A。 8 - 1 = 7, 18 个位比十位多 7,不符合;B. 6 - 1 = 5, 16 个位比十位多 5,符合;C. 4 - 1 = 3, 14 个位比十位多 3,不符合。这个数可能是 16。故答案为: B", + "knowledge_points": [ + "20以内数的组成" + ], + "source": "24-25 一年级上·山西晋中·期末" + }, + { + "id": "216", + "unit": "第二单元 11~20的认识", + "question_type": "选择题", + "difficulty": 0.85, + "question": "在 4, 14, 8, 10, 18, 20 这 6 个数中,比 15 小的数有 ( )个。", + "options": [ + "A. 4", + "B. 3", + "C. 2" + ], + "answer": "A", + "solution": "【分析】根据题意可知,题目要求在给定的6个数(4,14,8,10,18,20) 中找出比 15 小的数, 20 以内数从小到大为: 0 \u003c 1 \u003c 2 \u003c 3 \u003c 4 \u003c 5 \u003c 6 \u003c 7 \u003c 8 \u003c 9 \u003c 10 \u003c 11\u003c12 \u003c 13 \u003c 14 \u003c 15 \u003c 16 \u003c 17 \u003c 18 \u003c 19 \u003c 20,由此比较大小即可;18,20 均大于 15,不满足条件,而 4,14,8,10 均小于 15,共 4 个.\n【详解】在 4, 14, 8, 10, 18, 20 这 6 个数中,比 15 小的数有: 4,14,8,10,数一数可知,共 4 个。故答案为: A", + "knowledge_points": [ + "20以内数的排序", + "20以内数的比大小" + ], + "source": "24-25 一年级上·湖南湘西·期末" + }, + { + "id": "217", + "unit": "第二单元 11~20的认识", + "question_type": "选择题", + "difficulty": 0.85, + "question": "在算式 15 - 4 = 11 中,减数是()。", + "options": [ + "A. 15", + "B. 4", + "C. 11" + ], + "answer": "B", + "solution": "【分析】在减法算式\"被减数 - 减数 = 差\"中:被减数是第一个数(要减去的数),对应题目中的 15,减数是第二个数(用来减去的数),对应题目中的 4,差是结果,对应 11.\n【详解】在算式 15 - 4 = 11 中的减数是 4 。故答案为: B", + "knowledge_points": [ + "不退位减法 (20以内)" + ], + "source": "24-25一年级上·湖南湘西·期末" + }, + { + "id": "218", + "unit": "第二单元 11~20的认识", + "question_type": "选择题", + "difficulty": 0.85, + "question": "16 后面的第 3 个数是()。", + "options": [ + "A. 17", + "B. 18", + "C. 19" + ], + "answer": "C", + "solution": "【分析】根据题意可知,题目要求找出 16 后面的第 3 个数,从 16 开始往后数,第 1 个数是 17,第 2 个数是 18,第 3 个数是 19,据此选择.\n【详解】根据分析可得:16 后面的第 3 个数是 19。 故答案为: C", + "knowledge_points": [ + "20以内数的排序" + ], + "source": "24-25 一年级上·湖南湘西·期末" + }, + { + "id": "219", + "unit": "第二单元 11~20的认识", + "question_type": "选择题", + "difficulty": 0.85, + "question": "20 前面第 4 个数是()。", + "options": [ + "A. 9", + "B. 16", + "C. 18" + ], + "answer": "B", + "solution": "【分析】要求 20 前面的第 4 个数是多少,根据 20 以内整数的排序,进行解答即可.\n【详解】20前面的第一个数是19,第二个数是18,第三个数是17,第四个数是16,所以20前面第4个数是16。故答案为:B", + "knowledge_points": [ + "20以内数的排序" + ], + "source": "24-25 一年级上·湖北襄阳·期末" + }, + { + "id": "220", + "unit": "第二单元 11~20的认识", + "question_type": "选择题", + "difficulty": 0.85, + "question": "□ \u003c 14,□ 里最大填()。", + "options": [ + "A. 20", + "B. 16", + "C. 13" + ], + "answer": "C", + "solution": "【分析】11 到 20,从小到大排序:11,12,13,14,15,16,17,18,19,20。据此解决.\n【详解】由分析可得:A. 20 \u003e 14;B. 16 \u003e 14;C. 13 \u003c 14;即,□ \u003c 14 , □ 里最大填 13 。故答案为: C", + "knowledge_points": [ + "20以内数的比大小" + ], + "source": "24-25 一年级上·湖北襄阳·期末" + }, + { + "id": "221", + "unit": "第二单元 11~20的认识", + "question_type": "选择题", + "difficulty": 0.65, + "question": "今年军军 6 岁,姐姐 8 岁,当姐姐 15 岁时,军军 ( )。", + "options": [ + "A. 13岁", + "B. 14岁", + "C. 15岁" + ], + "answer": "A", + "solution": "【分析】用姐姐今年的岁数减军军今年的岁数,求出姐姐比军军大多少岁。年龄差始终不变,用 15 减姐姐比军军大的岁数,即可求出军军的岁数.\n【详解】 8 - 6 = 2(岁);15 - 2 = 13 (岁)。当姐姐 15 岁时,军军 13 岁。故答案为: A", + "knowledge_points": [ + "8,9 的加减法", + "年龄问题", + "不退位减法(20以内)" + ], + "source": "24-25 一年级下·河南周口·阶段练习" + }, + { + "id": "222", + "unit": "第二单元 11~20的认识", + "question_type": "选择题", + "difficulty": 0.85, + "question": "个位上和十位上相同的数是 ( )。", + "options": [ + "A. 12", + "B. 11", + "C. 13" + ], + "answer": "B", + "solution": "【分析】一个两位数,从右往左依次是个位,十位,逐项找到个位和十位数字相同的选项即可.\n【详解】A。12,个位上是2,十位上是1,个位上和十位上的数不相同;B. 11,个位上是 1,十位上是 1,个位上和十位上的数相同;C. 13,个位上是 3,十位上是 1,个位上和十位上的数不相同。故答案为: B", + "knowledge_points": [ + "20以内数的组成" + ], + "source": "24-25 一年级上·四川乐山·期末" + }, + { + "id": "223", + "unit": "第二单元 11~20的认识", + "question_type": "选择题", + "difficulty": 0.85, + "question": "最小的两位数与最大的一位数之和是 ( )。", + "options": [ + "A. 11", + "B. 19", + "C. 10" + ], + "answer": "B", + "solution": "【分析】根据对数的认识可知,最小的两位数是 10,最大的一位数是 9,相加即可求出和.\n【详解】 10 + 9 = 19,最小的两位数与最大的一位数之和是 19 。故答案为: B", + "knowledge_points": [ + "不进位加法 (20 以内)" + ], + "source": "24-25 一年级上·贵州黔东南·期末" + }, + { + "id": "224", + "unit": "第二单元 11~20的认识", + "question_type": "选择题", + "difficulty": 0.85, + "question": "同学们排队报数,8一15号是男生,男生有()。", + "options": [ + "A. 7人", + "B. 8人", + "C. 9人" + ], + "answer": "B", + "solution": "【分析】数一数 8 到 15 号有哪些,8,9,10,11,12,13,14,15,共8人.\n【详解】同学们排队报数, 8-15 号是男生,男生有 8 人。故答案为: B", + "knowledge_points": [ + "20以内数的排序" + ], + "source": "24-25 一年级下·河南周口·阶段练习" + }, + { + "id": "225", + "unit": "第二单元 11~20的认识", + "question_type": "选择题", + "difficulty": 0.85, + "question": "与19相邻的两个数是()。", + "options": [ + "A. 18 与 19", + "B. 19 和 20", + "C. 18 和 20" + ], + "answer": "C", + "solution": "【分析】20以内数的顺序为0,1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,与 19 相邻的两个数即 19 左右两侧的数,据此解答即可.\n【详解】由 20 以内数的顺序: 18,19,20 可知,与 19 相邻的两个数是 18 和 20。故答案为: C", + "knowledge_points": [ + "20以内数的排序" + ], + "source": "24-25 一年级上·四川乐山·期末" + }, + { + "id": "226", + "unit": "第二单元 11~20的认识", + "question_type": "选择题", + "difficulty": 0.85, + "question": "在算式 13 - 5 = 8 中, 5 是 ( )。", + "options": [ + "A. 减数", + "B. 被减数", + "C. 差" + ], + "answer": "A", + "solution": "【分析】在减法算式中,被减数 - 减数 = 差,据此解答即可.\n【详解】由分析可知:在算式 13 - 5 = 8 中, 5 是减数。故答案为: A", + "knowledge_points": [ + "加,减法的意义和各部分间的关系" + ], + "source": "24-25 一年级上·四川乐山·期末" + }, + { + "id": "227", + "unit": "第二单元 11~20的认识", + "question_type": "选择题", + "difficulty": 0.85, + "question": "育红小学一(1)班男生排队进行体检,从前往后数,小明排第5,小东排第11,小明和小东之间有()名小朋友。", + "options": [ + "A. 5", + "B. 6", + "C. 7" + ], + "answer": "A", + "solution": "【分析】小明和小东之间还有第 6,7,8,9,10 个同学,数一数即可求解.\n【详解】由分析可知,从前往后数,小明排第 5,小东排第 11,小明和小东之间有 5 名小朋友。故答案为: A", + "knowledge_points": [ + "20以内数的排序" + ], + "source": "24-25 一年级上·河南安阳·期末" + }, + { + "id": "228", + "unit": "第二单元 11~20的认识", + "question_type": "选择题", + "difficulty": 0.85, + "question": "红红和明明读同一本故事书,红红读了 12 页,明明读了 17 页,剩下的页数比一比, ( ) 剩下的多。", + "options": [ + "A. 红红", + "B. 明明", + "C. 无法比较" + ], + "answer": "A", + "solution": "【分析】根据题意可知,他们读的是同一本书,要比较剩下页数的多少,则比较他们读了的页数即可。读了的页数多,剩下的页数少,读了的页数少,剩下的页数多.\n【详解】 17 \u003e 12,明明读了的页数多,剩下的页数少;红红读了的页数少,剩下的页数多。故答案为: A", + "knowledge_points": [ + "20以内数的比大小" + ], + "source": "24-25 一年级上·贵州铜仁·期末" + }, + { + "id": "229", + "unit": "第二单元 11~20的认识", + "question_type": "选择题", + "difficulty": 0.85, + "question": "11 后面的第 4 个数是()。", + "options": [ + "A. 7", + "B. 15", + "C. 14" + ], + "answer": "B", + "solution": "【分析】根据 20 以内数的排序,数到 11,在往后数 4 个数即可求出 11 后面的第 4 个数是几.\n【详解】1,2,3,4,5,6,7,8,9,10,11,12,13,14,15。则11后面的第4个数是15。故答案为: B", + "knowledge_points": [ + "20以内数的排序" + ], + "source": "24-25 一年级上·贵州铜仁·期末" + }, + { + "id": "230", + "unit": "第二单元 11~20的认识", + "question_type": "选择题", + "difficulty": 0.85, + "question": "学校门口插了 10 面红旗,每两面红旗中间又插了一面黄旗,一共有 ( ) 面旗。", + "options": [ + "A. 10", + "B. 15", + "C. 19", + "D. 20" + ], + "answer": "C", + "solution": "【分析】根据题意可知,先算出黄旗的数量,每两面红旗中间又插了一面黄旗,黄旗的数量等于红旗的数量少 1,再用黄旗的数量加上红旗的数量,等于一共有多少面旗,据此解答.\n【详解】根据分析可得:黄旗的数量:10 - 1 = 9 (面);旗的总数量:10 + 9 = 19 (面),一共有 19 面旗。故答案为: C", + "knowledge_points": [ + "植树问题(两端都不栽)", + "10 的加减法", + "不进位加法 (20 以内)" + ], + "source": "24-25 二年级上·浙江温州·期末" + }, + { + "id": "231", + "unit": "第二单元 11~20的认识", + "question_type": "选择题", + "difficulty": 0.85, + "question": "从 5 数到 13,一共数了 ( ) 个数。", + "options": [ + "A. 8", + "B. 7", + "C. 9" + ], + "answer": "C", + "solution": "【分析】根据题意,按照 20 以内数的顺序从 5 数到 13,数出数字的个数即可,包括 5 和 13.\n【详解】从5数到13,依次为5, 6, 7, 8, 9, 10, 11, 12, 13,一共数了 9 个数。故答案为: C", + "knowledge_points": [ + "数 100 以内的数" + ], + "source": "24-25 一年级上·湖南株洲·期末" + }, + { + "id": "232", + "unit": "第二单元 11~20的认识", + "question_type": "选择题", + "difficulty": 0.85, + "question": "下列说法中,正确的一项是 ( )。", + "options": [ + "A. 10 - 10 = 0,则 11 - 10 = 0。", + "B. 12 比 11 大 1。", + "C. 十七可以分成 1 和 17。", + "D. 分针指向 12,时针指向 7,是 12 时。" + ], + "answer": "B", + "solution": "【分析】A。 根据整数加减法的计算法则,计算出结果进行判断;B. 求一个数比另一个数大几,用这个数一另一个数计算;C. 将题中分成的两个数相加,看得出的和与 17 是否相同即可;D. 钟面上长针是分针,短针是时针,分针指向 12,时针指向几就是几时整.\n【详解】A。10 - 10 = 0,11是10后边的1个数,比10大1,则 11 - 10 = 1 。原题说法错误;B. 12 - 11 = 1, 12 比 11 大 1 。原题说正确;C. 1 + 17 = 18, 18 不等于 17,原题说法错误;D. 分针指向 12,时针指向 7,是 7 时。原题说法错误。则说法正确的是12比11大1。故答案为: B", + "knowledge_points": [ + "不进位加法(20以内)", + "不退位减法(20以内)", + "整点时间与钟面指针的位置" + ], + "source": "24-25 一年级上·浙江温州·期末" + }, + { + "id": "233", + "unit": "第二单元 11~20的认识", + "question_type": "选择题", + "difficulty": 0.85, + "question": "下面哪个算式得数跟 17-14 的得数一样 ( )。", + "options": [ + "A. 2 + 5", + "B. 6 + 4", + "C. 8 - 5" + ], + "answer": "C", + "solution": "【分析】算出各算式的得数即可求解。减法计算时,相同数位对齐,从个位减起.\n【详解】17 - 14 = 3;A. 2 + 5 = 7,不一样;B. 6 + 4 = 10,不一样;C. 8 - 5 = 3,一样。算式 8 - 5 的得数跟 17 - 14 的得数一样。故答案为: C", + "knowledge_points": [ + "8,9 的加减法", + "7 的加减法", + "10 的加减法", + "不退位减法 (20 以内)" + ], + "source": "23-24 二年级下·广东汕头·期中" + }, + { + "id": "234", + "unit": "第二单元 11~20的认识", + "question_type": "选择题", + "difficulty": 0.85, + "question": "从8数到15,一共数了()个数。", + "options": [ + "A. 6", + "B. 7", + "C. 8" + ], + "answer": "C", + "solution": "【分析】从 8 数到 15,有8,9,10,11,12,13,14,15,共8个数.\n【详解】从 8 数到 15,一共数了 8 个数。故答案为: C", + "knowledge_points": [ + "20以内数的排序" + ], + "source": "22-23一年级上·云南玉溪·期末" + }, + { + "id": "235", + "unit": "第二单元 11~20的认识", + "question_type": "选择题", + "difficulty": 0.65, + "question": "一个数,个位上的数字比十位上的数字多 5,这个数可能是 ( )。", + "options": [ + "A. 18", + "B. 16", + "C. 14" + ], + "answer": "B", + "solution": "【分析】用个位上的数字减十位上的数字,找出得数是 5 的即可.\n【详解】A。 8 - 1 = 7, 18 个位比十位多 7,不符合;B. 6 - 1 = 5, 16 个位比十位多 5,符合;C. 4 - 1 = 3, 14 个位比十位多 3,不符合。这个数可能是 16。故答案为: B", + "knowledge_points": [ + "20以内数的组成" + ], + "source": "24-25 一年级上·山西晋中·期末" + }, + { + "id": "236", + "unit": "第二单元 11~20的认识", + "question_type": "选择题", + "difficulty": 0.85, + "question": "在 4, 14, 8, 10, 18, 20 这 6 个数中,比 15 小的数有 ( )个。", + "options": [ + "A. 4", + "B. 3", + "C. 2" + ], + "answer": "A", + "solution": "【分析】根据题意可知,题目要求在给定的6个数(4,14,8,10,18,20) 中找出比 15 小的数, 20 以内数从小到大为: 0 \u003c 1 \u003c 2 \u003c 3 \u003c 4 \u003c 5 \u003c 6 \u003c 7 \u003c 8 \u003c 9 \u003c 10 \u003c 11\u003c12 \u003c 13 \u003c 14 \u003c 15 \u003c 16 \u003c 17 \u003c 18 \u003c 19 \u003c 20,由此比较大小即可;18,20 均大于 15,不满足条件,而 4,14,8,10 均小于 15,共 4 个.\n【详解】在 4, 14, 8, 10, 18, 20 这 6 个数中,比 15 小的数有: 4,14,8,10,数一数可知,共 4 个。故答案为: A", + "knowledge_points": [ + "20以内数的排序", + "20以内数的比大小" + ], + "source": "24-25 一年级上·湖南湘西·期末" + }, + { + "id": "237", + "unit": "第二单元 11~20的认识", + "question_type": "选择题", + "difficulty": 0.85, + "question": "在算式 15 - 4 = 11 中,减数是()。", + "options": [ + "A. 15", + "B. 4", + "C. 11" + ], + "answer": "B", + "solution": "【分析】在减法算式\"被减数 - 减数 = 差\"中:被减数是第一个数(要减去的数),对应题目中的 15,减数是第二个数(用来减去的数),对应题目中的 4,差是结果,对应 11.\n【详解】在算式 15 - 4 = 11 中的减数是 4 。故答案为: B", + "knowledge_points": [ + "不退位减法 (20以内)" + ], + "source": "24-25一年级上·湖南湘西·期末" + }, + { + "id": "238", + "unit": "第二单元 11~20的认识", + "question_type": "选择题", + "difficulty": 0.85, + "question": "16 后面的第 3 个数是()。", + "options": [ + "A. 17", + "B. 18", + "C. 19" + ], + "answer": "C", + "solution": "【分析】根据题意可知,题目要求找出 16 后面的第 3 个数,从 16 开始往后数,第 1 个数是 17,第 2 个数是 18,第 3 个数是 19,据此选择.\n【详解】根据分析可得:16 后面的第 3 个数是 19。 故答案为: C", + "knowledge_points": [ + "20以内数的排序" + ], + "source": "24-25 一年级上·湖南湘西·期末" + }, + { + "id": "239", + "unit": "第二单元 11~20的认识", + "question_type": "选择题", + "difficulty": 0.85, + "question": "20 前面第 4 个数是()。", + "options": [ + "A. 9", + "B. 16", + "C. 18" + ], + "answer": "B", + "solution": "【分析】要求 20 前面的第 4 个数是多少,根据 20 以内整数的排序,进行解答即可.\n【详解】20前面的第一个数是19,第二个数是18,第三个数是17,第四个数是16,所以20前面第4个数是16。故答案为:B", + "knowledge_points": [ + "20以内数的排序" + ], + "source": "24-25 一年级上·湖北襄阳·期末" + }, + { + "id": "240", + "unit": "第二单元 11~20的认识", + "question_type": "选择题", + "difficulty": 0.85, + "question": "□\u003c14,□ 里最大填()。", + "options": [ + "A. 20", + "B. 16", + "C. 13" + ], + "answer": "C", + "solution": "【分析】11 到 20,从小到大排序:11,12,13,14,15,16,17,18,19,20。据此解决.\n【详解】由分析可得:A. 20 \u003e 14;B. 16 \u003e 14;C. 13 \u003c 14;即, □ \u003c 14 , □ 里最大填 13 。故答案为: C", + "knowledge_points": [ + "20以内数的比大小" + ], + "source": "24-25 一年级上·湖北襄阳·期末" + }, + { + "id": "241", + "unit": "第二单元 11~20的认识", + "question_type": "选择题", + "difficulty": 0.65, + "question": "今年军军 6 岁,姐姐 8 岁,当姐姐 15 岁时,军军 ( )。", + "options": [ + "A. 13岁", + "B. 14岁", + "C. 15岁" + ], + "answer": "A", + "solution": "【分析】用姐姐今年的岁数减军军今年的岁数,求出姐姐比军军大多少岁。年龄差始终不变,用 15 减姐姐比军军大的岁数,即可求出军军的岁数.\n【详解】 8 - 6 = 2(岁);15 - 2 = 13 (岁)。当姐姐 15 岁时,军军 13 岁。故答案为: A", + "knowledge_points": [ + "8,9 的加减法", + "年龄问题", + "不退位减法(20以内)" + ], + "source": "24-25 一年级下·河南周口·阶段练习" + }, + { + "id": "242", + "unit": "第二单元 11~20的认识", + "question_type": "选择题", + "difficulty": 0.85, + "question": "个位上和十位上相同的数是 ( )。", + "options": [ + "A. 12", + "B. 11", + "C. 13" + ], + "answer": "B", + "solution": "【分析】一个两位数,从右往左依次是个位,十位,逐项找到个位和十位数字相同的选项即可.\n【详解】A。12,个位上是2,十位上是1,个位上和十位上的数不相同;B. 11,个位上是 1,十位上是 1,个位上和十位上的数相同;C. 13,个位上是 3,十位上是 1,个位上和十位上的数不相同。故答案为: B", + "knowledge_points": [ + "20以内数的组成" + ], + "source": "24-25 一年级上·四川乐山·期末" + }, + { + "id": "243", + "unit": "第二单元 11~20的认识", + "question_type": "选择题", + "difficulty": 0.85, + "question": "最小的两位数与最大的一位数之和是 ( )。", + "options": [ + "A. 11", + "B. 19", + "C. 10" + ], + "answer": "B", + "solution": "【分析】根据对数的认识可知,最小的两位数是 10,最大的一位数是 9,相加即可求出和.\n【详解】 10 + 9 = 19,最小的两位数与最大的一位数之和是 19 。故答案为: B", + "knowledge_points": [ + "不进位加法 (20 以内)" + ], + "source": "24-25 一年级上·贵州黔东南·期末" + }, + { + "id": "244", + "unit": "第二单元 11~20的认识", + "question_type": "选择题", + "difficulty": 0.85, + "question": "同学们排队报数,8一15号是男生,男生有()。", + "options": [ + "A. 7人", + "B. 8人", + "C. 9人" + ], + "answer": "B", + "solution": "【分析】数一数 8 到 15 号有哪些,8,9,10,11,12,13,14,15,共8人.\n【详解】同学们排队报数, 8-15 号是男生,男生有 8 人。故答案为: B", + "knowledge_points": [ + "20以内数的排序" + ], + "source": "24-25 一年级下·河南周口·阶段练习" + }, + { + "id": "245", + "unit": "第二单元 11~20的认识", + "question_type": "选择题", + "difficulty": 0.85, + "question": "与19相邻的两个数是()。", + "options": [ + "A. 18 与 19", + "B. 19 和 20", + "C. 18 和 20" + ], + "answer": "C", + "solution": "【分析】20以内数的顺序为0,1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,与 19 相邻的两个数即 19 左右两侧的数,据此解答即可.\n【详解】由 20 以内数的顺序: 18,19,20 可知,与 19 相邻的两个数是 18 和 20。故答案为: C", + "knowledge_points": [ + "20以内数的排序" + ], + "source": "24-25 一年级上·四川乐山·期末" + }, + { + "id": "246", + "unit": "第二单元 11~20的认识", + "question_type": "选择题", + "difficulty": 0.85, + "question": "在算式 13 - 5 = 8 中, 5 是 ( )。", + "options": [ + "A. 减数", + "B. 被减数", + "C. 差" + ], + "answer": "A", + "solution": "【分析】在减法算式中,被减数 - 减数 = 差,据此解答即可.\n【详解】由分析可知:在算式 13 - 5 = 8 中, 5 是减数。故答案为: A", + "knowledge_points": [ + "加,减法的意义和各部分间的关系" + ], + "source": "24-25 一年级上·四川乐山·期末" + }, + { + "id": "247", + "unit": "第二单元 11~20的认识", + "question_type": "选择题", + "difficulty": 0.85, + "question": "育红小学一(1)班男生排队进行体检,从前往后数,小明排第5,小东排第11,小明和小东之间有()名小朋友。", + "options": [ + "A. 5", + "B. 6", + "C. 7" + ], + "answer": "A", + "solution": "【分析】小明和小东之间还有第 6,7,8,9,10 个同学,数一数即可求解.\n【详解】由分析可知,从前往后数,小明排第 5,小东排第 11,小明和小东之间有 5 名小朋友。故答案为: A", + "knowledge_points": [ + "20以内数的排序" + ], + "source": "24-25 一年级上·河南安阳·期末" + }, + { + "id": "248", + "unit": "第二单元 11~20的认识", + "question_type": "选择题", + "difficulty": 0.85, + "question": "红红和明明读同一本故事书,红红读了 12 页,明明读了 17 页,剩下的页数比一比, ( ) 剩下的多。", + "options": [ + "A. 红红", + "B. 明明", + "C. 无法比较" + ], + "answer": "A", + "solution": "【分析】根据题意可知,他们读的是同一本书,要比较剩下页数的多少,则比较他们读了的页数即可。读了的页数多,剩下的页数少,读了的页数少,剩下的页数多.\n【详解】 17 \u003e 12,明明读了的页数多,剩下的页数少;红红读了的页数少,剩下的页数多。故答案为: A", + "knowledge_points": [ + "20以内数的比大小" + ], + "source": "24-25 一年级上·贵州铜仁·期末" + }, + { + "id": "249", + "unit": "第二单元 11~20的认识", + "question_type": "选择题", + "difficulty": 0.85, + "question": "11 后面的第 4 个数是()。", + "options": [ + "A. 7", + "B. 15", + "C. 14" + ], + "answer": "B", + "solution": "【分析】根据 20 以内数的排序,数到 11,在往后数 4 个数即可求出 11 后面的第 4 个数是几.\n【详解】1,2,3,4,5,6,7,8,9,10,11,12,13,14,15。则11后面的第4个数是15。故答案为: B", + "knowledge_points": [ + "20以内数的排序" + ], + "source": "24-25 一年级上·贵州铜仁·期末" + }, + { + "id": "250", + "unit": "第二单元 11~20的认识", + "question_type": "选择题", + "difficulty": 0.85, + "question": "学校门口插了 10 面红旗,每两面红旗中间又插了一面黄旗,一共有 ( ) 面旗。", + "options": [ + "A. 10", + "B. 15", + "C. 19", + "D. 20" + ], + "answer": "C", + "solution": "【分析】根据题意可知,先算出黄旗的数量,每两面红旗中间又插了一面黄旗,黄旗的数量等于红旗的数量少 1,再用黄旗的数量加上红旗的数量,等于一共有多少面旗,据此解答.\n【详解】根据分析可得:黄旗的数量:10 - 1 = 9 (面);旗的总数量:10 + 9 = 19 (面),一共有 19 面旗。故答案为: C", + "knowledge_points": [ + "植树问题(两端都不栽)", + "10 的加减法", + "不进位加法 (20 以内)" + ], + "source": "24-25 二年级上·浙江温州·期末" + }, + { + "id": "251", + "unit": "第二单元 11~20的认识", + "question_type": "选择题", + "difficulty": 0.85, + "question": "从 5 数到 13,一共数了 ( ) 个数。", + "options": [ + "A. 8", + "B. 7", + "C. 9" + ], + "answer": "C", + "solution": "【分析】根据题意,按照 20 以内数的顺序从 5 数到 13,数出数字的个数即可,包括 5 和 13.\n【详解】从5数到13,依次为5, 6, 7, 8, 9, 10, 11, 12, 13,一共数了 9 个数。故答案为: C", + "knowledge_points": [ + "数 100 以内的数" + ], + "source": "24-25 一年级上·湖南株洲·期末" + }, + { + "id": "252", + "unit": "第二单元 11~20的认识", + "question_type": "选择题", + "difficulty": 0.85, + "question": "下列说法中,正确的一项是 ( )。", + "options": [ + "A. 10 - 10 = 0,则 11 - 10 = 0 。", + "B. 12 比 11 大 1。", + "C. 十七可以分成 1 和 17。", + "D. 分针指向 12,时针指向 7,是 12 时。" + ], + "answer": "B", + "solution": "【分析】A。 根据整数加减法的计算法则,计算出结果进行判断;B. 求一个数比另一个数大几,用这个数一另一个数计算;C. 将题中分成的两个数相加,看得出的和与 17 是否相同即可;D. 钟面上长针是分针,短针是时针,分针指向 12,时针指向几就是几时整.\n【详解】A。10 - 10 = 0,11是10后边的1个数,比10大1,则 11 - 10 = 1 。原题说法错误;B. 12 - 11 = 1, 12 比 11 大 1 。原题说正确;C. 1 + 17 = 18, 18 不等于 17,原题说法错误;D. 分针指向 12,时针指向 7,是 7 时。原题说法错误。则说法正确的是12比11大1。故答案为: B", + "knowledge_points": [ + "不进位加法(20以内)", + "不退位减法(20以内)", + "整点时间与钟面指针的位置" + ], + "source": "24-25 一年级上·浙江温州·期末" + }, + { + "id": "253", + "unit": "第二单元 11~20的认识", + "question_type": "选择题", + "difficulty": 0.85, + "question": "下面哪个算式得数跟 17-14 的得数一样 ( )。", + "options": [ + "A. 2 + 5", + "B. 6 + 4", + "C. 8 - 5" + ], + "answer": "C", + "solution": "【分析】算出各算式的得数即可求解。减法计算时,相同数位对齐,从个位减起.\n【详解】17 - 14 = 3;A. 2 + 5 = 7,不一样;B. 6 + 4 = 10,不一样;C. 8 - 5 = 3,一样。算式 8 - 5 得数跟 17 - 14 的得数一样。故答案为: C", + "knowledge_points": [ + "8,9 的加减法", + "7 的加减法", + "10 的加减法", + "不退位减法 (20 以内)" + ], + "source": "23-24 二年级下·广东汕头·期中" + }, + { + "id": "254", + "unit": "第二单元 11~20的认识", + "question_type": "选择题", + "difficulty": 0.65, + "question": "一本故事书 20 页,丽丽今天从第 5 页看到第 12 页,明天丽丽应该从第()页开始看。", + "options": [ + "A. 6", + "B. 13", + "C. 17" + ], + "answer": "B", + "solution": "【分析】把今天看到的第 12 页加上 1 页,算出的结果就是明天应该开始看的页码.\n【详解】 12 + 1 = 13(页)即,一本故事书 20 页,丽丽今天从第 5 页看到第 12 页,明天丽丽应该从第 13 页开始看。故答案为: B", + "knowledge_points": [ + "不进位加法 (20 以内)" + ], + "source": "24-25 一年级上·福建福州·期末" + }, + { + "id": "255", + "unit": "第二单元 11~20的认识", + "question_type": "选择题", + "difficulty": 0.65, + "question": "小于 15 的两位数有()个。", + "options": [ + "A. 5", + "B. 6", + "C. 4" + ], + "answer": "A", + "solution": "【分析】小于 15 的两位数有: 14,13,12,11,10,共 5 个.\n【详解】小于15的两位数有5个。故答案为: A", + "knowledge_points": [ + "20以内数的比大小" + ], + "source": "24-25 一年级上·四川广元·期末" + }, + { + "id": "256", + "unit": "第二单元 11~20的认识", + "question_type": "选择题", + "difficulty": 0.85, + "question": "下面各数最接近 10的是()。", + "options": [ + "A. 8", + "B. 9", + "C. 12" + ], + "answer": "B", + "solution": "【分析】20以内数从小到大排列顺序为:0,1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,据此解答即可.\n【详解】根据观察可知:A. 8 是 10 前一个数的前一个,不是最接近的数;B. 9 是 10 前一个数,是最接近的数;C. 12 是 10 后一个数的后一个,不是最接近的数;故答案为: B", + "knowledge_points": [ + "20以内数的排序" + ], + "source": "24-25 一年级上·湖北随州·期末" + }, + { + "id": "257", + "unit": "第二单元 11~20的认识", + "question_type": "选择题", + "difficulty": 0.85, + "question": "从 10 开始数, 10,11,12。数到 20,一共数了()个数。", + "options": [ + "A. 11", + "B. 10", + "C. 9" + ], + "answer": "A", + "solution": "【分析】按照 20 的排序,结合题干要求数一数,即可得出答案.\n【详解】10,11,12,13,14,15,16,17,18,19,20,所以从 10 开始数到 20 一共数了 11 个数。故答案为:A", + "knowledge_points": [ + "20以内数的排序" + ], + "source": "24-25 一年级上·湖北黄石·期末" + }, + { + "id": "258", + "unit": "第二单元 11~20的认识", + "question_type": "选择题", + "difficulty": 0.85, + "question": "2 个 2 个地数, 10 后面是 ( )。", + "options": [ + "A. 8", + "B. 11", + "C. 12" + ], + "answer": "C", + "solution": "【分析】2 个 2 个地数,后一个数比前一个数多 2;据此解答.\n【详解】根据分析可得:10 + 2 = 12故,2个2个地数,10后面是12。故答案为: C", + "knowledge_points": [ + "20以内数的排序", + "不进位加法(20以内)" + ], + "source": "24-25 一年级上·福建三明·期末" + }, + { + "id": "259", + "unit": "第二单元 11~20的认识", + "question_type": "填空题", + "difficulty": 0.85, + "question": "比 18 多 1 的数是( ), 比 14 少 1 的数是( )。", + "options": [ + + ], + "answer": "19,13", + "solution": "【分析】1 到 20,从小到大排序:1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20。一个数前面第一个数比它少 1,后面第一个数比它多1.\n【详解】比 18 多 1 的数是 19,比 14 少 1 的数是 13。", + "knowledge_points": [ + "20以内数的排序" + ], + "source": "24-25 一年级上·河南周口·期末" + }, + { + "id": "260", + "unit": "第二单元 11~20的认识", + "question_type": "填空题", + "difficulty": 0.85, + "question": "9 个一和 1 个十合起来是( ),它前面的第 5 个数是( )。", + "options": [ + + ], + "answer": "19;14", + "solution": "【分析】一个两位数,从右往左依次为个位,十位。十位上的数表示几个十,个位上的数表示几个一。9个一是9,1个十是10,合起来是19。它前面的第5个数,根据数的顺序解答.\n【详解】19前面的第一个数是 18,第二个数是 17,第三个数是 16,第四个数是 15,第五个数是 14.9个一和1个十合起来是19,它前面的第5个数是 14。", + "knowledge_points": [ + "20以内数的组成", + "20以内数的排序" + ], + "source": "24-25 一年级上·山西晋中·期末" + }, + { + "id": "261", + "unit": "第二单元 11~20的认识", + "question_type": "填空题", + "difficulty": 0.85, + "question": "7 后面的第 4 个数是( )。", + "options": [ + + ], + "answer": "11", + "solution": "【分析】根据 20 以内数的顺序,从 7 开始,后面的数依次为 8,9,10。由此找出对应的数.\n【详解】由分析得:7后面第1个数是8,第2个数是9,第3个数是10,第4个数是11。", + "knowledge_points": [ + "20以内数的排序" + ], + "source": "24-25 一年级上·山西长治·期末" + }, + { + "id": "262", + "unit": "第二单元 11~20的认识", + "question_type": "填空题", + "difficulty": 0.85, + "question": "13 里面有( )个十和( )个一;2 个十是( )。", + "options": [ + + ], + "answer": "1;3;20", + "solution": "【分析】一个两位数,从右往左依次是个位,十位,十位上是几就表示几个十,个位上是几就表示几个一.\n【详解】由分析得:13里面有1个十和3个一;2个十是 20。", + "knowledge_points": [ + "20以内数的组成" + ], + "source": "24-25 一年级上·山东济南·期末" + }, + { + "id": "263", + "unit": "第二单元 11~20的认识", + "question_type": "填空题", + "difficulty": 0.85, + "question": "由 12 个一组成 的数是( ),和它相邻的两个数是( )和( )。", + "options": [ + + ], + "answer": "12;11;13", + "solution": "【分析】根据数的组成可知, 1 个十和 2 个一合起来是 12 , 12 个一即 12 个 1 相加,结果为 12;相邻的两个数是指比该数小 1 和大 1 的数,因此, 12 的相邻数是 11 和 13.\n【详解】根据分析可得:12 - 1 = 11;2 + 1 = 13,由 12 个一组成的数是 12,和它相邻的两个数是 11 和 13。", + "knowledge_points": [ + "20以内数的组成", + "不进位加法(20以内)", + "不退位减法(20以内)" + ], + "source": "24-25 一年级下·广东揭阳·阶段练习" + }, + { + "id": "264", + "unit": "第二单元 11~20的认识", + "question_type": "填空题", + "difficulty": 0.65, + "question": "在括号里填上\"+\"或\"-\".\n\n19( ) 9 = 10;14( ) 6 = 20;9( ) 6 \u003c 10;18( ) 7 \u003c 12", + "options": [ + + ], + "answer": "-;+;-;-", + "solution": "【分析】根据整数加减法的计算法则即数的比大小进行解答。19 可以分成 9 和 10,即用减法计算;14后边的第1个数是15,第2个数是16,第3个数是17,第4个数是18,第5个数是19,第6个数是20,即用加法计算;左侧的结果要小于 10,只有 9 可以分成 6 和 3 符合题意,即用减法计算;左侧的结果要小于 12,只有 18 分成 7 和 11 符合题意,即用减法计算.\n【详解】 19 - 9 = 1014 + 6 = 209 - 6 \u003c 1018 - 7 \u003c 12", + "knowledge_points": [ + "8,9 的加减法", + "不退位减法(20 以内)", + "20 以内数的比大小" + ], + "source": "24-25 一年级上·山东济宁·期末" + }, + { + "id": "265", + "unit": "第二单元 11~20的认识", + "question_type": "填空题", + "difficulty": 0.85, + "question": "在括号里填上\"\u003c\" \"\u003e\"或\"=\".\n\n9 () 11;8 - 7 () 12 + 3;19 - 9 () 10 + 1;3 + 7 () 5 + 5", + "options": [ + + ], + "answer": "\u003c;\u003c;\u003c;=", + "solution": "【分析】根据整数加减法的计算法则,依次计算出各算式的结果再比较大小。20 以内数从大到小关系为 20 \u003e 19 \u003e 18 \u003e17 \u003e16 \u003e15 \u003e14\u003e 13 \u003e 12 \u003e11 \u003e 10 \u003e 9 \u003e 8 \u003e7 \u003e 6 \u003e 5 \u003e 4 \u003e 3 \u003e2 \u003e1 \u003e 0,由此比较.\n【详解】 9 \u003c 11;8 - 7 = 1;12 + 3 = 15;1 \u003c 15,则 8 - 7 \u003c 12 + 3;19 - 9 = 10;10 + 1 = 11;10 \u003c 11,则 19 - 9 \u003c 10 + 1;3 + 7 = 10;5 + 5 = 10;10 = 10,则 3 + 7 = 5 + 5 。", + "knowledge_points": [ + "10 的加减法", + "不进位加法(20 以内)", + "不退位减法(20 以内)", + "20 以内数的比大小" + ], + "source": "24-25 一年级上·山东济宁·期末" + }, + { + "id": "266", + "unit": "第二单元 11~20的认识", + "question_type": "填空题", + "difficulty": 0.85, + "question": "19 里面有( )个十和( )个一。", + "options": [ + + ], + "answer": "1;9", + "solution": "【分析】一个两位数,从右往左数,第一位是个位,个位上的数表示几个一;第二位是十位,十位上的数表示几个十.\n【详解】19里面有1个十和9个一。", + "knowledge_points": [ + "20以内数的组成" + ], + "source": "24-25 一年级上·山东济宁·期末" + }, + { + "id": "267", + "unit": "第二单元 11~20的认识", + "question_type": "填空题", + "difficulty": 0.85, + "question": "17 的个位上是( ),表示( )个一,十位上是( ),表示( )个十。", + "options": [ + + ], + "answer": "7;7;1;1", + "solution": "【分析】一个两位数,从右往左依次为个位,十位,十位上的数表示几个十,个位上的数表示几个一,由此解答.\n【详解】17 的个位上是 7,表示 7 个一,十位上是 1,表示 1 个十。", + "knowledge_points": [ + "20以内数的组成" + ], + "source": "24-25 一年级下·广东揭阳·阶段练习" + }, + { + "id": "268", + "unit": "第二单元 11~20的认识", + "question_type": "填空题", + "difficulty": 0.85, + "question": "16 里面有( )个十和( )个一。", + "options": [ + + ], + "answer": "1;6", + "solution": "【分析】一个两位数,从右往左数,第一位是个位,个位上的数表示几个一;第二位是十位,十位上的数表示几个十.\n【详解】16里面有1个十和6个一。", + "knowledge_points": [ + "20以内数的组成" + ], + "source": "21-22 一年级上·山西大同·期末" + }, + { + "id": "269", + "unit": "第二单元 11~20的认识", + "question_type": "填空题", + "difficulty": 0.65, + "question": "与18相邻的两个数分别是( )和( )。", + "options": [ + + ], + "answer": "17;19", + "solution": "【分析】与一个数相邻的两个数分别是比它小 1 的数和比它大 1 的数。比 18 小 1 的数是: 18 - 1 = 17;比 18 大 1 的数是: 18 + 1 = 19。因此,与 18 相邻的两个数是 17 和 19.\n【详解】与18相邻的两个数分别是17和 19。", + "knowledge_points": [ + "20以内数的排序" + ], + "source": "24-25 一年级上·湖南湘西·期末" + }, + { + "id": "270", + "unit": "第二单元 11~20的认识", + "question_type": "填空题", + "difficulty": 0.85, + "question": "在 12 和 14 之间的是( ),它是由( )个十和( )个一组成的。", + "options": [ + + ], + "answer": "13;1;3", + "solution": "【分析】根据20以内数的排序即可求出12和14之间的数。0,1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20。一个两位数,从右边往左数,第一位是个位,个位上是几,就表示几个一,第二位是十位,十位上是几,就表示几个十.\n【详解】在 12 和 14 之间的是 13,它是由 1 个十和 3 个一组成的。", + "knowledge_points": [ + "20以内数的组成", + "20以内数的排序" + ], + "source": "24-25 一年级上·安徽黄山·期末" + }, + { + "id": "271", + "unit": "第二单元 11~20的认识", + "question_type": "填空题", + "difficulty": 0.65, + "question": "在括号填上\"\u003e\",\"\u003c\"或\"=\".\n\n3 + 5 ( ) 12;9 - 1 ( ) 8 - 0;3 + 7 ( ) 9 - 2;20 ( ) 16 + 3", + "options": [ + + ], + "answer": "\u003c;=;\u003e;\u003e", + "solution": "【分析】20 以内的数从小到大排列是: 1 \u003c 2 \u003c 3 \u003c 4 \u003c 5 \u003c 6 \u003c 7 \u003c 8 \u003c 9 \u003c 10 \u003c 11 \u003c 12 \u003c 13 \u003c 14 \u003c 15 \u003c 16 \u003c 17 \u003c 18 \u003c 19 \u003c20。含有算式的,可以先计算出算式的结果,再比较大小.\n【详解】 3 + 5 = 8,所以 3 + 5 \u003c 12;9 - 1 = 8;8 - 0 = 8,所以9 - 1 = 8 - 0;3 + 7 = 10, 9 - 2 = 7,所以 3 + 7 \u003e 9 - 2;16 + 3 = 19,所以20 \u003e 16 + 3 。", + "knowledge_points": [ + "8,9 的加减法", + "10 的加减法", + "不进位加法(20以内)", + "20 以内数的比大小" + ], + "source": "24-25一年级上·安徽黄山·期末" + }, + { + "id": "272", + "unit": "第二单元 11~20的认识", + "question_type": "填空题", + "difficulty": 0.85, + "question": "与 17 相邻的数是( )和( )。", + "options": [ + + ], + "answer": "16;18", + "solution": "【分析】一个数前面第一个数比它小 1,后面第一个数比它大 1,据此解答即可.\n【详解】与 17 相邻的数是 16 和 18。", + "knowledge_points": [ + "20以内数的排序" + ], + "source": "24-25 一年级上·湖北黄冈·期末" + }, + { + "id": "273", + "unit": "第二单元 11~20的认识", + "question_type": "填空题", + "difficulty": 0.65, + "question": "树干刷石灰水可以有效防止病虫害。张叔叔负责刷第 10 棵到第 19 棵树,张叔叔需要刷( )棵树。", + "options": [ + + ], + "answer": "10", + "solution": "【分析】根据题意,张叔叔刷第 10 到第 19 棵树,则从 10 数到 19,有几个数,就是需要刷几棵树.\n【详解】按顺序从10数到19依次为:10, 11, 12, 13, 14, 15, 16, 17, 18, 19,共 10 个数。张叔叔需要刷 10 棵树。", + "knowledge_points": [ + "20以内数的排序" + ], + "source": "24-25 一年级上·贵州铜仁·期末" + }, + { + "id": "274", + "unit": "第二单元 11~20的认识", + "question_type": "填空题", + "difficulty": 0.85, + "question": "一个两位数个位上的数字是最大的一位数,十位上的数字是 1,这个数是( ),与它相邻的两个数是( )和( )。", + "options": [ + + ], + "answer": "19;18;20", + "solution": "【分析】一个两位数,从右边数起,第一位是个位,第二位是十位;最大的一位数是 9。据此写出该数即可;然后求与其相邻的两个数,即求比其小 1 和多 1 的数即可。即减 1 或加 1.\n【详解】 19 - 1 = 18, 19 + 1 = 20,则一个两位数个位上的数字是最大的一位数,十位上的数字是 1,这个数是 (19) , 与它相邻的两个数是 (18) 和 (20)。", + "knowledge_points": [ + "20以内数的组成", + "不退位减法(20以内)" + ], + "source": "24-25 一年级上·贵州铜仁·期末" + }, + { + "id": "275", + "unit": "第二单元 11~20的认识", + "question_type": "填空题", + "difficulty": 0.85, + "question": "在7,12,10,18,0,20这些数中,最大的数是( ),最小的数是( ),大于10的数有( )个,小于10的数有( )个。", + "options": [ + + ], + "answer": "20;0;3;2", + "solution": "【分析】20 以内数从大到小关系为: 20 \u003e 19 \u003e 18 \u003e 17 \u003e 16 \u003e15 \u003e 14 \u003e 13 \u003e 12 \u003e 11 \u003e 10 \u003e 9 \u003e 8 \u003e 7 \u003e 6 \u003e 5 \u003e 4 \u003e 3 \u003e 2 \u003e 1 \u003e0,由此比较这些数字的大小即可解答.\n【详解】 20 \u003e 18 \u003e 12 \u003e 10 \u003e 7 \u003e 0,大于10的数有20,18,12,共3个,小于10的数有7,0,共2个。在7,12,10,18,0,20这些数中,最大的数是20,最小的数是 0,大于 10 的数有 3 个,小于 10 的数有 2 个。", + "knowledge_points": [ + "20以内数的比大小" + ], + "source": "24-25 一年级上·贵州铜仁·期末" + }, + { + "id": "276", + "unit": "第二单元 11~20的认识", + "question_type": "填空题", + "difficulty": 0.85, + "question": "15个同学排队买票,排在乐乐前面的有4个同学,排在乐乐后面的有( )个同学。", + "options": [ + + ], + "answer": "10", + "solution": "【分析】根据题意,排队的总人数 - 乐乐前面的人数 - 乐乐 = 乐乐后面的人数.\n【详解】15 - 4 - 1 = 10 (个),15 个同学排队买票,排在乐乐前面的有 4 个同学,排在乐乐后面的有 10 个同学。", + "knowledge_points": [ + "不进位,不退位连加,连减(20以内)" + ], + "source": "24-25一年级上·湖北孝感·期末" + }, + { + "id": "277", + "unit": "第二单元 11~20的认识", + "question_type": "填空题", + "difficulty": 0.85, + "question": "最小的两位数是( ),最大的一位数是( ), 它们相差( )。", + "options": [ + + ], + "answer": "10;9;1", + "solution": "【分析】最大的一位数是 9;最小的两位数的十位上是 1,个位上是 0,也就是 10;用减法计算可得两数相差多少;据此解决.\n【详解】由分析可知:10 - 9 = 1,即,最小的两位数是 10,最大的一位数是 9,它们相差 1 。", + "knowledge_points": [ + "10 的加减法", + "10 的认识和读写", + "8,9 的认识和读写" + ], + "source": "16-17 一年级·北京·课后作业" + }, + { + "id": "278", + "unit": "第二单元 11~20的认识", + "question_type": "填空题", + "difficulty": 0.85, + "question": "1 个十和 2 个一合起来是 ( )。", + "options": [ + + ], + "answer": "12", + "solution": "【分析】1个十是10,2个一是2, 10 + 2 = 12 .\n【详解】1个十和2个一合起来是12。", + "knowledge_points": [ + "20以内数的组成" + ], + "source": "17-18 一年级上·全国·期末" + }, + { + "id": "279", + "unit": "第二单元 11~20的认识", + "question_type": "填空题", + "difficulty": 0.85, + "question": "一个数由 3 个一和 1 个十组成,这个数是( )。与它相邻的数是( )和( )它们相差( )。", + "options": [ + + ], + "answer": "13;12;14;2", + "solution": "【分析】一个两位数,从右往左依次为个位,十位,十位上的数表示几个十,个位上的数表示几个一。3个一是3,1个十是10,合起来是13,与它相邻的数是比它小1的数,用它-1计算,和比它大1的数,用它+1计算。这两个数相减即可求出相差多少.\n【详解】13 - 1 = 12;13 + 1 = 14;14 - 12 = 2,一个数由 3 个一和 1 个十组成,这个数是 13。与它相邻的数是 12 和 14,它们相差 2。", + "knowledge_points": [ + "20以内数的组成", + "不进位加法(20以内)", + "不退位减法(20以内)" + ], + "source": "24-25 一年级上·湖南株洲·期末" + }, + { + "id": "280", + "unit": "第二单元 11~20的认识", + "question_type": "解答题", + "difficulty": 0.65, + "question": "有两篮苹果,第一篮有 18 个,第二篮有 10 个,要从第一篮中拿个放入第二篮,两篮的苹果数量相同。", + "options": [ + + ], + "answer": "4", + "solution": "【分析】先用减法计算出第一篮比第二篮多的个数,再计算出多的个数的一半,即可计算出要从第一篮中拿多少个放入第二篮.\n【详解】18 - 10 = 8 (个);4 + 4 = 8 (个),要从第一篮中拿 4 个放入第二篮,两篮的苹果数量相同。", + "knowledge_points": [ + "8,9 的加减法", + "不退位减法(20以内)" + ], + "source": "24-25 一年级上·浙江温州·期末" + }, + { + "id": "281", + "unit": "第二单元 11~20的认识", + "question_type": "填空题", + "difficulty": 0.85, + "question": "一个两位数,十位上是 1,那么这个数最大是。", + "options": [ + + ], + "answer": "19", + "solution": "【分析】十位上是 1,最大的一位数是 9,所以这个数个位上是 9,根据整数的写法,从高位写起,依次写出各位上的数字即可.\n【详解】根据分析可得:一个两位数,十位上是 1,个位上是 9,那么这个数最大是 19。", + "knowledge_points": [ + "20以内数的组成", + "11~20 的认识和读写" + ], + "source": "24-25 一年级上·浙江温州·期末" + }, + { + "id": "282", + "unit": "第二单元 11~20的认识", + "question_type": "填空题", + "difficulty": 0.85, + "question": "在 20,8,7,16 中,比 10 大的数是( ),( ), 比 10 小的数是( ),( )。", + "options": [ + + ], + "answer": "20;16;8;7", + "solution": "【分析】20以内数从大到小关系为: 20 \u003e 19 \u003e 18 \u003e 17 \u003e 16\u003e15 \u003e 14 \u003e 13 \u003e 12 \u003e 11 \u003e 10 \u003e 9 \u003e 8 \u003e 7 \u003e 6 \u003e 5 \u003e 4 \u003e 3 \u003e 2 \u003e 1 \u003e0,由此比较出这些数字的大小即可解答.\n【详解】 20 \u003e 16 \u003e 10 \u003e 8 \u003e 7,在 20,8,7,16 中,比 10 大的数是 20,16,比 10 小的数是 8,7。", + "knowledge_points": [ + "20以内数的比大小" + ], + "source": "24-25 一年级上·河北沧州·期末" + }, + { + "id": "283", + "unit": "第二单元 11~20的认识", + "question_type": "解答题", + "difficulty": 0.85, + "question": "有 11 个小朋友玩老鹰捉小鸡,有 5 个小朋友被抓住了,现在还有个小朋友没有被抓住。", + "options": [ + + ], + "answer": "4", + "solution": "【分析】老鹰捉小鸡游戏中, 1 人是老鹰, 1 人是母鸡,其余的是小鸡,则用小朋友的总人数先减去老鹰和母鸡的人数,求出一共有多少只小鸡,再减去被抓住的数量,即可求出没被抓住的数量.\n【详解】11 - 1 - 1 = 9 (个),9 - 5 = 4 (个)有 11 个小朋友玩老鹰捉小鸡,有 5 个小朋友被抓住了,现在还有 4 个小朋友没有被抓住。", + "knowledge_points": [ + "8,9 的加减法", + "不进位,不退位连加,连减 (20 以内)" + ], + "source": "24-25 一年级上·浙江温州·期末" + }, + { + "id": "284", + "unit": "第二单元 11~20的认识", + "question_type": "填空题", + "difficulty": 0.85, + "question": "8 比( )多 3, 16 比( )少 2。", + "options": [ + + ], + "answer": "5;18", + "solution": "【分析】已知一个数比另一个多多少,求另一个数,用减法列式解决;已知一个数比另一个少多少,求另一个数,用加法列式解决;据此解决.\n【详解】8 - 3 = 5,16 + 2 = 18即,8比5多3,16比18少2。", + "knowledge_points": [ + "8,9 的加减法", + "不退位减法(20以内)" + ], + "source": "24-25 一年级上·河南漯河·期末" + }, + { + "id": "285", + "unit": "第二单元 11~20的认识", + "question_type": "填空题", + "difficulty": 0.85, + "question": "20 的个位上是( ),十位上是( ),表示( )个( )。", + "options": [ + + ], + "answer": "0;2;2;十", + "solution": "【分析】一个两位数,从右边到左边开始数,第一位是个位,个位上是几就表示几个一,第二位是十位,十位上几就表示几个十.\n【详解】20 的个位上是 (0),十位上是 (2),表示 (2)个 (十)。", + "knowledge_points": [ + "20以内数的组成" + ], + "source": "24-25 一年级上·广西贵港·期末" + }, + { + "id": "286", + "unit": "第二单元 11~20的认识", + "question_type": "解答题", + "difficulty": 0.85, + "question": "小亮昨天看了 10 页书,今天从第 11 页看到第 16 页,这两天一共看了( )页。", + "options": [ + + ], + "answer": "16", + "solution": "【分析】用今天看到的页数减去今天起始看的页数,再加上1页,即可计算出今天看的页数,最后加上昨天看的页数,即可计算出这两天一共看了多少页.\n【详解】16 - 11 + 1 = 5 + 1 =6 (页),10 + 6 = 16 (页),则这两天一共看了 16 页。", + "knowledge_points": [ + "不进位加法(20以内)", + "加减混合运算(20以内)" + ], + "source": "24-25一年级上·浙江宁波·期末" + }, + { + "id": "287", + "unit": "第二单元 11~20的认识", + "question_type": "填空题", + "difficulty": 0.65, + "question": "一个数个位上的数字比十位上的数字大 5,十位上是 1,这个数后面第一个数是( )。", + "options": [ + + ], + "answer": "17", + "solution": "【分析】一个两位数,从右往左依次为个位,十位。十位是1,个位数字比十位数字大5,则用十位的数字 +5 = 个位数字,由此组成数字,这个数后面的第一个数也就是比它大1的数,用它 +1 即可.\n【详解】十位是 1,个位: 1 + 5 = 6,组成的数字是 16;16 + 1 = 17,一个数个位上的数字比十位上的数字大 5,十位上是 1,这个数后面第一个数是 17。", + "knowledge_points": [ + "20以内数的组成", + "20以内数的排序" + ], + "source": "24-25 一年级上·浙江宁波·期末" + }, + { + "id": "288", + "unit": "第二单元 11~20的认识", + "question_type": "填空题", + "difficulty": 0.85, + "question": "比16大并且比19小的数有( )个。", + "options": [ + + ], + "answer": "2", + "solution": "【分析】20 以内数从大到小关系为: 20 \u003e 19 \u003e 18 \u003e 17 \u003e 16\u003e15 \u003e 14 \u003e 13 \u003e 12 \u003e 11 \u003e 10 \u003e 9 \u003e 8 \u003e 7 \u003e 6 \u003e 5 \u003e 4 \u003e 3 \u003e 2 \u003e 1 \u003e0,由此找出比 16 大比 19 小的数即可。 \n【详解】由分析可知,比 16 大并且比 19 小的数有 17, 18,共有 2 个。 ", + "knowledge_points": [ + "20以内数的比大小" + ], + "source": "24-25 一年级上·浙江宁波·期末" + }, + { + "id": "289", + "unit": "第二单元 11~20的认识", + "question_type": "填空题", + "difficulty": 0.85, + "question": "14 里的 \"1\" 在( )位上,表示( )个( )。", + "options": [ + + ], + "answer": "十;1;十", + "solution": "【分析】一个两位数,从右往左依次为个位,十位,十位是几表示几个十,个位是几表示几个一,由此解答.\n【详解】14里的\"1\"在十位上,表示1个十。", + "knowledge_points": [ + "20以内数的组成" + ], + "source": "24-25 一年级上·浙江宁波·期末" + }, + { + "id": "290", + "unit": "第二单元 11~20的认识", + "question_type": "填空题", + "difficulty": 0.85, + "question": "一个两位数比 20 小,十位上的数字和个位上的数字相同,这个两位数是( )。", + "options": [ + + ], + "answer": "11", + "solution": "【分析】两位数比 20 小,十位上的数字是 1,十位上的数字和个位上的数字相同,个位上的数字也是 1,这个两位数是 11.\n【详解】一个两位数比 20 小,十位上的数字和个位上的数字相同,这个两位数是 11。", + "knowledge_points": [ + "20以内数的组成", + "11~20 的认识和读写" + ], + "source": "24-25 一年级上·湖北武汉·期末" + }, + { + "id": "291", + "unit": "第二单元 11~20的认识", + "question_type": "填空题", + "difficulty": 0.85, + "question": "从右边起第一位是( )位,第二位是( )位。有 1 个十在十位写( ), 有 2 个十在十位写( ), 有 8 个一在个位写( )。", + "options": [ + + ], + "answer": "个;十;1;2;8", + "solution": "【分析】一个整数,从右边起,第一位是个位,第二位是十位。写数时,从高位写起,有几个十就在十位写几,有几个一就在个位写几.\n【详解】从右边起第一位是个位,第二位是十位。有 1 个十在十位写 1,有 2 个十在十位写 2,有 8 个一在个位写 8。", + "knowledge_points": [ + "20以内数的组成", + "11~20 的认识和读写" + ], + "source": "24-25 一年级上·广东云浮·期末" + }, + { + "id": "292", + "unit": "第二单元 11~20的认识", + "question_type": "判断题", + "difficulty": 0.85, + "question": "从 10 开始数到 20,一共数了 10 个数。( )", + "options": [ + "√", + "*" + ], + "answer": "×", + "solution": "【分析】从 10 开始数到 20 依次是10,11,12,13,14,15,16,17,18,19,20,共11个数.\n【详解】从 10 开始数到 20,一共数了 11 个数。原题说法错误。", + "knowledge_points": [ + "20以内数的排序" + ], + "source": "24-25 一年级下·江西吉安·阶段练习" + }, + { + "id": "293", + "unit": "第二单元 11~20的认识", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式计算.\n![](images/屏幕截图%202025-12-02%20221202.jpg)\n□ ○ □ = □(支)", + "options": [ + + ], + "answer": "18 - 4 = 14", + "solution": "【分析】一共有 18 支笔,左边有 4 支,求右边盒子里有几支,用减法计算,即总数量 - 左边的数量 = 右边的数量.\n【详解】18 - 4 = 14 (支),右边盒子里有 14 支。", + "knowledge_points": [ + "图文问题", + "不退位减法(20以内)" + ], + "source": "24-25一年级上·贵州黔东南·期末" + }, + { + "id": "294", + "unit": "第二单元 11~20的认识", + "question_type": "计算题", + "difficulty": 0.85, + "question": "说图意,填算式.\n![](images/357c4d90d4862c964381eba08897214f72f5328670126c832bbe1a4dacd0fb2c.jpg)\n□ ○ □ = □(个)", + "options": [ + + ], + "answer": "13 - 3 = 10", + "solution": "【分析】两部分的数量合起来是 13 个,已知右边的数量,求左边的数量,用减法计算,即总数量 - 右边的数量 = 左边的数量.\n【详解】图意:一共有 13 个足球,右边有 3 个,求左边盒子里有几个。13 - 3 = 10 (个),左边盒子里有 10 个。", + "knowledge_points": [ + "图文问题", + "不退位减法(20以内)" + ], + "source": "24-25一年级上·福建龙岩·期末" + }, + { + "id": "295", + "unit": "第二单元 11~20的认识", + "question_type": "解答题", + "difficulty": 0.65, + "question": "来到黄河公园,1号游览车坐了17人,2号游览车坐了5人,1号车比2号车多坐了多少人。\n□ ○ □ = □(人)", + "options": [ + + ], + "answer": "17 - 5 = 12", + "solution": "【分析】根据求一个数比另一个数多几,用减法计算。即可解答.\n【详解】 17 - 5 = 12(人),答: 1 号车比 2 号车多坐了 12 人。", + "knowledge_points": [ + "不退位减法 (20 以内)" + ], + "source": "24-25一年级上·河南三门峡·期末" + }, + { + "id": "296", + "unit": "第二单元 11~20的认识", + "question_type": "解答题", + "difficulty": 0.65, + "question": "有一群小羊,走了 12 只,还剩 6 只。原来有多少只。\n□ ○ □ = □( )", + "options": [ + + ], + "answer": "12 + 6 = 18", + "solution": "【分析】用走了的只数加还剩的只数即可求出原来的只数.\n【详解】 12 + 6 = 18(只),答:原来有 18 只。", + "knowledge_points": [ + "不进位加法(20以内)" + ], + "source": "24-25 一年级上·云南保山·期末" + }, + { + "id": "297", + "unit": "第二单元 11~20的认识", + "question_type": "解答题", + "difficulty": 0.65, + "question": "一个停车场原来有15辆汽车,先开走了4辆,又开来了2辆,停车场现有几辆汽车。\n□ ○ □ ○ □ = □ (辆)", + "options": [ + + ], + "answer": "15 - 4 + 2 = 13", + "solution": "【分析】根据题意,先开走的数量要减去,又开来的数量要加上,即原来的数量 - 先开走的数量 + 又开来的数量 =现在的数量.\n【详解】 15 - 4 + 2 = 13 (辆),答:停车场现有 13 辆汽车。", + "knowledge_points": [ + "不进位,不退位加减混合运算 (20 以内)" + ], + "source": "24-25 一年级上·山东济南·期末" + }, + { + "id": "298", + "unit": "第二单元 11~20的认识", + "question_type": "解答题", + "difficulty": 0.65, + "question": "一本故事书,小红看了16页,还剩3页没看,这本故事书原来有多少页。\n□ ○ □ = □(页)", + "options": [ + + ], + "answer": "16 + 3 = 19", + "solution": "【分析】用看了的页数加上没看的页数,即可求出这本故事书原来有多少页.\n【详解】16 + 3 = 19(页),答:这本故事书原来有 19 页。", + "knowledge_points": [ + "不进位加法 (20 以内)" + ], + "source": "24-25 一年级下·广东揭阳·阶段练习" + }, + { + "id": "299", + "unit": "第二单元 11~20的认识", + "question_type": "解答题", + "difficulty": 0.65, + "question": "芳芳从第 10 页看起,看了 8 页,那么他第二天应该从第几页开始看起。", + "options": [ + + ], + "answer": "第18页", + "solution": "【分析】从 10 开始,一个一个地数,一共数 8 下,最后数到几就看到了第几页,最后用这个页数加 1 即可求出他第二天应该从第几页开始看起.\n【详解】10,11,12,13,14,15,16,17,看到了第 17 页。17 + 1 = 18 (页),答:他第二天应该从第 18 页开始看起。", + "knowledge_points": [ + "20以内数的排序", + "不进位加法(20以内)" + ], + "source": "24-25 一年级上·浙江温州·期末" + }, + { + "id": "300", + "unit": "第二单元 11~20的认识", + "question_type": "解答题", + "difficulty": 0.65, + "question": "三 (1) 班有 18 个学生在听课,走了 5 个,又来了 6 个,请问还有多少个学生在听课。", + "options": [ + + ], + "answer": "19 个", + "solution": "【分析】用原来在听课的人数减去走了的人数,再加上又来了的人数即可求出还有多少个学生在听课.\n【详解】18 - 5 + 6 = 19(个),答:还有19个学生在听课。", + "knowledge_points": [ + "加减混合运算 (20 以内)" + ], + "source": "23-24 二年级下·广东汕头·期中" + }, + { + "id": "301", + "unit": "11~20的认识", + "question_type": "选择题", + "difficulty": 0.65, + "question": "下面的数, ( ) 与 17 相邻,又比 17 大。", + "options": [ + "A. 16", + "B. 18", + "C. 19" + ], + "answer": "B", + "solution": "【分析】20 以内的数从小到大排列是: 1 \u003c 2 \u003c 3 \u003c 4 \u003c 5 \u003c 6 \u003c7 \u003c 8 \u003c 9\u003c10 \u003c 11 \u003c 12 \u003c 13 \u003c 14 \u003c 15 \u003c 16 \u003c 1718 \u003c 19 \u003c 20。据此解答.\n【详解】与 17 相邻的是 16 和 18.16 \u003c 17 \u003c 18,所以 18 与 17 相邻,又比 17 大。故答案为: B", + "knowledge_points": [ + "20以内数的排序", + "20以内数的比大小" + ], + "source": "24-25 一年级上·山东菏泽·期末" + }, + { + "id": "302", + "unit": "11~20的认识", + "question_type": "选择题", + "difficulty": 0.85, + "question": "笑笑看一本故事书,从第 10 页看到 17 页,笑笑看了 ( ) 页。", + "options": [ + "A. 7", + "B. 8", + "C. 9" + ], + "answer": "B", + "solution": "【分析】从 10 开始,一个一个地数,一直数到 17,数了几个数,就表示笑笑看了几页书.\n【详解】由题意分析得:10, 11, 12, 13, 14, 15, 16, 17;即,笑笑看一本故事书,从第 10 页看到 17 页,笑笑看了 8 页。故答案为: B", + "knowledge_points": [ + "数一数", + "20以内数的排序" + ], + "source": "24-25 一年级上·河南驻马店·期末" + }, + { + "id": "303", + "unit": "11~20的认识", + "question_type": "选择题", + "difficulty": 0.85, + "question": "一个数,个位和十位上的数都是 1,这个数是 ( )。", + "options": [ + "A. 20", + "B. 10", + "C. 11" + ], + "answer": "C", + "solution": "【分析】一个两位数从右往左依次是个位,十位。个位上是 1,表示 1 个一,十位上也是 1,表示 1 个十。1 个十和 1 个一合起来是 11 .\n【详解】由分析可知:一个数,个位和十位上的数都是 1,这个数是 11 。故答案为: C", + "knowledge_points": [ + "20以内数的组成" + ], + "source": "24-25 一年级上·河南驻马店·期末" + }, + { + "id": "304", + "unit": "11~20的认识", + "question_type": "选择题", + "difficulty": 0.85, + "question": "在下面的算式中,差是 8 的算式是 ( )。", + "options": [ + "A. 18 - 10", + "B. 18 - 8", + "C. 6 + 2" + ], + "answer": "A", + "solution": "【分析】分别计算出各算式的结果,选出差是 8 的算式即可.\n【详解】A。18 - 10 = 8,差是8,符合题意;B。18 - 8 = 10,差是 10,不符合题意;C。6 + 2 = 8,和是 8,不符合题意。故答案为: A", + "knowledge_points": [ + "8,9 的加减法", + "不退位减法(20 以内)" + ], + "source": "24-25 一年级上·广东汕头·期末" + }, + { + "id": "305", + "unit": "11~20的认识", + "question_type": "选择题", + "difficulty": 0.65, + "question": "一个两位数,个位上的数字比十位上的数字大 6,十位上的数字是 1,这个数是 ( )。", + "options": [ + "A. 15", + "B. 16", + "C. 17" + ], + "answer": "C", + "solution": "【分析】用 1 加 6 可以求出个位上的数。一个两位数,从右往左数,第一位是个位,第二位是十位,据此解答.\n【详解】1 + 6 = 7,个位是 7,十位是 1,这个数是 17 。故答案为: C", + "knowledge_points": [ + "20以内数的组成", + "整数的数级,数位和计数单位的认识" + ], + "source": "24-25 一年级上·福建厦门·期末" + }, + { + "id": "306", + "unit": "11~20的认识", + "question_type": "选择题", + "difficulty": 0.85, + "question": "下面各数中,\"2\"表示的意义和其他不同的是 ( )。", + "options": [ + "A. 2", + "B. 12", + "C. 20" + ], + "answer": "C", + "solution": "【分析】一个一位数表示几个一;一个两位数,从右往左数,第一位是个位,表示几个一;第二位是十位,表示几个十;据此解决此题.\n【详解】A.\"2\"表示2个一;B. 12 中的 \"2\" 表示 2 个一;C. 20 中的 \"2\" 表示 2 个十;即,这三个数中,\"2\"表示的意义和其他不同的是(20)。故答案为: C", + "knowledge_points": [ + "20以内数的组成" + ], + "source": "24-25 一年级上·福建厦门·期末" + }, + { + "id": "307", + "unit": "11~20的认识", + "question_type": "选择题", + "difficulty": 0.85, + "question": "大于 3 且小于 12 的数有()个。", + "options": [ + "A. 7", + "B. 8", + "C. 9" + ], + "answer": "B", + "solution": "【分析】20 以内的数从小到大排列是: 1 \u003c 2 \u003c 3 \u003c 4 \u003c 5 \u003c 6 \u003c 7 \u003c 8 \u003c 9 \u003c 10 \u003c 11 \u003c 12 \u003c 13 \u003c 14 \u003c 15 \u003c 16 \u003c 17 \u003c 18 \u003c 19 \u003c 20,据此数一数.\n【详解】大于3且小于12的数有4,5,6,7,8,9,10,11,共8个。故答案为: B", + "knowledge_points": [ + "20以内数的排序", + "20以内数的比大小" + ], + "source": "24-25 一年级上·河南南阳·期末" + }, + { + "id": "308", + "unit": "11~20的认识", + "question_type": "选择题", + "difficulty": 0.85, + "question": "用两颗珠子在计数器上表示数,不能表示出 ( )。", + "options": [ + "A. 2", + "B. 12", + "C. 20" + ], + "answer": "B", + "solution": "【分析】用两颗珠子在计数器上表示数,则个位和十位上的数的和应该是 2,据此计算.\n【详解】A。 2 = 2,可以表示出来;B。1 + 2 = 3,不可以表示出来;C。2 + 0 = 2,可以表示出来。不能表示出 12。故答案为: B", + "knowledge_points": [ + "20以内数的组成" + ], + "source": "24-25 一年级上·河南南阳·期末" + }, + { + "id": "309", + "unit": "11~20的认识", + "question_type": "选择题", + "difficulty": 0.85, + "question": "一个加数是最小的两位数,另一个加数是最大的一位数,它们的和是 ( )。", + "options": [ + "A. 10", + "B. 20", + "C. 19" + ], + "answer": "C", + "solution": "【分析】最小的两位数是 10,最大的一位数是 9,根据 \"加数 + 加数 = 和\",据此解答.\n【详解】根据分析可列式:10 + 9 = 19,故答案为: C", + "knowledge_points": [ + "不进位加法(20以内)" + ], + "source": "24-25一年级上·河南漯河·期末" + }, + { + "id": "310", + "unit": "11~20的认识", + "question_type": "填空题", + "difficulty": 0.85, + "question": "与16相邻的数是( )和( ),它们两个相差( )。", + "options": [ + + ], + "answer": "15;17;2", + "solution": "【分析】相邻两个数的差是 1,和 16 相邻的两个数分别是 16 少 1 , 16 多 1,分别计算出这两个数,再相减求出它们的差即可.\n【详解】 16 - 1 = 15;16 + 1 = 17;17 - 15 = 2与 16 相邻的数是 15 和 17,它们两个相差 2。", + "knowledge_points": [ + "20以内数的排序", + "不进位加法(20以内)", + "不退位减法(20以内)" + ], + "source": "24-25 一年级上·广东云浮·期末" + }, + { + "id": "311", + "unit": "11~20的认识", + "question_type": "填空题", + "difficulty": 0.65, + "question": "2个十是( ),16里面有( )个一。", + "options": [ + + ], + "answer": "20;16", + "solution": "【分析】一个两位数,从右边起第一位是个位,个位上是几,就表示几个一,第二位是十位,十位上是几,就表示几个十,1个十就是10个一.\n【详解】2 个十是 20, 16 里面有 1 个十和 6 个一,也就是 16 个一。", + "knowledge_points": [ + "20以内数的组成" + ], + "source": "24-25一年级上·广东云浮·期末" + }, + { + "id": "312", + "unit": "11~20的认识", + "question_type": "填空题", + "difficulty": 0.85, + "question": "15 是由( )个十和( )个一组成,这个数加上( )就等于 20。", + "options": [ + + ], + "answer": "1;5;5", + "solution": "【分析】一个两位数,从右到左数,第一位是个位,个位是几就表示几个一,第二位是十位,十位是几就表示几个十;求这个数加几等于20,用20减去这个数即可.\n【详解】20 - 15 = 5\n\n15 是由 (1) 个十和 (5) 个一组成,这个数加上 (5) 就等于 20。", + "knowledge_points": [ + "20以内数的组成" + ], + "source": "24-25 一年级上·湖南娄底·期末" + }, + { + "id": "313", + "unit": "11~20的认识", + "question_type": "填空题", + "difficulty": 0.85, + "question": "比 14 多 3 的数是( ), 比 18 少( )的数是 12 。", + "options": [ + + ], + "answer": "17;6", + "solution": "【分析】根据求比一个数多几的数,用加法计算。求比一个数少几的数是 12,则用一个数减去 12 即可.\n【详解】14 + 3 = 17,18 - 12 = 6,则比 14 多 3 的数是 17,比 18 少 6 的数是 12。", + "knowledge_points": [ + "不进位加法(20以内)", + "不退位减法(20以内)" + ], + "source": "24-25 一年级上·湖南娄底·期末" + }, + { + "id": "314", + "unit": "11~20的认识", + "question_type": "填空题", + "difficulty": 0.85, + "question": "20 的前一个数是( ), 10 的后一个数是( )。", + "options": [ + + ], + "answer": "19;11", + "solution": "【分析】从 10 开始,一个一个地数,一直数到 20,即可找出 20 的前一个数是几和 10 的后一个数是几.\n【详解】由题意分析得:10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20;即, 20 的前一个数是 19, 10 的后一个数是 11。", + "knowledge_points": [ + "20以内数的排序" + ], + "source": "24-25 一年级上·湖南娄底·期末" + }, + { + "id": "315", + "unit": "11~20的认识", + "question_type": "填空题", + "difficulty": 0.85, + "question": "妈妈买回来十几个桃子,小明5个5个地数,数了2次,最后剩3个,妈妈买回来( )个桃子。", + "options": [ + + ], + "answer": "13", + "solution": "【分析】5个5个地数,数了2次,表示先数了2个5的和,计算时,先把5与5加起来,求出和,然后加上3,求出和,就是妈妈买回来的桃子数量.\n【详解】5 + 5 = 10(个),10 + 3 = 13 (个),即,妈妈买回来十几个桃子,小明5个5个地数,数了2次,最后剩3个,妈妈买回来13个桃子。", + "knowledge_points": [ + "10 的加减法", + "不进位加法(20 以内)" + ], + "source": "24-25 一年级上·河南郑州·期末" + }, + { + "id": "316", + "unit": "11~20的认识", + "question_type": "填空题", + "difficulty": 0.85, + "question": "5个一和1个十合起来是( ),它前面的一个数是( ),后面的一个数是( )。", + "options": [ + + ], + "answer": "15;14;16", + "solution": "【分析】一个数由几个一组成,就在个位上写几,由几个十组成,就在十位上写几;一个数前面的一个数就是把这个数减 1,一个数后面的一个数就是把这个数加 1.\n【详解】5 个一和 1 个十合起来是(15),它前面的一个数是(14),后面的一个数是(16)。", + "knowledge_points": [ + "11~20 的认识和读写", + "20以内数的组成", + "不进位加法(20以内)", + "不退位减法(20以内)" + ], + "source": "24-25一年级上·河南郑州·期末" + }, + { + "id": "317", + "unit": "11~20的认识", + "question_type": "填空题", + "difficulty": 0.85, + "question": "小雪看一本《西游记》,今天从第 11 页读到第 15 页,今天一共读了( )页,明天该读第( )页了。", + "options": [ + + ], + "answer": "5;16", + "solution": "【分析】从 11 开始,一个一个地数,一直数到 15,数了几个数就表示一共读了几页书;然后用 15 加 1,求出和,就是明天该读的页码.\n【详解】由题意分析得:11, 12, 13, 14, 15;15 + 1 = 16(页)即,小雪看一本《西游记》, 今天从第 11 页读到第 15 页,今天一共读了 5 页,明天该读第 16 页了。", + "knowledge_points": [ + "20以内数的排序", + "不进位加法(20以内)" + ], + "source": "24-25 一年级上·河南郑州·期末" + }, + { + "id": "318", + "unit": "11~20的认识", + "question_type": "填空题", + "difficulty": 0.85, + "question": "12 里面有( )个一, 20 里面有( )个十。", + "options": [ + + ], + "answer": "12;2", + "solution": "【分析】一个两位数,从右往左依次为个位,十位。十位是几就有几个十,个位是几就有几个一,1个十就是10个一,由此解答.\n【详解】12里面有1个十和2个一,也就是有12个一,20里面有2个十。", + "knowledge_points": [ + "20以内数的组成" + ], + "source": "24-25 一年级上·河南郑州·期末" + }, + { + "id": "319", + "unit": "11~20的认识", + "question_type": "填空题", + "difficulty": 0.85, + "question": "小贝读一本故事书,他昨天从第11页读到了第16页,他昨天一共读了( )页。", + "options": [ + + ], + "answer": "6", + "solution": "【分析】根据题意可知:结束读的页数减去开始读的页数,再加 1 即可.\n【详解】 16 - 11 + 1 = 5 + 1 = 6 (页),则他昨天一共读了6页。", + "knowledge_points": [ + "加减混合运算(20以内)" + ], + "source": "24-25一年级上·陕西延安·期末" + }, + { + "id": "320", + "unit": "11~20的认识", + "question_type": "填空题", + "difficulty": 0.85, + "question": "从小到大一个一个地数数, 18 前面一个数是( ), 后面一个数是( )。", + "options": [ + + ], + "answer": "17;19", + "solution": "【分析】根据 20 以内数的认识,一个一个地数数, 18 前面一个数比它少 1,是 17 , 18 后面的数比它多 1,是 19,由此解答.\n【详解】从小到大一个一个地数数,18前面一个数是17,后面一个数是19。", + "knowledge_points": [ + "20以内数的排序" + ], + "source": "24-25 一年级上·浙江嘉兴·期末" + }, + { + "id": "321", + "unit": "11~20的认识", + "question_type": "填空题", + "difficulty": 0.65, + "question": "比 13 大,比 15 小的数是( ) , 它是由( )个十和( )个一组成的。", + "options": [ + + ], + "answer": "14;1;4", + "solution": "【分析】根据 20 以内数的排序可知:比 13 大,比 15 小的数即在 13 和 15 之间的数是 14;一个两位数,右边第一位是个位,第二位是十位,个位上是几,表示几个 1,十位上是几,就表示几个十.\n【详解】比 13 大,比 15 小的数是 14,它是由 1 个十和 4 个一组成的。", + "knowledge_points": [ + "20以内数的组成", + "20以内数的比大小" + ], + "source": "24-25 一年级上·浙江嘉兴·期末" + }, + { + "id": "322", + "unit": "11~20的认识", + "question_type": "填空题", + "difficulty": 0.85, + "question": "找规律填数.\n\n1,3,5,( ),9,( )。", + "options": [ + + ], + "answer": "7;11", + "solution": "【分析】结合已知数字,可以发现规律:后面的数比前面的数大 2,据此解答.\n【详解】根据分析可得:1, 3, 5, 7, 9, 11", + "knowledge_points": [ + "整数排列的规律" + ], + "source": "24-25 一年级上·四川广元·期末" + }, + { + "id": "323", + "unit": "11~20的认识", + "question_type": "填空题", + "difficulty": 0.85, + "question": "一个两位数,十位上是 1,个位上的数比十位上的数多 7,这个数是( ), 再添( )个一就是 2 个十。", + "options": [ + + ], + "answer": "18;2", + "solution": "【分析】一个两位数,从右往左数,第一位是个位,第二位是十位,据此组数。几个十就是几十.\n\n先用十位上的数加上 7,求出和,就是个位上的数,然后组数即可;再从这个数开始,一个一个地往后数,一直数到 20 (2 个十就是 20), 看看 18 后面数了几个数,就表示再添几个一就是 2 个十.\n【详解】由题意分析得:1 + 7 = 8则这个数是 18;18,19,20,即 18 后面数了 2 个数;即,一个两位数,十位上是 1,个位上的数比十位上的数多7,这个数是 18,再添 2 个一就是 2 个十。", + "knowledge_points": [ + "20以内数的组成", + "数一数" + ], + "source": "24-25 一年级上·四川广元·期末" + }, + { + "id": "324", + "unit": "11~20的认识", + "question_type": "填空题", + "difficulty": 0.65, + "question": "小文看一本故事书,今天从第 10 页看到了第 16 页,明天该看第 17 页了,她今天看了( )页。", + "options": [ + + ], + "answer": "7", + "solution": "【分析】用今天看到的页数减去开始看的页数,由于 16 页已经看完了,再加上1,即可求出今天看了多少页.\n【详解】16 - 10 = 6, 6 + 1 = 7 (页),她今天看了 7 页。", + "knowledge_points": [ + "不退位减法 (20 以内)" + ], + "source": "24-25 一年级上·四川广元·期末" + }, + { + "id": "325", + "unit": "11~20的认识", + "question_type": "填空题", + "difficulty": 0.65, + "question": "16 里面有( )个十和( )个一;它再添上( )个一就是2个十。", + "options": [ + + ], + "answer": "1;6;4", + "solution": "【分析】一个两位数,从右往左数,第一位是个位,个位上的数表示几个一;第二位是十位,十位上的数表示几个十。2 个十是 20,从 16 开始,一个一个地数,数几下到 20 则需要再添几个一.\n【详解】16 里面有 1 个十和 6 个一;它再添上 4 个一就是 2 个十。", + "knowledge_points": [ + "20以内数的组成", + "20以内数的排序" + ], + "source": "24-25 一年级上·河南郑州·期末" + }, + { + "id": "326", + "unit": "11~20的认识", + "question_type": "填空题", + "difficulty": 0.85, + "question": "一个一个的数,()的后面是 15 , 19 前面的数是( )。", + "options": [ + + ], + "answer": "14;18", + "solution": "【分析】一个一个的数,一个数前面第一个数比它小 1,后面第一个数比它大 1.20 以内的数从小到大排列是: 1 \u003c 2 \u003c 3 \u003c 4 \u003c 5 \u003c 6 \u003c 7 \u003c 8 \u003c 9 \u003c 10 \u003c 11 \u003c 12 \u003c 13 \u003c 14 \u003c 15 \u003c 16 \u003c 17 \u003c 18 \u003c 19 \u003c 20,据此填空.\n【详解】一个一个的数, 14 的后面是 15 , 19 前面的数是 18。", + "knowledge_points": [ + "20以内数的排序" + ], + "source": "24-25一年级上·湖北孝感·期末" + }, + { + "id": "327", + "unit": "11~20的认识", + "question_type": "填空题", + "difficulty": 0.85, + "question": "比 10 大 8 的数是( )。", + "options": [ + + ], + "answer": "18", + "solution": "【分析】根据题意,\"比 10 大 8 的数是多少\",意思就是在 10 的基础上再增加 8,求得到的结果。用加法计算.\n【详解】10 + 8 = 18,比 10 大 8 的数是 18。", + "knowledge_points": [ + "不进位加法(20以内)" + ], + "source": "24-25 一年级上·湖北孝感·期末" + }, + { + "id": "328", + "unit": "11~20的认识", + "question_type": "填空题", + "difficulty": 0.85, + "question": "从 9 往后数第 6 个数是( ),13 后面第 5 个数是( )。", + "options": [ + + ], + "answer": "15;18", + "solution": "【分析】从 9 开始,一个一个地数一数,一直数到 20,即可解决此题.\n【详解】由题意分析得:9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20;即,从9往后数第6个数是15,13后面第5个数是18。", + "knowledge_points": [ + "数一数", + "20以内数的排序" + ], + "source": "24-25 一年级上·福建福州·期末" + }, + { + "id": "329", + "unit": "11~20的认识", + "question_type": "填空题", + "difficulty": 0.65, + "question": "有一个两位数,十位上的数字是 1,个位上的数字比十位上的数字大 3,这个数是( )。", + "options": [ + + ], + "answer": "14", + "solution": "【分析】一个两位数,从右往左依次为个位,十位。十位是1,个位比十位大3,个位为 1 + 3 = 4,即十位是1,个位是4,由此写数即可.\n【详解】由分析可知:有一个两位数,十位上的数字是 1,个位上的数字比十位上的数字大 3,这个数是 14。", + "knowledge_points": [ + "11~20 的认识和读写", + "20以内数的组成" + ], + "source": "24-25 一年级上·浙江·期末" + }, + { + "id": "330", + "unit": "11~20的认识", + "question_type": "填空题", + "difficulty": 0.85, + "question": "在7,12,0,9,4,20这些数中,最大的数是( ),最小的数是( ),最接近10的数是( )。", + "options": [ + + ], + "answer": "20;0;9", + "solution": "【分析】1到20,从小到大排序:1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20;据此找出最大数和最小数;再根据\"两个数之间的数越少,表示这两个数越接近\"找出最接近10的数即可.\n【详解】由题意分析得:1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,20 \u003e 12 \u003e 9 \u003e 7 \u003e 4 \u003e 0,9和10之间没有数,故,9最接近10;即,在 7,12,0,9,4,20 这些数中,最大的数是 20,最小的数是 0,最接近 10 的数是 9。", + "knowledge_points": [ + "20以内数的排序", + "20以内数的比大小" + ], + "source": "24-25 一年级上·内蒙古通辽·期末" + }, + { + "id": "331", + "unit": "11~20的认识", + "question_type": "填空题", + "difficulty": 0.85, + "question": "两个加数都是 5,和是( );在算式 18 - 3 = 15 中,减数是( )。", + "options": [ + + ], + "answer": "10,3", + "solution": "【分析】根据加数 + 加数 = 和,列式计算出结果即可;在算式 18 - 3 = 15 中,减号前面的数是被减数,后面的数是减数,结果是差;据此解答.\n【详解】5 + 5 = 10,两个加数都是 5,和是 10;在算式 18 - 3 = 15 中,减数是 3。", + "knowledge_points": [ + "10 的加减法", + "不退位减法 (20 以内)" + ], + "source": "24-25 一年级上·重庆九龙坡·期末" + }, + { + "id": "332", + "unit": "11~20的认识", + "question_type": "填空题", + "difficulty": 0.85, + "question": "17 前面的一个数是( ),后面的一个数是( ),比 20 小 1 的数是( )。", + "options": [ + + ], + "answer": "16;18;19", + "solution": "【分析】20以内数从小到大顺序为:0,1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20;比 20 小 1 就是 20 前面的一个数,由此找出符合题意的数,填空即可;【详解】17前面的一个数是 16,后面的一个数是 18,比 20 小 1 的数是 19。", + "knowledge_points": [ + "20以内数的排序", + "20以内数的比大小" + ], + "source": "24-25 一年级上·重庆九龙坡·期末" + }, + { + "id": "333", + "unit": "11~20的认识", + "question_type": "填空题", + "difficulty": 0.85, + "question": "在 15,11,8,12,18中,最大的数是( ),最小的数是( ),( )更接近 20。", + "options": [ + + ], + "answer": "18;8;18", + "solution": "【分析】20 以内从小到大关系为:0,1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,由此找出最大的数和最小的数,再找出更接近 20 的数填空即可.\n【详解】根据分析可得:在 15,11,8,12,18 中,最大的数是 18,最小的数是8, 18 更接近 20。 ", + "knowledge_points": [ + "20以内数的排序", + "20以内数的比大小" + ], + "source": "24-25 一年级上·湖北黄石·期末" + }, + { + "id": "334", + "unit": "11~20的认识", + "question_type": "填空题", + "difficulty": 0.65, + "question": "比 10 多 6 的数是( ), 比 9 少 4 的数是( )。", + "options": [ + + ], + "answer": "16;5", + "solution": "【分析】求比一个数多几的数是多少用加法计算;求比一个数少几的数是多少用减法计算.\n【详解】10 + 6 = 16,9 - 4 = 5,所以比 10 多 6 的数是 16,比 9 少 4 的数是 5。", + "knowledge_points": [ + "8,9 的加减法", + "不进位加法(20以内)" + ], + "source": "24-25 一年级上·江西赣州·期末" + }, + { + "id": "335", + "unit": "11~20的认识", + "question_type": "填空题", + "difficulty": 0.85, + "question": "学校从星期三到星期日放假,一共放假( )天。", + "options": [ + + ], + "answer": "5", + "solution": "【分析】从星期三开始,一天一天地数,一直数到星期日,数了几天就是放假几天.\n【详解】由题意分析得:星期三,星期四,星期五,星期六,星期日;即,学校从星期三到星期日放假,一共放假5天。", + "knowledge_points": [ + "数一数" + ], + "source": "24-25 一年级上·河南驻马店·期末" + }, + { + "id": "336", + "unit": "11~20的认识", + "question_type": "填空题", + "difficulty": 0.85, + "question": "14前面的一个数是( ),比17大,且小于20的单数是( )。", + "options": [ + + ], + "answer": "13;19", + "solution": "【分析】11到20,从小到大排序:11,12,13,14,15,16,17,18,19,20。个位数是 1,3,5,7,9 的数是单数;个位上是0,2,4,6,8 的数是双数。据此数一数,找出符合题意的数即可.\n【详解】由题意分析得:11,12,13,14,15,16,17,18,19,20。即, 14前面的一个数是 13,比 17 大,且小于 20 的单数是 19。", + "knowledge_points": [ + "20以内数的排序", + "20以内数的比大小" + ], + "source": "24-25一年级上·河南驻马店·期末" + }, + { + "id": "337", + "unit": "11~20的认识", + "question_type": "填空题", + "difficulty": 0.85, + "question": "12 再添 3 个一,就是( )个十和( )个一。", + "options": [ + + ], + "answer": "1;5", + "solution": "【分析】3 个一就是 3,则, 12 再添 3 个一是多少,就是 12 再加 3 是多少,用加法先计算出得数,然后结合得数和 \"一个两位数,从右往左数,第一位是个位,表示几个一,第二位是十位,表示几个十\" 来解决即可.\n【详解】12 + 3 = 15,15 就是 1 个十和 5 个一。即, 12 再添 3,就是 1 个十和 5 个一。", + "knowledge_points": [ + "20以内数的组成", + "不进位加法(20以内)" + ], + "source": "24-25 一年级上·河南周口·期末" + }, + { + "id": "338", + "unit": "11~20的认识", + "question_type": "填空题", + "difficulty": 0.85, + "question": "18 是由( )个十和( )个一组成的,与它相邻的两个数是( )和( )。", + "options": [ + + ], + "answer": "1;8;17;19", + "solution": "【分析】一个两位数,左边的数位是十位,十位是几表示几个十,右边的数位是个位,个位是几表示几个一,数数时排在这个数前面的一个数和后面的一个数都是与它相邻的数,据此得出结论即可.\n【详解】根据分析知:18 是由 1 个十和 8 个一组成的,与它相邻的两个数是 17 和 19。", + "knowledge_points": [ + "20以内数的组成", + "20以内数的排序" + ], + "source": "24-25 一年级上·广东汕头·期末" + }, + { + "id": "339", + "unit": "11~20的认识", + "question_type": "填空题", + "difficulty": 0.85, + "question": "一个加数是 13,另一加数是 6,和是( )。被减数是 10,减数是 6,差是( )。", + "options": [ + + ], + "answer": "19;4", + "solution": "【分析】根据\"加数 + 加数 = 和,被减数 - 减数 = 差\"来解决此题.\n【详解】13 + 6 = 19,10 - 6 = 4,即,一个加数是 13,另一加数是 6,和是 19。被减数是10,减数是 6,差是 4 。", + "knowledge_points": [ + "10 的加减法", + "不进位加法(20 以内)" + ], + "source": "24-25 一年级上·河南驻马店·期末" + }, + { + "id": "340", + "unit": "11~20的认识", + "question_type": "填空题", + "difficulty": 0.85, + "question": "15 里面有( )个十和( )个一。它的前一个数是( ),后一个数是( )。", + "options": [ + + ], + "answer": "1;5;14;16", + "solution": "【分析】一个两位数,从左往左数,第一位是个位,表示几个一,第二位是十位,表示几个十。相邻的两个数,前一个数比后一个数少 1,后一个数比前一个多 1;据此解决.\n【详解】15 - 1 = 14,15 + 1 = 16,即, 15里面有1个十和5个一。它的前一个数是14,后一个数是16。", + "knowledge_points": [ + "20以内数的组成", + "不进位加法(20以内)", + "不退位减法 (20 以内)" + ], + "source": "24-25 一年级上·河南驻马店·期末" + }, + { + "id": "341", + "unit": "11~20的认识", + "question_type": "填空题", + "difficulty": 0.85, + "question": "比 12 多 3 的数是( )。", + "options": [ + + ], + "answer": "15", + "solution": "【分析】求比一个数多几的数是多少,用加法列式解决.\n【详解】12 + 3 = 15,即,比12多3的数是 15。", + "knowledge_points": [ + "不进位加法(20以内)" + ], + "source": "24-25 一年级上·甘肃天水·期末" + }, + { + "id": "342", + "unit": "11~20的认识", + "question_type": "填空题", + "difficulty": 0.65, + "question": "2 个十是( ),个位和十位上都是 1,这个数是( )。", + "options": [ + + ], + "answer": "20;11", + "solution": "【分析】一个两位数,左边的数位是十位,十位上的数字是几就表示几个十,右边的数位是个位,个位是几就表示几个一,据此得出结论即可.\n【详解】根据分析知:2 个十是 20,个位和十位上都是 1,这个数是 11。", + "knowledge_points": [ + "20以内数的组成" + ], + "source": "24-25 一年级上·甘肃天水·期末" + }, + { + "id": "343", + "unit": "11~20的认识", + "question_type": "填空题", + "difficulty": 0.85, + "question": "一个数由 8 个一和 1 个十组成,这个数是( )。", + "options": [ + + ], + "answer": "18", + "solution": "【分析】一个两位数,从右往左数,第一位是个位,第二位是十位。8个一是8,1个十是10,合起来组成数是18.\n【详解】由题意分析得:一个数由 8 个一和 1 个十组成,这个数是 18。", + "knowledge_points": [ + "20以内数的组成" + ], + "source": "24-25 一年级上·甘肃天水·期末" + }, + { + "id": "344", + "unit": "11~20的认识", + "question_type": "填空题", + "difficulty": 0.85, + "question": "15 前面的一个数是( ), 后面的一个数是( )。", + "options": [ + + ], + "answer": "14;16", + "solution": "【分析】从 11 开始,一个一个地数,一直数到 20,即可找到 15 前面的一个数和后面的一个数.\n【详解】由题意分析得:11, 12, 13, 14, 15, 16, 17, 18, 19, 20;即, 15 前面的一个数是 14,后面的一个数是 16。", + "knowledge_points": [ + "20以内数的排序" + ], + "source": "24-25 一年级上·甘肃天水·期末" + }, + { + "id": "345", + "unit": "11~20的认识", + "question_type": "填空题", + "difficulty": 0.65, + "question": "我的个位是 9,十位是 1,我是( )。", + "options": [ + + ], + "answer": "19", + "solution": "【分析】一个两位数,从右边起第一位是个位,第二位是十位,据此得出结论即可.\n【详解】根据分析知:我的个位是 9,十位是 1,我是 19 。", + "knowledge_points": [ + "20以内数的组成" + ], + "source": "24-25 一年级上·湖南怀化·期末" + }, + { + "id": "346", + "unit": "11~20的认识", + "question_type": "填空题", + "difficulty": 0.85, + "question": "17 和 19 中间的数是( );和 11 相邻的两个数是( )和( )。", + "options": [ + + ], + "answer": "18;10;12", + "solution": "【分析】从11开始,一个一个地数,一直数到20,即可解决此题.\n【详解】由题意分析得:11, 12, 13, 14, 15, 16, 17, 18, 19, 20;即,17和19中间的数是18;和11相邻的两个数是10和12。", + "knowledge_points": [ + "20以内数的排序" + ], + "source": "24-25一年级上·湖南怀化·期末" + }, + { + "id": "347", + "unit": "11~20的认识", + "question_type": "填空题", + "difficulty": 0.85, + "question": "在括号里填上\"+\"或\"-\".\n10 ( ) 6 = 16;18 ( ) 8 = 10;5 ( ) 5 = 0;11 ( ) 5 = 16", + "options": [ + + ], + "answer": "+;-;-;+", + "solution": "【分析】一般情况下,加法运算会让得数变多或不变,减法运算会让得数变少或不变,据此试填.\n【详解】10 + 6 = 16;18 - 8 = 10;5 - 5 = 0;11 + 5 = 16。", + "knowledge_points": [ + "5 以内数的减法", + "不进位加法(20 以内)", + "不退位减法(20 以内)", + "有关 0 的加减法" + ], + "source": "24-25 一年级上·湖南常德·期末" + }, + { + "id": "348", + "unit": "11~20的认识", + "question_type": "填空题", + "difficulty": 0.85, + "question": "在 5,0,6,11,13,20,15这几个数中,最大的数是( );最小的数是( );最大的数和最小的数相差( )。", + "options": [ + + ], + "answer": "20;0;20", + "solution": "【分析】0 到 20,从小到大排序:0,1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20。据此找出最大的数和最小的数。求两个数的差,用减法列式解决.\n【详解】20 \u003e 15 \u003e 13 \u003e 11 \u003e 6 \u003e 5 \u003e 0,20 - 0 = 20,即,在 5,0,6,11,13,20,15 这几个数中,最大的数是 20;最小的数是 0;最大的数和最小的数相差 20。", + "knowledge_points": [ + "不退位减法(20以内)", + "20以内数的比大小" + ], + "source": "24-25 一年级上·辽宁鞍山·期末" + }, + { + "id": "349", + "unit": "11~20的认识", + "question_type": "填空题", + "difficulty": 0.65, + "question": "小红折了 16 颗星星,小华折了6颗星星,小华还要折( )颗星星就和小红同样多。", + "options": [ + + ], + "answer": "10", + "solution": "【分析】求两者的差距用减法计算。用小红折的数量减去小华折的数量即可求解.\n【详解】16 - 6 = 10(颗),小红折了 16 颗星星,小华折了 6 颗星星,小华还要折 10 颗星星就和小红同样多。", + "knowledge_points": [ + "不退位减法(20以内)" + ], + "source": "24-25一年级上·安徽芜湖·期末" + }, + { + "id": "350", + "unit": "11~20的认识", + "question_type": "填空题", + "difficulty": 0.85, + "question": "一个数的个位上是2,十位上是1,这个数是( ),读作:( )。", + "options": [ + + ], + "answer": "12;十二", + "solution": "【分析】一个两位数,从右往左依次为个位,十位,写数时,从高位写起,按数位顺序写,哪一位上是几就写在对应数位上;读数时,从高位读起,十位是几读作几十,个位是几读作几.\n【详解】一个数的个位上是 2,十位上是 1,这个数是 12,读作:十二。", + "knowledge_points": [ + "11~20 的认识和读写" + ], + "source": "24-25 一年级上·吉林四平·期末" + }, + { + "id": "351", + "unit": "11~20的认识", + "question_type": "填空题", + "difficulty": 0.85, + "question": "15 读作( ),它的前一个数是( ),后一个数是( )。16 后面的第 3 个数是( )。", + "options": [ + + ], + "answer": "十五;14;16;19", + "solution": "【分析】一个两位数,从右往左依次为个位,十位,读数时,从高位读起,十位是几读作几十,个位是几读作几。20 以内数从小到大顺序为:1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20,由此找出对应的数即可.\n【详解】15 读作十五,它的前一个数是 14,后一个数是16.16 后面的第 3 个数是 19。", + "knowledge_points": [ + "11~20 的认识和读写", + "20以内数的排序" + ], + "source": "24-25 一年级上·云南玉溪·期末" + }, + { + "id": "352", + "unit": "11~20的认识", + "question_type": "填空题", + "difficulty": 0.85, + "question": "在括号里填上\"\u003e\" \"\u003c\"或\"=\".\n16( )19;18-6( )12;4 + 4( )5 + 1\n7( )8;7( )3+6;17+2( )18-6", + "options": [ + + ], + "answer": "\u003c;=;\u003e;\u003c;\u003c;\u003e", + "solution": "【分析】根据整数加减法的计算法则,依次计算出各算式的结果再比较大小。20以内数从大到小关系为:20 \u003e 19\u003e 18 \u003e 17 \u003e 16 \u003e 15 \u003e 14 \u003e 13 \u003e 12 \u003e 11 \u003e 10 \u003e 9 \u003e 8 \u003e 7 \u003e 6 \u003e 5\u003e 4 \u003e 3 \u003e 2 \u003e 1 \u003e 0,由此比较.\n【详解】16 \u003c 19;18 - 6 = 12;4 + 4 = 8,5 + 1 = 6,所以 4 + 4 \u003e 5 + 1;7 \u003c 8;3 + 6 = 9,所以 7 \u003c 3 + 6;17 + 2 = 19,18 - 6 = 12,所以 17 + 2 \u003e 18 - 6。", + "knowledge_points": [ + "8,9 的加减法", + "不进位加法(20 以内)", + "不退位减法(20 以内)", + "20 以内数的比大小" + ], + "source": "24-25一年级上·新疆喀什·期末" + }, + { + "id": "353", + "unit": "11~20的认识", + "question_type": "填空题", + "difficulty": 0.85, + "question": "比 19 小 1 的数是( );9 和 11 中间的数是( )。", + "options": [ + + ], + "answer": "18;10", + "solution": "【分析】求比一个数小几的数是多少,用减法列式解决;一个一个地数一数,即可知道 9 和 11 中间的数是几;据此解决.\n【详解】19 - 1 = 18,9,10,11;即,比19小1的数是18;9和11中间的数是10。", + "knowledge_points": [ + "20以内数的排序", + "不退位减法(20以内)" + ], + "source": "24-25 一年级上·陕西西安·期末" + }, + { + "id": "354", + "unit": "11~20的认识", + "question_type": "填空题", + "difficulty": 0.85, + "question": "17 里面有( )个十和( )个一,与它相邻的两个数分别是( )和( )。个位和十位都是 1 的数是( )。", + "options": [ + + ], + "answer": "1;7;16;18;11", + "solution": "【分析】一个两位数,从右往左数,第一位是个位,个位上的数表示几个一;第二位是十位,十位上的数表示几个十。一个数前面第一个数比它小 1,后面第一个数比它大 1.\n【详解】17 里面有 1 个十和 7 个一,与它相邻的两个数分别是16 和 18。个位和十位都是 1 的数是 11。", + "knowledge_points": [ + "11~20 的认识和读写", + "20以内数的组成", + "20以内数的排序" + ], + "source": "24-25 一年级上·安徽芜湖·期末" + }, + { + "id": "355", + "unit": "11~20的认识", + "question_type": "填空题", + "difficulty": 0.85, + "question": "15 后面第二个数是( ), 20 前面第二个数是( )。", + "options": [ + + ], + "answer": "17;18", + "solution": "【分析】从 15 开始,一个一个地数,一直数到 20,即可解决此题.\n【详解】由题意分析得:15, 16, 17, 18, 19, 20;即, 15 后面第二个数是 17, 20 前面第二个数是 18。", + "knowledge_points": [ + "20以内数的排序" + ], + "source": "24-25 一年级上·河南漯河·期末" + }, + { + "id": "356", + "unit": "11~20的认识", + "question_type": "填空题", + "difficulty": 0.85, + "question": "小明读一本故事书,从第 9 页读到第 16 页,他今天读了( )页。", + "options": [ + + ], + "answer": "8", + "solution": "【分析】从 9 开始,一个一个地数,一直数到 16,看看数了几个数,就表示读了几页.\n【详解】由题意分析得:9, 10, 11, 12, 13, 14, 15, 16;即,小明读一本故事书,从第 9 页读到第 16 页,他今天读了 8 页。", + "knowledge_points": [ + "数一数" + ], + "source": "24-25 一年级上·河南漯河·期末" + }, + { + "id": "357", + "unit": "11~20的认识", + "question_type": "填空题", + "difficulty": 0.85, + "question": "个位上是 6,十位上是 1,这个数是( )。", + "options": [ + + ], + "answer": "16", + "solution": "【分析】一个两位数,从右往左数,第一位是个位,个位上写 6,第二位十位,十位上写 1;据此解决.\n【详解】由题意分析得:个位上是 6,十位上是 1,这个数是 16。", + "knowledge_points": [ + "20以内数的组成" + ], + "source": "24-25 一年级上·河南漯河·期末" + }, + { + "id": "358", + "unit": "11~20的认识", + "question_type": "填空题", + "difficulty": 0.85, + "question": "13 和 20 之间有( )个数。", + "options": [ + + ], + "answer": "6", + "solution": "【分析】写出13和20之间的数字,然后数一数.\n【详解】13和20之间有14,15,16,17,18,19,有6个数。", + "knowledge_points": [ + "20以内数的排序" + ], + "source": "24-25 一年级上·湖南常德·期末" + }, + { + "id": "359", + "unit": "11~20的认识", + "question_type": "填空题", + "difficulty": 0.85, + "question": "6 个一和 1 个十合起来是( )。19里面有( )个十和( )个一。和10相邻的两个数是( )和( )。", + "options": [ + + ], + "answer": "16;1;9;9;11", + "solution": "【分析】几个十就是几十,几个一就是几。一个两位数,从右往左数,第一位是个位,个位上的数表示几个一;第二位是十位,十位上的数表示几个十。一个数前面第一个数比它小 1,后面第一个数比它大 1.\n【详解】6个一和1个十合起来是16.19里面有1个十和9个一。和10相邻的两个数是9和11。", + "knowledge_points": [ + "20以内数的组成", + "20以内数的排序" + ], + "source": "24-25 一年级上·广东阳江·期末" + }, + { + "id": "360", + "unit": "11~20的认识", + "question_type": "填空题", + "difficulty": 0.85, + "question": "一个加数是 15,另一个加数是 4,和是( )。", + "options": [ + + ], + "answer": "19", + "solution": "【分析】根据\"一个加数 + 另一个加数 = 和\"来完成此题.\n【详解】15 + 4 = 19,即一个加数是 15,另一个加数是 4,和是 19。", + "knowledge_points": [ + "不进位加法 (20以内)" + ], + "source": "24-25一年级上·新疆喀什·期末" + }, + { + "id": "361", + "unit": "11~20的认识", + "question_type": "填空题", + "difficulty": 0.85, + "question": "19 和 12, ( )更接近 20, ( )更接近 10。", + "options": [ + + ], + "answer": "19;12", + "solution": "【分析】结合整数的认识,10 的后面的第二个数是 12,而 19 距离 10 很远,所以 12 更接近 10;20 的前面 1 个数就是 19,12 距离 20 很远,所以 19 更接近 20。据此答题即可.\n【详解】19和12两个数,19更接近20,12更接近10。", + "knowledge_points": [ + "20以内数的排序" + ], + "source": "24-25 一年级上·湖北武汉·期末" + }, + { + "id": "362", + "unit": "11~20的认识", + "question_type": "填空题", + "difficulty": 0.85, + "question": "6 个一和 1 个十合起来是( ),和它相邻的数是( )和( )。", + "options": [ + + ], + "answer": "16;15;17", + "solution": "【分析】根据题意可知:一个两位数,从右往左数,第一位是个位,个位上是几就表示几个一,第二位是十位,十位上是几就表示几个十,据此写数即可。求其相邻数就是求比其少 1 和多 1 的数,分别减 1,加 1 即可.\n【详解】16 - 1 = 15,16 + 1 = 17,则 6 个一和 1 个十合起来是 16,和它相邻的数是 15 和 17。", + "knowledge_points": [ + "20以内数的组成", + "不进位加法(20以内)", + "不退位减法(20以内)" + ], + "source": "24-25 一年级上·湖北武汉·期末" + }, + { + "id": "363", + "unit": "11~20的认识", + "question_type": "填空题", + "difficulty": 0.65, + "question": "一个加数是 10,另一个加数是 5,和是( )。被减数是 10,减数是 5,差是( )。", + "options": [ + + ], + "answer": "15;5", + "solution": "【分析】在加法算式中,加数 + 加数 = 和;在减法算式中,被减数 - 减数 = 差.\n【详解】10 + 5 = 15,10 - 5 = 5;所以和是 15,差是 5。", + "knowledge_points": [ + "不进位加法(20以内)" + ], + "source": "24-25 一年级上·湖北武汉·期末" + }, + { + "id": "364", + "unit": "11~20的认识", + "question_type": "填空题", + "difficulty": 0.65, + "question": "15 是由( )个十和( )个一组成的;2 个十是( )。", + "options": [ + + ], + "answer": "1;5;20", + "solution": "【分析】在数位顺序表中,从右边起第一位是个位,第二位是十位,十位上的数字是几表示几个十,个位上的数字是几表示几个一.\n【详解】15 的个位是 5 表示 5 个一,十位是 1 表示 1 个十;2 个十是 20。", + "knowledge_points": [ + "20以内数的组成" + ], + "source": "24-25 一年级上·湖北武汉·期末" + }, + { + "id": "365", + "unit": "11~20的认识", + "question_type": "填空题", + "difficulty": 0.85, + "question": "1 个十和 4 个一合起来是( ),它和( )合起来是 20。", + "options": [ + + ], + "answer": "14;6", + "solution": "【分析】几个十就是几十,几个一就是几;十位上是几就是几十,个位上是几就是几,所以1个十和4个一合起来是14;从14开始往后数,15,16,17,18,19,20,一共数了6个数,所以14和6合起来是20.\n【详解】1 个十和 4 个一合起来是 14,它和 6 合起来是 20。", + "knowledge_points": [ + "20以内数的组成", + "20以内数的排序" + ], + "source": "24-25 一年级上·河北保定·期末" + }, + { + "id": "366", + "unit": "11~20的认识", + "question_type": "填空题", + "difficulty": 0.85, + "question": "11 后面的第 3 个数是( ),19 在( )和( )之间。", + "options": [ + + ], + "answer": "14;18;20", + "solution": "【分析】从 11 开始,一个一个地往后数,一直数到 19 后面的一个数,据此即可解决此题.\n【详解】由题意分析得:11, 12, 13, 14, 15, 16, 17, 18, 19, 20;即,11后面的第3个数是14,19在18和20之间。", + "knowledge_points": [ + "数一数", + "20以内数的排序" + ], + "source": "24-25 一年级上·辽宁鞍山·期末" + }, + { + "id": "367", + "unit": "11~20的认识", + "question_type": "填空题", + "difficulty": 0.85, + "question": "小强家的上面有 5 层,下面有 9 层,小强家住第( )层,这栋楼一共有( )层。", + "options": [ + + ], + "answer": "10;15", + "solution": "【分析】小强家住的楼层 = 下面的楼层 + 1 层;一共的楼层 = 小强家住的楼层 + 他家上面的楼层即可,用加法计算,据此解答.\n【详解】9 + 1 = 10(层),10 + 5 = 15(层),所以小强家住第10层,这栋楼一共有15层。", + "knowledge_points": [ + "10 的加减法", + "不进位加法(20以内)" + ], + "source": "24-25 一年级上·湖南岳阳·期末" + }, + { + "id": "368", + "unit": "11~20的认识", + "question_type": "填空题", + "difficulty": 0.85, + "question": "( )里面有 8 个一和 1 个十;20 里面有( )个十。", + "options": [ + + ], + "answer": "18;2", + "solution": "【分析】一个两位数,从右往左依次为个位,十位。十位是几就有几个十,个位是几就有几个一,由此解答.\n【详解】18 里面有 8 个一和 1 个十;20 里面有 2 个十。", + "knowledge_points": [ + "20以内数的组成" + ], + "source": "24-25一年级上·新疆喀什·期末" + }, + { + "id": "369", + "unit": "11~20的认识", + "question_type": "填空题", + "difficulty": 0.85, + "question": "16 里面有( )个十和( )个一。和它相邻的数是( )和( )。", + "options": [ + + ], + "answer": "1;6;15;17", + "solution": "【分析】一个两位数,从右往左依次为个位,十位,十位是几表示几个十,个位是几表示几个一。它的相邻数是它两侧的数,20以内数从小到大顺序为:0,1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,由此解答.\n【详解】16里面有1个十和6个一。和它相邻的数是15和17。", + "knowledge_points": [ + "20以内数的组成", + "20以内数的排序" + ], + "source": "24-25 一年级上·内蒙古通辽·期末" + }, + { + "id": "370", + "unit": "11~20的认识", + "question_type": "填空题", + "difficulty": 0.85, + "question": "2 个十是( );8个一和 1 个十组成( )。", + "options": [ + + ], + "answer": "20;18", + "solution": "【分析】从右边起第一位是个位,个位上是几,就表示几,第二位是十位,十位上是几,就表示几十,据此结合题干要求进行解答即可.\n【详解】2个十是20;8个一是8,1个十是10,组成是18。", + "knowledge_points": [ + "20以内数的组成" + ], + "source": "24-25 一年级上·山东菏泽·期末" + }, + { + "id": "371", + "unit": "11~20的认识", + "question_type": "填空题", + "difficulty": 0.85, + "question": "一个一个地数,从 6 数到 17,一共数了( )个数。", + "options": [ + + ], + "answer": "12", + "solution": "【分析】从 6 开始,一个一个地数,一直数到 17,即可知道一共数了几个数.\n【详解】由题意分析得:6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17;即,一个一个地数,从 6 数到 17,一共数了 12 个数。", + "knowledge_points": [ + "数一数" + ], + "source": "24-25 一年级上·山东济宁·期末" + }, + { + "id": "372", + "unit": "11~20的认识", + "question_type": "填空题", + "difficulty": 0.65, + "question": "李老师按学号抽查学生背诵《三字经》, 今天一共抽查了( )位学生.\n![](images/屏幕截图%202025-12-03%20194908.jpg)", + "options": [ + + ], + "answer": "10", + "solution": "【分析】用 19 减 10,多减了 1 位 (10 号), 再加上 1 即可求解.\n【详解】19 - 10 + 1 = 10(位),今天一共抽查了 10 位学生。", + "knowledge_points": [ + "加减混合运算(20以内)", + "图文问题" + ], + "source": "24-25 一年级上·河北张家口·期末" + }, + { + "id": "373", + "unit": "11~20的认识", + "question_type": "判断题", + "difficulty": 0.65, + "question": "6 个一和 1 个十组成的数是 61。( )", + "options": [ + + ], + "answer": "×", + "solution": "【分析】6 个一是 6, 1 个十是 10, 6 个一和 1 个十组成的数是 16.\n【详解】6个一和1个十组成的数是 16。故答案为: ×", + "knowledge_points": [ + "20以内数的组成" + ], + "source": "24-25 一年级上·四川广元·期末" + }, + { + "id": "374", + "unit": "11~20的认识", + "question_type": "判断题", + "difficulty": 0.85, + "question": "11 的个位和十位数字相同,所以表示的意义也相同。( )", + "options": [ + + ], + "answer": "×", + "solution": "【分析】一个两位数,从右往左数,第一位是个位,个位上的数表示几个一;第二位是十位,十位上表示几个十,据此解答.\n【详解】11 个位上的数是\"1\",表示 1 个一;十位上也是\"1\",表示 1 个十,表示的意义不相同,原说法错误。故答案为: ×", + "knowledge_points": [ + "11~20 的认识和读写", + "20以内数的组成" + ], + "source": "24-25 一年级上·四川广元·期末" + }, + { + "id": "375", + "unit": "11~20的认识", + "question_type": "判断题", + "difficulty": 0.85, + "question": "15 前面的第 5 个数是 10。( )", + "options": [ + + ], + "answer": "√", + "solution": "【分析】根据数的排列顺序,15前面的数是:0,1,2,3,4,5,6,7,8,9,10,11,12,13,14,15, 15 前面的第 5 个数是 10 .\n【详解】根据分析可得:15前面的第5个数是10。所以原说法正确。故答案为: √", + "knowledge_points": [ + "认识几和第几", + "20以内数的排序" + ], + "source": "24-25 一年级上·四川广元·期末" + }, + { + "id": "376", + "unit": "11~20的认识", + "question_type": "判断题", + "difficulty": 0.85, + "question": "20 里面有 20 个一。 ( )", + "options": [ + + ], + "answer": "√", + "solution": "【分析】一个一个的数数到 20 要数 20 个,也就是 20 里面有 20 个一。据此得出结论即可.\n【详解】根据分析知:20 里面有 20 个一。说法正确。故答案为:√", + "knowledge_points": [ + "20以内数的组成" + ], + "source": "18-19 一年级上·全国·单元测试" + }, + { + "id": "377", + "unit": "11~20的认识", + "question_type": "判断题", + "difficulty": 0.65, + "question": "与 17 相邻的两个数是 15 与 18。()", + "options": [ + + ], + "answer": "×", + "solution": "【分析】与 17 相邻的两个数是 16 与 18,据此得出结论即可.\n【详解】根据分析知:与 17 相邻的两个数是 15 与 18,说法错误。故答案为: ×", + "knowledge_points": [ + "20以内数的排序" + ], + "source": "24-25 一年级上·甘肃天水·期末" + }, + { + "id": "378", + "unit": "11~20的认识", + "question_type": "判断题", + "difficulty": 0.65, + "question": "11 中的两个 \"1\"表示的意义相同。( )", + "options": [ + + ], + "answer": "×", + "solution": "【分析】一个两位数,左边的数位是十位,十位上是几表示几个十,右边的数位是个位,个位上是几表示几个一,据此得出结论即可.\n【详解】根据分析知:11 中的两个\"1\",左边的\"1\"表示 1 个十,右边的\"1\"表示 1 个一,表示的意义不相同。故答案为: ×", + "knowledge_points": [ + "20以内数的组成" + ], + "source": "24-25 一年级上·甘肃天水·期末" + }, + { + "id": "379", + "unit": "11~20的认识", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式.\n![](images/646fce90332ac6edea15f4747198c53af4e22ebc7f81364b4cf688d19479e2eb.jpg)\n□ ○ □ ○ □ = □ (只)", + "options": [ + + ], + "answer": "7 + 3 + 2 = 12", + "solution": "【分析】根据图片可知:求一共多少只。用左边的数量加中间的数量再加右边的数量即可.\n【详解】7 + 3 + 2 = 12(只)", + "knowledge_points": [ + "连加(20以内)", + "图文问题" + ], + "source": "24-25 一年级上·河南周口·期末" + }, + { + "id": "380", + "unit": "11~20的认识", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式计算.\n![](images/a43ba15bbd5da3d5189972fa7fcf3bf8e4a39ac6db53461a43a83d7de28f217f.jpg)\n□ ○ □ = □ (个)", + "options": [ + + ], + "answer": "16 - 2 = 14", + "solution": "【分析】根据图片可知:求左边的数量。用共有的数量减去右边的数量即可.\n【详解】16 - 2 = 14(个)", + "knowledge_points": [ + "不退位减法(20以内)", + "图文问题" + ], + "source": "24-25一年级上·湖北省直辖县级单位·期末" + }, + { + "id": "381", + "unit": "11~20的认识", + "question_type": "计算题", + "difficulty": 0.85, + "question": "我会看图列式.\n![](images/fe7864d6598b2c1e3b25691589ecd9968b33e26e0e867226c7cbc628accf8f72.jpg)\n□ ○ □ = □ (个)", + "options": [ + + ], + "answer": "15 - 3 = 12", + "solution": "【分析】如图,用草莓的总数减去右边的个数,即可计算出左边有多少个.\n【详解】15 - 3 = 12(个)", + "knowledge_points": [ + "不退位减法(20以内)" + ], + "source": "24-25 一年级上·浙江宁波·期末" + }, + { + "id": "382", + "unit": "11~20的认识", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式计算.\n![](images/bc7f9f430af93bd5e7191f967d33d110f7e4e70560e319af7cb57654078e25bb.jpg)\n□ ○ □ = □ (个)", + "options": [ + + ], + "answer": "16 - 2 = 14", + "solution": "【分析】用总数减去右面的个数,即可求出左面的个数.\n【详解】16 - 2 = 14(个)", + "knowledge_points": [ + "不退位减法(20以内)", + "图文问题" + ], + "source": "24-25 一年级上·湖北武汉·期末" + }, + { + "id": "383", + "unit": "11~20的认识", + "question_type": "计算题", + "difficulty": 0.85, + "question": "列算式.\n![](images/f8343cf8bd786dfabdaf3a124c5537d39757fdab3414f1b3a11c2e9ceadb1c1b.jpg)\n□ ○ □ = □ (个)", + "options": [ + + ], + "answer": "17 - 7 = 10", + "solution": "【分析】用胡萝卜的总数量减去右边的数量,求出差,就是左边筐里的数量.\n【详解】17 - 7 = 10(个)", + "knowledge_points": [ + "不退位减法(20以内)", + "图文问题" + ], + "source": "24-25 一年级上·湖南娄底·期末" + }, + { + "id": "384", + "unit": "11~20的认识", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式计算.\n![](images/e334aef98769abf67da15a9b7dd9997020b3c6de097c6e200d1ab12b29f51b57.jpg)\n□ ○ □ = □ (支)", + "options": [ + + ], + "answer": "15 - 5 = 10", + "solution": "【分析】铅笔的总支数减去右边的支数,等于文具袋中的支数,据此解答即可.\n【详解】15 - 5 = 10(支),文具袋中有 10 支铅笔。", + "knowledge_points": [ + "不退位减法(20以内)", + "图文问题" + ], + "source": "24-25 一年级上·四川广元·期末" + }, + { + "id": "385", + "unit": "11~20的认识", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式计算.\n![](images/f317478bbc3189e7187fac21ae2929d18b9e294d98cee7fd5863b9fcb0010974.jpg)\n□ ○ □ = □ (本)", + "options": [ + + ], + "answer": "3 + 12 = 15", + "solution": "【分析】把左边的书数量与书包里的数量加起来,求出和,就是一共的数量.\n【详解】3 + 12 = 15(本)", + "knowledge_points": [ + "不进位加法(20以内)", + "图文问题" + ], + "source": "24-25 一年级上·四川广元·期末" + }, + { + "id": "386", + "unit": "11~20的认识", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式计算.\n![](images/a10949e0aceb338f5ff056575ff5d0e390a7191f1e090c7222412b6eed955156.jpg)\n□ ○□ ○ □ = □ (支)", + "options": [ + + ], + "answer": "15 - 3 - 2 = 10", + "solution": "【分析】已知一共有 15 支铅笔,已知左边有 3 支铅笔,中间有 2 支铅笔,要求右边的文具盒里面有多少支铅笔,根据减法的意义,用 15 - 3 - 2 进行解答即可.\n【详解】15 - 3 - 2 = 12 - 2 = 10(支)", + "knowledge_points": [ + "连减(20以内)", + "图文问题" + ], + "source": "24-25 一年级上·湖北黄石·期末" + }, + { + "id": "387", + "unit": "11~20的认识", + "question_type": "计算题", + "difficulty": 0.65, + "question": "看图列式计算.\n![](images/00a8fe33121ab5779d1f3226c1a927dabc04baff15edc93fa99841c9ab0c36ec.jpg)\n□ ○ □ = □ (个)", + "options": [ + + ], + "answer": "17 - 5 = 12", + "solution": "【分析】球的总个数减去右边的个数等于左边盒子里的个数,据此列式解答.\n【详解】17 - 5 = 12(个),盒子里有 12 个球。", + "knowledge_points": [ + "不退位减法(20以内)", + "图文问题" + ], + "source": "24-25 一年级上·甘肃兰州·期末" + }, + { + "id": "388", + "unit": "11~20的认识", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式计算.\n![](images/044a33168ed64da4675392433cc3b70c2c9bf35637e4cbfe54a100e2ef964b00.jpg)\n□ ○ □ = □ (个)", + "options": [ + + ], + "answer": "17 - 5 = 12", + "solution": "【分析】用一共的 17 个减去右边的 5 个,即可求出左边的个数.\n【详解】17 - 5 = 12(个)", + "knowledge_points": [ + "不退位减法(20以内)", + "图文问题" + ], + "source": "24-25 一年级上·河北邯郸·期末" + }, + { + "id": "389", + "unit": "11~20的认识", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列算式.\n![](images/f771c3c4813548ebf698b8a9a64ef2d13730f74839640757c74276486fab1175.jpg)\n□ ○ □ = □ (只)", + "options": [ + + ], + "answer": "16 - 5 = 11", + "solution": "【分析】用一共的 16 只减去左边的 5 只即可求出右边的只数.\n【详解】16 - 5 = 11(只),右边房子里有 11 只鸟。", + "knowledge_points": [ + "不退位减法(20以内)", + "图文问题" + ], + "source": "24-25 一年级上·湖南常德·期末" + }, + { + "id": "390", + "unit": "11~20的认识", + "question_type": "计算题", + "difficulty": 0.65, + "question": "看图列算式.\n![](images/7acdb2a2189202af4d640731ae41b520b2d4aab9112280051511841bb32c659b.jpg)\n□ ○ □ = □ (根)", + "options": [ + + ], + "answer": "15 - 3 = 12", + "solution": "【分析】根据题意,一共有 15 根,左边有 3 根,求右边有几根。用总的数量减去左边的数量,即可求出右边的数量。用减法列式计算.\n【详解】15 - 3 = 12(根),右边有 12 根。", + "knowledge_points": [ + "不退位减法(20以内)", + "图文问题" + ], + "source": "24-25 一年级上·湖南常德·期末" + }, + { + "id": "391", + "unit": "11~20的认识", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式.\n![](images/8cbca26559dbfc2c7ce5e828583c1a019fed17fed29be70df0d51f9982ebc332.jpg)\n□ ○ □ = □ (本)", + "options": [ + + ], + "answer": "15 - 5 = 10", + "solution": "【分析】根据图片可知:一共 15 支笔,右边有 5 支笔,求左边有多少支。 用共有的数量减去右边的数量即可.\n【详解】15 - 5 = 10(支)", + "knowledge_points": [ + "不退位减法(20以内)" + ], + "source": "24-25一年级上·山东聊城·期末" + }, + { + "id": "392", + "unit": "11~20的认识", + "question_type": "解答题", + "difficulty": 0.65, + "question": "一(1)班小朋友放学排队,小明排在第7,小东排在第17,小明和小东之间有几人。", + "options": [ + + ], + "answer": "9人", + "solution": "【分析】由题意可知要求小明和小东之间的人数,应该不包括小明和小东,先用小东的位置数减去小明的位置数,但是这个结果包含了小东所在的位置,所以要把小东这一位置去掉,也就是再减去 1,列式为 17 - 7 - 1.\n【详解】17 - 7 - 1 = 9(人),答:小明和小东之间有 9 人。", + "knowledge_points": [ + "不进位,不退位连加,连减(20以内)" + ], + "source": "24-25一年级上·江西赣州·期末" + }, + { + "id": "393", + "unit": "11~20的认识", + "question_type": "解答题", + "difficulty": 0.85, + "question": "一盒彩笔 18 支,拿走一些后,还剩 8 支,拿走了多少支。", + "options": [ + + ], + "answer": "10支", + "solution": "【分析】一盒彩笔的数量减去还剩下的数量,等于拿走的数量.\n【详解】18 - 8 = 10(支),答:拿走了 10 支。", + "knowledge_points": [ + "不退位减法 (20 以内)" + ], + "source": "24-25 一年级上·福建漳州·期末" + }, + { + "id": "394", + "unit": "11~20的认识", + "question_type": "解答题", + "difficulty": 0.85, + "question": "草地上原来有 19 只小羊,走了 7 只,又来了 6 只,现在草地上还有多少只羊。", + "options": [ + + ], + "answer": "18只", + "solution": "【分析】草地上原来小羊的数量减去走的数量,再加上来的数量,等于现在小羊的数量.\n【详解】19 - 7 = 12(只),12 + 6 = 18(只),答:现在草地上还有 18 只羊。", + "knowledge_points": [ + "不进位加法(20以内)", + "不退位减法(20以内)" + ], + "source": "24-25 一年级上·福建漳州·期末" + }, + { + "id": "395", + "unit": "11~20的认识", + "question_type": "解答题", + "difficulty": 0.65, + "question": "树上原来有 17 只鸟,飞走了 5 只,现在树上还剩几只鸟。", + "options": [ + + ], + "answer": "12只", + "solution": "【分析】原来的鸟的数量一飞走的鸟的数量 = 还剩的鸟的数量,据此列式解答即可.\n【详解】17 - 5 = 12(只),答:现在树上还剩 12 只鸟。", + "knowledge_points": [ + "不退位减法(20以内)" + ], + "source": "24-25 一年级上·甘肃天水·期末" + }, + { + "id": "396", + "unit": "11~20的认识", + "question_type": "解答题", + "difficulty": 0.65, + "question": "盘子里原来有15个鸡蛋,吃了4个,还剩几个。\n□ ○ □ = □ (个)", + "options": [ + + ], + "answer": "15 - 4 = 11", + "solution": "【分析】原来的鸡蛋数量一吃了的鸡蛋数量 = 还剩的鸡蛋数量,据此列式解答即可.\n【详解】15 - 4 = 11(个),答:还剩下 11 个。", + "knowledge_points": [ + "不退位减法 (20 以内)" + ], + "source": "24-25一年级上·河北邯郸·期末" + }, + { + "id": "397", + "unit": "11~20的认识", + "question_type": "解答题", + "difficulty": 0.85, + "question": "车上原来有 16 人,到站后有 2 人下车, 3 人上车。现在车上有多少人。\n□ ○ □ ○ □ = □ (本)", + "options": [ + + ], + "answer": "16 - 2 + 3 = 17", + "solution": "【分析】从题干可知:下车2人,表示车上人数减少2人,上车3人,表示车上人数增加3人,根据整数加减法运算,即可得出现在车上有多少人.\n【详解】16 - 2 + 3 = 14 + 3 = 17(人),答:现在车上有 17 人。", + "knowledge_points": [ + "加减混合运算 (20 以内)" + ], + "source": "24-25 一年级上·安徽芜湖·期末" + }, + { + "id": "398", + "unit": "11~20的认识", + "question_type": "解答题", + "difficulty": 0.85, + "question": "树上一共有15只小鸟,飞走了5只,又飞来2只,现在树上有几只小鸟。\n□ ○ □ ○ □ = □ (只)", + "options": [ + + ], + "answer": "15 - 5 + 2 = 12", + "solution": "【分析】用树上一共的小鸟数量先减去飞走的数量,求出差,再加上又飞来的数量,求出和,即可解决.\n【详解】15 - 5 + 2 = 10 + 2 = 12(只),答:现在树上有 12 只小鸟。", + "knowledge_points": [ + "不进位,不退位加减混合运算(20以内)" + ], + "source": "24-25一年级上·河南漯河·期末" + }, + { + "id": "399", + "unit": "11~20的认识", + "question_type": "解答题", + "difficulty": 0.65, + "question": "她今天读了几页。\n![](images/屏幕截图%202025-12-03%20200548.jpg)\n□ ○ □ ○ □ = □ (页)", + "options": [ + + ], + "answer": "18 - 10 + 1 = 9", + "solution": "【分析】用 18 减 10,多减了 1 页 (第 10 页), 再加上 1 即可求解.\n【详解】18 - 10 + 1 = 9(页),答:她今天读了 9 页。", + "knowledge_points": [ + "加减混合运算(20以内)", + "图文问题" + ], + "source": "24-25一年级上·湖南常德·期末" + }, + { + "id": "400", + "unit": "11~20的认识", + "question_type": "解答题", + "difficulty": 0.85, + "question": "我会解决问题.\n![](images/3ec5139b5f1842077cb975b328ff4f4992735e95a3149cb7b144d7428bb24891.jpg)\n□ ○ □ = □(棵)", + "options": [ + + ], + "answer": "16 - 3 = 13", + "solution": "【分析】根据图片可知:一共有 16 棵白菜,左边有 3 棵,问右边篮子里有多少棵。用共有的数量减去左边的数量即可.\n【详解】16 - 3 = 13(棵);答:篮子里有 13 棵。", + "knowledge_points": [ + "不退位减法(20以内)" + ], + "source": "24-25 一年级上·广西柳州·期末" + }, + { + "id": "401", + "unit": "11~20的认识", + "question_type": "选择题", + "difficulty": 0.85, + "question": "几个小朋友一起比赛投篮,第一名投中19个,第三名投中16个,那么第二名不可能投中()个。", + "options": [ + "A. 17", + "B. 18", + "C. 20" + ], + "answer": "C", + "solution": "【分析】第一名投中 19 个,第三名投中 16 个,则第二名投中的个数要比 16 个多,且比 19 个少;而第二名投中其它的个数都是不可能的,据此解决即可。11 到 20,从小到大排序:11,12,13,14,15,16,17,18,19,20.\n【详解】A。16个\u003c17个\u003c19个;B. 16 个\u003c 18个\u003c 19 个;C. 16 个\u003c19 个\u003c20 个;即,几个小朋友一起比赛投篮,第一名投中 19 个,第三名投中 16 个,那么第二名不可能投中 20 个。故答案为: C", + "knowledge_points": [ + "20以内数的比大小" + ], + "source": "24-25一年级上·辽宁鞍山·期末" + }, + { + "id": "402", + "unit": "11~20的认识", + "question_type": "选择题", + "difficulty": 0.85, + "question": "9 后面第 3 个数是 ( )。", + "options": [ + "A. 3", + "B. 6", + "C. 9", + "D. 12" + ], + "answer": "D", + "solution": "【分析】9 后面第 1 个数是 10,第 2 个数是 11,第 3 个数是 12,据此选择即可.\n【详解】由分析可知:9 后面第 3 个数是 12。故答案为: D", + "knowledge_points": [ + "20以内数的排序" + ], + "source": "24-25 一年级上·辽宁鞍山·期末" + }, + { + "id": "403", + "unit": "11~20的认识", + "question_type": "选择题", + "difficulty": 0.85, + "question": "找规律7,10,13,16,()。", + "options": [ + "A. 18", + "B. 19", + "C. 20" + ], + "answer": "B", + "solution": "【分析】观察题干可知: 7 和 10 之间相差 3, 10 和 13 之间相差 3, 13 和 16 之间相差 3,所以这列数的变化规律是从左往右依次增加 3.\n【详解】16 + 3 = 19,所以这列数是 7,10,13,16,19。故答案为: B", + "knowledge_points": [ + "整数排列的规律", + "不进位加法(20以内)" + ], + "source": "24-25一年级上·内蒙古通辽·期末" + }, + { + "id": "404", + "unit": "11~20的认识", + "question_type": "选择题", + "difficulty": 0.85, + "question": "比 19 小,又比 12 大的数有 ( ) 个。", + "options": [ + "A. 4", + "B. 5", + "C. 6" + ], + "answer": "C", + "solution": "【分析】从 12 开始,一个一个地数,一直数到 19,即可找出比 19 小,又比 12 大的数有几个。11 到 20,从小到大排序: 11,12,13,14,15,16,17,18,19,20.\n【详解】由题意分析得:12, 13, 14, 15, 16, 17, 18, 19;即,比19小,又比12大的数有6个。故答案为: C", + "knowledge_points": [ + "20以内数的比大小" + ], + "source": "24-25 一年级上·内蒙古通辽·期末" + }, + { + "id": "405", + "unit": "11~20的认识", + "question_type": "选择题", + "difficulty": 0.85, + "question": "20 是由 ( ) 组成的。", + "options": [ + "A. 2 个一", + "B. 10 个一", + "C. 2 个十" + ], + "answer": "C", + "solution": "【分析】十位上是几就是几十,个位上是几就是几。几个十就是几十,几个一就是几.\n【详解】20是由2个十或者20个一组成的。故答案为: C", + "knowledge_points": [ + "20以内数的组成" + ], + "source": "24-25 一年级上·陕西西安·期末" + }, + { + "id": "406", + "unit": "11~20的认识", + "question_type": "选择题", + "difficulty": 0.85, + "question": "排队上公交车,我前面有 6 人,后面有 4 人,一共有 ( ) 人排队上车。", + "options": [ + "A. 11", + "B. 10", + "C. 12" + ], + "answer": "A", + "solution": "【分析】求一共有多少人,用加法计算,即前面的人数 + 后面的人数 + \"我\" 自己 = 总人数.\n【详解】6 + 4 + 1 = 11(人)一共有 11 人排队上车。故答案为: A", + "knowledge_points": [ + "不进位,不退位连加,连减(20以内)" + ], + "source": "24-25 一年级上·云南玉溪·期末" + }, + { + "id": "407", + "unit": "11~20的认识", + "question_type": "选择题", + "difficulty": 0.94, + "question": "明明读一本故事书,今天从第 11 页读到了第 17 页,明天他该从第()页开始读。", + "options": [ + "A. 17", + "B. 18", + "C. 11" + ], + "answer": "B", + "solution": "【分析】明天读的页码是今天读的页码的下一页,即 17 加 1,据此解答.\n【详解】17 + 1 = 18(页)所以明天他该从第 18 页开始读。故答案为: B", + "knowledge_points": [ + "不进位加法(20以内)", + "20以内数的排序" + ], + "source": "24-25 一年级上·云南玉溪·期末" + }, + { + "id": "408", + "unit": "11~20的认识", + "question_type": "选择题", + "difficulty": 0.65, + "question": "小朋友在游乐园排队玩滑坡,从前往后数,小东排第9,小丽排第14,他们两人之间一共有()人。", + "options": [ + "A. 4", + "B. 5", + "C. 6" + ], + "answer": "A", + "solution": "【分析】根据 20 以内数的排序,从 9 数到 14,它们之间有几个数字也就是有几个人,由此解答.\n【详解】从 9 数到 14 依次为:9,10,11,12,13,14.9和 14 之间有 4 个数字,即他们两人之间一共有 4 人。故答案为:A", + "knowledge_points": [ + "20以内数的排序" + ], + "source": "24-25一年级上·云南玉溪·期末" + }, + { + "id": "409", + "unit": "11~20的认识", + "question_type": "选择题", + "difficulty": 0.85, + "question": "20读作: ( )", + "options": [ + "A. 十二", + "B. 二十", + "C. 二" + ], + "answer": "B", + "solution": "【分析】整十数就读作几十,最后的零不读出来.\n【详解】20 读作:二十。故答案为: B", + "knowledge_points": [ + "11~20 的认识和读写" + ], + "source": "24-25 一年级上·广东汕头·期末" + }, + { + "id": "410", + "unit": "11~20的认识", + "question_type": "选择题", + "difficulty": 0.85, + "question": "被减数是 12,减数是 2,差是 ( )。", + "options": [ + "A. 14", + "B. 8", + "C. 10" + ], + "answer": "C", + "solution": "【分析】减法算式中,被减数 - 减数 = 差,据此列式计算.\n【详解】 12 - 2 = 10差是 10 。故答案为: C", + "knowledge_points": [ + "不退位减法 (20 以内)" + ], + "source": "24-25 一年级上·广东汕头·期末" + }, + { + "id": "411", + "unit": "11~20的认识", + "question_type": "选择题", + "difficulty": 0.85, + "question": "下面关于 17 的说法中,正确的是 ( )。", + "options": [ + "A. 17 比 20 大", + "B. 17 是 15 和 19 之间的单数", + "C. 17 的十位上是 1,个位上的数字比十位上的数字大 7" + ], + "answer": "B", + "solution": "【分析】A。20以内数从大到小关系为: 20 \u003e 19 \u003e 18 \u003e 17\u003e 16 \u003e 15 \u003e 14 \u003e 13 \u003e 12 \u003e 11 \u003e 10 \u003e 9 \u003e 8 \u003e 7 \u003e 6 \u003e 5 \u003e 4 \u003e 3 \u003e 2 \u003e1\u003e0,由此比较;B. 一个两位数,从右往左依次为个位,十位,个位是 1, 3, 5, 7, 9 的数是单数,由此找出 15 和 19 之间的单数即可;C. 个位上的数 - 十位上的数 = 个位上比十位上大的数。由此解答.\n【详解】A。 17 \u003c 20 ,17比20小,原说法错误;B. 15, 16, 17, 18, 19.17是15和19之间的单数,原说法正确;C. 7 - 1 = 6, 17 的十位上是 1,个位上的数字比十位上的数字大 6,原说法错误。说法正确的是 17 是 15 和 19 之间的单数。故答案为: B", + "knowledge_points": [ + "20以内数的组成", + "20以内数的比大小", + "20以内数的排序" + ], + "source": "24-25 一年级上·甘肃陇南·期末" + }, + { + "id": "412", + "unit": "11~20的认识", + "question_type": "选择题", + "difficulty": 0.85, + "question": "木木读《西游记》,从第 8 页读到了第 15 页,一共读了 ( ) 页。", + "options": [ + "A. 7", + "B. 8", + "C. 9" + ], + "answer": "B", + "solution": "【分析】根据题意,按照 20 以内数的顺序,依次从 8 数到 15,数了几个数就是读了几页.\n【详解】从8数到15,依次为:8, 9, 10, 11, 12, 13, 14, 15,共数了 8 个数。即一共读了8页。故答案为: B", + "knowledge_points": [ + "20以内数的排序" + ], + "source": "24-25 一年级上·甘肃陇南·期末" + }, + { + "id": "413", + "unit": "11~20的认识", + "question_type": "选择题", + "difficulty": 0.65, + "question": "10+ ( ) \u003e17,括号里最小填 ( )。", + "options": [ + "A. 7", + "B. 8", + "C. 9" + ], + "answer": "B", + "solution": "【分析】想 10 + ( ) = 17,用 17 - 10 = 7 算出 ( ) =7,则, 10 + 7 = 17;如果 10 + ( ) \u003e 17,那么 ( ) 里最小只要比 7 大 1 即可.\n【详解】由题意分析得:17 - 10 = 7, 7 + 1 = 8,10 + 8 = 18,则, 10 + 8 \u003e 17;即, 10 + () \u003e 17,括 号 里 最 小 填 8 。故答案为: B", + "knowledge_points": [ + "20 以内数的比大小", + "8,9 的加减法", + "不进位加法(20 以内)", + "不退位减法(20 以内)" + ], + "source": "24-25 一年级上·吉林·期末" + }, + { + "id": "414", + "unit": "11~20的认识", + "question_type": "选择题", + "difficulty": 0.85, + "question": "与15更接近的数是( )。", + "options": [ + "A. 5", + "B. 20", + "C. 17" + ], + "answer": "C", + "solution": "【分析】两个数之间的数越少,表示这两个越接近;先一个一个地数一数,然后找出两个数之间各有几个数,并进行比较,即可解决.\n【详解】由题意分析得:5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20;A. 5 与 15 之间有: 6, 7, 8, 9, 10, 11, 12, 13, 14,共 9 个数;B. 15 与 20 之间有: 16, 17, 18, 19,共 4 个数;C. 15 与 17 之间有: 16,共 1 个数;9 \u003e 4 \u003e 1即,与 15 更接近的数是 17 .\n故答案为: C", + "knowledge_points": [ + "10以内数的比大小", + "数一数", + "20以内数的排序" + ], + "source": "24-25 一年级上·吉林·期末" + }, + { + "id": "415", + "unit": "11~20的认识", + "question_type": "选择题", + "difficulty": 0.85, + "question": "被减数是18,减数是 8,差是 10,正确的算式是()。", + "options": [ + "A. 10 + 8 = 18", + "B. 18 - 10 = 8", + "C. 18 - 8 = 10" + ], + "answer": "C", + "solution": "【分析】在减法算式中,减号前面的是被减数,减号后面的是减数,等号后面的数是差,据此解答.\n【详解】A。 10 + 8 = 18 是加法算式,故答案不正确;B. 被减数用的正确,但是减数和差用反了,故答案不正确;C. 这个算式被减数,减数和差,位置正确。故答案为: C", + "knowledge_points": [ + "不退位减法(20以内)" + ], + "source": "24-25 一年级上·内蒙古呼伦贝尔·期末" + }, + { + "id": "416", + "unit": "11~20的认识", + "question_type": "选择题", + "difficulty": 0.65, + "question": "3 + □\u003c 15,里最大能填( )。", + "options": [ + "A. 11", + "B. 12", + "C. 10" + ], + "answer": "A", + "solution": "【分析】小于 15 的数中最小的是 14, 3 + □ 得数是 14 时符合条件,用 14 减 3 即可求解.\n[详解 15 - 1 = 14,14 - 3 = 11,3 + □ \u003c 15,里最大能填11。故答案为: A", + "knowledge_points": [ + "20以内数的比大小", + "不退位减法(20以内)" + ], + "source": "24-25 一年级上·安徽芜湖·期末" + }, + { + "id": "417", + "unit": "11~20的认识", + "question_type": "选择题", + "difficulty": 0.65, + "question": "今天聪聪从一本书的第11页读到了第15页,明天聪聪该从第16页读了,聪聪今天一共读了()页。", + "options": [ + "A. 4", + "B. 5", + "C. 6" + ], + "answer": "B", + "solution": "【分析】用 15 减 11,多减了 1 页(第 11 页),再加上 1 即可求解.\n【详解】15 - 11 + 1 = 5 (页)聪聪今天一共读了5页。故答案为: B", + "knowledge_points": [ + "不退位减法(20以内)", + "加减混合运算(20以内)" + ], + "source": "24-25一年级上·青海果洛·期末" + }, + { + "id": "418", + "unit": "11~20的认识", + "question_type": "选择题", + "difficulty": 0.85, + "question": "14 位小朋友排队进入太空舱参观,凡凡前面有 2 人,后面有()人。", + "options": [ + "A. 9", + "B. 10", + "C. 11" + ], + "answer": "C", + "solution": "【分析】要求凡凡后面有多少人,根据减法的意义,用 14 原来减去凡凡前面的人,再减去凡凡这个人,据此解答即可.\n【详解】14 - 2 - 1= 12 - 1= 11 (人)所以凡凡后面有 11 人。故答案为: C", + "knowledge_points": [ + "连减 (20以内)" + ], + "source": "24-25 一年级上·河北秦皇岛·期末" + }, + { + "id": "419", + "unit": "11~20的认识", + "question_type": "选择题", + "difficulty": 0.85, + "question": "下面和 13 最接近的数是()。", + "options": [ + "A. 10", + "B. 15", + "C. 20" + ], + "answer": "B", + "solution": "【分析】从 10 开始,一个一个地数,一直数到 20,再根据两个数之间的数越少,表示这两个数越接近.\n【详解】由题意分析得:10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20;A. 10 和 13 之间有 2 个数;B. 13 和 15 之间有 1 个数;C. 13 和 20 之间有 6 个数;即,最接近 13 的数是 15。故答案为: B", + "knowledge_points": [ + "数一数" + ], + "source": "24-25 一年级上·河北秦皇岛·期末" + }, + { + "id": "420", + "unit": "11~20的认识", + "question_type": "选择题", + "difficulty": 0.85, + "question": "与18最接近的数是( )。", + "options": [ + "A. 17", + "B. 16", + "C. 20" + ], + "answer": "A", + "solution": "【分析】要求与 18 最接近的数是多少,即求比 18 多 1 或者少 1 的数是多少.\n【详解】18 - 1 = 17,18 + 1 = 19,所以与 18 最接近的数是 17 和 19。故答案为: A", + "knowledge_points": [ + "不进位加法(20以内)", + "不退位减法(20以内)", + "20以内数的排序" + ], + "source": "24-25 一年级上·广西柳州·期末" + }, + { + "id": "421", + "unit": "11~20的认识", + "question_type": "选择题", + "difficulty": 0.85, + "question": "9 后面第 3 个数是 ( )。", + "options": [ + "A. 6", + "B. 12", + "C. 9" + ], + "answer": "B", + "solution": "【分析】9 后面第 1 个数是 10,第 2 个数是 11,第 3 个数是 12,据此得出结论即可.\n【详解】根据分析知:9 后面第 3 个数是 12。故答案为: B", + "knowledge_points": [ + "20以内数的排序" + ], + "source": "24-25 一年级上·全国·单元测试" + }, + { + "id": "422", + "unit": "11~20的认识", + "question_type": "填空题", + "difficulty": 0.85, + "question": "1 个十和 7 个一合起来是( ),这个数读作( )。", + "options": [ + + ], + "answer": "17;十七", + "solution": "【分析】几个十就是几十,几个一就是几。1个十就是 10,7个一就是7,合起来就是17。读数时从高位读起,几 个十读作几十,几个一读作几.\n【详解】1个十和7个一合起来是17,这个数读作十七。", + "knowledge_points": [ + "20以内数的组成", + "11~20 的认识和读写" + ], + "source": "24-25 一年级上·甘肃天水·期末" + }, + { + "id": "423", + "unit": "11~20的认识", + "question_type": "填空题", + "difficulty": 0.85, + "question": "按规律填一填。(1)9, 11, ( ), 15, ( )19。 (2)20, ( ), 10, 5, ( )。", + "options": [ + + ], + "answer": "13;17;15;0", + "solution": "【分析】(1)结合已知数字,可以发现规律:后面的数比前面的数大 2;(2) 结合已知数字,可以发现规律:后面的数比前面的数小 5,据此解答.\n【详解】 (1) 11 + 2 = 13, 15 + 2 = 17;根据分析可得:9, 11, 13, 15, 17, 19。(2) 20 - 5 = 15, 5 - 5 = 0;根据分析可得:20, 15, 10, 5, 0。", + "knowledge_points": [ + "整数排列的规律", + "20以内数的排序" + ], + "source": "24-25 一年级上·湖南岳阳·期末" + }, + { + "id": "424", + "unit": "11~20的认识", + "question_type": "填空题", + "difficulty": 0.85, + "question": "福建舰是我国的航空母舰,它的舷号是\"18\",这个数读作( ),由( )个十和( )个一组成。", + "options": [ + + ], + "answer": "十八;1;8", + "solution": "【分析】整数的读法:从高位到低位,一级一级地读,每一级末尾的 0 都不读出来,其余数位连续几个 0 都只读一个零。一个两位数,从右往左数,第一位是个位,个位上的数表示几个一;第二位是十位,十位上的数表示几个十.\n【详解】福建舰是我国的航空母舰,它的舷号是\"18\",这个数读作:十八,由 1 个十和 8 个一组成。", + "knowledge_points": [ + "20以内数的组成", + "11~20的认识和读写" + ], + "source": "24-25 一年级上·湖南常德·期末" + }, + { + "id": "425", + "unit": "11~20的认识", + "question_type": "填空题", + "difficulty": 0.85, + "question": "比 12 大 1 的数是( )。", + "options": [ + + ], + "answer": "13", + "solution": "【分析】求比一个数大几的数是多少,用加法列式解决.\n【详解】12 + 1 = 13即,比 12 大 1 的数是 13。", + "knowledge_points": [ + "不进位加法(20以内)" + ], + "source": "24-25 一年级上·甘肃天水·期末" + }, + { + "id": "426", + "unit": "11~20的认识", + "question_type": "填空题", + "difficulty": 0.85, + "question": "1 个十和 8 个一合起来是( ),再添上 1 就是( )。", + "options": [ + + ], + "answer": "18;19", + "solution": "【分析】18 由 1 个十和 8 个一组成,所以 1 个十和 8 个一合起来是 18,添上 1 就是从 18 向后数 1,据此完成填空即可.\n【详解】根据分析可知:1个十和8个一合起来是18;18再添上1就是19。", + "knowledge_points": [ + "20以内数的组成", + "20以内数的排序" + ], + "source": "24-25 一年级上·云南玉溪·期末" + }, + { + "id": "427", + "unit": "11~20的认识", + "question_type": "填空题", + "difficulty": 0.85, + "question": "10 和 19, ( )更接近 13, 20 里面有( )个一。", + "options": [ + + ], + "answer": "10;20", + "solution": "【分析】20 以内数的排列从小到大为: 0 \u003c 1 \u003c 2 \u003c 3 \u003c 4 \u003c 5 \u003c 6 \u003c 7 \u003c 8 \u003c 9 \u003c 10 \u003c 11 \u003c 12 \u003c 13 \u003c 14 \u003c 15 \u003c 16 \u003c 17 \u003c 18 \u003c 19 \u003c 20, 10 到 13 之间有 2 个数,而 19 和 13 之间有 5 个数,据此可找出更接近 13 的数;10 个一是 1 个十, 20 个一是 2 个十即 20,根据分析即可填空.\n【详解】根据分析可得:10 和 19,10 更接近 13;因为 20 个一是 20,所以 20 里面有 20 个一。", + "knowledge_points": [ + "20以内数的组成", + "20以内数的排序" + ], + "source": "24-25 一年级上·云南玉溪·期末" + }, + { + "id": "428", + "unit": "11~20的认识", + "question_type": "填空题", + "difficulty": 0.85, + "question": "18 的个位上是( ),表示( )个( ), 18 再添上( )是 20。", + "options": [ + + ], + "answer": "8;8;一;2", + "solution": "【分析】一个两位数,从右往左依次为个位,十位,十位是几表示几个十,个位是几表示几个一。18 后面的数为 19,20,也就是再数 2 个数是 20,即再加上 2 是 20.\n【详解】18 的个位上是 8,表示 8 个一, 18 再添上 2 是 20。", + "knowledge_points": [ + "20以内数的组成", + "20以内数的排序" + ], + "source": "24-25 一年级上·甘肃平凉·期末" + }, + { + "id": "429", + "unit": "11~20的认识", + "question_type": "填空题", + "difficulty": 0.85, + "question": "14 前面一个数是( ), 后面一个数是( );与 19 相邻的两个数是( )和( )。", + "options": [ + + ], + "answer": "13;15;18;20", + "solution": "【分析】20以内数从前往后顺序为:1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16, 17, 18, 19, 20。相邻数也就是这个数两侧的数,由此找出对应的数即可.\n【详解】14前面一个数是 13,后面一个数是 15;与 19 相邻的两个数是 18 和 20 。", + "knowledge_points": [ + "20以内数的排序" + ], + "source": "24-25 一年级上·甘肃平凉·期末" + }, + { + "id": "430", + "unit": "11~20的认识", + "question_type": "填空题", + "difficulty": 0.85, + "question": "1 个十和 5 个一组成的数是( ),与它相邻的两个数是( )和( )。", + "options": [ + + ], + "answer": "15;14;16", + "solution": "【分析】几个十就是几十,几个一就是几,十位上是几就是几十,个位上是几就是几。一个两位数,从右往左数,第一位是个位,第二位是十位,据此写数。20 以内的数从小到大排序是: 1 \u003c 2 \u003c 3 \u003c 4 \u003c 5 \u003c 6 \u003c 7 \u003c 8 \u003c 9\u003c 10 \u003c 11 \u003c 12 \u003c 13 \u003c 14 \u003c 15 \u003c 16 \u003c 17 \u003c 18 \u003c 19 \u003c 20,据此填空.\n【详解】1 个十和 5 个一组成的数是 15,与它相邻的两个数是 14 和 16 。", + "knowledge_points": [ + "20以内数的组成", + "20以内数的排序" + ], + "source": "24-25 一年级上·广东汕头·期末" + }, + { + "id": "431", + "unit": "11~20的认识", + "question_type": "填空题", + "difficulty": 0.85, + "question": "在6,5,18,0,3,20这些数中,最大的数是( ),最小的数是( )。", + "options": [ + + ], + "answer": "20;0", + "solution": "【分析】20 以内的数从小到大排列是: 1 \u003c 2 \u003c 3 \u003c 4 \u003c 5 \u003c 6 \u003c 7 \u003c 8 \u003c 9 \u003c 10 \u003c 11 \u003c 12 \u003c 13 \u003c 14 \u003c 15 \u003c 16 \u003c 17 \u003c 18 \u003c 19 \u003c 20,据此比较.\n【详解】 20 \u003e 18 \u003e 6 \u003e 5 \u003e 3 \u003e 0在 6,5,18,0,3,20 这些数中,最大的数是 20,最小的数是 0 。", + "knowledge_points": [ + "20以内数的比大小" + ], + "source": "24-25 一年级上·广东江门·期末" + }, + { + "id": "432", + "unit": "11~20的认识", + "question_type": "填空题", + "difficulty": 0.85, + "question": "和 11 相邻的两个数是( )和( ), 17 后面的一个数是( )。", + "options": [ + + ], + "answer": "10;12;18", + "solution": "【分析】20 以内的数从小到大排列是: 1 \u003c 2 \u003c 3 \u003c 4 \u003c 5 \u003c 6 \u003c 7 \u003c 8 \u003c 9 \u003c 10 \u003c 11 \u003c 12 \u003c 13 \u003c 14 \u003c 15 \u003c 16 \u003c 17 \u003c 18 \u003c 19 \u003c 20,据此填空.\n【详解】和 11 相邻的两个数是 10 和 12, 17 后面的一个数是 18。", + "knowledge_points": [ + "20以内数的排序" + ], + "source": "24-25 一年级上·广东江门·期末" + }, + { + "id": "433", + "unit": "11~20的认识", + "question_type": "填空题", + "difficulty": 0.85, + "question": "18 里面有( )个十和( )个一;3 个一和 1 个十组成的数是( )。", + "options": [ + + ], + "answer": "1;8;13", + "solution": "【分析】一个两位数,从右往左数,第一位是个位,个位上的数表示几个一;第二位是十位,十位上的数表示几个十。几个十就是几十,几个一就是几,据此解答.\n【详解】18 里面有 1 个十和 8 个一;3 个一和 1 个十组成的数是 13。", + "knowledge_points": [ + "20以内数的组成" + ], + "source": "24-25 一年级上·广东江门·期末" + }, + { + "id": "434", + "unit": "11~20的认识", + "question_type": "填空题", + "difficulty": 0.85, + "question": "16 里面的 \"6\" 表示 6 个( )。20 里的 \"2\" 表示 2 个( ),一个一个地数,20 前面的一个数是( )。", + "options": [ + + ], + "answer": "一;十;19", + "solution": "【分析】一个两位数,从右往左数,第一位是个位,个位上的数表示几个一;第二位是十位,十位上的数表示几个十。一个数前面第一个数比它小 1,后面第一个数比它大 1.20以内的数从小到大排列是: 1 \u003c 2 \u003c 3 \u003c 4 \u003c 5 \u003c 6 \u003c 7 \u003c 8 \u003c 9 \u003c10 \u003c 11 \u003c 12 \u003c 13 \u003c 14 \u003c 15 \u003c 16 \u003c 17 \u003c 18 \u003c 19 \u003c 20,据此填空.\n【详解】16 里面的 \"6\"表示 6 个一。20 里的 \"2\"表示 2 个十,一个一个地数,20前面的一个数是 19 。", + "knowledge_points": [ + "20以内数的组成", + "20以内数的排序" + ], + "source": "24-25 一年级上·山东济南·期末" + }, + { + "id": "435", + "unit": "11~20的认识", + "question_type": "填空题", + "difficulty": 0.65, + "question": "比 12 大又比 14 小的数是( )。比10多1的数是( )。", + "options": [ + + ], + "answer": "13;11", + "solution": "【分析】(1)根据数数 10, 11, 12, 13, 14 可知,比 12大又比 14 小的数是 13;(2) 要求比 10 多 1 的数,即从 10 往后数一个数,即是11.\n【详解】比 12 大又比 14 小的数是 13。比 10 多 1 的数是 11。", + "knowledge_points": [ + "20以内数的比大小", + "20以内数的排序" + ], + "source": "24-25 一年级上·山东济南·期末" + }, + { + "id": "436", + "unit": "11~20的认识", + "question_type": "填空题", + "difficulty": 0.85, + "question": "比 16 大 1 的数是( ), 比 16 小 1 的数是( )。", + "options": [ + + ], + "answer": "17;15", + "solution": "【分析】求比一个数大几的数是多少,用这个数十大的数计算;求比一个数小几的数是多少,用这个数一小的数计算.\n【详解】16 + 1 = 17;16 - 1 = 15比16大1的数是17,比16小1的数是 15。", + "knowledge_points": [ + "不进位加法(20以内)", + "不退位减法(20以内)" + ], + "source": "24-25 一年级上·甘肃嘉峪关·期末" + }, + { + "id": "437", + "unit": "11~20的认识", + "question_type": "填空题", + "difficulty": 0.85, + "question": "20 里面有( )个十。", + "options": [ + + ], + "answer": "2", + "solution": "【分析】几十里面就有几个十;据此解决即可.\n【详解】由题意分析得:20里面有2个十。", + "knowledge_points": [ + "20以内数的组成" + ], + "source": "24-25 一年级上·河北·课后作业" + }, + { + "id": "438", + "unit": "11~20的认识", + "question_type": "填空题", + "difficulty": 0.65, + "question": "个位上和十位上的数都是 1,这个数是( )。", + "options": [ + + ], + "answer": "11", + "solution": "【分析】个位上是 1,表示 1 个一。十位上也是 1,表示 1 个十。1 个十和 1 个一合起来就是 11 .\n【详解】根据分析:个位上和十位上的数都是 1,这个数是 11。", + "knowledge_points": [ + "20以内数的组成" + ], + "source": "19-20 一年级上·辽宁·单元测试" + }, + { + "id": "439", + "unit": "11~20的认识", + "question_type": "填空题", + "difficulty": 0.85, + "question": "比 13 大 2 的数是( ), 比 16 小 5 的数是( )。", + "options": [ + + ], + "answer": "15;11", + "solution": "【分析】求比一个数大多少的数用加法计算。求比一个数小多少的数用减法计算.\n【详解】13 + 2 = 15;16 - 5 = 11,比 13 大 2 的数是 15,比 16 小 5 的数是 11。", + "knowledge_points": [ + "不进位加法(20以内)", + "不退位减法(20以内)" + ], + "source": "24-25 一年级上·山东济南·期末" + }, + { + "id": "440", + "unit": "11~20的认识", + "question_type": "填空题", + "difficulty": 0.85, + "question": "16 - 6 = ( )。这里被减数是( ),减数是( ),差是( )。", + "options": [ + + ], + "answer": "10;16;6;10", + "solution": "【分析】计算可知,结果是 10。减法算式为被减数 - 减数=差,被减数数是减号前面的,减数是减号后面的,差是等号后面的,由此解答.\n【详解】16 - 6 = 10 。这里被减数是 16,减数是 6,差是 10。", + "knowledge_points": [ + "不退位减法(20以内)" + ], + "source": "24-25 一年级上·山东济南·期末" + }, + { + "id": "441", + "unit": "11~20的认识", + "question_type": "填空题", + "difficulty": 0.85, + "question": "15 和 18 之间的数是( )和( )。", + "options": [ + + ], + "answer": "16;17", + "solution": "【分析】一个一个地数一数,即可知道 15 和 18 之间的两个数分别是多少.\n【详解】由题意分析得:15, 16, 17, 18;即,15和18之间的数是16和17。", + "knowledge_points": [ + "20以内数的排序" + ], + "source": "24-25 一年级上·黑龙江齐齐哈尔·期末" + }, + { + "id": "442", + "unit": "11~20的认识", + "question_type": "填空题", + "difficulty": 0.85, + "question": "19 是由( )个十和( )个一组成的,与它相邻的两个数分别是( )和( )。", + "options": [ + + ], + "answer": "1;9;18;20", + "solution": "【分析】一个两位数,从右往左数,第一位是个位,表示几个一,第二位是十位,表示几个十;相邻的两个数,前一个数比后一个数少 1,后一个数比前一个多 1,即,与 19 相邻的前一个数是 18,后一个数是 20;据此解决.\n【详解】由题意分析得:19 是由 1 个十和 9 个一组成的,与它相邻的两个数分别是 18 和 20。", + "knowledge_points": [ + "20以内数的组成", + "20以内数的排序" + ], + "source": "24-25 一年级上·黑龙江齐齐哈尔·期末" + }, + { + "id": "443", + "unit": "11~20的认识", + "question_type": "填空题", + "difficulty": 0.85, + "question": "18 里面有( )个十和( )个一。比 19 大 1 的数是( )。", + "options": [ + + ], + "answer": "1;8;20", + "solution": "【分析】一个两位数,从右往左数,第一位是个位,个位上的数表示几个一;第二位是十位,十位上的数表示几个十。一个数前面第一个数比它小 1,后面第一个数比它大 1.20 以内的数从小到大排列是: 1 \u003c 2 \u003c 3 \u003c 4 \u003c 5 \u003c 6 \u003c 7 \u003c 8 \u003c 9 \u003c 10 \u003c 11 \u003c 12 \u003c 13 \u003c 14 \u003c 15 \u003c 16 \u003c 17 \u003c 18 \u003c 19 \u003c 20 .\n【详解】18里面有1个十和8个一。比19大1的数是20。", + "knowledge_points": [ + "20以内数的组成", + "20以内数的排序" + ], + "source": "24-25 一年级上·青海西宁·期末" + }, + { + "id": "444", + "unit": "11~20的认识", + "question_type": "填空题", + "difficulty": 0.65, + "question": "一个加数是 12,另一个加数是 5,和是( )。", + "options": [ + + ], + "answer": "17", + "solution": "【分析】根据加数 + 加数 = 和,两数相加即可求出和是多少,据此解答.\n【详解】12 + 5 = 17一个加数是 12,另一个加数是 5,和是 17 。", + "knowledge_points": [ + "不进位加法(20以内)" + ], + "source": "24-25 一年级上·吉林·期末" + }, + { + "id": "445", + "unit": "11~20的认识", + "question_type": "填空题", + "difficulty": 0.65, + "question": "小明读一本书,今天从第 6 页读到第 10 页,他今天读了( )页,明天应该从第( )页继续读。", + "options": [ + + ], + "answer": "5;11", + "solution": "【分析】小明读一本书,今天从第 6 页读到第 10 页,用 10 减去 6,多减了 1 页 (第 6 页), 再加上 1 即可求出一共读的页数。明天应该从今天读的最后一页的下一页读起,据此解答.\n【详解】 10 - 6 + 1 = 5 (页);10 + 1 = 11 (页)小明读一本书,今天从第 6 页读到第 10 页,他今天读了 5 页,明天应该从第 11 页继续读。", + "knowledge_points": [ + "加减混合运算(10以内)", + "不进位加法(20以内)" + ], + "source": "24-25 一年级上·吉林·期末" + }, + { + "id": "446", + "unit": "11~20的认识", + "question_type": "填空题", + "difficulty": 0.65, + "question": "18 和 13 这两个数, ( ) 更接近 10 , ( ) 更接近 19 。", + "options": [ + + ], + "answer": "13;18", + "solution": "【分析】根据10到20从小到大排序:10,11,12,13,14,15,16,17,18,19,20;所以,13 更接近 10, 18 更接近 19.\n【详解】由分析可知,18 和 13 这两个数,13 更接近10, 18 更接近 19。", + "knowledge_points": [ + "20以内数的排序" + ], + "source": "24-25 一年级上·安徽芜湖·期末" + }, + { + "id": "447", + "unit": "11~20的认识", + "question_type": "填空题", + "difficulty": 0.85, + "question": "计数器从右边起,第一位是( )位,第二位是( )位;在计数器上用5个珠子表示小于19的数,这个数可能是( ),也可能是( )。", + "options": [ + + ], + "answer": "个;十;5;14", + "solution": "【分析】计数器从右边起第一位是个位,第二位是十位。要求在计数器上用 5 个珠子表示小于 19 的数,即 5 个珠子都在个位上,或 1 个珠子在十位上,其余 4 个珠子在个位上,据此解答即可.\n【详解】计数器从右边起,第一位是个位,第二位是十位;在计数器上用 5 个珠子表示小于 19 的数,这个数可能是 5,也可能是 14。", + "knowledge_points": [ + "20以内数的组成" + ], + "source": "24-25 一年级上·安徽芜湖·期末" + }, + { + "id": "448", + "unit": "11~20的认识", + "question_type": "填空题", + "difficulty": 0.85, + "question": "1 个十和 9 个一合起来是( ),2 个十是( )。", + "options": [ + + ], + "answer": "19;20", + "solution": "【分析】几个十就是几十,几个一就是几。1个十是10,9个一是9,合起来是19;2个十就是20.\n【详解】1个十和9个一合起来是19,2个十是 20。", + "knowledge_points": [ + "20以内数的组成", + "11~20 的认识和读写" + ], + "source": "24-25 一年级上·河北唐山·期末" + }, + { + "id": "449", + "unit": "11~20的认识", + "question_type": "填空题", + "difficulty": 0.85, + "question": "一个两位数的个位上是 2,十位上是 1,这个两位数是( )。", + "options": [ + + ], + "answer": "12", + "solution": "【分析】这个两位数十位上是 1,就在十位上写 1,个位上是 2,就在个位上写 2 , 1 个十和 2 个一,合起来的数是 12,据此解答.\n【详解】根据分析可得:一个两位数的个位上是 2,十位上是 1,这个两位数是12。", + "knowledge_points": [ + "20以内数的组成", + "11~20 的认识和读写" + ], + "source": "24-25 一年级上·黑龙江齐齐哈尔·期末" + }, + { + "id": "450", + "unit": "11~20的认识", + "question_type": "填空题", + "difficulty": 0.85, + "question": "14 里面有( )个十和( )个一;17里面有( )个一和( )个十;( )个十是20。", + "options": [ + + ], + "answer": "1;4;7;1;2", + "solution": "【分析】一个两位数,从右往左数,第一位是个位,表示几个一;第二位是十位,表示几个十;几十里面就有几个十;据此解决.\n【详解】由题意分析得:14里面有1个十和4个一;17里面有7个一和1个十;2个十是 20 。", + "knowledge_points": [ + "20以内数的组成" + ], + "source": "2024 一年级上·全国·专题练习" + }, + { + "id": "451", + "unit": "11~20的认识", + "question_type": "填空题", + "difficulty": 0.85, + "question": "2 个十是( );1 个十和 6 个一合起来是( )。", + "options": [ + + ], + "answer": "20;16", + "solution": "【分析】一个两位数,从右往左依次为个位,十位。有几个十就在十位写几,有几个一就在个位写几,由此解答.\n【详解】2个十是20;1个十和6个一合起来是 16。", + "knowledge_points": [ + "20以内数的组成" + ], + "source": "24-25 一年级上·全国·课后作业" + }, + { + "id": "452", + "unit": "11~20的认识", + "question_type": "填空题", + "difficulty": 0.85, + "question": "13 里面有( )个一和( )个十;由 1 个十和 6 个一组成的数是( )。", + "options": [ + + ], + "answer": "3;1;16", + "solution": "【分析】一个两位数,从右往左数,第一位是个位,表示几个一;第二位是十位,表示几个十;几个十就是几十,几个一就是几,据此组数.\n【详解】由题意分析得:13里面有3个一和1个十;由1个十和6个一组成的数是16。", + "knowledge_points": [ + "20以内数的组成" + ], + "source": "24-25 一年级上·全国·期末" + }, + { + "id": "453", + "unit": "11~20的认识", + "question_type": "填空题", + "difficulty": 0.85, + "question": "比 17 小 5 的数是( );比 13 大,比 19 小的数有( )个。", + "options": [ + + ], + "answer": "12;5", + "solution": "【分析】根据减法的概念,求比一个数小几的数用减法计算;根据数的大小关系,数出比 13 大且比 19 小的数的个数.\n【详解】 17 - 5 = 12;比13大,比19小的数有:14,15,16,17,18共5个。", + "knowledge_points": [ + "20 以内数的比大小", + "不退位减法(20 以内)" + ], + "source": "24-25 一年级上·全国·期末" + }, + { + "id": "454", + "unit": "11~20的认识", + "question_type": "填空题", + "difficulty": 0.85, + "question": "和 10 相邻的数是( )和( );19 后面的一个数是( )。", + "options": [ + + ], + "answer": "9;11;20", + "solution": "【分析】一个一个地数一数,即可找出和 10 相邻的数及 19 后面的一个数;据此解决.\n【详解】由题意分析得:9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20;故,和 10 相邻的数是 9 和 11;19 后面的一个数是 20。", + "knowledge_points": [ + "20以内数的排序" + ], + "source": "2024一年级上·全国·专题练习" + }, + { + "id": "455", + "unit": "11~20的认识", + "question_type": "填空题", + "difficulty": 0.85, + "question": "一本《数学文化》,小丽从第10页读到第15页,她一共读了( )页。", + "options": [ + + ], + "answer": "6", + "solution": "【分析】从 10 开始,一个一个地数,一直数到 15,数了几个数,就表示一共读了多少页;据此解决.\n【详解】由题意分析得:10,11,12,14,14,15,一共数了 6 个数;即,一本《数学文化》, 小丽从第 10 页读到第 15 页,她一共读了 6 页。", + "knowledge_points": [ + "数一数" + ], + "source": "2024一年级上·全国·专题练习" + }, + { + "id": "456", + "unit": "11~20的认识", + "question_type": "填空题", + "difficulty": 0.85, + "question": "11 十位上的 \"1\"表示( )个( ),个位上的 \"1\"表示( )个( )。", + "options": [ + + ], + "answer": "1;十;1;一", + "solution": "【分析】从右边起第一位是个位,个位上是几,就表示几个一,第二位是十位,十位上是几,就表示几个十,据此解答即可.\n【详解】11 十位上的 \"1\"表示 1 个十,个位上的 \"1\"表示 1 个一。", + "knowledge_points": [ + "20以内数的组成" + ], + "source": "2024一年级上·全国·专题练习" + }, + { + "id": "457", + "unit": "11~20的认识", + "question_type": "填空题", + "difficulty": 0.85, + "question": "一个数的个位上是 8,十位上是 1,这个数是( )。", + "options": [ + + ], + "answer": "18", + "solution": "【分析】一个两位数,从右往左数,第一位是个位,第二位是十位;据此解决.\n【详解】由题意分析得:一个数的个位上是 8,十位上是 1,这个数是 18 。", + "knowledge_points": [ + "20以内数的组成" + ], + "source": "24-25 一年级上·全国·期末" + }, + { + "id": "458", + "unit": "11~20的认识", + "question_type": "填空题", + "difficulty": 0.85, + "question": "由4个一和1个十组成的数是( );2个十是( )。", + "options": [ + + ], + "answer": "14;20", + "solution": "【分析】一个两位数右边的数位是个位,个位是几表示几个一,左边的数位是十位,十位是几表示几个十,据此写数即可.\n【详解】根据分析知:由 4 个一和 1 个十组成的数是 14;2 个十是 20。", + "knowledge_points": [ + "20以内数的组成" + ], + "source": "2024 一年级上·全国·专题练习" + }, + { + "id": "459", + "unit": "11~20的认识", + "question_type": "填空题", + "difficulty": 0.85, + "question": "一本故事书,今天我读完1到18页,明天我该从第( )页开始读。", + "options": [ + + ], + "answer": "19", + "solution": "【分析】明天读的页码是今天读的页码的下一页,即 18 + 1,即可得出答案.\n【详解】18 + 1 = 19 (页)所以明天我该从第 19 页开始读。", + "knowledge_points": [ + "不进位加法(20以内)" + ], + "source": "2024一年级上·全国·专题练习" + }, + { + "id": "460", + "unit": "11~20的认识", + "question_type": "填空题", + "difficulty": 0.85, + "question": "18 和 20 中间的数是( ), 20 的前一个数是( )。", + "options": [ + + ], + "answer": "19;19", + "solution": "【分析】根据20以内整数的排序,结合题干要求进行解答即可.\n【详解】18,19,20,所以18和20中间的数是19,20的前一个数是19。", + "knowledge_points": [ + "20以内数的排序" + ], + "source": "2024 一年级上·全国·专题练习" + }, + { + "id": "461", + "unit": "11~20的认识", + "question_type": "填空题", + "difficulty": 0.85, + "question": "被减数是 17,减数是 10,算式是( ), 差是( )。", + "options": [ + + ], + "answer": "17 - 10 = 7;7", + "solution": "【分析】减法算式为:被减数 - 减数 = 差,由此代入计算即可.\n【详解】被减数是 17,减数是 10,算式是 17 - 10 = 7,差是 7 。", + "knowledge_points": [ + "不退位减法 (20 以内)" + ], + "source": "24-25 一年级上·全国·课后作业" + }, + { + "id": "462", + "unit": "11~20的认识", + "question_type": "填空题", + "difficulty": 0.85, + "question": "17 - 5 = ( ), 被减数是( ), 减数是( )。", + "options": [ + + ], + "answer": "12;17;5", + "solution": "【分析】根据被减数 - 减数 = 差,结合题干要求进行解答即可.\n【详解】17 - 5 = 12,被减数是17,减数是5。", + "knowledge_points": [ + "不退位减法 (20以内)" + ], + "source": "24-25 一年级上·全国·期末" + }, + { + "id": "463", + "unit": "11~20的认识", + "question_type": "填空题", + "difficulty": 0.85, + "question": "20里面有( )个十,20的个位上是( ),十位上是( )。", + "options": [ + + ], + "answer": "2;0;2", + "solution": "【分析】一个整十数,十位上是几就表示含有几个十;一个两位数,从右往左数,第一位是个位,表示几个一,第二位是十位,表示几个十;据此解决.\n【详解】由题意分析得:20里面有2个十,20的个位上是0,十位上是2。", + "knowledge_points": [ + "20以内数的组成" + ], + "source": "2024一年级上·全国·专题练习" + }, + { + "id": "464", + "unit": "11~20的认识", + "question_type": "填空题", + "difficulty": 0.85, + "question": "16 里面有( )个十和( )个一;由 1 个十和 8 个一组成的数是( ), 读作( )。", + "options": [ + + ], + "answer": "1;6;18;十八", + "solution": "【分析】一个两位数,从右往左数,第一位是个位,表示几个一,第二位是十位,表示几个十;几个一就是几,几个十就是几十,据此组数;读一个两位数时,先读十位上的数,读作几十,再读个位数的数,读作几.\n【详解】由题意分析得:16里面有1个十和6个一;由1个十和8个一组成的数是 \n18,读作:十八。", + "knowledge_points": [ + "20以内数的组成", + "11~20 的认识和读写" + ], + "source": "2024 一年级上·全国·专题练习" + }, + { + "id": "465", + "unit": "11~20的认识", + "question_type": "填空题", + "difficulty": 0.85, + "question": "一个两位数,个位上是4,十位上是1,这个数是( ),读作( )。", + "options": [ + + ], + "answer": "14;十四", + "solution": "【分析】一个两位数,从右往左数,第一位是个位,第二位是十位,据此组数;读一个两位数,先读十位上的数,读作几十,再读个位数的数,读作几;据此解决.\n【详解】由题意分析得:一个两位数,个位上是 4,十位上是 1,这个数是 14,读作:十四。", + "knowledge_points": [ + "20 以内数的组成", + "11~20的认识和读写" + ], + "source": "24-25 一年级上·全国·期末" + }, + { + "id": "466", + "unit": "11~20的认识", + "question_type": "填空题", + "difficulty": 0.85, + "question": "17 的个位上是( ),十位上是( )。", + "options": [ + + ], + "answer": "7;1", + "solution": "【分析】一个两位数,从右往左数,第一位是个位,第二位是十位;据此解决.\n【详解】由题意分析得:17 的个位上是 7,十位上是 1 。", + "knowledge_points": [ + "20以内数的组成" + ], + "source": "2024 一年级上·全国·专题练习" + }, + { + "id": "467", + "unit": "11~20的认识", + "question_type": "填空题", + "difficulty": 0.85, + "question": "18 比 10 多( ),比 12 大 5 的数是( ), 12 添上 3 是( )。", + "options": [ + + ], + "answer": "8;17;15", + "solution": "【分析】求一个数比另一个数多几,用这个数一另一个数计算;求比一个数大几的数是多少,用这个数十大的数计算;求一个数添上几是多少,用这个数十添的数计算.\n【详解】18 - 10 = 8;12 + 5 = 17;12 + 3 = 15.18 比 10 多 8,比 12 大 5 的数是 17 , 12 添上 3 是 15 。", + "knowledge_points": [ + "不进位加法(20以内)", + "不退位减法(20以内)" + ], + "source": "24-25 一年级上·河南信阳·期中" + }, + { + "id": "468", + "unit": "11~20的认识", + "question_type": "填空题", + "difficulty": 0.85, + "question": "从15数到19一共数了( )个数。", + "options": [ + + ], + "answer": "5", + "solution": "【分析】从 15 数到 19 数了 15, 16, 17, 18, 19,共 5 个数,据此得出结论即可.\n【详解】根据分析知:从 15 数到 19 一共数了 5 个数。", + "knowledge_points": [ + "20以内数的排序" + ], + "source": "2024一年级上·全国·专题练习" + }, + { + "id": "469", + "unit": "11~20的认识", + "question_type": "填空题", + "difficulty": 0.85, + "question": "14前面的第一个数是( ),18后面的第一个数是( )。", + "options": [ + + ], + "answer": "13;19", + "solution": "【分析】据题意,将 10 到 20 之间的数字的按照顺序数一数 10,11,12,13,14,15,16,17,18,19,20,然后找一找 14 前面和 18 后面的第一个数即可得出答案.\n【详解】14前面的第一个数是(13),18后面的第一个数是(19).\n[点睛]考查学生20以内数的认识和排序。", + "knowledge_points": [ + "11~20的认识和读写", + "20以内数的排序" + ], + "source": "2024一年级上·全国·专题练习" + }, + { + "id": "470", + "unit": "11~20的认识", + "question_type": "填空题", + "difficulty": 0.65, + "question": "5 个一和 1 个十组成的数是( ),与它相邻的两个数是( )和( )。", + "options": [ + + ], + "answer": "15;14;16", + "solution": "【分析】5 个一表示 5 , 1 个十表示 10,先表示出这个数,再确定与它相邻的两个数,相邻的前一位是这个数减 1,相邻的后一位是这个数加 1,据此解答.\n【详解】由分析可得:5个一和1个十组成的数是 15.15 - 1 = 14;15 + 1 = 16,与它相邻的两个数是 14 和 16.5 个一和 1 个十组成的数是 15,与它相邻的两个数是 14 和 16。", + "knowledge_points": [ + "20以内数的组成", + "20以内数的排序" + ], + "source": "16-17 一年级·四川·课后作业" + }, + { + "id": "471", + "unit": "11~20的认识", + "question_type": "填空题", + "difficulty": 0.85, + "question": "在括号里填上合适的数。7 + ( ) = 18;17 - ( ) = 12;( ) + 3 = 14;( ) - 9 = 10", + "options": [ + + ], + "answer": "11;5;11;19", + "solution": "【分析】根据\"加数 = 和 - 另一个加数,减数 = 被减数 - 差,被减数 = 差 + 减数\"及整数加减法的计算法则来解决此题.\n【详解】18 - 7 = 11,故,7 + 11 = 18;17 - 12 = 5,故, 17 - 5 = 12;14 - 3 = 11,故, 11 + 3 = 14;10 + 9 = 19,故, 19 - 9 = 10 。", + "knowledge_points": [ + "不进位加法(20以内)", + "不退位减法(20以内)" + ], + "source": "24-25 一年级上·全国·单元测试" + }, + { + "id": "472", + "unit": "11~20的认识", + "question_type": "填空题", + "difficulty": 0.85, + "question": "16 和 19 之间有( )个数。", + "options": [ + + ], + "answer": "2", + "solution": "【分析】从 16 开始,一个一个地数,数到 19,即可知道 16 和 19 之间有几个数.\n【详解】由题意分析得:16, 17, 18, 19;即,16和19之间有2个数。", + "knowledge_points": [ + "数一数", + "20以内数的排序" + ], + "source": "24-25 一年级上·全国·单元测试" + }, + { + "id": "473", + "unit": "11~20的认识", + "question_type": "填空题", + "difficulty": 0.85, + "question": "被减数是 11,减数是10,差是( )。12和( )合起来是18。", + "options": [ + + ], + "answer": "1;6", + "solution": "【分析】根据\"被减数 - 减数 = 差\"及整数加减法的计算法则来解决此题;求 12 和几合起来是 18,就是求 12 加几等于 18,据此即可解答.\n【详解】11 - 10 = 1;12 + 6 = 18,即,被减数是 11,减数是 10,差是 1.12 和 6 合起来是 18。", + "knowledge_points": [ + "不进位加法(20以内)", + "不退位减法(20以内)" + ], + "source": "24-25 一年级上·全国·单元测试" + }, + { + "id": "474", + "unit": "11~20的认识", + "question_type": "填空题", + "difficulty": 0.85, + "question": "18 - 4 = ( ), 被减数是( ), 减数是( ), 差是( )。", + "options": [ + + ], + "answer": "14;18;4;14", + "solution": "【分析】在减法算式中,被减数 - 减数 = 差,因此 18 - 4 = 14 中,被减数是 18,减数是 4,差是 14。据此填空即可.\n【详解】由分析可知:18 - 4 = 14,被减数是 18,减数是 4,差是 14 。", + "knowledge_points": [ + "不退位减法 (20以内)" + ], + "source": "24-25 一年级上·全国·单元测试" + }, + { + "id": "475", + "unit": "11~20的认识", + "question_type": "填空题", + "difficulty": 0.85, + "question": "与13相邻的数中,13前面的数是( ),后面的数是( )。", + "options": [ + + ], + "answer": "12;14", + "solution": "【分析】一个数前面第一个数比它小 1,后面第一个数比它大 1,据此解答.\n【详解】与 13 相邻的数中, 13 前面的数是 12,后面的数是14。", + "knowledge_points": [ + "20以内数的排序" + ], + "source": "24-25 一年级上·全国·单元测试" + }, + { + "id": "476", + "unit": "11~20的认识", + "question_type": "填空题", + "difficulty": 0.85, + "question": "19 的个位上的数是( ), 十位上的数是( ), 19 再添上( )个一就是 20。", + "options": [ + + ], + "answer": "9;1;1", + "solution": "【分析】一个两位数,从右往左数,第一位是个位,第二位是十位。然后从 19 往下数 1 个数就是 20,则再添上 1 个一就是 20.\n【详解】19 的个位上的数是 (9),十位上的数是(1) , 19 再添上 (1) 个一就是 20。", + "knowledge_points": [ + "20以内数的组成" + ], + "source": "24-25 一年级上·全国·单元测试" + }, + { + "id": "477", + "unit": "11~20的认识", + "question_type": "填空题", + "difficulty": 0.85, + "question": "5 个一和 1 个十组成的数是( ),它后面的第一个数是( )。", + "options": [ + + ], + "answer": "15;16", + "solution": "【分析】一个两位数,从右往左数,第一位是个位,第二位是十位。5 个一是 5, 1 个十是 10,合起来是 15。相邻的两个数相差 1,后一个数比前一个数多 1,前一个数比后一个数少 1;据此解决.\n【详解】15 + 1 = 16则 5 个一和 1 个十组成的数是 (15), 它后面的第一个数是 (16) 。", + "knowledge_points": [ + "20以内数的组成", + "不进位加法(20以内)" + ], + "source": "24-25 一年级上·全国·单元测试" + }, + { + "id": "478", + "unit": "11~20的认识", + "question_type": "计算题", + "difficulty": 0.65, + "question": "列算式。 ![](images/3b60698b14098f19bb50d174d760a342b68ed0da097f7ebd77d80ea9b12c4f9e.jpg)", + "options": [ + + ], + "answer": "18 - 10 = 8", + "solution": "【分析】根据题意分析,大括号下面表示总和,一共有 18 个足球,数出左边有 10 个足球,求右边箱子里的数量,用总和减去左边的足球数量即可.\n【详解】18 - 10 = 8(个)右边箱子里有 8 个足球。", + "knowledge_points": [ + "不退位减法(20以内)" + ], + "source": "24-25 一年级上·湖北武汉·期末" + }, + { + "id": "479", + "unit": "11~20的认识", + "question_type": "计算题", + "difficulty": 0.85, + "question": "列算式。 ![](images/721ed38f11e521f48db64d495c8f38884b8ea4860a7b2037298045dcbbf58b91.jpg) □ ○ □ = □(根)", + "options": [ + + ], + "answer": "10 + 3 = 13", + "solution": "【分析】左边萝卜的数量 + 右边萝卜的数量 = 一共有多少根,据此解答.\n【详解】根据分析可得:10 + 3 = 13 (根),一共有 13 根。", + "knowledge_points": [ + "不进位加法(20以内)", + "图文问题" + ], + "source": "24-25 一年级上·湖北武汉·期末" + }, + { + "id": "480", + "unit": "11~20的认识", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式。 ![](images/d2513aeff3b098f61c965ca30185be035467134f0aab69cabf5c34d54088f703.jpg) □ ○ □ = □(个)", + "options": [ + + ], + "answer": "16 - 5 = 11", + "solution": "【分析】从图上可得:一共有 16 个苹果,已知右边有 5 个,要求左边的篮子里面有多少个苹果,根据减法的意义,用 16 - 5 进行解答即可.\n【详解】16 - 5 = 11(个),篮子里有11个苹果。", + "knowledge_points": [ + "不退位减法(20以内)", + "图文问题" + ], + "source": "24-25 一年级上·广西柳州·期末" + }, + { + "id": "481", + "unit": "11~20的认识", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式计算。 ![](images/65bab767264b65580dbac1a60cb0a10e48ff4ecc262bbb4c96d368cfef1f3d06.jpg) □ ○ □ ○ □ = □(只)", + "options": [ + + ], + "answer": "16 - 4 - 2 = 10", + "solution": "【分析】总数量减去第一次飞走的数量,再减去第二次飞走的数量,等于还剩下数量,据此解答.\n【详解】根据分析可得:16 - 4 - 2 = 10(只),还剩下10只。", + "knowledge_points": [ + "不进位,不退位连加,连减(20以内)", + "不退位减法(20以内)", + "图文问题" + ], + "source": "24-25 一年级上·湖南岳阳·期末" + }, + { + "id": "482", + "unit": "11~20的认识", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式。 ![](images/2d373d60c7a634ae2cce268ebd949bd68986f2267303efb28e91bb00ca26d7e9.jpg) □ ○ □ = □(个)", + "options": [ + + ], + "answer": "13 - 3 = 10", + "solution": "【分析】用苹果的总数量减去左边的数量,求出差,就是右边篮子里的苹果数量.\n【详解】由题意分析得:13 - 3 = 10 (个),右边篮子里有 10 个苹果。", + "knowledge_points": [ + "不退位减法(20以内)", + "图文问题" + ], + "source": "24-25 一年级上·内蒙古通辽·期末" + }, + { + "id": "483", + "unit": "11~20的认识", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式计算。 ![](images/59534ad8d24d136ad75e281acf888be53038f9b36bcd432c43fa79c162c4cf76.jpg) □ ○ □ = □(个)", + "options": [ + + ], + "answer": "14 - 4 = 10", + "solution": "【分析】用总数量减去左边的数量,求出差,就是右边盒子里的数量.\n【详解】由题意分析得:14 - 4 = 10 (个)", + "knowledge_points": [ + "不退位减法(20以内)", + "图文问题" + ], + "source": "24-25 一年级上·湖南常德·期末" + }, + { + "id": "484", + "unit": "11~20的认识", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式计算。 ![](images/cdd2e3fea45832e417fbb158d45e0cb863ad6b1a5371fab2e9f309b7fae7f3c7.jpg) □ ○ □ = □(个)", + "options": [ + + ], + "answer": "16 - 5 = 11", + "solution": "【分析】用草莓的总数量减去左边的数量,求出差,就是右边的数量.\n【详解】由题意分析得:16 - 5 = 11 (个)", + "knowledge_points": [ + "不退位减法(20以内)", + "图文问题" + ], + "source": "24-25 一年级上·甘肃天水·期末" + }, + { + "id": "485", + "unit": "11~20的认识", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式并计算。 ![](images/764e34e28033c943aad82e9e50abda31456eb93cc6869ec969119c6117cd956c.jpg) □ ○ □ = □(个)", + "options": [ + + ], + "answer": "19 - 5 = 14", + "solution": "【分析】根据图片可知:一共 19 个,右边有 5 个,求盒子里有多少个。 用共有的数量减去右边的数量即可.\n【详解】19 - 5 = 14 (个,则盒子里有 14 个。", + "knowledge_points": [ + "不退位减法(20以内)" + ], + "source": "24-25一年级上·陕西榆林·期末" + }, + { + "id": "486", + "unit": "11~20的认识", + "question_type": "计算题", + "difficulty": 0.85, + "question": "我会看图列算式。 ![](images/c516bbc90914819ec6dd21e4d81bb71ca50a184e98168f0496b9832576c8ef0d.jpg) □ ○ □ = □(个)", + "options": [ + + ], + "answer": "17 - 5 = 12", + "solution": "【分析】一共有 17 个球,右边有 5 个,求左边盒子里有几个,用减法计算,即总数量 - 右边的数量 = 左边的数量.\n【详解】17 - 5 = 12 (个),左边盒子里有 12 个球。", + "knowledge_points": [ + "不退位减法(20以内)", + "图文问题" + ], + "source": "24-25 一年级上·甘肃平凉·期末" + }, + { + "id": "487", + "unit": "11~20的认识", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式计算。 ![](images/0bebb33a34cd5db655d2670a0aa99fd02f74aae32a4ccf7f9de57c4b3fc6fb7e.jpg) □○ □ ○ □ = □( )", + "options": [ + + ], + "answer": "15 - 3 - 2 = 10 (个)", + "solution": "【分析】用一共的 15 个减去中间的 3 个,再减去右边的 2 个即可求出左边的个数.\n【详解】15 - 3 - 2 = 10(个)", + "knowledge_points": [ + "连减(20以内)", + "图文问题" + ], + "source": "24-25 一年级上·山东济南·期末" + }, + { + "id": "488", + "unit": "11~20的认识", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式计算。 ![](images/e6317c4094e3b2737cdd0f1ba5f0935187f4f1303169350181d304aa24069815.jpg) □ ○ □ = □( )", + "options": [ + + ], + "answer": "18 - 8 = 10(块)", + "solution": "【分析】一共有 18 块饼干,右边有 8 块,求左边盒子里有几块,用减法计算,即总数量 - 右边的数量 = 左边的数量.\n【详解】18 - 8 = 10(块),左边盒子里有 10 块。", + "knowledge_points": [ + "不退位减法(20以内)", + "图文问题" + ], + "source": "24-25 一年级上·山东济南·期末" + }, + { + "id": "489", + "unit": "11~20的认识", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列算式并计算。 ![](images/3b65ea8530099444d01541c2595fee66373728d1f02cebb558e70d3f84a3adf5.jpg) □ ○ □ = □(个)", + "options": [ + + ], + "answer": "3 + 11 = 14", + "solution": "【分析】左边有 3 个苹果,右边筐里有 11 个苹果,求一共有多少个苹果,用加法计算,即左边的数量 + 右边的数量 = 总数量.\n【详解】3 + 11 = 14(个),一共有 14 个苹果。", + "knowledge_points": [ + "不进位加法(20以内)", + "图文问题" + ], + "source": "24-25 一年级上·甘肃陇南·期末" + }, + { + "id": "490", + "unit": "11~20的认识", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式计算。 ![](images/976c6377a3f7ea2d56126aa5a19771e497f319dec81838849b686208ee1f2bd6.jpg) □ ○ □ = □(支)", + "options": [ + + ], + "answer": "18 - 5 = 13", + "solution": "【分析】用总支数减右边的5支即可得出左边多少支.\n【详解】18 - 5 = 13(支)", + "knowledge_points": [ + "不退位减法(20以内)", + "图文问题" + ], + "source": "24-25 一年级上·青海果洛·期末" + }, + { + "id": "491", + "unit": "11~20的认识", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式计算。 ![](images/f451ba546297d1dd3bb0dda1f1801cdcf601d405359bd689b437c7ab45d3627e.jpg) □ ○ □ = □(支)", + "options": [ + + ], + "answer": "5 + 12 = 17", + "solution": "【分析】左边有 5 支笔,右边盒子里有 12 支,求一共有多少支笔,用加法计算,即左边的数量 + 右边的数量 = 总数量.\n【详解】5 + 12 = 17 (支),一共有 17 支笔。", + "knowledge_points": [ + "不进位加法(20以内)", + "图文问题" + ], + "source": "24-25一年级上·青海西宁·期末" + }, + { + "id": "492", + "unit": "11~20的认识", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式并计算。 ![](images/70d4d532e056b8726f424b7eb3831ae8caa21951b8007e4aef7b0a2581843e66.jpg) □ ○ □ = □(个)", + "options": [ + + ], + "answer": "10 + 5 = 15", + "solution": "【分析】把左边的杯子数量与右边的数量加起来,求出和,就是一共的杯子数量.\n【详解】由题意分析得:10 + 5 = 15 (个),一共有 15 个杯子。", + "knowledge_points": [ + "不进位加法(20以内)", + "图文问题" + ], + "source": "24-25 一年级上·吉林·期末" + }, + { + "id": "493", + "unit": "11~20的认识", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式计算。 ![](images/c4d361fa58fad3ca2ba0d4254b44789db38e459a09751863d16c990d65f28196.jpg) □ ○ □ = □(棵)", + "options": [ + + ], + "answer": "16 - 3 = 13", + "solution": "【分析】用白菜的总数量减去左边的数量,求出差,就是右边的数量.\n【详解】由题意分析得:16 - 3 = 13 (棵)", + "knowledge_points": [ + "不退位减法(20以内)", + "图文问题" + ], + "source": "24-25 一年级上·黑龙江齐齐哈尔·期末" + }, + { + "id": "494", + "unit": "11~20的认识", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列算式。 ![](images/239c5084836008dea43494d19b619fd3b6028f6c46e5d80b3246389f1584c6f0.jpg) □ ○ □ = □(个)", + "options": [ + + ], + "answer": "13 - 3 = 10", + "solution": "【分析】一共有 13 个草莓,右边有 3 个,求左边筐里有几个草莓,用减法计算,即总数量 - 右边的数量 = 左边筐里的数量.\n【详解】13 - 3 = 10 (个),左边筐里有 10 个草莓。", + "knowledge_points": [ + "不退位减法(20以内)", + "图文问题" + ], + "source": "24-25 一年级上·河北秦皇岛·期末" + }, + { + "id": "495", + "unit": "11~20的认识", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式计算。 ![](images/93215905a4f872cb485c0b6b09aa2d13332f00f70e2b67a2511f0bc24b78d5f9.jpg) □ ○ □ = □(本)", + "options": [ + + ], + "answer": "17 - 4 = 13", + "solution": "【分析】一共有 17 本书,右边有 4 本,求左边书包里有几本,用减法计算,即总数量 - 右边的数量 = 左边书包里的数量.\n【详解】17 - 4 = 13 (本),左边书包里有 13 本。", + "knowledge_points": [ + "不退位减法(20以内)", + "图文问题" + ], + "source": "24-25 一年级上·全国·单元测试" + }, + { + "id": "496", + "unit": "11~20的认识", + "question_type": "解答题", + "difficulty": 0.85, + "question": "原来一共有14瓶牛奶,还剩多少瓶。 ![](images/a7048e8db65fed797be271c8856430641c67abbad2723c9d882d15e4e0325d77.jpg) □ ○ □ ○ □ = □(瓶)", + "options": [ + + ], + "answer": "14 - 4 - 4 = 6", + "solution": "【分析】用原来的牛奶数量先减去男孩喝了的数量,求出差,再减去女孩喝了的数量,求出差,即可解决.\n【详解】14 - 4 - 4 = 10 - 4 = 6(瓶)\n答:还剩 6 瓶。", + "knowledge_points": [ + "连减 (20 以内)" + ], + "source": "24-25一年级上·山东菏泽·期末" + }, + { + "id": "497", + "unit": "11~20的认识", + "question_type": "解答题", + "difficulty": 0.85, + "question": "同学们在排队,小红的前面有9人,后面有7人,一共有多少人在排队。 □ ○ □ ○ □ = □(人)", + "options": [ + + ], + "answer": "9 + 1 + 7 = 17", + "solution": "【分析】求一共有多少人在排队,用加法计算,即小红前面的人数 + 小红 + 小红后面的人数 = 总人数.\n【详解】9 + 1 + 7 = 17(人)答:一共有 17 人在排队。", + "knowledge_points": [ + "不进位,不退位连加,连减(20以内)" + ], + "source": "24-25一年级上·山东临沂·期末" + }, + { + "id": "498", + "unit": "11~20的认识", + "question_type": "解答题", + "difficulty": 0.65, + "question": "有一群小羊,走了 12 只,还剩 5 只。原来有多少只。 □ ○ □ = □( )", + "options": [ + + ], + "answer": "12 + 5 = 17(只)", + "solution": "【分析】根据题意,用剩下的数量加上走了的数量即可求出原来的数量,用加法列式计算.\n【详解】12 + 5 = 17 (只)答:原来有 17 只。", + "knowledge_points": [ + "不进位加法(20以内)" + ], + "source": "24-25 一年级上·吉林四平·期末" + }, + { + "id": "499", + "unit": "11~20的认识", + "question_type": "解答题", + "difficulty": 0.85, + "question": "树上原来有 16 只小鸟,飞走了 4 只,还剩多少只。", + "options": [ + + ], + "answer": "12 只", + "solution": "【分析】求还剩多少只,用减法计算,即总数量 -飞走的数量 = 还剩的数量.\n【详解】16 - 4 = 12 (只),答:还剩 12 只。", + "knowledge_points": [ + "不退位减法 (20以内)" + ], + "source": "24-25 一年级上·河南信阳·期中" + }, + { + "id": "500", + "unit": "11~20的认识", + "question_type": "解答题", + "difficulty": 0.85, + "question": "有17只小羊在吃草,跑走了5只,还剩下几只小羊在吃草。", + "options": [ + + ], + "answer": "12只", + "solution": "【分析】求还剩下几只,用减法计算,即小羊的总数量 - 跑走的数量 = 还剩的数量.\n【详解】17 - 5 = 12 (只),答:还剩下 12 只小羊在吃草。", + "knowledge_points": [ + "不退位减法 (20以内)" + ], + "source": "24-25一年级上·山东济宁·期中" + } +] \ No newline at end of file diff --git "a/\344\270\200\345\271\264\347\272\247\351\242\230\351\233\206/\344\270\200\345\271\264\347\272\247\344\270\213/images/001cdd8b68650716e0b93fd293a43d37f4727077a4d16564d92db0d34443b979.jpg" "b/\344\270\200\345\271\264\347\272\247\351\242\230\351\233\206/\344\270\200\345\271\264\347\272\247\344\270\213/images/001cdd8b68650716e0b93fd293a43d37f4727077a4d16564d92db0d34443b979.jpg" new file mode 100644 index 0000000000000000000000000000000000000000..28afd6589e2e4a730b835df79cde060cf1de8dfd --- /dev/null +++ "b/\344\270\200\345\271\264\347\272\247\351\242\230\351\233\206/\344\270\200\345\271\264\347\272\247\344\270\213/images/001cdd8b68650716e0b93fd293a43d37f4727077a4d16564d92db0d34443b979.jpg" @@ -0,0 +1,3 @@ +version https://git-lfs.github.com/spec/v1 +oid sha256:9c029f8c5531cefdf1c2370227ad183364f542e9748f938c9a969c710b6bef87 +size 2120 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"选择题", + "difficulty": 0.85, + "question": "用 4 根同样长的小棒不可能拼成一个 ( )。", + "options": [ + "A. 长方形", + "B. 正方形", + "C. 平行四边形" + ], + "answer": "A", + "solution": "【分析】根据长方形,正方形,平行四边形的图形特点即可判断.\n【详解】A。长方形:相对的两条边相等的四边形,但是不相对的两条边不一定相等,若都相等则变成了正方形,不能拼成;B. 正方形:四条边都相等的四边形,可以拼成;C. 平行四边形:可以是相对的两条边相等,也可以是四条边相等的四边形,可以拼成。故答案为: A", + "knowledge_points": [ + "长方形的概念及特点", + "平行四边形的概念及特点", + "正方形的概念及特点" + ], + "source": "24-25 一年级下·河北石家庄·期中" + }, + { + "id": "2", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "折一折,用![](images/312afd1772046f7aee9a93f58b896f39d3bcc01f2a0a790dc946b86d88ab4027.jpg)做一个正方体,'小'的对面是( )。", + "options": [ + "A. 我", + "B. 是", + "C. 好", + "D. 学" + ], + "answer": "A", + "solution": "【分析】根据正方体的展开图'相对不相邻'可知,我和小相对;是和生相对;学和好相对,由此解答.\n【详解】由分析可知:折一折,用该图做一个正方体,'小' 的对面是'我'。故答案为: A", + "knowledge_points": [ + "正方体的展开图" + ], + "source": "24-25 一年级下·湖南怀化·期中" + }, + { + "id": "3", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "下面图形中不是平行四边形的是 ( )。", + "options": [ + "A. ![](images/a853a59730d91ce05c7ebd3c287d862801dae4178f04c9f1b128ae935b14da9f.jpg)", + "B. ![](images/0fc341e956e254f8e6185614c8a6f1d3a6f8f6c3f78a0b0bd012b1e6b95a71e2.jpg)", + "C. ![](images/1809ceba3dc3d92d963680e983c36055a50b0417e601b99e822cc03df8936c0c.jpg)" + ], + "answer": "A", + "solution": "【分析】根据平行四边形的特点,对应的两条边是相等的,根据这一特点再结合选项中给出的图形即可得出答案.\n【详解】A。四边形对应的两条边不相等,所以不是平行四边形;B. 四边形对应的两条边是相等的,所以是平行四边形;C. 四边形对应的两条边是相等的,所以是平行四边形。故答案为: A", + "knowledge_points": [ + "平行四边形的初步认识" + ], + "source": "24-25 二年级上·河南周口·期中" + }, + { + "id": "4", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.65, + "question": "手工课上,小丽从一张长方形纸上剪下了一个三角形(只剪一刀),剩下的纸的形状不可能是( )。", + "options": [ + "A. 三角形", + "B. 五边形", + "C. 正方形" + ], + "answer": "C", + "solution": "【分析】长方形是四个角相等的四边形,长长的方方的;三角形有三条边。五边形有五条边;四条边都相等,四个角都相等的四边形是正方形,方方正正的,据此解答.\n【详解】A。![](images/63f839312171ebc5348613b101117cc3c904f6bbae4fb986d6e94d199fa403b0.jpg)可能是三角形;B。![](images/bcf28300c0e866ae2617e43eccff534f8a9c891176480b065ef96bf768fd2971.jpg)可能是五边形;C. 剪不出正方形。剩下的纸的形状不可能是正方形。故答案为: C", + "knowledge_points": [ + "平面图形的分割", + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "24-25 二年级上·河南郑州·期中" + }, + { + "id": "5", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.65, + "question": "把下边的图形分成三角形,最少能分成 ( ) 个.\n\n![](images/9c9813eaae7e0c97bc32c3e86a4fda0bcbba55773b2ba01a77f6a8bd8f03a567.jpg)", + "options": [ + "A. 2", + "B. 3", + "C. 4" + ], + "answer": "B", + "solution": "【分析】先找出一个顶点,然后把这个顶点与它不相邻的顶点分别连接起来,然后数一数,即可知道最少能分成几个三角形。![](images/3d40c2f574d29245679dc33a062351c24fcb82898885a32ae3d79ba49c8ceb21.jpg)\n【详解】由分析可知,把该图形分成三角形,最少能分成3个。故答案为: B", + "knowledge_points": [ + "平面图形的分割" + ], + "source": "23-24 二年级上·安徽芜湖·期中" + }, + { + "id": "6", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "用一个长方体画出不同的长方形,最多能画出( )个。", + "options": [ + "A. 2", + "B. 3", + "C. 4" + ], + "answer": "B", + "solution": "【分析】据题意可知,题目中是一个长方体,数一数长方体的面有 6 个,但是长方体是相对的面分别相等的图形,所以不同的面一共有 3 对,就可以得出答案.\n【详解】据分析可知,用一个长方体画出不同的长方形,最多能画出 3 个。故答案为: B", + "knowledge_points": [ + "长方体的认识及特征" + ], + "source": "23-24 一年级下·四川乐山·期末" + }, + { + "id": "7", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "折一折,用![](images/2025-12-08%20173940.jpg)做一个正方体,'生'的对面是( )。", + "options": [ + "A. 我", + "B. 是", + "C. 小" + ], + "answer": "B", + "solution": "【分析】根据正方体的展开图'相对不相邻'可知,'我'和'小'相对;'是'和'生'相对;'学'和'好'相对,由此解答.\n【详解】由分析可知,用该图做一个正方体 , '生'的对面'是'。故答案为: B", + "knowledge_points": [ + "正方体的展开图" + ], + "source": "23-24一年级下·江西鹰潭·期末" + }, + { + "id": "8", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.65, + "question": "用等腰直角三角形拼下边的图形,一共需要 ( ) 个才能拼成.\n\n![](images/33cb96a7d0a9d8be6dfef6af5d70e01172751b4ebfded971d7c944a02fdceaa9.jpg)", + "options": [ + "A. 4", + "B. 6", + "C. 8" + ], + "answer": "B", + "solution": "【分析】由图可知,一个 □ 是由 2 个等腰直角三角形拼成的,据此数出图形中正方形和三角形的数量,再求和即可.\n【详解】数出图形中一共有 2 个正方形和 2 个三角形。 2 + 2 + 1 + 1 = 6 (个)所以用等腰直角三角形拼下边的图形,一共需要 6 个才能拼成。故答案为: B", + "knowledge_points": [ + "平面图形的拼接", + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "23-24 一年级下·湖北孝感·期末" + }, + { + "id": "9", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "魔方的每个面都能画出 ( )。", + "options": [ + "A. 正方形", + "B. 长方形", + "C. 圆形" + ], + "answer": "A", + "solution": "【分析】正方形是方方正正的,有 4 条直直的边,每条边都相等;长方形是长长方方的,有 4 条直直的边,对边相等;圆没有直直的边。魔方中有什么样的面就能画出什么图形,由此解答.\n【详解】如图是魔方![](images/4c7cdccc8726c9a35fd84f5307b8e6fc566c69b78830c1274c4ba6a104c715ab.jpg)。魔方是正方体,每个面都是正方形。所以魔方的每个面都能画出正方形。故答案为: A", + "knowledge_points": [ + "立体图形的认识", + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "23-24 一年级下·广东汕头·期末" + }, + { + "id": "10", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "把一个正方形剪成一样的两部分,不能得到的是 ( )。", + "options": [ + "A. ![](images/4f27fb6d5b01683e80711ff096c16184ce35f9affe30fa1d65c00297631537f5.jpg)\n(图a)", + "B. ![](images/7605e4cdadbae68f601e4d1834a363eb70537b510bb877af9777753f45918f34.jpg)\n(图b)", + "C. ![](images/783fde891fb7f3e93764513ff7d41697477ceaa5ccb15d34a0890c988ff2c3d5.jpg)\n(图c)" + ], + "answer": "C", + "solution": "【分析】正方形是方方正正的,有 4 条直直的边,每条边都相等。由此将各选项拼接在一起,看原图形是否是正方形即可.\n【详解】A。 图a,原图形是正方形;B. 图b,原图形是正方形;C。图c,原图形不是正方形。所以把一个正方形剪成一样的两部分,不能得到的是图c。故答案为: C", + "knowledge_points": [ + "平面图形的拼接", + "平面图形的分割", + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "23-24 一年级下·安徽淮南·期末" + }, + { + "id": "11", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.65, + "question": "![](images/d1dc9481eafb838844d9fca3cf6019efd1331a2a33819f13a3604bf4a177d21b.jpg)中有几个三角形,几个正方形。( )", + "options": [ + "A. 8, 3", + "B. 4, 3", + "C. 8, 2" + ], + "answer": "A", + "solution": "【分析】四条边都相等,四个角都相等的四边形是正方形;三角形是由同一平面内不在同一直线上的三条线段'首尾'顺次连接所组成的封闭图形.\n【详解】该图中有8个三角形,3个正方形。故答案为: A", + "knowledge_points": [ + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "23-24 一年级下·安徽淮南·期末" + }, + { + "id": "12", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "用下面的图形不能画出 '○' 的是 ( )。", + "options": [ + "A. 圆锥", + "B. 长方体", + "C. 圆柱体" + ], + "answer": "B", + "solution": "【分析】利用有圆形的一面才能画出'○',观察三个图的表面即可解答.\n【详解】A。圆锥利用下面的面可以画出'○';B。长方体表面都是四四方方的面,不能画出'○';C。圆柱体 利用左右两边的面可以画出'○'。不能画出'○'的是长方体。故答案为: B", + "knowledge_points": [ + "立体图形的认识", + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "23-24 一年级下·湖南岳阳·期末" + }, + { + "id": "13", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "圆柱体下面的面是( )图形。", + "options": [ + "A. ![](images/c4741c2052e518b4b16133b45c95b8c76b3fa1233e05234c5723c3a325148058.jpg)\n(图a)", + "B. ![](images/58f733581e98f9030b977df1596bfe5ed13a2b816df94a163c52b220ee65618b.jpg)\n(图b)", + "C. ![](images/5a1cbc50d03c54d4d1ca65e3bea6de293729233dace848f512e186428806d68c.jpg)\n(图c)" + ], + "answer": "B", + "solution": "【分析】圆柱上下是平平的面且上下一样粗。圆柱的上下面是和太阳相同的形状,没有直直的边,由此解答.\n【详解】A. 图a,是长长方方的,有 4 条直直的边,对边相等,是长方形,不符合题意;B. 图b,没有直直的边,和太阳的形状相同,符合题意;C. 图c,是方方正正的,有 4 条直直的边,每条边都相等,是正方形,不符合题意;所以下面的面是圆形。故答案为: B", + "knowledge_points": [ + "立体图形的认识", + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "23-24 一年级下·湖北恩施·期末" + }, + { + "id": "14", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "折一折,用![](images/40a9da1957b8646c42a9049eb00778fae42ca99998c7c3e3577d81236aabf8b5.jpg)做一个正方体,'3'的对面是( )。", + "options": [ + "A. 1", + "B. 2", + "C. 4" + ], + "answer": "C", + "solution": "【分析】根据正方体的展开图'相对不相邻'可知,1和2相对;4和3相对;6和5相对,由此解答.\n【详解】由分析可知,用该图做一个正方体,'3'的对面是4。故答案为: C", + "knowledge_points": [ + "正方体的展开图" + ], + "source": "23-24 一年级下·山西长治·期末" + }, + { + "id": "15", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.65, + "question": "折一折,用![](images/8150c037dc1b753fb87d486bcafbe42e07b861187e4869c0a20427e6f55c96d4.jpg)做一个正方体, 4 的对面是 ( )。", + "options": [ + "A. 3", + "B. 5", + "C. 6" + ], + "answer": "A", + "solution": "【分析】正方体展开图相对面的找法:同一层间隔一面是相对面, 4 和 3 中间隔着 2,故, 4 和 3 是相对面;据此解决.\n【详解】由题意分析得:折一折,用该图做一个正方体 , 4 的对面是 (3)。故答案为: A", + "knowledge_points": [ + "正方体的展开图" + ], + "source": "23-24 一年级下·湖北武汉·期末" + }, + { + "id": "16", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "用两个同样的![](images/2025-12-08%20181550.jpg),不可能拼成( )。", + "options": [ + "A. 长方形", + "B. 平行四边形", + "C. 正方形" + ], + "answer": "C", + "solution": "【分析】图片中的三角形是直角三角形,用两个三角形进行其它图形的拼摆,根据对图形的认识,长方形沿着中间的折叠,可以形成两个三角形,平行四边形沿着中间进行折叠,也可以形成两个三角形,而正方形的四条边都相等,沿着中间进行折叠,会形成两个边相等的三角形,图片给出的三角形没有两条边相等的,可以推断出答案;或者用剪刀剪两个三角形拼一拼也可得出答案。考查学生对于图形的认识和拼接.\n【详解】考查学生对于图形的认识和拼接。A。长方形沿着中间折叠可以变成两个如图所示的三角形;B. 平行四边形沿着中间折叠可以变成两个如图所示的三角形;C. 正方形四条边相等,所以沿着中间折叠变成两条边相等的三角形,不能变成如图所示的三角形。故答案为: C", + "knowledge_points": [ + "平面图形的拼接", + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "23-24一年级下·河南南阳·期末" + }, + { + "id": "17", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "将一张正方形纸对折后剪开,不能剪成两个 ( )。", + "options": [ + "A. 长方形", + "B. 三角形", + "C. 圆" + ], + "answer": "C", + "solution": "【分析】正方形是方方正正的,有 4 条直直的边,每条边都相等;长方形是长长方方的,有 4 条直直的边,对边相等;三角形有 3 条直直的边;圆没有直直的边。由此作图选择即可.\n【详解】A。![](images/7e86b7b49c6e4cdc2a552ea23abef1cb17c29050476e22384e5b18c1f2d7dfb7.jpg)可以剪成两个长方形;B。![](images/1e39c73bc080f55c1bb51e844b9d07eb39b4df7fd5130455aa33b72328e34044.jpg)可以剪成两个三角形;C. 不能剪成两个圆。将一张正方形纸对折后剪开,不能剪成两个圆。故答案为: C", + "knowledge_points": [ + "平面图形的分割", + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "23-24 一年级下·山东菏泽·期末" + }, + { + "id": "18", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "相同的两个长方形,一定不能拼成( )。", + "options": [ + "A. 正方形", + "B. 长方形", + "C. 三角形" + ], + "answer": "C", + "solution": "【分析】长方形是长长方方的,有 4 条直直的边,对边相等。正方形是方方正正的,有 4 条直直的边,每条边都相等;三角形有 3 条直直的边。由此作图可得出拼成的图形.\n【详解】A。![](images/23dad41b403efdccbf178ddc3b54cb503c71aa9afb5c4ced9baa00e022c62aea.jpg)可以拼成正方形;B。![](images/00572ab92980e5cb33835d26a9990d2f6b1b3738124a517d35bb50760ce693b0.jpg)可以拼成长方形;C. 不能拼成三角形;相同的两个长方形,一定不能拼成三角形。故答案为: C", + "knowledge_points": [ + "平面图形的拼接", + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "23-24 一年级下·吉林·期末" + }, + { + "id": "19", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.65, + "question": "长方形和平行四边形的共同特征是 ( )。", + "options": [ + "A. 四条边都相等", + "B. 四个角都是直角", + "C. 对边长度相等" + ], + "answer": "C", + "solution": "【分析】长方形:有四条边,对边相等,四个角都是直角;平行四边形:有四条边,对边相等,四个角都不是直角.\n【详解】根据分析可知,长方形和平行四边形的共同特征是对边长度相等。故答案为: C", + "knowledge_points": [ + "长方形的概念及特点", + "平行四边形的概念及特点" + ], + "source": "23-24 二年级下·河北保定·期末" + }, + { + "id": "20", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.65, + "question": "将两个完全一样的三角形拼在一起,不能得到( )。", + "options": [ + "A. 平行四边形", + "B. 长方形", + "C. 圆形" + ], + "answer": "C", + "solution": "【分析】根据题意,将两个完全一样的三角形能拼成的图形列举出来即可;两个完全一样的三角形能拼成一个长方形,如图:![](images/2025-12-08%20182059.jpg);两个完全一样的三角形能拼成一个正方形,如图:![](images/2025-12-08%20182313.jpg);两个完全一样的三角形能拼成一个平行四边形,如图:![](images/2025-12-08%20182350.jpg)两个完全一样的三角形能拼成一个三角形,如图:![](images/230b45298d67e5f96264b69650a9646a72a903614f30dc3e6c04518545dfe05d.jpg)\n【详解】根据分析可知,两个完全一样的三角形能拼成平行四边形,正方形,长方形,三角形,拼不成圆形。故答案为:C", + "knowledge_points": [ + "平面图形的拼接" + ], + "source": "23-24 一年级下·山东济南·期末" + }, + { + "id": "21", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "把一张正方形纸连续对折两次,不能折出的图形是 ( )。", + "options": [ + "A. 正方形", + "B. 圆", + "C. 三角形" + ], + "answer": "B", + "solution": "【分析】正方形是方方正正的,有 4 条直直的边,每条边都相等。图 1 折出的图形是正方形;图 2 折出的图形是长长方方的,有 4 条直直的边,对边相等,是长方形;图 3 折出的图形有 3 条直直的边,是三角形。圆没有直直的边,不能折出。由此解答。![](images/ec687802a3f9f251f8d62440815dcf48adef220aa377c539d6e4a9e9b39b86b6.jpg)\n【详解】由分析可知,把一张正方形纸连续对折两次,可以折出正方形,长方形和三角形,不能折出的图形是圆。故答案为: B", + "knowledge_points": [ + "图形的折叠问题", + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "23-24 一年级下·河北保定·期末" + }, + { + "id": "22", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "七巧板里有 ( ) 个 △ 。", + "options": [ + "A. 1", + "B. 5", + "C. 6" + ], + "answer": "B", + "solution": "【分析】七巧板里有 1 个平行四边形, 1 个正方形和 5 个三角形 (如下图);据此解决即可。![](images/072d68b6b1489089ccb2b6b0bce705715f44007888e7c09559052e7112043d3f.jpg)\n【详解】由题意分析得:七巧板里有 5 个 △ 。故答案为: B", + "knowledge_points": [ + "平行四边形的初步认识", + "长方形,正方形,三角形和圆的初步认识", + "用七巧板拼图形" + ], + "source": "23-24 一年级下·广东河源·期末" + }, + { + "id": "23", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "至少用 ( ) 个相同的 □, 能拼成一个大的正方形。", + "options": [ + "A. 2", + "B. 4", + "C. 8" + ], + "answer": "B", + "solution": "【分析】根据平面图形的初步认识,正方形四四方方的,边都是直直的,并且四条边一样长,据此解答.\n【详解】根据分析:至少用(4)个相同的□,能拼成一个大的正方形。故答案为: B", + "knowledge_points": [ + "平面图形的拼接", + "正方形的概念及特点" + ], + "source": "23-24 一年级下·广东河源·期末" + }, + { + "id": "24", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "用下面哪个物品可以画出 △ 。 ( )", + "options": [ + "A. ![](images/b3ccb2cccbfae62f16fb8c4beadbe1520591758e597205192ce0a4bf27992532.jpg)\n(图a)", + "B. ![](images/3d135e11c2e5bef05db690f455bdd803efdc17c8c0474eef78ac05bd359c28a0.jpg)\n(图b)", + "C. ![](images/28a4b2ebed2c8a0de9cc2f24bb9f7d1150ce1c3bf3497181468c3e7532b2dcfd.jpg)\n(图c)" + ], + "answer": "A", + "solution": "【分析】正方体:正正的方方的,有 6 个平平的面都相等;圆形由一条曲线围成。再结合三角形是由 3 条直直的线首尾依次连接而成的封闭图形,即可得出答案.\n【详解】A。图a,可以画出 △;B。图b,可以画出□;C. 图c,可以画出○ 。故答案为: A", + "knowledge_points": [ + "立体图形的认识", + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "23-24 一年级下·陕西安康·期末" + }, + { + "id": "25", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.65, + "question": "下图里有 ( ) 个三角形.\n\n![](images/55838b93ce393f70a3492f146f30395ce73b6255fd1e17a18e89ff04f4131a3e.jpg)", + "options": [ + "A. 6", + "B. 8", + "C. 10" + ], + "answer": "C", + "solution": "【分析】三角形是由 3 条直直的线首尾依次连接而成的封闭图形.\n\n先数出小三角形的个数,再数出由 4 个小三角形组成的大三角形的个数,相加即可.\n【详解】8 + 2 = 10 (个)图里有 10 个三角形。故答案为: C", + "knowledge_points": [ + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "23-24 一年级下·陕西安康·期末" + }, + { + "id": "26", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.65, + "question": "用![](images/bda53200ae42111693b70d902243c8eee6d9c895c2b5fd015f11bc73baa58893.jpg)不能拼成的图形是()。", + "options": [ + "A. 长方形", + "B. 平行四边形", + "C. 圆" + ], + "answer": "C", + "solution": "【分析】长方形是长长方方的,由4条边围成;平行四边形由 4 条边围成,且对边一样长;圆是由一条曲线围成的封闭图形,用两个三角形不能拼成圆.\n【详解】用两个直角三角形不能拼成的图形是圆。故答案为:C", + "knowledge_points": [ + "平面图形的拼接", + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "23-24 一年级下·陕西安康·期末" + }, + { + "id": "27", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.65, + "question": "用两个![](images/2025-12-08%20184003.jpg)能拼成的图形是 ( )。", + "options": [ + "A. 正方形", + "B. 长方形", + "C. 圆" + ], + "answer": "C", + "solution": "【分析】正方形是正正方方的,由 4 条边围成;长方形是长长方方的,由 4 条边围成;圆形由一条曲线围成。据此解答即可.\n【详解】A。正方形的四条边都是直边,不符合题意;B. 长方形的四条边都是直边,不符合题意;C. 圆由一条曲线围成,能用两个这样的图形拼成,符合题意。故答案为: C", + "knowledge_points": [ + "平面图形的拼接", + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "23-24 一年级下·河南周口·期末" + }, + { + "id": "28", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.65, + "question": "折一折,用![](images/9bbf60be96044980730076942b838f191a65d507090eee6cafdd90815ed9f5cb.jpg)做一个正方体,2 的对面是( )。", + "options": [ + "A. 4", + "B. 5", + "C. 3" + ], + "answer": "A", + "solution": "【分析】此图属于正方体展开图的,根据折痕可知:折成正方体后, 1 的对面是 6, 2 的对面是 4, 3 的对面是 5.\n【详解】用该图做成一个正方体, 2 的对面是 4。故答案为:A", + "knowledge_points": [ + "立体图形的认识", + "正方体的展开图" + ], + "source": "23-24一年级下·河北廊坊·期末" + }, + { + "id": "29", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.65, + "question": "用同样长的小棒摆 3个长方形,最少用( )根小棒。", + "options": [ + "A. 15", + "B. 14", + "C. 16" + ], + "answer": "B", + "solution": "【分析】长方形是四个角相等的四边形。当长为 2 根小棒,宽为 1 根小棒时,摆成的长方形所用小棒最少,如下图:![](images/cf6c1eabf6fa3a3f00ebc9f014c5bc58b45e513e1220aba330e53f2b3dcd650d.jpg)\n【详解】用同样长的小棒摆 3 个长方形,最少用 14 根小棒。故答案为: B", + "knowledge_points": [ + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "23-24一年级下·江西上饶·期末" + }, + { + "id": "30", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "用![](images/2025-12-08%20173940.jpg)折成一个正方体,'三'的对面是( )。", + "options": [ + "A. 我", + "B. 是", + "C. 好" + ], + "answer": "A", + "solution": "【分析】正方体展开图相对面的找法:同一层间隔一面是相对面,'我'和'三'中间隔着'是',故,'我'和'三'是相对面;据此解决.\n【详解】由题意分析得:用该图折成一个正方体,'三' 的对面是 '我'。故答案为:A", + "knowledge_points": [ + "正方体的展开图" + ], + "source": "23-24一年级下·贵州黔东南·期末" + }, + { + "id": "31", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "把一张正方形的纸对折一次,可能出现的图形是 ( )。", + "options": [ + "A. 等腰直角三角形", + "B. 平行四边形", + "C. 正方形" + ], + "answer": "A", + "solution": "【分析】沿着一张正方形的纸的一条对角线对折,折出的图形是三角形;把正方形的纸的对边对齐再进行对折,折出的图形是长方形;据此解决.\n【详解】由题意分析得:把一张正方形的纸对折一次,可能出现的图形是等腰直角三角形 。故答案为:A", + "knowledge_points": [ + "图形的折叠问题", + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "23-24 一年级下·河北唐山·期末" + }, + { + "id": "32", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "这个图形有 ( ) 个长方形.\n\n![](images/94d083132746f07945a9821910d80540142a55c059c85e3faf5409c16fa35f4e.jpg)", + "options": [ + "A. 3", + "B. 1", + "C. 2" + ], + "answer": "A", + "solution": "【分析】长方形是长长方方的,有 4 条直直的边,对边相等。由此数出单独的长方形的数量和组合成的长方形数量即可.\n【详解】单独的小长方形有 2 个, 2 个小长方形组成的大长方形有 1 个,一共有 2 + 1 = 3 (个)。这个图形有3个长方形。故答案为: A", + "knowledge_points": [ + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "23-24 一年级上·江苏淮安·期末" + }, + { + "id": "33", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "用两个完全一样的等腰直角三角形不能拼成 ( )。", + "options": [ + "A. 正方形", + "B. 三角形", + "C. 圆" + ], + "answer": "C", + "solution": "【分析】根据正方形,三角形及圆形的特征来解决即可。正方形是正正方方的,由4条边围成,且4条边都一样长;三角形是由3条直直的线首尾依次连接而成的封闭图形;圆形由一条曲线围成。把两个完全一样的等腰直角三角形的最长两条边拼接在一起,可以拼成正方形;把两个完全一样的等腰直角三角形的两条一样的短边拼接在一起,可以拼成三角形;圆的边是曲线,所以用两个完全一样的等腰直角三角形不能拼成圆.\n【详解】由题意分析得:用两个完全一样的等腰直角三角形不能拼成圆。故答案为: C", + "knowledge_points": [ + "平面图形的拼接", + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "23-24 一年级下·广东深圳·期末" + }, + { + "id": "34", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "用下面立体图形能画出圆的是 ( )。", + "options": [ + "A. 圆柱体", + "B. 正方体", + "C. 三棱柱" + ], + "answer": "A", + "solution": "【分析】圆柱由 2 个圆形和 1 个曲面围成,用圆柱能画出圆;正方体由 6 个正方形的面围成,用正方体能画出正方形,不能画出圆;正三棱柱由 2 个三角形和 3 个长方形的面围成,用正三棱柱能画出三角形和长方形,不能画出圆;据此解决.\n【详解】A。圆柱体,用圆柱能画出圆;B。正方体,用正方体不能画出圆;C。三棱柱,用正三棱柱不能画出圆;即,用圆柱体能画出圆。故答案为: A", + "knowledge_points": [ + "立体图形的认识", + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "23-24 一年级下·青海果洛·期末" + }, + { + "id": "35", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.65, + "question": "下图中有 ( ) 个长方形.\n\n![](images/c0a917a538307b0095f2f50c0fca49f7183f81a60dd36a7aaef8530395ca1dea.jpg)", + "options": [ + "A. 6", + "B. 7", + "C. 8", + "D. 9" + ], + "answer": "D", + "solution": "【分析】1 个大长方形分成了 4 个小长方形, 1 个大长方形 +4 个小长方形 = 5 个长方形,大长方形的上半部分和下半部分是 2 个长方形,大长方形的左半部分和右半部分是 2 个长方形,一共: 5 + 2 + 2 = 9 (个).\n【详解】下图中有9个长方形。故答案为: D", + "knowledge_points": [ + "长方形的概念及特点" + ], + "source": "23-24 一年级下·辽宁鞍山·期末" + }, + { + "id": "36", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "下面 ( ) 是由七巧板拼成的。", + "options": [ + "A. ![](images/856017d3004e4268034e868a8f73768017b466d12f1983917a242464f461ff6a.jpg)\n(图a)", + "B. ![](images/1a4cefb57b1b20c0e5c601bee68d4697c57f76471e75ee3baecd84d9faf9ccac.jpg)\n(图b)", + "C. ![](images/594bdec5b24348b802a8247a643d343a965adeec7b71c1b2dd32e69edb2cda1f.jpg)\n(图c)" + ], + "answer": "C", + "solution": "【分析】七巧板里面包含 7 个图形(如下图),其中包含 5 个三角形,1 个正方形和 1 个平行四边形;据此解决此题。![](images/c9da4d7cff21db14b9b495a9a5398f8b2d38be75f58c25ea9696be23cfe15a35.jpg)\n【详解】由题意分析得:图c,是由七巧板拼成的。故答案为: C", + "knowledge_points": [ + "平面图形的拼接", + "平行四边形的初步认识", + "长方形,正方形,三角形和圆的初步认识", + "用七巧板拼图形" + ], + "source": "23-24 一年级下·广东梅州·期末" + }, + { + "id": "37", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "折一折,用![](images/2025-12-08%20185705.jpg)做一个正方体,4的对面是( )。", + "options": [ + "A. 2", + "B. 3", + "C. 5" + ], + "answer": "B", + "solution": "【分析】根据正方体的展开图'相对不相邻'可知,1和2相对,6和5相对,4和3相对。由此解答.\n【详解】折一折,用该图做一个正方体, 4 的对面是 3。故答案为: B", + "knowledge_points": [ + "正方体的展开图" + ], + "source": "19-20 一年级下·贵州遵义·期末" + }, + { + "id": "38", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "用![](images/2025-12-08%20190144.jpg)不能拼成的图形是( )。", + "options": [ + "A. ![](images/c1b18d6254b8c6480b6e9fc6520a4096d45b5fc1236bfcf5ce984d68cc0391e1.jpg)\n(图a)", + "B. ![](images/74e30e5412972f0b21eeffa082aaee40a6d3b0344e46500b9e6fb7419def0bcd.jpg)\n(图b)", + "C. ![](images/d52d6895a862839e774a28a08beac354ed4c66e8c020df38bc33759959fdd182.jpg)\n(图c)" + ], + "answer": "B", + "solution": "【分析】根据长方形,三角形及圆形的特征来解决即可。长方形是长长方方的,由4条边围成,且对边一样长;平行四边形由4条边围成,且对边都一样长;三角形由3条线段首尾依次连接而成的封闭图形;圆形由一条曲线围成.\n【详解】A。 用该图能拼成图a;B. 用该图不能拼成图b;C. 用该图能拼成图c。故答案为: B", + "knowledge_points": [ + "平面图形的拼接", + "平行四边形的初步认识", + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "23-24 一年级下·广东汕头·期末" + }, + { + "id": "39", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.65, + "question": "在下面的长方形里画一条直直的线,将它分成两部分,其中一部分不可能是图形 ( )。\n\n![](images/4ea2018f6de501642db61a6fa8f95b9f00138928373cda79aeeee38453327f07.jpg)", + "options": [ + "A. ![](images/43e2e4902320174167f34ebd0370fa54651700faffbb06d2ec0095958db75909.jpg)\n(图a)", + "B. ![](images/b3f85f2948c566b3e99a6ca69b48411cf7edb813a6b24eb043279d6ecdf7461a.jpg)\n(图b)", + "C. ![](images/01f8d58a82308e635687e9e064ff8297fcc3867ee0bd10ee039aa28736e4e755.jpg)\n(图c)" + ], + "answer": "C", + "solution": "【分析】依据对平面图形的认识分一分可知:不可能是 C 项中的三角形.\n【详解】沿着对角线画一条线段,应该是两个直角三角形,其中一部分不可能是图形图c。故答案为: C.", + "knowledge_points": [ + "平面图形的分割" + ], + "source": "23-24 一年级下·浙江台州·期末" + }, + { + "id": "40", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.65, + "question": "折一折,用![](images/debdd9e177a17270d60986fdd73560bdcc70b34874e8baed528e7c66bdcb7116.jpg)做一个正方体, 6 的对面是 ( )。", + "options": [ + "A. 1", + "B. 4", + "C. 5" + ], + "answer": "A", + "solution": "【分析】根据正方体的特点,正方体相对的面不相邻,所以6的对面是1,据此解答.\n【详解】1 和 6 相对,4 和 3 相对,2 和 5 相对。故答案为:A", + "knowledge_points": [ + "正方体的展开图" + ], + "source": "23-24 一年级下·江西九江·期末" + }, + { + "id": "41", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "将![](images/52bc8e0b50f401b8b4c5e42fd0822d4378b0467c1ed253d6d89ac16890226637.jpg)做成一个正方体 , '5'的对面是 ( )。", + "options": [ + "A. 2", + "B. 3", + "C. 4" + ], + "answer": "B", + "solution": "【分析】正方体展开图相对面的找法:同一层间隔一面是相对面,3和5中间隔着4,故,3和5是相对面;据此解决即可.\n【详解】由题意分析得:将该图做成一个正方体,'5'的对面是3。故答案为: B", + "knowledge_points": [ + "正方体的展开图" + ], + "source": "23-24 一年级下·河北保定·期末" + }, + { + "id": "42", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.65, + "question": "至少 ( ) 个同样的等腰直角三角形可以拼成一个正方形。", + "options": [ + "A. 2", + "B. 3", + "C. 5" + ], + "answer": "A", + "solution": "【分析】如图![](images/2025-12-08%20190856.jpg), 这个正方形中有 2 个等腰直角三角形,即至少 2 个同样的等腰直角三角形可以拼成一个正方形.\n【详解】根据分析知:至少 2 个同样的等腰直角三角形可以拼成一个正方形。故答案为: A", + "knowledge_points": [ + "平面图形的拼接", + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "23-24 一年级下·山东菏泽·期末" + }, + { + "id": "43", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.65, + "question": "把![](images/906bf216b2d509a1d9ad5d338453457d96563518d3c3e2a6939e957e9032288c.jpg)沿虚线剪开,得到的两个图形还可以拼成( )。", + "options": [ + "A. 正方形", + "B. 圆", + "C. 三角形" + ], + "answer": "C", + "solution": "【分析】剪开的图形可以拼成![](images/fe7fa20eaf110a8a19bd2d660443182542de600ad7682a828c888072ba5aed5a.jpg)或![](images/1f375e92d8c3b4d1c8980da935361b1b52dd08b786e3efd03a5183f0c7e981d9.jpg),据此得出结论即可.\n【详解】根据分析知:把![](images/62d7290d0175502a975f83373adda646c85ef48bf1cabe1a95c0cf2005f9c2af.jpg)沿虚线剪开,得到的两个图形还可以拼成三角形,故答案为: C", + "knowledge_points": [ + "平面图形的拼接" + ], + "source": "23-24一年级下·河北衡水·期末" + }, + { + "id": "44", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "下面第 ( ) 组能拼成一个正方形。", + "options": [ + "A. ![](images/2025-12-08%20191544.jpg)\n(图a)", + "B. ![](images/7e2454b92af961cd6d155d8f0c06efe57404764d8564ea303a87b3e1fa29f0ae.jpg)\n(图b)", + "C. ![](images/2025-12-08%20191551.jpg)\n(图c)" + ], + "answer": "C", + "solution": "【分析】正方形是方方正正的,有 4 条直直的边,每条边都相等;由此将各组图形拼一拼,选择即可.\n【详解】A。不能拼成正方形;B. 不能拼成正方形;C。![](images/2025-12-08%20191810.jpg)能拼成正方形。图c能拼成正方形。故答案为: C", + "knowledge_points": [ + "平面图形的拼接", + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "23-24 一年级下·湖南益阳·期末" + }, + { + "id": "45", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "把一张 □ 对折一次,不可能出现的图形是 ( )。", + "options": [ + "A. ![](images/9127ffc4b3e306196e7edcd351303478b2ad56678f6403d67447ce0c5a59fba9.jpg)", + "B. ![](images/107dc09cf1b83a2ff3f088252394ebfd1e3a9a72d00e398577ec83b4f033fb96.jpg)", + "C. ![](images/ccb0105a95e23a209366d91096208176efcb214fa250258a9456e6f59c55c25a.jpg)" + ], + "answer": "C", + "solution": "【分析】正方形沿着一组对边对折,折后出现的图形是两个长方形;正方形沿着一组对角对折,折后出现的图形是两个三角形;对折后不可能出现的是平行四边形;据此解决.\n【详解】由题意分析得:把一张□对折一次,不可能出现的图形是平行四边形。故答案为: C", + "knowledge_points": [ + "图形的折叠问题", + "平行四边形的初步认识", + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "23-24 一年级下·浙江杭州·期末" + }, + { + "id": "46", + "unit": "认识图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "平行四边形的两组对边长度分别( )。长方形和正方形都是特殊的( )。", + "options": [], + "answer": "相等;平行四边形", + "solution": "【分析】两组对边平行且相等的四边形叫做平行四边形;长方形有 4 条边,对边相等且平行。属于特殊平行四边形正方形有 4 条边且相等,对边平行;属于特殊平行四边形.\n【详解】由分析可得:平行四边形的两组对边长度分别(相等)。长方形和正方形都是特殊的(平行四边形)。", + "knowledge_points": [ + "长方形的概念及特点", + "平行四边形的概念及特点", + "正方形的概念及特点" + ], + "source": "24-25 二年级上·河南新乡·期中" + }, + { + "id": "47", + "unit": "认识图形", + "question_type": "填空题", + "difficulty": 0.65, + "question": "数一数,一共有( )个长方形.\n\n![](images/3aa2f4aa5cb4203669c25187b1fb257b690a4ef3dfaf444cbac134024e74d8fb.jpg)", + "options": [], + "answer": "11", + "solution": "【分析】长方形是长长方方的,有 4 条直直的边,对边相等;单独的小长方形有 5 个,2 个小长方形组成的大长方形有 4 个,3 个小长方形组成的大长方形有 2 个,相加就是总数量;据此解答.\n【详解】根据分析:5 + 4 + 2 = 11(个),所以一共有 11 个长方形。", + "knowledge_points": [ + "连加(20以内)", + "数图形", + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "24-25 二年级上·山东济宁·期中" + }, + { + "id": "48", + "unit": "认识图形", + "question_type": "填空题", + "difficulty": 0.65, + "question": "图中有( )个三角形.\n\n![](images/b470566d27b5886cc224f6862a51713da252a241b69f7ffbcfbb539b11abb921.jpg)", + "options": [], + "answer": "8", + "solution": "【分析】三角形有 3 条直直的边。由图可知,单个的小三角形有 4 个,由 2 个小三角形组成的大三角形有 4 个;据此相加求出三角形的总数即可.\n【详解】4 + 4 = 8 (个),所以图中有 8 个三角形。", + "knowledge_points": [ + "数一数", + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "23-24 一年级下·河南漯河·期末" + }, + { + "id": "49", + "unit": "认识图形", + "question_type": "填空题", + "difficulty": 0.65, + "question": "![](images/2025-12-08%20192220.jpg)图中有( )个 □,至少再添上( )个这样的 □,就可以拼成一个大正方形。", + "options": [], + "answer": "4;5", + "solution": "【分析】通过数一数即可知图中有几个 □;正方形是方方正正的,有四条直直的边,每条边都相等。根据正方形的特征,可知要想得到至少再添上几个这样的 □,就可以拼成一个大正方形,只需要让大正方形的边长占3个方格即可,这样大正方形就有9个 □,还需要再添上 9 - 4 = 5 (个)这样的 □ 即可.\n【详解】由分析可知:图中有4个 □,至少再添上5个这样的□,就可以拼成一个大正方形。", + "knowledge_points": [ + "平面图形的拼接", + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "23-24 一年级下·浙江嘉兴·期末" + }, + { + "id": "50", + "unit": "认识图形", + "question_type": "填空题", + "difficulty": 0.65, + "question": "数一数,填一填.\n\n![](images/53ec7aab103131f0aa53ba7ef5ab8c5f8346c9b41db830a5a67bb91ded41d6f9.jpg)\n\n![](images/9d256df6e071d1305ba94a1a200d0d4932ff36c98ca66d51c13c8fc3b5e02fd8.jpg)\n\n![](images/df839c364716faf96016874539acf9a8fa8239b5d3a2f6582216ac4875749d9c.jpg)\n\n有( )个长方形;有( )个正方形;有( )个三角形。", + "options": [], + "answer": "6;5;3", + "solution": "【分析】长方形是长长方方的,有 4 条直直的边,对边相等;正方形是方方正正的,有 4 条直直的边,每条边都相等;三角形有 3 条直直的边。图一:单个的小长方形有 3 个,由 2 个小长方形组成的长方形有 2 个,由 3 个小长方形组成的大长方形有 1 个;图二:单个的小正方形有 4 个,由 4 个小正方形组成的大正方形有 1 个;图三:单个的小三角形有 2 个,由 2 个小三角形组成的大三角形有 1 个;据此相加求出各图形的总数即可.\n【详解】 3 + 2 + 1 = 6 (个);4 + 1 = 5 (个);2 + 1 = 3 (个)", + "knowledge_points": [ + "连加,连减(10以内)", + "数一数", + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "23-24 一年级下·山西晋中·期末" + }, + { + "id": "51", + "unit": "认识图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "下图中有( )个长方形, ( )个三角形, ( )个圆和( )个平行四边形.\n\n![](images/b190587b3b0d9d2cc1487e0573436c6614b5ff790d63d3a86170e11e10abe8b3.jpg)", + "options": [], + "answer": "3;2;3;3", + "solution": "【分析】长方形是对边相等的图形,三角形是三条边首尾依次连接组成的图形,平行四边形是在长方形的基础上,对角向外拉扯即可形成,也可用纸张分别剪出对应图形,在对照剪出的图形在图中找一找即可,根据对图形的认识在图片中找一找即可.\n【详解】下图中有(3)个长方形,(2)个三角形,(3)个圆和(3)个平行四边形。", + "knowledge_points": [ + "平行四边形的初步认识", + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "23-24 一年级下·河南郑州·期末" + }, + { + "id": "52", + "unit": "认识图形", + "question_type": "填空题", + "difficulty": 0.65, + "question": "用![](images/2025-12-08%20193100.jpg)做一个正方体,'3'的对面是( )。", + "options": [], + "answer": "4", + "solution": "【分析】正方体展开图相对面的找法:同一层间隔一面是相对面,3和4中间隔着2,所以3和4是相对面;据此解答即可.\n【详解】由分析可得,用该图做一个正方体,'3'的对面是'4'。", + "knowledge_points": [ + "正方体的展开图" + ], + "source": "23-24 年级下·湖北黄石·期末" + }, + { + "id": "53", + "unit": "认识图形", + "question_type": "填空题", + "difficulty": 0.65, + "question": "如图,做成一个正方体,数字 '1' 对面的数是( ), 数字 '3' 的对面是( ).\n\n![](images/590990fca919a0a6c3c52173954a22cbdd74eac0f4f75b749813380bb1913ff1.jpg)", + "options": [], + "answer": "4;6", + "solution": "【分析】相邻的不会相对,观察可知,4和1相对,3和6相对,5和2相对,据此填空.\n【详解】如图,做成一个正方体,数字'1'对面的数是4,数字 '3'的对面是 6。", + "knowledge_points": [ + "正方体的展开图" + ], + "source": "23-24 一年级下·山东临沂·期末" + }, + { + "id": "54", + "unit": "认识图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "如图,七巧板是由( )种图形组成的,其中三角形板有( )块,正方形板有( )块,平行四边形板有( )块.\n\n![](images/c18a608ad8d70fd1cc17fce2ffba64d67f14856be538b29be49f708c59a89032.jpg)", + "options": [], + "answer": "3;5;1;1", + "solution": "【分析】三角形有三条直直的边;正方形是方方正正的,有4条直直的边,每条边都相等;平行四边形有4条直直的边,对边相等,有2条同方向的斜边。可知1,2,4,6,7是三角形;5 是正方形, 3 是平行四边形,由此解答.\n【详解】如图,七巧板是由 3 种图形组成的,其中三角形板有 5 块,正方形板有 1 块,平行四边形板有 1 块。", + "knowledge_points": [ + "平行四边形的初步认识", + "长方形,正方形,三角形和圆的初步认识", + "用七巧板拼图形" + ], + "source": "23-24 一年级下·湖南岳阳·期末" + }, + { + "id": "55", + "unit": "认识图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "用![](images/2025-12-08%20193653.jpg)做一个正方体 '是' 对面的汉字是( )。", + "options": [], + "answer": "先", + "solution": "【分析】根据正方体的展开图'相对不相邻'可知,'我'和'少'相对;'是'和'先'相对;'队'和'员'相对,由此解答.\n【详解】由分析可知,用该图做一个 '是' 对面的汉字是先。", + "knowledge_points": [ + "正方体的展开图" + ], + "source": "23-24 一年级下·湖北恩施·期末" + }, + { + "id": "56", + "unit": "认识图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "下图中有( )个长方形。![](images/ee0408d347b60403ae951add22ed170061c53fd4f73453f75843d2769ede9b09.jpg)", + "options": [], + "answer": "3", + "solution": "【分析】长方形是长长方方的,有 4 条直直的边,对边相等,由此数出数量即可.\n【详解】该图中有3个长方形。", + "knowledge_points": [ + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "23-24 一年级下·河南周口·期末" + }, + { + "id": "57", + "unit": "认识图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "用![](images/47c9daf4afe4a80e5cdcc1a8c3cab84d7d8ab14fe7544c828b91df1764e08294.jpg)折成一个正方体,字母E的对面是字母( ),字母C的对面是字母( )。", + "options": [], + "answer": "F;A", + "solution": "【分析】根据正方体的展开图'相对不相邻'可知,D和B相对;A和C相对;E和F相对,由此解答.\n【详解】用该图折成一个正方体,字母E的对面是字母F,字母C的对面是字母A。", + "knowledge_points": [ + "正方体的展开图" + ], + "source": "23-24 一年级下·福建漳州·期末" + }, + { + "id": "58", + "unit": "认识图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "数学书的封面是( )形的;红领巾是( )形的;用![](images/bba80c9891ccbb4823e4f39b43640812b5fcfdde1d495ea8630a4f5ee4d63643.jpg)可以画( )形。", + "options": [], + "answer": "长方;三角;圆", + "solution": "【分析】根据数学课本的封面是四个角都是直角的平行四边形,所以数学书封面是长方形的;结合生活实际,红领巾是三角形的;硬币是圆形的,所以它可以用来画圆形.\n【详解】数学书的封面是长方形的;红领巾是三角形的;用硬币可以画圆形。", + "knowledge_points": [ + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "23-24 一年级下·河南南阳·期末" + }, + { + "id": "59", + "unit": "认识图形", + "question_type": "填空题", + "difficulty": 0.65, + "question": "折一折,用![](images/8437c505fe13d326b792fc273e15810bc8c53bf010b4ed83466dab8ec195dd3a.jpg)做一个正方体 ,1 的对面是( )。", + "options": [], + "answer": "3", + "solution": "【分析】观察可以发现,是正方体的展开图形,可以按照图片中的形状自己做一个,然后折一折即可得出答案;或者想想正方形的立体样子,根据展开的图形进行还原,5和6作为正方体的上下两个面可以排除,4,1,2,3则是中间的四个面,1和3正好中间有2相隔,可以形成对面的关系.\n【详解】折一折,用该图做一个正方体,1 的对面是 3。", + "knowledge_points": [ + "正方体的展开图" + ], + "source": "23-24一年级下·山东临沂·期末" + }, + { + "id": "60", + "unit": "认识图形", + "question_type": "填空题", + "difficulty": 0.65, + "question": "用七巧板中两个相同的三角形可以拼成一个( ), 也可以拼成一个( ), 还可以拼成一个( )。", + "options": [], + "answer": "正方形;三角形;平行四边形", + "solution": "【分析】如果把七巧板中两个相同的三角形的斜边挨着一起,可以拼成一个正方形;如果把七巧板中两个相同的三角形的两条直角边挨在一起,可以拼成一个三角形,也可以拼成一个平行四边形.\n【详解】由题意分析得:用七巧板中两个相同的三角形可以拼成一个正方形,也可以拼成一个三角形,还可以拼成一个平行四边形。", + "knowledge_points": [ + "平面图形的拼接", + "平行四边形的初步认识", + "长方形,正方形,三角形和圆的初步认识", + "用七巧板拼图形" + ], + "source": "23-24 一年级下·湖北黄冈·期末" + }, + { + "id": "61", + "unit": "认识图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "下图中有( )个正方形, ( )个长方形.\n\n![](images/21b682a81a846e4fe4ede6df9465ec44fe8934535713181173030eceadb40248.jpg)", + "options": [], + "answer": "2;3", + "solution": "【分析】正方形是正正方方的,有 4 条直直的边,每条边都相等;长方形是长长方方的,有 4 条直直的边,对边相等,由此数出图形的数量即可.\n【详解】该图中有2个正方形,3个长方形。", + "knowledge_points": [ + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "22-23 二年级下·河南周口·期末" + }, + { + "id": "62", + "unit": "认识图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "![](images/2025-12-09%20201749.jpg)是由( )个![](images/2025-12-09%20201819.jpg)(图1)拼成的,或是由( )个![](images/2025-12-09%20201845.jpg)(图2)拼成的。", + "options": [], + "answer": "4;2", + "solution": "【分析】图1,由3条直直的边围成,是三角形;图2,整体有4条直直的边,对边相等,有2条同方向的斜边,是平行四边形;由此数出图1和图2的数量即可.\n【详解】![](images/ee7286a1fc686769705a94e4784acc51e2d88eff774564ba66eee3855724e170.jpg)该图是由4个图1拼成的,或是由2个图2拼成的。", + "knowledge_points": [ + "平面图形的拼接", + "平行四边形的初步认识", + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "23-24一年级下·四川凉山·期末" + }, + { + "id": "63", + "unit": "认识图形", + "question_type": "填空题", + "difficulty": 0.65, + "question": "将一张正方形的纸对折后沿虚线剪开,可以剪成两个完全相同的( ),还可以剪成两个完全相同的( )。", + "options": [], + "answer": "长方形;三角形", + "solution": "【分析】正方形是方方正正的,有 4 条直直的边,每条边都相等。长方形是长长方方的,有 4 条直直的边,对边相等;三角形有 3 条直直的边。如图为对折后的图形,剪开后是长方形和三角形,由此解答。![](images/52961441cd9ab38103fc57b905725b58c6003f6468a398f05dc18a235782f2af.jpg)\n【详解】由分析可知,将一张正方形的纸对折后沿虚线剪开,可以剪成两个完全相同的长方形,还可以剪成两个完全相同的三角形。", + "knowledge_points": [ + "平面图形的分割", + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "23-24 一年级下·山东济宁·期末" + }, + { + "id": "64", + "unit": "认识图形", + "question_type": "填空题", + "difficulty": 0.65, + "question": "用![](images/4d8c0c5df6b6d4ad516c74f6b82c2794c9f33b2e3c5da5c77fc19ad61b812c1f.jpg)做成一个正方体,数字4的对面是数字( )。", + "options": [], + "answer": "5", + "solution": "【分析】根据正方体的展开图'相对不相邻'可知,4和5相对,1和3相对,2和6相对,由此解答.\n【详解】该图做成一个正方体,数字4的对面是数字5。", + "knowledge_points": [ + "正方体的展开图" + ], + "source": "23-24 一年级下·山东济宁·期末" + }, + { + "id": "65", + "unit": "认识图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "折一折,用![](images/45bbc9aaa9137f5ad94035f11b497078092dc01227a647d4a1ede0c08a15494c.jpg)做一个正方体,'是'的对面是( ),'好'在( )的对面。", + "options": [], + "answer": "我;们", + "solution": "【分析】根据正方体的展开图'相对不相邻'可知,'是'和'我'相对;们和好相对;孩和子相对,由此解答.\n【详解】由分析可知:用该图做一个正方体,'是'的对面是'我', '好'在'们'的对面。", + "knowledge_points": [ + "正方体的展开图" + ], + "source": "23-24 一年级下·湖南湘西·期末" + }, + { + "id": "66", + "unit": "认识图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "把![](images/7aa40c12f0da0159c07757508f0143f2d854ba4d10d8137bfcf1907de639e69f.jpg)折成一个正方体,数字'2'的对面是数字( ),数字'1'的对面是数字( )。", + "options": [], + "answer": "6;5", + "solution": "【分析】根据正方体的展开图'相对不相邻'可知,4和3相对;2和6相对;5和1相对,由此解答.\n【详解】把该图折成一个正方体,数字'2'的对面是数字'6',数字'1'的对面是数字'5'。", + "knowledge_points": [ + "正方体的特征", + "正方体的展开图" + ], + "source": "23-24 一年级下·福建福州·期末" + }, + { + "id": "67", + "unit": "认识图形", + "question_type": "填空题", + "difficulty": 0.65, + "question": "数一数图中一共有( )个三角形。![](images/10f49addaf47f79674db19d2ffb79cc138ad99eacc5465d9c8a8723174cba829.jpg)", + "options": [], + "answer": "3", + "solution": "【分析】三角形是由3条直直的边围成的图形,依次数出单独的三角形和组合成的三角形数量,相加即可.\n【详解】单独的小三角形有 2 个;整体是 1 个大三角形。 2 + 1 = 3 (个),图中一共有3个三角形。", + "knowledge_points": [ + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "23-24 一年级下·山东济宁·期末" + }, + { + "id": "68", + "unit": "认识图形", + "question_type": "填空题", + "difficulty": 0.65, + "question": "一套七巧板有( )块,其中有( )个□,( )个 △,( )个 平行四边形。", + "options": [], + "answer": "7;1;5;1", + "solution": "【分析】三角形有 3 条直直的边;正方形是方方正正的,有 4 条直直的边,每条边都相等;平行四边形有 4 条直直的边,对边相等,有 2 条同方向的斜边。如下图,由七巧板的组成可知,七巧板一共有 7 块,由 3 种图形组成,其中有 1 个正方形,有 5 个三角形, 1 个平行四边形,据此解答即可。![](images/2741e326cff364c0996705a274042055dcdc6b47021e2b89d2683bc11e3854b0.jpg)\n【详解】由分析可得,一套七巧板有 7 块,其中有 1 个 □ ,5 个 △ ,1 个平行四边形。", + "knowledge_points": [ + "平行四边形的初步认识", + "长方形,正方形,三角形和圆的初步认识", + "用七巧板拼图形" + ], + "source": "23-24 一年级下·山东济宁·期末" + }, + { + "id": "69", + "unit": "认识图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "用![](images/2025-12-09%20204207.jpg)折成一个正方体,'我'的对面是( ),'学'的对面是( )。", + "options": [], + "answer": "小;好", + "solution": "【分析】根据正方体的展开图'相对不相邻'可知,我和小相对;是和生相对;学和好相对。由此解答.\n【详解】用该图折成一个正方体,'我'的对面是小, '学'的对面是好。", + "knowledge_points": [ + "正方体的展开图" + ], + "source": "23-24 一年级下·贵州铜仁·期末" + }, + { + "id": "70", + "unit": "认识图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "摆一个正方形至少需要( )根同样长的小棒;摆一个三角形至少需要( )根同样长的小棒。", + "options": [], + "answer": "4;3", + "solution": "【分析】正方形是方方正正的,有 4 条直直的边,每条边都相等,如图 1,至少需要 4 根同样长的小棒;三角形有 3 条直直的边,如图 2,至少需要 3 根同样长的小棒。![](images/5f0fc29d8973ae58c7de1a15be503da767224080293a6c51e185eac5a55db5a0.jpg)![](images/f38ddc40f876393a06b37d4666e8c7edeee9ebab721642314dc62eba660d14d4.jpg)\n【详解】摆一个正方形至少需要 4 根同样长的小棒;摆一个三角形至少需要 3 根同样长的小棒。", + "knowledge_points": [ + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "23-24一年级下·山东临沂·期末" + }, + { + "id": "71", + "unit": "认识图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "用涂色部分的小三角形拼满下图,一共需要( )个这样的小三角形。![](images/c01559169a25fd13ea24a61473b56d3705243cb94fff81c71aff8ababbaf8e50.jpg)", + "options": [], + "answer": "8", + "solution": "【分析】根据题意,将图形分一分,分成与涂色三角形相同大小的三角形,数出三角形的数量即可.\n【详解】作图如下:![](images/f21433e6b326c61c8ef6100c950984f73900b03218c0b354074afedafdff4e7f.jpg)数一数可知,用涂色部分的小三角形拼满图形,一共需要 8 个这样的小三角形。", + "knowledge_points": [ + "平面图形的拼接", + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "23-24 一年级下·浙江·期末" + }, + { + "id": "72", + "unit": "认识图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "七巧板是一种智力玩具,它由( ), ( )和( )组成。", + "options": [], + "answer": "正方形;三角形;平行四边形", + "solution": "【分析】三角形是由 3 条直直的线首尾依次连接而成的封闭图形;正方形是正正方方的,由 4 条边围成;平行四边形由 4 条边围成,且其中一组对边向同一个方向倾斜。根据题意,通过观察七巧板![](images/251dd7f90f65e0156e18ca6e63635c47c6a89769c1255ba3717a9463ccf69a0a.jpg),是由正方形,三角形,平行四边形三种图形组成的,据此解答.\n【详解】由分析可得,七巧板是一种智力玩具,它由正方形,三角形和平行四边形组成。", + "knowledge_points": [ + "平行四边形的初步认识", + "长方形,正方形,三角形和圆的初步认识", + "用七巧板拼图形" + ], + "source": "22-23 二年级下·河南周口·期末" + }, + { + "id": "73", + "unit": "认识图形", + "question_type": "填空题", + "difficulty": 0.65, + "question": "一套七巧板有( )个图形,其中有( )个三角形。", + "options": [], + "answer": "7;5", + "solution": "【分析】一套七巧板有 7 个图形,其中 5 个三角形, 1 个正方形, 1 个平行四边形,据此得出结论即可.\n【详解】根据分析知:一套七巧板有 7 个图形,其中有 5 个三角形。", + "knowledge_points": [ + "长方形,正方形,三角形和圆的初步认识", + "用七巧板拼图形" + ], + "source": "22-23 一年级下·江西吉安·期末" + }, + { + "id": "74", + "unit": "认识图形", + "question_type": "填空题", + "difficulty": 0.65, + "question": "用![](images/e02adfaaa3560be9128b841c1e175130ae9c316bb8dce25fef9cf5c37ff4936e.jpg)折成一个正方体,'2'的对面是( ),'6'的对面是( )。", + "options": [], + "answer": "4;1", + "solution": "【分析】此图属于正方体展开图的 '1-4-1'型,折成正方体后'1'的对面是'6','2'的对面是'4','3'的对面是'5'.\n【详解】用该图折成一个正方体 , '2'的对面是'4', '6'的对面是'1'。", + "knowledge_points": [ + "正方体的展开图" + ], + "source": "23-24 一年级下·湖南郴州·期末" + }, + { + "id": "75", + "unit": "认识图形", + "question_type": "填空题", + "difficulty": 0.65, + "question": "把一个正方形对折一次后,可以得到( )形或( )形。", + "options": [], + "answer": "三角;长方", + "solution": "【分析】把一个正方形对折一次可如图对折,![](images/0925af8b06d8d9769afb4d2a9e3ac4f5a3eddab006e1217ecfb2055d71644844.jpg),即可以得到三角形或长方形.\n【详解】根据分析知:把一个正方形对折一次后,可以得到三角形或长方形。", + "knowledge_points": [ + "图形的折叠问题" + ], + "source": "23-24 一年级下·湖北黄冈·期末" + }, + { + "id": "76", + "unit": "认识图形", + "question_type": "填空题", + "difficulty": 0.65, + "question": "我的红领巾是( )形,它有( )条边。", + "options": [], + "answer": "三角;3", + "solution": "【分析】红领巾的形状是一个三角形,三角形有3个角,3条边。据此解答.\n【详解】由分析可知,我的红领巾是三角形,它有3条边。", + "knowledge_points": [ + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "23-24 一年级下·河南南阳·期末" + }, + { + "id": "77", + "unit": "认识图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "两个同样大小的长方形一定能拼成( )。", + "options": [], + "answer": "长方形", + "solution": "【分析】长方形是长长方方的,由 4 条边围成,且对边一样长;正方形是正正方方的,由 4 条边围成,且 4 条边都一样长。两个同样大小的长方形一定能拼成(如左下图);特殊的时候也能拼成正方形(如右下图),但不是一定能拼成。![](images/2025-12-09%20205011.jpg)\n【详解】由题意分析得:两个同样大小的长方形一定能拼成长方形。", + "knowledge_points": [ + "平面图形的拼接", + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "22-23一年级下·山东菏泽·阶段练习" + }, + { + "id": "78", + "unit": "认识图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "两个同样的 □ 可以拼成一个( )形,四个同样的 □ 可以拼成一个( )形或( )形。", + "options": [], + "answer": "长方;长方;正方", + "solution": "【分析】正方形是方方正正的,有 4 条直直的边,每条边都相等;长方形是长长方方的,有 4 条直直的边,对边相等。图1:两个正方形拼成的是长方形;图2:四个正方形拼成的是长方形;图3:四个正方形拼成的是正方形.\n\n![](images/5cdff305c1d221113922bea667983fdb814a413b7e8dc80b05bbc140a553ae55.jpg)\n\n![](images/bd0f935706f039f155be44f79a178814d79080e2b9294020b2eafa894802e0ed.jpg)\n\n![](images/062e675db095ac18845474786324b841809f42883a8906736bc5e54251690ce1.jpg)\n\n【详解】两个同样的 □ 可以拼成一个长方形,四个同样的 □ 可以拼成一个长方形或正方形。", + "knowledge_points": [ + "平面图形的拼接", + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "22-23 一年级下·江西宜春·期中" + }, + { + "id": "79", + "unit": "认识图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "下图七巧板中, ( )号是平行四边形, ( )号是正方形.\n\n![](images/c5ed97e1c5910c8017f56aeedaf74b0888b407aa76da60066a116b13df8ff813.jpg)", + "options": [], + "answer": "3;5", + "solution": "【分析】平行四边形有 4 条直直的边,对边相等,有 2 条同方向的斜边;正方形是方方正正的,有 4 条直直的边,每条边都相等,由此解答.\n【详解】由图中的七巧板可知,3号是平行四边形,5号是正方形。", + "knowledge_points": [ + "平行四边形的初步认识", + "长方形,正方形,三角形和圆的初步认识", + "用七巧板拼图形" + ], + "source": "23-24一年级下·吉林四平·期末" + }, + { + "id": "80", + "unit": "认识图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "下图是由一个( )形和两个相同的( )形拼成的( )形.\n\n![](images/4ed43c3fe8e13784aca26dd773119607db54d16822d67680a763eae17f396346.jpg)", + "options": [], + "answer": "正方;三角;平行四边", + "solution": "【分析】根据平面图形的特征来解决即可。正方形是正正方方的,由 4 条边围成;三角形是由 3 条直直的线首尾依次连接而成的封闭图形;平行四边形由 4 条边围成,且对边一样长.\n【详解】由题意分析得:该图是由一个正方形和两个相同的三角形拼成的平行四边形。", + "knowledge_points": [ + "平面图形的拼接", + "平行四边形的概念及特点", + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "23-24 一年级下·广东汕头·期末" + }, + { + "id": "81", + "unit": "认识图形", + "question_type": "填空题", + "difficulty": 0.65, + "question": "折一折,用![](images/46590ec76c6385bc48a6809cfbb5bb3af3d8e5359a36f048e89298efba7dca6b.jpg)可以做一个正方体 ,2 的对面是( ),4 的对面是( )。", + "options": [], + "answer": "6;5", + "solution": "【分析】相邻的不相对,观察可知,4和5相对,2和6相对,1和3相对,据此填空.\n【详解】折一折,用该图可以做一个正方体 ,2 的对面是6,4的对面是5。", + "knowledge_points": [ + "图形的折叠问题", + "正方体的展开图" + ], + "source": "23-24一年级下·广东广州·期末" + }, + { + "id": "82", + "unit": "认识图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "用七巧板拼三角形。一套七巧板有( )块,其中有( )个正方形,( )个平行四边形,( )个三角形。", + "options": [], + "answer": "7;1;1;5", + "solution": "【分析】七巧板是一套由7块几何板组成的拼图玩具,包含三种基本图形:三角形,正方形和平行四边形。通过观察七巧板的组成结构,可以准确统计出各类图形的数量.\n【详解】一套完整的七巧板共有7块。其中包括:1个正方形,1个平行四边形和5个三角形(所有三角形均为等腰直角三角形)。因此,答案为:7;1;1;5.\n\n![](images/5c794b6977952eee438b06119d216c7cdd12cc1949cff4a3eb442d16bebc3732.jpg)", + "knowledge_points": [ + "平行四边形的初步认识", + "长方形,正方形,三角形和圆的初步认识", + "用七巧板拼图形" + ], + "source": "23-24 一年级下·河北·期末" + }, + { + "id": "83", + "unit": "认识图形", + "question_type": "判断题", + "difficulty": 0.85, + "question": "七巧板中的每块板都是三角形。( )", + "options": [], + "answer": "×", + "solution": "【分析】三角形有 3 条直直的边;正方形是方方正正的,有 4 条直直的边,每条边都相等;平行四边形有 4 条直直的边,对边相等,有 2 条同方向的斜边,由此解答.\n【详解】如图为七巧板,有 5 块三角形, 1 块正方形和 1 块平行四边形,原题说法错误.\n\n![](images/eb30301d3afd972130aa2e2d411df51d5aebdb63aae7cf8c63557ac2736e9358.jpg)\n\n故答案为: ×", + "knowledge_points": [ + "平行四边形的初步认识", + "长方形,正方形,三角形和圆的初步认识", + "用七巧板拼图形" + ], + "source": "24-25 二年级上·河南驻马店·期中" + }, + { + "id": "84", + "unit": "认识图形", + "question_type": "判断题", + "difficulty": 0.85, + "question": "将一个正方形对折,可能会得到两个长方形,也可能会得到两个三角形。( )", + "options": [], + "answer": "√", + "solution": "【分析】本题考查的是图形的折叠问题,动手操作是解答关键。动手操作,可以看出将一个正方形对折,因为正方形四条边相等,所以上下,左右对折会得到两个长方形,沿对角线对折会得到两个三角形,据此解答.\n【详解】因为正方形四条边相等,所以将一个正方形对折,可能会得到两个长方形,也可能会得到两个三角形,原题答案 √。故答案为: √", + "knowledge_points": [ + "图形的折叠问题", + "正方形的概念及特点" + ], + "source": "23-24 二年级上·河南商丘·期中" + }, + { + "id": "85", + "unit": "认识图形", + "question_type": "判断题", + "difficulty": 0.85, + "question": "在![](images/2025-12-09%20205936.jpg)中有 3 个三角形。( )", + "options": [], + "answer": "√", + "solution": "【分析】三角形有 3 条直直的边。由图可知,单个的小三角形有 2 个,由 2 个小三角形组成的大三角形有 1 个;据此相加求出三角形的总数即可.\n【详解】2 + 1 = 3 (个),所以在该图中有3个三角形。原题说法正确。故答案为:√", + "knowledge_points": [ + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "23-24一年级下·河南漯河·期末" + }, + { + "id": "86", + "unit": "认识图形", + "question_type": "判断题", + "difficulty": 0.85, + "question": "两个相同的长方形一定能拼出正方形。( )", + "options": [], + "answer": "×", + "solution": "【分析】长方形是长长方方的,有 4 条直直的边,对边相等;正方形是方方正正的,有 4 条直直的边,每条边都相等。图 1 拼成的是长方形;图 2 拼成的是正方形,由此解答.\n\n![](images/bfc89519658d50fd51b74fb186b1150eb8ea80dcddb2a5f9d290fb17dc7295b2.jpg)\n\n![](images/56bfcd0ec81e061671312c73fff4858f9c528141da8d824fd391e4398aedff8c.jpg)\n\n【详解】由分析可知,两个相同的长方形可能拼出正方形。原题说法错误。故答案为: ×", + "knowledge_points": [ + "平面图形的拼接", + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "23-24 一年级下·湖北武汉·期末" + }, + { + "id": "87", + "unit": "认识图形", + "question_type": "判断题", + "difficulty": 0.85, + "question": "七巧板是我国的一种传统益智玩具,其中正方形有1块,平行四边形有1块,三角形有5块。( )", + "options": [], + "answer": "√", + "solution": "【分析】正方形有四条边,四个角,四条边一样长;三角形有三条边,三个角;再结合生活经验认出平行四边形即可.\n【详解】由分析可知:七巧板中正方形有 1 块,平行四边形有 1 块,三角形有 5 块,原题说法正确。故答案为: √", + "knowledge_points": [ + "平行四边形的初步认识", + "长方形,正方形,三角形和圆的初步认识", + "用七巧板拼图形" + ], + "source": "23-24一年级下·湖北武汉·期末" + }, + { + "id": "88", + "unit": "认识图形", + "question_type": "判断题", + "difficulty": 0.85, + "question": "七巧板是我国的一种传统的益智玩具,由 7 块板组成,用它们可以拼出千变万化的图案。( )", + "options": [], + "answer": "√", + "solution": "【分析】三角形有 3 条直直的边;正方形是方方正正的,有 4 条直直的边,每条边都相等;平行四边形有 4 条直直的边,对边相等,有 2 条同方向的斜边。如图为七巧板。它由 5 块三角形, 1 块正方形和 1 块平行四边形的板组成,可以拼不同的图案,由此解答。![](images/38cf0c329d802584717c82237140733a36b5536dcc6d41b7f2619d9bb4473168.jpg)\n【详解】由分析可知,七巧板是我国的一种传统的益智玩具,由 7 块板组成,用它们可以拼出千变万化的图案。例如:可以拼成小狗,拼成人等。原题说法正确。![](images/a45087c357308d9af651b831586e39cae77191a542fb55357524319d2df21f0f.jpg)故答案为: √", + "knowledge_points": [ + "平面图形的拼接", + "平行四边形的初步认识", + "长方形,正方形,三角形和圆的初步认识", + "用七巧板拼图形" + ], + "source": "23-24一年级下·河南南阳·期末" + }, + { + "id": "89", + "unit": "认识图形", + "question_type": "判断题", + "difficulty": 0.85, + "question": "一套七巧板中有 1 个正方形,1 个平行四边形和 5 个三角形。( )", + "options": [], + "answer": "√", + "solution": "【分析】正方形是方方正正的,有 4 条直直的边,每条边都相等;三角形有 3 条直直的边;平行四边形有 4 条直直的边,对边相等,有 2 条同方向的斜边。由此数出七巧板中各图形的数量即可.\n【详解】如图为七巧板,其中有 1 个正方形,1 个平行四边形和 5 个三角形,原题说法正确。![](images/c9e9d8ce73a6b1621b812ce661c8a8dce626d9c70db8d61b8cab7175381f8514.jpg)故答案为: √", + "knowledge_points": [ + "平行四边形的初步认识", + "长方形,正方形,三角形和圆的初步认识", + "用七巧板拼图形" + ], + "source": "23-24 一年级下·四川凉山·期末" + }, + { + "id": "90", + "unit": "认识图形", + "question_type": "判断题", + "difficulty": 0.85, + "question": "把一张正方形纸对折一次得到的图形一定是长方形。( )", + "options": [], + "answer": "×", + "solution": "【分析】根据题意:如图![](images/1a5859aa310bac13e81697ed9977e04eb92dd28d3ddb4bd7f430e3b97068ef81.jpg)正方形的纸可以按照边上的虚线对折,对折一次得到的是长方形,如图![](images/5b31a273c9433baeaa54a7209e2f44653334b799c1842f60f5ad99b6460f5f5d.jpg)也可以按照角的虚线对折,对折一次得到的是三角形,据此解答.\n【详解】根据分析:把一张正方形纸对折一次得到的图形可能是长方形。原题说法错误。故答案为: ×", + "knowledge_points": [ + "图形的折叠问题", + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "23-24 一年级下·河北邢台·期末" + }, + { + "id": "91", + "unit": "认识图形", + "question_type": "判断题", + "difficulty": 0.85, + "question": "把一个正方形斜对角对齐后对折形成两个三角形。( )", + "options": [], + "answer": "√", + "solution": "【分析】正方形是正正方方的,由4条边围成,且4条边都一样长;三角形由 3 条线段首尾依次连接而成的封闭图形。把一个正方形斜对角对齐后对折形成两个三角形 (如下图)。![](images/d03937e63f084bbc8ae3dbeafb984ed1da4f88659d2d7d6f6840d25428cbc8ba.jpg)\n【详解】由题意分析得:把一个正方形斜对角对齐后对折形成两个三角形;此说法正确。故答案为: √", + "knowledge_points": [ + "图形的折叠问题", + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "22-23一年级下·河南驻马店·期末" + }, + { + "id": "92", + "unit": "认识图形", + "question_type": "判断题", + "difficulty": 0.85, + "question": "摆一个三角形,最少用三根小棒。( )", + "options": [], + "answer": "√", + "solution": "【分析】三角形是由3条直直的线首尾依次连接而成的封闭图形,据此判断即可.\n【详解】由分析可得,摆一个三角形,最少用三根小棒,原题说法正确。故答案为:√", + "knowledge_points": [ + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "23-24 一年级下·河南周口·期末" + }, + { + "id": "93", + "unit": "认识图形", + "question_type": "判断题", + "difficulty": 0.85, + "question": "妈妈帮小明买了一个足球,这个足球是一个圆形。( )", + "options": [], + "answer": "×", + "solution": "【分析】圆形由一条曲线围成。球没有平面可以向任意方向滚动;根据圆形和球的概念判断即可.\n【详解】由分析可得,妈妈帮小明买了一个足球,这个足球应该是一个球形。原题说法错误。故答案为: ×", + "knowledge_points": [ + "立体图形的认识", + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "22-23一年级下·江西吉安·期末" + }, + { + "id": "94", + "unit": "认识图形", + "question_type": "判断题", + "difficulty": 0.85, + "question": "在![](images/2025-12-09%20210453.jpg)中有 2 个三角形。( )", + "options": [], + "answer": "×", + "solution": "【分析】从图上可得:单个的三角形有 2 个,两部分组成的有 1 个,然后把个数相加即可.\n【详解】2 + 1 = 3 (个),即在该图中有 3 个三角形,所以原题说法错误。故答案为: ×", + "knowledge_points": [ + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "23-24一年级下·河北廊坊·期末" + }, + { + "id": "95", + "unit": "认识图形", + "question_type": "判断题", + "difficulty": 0.85, + "question": "两个三角形有可能拼成一个正方形。( )", + "options": [], + "answer": "√", + "solution": "【分析】三角形有 3 条直直的边;正方形是方方正正的,有 4 条直直的边,每条边都相等。如图,两个三角形可以拼成正方形。![](images/639fdd87b0e8c408413348685372a52354b2884f24ae37225a2483b5f0a99466.jpg)\n【详解】由分析可知,两个三角形有可能拼成一个正方形。原题说法正确。故答案为: √", + "knowledge_points": [ + "平面图形的拼接", + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "23-24 一年级下·河南南阳·期末" + }, + { + "id": "96", + "unit": "认识图形", + "question_type": "判断题", + "difficulty": 0.85, + "question": "一套七巧板有 7 块,其中有 1 个正方形, 1 个平行四边形, 5 个三角形。( )", + "options": [], + "answer": "√", + "solution": "【分析】正方形是方方正正的,有4条直直的边,每条边都相等;平行四边形有 4 条直直的边,对边相等,有 2 条同方向的斜边;三角形有 3 条直直的边。如图为七巧板,有 5 个三角形, 1 个正方形和 1 个平行四边形组成,由此解答。![](images/6cb6d428d543fe4405ee5a364d94453e769e7debe42b6479be19eb6c28b28c8c.jpg)\n【详解】一套七巧板有 7 块,其中有 1 个正方形, 1 个平行四边形, 5 个三角形。原题说法正确。故答案为: √", + "knowledge_points": [ + "平行四边形的初步认识", + "长方形,正方形,三角形和圆的初步认识", + "用七巧板拼图形" + ], + "source": "23-24 一年级下·贵州铜仁·期末" + }, + { + "id": "97", + "unit": "认识图形", + "question_type": "判断题", + "difficulty": 0.85, + "question": "一个四边形对边相等,这个四边形一定是长方形。( )", + "options": [], + "answer": "×", + "solution": "【分析】长方形有四条边,4个角都是直角且对边相等。平行四边形有四条边对边相等且平行。则对边相等的四边形可能是长方形,平行四边形或者其他四边形.\n【详解】一个四边形对边相等,这个四边形可能是长方形,原题干说法错误。故答案为: ×", + "knowledge_points": [ + "长方形的概念及特点", + "平行四边形的概念及特点" + ], + "source": "23-24 二年级下·广东韶关·期末" + }, + { + "id": "98", + "unit": "认识图形", + "question_type": "判断题", + "difficulty": 0.85, + "question": "摆 1 个 △ 最少要用 3 根小棒,摆2个不相连的 △ 最少要用6根小棒。( )", + "options": [], + "answer": "√", + "solution": "【分析】摆 1 个 △ 最少要用 3 根小棒,摆 2 个不相连的 △ 最少要用 (3 + 3 = 6) 根小棒;据此解决。不相连的三角形,就是一个一个分开的三角形,每个三角形至少需要 3 根小棒才能摆出来.\n【详解】由题意分析得:摆 1 个 △ 最少要用 3 根小棒,摆 2 个不相连的 △ 最少要用 6根小棒;此说法正确。故答案为: √", + "knowledge_points": [ + "6 的加减法", + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "23-24 一年级下·湖南·期末" + }, + { + "id": "99", + "unit": "认识图形", + "question_type": "解答题", + "difficulty": 0.85, + "question": "下图中有多少个三角形。\n\n![](images/1827658ec5a4277786d62ea41e7d69e56bce24aad61ea779db10ac8c79bc2eee.jpg)", + "options": [], + "answer": "6个", + "solution": "【分析】在三角形比较多的情况下,数三角形要按照一定的顺序。先数基本的三角形,有 3 个;再数由 2 个基本三角形组成的三角形,有 2 个;由 3 个基本三角形组成的三角形,有 1 个;然后全部加起来,求出和,即可解决.\n【详解】3+2+1=6(个)。答:图中有6个三角形。", + "knowledge_points": [ + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "23-24 二年级上·全国·课后作业" + }, + { + "id": "100", + "unit": "认识图形", + "question_type": "解答题", + "difficulty": 0.65, + "question": "下图中一共有多少个三角形。\n\n![](images/944fc96ff81dcd3be2b2b9f75cd7533e4304aea2b7a4da22db6abb92bef3b8a7.jpg)", + "options": [], + "answer": "18个", + "solution": "【分析】由 3 条边围成的闭合图形是三角形,据此判断出三角形,然后数出三角形的数量,第一层:先数单独的小三角形有 3 个,然后再数两个小三角形拼成的有 2 个,再数三个小三角形拼成的有 1 个,即第一层有 3+2+1=6(个)三角形,共三层,也就是 6+6+6=18(个)三角形,据此得出结论即可.\n【详解】3+2+1=6(个),6+6+6=18(个)。答:一共有18个三角形。", + "knowledge_points": [ + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "23-24 二年级上·全国·课后作业" + }, + { + "id": "101", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.65, + "question": "用七巧板(如图)中 4 和 6 两个图形不能拼出的是 ( ).\n\n![](images/adb565111be4eff5df79bba146686b66b5e634361ac2e2d73d7371dceb081d88.jpg)", + "options": [ + "A. 正方形", + "B. 长方形", + "C. 平行四边形", + "D. 三角形" + ], + "answer": "B", + "solution": "【分析】4和6是两个一样大的三角形,这两个一样的三角形可以拼成正方形,平行四边形,三角形.\n【详解】A。可以拼出正方形,错误;B. 不能拼出长方形,因为这是两个一样大的三角形,拼出来的是正方形,每条边都一样长,正确;C. 可以拼出三角形平行四边形,错误;D. 可以拼出三角形,错误;故答案为: B", + "knowledge_points": [ + "用七巧板拼图形", + "平面图形的拼接" + ], + "source": "23-24一年级下·浙江杭州·期末" + }, + { + "id": "102", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "用两个一样的三角形不可能拼成的图形是 ( )。", + "options": [ + "A. 圆", + "B. 平行四边形", + "C. 三角形" + ], + "answer": "A", + "solution": "【分析】平行四边形是由4条边围成,且对边一样长;三角形由3条线段首尾依次连接而成的封闭图形;圆形由一条曲线围成。用两个相同的三角形可以拼成三角形,也可以拼成平行四边形(如下图),但不能拼成圆.\n![](images/0c43145b8b7e718df076701369de1fc8ce00c7d078b369eff023f4fdaccd6068.jpg)\n![](images/7b001f2edeb8dc66f51192f13b97f3e91ac6e2ca62a3bbec589583e7692d5449.jpg)\n【详解】由题意分析得:用两个一样的三角形不可能拼成的图形是圆。故答案为: A", + "knowledge_points": [ + "平行四边形的概念及特点", + "长方形,正方形,三角形和圆的初步认识", + "平面图形的拼接" + ], + "source": "23-24 一年级下·广东汕头·期末" + }, + { + "id": "103", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.65, + "question": "用下面图形折成一个正方体,\"数\"的对面是( ).\n![](images/2025-12-10%20195239.jpg)", + "options": [ + "A. 我", + "B. 是", + "C. 冠", + "D. 军" + ], + "answer": "A", + "solution": "【分析】根据题图,正方体的对立面不相邻,对立面之间必定间隔一个面.\"我\"和\"数\"是对立面,\"是\"和\"学\"是对立面,\"冠\"和\"军\"是对立面,据此解答.\n【详解】根据分析:用下面图形折成一个正方体,\"数\"的对面是\"我\"。故答案为:A", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "23-24 一年级下·山东菏泽·期末" + }, + { + "id": "104", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.65, + "question": "用物体 ( ) 可以画出  ○  。", + "options": [ + "A. 正方体", + "B. 长方体", + "C. 圆柱体", + "D. 球体" + ], + "answer": "C", + "solution": "【分析】物体上有圆形面的能画出 ○ ,据此得出结论即可.\n【详解】根据分析知:圆柱体可以画  ○,故答案为: C", + "knowledge_points": [ + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "23-24 一年级下·山东菏泽·期末" + }, + { + "id": "105", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "两个完全一样的 ( ) 一定拼成的是一个长方形。", + "options": [ + "A. 正方形", + "B. 长方形", + "C. 三角形" + ], + "answer": "A", + "solution": "【分析】把两个完全一样的正方形,无论怎么拼都能拼成长方形。据此解答即可.\n【详解】据分析可知:两个完全一样的正方形一定拼成的是一个长方形。故答案为:A", + "knowledge_points": [ + "长方形,正方形,三角形和圆的初步认识", + "平面图形的拼接" + ], + "source": "23-24 一年级下·甘肃陇南·期末" + }, + { + "id": "106", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.65, + "question": "用三个等腰直角三角形不能拼成的图形是 ( )。", + "options": [ + "A. ![](images/d0f00b7ec6ce3f81e628458881a79a8e9bb552ae90b3cb2a82494a06ff56de23.jpg)(图a)", + "B. ![](images/c5d1bd2185f28ed198087a343fb7fab8fdb4ff81490cddf44a671b14894df387.jpg)(图b)", + "C. ![](images/90f901213b0863f54b774a433d90d1d74aea08235e0277f1228351d725030013.jpg)(图c)" + ], + "answer": "B", + "solution": "【分析】三角形有 3 条直直的边。拼成的图形也一定有直直的边。由此依次作图拼一拼即可.\n【详解】A。 可以用三个等腰直角三角形拼成图a;B. 不能用三个等腰直角三角形拼成图b。 C. 可以用三个等腰直角三角形拼成图c。用三个等腰直角三角形不能拼成的图形是图b 。故答案为: B", + "knowledge_points": [ + "长方形,正方形,三角形和圆的初步认识", + "平面图形的拼接" + ], + "source": "23-24 一年级下·内蒙古鄂尔多斯·期末" + }, + { + "id": "107", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "下面各图形剪成大小相等的两部分,不能得到三角形的是 ( )。", + "options": [ + "A. 正方形", + "B. 长方形", + "C. 圆形", + "D. 等边三角形" + ], + "answer": "C", + "solution": "【分析】三角形有 3 条直直的边,根据题意作图,选择不能分成相同的两个三角形的即可.\n【详解】A。![](images/2025-12-10%20200826.jpg)可以分成两个相等的三角形;B。![](images/2025-12-10%20200850.jpg)可以分成两个相等的三角形;C。![](images/2025-12-10%20200906.jpg)不能得到三角形;D。![](images/2025-12-10%20200931.jpg)可以分成两个相等的三角形。不能得到三角形的是圆形。故答案为: C", + "knowledge_points": [ + "平面图形的分割", + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "23-24 一年级下·广东东莞·期末" + }, + { + "id": "108", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.65, + "question": "七巧板中一共有( )块板。", + "options": [ + "A. 4", + "B. 5", + "C. 7" + ], + "answer": "C", + "solution": "【分析】根据七巧板中有 5 个三角形, 1 个正方形, 1 个平行四边形,共有 7 块板.\n【详解】根据分析知:七巧板中一共有7块板。故答案为: C", + "knowledge_points": [ + "用七巧板拼图形", + "平面图形的拼接" + ], + "source": "23-24 一年级下·山东临沂·期末" + }, + { + "id": "109", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.65, + "question": "摆一个正方形,你会选择第 ( ) 组小棒。", + "options": [ + "A. ![](images/dd8c79205323f531166b7ae4e11a19600040f1a5f9a9787c7477e32e11173487.jpg)", + "B. ![](images/860704b00e19718930f52f9be7b6d1e0b82db00e7dd82bb802ac91b65353f40a.jpg)", + "C. ![](images/f10376092b2b64f2d881e7f61c158a7fb5befc83fad6f90c8cbda8d545c8482e.jpg)" + ], + "answer": "A", + "solution": "【分析】正方形的四条边同样长,要摆一个正方形选四根同样长的小棒,据此得出结论即可.\n【详解】根据分析知,选四根同样长的小棒。故答案为:A", + "knowledge_points": [ + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "23-24一年级下·浙江宁波·期末" + }, + { + "id": "110", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "下图中停车位的形状是 ( ).\n\n![](images/61b6d76c3bb101501ce085cef01ddd594c0dce0668d50bb799132834fa6b262b.jpg)", + "options": [ + "A. 正方形", + "B. 长方形", + "C. 平行四边形" + ], + "answer": "C", + "solution": "【分析】正方形是方方正正的,有 4 条直直的边,每条边都相等;长方形是长长方方的,有 4 条直直的边,对边相等;平行四边形有 4 条直直的边,对边相等,有 2 条同方向的斜边。由此选择即可.\n【详解】由分析可知,图中停车位对边相等,有 2 条同方向的斜边,是平行四边形。故答案为: C", + "knowledge_points": [ + "平行四边形的初步认识", + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "23-24 一年级下·河北邯郸·期末" + }, + { + "id": "111", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.65, + "question": "我们的数学书面的形状是 ( );一元硬币的形状是 ( )。", + "options": [ + "A. 正方形; 三角形", + "B. 三角形; 圆", + "C. 长方形;圆", + "D. 圆; 长方形" + ], + "answer": "C", + "solution": "【分析】长方形是长长方方的,有四条边和四个直直的角,且两条相对的边一样长;三角形有三条边,三个角;圆是由曲线围成的,像车轮一样圆圆的;据此得出结论即可.\n【详解】根据分析知:我们的数学书面的形状是长方形;一元硬币的形状是圆。故答案为: C", + "knowledge_points": [ + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "23-24 一年级下·河北邢台·期末" + }, + { + "id": "112", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "下面的图形是由2个( )拼成的.\n\n![](images/965f157c5cb11ae78f13e5a7709f7d6ab1bc84fbbe9edab4a5d6638fdd6bfbc2.jpg)", + "options": [ + "A. 三角形", + "B. 正方形", + "C. 长方形" + ], + "answer": "A", + "solution": "【分析】长方形是四个角相等的四边形;四条边都相等,四个角都相等的四边形是正方形;三角形是由同一平面内不在同一直线上的三条线段\"首尾\"顺次连接所组成的封闭图形。据此解答.\n【详解】该图是由2个三角形拼成的。故答案为:A", + "knowledge_points": [ + "长方形,正方形,三角形和圆的初步认识", + "平面图形的拼接" + ], + "source": "23-24 一年级下·河北邢台·期末" + }, + { + "id": "113", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "用下面 ( ) 不能画出正方形。", + "options": [ + "A. ![](images/bb57d252407b1248603a22d2102674bd98209122ab961de7eaa6089a47700aa2.jpg)(图a)", + "B. ![](images/001cdd8b68650716e0b93fd293a43d37f4727077a4d16564d92db0d34443b979.jpg)(图b)", + "C. ![](images/c059f5b94235cdf78b7631d6968d0705580f83030b0374759c153d3d7ba3e56c.jpg)(图c)" + ], + "answer": "C", + "solution": "【分析】长方体是长长方方的,有 6 个平平的面,且相对的两个面大小一样(特殊情况下有四个面相同);正方体是正正方方的有平平的面;球没有平面可以任意方向滚动。根据它们的特征判别即可.\n【详解】A。图a用前后的面可以画出正方形;B。图b6个面中任意一个面都可以画出正方形;C。图c不能画出正方形。故答案为: C", + "knowledge_points": [ + "正方形的概念及特点", + "立体图形的认识" + ], + "source": "23-24 一年级下·河北邢台·期末" + }, + { + "id": "114", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.65, + "question": "用![](images/2025-12-10%20201719.jpg)做一个正方体,数字\"1\"的对面是哪个数( )。", + "options": [ + "A. 2", + "B. 5", + "C. 4" + ], + "answer": "B", + "solution": "【分析】根据正方体的展开图\"相对不相邻\"可知,1和5相对;2和4相对;3和6相对,由此解答.\n【详解】用该图做一个正方体 , 数字 \"1\" 的对面是 5 。故答案为: B", + "knowledge_points": [ + "正方体的展开图" + ], + "source": "23-24 一年级下·湖北荆州·期末" + }, + { + "id": "115", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "两个完全一样的![](images/2025-12-10%20201954.jpg)可以拼成一个( )。", + "options": [ + "A. 长方形", + "B. 圆形", + "C. 正方形" + ], + "answer": "A", + "solution": "【分析】三角形有 3 条直直的边,拼成的图形也有直直的边;每条边的长度不相同,拼出的图形不会有全部相同的边。根据题意,将图形进行拼接,选择拼接出的图形即可.\n【详解】由分析作图如下:![](images/d7b16de40c47a5ea22fad3deda09d16e4d6f3f5f69163144d1029ac9be2ea129.jpg)两个完全一样的该图形可以拼成一个长方形。故答案为:A", + "knowledge_points": [ + "长方形,正方形,三角形和圆的初步认识", + "平面图形的拼接" + ], + "source": "23-24 一年级下·河北唐山·期末" + }, + { + "id": "116", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "折一折,用![](images/2025-12-10%20202201.jpg)做一个正方体 ,\"2\"的对面是( )。", + "options": [ + "A. 1", + "B. 4", + "C. 6" + ], + "answer": "A", + "solution": "【分析】正方体展开图相对面的找法:同一层间隔一面是相对面,1和2中间隔着4,故,1和2是相对面;据此解决.\n【详解】由题意分析得:折一折,用该图做一个正方体,\"2\"的对面是\"1\"。故答案为: A", + "knowledge_points": [ + "正方体的展开图" + ], + "source": "23-24一年级下·浙江嘉兴·期末" + }, + { + "id": "117", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.65, + "question": "将正方形的纸对折一次后,可能出现的图形是 ( )。", + "options": [ + "A. 正方形", + "B. 等腰直角三角形", + "C. 平行四边形" + ], + "answer": "B", + "solution": "【分析】将正方形对折后得到的可能是长方形也可能是三角形,据此得出结论即可.\n【详解】将正方形沿虚线对折如下图:![](images/68b81454ecb6848b1936d049b802633e3abee3e137443819149c63a8692e162b.jpg)即可能出现的图形是长方形或三角形。故答案为: B", + "knowledge_points": [ + "图形的折叠问题" + ], + "source": "23-24 一年级下·河南南阳·期末" + }, + { + "id": "118", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "用 4 个同样![](images/2025-12-10%20202650.jpg)可以拼成的图形是( ).\n\n![](images/3806ed20933dbffb1737c5918350828e025e1721e1923d010d54de9e11b6e9de.jpg)\n![](images/40d4d3816ea8e13883342dcec04a60ea994d15f24624516e1592236b7dcae012.jpg)\n![](images/7b6b54aaecfd89b353758faf63af24c00cd653b3d3e7415c5c1d6f83ef30a230.jpg)", + "options": [ + "A. ①③", + "B. ①②", + "C. ②③" + ], + "answer": "A", + "solution": "【分析】三角形有 3 条直直的边,依次数出各图形是由几个 △ 拼成的即可.\n【详解】①由4个该图形拼成;②由5个该图形拼成;③由4个该图形 拼成。用 4 个同样的该图形可以拼成的图形是①③。故答案为: A", + "knowledge_points": [ + "长方形,正方形,三角形和圆的初步认识", + "平面图形的拼接" + ], + "source": "23-24 一年级下·福建福州·期末" + }, + { + "id": "119", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "用 ![](images/b40689d276af4ce8380359149219e721efa467d3080495e5610772a6f6b5851b.jpg)做一个正方体 , 1 的对面是 ( )。", + "options": [ + "A. 2", + "B. 5", + "C. 3" + ], + "answer": "A", + "solution": "【分析】根据正方体的展开图\"相对不相邻\"可知,1和2相对;4和3相对;6和5相对,由此解答.\n【详解】由分析可知,用该图形做一个正方体 ,1的对面是  2。故答案为:A", + "knowledge_points": [ + "正方体的展开图" + ], + "source": "23-24 一年级下·福建福州·期末" + }, + { + "id": "120", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "折一折,用![](images/cc6230da366d02479064681e548e211a59bdc7ffd52e9215436043d11c9d9796.jpg)做一个正方体,△的对面是( )。", + "options": [ + "A. ○", + "B. □", + "C. △" + ], + "answer": "B", + "solution": "【分析】正方体展开图相对面的找法:同一层间隔一面是相对面,△和□中间隔着○,故,△和□是相对面;据此解决即可.\n【详解】由题意分析得:折一折,用该图做一个正方体,△的对面是□。故答案为: B", + "knowledge_points": [ + "正方体的展开图" + ], + "source": "23-24 一年级下·山西阳泉·期末" + }, + { + "id": "121", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "用下图做一个正方体,数字 \"3\" 的对面是数字 ( ).\n\n![](images/4dcb9e3a7fb1a8b16753c80cf0336a6d4a9cfe35ffd45ad06d39457a4e8ddb8b.jpg)", + "options": [ + "A. 6", + "B. 2", + "C. 4" + ], + "answer": "C", + "solution": "【分析】根据正方体的展开图\"相对不相邻\"可知,1和2相对;4和3相对;6和5相对,由此解答.\n【详解】由分析可知,用该图做一个正方体,数字 \"3\" 的对面是数字 \"4\"。故答案为: C", + "knowledge_points": [ + "正方体的展开图" + ], + "source": "23-24 一年级下·河南郑州·期末" + }, + { + "id": "122", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "用![](images/accbdf194d84da425ac2c2e6957ef8b78d0a695b237469db016cb2f553019cc7.jpg)做一个正方体,\"数\"的对面是( )。", + "options": [ + "A. 手", + "B. 能", + "C. 我" + ], + "answer": "B", + "solution": "【分析】根据正方体的展开图\"相对不相邻\"可知,是和学相对;数和能相对;我和手相对,由此解答.\n【详解】由分析可知,用该图做一个正方体,\"数\"的对面是\"能\"。故答案为: B", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "23-24一年级下·河南信阳·期末" + }, + { + "id": "123", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "下面 ( ) 号图形可以画出正方形。", + "options": [ + "A. ![](images/bbfcae88fa647b03ea0bf97309f920591f5b962b0916865d209134d3b5139165.jpg)(图a)", + "B. ![](images/746798312dbb082d9f5f4e5739934adbdef48da8dfd5fcfdc835922b44e7255c.jpg)(图b)", + "C. ![](images/c35452d6f0da5c29d6adf8133c201dec7ad437d3b069e3cc1b511af054c521ef.jpg)(图c)" + ], + "answer": "C", + "solution": "【分析】要画出正方形,则图形中要有正方形的面。正方形是方方正正的,有 4 条直直的边,每条边都相等,由此选择.\n【详解】A。图a没有正方形的面,不能画出正方形;B。图b 没有正方形的面,不能画出正方形;C. 图c有正方形的面,可以画出正方形。可以画出正方形。故答案为: C", + "knowledge_points": [ + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "23-24 一年级下·河南郑州·期末" + }, + { + "id": "124", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.65, + "question": "将一张正方形纸对折,沿折痕剪成两部分。其中一部分不可能是下面的 ( )。", + "options": [ + "A. 等边三角形", + "B. 长方形", + "C. 等腰直角三角形" + ], + "answer": "A", + "solution": "【分析】将一张正方形纸对折,折痕如图:![](images/2025-12-11%20202656.jpg)沿折痕剪成两部分,可能是长方形或等腰直角三角形,据此得出结论即可.\n【详解】根据分析知:剪成两部分后,可能是长方形或等腰直角三角形,不可能是等边三角形,故答案为: A", + "knowledge_points": [ + "平面图形的分割", + "图形的折叠问题" + ], + "source": "23-24 一年级下·河南郑州·期末" + }, + { + "id": "125", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "站在不同的位置观察物体,看到物体的形状是( )。", + "options": [ + "A. 不相同", + "B. 相同", + "C. 无法确定" + ], + "answer": "C", + "solution": "【分析】根据题意可知:站在不同的位置观察物体,因为没有告诉物体的形状,则看到物体的形状不一定相同,据此解答.\n【详解】根据分析可知:无法确定看到物体的形状。故答案为: C", + "knowledge_points": [ + "从不同位置观察单个物体" + ], + "source": "23-24一年级下·河南信阳·期末" + }, + { + "id": "126", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "用下面哪个物体能画出 \"○\"。 ( )", + "options": [ + "A. 圆锥", + "B. 正方体", + "C. 长方体" + ], + "answer": "A", + "solution": "【分析】圆锥:由一个圆和一个曲面围成,用圆锥可以画出圆;正方体:由 6 个正方形的面围成,用正方体只能画出正方形;长方体:一般的由 6 个长方形的面围成,用长方体一般只能画出长方形;特殊的长方体由2个正方形的面和4个长方形的面组成,用特殊的长方体能画出长方形和正方形;据此解决.\n【详解】由题意分析得:A. 圆锥能画出圆。 B. 正方体只能画出正方形,不能画出圆。 C. 长方体能画出长方形和正方形,不能画出圆。能画出\"○\"。故答案为:A", + "knowledge_points": [ + "长方形,正方形,三角形和圆的初步认识", + "立体图形的认识" + ], + "source": "23-24 一年级下·河南郑州·期末" + }, + { + "id": "127", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "下列图形中与其他两个不同类的是 ( )。", + "options": [ + "A. ![](images/ce5781efe468364981ecc04b3fdaaac9059336f85b7a86ded4b6724685a820e9.jpg)(图a)", + "B. ![](images/51246674832a7c20e085cbd97425cf28e3c1a407a9eb33325b93a41c9b154d9b.jpg)(图b)", + "C. ![](images/ce23099a5744604dcae9d4628eab2503a2b08d1cf4b984e3127b97fb46161946.jpg)(图c)" + ], + "answer": "C", + "solution": "【分析】长方体是长长方方的,有 6 个平平的面,且相对的两个面大小一样(特殊情况下有四个面相同),是立体图形.\n【详解】A。 图a是正方形,是平面图形;B. 图b是长方形,是平面图形;C. 图c是长方体,是立体图形。与其他两个不同类的是图c。故答案为: C", + "knowledge_points": [ + "长方形,正方形,三角形和圆的初步认识", + "立体图形的认识" + ], + "source": "23-24 一年级下·福建福州·期末" + }, + { + "id": "128", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.65, + "question": "至少用 ( ) 根同样长的小棒能拼成两个正方形。", + "options": [ + "A. 4", + "B. 7", + "C. 8" + ], + "answer": "B", + "solution": "【分析】正方形的 4 条边都相等,拼成一个正方形需要 4 根同样长的小棒,拼成两个正方形需要 8 根同样长的小棒,当这两个正方形靠在一起共用一条边的时候,可以节省一根小棒,用 7 根小棒即可拼成.\n【详解】由分析可知:至少用 7 根同样长的小棒能拼成两个正方形。故答案为: B", + "knowledge_points": [ + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "22-23一年级下·山西长治·期中" + }, + { + "id": "129", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.65, + "question": "( )个 □ 可以拼成一个大正方形。", + "options": [ + "A. 2", + "B. 4", + "C. 3" + ], + "answer": "B", + "solution": "【分析】正方形的四个边是一样长的,用□拼,则列数和行数相等,如2行2列,即4个;3行3列,即9个,据此得出结论即可.\n【详解】A。选项2个□不能拼成一个大正方形,不符合题意;![](images/6153b6c1e53c8c761919b836d48eae01d1d7cdd7b35d5f25a37d02b4676d97e9.jpg)B。 选项 4 个 □ 能拼成一个大正方形,如:符合题意;C. 选项 3 个 □ 不能拼成一个大正方形,不符合题意;故答案为: B", + "knowledge_points": [ + "长方形,正方形,三角形和圆的初步认识", + "平面图形的拼接" + ], + "source": "22-23 一年级下·浙江台州·期末" + }, + { + "id": "130", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "![](images/785b2a4e7007c1805da7bd9d0ccede26bcbed16d2081339a0de3e89e351fd2b4.jpg)的底面的形状是( )形。", + "options": [ + "A. 三角", + "B. 长方", + "C. 圆" + ], + "answer": "C", + "solution": "【分析】圆柱的上下是平平的面,上下一样粗,侧面是一个曲面。平平的面没有直直的边,是圆形。据此解答即可.\n【详解】由分析可知:该图的底面的形状是圆形。故答案为: C", + "knowledge_points": [ + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "22-23 一年级下·河南周口·期末" + }, + { + "id": "131", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.65, + "question": "用一套七巧板不能拼出的图案是 ( )。", + "options": [ + "A. 三角形", + "B. 正方形", + "C. 圆形" + ], + "answer": "C", + "solution": "【分析】如图,用七巧板拼板玩具可以拼出很多有趣的图案,七巧板由 5 个三角形,1 个平行四边形和 1 个正方形组成的,由此逐项进行分析。![](images/100eadc441d2b9e26d37187379db6042044ef51d950a478bf78d483ca24e8471.jpg)\n【详解】A。三角形,两个同样大的小三角形可以拼成一个大三角形,能拼出;B. 正方形,两个同样的同样大的小三角形可以拼成一个正方形,能拼出;C. 圆形,因为圆是一条曲线,所以用七巧板的图形无法拼出;故答案为: C", + "knowledge_points": [ + "长方形,正方形,三角形和圆的初步认识", + "用七巧板拼图形", + "平面图形的拼接" + ], + "source": "20-21一年级下·河北廊坊·期末" + }, + { + "id": "132", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "把一张正方形纸对折后剪开,我们发现一个正方形不能剪成两个相同的( )。", + "options": [ + "A. 长方形", + "B. 三角形", + "C. 平行四边形" + ], + "answer": "C", + "solution": "【分析】正方形是方方正正的,有 4 条直直的边,每条边都相等;长方形是长长方方的,有 4 条直直的边,对边相等;三角形有 3 条直直的边;平行四边形有 4 条直直的边,对边相等,有 2 条同方向的斜边。如图:正方形对折剪开后的图形有长方形和三角形,不能剪成两个相同的平行四边形.\n![](images/627bef8210381176ca601bba32b1e36611251dbbee156456539de8755d2d2d35.jpg)\n![](images/51166cd53c7fcb4e9fbb95673cf45c481de7ec8c188fa831767aac91836e32f6.jpg)\n![](images/18178739155e88cf0cb333f4ed1e1bded725bf49d0fb82761b08e30063abab1c.jpg)\n【详解】由分析可知,把一张正方形纸对折后剪开,我们发现一个正方形不能剪成两个相同的平行四边形。故答案为: C", + "knowledge_points": [ + "平行四边形的初步认识", + "平面图形的分割", + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "22-23一年级下·河北廊坊·期末" + }, + { + "id": "133", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "![](images/2025-12-11%20203807.jpg)这两个相同的三角形可以拼成一个( )。", + "options": [ + "A. 三角形", + "B. 平行四边形", + "C. 长方形" + ], + "answer": "B", + "solution": "【分析】两个完全一样的三角形可以拼成一个平行四边形(如下图)。![](images/4e1c236f17a8684f3bc043603d68e16d82d1ec5c4cbc4bc2c38a8ed6fd7851be.jpg)\n【详解】由题意分析得:这两个相同的三角形可以拼成一个平行四边形。故答案为: B", + "knowledge_points": [ + "平行四边形的概念及特点", + "长方形,正方形,三角形和圆的初步认识", + "平面图形的拼接" + ], + "source": "23-24 一年级下·全国·期末" + }, + { + "id": "134", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "用下面的 ( ) 可以画出 ○ 。", + "options": [ + "A. 圆柱体", + "B. 正方体", + "C. 长方体" + ], + "answer": "A", + "solution": "【分析】选项中哪个物体含有圆形的面就能画出 ○ 。由此解答.\n【详解】A。圆柱上下一样粗,上下面是圆,可以画出 ○ B. 正方体是方方正正的,每个面都是正方形,不能画出 ○;C. 长方体是长长方方的,没有圆形的面,不能画出 ○ 。用圆柱体可以画出 ○ 。故答案为: A", + "knowledge_points": [ + "长方形,正方形,三角形和圆的初步认识", + "立体图形的认识" + ], + "source": "19-20 一年级下·江苏连云港·期末" + }, + { + "id": "135", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.65, + "question": "用七巧板拼三角形,不能拼成三角形的是 ( )。", + "options": [ + "A. 1 和 2", + "B. 6和7", + "C. 4和5", + "D. 3,6 和 7" + ], + "answer": "C", + "solution": "【分析】七巧板是由七块板组成的,有五块等腰直角三角形(两块较小的三角形,一块中等大小的三角形和两块较大的三角形),一块正方形和一块平行四边形。拼一拼即可求解.\n【详解】A。![](images/706168cab0814fb94d5d077dd2265c50b513f7d47eccfd6f340b6db1902f6884.jpg)1 和 2 可以拼成三角形;B。![](images/c96f17152eff021cdab8581d9c9d78da86402eb43ec812cef48d71d7f17726ad.jpg)6和7可以拼成三角形;C. 4 和 5 不能拼成三角形。![](images/d903b2d231e14726a00865c4e4de5945df89716ff661789f5593fb4fbfd9d940.jpg)3,6和7可以拼成三角形。不能拼成三角形的是 4 和 5 。故答案为: C", + "knowledge_points": [ + "长方形,正方形,三角形和圆的初步认识", + "用七巧板拼图形", + "平面图形的拼接" + ], + "source": "22-23 一年级下·福建龙岩·期末" + }, + { + "id": "136", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "用两个等腰直角三角形拼图形,不能拼出来的图形是 ( )。", + "options": [ + "A. ![](images/2b9d130a1b6f08a1e1e750ac528c2e95658fced5f7ee5cf8e716b075117aac61.jpg)(图a)", + "B. ![](images/73121dc0d31860fd84fd5e08357f596a964be0df2fed64d76536625939564e38.jpg)(图b)", + "C. ![](images/8138ce9333965acd3cff4bd9fee8bc513d55efea3cc64b4b193af26b0b3ae69a.jpg)(图c)" + ], + "answer": "B", + "solution": "【分析】三角形有 3 条直直的边;正方形是方方正正的,有 4 条直直的边。题中图形为三角形,如图可以拼成三角形和正方形。由此解答。![](images/2025-12-12%20204245.jpg)\n【详解】由分析可知,用两个等腰直角三角形拼图形,不能拼出来的图形是图b。故答案为: B", + "knowledge_points": [ + "长方形,正方形,三角形和圆的初步认识", + "平面图形的拼接" + ], + "source": "23-24 一年级下·山西长治·期中" + }, + { + "id": "137", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "两个完全一样的正方形可以拼成一个 ( )。", + "options": [ + "A. 正方形", + "B. 长方形", + "C. 圆" + ], + "answer": "B", + "solution": "【分析】长方形是长长方方的,由 4 条边围成;正方形是正正方方的,由 4 条边围成。两个完全一样的正方形可以拼成一个长方形(如下图)。![](images/7b30779e72e82606fae4df46ff0564f5fcafda814fc7736192061e4764652e0c.jpg)\n【详解】由题意分析得:两个完全一样的正方形可以拼成一个长方形。故答案为: B", + "knowledge_points": [ + "长方形,正方形,三角形和圆的初步认识", + "平面图形的拼接" + ], + "source": "22-23一年级下·贵州铜仁·期末" + }, + { + "id": "138", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.65, + "question": "请问下面哪个是平行四边形 ( )。", + "options": [ + "A. ![](images/4e43c498bdae59164e5254b6bbcc8de9cf04adf69798f92ff3c518c0c8b2989f.jpg)(图a)", + "B. ![](images/157fb89d1426f2bbb1c48b683a8b26c4c8760efb8fb1a544817b6ac3351bfb68.jpg)(图b)", + "C. ![](images/949809d7b5d96e247382899a1725ffceea927bb522b7d80e44d88fbb81d38a66.jpg)(图c)" + ], + "answer": "B", + "solution": "【分析】平行四边形有四条边,相对的两个边一样长,并且向同一个方向倾斜,据此得出结论即可.\n【详解】根据分析知:图b是平行四边形。故答案为:B", + "knowledge_points": [ + "平行四边形的初步认识" + ], + "source": "23-24 二年级下·广东韶关·期中" + }, + { + "id": "139", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.65, + "question": "用![](images/bf793eaa58129064081414f4cbfa556ded43edd74708dc3b6e5a445bf1378d7a.jpg)做一个正方体,3的对面是( )。", + "options": [ + "A. 2", + "B. 4", + "C. 5", + "D. 1" + ], + "answer": "C", + "solution": "【分析】观察可知, 2 和 4 相对,3 和 5 相对,1 和 6 相对,据此解答.\n【详解】用该图做一个正方体,3 的对面是 5 。故答案为: C", + "knowledge_points": [ + "正方体的展开图" + ], + "source": "23-24 一年级下·江西九江·期中" + }, + { + "id": "140", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "用![](images/2db96cccbc07ad991077afafa64919e456478cc40e3b2a16a6db05f6aee1cc01.jpg)不能画出 ( )。", + "options": [ + "A. 正方形", + "B. 长方形", + "C. 圆形" + ], + "answer": "C", + "solution": "【分析】题中图形长长方方的,有平平的面,是长方体。前后面是方方正正的,有 4 条直直的边,每条边都相等,是正方形;4 个侧面都是长长方方的,有 4 条直直的边,对边相等,是长方形。立体图形上有哪个面,就可以画出那个面。由此解答.\n【详解】A。 前后面是正方形,可以画出正方形;B. 侧面是长方形,可以画出 长方形;C. 圆没有直直的边,长方体上没有圆形的面,不能画出圆形。用该图不能画出圆形。故答案为: C", + "knowledge_points": [ + "长方形,正方形,三角形和圆的初步认识", + "立体图形的认识" + ], + "source": "23-24 一年级下·河北保定·期中" + }, + { + "id": "141", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "给下面的图形加一条线,不能分成两个三角形的是 ( )。", + "options": [ + "A. 等边三角形", + "B. 圆形", + "C. 长方形" + ], + "answer": "B", + "solution": "【分析】三角形有 3 条直直的边,依次作图分析各选项,找到不能分成两个三角形的即可.\n【详解】A。![](images/2025-12-11%20205939.jpg)可以分成两个三角形;B. ○不能分成两个三角形;C。![](images/2025-12-11%20205951.jpg)可以分成两个三角形。不能分成两个三角形的是圆形。故答案为: B", + "knowledge_points": [ + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "23-24 一年级下·河北沧州·期中" + }, + { + "id": "142", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.65, + "question": "人民币一元硬币的正反两个面都是( )。", + "options": [ + "A. 长方形", + "B. 正方形", + "C. 圆" + ], + "answer": "C", + "solution": "【分析】三角形是由3条直直的线首尾依次连接而成的封闭图形;正方形是正正方方的,由4条边围成;长方形是长长方方的,由4条边围成;平行四边形由4条边围成,且对边一样长;圆形由一条曲线围成。根据对平面图形长方形,正方形,三角形,圆形,平行四边形的认识可知:人民币一元硬币的正反两个面都是圆形.\n【详解】由分析可得,人民币一元硬币的正反两个面都是圆形。故答案为: C", + "knowledge_points": [ + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "23-24 一年级下·湖北省直辖县级单位·期中" + }, + { + "id": "143", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.65, + "question": "如果把下图围成一个正方体, ( ) 的对面是 5.\n\n![](images/8fb6bbb5ca3f808a2b88ebfab816659bb8cbcfea6a729c679fbc6845f694a87b.jpg)", + "options": [ + "A. 1", + "B. 3", + "C. 2" + ], + "answer": "B", + "solution": "【分析】正方体相对的面不相邻, 2 和 4 相对, 3 和 5 相对, 1 和 6 相对.\n【详解】3 的对面是 5, 2 的对面是 4, 1 的对面是 6。故答案为: B", + "knowledge_points": [ + "正方体的展开图" + ], + "source": "23-24 一年级下·湖北省直辖县级单位·期中" + }, + { + "id": "144", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "把![](images/2025-12-11%20210351.jpg)沿虚线剪开,得到的图形不可能拼成( )。", + "options": [ + "A. 正方形", + "B. 平行四边形", + "C. 三角形" + ], + "answer": "A", + "solution": "【分析】有 4 条直直的边,每条边都相等的是正方形;三角形有三条直直的边;平行四边形有 4 条直直的边,对边相等,有 2 条同方向的斜边。据此拼一拼.\n【详解】A。不可能拼成正方形;B。![](images/99cbaecedb6b4eb1bbed8b161e738b324a96fe4a086263943cc4a9b370ed8177.jpg)能拼成平行四边形;C。![](images/c4838070479adedeab8740dcb6552b3c11d1e76dd14a088cf5a0b3a5efd4f1d8.jpg)能拼成三角形。把该图沿虚线剪开,得到的图形不可能拼成正方形。故答案为: A", + "knowledge_points": [ + "平行四边形的初步认识", + "长方形,正方形,三角形和圆的初步认识", + "平面图形的拼接" + ], + "source": "23-24 二年级下·河南周口·期中" + }, + { + "id": "145", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "用 2 个等腰直角三角形不能拼成下面的 ( ) 图形。", + "options": [ + "A. 正方形", + "B. 长方形", + "C. 等腰三角形" + ], + "answer": "B", + "solution": "【分析】可以通过拼一拼,画一画的方法来解决此题。长方形是长长方方的,由 4 条边围成;正方形是正正方方的,由 4 条边围成;三角形由 3 条线段首尾依次连接而成的封闭图形.\n【详解】A。用2个等腰直角三角形能拼成正方形,如图![](images/2025-12-11%20211143.jpg) B。 用2 个等腰直角三角形不能拼成长方形。C。 用 2 个等腰直角三角形能拼成等腰三角形,如图:![](images/2025-12-11%20211207.jpg);即,用 2 个等腰直角三角形不能拼成的长方形。故答案为: B", + "knowledge_points": [ + "长方形,正方形,三角形和圆的初步认识", + "平面图形的拼接" + ], + "source": "23-24 一年级下·贵州铜仁·期中" + }, + { + "id": "146", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.65, + "question": "用两个相同的 ( )可以拼成一个平行四边形。", + "options": [ + "A. 长方形", + "B. 正方形", + "C. 平行四边形" + ], + "answer": "C", + "solution": "【分析】长方形是四个内角相等的四边形;四条边都相等,四个角都相等的四边形是正方形。分别将每个选项中的图形拼一拼即可求解.\n【详解】A。![](images/fc12e34f7569dfd0851f69facc12c733fd37b6cc28660591eabcf8869c863b4b.jpg)两个相同的长方形可以拼成长方形或正方形,不能拼成一个平行四边形;B。![](images/2d26bad43786cb3f18fe0cff7cdd766af8ebe3b42de5e24d5b7bd15e468b9078.jpg)两个相同的正方形可以拼成长方形,不能拼成一个平行四边形;C。![](images/899b5861a770e37fdb085909f1095d09d4baa793490bb42237686dedc49a8152.jpg)两个相同的平行四边形可以拼成一个平行四边形。故答案为: C", + "knowledge_points": [ + "平行四边形的概念及特点", + "平面图形的拼接" + ], + "source": "23-24 一年级下·四川绵阳·期中" + }, + { + "id": "147", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "下面图形能分成两个完全一样的三角形的是 ( )。", + "options": [ + "A. ![](images/5479ad05713e3ef1564e1a5ddb416fb9e6e7c9c4e6f8f10c1f003388174e705b.jpg)(图a)", + "B. ![](images/6f61557476ceaf2940eade1290aa5c033529a357b82c6afba2d5acba6f10ddc4.jpg)(图b)", + "C. ![](images/b9a42def05998ce940781b4213817c87b1b6f005c077be015e8167c32622f76a.jpg)(图c)" + ], + "answer": "B", + "solution": "【分析】三角形有 3 条直直的边;平行四边形有 4 条直直的边,对边相等,有 2 条同方向的斜边;圆没有直直的边。由此将选项作图选出符合题意的即可.\n【详解】A。 图a不能分成两个完全一样的三角形;B。![](images/2025-12-11%20211532.jpg)可以分成两个完全一样的三角形。 C. 图c不能分成两个完全一样的三角形。能分成两个完全一样的三角形的是图b。故答案为: B", + "knowledge_points": [ + "平行四边形的初步认识", + "平面图形的分割", + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "23-24 一年级下·山西忻州·期中" + }, + { + "id": "148", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "摆一个正方形至少需要( )根同样长的小棒。", + "options": [ + "A. 3", + "B. 4", + "C. 8" + ], + "answer": "B", + "solution": "【分析】四条边都相等,四个角都相等的四边形是正方形。如图:![](images/7b2a8fc8600a26bf522507f3b3abc2d85dd989d5f7b980787ef99d0424c0d37e.jpg)\n【详解】观察可知:摆一个正方形至少需要 4 根同样长的小棒。故答案为: B", + "knowledge_points": [ + "正方形的概念及特点" + ], + "source": "23-24 一年级下·山西忻州·期中" + }, + { + "id": "149", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "把一张正方形纸对折一次,可能是 ( )。", + "options": [ + "A. 正方形", + "B. 等腰直角三角形", + "C. 圆形" + ], + "answer": "B", + "solution": "【分析】正方形是方方正正的,有 4 条直直的边,每条边都相等;长方形是长长方方的,有 4 条直直的边,对边相等;三角形有 3 条直直的边;圆没有直直的边。由此可作图解答.\n【详解】由分析作图如下:![](images/a91418a49c79ae6c8acd89f79c173eddd4853bcc8397ef351ad5b8fbe6893e98.jpg)把一张正方形纸对折一次,可能是长方形或三角形。故答案为: B", + "knowledge_points": [ + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "23-24 一年级下·浙江温州·期中" + }, + { + "id": "150", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "下列图形中,不能用两个同样的长方形组成的是 ( )。", + "options": [ + "A. 长方形", + "B. 正方形", + "C. 平行四边形" + ], + "answer": "C", + "solution": "【分析】两个同样的长方形可以组成![](images/7d7be89ccbf5af3d5c58c244335dfc2c4f53d868110ebf924bd05f51f7720a12.jpg)和![](images/d417a372400bcf481383894ddf4024fee51b3672286d81f7f5f42227dbf00fed.jpg),据此解答.\n【详解】A。两个同样的长方形能组成正方形;B. 两个同样的长方形能组成长方形;C. 两个同样的长方形不能组成平行四边形。故答案为:C", + "knowledge_points": [ + "长方形,正方形,三角形和圆的初步认识", + "平面图形的拼接" + ], + "source": "23-24 一年级下·甘肃天水·期中" + }, + { + "id": "151", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.65, + "question": "用![](images/d0a47c29dfea8e1c8d5457578e5235e2e472f77bc5c24e71ce5a7c0bc0cf5a68.jpg)做成一个正方体,数字4的对面是数字( )。", + "options": [ + "A. 5", + "B. 1", + "C. 3" + ], + "answer": "A", + "solution": "【分析】正方体展开图相对面的找法: ①同一层间隔一面是相对面, 4 和 5 中间隔着 1,故, 4 和 5 是相对面;1 和 3 中间隔着 5,故, 4 和 5 是相对面;②剩下两面必是相对面,故, 2 和 6 时相对面。据此解决.\n【详解】由题意分析得:用该图做成一个正方体,数字 4 的对面是数字 5。故答案为: A", + "knowledge_points": [ + "正方体的展开图" + ], + "source": "23-24 一年级下·广西南宁·期中" + }, + { + "id": "152", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.65, + "question": "把一张正方形纸对折一次,可能折出的图形是( )。", + "options": [ + "A. 正方形", + "B. 长方形", + "C. 平行四边形" + ], + "answer": "B", + "solution": "【分析】正方形沿着对边对折一次,可以折出长方形;沿着对角对折一次,可以折出三角形;正方形对折一次不能折出正方形或平行四边形;据此解决.\n【详解】由题意分析得:把一张正方形纸对折一次,可能折出的图形是长方形。故答案为: B", + "knowledge_points": [ + "平行四边形的初步认识", + "长方形,正方形,三角形和圆的初步认识", + "图形的折叠问题" + ], + "source": "22-23一年级下·福建福州·期中" + }, + { + "id": "153", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "用圆柱体能画出( )。", + "options": [ + "A. 长方形", + "B. 三角形", + "C. 圆形" + ], + "answer": "C", + "solution": "【分析】圆柱上下是圆,上下一样粗,侧面是曲面。圆柱中有什么样的面就能画出什么图形。由此解答.\n【详解】A。长长方方的,有4条直直的边,对边相等,是长方形,圆柱没有长方形的面,不能画出;B. 有 3 条直直的边,是三角形,圆柱没有三角形的面,不能画出;C. 没有直直的边,是圆形,圆柱上下面是圆,能画出。用圆柱体能画出圆形。故答案为: C", + "knowledge_points": [ + "长方形,正方形,三角形和圆的初步认识", + "立体图形的认识" + ], + "source": "22-23一年级下·河南南阳·期中" + }, + { + "id": "154", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.65, + "question": "把一张长方形纸剪成大小相等的两部分,有 ( ) 种剪法。", + "options": [ + "A. 2", + "B. 3", + "C. 无数" + ], + "answer": "C", + "solution": "【分析】长方形是长长方方的,有 4 条直直的边,对边相等。要想剪成大小相等的两部分,如图,可以上下对折,左右对折,或者上下左右对折的交点处,画任意一条直线剪开,由此解答.\n【详解】由分析可知,把一张长方形纸剪成大小相等的两部分,有无数种剪法。故答案为: C", + "knowledge_points": [ + "平面图形的分割", + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "23-24一年级下·福建莆田·期中" + }, + { + "id": "155", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.4, + "question": "用![](images/2ff4e273c5d5b77877008bd3ba6af8366615c5c116e65255f01d212691f8c8c3.jpg)做一个正方体,\"2\"的对面是( )。", + "options": [ + "A. 1", + "B. 4", + "C. 6" + ], + "answer": "A", + "solution": "【分析】根据正方体的展开图\"相对不相邻\"可知,1和2相对,3和5相对,4和6相对,由此解答.\n【详解】由分析可知,用该图做一个正方体,\"2\"的对面是1。故答案为: A", + "knowledge_points": [ + "正方体的展开图" + ], + "source": "23-24一年级下·浙江温州·期中" + }, + { + "id": "156", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.65, + "question": "下面各组中的两个图形,正好可以拼成一个长方形的是 ( )。", + "options": [ + "A. ![](images/7a29a699df9cf1a44c450301f9bbd51631995afc43474377390597a99d740cea.jpg)(图a)", + "B. ![](images/c81660390ffc03e026ea8c512646b49285756a3d2e68b9c9dd59e8294cb38737.jpg)(图b)", + "C. ![](images/aa4121519fb7d26b91c694ef3ad2600dace4268f6d6100f3f1d4bcc2c02cb819.jpg)(图c)" + ], + "answer": "C", + "solution": "【分析】长方形是长长方方的,有 4 条直直的边,对边相等;三角形有 3 条直直的边;平行四边形有 4 条直直的边,对边相等,有 2 条斜边。由此作图看哪个选项可以拼成长方形即可.\n【详解】A。 图a拼成的是平行四边形;B。图b拼成的是平行四边形;C。图c拼成的是长方形。正好可以拼成一个长方形的是图c。故答案为: C", + "knowledge_points": [ + "平行四边形的初步认识", + "长方形,正方形,三角形和圆的初步认识", + "平面图形的拼接" + ], + "source": "23-24 一年级下·浙江温州·期中" + }, + { + "id": "157", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "用![](images/dfde899d988f11497fe1f47abf2dc50d04df38f4df01e6e5ef9639b3db3a4d21.jpg)做成一个正方体,数字\"3\"的对面是( )。", + "options": [ + "A. 2", + "B. 5", + "C. 1" + ], + "answer": "B", + "solution": "【分析】根据正方体的展开图\"相对不相邻\"可知,2和4相对,3和5相对,1和6相对,由此解答.\n【详解】由分析可知,用该图做成一个正方体,数字\"3\"的对面是5。故答案为:B", + "knowledge_points": [ + "正方体的展开图" + ], + "source": "23-24 一年级下·江西宜春·期中" + }, + { + "id": "158", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "一副七巧板中有( )种不同的图形。", + "options": [ + "A. 2", + "B. 4", + "C. 3" + ], + "answer": "C", + "solution": "【分析】根据七巧板的特征可知,七巧板有 5 个等腰直角三角形, 1 个正方形, 1 个平行四边形,故有 3 种不同形状的图形.\n【详解】由分析可知:一副七巧板中有3种不同的图形;故答案为: C", + "knowledge_points": [ + "长方形,正方形,三角形和圆的初步认识", + "用七巧板拼图形" + ], + "source": "17-18一年级下·全国·课后作业" + }, + { + "id": "159", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "用一个正方形和两个等腰直角三角形拼成一个长方形,拼法 ( ) 是正确的。", + "options": [ + "A. ![](images/83ef7df0eb4a26fd0c15a610a7a8533eea9e28e7b3b1b3d2c21611fc4bb1e215.jpg)(图a)", + "B. ![](images/08133887a9abe4ddb2ed97d5c4d831cc258245f03a97c4878f4bc9c720d00edd.jpg)(图b)", + "C. ![](images/711bf4309a0227b686959750b0bc93ee51f8a7d8e7cea66af46b89780c7bb785.jpg)(图c)" + ], + "answer": "C", + "solution": "【分析】长方形是长长方方的,由 4 条边围成,边都是对边相等的;根据长方形的特征,找出选项中,符合要求的答案即可.\n【详解】A。 图a,这不是长方形;B。图b,这不是长方形;C. 图c, 这是长方形,且是用一个正方形和两个等腰直角三角形拼成的;即,用一个正方形和两个等腰直角三角形拼成一个长方形,拼法图c是正确的。故答案为: C", + "knowledge_points": [ + "长方形,正方形,三角形和圆的初步认识", + "平面图形的拼接" + ], + "source": "23-24 一年级下·河南新乡·期中" + }, + { + "id": "160", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.65, + "question": "下图中一共有 ( )个三角形.\n\n![](images/96bedaa26614c5348464df844f39d95382b40b032b94900d16502134363ec429.jpg)", + "options": [ + "A. 4", + "B. 5", + "C. 6" + ], + "answer": "A", + "solution": "【分析】三角形是由三条边围成的,有三个角,注意不要落下拼成的较大的三角形,据此得出结论即可.\n【详解】根据分析知:图中有 3 个较小的三角形,还有 1 个较大的三角形,共有 4 个三角形。故答案为: A", + "knowledge_points": [ + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "17-18 一年级下·全国·单元测试" + }, + { + "id": "161", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "下图中有 ( ) 个长方形.\n\n![](images/d1f7623a3ae6e3a7869522de8a982e0b659aa6b7f01b17d9972566c018dc3fa6.jpg)", + "options": [ + "A. 8", + "B. 10", + "C. 12" + ], + "answer": "B", + "solution": "【分析】长方形是由四条边首尾依次连接围成的封闭图形,对边相等。由此数出数量即可.\n【详解】图中单独的小长方形有 5 个;2 个小长方形组成的大长方形有 1 个;3 个小长方形组成的大长方形有 2 个;4个小长方形组成的大长方形有 1 个;5 个小长方形组成的大长方形有 1 个。一共有 5 + 1 + 2 + 1 + 1 = 10 (个) 。图中有 10 个长方形。故答案为: B", + "knowledge_points": [ + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "23-24 一年级下·河南周口·期中" + }, + { + "id": "162", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "在正方形中画一条线,不能使它变成两个同样的 ( )。", + "options": [ + "A. 正方形", + "B. 长方形", + "C. 三角形" + ], + "answer": "A", + "solution": "【分析】正方形是由四条边首尾依次连接组成的封闭图形,四条边都相等;长方形是由四条边首尾依次连接组成的封闭图形,对边相等;三角形是由三条边首尾依次连接组成的封闭图形;由此可作图选择即可.\n【详解】由分析作图如下:\n![](images/56e7f5ae40134bdcada84d3c9bd88b4950bdf90d41913c530f1b3f8b48bac042.jpg)\n\n![](images/04a87c8db0ca431e57d7141895bfad00d705f977af66cce7fac9c3cc32ab309f.jpg)\n\n在正方形中画一条线,能使它变成两个同样的三角形和长方形,不能变成两个同样的正方形。故答案为: A", + "knowledge_points": [ + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "23-24 一年级下·福建福州·期中" + }, + { + "id": "163", + "unit": "认识图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "用![](images/7ec4cef4c012855aef37eeed7a1c7a648ac9baab71c4cb5f94ae3ea69a469d0e.jpg)做成一个正方体,数字\"2\"的对面是数字( )。", + "options": [], + "answer": "6", + "solution": "【分析】根据正方体的展开图\"相对不相邻\"可知,1和4相对,2和6相对,3和5相对,由此解答.\n【详解】用该图做一个正方体,数字\"2\"的对面是数字6。", + "knowledge_points": [ + "正方体的展开图" + ], + "source": "23-24一年级下·浙江台州·期末" + }, + { + "id": "164", + "unit": "认识图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "把一张正方形纸对折后剪开,我发现:一个正方形能剪成两个相同的( )形,还能剪成两个相同的( )形。", + "options": [], + "answer": "长方;三角", + "solution": "【分析】将一个正方形按对边对折一次折成相等的两部分是长方形,按四个角对折一次折成相等的两部分是三角形,所以这相等的两部分的图形不可能是正方形,据此解答.\n【详解】把一张正方形纸对折后剪开,我发现:一个正方形能剪成两个相同的长方形,还能剪成两个相同的三角形。", + "knowledge_points": [ + "平面图形的分割", + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "23-24一年级下·河南三门峡·期末" + }, + { + "id": "165", + "unit": "认识图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "如图.\n\n![](images/26bfaafc14d46fa4981b29723a8ac6bf1f55705ec8ab67813bf0dd70b5d11b32.jpg)\n\n(1)在这副七巧板中,( )号图形和( )号图形完全一样,( )号图形和( )号图形完全一样.\n(2)在这副七巧板中,1号图形和2号图形可以拼成( )形。", + "options": [], + "answer": "1;2;4;6;三角/正方/平行四边", + "solution": "【分析】(1)由图可知,七巧板中有 2 组三角形完全一样,分别是 1 号和 2 号, 4 号和 6 号;(2) 1 号和 2 号可以拼成正方形,三角形或平行四边形.\n【详解】(1)在这副七巧板中,1 号图形和 2 号图形完全一样,4 号图形和 6 号图形完全一样。(2) 在这副七巧板中, 1 号图形和 2 号图形可以拼成三角形或正方形或平行四边形。", + "knowledge_points": [ + "平行四边形的初步认识", + "长方形,正方形,三角形和圆的初步认识", + "用七巧板拼图形", + "平面图形的拼接" + ], + "source": "23-24一年级下·广东揭阳·期末" + }, + { + "id": "166", + "unit": "认识图形", + "question_type": "填空题", + "difficulty": 0.65, + "question": "小清将![](images/37c58e6f40a6916e0f3b2ab4dfebf8c04816440a31dc8a998492bc9007a2ccd6.jpg)折成一个小正方体后,1和它对面的数字2之和是( ),5 和它对面的数字之和是( )。", + "options": [], + "answer": "3;11", + "solution": "【分析】将该图折成一个小正方体后,1和2相对,5和6相对, 3 和 4 相对。用 1 + 2 即可求出 1 和它对面的数字 2 之和是多少;用 5 + 6 即可求出 5 和它对面的数字之和是多少.\n【详解】由分析得:1 + 2 = 3,5 + 6 = 11,1 和它对面的数字 2 之和是 3, 5 和它对面的数字之和是 11。", + "knowledge_points": [ + "5~2加几的进位加法", + "5以内数的加法", + "正方体的展开图" + ], + "source": "23-24一年级下·河南南阳·期末" + }, + { + "id": "167", + "unit": "认识图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "从圆柱中可以找到( )形;正方体中可以找到( )形。", + "options": [], + "answer": "圆;正方", + "solution": "【分析】圆柱:由 1 个曲面和 2 个圆形的面围成;故,从圆柱中可以找到圆形;正方体:由 6 个正方形的面围成;故,从正方体中可以找到正方形.\n【详解】由题意分析得:从圆柱中可以找到圆形;正方体中找到正方形。", + "knowledge_points": [ + "长方形,正方形,三角形和圆的初步认识", + "立体图形的认识" + ], + "source": "23-24 一年级下·河北邢台·期末" + }, + { + "id": "168", + "unit": "认识图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "一个正方形对折 1 次后,能剪成两个相同的( )形,也可以剪成两个相同的( )形。", + "options": [], + "answer": "长方;三角", + "solution": "【分析】正方形是正正方方的,有 4 条直直的边,每条边都相等;长方形是长长方方的,有 4 条直直的边,对边相等;三角形有 3 条直直的边。如图为对折后的图形,剪开是长方形和三角形,由此解答。![](images/7e20b722cec5fcb2f61c0b177e7a043c9fb869cf20678fe1fc78c1b774679e04.jpg)\n【详解】一个正方形对折 1 次后,能剪成两个相同的长方形,也可以剪成两个相同的三角形。", + "knowledge_points": [ + "平面图形的分割", + "长方形,正方形,三角形和圆的初步认识", + "图形的折叠问题" + ], + "source": "23-24 一年级下·浙江·期末" + }, + { + "id": "169", + "unit": "认识图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "下图七巧板中( )号图形是平行四边形, 5 号图形是( )。七巧板上共有( )种图形,三角形有( )个.\n\n![](images/7d91964cbd87f322cc28f171ebf62a8cecb687ff46db913697e9fb198355a88b.jpg)", + "options": [], + "answer": "6;三角形;三;5", + "solution": "【分析】四条边都相等,四个角都相等的四边形是正方形;三角形是由同一平面内不在同一直线上的三条线段\"首尾\"顺次连接所组成的封闭图形。平行四边形两组相对的边分别平行。据此观察并解答.\n【详解】如图七巧板中 6 号图形是平行四边形, 5 号图形是三角形。七巧板上共有三种图形,三角形有5个。", + "knowledge_points": [ + "平行四边形的初步认识", + "长方形,正方形,三角形和圆的初步认识", + "用七巧板拼图形" + ], + "source": "23-24 一年级下·山西阳泉·期末" + }, + { + "id": "170", + "unit": "认识图形", + "question_type": "填空题", + "difficulty": 0.65, + "question": "2 个一样的平行四边形可以拼成一个( )形。", + "options": [], + "answer": "平行四边", + "solution": "【分析】平行四边形有 4 条直直的边,对边相等,有 2 条同方向的斜边。如图,拼接在一起,拼成的还是平行四边形.\n![](images/c79d6ace4072edc195516a6a3b5201311a0332a9b11704223e20fdb5c84165af.jpg)\n![](images/24cdbd6e6c567589a92900b6fd5cd9e43952f32ca0a6727ba05d8b7adcef9c14.jpg)\n【详解】由分析可知, 2 个一样的平行四边形可以拼成一个平行四边形。", + "knowledge_points": [ + "平行四边形的初步认识", + "平面图形的拼接" + ], + "source": "23-24 一年级下·福建福州·期末" + }, + { + "id": "171", + "unit": "认识图形", + "question_type": "填空题", + "difficulty": 0.65, + "question": "用![](images/0be4c901f79c3f0a3beab32e6789eb7153b620bdb183052d25f1325dfe2e6f08.jpg)折一个正方体,\"学\"的对面是( ),\"做\"的对面是( )。", + "options": [], + "answer": "三;生", + "solution": "【分析】正方体展开图相对面的找法:①同一层间隔一面是相对面,\"三\"和\"学\"中间隔着\"好\",故,\"三\"和\"学\"是相对面;②异层间隔两面是相对面,\"争\"和\"好\"之间隔着\"做,三\",故,\"争\"和\"好\"是相对面;③剩下两面必是相对面,故,\"做\"和\"生\"时相对面.\n【详解】由题意分析得:用该图折一个正方体,\"学\"的对面是\"三\",\"做\"的对面是\"生\"。", + "knowledge_points": [ + "正方体的展开图" + ], + "source": "23-24 一年级下·河南郑州·期末" + }, + { + "id": "172", + "unit": "认识图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "我国国旗是( )形的,少先队员的红领巾是( )形的。", + "options": [], + "answer": "长方;三角", + "solution": "【分析】长方形是四个角相等的四边形;三角形是由同一平面内不在同一直线上的三条线段\"首尾\"顺次连接所组成的封闭图形。据此观察解答.\n![](images/5b469cce4e998cf3bc9ce55a897cd6587a1a45579abbd594bf05a4c25dc00fe3.jpg)(国旗)\n![](images/c0e2b54f7158cecf9e5346bb287d1594cde4bf65937bd0c0ab96714eb71c7898.jpg)(红领巾)\n【详解】我国国旗是长方形的,少先队员的红领巾是三角形的。", + "knowledge_points": [ + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "22-23一年级下·广东汕头·期末" + }, + { + "id": "173", + "unit": "认识图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "用下面的图形做一个正方体,\"勤\"字的对面是( )字,\"手\"字的对面是( )字.\n\n![](images/a9d362a15a9b7172eb3fdcf29450615c223021da5c36afc9985653619b997402.jpg)", + "options": [], + "answer": "脑;动", + "solution": "【分析】根据正方体的展开图相对不相邻可知,勤和脑相对;左边的动和多相对;上边的动和手相对,由此解答.\n【详解】用该图做一个正方体,\"勤\"字的对面是\"脑\"字,\"手\"字的对面是\"动\"字。", + "knowledge_points": [ + "正方体的展开图" + ], + "source": "23-24 一年级下·全国·期末" + }, + { + "id": "174", + "unit": "认识图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "如图是由两个( )形拼成的一个( )形.\n\n![](images/196f67ba3c0026f8ccc0418940f01a91dfca54398db24bae5f475445eccfb7d1.jpg)", + "options": [], + "answer": "三角;长方", + "solution": "【分析】长方形的特点是长长的,有2条长边,2条短边,且两组对边长度相等,如图所示: 。三角形由三条边围成,如图所示: , 据此解答.\n【详解】如图是由两个三角形拼成的一个长方形。", + "knowledge_points": [ + "长方形,正方形,三角形和圆的初步认识", + "平面图形的拼接" + ], + "source": "23-24 一年级下·江西宜春·期中" + }, + { + "id": "175", + "unit": "认识图形", + "question_type": "填空题", + "difficulty": 0.65, + "question": "2 个同样的长方形一定可以拼成一个( )形。", + "options": [], + "answer": "长方", + "solution": "【分析】长方形是长长方方的,有4条直直的边,对边相等.\n如图:长边拼在一起可以拼成长方形,短边拼在一起可以拼成长方形,由此解答.\n![](images/017817fe1f9c4c55bbf0e36ca0e1f6dda0b679f2d7ebe07929bbc1eb6c6e2107.jpg)\n![](images/3590741c8d0e6f0ad86e69687badce2b2247a2a0060e9a09c73f4d1e6c3e077c.jpg)\n【详解】由分析可知, 2 个同样的长方形一定可以拼成一个长方形。", + "knowledge_points": [ + "长方形,正方形,三角形和圆的初步认识", + "平面图形的拼接" + ], + "source": "23-24 一年级下·吉林白山·期中" + }, + { + "id": "176", + "unit": "认识图形", + "question_type": "填空题", + "difficulty": 0.65, + "question": "小林用![](images/e1ca9c334899f5f42faa215d2904072bdc116c2bd61cab527033c4ceef4aaf43.jpg)做了一个正方体,\"6\"的对面是( )。", + "options": [], + "answer": "2", + "solution": "【分析】正方体展开图相对面的找法: ①同一层间隔一面是相对面, 3 和 5 之间隔着 1,故, 3 和 5 是相对面;1 和 4之间隔着 5,故, 1 和 4 是相对面;②剩下两面必是相对面,故,2和6是相对面.\n【详解】由题意分析得:小林用该图做了一个正方体 , \"6\"的对面是\"2\"。", + "knowledge_points": [ + "正方体的展开图" + ], + "source": "23-24一年级下·山西长治·期中" + }, + { + "id": "177", + "unit": "认识图形", + "question_type": "填空题", + "difficulty": 0.65, + "question": "![](images/2025-12-11%20215224.jpg)(图1)中有( )个长方形;![](images/2025-12-11%20215242.jpg)(图2)中有( )个三角形。", + "options": [], + "answer": "3;5", + "solution": "【分析】长方形是长长方方的,有 4 条直直的边,对边相等;三角形有 3 条直直的边.\n长方形的总个数 = 2 个小的长方形 + 整个大的长方形;三角形的总个数 = 4 个小的三角形 + 1 个大的三角形.\n【详解】2 + 1 = 3(个),4 + 1 = 5 (个),图1中有3个长方形;图2中有5个三角形。", + "knowledge_points": [ + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "23-24一年级下·湖南邵阳·期中" + }, + { + "id": "178", + "unit": "认识图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "一副七巧板中有( )个正方形,( )个三角形。", + "options": [], + "answer": "1;5", + "solution": "【分析】七巧板是由七块板组成的,有五块等腰直角三角形(两块较小的三角形,一块中等大小的三角形和两块较大的三角形),一块正方形和一块平行四边形。据此解答.\n【详解】一副七巧板中有 1 个正方形,5 个三角形。", + "knowledge_points": [ + "长方形,正方形,三角形和圆的初步认识", + "用七巧板拼图形" + ], + "source": "23-24 一年级下·河南驻马店·期中" + }, + { + "id": "179", + "unit": "认识图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "用![](images/e7b526897833d019560885564f00b15379a62cfa864c32b20e9cbb07b62c38e7.jpg)折成一个正方体,\"5\"的对面是( )。", + "options": [], + "answer": "4", + "solution": "【分析】根据正方体的展开图\"相对不相邻\"可知,4和5相对;1和3相对;2和6相对。由此解答.\n【详解】用该图折成一个 正方体,\"5\"的对面是\"4\"。", + "knowledge_points": [ + "正方体的展开图" + ], + "source": "23-24 一年级下·新疆和田·期中" + }, + { + "id": "180", + "unit": "认识图形", + "question_type": "填空题", + "difficulty": 0.65, + "question": "七巧板是由( )块板组成的,有( )种图形,其中有( )个三角形,( )个正方形,( )个平行四边形。", + "options": [], + "answer": "7;3;5;1;1", + "solution": "【分析】七巧板是由 7 块板组成的,例如![](images/3848d8ab14914bb74fee36fa59cd4e46b4e08e7168456c4ce1f4d3e48ac40cb5.jpg),可以看出它有三角形,正方形,平行四边形 3 种图形,然后根据三角形,正方形,平行四边形的特征数出它们的数量即可。三角形是由 3 条直直的线依次首尾连接而成的封闭图形;正方形是正正方方的,由4条边围成;平行四边形由4条边围成,且对边一样长.\n【详解】数出分析中的七巧板中,有 5 个三角形,1 个正方形,1个平行四边形。所以七巧板是由 7 块板组成的,有 3 种图形,其中有 5 个三角形,1个正方形,1个平行四边形。", + "knowledge_points": [ + "平行四边形的初步认识", + "长方形,正方形,三角形和圆的初步认识", + "用七巧板拼图形" + ], + "source": "23-24 一年级下·湖北省直辖县级单位·期中" + }, + { + "id": "181", + "unit": "认识图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "折一折,用![](images/0557f3ac60d55cae4660866c318bd496f4e2f3f21a09f084f8d18b7d843ba077.jpg)做一个正方体 ,3 的对面是( )。", + "options": [], + "answer": "5", + "solution": "【分析】根据正方体的展开图\"相对不相邻\"可知,1和2相对,4和6相对,5和3相对,由此解答.\n【详解】折一折,用该图做一个正方体 ,3的对面是5。", + "knowledge_points": [ + "正方体的展开图" + ], + "source": "23-24 一年级下·四川乐山·期中" + }, + { + "id": "182", + "unit": "认识图形", + "question_type": "填空题", + "difficulty": 0.65, + "question": "用![](images/2025-12-11%20215855.jpg)做成一个正方体,数字3的对面是数字( )。", + "options": [], + "answer": "1", + "solution": "【分析】组成正方体后,5和6是上下相对,1和3是左右相对,2和4是前后相对,据此解答.\n【详解】填空如下:字母 3 的对面是数字(1)。", + "knowledge_points": [ + "正方体的展开图" + ], + "source": "23-24 一年级下·福建福州·期中" + }, + { + "id": "183", + "unit": "认识图形", + "question_type": "填空题", + "difficulty": 0.65, + "question": "用![](images/9697dc4538f4713acaeb92995f7499cb946a6ee5de2137787db7f54239153623.jpg)做成一个正方体 ,数字\"3\"的对面是数字( )。", + "options": [], + "answer": "1", + "solution": "【分析】正方体展开图相对面的找法: ①同一层间隔一面是相对面, 4 和 2 中间隔着 3,故, 4 和 2 是相对面;3 和 1中间隔着 2,故, 3 和 1 是相对面;②剩下两面必是相对面,故, 5 和 6 是相对面.\n【详解】由题意分析得:用该图做成一个正方体,数字\"3\"的对面是数字1。", + "knowledge_points": [ + "正方体的展开图", + "立体图形的认识" + ], + "source": "23-24 一年级下·湖南张家界·期中" + }, + { + "id": "184", + "unit": "认识图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "将一张正方形纸对折一次后剪开,能剪成两个相同的( )或两个相同的( )。", + "options": [], + "answer": "长方形;三角形", + "solution": "【分析】正方形是方方正正的,有 4 条直直的边,每条边都相等。长方形是长长方方的,有 4 条直直的边,对边相等;三角形有 3 条直直的边。如图为对折后的图形,剪开是长方形和三角形,由此解答.\n![](images/7fc2a7d2d5883ad117249dbcc8ff52a2f0092ac7096a5040e91cb791f7a6666c.jpg)\n![](images/880abfd2219cf4eb48753d9008719e6f2a25051066994a63aea377660c662c68.jpg)\n【详解】由分析可知,将一张正方形纸对折一次后剪开,能剪成两个相同的长方形或两个相同的三角形。", + "knowledge_points": [ + "平面图形的分割", + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "23-24 一年级下·福建三明·期中" + }, + { + "id": "185", + "unit": "认识图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "华伦星球的墙坏了,需要( )块砖才能把墙补好.\n\n![](images/bbc4456f9237c65d96d1499dd9c762ae8b2e9a145aa2a950753756d3d2089138.jpg)", + "options": [], + "answer": "6", + "solution": "【分析】由图示可知,第二行需要补3块砖,第三行需要补3块砖,加起来,就是一共需要补的砖数量.\n【详解】3 + 3 = 6 (块)即,需要 6 块砖才能把墙补好。", + "knowledge_points": [ + "长方形,正方形,三角形和圆的初步认识", + "平面图形的拼接" + ], + "source": "22-23 一年级下·福建福州·期中" + }, + { + "id": "186", + "unit": "认识图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "拼成一个三角形需要( )根小棒;拼成一个长方形或正方形需要( )根小棒。", + "options": [], + "answer": "3;4", + "solution": "【分析】三角形有 3 条直直的边;正方形是方方正正的,有 4 条直直的边,每条边都相等;长方形是长长方方的,有 4 条直直的边,对边相等。有几条边就需要几根小棒,由此解答.\n【详解】拼成一个三角形需要 3 根小棒;拼成一个长方形或正方形需要 4 根小棒。", + "knowledge_points": [ + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "22-23一年级下·河南南阳·期中" + }, + { + "id": "187", + "unit": "认识图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "用( )个同样的![](images/88c73e8bc315f9a22c587075bbb4e3049ad79cc8c1720ded44b517e059d93261.jpg)\n(图1),可以拼成![](images/2025-12-12%20163703.jpg)(图2)", + "options": [], + "answer": "4", + "solution": "【分析】![](images/4e239b5b5accec0a31df9e76b09ec9f6c2aefab95218bff7f78cb76bcdb4a933.jpg)观察可知,图2可以用4个同样的图1拼成.\n【详解】分析可知:用4个同样的图1,可以拼成图2。", + "knowledge_points": [ + "平面图形的拼接" + ], + "source": "22-23 一年级下·湖北荆州·期中" + }, + { + "id": "188", + "unit": "认识图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "用![](images/7e3432751647fdbc6eca82529b64560ea54d43fb954ef9e0b24d836e7c9c0c83.jpg)做成一个正方体,数字\"2\"的对面是数字( ),数字\"5\"的对面是数字( )。", + "options": [], + "answer": "4;3", + "solution": "【分析】根据正方体的展开图\"相对不相邻\"可知,2和4相对;3和5相对;1和6相对,由此解答.\n【详解】用该图做成一个正方体,数字 \"2\" 的对面是数字\"4\",数字 \"5\"的对面是数字 \"3\"。", + "knowledge_points": [ + "正方体的展开图", + "立体图形的认识" + ], + "source": "23-24 一年级下·湖南常德·期中" + }, + { + "id": "189", + "unit": "认识图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "用![](images/d51e089e1eeb8a670f49bc58116fea73e6db0e303670aa7bb815c3a2b50cba0f.jpg)\n做一个正方体 ,1的对面是( )。", + "options": [], + "answer": "3", + "solution": "【分析】根据这个图形的展开图可知:4和5相对,6和2相对,1和3相对,据此解答即可.\n【详解】据分析可知:用该图做一个 正方体, 1 的对面是 3。", + "knowledge_points": [ + "正方体的展开图" + ], + "source": "22-23 一年级下·河南南阳·期中" + }, + { + "id": "190", + "unit": "认识图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "折一折,用![](images/872a73dbcaa4833dd08d23f7671c23c91ac27f8b1747ed853cba36347ffb9c7e.jpg)做一个正方体,\"数\"的对面是( ),\"算\"的对面是( )。", + "options": [], + "answer": "我;口", + "solution": "【分析】根据正方体的展开图\"相对不相邻\"可知,我和数相对,爱和学相对,口和算相对,由此解答.\n【详解】由分析得:折一折,用该图做一个正方体,\"数\"的对面是\"我\",\"算\"的对面是\"口\"。", + "knowledge_points": [ + "正方体的展开图" + ], + "source": "23-24 一年级下·福建福州·期中" + }, + { + "id": "191", + "unit": "认识图形", + "question_type": "判断题", + "difficulty": 0.85, + "question": "![](images/f84084e60dbf26f9c8f68f4401df1bc6f12c2c314613f2c45682bae1f9688544.jpg)左图中有 4个三角形。( )", + "options": [], + "answer": "×", + "solution": "【分析】三角形有 3 条直直的边。单独的小三角形有 4 个, 4 个小三角形组成的大三角形有 1 个,一共有 4 + 1 = 5 (个).\n【详解】该图中有5个三角形。原题说法错误。故答案为: ×", + "knowledge_points": [ + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "23-24一年级下·广东潮州·期末" + }, + { + "id": "192", + "unit": "认识图形", + "question_type": "判断题", + "difficulty": 0.65, + "question": "至少要用8个相同的小正方形才能拼成一个大正方形。( )", + "options": [], + "answer": "×", + "solution": "【分析】如图:![](images/14a3b2d916f5f26471a1ce5eb74c8429daec21699022816df43e42ba04b1e028.jpg)用四个相同的小正方形能拼成一个大正方形,据此得出结论即可.\n【详解】根据分析知:至少要用 4 个相同的小正方形才能拼成一个大正方形。原题说法错误。故答案为: ×", + "knowledge_points": [ + "正方形的概念及特点", + "平面图形的拼接" + ], + "source": "23-24一年级下·新疆克孜勒苏·期末" + }, + { + "id": "193", + "unit": "认识图形", + "question_type": "判断题", + "difficulty": 0.65, + "question": "一个正方形一定可以剪成4个三角形。( )", + "options": [], + "answer": "√", + "solution": "【分析】正方形是方方正正的,有 4 条直直的边,每条边都相等。如图剪成的图形有 3 条直直的边,是三角形.\n![](images/0be0cb759491de6f4aece7075d63a9e727cfb9328adfe57fb49d6a477fe58b5a.jpg)\n【详解】由分析可知,一个正方形一定可以剪成 4 个三角形。原题说法正确。故答案为: √", + "knowledge_points": [ + "平面图形的分割", + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "23-24 一年级下·甘肃陇南·期末" + }, + { + "id": "194", + "unit": "认识图形", + "question_type": "判断题", + "difficulty": 0.65, + "question": "用4个![](images/2025-12-12%20164941.jpg)和4个![](images/3e6268354ea622ad46f6e08ecd717874b8cd43727766ee6242d19e3f8cd1f375.jpg)可以拼成一个正方形或平行四边形。( )", + "options": [], + "answer": "√", + "solution": "【分析】正方形是正正方方的,有 4 条直直的边,每条边都相等;平行四边形有 4 条直直的边,对边相等,有 2 条同方向的斜边。可作图进行判断.\n【详解】作图如下:用这些图形可以拼成一个正方形或平行四边形。原题说法正确.\n![](images/c2eb7f7d8513397aa66462f14805dba6ace547409580ca903ea670612ad64fa2.jpg)\n故答案为: √", + "knowledge_points": [ + "平行四边形的初步认识", + "长方形,正方形,三角形和圆的初步认识", + "平面图形的拼接" + ], + "source": "23-24一年级下·山东菏泽·期末" + }, + { + "id": "195", + "unit": "认识图形", + "question_type": "判断题", + "difficulty": 0.85, + "question": "正方形![](images/2025-12-12%20165306.jpg)是由 3 个长方形拼成的。( )", + "options": [], + "answer": "√", + "solution": "【分析】正方形是方方正正的,有 4 条直直的边,每条边都相等;长方形是长长方方的,有 4 条直直的边,对边相等;由此数出长方形的数量即可.\n【详解】数一数可知,该正方形是由 3 个长方形拼成的。原题说法正确。故答案为: √ ", + "knowledge_points": [ + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "23-24 一年级下·河北邯郸·期末" + }, + { + "id": "196", + "unit": "认识图形", + "question_type": "判断题", + "difficulty": 0.65, + "question": "8 个同样的![](images/99656a08fad9604fa3119010aaa953aed8f3a63db5eadb9db70e3f16a026fc4c.jpg)\n可以拼成一个正方形。( )", + "options": [], + "answer": "√", + "solution": "【分析】正方形是方方正正的,有 4 条直直的边,每条边都相等。三角形有 3 条直直的边,如图可以两个三角形的斜边拼在一起,可以拼成小正方形,8 个三角形可以拼成大正方形.\n![](images/2d81f38a490f36936975f59bf8174949e2d1dc5c0c1e042a03ac90d41383cbc8.jpg)\n![](images/a7f7b7250df80daac385f303a09490afa0f1aa378af48f8ea4babc6b73929d5c.jpg)\n【详解】由分析可知,8个同样的等腰直角三角形可以拼成一个正方形。原题说法正确。故答案为:√", + "knowledge_points": [ + "长方形,正方形,三角形和圆的初步认识", + "平面图形的拼接" + ], + "source": "23-24 一年级下·河北保定·期中" + }, + { + "id": "197", + "unit": "认识图形", + "question_type": "判断题", + "difficulty": 0.65, + "question": "两个三角形一定可以拼成一个长方形。( )", + "options": [], + "answer": "×", + "solution": "【分析】三角形有3条直直的边;长方形是长长方方的,有4条直直的边,对边相等;正方形是正正方方的,有4条直直的边,每条边都相等;平行四边形有4条直直的边,对边相等,有2条同方向的斜边。图1:两个三角形拼成的是长方形;图2:两个三角形拼成的是正方形;图3:两个三角形拼成的是平行四边形。由此解答.\n![](images/16868b02c9f32ef9b2c6abf9ed531d82209a83244caeafdf383f48a59b140ae5.jpg)\n【详解】由分析可知,两个三角形不一定可以拼成一个长方形,原题说法错误。故答案为: ×", + "knowledge_points": [ + "平行四边形的初步认识", + "长方形,正方形,三角形和圆的初步认识", + "平面图形的拼接" + ], + "source": "23-24 一年级下·吉林白山·期中" + }, + { + "id": "198", + "unit": "认识图形", + "question_type": "判断题", + "difficulty": 0.85, + "question": "用2个这样的![](images/463828f83f165de70d955d85f514e2ca5d9c200ad925fea39528d455c3193c0a.jpg)能拼成一个长方形。( )", + "options": [], + "answer": "√", + "solution": "【分析】题中图形有 3 条直直的边,是三角形。如图为拼成的图形,长长方方的,有 4 条直直的边,对边相等,是长方形。由此解答.\n![](images/e3cc3d838f65220ed65edcecfa8d04ae55e65b74e32f7cd378b5e5dc5e034c9b.jpg)\n【详解】由分析可知,用 2 个这样的三角形能拼成一个长方形。原题说法正确。故答案为: √", + "knowledge_points": [ + "长方形,正方形,三角形和圆的初步认识", + "平面图形的拼接" + ], + "source": "23-24 一年级下·河南驻马店·期中" + }, + { + "id": "199", + "unit": "认识图形", + "question_type": "判断题", + "difficulty": 0.65, + "question": "两个相同的三角形一定可以拼成一个正方形。( )", + "options": [], + "answer": "×", + "solution": "【分析】两个相同的三角形一定可以拼成一个平行四边形,不一定拼成一个正方形.\n【详解】两个相同的三角形不一定拼成一个正方形,原题干说法错误.\n故答案为: × 。", + "knowledge_points": [ + "平面图形的拼接" + ], + "source": "23-24 一年级下·湖北省直辖县级单位·期中" + }, + { + "id": "200", + "unit": "认识图形", + "question_type": "作图题", + "difficulty": 0.65, + "question": "四个完全一样的正方形可以拼成什么图形。 画出来。", + "options": [], + "answer": "见详解", + "solution": "【分析】长方形是四个角相等的四边形;四条边都相等,四个角都相等的四边形是正方形,据此作图.\n【详解】可以拼成长方形或正方形,作图如下:![](images/a9fb699964c8d35a4df726afa3ef45dccf88d92f7a02dabaa1a15366943851a5.jpg)或![](images/d46124e0dffeda840d80ad37b277f7fc9a7c530e5c79e2244483aeebdcdcfa73.jpg)\n(答案不唯一)", + "knowledge_points": [ + "长方形,正方形,三角形和圆的初步认识", + "平面图形的拼接" + ], + "source": "22-23 一年级下·甘肃庆阳·阶段练习" + }, + { + "id": "201", + "unit": "第二单元 位置与方向", + "question_type": "选择题", + "difficulty": 0.85, + "question": "用 ( ) 物体可以画出 ○ 。", + "options": [ + "A. ![](images/66d3e49f48bc229da847918effac0eaed1b4076820d812c60a7f9fb6dedfd941.jpg)\n(图a)", + "B. ![](images/65a1c6fd6f17509c67a8683ea2578caa8c533af9691877b80d3d02c5afc0bdac.jpg)\n(图b)", + "C. ![](images/88bf90484cffb0e8f55333d8467aee5f2215a8308cd79475dfac0bbd39c080a9.jpg)\n(图c)" + ], + "answer": "C", + "solution": "【分析】圆是由曲线围成的封闭图形。则选项中哪个图形如果有一面与圆相同,就可以画出圆,由此解答.\n【详解】A。 图a,没有圆形的面,画不出圆形;B. 图b,没有圆形的面,画不出圆形;C. 图c,上下面是圆形,可以画出圆形;用圆柱体可以画出圆形。故答案为: C", + "knowledge_points": [ + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "19-20 一年级下·辽宁·单元测试" + }, + { + "id": "202", + "unit": "第二单元 位置与方向", + "question_type": "选择题", + "difficulty": 0.85, + "question": "用下面的物体画圆,能画成功的是 ( )。", + "options": [ + "A. ![](images/c3569d1f42a2b26f37a41ecdaaaa2692502197a50dd237e036ae2f2482a72f14.jpg)", + "B. ![](images/a609292d260efaaf1a49c4d7bd07766dfc35553158c26ba004454b7bd39746c5.jpg)", + "C. ![](images/7c354a2072bb038de3b349a83f3faa6565d05eda9153c8263659ace2e0c017a4.jpg)" + ], + "answer": "A", + "solution": "【分析】长方体是由 6 个长方形(特殊的由 2 个正方形和 4 个长方形)的面围成,故,用长方体形状的物体不能画圆;圆柱是由 2 个圆和 1 个曲面围成,故,用圆柱体形状的物体能画圆;球由 1 个曲面围成,故,用球体形状的物体不能画圆;据此解决.\n【详解】A。用杯子的底面可以画出圆;B. 用橡皮擦不可以画出圆;C. 用篮球不可以画出圆;即,用这些物体画圆,能画成功的是选项A。故答案为: A", + "knowledge_points": [ + "长方形,正方形,三角形和圆的初步认识", + "立体图形的认识" + ], + "source": "22-23 一年级下·湖北十堰·期中" + }, + { + "id": "203", + "unit": "第二单元 位置与方向", + "question_type": "选择题", + "difficulty": 0.85, + "question": "用4个□( )拼出一个长方形。", + "options": [ + "A. 不能", + "B. 能", + "C. 不一定" + ], + "answer": "B", + "solution": "【分析】正方形是由四条边首尾依次连接围成的封闭图形,四条边都相等。长方形是由四条边首尾依次连接围成的封闭图形,对边相等。由此作图解答即可.\n【详解】由分析作图如下:用 4 个 □ 能拼出一个长方形。", + "knowledge_points": [ + "长方形,正方形,三角形和圆的初步认识", + "平面图形的拼接" + ], + "source": "22-23一年级下·吉林·期中" + }, + { + "id": "204", + "unit": "第二单元 位置与方向", + "question_type": "选择题", + "difficulty": 0.85, + "question": "看到的立体图形的一个面是正方形,它不可能是我们学过的 ( )。", + "options": [ + "A. 球", + "B. 正方体", + "C. 长方体" + ], + "answer": "A", + "solution": "【分析】根据长方体是长长方方的有平平的面,正方体是正正方方的有平平的面,球没有平面可以任意方向滚动的特征进行分类识别.\n【详解】由题意分析得:看到的立体图形的一个面是正方形,它不可能是我们学过的球。故答案为:A", + "knowledge_points": [ + "长方形,正方形,三角形和圆的初步认识", + "立体图形的认识" + ], + "source": "23-24 二年级上·山东临沂·期末" + }, + { + "id": "205", + "unit": "第二单元 位置与方向", + "question_type": "选择题", + "difficulty": 0.85, + "question": "七巧板中有 ( ) 个三角形。", + "options": [ + "A. 7", + "B. 5", + "C. 3" + ], + "answer": "B", + "solution": "【分析】![](images/1ca166c2d8d938a683e970ad9d3f88e0afe8b64896c2a5cd64076cf72d901746.jpg)三角形是由同一平面内不在同一直线上的三条线段\"首尾\"顺次连接所组成的封闭图形。据此数一数.\n【详解】七巧板中有5个三角形。故答案为: B", + "knowledge_points": [ + "用七巧板拼图形", + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "23-24 二年级上·贵州遵义·期末" + }, + { + "id": "206", + "unit": "第二单元 位置与方向", + "question_type": "选择题", + "difficulty": 0.85, + "question": "哪个图形不能用6根小棒摆出来。( )", + "options": [ + "A. 长方形", + "B. 三角形", + "C. 圆" + ], + "answer": "C", + "solution": "【分析】根据图形的特点:长用2根小棒,宽用1根小棒,可以摆成长方形;每条边用 2 根小棒,可以摆成等边三角形;圆形不能用6根同样长的小棒摆成,据此选择。本题注意考查平面图形的分类及识别,关键根据平面图形的特征做题.\n【详解】据分析可知:圆不能用6根同样长的小棒摆成。故答案为: C.", + "knowledge_points": [ + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "22-23一年级·全国·假期作业" + }, + { + "id": "207", + "unit": "第二单元 位置与方向", + "question_type": "选择题", + "difficulty": 0.65, + "question": "用 2 个同样的![](images/59a94c052327e354e16b1968999a286522003429faec58fc4ca1cf221231603e.jpg)可以拼成一个( )。", + "options": [ + "A. 长方形", + "B. 正方形", + "C. 平行四边形" + ], + "answer": "C", + "solution": "【分析】在同一个二维平面内,由两组平行线段组成的闭合图形,称为平行四边形.\n【详解】熟练掌握平行四边形的定义是解题关键。![](images/11d3fd523320682e430f995af0c5e52139a9d32b06d801a3bfec09206eec9b40.jpg)如图,将两个平行四边形并排放在一起,还是可以拼成一个平行四边形。故答案为: C", + "knowledge_points": [ + "平行四边形的概念及特点" + ], + "source": "22-23 一年级下·全国·单元测试" + }, + { + "id": "208", + "unit": "第二单元 位置与方向", + "question_type": "选择题", + "difficulty": 0.65, + "question": "用![](images/1c3aad99bac1d34dae3e7f4f8dc6c503df30eb96daaf576594a853bb75994387.jpg)折成一个正方体,\"2\"的对面是( )。", + "options": [ + "A. 6", + "B. 5", + "C. 4" + ], + "answer": "A", + "solution": "【分析】根据正方体的展开图特征可知: 1 的对面是 3,4 的对面是 5,2 的对面是 6,熟练掌握正方体展开图的特征是解题关键.\n【详解】用该图折成一个正方体,\"2\"的对面是\"6\"。故答案为:A.", + "knowledge_points": [ + "正方体的展开图" + ], + "source": "20-21 一年级下·河北保定·期末" + }, + { + "id": "209", + "unit": "第二单元 位置与方向", + "question_type": "选择题", + "difficulty": 0.65, + "question": "下面的图形都是由两个三角形拼成的,其中是平行四边形的是 ( )。", + "options": [ + "A. ![](images/ae9218e47587fee5f9b40bb08d5cc197bb42ad4da928e185dba60391b84b9b50.jpg)", + "B. ![](images/877fa4ea3a0fabf92cc925e7d0c9c88e101a086c7fc20cc91ce2aa7226a738a1.jpg)", + "C. ![](images/f56b90ab601ccc25bdb9e179cc75fbe84f9d01f8d8331ab3a979fd2bbac9ce76.jpg)" + ], + "answer": "B", + "solution": "【分析】根据平行四边形的特征,对边相等的四边形是平行四边形解答即可。本题主要考查平面图形的拼组和平面图形的认识,可以通过动手实践拼一拼等方法进行操作,可以帮我们解答此类问题.\n【详解】由分析可知: A,B,C,三个选项中,只有 B 的对边相等,所以![](images/79db76e6e3e16ef3a07343c4485e1db23bb8749d4a5136c02e8d7b109820d1c4.jpg)是平行四边形;故答案为: B", + "knowledge_points": [ + "平行四边形的初步认识", + "平面图形的拼接" + ], + "source": "21-22 一年级下·黑龙江双鸭山·期末" + }, + { + "id": "210", + "unit": "第二单元 位置与方向", + "question_type": "选择题", + "difficulty": 0.65, + "question": "把一张正方形纸对折一次,可能出现的图形是( )。", + "options": [ + "A. ![](images/b0b5c2458327496ba31b3ca656550b9e7aedb193a8e434b1d6fa6a570d78bc83.jpg)\n(图a)", + "B. ![](images/d2ff9eb55a44a71199b13f4e04577bf6137041d207f8536c49d129886229bd27.jpg)\n(图b)", + "C. ![](images/c337a018360cc95123946ab3474e205afb0fa8f86e1728da8d5402182e4bc0d0.jpg)\n(图c)" + ], + "answer": "A", + "solution": "【分析】把一张正方形纸对折一次,可能出现长方形或三角形。据此解答。本题主要考查图形的折叠问题,关键培养学生的动手操作能力.\n【详解】把一张正方形纸对折一次,可能出现的图形是图a。故答案为: A.", + "knowledge_points": [ + "长方形,正方形,三角形和圆的初步认识", + "图形的折叠问题" + ], + "source": "21-22 一年级下·重庆大渡口·期末" + }, + { + "id": "211", + "unit": "第二单元 位置与方向", + "question_type": "选择题", + "difficulty": 0.65, + "question": "能用正方体画出的图形是( )。", + "options": [ + "A. 圆形", + "B. 正方形", + "C. 三角形" + ], + "answer": "B", + "solution": "【分析】用一个正方体能画出正方形,因为正方体的六个面完全一样,都是正方形,所以能画出正方形。本题考查了正方体的特征,结合题意解答即可.\n【详解】能用正方体画出的图形是正方形。故答案为: B.", + "knowledge_points": [ + "正方体的特征", + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "21-22 一年级下·浙江温州·期末" + }, + { + "id": "212", + "unit": "第二单元 位置与方向", + "question_type": "选择题", + "difficulty": 0.85, + "question": "用硬币可以画出 ( )。", + "options": [ + "A. 长方形", + "B. 正方形", + "C. 圆形" + ], + "answer": "C", + "solution": "【分析】根据硬币的特点可知,其上下两个面是圆,所以可以画圆形。本题主要利用立体图形的特征解答.\n【详解】用硬币可以画出圆形 。故答案为: C.", + "knowledge_points": [ + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "21-22 一年级下·四川广元·期末" + }, + { + "id": "213", + "unit": "第二单元 位置与方向", + "question_type": "选择题", + "difficulty": 0.65, + "question": "下面的这面墙缺了( ) 块砖。", + "options": [ + "A. 9", + "B. 10", + "C. 8" + ], + "answer": "B", + "solution": "【分析】第二行对比第六行可知缺了 2 块砖,第三行对比第一行可知缺了 3 块砖,第四行对比第六行可知缺了 3 块砖,第五行对比第一行可知缺了 2 块砖,据此解答即可。本题考查了图形的认识,解题的关键是找到相同砌法的砖行进行对比.\n【详解】2+3+3+2=10(块)。故答案为: B.", + "knowledge_points": [ + "连加,连减(10以内)", + "平面图形的拼接" + ], + "source": "20-21 一年级下·湖北十堰·期末" + }, + { + "id": "214", + "unit": "第二单元 位置与方向", + "question_type": "选择题", + "difficulty": 0.65, + "question": "数一数,下图中有 ( ) 个平行四边形。", + "options": [ + "A. 1", + "B. 2", + "C. 3" + ], + "answer": "B", + "solution": "【分析】数平行四边形时要按照一定的顺序数,先数单个的平行四边形,再数2个四边形合成1个平行四边形的,最后数3个四边形合成1个平行四边形的。据此解答。本题考查组合图形的计数,按一定顺序不重不漏地数是解本题的关键.\n【详解】图中单个的平行四边形有 2 个,无其他合成的平行四边形。故答案为: B.", + "knowledge_points": [ + "平行四边形的初步认识" + ], + "source": "21-22 二年级下·河南周口·期末" + }, + { + "id": "215", + "unit": "第二单元 位置与方向", + "question_type": "选择题", + "difficulty": 0.65, + "question": "相同的两个三角形不可以拼成 ( )。", + "options": [ + "A. 三角形", + "B. 长方形", + "C. 正方形", + "D. 圆" + ], + "answer": "D", + "solution": "【分析】如图,两个同样的三角形可能拼成长方形,正方形和三角形,不能拼成圆,由此解答.\n![](images/b9c1f720ff89952262ead082f13a567fb766f7194627344c2d51464a22481af0.jpg)\n![](images/adfc0f867df3d1bfd209263390421a0fc40fd2720e84bc615cb09f0e18117eff.jpg)\n![](images/d941d86a8914955cedea305e9727b416ff3f93bb38571ca6fcafef5a760f1a5d.jpg)\n解答本题关键是明确平面图形拼接的特点.\n【详解】由分析可得:两个形状完全相同的三角形不可能拼成一个圆。故答案为: D.", + "knowledge_points": [ + "长方形,正方形,三角形和圆的初步认识", + "平面图形的拼接" + ], + "source": "21-22 一年级下·黑龙江鸡西·期末" + }, + { + "id": "216", + "unit": "第二单元 位置与方向", + "question_type": "选择题", + "difficulty": 0.85, + "question": "下面是长方形的是 ( )。", + "options": [ + "A. ![](images/af79ad064c362b2337ebf83af738c9eead1123e0b4699ea72cece6e39aa17d77.jpg)", + "B. ![](images/63fac09f0e12d2b65b0308a34680dbc304afb88c954de19ceea63fe41d793203.jpg)", + "C. ![](images/5a3c815bef2436a7eba6681915ef9d01966c22561fcc8f73af899508f392c4c5.jpg)" + ], + "answer": "C", + "solution": "【分析】根据长方形的特征:对边相等,四个角都是直角,进行解答即可。本题考查了长方形的认识,注意掌握各种图形的特征.\n【详解】根据长方形的特征,C选项是长方形;故答案为: C.", + "knowledge_points": [ + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "20-21 一年级下·青海玉树·期末" + }, + { + "id": "217", + "unit": "第二单元 位置与方向", + "question_type": "选择题", + "difficulty": 0.65, + "question": "用 2 个直角三角形不能拼成的图形是 ( )。", + "options": [ + "A. 长方形", + "B. 圆形", + "C. 等腰三角形" + ], + "answer": "B", + "solution": "【分析】长方形是指四个内角相等的四边形;圆指的是平面中到一个定点距离为定值的所有点的集合;三角形是由同一平面内不在同一直线上的三条线段\"首尾\"顺次连接所组成的封闭图形,据此解答。熟练掌握长方形,圆以及三角形的定义和特征是解题关键.\n【详解】用2个直角三角形能拼成长方形和等腰三角形,不能拼成圆形。故答案为:B.", + "knowledge_points": [ + "长方形,正方形,三角形和圆的初步认识", + "平面图形的拼接" + ], + "source": "20-21 一年级下·湖南永州·期中" + }, + { + "id": "218", + "unit": "第二单元 位置与方向", + "question_type": "选择题", + "difficulty": 0.65, + "question": "如图是一张纸,如果沿虚线折一折,折出来的是 ( )。", + "options": [ + "A. 三角形", + "B. 正方形", + "C. 长方形" + ], + "answer": "A", + "solution": "【分析】把一张正方形纸沿两条对角线对折,则折痕互相垂直,把正方形分成四个三角形,据此解答即可。熟练掌握折纸的方法和三角形,正方形的定义是解题关键.\n【详解】将这张纸沿虚线折一折,折出来的是三角形。故答案为:A.", + "knowledge_points": [ + "正方形的概念及特点", + "长方形,正方形,三角形和圆的初步认识", + "图形的折叠问题" + ], + "source": "21-22 一年级下·河南漯河·期末" + }, + { + "id": "219", + "unit": "第二单元 位置与方向", + "question_type": "选择题", + "difficulty": 0.65, + "question": "用 2 个同样的![](images/4c518eb6d3dc6dc4630df5196eb07951ffc5359ba801a7f72437e37b148135bc.jpg)可以拼成一个( )。", + "options": [ + "A. 长方形", + "B. 正方形", + "C. 三角形", + "D. 平行四边形" + ], + "answer": "D", + "solution": "【分析】在同一个二维平面内,由两组平行线段组成的闭合图形,称为平行四边形。熟练掌握平行四边形的定义是解题关键.\n【详解】![](images/2025-12-12%20214453.jpg)如图,将两个平行四边形并排放在一起,还是可以拼成一个平行四边形。故答案为: D.", + "knowledge_points": [ + "平行四边形的概念及特点", + "平行四边形的切拼", + "长方形,正方形,三角形和圆的初步认识", + "平面图形的拼接" + ], + "source": "21-22 一年级下·福建龙岩·期末" + }, + { + "id": "220", + "unit": "第二单元 位置与方向", + "question_type": "选择题", + "difficulty": 0.65, + "question": "折一折,用![](images/2025-12-12%20214736.jpg)做一个正方体,\"3\"的对面是( )。", + "options": [ + "A. 5", + "B. 2", + "C. 6" + ], + "answer": "A", + "solution": "【分析】由图可知,正方体的展开图相对的面再展开图中不相邻,折叠起来后 3 和 1, 2, 4, 6 相邻,所以 3 的对面是 5,由此解答。此题考查了正方体的展开图,要多锻炼自己的空间想象能力.\n【详解】用该图做一个 正方体,\"3\"的对面是5;故答案为:A.", + "knowledge_points": [ + "正方体的展开图" + ], + "source": "21-22一年级下·湖北省直辖县级单位·期末" + }, + { + "id": "221", + "unit": "第二单元 位置与方向", + "question_type": "选择题", + "difficulty": 0.65, + "question": "一副七巧板中,两个完全一样的三角形不能拼成 ( ) 形。", + "options": [ + "A. 三角", + "B. 正方", + "C. 长方" + ], + "answer": "C", + "solution": "【分析】两个完全一样的三角形,在七巧板中是两个等腰直角三角形,如果斜边挨着一起,可以拼成一个正方形,如果两个直角边挨在一起,可以拼成一个平行四边形或者三角形;不能拼成长方形。据此解答。\n【详解】七巧板中,两个完全一样的三角形可以拼成正方形、三角形、平行四边形,不能拼成长方形。故答案为: C.", + "knowledge_points": [ + "用七巧板拼图形", + "平面图形的拼接" + ], + "source": "21-22一年级下·广东阳江·期末" + }, + { + "id": "222", + "unit": "第二单元 位置与方向", + "question_type": "选择题", + "difficulty": 0.65, + "question": "用![](images/9a0edfb0c7eb0809cdc16e8ffaf88121bb18da45ee7c520f4f9bd6424c9340e1.jpg)折成一个正方体,数字 4 的对面是数字 ( )。", + "options": [ + "A. 1", + "B. 3", + "C. 2" + ], + "answer": "C", + "solution": "【分析】在同一行或者同一列中的几个数字,相对的两个数字中间隔了一个数字,所以 4 的对面是 2.\"面围成体\",在脑中用六个正方形(平面图形)折出一个正方体(立体图形),从而找出谁与谁是对立面。这样可以培养空间观念和想象力.\n【详解】根据分析可知,数字 4 对面是 2。故答案为:C.", + "knowledge_points": [ + "正方体的展开图", + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "21-22 一年级下·广东阳江·期末" + }, + { + "id": "223", + "unit": "第二单元 位置与方向", + "question_type": "选择题", + "difficulty": 0.65, + "question": "![](images/fe314b814d31c43685a5da87e4084b319a199d3615b1a45c04a93d8847980c6b.jpg)\n做成一个正方体,\"5\"的对面是( )。", + "options": [ + "A. 3", + "B. 4", + "C. 6" + ], + "answer": "C", + "solution": "【分析】假设3在底面,将4和2向上折起,左面是4,右面是2,上面是1,前面是6,后面是5,据此解答。考查学生对正方形和正方体的认识.\n【详解】A。3的对面是1;B. 4 的对面是 2;C. 6 的对面是 5 。故答案为: C.", + "knowledge_points": [ + "正方体的展开图", + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "20-21 一年级下·河南安阳·期中" + }, + { + "id": "224", + "unit": "第二单元 位置与方向", + "question_type": "选择题", + "difficulty": 0.4, + "question": "用 3 根同样长的小棒能拼成一个三角形,拼一个再大一点的三角形至少需要( ) 根这样的小棒。", + "options": [ + "A. 5", + "B. 8", + "C. 9" + ], + "answer": "A", + "solution": "【分析】3 根同样长的小棒能拼成一个三角形,至少再增加 2 根同样长的小棒,就可以拼成一个边长分别 2 , 2 , 1 的三角形了。据此解答即可。本题考查学生对三角形特点的掌握和运用.\n【详解】根据分析可得:2+2+1=5(根)。所以,拼一个再大一点的三角形至少需要 5 根这样的小棒。", + "knowledge_points": [ + "三角形三边关系", + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "21-22 一年级下·浙江台州·期末" + }, + { + "id": "225", + "unit": "第二单元 位置与方向", + "question_type": "选择题", + "difficulty": 0.85, + "question": "1 元硬币的上下两个面是 ( )。", + "options": [ + "A. 长方形", + "B. 正方形", + "C. 圆" + ], + "answer": "C", + "solution": "【分析】1元硬币的形状是一个圆柱体,它的上下两个面都是圆形。本题考查学生对立体图形特点的掌握和运用.\n【详解】1元硬币的上下两个面是圆形。故答案为: C.", + "knowledge_points": [ + "圆柱的认识及特征", + "立体图形的认识" + ], + "source": "21-22 一年级下·山东临沂·期末" + }, + { + "id": "226", + "unit": "第二单元 位置与方向", + "question_type": "选择题", + "difficulty": 0.85, + "question": "足球是 ( )。", + "options": [ + "A. 球体", + "B. 圆", + "C. 不规则图形" + ], + "answer": "A", + "solution": "【分析】足球是一个立体图形,球体是立体图形,而圆是平面图形,不规则图形也是平面图形,据此进行判断即可。本题考查学生对立体图形和平面图形的认识,要求学生牢记它们的特点.\n【详解】足球是球体,是立体图形。圆和不规则图形是平面图形。故答案为: A.", + "knowledge_points": [ + "长方形,正方形,三角形和圆的初步认识", + "四边形,五边形及多边形的初步认识", + "立体图形的认识" + ], + "source": "21-22 一年级下·广东深圳·期末" + }, + { + "id": "227", + "unit": "第二单元 位置与方向", + "question_type": "选择题", + "difficulty": 0.65, + "question": "七巧板有 ( ) 种图形。", + "options": [ + "A. 3", + "B. 7", + "C. 6" + ], + "answer": "A", + "solution": "【分析】七巧板由七块板组成,其中包括:5 块三角形,1 块正方形和 1 块平行四边形,据此即可得出答案。本题考查学生对平面图形的认识和运用.\n【详解】七巧板由 5 块三角形, 1 块正方形和 1 块平行四边形组成,一共有 3 种图形。故答案为: A.", + "knowledge_points": [ + "平行四边形的初步认识", + "用七巧板拼图形", + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "19-20 二年级下·甘肃定西·期末" + }, + { + "id": "228", + "unit": "第二单元 位置与方向", + "question_type": "选择题", + "difficulty": 0.65, + "question": "下图中 ( ) 是长方体。", + "options": [ + "A. ![](images/d9395b3910f775add3c0e1a5d10743f64eb9b3491b452b84184e63e1701466d7.jpg)\n(图a)", + "B. ![](images/26354718fb33792d1f12d26c64f39e5cc7eb2b2565014c51d49f9a7032b916c9.jpg)\n(图b)", + "C. ![](images/8b793b265546e7f2f43ca7331751e66ca2e3ece32f25231e98ed32cef60f854e.jpg)\n(图c)" + ], + "answer": "C", + "solution": "【分析】根据长方体的特征:六个面都是长方形的立体图形,进行解答即可。本题主要考查了对长方体的认识.\n【详解】A。 图a是台体;故该选项错误;B。图b 是圆柱体;故该选项错误;C。图c 是长方体,故该选项正确。故答案为: C.", + "knowledge_points": [ + "长方体的认识及特征", + "立体图形的认识" + ], + "source": "21-22 一年级下·广东韶关·期末" + }, + { + "id": "229", + "unit": "第二单元 位置与方向", + "question_type": "选择题", + "difficulty": 0.85, + "question": "相同的 2 个![](images/f34410adf1c995b432f88779f4c72f88c0369ff1c29e26bdb2d38883bbc97d9f.jpg)可以拼成( )。", + "options": [ + "A. 平行四边形", + "B. 长方形", + "C. 三角形" + ], + "answer": "B", + "solution": "【分析】利用平面图形的拼接,尝试一下即可得出结果。考查了平面图形的认识,动手操作一下更容易得出答案.\n【详解】用这样的两个图形,可以拼成以下图形:![](images/17a79952f0fb48289d4a7a1deb985801b65388003662f2414f95c2466cce472a.jpg)或者![](images/af3fa09c93e86b21141b02aadae09797a3291f5204fc4a06257c0a47d1ef3594.jpg),两种都是长方形。故答案为: B.", + "knowledge_points": [ + "平行四边形的初步认识", + "长方形,正方形,三角形和圆的初步认识", + "平面图形的拼接" + ], + "source": "21-22 一年级下·青海西宁·期末" + }, + { + "id": "230", + "unit": "第二单元 位置与方向", + "question_type": "选择题", + "difficulty": 0.65, + "question": "下面每组图形中,能拼成正方形的是( )。", + "options": [ + "A. ![](images/b7eca7e260379b8aeab78f5ab78f658dfa26a3bbc3e4d308ebfa5d070d655108.jpg)\n(图a)", + "B. ![](images/dfc080253fb30e3b597b388c26267e30c40694570576bde53eb11dbe02e287e3.jpg)\n(图b)", + "C. ![](images/bb72f02a9e169e8f16f97105702129b58221b6d3ce746d2b65359f5c7aa5f0cb.jpg)\n(图c)" + ], + "answer": "B", + "solution": "【分析】根据正方形的特点四条边相等,四个角相等,逐项分析即可。考查了正方形的初步认识和平面图形的拼组.\n【详解】A。 图a,两个图形大小不一样,不能拼成正方形;B图b, 可以拼成正方形;C。图c,可以拼成一个长方形,拼不成正方形。故答案为: B.", + "knowledge_points": [ + "长方形,正方形,三角形和圆的初步认识", + "平面图形的拼接" + ], + "source": "21-22 一年级下·青海西宁·期末" + }, + { + "id": "231", + "unit": "第二单元 位置与方向", + "question_type": "选择题", + "difficulty": 0.65, + "question": "下面图形中能拼成长方形的是 ( )。", + "options": [ + "A. ![](images/f2e4190ac5c019fa1d8af440bec3a1eb04b3fbeb860acaa5b054bd9ce1ae8e83.jpg)", + "B. ![](images/beb9c8f60ef83204e6af8f5f21298491b486ba14008a849b4bb38d68d2cb51f2.jpg)", + "C. ![](images/589fd5c034b4c8c5dac2d6c90d9feef0991da0f220bdbb33bef8561a38cfc7ed.jpg)" + ], + "answer": "C", + "solution": "【分析】根据题意需要知道长方形的特征,四个角都是直角,对边相等,据此解答。本题主要考查了长方形的认识.\n【详解】A。两个相等的三角拼接,拼成的图形它的角不是直角,不符合;B. 一个梯形和一个长方形不能拼成长方形,不符合;C. 两个长相等的长方形可以拼成长方形,符合。故答案为: C.", + "knowledge_points": [ + "长方形,正方形,三角形和圆的初步认识", + "平面图形的拼接" + ], + "source": "21-22 一年级下·福建三明·期末" + }, + { + "id": "232", + "unit": "第二单元 位置与方向", + "question_type": "选择题", + "difficulty": 0.65, + "question": "一副七巧板是由( )种图形组成的。", + "options": [ + "A. 3", + "B. 4", + "C. 7", + "D. 5" + ], + "answer": "A", + "solution": "【分析】一副七巧板里面包含 5 个三角形, 1 个正方形, 1 个平行四边形,据此解答即可。本题要求学生熟练掌握七巧板的组成图形有哪些.\n【详解】一副七巧板是由三角形,正方形,平行四边形这 3 种图形组成的。故答案为:A.", + "knowledge_points": [ + "用七巧板拼图形", + "长方形,正方形,三角形和圆的初步认识", + "平面图形的拼接" + ], + "source": "21-22 一年级下·西藏那曲·期末" + }, + { + "id": "233", + "unit": "第二单元 位置与方向", + "question_type": "选择题", + "difficulty": 0.65, + "question": "( )个这样的 △ 可以拼出\n![](images/eda0da37856208995aed06f753412e08bcf727d5c844c0bcd03e3743b4f130f9.jpg)", + "options": [ + "A. 8", + "B. 9", + "C. 10" + ], + "answer": "B", + "solution": "【分析】观察发现图形由三层组成,第一层需要三个 △ 以及两个旋转 180° 的 △ ,第二层需要两个 △ 以及一个旋转 180° 的 △ ,第三层需要一个 △ ,三层需要的 △ 相加即可得出答案.\n【详解】由分析得: (3+2)+(2+1)+1=5+3+1=9。故答案为: B", + "knowledge_points": [ + "长方形,正方形,三角形和圆的初步认识", + "平面图形的拼接" + ], + "source": "21-22 一年级下·全国·单元测试" + }, + { + "id": "234", + "unit": "第二单元 位置与方向", + "question_type": "选择题", + "difficulty": 0.65, + "question": "两块完全一样的三角尺 ( ) 可以拼成一个平行四边形。", + "options": [ + "A. 可以", + "B. 不可以" + ], + "answer": "A", + "solution": "【分析】两块完全一样的三角尺通常是两个全等的直角三角形。根据平行四边形的定义(两组对边分别平行且相等),可以通过将两个全等三角形沿一条边拼接来构造平行四边形.\n【详解】两块完全一样的三角尺,通常是相同的直角三角形。当我们将这两个三角形的对应斜边对齐并拼合,或者将它们的一条直角边相对拼接时,就可以拼成一个平行四边形。", + "knowledge_points": [ + "长方形,正方形,三角形和圆的初步认识", + "平面图形的拼接" + ], + "source": "19-20 二年级上·广西梧州·期中" + }, + { + "id": "235", + "unit": "第二单元 位置与方向", + "question_type": "选择题", + "difficulty": 0.65, + "question": "一个六边形最少能分成 ( ) 个三角形。", + "options": [ + "A. 3", + "B. 4", + "C. 5", + "D. 6" + ], + "answer": "B", + "solution": "【分析】将一个多边形分割成三角形时,最少三角形个数与多边形的边数有关。从一个顶点出发,向所有不相邻的顶点连线,可将 n 边形分成 (n-2) 个三角形.\n【详解】通过平面图形分割的方法分析:从六边形的一个顶点出发,向不相邻的顶点连线,数出三角形个数为4。故答案为:B", + "knowledge_points": [ + "平面图形的分割", + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "21-22 二年级上·福建宁德·期末" + }, + { + "id": "236", + "unit": "第二单元 位置与方向", + "question_type": "选择题", + "difficulty": 0.4, + "question": "要拼成一个大正方体,下面的图形至少还需要( )个正方体。", + "options": [ + "A. 7", + "B. 8", + "C. 9" + ], + "answer": "B", + "solution": "【分析】看图,这个大正方体由三排小正方体组成。第一排还需要 5 个小正方体,第二排还需要 3 个小正方体,利用加法求出一共还需要几个小正方体。本题考查了立体图形的拼接,有一定空间想象能力是解题的关键.\n【详解】 5 + 3 = 8 (个)所以,要拼成一个大正方体,下面的图形至少还需要 8 个正方体。故答案为: B.", + "knowledge_points": [ + "立体图形的切拼", + "立体图形的认识" + ], + "source": "20-21一年级上·河南南阳·期末" + }, + { + "id": "237", + "unit": "第二单元 位置与方向", + "question_type": "选择题", + "difficulty": 0.65, + "question": "下图中共有 ( )个长方形。", + "options": [ + "A. 7", + "B. 8", + "C. 6" + ], + "answer": "C", + "solution": "【分析】长方形是由四条边组成的四边形,对边相等,四个角都是直角。在数组合图形中的长方形数量时,应按照从小到大的顺序分类计数,先数单个的小长方形,再数由两个小长方形拼成的长方形,最后数由更多小长方形拼成的大长方形,避免遗漏或重复.\n【详解】图中单个的小长方形有3个;由两个小长方形拼成的长方形有2个(第1和第2个拼成1个,第2和第3个拼成1个);由三个小长方形拼成的大长方形有1个。总数为:3 + 2 + 1 = 6(个)。故答案为:C", + "knowledge_points": [ + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "20-21 二年级下·浙江金华·期末" + }, + { + "id": "238", + "unit": "第二单元 位置与方向", + "question_type": "选择题", + "difficulty": 0.65, + "question": "用 4 个同样的正方形不能拼成的图形是 ( )。", + "options": [ + "A. 正方形", + "B. 长方形", + "C. 三角形" + ], + "answer": "C", + "solution": "【分析】根据正方形,长方形和三角形的图形特征及拼接规律进行判断。4个同样的正方形通过不同排列可以拼成大正方形或长方形,但无法拼出由三条边围成的三角形.\n【详解】A。 把4个同样的正方形摆成2行2列,可以拼成一个大正方形;B. 把4个同样的正方形摆成1行4列或4行1列,可以拼成一个长方形;C. 三角形是由三条边围成的封闭图形,正方形的四条边均为直边且角为直角,无论如何拼接都无法形成三角形的形状。因此,不能拼成的图形是三角形。故答案为:C.", + "knowledge_points": [ + "长方形,正方形,三角形和圆的初步认识", + "平面图形的拼接" + ], + "source": "19-20 一年级下·河南南阳·期中" + }, + { + "id": "239", + "unit": "第二单元 位置与方向", + "question_type": "选择题", + "difficulty": 0.85, + "question": "下面每组中的两个三角形是完全相同的,可以拼成长方形的是哪一组。 ( )", + "options": [ + "A. ![](images/cde5e5ba7035558827afca1df11e256e1fa3b0681f11743deb075082c4abd5c4.jpg)", + "B. ![](images/c55a763fb686d5bf532646511950cbdf90eae4326209fc4bf9b07e719304102e.jpg)", + "C. ![](images/a0bda398005cc813e98e5763193f3137e754f21885b4ed147189432f85ebdefd.jpg)" + ], + "answer": "A", + "solution": "【分析】长方形有四个直角。能拼成长方形的两个三角形必须是完全相同的直角三角形,拼接时让直角边重合,才能形成四个直角.\n【详解】A。 这是两个完全相同的直角三角形,将它们的斜边或对应的直角边拼接,可以组成一个长方形;B. 这是两个普通的锐角三角形,拼接后无法形成四个直角;C. 这是两个普通的锐角三角形,拼接后也无法形成四个直角。因此,可以拼成长方形的是选项A。故答案为:A.", + "knowledge_points": [ + "平面图形的拼接" + ], + "source": "20-21 一年级下·江苏无锡·期末" + }, + { + "id": "240", + "unit": "第二单元 位置与方向", + "question_type": "选择题", + "difficulty": 0.65, + "question": "折一折,用![](images/9ebf9ce99e9483b282905d17df79895a45eaf2c90202cff4157df602dbc23757.jpg)做一个正方体,\"1\"的对面是( )。", + "options": [ + "A. 2", + "B. 3", + "C. 4" + ], + "answer": "B", + "solution": "【分析】本题考查正方体展开图的相对面判断。可以运用\"相对不相邻\"的原则,或通过空间想象进行折叠,确定每个数字对面的数字.\n【详解】将展开图进行折叠:假设\"2\"为正面,则\"5\"折上去为上面,\"6\"折下来为下面;将\"1\"向\"2\"的左边折,\"3\"向\"2\"的右边折,\"4\"向\"3\"的右边折。折叠后可以发现,\"1\"的对面是\"3\"。故答案为:B.", + "knowledge_points": [ + "正方体的展开图", + "立体图形的认识" + ], + "source": "20-21 一年级下·四川广元·期末" + }, + { + "id": "241", + "unit": "第二单元 位置与方向", + "question_type": "选择题", + "difficulty": 0.65, + "question": "正方形有 4 条边,( ) 条边相等。", + "options": [ + "A. 2", + "B. 3", + "C. 4" + ], + "answer": "C", + "solution": "【分析】根据正方形的定义和基本特征进行判断。正方形是一种特殊的四边形.\n【详解】正方形的特征是:四条边长度都相等,并且四个角都是直角。因此,正方形有4条边,并且4条边都相等。故答案为:C.", + "knowledge_points": [ + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "21-22一年级下·江西吉安·期中" + }, + { + "id": "242", + "unit": "第二单元 位置与方向", + "question_type": "选择题", + "difficulty": 0.65, + "question": "用两个完全一样的![](images/bc4eaaab8e627c9980d569ef7de4314140067d7af0f8b48ea9413f5d614cdc87.jpg)能拼出( )。", + "options": [ + "A. ![](images/72c5ef7d1cc504b832bb21b0045b490d00f7c209774ac2290b787527e3c81434.jpg)", + "B. ![](images/2ae17245c9d5d65148b0b279c7bbb27ec2621d866063202ce1bff09d2ca2db7c.jpg)", + "C. ![](images/f4f230bc6177b550ec5616d0baebc458781b59fb43fd4e9121c90b16306e8ee8.jpg)" + ], + "answer": "B", + "solution": "【分析】观察原图,这是两个完全一样的直角三角形。根据直角三角形和长方形,正方形的特征,判断它们可以拼接成的图形.\n【详解】两个完全一样的直角三角形,当将它们相等的直角边重合时,可以拼成一个长方形(或平行四边形);但图中三角形的两条直角边不等长,因此不能拼成正方形(正方形要求四边相等)。选项A是普通平行四边形,选项B是长方形,选项C是正方形。因此,用这两个三角形能拼出的是长方形,对应选项B。故答案为:B.", + "knowledge_points": [ + "平行四边形的初步认识", + "长方形,正方形,三角形和圆的初步认识", + "平面图形的拼接" + ], + "source": "20-21 一年级下·福建厦门·期末" + }, + { + "id": "243", + "unit": "第二单元 位置与方向", + "question_type": "选择题", + "difficulty": 0.65, + "question": "下面图形中,不能用两个三角形拼成的是 ( )。", + "options": [ + "A. 三角形", + "B. 圆", + "C. 平行四边形" + ], + "answer": "B", + "solution": "【分析】三角形是由三条直线段围成的图形,而圆是由一条曲线围成的图形。考虑两个三角形通过边与边的拼接,能形成哪些由直线段组成的图形.\n【详解】A。 用两个完全一样的三角形,可以将它们的一条相等边拼接,拼成一个更大的三角形;C. 用两个完全一样的三角形,同样可以将一条相等边拼接,拼成一个平行四边形。B。 圆是曲线图形,两个三角形的所有边都是直线段,无论如何拼接,只能组成由直线段构成的多边形,无法拼出圆形的曲线边界。因此,不能用两个三角形拼成的是圆。故答案为:B.", + "knowledge_points": [ + "平行四边形的初步认识", + "长方形,正方形,三角形和圆的初步认识", + "平面图形的拼接" + ], + "source": "21-22 一年级下·云南保山·期中" + }, + { + "id": "244", + "unit": "第二单元 位置与方向", + "question_type": "选择题", + "difficulty": 0.65, + "question": "下面图形中, ( )是下图长方体的左面。", + "options": [ + "A. ![](images/b6e562823f7b0971619e3cfcfbddc4d04440877f3dd4e0a1209f86103fbaca08.jpg)\n(图a)", + "B. ![](images/0b1d82b975fa210e060eca055e986bb87721fab6bbbbfb4f97b35731791f4552.jpg)\n(图b)", + "C. ![](images/926e442e0f52d0a60e1377c4ec1c01df8dbd33a97d980ef830de09149c31b139.jpg)\n(图c)" + ], + "answer": "A", + "solution": "【分析】根据长方体的特征,长方体的 6 个面一般都是长方形(特殊情况有两个相对的面是正方形),相对的面面积相等。从上面看到的是最大的长方形,从左面看到的是最小的长方形,从前面看到的是图中 C 的那个长方形。据此解答即可。此题考查的目的是理解掌握长方体特征及应用,以及从不同的方向观察物体的方法及应用.\n【详解】由分析可得:图形中,图a是下图长方体的左面。故答案为: A.", + "knowledge_points": [ + "长方形,正方形,三角形和圆的初步认识", + "立体图形的认识" + ], + "source": "21-22 一年级下·云南保山·期中" + }, + { + "id": "245", + "unit": "第二单元 位置与方向", + "question_type": "选择题", + "difficulty": 0.65, + "question": "![](images/2025-12-13%20205649.jpg)中有( )个长方形。", + "options": [ + "A. 1", + "B. 2", + "C. 3" + ], + "answer": "C", + "solution": "【分析】长方形是由四条边组成的封闭图形,对边相等。在数图形中的长方形数量时,应按照从小到大的顺序分类计数,先数单个的小长方形,再数由多个小长方形组合而成的大长方形.\n【详解】图中有 2 个独立的小长方形;此外,这 2 个小长方形上下拼接,还组成了 1 个更大的长方形。因此,长方形的总数为:2 + 1 = 3(个)。故答案为:C.", + "knowledge_points": [ + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "21-22 一年级下·湖南岳阳·期中" + }, + { + "id": "246", + "unit": "第二单元 位置与方向", + "question_type": "选择题", + "difficulty": 0.65, + "question": "如图是一套七巧板,其中 4 号图形与 ( ) 号图形能拼成一个正方形。", + "options": [ + "A. 2", + "B. 6", + "C. 7" + ], + "answer": "B", + "solution": "【分析】正方形由四条相等的边和四个直角组成。要判断哪两块图形能拼成正方形,需寻找与4号图形形状,大小完全相同的等腰直角三角形,并通过拼接验证是否能构成正方形.\n【详解】4号图形是一个等腰直角三角形。观察各选项:A(2号)是更大的等腰直角三角形,与4号大小不同;B(6号)是与4号完全相同的等腰直角三角形;C(7号)是平行四边形,形状不同。将4号与6号的斜边拼接,可组成一个正方形。因此,4号图形与6号图形能拼成一个正方形。故答案为:B.", + "knowledge_points": [ + "用七巧板拼图形", + "长方形,正方形,三角形和圆的初步认识", + "平面图形的拼接" + ], + "source": "21-22 一年级下·甘肃甘南·期中" + }, + { + "id": "247", + "unit": "第二单元 位置与方向", + "question_type": "填空题", + "difficulty": 0.85, + "question": "一副七巧板有( )块,其中有5块( )形, ( )块正方形, ( )块平行四边形。", + "options": [], + "answer": "7;三角形;1;1", + "solution": "【分析】如图,![](images/4859866341d9a1c9d4ea6048807b131cbd94be320f15483e2ac838a7169d2dc2.jpg)这是一副七巧板,一共有7个,三角形最多,有 5 个,正方形和平行四边形各 1 个,据此解答.\n【详解】一副七巧板有(7)块,其中有5块三角形,(1)块正方形,(1)块平行四边形。", + "knowledge_points": [ + "用七巧板拼图形", + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "22-23一年级下·广东江门·期中" + }, + { + "id": "248", + "unit": "第二单元 位置与方向", + "question_type": "填空题", + "difficulty": 0.65, + "question": "用![](images/2025-12-13%20210957.jpg)做成一个正方体,( )的对面是4。", + "options": [], + "answer": "2", + "solution": "【分析】根据正方体的展开图\"相对不相邻\"可知,1和3相对,2和4相对,5和6相对,由此解答.\n【详解】由分析可知:用该图做一个正方体。 \"2\"的对面是\"4\"。", + "knowledge_points": [ + "正方体的展开图" + ], + "source": "22-23一年级下·湖南张家界·期中" + }, + { + "id": "249", + "unit": "第二单元 位置与方向", + "question_type": "填空题", + "difficulty": 0.85, + "question": "将一个正方形对折后剪开,可以得到两个相同的( )形或两个相同的( )形。", + "options": [], + "answer": "三角;长方", + "solution": "【分析】正方形是由四条边首尾依次连接围成的封闭图形,四条边都相等;长方形是由四条边首尾依次连接围成的封闭图形,对边相等;三角形是由三条边首尾依次连接围成的封闭图形。对折时可边和边重合,也可以角和角重合.\n【详解】由分析作图如下:\n![](images/c3e7030c5cdd911ef7f9d696af7ccd8438635e8fa1883518ea9b4eed8fe494d3.jpg)\n![](images/102974060829e677a9674c8c6665fb4efab389f42a5b380f052f2240e11f246a.jpg)\n将一个正方形对折后剪开,可以得到两个相同的三角形或两个相同的长方形。", + "knowledge_points": [ + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "22-23 一年级下·山东济宁·期中" + }, + { + "id": "250", + "unit": "第二单元 位置与方向", + "question_type": "填空题", + "difficulty": 0.85, + "question": "数一数下图中一共有( )个三角形和( )个正方形。", + "options": [], + "answer": "4;2", + "solution": "【分析】三角形是由三条边首尾依次连接围成的封闭图形;正方形是由四条边首尾依次连接围成的封闭图形,四条边都相等。由此数出图形数量填空即可.\n【详解】数一数该图中一共有4个三角形和2个正方形。", + "knowledge_points": [ + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "22-23一年级下·山东济宁·期中" + }, + { + "id": "251", + "unit": "第二单元 位置与方向", + "question_type": "填空题", + "difficulty": 0.65, + "question": "数一数下边的图形有( )个长方形。", + "options": [], + "answer": "5", + "solution": "【分析】长方形有四个直直的角,两条对边分别相等,据此判断长方形的形状,然后数出数量即可。注意不要落下拼成的较大的长方形.\n【详解】根据分析知:图中有5个长方形。", + "knowledge_points": [ + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "22-23 二年级下·广西贵港·期中" + }, + { + "id": "252", + "unit": "第二单元 位置与方向", + "question_type": "填空题", + "difficulty": 0.85, + "question": "折一折,用![](images/d2ca95364beeea5a6bb9d77f1840e968ccbcb1ddd3a7f5f43598a3941a9c1bd5.jpg)做一个正方体,\"5\"的对面是( ),\"3\"的对面是( )。", + "options": [], + "answer": "6;1", + "solution": "【分析】根据正方体的展开图\"相对不相邻\"可知,1和3相对;2和4相对;5和6相对,由此解答.\n【详解】由分析得:折一折,用该图做一个正方体,\"5\"的对面是6,\"3\"的对面是 1。", + "knowledge_points": [ + "正方体的展开图" + ], + "source": "22-23 一年级下·湖南常德·期中" + }, + { + "id": "253", + "unit": "第二单元 位置与方向", + "question_type": "填空题", + "difficulty": 0.85, + "question": "折一折,将![](images/bd9d9cea37871a1a2a04606d18bca8ba218e741b0770996b46f3bd61a3a402f3.jpg)折成正方体,数字\"1\"的对面是数字\"( )。", + "options": [], + "answer": "6", + "solution": "【分析】根据正方体的展开图\"相对不相邻\"可知,1和6相对;4和2相对;3和5相对,由此解答.\n【详解】由分析得:折一折,用该图折成方体,数字 \"1\" 的对面是数字 \"6\"。", + "knowledge_points": [ + "正方体的展开图" + ], + "source": "22-23 一年级下·湖北孝感·期中" + }, + { + "id": "254", + "unit": "第二单元 位置与方向", + "question_type": "填空题", + "difficulty": 0.85, + "question": "一个正方形能剪成两个相同的( )。", + "options": [], + "answer": "长方形(或三角形)", + "solution": "【分析】正方形是由四条边首尾依次连接组成的封闭图形,四条边都相等;三角形是由三条边首尾依次连接组成的封闭图形;长方形是由四条边首尾依次连接组成的封闭图形,对边相等;如图 1 剪开是两个相同的长方形;图 2 剪开是两个相同的三角形.\n![](images/978f03ea0fcb682a8e47e4113342979d7ef2ed4edafe84650f76ab4a0a687a8d.jpg)\n【详解】一个正方形能剪成两个相同的长方形(或三角形)。", + "knowledge_points": [ + "平面图形的分割", + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "22-23一年级下·河北保定·期中" + }, + { + "id": "255", + "unit": "第二单元 位置与方向", + "question_type": "填空题", + "difficulty": 0.85, + "question": "如图,做成一个正方体,数字\"1\"对面的数是( ),数字\"3\"的对面是( )。", + "options": [], + "answer": "4;6", + "solution": "【分析】根据正方体的展开图\"相对不相邻\"可知,4和1是相对面;2和5是相对面;剩下的3和6是相对面,由此解答。本题主要考查了正方体的展开图,要充分发挥想象力.\n【详解】由分析得:数字 \"1\"对面的数是 4,数字 \"3\"的对面是 6 。", + "knowledge_points": [ + "正方体的展开图" + ], + "source": "22-23一年级下·浙江杭州·期末" + }, + { + "id": "256", + "unit": "第二单元 位置与方向", + "question_type": "填空题", + "difficulty": 0.65, + "question": "把一个 □ 对折,可以分成两个相同的( )形或( )形。", + "options": [], + "answer": "三角;长方", + "solution": "【分析】![](images/2025-12-13%20211731.jpg)这样对折出来是两个相同的三角形,![](images/e321635e6ff3bed4e11c53b8ba10211558db2e8666c7c188cfbd3e8b842c096f.jpg)这样对折出来是两个相同的长方形,据此填空。熟练掌握对平面图形的认识是解题关键.\n【详解】把一个 □ 对折,可以分成两个相同的三角形或长方形。", + "knowledge_points": [ + "长方形,正方形,三角形和圆的初步认识", + "图形的折叠问题" + ], + "source": "22-23 一年级下·浙江杭州·期末" + }, + { + "id": "257", + "unit": "第二单元 位置与方向", + "question_type": "填空题", + "difficulty": 0.65, + "question": "两块板可以拼成一个三角形:由两个( )或两个( )拼成。", + "options": [], + "answer": "小三角形;大三角形", + "solution": "【分析】举例:七巧板一共有 7 块,由 1 个正方形,2 个大三角形,1个中三角形,2个小三角形和1个平行四边形组成。动手拼一拼,看看三角形可以有什么图形拼成。![](images/ed3f55bc3273701b8c671432de60ed3e14df91788d9cdf5b593ee708f62e62e7.jpg)本题考查平面图形的初步认识,要掌握三角形的特征.\n【详解】例如七巧板的两个小三角形可以拼成一个三角形,两个大三角形也可以拼成一个三角形。所以,两块板可以拼成一个三角形:由两个小三角形或两个大三角形拼成。", + "knowledge_points": [ + "长方形,正方形,三角形和圆的初步认识", + "平面图形的拼接" + ], + "source": "22-23一年级下·全国·随堂练习" + }, + { + "id": "258", + "unit": "第二单元 位置与方向", + "question_type": "填空题", + "difficulty": 0.65, + "question": "下图是由( )个大小相同的三角形拼成的。", + "options": [], + "answer": "6", + "solution": "【分析】三角形有三条直直的边,据此数出三角形的个数即可。本题考查平面图形(三角形)的认识,要掌握其特征.\n【详解】该图是由 6 个大小相同的三角形拼成的。", + "knowledge_points": [ + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "22-23 一年级下·全国·随堂练习" + }, + { + "id": "259", + "unit": "第二单元 位置与方向", + "question_type": "填空题", + "difficulty": 0.85, + "question": "1 元硬币的正面是( )形,红领巾是( )形,数学课本的封面是( )形。", + "options": [], + "answer": "圆;三角;长方", + "solution": "【分析】1元硬币的面是圆圆的圆形;展开的红领巾的面是三条边,三个角的三角形;数学课本的封面是一个四个角都为直角的四边形,长长的方方的;据此填写即可。本题主要考查了平面图形的分类及识别,解题的关键是掌握三角形,圆和长方形的特征.\n【详解】1元硬币的正面是圆形,红领巾是三角形,数学课本的封面是长方形。", + "knowledge_points": [ + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "22-23 一年级下·全国·假期作业" + }, + { + "id": "260", + "unit": "第二单元 位置与方向", + "question_type": "填空题", + "difficulty": 0.85, + "question": "用![](images/ab63479fdeeab17f23266b1899c09066e8656157e7270bd0526f64873f6e49f9.jpg)做成一个正方体,\"1\"的对面是( ),\"3\"的对面是( )。", + "options": [], + "answer": "2;4", + "solution": "【分析】根据正方体展开图的特征,图形属于正方体展开图的\"1-4-1\"型,折叠成正方体后,数字1与2相对,4和1,2,5,6相邻,只有3与4相对。本题考查正方体展开图的特征,要记住相关规律.\n【详解】根据分析可知,用该图做成一个正方体,\"1\"的对面是2,\"3\"的对面是4。", + "knowledge_points": [ + "正方体的展开图" + ], + "source": "21-22 一年级下·广东佛山·期末" + }, + { + "id": "261", + "unit": "第二单元 位置与方向", + "question_type": "填空题", + "difficulty": 0.85, + "question": "![](images/16c2c2d39b46a2a82277a489bf3bef5bc7d9f6c38d2ae07822c05fb5e6096edc.jpg)是( )形,它的四条边相等。", + "options": [], + "answer": "正方", + "solution": "【分析】正方形的特征是四条边相等,四个角都是直角。本题主要考查正方形的特征.\n【详解】根据题意及分析可知,该图是正方形,它的四条边相等。", + "knowledge_points": [ + "正方形的概念及特点" + ], + "source": "22-23 一年级下·全国·课前预习" + }, + { + "id": "262", + "unit": "第二单元 位置与方向", + "question_type": "填空题", + "difficulty": 0.85, + "question": "最少用( )个相同的小正方形拼成一个大正方形;七巧板是由( )个正方形,( )个平行四边形和( )个三角形组成的。", + "options": [], + "answer": "4;1;1;5", + "solution": "【分析】正方形的四条边相等,要想拼成正方形可以这样拼接:![](images/1fac9eab9da6a483eb45284b5eb7efb62c735c54a82a0f69511b49e341adbd85.jpg);图中为一套七巧板。根据正方形,平行四边形,三角形三种图形的概念理解与实际认知即可判断。①②③⑤⑦为三角形;④为正方形;⑥为平行四边形。![](images/607f064a44206cde8e0c029457a3f0178901f2e302b2e2bd8ac4bbaccbba50c9.jpg)本题考查平面图形的认识.\n【详解】根据分析可知,最少用 4 个相同的小正方形拼成一个大正方形;七巧板是由 1 个正方形,1 个平行四边形和 5 个三角形组成的。", + "knowledge_points": [ + "平行四边形的初步认识", + "用七巧板拼图形", + "长方形,正方形,三角形和圆的初步认识", + "平面图形的拼接" + ], + "source": "22-23 一年级下·全国·课前预习" + }, + { + "id": "263", + "unit": "第二单元 位置与方向", + "question_type": "填空题", + "difficulty": 0.85, + "question": "![](images/e54f8e4a2899546a9c03e18a4271697a89104e67be651c0bccc476e23f7ca8e7.jpg)是( )形,它的对边相等。", + "options": [], + "answer": "平行四边", + "solution": "【分析】根据平行四边形的特点,平行四边形对边相等。本题主要考查平行四边形的特征。注意基础知识的掌握.\n【详解】该图是平行四边形,它的对边相等。", + "knowledge_points": [ + "平行四边形的初步认识" + ], + "source": "22-23 一年级下·全国·课前预习" + }, + { + "id": "264", + "unit": "第二单元 位置与方向", + "question_type": "填空题", + "difficulty": 0.85, + "question": "![](images/59575c168175531548e9285468e964072209918cd41deb7b331a4019aca9802c.jpg)是( )形,它的对边相等。", + "options": [], + "answer": "长方", + "solution": "【分析】有两条长边,两条短边,对边相等,有四个角的四边形是长方形。本题主要考查长方形的认识.\n【详解】根据题意及分析可知,该图是长方形,它的对边相等。", + "knowledge_points": [ + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "22-23 一年级下·全国·课前预习" + }, + { + "id": "265", + "unit": "第二单元 位置与方向", + "question_type": "填空题", + "difficulty": 0.85, + "question": "![](images/754524f51d7a9ade99cfc8e430e902d1790bfa2a50cb3a67bbfd0d4da83b4dac.jpg)是由( )形和( )形拼成的。", + "options": [], + "answer": "平行四边;三角", + "solution": "【分析】根据对图形的认识进行解答。本题考查了熟练掌握对平面图形的认识.\n【详解】图中左侧是平行四边形,右侧是三角形。", + "knowledge_points": [ + "平行四边形的初步认识", + "长方形,正方形,三角形和圆的初步认识", + "平面图形的拼接" + ], + "source": "22-23 一年级下·全国·单元测试" + }, + { + "id": "266", + "unit": "第二单元 位置与方向", + "question_type": "填空题", + "difficulty": 0.85, + "question": "长方形有( )个顶点, ( )个角。", + "options": [], + "answer": "4;4", + "solution": "【分析】长方形为四个内角相等的四边形。熟练掌握长方形的定义是解题关键.\n【详解】长方形有 4 个顶点,4 个角。", + "knowledge_points": [ + "长方形的概念及特点" + ], + "source": "20-21 二年级上·海南省直辖县级单位·期末" + }, + { + "id": "267", + "unit": "第二单元 位置与方向", + "question_type": "填空题", + "difficulty": 0.4, + "question": "折一折,用![](images/4796f0c958b4f7dec6f1cfd1e0002ecffe8acd88aef9ec51ab6fd89a09233b00.jpg)做一个正方体,\"绿\"的对面是( )。", + "options": [], + "answer": "底", + "solution": "【分析】根据正方体的展开图,分清楚底面和侧面,将展开图折叠起来,即可得出答案。本题考查学生对正方体展开图的掌握和运用.\n【详解】折一折,用该图做一个正方体,\"绿\"的对面是\"底\"。", + "knowledge_points": [ + "立体图形的认识", + "图形的折叠问题" + ], + "source": "21-22 一年级下·黑龙江双鸭山·期末" + }, + { + "id": "268", + "unit": "第二单元 位置与方向", + "question_type": "填空题", + "difficulty": 0.65, + "question": "用![](images/c4ef0dafd44e6d94a9262edd9c23cbc3a9dc19017bcd915b685afb6baa355d74.jpg)做成正方体,数字 \"3\" 的对面是数字( )。", + "options": [], + "answer": "4", + "solution": "【分析】根据正方体展开图的 11 种特征,此图属于正方体展开图的 \" 1 - 4 - 1 \"型,折成正方体后,数字 \"1\"与 \"2\"相对;\"3\"与 \"4\"相对,\"5\"与 \"6\"相对.\n【详解】此图属于正方体展开图的 \"1-4-1\"型,用该图成正方体,数字 \"3\"的对面是数字 4。正方体展开图分四种类型, 11 种情况,每种情况折成正方体后哪些面相对是有规律的,可自己动手操作一下并记住,能快速解答此类题。", + "knowledge_points": [ + "正方体的展开图" + ], + "source": "21-22 一年级下·湖北随州·期末" + }, + { + "id": "269", + "unit": "第二单元 位置与方向", + "question_type": "填空题", + "difficulty": 0.85, + "question": "下图有( )个三角形。", + "options": [], + "answer": "2", + "solution": "【分析】由图可知,将一个长方形分成了两个三角形,据此解答即可.\n【详解】1+1=2(个),图中有2个三角形。数三角形个数时,要按照顺序数,才能做到不重不漏。", + "knowledge_points": [ + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "21-22 一年级下·广西玉林·期末" + }, + { + "id": "270", + "unit": "第二单元 位置与方向", + "question_type": "填空题", + "difficulty": 0.65, + "question": "想一想,填一填。用![](images/00f81a55b8bf0ef62f9dd30936a3db9397b64c61f5126b8515f8c7d43703f068.jpg)做一个正方体,\"4\"的对面是( )。", + "options": [], + "answer": "3", + "solution": "【分析】根据正方体展开图的 11 种特征,此图属于正方体展开图的 \"1-4-1\"型,做成一个正方体后,数字 \"1\"与\"2\"相对,\"3\"与\"4\"相对,\"5\"与\"6\"相对.\n【详解】用该图做一个正方体,\"4\"的对面是\"3\"。正方体展开图分四种类型, 11 种情况,每种情况折成正方体后哪些面相对是有规律的,可自己动手操作一下并记住规律,能快速解答此类题。", + "knowledge_points": [ + "正方体的展开图" + ], + "source": "21-22 一年级下·浙江杭州·期末" + }, + { + "id": "271", + "unit": "第二单元 位置与方向", + "question_type": "填空题", + "difficulty": 0.65, + "question": "如图:一套七巧板由7小块组成,其中有( )个正方形,( )个平行四边形,( )个等腰直角三角形.\n![](images/b464be964475853b47f4d8a1a6e51f3b1e7f7042e91b9b157c5e94b2fe500182.jpg)", + "options": [], + "answer": "1;1;5", + "solution": "【分析】七巧板是一套经典的几何拼图玩具,由7块板组成,包括三角形,正方形和平行四边形三种基本图形。所有三角形都是等腰直角三角形。通过观察图中七巧板的构成,可以逐一辨认并统计各类图形的数量.\n【详解】一副七巧板共有7块。其中,正方形有1块(通常为中等大小的正方形);平行四边形有1块(形状类似菱形);其余5块均为大小不同的等腰直角三角形。因此,七巧板中有1个正方形,1个平行四边形和5个等腰直角三角形。", + "knowledge_points": [ + "平行四边形的初步认识", + "用七巧板拼图形", + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "21-22一年级下·广东阳江·期末" + }, + { + "id": "272", + "unit": "第二单元 位置与方向", + "question_type": "填空题", + "difficulty": 0.65, + "question": "用![](images/5800514bb0fa099f0482b702eb7560dc265f7f2b7e371541d1c0f72bbe74f1b9.jpg)做成一个正方体,数字6的对面是数字( )。", + "options": [], + "answer": "5", + "solution": "【分析】根据正方体的展开图是隔面相对的,所以\"6\"与\"5\"相对,据此解答。本题考查正方体的认识及展开图的掌握情况.\n【详解】根据分析可知,数字 6 的对面是数字(5)。", + "knowledge_points": [ + "正方体的展开图" + ], + "source": "21-22 一年级下·广东东莞·期中" + }, + { + "id": "273", + "unit": "第二单元 位置与方向", + "question_type": "填空题", + "difficulty": 0.65, + "question": "折一折,用![](images/d4c2e3e90f669364eedf3ec5c6bbee6b385fea6925cfc7acf77e26658823a71f.jpg)做成一个正方体,数字\"5\"对面的数字是( )。", + "options": [], + "answer": "6", + "solution": "【分析】根据正方体图形展开图的认识,将这个图形折叠起来后,数字 1 和 3 相对, 2 和 4 相对, 5 和 6 相对,由此解答。本题是考查简单图形的折叠问题,要有一定的空间想象能力.\n【详解】折一折,用该图做成一个正方体,数字\"5\"对面的数字是6。", + "knowledge_points": [ + "图形的折叠问题" + ], + "source": "21-22 一年级下·四川广元·期末" + }, + { + "id": "274", + "unit": "第二单元 位置与方向", + "question_type": "填空题", + "difficulty": 0.65, + "question": "用![](images/993587743367025a65aae21878227a35ef1fbddcbe89f130b269e7c4f2d3934d.jpg)做一个正方体,\"3\"的对面是( )。", + "options": [], + "answer": "1", + "solution": "【分析】此图属于正方体展开图中的\"141型\",据此解答.\n【详解】此图属于正方体展开图中的\"141型\",\"2\",\"4\",\"5\",\"6\"都和\"3\"相邻,\"3\"的对面应该是1。熟练掌握正方体的 11 种展开图是解题关键。", + "knowledge_points": [ + "正方体的展开图" + ], + "source": "20-21 一年级下·江西赣州·期末" + }, + { + "id": "275", + "unit": "第二单元 位置与方向", + "question_type": "填空题", + "difficulty": 0.65, + "question": "一张正方形的纸片对折,可以得到( )个( )形。", + "options": [], + "answer": "2;长方", + "solution": "【分析】一个正方形沿对边中点连线对折一次后,可得到 2个长为原正方形边长,宽为原正方形边长一半的长方形;把一个正方形沿对角线对折一次,可得到2个两直角边为原正方形边长的等腰直角三角形;据此解答即可。本题是考查简单图形的折叠问题,要有一定的空间想象能力.\n【详解】一张正方形的纸片对折,可以得到 2 个长方形或者三角形。", + "knowledge_points": [ + "图形的折叠问题" + ], + "source": "20-21 一年级下·河南信阳·期末" + }, + { + "id": "276", + "unit": "第二单元 位置与方向", + "question_type": "填空题", + "difficulty": 0.85, + "question": "![](images/9911efd45ea296c8c9e7656004066edffa837cde422b52451f44a905fad0ff4a.jpg)这是一个( ), 它上下两个面的图形都是( )。", + "options": [], + "answer": "圆柱;圆", + "solution": "【分析】根据对立体图形的认识,题干上的立体图形是一个圆柱,圆柱的上下两个面都是圆形,据此解答即可。本题考查学生对圆柱体特点的掌握和运用.\n【详解】这是一个圆柱,它上下两个面的图形都是圆形。", + "knowledge_points": [ + "圆柱的认识及特征", + "立体图形的认识" + ], + "source": "21-22一年级下·河北张家口·期末" + }, + { + "id": "277", + "unit": "第二单元 位置与方向", + "question_type": "填空题", + "difficulty": 0.85, + "question": "下图是一套七巧板拼成的图形,七巧板一共有( )块,其中正方形有( )块,平行四边形有( )块,三角形有( )块.\n![](images/a0998cdb477943a586f05122ecfee7961864e4eaab291eb842c342c7bf7fd2ed.jpg)", + "options": [], + "answer": "7;1;1;5", + "solution": "【分析】七巧板是一套由7块板组成的拼图玩具,包括三角形,正方形和平行四边形三种基本图形。通过观察图中拼出的图形,可以辨认并统计出各类图形的数量.\n【详解】一副完整的七巧板共有7块。其中,正方形有1块(通常是中等大小的那块),平行四边形有1块(形状像菱形),其余5块均为大小不等的三角形。因此,七巧板一共有7块,其中正方形有1块,平行四边形有1块,三角形有5块。", + "knowledge_points": [ + "用七巧板拼图形", + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "21-22一年级下·山东临沂·期末" + }, + { + "id": "278", + "unit": "第二单元 位置与方向", + "question_type": "填空题", + "difficulty": 0.65, + "question": "![](images/fd6e444cbdd39b63237bada5dd222c91a39fa262233c9cc5f0e41412bfd03d8f.jpg)有( )个三角形,![](images/40280c07378d76f7b4e3df1e206f2ee828f77a8f87d2222cc0c8116216570906.jpg)有( )个三角形。", + "options": [], + "answer": "5;4", + "solution": "【分析】根据三角形的特点,结合图片,数清楚各个图形中三角形的数量即可得出答案。数图形时要注意,图形拼组在一起的组成的大图形的形状,有存在是三角形的可能性,学生要注意数清楚,不遗漏.\n【详解】![](images/3908ecd2be94b64f929b849343bad270e997d44fcc11eb067f5124798dd89e42.jpg)有5个三角形,![](images/158366b59126f0a32e4279d80fd85133d1128118262d516f051bd5c7a8ca6172.jpg)有4个三角形。", + "knowledge_points": [ + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "21-22 一年级下·河南信阳·期中" + }, + { + "id": "279", + "unit": "第二单元 位置与方向", + "question_type": "填空题", + "difficulty": 0.65, + "question": "至少用( )根同样长的小棒可以摆出一个长方形。至少用( )个□才能拼成一个大正方形。", + "options": [], + "answer": "6;4", + "solution": "【分析】(1)长方形有两条相等的长边,两条相等的短边,用2根同样长的小棒摆出两条相等的短边后,那么两条相等的长边需要4根这样的小棒,即2+4=6(根);(2)正方形的4条边都相等,2个□或3个□只能拼成一个长方形,4个□可以拼成一个大正方形。掌握长方形和正方形边的特点是解答此题的关键.\n【详解】根据分析知道至少用6根同样长的小棒可以摆出一个长方形。至少用4个□才能拼成一个大正方形。", + "knowledge_points": [ + "长方形,正方形,三角形和圆的初步认识", + "平面图形的拼接" + ], + "source": "21-22 一年级下·河南信阳·期中" + }, + { + "id": "280", + "unit": "第二单元 位置与方向", + "question_type": "填空题", + "difficulty": 0.85, + "question": "课桌的面是( )形,一元硬币的面是( )形,展开的红领巾的面是( )形。", + "options": [], + "answer": "长方;圆;三角", + "solution": "【分析】根据平面图形中长方形,圆,三角形的特点进行判断即可。本题主要考查平面图形的认识,牢记图形的特点是关键.\n【详解】课桌的面是长方形,一元硬币的面是圆形,展开的红领巾的面是三角形。", + "knowledge_points": [ + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "20-21 一年级下·山东滨州·期末" + }, + { + "id": "281", + "unit": "第二单元 位置与方向", + "question_type": "填空题", + "difficulty": 0.65, + "question": "缺了( )块砖.\n![](images/74a894b80506ce7aa67f29d8e0c37a80f80b5427577c932567382e4546c2c4cc.jpg)", + "options": [], + "answer": "10", + "solution": "【分析】如图:![](images/28501d09f7708e841a458582d95e5bfb56fb7850424ab2889b321bf88af73a4e.jpg)看图可算数缺了几块砖。本题考查图形的认识.\n【详解】根据分析可知:1 + 2 + 2 + 2 + 3 = 3 + 4 + 3 = 7 + 3 = 10,所以缺了 10 块砖。", + "knowledge_points": [ + "长方形,正方形,三角形和圆的初步认识", + "平面图形的拼接" + ], + "source": "20-21 一年级下·河南三门峡·期末" + }, + { + "id": "282", + "unit": "第二单元 位置与方向", + "question_type": "填空题", + "difficulty": 0.4, + "question": "用![](images/974669c88a46b363d213a19f87cb41b2e0d20cdb91e539b07a2eed16188170db.jpg)做成一个正方体,\"4\"的对面是( )。", + "options": [], + "answer": "6", + "solution": "【分析】根据正方体的展开图可知此图是:\"141\"型,所以 4 的对面是 6。本题考查长方体和正方体的认识及展开图的认识.\n【详解】根据分析可知:\"4\"的对面是\"6\"。", + "knowledge_points": [ + "正方体的展开图" + ], + "source": "21-22 一年级下·四川德阳·期末" + }, + { + "id": "283", + "unit": "第二单元 位置与方向", + "question_type": "填空题", + "difficulty": 0.65, + "question": "用七巧板中的两个完全一样的三角形,可以拼成一个( )形,也可以拼成一个( )形.\n![](images/93cac25e0ec87a6d4592f0c8e890114408fda8412cadc90260b1b574a129ae65.jpg)", + "options": [], + "answer": "三角;正方", + "solution": "【分析】两个完全一样的三角形,在七巧板中是两个等腰直角三角形,如果斜边挨着一起,可以拼成一个正方形,如果两个直角边挨在一起,可以拼成一个平行四边形或者三角形.\n【详解】用七巧板中的两个完全一样的三角形,可以拼成一个三角形,也可以拼成一个正方形。(答案不唯一)本题考查了图形的拼接。可以恰当结合手头的实物操作,更容易直观得出结论。", + "knowledge_points": [ + "用七巧板拼图形", + "长方形,正方形,三角形和圆的初步认识", + "平面图形的拼接" + ], + "source": "20-21一年级下·河南漯河·期中" + }, + { + "id": "284", + "unit": "第二单元 位置与方向", + "question_type": "填空题", + "difficulty": 0.65, + "question": "折一折,用![](images/279df26448c84ad234166ade2db04907aa7e463a79572de0f07f85e4c0b0f3f4.jpg)做一个正方体,\"2\"的对面是( )。", + "options": [], + "answer": "4", + "solution": "【分析】此图属于正方体展开图的 \"1-4-1\"型,折成正方体后,\"1\"与\"3\"相对,\"2\"与\"4\"相对,\"5\"与\"6\"相对.\n【详解】用该图做一个正方体,\"2\"的对面是4。正方体展开图分四种类型, 11 种情况,每种情况折成正方体后哪些面相对是有规律的,可自己动手操作一下并记住,能快速解答此类题。", + "knowledge_points": [ + "正方体的展开图" + ], + "source": "21-22 一年级下·河南三门峡·期末" + }, + { + "id": "285", + "unit": "第二单元 位置与方向", + "question_type": "填空题", + "difficulty": 0.65, + "question": "至少用( )个同样的正方形就可以拼成一个长方形;至少用( )个同样的正方形可以拼成一个大一些的正方形。", + "options": [], + "answer": "2;4", + "solution": "【分析】四条边都相等,四个角都是直角的四边形是正方形;长方形为四个内角相等的四边形。解答本题的关键是要了解正方形和长方形的定义.\n【详解】至少用 2 个同样的正方形就可以拼成一个长方形;至少用 4 个同样的正方形可以拼成一个大一些的正方形。", + "knowledge_points": [ + "长方形的概念及特点", + "正方形的概念及特点", + "平面图形的拼接" + ], + "source": "17-18 一年级下·全国·单元测试" + }, + { + "id": "286", + "unit": "第二单元 位置与方向", + "question_type": "填空题", + "difficulty": 0.65, + "question": "最少要( )个完全一样的 □ , 可以拼出一个大正方形。", + "options": [], + "answer": "4", + "solution": "【分析】正方形的特征是四条边长度相等,四个角都是直角。要拼成一个更大的正方形,需要用小正方形进行排列组合,确保拼出图形的四条边相等.\n【详解】用完全一样的小正方形拼大正方形时,最少需要4个。将它们摆成2行2列(即每行2个,每列2个),即可拼成一个每条边由2个小正方形组成的大正方形。故答案为:4。", + "knowledge_points": [ + "正方形的概念及特点", + "平面图形的拼接" + ], + "source": "21-22 一年级下·全国·单元测试" + }, + { + "id": "287", + "unit": "认识图形", + "question_type": "填空题", + "difficulty": 0.65, + "question": "下图是由 4 个相同的小( )形拼成的一个大( )形.\n![](images/b3308849b8aee630068c2fc0186f14efca2b32eb1650f577f806b5d3849e1502.jpg)", + "options": [], + "answer": "三角;三角", + "solution": "【分析】整个大的图形是三角形,里面的小图形是三角形,据此可得出答案。本题主要考查的是三角形的特征,解题的关键是熟练掌握三角形的特征,进而得出答案.\n【详解】该图是由 4 个相同的小三角形拼成的一个大三角形。", + "knowledge_points": [ + "长方形", + "正方形", + "三角形和圆的初步认识" + ], + "source": "2022 一年级下·全国·专题练习" + }, + { + "id": "288", + "unit": "认识图形", + "question_type": "填空题", + "difficulty": 0.65, + "question": "下图是由 4 个相同的( )形拼成的一个( )形.\n![](images/4738491a21b9f2cfc72bcda516e84e8dc26362a22810d76472a0440f19b7c7d8.jpg)", + "options": [], + "answer": "三角;正方", + "solution": "【分析】连接正方形的两条对角线,就可以把正方形分成四个相同的三角形.\n【详解】根据分析可得:题图是由4个相同的三角形拼成的一个正方形。", + "knowledge_points": [ + "长方形", + "正方形", + "三角形和圆的初步认识" + ], + "source": "17-18 一年级下·山东青岛·单元测试" + }, + { + "id": "289", + "unit": "认识图形", + "question_type": "填空题", + "difficulty": 0.65, + "question": "下图是由 2 个相同的 ( )形拼成的一个( )形.\n![](images/7e0804eadd0fa0dfea4f52c400a890690ed31191db7f908173609f42e5298749.jpg)", + "options": [], + "answer": "长方;正方", + "solution": "【分析】根据长方形,正方形的特征及性质可知:四个角都是直角的四边形为长方形,四条边都相等且四个角都是直角的四边形为正方形;据此解答。本题主要考查了图形的拼组,掌握长方形,正方形的初步认识是解答本题的关键.\n【详解】图中是由 2 个相同的长方形拼成的一个正方形。", + "knowledge_points": [ + "长方形", + "正方形", + "三角形和圆的初步认识", + "平面图形的拼接" + ], + "source": "2022一年级下·全国·专题练习" + }, + { + "id": "290", + "unit": "认识图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "最少用( )根相同的小棒能摆成一个□。", + "options": [], + "answer": "4", + "solution": "【分析】正方形是由四条长度相等的边围成的封闭图形,四个角都是直角。用相同长度的小棒摆正方形,每根小棒代表正方形的一条边.\n【详解】因为正方形有4条边,所以最少需要用4根相同的小棒才能摆出一个正方形。故答案为:4。", + "knowledge_points": [ + "长方形", + "正方形", + "三角形和圆的初步认识" + ], + "source": "2022一年级下·全国·专题练习" + }, + { + "id": "291", + "unit": "认识图形", + "question_type": "判断题", + "difficulty": 0.65, + "question": "4 个完全一样的小正方形可以拼成一个大正方形。( )", + "options": [], + "answer": "√", + "solution": "【分析】4 个完全一样的小正方形按如下图方式可以拼成一个大正方形。![](images/0451dd339357cc3b626528bca6edf656523cb3f1eba9a57c4649bc56638d8c62.jpg)\n【详解】根据分析知, 4 个完全一样的小正方形可以拼成一个大正方形。说法正确。故答案为: √", + "knowledge_points": [ + "长方形", + "正方形", + "三角形和圆的初步认识" + ], + "source": "22-23 一年级下·湖北十堰·期中" + }, + { + "id": "292", + "unit": "认识图形", + "question_type": "判断题", + "difficulty": 0.85, + "question": "一个正方形能剪成两个相同的长方形或两个相同的三角形。( )", + "options": [], + "answer": "√", + "solution": "【分析】正方形是由四条边首尾依次连接组成的封闭图形,四条边都相等;长方形是由四条边首尾依次连接组成的封闭图形,对边相等;三角形是由三条边首尾依次连接组成的封闭图形;如图 1 剪开是两个相同的长方形;图 2 剪开是两个相同的三角形。![](images/262122a7cd1462de5553ef0f9b8b16e80c17da80a8073a9d45fec5a1230aa6a3.jpg)\n![](images/19727f484e9ddec7fd6c6f21e03bb3858bf426667b4ae1d7cbeff98dce2e1dc0.jpg)\n【详解】由分析可知,一个正方形能剪成两个相同的长方形或两个相同的三角形。原题说法正确。故答案为: √", + "knowledge_points": [ + "平面图形的分割", + "长方形", + "正方形", + "三角形和圆的初步认识" + ], + "source": "22-23一年级下·湖南常德·期中" + }, + { + "id": "293", + "unit": "认识图形", + "question_type": "判断题", + "difficulty": 0.65, + "question": "拼成一个大正方形至少需要 8 个小正方形。( )", + "options": [], + "answer": "×", + "solution": "【分析】自己动手画一画即可得出结论.\n【详解】如图:![](images/384fcbc408ee0ec7c99f12b5855801e693e86d94430ed1694fa1c409de41f760.jpg)拼成一个大正方形至少需要 4 个小正方形,原题结论错误。故答案为: ×", + "knowledge_points": [ + "正方形的概念及特点" + ], + "source": "23-24 一年级上·广东河源·期末" + }, + { + "id": "294", + "unit": "认识图形", + "question_type": "判断题", + "difficulty": 0.85, + "question": "用4个小□可以拼成一个大的正方形。( )", + "options": [], + "answer": "√", + "solution": "【分析】正方形:由 4 条边围成,且 4 条边都是一样长的。一行摆 2 个小 □,摆 2 行,就可以拼成一个大的正方形(如下图)。![](images/350e7cf9c4e877e5499c8ecf1e863789f1723f2749ebcd98bda1cfd387efe7aa.jpg)\n【详解】由题意分析得:用 4 个小 □ 可以拼成一个大的正方形;此说法正确。故答案为: √", + "knowledge_points": [ + "正方形的概念及特点", + "平面图形的拼接" + ], + "source": "22-23一年级下·山东菏泽·期中" + }, + { + "id": "295", + "unit": "认识图形", + "question_type": "判断题", + "difficulty": 0.85, + "question": "至少需要 4 个小正方形就可以拼出一个大正方形。( )", + "options": [], + "answer": "×", + "solution": "【分析】正方形的四条边相等,四个角都是直角;4个相同的小正方形才可以拼出一个大正方形。据此判断。熟练掌握对正方形的认识是解题关键.\n【详解】根据分析可知:至少需要 4 个相同的小正方形才可以拼出一个大正方形。原题说法错误。故答案为: ×。", + "knowledge_points": [ + "正方形的概念及特点" + ], + "source": "22-23 一年级下·浙江绍兴·期末" + }, + { + "id": "296", + "unit": "认识图形", + "question_type": "判断题", + "difficulty": 0.85, + "question": "一套七巧板有 7 块,其中三角形有 5 块,正方形有 2 块。( )", + "options": [], + "answer": "×", + "solution": "【分析】七巧板由正方形分割成七小块,其中:五块三角形,一块正方形和一块平行四边形组成;依此即可作答。本题考查学生对七巧板组成的掌握和运用.\n【详解】一套七巧板有 7 块,三角形有 5 块,正方形 1 块,平行四边形 1 块,所以题干说法错误。故答案为: ×。", + "knowledge_points": [ + "平行四边形的初步认识", + "用七巧板拼图形", + "长方形", + "正方形", + "三角形和圆的初步认识" + ], + "source": "22-23一年级·全国·假期作业" + }, + { + "id": "297", + "unit": "认识图形", + "question_type": "判断题", + "difficulty": 0.65, + "question": "![](images/7a6315d71ef7087ed582f9ebe99aba36ec711a7c99c720387cec4bfbbdd812c1.jpg) 这个图形中有3个平行四边形。( )", + "options": [], + "answer": "√", + "solution": "【分析】根据图示可知,该图有 1 个大平行四边形和 2 个小平行四边形,所以这个图形中有 3 个平行四边形;据此解答即可。本题考查了平行四边形的认识和图形的计数知识,结合图示解答即可.\n【详解】该图有1个大平行四边形和2个小平行四边形,所以这个图形中有 3 个平行四边形。故答案为: √。", + "knowledge_points": [ + "平行四边形的初步认识" + ], + "source": "20-21一年级下·青海玉树·期末" + }, + { + "id": "298", + "unit": "认识图形", + "question_type": "判断题", + "difficulty": 0.65, + "question": "用4个正方形只能拼成一个大的长方形。( )", + "options": [], + "answer": "×", + "solution": "【分析】如图,四个正方形既可以拼成长方形也可以拼成正方形,由此解答。![](images/2c49bbbfd37d624c355291372b32b9cf6512a03fe7c036dbd01f791cd966f0db.jpg)\n![](images/9e481accbd7e7ed06658a21473b49f666352321a03f33ca9abb0bd3a924ef991.jpg)。解答本题的关键是熟练掌握平面图形的特征,注意日常生活中对自己空间想象能力的培养.\n【详解】由分析可知,用 4 个正方形可以拼成一个大的长方形,也可以拼成一个正方形,原题说法错误;故答案为: ×", + "knowledge_points": [ + "长方形", + "正方形", + "三角形和圆的初步认识", + "平面图形的拼接" + ], + "source": "20-21一年级下·河北张家口·期末" + }, + { + "id": "299", + "unit": "认识图形", + "question_type": "判断题", + "difficulty": 0.85, + "question": "两个三角形可以拼成一个正方形。( )", + "options": [], + "answer": "×", + "solution": "【分析】如图:![](images/4fed1fc7f36b723438562ff17e4504983150da8c3ea03062ef15053721354c2d.jpg)只有如上图那样的两个完全一样的三角形才可以拼成一个正方形,据此判断即可。本题主要考查图形的拼组,关键是利用三角形和正方形的特点做题.\n【详解】两个三角形可以拼成一个正方形,原题说法错误。故答案为: ×。", + "knowledge_points": [ + "长方形", + "正方形", + "三角形和圆的初步认识", + "平面图形的拼接" + ], + "source": "21-22 一年级下·安徽宿州·期末" + }, + { + "id": "300", + "unit": "认识图形", + "question_type": "判断题", + "difficulty": 0.85, + "question": "长方形有 4 条边, 4 条边都相等。( )", + "options": [], + "answer": "×", + "solution": "【分析】长方形有 4 条边, 4 个直角,相对的两条边相等;正方形有 4 条相等的边, 4 个直角,据此即可解答。本题主要考查学生对长方形,正方形的初步认识.\n【详解】根据分析可知,长方形有 4 条边,相对的两条边相等,有 4 个直角,原说法错误。故答案为: ×。", + "knowledge_points": [ + "长方形", + "正方形", + "三角形和圆的初步认识" + ], + "source": "21-22 一年级下·全国·单元测试" + }, + { + "id": "301", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.65, + "question": "下面第 ( ) 个物体一定能画出 □ 。", + "options": [ + "A. 正方体", + "B. 长方体", + "C. 圆柱体" + ], + "answer": "A", + "solution": "【分析】要能画出正方形,物体必须有一个面是正方形。根据常见立体图形的特征,判断哪个物体的面全部或部分是正方形.\n【详解】A。 正方体的所有面都是正方形,一定能画出 □;B. 长方体的面可能是长方形(不一定是正方形);C. 圆柱体的底面是圆形,侧面是曲面,无法画出正方形。故答案为:A.", + "knowledge_points": [ + "立体图形的认识", + "长方形", + "正方形", + "三角形和圆的初步认识" + ], + "source": "21-22 一年级下·山西阳泉·期中" + }, + { + "id": "302", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.65, + "question": "用两个完全一样的三角形一定可以拼成下面哪个图形 ( )。", + "options": [ + "A. 长方形", + "B. 平行四边形", + "C. 正方形" + ], + "answer": "B", + "solution": "【分析】两个完全一样的三角形,只要将它们相等的一组边重合拼接,一定能拼成一个平行四边形。长方形和正方形则需要三角形是特定的类型(如直角三角形)才能拼成.\n【详解】无论三角形的形状如何,只要两个完全一样,将它们的一条相等边对齐拼接,一定能拼成一个平行四边形。而拼成长方形或正方形则需要三角形是直角三角形(且特定边长比例),并非\"一定\"能拼成。故答案为:B.", + "knowledge_points": [ + "平面图形的拼接", + "长方形", + "正方形", + "三角形和圆的初步认识", + "平行四边形的初步认识" + ], + "source": "18-19 四年级上·河南三门峡·期末" + }, + { + "id": "303", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.65, + "question": "数一数,下边的图形中共有 ( ) 个正方形.\n\n![](images/6b1ffbf1e9336c8f9018b8a65eb6696b1999af84061fbb4318b44bb092ccbe4c.jpg)", + "options": [ + "A. 5", + "B. 4", + "C. 1" + ], + "answer": "A", + "solution": "【分析】正方形是四条边相等,四个角都是直角的四边形。在数组合图形中的正方形时,应按照从小到大的顺序分类计数,既包括单独的小正方形,也包括由小正方形拼成的大正方形.\n【详解】图中单独的小正方形有4个;此外,这4个小正方形还组合成1个更大的正方形。因此,正方形的总数为:4 + 1 = 5(个)。故答案为:A.", + "knowledge_points": [ + "长方形", + "正方形", + "三角形和圆的初步认识" + ], + "source": "19-20一年级下·河南南阳·期中" + }, + { + "id": "304", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.65, + "question": "下图有 ( ) 个长方形.\n\n![](images/0476dd49bf072b2baa81f2c18330ca0ef4149d32e52113ef778a6181c888b2c7.jpg)", + "options": [ + "A. 1", + "B. 2", + "C. 3" + ], + "answer": "C", + "solution": "【分析】长方形是由四条边组成的四边形,对边相等,四个角都是直角。在数图形时,应先数单个的小长方形,再数由多个小长方形拼成的大长方形.\n【详解】图中单独的小长方形有2个;此外,这两个小长方形上下拼接,还组成了1个更大的长方形。因此,长方形的总数为:2 + 1 = 3(个)。故答案为:C.", + "knowledge_points": [ + "长方形", + "正方形", + "三角形和圆的初步认识" + ], + "source": "19-20 一年级下·四川德阳·期末" + }, + { + "id": "305", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.65, + "question": "七巧板是由 3 种图形拼成的,分别是 ( )。", + "options": [ + "A. 三角形,长方形,正方形", + "B. 三角形,平行四边形,正方形", + "C. 三角形,平行四边形,长方形" + ], + "answer": "B", + "solution": "【分析】七巧板是一套由7块几何板组成的拼图玩具。了解其基本构成是解答本题的关键,需要回忆或观察七巧板中包含哪些类型的平面图形.\n【详解】一副完整的七巧板包含以下三种图形:5个三角形,1个平行四边形和1个正方形。因此,七巧板是由三角形,平行四边形,正方形这三种图形拼成的。故答案为:B.", + "knowledge_points": [ + "长方形", + "正方形", + "三角形和圆的初步认识", + "用七巧板拼图形", + "平行四边形的初步认识" + ], + "source": "20-21 一年级下·四川乐山·期末" + }, + { + "id": "306", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.65, + "question": "人民币一角硬币的上下两个面都是 ( )。", + "options": [ + "A. 长方形", + "B. 圆", + "C. 正方形", + "D. 三角形" + ], + "answer": "B", + "solution": "【分析】因为硬币的形状是一个圆柱,圆柱的特征:圆柱的上下两个面叫作底面,它们是完全相同的两个圆,圆柱有一个曲面,叫作侧面;由此解答即可.\n【详解】因为硬币的形状是一个圆柱,圆柱的上下两个面都是圆形,所以人民币一角硬币的上下两个面都是圆。故选:B。此题考查了圆柱的特征,应理解并灵活运用。", + "knowledge_points": [ + "长方形", + "正方形", + "三角形和圆的初步认识" + ], + "source": "21-22 一年级下·湖北省直辖县级单位·期中" + }, + { + "id": "307", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.65, + "question": "把一张正方形的纸对折一次后,不可能出现的图形是 ( )。", + "options": [ + "A. 三角形", + "B. 长方形", + "C. 平行四边形" + ], + "answer": "C", + "solution": "【分析】正方形纸对折一次只有两种方式:沿对角线折或沿对边中点连线折。分析这两种折叠方式分别能得到什么图形,即可判断不可能出现的图形.\n【详解】把一张正方形纸对折一次:沿对角线折叠,展开后折痕两侧是两个完全相同的三角形;沿对边中点连线折叠,展开后折痕两侧是两个完全相同的长方形。无论哪种折法,都不可能得到平行四边形。故答案为:C.", + "knowledge_points": [ + "图形的折叠问题", + "长方形", + "正方形", + "三角形和圆的初步认识", + "平行四边形的初步认识" + ], + "source": "20-21一年级下·广西河池·期末" + }, + { + "id": "308", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "4 个同样的 □ 可以拼成一个( )。", + "options": [ + "A. 正方形", + "B. 长方形", + "C. 正方形或长方形" + ], + "answer": "C", + "solution": "【分析】4个同样的小正方形,通过不同的排列方式可以拼成不同的图形。考虑所有可能的排列情况,判断能拼成哪些图形.\n【详解】4个同样的小正方形:如果排成2行2列(即每行2个,每列2个),可以拼成一个大正方形;如果排成1行4列或4行1列,则可以拼成一个长方形。因此,可以拼成正方形或长方形。故答案为:C.", + "knowledge_points": [ + "平面图形的拼接" + ], + "source": "20-21 一年级下·云南文山·期末" + }, + { + "id": "309", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.65, + "question": "用圆柱体可以画出( )。", + "options": [ + "A. 平行四边形", + "B. 等边三角形", + "C. 圆形" + ], + "answer": "C", + "solution": "【分析】圆柱体是一个立体图形,它的底面是圆形。考虑用圆柱体的哪个部分与纸面接触,能够印出或画出什么形状.\n【详解】圆柱体的上下两个底面是完全相同的圆形。将圆柱体的底面蘸上颜料或在纸上滚动,可以画出圆形。而平行四边形和等边三角形都是直线围成的图形,无法通过圆柱体的曲面或圆形底面画出。故答案为:C.", + "knowledge_points": [ + "长方形", + "正方形", + "三角形和圆的初步认识" + ], + "source": "20-21 一年级下·云南文山·期末" + }, + { + "id": "310", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.65, + "question": "用![](images/13cf9f9055b223c1c74605fb19aef222169c23cc241fc90c0edc4ccfeac65e4d.jpg)做一个正方体,\"4\"的对面是( )。", + "options": [ + "A. 1", + "B. 3", + "C. 5" + ], + "answer": "B", + "solution": "【分析】正方体有 6 个面, 12 条棱,当沿着某棱将正方体剪开,可以得到正方体的展开图形,很显然,正方体的展开图形不是唯一的,但也不是无限的,事实上,正方体的展开图形有且只有11种,11种展开图形又可以分为4种类型:141型:中间一行4个作侧面,上下两个各作为上下底面,共有6种基本图形。231型:中间一行3个作侧面,共3种基本图形。222型:中间两个面,只有1种基本图形。33 型:中间没有面,两行只能有一个正方形相连,只有 1 种基本图形。根据正方体展开此图属于正方体展开图的 \"141\"型,做成一个正方体后,数字 \"1\"与 \"2\"相对,\"3\"与 \"4\"相对,\"5\"与 \"6\"相对.\n【详解】用该图做一个正方体,\"4\"的对面是\"3\"。 故答案为:B", + "knowledge_points": [ + "立体图形的认识", + "正方体的特征", + "正方体的展开图" + ], + "source": "2022·山东德州·小升初真题" + }, + { + "id": "311", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "这面墙缺了 ( ) 块砖.\n\n![](images/98e3ec3fd435e1fac1863930a1de10761e3b0aee276d14f885529ea683b6442f.jpg)", + "options": [ + "A. 8", + "B. 9", + "C. 10" + ], + "answer": "A", + "solution": "【分析】观察墙面上完整的砖块排列规律。通常,砖墙的砌法是有规律的,相邻两行的砖缝是错开的。通过对比各行砖的数量和位置,可以逐行计算出缺少的砖块数.\n【详解】观察墙面的排列规律(每行砖的数量和错位方式),依次数出空缺部分:第 2 行缺 2 块,第 3 行缺 3 块,第 4 行缺 3 块,总共2+3+3=8块。故选 A.", + "knowledge_points": [ + "平面图形的拼接" + ], + "source": "20-21一年级下·湖北荆州·期末" + }, + { + "id": "312", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "下面图形中与其他图形不是同类的是 ( )。", + "options": [ + "A. ![](images/0f4269a895a909c0aaa7538fd41e6bc61ee20268492919fbf64823241a7446d1.jpg)", + "B. ![](images/c47a8f196cfd78128f26a58bcbc35b582c3b7d51810d85953fe990a6deda01b8.jpg)", + "C. ![](images/39cf7d8ac384fb327a1cf84590dd02eda877675eb4bc2826cb6af4258f9008f0.jpg)" + ], + "answer": "B", + "solution": "【分析】根据平面图形和立体图形的概念选择即可.\n【详解】A。图形是长方形;B. 图形是立体图形中的长方体;C. 图形是正方形。A 和 C 属于平面图形,B 是立体图形。故答案为: B。本题主要考查了立体图形和平面图形的识别,解题的关键是分清平面图形与立体图形。", + "knowledge_points": [ + "立体图形的认识", + "长方形", + "正方形", + "三角形和圆的初步认识" + ], + "source": "20-21 一年级下·湖北孝感·期末" + }, + { + "id": "313", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.65, + "question": "最少用( )个相同![](images/2025-12-15%20193435.jpg)的可以拼成一个![](images/2025-12-15%20193505.jpg)", + "options": [ + "A. 3", + "B. 4", + "C. 5" + ], + "answer": "B", + "solution": "【分析】题目要求用若干个相同的小三角形拼成一个大梯形。需要先分析目标梯形的结构,思考如何用最少数量的小三角形通过拼接组合来覆盖其形状.\n【详解】观察目标梯形:可以将其分割为一个平行四边形和两个小三角形。先用2个小三角形拼成一个平行四边形,然后用另外2个小三角形分别拼在平行四形的上下两侧(或左右两侧),即可组成一个大梯形。因此,最少需要用4个相同的小三角形来拼成。故答案为:B.", + "knowledge_points": [ + "平面图形的拼接", + "长方形", + "正方形", + "三角形和圆的初步认识" + ], + "source": "17-18一年级下·辽宁·期末" + }, + { + "id": "314", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.65, + "question": "下面图形中, ( )是正方形。", + "options": [ + "A. ![](images/659be2482ace8980bc8a60a47e364759e7ff3f7bdc9c9b8542f2733f8fde938d.jpg)(图a)", + "B. ![](images/4b3bba584c8719effb70dbfcd650d4ebda84975c514f32657f88dae8e4cb7227.jpg)(图b)", + "C. ![](images/bcf64a988b7dd96d15e7e40bdcee0a4b311eb7598db54dcc69ab96ad7c34d240.jpg)(图c)" + ], + "answer": "C", + "solution": "【分析】根据正方形的定义,四个角都是直角,四条边都相等的四边形是正方形,解答此题即可.\n【详解】A。 图a是长方形;B. 图b是平行四边形;C. 图c是正方形。故答案为: C", + "knowledge_points": [ + "长方形", + "正方形", + "三角形和圆的初步认识", + "平行四边形的初步认识" + ], + "source": "20-21 一年级下·湖北孝感·期末" + }, + { + "id": "315", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "长方体有( )个面。", + "options": [ + "A. 3", + "B. 4", + "C. 6" + ], + "answer": "C", + "solution": "【分析】本题考查长方体的基本特征。长方体是一种常见的立体图形,有明确的面,棱,顶点数量.\n【详解】长方体是一个六面体,它有上,下,前,后,左,右共6个面。因此,长方体有6个面。故答案为:C.", + "knowledge_points": [ + "长方体的认识及特征", + "立体图形的认识" + ], + "source": "20-21 一年级下·黑龙江绥化·期末" + }, + { + "id": "316", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.94, + "question": "用( )物体可以画出 □ 。", + "options": [ + "A. 圆柱体", + "B. 正方体", + "C. 球体" + ], + "answer": "B", + "solution": "【分析】要画出正方形,需要物体的一个面是正方形。根据常见立体图形的特征,分析每个选项物体的面是否包含正方形.\n【详解】A。 圆柱体的底面是圆形,侧面是曲面,无法画出正方形;B. 正方体的所有面都是正方形,用其任何一个面都能画出 □;C. 球体是曲面,无法画出平面图形。因此,可以画出 □ 的物体是正方体。故答案为:B", + "knowledge_points": [ + "立体图形的认识", + "长方形", + "正方形", + "三角形和圆的初步认识" + ], + "source": "20-21一年级下·广东珠海·期末" + }, + { + "id": "317", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.65, + "question": "用下面哪个物体可以画出长方形。 ( )。", + "options": [ + "A. 球体", + "B. 长方体", + "C. 正方体" + ], + "answer": "B", + "solution": "【分析】要画出长方形,需要物体的一个面是长方形。根据常见立体图形的特征,判断哪个物体的面包含长方形.\n【详解】A。 球体是曲面,无法画出平面图形;B. 长方体的面通常是长方形(有时有正方形,正方形是特殊的长方形),因此可以用长方体的面画出长方形;C. 正方体的所有面都是正方形,画出的图形是正方形。因此,可以画出长方形的物体是长方体。故答案为:B.", + "knowledge_points": [ + "立体图形的认识", + "长方形", + "正方形", + "三角形和圆的初步认识" + ], + "source": "20-21 一年级下·吉林通化·期末" + }, + { + "id": "318", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.65, + "question": "下图的墙需要 ( )块砖才能补好.\n\n![](images/fa55b2985d5aaf57f4bac2d2f91950131df10373a3f3b041cdb8b786183b4a70.jpg)", + "options": [ + "A. 9", + "B. 10", + "C. 11" + ], + "answer": "C", + "solution": "【分析】观察砖墙的排列规律,通常上下两行砖缝错开。通过对比每一行完整应有的砖块数量与实际已有的砖块数量,逐行计算缺少的砖块数,再求和.\n【详解】观察墙面的错位排列规律,逐行数空缺:第 2 行缺 2 块,第 3 行缺 3 块,第 4 行缺 3 块,第 5 行缺 3 块,总共2+3+3+3=11块。故答案为:C.", + "knowledge_points": [ + "平面图形的拼接", + "长方形", + "正方形", + "三角形和圆的初步认识" + ], + "source": "20-21 一年级下·四川广元·期中" + }, + { + "id": "319", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.65, + "question": "用四个相同的 □ 不可能拼成( )。", + "options": [ + "A. 三角形", + "B. 正方形", + "C. 长方形" + ], + "answer": "A", + "solution": "【分析】根据题意,动手画一画,选择即可.\n【详解】如图:![](images/8276206e0ad6ceab39b2010517a0fcda6e3565b0a7041132b6041cd3e2268f3c.jpg)用四个相同的□可以拼成正方形和长方形,不能拼成三角形。故答案为: A", + "knowledge_points": [ + "平面图形的拼接", + "长方形", + "正方形", + "三角形和圆的初步认识" + ], + "source": "20-21 一年级下·内蒙古包头·期末" + }, + { + "id": "320", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.65, + "question": "![](images/f118e49cdc05979277763ed4a451f6b1a024f3faa021e87306d7df2ff3945242.jpg)是由第( ) 组图形组成的。", + "options": [ + "A. ![](images/5d596a05cb9eb5554c036b2b5c13cfef633e9e554fba32666ccff18a42117c94.jpg)(图a)", + "B. ![](images/af14200f0869b6de6d00655ff9172b2588e9a0edff3ccd94730617eaaea6b6a3.jpg)(图b)", + "C. ![](images/e22ebfafb1aab216e01be4e7b5a299e14c9fbb8d7105d50a3658376b20cee138.jpg)(图c)" + ], + "answer": "C", + "solution": "【分析】根据图示所给图形的形状,找到特征:由一个正方形和一个直角三角形拼成,进行选择.\n【详解】该图由图c组成的。故答案为: C", + "knowledge_points": [ + "平面图形的拼接", + "长方形", + "正方形", + "三角形和圆的初步认识" + ], + "source": "20-21 一年级下·内蒙古包头·期末" + }, + { + "id": "321", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.65, + "question": "七巧板是 ( ) 古代的一种拼板玩具。", + "options": [ + "A. 中国", + "B. 印度", + "C. 美国" + ], + "answer": "A", + "solution": "【分析】七巧板是一种古老的中国传统智力玩具,顾名思义,是由七块板组成的.\n【详解】七巧板是中国古代的一种拼板玩具。故答案为: A七巧板是由下面七块板组成的,完整图案为一正方形:五块等腰直角三角形(两块小形三角形,一块中形三角形和两块大形三角形),一块正方形和一块平行四边形。", + "knowledge_points": [ + "长方形", + "正方形", + "三角形和圆的初步认识", + "用七巧板拼图形" + ], + "source": "20-21 一年级下·山西晋中·期末" + }, + { + "id": "322", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.65, + "question": "下图有 ( ) 个长方形.\n\n![](images/81154b951c4f481908dd99d03a6eaa3eb36d52c3808fa30fe80d61a52fcb89f2.jpg)", + "options": [ + "A. 1", + "B. 2", + "C. 3" + ], + "answer": "C", + "solution": "【分析】长方形是由四条边组成的四边形,对边相等,四个角都是直角。在数组合图形中的长方形数量时,应按照从小到大的顺序分类计数,先数单个的小长方形,再数由多个小长方形拼成的大长方形,避免遗漏.\n【详解】图中单独的小长方形有2个(位于图形两侧);此外,这两个小长方形左右相连,还组成了1个更大的长方形。因此,长方形的总数为:2 + 1 = 3(个)。故答案为:C.", + "knowledge_points": [ + "长方形", + "正方形", + "三角形和圆的初步认识" + ], + "source": "20-21 一年级下·四川德阳·期末" + }, + { + "id": "323", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.65, + "question": "两个同样的正方形可以拼成一个( )。", + "options": [ + "A. 长方形", + "B. 正方形", + "C. 三角形" + ], + "answer": "A", + "solution": "【分析】用两个完全一样正方形是可以拼成一个长方形.\n【详解】两个同样的正方形可以拼成一个长方形。如图:![](images/aba1f42c0d6223280914c971992409543f8ad38ba9673200116c1524459de973.jpg)故答案为: A。本题主要考查图形的拼组,关键培养学生的操作能力和想象能力。", + "knowledge_points": [ + "平面图形的拼接", + "长方形", + "正方形", + "三角形和圆的初步认识" + ], + "source": "17-18一年级下·山东济宁·期末" + }, + { + "id": "324", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.65, + "question": "用两个同样的 □ 可以拼成一个( )。", + "options": [ + "A. 三角形", + "B. 长方形", + "C. 正方形" + ], + "answer": "B", + "solution": "【分析】根据长方形,正方形,三角形的特征,用两个同样的正方形可以拼成一个长方形。据此解答.\n【详解】用两个同样的□可以拼成一个长方形。故答案为: B。本题主要考查图形的拼组,关键是利用长方形,正方形,三角形的特征做题。", + "knowledge_points": [ + "平面图形的拼接", + "长方形", + "正方形", + "三角形和圆的初步认识" + ], + "source": "20-21一年级下·湖南永州·期末" + }, + { + "id": "325", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.65, + "question": "我国古代的一种拼板玩具,由7块板组成,拼出的图案变化万千,它是( )。", + "options": [ + "A. 七巧板", + "B. 九连环", + "C. 乐高积木" + ], + "answer": "A", + "solution": "【分析】本题考察对中国传统益智玩具的了解。需要根据\"7块板\"\"拼出图案变化万千\"等关键描述,对应到具体的玩具名称.\n【详解】我国古代有一种经典的拼板玩具,由7块几何板(三角形,正方形,平行四边形)组成,可以拼出人物,动物,建筑等成千上万种图案,这种玩具就是\"七巧板\"。九连环是一种金属环类解环玩具,乐高积木是现代塑料积木。因此,由7块板组成且拼图变化万千的玩具是七巧板。故答案为:A.", + "knowledge_points": [ + "平面图形的拼接", + "长方形", + "正方形", + "三角形和圆的初步认识", + "用七巧板拼图形" + ], + "source": "20-21一年级下·湖南怀化·期末" + }, + { + "id": "326", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.65, + "question": "如图中缺了 ( ) 块砖.\n\n![](images/5ddae1c10a9ebf121d1b4277fe963494531252074d6ee531b9cc206c6cf40f1b.jpg)", + "options": [ + "A. 6", + "B. 7", + "C. 4" + ], + "answer": "A", + "solution": "【分析】观察砖墙的排列规律,上下两行砖缝错开。通过对比每一行完整应有的砖块数量与实际已有的砖块数量,逐行计算缺少的砖块数,再求和.\n【详解】观察墙面的错位排列规律,逐行数空缺:第 2 行缺 2 块,第 3 行缺 4 块,总共2+4=6块。故答案为:A", + "knowledge_points": [ + "平面图形的拼接", + "长方形", + "正方形", + "三角形和圆的初步认识" + ], + "source": "20-21一年级下·湖南郴州·期末" + }, + { + "id": "327", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.65, + "question": "把一张长方形的纸剪成大小相等的两块,有( )种不同的剪法。", + "options": [ + "A. 2", + "B. 3", + "C. 4" + ], + "answer": "C", + "solution": "【分析】将长方形剪成大小相等的两块,关键是要找到能使两部分完全重合的剪裁线。这些剪裁线通常是经过长方形中心的直线,包括沿对称轴或对角线等.\n【详解】把一张长方形的纸剪成大小相等的两块,有以下四种不同的剪法:沿长方形的长的中点连线(垂直方向)剪开,得到两个小长方形。沿长方形的宽的中点连线(水平方向)剪开,得到两个小长方形。沿长方形的一条对角线剪开,得到两个直角三角形。沿长方形的另一条对角线剪开,得到两个直角三角形。因此,共有4种不同的剪法。故答案为:C.", + "knowledge_points": [ + "平面图形的分割", + "长方形", + "正方形", + "三角形和圆的初步认识" + ], + "source": "20-21一年级下·湖南张家界·期末" + }, + { + "id": "328", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.65, + "question": "小明用![](images/3d122703041e6738aa1c9cf42d92f2dfae878d44f50d7733b520596519e10894.jpg)做一个正方体,\"6\"的对面是 ( )。", + "options": [ + "A. 5", + "B. 3", + "C. 1" + ], + "answer": "A", + "solution": "【分析】本题考查正方体展开图中相对面的判断。该展开图属于\"1-4-1\"型。在这种类型的展开图中,处于中间一行四个面的两侧的两个面是相对的.\n【详解】在给出的\"1-4-1\"型展开图中,数字\"6\"和\"5\"位于中间一行四个面的上下两侧,折叠成正方体后,它们会成为相对的面。因此,\"6\"的对面是\"5\"。故答案为:A.", + "knowledge_points": [ + "长方形", + "正方形", + "三角形和圆的初步认识", + "正方体的展开图" + ], + "source": "20-21一年级下·湖南岳阳·期末" + }, + { + "id": "329", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "在拼成的下边图形中没有用到的是( ).\n\n![](images/dc0ac0bef2909862196598240928c8c4a56dd3340386594edbfb8744a6d6f5c9.jpg)", + "options": [ + "A. 长方形", + "B. 正方形", + "C. 三角形", + "D. 圆形" + ], + "answer": "A", + "solution": "【分析】根据图示可知,拼成的小船图案用到的图形为:三角形,正方形,圆形,据此解答即可.\n【详解】根据分析可知,在拼成的图形中没有用到长方形。故答案为:A。本题主要考查对长方形,正方形,三角形和圆的初步认识,关键是能掌握平面图形的特征。", + "knowledge_points": [ + "长方形", + "正方形", + "三角形和圆的初步认识" + ], + "source": "20-21一年级下·湖南岳阳·期末" + }, + { + "id": "330", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "下图中有 ( ) 个正方形.\n\n![](images/2885557e39f10623e1383647df473a0048868314968099995bfbcfc333f3362c.jpg)", + "options": [ + "A. 2", + "B. 3", + "C. 4" + ], + "answer": "A", + "solution": "【分析】正方形是四条边相等,四个角都是直角的四边形。在复杂的图案中数正方形,需要仔细观察图形的每一部分,判断哪些部分符合正方形的特征.\n【详解】观察火箭图案:火箭头部是三角形,身体部分主要由长方形组成。仅在火箭身体中间部分,有两段(或两个)独立的,四条边相等且角为直角的图形,符合正方形的特征。因此,图中共有2个正方形。故答案为:A", + "knowledge_points": [ + "长方形", + "正方形", + "三角形和圆的初步认识" + ], + "source": "20-21 一年级下·河南濮阳·期末" + }, + { + "id": "331", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.65, + "question": "![](images/69cb2e956b0ff05b26a503a026ff0282841e770c00b08b7adc5af6c289c7d01e.jpg)图中有( )个三角形。", + "options": [ + "A. 5", + "B. 4", + "C. 3", + "D. 2" + ], + "answer": "C", + "solution": "【分析】根据三角形的特点,判定有几个三角形。找到同一个顶点组成的角,标上数字,将所有的数字相加,即可求出一共有多少个三角形.\n【详解】1+2=3(个),故答案为: C。本题主要考查三角形的特点。根据三角形的特点,找出一共有几个三角形。", + "knowledge_points": [ + "长方形", + "正方形", + "三角形和圆的初步认识" + ], + "source": "20-21一年级下·河南三门峡·期中" + }, + { + "id": "332", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.65, + "question": "这两个相同的三角形可以拼成一个( ).\n\n![](images/4fefe090e32cd99031181fa224c26604ade41a1e42ff5675a808487ed0b15a52.jpg)\n\n其中 A 表示三角形,B 表示长方形,C 表示圆形,D 表示正方形。", + "options": [ + "A. AD", + "B. BC", + "C. BD", + "D. CD" + ], + "answer": "A", + "solution": "【分析】图中是两个完全相同的等腰直角三角形。考虑它们通过不同边的拼接,可以组成哪些新的图形。尤其注意等腰直角三角形拼接的特殊性.\n【详解】这两个等腰直角三角形,如果将它们的斜边拼接在一起,可以组成一个更大的等腰三角形;如果将它们的直角边拼接在一起(长边对长边或短边对短边),可以组成一个正方形。因此,它们可以拼成三角形(A选项)和正方形(D选项)。故答案为:A(对应AD选项)。", + "knowledge_points": [ + "平面图形的拼接", + "长方形", + "正方形", + "三角形和圆的初步认识" + ], + "source": "19-20一年级下·福建龙岩·期末" + }, + { + "id": "333", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.65, + "question": "用![](images/2025-12-15%20201116.jpg)做成一个正方体,数字 2 的对面是 ( )。", + "options": [ + "A. 3", + "B. 4", + "C. 5", + "D. 1" + ], + "answer": "D", + "solution": "【分析】本题考查正方体展开图中相对面的判断。该展开图属于\"1-4-1\"型,中间一行有四个面。在这种类型的展开图中,相对的两个面通常位于中间一行的两端(即隔一个面的两个面),或者是上下两个单独的面相对.\n【详解】在给出的\"1-4-1\"型展开图中,中间一行从左到右依次是1,4,2,3。根据\"相对的面不相邻\"的规律,数字\"2\"与它相邻的数字是4,3,因此它的对面只能是\"1\"。故答案为:D.", + "knowledge_points": [ + "图形的折叠问题", + "正方体的展开图" + ], + "source": "19-20 一年级下·福建龙岩·期末" + }, + { + "id": "334", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.65, + "question": "折一折,用![](images/52176a2bed664aa44eee507fb1184fa9818ae9ebe27e5439d0fae5ebb55a0638.jpg)做一个正方体,\"3\"的对面是( )。", + "options": [ + "A. 2", + "B. 5", + "C. 1" + ], + "answer": "C", + "solution": "【分析】本题考查正方体展开图中相对面的判断。该展开图属于\"1-4-1\"型,中间一行有四个数字。需要找出与数字\"3\"不相邻的数字,即为它的对面.\n【详解】在给出的\"1-4-1\"型展开图中,中间一行从左到右依次是1,2,3,4,上下分别是5和6。数字\"3\"与2,4都相邻,只有\"1\"与它隔着一个数字\"2\",根据\"相对不相邻\"原则,\"3\"的对面是\"1\"。故答案为:C.", + "knowledge_points": [ + "图形的折叠问题" + ], + "source": "20-21 一年级下·福建莆田·期末" + }, + { + "id": "335", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.65, + "question": "把下边的三角形沿虚线剪开,得到的两个图形还可以拼成( ).\n\n![](images/23dbb779d6f9f36b12fcdedcbdc14eae0e1ebc6fdb0e93055c3c4a1d201e198c.jpg)", + "options": [ + "A. 正方形", + "B. 圆", + "C. 长方形" + ], + "answer": "C", + "solution": "【分析】观察原图,这是一个直角三角形。沿虚线(即斜边上的高线)剪开,会得到两个完全相同的直角三角形。分析这两个直角三角形通过拼接可能组成的图形.\n【详解】沿虚线剪开后,得到两个完全相同的直角三角形。这两个直角三角形可以通过将它们的斜边或直角边进行拼接。如果将它们的斜边拼接,可以组成一个长方形;如果将两条相等的直角边拼接,可以组成一个等腰三角形。但无法拼成正方形(需要等腰直角三角形)或圆形(由曲线围成)。因此,可以拼成的图形是长方形。故答案为:C.", + "knowledge_points": [ + "平面图形的拼接", + "平面图形的分割", + "长方形", + "正方形", + "三角形和圆的初步认识" + ], + "source": "20-21 一年级下·福建南平·期末" + }, + { + "id": "336", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.4, + "question": "折一折,用![](images/af8e1ad6550920fadd617be73993a90af8b206b98b44382e4399bacee842a6ed.jpg)做一个正方体,\"们\"的对面是( )。", + "options": [ + "A. 我", + "B. 好", + "C. 是" + ], + "answer": "B", + "solution": "【分析】本题考查正方体展开图中相对面的判断。该展开图属于\"1-4-1\"型,中间一行有四个汉字。需要找出与\"们\"字不相邻的汉字,即为它的对面.\n【详解】在给出的\"1-4-1\"型展开图中,中间一行从左到右依次是\"我\",\"们\",\"是\",\"好\"。根据\"相对的面不相邻\"的原则,\"们\"字与\"我\",\"是\"相邻,与\"好\"字中间隔着一个\"是\"字,因此\"们\"的对面是\"好\"。故答案为:B.", + "knowledge_points": [ + "长方形", + "正方形", + "三角形和圆的初步认识", + "正方体的展开图" + ], + "source": "20-21 一年级下·福建泉州·期中" + }, + { + "id": "337", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.65, + "question": "下面能拼成正方形的图形是 ( )。", + "options": [ + "A. ![](images/10e496f9e31cadd7fc04f34d7d0aa0a74b6a818f9072cabd12373cb2859e55eb.jpg)", + "B. ![](images/150d6928d0290de7404ad5fe9fdd061a9bbb59c1d82f86419cc13117fa1d6f6d.jpg)", + "C. ![](images/218fd731fb13566aca18d9067745d74de2b29b7fba2af0f2488d03e62634b9a0.jpg)" + ], + "answer": "C", + "solution": "【分析】根据所给图形的特点及正方形的特点进行选择即可.\n【详解】A。 选项两个两条直角边不相等的直角三角形可以拼成长方形和平行四边形,不能拼成正方形;B. 选项两个正方形可以拼成长方形,不能拼成正方形;C. 选项两个图形拼在一起,可以拼成正方形。故答案为: C。本题主要考查图形的拼组,关键利用正方形的特点做题。", + "knowledge_points": [ + "平面图形的拼接", + "长方形", + "正方形", + "三角形和圆的初步认识" + ], + "source": "20-21 一年级下·福建福州·期末" + }, + { + "id": "338", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.65, + "question": "用 4 根同样长的小棒,可以摆成的图形是 ( )。", + "options": [ + "A. 长方形", + "B. 正方形", + "C. 三角形" + ], + "answer": "B", + "solution": "【分析】用给定数量的小棒摆图形,需要结合各种平面图形边的数量特征来判断。三角形有3条边,长方形和正方形都有4条边,但长方形对边相等,正方形四条边都相等。由于小棒长度相同,只能摆出四条边都相等的图形.\n【详解】用4根同样长的小棒:A. 长方形需要对边相等,四条边不一定相等;B. 正方形的4条边长度相等,刚好可以用4根小棒摆成;C. 三角形只有3条边,4根小棒无法摆成。故答案为:B。", + "knowledge_points": [ + "长方形", + "正方形", + "三角形和圆的初步认识" + ], + "source": "20-21 一年级下·安徽铜陵·期末" + }, + { + "id": "339", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.65, + "question": "用两个同样的 ( ) 可以拼成一个平行四边形。", + "options": [ + "A. 三角形", + "B. 长方形", + "C. 正方形" + ], + "answer": "A", + "solution": "【分析】平行四边形是由两组对边分别平行的四边形。判断两个同样的哪种图形能拼成平行四边形,需要考虑图形拼接后的边角关系.\n【详解】两个完全相同的三角形,将它们的相等边拼接,可以组成一个平行四边形;而两个长方形或正方形拼接后通常是长方形(或正方形),不是平行四边形。故答案为:A.", + "knowledge_points": [ + "平行四边形的切拼", + "长方形", + "正方形", + "三角形和圆的初步认识" + ], + "source": "20-21 一年级下·河北张家口·期中" + }, + { + "id": "340", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.65, + "question": "把下面的图形补成一个大一些的正方形,至少还要加( )个小正方形.\n\n![](images/1c2030ebfd6015b796409ed0b261076017301e2d0c4c70d4a3726d52ce361990.jpg)", + "options": [ + "A. 1", + "B. 2", + "C. 3", + "D. 4" + ], + "answer": "D", + "solution": "【分析】要补成一个大正方形,需要使图形在水平和垂直方向上都达到相同的长度(即边长)。观察原图形,找出当前图形在水平和垂直方向上的最大长度,然后计算需要添加的小正方形数量,使图形扩展成一个完整的正方形网格.\n【详解】观察图形,当前图形最宽处(水平方向)占3个小正方形的边长,最高处(垂直方向)也占3个小正方形的边长。要补成一个完整的3×3大正方形,需要添加的小正方形数量为:大正方形总格子数(9个)减去现有小正方形数量(5个)。现有5个小正方形,因此需要添加 9 - 5 = 4(个)小正方形。故答案为:D.", + "knowledge_points": [ + "正方形的概念及特点", + "平面图形的拼接" + ], + "source": "20-21 一年级下·江苏南京·期中" + }, + { + "id": "341", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.65, + "question": "下面不是平行四边形的是( )。", + "options": [ + "A. ![](images/4ca9e112613f6803134da641e0b3a6886c4ba662b1ae1b33f09b989572510a6f.jpg)", + "B. ![](images/44047bcdde7fdac847a443017a33d13d424d3e46e03fc4d3e0c2153da1ed66ee.jpg)", + "C. ![](images/46820ad09f04297ed1f17b4111dedb3f64907d9f4dca05c4c90d732f5dfdf370.jpg)" + ], + "answer": "A", + "solution": "【分析】平行四边形的定义是\"两组对边分别平行的四边形\"。判断一个图形是否为平行四边形,需要看它的对边是否平行.\n【详解】A。 这是一个梯形,只有一组对边平行,另一组对边不平行,因此不是平行四边形。B。 这是一个普通的平行四边形,两组对边分别平行。C。 这是一个菱形,菱形是特殊的平行四边形(两组对边分别平行且相等)。因此,不是平行四边形的是选项A。故答案为:A.", + "knowledge_points": [ + "长方形", + "正方形", + "三角形和圆的初步认识" + ], + "source": "20-21 一年级下·河北张家口·期末" + }, + { + "id": "342", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.94, + "question": "下面的图形能拼成正方形的是 ( )。", + "options": [ + "A. ![](images/f286c8de5869a56637c5378c62df5be22ca21128816f07b06b39fe1c0fec25d5.jpg)", + "B. ![](images/48630265b8e4a1e809dc4a59074df1e3409bdbc09870abea14678a355cf73f83.jpg)", + "C. ![](images/2025-12-15%20203057.jpg)" + ], + "answer": "C", + "solution": "【分析】判断两个图形能否拼成正方形,需要观察两个图形的形状,大小以及拼接方式,看是否能组合成一个四条边相等,四个角都是直角的图形.\n【详解】A。 两个完全相同的直角三角形,拼在一起可以组成一个长方形或平行四边形,但不能直接拼成正方形(除非是等腰直角三角形)。B。 两个小正方形拼在一起,只能组成一个长方形,不能拼成正方形。C。 左边是一个缺了一个小长方形的近似\"L\"形,右边是一个小长方形。将右边的小长方形填补到左边的缺口处,可以组成一个完整的正方形。因此,能拼成正方形的是选项C。故答案为:C.", + "knowledge_points": [ + "平面图形的拼接", + "长方形", + "正方形", + "三角形和圆的初步认识" + ], + "source": "17-18 一年级下·全国·期末" + }, + { + "id": "343", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.65, + "question": "从一张长 13 厘米,宽 5 厘米的长方形纸片上可以剪下( )个最大的正方形。", + "options": [ + "A. 1", + "B. 2", + "C. 3" + ], + "answer": "B", + "solution": "【分析】要从长方形中剪出最大的正方形,正方形的边长应等于长方形的宽(5厘米)。然后看长方形的长(13厘米)里面最多能包含几个这样的边长(5厘米).\n【详解】最大的正方形边长是5厘米(等于长方形的宽)。长方形的长是13厘米。剪第一个正方形后,剩下纸片的长为:13 - 5 = 8(厘米),宽仍为5厘米。剪第二个正方形后,剩下纸片的长为:8 - 5 = 3(厘米),宽仍为5厘米。此时剩下的长3厘米小于正方形的边长5厘米,无法再剪出一个完整的正方形。因此,最多可以剪下2个最大的正方形。故答案为:B.", + "knowledge_points": [ + "平面图形的分割", + "长方形", + "正方形", + "三角形和圆的初步认识" + ], + "source": "20-21 二年级下·河南商丘·期末" + }, + { + "id": "344", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.65, + "question": "用两个完全相同的长方形不能拼成( )。", + "options": [ + "A. 正方形", + "B. 长方形", + "C. 圆" + ], + "answer": "C", + "solution": "【分析】将两个完全相同的长方形的长边重合,可能拼成一个正方形;将两个完全相同的长方形的短边重合,可以拼成一个长方形;长方形:有四个尖尖的角,四条直直的边,相对的两条边一样长;圆:没有尖尖的角,没有直直的边,圆溜溜的;据此解答.\n【详解】根据分析:A. 将两个完全相同的长方形的长边重合,可能拼成一个正方形,如图:![](images/c7f5caa97169cb252b97bd7f9c61dff698e0528cc52b554fd5ac57ef4cafa5cc.jpg) B. 将两个完全相同的长方形的短边重合,可以拼成一个长方形,如图:![](images/9e6829a8abbf9e2f9bae17e5f7772b77fe9c9ceb034a52a424784ba005c0748f.jpg) C. 长方形有四个尖尖的角,圆没有尖尖的角,所以两个完全相同的长方形不能拼成圆。故答案为: C", + "knowledge_points": [ + "平面图形的拼接", + "长方形", + "正方形", + "三角形和圆的初步认识" + ], + "source": "20-21 一年级下·江西抚州·期末" + }, + { + "id": "345", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "下面可以画出正方形的物体是( )。", + "options": [ + "A. 圆柱体", + "B. 长方体", + "C. 正方体" + ], + "answer": "C", + "solution": "【分析】要能画出正方形,物体必须有一个面是正方形。根据常见立体图形的特征,分析每个选项的物体是否有正方形的面.\n【详解】A。 圆柱体的上下底面是圆形,侧面是曲面,无法画出正方形。B。 长方体的面通常是长方形(特殊情况下可能有两个面是正方形),但不能保证一定有一个面是正方形。C。 正方体的所有面都是正方形,用它的任何一个面都能画出正方形。因此,可以画出正方形的物体是正方体。故答案为:C.", + "knowledge_points": [ + "长方形", + "正方形", + "三角形和圆的初步认识" + ], + "source": "18-19一年级下·四川绵阳·期末" + }, + { + "id": "346", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.65, + "question": "![](images/e73e48ff99cc3cc418ea2b224d975b762f629a0bc93836e8c7553606b1119703.jpg)左图中有( ) 个圆。", + "options": [ + "A. 5", + "B. 4", + "C. 6" + ], + "answer": "A", + "solution": "【分析】圆是由一条曲线围成的封闭图形。观察左图,这是奥运五环标志,由五个环形相交组成。需要仔细辨认每个独立的环形轮廓.\n【详解】图中是奥运五环图案,由五个相互连接的环组成,每个环都是一个独立的圆形。因此,图中一共有5个圆。故答案为:A.", + "knowledge_points": [ + "数一数", + "长方形", + "正方形", + "三角形和圆的初步认识" + ], + "source": "21-22 一年级下·全国·周测" + }, + { + "id": "347", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.65, + "question": "用 ( ) 个三角形可以拼成一个平行四边形。", + "options": [ + "A. 4", + "B. 3", + "C. 2" + ], + "answer": "C", + "solution": "【分析】平行四边形的两组对边分别平行且相等。考虑如何用三角形拼接出这样的图形。两个完全一样的三角形,通过将它们的相等边重合,可以组成一个平行四边形.\n【详解】两个完全相同的三角形,将它们的一条相等边对齐拼接,可以组成一个平行四边形。这是构成平行四边形最常用的方法。因此,用2个三角形可以拼成一个平行四边形。故答案为:C.", + "knowledge_points": [ + "平面图形的拼接", + "长方形", + "正方形", + "三角形和圆的初步认识" + ], + "source": "21-22一年级下·全国·周测" + }, + { + "id": "348", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.94, + "question": "用小棒摆1个正方形,至少要( )根同样长的小棒。", + "options": [ + "A. 4", + "B. 5", + "C. 6" + ], + "answer": "A", + "solution": "【分析】正方形有4条边,且四条边长度相等。用小棒摆正方形,每根小棒代表一条边.\n【详解】因为正方形有4条边,所以至少需要用4根同样长的小棒才能摆出一个正方形。故答案为:A.", + "knowledge_points": [ + "长方形", + "正方形", + "三角形和圆的初步认识" + ], + "source": "19-20一年级下·湖南怀化·单元测试" + }, + { + "id": "349", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.65, + "question": "![](images/d5be02aef272caec4e110fe198a32ee336d089826d01f3b0851cd37884971819.jpg)左图中共有( )个三角形。", + "options": [ + "A. 3", + "B. 6", + "C. 10" + ], + "answer": "B", + "solution": "【分析】三角形是由三条边围成的封闭图形。在组合图形中数三角形,需要按照一定的顺序(如从小到大)分类计数,避免遗漏或重复.\n【详解】观察图形,可以分层计数:最小的单个三角形有3个。由两个小三角形组成的三角形有2个(位于图形两侧)。由三个小三角形组成的大三角形有1个(整个图形)。因此,三角形的总数为:3 + 2 + 1 = 6(个)。故答案为:B.", + "knowledge_points": [ + "长方形", + "正方形", + "三角形和圆的初步认识" + ], + "source": "20-21 一年级下·山西太原·期末" + }, + { + "id": "350", + "unit": "认识图形", + "question_type": "填空题", + "difficulty": 0.65, + "question": "![](images/87a0c00ef5007811d67edf0fde1516b4abd46fe6c9c86e7985f044d0abe68565.jpg)左图用了( )个同样的小正方形,至少再添( )个这样的小正方形就可以拼成一个大正方形。", + "options": [], + "answer": "5;4", + "solution": "【分析】先数出图中现有小正方形的个数。要拼成一个大正方形,大正方形的边长需要是整数个小正方形。找出能包含现有图形的最小大正方形边长,计算所需小正方形的总数,再减去已有的数量.\n【详解】图中是由5个小正方形组成的\"十\"字形。要拼成一个大正方形,最小的可能性是拼成一个边长为3个小正方形的大正方形(共9个小正方形)。因此,总共需要9个小正方形。已有5个,还需要添加:9-5=4(个)。故答案为:5;4。", + "knowledge_points": [ + "平面图形的拼接", + "长方形", + "正方形", + "三角形和圆的初步认识" + ], + "source": "21-22 一年级下·福建三明·期中" + }, + { + "id": "351", + "unit": "认识图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "如图,\"七巧板\"是我国古代的一种拼板玩具,它是由( )个三角形,( )个正方形和( )个平行四边形组成的.\n\n![](images/aca24159282474cf5325e2f109ccd6519b63e59a97666e155f2fa4eb9a8d321d.jpg)", + "options": [], + "answer": "5;1;1", + "solution": "【分析】七巧板是一套经典的拼图玩具,由7块几何板组成。需要熟悉七巧板的构成,准确数出其中三角形,正方形和平行四边形的数量.\n【详解】一副完整的七巧板包含以下图形:5个三角形(2个大三角形,1个中三角形,2个小三角形),1个正方形,1个平行四边形。因此,它是由5个三角形,1个正方形和1个平行四边形组成的。故答案为:5;1;1。", + "knowledge_points": [ + "长方形", + "正方形", + "三角形和圆的初步认识", + "用七巧板拼图形", + "平行四边形的初步认识" + ], + "source": "20-21一年级下·四川绵阳·期末" + }, + { + "id": "352", + "unit": "认识图形", + "question_type": "填空题", + "difficulty": 0.65, + "question": "用![](images/798a745a4c5ce95f268fa487b11cb50257f99d07025d1ef72cbd0c2627c29eca.jpg)做一个正方体,\"2\"的对面是( )。", + "options": [], + "answer": "4", + "solution": "【分析】由图可知,如果以 \"2\" 所在的正方形为底面,那么 \"3\"所在的正方形在前面,\"1\"所在的正方形在后面,\"5\"所在的正方形在左面,\"6\"所在的正方形在右面,\"4\"所在的正方形在最上面。据此解答.\n【详解】由分析可得,如果 \"2\" 所在的正方形为底面,那么 \"4\" 所在的正方形在最上面,\"2\"和 \"4\"相对。故用该图做一个正方体,\"2\"的对面是\"4\"。", + "knowledge_points": [ + "立体图形的认识", + "正方体的展开图" + ], + "source": "20-21 一年级下·甘肃陇南·阶段练习" + }, + { + "id": "353", + "unit": "认识图形", + "question_type": "填空题", + "difficulty": 0.65, + "question": "至少用( )个相同的 □ 可以拼成一个大正方形,至少用( )个相同的正方体可以拼成一个大正方体。", + "options": [], + "answer": "4;8", + "solution": "【分析】小正方形拼组大正方形,每条边长上至少需要2个小正方形,由此即可求得小正方形的个数;小正方体拼组大正方体,每条棱长上至少需要2个小正方体,由此即可求得小正方体的个数.\n【详解】至少用4个完全相同的□才可以拼成一个大正方形;至少用8个完全相同的正方体才可以拼成一个大正方体。故答案为:4;8。", + "knowledge_points": [ + "立体图形的切拼", + "立体图形的认识", + "平面图形的拼接", + "长方形", + "正方形", + "三角形和圆的初步认识" + ], + "source": "20-21 一年级下·山西阳泉·期中" + }, + { + "id": "354", + "unit": "认识图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "两个完全一样大的长方形可以拼成一个( )形或者( )形。", + "options": [], + "answer": "长方;正方", + "solution": "【分析】两个完全一样的长方形,通过不同的拼接方式,可以组成新的图形。考虑将它们的哪一组边拼接在一起.\n【详解】两个完全一样的长方形:如果将它们的长边拼接在一起,可以拼成一个更长的长方形。如果长方形的长是宽的2倍,将它们的宽边拼接在一起,可以拼成一个正方形(因为此时新图形的长和宽相等)。因此,可以拼成一个长方形或者正方形。故答案为:长方;正方。", + "knowledge_points": [ + "平面图形的拼接", + "长方形", + "正方形", + "三角形和圆的初步认识" + ], + "source": "20-21一年级下·新疆省直辖县级单位·期中" + }, + { + "id": "355", + "unit": "认识图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "一元硬币的面是( )形;红领巾的面是( )形。", + "options": [], + "answer": "圆;三角", + "solution": "【分析】根据日常生活中常见物品的形状进行判断。一元硬币是圆柱体,它的上下底面是圆形;展开的红领巾是三角形.\n【详解】一元硬币的上下两个面都是圆形;红领巾展开后是一个三角形。故答案为:圆;三角。", + "knowledge_points": [ + "长方形", + "正方形", + "三角形和圆的初步认识" + ], + "source": "19-20 一年级下·河南南阳·期中" + }, + { + "id": "356", + "unit": "认识图形", + "question_type": "填空题", + "difficulty": 0.65, + "question": "![](images/2025-12-15%20205507.jpg)是由( )个长方形和( )个三角形拼成的。", + "options": [], + "answer": "2;3", + "solution": "【分析】观察图形(类似小船),识别出组成它的基本图形:长方形和三角形。按照图形的位置和形状逐一计数.\n【详解】该图形中:长方形:船身的主体部分(下方的矩形)和船帆的竖杆部分,共2个。三角形:船身两侧的两个小三角形和船帆顶部的三角形,共3个。因此,它是由2个长方形和3个三角形拼成的。故答案为:2;3。", + "knowledge_points": [ + "长方形", + "正方形", + "三角形和圆的初步认识" + ], + "source": "19-20 一年级下·河南南阳·期中" + }, + { + "id": "357", + "unit": "认识图形", + "question_type": "填空题", + "difficulty": 0.65, + "question": "一套七巧板中有( )块三角形, ( )块正方形, ( )块平行四边形。", + "options": [], + "answer": "5;1;1", + "solution": "【分析】七巧板是经典的拼图玩具,由7块几何板组成。需要准确记忆或观察七巧板的构成,数出每种图形的数量.\n【详解】一套七巧板共有7块,其中包括:5个三角形(2个大三角形,1个中三角形,2个小三角形),1个正方形,1个平行四边形。故答案为:5;1;1。", + "knowledge_points": [ + "长方形", + "正方形", + "三角形和圆的初步认识", + "用七巧板拼图形", + "平行四边形的初步认识" + ], + "source": "21-22 一年级下·湖北省直辖县级单位·期中" + }, + { + "id": "358", + "unit": "认识图形", + "question_type": "填空题", + "difficulty": 0.65, + "question": "![](images/aa9d19b82e846f1d7b85e77cf68fac08e772bf19c9684142b6a3db4300b18995.jpg)沿虚线对折后,折成的图形是( )形。", + "options": [], + "answer": "正方", + "solution": "【分析】观察原图是一个长方形,虚线位于长方形长的中点。对折后,长方形的长变为原来的一半,而宽不变。分析对折后图形的边长关系,判断其形状.\n【详解】原长方形沿虚线(长的中点连线)对折后,长方形的长被平分,新图形的长变为原长的一半,宽不变。由于图中长方形的宽正好等于原长的一半(根据虚线位置判断),因此对折后,新图形的两条邻边长度相等,且四个角都是直角,所以它是一个正方形。故答案为:正方。", + "knowledge_points": [ + "图形的折叠问题", + "长方形", + "正方形", + "三角形和圆的初步认识" + ], + "source": "21-22一年级下·河南周口·阶段练习" + }, + { + "id": "359", + "unit": "认识图形", + "question_type": "填空题", + "difficulty": 0.65, + "question": "用![](images/2025-12-15%20210000.jpg)可以画出( )个不同的长方形。", + "options": [], + "answer": "3", + "solution": "【分析】长方体有6个面,且都是长方形,上下面相等,左右面相等,前后面相等,因此用该图可以画出3个不同的长方形.\n【详解】用该图可以画出3个不同的长方形。故答案为:3。", + "knowledge_points": [ + "立体图形的认识", + "长方形", + "正方形", + "三角形和圆的初步认识" + ], + "source": "21-22一年级下·河南周口·阶段练习" + }, + { + "id": "360", + "unit": "认识图形", + "question_type": "填空题", + "difficulty": 0.4, + "question": "用![](images/d38d5098d68f8295c047bf75051d1e055e764d3110525438eba6f1d1b1d75480.jpg)做成一个正方体,数字\"4\"的对面是数字( )。", + "options": [], + "answer": "2", + "solution": "【分析】本题考查正方体展开图中相对面的判断。该展开图属于\"1-4-1\"型,中间一行有四个数字。根据\"相对的面不相邻\"的原则,找出与数字\"4\"不相邻的数字.\n【详解】在给出的\"1-4-1\"型展开图中,中间一行从左到右依次是1,2,3,4。数字\"4\"与1,3,5,6相邻,与\"2\"中间隔着\"3\",因此\"4\"的对面是\"2\"。故答案为:2。", + "knowledge_points": [ + "正方体的展开图" + ], + "source": "19-20 一年级下·四川乐山·期末" + }, + { + "id": "361", + "unit": "认识图形", + "question_type": "填空题", + "difficulty": 0.65, + "question": "![](images/85121db284a99ef4619cf0c63fa878206d3b3244720ecd930d8dfca7e2d5e228.jpg)(图1)有( )个长方形,![](images/0f94e4eb052e4975d31345743e6fb65a66ad4adb17c1b0e2c9784e5eeb33d9d8.jpg)(图2)中有( )个三角形。", + "options": [], + "answer": "3;5", + "solution": "【分析】长方形是长长方方的,有4条直直的边,对边相等;三角形有3条直直的边。长方形的总个数=2个小的长方形+整个大的长方形;三角形的总个数=4个小的三角形+1个大的三角形.\n【详解】2+1=3(个),4+1=5(个),图1中有3个长方形;图2中有5个三角形。", + "knowledge_points": [ + "数一数", + "长方形", + "正方形", + "三角形和圆的初步认识" + ], + "source": "21-22 一年级下·贵州毕节·期中" + }, + { + "id": "362", + "unit": "认识图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "用 20 根小棒摆正方形,可以摆( )个;如果摆成三角形,可以摆( )个,还剩( )根。", + "options": [], + "answer": "5;6;2", + "solution": "【分析】这是一个关于除法或连续减法的应用题。摆一个正方形需要4根小棒,摆一个三角形需要3根小棒。求20根小棒分别能摆多少个正方形或三角形,就是求20里面最多有几个4或几个3.\n【详解】摆正方形(每个需要4根小棒):20÷4=5,能摆5个正方形。摆三角形(每个需要3根小棒):20÷3=6……2,能摆6个,剩2根。故答案为:5;6;2。", + "knowledge_points": [ + "长方形", + "正方形", + "三角形和圆的初步认识" + ], + "source": "20-21 二年级下·云南大理·期末" + }, + { + "id": "363", + "unit": "认识图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "![](images/6e1728679cd2cbe2872f3cc3320df57a7b30aee143bed5487bb10ae49b0905f4.jpg)一套七巧板一共有( )块,其中( )号是正方形, ( )号是平行四边形。( )号一样大。", + "options": [], + "answer": "7;4;6;1;2", + "solution": "【分析】本题考查对七巧板组成的熟悉程度。七巧板由7块几何板组成,包括三角形,正方形和平行四边形。需要根据图中编号,识别出正方形,平行四边形,并找出大小相同的两块板.\n【详解】一套七巧板共有7块:其中4号是正方形;6号是平行四边形;1号和2号是两个一样大的小三角形。故答案为:7;4;6;1;2。", + "knowledge_points": [ + "长方形", + "正方形", + "三角形和圆的初步认识", + "用七巧板拼图形", + "平行四边形的初步认识" + ], + "source": "20-21 一年级下·新疆吐鲁番·期中" + }, + { + "id": "364", + "unit": "认识图形", + "question_type": "填空题", + "difficulty": 0.4, + "question": "用![](images/2025-12-15%20211144.jpg)做一个正方体,\"3\"的对面是( ),\"( )\"的对面是\"5\"。", + "options": [], + "answer": "2;4", + "solution": "【分析】根据正方体展开图的11种特征,此图属于正方体展开图的 \"1-4-1\"型,做成一个正方体后,数字 \"1\"与\"6\"相对,\"2\"与\"3\"相对,\"4\"与\"5\"相对.\n【详解】用该图做一个正方体,\"3\"的对面是 \"2\",\"4\"的对面是\"5\"。", + "knowledge_points": [ + "正方体的展开图" + ], + "source": "20-21一年级下·贵州铜仁·期中" + }, + { + "id": "365", + "unit": "认识图形", + "question_type": "填空题", + "difficulty": 0.65, + "question": "把![](images/e9154b2adeb7e1acbfa52c75bae5d4138745bfc3c201842ba641aff8e57a5b71.jpg)折成一个正方体,( )的对面是\"4\"。", + "options": [], + "answer": "2", + "solution": "【分析】本题考查正方体展开图中相对面的判断。该展开图属于\"1-4-1\"型,中间一行有四个数字。根据\"相对的面不相邻\"的原则,找出与数字\"4\"不相邻的数字.\n【详解】这是正方体的\"1-4-1\"型展开图(中间一行4个面,上下各1个面)。在这种展开图中,中间一行相对的面不相邻:中间行的\"1\"\"2\"\"3\"\"4\"里,\"1\"和\"3\"相对,\"2\"和\"4\"相对;上下的\"5\"和\"6\"相对。因此\"2\"的对面是\"4\"。", + "knowledge_points": [ + "立体图形的认识", + "图形的折叠问题" + ], + "source": "21-22 一年级下·湖北孝感·期中" + }, + { + "id": "366", + "unit": "认识图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "三角形有( )条边,正方形有( )条边。", + "options": [], + "answer": "3;4", + "solution": "【分析】根据三角形和正方形的概念可知,由三条线段首尾顺次相连得到的封闭几何图形叫作三角形,有四条边且四条边长度都相等的特殊长方形叫做正方形。据此解答即可.\n【详解】由分析可知,三角形有3条边,正方形有4条边。", + "knowledge_points": [ + "长方形", + "正方形", + "三角形和圆的初步认识" + ], + "source": "19-20 一年级下·广东深圳·期中" + }, + { + "id": "367", + "unit": "认识图形", + "question_type": "填空题", + "difficulty": 0.65, + "question": "将![](images/0ed77a74b6dc2985370a03884bc3de20a701a135b0ebf96cbabba336e2048029.jpg)折成一个正方体,\"2\"对面的数是( )。", + "options": [], + "answer": "4", + "solution": "【分析】本题考查正方体展开图中相对面的判断。该展开图属于\"1-4-1\"型,中间一行有四个数字。根据\"相对的面不相邻\"的原则,找出与数字\"2\"不相邻的数字.\n【详解】这是正方体的 \"1-4-1\" 型展开图(中间一行 4 个面,上下各 1 个面)。在这种展开图中,中间一行的面是依次相邻的,相对的面不相邻:中间行的 \"1,2,3,4\" 里,\"1\" 和 \"3\" 相对,\"2\" 和 \"4\" 相对;上下的 \"5\" 和 \"6\" 相对。因此 \"2\" 对面的数是 4。", + "knowledge_points": [ + "图形的折叠问题", + "长方形", + "正方形", + "三角形和圆的初步认识" + ], + "source": "20-21 一年级下·湖北荆门·期中" + }, + { + "id": "368", + "unit": "认识图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "用下图做成一个正方体,\"小\"的对面是( );\"数\"的对面是( ).\n\n![](images/2025-12-15%20211711.jpg)", + "options": [], + "answer": "家;是", + "solution": "【分析】本题考查正方体展开图中相对面的判断。该展开图属于\"1-4-1\"型,需要根据图中汉字的位置关系,找出相对的两个面.\n【详解】这是正方体的\"1-4-1\"型展开图(中间一行4个面,上下各1个面)。在这种展开图中,相对的面不相邻:中间行的\"是,小,数\"与上下的\"我,学,家\"中,\"小\"在中间行的中间位置,其上下对应的面是\"我\"和\"家\",因此\"小\"的对面是\"家\";中间行的\"是\"和\"数\"是相对的面,因此\"数\"的对面是\"是\"。故答案为:家;是。", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "21-22 一年级下·山东菏泽·期中" + }, + { + "id": "369", + "unit": "认识图形", + "question_type": "填空题", + "difficulty": 0.65, + "question": "用( )个等腰直角三角形可以拼成一个![](images/2025-12-15%20211939.jpg)", + "options": [], + "answer": "6", + "solution": "【分析】观察目标图形,它是由三个小正方形组成的长方形。每个小正方形可以由两个等腰直角三角形拼成。因此,所需三角形的总数量等于小正方形的数量乘以2.\n【详解】目标图形是由3个小正方形拼成的长方形。每个小正方形需要2个等腰直角三角形来拼成。因此,总共需要3×2=6(个)等腰直角三角形。故答案为:6。", + "knowledge_points": [ + "平面图形的拼接", + "长方形", + "正方形", + "三角形和圆的初步认识" + ], + "source": "20-21一年级下·黑龙江齐齐哈尔·期末" + }, + { + "id": "370", + "unit": "认识图形", + "question_type": "填空题", + "difficulty": 0.65, + "question": "数一数,填一填.\n\n![](images/b8f800a31335327af5c82d694899ebbb05b633646f23ce2666caf493851c6371.jpg)\n\n正方形( )个,长方形( )个,三角形( )个,圆形( )个,三角形比正方形多( )个。", + "options": [], + "answer": "1;3;3;2;2", + "solution": "【分析】根据正方形,长方形,三角形,圆形的特征,仔细辨认图中的每个图形,分别数出它们的个数。然后计算三角形比正方形多几个.\n【详解】数图中图形:正方形:1个;长方形:3个;三角形:3个;圆:2个;三角形比正方形多的数量:3-1=2(个)。故答案为:1;3;3;2;2。", + "knowledge_points": [ + "5 以内数的减法", + "数一数", + "长方形", + "正方形", + "三角形和圆的初步认识" + ], + "source": "20-21 一年级下·吉林四平·期中" + }, + { + "id": "371", + "unit": "认识图形", + "question_type": "填空题", + "difficulty": 0.65, + "question": "用两个完全一样![](images/83367b6896ad96a57cd18300c2b9f1de4862e37aec2898db1d89275255aa2534.jpg)可以拼出一个( )形。", + "options": [], + "answer": "三角形或长方", + "solution": "【分析】![](images/2b6b30369563a79de3d9e7358abdbc13a7dd237483edc02ec4b56473f4b772b5.jpg)用两个完全一样的该图拼一拼,就能拼出正确结果.\n【详解】用两个完全一样该图可以拼出一个三角形或长方形。动手拼一拼,拼出正确答案,提高动手能力。", + "knowledge_points": [ + "平面图形的拼接", + "长方形", + "正方形", + "三角形和圆的初步认识" + ], + "source": "20-21 一年级下·山西晋中·期末" + }, + { + "id": "372", + "unit": "认识图形", + "question_type": "填空题", + "difficulty": 0.65, + "question": "我们可以从正方体上画出( )形,从圆柱体上画出( )形。", + "options": [], + "answer": "正方;圆", + "solution": "【分析】正方体每个面都是正方形,所以可以从正方体上画出正方形;圆柱体有两个面是圆形,所以可以从圆柱体上画出圆形.\n【详解】我们可以从正方体上画出正方形,从圆柱体上画出圆形。本题主要考查立体图形的认识,运用立体图形的特征解决问题。", + "knowledge_points": [ + "立体图形的认识", + "长方形", + "正方形", + "三角形和圆的初步认识" + ], + "source": "20-21 一年级下·山西晋中·期末" + }, + { + "id": "373", + "unit": "认识图形", + "question_type": "填空题", + "difficulty": 0.65, + "question": "如下图,七巧板是我国古代的一种拼板玩具,一套七巧板由( )块板组成,可以拼出多种不同的图案.\n\n![](images/5e564d271f1dae027daaf6a5553ae26a95d84d018144f45a57b8b61c3ea19f35.jpg)", + "options": [], + "answer": "7", + "solution": "【分析】一套七巧板里面有7块板.\n【详解】一套七巧板由 7 块板组成,可以拼出各种不同的图案。这道题解题的关键是要对七巧板有所了解。", + "knowledge_points": [ + "平面图形的拼接", + "长方形", + "正方形", + "三角形和圆的初步认识", + "用七巧板拼图形" + ], + "source": "19-20 一年级下·四川遂宁·期中" + }, + { + "id": "374", + "unit": "认识图形", + "question_type": "填空题", + "difficulty": 0.65, + "question": "![](images/65656926ae20f9434d6691470012d470912ff3fcafd6045f3162b9749ad086f9.jpg)是由( )个△拼成的。至少( )个□才能拼成一个大正方形。", + "options": [], + "answer": "6;4", + "solution": "【分析】第一问:观察左边图形,它是一个六边形,由若干个相同的小三角形拼成。数一数小三角形的数量。第二问:用小正方形拼成大正方形,大正方形的边长需要是整数个小正方形。最小的可能情况是边长为2个小正方形的大正方形.\n【详解】观察图形:第一个空:图中的六边形是由6个相同的三角形拼成的,所以填6;第二个空:用小正方形拼大正方形时,至少需要2+2=4个小正方形(排成2行2列),所以填4。故答案为:6;4。", + "knowledge_points": [ + "平面图形的拼接", + "长方形", + "正方形", + "三角形和圆的初步认识" + ], + "source": "20-21 一年级下·湖南张家界·期末" + }, + { + "id": "375", + "unit": "认识图形", + "question_type": "填空题", + "difficulty": 0.65, + "question": "用![](images/0899cf04c01d4a941008bc4aa5a13ffc348f568b58fd39d1eb1ec44f3d855084.jpg)做一个正方体,\"1\"的对面是( ),\"4\"的对面是( )。", + "options": [], + "answer": "3;6", + "solution": "【分析】本题考查正方体展开图中相对面的判断。该展开图属于\"1-4-1\"型,但具体排列稍有不同。需要根据\"相对的面不相邻\"的原则,分析每个数字的相邻关系,找出其对面.\n【详解】这是正方体的\"1-4-1\"型展开图(左侧1列3个面,右侧1行4个面)。在这种展开图中,相对的面不相邻:左侧列的\"1\"和\"3\"是上下相对的面,因此\"1\"的对面是\"3\";右侧行的\"4\"和\"6\"是左右相对的面,因此\"4\"的对面是\"6\"。故答案为:3;6。", + "knowledge_points": [ + "正方体的展开图" + ], + "source": "20-21 一年级下·湖南张家界·期末" + }, + { + "id": "376", + "unit": "认识图形", + "question_type": "填空题", + "difficulty": 0.65, + "question": "用 2 个同样大的正方形能拼出一个( )形;至少用( )个同样大的正方形可以拼出一个大正方形。", + "options": [], + "answer": "长方;4", + "solution": "【分析】两个小正方形拼接时,考虑它们的排列方式。用小正方形拼大正方形时,考虑大正方形的边长需要是整数个小正方形.\n【详解】 用 2 个同样大的正方形拼接:将它们并排摆放,会形成一个长是宽的两倍的长方形,所以第一个空填 \"长方\";拼大正方形:需要小正方形排成 2 行 2 列,共2 + 2=4个,所以第二个空填 \"4\"。故答案为:长方;4。", + "knowledge_points": [ + "平面图形的拼接", + "长方形", + "正方形", + "三角形和圆的初步认识" + ], + "source": "19-20 一年级下·福建龙岩·期末" + }, + { + "id": "377", + "unit": "认识图形", + "question_type": "填空题", + "difficulty": 0.65, + "question": "数一数。如图中长方形有( )个,正方形有( )个,平行四边形有( )个.\n\n![](images/513c6eaa3610619d44be185a3159e2bcbd50a122a92b90266f58ffed78d31507.jpg)", + "options": [], + "answer": "3;3;3", + "solution": "【分析】根据长方形,正方形和平行四边形的定义,仔细辨认图中的每一个图形。注意组合图形可能形成新的长方形,正方形或平行四边形.\n【详解】观察图形(由3组\"三角形+小正方形\"拼接而成):长方形:每2个相邻的小图形可组成1个长方形,共3个;正方形:图中独立的小正方形有3个;平行四边形:每2个三角形可组成1个平行四边形,共3个。故答案为:3;3;3。", + "knowledge_points": [ + "长方形", + "正方形", + "三角形和圆的初步认识", + "平行四边形的初步认识" + ], + "source": "20-21 二年级下·河南周口·期末" + }, + { + "id": "378", + "unit": "认识图形", + "question_type": "填空题", + "difficulty": 0.65, + "question": "![](images/1b5ce1b94e01f245f74db3dd7d1b963d685fc03c81a33ffa7b5f86bbe7103eec.jpg)\n\n用了( )个□,至少再添( )个这样的□,可拼成一个大正方形。", + "options": [], + "answer": "5;4", + "solution": "【分析】该图可以数出一共用了5个□ ,而且每行,每列都是3个□ ,那么拼成一个大正方形就至少需要( 3 + 3 + 3 )个□ ,再减去已经有的5个□ ,就是需要添加□ 的个数.\n【详解】该图可以数出一共用了 5 个□ ,3 + 3 + 3 = 9 (个);9 - 5 = 4 (个),即:至少再添 4 个这样的 □ , 可拼成一个大正方形。解决本题关键是正确地找出拼成大正方形需要小正方形的个数,从而解决问题。", + "knowledge_points": [ + "平面图形的拼接", + "8,9 的加减法", + "长方形", + "正方形", + "三角形和圆的初步认识", + "连加,连减(10 以内)" + ], + "source": "20-21 一年级下·河南许昌·期中" + }, + { + "id": "379", + "unit": "认识图形", + "question_type": "填空题", + "difficulty": 0.65, + "question": "这是一个( )形,它是由( )个三角形,( )个长方形,( )个正方形拼成的.\n\n![](images/3366ffc4d21aa18134f621304608380e44a1a60ad1581937af0a7a34ccb9ea3b.jpg)", + "options": [], + "answer": "平行四边;2;2;1", + "solution": "【分析】根据图示,结合平行四边形,三角形,长方形和正方形的特征做题.\n【详解】这是一个平行四边形,它是由2个三角形,2个长方形 , 1个正方形拼成的。此题主要考查计数方法的应用,养成按照一定顺序观察思考问题的习惯,逐步学会通过观察思考探寻事物规律的能力。", + "knowledge_points": [ + "数一数", + "长方形", + "正方形", + "三角形和圆的初步认识", + "平行四边形的初步认识" + ], + "source": "20-21 一年级下·河南焦作·期中" + }, + { + "id": "380", + "unit": "认识图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "正方形有( )条边。长方形有( )条边,对边( )。", + "options": [], + "answer": "4;4;平行且相等", + "solution": "【分析】正方形的四条边都相等,四个角都是直角,长方形的四个角都是直角,对边平行且相等,据此解答即可.\n【详解】正方形有 4 条边。长方形有 4 条边,对边平行且相等。熟练掌握长方形和正方形的特征,是解答此题的关键。", + "knowledge_points": [ + "长方形", + "正方形,三角形和圆的初步认识" + ], + "source": "20-21 一年级下·河南开封·期末" + }, + { + "id": "381", + "unit": "认识图形", + "question_type": "填空题", + "difficulty": 0.65, + "question": "如图中圆形有( )个,正方形有( )个,三角形有( )个,长方形有( )个.\n\n![](images/5fff3f83ed85e65b9c79fae9f7322740de05e08380cd7815ee3333c070b63002.jpg)", + "options": [], + "answer": "2;2;3;0", + "solution": "【分析】根据圆形,正方形,三角形,长方形的特征,仔细辨认图中的每一个图形,分别数出它们的个数。注意长方形是两组对边分别相等且四个角都是直角的四边形.\n【详解】数图中各类图形:圆:顶部 2 个,共 2 个;正方形:底部 2 个菱形(正方形变形),共 2 个;三角形:顶部 1 个小三角形 + 中间 1 个大三角形 + 底部 1 个大三角形,共 3 个;长方形:图中无长方形,共 0 个。故答案为: 2;2;3;0", + "knowledge_points": [ + "长方形", + "正方形", + "三角形和圆的初步认识" + ], + "source": "20-21 一年级下·河北张家口·期末" + }, + { + "id": "382", + "unit": "认识图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "如下图,七巧板是我国古代的一种拼板玩具,一套七巧板由( )种图形组成,其中有( )个三角形块,( )块正方形,( )块平行四边形\n\n![](images/5e564d271f1dae027daaf6a5553ae26a95d84d018144f45a57b8b61c3ea19f35.jpg)", + "options": [], + "answer": "3;5;1;1", + "solution": "【分析】本题考查对七巧板组成的熟悉程度。七巧板由7块几何板组成,包含三角形,正方形和平行四边形三种基本图形。需要根据图中编号,数出每种图形的数量.\n【详解】一套七巧板由3 种图形组成(三角形,正方形,平行四边形): 三角形有 5 块(图中 1,2,3,6,7);正方形有 1 块(图中 4);平行四边形有 1 块(图中 5)。故答案为:3;5;1;1", + "knowledge_points": [ + "长方形", + "正方形", + "三角形和圆的初步认识", + "用七巧板拼图形", + "平行四边形的初步认识" + ], + "source": "19-20 一年级下·山西忻州·期末" + }, + { + "id": "383", + "unit": "认识图形", + "question_type": "填空题", + "difficulty": 0.65, + "question": "下图中,沿着虚线剪开得到( )个长方形.\n\n![](images/d3cbb3f5ff2166a6241c523f14fcb0e9d2686acb23a4978271fc861e79f8b1e5.jpg)", + "options": [], + "answer": "2", + "solution": "【分析】原图是一个长方形。沿虚线(一条水平线)剪开,会将原长方形分成两部分。判断这两部分的形状.\n【详解】原图是一个大长方形。虚线是横穿长方形的一条直线(位于中间位置)。沿这条虚线剪开后,原长方形被分成上下两个小长方形。因此,会得到2个长方形。故答案为:2。", + "knowledge_points": [ + "长方形", + "正方形", + "三角形和圆的初步认识" + ], + "source": "20-21 一年级下·广西玉林·期中" + }, + { + "id": "384", + "unit": "认识图形", + "question_type": "填空题", + "difficulty": 0.65, + "question": "下图是用( )个三角形和( )个正方形拼成的.\n\n![](images/50d6624709aabdaa18989f333704d98fe865b21838b02020d9e46850a78ac677.jpg)", + "options": [], + "answer": "2;1", + "solution": "【分析】观察组合图形,辨认出组成它的基本图形:三角形和正方形。分别数出它们的数量.\n【详解】该组合图形由三部分组成:左侧是一个三角形,右侧是一个三角形,中间是一个正方形。因此,它用了2个三角形和1个正方形拼成。故答案为:2;1。", + "knowledge_points": [ + "平面图形的拼接", + "长方形", + "正方形", + "三角形和圆的初步认识" + ], + "source": "20-21 一年级下·广西玉林·期中" + }, + { + "id": "385", + "unit": "认识图形", + "question_type": "填空题", + "difficulty": 0.65, + "question": "想一想,用![](images/65dd79fa1047f89c3238626344a302eb013bc35e7cab692f93820c9368ed80d3.jpg)做一个正方体,\"1\"的对面是( )。", + "options": [], + "answer": "6", + "solution": "【分析】本题考查正方体展开图中相对面的判断。该展开图属于\"1-4-1\"型,需要找出与数字\"1\"不相邻的数字.\n【详解】这是正方体的 \"1-4-1\" 型展开图(中间一行 4 个面,上下各 1 个面)。在这种展开图中,上下相对的面不相邻:\"1\" 在顶部面,其正下方对应的面是 \"6\",因此 \"1\" 的对面是 \"6\"。故答案为: 6", + "knowledge_points": [ + "正方体的展开图" + ], + "source": "19-20 一年级下·重庆永川·期末" + }, + { + "id": "386", + "unit": "认识图形", + "question_type": "填空题", + "difficulty": 0.65, + "question": "用下图这套七巧板中的 4 号正方形,( )号三角形和( )号三角形可以拼成一个新的三角形.\n\n![](images/f952c35826b0bb6bb0cd6a39a1badbc9841312021250c9e3c39b9ee79f31cb00.jpg)", + "options": [], + "answer": "3;5", + "solution": "【分析】题目要求用指定的正方形和两个三角形拼成一个新的三角形。需要观察七巧板中各个图形的形状和大小,尝试组合.\n【详解】观察七巧板:4号是正方形,3号和5号是两个大小相同的小三角形。将4号正方形放在中间,3号和5号三角形分别拼在正方形的两侧,可组成一个新的三角形。故答案为:3;5。", + "knowledge_points": [ + "平面图形的拼接", + "长方形", + "正方形", + "三角形和圆的初步认识", + "用七巧板拼图形" + ], + "source": "20-21 一年级下·重庆永川·期末" + }, + { + "id": "387", + "unit": "认识图形", + "question_type": "填空题", + "difficulty": 0.65, + "question": "用![](images/2025-12-15%20215104.jpg)做成一个正方体,数字\"4\"的对面是数字( ),数字\"5\"的对面是数字( )。", + "options": [], + "answer": "3;6", + "solution": "【分析】本题考查正方体展开图中相对面的判断。该展开图属于\"1-4-1\"型,需要根据\"相对的面不相邻\"的原则,找出每个数字的对面.\n【详解】这是正方体的 \"1-4-1\" 型展开图(中间一行 4 个面,上下各 1 个面):中间行的 \"1,4,2,3\" 中,\"4\" 和 \"3\" 是相对的面;上下的 \"6\" 和 \"5\" 是相对的面。因此数字 \"4\" 的对面是 3,数字 \"5\" 的对面是 6。", + "knowledge_points": [ + "正方体的展开图" + ], + "source": "21-22一年级下·全国·周测" + }, + { + "id": "388", + "unit": "认识图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "![](images/ccf8c19b1cf679b35c4af8fc7598399eadc884a68cec69bb62332f41d0ac0ee6.jpg)是由2个( )形拼成的( )形。", + "options": [], + "answer": "正方;长方", + "solution": "【分析】观察图形,它是由两个完全相同的四边形拼接而成。判断每个小四边形的形状,以及拼接后的大图形的形状.\n【详解】这个图形由两个完全一样的小正方形并排拼接而成。拼接后,形成了一个长是宽的两倍的长方形。因此,它是由2个正方形拼成的长方形。故答案为:正方;长方。", + "knowledge_points": [ + "平面图形的拼接", + "长方形", + "正方形", + "三角形和圆的初步认识" + ], + "source": "17-18 一年级下·全国·课后作业" + }, + { + "id": "389", + "unit": "认识图形", + "question_type": "判断题", + "difficulty": 0.65, + "question": "两个这样的 △ 可以拼成一个长方形。( )", + "options": [], + "answer": "×", + "solution": "【分析】判断两个三角形能否拼成长方形,关键在于三角形的类型和拼接方式。长方形有四个直角,因此能拼成长方形的两个三角形必须是完全相同的直角三角形,且拼接时需要将它们的直角边重合.\n【详解】只有直角三角形(且是两个完全相同的直角三角形)才能拼成长方形;如果是普通三角形(比如锐角三角形,钝角三角形),两个无法拼成长方形。题目中没说明是直角三角形,所以该表述不成立,故答案为: ×", + "knowledge_points": [ + "平面图形的拼接" + ], + "source": "20-21 一年级下·新疆省直辖县级单位·期末" + }, + { + "id": "390", + "unit": "认识图形", + "question_type": "判断题", + "difficulty": 0.65, + "question": "把一张正方形纸对折后剪开,有可能得到两个同样的三角形。( )", + "options": [], + "answer": "√", + "solution": "【分析】把一张正方形的纸折成两个完全一样的三角形,只能沿着对角线,根据正方形的四个角都是直角,四条边都相等可以解决问题.\n【详解】如图:![](images/5cf178ea7d794933da66934608c4099f03a344b0451c44c7f8c117904a5049cf.jpg)把一张正方形纸对折后剪开,有可能得到两个同样的三角形,原题说法正确。故答案为: √。此题主要利用正方形的特征:正方形的四个角都是直角,四条边都相等来解决问题。", + "knowledge_points": [ + "平面图形的分割", + "长方形", + "正方形", + "三角形和圆的初步认识" + ], + "source": "20-21 一年级下·云南楚雄·期末" + }, + { + "id": "391", + "unit": "认识图形", + "question_type": "判断题", + "difficulty": 0.85, + "question": "用2个这样的等腰直角三角形可以拼成一个□。( )", + "options": [], + "answer": "√", + "solution": "【分析】用两个完全一样的等腰直角三角形可以拼成一个正方形。据此判断.\n【详解】用 2 个这样的等腰直角三角形可以拼成一个 □ 。原题说法正确。故答案为:√", + "knowledge_points": [ + "平面图形的拼接", + "长方形", + "正方形", + "三角形和圆的初步认识" + ], + "source": "20-21一年级下·湖北孝感·期末" + }, + { + "id": "392", + "unit": "认识图形", + "question_type": "判断题", + "difficulty": 0.65, + "question": "用两个![](images/2025-12-15%20220050.jpg)可以拼成一个![](images/2025-12-15%20220105.jpg),也可以拼成一个![](images/2025-12-15%20220139.jpg)。( )", + "options": [], + "answer": "√", + "solution": "【分析】判断两个完全相同的直角三角形能否拼成长方形或大三角形,需要根据直角三角形的特性,考虑不同的拼接方式.\n【详解】题目中的三角形是完全相同的直角三角形:将两个直角三角形的直角边拼接,可组成长方形;将两个直角三角形的斜边拼接,可组成大三角形。故答案为:√", + "knowledge_points": [ + "平面图形的拼接", + "长方形", + "正方形", + "三角形和圆的初步认识" + ], + "source": "20-21一年级下·河南驻马店·期中" + }, + { + "id": "393", + "unit": "认识图形", + "question_type": "判断题", + "difficulty": 0.94, + "question": "七巧板是由 5 个三角形,一个正方形和一个平行四边形组成的。( )", + "options": [], + "answer": "√", + "solution": "【分析】根据七巧板的形状进行判断即可.\n【详解】观察发现七巧板有 7 块,有 5 个三角形,1 个正方形和 1 个平行四边形。故答案为: √。本题主要考查图形的组成,认识七巧板是解答此题关键。", + "knowledge_points": [ + "长方形", + "正方形", + "三角形和圆的初步认识", + "用七巧板拼图形", + "平行四边形的初步认识" + ], + "source": "18-19 一年级下·全国·单元测试" + }, + { + "id": "394", + "unit": "认识图形", + "question_type": "判断题", + "difficulty": 0.4, + "question": "![](images/7f3dd78eb5e631b6956cbe930e1d626808c6a3bb31cbc9f3273318d96cfb7631.jpg)做成一个正方体,数字\"4\"的对面数字是\"2\"。( )", + "options": [], + "answer": "√", + "solution": "【分析】将正方体展开图动手折一折,做成一个正方体,找出数字\"4\"相对的面,据此解答.\n【详解】折成正方体后发现:数字\"1\"与数字\"3\"相对,数字\"2\"与数字\"4\"相对,数字\"5\"与数字\"6\"相对。故答案为:√。本题主要考查学生的动手能力,可以动手实践操作下。", + "knowledge_points": [ + "正方体的展开图" + ], + "source": "20-21一年级下·河南安阳·期末" + }, + { + "id": "395", + "unit": "认识图形", + "question_type": "判断题", + "difficulty": 0.65, + "question": "用一张长 8 厘米,宽2厘米的长方形纸剪成的正方形边长最大是2厘米。( )", + "options": [], + "answer": "√", + "solution": "【分析】要从长方形中剪出最大的正方形,正方形的边长受限于长方形的较短边。因为正方形的四条边相等,其边长不能超过长方形的宽.\n【详解】正方形的边长需要同时满足长方形的长和宽的限制,长方形的宽是 2 厘米,因此剪成的正方形边长最大只能等于长方形的宽(2 厘米),无法超过这个长度。故答案为:√", + "knowledge_points": [ + "平面图形的分割", + "长方形", + "正方形", + "三角形和圆的初步认识" + ], + "source": "20-21 二年级下·广西贺州·期末" + }, + { + "id": "396", + "unit": "认识图形", + "question_type": "判断题", + "difficulty": 0.65, + "question": "左图中有3个长方形。( )", + "options": [], + "answer": "√", + "solution": "【分析】长方形是有一个角是直角的平行四边形,据此性质在图中找出长方形个数即可.\n【详解】由分析得:图中有两个小的长方形,两个小长方形组成了一个大的长方形;所以图中有三个长方形。故答案为: √", + "knowledge_points": [ + "长方形", + "正方形", + "三角形和圆的初步认识" + ], + "source": "17-18一年级下·吉林·期中" + }, + { + "id": "397", + "unit": "认识图形", + "question_type": "判断题", + "difficulty": 0.65, + "question": "![](images/8be1fa37686ff6232cf63fa467c52959039c2cc94bb04bea58d633575d37930d.jpg)正方形,沿虚线剪开可得到4个小正方形。( )", + "options": [], + "answer": "√", + "solution": "【分析】观察图形,虚线将正方形横竖各分成了两等份。判断沿虚线剪开后,得到的四个小图形是否都是正方形.\n【详解】图中的正方形被虚线(横竖各一条中线)分成了 4 个大小相等的小正方形,沿虚线剪开后正好得到 4 个小正方形。故答案为:√", + "knowledge_points": [ + "长方形", + "正方形", + "三角形和圆的初步认识" + ], + "source": "20-21一年级下·广西玉林·期末" + }, + { + "id": "398", + "unit": "认识图形", + "question_type": "判断题", + "difficulty": 0.65, + "question": "用![](images/50d848752b4740dfc6c63fccbf93a64868e6907496afdf261ff698a8afd077b5.jpg)做成一个正方体,数字\"4\"的对面是数字\"1\"。( )", + "options": [], + "answer": "×", + "solution": "【分析】本题考查正方体展开图中相对面的判断。该展开图属于\"1-4-1\"型,需要根据\"相对的面不相邻\"的原则,找出数字\"4\"的对面.\n【详解】这是正方体的 \"1-4-1\" 型展开图,中间一行的 \"1,2,3,4\" 中,\"4\" 的对面是 \"1\" 的相邻面(实际 \"4\" 的对面是 \"2\"),因此 \"4\" 的对面不是 \"1\"。故答案为: ×", + "knowledge_points": [ + "正方体的展开图" + ], + "source": "20-21 一年级下·湖北十堰·期末" + }, + { + "id": "399", + "unit": "认识图形", + "question_type": "判断题", + "difficulty": 0.65, + "question": "一个正方形可以分成2个相同的三角形。( )", + "options": [], + "answer": "√", + "solution": "【分析】判断一个正方形能否分成两个相同的三角形,需要考虑分割线的位置。常见的分割方式有沿对角线剪开.\n【详解】将正方形沿对角线剪开,就能得到 2 个完全相同的等腰直角三角形。故答案为:√", + "knowledge_points": [ + "平面图形的分割" + ], + "source": "20-21 一年级下·辽宁盘锦·期末" + }, + { + "id": "400", + "unit": "认识图形", + "question_type": "解答题", + "difficulty": 0.65, + "question": "拼一个![](images/b0d02014878ab3a7373e912393178878b3a7021123988954271d72fe7d2cf4f5.jpg)需要( )个![](images/2025-12-15%20220941.jpg)。", + "options": [ + "A. 3", + "B. 6", + "C. 7" + ], + "answer": "B", + "solution": "【分析】一个小长方形需要2个小三角形拼成,那么3个小长方形拼成的大长方形需要2+2+2=6(个)小三角形.\n【详解】2+2+2=6(个),拼一个该图需要6个这样的三角形。故答案为:B。", + "knowledge_points": [ + "平面图形的拼接", + "长方形", + "正方形", + "三角形和圆的初步认识" + ], + "source": "20-21一年级下·福建三明·期末" + }, + { + "id": "401", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "一张正方形的纸上剪下一个角,剩下的图形不可能是 ( )。", + "options": [ + "A. 三角形", + "B. 四边形", + "C. 六边形" + ], + "answer": "C", + "solution": "【分析】根据正方形的特征,画一画试一试即可得到答案。如图:\n\n![](images/7ae413984bab4ac6f8db0a9a276ba8f3605f698c947da0cf533b2e5bebdf00fc.jpg)\n\n【详解】一张正方形的纸上剪下一个角,剩下的图形可能是三角形,四边形,五边形,不可能是六边形。故答案为: C", + "knowledge_points": [ + "长方形,正方形,三角形和圆的初步认识", + "四边形,五边形及多边形的初步认识", + "平面图形的分割" + ], + "source": "19-20 二年级上·安徽黄山·期中" + }, + { + "id": "402", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.65, + "question": "三角形剪掉一个角后不能变成 ( )。", + "options": [ + "A. 三角形", + "B. 四边形", + "C. 五边形" + ], + "answer": "C", + "solution": "【分析】剪掉三角形的一个角时,若剪线经过两个顶点,会得到新的三角形;若剪线经过两条边,会得到四边形;三角形本身只有3个角,剪掉一个角后最多增加1个角,形成4个角的图形,无法得到5个角的五边形.\n【详解】三角形剪掉一个角后不能变成五边形。故答案为:C", + "knowledge_points": [ + "三角形的概念及表示方法", + "四边形,五边形及多边形的初步认识", + "平面图形的分割" + ], + "source": "19-20 二年级上·湖南邵阳·期中" + }, + { + "id": "403", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "将下图折成一个正方体,与 ○ 相对的是 ( )。\n\n![](images/9844ed8a8bd630163efe10b7c5031de3a1aa12636624039e77b4f819c6fd40e0.jpg)", + "options": [ + "A. ☆", + "B. △", + "C. □" + ], + "answer": "A", + "solution": "【分析】这是正方体的\"1-4-1\"型展开图,相对的面不相邻.\n【详解】这是正方体的\"1-4-1\"型展开图(中间一行4个面,上下各1个面)。在中间一行中,相对的面不相邻,因此\"○\"的对面是\"☆\"。故答案为:A", + "knowledge_points": [ + "正方体的展开图" + ], + "source": "20-21一年级下·陕西延安·期末" + }, + { + "id": "404", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "下图中是平行四边形的是 ( )。", + "options": [ + "A. ![](images/dd3c868cf2015d0d84d2b628bac62dc7e6ed53f3514f230928a7a1a8bd96a456.jpg)", + "B. ![](images/ccaeefdcbc25d073313970292f7c4f19d704274d3605914774630d0502e4b8ab.jpg)", + "C. ![](images/9d8b82798319426b6365453b5d983cf8fd82a67e55762ec9c83b42e1dd010f04.jpg)" + ], + "answer": "B", + "solution": "【详解】A。圆形;B。平行四边形;C。三角形。故答案为:B", + "knowledge_points": [ + "平行四边形的初步认识" + ], + "source": "20-21 一年级下·陕西延安·期末" + }, + { + "id": "405", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.65, + "question": "用两个![](images/2025-12-16%20163535.jpg)可以拼成一个( )。", + "options": [ + "A. 长方形", + "B. 正方体", + "C. 三角形", + "D. 圆" + ], + "answer": "A", + "solution": "【分析】题目中的图形是小长方形,两个完全相同的小长方形拼接:A。若将长边拼接,可组成一个更大的长方形;B。正方体是立体图形,而题目是平面图形拼接,不符合;C。三角形由三条边组成,长方形无法拼出三角形,不符合;D。圆是曲线图形,长方形是直线图形,无法拼成圆,不符合。因此两个小长方形可以拼成一个长方形。故答案为:A", + "knowledge_points": [ + "平面图形的拼接" + ], + "source": "20-21 一年级下·贵州遵义·期末" + }, + { + "id": "406", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.65, + "question": "用![](images/ef5e0fb1b15f600ef939f0e2d9815e256a4471795f9b6ecc7f7e9df80b21f55c.jpg)做一个正方体,\"1\"的对面是( )。", + "options": [ + "A. 3", + "B. 4", + "C. 5" + ], + "answer": "A", + "solution": "【详解】这是正方体的 \"1-4-1\" 型展开图(结构为 \"上下各 1 个面,中间一行 4 个面\")。在这种展开图中,中间一行的面呈 \"相邻分布\",相对的面不相邻:中间一行的面依次是 \"1,2,3,4\",其中 \"1\" 和 \"3\" 是相对的面(间隔 1 个面);\"2\" 的相对面是 \"4\",\"6\" 的相对面是 \"5\"。因此 \"1\" 的对面是 \"3\"。故答案为:A", + "knowledge_points": [ + "正方体的特征" + ], + "source": "18-19 一年级下·贵州黔东南·期末" + }, + { + "id": "407", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "用![](images/2025-12-16%20164307.jpg)可以画出( )和( )。", + "options": [ + "A. 等边三角形;长方形", + "B. 正方形;长方形", + "C. 圆形;正方形", + "D. 长方形;圆形" + ], + "answer": "B", + "solution": "【分析】题目中的立体图形是长方体(其中一组对面是正方形),长方体的面由长方形和正方形组成:长方体的长,宽,高不完全相等时,会有 4 个长方形的面和 2 个正方形的面;A。等边三角形不是长方体的面,不符合;C,D。圆形是曲线图形,长方体的面都是直线图形,不符合;B。正方形和长方形都是长方体的面,符合特征。因此用这个长方体可以画出正方形和长方形。故答案为:B", + "knowledge_points": [ + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "20-21一年级下·新疆伊犁·期末" + }, + { + "id": "408", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "下面物体可以画出长方形的是 ( )。", + "options": [ + "A. 圆柱体", + "B. 长方体", + "C. 正方体" + ], + "answer": "B", + "solution": "【分析】 A。圆柱体的面包括圆形(上下底面)和曲面(侧面),无法直接画出长方形;B。长方体的面主要是长方形(或有 2 个相对的面是正方形),可以直接画出长方形;C。正方体的所有面都是正方形,无法画出长方形。因此能画出长方形的物体是长方体。故答案为:B", + "knowledge_points": [ + "长方形,正方形,三角形和圆的初步认识", + "立体图形的认识" + ], + "source": "19-20一年级下·新疆昌吉·期末" + }, + { + "id": "409", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.65, + "question": "拼一拼,用 ( ) 个相同的 \" □ \",可以拼成一个大正方形。", + "options": [ + "A. 2", + "B. 3", + "C. 4", + "D. 8" + ], + "answer": "C", + "solution": "【分析】要拼成大正方形,需要小正方形的数量满足 \"每行每列的小正方形数量相等\":用 2 个小正方形只能拼成长方形,无法拼成正方形;用 3 个小正方形只能拼成长方形,无法拼成正方形;用 4 个小正方形(排成 2 行 2 列),可以组成边长为 2 个小正方形边长的大正方形;8 个小正方形虽然能拼出长方形,但无法排成边长相等的正方形(3×3 需要 9 个)。故答案为:C", + "knowledge_points": [ + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "19-20一年级下·新疆哈密·期末" + }, + { + "id": "410", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "下面物体可以画出圆的是 ( )。", + "options": [ + "A. 圆柱体", + "B. 正方体", + "C. 长方体" + ], + "answer": "A", + "solution": "【详解】 A。圆柱体的上下底面是圆形,将圆柱体的底面平放在纸上,可直接画出圆;B。正方体的所有面都是正方形,无法画出圆;C。长方体的面是长方形或正方形,无法画出圆。因此能画出圆的物体是圆柱体。故答案为:A", + "knowledge_points": [ + "长方形,正方形,三角形和圆的初步认识", + "立体图形的认识" + ], + "source": "17-18 一年级上·河南郑州·期末" + }, + { + "id": "411", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.65, + "question": "用两个一样的三角形不能拼成( )。", + "options": [ + "A. 正方形", + "B. 圆", + "C. 平行四边形" + ], + "answer": "B", + "solution": "【分析】A。两个完全相同的等腰直角三角形,可拼成正方形;B。圆是曲线图形,而三角形是直线图形,无论怎么拼接,都无法组成曲线形状的圆;C。两个完全相同的三角形(任意三角形),都可以拼成平行四边形。因此两个一样的三角形不能拼成圆.\n【详解】两个一样的三角形不能拼成圆。故答案为:B", + "knowledge_points": [ + "平面图形的拼接" + ], + "source": "20-21一年级下·浙江杭州·期末" + }, + { + "id": "412", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.65, + "question": "用![](images/980e1c45d5005734d3acfa11840e74c770fae098c5bfc2a2a1d0a27bcc7c951c.jpg)做成一个正方体,数字\"1\"的对面是( )。", + "options": [ + "A. 5", + "B. 6", + "C. 3" + ], + "answer": "B", + "solution": "【分析】根据正方体的展开图可知,数字\"1\"的面如果作为底面,那么数字\"4\"的面就是前面,数字\"2\"的面就是后面,数字 \"3\"的面是左面,数字 \"5\"的面是右面,数字 \"6\"的面是上面。所以与数字 \"1\"相对的面是数字 \"6\"。\n\n【详解】根据上面的分析得:数字\"1\"的对面是数字\"6\"。故答案为:B。此题主要考查正方体的特征,需要熟悉正方体展开图的形状。", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "19-20 一年级下·浙江宁波·期末" + }, + { + "id": "413", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.65, + "question": "![](images/3d41dab43dc3672802b274609bea4848783fe76867be91ed63981adb6f6eacf8.jpg)把该图折成正方体,数字\"2\"的对面是( )。", + "options": [ + "A. \"1\"", + "B. \"5\"", + "C. \"6\"" + ], + "answer": "B", + "solution": "【分析】这是正方体的 \"1-4-1\" 型展开图(结构为 \"上下各 1 个面,中间一行 4 个面\")。在这种展开图中,中间一行的面呈相邻分布,相对的面会间隔 1 个面:中间一行的面依次是 \"5,1,2,3\",其中 \"2\" 和 \"5\" 间隔 1 个面(\"1\"),因此 \"2\" 的对面是 \"5\";同时,\"1\" 的对面是 \"3\",\"6\" 的对面是 \"4\"。因此数字 \"2\" 的对面是 \"5\"。故答案为:B", + "knowledge_points": [ + "正方体的展开图" + ], + "source": "19-20 一年级下·浙江温州·期末" + }, + { + "id": "414", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.65, + "question": "![](images/51a999d3de8fe3631a7fb08f2c90bda7e83a419044f601b8eb4186ccc748c165.jpg)用左图折出一个正方体,\"3\"的对面是( )。", + "options": [ + "A. 4", + "B. 5", + "C. 6" + ], + "answer": "A", + "solution": "【分析】这是正方体的 \"1-4-1\" 型展开图(结构为 \"上下各 1 个面,中间一行 4 个面\")。在这种展开图中,中间一行的面呈相邻分布,相对的面会间隔 1 个面:中间一行的面依次是 \"6,3,5,4\",其中 \"3\" 和 \"4\" 间隔 1 个面(\"5\"),因此 \"3\" 的对面是 \"4\";同时,\"6\" 的对面是 \"5\",\"1\" 的对面是 \"2\"。因此数字 \"3\" 的对面是 \"4\"。故答案为:A", + "knowledge_points": [ + "正方体的展开图" + ], + "source": "18-19一年级下·浙江宁波·期末" + }, + { + "id": "415", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "两个同样的三角形可以拼成 ( )。", + "options": [ + "A. 正方体", + "B. 平行四边形", + "C. 长方体" + ], + "answer": "B", + "solution": "【分析】 A。正方体是立体图形,而三角形是平面图形,两个平面三角形无法拼成立体的正方体;B。将两个完全相同的三角形的对应边拼接,可组成两组对边分别平行的四边形,即平行四边形(任意三角形都能拼成);C。长方体是立体图形,平面三角形无法拼成长方体。因此两个同样的三角形可以拼成平行四边形。故答案为:B", + "knowledge_points": [ + "长方形,正方形,三角形和圆的初步认识", + "平面图形的拼接" + ], + "source": "18-19一年级下·浙江宁波·期末" + }, + { + "id": "416", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "我们少先队员佩戴的红领巾的形状是( )。", + "options": [ + "A. ![](images/2025-12-16%20170331.jpg)", + "B. ![](images/2025-12-16%20170356.jpg)", + "C. ![](images/2025-12-16%20170415.jpg)" + ], + "answer": "C", + "solution": "【分析】根据生活实际,红领巾都是三角形的,据此求解。\n\n【详解】A。 为长方形,不符合;B. 为平行四边形,不符合;C. 为三角形,符合。故答案为: C。本题主要考查三角形在生活中的应用。", + "knowledge_points": [ + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "19-20一年级下·浙江绍兴·期末" + }, + { + "id": "417", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "2 个![](images/2025-12-16%20170545.jpg)可以拼成一个( )。", + "options": [ + "A. 长方形", + "B. 正方形", + "C. 圆" + ], + "answer": "A", + "solution": "【分析】题目中的三角形是直角三角形(非等腰直角三角形):A。将两个完全相同的直角三角形的斜边拼接,可组成一个长方形;B。正方形需要由等腰直角三角形拼接,而此三角形不是等腰直角三角形,无法拼成正方形;C。圆是曲线图形,直角三角形是直线图形,无法拼成圆。因此 2 个这样的三角形可以拼成一个长方形。故答案为:A", + "knowledge_points": [ + "平面图形的拼接" + ], + "source": "18-19 一年级下·浙江绍兴·期末" + }, + { + "id": "418", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.65, + "question": "拼成一个正方形,至少要用( )个![](images/2025-12-16%20170909.jpg)。", + "options": [ + "A. 2 个", + "B. 4 个", + "C. 6 个" + ], + "answer": "A", + "solution": "【分析】题目中的三角形是等腰直角三角形:等腰直角三角形的两条直角边长度相等,将 2 个这样的三角形的斜边拼接,可组成一个正方形(两条直角边成为正方形的边长)。4个虽然也能拼成正方形,但不是最少。故答案为:A", + "knowledge_points": [ + "平面图形的拼接" + ], + "source": "18-19一年级下·浙江宁波·期末" + }, + { + "id": "419", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "![](images/e7475ee70b742d3becffa5cfb2066efb8e86085c70f96d5c4a8bdf2828b8f1f0.jpg)这个长方体上有( )种不同的长方形。", + "options": [ + "A. 2", + "B. 3", + "C. 6" + ], + "answer": "B", + "solution": "【分析】长方体有 6 个面,且相对的面完全相同,其面的形状由长,宽,高的长度决定:第 1 种长方形:由 \"长×宽\" 组成的面;第 2 种长方形:由 \"长×高\" 组成的面;第 3 种长方形:由 \"宽×高\" 组成的面。因此这个长方体上有 3 种不同的长方形。故答案为:B", + "knowledge_points": [ + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "18-19一年级下·浙江宁波·期末" + }, + { + "id": "420", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "用![](images/c5badf46f480aaa60d27b6392251cd669af97a30a3711d1a64dae19bba163769.jpg)做成一个正方体,数字\"4\"的对面是数字( )。", + "options": [ + "A. 3", + "B. 2", + "C. 1" + ], + "answer": "B", + "solution": "【分析】这是正方体的 \"1-4-1\" 型展开图(结构为 \"上下各 1 个面,中间一行 4 个面\")。在这种展开图中,中间一行的面呈相邻分布,相对的面会间隔 1 个面:中间一行的面依次是 \"1,2,3,4\",其中 \"4\" 和 \"2\" 间隔 1 个面(\"3\"),因此 \"4\" 的对面是 \"2\";同时,\"1\" 的对面是 \"3\",\"5\" 的对面是 \"6\"。因此数字 \"4\" 的对面是数字 \"2\"。故答案为:B", + "knowledge_points": [ + "正方体的展开图" + ], + "source": "18-19 一年级下·浙江宁波·期末" + }, + { + "id": "421", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.65, + "question": "用 ( ) 个小正方形可以拼成大正方形。", + "options": [ + "A. 4", + "B. 8", + "C. 6" + ], + "answer": "A", + "solution": "【分析】要拼成大正方形,小正方形的数量需满足 \"每行每列的小正方形数量相等\"(即数量为完全平方数):A。4 个小正方形可排成 2 行 2 列,组成边长为 2 个小正方形边长的大正方形;B。8 个小正方形只能拼成长方形(如 2×4),无法排成边长相等的正方形;C:6 个小正方形只能拼成长方形(如 2×3),无法拼成正方形。因此用 4 个小正方形可以拼成大正方形。故答案为:A", + "knowledge_points": [ + "长方形,正方形,三角形和圆的初步认识", + "平面图形的拼接" + ], + "source": "18-19 一年级下·浙江宁波·期末" + }, + { + "id": "422", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "下面哪个图形是用两个相同的长方形拼成的。 ( )", + "options": [ + "A. ![](images/6edc1c74dbd99cb765c312b526d2aea1c5ad3b391a929ff5f359e56e0fa203de.jpg)", + "B. ![](images/03bd3e882909d7a2a3d2cf2838f373eb80ac23c536fe541be378746db78e1853.jpg)", + "C. ![](images/9c1d1921f5f646d414a3974b45347440263cf917fe7f067c874e52c5ca85769d.jpg)" + ], + "answer": "A", + "solution": "【分析】A。图形是由两个完全相同的长方形(上下拼接)组成的大长方形,符合 \"两个相同的长方形拼成\" 的要求;B。图形是两个正方形拼接而成,不是长方形;C。图形是由正方形和长方形拼接而成,并非两个相同的长方形。因此只有选项 A 是用两个相同的长方形拼成的。故答案为:A", + "knowledge_points": [ + "长方形,正方形,三角形和圆的初步认识", + "平面图形的拼接" + ], + "source": "18-19 一年级下·浙江宁波·期末" + }, + { + "id": "423", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.65, + "question": "用![](images/2025-12-16%20171924.jpg)做成一个正方体,\"2\"的对面是( )。", + "options": [ + "A. 5", + "B. 3", + "C. 6" + ], + "answer": "B", + "solution": "【分析】这是正方体的 \"1-4-1\" 型展开图(结构为 \"上下各 1 个面,中间一行 4 个面\")。在这种展开图中,上下分布的面互为相对面:图中 \"3\" 位于上方,\"2\" 位于下方,二者是上下对应的面;同时,\"1\" 的对面是 \"5\",\"4\" 的对面是 \"6\"。因此 \"2\" 的对面是 \"3\"。故答案为:B", + "knowledge_points": [ + "正方体的展开图" + ], + "source": "19-20 一年级下·甘肃兰州·期末" + }, + { + "id": "424", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "用4个大小一样的正方形,能拼成( )。", + "options": [ + "A. 正方形", + "B. 长方形", + "C. 正方形或长方形" + ], + "answer": "C", + "solution": "【分析】用 4 个大小一样的正方形拼接,有两种方式:方式 1:排成 2 行 2 列,可组成边长为 2 个小正方形边长的大正方形。方式 2:排成 1 行 4 列(或 4 行 1 列),可组成长方形。因此 4 个大小一样的正方形既能拼出正方形,也能拼出长方形。故答案为:C", + "knowledge_points": [ + "平面图形的拼接" + ], + "source": "18-19一年级下·甘肃庆阳·期末" + }, + { + "id": "425", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.4, + "question": "墙上缺了 ( ) 块砖.\n\n![](images/5e3a845e383c9e433d64f8401864d6cd903d90fd5f862595274c35d9551be52f.jpg)", + "options": [ + "A. 11", + "B. 12", + "C. 13" + ], + "answer": "B", + "solution": "【详解】通过观察题中的图可以发现,从上往下,第一行,第三行,第五行的砖块的摆放方式相同;第二行,第四行,第六行的砖块的摆放方式相同,所以可以根据第六行补画第二行和第四行,根据第一行补画第三行和第五行。", + "knowledge_points": [ + "平面图形的拼接" + ], + "source": "17-18 一年级下·北京朝阳·期末" + }, + { + "id": "426", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "把一张正方形纸对折1次,能折出两个( )。", + "options": [ + "A. 三角形", + "B. 圆", + "C. 正方形" + ], + "answer": "A", + "solution": "【分析】将正方形纸对折 1 次,有两种常见折法:沿对角线对折:会折出两个完全相同的等腰直角三角形;沿对边中点连线对折:会折出两个完全相同的长方形(但选项中无长方形,结合选项,对角线对折的结果 \"三角形\" 符合要求)。而选项 B 的圆是曲线图形,无法通过正方形对折得到;选项 C 的正方形也无法通过 1 次对折得到(对折 1 次会将正方形分成两个部分,无法保持正方形形状)。因此把一张正方形纸对折 1 次,能折出两个三角形。故答案为:A", + "knowledge_points": [ + "图形的折叠问题" + ], + "source": "18-19一年级下·广西防城港·期中" + }, + { + "id": "427", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "用两个同样的三角形,不能拼成下面哪个图形。( )", + "options": [ + "A. 正方形", + "B. 梯形", + "C. 长方形" + ], + "answer": "B", + "solution": "【分析】A:两个完全相同的等腰直角三角形,可拼成正方形;B:梯形只有一组对边平行,而两个相同的三角形拼接后,会形成两组对边分别平行的图形(如平行四边形,长方形等),无法拼出只有一组对边平行的梯形;选项 C:两个完全相同的直角三角形,可拼成长方形。因此用两个同样的三角形不能拼成梯形。故答案为:B", + "knowledge_points": [ + "平面图形的拼接" + ], + "source": "18-19 一年级下·广西来宾·期末" + }, + { + "id": "428", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.94, + "question": "我们教室的门是 ( )。", + "options": [ + "A. 长方形", + "B. 正方形", + "C. 平行四边形" + ], + "answer": "A", + "solution": "【分析】教室的门通常是 \"长大于宽\" 的四边形,且四个角都是直角: A。长方形的特征是对边相等,四个角为直角,符合教室门的形状;B。正方形的边长都相等,教室门的长和宽不相等,不符合;C。平行四边形的角不是直角,且形状不稳定,不符合教室门的实际形状。因此教室的门是长方形。故答案为:A", + "knowledge_points": [ + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "19-20 一年级下·广西南宁·期末" + }, + { + "id": "429", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "下面的 3 组图形中,能拼成一个正方形的是 ( )。", + "options": [ + "A. ![](images/17d805894db655eb8f83fee6e8fe6e2514802e9158d04863f5478ff22a03357d.jpg)", + "B. ![](images/97107a4d9bb8e67bd6395e5e98c35337caab459aa26627280b31dcadbf8d014e.jpg)", + "C. ![](images/fe744e45df229e28bba74e663f2251052bb468fa9f6b3c4b203ebc70e724fdff.jpg)" + ], + "answer": "A", + "solution": "【分析】A。两个一样的长方形,且长是宽的两倍,可组成一个大正方形;B。两个三角形只能拼成平行四边形或长方形,无法拼成正方形;C。长方形和正方形的边长不匹配,无法拼成正方形。因此能拼成一个正方形的是选项 A.", + "knowledge_points": [ + "平面图形的拼接" + ], + "source": "17-18 一年级下·广西河池·期末" + }, + { + "id": "430", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "下图是由 ( ) 图形拼成的.\n\n![](images/d87fbaefc226e6d6af5142f5eb3bc6c5ee09cdac5e98cae64f6baa9c22fc42e3.jpg)", + "options": [ + "A. ![](images/9e379a6774f10dc8f77b2a22ffbac280f0c8fb7dcb04059c97924c5586db43fe.jpg)", + "B. ![](images/6c0610b81ee854c6da226db2538bdcd823e7b0a9492aa027f996a7dd64bab0ba.jpg)", + "C. ![](images/224b37693a9a27984e0798f8b8551b629443f1e0cf1fa83626823c091af711f9.jpg)" + ], + "answer": "B", + "solution": "【分析】该图由7个小多边形组成,每个多边形有六条边。所以该图由六边形组成。故答案为:B", + "knowledge_points": [ + "平面图形的拼接" + ], + "source": "19-20 一年级下·广西玉林·期末" + }, + { + "id": "431", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "拼成一个![](images/b58056aa49b731782821c5f90a25cbeaa2449fd503d0a591d3a6f2c16c35efe2.jpg), 需要用 ( ) 个这样的![](images/2025-12-16%20173720.jpg)。", + "options": [ + "A. 6", + "B. 5", + "C. 4" + ], + "answer": "C", + "solution": "【分析】一个长方形由两个这样的三角形拼成。图中有两个长方形,需要2+2=4个.\n【详解】拼成该图需要4个这样的三角形。故答案为:C", + "knowledge_points": [ + "平面图形的拼接" + ], + "source": "19-20 一年级下·广西崇左·期中" + }, + { + "id": "432", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "2 个同样的三角形不能拼成 ( )。", + "options": [ + "A. 长方形", + "B. 三角形", + "C. 圆形" + ], + "answer": "C", + "solution": "【分析】根据平面图形的拼接关系可知:两个同样的三角形,当它们为直角三角形或以适当方式拼接时,可以拼成一个长方形(实为平行四边形,特殊情况下为长方形);两个同样的三角形,以对应边对齐拼接,可以拼成一个更大的三角形;由于圆形的边是光滑的曲线,而三角形的边均为直线,无论怎样拼接两个三角形,都不能拼出圆形。因此,两个同样的三角形不能拼成圆形。故答案为:C", + "knowledge_points": [ + "平面图形的拼接" + ], + "source": "17-18 一年级下·内蒙古巴彦淖尔·期末" + }, + { + "id": "433", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "用两个同样的△ 可以拼成一个( )。", + "options": [ + "A. 三角形", + "B. 圆", + "C. 平行四边形" + ], + "answer": "C", + "solution": "【分析】用两个同样的三角形,如果将它们对应的边对齐并贴合,可以拼成一个平行四边形。故答案为:C", + "knowledge_points": [ + "长方形,正方形,三角形和圆的初步认识", + "平面图形的拼接" + ], + "source": "19-20 一年级下·内蒙古赤峰·期末" + }, + { + "id": "434", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.65, + "question": "折一折,用![](images/5079a1327c73c33da9f6791d316916cf1d53c7c80b442db15197d71fcd8c20cd.jpg)做一个正方体,\"3\"的对面是( )。", + "options": [ + "A. 4", + "B. 1", + "C. 6" + ], + "answer": "C", + "solution": "【分析】这是正方体的\"1-4-1\"型展开图(结构为\"上下各1个面,中间一行4个面\")。在这种展开图中,中间一行的面呈相邻分布,相对的面会间隔2个面:中间一行的面依次是\"4,3,1,6\",其中\"3\"和\"6\"间隔2个面(\"1\"),因此\"3\"的对面是\"6\";同时,\"4\"的对面是\"1\",\"2\"的对面是\"5\".\n【详解】因此\"3\"的对面是\"6\"。故答案为:C", + "knowledge_points": [ + "正方体的展开图" + ], + "source": "19-20一年级下·内蒙古赤峰·期末" + }, + { + "id": "435", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "下列图形是平行四边形的是 ( )。", + "options": [ + "A. ![](images/09d742b350ff96202bb333ad7c9222a2d24029f60728fde17a1555cb4d05e7db.jpg)", + "B. ![](images/c2fd3fda1e9cd19ec45e50daf28d79af481786cc7383ef6f913bace1eeeed181.jpg)", + "C. ![](images/fa343a1326d013b869541fb780541bacce92f7a4f074c8b17cc64e5d02b9fc17.jpg)" + ], + "answer": "C", + "solution": "【分析】平行四边形对边相等,四个角不是直角。由此判断平行四边形即可。\n\n【详解】A是长方形,B是正方形,C是平行四边形。故答案为:C", + "knowledge_points": [ + "平行四边形的初步认识" + ], + "source": "18-19 一年级下·江苏·单元测试" + }, + { + "id": "436", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.4, + "question": "![](images/2025-12-16%20180422.jpg)中有( )个三角形。", + "options": [ + "A. 5", + "B. 4", + "C. 3", + "D. 6" + ], + "answer": "D", + "solution": "【分析】数三角形时,可按 \"单个小三角形\" 和 \"组合三角形\" 分类统计:单个小三角形:图中有 4个独立的小三角形;由 2 个小三角形组成的三角形:有 2 个。4 + 2 =6。故答案为:D", + "knowledge_points": [ + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "18-19 一年级下·江西南昌·期末" + }, + { + "id": "437", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "4 个![](images/2025-12-16%20180822.jpg)不可能拼成一个( )。", + "options": [ + "A. 长方形", + "B. 正方形", + "C. 平行四边形", + "D. 圆" + ], + "answer": "D", + "solution": "【分析】题目中的图形是直角三角形,分析各选项: A。4 个直角三角形可拼成长方形(将三角形两两拼接成长方形,再组合);B。4 个等腰直角三角形可拼成正方形(拼接成 2×2 的正方形结构);C。任意 4 个相同的三角形可拼成平行四边形;D。圆是曲线图形,而三角形是直线图形,无论多少个直线图形都无法拼出曲线图形的圆。因此 4 个这样的三角形不可能拼成的是圆。故答案为:D", + "knowledge_points": [ + "平面图形的拼接" + ], + "source": "18-19 一年级下·江西南昌·期末" + }, + { + "id": "438", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.4, + "question": "用 4 个大小相同的小正方形一定可以拼成一个 ( )。", + "options": [ + "A. 圆", + "B. 三角形", + "C. 大正方形" + ], + "answer": "C", + "solution": "【分析】四个相同的正方形可以拼成 2×2 的正方形结构。故答案为:C", + "knowledge_points": [ + "平面图形的拼接" + ], + "source": "19-20 一年级下·江西萍乡·期末" + }, + { + "id": "439", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.65, + "question": "用两个同样的 ( )可以拼一个![](images/2025-12-16%20181403.jpg) 。", + "options": [ + "A. 正方形", + "B. 三角形", + "C. 长方形" + ], + "answer": "B", + "solution": "【分析】题目要拼的图形是平行四边形,分析各选项:A。两个相同的正方形拼接后得到的是长方形(属于特殊平行四边形,但不是题目所示的一般平行四边形);B。两个完全相同的三角形,将它们的一组对应边重合拼接,可组成两组对边分别平行的四边形,即平行四边形(符合题目图形的形状);C。两个相同的长方形拼接后得到的是大长方形(同样是特殊平行四边形,不符合题目图形)。因此用两个同样的三角形可以拼成该平行四边形。故答案为:B", + "knowledge_points": [ + "长方形,正方形,三角形和圆的初步认识", + "平面图形的拼接", + "平行四边形的初步认识" + ], + "source": "19-20 一年级下·江西吉安·期末" + }, + { + "id": "440", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.65, + "question": "摆1个正方形用4根小棒,摆4个正方形用( )小棒。", + "options": [ + "A. 16 根", + "B. 8 根", + "C. 9 根" + ], + "answer": "A", + "solution": "【分析】4 + 4 + 4 + 4 = 16(根),故答案为:A", + "knowledge_points": [ + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "19-20一年级下·山西忻州·期中" + }, + { + "id": "441", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "用这样两个完全相同的\n\n![](images/22538a89509efd873474fa2c89d9a17114690ae2190e566007124fd0e502ed0a.jpg)\n\n不能拼成图()。", + "options": [ + "A. ![](images/b0749af29f5a92979d85bb83da52cc7ec40fbce347079e1e4a8061b941af22cf.jpg)", + "B. ![](images/876c3699169a1b9116efd0c376bcd6eaa59c4ca4002b6f3bafa5589fcd020ccf.jpg)", + "C. ![](images/1abe3323f9d251a81e1b66bc7b4f6959d673044c9ae552666cbe6762dd2a547a.jpg)" + ], + "answer": "B", + "solution": "【分析】该图是直角三角形,B中的三角形显然不是。故答案为:B", + "knowledge_points": [ + "平面图形的拼接" + ], + "source": "14-15 一年级下·天津·期末" + }, + { + "id": "442", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.65, + "question": "用下面物体 ( ) 可以画一个圆。", + "options": [ + "A. ![](images/af6621d9f10ea7b098f31004e7d0dbea98f21fec1a00887849623a73e8373221.jpg)", + "B. ![](images/dc879037abbdd9e2f3ea6ef346daf735e3780a8056deb42dbb26a67d329f4caa.jpg)", + "C. ![](images/7cdaed9b1af1b6321f0480fb9ceb6f0afcbc30542f607eb0ee969e3c7dd4f7cb.jpg)" + ], + "answer": "A", + "solution": "【分析】分析各选项物体的形状特征:A。该物体是圆锥,其底面是圆形。将圆锥的底面贴在纸上,沿边缘描线即可画出圆;B。该物体是球体,球体表面是曲面,无法直接在平面上画出标准的圆;C。该物体是长方体,其面都是长方形(或正方形),没有圆形的面,无法画出圆。因此用圆锥可以画一个圆。故答案为:A", + "knowledge_points": [ + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "20-21 一年级下·全国·期中" + }, + { + "id": "443", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.65, + "question": "2 个同样的 ( ) 可以拼成一个平行四边形。", + "options": [ + "A. 正方形", + "B. 长方形", + "C. 三角形" + ], + "answer": "C", + "solution": "【分析】根据三角形,平行四边形的特征和关系,解题即可。\n\n【详解】2 个同样的正方形或者长方形都只能拼成一个长方形,而 2 个同样的三角形可以拼成一个平行四边形。故答案为: C。本题考查了平面图形的拼接,认识三角形,平行四边形,长方形以及正方形是解题的关键。", + "knowledge_points": [ + "长方形,正方形,三角形和圆的初步认识", + "平面图形的拼接", + "平行四边形的初步认识" + ], + "source": "18-19 一年级下·福建厦门·期中" + }, + { + "id": "444", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "用下面的物体,能画出 ○ 的是 ( )。", + "options": [ + "A. ![](images/56b52264fd534a99be158ea6bb535409734ea9a13d48368685b14c0bcaf484bb.jpg)", + "B. ![](images/bcf5a7f53129b2f1679ee194c079d6a2cd7e49816a70412c1a799471e2eb5bf5.jpg)", + "C. ![](images/3fd8b6cb14040be0a331955d1ad2c15cc11516a555684f7ea4efedf354a85666.jpg)" + ], + "answer": "C", + "solution": "【分析】分析各选项物体的形状:A。物体是长方体,其面均为长方形(或正方形),无圆形面,无法画出圆;B。物体是球体,球体表面是曲面,无法在平面上直接画出标准的圆;C。物体是圆柱,其上下底面是圆形。将圆柱的底面贴在纸上,沿边缘描线即可画出圆。因此能画出 ○ 的是圆柱(选项 C)。", + "knowledge_points": [ + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "19-20 一年级下·云南德宏·期末" + }, + { + "id": "445", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.65, + "question": "用![](images/5cf2dff3a0a559af137a5c4bcb603f4e207ceea49c05ed37a8137214883895dd.jpg)\n做成一个正方体,数字 3 的对面是 ( )。", + "options": [ + "A. 2", + "B. 4", + "C. 5" + ], + "answer": "B", + "solution": "【分析】这是正方体的 \"1-4-1\" 型展开图(结构为 \"上下各 1 个面,中间一行 4 个面\")。在这种展开图中,中间一行的面呈相邻分布,相对的面会间隔 1 个面:中间一行的面依次是 \"4,5,3,2\",其中 \"3\" 和 \"4\" 间隔 1 个面(\"5\"),因此 \"3\" 的对面是 \"4\";同时,\"6\" 的对面是 \"1\",\"5\" 的对面是 \"2\"。因此数字 3 的对面是 4。故答案为:B", + "knowledge_points": [ + "正方体的展开图" + ], + "source": "17-18 一年级下·云南红河·期末" + }, + { + "id": "446", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.65, + "question": "下面三组图形中,能拼成正方形的是 ( )。", + "options": [ + "A. ![](images/2025-12-16%20182500.jpg)", + "B. ![](images/2025-12-16%20182512.jpg)", + "C. ![](images/48c52ddd3dd924963d16c4777c099dbab77f1b75e6eb566b17f2876c466ea9e4.jpg)" + ], + "answer": "C", + "solution": "【分析】分析各组图形:A。两个三角形形状,大小不一致,无法拼接成规则图形;B。两个三角形只能拼出平行四边形,无法组成正方形;C。两个完全相同的等腰直角三角形,将它们的斜边拼接,可组成一个正方形。因此能拼成正方形的是选项 C。故答案为:C", + "knowledge_points": [ + "长方形,正方形,三角形和圆的初步认识", + "平面图形的拼接" + ], + "source": "19-20 一年级下·云南昆明·期末" + }, + { + "id": "447", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.94, + "question": "图中,它上面的形状是 ( ).\n\n![](images/1456f0aeafe6ed452dd7b48a0a4a7a7dd1917b1568fc575809f21f8d9d6b18fe.jpg)", + "options": [ + "A. ![](images/4dda98a8f76f9d6be413475fc9bb59c66166d623760a3efb433ea630d4455486.jpg)", + "B. ![](images/7b7b75ce877405bad35e630bbf84382c72465e08749e435a5811af49b91d166c.jpg)", + "C. ![](images/1d82f266798c85b5b35336f4a7927a9efed733242f97a68536b359b5cad62301.jpg)" + ], + "answer": "A", + "solution": "【分析】图中的立体图形是长方体,其上下底面是正方形。因此它上面的形状是正方形,故答案为:A", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "16-17 一年级下·云南德宏·期末" + }, + { + "id": "448", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "两个完全一样的长方形,可以拼成一个( )。", + "options": [ + "A. 长方形", + "B. 正方形", + "C. 长方形或正方形" + ], + "answer": "C", + "solution": "【分析】分两种情况分析:拼成长方形:将两个长方形的长边(或短边)拼接,可组成一个长(或宽)加倍的大长方形;拼成正方形:若长方形的长是宽的 2 倍,将两个长方形的宽边拼接,可组成边长等于原长方形长的正方形。因此两个完全一样的长方形,既可以拼成长方形,也可以拼成正方形。故答案为:C", + "knowledge_points": [ + "平面图形的拼接" + ], + "source": "19-20一年级下·云南楚雄·期末" + }, + { + "id": "449", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "下面的物体能画出 ○ 的是 ( )。", + "options": [ + "A. 圆柱体", + "B. 长方体", + "C. 正方体" + ], + "answer": "A", + "solution": "【分析】要能画出圆,物体必须有一个面是圆形。圆柱体上下底面是圆,长方体和正方体的面都是直线围成的平面图形.\n【详解】圆柱体的上下底面是圆形,可以画出○;长方体和正方体无法画出圆。故答案为:A", + "knowledge_points": [ + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "17-18 一年级下·云南德宏·期末" + }, + { + "id": "450", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.65, + "question": "用 ( ) 可以画出 ○ 。", + "options": [ + "A. 圆柱体", + "B. 正方体", + "C. 长方体" + ], + "answer": "A", + "solution": "【分析】正方体每个面都是正方形;长方体的面是长方形或正方形;圆柱上下两个面是大小相同的圆形,侧面是曲面。只有圆柱的底面可以画出圆.\n【详解】用圆柱体可以画出○。故答案为:A", + "knowledge_points": [ + "长方形,正方形,三角形和圆的初步认识", + "立体图形的认识" + ], + "source": "19-20 一年级下·云南楚雄·期末" + }, + { + "id": "451", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.85, + "question": "用 ( ) 可以画出![](images/2025-12-16%20183332.jpg)。", + "options": [ + "A. 圆柱体", + "B. 正方体", + "C. 长方体" + ], + "answer": "C", + "solution": "【分析】分析各选项立体图形的面特征:A。圆柱体的面是圆形和曲面,无法画出长方形;B。正方体的面是正方形,不能直接画出长方形(正方形是特殊长方形,但题目中的图形是一般长方形);C。长方体有长方形的面,将长方体的长方形面贴在纸上,沿边缘描线即可画出该长方形。因此用长方体可以画出这个图形。故答案为:C", + "knowledge_points": [ + "长方形,正方形,三角形和圆的初步认识", + "立体图形的认识" + ], + "source": "18-19 一年级下·云南楚雄·期末" + }, + { + "id": "452", + "unit": "认识图形", + "question_type": "选择题", + "difficulty": 0.4, + "question": "把下图围成一个正方体,\"5\"和 ( ) 相对,\"1\"和 ( ) 相对.\n\n![](images/e84a9b0fcce5ff59709f95360c08d67c0ef27ac67aa222a843c98e35a51fd36e.jpg)", + "options": [ + "A. 3,4", + "B. 6,4", + "C. 6,3" + ], + "answer": "C", + "solution": "【分析】该图是正方体的\"1-4-1\"型展开图(上下各1个面,中间一行4个面),此类展开图中相对面会间隔1个面:\"5\"位于上方的面,与之相对的是下方的\"6\";\"1\"在中间行左侧,与之相对的是中间行的\"3\"(间隔\"2\")。因此\"5\"和\"6\"相对,\"1\"和\"3\"相对.\n【详解】故答案为:C", + "knowledge_points": [ + "长方形,正方形,三角形和圆的初步认识", + "正方体的展开图" + ], + "source": "17-18一年级下·甘肃金昌·期中" + }, + { + "id": "453", + "unit": "认识图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "如下图,沿虚线折出来的是正方体,其中1与( )相对.\n\n![](images/34006c9022d71e2ce1c795d6d1cc469609d350cf5c5b2f0e7a88ec6a371ab549.jpg)", + "options": [], + "answer": "3", + "solution": "【分析】这是正方体的 \"1-4-1\" 型展开图(中间一行 4 个面,上下各 1 个面),此类展开图中上下相对,中间间隔相对:数字 \"1\" 位于上方的面,与之相对的是下方的 \"3\"(上下对应)。因此 1 与 3 相对。", + "knowledge_points": [ + "正方体的展开图" + ], + "source": "19-20 一年级下·贵州六盘水·期末" + }, + { + "id": "454", + "unit": "认识图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "折一折,用![](images/15d02f3123abe3c79ffcbde5108f03f95710d4449dda3b75ecd3f7d0486777ea.jpg)做一个正方体,\"3\"的对面是( )。", + "options": [], + "answer": "4", + "solution": "【分析】这是正方体的 \"1-4-1\" 型展开图(中间一行 4 个面,上下各 1 个面),此类展开图中中间行的相对面会间隔 1 个面:数字 \"3\" 在中间行最右侧,与之间隔 1 个面 \"2\" 的是 \"4\",因此 \"3\" 的对面是 \"4\"。", + "knowledge_points": [ + "正方体的展开图" + ], + "source": "20-21一年级下·贵州铜仁·期末" + }, + { + "id": "455", + "unit": "认识图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "用![](images/e5ee01638654be494bfadcaa99869042ee41a3aebc930e0eb0cfddf8c85ac9b4.jpg)做一个正方体,数字2的对面是数字( ),数字5的对面是数字( )。", + "options": [], + "answer": "6;3", + "solution": "【分析】这是正方体的\"1-4-1\"型展开图(上下各1个面,中间一行4个面),此类展开图的相对面规律是\"上下相对,中间间隔相对\":数字\"2\"位于中间行左侧,与之间隔1个面\"1\"的是\"6\";数字\"5\"位于下方的面,与之相对的是上方的\"3\".\n【详解】数字2的对面是6,数字5的对面是3。故答案为:6;3", + "knowledge_points": [ + "正方体的展开图" + ], + "source": "20-21一年级下·浙江杭州·期末" + }, + { + "id": "456", + "unit": "认识图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "用![](images/4a794d6d3a20d29a2fc3f1a7f03b86d5f405eaea99ca97d19a93534d2ad70b8f.jpg)做成一个正方体,数字\"4\"对面的数字是( )。", + "options": [], + "answer": "2", + "solution": "【分析】这是正方体的 \"1-4-1\" 型展开图(上下各 1 个面,中间一行 4 个面),此类展开图中中间行的相对面会间隔 1 个面:数字 \"4\" 位于中间行最右侧,与之间隔 1 个面 \"3\" 的是 \"2\",因此 \"4\" 的对面是 \"2\"。", + "knowledge_points": [ + "正方体的展开图" + ], + "source": "18-19一年级下·贵州铜仁·期末" + }, + { + "id": "457", + "unit": "认识图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "数一数,下图中需要( )块砖才能把墙补好.\n\n![](images/041f9febec6f8acfa44a2140bfa19a729953a301593cc02260978f82e8858566.jpg)", + "options": [], + "answer": "8", + "solution": "【分析】补墙问题可按 \"每行缺砖数相加\" 计算:观察墙面的砖排列规律(每行砖数一致,错位排列):第 2 行缺 2 块;第 3 行缺 3 块;第 4 行缺 3 块。总计缺砖数:2+3+3=8。", + "knowledge_points": [ + "平面图形的拼接" + ], + "source": "19-20 一年级下·贵州遵义·期末" + }, + { + "id": "458", + "unit": "认识图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "用![](images/7ce8fab0301e54b231de8579685bbb9a9c2fe7fcb261df28d813949d57903de3.jpg)做成一个正方体,\"5\"的对面是( )。", + "options": [], + "answer": "6", + "solution": "【分析】这是正方体的 \"1-4-1\" 型展开图(上下各 1 个面,中间一行 4 个面),此类展开图的相对面规律为 \"上下对应相对\":数字 \"5\" 位于上方的面,与之相对的是下方的 \"6\"。", + "knowledge_points": [ + "正方体的展开图" + ], + "source": "20-21 一年级下·陕西渭南·期末" + }, + { + "id": "459", + "unit": "认识图形", + "question_type": "填空题", + "difficulty": 0.65, + "question": "用同样大小的正方形拼成一个大正方形,最少要( )个。", + "options": [], + "answer": "4", + "solution": "【详解】用同样大小的正方形拼大正方形,需满足 \"每行每列的正方形数量相等\":最少需要 2×2 排列的正方形,共2×2=4个(1 个无法拼大正方形,2,3 个只能拼成长方形)。", + "knowledge_points": [ + "平面图形的拼接" + ], + "source": "18-19 一年级下·北京·单元测试" + }, + { + "id": "460", + "unit": "认识图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "![](images/3c8847f84b8e8fc34738d9685290b2a513c003172d09b1a1c1cd1656fd0badd1.jpg)有( )个正方体。", + "options": [], + "answer": "5", + "solution": "【分析】数立体图形的小正方体时,需分层统计(避免遗漏被遮挡的部分):下层有 4 个小正方体(能直接看到的基础层);上层有 1 个小正方体(叠在下层的小正方体上);总计:4+1=5个。", + "knowledge_points": [ + "立体图形的认识" + ], + "source": "20-21一年级下·贵州铜仁·期末" + }, + { + "id": "461", + "unit": "认识图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "用小棒摆一个三角形至少需要( )根。", + "options": [], + "answer": "3", + "solution": "【详解】三角形的定义是 \"由 3 条线段首尾顺次连接围成的封闭图形\",因此用小棒摆一个三角形,至少需要 3 根小棒(每根小棒对应三角形的一条边)。", + "knowledge_points": [ + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "18-19 一年级下·新疆阿克苏·期末" + }, + { + "id": "462", + "unit": "认识图形", + "question_type": "填空题", + "difficulty": 0.94, + "question": "我们数学书的封面是( )形。", + "options": [], + "answer": "长方", + "solution": "【详解】数学书的封面具有 \"对边相等,四个角都是直角\" 的特征,符合长方形的定义,因此它的封面是长方形。", + "knowledge_points": [ + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "16-17 一年级·全国·课后作业" + }, + { + "id": "463", + "unit": "认识图形", + "question_type": "填空题", + "difficulty": 0.65, + "question": "用![](images/61b9d170cffad1ffc395b7297eb72c6943279b8b04f25d024453c032fef3876c.jpg)做成正方体,数字\"2\"的对面是数字( )。", + "options": [], + "answer": "1", + "solution": "【详解】这是正方体的 \"1-4-1\" 型展开图(上下各 1 个面,中间一行 4 个面),此类展开图中中间行的相对面会间隔 1 个面:数字 \"2\" 位于中间行,与之间隔 1 个面 \"4\" 的是 \"1\",因此 \"2\" 的对面是 \"1\"。", + "knowledge_points": [ + "正方体的展开图" + ], + "source": "18-19 一年级下·浙江宁波·期末" + }, + { + "id": "464", + "unit": "认识图形", + "question_type": "填空题", + "difficulty": 0.65, + "question": "用![](images/1d1f33a5d5bdabdd2dd536b734022fce72bd164af077b948cbe04ca62417e480.jpg)做成一个正方体,2的对面是( );6的对面是( )。", + "options": [], + "answer": "1;5", + "solution": "【分析】这是正方体的 \"1-4-1\" 型展开图(上下各 1 个面,中间一行 4 个面),遵循 \"中间间隔相对,上下对应相对\" 的规律:数字 \"2\" 在中间行,与之间隔 1 个面 \"4\" 的是 \"1\",因此 \"2\" 的对面是 \"1\";数字 \"6\" 位于上方的面,与之相对的是下方的 \"5\"。", + "knowledge_points": [ + "正方体的展开图" + ], + "source": "19-20 一年级下·甘肃平凉·期末" + }, + { + "id": "465", + "unit": "认识图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "一个正方形可以分成两个同样的( ),也可以分成两个同样的( )。", + "options": [], + "answer": "三角形;长方形", + "solution": "【分析】分割正方形的两种常见方式:沿对角线分割可分成两个完全相同的三角形;沿对边中点连线分割可分成两个完全相同的长方形.\n【详解】一个正方形可以分成两个同样的三角形,也可以分成两个同样的长方形。故答案为:三角形;长方形", + "knowledge_points": [ + "平面图形的分割" + ], + "source": "18-19 一年级下·甘肃武威·期末" + }, + { + "id": "466", + "unit": "认识图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "红领巾是( )形,至少用( )个完全一样的三角形可以拼成一个平行四边形。", + "options": [], + "answer": "三角;2", + "solution": "【分析】红领巾是三角形;用2个完全一样的三角形将相等的边拼接,即可拼成一个平行四边形.\n【详解】红领巾是三角形,至少用2个完全一样的三角形可以拼成一个平行四边形。故答案为:三角;2", + "knowledge_points": [ + "长方形,正方形,三角形和圆的初步认识", + "平面图形的拼接" + ], + "source": "18-19 一年级下·甘肃庆阳·期末" + }, + { + "id": "467", + "unit": "认识图形", + "question_type": "填空题", + "difficulty": 0.4, + "question": "用![](images/2025-12-17%20182430.jpg)做成一个正方体,数字\"4\"的对面是数字( ),数字\"3\"的对面是数字( )。", + "options": [], + "answer": "6;1", + "solution": "【分析】这是正方体的 \"1-4-1\" 型展开图(左侧 1 个面,中间一行 4 个面,右侧无额外面),相对面规律为 \"中间间隔相对,上下对应相对\":数字 \"4\" 在中间行,与之间隔 1 个面 \"5\" 的是 \"6\",因此 \"4\" 的对面是 \"6\";数字 \"3\" 位于下方的面,与之相对的是上方的 \"1\"。", + "knowledge_points": [ + "正方体的展开图" + ], + "source": "19-20一年级下·甘肃庆阳·期末" + }, + { + "id": "468", + "unit": "认识图形", + "question_type": "填空题", + "difficulty": 0.4, + "question": "下图中有( )个三角形.\n\n![](images/e3670ee6a708ad8755f1de732433951182d53be5323f2e2d95cd934a620d0f94.jpg)", + "options": [], + "answer": "3", + "solution": "【分析】数三角形时,可按 \"单个 + 组合\" 的顺序统计:图中有 2 个小三角形;这 2 个小三角形还能组合成 1 个大三角形;总计:2+1=3个。", + "knowledge_points": [ + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "17-18 一年级下·广西河池·期中" + }, + { + "id": "469", + "unit": "认识图形", + "question_type": "填空题", + "difficulty": 0.4, + "question": "下图中有( )个三角形.\n\n![](images/e3670ee6a708ad8755f1de732433951182d53be5323f2e2d95cd934a620d0f94.jpg)", + "options": [], + "answer": "3", + "solution": "【分析】数三角形时,可按 \"单个 + 组合\" 的顺序统计:图中有 2 个小三角形;这 2 个小三角形还能组合成 1 个大三角形;总计:2+1=3个。", + "knowledge_points": [ + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "17-18 一年级下·广西河池·期中" + }, + { + "id": "470", + "unit": "认识图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "看图填空.\n\n![](images/cf94153852cc82b322c501d7dcc9ed962e4ff88aa144560957ba1f36fa119296.jpg)\n\n图中有( )个长方形,有( )个三角形,有( )个平行四边形。", + "options": [], + "answer": "1;4;1", + "solution": "【分析】按图形类型分类统计:长方形:图中间有1个;三角形:上下左右各有1个,共4个;平行四边形:整个外框是1个.\n【详解】图中有1个长方形,4个三角形,1个平行四边形。故答案为:1;4;1", + "knowledge_points": [ + "长方形,正方形,三角形和圆的初步认识", + "平行四边形的初步认识" + ], + "source": "17-18 一年级下·江西赣州·期末" + }, + { + "id": "471", + "unit": "认识图形", + "question_type": "填空题", + "difficulty": 0.4, + "question": "把下图形折成一个正方体,其中数字4的对面是数字( ).\n\n![](images/c44dff209afe3b04d328da16fc99ea4c94e8856298d1eedd24f88220c4e52fe4.jpg)", + "options": [], + "answer": "1", + "solution": "【分析】这是正方体的\"1-4-1\"型展开图(上下各1个面,中间一行4个面),相对面遵循\"上下对应相对\"的规律:数字\"4\"位于上方的面,与之相对的是下方的\"1\".\n【详解】数字4的对面是1。故答案为:1", + "knowledge_points": [ + "正方体的展开图" + ], + "source": "18-19一年级下·广西南宁·期末" + }, + { + "id": "472", + "unit": "认识图形", + "question_type": "填空题", + "difficulty": 0.4, + "question": "![](images/6dc5316511014fb1f7cc17c1455a7d031e03565225df78af773352a38b95c5d4.jpg)\n\n![](images/9095b532141feaba859e7286b68fd2f9d56b593d1d7eb66f879f8257d57d6349.jpg)\n\n有( )个三角形 有( )个长方形", + "options": [], + "answer": "3;10", + "solution": "【分析】三角形计数按 \"单个 + 组合\" 统计:单个小三角形有 2 个;2 个小三角形组合成 1 个大三角形;总计:2+1=3个。长方形计数按 \"不同大小\" 分层统计(2 行 3 列的小长方形组合):1 个小长方形:6 个;2 个小长方形组合(横向 / 纵向):横向 2 个一组有 2 组,纵向 2 个一组有 3 组,共2+3=5个;3 个小长方形组合(横向):2 个;4 个小长方形组合(2×2):2 个;6 个小长方形组合(2×3):1 个;总计:6+5+2+2+1=10个。", + "knowledge_points": [ + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "18-19 一年级下·江西赣州·期末" + }, + { + "id": "473", + "unit": "认识图形", + "question_type": "填空题", + "difficulty": 0.4, + "question": "下图中缺了( )块砖\n\n![](images/e9befc0d3724d4e1f09b5c80d4cb768bff7bc9e2ee1f87ebfbd2a95e82c1522f.jpg)", + "options": [], + "answer": "9", + "solution": "【分析】补墙问题按 \"每行缺砖数相加\" 计算(观察砖的错位排列规律,每行砖数一致): 第 1 行缺 2 块;第 2 行缺 3 块;第 3 行缺 2 块;第 4 行缺 2 块;总计:2+3+2+2=9块。", + "knowledge_points": [ + "平面图形的分割" + ], + "source": "20-21 一年级下·福建福州·期中" + }, + { + "id": "474", + "unit": "认识图形", + "question_type": "填空题", + "difficulty": 0.65, + "question": "用![](images/218dce14db91b2cfe1a2d02322345bb2cbcc219d33f6b7c70d5f5f05db6f1f15.jpg)做成一个正方体,数字6的对面是数字( )。", + "options": [], + "answer": "1", + "solution": "【分析】这是正方体的 \"1-4-1\" 型展开图(上下各 1 个面,中间一行 4 个面),相对面遵循 \"上下对应相对\" 的规律:数字 \"6\" 位于上方的面,与之相对的是下方的 \"1\"。", + "knowledge_points": [ + "正方体的展开图" + ], + "source": "19-20 一年级下·江西赣州·期末" + }, + { + "id": "475", + "unit": "认识图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "用同样长的小棒摆图形,摆一个三角形至少要( )根小棒;摆一个长方形至少要( )根小棒。", + "options": [], + "answer": "3;4", + "solution": "【分析】摆三角形的小棒数量:三角形由 3 条线段围成,因此至少需要 3 根同样长的小棒(每根对应一条边);摆长方形的小棒数量:长方形有 4 条边(对边相等),用同样长的小棒摆时,至少需要 4 根(2 根为长,2 根为宽)。", + "knowledge_points": [ + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "12-13一年级下·天津宝坻·期中" + }, + { + "id": "476", + "unit": "认识图形", + "question_type": "填空题", + "difficulty": 0.4, + "question": "![](images/8e087c1a82c3e08fb14118dadd74d231708462587af2b862010699152940af76.jpg)将左图做成一个正方体,数字\"3\"对面的数字是( )。我还知道数字( )对面的数字是( )。", + "options": [], + "answer": "1;5;6", + "solution": "【分析】这是正方体的 \"1-4-1\" 型展开图(上下各 1 个面,中间一行 4 个面),相对面遵循 \"上下对应相对,中间间隔相对\" 的规律:数字 \"3\" 在中间行,其上下对应的面是 \"1\",因此 \"3\" 的对面是 \"1\";中间行的 \"5\" 和 \"6\" 间隔排列,因此 \"5\" 的对面是 \"6\"(同理 \"2\" 的对面是 \"4\")。", + "knowledge_points": [ + "正方体的展开图" + ], + "source": "20-21 一年级下·福建福州·期中" + }, + { + "id": "477", + "unit": "认识图形", + "question_type": "填空题", + "difficulty": 0.4, + "question": "用 ![](images/083be00448f9ba5fb87a5a40876126055e53d810322707e6d1754ce6e6f86b57.jpg) 折一个正方体,\"2\"的对面是( ),\"5\"的对面是( )。", + "options": [], + "answer": "4;6", + "solution": "【分析】这是正方体的 \"1-4-1\" 型展开图(上下各 1 个面,中间一行 4 个面),遵循相对面规律:数字 \"2\" 在中间行,与之间隔 1 个面 \"3\" 的是 \"4\",因此 \"2\" 的对面是 \"4\";数字 \"5\" 位于上方的面,与之相对的是下方的 \"6\"。", + "knowledge_points": [ + "从不同位置观察单个物体", + "正方体的展开图" + ], + "source": "17-18一年级下·云南德宏·期末" + }, + { + "id": "478", + "unit": "认识图形", + "question_type": "填空题", + "difficulty": 0.65, + "question": "将一张正方形纸先对折,然后按照折痕剪开,会剪成两个相同的( )或( )。", + "options": [], + "answer": "长方形;三角形", + "solution": "【分析】沿对边中点连线对折剪开,得到两个相同的长方形;沿对角线对折剪开,得到两个相同的三角形.\n【详解】会剪成两个相同的长方形或三角形。故答案为:长方形;三角形", + "knowledge_points": [ + "长方形,正方形,三角形和圆的初步认识", + "平面图形的分割" + ], + "source": "20-21 一年级下·河北沧州·阶段练习" + }, + { + "id": "479", + "unit": "认识图形", + "question_type": "填空题", + "difficulty": 0.65, + "question": "用![](images/47c7c8350a24b5facfabc207ac763f2a2ec522ae379b971a3bfabeb0fa1e8bd9.jpg)可以拼成一个正方体,与\"3\"相对的数是( )。", + "options": [], + "answer": "4", + "solution": "【分析】这是正方体的 \"1-4-1\" 型展开图(上下各 1 个面,中间一行 4 个面),相对面遵循 \"中间间隔相对\" 的规律:数字 \"3\" 在中间行,与之间隔 1 个面 \"2\" 的是 \"4\",因此 \"3\" 的对面是 \"4\"。", + "knowledge_points": [ + "正方体的展开图" + ], + "source": "17-18 一年级下·云南昆明·期末" + }, + { + "id": "480", + "unit": "认识图形", + "question_type": "填空题", + "difficulty": 0.4, + "question": "用![](images/ac6e5abffe94a0b1968181adcf05a7d0bfcea0ffac2d863f95f16a8da9dac23d.jpg)做成一个正方体,数字\"3\"的对面是数字( )。", + "options": [], + "answer": "5", + "solution": "【分析】这是正方体的 \"1-4-1\" 型展开图(上下各 1 个面,中间一行 4 个面),相对面遵循 \"中间间隔相对\" 的规律:数字 \"3\" 在中间行,与之间隔 1 个面 \"4\" 的是 \"5\",因此 \"3\" 的对面是 \"5\"。", + "knowledge_points": [ + "正方体的展开图" + ], + "source": "19-20 一年级下·云南玉溪·期末" + }, + { + "id": "481", + "unit": "认识图形", + "question_type": "填空题", + "difficulty": 0.65, + "question": "折一折,用![](images/5407af95c52c4dbea3c0cdafd53644db04033208fa9a049d79d5b8d2f6ebaaac.jpg)做一个正方体,\"4\"的对面是( )。", + "options": [], + "answer": "5", + "solution": "【分析】这是正方体的 \"1-4-1\" 型展开图(上下各 1 个面,中间一行 4 个面),相对面遵循 \"上下对应相对\" 的规律:数字 \"4\" 位于上方的面,与之相对的是下方的 \"5\",因此 \"4\" 的对面是 \"5\"。", + "knowledge_points": [ + "正方体的展开图" + ], + "source": "18-19一年级下·云南·期末" + }, + { + "id": "482", + "unit": "认识图形", + "question_type": "填空题", + "difficulty": 0.65, + "question": "下图是由( )个小三角形拼成的。一个正方形可以折成 2 个完全一样的长方形或( ).\n\n![](images/16f921629df44d2d8a499ad3259c8fd767c5aaea35093eb7dc54a2773bc6a0a9.jpg)", + "options": [], + "answer": "5;三角形", + "solution": "【分析】小三角形数量:按 \"单个 + 组合\" 统计:图中有 4 个小三角形,加上由这 4 个小三角形组成的 1 个大三角形,总计4+1=5个。 正方形的折叠分割:正方形沿对角线对折剪开,可得到 2 个完全一样的三角形,因此除了长方形,还可以折成三角形。", + "knowledge_points": [ + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "17-18 一年级下·云南临沧·期中" + }, + { + "id": "483", + "unit": "认识图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "七巧板是我国古代的一种拼板玩具,由( )块板组成。有1块正方形,1块平行四边形和( )块三角形组成。", + "options": [], + "answer": "7;5", + "solution": "【分析】七巧板的组成是固定的:总块数为 7 块;其中包含 1 块正方形,1 块平行四边形,剩下的7-1-1=5块是三角形。", + "knowledge_points": [ + "长方形,正方形,三角形和圆的初步认识", + "用七巧板拼图形" + ], + "source": "17-18一年级下·云南临沧·期中" + }, + { + "id": "484", + "unit": "认识图形", + "question_type": "填空题", + "difficulty": 0.85, + "question": "下图是由( )个小三角形拼成的.\n\n![](images/f12d5c8606b34b0d40489ff718cae61c33a47221a690070550ea30bf45c408e1.jpg)", + "options": [], + "answer": "4", + "solution": "【分析】三角形是由 3 条直直的边围成的封闭图形。由此数出图中小三角形的数量即可。\n\n【详解】\n\n![](images/91c281a92b331ccf4be83169e2435fcd19fa27397127bce6871bdcddad7bda09.jpg)\n\n![](images/bbd4875ccf7783a3869c337c4360479f8357ca8686d19fa9a0814cf2574ef4f7.jpg)\n\n![](images/ce8a939b7932c0083de20ab0e450622d9976967913621e831e19402bb1fa05dc.jpg)\n\n![](images/deb9a2adb5d61f52f1e849c99f57e9cf70c36988ca435355aba8fdeaff9f0aaf.jpg)\n\n图形是由 4 个小三角形拼成的。", + "knowledge_points": [ + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "20-21 一年级下·全国·单元测试" + }, + { + "id": "485", + "unit": "认识图形", + "question_type": "填空题", + "difficulty": 0.4, + "question": "用下图的纸片做一个正方体,数字\"1\"的对面是数字( ),数字\"2\"的对面是数字( ),数字\"3\"的对面是数字( ).\n\n![](images/5f0b3ddccb04c5153a0c352d98fecb9e8836754daca6869793da62adf232df23.jpg)", + "options": [], + "answer": "5;6;4", + "solution": "【分析】想象以\"3\"为底,\"6\"为正面,则\"1\"为左面,\"5\"为右面,即\"1\"和\"5\"相对,\"4\"为上面,与\"3\"相对,剩下的2个面相对,即\"2\"与\"6\"相对.\n【详解】根据分析可知,数字\"1\"的对面是\"5\",数字\"2\"的对面是\"6\",数字\"3\"的对面是\"4\"。", + "knowledge_points": [ + "正方体的展开图" + ], + "source": "20-21 一年级下·全国·期末" + }, + { + "id": "486", + "unit": "认识图形", + "question_type": "判断题", + "difficulty": 0.85, + "question": "平行四边形也是四边形。( )", + "options": [], + "answer": "√", + "solution": "【分析】四边形的定义是 \"由四条线段围成的封闭图形\",而平行四边形满足 \"有四条边\" 的条件,因此平行四边形属于四边形的一种。", + "knowledge_points": [ + "平行四边形的概念及特点", + "四边形的分类及关系" + ], + "source": "19-20 二年级上·湖南邵阳·期中" + }, + { + "id": "487", + "unit": "认识图形", + "question_type": "判断题", + "difficulty": 0.65, + "question": "一个正方形不能剪成两个相同的三角形。( )", + "options": [], + "answer": "×", + "solution": "【分析】正方形沿对角线剪开,会得到两个完全一样的等腰直角三角形.\n【详解】一个正方形能剪成两个相同的三角形,原题说法错误。故答案为:×", + "knowledge_points": [ + "长方形,正方形,三角形和圆的初步认识", + "平面图形的分割" + ], + "source": "20-21 一年级下·贵州铜仁·期末" + }, + { + "id": "488", + "unit": "认识图形", + "question_type": "判断题", + "difficulty": 0.65, + "question": "用 4 个同样的正方形可以拼成长方形或者正方形。( )", + "options": [], + "answer": "√", + "solution": "【分析】用 4 个同样的正方形拼接时:拼成长方形:将 4 个正方形排成 1 排(1×4 的形式),得到长为 4 个边长,宽为 1 个边长的长方形;拼成正方形:将 4 个正方形排成 2 排 2 列(2×2 的形式),得到边长为 2 个边长的大正方形。", + "knowledge_points": [ + "长方形,正方形,三角形和圆的初步认识", + "平面图形的拼接" + ], + "source": "19-20 一年级下·贵州铜仁·期末" + }, + { + "id": "489", + "unit": "认识图形", + "question_type": "判断题", + "difficulty": 0.85, + "question": "用四根同样长的小棒可以拼成一个正方形。( )", + "options": [], + "answer": "√", + "solution": "【详解】根据正方形的特征,正方形的4条边的长度都相等。4根一样长的小棒可以围成一个正方形。此说法正确。故答案为:√", + "knowledge_points": [ + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "20-21 一年级下·贵州铜仁·期末" + }, + { + "id": "490", + "unit": "认识图形", + "question_type": "判断题", + "difficulty": 0.85, + "question": "用 2 个同样的三角形只能拼成一个大三角形。( )", + "options": [], + "answer": "×", + "solution": "【分析】2 个同样的三角形(比如等腰直角三角形),不仅能拼成大三角形,还能拼成长方形,平行四边形等图形。例如:将两个等腰直角三角形的斜边对在一起,可拼成大三角形;将直角边对在一起,可拼成长方形。", + "knowledge_points": [ + "平面图形的拼接" + ], + "source": "20-21 一年级下·新疆伊犁·期末" + }, + { + "id": "491", + "unit": "认识图形", + "question_type": "判断题", + "difficulty": 0.85, + "question": "圆是平面图形,球是立体图形。( )", + "options": [], + "answer": "√", + "solution": "【分析】圆在同一平面内,是平面图形;球是立体图形.\n【详解】球是立体图形,圆是平面图形,原题说法正确。故答案为:√", + "knowledge_points": [ + "长方形,正方形,三角形和圆的初步认识", + "立体图形的认识" + ], + "source": "19-20一年级下·新疆塔城·期末" + }, + { + "id": "492", + "unit": "认识图形", + "question_type": "判断题", + "difficulty": 0.85, + "question": "两个三角形一定能拼成一个正方形。( )", + "options": [], + "answer": "×", + "solution": "【分析】只有两个完全一样的等腰直角三角形才能拼成正方形.\n【详解】两个完全一样的等腰直角三角形一定能拼成一个正方形,原题说法错误。故答案为:×", + "knowledge_points": [ + "长方形,正方形,三角形和圆的初步认识", + "平面图形的拼接" + ], + "source": "18-19一年级下·甘肃武威·期末" + }, + { + "id": "493", + "unit": "认识图形", + "question_type": "判断题", + "difficulty": 0.85, + "question": "正方形有四条边。( )", + "options": [], + "answer": "√", + "solution": "【分析】正方形的定义是 \"有四条相等的边和四个直角的四边形\",核心特征之一就是 \"四条边\",因此该表述是正确的。", + "knowledge_points": [ + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "18-19 一年级下·甘肃庆阳·期末" + }, + { + "id": "494", + "unit": "认识图形", + "question_type": "判断题", + "difficulty": 0.85, + "question": "一枚 1 元硬币是圆形。( )", + "options": [], + "answer": "√", + "solution": "【分析】从平面图形的角度看,1 元硬币的正面 / 反面轮廓是 \"在一个平面内,到定点的距离等于定长的所有点组成的图形\",符合圆的定义,因此可以说 1 元硬币(的面)是圆形。", + "knowledge_points": [ + "长方形,正方形,三角形和圆的初步认识", + "立体图形的认识" + ], + "source": "20-21 一年级下·广西防城港·期中" + }, + { + "id": "495", + "unit": "认识图形", + "question_type": "判断题", + "difficulty": 0.4, + "question": "用![](images/17acc2cfe7f0e49dc8f7df21ecfce37cf348419a21e63de1ae0781a677845d97.jpg)做成一个正方体,\"1\"的对面是\"4\"。( )", + "options": [], + "answer": "×", + "solution": "【分析】这是正方体的 \"1-4-1\" 型展开图,中间一行的数字遵循 \"间隔相对\" 的规律:数字 \"1\" 在中间行,与它间隔 1 个面(数字 \"2\")的是数字 \"3\",因此 \"1\" 的对面是 \"3\",不是 \"4\"。", + "knowledge_points": [ + "正方体的展开图" + ], + "source": "18-19 一年级下·江西赣州·期末" + }, + { + "id": "496", + "unit": "认识图形", + "question_type": "判断题", + "difficulty": 0.85, + "question": "两个完全相同的 □ 能拼成一个大正方形。( )", + "options": [], + "answer": "×", + "solution": "【分析】两个完全相同的正方形拼接时,只能拼成长方形(排成 1 排,长为 2 个边长,宽为 1 个边长);而拼成大正方形需要至少 4 个完全相同的正方形(排成 2 排 2 列)。", + "knowledge_points": [ + "长方形,正方形,三角形和圆的初步认识", + "平面图形的拼接" + ], + "source": "19-20一年级下·江西吉安·期末" + }, + { + "id": "497", + "unit": "认识图形", + "question_type": "判断题", + "difficulty": 0.85, + "question": "折一折,用![](images/0f6204bb7785fc6112e76a8b024c8b43ada7b4fb5dcd4f6dfa8dab9a88e0e31d.jpg)做一个正方体,\"3\"的对面是\"1\"。( )", + "options": [], + "answer": "×", + "solution": "【详解】这是正方体的 \"1-4-1\" 型展开图,中间一行的数字遵循 \"间隔相对\" 的规律:数字 \"3\" 在中间行,与它间隔 1 个面(数字 \"2\")的是数字 \"4\",因此 \"3\" 的对面是 \"4\",不是 \"1\"。", + "knowledge_points": [ + "正方体的展开图" + ], + "source": "18-19一年级下·天津·期末" + }, + { + "id": "498", + "unit": "认识图形", + "question_type": "判断题", + "difficulty": 0.65, + "question": "折一折,用![](images/8d24c7bb487e72b803bb869d411d2f5ca3b8c3541b7923d5a2eddb963bdb4360.jpg)做一个正方体,\"3\"的对面是 4. ( )", + "options": [], + "answer": "√", + "solution": "【分析】这是正方体的 \"1-4-1\" 型展开图,中间一行的数字遵循 \"间隔相对\" 的规律:数字 \"3\" 在中间行,与它间隔 1 个面(数字 \"2\")的是数字 \"4\",因此 \"3\" 的对面是 \"4\"。", + "knowledge_points": [ + "正方体的展开图" + ], + "source": "18-19一年级下·云南曲靖·期中" + }, + { + "id": "499", + "unit": "认识图形", + "question_type": "判断题", + "difficulty": 0.65, + "question": "任意一个长方形都能分成两个完全一样的三角形。( )", + "options": [], + "answer": "√", + "solution": "【分析】长方形的对角线可以将其分成两个三角形,由于长方形的对边相等,四个角都是直角,对角线作为公共边,这两个三角形的三条边和三个角都分别相等,因此是完全一样的三角形。", + "knowledge_points": [ + "长方形,正方形,三角形和圆的初步认识", + "平面图形的分割" + ], + "source": "17-18 一年级下·甘肃金昌·期中" + }, + { + "id": "500", + "unit": "认识图形", + "question_type": "连线题", + "difficulty": 0.65, + "question": "下面哪两个图形可以拼成一个长方形。连一连.\n\n![](images/6fdff6dd66ebacf32db00c4c2ab3d6cf6fa82521348ff3390bed270c393ef977.jpg)\n\n![](images/dd82db9474c15cdfadd0a8ff5651a222a56d19c7e890d3f2fb33f5a9d02fb498.jpg)\n\n![](images/0458edd7d31c062baf9f54676f476891aadf6b0b4a4c7b01a17d6f1656816ffb.jpg)\n\n![](images/be6fcd01fb1ce07ffb342b11210b8fb9363c01ce601863f61bf6fb4ed1ceaae7.jpg)\n\n![](images/2172b39157120b1d37ef02ef549de3820f8656397b06a8409e41ecf7b9d4512b.jpg)\n\n![](images/ba45f5c1147b9b59e89262b8514bada2da31aa39fa20db1939243a21cb86527a.jpg)\n\n![](images/b56b8ea51535d32c067b5b5d36a8610c4c8aefd045eb9697e9f42b7887ed4f49.jpg)\n\n![](images/8c936ec0f1bdc2791160ecf0b89d7e114bec3accbbc03fcb0ad64085041814d7.jpg)", + "options": [], + "answer": "见详解", + "solution": "【分析】观察每组两个图形,将能拼成长方形的两个图形连起来.\n【详解】![](images/2692aea314887a274814f83e12c930d896a22fd8bd23a5d1ba99ab56dc5a3965.jpg)", + "knowledge_points": [ + "平面图形的拼接" + ], + "source": "20-21一年级下·全国·期末" + } +] \ No newline at end of file diff --git "a/\344\270\200\345\271\264\347\272\247\351\242\230\351\233\206/\344\270\200\345\271\264\347\272\247\344\270\213/\344\270\200\345\271\264\347\272\247\344\270\213\347\254\254\344\270\203\345\215\225\345\205\203\346\211\276\350\247\204\345\276\213.json" "b/\344\270\200\345\271\264\347\272\247\351\242\230\351\233\206/\344\270\200\345\271\264\347\272\247\344\270\213/\344\270\200\345\271\264\347\272\247\344\270\213\347\254\254\344\270\203\345\215\225\345\205\203\346\211\276\350\247\204\345\276\213.json" new file mode 100644 index 0000000000000000000000000000000000000000..a19f50bb8614e3724e9cacc2cdf2f5d77c1b6799 --- /dev/null +++ "b/\344\270\200\345\271\264\347\272\247\351\242\230\351\233\206/\344\270\200\345\271\264\347\272\247\344\270\213/\344\270\200\345\271\264\347\272\247\344\270\213\347\254\254\344\270\203\345\215\225\345\205\203\346\211\276\350\247\204\345\276\213.json" @@ -0,0 +1,4634 @@ +[ + { + "id": "1", + "unit": "找规律", + "question_type": "选择题", + "difficulty": 0.65, + "question": "丽丽穿一串手链送给妈妈,她按照一定的规律,从左往右已经穿好了一部分(如图)。你知道接下去穿哪一种颜色的珠子吗。()\n\n![](images/Pasted image 20251208145132.png)", + "options": [ + "A. ![](images/Pasted image 20251208145153.png)", + "B. ![](images/Pasted image 20251208145219.png)", + "C. ![](images/Pasted image 20251208145226.png)" + ], + "answer": "B", + "solution": "【分析】\n红珠子紫珠子蓝珠子,这三颗珠子依次循环排列;据此解决此题。\n\n【详解】由题意分析得:\n\n丽丽穿一串手链送给妈妈,她按照一定的规律,从左往右已经穿好了一部分(如图)。接下去应穿紫色的珠子.\n\n![](images/Pasted image 20251208145330.png)\n\n故答案为: B", + "knowledge_points": [ + "图形的变化规律" + ], + "source": "24-25 一年级上·全国·单元测试" + }, + { + "id": "2", + "unit": "找规律", + "question_type": "选择题", + "difficulty": 0.85, + "question": "按规律,我知道下一个图形是: ( ).\n\n![](images/Pasted image 20251208201851.png)", + "options": [ + "A. △", + "B. ○" + ], + "answer": "A", + "solution": "【分析】根据图片可知:该组规律为: △ ○ 为一组重复出现的,则 ○ 下面是 △ 。\n\n【详解】由分析可得:按规律,我知道下一个图形是: △ 。故答案为:A", + "knowledge_points": [ + "图形的变化规律" + ], + "source": "24-25 一年级上·河南南阳·期中" + }, + { + "id": "3", + "unit": "找规律", + "question_type": "选择题", + "difficulty": 0.85, + "question": "根据下面的游戏规则,想一想:表格中的 \"。 \" 处应填 ( ).\n\n![](images/Pasted image 20251208201922.png)\n
31
2
2。
", + "options": [ + "A. 1", + "B. 2", + "C. 3" + ], + "answer": "C", + "solution": "【分析】根据题意,从出现数字较多的地方开始推算。也就是先推算出第三行第 1 格应填的数字,进而推算出 \"。\"处应填的数字。\n\n【详解】第三行第1格所在的行,列出现了2,3,则第三\n\n行第 1 格只能是 1 。此时 \"。 \" 所在的行出现了 1 , 2,则 \"。 \" 处应填 3 .\n\n故答案为: C", + "knowledge_points": [ + "数表中的规律", + "填数游戏" + ], + "source": "23-24 一年级下·福建福州·期末" + }, + { + "id": "4", + "unit": "找规律", + "question_type": "选择题", + "difficulty": 0.65, + "question": "下图中遮住了 9 颗珠子,有 ( ) 颗黑珠子.\n\n![](images/Pasted image 20251208203558.png)", + "options": [ + "A. 5", + "B. 6", + "C. 7" + ], + "answer": "C", + "solution": "【分析】\n\n这组珠子按照 ![](images/Pasted image 20251208203635.png) 为一组重复排列,前边排列了完整的 3 组,遮住的 9 颗应该为第 4 组的 5 颗和第 5 组的前 4 颗,由此数出黑色珠子的数量即可。\n\n【详解】\n\n由分析可知,遮住的 9 颗珠子是 ![](images/Pasted image 20251208203649.png) ,有 7 颗黑珠子。故答案为: C", + "knowledge_points": [ + "图形的变化规律" + ], + "source": "23-24 一年级下·河南南阳·期末" + }, + { + "id": "5", + "unit": "找规律", + "question_type": "选择题", + "difficulty": 0.65, + "question": "如图是从百数表中取出的一部分,被 \"熊猫头\" 图挡住的数是 ( ).\n\n![](images/Pasted image 20251208203713.png)", + "options": [ + "A. 85", + "B. 67", + "C. 65" + ], + "answer": "C", + "solution": "【分析】在百数表里,相邻的两个数,左边数比右边数小 1,上边数比下边数小 10;据此解答即可。\n\n【详解】 76 - 10 - 1=66-1=65 所以被\"熊猫头\"图挡住的数是 65 。 故答案为: C", + "knowledge_points": [ + "百数表", + "100以内数的连减运算" + ], + "source": "23-24 一年级下·湖北黄石·期末" + }, + { + "id": "6", + "unit": "找规律", + "question_type": "选择题", + "difficulty": 0.85, + "question": "下图方框中遮住了 8 颗珠子,有 ( ) 颗是黑色的.\n\n![](images/Pasted image 20251208203805.png)", + "options": [ + "A. 6", + "B. 5", + "C. 2" + ], + "answer": "B", + "solution": "【分析】根据题意可知:该组规律为 2 颗白珠子,3 颗黑珠子循环重复出现的,则遮住的 8 颗珠子为:2 颗黑珠子,2颗白珠子 3 颗黑珠子,1 颗白珠子。然后把黑珠子相加求出一共有的黑珠子数。\n\n【详解】由分析可得: 2 + 3 = 5 (颗) 所以有 5 颗是黑色的。 故答案为: B", + "knowledge_points": [ + "图形的变化规律" + ], + "source": "23-24 一年级下·福建莆田·期末" + }, + { + "id": "7", + "unit": "找规律", + "question_type": "选择题", + "difficulty": 0.65, + "question": "根据下面算式的规律,第 4 个算式的得数应该是 ( ).\n\n1 + 2 + 3 = 6, 2 + 3 + 4 = 9, 3 + 4 + 5 = 12", + "options": [ + "A. 14", + "B. 15", + "C. 16", + "D. 17" + ], + "answer": "B", + "solution": "【分析】由题意可知,每个算式都是从小到大连续的 3 个数,后一个算式的前两个数是前一个算式的后两个数,由此写出算式再计算出结果即可。\n\n【详解】 1 + 2 + 3 = 6, 2 + 3 + 4 = 9, 3 + 4 + 5 = 12, 4 + 5 + 6 = 15。 第 4 个算式的得数应该是 15。故答案为: B", + "knowledge_points": [ + "算式的规律(整数)" + ], + "source": "23-24 一年级下·福建漳州·期末" + }, + { + "id": "8", + "unit": "找规律", + "question_type": "选择题", + "difficulty": 0.85, + "question": "□ □△〇 □ □△〇, 接下去画的是 ( )。", + "options": [ + "A. □", + "B. △", + "C. ○" + ], + "answer": "A", + "solution": "【分析】这组图形按照 □ □ △ ○ 为一组重复排列,已经有完整的两组,下一个图形是第三组的第一个,是 □ 。\n\n【详解】由分析可知, □ □ △ ○ □ □ △ ○ , 接下去画的是 □ 。故答案为:A", + "knowledge_points": [ + "图形的变化规律" + ], + "source": "23-24 一年级下·河南商丘·期末" + }, + { + "id": "9", + "unit": "找规律", + "question_type": "选择题", + "difficulty": 0.85, + "question": "△ □ ☆ △ □ ☆ △ □( ), 括号里应摆的图形是 ( )。", + "options": [ + "A. △", + "B. ☆", + "C. □" + ], + "answer": "B", + "solution": "【分析】题中图形按照 △ □ ☆ 为一组重复排列,第 1, 2 组是完整的,缺少的是第 3 组的第 3 个图形,由此解答。\n\n【详解】 △ □ ☆ △ □ ☆ △ □ ( ), 横线上应摆的图形是 ☆ 。故答案为: B", + "knowledge_points": [ + "图形的变化规律" + ], + "source": "23-24 一年级下·河南南阳·期末" + }, + { + "id": "10", + "unit": "找规律", + "question_type": "选择题", + "difficulty": 0.85, + "question": "△ △ □ ○ △ △ □ ○ △ △ □ □ △ △ □ ○ , 缺少的图形是 ( )。", + "options": [ + "A. △", + "B. □", + "C. ○" + ], + "answer": "C", + "solution": "【分析】题中图形按照 △ △ □ ○ 的顺序重复排列,第1, 2, 4 组是完整的,缺少的是第 3 组的第 4 个图形,由此解答。\n\n【详解】由分析可知,每组的第 4 个图形是 ○ , 也就是缺少的图形是 ○ 。故答案为: C", + "knowledge_points": [ + "图形的变化规律" + ], + "source": "23-24 一年级下·湖南湘西·期末" + }, + { + "id": "11", + "unit": "找规律", + "question_type": "选择题", + "difficulty": 0.65, + "question": "一共有 12 个男生,老师让相邻两个男生之间站一个女生,一共可以站 ( ) 个女生。", + "options": [ + "A. 12", + "B. 11", + "C. 13" + ], + "answer": "B", + "solution": "【分析】有 12 个男生,中间有(12-1)个间隔,因此一共\n\n可以站进(12- 1)个女生。据此解答即可。\n\n【详解】 12 - 1 = 11 (个)\n\n所以 12 个男生有 11 个间隔,一共可以站 11 个女生.\n\n故答案为: B", + "knowledge_points": [ + "不退位减法(20以内)", + "植树问题(两端都栽)", + "相邻的数" + ], + "source": "23-24 一年级下·山东临沂·期末" + }, + { + "id": "12", + "unit": "找规律", + "question_type": "选择题", + "difficulty": 0.85, + "question": "如图\n\n![](images/Pasted image 20251209184406.png)\n\n所示,第14面小旗是( )色。", + "options": [ + "A. 红", + "B. 黄", + "C. 蓝" + ], + "answer": "B", + "solution": "【分析】观察图形可知,这组图形是 3 种颜色小旗一个循环周期,分别按照:红,黄,蓝的顺序依次循环排列,计算\n\n出第 14 个图形是第几个周期的第几个即可。\n\n【详解】 14 - 3 = 11(面) 11 - 3 = 8 (面) 8 - 3 = 5 (面) 5 - 3 = 2 (面) 所以第 14 面小旗是第 5 个周期第 2 面,是黄色。故答案为: B", + "knowledge_points": [ + "间隔问题", + "不退位减法(20以内)", + "十几减 5 ~ 2 的退位减法" + ], + "source": "23-24 一年级下·湖南益阳·期末" + }, + { + "id": "13", + "unit": "找规律", + "question_type": "选择题", + "difficulty": 0.65, + "question": "下面的箱子中○ 有()个.\n\n![](images/Pasted image 20251209220000.png)", + "options": [ + "A. 1", + "B. 2", + "C. 3" + ], + "answer": "C", + "solution": "【分析】规律:1个白色圆,1个黑色圆,2个白色圆,1个黑色圆,3个白色圆,1个黑色圆,4个白色圆,1个黑色圆,5 个白色圆, 1 个黑色圆, 6 个白色圆, 1 个黑色圆;据此解决。\n\n【详解】由题意分析得:![](images/Pasted image 20251209220418.png)\n\n箱子中 ○ 有 3 个。故答案为: C", + "knowledge_points": [ + "图形的变化规律" + ], + "source": "23-24 一年级下·陕西安康·期末" + }, + { + "id": "14", + "unit": "找规律", + "question_type": "选择题", + "difficulty": 0.65, + "question": "在▲○□☆◆▲○□☆◆▲○□☆◆中,第 17 个图形是 ( )。", + "options": [ + "A. ▲", + "B. ○", + "C. □" + ], + "answer": "B", + "solution": "【分析】根据题意分析,图形中是按照 ▲○ □ ☆ ◆ 规律依次排列下去的, 5 个为一组循环,按照规律数出第 17 个图形的形状即可。\n\n【详解】▲○ □ ☆◆ ▲○ □☆◆ ▲○ □☆◆ ▲○ 所以第 17 个图形形状是 ○ 。故答案为: B", + "knowledge_points": [ + "间隔问题" + ], + "source": "23-24一年级下·江西吉安·期末" + }, + { + "id": "15", + "unit": "找规律", + "question_type": "选择题", + "difficulty": 0.85, + "question": "找规律填图:□□□□*□□□**□□***()。", + "options": [ + "A. □□***", + "B. □□□**", + "C. □****" + ], + "answer": "C", + "solution": "【分析】观察这组图形,可知 □ 的个数依次减 1 个, * 的个数依次加 1 个,据此选择即可。\n\n【详解】由题意分析得:□□□□*□□□**□□***(□****) 故答案为: C", + "knowledge_points": [ + "图形的变化规律" + ], + "source": "23-24一年级下·贵州黔西·期末" + }, + { + "id": "16", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.65, + "question": "照样子,找规律填一填.\n\n15,25,( ),( ),55。", + "options": [], + "answer": "35;45", + "solution": "【分析】观察这组数可以发现,后一个数会比前一个数大10。根据此规律写出题目所求的数即可解答。\n\n【详解】根据分析可得:15,25,35,45,55所以,括号内分别应填写35,45。", + "knowledge_points": [ + "整数排列的规律" + ], + "source": "24-25一年级下·河北唐山·期末" + }, + { + "id": "17", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.85, + "question": "典典画了 8 个 ○,想在相邻两个 ○ 之间各画一个 △ , 一共可以画( )个 △ 。", + "options": [], + "answer": "7", + "solution": "【分析】两个 ○ 会有一个间隔,一个间隔可以画一个 △ 。根据 ○ 总数 -1 = 间隔数,算出答案即可求解。\n\n【详解】 8 - 1 = 7 有 7 个间隔,可以画 7 个 △ 。 所以,典典画了 8 个〇,想在相邻两个〇之间各画一个 △ ,一共可以画 7 个 △ 。", + "knowledge_points": [ + "图形的变化规律" + ], + "source": "24-25 一年级下·湖北省直辖县级单位·期中" + }, + { + "id": "18", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.65, + "question": "找规律填数.\n\n(1)2, 7, 4, 9, 6, 11, ( ), 17,( ) .\n(2)1,1,2,3,5,8,( ),21.\n(3)△△□○△△□○△( )。", + "options": [], + "answer": "13;14;△", + "solution": "【分析】(1)双数项是双数,单数项是单数。单数项和双数项都依次加2,单数项后面一项比它少3,双数项后面一项比它多5;(2) 从第三项起,每一项都等于前两项之和;(3) 每 △ △ □ ○ 为一个循环。\n\n【详解】 (1) 11 + 2 = 13, 17 - 3 = 14, 2, 7, 4, 9, 6, 11, 13, 17, 14;(2) 5 + 8 = 13, 1, 1, 2, 3, 5, 8, 13, 21;(3) △ △ □ ○ △ △ □ ○ △ △", + "knowledge_points": [ + "整数排列的规律", + "图形的变化规律" + ], + "source": "24-25一年级上·浙江温州·期末" + }, + { + "id": "19", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.65, + "question": "找规律填空.\n(1)5, 10, 20, 40, ( ), 160.\n(2) □ ○ △, ○ △ □, △ □ ○, ( ) 。", + "options": [], + "answer": "80;□ ○ △", + "solution": "【分析】(1)观察发现 5×2=10,10×2=20,20×2=40,前一个数乘 2 得到下一个数,所以括号里的数为 40×2 = 80。(2) 观察发现第 1 个排列为正方形,圆,三角形,第 2 个排列为三角形,正方形,圆,第 3 个排列为圆,三角形,正方形,按正方形,圆,三角形的顺序,在前一个的基础上依次向后挪一个位置排列,所以第 4 个排列为正方形,圆,三角形;据此解答。\n\n【详解】根据分析可知:(1) 5, 10, 20, 40, 80, 160。 (2) □○ △ , △□ ○ , ○ △ □ , □ ○ △ 。", + "knowledge_points": [ + "整数排列的规律", + "图形的变化规律" + ], + "source": "23-24 三年级上·重庆云阳·期末" + }, + { + "id": "20", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.65, + "question": "找规律,填一填.\n\n(1)83, 75, 67, ( ), ( ).\n(2)15,20,25,( ),( )。", + "options": [], + "answer": "59;51 30;35", + "solution": "【分析】这组数依次变小,每后一个数比前一个数小 8,依次减 8 即可得出答案;这组数依次变大,每后一个数比前一个数大 5,依次加 5 即可得出答案。\n\n【详解】 (1) 67 - 8 = 59;59 - 8 = 5183, 75, 67, 59, 51。 (2) 25 + 5 = 30;30 + 5 = 3515,20,25,30,35。", + "knowledge_points": [ + "一位数与两位数的进位加法", + "一位数与两位数的退位减法", + "整数排列的规律" + ], + "source": "24-25 二年级上·河南驻马店·期中" + }, + { + "id": "21", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.65, + "question": "按规律填数.\n\n(1)2,5,8,11,( ),( )。 (2)36,32,28,( ),( )。", + "options": [], + "answer": "14;17 24;20", + "solution": "【分析】(1)观察已知数据可知规律,后面的数比前面相邻的数多3;(2) 观察已知数据可知规律,后面的数比前面相邻的数少 4。据此填空。\n\n【详解】 (1) 2 + 3 = 55+3=88+3=1111+3=1414+3=172,5,8,11,14,17.\n\n(2)36-4=3232-4=2828-4=2424-4=2036,32,28,24,20。", + "knowledge_points": [ + "不进位加法(20以内)", + "两位数与一位数的减法(不退位)", + "一位数与两位数的退位减法", + "整数排列的规律" + ], + "source": "24-25 二年级上·河南商丘·期中" + }, + { + "id": "22", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.65, + "question": "找规律: 82, ( ),66,58,50。", + "options": [], + "answer": "74", + "solution": "【分析】观察已知数据可得, 66 - 58 = 8, 58 - 50 = 8,那么这组数依次变小,每后一个数比前一个数小 8,那么用 82 减去 8 即可;据此解答。\n\n【详解】根据分析:82 - 8 = 74 所以找规律:82,74,66,58,50。", + "knowledge_points": [ + "两位数与两位数的不退位减法", + "一位数与两位数的退位减法", + "整数排列的规律" + ], + "source": "24-25 二年级上·山东日照·期中" + }, + { + "id": "23", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.65, + "question": "按规律填一填.\n\n15,24,33,( ),( )。", + "options": [], + "answer": "42;51", + "solution": "【分析】右边的数比左边相邻的数大9,据此计算。\n\n【详解】 33 + 9 = 4242 + 9 = 5115, 24, 33, 42, 51。", + "knowledge_points": [ + "一位数与两位数的进位加法", + "整数排列的规律" + ], + "source": "24-25 二年级上·陕西汉中·期中" + }, + { + "id": "24", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.65, + "question": "按规律填一填.\n(1)30, 38, 46, ( ), ( ), 70.\n(2)94, 87, 80, ( ), ( ), ( )。", + "options": [], + "answer": "54;62 73;66;59", + "solution": "【分析】(1)观察已知数据可得,这组数依次变大,每后一个数比前一个数大 8,也就是从 30 开始,八个八个地正着数,依次填写 54,62;(2) 观察已知数据可得,这组数依次变小,每后一个数比前一个数小 7,也就是从 94 开始,七个七个地倒着数,依次填写 73, 66, 59。\n\n【详解】 (1) 30, 38, 46, 54, 62, 70。(2) 94, 87, 80, 73, 66, 59。", + "knowledge_points": [ + "数 100 以内的数", + "整数排列的规律" + ], + "source": "24-25 二年级上·宁夏中卫·期中" + }, + { + "id": "25", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.85, + "question": "找规律填一填:\n\n100,93,86,( ),( )。", + "options": [], + "answer": "79;72", + "solution": "【分析】观察已知数据可得,这组数依次变小,每后一个数比前一个数小 7,也就是从 100 开始,七个七个地倒着数,依次填写 79, 72。\n\n【详解】由分析可得,找规律填一填:100,93,86,79,72。", + "knowledge_points": [ + "数 100 以内的数", + "整数排列的规律" + ], + "source": "24-25 二年级上·湖南娄底·期中" + }, + { + "id": "26", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.65, + "question": "按规律填数.\n(1)95, 84, 73, ( ), ( ), 40, ( ).\n(2)6, 13, 20, ( ), ( ), 41, ( )。", + "options": [], + "answer": "62;51;29 27;34;48", + "solution": "【分析】(1)观察已知数据可得,这组数依次变小,每后一个数比前一个数小 11,也就是从 95 开始,十一十一地倒着数,依次填写 62,51,29;(2) 观察已知数据可得,这组数依次变大,每后一个数比前一个数大 7,也就是从 6 开始,七个七个地正着数,依次填写 27, 34, 48。\n\n【详解】 (1) 95, 84, 73, 62, 51, 40, 29。(2) 6, 13, 20, 27, 34, 41, 48。", + "knowledge_points": [ + "数 100 以内的数", + "整数排列的规律" + ], + "source": "24-25 二年级上·河北·期中" + }, + { + "id": "27", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.85, + "question": "找规律,填一填.\n(1)4, 8, 12, ( ), ( ).\n(2)27, 24, (), 18, ()。", + "options": [], + "answer": "16;20;21;15", + "solution": "【分析】根据题目中给出的数字,4加4等于8,8加4等于12,每个数字之间相差4,依次加4即可得出答案;27减3等于24,24减6等于18,可计算出中间空出来的数字,每个数字之间相差 3,依次减 3 即可得出答案。\n\n【详解】据分析可得: 12 + 4 = 16 , 16 + 4 = 20,所以应该填:4,8,12,16,20\n24 - 3 = 21, 18 - 3 = 15,所以应该填:27,24,21,18,15", + "knowledge_points": [ + "整数排列的规律" + ], + "source": "23-24 二年级上·湖北孝感·期中" + }, + { + "id": "28", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.85, + "question": "按规律填一填:\n27, 24, 21, ( ), ( ), 12。", + "options": [], + "answer": "18;15", + "solution": "【分析】观察已知数据可得,这组数依次变小,每后一个数比前一个数小 3,也就是从 27 开始,三个三个地倒着数,依次填写 18, 15。\n\n【详解】由分析可得,按规律填一填: 27, 24, 21, 18, 15, 12。", + "knowledge_points": [ + "数 100 以内的数", + "整数排列的规律" + ], + "source": "22-23 二年级上·河南南阳·期中" + }, + { + "id": "29", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.65, + "question": "找规律,填一填.\n(1) 11, 18, 25, ( ), 39, ( ), 53.\n(2) 81, 78, 75, ( ), 69, ( ), 63。", + "options": [], + "answer": "32;46;72;66", + "solution": "【分析】(1)观察已知数据可得,这组数依次变大,每后一个数比前一个数大 7,也就是从 11 开始,七个七个地正着数,依次填写 32,46;(2) 观察已知数据可得,这组数依次变小,每后一个数比前一个数小 3,也就是从 81 开始,三个三个地倒着数,依次填写 72, 66。\n\n【详解】由分析可得,(1) 11, 18, 25, 32, 39, 46, 53。 (2) 81, 78, 75, 72, 69, 66, 63。", + "knowledge_points": [ + "数 100 以内的数", + "整数排列的规律" + ], + "source": "23-24 二年级上·山东济宁·期中" + }, + { + "id": "30", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.65, + "question": "按规律填数:\n64, 70, 76, ( ), 88, ( )。", + "options": [], + "answer": "82;94", + "solution": "【分析】观察各个数字的大小,右边的数比左边相邻的数大 6,据此计算。\n\n【详解】 76 + 6 = 8288 + 6 = 9464, 70, 76, 82, 88, 94。", + "knowledge_points": [ + "一位数与两位数的进位加法", + "整数排列的规律" + ], + "source": "23-24 二年级上·河南南阳·期中" + }, + { + "id": "31", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.65, + "question": "按规律,填一填.\n (1)14, 21, 28, ( ), ( ), 49。 (2)73, 68, 63, (), (), 48。", + "options": [], + "answer": "35;42;58;53", + "solution": "【分析】(1)观察这一列数字,后一个数比前一个多7;(2) 观察这一列数字,后一个数比前一个少 5;据此解决。\n\n【详解】(1) 28 + 7 = 35, 35 + 7 = 42,即,14,21,28,35,42,49。(2) 63 - 5 = 58, 58 - 5 = 53,即,73,68,63,58,53,48。", + "knowledge_points": [ + "整数排列的规律" + ], + "source": "23-24 二年级上·福建漳州·期中" + }, + { + "id": "32", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.65, + "question": "按规律填数.\n\n(1)23,27,31,35,( ),43,( ),51.\n(2)70, 65, 60, 55, ( ), 45, ( ), 35。", + "options": [], + "answer": "39;47 50;40", + "solution": "【分析】(1)观察已知数据可得,这组数依次变大,每后一个数比前一个数大 4,也就是从 23 开始,四个四个地正着数,依次填写 39, 47;(2) 观察已知数据可得,这组数依次变小,每后一个数比前一个数小 5,也就是从 70 开始,五个五个地倒着数,依次填写 50, 40。\n\n【详解】 (1) 23, 27, 31, 35, 39, 43, 47, 51。(2) 70, 65, 60, 55, 50, 45, 40, 35。", + "knowledge_points": [ + "数 100 以内的数", + "整数排列的规律" + ], + "source": "23-24 二年级上·贵州黔南·期中" + }, + { + "id": "33", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.65, + "question": "按规律填一填.\n\n![](images/Pasted image 20251209223318.png)", + "options": [], + "answer": "13;13", + "solution": "【分析】观察第一组数可知: 3 + 3 + 4 = 10;观察第二组数可知: 3 + 4 + 4 = 11,所以一组数中下面两个数相加的和再加上 4 等于上面这个 数,据此解答即可。\n\n【详解】 3 + 6 + 4 = 134 + 5 + 4 = 13 填空如下:\n\n![](images/Pasted image 20251210002506.png)", + "knowledge_points": [ + "连加(20以内)", + "整数排列的规律" + ], + "source": "23-24 二年级上·山东菏泽·期中" + }, + { + "id": "34", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.65, + "question": "按规律填数字.\n3,6,9,( ),( ),( ).\n45,40,35,( ),( ),( )。", + "options": [], + "answer": "12;15;18;30;25;20", + "solution": "【分析】(1)观察已知数据可得,这组数依次变大,每后一个数比前一个数大 3,也就是从 3 开始,三个三个地正着数,依次填写 12,15,18;(2) 观察已知数据可得,这组数依次变小,每后一个数比前一个数小 5,也就是从 45 开始,五个五个地倒着数,依次填写 30, 25, 20。\n\n【详解】3,6,9,12,15,18.45, 40, 35, 30, 25, 20。", + "knowledge_points": [ + "数 100 以内的数", + "整数排列的规律" + ], + "source": "23-24 二年级上·山东济南·期中" + }, + { + "id": "35", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.65, + "question": "按规律填数.\n\n(1)51,58,65,( ),79,( ),93.\n(2)36,30,24,18,( ),( )。", + "options": [], + "answer": "72;86 12;6", + "solution": "【分析】(1)观察已知数据可得,这组数依次变大,每后一个数比前一个数大 7,也就是从 51 开始,七个七个地正着数,依次填写 72,86;(2) 观察已知数据可得,这组数依次变小,每后一个数比前一个数小 6,也就是从 36 开始,六个六个地倒着数,依次填写 12, 6。\n\n【详解】 (1) 51, 58, 65, 72, 79, 86, 93;(2) 36, 30, 24, 18, 12, 6。", + "knowledge_points": [ + "数 100 以内的数", + "整数排列的规律" + ], + "source": "23-24 二年级上·山东济宁·期中" + }, + { + "id": "36", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.65, + "question": "找规律,填一填.\n\n(1)5, 10, 15, ( ), ( ).\n(2)45, 36, 27, ( ), ( ).\n(3)2,4,6,( ),( )。", + "options": [], + "answer": "20;25;18;9 8;10", + "solution": "【分析】(1)从5开始,五个五个地数,数到25。(2) 从左到右依次减 9;(3) 从 2 开始,两个两个地数,数到 10 。\n\n【详解】 (1) 5,10,15,20,25;(2) 27 - 9 = 1818 - 9 = 945,36,27,18,9;(3) 2,4,6,8,10。", + "knowledge_points": [ + "数 100 以内的数", + "一位数与两位数的退位减法", + "整数排列的规律" + ], + "source": "23-24 二年级上·河南商丘·期中" + }, + { + "id": "37", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.85, + "question": "按规律填一填.\n\n(1) 15, 20, 25, ( ), 35, ( ).\n(2)90, 88, 86, ( ), 82, ( )。", + "options": [], + "answer": "30;40 84;80", + "solution": "【分析】(1)从 15 开始,五个五个地数,数到 40。 (2) 从 90 开始,两个两个地倒着数,数到 80。\n\n【详解】 (1) 15, 20, 25, 30, 35, 40;(2) 90, 88, 86, 84, 82, 80。", + "knowledge_points": [ + "数 100 以内的数", + "整数排列的规律" + ], + "source": "23-24 二年级上·新疆和田·期中" + }, + { + "id": "38", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.85, + "question": "按规律填数:\n\n15,20,( ),( ),35。", + "options": [], + "answer": "25;30", + "solution": "【分析】观察这组数字,可知规律为从 15 开始,五个五个地数,数到 35。\n\n【详解】按规律填数:15,20,25,30,35。", + "knowledge_points": [ + "数 100 以内的数", + "整数排列的规律" + ], + "source": "22-23 二年级上·河南商丘·期中" + }, + { + "id": "39", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.65, + "question": "找规律填一填.\n\n(1) 27, 24, (), (), (), 12.\n(2) 16, (), (), 28, 32, ()。", + "options": [], + "answer": "21;18;15;20;24;36", + "solution": "【分析】(1)右边的数比左边相邻的数少3,据此计算.\n(2) 右边的数比左边相邻的数大 4,据此计算。\n\n【详解】 (1) 24 - 3 = 2121-3=1818-3=1527,24,21,18,15,12.\n(2)16+4=2020+4=2432+4=3616,20,24,28,32,36。", + "knowledge_points": [ + "整十数加", + "减一位数", + "两位数与一位数的加法(不进位)", + "一位数与两位数的退位减法", + "整数排列的规律" + ], + "source": "23-24 二年级上·山西朔州·期中" + }, + { + "id": "40", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.85, + "question": "找规律.\n (1)45, ( ), 35, 30, ( )。 (2)19, 16, 13, ( ), ( ), ( )。 (3)32, 34, 36, (), (), ()。 (4)86, 80, (), ( ), 62, 56。", + "options": [], + "answer": "40;25 10;7;4 38;40;42 74;68", + "solution": "【分析】 (1) 后一个数比前一个数少 5;(2) 后一个数比前一个数少 3;(3) 后一个数比前一个数多 2;(4) 后一个数比前一个数少 6;据此解决。\n\n【详解】 (1) 45 - 5 = 40, 30 - 5 = 25,即,45,40,35,30,25。(2) 13 - 3 = 10, 10 - 3 = 7, 7 - 3 = 4,即,19,16,13,10,7,4。(3) 36 + 2 = 38, 38 + 2 = 40, 40 + 2 = 42,即,32,34,36,38,40,42。(4) 80 - 6 = 74, 74 - 6 = 68,即,86,80,74,68,62,56。", + "knowledge_points": [ + "整数排列的规律" + ], + "source": "23-24 一年级下·河南漯河·期末" + }, + { + "id": "41", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.85, + "question": "按规律画一画或写一写.\n (1)■☆△■☆△■,( ),( ),( )。 (2)1, 4, 7, 10, ( ), ( ), ( )。", + "options": [], + "answer": "☆;△;■ 13;16;19", + "solution": "【分析】(1)这组图形按照 ■☆△ 为一组重复排列,可知后边应为 ☆、△、■;(2) 这组数字依次变大, 1 + 3 = 4;4 + 3 = 7;7 + 3 = 10;10 + 3 = 13;13 + 3 = 16;16 + 3 = 19,依次填写 13, 16, 19。\n\n【详解】 (1)■☆△ ■☆△ ■,☆,△ ,■。(2)1,4,7,10,13,16,19。", + "knowledge_points": [ + "整数排列的规律", + "图形的变化规律" + ], + "source": "23-24 一年级下·河北保定·期末" + }, + { + "id": "42", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.65, + "question": "按规律写数.\n\n(1)50,46,42,( ),( ),( ).\n(2)12,20,28,( ),( ),( )。", + "options": [], + "answer": "38;34;30 36;44;52", + "solution": "【分析】(1)这组数字依次变小, 50 - 4 = 46;46 - 4 = 42;42 - 4 = 38;38 - 4 = 34;34 - 4 = 30,依次填写38,34,30;(2) 这组数字依次变大, 12 + 8 = 20;20 + 8 = 28;28 + 8 = 36;36 + 8 = 44;44 + 8 = 52,依次填写 36, 44, 52。\n\n【详解】 (1) 50, 46, 42, 38, 34, 30。(2) 12, 20, 28, 36, 44, 52。", + "knowledge_points": [ + "整数排列的规律" + ], + "source": "23-24 一年级下·河北保定·期末" + }, + { + "id": "43", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.85, + "question": "找规律,填一填,画一画.\n\n(1)13,16,19,22,( ),( )。 (2) ○ △ ○ △ ○ ( )。", + "options": [], + "answer": "25;28;△ ○", + "solution": "【分析】(1)这组数字依次变大, 13 + 3 = 16;16 + 3 = 19;19 + 3 = 22;22 + 3 = 25;25 + 3 = 28,依次填写 25,28;(2) 这组图形按照 ○ △ 为一组重复排列,可知后边应为 △○\n\n【详解】 (1) 13, 16, 19, 22, 25, 28。(2) ○ △ ○ △ ○ △ ○ 。", + "knowledge_points": [ + "整数排列的规律", + "图形的变化规律" + ], + "source": "23-24 一年级下·浙江嘉兴·期末" + }, + { + "id": "44", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.85, + "question": "找规律填数.\n\n(1)45, 50, ( ), 60, 65, 70, ( ).\n(2)50, 60, (), 80, (), ()。", + "options": [], + "answer": "55;75 70;90;100", + "solution": "【分析】(1)观察这组数据, 45 + 5 = 50,后一个数比前一个数多5;(2) 观察这组数据, 50 + 10 = 60,后一个数比前一个数多 10;据此解决。\n\n【详解】 (1) 50 + 5 = 55, 70 + 5 = 75,即,45,50,55,60,65,70,75。(2) 60 + 10 = 70, 80 + 10 = 90, 90 + 10 = 100,即,50,60,70,80,90,100。", + "knowledge_points": [ + "整数排列的规律" + ], + "source": "23-24 一年级下·贵州铜仁·期末" + }, + { + "id": "45", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.85, + "question": "★□★□□★□□□,( ),( ),( ),( )。", + "options": [], + "answer": "★;□;□;□", + "solution": "【分析】每组第一个都是★,□的数量依次增多,分别为1个, 2 个, 3 个, 4 个。可知后边 4 个图形依次为 ★ □ □ □。\n\n【详解】 ★□ ★□□ ★□□□ ,★, □ ,□,□。", + "knowledge_points": [ + "图形的变化规律" + ], + "source": "23-24一年级下·福建福州·期末" + }, + { + "id": "46", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.85, + "question": "按规律,填一填.\n(1)53,63,( ),( ),93.\n(2)我爱郑州我爱郑州我( )( )州。", + "options": [], + "answer": "73;83 爱;郑", + "solution": "【分析】(1)这组数字依次变大,每后一个数比前一个数大 10,也就是从 53 开始,一十一十地正着数,依次填写 73, 83;(2) 这组文字按照我爱郑州为一组重复排列,可知依次填写爱,郑。\n\n【详解】 (1) 53, 63, 73, 83, 93。(2) 我爱郑州我爱郑州我爱郑州。", + "knowledge_points": [ + "整数排列的规律", + "周期问题" + ], + "source": "23-24一年级下·河南郑州·期末" + }, + { + "id": "47", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.65, + "question": "按规律填一填.\n\n(1)12,16,( ),( ),28\n(2)48, ( ), 38, 33, ( )。", + "options": [], + "answer": "20;24;43;28", + "solution": "【分析】(1)这组数字依次变大, 12 + 4 = 16;16 + 4 = 20;20 + 4 = 24;24 + 4 = 28,依次填写20,24;(2) 这组数字依次变小, 48 - 5 = 43;43 - 5 = 38;38 - 5 = 33;33 - 5 = 28;依次填写 43, 28。\n\n【详解】 (1) 12, 16, 20, 24, 28。(2) 48, 43, 38, 33, 28。", + "knowledge_points": [ + "整数排列的规律" + ], + "source": "23-24 一年级下·河南南阳·期末" + }, + { + "id": "48", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.65, + "question": "找规律.\n\n(1)4, 7, 10, 13, ( ), ( )。 (2) □ □ △ ○ □ □ △ ○ □ □ △ ○ □ , ( ), ( ), ○ 。", + "options": [], + "answer": "16;19;□;△", + "solution": "【分析】(1)观察已知数据可得,这组数依次变大,每后一个数比前一个数大 3,也就是从 4 开始,三个三个地正着数,依次填写 16,19;(2) 观察已知图形可得,这组图形的排列特点是: 4 个图形一个循环周期,分别按照: □ □ △ ○ 依次循环排列,据此解答即可。\n\n【详解】 (1) 4, 7, 10, 13, 16, 19。(2) □ □ △ ○ □ □ △ ○ □ □ △ ○ □ , □, △, ○ 。", + "knowledge_points": [ + "整数排列的规律", + "图形的变化规律" + ], + "source": "23-24 一年级下·湖北黄石·期末" + }, + { + "id": "49", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.65, + "question": "![](images/Pasted image 20251211144825.png)\n\n□ 遮住了6个图形,被遮住的 ○ 有( )个, ◆ 有( )个。", + "options": [], + "answer": "4;2", + "solution": "【分析】5 个图形为一组,依次重复排列,每组有 2 个 ○ 和 1 个 ◆,所以被遮住的 ○ 有 4 个, ◆ 有 2 个。\n\n【详解】遮住了 6 个图形,被遮住的 ○ 有 4 个, ◆ 有 2 个。", + "knowledge_points": [ + "图形的变化规律" + ], + "source": "23-24 一年级下·湖北孝感·期末" + }, + { + "id": "50", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.65, + "question": "找规律,填一填.\n\n(1)2, 4, 6, 8, (), 12。 (2)75, 70, (), 60, ()。", + "options": [], + "answer": "10 65;55", + "solution": "【分析】(1)观察已知数据可得,这组数依次变大,每后一个数比前一个数大 2,也就是从 2 开始,两个两个地正着数,填写 10;(2) 观察已知数据可得,这组数依次变小,每后一个数比前一个数小 5,也就是从 75 开始,五个五个地倒着数,依次填写 65, 55。\n\n【详解】 (1) 2, 4, 6, 8, 10, 12。(2) 75, 70, 65, 60, 55。", + "knowledge_points": [ + "数 100 以内的数", + "整数排列的规律" + ], + "source": "23-24一年级下·湖北黄冈·期末" + }, + { + "id": "51", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.65, + "question": "按规律填数:\n\n(1)( ),45,( ),( ),60,( ).\n\n(2)( ),70,( ),( ),100。", + "options": [], + "answer": "40;50;55;65 60;80;90", + "solution": "【分析】(1)观察已知数据可得,这组数依次变大,每后一个数比前一个数大 5,也就是从 40 开始,五个五个地正着数,依次填写 40,50,55,65;(2) 观察已知数据可得,这组数依次变大,每后一个数比前一个数大 10,也就是从 60 开始,一十一十地正着数,依次填写 60, 80, 90。\n\n【详解】 (1) 40, 45, 50, 55, 60, 65。(2) 60, 70, 80, 90, 100。", + "knowledge_points": [ + "数 100 以内的数", + "整数排列的规律" + ], + "source": "23-24 一年级下·河南三门峡·期末" + }, + { + "id": "52", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.65, + "question": "找规律,再填空.\n\n(1)87, 77, 67, (), (), 37.\n(2)0,1,3,6,10,15,( ),( )。", + "options": [], + "answer": "57;47 21;28", + "solution": "【分析】 (1) 后一个数比前一个数少 10;(2) 从左往右依次加 1,加 2,加 3,加 4,加 5,加 6,加 7, 。;据此解决。\n\n【详解】 (1) 67 - 10 = 57, 57 - 10 = 47,即87,77,67,57,47,37。(2) 15 + 6 = 21, 21 + 7 = 28,即0,1,3,6,10,15,21,28。", + "knowledge_points": [ + "整数排列的规律" + ], + "source": "23-24 一年级下·湖北武汉·期末" + }, + { + "id": "53", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.65, + "question": "按规律填写.\n\n(1)36, 40, 44, ( ), 52, ( ), 60。(2)( ),60,55,( ),45。", + "options": [], + "answer": "48;56 65;50", + "solution": "【分析】 (1) 这组数字依次变大, 36 + 4 = 40;40 + 4 =44;44 + 4 = 48;48 + 4 = 52;52 + 4 = 56;56 + 4 = 60 。依次填写 48, 56;(2) 这组数字依次变小, 65 - 5 = 60;60 - 5 = 55;55 - 5 = 50;50 - 5 = 45,依次填写 65, 50.\n【详解】 (1) 36, 40, 44, 48, 52, 56, 60。 (2) 65, 60, 55, 50, 45。", + "knowledge_points": [ + "整数排列的规律" + ], + "source": "23-24 一年级下·山东临沂·期末" + }, + { + "id": "54", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.65, + "question": "找规律填数.\n(1) 99, 88, ( ) , ( ) , 55.\n(2) 20, 25, ( ) , ( ) , 40.\n(3)![](images/Pasted image 20251211153749.png)", + "options": [], + "answer": "77;66 30;35 68;70", + "solution": "【分析】(1)这组数字每个数的十位和个位都相同,每后一个数的十位和个位的数字,都比前一个数十位和个位的数字小 1,依次填写 77,66;(2) 这组数字依次变大, 20 + 5 = 25;25 + 5 = 30;30 + 5 = 35;35 + 5 = 40,依次填写 30, 35;(3) 这组数字中间的数 + 右边的数 = 左边的数;左边的数 - 中间的数 = 右边的数量;左边的数 - 右边的数 = 中间的数。 60 + 8 = 68;73 - 3 = 70,依次填写 68, 70。\n\n【详解】 (1) 99, 88, 77, 66, 55。(2) 20, 25, 30, 35, 40。(3)![](images/Pasted image 20251211155150.png)", + "knowledge_points": [ + "整数排列的规律" + ], + "source": "23-24 一年级下·广东汕头·期末" + }, + { + "id": "55", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.65, + "question": "如图,每行每列都有数字 1 ~ 3,并且每个数字在每行每列都只出现 1 次,那么在☆处应该填( ).\n\n
32
2☆
13
", + "options": [], + "answer": "3", + "solution": "【分析】本题考查根据规律填数。因为每行每列都是1,2,3三个数,并且不能重复,所以第一行中间填写1,最下面一行的中间填写2,那么第二列的中间☆处应填写3。\n\n【详解】如图,每行每列都有数字 1 ~ 3,并且每个数字在每行每列都只出现 1 次,那么在☆处应该填 3.\n\n
312
231
123
", + "knowledge_points": [ + "数表中的规律", + "填数游戏" + ], + "source": "23-24 一年级下·安徽淮南·期末" + }, + { + "id": "56", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.65, + "question": "按规律填一填,画一画.\n\n(1)1, 3, 5, 7, 9, ( ), 13, ( ).\n(2)14,24,34,44,( ),( ),74.\n(3)□○□○○□○○,( ),( ),○○○○。", + "options": [], + "answer": "11;15 54;64 ○;□", + "solution": "【分析】(1)这组数字依次变大。 1 + 2 = 3;3 + 2 = 5;5 + 2 = 7;7 + 2 = 9;9 + 2 = 11;11 + 2 = 13;13 + 2 = 15;依次填写11,15;(2) 这组数字依次变大, 14 + 10 = 24;24 + 10 = 34;34 + 10 = 44;44 + 10 = 54;54 + 10 = 64;64 + 10 = 74;依次填写 54, 64;(3) 这组图形中每组第一个都是 □ , 每组 ○ 的数量依次多\n\n1。 第 1, 2 组是完整的,缺少的是第 3 组的最后一个 ○ 和第 4 组的第一个 □ 。\n\n【详解】 (1) 1, 3, 5, 7, 9, 11, 13, 15。(2) 14, 24, 34, 44, 54, 64, 74。 (3) □ ○ □ ○ ○ □ ○ ○ , ○ , □ , ○ ○ ○ ○ 。", + "knowledge_points": [ + "整数排列的规律", + "图形的变化规律" + ], + "source": "23-24 一年级下·山西长治·期末" + }, + { + "id": "57", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.65, + "question": "按规律填数.\n\n(1) 11, 22, 33, ( ) , ( ) , ( ) , 77.\n(2) ![](images/487188a04ba5678a3ef4cd36eba451f5.png)", + "options": [], + "answer": "44;55;66 76;29", + "solution": "【分析】(1)这组数字十位和个位相同,每后一个数十位和个位的数字比前一个数十位和个位数字大 1,依次填写 44, 55, 66;(2) 这组数字,左上角的数+右上角的数=中间的数;中间的数减左上角的数=右上角的数;70 + 6 = 76;37 - 8 =29,依次填写 76,29。\n\n【详解】 (1) 11, 22, 33, 44, 55, 66, 77。(2)![](images/Pasted image 20251211161028.png)", + "knowledge_points": [ + "整数排列的规律" + ], + "source": "23-24 一年级下·福建漳州·期末" + }, + { + "id": "58", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.65, + "question": "找规律,填一填,画一画.\n\n(1) 36, 30, 24, ( ) , ( ) , 6, ( ) .\n\n(2)![](images/Pasted image 20251211161134.png)\n(3) △ ○ □ △ ○ □ △ ○ □ △ ( ) □ 。", + "options": [], + "answer": "18;12;0 17;16;20 ○", + "solution": "【分析】 (1) 36 - 30 = 6,则后一个数比前一个数少 6;(2) 上面两个数相加的和等于下面这个数;下面这个数减去上面的一个数,求出的差就是上面的另一个数;(3) △ ○ □ , 这三个图形依次重复出现;据此解决。\n\n【详解】 (1) 24 - 6 = 18, 18 - 6 = 12, 6 - 6 = 0,即,36,30,24,18,12,6,0。(2) 9 + 8 = 17, 20 - 4 = 16, 60 - 40 = 20,![](images/Pasted image 20251211161243.png)\n\n(3) △ ○ □ △ ○ □ △ ○ □ △ ○ □ 。", + "knowledge_points": [ + "整数排列的规律", + "图形的变化规律" + ], + "source": "23-24 一年级下·湖北武汉·期末" + }, + { + "id": "59", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.85, + "question": "按顺序填数.\n\n
979899()
\n\n
85()6555
", + "options": [], + "answer": "100;75", + "solution": "【分析】第一组数,后一个数比前一个数多 1;第二组数,后一个数比前一个数少 10;据此解决。\n\n【详解】由题意分析得:99 + 1 = 100
979899100
85 - 10 = 75
85756555
", + "knowledge_points": [ + "数 100 以内的数", + "整数排列的规律" + ], + "source": "23-24 一年级下·河南南阳·期末" + }, + { + "id": "60", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.85, + "question": "找规律,接着写。
406070
100989695
", + "options": [], + "answer": "50;80;90 99;97;94", + "solution": "【分析】第一组数,后一个数比前一个数多 10;第二组数,后一个数比前一个数少 1;据此解决。\n\n【详解】 40 + 10 = 50, 70 + 10 = 80, 80 + 10 = 90,即,
405060708090
100 - 1 = 99, 98 - 1 = 97, 95 - 1 = 94,即,
100999897969594
", + "knowledge_points": [ + "整数排列的规律" + ], + "source": "23-24 一年级下·河南周口·期末" + }, + { + "id": "61", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.65, + "question": "按规律填数和图.\n\n(1)6, 8, ( ), 12, 14, ( ).\n(2)5, 9, 13, 17, ( ), ( ), 29.\n(3) □ □ ○ ○ ○ □ □ ○ ○ ○ □ □ ○ ○ ( ) 。", + "options": [], + "answer": "10;16 21;25 ○", + "solution": "【分析】(1)通过给出的数据可知规律为:前一个数比后一个数少 2,后一个数比前一个数多 2。(2) 通过给出的数据可知规律为:前一个数比后一个数少 4,后一个数比前一个数多 4 。 (3) 通过给出的图形可知规律为:按 □ □ ○ ○ ○ 的顺序重复出现,按此规律填入缺少的图形即可。\n\n【详解】 (1) 8 + 2 = 10, 14 + 2 = 16 这组数据为:6,8,(10),12,14,(16)。(2) 17 + 4 = 21, 21 + 4 = 25这组数据为:5,9,13,17,(21),(25),29。(3) 由分析可知:这组图形为:□□〇〇〇□□〇〇〇□□〇〇(〇)。", + "knowledge_points": [ + "整数排列的规律", + "图形的变化规律" + ], + "source": "23-24 一年级下·湖北黄冈·期末" + }, + { + "id": "62", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.85, + "question": "按规律填数.\n\n(1)( ),90,80,( ),60,50.\n(2)7, 14, 21, (), 35, ()。", + "options": [], + "answer": "100;70 28;42", + "solution": "【分析】根据给出的数字可以判断数字是按照整数越来越小,可以判断比90大的整数是多少,比80小比60大的整数是多少;前面的数字比下一个数字大10;计算可以发现出现的数字都与7有关,14是两个7,21是3个7,35是5个7,那么中间就是4个7,后面就是6个7,相加即可得出答案。考查学生的找规律和对数字的认识。\n\n【详解】 (1) (100), 90, 80, (70), 60, 50(2) 7, 14, 21, (28), 35, (42)", + "knowledge_points": [ + "100以内数的排序", + "一位数与两位数的进位加法" + ], + "source": "23-24 一年级下·湖南邵阳·期末" + }, + { + "id": "63", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.85, + "question": "鸡妈妈们带小鸡们去草地上捉虫。按照![](images/Pasted image 20251211170922.png) 这样的队伍排列,第12只是( )(填\"母鸡\"或\"小鸡\"),这12只鸡中共有( )只母鸡, ( )只小鸡。", + "options": [], + "answer": "小鸡;3;9", + "solution": "【分析】根据题意,它们按照图中规律为一组重复排列。已经排列了 10 只,第 11 只是母鸡,第 12 只是小鸡。将母鸡和小鸡的数量分别相加计算出总数量即可。\n\n【详解】![](images/Pasted image 20251211174535.png)母鸡: 1 + 1 + 1 = 3 (只)小鸡: 4 + 4 + 1 = 9 (只)\n\n鸡妈妈们带小鸡们去草地上捉虫。按照![](images/Pasted image 20251211174554.png)这样的队伍排列,第12只是小鸡,这12只鸡中共有3只母鸡,9只小鸡。", + "knowledge_points": [ + "间隔问题" + ], + "source": "23-24 一年级下·吉林·期末" + }, + { + "id": "64", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.65, + "question": "找规律,填一填.\n\n(1) △ ○ □ △ ○ □ △ ( )( ) .\n(2)8, 12, 16, ( ), ( ), 28, 32。", + "options": [], + "answer": "○;□ 20;24", + "solution": "【分析】(1) 这组图形按照 ![](images/Pasted image 20251211174706.png) 为一组重复排列,可知后边应为 ![](images/Pasted image 20251211174717.png);(2) 这组数字依次变大。 8 + 4 = 12;12 + 4 = 16;16 + 4 =20;20 + 4 = 24;24 + 4 = 28;28 + 4 = 32 。依次填写 20, 24。\n\n【详解】 (1)![](images/Pasted image 20251211174725.png)(2) 8, 12, 16, 20, 24, 28, 32。", + "knowledge_points": [ + "整数排列的规律", + "图形的变化规律" + ], + "source": "23-24一年级下·山东日照·期末" + }, + { + "id": "65", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.85, + "question": "按规律填数:\n\n5,10,15,( ),( ),( )。", + "options": [], + "answer": "20;25;30", + "solution": "【分析】这组数字依次变大。 5 + 5 = 10;10 + 5 = 15;15 + 5 = 20;20 + 5 = 25;25 + 5 = 30,依次填写20,25,30。\n\n【详解】按规律填数:5,10,15,20,25,30。", + "knowledge_points": [ + "整数排列的规律" + ], + "source": "23-24 一年级下·广东佛山·期末" + }, + { + "id": "66", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.85, + "question": "○ △ △ ○ , ( ), △ , ( ), ( ) , △ 。", + "options": [], + "answer": "△;○;△", + "solution": "【分析】这组图形按照 ○ △ △ 为一组重复排列,可知依次填写 △ , ○ , △ 。\n\n【详解】 ○ △ △ ○ , △ , △ , ○ , △ , △ 。", + "knowledge_points": [ + "图形的变化规律" + ], + "source": "23-24 一年级下·广东佛山·期末" + }, + { + "id": "67", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.85, + "question": "按规律填数.\n\n4, 7, 10, 13, ( ), ( ), 22。", + "options": [], + "answer": "16;19", + "solution": "【分析】这组数字依次变大。 4 + 3 = 7;7 + 3 = 10;10 + 3 = 13;13 + 3 = 16;16 + 3 = 19;19 + 3 = 22;依次填写16, 19。\n\n【详解】由分析填写如下:\n\n4, 7, 10, 13, 16, 19, 22。", + "knowledge_points": [ + "整数排列的规律" + ], + "source": "23-24 一年级下·山东济宁·期末" + }, + { + "id": "68", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.85, + "question": "找规律。接着写数或图形.\n(1)2, 4, ( ), ( ), ( ), 12.\n(2)95,85,75,( ),( ),( ).\n(3) △, ○, △, ○, △, ○, ( ), ( ) 。", + "options": [], + "answer": "6;8;10 65;55;45 △;○", + "solution": "【分析】(1)这组数字依次变大。 2 + 2 = 4;4 + 2 = 6;6 + 2 = 8;8 + 2 = 10;10 + 2 = 12;依次填写6,8,10;(2) 这组数字依次变小。 95 - 10 = 85;85 - 10 = 75;75-10 = 65;65 - 10 = 55;55 - 10 = 45;依次填写 65, 55, 45;(3) 这组图形按照△ ,○ 为一组重复排列,可知后边依次为△ ,○。\n\n【详解】 (1) 2, 4, 6, 8, 10, 12.\n(2) 95, 85, 75, 65, 55, 45.\n(3) △, ○, △, ○, △, ○, △, ○ 。", + "knowledge_points": [ + "整数排列的规律", + "图形的变化规律" + ], + "source": "23-24 一年级下·山东济南·期末" + }, + { + "id": "69", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.65, + "question": "找规律填数或画出相应的图形.\n(1)24,22,( ),18,( ).\n(2)5,9,13,( ),( ).\n(3)□○○□○○□○○□○○,( ),( )。", + "options": [], + "answer": "20;16 17;21 ○;□", + "solution": "【分析】(1)这组数字依次变小。 24 - 2 = 22;22 - 2 =20;20 - 2 = 18;18 - 2 = 16;依次填写 20, 16;(2) 这组数字依次变大。 5 + 4 = 9;9 + 4 = 13;13 + 4 =17;17 + 4 = 21;依次填写 17, 21;(3) 这组图形按照 □ ○ ○ 为一组重复排列,可知后边应为 ○ , □ 。\n\n【详解】\n(1) 24, 22, 20, 18, 16.\n(2) 5, 9, 13, 17, 21 .\n(3) □ ○ ○ □ ○ ○ □ ○ , ○ , □", + "knowledge_points": [ + "整数排列的规律", + "图形的变化规律" + ], + "source": "23-24 一年级下·湖南衡阳·期末" + }, + { + "id": "70", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.65, + "question": "找规律,填一填,画一画.\n(1)16,24,32,40,( ),( ),( ).\n(2) ![](images/Pasted image 20251211193017.png)( )", + "options": [], + "answer": "48;56;64 ○;△", + "solution": "【分析】(1)通过观察相邻的数字可知规律为:前一个数比后一个数少 8,后一个数比前一个数多 8。(2) 这组图形按 ○○△ ☆ 为一组重复排列,可知后面依次画 ○△ 。\n\n【详解】 (1) 由分析可知:40 + 8 = 48, 48 + 8 = 56, 56 + 8 = 64这列数字为: 16, 24, 32, 40, (48), (56), (64)。(2) 由分析可知:这组图形为:○○△ ☆○○△ ☆○○△ ☆(○),(△) 。", + "knowledge_points": [ + "整数排列的规律", + "图形的变化规律" + ], + "source": "23-24 一年级下·山东济宁·期末" + }, + { + "id": "71", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.85, + "question": "找规律,填一填。(1)4, 8, 12, 16, ( ), ( )。(2)12,22,32,( ),( )。", + "options": [], + "answer": "20;24 42;52", + "solution": "【分析】 (1) 这组数字依次变大, 4 + 4 = 8;8 + 4 = 12;12 + 4 = 16;16 + 4 = 20;20 + 4 = 24,依次填写20,24;(2) 这组数字依次变大, 12 + 10 = 22;22 + 10 = 32;32+10 = 42;42 + 10 = 52,依次填写42,52。\n\n【详解】 (1) 4, 8, 12, 16, 20, 24。(2) 12, 22, 32, 42, 52。", + "knowledge_points": [ + "整数排列的规律" + ], + "source": "23-24一年级下·山东临沂·期末" + }, + { + "id": "72", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.85, + "question": "按规律填空.\n\n(1)41, 43, 45, 47, ( ), ( )。 (2) □ △ ○ □ □ △ ○ □ □ ( ), ( )。", + "options": [], + "answer": "49;51;△;○", + "solution": "【分析】(1)这组数字依次变大, 41 + 2 = 43;43 + 2 = 45;45 + 2 = 47;47 + 2 = 49;49 + 2 = 51,依次填写 49, 51;(2) 这组图形按照 □ △ ○ 为一组重复排列,可知后边依次为 △ , ○ 。\n\n【详解】 (1) 41, 43, 45, 47, 49, 51。(2) □ △ ○ □ □ △ ○ □ □ △ , ○ 。", + "knowledge_points": [ + "整数排列的规律", + "图形的变化规律" + ], + "source": "23-24 一年级下·河北邢台·期末" + }, + { + "id": "73", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.65, + "question": "找规律.\n\n(1)90, 85, 80, ( ).\n\n(2)28, 38, 48, ( )。", + "options": [], + "answer": "75 58", + "solution": "【分析】(1)这组数字依次变小。 90 - 5 = 85;85 - 5 =80;80 - 5 = 75,填写 75;(2) 这组数字依次变大。28 + 10 = 38;38 + 10 = 48;48 + 10 = 58,填写 58。\n\n【详解】 (1) 90, 85, 80, 75。(2) 28, 38, 48, 58。", + "knowledge_points": [ + "两位数与整十数的加法", + "一位数与两位数的退位减法", + "整数排列的规律" + ], + "source": "23-24 一年级下·广东河源·期末" + }, + { + "id": "74", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.85, + "question": "按规律填数.\n\n(1)
191615
\n\n(2) ( ) , ( ) , 6, ( ) , 10, ( ) , ( ) 。", + "options": [], + "answer": "18;17;14;13;12 2;4;8;12;14", + "solution": "【分析】(1)根据题意可知:该组规律:数字从左到右依次减 1.\n\n(2) 该组规律:数字从左到右依次加 2。\n\n【详解】 (1)
1918171615141312
\n\n(2) (2), (4), 6, (8), 10, (12), (14)。", + "knowledge_points": [ + "20以内数的排序", + "不进位加法(20以内)", + "不 退位减法(20以内)", + "整数排列的规律" + ], + "source": "23-24一年级上·福建莆田·期末" + }, + { + "id": "75", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.65, + "question": "小袋鼠,跳一跳.\n\n![](images/Pasted image 20251211202851.png)\n\n(1)小袋鼠每次跳( )个圆,其中有( )个○,( )个●.\n(2)小袋鼠一共要跳( )次才能跳完所有的圆。", + "options": [], + "answer": "3;2;1 9", + "solution": "【分析】(1)根据题图可知,小袋鼠每次跳3个圆,2个 ○ ,1个 ●;(2) 根据题图可知, 3 个圆一个循环,画一画,数一数图中有几个循环即可判断出小袋鼠跳的次数,据此解答即可。\n\n【详解】(1)小袋鼠每次跳3个圆,其中有2个 ○ , 1 个 ● .\n\n(2)![](images/Pasted image 20251211212357.png)", + "knowledge_points": [ + "间隔问题" + ], + "source": "23-24一年级下·陕西安康·期末" + }, + { + "id": "76", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.65, + "question": "按规律填数.\n\n(1)5,10,15,20,25,( ),( ),40。 (2)99, ( ), 77, 66, 55, 44, ( ), 22。 (3)3,8,13,( ),23,28,( ),38。", + "options": [], + "answer": "30;35 88;33 18;33", + "solution": "【分析】(1)观察已知数据可得,后一个数等于前一个数加 5;(2) 观察已知数据可得,十位数和个位数一样,且都比前面的数小 1;(3) 观察已知数据可得,后一个数等于前一个数加 5,据此解答。\n\n【详解】 (1) 25 + 5 = 30, 30 + 5 = 35 所以5,10,15,20,25,30,35,40。(2) 9 - 1 = 8, 4 - 1 = 3\n所以99,88,77,66,55,44,33,22。(3) 13 + 5 = 18, 28 + 5 = 33所以3,8,13,18,23,28,33,38。", + "knowledge_points": [ + "整十数加", + "减一位数", + "两位数与一位数的加法(不进位)", + "一位数与两位数的进位加法", + "整数排列的规律" + ], + "source": "23-24 一年级下·陕西安康·期末" + }, + { + "id": "77", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.65, + "question": "接着画一画:\n\n● △ ● △ △ ● △ △ △ ● △ △ ( ) ( )( )", + "options": [], + "answer": "△;△;●", + "solution": "【分析】一个 ● 一个 △ , 一个 ● 2 个 △ , 一个 ● 3 个 △ , 一个 ● 4 个 △ , 依次类推,据此规律得出结论即可。\n\n【详解】根据分析知:●△ ●△△ ●△△△ ●△△△△ ●△△△△△ 。", + "knowledge_points": [ + "图形的变化规律" + ], + "source": "22-23一年级下·江西吉安·期末" + }, + { + "id": "78", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.85, + "question": "找规律填数.\n(1)18,20,( ),24,26,28,( ),( ).\n(2)( ),90,80,( ),60,50,( )。", + "options": [], + "answer": "22;30;32;100;70;40", + "solution": "【分析】 (1) 后一个数比前一个数多 2;(2) 后一个数比前一个数少 10,前一个数比后一个数多 10;据此解决。\n\n【详解】 (1) 20 + 2 = 22, 28 + 2 = 30, 30 + 2 = 32,即,18,20,22,24,26,28,30,32。 (2) 90 + 10 = 100, 80 - 10 = 70, 50 - 10 = 40,即,100,90,80,70,60,50。", + "knowledge_points": [ + "整数排列的规律" + ], + "source": "22-23一年级下·江西吉安·期末" + }, + { + "id": "79", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.65, + "question": "找规律接着填.\n\n(1)16,26,36,( ),( ).\n(2) ● ○ ○ □ ● ○ ○ □ ● ○ ( ) , ( )。", + "options": [], + "answer": "46;56;○;□", + "solution": "【分析】(1)从 16 开始十个十个的数,然后填入缺少的数字。 (2) 按 ● ○ ○ □ 的顺序,四个一组循环出现,据此规律填入缺少的图形即可.\n【详解】 (1) 16, 26, 36, 46, 56。 (2) ● ○ ○ □ ● ○ ○ □ ● ○ ○ □ 。", + "knowledge_points": [ + "整数排列的规律", + "周期问题" + ], + "source": "23-24 一年级下·河南周口·期末" + }, + { + "id": "80", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.65, + "question": "按规律填一填,画一画.\n\n(1)3, 6, 9, ( ), ( ), 18, ( ), 24。 (2)95,85,( ),( ),55,( ),( ),25。 (3) △●△ △● △ △ △ ( )● △ △ △ △ △ 。", + "options": [], + "answer": "12;15;21 75;65;45;35 △", + "solution": "【分析】 (1) 后一个数比前一个数多 3;(2) 后一个数比前一个数少 10;(3) 依次是 1 个 △ , 1 个 ● , 2 个 △ , 1 个 ● , 3 个 △ , 1 个 ● , 4 个 △ , 1 个 ● ,5 个 △;据此解决。\n\n【详解】 (1) 9 + 3 = 12, 12 + 3 = 15, 18 + 3 = 21,即,3,6,9,12,15,18,21,24。(2) 85 - 10 = 75, 75 - 10 = 65, 55 - 10 = 45, 45 - 10 =35,即,95,85,75,65,55,45,35,25。 (3) △ ● △ △ ● △ △ △ ● △ △ △ △ ● △ △ △ △ △ 。", + "knowledge_points": [ + "整数排列的规律", + "图形的变化规律" + ], + "source": "23-24 一年级下·河北廊坊·期末" + }, + { + "id": "81", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.65, + "question": "找规律,填一填,画一画.\n\n(1)30, 27, 24, ( ), ( ), 15, 12.\n(2)△□○△□○△□( )( )□○。", + "options": [], + "answer": "21;18 ○;△", + "solution": "【分析】(1)观察已知数据可得,后一个数等于前一个数减3;(2) 观察已知图形可得, △ □ ○ 为一组,依次重复出现,据此解答即可。\n\n【详解】 (1) 24 - 3 = 21, 21 - 3 = 18所以30,27,24,21,18,15,12。(2) △ □ ○ △ □ ○ △ □ ○ △ □ ○ 。", + "knowledge_points": [ + "两位数与一位数的减法(不退位)", + "一位数与两位数的退位减法", + "整数排列的规律", + "图形的变化规律" + ], + "source": "23-24 一年级下·贵州六盘水·期末" + }, + { + "id": "82", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.85, + "question": "找规律填数.\n(1)30, 35, 40, ( ), 50, ( ), ( )。\n(2)21,18,( ),( ),9,6,( )。", + "options": [], + "answer": "45;55;60 15;12;3", + "solution": "【分析】(1)这组数字依次变大。 30 + 5 = 35;35 + 5 =40;40 + 5 = 45;45 + 5 = 50;50 + 5 = 55;55 + 5 = 60。依次填写45,55,60;(2) 这组数字依次变小。 21 - 3 = 18;18 - 3 = 15;15 - 3 = 12;12 - 3 = 9;9 - 3 = 6;6 - 3 = 3 。依次填写 15, 12, 3。\n\n【详解】(1) 30, 35, 40, 45, 50, 55, 60。(2) 21, 18, 15, 12, 9, 6, 3。", + "knowledge_points": [ + "一位数与两位数的进位加法", + "一位数与两位数的退位减法", + "整数排列的规律" + ], + "source": "23-24 一年级下·广东汕尾·期末" + }, + { + "id": "83", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.65, + "question": "下面每个括号里的两个数都是按一定的规律组合的,在横线上填上适当的数.\n\n(8, 4) (5, 7) (10, 2) (( ), 9)", + "options": [], + "answer": "3", + "solution": "【分析】经仔细观察,分析,不难发现:前三个括号里,每个括号里的两个数相加的和都是 12,据此规律填出答案即可。\n\n【详解】根据分析得出的这一规律,横线上所填的数应为: 12 - 9 = 3 (8, 4) (5, 7) (10, 2) (3, 9)", + "knowledge_points": [ + "整数排列的规律" + ], + "source": "23-24 四年级上·全国·课后作业" + }, + { + "id": "84", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.65, + "question": "先找出规律,然后在括号里填上适当的数.\n\n23,4,20,6,17,8,( ),( ),11,12。", + "options": [], + "answer": "14;10", + "solution": "【分析】在这列数中,第一个数减去3的差是第三个数,第二个数加上 2 的和是第四个数,第三个数减去 3 的差是第五个数,第四个数加上 2 的和是第六个数。依此规律,给 17 减 3 即可求出第 7 个数,给 8 加 2 即可求出第 8 个数。\n\n【详解】 17 - 3 = 14, 23,4,20,6,17,8,14,10,11,12。", + "knowledge_points": [ + "整数排列的规律" + ], + "source": "23-24 四年级上·全国·课后作业" + }, + { + "id": "85", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.85, + "question": "找规律,填空.\n\n(1) ○, □, △, ○, □, △, ( ), ( ) .\n(2)85, 80, 75, ( ), ( ), 60。", + "options": [], + "answer": "○;□ 70;65", + "solution": "【分析】(1)这组图形按照 ○, □, △ 的顺序重复排列,可知应填写 ○, □;(2) 这组数字依次变小,每后一个数比前一个数小 5,也就是从 85 开始,五个五个地倒着数,依次填写 70, 65。\n\n【详解】 (1) ○, □, △, ○, □, △, ○, □ 。(2) 85, 80, 75, 70, 65, 60。", + "knowledge_points": [ + "数 100 以内的数", + "整数排列的规律", + "图形的变化规律" + ], + "source": "23-24 一年级下·河南安阳·期末" + }, + { + "id": "86", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.85, + "question": "按规律填一填,画一画.\n\n(1)99, 88, 77, ( ), ( ).\n(2) ![](images/Pasted image 20251212132815.png)( )。", + "options": [], + "answer": "66;55 ![](images/Pasted image 20251212132830.png)", + "solution": "【分析】(1)这组数字依次减小。十位和个位数字相同。每后一个数十位和个位数字都比前一个数字小 1,依次填写 66, 55;(2) 这组图形白色三角个数依次加 1,黑色三角个数不变。可知应填写下一组图形。\n\n【详解】 (1) 99, 88, 77, 66, 55。(2)![](images/Pasted image 20251212132830.png)", + "knowledge_points": [ + "整数排列的规律", + "图形的变化规律" + ], + "source": "23-24一年级下·广西柳州·期末" + }, + { + "id": "87", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.65, + "question": "找规律填一填.\n\n(1)4,18,6,28,8,38,( ),( ).\n(2)1,2,3,5,5,8,7,( ),( )。", + "options": [], + "answer": "10;48;11;9", + "solution": "【分析】(1)第一个数和第三个数和第五个数分别是:4, 6, 8,都是依次加 2 的双数;第二个数和第四个数和第六个数分别是:18,28,38,规律是依次加 10;所以第七个数是: 8 + 2 = 10,第八个数是: 38 + 10 = 48.\n\n(2) 第一个数和第三个数和第五个数和第七个数分别是: 1, 3, 5, 7,都是依次加 2 的单数;第二个数和第四个数和第六个数分别是:2,5,8,规律是依次加3;所以第八个数是: 8 + 3 = 11,第九个数是: 7 + 2 = 9 。\n\n【详解】 (1) 8 + 2 = 10, 38 + 10 = 48, 4, 18, 6, 28, 8, 38, 10, 48。 (2) 8 + 3 = 11, 7 + 2 = 9, 1, 2, 3, 5, 5, 8, 7, 11, 9。", + "knowledge_points": [ + "10 的加减法", + "8 加几的进位加法", + "两位数与整十数的加法", + "整数排列的规律" + ], + "source": "23-24 一年级下·河南南阳·期末" + }, + { + "id": "88", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.85, + "question": "找规律,再填空.\n\n(1) □ □ ○ □ □ ○ □ □ ○ □ ( ) ( ).\n(2)3,1,4,3,1,4,3,1,4,3,( ),( )。", + "options": [], + "answer": "○;□ 1;4", + "solution": "【分析】(1)这组图形按照□□○为一组重复排列,可知依次填写○,□;(2) 这组数字按照 3, 1, 4 为一组重复排列,可知依次填写 1, 4.\n【详解】 (1) □ □ ○ □ □ ○ □ □ ○ □ ○ □ 。 (2) 3, 1, 4, 3, 1, 4, 3, 1, 4, 3, 1, 4。", + "knowledge_points": [ + "整数排列的规律", + "图形的变化规律" + ], + "source": "23-24一年级下·山东临沂·期末" + }, + { + "id": "89", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.85, + "question": "按规律填数.\n\n
579171514
", + "options": [], + "answer": "4;6;8;16;13;12", + "solution": "【分析】第一组数:后一个数比前一个数多 1;第二组数:后一个比前一个数少 1;据此解决。\n\n【详解】由题意分析得:5 - 1 = 4, 5 + 1 = 6, 7 + 1 = 8 .\n
456789
\n17 - 1 = 16, 14 - 1 = 13, 13 - 1 = 12 .\n
171615141312
", + "knowledge_points": [ + "整数排列的规律" + ], + "source": "22-23 一年级下·广西柳州·期末" + }, + { + "id": "90", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.65, + "question": "按规律填一填.\n\n(1) ( ) , 46, 48, ( ) , ( ) , 54.\n\n(2)![](images/Pasted image 20251212133537.png)", + "options": [], + "answer": "44;50;52 8;6", + "solution": "【分析】 (1) 规律是:依次加 2;(2) 规律是:外面三个数之和等于中间的数,中间的数减\n\n外面两个数等于另一个数。\n\n【详解】 (1) 46 - 2 = 44, 48 + 2 = 50, 50 + 2 = 52.44, 46, 48, 50, 52, 54 (2) 28 - 5 - 15 = 8, 36 - 23 - 7 = 6 .\n\n![](images/Pasted image 20251213121604.png)", + "knowledge_points": [ + "整数排列的规律" + ], + "source": "23-24一年级下·贵州黔西·期末" + }, + { + "id": "91", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.85, + "question": "按规律填数.\n(1)34,44,54,( ),( ),84.\n(2)( ),( ),88,( ),( )。", + "options": [], + "answer": "64;74 86;87;89;90", + "solution": "【分析】(1)这组数字依次变大,每后一个数比前一个数大 10,也就是从 34 开始,十个十个地往后数,依次填写 64, 74;(2) 这组数字中间只有一个 88,所以只要填写的数字之间有一定的规律即可,可使每后一个数字比前一个数字大 1,也就是从 86 开始,一个一个地往后数,依次填写 86, 87, 89, 90。\n\n【详解】 (1) 34, 44, 54, 64, 74, 84。(2) 86, 87, 88, 89, 90。(答案不唯一)", + "knowledge_points": [ + "数 100 以内的数", + "整数排列的规律" + ], + "source": "22-23 一年级下·江西宜春·期中" + }, + { + "id": "92", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.85, + "question": "看图画一画.\n\n(1)△○□△○□( ),( ),( ).\n(2) ○ △ △ ○ △ △ ( ), ( ), ( ) 。", + "options": [], + "answer": "△;○;□ ○;△;△", + "solution": "【分析】(1)这组图形按照 △ ○ □ 为一组重复排列,可知后边应为 △ ○ □;(2) 这组图形按照 ○ △ △ 为一组重复排列,可知后边应为 ○ △ △ 。\n\n【详解】 (1) △ ○ □ △ ○ □ △ , ○ , □ 。(2) ○ △ △ ○ △ △ , ○ , △ , △ 。", + "knowledge_points": [ + "图形的变化规律" + ], + "source": "23-24 二年级下·湖南益阳·期末" + }, + { + "id": "93", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.85, + "question": "按顺序填一填.\n\n(1)29, ( ), ( ), 32, ( )。 (2)( ),( ),80,70,()。", + "options": [], + "answer": "30;31;33;100;90;60", + "solution": "【分析】(1)这组数字依次变大,29 和 32 之间间隔 2 个数,相差 3,可知每后一个数比前一个数大 1,依次填写 30,31,33;(2) 这组数字依次变小,每后一个数比前一个数小 10,依次填写 100, 90, 60。\n\n【详解】 (1) 29, 30, 31, 32, 33。(2) 100, 90, 80, 70, 60。", + "knowledge_points": [ + "整数排列的规律" + ], + "source": "23-24 一年级下·四川南充·期末" + }, + { + "id": "94", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.65, + "question": "找规律,填数.\n\n32,27,22,( ),12,( )。", + "options": [], + "answer": "17;7", + "solution": "【分析】这组数依次变小, 32 - 5 = 27;27 - 5 = 22;22 - 5 = 17;17 - 5 = 12;12 - 5 = 7,依次填写 17, 7。\n\n【详解】32,27,22,17,12,7。", + "knowledge_points": [ + "两位数与一位数的减法(不退位)", + "一位数与两位数的退位减法", + "整数排列的规律" + ], + "source": "23-24 一年级下·贵州铜仁·期末" + }, + { + "id": "95", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.85, + "question": "按规律填数.\n\n(1) 100, ( ), 80, ( ), 60;(2)42, (), 46, (), 50。", + "options": [], + "answer": "90;70;44;48", + "solution": "【分析】从 100 开始,十个十个地倒着数,数到 60。从 42 开始,两个两个地数,数到 50 。\n\n【详解】 (1) 100, 90, 80, 70, 60。(2) 42, 44, 46, 48, 50。", + "knowledge_points": [ + "数 100 以内的数", + "整数排列的规律" + ], + "source": "22-23 一年级下·云南保山·期中" + }, + { + "id": "96", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.65, + "question": "如图是一组有规律的图案,第1个图案是由4个基本图形组成,第2个图案是由 7 个基本图形组成,则第 5 个图案是由( )个基本图形组成.\n\n![](images/Pasted image 20251213174217.png)", + "options": [], + "answer": "16", + "solution": "【分析】第 1 个图案是由 4 个基本图形组成,第 2 个图案是由 (4 + 3 = 7)个基本图形组成,第 3 个图案是由(4 + 3 + 3= 10 )个基本图形组成,第4个图案是由 (4 + 3 + 3 + 3 =13) 个基本图形组成,第 5 个图案是由 (4 + 3 + 3 + 3 + 3 = 16) 个基本图形组成,据此解决。\n\n【详解】由题意分析得:4+3+3+3+3=16(个)即,如图是一组有规律的图案,第 1 个图案是由 4 个基本图形组成,第 2 个图案是由 7 个基本图形组成,则第 5 个图案是由 16 个基本图形组成.\n\n![](images/Pasted image 20251213174353.png)", + "knowledge_points": [ + "图形的变化规律" + ], + "source": "22-23 二年级下·河南周口·期中" + }, + { + "id": "97", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.85, + "question": "按规律写数.\n\n(1)18,28,( ),( ),58,( ),( ),88,98.\n(2)20,40,( ),80,( )。", + "options": [], + "answer": "38;48;68;78;60;100", + "solution": "【分析】(1)这组数字依次变大,每后一个数比前一个数大 10,也就是从 18 开始,十个十个地正着数,依次填写 38, 48, 68, 78;(2) 这组数字依次变大,每后一个数比前一个数大 20,也就是从 20 开始,二十二十地正着数,依次填写 60, 100。\n\n【详解】(1)18,28,38,48,58,68,78,88,98。(2) 20, 40, 60, 80, 100。", + "knowledge_points": [ + "数 100 以内的数", + "整数排列的规律" + ], + "source": "22-23一年级下·广西柳州·期中" + }, + { + "id": "98", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.65, + "question": "按规律填数.\n\n(1)( ),( ),98,97,( ).\n\n(2)70, 65, 60, ( ), ( )。", + "options": [], + "answer": "100;99;96;55;50", + "solution": "【分析】(1)规律是往后依次减 1,数越来越小,往前依次加 1.\n(2) 规律是:依次减 5 。\n\n【详解】 (1) 97 - 1 = 96, 98 + 1 = 99, 99 + 1 = 100 。故:100,99,98,97,96。(2) 60 - 5 = 55, 55 - 5 = 50 。故: 70, 65, 60, 55, 50。", + "knowledge_points": [ + "整数排列的规律" + ], + "source": "23-24 一年级下·辽宁鞍山·期末" + }, + { + "id": "99", + "unit": "找规律", + "question_type": "判断题", + "difficulty": 0.85, + "question": "○○□○○□○○□○○。接下来应该摆□。()", + "options": [], + "answer": "√", + "solution": "【分析】观察图形可知:这组图形的排列特点是: 3 个图形,一个循环周期,分别按照: ○ ○ □ 依次循环排列,据此解答即可。\n\n【详解】由分析可得,○○□○○□○○□○○□。即接下来应该摆□。原题说法正确。故答案为:√", + "knowledge_points": [ + "图形的变化规律" + ], + "source": "23-24 一年级下·湖北孝感·期末" + }, + { + "id": "100", + "unit": "找规律", + "question_type": "判断题", + "difficulty": 0.65, + "question": "按0,1,3,6,10,15。的规律,下一个数应该是21。()", + "options": [], + "answer": "√", + "solution": "【分析】依次增加 1,2,3,4,5,6,。;据此解决。\n\n【详解】 0 + 1 = 1, 1 + 2 = 3, 3 + 3 = 6, 6 + 4 = 10, 10 + 5 = 15, 15 + 6 = 21;即,按 0,1,3,6,10,15。的规律,下一个数应该是 21;此说法正确。故答案为: √", + "knowledge_points": [ + "整数排列的规律" + ], + "source": "23-24一年级下·河南南阳·期末" + }, + { + "id": "101", + "unit": "找规律", + "question_type": "选择题", + "difficulty": 0.85, + "question": "●■▲●■▲() ■▲,按规律,括号里的图形是()。", + "options": [ + "A. ●", + "B. ■", + "C. ▲" + ], + "answer": "A", + "solution": "【分析】●■▲,这三个图形依次重复出现,即,●■▲●■▲●■▲,据此解决。\n\n【详解】由题意分析得:●■▲●■▲( )■▲,按规律,括号里的图形是●。故答案为:A", + "knowledge_points": [ + "图形的变化规律" + ], + "source": "23-24 一年级下·广东深圳·期末" + }, + { + "id": "102", + "unit": "找规律", + "question_type": "选择题", + "difficulty": 0.65, + "question": "图中被盖住的可能是下面的( )号图.\n\n![](images/Pasted%20image%2020251213175506.png)", + "options": [ + "A. ![](images/Pasted%20image%2020251213175513.png)", + "B. ![](images/Pasted%20image%2020251213175522.png)", + "C. ![](images/Pasted%20image%2020251213175529.png)" + ], + "answer": "A", + "solution": "【分析】图形按 ![](images/Pasted%20image%2020251213180132.png) 的顺序循环排列,一个 ![](images/Pasted%20image%2020251213180150.png) 后面依次是 ![](images/Pasted%20image%2020251213180201.png)。\n\n【详解】图中被盖住的可能是 ![](images/Pasted%20image%2020251213180205.png)。故答案为:A", + "knowledge_points": [ + "图形的变化规律" + ], + "source": "23-24一年级下·新疆哈密·期末" + }, + { + "id": "103", + "unit": "找规律", + "question_type": "选择题", + "difficulty": 0.85, + "question": "\"你,真,棒,你,真,棒,你,真,\",按规律填,应填()。", + "options": [ + "A. 你", + "B. 真", + "C. 棒" + ], + "answer": "C", + "solution": "【分析】题中文字按照你,真,棒为一组重复排列,由此可知真后边应填写棒。\n\n【详解】由分析得:\"你,真,棒,你,真,棒,你,真,\",按规律填,应填棒。故答案为:C", + "knowledge_points": [ + "周期问题" + ], + "source": "23-24 一年级下·广东汕头·期末" + }, + { + "id": "104", + "unit": "找规律", + "question_type": "选择题", + "difficulty": 0.85, + "question": "如图,兰兰的项链有几颗珠子被挡住了,被挡住了( )颗白珠子.\n\n![](images/Pasted%20image%2020251213180822.png)", + "options": [ + "A. 3", + "B. 4", + "C. 5" + ], + "answer": "A", + "solution": "【分析】这些珠子,依次为1白1黑,2白1黑,3白1黑,4白1黑,5白1黑。的顺序排列。第1,2,3,5组是完整的,第4组缺少了3白1黑,由此解答。\n\n【详解】由分析可知,兰兰的项链有几颗珠子被挡住了,被挡住了3颗白珠子。故答案为:A", + "knowledge_points": [ + "图形的变化规律" + ], + "source": "23-24 一年级下·山东济宁·期末" + }, + { + "id": "105", + "unit": "找规律", + "question_type": "选择题", + "difficulty": 0.65, + "question": "按 △ ● □ △ ● □ 的规律摆图形,第10个图形是( )。", + "options": [ + "A. ▲", + "B. ●", + "C. ■" + ], + "answer": "A", + "solution": "【分析】按照\"△ ● □\"三个图形为一组循环,依次列举出来,即可知道第10个图形是△。\n\n【详解】由题意分析得:△ ● □ △ ● □ △ ● □ △ ● □ ……,第10个图形是△。故答案为:A", + "knowledge_points": [ + "图形的变化规律" + ], + "source": "23-24 一年级下·江西九江·期末" + }, + { + "id": "106", + "unit": "找规律", + "question_type": "选择题", + "difficulty": 0.65, + "question": "按规律接着摆,下一个图形是().\n\n![](images/Pasted%20image%2020251213181959.png)", + "options": [ + "A. 正方形", + "B. 三角形", + "C. 圆形" + ], + "answer": "A", + "solution": "【分析】观察已知图形可知,图形按两个正方形,一个三角形,一个圆的顺序循环出现,据此规律得出结论即可。\n\n【详解】根据分析知:下一个图形是□。故答案为:A", + "knowledge_points": [ + "周期问题" + ], + "source": "23-24 一年级下·新疆克孜勒苏·期末" + }, + { + "id": "107", + "unit": "找规律", + "question_type": "选择题", + "difficulty": 0.65, + "question": "![](images/Pasted%20image%2020251213190827.png)( ),括号里应该画()。", + "options": [ + "A. ![](images/Pasted%20image%2020251213190939.png)", + "B. ![](images/Pasted%20image%2020251213190946.png)", + "C. ![](images/Pasted%20image%2020251213190955.png)" + ], + "answer": "C", + "solution": "【分析】前三个图形最下面的圆的个数分别是2,3,4,不断的加1,所以下一个图形最下面圆的个数应该是4+1=5(个)。\n\n【详解】横线上应该画![](images/Pasted%20image%2020251213190955.png)。故答案为:C", + "knowledge_points": [ + "图形的变化规律" + ], + "source": "23-24 一年级下·山西太原·期末" + }, + { + "id": "108", + "unit": "找规律", + "question_type": "选择题", + "difficulty": 0.85, + "question": "被遮挡住的部分是().\n\n![](images/Pasted%20image%2020251213191041.png)", + "options": [ + "A. ![](images/Pasted%20image%2020251213191049.png)", + "B. ![](images/Pasted%20image%2020251213191056.png)", + "C. ![](images/Pasted%20image%2020251213191102.png)" + ], + "answer": "A", + "solution": "【分析】这组珠子中依次有1个圆形1个长方形,2个圆形1个长方形;3个圆形1个长方形;4个圆形1个长方形;5个圆形1个长方形。第1,2,3,5组是完整的,第4组缺少3个圆形,由此解答。\n\n【详解】由分析可知,被遮挡住的部分是![](images/Pasted%20image%2020251213214834.png).\n\n![](images/Pasted%20image%2020251213214841.png)故答案为:A", + "knowledge_points": [ + "图形的变化规律" + ], + "source": "23-24一年级下·内蒙古鄂尔多斯·期末" + }, + { + "id": "109", + "unit": "找规律", + "question_type": "选择题", + "difficulty": 0.65, + "question": "如图是一串有规律的珠子,遮住了7颗珠子,那么一共遮住了( )颗白珠子.\n\n![](images/Pasted%20image%2020251213214852.png)", + "options": [ + "A. 5", + "B. 4", + "C. 2" + ], + "answer": "C", + "solution": "【分析】珠子按![](images/Pasted%20image%2020251213214921.png)的规律循环排列,所以遮![](images/Pasted%20image%2020251213214929.png)住的是,数一数即可求解。\n\n【详解】由分析可知,一共遮住了2颗白珠子。故答案为:C", + "knowledge_points": [ + "图形的变化规律" + ], + "source": "23-24 一年级下·河南濮阳·期末" + }, + { + "id": "110", + "unit": "找规律", + "question_type": "选择题", + "difficulty": 0.65, + "question": "如下图所示,被口遮住的有6颗珠子,其中黑珠子有( )颗.\n\n![](images/Pasted%20image%2020251213214945.png)", + "options": [ + "A. 4", + "B. 5", + "C. 6" + ], + "answer": "B", + "solution": "【分析】由图我们可以发现这串珠子是按照:1白1黑,1白2黑,1白3黑,1白4黑。的顺序穿起来的。\n\n【详解】如图:由图可知,其中黑珠子有5颗。故答案为:B", + "knowledge_points": [ + "间隔问题" + ], + "source": "23-24 一年级下·江西萍乡·期末" + }, + { + "id": "111", + "unit": "找规律", + "question_type": "选择题", + "difficulty": 0.85, + "question": "按规律串珠子,\n\n![](images/Pasted%20image%2020251213215006.png)\n\n中被挡住部分是()。", + "options": [ + "A. ![](images/Pasted%20image%2020251213215015.png)", + "B. ![](images/Pasted%20image%2020251213215335.png)", + "C. ![](images/Pasted%20image%2020251213215347.png)" + ], + "answer": "B", + "solution": "【分析】根据图片可以看出该规律为:一个黑珠子一个白珠子一个黑珠子两个白珠子一个黑珠子三个白珠子,白珠子依次加1,接下来是一个黑珠子四个白珠子,则挡住部分是3个白色珠子。\n\n【详解】由分析可得:挡住部分是三个白色珠子。故答案为:B", + "knowledge_points": [ + "图形的变化规律" + ], + "source": "23-24一年级下·河北邢台·期末" + }, + { + "id": "112", + "unit": "找规律", + "question_type": "选择题", + "difficulty": 0.65, + "question": "按照下面的规律,盒子里可能有( )颗珠子.\n\n![](images/Pasted%20image%2020251213215505.png)", + "options": [ + "A. 2", + "B. 3", + "C. 4" + ], + "answer": "B", + "solution": "【分析】每两颗○之间依次是1颗○,2颗○,3颗○。所以第4颗○后面有4颗○,已经有1颗○,用4减1即可求出还可能有几颗○。\n\n【详解】4 - 1 = 3(颗)按照下面的规律,盒子里可能有3颗珠子.\n\n![](images/Pasted%20image%2020251213215555.png)故答案为:B", + "knowledge_points": [ + "图形的变化规律" + ], + "source": "23-24一年级下·山西阳泉·期末" + }, + { + "id": "113", + "unit": "找规律", + "question_type": "选择题", + "difficulty": 0.65, + "question": "小丁按规律穿了一串手链(如下图),方框中挡住的是().\n\n![](images/Pasted%20image%2020251213215619.png)", + "options": [ + "A. ![](images/Pasted%20image%2020251213215629.png)", + "B. ![](images/Pasted%20image%2020251213215640.png)", + "C. ![](images/Pasted%20image%2020251213215655.png)" + ], + "answer": "B", + "solution": "【分析】图形按![](images/Pasted%20image%2020251213215836.png)的顺序循环排列。\n\n【详解】小丁按规律穿了一串手链(如下图),方框中挡住的是\n\n![](images/Pasted%20image%2020251213215920.png)故答案为:B", + "knowledge_points": [ + "图形的变化规律" + ], + "source": "23-24 一年级下·浙江宁波·期末" + }, + { + "id": "114", + "unit": "找规律", + "question_type": "选择题", + "difficulty": 0.65, + "question": "华华按规律穿了一串珠子,掉了3颗,掉的是().\n\n![](images/Pasted%20image%2020251213215935.png)", + "options": [ + "A. ![](images/Pasted%20image%2020251213215947.png)", + "B. ![](images/Pasted%20image%2020251213215956.png)", + "C. ![](images/Pasted%20image%2020251213220005.png)" + ], + "answer": "A", + "solution": "【分析】这串珠子第1组为1白1黑;第2组为2白1黑;第3组为3白1黑;第4组为4白1黑;第5组为5白1黑。其中第1,2,5组是完整的,第3组缺少1颗白色1颗黑色,第4组缺少1颗白色,由此解答。\n\n【详解】由分析可知,掉的3颗顺序为1颗白色,1颗黑色,1颗白色,也就是![](images/Pasted%20image%2020251213220025.png)。故答案为:A", + "knowledge_points": [ + "图形的变化规律" + ], + "source": "23-24 一年级下·福建福州·期末" + }, + { + "id": "115", + "unit": "找规律", + "question_type": "选择题", + "difficulty": 0.65, + "question": "下面的盒子里有( )颗珠子.\n\n![](images/Pasted%20image%2020251213220038.png)", + "options": [ + "A. 4", + "B. 5", + "C. 6" + ], + "answer": "B", + "solution": "【分析】题中珠子依次为1黑1白,1黑2白,1黑3白。每组都有1颗黑色珠子,白色珠子依次加1,盒子右边为1颗黑色5颗白色,可知盒子里的是1黑4白,由此解答。\n\n【详解】1 + 4 = 5(颗)下面的盒子里有5颗珠子。![](images/Pasted%20image%2020251213220106.png)故答案为:B", + "knowledge_points": [ + "图形的变化规律" + ], + "source": "22-23 一年级下·河北廊坊·期末" + }, + { + "id": "116", + "unit": "找规律", + "question_type": "选择题", + "difficulty": 0.85, + "question": "按照规律,下一个图形是().\n\n![](images/Pasted%20image%2020251213220117.png)", + "options": [ + "A. □", + "B. ○", + "C. △" + ], + "answer": "B", + "solution": "【分析】题中图形按照△ ○ □为一组重复排列,最后一个图形是△,则下一个图形应是○,由此解答。\n\n【详解】由分析可知,按照规律,下一个图形是○。故答案为:B", + "knowledge_points": [ + "图形的变化规律" + ], + "source": "23-24一年级下·山东聊城·期中" + }, + { + "id": "117", + "unit": "找规律", + "question_type": "选择题", + "difficulty": 0.65, + "question": "从1到100,含有数字\"7\"的整数共有( )个。", + "options": [ + "A. 19", + "B. 20", + "C. 21", + "D. 22" + ], + "answer": "A", + "solution": "【分析】从1到10里面含有7,11到20里面含有17,21到30里面含有27,以此类推31到40,41到50,51到60,81到90,91到100,每十个整数里面都有1个整数是含有数字7的整数。从61到70含有67和70两个含7的整数;从71到80含有九个含7的整数,据此解答。\n\n【详解】从1到100,含有数字7的整数有7,17,27,37,47,57,67,70,71,72,73,74,75,76,77,78,79,87,97,一共19个。故答案为:A", + "knowledge_points": [ + "数字排列的规律" + ], + "source": "2011 三年级·全国·竞赛" + }, + { + "id": "118", + "unit": "找规律", + "question_type": "选择题", + "difficulty": 0.85, + "question": "接下来应该摆一个().\n\n![](images/Pasted%20image%2020251213220412.png)", + "options": [ + "A. 球", + "B. 正方体", + "C. 圆柱体" + ], + "answer": "B", + "solution": "【分析】球,正方体,圆柱体,这三个图形依次重复出现,据此解决。\n\n【详解】由题意分析得:![](images/Pasted%20image%2020251213220545.png)![](images/Pasted%20image%2020251213220603.png)\n\n即,接下来应该摆一个![](images/Pasted%20image%2020251213220558.png)故答案为:B", + "knowledge_points": [ + "图形的规律" + ], + "source": "23-24 一年级上·贵州黔西·期末" + }, + { + "id": "119", + "unit": "找规律", + "question_type": "选择题", + "difficulty": 0.65, + "question": "○●○●●○●●● 接下来是()。", + "options": [ + "A. ○", + "B. ●", + "C. 不确定" + ], + "answer": "A", + "solution": "【分析】一个白色圆圈做间隔,把一个黑色圆圈,两个黑色圆圈,三个黑色圆圈。用一个白色圆圈间隔,据此得出结论即可。\n\n【详解】根据分析知,接下来的是白色圆圈。故答案为:A", + "knowledge_points": [ + "图形的规律" + ], + "source": "23-24一年级上·广东河源·期末" + }, + { + "id": "120", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.65, + "question": "找规律.\n(1)80,75,70,65,( ),( ),( ).\n(2)△ ○ □ △ ○ □ △ ○ □ △ ( ) □。", + "options": [], + "answer": "60;55;50 ○", + "solution": "【分析】(1) 规律是:依次减5 (2) 规律是:△ ○ □ 3个图形为一组,依次重复出现。\n\n【详解】(1) 65 - 5 = 60,60 - 5 = 55,55 - 5 = 50。故:80,75,70,65,60,55,50。(2) 三角形接下来是圆。故:△ ○ □ △ ○ □ △ ○ □ △ ○ □。", + "knowledge_points": [ + "整数排列的规律", + "图形的变化规律" + ], + "source": "23-24 一年级下·贵州铜仁·期末" + }, + { + "id": "121", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.65, + "question": "![](images/Pasted%20image%2020251213220845.png) ![](images/Pasted%20image%2020251213220856.png)盖住了4个珠子,其中有个![](images/Pasted%20image%2020251213220916.png),有个![](images/Pasted%20image%2020251213220925.png)。", + "options": [], + "answer": "3;1", + "solution": "【分析】三个黑珠子,一个白珠子这四个图形依次重复出现,故有![](images/Pasted%20image%2020251213221022.png),据此解决。\n\n【详解】由题意分析得:![](images/Pasted%20image%2020251213220845.png) ![](images/Pasted%20image%2020251213220856.png)盖住了4个珠子,其中有3个![](images/Pasted%20image%2020251213220916.png),有1个![](images/Pasted%20image%2020251213220925.png)。", + "knowledge_points": [ + "图形的变化规律" + ], + "source": "23-24一年级下·河北保定·期末" + }, + { + "id": "122", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.85, + "question": "找规律,填一填.\n\n
504840
\n\n
354055
", + "options": [], + "answer": "46;44;42 45", + "solution": "【分析】第1组数字依次变小,每后一个数比前一个数小2,也就是从50开始,两个两个地倒着数,依次填写46,44,42,40。第2组数字依次变大,每后一个数比前一个数大5,依次填写45。\n\n【详解】填写如下:
504846444240
\n\n
35404555
", + "knowledge_points": [ + "数100以内的数", + "整数排列的规律" + ], + "source": "23-24 一年级下·广东深圳·期末" + }, + { + "id": "123", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.65, + "question": "找一找规律,填上适当的数字.\n(1)90,80,70,( ),50,40,( ),20,10.\n(2)4,7,10,13,( ),( ),22,25,28,31。", + "options": [], + "answer": "60;30 16;19", + "solution": "【分析】(1) 这一组都是整十数,并且是逐渐变小的,相邻的两个数之间,用前面的数减10等于后面的数,也可以通过数数的方法从后往前10个10个的数;(2) 这组数是逐渐变大的,相邻的两个数之间,前面的数加3等于后面的数,也可以通过3个3个的数,据此解答。\n\n【详解】(1) 90,80,70,(60),50,40,(30),20,10。(2) 4,7,10,13,(16),(19),22,25,28,31。", + "knowledge_points": [ + "整数排列的规律" + ], + "source": "23-24 一年级下·广东汕头·期末" + }, + { + "id": "124", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.85, + "question": "找规律,填一填:\n30,32,( ),( ),38,( ).\n65,60,( ),( ),( ),40。", + "options": [], + "answer": "34;36;40;55;50;45", + "solution": "【分析】从30开始,两个两个地数,数到40;从65开始,五个五个地倒着数,数到40。\n\n【详解】30,32,34,36,38,40.65,60,55,50,45,40。", + "knowledge_points": [ + "数100以内的数", + "整数排列的规律" + ], + "source": "23-24一年级下·广东梅州·期末" + }, + { + "id": "125", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.85, + "question": "按规律填数.\n(1)2,4,( ),8,( ).\n(2)10,20,( ),40,( )。", + "options": [], + "answer": "6;10 30;50", + "solution": "【分析】(1) 后一个数比前一个数多2;(2) 后一个数比前一个数多10;据此解决。\n\n【详解】(1) 4 + 2 = 6,8 + 2 = 10,即2,4,6,8,10。(2) 20 + 10 = 30,40 + 10 = 50,即10,20,30,40,50。", + "knowledge_points": [ + "6的加减法", + "10的加减法", + "整十数之间的加减法", + "整数排列的规律" + ], + "source": "23-24 一年级下·广东汕头·期末" + }, + { + "id": "126", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.65, + "question": "找规律填数.\n(1)7,9,11,13,( ),( ).\n(2)( ),45,40,35,30,( )。", + "options": [], + "answer": "15;17 50;25", + "solution": "【分析】(1) 后一个数比前一个数多2;(2) 后一个数比前一个数少5,前一个数比后一个数多5;据此解决。\n\n【详解】(1) 13 + 2 = 15,15 + 2 = 17,即7,9,11,13,15,17。(2) 45 + 5 = 50,30 - 5 = 25,即50,45,40,35,30,25。", + "knowledge_points": [ + "不进位加法(20以内)", + "整十数加,减一位数", + "一位数与两位数的退位减法", + "整数排列的规律" + ], + "source": "23-24 一年级下·广西玉林·期末" + }, + { + "id": "127", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.85, + "question": "按规律填一填.\n(1)6,16,26,( ),( ),56,66.\n(2)90,85,80,( ),70,( ),60.\n(3)☆☆♡☆☆♡☆☆♡☆,( ),( )。", + "options": [], + "answer": "36;46 75;65 ☆;♡", + "solution": "【分析】(1) 前面的数依次加上10等于后面的数;(2) 前面的数依次减去5等于后面的数;(3) 按照\"☆☆♡\"3个图形为一组的规律排列,据此解答。\n\n【详解】(1) 6+10=16,16+10=26,26+10=36,36+10=46,46+10=56,56+10=66,即6,16,26,(36),(46),56,66。(2) 90-5=85,85-5=80,80-5=75,75-5=70,70-5=65,65-5=60,即90,85,80,(75),70,(65),60。(3) ☆☆♡☆☆♡☆☆♡☆☆♡。", + "knowledge_points": [ + "整数排列的规律", + "图形的变化规律" + ], + "source": "23-24一年级下·浙江宁波·期末" + }, + { + "id": "128", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.65, + "question": "按规律填一填.\n(1)5,8,11,( ),( ),( ),( ).\n(2)97,87,77,( ),( ),( ),( ).\n(3)33连续加7:( ),( ),( ),( ),( ).\n(4)82连续减9:( ),( ),( ),( ),( )。", + "options": [], + "answer": "14;17;20;23 67;57;47;37 40;47;54;61;68 73;64;55;46;37", + "solution": "【分析】(1) 从左往右依次加3。(2) 从左往右依次减10。(3) 从左往右依次加7。(4) 从左往右依次减9。\n\n【详解】(1) 11 + 3 = 14,14 + 3 = 17,17 + 3 = 20,20 + 3 = 23,则5,8,11,(14),(17),(20),(23)。(2) 77 - 10 = 67,67 - 10 = 57,57 - 10 = 47,47 - 10 = 37,则97,87,77,(67),(57),(47),(37)。(3) 33 + 7 = 40,40 + 7 = 47,47 + 7 = 54,54 + 7 = 61,61 + 7 = 68,则(40),(47),(54),(61),(68)。(4) 82 - 9 = 73,73 - 9 = 64,64 - 9 = 55,55 - 9 = 46,46 - 9 = 37,则(73),(64),(55),(46),(37)。", + "knowledge_points": [ + "两位数与整十数的减法", + "一位数与两位数的进位加法", + "一位数与两位数的退位减法", + "整数排列的规律" + ], + "source": "23-24一年级下·新疆昌吉·期末" + }, + { + "id": "129", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.65, + "question": "按规律填一填.\n(1)7,17,27,( ),( ),( ),67.\n(2)○ △ ○ △ ○ △ ○ …… 按这样的规律,从左边数起第20个是( ).\n(3)按21-3,22-4,23-5……这样的规律往下写,第4个算式是( )。", + "options": [], + "answer": "37;47;57 △ 24-6=18", + "solution": "【分析】(1) 规律是:依次加上10;(2) 按照\"1个○ 1个△\"两个图形为一组循环,第20个图形是这一组中第二个图形△;(3) 规律是:一组中前、后两个数字等于相邻前面一组前、后两个数字分别加上1。\n\n【详解】(1) 27 + 10 = 37;37 + 10 = 47;47 + 10 = 57,故7,17,27,37,47,57,67。(2) 从左边数起第20个是△。(3) 23 + 1 = 24,5 + 1 = 6,第4个算式是24-6=18。", + "knowledge_points": [ + "整数排列的规律", + "图形的变化规律" + ], + "source": "23-24一年级下·浙江台州·期末" + }, + { + "id": "130", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.65, + "question": "找规律.\n(1)99,88,( ),( ),55,( ).\n(2)45,( ),55,60,( ),( )。", + "options": [], + "answer": "77;66;44 50;65;70", + "solution": "【分析】(1) 这组数字十位和个位相同,后一个数十位和个位上的数比前一个数小1,依次填写77,66,44;(2) 这组数字依次变大,每后一个数比前一个数大5,依次填写50,65,70。\n\n【详解】(1) 99,88,77,66,55,44。(2) 45,50,55,60,65,70。", + "knowledge_points": [ + "整数排列的规律" + ], + "source": "23-24 一年级下·河南周口·期末" + }, + { + "id": "131", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.85, + "question": "按规律填数.\n\n
707278
", + "options": [], + "answer": "74;76;80", + "solution": "【分析】题中数字依次变大,每后一个数比前一个数大2。72 + 2 = 74;74 + 2 = 76;78 + 2 = 80。依次填写74,76,80。\n\n【详解】填写如下:\n\n
707274767880
", + "knowledge_points": [ + "一位数与两位数的进位加法", + "一位数与两位数的退位减法", + "整数排列的规律" + ], + "source": "23-24 一年级下·江西九江·期末" + }, + { + "id": "132", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.65, + "question": "找规律,填一填.\n(1)97,93,89,85,( ),( ).\n(2)21,28,35,42,( ),( )。", + "options": [], + "answer": "81;77 49;56", + "solution": "【分析】(1) 这组数字依次变小,每后一个数比前一个数小4,85 - 4 = 81;81 - 4 = 77,依次填写81,77;(2) 这组数字依次变大,每后一个数比前一个数大7,42 + 7 = 49;49 + 7 = 56,依次填写49,56。\n\n【详解】(1) 97,93,89,85,81,77。(2) 21,28,35,42,49,56。", + "knowledge_points": [ + "整数排列的规律" + ], + "source": "23-24 一年级下·山东菏泽·期末" + }, + { + "id": "133", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.65, + "question": "找规律接着填数或画图.\n(1)80,75,70,( ),( ).\n(2)△ □ □ △ □ □ △ □ □ △( )。", + "options": [], + "answer": "65;60 □", + "solution": "【分析】(1) 规律是不断的减5;(2) △ □ □为一组,依次重复出现。\n\n【详解】(1) 70 - 5 = 65,65 - 5 = 60。(2) △ □ □ △ □ □ △ □ □ △ □。", + "knowledge_points": [ + "整数排列的规律", + "图形的变化规律" + ], + "source": "23-24 一年级下·山东菏泽·期末" + }, + { + "id": "134", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.65, + "question": "按规律填空.\n90,85,80,( ),70,( ),( )。", + "options": [], + "answer": "75;65;60", + "solution": "【分析】从90开始5个5个倒着数,然后填入缺少的数字即可。\n\n【详解】90,85,80,75,70,65,60。", + "knowledge_points": [ + "整数排列的规律", + "周期问题" + ], + "source": "23-24 一年级下·甘肃平凉·期末" + }, + { + "id": "135", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.85, + "question": "按规律填空.\n65,60,( ),( ),45,40,( ).\n22,25,( ),( ),34,( ),( )。", + "options": [], + "answer": "55;50;35 28;31;37;40", + "solution": "【分析】第1组数字依次变小,每后一个数比前一个数小5,也就是从65开始,五个五个地倒着数;第2组数字依次变大,每后一个数比前一个数大3,也就是从22开始,三个三个地往后数。\n\n【详解】65,60,55,50,45,40,35;22,25,28,31,34,37,40。", + "knowledge_points": [ + "数100以内的数", + "整数排列的规律" + ], + "source": "23-24 一年级下·湖南益阳·期末" + }, + { + "id": "136", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.85, + "question": "填数.\n31,33,( ),37,39,41,( )。", + "options": [], + "answer": "35;43", + "solution": "【分析】后一个数比前一个数多2,即31,33,35,37,39,41,43;据此解决。\n\n【详解】由题意分析得:31,33,35,37,39,41,43。", + "knowledge_points": [ + "整数排列的规律" + ], + "source": "23-24 一年级下·浙江杭州·期末" + }, + { + "id": "137", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.65, + "question": "按规律画一画.\n△☆☆○△☆☆○△☆☆( )△☆", + "options": [], + "answer": "○", + "solution": "【分析】这组图形按照△☆☆○为一组重复排列,已经排列了完整的两组,第三组△☆☆,接下来应该是○。据此解答。\n\n【详解】已经排列了两组,第三组△☆☆,接下来应该是完整的排列为:△☆☆○△☆☆○△☆☆○△☆。故答案为:○", + "knowledge_points": [ + "图形的变化规律" + ], + "source": "23-24一年级下·浙江杭州·期末" + }, + { + "id": "138", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.85, + "question": "按规律填数.\n(1)15,20,25,30,35,( ),( ).\n(2)50,( ),46,44,42,40,( )。", + "options": [], + "answer": "40;45 48;38", + "solution": "【分析】(1) 这组数字依次变大,每后一个数比前一个数大5,也就是从15开始,五个五个地往后数;(2) 这组数字依次变小,每后一个数比前一个数小2,也就是从50开始,两个两个地往前数。\n\n【详解】(1) 15,20,25,30,35,40,45。(2) 50,48,46,44,42,40,38。", + "knowledge_points": [ + "数100以内的数", + "整数排列的规律" + ], + "source": "23-24 一年级下·广东潮州·期末" + }, + { + "id": "139", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.65, + "question": "找规律填数.\n\n
384041
10095
", + "options": [], + "answer": "39;42 90;85;80", + "solution": "【分析】观察已知数据可得:第一行的规律是从左到右不断加1;第二行的规律是从左到右不断减5。\n\n【详解】38 + 1 = 39,41 + 1 = 42;95 - 5 = 90,90 - 5 = 85,85 - 5 = 80.\n\n
3839404142
10095908580
", + "knowledge_points": [ + "两位数与一位数的加法(不进位)", + "两位数与一位数的减法(不退位)", + "一位数与两位数的退位减法", + "整数排列的规律" + ], + "source": "23-24 一年级下·新疆克孜勒苏·期末" + }, + { + "id": "140", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.85, + "question": "按规律填数.\n(1)5,15,( ),( ),45.\n(2)70,68,( ),( ),62。", + "options": [], + "answer": "25;35 66;64", + "solution": "【分析】(1) 这组数字依次变大,每后一个数比前一个数大10,也就是从5开始,十个十个地往后数;(2) 这组数字依次变小,每后一个数比前一个数小2,也就是从70开始,两个两个地往前数。\n\n【详解】(1) 5,15,25,35,45。(2) 70,68,66,64,62。", + "knowledge_points": [ + "数100以内的数", + "整数排列的规律" + ], + "source": "23-24 一年级下·广东揭阳·期末" + }, + { + "id": "141", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.85, + "question": "找规律填数.\n(1)5,10,5,10,5,10,( ),( ).\n(2)100,90,80,( ),60,( ),40。", + "options": [], + "answer": "5;10 70;50", + "solution": "【分析】(1) 这组数字按照5,10为一组重复排列;(2) 这组数字依次变小,每后一个数比前一个数小10,也就是从100开始,十个十个地倒着数。\n\n【详解】(1) 5,10,5,10,5,10,5,10。(2) 100,90,80,70,60,50,40。", + "knowledge_points": [ + "整数排列的规律" + ], + "source": "23-24一年级下·湖南怀化·期末" + }, + { + "id": "142", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.65, + "question": "下图中盒子遮住了( )颗珠子.\n\n![](images/Pasted%20image%2020251214144711.png)", + "options": [], + "answer": "5", + "solution": "【分析】珠子的摆放规律是:1黑,1白,1黑,2白,1黑,3白,1黑,4白,1黑,5白,1黑,。;据此解决。\n\n【详解】由题意分析得:图中盒子遮住了4个白珠子,1个黑珠子,4+1=5(个)。即图中盒子遮住了5颗珠子。", + "knowledge_points": [ + "5以内数的加法", + "图形的变化规律" + ], + "source": "23-24 一年级下·陕西安康·期末" + }, + { + "id": "143", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.65, + "question": "找规律,填一填,画一画.\n(1)97,83,69,( ),( ),27,( ).\n(2)14,30,21,37,28,44,( ),( ).\n(3)△ ○ △ ○ ○ △ ○ ○ ○,( ),( ),( )(每个括号里画一个图形)。", + "options": [], + "answer": "55;41;13 35;51 △;○;○", + "solution": "【分析】(1) 这组数字依次变小,每后一个数比前一个数小14;(2) 规律是依次加16,减9;(3) 一个三角形一个圆形,一个三角形两个圆形,一个三角形三个圆形,圆形个数依次加1。\n\n【详解】(1) 69-14=55,55-14=41,41-14=27,27-14=13,这组数字是:97,83,69,55,41,27,13。(2) 44-9=35,35+16=51,这组数字是:14,30,21,37,28,44,35,51。(3) 接下来应该是△ ○ ○ ○(一个三角形四个圆形),题目只给了3个空,所以应该画△ ○ ○(每个括号里画一个图形).\n\n即这组图形是:△ ○ △ ○ ○ △ ○ ○ △ ○ ○。", + "knowledge_points": [ + "整数排列的规律", + "图形的变化规律" + ], + "source": "23-24 一年级下·河北邢台·期末" + }, + { + "id": "144", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.65, + "question": "如图:按规律画一画.\n\n△ ○ □ △ ○ □,( ),( )。", + "options": [], + "answer": "△;○", + "solution": "【分析】按三角形,圆形,正方形的顺序循环出现,依次规律画出缺少的图形即可。\n\n【详解】△ ○ □ △ ○ □,△ ○", + "knowledge_points": [ + "图形的变化规律", + "周期问题" + ], + "source": "23-24 一年级下·湖南怀化·期末" + }, + { + "id": "145", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.65, + "question": "按规律,填出最后一个时刻.\n9:30,10:00,10:30,( )。", + "options": [], + "answer": "11:00", + "solution": "【分析】从第二个时刻开始,每个时刻都比前一个时刻多30分钟,据此得出结论即可。\n\n【详解】根据分析知:9:30,10:00,10:30,11:00。", + "knowledge_points": [ + "时,分,秒时间的推算", + "周期问题" + ], + "source": "23-24 一年级下·广西贵港·期末" + }, + { + "id": "146", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.65, + "question": "找规律填数:\n14,18,22,26,( ),( ),( ).\n34,33,32,31,( ),( ),( )。", + "options": [], + "answer": "30;34;38 30;29;28", + "solution": "【分析】第一行从14开始4个4个数;第二行从34开始1个1个倒着数;然后填入缺少的数。\n\n【详解】14,18,22,26,30,34,38;34,33,32,31,30,29,28。", + "knowledge_points": [ + "整数排列的规律" + ], + "source": "23-24 一年级下·山东临沂·期末" + }, + { + "id": "147", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.65, + "question": "找规律填数.\n(1)16,19,22,( ),( ),31.\n(2)80,75,70,65,60,( ),( )。", + "options": [], + "answer": "25;28 55;50", + "solution": "【分析】(1) 从16开始3个3个地数;(2) 从80开始5个5个地倒着数;然后填入缺少的数。\n\n【详解】(1) 16,19,22,25,28,31。(2) 80,75,70,65,60,55,50。", + "knowledge_points": [ + "整数排列的规律" + ], + "source": "23-24 一年级下·江西萍乡·期末" + }, + { + "id": "148", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.85, + "question": "找规律填一填.\n43,45,47,( ),( ),( )。", + "options": [], + "answer": "49;51;53", + "solution": "【分析】题中数依次变大,每后一个数比前一个数大2:43+2=45,45+2=47,47+2=49,49+2=51,51+2=53;依次填写49,51,53。\n\n【详解】43,45,47,49,51,53。", + "knowledge_points": [ + "两位数与一位数的加法(不进位)", + "一位数与两位数的进位加法", + "整数排列的规律" + ], + "source": "23-24 一年级下·广东东莞·期末" + }, + { + "id": "149", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.65, + "question": "按规律填一填.\n(1)△△□△△□△( ) ( ) ( ).\n(2)70,65,60,( ),( ),45,( )。", + "options": [], + "answer": "△;□;△ 55;50;40", + "solution": "【分析】(1) 这组图形按照△△□为一组重复排列;(2) 这组数依次变小,每后一个数比前一个数小5,也就是从70开始五个五个地倒着数。\n\n【详解】(1) △△□△△□△△□△。(2) 70,65,60,55,50,45,40。", + "knowledge_points": [ + "整数排列的规律", + "图形的变化规律" + ], + "source": "23-24 一年级下·浙江宁波·期末" + }, + { + "id": "150", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.85, + "question": "按规律填数.\n11,14,17,20,( ),( ),( )。", + "options": [], + "answer": "23;26;29", + "solution": "【分析】题中数字依次变大,每后一个数比前一个数大3:11+3=14,14+3=17,17+3=20。据此依次填写。\n\n【详解】11,14,17,20,23,26,29。", + "knowledge_points": [ + "整数排列的规律" + ], + "source": "23-24 一年级下·河北邯郸·期末" + }, + { + "id": "151", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.85, + "question": "找规律,接着写,接着画.\n(1)68,60,52,44,( ),( ).\n(2)□ △ ○ □ △ ○ □ △ ○,( ),△,( )。", + "options": [], + "answer": "36;28 □;○", + "solution": "【分析】(1) 相邻两数相差8,规律是后一个数=前一个数-8;(2) 图形按□△○的顺序循环。\n\n【详解】(1) 44-8=36,36-8=28,所以68,60,52,44,(36),(28)。(2) 最后一个是○,所以下一个是一个循环中的□,因此填(□);△之后应是(○)。", + "knowledge_points": [ + "整数排列的规律", + "图形的变化规律" + ], + "source": "23-24 一年级下·湖南岳阳·期末" + }, + { + "id": "152", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.65, + "question": "箱子中有( )颗,( )颗.\n\n![](images/Pasted%20image%2020251214145422.png)", + "options": [], + "answer": "2;4", + "solution": "【分析】珠子的排列顺序是一颗白色珠子2颗黑色珠子,2颗白色珠子2颗黑色珠子,3颗白色珠子2颗黑色珠子,4颗白色珠子2颗黑色珠子,5颗白色珠子2颗黑色珠子。据此得出箱子里的珠子。\n\n【详解】根据分析知:箱子中有2颗●,4颗○。", + "knowledge_points": [ + "间隔问题" + ], + "source": "23-24 一年级下·广东江门·期末" + }, + { + "id": "153", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.65, + "question": "找规律填数.\n(1)57,55,53,( ),( ),47.\n(2)△○○△○○△○( ) ( ) ○。", + "options": [], + "answer": "51;49 ○;△", + "solution": "【分析】(1) 这组数字依次变小,每后一个数比前一个数小2;(2) 图形按照△○○为一组重复排列。\n\n【详解】(1) 57,55,53,51,49,47。(2) △○○△○○△○○△○。", + "knowledge_points": [ + "数100以内的数", + "整数排列的规律", + "图形的变化规律" + ], + "source": "23-24 一年级下·福建福州·期末" + }, + { + "id": "154", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.85, + "question": "按规律接着画一画.\n△○○△○○△○○△○( ) ( )。", + "options": [], + "answer": "○;△", + "solution": "【分析】观察题干可知:这列图形的排列规律是1个△,2个○为一组进行排列。\n\n【详解】△OO△OO△OO△O O△", + "knowledge_points": [ + "图形的变化规律" + ], + "source": "23-24一年级下·河南南阳·期末" + }, + { + "id": "155", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.65, + "question": "找规律填数.\n(1)42,45,48,( ),( ),57.\n(2)98,90,82,( ),( )。", + "options": [], + "answer": "51;54 74;66", + "solution": "【分析】(1) 这组数字依次变大,每后一个数比前一个数大3;(2) 这组数字依次变小,每后一个数比前一个数小8。\n\n【详解】(1) 42,45,48,51,54,57。(2) 98,90,82,74,66。", + "knowledge_points": [ + "整数排列的规律" + ], + "source": "23-24 一年级下·河南南阳·期末" + }, + { + "id": "156", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.65, + "question": "一共遮住了4个珠子,有( )个●,( )个○.\n\n![](images/Pasted%20image%2020251214145722.png)", + "options": [], + "answer": "2;2", + "solution": "【分析】两个白圆圈两个黑圆圈循环出现,按此规律补图得出结论。\n\n【详解】根据分析补图如下:![](images/Pasted%20image%2020251214145732.png)故一共遮住了4个珠子,有2个●,2个○。", + "knowledge_points": [ + "间隔问题" + ], + "source": "23-24一年级下·福建福州·期末" + }, + { + "id": "157", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.85, + "question": "找规律.\n(1)44,42,40,( ),( ),( ).\n(2)○ □ △ ○ □ △( ),( ),( )。", + "options": [], + "answer": "38;36;34 ○;□;△", + "solution": "【分析】(1) 这组数字依次变小,每后一个数比前一个数小2;(2) 这组图形按\"○ □ △\"为一组重复排列。\n\n【详解】(1) 44,42,40,38,36,34。(2) ○ □ △ ○ □ △ ○ □ △。", + "knowledge_points": [ + "数100以内的数", + "整数排列的规律", + "图形的变化规律" + ], + "source": "23-24 一年级下·江西宜春·期末" + }, + { + "id": "158", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.85, + "question": "找规律,填一填.\n(1)83,81,79,77,( ),( ).\n(2)△○○△○○△○○△( ) ( )。", + "options": [], + "answer": "75;73 ○;○", + "solution": "【分析】(1) 该组规律为:从左到右依次减2;(2) 按照△○○为一组重复出现的规律进行排列。\n\n【详解】(1) 83,81,79,77,(75),(73)。(2) △○○△○○△○○△(○)(○)。", + "knowledge_points": [ + "两位数与两位数的不退位减法", + "一位数与两位数的退位减法", + "整数排列的规律", + "图形的变化规律" + ], + "source": "23-24一年级下·河南新乡·期末" + }, + { + "id": "159", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.85, + "question": "![](images/Pasted%20image%2020251214150136.png)遮住了6颗珠子,其中有( )颗黑珠子,( )颗白珠子.\n\n![](images/Pasted%20image%2020251214150308.png)", + "options": [], + "answer": "4;2", + "solution": "【分析】这组珠子按照2颗白色,3颗黑色为一组重复排列。前边有完整的2组,一共缺少6颗,可知第3组缺少2颗黑色,第4组缺少2颗白色,2颗黑色,由此解答。\n\n【详解】由分析可知,![](images/Pasted%20image%2020251214150255.png)遮住了6颗珠子,其中有4颗黑珠子,2颗白珠子。", + "knowledge_points": [ + "图形的变化规律" + ], + "source": "23-24一年级下·河南信阳·期末" + }, + { + "id": "160", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.65, + "question": "按规律填数或画图.\n(1)6,16,26,36,( ),( ).\n(2)1,8,15,( ),( ).\n(3)○ △ ○ △ △ ○ △ △ △( )( )( )( )( )( )( )。", + "options": [], + "answer": "46;56 22;29 ○;△;△;△;△;△", + "solution": "【分析】(1) 每后一个数比前一个数大10;(2) 每后一个数比前一个数大7;(3) 每组都有1个○,每后一组三角形的数量比前一组多1。\n\n【详解】(1) 6,16,26,36,46,56。(2) 1,8,15,22,29。(3) ○△○△△○△△△○△△△△△。", + "knowledge_points": [ + "一位数与两位数的进位加法", + "整数排列的规律", + "图形的变化规律" + ], + "source": "23-24 一年级下·河南信阳·期末" + }, + { + "id": "161", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.65, + "question": "在括号内填适当的数.\n(1)2,4,6,8,( ),( ).\n(2)50,45,40,35,( ),( )。", + "options": [], + "answer": "10;12 30;25", + "solution": "【分析】(1) 这组数字依次变大,每后一个数比前一个数大2;(2) 这组数字依次变小,每后一个数比前一个数小5。\n\n【详解】(1) 2,4,6,8,10,12。(2) 50,45,40,35,30,25。", + "knowledge_points": [ + "数100以内的数", + "整数排列的规律" + ], + "source": "23-24 一年级下·河南周口·期末" + }, + { + "id": "162", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.65, + "question": "被挡住了( )个图形,其中有( )个![](images/Pasted%20image%2020251214150658.png),( )个![](images/Pasted%20image%2020251214150709.png).\n\n![](images/Pasted%20image%2020251214150646.png)", + "options": [], + "answer": "4;3;1", + "solution": "【分析】第1组为1个三角形1个圆形;第2组为1个三角形2个圆形;第3组为1个三角形3个圆形;第4组为1个三角形4个圆形;第5组为1个三角形5个圆形。其中第1,2,5组是完整的,第3组缺少3个圆形,第4组缺少1个三角形,由此解答。\n\n【详解】由分析可知,被挡住了4个图形,其中有3个圆形,1个三角形。![](images/Pasted%20image%2020251214150739.png)", + "knowledge_points": [ + "图形的变化规律" + ], + "source": "23-24 一年级下·河南郑州·期末" + }, + { + "id": "163", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.65, + "question": "找规律,填一填.\n83,81,79,77,( ),( ),( ),( ),( )。", + "options": [], + "answer": "75;73;71;69;67", + "solution": "【分析】规律是:后一个数比前一个数少2;也就是83,81,79,77,75,73,71,69,67;据此解决。\n\n【详解】由题意分析得:83,81,79,77,75,73,71,69,67。", + "knowledge_points": [ + "整数排列的规律" + ], + "source": "23-24 一年级下·河南郑州·期末" + }, + { + "id": "164", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.65, + "question": "按规律写一写,画一画.\n(1)( ),( ),39,44,49.\n(2)□○○□○○□( )( )。", + "options": [], + "answer": "29;34 ○;○", + "solution": "【分析】(1) 这组数字依次变大,每后一个数比前一个数大5;39-5=34,34-5=29;(2) 这组图形按\"□○○\"为一组重复排列。\n\n【详解】(1) 29,34,39,44,49。(2) □○○□○○□○○。", + "knowledge_points": [ + "一位数与两位数的退位减法", + "整数排列的规律", + "图形的变化规律" + ], + "source": "22-23一年级下·重庆潼南·期末" + }, + { + "id": "165", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.65, + "question": "找规律填一填.\n(1)△△□△△□( )( ).\n(2)1,4,7,10,( ),( ),( )。", + "options": [], + "answer": "△;△;□ 13;16;19", + "solution": "【分析】(1) △△□三个图形依次重复出现;(2) 后一个数比前一个数多3。\n\n【详解】(1) △△□△△□△△□。(2) 1,4,7,10,13,16,19。", + "knowledge_points": [ + "整数排列的规律", + "图形的变化规律" + ], + "source": "22-23一年级下·浙江杭州·期末" + }, + { + "id": "166", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.65, + "question": "按规律填数.\n(1)46,49,( ),( ),58.\n(2)81,82,83,( ),( ),( )。", + "options": [], + "answer": "52;55 84;85;86", + "solution": "【分析】(1) 后一个数比前一个数多3;(2) 后一个数比前一个数多1。\n\n【详解】(1) 46,49,52,55,58。(2) 81,82,83,84,85,86。", + "knowledge_points": [ + "整数排列的规律" + ], + "source": "22-23 一年级下·山西运城·期末" + }, + { + "id": "167", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.65, + "question": "按规律填数.\n(1)34,42,50,( ),66,( ),( ).\n(2)10,19,28,( ),46,( ),( )。", + "options": [], + "answer": "58;74;82 37;55;64", + "solution": "【分析】(1) 这组数字依次变大,每后一个数比前一个数多8;(2) 这组数字依次变大,每后一个数比前一个数多9。\n\n【详解】(1) 34,42,50,58,66,74,82。(2) 10,19,28,37,46,55,64。", + "knowledge_points": [ + "一位数与两位数的进位加法", + "整数排列的规律" + ], + "source": "22-23 一年级下·河北沧州·期末" + }, + { + "id": "168", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.65, + "question": "按规律填一填.\n13,15,17,19,( ),( ),( )。", + "options": [], + "answer": "21;23;25", + "solution": "【分析】通过观察这些数是逐渐变大的,前面一个数+2=后面的数,据此解答。\n\n【详解】13+2=15,15+2=17,17+2=19,19+2=21,21+2=23,23+2=25.13,15,17,19,(21),(23),(25)。", + "knowledge_points": [ + "整数排列的规律" + ], + "source": "22-23 一年级下·河北廊坊·期末" + }, + { + "id": "169", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.85, + "question": "
32( )34( )36
9490( )82( )
", + "options": [], + "answer": "33;35;86;78", + "solution": "【分析】第一行:34和32相差2,它们之间有2个间隔,所以每个间隔是1,数字从左往右依次增加1。第二行:94和90相差4,82和90相差8,它们之间有2个间隔,所以每个间隔是4,数字从左往右依次减少4。\n\n【详解】32+1=33,34+1=35,90-4=86,82-4=78.\n\n
32(33)34(35)36
9490(86)82(78)
", + "knowledge_points": [ + "两位数与一位数的加法(不进位)", + "一位数与两位数的退位减法", + "整数排列的规律" + ], + "source": "23-24 一年级下·全国·期末" + }, + { + "id": "170", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.65, + "question": "按规律写数或画图.\n(1)98,96,94,( ),90,( ).\n(2)○ □ △ ○ □ △ ○,( ),( )。", + "options": [], + "answer": "92;88 □;△", + "solution": "【分析】(1)这组数字依次减小,每后一个数比前一个数小2;(2)这组图形按照\"○ □ △\"为一组重复排列。\n\n【详解】(1)98,96,94,92,90,88。(2)○ □ △ ○ □ △ ○ □ △。", + "knowledge_points": [ + "整数排列的规律", + "图形的变化规律" + ], + "source": "23-24 一年级下·广东韶关·期中" + }, + { + "id": "171", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.85, + "question": "按规律填数:\n12,16,20,( ),28,( )。", + "options": [], + "answer": "24;32", + "solution": "【分析】后一个数比前一个数多4,据此解决。\n\n【详解】12+4=16,16+4=20,20+4=24,24+4=28,28+4=32,即12,16,20,24,28,32。", + "knowledge_points": [ + "不进位加法(20以内)", + "整十数加,减一位数", + "一位数与两位数的进位加法", + "整数排列的规律" + ], + "source": "23-24 二年级下·广东韶关·期中" + }, + { + "id": "172", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.65, + "question": "按规律填数.\n(1)( ),90,( ),70,( ).\n(2)( ),38,( ),42,44。", + "options": [], + "answer": "100;80;60 36;40", + "solution": "【分析】(1)从100开始,一十,一十地倒着数,数到60;(2)从36开始,两个两个地正着数,数到44。\n\n【详解】(1)100,90,80,70,60。(2)36,38,40,42,44。", + "knowledge_points": [ + "数100以内的数", + "整数排列的规律" + ], + "source": "23-24 一年级下·河南驻马店·期中" + }, + { + "id": "173", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.85, + "question": "85,80,75,( ),( ),( ),( ),50,( ),( )。", + "options": [], + "answer": "70;65;60;55;45;40", + "solution": "【分析】该组规律是从左到右,数字依次减5。\n\n【详解】75-5=70,70-5=65,65-5=60,60-5=55,55-5=50,50-5=45,45-5=40。填空后为:85,80,75,70,65,60,55,50,45,40。", + "knowledge_points": [ + "整十数加,减一位数", + "两位数与一位数的减法(不退位)", + "整数排列的规律" + ], + "source": "23-24一年级下·广东汕头·期中" + }, + { + "id": "174", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.65, + "question": "想一想,再填数.\n(1)3,13,( ),( ),43.\n(2)6,14,16,24,26,34,( )。", + "options": [], + "answer": "23;33 36", + "solution": "【分析】(1)后一个数比前一个数多10;(2)第1,3,5,7个数依次加10,第2,4,6个数也依次加10。\n\n【详解】(1)3+10=13,13+10=23,23+10=33,33+10=43,即3,13,23,33,43。(2)6+10=16,16+10=26,26+10=36,14+10=24,24+10=34,即6,14,16,24,26,34,36。", + "knowledge_points": [ + "两位数与整十数的加法", + "整数排列的规律" + ], + "source": "23-24一年级下·河南驻马店·期中" + }, + { + "id": "175", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.65, + "question": "按规律填数.\n(1)10,15,20,( ),( ),35,( ),( ).\n(2)36,34,32,30,( ),26,( ),( )。", + "options": [], + "answer": "25;30;40;45 28;24;22", + "solution": "【分析】(1)每后一个数比前一个数大5;(2)每后一个数比前一个数小2。\n\n【详解】(1)10,15,20,25,30,35,40,45。(2)36,34,32,30,28,26,24,22。", + "knowledge_points": [ + "整数排列的规律" + ], + "source": "23-24 一年级下·广东佛山·期中" + }, + { + "id": "176", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.85, + "question": "按规律填数.\n82,81,80,79,( ),( )。", + "options": [], + "answer": "78;77", + "solution": "【分析】后一个数比前一个数少1,即82,81,80,79,78,77。\n\n【详解】由题意分析得:82,81,80,79,78,77。", + "knowledge_points": [ + "整数排列的规律" + ], + "source": "23-24 二年级下·福建三明·期中" + }, + { + "id": "177", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.65, + "question": "按规律填数.\n(1)4,8,12,( ),( ).\n(2)20,16,12,( ),( )。", + "options": [], + "answer": "16;20 8;4", + "solution": "【分析】(1)后一个数比前一个数多4;(2)后一个数比前一个数少4。\n\n【详解】(1)4+4=8,8+4=12,12+4=16,16+4=20,即4,8,12,16,20。(2)20-4=16,16-4=12,12-4=8,8-4=4,即20,16,12,8,4。", + "knowledge_points": [ + "不退位减法(20以内)", + "十几减5~2的退位减法", + "8加几的进位加法", + "整数排列的规律" + ], + "source": "22-23 一年级下·广东江门·期中" + }, + { + "id": "178", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.65, + "question": "找规律填数.\n(1)26,28,( ),( ),34.\n(2)60,55,( ),( ),40。", + "options": [], + "answer": "30;32 50;45", + "solution": "【分析】(1)后面的数比前面的数多2;(2)后面的数比前面的数少5。\n\n【详解】(1)28+2=30,30+2=32。(2)55-5=50,50-5=45。", + "knowledge_points": [ + "数字排列的规律" + ], + "source": "22-23 一年级下·浙江温州·期中" + }, + { + "id": "179", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.65, + "question": "我会按规律填数.\n(1)29,( ),49,59,( ),79.\n(2)35,( ),45,50,( ),60。", + "options": [], + "answer": "39;69 40;55", + "solution": "【分析】(1)后一个数比前一个数多10;(2)后一个数比前一个数多5。\n\n【详解】(1)59-49=10,29+10=39,59+10=69,所以29,39,49,59,69,79。(2)50-45=5,35+5=40,50+5=55,所以35,40,45,50,55,60。", + "knowledge_points": [ + "数字排列的规律", + "两位数与整十数的减法", + "一位数与两位数的进位加法", + "一位数与两位数的退位减法" + ], + "source": "22-23 一年级下·湖北十堰·期中" + }, + { + "id": "180", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.65, + "question": "按规律填一填.\n(1)14,23,32,( ),50,59,( ).\n(2)64,56,( ),40,( ),( ),16。", + "options": [], + "answer": "41;68 48;32;24", + "solution": "【分析】(1)后一个数比前一个数多9;(2)后一个数比前一个数少8。\n\n【详解】(1)23-14=9,32-23=9,59-50=9;32+9=41,59+9=68,所以14,23,32,41,50,59,68。(2)64-56=8;56-8=48;40-8=32;32-8=24,所以64,56,48,40,32,24,16。", + "knowledge_points": [ + "数字排列的规律", + "一位数与两位数的进位加法", + "一位数与两位数的退位减法" + ], + "source": "23-24 二年级上·新疆塔城·期末" + }, + { + "id": "181", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.65, + "question": "找出每行数的规律,并按规律接着写出三个数.\n(1)82,72,62,52,( ),( ),( ).\n(2)6,9,12,15,18,( ),( ),( )。", + "options": [], + "answer": "42;32;22 21;24;27", + "solution": "【分析】(1)每后一个数比前一个数少10;(2)每后一个数比前一个数大3。\n\n【详解】(1)52-10=42,42-10=32,32-10=22,所以82,72,62,52,42,32,22。(2)18+3=21,21+3=24,24+3=27,所以6,9,12,15,18,21,24,27。", + "knowledge_points": [ + "数字排列的规律", + "两位数与一位数的加法(不进位)", + "两位数与整十数的减法", + "一位数与两位数的进位加法" + ], + "source": "22-23一年级下·广西贵港·期中" + }, + { + "id": "182", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.65, + "question": "盒子里一共有( )个白珠,( )个黑珠.\n\n![](images/Pasted image 20251214152225.png)", + "options": [], + "answer": "9;1", + "solution": "【分析】盒子里珠子的排列顺序是:4颗白珠,1颗黑珠,5颗白珠,据此计算即可。\n\n【详解】4 + 5 = 9(颗),盒子里一共有9个白珠,1个黑珠。", + "knowledge_points": [ + "图文问题", + "图形的规律", + "8,9的加减法" + ], + "source": "23-24 一年级上·福建泉州·期末" + }, + { + "id": "183", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.85, + "question": "![](images/Pasted image 20251214152302.png)遮住了7颗珠子,黄色珠子有( )颗,红色珠子有( )颗。![](images/Pasted image 20251214152248.png)", + "options": [], + "answer": "4;3", + "solution": "【分析】题中珠子按照2颗红色,3颗黄色为一组重复排列。遮住部分的前边有1颗红色珠子,说明遮住的第1颗珠子是红色;后边有3颗黄色珠子,因为一共有7颗珠子,所以后边还有2颗红色珠子,1颗黄色珠子。\n\n【详解】由分析作图如下:遮住了7颗珠子,黄色珠子有4颗,红色珠子有3颗.\n\n![](images/Pasted image 20251214152405.png)", + "knowledge_points": [ + "图形的规律" + ], + "source": "23-24 一年级下·全国·课后作业" + }, + { + "id": "184", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.65, + "question": "按规律填数.\n\n
14( )1617( )
20( )18( )16
11( )15( )19
", + "options": [], + "answer": "15;18;19;17;13;17", + "solution": "【分析】观察表格可知:第一行数依次加1;第二行数依次减1;第三行数依次加2。\n\n【详解】14+1=15,15+1=16,16+1=17,17+1=18;20-1=19,19-1=18,18-1=17,17-1=16;11+2=13,13+2=15,15+2=17,17+2=19。故填空后为:\n\n
14(15)1617(18)
20(19)18(17)16
11(13)15(17)19
", + "knowledge_points": [ + "数字排列的规律" + ], + "source": "23-24一年级上·黑龙江哈尔滨·期末" + }, + { + "id": "185", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.65, + "question": "找规律,在( )里填上合适的数.\n(1)4,8,12,( ),20,( ).\n(2)2,3,5,( ),13,( )。", + "options": [], + "answer": "16;24 8;21", + "solution": "【分析】(1)这组数字依次变大,每后一个数比前一个数大4;(2)这组数字中,每前两个数相加等于后一个数。\n\n【详解】(1)12+4=16,20+4=24,所以4,8,12,16,20,24。(2)3+5=8,5+8=13,8+13=21,所以2,3,5,8,13,21。", + "knowledge_points": [ + "数字排列的规律", + "5~2加几的进位加法", + "两位数与一位数的加法(不进位)", + "一位数与两位数的进位加法" + ], + "source": "23-24 一年级上·浙江台州·期末" + }, + { + "id": "186", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.65, + "question": "按规律填数.\n(1)7,14,( ),28,35.\n(2)90,84,78,( ),66,( )。", + "options": [], + "answer": "21 72;60", + "solution": "【分析】(1)从左至右依次加7;(2)从左至右依次减6。\n\n【详解】(1)14+7=21,故7,14,21,28,35。(2)78-6=72,66-6=60,故90,84,78,72,66,60。", + "knowledge_points": [ + "数字排列的规律" + ], + "source": "23-24 二年级上·浙江台州·期末" + }, + { + "id": "187", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.65, + "question": "按规律填数.\n(1)2,4,( ),( ),10,( ),( ).\n(2)( ),15,10,( )。", + "options": [], + "answer": "6;8;12;14 20;5", + "solution": "【分析】(1)从2开始,2个2个地数;(2)后一个数比前一个数少5,前一个数比后一个数多5。\n\n【详解】(1)填6,8,12,14。(2)15前面的数是15+5=20;10后面的数是10-5=5。", + "knowledge_points": [ + "数字排列的规律", + "10的加减法", + "一位数与两位数的进位加法" + ], + "source": "21-22 一年级上·河北邯郸·期末" + }, + { + "id": "188", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.65, + "question": "按规律填数.\n(1)8,16,24,( ),40,( ).\n(2)72,66,( ),54,( ),42。", + "options": [], + "answer": "32;48 60;48", + "solution": "【分析】(1)后一个数比前一个数多8;(2)后一个数比前一个数少6。\n\n【详解】(1)24+8=32,40+8=48,故8,16,24,32,40,48。(2)66-6=60,54-6=48,故72,66,60,54,48,42。", + "knowledge_points": [ + "数字排列的规律", + "两位数与一位数的减法(不退位)", + "一位数与两位数的进位加法", + "一位数与两位数的退位减法" + ], + "source": "23-24 二年级上·甘肃天水·期末" + }, + { + "id": "189", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.65, + "question": "找规律填数.\n(1)3,6,9,12,( ).\n(2)72,63,54,( )。", + "options": [], + "answer": "15;45", + "solution": "【分析】(1)后一个数比前一个数多3;(2)后一个数比前一个数少9。\n\n【详解】(1)12+3=15,故3,6,9,12,15。(2)72-9=63,63-9=54,54-9=45,故72,63,54,45。", + "knowledge_points": [ + "数字排列的规律", + "不进位加法(20以内)", + "9加几的进位加法", + "一位数与两位数的退位减法" + ], + "source": "23-24 二年级上·湖南怀化·期末" + }, + { + "id": "190", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.85, + "question": "找规律填一填:\n8,15,22,( ),( )。", + "options": [], + "answer": "29;36", + "solution": "【分析】后一个数比前一个数多7,据此解决。\n\n【详解】22+7=29,29+7=36,故8,15,22,29,36。", + "knowledge_points": [ + "数字排列的规律", + "两位数与一位数的加法(不进位)", + "一位数与两位数的进位加法" + ], + "source": "23-24 二年级上·陕西安康·期末" + }, + { + "id": "191", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.65, + "question": "按规律填数.\n3,6,9,12,15,( ),21,( ),30。", + "options": [], + "answer": "18;24;27", + "solution": "【分析】后一个数等于前一个数加3。\n\n【详解】15+3=18,21+3=24,24+3=27,所以3,6,9,12,15,18,21,24,27,30。", + "knowledge_points": [ + "数字排列的规律" + ], + "source": "23-24 二年级上·浙江温州·期末" + }, + { + "id": "192", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.65, + "question": "找规律,在( )内填适当的数.\n15,6,13,7,11,8,( ),9。", + "options": [], + "answer": "9", + "solution": "【分析】偶数位:6,7,8,9依次加1;奇数位:15,13,11,( )依次减2,所以第7个数应比11少2。\n\n【详解】11-2=9,所以15,6,13,7,11,8,9,9。", + "knowledge_points": [ + "数字排列的规律" + ], + "source": "23-24 三年级上·吉林四平·期末" + }, + { + "id": "193", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.65, + "question": "按规律填数.\n(1)28,35,42,( ),( ),63,( ).\n(2)77,72,( ),62,( ),( )。", + "options": [], + "answer": "49;56;70 67;57;52", + "solution": "【分析】(1)每后一个数比前一个数大7;(2)每后一个数比前一个数少5。\n\n【详解】(1)28,35,42,49,56,63,70。(2)77,72,67,62,57,52。", + "knowledge_points": [ + "数字排列的规律" + ], + "source": "23-24 二年级上·湖南长沙·期中" + }, + { + "id": "194", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.85, + "question": "
575960
1009894
", + "options": [], + "answer": "58;61;62;96;92;90", + "solution": "【分析】第一行从小到大依次加1;第二行从大到小依次减2。\n\n【详解】\n\n
575859606162
1009896949290
", + "knowledge_points": [ + "数字排列的规律" + ], + "source": "22-23一年级下·浙江温州·期末" + }, + { + "id": "195", + "unit": "找规律", + "question_type": "判断题", + "difficulty": 0.85, + "question": "□○□○□○,第10个图形是○。( )", + "options": [], + "answer": "√", + "solution": "【分析】该组规律为\"□ ○\"为一组重复出现,依次列举出来,画到第10个图形判断即可。\n\n【详解】由分析可得:□○□○□○□○□○。第10个图形是○,原题说法正确。故答案为:√", + "knowledge_points": [ + "图形的变化规律" + ], + "source": "23-24 一年级下·新疆·期末" + }, + { + "id": "196", + "unit": "找规律", + "question_type": "判断题", + "difficulty": 0.65, + "question": "![](images/Pasted image 20251214154528.png),接下来应该摆![](images/Pasted image 20251214154535.png)。()", + "options": [], + "answer": "×", + "solution": "【分析】![](images/Pasted image 20251214154547.png),这四个图形依次重复出现;即每三个圆柱后摆一个长方体,所以接下来应该摆一个圆柱。\n\n【详解】由题意分析得:![](images/Pasted image 20251214154556.png),接下来应该摆圆柱;故原题说法错误。故答案为: ×。", + "knowledge_points": [ + "图形的规律", + "立体图形的认识" + ], + "source": "23-24一年级上·河北保定·期末" + }, + { + "id": "197", + "unit": "找规律", + "question_type": "作图题", + "difficulty": 0.85, + "question": "小红按规律穿了一串手链,但不小心掉了3颗珠子,掉的是哪3颗。请在图上画一画.\n\n![](images/Pasted image 20251214154612.png)", + "options": [], + "answer": "见详解", + "solution": "【分析】题中珠子按照两颗白色两颗黑色为一组重复排列,已经有2组完整的,第3组只有1颗白色,掉了3颗,则掉的是1颗白色,2颗黑色。\n\n【详解】由分析作图如下:![](images/Pasted image 20251214154619.png)", + "knowledge_points": [ + "图形的变化规律" + ], + "source": "23-24一年级下·湖北随州·期末" + }, + { + "id": "198", + "unit": "找规律", + "question_type": "解答题", + "difficulty": 0.65, + "question": "按规律写数.\n(1)3,6,9,( ),( ).\n(2)97,87,( ),( ),57,( )。", + "options": [], + "answer": "12;15 77;67;47", + "solution": "【分析】(1)这组数字依次变大,每后一个数比前一个数大3;(2)这组数字依次变小,每后一个数比前一个数小10。\n\n【详解】(1)3,6,9,12,15。(2)97,87,77,67,57,47。", + "knowledge_points": [ + "整数排列的规律" + ], + "source": "23-24 一年级下·甘肃天水·期末" + }, + { + "id": "199", + "unit": "找规律", + "question_type": "解答题", + "difficulty": 0.65, + "question": "小刚摆积木,第一层摆了10块,以后每层依次少摆2块,摆了5层。一共摆了多少块积木。", + "options": [], + "answer": "30块", + "solution": "【分析】第一层10块,以后每层少2块:第二层10-2=8块,第三层8-2=6块,第四层6-2=4块,第五层4-2=2块,把各层数量相加即可。\n\n【详解】10+8+6+4+2=30(块)。答:一共摆了30块积木。", + "knowledge_points": [ + "间隔问题", + "100以内数的连加运算" + ], + "source": "23-24 一年级下·山东济宁·期末" + }, + { + "id": "200", + "unit": "找规律", + "question_type": "解答题", + "difficulty": 0.85, + "question": "穿手链,还缺3颗珠子.\n\n![](images/Pasted image 20251214154729.png)\n\n缺少( )颗圆形,( )颗正方形。", + "options": [], + "answer": "1;2", + "solution": "【分析】这个手链按照![](images/Pasted image 20251214154800.png)为一组重复排列,已经排列了4组,缺了3颗,也就是缺少完整的一组。\n\n【详解】缺少的是![](images/Pasted image 20251214154757.png)。答:缺少1颗圆形,2颗正方形。", + "knowledge_points": [ + "图形的变化规律" + ], + "source": "23-24 一年级下·全国·假期作业" + }, + { + "id": "201", + "unit": "找规律", + "question_type": "选择题", + "difficulty": 0.65, + "question": "下图中( )处应画( )个黑点.\n\n![](images/Pasted image 20251214155109.png)", + "options": [ + "A. 12", + "B. 8", + "C. 7", + "D. 9" + ], + "answer": "D", + "solution": "【分析】依次观察各图形的黑点个数,分别为1,3,5,7,发现规律是后一个图形比前一个图形多2个黑点,那么( )处应画 (7 + 2) 个黑点;据此解答。解答本题的关键是认真观察图形,找出图中黑点的规律后即可解答。\n\n【详解】 7 + 2 = 9 (个)所以,( )处应画9个黑点。故答案为: D", + "knowledge_points": [ + "图形的规律" + ], + "source": "21-22 五年级上·吉林·期末" + }, + { + "id": "202", + "unit": "找规律", + "question_type": "选择题", + "difficulty": 0.65, + "question": "9,18,27,36,45,54,□,72,81,90,方框里的数是( )。", + "options": [ + "A. 63", + "B. 19", + "C. 67" + ], + "answer": "A", + "solution": "【分析】右边的数比左边相邻的数大 9,据此解答。找出数据排列的规律是解题关键。\n\n【详解】 54 + 9 = 63 所以方框里的数是 63。 故答案为: A", + "knowledge_points": [ + "数字排列的规律" + ], + "source": "21-22 一年级下·全国·单元测试" + }, + { + "id": "203", + "unit": "找规律", + "question_type": "选择题", + "difficulty": 0.85, + "question": "一列小旗按![](images/Pasted image 20251214155206.png)的规律排列,第10面小旗是( )。", + "options": [ + "A. 白旗", + "B. 黑旗", + "C. 无法确定" + ], + "answer": "A", + "solution": "【分析】由小旗的排列规律可知,单数为黑色的小旗,双数为白色的小旗,据此解答。本题考查图形的排列规律。\n\n【详解】由分析可知,第10面小旗是白旗。故答案为: A", + "knowledge_points": [ + "图形的规律" + ], + "source": "22-23 一年级下·全国·单元测试" + }, + { + "id": "204", + "unit": "找规律", + "question_type": "选择题", + "difficulty": 0.65, + "question": "下图中 ![](images/Pasted image 20251214155254.png)遮住的 4 个珠子里面有 ( ) 个 ![](images/Pasted image 20251214155313.png) .\n\n![](images/Pasted image 20251214155246.png)", + "options": [ + "A. 1", + "B. 2", + "C. 3" + ], + "answer": "B", + "solution": "【分析】如图所示,珠子的摆放规律为 2 个白色和 2 个黑色交替出现,方框盖住的部分左侧为 1 个白色珠子,右侧也是 1 个白色珠子,据此解答。本题重点考查图形找规律。\n\n【详解】根据分析可知, 1 个白色珠子下来是 1 个白色珠子,然后是两个黑色珠子,然后是 1 个白色珠子,所以方框里的珠子颜色为白黑黑白,所以黑色的珠子有 2 个。故答案为: B", + "knowledge_points": [ + "图形的规律" + ], + "source": "22-23 一年级下·全国·单元测试" + }, + { + "id": "205", + "unit": "找规律", + "question_type": "选择题", + "difficulty": 0.4, + "question": "用同样长的小棒按照下面的方式依次摆出如下的图形,图10需要( )根小棒.\n\n![](images/Pasted image 20251214155324.png)", + "options": [ + "A. 32", + "B. 40", + "C. 41" + ], + "answer": "C", + "solution": "【分析】根据图形找出规律解答此题。图1,5根,(1+4)根;图2,9根,(1+4+4)根;图3,13根,(1+4+4+4)根。依此类推。此题主要考查找规律。提高学生的逻辑思维的能力。\n\n【详解】根据分析可知,图10,1+4+4+4+4+4+4+4+4+4+4=41(根);故答案为:C", + "knowledge_points": [ + "图形的规律" + ], + "source": "22-23 一年级下·全国·单元测试" + }, + { + "id": "206", + "unit": "找规律", + "question_type": "选择题", + "difficulty": 0.85, + "question": "按规律选择 (如图), ( )处应该填 ( ).\n\n![](images/Pasted image 20251214155442.png)", + "options": [ + "A. ○", + "B. ☆", + "C. □" + ], + "answer": "C", + "solution": "【分析】题中的图形每一横行和每一竖列均有圆形,五角星和正方形,依此推断( )处应该填正方形。\n\n【详解】根据分析填写如图:![](images/Pasted image 20251214155456.png)故答案为: C\n\n[点睛]本题是找规律的题型,从已知的图形中找到规律,并按规律解题。", + "knowledge_points": [ + "图形的规律" + ], + "source": "22-23 一年级下·全国·单元测试" + }, + { + "id": "207", + "unit": "找规律", + "question_type": "选择题", + "difficulty": 0.85, + "question": "一串手链,![](images/Pasted image 20251214155503.png)右边再依次添 2 颗珠子,依次是( )。", + "options": [ + "A. ![](images/Pasted image 20251214155512.png)", + "B. ![](images/Pasted image 20251214155519.png)", + "C. ![](images/Pasted image 20251214155527.png)" + ], + "answer": "C", + "solution": "【分析】根据题意可知,珠子的排列顺序为两个黑色和一个白色为一组,所以右边再添两个珠子应为一个黑色一个白色。本题考查图形的排列规律。\n\n【详解】根据分析可知,右边两个珠子依次为 ![](images/Pasted image 20251214155535.png) 。故答案为: C.", + "knowledge_points": [ + "图形的规律" + ], + "source": "21-22一年级下·全国·单元测试" + }, + { + "id": "208", + "unit": "找规律", + "question_type": "选择题", + "difficulty": 0.85, + "question": "按照下图中图形的规律,空格的地方应该画 ( ).\n\n![](images/Pasted image 20251214155545.png)", + "options": [ + "A. ![](images/Pasted image 20251214155551.png)", + "B. ![](images/Pasted image 20251214155600.png)", + "C. ![](images/Pasted image 20251214155610.png)" + ], + "answer": "A", + "solution": "【分析】由图可知,每行每列中均有太阳,笑脸和月亮,空格缺少的是太阳。本题考查图形的排列规律。\n\n【详解】根据分析可得,空格的地方应该画太阳,故答案为: A.", + "knowledge_points": [ + "图形的规律" + ], + "source": "21-22 一年级下·全国·单元测试" + }, + { + "id": "209", + "unit": "找规律", + "question_type": "选择题", + "difficulty": 0.85, + "question": "![](images/Pasted image 20251214155640.png)后面一个图形是( )。", + "options": [ + "A. 三角形", + "B. 正方形", + "C. 圆形" + ], + "answer": "B", + "solution": "【分析】根据题意可知,图形 ![](images/Pasted image 20251214155724.png)为一组重复排列,所以后边的图形应该为 正方形。\n\n【详解】据分析,可知后面一个图形是正方形 。故答案为: B\n\n[点睛]本题主要考查学生对图形按照一定规律排列问题的掌握情况。解决此题先观察图形之间的关系,找出对应的规律即可。", + "knowledge_points": [ + "图形的规律" + ], + "source": "21-22一年级下·全国·单元测试" + }, + { + "id": "210", + "unit": "找规律", + "question_type": "选择题", + "difficulty": 0.85, + "question": "按规律写数:\n\n30, 25, 20, □ , 10。□里是( )。", + "options": [ + "A. 16", + "B. 15", + "C. 14" + ], + "answer": "B", + "solution": "【分析】此题可根据数之间的排列规律得出答案。本题主要考查学生对数按照一定规律排列问题的掌握情况。解决此题先观察数字之间的关系,找出对应的规定即可。\n\n【详解】根据已知数发现这组数从头到尾每后一个数比前一个数字少 5 。所以这组数应为 30, 25, 20, 15, 10故答案为: B", + "knowledge_points": [ + "数字排列的规律" + ], + "source": "22-23 一年级下·全国·单元测试" + }, + { + "id": "211", + "unit": "找规律", + "question_type": "选择题", + "difficulty": 0.65, + "question": "用同样长的小棒按照下面的方式依次摆出如下的图形,图10需要( )根小棒.\n\n![](images/Pasted image 20251214155802.png)", + "options": [ + "A. 32", + "B. 40", + "C. 41", + "D. 50" + ], + "answer": "C", + "solution": "【分析】根据图形找出规律解答此题。 图 1, 5 根, (1+4) 根;图2,9根, (1 + 4 + 4) 根;图3,13根, (1 + 4 + 4 + 4) 根。依此类推。此题主要考查找规律。提高学生的逻辑思维的能力。\n\n【详解】根据分析可知,图10,1+4+4+4+4+4+4+4+4+4+4=41(根);故答案为:C", + "knowledge_points": [ + "图形的规律" + ], + "source": "22-23一年级下·全国·单元测试" + }, + { + "id": "212", + "unit": "找规律", + "question_type": "选择题", + "difficulty": 0.65, + "question": "一个加数增加 10,另一个加数也增加 10,它们的和( )。", + "options": [ + "A. 增加 10", + "B. 不变", + "C. 增加 20" + ], + "answer": "C", + "solution": "【分析】根据加法的计算方法,加数+加数=和,所以一个加数增加 10,另一个加数增加 10,它们的和增加 20,由此解答。此题考查了整数的加法计算方法,以及加数,和的关系,一个加数增加(减少)几,和也会增加(减少)几。\n\n【详解】一个加数增加 10,另一个加数也增加 10,它们的和增加 20 。故答案为: C", + "knowledge_points": [ + "和与差的变化规律" + ], + "source": "21-22 二年级下·四川自贡·期末" + }, + { + "id": "213", + "unit": "找规律", + "question_type": "选择题", + "difficulty": 0.65, + "question": "![](images/Pasted image 20251214155918.png)![](images/Pasted image 20251214155927.png) 遮住了7颗,被遮住了( )颗 ○ 。", + "options": [ + "A. 4", + "B. 5", + "C. 6" + ], + "answer": "B", + "solution": "【分析】图形是按○,○,●的顺序循环排列的,●后面的7颗依次是○,○,●,○,○,●,○,据此解答。仔细观察,找出图形排列的规律是解题关键。\n\n【详解】由分析可知:被遮住的 7 颗珠子中有 5 颗 ○ 。故答案为:B.", + "knowledge_points": [ + "图形的规律" + ], + "source": "20-21 一年级下·河北保定·期末" + }, + { + "id": "214", + "unit": "找规律", + "question_type": "选择题", + "difficulty": 0.85, + "question": "△□▱△□▱△□,按规律下一个图形是( )。", + "options": [ + "A. △", + "B. □", + "C. ▱" + ], + "answer": "C", + "solution": "【分析】根据图示发现,这组图形的排列规律是:每3个图形一循环,按△,□,▱的顺序排,据此选择即可。得出这组图形的排列规律是解答本题的关键。\n\n【详解】△□▱△□▱△□,按规律下一个图形是▱。故答案为:C", + "knowledge_points": [ + "图形的规律" + ], + "source": "21-22 一年级下·四川广元·期末" + }, + { + "id": "215", + "unit": "找规律", + "question_type": "选择题", + "difficulty": 0.85, + "question": "按规律选一个图填在括号里.\n\n![](images/Pasted image 20251214160023.png)( )", + "options": [ + "A. 圆柱", + "B. 笑脸", + "C. 六角星" + ], + "answer": "B", + "solution": "【分析】图形是按一个圆柱,一个笑脸的顺序循环排列的,据此解答。找出图形排列的规律是解题关键。\n\n【详解】圆柱后面应该是笑脸,故答案为: B.", + "knowledge_points": [ + "图形的规律" + ], + "source": "21-22 一年级下·贵州遵义·期末" + }, + { + "id": "216", + "unit": "找规律", + "question_type": "选择题", + "difficulty": 0.65, + "question": "下图中![](images/Pasted image 20251214160209.png) 遮住的4个珠子里面有( )个![](images/Pasted image 20251214160221.png) .\n\n![](images/Pasted image 20251214160202.png)", + "options": [ + "A. 1", + "B. 2", + "C. 3", + "D. 4" + ], + "answer": "B", + "solution": "【分析】如图所示,珠子的摆放规律为 2 个白色和 2 个黑色交替出现,方框盖住的部分左侧为 1 个白色珠子,右侧也是 1 个白色珠子,据此解答。本题重点考查图形找规律。\n\n【详解】根据分析可知, 1 个白色珠子下来是 1 个白色珠子,然后是两个黑色珠子,然后是 1 个白色珠子,所以方框里的珠子颜色为白黑黑白,所以黑色的珠子有 2 个。故答案为: B.", + "knowledge_points": [ + "图形的规律" + ], + "source": "21-22一年级下·福建龙岩·期末" + }, + { + "id": "217", + "unit": "找规律", + "question_type": "选择题", + "difficulty": 0.4, + "question": "下图中遮住了 9 个珠子,有 ( ) 个白珠子和 ( ) 个黑珠子.\n\n![](images/Pasted image 20251214160246.png)①2 ②3 ③4 ④5", + "options": [ + "A. ①②", + "B. ②③", + "C. ③④", + "D. ①④" + ], + "answer": "C", + "solution": "【分析】由图形可知题中的规律是: 2 个白色珠子和 3 个黑色球子循环,由此根据规律即可。解答本题的关键是找出题中的规律,再由规律作答。\n\n【详解】被遮住的9个珠子是:2白3黑2白2黑,所以白珠子的个数为:2+2=4(个)黑珠子的个数为:3+2=5(个)故答案为:C.", + "knowledge_points": [ + "间隔问题", + "5以内数的加法" + ], + "source": "19-20 一年级下·青海果洛·期末" + }, + { + "id": "218", + "unit": "找规律", + "question_type": "选择题", + "difficulty": 0.65, + "question": "按规律排列,▲○▲▲○![](images/Pasted image 20251214160409.png)○▲▲▲▲○,![](images/Pasted image 20251214160412.png)遮住的是(    )。", + "options": [ + "A. ▲", + "B. ▲▲", + "C. ▲▲▲" + ], + "answer": "C", + "solution": "【分析】根据上图所给图形可知,1个▲,1个○,2个▲,1个○,3个▲,1个○,4个▲,据此规律判断即可。本题考查简单的图形周期,间隔的规律,培养学生的逻辑推理的能力。\n\n【详解】据分析可知,![](images/Pasted image 20251214160414.png)遮住的是3个▲。故答案为:C.", + "knowledge_points": [ + "周期问题" + ], + "source": "20-21一年级下·湖北鄂州·期末" + }, + { + "id": "219", + "unit": "找规律", + "question_type": "选择题", + "difficulty": 0.65, + "question": "△ ○ ○ □ △ ○ ○ □ △ ○ ○ □ △ ○ ○ □ △ ○ , 照左边的排列规律,( )处是 ( )。", + "options": [ + "A. □", + "B. △", + "C. ○" + ], + "answer": "C", + "solution": "【分析】观察图形的排列情况可知,该列图形的排列规律为: △ ○ ○ □ , 以此为一组依次排列下去,据此解答即可。本题考查学生对图形排列规律的掌握和运用。\n\n【详解】△ ○ ○ □ △ ○ ○ □ △ ○ ○ □ △ ○ ○ □ △ ○ ○ ,照左边的排列规律,( )处是 ○ 。故答案为: C", + "knowledge_points": [ + "图形的规律" + ], + "source": "21-22 二年级下·吉林·期末" + }, + { + "id": "220", + "unit": "找规律", + "question_type": "选择题", + "difficulty": 0.65, + "question": "下面的箱子中○有( ) 个.\n\n![](images/Pasted image 20251214160439.png)", + "options": [ + "A. 1", + "B. 2", + "C. 3" + ], + "answer": "C", + "solution": "【分析】看图可知排列的规律是: 1 个 ○ , 1 个 ● , 2 个 ○ , 1 个 ● , 3 个 ○ , 1 个 ● , 4 个 ○ , 1 个 ● , 5 个 ○ 。, 据此解答。\n\n【详解】根据分析可知:箱子里有 3 个 ○ ,1 个 ● 。故答案为: C\n\n[点睛]本题考查图形的间隔,周期规律。", + "knowledge_points": [ + "间隔问题" + ], + "source": "21-22 一年级下·四川德阳·期末" + }, + { + "id": "221", + "unit": "找规律", + "question_type": "选择题", + "difficulty": 0.65, + "question": "同学们排队,一共有9个男生,每相邻两个男生之间站一个女生。一共可以站进( )个女生。", + "options": [ + "A. 9", + "B. 10", + "C. 8" + ], + "answer": "C", + "solution": "【分析】根据题意,每相邻两个男生之间站一个女生,到第九个男生时就结束,所以间隙有 9 - 1 = 8 个;据此解答。此题的关键是要找出九个男生之间有 8 个间隙。\n\n【详解】根据分析得:间隙一共有 9 - 1 = 8(个),所以一共可以站 8 个女生。故答案为: C.", + "knowledge_points": [ + "间隔问题", + "相邻的数" + ], + "source": "20-21一年级下·河南漯河·期中" + }, + { + "id": "222", + "unit": "找规律", + "question_type": "选择题", + "difficulty": 0.65, + "question": "布置核酸采集点,学校门口两边各摆放5张桌子,如果每两张桌子之间摆2把椅子,需要( )把椅子。", + "options": [ + "A. 10", + "B. 8", + "C. 16" + ], + "answer": "C", + "solution": "【分析】因为每两张桌子之间摆 2 把椅子,即 5 张桌子之间有 4 个空需要摆放椅子,所以两边各摆放 8 把椅子,据此即可得出答案。本题的解答关键是先得出 5 张桌子之间需要摆放几把椅子。\n\n【详解】2+2+2+2=8(把)8+8=16(把)所以,需要16把椅子。 故答案为:C.", + "knowledge_points": [ + "间隔问题", + "数与形" + ], + "source": "21-22一年级下·福建泉州·期中" + }, + { + "id": "223", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.65, + "question": "先找规律,再根据所找规律填数.\n\n(1)3,11,19,27,( ).\n\n(2)15,25,35,45,( ).\n\n(3)60,56,52,48,( ).\n\n(4)96,86,76,66,( )。", + "options": [], + "answer": "35;55;44;56", + "solution": "【分析】(1)后一个数字比前一个数字多8;(2)后一个数字比前一个数字多10;(3)后一个数字比前一个数字少4;(4)后一个数字比前一个数字少10;本题考查学生的逻辑推理能力,要培养学生的观察力和总结规律的能力。\n\n【详解】(1)27+8=35, 3,11,19,27,35。(2)45+10=55, 15,25,35,45,55.\n(3)48-4=44, 60,56,52,48,44。(4)66-10=56, 96,86,76,66,56。", + "knowledge_points": [ + "数字排列的规律", + "两位数与一位数的加法(不进位)", + "两位数与整十数的加法", + "两位数与整十数的减法" + ], + "source": "22-23一年级下·全国·随堂练习" + }, + { + "id": "224", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.85, + "question": "找规律填数.\n\n(1)81,72,63,( ),( ),36.\n\n(2)8,16,24,( ),40,( ).\n\n(3)49,42,( ),28,( ),14。", + "options": [], + "answer": "54;45;32;48;35;21", + "solution": "【分析】由题意可知,(1)81,72,63,这几个数字是从小到大的顺序排列的,并且依次小9,那么下一个空填的数字是用前一个数字减9即可得到,即63-9=54,54-9=45;(2)8,16,24,这几个数字依次增大,而且依次增加8,那么下一个数字就是24+8=32,40+8=48;(3)49,42,前面这两个数字依次减小,而且第二个数字比第一个数字小7,说明下一个数字用前一个数字减7即可得到,则42-7=35,28-7=21,据此解答即可。熟练掌握发现数字排列的规律是解决此题的关键。\n\n【详解】(1)81,72,63,(  54    ),(   45   ),36。(2)8,16,24,(   32   ),40,(   48   )。(3)49,42,(   35   ),28,(   21   ),14。", + "knowledge_points": [ + "数字排列的规律" + ], + "source": "23-24 二年级上·全国·课后作业" + }, + { + "id": "225", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.85, + "question": "找规律接着画下去.\n\n○□△△○□△△○□△( )。", + "options": [], + "answer": "△", + "solution": "【分析】根据图示可知,图形按〇□△△为一组重复排列,依此可知后边应该为一个三角形。本题只要找出这组图形的排列规律即可解答。\n\n【详解】据分析可知,这组图形应为〇□△△〇□△△〇□△△。", + "knowledge_points": [ + "图形的规律" + ], + "source": "22-23一年级·全国·假期作业" + }, + { + "id": "226", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.65, + "question": "△○□△○□△○□接着画下一个是( )。", + "options": [], + "answer": "△", + "solution": "【分析】根据题干得知,图中的图形是按三角形,圆,正方形的顺序排列的,据此画一画就可以得到答案了。此题考查的主要是找规律,首先要读一读图中的图形是按什么样的顺序来排列的,明确图中的排列顺序,找到其中的规律,就可以画出下一个图形了。\n\n【详解】由分析得知,△○□△○□△○□接着画下一个是( △ )。", + "knowledge_points": [ + "图形的规律" + ], + "source": "22-23 一年级·全国·假期作业" + }, + { + "id": "227", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.65, + "question": "照样子接着画三个图形.\n\n(1) ○ □ ○ □ ○ □ ○ □ ( )( )( ).\n\n(2) △ △ ○ △ △ ○ △ △ ○ ( )( )( )。", + "options": [], + "answer": "○;□;○ △;△;○", + "solution": "【分析】几个图形为一组,依次不断地重复出现(至少出现 3 次)就叫做有规律的排列。可以通过读一读,明确图形的排列规律。(1)是按 ○ ,□排列的,据此画一画, (2) 是按两个 △ ,一个 ○ 排列的,据此来画一画。此题考查的是图形的找规律,可以通过读一读,明确图形的排列规律,据此画一画就可以了。\n\n【详解】(1)由分析得知, ○ □ ○ □ ○ □ ○ □ ( ○ □ ○ )。 (2) 由分析得知, △ △ ○ △ △ ○ △ ○ (△ △ ○) 。", + "knowledge_points": [ + "图形的规律" + ], + "source": "22-23一年级·全国·假期作业" + }, + { + "id": "228", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.85, + "question": "遮住了7个珠子,白珠子有( )个,黑珠子有( )个.\n\n![](images/Pasted image 20251214161010.png)", + "options": [], + "answer": "4;3", + "solution": "【分析】根据图示,是按照 2 黑 3 白的规律排列的,据此解答即可。本题考查了事物的排列规律知识,结合题意分析解答即可。\n\n【详解】根据题意,遮住了 7 个珠子,应该是 1 黑 3 白 2 黑 1 白,所以白珠子有 4 个,黑珠子有 3 个。", + "knowledge_points": [ + "图形的规律" + ], + "source": "22-23一年级·全国·假期作业" + }, + { + "id": "229", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.65, + "question": "在下面括号里填上合适的数.\n\n(1)4, 13, ( ), 31, ( ).\n\n(2)80;( );62;( );44;35;26;( )。", + "options": [], + "answer": "22;40 71;53;17", + "solution": "【分析】 (1) 后一个数比前一个数多 9;(2) 后一个数比前一个数少 9;据此解决。此题主要考查的是数字排列的规律,关键是找出相邻两数之间的关系。\n\n【详解】(1)13+9=22,31+9=40;故,4,13,22,31,40。 (2)80-9=71,62-9=53,26-9=17;故,80,71,62,53,44,35,26,17。", + "knowledge_points": [ + "数字排列的规律", + "一位数与两位数的进位加法", + "一位数与两位数的退位减法" + ], + "source": "22-23一年级下·全国·单元测试" + }, + { + "id": "230", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.65, + "question": "找规律,再填空.\n\n70,( ),50,( ),30,( ),10;79, 69, ( ), 49, ( ), ( ), 19。", + "options": [], + "answer": "60;40;20;59;39;29", + "solution": "【分析】(1)已知数字依次减小,70和50,50和30,30和10中间都相隔一个数,相差20,由此可知,每两个数字之间相差10。即70-10=60;50-10=40;30-10=20,由此填写;(2)已知数字依次减小,后一个数比前一个数少10。即69-10=59;49-10=39;39-10=29,由此填写。本题主要考查了数字间的排列规律。\n\n【详解】由分析得数字排列如下:70,60,50,40,30,20,10;79,69,59,49,39,29,19。", + "knowledge_points": [ + "数字排列的规律", + "整十数之间的加减法", + "两位数与整十数的减法" + ], + "source": "21-22一年级下·广东广州·期末" + }, + { + "id": "231", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.65, + "question": "按顺序填空.\n\n
7876( )72( )( )
\n\n
( )30( )32( )34
", + "options": [], + "answer": "74;70;68;29;31;33", + "solution": "【分析】根据题意,第一个表格中的数字从左到右依次变小,后一个数字比前一个数字少2,76-2=74;72-2=70;70-2=68,可知从左到右应填写的数字为74,70,68;第二个表格中的数字从左到右依次变大,根据30和32,32和34都相差2,中间都间隔一个数字,可知后一个数字比前一个数字多1,30-1=29;32-1=31;34-1=33,从左到右应填写的数字为29,31,33。本题主要考查 100 以内数的认识及数字间的排列规律。\n\n【详解】根据分析填写如下:
787674727068
293031323334
", + "knowledge_points": [ + "数字排列的规律" + ], + "source": "21-22一年级下·广东佛山·期末" + }, + { + "id": "232", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.65, + "question": "一串珠子按 2 红,1 黄,1 蓝穿起来,那么第 6 颗珠子是( )色。", + "options": [], + "answer": "红", + "solution": "【分析】从题干可知:珠子颜色的排列顺序为 2 个红色珠子,1 个黄色珠子,1 个蓝色珠子为一个循环,据此进行解答即可。本题的解答关键是先搞清楚珠子颜色的循环规律。\n\n【详解】据分析可知:珠子颜色的排列顺序为珠子颜色的排列顺序为 2 个红色珠子,1 个黄色珠子,1 个蓝色珠子,一共 4 个珠子。6 - 4 = 2 (颗) 所以,第6颗珠子是第二个循环里面的第二颗,是红色。", + "knowledge_points": [ + "间隔问题" + ], + "source": "21-22一年级下·广东佛山·期末" + }, + { + "id": "233", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.65, + "question": "找规律填数.\n\n2,5,8,11,14,( ),( )。", + "options": [], + "answer": "17;20", + "solution": "【分析】根据题中已知数据可知,从左往右数字依次变大,后一个数比前一个数大 3,则14 + 3 = 17, 17 + 3 = 20,所以应填写 17 和 20 。\n\n【详解】由分析得,数字排列如下:2, 5, 8, 11, 14, 17, 20.\n\n[点睛]本题考查数字间的排列规律。", + "knowledge_points": [ + "数字排列的规律", + "不进位加法(20以内)", + "8加几的进位加法" + ], + "source": "21-22 一年级下·广东佛山·期末" + }, + { + "id": "234", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.65, + "question": "找规律,填一填.\n\n(1) 1234, 4123, 3412, ( ).\n(2)东西南北,北东西南,南北东西,( )。", + "options": [], + "answer": "2341;西南北东", + "solution": "【分析】(1)根据题意,循环顺序为依次将最后一个数字放在最前面,由此得出下一个是将 2 放在最前面,即2341,由此解答;(2) 根据题意,循环顺序为依次将最后一个字放在最前面,由此得出下一个是将西放在最前面,即西南北东,由此解答;解答本题时要先观察已给出的例子,从已给的数字或文字中找出排列规律,再进行解答。\n\n【详解】(1)由分析可知:1234,4123,3412,2341。(2) 由分析可知:东西南北,北东西南,南北东西,西南北东。", + "knowledge_points": [ + "周期问题" + ], + "source": "22-23 二年级下·全国·课前预习" + }, + { + "id": "235", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.85, + "question": "你知道括号里应该填什么吗。\n\n2,2,3,2,2,3,2,2,3,( )。", + "options": [], + "answer": "2", + "solution": "【分析】该数字排列规律 2, 2, 3 为一组,后面依次重复,按照规律回答即可。主要考查数字的排列规律。\n\n【详解】根据分析填写如下:2, 2, 3, 2, 2, 3, 2, 2, 3, (2)", + "knowledge_points": [ + "数字排列的规律" + ], + "source": "22-23一年级下·全国·课前预习" + }, + { + "id": "236", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.94, + "question": "找规律,填数.\n\n2,3,2,3,2,3,2,3,( ),( )。", + "options": [], + "answer": "2;3", + "solution": "【分析】该数字排列规律 2, 3 为一组,后面依次重复,按照规律回答即可。主要考查数字排列的规律。\n\n【详解】根据分析填写如下:2, 3, 2, 3, 2, 3, 2, 3, (2), (3)", + "knowledge_points": [ + "数字排列的规律" + ], + "source": "22-23 一年级下·全国·课前预习" + }, + { + "id": "237", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.65, + "question": "按规律填出下一个数.\n\n(1)1, 5, 9, 13, ( ).\n(2)42,32,22,12,( )。", + "options": [], + "answer": "17;2", + "solution": "【分析】第一组数的规律是后面一个数比前一个数多 4,按此计算即可。第二组数的规律是前一个数比后一个数多 10,按此计算即可。主要考查了数字排列的规律,并找出相邻两个数之间的关系。\n\n【详解】 (1) 13 + 4 = 17(2) 12 - 10 = 2。", + "knowledge_points": [ + "数字排列的规律" + ], + "source": "22-23 一年级下·全国·课前预习" + }, + { + "id": "238", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.94, + "question": "找规律,填数.\n\n6, 7, 6, 7, 6, 7, 6, 7, ( ), ( )。", + "options": [], + "answer": "6;7", + "solution": "【分析】数字排列规律 6, 7 为一组,后面依次重复,按照规律回答即可。主要考查数字排列的规律。\n\n【详解】根据分析填写如下:6, 7, 6, 7, 6, 7, 6, 7, (6), (7)", + "knowledge_points": [ + "数字排列的规律" + ], + "source": "22-23 一年级下·全国·课前预习" + }, + { + "id": "239", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.85, + "question": "你知道下一个是什么图形吗。\n\n○ □ △ ○ □ △ ○ □ △( )。", + "options": [], + "answer": "○", + "solution": "【分析】该图形排列规律: ○ □ △ 为一组,后面依次重复,按照规律回答即可。主要考查了图形的排列规律。\n\n【详解】根据分析填写如下: ○ □ △ ○ □ △ ○ □ △( ○)", + "knowledge_points": [ + "图形的规律" + ], + "source": "22-23 一年级下·全国·课前预习" + }, + { + "id": "240", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.85, + "question": "找规律,填一填\n\n5+5+5+5+5=25\n\n6+6+6+6+6=30\n\n(        )+(        )+(        )+(        )+(        )=35", + "options": [], + "answer": "7;7;7;7;7", + "solution": "【分析】根据题中数据可知,每一行算式都是相同的5个数相加,下边一行比上边一行的加数多1,得数多5,所以第3行应该为5个7相加。本题考查算式排列规律。\n\n【详解】由分析可得算式为:7+7+7+7+7=35", + "knowledge_points": [ + "算式的规律" + ], + "source": "21-22 一年级下·全国·单元测试" + }, + { + "id": "241", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.65, + "question": "观察 1,3,6,10, 的排列规律,第 6 个数应该填( )。", + "options": [], + "answer": "21", + "solution": "【分析】3-1=2,6-3=3,10-6=4,由此发现规律:第一个数增加2等于第二个数,第二个数增加3等于第三个数,第三个数增加4等于第四个数,也就是相邻两个数的差依次是2,3,4,。据此规律解答即可。按照一定的顺序排列的一列数,只要从连续的几个数中找到规律,那么就可以知道其余的数。寻找数列的排列规律,除了从相邻两数的和,差考虑,有时还要从积,商考虑。善于发现数列的规律是解决填数问题的关键。\n\n【详解】10+5=15 ,15+6=21 所以第6个数应该填21。", + "knowledge_points": [ + "数字排列的规律" + ], + "source": "2022·湖北十堰·小升初真题" + }, + { + "id": "242", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.85, + "question": "找规律,填一填.\n\n0,3,6,9,( ),( ),( ),( )。", + "options": [], + "answer": "12;15;18;21", + "solution": "【分析】由题中数据可知,每后一个数字比前一个数字多3,依此填写即可。本题主要考查数字的排列规律。\n\n【详解】9+3=12;12+3=15;15+3=18;18+3=21所以这组数字应该为 0, 3, 6, 9, 12, 15, 18, 21。", + "knowledge_points": [ + "数字排列的规律" + ], + "source": "21-22一年级下·全国·单元测试" + }, + { + "id": "243", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.85, + "question": "找规律,填一填.\n\n30,35,40,45,( ),( ),( ),( )。", + "options": [], + "answer": "50;55;60;65", + "solution": "【分析】由题中数据可知,每后一个数字比前一个数字多 5,依此填写即可。本题主要考查数字的排列规律。\n\n【详解】 45+5=50;50+5=55;55+5=60;60+5=65所以这组数字应为30,35,40,45,50,55,60,65。", + "knowledge_points": [ + "数字排列的规律" + ], + "source": "21-22一年级下·全国·单元测试" + }, + { + "id": "244", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.65, + "question": "找规律填一填.\n\n(1)6, 16, 26, 36, ( ), ( ), 66, 76, 86.\n(2)如图,小丽按规律穿了一串手链,但掉了 3 颗珠子,掉的是 ( )颗![](images/Pasted image 20251214161824.png) 和 ( )颗 ![](images/Pasted image 20251214161830.png)。![](images/Pasted image 20251214161758.png)", + "options": [], + "answer": "46;56;1;2", + "solution": "【分析】(1)右边的数比左边相邻的数大 10,据此求解。(2) 图形的变化规律:一个圆珠子,两个方珠子;两个圆珠子,两个方珠子;三个圆珠子,两个方珠子;。;据此填空。此题主要考查的是数字的排列规律及图形的变化规律,关键是要发现规律。\n\n【详解】 (1)36+10=46,46+10=56故,6,16,26,36,46,56,66,76,86。(2) 由题意分析可知,掉的三个珠子分别是 1 颗 圆珠子和 2 颗方珠子 .\n\n[点睛]", + "knowledge_points": [ + "数字排列的规律", + "图形的规律" + ], + "source": "22-23 一年级下·全国·单元测试" + }, + { + "id": "245", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.85, + "question": "找规律填一填.\n\n(1)3, 7, 11, 15, ( ), ( ).\n(2) △ ○ △ △ ○ ○ △ △ △ ○ ○ ○ ( )( )", + "options": [], + "answer": "19;23 △△△△;○○○○", + "solution": "【分析】此题可根据数字和图形之间的排列规律得出答案。本题主要考查学生对图形,数字等按照一定规律排列问题的掌握情况。解决此题先观察图形或者数字之间的关系,找出对应的规律即可。\n\n【详解】(1)根据已知数字发现这组数字从头到尾每后一个数字比前一个数字多 4 。分析可得,后边的数字应为 19, 23。(2) 根据已知图形可知排列规律为一个三角形和一个圆形,两个三角形和两个圆形,三个三角形和三个圆形。分析可得后边的图形应为四个三角形和四个圆形,即 △△△△ ○○○○。", + "knowledge_points": [ + "数字排列的规律", + "图形的规律" + ], + "source": "22-23 一年级下·全国·单元测试" + }, + { + "id": "246", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.4, + "question": "按规律填空.\n\n1, 1, 2, 3, 5, ( ), 13。", + "options": [], + "answer": "8", + "solution": "【分析】1+1=2,1+2=3,2+3=5,通过观察,分析,不难发现规律:从第三个数开始,每一个数都等于它前面两个数的和。根据这一规律解答即可。上面这个数列叫作斐波那切(意大利古代著名数学家)数列,也叫作\"兔子数列\"。解答此题关键是先找出规律,再利用规律解题。\n\n【详解】3+5=8所以数列中的第 6 个数是 8。", + "knowledge_points": [ + "数字排列的规律" + ], + "source": "2023 六年级下·全国·专题练习" + }, + { + "id": "247", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.85, + "question": "按照规律填数:\n\n6, 12, 18, ( ), ( )。", + "options": [], + "answer": "24;30", + "solution": "【分析】观察题干可知: 6 和 12 相差 6, 12 和 18 相差 6,依此可知,这列数字的变化规律是从左往右依次增加 6。本题的解答关键是先找出数字的变化规律。\n\n【详解】按照规律填数:6,12,18,24,30。", + "knowledge_points": [ + "数字排列的规律" + ], + "source": "22-23 二年级上·山东菏泽·期末" + }, + { + "id": "248", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.65, + "question": "找规律填空.\n\n10,19,28,( ),( ),( ),( )。", + "options": [], + "answer": "37;46;55;64", + "solution": "【分析】根据题意可知,从左到右依次加9,据此解答。本题考查找规律填数,重点是要知道数与数之间的规律,培养学生逻辑思维的能力。\n\n【详解】 10+9=19, 19+9=28, 28+9=37, 37+9=46, 46+9=55, 55+9=64, 所以10,19,28,(37),(46),(55),(64)。", + "knowledge_points": [ + "数字排列的规律" + ], + "source": "22-23 二年级上·全国·期末" + }, + { + "id": "249", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.65, + "question": "用 2,4,9 三张数字卡片组成两位数,小红组成的数是 24,42,29,49,94。她是漏掉了排在( )后面的( )。", + "options": [], + "answer": "29;92", + "solution": "【分析】从左到右每两个数之间将个位和十位交换位置,据此求解。熟练掌握 100 以内数的组成是解题关键。\n\n【详解】小红组成的数应该是 24,42,29,92,49,94,所以她是漏掉了排在 29 后面的 92。", + "knowledge_points": [ + "数字排列的规律", + "100以内数的组成" + ], + "source": "22-23 二年级上·全国·期末" + }, + { + "id": "250", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.65, + "question": "找规律,画一画,填一填.\n\n(1) △○○△○○( ),( ),△○○\n(2)2, 6, 10, 14, ( ), ( )。", + "options": [], + "answer": "△;○ 18;22", + "solution": "【分析】(1)图形按△,○,○的顺序循环排列;(2) 右边的数比左边相邻的数多 4 。仔细观察,找出图形和数字排列的规律是解题关键。\n\n【详解】(1) 连续两个 ○ 后应该是 △ , ○;(2)14+4=18,18+4=22", + "knowledge_points": [ + "数字排列的规律", + "图形的规律", + "不进位加法(20 以内)", + "一位数与两位数的进位加法" + ], + "source": "20-21一年级下·河北保定·期末" + }, + { + "id": "251", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.65, + "question": "找规律填一填.\n\n(1)25,( ),35,40,45,( ).\n(2)30, ( ), 26, 24, ( ).\n(3)□,○,◆,□,○,◆,□,( ),( )。", + "options": [], + "answer": "30;50 28;22 ○;◆", + "solution": "【分析】(1)从左到右,依次加5,据此回答即可;(2) 从左到右,依次减 2,据此回答即可;(3) 从左到右, 1 个白色正方形, 1 个白色圆形, 1 个黑色菱形,循环出现,据此回答即可。\n\n【详解】(1)25+5=30,45+5=50, 25,(30),35,40,45,(50)。(2)30-2=28,24-2=22, 30,(28),26,24,(22)。(3)□,○,◆,□,○,◆,□,(○),(◆)。", + "knowledge_points": [ + "数字排列的规律", + "图形的规律" + ], + "source": "21-22一年级下·广东江门·期末" + }, + { + "id": "252", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.65, + "question": "找规律,画一画,写一写.\n\n(1)◆ ○ ○ △ ◆ ○ ○ △ ◆ ○ ○ △ ◆ ○( )\n(2)8, 12, 16, 20, ( )。", + "options": [], + "answer": "○;24", + "solution": "【分析】(1)图形按 菱形,圆形,圆形,三角形的顺序循环排列;(2) 右边的数比左边相邻的数大 4 。仔细观察,找出图形和数字排列的规律是解题关键。\n\n【详解】 (1) 一个圆形后面应该还有一个圆形;(2) 20 + 4 = 24, 8, 12, 16, 20, 24。", + "knowledge_points": [ + "数字排列的规律", + "图形的规律" + ], + "source": "21-22一年级下·山东菏泽·期末" + }, + { + "id": "253", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.65, + "question": "找规律填数.\n\n(1)90,85,80,( ),( ),65,60.\n(2)( ),( ),33,43,53,63。", + "options": [], + "answer": "75;70;13;23", + "solution": "【分析】(1)从左到右,数字依次减5,据此解答即可;(2) 从左到右,数字依次加 10,据此解答即可。通过观察,分析,归纳发现其中的规律,并应用发现的规律解决问题是应该具备的基本能力。\n\n【详解】 (1) 90, 85, 80, 75, 70, 65, 60。 (2) 13, 23, 33, 43, 53, 63。", + "knowledge_points": [ + "数字排列的规律" + ], + "source": "21-22 一年级下·山东德州·期末" + }, + { + "id": "254", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.65, + "question": "找规律填数.\n\n(1)8,12,16,( ),( ),28,32,36.\n(2)42,36,30,24,( ),( ),( )。", + "options": [], + "answer": "20;24;18;12;6", + "solution": "【分析】(1)第一行整数从左到右,依次加 4,据此解答即可;(2) 第二行整数从左到右,依次减 6,据此解答即可。通过观察,分析,归纳发现其中的规律,并应用发现的规律解决问题是应该具备的基本能力。\n\n【详解】(1)16+4=20,20+4=24,8,12,16,20,24,28,32,36。(2)24-6=18,18-6=12,42,36,30,24,18,12,6。", + "knowledge_points": [ + "数字排列的规律" + ], + "source": "21-22 一年级下·湖北孝感·期末" + }, + { + "id": "255", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.65, + "question": "如图所示方盒遮住了( )颗珠子.\n\n![](images/Pasted image 20251214162846.png)", + "options": [], + "answer": "5", + "solution": "【分析】首先观察图示,发现规律:黑珠子 1 个,白珠子呈现出 1,2,3,4,5,6,。通过图可知,盒子前是一颗黑色珠子,接下来应该会出现 4 颗黑色珠子,由于盒子外面有 5 个黑色珠子,即盒子内还会有一颗黑色珠子,据此答题即可。\n\n【详解】由图分析可得:方盒遮住了 4 颗白珠子,1 颗黑珠子。4 + 1 = 5 (颗)方盒遮住了 5 颗珠子.\n\n[点睛]本题考查找规律问题,找到共同特征解决问题即可。", + "knowledge_points": [ + "间隔问题" + ], + "source": "21-22 一年级下·湖南娄底·期末" + }, + { + "id": "256", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.65, + "question": "找规律填数.\n\n(1)
124711( )( )
\n(2)
36302418( )( )
", + "options": [], + "answer": "16;22;12;6", + "solution": "【分析】(1)从左往右依次增加 1,2,3,4,5,6;(2) 从左往右依次减少 6。通过观察,分析,归纳发现其中的规律,并应用发现的规律解决问题是应该具备的基本能力。\n\n【详解】 (1) 11 + 5 = 16;16 + 6 = 22
1247111622
(2) 18 - 6 = 12;12 - 6 = 6
36302418126
", + "knowledge_points": [ + "数字排列的规律" + ], + "source": "21-22 一年级下·湖南娄底·期末" + }, + { + "id": "257", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.85, + "question": "按顺序填数.\n\n38,39,( ),41,( ).\n\n80, 78, ( ), 74, ( )。", + "options": [], + "answer": "40;42;76;72", + "solution": "【分析】 (1) 从左到右依次加 1;(2) 从左到右依次减 2。通过观察,分析,归纳发现其中的规律,并应用发现的规律解决问题是应该具备的基本能力。\n\n【详解】(1)39+1=4041+1=4238,39,40,41,42。 (2)78-2=7674-2=7280,78,76,74,72。", + "knowledge_points": [ + "数字排列的规律" + ], + "source": "21-22一年级下·广东东莞·期末" + }, + { + "id": "258", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.85, + "question": "(1)90, 80, ( ), 60, ( ), 40.\n\n(2)32,34,36,( ),( ),42。", + "options": [], + "answer": "70;50;38;40", + "solution": "【分析】(1)从左到右依次减10;(2)从左到右依次加2。通过观察,分析,归纳发现其中的规律,并利用发现的规律解决问题是应该具备的基本能力。\n\n【详解】(1)80-10=7060-10=5090,80,70,60,50,40。 (2)36+2=3838+2=40\n32,34,36,38,40,42。", + "knowledge_points": [ + "数字排列的规律", + "整十数之间的加减法", + "两位数与一位数的加法(不进位)", + "一位数与两位数的进位加法" + ], + "source": "21-22一年级下·广东东莞·期末" + }, + { + "id": "259", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.85, + "question": "找规律填一填.\n\n(1)12,16,( ),( ),28,( ).\n\n(2)△☆☆○△( )( )。", + "options": [], + "answer": "20;24;32 ☆;○", + "solution": "【分析】 (1) 从左往右依次加 4;(2) 每 4 个图形一循环,按三角形,五角星,五角星,圆的顺序排列。通过观察,分析,归纳发现其中的规律,并利用发现的规律解决问题是应该具备的基本能力。\n\n【详解】(1)16+4=20,20+4=24,28+4=32, 12,16,20,24,28,32。(2)三角形后面是五角星,两个五角星后面是圆。△☆☆○△☆☆○。", + "knowledge_points": [ + "数字排列的规律", + "图形的规律", + "两位数与一位数的加法(不进位)" + ], + "source": "21-22 一年级下·河南郑州·期末" + }, + { + "id": "260", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.65, + "question": "在括号里写适当的数.\n\n(1)40, 45, 50, 55, ( ), ( ).\n\n(2)20,24,28,32,( ),( )。", + "options": [], + "answer": "60;65;36;40", + "solution": "【分析】(1)规律:从左到右依次加5;(2) 规律:从左到右依次加 4 。通过观察,分析,归纳发现其中的规律,并应用发现的规律解决问题是应该具备的基本能力。\n\n【详解】 (1)55+5=6060+5=6540,45,50,55,60,65。 (2)32+4=3636+4=4020,24,28,32,36,40。", + "knowledge_points": [ + "数字排列的规律", + "整十数加,减一位数", + "两位数与一位数的加法(不进位)", + "一位数与两位数的进位加法" + ], + "source": "21-22 一年级下·河南周口·期末" + }, + { + "id": "261", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.65, + "question": "找规律填数.\n\n(1)45, 50, ( ), 60.\n\n(2)92, 90, 88, ( )。", + "options": [], + "answer": "55;86", + "solution": "【分析】(1)右边的数比左边相邻的数大 5;(2) 右边的数比左边相邻的数小 2 。通过观察,分析,归纳发现其中的规律,并应用发现的规律解决问题是应该具备的基本能力。\n\n【详解】(1)50+5=5545,50,55,60。 (2)88-2=8692,90,88,86。", + "knowledge_points": [ + "数字排列的规律" + ], + "source": "21-22 一年级下·四川广元·期末" + }, + { + "id": "262", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.65, + "question": "按规律填数.\n\n25,35,45,( ),( ),75。", + "options": [], + "answer": "55;65", + "solution": "【分析】根据题干,得出规律:相邻两数之间相差 10,并且从左到右数越来越大。据此根据数数的方法数出即可。本题考查找数列中的规律,注意两数间的关系。\n\n【详解】由分析可知:25,35,45,55,65,75。", + "knowledge_points": [ + "数字排列的规律" + ], + "source": "21-22 一年级下·湖南怀化·期末" + }, + { + "id": "263", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.65, + "question": "找规律填数.\n\n2, 4, 6, 8, ( ), ( ), ( ).\n\n1, 11, 21, ( ), 41, 51, ( ), ( )。", + "options": [], + "answer": "10;12;14 31;61;71", + "solution": "【分析】第一行数从左到右,依次加 2,据此解答;第二行数从左到右,依次加 10,据此解答。通过观察,分析,归纳发现其中的规律,并应用发现的规律解决问题是应该具备的基本能力。\n\n【详解】2,4,6,8,(10),(12),(14)。 1,11,21,(31),41,51,(61),(71)。", + "knowledge_points": [ + "数字排列的规律" + ], + "source": "21-22 一年级下·广东汕尾·期末" + }, + { + "id": "264", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.65, + "question": "找规律填数.\n\n2, 3, 5, 7, 10, 15, ( ), 32。", + "options": [], + "answer": "22", + "solution": "【分析】通过观察可知,2+5=7,3+7=10,5+10=15,按照此规律解答即可。此题主要考查学生对找规律问题的分析和应用。\n\n【详解】7+15=22", + "knowledge_points": [ + "数字排列的规律" + ], + "source": "21-22 六年级上·广东揭阳·期中" + }, + { + "id": "265", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.65, + "question": "找规律填数.\n\n(1)3, 6, 9, 12, ( ), ( ), 21.\n(2)11,22,( ),( ),55,66,77.\n(3)57,51,( ),( ),33,( ),21。", + "options": [], + "answer": "15;18;33;44 45;39;27", + "solution": "【分析】 (1) 从左往右,依次加 3;(2) 从左往右,依次加 11;(3) 从左往右,依次减 6。通过观察,分析,归纳发现其中的规律,并应用发现的规律解决问题是应该具备的基本能力。\n\n【详解】 (1) 3, 6, 9, 12, 15, 18, 21。(2) 11, 22, 33, 44, 55, 66, 77。 (3) 57, 51, 45, 39, 33, 27, 21。", + "knowledge_points": [ + "数字排列的规律" + ], + "source": "20-21 一年级下·青海玉树·期末" + }, + { + "id": "266", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.65, + "question": "按规律填一填.\n\n(1) □ △ △ □ △ △ □ △ △ ( ) ( ) .\n(2) 75, 80, 85, 90, ( ), ( )。", + "options": [], + "answer": "□;△;95;100", + "solution": "【分析】(1)规律:依次按□ △排列;(2) 规律:依次加 5 进行填写。通过观察,分析,归纳发现其中的规律,并应用发现的规律解决问题是应该具备的基本能力。\n\n【详解】 (1) □ △ △ □ △ △ □ △ △ □ △ (2) 75,80,85,90,95,100。", + "knowledge_points": [ + "数字排列的规律", + "周期问题" + ], + "source": "21-22 一年级下·广东汕尾·期末" + }, + { + "id": "267", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.65, + "question": "找规律填数.\n\n7, 9, 11, ( ), ( ), ( ), 19, 21.\n\n30,26,22,18,( ),( ),( )。", + "options": [], + "answer": "13;15;17;14;10;6", + "solution": "【分析】(1)根据题中数据,从左往右依次增加 2,由此解答;(2) 根据题中数据,从左往右依次减少 4,由此解答。通过观察,分析,归纳发现其中的规律,并应用发现的规律解决问题是应该具备的基本能力。\n\n【详解】11+2=13   13+2=15   15+2=177,9,11,13,15,17,19,21.18-4=14   14-4=10   10-4=630,26,22,18,14,10,6。", + "knowledge_points": [ + "数字排列的规律" + ], + "source": "21-22一年级下·广西玉林·期末" + }, + { + "id": "268", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.65, + "question": "按规律填数.\n\n(1)3,7,11,( ),( ),23,27,31.\n(2)70, 75, ( ), 85, ( )。", + "options": [], + "answer": "15;19;80;90", + "solution": "【分析】(1)根据题中数据,从左往右依次增加 4,由此解答;(2) 根据题中数据,从左往右依次增加 5,由此解答。通过观察,分析,归纳发现其中的规律,并应用发现的规律解决问题。\n\n【详解】(1)11+4=15, 15+4=19, 3,7,11,15,19,23,27,31。(2)75+5=80, 85+5=90, 70,75,80,85,90。", + "knowledge_points": [ + "数字排列的规律" + ], + "source": "21-22 一年级下·黑龙江鸡西·期末" + }, + { + "id": "269", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.65, + "question": "按规律填出下一个数.\n\n7,11,15,( ),( ),27,( ),35。", + "options": [], + "answer": "19;23;31", + "solution": "【分析】根据题中数据,从左往右依次多4,由此解答。通过观察,分析,归纳发现其中的规律,并应用发现的规律解决问题是应该具备的基本能力。\n\n【详解】15+4=19, 19+4=23, 27+4=31, 7,11,15,19,23,27,31,35。", + "knowledge_points": [ + "数字排列的规律" + ], + "source": "20-21 一年级下·河北张家口·期末" + }, + { + "id": "270", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.65, + "question": "按规律填一填.\n\n(1)1,3,5,7,9,( ),( ),( ).\n(2)36,45,54,63,72,( ),( )。", + "options": [], + "answer": "11;13;15;81;90", + "solution": "【分析】 (1) 依次加 2;(2) 依次加 9。通过观察,分析,归纳发现其中的规律,并应用发现的规律解决问题是应该具备的基本能力。\n\n【详解】(1)9+2=11,11+2=13,13+2=151,3,5,7,9,11,13,15。 (2)72+9=81,81+9=90, 36,45,54,63,72,81,90。", + "knowledge_points": [ + "数字排列的规律", + "一位数与两位数的进位加法" + ], + "source": "21-22 一年级下·河南漯河·期末" + }, + { + "id": "271", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.85, + "question": "先找出下列数排列的规律,然后在括号里填上适当的数.\n\n3,2,5,2,7,2,( ),( ),( ),2。", + "options": [], + "answer": "9;2;11", + "solution": "【分析】 5-3=2;7-5=2,即单数项依次加2,双数项都是2,依此填空。此题考查的是数字排列的规律,应先根据已知数找到规律再填空。\n\n【详解】7+2=9,9+2=11,即:3,2,5,2,7,2,9,2,11,2。", + "knowledge_points": [ + "数字排列的规律" + ], + "source": "21-22 四年级下·湖南娄底·期末" + }, + { + "id": "272", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.65, + "question": "找规律填数.\n\n(1)5, 10, ( ), 20, ( ).\n(2)64,54,44,( ),24。", + "options": [], + "answer": "15;25;34", + "solution": "【分析】(1)从左到右依次加 5,据此解答;(2) 从左到右依次减 10 即可。本题考查数列的排列,培养学生逻辑思维能力。\n\n【详解】(1)5+5=10,10+5=15,15+5=20,20+5=25,所以5,10,(   15   ),20,(   25   ).\n(2)64-10=54,54-10=44,44-10=34,34-10=24,所以64,54,44,(   34   ),24。", + "knowledge_points": [ + "数字排列的规律" + ], + "source": "21-22一年级下·浙江温州·期中" + }, + { + "id": "273", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.65, + "question": "找规律填数:\n\n16,18,20,( ),( ),26,28。", + "options": [], + "answer": "22;24", + "solution": "【分析】根据题意可知,从左到右依次加 2 即可解答。本题考查数字的排列,培养学生的逻辑思维能力。\n\n【详解】16+2=18,18+2=20,20+2=22,22+2=24,24+2=26,26+2=28;所以16,18,20,(   22   ),(   24   ),26,28。", + "knowledge_points": [ + "数字排列的规律" + ], + "source": "21-22 一年级下·贵州遵义·期末" + }, + { + "id": "274", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.65, + "question": "在括号里写适当的数.\n\n(1)6, 10, 14, ( ), 22, ( ).\n(2)96, 93, 90, ( ), 84, ( )。", + "options": [], + "answer": "18;26;87;81", + "solution": "【分析】(1)中的数从左到右,依次加4,据此解答即可;(2) 中的数从左到右,依次减3,据此解答即可。通过观察,分析,归纳并发现其中的规律,并应用发现的规律解决问题是应该具备的基本能力。\n\n【详解】 (1) 6, 10, 14, (18), 22, (26)。(2) 96, 93, 90, (87), 84, (81)。", + "knowledge_points": [ + "数字排列的规律" + ], + "source": "21-22 一年级下·四川眉山·期末" + }, + { + "id": "275", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.65, + "question": "找规律,画一画,填一填.\n\n(1) ○ △ △ ○ △ △ ○ △ △ ( )( )\n(2)7, 11, 15, ( ), ( ), 27。", + "options": [], + "answer": "○;△;19;23", + "solution": "【分析】(1)根据题意可知: ○ △ △ 为一循环,按此顺序循环,据此解答;(2) 从左到右依次加 4 即可;\n\n【详解】(1)根据分析可知,○ △ △ ○ △ △ ○ △ △( ○ , △ )。(2) 7+4=11,11+4=15,15+4=19,19+4=23,23+4=27,所以7,11,15,19,23,27。", + "knowledge_points": [ + "数字排列的规律", + "周期问题" + ], + "source": "21-22一年级下·西藏林芝·期末" + }, + { + "id": "276", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.85, + "question": "▲○▲○▲○▲( )( )。", + "options": [], + "answer": "○;▲", + "solution": "【分析】由图形可知题中的规律是:一个黑色的三角形和一个白色的圆形循环,由此根据规律即可写答案。解答本题的关键是找出题中的规律,再由规律作答。\n\n【详解】 ▲○▲○▲○▲(○)(▲)。", + "knowledge_points": [ + "图形的规律", + "间隔问题" + ], + "source": "19-20 一年级下·青海果洛·期末" + }, + { + "id": "277", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.65, + "question": "按规律填一填.\n\n12,15,18,( ),24,( ),30,( )。", + "options": [], + "answer": "21;27;33", + "solution": "【分析】根据数据,可知规律为:从左往右依次多 3,由此解答。通过观察,分析,归纳发现其中的规律,并应用发现的规律解决问题是应该具备的基本能力。\n\n【详解】18+3=21,24+3=27,30+3=33,12,15,18,21,24,27,30,33。", + "knowledge_points": [ + "数字排列的规律" + ], + "source": "21-22一年级下·甘肃天水·期末" + }, + { + "id": "278", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.65, + "question": "按规律画一画.\n\n○ ○ □ ○ ○ □ ○ ○ □ ○ ( ),( ),( )。", + "options": [], + "answer": "○;□;○", + "solution": "【分析】由题可知,规律为 2 个 ○ 和 1 个 □ 是一个循环,据此画出。通过观察,分析,归纳发现其中的规律,并应用发现的规律解决问题是应该具备的基本能力。\n\n【详解】由分析可知:○ ○ □ ○ ○ □ ○ ○ □ ○ ○ □ ○。", + "knowledge_points": [ + "图形的规律" + ], + "source": "21-22 一年级下·甘肃天水·期末" + }, + { + "id": "279", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.65, + "question": "找规律,填一填.\n\n(1)6, 16, 26, 36, ( ), ( ).\n(2) ○ △ □ ○ △ □ ○ △ □ ( )( ).\n(3)▲ ○ ▲ ○ ○ ▲ ○ ○ ○ ▲ ○ ○( )", + "options": [], + "answer": "46;56 ○;△ ○;○;▲", + "solution": "【分析】这道题主要考查学生对数字和图形排列规律的观察能力。(1)数字 6,16,26,36 依次增加 10,所以后面的两个数也要在前一个数的基础上加 10。(2)图形按\"○,△,□\"的顺序循环排列,已经出现了三组完整的排列,因此后面应继续按照这个顺序填写。(3)观察可知,▲之间夹着的○个数依次增加:第1次有1个○,第2次有2个○,第3次有3个○,所以后面应接着补上2个○,再出现1个▲。\n\n【详解】(1)因为相邻两个数相差 10,所以 36+10=46,46+10=56。填空为:46,56。(2)图形是按\"○,△,□\"依次重复排列的:○ △ □ ○ △ □ ○ △ □ 。所以后面应填:○,△。(3)图形排列为:▲ ○ ▲ ○ ○ ▲ ○ ○ ○ ▲ ○ ○( )可以发现:第1个▲和第2个▲之间有1个○;第2个▲和第3个▲之间有2个○;第3个▲和第4个▲之间有3个○。按照这个规律,接下来应先补满3个○,再出现下一个▲。题中第4组后面已经有2个○,所以还缺1个○;再往后继续填1个○,▲。因此应填:○,○,▲。", + "knowledge_points": [ + "数字排列的规律", + "图形的规律" + ], + "source": "21-22 一年级下·江西上饶·期末" + }, + { + "id": "280", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.65, + "question": "想一想,再填数.\n\n( ),5,9,13,( ),( ),25。", + "options": [], + "answer": "1;17;21", + "solution": "【分析】由题可知规律为:从左往右依次多 4,由此解答。通过观察,分析,归纳发现其中的规律,并应用发现的规律解决问题是应该具备的基本能力。\n\n【详解】5-4=1, 13+4=17, 17+4=21, 1,5,9,13,17,21,25。", + "knowledge_points": [ + "数字排列的规律" + ], + "source": "21-22 一年级下·四川广元·期末" + }, + { + "id": "281", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.65, + "question": "按规律填数.\n\n(1)98, 88, 78, ( ), ( ).\n(2)2, 6, 10, ( ), ( ), 22。", + "options": [], + "answer": "68;58;14;18", + "solution": "【分析】(1)从左到右,依次减 10,解答即可;(2) 从左到右,依次加 4,解答即可;本题考查数字的排列规律,培养学生的逻辑思维能力。\n\n【详解】(1)98-10=88,88-10=78,78-10=68,68-10=58,所以98,88,78,(  68  ),(  58  )。(2)2+4=6,6+4=10,10+4=14,14+4=18,18+4=22,所以2,6,10,(  14  ),(  18  ),22。", + "knowledge_points": [ + "数字排列的规律" + ], + "source": "21-22 一年级下·河南南阳·期末" + }, + { + "id": "282", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.65, + "question": "找规律填空.\n\n(1)5,10,15,20,( ),( ).\n(2)12,14,16,18,( ),( )。", + "options": [], + "answer": "25;30;20;22", + "solution": "【分析】(1)从左到右依次加 5,据此解答;(2) 从左到右依次加 2,据此解答。本题考查数字之间的规律,培养学生逻辑推理能力。\n\n【详解】(1)5+5=10,10+5=15,15+5=20,20+5=25,25+5=30,所以5,10,15,20,(   25   ),(   30   )。(2)12+2=14,14+2=16,16+2=18,18+2=20,20+2=22,所以12,14,16,18,(   20   ),(   22   )。", + "knowledge_points": [ + "数字排列的规律" + ], + "source": "20-21 一年级下·广东江门·期末" + }, + { + "id": "283", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.65, + "question": "按规律填数\n\n(1)49, 51, ( ), 55, ( ).\n(2)( ),80,70( ),50。", + "options": [], + "answer": "53;57;90;60", + "solution": "【分析】(1)从左到右,依次加2,解答即可;(2) 从右到左,依次加 10,解答即可。本题考查找规律填数,通过观察找到数与数之间的规律。\n\n【详解】 (1)49+2=51,51+2=53,53+2=55,55+2=57,所以49,51,(   53   ),55,(   57   )。(2)50+10=60,60+10=70,70+10=80,80+10=90,所以(   90   ),80,70,(  60   ),50。", + "knowledge_points": [ + "数字排列的规律" + ], + "source": "20-21 一年级下·湖北鄂州·期末" + }, + { + "id": "284", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.65, + "question": "小花按规律穿了一串手链,但掉了6颗珠子,掉的是( )颗黑珠子,( )颗白珠子.\n\n![](images/Pasted image 20251214164927.png)", + "options": [], + "answer": "3;3", + "solution": "【分析】由图可知, 2 颗黑珠子和 3 颗白珠子为一个周期,所以掉的六颗珠子的顺序是: ●○○○●●, 数出对应的数量,解答即可。本题考查简单的周期,间隔问题,培养学生逻辑思维的能力。\n\n【详解】根据分析可知,掉的是 3 颗黑珠子,3 颗白珠子。", + "knowledge_points": [ + "周期问题" + ], + "source": "21-22一年级下·湖南岳阳·期末" + }, + { + "id": "285", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.65, + "question": "按规律填一填.\n\n(1)○ △ △ ○ △ △ ○ △ △( )( )( )\n(2)19, 29, 39, ( ), ( )。", + "options": [], + "answer": "○;△;△ 49;59", + "solution": "【分析】(1)题目中的图形是按 ○ △△的顺序循环排列的;(2) 这组数据中右边的数比左边相邻的数大 10,用左边的数加 10 即可得到右边相邻的数。找出图形和数据的排列规律是解题的关键。\n\n【详解】(1)由分析可知:这三个横线上依次填 ○;△;△ (2) 39 + 10 = 49, 49 + 10 = 59。", + "knowledge_points": [ + "数字排列的规律", + "图形的规律", + "两位数与整十数的加法" + ], + "source": "21-22一年级下·河南三门峡·期末" + }, + { + "id": "286", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.65, + "question": "接着画一画.\n\n△ △△ △△△( )( )( )", + "options": [], + "answer": "△△△△;△△△△△;△△△△△△", + "solution": "【分析】观察图形数量可知,从左往右每次增加一个三角形,据此画出图形即可。本题的解答关键是先观察出图形变化规律。\n\n【详解】△ △△ △△△ △△△△ △△△△△ △△△△△△", + "knowledge_points": [ + "图形的规律", + "数一数" + ], + "source": "21-22 一年级下·河南信阳·期末" + }, + { + "id": "287", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.65, + "question": "按规律写数.\n\n3,6,9,12,15,( ),( ).\n\n99,88,77,66,( ),( )。", + "options": [], + "answer": "18;21;55;44", + "solution": "【分析】(1)从左往右每次加3,由此解答;(2) 从左往右依次减11,由此解答。本题主要考查数字的规律,解答的关键是根据已有数据找出规律,再解答。\n\n【详解】3,6,9,12,15,18,21;99, 88, 77, 66, 55, 44。", + "knowledge_points": [ + "数字排列的规律" + ], + "source": "21-22 一年级下·山东临沂·期末" + }, + { + "id": "288", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.65, + "question": "按规律填数.\n\n( ),88,( ),( ),( ),( ).\n\n60,( ),( ),45,( )。", + "options": [], + "answer": "99;77;66;55;50 55;50;40", + "solution": "【分析】(1)由题可知,从左往右依次少 11,由此规律解答;(2) 从左向右依次少 5,由此规律解答。通过观察,分析,归纳并发现其中的规律,并应用发现的规律解决问题是应该具备的基本能力。\n\n【详解】(1)99,88,77,66,55,50。(2)60,55,50,45,40。", + "knowledge_points": [ + "数字排列的规律" + ], + "source": "21-22 一年级下·福建泉州·期中" + }, + { + "id": "289", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.65, + "question": "找规律填一填.\n\n65,70,75,80,( ),( ),( )。", + "options": [], + "answer": "85;90;95", + "solution": "【分析】观察题干相邻的数字可得:从左往右,相邻的两个数字每次增加 5,据此即可得出答案。本题的解答关键是先找出各个数字之间存在的规律。\n\n【详解】65,70,75,80,(85),(90),(95)。", + "knowledge_points": [ + "数字排列的规律" + ], + "source": "21-22 一年级下·河南信阳·期末" + }, + { + "id": "290", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.65, + "question": "按规律写数.\n\n26,32,( ),44,50,( ).\n\n80,75,80,75,( ),( ),80。", + "options": [], + "answer": "38;56;80;75", + "solution": "【分析】(1)通过观察用前面一个数加 6 等于后面的数;(2) 通过观察 80 和 75 依次循环。本题主要考查了数字的排列规律。\n\n【详解】 26+6=32, 32+6=38, 38+6=44, 44+6=50, 50+6=56, 26,32,(38),44,50,(56); 80,75,80,75,(80),(75),80", + "knowledge_points": [ + "数字排列的规律" + ], + "source": "21-22 一年级下·湖北省直辖县级单位·期末" + }, + { + "id": "291", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.85, + "question": "按□☆○□☆○这样的顺序摆图形,第 16 个图形是( )。", + "options": [], + "answer": "□", + "solution": "【分析】根据题意,图中每 3 个循环一次,据此可知第 16 个是第 6 个周期的第一个,由此解答。解答本题的关键是找出题中的规律,再进一步解答。\n\n【详解】□☆○□☆○这样的顺序摆图形,第 16 个图形是□。", + "knowledge_points": [ + "图形的规律" + ], + "source": "21-22 一年级下·四川德阳·期末" + }, + { + "id": "292", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.65, + "question": "按规律填一填.\n\n(1)10,19,28,( ),( ),55.\n(2)77, 66, ( ), ( ), 33。", + "options": [], + "answer": "37;46;55;44", + "solution": "【分析】(1)观察前面3个数可知:19=10+9,28=19+9;由此得后面一个数等于前面一个数加9;(2)观察前面两个数可知,十位数和个位数一样,且都比前面的数小1;据此解答。本题主要考查了数字排列的规律。\n\n【详解】(1)28+9=37,37+9=46,所以28后面的两个数分别为37,46。(2)6-1=5,5-1=4,所以66后面的两个数分别为:55,44。", + "knowledge_points": [ + "数字排列的规律" + ], + "source": "21-22一年级下·广东韶关·期末" + }, + { + "id": "293", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.85, + "question": "按规律填空:\n\n3,5,9,( ),23,33。", + "options": [], + "answer": "15", + "solution": "【分析】通过观察可知:3+2=5,5+4=9,9+6=15,15+8=23,23+10=33,发现规律:相邻两数的差分别为:2,4,6,8,10。由此解答。通过观察,分析,归纳发现数列中的规律,并应用发现的规律解决问题。\n\n【详解】 9 + 6 = 15, 3, 5, 9, 15, 23, 33。", + "knowledge_points": [ + "数字排列的规律" + ], + "source": "2022·云南曲靖·小升初真题" + }, + { + "id": "294", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.65, + "question": "先找规律再填数.\n\n(1)33, 35, 37, ( ), ( ).\n(2)65, 60, 55, ( ), ( )。", + "options": [], + "answer": "39;41;50;45", + "solution": "【分析】(1)根据前面的三个数可得数字排列的规律为:依次加 2;(2) 根据前面的三个数可得数字排列的规律为:依次减5。此题的关键是通过观察,分析,归纳发现其中的规律,并应用发现的规律解决问题。 \n\n【详解】(1)由分析得: 37+2=39,39+2=41,则剩下的两个数为:39,41。(2)由分析得: 55-5=50,50-5=45,则剩下的两个数为:50,45。", + "knowledge_points": [ + "数字排列的规律" + ], + "source": "21-22 一年级下·四川自贡·期末" + }, + { + "id": "295", + "unit": "找规律", + "question_type": "填空题", + "difficulty": 0.65, + "question": "找规律填一填.\n\n(1)66,55,44,( ),( ).\n(2)玲玲按规律穿了一串手链,但最右端掉了4颗珠子,掉的是( )颗●,( )颗○.\n\n![](images/Pasted image 20251214165827.png)", + "options": [], + "answer": "33;22 1;3", + "solution": "【分析】这道题考查学生发现数字排列规律和图形排列规律的能力。(1)66,55,44这几个数的个位和十位上的数字都相同,并且依次减少1,所以后面的数也应继续按这个规律填写.\n(2)观察手链上的珠子可以发现,珠子是按\"2颗黑珠,3颗白珠\"这样的顺序重复排列的。最右端掉了4颗珠子,只要按照前面的排列规律继续往后推,就能判断掉了哪几颗珠子。\n\n【详解】(1)66,55,44中,个位和十位数字相同,而且每次都减少1:66→55→44→33→22\n所以括号里应填:33,22。(2)手链上的珠子排列规律是:●●○○○ ●●○○○ ●●○○○ 。也就是每5颗珠子为一组,其中前2颗是黑珠,后3颗是白珠。题中最右边露出的最后1颗是黑珠,说明这一组已经出现了第1颗黑珠,后面掉落的4颗珠子应依次是:第2颗黑珠,3颗白珠。所以掉的是1颗黑珠,3颗白珠。", + "knowledge_points": [ + "数字排列的规律", + "图形的规律" + ], + "source": "21-22 一年级下·福建三明·期末" + }, + { + "id": "296", + "unit": "找规律", + "question_type": "改错题", + "difficulty": 0.65, + "question": "圈出不符合规律的数字或图形,改在横线上.\n\n(1) □ □ △ □ □ △ △ □ \n(2) 4,7,10,13,15,17,19。", + "options": [], + "answer": "见详解", + "solution": "【分析】(1)由图可知,排列规律为 □ □ △ 为一组重复排列,所以第三个三角形错误,应改为长方形;(2) 由数字排列可知,每后一个数字比前一个数字多 3,所以 15,17,19 错误,应该改为 16,19,22。本题主要考查学生对图形,数字等按照一定规律排列问题的掌握情况。解决此题先观察图形,数字之间的关系,找出对应的规律即可。\n\n【详解】根据分析可知应修改如下:(1)![](images/Pasted image 20251214165939.png)(2)![](images/Pasted image 20251214170023.png)16,19,22", + "knowledge_points": [ + "数字排列的规律", + "图形的规律" + ], + "source": "21-22一年级下·全国·单元测试" + }, + { + "id": "297", + "unit": "找规律", + "question_type": "作图题", + "difficulty": 0.65, + "question": "按规律在下图的□里画一画.\n\n![](images/Pasted image 20251214170935.png)", + "options": [], + "answer": "![](images/Pasted image 20251214170947.png)", + "solution": "【分析】观察图形,可知其规律是黑珠子每隔 1 颗白珠子,则多 1 颗。解答本题的关键是找出题中的规律,再由规律作答。\n\n【详解】![](images/Pasted image 20251214170947.png)", + "knowledge_points": [ + "图形的规律" + ], + "source": "20-21一年级下·湖北十堰·期末" + }, + { + "id": "298", + "unit": "找规律", + "question_type": "作图题", + "difficulty": 0.65, + "question": "后面一个图形该是什么图形,在方框内圈一圈.\n\n![](images/Pasted image 20251214171022.png)", + "options": [], + "answer": "![](images/Pasted image 20251214171126.png)", + "solution": "【分析】![](images/Pasted image 20251214171052.png)每三个图形重复一次,因此正方形后面应该是圆形,善于发现图形的变化规律是解题的关键。\n\n【详解】![](images/Pasted image 20251214171118.png)", + "knowledge_points": [ + "图形的规律" + ], + "source": "21-22一年级下·山东菏泽·期末" + }, + { + "id": "299", + "unit": "找规律", + "question_type": "解答题", + "difficulty": 0.65, + "question": "哪个数不符合规律,把它圈出来,并改正在括号里.\n\n(1) 30, 32, 34, 36, 37, 40。 圈出( ) 改成()\n(2) 98, 88, 78, 65, 58, 48。圈出( ) 改成()\n(3) 42, 36, 27, 24, 18。 圈出( ) 改成()", + "options": [], + "answer": "37;38 65;68 27;30", + "solution": "【分析】(1)右边的数比左边相邻的数大 2,应该按 30,32,34,36,38,40 排列,37 不符合规律;(2) 右边的数比左边相邻的数小 10,按 98,88,78,68,58,48 排列, 65 不符合规律;(3) 右边的数比左边相邻的数小 6,按 42, 36, 30, 24, 18, 27 不符合规律。找出数据排列的规律是解题关键。\n\n【详解】 (1) 圈出 37;改成38。(2) 圈出 65;改成68。(3) 圈出 27;改成30。", + "knowledge_points": [ + "数字排列的规律" + ], + "source": "22-23 一年级下·全国·单元测试" + }, + { + "id": "300", + "unit": "找规律", + "question_type": "解答题", + "difficulty": 0.4, + "question": "按规律填上合适的数或图形.\n\n(1)20,5,15,5,10,5,( ),( ).\n(2)○, △ , ○○, △ , ○○○, △ , ( ), ( )。", + "options": [], + "answer": "5;5;○○○○;△", + "solution": "【分析】(1)单数项依次减5;双数项都是5。 (2) 单数项圆的个数依次加 1,双数项都是 1 个三角形。通过观察,分析,归纳发现其中的规律,并应用发现的规律解决问题是应该具备的基本能力。\n\n【详解】 (1) 20, 5, 15, 5, 10, 5, 5, 5。(2)○, △ , ○○, △ , ○○○, △ ,○○○○,△", + "knowledge_points": [ + "数字排列的规律", + "图形的规律", + "周期问题" + ], + "source": "20-21 二年级下·重庆黔江·期末" + } +] diff --git "a/\344\270\200\345\271\264\347\272\247\351\242\230\351\233\206/\344\270\200\345\271\264\347\272\247\344\270\213/\344\270\200\345\271\264\347\272\247\344\270\213\347\254\254\344\270\211\345\215\225\345\205\203\345\210\206\347\261\273\344\270\216\346\225\264\347\220\206.json" "b/\344\270\200\345\271\264\347\272\247\351\242\230\351\233\206/\344\270\200\345\271\264\347\272\247\344\270\213/\344\270\200\345\271\264\347\272\247\344\270\213\347\254\254\344\270\211\345\215\225\345\205\203\345\210\206\347\261\273\344\270\216\346\225\264\347\220\206.json" new file mode 100644 index 0000000000000000000000000000000000000000..91df65a9e178c6b98c4dc34c3d10a1308df7cd23 --- /dev/null +++ "b/\344\270\200\345\271\264\347\272\247\351\242\230\351\233\206/\344\270\200\345\271\264\347\272\247\344\270\213/\344\270\200\345\271\264\347\272\247\344\270\213\347\254\254\344\270\211\345\215\225\345\205\203\345\210\206\347\261\273\344\270\216\346\225\264\347\220\206.json" @@ -0,0 +1,3229 @@ +[ + { + "id": "1", + "unit": "第三单元分类与整理", + "question_type": "选择题", + "difficulty": 0.85, + "question": "下列物品中,( )不是学习用品。", + "options": [ + "A. 铅笔盒", + "B. 足球", + "C. 作业本" + ], + "answer": "B", + "solution": "【分析】根据题意,逐项分析各个选项,找出不是学习用品即可解答.\n【详解】A. 铅笔盒:用于收纳铅笔,橡皮等文具,属于学习用品。B. 足球:是体育运动的器材,不属于学习用品。C. 作业本:用于完成作业或记录学习内容,属于学习用品。故答案为:B", + "knowledge_points": [ + "按不同标准分类(单次)" + ], + "source": "24-25一年级下·湖南岳阳·期中" + }, + { + "id": "2", + "unit": "第三单元分类与整理", + "question_type": "选择题", + "difficulty": 0.85, + "question": "选出与其他两个不同类的图形 ( )。", + "options": [ + "A. ![](images/275489f8b7c4d89769c0527d0b572445.png)", + "B. ![](images/ae324ab98c58e461cc15affa43563a041c6d5431e6f24f4d6e7513837cd9bb57.jpg)", + "C. ![](images/bf02e1b937f93d9bc17c1e1328e8561d1e984a9d78a361fd34b82b9d63af5fc4.jpg)" + ], + "answer": "B", + "solution": "【分析】根据平面图形和立体图形的概念,依次分析各图形所属的类别,找出不同类的即可.\n【详解】A. 长长方方的,有4条直直的边,对边相等,是长方形,属于平面图形;B. 正正方方的,每个面都相同,是正方体,属于立体图形;C. 有 3 条直直的边,是三角形,属于平面图形。![](images/4ca9cc36c4b810d19023eb596467b5c27c1ad1b1c92de3cc2e70421525c79878.jpg)与其他两个不是同一类。故答案为:B", + "knowledge_points": [ + "立体图形的认识", + "按不同标准分类(单次)", + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "23-24 一年级下·江西抚州·期末" + }, + { + "id": "3", + "unit": "第三单元分类与整理", + "question_type": "选择题", + "difficulty": 0.85, + "question": "生活中的食物丰富多样,下面四种食物中,与其它三个不同类的是( )。", + "options": [ + "A. ![](images/a7c76aa55e11c66200ea3160535109bcda5ac6346a627b6bc291b7775a052485.jpg)", + "B. ![](images/b1e8507ab5619f2c6f67c6fb82c7103b2f8d8c83e0aacca7a5a8409a064547eb.jpg)", + "C. ![](images/ad64ef1f77d0973f114bb85ee73238f3502f010eb9174b3c91d1bb001882578.jpg)", + "D. ![](images/81f12a66c84c9823abe07b42e9ffcc588027508b304f3bc299f7f9ab0e0628f2.jpg)" + ], + "answer": "D", + "solution": "【分析】根据题意,依次分析各选项的食物所属的类别,找出不同类的即可.\n【详解】A. 萝卜属于蔬菜;B. 茄子属于蔬菜;C. 白菜属于蔬菜;D. 葡萄属于水果。与其它三个不同类的是葡萄。故答案为:D", + "knowledge_points": [ + "按不同标准分类(单次)" + ], + "source": "23-24 一年级下·福建龙岩·期末" + }, + { + "id": "4", + "unit": "第三单元分类与整理", + "question_type": "选择题", + "difficulty": 0.85, + "question": "下面一组图形中,不同类的是 ( )。", + "options": [ + "A. ![](images/e5c2fd5da455698cadba193b989b4ac7402812a0a6290696d7fab185b27bfe7c.jpg)", + "B. ![](images/750a92fc1a2ea204900405f7a1fb8b9664c7650bb8fed2d5f76205fb67007b1b.jpg)", + "C. ![](images/f5d6d99392c0c2993e7f97ae0f209501c380816ece42461b4a72f3e45677507a.jpg)" + ], + "answer": "C", + "solution": "【分析】根据立体图形和平面图形的初步认识进行分类,长方体:长长的方方的,有6个平平的面,相对的面一样大,正方体:正正的方方的,有6个平平的面都相等。三角形尖尖的,3条直直的边,首尾顺次相连,据此解答.\n【详解】A. ![](images/0dd7fdca123a04a4e88670c77e77222d99f681588f9fed1f53ea7ac786d63180.jpg)是立体图形;B. ![](images/200eda2ccc3bda70fbef4689ba6202a0689948332e45032eed05c7a46afbf8bd.jpg)是立体图形;C. ![](images/7770e5a0ad2e756a4bf6cb2ca92c6348c6764e87bdf6882488e8cb9d92a79a39.jpg)是平面图形;正方体和长方体是立体图形,三角形是平面图形,则不同类的是三角形。故答案为:C", + "knowledge_points": [ + "立体图形的认识", + "按不同标准分类(单次)", + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "23-24 一年级下·江西赣州·期末" + }, + { + "id": "5", + "unit": "第三单元分类与整理", + "question_type": "选择题", + "difficulty": 0.94, + "question": "下列物体中是由金属材料制成的是 ( )。", + "options": [ + "A. 钥匙", + "B. 数学书", + "C. 帽子", + "D. 纸杯" + ], + "answer": "A", + "solution": "【分析】根据生活经验,结合选项和题干要求进行解答即可.\n【详解】A. 钥匙是由金属材料制成的,符合题意;B. 数学书是由纸制成的,不符合题意;C. 帽子是由丝线和布制成的,不符合题意;D. 纸杯是由纸制成的,不符合题意。故答案为:A", + "knowledge_points": [ + "按不同标准分类(单次)" + ], + "source": "23-24 二年级上·福建莆田·期末" + }, + { + "id": "6", + "unit": "第三单元分类与整理", + "question_type": "选择题", + "difficulty": 0.85, + "question": "如图( )和其他两个不是一类的。", + "options": [ + "A. ![](images/bbd8af4bb9802548cfa2df3018c81115b46b789e48e5306ac2cfdbbea286bc0d.jpg)", + "B. ![](images/884a5e5ff77ed9acaecac1f8839248208dec82ad5db97d39ea18548b41035b0f.jpg)", + "C. ![](images/60a104fe0646e2fb2dd018227991f847a08f5a2fc0d81f0b4ca72581167dafc7.jpg)" + ], + "answer": "B", + "solution": "【分析】由题可知,白菜和茄子都是蔬菜,西瓜是水果,不是一类。据此解答.\n【详解】白菜和茄子都是蔬菜,西瓜是水果;所以西瓜和其他两个不是一类的。故答案为:B", + "knowledge_points": [ + "按不同标准分类(单次)" + ], + "source": "23-24一年级下·贵州六盘水·期末" + }, + { + "id": "7", + "unit": "第三单元分类与整理", + "question_type": "选择题", + "difficulty": 0.85, + "question": "下列图形中,( )和其他两个不同类。", + "options": [ + "A. 正方体", + "B. 平行四边形", + "C. 正方形" + ], + "answer": "A", + "solution": "【分析】正方体属于立体图形,正方形和平行四边形属于平面图形;也就是正方体和正方形,平行四边形是不同类;据此解决.\n【详解】由题意分析得:下列图形中,正方体和其他两个不同类。![](images/4c98f10d06a8fef960ff4226c235e1d48c440429fdb03a3b95df0e0f1a55920f.jpg)故答案为:A", + "knowledge_points": [ + "立体图形的认识", + "按不同标准分类(单次)", + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "22-23一年级下·甘肃天水·期中" + }, + { + "id": "8", + "unit": "第三单元分类与整理", + "question_type": "选择题", + "difficulty": 0.65, + "question": "给下边的图形分类,下面正确的是( )。", + "options": [ + "A. ![](images/46ee35011fdd84da2faf16a6dbfbf49a8bbfd55c705faebdbf3657bfa3a8add1.jpg)\n\n三角形 圆 平行四边形\n\n(每个●代表一个图形)", + "B. 图形统计表:\n\n| 图形 | | |\n| ---- | -- | -- |\n| 个数 | 4 | 2 |", + "C. 形状统计表:\n\n| 形状 | 三角形 | 圆 | 平行四边形 | 长方形 |\n| -------- | ------ | -- | ---------- | ------ |\n| 个数 | 2 | 2 | 2 | 1 |" + ], + "answer": "A", + "solution": "【分析】三角形有3条直直的边;圆没有直直的边;平行四边形有4条直直的边,对边相等,有 2 条同方向的斜边;长方形是长长方方的,有 4 条直直的边,对边相等。由此数出各图形的数量填空或判断.\n【详解】A. 三角形有2个;圆有2个;平行四边形有3个。此选项正确;B. 按图案分,画点的有 4 个,画斜线的有 2 个,还有一个没有图案的,此选项错误;C. 图中没有长方形,此选项错误.\n![](images/fe22038dd6f796af0a00ca97d6dd12b6.png)\n正确的是三角形 圆 平行四边形。故答案为:A", + "knowledge_points": [ + "按不同标准分类(单次)", + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "23-24一年级下·福建福州·期末" + }, + { + "id": "9", + "unit": "第三单元分类与整理", + "question_type": "选择题", + "difficulty": 0.85, + "question": "下面第( )组中的两种物品不是同一类。", + "options": [ + "A. 书包和文具盒", + "B. 上衣和裤子", + "C. 袜子和课桌椅" + ], + "answer": "C", + "solution": "【分析】依次分析各选项物品所属的类别,找出不是同一类的即可.\n【详解】A. 书包和文具盒都属于学习用品,是同一类;B. 上衣和裤子都属于衣服,是同一类;C. 袜子属于衣物类,课桌椅属于学习用品类,不是同一类。袜子和课桌椅不是同一类。故答案为:C", + "knowledge_points": [ + "按不同标准分类(单次)" + ], + "source": "22-23一年级下·广东汕头·期末" + }, + { + "id": "10", + "unit": "第三单元分类与整理", + "question_type": "选择题", + "difficulty": 0.85, + "question": "下面哪个图形与其他图形不是同一类。( )", + "options": [ + "A. ![](images/c1c481351dc5d04c3125df5d4046ccf9ea29e7f3572889f6210879716df3cef2.jpg)", + "B. ![](images/e449938b04929130a43cfe7372e0086d5fa50f6a39e4333d5629ad7850ab1bdc.jpg)", + "C. ![](images/345252ab887064f8afe1c181e73a004f74129572b00b964d3578d6f1dc0f5d4f.jpg)" + ], + "answer": "C", + "solution": "【分析】根据平面图形和立体图形的概念,依次分析各图形所属的类别,找到不是同一类的即可.\n【详解】A. 长长方方的,有4条直直的边,对边相等,是长方形,属于平面图形;B. 有 4 条直直的边,对边相等,有 2 条同方向的斜边,是平行四边形,属于平面图形;C. 正正方方的,每个面都相同,是正方体,属于立体图形。![](images/e3280fcc7b4bcbc1879c027dfadb5a874c37026155d7795d66ae602791e7354f.jpg)与其他图形不是同一类。故答案为:C", + "knowledge_points": [ + "立体图形的认识", + "按不同标准分类(单次)", + "平行四边形的初步认识", + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "23-24 一年级下·河南驻马店·期中" + }, + { + "id": "11", + "unit": "第三单元分类与整理", + "question_type": "选择题", + "difficulty": 0.85, + "question": "下面( )不是交通工具。", + "options": [ + "A. ![](images/18a0e3af9df1bf9e26f9cc6fba5330ff877937498bdc923d74d3252f0eee0e23.jpg)", + "B. ![](images/903c5ac797ccf70c2371f051d8b96f7b09c8eb1fe949f702123fee374f2dff1e.jpg)", + "C. ![](images/fa0a2b5fbe128ab0ae43875a631798ba44c51c6eb7cba1721540f0c4dab19440.jpg)" + ], + "answer": "A", + "solution": "【分析】根据分类的标准,结合生活实际可知,![](images/3cc4aa617079ee535cdf765c4d47a17e0675376efbd40b89334e185674bd4af9.jpg)![](images/3a3b5df37c1ed2ff5e3e5a1926bd18ee8b4197277188dee3091390b6bc0d75b9.jpg)是交通工具,![](images/45cbe09c763ce53b4dc5a2b1168fef2e57346965e3fc614125efbf65ab2d5a10.jpg)不是交通工具。据此解答即可.\n【详解】A. ![](images/2b5747846d98735bf4963598f131e4868b7db114d0e9f99cc7dc2322ee9fbf56.jpg)不是交通工具。![](images/1ba5d183ae544b80f9dcc6e77d1d53fe0ee83c47c34afa717c352136568e9022.jpg)是交通工具。B. ![](images/a44f6af84bcae539068556ad575cbab0de906e2cb44300ecae1bd48e05ee275.jpg)是交通工具。C. 是交通工具。故答案为:A", + "knowledge_points": [ + "按不同标准分类(单次)" + ], + "source": "23-24一年级下·河北沧州·期中" + }, + { + "id": "12", + "unit": "第三单元分类与整理", + "question_type": "选择题", + "difficulty": 0.85, + "question": "下面图形中,与其他不同的是 ( )。", + "options": [ + "A. ![](images/55f3d13d25be62d34dc428e04b9fa1372ea0de5e62bc263c9214f8bc2dbf1edd.jpg)", + "B. □", + "C. △", + "D. ○" + ], + "answer": "D", + "solution": "【分析】依次分析各图形的特点,找到与其他图形没有共同点的一个即可.\n【详解】A. ![](images/55f3d13d25be62d34dc428e04b9fa1372ea0de5e62bc263c9214f8bc2dbf1edd.jpg)有直直的边;B. □有直直的边;C. △ 有直直的边;D. ○没有直直的边。只有○没有直直的边,其他图形都有,所以与其他不同的是○。故答案为:D", + "knowledge_points": [ + "按不同标准分类(单次)", + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "23-24 一年级下·四川乐山·期中" + }, + { + "id": "13", + "unit": "第三单元分类与整理", + "question_type": "选择题", + "difficulty": 0.85, + "question": "给下面卡片分类的话,可以有( )种分法。", + "options": [ + "A. 2", + "B. 1", + "C. 不确定" + ], + "answer": "A", + "solution": "【分析】题中卡片上水果有:桃子,苹果,梨,可按水果种类分;正方形是由四条边首尾依次连接组成的封闭图形,四条边都相等;三角形是由三条边首尾依次连接组成的封闭图形;圆是由曲线围成的封闭图形。卡片形状有三角形,正方形,圆形,可按卡片形状分.\n【详解】由分析可知,给下面卡片分类的话,可以按水果种类或卡片形状分类,有 2 种分法。![](images/059a120735c0ddfef8ca358db4eef4ae.png)", + "knowledge_points": [ + "按不同标准分类(单次)" + ], + "source": "22-23一年级下·吉林·期中" + }, + { + "id": "14", + "unit": "第三单元分类与整理", + "question_type": "选择题", + "difficulty": 0.85, + "question": "下面哪一个物体与其他三个不是同一类。( )", + "options": [ + "A. ![](images/cbb718ddd76c8067b50c011cef3cccfe6160040e7f97c0345fed00513b8bf93d.jpg)", + "B. ![](images/d0a6011754057c7bf3777d8ed5643ad19d3300b12174508074d264c18ccb86c3.jpg)", + "C. ![](images/bb4b83eb42f151aeb85383fe53e57259d591e1ebab49be895cce11b61bcbd862.jpg)", + "D. ![](images/c84a416d3d4caaab63cd7e3fff1a7d25d4c0439bd9bc30ec1741483bae1ad693.jpg)" + ], + "answer": "C", + "solution": "【分析】依次分析各选项物品所属的类别,找到不同类的即可.\n【详解】A. 苹果属于水果;B. 梨属于水果;C. 小熊属于玩具;D. 桃子属于水果。小熊和其他三个不是同一类。故答案为:C", + "knowledge_points": [ + "按不同标准分类(单次)" + ], + "source": "23-24一年级上·广东河源·期末" + }, + { + "id": "15", + "unit": "第三单元分类与整理", + "question_type": "选择题", + "difficulty": 0.85, + "question": "与![](images/d9bea90fb2fdfe1bea6a218b409d18bb1c304fedc1310ce7b511418b0bbeec19.jpg)同类的是( )。", + "options": [ + "A. ![](images/830c2dd5529f9b1403acf40eb4674258bc90198e28e51505384c5c8a6a560aba.jpg)", + "B. ![](images/255a4a2c4467071ed21215cb85162bd4bee4801109926984fbcfd64c9b9264d2.jpg)", + "C. ![](images/41d824d00de27d03e8c20fd42f78fe59c630b0673074939e5991153c6b388141.jpg)" + ], + "answer": "C", + "solution": "【分析】苹果属于水果类,找到选项中属于水果类的即可.\n【详解】A. ![](images/e071ecec680ac890e5142dda457c3f802536d39d6b4ea4d61873b367d19cab9f.jpg) 属于花朵类;B. ![](images/916592da147ed6e45b964fbf097d3da84ca07d60b6752cc797d34bbbf94ea56b.jpg) 属于蔬菜类;C. ![](images/825484b5c62382bd94921b758fe7209068b82be1e1ea7ea11d5f72f659ee38eb.jpg) 属于水果类。与![](images/20ab9c8696edf93b7b28bf5fb9e848daa042545632c28c8bcb3a9536e7a99da1.jpg)同类的是![](images/825484b5c62382bd94921b758fe7209068b82be1e1ea7ea11d5f72f659ee38eb.jpg),故答案为:C", + "knowledge_points": [ + "按不同标准分类(单次)" + ], + "source": "23-24一年级上·河南驻马店·期末" + }, + { + "id": "16", + "unit": "第三单元分类与整理", + "question_type": "选择题", + "difficulty": 0.85, + "question": "下面不是文具的一项是( )。", + "options": [ + "A. ![](images/47ff14de0cafee97299eb3b1c8fdc570902e58a9b941ecec1249f714ff4dfb25.jpg)", + "B. ![](images/3cd829d471742059e09c3c0231adda874edcc201e1f8baed3ed04c24ad15c7e7.jpg)", + "C. ![](images/f0606a09ee5f839e65e5cb7e16dfdceab0dff609e07f977596b4892b0b576e6e.jpg)" + ], + "answer": "C", + "solution": "【分析】根据生活常识可知铅笔和橡皮都是文具,花不是文具,据此解答即可.\n【详解】不是文具的一项是花。故答案为:C", + "knowledge_points": [ + "按不同标准分类(单次)" + ], + "source": "23-24一年级上·河北保定·期末" + }, + { + "id": "17", + "unit": "第三单元分类与整理", + "question_type": "选择题", + "difficulty": 0.85, + "question": "下图是服装的有( )个。", + "options": [ + "A. 6", + "B. 5", + "C. 4" + ], + "answer": "C", + "solution": "【分析】根据题意作图如下:图中圈出来的是服装类的,数出数量解答即可.\n【详解】![](images/c0e2ee7a061d9a9bc4197f5c8eaed6e8.png)\n由分析可知,图中是服装的有4个。故答案为:C", + "knowledge_points": [ + "按不同标准分类(单次)" + ], + "source": "23-24一年级上·河北邯郸·期末" + }, + { + "id": "18", + "unit": "第三单元分类与整理", + "question_type": "选择题", + "difficulty": 0.65, + "question": "下面的食物中哪一种不是肉类的。 ( )", + "options": [ + "A. 烤肉片", + "B. 牛肉", + "C. 包子", + "D. 火腿" + ], + "answer": "C", + "solution": "【分析】根据生活常识中是肉类的标准即可解答。本题主要考查根据一定的标准,对事物进行分类。找到正确的分类方法是解答本题的关键.\n【详解】A. 烤肉片是肉类;B. 牛肉是肉类;C. 包子不一定有肉,所以不是肉类;D. 火腿是肉类。故答案为:C", + "knowledge_points": [ + "按不同标准分类(单次)" + ], + "source": "21-22 四年级上·福建莆田·期末" + }, + { + "id": "19", + "unit": "第三单元分类与整理", + "question_type": "选择题", + "difficulty": 0.85, + "question": "桌上有一些扣子,小明将它们逐层分类 (如下图)。他这样分类的标准是:( )。", + "options": [ + "A. 都按颜色分", + "B. 先按颜色分,再按扣眼数分", + "C. 都按扣眼数分", + "D. 先按颜色分,再按形状分" + ], + "answer": "B", + "solution": "【分析】观察题意可知,第一层把白色的扣子放一起,其他颜色放一起;第二层把扣眼相同的扣子放一起。据此解答。本题主要考查了按不同标准进行分类,比较简单.\n【详解】小明的分类标准是先按颜色分,再按扣眼数分。故答案为:B", + "knowledge_points": [ + "按不同标准分类(逐层)" + ], + "source": "23-24 五年级上·云南昆明·期中" + }, + { + "id": "20", + "unit": "第三单元分类与整理", + "question_type": "填空题", + "difficulty": 0.94, + "question": "分一分。(填序号)\n\n![](images/3c22d259413c654d75e52605a4d2c03a.png)\n\n奇奇:\"按照凳子腿的数量分( ),( ).\" 妙妙:\"按照凳子有没有靠背分( ),( ).\" 甜甜:\"我分成两类: ①,②③④⑤, 我是按( )分的.\"", + "options": [], + "answer": "①②③⑤;④;①③;②④⑤;有没有扶手", + "solution": "【分析】依据题意结合图示,按照凳子腿的数量4和3回答奇奇的问题,按照凳子有没有靠背回答妙妙的问题,甜甜按照有没有扶手分成两类,由此解答本题.\n【详解】奇奇:\"按照凳子腿的数量分①②③⑤,④.\"妙妙:\"按照凳子有没有靠背分①③,②④⑤.\"甜甜:\"我分成两类: ①,②③④⑤, 我是按有没有扶手分的.\"", + "knowledge_points": [ + "按不同标准分类(单次)" + ], + "source": "24-25一年级上·辽宁本溪·期中" + }, + { + "id": "21", + "unit": "第三单元分类与整理", + "question_type": "填空题", + "difficulty": 0.65, + "question": "分一分,填一填.\n\n![](images/78aefcbbdc4bf67ef78a6213711ff892352ada709f00f9d4aed4291179df70de.jpg)\n\n把分类的结果整理在表中.\n按颜色分:\n\n| 颜色 | 灰色 | 白色 |\n| ---- | ---- | ---- |\n| 个数 | | |\n\n按形状分:\n\n| 形状 | 圆柱 | 正方体 | 圆 | 三角形 |\n| ---- | ---- | ------ | -- | ------ |\n| 个数 | | | | |", + "options": [], + "answer": "5;14;5;3;5;6", + "solution": "【分析】根据颜色的划分,先数出灰色图形的数量和白色图形的数量,再进行填空即可解答。根据三角形有 3 条直直的边;正方形是方方正正的,有 4 条直直的边,每条边都相等,立方体由 6 个完全相同的正方形围成;圆没有直直的边;圆柱的上,下两个底面是完全相同的圆,侧面是一个曲面,展开后是一个长方形。数出各平面图形的数量并填空即可.\n【详解】根据图分析,可知灰色图形有5个,白色图形有14个。按颜色分,数量填写如下表:\n\n| 颜色 | 灰色 | 白色 |\n| ---- | ---- | ---- |\n| 个数 | 5 | 14 |\n\n根据图分析,可知圆柱有 5 个,正方体有 3 个,圆有 5 个,三角形有 6 个。按形状分,数量填写如下表:\n\n| 形状 | 圆柱 | 正方体 | 圆 | 三角形 |\n| ---- | ---- | ------ | -- | ------ |\n| 个数 | 5 | 3 | 5 | 6 |", + "knowledge_points": [ + "按不同标准分类(单次)", + "长方形,正方形,三角形和圆的初步认识", + "立体图形的认识及分类" + ], + "source": "24-25一年级下·广东汕尾·期中" + }, + { + "id": "22", + "unit": "第三单元分类与整理", + "question_type": "填空题", + "difficulty": 0.65, + "question": "分一分。(填序号)\n\n![](images/d857c26612f08ac2db33a61083dd349b8f88aa0d3000f13a4196491382b1b657.jpg)", + "options": [], + "answer": "水果:②③⑥⑧;玩具:①⑤⑨;文具:④⑦⑩", + "solution": "【分析】本题根据题目规定的分类标准,将物品分类即可。水果有:梨,葡萄,西瓜,香蕉;玩具有:玩具汽车,布娃娃,玩具小熊;文具有:铅笔,橡皮擦,文具盒。据此将相应物品的序号填进相应的框里即可.\n【详解】填空如下:\n![](images/4f24384d310f1dce6e88f5ca10050fe9162025c7e5d43a87c202b85e4948bfc9.jpg)", + "knowledge_points": [ + "按不同标准分类(单次)" + ], + "source": "24-25一年级上·河南新乡·期中" + }, + { + "id": "23", + "unit": "第三单元分类与整理", + "question_type": "填空题", + "difficulty": 0.65, + "question": "把这些物品分类,把序号填到相应的地方.\n\n![](images/cb270a19340285343ad3dee6acccba13.png)\n\n学习用品:( )。玩具:( )。服装鞋帽:( )。", + "options": [], + "answer": "④⑥⑨;①③⑦⑩;②⑤⑧", + "solution": "【分析】布娃娃,玩具车,足球都属于玩具,鞋子,衣服,帽子都属于服装鞋帽类,三角尺,铅笔,书包都属于学习用品,据此填空.\n【详解】![](images/cb270a19340285343ad3dee6acccba13.png)\n学习用品:④⑥⑨。 玩具:①③⑦⑩。服装鞋帽:②⑤⑧。", + "knowledge_points": [ + "按不同标准分类(单次)" + ], + "source": "24-25一年级上·河南商丘·期中" + }, + { + "id": "24", + "unit": "第三单元分类与整理", + "question_type": "填空题", + "difficulty": 0.85, + "question": "分一分,填一填。(填编号)\n\n![](images/47851310d4f2d94f3f6d9f465992eec9e48cbfce8ead4f6a1ada61bc20d69867.jpg)\n\n(1)按图形的形状分:①⑤⑨,( ),和( )。 (2)按图形中点子数的多少分:( ),( ),( )。", + "options": [], + "answer": "②③⑥;④⑦⑧ ①③④;②⑤⑦;⑥⑧⑨", + "solution": "【分析】(1)三角形有3条直直的边;圆没有直直的边;正方形是方方正正的,有4条直直的边,每条边都相等;由此按形状填写;(2) 按点子的个数,分别有 1 个,2 个,3 个,填写对应序号即可.\n【详解】(1) 按图形的形状分:①⑤⑨,②③⑥,和④⑦⑧.\n(2) 按图形中点子数的多少分: ①③④,②⑤⑦,⑥⑧⑨。", + "knowledge_points": [ + "按不同标准分类(单次)" + ], + "source": "23-24一年级下·湖北恩施·期末" + }, + { + "id": "25", + "unit": "第三单元分类与整理", + "question_type": "填空题", + "difficulty": 0.85, + "question": "按要求分一分。(填图形序号)\n\n![](images/aa46d4096d382e96e3229d47b6e5b57b.png)\n\n(1)按外部图形分,可以把( )分为一类,把( )分为一类,把( )分为一类。 (2)按内部图形分,可以把( )分为一类,把( )分为一类,把( )分为一类。", + "options": [], + "answer": "①④⑨;②⑤⑦;③⑥⑧ ①⑦⑧;②③⑨;④⑤⑥", + "solution": "【分析】(1)外部形状有正方形,三角形和圆形,由此分类;(2) 按内部形状有五角星,心形和正方形,由此分类.\n【详解】(1)按外部图形分,可以把①④⑨分为一类,把②⑤⑦分为一类,把③⑥⑧分为一类.\n(2) 按内部图形分,可以把①⑦⑧分为一类,把②③⑨分为一类,把④⑤⑥分为一类。", + "knowledge_points": [ + "按不同标准分类(单次)" + ], + "source": "23-24二年级下·河南周口·期末" + }, + { + "id": "26", + "unit": "第三单元分类与整理", + "question_type": "填空题", + "difficulty": 0.85, + "question": "把分组结果整理在表格中.\n\n![](images/8326de81ad6df8ab40db7cc53cc9dff039a7864b0db597b3e32fc0a7b4af414a.jpg)\n![](images/c20103e65f1737d35cdc1753a0ff1a96d518858dcd8fe4a32ab42b9008536679.jpg)\n\n| 类别 | 大人 | 孩子 |\n| ---- | ---- | ---- |\n| 人数(个) | () | () |\n\n| 性别 | 男 | 女 |\n| ---- | -- | -- |\n| 人数(个) | () | () |", + "options": [], + "answer": "6;7 7;6", + "solution": "【分析】先按照大人与小孩分别数一数各有几个人并填空;然后按照性别分别数一数各有几人并填空即可.\n【详解】由题意分析得:\n\n| 类别 | 大人 | 孩子 |\n| ---- | ---- | ---- |\n| 人数(个) | 6 | 7 |\n\n| 性别 | 男 | 女 |\n| ---- | -- | -- |\n| 人数(个) | 7 | 6 |", + "knowledge_points": [ + "按不同标准分类(单次)" + ], + "source": "22-23一年级下·河南驻马店·期末" + }, + { + "id": "27", + "unit": "第三单元分类与整理", + "question_type": "填空题", + "difficulty": 0.85, + "question": "分一分,做一做。下面是实验小学一(1)班五个小组20名同学喜欢吃的水果统计表.\n\n| | 第一小组 | 第二小组 | 第三小组 | 第四小组 | 第五小组 |\n| --- | -------- | -------- | -------- | -------- | -------- |\n| 1号 | 苹果 | 苹果 | 梨 | 苹果 | 梨 |\n| 2号 | 梨 | 梨 | 苹果 | 香蕉 | 苹果 |\n| 3号 | 香蕉 | 草莓 | 梨 | 草莓 | 香蕉 |\n| 4号 | 苹果 | 梨 | 香蕉 | 苹果 | 草莓 |\n\n(1) 分一分,填一填.\n\n| 水果 | 苹果 | 香蕉 | 梨 | 草莓 |\n| ---- | ---- | ---- | -- | ---- |\n| 人数 | ()人 | ()人 | ()人 | ()人 |\n\n(2) 喜欢吃()的人数最多,喜欢吃()的人数最少。 \n(3) 喜欢吃苹果和梨的共有()人,喜欢吃草莓的比喜欢吃苹果的少()人。", + "options": [], + "answer": "7;4;6;3;苹果;草莓;13;4", + "solution": "【分析】(1)按照从左往右的顺序,一行一行地数一数各水果各有多少人,然后统计填表。(2) 比较各水果数量的大小,做出判断。 (3) 求共有人数用加法计算,比多少用减法计算.\n【详解】(1) 分一分,填一填:\n\n| 水果 | 苹果 | 香蕉 | 梨 | 草莓 |\n| ---- | ---- | ---- | -- | ---- |\n| 人数 | 7人 | 4人 | 6人 | 3人 |\n\n(2) 7 > 6 > 4 > 3 喜欢吃苹果的人数最多,喜欢吃草莓的人数最少.\n(3) 7 + 6 = 13 (人);7 - 3 = 4 (人)。喜欢吃苹果和梨的共有13人,喜欢吃草莓的比喜欢吃苹果的少4人。", + "knowledge_points": [ + "10以内数的比大小", + "数据的搜集与整理", + "7,6加几的进位加法" + ], + "source": "23-24一年级下·河南安阳·期末" + }, + { + "id": "28", + "unit": "第三单元分类与整理", + "question_type": "填空题", + "difficulty": 0.65, + "question": "分一分.\n\n![](images/e13939f1dff57e21dd64fc8db61061fb.png)\n(1) 按动物的种类分.\n\n| 种类 | 青蛙 | 小鸟 | 小猪 |\n| ---- | ---- | ---- | ---- |\n| 个数 | | | |\n\n(2) 按卡片的形状分.\n\n| 形状 | 正方形 | 三角形 | 圆 |\n| ---- | ------ | ------ | -- |\n| 个数 | | | |", + "options": [], + "answer": "4;5;1 3;3;4", + "solution": "【分析】按动物分类时,直接数出青蛙,小鸟和小猪的个数即可;按形状分类时,直接数出正方形,三角形和圆的个数即可。三角形是由3条直直的线首尾依次连接而成的封闭图形;正方形是正正方方的,由4条边围成;圆形由一条曲线围成.\n【详解】(1) 按动物的种类分:\n\n| 种类 | 青蛙 | 小鸟 | 小猪 |\n| ---- | ---- | ---- | ---- |\n| 个数 | 4 | 5 | 1 |\n\n(2) 按卡片的形状分:\n\n| 形状 | 正方形 | 三角形 | 圆 |\n| ---- | ------ | ------ | -- |\n| 个数 | 3 | 3 | 4 |", + "knowledge_points": [ + "按不同标准分类(单次)", + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "22-23一年级下·甘肃天水·期中" + }, + { + "id": "29", + "unit": "第三单元分类与整理", + "question_type": "填空题", + "difficulty": 0.85, + "question": "我会分类.\n\n![](images/361d8ce7939b0d3f36167a23ddaffee1.png)\n服装鞋帽( ),蔬菜( ),水果( ),零食( )。", + "options": [], + "answer": "①③⑤;⑦⑨;②④⑥;⑧⑩", + "solution": "【分析】根据题意可知:裙子,帽子,鞋属于服装鞋帽;豌豆,茄子属于蔬菜;香蕉,葡萄,草莓属于水果;冰激凌属于零食,由此解答.\n【详解】![](images/361d8ce7939b0d3f36167a23ddaffee1.png)\n服装鞋帽①③⑤,蔬菜⑦⑨,水果②④⑥,零食⑧⑩。", + "knowledge_points": [ + "按不同标准分类(单次)" + ], + "source": "22-23一年级下·江西宜春·期中" + }, + { + "id": "30", + "unit": "第三单元分类与整理", + "question_type": "填空题", + "difficulty": 0.65, + "question": "我会整理.\n\n![](images/beac36c21e92ead50761685e4d7fc4887a5d5b424cd093a761552140579b253c.jpg)\n(1) 数一数,完成下面的表格.\n\n| 图形 | △ | ○ | □ | ▭ |\n| ---- | ---- | ---- | ---- | ---- |\n| 个数 | | | | |\n\n(2) ( )最多,( )和( )一样多.\n(3) □ 再增加()个就 ▭和同样多了.\n(4) 小军摆了 3 个![](images/6a3b3becc1a9838f59e6fd44bb2ea9c907b359dc2ed1d025ca7ca11941808a98.jpg),一共用了()个○", + "options": [], + "answer": "3;5;3;4 圆;三角形;正方形 1 15", + "solution": "【分析】(1)三角形有3条直直的边;圆没有直直的边;正方形是方方正正的,有4条直直的边,每条边都相等;长方形是长长方方的,有4条直直的边,对边相等。由此数出各图形的数量填空即可;(2) 把各个图形的数量比较大小,找出最多的和一样多的;(3) 正方形要和长方形同样多,需要再加上正方形的个数 = 长方形的个数 - 正方形的个数;(4) 小军摆了 3 个这样的图形,一共用圆形的个数 = 每个图形用圆形的个数 + 每个图形用圆形的个数 + 每个图形用圆形的个数.\n【详解】(1) 表格填写如下:\n\n| 图形 | 三角形 | 圆 | 正方形 | 长方形 |\n| ---- | ------ | -- | ------ | ------ |\n| 个数 | 3 | 5 | 3 | 4 |\n\n(2) 5 > 4 > 3 = 3 圆最多,三角形和正方形一样多.\n(3) 4 - 3 = 1(个),正方形再增加1个就和长方形同样多了.\n(4) 5 + 5 + 5 = 15 (个),小军摆了3个![](images/6a3b3becc1a9838f59e6fd44bb2ea9c907b359dc2ed1d025ca7ca11941808a98.jpg),一共用了15个圆。", + "knowledge_points": [ + "按不同标准分类(单次)", + "长方形,正方形,三角形和圆的初步认识", + "连加(20以内)" + ], + "source": "23-24一年级下·浙江嘉兴·期末" + }, + { + "id": "31", + "unit": "第三单元分类与整理", + "question_type": "填空题", + "difficulty": 0.65, + "question": "![](images/c5eb65cc04cacc0e890ab22ebb4654021ae1fc2b57f82cb8175b4846a7befa4f.jpg)\n(1) 按卡片的形状分.\n形状:\n数量:\n(2) 按动物的种类分.\n\n| 动物 | 熊猫 | 燕子 | 马 |\n| ---- | ---- | ---- | -- |\n| 数量 | | | |", + "options": [], + "answer": "3;3;6 4;3;5", + "solution": "【分析】(1) 圆的特点:没有角,没有边,是一条封闭曲线;三角形特点:有3条边,3个尖尖的角;平行四边形:4个角,4条边,对边平行且相等。根据特点进行分类即可。(2) 数各动物的数量即可.\n【详解】(1) 按卡片的形状分:\n\n形状:圆;三角形;平行四边形\n数量:3;3;6\n\n(2) 按动物的种类分:\n\n| 动物 | 熊猫 | 燕子 | 马 |\n| ---- | ---- | ---- | -- |\n| 数量 | 4 | 3 | 5 |", + "knowledge_points": [ + "按不同标准分类(单次)", + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "23-24一年级下·山西晋城·期末" + }, + { + "id": "32", + "unit": "第三单元分类与整理", + "question_type": "填空题", + "difficulty": 0.85, + "question": "(1) 根据下面拼图,数一数,填一填.\n![](images/efb8ae967359ed8c34d64d7793ee7525da7c18c31a0f5a61e8f9cdfedf0a2f06.jpg)\n\n| 图形 | 长方形 | 圆 | 三角形 | 正方形 | 平行四边形 |\n| ---- | ------ | -- | ------ | ------ | ---------- |\n| 个数 | | | | | |\n\n(2) ( )最少,( )和( )同样多。 (3) 一共有()个图形,三角形和正方形相差()个。(4)小松摆了四个![](images/b7fc9e094a7f0771954d60936702b2be6c55390076e44f55ecb2e37e471db8fa.jpg) 用了()个平行四边形。", + "options": [], + "answer": "8;5;8;1;6 正方形;长方形;三角形 28;7 16", + "solution": "【分析】(1) 根据长方形,正方形,三角形,圆形及平行四边形的特征分别数一数各有几个即可解决。长方形是长长方方的,由4条边围成,且对边一样长;正方形是正正方方的,由4条边围成,且4条边都一样长;三角形由3条线段首尾依次连接而成的封闭图形;圆形由一条曲线围成;平行四边形由4条边围成,且对边一样长。(2) 比较一下各种图形数量的多少,即可知道哪种图形最少,哪两种图形同样多。 (3) 把所有的图形数量加起来,求出和,就是一共有几个图形;求三角形和正方形相差几个,就是求两个数的差,用减法列式计算。(4) 摆了1个![](images/b7fc9e094a7f0771954d60936702b2be6c55390076e44f55ecb2e37e471db8fa.jpg)用了4个平行四边形,求摆四个这样的图形需要几个平行四边形,就是求4个4的和是多少,可以用连加列式计算.\n【详解】(1) 表格填写如下:\n\n| 图形 | 长方形 | 圆 | 三角形 | 正方形 | 平行四边形 |\n| ---- | ------ | -- | ------ | ------ | ---------- |\n| 个数 | 8 | 5 | 8 | 1 | 6 |\n\n(2) 8 = 8 > 6 > 5 > 1,即正方形最少,长方形和三角形同样多.\n(3) 8 + 5 + 8 + 1 + 6 = 28 (个);8 - 1 = 7 (个),一共有28个图形,三角形和正方形相差7个.\n(4) 4 + 4 + 4 + 4 = 16 (个),小松摆了四个![](images/25133af2d33998cbd8c3d29b6dfb666097771108c6f3bc61c0b8d859d55b578a.jpg)用了16个平行四边形。", + "knowledge_points": [ + "数据的搜集与整理", + "按不同标准分类(单次)", + "数一数", + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "23-24一年级下·浙江台州·期末" + }, + { + "id": "33", + "unit": "第三单元分类与整理", + "question_type": "填空题", + "difficulty": 0.65, + "question": "如图:根据图形填空.\n\n![](images/1bccd3ecfbaf42a8fb447566d84014903c3f326bd791d681a12b9f6577834aed.jpg)\n\n| 图形 | 正方形 | 长方形 | 圆 | 三角形 |\n| ---- | ------ | ------ | -- | ------ |\n| 个数 | | | | |\n\n(1) 数一数,填好图形个数。 (2) ( ) 图形最多;( ) 图形最少。", + "options": [], + "answer": "3;4;2;1 长方形;三角形", + "solution": "【分析】(1) 数一数,依次是3个,4个,2个,1个,据此填空。 (2) 将各种图形的数量作比较即可.\n【详解】![](images/ce66fb85e1146863b2006fc21ec60ccc2922b34cd6dfeb7c18133b515e345cb0.jpg)\n\n| 图形 | 正方形 | 长方形 | 圆形 | 三角形 |\n| ---- | ------ | ------ | ---- | ------ |\n| 个数 | 3 | 4 | 2 | 1 |\n\n(1) 数一数,填好图形个数。 (2) 4 > 3 > 2 > 1,长方形图形最多;三角形图形最少。", + "knowledge_points": [ + "5 以内数的比大小", + "数据的搜集与整理", + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "23-24一年级下·湖南怀化·期末" + }, + { + "id": "34", + "unit": "第三单元分类与整理", + "question_type": "填空题", + "difficulty": 0.65, + "question": "今年 5 月份西安市的天气情况如下(每个○代表1天)。![](images/a7690c94e4966f48f06a00a1bdc5262bb4866fe257210ae4f163bf64dceb7dcf.jpg)\n(1) 根据上图填写下表.\n\n| 天气 | 晴 | 多云 | 阴 | 雨 |\n| ---- | ---- | ---- | ---- | ---- |\n| 天数 | | | | |\n\n(2) 这个月()天最多,这个月()天最少。", + "options": [], + "answer": "9;7;5;10 雨;阴", + "solution": "【分析】(1)数一数,依次是9天,7天,5天,10天,据此填空;(2) 将各天气的天数作比较即可。10 以内数大小关系为: 0 < 1 < 2 < 3 < 4 < 5 < 6 < 7 < 8 < 9 < 10.\n【详解】(1) 填表如下:\n\n| 天气 | 晴 | 多云 | 阴 | 雨 |\n| ---- | ---- | ---- | ---- | ---- |\n| 天数 | 9 | 7 | 5 | 10 |\n\n(2) 5 < 7 < 9 < 10 这个月雨天最多,这个月阴天最少。", + "knowledge_points": [ + "数据的搜集与整理" + ], + "source": "23-24 一年级下·陕西安康·期末" + }, + { + "id": "35", + "unit": "第三单元分类与整理", + "question_type": "填空题", + "difficulty": 0.85, + "question": "按规律接着在括号上画一画,再数一数。![](images/82b01516fa1285feb92c25e04df2d594ef6558381d673c2d3c1e06f176d7af87.jpg) 上图中 ● 有( )个, ○ 有( )个。", + "options": [], + "answer": "○;○;5;15", + "solution": "【分析】根据题意可知:第一组是5个○,1个●;第二组是4个○,1个●;第三组是3个○,1个●;第四组是2个○,1个●,最后一组是1个○,1个●;然后再分别数出○和●的个数。据此解答.\n【详解】根据分析可知:![](images/e16fff50777cbf6d43ece4c8af9ca6297ad8420e057d00fdf5422d9a3fb7ebeb.jpg)\n图中●有(5)个,○有(15)个.\n[点睛]找到数字规律,熟悉20以内数的组成是解题关键。", + "knowledge_points": [ + "图形的变化规律" + ], + "source": "23-24 一年级下·湖北省直辖县级单位·期末" + }, + { + "id": "36", + "unit": "第三单元分类与整理", + "question_type": "填空题", + "difficulty": 0.65, + "question": "分一分,填一填。![](images/88485d5f80427c611b7d75691687fdb067ea0aec1cea94d2f96d87143558e110.jpg)\n\n| | 梨 | 桃 | 苹果 | | | 三角形 | 正方形 |\n| ---- | -- | -- | ---- | ---- | ---- | ------ | ------ |\n| 个数(个) | () | () | () | | 个数(个) | () | () |", + "options": [], + "answer": "3;2;3 3;5", + "solution": "【分析】按水果种类数一数,梨3个,桃2个,苹果3个;按形状数一数,三角形3个,正方形5个,据此填空.\n【详解】\n\n| | 梨 | 桃 | 苹果 |\n| ---- | -- | -- | ---- |\n| 个数(个) | 3 | 2 | 3 |\n\n| | 三角形 | 正方形 |\n| ---- | ------ | ------ |\n| 个数(个) | 3 | 5 |", + "knowledge_points": [ + "数据的搜集与整理", + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "23-24一年级下·河南周口·期末" + }, + { + "id": "37", + "unit": "第三单元分类与整理", + "question_type": "填空题", + "difficulty": 0.65, + "question": "分类整理卡片。![](images/1632dde3bfffc22baf878c4e13b1a10d.png)\n(1) 按外框形状分类.\n\n| 形状 | 三角形 | 圆 | 正方形 |\n| ---- | ------ | -- | ------ |\n| 个数 | ()个 | ()个 | ()个 |\n\n(2) 按圆点的个数分类(请填序号).\n\n| 圆点个数 | 1个 | 2个 | 3个 |\n| -------- | --- | --- | --- |\n| 序号 | | | |", + "options": [], + "answer": "2;4;4 ①⑤⑥⑦;②③⑨;④⑧⑩", + "solution": "【分析】(1)按形状分有三角形,圆形,正方形,三角形特点:由三条边组成的封闭图形;圆形特点:圆圆的,由一条曲线组成的封闭图形;正方形特点:由四条相同的边组成的封闭图形,分别数出各图形有几个,填在对应表格里。据此解答。(2) 按圆点的个数有一个点,两个点,三个点,将相应序号填在对应表格里,据此解答.\n【详解】(1) 填表如下:\n\n| 形状 | 三角形 | 圆 | 正方形 |\n| ---- | ------ | -- | ------ |\n| 个数 | 2个 | 4个 | 4个 |\n\n(2)\n\n| 圆点个数 | 1个 | 2个 | 3个 |\n| -------- | --------- | ------- | ------- |\n| 序号 | ①⑤⑥⑦ | ②③⑨ | ④⑧⑩ |", + "knowledge_points": [ + "按不同标准分类(单次)", + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "22-23一年级下·重庆潼南·期末" + }, + { + "id": "38", + "unit": "第三单元分类与整理", + "question_type": "填空题", + "difficulty": 0.65, + "question": "分一分,填一填。(填序号)\n\n![](images/46bd9335a39f88a78026c21787c4e05d.png)", + "options": [], + "answer": "学习用品:①③⑦ 家用电器:④⑥⑨ 体育用品:②⑤⑧", + "solution": "【分析】根据题意,图中物品可以分成三类:学习用品,家用电器,体育用品,可依据此标准并结合生活常识进行分类。据此解答.\n【详解】由分析可知, ①,③,⑦为学习用品, ④,⑥,⑨为家用电器, ②,⑤,⑧为体育用品:![](images/9eeaf6b503b129443a27130b5055e05fcf50040ed35a9124e23bfd834e8e16ef.jpg)\n学习用品![](images/df540a8c178e7420cbb6e7cb0bae745d5c029c7d58fa9c982972aef0b83835a1.jpg)\n家用电器![](images/a2ca2d8a62cfea8cb1ccd232d26545e1def02d5f3b469fd32b4bc756b98e8d39.jpg)\n体育用品", + "knowledge_points": [ + "按不同标准分类(单次)" + ], + "source": "22-23一年级下·河南周口·期末" + }, + { + "id": "39", + "unit": "第三单元分类与整理", + "question_type": "填空题", + "difficulty": 0.65, + "question": "(1) 按形状分.\n\n| 形状 | 三角形 | 正方形 | 圆 |\n| ---- | ------ | ------ | -- |\n| 个数 | | | |\n\n(2) 按点数分.\n\n| 点数 | 1 | 2 | 3 |\n| ---- | - | - | - |\n| 个数 | | | |", + "options": [], + "answer": "4;4;5 4;4;5", + "solution": "【分析】(1)数一数,三角形有4个,正方形有4个,圆有5个;(2) 数一数, 1 个点的有 4 个,2 个点的有 4 个,3 个点的有 5 个.\n【详解】(1)\n\n| 形状 | 三角形 | 正方形 | 圆 |\n| ---- | ------ | ------ | -- |\n| 个数 | 4 | 4 | 5 |\n\n(2)\n\n| 点数 | 1 | 2 | 3 |\n| ---- | - | - | - |\n| 个数 | 4 | 4 | 5 |", + "knowledge_points": [ + "按不同标准分类(单次)", + "数一数", + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "23-24一年级下·河南驻马店·期中" + }, + { + "id": "40", + "unit": "第三单元分类与整理", + "question_type": "填空题", + "difficulty": 0.85, + "question": "将对应的序号填在下面的圈里。![](images/02017b42eed41c814b94ba5a2d24b042.png)", + "options": [], + "answer": "文具:②⑤⑥;玩具:①③④⑦", + "solution": "【分析】题中钢笔,文具盒,计算器是文具;小汽车,飞机,毽子和小熊是玩具,由此填写即可.\n【详解】由分析填写如下:![](images/a041f4d283edc2c971c9502d3a6acafe.png)", + "knowledge_points": [ + "按不同标准分类(单次)" + ], + "source": "23-24一年级下·新疆和田·期中" + }, + { + "id": "41", + "unit": "第三单元分类与整理", + "question_type": "填空题", + "difficulty": 0.65, + "question": "下面的图形按点的个数,可以分成( )组;也可以按( )分,分成( )组。![](images/c7868ed6b62df75d22543748fa8fc449.png)", + "options": [], + "answer": "2;形状;3", + "solution": "【分析】按点的个数分有一个点和四个点,分成 2 组;按形状分有三角形,圆形和正方形,分成 3 组。据此得出结论即可.\n【详解】根据分析知:题中图形按点的个数,可以分成 2 组;也可以按形状分,分成 3 组。", + "knowledge_points": [ + "按不同标准分类(单次)" + ], + "source": "23-24一年级下·湖北省直辖县级单位·期中" + }, + { + "id": "42", + "unit": "第三单元分类与整理", + "question_type": "填空题", + "difficulty": 0.85, + "question": "分一分,填序号。![](images/faae1c3ae2c44bdc546dea12522844bc.png)\n按形状分:![](images/818ced2e77cc9bcec0f3a5d57bb163dd.png)\n按点数分:![](images/818ced2e77cc9bcec0f3a5d57bb163dd.png)", + "options": [], + "answer": "按形状分:三角形①④⑩;正方形②⑤⑧;圆③⑥⑦⑨\n按点数分:1个点①②③;2个点④⑤⑧;4个点⑥⑦⑨⑩", + "solution": "【分析】三角形有3条直直的边;正方形是方方正正的,有4条直直的边,每条边是相等;圆形没有直直的边,由此按形状分类;点数有 1 个,2 个和 4 个,由此按点数分类.\n【详解】由分析填写如下:![](images/faae1c3ae2c44bdc546dea12522844bc.png)\n按形状分:![](images/706d249e63beb3e98e158b6ff89147ef.png)\n按点数分:![](images/0d28e70828a7803dc654e8db112a19898214a0b1b6cad2799069fd815a989164.jpg)", + "knowledge_points": [ + "按不同标准分类(单次)", + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "23-24一年级下·湖南常德·期中" + }, + { + "id": "43", + "unit": "第三单元分类与整理", + "question_type": "填空题", + "difficulty": 0.85, + "question": "正方形有( )个,长方形有( )个,三角形有( )个,圆有( )个.\n\n![](images/0f74944d6924c4769d2647c3b8be731a7ada4a43e3c67959b15a3328dc4b325a.jpg)", + "options": [], + "answer": "4;5;2;5", + "solution": "【分析】长方形是四个内角相等的四边形;四条边都相等,四个角都相等的四边形是正方形;圆指的是平面中到一个定点距离为定值的所有点的集合;三角形是由同一平面内不在同一直线上的三条线段\"首尾\"顺次连接所组成的封闭图形。据此数一数.\n【详解】正方形有4个,长方形有5个,三角形有2个,圆有5个。![](images/1e370f808828e05b08ee9417d5df286e1178ff180aba7574025962d2661c5974.jpg)", + "knowledge_points": [ + "数据的搜集与整理", + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "23-24一年级下·河南周口·期中" + }, + { + "id": "44", + "unit": "第三单元分类与整理", + "question_type": "填空题", + "difficulty": 0.85, + "question": "分一分,填一填。![](images/d4754e0ad33b08f002339b5276e6505d5e857b65102b9d88dfaa58b3871998cd.jpg)\n(1) 按外框形状分:\n\n| 形状 | 正方形 | 三角形 | 圆 |\n| ---- | ------ | ------ | -- |\n| 个数 | | | |\n\n(2) 按内部有无图形分:\n\n| 类别 | 有图形 | 无图形 |\n| ---- | ------ | ------ |\n| 个数 | | |", + "options": [], + "answer": "按外框形状分:正方形3;三角形3;圆3\n按内部有无图形分:有图形6;无图形3", + "solution": "【分析】(1)正方形是方方正正的,有4条直直的边,每条边都相等;三角形有3条直直的边;圆没有直直的边;由此数出数量即可;(2) 依次数出有图形和无图形的数量填空即可.\n【详解】(1) 按外框形状分:\n\n| 形状 | 正方形 | 三角形 | 圆 |\n| ---- | ------ | ------ | -- |\n| 个数 | 3 | 3 | 3 |\n\n(2) 按内部有无图形分:\n\n| 类别 | 有图形 | 无图形 |\n| ---- | ------ | ------ |\n| 个数 | 6 | 3 |", + "knowledge_points": [ + "按不同标准分类(单次)", + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "23-24一年级下·浙江温州·期中" + }, + { + "id": "45", + "unit": "第三单元分类与整理", + "question_type": "填空题", + "difficulty": 0.85, + "question": "我会分,我会填。![](images/52db623e71bb1fddd591f91b4b6ef99a8358cf0b862c17e64311a4381fa0c88a.jpg)\n根据上图填一填。![](images/08cd0d43a348fbee5c0d7ed2445955e3.png)\n( )最多,( )和( )一样多。", + "options": [], + "answer": "长方体;球;正方体", + "solution": "【分析】长方体是长长方方的有平平的面;正方体是正正方方的有平平的面;圆柱上下是圆且上下一样粗;球没有平面可以任意方向滚动;根据立体图形的特征,先数一数,再填空。然后比较各种图形数量的大小,即可解决.\n【详解】由题意分析得:\n\n| | 长方体 | 球 | 圆柱 | 正方体 |\n| ---- | ------ | -- | ---- | ------ |\n| 个数 | 6 | 3 | 4 | 3 |\n\n6 > 4 > 3 = 3 即,长方体最多,球和正方体一样多。", + "knowledge_points": [ + "立体图形的认识", + "数据的搜集与整理", + "按不同标准分类(单次)", + "7以内数的比大小" + ], + "source": "23-24一年级下·广东河源·期中" + }, + { + "id": "46", + "unit": "第三单元分类与整理", + "question_type": "填空题", + "difficulty": 0.85, + "question": "下方是我区某个月前20天的天气情况。![](images/9fa2af40be7782db3725453501eb24aa3f73d510172538b36f16b28fc3de9f89.jpg)\n(1) 数一数,填统计表。![](images/638c7eebe5d4ea17c590593aad4342ca.png)\n(2) 从上表看出,()最多,()最少。", + "options": [], + "answer": "7;5;5;3 晴天;雨天", + "solution": "【分析】(1)根据给出的天气情况,分别数一数各种天气各有几天,然后完成填空即可。(2) 比较一下各种天气天数的多少,即可解决.\n【详解】(1) 统计表填写如下:\n\n| 天气 | 晴天 | 阴天 | 多云 | 雨天 |\n| ---- | ---- | ---- | ---- | ---- |\n| 天数 | 7 | 5 | 5 | 3 |\n\n(2) 7 > 5 = 5 > 3,从上表看出晴天最多,雨天最少。", + "knowledge_points": [ + "数据的搜集与整理", + "单式统计表的特点及填补", + "7以内数的比大小", + "数一数" + ], + "source": "23-24一年级下·广东江门·期中" + }, + { + "id": "47", + "unit": "第三单元分类与整理", + "question_type": "填空题", + "difficulty": 0.65, + "question": "数一数,填一填。![](images/ed75f711c13598fa0cc4111b1045f108.png)\n(1)按物品的种类分一分.\n![](images/fa90a876cfc99a767570993df2daaaf4.png)( )个, ![](images/45e77ba55fdb0e9dde26fd1f8454302bda8a46afd4a1c802ad78823cf587bfc2.jpg)( )个,![](images/19e8c9344bdec58f707594cd93126e4ff524599b4f868d269f14dbe390f0c1e3.jpg)( )个.\n(2)按卡片的形状分一分.\n△ ( )个, ○ ( )个, □ ( )个。", + "options": [], + "answer": "3;2;3 3;3;2", + "solution": "【分析】物体的分类与整理,按种类分指的是物体是一样的合在一起,按卡片形状分就是卡片形状是一样的合在一起,据此解答.\n【详解】(1) 填空如下:![](images/e4ce1aa613c121913394d8c8b62fc9000a235c687093e59077f654111dbeb34d.jpg)\n第一个种类3个,第二个种类2个,第三个种类3个.\n(2) 填空如下:△ (3)个, ○ (3)个, □ (2)个。", + "knowledge_points": [ + "按不同标准分类(单次)" + ], + "source": "23-24一年级下·广东江门·期中" + }, + { + "id": "48", + "unit": "第三单元分类与整理", + "question_type": "填空题", + "difficulty": 0.85, + "question": "![](images/eac10af001755790017de491ed583e48.png)\n(1) 按水果种类分.\n![](images/c09ea8c5bfda3610fd6717e19ee1a3de.png)\n(2) 按卡片形状分一分.\n\n| 图形 | 三角形 | 圆形 | 正方形 |\n| ---- | ------ | ---- | ------ |\n| 个数 | | | |", + "options": [], + "answer": "5;4;3 4;4;4", + "solution": "【分析】(1)按照水果种类,依次数出梨,苹果和桃子的个数填空即可;(2) 正方形是由四条边首尾依次连接组成的封闭图形,四条边都相等;三角形是由三条边首尾依次连接组成的封闭图形;圆形是由曲线围成的封闭图形。由此数出卡片的数量填空即可.\n【详解】(1) 梨有5个;苹果有4个;桃子有3个。填写如下:![](images/5ad9c8ac592ae467ab2db636ffc610a5.png)\n(2) 三角形卡片有4个;圆形卡片有4个;正方形卡片有4个。填写如下:\n\n| 图形 | 三角形 | 圆形 | 正方形 |\n| ---- | ------ | ---- | ------ |\n| 个数 | 4 | 4 | 4 |", + "knowledge_points": [ + "按不同标准分类(单次)", + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "22-23一年级下·广东江门·期中" + }, + { + "id": "49", + "unit": "第三单元分类与整理", + "question_type": "填空题", + "difficulty": 0.65, + "question": "下面是某城市今年三月份的天气情况。![](images/2301baab08666d8e8c354e9657ad76f7e7988b74d07d8ceaff900016c57e3880.jpg)\n(1) 根据上图填写各种天气的天数。![](images/f458c077360311b07c1d04f8e242256f.png)\n(2) ()天数最多。 \n(3) ()和()的天数同样多。 \n(4)![](images/810596c3b6df44c650ddf9313d31d32d.png)\n(5) ![](images/52c55a835a73511c093f78ee6687ec39.png)\n(6) 阴天和雨天一共有()天。", + "options": [], + "answer": "10;13;4;4 阴天;雨天;雪天 3;9;17", + "solution": "【分析】(1)数一数,晴天10天,阴天13天,雨天4天,雪天4天。(2)(3) 比较一下即可求解。 (4) 用阴天的13天减去晴天10天即可。 (5) 用阴天的13天减去雪天的4天即可。 (6) 用阴天天数加雨天天数即可.\n【详解】(1) 统计表如下:![](images/3c590f22a4bd2ae29c12c994eb7c9a0c.png)\n(2) 13 > 10 > 4 = 4 阴天天数最多.\n(3) 雨天和雪天的天数同样多。 \n(4) 13 - 10 = 3 (天).\n(5) 13 - 4 = 9 (天).\n(6) 13 + 4 = 17 (天),阴天和雨天一共有17天。", + "knowledge_points": [ + "十几减5~2的退位减法", + "数据的搜集与整理", + "20以内数的比大小", + "不退位减法(20以内)" + ], + "source": "22-23一年级下·山东济宁·期中" + }, + { + "id": "50", + "unit": "第三单元分类与整理", + "question_type": "填空题", + "difficulty": 0.65, + "question": "认真数一数,填一填。![](images/b8eefee7860ced4b595c9a66eec6ad796ea557ffe49a29af06b31b0bfca74523.jpg)![](images/c0b3f458fe7b86951cc7b1a66d766d11.png)\n( )的个数最多,( )的个数最少。", + "options": [], + "answer": "5;3;9;4;6 圆;正方形", + "solution": "【分析】长方形是四个内角相等的四边形;四条边都相等,四个角都相等的四边形是正方形;圆指的是平面中到一个定点距离为定值的所有点的集合;三角形是由同一平面内不在同一直线上的三条线段\"首尾\"顺次连接所组成的封闭图形。分别数一数,然后比较。10 以内数大小关系为: 0 < 1 < 2 < 3 < 4 < 5 < 6 < 7 < 8 < 9 < 10.\n【详解】![](images/27d9cb8c265d2f9ad0d3674cb93d6cddc082017f259437845fcead67dd91781e.jpg)![](images/e239e0f05b467c0c9c32f413157c793a.png)\n9 > 6 > 5 > 4 > 3,圆的个数最多,正方形的个数最少。", + "knowledge_points": [ + "10以内数的比大小", + "数据的搜集与整理", + "数一数", + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "22-23一年级下·山东济宁·期中" + }, + { + "id": "51", + "unit": "第三单元分类与整理", + "question_type": "填空题", + "difficulty": 0.85, + "question": "数一数,填一填。![](images/a60853a47d127579977bca12e7068bbb6cd96d9dc759b32885378b4312450a8e.jpg)\n按形状分:\n\n| 形状 | 带把手 | 不带把手 |\n| ---- | ------ | -------- |\n| 个数 | ( )个 | ( )个 |", + "options": [], + "answer": "2;7", + "solution": "【分析】根据题意,数出带把手和不带把手杯子的数量填空即可.\n【详解】带把手的有 2 个,不带把手的有 7 个。填写如下:\n\n| 形状 | 带把手 | 不带把手 |\n| ---- | ------ | -------- |\n| 个数 | 2个 | 7个 |", + "knowledge_points": [ + "按不同标准分类(单次)" + ], + "source": "22-23一年级下·广西河池·期中" + }, + { + "id": "52", + "unit": "第三单元分类与整理", + "question_type": "填空题", + "difficulty": 0.65, + "question": "下面是一(3)班同学最喜欢的交通工具的调查情况图。![](images/8178925a861662d0c7af18cfb26119dd8bb7d8be253d8174764e2ba301900c85.jpg)\n(1) 请根据上图填写下表.\n\n| | 公交车 | 自行车 | 汽车 | 火车 | 飞机 |\n| ---- | ------ | ------ | ---- | ---- | ---- |\n| 人数 | | | | | |\n\n(2) 喜欢坐 ( ) 的人数最少,喜欢坐 ( ) 的人数最多。 \n(3) 喜欢坐 ( ) 和喜欢坐 ( ) 的人数同样多。 \n(4) 喜欢坐自行车的人数比喜欢坐汽车的人数少 ( ) 人。", + "options": [], + "answer": "5;3;7;5;8 自行车;飞机 公交车;火车 4", + "solution": "【分析】(1)数一数,从左到右分别是5人,3人,7人,5人,8人。 (2) 比较一下各人数即可求解。 (3) 喜欢坐公交车和喜欢坐火车的人数都是 5 人,据此解答。 (4) 用喜欢坐汽车的人数减喜欢坐自行车的人数即可.\n【详解】(1)\n\n| | 公交车 | 自行车 | 汽车 | 火车 | 飞机 |\n| ---- | ------ | ------ | ---- | ---- | ---- |\n| 人数 | 5 | 3 | 7 | 5 | 8 |\n\n(2) 8 > 7 > 5 = 5 > 3 喜欢坐自行车的人数最少,喜欢坐飞机的人数最多.\n(3) 喜欢坐公交车和喜欢坐火车的人数同样多.\n(4) 7 - 3 = 4 (人) 喜欢坐自行车的人数比喜欢坐汽车的人数少4人。", + "knowledge_points": [ + "数据的搜集与整理" + ], + "source": "22-23一年级下·广东江门·期中" + }, + { + "id": "53", + "unit": "第三单元分类与整理", + "question_type": "填空题", + "difficulty": 0.65, + "question": "![](images/62b936825790c6619d842a5c49784db4.png)\n学习用品:①( ) 体育用品:( ) 食物:( )", + "options": [], + "answer": "学习用品:①③⑤ 体育用品:⑦ 食物:②④⑥", + "solution": "【分析】橡皮,书包,铅笔是学习用品,梨,蛋糕,西红柿是食物,足球是体育用品,据此得出结论即可.\n【详解】根据分析知:学习用品:①③⑤ 体育用品:⑦ 食物:②④⑥", + "knowledge_points": [ + "按不同标准分类(单次)" + ], + "source": "23-24一年级下·广东江门·期中" + }, + { + "id": "54", + "unit": "第三单元分类与整理", + "question_type": "填空题", + "difficulty": 0.85, + "question": "把杯子分类。![](images/a37d0b09dfafc4f484359d9eb529802f.png)\n\n| 按形状分 | 带把手 | 不带把手 |\n| -------- | ------ | -------- |\n| 个数 | | |\n\n| 按颜色分 | 蓝色的 | 紫色的 | 绿色的 |\n| -------- | ------ | ------ | ------ |\n| 个数 | | | |", + "options": [], + "answer": "6;4;3;3;4", + "solution": "【分析】数一数,带把手的 6 个,不带把手的 4 个;蓝色的 3 个,紫色的 3 个,绿色的 4 个.\n【详解】\n\n| 按形状分 | 带把手 | 不带把手 |\n| -------- | ------ | -------- |\n| 个数 | 6 | 4 |\n\n| 按颜色分 | 蓝色的 | 紫色的 | 绿色的 |\n| -------- | ------ | ------ | ------ |\n| 个数 | 3 | 3 | 4 |", + "knowledge_points": [ + "按不同标准分类(单次)" + ], + "source": "23-24一年级下·全国·课后作业" + }, + { + "id": "55", + "unit": "第三单元分类与整理", + "question_type": "选择题", + "difficulty": 0.85, + "question": "图1和图2是给若干图形分类的结果。![](images/b5b434f34ed6e5ee1cc6feee2def6cba.png)\n图1是按( )分类的,图2是按( )分类的.\n① 颜色 ② 形状", + "options": [ + "A. ① ②", + "B. ② ①" + ], + "answer": "A", + "solution": "【分析】根据分类的结果可知图 1 中分成了两组,一组紫色,一组黄色,也就是按颜色分类,图 2 中分成了四组,一组圆形,一组三角形,一组正方形,一组平行四边形,也就是按形状分类.\n【详解】由分析可知:图 1 是按①分类的,图 2 是按②分类的。故答案为:A", + "knowledge_points": [ + "按不同标准分类(单次)" + ], + "source": "23-24一年级下·全国·课后作业" + }, + { + "id": "56", + "unit": "第三单元分类与整理", + "question_type": "填空题", + "difficulty": 0.85, + "question": "按要求分类。(只写序号) ![](images/aab36e2e503723856a1b13534a0d6ebb.png)\n车:( ) 水果:( ) 动物:( )", + "options": [], + "answer": "车:③⑦⑨⑩;水果:①⑤⑥⑩;动物:②④⑧⑪", + "solution": "【分析】车有:![](images/9a11dd921d76f91fa0ba664b4d3620e8.png) 水果有:![](images/46b4f75b3fafb063b75451604cd87bb1.png) 动物有:![](images/e112b8d6222f1a0a406a36f151d3f8b7.png);据此解决.\n【详解】由题意分析得:车:③⑦⑨⑩;水果:①⑤⑥⑩;动物:②④⑧⑪", + "knowledge_points": [ + "按不同标准分类(单次)" + ], + "source": "23-24一年级上·河北保定·期末" + }, + { + "id": "57", + "unit": "第三单元分类与整理", + "question_type": "填空题", + "difficulty": 0.85, + "question": "比一比,分一分。![](images/ef8edb4d769e494ccbf871588f4252ed.png)\n(1)按形状分:( ),( ),( )。 \n(2)按动物分:( ),( ),( )。", + "options": [], + "answer": "①④⑧⑩;②⑥⑨;③⑤⑦ ①⑤⑨;②⑧⑩;③④⑥⑦", + "solution": "【分析】(1)根据题意,按形状分 ①④⑧⑩ 形状相同;②⑥⑨都是三角形;③⑤⑦形状相同;(2) 按动物分①⑤⑨都是大象;②⑧⑩都是猴子;③④⑥⑦都是熊猫.\n【详解】(1)由分析可知:按形状分:①④⑧⑩,②⑥⑨,③⑤⑦.\n(2)由分析可知:按动物分①⑤⑨,②⑧⑩,③④⑥⑦。", + "knowledge_points": [ + "按不同标准分类(单次)" + ], + "source": "22-23一年级上·甘肃天水·期末" + }, + { + "id": "58", + "unit": "第三单元分类与整理", + "question_type": "填空题", + "difficulty": 0.65, + "question": "数一数,填一填。![](images/72cf48ccc4e1f840edeee7c52ec0fc84705a2c211e4fd908b3b56b094cc6f6c8.jpg)\n数一数,上图中每种图形各有多少个。填到下面表格里。![](images/7832a195d83a04701a125901e2ce64e6.png)\n(2) 上面的五种图形一共有( )个。( )形的数量最多。 (3) 长方形比三角形少( )个,正方形比平行四边形多( )个。(4) 文文摆了 3 个 ![](images/fcb81696459c3d7025fcfc302925cae2.png), 一共用了 ( ) 个圆。", + "options": [], + "answer": "4;3;3;7;1 18;三角 3;2 6", + "solution": "【分析】(1)(2)(3) 长方形和正方形都有四条边,四个角都一样大,正方形四条边相等,长方形相邻的边不相等;圆形是一条曲线围成的;三角形有三条边,三个角;平行四边形的对边平行且相等,据此解答。求两个数的差用减法计算。求一共有多少用加法计算。(4) 每个![](images/fcb81696459c3d7025fcfc302925cae2.png)里有2个圆,用3个2相加即可.\n【详解】(1) 统计表如下:![](images/259718a912468dff9430b02589abf703.png)\n(2) 4 + 3 + 3 + 7 + 1 = 18 (个) 所以上面五种图形一共有18个。7 > 4 > 3 > 1,所以三角形的数量最多.\n(3) 7 - 4 = 3 (个),所以长方形比三角形少3个。3 - 1 = 2 (个),所以正方形比平行四边形多2个.\n(4) 文文摆了 1 个需要 2 个圆。所以3个需要 2 + 2 + 2 = 6,一共用了6个圆。", + "knowledge_points": [ + "数据的搜集与整理", + "长方形,正方形,三角形和圆的初步认识", + "连加(20以内)" + ], + "source": "22-23一年级下·山东菏泽·期中" + }, + { + "id": "59", + "unit": "第三单元分类与整理", + "question_type": "填空题", + "difficulty": 0.85, + "question": "我会填。![](images/cf1d64f44789193bbff87a24c655737ecd6c7c15921c2a5201464787b1e428ef.jpg)\n(1) 把表格补充完整。![](images/df854514795c427e88a3a83c2420a798.png)\n(2) ( ) 最多, ( ) 最少.\n(3) ![](images/3ffc51d24c7b4225ac274442f916c506.png)减少( )个就和![](images/dab71f9137469e490ad137d6bd984d80.png)同样多了。", + "options": [], + "answer": "2;5;6;3;1 圆;平行四边形 2", + "solution": "【分析】由题意可知,通过数一数,正方形有2个,长方形有5个,圆有6个,三角形有3个,平行四边形有1个;因为 6 > 5 > 3 > 2 > 1,所以圆的数量是最多的,平行四边形的数量是最少的;长方形有5个,三角形有3个,则长方形应减少2个就和三角形同样多了,列式为 5 - 2 = 3 (个),据此解答即可。熟练掌握按不同标准分类是解决此题的关键.\n【详解】(1) 把表格补充完整:![](images/dd2a70549851f4b253de4c6fa2013934.png)\n(2) (圆) 最多,(平行四边形)最少.\n(3) 减少 (2) 个就和三角形同样多了。", + "knowledge_points": [ + "按不同标准分类(单次)", + "数一数", + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "22-23一年级下·浙江杭州·期末" + }, + { + "id": "60", + "unit": "第三单元分类与整理", + "question_type": "填空题", + "difficulty": 0.65, + "question": "自主学习教材第28页例2。![](images/7a9e0fb4f55e8859fdc5a81c10dea44cec57f07dcbe02ae7c10daca6048bfdff.jpg)\n(1) 可以按 ( ) 分,把分类结果整理到表中.\n\n| | 大人 | 孩子 |\n| ---- | ---- | ---- |\n| 人数 | | |\n\n(2) 可以按 ( ) 分,把分类结果整理到表中.\n\n| | 男 | 女 |\n| ---- | -- | -- |\n| 人数 | | |\n\n(3) 根据上表可知,分类标准不同,分类结果也 ( ) , 但总数 ( ) 。", + "options": [], + "answer": "年龄;8;6 性别;7;7 不同;相同", + "solution": "【分析】根据不同的分类标准可以对人群进行分类,可以根据年龄分成大人和孩子,也可以根据性别分成男人和女人,不同的分类方式,分类结果不同,但不影响总数。本题考查根据不同的标准进行分类.\n【详解】(1) 可以按(年龄)分,把分类结果整理到表中.\n\n| | 大人 | 孩子 |\n| ---- | ---- | ---- |\n| 人数 | 8 | 6 |\n\n(2) 可以按(性别)分,把分类结果整理到表中.\n\n| | 男 | 女 |\n| ---- | -- | -- |\n| 人数 | 7 | 7 |\n\n(3) 8 + 6 = 14 (人);7 + 7 = 14 (人)。根据上表可知,分类标准不同,分类结果也(不同),但总数(相同)。", + "knowledge_points": [ + "按不同标准分类(单次)" + ], + "source": "22-23一年级下·全国·随堂练习" + }, + { + "id": "61", + "unit": "第三单元分类与整理", + "question_type": "填空题", + "difficulty": 0.85, + "question": "数一数,填一填。![](images/54c370df0296fe0ab241e83a0ce6570e3ed124eeeec8c44acb35825b6c565921.jpg)\n\n| | 个数 |\n| ---- | ---- |\n| 正方形 | () |\n| 三角形 | () |\n| 圆 | () |\n| 长方形 | () |", + "options": [], + "answer": "1;3;1;2", + "solution": "【分析】长方形和正方形都有四条边,四个角都是直角,正方形四条边相等,圆形是一条曲线围成的,三角形是由三条边,三个角组成,据此解答.\n【详解】从图上可得:\n\n| | 个数 |\n| ---- | ---- |\n| 正方形 | 1 |\n| 三角形 | 3 |\n| 圆 | 1 |\n| 长方形 | 2 |\n\n[点睛]本题考查了学生对长方形,正方形,圆形及三角形特征的掌握。", + "knowledge_points": [ + "数据的搜集与整理", + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "22-23一年级·全国·假期作业" + }, + { + "id": "62", + "unit": "第三单元分类与整理", + "question_type": "填空题", + "difficulty": 0.85, + "question": "数一数。![](images/29730dcb2e3488aa84dc851d4a331098e7bcaa23d36fe883715943a2b4c02322.jpg)![](images/d18f230a000c19153d24d463cc27e179.png)", + "options": [], + "answer": "4;3;3;2", + "solution": "【分析】长方形和正方形都有四条边,四个角都是直角,正方形四条边相等,圆形是一条曲线围成的,三角形是由三条边,三个角组成,据此解答。本题考查学生对各种平面图形特征的掌握和运用.\n【详解】从图上可得:![](images/84222c51ab81d95500c2899d6442ca4f.png)\n依次为:4 个圆,3 个正方形,3 个三角形,2 个长方形。", + "knowledge_points": [ + "数据的搜集与整理", + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "22-23一年级·全国·假期作业" + }, + { + "id": "63", + "unit": "第三单元分类与整理", + "question_type": "填空题", + "difficulty": 0.85, + "question": "把下面的图形按要求分一分。![](images/6fb98d1ded45363a850ea578eeb0b08f3cc1cf586dc7f5ee8b7a4b610e9bb6a2.jpg)\n正方形有( )个,长方形有( )个,圆有( )个。", + "options": [], + "answer": "3;4;4", + "solution": "【分析】长方形和正方形都有四条边,四个角都是直角,正方形四条边相等,圆形是一条曲线围成的,据此解答即可。本题考查学生对各种平面图形特征认识的掌握和运用.\n【详解】从图上可得:正方形有3个,长方形有4个,圆有4个。", + "knowledge_points": [ + "数据的搜集与整理", + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "22-23一年级·全国·假期作业" + }, + { + "id": "64", + "unit": "第三单元分类与整理", + "question_type": "填空题", + "difficulty": 0.85, + "question": "数一数。有( )个圆,有( )个正方形,有( )个三角形,有( )个长方形,有( )个平行四边形。![](images/e3ef30e7433ee6dde61fe37e44ed4d9182e301d2a094e07aed15ae99047a38c6.jpg)", + "options": [], + "answer": "4;4;2;2;1", + "solution": "【分析】长方形和正方形都有四条边,四个角都是直角,正方形四条边相等,圆形是一条曲线围成的,三角形是由三条边,三个角组成,平行四边形的对边平行且相等,据此解答。本题考查学生对各种平面图形特征的掌握和运用.\n【详解】从图上可得:有 4 个圆,有 4 个正方形,有 2 个三角形,有 2 个长方形,有 1 个平行四边形。", + "knowledge_points": [ + "数据的搜集与整理", + "平行四边形的初步认识", + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "22-23一年级·全国·假期作业" + }, + { + "id": "65", + "unit": "第三单元分类与整理", + "question_type": "填空题", + "difficulty": 0.85, + "question": "数一数,填一填。![](images/24149fa043d1807b3edc3fcb056bd81b541794df7061e2fc1e4402fb03ed84d7.jpg)\n\n| 图形 | 长方形 | 正方形 | 三角形 | 圆 |\n| ---- | ------ | ------ | ------ | -- |\n| 个数 | ()个 | ()个 | ()个 | ()个 |", + "options": [], + "answer": "3;4;3;6", + "solution": "【分析】长方形和正方形都有四条边,四个角都是直角,正方形四条边相等,圆形是一条曲线围成的,三角形是由三条边,三个角组成,据此解答。本题考查学生对平面图形认识的掌握和运用.\n【详解】从图上可得:\n\n| 图形 | 长方形 | 正方形 | 三角形 | 圆 |\n| ---- | ------ | ------ | ------ | -- |\n| 个数 | 3个 | 4个 | 3个 | 6个 |", + "knowledge_points": [ + "数据的搜集与整理", + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "22-23一年级下·全国·课前预习" + }, + { + "id": "66", + "unit": "第三单元分类与整理", + "question_type": "填空题", + "difficulty": 0.85, + "question": "分类标准不同,分类结果也可能( ), 但总数( )。", + "options": [], + "answer": "不同;相同", + "solution": "【分析】如图,若按大人和孩子分,分别有8人和4人;若按男,女分,分别有6人和6人。依此解答即可。本题考查按不同标准分类,不管按什么标准,总数都是相同的。![](images/06f910e1d780c2e09cc36d3fdc945cc89f9e645d1ab8dec1b06927d8e1528577.jpg)\n【详解】根据分析可知,分类标准不同,分类结果也可能不同,但总数相同。", + "knowledge_points": [ + "按不同标准分类(单次)" + ], + "source": "22-23一年级下·全国·课前预习" + }, + { + "id": "67", + "unit": "第三单元分类与整理", + "question_type": "判断题", + "difficulty": 0.85, + "question": "分类时只能按颜色分,不能按形状分。( )", + "options": [ + "√", + "*" + ], + "answer": "×", + "solution": "【分析】分类时根据物品的特征分,比如颜色,形状。.\n【详解】分类时可以按颜色分,也可以按形状分。原题说法错误。故答案为: ×", + "knowledge_points": [ + "按不同标准分类(单次)" + ], + "source": "24-25一年级下·湖南岳阳·期中" + }, + { + "id": "68", + "unit": "第三单元分类与整理", + "question_type": "判断题", + "difficulty": 0.85, + "question": "我们在将物体分类时,只能有一种分法。( )", + "options": [ + "√", + "*" + ], + "answer": "×", + "solution": "【分析】我们在将物体分类时,根据不同的物体特点,有些物体只有一种分法,也有一些物体有多种分法。如下图,可以这样分: ①按内部图案分, ②按外部形状分, ③按平面图形和立体图形分。所以原题说法错误。![](images/5a0b5fe8b651d73e76b094599c122292.png)\n【详解】由题意分析得:我们在将物体分类时,有些物体只有一种分法,也有一些物体有多种分法;原说法错误。故答案为: ×", + "knowledge_points": [ + "按不同标准分类(单次)" + ], + "source": "23-24一年级下·黑龙江哈尔滨·期末" + }, + { + "id": "69", + "unit": "第三单元分类与整理", + "question_type": "判断题", + "difficulty": 0.65, + "question": "苹果和西瓜都是水果。( )", + "options": [ + "√", + "*" + ], + "answer": "√", + "solution": "【分析】苹果和西瓜都是水果,据此得出结论即可.\n【详解】根据分析知:原题结论正确。故答案为:√", + "knowledge_points": [ + "按不同标准分类(单次)" + ], + "source": "23-24 一年级下·湖南怀化·期末" + }, + { + "id": "70", + "unit": "第三单元分类与整理", + "question_type": "解答题", + "difficulty": 0.85, + "question": "完成统计表并填空.\n\n![](images/187280a94abf126fd46af985b0168f9f22537ae9af40c08e2c55014e3a1d7c38.jpg)\n\n![](images/8f4f0cbce65b3a75f0191bc983a28247b41ab9b951e9ce5f6258e0057e20091e.jpg)\n\n(1) 你能把各种图形整理一下填入下表吗。\n\n| 图形 | 长方形 | 正方形 | 圆 | 三角形 |\n| ------ | ------ | ------ | -- | ------ |\n| 个数 | | | | |\n\n(2) 根据统计结果填一填:![](images/7c6b28eb6a6f25ad5dc8081f5b819b44.png)", + "options": [], + "answer": "8;2;10;2 6;8", + "solution": "【分析】(1)根据长方形,正方形,三角形及圆形的特征来解决即可。长方形是长长方方的,由4条边围成,且对边一样长;正方形是正正方方的,由4条边围成,且4条边都一样长;三角形由3条线段首尾依次连接而成的封闭图形;圆形由一条曲线围成。数一数各种图形的个数,整理到统计表中即可。(2) 求一个数比另一个数多(少)多少,用减法列式解决.\n【详解】(1) 统计表如下:\n\n| 图形 | 长方形 | 正方形 | 圆 | 三角形 |\n| ------ | ------ | ------ | --- | ------ |\n| 个数 | 8 | 2 | 10 | 2 |\n\n(2) 8 - 2 = 6 (个) 表示长方形比正方形多6个;10 - 2 = 8 (个) 表示圆比三角形多8个。![](images/609cc8bfdc9a34bc29a94828a456d0d4.png)", + "knowledge_points": [ + "8,9 的加减法", + "单式统计表的特点及填补", + "10 的加减法", + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "23-24一年级下·河南漯河·期末" + }, + { + "id": "71", + "unit": "第三单元分类与整理", + "question_type": "解答题", + "difficulty": 0.65, + "question": "给下列图形分类.\n\n![](images/13bb0d15343c0741e8ae131a3cf8ac796dc3eadf29d9c82569f05603bd07ad97.jpg)\n\n(1) 按颜色的不同分一分,填写下表.\n\n| | 白色 | 深黑色 | 浅黑色 |\n| ---- | ---- | ------ | ------ |\n| 个数 | | | |\n\n(2) 按形状的不同分一分,填写下表.\n\n| 形状1 | 形状2 | 形状3 | 形状4 | 形状5 |\n| ------ | ------ | ------ | ------ | ------ |\n| 个数 | | | | |", + "options": [], + "answer": "6;7;4 3;3;4;4;3", + "solution": "【分析】(1)根据颜色数一数即可知白色,深黑色,浅黑色各有多少个。(2)根据每个图形的特征数一数即可知每个图形各有多少个.\n【详解】(1) 按颜色分:\n\n| | 白色 | 深黑色 | 浅黑色 |\n| ---- | ---- | ------ | ------ |\n| 个数 | 6 | 7 | 4 |\n\n(2) 按形状分:\n\n| 形状 | ① | ② | ③ | ④ | ⑤ |\n| ---- | -- | -- | -- | -- | -- |\n| 个数 | 3 | 3 | 4 | 4 | 3 |\n\n![](images/97bf1251b9f7490e51f83c8fe0cb1986.png)", + "knowledge_points": [ + "按不同标准分类(单次)", + "平行四边形的初步认识", + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "23-24一年级下·江西吉安·期末" + }, + { + "id": "72", + "unit": "第三单元分类与整理", + "question_type": "解答题", + "difficulty": 0.85, + "question": "我会分类与整理.\n\n![](images/3d537787e7b315bad74a7087a1ea2289.png)\n\n(1) 按卡片的形状分.\n\n| | 正方形 | 三角形 | 圆 |\n| ---- | ------ | ------ | -- |\n| 张数 | | | |\n\n(2) 按水果的种类分.\n\n| | 苹果 | 桃 | 香蕉 |\n| ---- | ---- | -- | ---- |\n| 张数 | | | |", + "options": [], + "answer": "4;5;3 3;5;4", + "solution": "【分析】(1)正方形是方方正正的,有4条直直的边,每条边都相等;三角形有3条直直的边;圆没有直直的边,由此数出各形状的数量即可。(2) 分别数出苹果,桃,香蕉的数量填空即可.\n【详解】(1) 按卡片的形状分:\n\n| | 正方形 | 三角形 | 圆 |\n| ---- | ------ | ------ | -- |\n| 张数 | 4 | 5 | 3 |\n\n(2) 按水果的种类分:\n\n| | 苹果 | 桃 | 香蕉 |\n| ---- | ---- | -- | ---- |\n| 张数 | 3 | 5 | 4 |", + "knowledge_points": [ + "按不同标准分类(单次)", + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "18-19一年级下·全国·期末" + }, + { + "id": "73", + "unit": "第三单元分类与整理", + "question_type": "解答题", + "difficulty": 0.65, + "question": "先把下面的水果分一分,再涂一涂,填一填.\n\n![](images/530df2098e30ce5fb80b6252e07f098c.png)\n\n(1) 根据你的分类,把各种水果数量填在下面的表格中.\n\n| 水果 | 西瓜 | 苹果 | 草莓 | 香蕉 |\n| ---- | ---- | ---- | ---- | ---- |\n| 个数 | | | | |\n\n(2) ( )的数量最多.\n\n(3) 至少再添 ( ) 个西瓜,西瓜的数量就是最多的。", + "options": [], + "answer": "4;2;6;5 草莓;3", + "solution": "【分析】依次数出每种水果的数量涂色即可,1个圆代表1个,从下往上涂。(1) 根据数出的数量填写表格;(2) 比较每种水果的数量,找出数量最多的即可;(3) 先用减法求出数量最多的比西瓜多几个,要想西瓜最多,求出的结果再加上 1 个即可.\n【详解】![](images/4e3773280a50b12b30c9b9edb8b03a72.png)\n\n(1) 表格填写:\n\n| 水果 | 西瓜 | 苹果 | 草莓 | 香蕉 |\n| ---- | ---- | ---- | ---- | ---- |\n| 个数 | 4 | 2 | 6 | 5 |\n\n(2) 6 > 5 > 4 > 2 草莓的数量最多.\n(3) 6 - 4 = 2 (个);2 + 1 = 3 (个)。至少再添3个西瓜,西瓜的数量就是最多的。", + "knowledge_points": [ + "按不同标准分类(单次)" + ], + "source": "23-24一年级下·福建福州·期末" + }, + { + "id": "74", + "unit": "第三单元分类与整理", + "question_type": "解答题", + "difficulty": 0.85, + "question": "分一分,填一填.\n\n![](images/b7f80c65c79e488879aa5e49d3be3e4253dc523139e4b76d61e4869e4137d69a.jpg)\n\n(1) 填一填.\n\n| 蔬菜 | 胡萝卜 | 茄子 | 西红柿 | 青菜 |\n| ---- | ------ | ---- | ------ | ---- |\n| 个数 | | | | |\n\n(2) ( ) 的个数最多,( )的个数最少。", + "options": [], + "answer": "10;6;3;4 胡萝卜;茄子", + "solution": "【分析】(1)分别数出各种蔬菜的数量并填空即可;(2) 直接比较各蔬菜的数量即可判断出数量最多和最少分别是哪种蔬菜.\n【详解】(1) 填表如下:\n\n| 蔬菜 | 胡萝卜 | 茄子 | 西红柿 | 青菜 |\n| ---- | ------ | ---- | ------ | ---- |\n| 个数 | 10 | 6 | 3 | 4 |\n\n(2) 10 > 6 > 4 > 3 所以胡萝卜的个数最多,茄子的个数最少。", + "knowledge_points": [ + "10以内数的比大小", + "按不同标准分类(单次)" + ], + "source": "23-24一年级下·湖北孝感·期末" + }, + { + "id": "75", + "unit": "第三单元分类与整理", + "question_type": "解答题", + "difficulty": 0.65, + "question": "我会分类与整理.\n\n![](images/19308c7e5a7ce7729961c942bb3290d0.png)\n\n(1) 按卡片的形状来分.\n\n| 图形 | 正方形 | 三角形 | 圆 |\n| ---- | ------ | ------ | -- |\n| 张数 | | | |\n\n(2) 按水果的种类来分.\n\n| 水果 | 苹果 | 桃 | 香蕉 |\n| ---- | ---- | -- | ---- |\n| 个数 | | | |\n\n(3) 根据上面的统计结果,你能提出一个数学问题吗。", + "options": [], + "answer": "4;5;3 3;5;4 见详解", + "solution": "【分析】(1)数一数,依次是4张,5张,3张,据此填空;(2) 数一数,依次是 3 个,5 个,4 个,据此填空。 (3) 合理即可,答案不唯一。如:一共有多少个水果。\n【详解】(1) 按卡片的形状来分:\n\n| 图形 | 正方形 | 三角形 | 圆 |\n| ---- | ------ | ------ | -- |\n| 张数 | 4 | 5 | 3 |\n\n(2) 按水果的种类来分:\n\n| 水果 | 苹果 | 桃 | 香蕉 |\n| ---- | ---- | -- | ---- |\n| 个数 | 3 | 5 | 4 |\n\n(3) 示例问题:一共有多少个水果。\n解:3 + 5 + 4 = 12 (个)。答:一共有12个水果。(问题与答案不唯一,合理即可。)", + "knowledge_points": [ + "数据的搜集与整理", + "按不同标准分类(单次)", + "\"提问题\"\"填条件\"问题" + ], + "source": "23-24一年级下·湖南岳阳·期末" + }, + { + "id": "76", + "unit": "第三单元分类与整理", + "question_type": "解答题", + "difficulty": 0.85, + "question": "先填表,再回答问题.\n\n![](images/344728bef7e90f9836b1899e17ea03c1ef8ef143ea67f5c2e1398a7004797397.jpg)\n\n| 图形 | 长方形 | 正方形 | 三角形 | 圆 | 平行四边形 |\n| ---- | ------ | ------ | ------ | -- | ---------- |\n| 个数/个 | | | | | |\n\n(1) 数量最多的图形是 ( ),数量最少的图形是 ( ).\n\n(2) 小明摆了 4 棵 ![](images/682f39632b403ea0cb95ddded05779cd.png) , 一共用了 ( ) 个△。", + "options": [], + "answer": "6;1;7;6;2 三角形;正方形 12", + "solution": "【分析】根据长方形,正方形,平行四边形,三角形及圆形的特征来完成表格。长方形是长长方方的,由4条边围成,且对边一样长;正方形是正正方方的,由4条边围成,且4条边都一样长;平行四边形是由4条边围成,且对边一样长,一组对边向同一个方向倾斜;三角形由3条线段首尾依次连接而成的封闭图形;圆形由一条曲线围成。(1) 比较一下各种图形数量的多少,即可知道哪种图形数量最多,哪种图形数量最少。(2) 摆1棵![](images/682f39632b403ea0cb95ddded05779cd.png)需要用 3 个△, 摆4棵就是求4个3的和,可以用连加.\n【详解】填表:\n\n| 图形 | 长方形 | 正方形 | 三角形 | 圆 | 平行四边形 |\n| ---- | ------ | ------ | ------ | -- | ---------- |\n| 个数/个 | 6 | 1 | 7 | 6 | 2 |\n\n(1) 7 > 6 > 2 > 1,即数量最多的图形是三角形,数量最少的图形是正方形.\n(2) 3 + 3 + 3 + 3 = 12 (个)。小明摆了4棵![](images/682f39632b403ea0cb95ddded05779cd.png),一共用了12个△。", + "knowledge_points": [ + "数据的搜集与整理", + "平行四边形的初步认识", + "单式统计表的特点及填补", + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "23-24一年级下·湖北武汉·期末" + }, + { + "id": "77", + "unit": "第三单元分类与整理", + "question_type": "解答题", + "difficulty": 0.65, + "question": "我会分类整理.\n\n![](images/883da1b25cea7f32767ec44566d773b5bb42364a6a425adccd71a9bad13fd884.jpg)\n\n(1) 按形状分一分,看看每种图形各有几个.\n\n| 图形 | 三角形 | 圆 | 正方形 | 长方形 | 平行四边形 |\n| ---------- | ------ | -- | ------ | ------ | ---------- |\n| 个数(个) | | | | | |\n\n(2) ![](images/3275fb7fd55818bf26421132e8a92e5f26dc5f31df49949732dc4146db9f38b6.jpg)比 ![](images/746d4ede1aa0057fb6f0ce10117de66582d4765914c9586881cedd7d60991d1f.jpg)多()个,比![](images/8ea4925ac8576c7c387f490a941bd114b895fadb643169aa3708455fe162f4b0.jpg)少()个。 \n(3) 以上图形个数一共有()个。", + "options": [], + "answer": "4;6;2;3;4 2;2 19", + "solution": "【分析】(1)三角形有3条直直的边;正方形是方方正正的,有4条直直的边,每条边都相等;平行四边形有4条直直的边,对边相等,有2条同方向的斜边;长方形是长长方方的,有4条直直的边,对边相等;圆没有直直的边;据此数出各平面图形的数量并填空即可。(2)根据减法的意义,用![](images/3275fb7fd55818bf26421132e8a92e5f26dc5f31df49949732dc4146db9f38b6.jpg)的数量减去![](images/746d4ede1aa0057fb6f0ce10117de66582d4765914c9586881cedd7d60991d1f.jpg)的数量即可;用![](images/8ea4925ac8576c7c387f490a941bd114b895fadb643169aa3708455fe162f4b0.jpg)的数量减去![](images/3275fb7fd55818bf26421132e8a92e5f26dc5f31df49949732dc4146db9f38b6.jpg)的数量即可。(3) 根据加法的意义,将各平面图形的数量相加即可求出总数量.\n【详解】(1) 填表如下:\n\n| 图形 | 三角形 | 圆 | 正方形 | 长方形 | 平行四边形 |\n| ---------- | ------ | -- | ------ | ------ | ---------- |\n| 个数(个) | 4 | 6 | 2 | 3 | 4 |\n\n(2) 4 - 2 = 2 (个);6 - 4 = 2 (个)。所以![](images/3275fb7fd55818bf26421132e8a92e5f26dc5f31df49949732dc4146db9f38b6.jpg)比![](images/746d4ede1aa0057fb6f0ce10117de66582d4765914c9586881cedd7d60991d1f.jpg)多2个,比![](images/8ea4925ac8576c7c387f490a941bd114b895fadb643169aa3708455fe162f4b0.jpg)少2个.\n(3) 4 + 6 + 2 + 3 + 4 = 19 (个),以上图形个数一共有19个。", + "knowledge_points": [ + "数据的搜集与整理", + "6 的加减法", + "长方形,正方形,三角形和圆的初步认识", + "连加 (20以内)" + ], + "source": "22-23一年级下·广东汕尾·期中" + }, + { + "id": "78", + "unit": "第三单元分类与整理", + "question_type": "解答题", + "difficulty": 0.65, + "question": "(1) 把上面的卡片按形状分一分.\n\n![](images/b7f80c65c79e488879aa5e49d3be3e4253dc523139e4b76d61e4869e4137d69a.jpg)\n\n| 形状 | 正方形 | 长方形 | 三角形 | 圆 | 平行四边形 |\n| ---------- | ------ | ------ | ------ | -- | ---------- |\n| 张数(张) | | | | | |\n\n(2) 把上面的卡片按汉字的偏旁分一分.\n\n| 偏旁 | 口 | 辶 |\n| ---- | -- | -- |\n| 张数(张) | | |\n\n(3) 一共有()张卡片.\n\n(4) \"辶\"的字比\"口\"的字少几张。", + "options": [], + "answer": "2;2;1;2;1 5;3 8;2", + "solution": "【分析】(1)三角形有3条直直的边;正方形是方方正正的,有4条直直的边,每条边都相等;平行四边形有4条直直的边,对边相等,有2条同方向的斜边;长方形是长长方方的,有4条直直的边,对边相等;圆没有直直的边;据此数出各平面图形的个数即可。(2) 分别数出偏旁为\"口\"和\"辶\"的汉字的数量并填空即可。(3) 用\"口\"的字与\"辶\"的字数量相加即可求出卡片总数。(4) 用\"口\"的字的数量减去\"辶\"的字的数量即可.\n【详解】(1) 按形状分:\n\n| 形状 | 正方形 | 长方形 | 三角形 | 圆 | 平行四边形 |\n| ---------- | ------ | ------ | ------ | -- | ---------- |\n| 张数(张) | 2 | 2 | 1 | 2 | 1 |\n\n(2) 按偏旁分:\n\n| 偏旁 | 口 | 辶 |\n| ---- | -- | -- |\n| 张数(张) | 5 | 3 |\n\n(3) 5 + 3 = 8 (张),一共有8张卡片.\n(4) 5 - 3 = 2 (张),\"辶\"的字比\"口\"的字少2张。", + "knowledge_points": [ + "8,9 的加减法", + "按不同标准分类(单次)", + "5 以内数的减法" + ], + "source": "23-24一年级下·福建龙岩·期末" + }, + { + "id": "79", + "unit": "第三单元分类与整理", + "question_type": "解答题", + "difficulty": 0.85, + "question": "看图分类整理,填写如表,再回答问题.\n\n![](images/ab3f660feb4c4ae96c6c1fbefd84b6f1643d5297885324d020e63f15d711dbc6.jpg)\n![](images/0ec52ddaca708274501a4b26d98a8a803aef0c846a94d7d8a852dcaa8b274a95.jpg)\n\n(1) 填表.\n\n| 三角形 | 圆形 | 正方形 | 长方形 | 灰色 | 白色 |\n| ------ | ---- | ------ | ------ | ---- | ---- |\n| 个数 | ()个 | ()个 | ()个 | ()个 | ()个 | ()个 |\n\n(2) 4种图形中,()最多,()最少,一共有()个图形。", + "options": [], + "answer": "7;4;2;3;7;9 三角形;正方形;16", + "solution": "【分析】(1)三角形有3条直直的边;圆没有直直的边;正方形有4条直直的边,每条边都相等;长方形有4条直直的边,对边相等;由此数出图形的数量及各颜色图形数量填表即可。(2) 比较每种图形的数量,找出最多的和最少的。4种图形数量相加就是总数量.\n【详解】(1) 填表如下:\n\n| 三角形 | 圆形 | 正方形 | 长方形 | 灰色 | 白色 |\n| ------ | ---- | ------ | ------ | ---- | ---- |\n| 个数 | 7个 | 4个 | 2个 | 3个 | 7个 | 9个 |\n\n(2) 7 > 4 > 3 > 2,三角形最多,正方形最少;7 + 4 + 2 + 3 = 16 (个),一共有16个图形。", + "knowledge_points": [ + "按不同标准分类(单次)", + "7以内数的比大小", + "长方形,正方形,三角形和圆的初步认识", + "连加(20以内)" + ], + "source": "23-24 二年级下·河南周口·期末" + }, + { + "id": "80", + "unit": "第三单元分类与整理", + "question_type": "解答题", + "difficulty": 0.85, + "question": "分一分.\n\n![](images/176476f3f1d220fbd328cda70096ef4c0cf141dbdbbf22098cfe781f69ca36e2.jpg)\n\n(1) 上面的图形按颜色分,完成下表.\n\n| | 白色 | 黑色 |\n| ---- | ---- | ---- |\n| 个数(个) | () | () |\n\n(2) 上面的图形按形状分,完成下表.\n\n| 形状 | 三角形 | 圆 | 正方形 | 长方形 |\n| ---------- | ------ | -- | ------ | ------ |\n| 个数(个) | | | | |\n\n(3) 一共有多少个图形。", + "options": [], + "answer": "10;7 6;4;4;3 17个", + "solution": "【分析】(1)按颜色的不同,分别数一数,即可解决。 (2) 按图形形状的不同,分别数一数,即可解决。长方形是长长方方的,由4条边围成,且对边一样长;平行四边形是由4条边围成,且对边一样长,一组对边向同一个方向倾斜;三角形由3条线段首尾依次连接而成的封闭图形;圆形由一条曲线围成。(3) 把白色图形的数量与黑色图形的数量相加即可.\n【详解】(1) 按颜色分:\n\n| | 白色 | 黑色 |\n| ---- | ---- | ---- |\n| 个数(个) | 10 | 7 |\n\n(2) 按形状分:\n\n| 形状 | 三角形 | 圆 | 正方形 | 长方形 |\n| ---------- | ------ | -- | ------ | ------ |\n| 个数(个) | 6 | 4 | 4 | 3 |\n\n(3) 10 + 7 = 17 (个)。答:一共有17个图形。", + "knowledge_points": [ + "按不同标准分类(单次)", + "平行四边形的初步认识", + "长方形,正方形,三角形和圆的初步认识", + "不进位加法(20以内)" + ], + "source": "22-23一年级下·江西吉安·期末" + }, + { + "id": "81", + "unit": "第三单元分类与整理", + "question_type": "解答题", + "difficulty": 0.85, + "question": "你能把各种图形整理一下吗。\n\n![](images/7a49b0d13fe4ab3b9323794dc4b4ed4a45320963106e7781605c20ed52f031f1.jpg)\n\n![](images/d410e34cc195bcb31531f9f9c312d2ed.png)\n\n(1) ( ) 最多, ( ) 最少。 \n(2) □比△多()个,○比□多()个。", + "options": [], + "answer": "6;5;10;8 圆;正方形 1;4", + "solution": "【分析】长方形是长长方方的,有4条直直的边,对边相等;正方形是方方正正的,有4条直直的边,每条边都相等;圆没有直直的边;三角形有3条直直的边。由此数出每种图形的数量,将数量相加就是总数量。(1) 比较各种图形数量的多少,找到最多的和最少的;(2) 根据减法的意义,长方形的数量减去正方形的数量 = 长方形比正方形多的数量;圆的数量减去长方形的数量 = 圆比长方形多的数量.\n【详解】长方形有6个;正方形有5个;圆有10个;三角形有8个.\n\n| 图形 | 长方形 | 正方形 | 圆 | 三角形 |\n| ---- | ------ | ------ | -- | ------ |\n| 个数 | 6 | 5 | 10 | 8 |\n\n(1) 10 > 8 > 6 > 5 圆最多,正方形最少.\n(2) 6 - 5 = 1 (个);10 - 6 = 4 (个)。所以□比△多1个,○比□多4个。", + "knowledge_points": [ + "10以内数的比大小", + "按不同标准分类(单次)", + "10的加减法", + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "23-24 一年级下·甘肃平凉·期末" + }, + { + "id": "82", + "unit": "第三单元分类与整理", + "question_type": "解答题", + "difficulty": 0.65, + "question": "我会分类整理.\n\n![](images/c32af5f9a2209d42786cda4987549170c294ff3368977dadd069419e7e508ac7.jpg)\n\n(1) 数一数,填一填.\n\n| 图形 | 长方形 | 正方形 | 圆 | 三角形 | 平行四边形 |\n| ---- | ------ | ------ | -- | ------ | ---------- |\n| 个数 | | | | | |\n\n(2)上面的图形()的个数最多。 \n(3) 正方形比圆形少()个。 \n(4) 你还能提出其他数学问题并解答吗。", + "options": [], + "answer": "12;2;4;3;2 长方形;1 见详解", + "solution": "【分析】(1)长方形是长长方方的,有 4 条直直的边,对边相等;正方形是方方正正的,有 4 条直直的边,每条边都相等;三角形有 3 条直直的边;圆没有直直的边;平行四边形有 4 条直直的边,对边相等,有 2 条同方向的斜边。由此数出各图形的数量填空即可。(2) 比较各图形的数量,找出最多的即可;(3) 根据减法的意义,圆形的数量减去正方形的数量 = 正方形比圆形少的数量;(4) 提出的问题符合题意即可,答案不唯一.\n【详解】(1) 表格填写如下:\n\n| 图形 | 长方形 | 正方形 | 圆 | 三角形 | 平行四边形 |\n| ---- | ------ | ------ | -- | ------ | ---------- |\n| 个数 | 12 | 2 | 4 | 3 | 2 |\n\n(2) 12 > 4 > 3 > 2 = 2,上面的图形长方形的个数最多.\n(3) 3 - 2 = 1 (个),正方形比圆形少1个.\n(4) 示例:长方形和正方形一共有多少个。12 + 2 = 14 (个)。答:长方形和正方形一共有14个。(问题不唯一。)", + "knowledge_points": [ + "20以内数的比大小", + "按不同标准分类(单次)", + "\"提问题\"\"填条件\"问题", + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "23-24一年级下·河北唐山·期末" + }, + { + "id": "83", + "unit": "第三单元分类与整理", + "question_type": "解答题", + "difficulty": 0.85, + "question": "把这些卡片分一分.\n\n![](images/1d7a33c604ced6fa2cff761422a9937677907a27a4a617bf5d7b0b6c714f003.jpg)\n\n(1) 按卡片的形状来分.\n\n| 形状 | 圆形 | 三角形 | 正方形 |\n| ---- | ---- | ------ | ------ |\n| 张数 | | | |\n\n(2) 按卡片上动物的种类来分.\n\n| 动物 | 熊猫 | 小猴 | 小鸟 |\n| ---- | ---- | ---- | ---- |\n| 张数 | | | |", + "options": [], + "answer": "3;5;4 4;3;5", + "solution": "【分析】(1)圆没有直直的边;三角形有3条直直的边;正方形是方方正正的,有4条直直的边,每条边都相等。由此数出各形状卡片的数量填空。(2) 依次数出各动物卡片的数量填空.\n【详解】(1) 按卡片的形状来分:\n\n| 形状 | 圆形 | 三角形 | 正方形 |\n| ---- | ---- | ------ | ------ |\n| 张数 | 3 | 5 | 4 |\n\n(2) 按卡片上动物的种类来分:\n\n| 动物 | 熊猫 | 小猴 | 小鸟 |\n| ---- | ---- | ---- | ---- |\n| 张数 | 4 | 3 | 5 |", + "knowledge_points": [ + "按不同标准分类(单次)", + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "23-24一年级下·湖北孝感·期末" + }, + { + "id": "84", + "unit": "第三单元分类与整理", + "question_type": "解答题", + "difficulty": 0.85, + "question": "数一数,填一填.\n\n![](images/0948119e043dfa8c788c5f5c46dcba8d06d67bcec4f3ea36546b879d1243bfe2.jpg)\n\n(1) 把下表填写完整.\n\n| 图形 | 圆形 | 三角形 | 长方形 | 正方形 |\n| ---- | ---- | ------ | ------ | ------ |\n| 个数 | | | | |\n\n(2) 根据统计的数据填空.\n\n( )最多,( )最少。 □比△多( )个,□比○少( )个。", + "options": [], + "answer": "10;7;6;5 圆形;正方形;4;5", + "solution": "【分析】(1)据长方形,正方形,三角形及圆形的特征来解决即可。长方形是长长方方的,由4条边围成,且对边一样长;正方形是正正方方的,由4条边围成,且4条边都一样长;三角形由3条线段首尾依次连接而成的封闭图形;圆形由一条曲线围成。(2) 比较一下各类图形数量的多少,即可知道什么图形最多,什么图形最少;求一个数比另一个数多(少)多少,用减法列式计算.\n【详解】(1) 填表如下:\n\n| 图形 | 圆形 | 三角形 | 长方形 | 正方形 |\n| ---- | ---- | ------ | ------ | ------ |\n| 个数 | 10 | 7 | 6 | 5 |\n\n(2) 10 > 7 > 6 > 5 圆形最多,正方形最少。10 - 6 = 4 (个),表示○比△多4个;10 - 5 = 5 (个),表示□比○少5个。", + "knowledge_points": [ + "10以内数的比大小", + "数据的搜集与整理", + "10的加减法", + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "22-23一年级下·甘肃天水·期末" + }, + { + "id": "85", + "unit": "第三单元分类与整理", + "question_type": "解答题", + "difficulty": 0.85, + "question": "按形状将下面的卡片分一分:把下面的图片分成两类.\n\n![](images/3b2fd1c13c260a3054de92259c1ea60ceefab7ea9cefc318258759aae3b1a83b.jpg)\n\n按形状:\n\n| | □ | △ | □ |\n| ---- | -- | -- | -- |\n| 数量(个) | () | () | () |\n\n按是否带色:\n\n| | 带色的 | 不带色的 |\n| ---- | ------ | -------- |\n| 数量(个) | () | () |", + "options": [], + "answer": "3;3;3 4;5", + "solution": "【分析】正方形是方方正正的,有 4 条直直的边,每条边都相等;三角形有 3 条直直的边;平行四边形有 4 条直直的边,对边相等,有 2 条同方向的斜边;由此数出数量填空。再数出带色和不带色的数量填空.\n【详解】填表如下:\n\n| | □ | △ | □ |\n| ---- | -- | -- | -- |\n| 数量(个) | 3 | 3 | 3 |\n\n| | 带色的 | 不带色的 |\n| ---- | ------ | -------- |\n| 数量(个) | 4 | 5 |", + "knowledge_points": [ + "按不同标准分类(单次)", + "平行四边形的初步认识", + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "23-24一年级下·吉林四平·期末" + }, + { + "id": "86", + "unit": "第三单元分类与整理", + "question_type": "解答题", + "difficulty": 0.85, + "question": "我会填.\n\n![](images/bb53b1b7ef63588513b0cafa26ba9b5a.png)\n\n(1) 根据上图填写下表.\n\n| 水果 | 苹果 | 香蕉 | 梨 | 葡萄 | 桃 |\n| ---- | ---- | ---- | -- | ---- | -- |\n| 人数 | | | | | |\n\n(2) 根据上面的统计结果回答问题.\n\n①喜欢吃()的人数最多,喜欢吃()的人数最少。 \n②喜欢吃苹果的比喜欢吃香蕉的多()人.\n\n(3) 你还能提出什么数学问题并解答。", + "options": [], + "answer": "7;6;5;4;8 桃;葡萄;1 见详解", + "solution": "【分析】(1)根据图片把各水果上面的涂色圆点数一数即各水果的数量。(2) ①将喜欢各水果的人数进行比较即可。②用喜欢吃苹果的人数减去喜欢吃香蕉的人数即可。 (3) 根据题意提出问题合理即可,如\"喜欢吃苹果的和喜欢吃梨的一共多少人\"。\n【详解】(1) 填表如下:\n\n| 水果 | 苹果 | 香蕉 | 梨 | 葡萄 | 桃 |\n| ---- | ---- | ---- | -- | ---- | -- |\n| 人数 | 7 | 6 | 5 | 4 | 8 |\n\n(2) ① 8 > 7 > 6 > 5 > 4,喜欢吃桃的人数最多,喜欢吃葡萄的人数最少.\n② 7 - 6 = 1 (人)。喜欢吃苹果的比喜欢吃香蕉的多1人.\n\n(3) 示例:喜欢吃苹果的和喜欢吃梨的一共多少人。\n解:7 + 5 = 12 (人)。答:喜欢吃苹果的和喜欢吃梨的一共12人。(问题不唯一。)", + "knowledge_points": [ + "数据的搜集与整理", + "\"提问题\"\"填条件\"问题" + ], + "source": "22-23一年级下·吉林白城·期中" + }, + { + "id": "87", + "unit": "第三单元分类与整理", + "question_type": "解答题", + "difficulty": 0.65, + "question": "数一数.\n\n![](images/73c930ecba67d9b4c7ee81be5291189ff620970377b9ad6ab4a804e47fe55b49.jpg)\n![](images/96f4ff8740cb93841ad79d243ee7270006f42a33fc3c094e8ccf42d1ed29b5ca.jpg)\n![](images/3681f8a36465c495465e7446a985a84e9222304bb8bebf5b80182f8fc6e71004.jpg)\n\n(1) 你能把各种图形整理一下吗。\n\n![](images/3b35400ebfc096bc2058c966d3dc3558.png)\n\n(2) ( )最多,( )和( )同样多.\n\n(3) ![](images/06cda06435545aadc4ee8509ce00871d.png)", + "options": [], + "answer": "12;3;15;3 33 圆;正方形;三角形 9个;12个", + "solution": "【分析】(1)长方形是长长方方的,有 4 条直直的边,对边相等;正方形是方方正正的,有 4 条直直的边,每条边都相等;圆没有直直的边;三角形有 3 条直直的边。由此数出各图形的数量和总数量即可。(2) 比较各图形的数量,找出最多的和相同的;(3) 根据减法的意义,长方形的数量减去正方形的数量 = 长方形比正方形多的数量;圆的数量减去三角形的数量 = 圆比三角形多的数量.\n【详解】(1) 填表如下:\n\n| 图形 | 长方形 | 正方形 | 圆 | 三角形 |\n| ------ | ------ | ------ | --- | ------ |\n| 个数 | 12 | 3 | 15 | 3 |\n| 总数 | | | | 33 |\n\n(2) 15 > 12 > 3 = 3 圆最多,正方形和三角形同样多.\n(3) 12 - 3 = 9 (个);15 - 3 = 12 (个)。即![](images/633906bad35604bd47c78946038805f11b1e87af3f68288d101963fe1b73c39e.jpg)比□多9个,○比△多12个。", + "knowledge_points": [ + "十几减 5~2 的退位减法", + "20 以内数的比大小", + "按不同标准分类(单次)", + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "23-24一年级下·甘肃天水·期末" + }, + { + "id": "88", + "unit": "第三单元分类与整理", + "question_type": "解答题", + "difficulty": 0.85, + "question": "根据一(2)班学生最喜欢的乐器情况完成下面各题。(每人只选一种,每个🎵代表1名同学。)\n\n![](images/b94afc9181921d23bc721a2347e1679915015a7316b1ce24d87592b57864c350.jpg)\n\n(1)根据上图填写下表.\n\n| 乐器 | ① | ② | ③ | ④ |\n| ---- | -- | -- | -- | -- |\n| 人数 | | | | |\n\n(2)根据统计结果选一选。最喜欢( )的人数最多,( )最不受欢迎.\n\n![](images/52b20efa7ea4a7c73d8d308fee512b31.png)\n\nA. ①② B. ②③ C. ①③\n\n(3)最喜欢( )和( )的人数同样多.\n\n![](images/c39c34a5ec84ca1bb42b4c87434c1515.png)\n\nA. ②③ B. ①③ C. ①②", + "options": [ + "A. ①②", + "B. ②③", + "C. ①③" + ], + "answer": "9;5;8;8 A ③;④", + "solution": "【分析】(1)依次数出喜欢每种乐器的有几个人,填写表格;(2) 比较喜欢各种乐器的人数,找出最多的和最少的,最少的就是最不受欢迎的;(3) 根据人数的比较,找出人数相同的即可.\n【详解】(1) 填表如下:\n\n| 乐器 | ① | ② | ③ | ④ |\n| ---- | -- | -- | -- | -- |\n| 人数 | 9 | 5 | 8 | 8 |\n\n(2) 9 > 8 = 8 > 5,最喜欢①的人数最多,②最不受欢迎,对应选项A.\n(3) 8 = 8,最喜欢③和④的人数同样多。", + "knowledge_points": [ + "10以内数的比大小", + "按不同标准分类(单次)" + ], + "source": "23-24一年级下·青海果洛·期末" + }, + { + "id": "89", + "unit": "第三单元分类与整理", + "question_type": "解答题", + "difficulty": 0.85, + "question": "分类与整理.\n\n![](images/53798578a12fd502f503a44ab9a303c9.png)\n\n(1) 把上面的卡片按图形分一分.\n\n| 图形 | □ | △ | ○ |\n| ---- | -- | -- | -- |\n| 个数/个 | | | |\n\n(2) 把上面的卡片按字母分一分.\n\n| 字母 | A | B | C |\n| ---- | - | - | - |\n| 个数/个 | | | |", + "options": [], + "answer": "3;3;3 2;4;3", + "solution": "【分析】(1)根据正方形,三角形及圆形的特征分别数一数各有几个,即可解决。正方形是正正方方的,由4条边围成,且4条边都一样长;三角形由3条直直的线首尾依次连接而成的封闭图形;圆形由一条曲线围成。(2) 根据字母的不同,分别数一数各有几个,即可解决.\n【详解】(1) 按图形分:\n\n| 图形 | □ | △ | ○ |\n| ---- | -- | -- | -- |\n| 个数/个 | 3 | 3 | 3 |\n\n(2) 按字母分:\n\n| 字母 | A | B | C |\n| ---- | - | - | - |\n| 个数/个 | 2 | 4 | 3 |", + "knowledge_points": [ + "数据的搜集与整理", + "按不同标准分类(单次)", + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "23-24一年级下·广东汕头·期末" + }, + { + "id": "90", + "unit": "第三单元分类与整理", + "question_type": "解答题", + "difficulty": 0.65, + "question": "一(1)班同学最喜欢的水果的情况如下图.\n\n![](images/ba79f29175b4072274585cf241dda7bfe2f194a2ab79fcbd1ad28bccffff8588.jpg)\n\n(1) 根据上图填写下表.\n\n| 水果 | 苹果 | 草莓 | 菠萝 | 西瓜 | 香蕉 |\n| ---- | ---- | ---- | ---- | ---- | ---- |\n| 人数 | | | | | |\n\n(2) 最喜欢 ( ) 的同学最多,最喜欢 ( ) 的同学最少。 \n(3) 最喜欢( )和( )的同学同样多。 \n(4) 最喜欢西瓜的同学比最喜欢苹果的同学多( )个。", + "options": [], + "answer": "3;8;4;12;4 西瓜;苹果 菠萝;香蕉 9", + "solution": "【分析】(1)数一数,依次有3人,8人,4人,12人,4人,据此填空。(2)(3) 将人数作比较即可求解。(4) 用最喜欢西瓜的人数减最喜欢苹果的人数即可求解.\n【详解】(1) 填表如下:\n\n| 水果 | 苹果 | 草莓 | 菠萝 | 西瓜 | 香蕉 |\n| ---- | ---- | ---- | ---- | ---- | ---- |\n| 人数 | 3 | 8 | 4 | 12 | 4 |\n\n(2) 12 > 8 > 4 = 4 > 3 最喜欢西瓜的同学最多,最喜欢苹果的同学最少.\n(3) 4 = 4 最喜欢菠萝和香蕉的同学同样多.\n(4) 12 - 3 = 9 (人),最喜欢西瓜的同学比最喜欢苹果的同学多9个。", + "knowledge_points": [ + "数据的搜集与整理" + ], + "source": "23-24一年级下·山西阳泉·期末" + }, + { + "id": "91", + "unit": "第三单元分类与整理", + "question_type": "解答题", + "difficulty": 0.65, + "question": "数一数,填一填.\n\n![](images/a9f5e5b0b788ebdde00bd4dd11a538f4333b9432985883e262369996f7f9082b.jpg)\n\n(1) 填表.\n\n| | 三角形 | 正方形 | 长方形 | 平行四边形 | 圆 |\n| ---- | ------ | ------ | ------ | ---------- | -- |\n| 数量 | ()个 | ()个 | ()个 | ()个 | ()个 |\n\n(2) ( ) 的个数最多, ( ) 的个数最少。 \n(3) 一共有()个平面图形。", + "options": [], + "answer": "7;2;5;1;5 三角形;平行四边形 20", + "solution": "【分析】长方形是四个角相等的四边形;四条边都相等,四个角都相等的四边形是正方形;圆是由一条曲线组成的圈,圆圆的;三角形是由同一平面内不在同一直线上的三条线段\"首尾\"顺次连接所组成的封闭图形;平行四边形两组相对的边分别平行。据此数一数。(2) 比较数量大小;(3) 将每种图形的数量相加即可求解.\n【详解】(1) 填表如下:\n\n| | 三角形 | 正方形 | 长方形 | 平行四边形 | 圆 |\n| ---- | ------ | ------ | ------ | ---------- | -- |\n| 数量 | 7个 | 2个 | 5个 | 1个 | 5个 |\n\n(2) 7 > 5 = 5 > 2 > 1,三角形的个数最多,平行四边形的个数最少.\n(3) 7 + 2 + 5 + 1 + 5 = 20 (个),一共有20个平面图形。", + "knowledge_points": [ + "7 以内数的比大小", + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "23-24一年级下·浙江宁波·期末" + }, + { + "id": "92", + "unit": "第三单元分类与整理", + "question_type": "解答题", + "difficulty": 0.65, + "question": "数一数每种图形各有多少个。\n\n![](images/ba9a95ca535f8cc4ccded1eb9533c477541267c27f72b9fb48c2214ce23556df.jpg)\n\n(1) 填表.\n\n| 形状 | 圆 | 正方形 | 长方形 | 平行四边形 | 三角形 |\n| ---- | -- | ------ | ------ | ---------- | ------ |\n| 个数 | | | | | |\n\n(2) 按颜色给这些图形分类.\n\n| 颜色 | 黑色 | 白色 |\n| ---- | ---- | ---- |\n| 个数 | | |\n\n(3) 摆3个![](images/650e3c8154fa00a5a9e4ac23f76455c6.png)用了()个圆。", + "options": [], + "answer": "6;3;2;2;3 8;8 18", + "solution": "【分析】(1)依据对平面图形长方形,正方形,三角形,圆形,平行四边形的认识,先数一数,再填空。当多种图形在一起,数其中某种图形的个数时,要按一定的顺序边数边做标记,避免重数或漏数;(2)分别数出黑色图形和白色图形的个数填表即可。 (3)图中一个![](images/f17ca84cab7b9ddd21c2db3b8992887a206d45620220019bebfae4aa0eb47424.jpg)含6个圆,3个这样的图形用圆的总数为3个6的和.\n【详解】(1) 按形状分:\n\n| 形状 | 圆 | 正方形 | 长方形 | 平行四边形 | 三角形 |\n| ---- | -- | ------ | ------ | ---------- | ------ |\n| 个数 | 6 | 3 | 2 | 2 | 3 |\n\n(2) 按颜色分:\n\n| 颜色 | 黑色 | 白色 |\n| ---- | ---- | ---- |\n| 个数 | 8 | 8 |\n\n(3) 6 + 6 + 6 = 18 (个)。故摆3个![](images/f17ca84cab7b9ddd21c2db3b8992887a206d45620220019bebfae4aa0eb47424.jpg)用了18个圆。", + "knowledge_points": [ + "数据的搜集与整理", + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "23-24 一年级下·福建福州·期末" + }, + { + "id": "93", + "unit": "第三单元分类与整理", + "question_type": "解答题", + "difficulty": 0.65, + "question": "我会整理.\n\n![](images/af8f9423f7aff4ff20d5e7767ae19d28c34ed25dd7d8c698132ab5f7b0ad4971.jpg)\n\n(1) 数一数,完成下面的表格.\n\n| 图形 | 正方形 | 三角形 | 长方形 | 圆 | 平行四边形 |\n| ---- | ------ | ------ | ------ | -- | ---------- |\n| 个数 | | | | | |\n\n(2)()最多,()最少。 \n(3) 再增加()个正方形,就和长方形同样多了。 \n(4) 我还知道: ( )。", + "options": [], + "answer": "2;3;4;5;1 圆;平行四边形 1 见详解", + "solution": "【分析】(1)根据平面图形的特征,圆有一条曲线围成;三角形由3条线段围成;正方形四条边相等,四个角都是直角;长方形对边相等,四个角都是直角;平行四边形对边相等;由此数出各有多少个即可。(2) 将每种图形的个数比较即可解答;(3) 计算出长方形和正方形相差的个数,即可解答;(4) 答案不唯一,如:圆和平行四边形一共有 6 个.\n【详解】(1) 填表如下:\n\n| 图形 | 正方形 | 三角形 | 长方形 | 圆 | 平行四边形 |\n| ---- | ------ | ------ | ------ | -- | ---------- |\n| 个数 | 2 | 3 | 4 | 5 | 1 |\n\n(2) 5 > 4 > 3 > 2 > 1 圆最多,平行四边形最少.\n(3) 4 - 2 = 1 (个),再增加1个正方形,就和长方形同样多了.\n(4) 示例:圆和平行四边形一共有 5 + 1 = 6 个。", + "knowledge_points": [ + "10以内数的比大小", + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "23-24一年级下·浙江杭州·期末" + }, + { + "id": "94", + "unit": "第三单元分类与整理", + "question_type": "解答题", + "difficulty": 0.85, + "question": "数一数,填一填.\n\n![](images/5adbdac3f5e4ccf540c295e85c3bf1cbc93557ac20d471b3523a897a748e2c50.jpg)\n![](images/16cb70a9328c691bd7dccf369bc0d2c8bd1cbb7e6085558058cfe1c2d296e1aa.jpg)\n\n(1) 上面两幅图中共有()个正方形,()个长方形,()个圆,()个三角形,()个平行四边形。 \n(2) 上面的图形还可以怎么分。\n\n| | | |\n| ---- | ---- | ---- |\n| 个数 | | |", + "options": [], + "answer": "3;2;6;3;2 见详解", + "solution": "【分析】(1)长方形有四条边,四个角,对边一样长,正方形有四条边,四个角,四条边一样长,三角形有三条边,三个角,圆是曲线围成的图形,结合生活经验找出平行四边形,据此解答即可。 (2) 观察图上可知:图形的颜色有黑色和白色,所以还可以按照图形的颜色分为两类.\n【详解】(1) 上面两幅图中共有3个正方形,2个长方形,6个圆,3个三角形,2个平行四边形.\n(2) 还可按照颜色分为黑色和白色:\n\n| | 黑色 | 白色 |\n| ---- | ---- | ---- |\n| 个数 | 8 | 8 |", + "knowledge_points": [ + "按不同标准分类(单次)", + "平行四边形的初步认识", + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "22-23一年级下·河南许昌·期末" + }, + { + "id": "95", + "unit": "第三单元分类与整理", + "question_type": "解答题", + "difficulty": 0.65, + "question": "下面是 4 月中上旬的天气情况记录表.\n\n![](images/f79df7d9cbe4a619dd45a5f69812b92c.png)\n![](images/6b64c657dd8bed30b14aeca0306e67ec.png)\n\n(1) 填空:晴天()天,阴天()天,雨天()天.\n(2) 晴天比阴天多( )天.\n(3) 雨天比晴天少( )天。", + "options": [], + "answer": "12;5;3 7;9", + "solution": "【分析】(1)分别数出晴天,阴天,雨天的数量,然后填入表中即可。注意边数边做记号,避免漏数和重复数。(2) 根据 (1) 中的数据用晴天的天数减阴天的天数即可得出晴天比阴天多几天。 (3) 根据 (1) 中的数据用晴天的天数减雨天的天数即可得出雨天比晴天少几天.\n【详解】(1) 根据分析填表如下:\n\n| 天气 | 晴 | 阴 | 雨 |\n| ---- | -- | -- | -- |\n| 天数 | 12 | 5 | 3 |\n\n(2) 12 - 5 = 7 (天)。答:晴天比阴天多7天.\n(3) 12 - 3 = 9 (天)。答:雨天比晴天少9天。", + "knowledge_points": [ + "十几减 5 ~ 2 的退位减法", + "数据的搜集与整理" + ], + "source": "23-24 一年级下·全国·假期作业" + }, + { + "id": "96", + "unit": "第三单元分类与整理", + "question_type": "解答题", + "difficulty": 0.65, + "question": "一 (2) 班同学喜欢吃的水果情况如图所示.\n\n![](images/0047d269e9b70e636d98f42432c568b31f79609e604ebbb129af7171b56bbece.jpg)\n\n(1) 根据上图填写下表.\n\n| 水果 | 苹果 | 梨 | 西瓜 | 草莓 |\n| ---- | ---- | -- | ---- | ---- |\n| 人数 | | | | |\n\n(2) 喜欢吃()的人数最多,喜欢吃()的人数最少。 \n(3) 喜欢吃()和()的人数一样多。", + "options": [], + "answer": "5;3;5;8 草莓;梨 苹果;西瓜", + "solution": "【分析】(1)分别数出喜欢各种水果的人的数量,注意边数边标记,不要漏数和重复数。(2) 根据 (1) 中的数据比较大小得出结论即可。 (3) 根据 (1) 中的数据得出结论即可.\n【详解】(1) 填表如下:\n\n| 水果 | 苹果 | 梨 | 西瓜 | 草莓 |\n| ---- | ---- | -- | ---- | ---- |\n| 人数 | 5 | 3 | 5 | 8 |\n\n(2) 3 < 5 < 8 故喜欢吃草莓的人数最多,喜欢吃梨的人数最少.\n(3) 5 = 5 故喜欢吃苹果和西瓜的人数一样多。", + "knowledge_points": [ + "数据的搜集与整理" + ], + "source": "23-24一年级下·全国·假期作业" + }, + { + "id": "97", + "unit": "第三单元分类与整理", + "question_type": "解答题", + "difficulty": 0.65, + "question": "分类整理.\n\n![](images/ccee54d057fbc47ed92d36ee66c235805dab3b90548c238f15051b8bc071bf29.jpg)\n\n(1) 我能把各种图形按颜色整理一下.\n\n| 颜色 | 黑色 | 白色 | 灰色 |\n| ---- | ---- | ---- | ---- |\n| 个数 | () | () | () |\n\n(2) 我还可以按图形的形状整理上面的图形.\n\n| 图形 | 长方形 | 正方形 | 三角形 | 平行四边形 | 圆 |\n| ------ | ------ | ------ | ------ | ---------- | -- |\n| 个数 | () | () | () | () | () |\n\n(3) ()(填颜色)的图形个数最少。 ()(填形状)的图形个数最多。 \n(4) 三角形比圆多()个。 \n(5) 一共有 ()个图形。", + "options": [], + "answer": "3;7;6 5;3;4;2;2 黑色;长方形 2 16", + "solution": "【分析】(1)按照颜色分成3类,黑色3个,白色7个,灰色6个。(2) 按图形的形状分成5类,长方形5个,正方形3个,三角形4个,平行四边形2个,圆2个。 (3) 把各种分类方法中,各自的数量比较大小。 (4) 三角形比圆多的个数 = 三角形的个数 - 圆的个数。(5) 一共有图形的个数 = 三种颜色图形的数量相加.\n【详解】(1) 按颜色整理:\n\n| 颜色 | 黑色 | 白色 | 灰色 |\n| ---- | ---- | ---- | ---- |\n| 个数 | 3 | 7 | 6 |\n\n(2) 按形状整理:\n\n| 图形 | 长方形 | 正方形 | 三角形 | 平行四边形 | 圆 |\n| ------ | ------ | ------ | ------ | ---------- | -- |\n| 个数 | 5 | 3 | 4 | 2 | 2 |\n\n(3) 7 > 6 > 3,因此黑色的图形个数最少;5 > 4 > 3 > 2,长方形的图形个数最多.\n(4) 4 - 2 = 2 (个),三角形比圆多2个.\n(5) 3 + 7 + 6 = 16 (个)。一共有16个图形。", + "knowledge_points": [ + "数据的搜集与整理", + "7以内数的比大小", + "长方形,正方形,三角形和圆的初步认识", + "连加(20以内)" + ], + "source": "23-24 一年级下·河北保定·期中" + }, + { + "id": "98", + "unit": "第三单元分类与整理", + "question_type": "解答题", + "difficulty": 0.85, + "question": "![](images/9faf374682951c749809a0f41c937c952f8a52baf855570d2131189f15a2e471.jpg)\n\n(1) 按水果种类分一分,填一填.\n\n| 水果种类 | 桃子 | 苹果 | 梨 |\n| -------- | ---- | ---- | -- |\n| 个数 | | | |\n\n(2) 按卡片形状分一分,填一填.\n\n| 形状 | 三角形 | 正方形 | 圆 |\n| ---- | ------ | ------ | -- |\n| 个数 | | | |\n\n(3) 一共有()个水果。", + "options": [], + "answer": "6;4;5 4;5;6 15", + "solution": "【分析】(1)依次数出各种水果的数量填空即可;(2) 三角形有 3 条直直的边;正方形有 4 条直直的边,每条边都相等;圆没有直直的边。由此按卡片形状数出数量填空即可;(3) 将水果的数量相加即可求出总数量.\n【详解】(1) 按水果种类分一分:\n\n| 水果种类 | 桃子 | 苹果 | 梨 |\n| -------- | ---- | ---- | -- |\n| 个数 | 6 | 4 | 5 |\n\n(2) 按卡片形状分一分:\n\n| 形状 | 三角形 | 正方形 | 圆 |\n| ---- | ------ | ------ | -- |\n| 个数 | 4 | 5 | 6 |\n\n(3) 6 + 4 + 5 = 15 (个)。一共有15个水果。", + "knowledge_points": [ + "按不同标准分类(单次)", + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "23-24 一年级下·四川乐山·期中" + }, + { + "id": "99", + "unit": "第三单元分类与整理", + "question_type": "解答题", + "difficulty": 0.85, + "question": "给铅笔分类.\n\n![](images/c1545e8d325dbb93663dc282e7328c90490cacc67c9420f09a0423ec2d78d00e.jpg)\n\n(1) 按有无橡皮分.\n\n| 有无橡皮 | 有橡皮 | 无橡皮 |\n| -------- | ------ | ------ |\n| 支数 | | |\n\n(2) 如果把这些铅笔分成三组可以怎样分。 把分组的结果表示出来(按颜色).\n\n![](images/5960ecfc3d19af0f54ca0a30d11c0304.png)\n\n(3) 根据上面的信息,你能提出什么数学问题并解答。", + "options": [], + "answer": "4;11 见详解 见详解", + "solution": "【分析】(1)根据图中给出的图片,按有无橡皮分别数一数各有几支即可。(2) 按颜色的不同,这些铅笔分成三组,分别是白色,灰色和粉色;然后根据颜色的不同,分别数一数各有几支并填空。 (3) 根据已知条件提问题,合理即可,答案不唯一.\n【详解】(1)\n\n| 有无橡皮 | 有橡皮 | 无橡皮 |\n| -------- | ------ | ------ |\n| 支数 | 4 | 11 |\n\n(2) 可按颜色分组(示意):\n\n| 颜色 | 白色 | 灰色 | 粉色 |\n| ---- | ---- | ---- | ---- |\n| 支数 | 3 | 5 | 7 |\n\n(3) 示例问题:有橡皮的铅笔比无橡皮的铅笔少多少支。\n解:11 - 4 = 7 (支)。答:有橡皮的铅笔比无橡皮的铅笔少7支。(问题不唯一。)", + "knowledge_points": [ + "十几减 5~2 的退位减法", + "数据的搜集与整理", + "单式统计表的特点及填补", + "\"提问题\" \"填条件\" 问题" + ], + "source": "23-24 一年级下·全国·课后作业" + }, + { + "id": "100", + "unit": "第三单元分类与整理", + "question_type": "解答题", + "difficulty": 0.65, + "question": "按图形的种类分一分,数一数,涂一涂.\n\n![](images/58c99f97b19b24d2ce10066bd60b368c61bf6d1c72caeeb2971336e069b035af.jpg)\n\n□有()个,○有()个,▭有()个,△有()个.\n\n(1) ( ) 最多, ( ) 最少。 \n(2) △比○多几个。 \n(3) 请你提出一个问题,根据你的问题列出算式。", + "options": [], + "answer": "2;5;3;6 三角形;正方形 1个 见详解", + "solution": "【分析】长方形和正方形都有四条边,四个角都是直角,正方形四条边相等,圆形是一条曲线围成的,三角形是由三条边,三个角组成,据此数清楚各种图形的数量。(1) 将数出的图形的数量进行比较大小,据此即可得出答案。 (2) 用三角形的数量减去圆形的数量,即可得出答案。 (3) 根据题干的数学信息,结合学过的数学知识,提出问题并解答即可,本小题答案不唯一.\n【详解】从图上可得:□有2个,○有5个,▭有3个,△有6个.\n(1) 6 > 5 > 3 > 2,所以三角形最多,正方形最少.\n(2) 6 - 5 = 1 (个),△比○多1个.\n(3) 示例:长方形和三角形一共多少个。 3 + 6 = 9 (个)。答:长方形和三角形一共9个。(本小题答案不唯一。)", + "knowledge_points": [ + "10以内数的比大小", + "数据的搜集与整理", + "\"提问题\"\"填条件\"问题", + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "22-23一年级·全国·假期作业" + }, + { + "id": "101", + "unit": "第三单元分类与整理", + "question_type": "选择题", + "difficulty": 0.65, + "question": "下面的物体,哪个不是同一类的 ( )。", + "options": [ + "A. ![](images/0728df66dde1f430fbe30eab530ffbbbf6dd5547e8099d474af75829bddd17b1.jpg)", + "B. ![](images/5b288a46886ee643bf5c153a12d34c474f8ec1664840c3b5364e668e2342f036.jpg)", + "C. ![](images/e0034f107857829ace3eb565f32ee0bc59a4eb4ef93e1b304e5c718672373605.jpg)" + ], + "answer": "B", + "solution": "【分析】根据生活经验可知:苹果和西瓜是水果,青菜是蔬菜,据此解答。本题主要考查了物体的比较与分类,需要学生具有一定的生活常识.\n【详解】苹果和西瓜是水果,青菜是蔬菜,所以 B 和其他的不是同一类。故答案为: B", + "knowledge_points": [ + "按不同标准分类(单次)" + ], + "source": "22-23一年级下·全国·单元测试" + }, + { + "id": "102", + "unit": "第三单元分类与整理", + "question_type": "选择题", + "difficulty": 0.65, + "question": "下面说法中错误的一项是 ( )。", + "options": [ + "A. 统计的数据比较多时,可以先分小组统计,再汇总", + "B. 把数据按照不同的标准分类,一般会得到不同的结果", + "C. 调查的对象不同,得到的结果一定不同" + ], + "answer": "C", + "solution": "【分析】根据我们平时统计数据的方法,结合选项进行分析解答即可。此题是考查统计数据的方法,根据题意分析解答即可.\n【详解】A. 统计的数据比较多时,可以先分小组统计,再汇总。说法正确。B. 把数据按照不同的标准分类,一般会得到不同的结果。说法正确。C. 调查的对象不同,得到的结果可能会相同。选项说法错误。故答案为: C", + "knowledge_points": [ + "数据的搜集与整理", + "按不同标准分类(单次)" + ], + "source": "21-22 二年级下·江苏·单元测试" + }, + { + "id": "103", + "unit": "第三单元分类与整理", + "question_type": "选择题", + "difficulty": 0.65, + "question": "下图中不是同类的是 ( )。", + "options": [ + "A. ![](images/c5323bd0c84976a576f2438f7a606c44f495bf8552ea171ac29c954e6cbe5a97.jpg)", + "B. ![](images/dd2d463ac19710fdb89924d5f01d400a0484cabf1b46f5dfad89fb757719dc68.jpg)", + "C. ![](images/c37bbc9d72412288e7f616014e092ea3d92867e30ce386f8158e565feba07178.jpg)" + ], + "answer": "A", + "solution": "【分析】根据生活经验可知:墨水和笔属于学习用品,帽子属于服饰。据此做题。本题主要考查物体的分类,关键是利用生活常识做题.\n【详解】墨水和笔属于学习用品,帽子属于服饰。故答案为: A", + "knowledge_points": [ + "按不同标准分类(单次)" + ], + "source": "22-23 一年级下·全国·单元测试" + }, + { + "id": "104", + "unit": "第三单元分类与整理", + "question_type": "选择题", + "difficulty": 0.85, + "question": "下列图形中, ( )和其他两个不是同一类。", + "options": [ + "A. 正方体", + "B. 平行四边形", + "C. 三角形" + ], + "answer": "A", + "solution": "【分析】正方体是立体图形,平行四边形和三角形是平面图形,据此解答.\n【详解】根据分析可知: A. 正方体是立体图形;B. 平行四边形是平面图形;C. 三角形是平面图形;A 项和其他两项不同。故答案为: A\n[点睛]本题主要考查了分类与整理。", + "knowledge_points": [ + "立体图形的认识", + "按不同标准分类(单次)" + ], + "source": "22-23 一年级下·全国·单元测试" + }, + { + "id": "105", + "unit": "第三单元分类与整理", + "question_type": "选择题", + "difficulty": 0.94, + "question": "下列选项中是学习用品的是 ( )。", + "options": [ + "A. ![](images/47104ca30a4392d4185e826fb2778c084e468a4a073ba0d66e4e874eefc50b7d.jpg)", + "B. ![](images/a0bb40b73243f76b327e311c1b52d80f5e61b800c2c9d3548e74be6eec63a791.jpg)", + "C. ![](images/633f61cdddd256ca906ae906357e1220a8ee0a66141495e8008311c7ee36a9d6.jpg)" + ], + "answer": "C", + "solution": "【分析】根据日常生活中的分类找出学习用品即可解答。本题主要考查了分类与整理.\n【详解】A. 是小乌龟,是动物,不符合题意;B. 是帽子,是服装类,不符合题意;C. 是钢笔,是学习用品,符合题意;学习用品只有钢笔,故答案为: C", + "knowledge_points": [ + "按不同标准分类(单次)" + ], + "source": "22-23 一年级下·全国·单元测试" + }, + { + "id": "106", + "unit": "第三单元分类与整理", + "question_type": "选择题", + "difficulty": 0.65, + "question": "按颜色分:( )为一类;按形状分:( )分为一类。", + "options": [ + "A. ③⑤⑧,②⑥⑦", + "B. ②⑥⑦,①③", + "C. ①③⑥,③⑤⑧" + ], + "answer": "C", + "solution": "【分析】从图上可得按颜色分,可分为白色和黑色;再根据对平面图形特点的认识,进行分类即可。据此结合选项进行解答即可。本题考查学生对平面图形分类的掌握和运用.\n【详解】按颜色分:①③⑥是黑色,为一类;②④⑤⑦⑧是白色,为一类;按形状分:①是圆形;②④⑦是正方形;③⑤⑧是三角形;⑥是平行四边形。所以,按颜色分:①③⑥为一类;按形状分:③⑤⑧分为一类。故答案为: C", + "knowledge_points": [ + "按不同标准分类(单次)", + "长方形,正方形,三角形和圆的初步认识", + "平行四边形的初步认识" + ], + "source": "22-23 一年级下·全国·单元测试" + }, + { + "id": "107", + "unit": "第三单元分类与整理", + "question_type": "选择题", + "difficulty": 0.65, + "question": "下面不是同一类的是 ( )。", + "options": [ + "A. ![](images/10fa187d1b398faac0df295ceb1753bc911c1d22cf771aa2b46b2af0faaa57c1.jpg)", + "B. ![](images/7a5e673d03fb7aaac85c50e328a6281375207eb00dcf766e16ab6b58713e635b.jpg)", + "C. ![](images/82aa0abbc3a5243866bde8aed440410efcf009d3e1ee705fbac5b8bd8ccd61ee.jpg)" + ], + "answer": "C", + "solution": "【分析】根据不同的动物的生活习性进行分类,蝴蝶和蜻蜓都是昆虫都会飞,小鸡不是昆虫。据此解答即可。此题考查的目的是理解掌握物体的比较,分类的方法及应用.\n【详解】由分析得:不是同一类的是小鸡。故答案为: C", + "knowledge_points": [ + "按不同标准分类(单次)" + ], + "source": "22-23 一年级下·全国·单元测试" + }, + { + "id": "108", + "unit": "第三单元分类与整理", + "question_type": "选择题", + "difficulty": 0.65, + "question": "不同类的一个是 ( )。", + "options": [ + "A. 篮球", + "B. 排球", + "C. 苹果" + ], + "answer": "C", + "solution": "【分析】根据对物体分类的认识可知:篮球,排球,足球都属于球类,而苹果属于水果,所以不同类的一个是苹果。本题主要考查了对物体的分类,在平时要注意积累.\n【详解】根据分析得:不同类的一个是苹果。故答案为: C", + "knowledge_points": [ + "按不同标准分类(单次)" + ], + "source": "22-23 一年级下·全国·单元测试" + }, + { + "id": "109", + "unit": "第三单元分类与整理", + "question_type": "选择题", + "difficulty": 0.85, + "question": "下列图形不是同类的是 ( )。", + "options": [ + "A. ![](images/135d02d73650b583f98bd91c3977cd5f.png)", + "B. ![](images/b2ae3eec4c7df5bb334ed6efa1c9fdd6.png)", + "C. ![](images/e9435a13f39492a025bda41b2ed1bf88.png)" + ], + "answer": "B", + "solution": "【分析】根据分类的方法,结合平面图形和立体图形的概念选择即可。本题主要考查了立体图形和平面图形的识别,解题的关键是分清平面图形与立体图形.\n【详解】A. ![](images/135d02d73650b583f98bd91c3977cd5f.png) 是正方形,是平面图形;B. ![](images/b2ae3eec4c7df5bb334ed6efa1c9fdd6.png)是正方体,是立体图形;C. ![](images/e9435a13f39492a025bda41b2ed1bf88.png) 是长方形,是平面图形;故答案为: B", + "knowledge_points": [ + "立体图形的认识", + "按不同标准分类(单次)", + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "21-22 一年级下·湖南怀化·期末" + }, + { + "id": "110", + "unit": "第三单元分类与整理", + "question_type": "选择题", + "difficulty": 0.65, + "question": "下图中不是同类的是( )。", + "options": [ + "A. ![](images/9342a243e0306570561d10eb61f5232beea1612edd7177d7c00118cbea694129.jpg)", + "B. ![](images/9ee646a63601842cd2c3eae660eece1fb693e2a4992c631b9a7eb8de0e500637.jpg)", + "C. ![](images/6eadfdf0e8567525e9a9d9d04e670e187a0e1b8177c46c36ba68ae675c6a7992.jpg)", + "D. ![](images/cd6111697b660b4a3a18aa24e4056f87e361c9d324abecf6ebb2fddad40a7981.jpg)" + ], + "answer": "A", + "solution": "【分析】选项可以分为学习用品和生活用品,依据生活的实际情况进行选择分类。本题主要考查物体的分类,关键是利用生活常识做题.\n【详解】文具盒,笔,墨水属于学习用品,帽子属于生活用品。故答案为: A", + "knowledge_points": [ + "按不同标准分类(单次)" + ], + "source": "21-22 一年级下·广东汕尾·期末" + }, + { + "id": "111", + "unit": "第三单元分类与整理", + "question_type": "选择题", + "difficulty": 0.65, + "question": "下列选项中是学习用品的是( )。", + "options": [ + "A. ![](images/8fcdac55b4e2b1819b447273289c762b203bd58bdb49331681184fc90c498742.jpg)", + "B. ![](images/2615cafe95eab5ee4183cfe5a8250cfa613c8a6d2ac3969aaee2777b7edee4c2.jpg)", + "C. ![](images/39eba56d9da2bcaa0c5c84db2653dfb569a332050f79c7775748be86b06da40d.jpg)", + "D. ![](images/7e4edcd3c2628981748f4b8286fbbc296c37f5cfc2a227c179e596f6fb418de0.jpg)" + ], + "answer": "C", + "solution": "【分析】根据生活常识可知,四个选项中,只有笔是学习用品,据此选择。解答本题的关键是熟练掌握生活常识.\n【详解】选项中是学习用品的是笔。故答案为: C", + "knowledge_points": [ + "按不同标准分类(单次)" + ], + "source": "20-21 一年级下·山东济宁·期末" + }, + { + "id": "112", + "unit": "第三单元分类与整理", + "question_type": "选择题", + "difficulty": 0.65, + "question": "( ) 是羽毛球。", + "options": [ + "A. ![](images/d70e343ec21b99b9225a92585346a9bc95601837b82b5344c3364e640046987a.jpg)", + "B. ![](images/5e383b254e23ee64c6fedea1fb07b04b1d34fb20898b2628a652a56004d83e7b.jpg)", + "C. ![](images/0d2d570b775de6f6c90a26984c07aae899fef243b264ef997310ba49bb30fbe0.jpg)" + ], + "answer": "C", + "solution": "【分析】联系实际生活来区分各种球类可以解题.\n【详解】A. 是橄榄球;B. 是篮球;C. 是羽毛球。故答案为: C\n[点睛]解答本题的关键是要联系生活,实际生活中多接触球类运动。", + "knowledge_points": [ + "按不同标准分类(单次)" + ], + "source": "22-23 一年级上·全国·课后作业" + }, + { + "id": "113", + "unit": "第三单元分类与整理", + "question_type": "选择题", + "difficulty": 0.65, + "question": "下面动物中,与其他几个不是同一类的是 ( )。", + "options": [ + "A. ![](images/79ac40a05a2e04d3430f81ee0acaacc7fb79b2c0be1d5df1f848c9e4286acad2.jpg)", + "B. ![](images/e393977576e4a76f8c22d80f27668eed0e9f8f054090715492b62416dfefabd7.jpg)", + "C. ![](images/19054578557487989c97556bc3bcd0a294d130f0629bcecb2660ac81589f21d0.jpg)", + "D. ![](images/cce11e6d90c5ed24da681115c97ef695c6066da4ec58cb6a47c711ecdca2aa2b.jpg)" + ], + "answer": "D", + "solution": "【分析】根据给出的选项里的动物所含有的特征进行解答即可。本题主要考查了物体的分类.\n【详解】A,B,C这三个选项的动物都是鸟类,D选项的动物是鱼类,鱼类与鸟类不一样。故答案为: D", + "knowledge_points": [ + "按不同标准分类(单次)" + ], + "source": "21-22 一年级下·河南南阳·期末" + }, + { + "id": "114", + "unit": "第三单元分类与整理", + "question_type": "选择题", + "difficulty": 0.85, + "question": "下面不是同一类的是 ( )。", + "options": [ + "A. ![](images/67f8ddb87d0a2c4bbc7f6ecc6a93a2ecdccd24131ca55e547b23232c3e31f560.jpg)", + "B. ![](images/41a4f89ec62c8f671c6bc8ba6ad15a3e1441926976613885ffc7a98ab0dd21ec.jpg)", + "C. ![](images/763eba17892939eb89c44b05cca17190f5cd8a8865733c1940e3d625aa7054c5.jpg)", + "D. ![](images/297b9c73550cab561bd72a89caf63b68e5f9f8e26d49dbeddc091bd78b8957e6.jpg)" + ], + "answer": "D", + "solution": "【分析】根据题意可将选项中的动物分成天空中飞行的,地上行走的两大类,然后再进行选择即可.\n【详解】A. ![](images/67f8ddb87d0a2c4bbc7f6ecc6a93a2ecdccd24131ca55e547b23232c3e31f560.jpg)是在天空中飞行的。B. ![](images/41a4f89ec62c8f671c6bc8ba6ad15a3e1441926976613885ffc7a98ab0dd21ec.jpg)是在天空中飞行的。C. ![](images/763eba17892939eb89c44b05cca17190f5cd8a8865733c1940e3d625aa7054c5.jpg)是在天空中飞行的。D. ![](images/297b9c73550cab561bd72a89caf63b68e5f9f8e26d49dbeddc091bd78b8957e6.jpg)是在地上行走的。由此可知,不是同一类的是![](images/297b9c73550cab561bd72a89caf63b68e5f9f8e26d49dbeddc091bd78b8957e6.jpg)故答案为: D\n[点睛]此题考查的是按不同标准将动物分类,应结合实际进行解答。", + "knowledge_points": [ + "按不同标准分类(单次)" + ], + "source": "20-21 一年级上·广西百色·期末" + }, + { + "id": "115", + "unit": "第三单元分类与整理", + "question_type": "选择题", + "difficulty": 0.65, + "question": "下列物品中不属于同类的是 ( )。", + "options": [ + "A. ![](images/4ced09b775450e60e6ca9cd9e51cff9924f8eb042d1a332a280f2d6e988e4e9e.jpg)", + "B. ![](images/f399e6a1eb5f5117733316fcc0e139a7b2a123a1e34595fc7ad2345444a06196.jpg)", + "C. ![](images/d95a7fccaa331e3e5ba10e8c3db4d211763464eead4183a81a90bfb4db39c3fc.jpg)" + ], + "answer": "B", + "solution": "【分析】三样物品,订书机和尺子都属于学习用品,布偶属于玩具,据此选择。物品的分类关键是确定标准.\n【详解】订书机,布偶和尺子,不属于同类的是布偶。故答案为: B", + "knowledge_points": [ + "按不同标准分类(单次)" + ], + "source": "20-21 一年级下·贵州六盘水·期中" + }, + { + "id": "116", + "unit": "第三单元分类与整理", + "question_type": "选择题", + "difficulty": 0.65, + "question": "下图中,与其他两个不同类的是 ( )。", + "options": [ + "A. ![](images/ffa29b00ddccf18699e4b2417da7f7866e86fbd1e6fbc5e6ab995f856f276eb7.jpg)", + "B. ![](images/d818211371239f92d9454187bd7b5a64fe6f3594ce1c945f946b150318e146c7.jpg)", + "C. ![](images/317ae3bd32004b420a05fffe95d977de125f778d75f56daf23eb41ffa95ab2e6.jpg)" + ], + "answer": "C", + "solution": "【分析】根据每个选项是立体图形还是平面图形进行分类。本题考查立体图形和平面图形的认识.\n【详解】A. 图形是正方体,属于立体图形。B. 图形是圆柱,属于立体图形。C. 图形是长方形,属于平面图形。故答案为: C", + "knowledge_points": [ + "立体图形的认识", + "按不同标准分类(单次)", + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "20-21 五年级下·山西阳泉·期末" + }, + { + "id": "117", + "unit": "第三单元分类与整理", + "question_type": "选择题", + "difficulty": 0.85, + "question": "下面小动物中,与其他几个不同类的是 ( )。", + "options": [ + "A. ![](images/d75fd080c51c15afb90ff0724136ff605bdfe3666667e1b96dc90bd8ec36900c.jpg)", + "B. ![](images/b978657862fcae484607183343f9664a5b31e3b6d29241dc064d50e2fb1e5178.jpg)", + "C. ![](images/46defaccb9e0054c25bd701f625107c86ff6a6a3a807d70f50d3eb015be7472b.jpg)" + ], + "answer": "B", + "solution": "【分析】根据动物能否飞行,我们将动物分为会飞的和不会飞的。以此为分类标准,将题中的动物进行分类,即可解答。本题主要考查按照不同的标准进行分类,属于基础知识,要熟练掌握.\n【详解】A. 兔子不会飞;B. 燕子会飞;C. 大熊猫不会飞。所以三种动物中,与其他两个不同类的是 B 。故答案为: B", + "knowledge_points": [ + "按不同标准分类(单次)" + ], + "source": "20-21 一年级下·湖北荆门·期末" + }, + { + "id": "118", + "unit": "第三单元分类与整理", + "question_type": "选择题", + "difficulty": 0.85, + "question": "下面物体中, ( )是不同类的一项。", + "options": [ + "A. ![](images/934cb150064a238fcfdfdacfdac7102b64cd1b94e5699b1ca2bda219b9f0fdea.jpg)", + "B. ![](images/bbc0daeeecfc9e64a744f7d52a6cb8b61fa9ea25eab6f7b7e62340febc9e7343.jpg)", + "C. ![](images/1786ca33f1dfe2caab44302d55b67be5c74aa935ac6c508e1356b9b86288dc68.jpg)" + ], + "answer": "C", + "solution": "【分析】由题意可知,网球拍与乒乓球拍都是用来打球的,而鞋子是用来走路的,据此解答即可。联系生活实际,应灵活的选择.\n【详解】由分析可得:鞋子和乒乓球拍,网球拍不是同类项。故答案为: C", + "knowledge_points": [ + "按不同标准分类(单次)" + ], + "source": "18-19一年级下·浙江宁波·期末" + }, + { + "id": "119", + "unit": "第三单元分类与整理", + "question_type": "选择题", + "difficulty": 0.65, + "question": "下列图形中, ( )和其他三个不是同一类。", + "options": [ + "A. 正方体", + "B. 平行四边形", + "C. 三角形", + "D. 正方形" + ], + "answer": "A", + "solution": "【分析】平行四边形,三角形,正方形都是平面图形,只有正方体是立体图形.\n【详解】平行四边形,三角形,正方形都是平面图形,只有正方体是立体图形,所以正方体和其他三个不是同一类。故答案为: A", + "knowledge_points": [ + "按不同标准分类(单次)" + ], + "source": "18-19 一年级下·浙江宁波·期末" + }, + { + "id": "120", + "unit": "第三单元分类与整理", + "question_type": "选择题", + "difficulty": 0.85, + "question": "鸡,羊,鸭,鹅四种动物中,其中不同类的是 ( )。", + "options": [ + "A. 羊", + "B. 鸭", + "C. 鹅" + ], + "answer": "A", + "solution": "【分析】鸡、鸭、鹅是禽类,羊是家畜,与其它三种不是同一类.\n【详解】鸡、鸭、鹅是禽类,羊是家畜,其中不同类的是羊。故答案为: A", + "knowledge_points": [ + "按不同标准分类(单次)" + ], + "source": "18-19 一年级下·浙江宁波·期末" + }, + { + "id": "121", + "unit": "第三单元分类与整理", + "question_type": "选择题", + "difficulty": 0.65, + "question": "下面物体中与其它不是同一类的是 ( )。", + "options": [ + "A. ![](images/487b545ac30e2058695b49c22357af29736c87831e6510605398ffc5324b41e7.jpg)", + "B. ![](images/db059586a6bca206a88a343f48743b454353eaef5c11df9010b8cf0017c429ac.jpg)", + "C. ![](images/c8fe9d4b79bc15b83c456ef793c58e66036df8c272a0c4fe1a2809d3f38941e0.jpg)" + ], + "answer": "B", + "solution": "【分析】可从是否为蔬菜类进行辨别,做出选择.\n【详解】A. 苹果是水果,不是蔬菜;B. 辣椒是蔬菜;C. 西瓜是水果,不是蔬菜。故答案为: B", + "knowledge_points": [ + "按不同标准分类(单次)" + ], + "source": "18-19 一年级下·广西玉林·期末" + }, + { + "id": "122", + "unit": "第三单元分类与整理", + "question_type": "选择题", + "difficulty": 0.85, + "question": "下图中,按物品的种类可以分成 ( ) 种。", + "options": [ + "A. 2", + "B. 3", + "C. 4" + ], + "answer": "A", + "solution": "【分析】图中物品可按种类分成蔬菜类和水果类.\n【详解】![](images/ba9a687480454c3b56defbadce049ed7.png)属于蔬菜类;![](images/6308f8bf5ea76eac892cf03361aec66d.png)都属于水果类,所以以上物品按种类分可以分成 2 种。故答案为: A", + "knowledge_points": [ + "按不同标准分类(单次)" + ], + "source": "20-21 一年级下·广西南宁·期中" + }, + { + "id": "123", + "unit": "第三单元分类与整理", + "question_type": "选择题", + "difficulty": 0.85, + "question": "下图中,不同类的是 ( )。", + "options": [ + "A. ![](images/f39de6f845386633d9c19a7c62550467a9eb1b27ac526655125dc1bbe233fba4.jpg)", + "B. ![](images/f8afbeeb4447a7efef479c24626b76521a93aefde1fd4cd7e7e35215e8f7385d.jpg)", + "C. ![](images/869e290461f5e7d4ee6c8acdee36365ebb7c0ccaa23863309185f1e255ddc3a5.jpg)", + "D. ![](images/0e5142b4418e7daec0e2397e5f62fa04a8da87e1903975f37a0f4eca4b42ab00.jpg)" + ], + "answer": "C", + "solution": "【分析】略", + "knowledge_points": [ + "按不同标准分类(单次)" + ], + "source": "19-20 一年级下·广西南宁·期末" + }, + { + "id": "124", + "unit": "第三单元分类与整理", + "question_type": "选择题", + "difficulty": 0.85, + "question": "下面的物品中与![](images/4624adcaeeff96ef9ae84dbb50f03cb8b959c87c19044f2e7ba70607b0dda9bc.jpg)不同类的是 ( )。", + "options": [ + "A. ![](images/b7488987bbdc1f75d03975194db45caa1b7f11bc7b111ce24536fa5ad4d560e5.jpg)", + "B. ![](images/77331dbf469db1b6e9abac5d686d3c157cad18b2f2c06808bac2b88c532e132b.jpg)", + "C. ![](images/f921fecfbb75b9d69bf2eac2e12b1c1e269b2bcecba3921d7bd8325274512f57.jpg)" + ], + "answer": "C", + "solution": "【分析】铅笔属于学习用品,笔袋和书包都是学习用品,木马属于玩具,据此找出不同类的即可。本题主要考查了分类的知识点.\n【详解】下面的物品中与![](images/5b1107d726d14f62dad2c3dd9534094b8eb129e88b7ad90a1efea617ddb4ddd7.jpg)不同类的是![](images/cea2f4adabf8a16e002eeb835ad84ce4f7ddd18974a7c564e40d1bf9c7099fca.jpg)故答案为: C", + "knowledge_points": [ + "按不同标准分类(单次)" + ], + "source": "18-19 一年级下·广西南宁·期末" + }, + { + "id": "125", + "unit": "第三单元分类与整理", + "question_type": "选择题", + "difficulty": 0.94, + "question": "下列动物中,与其他几个不是同一类的是 ( )。", + "options": [ + "A. ![](images/70dac1a2b92957967233392146444409ecdbe4f331fedb5aba4e9d5b9105793b.jpg)", + "B. ![](images/731011f68e130ad5f0ea6bacb893791dd5d349a00d5d86fd9f7fcbc8f2218637.jpg)", + "C. ![](images/b7f7b9fa2fcff80f9a97e44bbabcdf5904544461eca550a06ab94f001ac24db3.jpg)" + ], + "answer": "A", + "solution": "【分析】略", + "knowledge_points": [ + "按不同标准分类(单次)" + ], + "source": "19-20 一年级下·青海海东·期末" + }, + { + "id": "126", + "unit": "第三单元分类与整理", + "question_type": "选择题", + "difficulty": 0.85, + "question": "按颜色分:( )为一类;按形状分:( )分为一类。", + "options": [ + "A. ③⑤⑧,②⑥⑦", + "B. ②⑥⑦,①③", + "C. ①③⑥,③⑤⑧" + ], + "answer": "C", + "solution": "【详解】按颜色分:①③⑥是黑色,为一类;②④⑤⑦⑧是白色,为一类;按形状分:①是圆形;②④⑦是正方形;③⑤⑧是三角形;⑥是平行四边形。所以,按颜色分: ①③⑥为一类;按形状分: ③⑤⑧分为一类。故答案为: C", + "knowledge_points": [ + "按不同标准分类(单次)" + ], + "source": "18-19 一年级下·江西南昌·期末" + }, + { + "id": "127", + "unit": "第三单元分类与整理", + "question_type": "选择题", + "difficulty": 0.65, + "question": "下列物体中,与其他两个不同类的一项是 ( )。", + "options": [ + "A. ![](images/acf3ad6360f9b2c763b356c3178376460067970f553db5a443dc7a8ee4b4ebe1.jpg)", + "B. ![](images/f88865de0aa6791d896285cc5d8aa9f0c6731b7f8fbdf99ed795de4db0059ac2.jpg)", + "C. ![](images/88023882d0c4884a5def8a6cd516bd5598441f3d06924285f16723244df12943.jpg)" + ], + "answer": "B", + "solution": "【分析】A项和C项中的物品都是文具,而B项中的物品是交通工具.\n【详解】B项中的物品与其他两个不同类。故答案为: B", + "knowledge_points": [ + "按不同标准分类(单次)" + ], + "source": "19-20 一年级上·辽宁·期末" + }, + { + "id": "128", + "unit": "第三单元分类与整理", + "question_type": "选择题", + "difficulty": 0.85, + "question": "有 4 只动物:牛,羊,马,鸟。其中与其他三只不同类的是 ( )。", + "options": [ + "A. 羊", + "B. 马", + "C. 鸟" + ], + "answer": "C", + "solution": "【分析】牛、羊、马在陆地上生活,鸟会飞.\n【详解】在牛,羊,马,鸟这 4 只动物中,牛,羊,马,都没有翅膀,在陆地上生活;而鸟有翅膀,可以飞翔在天空中,所以与其他三只不同类的是鸟。故答案为: C", + "knowledge_points": [ + "按不同标准分类(单次)" + ], + "source": "20-21 一年级下·全国·期末" + }, + { + "id": "129", + "unit": "第三单元分类与整理", + "question_type": "选择题", + "difficulty": 0.65, + "question": "下面物体中与其他两个不是同一类的是 ( )。", + "options": [ + "A. ![](images/b890d588df5c5b075cc2229b7056678e5c53375765e70704d668db0870d62540.jpg)", + "B. ![](images/fab25ba8e03e543b54321d5860425da9a5c0efecc9c046334dd72d2e133a40a0.jpg)", + "C. ![](images/3165980942d60505479e58bee17286ac503f00a328aeb749cbf4c9c8bd26905e.jpg)" + ], + "answer": "B", + "solution": "【分析】略", + "knowledge_points": [ + "按不同标准分类(单次)" + ], + "source": "19-20 一年级下·山东菏泽·期末" + }, + { + "id": "130", + "unit": "第三单元分类与整理", + "question_type": "选择题", + "difficulty": 0.65, + "question": "下图中不同类的是 ( )。", + "options": [ + "A. ![](images/135d02d73650b583f98bd91c3977cd5f.png)", + "B. ![](images/e9435a13f39492a025bda41b2ed1bf88.png)", + "C. ![](images/280d34e6e44ec17ddad2153e2cc85080.png)" + ], + "answer": "C", + "solution": "【分析】略", + "knowledge_points": [ + "立体图形的认识", + "按不同标准分类(单次)", + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "19-20 一年级下·全国·期末" + }, + { + "id": "131", + "unit": "第三单元分类与整理", + "question_type": "选择题", + "difficulty": 0.65, + "question": "下面说法中错误的一项是 ( )。", + "options": [ + "A. 统计数据比较多时,可以先分小组统计,再汇总", + "B. 把数据按照不同的标准分类,可以得到不同的信息", + "C. 调查的对象不同,得到的结果一定相同" + ], + "answer": "C", + "solution": "【分析】调查的对象不同,得到的结果可能相同,也可能不同,不一定相同.\n【详解】统计数据较多时可先分小组统计再汇总;按不同标准分类一般会得到不同结果;调查对象不同结果不一定相同,故C错误。故答案为: C", + "knowledge_points": [ + "单式统计表的特点及填补" + ], + "source": "19-20 一年级下·全国·单元测试" + }, + { + "id": "132", + "unit": "第三单元分类与整理", + "question_type": "选择题", + "difficulty": 0.65, + "question": "下面是一年六班选举班干部时四名候选人的得票结果。若选一个人当班长,比较合适的是 ( )\n\n| 姓名 | 王宇 | 李晴 | 张丹 | 王优 |\n| --- | --- | --- | --- | --- |\n| 得票数 | 12 | 4 | 9 | 16 |", + "options": [ + "A. 王宇", + "B. 李晴", + "C. 王优", + "D. 张丹" + ], + "answer": "C", + "solution": "【分析】比较四名候选人得票数,得票最多者较合适.\n【详解】王优得票16票最多,适合当班长。故答案为: C", + "knowledge_points": [ + "统计图表的综合应用" + ], + "source": "19-20 一年级下·全国·单元测试" + }, + { + "id": "133", + "unit": "第三单元分类与整理", + "question_type": "选择题", + "difficulty": 0.85, + "question": "下面的图形中,最与众不同的图形是 ( ) 。", + "options": [ + "A. ![](images/9e267efd6bc792fe842527de9c69478694d270ce5edec00402342d6611ad37e2.jpg)", + "B. ![](images/7c6b9ee8fcca50c6dad2e5489b0b921a17031162ba37e64639adb72d7b1e62e4.jpg)", + "C. ![](images/aff6e6ff7c121a301a407580a6fa539dcbaa211e2fe79bbbddd790ca887362ca.jpg)", + "D. ![](images/f2bc04e29935b503787bb46fae735ca1a573336cd6628d076fa9f932126b7723.jpg)" + ], + "answer": "D", + "solution": "【分析】比较各图形特征,找出与其他图形不属于同一类的.\n【详解】A、B、C为同一类图形,D与众不同。故答案为: D", + "knowledge_points": [ + "长方形,正方形,三角形和圆的初步认识", + "平行四边形的初步认识" + ], + "source": "15-16 六年级下·山东日照·期末" + }, + { + "id": "134", + "unit": "第三单元分类与整理", + "question_type": "填空题", + "difficulty": 0.65, + "question": "我们经常说班上的男同学有多少个,班上的女同学有多少个,说明我们把班上的同学进行了( ),分为男生和女生。", + "options": [], + "answer": "分类", + "solution": "【详解】我们经常说班上的男同学有多少个,班上的女同学有多少个,说明我们把班上的同学进行了分类,分为男生和女生。例如:按照性别进行分类,我们班的同学可以分为男生和女生两类.\n\n| | 男 | 女 |\n| --- | --- | --- |\n| 人数 | 21 | 16 |", + "knowledge_points": [ + "数据的搜集与整理", + "按不同标准分类(单次)" + ], + "source": "22-23 一年级下·全国·课前预习" + }, + { + "id": "135", + "unit": "第三单元分类与整理", + "question_type": "填空题", + "difficulty": 0.85, + "question": "看图按有把杯,无把杯分类,以及按价格分类,完成下列表格.\n\n![](images/f01b74ac15c63828f7bf7a96700290a3.png)\n\n(1)按有把杯,无把杯分类.\n(2)按价格分类。", + "options": [], + "answer": "5;4 3;4;2", + "solution": "【分析】根据图示,按照分类统计的方法,分别按照要求数出相应的数量填表即可。本题考查了按照不同的标准进行分类统计的知识,结合题意分析解答即可.\n【详解】(1)按有把杯,无把杯分类.\n\n| | 有把杯 | 无把杯 |\n| ---- | ------ | ------ |\n| 个数 | 5个 | 4个 |\n\n(2) 按价格分类.\n\n| | 8元 | 9元 | 10元 |\n| ---- | --- | --- | ---- |\n| 个数 | 3个 | 4个 | 2个 |", + "knowledge_points": [ + "数一数", + "按不同标准分类(单次)" + ], + "source": "21-22 一年级下·河南周口·期末" + }, + { + "id": "136", + "unit": "第三单元分类与整理", + "question_type": "填空题", + "difficulty": 0.85, + "question": "给这些杯子分类.\n\n![](images/8b850b021327f9f8060eb5c848026357.png)\n\n(1)带把手的有( )个,不带把手的有( )个.\n(2)按颜色分,黑色的有( )个,白色的有( )个。", + "options": [], + "answer": "2;5 3;4", + "solution": "【分析】根据不同的分类标准数出杯子的个数即可。本题主要考查物体的分类,关键注意分类的标准.\n【详解】(1)带把手的有 2 个,不带把手的有 5 个。(2) 按颜色分,黑色的有 3 个,白色的有 4 个。", + "knowledge_points": [ + "按不同标准分类(单次)" + ], + "source": "21-22 一年级下·四川广元·期末" + }, + { + "id": "137", + "unit": "第三单元分类与整理", + "question_type": "填空题", + "difficulty": 0.65, + "question": "我能分类整理.\n\n![](images/430a8700ac6bfa641139064a034e5246169657c0681ba0750b832f3852aa4327.jpg)\n\n(1) 按形状分类整理.\n(2) 按颜色分类整理。", + "options": [], + "answer": "5;6;7;8 14;9;3", + "solution": "【分析】(1)根据正方形,圆,三角形,平行四边形的含义及特征进行分类;(2) 根据白色,灰色,黑色进行分类。然后填入统计表。此题考查了平面图形的特点,分类及识别,尤其注意对颜色识别的掌握.\n【详解】(1)按形状分类整理.\n\n| 形状 | 正方形 | 圆形 | 平行四边形 | 三角形 |\n| -------- | ------ | ---- | ---------- | ------ |\n| 数量(个) | 5 | 6 | 7 | 8 |\n\n(2) 按颜色分类整理.\n\n| 颜色 | 黑色 | 白色 | 灰色 |\n| ---- | ---- | ---- | ---- |\n| 数量(个) | 14 | 9 | 3 |", + "knowledge_points": [ + "四边形的分类及关系", + "按不同标准分类(单次)", + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "21-22 一年级下·广东汕尾·期末" + }, + { + "id": "138", + "unit": "第三单元分类与整理", + "question_type": "填空题", + "difficulty": 0.65, + "question": "认一认,数一数.\n\n![](images/a3512f91b1e54f0f3a759e2b1c93f542.png)", + "options": [], + "answer": "4;6;3;3", + "solution": "【分析】图中的图形有长方形,三角形,正方形和圆,数一数各个图形的个数进行填空即可。熟练掌握图形的分类与整理是关键;数数时需要仔细.\n【详解】![](images/74eb0cd36187c6c69ef3cbc66d031df4.png)", + "knowledge_points": [ + "数一数", + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "20-21 一年级下·天津红桥·期末" + }, + { + "id": "139", + "unit": "第三单元分类与整理", + "question_type": "填空题", + "difficulty": 0.65, + "question": "数一数,填一填.\n\n![](images/f9b6d3e7a235f646217eb44e55d830c2.png)", + "options": [], + "answer": "17;3;8;6;1", + "solution": "【分析】根据所给图形数出每个图形对应的数量,据此解答.\n【详解】![](images/d164b756237cdb8631db4a5a985a4936.png)本题不同图形的收集与整理,培养学生的数据分析的能力。", + "knowledge_points": [ + "数据的搜集与整理" + ], + "source": "21-22 一年级下·广东东莞·期中" + }, + { + "id": "140", + "unit": "第三单元分类与整理", + "question_type": "填空题", + "difficulty": 0.65, + "question": "看图填空.\n\n![](images/2de4a8d2b9c6cf3334ab907da696252740051b2e95af6bd33a2241db08f2f7dc.jpg)\n\n(1)看图填表.\n![](images/afc7843b34c21d53b408a8883f9163b3.png)\n(2)根据图形总数和数量相等等问题完成填空。", + "options": [], + "answer": "4;3;5;3;2 17;□;△", + "solution": "【分析】(1)数一数,将数量填入对应图形的下面;(2) 数一数图形的总数量,然后找到数量相等的两个;(3) 用 ○ 的数量减去 ![](images/3c6981cbfb876dd65e3e78ddf44660d0.png) 的数量即可。熟练掌握图形的分类与整理是解题关键,数数时要认真仔细.\n【详解】 (1)![](images/985e362524f2dd294ad530f9e2590bbd.png)\n(2)一共有 17 个图形, □ 和 △ 一样多。 (3) 5 - 4 = 1 (个)", + "knowledge_points": [ + "图文问题", + "数据的搜集与整理", + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "21-22 一年级下·浙江温州·期中" + }, + { + "id": "141", + "unit": "第三单元分类与整理", + "question_type": "填空题", + "difficulty": 0.65, + "question": "分一分,填一填.\n\n![](images/4f15d0c1da3e21f798ff2008c0d73d81.png)\n\n(1)按杯子不同特征分类并填表.\n(2)统计总数并比较多与少.\n(3)求两种杯子个数的差。", + "options": [], + "answer": "3;4 12;3 1", + "solution": "【分析】 (1) (2) 根据图中杯子的特征:有盖子,没盖子有把手,没盖子没把手,数数即可;(3) 分别数出![](images/090decdfdd6dbd4210d2862514aca4cb098f9c2493bba07e4fd0c21eeb35a65b.jpg)有 4 个,![](images/c7e7e8cb61dc72e90948d64e821cdb1676569bc571d308b63afc44c5056bbe07.jpg)有 5 个,两者相减即可。本题主要考查了观察图中杯子特征的能力,解题的关键认清杯子的特征.\n【详解】![](images/5192de90f579b87624d535d0d9447f46.png)", + "knowledge_points": [ + "数据的搜集与整理" + ], + "source": "21-22 一年级下·四川眉山·期末" + }, + { + "id": "142", + "unit": "第三单元分类与整理", + "question_type": "解答题", + "difficulty": 0.65, + "question": "我会做一做.\n\n![](images/b08e9635bf5aa8e75ee1abd3035f594804b76f89b5f0d70d304a50930e0b2e54.jpg)\n\n(1)按形状分一分,填一填.\n![](images/2f92256992cd46c3d58ed57f8d1dcb2c.png)\n(2)如果把这些图形分成两组,可以怎样分。把分组的结果表示出来。", + "options": [], + "answer": "3;2;4;2;1;4;6 11;11", + "solution": "【分析】(1)数一数,将数据填入对应的图形下面;(2) 图中有平面图形和立体图形两种,可以按此分类整理。熟练掌握数据的分类与整理方法是解题关键.\n【详解】 (1)![](images/639c560c5fd0527d007dfc546c9b11b0.png)\n(2)\n\n| | 平面图形 | 立体图形 |\n| ---- | -------- | -------- |\n| 个数 | 11 | 11 |", + "knowledge_points": [ + "数据的搜集与整理", + "立体图形的认识", + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "21-22 一年级下·河南南阳·期末" + }, + { + "id": "143", + "unit": "第三单元分类与整理", + "question_type": "解答题", + "difficulty": 0.65, + "question": "根据要求完成题目.\n\n![](images/d9eddca59fa596033cad50994ef2c714a022206960c3e2d595dc8f5eb1563737.jpg)\n\n(1)把分类的结果填在表中.\n(2)( )的个数最多,( )的个数最少.\n(3)( )和( )的个数一样多.\n(4)正方形比平行四边形多( )个,比长方形少( )个。", + "options": [], + "answer": "6;5;4;5;3 长方形;平行四边形 正方形;圆 2;1", + "solution": "【分析】(1)根据所给图形数出各个图形的数量即可;(2) 根据 (1) 比较各个图形数量的大小,最大的就是最多的,最小的就是最少的;(3) 根据 (1) 可知数量相等的两种图形;(4) 用正方形的个数减平行四边形的个数;用长方形的个数减正方形的个数;据此回答。本题考查数据的收集与整理,认真数出每个图形的个数.\n【详解】 (1)\n\n| 图形 | 长方形 | 正方形 | 三角形 | 圆 | 平行四边形 |\n| ---------- | ------ | ------ | ------ | -- | ---------- |\n| 个数 | 6 | 5 | 4 | 5 | 3 |\n\n(2) 6 > 5 > 4 > 3,所以长方形最多,平行四边形最少;(3) 5 = 5,所以正方形和圆一样多;(4) 5 - 3 = 2 (个), 6 - 5 = 1 (个), 所以正方形比平行四边形多 2 个,比长方形少 1 个。", + "knowledge_points": [ + "数据的搜集与整理", + "长方形,正方形,三角形和圆的初步认识", + "平行四边形的初步认识" + ], + "source": "20-21 一年级下·湖北鄂州·期末" + }, + { + "id": "144", + "unit": "第三单元分类与整理", + "question_type": "解答题", + "difficulty": 0.65, + "question": "数一数,填一填.\n\n![](images/5eb7864c991010bc946b701d4500aa0f583b620b076588fb29dfea333be61136.jpg)\n\n(1)数一数,完成下表.\n![](images/d8eb3c508f10a5a8e410aabb8dc3c7e0.png)\n(2)( )最多,( )最少,它们相差( )个.\n(3)一共有( )个图形。", + "options": [], + "answer": "4;2;7;4;1 ○;▱;6 18", + "solution": "【分析】(1)根据所给图形数出各个图形的数量,填表即可;(2) 比较数量的大小,最大即最多,最小即最少,相差用减法计算;(3) 把所有图形的数量加在一起即可。本题考查数据的整理与分类,按给定的标准分类,结果是一定的.\n【详解】 (1)![](images/96539e7152cc74a7d6e5af7e4610d7c9.png)\n(2) 7>4>2>1, 7-1=6(个),所以( ○)最多,(▱ )最少,它们相差(6)个。(3) 4 + 2 + 7 + 4 + 1=6 +11 + 1=17 +1 = 18(个),所以一共有18个图形。", + "knowledge_points": [ + "按不同标准分类(单次)", + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "20-21一年级下·江西赣州·期末" + }, + { + "id": "145", + "unit": "第三单元分类与整理", + "question_type": "解答题", + "difficulty": 0.65, + "question": "数一数.\n\n![](images/96dfb0122493da73fa932b0d7841a24d0dc1d4cdda0128d7410fe0f648281d9c.jpg)\n\n(1)填一填.\n\n| | □ | △ | ○ |\n| ---- | -- | -- | -- |\n| 个数 | ( ) | ( ) | ( ) |\n\n(2)( )的个数最少,( )的个数最多.\n(3) △ 比 ○ 少( )个。", + "options": [], + "answer": "3;1;10 △;○ 9", + "solution": "【分析】(1)数一数,长方形有3个, △ 有1个, ○ 有10个;(2) 将三个数比较大小后可知;(3) 用 ○ 的个数减去 △ 的个数即可。熟练掌握图形的分类与整理是解题关键.\n【详解】 (1)![](images/4eb23dd5d3353c1981e9655d6315551b.png)\n(2) 1 < 3 < 10,所以 △ 的个数最少, ○ 的个数最多;(3) 10 - 1 = 9 (个)所以 △ 比 ○ 少9个。", + "knowledge_points": [ + "数一数", + "比较物体多少", + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "21-22 一年级下·江西上饶·期末" + }, + { + "id": "146", + "unit": "第三单元分类与整理", + "question_type": "解答题", + "difficulty": 0.65, + "question": "按要求分一分再填空.\n\n![](images/36ac1331ca0051c41c0592f1afbce6879fd01321838790aa08dad3d190e3a3e0.jpg)\n\n(1)按颜色分,完成\"灰色,白色\"统计表.\n(2)按形状分,完成\"圆柱,正方体,圆形,三角形\"统计表。", + "options": [], + "answer": "5;14;5;3;5;6", + "solution": "【分析】数清楚图中各种颜色和形状的图形数量,填入表格即可.\n【详解】\n\n| | 灰色 | 白色 |\n| ---- | ---- | ---- |\n| 个数 | 5 | 14 |\n\n| | 圆柱 | 正方体 | 圆形 | 三角形 |\n| ---- | ---- | ------ | ---- | ------ |\n| 个数 | 5 | 3 | 5 | 6 |", + "knowledge_points": [ + "数据的搜集与整理", + "立体图形的认识", + "按不同标准分类(单次)", + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "21-22 一年级下·河南信阳·期末" + }, + { + "id": "147", + "unit": "第三单元分类与整理", + "question_type": "解答题", + "difficulty": 0.85, + "question": "按要求分类.\n\n![](images/7805b7e24981b3e7262db38a11cb5b26.png)\n\n将图中的交通工具按\"天上飞的交通工具\"\"水上行的交通工具\"\"地上跑的交通工具\"分类并填表。", + "options": [], + "answer": "3;2;3", + "solution": "【分析】由图根据分类标准,数出每类交通工具的数量即可。本题主要考查根据不同标准进行分类与整理。关键是分清类别.\n【详解】由图可知,天上飞的交通工具的数量是: 3;水上行的交通工具的数量是: 2;地上跑的交通工具数量是: 3。", + "knowledge_points": [ + "按不同标准分类(单次)" + ], + "source": "21-22 一年级下·河北张家口·期末" + }, + { + "id": "148", + "unit": "第三单元分类与整理", + "question_type": "解答题", + "difficulty": 0.65, + "question": "数一数,填一填.\n\n![](images/a75ffa3003623f859563a2b2d4f6577b72f682f803ab4f4a3516cb0e66c33df7.jpg)\n\n按形状分:带把手和不带把手.\n按颜色分:白色和黑色。", + "options": [], + "answer": "2;7;4;5", + "solution": "【分析】根据所给图,按分类的标准解答即可。本题考查数据的整理与分类.\n【详解】按形状分:带把手的有 2 个,不带把手的有 7 个;按颜色分:白色的有 4 个,黑色的有 5 个。", + "knowledge_points": [ + "数据的搜集与整理", + "按不同标准分类(单次)" + ], + "source": "20-21一年级下·河南三门峡·期末" + }, + { + "id": "149", + "unit": "第三单元分类与整理", + "question_type": "解答题", + "difficulty": 0.65, + "question": "将这些羊分类的结果填在下表中.\n\n![](images/00f083fd4f5530799fcac1b13ecc3204d6484e83b68bcf29a56e1f20eb913c68.jpg)\n\n按颜色分成黑羊和白羊,按大小分成大羊和小羊。", + "options": [], + "answer": "6;5;6;5", + "solution": "【分析】根据颜色可知:黑羊有 6 只,白羊有 5 只。从羊的大小可知:大羊有 6 只,小羊有 5 只。本题考查学生的数据分析和整理的能力.\n【详解】\n\n| | 黑羊 | 白羊 |\n| ---- | ---- | ---- |\n| 只数 | (6) | (5) |\n\n| | 大羊 | 小羊 |\n| ---- | ---- | ---- |\n| 只数 | (6) | (5) |", + "knowledge_points": [ + "数据的搜集与整理", + "按不同标准分类(单次)" + ], + "source": "21-22 一年级下·山东菏泽·期末" + }, + { + "id": "150", + "unit": "第三单元分类与整理", + "question_type": "解答题", + "difficulty": 0.65, + "question": "先数一数,再填一填.\n\n![](images/28a055bcb1cc115c0a5365c779661c5e235c7446099592463dc599f3364c5d43.jpg)\n\n(1)数一数,把结果整理在表格中.\n(2)苹果比桃多( )个,梨比苹果少( )个。", + "options": [], + "answer": "4;5;5;7 2;3", + "solution": "【分析】(1)认真数出各种水果的个数填入空里即可;(2) 数出苹果的个数减去桃的个数可知苹果比桃多几个;用苹果的个数减去梨的个数可知梨比苹果少几个。 (1) 根据图片可以数出:梨有 4 个,桃有 5 个,香蕉有 5 个,苹果有 7 个。 (2) 7 - 5 = 2 (个),苹果比桃多2个;7 - 4 = 3 (个),梨比苹果少3个。解答本题的关键是要能数对每种水果的个数。", + "knowledge_points": [ + "数据的搜集与整理", + "7 的加减法" + ], + "source": "21-22一年级下·山东泰安·期末" + }, + { + "id": "151", + "unit": "第三单元分类与整理", + "question_type": "解答题", + "difficulty": 0.65, + "question": "数一数,填一填.\n\n![](images/63b3ee9fd83545834cca0a98eaef35a7f164bfc9ef61ec05e61ab45da4266522.jpg)\n\n![](images/253eef88fcb333970c4f52ceba7db64a.png)", + "options": [], + "answer": "5;3;1;4;1", + "solution": "【分析】根据长方形,正方形,圆形,三角形与平行四边形的特征区分各个图形并数出它们的个数,填入统计表中。解答此题的关键是要能区分各种图形.\n【详解】长方形5个;正方形3个;圆形1个;三角形4个;平行四边形 1 个。", + "knowledge_points": [ + "按不同标准分类(单次)", + "长方形,正方形,三角形和圆的初步认识", + "平行四边形的初步认识" + ], + "source": "21-22一年级下·广东韶关·期末" + }, + { + "id": "152", + "unit": "第三单元分类与整理", + "question_type": "解答题", + "difficulty": 0.65, + "question": "一年 (6) 班同学喜欢吃的水果情况如下图:\n\n![](images/33a98ae6b651f2c7d698f248881c40a1fee8a072d2f80ce47d69213b9089c6ff.jpg)\n\n(1)根据上图填写下表:\n(2)喜欢吃( )的人最少,喜欢吃( )的人最多.\n(3)喜欢吃( )和喜欢吃( )的人一样多.\n(4)喜欢吃苹果的人比喜欢吃草莓的人少( )人。", + "options": [], + "answer": "5;3;7;5;8 梨;草莓 苹果;西瓜 3", + "solution": "【详解】 (1) 略(2) 略 (3) 略 (4) 略", + "knowledge_points": [ + "数一数", + "10以内数的比大小", + "按不同标准分类(单次)" + ], + "source": "21-22 一年级下·内蒙古通辽·期中" + }, + { + "id": "153", + "unit": "第三单元分类与整理", + "question_type": "解答题", + "difficulty": 0.65, + "question": "按分类填入序号.\n\n![](images/d8767eeb2567334678bf506d90a2aea86335d7eeafc90faec3b709c7f0efffb6.jpg)", + "options": [], + "answer": "见图中所示序号填法", + "solution": "【详解】略\n\n![](images/8ad2e9365edd050557b187b833bf4e42.png)", + "knowledge_points": [ + "按不同标准分类(单次)" + ], + "source": "21-22 一年级下·内蒙古通辽·期中" + }, + { + "id": "154", + "unit": "第三单元分类与整理", + "question_type": "解答题", + "difficulty": 0.65, + "question": "下面是一幅剪贴画中所用图形个数的情况统计图.\n\n![](images/b71cf142db0e98bf92869b67cc076f4b4841812d7a762ec746dec9bb1b93a174.jpg)\n\n(1)根据上图填写下表.\n![](images/ac7d9bb8dda7f0c81668d4020569831b.png)\n(2)一共有( )个图形.\n![](images/ab284dde842c7d39efd3293ed09f8d6e.png)", + "options": [], + "answer": "5;3;6;4 18 3;1", + "solution": "【详解】 (1) 略 (2) 略 (3) 略", + "knowledge_points": [ + "8 加几的进位加法", + "按不同标准分类(单次)", + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "19-20 一年级下·四川绵阳·期末" + }, + { + "id": "155", + "unit": "第三单元分类与整理", + "question_type": "解答题", + "difficulty": 0.65, + "question": "分类整理.\n\n![](images/54ebb54c4fa76c8b603f104415415e16a8a3a5bd0bd2a54d7d08dc2299205c46.jpg)\n\n(1)填一填.\n(2)一共有( )个图形,( )的数量最多,( )的数量最少.\n(3)图中正方形比三角形多( )个,圆形和长方形一共有( )个。", + "options": [], + "answer": "5;3;4;4;4 20;圆形;三角形 1;9", + "solution": "【详解】 (1) 略(2) 略 (3) 略", + "knowledge_points": [ + "按不同标准分类(单次)", + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "20-21 一年级下·黑龙江齐齐哈尔·期末" + }, + { + "id": "156", + "unit": "第三单元分类与整理", + "question_type": "解答题", + "difficulty": 0.65, + "question": "分一分,填一填.\n\n![](images/6453eb2c1cce667711e2cfcfc8a648648ee4ddd0c9ec31642161587873f5ca6f.jpg)\n\n![](images/beb0406d1a218cfbd236f76477ed2e588566b1acb855e48ba2ae8303c50a82e0.jpg)", + "options": [], + "answer": "见下图统计结果", + "solution": "【详解】见下图:\n\n![](images/c4334ad2f504e2e6ee6ad118f4ec4e229544c86f0f6c1a2d3c21fe2a6218935e.jpg)", + "knowledge_points": [ + "按不同标准分类(单次)" + ], + "source": "21-22 一年级下·山西晋中·期中" + }, + { + "id": "157", + "unit": "第三单元分类与整理", + "question_type": "解答题", + "difficulty": 0.85, + "question": "按标准给小动物分类.\n\n![](images/4586cfed91fb25bc571dbd4a3aa64549.png)\n\n按腿的条数分:\n\n| | 四条腿的动物 | 两条腿的动物 | 没有腿的动物 |\n| ---------- | ------------ | ------------ | ------------ |\n| 序号填写为 | | | |", + "options": [], + "answer": "③⑥;①⑤;②④", + "solution": "【分析】按脚的条数分: ①有两条腿, ②没有腿, ③有四条腿, ④没有腿, ⑤有两条腿, ⑥有四条腿。本题主要考查分类知识,根据分类标准进行分类即可.\n【详解】根据题意填表如下,\n\n| 四条腿的动物 | 两条腿的动物 | 没有腿的动物 |\n| ------------ | ------------ | ------------ |\n| ③⑥ | ①⑤ | ②④ |", + "knowledge_points": [ + "按不同标准分类(单次)" + ], + "source": "20-21 一年级下·广东韶关·期末" + }, + { + "id": "158", + "unit": "第三单元分类与整理", + "question_type": "解答题", + "difficulty": 0.65, + "question": "按要求分卡片,填一填.\n\n![](images/a584bbcca9d3f43ee457ac46999d25aeb36eba055b3eedd96aed8516543eaedf.jpg)\n\n(1)可以按形状分一分,填一填(三角形,正方形,圆,正方体,圆柱).\n(2)可以按颜色分一分,填一填(白色,黑色)。", + "options": [], + "answer": "2;4;5;6;3 11;9", + "solution": "【详解】 (1) 略 (2) 略", + "knowledge_points": [ + "按不同标准分类(单次)" + ], + "source": "20-21 一年级下·河南南阳·期中" + }, + { + "id": "159", + "unit": "第三单元分类与整理", + "question_type": "解答题", + "difficulty": 0.65, + "question": "分类与整理.\n\n![](images/6c944eaf279dc9b69f72a68e0c1b1a47.png)\n\n(1) 按卡片的形状分一分。△( )○( ) □( )\n(2) 按水果的种类分一分。苹果( )桃( )", + "options": [], + "answer": "4;2;2 5;3", + "solution": "【分析】(1)按卡片的形状分一分,根据正方形,三角形,圆的特征分类数数即可;(2) 按水果的种类分类数数即可。本题主要考查了平面图形的分类及识别,解题的关键是明确分类的方法.\n【详解】 (1) 按卡片的形状分一分.\n\n| | △ | ○ | □ |\n| ---- | - | - | - |\n| 数量 | 4 | 2 | 2 |\n\n(2) 按水果的种类分一分.\n\n![](images/13d9dc15b335697f32587d38fd4e886d.png)", + "knowledge_points": [ + "数一数", + "按不同标准分类(单次)", + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "20-21 一年级下·河南郑州·期中" + }, + { + "id": "160", + "unit": "第三单元分类与整理", + "question_type": "解答题", + "difficulty": 0.65, + "question": "看图形,分一分.\n\n![](images/0ca75fc92f370e1fd8ae229bf7324c3e.png)\n\n(1) 按颜色分一分,填一填(白色,黑色,灰色).\n(2) 按形状分一分,填一填(圆,三角形,正方形,长方形)。", + "options": [], + "answer": "7;2;1;3;3;3;1", + "solution": "【详解】略", + "knowledge_points": [ + "按不同标准分类(单次)" + ], + "source": "19-20 一年级下·福建龙岩·期末" + }, + { + "id": "161", + "unit": "第三单元分类与整理", + "question_type": "解答题", + "difficulty": 0.85, + "question": "给这些杯子分类.\n\n![](images/581ebc58ac2d1f861850488336b9ce9d.png)\n\n(1) 按要求分一分,填一填(带把手,不带把手).\n(2) 还可以怎样分。 填一填(例如按颜色黑色,白色)。", + "options": [], + "answer": "4;5 黑色;白色;5;4", + "solution": "【分析】略", + "knowledge_points": [ + "按不同标准分类(单次)" + ], + "source": "20-21 一年级下·河北唐山·期中" + }, + { + "id": "162", + "unit": "第三单元分类与整理", + "question_type": "填空题", + "difficulty": 0.65, + "question": "在括号里填上 \">\" \"<\" 或 \"=\".\n\n11-5( )7\n12-9( )9\n15-7( )6\n\n75( )5\n80+7( )87\n9+8( )17", + "options": [], + "answer": "<;<;>;>;=;=", + "solution": "【详解】略", + "knowledge_points": [ + "100 以内数的比大小", + "十几减 7", + "6 的退位减法", + "9 加几的进位加法", + "两位数与一位数的加法(不进位)" + ], + "source": "19-20 一年级下·湖南怀化·单元测试" + }, + { + "id": "163", + "unit": "第三单元分类与整理", + "question_type": "填空题", + "difficulty": 0.65, + "question": "我会数.\n\n![](images/511162b19c697adbcdc3d843f91f2432.png)", + "options": [], + "answer": "7;1;10;7;4", + "solution": "【详解】略", + "knowledge_points": [ + "数一数", + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "19-20 一年级下·湖南怀化·单元测试" + }, + { + "id": "164", + "unit": "第三单元分类与整理", + "question_type": "填空题", + "difficulty": 0.65, + "question": "数一数,填一填.\n\n![](images/bc1df4ebb298403b713c7d14b0348b9f.png)\n\n(1) ( )的数量最多, ( )的数量最少.\n(2) 正方体比长方体少( )个.\n(3) 所有图形一共有( )个。", + "options": [], + "answer": "长方体;圆;5;11", + "solution": "【分析】略", + "knowledge_points": [ + "立体图形的认识", + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "18-19一年级下·贵州遵义·期末" + }, + { + "id": "165", + "unit": "第三单元分类与整理", + "question_type": "解答题", + "difficulty": 0.65, + "question": "一(1)班几名学生获得笑脸情况如下图.\n\n![](images/d3d558bef96be2020338bf36eea55e021d88bc1b1ead8307e8abfd80237aefd7.jpg)\n\n(1) 根据上图填写下表.\n(2) ( )和( )得笑脸的个数一样多.\n(3) 得笑脸最多的是( ),东东比珍珍多得( )个笑脸。", + "options": [], + "answer": "4;6;7;10;6;红红;芳芳;东东;6", + "solution": "【分析】略", + "knowledge_points": [ + "数据的搜集与整理" + ], + "source": "19-20 一年级下·贵州铜仁·期末" + }, + { + "id": "166", + "unit": "第三单元分类与整理", + "question_type": "解答题", + "difficulty": 0.65, + "question": "请按表内的不同分类统计下面的图形.\n\n![](images/9a726632506fd2247818fb04dd4b07df.png)\n\n(1) 请把下面的 2 个统计表补充完整。苹果( )梨( )桃( ) 三角形( )正方形( )圆()\n(2) 苹果比桃少( )个,桃和梨一共有( )个.\n(3) 三角形,正方形和圆一共有( )个。", + "options": [], + "answer": "3;5;6;4;5;5;3;11;14", + "solution": "【详解】略", + "knowledge_points": [ + "按不同标准分类(单次)" + ], + "source": "19-20 二年级下·陕西安康·期末" + }, + { + "id": "167", + "unit": "第三单元分类与整理", + "question_type": "解答题", + "difficulty": 0.65, + "question": "如下图,数一数上面的图案中每种图形有多少个,并填表,然后回答问题.\n\n![](images/07b31514741315350233714597488fc898fdae348556ac850ffa079872400223.jpg) (1)长方形()正方形()圆()三角形()平行四边形()(2)上面的五种图形一共有( )个。( )形的数量最多。(3)长方形比三角形少( )个,正方形比平行四边形多( )个。(4)文文摆了5个图中小车,一共用了( )个圆。", + "options": [], + "answer": "4;3;3;7;1;18;三角形;3;2;10", + "solution": "【分析】略", + "knowledge_points": [ + "按不同标准分类(单次)", + "长方形,正方形,三角形和圆的初步认识", + "平行四边形的初步认识" + ], + "source": "17-18 一年级下·浙江杭州·期末" + }, + { + "id": "168", + "unit": "第三单元分类与整理", + "question_type": "解答题", + "difficulty": 0.65, + "question": "分类与整理.\n\n![](images/e590ee022c81e0ab04da5ecec1cbc9a053eb21038f910e8f9c267db590ad3852.jpg)\n\n(1) 按形状把上面的卡片分一分。□( ) △( ) ○( )\n(2) 把上面的动物分成两类(天上飞的,地上跑的)。", + "options": [], + "answer": "4;2;4;4;6", + "solution": "【分析】![](images/735e11fb58efb9bebc5ebcc2a4167e58.png)本题考查分类。分类的标准不同,\n【详解】(1)按形状把上面的卡片分一分.\n\n![](images/1ca19b70b77eebd2f2d86cf0a95d2516.png)", + "knowledge_points": [ + "按不同标准分类(单次)", + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "18-19 一年级下·甘肃兰州·期末" + }, + { + "id": "169", + "unit": "第三单元分类与整理", + "question_type": "解答题", + "difficulty": 0.85, + "question": "分类与整理.\n\n![](images/7da701244f17cfe70c3a5b8772fc16719b5f550041ed168e6db80142fccf0e08.jpg)\n\n(1) 按颜色把上面的卡片分一分,并统计每种颜色的卡片数量。黑色( )白色( )\n(2) 按形状把上面的卡片分一分,并统计每种形状的卡片数量。三角形( )正方形( ) 长方形( )平行四边形( )", + "options": [], + "answer": "5;6;4;2;3;2", + "solution": "【分析】略\n【详解】略", + "knowledge_points": [ + "按不同标准分类(单次)", + "长方形,正方形,三角形和圆的初步认识", + "平行四边形的初步认识" + ], + "source": "18-19 一年级下·甘肃庆阳·期末" + }, + { + "id": "170", + "unit": "第三单元分类与整理", + "question_type": "填空题", + "difficulty": 0.65, + "question": "分类与整理。如图,按要求完成下列问题:\n 数一数,完成下表.\n![](images/f1b9149e352211389e102f997da970e4b4f87752e78ae32c01d2dee338f5586a.jpg);(1)![](images/4a821f7444f272eeb36f9bde1671c513.png)\n(2) ( )的数量最少, ( )的数量最多.\n(3) 立体图形有( )个,平面图形有( )个。", + "options": [], + "answer": "3;4;2;7;5;□;△;7;14", + "solution": "【分析】略", + "knowledge_points": [ + "立体图形的认识", + "按不同标准分类(单次)", + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "19-20 一年级下·江西赣州·期末" + }, + { + "id": "171", + "unit": "第三单元分类与整理", + "question_type": "填空题", + "difficulty": 0.65, + "question": "如图,分一分,填一填.\n(1) 分一分,每种水果各有多少个。\n![](images/66c23aeb3340ec3d7f919c7f86693860463a435a39e2e1f905e3dcf1f42f9a68.jpg)\n![](images/4cab01bd3799b01e0374f0e01cc9ce65.png)\n(2) 回答问题.\n![](images/9155aaf16790a096de2eb500f5845ed2.png)", + "options": [], + "answer": "9;9;4;18;5", + "solution": "【分析】略", + "knowledge_points": [ + "8,9 的加减法", + "8 加几的进位加法", + "按不同标准分类(单次)" + ], + "source": "19-20 一年级下·江西上饶·期末" + }, + { + "id": "172", + "unit": "第三单元分类与整理", + "question_type": "解答题", + "difficulty": 0.65, + "question": "给下面的物体分类。(填序号)\n![](images/57ac49d859b04cb1ece030bd1f481cf2.png)\n(1) 天上飞的:( );地上跑的:( );水里行的:( ).\n(2) 交通工具: ( );动物: ( )。", + "options": [], + "answer": "②④;①⑥;③⑤;①②③;④⑤⑥", + "solution": "【分析】天上飞的:飞机,鸟;地上跑的:汽车,小狗;水里行的:小船,小鱼。交通工具:汽车,飞机,小船;动物:鸟,小鱼,小狗。据此解答。本题考查分类。分类的标准不同,结果也就不同,关键是要找准分类标准.\n【详解】给下面的物体分类。(填序号)![](images/57ac49d859b04cb1ece030bd1f481cf2.png)\n(1) 天上飞的: (②④);地上跑的: (①⑥);水里行的: (③⑤)。 \n(2) 交通工具:(①②③);动物:(④⑤⑥)。", + "knowledge_points": [ + "按不同标准分类(单次)" + ], + "source": "20-21 一年级下·全国·单元测试" + }, + { + "id": "173", + "unit": "第三单元分类与整理", + "question_type": "填空题", + "difficulty": 0.65, + "question": "分一分.\n![](images/429c53363c257189ae7a426032c88313bd71f85c9b1e2b929cbcd45749a5ea35.jpg)\n(1)上面的图形按颜色分,完成下表.\n\n| | 白色 | 黑色 |\n| ---- | ---- | ---- |\n| 个数 | ( ) | ( ) |\n\n(2)上面的图形按形状分,完成下表.\n![](images/6b9ce50f2012ae8cb7fd6722316cbd94.png)", + "options": [], + "answer": "8;7;4;4;4;3", + "solution": "【分析】(1)根据黑,白颜色分类数数即可;(2) 根据长方形,平行四边形,三角形及圆的特征分类数数即可。本题主要考查了平面图形的分类及识别,解题的关键是根据黑,白颜色及长方形,平行四边形,三角形及圆的特征分类.\n【详解】 (1)\n\n| | 白色 | 黑色 |\n| ---- | ---- | ---- |\n| 个数 | 8 | 7 |\n\n(2)\n\n![](images/56d2b980ae6722596d028062376d6356.png)", + "knowledge_points": [ + "按不同标准分类(单次)" + ], + "source": "19-20 一年级下·湖北黄冈·期末" + }, + { + "id": "174", + "unit": "第三单元分类与整理", + "question_type": "解答题", + "difficulty": 0.65, + "question": "分一分,填一填.\n![](images/0df557617e99a57a99c7d3255bd2b956.png)\n在下面的框中填上对应的序号.\n![](images/a5ae6aae92967efe265b16f97241bbd5.png)", + "options": [], + "answer": "①③⑦⑨;⑧⑩⑪;②④⑤⑥", + "solution": "【详解】略", + "knowledge_points": [ + "按不同标准分类(单次)" + ], + "source": "19-20 一年级下·全国·单元测试" + }, + { + "id": "175", + "unit": "第三单元分类与整理", + "question_type": "解答题", + "difficulty": 0.65, + "question": "请你仔细观察下面物体,看看哪些是长方体,哪些是球,哪些是正方体,哪些是圆柱,把它们的序号写在合适的 ( ) 里.\n![](images/d94fa72d1e8b4f736733ff8010cdd4f5.png)\n( )是长方体;( )是正方体;( )是圆柱体;( )是球。", + "options": [], + "answer": "④⑤⑦;③;①⑥⑧⑩;②⑨", + "solution": "【详解】略", + "knowledge_points": [ + "立体图形的认识", + "按不同标准分类(单次)" + ], + "source": "19-20 一年级下·全国·单元测试" + }, + { + "id": "176", + "unit": "第三单元分类与整理", + "question_type": "解答题", + "difficulty": 0.65, + "question": "(1) 数一数,把结果填在下表中.\n![](images/21b95514f7597ebb5aece2b8073e740aec5461a55e62303db2f72bf4ad500f76.jpg)\n\n| 图形 | 长方形 | 正方形 | 三角形 | 圆 |\n| ---- | ------ | ------ | ------ | -- |\n| 个数 | ( ) | ( ) | ( ) | ( ) |\n\n(2) 一共有( )个图形.\n(3) 长方形比正方形多( )个,圆比三角形少( )个。", + "options": [], + "answer": "4;3;8;2;17;1;6", + "solution": "【分析】此题解答的关键是:一定要认真观察,有条理,有顺序的进行数,做到不重复,不遗漏.\n【详解】(1)抓住长方形,正方形,三角形和圆的特点即可在图形中找出所有符合题意的平面图形,完成表格.\n\n| 图形 | 长方形 | 正方形 | 三角形 | 圆 |\n| ---- | ------ | ------ | ------ | -- |\n| 个数 | 4 | 3 | 8 | 2 |\n\n(2) 求各种图形的个数和: 4 + 3 + 8 + 2 = 17 (个) \n(3) 用长方形的个数减去正方形的个数,用三角形个数减去圆的个数即可。 4 - 3 = 1 (个), 8 - 2 = 6 (个) 。", + "knowledge_points": [ + "数据的搜集与整理", + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "19-20 一年级下·全国·期中" + }, + { + "id": "177", + "unit": "第三单元分类与整理", + "question_type": "解答题", + "difficulty": 0.65, + "question": "数数,再填表.\n![](images/86b0a6380d0ae74f01b7a2b924cb9ea84e8f54fa975f5b5dfcb090f209ded706.jpg) | | 三角形 | 四边形 | 五边形 | 六边形 |\n| ---- | ------ | ------ | ------ | ------ |\n| 个数 | ( )个 | ( )个 | ( )个 | ( )个 |", + "options": [], + "answer": "2;4;2;2", + "solution": "【分析】按边数辨认三角形、四边形、五边形、六边形并数一数.\n【详解】\n![](images/6d0b4a96dbea89bdc8e1421cd83e1dc7.png)\n\n| | 三角形 | 四边形 | 五边形 | 六边形 |\n| ---- | ------ | ------ | ------ | ------ |\n| 个数 | 2个 | 4个 | 2个 | 2个 |", + "knowledge_points": [ + "四边形的分类及关系", + "长方形,正方形,三角形和圆的初步认识", + "四边形,五边形及多边形的初步认识" + ], + "source": "19-20 一年级下·全国·期中" + }, + { + "id": "178", + "unit": "第三单元分类与整理", + "question_type": "解答题", + "difficulty": 0.65, + "question": "分水果.\n![](images/e65c7e7e7e6d6dfb3e28ea736b67b04eac5a85a771433bd7b71054749a0ceb0b.jpg)\n![](images/7bdf5a62aad5042f6e57a73c90784081.png)", + "options": [], + "answer": "7;3;5;3", + "solution": "【分析】略\n【详解】略", + "knowledge_points": [ + "按不同标准分类(单次)" + ], + "source": "19-20 一年级下·全国·单元测试" + }, + { + "id": "179", + "unit": "第三单元分类与整理", + "question_type": "解答题", + "difficulty": 0.65, + "question": "将下面的动物分类,把结果整理在表中.\n![](images/d1f26b5c1087e2a08e2f8c5f1817f59c.png)", + "options": [], + "answer": "5;7", + "solution": "【分析】略\n【详解】略", + "knowledge_points": [ + "按不同标准分类(单次)" + ], + "source": "19-20 一年级下·全国·单元测试" + }, + { + "id": "180", + "unit": "第三单元分类与整理", + "question_type": "填空题", + "difficulty": 0.65, + "question": "仔细观察小火车,填写下表.\n![](images/ddb4ac2727e2738e0093bcb396d056d42355c036273a0ead7f4e4bc3b220702a.jpg)\n\n| 图形 | 长方形 | 正方形 | 三角形 | 圆 | 合计 |\n| ------ | ------ | ------ | ------ | -- | ---- |\n| 个数 | ( )个 | ( )个 | ( )个 | ( )个 | ( )个 |", + "options": [], + "answer": "4;4;2;6;16", + "solution": "【详解】略", + "knowledge_points": [ + "数据的搜集与整理", + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "18-19 一年级下·山东枣庄·期末" + }, + { + "id": "181", + "unit": "第三单元分类与整理", + "question_type": "填空题", + "difficulty": 0.65, + "question": "分类整理下面的图形.\n![](images/050d4ca0eefec5d2af80753cd5598dfb378cad56cc477be7e79bdd012a34ef56.jpg)\n![](images/9e643d1d6986a95bd86cbd96dd87b70b.png)\n(1) 按形状分一分,数一数,在表格中写出每组图形的个数.\n(2) 按形状分,( )最多,( )最少。", + "options": [], + "answer": "4;5;3;2;1;长方形;正方形", + "solution": "【详解】略", + "knowledge_points": [ + "单式统计表的特点及填补", + "按不同标准分类(单次)", + "长方形,正方形,三角形和圆的初步认识", + "平行四边形的初步认识" + ], + "source": "17-18 一年级下·湖南永州·期中" + }, + { + "id": "182", + "unit": "第三单元分类与整理", + "question_type": "填空题", + "difficulty": 0.65, + "question": "数一数.\n![](images/096625821e8bb8cc04397d59fc2677fb.png)", + "options": [], + "answer": "3;6;5;3;2", + "solution": "【分析】根据图形的特征进行分类计数:正方形四条边都相等,四个角都是直角;长方形对边相等,四个角都是直角;圆形没有角;平行四边形两组对边分别平行;三角形有三条边和三个角。按题目下面给出的图形顺序,依次数出每类图形的个数即可。【详解】观察图中各类图形:正方形有 3 个;长方形有 6 个;圆形有 5 个;平行四边形有 3 个;三角形有 2 个。所以答案为:3;6;5;3;2。", + "knowledge_points": [ + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "18-19 一年级下·宁夏吴忠·期中" + }, + { + "id": "183", + "unit": "第三单元分类与整理", + "question_type": "填空题", + "difficulty": 0.65, + "question": "下面是一幅由各种图形拼成的\"坦克\"图,先数一数,再填一填.\n![](images/f862022b164f6d0034f33e52a399a622.png)", + "options": [], + "answer": "3;1;4;4;12", + "solution": "【分析】此题主要考查了平面图形的认识,根据图形的特点,按从上到下的顺序数出各种图形的个数即可.\n【详解】通过数数,填表如下:\n\n![](images/5ee1d65b324c2e5128afeb45a9e0b829.png)", + "knowledge_points": [ + "数据的搜集与整理", + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "18-19 一年级下·宁夏吴忠·期中" + }, + { + "id": "184", + "unit": "第三单元分类与整理", + "question_type": "填空题", + "difficulty": 0.65, + "question": "如图,根据图形完成表格并回答问题.\n![](images/f683d110ef577bafd84b13e7c9d4c02398a64d7ed911857ba61cb81a2ee23112.jpg)\n\n| (1) | 黑色 | 白色 |\n| ---- | ---- | ---- |\n| 个数 | ( ) | ( ) |\n\n▭( ) □( ) △( ) ○( )\n(2) 按形状分, ( )图形最多, ( )图形最少;(3) 按颜色分,黑色图形比白色图形少 ( )个,共有 ( )图形。", + "options": [], + "answer": "6;12;6;2;3;7;圆;正方形;6;18", + "solution": "【详解】略", + "knowledge_points": [ + "数据的搜集与整理" + ], + "source": "16-17 一年级下·宁夏石嘴山·期末" + }, + { + "id": "185", + "unit": "第三单元分类与整理", + "question_type": "填空题", + "difficulty": 0.65, + "question": "如图按颜色和形状分类.\n![](images/1dd444eb2c67074a39fd8b078d2d0aac81118e683f9ff588dcbaea02828e95e1.jpg)\n按颜色分:\n\n| | 灰色 | 白色 |\n| ---- | ---- | ---- |\n| 个数 | | |\n\n按形状分:\n\n| | 圆柱 | 正方体 | 圆 | 三角形 |\n| ---- | ---- | ------ | -- | ------ |\n| 个数 | | | | |", + "options": [], + "answer": "6;15;6;3;6;6", + "solution": "【详解】略", + "knowledge_points": [ + "立体图形的认识", + "按不同标准分类(单次)" + ], + "source": "18-19一年级下·吉林·期中" + }, + { + "id": "186", + "unit": "第三单元分类与整理", + "question_type": "判断题", + "difficulty": 0.65, + "question": "苹果和西红柿都是水果。( )", + "options": [], + "answer": "×", + "solution": "【详解】苹果是水果,西红柿是蔬菜。解:苹果是水果,西红柿是蔬菜,所以题干中的说法是错误的。故答案为: × 。这道题考查的是物体的分类,要熟练掌握。", + "knowledge_points": [ + "按不同标准分类(单次)" + ], + "source": "20-21 一年级上·辽宁抚顺·期末" + }, + { + "id": "187", + "unit": "第三单元分类与整理", + "question_type": "判断题", + "difficulty": 0.65, + "question": "把一些物体分类,不管怎么分,结果是一样的。( )", + "options": [], + "answer": "×", + "solution": "【分析】把一些物体分类,可以按照物体的大小,按照物体的形状,或按照物体的颜色等进行分类;那么按照不同方式分类,数量可能不同,据此即可判断。本题主要考查物体的分类,熟练掌握它的分类方法并灵活运用.\n【详解】由分析可知:当一些物体如果按照大小分,可能有大的和小的数量是一样的;但是按颜色分,如果涂色的可能比不涂色的多一些,导致结果不同.\n所以把一些物体分类,不管怎么分,结果可能不同,可能一样。原说法错误。故答案为: ×", + "knowledge_points": [ + "按不同标准分类(单次)" + ], + "source": "19-20 一年级下·全国·单元测试" + }, + { + "id": "188", + "unit": "第三单元分类与整理", + "question_type": "判断题", + "difficulty": 0.85, + "question": "分类的标准不同,分类的结果就不同。( )", + "options": [], + "answer": "√", + "solution": "【分析】对于一些事物,按照分类标准的不同,分类的结果就不相同,可以举例说明。此题考查物体分类与整理的相关知识,分类的关键是善于发现事物的不同特征,根据不同特征,把有相同特征的分为一类.\n【详解】![](images/6e63674692fed11ae4a235b284b5fd9f.png)观察这些图形,可以按颜色分,也可以按照形状分。分类的标准不同,分类的结果就不同。所以原题说法正确。故答案为: √", + "knowledge_points": [ + "按不同标准分类(单次)" + ], + "source": "19-20 一年级下·湖南常德·期中" + }, + { + "id": "189", + "unit": "第三单元分类与整理", + "question_type": "判断题", + "difficulty": 0.85, + "question": "长方形与长方体可以分为一类。( )", + "options": [], + "answer": "×", + "solution": "【分析】长方形是平面图形,长方体的是立体图形,不可以分为一类。据此判断即可。本题考查平面图形和立体图形,明确它们之间的区别是解题的关键.\n【详解】由分析可知:长方形与长方体可以分为一类。说法错误。故答案为: ×", + "knowledge_points": [ + "长方形的概念及特点", + "长方体的认识及特征" + ], + "source": "18-19 一年级下·山东菏泽·期中" + }, + { + "id": "190", + "unit": "第三单元分类与整理", + "question_type": "判断题", + "difficulty": 0.85, + "question": "小明和爸爸,妈妈,姐姐一起做游戏,小明说:\"我按性别把大家分为\"大人和小孩\"两个小组\",小明这样分类,对吗。( )", + "options": [], + "answer": "×", + "solution": "【分析】根据分类知识可知,按照不同的标准分类,统计的结果不同。把小明和爸爸,妈妈,姐姐分成两类,可以按性别分,也可以按年龄分,据此解答。本题关键是明确对同一组数据可以按照不同的标准分类.\n【详解】由分析可得:小明和爸爸,妈妈,姐姐一起做游戏,可以按性别把大家分为\"男女\"两组,原题说法错误。故答案为: ×", + "knowledge_points": [ + "按不同标准分类(单次)" + ], + "source": "17-18一年级下·湖北武汉·期末" + }, + { + "id": "191", + "unit": "第三单元分类与整理", + "question_type": "解答题", + "difficulty": 0.65, + "question": "下面是一些常见的图形.\n![](images/956a825b8f31ba491f1bb468618c06ae.png)\n(1) 你能把各种图形整理一下吗。圆( )正方形( )三角形( )长方形( ) 正方体( )圆柱( ) 长方体( )\n(2) ( ),( ),( )个数同样多。(3) 圆比正方体的个数少( )个;三角形比长方形的个数少( )个;圆柱比长方体的个数多( )个。", + "options": [], + "answer": "2;3;3;5;3;5;2 正方形;正方体;三角形 1;2;3", + "solution": "【分析】![](images/d652e1ea34b50913aba56693d7a1f0fd.png)本题考查对图形的分类整理.\n【详解】(1)根据图形的形状数一数,填一填.\n![](images/5c807e3405d6f988796369f228665e48.png)\n(2) 正方形,正方体,三角形的个数同样多。 \n(3) 3 - 2 = 1 (个)圆形比正方体的个数少 1 个。5 - 3 = 2 (个)三角形比长方形的个数少2个。5 - 2 = 3 (个)圆柱比长方体的个数多3个。", + "knowledge_points": [ + "\"提问题\"\"填条件\"问题", + "按不同标准分类(单次)" + ], + "source": "21-22一年级下·全国·单元测试" + }, + { + "id": "192", + "unit": "第三单元分类与整理", + "question_type": "解答题", + "difficulty": 0.65, + "question": "数一数,填一填.\n(1) ![](images/4f3f389d9ca2eaac56b50939ff928170.png)\n(2) ( ) 最多, ( ) 和 ( ) 一样多.\n(3) 回答\"多多少,少多少\"的问题.\n(4) 你还能提出什么数学问题并解答。", + "options": [], + "answer": "3;7;3;5 ○;□;△ 4;2 见详解", + "solution": "【分析】根据平面图形的分类和识别知识,按照要求分类统计填表即可。(1) 分别比较每种图形额个数,即可解答;(2) 用多的减去少的,即可求出多多少或少多少;(3) 答案不唯一,如: ○ 和 △ 一共多少个。根据平面图形的分类和识别知识,按照要求分类统计填表即可。注意:在数图形时不能漏数,也不能多数.\n【详解】![](images/2194bf77abcb4d1a8762967925b8abe9.png)\n(1) 7 > 5 > 3;○最多, □ 和 △ 一样多.\n(2) 7 - 3 = 4 (个)5 - 3 = 2 (个);○比 □ 多4个。△比![](images/4f58986d7032ba7fc5b50d3d7537a9df.png) 少2个.\n(3) 答案不唯一,如: ○ 和 △ 一共多少个。 7 + 3 = 10 (个)答: ○ 和 △ 一共 10 个。", + "knowledge_points": [ + "数据的搜集与整理", + "\"提问题\"\"填条件\"问题", + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "21-22一年级下·甘肃天水·期末" + }, + { + "id": "193", + "unit": "第三单元分类与整理", + "question_type": "解答题", + "difficulty": 0.65, + "question": "看图形填空.\n![](images/5ef97fc3f028d3b6139a244026d0c0fe.png)\n(1) 你能把各种图形整理一下吗。\n![](images/82f2dda5e8fa9c744ab9208472407ad5.png)\n(2) ( ) 最少, ( ) 和 ( ) 同样多.\n(3)![](images/e9435a13f39492a025bda41b2ed1bf88.png)比![](images/135d02d73650b583f98bd91c3977cd5f.png)多()个,比![](images/f2bc04e29935b503787bb46fae735ca1a573336cd6628d076fa9f932126b7723.jpg)少()个.\n(4) 你还能提出什么数学问题,并解答。", + "options": [], + "answer": "15;0;15;3;33 □;□;○ 15;0 见详解", + "solution": "【分析】(1)将各个图形数一数并填入表格中即可;(2) 将它们的数量排序后即可求解;(3) 用 □ 的数量减去 □ 的数量;用 □ 减去 ○ 的数量即可;(4) 根据题目提出问题,合理即可,答案不唯一。本题中三个图片一样,数出其中一个图片中各图形的数量即可知道其他的.\n【详解】 (1) □ 有 15 个, □ 有 0 个, ○ 有 15 个, △ 有 3 个;15 + 0 + 15 + 3 = 33 (个)\n\n| 图形 | □ | | ○ | △ | 合计 |\n| ---- | -- | -- | -- | -- | ---- |\n| 个数 | 15 | 0 | 15 | 3 | 33 |\n\n(2) 15 = 15 > 3 > 0,所以 □ 最少, □ 和 ○ 同样多;(3) 15 - 0 = 15 (个) 15 - 15 = 0 (个) \n(4) △ 比口多多少个。(答案不唯一)3 - 0 = 3\n\n答: △ 比口多 3 个。", + "knowledge_points": [ + "\"提问题\"\"填条件\"问题", + "数一数", + "按不同标准分类(单次)", + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "21-22 一年级下·云南保山·期末" + }, + { + "id": "194", + "unit": "第三单元分类与整理", + "question_type": "解答题", + "difficulty": 0.65, + "question": "给这些图形分类.\n![](images/a525d8142695bc98df0e33a7377ff1e0ef4f084806864f63b2e3e90d4abe16ef.jpg)\n(1)按形状分一分.\n\n| | 正方形 | 三角形 | 圆 |\n| ---- | ------ | ------ | -- |\n| 个数 | ( ) | ( ) | ( ) |\n\n(2)按颜色分一分.\n\n| | 白色 | 黑色 |\n| ---- | ---- | ---- |\n| 个数 | ( ) | ( ) |", + "options": [], + "answer": "4;7;5 11;5", + "solution": "【分析】(1)区分出正方形,圆形,三角形,不用管有没有颜色,并数出它们的个数;(2) 区分出黑色图形与白色图形,并数出它们的个数。解答本题的关键是能根据不同的标准来分类物品.\n【详解】(1)根据分析知:正方形有 4 个,三角形有 7 个,圆形有 5 个。(2) 白色图形有 11 个,黑色图形有 5 个。", + "knowledge_points": [ + "按不同标准分类(单次)", + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "21-22 一年级下·湖南常德·期末" + }, + { + "id": "195", + "unit": "第三单元分类与整理", + "question_type": "解答题", + "difficulty": 0.65, + "question": "原来有 5 个,拿走 □ 个,还剩 □ 个.\n![](images/96c28beb61444c8d91e7138d7d71e03f729796ad5582a3755c8dfc265ace0387.jpg)\n![](images/2963dd96a75d94c924bc036616a3811028b1824c3b5205a37c03384e85c38364.jpg)", + "options": [], + "answer": "2;3;3", + "solution": "【分析】由图可知,图上一共有 5 个苹果,小朋友拿走了 2 个,还剩下 (5-2) 个;据此解答。本题考查数一数和 5 以内数的减法计算.\n【详解】由图可知,原来有 5 个,拿走 2 个,还剩 3 个。 5 - 2 = 3 (个)答:还剩 3 个。", + "knowledge_points": [ + "5以内数的减法" + ], + "source": "20-21 一年级下·江西抚州·单元测试" + }, + { + "id": "196", + "unit": "第三单元分类与整理", + "question_type": "解答题", + "difficulty": 0.65, + "question": "观察图形并完成表格和问题.\n![](images/2ede8254a87c5fbcca969a97b9d346b9439c8820830922c6aa2db9f275e5c0f3.jpg)\n(1) 填写表格.\n\n| 图形 | △ | □ | □ | ○ |\n| ---- | -- | -- | -- | -- |\n| 数量 | ( ) | ( ) | ( ) | ( ) |\n\n(2) ○ 比 △ 多( )个.\n(3) 再添上( )个 □ , □ 个数就和 □ 个数一样多了.\n(4) 你还能提出什么数学问题并解答。", + "options": [], + "answer": "1;4;8;12;11;4 见详解", + "solution": "【分析】略\n【详解】略", + "knowledge_points": [ + "比较物体多少", + "按不同标准分类(单次)", + "\"一样多\"问题" + ], + "source": "18-19一年级下·内蒙古呼伦贝尔·期末" + }, + { + "id": "197", + "unit": "第三单元分类与整理", + "question_type": "解答题", + "difficulty": 0.65, + "question": "分一分,填一填.\n![](images/048225bddc63d84701212d699e659e0ecec2fff182561cf3665d1dcbfe8ef63f.jpg)\n(1) 上面的图形按形状分,完成下表.\n\n| | | | | |\n| ---- | ---- | ---- | ---- | ---- |\n| 个数 | | | | |\n\n(2) 如果按颜色分成两组,完成下表.\n\n| | 白色 | 灰色 |\n| ---- | ---- | ---- |\n| 个数 | | |\n\n(3) 说一说你知道了什么信息。", + "options": [], + "answer": "3;3;3;3 6;6", + "solution": "【分析】按形状、颜色分别统计图中图形个数.\n【详解】按形状分各有3个;按颜色分白色、灰色各有6个。白色与灰色个数都同样多。", + "knowledge_points": [ + "按不同标准分类(单次)", + "长方形,正方形,三角形和圆的初步认识" + ], + "source": "19-20一年级下·陕西宝鸡·期末" + }, + { + "id": "198", + "unit": "第三单元分类与整理", + "question_type": "解答题", + "difficulty": 0.65, + "question": "我会分类与整理.\n![](images/cfd4a06f28df94736127888c822eaf869917bea0787eb31450b05ee3a2d0e976.jpg)\n(1) 按卡片的形状来分.\n\n| | 正方形 | 三角形 | 圆 |\n| ---- | ------ | ------ | -- |\n| 张数 | | | |\n\n(2) 按水果的种类来分.\n\n| | 苹果 | 桃 | 香蕉 |\n| ---- | ---- | -- | ---- |\n| 个数 | | | |\n\n(3) 正方形比三角形少 ( ) 个;苹果再添 ( ) 个和桃一样多.\n(4) 你还能提出什么问题并解答。", + "options": [], + "answer": "4;5;3 3;5;4 1;2 见详解", + "solution": "【分析】略\n【详解】略", + "knowledge_points": [ + "按不同标准分类(单次)", + "\"一样多\"问题" + ], + "source": "19-20 一年级下·云南大理·期末" + }, + { + "id": "199", + "unit": "第三单元分类与整理", + "question_type": "解答题", + "difficulty": 0.65, + "question": "填一填.\n![](images/30fe3623df1b67be4f1c7962d4349143b52306591350940a24613787cf771e9b.jpg)\n(1) 填表.\n\n| 图形 | | | | |\n| ---- | ---- | ---- | ---- | ---- |\n| 数量 | | | | |\n\n(2) 涂一涂.\n![](images/2484128d56b64fda8d8b16401a029bf820e9022b104a328e66615c0e8bd218eb.jpg)\n(3) 想一想.\n( )最多,( )最少,□比□多( )个,△比 ○ 少( )个。", + "options": [], + "answer": "5;1;6;2;见图 ○;□;4;4", + "solution": "【详解】略\n\n![](images/0aa5f628c093709bc75526771e9d765f6a9651ab3351901997d7cbd58af20b82.jpg)", + "knowledge_points": [ + "按不同标准分类(单次)" + ], + "source": "19-20一年级下·全国·期末" + }, + { + "id": "200", + "unit": "第三单元分类与整理", + "question_type": "解答题", + "difficulty": 0.65, + "question": "统计下面三种水果的数量.\n![](images/f47e9cef4fb39324a7bb632c1359f14e7a17e317475f5f4e59c2a3fbd99e6f6c.jpg)\n(1) 梨有 ( ) 个,苹果有 ( ) 个,桃有 ( ) 个.\n(2) 苹果比梨多 ( ) 个,桃比梨少 ( ) 个.\n(3) 你能提出什么数学问题。", + "options": [], + "answer": "9;9;4 0;5 见详解", + "solution": "【详解】略", + "knowledge_points": [ + "数据的搜集与整理" + ], + "source": "19-20 一年级下·全国·期末" + } +] diff --git "a/\344\270\200\345\271\264\347\272\247\351\242\230\351\233\206/\344\270\200\345\271\264\347\272\247\344\270\213/\344\270\200\345\271\264\347\272\247\344\270\213\347\254\254\344\272\214\345\215\225\345\205\20320\344\273\245\345\206\205\347\232\204\351\200\200\344\275\215\345\207\217\346\263\225.json" "b/\344\270\200\345\271\264\347\272\247\351\242\230\351\233\206/\344\270\200\345\271\264\347\272\247\344\270\213/\344\270\200\345\271\264\347\272\247\344\270\213\347\254\254\344\272\214\345\215\225\345\205\20320\344\273\245\345\206\205\347\232\204\351\200\200\344\275\215\345\207\217\346\263\225.json" new file mode 100644 index 0000000000000000000000000000000000000000..cfc9e2a0fefe55da23fa30bf17a4c2b99314efcf --- /dev/null +++ "b/\344\270\200\345\271\264\347\272\247\351\242\230\351\233\206/\344\270\200\345\271\264\347\272\247\344\270\213/\344\270\200\345\271\264\347\272\247\344\270\213\347\254\254\344\272\214\345\215\225\345\205\20320\344\273\245\345\206\205\347\232\204\351\200\200\344\275\215\345\207\217\346\263\225.json" @@ -0,0 +1,7892 @@ +[ + { + "id": "1", + "unit": "20以内的退位减法1", + "question_type": "选择题", + "difficulty": 0.85, + "question": "科技展览上,机器人甲完成了14个任务,机器人乙比机器人甲少完成7个,那么机器人乙完成了()个任务。", + "options": [ + "A. 7", + "B. 8", + "C. 9" + ], + "answer": "A", + "solution": "【分析】机器人甲完成了14个任务,机器人乙比甲少完成7个,因此乙的任务数为甲的任务数减去7.\n【详解】机器人乙完成的任务数为:14 - 7 = 7(个)。故答案为:A.", + "knowledge_points": [ + "十几减 7,6 的退位减法" + ], + "source": "24-25 一年级下·河北石家庄·期中" + }, + { + "id": "2", + "unit": "20以内的退位减法1", + "question_type": "选择题", + "difficulty": 0.85, + "question": "下面算式中,( )的结果大于10。", + "options": [ + "A. 12 - 5", + "B. 9 + 2", + "C. 14 - 5" + ], + "answer": "B", + "solution": "【分析】根据选项中给出的算式,计算每个选项的结果,再与10进行比较,判断是否大于10.\n【详解】.12-5=7,7<10,此选项不符合题意;B.9+2=11,11>10,此选项符合题意;C.14-5=9,9<10,此选项不符合题意。故答案为:B.", + "knowledge_points": [ + "十几减 5~2 的退位减法", + "9 加几的进位加法" + ], + "source": "24-25 一年级下·河北石家庄·期中" + }, + { + "id": "3", + "unit": "20以内的退位减法1", + "question_type": "选择题", + "difficulty": 0.65, + "question": "\"小玲有12个苹果,她吃掉了一些后还剩下9个.\"能表示出这道题的数量关系的算式是()。", + "options": [ + "A. 12 + 9 = □", + "B. 9 = 12 + □", + "C. 12 - □ = 9", + "D. 9 - □ = 12" + ], + "answer": "C", + "solution": "【分析】小玲有12个苹果,她吃掉了一些后还剩下9个。那么总共的个数 - 吃掉的个数 = 还剩的个数,这里吃掉的个数未知,用\"□\"表示.\n【详解】由分析可知:\"小玲有12个苹果,她吃掉了一些后还剩下9个.\"能表示出这道题的数量关系的算式是12 - □ = 9。故答案为:C.", + "knowledge_points": [ + "十几减9的退位减法" + ], + "source": "23-24 三年级下·重庆九龙坡·期末" + }, + { + "id": "4", + "unit": "20以内的退位减法1", + "question_type": "选择题", + "difficulty": 0.85, + "question": "航航有15个气球,比璐璐多8个,璐璐有( )个。", + "options": [ + "A. 23", + "B. 7", + "C. 22" + ], + "answer": "B", + "solution": "【分析】根据减法的意义,求比一个数少多少的数,用减法计算,用航航有的气球的数量减去8即可求出璐璐有的气球的数量.\n【详解】15 - 8 = 7(个),所以璐璐有7个。故答案为:B.", + "knowledge_points": [ + "十几减8的退位减法" + ], + "source": "22-23 二年级上·河南商丘·期中" + }, + { + "id": "5", + "unit": "20以内的退位减法1", + "question_type": "选择题", + "difficulty": 0.65, + "question": "小羊有12棵白菜,小兔有4棵白菜,如果小羊给小兔( )棵白菜,它们的白菜就同样多了。", + "options": [ + "A. 4", + "B. 5", + "C. 8" + ], + "answer": "A", + "solution": "【分析】先用小羊的白菜数量减去小兔的白菜数量,求出差,再把这个差平均分成2份,把其中的1份给小兔,那么它们的白菜就同样多了.\n【详解】12 - 4 = 8(棵);4 + 4 = 8(棵);所以如果小羊给小兔4棵白菜,它们的白菜就同样多了。故答案为:A.", + "knowledge_points": [ + "十几减 5~2 的退位减法", + "8,9 的加减法" + ], + "source": "23-24 一年级下·湖北孝感·期末" + }, + { + "id": "6", + "unit": "20以内的退位减法1", + "question_type": "选择题", + "difficulty": 0.85, + "question": "用13根同样长的小棒摆一个![](images/2025-12-14%20001758.jpg),还剩( )根小棒。", + "options": [ + "A. 7", + "B. 6", + "C. 5" + ], + "answer": "A", + "solution": "【分析】已知摆一个六边形需要6根小棒,根据减法的意义,用13 - 6即可得出还剩多少根小棒.\n【详解】13 - 6 = 7(根),所以还剩7根小棒。故答案为:A.", + "knowledge_points": [ + "十几减 7,6 的退位减法" + ], + "source": "23-24 一年级下·河南南阳·期末" + }, + { + "id": "7", + "unit": "20以内的退位减法1", + "question_type": "选择题", + "difficulty": 0.85, + "question": "小新在做一道减法算式时,先算10 - 5 = 5,再算5 + 1 = 6,他计算的算式是()。", + "options": [ + "A. 11 - 5", + "B. 15 - 5", + "C. 11 - 6" + ], + "answer": "A", + "solution": "【分析】根据选项中给出的算式,逐一分析,找出符合题意的算式.\n【详解】. 计算11 - 5时,先算10 - 5 = 5,再算5 + 1 = 6;B. 计算15 - 5时,先算5 - 5 = 0,再算10 + 0 = 10;C. 计算11 - 6时,先算10 - 6 = 4,再算4 + 1 = 5。即,小新在做一道减法算式时,先算10 - 5 = 5,再算5 + 1 = 6,他计算的算式是11 - 5。故答案为:A.", + "knowledge_points": [ + "十几减 5~2 的退位减法", + "十几减 7,6 的退位减法" + ], + "source": "23-24 一年级下·河南南阳·期末" + }, + { + "id": "8", + "unit": "20以内的退位减法1", + "question_type": "选择题", + "difficulty": 0.85, + "question": "李大爷家养了15只鸡,其中公鸡有6只,母鸡有多少只。( )", + "options": [ + "A. 9", + "B. 14", + "C. 2" + ], + "answer": "A", + "solution": "【分析】根据减法的意义,鸡的总数量 - 公鸡的数量 = 母鸡的数量.\n【详解】15 - 6 = 9(只),母鸡有9只。故答案为:A.", + "knowledge_points": [ + "十几减 7,6 的退位减法" + ], + "source": "23-24 一年级下·山东临沂·期末" + }, + { + "id": "9", + "unit": "20以内的退位减法1", + "question_type": "选择题", + "difficulty": 0.85, + "question": "小红有12本书,小青有4本书,小红给小青( )本书,两人的书就一样多了。", + "options": [ + "A. 2", + "B. 3", + "C. 5", + "D. 4" + ], + "answer": "D", + "solution": "【分析】根据题意,小红书的数量 - 小青书的数量 = 小红比小青多的数量,将多的数量分成同样多的两份,其中一份给小青,两人的书就一样多了.\n【详解】12 - 4 = 8(本),8可以分成4和4。即12 - 4 = 8(本),4 + 4 = 8(本),小红给小青4本书,两人的书就一样多了。故答案为:D.", + "knowledge_points": [ + "十几减 5~2 的退位减法", + "8,9 的加减法" + ], + "source": "23-24 一年级下·甘肃平凉·期末" + }, + { + "id": "10", + "unit": "20以内的退位减法1", + "question_type": "选择题", + "difficulty": 0.65, + "question": "哥哥今年12岁,妹妹去年6岁,哥哥比妹妹大几岁。( )", + "options": [ + "A. 4", + "B. 5", + "C. 6" + ], + "answer": "B", + "solution": "【分析】先求出妹妹今年的岁数,再用哥哥今年的岁数减去妹妹今年的岁数就是哥哥比妹妹大几岁.\n【详解】妹妹去年6岁,则妹妹今年是6 + 1 = 7(岁),12 - 7 = 5(岁),哥哥比妹妹大5岁。故答案为:.解答本题关键注意哥哥和妹妹的年龄差不变。", + "knowledge_points": [ + "年龄问题", + "十几减 7,6 的退位减法", + "7 的加减法" + ], + "source": "23-24 一年级下·河南南阳·期末" + }, + { + "id": "11", + "unit": "20以内的退位减法1", + "question_type": "选择题", + "difficulty": 0.85, + "question": "鸡有17只,鸭有10只,母鸡有8只。公鸡有( )只。", + "options": [ + "A. 7", + "B. 2", + "C. 9" + ], + "answer": "C", + "solution": "【分析】用鸡的总数量减去母鸡的数量,求出差,就是公鸡的数量.\n【详解】17 - 8 = 9(只),即鸡有17只,鸭有10只,母鸡有8只,公鸡有9只。故答案为:C.", + "knowledge_points": [ + "十几减8的退位减法" + ], + "source": "22-23 一年级下·甘肃天水·期中" + }, + { + "id": "12", + "unit": "20以内的退位减法1", + "question_type": "选择题", + "difficulty": 0.65, + "question": "有12朵花,先剪掉3朵,再剪掉4朵,还剩( )朵花。", + "options": [ + "A. 9", + "B. 5", + "C. 6" + ], + "answer": "B", + "solution": "【分析】用花的总数依次减去剪掉的花即可得到还剩的花.\n【详解】花的总数:12朵,先剪3朵,再剪4朵,还剩:12 - 3 - 4 = 5(朵),还剩5朵花。故答案为:B.", + "knowledge_points": [ + "连减 (20以内)" + ], + "source": "23-24 一年级下·贵州铜仁·期末" + }, + { + "id": "13", + "unit": "20以内的退位减法1", + "question_type": "选择题", + "difficulty": 0.65, + "question": "学校买来18个篮球,( ),还剩多少个篮球。缺少的信息是( )。", + "options": [ + "A. 拿走了9个篮球", + "B. 拿来了9个篮球", + "C. 拿走了9个排球" + ], + "answer": "A", + "solution": "【分析】根据题意,问还剩多少个篮球,需要知道拿走了多少个篮球,所以缺少的信息是拿走了9个篮球.\n【详解】学校买来18个篮球,(),还剩多少个篮球。缺少的信息是拿走了9个篮球。故答案为:A.", + "knowledge_points": [ + "\"提问题\"\"填条件\"问题", + "十几减9的退位减法" + ], + "source": "23-24 一年级下·河北保定·期末" + }, + { + "id": "14", + "unit": "20以内的退位减法1", + "question_type": "选择题", + "difficulty": 0.85, + "question": "把11块糖放在两个盘子里,每个盘子都不能空,有( )种放法。", + "options": [ + "A. 10", + "B. 9", + "C. 11" + ], + "answer": "A", + "solution": "【分析】解题时,可以实际摆一摆,把盘子分成左右两个,左边放1个,右边放10个;左边放2个,右边放9个;左边放3个,右边放8个,以此类推,左边一直放到10个,共有多少种放法.\n【详解】一个盘子放1个,另一个放10个;一个盘子放2个,另一个放9个;一个盘子放3个,另一个放8个;一个盘子放4个,另一个放7个;一个盘子放5个,另一个放6个;一个盘子放6个,另一个放5个;一个盘子放7个,另一个放4个;一个盘子放8个,另一个放3个;一个盘子放9个,另一个放2个;一个盘子放10个,另一个放1个。一共放了10次,即10种放法。故答案为:A.", + "knowledge_points": [ + "十几减 5~2 的退位减法" + ], + "source": "23-24 一年级下·山东济南·期末" + }, + { + "id": "15", + "unit": "20以内的退位减法1", + "question_type": "选择题", + "difficulty": 0.65, + "question": "停车场里有12辆小汽车,( ),还剩下几辆小汽车。缺少的信息可能是( )。", + "options": [ + "A. 有8辆大客车", + "B. 开走了3辆小汽车", + "C. 又开来了4辆大客车" + ], + "answer": "B", + "solution": "【分析】已知停车场里有12辆小汽车,求还剩下几辆小汽车,就是两个数的差,用减法计算,要解决这一问题,还要知道开走了几辆小汽车.\n【详解】A.\"有8辆大客车\",此条件加入题中,无法解决\"还剩几辆小汽车\"的问题;B.\"开走了3辆小汽车\",此条件加入题中,可以用减法解决\"还剩几辆小汽车\"的问题;C.\"又开来了4辆大客车\",此条件加入题中,无法解决\"还剩几辆小汽车\"的问题。即,停车场里有12辆小汽车,(),还剩下几辆小汽车。缺少的信息可能是:开走了3辆小汽车。故答案为:B.", + "knowledge_points": [ + "十几减 5~2 的退位减法", + "\"提问题\" \"填条件\"问题" + ], + "source": "23-24 一年级下·青海果洛·期末" + }, + { + "id": "16", + "unit": "20以内的退位减法1", + "question_type": "选择题", + "difficulty": 0.85, + "question": "有16人要来操场踢球,现在来了9人。一年级队踢进了10个球。还有几人没来。要解决这个问题,不需要的信息是()。", + "options": [ + "A. 一年级队踢进了10个球", + "B. 有16人要来操场踢球", + "C. 现在来了9人" + ], + "answer": "A", + "solution": "【分析】要求一年级还有几个人没来,用要来的总人数减去来了的总人数即可得出答案.\n【详解】16 - 9 = 7(人),所以还有7人没来。用到的信息是:有16人要来操场踢球和现在来了9人。不需要的信息是:一年级队踢进了10个球。故答案为:A.", + "knowledge_points": [ + "十几减9的退位减法" + ], + "source": "23-24 一年级下·山东菏泽·期末" + }, + { + "id": "17", + "unit": "20以内的退位减法1", + "question_type": "选择题", + "difficulty": 0.85, + "question": "奶奶家有12只鸡和7只鸭,其中公鸡有3只,母鸡有( )只。", + "options": [ + "A. 4", + "B. 9", + "C. 16" + ], + "answer": "B", + "solution": "【分析】根据减法的意义,鸡的总数量 - 公鸡的数量 = 母鸡的数量.\n【详解】12 - 3 = 9(只),母鸡有9只。故答案为:B.", + "knowledge_points": [ + "十几减 5~2 的退位减法" + ], + "source": "23-24 一年级下·山东菏泽·期末" + }, + { + "id": "18", + "unit": "20以内的退位减法1", + "question_type": "选择题", + "difficulty": 0.65, + "question": "要使算式\"○-9<5\"成立,\"○\"里最大可以填( )。", + "options": [ + "A. 13", + "B. 14", + "C. 9" + ], + "answer": "A", + "solution": "【分析】本题考查20以内减法的计算及应用。把各选项代入计算即可解答.\n【详解】.13-9=4,4<5,符合题意;.14-9=5,5=5,不符合题意;.9不是最大可填的数,不符合题意。故答案为:A.", + "knowledge_points": [ + "十几减9的退位减法" + ], + "source": "23-24 一年级下·河北衡水·期末" + }, + { + "id": "19", + "unit": "20以内的退位减法1", + "question_type": "选择题", + "difficulty": 0.65, + "question": "14-□>5,□里最大填( )。", + "options": [ + "A. 7", + "B. 8", + "C. 9" + ], + "answer": "B", + "solution": "【分析】左侧算式大于5,要想\"□\"里填的数最大,则左侧算式的结果是比5大的数中最小的数,也就是6,由此解答.\n【详解】令14 - □ = 6,可转换为14 - 6 = 8,□ 里最大填8。故答案为:B.", + "knowledge_points": [ + "十几减 7,6 的退位减法", + "10 以内数的比大小" + ], + "source": "23-24 一年级下·湖南怀化·期末" + }, + { + "id": "20", + "unit": "20以内的退位减法1", + "question_type": "选择题", + "difficulty": 0.85, + "question": "永定红柿是龙岩市永定区特产,也是国家农产品的地理标志。妈妈买了13个红柿,()。要用减法解决问题\"还剩几个红柿\",横线上要填的信息是( )。", + "options": [ + "A. 后来又买了5个", + "B. 还买了5个橘子", + "C. 还剩下5个红柿", + "D. 送给了奶奶5个" + ], + "answer": "D", + "solution": "【分析】根据减法的意义可知,求剩下的红柿数量,也就是从总数量里去掉了一部分,已经知道了买的红柿的总数量,要知道的是去掉的那一部分数量.\n【详解】妈妈买的红柿数量 - 送给奶奶的数量 = 还剩的数量。横线上要填的信息应是\"送给了奶奶5个\"。故答案为:D.", + "knowledge_points": [ + "十几减 5~2 的退位减法", + "\"提问题\" \"填条件\"问题" + ], + "source": "23-24 一年级下·福建龙岩·期末" + }, + { + "id": "21", + "unit": "20以内的退位减法1", + "question_type": "选择题", + "difficulty": 0.85, + "question": "哥哥有12支铅笔,月月有8支铅笔,哥哥要给月月( )支铅笔,他们的铅笔就可以一样多。", + "options": [ + "A. 2", + "B. 4", + "C. 8" + ], + "answer": "A", + "solution": "【分析】根据减法的意义,用12 - 8先算出哥哥比月月多几支铅笔,再将得出的铅笔差值分成两份相等的数量.\n【详解】12 - 8 = 4(支),4可以分成2和2,所以哥哥要给月月2支铅笔,他们的铅笔就可以一样多。故答案为:A.", + "knowledge_points": [ + "5 以内数的分与合(组成)", + "十几减8的退位减法" + ], + "source": "23-24 一年级下·河南三门峡·期末" + }, + { + "id": "22", + "unit": "20以内的退位减法1", + "question_type": "选择题", + "difficulty": 0.85, + "question": "兰兰有14元钱,红红8元钱,兰兰再给红红( )元钱,两人就一样多。", + "options": [ + "A. 6", + "B. 3", + "C. 4" + ], + "answer": "B", + "solution": "【分析】根据题意可知:求出兰兰比红红多的数量,然后把多的数量分成一样的两份,即是要给红红的钱数.\n【详解】14 - 8 = 6(元),6 = 3 + 3,则兰兰再给红红3元钱,两人就一样多。故答案为:B.", + "knowledge_points": [ + "十几减8的退位减法" + ], + "source": "23-24 一年级下·湖南株洲·期末" + }, + { + "id": "23", + "unit": "20以内的退位减法1", + "question_type": "选择题", + "difficulty": 0.65, + "question": "计算\"还剩多少个足球\",需要用到的信息是( )。", + "options": [ + "A. ①和③", + "B. ②和④", + "C. ①和④", + "D. ②和③" + ], + "answer": "B", + "solution": "【分析】求还剩多少个足球,也就是从原有的足球数量里去掉了一部分,所以需要知道原来的数量和去掉的那一部分数量.\n【详解】① 体育室有12个篮球;② 体育室有12个足球;③ 又买来了5个篮球;④ 借走了5个足球。由分析可知,需要用到的信息是\"② 体育室有12个足球\"和\"④ 借走了5个足球\",也就是选择②和④。故答案为:B.", + "knowledge_points": [ + "十几减 5~2 的退位减法", + "\"提问题\"\"填条件\"问题" + ], + "source": "23-24 一年级下·广东东莞·期末" + }, + { + "id": "24", + "unit": "20以内的退位减法1", + "question_type": "选择题", + "difficulty": 0.65, + "question": "计算13 - 4时,与下图表示的思考过程相同的是( )。![](images/249691f75f89db738f6fa51a3eb9d7d779a4f274f9584eec929da8d68f921d9f.jpg)", + "options": [ + "A. 4 + 9 = 13;13 - 4 = 9", + "B. 13 - 3 = 10;10 - 1 = 9", + "C. 10 - 4 = 6;6 + 3 = 9" + ], + "answer": "C", + "solution": "【分析】观察图可以发现,计算时先从10个里面减去4个,再把剩下的部分相加.\n【详解】A 与本图思考过程不相同,错误;B 与本图思考过程不相同,错误;C 本图是先从10个里面减去4个,再加上右边的3个。10 - 4 = 6,6 + 3 = 9,正确。故答案为:C.", + "knowledge_points": [ + "十几减 5~2 的退位减法", + "6 的加减法", + "10 的加减法" + ], + "source": "23-24 一年级下·河南濮阳·期末" + }, + { + "id": "25", + "unit": "20以内的退位减法1", + "question_type": "选择题", + "difficulty": 0.65, + "question": "把12个梨放到2个袋子里,一个袋子里放3个,另一个袋子里放多少个。下列算式正确的是( )。", + "options": [ + "A. 12 - 2", + "B. 12 - 3", + "C. 12 - 2 - 3" + ], + "answer": "B", + "solution": "【分析】梨的总数量减去一个袋子里梨的数量就是另一个袋子的梨的数量.\n【详解】根据分析列式如下:12 - 3 = 9(个),即另一个袋子里放9个。故答案为:B.", + "knowledge_points": [ + "十几减 5~2 的退位减法" + ], + "source": "23-24 一年级下·福建三明·期末" + }, + { + "id": "26", + "unit": "20以内的退位减法1", + "question_type": "选择题", + "difficulty": 0.85, + "question": "李奶奶家有14只鸡和5只鸭。公鸡有6只,母鸡有几只。要解决这个问题,不需要的信息是( )。", + "options": [ + "A. 14只鸡", + "B. 5只鸭", + "C. 公鸡有6只" + ], + "answer": "B", + "solution": "【分析】求母鸡有几只,根据减法的意义,鸡的总数量 - 公鸡的数量 = 母鸡的数量.\n【详解】列式为14 - 6 = 8(只)。需要的信息是鸡的总数量和公鸡的数量,不需要的是鸭的数量。故答案为:B.", + "knowledge_points": [ + "十几减 7,6 的退位减法" + ], + "source": "23-24 一年级下·河南郑州·期末" + }, + { + "id": "27", + "unit": "20以内的退位减法1", + "question_type": "选择题", + "difficulty": 0.85, + "question": "有15只鸡和6只鸭,公鸡有7只,母鸡有( )只。", + "options": [ + "A. 9", + "B. 8", + "C. 22" + ], + "answer": "B", + "solution": "【分析】用鸡的总数量减去公鸡的数量,求出差,就是母鸡的数量.\n【详解】15 - 7 = 8(只),即母鸡有8只。故答案为:B.", + "knowledge_points": [ + "十几减 7,6 的退位减法" + ], + "source": "22-23 一年级下·山西长治·期中" + }, + { + "id": "28", + "unit": "20以内的退位减法1", + "question_type": "填空题", + "difficulty": 0.85, + "question": "在绿色出行活动中,第一天有12人步行上学,第二天比第一天少3人,第二天有( )人步行上学。", + "options": [], + "answer": "9", + "solution": "【分析】根据题意,第一天有12人步行上学,第二天比第一天少3人,第二天的人数等于第一天的人数减去3人,用减法计算即可.\n【详解】12 - 3 = 9(人),所以,在绿色出行活动中,第一天有12人步行上学,第二天比第一天少3人,第二天有9人步行上学。", + "knowledge_points": [ + "十几减 5~2 的退位减法" + ], + "source": "24-25 一年级下·河北石家庄·期中" + }, + { + "id": "29", + "unit": "20以内的退位减法1", + "question_type": "填空题", + "difficulty": 0.85, + "question": "在算式17 - 9 = 8中,( )是减数。", + "options": [], + "answer": "9", + "solution": "【分析】在减法算式中,减号前面的数是被减数,减号后面的数是减数,结果是差,被减数 - 减数 = 差.\n【详解】在算式17 - 9 = 8中,9是减数。", + "knowledge_points": [ + "十几减9的退位减法" + ], + "source": "24-25 一年级下·内蒙古鄂尔多斯·期中" + }, + { + "id": "30", + "unit": "20以内的退位减法1", + "question_type": "填空题", + "difficulty": 0.65, + "question": "12比8多( ),12比19少( )。", + "options": [], + "answer": "4;7", + "solution": "【分析】求一个数比另一个数多多少用减法计算;求一个数比另一个数少多少也用减法计算.\n【详解】12 - 8 = 4;19 - 12 = 7.12比8多4,12比19少7。", + "knowledge_points": [ + "谁比谁多/少几的问题", + "十几减8的退位减法" + ], + "source": "23-24 二年级下·广东汕头·期中" + }, + { + "id": "31", + "unit": "20以内的退位减法1", + "question_type": "填空题", + "difficulty": 0.65, + "question": "在括号里填上\">\"\"<\"或\"=\"。\n10+2( )12;15-3( )15;11+5( )11-5;13-3( )8+2。", + "options": [], + "answer": "=;<;>;=", + "solution": "【分析】根据整数加减法的计算法则,依次计算出各算式的结果再比较大小。20以内数从大到小的关系为:20>19>18>17>16>15>14>13>12>11>10>9>8>7>6>5>4>3>2>1>0,由此比较.\n【详解】10+2=12;15-3=12,12<15,则15-3<15;11+5=16,11-5=6,16>6,则11+5>11-5;13-3=10,8+2=10,10=10,则13-3=8+2。", + "knowledge_points": [ + "不进位加法(20以内)", + "不退位减法(20以内)", + "20 以内数的比大小", + "十几减 5~2 的退位减法" + ], + "source": "24-25 一年级上·全国·单元测试" + }, + { + "id": "32", + "unit": "20以内的退位减法1", + "question_type": "填空题", + "difficulty": 0.85, + "question": "在括号里填上合适的数。5 + ( )= 13;( )+ 6 = 15;( )+ 3 = 11;( )+ 9 = 17;8 + 6 = 5 + ( );7 + 5 = ( )+ 3;4 + ( )= 10 + 3。", + "options": [], + "answer": "8;9;8;8;9;9;9", + "solution": "【分析】根据\"加数 = 和 - 另一个加数\"及整数加减法的计算法则来解决此题.\n【详解】13 - 5 = 8,所以5 + 8 = 13;15 - 6 = 9,所以9 + 6 = 15;11 - 3 = 8,所以8 + 3 = 11;17 - 9 = 8,所以8 + 9 = 17;8 + 6 = 14,14 - 5 = 9,所以8 + 6 = 5 + 9;7 + 5 = 12,12 - 3 = 9,所以7 + 5 = 9 + 3;10 + 3 = 13,13 - 4 = 9,所以4 + 9 = 10 + 3。", + "knowledge_points": [ + "5~2 加几的进位加法", + "十几减 5~2 的退位减法", + "十几减9的退位减法", + "十几减7,6的退位减法" + ], + "source": "24-25 一年级上·全国·课后作业" + }, + { + "id": "33", + "unit": "20以内的退位减法1", + "question_type": "填空题", + "difficulty": 0.85, + "question": "14位同学排成一队做操,笑笑的前面有7人,笑笑的后面有( )人。", + "options": [], + "answer": "6", + "solution": "【分析】根据题意,总人数 - 笑笑前面的人数 - 笑笑自己 = 笑笑后面的人数.\n【详解】14 - 7 - 1 = 6(人),14位同学排成一队做操,笑笑的前面有7人,笑笑的后面有6人。", + "knowledge_points": [ + "连减 (20以内)" + ], + "source": "23-24 一年级下·福建福州·期末" + }, + { + "id": "34", + "unit": "20以内的退位减法1", + "question_type": "填空题", + "difficulty": 0.65, + "question": "16个小朋友排队,玲玲前面有7人,后面有( )人。", + "options": [], + "answer": "8", + "solution": "【分析】用排队的总人数减去玲玲前面的人数,求出差,再减去1(玲玲自己),求出差,就是玲玲后面的人数.\n【详解】16 - 7 - 1 = 9 - 1 = 8(人),即16个小朋友排队,玲玲前面有7人,后面有8人。", + "knowledge_points": [ + "连减 (20以内)" + ], + "source": "23-24 一年级下·福建莆田·期末" + }, + { + "id": "35", + "unit": "20以内的退位减法1", + "question_type": "填空题", + "difficulty": 0.85, + "question": "两队进行拔河比赛,第一队有12人,第二队有8人。要使比赛公平,需要第一队减少( )人。", + "options": [], + "answer": "4", + "solution": "【分析】要使拔河比赛公平,就需要两队的人数一样多;故,用第一队的人数减去第二队的人数,求出差,即可解决.\n【详解】12 - 8 = 4(人),即两队进行拔河比赛,第一队有12人,第二队有8人,要使比赛公平,需要第一队减少4人。", + "knowledge_points": [ + "十几减8的退位减法" + ], + "source": "23-24 一年级下·山东临沂·期末" + }, + { + "id": "36", + "unit": "20以内的退位减法1", + "question_type": "填空题", + "difficulty": 0.65, + "question": "小兔有12棵白菜,小羊有4棵白菜,如果小兔给小羊( )棵白菜,那么它们的白菜就同样多了。", + "options": [], + "answer": "4", + "solution": "【分析】先用小兔的白菜数量减去小羊的白菜数量,求出差,再把这个差平均分成2份,把其中的1份给小羊,那么它们的白菜就同样多了.\n【详解】12 - 4 = 8(棵),8棵 = 4棵 + 4棵,即小兔有12棵白菜,小羊有4棵白菜,如果小兔给小羊4棵白菜,那么它们的白菜就同样多了。", + "knowledge_points": [ + "十几减 5~2 的退位减法", + "8,9 的加减法" + ], + "source": "23-24 一年级下·山东临沂·期末" + }, + { + "id": "37", + "unit": "20以内的退位减法1", + "question_type": "填空题", + "difficulty": 0.65, + "question": "我会比大小,在括号内填上\">\"\"<\"或\"=\"。\n16( )5+10;5( )9-3;13-6( )7;18( )9+9。", + "options": [], + "answer": ">;<;=;=", + "solution": "【分析】(1)将5+10的结果计算出来,再与16进行比较;(2)将9-3的结果计算出来,再与5进行比较;(3)将13-6的结果计算出来,再与7进行比较;(4)将9+9的结果计算出来,再与18进行比较.\n【详解】(1)5+10=15,16>15,所以16>5+10;(2)9-3=6,5<6,所以5<9-3;(3)13-6=7,7=7,所以13-6=7;(4)9+9=18,18=18,所以18=9+9。", + "knowledge_points": [ + "十几减 7,6 的退位减法", + "8,9 的加减法", + "9 加几的进位加法" + ], + "source": "22-23 一年级下·广东汕尾·期中" + }, + { + "id": "38", + "unit": "20以内的退位减法1", + "question_type": "填空题", + "difficulty": 0.85, + "question": "把12个足球分给两个年级,一个年级分2个,另一个年级分( )个。", + "options": [], + "answer": "10", + "solution": "【分析】根据题意可知,要把足球分给2个年级,足球一共12个,其中一个年级分了2个,用总的足球数减去分走的2个即可得出答案.\n【详解】12-2=10(个),故另一个年级分10个。", + "knowledge_points": [ + "不退位减法 (20以内)" + ], + "source": "23-24 二年级下·甘肃平凉·期末" + }, + { + "id": "39", + "unit": "20以内的退位减法1", + "question_type": "填空题", + "difficulty": 0.65, + "question": "从4,2,9这三个数中任意选取其中的两个数求和,得数有( )种可能,其中最大的和与最小的和相差( )。", + "options": [], + "answer": "3;7", + "solution": "【分析】将这三个数,两两相加,数出得数有几种可能;然后取求出的最大的和和最小的和进行相减即可.\n【详解】选取4,2的和为:4 + 2 = 6;选取4,9的和为:4 + 9 = 13;选取2,9的和为:9 + 2 = 11。结果有3种可能,其中最大的和是13,最小的和是6;13 - 6 = 7;最大的和与最小的和相差7;所以从4,2,9这三个数中任意选取其中的两个数求和,得数有3种可能,其中最大的和与最小的和相差7。", + "knowledge_points": [ + "十几减7,6的退位减法", + "9加几的进位加法" + ], + "source": "23-24 二年级上·福建莆田·期末" + }, + { + "id": "40", + "unit": "20以内的退位减法1", + "question_type": "填空题", + "difficulty": 0.65, + "question": "17个小朋友站成一排做操,从左数可可排在第8位,从右数她排在第( )位。", + "options": [], + "answer": "10", + "solution": "【分析】17个小朋友站成一排做操,从左数可可排在第8位,她的右边还有17 - 8 = 9(个)人,则从右边数可可排在第9 + 1 = 10(位),据此得出结论即可.\n【详解】17 - 8 + 1 = 9 + 1 = 10(位),故从右数她排在第10位。", + "knowledge_points": [ + "加减混合运算 (20 以内)" + ], + "source": "23-24 一年级下·湖北黄冈·期末" + }, + { + "id": "41", + "unit": "20以内的退位减法1", + "question_type": "填空题", + "difficulty": 0.65, + "question": "△有15个,□有9个,△比□多( )个,□比△少( )个。", + "options": [], + "answer": "6;6", + "solution": "【分析】用△的个数减去□的个数,即可求出△比□多几个;△比□多几个,□就比△少几个,据此解答即可.\n【详解】15 - 9 = 6(个),△比□多6个,□比△少6个。", + "knowledge_points": [ + "十几减9的退位减法" + ], + "source": "22-23 一年级下·甘肃天水·期中" + }, + { + "id": "42", + "unit": "20以内的退位减法1", + "question_type": "填空题", + "difficulty": 0.85, + "question": "9 + 6 = ( ),把它改写成两道减法算式,分别是( )和( )。", + "options": [], + "answer": "15;15-9=6;15-6=9", + "solution": "【分析】先根据整数加减法的计算法则算出结果,然后根据\"加数 = 和 - 另一个加数\"来写出两道减法算式即可.\n【详解】由题意分析得:9 + 6 = 15,把它改写成两道减法算式,分别是15 - 9 = 6和15 - 6 = 9。", + "knowledge_points": [ + "十几减9的退位减法", + "十几减 7,6 的退位减法", + "9 加几的进位加法" + ], + "source": "22-23 一年级下·甘肃天水·期中" + }, + { + "id": "43", + "unit": "20以内的退位减法1", + "question_type": "填空题", + "difficulty": 0.85, + "question": "14名同学排队,小林前面有5人,小林后面有( )人。", + "options": [], + "answer": "8", + "solution": "【分析】根据题意,总人数 - 小林前面的人数 - 小林 = 小林后面的人数.\n【详解】14 - 5 - 1 = 8(人),14名同学排队,小林前面有5人,小林后面有8人。", + "knowledge_points": [ + "连减 (20以内)" + ], + "source": "22-23 一年级下·江西宜春·期中" + }, + { + "id": "44", + "unit": "20以内的退位减法1", + "question_type": "填空题", + "difficulty": 0.85, + "question": "12与8的差是( )。", + "options": [], + "answer": "4", + "solution": "【分析】求两个数的差是多少,用减法列式计算.\n【详解】12 - 8 = 4,即12与8的差是4。", + "knowledge_points": [ + "十几减8的退位减法" + ], + "source": "22-23 一年级下·山东菏泽·阶段练习" + }, + { + "id": "45", + "unit": "20以内的退位减法1", + "question_type": "填空题", + "difficulty": 0.85, + "question": "两个数的和是18,其中一个加数是9,另一个加数是( )。", + "options": [], + "answer": "9", + "solution": "【分析】根据\"和 - 一个加数 = 另一个加数\"计算即可.\n【详解】18 - 9 = 9。两个数的和是18,其中一个加数是9,另一个加数是9。", + "knowledge_points": [ + "十几减9的退位减法" + ], + "source": "23-24 一年级下·浙江嘉兴·期末" + }, + { + "id": "46", + "unit": "20以内的退位减法1", + "question_type": "填空题", + "difficulty": 0.65, + "question": "小明有18颗糖,小红有4颗糖,小明给小红( )颗糖,两人的糖就一样多。用算式表示为:18 - ( )= 4 + ( )。", + "options": [], + "answer": "7;7;7", + "solution": "【分析】要使两人的糖一样多,小明给小红的颗数=小明比小红多的颗数的一半。先用减法计算出小明比小红多几颗,再将多的数量分成相等的两部分即可.\n【详解】18-4=14(颗),14可以分成7和7。小明给小红7颗糖,两人的糖就一样多。用算式表示为:18-7=4+7。", + "knowledge_points": [ + "不退位减法(20以内)", + "5~2 加几的进位加法", + "十几减7,6的退位减法" + ], + "source": "23-24 一年级下·浙江台州·期末" + }, + { + "id": "47", + "unit": "20以内的退位减法1", + "question_type": "填空题", + "difficulty": 0.85, + "question": "13比6多( ),9比17少( )。", + "options": [], + "answer": "7;8", + "solution": "【分析】求一个数比另一个数多(或少)几,用减法计算。据此解答.\n【详解】13 - 6 = 7;17 - 9 = 8.13比6多7,9比17少8。", + "knowledge_points": [ + "十几减9的退位减法", + "十几减7,6的退位减法" + ], + "source": "23-24 一年级下·江西九江·期末" + }, + { + "id": "48", + "unit": "20以内的退位减法1", + "question_type": "填空题", + "difficulty": 0.85, + "question": "有16支铅笔,插在2个笔筒里,一个笔筒插7支,另一个笔筒插( )支。", + "options": [], + "answer": "9", + "solution": "【分析】用铅笔的总数量减去一个笔筒里插的数量,求出差,就是另一个笔筒插的数量;据此解决.\n【详解】16 - 7 = 9(支),即有16支铅笔,插在2个笔筒里,一个笔筒插7支,另一个笔筒插9支。", + "knowledge_points": [ + "十几减 7,6 的退位减法" + ], + "source": "23-24 二年级下·山东菏泽·期末" + }, + { + "id": "49", + "unit": "20以内的退位减法1", + "question_type": "填空题", + "difficulty": 0.65, + "question": "有15个苹果,每6个苹果装一盒,一共可以装满( )盒,还剩( )个。", + "options": [], + "answer": "2;3", + "solution": "【分析】用苹果的数量依次减6,减到不能减为止,减了几次就能装满几盒,差是几就说明还剩几个.\n【详解】15 - 6 = 9(个),9 - 6 = 3(个),有15个苹果,每6个苹果装一盒,一共可以装满2盒,还剩3个。", + "knowledge_points": [ + "十几减 7,6 的退位减法", + "8,9 的加减法" + ], + "source": "23-24 一年级下·湖南怀化·期末" + }, + { + "id": "50", + "unit": "20以内的退位减法1", + "question_type": "填空题", + "difficulty": 0.65, + "question": "13个小朋友排成一队做操,小明的前面有6人,那么小明的后面有( )人。", + "options": [], + "answer": "6", + "solution": "【分析】用总人数减去小明前面的人数和小明即可求出小明后面有多少人.\n【详解】13 - 6 - 1 = 6(人),13个小朋友排成一队做操,小明的前面有6人,那么小明的后面有6人。", + "knowledge_points": [ + "连减(20以内)", + "前,后位置" + ], + "source": "23-24 一年级下·江西萍乡·期末" + }, + { + "id": "51", + "unit": "20以内的退位减法1", + "question_type": "填空题", + "difficulty": 0.85, + "question": "在括号里填上\">\"\"<\"或\"=\"。\n16-8( )9;14-7( )6;12-6( )6。", + "options": [], + "answer": "<;>;=", + "solution": "【分析】先计算出每个算式的结果,然后比较大小,即可解决.\n【详解】16-8=8,故16-8<9;14-7=7,故14-7>6;12-6=6。", + "knowledge_points": [ + "20 以内数的比大小", + "十几减 7,6 的退位减法", + "十几减 8 的退位减法" + ], + "source": "23-24 一年级下·湖北省直辖县级单位·期末" + }, + { + "id": "52", + "unit": "20以内的退位减法1", + "question_type": "填空题", + "difficulty": 0.85, + "question": "李奶奶养公鸡和母鸡共16只。其中公鸡有7只,母鸡有( )只。", + "options": [], + "answer": "9", + "solution": "【分析】根据题意可知:公鸡和母鸡共16只,其中公鸡有7只,求母鸡的只数,用减法计算,即16-7。据此解答.\n【详解】16-7=9(只),母鸡有9只。", + "knowledge_points": [ + "十几减 7,6 的退位减法" + ], + "source": "22-23 一年级下·河南驻马店·阶段练习" + }, + { + "id": "53", + "unit": "20以内的退位减法1", + "question_type": "填空题", + "difficulty": 0.65, + "question": "乐乐有12支铅笔,果果有5支铅笔。果果至少还要买( )支铅笔才能超过乐乐。", + "options": [], + "answer": "8", + "solution": "【分析】要想超过乐乐,则果果的铅笔数量最少比乐乐多1支。根据题意,乐乐铅笔的支数 - 果果铅笔的支数 + 1支 = 果果至少需要买的支数.\n【详解】12 - 5 + 1 = 8(支),果果至少还要买8支铅笔才能超过乐乐。", + "knowledge_points": [ + "加减混合运算(20以内)" + ], + "source": "23-24 一年级下·湖南邵阳·期中" + }, + { + "id": "54", + "unit": "20以内的退位减法1", + "question_type": "判断题", + "difficulty": 0.85, + "question": "计算13 - 8时可以用想加算减的方法。( )", + "options": [], + "answer": "√", + "solution": "【分析】想加算减法就是用\"和减去一个加数等于另一个加数\",也就是想8和5合起来是13,即13减8就得5,由此解答.\n【详解】由分析可知,计算13 - 8时可以用想加算减的方法。原题说法正确。故答案为:√。", + "knowledge_points": [ + "十几减8的退位减法" + ], + "source": "23-24 一年级下·山东日照·期末" + }, + { + "id": "55", + "unit": "20以内的退位减法1", + "question_type": "判断题", + "difficulty": 0.85, + "question": "4比12多8。( )", + "options": [], + "answer": "×", + "solution": "【分析】当一个数比另一个数小时,求出的差叫做一个数比另一个数少多少;当一个数比另一个数大时,求出的差叫做一个数比另一个数多多少;据此解决.\n【详解】12 - 4 = 8,4比12少8,原说法错误。故答案为: ×。", + "knowledge_points": [ + "十几减 5~2 的退位减法" + ], + "source": "22-23 一年级下·甘肃天水·期中" + }, + { + "id": "56", + "unit": "20以内的退位减法1", + "question_type": "判断题", + "difficulty": 0.85, + "question": "在算式6 + ○ = 11中,○里应填4。( )", + "options": [], + "answer": "×", + "solution": "【分析】根据\"加数 = 和 - 另一个加数\"及20以内退位减法的计算方法来解答.\n【详解】11 - 6 = 5,故6 + 5 = 11,即在算式6 + ○ = 11中,○里应填5;原说法错误。故答案为: ×。", + "knowledge_points": [ + "十几减 7,6 的退位减法", + "加,减法的意义和各部分间的关系", + "7,6加几的进位加法" + ], + "source": "23-24 一年级下·贵州铜仁·期末" + }, + { + "id": "57", + "unit": "20以内的退位减法1", + "question_type": "判断题", + "difficulty": 0.65, + "question": "已知12 - 3与6 + □的结果相同,那么□ = 3。( )", + "options": [], + "answer": "√", + "solution": "【分析】计算12 - 3的结果,假设题目中□ = 3,6 + □ = 6 + 3 = 9,看结果是否相等,据此得出结论即可.\n【详解】12 - 3 = 9,6 + □ = 6 + 3 = 9,原题结论正确。故答案为:√。", + "knowledge_points": [ + "十几减 5~2 的退位减法", + "8,9 的加减法" + ], + "source": "23-24 一年级下·河北邢台·期末" + }, + { + "id": "58", + "unit": "20以内的退位减法1", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图写算式。![](images/7c443015ea801ed7a11a1328673c150c4a671c7d688bdca459a9311b2dcdbd09.jpg)", + "options": [], + "answer": "14-5=9", + "solution": "【分析】一共有14本作业本,外面有5本,用总的数量减去外面的5本,即可得出书包里有几本.\n【详解】14-5=9(本),书包里有9本作业本。", + "knowledge_points": [ + "图文问题", + "十几减 5~2 的退位减法" + ], + "source": "24-25 一年级下·河南南阳·期中" + }, + { + "id": "59", + "unit": "20以内的退位减法1", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式计算。![](images/cae4a8a1e54e90c84b79defc697c5676e06298d8f1d816565d8140580f751b74.jpg)", + "options": [], + "answer": "16-8=8", + "solution": "【分析】用杯子的总数量减去左边的数量,求出差,就是右边的杯子数量.\n【详解】根据题意:16-8=8(个)。", + "knowledge_points": [ + "图文问题", + "十几减8的退位减法" + ], + "source": "23-24 一年级下·江西南昌·期末" + }, + { + "id": "60", + "unit": "20以内的退位减法1", + "question_type": "计算题", + "difficulty": 0.85, + "question": "列算式。![](images/3edb5627908ab56f21c49e67d99d11e52e4b61d2012a4ebdfd718e4f3cba77de.jpg)", + "options": [], + "answer": "16-7=9", + "solution": "【分析】根据减法的意义,用草莓的总数量减去左边草莓的数量即可求出右边盘子里草莓的数量,据此解答即可.\n【详解】16 - 7 = 9(个),所以右边盘子里一共有9个草莓。", + "knowledge_points": [ + "图文问题", + "十几减 7,6 的退位减法" + ], + "source": "23-24 一年级下·四川乐山·期末" + }, + { + "id": "61", + "unit": "20以内的退位减法1", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式计算。![](images/971327d0bbb8104461ee01370952da49a825ee87980648be12c5644205b46fb9.jpg)", + "options": [], + "answer": "13-6=7", + "solution": "【分析】一共13个,左边6个,用13减6即可求出右边的个数.\n【详解】13 - 6 = 7(个)。", + "knowledge_points": [ + "图文问题", + "十几减 7,6 的退位减法" + ], + "source": "23-24 一年级下·山东临沂·期末" + }, + { + "id": "62", + "unit": "20以内的退位减法1", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式计算。![](images/4e6f2fb4393064a1483ff29d9098d8b0c480603bbc014dafb75e00184a68f6ea.jpg)", + "options": [], + "answer": "14-5=9", + "solution": "【分析】用正方块的总数量减去左边的数量,求出差,就是右边的正方块数量.\n【详解】由题意分析得:14 - 5 = 9(块)。", + "knowledge_points": [ + "图文问题", + "十几减 5~2 的退位减法" + ], + "source": "23-24 一年级下·湖北武汉·期末" + }, + { + "id": "63", + "unit": "20以内的退位减法1", + "question_type": "计算题", + "difficulty": 0.85, + "question": "我会看图列式计算。![](images/a80e2753c51e1cdc25f7414c0823bf2b9394222dd395c69ea63414446a3a18c1.jpg)", + "options": [], + "answer": "17-9=8", + "solution": "【分析】用总数减去右边的支数,即可求出左边的支数,据此解答即可.\n【详解】17 - 9 = 8(支)。", + "knowledge_points": [ + "图文问题", + "十几减9的退位减法" + ], + "source": "23-24 一年级下·山东菏泽·期末" + }, + { + "id": "64", + "unit": "20以内的退位减法1", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式计算。![](images/19e9d821cbe152e71edf4148d161b63432fafc11425aae6d6cefa9e37cb054a3.jpg)", + "options": [], + "answer": "11-4=7", + "solution": "【分析】一共有11个,右边有4个,求左边的数量。根据减法的意义,总数量 - 右边的数量 = 左边的数量.\n【详解】11 - 4 = 7(个),左边有7个。", + "knowledge_points": [ + "图文问题", + "十几减 5~2 的退位减法" + ], + "source": "23-24 一年级下·广西柳州·期末" + }, + { + "id": "65", + "unit": "20以内的退位减法1", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式计算。![](images/269a7f4639283e2c8f8d4e24c269ddb7bcc9db4a1c366188abbab79029ae486d.jpg)", + "options": [], + "answer": "15-7=8", + "solution": "【分析】用糖的总数量减去右边的数量,求出差,就是左边袋子里的数量.\n【详解】由题意分析得:15 - 7 = 8(块)。", + "knowledge_points": [ + "图文问题", + "十几减7,6的退位减法" + ], + "source": "22-23 一年级下·河南周口·期中" + }, + { + "id": "66", + "unit": "20以内的退位减法1", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式计算。![](images/2edfa39b5885509b9760fab62edec57faff16607e587df38152be04af4a711cc.jpg)", + "options": [], + "answer": "13-4=9", + "solution": "【分析】用梨的总数量减去左边的数量,求出差,就是右边的数量.\n【详解】由题意分析得:13 - 4 = 9(个),所以右边有梨9个。", + "knowledge_points": [ + "图文问题", + "十几减 5~2 的退位减法" + ], + "source": "22-23 一年级下·河南周口·期中" + }, + { + "id": "67", + "unit": "20以内的退位减法1", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式计算。![](images/dfa5669c9174c4fef2b5172840957c1cf92830d0d74e6a73d7cda58f2ea210b3.jpg)", + "options": [], + "answer": "13-7=6", + "solution": "【分析】一共有13个蛋糕,右边有7个,求左边有多少个,根据减法的意义,总数量 - 右边的数量 = 左边的数量.\n【详解】13 - 7 = 6(个),左边有6个。", + "knowledge_points": [ + "图文问题", + "十几减 7,6 的退位减法" + ], + "source": "22-23 一年级下·河南许昌·期末" + }, + { + "id": "68", + "unit": "20以内的退位减法1", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式计算。![](images/2004d4d2373efd75c711a3419b091e9f49bb3e8ea481c26c0c3f97d40733c0a0.jpg)", + "options": [], + "answer": "16-7=9", + "solution": "【分析】共16条,左边7条,用16减7即可求出右边的条数.\n【详解】16 - 7 = 9(条)。", + "knowledge_points": [ + "图文问题", + "十几减 7,6 的退位减法" + ], + "source": "23-24 一年级下·河南驻马店·期中" + }, + { + "id": "69", + "unit": "20以内的退位减法1", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式计算。![](images/bd319ffbbfc701ed9876cff5a7b1290351cf415b7db332768632505bb00a29fb.jpg)", + "options": [], + "answer": "11-6=5", + "solution": "【分析】题中一共有11只小鸟,左边有6只,求右边树上有几只。根据减法的意义,总数量 - 左边的数量 = 右边树上的数量,计算即可.\n【详解】11 - 6 = 5(只),右边树上有5只。", + "knowledge_points": [ + "图文问题", + "十几减 7,6 的退位减法" + ], + "source": "23-24 一年级下·湖南湘西·期中" + }, + { + "id": "70", + "unit": "20以内的退位减法1", + "question_type": "解答题", + "difficulty": 0.94, + "question": "小花有15朵红花,小兰有9朵红花,小花比小兰多几朵红花。", + "options": [], + "answer": "6朵", + "solution": "【分析】根据求一个数比另一个数多几,用减法计算。用小花有的数量减去小兰有的数量即可求出小花比小兰多的数量.\n【详解】15 - 9 = 6(朵),答:小花比小兰多6朵红花。", + "knowledge_points": [ + "十几减9的退位减法", + "谁比谁多/少几的问题" + ], + "source": "25-26 二年级上·黑龙江佳木斯·开学考试" + }, + { + "id": "71", + "unit": "20以内的退位减法1", + "question_type": "解答题", + "difficulty": 0.85, + "question": "王琪比李军多擦了多少张桌子。![](images/c3455d24e99e2b229c421fe11050d81a8e545f69de7a9fe2db11922d7bf2a955.jpg)", + "options": [], + "answer": "8张", + "solution": "【分析】已知,王琪擦了17张桌子,李军擦了9张桌子,用王琪的桌子数量减去李军的,即可得出王琪比李军多擦了几张.\n【详解】17 - 9 = 8(张),答:王琪比李军多擦了8张桌子。", + "knowledge_points": [ + "十几减9的退位减法" + ], + "source": "24-25一年级下·河北石家庄·期中" + }, + { + "id": "72", + "unit": "20以内的退位减法1", + "question_type": "解答题", + "difficulty": 0.65, + "question": "小红折了8个星星,小明折了12个星星,小红再折多少个就和小明同样多了。", + "options": [], + "answer": "4个", + "solution": "【分析】小明比小红多的数量就是小红需要再折的数量。求两者的差距用减法计算。用小明折的数量减去小红折的数量即可求解.\n【详解】12 - 8 = 4(个),答:小红再折4个就和小明同样多了。", + "knowledge_points": [ + "十几减8的退位减法" + ], + "source": "24-25 一年级下·山东济宁·阶段练习" + }, + { + "id": "73", + "unit": "20以内的退位减法1", + "question_type": "解答题", + "difficulty": 0.85, + "question": "小朋友们排队,从左往右数亮亮是第8个,从右往左数亮亮是第5个,一共有多少个小朋友在排队。", + "options": [], + "answer": "12人", + "solution": "【分析】根据题意可知:用从左往右数亮亮的排名,加上从右往左数亮亮的排名,然后再减1即可求出一共有的人数.\n【详解】8 + 5 - 1 = 12(人),答:一共有12个小朋友在排队。", + "knowledge_points": [ + "加减混合运算(20以内)", + "左,右位置" + ], + "source": "24-25 一年级上·甘肃平凉·期末" + }, + { + "id": "74", + "unit": "20以内的退位减法1", + "question_type": "解答题", + "difficulty": 0.85, + "question": "一共有14根香蕉,分给两只猴子,一只分6根,另一只分多少根。", + "options": [], + "answer": "8根", + "solution": "【分析】求另一只分几根,用减法计算,即香蕉的总数量 - 分给一只猴子的数量 = 分给另一只猴子的数量.\n【详解】14 - 6 = 8(根),答:另一只分8根。", + "knowledge_points": [ + "十几减 7,6 的退位减法" + ], + "source": "23-24 二年级下·四川德阳·期末" + }, + { + "id": "75", + "unit": "20以内的退位减法1", + "question_type": "解答题", + "difficulty": 0.85, + "question": "音乐兴趣小组有女生14人,比男生多5人。男生有多少人。", + "options": [], + "answer": "9人", + "solution": "【分析】根据题意可知:求男生的人数,用女生的人数减去比男生多出来的人数即可.\n【详解】14 - 5 = 9(人),答:男生有9人。", + "knowledge_points": [ + "十几减 5~2 的退位减法" + ], + "source": "23-24 二年级上·福建福州·期中" + }, + { + "id": "76", + "unit": "20以内的退位减法1", + "question_type": "解答题", + "difficulty": 0.85, + "question": "小红做了15朵花,小华做了9朵花,小华比小红少做几朵。", + "options": [], + "answer": "6朵", + "solution": "【分析】求小华比小红少做几朵,就是求两个数的差,用减法列式解决.\n【详解】15 - 9 = 6(朵),答:小华比小红少做6朵。", + "knowledge_points": [ + "十几减9的退位减法" + ], + "source": "23-24 一年级下·河南濮阳·期末" + }, + { + "id": "77", + "unit": "20以内的退位减法1", + "question_type": "解答题", + "difficulty": 0.85, + "question": "小军家养了15只羊和10头牛。母羊有9只,公羊有几只。", + "options": [], + "answer": "6只", + "solution": "【分析】根据减法的意义,用羊的总数量减去母羊的数量即可求出公羊的数量,据此解答即可.\n【详解】15 - 9 = 6(只),答:公羊有6只。", + "knowledge_points": [ + "十几减9的退位减法" + ], + "source": "23-24 一年级下·四川乐山·期末" + }, + { + "id": "78", + "unit": "20以内的退位减法1", + "question_type": "解答题", + "difficulty": 0.85, + "question": "\"环保明星\"活动中,玲玲收集了16节废电池和45个塑料袋,丽丽收集了9节废电池,丽丽收集的废电池比玲玲少多少节。", + "options": [], + "answer": "7节", + "solution": "【分析】求一个数比另一个数少多少,用减法计算,即玲玲收集废电池的数量 - 丽丽收集废电池的数量 = 丽丽比玲玲少收集的数量.\n【详解】16 - 9 = 7(节),答:丽丽收集的废电池比玲玲少7节。", + "knowledge_points": [ + "十几减9的退位减法" + ], + "source": "23-24 一年级下·山东菏泽·期末" + }, + { + "id": "79", + "unit": "20以内的退位减法1", + "question_type": "解答题", + "difficulty": 0.65, + "question": "一年级有12人参加踢毽子比赛,现在来了5人,还有几人没来。", + "options": [], + "answer": "7人", + "solution": "【分析】根据减法的意义,用参加踢毽子比赛的总人数减去来了的人数即可求出没来的人数,据此解答即可.\n【详解】12 - 5 = 7(人),答:还有7人没来。", + "knowledge_points": [ + "十几减 5~2 的退位减法" + ], + "source": "22-23一年级下·广东汕头·期末" + }, + { + "id": "80", + "unit": "20以内的退位减法1", + "question_type": "解答题", + "difficulty": 0.65, + "question": "小白兔的菜园丰收了,它的菜园里有20根萝卜和18棵白菜,它拔了9棵白菜送给山羊伯伯,还剩几棵白菜。", + "options": [], + "answer": "9棵", + "solution": "【分析】根据减法的意义,用菜园里原有的白菜数量减去送给山羊伯伯的白菜数量即可求出还剩下的白菜数量.\n【详解】18 - 9 = 9(棵),答:还剩9棵白菜。", + "knowledge_points": [ + "十几减9的退位减法" + ], + "source": "23-24一年级下·贵州六盘水·期末" + }, + { + "id": "81", + "unit": "20以内的退位减法1", + "question_type": "解答题", + "difficulty": 0.85, + "question": "小美摘的红苹果比青苹果多多少个。![](images/2025-12-14%20120645.jpg)", + "options": [], + "answer": "8个", + "solution": "【分析】用小美摘的红苹果个数减去青苹果个数,即可计算出小美摘的红苹果比青苹果多多少个.\n【详解】14 - 6 = 8(个),答:小美摘的红苹果比青苹果多8个。", + "knowledge_points": [ + "十几减 7,6 的退位减法" + ], + "source": "23-24 一年级下·海南省直辖县级单位·期末" + }, + { + "id": "82", + "unit": "20以内的退位减法1", + "question_type": "解答题", + "difficulty": 0.85, + "question": "停车场原停有12辆货车,开走了3辆,还剩多少辆货车。", + "options": [], + "answer": "9辆", + "solution": "【分析】用停车场原停有货车的辆数减去开走的辆数,即可计算出还剩多少辆货车.\n【详解】12 - 3 = 9(辆),答:还剩9辆货车。", + "knowledge_points": [ + "十几减 5~2 的退位减法" + ], + "source": "23-24一年级下·海南省直辖县级单位·期末" + }, + { + "id": "83", + "unit": "20以内的退位减法1", + "question_type": "解答题", + "difficulty": 0.65, + "question": "学校合唱团原来女生比男生多5人,今年开学后增加了12名男生和8名女生,现在男生多还是女生多。多多少人。", + "options": [], + "answer": "女生多;1人", + "solution": "【分析】合唱团原来女生比男生多5人;12 - 8 = 4(人),也就是开学后增加的男生比女生多4人;5>4,故最终女生比男生多;5 - 4 = 1(人),女生比男生多1人;据此解决.\n【详解】12 - 8 = 4(人),5>4,5 - 4 = 1(人),答:现在女生多;多1人。", + "knowledge_points": [ + "5以内数的减法", + "5以内数的比大小", + "十几减8的退位减法" + ], + "source": "23-24 二年级上·全国·课后作业" + }, + { + "id": "84", + "unit": "20以内的退位减法1", + "question_type": "解答题", + "difficulty": 0.85, + "question": "张奶奶家鸡和鸭一共养了14只。鸡养了6只,鸭养了多少只。", + "options": [], + "answer": "8只", + "solution": "【分析】用鸡和鸭一共的数量减去鸡的数量,求出差,就是鸭的数量.\n【详解】14 - 6 = 8(只),答:鸭养了8只。", + "knowledge_points": [ + "十几减 7,6 的退位减法" + ], + "source": "22-23一年级下·河南周口·期中" + }, + { + "id": "85", + "unit": "20以内的退位减法1", + "question_type": "解答题", + "difficulty": 0.85, + "question": "小明要写18个大字,他已经写了9个,还要写多少个。![](images/914b9a28ed816e7b7933ee1c47d8a1a9e74f30ad7b7aa0bdd850f1fbb1e24a6c.jpg)", + "options": [], + "answer": "9个", + "solution": "【分析】用要写的大字数量减去已写的数量,求出差,就是还要写的数量.\n【详解】18 - 9 = 9(个),答:还要写9个。", + "knowledge_points": [ + "图文问题", + "十几减9的退位减法" + ], + "source": "22-23 一年级下·河南周口·期中" + }, + { + "id": "86", + "unit": "20以内的退位减法1", + "question_type": "解答题", + "difficulty": 0.65, + "question": "一共要包14个粽子,已经包了9个,还要包几个。", + "options": [], + "answer": "5个", + "solution": "【分析】一共要包的粽子数量 - 已经包了的粽子数量 = 还要包的粽子数量.\n【详解】14 - 9 = 5(个),答:还要包5个。", + "knowledge_points": [ + "十几减9的退位减法" + ], + "source": "23-24 一年级下·山东临沂·期末" + }, + { + "id": "87", + "unit": "20以内的退位减法1", + "question_type": "解答题", + "difficulty": 0.85, + "question": "小华有12本故事书,借给弟弟5本后,小华还有几本故事书。", + "options": [], + "answer": "7本", + "solution": "【分析】用故事书的总数量减去借给弟弟的数量,求出差,即可解决.\n【详解】12 - 5 = 7(本),答:小华还有7本故事书。", + "knowledge_points": [ + "十几减 5~2 的退位减法" + ], + "source": "22-23 一年级下·河南驻马店·阶段练习" + }, + { + "id": "88", + "unit": "20以内的退位减法1", + "question_type": "解答题", + "difficulty": 0.85, + "question": "还剩下多少朵。![](images/da373c279e01b6375bb777830ff9e1dd8488a381fc4bfb32dffaab8fa8415e86.jpg)", + "options": [], + "answer": "6朵", + "solution": "【分析】用花的总数量减去送给小朋友的数量,求出差,即可解决.\n【详解】13 - 7 = 6(朵),答:还剩下6朵。", + "knowledge_points": [ + "十几减 7,6 的退位减法" + ], + "source": "22-23 一年级下·宁夏固原·阶段练习" + }, + { + "id": "89", + "unit": "20以内的退位减法1", + "question_type": "解答题", + "difficulty": 0.85, + "question": "苹果和梨一共有14个,其中梨有6个。苹果有多少个。", + "options": [], + "answer": "8个", + "solution": "【分析】根据题意,用苹果和梨的总个数减去梨的个数,即可求出苹果的个数.\n【详解】14 - 6 = 8(个),答:苹果有8个。", + "knowledge_points": [ + "十几减 7,6 的退位减法" + ], + "source": "22-23一年级下·宁夏固原·阶段练习" + }, + { + "id": "90", + "unit": "20以内的退位减法1", + "question_type": "解答题", + "difficulty": 0.85, + "question": "家里来了13位客人,小美准备了5杯茶水,小美自己也要喝,还差几杯。", + "options": [], + "answer": "9杯", + "solution": "【分析】先用来了的客人数量减去已有的茶水数量,求出差,再加上1,求出和,即可解决.\n【详解】13 - 5 + 1 = 8 + 1 = 9(杯),答:还差9杯。", + "knowledge_points": [ + "加减混合运算 (20 以内)" + ], + "source": "22-23一年级下·河南驻马店·阶段练习" + }, + { + "id": "91", + "unit": "20以内的退位减法1", + "question_type": "解答题", + "difficulty": 0.85, + "question": "操场上原有13个小朋友在做游戏,走了一些后,还剩6人。走了几个小朋友。", + "options": [], + "answer": "7人", + "solution": "【分析】用操场上原来的人数减去还剩的人数,求出差,即可解决.\n【详解】13 - 6 = 7(人),答:走了7个小朋友。", + "knowledge_points": [ + "十几减 7,6 的退位减法" + ], + "source": "22-23一年级下·河南驻马店·阶段练习" + }, + { + "id": "92", + "unit": "20以内的退位减法1", + "question_type": "解答题", + "difficulty": 0.85, + "question": "原来有18架飞机,飞走了一部分,这儿还剩下9架,飞走了多少架飞机。", + "options": [], + "answer": "9架", + "solution": "【分析】用原来的数量减去还剩的数量即可求出飞走了多少架飞机.\n【详解】18 - 9 = 9(架),答:飞走了9架飞机。", + "knowledge_points": [ + "十几减9的退位减法" + ], + "source": "22-23一年级下·甘肃庆阳·阶段练习" + }, + { + "id": "93", + "unit": "20以内的退位减法1", + "question_type": "解答题", + "difficulty": 0.85, + "question": "家中原有苹果13个,吃掉了4个,还剩下多少个苹果。", + "options": [], + "answer": "9个", + "solution": "【分析】用原来的苹果个数减去吃掉的个数即可求出还剩下多少个苹果.\n【详解】13 - 4 = 9(个),答:还剩下9个苹果。", + "knowledge_points": [ + "十几减 5~2 的退位减法" + ], + "source": "22-23一年级下·甘肃庆阳·阶段练习" + }, + { + "id": "94", + "unit": "20以内的退位减法1", + "question_type": "解答题", + "difficulty": 0.85, + "question": "书架上有17本书,第一小组借走一些,第二小组又借走一些,书架上还剩下9本,两个小组一共借走了几本书。", + "options": [], + "answer": "8本", + "solution": "【分析】用书架上书的总本数减去还剩下的本数,求出差,即可解决.\n【详解】17 - 9 = 8(本),答:两个小组一共借走了8本书。", + "knowledge_points": [ + "十几减9的退位减法" + ], + "source": "22-23一年级下·江西九江·期末" + }, + { + "id": "95", + "unit": "20以内的退位减法1", + "question_type": "解答题", + "difficulty": 0.85, + "question": "奶奶家有15只鸡和6只鹅,母鸡8只,公鸡有多少只。", + "options": [], + "answer": "7只", + "solution": "【分析】用鸡的总数减去母鸡只数,即可求出公鸡有多少只.\n【详解】15 - 8 = 7(只),答:公鸡有7只。", + "knowledge_points": [ + "十几减8的退位减法" + ], + "source": "22-23一年级下·黑龙江绥化·期末" + }, + { + "id": "96", + "unit": "20以内的退位减法1", + "question_type": "解答题", + "difficulty": 0.85, + "question": "小猴摘了13个桃子,吃了9个,小猴现在还剩多少个桃子。", + "options": [], + "answer": "4个", + "solution": "【分析】用小猴摘的个数减去吃了的个数即可求出小猴现在还剩多少个桃子.\n【详解】13 - 9 = 4(个),答:小猴现在还剩4个桃子。", + "knowledge_points": [ + "十几减9的退位减法" + ], + "source": "23-24 一年级下·河南驻马店·期中" + }, + { + "id": "97", + "unit": "20以内的退位减法1", + "question_type": "解答题", + "difficulty": 0.85, + "question": "有17个蓝气球,8个红气球。红气球比蓝气球少几个。", + "options": [], + "answer": "9个", + "solution": "【分析】用蓝气球的个数减去红气球的个数即可求出红气球比蓝气球少几个.\n【详解】17 - 8 = 9(个),答:红气球比蓝气球少9个。", + "knowledge_points": [ + "十几减8的退位减法" + ], + "source": "23-24 一年级下·河南驻马店·期中" + }, + { + "id": "98", + "unit": "20以内的退位减法1", + "question_type": "解答题", + "difficulty": 0.85, + "question": "我们班一共有12人参加植树,要植8棵树,其中女生有7人,男生有几人。", + "options": [], + "answer": "5人", + "solution": "【分析】求男生有几人,根据减法的意义,总人数 - 女生的人数 = 男生的人数,计算即可.\n【详解】12 - 7 = 5(人),答:男生有5人。", + "knowledge_points": [ + "十几减 7,6 的退位减法" + ], + "source": "23-24一年级下·湖南湘西·期中" + }, + { + "id": "99", + "unit": "20以内的退位减法1", + "question_type": "解答题", + "difficulty": 0.85, + "question": "有14个包子,放在2个盘子里。一个盘子放6个,另一个盘子放几个。", + "options": [], + "answer": "8个", + "solution": "【分析】求另一个盘子里放几个,根据减法的意义,包子的总数量 - 一个盘子放的数量 = 另一个盘子放的数量,计算即可.\n【详解】14 - 6 = 8(个),答:另一个盘子放8个。", + "knowledge_points": [ + "十几减 7,6 的退位减法" + ], + "source": "23-24 一年级下·湖南湘西·期中" + }, + { + "id": "100", + "unit": "20以内的退位减法1", + "question_type": "解答题", + "difficulty": 0.85, + "question": "幼儿园大班有16个小朋友,现在有9个苹果,每人一个,还差几个苹果。", + "options": [], + "answer": "7个", + "solution": "【分析】根据题意,16个小朋友也就是需要16个苹果,求还差几个苹果,根据减法的意义,需要苹果的总数量 - 现在有的数量 = 还差的数量,计算即可.\n【详解】16 - 9 = 7(个),答:还差7个苹果。", + "knowledge_points": [ + "十几减9的退位减法" + ], + "source": "23-24 一年级下·湖南湘西·期中" + }, + { + "id": "101", + "unit": "20以内的退位减法1", + "question_type": "选择题", + "difficulty": 0.85, + "question": "与12-6的结果相同的算式是()。", + "options": [ + "A. 13 - 5", + "B. 15 - 9", + "C. 14 - 7" + ], + "answer": "B", + "solution": "【分析】12 - 6 = 6,依次计算出各选项的结果,找到得数是 6 的即可.\n【详解】. 13 - 5 = 8;B. 15 - 9 = 6;C. 14 - 7 = 7 。与 12 - 6 的结果相同的算式是 15 - 9 。故答案为: B", + "knowledge_points": [ + "十几减 5~2 的退位减法", + "十几减 9 的退位减法", + "十几减 7,6 的退位减法" + ], + "source": "23-24 一年级下·湖南湘西·期中" + }, + { + "id": "102", + "unit": "20以内的退位减法1", + "question_type": "选择题", + "difficulty": 0.85, + "question": "每 6 块橡皮装一盒,下面这些橡皮能装满 ( ) 盒.\n![](images/14bcac3a86c82746c51ecc5fe4a934409a2911a13a68dc24baa473d9a71e02b0.jpg)", + "options": [ + "A. 2", + "B. 3", + "C. 4" + ], + "answer": "B", + "solution": "【分析】先数一数橡皮一共多少块,然后用橡皮的总数减去 6,能减几次,就表示可以装几盒.\n【详解】橡皮一共有 18 块。18 - 6 = 12 (块),12 - 6 = 6 (块),6 - 6 = 0 (块),减了 3 次,则说明能装满 3 盒。故答案为: B", + "knowledge_points": [ + "十几减 7,6 的退位减法" + ], + "source": "23-24 一年级下·湖南湘西·期中" + }, + { + "id": "103", + "unit": "20以内的退位减法1", + "question_type": "选择题", + "difficulty": 0.65, + "question": "与16-7得数不同的是()。", + "options": [ + "A. 17 - 8", + "B. 11 - 2", + "C. 12 - 2" + ], + "answer": "C", + "solution": "【分析】根据 20 以内减法的运算法则计算出结果,找出结果不相同的算式即可.\n【详解】 16 - 7 = 9,A. 17 - 8 = 9,与 16 - 7 得数相同;B. 11 - 2 = 9,与 16 - 7 得数相同;C. 12 - 2 = 10, 9 != 10,与 16 - 7 得数不同。与 16-7 得数不同的是 12 - 2 。故答案为: C", + "knowledge_points": [ + "十几减 5~2 的退位减法", + "十几减 8 的退位减法", + "十几减 7,6 的退位减法", + "不退位减法 (20 以内)" + ], + "source": "23-24 一年级下·河南驻马店·期中" + }, + { + "id": "104", + "unit": "20以内的退位减法1", + "question_type": "选择题", + "difficulty": 0.85, + "question": "树上和树下共有13只猴子,树上有4只,树下有几只。()。", + "options": [ + "A. 13 - 4", + "B. 13 + 4", + "C. 4 + 13" + ], + "answer": "A", + "solution": "【分析】求树下有几只,根据减法的意义,一共的数量减去树上的数量=树下的数量,由此解答.\n【详解】由分析得:列式为13-4=9(只)。故答案为:A", + "knowledge_points": [ + "十几减 5~2 的退位减法" + ], + "source": "23-24一年级下·新疆和田·期中" + }, + { + "id": "105", + "unit": "20以内的退位减法1", + "question_type": "选择题", + "difficulty": 0.85, + "question": "1 □ -6 是退位减法, □ 里最大可以填 ( )。", + "options": [ + "A. 7", + "B. 6", + "C. 5" + ], + "answer": "C", + "solution": "【分析】1 □ -6 是退位减法,也就是个位数不够减 6,即,□ 里面的数要比 6 小,而比 6 小且是最大的数是 5;据此解决.\n【详解】由题意分析得:1□ -6 是退位减法, □ 里最大可以填 5 。故答案为: C", + "knowledge_points": [ + "十几减 7,6 的退位减法" + ], + "source": "23-24 一年级下·贵州铜仁·期中" + }, + { + "id": "106", + "unit": "20以内的退位减法1", + "question_type": "选择题", + "difficulty": 0.85, + "question": "明明有 8 支彩笔,军军有 14 支彩笔,明明比军军少 ( ) 支彩笔。", + "options": [ + "A. 4", + "B. 6", + "C. 8" + ], + "answer": "B", + "solution": "【分析】用军军的彩笔数量减明明的彩笔数量即可求出明明比军军少多少支彩笔.\n【详解】14 - 8 = 6 (支),明明比军军少 6 支彩笔。故答案为: B", + "knowledge_points": [ + "十几减8的退位减法" + ], + "source": "23-24 一年级下·贵州铜仁·期中" + }, + { + "id": "107", + "unit": "20以内的退位减法1", + "question_type": "选择题", + "difficulty": 0.85, + "question": "与13-6的结果相同的算式是()。", + "options": [ + "A. 12 - 6", + "B. 16 - 7", + "C. 11 - 4" + ], + "answer": "C", + "solution": "【分析】先按照整数加减法的计算法则,算出每个算式的结果,再找出结果相同的算式即可.\n【详解】13 - 6 = 7,A. 12 - 6 = 6;B. 16 - 7 = 9;C. 11 - 4 = 7;即,与 13 - 6 的结果相同的算式是 11 - 4 。故答案为: C", + "knowledge_points": [ + "十几减 5~2 的退位减法", + "十几减 7,6 的退位减法" + ], + "source": "23-24 一年级下·湖南常德·期中" + }, + { + "id": "108", + "unit": "20以内的退位减法1", + "question_type": "选择题", + "difficulty": 0.85, + "question": "树上有 12 只小鸟,飞走了3只,飞来2只,树上现在有几只小鸟。下面列式错误的是 ( )。", + "options": [ + "A. 12 - 3 - 2", + "B. 12 - 3 + 2", + "C. 12 + 2 - 3" + ], + "answer": "A", + "solution": "【分析】求现在有几只,可以用原来的数量 - 飞走的数量 + 飞来的数量;也可以用原来的数量 + 飞来的数量 - 飞走的数量,由此解答.\n【详解】. 12 - 3 - 2,表示飞走了 3 只,又飞走了 2 只,与题意不符;B. 12 - 3 + 2,表示飞走了 3 只,飞来了 2 只,与题意相符;C. 12 + 2 - 3,表示飞来了 2 只,飞走了 3 只,与题意相符。列式错误的是 12 - 3 - 2 。故答案为: A", + "knowledge_points": [ + "加减混合运算(20以内)", + "连减(20以内)" + ], + "source": "23-24一年级下·福建福州·期中" + }, + { + "id": "109", + "unit": "20以内的退位减法1", + "question_type": "选择题", + "difficulty": 0.85, + "question": "学校图书角有8个小朋友在读书,再来()个小朋友,正好可以坐满15个座位。", + "options": [ + "A. 7", + "B. 8", + "C. 9" + ], + "answer": "A", + "solution": "【分析】图书馆有 15 个座位,已经坐了 8 个小朋友,求再来几个小朋友可以把座位坐满。根据减法的意义,用 15 - 8 进行解答即可.\n【详解】15 - 8 = 7(个),所以,再来 7 个小朋友,正好可以坐满 15 个座位。故答案为: A", + "knowledge_points": [ + "十几减8的退位减法" + ], + "source": "23-24一年级下·山西忻州·期中" + }, + { + "id": "110", + "unit": "20以内的退位减法1", + "question_type": "选择题", + "difficulty": 0.85, + "question": "下面算式中得数最大的是 ( )。", + "options": [ + "A. 12 - 4", + "B. 12 - 5", + "C. 13 - 4" + ], + "answer": "C", + "solution": "【分析】先算出各个算式的得数,再进行比较大小即可.\n【详解】.12-4=8;B.12-5=7;C.13-4=9,所以9>8>7,所以13-4的得数最大。故答案为:C", + "knowledge_points": [ + "十几减 5~2 的退位减法", + "10 以内数的比大小" + ], + "source": "23-24 一年级下·山西忻州·期中" + }, + { + "id": "111", + "unit": "20以内的退位减法1", + "question_type": "选择题", + "difficulty": 0.85, + "question": "妈妈买了 12 个苹果(),还剩下多少个苹果。要使这个问题能解答,括号上应该填的信息是 ( )。", + "options": [ + "A. 又买来 25 个梨", + "B. 梨比苹果多 5 个", + "C. 吃了 8 个" + ], + "answer": "C", + "solution": "【分析】求还剩下多少个苹果,就要知道苹果的总数和减去的数量,由此解答.\n【详解】由分析可知,减去的数量也就是吃了 8 个,用买了的数量 - 吃了的数量 = 还剩的数量。所以横线上应该填的信息是吃了 8 个。故答案为: C", + "knowledge_points": [ + "十几减8的退位减法", + "\"提问题\"\"填条件\"问题" + ], + "source": "23-24 一年级下·浙江温州·期中" + }, + { + "id": "112", + "unit": "20以内的退位减法1", + "question_type": "选择题", + "difficulty": 0.85, + "question": "妈妈买回苹果 15 个,梨 8 个,橙子 11 个。()列式为: 11 - 8 = 3 (个), 那么问题可能是 ( )。", + "options": [ + "A. 苹果比梨多几个。", + "B. 橙子比梨少几个。", + "C. 橙子比梨多几个。" + ], + "answer": "C", + "solution": "【分析】两个相减,可以表示一个数比另一个数多(少)多少;据此解决。11 个表示橙子的数量, 8 个表示梨的数量,用 11 - 8 = 3(个), 可以表示橙子比梨多几个,也可以表示梨比橙子少几个.\n【详解】由题意分析得:妈妈买回苹果 15 个,梨 8 个,橙子 11 个。()列式为: 11 - 8 = 3 (个), 那么问题可能是:橙子比梨多几个。故答案为: C", + "knowledge_points": [ + "十几减8的退位减法", + "\"提问题\"\"填条件\"问题" + ], + "source": "22-23一年级下·福建福州·期中" + }, + { + "id": "113", + "unit": "20以内的退位减法1", + "question_type": "选择题", + "difficulty": 0.85, + "question": "被减数是 7 的算式是 ( )。", + "options": [ + "A. 7 + 2 = 9", + "B. 13 - 7 = 6", + "C. 7 - 2 = 5" + ], + "answer": "C", + "solution": "【分析】减法算式为:被减数 - 减数 = 差,加法算式为:加数 + 加数 = 和,由此解答.\n【详解】. 7 + 2 = 9, 7 是加数;B. 13 - 7 = 6, 7 是减数;C. 7 - 2 = 5, 7 是被减数。被减数是 7 的算式是 7 - 2 = 5 。故答案为: C", + "knowledge_points": [ + "8,9 的加减法", + "十几减 7,6 的退位减法", + "7 的加减法" + ], + "source": "22-23一年级下·山西长治·开学考试" + }, + { + "id": "114", + "unit": "20以内的退位减法1", + "question_type": "选择题", + "difficulty": 0.65, + "question": "15 个小朋友玩 \"老鹰捉小鸡\"的游戏,其中有1只老鹰和1只母鸡,已经捉住了9只小鸡。还有()只\"小鸡\"没有被捉到。", + "options": [ + "A. 4只", + "B. 5只", + "C. 6只" + ], + "answer": "A", + "solution": "【分析】求还有几只小鸡没被捉到,根据减法的意义,用总数量减去老鹰的数量,再减去母鸡的数量,求出一共有多少只小鸡,再用小鸡的总数量 - 已经捉住的小鸡数量 = 没被捉到的数量.\n【详解】 15 - 1 - 1 = 13 (只);13 - 9 = 4 (只),还有 4 只 \"小鸡\" 没有被捉到。故答案为: A", + "knowledge_points": [ + "十几减 9 的退位减法", + "不进位,不退位连加,连减 (20 以内)" + ], + "source": "23-24 一年级下·湖南邵阳·期中" + }, + { + "id": "115", + "unit": "20以内的退位减法1", + "question_type": "选择题", + "difficulty": 0.85, + "question": "妈妈买了 16 个苹果,()还剩下多少个苹果。要使这个问题能解答,括号内应该填的信息是()。", + "options": [ + "A. 20个梨子", + "B. 买的梨子比苹果多 3 个", + "C. 吃了 7" + ], + "answer": "C", + "solution": "【分析】求还剩下多少个苹果,就要知道苹果的总数和减去的数量,由此解答.\n【详解】由分析可知,减去的数量也就是吃了 7 个,用买了的数量 - 吃了的数量 = 还剩的数量。所以横线上应该填的信息是吃了 7 个。 故答案为: C", + "knowledge_points": [ + "十几减 7,6 的退位减法", + "\"提问题\" \"填条件\" 问题" + ], + "source": "23-24 一年级下·浙江温州·期中" + }, + { + "id": "116", + "unit": "20以内的退位减法1", + "question_type": "选择题", + "difficulty": 0.65, + "question": "已知 15 - △ = 8, △表示的数是()。", + "options": [ + "A. 7", + "B. 8", + "C. 9" + ], + "answer": "A", + "solution": "【分析】根据减数 = 被减数 - 差得出结论即可.\n【详解】 △ = 15 - 8 = 7,故答案为: A", + "knowledge_points": [ + "十几减8的退位减法" + ], + "source": "23-24 一年级下·广东河源·期中" + }, + { + "id": "117", + "unit": "20以内的退位减法1", + "question_type": "选择题", + "difficulty": 0.85, + "question": "把 12 个梨放到 2 个袋子里,一个袋子里放 3 个,另一个袋子里放 ( ) 个。", + "options": [ + "A. 9", + "B. 4", + "C. 2" + ], + "answer": "A", + "solution": "【分析】求另一个袋子里放几个,根据减法的意义,用总数量 - 一个袋子里放的数量 = 另一个袋子里放的数量.\n【详解】12 - 3 = 9 (个),另一个袋子里放9个。故答案为: A", + "knowledge_points": [ + "十几减 5~2 的退位减法" + ], + "source": "22-23 二年级下·河南驻马店·期中" + }, + { + "id": "118", + "unit": "20以内的退位减法1", + "question_type": "选择题", + "difficulty": 0.85, + "question": "15名小朋友排成一队,小明的前面有 8 名小朋友,小明的后面有 ( ) 名小朋友。", + "options": [ + "A. 5", + "B. 6", + "C. 7" + ], + "answer": "B", + "solution": "【分析】求小明后面有几名小朋友,根据减法的意义,用总数量 - 小明前面的人数 - 小明自己,计算即可.\n【详解】15 - 8 - 1 = 6 (名),小明的后面有 6 名小朋友。故答案为: B", + "knowledge_points": [ + "连减 (20以内)" + ], + "source": "22-23一年级下·贵州铜仁·期中" + }, + { + "id": "119", + "unit": "20以内的退位减法1", + "question_type": "选择题", + "difficulty": 0.85, + "question": "老师买来 16 面小旗分给三位同学。天天得到4面,明明得到5面,笑笑得到()面。", + "options": [ + "A. 6", + "B. 7", + "C. 8" + ], + "answer": "B", + "solution": "【分析】求笑笑得到几面,根据减法的意义,总数量 - 天天得到的数量 - 明明得到的数量 = 笑笑得到的数量,计算即可.\n【详解】16 - 4 - 5 = 7(面),笑笑得到7面。故答案为: B", + "knowledge_points": [ + "连减 (20以内)" + ], + "source": "23-24一年级下·福建莆田·期中" + }, + { + "id": "120", + "unit": "20以内的退位减法1", + "question_type": "选择题", + "difficulty": 0.85, + "question": "姐姐今年 11 岁,妹妹今年 5 岁,妹妹比姐姐小 ( ) 岁。", + "options": [ + "A. 16", + "B. 6", + "C. 5" + ], + "answer": "B", + "solution": "【分析】求妹妹比姐姐小几岁,根据减法的意义,用姐姐的年龄 - 妹妹的年龄,计算即可.\n【详解】11 - 5 = 6(岁),妹妹比姐姐小 6 岁。故答案为: B", + "knowledge_points": [ + "十几减 5~2 的退位减法" + ], + "source": "22-23一年级下·吉林·期中" + }, + { + "id": "121", + "unit": "20以内的退位减法1", + "question_type": "选择题", + "difficulty": 0.85, + "question": "12 颗糖分给 2 个同学。一个同学分 4 颗,另一个同学分 ( ) 颗。", + "options": [ + "A. 6", + "B. 3", + "C. 8" + ], + "answer": "C", + "solution": "【分析】用糖的总数量减去分给一个同学的糖数量,求出差,即可解决此题.\n【详解】12 - 4 = 8(颗)即, 12 颗糖分给 2 个同学。一个同学分 4 颗,另一个同学分 8 颗。故答案为: C", + "knowledge_points": [ + "十几减 5~2 的退位减法" + ], + "source": "22-23 二年级下·福建莆田·期中" + }, + { + "id": "122", + "unit": "20以内的退位减法1", + "question_type": "选择题", + "difficulty": 0.65, + "question": "小虎,小青和小文这个月都新买了14本课外书。小虎已经看完了7本,小青已经看完了8本,小文还有9本没看完。谁剩下没看完的课外书最少。()", + "options": [ + "A. 小虎", + "B. 小青", + "C. 小文" + ], + "answer": "B", + "solution": "【分析】根据题意,用新买的数量减去看完的数量=剩下没看的数量;再比较没看完数量的大小即可.\n【详解】小虎剩下没看的:14-7=7(本);小青剩下没看的:14-8=6(本);小文还有9本没看完。9>7>6,小青剩下没看完的课外书最少。故答案为:B", + "knowledge_points": [ + "十几减 8 的退位减法", + "十几减 7,6 的退位减法", + "10 以内数的比大小" + ], + "source": "23-24 一年级上·山东菏泽·期末" + }, + { + "id": "123", + "unit": "20以内的退位减法1", + "question_type": "选择题", + "difficulty": 0.85, + "question": "花丛里有 15 只蝴蝶,飞走了 7 只,还剩 ( ) 只。", + "options": [ + "A. 9", + "B. 8", + "C. 7" + ], + "answer": "B", + "solution": "【分析】根据减法的意义,剩下的数量 = 原有的数量 - 飞走的数量,由此解答.\n【详解】15 - 7 = 8(只),花丛里有 15 只蝴蝶,飞走了 7 只,还剩 8 只。故答案为: B", + "knowledge_points": [ + "十几减 7,6 的退位减法" + ], + "source": "23-24 一年级上·湖南怀化·期末" + }, + { + "id": "124", + "unit": "20以内的退位减法1", + "question_type": "选择题", + "difficulty": 0.85, + "question": "与算式 7 + 6 得数相等的算式是 ( )。", + "options": [ + "A. 8 + 5", + "B. 8 + 3", + "C. 15 - 7" + ], + "answer": "A", + "solution": "【分析】计算出每个算式的得数,找出与 7 + 6 得数相等的即可.\n【详解】 7 + 6 = 13,A. 8 + 5 = 13,与算式 7 + 6 得数相等;B. 8 + 3 = 11,与算式 7 + 6 得数不相等;C. 15 - 7 = 8,与算式 7 + 6 得数不相等。与算式 7 + 6 得数相等的算式是 8 + 5 。故答案为: A", + "knowledge_points": [ + "十几减 7,6 的退位减法", + "8 加几的进位加法", + "5~2 加几的进位加法" + ], + "source": "23-24一年级上·山东菏泽·期末" + }, + { + "id": "125", + "unit": "20以内的退位减法1", + "question_type": "选择题", + "difficulty": 0.85, + "question": "16-□>9,□最大填()。", + "options": [ + "A. 6", + "B. 7", + "C. 9" + ], + "answer": "A", + "solution": "【分析】先用16减去9求出差,再用差减去1,即可解决.\n【详解】16-9-1=7-1=6,因此16-□>9,□最大填6。故答案为:A", + "knowledge_points": [ + "连减(20以内)", + "20以内数的比大小" + ], + "source": "23-24 一年级上·甘肃陇南·期末" + }, + { + "id": "126", + "unit": "20以内的退位减法1", + "question_type": "填空题", + "difficulty": 0.65, + "question": "朵朵今年 9 岁,淘淘哥哥今年 11 岁。5 年后淘淘哥哥比朵朵大( )岁。", + "options": [], + "answer": "2", + "solution": "【分析】根据年龄差不变可知,今年淘淘哥哥比朵朵大几岁, 5 年后同样大几岁。根据减法的意义,淘淘哥哥今年的年龄 - 朵朵今年的年龄 = 大的年龄.\n【详解】11 - 9 = 2(岁),朵朵今年9岁,淘淘哥哥今年11岁。5年后淘淘哥哥比朵朵大2岁。", + "knowledge_points": [ + "十几减9的退位减法", + "年龄问题" + ], + "source": "23-24 一年级下·湖南湘西·期中" + }, + { + "id": "127", + "unit": "20以内的退位减法1", + "question_type": "填空题", + "difficulty": 0.85, + "question": "树上有 17 个松果,采了()个后,还剩下 9 个松果。", + "options": [], + "answer": "8", + "solution": "【分析】求采了几个,根据减法的意义,原有的数量 - 剩下的数量 = 采了的数量,计算即可.\n【详解】17 - 9 = 8(个),树上有 17 个松果,采了 8 个后,还剩下 9 个松果。", + "knowledge_points": [ + "十几减9的退位减法" + ], + "source": "23-24 一年级下·河南驻马店·期中" + }, + { + "id": "128", + "unit": "20以内的退位减法1", + "question_type": "填空题", + "difficulty": 0.65, + "question": "填上合适的数.\n11 - ( ) = 7;15 - ( ) = 4;( ) + 2 = 11\n( ) - 9 = 5;( ) - 8 = 7;7 + ( ) = 16", + "options": [], + "answer": "4;11;9;14;15;9", + "solution": "【分析】本题根据加数 + 加数 = 和,可转换为和 - 一个加数 = 另一个加数;被减数 - 减数 = 差,可转换为被减数 - 差 = 减数,或减数 + 差 = 被减数,代入计算即可.\n【详解】11 - () = 7,可转换为 11 - 7 = 4,括号里填 4;15 - () = 4,可转换为 15 - 4 = 11,括号里填 11;( ) +2 = 11,可转换为 11 - 2 = 9,括号里填 9;( ) -9 = 5,可转换为 9 + 5 = 14,括号里填 14;( ) -8 = 7,可转换为 8 + 7 = 15,括号里填 15;7+ () =16,可转换为 16 - 7 = 9,括号里填 9。", + "knowledge_points": [ + "十几减 5~2 的退位减法", + "9 加几的进位加法", + "十几减 7,6 的退位减法", + "8 加几的进位加法" + ], + "source": "23-24 一年级下·广东广州·期中" + }, + { + "id": "129", + "unit": "20以内的退位减法1", + "question_type": "填空题", + "difficulty": 0.85, + "question": "计算 14-6 可以这样想:先算 10 - 6 = ( ) ,再算 4 + ( ) = ( );也可以这样想:因为 6 + ( ) = 14,所以 14 - 6 = ( ) 。", + "options": [], + "answer": "4;4;8;8;8", + "solution": "【分析】计算 14 - 6 时,可以将 14 分成 10 和 4,先用 10 - 6,计算出的结果再加 4 即可;也可以根据想加算减法,6 和 4 合起来就是 10,再加 4 就是 14,也就是 6 + 8 = 14,加数 + 加数 = 和,可转换为和 - 一个加数 = 另一个加数,即 14 - 6 = 8 .\n【详解】计算 14 - 6 可以这样想:先算 10 - 6 = 4,再算 4 + 4 = 8;也可以这样想:因为 6 + 8 = 14,所以 14 - 6 = 8 。", + "knowledge_points": [ + "十几减 7,6 的退位减法" + ], + "source": "23-24 一年级下·四川乐山·期中" + }, + { + "id": "130", + "unit": "20以内的退位减法1", + "question_type": "填空题", + "difficulty": 0.65, + "question": "计算 15 - 7,可以这样想:先算 10 - 7 = () ,再算 5 + () = ();也可以想加算减:因为 7 + () = 15,所以 15 - 7 = () 。", + "options": [], + "answer": "3;3;8;8;8", + "solution": "【分析】先把 15 分成 10 和 5,再计算 10 - 7 的结果和 5 相加就是最后得数;想加算减就是用和减去一个加数等于另一个加数,据此解答.\n【详解】填空如下:计算 15 - 7,可以这样想:先算 10 - 7 = (3) , 再算 5+ (3) = (8);也可以想加算减:因为 7 + (8) = 15,所以 15 - 7 = (8) 。", + "knowledge_points": [ + "十几减 7,6 的退位减法" + ], + "source": "23-24 一年级下·四川绵阳·期中" + }, + { + "id": "131", + "unit": "20以内的退位减法1", + "question_type": "填空题", + "difficulty": 0.65, + "question": "小王有 14 颗糖,小胡有 8 颗糖,小王比小胡多( )颗糖;小王给小胡( )颗糖,两个人的糖就一样多了。", + "options": [], + "answer": "6;3", + "solution": "【分析】用小王的数量减去小胡的数量即可求出小王比小胡多多少颗糖。将小王比小胡多的颗数分成相同的两份,其中一份给小胡即可.\n【详解】14 - 8 = 6 (颗),3 + 3 = 6 (颗),小王有 14 颗糖,小胡有 8 颗糖,小王比小胡多 6 颗糖;小王给小胡 3 颗糖,两个人的糖就一样多了。", + "knowledge_points": [ + "十几减8的退位减法", + "6的加减法" + ], + "source": "23-24 一年级下·四川绵阳·期中" + }, + { + "id": "132", + "unit": "20以内的退位减法1", + "question_type": "填空题", + "difficulty": 0.85, + "question": "7 比 12 少( ), 14 比 8 多( )。", + "options": [], + "answer": "5;6", + "solution": "【分析】要求7比12少多少,根据减法的意义,用12-7进行解答即可。要求 14 比 8 多多少,根据减法的意义,用 14 - 8 进行解答即可.\n【详解】12 - 7 = 5,所以7比12少5.14 - 8 = 6,所以 14 比 8 多 6。", + "knowledge_points": [ + "十几减8的退位减法", + "十几减7,6的退位减法" + ], + "source": "23-24 一年级下·浙江温州·期中" + }, + { + "id": "133", + "unit": "20以内的退位减法1", + "question_type": "填空题", + "difficulty": 0.85, + "question": "计算 13 - 6,可以从10 里面减去( )得 4,再用 4 加( )得( ), 也可以想6加( )得13,13减6得( )。", + "options": [], + "answer": "6;3;7;7;7", + "solution": "【分析】根据 20 以内整数加减法运算,结合题干要求进行解答即可.\n【详解】计算 13 - 6,可以从 10 里面减去 6 得 4,再用 4 加 3 得 7;也可以想 6 加 7 得 13, 13 减 6 得 7。", + "knowledge_points": [ + "十几减 7,6 的退位减法" + ], + "source": "23-24一年级下·山西忻州·期中" + }, + { + "id": "134", + "unit": "20以内的退位减法1", + "question_type": "填空题", + "difficulty": 0.85, + "question": "计算 13 - 6,可以从10 里面减去( )得 4,再用 4 加( )得( ), 也可以想6加( )得13,13减6得( )。", + "options": [], + "answer": "6;3;7;7;7", + "solution": "【分析】根据 20 以内整数加减法运算,结合题干要求进行解答即可.\n【详解】计算 13 - 6,可以从 10 里面减去 6 得 4,再用 4 加 3 得 7;也可以想 6 加 7 得 13, 13 减 6 得 7。", + "knowledge_points": [ + "十几减 7,6 的退位减法" + ], + "source": "23-24一年级下·山西忻州·期中" + }, + { + "id": "135", + "unit": "20以内的退位减法1", + "question_type": "填空题", + "difficulty": 0.85, + "question": "12 比 5 多( );10 比 18 少( )。", + "options": [], + "answer": "7;8", + "solution": "【分析】求 12 比 5 多几,用 12-5 计算;求 10 比 18 少几,用 18-10 计算.\n【详解】12 - 5 = 7;18 - 10 = 8,12 比 5 多 7;10 比 18 少 8 。", + "knowledge_points": [ + "十几减 5~2 的退位减法", + "不退位减法(20以内)" + ], + "source": "23-24一年级下·浙江温州·期中" + }, + { + "id": "136", + "unit": "20以内的退位减法1", + "question_type": "填空题", + "difficulty": 0.65, + "question": "( )里最大能填几.\n8+( )<13;17-( )>9;3<10-( )", + "options": [], + "answer": "4;7;6", + "solution": "【分析】第1题:比13小的数有12,11,10。其中最大的是12,左侧算式结果为12即可;第2题:比9大的数有10,11,12。要想括号里的数最大,则左侧算式结果最小,为10即可;第3题:比3大的数有4,5,6。要想括号里的数最大,则右侧算式结果最小,为4即可.\n【详解】8+()=12,可转换为12-8=4,即8+4<13,括号里最大填4;17-()=10,可转换为17-10=7,即17-7>9,括号里最大填7;10-()=4,可转换为10-4=6,即3<10-6,括号里最大填6。", + "knowledge_points": [ + "十几减8的退位减法", + "不退位减法(20以内)", + "20 以内数的比大小", + "10 的加减法" + ], + "source": "23-24 一年级下·浙江温州·期中" + }, + { + "id": "137", + "unit": "20以内的退位减法1", + "question_type": "填空题", + "difficulty": 0.85, + "question": "小林折了 13 颗星星,小乐折的比小林少 6 颗,小乐折了( )颗星星。", + "options": [], + "answer": "7", + "solution": "【分析】求小乐折了几颗星星,根据减法的意义,小林折的数量 - 小乐比小林少折的数量 = 小乐折的数量,计算即可.\n【详解】 13 - 6 = 7 (颗),小林折了 13 颗星星,小乐折的比小林少 6 颗,小乐折了 7 颗星星。", + "knowledge_points": [ + "十几减 7,6 的退位减法" + ], + "source": "22-23 二年级上·河南南阳·期中" + }, + { + "id": "138", + "unit": "20以内的退位减法1", + "question_type": "填空题", + "difficulty": 0.65, + "question": "在括号里填上\">\"\"<\"或\"=\".\n9+8( )18;14-8( )15-9;17-9( )5", + "options": [], + "answer": "<;=;>", + "solution": "【分析】依次计算出各算式的结果再比较大小。比较大小时,数位多的数就大;数位相同比较最高位,最高位大的数就大;最高位相同比较下一位,直到比较出结果为止.\n【详解】9+8=17;17<18,则9+8<18;14-8=6;15-9=6;6=6,则14-8=15-9;17-9=8;8>5,则17-9>5。", + "knowledge_points": [ + "十几减8的退位减法", + "9加几的进位加法", + "十几减9的退位减法", + "20以内数的比大小" + ], + "source": "22-23 一年级下·湖南邵阳·期中" + }, + { + "id": "139", + "unit": "20以内的退位减法1", + "question_type": "填空题", + "difficulty": 0.85, + "question": "体育室有 15 个足球,一年级借走 4 个,二年级借走 6 个。体育室现在还剩( )个足球。", + "options": [], + "answer": "5", + "solution": "【分析】求还剩多少个足球,根据减法的意义,总数量 - 一年级借走的数量 - 二年级借走的数量=还剩的数量,计算即可.\n【详解】15 - 4 - 6 = 5(个),体育室现在还剩 5 个足球。", + "knowledge_points": [ + "连减 (20 以内)" + ], + "source": "23-24 一年级下·浙江温州·期中" + }, + { + "id": "140", + "unit": "20以内的退位减法1", + "question_type": "填空题", + "difficulty": 0.65, + "question": "淘气有12张卡片,笑笑有 7 张卡片,淘气和笑笑一共有( )张卡片;笑笑比淘气少( )张卡片。", + "options": [], + "answer": "19;5", + "solution": "【分析】淘气的卡片数量加上笑笑的卡片数量就是一共的卡片数量,淘气的卡片数量减笑笑的卡片数量就是笑笑比淘气少的卡片数量,据此得出结论即可.\n【详解】 12 + 7 = 19 (张), 12 - 7 = 5 (张),故:淘气有 12 张卡片,笑笑有 7 张卡片,淘气和笑笑一共有 19 张卡片;笑笑比淘气少 5 张卡片。", + "knowledge_points": [ + "十几减 7,6 的退位减法", + "不进位加法(20以内)" + ], + "source": "23-24一年级下·河南商丘·期中" + }, + { + "id": "141", + "unit": "20以内的退位减法1", + "question_type": "填空题", + "difficulty": 0.65, + "question": "13 比 8 多( ), 4 比 11 少( )。", + "options": [], + "answer": "5;7", + "solution": "【分析】13 比 8 多多少用减法计算, 4 比 11 少多少用减法计算,据此解答\n【详解】13 - 8 = 5;11 - 4 = 7;故填空如下:13比8多(5),4比11少(7)。", + "knowledge_points": [ + "十几减 5~2 的退位减法", + "十几减 8 的退位减法", + "谁比谁多/少几的问题" + ], + "source": "23-24 一年级下·河南商丘·期中" + }, + { + "id": "142", + "unit": "20以内的退位减法1", + "question_type": "填空题", + "difficulty": 0.65, + "question": "填出括号里的数字.\n( ) + 7 = 15;8 + ( ) = 13;18 - 9 = ( )", + "options": [], + "answer": "8;5;9", + "solution": "【分析】和 - 加数 = 另一个加数, 18 减 9 可以看作 10 减 9,再加上未参加计算的 8. \n【详解】15 - 7 = 8,所以 8 + 7 = 15;13 - 8 = 5,所以 8 + 5 = 13.18 - 9 = 9 ", + "knowledge_points": [ + "十几减9的退位减法", + "十几减7,6的退位减法", + "8加几的进位加法" + ], + "source": "22-23 一年级下·湖北荆州·期中" + }, + { + "id": "143", + "unit": "20以内的退位减法1", + "question_type": "填空题", + "difficulty": 0.85, + "question": "今年哥哥17岁,弟弟9岁,再过( )年,弟弟也17岁。", + "options": [], + "answer": "8", + "solution": "【分析】用 17 减去弟弟今年的年龄,求出差,即可解决此题.\n【详解】17 - 9 = 8(年),即今年哥哥 17 岁,弟弟 9 岁,再过 8 年,弟弟也 17 岁。", + "knowledge_points": [ + "十几减9的退位减法" + ], + "source": "23-24一年级下·广东河源·期中" + }, + { + "id": "144", + "unit": "20以内的退位减法1", + "question_type": "填空题", + "difficulty": 0.85, + "question": "计算 14 - 8 时,可以想: 10 - 8 = ( ) , ( ) + 4 = ( ) , 所以 14 - 8 = ( );也可以想( )+8=14,所以 14 - 8 = ( ) 。", + "options": [], + "answer": "2;2;6;6;6;6", + "solution": "【分析】计算 14 - 8 时,可以把 14 分成 10 和 4,用 10-8,结果再加 4 。或者也可以根据加数 + 加数 = 和,可转换为和 - 一个加数 = 另一个加数,由此解答.\n【详解】计算 14 - 8 时,可以想: 10 - 8 = 2, 2 + 4 = 6,所以 14 - 8 = 6;也可以想 6 + 8 = 14,所以 14 - 8 = 6 。", + "knowledge_points": [ + "十几减8的退位减法" + ], + "source": "23-24 一年级下·福建莆田·期中" + }, + { + "id": "145", + "unit": "20以内的退位减法1", + "question_type": "填空题", + "difficulty": 0.85, + "question": "在下面的括号里填上\"+\"或\" - \".\n9( )4=13;6( )7=13;16( )7=9;10( )5=15", + "options": [], + "answer": "+;+;-;+", + "solution": "【分析】等号右侧的数大于左侧的两个数填写 \"+\";等号右侧的数比左侧的第一个数小填写 \"-\".\n【详解】9 + 4 = 13;6 + 7 = 13;16 - 7 = 9;10 + 5 = 15", + "knowledge_points": [ + "9 加几的进位加法", + "十几减 7,6 的退位减法", + "不进位加法(20 以内)", + "7,6 加几的进位加法" + ], + "source": "22-23一年级下·浙江温州·期中" + }, + { + "id": "146", + "unit": "20以内的退位减法1", + "question_type": "填空题", + "difficulty": 0.85, + "question": "12 和 14 中间的数是( ),这个数减去 4 就是( )。", + "options": [], + "answer": "13;9", + "solution": "【分析】20以内数从小到大为:0,1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20;由此可知12和14之间的数是13。再用13减4计算即可.\n【详解】13-4=9,12和14中间的数是13,这个数减去4就是9。", + "knowledge_points": [ + "十几减 5~2 的退位减法", + "20 以内数的排序" + ], + "source": "22-23一年级上·云南玉溪·期末" + }, + { + "id": "147", + "unit": "20以内的退位减法1", + "question_type": "填空题", + "difficulty": 0.85, + "question": "2 个一和 1 个十组成的数是( ),它比 7 多( ),比 15 少( )。", + "options": [], + "answer": "12;5;3", + "solution": "【分析】2 个一就是 2, 1 个十就是 10,合起来就是 12。求一个数比另一个数多(少)多少,用减法列式计算.\n【详解】12 - 7 = 5,15 - 12 = 3,2 个一和 1 个十组成的数是 12,它比 7 多 5,比 15 少 3 。", + "knowledge_points": [ + "十几减 7,6 的退位减法", + "不退位减法(20以内)", + "20 以内数的组成" + ], + "source": "23-24 一年级上·山东菏泽·期末" + }, + { + "id": "148", + "unit": "20以内的退位减法1", + "question_type": "填空题", + "difficulty": 0.85, + "question": "在括号里填上\">\"\"<\"或\"=\".\n5+8( )14;9( )15-6;10-8( )7;6+7( )5+8", + "options": [], + "answer": "<;=;<;=", + "solution": "【分析】先计算出每个算式的结果,再比较大小即可.\n【详解】5+8=13,故5+8<14;15-6=9,故9=15-6;10-8=2,故10-8<7;6+7=13,5+8=13,故6+7=5+8。", + "knowledge_points": [ + "十几减 7,6 的退位减法", + "5~2 加几的进位加法", + "20 以内数的比大小", + "10 的加减法" + ], + "source": "23-24 一年级上·山东菏泽·期末" + }, + { + "id": "149", + "unit": "20以内的退位减法1", + "question_type": "填空题", + "difficulty": 0.85, + "question": "在括号填上合适的数.\n5 + ( ) = 13;( ) - 8 = 2;11 + ( ) = 15;7 - 5 = ( ) - 7", + "options": [], + "answer": "8;10;4;9", + "solution": "【分析】根据整数加减法的计算法则及数量关系来解决此题。加数 = 和 - 另一个加数;被减数 = 差 + 减数.\n【详解】由题意分析得:13 - 5 = 8,所以,5 + 8 = 13;2 + 8 = 10,所以,10 - 8 = 2;15 - 11 = 4,所以, 11 + 4 = 15;7 - 5 = 2, 2 + 7 = 9,所以,7 - 5 = 9 - 7 。", + "knowledge_points": [ + "十几减 5~2 的退位减法", + "不进位加法(20 以内)", + "5~2 加几的进位加法", + "10 的加减法" + ], + "source": "23-24 一年级上·河南南阳·期末" + }, + { + "id": "150", + "unit": "20以内的退位减法1", + "question_type": "填空题", + "difficulty": 0.85, + "question": "被减数是 11,减数是 7,差是( )。", + "options": [], + "answer": "4", + "solution": "【分析】减法算式为:被减数 - 减数 = 差,由此代入计算.\n【详解】11 - 7 = 4,被减数是 11,减数是 7,差是 4。", + "knowledge_points": [ + "十几减 7,6 的退位减法" + ], + "source": "23-24 一年级上·广东汕头·期末" + }, + { + "id": "151", + "unit": "20以内的退位减法1", + "question_type": "填空题", + "difficulty": 0.85, + "question": "在括号里填上\"+\"或\" - \".\n10 ( ) 7 = 17;15 ( ) 8 = 7;8 ( ) 8 = 16\n10 ( ) 2 = 8;15 ( ) 10 = 5;6 ( ) 6 = 0", + "options": [], + "answer": "+;-;+;-;-;-", + "solution": "【分析】根据整数加减法的计算法则及数量关系来选择运算符号即可。加数+加数=和;被减数-减数=差.\n【详解】根据题意:10+7=17;15-8=7;8+8=16;10-2=8;15-10=5;6-6=0", + "knowledge_points": [ + "8 加几的进位加法", + "不进位加法(20 以内)", + "不退位减法(20 以内)", + "10 的加减法" + ], + "source": "23-24一年级上·广东广州·期末" + }, + { + "id": "152", + "unit": "20以内的退位减法1", + "question_type": "填空题", + "difficulty": 0.65, + "question": "( ) -5 = 2;4 + ( ) = 11;9 = ( ) + 4", + "options": [], + "answer": "7;7;5", + "solution": "【分析】根据 20 以内加,减法的计算法则,再利用加法和减法的关系,被减数 = 减数+ 差,加数 = 和 - 另一个加数,代入数据进行计算即可.\n【详解】因为 2 + 5 = 7,所以 7 - 5 = 2;因为 11 - 4 = 7,所以 4 + 7 = 11;因为 9 - 4 = 5,所以 9 = 4 + 5 。", + "knowledge_points": [ + "8,9 的加减法", + "5~2 加几的进位加法", + "7 的加减法" + ], + "source": "23-24一年级上·河南信阳·期末" + }, + { + "id": "153", + "unit": "20以内的退位减法1", + "question_type": "填空题", + "difficulty": 0.65, + "question": "一个加数是 9,另一个加数是 3,和是( )。减数是 7,被减数是 16,差是( )。", + "options": [], + "answer": "12;9", + "solution": "【分析】根据加数+加数=和,被减数-减数=差,将数据代入,即可得出答案.\n【详解】9+3=12,所以一个加数是9,另一个加数是3,和是12;16-7=9,所以减数是7,被减数是16,差是9。", + "knowledge_points": [ + "9加几的进位加法", + "十几减7,6的退位减法" + ], + "source": "23-24一年级上·湖北襄阳·期末" + }, + { + "id": "154", + "unit": "20以内的退位减法1", + "question_type": "判断题", + "difficulty": 0.85, + "question": "有 14 个西瓜,卖出去几个后还剩 6 个西瓜。 应列式 14 + 6 。( )", + "options": [], + "answer": "×", + "solution": "【分析】用原有的西瓜的总数减去还剩的个数,即可求出卖出的个数,据此判断即可.\n【详解】有 14 个西瓜,卖出去几个后还剩 6 个西瓜。 应列式: 14 - 6 。原题说法错误。故答案为: ×", + "knowledge_points": [ + "十几减 7,6 的退位减法" + ], + "source": "23-24 一年级下·河北沧州·期中" + }, + { + "id": "155", + "unit": "20以内的退位减法1", + "question_type": "判断题", + "difficulty": 0.65, + "question": "用破十法计算 13 - 9 时,先算 10 - 9 = 1,再算 3 + 1 = 4 。( )", + "options": [], + "answer": "√", + "solution": "【分析】根据整数减法的口算方法,计算 13 - 9 时,可以把 13 看作 10 + 3,然后再用 10 减去 9 求出差,再用求出的差加上 3,以此简便计算即可.\n【详解】用破十法计算 13 - 9 时,先算 10 - 9 = 1,再算 3 + 1 = 4,原题干说法正确。故答案为: √", + "knowledge_points": [ + "十几减9的退位减法" + ], + "source": "23-24 一年级下·湖北省直辖县级单位·期中" + }, + { + "id": "156", + "unit": "20以内的退位减法1", + "question_type": "判断题", + "difficulty": 0.65, + "question": "8 名女生排队,站成一排,每相邻两名女生之间站一名男生,一共可以站 8 名男生。( )", + "options": [], + "answer": "×", + "solution": "【分析】由题意可知, 8 名女生排队,站成一排,每相邻两名女生之间站一名男生。求出 8 名女生之间有几个间隔,就可以知道一共可以站几名男生。据此判断即可.\n【详解】 8 - 1 = 7 (个),8名女生之间有7个间隔。8名女生排队,站成一排,每相邻两名女生之间站一名男生,一共可以站7名男生。故答案为: ×", + "knowledge_points": [ + "间隔问题" + ], + "source": "23-24 二年级下·河南许昌·期中" + }, + { + "id": "157", + "unit": "20以内的退位减法1", + "question_type": "判断题", + "difficulty": 0.85, + "question": "12个珠子, 5个一串,能穿2串。( )", + "options": [], + "answer": "√", + "solution": "【分析】根据题意用总数量 12 依次减穿一串珠子的个数,减了几次就是能穿几串.\n【详解】由分析得: 12 - 5 = 7 (个);7 - 5 = 2 (个), 剩下的 2 个不能串一串。减了 2 次,能穿 2 串,原题说法正确。故答案为: √", + "knowledge_points": [ + "十几减 5~2 的退位减法", + "7 的加减法" + ], + "source": "22-23一年级下·湖南常德·期中" + }, + { + "id": "158", + "unit": "20以内的退位减法1", + "question_type": "判断题", + "difficulty": 0.85, + "question": "12 个小朋友站成一排,从左往右数,苗苗排在第 3;从右往左数,冰冰排在第 5 。苗苗和冰冰之间有 4 人。( )", + "options": [], + "answer": "√", + "solution": "【分析】用总人数分别减去苗苗的排列数与冰冰的排列数即可.\n【详解】12 - 3 - 5 = 9 - 5 = 4 (人),即苗苗和冰冰之间有 4 人,所以原题说法正确。故答案为: √", + "knowledge_points": [ + "连减 (20 以内)" + ], + "source": "23-24 三年级上·河南周口·期末" + }, + { + "id": "159", + "unit": "20以内的退位减法1", + "question_type": "判断题", + "difficulty": 0.85, + "question": "17 比 9 多 9。( )", + "options": [], + "answer": "×", + "solution": "【分析】求一个数比另一个数多几,根据减法的意义,用大数减小数即可.\n【详解】17 - 9 = 8,17 比 9 多 8。原题说法错误。故答案为: ×", + "knowledge_points": [ + "十几减9的退位减法" + ], + "source": "23-24一年级上·河南周口·期末" + }, + { + "id": "160", + "unit": "20以内的退位减法1", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式计算.\n![](images/3d17a5eee3ada5bf3c243fa99a559c510f98f14ff966df5fed47c9fd7c989478.jpg)\n□ ○ □ = □ (本)", + "options": [], + "answer": "16-7=9", + "solution": "【分析】题中一共有 16 本书,右边有 7 本,求左边书包里有多少本,根据减法的意义,总数量 - 右边的数量 = 左边书包里的数量,计算即可.\n【详解】16 - 7 = 9 (本),左边书包里有 9 本。", + "knowledge_points": [ + "图文问题", + "十几减 7,6 的退位减法" + ], + "source": "23-24 一年级下·湖南湘西·期中" + }, + { + "id": "161", + "unit": "20以内的退位减法1", + "question_type": "计算题", + "difficulty": 0.85, + "question": "列算式.\n![](images/b3ed0ac0d8ab4e8c79760b592ab3584c227005e841f3ab45320848efe31aa3ba.jpg)\n□ ○ □ = □ (本)", + "options": [], + "answer": "16-7=9", + "solution": "【分析】题中一共有 16 块西瓜,左边有 7 块,求右边有多少块,根据减法的意义,总数量 - 左边的数量 = 右边的数量,计算即可.\n【详解】 16 - 7 = 9 (块),右边有 9 块。", + "knowledge_points": [ + "图文问题", + "十几减 7,6 的退位减法" + ], + "source": "23-24 一年级下·广东广州·期中" + }, + { + "id": "162", + "unit": "20以内的退位减法1", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式计算.\n![](images/360d466cc0efd7b577061d4002eb02ff259ec1461ec4370c30c8fd34d96feac8.jpg)\n□ ○ □ = □ (个)", + "options": [], + "answer": "17-9=8", + "solution": "【分析】题中一共有 17 个萝卜,右边有 9 个,求左边筐里有多少个,根据减法的意义,总数量 - 右边的数量 = 左边的数量,计算即可.\n【详解】 17 - 9 = 8 (个),左边筐里有 8 个。", + "knowledge_points": [ + "图文问题", + "十几减9的退位减法" + ], + "source": "22-23 一年级下·广东佛山·期中" + }, + { + "id": "163", + "unit": "20以内的退位减法1", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式.\n![](images/ab6bb679d32fb39c48b7995fc8618cdc21da758ab78d3d88b0847759548099ab.jpg)\n□ ○ □ = □ ( )", + "options": [], + "answer": "13-4=9", + "solution": "【分析】题中一共有 13 支笔,左边有 4 支,求右边盒子里有多少支笔,根据减法的意义,总数量 - 左边的数量 = 右边的数量,计算即可.\n【详解】 13 - 4 = 9 (支),右边盒子里有 9 支笔。", + "knowledge_points": [ + "十几减 5~2 的退位减法", + "图文问题" + ], + "source": "23-24 一年级下·山东日照·期中" + }, + { + "id": "164", + "unit": "20以内的退位减法1", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式计算.\n![](images/86a8f1f66a2abf5810ccd0a818dcfda242519cc0e645123e0673617faff317c4.jpg)\n□ ○ □ = □ (本)", + "options": [], + "answer": "14-5=9", + "solution": "【分析】共 14 本,右边 5 本,用总数减去右边的本数即可得出左边的本数.\n【详解】14 - 5 = 9 (本)", + "knowledge_points": [ + "十几减 5~2 的退位减法", + "图文问题" + ], + "source": "23-24 一年级下·浙江温州·期中" + }, + { + "id": "165", + "unit": "20以内的退位减法1", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式并计算.\n![](images/f63a8ccc99e041e399e1c0725ac9ab4b64afd6252859d9fc228a66563cf6cde0.jpg)\n□ ○ □ = □ (个)", + "options": [], + "answer": "17-9=8", + "solution": "【分析】共 17 个,左边 9 个,用总数减去左边的数量即可求出右边的数量.\n【详解】 17 - 9 = 8 (个)", + "knowledge_points": [ + "图文问题", + "十几减9的退位减法" + ], + "source": "23-24 一年级下·山西忻州·期中" + }, + { + "id": "166", + "unit": "20以内的退位减法1", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式计算.\n![](images/ba72c96ca1161ecc49ec3fc76b96418568acc8a69ddd336ba8bf4671ac30865e.jpg)\n□ ○ □ = □ ( )", + "options": [], + "answer": "16-7=9", + "solution": "【分析】共 16 个,右边 7 个,用 16 减 7 即可求出左边的个数.\n【详解】 16 - 7 = 9 (个)", + "knowledge_points": [ + "图文问题", + "十几减 7,6 的退位减法" + ], + "source": "23-24 一年级下·湖南邵阳·期中" + }, + { + "id": "167", + "unit": "20以内的退位减法1", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式计算.\n![](images/614fc3dd6068c898f9ffbbe80d58e1cead1dd77fb9c53a66cdb553a99749ead0.jpg)\n□ ○ □ = □ (个)", + "options": [], + "answer": "12-4=8", + "solution": "【分析】用羽毛球的总数量减去左边的数量,求出差,就是右边的数量.\n【详解】根据题意:12-4=8(个)", + "knowledge_points": [ + "十几减 5~2 的退位减法", + "图文问题" + ], + "source": "23-24 一年级下·甘肃庆阳·期中" + }, + { + "id": "168", + "unit": "20以内的退位减法1", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式计算.\n![](images/637c67f646a301227fe84a1b95f4a6fa485b90bf049317946eecd92b5ddf6047.jpg)\n□ ○ □ = □ ( )", + "options": [], + "answer": "13-7=6", + "solution": "【分析】用雨伞的总数量减去右边的数量,求出差,就是左边的数量.\n【详解】根据题意:13-7=6(把)", + "knowledge_points": [ + "图文问题", + "十几减 7,6 的退位减法" + ], + "source": "23-24 一年级下·福建三明·期中" + }, + { + "id": "169", + "unit": "20以内的退位减法1", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式计算.\n![](images/8ffa1b460adfaa95abf8b8ff875ef0e4694f737f35d8c03e1e85928ba6bb5cd1.jpg)\n□ ○ □ = □ (个)", + "options": [], + "answer": "14-7=7", + "solution": "【分析】共14个,右边7个,用14减7即可求出左边的个数.\n【详解】14-7=7(个)", + "knowledge_points": [ + "图文问题", + "十几减7,6的退位减法" + ], + "source": "22-23 一年级下·湖北荆州·期中" + }, + { + "id": "170", + "unit": "20以内的退位减法1", + "question_type": "计算题", + "difficulty": 0.85, + "question": "列式我可以.\n![](images/a6d25b314c4967549b1d48c87809eaf16ab50197a38d827b09bc4d895e0dd6ec.jpg)\n□ ○ □ = □ ( )", + "options": [], + "answer": "16-8=8", + "solution": "【分析】用笔的总数量减去右边的数量,求出差,就是左边的数量.\n【详解】根据题意:16-8=8(支)", + "knowledge_points": [ + "十几减8的退位减法", + "图文问题" + ], + "source": "23-24 一年级下·河南三门峡·期中" + }, + { + "id": "171", + "unit": "20以内的退位减法1", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式.\n![](images/8379648f25ef637f298ba4eb28f3f90084e6710a4eb5f3a88e5669c511edc716.jpg)\n□ ○ □ = □ (个)", + "options": [], + "answer": "12-7=5", + "solution": "【分析】题中一共有 12 个蛋糕,右边有 7 个,求左边盒子里有多少个蛋糕,根据减法的意义,用总数量 - 右边的数量 = 左边的数量,计算即可.\n【详解】 12 - 7 = 5 (个),左边盒子里有 5 个蛋糕", + "knowledge_points": [ + "图文问题", + "十几减 7,6 的退位减法" + ], + "source": "22-23 一年级下·吉林·期中" + }, + { + "id": "172", + "unit": "20以内的退位减法1", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式计算.\n![](images/0a2dd9d3bd3a54b64539737f4f9cc6ba1feef7ff3d9bd598bc4bc88cdf2b8036.jpg)\n□ ○ □ = □ (条)", + "options": [], + "answer": "13-9=4", + "solution": "【分析】题中一共有 13 条鱼,左边有 9 条,求右边有多少条鱼,根据减法的意义,用总数量 - 左边的数量,计算即可.\n【详解】 13 - 9 = 4 (条),右边有 4 条鱼。", + "knowledge_points": [ + "图文问题", + "十几减9的退位减法" + ], + "source": "22-23 一年级下·湖北孝感·期中" + }, + { + "id": "173", + "unit": "20以内的退位减法1", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式计算.\n![](images/db87f518e41ee9bc4a8ae99c1fd7d08902073f0c62d6ea8755971adb7ed7dcaa.jpg)", + "options": [], + "answer": "13-5=8", + "solution": "【分析】题中一共要放13个桃子,左边有5个,求右边盘子里应该放几个桃子,用总数量减去左边的数量,计算即可.\n【详解】13-5=8(个),右边盘子里应该放8个桃子。", + "knowledge_points": [ + "十几减 5~2 的退位减法", + "图文问题" + ], + "source": "22-23 一年级下·浙江温州·期中" + }, + { + "id": "174", + "unit": "20以内的退位减法1", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列出算式.\n![](images/54b342c9f7533fb3fba49edeb58f81d7f91933918acc49f588f9de655b6a4079.jpg)\n□ ○ □ = □ ( )", + "options": [], + "answer": "15-9=6", + "solution": "【分析】一共 15 个,右边 9 个,用 15 减去 9 即可求出左边的个数.\n【详解】15 - 9 = 6 (个)", + "knowledge_points": [ + "图文问题", + "十几减9的退位减法" + ], + "source": "22-23 一年级下·广东江门·阶段练习" + }, + { + "id": "175", + "unit": "20以内的退位减法1", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式计算.\n![](images/7c7f40d333093b2f557dd8d29fbd854647d4d4536aa6c9420ff8e405954f581c.jpg)\n□ ○ □ = □ (个)", + "options": [], + "answer": "12-4=8", + "solution": "【分析】用苹果的总数量减去右边的苹果数量,求出差,就是左边盒子里的苹果数量.\n【详解】根据题意:12-4=8(个)", + "knowledge_points": [ + "十几减 5~2 的退位减法", + "图文问题" + ], + "source": "23-24一年级上·内蒙古通辽·期末" + }, + { + "id": "176", + "unit": "20以内的退位减法1", + "question_type": "解答题", + "difficulty": 0.85, + "question": "原来有 11 张彩纸,折纸鹤用了7张,还剩多少张彩纸。", + "options": [], + "answer": "4张", + "solution": "【分析】求还剩多少张,根据减法的意义,原来的数量 - 用了的数量 = 还剩的数量,计算即可.\n【详解】 11 - 7 = 4 (张),答:还剩 4 张彩纸。", + "knowledge_points": [ + "十几减 7,6 的退位减法" + ], + "source": "23-24 一年级下·河北沧州·期中" + }, + { + "id": "177", + "unit": "20以内的退位减法1", + "question_type": "解答题", + "difficulty": 0.65, + "question": "13 名同学站成一队,小方后面有 6 人,他的前面有几人。", + "options": [], + "answer": "6人", + "solution": "【分析】求他前面有几人,根据减法的意义,总人数 - 小方后面的人数 - 小方自己 = 他前面的人数,计算即可.\n【详解】13 - 6 - 1 = 6 (人),答:他的前面有 6 人。", + "knowledge_points": [ + "连减 (20 以内)" + ], + "source": "23-24 一年级下·广东广州·期中" + }, + { + "id": "178", + "unit": "20以内的退位减法1", + "question_type": "解答题", + "difficulty": 0.65, + "question": "小明今年 15 岁,小丽今年7岁,再过2年,小明比小丽大几岁。", + "options": [], + "answer": "8岁", + "solution": "【分析】根据年龄差不变可知,今年小明和小丽差几岁,2年后同样还是差几岁。小明今年的年龄 - 小丽今年的年龄=大的年龄,计算即可.\n【详解】15 - 7 = 8(岁),答:再过 2 年,小明比小丽大 8 岁。", + "knowledge_points": [ + "十几减 7,6 的退位减法" + ], + "source": "22-23一年级下·广东佛山·期中" + }, + { + "id": "179", + "unit": "20以内的退位减法1", + "question_type": "解答题", + "difficulty": 0.85, + "question": "草地上有 14 只黑鸽子, 6 只白鸽子,白鸽子比黑鸽子少几只。", + "options": [], + "answer": "8只", + "solution": "【分析】要求白鸽子比黑鸽子少几只,用黑鸽子的数量减去白鸽子的数量,即可得出答案.\n【详解】14 - 6 = 8(只),答:白鸽子比黑鸽子少 8 只。", + "knowledge_points": [ + "十几减 7,6 的退位减法" + ], + "source": "23-24 一年级下·山东日照·期中" + }, + { + "id": "180", + "unit": "20以内的退位减法1", + "question_type": "解答题", + "difficulty": 0.85, + "question": "妈妈买回 14 个苹果,比梨多5个。妈妈买了多少个梨。", + "options": [], + "answer": "9个", + "solution": "【分析】用苹果的个数减5即可求出梨的个数.\n【详解】14-5=9(个),答:妈妈买了9个梨。", + "knowledge_points": [ + "十几减 5~2 的退位减法" + ], + "source": "23-24 一年级下·湖南邵阳·期中" + }, + { + "id": "181", + "unit": "20以内的退位减法1", + "question_type": "解答题", + "difficulty": 0.85, + "question": "给小树浇水,要浇16 棵小树。小明已经浇了 9 棵,还要浇几棵。\n□ ○ □ = □ (棵)", + "options": [], + "answer": "7棵", + "solution": "【分析】用要浇的小树总数量减去已经浇了的数量,求出差,即可解决.\n【详解】16 - 9 = 7(棵),答:还要浇 7 棵。", + "knowledge_points": [ + "十几减9的退位减法" + ], + "source": "23-24 一年级下·甘肃庆阳·期中" + }, + { + "id": "182", + "unit": "20以内的退位减法1", + "question_type": "解答题", + "difficulty": 0.85, + "question": "草地上原有 14 只羊,跑了 5 只后,还有几只。\n□ ○ □ = □ (只)", + "options": [], + "answer": "9只", + "solution": "【分析】用草地上原来的羊数量减去跑了的数量,求出差,即可解决.\n【详解】14 - 5 = 9(只),答:还有 9 只。", + "knowledge_points": [ + "十几减 5~2 的退位减法" + ], + "source": "23-24 一年级下·甘肃庆阳·期中" + }, + { + "id": "183", + "unit": "20以内的退位减法1", + "question_type": "解答题", + "difficulty": 0.85, + "question": "小明比小红多 14 本故事书,小芳比小红多 6 本故事书,小明比小芳多多少本故事书。", + "options": [], + "answer": "8本", + "solution": "【分析】用小明比小红多的故事书数量减去小芳比小红多的故事书数量,求出差,即可求出小明比小芳多多少本故事书.\n【详解】14 - 6 = 8 (本),答:小明比小芳多 8 本故事书。", + "knowledge_points": [ + "十几减 7,6 的退位减法" + ], + "source": "23-24 一年级下·广东江门·期中" + }, + { + "id": "184", + "unit": "20以内的退位减法1", + "question_type": "解答题", + "difficulty": 0.85, + "question": "14个学生参加华伦星球亲子活动,其中男生有9人,是家长的有7人。参加亲子活动的女生有多少人。", + "options": [], + "answer": "5人", + "solution": "【分析】用参加华伦星球亲子活动的学生人数减去男生人数,求出差,即可解决.\n【详解】14 - 9 = 5(人),答:参加亲子活动的女生有 5 人。", + "knowledge_points": [ + "十几减9的退位减法" + ], + "source": "22-23一年级下·福建福州·期中" + }, + { + "id": "185", + "unit": "20以内的退位减法1", + "question_type": "解答题", + "difficulty": 0.65, + "question": "水果店新进了 18 箱水果,上午卖出了 5 箱,下午卖出了 7 箱,水果店现在还有多少箱水果。", + "options": [], + "answer": "6箱", + "solution": "【分析】求现在还有多少箱,根据减法的意义,新进的数量 - 上午卖出的数量 - 下午卖出的数量 = 还剩的数量,计算即可.\n【详解】18 - 5 - 7 = 6(箱),答:水果店现在还有 6 箱水果。", + "knowledge_points": [ + "连减 (20以内)" + ], + "source": "23-24 一年级下·湖南邵阳·期中" + }, + { + "id": "186", + "unit": "20以内的退位减法1", + "question_type": "解答题", + "difficulty": 0.85, + "question": "金鱼缸里有 13 条红金鱼,6 条花金鱼,再买几条花金鱼就和红金鱼同样多。", + "options": [], + "answer": "7条", + "solution": "【分析】用红金鱼的数量减去花金鱼的数量,求出差,即可解决此题.\n【详解】13 - 6 = 7 (条),答:再买 7 条花金鱼就和红金鱼同样多。", + "knowledge_points": [ + "十几减 7,6 的退位减法" + ], + "source": "23-24 一年级下·广东河源·期中" + }, + { + "id": "187", + "unit": "20以内的退位减法1", + "question_type": "解答题", + "difficulty": 0.85, + "question": "有 14 个同学在捉迷藏,其中女同学 9 个,已经捉住了 8 个,男同学有几个。", + "options": [], + "answer": "5人", + "solution": "【分析】用玩捉迷藏的总人数减去女同学人数,求出差,就是男同学人数;已经捉住8人与求男同学人数无关.\n【详解】14-9=5(人),答:男同学有5人。", + "knowledge_points": [ + "十几减9的退位减法" + ], + "source": "22-23一年级下·广东江门·期中" + }, + { + "id": "188", + "unit": "20以内的退位减法1", + "question_type": "解答题", + "difficulty": 0.85, + "question": "树上有 15 只小鸟,12只蝴蝶,飞走了6只小鸟,树上还剩多少只小鸟。", + "options": [], + "answer": "9只", + "solution": "【分析】用树上原来小鸟的数量减去飞走的数量,求出差,就是树上还剩的小鸟数量.\n【详解】15 - 6 = 9(只),答:树上还剩 9 只小鸟。", + "knowledge_points": [ + "十几减 7,6 的退位减法" + ], + "source": "22-23 一年级下·河南南阳·期中" + }, + { + "id": "189", + "unit": "20以内的退位减法1", + "question_type": "解答题", + "difficulty": 0.85, + "question": "大班有 17 个小朋友,其中有9个男孩,女孩有几个。", + "options": [], + "answer": "8人", + "solution": "【分析】根据题意,已知总人数是17,男孩人数是9,求女孩人数,女孩人数=总人数-男孩人数,据此解答.\n【详解】17-9=8(人),答:女孩有8人。", + "knowledge_points": [ + "十几减9的退位减法" + ], + "source": "23-24一年级上·河南周口·期末" + }, + { + "id": "190", + "unit": "20以内的退位减法1", + "question_type": "解答题", + "difficulty": 0.65, + "question": "实验小学一(1)班共有15人参加朗诵比赛。得分比小明高的有8人,得分比小明低的有几人。", + "options": [], + "answer": "6人", + "solution": "【分析】得分比小明低的人数 = 参加朗诵比赛的总人数 - 得分比小明高的人数 - 小明自己.\n【详解】15 - 8 - 1 = 6(人),答:得分比小明低的有 6 人。", + "knowledge_points": [ + "连减 (20以内)" + ], + "source": "23-24一年级上·贵州遵义·期末" + }, + { + "id": "191", + "unit": "20以内的退位减法1", + "question_type": "解答题", + "difficulty": 0.65, + "question": "将一包糖果分给5个小朋友,如果每人分2块,还剩1块。如果每人分3块,这包糖果可以分给几个小朋友。", + "options": [], + "answer": "3个", + "solution": "【分析】用 5 个 2 相加,再加 1 即可求出糖的总数量。然后用糖的总数量连续减 3,减到不能减为止,减了几次就可以分给几个小朋友.\n【详解】2 + 2 + 2 + 2 + 2 = 10 (块);10 + 1 = 11 (块);11 - 3 = 8 (块);8 - 3 = 5 (块);5 - 3 = 2 (块),减了3次。答:这包糖果可以分给 3 个小朋友。", + "knowledge_points": [ + "十几减 5~2 的退位减法", + "8,9 的加减法", + "不进位加法(20 以内)", + "连加,连减(10 以内)" + ], + "source": "23-24一年级下·全国·课后作业" + }, + { + "id": "192", + "unit": "20以内的退位减法1", + "question_type": "解答题", + "difficulty": 0.85, + "question": "乐乐和淘淘读《弟子规》,读了一星期后,乐乐还剩 13 页没读,淘淘还剩 4 页没读。谁读的页数多。多多少页。", + "options": [], + "answer": "淘淘;9页", + "solution": "【分析】根据题意,两人读的书一样,比较剩的页数的多少,剩的多的读得少;剩的少的读得多;用剩的页数相减,计算出多几页即可.\n【详解】13>4,13-4=9(页),答:淘淘读的页数多,多9页。", + "knowledge_points": [ + "十几减 5~2 的退位减法", + "20 以内数的比大小" + ], + "source": "23-24 一年级下·全国·课后作业" + }, + { + "id": "193", + "unit": "20以内的退位减法1", + "question_type": "解答题", + "difficulty": 0.85, + "question": "从盒子里拿出 5 颗红弹珠,又放进 11 颗绿弹珠。盒子里多了几颗弹珠。", + "options": [], + "answer": "6颗", + "solution": "【分析】放进去的更多,用放进去的颗数减去拿出来的颗数即可求解.\n【详解】11 - 5 = 6(颗),答:盒子里多了 6 颗弹珠。", + "knowledge_points": [ + "十几减 5~2 的退位减法" + ], + "source": "23-24 一年级下·全国·课后作业" + }, + { + "id": "194", + "unit": "20以内的退位减法1", + "question_type": "解答题", + "difficulty": 0.65, + "question": "12 生肖排成一排,从左往右数,小马排第 7,小猪排第 12,小马和小猪之间有几个生肖。", + "options": [], + "answer": "4个", + "solution": "【分析】用 12 减去 7,其中包含了小猪,再减去 1 即可求解.\n【详解】12 - 7 - 1 = 4(个),答:小马和小猪之间有 4 个生肖。", + "knowledge_points": [ + "两个数之间有几个数", + "连减(20以内)" + ], + "source": "23-24一年级下·全国·课后作业" + }, + { + "id": "195", + "unit": "20以内的退位减法1", + "question_type": "解答题", + "difficulty": 0.65, + "question": "姐姐今年 12 岁,弟弟今年 8 岁,五年前两人的年龄和是多少岁。", + "options": [], + "answer": "10岁", + "solution": "【分析】用姐姐今年的年龄减 5 求出五年前姐姐的年龄,用弟弟今年的年龄减 5 求出弟弟五年前的年龄,然后再计算五年前两人的年龄和即可.\n【详解】12 - 5 = 7 (岁);8 - 5 = 3 (岁);7 + 3 = 10 (岁),答:五年前两人的年龄和是 10 岁。", + "knowledge_points": [ + "十几减 5~2 的退位减法", + "8,9 的加减法", + "10 的加减法" + ], + "source": "23-24 一年级下·全国·课后作业" + }, + { + "id": "196", + "unit": "20以内的退位减法1", + "question_type": "解答题", + "difficulty": 0.85, + "question": "小明养了一只小兔,它非常喜欢吃萝卜。原来有13个萝卜,小兔吃了一些,还剩7个,小兔吃了几个。\n![](images/5eaaa32b56c8999fdff66a9e557a02bc2306960a462a59b72cf612dabed7c394.jpg)\n□ ○ □ = □ (个)", + "options": [], + "answer": "6个", + "solution": "【分析】根据题意可知:求小兔吃了几个。用原有的个数减去剩下的即可.\n【详解】 13 - 7 = 6 (个),答:小兔吃了 6 个。", + "knowledge_points": [ + "十几减 7,6 的退位减法" + ], + "source": "23-24 一年级上·山东济宁·期末" + }, + { + "id": "197", + "unit": "20以内的退位减法1", + "question_type": "解答题", + "difficulty": 0.85, + "question": "一年级一班参加书法比赛的一共有 15 人,男生有 9 人,女生有多少人。\n□ ○ □ = □ (人)", + "options": [], + "answer": "6人", + "solution": "【分析】根据题意可知:求女生有多少人。用共有的人数减去男生的人数即可.\n【详解】 15 - 9 = 6 (人),答:女生有 6 人。", + "knowledge_points": [ + "十几减9的退位减法" + ], + "source": "23-24 一年级上·山东济宁·期末" + }, + { + "id": "198", + "unit": "20以内的退位减法1", + "question_type": "解答题", + "difficulty": 0.85, + "question": "盘子里一共有 12 块蛋糕,小明吃了 3 块后,盘子里现在有多少块蛋糕。\n□ ○ □ = □ (块)", + "options": [], + "answer": "9块", + "solution": "【分析】用盘子里原有的块数减去小明吃了的 3 块,即可求出现在的块数.\n【详解】 12 - 3 = 9 (块),答:盘子里现在有 9 块蛋糕。", + "knowledge_points": [ + "十几减 5~2 的退位减法" + ], + "source": "23-24 一年级上·河南信阳·期末" + }, + { + "id": "199", + "unit": "20以内的退位减法1", + "question_type": "解答题", + "difficulty": 0.65, + "question": "课间操的时候,男生 16 人排成一列队伍,其中小明的前面有 8 个小朋友,他的后面有多少个小朋友。", + "options": [], + "answer": "7人", + "solution": "【分析】16人排队,减去小明前面的人数和他自己,就是他后面的人数.\n【详解】16 - 8 - 1= 8 - 1 = 7 (个),答:他的后面有 7 个小朋友。", + "knowledge_points": [ + "连减 (20 以内)" + ], + "source": "23-24一年级上·浙江台州·期末" + }, + { + "id": "200", + "unit": "20以内的退位减法1", + "question_type": "解答题", + "difficulty": 0.65, + "question": "放寒假了。笑笑的爸爸给笑笑准备了 13 本《少儿画册》,第一个星期笑笑看了 8 本,第二个星期又看了 3 本。笑笑还有多少本没看。", + "options": [], + "answer": "2本", + "solution": "【分析】总共的书的本书减第一星期看完的本书,再减第二个星期看的本书,剩下的就是还没有看的本书,据此列式解答即可.\n【详解】13 - 8 - 3 = 2(本),答:笑笑还有 2 本没看。", + "knowledge_points": [ + "连减 (20 以内)" + ], + "source": "22-23一年级上·福建泉州·期末" + }, + { + "id": "201", + "unit": "20以内的退位减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "11 - 6 + 7 = ( )。", + "options": [ + "A. 12", + "B. 8", + "C. 9" + ], + "answer": "A", + "solution": "【分析】整数混合运算法则:同级运算,从左到右依次计算.\n【详解】11 - 6 + 7= 5 + 7 = 12,故答案为: A", + "knowledge_points": [ + "加减混合运算(20以内)" + ], + "source": "23-24一年级上·河南洛阳·期末" + }, + { + "id": "202", + "unit": "20以内的退位减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "学号为1号到17号的小朋友在操场上做游戏,其中4号到11号是女生,其余都是男生,男生有()人。", + "options": [ + "A. 7", + "B. 8", + "C. 9" + ], + "answer": "C", + "solution": "【分析】根据题意可知作图如下:一共有 17 人,先用 11 减 4 再加 1 求出女生的人数,再用总人数减去女生的人数,即可求出男生的人数。![](images/6785d1167753ee8eb760475a774dde3369a318b316bbb0917dc856e41cf21b81.jpg)\n【详解】11 - 4 + 1 = 8(人),17 - 8 = 9(人),男生有 9 人。故答案为: C", + "knowledge_points": [ + "十几减 8 的退位减法", + "加减混合运算 (20 以内)" + ], + "source": "23-24一年级上·河南周口·期末" + }, + { + "id": "203", + "unit": "20以内的退位减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "奶奶买了 12 个橘子和 8 个苹果。奶奶最少再买()个苹果,苹果就比橘子多。", + "options": [ + "A. 4", + "B. 5", + "C. 6" + ], + "answer": "B", + "solution": "【分析】从题干可知:奶奶买了 12 个橘子和 8 个苹果,要求奶奶最少再买几个苹果,苹果就比橘子多,即先求出橘子比苹果多几个,再加上 1,即可得出答案.\n【详解】12 - 8 + 1= 4 + 1 = 5(个) ,所以,奶奶最少再买 5 个苹果,苹果就比橘子多。故答案为: B", + "knowledge_points": [ + "加减混合运算(20以内)" + ], + "source": "23-24一年级上·河南周口·期末" + }, + { + "id": "204", + "unit": "20以内的退位减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "在算式 17 - 9 = 8 中,( ) 是减数。", + "options": [ + "A. 17", + "B. 9", + "C. 8" + ], + "answer": "B", + "solution": "【分析】根据被减数 - 减数 = 差即可解答.\n【详解】由分析可得: 17 - 9 = 8 中,9是减数。故答案为: B", + "knowledge_points": [ + "十几减9的退位减法" + ], + "source": "23-24 一年级上·甘肃庆阳·期末" + }, + { + "id": "205", + "unit": "20以内的退位减法", + "question_type": "选择题", + "difficulty": 0.65, + "question": "12 个小朋友排成一排,从左边数,平平排在第 8 个,从右边数,平平排在 ( )。", + "options": [ + "A. 第5个", + "B. 第4个", + "C. 第3个", + "D. 20 个" + ], + "answer": "A", + "solution": "【分析】从右边数平平排的位次=这一排的总人数-从左边数平平排的位次+1.\n【详解】根据题意:12-8+1=4+1=5(个),即从右边数,平平排在第5个。故答案为:A", + "knowledge_points": [ + "加减混合运算(20以内)" + ], + "source": "21-22 一年级上·浙江·期末" + }, + { + "id": "206", + "unit": "20以内的退位减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "14-7=( )。", + "options": [ + "A. 7", + "B. 8", + "C. 9", + "D. 21" + ], + "answer": "A", + "solution": "【分析】计算14-7=7,得出结论即可.\n【详解】14-7=7,故答案为:A", + "knowledge_points": [ + "十几减 7,6 的退位减法" + ], + "source": "19-20 一年级上·黑龙江·期末" + }, + { + "id": "207", + "unit": "20以内的退位减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "12-7=( )。", + "options": [ + "A. 5", + "B. 6", + "C. 9", + "D. 14" + ], + "answer": "A", + "solution": "【分析】先用10-7=3,再用3加12个位上的2得5,据此得出结论即可.\n【详解】12-7=5,故答案为:A", + "knowledge_points": [ + "十几减 7,6 的退位减法" + ], + "source": "19-20 一年级上·黑龙江·期末" + }, + { + "id": "208", + "unit": "20以内的退位减法", + "question_type": "选择题", + "difficulty": 0.65, + "question": "哥哥有 14 支铅笔,弟弟有 8 支铅笔,哥哥给弟弟 ( ) 支后,两人的铅笔数一样多。", + "options": [ + "A. 3", + "B. 6", + "C. 11" + ], + "answer": "A", + "solution": "【分析】先求出哥哥比弟弟多的支数,然后将多的支数分成相同的两份,其中一份给弟弟即可。求出哥哥比弟弟多的数量是解题关键.\n【详解】14 - 8 = 6(支),3 + 3 = 6(支),哥哥给弟弟3支后,两人的铅笔数一样多。故答案为: A.", + "knowledge_points": [ + "十几减8的退位减法", + "6的加减法" + ], + "source": "22-23一年级下·浙江绍兴·期末" + }, + { + "id": "209", + "unit": "20以内的退位减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "贝贝在计算 13 - 8 时,可以先算(),再算 2 + 3 = 5,所以 13 - 8 = 5 。", + "options": [ + "A. 10 - 8 = 2", + "B. 13 - 3 = 10", + "C. 8 + 5 = 13" + ], + "answer": "A", + "solution": "【分析】利用破十法,把13分成10和3,先算10-8=2,再算2+3=5,据此即可解答.\n【详解】根据分析可知:在计算13-8时,可以先算10-8=2,再算2+3=5,所以13-8=5。故答案为:A", + "knowledge_points": [ + "十几减8的退位减法" + ], + "source": "22-23一年级·全国·假期作业" + }, + { + "id": "210", + "unit": "20以内的退位减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "计算 15-7 时,下列方法 ( ) 是错误的。", + "options": [ + "A. 先算 7 - 5 = 2,再算 10 + 2 = 12 ", + "B. 先想 7 + 8 = 15,得出 15 - 7 = 8 ", + "C. 先算 10 - 7 = 3,再算 3 + 5 = 8 ", + "D. 先算 15 - 5 = 10,再算 10 - 2 = 8" + ], + "answer": "A", + "solution": "【分析】根据十几减7的计算方法,可以利用想加法算减法,先想7+8=15,得出15-7=8,B选项是正确的;也可以先算10-7=3,再算3+5=8,C选项是正确的;先算15-5=10,再算10-2=8,D选项是正确的;先算7-5=2,再算10+2=12,不合理,A选项是错误的.\n【详解】根据分析可知:计算15-7时,下列方法A选项是错误的。故答案为:A", + "knowledge_points": [ + "十几减 7,6 的退位减法" + ], + "source": "22-23 一年级·全国·假期作业" + }, + { + "id": "211", + "unit": "20以内的退位减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "17-9=12-□,□里应填( )。", + "options": [ + "A. 9", + "B. 8", + "C. 4" + ], + "answer": "C", + "solution": "【分析】此题需要先算出等式左边等于几,根据等式左右两边结果相等,从而算出等式右边的未知数是多少。此题考查等式左右两边结果相等,20 以内的退位减法问题.\n【详解】等式左边 17 - 9 = 8,等式右边也要等于 8,得出 12 - 4 = 8,所以选择 .故答案为: C.", + "knowledge_points": [ + "一位数与两位数的退位减法" + ], + "source": "22-23 一年级下·全国·单元测试" + }, + { + "id": "212", + "unit": "20以内的退位减法", + "question_type": "选择题", + "difficulty": 0.65, + "question": "与 15-7 的得数不一样的算式是()。", + "options": [ + "A. 16 - 8", + "B. 5 + 3", + "C. 15 - 8" + ], + "answer": "C", + "solution": "【分析】根据 20 以内整数加减法运算,算出各个算式的得数,再进行比较即可得出答案。本题考查学生对 20 以内整数加减运算的掌握和运用.\n【详解】15 - 7 = 8,A. 16 - 8 = 8,不符合题意。. 5 + 3 = 8,不符合题意。. 15 - 8 = 7,符合题意。故答案为: C.", + "knowledge_points": [ + "十几减8的退位减法", + "8,9的加减法", + "十几减7,6的退位减法" + ], + "source": "22-23一年级下·全国·单元测试" + }, + { + "id": "213", + "unit": "20以内的退位减法", + "question_type": "选择题", + "difficulty": 0.65, + "question": "一队同学去参加科学小组活动,李红在王明的前面,从前往后数,王明排第10,从后往前数,李红排第 10。李红和王明之间有 3 人,这一队共有()人。", + "options": [ + "A. 23", + "B. 20", + "C. 15", + "D. 17" + ], + "answer": "C", + "solution": "【分析】根据 '李红在王明的前面,从前往后数,王明排第 10,从后往前数,李红排第 10 。李红和王明之间有 3 人' 可知,李红,王明和他们中间的 3 个人被重复数了 2 次。所以共有 '10+10-5'人。本题主要考查了排队问题,关键是弄清两者的计算方向.\n【详解】10 + 10 - 5= 20 - 5 = 15 (人),所以,这一队共有 15 人。故答案为: C.", + "knowledge_points": [ + "加减混合运算(20以内)" + ], + "source": "22-23 四年级上·北京昌平·期末" + }, + { + "id": "214", + "unit": "20以内的退位减法", + "question_type": "选择题", + "difficulty": 0.65, + "question": "一张餐桌坐6人, 20人可以坐满 ( ) 张餐桌。", + "options": [ + "A. 3", + "B. 4", + "C. 5" + ], + "answer": "A", + "solution": "【分析】求20里面有几个6相加,就是坐满几张餐桌,据此解答.\n【详解】6+6=12(人),12+6=18(人),18+6=24(人),18<20<24,所以20人可以坐满3张餐桌。故答案为:A", + "knowledge_points": [ + "连加 (20 以内)" + ], + "source": "21-22一年级下·黑龙江双鸭山·期末" + }, + { + "id": "215", + "unit": "20以内的退位减法", + "question_type": "选择题", + "difficulty": 0.65, + "question": "3 个同学一起折千纸鹤,每人折了 4 只,他们一共折了 ( ) 只千纸鹤。", + "options": [ + "A. 12", + "B. 15", + "C. 7" + ], + "answer": "A", + "solution": "【分析】求 3 个人一共折了多少只,就是把三个人折的只数加起来,据此解答。本题考查 20 以内连加的简单应用.\n【详解】 4 + 4 + 4= 8 + 4 = 12(只),所以他们一共折了 12 只千纸鹤。故答案为: A.", + "knowledge_points": [ + "连加 (20 以内)" + ], + "source": "21-22 一年级下·黑龙江双鸭山·期末" + }, + { + "id": "216", + "unit": "20以内的退位减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "在计算 14 - 9 时,下面的方法错误的是 ( )。", + "options": [ + "A. 14 - 4 - 5", + "B. 14 - 9 + 9", + "C. 10 - 9 + 4" + ], + "answer": "B", + "solution": "【分析】先计算出 14 - 9 的得数,再分别计算出每个选项的得数,进行比较即可。本题考查 20 以内加,减法的计算,注意计算的准确性.\n【详解】14 - 9 = 5,A. 选项 14 - 4 - 5 = 5 ,B. 选项 14 - 9 + 9 = 14,C. 选项 10 - 9 + 4 = 5,故答案为: B.", + "knowledge_points": [ + "十几减9的退位减法" + ], + "source": "21-22 一年级下·四川广元·期末" + }, + { + "id": "217", + "unit": "20以内的退位减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "有 16 个草莓小明吃了 8 个,还剩()个。", + "options": [ + "A. 10", + "B. 9", + "C. 8" + ], + "answer": "C", + "solution": "【分析】用草莓的总数减去小明吃了的个数,即可求出还剩的个数。本题考查 20 以内的退位减法。理解题意,找出数量关系,列式计算即可.\n【详解】16 - 8 = 8(个),还剩 8 个。故答案为: C.", + "knowledge_points": [ + "十几减8的退位减法" + ], + "source": "21-22 一年级下·四川广元·期末" + }, + { + "id": "218", + "unit": "20以内的退位减法", + "question_type": "选择题", + "difficulty": 0.65, + "question": "下面算式中, ( )的得数最大。", + "options": [ + "A. 14 - 8", + "B. 13 - 5", + "C. 16 - 7" + ], + "answer": "C", + "solution": "【分析】根据题意,分别算出每个选项的得数,再比较即可解答.\n【详解】.14-8=6,B.13-5=8,C.16-7=9,9>8>6,故答案为:C", + "knowledge_points": [ + "十几减 8 的退位减法", + "十几减 5~2 的退位减法", + "十几减 7,6 的退位减法", + "10 以内数的比大小" + ], + "source": "21-22 一年级下·广西玉林·期末" + }, + { + "id": "219", + "unit": "20以内的退位减法", + "question_type": "选择题", + "difficulty": 0.65, + "question": "在计算 18- (9-5) 时应先算 ( )。", + "options": [ + "A. 18 - 9", + "B. 9 - 5", + "C. 18 - 5" + ], + "answer": "B", + "solution": "【分析】在混合运算中,有括号时,应先算括号里面的,再算括号外面的,据此选择即可。本题考查混合运算的运算顺序,关键是有括号时先算括号里面的.\n【详解】计算 18 - (9 - 5) , 应先算括号里面的,即 9 - 5 。故答案为: B", + "knowledge_points": [ + "带有小括号的混合运算" + ], + "source": "21-22 一年级下·贵州遵义·期末" + }, + { + "id": "220", + "unit": "20以内的退位减法", + "question_type": "选择题", + "difficulty": 0.65, + "question": "王奶奶一共养了白色、灰色、黑色的小兔子12只,其中白色3只,黑色2只。横线上可以填( )。", + "options": [ + "A. 灰色兔子有 7 只", + "B. 又养了 5 只", + "C. 灰色兔子有几只" + ], + "answer": "C", + "solution": "【分析】已知三种兔子的总只数、黑色和白色小兔子的只数,求灰色有几只,用减法列式即可.\n【详解】根据分析可得:横线上可以填灰色兔子有几只。故答案为:C", + "knowledge_points": [ + "\"提问题\" \"填条件\" 问题" + ], + "source": "21-22 一年级下·河南信阳·期末" + }, + { + "id": "221", + "unit": "20以内的退位减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "下面计算 14 - 7 的过程,错误的是 ( )。", + "options": [ + "A. 先算 10 - 7 = 3,再算 4 + 3 = 7 ", + "B. 因为 7 + 7 = 14,所以 14 - 7 = 7 ", + "C. 先算 4 + 7 = 11,再算 11 + 10 = 21" + ], + "answer": "C", + "solution": "【分析】 14 - 7 的计算过程:先算 10 - 7 = 3,再算 4 + 3 = 7 或因为 7 + 7 = 14,所以 14 - 7 = 7 。本题主要考查十几减 7 的知识点,要掌握计算过程并熟练计算.\n【详解】由分析可知,选项 A 和 B 是正确的,选项 C 是错误的。故答案为: C.", + "knowledge_points": [ + "十几减 7,6 的退位减法" + ], + "source": "21-22 一年级下·河北张家口·期末" + }, + { + "id": "222", + "unit": "20以内的退位减法", + "question_type": "填空题", + "difficulty": 0.65, + "question": "从盒子中拿出 5 颗红弹珠,又放进 11 颗绿弹珠,盒子中多了( )颗弹珠。", + "options": [], + "answer": "6", + "solution": "【分析】根据题意,先拿出 5 颗红弹珠,此时盒子里少了 5 颗,而又放进 11 颗绿弹珠,不仅补上了之前拿出的 5 颗,又多了 11 - 5 = 6 (颗)。由此解答.\n【详解】11 - 5 = 6(颗),盒子中多了 6 颗弹珠。", + "knowledge_points": [ + "十几减 5~2 的退位减法" + ], + "source": "23-24 一年级上·河南周口·期末" + }, + { + "id": "223", + "unit": "20以内的退位减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "两个加数都是 8,和是( );被减数是 14,减数是 5,差是( )。", + "options": [], + "answer": "16;9", + "solution": "【分析】两个加数都是8,求和,列式为 8 + 8;被减数是14,减数是 5,求差,列式为 14 - 5,由此解答.\n【详解】 8 + 8 = 16;14 - 5 = 9,所以两个加数都是 8,和是 16;被减数是 14,减数是 5,差是 9 。", + "knowledge_points": [ + "十几减 5~2 的退位减法", + "8加几的进位加法" + ], + "source": "23-24 一年级上·河南周口·期末" + }, + { + "id": "224", + "unit": "20以内的退位减法", + "question_type": "填空题", + "difficulty": 0.65, + "question": "同学们排成一队做操,小芳排第 9,小明排第 14,他们两人之间有( )人。", + "options": [], + "answer": "4", + "solution": "【分析】求他们两人之间的人数,用 14 减去 9 再减去 1 即可.\n【详解】14 - 9 - 1 = 4(人),他们两人之间有 4 人。", + "knowledge_points": [ + "连减 (20以内)" + ], + "source": "23-24 一年级上·甘肃庆阳·期末" + }, + { + "id": "225", + "unit": "20以内的退位减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "在括号里填上合适的数.\n\n4 + ( ) = 9;3 + ( ) = 11;15 - ( ) = 10\n( ) + 7 = 11;( ) - 10 = 3;( ) + 7 = 9", + "options": [], + "answer": "5;8;5;4;13;2", + "solution": "【分析】根据'加数 = 和 - 另一个加数,减数 = 被减数 - 差,被减数 = 差 + 减数'来解决此题.\n【详解】 9 - 4 = 5,故, 4 + 5 = 9;11 - 3 = 8,故, 3 + 8 = 11;15 - 10 = 5,故, 15 - 5 = 10;11 - 7 = 4,故, 4 + 7 = 11;3 + 10 = 13,故, 13 - 10 = 3;9 - 7 = 2,故, 2 + 7 = 9 。", + "knowledge_points": [ + "8,9 的加减法", + "十几减 5~2 的退位减法", + "十几减 7,6 的退位减法", + "不进位加法(20 以内)" + ], + "source": "22-23 一年级上·甘肃庆阳·期末" + }, + { + "id": "226", + "unit": "20以内的退位减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "括号里填上合适的数.\n\n5+( )=8;( )+4=13;7-( )=5;( )-5>6", + "options": [], + "answer": "3;9;2;12", + "solution": "【分析】根据加数=和-另一个加数,减数=被减数-差及整数加减法的计算法则来解决前3小题。最后1小题,先计算6加5的和,然后加上1,求出和,即可解决此题。(此小题答案不唯一)\n【详解】8-5=3,故5+3=8;13-4=9,故9+4=13;7-5=2,故7-2=5;6+5=11,11+1=12,12-5=7,故12-5>6。", + "knowledge_points": [ + "8,9 的加减法", + "7 的加减法", + "十几减 5~2 的退位减法", + "20 以内数的比大小" + ], + "source": "22-23 一年级上·山西忻州·期末" + }, + { + "id": "227", + "unit": "20以内的退位减法", + "question_type": "填空题", + "difficulty": 0.65, + "question": "在括号里填上合适的数.\n\n7 + ( ) = 11;( ) + 5 = 13;( ) - 6 = 10;18 - ( ) = 9", + "options": [], + "answer": "4;8;16;9", + "solution": "【分析】和 - 加数 = 另一个加数,差 + 减数 = 被减数,被减数 - 差 = 减数,据此计算.\n【详解】11 - 7 = 4,所以 7 + 4 = 11;13 - 5 = 8,所以 8 + 5 = 13;10 + 6 = 16,所以 16 - 6 = 10;18 - 9 = 9 。", + "knowledge_points": [ + "7,6 加几的进位加法", + "十几减 7,6 的退位减法", + "8 加几的进位加法", + "不退位减法 (20 以内)" + ], + "source": "22-23一年级上·湖北武汉·期末" + }, + { + "id": "228", + "unit": "20以内的退位减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "在减法算式13-5=8中,减数是( ),差是( )。", + "options": [], + "answer": "5;8", + "solution": "【分析】减法算式为:被减数-减数=差,由此可知13是被减数,5是减数,8是差.\n【详解】在减法算式13-5=8中,减数是5,差是8。", + "knowledge_points": [ + "加,减法的意义和各部分间的关系", + "十几减 5~2 的退位减法" + ], + "source": "22-23一年级上·浙江台州·期末" + }, + { + "id": "229", + "unit": "20以内的退位减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": " 7 + ( ) = 17;( ) +8 = 13;15 = ( ) + ( )", + "options": [], + "answer": "10;5;7;8", + "solution": "【分析】根据'加数 = 和 - 另一个加数'来完成此题。第3个算式,根据加法计算法则,找出两数相加等于15即可;答案不唯一.\n【详解】 17 - 7 = 10,故, 7 + 10 = 17;13 - 8 = 5,故, 5 + 8 = 13;7 + 8 = 15,即, 15 = 7 + 8 。(答案不唯一)", + "knowledge_points": [ + "十几减 8 的退位减法", + "7,6 加几的进位加法", + "不进位加法(20 以内)", + "不退位减法(20 以内)" + ], + "source": "21-22 一年级上·湖北武汉·期末" + }, + { + "id": "230", + "unit": "20以内的退位减法", + "question_type": "填空题", + "difficulty": 0.65, + "question": "按规律填数.\n\n(1)3, 6,( ),12, ( ).\n\n(2)20, 17, 14,( ),( )。", + "options": [], + "answer": "9;15;11;8", + "solution": "【分析】(1)右边的数比左边相邻的数大3,据此计算;(2) 右边的数比左边相邻的数小 3,据此计算.\n【详解】 (1) 6 + 3 = 9,12 + 3 = 15;3, 6, 9, 12, 15。 (2) 14 - 3 = 11,11 - 3 = 8;20, 17, 14, 11, 8。", + "knowledge_points": [ + "8,9 的加减法", + "十几减 5~2 的退位减法", + "数字排列的规律", + "不进位加法(20 以内)" + ], + "source": "21-22 一年级上·浙江·期末" + }, + { + "id": "231", + "unit": "20以内的退位减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "有11个小朋友,有9把椅子,还差( )把椅子才够一人一把。", + "options": [], + "answer": "2", + "solution": "【分析】由题意可知:一人一把椅子,则需要 11 把椅子,已经有 9 把椅子了,求还差几把椅子,根据减法的意义,列式解答即可。本题考查学生对 20 以内整数加减法运算的运用.\n【详解】 11 - 9 = 2 (把),所以,还差 2 把椅子才够一人一把。", + "knowledge_points": [ + "十几减9的退位减法" + ], + "source": "22-23一年级·全国·假期作业" + }, + { + "id": "232", + "unit": "20以内的退位减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "1,3,15这三个中,( )离11最近。", + "options": [], + "answer": "15", + "solution": "【分析】分别计算出1,3,15与11相差几,然后进行比较即可.\n【详解】11-1=10,11-3=8,15-11=4,10>8>4,所以1,3,15这三个中,15离11最近。", + "knowledge_points": [ + "20以内数的排序", + "两位数与两位数的加减法口算", + "不进位加法(20以内)", + "20以内数的比大小" + ], + "source": "20-21一年级上·北京丰台·期末" + }, + { + "id": "233", + "unit": "20以内的退位减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "星期天,猪妈妈一家 14 头猪去郊游,来到小河边,猪妈妈先带 7 头小猪过河,河对岸还有( )头猪。", + "options": [], + "answer": "6", + "solution": "【分析】用总的数量减去过河的小猪的数量再减去猪妈妈自己,就是剩下的数量。本题需要注意的是猪妈妈也过河了,要把它也减去.\n【详解】 14 - 7 - 1= 7 - 1 = 6 ( 头) ,河对岸还有 6 头猪。", + "knowledge_points": [ + "连减 (20以内)" + ], + "source": "21-22一年级下·广东佛山·期末" + }, + { + "id": "234", + "unit": "20以内的退位减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "两个小组共有13人,一组有6人,求另一组有几人,用总人数减去( )组人数,列式为( )。", + "options": [], + "answer": "一;13-6=7", + "solution": "【分析】要求另一组有多少人,根据减法的意义,用两个小组的总人数减去一组的人数=另一组的人数,据此解答即可.\n【详解】两个小组共有13人,一组有6人,求另一组有几人,用总人数减去一组人数,列式为13-6=7(人)。", + "knowledge_points": [ + "十几减 7,6 的退位减法" + ], + "source": "22-23 一年级下·全国·课前预习" + }, + { + "id": "235", + "unit": "20以内的退位减法", + "question_type": "填空题", + "difficulty": 0.94, + "question": "十几减 5,4,3,2有多种方法,最常用的有( )和( )。", + "options": [], + "answer": "想加算减法;破十法", + "solution": "【分析】要算十几减几,可以用想加法算减法的方法计算。也可以先把十几分成 10 和几,从 10 里拿走几,再将剩下的数再和个位上的数合起来。据此解答即可。此题主要考查了 20 以内退位减法的运算,要求学生熟练掌握.\n【详解】十几减 5,4,3,2 有多种方法,最常用的有 (想加算减法) 和 (破十法)。", + "knowledge_points": [ + "十几减 5~2 的退位减法" + ], + "source": "22-23 一年级下·全国·课前预习" + }, + { + "id": "236", + "unit": "20以内的退位减法", + "question_type": "填空题", + "difficulty": 0.65, + "question": "十几减 8,7,6 的方法很多,其中比较常用的方法有( )和( )。", + "options": [], + "answer": "想加算减法;破十法", + "solution": "【分析】此题可举例说明:计算13-7时,可以想7+6=13,即13-7=6,此方法为想加算减法。计算12-8时,把12分成10和2,先算10-8=2,再算2+2=4,即12-8=4。此方法为破十法.\n【详解】根据分析可知,十几减8,7,6的方法很多,其中比较常用的方法有想加算减法和破十法。", + "knowledge_points": [ + "十几减8的退位减法", + "十几减7,6的退位减法" + ], + "source": "22-23一年级下·全国·课前预习" + }, + { + "id": "237", + "unit": "20以内的退位减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "计算 10 - 9 + 6 时,按从( )到( )的顺序进行。", + "options": [], + "answer": "左;右", + "solution": "【分析】按照综合算式计算法则,如果只有加减法时,要从左往右计算,若有小括号时先算小括号里的,再算括号外面的。本题考查综合算式的计算,要注意计算法则的运用.\n【详解】依据分析可知, 10 - 9 + 6 在计算时,按从左到右的顺序进行。", + "knowledge_points": [ + "无括号的运算顺序", + "加减混合运算 (20 以内)" + ], + "source": "22-23一年级下·全国·课前预习" + }, + { + "id": "238", + "unit": "20以内的退位减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "状状有13块糖果,菲菲比状状多6块糖果,才才比状状少4块糖果,才才有( )块糖果。", + "options": [], + "answer": "9", + "solution": "【分析】根据题意计算谁比谁少多少,用减法计算即可。本题需要注意的是需要从题中找出有用的条件,排除多余的条件.\n【详解】状状有13块糖果,才才比状状少4块,求才才有多少块,列式如下:13-4=9(块),所以才才有9块糖果。", + "knowledge_points": [ + "一位数与两位数的退位减法" + ], + "source": "22-23一年级下·全国·单元测试" + }, + { + "id": "239", + "unit": "20以内的退位减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "动物王国举行长跑比赛,小松鼠是第 8 名,小猴是第 16 名。小松鼠和小猴之间还有( )名小动物。", + "options": [], + "answer": "7", + "solution": "【分析】小松鼠和小猴之间有多少名小动物,考虑最简单的第一名和第二名相差 1 名,但是二者之间却没有小动物。所以问之间有多少小动物,要用名次差减去 1,即可求出小松鼠和小猴之间还有几名小动物.\n【详解】16 - 8 = 8 (名),8 - 1 = 7 (名),小松鼠和小猴之间还有 7 名小动物。本题主要考查减法的计算,理解题意,找出数量关系,列式计算即可。", + "knowledge_points": [ + "十几减8的退位减法", + "8,9的加减法" + ], + "source": "20-21 一年级上·重庆黔江·期末" + }, + { + "id": "240", + "unit": "20以内的退位减法", + "question_type": "填空题", + "difficulty": 0.65, + "question": "被减数是 11,减数是3,差是( )。", + "options": [], + "answer": "8", + "solution": "【分析】根据被减数-减数=差,将数据代入,即可得出答案.\n【详解】11-3=8,所以被减数是11,减数是3,差是8。", + "knowledge_points": [ + "十几减 5~2 的退位减法" + ], + "source": "21-22一年级上·湖北恩施·期末" + }, + { + "id": "241", + "unit": "20以内的退位减法", + "question_type": "填空题", + "difficulty": 0.65, + "question": "18 连续减 3,可以依次得到: ( ),( ),( ),( )。", + "options": [], + "answer": "15;12;9;6", + "solution": "【分析】根据20以内减法运算的方法,列式解答即可.\n【详解】18 - 3 = 15;15 - 3 = 12;12 - 3 = 9;9 - 3 = 6,所以, 18 连续减 3,可以依次得到: 15,12,9,6。本题考查学生对 20 以内整数减法运算的掌握和运用。", + "knowledge_points": [ + "8,9 的加减法", + "十几减 5~2 的退位减法", + "不退位减法 (20 以内)" + ], + "source": "21-22一年级上·湖北恩施·期末" + }, + { + "id": "242", + "unit": "20以内的退位减法", + "question_type": "填空题", + "difficulty": 0.65, + "question": " 5 + ( ) = 18, ( ) - 8 = 4 。", + "options": [], + "answer": "13;12", + "solution": "【分析】根据20以内整数加减法运算方法,即可得出答案。本题考查学生对20以内整数加减法运算的掌握和运用.\n【详解】18 - 5 = 13,所以 5 + 13 = 18.8 + 4 = 12,所 以 12 - 8 = 4 。", + "knowledge_points": [ + "十几减8的退位减法", + "不进位加法(20以内)", + "不退位减法(20以内)" + ], + "source": "20-21 一年级上·海南省直辖县级单位·期末" + }, + { + "id": "243", + "unit": "20以内的退位减法", + "question_type": "填空题", + "difficulty": 0.65, + "question": "小明做了 13 朵小红花,小东做了 9 朵小红花,小东至少还要做( )朵小红花,才能超过小明。", + "options": [], + "answer": "5", + "solution": "【分析】用小明做的朵数减去小东做的朵数,再用它们的差加上 1,即可求出小东至少还要做几朵小红花,才能超过小明。理解题意,找出数量关系,列式计算即可.\n【详解】13 - 9 + 1= 4 + 1 = 5 ( 朵) ,所以小东至少还要做 5 朵小红花,才能超过小明。本题考查 20 以内加减法的计算及应用。", + "knowledge_points": [ + "加减混合运算(20以内)" + ], + "source": "21-22一年级下·湖北孝感·期末" + }, + { + "id": "244", + "unit": "20以内的退位减法", + "question_type": "填空题", + "difficulty": 0.65, + "question": "一个两位数,个位和十位上的数都是 1,这个数是( )。比这个数少 5 的数是( )。", + "options": [], + "answer": "11;6", + "solution": "【分析】从右起第一位是个位,第二位是十位,由此写出这个数;比这个数少 5,用这个数减去 5 即可解答。解答本题的要熟练掌握 20 以内数的写法,再根据求比一个数少的几的数是多少,用减法计算.\n【详解】一个两位数,个位和十位上的数都是 1,这个数是11;11 - 5 = 6,所以比这个数少 5 的数是 6。", + "knowledge_points": [ + "十几减 5~2 的退位减法", + " 11~20 的认识和读写" + ], + "source": "21-22一年级下·黑龙江鸡西·期末" + }, + { + "id": "245", + "unit": "20以内的退位减法", + "question_type": "填空题", + "difficulty": 0.65, + "question": "树上有 15 只鸟,飞走( )只后,还剩下8只。", + "options": [], + "answer": "7", + "solution": "【分析】用树上有鸟的数量减去还剩下的数量,即可求出飞走多少只.\n【详解】15 - 8 = 7(只),则飞走 7 只。本题主要考查了 20 以内减法的实际应用,找出题中所给的数量关系,根据数量关系列式解答即可。", + "knowledge_points": [ + "十几减8的退位减法" + ], + "source": "21-22 一年级下·河南漯河·期末" + }, + { + "id": "246", + "unit": "20以内的退位减法", + "question_type": "填空题", + "difficulty": 0.65, + "question": "有14个小朋友排成一队做操,从左边数起,小丽排在第9位,从右边数起,她排在第( )位。", + "options": [], + "answer": "6", + "solution": "【分析】14个小朋友排队做操,从左数起小丽排在第9位,用14减9得小丽右边人数,再加1得从右数起的位次.\n【详解】14-9+1=5+1=6(位),从右数起,她排在第6位。", + "knowledge_points": [ + "加减混合运算 (20 以内)" + ], + "source": "21-22 一年级下·四川广元·期末" + }, + { + "id": "247", + "unit": "20以内的退位减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "小华投进了 10 个球,小兰投进 8 个球。小华不投了,小兰至少还要投进( )个球,才能超过小华。", + "options": [], + "answer": "3", + "solution": "【分析】超过小华至少一共要投 11 个球,用 11 减去小兰已经投进的个数即可.\n【详解】11 - 8 = 3(个),所以小兰至少还要投进 3 个球,才能超过小华。解答此题的关键是要知道小兰要比小华多投 1 个才可以。", + "knowledge_points": [ + "十几减8的退位减法" + ], + "source": "21-22 一年级下·湖南岳阳·期末" + }, + { + "id": "248", + "unit": "20以内的退位减法", + "question_type": "填空题", + "difficulty": 0.65, + "question": "有 13 个苹果,每 4 个装一盘,可装满( )盘。再增加( )个,就可再装满 1 盘。", + "options": [], + "answer": "3;3", + "solution": "【分析】根据题意,用 13 连续减去 4,减去几个 4 就可以装满几袋,剩下的个数再加上几凑够 4 个,就是增加几个,由此解答。本题主要考查减法的实际应用,注意计算的准确性.\n【详解】13 - 4 - 4 - 4 = 1(个),1 + 3 = 4 (个),所以有 13 个苹果,每 4 个装一盘,可装满 3 盘。再增加 3 个,就可再装满 1 盘。", + "knowledge_points": [ + "连减 (20以内)" + ], + "source": "21-22 一年级下·吉林·期末" + }, + { + "id": "249", + "unit": "20以内的退位减法", + "question_type": "填空题", + "difficulty": 0.65, + "question": "17 个珠子,如果 5 个穿一串,能穿( )串,还剩( )个。", + "options": [], + "answer": "3;2", + "solution": "【分析】用总数量 17 连续减穿一串珠子的个数 5 即可求解。本题主要考查了20以内的数的连减应用.\n【详解】17 - 5 = 12(个),12 - 5 = 7(个),7 - 5 = 2(个),能穿 3 串,还剩 2 个。", + "knowledge_points": [ + "连减 (20 以内)" + ], + "source": "20-21 一年级下·山东济宁·期末" + }, + { + "id": "250", + "unit": "20以内的退位减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "计算 13 - (6 + 2) 时,先算( )法,再算( )法,最后得到的结果是( )。", + "options": [], + "answer": "加;减;5", + "solution": "【分析】有小括号混合运算里,先算小括号里的,再算小括号外的,由此计算解答。 本题主要考查带有小括号的混合运算计算,牢记运算顺序,计算时认真计算.\n【详解】计算 13 - (6 + 2)时,先算加法,再算减法。13 - (6 + 2)= 13 - 8 = 5 ", + "knowledge_points": [ + "带有小括号的混合运算" + ], + "source": "21-22 一年级下·河北张家口·期末" + }, + { + "id": "251", + "unit": "20以内的退位减法", + "question_type": "判断题", + "difficulty": 0.85, + "question": "减数是 7,被减数是12,差是多少。列式为 12 - 7 = 6 。()", + "options": [], + "answer": "×", + "solution": "【分析】根据被减数 - 减数 = 差,据此进行解答即可。本题考查学生对 20 以内退位减法的掌握和运用.\n【详解】 12 - 7 = 5,所以减数是 7,被减数是 12,差是 5 。原题说法错误。故答案为: ×。", + "knowledge_points": [ + "十几减 7,6 的退位减法" + ], + "source": "22-23 一年级·全国·假期作业" + }, + { + "id": "252", + "unit": "20以内的退位减法", + "question_type": "判断题", + "difficulty": 0.85, + "question": "计算 17 - 9 时,可以想 8 + 9 = 17 。( )", + "options": [], + "answer": "√", + "solution": "【分析】根据20以内的退位减法,可以利用想加法算减法的口算方法解答.\n【详解】因为8+9=17,所以计算17-9时,可以想8+9=17;所以原题说法正确。故答案为:√", + "knowledge_points": [ + "9加几的进位加法", + "十几减9的退位减法" + ], + "source": "22-23一年级·全国·假期作业" + }, + { + "id": "253", + "unit": "20以内的退位减法", + "question_type": "判断题", + "difficulty": 0.65, + "question": "被减数是 12,差是 5,减数就是 7 。( )", + "options": [], + "answer": "√", + "solution": "【分析】用被减数减去差,算出减数是多少,再判断题干是否正确。本题的解答关键是要熟悉:被减数 - 减数 = 差.\n【详解】 12 - 5 = 7,当被减数是12,差是5时,减数是7。原题说法正确。故答案为: √。", + "knowledge_points": [ + "十几减 5~2 的退位减法" + ], + "source": "20-21 一年级上·江西吉安·期末" + }, + { + "id": "254", + "unit": "20以内的退位减法", + "question_type": "判断题", + "difficulty": 0.65, + "question": "17 个小朋友排队做操,从左数起,小芳排在第 9 位,从右数起,她排在第 8 位。 ( )", + "options": [], + "answer": "×", + "solution": "【分析】用 17 减 9 算出小芳右边的人数,然后加 1 就是从右数起,小芳排的位数。熟练掌握 20 以内的退位减法计算是解题关键.\n【详解】17 - 9 = 8(个),8 + 1 = 9(位),从右数起,她排在第9位。故答案为: ×。", + "knowledge_points": [ + "8,9 的加减法", + "十几减 9 的退位减法" + ], + "source": "20-21 一年级下·湖北十堰·期末" + }, + { + "id": "255", + "unit": "20以内的退位减法", + "question_type": "判断题", + "difficulty": 0.85, + "question": "17减8的差是9。( )", + "options": [], + "answer": "√", + "solution": "【分析】根据题意,求出 17 - 8 的结果即可。本题主要考查 20 以内数的减法,正确计算出结果即可.\n【详解】17 - 8 = 9,故答案为: √。", + "knowledge_points": [ + "十几减8的退位减法" + ], + "source": "21-22 一年级下·河北张家口·期末" + }, + { + "id": "256", + "unit": "20以内的退位减法", + "question_type": "判断题", + "difficulty": 0.85, + "question": "小狗比小猫多 8 只,则小猫比小狗少 8 只。( )", + "options": [], + "answer": "√", + "solution": "【分析】由题可知,小狗比小猫多 8 只,说明小狗的数量多,小猫的数量少,也就是小猫比小狗少 8 只。由此判断即可。本题主要考查减法问题中求多多少和少多少问题,注意问题间的转化.\n【详解】由分析可知,小狗比小猫多 8 只,则小猫比小狗少 8 只。原说法正确。故答案为: √", + "knowledge_points": [ + "十几减8的退位减法" + ], + "source": "21-22 一年级下·山东临沂·期末" + }, + { + "id": "257", + "unit": "20以内的退位减法", + "question_type": "判断题", + "difficulty": 0.65, + "question": "12 枝花插在 2 个花瓶里,一个花瓶插 6 枝,另一个花瓶插 6 枝。( )", + "options": [], + "answer": "√", + "solution": "【分析】根据减法的意义,用 12 减去一个花瓶里面插的枝数,即得出另一个花瓶插多少枝,据此列式解答即可。本题考查学生对 20 以内减法运算的掌握和运用.\n【详解】 12 - 6 = 6(枝),所以,一个花瓶插6枝,另一个花瓶插6枝。原题说法正确。故答案为: √ 。", + "knowledge_points": [ + "十几减7,6的退位减法" + ], + "source": "21-22 二年级下·河南南阳·期中" + }, + { + "id": "258", + "unit": "20以内的退位减法", + "question_type": "计算题", + "difficulty": 0.65, + "question": "看图列式计算.\n\n![](images/21ffb801e9d724e778dc4d5f5a0d771d9bdeb310f8f7c0ab51c7e4fb8443fc2e.jpg)\n\n□ - □ = □ (个)", + "options": [], + "answer": "17-9=8", + "solution": "【分析】羽毛球的总数是 17 个,总数 - 右边的数量 = 左边未知的数量,据此列式计算.\n【详解】 17 - 9 = 8 (个),左边有 8 个羽毛球。", + "knowledge_points": [ + "十几减8的退位减法", + "图文问题" + ], + "source": "21-22 一年级下·全国·随堂练习" + }, + { + "id": "259", + "unit": "20以内的退位减法", + "question_type": "计算题", + "difficulty": 0.65, + "question": "看图列式计算.\n\n![](images/d7cfa177c338dd942cc2be013203d5875b03622669bef70572e0e2b3751d2b06.jpg)\n\n□ - □ = □ (块)", + "options": [], + "answer": "16-8=8", + "solution": "【分析】根据减法的意义可知:月饼总数 16 块 - 右边的块数 = 左边的月饼数量.\n【详解】 16 - 8 = 8 (块),所以,盒子里有 8 块月饼。", + "knowledge_points": [ + "十几减8的退位减法" + ], + "source": "21-22 一年级下·全国·随堂练习" + }, + { + "id": "260", + "unit": "20以内的退位减法", + "question_type": "计算题", + "difficulty": 0.65, + "question": "看图列式计算.\n\n![](images/08e152e120eb4f4a0551bffd6490fe87a81dcf6453541bf9536c9d539f813013.jpg)\n\n□ - □ = □ (个)", + "options": [], + "answer": "14-9=5", + "solution": "【分析】根据减法的意义,三角形的总数 14 个 - 右边的三角形的数量 = 左边三角形的数量。据此解答.\n【详解】 14 - 9 = 5 (个),左边有 5 个三角形。", + "knowledge_points": [ + "十几减9的退位减法" + ], + "source": "21-22 一年级下·全国·随堂练习" + }, + { + "id": "261", + "unit": "20以内的退位减法", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式计算.\n\n![](images/8e859f29e3130633c0173f93c83787c3da2505716e452cd295bf8b012a2bb7f1.jpg)\n\n□ ○ □ = □ (个)", + "options": [], + "answer": "13-4=9", + "solution": "【分析】根据图示,右边有 4 个菠萝,总共有 13 个菠萝,要求左边有多少个,列减法算式即可.\n【详解】13 - 4 = 9 (个),左边有 9 个菠萝。", + "knowledge_points": [ + "图文问题", + "十几减 5~2 的退位减法" + ], + "source": "22-23 一年级下·全国·课前预习" + }, + { + "id": "262", + "unit": "20以内的退位减法", + "question_type": "计算题", + "difficulty": 0.65, + "question": "看图列式.\n\n![](images/baf906cf417b2a46093d25daca9689aa2e5cb270b496c4c79e174e267cf65b93.jpg)\n\n□ ○ □ = □ (个)", + "options": [], + "answer": "15-6=9", + "solution": "【分析】由图可知,用总数 15 个减去右边的 6 个,即可求出盘子中菠萝的个数.\n【详解】 15 - 6 = 9 (个)", + "knowledge_points": [ + "十几减 7,6 的退位减法" + ], + "source": "22-23 一年级下·全国·单元测试" + }, + { + "id": "263", + "unit": "20以内的退位减法", + "question_type": "计算题", + "difficulty": 0.65, + "question": "看图列式计算.\n\n![](images/6bda626294bbb42f88d61bb2e326d72743d92c67b09efc6295376d419ef79bb5.jpg)\n\n□ ○ □ = □ (只)", + "options": [], + "answer": "16-7=9", + "solution": "【分析】已知总数量和其中一部分的数量,求另一部分的数量用减法。用总数量16只减去左边的7只即可求解.\n【详解】16-7=9(只)", + "knowledge_points": [ + "十几减 7,6 的退位减法" + ], + "source": "22-23 一年级下·全国·单元测试" + }, + { + "id": "264", + "unit": "20以内的退位减法", + "question_type": "计算题", + "difficulty": 0.65, + "question": "我会列式计算.\n\n![](images/8b0af49f10f5d385a92ce17dd745b136cd7d6b199e30de2db73f14ccdba5dd44.jpg)\n\n□ ○ □ ○ □= □ (个)", + "options": [], + "answer": "15-4-3=8", + "solution": "【分析】从图上可知:一共有 15 颗糖,已知左边有 4 颗,中间有 3 颗,要求右边有多少颗糖,根据减法的意义,列式解答即可.\n【详解】 15 - 4 - 3 = 8 (颗)", + "knowledge_points": [ + "连减 (20以内)" + ], + "source": "20-21 一年级上·四川乐山·期末" + }, + { + "id": "265", + "unit": "20以内的退位减法", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式计算.\n\n![](images/23d0eabac0e3f04509495bf65aa19714f573cf23d2d7d2fd18076ec559b50381.jpg)\n\n□ - □ = □ (只)", + "options": [], + "answer": "16-7=9", + "solution": "【分析】小兔总只数减去房子外的只数=房子里的只数。据此列式解答.\n【详解】根据分析:16-7=9(只)", + "knowledge_points": [ + "图文问题", + "十几减 7,6 的退位减法" + ], + "source": "21-22一年级下·福建漳州·期末" + }, + { + "id": "266", + "unit": "20以内的退位减法", + "question_type": "计算题", + "difficulty": 0.65, + "question": "看图列式并计算.\n\n![](images/f300950feec4c6329e307ef4b4476cb048df46dfe9bbfd724e3c2277e35bcc8f.jpg)\n\n□ ○ □ = □(颗)", + "options": [], + "answer": "18-9=9", + "solution": "【分析】根据减法的意义,用总数18颗,减去左边盘子的数量,即可求出右边盘子的数量.\n【详解】根据分析:18-9=9(颗)", + "knowledge_points": [ + "图文问题", + "十几减9的退位减法" + ], + "source": "21-22 一年级下·陕西渭南·期末" + }, + { + "id": "267", + "unit": "20以内的退位减法", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式计算.\n\n![](images/a1073a625e41ac0d008db7ff91fa96a4613c1faff77c7ce24f811585c89d782c.jpg)\n\n□ ○ □ = □ ( )", + "options": [], + "answer": "13-6=7", + "solution": "【分析】一共有 13 个,左边有 6 个,用 13 减去 6 即可得到右边的个数.\n【详解】 13 - 6 = 7 (个)", + "knowledge_points": [ + "图文问题", + "十几减 7,6 的退位减法" + ], + "source": "21-22 一年级下·广东江门·期末" + }, + { + "id": "268", + "unit": "20以内的退位减法", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式.\n\n![](images/a4b6dd8f2192d583555c82e45c837160f26ca7d35f4d3b6a2e445230b9630812.jpg)\n\n□ ○ □ = □( )", + "options": [], + "answer": "11-6=5", + "solution": "【分析】由图可知,用总数 11 只减去左边的 6 只,即可求出右边的只数.\n【详解】 11 - 6 = 5 (只)", + "knowledge_points": [ + "图文问题", + "十几减 7,6 的退位减法" + ], + "source": "20-21 一年级下·海南省直辖县级单位·期中" + }, + { + "id": "269", + "unit": "20以内的退位减法", + "question_type": "计算题", + "difficulty": 0.65, + "question": "看图列式小高手.\n\n![](images/c3533c5cd71d2394d2f62c2ba00bd38099e9baee05e3797b02e9eeaf1dae39a3.jpg)\n□ ○ □ = □ (只)", + "options": [], + "answer": "13-7=6", + "solution": "【分析】减法计算,用一共的 13 个减左面的 7 个,即可解答.\n【详解】 13 - 7 = 6 (个)", + "knowledge_points": [ + "图文问题", + "十几减 7,6 的退位减法" + ], + "source": "20-21 一年级下·江西赣州·期末" + }, + { + "id": "270", + "unit": "20以内的退位减法", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式.\n\n![](images/cdf697cb8f0c5c5f2e68465a15947595a68b1960417264fbd22085987b38c272.jpg)\n\n□ ○ □ = □ (个)", + "options": [], + "answer": "15-6=9", + "solution": "【分析】由图可知,用总数 15 个减去右边的 6 个,即可求出盘子的中的个数.\n【详解】 15 - 6 = 9(个)", + "knowledge_points": [ + "图文问题", + "十几减 7,6 的退位减法" + ], + "source": "21-22 一年级下·福建龙岩·期中" + }, + { + "id": "271", + "unit": "20以内的退位减法", + "question_type": "计算题", + "difficulty": 0.65, + "question": "看图列式细心算.\n\n![](images/bafe921b53dc2c932daad4bc78f498e7e7dc67ed30f22c2a060ff17fbceab035.jpg)\n\n□ ○ □ = □ (块)", + "options": [], + "answer": "12-3=9", + "solution": "【分析】看图可知:求左边盒子里有多少块,用一共的 12 块减右边的 3 块解答即可.\n【详解】 12 - 3 = 9", + "knowledge_points": [ + "图文问题", + "十几减 5~2 的退位减法" + ], + "source": "20-21 一年级下·河南三门峡·期末" + }, + { + "id": "272", + "unit": "20以内的退位减法", + "question_type": "计算题", + "difficulty": 0.65, + "question": "列算式.\n\n![](images/29a38b4554c880cf3dba7f8af214fab56452825ae47405aff85b8e9c07bc844b.jpg)\n\n□ ○ □ = □ (个)", + "options": [], + "answer": "13-5=8", + "solution": "【分析】用总的桃子数减去左边的 5 个桃子即可得到右边有几个桃子.\n【详解】13 - 5 = 8(个)", + "knowledge_points": [ + "图文问题", + "十几减 5~2 的退位减法" + ], + "source": "21-22 一年级下·广东韶关·期末" + }, + { + "id": "273", + "unit": "20以内的退位减法", + "question_type": "计算题", + "difficulty": 0.65, + "question": "看图列式计算.\n\n![](images/6512662a1af0301d7eb7fe68f93fb0181a952aba0477ea5a8d7ed48f8b5a612c.jpg)\n\n□ ○ □ = □ ( )", + "options": [], + "answer": "15-6=9", + "solution": "【分析】已知总的粉笔数是 15 支,其中一边有 6 支,求另一边粉笔盒里有几支粉笔,用 15 减 6 即可得解。本题考查了'十几减6的退位减法'的相关计算.\n【详解】 15 - 6 = 9 (支)。", + "knowledge_points": [ + "图文问题", + "十几减 7,6 的退位减法" + ], + "source": "20-21 一年级下·海南省直辖县级单位·期中" + }, + { + "id": "274", + "unit": "20以内的退位减法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "奶奶家养了 8 只母鸡,一共下了 17 个鸡蛋,孵出 15 只小鸡。小鸡比母鸡多几只。\n\n□ ○ □ = □ (只)", + "options": [], + "answer": "7只", + "solution": "【分析】根据题意,小鸡有15只,母鸡有8只,求小鸡比母鸡多几只,根据减法的意义,用小鸡的数量减去母鸡的数量,计算即可.\n【详解】15-8=7(只)。答:小鸡比母鸡多7只。", + "knowledge_points": [ + "十几减8的退位减法" + ], + "source": "23-24 一年级上·河南周口·期末" + }, + { + "id": "275", + "unit": "20以内的退位减法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "实验小学师生参加植树活动,男生植树 15 棵,女生植树 7 棵,老师植树 9 棵.\n\n(1) 老师和女生一共植树多少棵。 \n\n(2) 女生比男生少植树多少棵。", + "options": [], + "answer": "16棵;8棵", + "solution": "【分析】(1)求老师和女生一共植树多少棵,就是求两个数的和,用加法列式计算。(2)求女生比男生少植树多少棵,就是求两个数的差,用减法列式计算.\n【详解】(1)9+7=16(棵),答:老师和女生一共植树16棵。(2)15-7=8(棵),答:女生比男生少植树8棵。", + "knowledge_points": [ + "9加几的进位加法", + "十几减7,6的退位减法" + ], + "source": "22-23一年级下·山东菏泽·期中" + }, + { + "id": "276", + "unit": "20以内的退位减法", + "question_type": "解答题", + "difficulty": 0.65, + "question": "兔妈妈和兔宝宝有数量不等的胡萝卜。兔妈妈的胡萝卜比兔宝宝多 15 根,兔妈妈拿出 7 根给兔宝宝,现在兔妈妈比兔宝宝多几根胡萝卜。", + "options": [], + "answer": "1根", + "solution": "【分析】原来兔妈妈比兔宝宝多 15 根,兔妈妈拿出 7 根给兔宝宝,说明兔妈妈减少了 7 根,兔宝宝多了 7 根,现在兔妈妈比兔宝宝多的胡萝卜数量 = 原来多的 15 根 - 兔妈妈减少的 7 根 - 兔宝宝多的 7 根。据此解答.\n【详解】 15 - 7 - 7 = 1 (根),答:现在兔妈妈比兔宝宝多 1 根胡萝卜。解答此题时要注意当兔妈妈把胡萝卜给兔宝宝时,兔妈妈的胡萝卜在减少,而兔宝宝的胡萝卜在增加。", + "knowledge_points": [ + "连减 (20以内)" + ], + "source": "22-23 一年级下·全国·随堂练习" + }, + { + "id": "277", + "unit": "20以内的退位减法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "3 月 12 日是植树节,一年级(1)班和一年级(2)班共植树13棵,其中一年级(1) 班植了 7 棵。一年级 (2) 班植了多少棵树。", + "options": [], + "answer": "6棵", + "solution": "【分析】要求一年级(2)班植了多少棵树,将两个班级植树的总棵数减去一年级(1)班植的棵数,即可得出答案。本题考查学生对20以内整数退位减法的运用.\n【详解】13 - 7 = 6 (棵),答:一年级 (2) 班植了 6 棵树。", + "knowledge_points": [ + "十几减7,6的退位减法" + ], + "source": "22-23 一年级·全国·假期作业" + }, + { + "id": "278", + "unit": "20以内的退位减法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "小方家有 13 只鸡和 9 只羊,公鸡有 4 只,母鸡有几只。", + "options": [], + "answer": "9只", + "solution": "【分析】从题干可知:小方家有 13 只鸡,公鸡有 4 只,要求母鸡有几只,根据减法的意义,列式解答即可。本题考查学生对 20 以内整数退位减法的掌握和运用,要注意羊的条件是多余的.\n【详解】 13 - 4 = 9 (只),答:母鸡有 9 只。", + "knowledge_points": [ + "十几减 5~2 的退位减法" + ], + "source": "22-23 一年级·全国·假期作业" + }, + { + "id": "279", + "unit": "20以内的退位减法", + "question_type": "解答题", + "difficulty": 0.94, + "question": "停车场原来有16辆汽车,还剩7辆,开走了几辆。", + "options": [], + "answer": "9辆", + "solution": "【分析】要求开走了几辆,用停车场原来有的汽车数量减去剩下的汽车数量,即可得出答案。本题考查学生对 20 以内退位减法运算的运用.\n【详解】 16 - 7 = 9 (辆),答:开走了 9 辆。", + "knowledge_points": [ + "十几减 7,6 的退位减法" + ], + "source": "22-23一年级·全国·假期作业" + }, + { + "id": "280", + "unit": "20以内的退位减法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "王爷爷家有12只鸡和8只鸭。公鸡有6只,母鸡有多少只。", + "options": [], + "answer": "6只", + "solution": "【分析】根据题意,用鸡的总数减去公鸡的数量就是母鸡的数量。本题要注意的是鸭子的数量是个多余条件.\n【详解】 12 - 6 = 6 (只),答:母鸡有 6 只。", + "knowledge_points": [ + "十几减 7,6 的退位减法" + ], + "source": "21-22一年级下·广东佛山·期末" + }, + { + "id": "281", + "unit": "20以内的退位减法", + "question_type": "解答题", + "difficulty": 0.65, + "question": "小灰有 17 个松果,小黑有 5 个,小白有 8 个.\n\n(1) 小灰比小白多几个。 \n\n(2) 小黑比小灰少几个。", + "options": [], + "answer": "9个;12个", + "solution": "【分析】根据题意:(1)小灰有 17 个松果,小白有 8 个,求小灰比小白多几个,用小灰松果的数量减去小白的松果数量就是小灰比小白多的数量。(2)小灰有 17 个松果,小黑有 5 个,可以求出小灰比小黑多的数量,也就是小黑比小灰少的数量。主要考查了简单的减法应用题在实际生活中的应用.\n【详解】(1)17 - 8 = 9(个)答:小灰比小白多9个。(2)17 - 5 = 12(个)答:小黑比小灰少 12 个。", + "knowledge_points": [ + "实际问题(十几减 9~6 的退位减法)", + "十几减5~2 的退位减法", + "十几减 9 的退位减法" + ], + "source": "22-23一年级下·全国·课前预习" + }, + { + "id": "282", + "unit": "20以内的退位减法", + "question_type": "解答题", + "difficulty": 0.65, + "question": "小林家养了 15 只兔和 9 只羊。兔比羊多几只。 羊比兔少几只。", + "options": [], + "answer": "6只;6只", + "solution": "【分析】小林家养了 15 只兔和 9 只羊,兔比羊多几只就用兔子的数量减去羊的数量, 15 - 9 = 6 (只) 所以兔子比羊多了 6 只,反之羊比兔子少 6 只。主要考查了简单的减法应用题在实际生活中的应用,用 20 以内数的退位减法计算,需要细心作答.\n【详解】15 - 9 = 6 (只)答:兔子比羊多 6 只;羊比兔子少 6 只。", + "knowledge_points": [ + "实际问题(十几减 9~6 的退位减法)", + "十几减 9 的退位减法" + ], + "source": "22-23 一年级下·全国·课前预习" + }, + { + "id": "283", + "unit": "20以内的退位减法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "我们班一共有 20 人,有 14 人在玩捉迷藏,玩捉迷藏的男生有 6 人,玩捉迷藏的女生有多少人。", + "options": [], + "answer": "8人", + "solution": "【分析】根据题意可知,共有14人玩捉迷藏,其中男生有6人,求女生有几人,列减法算式即可。本题考查20以内减法的计算,要明确题中的20是多余条件.\n【详解】14-6=8(人),答:玩捉迷藏的女生有8人。", + "knowledge_points": [ + "十几减 7,6 的退位减法" + ], + "source": "22-23 一年级下·全国·课前预习" + }, + { + "id": "284", + "unit": "20以内的退位减法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "原来有 15 个气球,破了 8 个,还剩几个。", + "options": [], + "answer": "7个", + "solution": "【分析】用总的气球数量 - 破了的气球数量 = 剩下的气球数量,据此列式解答即可。本题考查学生对 20 以内整数退位减法的运用.\n【详解】 15 - 8 = 7 (个),答:还剩 7 个。", + "knowledge_points": [ + "十几减8的退位减法" + ], + "source": "22-23一年级下·全国·课前预习" + }, + { + "id": "285", + "unit": "20以内的退位减法", + "question_type": "解答题", + "difficulty": 0.65, + "question": "小丽做了7道题,对了6道题。小刚和小丽一共做了16道题,小刚做了多少道题。", + "options": [], + "answer": "9道", + "solution": "【分析】由题意知,小丽做了 7 道题,虽对了 6 道题,但是只算做题的总数。小刚和小丽一共做了 16 道题,已知小丽做题数量,可求小刚的做题数量,运用减法算式。主要考查 20 以内退位减法且会解决实际问题,关键是认真读题找到相关联的信息进行解决问题.\n【详解】16 - 7 = 9(道),答:小刚做了 9 道题。", + "knowledge_points": [ + "实际问题(十几减 9~6 的退位减法)" + ], + "source": "22-23一年级下·全国·单元测试" + }, + { + "id": "286", + "unit": "20以内的退位减法", + "question_type": "解答题", + "difficulty": 0.65, + "question": "一辆公交车上原有18人,到站后下去了9人,又上来了3人,现在这辆公交车上有多少人。\n\n□ ○ □ ○ □=□(人)", + "options": [], + "answer": "12人", + "solution": "【分析】从题干可知:到站后下去9人,表示车上人数减少9人,又上来3人,表示车上人数增加3人,据此根据整数的加减法,列式解答即可.\n【详解】18-9+3=12,答:现在这辆公交车上有12人。", + "knowledge_points": [ + "加减混合运算 (20 以内)" + ], + "source": "20-21一年级上·湖北鄂州·期末" + }, + { + "id": "287", + "unit": "20以内的退位减法", + "question_type": "解答题", + "difficulty": 0.65, + "question": "一辆公共汽车,到一小公交车站后上来8人,下去了7人,现在有16人,原来车上有多少人。", + "options": [], + "answer": "15人", + "solution": "【分析】根据题意,求原来车上的人数,则先用现在的人数减去到一小车站后上来的人数,再加上下去的人数,即可求出原来车上的人数。本题主要考查 20 以内加减法的应用,解答的关键是理解本题求的是原来的人数.\n【详解】 16 - 8 + 7= 8 + 7 = 15 (人) ,答:原来车上有 15 人。", + "knowledge_points": [ + "加减混合运算(20以内)" + ], + "source": "20-21一年级下·贵州六盘水·期末" + }, + { + "id": "288", + "unit": "20以内的退位减法", + "question_type": "解答题", + "difficulty": 0.65, + "question": "![](images/cbcbe1b26fe4f6650fef710f39dd5d77ac064c0ae31430a69d706b8564152f74.jpg)\n\n还剩下多少本。\n\n□ ○ □ = □ (本)", + "options": [], + "answer": "8本", + "solution": "【分析】根据减法的意义,根据原来的数量 - 拿走的数量 = 剩下的数量,代入数据计算即可。本题主要考查减法的应用,已知总数和拿走的部分数,求还剩下多少用减法解答.\n【详解】 13 - 5 = 8 (本),答:还剩下 8 本。", + "knowledge_points": [ + "十几减 5~2 的退位减法" + ], + "source": "21-22 一年级下·陕西渭南·期末" + }, + { + "id": "289", + "unit": "20以内的退位减法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "姐姐过生日了。蛋糕上有 15 支蜡烛,吹灭了 7 支,还有多少支亮着。", + "options": [], + "answer": "8支", + "solution": "【分析】利用蜡烛的总支数减去吹灭了的支数即可求解。求还剩多少用减法计算.\n【详解】 15 - 7 = 8 (支),答:还有 8 支亮着。", + "knowledge_points": [ + "十几减 7,6 的退位减法" + ], + "source": "21-22 一年级下·广东阳江·期末" + }, + { + "id": "290", + "unit": "20以内的退位减法", + "question_type": "解答题", + "difficulty": 0.65, + "question": "金鱼缸里有 15 条红金鱼,6条花金鱼,再买几条花金鱼就和红金鱼同样多。", + "options": [], + "answer": "9条", + "solution": "【分析】求再买几个物品就和某物品同样多,用减法即可。本题主要考查了两位数减一位数的实际应用,明确要用减法是解答本题的关键.\n【详解】 15 - 6 = 9 (条),答:再买 9 条花金鱼就和红金鱼同样多。", + "knowledge_points": [ + "实际问题(十几减 9~6 的退位减法)" + ], + "source": "19-20 一年级下·全国·期中" + }, + { + "id": "291", + "unit": "20以内的退位减法", + "question_type": "解答题", + "difficulty": 0.65, + "question": "猫妈妈给小白15条鱼,给小花10条鱼,小白吃了6条,小白还有几条鱼。", + "options": [], + "answer": "9条", + "solution": "【分析】用猫妈妈给小白的鱼减去小白吃了的鱼即可求解。不要被题目中多余的条件误导.\n【详解】 15 - 6 = 9 (条),答:小白还有 9 条鱼。", + "knowledge_points": [ + "十几减7,6的退位减法" + ], + "source": "20-21一年级下·湖北鄂州·期末" + }, + { + "id": "292", + "unit": "20以内的退位减法", + "question_type": "解答题", + "difficulty": 0.65, + "question": "我们班一共有16人参加植树,要植8棵树,其中女生有7人,男生有几人。", + "options": [], + "answer": "9人", + "solution": "【分析】要求男生有几人,用总人数16人减去女生的人数,即可求出男生的人数。本题主要考查减法的实际应用,注意找准解答问题的信息,本题中要植 8 棵树是干扰信息.\n【详解】 16 - 7 = 9 (人),答:男生有 9 人。", + "knowledge_points": [ + "十几减 7,6 的退位减法" + ], + "source": "21-22一年级下·福建泉州·期中" + }, + { + "id": "293", + "unit": "20以内的退位减法", + "question_type": "解答题", + "difficulty": 0.65, + "question": "乐乐买了 7 支铅笔,丽丽买了 15 支铅笔,丽丽买的铅笔比乐乐多几支。", + "options": [], + "answer": "8支", + "solution": "【分析】根据题意,用丽丽的支数减去乐乐的支数,即可解答。求一个数比另一个数多多少,用减法计算.\n【详解】 15 - 7 = 8 (支),答:丽丽买的铅笔比乐乐多 8 支。", + "knowledge_points": [ + "十几减 7,6 的退位减法" + ], + "source": "21-22 一年级下·福建泉州·期中" + }, + { + "id": "294", + "unit": "20以内的退位减法", + "question_type": "解答题", + "difficulty": 0.65, + "question": "一共有 16 人参加登山活动,有7人已经登上了山顶,其中女生有3人,还有几人没有登上山顶。\n\n![](images/aa125013fad2ad2a04f68be65744a6c02b61c3141124434a9dfa2ce24cdd5d7a.jpg)", + "options": [], + "answer": "9人", + "solution": "【分析】一共有 16 人登山,已经有 7 人登顶,求还有几人没有登顶,用减法解答。本题重点是题干中给出无用条件 '其中女生 3 人',一定要认真审题.\n【详解】 16 - 7 = 9 (人),答:还有 9 人没有登上山顶。", + "knowledge_points": [ + "图文问题", + "十几减 7,6 的退位减法" + ], + "source": "21-22 一年级下·河南信阳·期中" + }, + { + "id": "295", + "unit": "20以内的退位减法", + "question_type": "解答题", + "difficulty": 0.65, + "question": "小明每天要写 17 个毛笔字,背2首古诗,今天他已经写了8个毛笔字,还要写多少个毛笔字才能完成任务。", + "options": [], + "answer": "9个", + "solution": "【分析】用每天要写的字数减去已经写了的字数可以求出还要写的字数,据此解答。掌握十几减 8 的退位减法的计算方法是解答此题的关键.\n【详解】 17 - 8 = 9 (个),答:还要写 9 个毛笔字才能完成任务。", + "knowledge_points": [ + "十几减8的退位减法" + ], + "source": "20-21 一年级下·河南安阳·期中" + }, + { + "id": "296", + "unit": "20以内的退位减法", + "question_type": "解答题", + "difficulty": 0.65, + "question": "5路公车上有13人,到汽车站下去5人,又上来9人。现在车上有多少人。", + "options": [], + "answer": "17人", + "solution": "【分析】用原来的人数减去5再加9即可。掌握20以内数的加减混合运算是解题的关键.\n【详解】 13 - 5 + 9= 8 + 9 = 17 (人) ,答:现在车上有 17 人。", + "knowledge_points": [ + "加减混合运算 (20 以内)" + ], + "source": "20-21一年级下·河南安阳·期中" + }, + { + "id": "297", + "unit": "20以内的退位减法", + "question_type": "解答题", + "difficulty": 0.65, + "question": "悟空一共摘了 14 个桃子和 8 个西瓜,八戒吃了 8 个桃子,还剩多少个桃子。\n□ ○ □ = □ ( )", + "options": [], + "answer": "6个", + "solution": "【分析】从题干可知:悟空一共摘了 14 个桃子,八戒吃了 8 个桃子,所以桃子的数量减少 8 个。据此根据减法的意义,列式解答即可。本题考查学生对 20 以内整数减法运算的运用.\n【详解】 14 - 8 = 6 (个),答:还剩 6 个桃子。", + "knowledge_points": [ + "十几减8的退位减法" + ], + "source": "20-21一年级下·河南漯河·期中" + }, + { + "id": "298", + "unit": "20以内的退位减法", + "question_type": "解答题", + "difficulty": 0.65, + "question": "小明做一道减法题,错把减 9 看成减 7,结果得 8,正确的结果应该是多少。", + "options": [], + "answer": "6", + "solution": "【分析】依据题意,小明把减数看错了,但是被减数没有看错,所以先利用错误的减数和差计算被减数,再进行正确的计算,错把减数 9 看成 7,结果是 8,所以相加得到 7 + 8 = 15,之后减去 9 得到正确的结果。本题考查了整数加减法的计算,解题的关键是求出被减数.\n【详解】 7 + 8 = 15,15 - 9 = 6,答:正确的结果应该是 6。", + "knowledge_points": [ + "7,6加几的进位加法", + "十几减9的退位减法", + "错中求解问题(加减法)" + ], + "source": "21-22 一年级下·安徽宿州·期末" + }, + { + "id": "299", + "unit": "20以内的退位减法", + "question_type": "解答题", + "difficulty": 0.65, + "question": "同学们浇树,小兰浇了7棵,小丽浇了8棵,小明浇了11棵,小丽比小明少浇几棵。\n□ ○ □ = □ ( )", + "options": [], + "answer": "3棵", + "solution": "【分析】要求小丽比小明少浇几棵,根据整数减法的意义,用小明浇的棵数减去小丽浇的棵数,据此即可得出答案.\n【详解】11-8=3(棵),答:小丽比小明少浇3棵。", + "knowledge_points": [ + "十几减8的退位减法" + ], + "source": "20-21一年级下·海南省直辖县级单位·期中" + }, + { + "id": "300", + "unit": "20以内的退位减法", + "question_type": "解答题", + "difficulty": 0.65, + "question": "白兔有 14 只,比灰兔多 6 只,灰兔有多少只。\n□ ○ □ = □ ( )", + "options": [], + "answer": "8只", + "solution": "【分析】白兔有 14 只,比灰兔多 6 只,求灰兔多少只,用减法计算.\n【详解】 14 - 6 = 8 (只),答:灰兔有 8 只。", + "knowledge_points": [ + "十几减8的退位减法" + ], + "source": "20-21一年级下·海南省直辖县级单位·期中" + }, + { + "id": "301", + "unit": "20以内的退位减法", + "question_type": "选择题", + "difficulty": 0.65, + "question": "与 10 - (2 + 3) 的得数相等的算式是 ( )。", + "options": [ + "A. 10 - 2 + 3", + "B. 10 - 2 - 3", + "C. 10 + 2 - 3" + ], + "answer": "B", + "solution": "【分析】根据整数混合运算的法则,算出题干中算式的得数,再算出选项中各个算式的得数,再进行选择即可。本题考查学生对 20 以内加减混合运算,连减运算法则的掌握和运用.\n【详解】 10 - (2 + 3) = 5,A. 10 - 2 + 3 = 11;B. 10 - 2 - 3 = 5;C. 10 + 2 - 3 = 9,与 10 - (2 + 3) 的得出相等的算式是 10 - 2 - 3 。故答案为: B.", + "knowledge_points": [ + "加减混合运算(20以内)", + "连加,连减(10以内)", + "带有小括号的混合运算" + ], + "source": "21-22 一年级下·湖北孝感·期末" + }, + { + "id": "302", + "unit": "20以内的退位减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "得数最大的式子为 ( )。", + "options": [ + "A. 13 - 5", + "B. 8 + 7", + "C. 5 + 9" + ], + "answer": "B", + "solution": "【分析】要找出得数最大的式子,需要先分别计算出每个选项的得数,然后比较这三个数的大小.\n【详解】计算各选项:A.13-5=8;B.8+7=15;C.5+9=14。比较得数:15>14>8。因此,得数最大的式子是8+7。故答案为:B", + "knowledge_points": [ + "十几减 5~2 的退位减法", + " 5~2 加几的进位加法", + "8 加几的进位加法", + "20 以内数的比大小" + ], + "source": "21-22 一年级上·湖北黄石·期末" + }, + { + "id": "303", + "unit": "20以内的退位减法", + "question_type": "选择题", + "difficulty": 0.65, + "question": "赵恬折了 7 只纸鹤,李萧萧和她折的同样多,他们两人一共折了 ( ) 只纸鹤。", + "options": [ + "A. 7 + 7 = 14", + "B. 2 + 7 = 9", + "C. 14 - 7 = 7" + ], + "answer": "A", + "solution": "【分析】\"李萧萧和她折的同样多\"意味着李萧萧也折了7只纸鹤。求两人一共折了多少只,就是把赵恬折的数量和李萧萧折的数量加起来.\n【详解】赵恬折了7只,李萧萧也折了7只。总数为:7 + 7 = 14(只)。因此,他们两人一共折了14只纸鹤。故答案为:A.", + "knowledge_points": [ + "8,9 的加减法", + "7,6 加几的进位加法", + "十几减 7,6 的退位减法" + ], + "source": "20-21一年级上·湖南张家界·期末" + }, + { + "id": "304", + "unit": "20以内的退位减法", + "question_type": "选择题", + "difficulty": 0.65, + "question": "从5,7,7,9,14这五个数中选出哪三个,能组成两道加法算式和两道减法算式。()", + "options": [ + "A. 5,9 和 14", + "B. 7,7 和 14", + "C. 7,9和14" + ], + "answer": "A", + "solution": "【分析】从这 5 个数字中,选出 3 个数字,只要两数相加等于第三个数及用一个数减去另一个数等于第三个数即可。此题主要考查的是 20 以内数的加减法的计算,要熟练掌握.\n【详解】由题意分析得:5 + 9 = 14;9 + 5 = 14;14 - 5 = 9;14 - 9 = 5,故答案为:A.", + "knowledge_points": [ + "十几减 5~2 的退位减法", + "9 加几的进位加法", + "十几减 9 的退位减法" + ], + "source": "20-21一年级上·安徽宿州·期末" + }, + { + "id": "305", + "unit": "20以内的退位减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "有18个苹果,每9个装满一袋,可以满()袋。", + "options": [ + "A. 4", + "B. 3", + "C. 2" + ], + "answer": "C", + "solution": "【分析】求18个苹果每9个装一袋可以装满几袋,就是求18里面有几个9。可以用减法连续减去9,看能减几次;也可以用除法的思路(虽然一年级未正式学除法,但用连减理解).\n【详解】从18个苹果中装袋:装第一袋用去9个,剩下 18 - 9 = 9(个);装第二袋再用去9个,剩下 9 - 9 = 0(个)。装了2次后苹果正好用完,所以可以装满2袋。故答案为:C.", + "knowledge_points": [ + "十几减9的退位减法" + ], + "source": "19-20一年级下·广东肇庆·期末" + }, + { + "id": "306", + "unit": "20以内的退位减法", + "question_type": "选择题", + "difficulty": 0.65, + "question": "每辆玩具车四个轮子,19个轮子最多可以安装()辆玩具车。", + "options": [ + "A. 3", + "B. 4", + "C. 5" + ], + "answer": "B", + "solution": "【分析】每辆玩具车需要4个轮子。求19个轮子最多可以安装几辆车,就是求19里面最多有几个4,可以用连续减去4的方法,直到剩下的轮子不够装一辆车为止.\n【详解】用轮子安装车:第一辆车用4个,剩下 19 - 4 = 15(个);第二辆车用4个,剩下 15 - 4 = 11(个);第三辆车用4个,剩下 11 - 4 = 7(个);第四辆车用4个,剩下 7 - 4 = 3(个)。此时剩下3个轮子,不够再装一辆车(因为一辆车需要4个轮子)。所以,最多可以安装4辆玩具车。故答案为:B.", + "knowledge_points": [ + "连减 (20以内)" + ], + "source": "19-20一年级下·河南南阳·期末" + }, + { + "id": "307", + "unit": "20以内的退位减法", + "question_type": "选择题", + "difficulty": 0.65, + "question": "12个同学排队做操,小明前面有8个人,后面有()个人。", + "options": [ + "A. 4", + "B. 3", + "C. 2" + ], + "answer": "B", + "solution": "【分析】排队的总人数包括小明前面的人,小明自己和小明后面的人。已知总人数和小明前面的人数,求小明后面的人数,需要从总人数中先减去小明前面的人数,再减去小明自己.\n【详解】总共有12人。小明前面有8人,那么包括小明在内的后面部分有 12 - 8 = 4(人)。这4人中包括小明自己,所以小明后面的人数是 4 - 1 = 3(人)。故答案为:B.", + "knowledge_points": [ + "连减(20以内)", + "十几减8的退位减法" + ], + "source": "20-21一年级下·河南南阳·期末" + }, + { + "id": "308", + "unit": "20以内的退位减法", + "question_type": "选择题", + "difficulty": 0.65, + "question": "下列算式中得数与其它算式不相等的是 ( )。", + "options": [ + "A. 13 - 9", + "B. 17 - 9", + "C. 11 - 3" + ], + "answer": "A", + "solution": "【分析】分别计算出各个选项的得数,再进行选择即可。熟练掌握 20 以内数的减法计算是解题的关键.\n【详解】. 13 - 9 = 4;B. 17 - 9 = 8;C. 11 - 3 = 8;B 和 C 的得数相等。故答案为:A.", + "knowledge_points": [ + "十几减 5~2 的退位减法", + "十几减9的退位减法" + ], + "source": "18-19 一年级下·广东肇庆·期末" + }, + { + "id": "309", + "unit": "20以内的退位减法", + "question_type": "选择题", + "difficulty": 0.65, + "question": "有 11 块蛋糕,爸爸和小明 2 人吃了 8 块,还剩 ( ) 块。", + "options": [ + "A. 1", + "B. 3", + "C. 9" + ], + "answer": "B", + "solution": "【分析】用蛋糕的数量减去吃的数量,即可求出还剩多少块.\n【详解】11 - 8 = 3(块),答:还剩3块。故选: .本题主要考查了 20 以内减法的实际应用,找出题中的数量关系,用减法计算。", + "knowledge_points": [ + "十几减8的退位减法" + ], + "source": "21-22 一年级下·甘肃甘南·期中" + }, + { + "id": "310", + "unit": "20以内的退位减法", + "question_type": "选择题", + "difficulty": 0.65, + "question": "算式 7 + 6 - 5 的得数和算式 ( ) 的得数相等。", + "options": [ + "A. 13 - 6", + "B. 14 - 6", + "C. 15 - 6" + ], + "answer": "B", + "solution": "【分析】要找到与 7 + 6 - 5 得数相等的算式,首先需要计算出原式的准确结果。然后分别计算每个选项的得数,进行对比.\n【详解】计算原式:7 + 6 - 5 = 13 - 5 = 8。计算各选项:A. 13 - 6 = 7;B. 14 - 6 = 8;C. 15 - 6 = 9。通过比较,原式的得数 8 与选项 B (14 - 6) 的得数 8 相等。故答案为:B.", + "knowledge_points": [ + "加减混合运算(20以内)", + "十几减7,6的退位减法" + ], + "source": "20-21 一年级下·山西阳泉·期中" + }, + { + "id": "311", + "unit": "20以内的退位减法", + "question_type": "选择题", + "difficulty": 0.65, + "question": "用 11 根同样长的小棒摆一个![](images/96f496df1de4957bf43518f7e0afde4733ca05c5cd394118f3a4ab20f3765f97.jpg) ,还剩()根小棒。", + "options": [ + "A. 5", + "B. 6", + "C. 7" + ], + "answer": "A", + "solution": "【分析】本题需要先数出摆出指定图形(看起来是一个三角形或一个多边形)所用的小棒数量,然后用总的小棒数量减去所用的小棒数量,即可得出剩余的数量.\n【详解】11 - 6 = 5 (根),答:还剩 5 根小棒。故选: A.", + "knowledge_points": [ + "十几减 7,6 的退位减法" + ], + "source": "20-21 一年级下·福建漳州·期末" + }, + { + "id": "312", + "unit": "20以内的退位减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "一年级共有 18 名同学,其中男生有 9 人,那么女生有 ( ) 人。", + "options": [ + "A. 11", + "B. 8", + "C. 9" + ], + "answer": "C", + "solution": "【分析】这是一个简单的减法应用题。已知总人数和其中一部分(男生)的人数,求另一部分(女生)的人数,用总人数减去已知部分的人数即可.\n【详解】一年级总人数为18人,男生有9人。那么女生人数为:18 - 9 = 9(人)。故答案为:C.", + "knowledge_points": [ + "十几减9的退位减法" + ], + "source": "20-21 一年级下·陕西延安·期中" + }, + { + "id": "313", + "unit": "20以内的退位减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "14 - □ 的得数是一位数。□ 里可以填()。", + "options": [ + "A. 0", + "B. 4", + "C. 6" + ], + "answer": "C", + "solution": "【分析】14 - □ 的得数是一位数,则□里可以填的一位数要大于4。据此判断即可.\n【详解】14 - □ 的得数是一位数,则□里可以填的一位数要大于4,可以是5,6,7,8,9。故答案为: C", + "knowledge_points": [ + "十几减 5~2 的退位减法", + "十几减 8 的退位减法", + "十几减9的退位减法", + "十几减7,6的退位减法" + ], + "source": "20-21一年级下·湖北孝感·期末" + }, + { + "id": "314", + "unit": "20以内的退位减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "被减数是 12,减数是 8,差是 ( )。", + "options": [ + "A. 20", + "B. 4", + "C. 5" + ], + "answer": "B", + "solution": "【分析】根据被减数-减数=差进行计算即可.\n【详解】12-8=4,所以差是4。故答案为:B", + "knowledge_points": [ + "十几减8的退位减法" + ], + "source": "20-21一年级下·江西赣州·期中" + }, + { + "id": "315", + "unit": "20以内的退位减法", + "question_type": "选择题", + "difficulty": 0.65, + "question": "有 11 个苹果,吃了 4 个,还剩 ( ) 个。", + "options": [ + "A. 6", + "B. 7", + "C. 8" + ], + "answer": "B", + "solution": "【分析】用苹果的总个数减去吃了的个数,就是还剩的个数。考查了整数减法的实际应用,根据题中所给的量进行计算即可.\n【详解】 11 - 4 = 7 (个),所以,还剩7个。故答案为: B.", + "knowledge_points": [ + "十几减 5~2 的退位减法" + ], + "source": "20-21一年级下·江西赣州·期中" + }, + { + "id": "316", + "unit": "20以内的退位减法", + "question_type": "选择题", + "difficulty": 0.65, + "question": "12○6=6,○里填( )。", + "options": [ + "A. /", + "B. -", + "C. +" + ], + "answer": "B", + "solution": "【分析】题目要求在圆圈中填入正确的运算符号,使等式 12 ○ 6 = 6 成立。需要根据等式右边的结果 6,尝试不同的运算,判断哪个符号能使算式成立.\n【详解】将选项中的符号代入计算:A. 12÷6 = 2,结果不等于6,不符合。. 12 - 6 = 6,结果等于6,符合。. 12 + 6 = 18,结果不等于6,不符合。因此,圆圈里应填\"-\"。故答案为:B.", + "knowledge_points": [ + "十几减 7,6 的退位减法" + ], + "source": "20-21 二年级下·吉林四平·期中" + }, + { + "id": "317", + "unit": "20以内的退位减法", + "question_type": "选择题", + "difficulty": 0.65, + "question": "妞妞家有15只鸭和5只鹅。母鸭有8只,公鸭有( )只。", + "options": [ + "A. 10", + "B. 7", + "C. 2" + ], + "answer": "B", + "solution": "【分析】用鸭的总数减去母鸭的数量,剩下的就是公鸭的数量。熟练掌握 20 以内数的减法计算是解题的关键.\n【详解】15 - 8 = 7(只),公鸭有 7 只。故答案为: B.", + "knowledge_points": [ + "十几减8的退位减法" + ], + "source": "20-21一年级下·吉林四平·期中" + }, + { + "id": "318", + "unit": "20以内的退位减法", + "question_type": "选择题", + "difficulty": 0.65, + "question": "冬冬和月月学写毛笔字。冬冬写了 16 个字,月月写了 8 个字,冬冬比月月多写了 ( ) 个字。", + "options": [ + "A. 10", + "B. 9", + "C. 8" + ], + "answer": "C", + "solution": "【分析】用冬冬写字的个数减去月月写字的个数,就是冬冬比月月多写字的个数。据此解答。考查了整数减法的实际应用,根据题中所给的量进行计算即可.\n【详解】16 - 8 = 8 (个),则冬冬比月月多写了 8 个字。故答案为: C.", + "knowledge_points": [ + "十几减8的退位减法" + ], + "source": "20-21 一年级下·吉林·期中" + }, + { + "id": "319", + "unit": "20以内的退位减法", + "question_type": "选择题", + "difficulty": 0.65, + "question": "12-□=4,方框里能填( )。", + "options": [ + "A. 9", + "B. 8", + "C. 2" + ], + "answer": "B", + "solution": "【分析】根据12-□=4,用被减数减差求□,或把选项代入验算.\n【详解】12-8=4,所以□里应填8。故答案为:B", + "knowledge_points": [ + "十几减9的退位减法" + ], + "source": "20-21 一年级下·内蒙古包头·期末" + }, + { + "id": "320", + "unit": "20以内的退位减法", + "question_type": "选择题", + "difficulty": 0.4, + "question": "12 个小朋友玩\"老鹰抓小鸡\"的游戏,从前往后数,小飞是第 5 只鸡,小飞后面还有几只鸡。()", + "options": [ + "A. 5", + "B. 6", + "C. 7" + ], + "answer": "B", + "solution": "【分析】用小朋友总数减去 1,再减去小飞从前往后数的位数,就是小飞后面的鸡数。本题主要考查排队问题,关键是用小朋友的总数减去 1,也就是其中有一个小朋友当的老鹰.\n【详解】12 - 5 - 1= 7 - 1 = 6 ( 个) ,小飞后面还有 6 只鸡。故答案为: B", + "knowledge_points": [ + "十几减 5~2 的退位减法", + "连减(20以内)" + ], + "source": "20-21 一年级下·四川内江·期末" + }, + { + "id": "321", + "unit": "20以内的退位减法", + "question_type": "填空题", + "difficulty": 0.65, + "question": "姐姐今年 13 岁,弟弟今年 7 岁。3 年后姐姐比弟弟大( )岁。", + "options": [], + "answer": "6", + "solution": "【分析】由题意可知,今年姐姐比弟弟大 13 - 7 = 6 岁,根据年龄差不变的规律, 3 年后姐姐比弟弟还是大 6 岁。本题考查年龄问题,明确年龄差不变是解题的关键.\n【详解】13 - 7 = 6 (岁),则3年后姐姐比弟弟大6岁。", + "knowledge_points": [ + "十几减 7,6 的退位减法" + ], + "source": "21-22 二年级上·湖北襄阳·期末" + }, + { + "id": "322", + "unit": "20以内的退位减法", + "question_type": "填空题", + "difficulty": 0.65, + "question": "每人要写 12 个大字,丽丽还有 7 个大字没写好,她已经写好了( )个大字。", + "options": [], + "answer": "5", + "solution": "【分析】这是一个减法应用题。已知总任务量和未完成的部分,求已完成的部分。用总任务量减去未完成的数量,即可得到已完成的数量.\n【详解】总共要写12个大字。还没有写好的有7个。那么已经写好的大字数量为:12 - 7 = 5(个)。故答案为:5。", + "knowledge_points": [ + "十几减 7,6 的退位减法" + ], + "source": "20-21一年级下·山西太原·期末" + }, + { + "id": "323", + "unit": "20以内的退位减法", + "question_type": "填空题", + "difficulty": 0.65, + "question": "在括号里填上\"+\"或\"-\".\n\n11( ) 4 = 7;12( ) 7 = 19;14( ) 9 = 5;15( ) 0 = 15", + "options": [], + "answer": "-;+;-;+", + "solution": "【分析】根据口算方法,再选择合适的符号进行填空即可。此题主要考查的是 20 以内数的加减法计算,解题的关键是掌握数的加减运算法则.\n【详解】 11 - 4 = 7;12 + 7 = 19;14 - 9 = 5;15 + 0 = 15 (答案不唯一)", + "knowledge_points": [ + "不进位加法(20以内)", + "十几减9的退位减法", + "十几减7,6的退位减法" + ], + "source": "20-21一年级下·山西太原·期末" + }, + { + "id": "324", + "unit": "20以内的退位减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "计算 \"12-7\"时,可以想( ) +( ) = 12 。", + "options": [], + "answer": "5;7", + "solution": "【分析】本题考查\"想加算减\"的计算方法。在计算十几减几的退位减法时,可以通过思考\"几加几等于被减数\"来得到差.\n【详解】计算12-7时,想:因为 5 + 7 = 12,所以 12 - 7 = 5。因此,计算时可以想 5 + 7 = 12。故答案为:5;7。", + "knowledge_points": [ + "十几减7,6的退位减法" + ], + "source": "20-21 一年级下·福建福州·期中" + }, + { + "id": "325", + "unit": "20以内的退位减法", + "question_type": "填空题", + "difficulty": 0.65, + "question": "小丽读一本童话书,她今天从第6页读到第13页,明天就要开始读第14页了,她今天一共读了( )页。", + "options": [], + "answer": "8", + "solution": "【分析】用明天该看的页数减去今天开始看的页数,即可求出她今天读了多少页.\n【详解】14 - 6 = 8(页),她今天一共读了8页。本题主要考查了 20 以内减法的实际应用,首先弄清题意,分清已知与所求,再找出基本数量关系,用减法进行计算。", + "knowledge_points": [ + "十几减 7,6 的退位减法" + ], + "source": "21-22一年级上·福建福州·期末" + }, + { + "id": "326", + "unit": "20以内的退位减法", + "question_type": "填空题", + "difficulty": 0.65, + "question": "一个两位数,十位上是 1,个位上的数字比十位上的数字大 5,这个数是( ), 它与最大的一位数相差( )。", + "options": [], + "answer": "16;7", + "solution": "【分析】根据题意可知,个位上的数字比十位上的数字大5,用1+5,求出个位上的数字。进而求出这个数;最大的一位数是9,再用这个数减去9,即可解答.\n【详解】1+5=6,这个数是16;最大的一位数是9;16-9=7。一个两位数,十位上是1,个位上的数字比十位上的数字大5,这个数是16,它与最大的一位数相差7。", + "knowledge_points": [ + "20以内数的组成", + "十几减9的退位减法" + ], + "source": "21-22一年级上·山东菏泽·期末" + }, + { + "id": "327", + "unit": "20以内的退位减法", + "question_type": "填空题", + "difficulty": 0.65, + "question": "比 12 多 5 的数是( ), 9 比 17 少( )。", + "options": [], + "answer": "17;8", + "solution": "【分析】求比 12 多 5 的数,用 12 + 5 即可;求比 17 少 9 的数,用 17 - 9 即可。熟练掌握 20 以内加减法计算是解题的关键.\n【详解】12 + 5 = 17,比12多5的数17;17 - 9 = 8,9比17少8。", + "knowledge_points": [ + "不进位加法(20以内)", + "十几减9的退位减法" + ], + "source": "20-21 一年级上·贵州铜仁·期末" + }, + { + "id": "328", + "unit": "20以内的退位减法", + "question_type": "填空题", + "difficulty": 0.65, + "question": "两个加数都是 8,和是( ),被减数是15,减数是6,差是( )。", + "options": [], + "answer": "16;9", + "solution": "【分析】加数 + 加数 = 和,被减数 - 减数 = 差,据此解答。熟练掌握加,减法算式中各部分之间的关系是解答此题的关键.\n【详解】8 + 8 = 16;15 - 6 = 9,两个加数都是 8,和是 16,被减数是 15,减数是 6,差是 9 。", + "knowledge_points": [ + "加,减法的意义和各部分间的关系", + "十几减7,6 的退位减法", + "8 加几的进位加法" + ], + "source": "20-21 一年级上·贵州铜仁·期末" + }, + { + "id": "329", + "unit": "20以内的退位减法", + "question_type": "填空题", + "difficulty": 0.65, + "question": "朵朵今年8岁,淘淘哥哥今年11岁。5年后淘淘哥哥比朵朵大( )岁。", + "options": [], + "answer": "3", + "solution": "【分析】根据题意可知,朵朵今年 8 岁,淘淘哥哥今年 11 岁,淘淘哥哥比朵朵大 11-8 岁,无论过多少年,淘淘哥哥比朵朵大 11-8 岁,据此解答。关键是明确淘淘哥哥和朵朵的年纪差不会随着年纪增加而增加.\n【详解】11 - 8 = 3(岁),5年后淘淘哥哥比朵朵大3岁。", + "knowledge_points": [ + "十几减8的退位减法", + "年龄问题" + ], + "source": "19-20一年级上·吉林四平·期末" + }, + { + "id": "330", + "unit": "20以内的退位减法", + "question_type": "填空题", + "difficulty": 0.65, + "question": "括号里最大能填几。\n\n( )+6<10;( )-10<3;8+( )<11;( )-5<9", + "options": [], + "answer": "3;12;2;13", + "solution": "【分析】本题要求在每个不等式的括号中填入最大可能的整数,使不等式成立。解题关键是先将不等式转化为括号小于某个数的形式,然后找出比该数小的最大整数.\n【详解】( )+6<10→括号<10-6→括号<4,最大能填3;( )-10<3→括号<3+10→括号<13,最大能填12;8+( )<11→括号<11-8→括号<3,最大能填2;( )-5<9→括号<9+5→括号<14,最大能填13。因此,答案为:3;12;2;13。", + "knowledge_points": [ + "十几减 5~2 的退位减法", + "不退位减法(20以内)", + "10 的加减法", + "8 加几的进位加法" + ], + "source": "21-22 一年级上·河南南阳·期末" + }, + { + "id": "331", + "unit": "20以内的退位减法", + "question_type": "填空题", + "difficulty": 0.65, + "question": "在()里填上合适的数.\n\n9 + () = 13;11 - () = 6;7 + 6 = ();() + 11 = 15\n\n8 + 9 = ();5 + () = 11;9 + () = 13;() + 3 = 11", + "options": [], + "answer": "4;5;13;4;17;6;4;8", + "solution": "【分析】本题是根据加减法算式填空,主要运用加减法的互逆关系:一个加数 = 和 - 另一个加数;减数 = 被减数 - 差。需要根据已知数字,计算出括号中应填的数.\n【详解】9 + ( ) = 13 → ( ) = 13 - 9 = 4;11 - ( ) = 6 → ( ) = 11 - 6 = 5;7 + 6 = ( ) → ( ) = 7 + 6 = 13;( ) + 11 = 15 → ( ) = 15 - 11 = 4;8 + 9 = ( ) → ( ) = 8 + 9 = 17;5 + ( ) = 11 → ( ) = 11 - 5 = 6;9 + ( ) = 13 → ( ) = 13 - 9 = 4;( ) + 3 = 11 → ( ) = 11 - 3 = 8。因此,依次填入的数为:4;5;13;4;17;6;4;8。", + "knowledge_points": [ + "加,减法的意义和各部分间的关系", + "7,6加几的进位加法", + "十几减 7,6 的退位减法", + "8 加几的进位加法" + ], + "source": "20-21一年级上·黑龙江黑河·期末" + }, + { + "id": "332", + "unit": "20以内的退位减法", + "question_type": "填空题", + "difficulty": 0.65, + "question": "美美读一本书,今天从第9页读到第15页,明天该读第16页了。她今天读了 ( )页。", + "options": [], + "answer": "7", + "solution": "【分析】用明天该看的页数减去今天开始看的页数,即可求出她今天读了多少页。本题主要考查了 20 以内减法的实际应用,首先弄清题意,分清已知与所求,再找出基本数量关系,用减法进行计算.\n【详解】16 - 9 = 7(页),所以,她今天读了7页。", + "knowledge_points": [ + "十几减9的退位减法" + ], + "source": "21-22一年级上·福建莆田·期末" + }, + { + "id": "333", + "unit": "20以内的退位减法", + "question_type": "填空题", + "difficulty": 0.65, + "question": "同学们站成一队,王芳站在第 7,张语耘站在第 12,他们之间有( )人。", + "options": [], + "answer": "4", + "solution": "【分析】用 12 减去 7,再减去 1,求出他们之间的人数。本题考查了 20 以内的减法,有一定运算能力是解题的关键.\n【详解】12 - 7 - 1 = 5 - 1 = 4 (人),他们之间有 4 人。", + "knowledge_points": [ + "连减(20以内)", + "十几减7,6的退位减法" + ], + "source": "20-21 一年级上·湖南张家界·期末" + }, + { + "id": "334", + "unit": "20以内的退位减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "在括号里填上\">\"\"<\"或\"=\".\n\n10( )0;14( )19;5+8( )7+6;18-5( )13-5", + "options": [], + "answer": ">;<;=;>", + "solution": "【分析】20以内的数从小到大排列是:1<2<3<4<5<6<7<8<9<10<11<12<13<14<15<16<17<18<19<20。含有算式的,可以先计算出算式的结果,再比较大小.\n【详解】10>0,14<19;5+8=13,7+6=13,所以5+8=7+6;18-5=13,13-5=8,所以18-5>13-5。", + "knowledge_points": [ + "十几减 5~2 的退位减法", + "7,6 加几的进位加法", + "8 加几的进位加法", + "20 以内数的比大小" + ], + "source": "20-21 一年级上·浙江丽水·期末" + }, + { + "id": "335", + "unit": "20以内的退位减法", + "question_type": "填空题", + "difficulty": 0.65, + "question": "明明读一本故事书,今天从第 8 页读到了第 17 页,他今天一共读了( )页。", + "options": [], + "answer": "10", + "solution": "【分析】这是一个关于页码计算的题目。当从第A页读到第B页时,所读的页数应包括起始页A和结束页.计算时,可以用结束页码减去开始页码,再加上1(因为减去了开始页本身).\n【详解】从第8页读到第17页。先计算页数差:17 - 8 = 9。这个\"9\"表示从第8页之后到第17页(不包括第8页)有9页。由于阅读是从第8页开始的,需要把第8页也加上,所以总页数为:9 + 1 = 10(页)。因此,他今天一共读了10页。", + "knowledge_points": [ + "加减混合运算(20以内)", + "十几减8的退位减法" + ], + "source": "21-22一年级下·河南南阳·阶段练习" + }, + { + "id": "336", + "unit": "20以内的退位减法", + "question_type": "填空题", + "difficulty": 0.65, + "question": "亮亮有14张卡片,小东有8张卡片,亮亮送给小东( )张卡片后,他们的卡片数量就同样多。", + "options": [], + "answer": "3", + "solution": "【分析】依据减法意义,用 14 - 8,即可求出小亮亮比小东多的张数;再将多的张数分成两个相同的数相加,据此解答。熟练掌握 20 以内数的加减法是解题的关键.\n【详解】14 - 8 = 6(张),6 = 3 + 3,亮亮送给小东 3 张卡片后,他们的卡片数量就同样多。", + "knowledge_points": [ + "十几减8的退位减法" + ], + "source": "20-21一年级下·福建厦门·期末" + }, + { + "id": "337", + "unit": "20以内的退位减法", + "question_type": "填空题", + "difficulty": 0.65, + "question": "计算 13 - 8,应先算 10 - 8 = 2,再算( )。", + "options": [], + "answer": "2+3=5", + "solution": "【分析】计算13-8,可以用破十法计算,将被减数13分成10和3,先算10-8=2,再算2+3=5,由此解答即可.\n【详解】由分析可得:计算13-8,应先算10-8=2,再算2+3=5。", + "knowledge_points": [ + "十几减8的退位减法" + ], + "source": "21-22 一年级下·山东济宁·期中" + }, + { + "id": "338", + "unit": "20以内的退位减法", + "question_type": "填空题", + "difficulty": 0.4, + "question": "小红有 16 支铅笔,小芳有 9 支铅笔,小芳至少再买( )支铅笔才能比小红的铅笔多。", + "options": [], + "answer": "8", + "solution": "【分析】这是一个比较问题。首先需要求出小芳比小红少几支铅笔。要使小芳的铅笔比小红多,小芳的铅笔总数至少要超过小红的铅笔数1支。因此,小芳需要再买的铅笔数 = (小红铅笔数 - 小芳现有铅笔数) + 1.\n【详解】小红有16支,小芳有9支。小芳比小红少:16 - 9 = 7(支)。要使小芳的铅笔比小红多,至少需要比小红多1支,即小芳的总铅笔数应达到 16 + 1 = 17(支)。因此,小芳需要再买:17 - 9 = 8(支),或者直接用 7 + 1 = 8(支)。故答案为:8。", + "knowledge_points": [ + "十几减9的退位减法" + ], + "source": "20-21 一年级下·贵州六盘水·期中" + }, + { + "id": "339", + "unit": "20以内的退位减法", + "question_type": "填空题", + "difficulty": 0.65, + "question": "17个小朋友站成一排,从前往后数,丽丽排第9,她后面还有( )人。", + "options": [], + "answer": "8", + "solution": "【分析】这是一个排队位置问题。已知总人数和丽丽从前往后数的位置(第9位),要求她后面还有多少人。她后面的人数等于总人数减去包括丽丽在内的前9个人.\n【详解】总共有17人。丽丽排第9位,这意味着从第1位到第9位共有9个人。因此,丽丽后面的人数为:17 - 9 = 8(人)。故答案为:8。", + "knowledge_points": [ + "前,后位置", + "十几减9的退位减法" + ], + "source": "19-20一年级下·四川德阳·期末" + }, + { + "id": "340", + "unit": "20以内的退位减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "男生17人,女生9人,男生比女生多( )人。", + "options": [], + "answer": "8", + "solution": "【分析】这是一个简单的比较问题,求一个数比另一个数多多少。用较大的数(男生人数)减去较小的数(女生人数),即可得到多出的人数.\n【详解】男生有17人,女生有9人。男生比女生多:17 - 9 = 8(人)。故答案为:8。", + "knowledge_points": [ + "十几减9的退位减法" + ], + "source": "20-21一年级下·新疆省直辖县级单位·期中" + }, + { + "id": "341", + "unit": "20以内的退位减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "8 比 15 少( ),比 3 多 9 的数是( )。", + "options": [], + "answer": "7;12", + "solution": "【分析】本题考查两个问题:1. 求一个数比另一个数少多少,用减法;2. 求比一个数多几的数是多少,用加法.\n【详解】求8比15少多少:用15减去8,即 15 - 8 = 7。求比3多9的数是多少:用3加上9,即 3 + 9 = 12。因此,答案为:7;12。", + "knowledge_points": [ + "十几减8的退位减法", + "5~2加几的进位加法" + ], + "source": "20-21 一年级下·新疆吐鲁番·期中" + }, + { + "id": "342", + "unit": "20以内的退位减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "计算 14 - 8 时,想: 10 -() = (), () + 4 = () 。所以 14 - 8 =() 。", + "options": [], + "answer": "8;2;2;6;6", + "solution": "【分析】把 14 分成 10 和 4,然后结合 10 的组成计算即可求解。此题主要考查了整数减法运算,关键是熟练掌握计算法则正确进行计算.\n【详解】计算 14 - 8 时,想: 10 - 8 = 2, 2 + 4 = 6,所以 14 - 8 = 6 。", + "knowledge_points": [ + "十几减8的退位减法" + ], + "source": "20-21 一年级下·湖北孝感·期中" + }, + { + "id": "343", + "unit": "20以内的退位减法", + "question_type": "填空题", + "difficulty": 0.65, + "question": "汤姆叔叔有 12 个小机器人,送给小朋友们 7 个,他还有( )个小机器人。", + "options": [], + "answer": "5", + "solution": "【分析】这是一个简单的减法应用题。已知原有的数量和送出的数量,求剩余的数量,用原有的数量减去送出的数量即可.\n【详解】汤姆叔叔原有12个小机器人,送出7个后,剩余的数量为:12 - 7 = 5(个)。故答案为:5。", + "knowledge_points": [ + "十几减 7,6 的退位减法" + ], + "source": "20-21 一年级下·湖北武汉·期中" + }, + { + "id": "344", + "unit": "20以内的退位减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "在算式 17 - 8 中,可以想 8 + () = 17,所以 17 - 8 = ();也可以想:先算( )-( )=( ), 再算( )+( )=( )。", + "options": [], + "answer": "9;9;10;8;2;7;2;9", + "solution": "【分析】本题考查计算 17 - 8 的两种常用方法:想加算减法和破十法。想加算减法:思考\"8加几等于17\",得到的数就是差。破十法:把被减数17分成10和7,先用10减去减数8,得到2,再用剩下的7加上这个2,得到最终结果.\n【详解】方法一(想加算减):因为 8 + 9 = 17,所以 17 - 8 = 9。方法二(破十法):把17分成10和7。先算 10 - 8 = 2,再算 7 + 2 = 9。因此,填空依次为:9;9;10;8;2;7;2;9。", + "knowledge_points": [ + "十几减8的退位减法" + ], + "source": "21-22一年级下·湖北黄冈·期中" + }, + { + "id": "345", + "unit": "20以内的退位减法", + "question_type": "填空题", + "difficulty": 0.65, + "question": "被减数是15,差是9,减数是( )。", + "options": [], + "answer": "6", + "solution": "【分析】根据\"被减数-差 = 减数\"进行计算即可.\n【详解】15 - 9 = 6", + "knowledge_points": [ + "十几减9的退位减法" + ], + "source": "20-21 一年级下·内蒙古巴彦淖尔·期中" + }, + { + "id": "346", + "unit": "20以内的退位减法", + "question_type": "填空题", + "difficulty": 0.65, + "question": "口算 13 - 9 时,我们可以先想 ( ) + ( )=13,所以 13 - 9 = () 。", + "options": [], + "answer": "9;4;4", + "solution": "【分析】根据加减法之间的关系,想加法算减法,口算 13 - 9 时,我们可以先想 9 + 4 = 13,所以 13 - 9 = 4 。据此解答。此题考查的目的理解掌握 20 以内数的加减法的计算方法及应用,口算两位数减一位数时,一般利用想加法算减法进行解答.\n【详解】口算 13 - 9 时,我们可以先想 9 + 4 = 13,所以 13 - 9 = 4 。", + "knowledge_points": [ + "十几减9的退位减法" + ], + "source": "20-21 一年级下·山西晋中·期末" + }, + { + "id": "347", + "unit": "20以内的退位减法", + "question_type": "判断题", + "difficulty": 0.85, + "question": "△ 比 ○ 多 12 个,也就是 ○ 比△少 12 个。( )", + "options": [], + "answer": "√", + "solution": "【分析】根据数据的相对性即可求解。本题考查了 100 以内加减法,关键是理解两个数之间的多少关系具有相对性.\n【详解】△ 比 ○ 多 12 个,也就是 ○ 比 △ 少 12 个是正确的。故答案为: √。", + "knowledge_points": [ + "比较物体多少" + ], + "source": "20-21 一年级下·湖北孝感·期中" + }, + { + "id": "348", + "unit": "20以内的退位减法", + "question_type": "判断题", + "difficulty": 0.65, + "question": "12-9 与 11-8 得数相等。( )", + "options": [], + "answer": "√", + "solution": "【分析】分别计算出 12 - 9 和 11 - 8 的差,再进行比较即可。熟练掌握 20 以内数的减法计算是解题的关键.\n【详解】12 - 9 = 3;11 - 8 = 3;3 = 3;12-9 与 11-8 得数相等,原题说法正确。故答案为: √。", + "knowledge_points": [ + "十几减8的退位减法", + "十几减9的退位减法" + ], + "source": "20-21 一年级下·黑龙江哈尔滨·期末" + }, + { + "id": "349", + "unit": "20以内的退位减法", + "question_type": "判断题", + "difficulty": 0.65, + "question": "被减数是 12,减数是 3,差是 9 。 ( )", + "options": [], + "answer": "√", + "solution": "【分析】根据\"被减数 - 减数 = 差\"进行解答即可。熟练掌握 20 以内数的减法计算是解题的关键.\n【详解】12 - 3 = 9,原题计算正确。故答案为: √。", + "knowledge_points": [ + "十几减 5~2 的退位减法" + ], + "source": "20-21 一年级下·黑龙江哈尔滨·期末" + }, + { + "id": "350", + "unit": "20以内的退位减法", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式计算.\n\n![](images/be3add0abead7c59e2f5dcb599667a722326214864cff4fa27b0e434135ab49e.jpg)\n\n□ ○ □ = □", + "options": [], + "answer": "13-4=9", + "solution": "【分析】从图上可得:一共有 13 支彩粉笔,已知左边有 4 支,求右边的盒子里面有多少支。根据整数减法的意义,列式解答即可.\n【详解】13 - 4 = 9 (支)", + "knowledge_points": [ + "十几减 5~2 的退位减法" + ], + "source": "20-21 一年级下·海南省直辖县级单位·期末" + }, + { + "id": "351", + "unit": "20以内的退位减法", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式计算.\n\n![](images/1ca44e6a94bc63c7047abc38d1a509da3f33b4fb3cc3318378f6bb0d4f7d43e2.jpg)\n\n□ ○ □ = □ (人)", + "options": [], + "answer": "12-3=9", + "solution": "【分析】根据题意所知:图中数字表示共有 12 个人,图的上面已有 3 人,问阴影部分有几人来列算式.\n【详解】12 - 3 = 9 (人)", + "knowledge_points": [ + "十几减 5~2 的退位减法" + ], + "source": "21-22 一年级下·西藏那曲·期末" + }, + { + "id": "352", + "unit": "20以内的退位减法", + "question_type": "计算题", + "difficulty": 0.85, + "question": "我会看图列式计算.\n\n![](images/0a9e50c86cd8b8bae5f3bdca045639f5fa3df0cd5ce022af9c9a055f330777d5.jpg)\n\n□ ○ □ = □()", + "options": [], + "answer": "15-9=6", + "solution": "【分析】图中显示两部分积木:一部分是外露的,有9块;另一部分是盒子里的,数量未知。两部分合起来总共有15块。求盒子里的积木数量,用总数减去外露部分的数量.\n【详解】总数是15块,外露部分是9块,所以盒子里的积木数量为:15 - 9 = 6(块)。列式为:15 - 9 = 6(块)。", + "knowledge_points": [ + "图文问题", + "十几减9的退位减法" + ], + "source": "2022一年级下·全国·专题练习" + }, + { + "id": "353", + "unit": "20以内的退位减法", + "question_type": "计算题", + "difficulty": 0.85, + "question": "我会看图列式.\n\n![](images/796b1070646651c8b29571d243d438801ca4465edd538900e68a1e88cefc9815.jpg)\n\n□ ○ □ = □ (个)", + "options": [], + "answer": "13-8=5", + "solution": "【分析】图中显示两部分物品:右边外露的有8个,左边盒子里的数量未知。两部分合起来总共有13个。求盒子里的物品数量,用总数减去外露部分的数量.\n【详解】总数是13个,外露部分是8个,所以盒子里的物品数量为:13 - 8 = 5(个)。列式为:13 - 8 = 5(个)。", + "knowledge_points": [ + "图文问题", + "十几减8的退位减法" + ], + "source": "2022 一年级下·全国·专题练习" + }, + { + "id": "354", + "unit": "20以内的退位减法", + "question_type": "计算题", + "difficulty": 0.85, + "question": "我会看图列式.\n\n![](images/58c2b55ccdc0864894e5997ff78dd979fae3593985eda052f4aa8cb57caa0a62.jpg)\n\n□ ○ □ = □ (个)", + "options": [], + "answer": "17-9=8", + "solution": "【分析】图中显示两部分物品:左边外露的有9个,右边盒子里的数量未知。两部分合起来总共有17个。求盒子里的物品数量,用总数减去外露部分的数量.\n【详解】总数是17个,外露部分是9个,所以盒子里的物品数量为:17 - 9 = 8(个)。列式为:17 - 9 = 8(个)。", + "knowledge_points": [ + "图文问题", + "十几减9的退位减法" + ], + "source": "21-22 一年级下·全国·单元测试" + }, + { + "id": "355", + "unit": "20以内的退位减法", + "question_type": "计算题", + "difficulty": 0.65, + "question": "我会看图列式计算.\n\n![](images/683af2545b85598d5b3b42a9d331dbd48973ccf0cc3914014368a83d03610f96.jpg)\n\n□ ○ □ = □ (枝)", + "options": [], + "answer": "11-2=9", + "solution": "【分析】图中显示两部分花:右边外露的有2枝,左边袋子里的数量未知。两部分合起来总共有11枝。求袋子里的花数量,用总数减去外露部分的数量.\n【详解】总数是11枝,外露部分是2枝,所以袋子里的花数量为:11 - 2 = 9(枝)。列式为:11 - 2 = 9(枝)。", + "knowledge_points": [ + "十几减 5~2 的退位减法", + "图文问题" + ], + "source": "2022一年级下·全国·专题练习" + }, + { + "id": "356", + "unit": "20以内的退位减法", + "question_type": "计算题", + "difficulty": 0.65, + "question": "看图列式计算.\n\n![](images/c405521d883e4452d9ba76d020223e0f58dc18744d9a0e7ebf94ca1eddaa32f2.jpg)\n\n□ ○ □ = □ (块)", + "options": [], + "answer": "15-9=6", + "solution": "【分析】图中显示两部分积木:左边外露的有9块,右边盒子里的数量未知。两部分合起来总共有15块。求盒子里的积木数量,用总数减去外露部分的数量.\n【详解】总数是15块,外露部分是9块,所以盒子里的积木数量为:15 - 9 = 6(块)。列式为:15 - 9 = 6(块)。", + "knowledge_points": [ + "图文问题", + "十几减9的退位减法" + ], + "source": "2022 一年级下·全国·专题练习" + }, + { + "id": "357", + "unit": "20以内的退位减法", + "question_type": "计算题", + "difficulty": 0.85, + "question": "我会看图列式计算.\n\n![](images/8c72bef8c11487eeb677cfe6327aa8c72c8019770712c2c47e5c853891900242.jpg)\n\n□ ○ □ = □ ( )", + "options": [], + "answer": "15-9=6", + "solution": "【分析】图中显示两部分积木:左边外露的有9块,右边盒子里的数量未知。旁边的数字\"15\"表示两部分积木的总数。求盒子里的积木数量,用总数减去外露部分的数量.\n【详解】总数是15块,外露部分是9块,所以盒子里的积木数量为:15 - 9 = 6(块)。列式为:15 - 9 = 6(块)。", + "knowledge_points": [ + "图文问题", + "十几减9的退位减法" + ], + "source": "2022一年级下·全国·专题练习" + }, + { + "id": "358", + "unit": "20以内的退位减法", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式计算.\n\n![](images/a55a6bfa6aab341ef111ef34d2c960a7e76274ce49479d31834a9c8777a0406c.jpg)\n\n□ ○ □ = □ (个)", + "options": [], + "answer": "13-4=9", + "solution": "【分析】图中显示两部分物品:右边外露的有4个,左边盒子里的数量未知。旁边的数字\"13\"表示两部分物品的总数。求盒子里的物品数量,用总数减去外露部分的数量.\n【详解】总数是13个,外露部分是4个,所以盒子里的物品数量为:13 - 4 = 9(个)。列式为:13 - 4 = 9(个)。", + "knowledge_points": [ + "十几减 5~2 的退位减法", + "图文问题" + ], + "source": "2022 一年级下·全国·专题练习" + }, + { + "id": "359", + "unit": "20以内的退位减法", + "question_type": "计算题", + "difficulty": 0.65, + "question": "我会看图列式.\n\n![](images/0723ff7ce6ac19479ea85aa831eb023b40de7b4baeb585ad2b3f5aead0f3f1ce.jpg)\n\n□ ○ □ = □ (个)", + "options": [], + "answer": "12-4=8", + "solution": "【分析】图中显示两部分苹果:左边外露的有4个,右边篮子里的数量未知。旁边的数字\"12\"表示两部分苹果的总数。求篮子里的苹果数量,用总数减去外露部分的数量.\n【详解】总数是12个,外露部分是4个,所以篮子里的苹果数量为:12 - 4 = 8(个)。列式为:12 - 4 = 8(个)。", + "knowledge_points": [ + "十几减 5~2 的退位减法", + "图文问题" + ], + "source": "2022 一年级下·全国·专题练习" + }, + { + "id": "360", + "unit": "20以内的退位减法", + "question_type": "计算题", + "difficulty": 0.65, + "question": "看图列式.\n\n![](images/eee90f778b60ba1633fb3a528e588fc3ee054726f8895f0a19fcdc3c92473f56.jpg)\n\n□ ○ □ = □ (只)", + "options": [], + "answer": "14-5=9", + "solution": "【分析】图中显示两部分小鸡:左边外露的有5只,右边房子里的数量未知。旁边的数字\"14\"表示两部分小鸡的总数。求房子里的小鸡数量,用总数减去外露部分的数量.\n【详解】总数是14只,外露部分是5只,所以房子里的小鸡数量为:14 - 5 = 9(只)。列式为:14 - 5 = 9(只)。", + "knowledge_points": [ + "十几减 5~2 的退位减法", + "图文问题" + ], + "source": "2022 一年级下·全国·专题练习" + }, + { + "id": "361", + "unit": "20以内的退位减法", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式计算.\n\n![](images/1f71505698df22ccdea00335d97fba81e1384ab4bb7d261d5382b3c83cccb41b.jpg)\n\n□ ○ □ = □ ( )", + "options": [], + "answer": "15-7=8", + "solution": "【分析】图中显示两部分水果:右边外露的有7个,左边篮子里的数量未知。旁边的数字\"15\"表示两部分水果的总数。求篮子里的水果数量,用总数减去外露部分的数量.\n【详解】总数是15个,外露部分是7个,所以篮子里的水果数量为:15 - 7 = 8(个)。列式为:15 - 7 = 8(个)。", + "knowledge_points": [ + "图文问题", + "十几减 7,6 的退位减法" + ], + "source": "2022 一年级下·全国·专题练习" + }, + { + "id": "362", + "unit": "20以内的退位减法", + "question_type": "计算题", + "difficulty": 0.65, + "question": "看图列式计算我最棒.\n\n![](images/0d0679d7ee8be7b478e4ebd3d5b36f66567630cec01461c015ceaba13e580aa9.jpg)\n\n□ ○ □ = □ (朵)", + "options": [], + "answer": "14-5=9", + "solution": "【分析】图中显示两部分花:左边外露的有5朵,右边篮子里的数量未知。旁边的数字\"14\"表示两部分花的总数。求篮子里的花数量,用总数减去外露部分的数量.\n【详解】总数是14朵,外露部分是5朵,所以篮子里的花数量为:14 - 5 = 9(朵)。列式为:14 - 5 = 9(朵)。", + "knowledge_points": [ + "十几减 5~2 的退位减法", + "图文问题" + ], + "source": "2022 一年级下·全国·专题练习" + }, + { + "id": "363", + "unit": "20以内的退位减法", + "question_type": "计算题", + "difficulty": 0.65, + "question": "看图列式计算.\n\n![](images/71afd3920e4468ef1fdf3ccba02a154ca31b9229669995a3acfad2c98abf8143.jpg)\n\n□ ○ □ = □ (个)", + "options": [], + "answer": "12-3=9", + "solution": "【分析】图中显示两部分苹果:左边外露的有3个,右边篮子里的数量未知。旁边的数字\"12\"表示两部分苹果的总数。求篮子里的苹果数量,用总数减去外露部分的数量.\n【详解】总数是12个,外露部分是3个,所以篮子里的苹果数量为:12 - 3 = 9(个)。列式为:12 - 3 = 9(个)。", + "knowledge_points": [ + "十几减 5~2 的退位减法", + "图文问题" + ], + "source": "20-21 一年级下·山西太原·期末" + }, + { + "id": "364", + "unit": "20以内的退位减法", + "question_type": "计算题", + "difficulty": 0.65, + "question": "看图列式计算.\n\n![](images/31b6960db9b49f489bbc9a057a68603b9e17829e8a0c0e37bfd05a357ac96d3b.jpg)\n\n□ ○ □ = □ (只)", + "options": [], + "answer": "14-5=9", + "solution": "【分析】图中显示两部分兔子:右边外露的有5只,左边蘑菇屋里的数量未知。旁边的数字\"14\"表示两部分兔子的总数。求蘑菇屋里的兔子数量,用总数减去外露部分的数量.\n【详解】总数是14只,外露部分是5只,所以蘑菇屋里的兔子数量为:14 - 5 = 9(只)。列式为:14 - 5 = 9(只)。", + "knowledge_points": [ + "十几减 5~2 的退位减法", + "图文问题" + ], + "source": "20-21 一年级下·山西太原·期末" + }, + { + "id": "365", + "unit": "20以内的退位减法", + "question_type": "计算题", + "difficulty": 0.65, + "question": "看图写算式.\n\n![](images/67419723f9de193b3dc805320254f3a3b794e7f2240700b0819c28875cd5975f.jpg)\n\n□ ○ □ = □ (支)", + "options": [], + "answer": "12-4=8", + "solution": "【分析】图中显示两部分粉笔:左边外露的有4支,右边盒子里的数量未知。旁边的数字\"12\"表示两部分粉笔的总数。求盒子里的粉笔数量,用总数减去外露部分的数量.\n【详解】总数是12支,外露部分是4支,所以盒子里的粉笔数量为:12 - 4 = 8(支)。列式为:12 - 4 = 8(支)。", + "knowledge_points": [ + "十几减 5~2 的退位减法", + "图文问题" + ], + "source": "20-21 一年级下·福建福州·期中" + }, + { + "id": "366", + "unit": "20以内的退位减法", + "question_type": "计算题", + "difficulty": 0.85, + "question": "我会看图列式.\n\n![](images/586e61ee56d1d2064b89ef194524dcfdbf91d35ccdb461e4f2cd92f3fa4a8173.jpg)\n\n□ ○ □ = □ (支)", + "options": [], + "answer": "12-6=6", + "solution": "【分析】图中显示两部分铅笔:左边外露的有6支,右边盒子里的数量未知。旁边的数字\"12\"表示两部分铅笔的总数。求盒子里的铅笔数量,用总数减去外露部分的数量.\n【详解】总数是12支,外露部分是6支,所以盒子里的铅笔数量为:12 - 6 = 6(支)。列式为:12 - 6 = 6(支)。", + "knowledge_points": [ + "图文问题", + "十几减7,6的退位减法" + ], + "source": "21-22 一年级下·全国·课后作业" + }, + { + "id": "367", + "unit": "20以内的退位减法", + "question_type": "计算题", + "difficulty": 0.65, + "question": "看图写算式.\n\n![](images/29c1ea3dd6ede98e304fff45eb5810d7e9f446d014426a34e84ce5eb598f2bbe.jpg)", + "options": [], + "answer": "15-7=8", + "solution": "【分析】通过观察图片可知,一共有15支粉笔,粉笔盒外面有7支,求粉笔盒里有多少支,根据减法的意义,用减法解答.\n【详解】15-7=8(支)。", + "knowledge_points": [ + "图文问题", + "十几减 7,6 的退位减法" + ], + "source": "20-21 一年级上·河南濮阳·期末" + }, + { + "id": "368", + "unit": "20以内的退位减法", + "question_type": "计算题", + "difficulty": 0.65, + "question": "看图列式计算.\n\n![](images/ff5a48ae6d9eda03f57272cb8803f2b0b3a092c53d8bdfd3b6295ce7c64c15f6.jpg)", + "options": [], + "answer": "15-6=9", + "solution": "【分析】图中显示两部分糖果:左边外露的有6块,右边袋子里的数量未知。旁边的数字\"15\"表示两部分糖果的总数。求袋子里的糖果数量,用总数减去外露部分的数量.\n【详解】总数是15块,外露部分是6块,所以袋子里的糖果数量为:15 - 6 = 9(块)。列式为:15 - 6 = 9(块)。", + "knowledge_points": [ + "图文问题", + "十几减7,6的退位减法" + ], + "source": "19-20 一年级下·河南南阳·期中" + }, + { + "id": "369", + "unit": "20以内的退位减法", + "question_type": "计算题", + "difficulty": 0.65, + "question": "看图列式计算.\n\n![](images/47e298ca053cd76c7afb76b40d9e87fe3ec7b8a3213d01e93de388eff07d3856.jpg)\n\n□ ○ □ = □ ( )", + "options": [], + "answer": "12-7=5", + "solution": "【分析】图中显示两部分书:右边外露的有7本,左边书包里的数量未知。旁边的数字\"12\"表示两部分书的总数。求书包里的书数量,用总数减去外露部分的数量.\n【详解】总数是12本,外露部分是7本,所以书包里的书数量为:12 - 7 = 5(本)。列式为:12 - 7 = 5(本)。", + "knowledge_points": [ + "图文问题", + "十几减 7,6 的退位减法" + ], + "source": "18-19 一年级下·甘肃天水·期中" + }, + { + "id": "370", + "unit": "20以内的退位减法", + "question_type": "计算题", + "difficulty": 0.65, + "question": "看图列式并计算.\n\n![](images/57ca815bf513862e5420312689c9560c4282acdb65b091acafc21036b44bcb17.jpg)\n\n□ ○ □ = □ (根)", + "options": [], + "answer": "15-6=9", + "solution": "【分析】图中显示两部分粉笔:左边外露的有6根,右边盒子里的数量未知。旁边的数字\"15\"表示两部分粉笔的总数。求盒子里的粉笔数量,用总数减去外露部分的数量.\n【详解】总数是15根,外露部分是6根,所以盒子里的粉笔数量为:15 - 6 = 9(根)。列式为:15 - 6 = 9(根)。", + "knowledge_points": [ + "图文问题", + "十几减 7,6 的退位减法" + ], + "source": "20-21 一年级下·甘肃兰州·期中" + }, + { + "id": "371", + "unit": "20以内的退位减法", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式并计算.\n\n![](images/23a3552a2f7bcfc2312a154766a4daa0593c90cf21ec6f49d14820bc08fd5882.jpg)\n\n□ ○ □ = □ (个)", + "options": [], + "answer": "11-3=8", + "solution": "【分析】图中显示两部分玉米:左边外露的有3个,右边篮子里的数量未知。旁边的数字\"11\"表示两部分玉米的总数。求篮子里的玉米数量,用总数减去外露部分的数量.\n【详解】总数是11个,外露部分是3个,所以篮子里的玉米数量为:11 - 3 = 8(个)。列式为:11 - 3 = 8(个)。", + "knowledge_points": [ + "十几减 5~2 的退位减法", + "图文问题" + ], + "source": "20-21 一年级下·甘肃兰州·期中" + }, + { + "id": "372", + "unit": "20以内的退位减法", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式计算.\n\n![](images/89b5da716c277d9e8e6e8f664a5d71db0e7eb637bc1c7616c77fbc05d65c2f72.jpg)\n\n□ ○ □ = □ (个)", + "options": [], + "answer": "15-8=7", + "solution": "【分析】图中显示两部分苹果:右边外露的有8个,左边篮子里的数量未知。旁边的数字\"15\"表示两部分苹果的总数。求篮子里的苹果数量,用总数减去外露部分的数量.\n【详解】总数是15个,外露部分是8个,所以篮子里的苹果数量为:15 - 8 = 7(个)。列式为:15 - 8 = 7(个)。", + "knowledge_points": [ + "十几减8的退位减法" + ], + "source": "20-21 一年级下·湖北荆门·期中" + }, + { + "id": "373", + "unit": "20以内的退位减法", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列算式.\n\n![](images/2025-12-14%20194811.jpg)\n\n□ ○ □ ○ □ = □(个)", + "options": [], + "answer": "15-3-4=8", + "solution": "【分析】图中显示苹果的总数是15个。这些苹果被分成了三部分:左边第一堆有3个,第二堆有4个,篮子里(右边)的数量未知。求篮子里的苹果数量,需要用总数依次减去两堆外露的苹果数量.\n【详解】苹果总数是15个。先减去第一堆的3个:15 - 3 = 12(个);再减去第二堆的4个:12 - 4 = 8(个)。因此,篮子里的苹果数量为8个。列式为:15 - 3 - 4 = 8(个)。", + "knowledge_points": [ + "图文问题", + "连减(20以内)" + ], + "source": "20-21 一年级下·湖北武汉·期中" + }, + { + "id": "374", + "unit": "20以内的退位减法", + "question_type": "计算题", + "difficulty": 0.85, + "question": "列算式.\n\n![](images/762099d973d4b0be8c23bd5a655744e4d3d5571d9c207e9b01fff3de52c5daa1.jpg)\n\n□ ○ □ = □(个)", + "options": [], + "answer": "11-6=5", + "solution": "【分析】图中显示两部分桃子:左边外露的有6个,右边盒子里的数量未知。旁边的数字\"11\"表示两部分桃子的总数。求盒子里的桃子数量,用总数减去外露部分的数量.\n【详解】总数是11个,外露部分是6个,所以盒子里的桃子数量为:11 - 6 = 5(个)。列式为:11 - 6 = 5(个)。", + "knowledge_points": [ + "图文问题", + "十几减 7,6 的退位减法" + ], + "source": "21-22 一年级下·山东菏泽·期中" + }, + { + "id": "375", + "unit": "20以内的退位减法", + "question_type": "计算题", + "difficulty": 0.85, + "question": "列算式.\n\n![](images/c929b4b9b788649a16865922bf9a543f65e4989743b71052ec9e10bbfd36fbe1.jpg)\n\n□ ○ □ = □ (个)", + "options": [], + "answer": "13-6=7", + "solution": "【分析】图中显示两部分苹果:左边外露的有6个,右边篮子里的数量未知。旁边的数字\"13\"表示两部分苹果的总数。求篮子里的苹果数量,用总数减去外露部分的数量.\n【详解】总数是13个,外露部分是6个,所以篮子里的苹果数量为:13 - 6 = 7(个)。列式为:13 - 6 = 7(个)。", + "knowledge_points": [ + "图文问题", + "十几减 7,6 的退位减法" + ], + "source": "20-21 一年级下·山东日照·期末" + }, + { + "id": "376", + "unit": "20以内的退位减法", + "question_type": "计算题", + "difficulty": 0.65, + "question": "看图写算式.\n\n![](images/4accd10bf411edd608023c0f0d75faf291d4374a4dddd11e5ec73d51664f80d2.jpg)\n\n□ ○ □ = □ (个)", + "options": [], + "answer": "14-5=9", + "solution": "【分析】图中显示两部分苹果:右边外露的有5个,左边盒子里的数量未知。旁边的数字\"14\"表示两部分苹果的总数。求盒子里的苹果数量,用总数减去外露部分的数量.\n【详解】总数是14个,外露部分是5个,所以盒子里的苹果数量为:14 - 5 = 9(个)。列式为:14 - 5 = 9(个)。", + "knowledge_points": [ + "十几减 5~2 的退位减法", + "图文问题" + ], + "source": "20-21 一年级下·江西南昌·期末" + }, + { + "id": "377", + "unit": "20以内的退位减法", + "question_type": "解答题", + "difficulty": 0.65, + "question": "17个苹果,每5个装一袋,可以装满几袋。", + "options": [], + "answer": "3袋", + "solution": "【分析】要知道能装满几袋,需计算 17 里面有几个 5,用 17 连减 5 可得解.\n【详解】17 - 5 - 5 - 5 = 2(个),答:可以装满 3 袋。此题考查了\"一个数里面有几个另一个数\"的实际应用,可用连减的方法来计算。", + "knowledge_points": [ + "连减 (20以内)" + ], + "source": "21-22一年级下·江西赣州·期末" + }, + { + "id": "378", + "unit": "20以内的退位减法", + "question_type": "解答题", + "difficulty": 0.65, + "question": "有 12 朵花,插在 2 个花瓶里,一个花瓶插 4 朵,另一个花瓶插多少朵。", + "options": [], + "answer": "8朵", + "solution": "【分析】这是一个已知总量和其中一部分量,求另一部分量的减法问题。花的总数是12朵,其中一个花瓶插了4朵,求另一个花瓶插的数量,用总数减去已知的部分.\n【详解】已知花的总数为12朵,一个花瓶插了4朵。另一个花瓶插的数量为:12 - 4 = 8(朵)。答:另一个花瓶插8朵。", + "knowledge_points": [ + "十几减 5~2 的退位减法" + ], + "source": "21-22 二年级下·全国·课后作业" + }, + { + "id": "379", + "unit": "20以内的退位减法", + "question_type": "解答题", + "difficulty": 0.65, + "question": "树上要挂 15 个铃铛和 11 个小星星,已经挂上了 7 个小铃铛。还要再挂多少个铃铛。", + "options": [], + "answer": "8个", + "solution": "【分析】题目只问关于铃铛的数量.\"小星星\"的数量(11个)是干扰信息。需要关注的是铃铛的总需求量和已挂数量。求还要挂的数量,用总需求量减去已挂数量.\n【详解】要挂的铃铛总数为15个,已经挂上了7个。还要再挂的铃铛数量为:15 - 7 = 8(个)。答:还要再挂8个铃铛。", + "knowledge_points": [ + "十几减 7,6 的退位减法" + ], + "source": "21-22 一年级下·全国·单元测试" + }, + { + "id": "380", + "unit": "20以内的退位减法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "有 15 个同学参加绘画组,男生有 7 个,来了 8 个同学,还有多少个同学没来。", + "options": [], + "answer": "7人", + "solution": "【分析】这是一个简单的减法应用题。已知参加绘画组的总人数和已经来的人数,求没来的人数.\"男生有7个\"是无关信息,与问题无关。用总人数减去已到人数,即可得到缺席人数.\n【详解】参加绘画组的总人数是15人,已经来了8人。没来的同学人数为:15 - 8 = 7(个)。答:还有7个同学没来。", + "knowledge_points": [ + "十几减8的退位减法" + ], + "source": "21-22一年级下·全国·单元测试" + }, + { + "id": "381", + "unit": "20以内的退位减法", + "question_type": "解答题", + "difficulty": 0.65, + "question": "一本17页的故事书已经看了8页,还剩多少页。", + "options": [], + "answer": "9页", + "solution": "【分析】根据题意,用 17 页减去已看的 8 页,就是还剩下的页数。本题关键是明确,总页数减去看的页数就是剩下的页数.\n【详解】 17 - 8 = 9 (页),答:还剩 9 页。", + "knowledge_points": [ + "十几减8的退位减法" + ], + "source": "21-22一年级上·福建宁德·期末" + }, + { + "id": "382", + "unit": "20以内的退位减法", + "question_type": "解答题", + "difficulty": 0.65, + "question": "庆\"六一\",一共要12个节目,已经准备好了9个节目。还差几个节目。", + "options": [], + "answer": "3个", + "solution": "【分析】求一个数与另一个数相差多少,用减法计算。根据题意,已知共有 12 个节目,已经准备好了 9 个节目,求还差几个节目,用节目总数减去已经准备好的数量即可.\n【详解】12 - 9 = 3(个)。答:还差 3 个节目。", + "knowledge_points": [ + "十几减9的退位减法" + ], + "source": "21-22一年级下·湖北省直辖县级单位·期中" + }, + { + "id": "383", + "unit": "20以内的退位减法", + "question_type": "解答题", + "difficulty": 0.65, + "question": "阿姨买了17米布,做衣服用了9米,还剩几米。", + "options": [], + "answer": "8米", + "solution": "【分析】这是一个简单的减法应用题。已知布的总长度和用掉的长度,求剩下的长度。用总长度减去用掉的长度即可.\n【详解】阿姨买了17米布,做衣服用了9米。剩下的布长度为:17 - 9 = 8(米)。答:还剩8米。", + "knowledge_points": [ + "十几减9的退位减法" + ], + "source": "20-21一年级下·新疆省直辖县级单位·期中" + }, + { + "id": "384", + "unit": "20以内的退位减法", + "question_type": "解答题", + "difficulty": 0.65, + "question": "书柜上原有 16 本书,拿下来 8 本,还剩多少本。\n\n□ ○ □ = □ (本)", + "options": [], + "answer": "16-8=8", + "solution": "【分析】已知书柜上原有的书本总数和拿下来的本数,求剩下的本数。用原有的本数减去拿下来的本数即可.\n【详解】书柜上原有16本书,拿下来8本后,剩下的书本数量为:16 - 8 = 8(本)。答:还剩8本。", + "knowledge_points": [ + "十几减8的退位减法" + ], + "source": "20-21 一年级下·甘肃兰州·期中" + }, + { + "id": "385", + "unit": "20以内的退位减法", + "question_type": "解答题", + "difficulty": 0.65, + "question": "李奶奶养了 13 只鸡,其中公鸡有 6 只,母鸡有多少只。\n\n□ ○ □ = □ (只)", + "options": [], + "answer": "7只", + "solution": "【分析】已知鸡的总数和其中公鸡的数量,求母鸡的数量。这是一个部分与整体关系的问题,用总数减去已知部分的量,即可得到另一部分的量.\n【详解】李奶奶一共养了13只鸡,其中公鸡有6只。母鸡的数量为:13 - 6 = 7(只)。答:母鸡有7只。", + "knowledge_points": [ + "十几减 7,6 的退位减法" + ], + "source": "20-21 一年级下·甘肃兰州·期中" + }, + { + "id": "386", + "unit": "20以内的退位减法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "一共有 14 人参加歌唱比赛,他们排成了两排。第一排有 8 人,第二排有几人。\n\n□ ○ □ = □(人)", + "options": [], + "answer": "6人", + "solution": "【分析】已知参加比赛的总人数和第一排的人数,求第二排的人数。总人数等于两排人数之和,所以用总人数减去第一排人数,即可得到第二排人数.\n【详解】参加歌唱比赛的总人数是14人,第一排有8人。第二排的人数为:14 - 8 = 6(人)。答:第二排有6人。", + "knowledge_points": [ + "十几减8的退位减法" + ], + "source": "21-22 一年级下·山东菏泽·期中" + }, + { + "id": "387", + "unit": "20以内的退位减法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "小丽买了 15 本课外书和 8 本笔记本。课外书中有 6 本故事书,其它课外书有几本。", + "options": [], + "answer": "9本", + "solution": "【分析】用买的课外书的本数减去故事书的本数,就是其它课外书的本数。据此解答。考查了整数减法的实际应用,根据题中所给的量进行计算即可.\n【详解】15 - 6 = 9 (本)。答:其它课外书有 9 本。", + "knowledge_points": [ + "十几减 7,6 的退位减法" + ], + "source": "20-21 一年级下·山东临沂·期中" + }, + { + "id": "388", + "unit": "20以内的退位减法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "小华做了14个中国结,小亮做了6个,小亮比小华少做了几个。", + "options": [], + "answer": "8个", + "solution": "【分析】用小华做的个数减去小亮做的个数,就是小亮比小华少做的个数。据此解答。考查了整数减法的实际应用,求谁比谁少做多少,用减法进行计算.\n【详解】14 - 6 = 8(个),答:小亮比小华少做了 8 个。", + "knowledge_points": [ + "谁比谁多/少几的问题" + ], + "source": "20-21一年级下·山东临沂·期中" + }, + { + "id": "389", + "unit": "20以内的退位减法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "一本18页的画册,妹妹看了9页,还有多少页没看。", + "options": [], + "answer": "9页", + "solution": "【分析】用画册的页数减去妹妹看的页数,就是还没有看的页数。据此解答。考查了整数减法的实际应用,根据题中所给的量进行计算即可.\n【详解】18 - 9 = 9(页)。答:还有 9 页没看。", + "knowledge_points": [ + "十几减9的退位减法" + ], + "source": "20-21一年级下·山东临沂·期中" + }, + { + "id": "390", + "unit": "20以内的退位减法", + "question_type": "解答题", + "difficulty": 0.65, + "question": "食堂买了15个萝卜,用掉了一些,还剩9个,食堂用掉了几个萝卜。", + "options": [], + "answer": "6个", + "solution": "【分析】这是一个已知总量和剩余量,求消耗量的减法问题。食堂买的萝卜总数是15个,剩下的萝卜是9个,用掉的萝卜数等于总数减去剩余数.\n【详解】食堂买了15个萝卜,现在还剩下9个。用掉的萝卜数量为:15 - 9 = 6(个)。答:食堂用掉了6个萝卜。", + "knowledge_points": [ + "十几减9的退位减法" + ], + "source": "20-21一年级下·黑龙江绥化·期末" + }, + { + "id": "391", + "unit": "20以内的退位减法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "李伯伯家有兔子 13 只,羊 7 只,牛 9 只.\n\n(1) 李伯伯家的羊和牛一共有多少只。 \n\n(2) 其中白兔有 5 只,黑兔有多少只。", + "options": [], + "answer": "16只;8只", + "solution": "【分析】(1)用羊的只数加上牛的只数,就是羊和牛一共有的只数;(2)用兔子的只数减去白兔的只数,就是黑兔的只数.\n【详解】(1)7+9=16(只)。答:李伯伯家的羊和牛一共有16只。(2)13-5=8(只)。答:黑兔有8只", + "knowledge_points": [ + "十几减 5~2 的退位减法", + "7,6 加几的进位加法" + ], + "source": "20-21一年级下·江西萍乡·期中" + }, + { + "id": "392", + "unit": "20以内的退位减法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "小花家有 16 只鸡和 4 只鸭,公鸡有 8 只,母鸡有多少只。", + "options": [], + "answer": "8只", + "solution": "【分析】用鸡的总只数减去公鸡的只数,就是母鸡的只数。考查了整数减法的实际应用,注意\"4只鸭\"是与本题无关的数据.\n【详解】16 - 8 = 8(只)。答:母鸡有 8 只。", + "knowledge_points": [ + "十几减8的退位减法" + ], + "source": "20-21 一年级下·江西萍乡·期中" + }, + { + "id": "393", + "unit": "20以内的退位减法", + "question_type": "解答题", + "difficulty": 0.65, + "question": "小林家有 17 只鸡和6只鸭。公鸡有9只,母鸡有几只。", + "options": [], + "answer": "8只", + "solution": "【分析】用鸡的总只数减去公鸡的只数,就是母鸡的只数。据此解答。考查了整数减法的实际应用,注意鸭的只数和本题无关.\n【详解】17 - 9 = 8(只)。答:母鸡有 8 只。", + "knowledge_points": [ + "十几减9的退位减法" + ], + "source": "20-21一年级下·江西赣州·期中" + }, + { + "id": "394", + "unit": "20以内的退位减法", + "question_type": "解答题", + "difficulty": 0.65, + "question": "小林家养了18只羊和 12 只兔。小明家养了 9 只羊,小明家比小林家少养几只羊。\n\n□ ○ □ = □ (只)", + "options": [], + "answer": "9只", + "solution": "【分析】这是一个求两个数量差的减法问题。只需要比较小林家和小明家养羊的数量,\"12只兔\"是无关信息。求小明家比小林家少养几只羊,就是求小林家的羊比小明家的多几只,用小林家的羊数减去小明家的羊数即可.\n【详解】小林家养了18只羊,小明家养了9只羊。小明家比小林家少养的羊的数量为:18 - 9 = 9(只)。答:小明家比小林家少养9只羊。", + "knowledge_points": [ + "十几减9的退位减法" + ], + "source": "20-21一年级下·吉林白城·期末" + }, + { + "id": "395", + "unit": "20以内的退位减法", + "question_type": "解答题", + "difficulty": 0.65, + "question": "在学校运动会中,我们班有12人参加跑步比赛,其中男生有7人,女生多少人。", + "options": [], + "answer": "5人", + "solution": "【分析】已知参加跑步比赛的总人数和男生人数,求女生人数。这是一个部分与整体关系的问题,用总人数减去男生人数,即可得到女生人数.\n【详解】参加跑步比赛的总人数是12人,其中男生有7人。女生人数为:12 - 7 = 5(人)。答:女生有5人。", + "knowledge_points": [ + "十几减 7,6 的退位减法" + ], + "source": "20-21一年级下·黑龙江齐齐哈尔·期末" + }, + { + "id": "396", + "unit": "20以内的退位减法", + "question_type": "解答题", + "difficulty": 0.65, + "question": "奶奶家养了 17 只羊和 9 只兔。羊比兔多几只。\n\n□ ○ □ = □ ( )", + "options": [], + "answer": "8只", + "solution": "【分析】这是一个求两个数量相差多少的问题。已知羊的数量和兔的数量,求羊比兔多几只,用羊的数量减去兔的数量即可.\n【详解】奶奶家养了17只羊和9只兔。羊比兔多的只数为:17 - 9 = 8(只)。答:羊比兔多8只。", + "knowledge_points": [ + "十几减9的退位减法" + ], + "source": "20-21 一年级下·吉林通化·期中" + }, + { + "id": "397", + "unit": "20以内的退位减法", + "question_type": "解答题", + "difficulty": 0.65, + "question": "欢欢有 20 本故事书,聪聪有 15 本故事书,笑笑有 9 本故事书。聪聪比笑笑多几本故事书。", + "options": [], + "answer": "6本", + "solution": "【分析】这是一个比较两个数量多少的问题。题目问\"聪聪比笑笑多几本\",只需要比较聪聪和笑笑的故事书数量,\"欢欢有20本\"是干扰信息,与问题无关。用聪聪的故事书本数减去笑笑的故事书本数,即可得到聪聪比笑笑多的本数.\n【详解】聪聪有15本故事书,笑笑有9本故事书。聪聪比笑笑多的本数为:15 - 9 = 6(本)。答:聪聪比笑笑多6本故事书。", + "knowledge_points": [ + "十几减9的退位减法" + ], + "source": "20-21一年级下·江西南昌·期末" + }, + { + "id": "398", + "unit": "20以内的退位减法", + "question_type": "解答题", + "difficulty": 0.65, + "question": "一本书,一共有 17 页,我看了 9 页,还有多少页没看。", + "options": [], + "answer": "8页", + "solution": "【分析】用一本书的页数减去已经看的页数,就是没有看的页数.\n【详解】17 - 9 = 8(页)。答:还有 8 页没看。", + "knowledge_points": [ + "十几减9的退位减法" + ], + "source": "20-21一年级下·内蒙古巴彦淖尔·期中" + }, + { + "id": "399", + "unit": "20以内的退位减法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "花金鱼 15 条,黑金鱼 9 条,花金鱼比黑金鱼多多少条。", + "options": [], + "answer": "6条", + "solution": "【分析】这是一个求一个数比另一个数多多少的减法问题。已知花金鱼和黑金鱼各自的数量,求花金鱼比黑金鱼多几条,用花金鱼的数量减去黑金鱼的数量即可.\n【详解】花金鱼有15条,黑金鱼有9条。花金鱼比黑金鱼多的数量为:15 - 9 = 6(条)。答:花金鱼比黑金鱼多6条。", + "knowledge_points": [ + "十几减9的退位减法" + ], + "source": "21-22 一年级下·山西晋中·期中" + }, + { + "id": "400", + "unit": "20以内的退位减法", + "question_type": "解答题", + "difficulty": 0.65, + "question": "布置教室,要挂18个灯笼,还有9个没挂,已经挂了多少个。", + "options": [], + "answer": "9个", + "solution": "【分析】用一共要挂的 18 个灯笼减去还没挂的 9 个就是已经挂了多少个。本题考查了用 20 以内的减法解决实际问题的能力.\n【详解】18 - 9 = 9(个)。答:已经挂了 9 个。", + "knowledge_points": [ + "十几减9的退位减法" + ], + "source": "19-20一年级下·四川遂宁·期中" + }, + { + "id": "401", + "unit": "20以内的退位减法", + "question_type": "选择题", + "difficulty": 0.65, + "question": "在 12 - □ < 4 这道题中, □ 里最小能填 ( )。", + "options": [ + "A. 8", + "B. 9", + "C. 11" + ], + "answer": "B", + "solution": "【分析】可以将\"小于号\"先看作等号,计算 12 - 4 = 8 , □ 里的最小数为所求结果加上1,由此即可求解。考查了数大小的比较方法的应用,解答此类题目,把小于号看作等号再解答即可.\n【详解】12 - 9 < 4,故答案为: B.", + "knowledge_points": [ + "20以内数的比大小", + "十几减9的退位减法" + ], + "source": "20-21 一年级下·广东河源·期中" + }, + { + "id": "402", + "unit": "20以内的退位减法", + "question_type": "选择题", + "difficulty": 0.65, + "question": "一班共有50个人,下课后有 20 人在玩捉迷藏,外面有 6 人,藏起来 ( ) 人。", + "options": [ + "A. 44", + "B. 24", + "C. 14" + ], + "answer": "C", + "solution": "【分析】本题需要计算藏起来的人数。已知玩捉迷藏的总人数是20人,外面有6人。藏起来的人数等于玩捉迷藏的总人数减去外面的人数.\"一班共有50个人\"是无关信息,对解题没有影响.\n【详解】玩捉迷藏的总人数为20人,外面有6人。藏起来的人数为:20 - 6 = 14(人)。因此,藏起来14人,对应选项.故答案为:C.", + "knowledge_points": [ + "十几减 7,6 的退位减法" + ], + "source": "20-21一年级下·湖南岳阳·期末" + }, + { + "id": "403", + "unit": "20以内的退位减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "水果店有7个西瓜,15个哈密瓜,哈密瓜卖掉()个后就和西瓜一样多。", + "options": [ + "A. 4", + "B. 8", + "C. 15" + ], + "answer": "B", + "solution": "【分析】要使哈密瓜的数量和西瓜一样多,也就是把哈密瓜的数量减少到7个。已知哈密瓜原有15个,西瓜有7个。需要卖掉的数量等于哈密瓜原有数量减去西瓜数量.\n【详解】哈密瓜原有15个,西瓜有7个。要使两者一样多,需要卖掉哈密瓜:15 - 7 = 8(个)。因此,哈密瓜卖掉8个后就和西瓜一样多,对应选项.故答案为:B.", + "knowledge_points": [ + "十几减 7,6 的退位减法" + ], + "source": "20-21一年级下·湖南岳阳·期末" + }, + { + "id": "404", + "unit": "20以内的退位减法", + "question_type": "选择题", + "difficulty": 0.65, + "question": " A = 14 - 6 + 2 ,B=14-(6+2), A和B比较, ( )。", + "options": [ + "A. 一样大", + "B. A 比较大", + "C. B 比较大" + ], + "answer": "B", + "solution": "【分析】分别计算 A,B 的值,比较即可。本题主要考查 100 以内数的大小比较,关键是计算出 A,B 的值.\n【详解】14 - 6 + 2 = 8+2 = 10;14- (6+2) = 14-8 = 6;10 > 6,所以,A 比较大。故答案为: B.", + "knowledge_points": [ + "10以内数的比大小", + "加减混合运算(20以内)" + ], + "source": "20-21 一年级下·湖南株洲·期末" + }, + { + "id": "405", + "unit": "20以内的退位减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": " 17 ○ 8 = 9, ○ 里应填()。", + "options": [ + "A. +", + "B. -", + "C. 无法确定" + ], + "answer": "B", + "solution": "【分析】题目要求判断圆圈中应填什么运算符号,使等式 17 ○ 8 = 9 成立。需要根据等式右边的结果 9,尝试加法和减法运算,看哪个符号能使算式成立.\n【详解】将加法和减法符号分别代入计算:如果填\"+\":17 + 8 = 25,不等于9,不符合。如果填\"-\":17 - 8 = 9,等于9,符合等式。因此,圆圈里应填\"-\"。故答案为:B", + "knowledge_points": [ + "十几减8的退位减法" + ], + "source": "20-21 一年级下·河南驻马店·期中" + }, + { + "id": "406", + "unit": "20以内的退位减法", + "question_type": "选择题", + "difficulty": 0.65, + "question": "米米和兰兰各有 10 块糖,米米给兰兰 3 块糖后,兰兰比米米多 ( ) 块糖。", + "options": [ + "A. 6", + "B. 7", + "C. 13" + ], + "answer": "A", + "solution": "【分析】已知米米和兰兰各有 10 块糖,则米米给兰兰 3 块糖后,米米就有 10 - 3 = 7 块糖,兰兰有 10 + 3 = 13 块糖,用兰兰糖的块数减去米米糖的块数即可解答。熟练掌握 20 以内加减法计算是解题的关键.\n【详解】米米有:10 - 3 = 7(块);兰兰有: 10 + 3 = 13 (块)。13 - 7 = 6 (块),兰兰比米米多6块。故答案为:A.", + "knowledge_points": [ + "10 的加减法", + "十几减 7,6 的退位减法", + "不进位加法(20 以内)" + ], + "source": "20-21 一年级下·河南鹤壁·期中" + }, + { + "id": "407", + "unit": "20以内的退位减法", + "question_type": "选择题", + "difficulty": 0.65, + "question": "16 和 8 相差 ( );14 比 7 多 ( ) 。", + "options": [ + "A. 14; 8", + "B. 16; 7", + "C. 7; 16", + "D. 8; 7" + ], + "answer": "D", + "solution": "【分析】求 16 和 8 相差多少,用16 - 8;求 14 比 7 多多少,用14 - 7 。据此解答.\n【详解】16 - 8 = 8;14 - 7 = 7,则 16 和 8 相差 8, 14 比 7 多 7。故答案为: .考查了整数减法,求谁和谁相差多少,谁比谁多多少,用减法进行计算。", + "knowledge_points": [ + "十几减8的退位减法", + "十几减7,6的退位减法" + ], + "source": "20-21 一年级下·河南三门峡·期中" + }, + { + "id": "408", + "unit": "20以内的退位减法", + "question_type": "选择题", + "difficulty": 0.65, + "question": "小丽今年8岁,小明今年9岁,小红今年16岁。根据以上信息,不能回答的问题是()。", + "options": [ + "A. 小丽比小红小多少岁。", + "B. 小明和小丽一共多少岁。", + "C. 小明比小红小多少岁。 ", + "D. 明年小红比小青大多少岁。" + ], + "answer": "D", + "solution": "【分析】判断哪个问题不能回答,需要看问题中是否包含题目未提供的信息。A,B,C三个问题都只涉及已知的三人年龄,可以计算;而D问题中出现了\"小青\",其年龄未知,无法计算.\n【详解】已知小丽8岁,小明9岁,小红16岁。A:16 - 8 = 8(岁),可答;B:9 + 8 = 17(岁),可答;C:16 - 9 = 7(岁),可答;D:小青的年龄未知,无法计算明年小红比小青大多少岁。因此不能回答的问题是.故答案为:D.", + "knowledge_points": [ + "\"提问题\"\"填条件\"问题", + "十几减8的退位减法", + "9加几的进位加法", + "十几减9的退位减法" + ], + "source": "19-20一年级下·福建龙岩·期末" + }, + { + "id": "409", + "unit": "20以内的退位减法", + "question_type": "选择题", + "difficulty": 0.65, + "question": "与15 - 7 的得数不一样的算式是 ( )。", + "options": [ + "A. 16 - 8", + "B. 5 + 3", + "C. 15 - 8", + "D. 12 - 4" + ], + "answer": "C", + "solution": "【分析】先计算出15 - 7的结果,再分别计算每个选项的结果,找出得数不同的那个.\n【详解】先计算15-7=8,再依次计算各选项:A:16-8=8;B:5+3=8;C:15-8=7;D:12-4=8,只有 C 的得数不是 8,因此答案是 C.", + "knowledge_points": [ + "十几减 5~2 的退位减法", + "十几减 8 的退位减法", + "十几减 7,6 的退位减法" + ], + "source": "19-20 一年级下·福建龙岩·期末" + }, + { + "id": "410", + "unit": "20以内的退位减法", + "question_type": "选择题", + "difficulty": 0.65, + "question": "□ -7<5, □ 里最大可以填 ( )。", + "options": [ + "A. 11", + "B. 12", + "C. 13" + ], + "answer": "A", + "solution": "【分析】将不等式转化为'□ < 某个数'的形式,然后找出比该数小的最大整数.\n【详解】由 □ - 7 < 5 可得:□ < 5 + 7,即 □ < 12。因此,□ 里最大可以填11。故答案为:A.", + "knowledge_points": [ + "十几减 7,6 的退位减法" + ], + "source": "20-21 一年级下·福建泉州·期中" + }, + { + "id": "411", + "unit": "20以内的退位减法", + "question_type": "选择题", + "difficulty": 0.65, + "question": "表姐今年 17 岁,小丽比表姐小 9 岁,小丽今年 ( ) 岁。", + "options": [ + "A. 7", + "B. 8", + "C. 9" + ], + "answer": "B", + "solution": "【分析】已知表姐的年龄和小丽比表姐小的岁数,求小丽的年龄,用表姐的年龄减去小的岁数即可.\n【详解】表姐17岁,小丽比表姐小9岁。小丽今年:17 - 9 = 8(岁)。故答案为:B.", + "knowledge_points": [ + "十几减9的退位减法" + ], + "source": "20-21 一年级下·河北张家口·期中" + }, + { + "id": "412", + "unit": "20以内的退位减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "根据下图,小丽列的算式 12 - 7 = 5 表示的是 ( ).\n\n![](images/e56e615f6738d0915036f8a13c110c4cfa1aafe00fe1ca02e5d3d0e49da12186.jpg)", + "options": [ + "A. □ 的个数", + "B. △ 的个数", + "C. □ 比 △ 多的个数" + ], + "answer": "C", + "solution": "【分析】观察图形,数出 □ 和 △ 的数量,分析算式12 - 7 = 5的含义.\n【详解】图中有12个 □,7个 △。算式12 - 7 = 5表示从 □ 的数量中减去 △ 的数量,得到的差是5,即 □ 比 △ 多5个。故答案为:C.", + "knowledge_points": [ + "十几减 7,6 的退位减法" + ], + "source": "20-21 一年级下·河南郑州·期末" + }, + { + "id": "413", + "unit": "20以内的退位减法", + "question_type": "选择题", + "difficulty": 0.65, + "question": "计算 13 - 9,与下图表示的计算过程相同的是 ( ).\n\n![](images/e138f5e23e9f942a62c4666c5845b6a25d99f5a6c033d9cdedebc701d6b553b1.jpg)", + "options": [ + "A. 4 + 9 = 13, 13 - 9 = 4", + "B. 13 - 3 = 10, 10-6 = 4", + "C. 10 - 9 = 1, 1 + 3 = 4" + ], + "answer": "C", + "solution": "【分析】图中展示的是\"破十法\":把13分成10和3,先用10减9得1,再把1和3相加得4.\n【详解】观察图示,计算13 - 9时,先把13分成10和3,先算10 - 9 = 1,再算1 + 3 = 4。这与选项C的过程一致。故答案为:C.", + "knowledge_points": [ + "十几减9的退位减法" + ], + "source": "20-21 一年级下·河南郑州·期末" + }, + { + "id": "414", + "unit": "20以内的退位减法", + "question_type": "选择题", + "difficulty": 0.65, + "question": "差是 6 的算式是()。", + "options": [ + "A. 13 - 8", + "B. 3 + 3", + "C. 15 - 9" + ], + "answer": "C", + "solution": "【分析】逐一计算每个算式,找出结果为6的减法算式.\n【详解】A. 13 - 8 = 5;B. 3 + 3 = 6(这是加法,求的是和,不是差);C. 15 - 9 = 6。因此,差是6的算式是15 - 9。故答案为:C.", + "knowledge_points": [ + "十几减8的退位减法", + "6的加减法", + "十几减7,6的退位减法" + ], + "source": "20-21 一年级下·湖北黄冈·期末" + }, + { + "id": "415", + "unit": "20以内的退位减法", + "question_type": "选择题", + "difficulty": 0.65, + "question": "有 12 根香蕉,每只小猴子分 3 根,可以分给()只小猴子。", + "options": [ + "A. 3", + "B. 4", + "C. 5" + ], + "answer": "B", + "solution": "【分析】求12里面有几个3,可以用连续减去3的方法,直到减完为止.\n【详解】12 - 3 = 9,9 - 3 = 6,6 - 3 = 3,3 - 3 = 0。共减了4次,所以可以分给4只小猴子。故答案为:B.", + "knowledge_points": [ + "连减 (20以内)" + ], + "source": "18-19一年级下·湖北襄阳·期末" + }, + { + "id": "416", + "unit": "20以内的退位减法", + "question_type": "选择题", + "difficulty": 0.65, + "question": "小白兔采了 16 个萝卜,小灰兔采的比小白兔采的少了 7 个,小灰兔采了()个。", + "options": [ + "A. 8", + "B. 7", + "C. 9" + ], + "answer": "C", + "solution": "【分析】已知小白兔采的数量,以及小灰兔比小白兔少采的数量,求小灰兔采的数量,用小白兔的数量减去少的数量.\n【详解】小白兔采了16个萝卜,小灰兔比小白兔少采7个。小灰兔采了:16 - 7 = 9(个)。故答案为:C.", + "knowledge_points": [ + "十几减 7,6 的退位减法" + ], + "source": "18-19一年级下·河南商丘·期末" + }, + { + "id": "417", + "unit": "20以内的退位减法", + "question_type": "选择题", + "difficulty": 0.65, + "question": "11个巧克力分给一年级小朋友,每人分5个,最多可以分给()个小朋友。", + "options": [ + "A. 2", + "B. 3", + "C. 4" + ], + "answer": "A", + "solution": "【分析】求11里面最多有几个5,可以用连续减去5的方法,看能减几次.\n【详解】11 - 5 = 6,6 - 5 = 1。减了2次后还剩下1个,不够再分给一个小朋友。因此,最多可以分给2个小朋友。故答案为:A.", + "knowledge_points": [ + "连减 (20 以内)" + ], + "source": "19-20一年级下·湖南怀化·单元测试" + }, + { + "id": "418", + "unit": "20以内的退位减法", + "question_type": "选择题", + "difficulty": 0.65, + "question": "党的十九届六中全会于2021年11月8日到11月11日在北京召开,大会共开了()天。", + "options": [ + "A. 3", + "B. 4", + "C. 5" + ], + "answer": "B", + "solution": "【分析】计算会议持续的天数,应包括开始和结束日期。天数 = 结束日 - 开始日 + 1.\n【详解】开始是11月8日,结束是11月11日。会议共开了:11 - 8 + 1 = 3 + 1 = 4(天)。故答案为:B.", + "knowledge_points": [ + "加减混合运算(20以内)" + ], + "source": "21-22 一年级上·吉林·期末" + }, + { + "id": "419", + "unit": "20以内的退位减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "小红做了 15 只千纸鹤,小青做了 8 只千纸鹤,小青还要做()只千纸鹤就和小红同样多。", + "options": [ + "A. 7", + "B. 8", + "C. 15", + "D. 23" + ], + "answer": "A", + "solution": "【分析】已知小红和小青各自做的数量,求小青还要做多少只才能和小红一样多,就是求小红比小青多做了多少只.\n【详解】小红做了15只,小青做了8只。小红比小青多:15 - 8 = 7(只)。因此,小青还要做7只才能和小红同样多。故答案为:A.", + "knowledge_points": [ + "十几减8的退位减法" + ], + "source": "2021一年级下·全国·专题练习" + }, + { + "id": "420", + "unit": "20以内的退位减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "红金鱼和花金鱼一共有 15 条,花金鱼有几条。 ( )", + "options": [ + "A. 其中 8 条是红金鱼", + "B. 游走了 8 条花金鱼", + "C. 其中 8 条是花金鱼" + ], + "answer": "A", + "solution": "【分析】已知总数(15条)和其中一种鱼的数量,可以求出另一种鱼的数量。需要选择一个能提供其中一种鱼数量的条件.\n【详解】已知红金鱼和花金鱼共15条。要算花金鱼有几条,需要知道红金鱼的数量。选项A提供了红金鱼有8条,那么花金鱼有:15 - 8 = 7(条)。选项B和C都无法直接求出花金鱼的数量。故答案为:A.", + "knowledge_points": [ + "十几减8的退位减法" + ], + "source": "2021一年级下·全国·专题练习" + }, + { + "id": "421", + "unit": "20以内的退位减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "学校要买17个篮球,9个足球,已经买了8个篮球,还要买多少个篮球。()", + "options": [ + "A. 7", + "B. 8", + "C. 9", + "D. 10" + ], + "answer": "C", + "solution": "【分析】问题只与篮球有关,足球数量是干扰信息。用需要买的篮球总数减去已经买的篮球数,就是要再买的篮球数.\n【详解】需要买17个篮球,已经买了8个。还要买:17 - 8 = 9(个)篮球。故答案为:C.", + "knowledge_points": [ + "十几减8的退位减法" + ], + "source": "2021一年级下·全国·专题练习" + }, + { + "id": "422", + "unit": "20以内的退位减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "军军和明明跳绳,军军跳了15下,明明跳了8下,明明至少再跳多少下,才能超过军军。()", + "options": [ + "A. 7", + "B. 8", + "C. 9" + ], + "answer": "B", + "solution": "【分析】先求明明比军军少跳多少下,要超过军军,至少要比军军多跳1下.\n【详解】军军跳了15下,明明跳了8下。明明比军军少跳:15 - 8 = 7(下)。要超过军军,至少需要再跳:7 + 1 = 8(下)。故答案为:B.", + "knowledge_points": [ + "十几减8的退位减法" + ], + "source": "2021一年级下·全国·专题练习" + }, + { + "id": "423", + "unit": "20以内的退位减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": " 13 - 9 =()。", + "options": [ + "A. 2", + "B. 4", + "C. 7", + "D. 18" + ], + "answer": "B", + "solution": "【分析】计算13 - 9,可以用\"破十法\":把13分成10和3,先算10减9,再加3.\n【详解】13 - 9,把13分成10和3,10 - 9 = 1,1 + 3 = 4。故答案为:B.", + "knowledge_points": [ + "十几减9的退位减法" + ], + "source": "2021 一年级下·全国·专题练习" + }, + { + "id": "424", + "unit": "20以内的退位减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": " 11 - 9 = ( )。", + "options": [ + "A. 2", + "B. 4", + "C. 5" + ], + "answer": "A", + "solution": "【分析】计算11 - 9,可以用\"破十法\":把11分成10和1,先算10减9,再加1.\n【详解】11 - 9,把11分成10和1,10 - 9 = 1,1 + 1 = 2。故答案为:A.", + "knowledge_points": [ + "十几减9的退位减法" + ], + "source": "2021 一年级下·全国·专题练习" + }, + { + "id": "425", + "unit": "20以内的退位减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "小红做了11朵花,小明做了9朵花,小明至少还要做多少朵才能超过小红()。", + "options": [ + "A. 2", + "B. 3", + "C. 4" + ], + "answer": "B", + "solution": "【分析】先求小明比小红少做多少朵,要超过小红,至少要比小红多做1朵.\n【详解】小红做了11朵,小明做了9朵。小明比小红少做:11 - 9 = 2(朵)。要超过小红,至少需要再做:2 + 1 = 3(朵)。故答案为:B.", + "knowledge_points": [ + "十几减9的退位减法" + ], + "source": "2021一年级下·全国·专题练习" + }, + { + "id": "426", + "unit": "20以内的退位减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "我今年 6 岁,姐姐 15 岁,姐姐比我大几岁。()。", + "options": [ + "A. 6", + "B. 7", + "C. 8", + "D. 9" + ], + "answer": "D", + "solution": "【分析】求一个数比另一个数多几,用减法计算.\n【详解】姐姐15岁,我6岁。姐姐比我大:15 - 6 = 9(岁)。故答案为:D.", + "knowledge_points": [ + "十几减 7,6 的退位减法" + ], + "source": "2021一年级下·全国·专题练习" + }, + { + "id": "427", + "unit": "20以内的退位减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "小丽做了14朵花,小明做了6朵。小明至少还要做()朵,才能超过小丽。", + "options": [ + "A. 8朵", + "B. 9朵", + "C. 10朵" + ], + "answer": "B", + "solution": "【分析】先求小明比小丽少做多少朵,要超过小丽,至少要比小丽多做1朵.\n【详解】小丽做了14朵,小明做了6朵。小明比小丽少做:14-6=8(朵)。要超过小丽,至少需要再做:8+1=9(朵)。故答案为:B.", + "knowledge_points": [ + "十几减 7,6 的退位减法" + ], + "source": "2021一年级下·全国·专题练习" + }, + { + "id": "428", + "unit": "20以内的退位减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": " 6 + □ = 14 ( )。", + "options": [ + "A. 5", + "B. 8", + "C. 7" + ], + "answer": "B", + "solution": "【分析】已知一个加数与和,求另一个加数,用和减去已知的加数.\n【详解】已知和是14,一个加数是6。另一个加数为:14 - 6 = 8。故答案为:B.", + "knowledge_points": [ + "十几减 7,6 的退位减法" + ], + "source": "2021 一年级下·全国·专题练习" + }, + { + "id": "429", + "unit": "20以内的退位减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "一一带了12颗草莓,他分给博士7颗草莓后,一一自己还剩下几颗草莓呢。()颗.\n\n![](images/d9c072b128c941647ce3393f49d6a3330578bf219a60870d2844dbc2623d8180.jpg)", + "options": [ + "A. 4", + "B. 7", + "C. 5", + "D. 9" + ], + "answer": "C", + "solution": "【分析】已知原有草莓数量和分出的数量,求剩余数量,用原有数量减去分出的数量.\n【详解】一一原有12颗草莓,分给博士7颗后,还剩下:12-7=5(颗)。故答案为:C.", + "knowledge_points": [ + "十几减 7,6 的退位减法" + ], + "source": "2021一年级下·全国·专题练习" + }, + { + "id": "430", + "unit": "20以内的退位减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "明明有16元钱,买文具用去7元,还剩下()元。", + "options": [ + "A. 7", + "B. 8", + "C. 9" + ], + "answer": "C", + "solution": "【分析】已知总钱数和花掉的钱数,求剩下的钱数,用总钱数减去花掉的钱数.\n【详解】明明有16元,用去7元,还剩下:16 - 7 = 9(元)。故答案为:C.", + "knowledge_points": [ + "十几减 7,6 的退位减法" + ], + "source": "2021一年级下·全国·专题练习" + }, + { + "id": "431", + "unit": "20以内的退位减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "体育课上, 15 个小朋友排成一队,力力排在第 7,他后面有 ( ) 人。", + "options": [ + "A. 9", + "B. 8", + "C. 7" + ], + "answer": "B", + "solution": "【分析】排队的总人数包括力力前面的人,力力自己和力力后面的人。已知总人数和力力排第7(即他前面有6人),求他后面的人数,用总人数减去包括力力在内的前7人.\n【详解】总共有15人。力力排第7,说明他前面有6人,他自己是第7个。因此,从第1位到第7位共有7人。力力后面的人数为:15 - 7 = 8(人)。故答案为:B.", + "knowledge_points": [ + "十几减 7,6 的退位减法" + ], + "source": "19-20 一年级下·全国·期末" + }, + { + "id": "432", + "unit": "20以内的退位减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "下面哪个算式的得数与其他两个算式的得数不相同()。", + "options": [ + "A. 13-8", + "B. 11-6", + "C. 18-9" + ], + "answer": "C", + "solution": "【分析】分别计算出每个算式的得数,然后比较.\n【详解】A. 13-8=5;B. 11-6=5;C. 18-9=9。因此,得数与其他两个不同的是18-9。故答案为:C.", + "knowledge_points": [ + "十几减8的退位减法", + "十几减9的退位减法", + "十几减7,6的退位减法" + ], + "source": "2021一年级下·全国·专题练习" + }, + { + "id": "433", + "unit": "20以内的退位减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "今天我要编16个花篮,还要编7个,已经编了几个。算式()。", + "options": [ + "A. 16 - 7 = 8", + "B. 16 - 9 = 7", + "C. 16 - 7 = 9", + "D. 7 + 9 = 16" + ], + "answer": "C", + "solution": "【分析】已知要编的总数和还要编的数量,求已经编的数量,用总数减去还要编的数量.\n【详解】要编16个花篮,还要编7个。已经编了:16 - 7 = 9(个)。对应的算式是16 - 7 = 9。故答案为:C.", + "knowledge_points": [ + "十几减 7,6 的退位减法" + ], + "source": "2021一年级下·全国·专题练习" + }, + { + "id": "434", + "unit": "20以内的退位减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "与 13 - 6 的结果相同的算式是 ( )。", + "options": [ + "A. 12 - 6", + "B. 15 - 9", + "C. 14 - 7" + ], + "answer": "C", + "solution": "【分析】先计算出13 - 6的结果,再分别计算每个选项的结果,找出得数相同的.\n【详解】13 - 6 = 7。计算各选项:A. 12 - 6 = 6;B. 15 - 9 = 6;C. 14 - 7 = 7。因此,与13 - 6结果相同的是14 - 7。故答案为:C.", + "knowledge_points": [ + "十几减9的退位减法", + "十几减7,6的退位减法" + ], + "source": "17-18 一年级下·全国·期中" + }, + { + "id": "435", + "unit": "20以内的退位减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "小朋友们踢毽子,小文踢了5下,小军踢了7下,小丽踢了12下,小文再踢()下就和小丽一样多。", + "options": [ + "A. 5", + "B. 7", + "C. 6" + ], + "answer": "B", + "solution": "【分析】求小文再踢多少下就和小丽一样多,就是求小丽比小文多踢了多少下.\n【详解】小丽踢了12下,小文踢了5下。小丽比小文多踢:12 - 5 = 7(下)。因此,小文再踢7下就和小丽一样多。故答案为:B.", + "knowledge_points": [ + "十几减 5~2 的退位减法" + ], + "source": "2021一年级下·全国·专题练习" + }, + { + "id": "436", + "unit": "20以内的退位减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "下图中, 11 - 2 表示( ).\n\n![](images/3044a8b8c185d0cd7c29101f6645eeb6ea239461a89647e8652d0bdcdf893052.jpg)", + "options": [ + "A. △ 比 ○ 多的个数", + "B. △ 比 ○ 少的个数", + "C. ○ 的个数" + ], + "answer": "C", + "solution": "【分析】观察图形,数出 △ 和 ○ 的数量,分析算式11 - 2的含义.\n【详解】图中有11个 △,○ 比 △ 少2个。那么 ○ 的数量为:11 - 2 = 9(个)。因此,11 - 2表示的是 ○ 的个数。故答案为:C.", + "knowledge_points": [ + "十几减 5~2 的退位减法" + ], + "source": "2021一年级下·全国·专题练习" + }, + { + "id": "437", + "unit": "20以内的退位减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "铅笔盒里原来有 12支铅笔,丽丽拿出 5 支,还剩()支。", + "options": [ + "A. 6", + "B. 7", + "C. 5" + ], + "answer": "B", + "solution": "【分析】已知原有铅笔数量和拿出的数量,求剩余数量,用原有数量减去拿出的数量.\n【详解】原有12支铅笔,拿出5支,还剩下:12 - 5 = 7(支)。故答案为:B.", + "knowledge_points": [ + "十几减 5~2 的退位减法" + ], + "source": "2021一年级下·全国·专题练习" + }, + { + "id": "438", + "unit": "20以内的退位减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "从14里面去掉5个1是()。", + "options": [ + "A. 10", + "B. 9", + "C. 8" + ], + "answer": "B", + "solution": "【分析】'5个1'就是5,从14里面去掉5,用减法计算.\n【详解】14 - 5 = 9。因此,从14里面去掉5个1是9。故答案为:B.", + "knowledge_points": [ + "十几减 5~2 的退位减法" + ], + "source": "2021一年级下·全国·专题练习" + }, + { + "id": "439", + "unit": "20以内的退位减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "13 比 4 多 ( )。", + "options": [ + "A. 9", + "B. 11", + "C. 17" + ], + "answer": "A", + "solution": "【分析】求一个数比另一个数多多少,用减法计算.\n【详解】13比4多:13 - 4 = 9。故答案为:A.", + "knowledge_points": [ + "十几减 5~2 的退位减法" + ], + "source": "2021一年级下·全国·专题练习" + }, + { + "id": "440", + "unit": "20以内的退位减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "妈妈买了 12 个苹果,哥哥吃掉了 3 个,还剩下几个呢。 请你选一选吧。()\n\n![](images/e128ff2bf4d157b5f141422954e49d195459286d0f6722e036851f3ec8592b11.jpg)", + "options": [ + "A. 12", + "B. 3", + "C. 7", + "D. 9" + ], + "answer": "D", + "solution": "【分析】已知苹果总数和吃掉的数量,求剩余数量,用总数减去吃掉的数量.\n【详解】妈妈买了12个苹果,哥哥吃掉3个,还剩下:12 - 3 = 9(个)。故答案为:D.", + "knowledge_points": [ + "十几减 5~2 的退位减法" + ], + "source": "2021一年级下·全国·专题练习" + }, + { + "id": "441", + "unit": "20以内的退位减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "( )加上4等于12。", + "options": [ + "A. 8", + "B. 9", + "C. 16" + ], + "answer": "A", + "solution": "【分析】已知一个加数和和,求另一个加数,用和减去已知的加数.\n【详解】因为 8 + 4 = 12,所以8加上4等于12。或者用减法:12 - 4 = 8。故答案为:A.", + "knowledge_points": [ + "十几减 5~2 的退位减法" + ], + "source": "2021一年级下·全国·专题练习" + }, + { + "id": "442", + "unit": "20以内的退位减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "下列哪一道算式正确的是()。", + "options": [ + "A. 12 - 7 = 6", + "B. 14 - 5 = 8", + "C. 13 - 4 = 9", + "D. 15 - 9 = 7" + ], + "answer": "C", + "solution": "【分析】逐一计算每个算式,找出计算正确的.\n【详解】A. 12-7=5,错误;B. 14-5=9,错误;C. 13-4=9,正确;D. 15-9=6,错误。因此,正确的算式是13-4=9。故答案为:C.", + "knowledge_points": [ + "十几减 5~2 的退位减法", + "十几减 9 的退位减法", + "十几减 7,6 的退位减法" + ], + "source": "2021一年级下·全国·专题练习" + }, + { + "id": "443", + "unit": "20以内的退位减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "下列()算式的结果和其他的不同。", + "options": [ + "A. 7 + 2", + "B. 4 + 4", + "C. 11 - 2", + "D. 3 + 6" + ], + "answer": "B", + "solution": "【分析】分别计算出每个算式的结果,然后找出与其他三个不同的.\n【详解】A. 7+2=9;B. 4+4=8;C. 11-2=9;D. 3+6=9。因此,结果与其他三个不同的是4+4=8。故答案为:B.", + "knowledge_points": [ + "十几减 5~2 的退位减法", + "8,9 的加减法" + ], + "source": "2021一年级下·全国·专题练习" + }, + { + "id": "444", + "unit": "20以内的退位减法", + "question_type": "选择题", + "difficulty": 0.65, + "question": "小明看一本故事书,从第7页看到了第12页,小明看了()页。", + "options": [ + "A. 5", + "B. 6", + "C. 7" + ], + "answer": "B", + "solution": "【分析】计算从第A页看到第B页所看的页数,应包括起始页和结束页。公式:看的页数 = 结束页 - 起始页 + 1.\n【详解】从第7页看到第12页。小明看的页数为:12 - 7 + 1 = 5 + 1 = 6(页)。故答案为:B.", + "knowledge_points": [ + "加减混合运算(20以内)" + ], + "source": "2021一年级下·全国·专题练习" + }, + { + "id": "445", + "unit": "20以内的退位减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "与 12 - (4 + 5) 得数相等的算式是 ( )。", + "options": [ + "A. 12 - 4 + 5", + "B. 12 - 4 - 5", + "C. 12 + 4 - 5" + ], + "answer": "B", + "solution": "【分析】根据题意分析可知,在连减算式中可以改写成第一个数减去后面两个数的和,由此解答.\n【详解】由分析可知:与 12 - (4 + 5) 得数相等的算式是:12 - 4 - 5。故答案为: B.", + "knowledge_points": [ + "带有小括号的混合运算" + ], + "source": "2021 一年级下·全国·专题练习" + }, + { + "id": "446", + "unit": "20以内的退位减法", + "question_type": "选择题", + "difficulty": 0.65, + "question": "以下哪一项算式是不正确的。()", + "options": [ + "A. (9 + 4) - 11 = 9 + 4 - 11", + "B. 11 + (9 - 4) = 11 + 9 - 4", + "C. 15 - (8 + 6) = 15 - 8 + 6", + "D. (8 - 6) + 15 = 8 - 6 + 15" + ], + "answer": "C", + "solution": "【分析】本题考查的是四则运算中的去括号问题。括号前是'+'号,去括号后里面不变号;括号前是'-'号,去括号后里面算式变号.\n【详解】A. (9+4)-11=9+4-11,故A正确;B. 11+(9-4)=11+9-4,故B正确;C. 15-(8+6)=15-8+6,故C错误;D. (8-6)+15=8-6+15,故D正确。故答案为:C.", + "knowledge_points": [ + "带有小括号的混合运算" + ], + "source": "2021一年级下·全国·专题练习" + }, + { + "id": "447", + "unit": "20以内的退位减法", + "question_type": "选择题", + "difficulty": 0.65, + "question": "算式 13 - (6 + 3) 应该先算 ( )。", + "options": [ + "A. 13 - 6", + "B. 6 + 3", + "C. 13 + 3" + ], + "answer": "B", + "solution": "【分析】13 - (6 + 3) 这个算式里,应先算小括号里的加法,再算括号外的减法,由此计算出结果.\n【详解】13 - (6 + 3) = 13 - 9 = 4。故答案为: B.", + "knowledge_points": [ + "加减混合运算(20以内)" + ], + "source": "2021 一年级下·全国·专题练习" + }, + { + "id": "448", + "unit": "20以内的退位减法", + "question_type": "选择题", + "difficulty": 0.65, + "question": "小丽要折 15 只千纸鹤,先折了 3 只,再折了 5 只,还要折几只千纸鹤。下面列式不正确的是()。", + "options": [ + "A. 15 - 3 - 5", + "B. 15 - (3 + 5)", + "C. 15 - 3 + 5" + ], + "answer": "C", + "solution": "【分析】根据减法的意义,用要折的千纸鹤总数分别减去先折的3只与后来折的5只,即得还要折几只千纸鹤;也可先根据加法的意义求出一共折了多少只,然后用减法求出还要折几只千纸鹤.\n【详解】15 - 3 - 5 = 7(只),15 - (3 + 5) = 7(只),所以列式不正确的是:15 - 3 + 5。故答案为: C.", + "knowledge_points": [ + "连减(20以内)", + "加减混合运算(20以内)" + ], + "source": "2021一年级下·全国·专题练习" + }, + { + "id": "449", + "unit": "20以内的退位减法", + "question_type": "选择题", + "difficulty": 0.65, + "question": "原来小青比小红多 12 张卡片,现在小青给小红 3 张后,小青比小红还多()张。", + "options": [ + "A. 9", + "B. 3", + "C. 6" + ], + "answer": "C", + "solution": "【分析】这是一个关于数量变化的问题。原来小青比小红多12张。当小青给小红3张后,小青的卡片减少3张,同时小红的卡片增加3张,这样一来一回,两人之间的差距会减少两个3张.\n【详解】原来小青比小红多12张。小青给小红3张后,小青少了3张,小红多了3张,两人的差距减少了:3 + 3 = 6(张)。因此,小青比小红还多:12 - 6 = 6(张)。故答案为:C.", + "knowledge_points": [ + "连减 (20 以内)" + ], + "source": "2021一年级上·全国·专题练习" + }, + { + "id": "450", + "unit": "20以内的退位减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "盒子里有 12 支铅笔,如果 4 支 4 支地拿, ( ) 次可以拿完。", + "options": [ + "A. 3", + "B. 4", + "C. 5" + ], + "answer": "A", + "solution": "【分析】求12支铅笔每次拿4支,几次可以拿完,就是求12里面有几个4。可以用连续减去4的方法,看能减几次,直到减完为止.\n【详解】从12支铅笔中拿铅笔:第一次拿4支,剩下 12 - 4 = 8(支);第二次拿4支,剩下 8 - 4 = 4(支);第三次拿4支,剩下 4 - 4 = 0(支)。一共拿了3次。因此,3次可以拿完,对应选项.故答案为:A.", + "knowledge_points": [ + "连减 (20 以内)" + ], + "source": "20-21 一年级上·湖北十堰·期末" + }, + { + "id": "451", + "unit": "20以内的退位减法", + "question_type": "选择题", + "difficulty": 0.85, + "question": "根据'二班比一班少3面红旗'这一信息,下面说法正确的是()。", + "options": [ + "A. 二班红旗数减3面红旗等于一班红旗数", + "B. 二班红旗数减一班红旗数等于3面", + "C. 二班红旗数加3面红旗等于一班红旗数", + "D. 二班红旗数加一班红旗数等于3面" + ], + "answer": "C", + "solution": "【分析】可把'二班比一班少3面红旗'这一条件尽可能转化,保持本意但叙述方式发生变化,并逐项分析,确定答案.\n【详解】A. 二班红旗数 - 3 = 一班红旗数,与条件不符;B. 一班红旗数 - 二班红旗数 = 3(面),虽数值对但方向不同;C. 二班红旗数 + 3 = 一班红旗数,和原意相符;D. 二班红旗数与一班红旗数之和,题目里未提及。故答案为:C.", + "knowledge_points": [ + "谁比谁多/少几的问题" + ], + "source": "19-20二年级上·福建厦门·期中" + }, + { + "id": "452", + "unit": "20以内的退位减法", + "question_type": "填空题", + "difficulty": 0.65, + "question": "计算 13 - 5 时,可以这样想: 5 + ( ) = 13 , 13 - 5 =( ) 。", + "options": [], + "answer": "8;8", + "solution": "【分析】计算 13 - 5 时,可以运用想加算减的方法,想5加几等于13,那么13减去5就等于几。本题考查了运用'想加算减'计算退位减法的方法.\n【详解】计算 13 - 5 时,可以这样想:5 + 8 = 13,13 - 5 = 8。所以填:8;8。", + "knowledge_points": [ + "十几减 5~2 的退位减法" + ], + "source": "20-21 一年级下·河南三门峡·期中" + }, + { + "id": "453", + "unit": "20以内的退位减法", + "question_type": "填空题", + "difficulty": 0.65, + "question": "男生比女生多 7 人,也就是说女生比男生少( )人;最少需要( )个同样的小正方形可以拼成一个大正方形。", + "options": [], + "answer": "7;4", + "solution": "【分析】男生比女生多7人,即男女生的人数差是7人,反过来说就是女生比男生少7人;要用小正方形拼成一个大正方形,则每个边长上至少需要2个小正方形,据此需要 2×2 = 4 个小正方形.\n【详解】男生比女生多7人,也就是说女生比男生少7人;最少需要4个同样的小正方形可以拼成一个大正方形。", + "knowledge_points": [ + "平面图形的拼接", + "长方形,正方形,三角形和圆的初步认识", + "谁比谁多/少几的问题" + ], + "source": "20-21 一年级下·河南南阳·期中" + }, + { + "id": "454", + "unit": "20以内的退位减法", + "question_type": "填空题", + "difficulty": 0.65, + "question": "奇奇有13张卡片,奇妙有9张,奇奇要给奇妙( )张,两人的卡片就同样多。", + "options": [], + "answer": "2", + "solution": "【分析】要使两人卡片同样多,需要将奇奇比奇妙多的卡片数平均分给两人。先求出奇奇比奇妙多多少张,然后将多出的张数平分.\n【详解】奇奇有13张,奇妙有9张。奇奇比奇妙多:13 - 9 = 4(张)。将这4张卡片平均分,每人应得 4÷2 = 2(张)。因此,奇奇给奇妙2张后,两人各有11张,卡片数量相同。故答案为:2。", + "knowledge_points": [ + "十几减9的退位减法" + ], + "source": "20-21一年级下·福建莆田·期末" + }, + { + "id": "455", + "unit": "20以内的退位减法", + "question_type": "填空题", + "difficulty": 0.4, + "question": "笑笑在计算一道减法算式时,不小心把被减数 16 看成 18,算出得数是 9,原来正确的得数是( )。", + "options": [], + "answer": "7", + "solution": "【分析】由于被减数看错,导致计算结果错误。可以根据错误的被减数和错误的差,先求出正确的减数,再用正确的被减数减去这个减数,得到正确的差.\n【详解】错误的被减数是18,错误的差是9。根据'减数 = 被减数 - 差',可得减数为:18 - 9 = 9。正确的被减数是16,减数仍然是9。因此,正确的差为:16 - 9 = 7。故答案为:7。", + "knowledge_points": [ + "错中求解问题(加减法)", + "十几减9的退位减法" + ], + "source": "20-21一年级下·福建泉州·期中" + }, + { + "id": "456", + "unit": "20以内的退位减法", + "question_type": "填空题", + "difficulty": 0.94, + "question": "4 月 8 日再过 5 天是 4 月( )日;5 月 9 日再过( )天是 5 月 14 日。", + "options": [], + "answer": "13;5", + "solution": "【分析】第一问:计算从某一天开始,经过若干天后的日期,用起始日期加上经过的天数。第二问:计算两个日期之间相差的天数,用较晚的日期减去较早的日期.\n【详解】第一问:4月8日再过5天,日期为:8 + 5 = 13,即4月13日。第二问:5月14日减去5月9日,相差:14 - 9 = 5(天)。因此答案为:13;5。", + "knowledge_points": [ + "十几减9的退位减法", + "8加几的进位加法" + ], + "source": "20-21一年级下·福建泉州·期中" + }, + { + "id": "457", + "unit": "20以内的退位减法", + "question_type": "填空题", + "difficulty": 0.65, + "question": "16 个小朋友排成一行做操,从左数起,小芳排在第 9 位,从右数起,她排在第 ( )位。", + "options": [], + "answer": "8", + "solution": "【分析】已知总人数和小芳从左数的位置,可以先求出小芳右边有多少人。从右数小芳的位置等于她右边的人数加1(包括她自己).\n【详解】总共有16人。小芳从左数排第9,说明她左边有8人,她自己排在第9个。那么她右边的人数为:16 - 9 = 7(人)。从右数起,小芳排在第 7 + 1 = 8(位)。故答案为:8。", + "knowledge_points": [ + "加减混合运算(20以内)" + ], + "source": "19-20 一年级下·安徽淮北·期末" + }, + { + "id": "458", + "unit": "20以内的退位减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "计算 12 - 4 = ( )时,可以先算 ( ) - 4 = ( ) , 再算 ( ) + 2 = ( ) 。", + "options": [], + "answer": "8;10;6;6;8", + "solution": "【分析】本题考查'破十法'的计算过程。计算12 - 4时,将12拆分为10和2,先用10减去4,得到的结果再加上剩下的2.\n【详解】计算12 - 4:先把12分成10和2。先算 10 - 4 = 6,再算 6 + 2 = 8。因此,12 - 4 = 8。填空依次为:8;10;6;6;8。", + "knowledge_points": [ + "十几减 5~2 的退位减法" + ], + "source": "20-21 一年级下·河北唐山·期中" + }, + { + "id": "459", + "unit": "20以内的退位减法", + "question_type": "填空题", + "difficulty": 0.65, + "question": "5 枝花扎一束, 16 枝花最多可以扎( )束。", + "options": [], + "answer": "3", + "solution": "【分析】求16枝花每5枝一束最多可以扎几束,就是求16里面最多有几个5。可以用连续减去5的方法,直到剩下的花不够扎一束为止.\n【详解】16 - 5 = 11(第1束);11 - 5 = 6(第2束);6 - 5 = 1(第3束,剩下1枝不够扎一束)。所以,最多可以扎3束。故答案为:3。", + "knowledge_points": [ + "连减 (20以内)" + ], + "source": "19-20 一年级下·湖南怀化·单元测试" + }, + { + "id": "460", + "unit": "20以内的退位减法", + "question_type": "填空题", + "difficulty": 0.65, + "question": "一共有 15 串珠子,小红拿了 9 串,还剩( )串。", + "options": [], + "answer": "6", + "solution": "【分析】已知珠子总串数和拿走的串数,求剩余的串数,用总串数减去拿走的串数.\n【详解】共有15串珠子,小红拿了9串。还剩:15 - 9 = 6(串)。故答案为:6。", + "knowledge_points": [ + "十几减9的退位减法" + ], + "source": "20-21 一年级下·广西玉林·期末" + }, + { + "id": "461", + "unit": "20以内的退位减法", + "question_type": "填空题", + "difficulty": 0.65, + "question": "小明有 15 元钱,花 9 元钱买一本科普书,还剩( )元。", + "options": [], + "answer": "6", + "solution": "【分析】已知总钱数和花掉的钱数,求剩下的钱数,用总钱数减去花掉的钱数.\n【详解】小明有15元,花掉9元。还剩:15 - 9 = 6(元)。故答案为:6。", + "knowledge_points": [ + "十几减9的退位减法" + ], + "source": "20-21 一年级下·广西玉林·期中" + }, + { + "id": "462", + "unit": "20以内的退位减法", + "question_type": "填空题", + "difficulty": 0.65, + "question": "有 17 个小朋友排队做操,从左边数起,小芳排在第 9 位,从右边数起,她排在第( )位。", + "options": [], + "answer": "9", + "solution": "【分析】已知总人数和小芳从左数的位置,可以先求出小芳右边的人数。从右数小芳的位置等于她右边的人数加1.\n【详解】总共有17人。小芳从左数排第9,说明她左边有8人,她自己排在第9个。那么她右边的人数为:17 - 9 = 8(人)。从右边数起,小芳排在第 8 + 1 = 9(位)。故答案为:9。", + "knowledge_points": [ + "20以内数的排序", + "十几减9的退位减法" + ], + "source": "20-21 一年级下·四川巴中·期末" + }, + { + "id": "463", + "unit": "20以内的退位减法", + "question_type": "填空题", + "difficulty": 0.65, + "question": "计算 12 - 7,可以用破十法,先算 10 - 7 = ( ), 再算( )。也可以想加算减,想: 7 + () = 12, 12 - 7 = () 。", + "options": [], + "answer": "3;3 + 2 = 5;5;5", + "solution": "【分析】计算 12 - 7,把 12 分成 10 加 2,先计算 10 - 7 = 3,再计算 3 + 2 = 5;也可以想几加7等于12,则12减7就等于几.\n【详解】计算12 - 7,可以用破十法,先算 10 - 7 = 3,再算 3 + 2 = 5;也可以想加算减,想:7 + 5 = 12,12 - 7 = 5。所以答案为:3;3 + 2 = 5;5;5。", + "knowledge_points": [ + "十几减 7,6 的退位减法" + ], + "source": "20-21 一年级下·四川绵阳·期末" + }, + { + "id": "464", + "unit": "20以内的退位减法", + "question_type": "填空题", + "difficulty": 0.65, + "question": "同学们排成一队,小宇排第7,小艺排第11,小宇和小艺之间有( )人。", + "options": [], + "answer": "3", + "solution": "【分析】求两人之间有多少人,'之间'不包括两人本身。可以先计算两人的位置差,再减去1.\n【详解】小艺排第11,小宇排第7。两人的位置差为:11 - 7 = 4。这4包括了小艺本人和小宇之间的所有人,因此他们之间的人数为:4 - 1 = 3(人)。故答案为:3。", + "knowledge_points": [ + "连减 (20以内)" + ], + "source": "20-21一年级上·广东汕头·期末" + }, + { + "id": "465", + "unit": "20以内的退位减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "一个加数是 7,另一个加数是 5,和是( );被减数是 12,减数是 5,差是( )。", + "options": [], + "answer": "12;7", + "solution": "【分析】本题考查加法与减法的基本概念。加法:和 = 加数 + 加数。减法:差 = 被减数 - 减数.\n【详解】加法:7 + 5 = 12,所以和是12。减法:12 - 5 = 7,所以差是7。故答案为:12;7。", + "knowledge_points": [ + "十几减 5~2 的退位减法", + "10 的加减法", + "不退位减法 (20 以内)" + ], + "source": "19-20 一年级上·四川乐山·期末" + }, + { + "id": "466", + "unit": "20以内的退位减法", + "question_type": "填空题", + "difficulty": 0.65, + "question": "有 15 个人排一条路队回家,小东的前面有 8 人,小东的后面有( )人。", + "options": [], + "answer": "6", + "solution": "【分析】排队总人数包括小东前面的人,小东自己和小东后面的人。已知总人数和小东前面的人数,求后面的人数,用总人数减去前面人数再减去小东自己.\n【详解】总共有15人。小东前面有8人,那么包括小东在内的前面部分有 8 + 1 = 9(人)。小东后面的人数为:15 - 9 = 6(人)。故答案为:6。", + "knowledge_points": [ + "前,后位置", + "连减(20以内)" + ], + "source": "21-22 一年级上·甘肃金昌·期末" + }, + { + "id": "467", + "unit": "20以内的退位减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "15 比 7 多( );10比( )少3。", + "options": [], + "answer": "8;13", + "solution": "【分析】第一问:求一个数比另一个数多多少,用减法。第二问:已知一个数比另一个数少几,求另一个数,用加法.\n【详解】第一问:15比7多:15 - 7 = 8。第二问:10比一个数少3,说明这个数比10多3,所以这个数是:10 + 3 = 13。故答案为:8;13。", + "knowledge_points": [ + "十几减 7,6 的退位减法", + "不进位加法(20以内)" + ], + "source": "21-22 一年级上·广东揭阳·期末" + }, + { + "id": "468", + "unit": "20以内的退位减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "在 15 - 6 = 9 这个算式中,被减数是( )。", + "options": [], + "answer": "15", + "solution": "【分析】本题考查减法算式中各部分的名称。在减法算式'被减数 - 减数 = 差'中,减号前面的数是被减数.\n【详解】在算式 15 - 6 = 9 中,15 是被减数,6 是减数,9 是差。故答案为:15。", + "knowledge_points": [ + "十几减 7,6 的退位减法" + ], + "source": "21-22 一年级上·吉林·期末" + }, + { + "id": "469", + "unit": "20以内的退位减法", + "question_type": "填空题", + "difficulty": 0.65, + "question": "小朋友排队去参观动物园。小丽排第8,小明排第16,小丽和小明之间有()人。", + "options": [], + "answer": "7", + "solution": "【分析】求两人之间有多少人,'之间'不包括两人本身。可以先计算两人的位置差,再减去1.\n【详解】小明排第16,小丽排第8。两人的位置差为:16 - 8 = 8。这8包括了小明本人和小丽之间的所有人,因此他们之间的人数为:8 - 1 = 7(人)。故答案为:7。", + "knowledge_points": [ + "连减 (20以内)" + ], + "source": "20-21一年级上·湖南怀化·单元测试" + }, + { + "id": "470", + "unit": "20以内的退位减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "小芳在队伍中排在第9位,小红排在第13位,她们中间有( )人。", + "options": [], + "answer": "3", + "solution": "【分析】求两人之间有多少人,\"之间\"不包括两人本身。可以先计算两人的位置差,再减去1(减去小红本人).\n【详解】小红排第13,小芳排第9。两人的位置差为:13 - 9 = 4。这4包括了小红本人和小芳之间的所有人,因此她们之间的人数为:4 - 1 = 3(人)。故答案为:3。", + "knowledge_points": [ + "连减 (20以内)" + ], + "source": "20-21一年级上·湖南怀化·单元测试" + }, + { + "id": "471", + "unit": "20以内的退位减法", + "question_type": "填空题", + "difficulty": 0.65, + "question": "小明今年9岁,再过( )年,他就13岁了。", + "options": [], + "answer": "4", + "solution": "【分析】已知小明现在的年龄和目标年龄,求经过的年数,用目标年龄减去现在年龄.\n【详解】小明今年9岁,目标年龄是13岁。需要经过的年数为:13 - 9 = 4(年)。故答案为:4。", + "knowledge_points": [ + "十几减9的退位减法" + ], + "source": "21-22一年级上·全国·单元测试" + }, + { + "id": "472", + "unit": "20以内的退位减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "被减数是 15,减数是 5,差是( )。", + "options": [], + "answer": "10", + "solution": "【分析】根据减法公式\"差 = 被减数 - 减数\",直接计算.\n【详解】被减数是15,减数是5,差为:15 - 5 = 10。故答案为:10。", + "knowledge_points": [ + "不退位减法 (20以内)" + ], + "source": "21-22 一年级上·全国·单元测试" + }, + { + "id": "473", + "unit": "20以内的退位减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "在括号里填上合适的数.\n7 + ( ) = 10;( ) + 4 = 12;11 + ( ) = 13", + "options": [], + "answer": "3;8;2", + "solution": "【分析】这三题都是根据加法算式求未知加数,利用\"和 - 一个加数 = 另一个加数\"进行计算.\n【详解】第一空:10 - 7 = 3,所以填3。第二空:12 - 4 = 8,所以填8。第三空:13 - 11 = 2,所以填2。因此,答案为:3;8;2。", + "knowledge_points": [ + "十几减 5~2 的退位减法", + "10 的加减法", + "不退位减法 (20 以内)" + ], + "source": "21-22 一年级上·全国·期末" + }, + { + "id": "474", + "unit": "20以内的退位减法", + "question_type": "填空题", + "difficulty": 0.65, + "question": "黄花有 13 朵,红花比黄花少 7 朵,红花有( )朵。", + "options": [], + "answer": "6", + "solution": "【分析】已知黄花数量和红花比黄花少的数量,求红花的数量,用黄花的数量减去少的数量.\n【详解】黄花有13朵,红花比黄花少7朵。红花有:13 - 7 = 6(朵)。故答案为:6。", + "knowledge_points": [ + "十几减 7,6 的退位减法" + ], + "source": "20-21 二年级上·云南昆明·期中" + }, + { + "id": "475", + "unit": "20以内的退位减法", + "question_type": "填空题", + "difficulty": 0.4, + "question": "放学排队,从前面数,小方排第5个,从后面数,小方排第7个,这行队一共有( )人。", + "options": [], + "answer": "11", + "solution": "【分析】这是一个排队计数问题。从前面数和从后面数都包括小方自己,因此他会被数两次。总人数等于前后两次数的序数之和减去1(减去重复计算的小方).\n【详解】从前面数小方排第5,从后面数他排第7。总人数为:5 + 7 - 1 = 11(人)。故答案为:11。", + "knowledge_points": [ + "连加 (20 以内)" + ], + "source": "19-20二年级上·甘肃天水·期中" + }, + { + "id": "476", + "unit": "20以内的退位减法", + "question_type": "填空题", + "difficulty": 0.85, + "question": "减数是 8,被减数是 16,差是( )。", + "options": [], + "answer": "8", + "solution": "【分析】根据\"被减数 - 减数 = 差\",代入数值进行计算即可。本题主要考查了整数减法,明确整数减法的各部分之间的关系是解答本题的关键.\n【详解】16 - 8 = 8,所以,减数是8,被减数是16,差是8。", + "knowledge_points": [ + "十几减8的退位减法" + ], + "source": "20-21 一年级下·贵州铜仁·期末" + }, + { + "id": "477", + "unit": "20以内的退位减法", + "question_type": "判断题", + "difficulty": 0.65, + "question": "15-6 与 17-8的得数一样。( )", + "options": [], + "answer": "√", + "solution": "【分析】分别计算出 15 - 6 与 17 - 8 的得数,再进行比较即可.\n【详解】15 - 6 = 9,17 - 8 = 9,9 = 9,15-6 与 17-8 的得数一样,原题说法正确。故答案为:√。", + "knowledge_points": [ + "十几减 8 的退位减法", + "十几减 7,6 的退位减法" + ], + "source": "20-21一年级下·河南开封·期中" + }, + { + "id": "478", + "unit": "20以内的退位减法", + "question_type": "判断题", + "difficulty": 0.65, + "question": "13 与 9 的差是4。( )", + "options": [], + "answer": "√", + "solution": "【分析】计算两个数的差,用较大的数减去较小的数。判断13与9的差是否为4,计算13减9即可.\n【详解】13 - 9 = 4。因此,13与9的差是4,说法正确。故答案为:√。", + "knowledge_points": [ + "十几减9的退位减法" + ], + "source": "20-21 一年级下·河北张家口·期中" + }, + { + "id": "479", + "unit": "20以内的退位减法", + "question_type": "计算题", + "difficulty": 0.65, + "question": "列算式.\n\n![](images/c6b7270187d5a98200a8f75311ed2285988eb74ff37805529f61e52aa6d9ff88.jpg)\n\n□ ○ □ = □(个)", + "options": [], + "answer": "14-8=6", + "solution": "【分析】图中显示两部分苹果:左边外露的有8个,右边篮子里的数量未知。旁边的数字\"14\"表示两部分苹果的总数。求篮子里的苹果数量,用总数减去外露部分的数量.\n【详解】苹果总数是14个,左边有8个。篮子里的苹果数量为:14 - 8 = 6(个)。列式为:14 - 8 = 6(个)。", + "knowledge_points": [ + "十几减8的退位减法", + "图文问题" + ], + "source": "20-21 一年级下·湖南衡阳·期中" + }, + { + "id": "480", + "unit": "20以内的退位减法", + "question_type": "计算题", + "difficulty": 0.65, + "question": "看图列式计算.\n\n![](images/138e2c1e2c2c63c35c2c7261bc69c955bd3d7f0a00b68e8cb66f09498e4c39e1.jpg)\n\n□ ○ □ = □ (个)", + "options": [], + "answer": "15-7=8", + "solution": "【分析】图中显示两部分苹果:左边外露的有7个,右边篮子里的数量未知。旁边的数字\"15\"表示两部分苹果的总数。求篮子里的苹果数量,用总数减去外露部分的数量.\n【详解】苹果总数是15个,左边有7个。篮子里的苹果数量为:15 - 7 = 8(个)。列式为:15 - 7 = 8(个)。", + "knowledge_points": [ + "图文问题", + "十几减 7,6 的退位减法" + ], + "source": "20-21 一年级下·河南驻马店·期中" + }, + { + "id": "481", + "unit": "20以内的退位减法", + "question_type": "计算题", + "difficulty": 0.65, + "question": "看图列算式.\n\n![](images/28a6fd57094e844379ef8b6efbf797c3026602c90c177fbbca9cc07c27870fe8.jpg)\n\n□ ○ □ = □ (只)", + "options": [], + "answer": "15-6=9", + "solution": "【分析】图中显示两部分鸟:左边外露的有6只,右边房子里的数量未知。旁边的数字\"15\"表示两部分鸟的总数。求房子里的鸟的数量,用总数减去外露部分的数量.\n【详解】鸟的总数是15只,左边有6只。房子里的鸟的数量为:15 - 6 = 9(只)。列式为:15 - 6 = 9(只)。", + "knowledge_points": [ + "实际问题(十几减 9~6 的退位减法)", + "十几减7,6 的退位减法" + ], + "source": "20-21 一年级下·河北沧州·期中" + }, + { + "id": "482", + "unit": "20以内的退位减法", + "question_type": "计算题", + "difficulty": 0.65, + "question": "我会看图列式计算.\n\n![](images/c893b672a1886e2071d829bac814684a8005592c2f982c95060481baf1a11fa0.jpg)\n\n□ ○ □ = □ ( )", + "options": [], + "answer": "11-5=6", + "solution": "【分析】图中显示两部分鸟:右边外露的有5只,左边房子里的数量未知。旁边的数字\"11\"表示两部分鸟的总数。求房子里的鸟的数量,用总数减去外露部分的数量.\n【详解】鸟的总数是11只,右边有5只。房子里的鸟的数量为:11 - 5 = 6(只)。列式为:11 - 5 = 6(只)。", + "knowledge_points": [ + "十几减 5~2 的退位减法", + "图文问题" + ], + "source": "19-20 一年级下·湖南怀化·单元测试" + }, + { + "id": "483", + "unit": "20以内的退位减法", + "question_type": "计算题", + "difficulty": 0.65, + "question": "我会看图列式计算.\n\n![](images/98c7723f6ac34db3081e3c2f57fc38548eba269076af625cf80a0df9e40732a4.jpg)", + "options": [], + "answer": "12-4=8", + "solution": "【分析】图中显示两部分苹果:左边外露的有4个,右边篮子里的数量未知。旁边的数字\"12\"表示两部分苹果的总数。求篮子里的苹果数量,用总数减去外露部分的数量.\n【详解】苹果总数是12个,左边有4个。篮子里的苹果数量为:12 - 4 = 8(个)。列式为:12 - 4 = 8(个)。", + "knowledge_points": [ + "十几减 5~2 的退位减法", + "图文问题" + ], + "source": "19-20 一年级下·湖南怀化·单元测试" + }, + { + "id": "484", + "unit": "20以内的退位减法", + "question_type": "计算题", + "difficulty": 0.85, + "question": "列算式.\n\n![](images/8aee4e7bf9b671b86424e85700fe173eb409b3b1dde693491fac9547d8dcb0a6.jpg)\n\n□ ○ □ = □ (本)", + "options": [], + "answer": "11-4=7", + "solution": "【分析】根据题干可知:总共有11本书,右边有4本,书包里面的本数等于总数减去右边的本数.\n【详解】11 - 4 = 7(本),所以书包里有7本。列式为:11 - 4 = 7(本)。", + "knowledge_points": [ + "十几减 5~2 的退位减法", + "图文问题" + ], + "source": "20-21 一年级下·广东广州·期末" + }, + { + "id": "485", + "unit": "20以内的退位减法", + "question_type": "解答题", + "difficulty": 0.65, + "question": "小红去文具店买了3支铅笔用了6元钱,买2张贴纸用了8元,她付给收银员20元钱,应找回多少钱。", + "options": [], + "answer": "6元", + "solution": "【分析】根据题意,要求应找回多少钱,用付给收银员的钱数减去买铅笔和买贴纸花的钱数即可。这是整数连减的应用.\n【详解】共花钱:6 + 8 = 14(元)。应找回的钱数为:20 - 6 - 8 = 14 - 8 = 6(元)。答:应找回6元钱。", + "knowledge_points": [ + "连减 (20以内)" + ], + "source": "20-21二年级下·广东河源·期中" + }, + { + "id": "486", + "unit": "20以内的退位减法", + "question_type": "解答题", + "difficulty": 0.65, + "question": "金鱼缸里有 15 条红金鱼, 6 条花金鱼,红金鱼比花金鱼多几条。", + "options": [], + "answer": "9条", + "solution": "【分析】根据题意,用红金鱼的数量减去花金鱼的数量就是\"红金鱼比花金鱼多\"的条数.\n【详解】15 - 6 = 9(条),答:红金鱼比花金鱼多9条。", + "knowledge_points": [ + "实际问题(十几减 9~6 的退位减法)" + ], + "source": "20-21 一年级下·湖南永州·期末" + }, + { + "id": "487", + "unit": "20以内的退位减法", + "question_type": "解答题", + "difficulty": 0.65, + "question": "商店运来13箱苹果和8箱梨,卖出7箱苹果后,还剩多少箱苹果。", + "options": [], + "answer": "6箱", + "solution": "【分析】用运来的苹果箱数减去卖出的箱数,求剩余箱数即可;8箱梨是多余条件.\n【详解】苹果剩下:13 - 7 = 6(箱)。答:还剩6箱苹果。", + "knowledge_points": [ + "十几减 7,6 的退位减法" + ], + "source": "20-21一年级下·湖南株洲·期末" + }, + { + "id": "488", + "unit": "20以内的退位减法", + "question_type": "解答题", + "difficulty": 0.85, + "question": "有15个小朋友要在一起做游戏,现在来了8个小朋友,其中有6个是女孩,还有几个小朋友没有来。", + "options": [], + "answer": "7个", + "solution": "【分析】用要玩游戏的小朋友个数减去已经来了的小朋友个数,就是没有来的小朋友个数.\"其中有6个是女孩\"是无关信息.\n【详解】没有来的小朋友有:15 - 8 = 7(个)。答:还有7个小朋友没有来。", + "knowledge_points": [ + "实际问题(十几减 9~6 的退位减法)" + ], + "source": "19-20一年级下·河南漯河·期中" + }, + { + "id": "489", + "unit": "20以内的退位减法", + "question_type": "解答题", + "difficulty": 0.65, + "question": "讲台上有 18 本课外书, 15 本作业本,同学们借走 9 本书,还剩几本书。", + "options": [], + "answer": "9本", + "solution": "【分析】题目隐含的是借走的是课外书,用课外书本数减去借走的本数,求剩余本数.\n【详解】课外书还剩:18 - 9 = 9(本)。答:还剩9本书。", + "knowledge_points": [ + "十几减9的退位减法" + ], + "source": "20-21 一年级下·河南三门峡·期中" + }, + { + "id": "490", + "unit": "20以内的退位减法", + "question_type": "解答题", + "difficulty": 0.65, + "question": "两个小组一共植树 15 棵,第一小组植树7棵,第二小组植树多少棵。\n\n![](images/2025-12-15%20134324.jpg)", + "options": [], + "answer": "8棵", + "solution": "【分析】两个小组一共植树15棵,第一小组植树7棵,第二小组植树棵数等于总数减去第一小组的棵数.\n【详解】第二小组植树:15 - 7 = 8(棵)。答:第二小组植树8棵。", + "knowledge_points": [ + "十几减 7,6 的退位减法" + ], + "source": "20-21一年级下·河南郑州·期中" + }, + { + "id": "491", + "unit": "20以内的退位减法", + "question_type": "解答题", + "difficulty": 0.65, + "question": "奶奶家养了 17 只羊和 9 只兔。羊比兔多几只。", + "options": [], + "answer": "8只", + "solution": "【分析】用奶奶养的羊的只数减去兔子的只数即可求解.\n【详解】17 - 9 = 8(只)。答:羊比兔多8只。", + "knowledge_points": [ + "谁比谁多/少几的问题", + "十几减9的退位减法" + ], + "source": "20-21一年级下·河南郑州·期中" + }, + { + "id": "492", + "unit": "20以内的退位减法", + "question_type": "解答题", + "difficulty": 0.65, + "question": "超市原来有15桶油,上午运来5桶,下午卖出7桶,超市现在有多少桶油。", + "options": [], + "answer": "13桶", + "solution": "【分析】用原有的桶数加上运来的桶数,再减去卖出的桶数,即可得到现在的桶数.\n【详解】现有桶数:15 + 5 - 7 = 20 - 7 = 13(桶)。答:超市现在有13桶油。", + "knowledge_points": [ + "十几减 7,6 的退位减法", + "加减混合运算 (20 以内)" + ], + "source": "20-21一年级下·河南安阳·期末" + }, + { + "id": "493", + "unit": "20以内的退位减法", + "question_type": "解答题", + "difficulty": 0.65, + "question": "两个小组一共有13人,一组有7人,另一组有多少人。", + "options": [], + "answer": "6人", + "solution": "【分析】用两个小组一共有的人数减去一组的人数,就是另一组的人数.\n【详解】另一组人数:13 - 7 = 6(人)。答:另一组有6人。", + "knowledge_points": [ + "十几减 7,6 的退位减法" + ], + "source": "20-21一年级下·河南新乡·期中" + }, + { + "id": "494", + "unit": "20以内的退位减法", + "question_type": "解答题", + "difficulty": 0.65, + "question": "一(3)班原来有15个皮球和3个足球,被一(5)班借走了8个皮球,还剩多少个皮球。", + "options": [], + "answer": "7个", + "solution": "【分析】原来有15个皮球,被借走8个皮球,剩余个数等于原有个数减去借走的个数,与足球个数无关.\n【详解】剩下皮球个数:15 - 8 = 7(个)。答:还剩7个皮球。", + "knowledge_points": [ + "十几减8的退位减法" + ], + "source": "19-20一年级下·浙江台州·期末" + }, + { + "id": "495", + "unit": "20以内的退位减法", + "question_type": "解答题", + "difficulty": 0.65, + "question": "小朋友排队,小林所在的一队小朋友共有16人,其中小林前面有9人,他后面有多少人。", + "options": [], + "answer": "6人", + "solution": "【分析】总人数包括小林前面的人,小林自己和小林后面的人。已知总人数和前面的人数,求后面人数,用总人数减去前面人数再减去小林自己.\n【详解】包括小林在内的前面部分有 9 + 1 = 10(人),后面人数为:16 - 10 = 6(人),也可列式:16 - 9 - 1 = 6(人)。答:他后面有6人。", + "knowledge_points": [ + "连减 (20以内)" + ], + "source": "20-21一年级下·河南商丘·期中" + }, + { + "id": "496", + "unit": "20以内的退位减法", + "question_type": "解答题", + "difficulty": 0.65, + "question": "池塘里有15条鱼,游走了8条鱼,又来了4条鱼,现在有几条鱼。", + "options": [], + "answer": "11条", + "solution": "【分析】这是一个两步计算的加减混合问题。池塘里鱼的数量先减少(游走),后增加(又来),先算减法再算加法.\n【详解】先游走8条,剩下:15 - 8 = 7(条);又来了4条,现在有:7 + 4 = 11(条)。综合算式为:15 - 8 + 4 = 11(条)。答:现在有11条鱼。", + "knowledge_points": [ + "加减混合运算(20以内)" + ], + "source": "20-21一年级上·西藏林芝·期末" + }, + { + "id": "497", + "unit": "20以内的退位减法", + "question_type": "解答题", + "difficulty": 0.65, + "question": "哥哥给弟弟4块糖果后,哥哥与弟弟的糖果数就一样多了,原来哥哥比弟弟多几块糖果。", + "options": [], + "answer": "8块", + "solution": "【分析】哥哥给弟弟4块后两人一样多,说明原来哥哥比弟弟多的块数等于给出的两倍。可以设想\"后来都有x块糖\",再反推原来各有多少.\n【详解】假设后来都有10块糖,那么:哥哥原来有10 + 4 = 14(块),弟弟原来有10 - 4 = 6(块),原来哥哥比弟弟多:14 - 6 = 8(块)。一般规律:甲给乙若干后相等,则原来甲比乙多的数量是给出数量的2倍。答:原来哥哥比弟弟多8块糖果。", + "knowledge_points": [ + "\"一样多\"问题", + "十几减7,6的退位减法", + "不进位加法(20以内)" + ], + "source": "20-21一年级上·河南许昌·期末" + }, + { + "id": "498", + "unit": "20以内的退位减法", + "question_type": "解答题", + "difficulty": 0.65, + "question": "三种颜色的球一共有 13 个,红气球有 5 个,蓝气球有 2 个,黄气球有多少个。", + "options": [], + "answer": "6个", + "solution": "【分析】已知三种颜色气球的总数和其中两种颜色的数量,求第三种颜色的数量,用总数依次减去红气球和蓝气球的数量即可.\n【详解】黄气球数量为:13 - 5 - 2 = 6(个)。列式:13 - 5 - 2 = 6。答:黄气球有6个。", + "knowledge_points": [ + "连减 (20以内)" + ], + "source": "21-22一年级上·北京房山·期末" + }, + { + "id": "499", + "unit": "20以内的退位减法", + "question_type": "解答题", + "difficulty": 0.65, + "question": "图书角原有科技书13本,又买来2本,后来借出7本,还剩多少本。", + "options": [], + "answer": "8本", + "solution": "【分析】先加后减的两步计算问题。先算买来后的总本数,再减去借出的本数.\n【详解】买来后共有:13 + 2 = 15(本),借出7本后还剩:15 - 7 = 8(本)。综合算式为:13 + 2 - 7 = 8(本)。答:还剩8本。", + "knowledge_points": [ + "加减混合运算(20以内)" + ], + "source": "21-22一年级上·辽宁·单元测试" + }, + { + "id": "500", + "unit": "20以内的退位减法", + "question_type": "解答题", + "difficulty": 0.65, + "question": "丽丽原来有 15 支铅笔,借给玲玲3支,妈妈又给她买来5支,丽丽现在有多少支铅笔。", + "options": [], + "answer": "17支", + "solution": "【分析】用原来有的铅笔支数减去借出去的支数,再加上妈妈买给她的支数,就是现在有的支数。借出去用减法,又买来用加法.\n【详解】先减去借出的:15 - 3 = 12(支),再加上买来的:12 + 5 = 17(支)。综合算式为:15 - 3 + 5 = 17(支)。答:丽丽现在有17支铅笔。", + "knowledge_points": [ + "加减混合运算 (20 以内)" + ], + "source": "20-21一年级上·山东东营·期末" + } +] \ No newline at end of file diff --git "a/\344\270\200\345\271\264\347\272\247\351\242\230\351\233\206/\344\270\200\345\271\264\347\272\247\344\270\213/\344\270\200\345\271\264\347\272\247\344\270\213\347\254\254\344\272\224\345\215\225\345\205\203\350\256\244\350\257\206\344\272\272\346\260\221\345\270\201.json" "b/\344\270\200\345\271\264\347\272\247\351\242\230\351\233\206/\344\270\200\345\271\264\347\272\247\344\270\213/\344\270\200\345\271\264\347\272\247\344\270\213\347\254\254\344\272\224\345\215\225\345\205\203\350\256\244\350\257\206\344\272\272\346\260\221\345\270\201.json" new file mode 100644 index 0000000000000000000000000000000000000000..9c2a22450d199a45ec62665871d90bd7ff55f5a2 --- /dev/null +++ "b/\344\270\200\345\271\264\347\272\247\351\242\230\351\233\206/\344\270\200\345\271\264\347\272\247\344\270\213/\344\270\200\345\271\264\347\272\247\344\270\213\347\254\254\344\272\224\345\215\225\345\205\203\350\256\244\350\257\206\344\272\272\346\260\221\345\270\201.json" @@ -0,0 +1,8522 @@ +[ + { + "id": "1", + "unit": "第五单元认识人民币", + "question_type": "选择题", + "difficulty": 0.85, + "question": "小丁一共有 ( ) 钱.\n![](images/201952.png)", + "options": [ + "A. 19元", + "B. 17元4角", + "C. 18元6角" + ], + "answer": "C", + "solution": "【分析】根据题意,将所有人民币的面值相加,就是总面值。计算时,元和元相加,角和角相加,根据 1 元 = 10 角换算单位即可.\n【详解】10元+5元+1元+1元=17元 5角+5角+5角+1角=16角=1元6角;17元+1元6角=18元6角;小丁一共有 18 元 6 角。故答案为: C", + "knowledge_points": [ + "元,角,分的认识及换算", + "十元以下人民币的认识与计算", + "十元以上人民币的认识与计算" + ], + "source": "23-24 二年级上·广东韶关·期末" + }, + { + "id": "2", + "unit": "第五单元认识人民币", + "question_type": "选择题", + "difficulty": 0.85, + "question": "一顶帽子 8 元 4 角,下面()种付钱方法是错误的。", + "options": [ + "A. 8 张 1 元, 4 张 1 角", + "B. 4 张 1 元, 8 张 1 角", + "C. 1 张 5 元, 3 张 1 元, 4 张 1 角" + ], + "answer": "B", + "solution": "【分析】据题意,一顶帽子花了 8 元 4 角,人民币之间的换算是 1 元 = 10 角,根据选项中给出的答案计算出每个的总钱数,再对照是不是帽子的金额即可得出答案.\n【详解】A。8张1元 = 8 元,4张1角 = 4 角,所以是8元4角,符合题意;B. 4 张 1 元 = 4 元, 8 张 1 角 = 8 角,所以是 4 元 8 角,不符合题意;C. 3 张 1 元 = 3 元, 3 元 + 5 元 = 8 元, 4 张 1 角 = 4 角,所以是 8 元 4 角,符合题意。故答案为: B", + "knowledge_points": [ + "元,角,分的认识及换算", + "十元以下人民币的认识与计算" + ], + "source": "24-25 二年级上·广东梅州·期中" + }, + { + "id": "3", + "unit": "第五单元认识人民币", + "question_type": "选择题", + "difficulty": 0.65, + "question": "一张 20 元可以换成()张 5 元。", + "options": [ + "A. 5", + "B. 3", + "C. 4" + ], + "answer": "C", + "solution": "【分析】几个5相加得20就可以换几个5元,据此计算.\n【详解】 5 + 5 + 5 + 5 = 20 (元);一张20元可以换成4张5元。故答案为: C", + "knowledge_points": [ + "连加(20以内)", + "十元以上人民币的认识与计算" + ], + "source": "23-24 二年级上·广东韶关·期中" + }, + { + "id": "4", + "unit": "第五单元认识人民币", + "question_type": "选择题", + "difficulty": 0.85, + "question": "淘气有 4 元 3 角钱,买了 1 本书用去 2 元,还剩 ( )。", + "options": [ + "A. 2元1角", + "B. 2元3角", + "C. 3角" + ], + "answer": "B", + "solution": "【分析】根据题意可知:求还剩下多少钱。用淘气有的钱减去买书用的钱即可.\n【详解】4元3角-2元=2元3角,则还剩2元3角。故答案为: B", + "knowledge_points": [ + "十元以下人民币的认识与计算" + ], + "source": "23-24 二年级上·广东韶关·期中" + }, + { + "id": "5", + "unit": "第五单元认识人民币", + "question_type": "选择题", + "difficulty": 0.85, + "question": "婷婷要买一个 11 元的笔记本,下面付款方法不对的是 ( )。", + "options": [ + "A. ![](images/29024cbbe787fbae8fe2b52601ec03abb02e2040c1cf508790fadc9353b118f3.jpg)", + "B. ![](images/a4dcd2840080a601fa9bd31d746b15269b354b417cf11dadf6ced6695918a795.jpg)", + "C. ![](images/1c590732670b04d599ef8c10c4c28587c6c6b6c4147a64019166b3930327a8ff.jpg)" + ], + "answer": "C", + "solution": "【分析】根据题意,将每张人民币的面值相加,找出结果不是 11 元的就是付款方法不对的。元和元相加,角和角相加.\n【详解】A。5元+5元+1元=11元,付款方法正确;B. 10元+1元=11元,付款方法正确;C. 5元 +1 元 +5 角 = 6 元 5 角,付款方法不正确;![](images/7e5c2abb0c02922eb80cf4a7dc6736718de8200a23a469978daf2330d98d7036.jpg)\n所以付款方法不对的是c,故答案为: C", + "knowledge_points": [ + "十元以下人民币的认识与计算", + "十元以上人民币的认识与计算" + ], + "source": "23-24 二年级上·河南驻马店·期中" + }, + { + "id": "6", + "unit": "第五单元认识人民币", + "question_type": "选择题", + "difficulty": 0.65, + "question": "一支笔 2 元,一个练习本 4 元 5 角,李亮有 5 元钱,想买一支笔和一个练习本,还差 ( )。", + "options": [ + "A. 5角", + "B. 1元5角", + "C. 1元" + ], + "answer": "B", + "solution": "【分析】先算出买一支笔和一个练习本的钱,然后减去 5 元即可.\n【详解】2元+4元5角=6元5角;6元5角-5元=1元5角;还差 1 元 5 角。故答案为: B", + "knowledge_points": [ + "十元以下人民币的认识与计算" + ], + "source": "23-24 二年级上·广东佛山·期中" + }, + { + "id": "7", + "unit": "第五单元认识人民币", + "question_type": "选择题", + "difficulty": 0.65, + "question": "一瓶可乐的价格是()。", + "options": [ + "A. 30 分", + "B. 30角", + "C. 30 元" + ], + "answer": "B", + "solution": "【分析】根据 1 角 = 10 分, 1 元 = 10 角,计量较贵的物品常用元作单位;计量较便宜的物品常用角作单位,可乐是较贵的物品,应该用 \"元\" 作单位.\n【详解】A。30分=3角,3角太小了,不符合题意;B. 30角 = 3 元, 3 元符合一瓶可乐的价钱;C. 30 元太大了,不符合题意。故答案为: B", + "knowledge_points": [ + "元,角,分的认识及换算" + ], + "source": "23-24 二年级上·安徽亳州·期中" + }, + { + "id": "8", + "unit": "第五单元认识人民币", + "question_type": "选择题", + "difficulty": 0.65, + "question": "小红用 5 元去买 2 元 7 角的文具,请问能找回 ( )。", + "options": [ + "A. 2元3角", + "B. 3元7角", + "C. 1元3角" + ], + "answer": "A", + "solution": "【分析】用小红的钱数减文具的价钱即可求出找回多少钱。注意 1 角 = 10 角,据此计算.\n【详解】5元-2元7角=2元3角;能找回2元3角。故答案为: A", + "knowledge_points": [ + "十元以下人民币的认识与计算" + ], + "source": "22-23 二年级上·河南商丘·期中" + }, + { + "id": "9", + "unit": "第五单元认识人民币", + "question_type": "选择题", + "difficulty": 0.65, + "question": "一个文具盒的价钱是14元,该怎样付钱。下面付钱方式不正确的是()。", + "options": [ + "A. 付 1 张 10 元和 4 张 1 元", + "B. 付1张14元", + "C. 付 14 张 1 元" + ], + "answer": "B", + "solution": "【分析】总金额不变,付的总钱数是 14 元即可。需要注意有没有对应的面值.\n【详解】A。 付1张10元和4张1元一共是14元,正确;B. 没有 14 元的面值,不正确;C. 付 14 张 1 元一共是 14 元,正确。付钱方式不正确的是:付 1 张 14 元。故答案为: B", + "knowledge_points": [ + "十元以上人民币的认识与计算" + ], + "source": "23-24 二年级上·山西朔州·期中" + }, + { + "id": "10", + "unit": "第五单元认识人民币", + "question_type": "选择题", + "difficulty": 0.85, + "question": "一件上衣 56 元,妈妈至少给售货员 ( ) 张 10 元。", + "options": [ + "A. 5", + "B. 7", + "C. 6" + ], + "answer": "C", + "solution": "【分析】一件上衣 56 元,且妈妈所付的钱都是 10 元的,所以,所付的钱是整十元,且大于 56 元;大于 56 且是整十数,最小的是 60,故,妈妈至少要付 60元,也就是6张10元;据此解决.\n【详解】由题意分析得:A. 5 张 10 元是 50 元, 50 元 \u003c 56 元,所付的钱不够;B. 7 张 10 元是 70 元, 70 元 \u003e56 元,所付的钱够;C. 6 张 10 元是 60 元, 60 元 \u003e56 元,所付的钱够;60元\u003c70元,即,一件上衣56元,妈妈至少给售货员6张10元。故答案为: C", + "knowledge_points": [ + "100以内数的比大小", + "十元以上人民币的认识与计算" + ], + "source": "23-24 一年级下·河南漯河·期末" + }, + { + "id": "11", + "unit": "第五单元认识人民币", + "question_type": "选择题", + "difficulty": 0.85, + "question": "小军买文具用去了4元6角,他付给收银员5元,应找回()钱。", + "options": [ + "A. 1元4角", + "B. 4角", + "C. 2 元 6 角" + ], + "answer": "B", + "solution": "【分析】应找回的钱 = 付给收银员的钱 - 买文具花的钱, 1 元 = 10 角;据此解决.\n【详解】5元-4元6角 = 4 角,即,小军买文具用去了 4 元 6 角,他付给收银员 5 元,应找回 4 角钱。故答案为: B", + "knowledge_points": [ + "十元以下人民币的认识与计算" + ], + "source": "23-24一年级下·河南漯河·期末" + }, + { + "id": "12", + "unit": "第五单元认识人民币", + "question_type": "选择题", + "difficulty": 0.85, + "question": "1 张 10 元的纸币能换()的纸币。", + "options": [ + "A. 10 张 1 角", + "B. 10 张 1 元", + "C. 5 张 5 角" + ], + "answer": "B", + "solution": "【分析】人民币的兑换即总面值不变,由此计算出各选项人民币的总面值选择即可.\n【详解】A。 1角 + 1 角 + 1 角 + 1 角 + 1 角 + 1 角 + 1 角 + 1 角 + 1 角 = 10 角, 10 角 = 1 元,与 1 张 10 元不相等;B. 1 元 +1 元 +1 元 +1 元 +1 元 +1 元 +1 元 +1 元 = 10 元,与 1 张 10 元相等;C. 5角 + 5角 + 5角 + 5角 + 5角 = 25角, 25角 = 2元 5角,与1张10元不相等。1 张 10 元的纸币能换 10 张 1 元的纸币。故答案为: B", + "knowledge_points": [ + "元,角,分的认识及换算", + "十元以下人民币的认识与计算" + ], + "source": "23-24 一年级下·湖北·期末" + }, + { + "id": "13", + "unit": "第五单元认识人民币", + "question_type": "选择题", + "difficulty": 0.85, + "question": "一盒鲜牛奶的价格大约是5()。", + "options": [ + "A. 元", + "B. 角", + "C. 分" + ], + "answer": "A", + "solution": "【分析】结合题意及生活中的实际情况来选择合适的人民币单位即可。一般情况下一盒牛奶的价格是 5 元左右.\n【详解】A。5元符合一盒鲜牛奶的价格;B. 5角大约是一块橡皮的价格,不符合题意;C. 5 分很少,还不到 1 根铅笔的价格,不符合题意;所以一盒鲜牛奶的价格大约是 5 元。故答案为: A", + "knowledge_points": [ + "元,角,分的认识及换算" + ], + "source": "23-24 一年级下·山东临沂·期末" + }, + { + "id": "14", + "unit": "第五单元认识人民币", + "question_type": "选择题", + "difficulty": 0.85, + "question": "一把牙刷的价钱可能是 ( )。", + "options": [ + "A. 38元", + "B. 3元8角", + "C. 38分" + ], + "answer": "B", + "solution": "【分析】根据生活经验可知,一把牙刷的价格比较便宜,一般为 3 到 5 元,由此选择合适的即可.\n【详解】A。38元大约是一个书包的价格,不符合题意;B。3元8角符合一把牙刷的价格;C. 1 角 = 10 分, 38 分 = 3 角 8 分,大约是一块橡皮的价格,不符合题意。所以一把牙刷的价钱可能是 3 元 8 角。故答案为: B", + "knowledge_points": [ + "元,角,分的认识及换算" + ], + "source": "23-24 一年级下·广东汕头·期末" + }, + { + "id": "15", + "unit": "第五单元认识人民币", + "question_type": "选择题", + "difficulty": 0.85, + "question": "14 元钱正好可以买 ( ) 和 ( ).\n![](images/203159.png)\n8元", + "options": [ + "A. ①②", + "B. ②③", + "C. ①③" + ], + "answer": "C", + "solution": "【分析】根据题意, 14 元正好可以买两件物品,也就是两件物品的价格和是 14 元,分别用加法计算出结果选择即可.\n【详解】A。 6 + 7 = 13 (元),不符合题意;B. 7 + 8 = 15 (元), 不符合题意;C. 6 + 8 = 14 (元), 符合题意。14元钱正好可以买\n![](images/b094b8e404100d72cc62c85212e866584c23f01d3566bdee5b3bdf89be803192.jpg)故答案为: C", + "knowledge_points": [ + "十元以下人民币的认识与计算", + "十元以上人民币的认识与计算" + ], + "source": "23-24 一年级下·广东汕头·期末" + }, + { + "id": "16", + "unit": "第五单元认识人民币", + "question_type": "选择题", + "difficulty": 0.65, + "question": "一箱桃子77元,只用10元的人民币付钱,妈妈至少要付()张。", + "options": [ + "A. 7", + "B. 8", + "C. 9", + "D. 10" + ], + "answer": "B", + "solution": "【分析】付的钱数得比 77 大,并且是尽量接近 77 的整十数,应该是 80 元。几张十元就是几十元, 8 张十元就是 80 元,据此解答.\n【详解】由分析得,一箱桃子 77 元,只用 10 元的人民币付钱,妈妈至少要付 8 张。故答案为: B", + "knowledge_points": [ + "十元以上人民币的认识与计算" + ], + "source": "23-24 一年级下·山东济南·期末" + }, + { + "id": "17", + "unit": "第五单元认识人民币", + "question_type": "选择题", + "difficulty": 0.65, + "question": "一张 10 元可以换 1张5元和()张1元。", + "options": [ + "A. 5", + "B. 10", + "C. 15" + ], + "answer": "A", + "solution": "【分析】人民币的兑换只要面值相等即可,一张 10 元可以换 2 张 5 元,一张 5 元可以换 5 张 1 元.\n【详解】10元 = 5 元 + 1 元 + 1 元 + 1 元 + 1 元 + 1 元所以一张10元可以换1张5元和5张1元。故答案为:A", + "knowledge_points": [ + "十元以下人民币的认识与计算" + ], + "source": "23-24一年级下·湖南岳阳·期末" + }, + { + "id": "18", + "unit": "第五单元认识人民币", + "question_type": "选择题", + "difficulty": 0.65, + "question": "买![](images/203557.png) (5 角) 和![](images/39c8be16b7410f5a4d867e2e36a864e8130c62be78b02a50bdcf0ba33f5e6e1a.jpg)\n(8 角), 小明只有 1 元钱,还差 ( ) 钱。", + "options": [ + "A. 5角", + "B. 3角", + "C. 2角" + ], + "answer": "B", + "solution": "【分析】根据题意,先用![](images/203557.png)的价格加![](images/39c8be16b7410f5a4d867e2e36a864e8130c62be78b02a50bdcf0ba33f5e6e1a.jpg) 的价格,求出一共需要多少钱,再用需要的钱数减去小明的钱数,就是还差的钱数,根据\"1元 = 10 角\"统一单位再计算.\n【详解】5角 + 8角 = 13角,13角-1元=13角-10角=3角,还差3角钱。故答案为: B", + "knowledge_points": [ + "元,角,分的认识及换算", + "十元以下人民币的认识与计算" + ], + "source": "23-24 一年级下·湖北恩施·期末" + }, + { + "id": "19", + "unit": "第五单元认识人民币", + "question_type": "选择题", + "difficulty": 0.85, + "question": "一张 20 元,五张 10 元,一张 5 角的人民币组成 ( )。", + "options": [ + "A. 21元5角", + "B. 25元5角", + "C. 20 元 5 角" + ], + "answer": "B", + "solution": "【分析】1元 = 10 角,根据人民币的认识,用加法把所有的钱数加起来,求出和,即可解决此题.\n【详解】由题意分析得:五张1元的人民币就是5元,20元+5元+5角=25元5角,即,一张 20 元,五张 1 元,一张 5 角的人民币组成 25 元 5 角。故答案为: B", + "knowledge_points": [ + "十元以上人民币的认识与计算" + ], + "source": "23-24 一年级下·湖北黄冈·期末" + }, + { + "id": "20", + "unit": "第五单元认识人民币", + "question_type": "选择题", + "difficulty": 0.65, + "question": "一个书包36元,妈妈付的全是10元,至少应付()张。", + "options": [ + "A. 3", + "B. 5", + "C. 4" + ], + "answer": "C", + "solution": "【分析】根据题意,36有3个10,1个6组成,据此解答.\n【详解】36 里面有 3 个 10 元,还有 6 元,那么一个书包 36 元,妈妈付的全是 10 元,所以 6 元也需要付 10 元,然后再找零,至少应付 40 元,即 4 张 10 元。故答案为:C", + "knowledge_points": [ + "十元以下人民币的认识与计算" + ], + "source": "23-24一年级下·湖南邵阳·期末" + }, + { + "id": "21", + "unit": "第五单元认识人民币", + "question_type": "选择题", + "difficulty": 0.65, + "question": "1 张 10 元, 2 张 1 元和 1 张 5 角组成 ( )。", + "options": [ + "A. 12元", + "B. 12元5角", + "C. 20元" + ], + "answer": "B", + "solution": "【分析】根据题意,将每张人民币的面值相加就是总面值。计算时元和元相加,角和角相加.\n【详解】10元+1元+1元+5角=12元5角 1张10元,2张1元和1张5角组成12元5角。 故答案为:B", + "knowledge_points": [ + "十元以下人民币的认识与计算" + ], + "source": "22-23 一年级下·广东汕头·期末" + }, + { + "id": "22", + "unit": "第五单元认识人民币", + "question_type": "选择题", + "difficulty": 0.85, + "question": "22。(23-24一年级下·广西柳州·期末)妈妈买了23元的![](images/70ea0fb0d5cfb8ab57b48932c3a7773c4aeae2751522c7dd8b0b4d4792d222e8.jpg)\n和10元的![](images/063319df48adbaed302a5a7dde26220c4f4efa0017751d0f7ef6583f112937df.jpg),全用10元的人民币付钱,至少要付()张。", + "options": [ + "A. 3", + "B. 4", + "C. 5" + ], + "answer": "B", + "solution": "【分析】根据题意,买了 10 元的香蕉,也就是需要付一张 10 元。23 元里面有 2 个 10 元,剩下的 3 元也需要 1 张 10 元,即一共需要付 1 + 2 + 1 = 4 (张).\n【详解】由分析可知,妈妈买了23元的![](images/d8f7dd29aa7a26428321bbc9cc9497d55dd8f974d6bd268e6880591b0e72f14d.jpg)和 10 元的\n![](images/b72d1cb9d57afd3d3304a05c1ab507d3b089eb69edfe548cece71e2c40b137ea.jpg),全用 10 元的人民币付钱,至少要付 4 张。故答案为: B", + "knowledge_points": [ + "十元以上人民币的认识与计算" + ], + "source": "23-24一年级下·广西柳州·期末" + }, + { + "id": "23", + "unit": "第五单元认识人民币", + "question_type": "选择题", + "difficulty": 0.85, + "question": "一本![](images/52c82f9d900c9f95bedff226c9230122f21ce0da464c9c0e756f10d958f094a2.jpg)的价格可能是 ( )。", + "options": [ + "A. 18元", + "B. 1元8角", + "C. 18角" + ], + "answer": "A", + "solution": "【分析】据题意可知,对一本书的价格进行估计,按照我们日常生活经验可知,一本书的价格一般为元,在根据选项进行分析,人民币的换算为1元 = 10 角, 1 角 = 10 分,换算完成后即可得出答案.\n【详解】A。18元,价格符合一本书的价格;B. 1 元 8 角,可以换算成 18 角,与答案 C 相同,且价格不符合一本书;C. 18 角,可以换算为 1 元 8 角,与答案 B 相同,且价格不符合一本书。故答案为: A", + "knowledge_points": [ + "元,角,分的认识及换算" + ], + "source": "23-24 一年级下·福建福州·期末" + }, + { + "id": "24", + "unit": "第五单元认识人民币", + "question_type": "选择题", + "difficulty": 0.85, + "question": "一支铅笔 5 角, 2 元可以买 ( ) 根这样的铅笔。", + "options": [ + "A. 2", + "B. 4", + "C. 6" + ], + "answer": "B", + "solution": "【分析】根据题意, 1 元 = 10 角, 2 元 = 20 角, 5 + 5 + 5 + 5 = 20 (角), 据此解答.\n【详解】根据分析:1 支铅笔 5 角,2 元可以买(4)根这样的铅笔。故答案为: B", + "knowledge_points": [ + "元,角,分的认识及换算", + "十元以下人民币的认识与计算" + ], + "source": "23-24 一年级下·山东济南·期末" + }, + { + "id": "25", + "unit": "第五单元认识人民币", + "question_type": "选择题", + "difficulty": 0.65, + "question": "一张 10 元,一张 5元,两张一元,一张5角的钱正好能买()。", + "options": [ + "A. ![](images/642b14f709780d8e55898f9829cf77b2396b41bae196787054543f194238de3c.jpg)51元", + "B. ![](images/62669c145e83203274547c6a2bba821c66f013cf267e53072ed85742d8ce7797.jpg)17元5角", + "C. ![](images/0c08a855fc312ebde68ffe54a3e50a86c7aa4118119fe101ba04633540c5e912.jpg)18元5角" + ], + "answer": "B", + "solution": "【分析】把一张 10 元,一张 5 元,两张一元,一张 5 角加起来, 10 元 + 5 元 + 2 元 + 5 角 = 17 元 5 角.\n【详解】一张 10 元,一张 5 元,两张一元,一张 5 角的钱正好能买选项 B 的物品。故答案为: B", + "knowledge_points": [ + "十元以下人民币的认识与计算" + ], + "source": "23-24 一年级下·山东临沂·期末" + }, + { + "id": "26", + "unit": "第五单元认识人民币", + "question_type": "选择题", + "difficulty": 0.85, + "question": "1 张 10 元, 2 张 20 元, 1 张 5 角组成 ( )。", + "options": [ + "A. 30元5角", + "B. 50元5角", + "C. 40元5角" + ], + "answer": "B", + "solution": "【分析】根据题意,将每张人民币的面值相加就是总面值。计算时元和元相加,角和角相加.\n【详解】10元+20元+20元+5角=50元5角 1张10元,2张20元,1张5角组成50元5角。 故答案为:B", + "knowledge_points": [ + "十元以上人民币的认识与计算" + ], + "source": "23-24 一年级下·贵州铜仁·期末" + }, + { + "id": "27", + "unit": "第五单元认识人民币", + "question_type": "选择题", + "difficulty": 0.65, + "question": "一支铅笔 6 角钱,一块橡皮 7 角钱,拿 1 元钱买这两样文具,还差 ( )。", + "options": [ + "A. 1角钱", + "B. 3角钱", + "C. 5角钱" + ], + "answer": "B", + "solution": "【分析】根据加法的意义,用一支铅笔的价钱加上一块橡皮的价钱求出这两样文具的总花费,再根据减法的意义,用总花费减去一元即可求出还差的钱数。注意根据 1 元 = 10角进行单位换算.\n【详解】6角+7角=13角;1元 = 10 角;13角-1元=13角-10角=3角所以还差 3 角钱。故答案为: B", + "knowledge_points": [ + "元,角,分的认识及换算", + "十元以下人民币的认识与计算" + ], + "source": "23-24 一年级下·河北保定·期末" + }, + { + "id": "28", + "unit": "第五单元认识人民币", + "question_type": "选择题", + "difficulty": 0.65, + "question": "向阳坊推出的全奶拉丝面包一个 27 元,椰子葡萄吐司一个 20 元,全奶拉丝面包的价格比椰子吐司的价格()。", + "options": [ + "A. 贵一些", + "B. 贵得多", + "C. 便宜一些", + "D. 便宜得多" + ], + "answer": "A", + "solution": "【分析】比较两个价格的多少时,如果两个价格的大小比较接近,就说高的价格比低的价格贵一些,或低的价格比高的价格便宜一些;如果两个价钱的大小相差很多,就说高的价格比低的价格贵得多,或低的价格比高的价格便宜得多,据此解答即可.\n【详解】27元比20元贵一些,所以全奶拉丝面包的价格比椰子吐司的价格贵一些。故答案为: A", + "knowledge_points": [ + "数的相对大小关系", + "元,角,分的认识及换算" + ], + "source": "23-24 一年级下·福建龙岩·期末" + }, + { + "id": "29", + "unit": "第五单元认识人民币", + "question_type": "选择题", + "difficulty": 0.65, + "question": "这束花的价钱可能是()元.\n![](images/204233.png)", + "options": [ + "A. 85", + "B. 75", + "C. 76", + "D. 66" + ], + "answer": "C", + "solution": "【分析】买这束花付了 8 张 10 元,也就是 80 元,这束花的价钱不能超过 80 元,也不会低于 70 元,选择最接近 80 元的即可.\n【详解】A。不可能超过80元,错误;B. 如果是 75 元,只需付 7 张 10 元和 1 张 5 元即可,错误;C. 76 元最接近 80 元,正确;D. 如果是 66 元,只需要付 7 张 10 元,错误。故答案为: C", + "knowledge_points": [ + "十元以上人民币的认识与计算" + ], + "source": "23-24 一年级下·福建龙岩·期末" + }, + { + "id": "30", + "unit": "第五单元认识人民币", + "question_type": "选择题", + "difficulty": 0.85, + "question": "爸爸要买一箱68元的牛奶,如果全付10元的人民币,至少需要付()张。", + "options": [ + "A. 6", + "B. 7", + "C. 8" + ], + "answer": "B", + "solution": "【分析】一箱牛奶要 68 元,如果全付 10 元的人民币,买这箱牛奶至少需要付多少钱,则所付的钱要大于 68 元;再根据\"几张10元的就是几十元\"及整数比较大小的方法来解决此题即可.\n【详解】6 张 10 元的是 60 元,7 张 10 元的是 70 元;60 \u003c 68 \u003c 70 即,爸爸要买一箱 68 元的牛奶,如果全付 10 元的人民币,至少需要付 7 张。故答案为:B", + "knowledge_points": [ + "十元以上人民币的认识与计算" + ], + "source": "23-24一年级下·陕西安康·期末" + }, + { + "id": "31", + "unit": "第五单元认识人民币", + "question_type": "选择题", + "difficulty": 0.85, + "question": "一盒牙膏的价钱是( )。", + "options": [ + "A. 90 分", + "B. 10角", + "C. 8元" + ], + "answer": "C", + "solution": "【分析】根据生活经验以及数据的大小,选择合适的计量单位,即可解决。1元=10角,1角=10分.\n【详解】A。 90分 = 9 角,一盒牙膏的价钱是9角,太便宜了;不符合实际情况;B. 10角 = 1 元,一盒牙膏的价钱是 1 元,太便宜了;不符合实际情况;C. 一盒牙膏的价钱是 8 元;符合实际情况。故答案为: C", + "knowledge_points": [ + "元,角,分的认识及换算" + ], + "source": "23-24 一年级下·福建福州·期末" + }, + { + "id": "32", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.85, + "question": "一包饼干 3 元 4 角,妈妈给售货员阿姨 10 元,应找回( )元( )角。", + "options": [ + + ], + "answer": "6, 6", + "solution": "【分析】根据减法的意义,给售货员阿姨的钱数--包饼干的钱数 = 应找回的钱数,计算时元和元相减,角和角相减,若不够减则借 1 元为 10 角计算.\n【详解】10元-3元4角 = 9 元10角-3元4角 = 6 元6角,一包饼干 3 元 4 角,妈妈给售货员阿姨 10 元,应找回 6 元 6 角。", + "knowledge_points": [ + "十元以下人民币的认识与计算" + ], + "source": "24-25 二年级上·广东梅州·期中" + }, + { + "id": "33", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.85, + "question": "3 元 5 角= ()角 65角 = () 元( )角 70角 = () 元", + "options": [ + + ], + "answer": "35;6;5;7", + "solution": "【分析】1元 = 10 角,几元就是几十角;10 角 = 1 元,几十角就是几元,由此换算即可.\n【详解】3元5角 = 30 角 +5角 = 35 角;65角 = 60角 + 5角 = 6元 5角;70角 = 7 元", + "knowledge_points": [ + "元,角,分的认识及换算", + "十元以下人民币的认识与计算" + ], + "source": "24-25 二年级上·河南商丘·期中" + }, + { + "id": "34", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.85, + "question": "填一填。1 张 20 元可以换( )张 5 元。1 张 10 元可以换( )张 1 元。1 张 100 元可以换( )张 50 元,还可以换( )张 20 元。", + "options": [ + + ], + "answer": "4;10;2;5", + "solution": "【分析】只要前后总钱数不变即可。几个 5 元相加是 20 元就能换几张;几个 1 元相加是 10 元就能换几张;几个 50 元相加是 100 元就能换几张 50 元;几个 20 元相加是 100 元就能换几张 20 元。5元+5元+5元+5元=20,则可以换4张5元;1元+1元+1元+1元+1元+1元+1元+1元+1元 = 10 元,则可以换 10 张 1 元;50 元 + 50 元 = 100 元,则可以换 2 张 50 元;20 元 + 20 元 + 20 元 + 20 元 + 20 元 = 100 元则可以换 5 张 20元.\n【详解】由分析可得:1 张 20 元可以换 4 张 5 元;1 张 10 元可以换 10 张 1 元;1 张 100 元可以换 2 张 50 元,还可以换 5 张 20 元", + "knowledge_points": [ + "元,角,分的认识及换算", + "十元以下人民币的认识与计算", + "十元以上人民币的认识与计算" + ], + "source": "24-25 二年级上·广东揭阳·期中" + }, + { + "id": "35", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.85, + "question": "4 元=()角 30分=()角 5元6角 = () 角 12分 = ( )角( )分", + "options": [ + + ], + "answer": "40;3;56;1;2", + "solution": "【分析】根据1元 = 10 角,1角 = 10 分进行单位换算即可.\n【详解】4元 = 40 角 30分 = 3 角;5元6角 = 50 角 +6 角 = 56 角; 12 分 = 10 分 +2 分 = 1 角 2分", + "knowledge_points": [ + "元,角,分的认识及换算" + ], + "source": "24-25 二年级上·广东揭阳·期中" + }, + { + "id": "36", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.85, + "question": "1 张\n![](images/e7e56aebd7f5eae60b09b99e07284ddcfd9f9f14d9553ac4b5bf4e8c41bb3a86.jpg)能换( )张![](images/b581c64c4aa6b6cbbd939c0d56821b4b40b77326ac6791469ee662a339396ff5.jpg);1张![](images/01570d370dcf642790ac6cc3d0bc84a9711cb9b6e750cb548d267226ccbb6d22.jpg),能换( )张![](images/c2e0afaed74e89744a12a6a77c3503691aae6f4e94fe921e0981d2cad9ff9744.jpg)", + "options": [ + + ], + "answer": "2, 4", + "solution": "【分析】根据人民币的币值进行填空,100元等于2个50元,20元等于4个5元.\n【详解】由分析可得:1张100元人民币能换(2)张50元人民币;1 张20元人民币,能换(4)张5元人民币。", + "knowledge_points": [ + "十元以上人民币的认识与计算" + ], + "source": "23-24 二年级上·河南驻马店·期中" + }, + { + "id": "37", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.65, + "question": "人民币的换算中国人民银行:1 张1元能换( )张五角;1 张2元能换( )张五角;4 张5元能换( )张20元;1 张100元能换( )张50元,也可以换( )张10元", + "options": [ + + ], + "answer": "2;1;2;10", + "solution": "【分析】1元 = 10 角,几个5角相加是10角就能换几张;2元 = 20 角,几个5角相加是20角就能换几张;4 张 5 元是 20 元,所以只能换 1 张;几个 50 元相加是 100 元就能换几张 50 元;几个 10 元相加是 100 元就能换几张 10 元.\n【详解】1元 = 10 角5角+5角=10角,2元 = 20 角5角+5角+5角+5角=20角;5元+5元+5元+5元=20元20元 = 20 元;50元+50元=100元;10元+10元+10元+10元+10元+10元+10元+;10元+10元=100元。", + "knowledge_points": [ + "元,角,分的认识及换算", + "十元以下人民币的认识与计算", + "十元以上人民币的认识与计算" + ], + "source": "23-24 二年级上·广东韶关·期中" + }, + { + "id": "38", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.85, + "question": "38。(23-24二年级上·广东河源·期中)5元 =( )角 10分 = ( ) 角", + "options": [ + + ], + "answer": "50, 1", + "solution": "【分析】根据1元 = 10 角,1角 = 10 分进行单位换算即可.\n【详解】5元 = 50 角 10分 = 1 角", + "knowledge_points": [ + "元,角,分的认识及换算" + ], + "source": "23-24二年级上·广东河源·期中" + }, + { + "id": "39", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.85, + "question": "1 角 = ( ) 分 35角 = ( ) ( )元( )角 3元8角-1元8角 = ( ) 元", + "options": [ + + ], + "answer": "10;3;5;2", + "solution": "【分析】根据1元 = 10 角;1角 = 10 分换算。几十几角 =几十角 + 几角 = 几元几角,计算时元和元相加减,角和角相加减.\n【详解】1角 = 10 分;35角 = 30 角 +5 角 = 3 元5角;3元8角-1元8角=2元", + "knowledge_points": [ + "元,角,分的认识及换算", + "十元以下人民币的认识与计算" + ], + "source": "23-24 二年级上·广东梅州·期中" + }, + { + "id": "40", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.85, + "question": "填空。3元6角 = ( ) 角 70分 = ( )角", + "options": [ + + ], + "answer": "36, 7", + "solution": "【分析】1元 = 10 角, 1角 = 10 分,据此解答即可.\n【详解】3元6角 = 30 角 +6 角 = 36 角 70分 = 7 角", + "knowledge_points": [ + "元,角,分的认识及换算" + ], + "source": "22-23 二年级上·河南商丘·期中" + }, + { + "id": "41", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.65, + "question": "41。(23-24二年级上·山西朔州·期中)小丽有10元钱,买橡皮花了1元8角,买尺子花了2元5角,一共花了( )钱。", + "options": [ + + ], + "answer": "4元3角", + "solution": "【分析】1元 = 10 角,用买橡皮花的钱数加买尺子花的钱数即可求出一共花了多少钱.\n【详解】1元8角+2元5角=4元3角一共花了4元3角钱。", + "knowledge_points": [ + "元,角,分的认识及换算", + "十元以下人民币的认识与计算" + ], + "source": "23-24二年级上·山西朔州·期中" + }, + { + "id": "42", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.85, + "question": "20 角 = ( ) 元 2元8角 = ( )角 1元2角 +2 元 = ( )元( )角", + "options": [ + + ], + "answer": "2;28;3;2", + "solution": "【分析】根据 \"1 元 = 10 角\" 及整数加减法的计算法则来解决此题.\n【详解】由题意分析得:10角 = 1 元,故,20角 = 2 元;2元 = 20 角,故, 2元 8 角 = 28 角;1元2角+2元=3元2角。", + "knowledge_points": [ + "元,角,分的认识及换算", + "十元以下人民币的认识与计算" + ], + "source": "23-24 一年级下·江西吉安·期末" + }, + { + "id": "43", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.85, + "question": "45 分=( )角()分 15元-6元 = ( )元", + "options": [ + + ], + "answer": "4;5;9", + "solution": "【分析】根据1角 = 10 分换算,计算时元和元相加减.\n【详解】45分 = 40 分 +5 分 = 4 角5分;15元-6元=9元", + "knowledge_points": [ + "元,角,分的认识及换算", + "十元以上人民币的认识与计算" + ], + "source": "23-24 一年级下·河南濮阳·期末" + }, + { + "id": "44", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.85, + "question": "80 分=( )角 7元 = ( )角 78角 = ( ) 元( )角 5角6分 = ( )分", + "options": [ + + ], + "answer": "8;70;7;8;56", + "solution": "【分析】根据1元 = 10 角,1角 = 10 分,解答此题即可.\n【详解】80分 = 8 角 7元 = 70 角;78角 = 70 角 +8 角 = 7 元8角 5角6分 = 50 分 +6 分 =56分", + "knowledge_points": [ + "元,角,分的认识及换算" + ], + "source": "23-24 一年级下·山西晋中·期末" + }, + { + "id": "45", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.65, + "question": "4 元 = ( )角 6角+8角 = ( )元( )角 7元2角 = ( ) 角 62分 = ( )角( )分", + "options": [ + + ], + "answer": "40;1;4;72;62", + "solution": "【分析】根据 1 元 = 10 角, 1 角 = 10 分进行单位换算然后得出结论即可。如: 4 元 = 40 角.\n【详解】4元 = 40 角 6角 +8角 =14角 =1元 4角;7元2角 = 72 角 62分 = 6 角2分", + "knowledge_points": [ + "元,角,分的认识及换算" + ], + "source": "23-24 一年级下·湖南长沙·期末" + }, + { + "id": "46", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.65, + "question": "在括号里填上\"\u003e\"\"\u003c\"或\"=\"。100分( )10分 8角9分( )89角 42角()5元 1元6角()2元", + "options": [ + + ], + "answer": "\u003e;\u003c;\u003c;\u003c", + "solution": "【分析】同单位的数越大,金额越大;不同单位的根据 1 元 = 10 角;1 角 = 10 分;统一单位后进行比较即可.\n【详解】100分 \u003e10 分;8角9分 = 80 分+9分 = 89 分;89分 \u003c 100 分;10角 = 100分;10角 \u003c 89 角,则8角9分 \u003c 89 角;5元 = 50 角;42 角 \u003c 50 角,则 42 角 \u003c 5 元;1 元 6 角 = 10 角 + 6 角 = 16 角;2 元 = 20 角;16 角 \u003c 20 角,则 1 元 6 角 \u003c 2 元。", + "knowledge_points": [ + "元,角,分的认识及换算", + "十元以下人民币的认识与计算" + ], + "source": "23-24一年级下·河南漯河·期末" + }, + { + "id": "47", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.85, + "question": "2 张 5 元, 3 张 5 角是( )元( )角。", + "options": [ + + ], + "answer": "115", + "solution": "【分析】将每张人民币的面值相加就是总面值,根据 1 元 = 10 角换算.\n【详解】5元+5元+5角+5角+5角=10元15角 15角=1元5角则 10 元 15 角 = 11 元 5 角;2 张 5 元, 3 张 5 角是 11 元 5 角。", + "knowledge_points": [ + "元,角,分的认识及换算", + "十元以下人民币的认识与计算", + "十元以上人民币的认识与计算" + ], + "source": "23-24 一年级下·河北保定·期末" + }, + { + "id": "48", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.85, + "question": "5元一3元 = ( )元1元8角 +6 角 = ( )元( )角", + "options": [ + + ], + "answer": "2;2;4", + "solution": "【分析】根据 1 元 = 10 角换算,计算时元和元相加减,角和角相加减.\n【详解】5元-3元=2元;1元8角+6角=18角+6角=24角=20角+4角=2元4角", + "knowledge_points": [ + "元,角,分的认识及换算", + "十元以下人民币的认识与计算" + ], + "source": "23-24一年级下·河南漯河·期末" + }, + { + "id": "49", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.85, + "question": "7 元 8 角= ()角 59角 =() 元( )角 8角-3角 = ()角 5角+6元3角 = ( )元( )角", + "options": [ + + ], + "answer": "78;5;9;5;6;8", + "solution": "【分析】根据 1 元 = 10 角换算,计算时元和元相加减,角和角相加减.\n【详解】7元8角 = 70 角 +8 角 = 78 角;59角 = 50 角 +9 角 = 5 元 9 角;8角-3角=5角;5角 +6 元3角 = 6 元8角", + "knowledge_points": [ + "元,角,分的认识及换算", + "十元以下人民币的认识与计算" + ], + "source": "23-24 一年级下·河南郑州·期末" + }, + { + "id": "50", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.85, + "question": "想一想,填一填。2元8角 = ( ) 角 3元5角 +4 角 = ( )元( )角;1元-7角 = ( )角 3元+5元2角 = ( )元( )角", + "options": [ + + ], + "answer": "28;3;9;3;8;2", + "solution": "【分析】根据 1 元 = 10 角换算,计算时元和元相加减,角和角相加减.\n【详解】2元8角 = 20 角 +8 角 = 28 角;3元5角+4角=3元9角;1元-7角=10角-7角=3角;3元+5元2角=8元2角。", + "knowledge_points": [ + "元,角,分的认识及换算", + "十元以下人民币的认识与计算" + ], + "source": "23-24一年级下·湖北黄石·期末" + }, + { + "id": "51", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.65, + "question": "在括号里填上\"\u003e\" \"\u003c\"或\"=\".\n8角( )1元 97( )59+2025+3( )23+5 \n87( )781元( )50分 20角+5角( )2元5角", + "options": [ + + ], + "answer": "\u003c;\u003e;=;\u003e;\u003e;=", + "solution": "【分析】1元=10角,1元=100分。比较数的大小,先看位数的多少,位数多的数就大,位数相同,从高位比较,高位上的数大则这个数大,高位上的数相同,就比较下一位,直到比较出结果为止.\n【详解】1元 = 10 角, 8角 \u003c 1 元;59 + 20 = 79, 97 \u003e 79;25 + 3 = 28, 23 + 5 = 28, 25 + 3 = 23 + 5;87 \u003e 78;1 元 = 100 分, 1 元 \u003e 50 分;20 角 +5 角 = 25 角 =2元5角", + "knowledge_points": [ + "100 以内数的比大小", + "两位数与整十数的加法", + "元,角,分的认识及换算" + ], + "source": "23-24 一年级下·湖北孝感·期末" + }, + { + "id": "52", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.85, + "question": "5 元 5 角= ()角 69角 = () 元( )角 5角 +5 元3角 = ( )元( )角 7元-2元4角 = ()角", + "options": [ + + ], + "answer": "55;6;9;5;8;46", + "solution": "【分析】根据 1 元 = 10 角,结合题干要求进行解答即可。元加元,角加角,满十角变 1 元;元减元,角减角,若角不够减,跟元借 1 变成 10 角,再进行解答即可.\n【详解】5元5角 = 55 角;69角 = 6 元9角;5角+5元3角=5元8角;7元-2元4角=70角-24角=46角", + "knowledge_points": [ + "元,角,分的认识及换算", + "十元以下人民币的认识与计算" + ], + "source": "23-24 一年级下·湖北武汉·期末" + }, + { + "id": "53", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.65, + "question": "53。(23-24一年级下·湖南岳阳·期末)80角( )元 64角=( ) 元( )角 1元-6角( )角 4元+30角=( )元", + "options": [ + + ], + "answer": "8;6;4;4;7", + "solution": "【分析】根据 1 元 = 10 角换算,计算时元和元相加减,角和角相加减.\n【详解】80角 = 8 元;64角 = 60 角 +4 角 = 6 元4角;1元一6角 = 10 角一6角 = 4 角;4元+30角=4元+3元=7元。", + "knowledge_points": [ + "元,角,分的认识及换算", + "十元以下人民币的认识与计算" + ], + "source": "23-24一年级下·湖南岳阳·期末" + }, + { + "id": "54", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.85, + "question": "在括号里填上\"\u003e\"\"\u003c\"或\"=\".\n27+6( )39-5    49+4( )49-4    1+99( )100\n1元( )10角    4元5角( )40角+3角    5角5分( )5元5角", + "options": [ + + ], + "answer": "6;6;6;6;6", + "solution": "【分析】对前后两个数值进行比较,首先要将需要计算的计算题计算出来,在进行大小的比较,需要进行单位换算的要先进行换算在进行比较,1元 = 10 角,1角 = 10 分,据此可得出答案.\n【详解】 27 + 6 = 33 , 39 - 5 = 34,所以 27 + 6 + 39 - 5; 49 + 4 = 53 , 49 - 4 = 45,所以 49 + 4 + 49 - 4; 1 + 99 = 100,所以 1 + 99 = 100;1元 = 10 角;4元5角 = 45 角,40角 +3 角 = 43 角,所以4元5角40角 +3 角;5角5分5元5角。 \n[点睛]考查人民币的认识和换算以及大小的比较。", + "knowledge_points": [ + "两位数与一位数的减法(不退位)", + "一位数与两位数的进位加法", + "元,角,分的认识及换算" + ], + "source": "23-24一年级下·湖北恩施·期末" + }, + { + "id": "55", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.85, + "question": "48 角 = ( ) 元( )角 1元-3角 = ( )角", + "options": [ + + ], + "answer": "4;8;7", + "solution": "【分析】根据1元 = 10 角换算,计算时元和元相减,角和角相减.\n【详解】48角 = 40 角 +8 角 = 4 元8角;1元-3角=10角-3角=7角。", + "knowledge_points": [ + "元,角,分的认识及换算", + "十元以下人民币的认识与计算" + ], + "source": "23-24 一年级下·湖北恩施·期末" + }, + { + "id": "56", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.85, + "question": "一张 100 元能换( )张 50 元。( )张 10 元能换一张 50。", + "options": [ + + ], + "answer": "2, 5", + "solution": "【分析】根据人民币的认识可知,2个50是100,一张100元能换 2 张 50 元;5 个 10 是 50, 5 张 10 元能换一张 50 元.\n【详解】由分析可知:一张 100 元能换 2 张 50 元。5 张 10 元能换一张 50 。", + "knowledge_points": [ + "元,角,分的认识及换算" + ], + "source": "23-24 一年级下·河南周口·期末" + }, + { + "id": "57", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.65, + "question": "在括号里填上 \"\u003e\"\"\u003c\"或\"=\"。6元+8角( )68角 2元3分( )23角 4角3分( )3角4分", + "options": [ + + ], + "answer": "=;\u003c;\u003e", + "solution": "【分析】根据 1 元 = 10 角, 1 角 = 10 分,将单位统一后再根据整数比较大小的方法比较即可。比较时,位数多的数就大;位数相同比较最高位,最高位大的数就大;最高位相同比较下一位,直到比较出结果为止.\n【详解】6元+8角=60角+8角=68角;2元3分=20角3分;20角3分\u003c23角,则2元3分\u003c23角;4角3分 = 43 分;3角4分 = 34 分;43分 \u003e 34 分,则4角3分 \u003e 3 角4分。", + "knowledge_points": [ + "元,角,分的认识及换算", + "十元以下人民币的认识与计算" + ], + "source": "23-24 一年级下·吉林·期末" + }, + { + "id": "58", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.85, + "question": "67角=( )元( )角   4元+2元8角=( )元( )角 3元-1元5角=( )元( )角", + "options": [ + + ], + "answer": "6;7;6;8;1;5", + "solution": "【分析】根据 \"1 元 = 10 角\" 及整数加减法的计算法则来解决此题.\n【详解】由题意分析得:60角 = 6 元, 67角 -60 角 = 7 角,故, 67角 = 6 元 7 角;4元+2元=6元,故,4元+2元8角=6元8角;1元 = 10 角, 10角 -5 角 = 5 角, 2元 -1 元 = 1 元,故, 3元 -1 元 5 角 = 1 元 5 角。", + "knowledge_points": [ + "元,角,分的认识及换算", + "十元以下人民币的认识与计算" + ], + "source": "23-24 一年级下·山西长治·期末" + }, + { + "id": "59", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.65, + "question": "在括号里填上\"\u003e\" \"\u003c\"或\"=\".\n13-4( )420+8( )251元( )10角 58( )85", + "options": [ + + ], + "answer": "\u003e;\u003e;=;\u003c", + "solution": "【分析】根据整数加减法的计算法则,依次计算出各算式的结果再比较大小。比较时,位数多的数就大;位数相同比较最高位,最高位大的数就大;最高位相同比较下一位,直到比较出结果为止。人民币的题目根据1元=10角统一单位再比较.\n【详解】 13 - 4 = 9;9 \u003e 4,则 13 - 4 \u003e 4; 20 + 8 = 28;28 \u003e 25,则 20 + 8 \u003e 25;1元=10角;58 \u003c 85 。", + "knowledge_points": [ + "100 以内数的比大小", + "十几减 5 ~ 2 的退位减法", + "整十数加,减一位数", + "元,角,分的认识及换算" + ], + "source": "23-24 一年级下·河南周口·期末" + }, + { + "id": "60", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.85, + "question": "30角=( )元   3元7角=( )角   45角=( )元( )角    8角=( )分", + "options": [ + + ], + "answer": "3;37;4;5;80", + "solution": "【分析】根据1元 = 10 角,1角 = 10 分换算即可.\n【详解】30角 = 3 元;3元7角 = 30 角 +7 角 = 37 角;45角 = 40 角 +5 角 = 4 元5角;8角 = 80 分。", + "knowledge_points": [ + "元,角,分的认识及换算", + "十元以下人民币的认识与计算" + ], + "source": "23-24 一年级下·河南周口·期末" + }, + { + "id": "61", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.85, + "question": "2元=( )角    5元2角=( )角   48分=( )角( )分", + "options": [ + + ], + "answer": "20;52;4;8", + "solution": "【分析】根据\"1元=10角,1角=10分\"及整数加减法的\n计算法则来解决此题.\n【详解】1元 = 10 角,故,2元 = 20 角;5元 = 50 角, 50 角 +2 角 = 52 角,故, 5 元 2 角 = 52 角;40 分=4 角, 48 分-40 分=8 分,故, 48 分=4 角 8 分。", + "knowledge_points": [ + "元,角,分的认识及换算" + ], + "source": "23-24 一年级下·山东菏泽·期末" + }, + { + "id": "62", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.65, + "question": "8元3角= ( ) 角    52角=( )元( )角 100分=( )角=( )元    6角7分-4角2分=( )角( )分 \n7元-6角=( )元( )角    3元8角+5元1角=( )元( )角", + "options": [ + + ], + "answer": "83;5;2;10;1;2;5;6;4;8;9", + "solution": "【分析】根据 1 元 = 10 角, 1 角 = 10 分换算,计算时元和元相加减,角和角相加减,分和分相加减.\n【详解】8元3角 = 80 角 +3 角 = 83 角;52角 = 50 角 +2 角 = 5 元2角;100分=10角=1元;6角7分-4角2分=2角5分;7元一6角:7元可以分成6元和1元;1元=10角;10角\n-6角 = 4角;4角 + 6元 = 6元 4角;则 7元 - 6角 = 6元 4角;3元8角+5元1角=8元9角。", + "knowledge_points": [ + "元,角,分的认识及换算", + "十元以下人民币的认识与计算" + ], + "source": "23-24 一年级下·湖北黄冈·期末" + }, + { + "id": "63", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.65, + "question": "3 角 = ( ) 分 3元1角 = ( )角 70角 = ( ) 元6角 +8 角 = ( ) 元( )角 5角 = ( ) 分", + "options": [ + + ], + "answer": "30;31;7;1;4;50", + "solution": "【分析】根据元,角,分单位间的进率进行单位换算,1 元 = 10 角,1 角 = 10 分.\n【详解】3角 = 30 分;3元1角 = 31 角;70角 = 7 元;6角+8角=1元4角;5角 = 50 分", + "knowledge_points": [ + "元,角,分的认识及换算" + ], + "source": "23-24 一年级下·河南商丘·期末" + }, + { + "id": "64", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.85, + "question": "1角=( )分    60角=( )元 36角=( )元( )角         3角2分=( )分", + "options": [ + + ], + "answer": "10;6;3;6;32", + "solution": "【分析】根据1元 = 10 角;1角 = 10 分换算即可.\n【详解】1角 = 10 分;60角 = 6 元;36角 = 30 角 +6 角 = 3 元6角;3角2分=30分+2分=32分。", + "knowledge_points": [ + "元,角,分的认识及换算", + "十元以下人民币的认识与计算" + ], + "source": "23-24 一年级下·河南商丘·期末" + }, + { + "id": "65", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.85, + "question": "一张 50 元可以换( )张 10 元, 1 枚 1 元可以换( )枚 5 角或( )枚 1 角。", + "options": [ + + ], + "answer": "5;2;10", + "solution": "【分析】人民币的兑换即总面值保持不变。由此用加法将 10 元,5 角,1 角的人民币分别相加,直到结果和要兑换的面值相同即可.\n【详解】10元+10元+10元+10元+10元=50元;5角+5角=10角=1元;1角+1角+1角+1角+1角+1角+1角+1角=10角=1元;一张 50 元可以换 5 张 10 元, 1 枚 1 元可以换 2 枚 5 角或 10 枚 1 角。", + "knowledge_points": [ + "元,角,分的认识及换算", + "十元以下人民币的认识与计算", + "十元以上人民币的认识与计算" + ], + "source": "23-24 一年级下·河南商丘·期末" + }, + { + "id": "66", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.65, + "question": "一套《儿童故事书》85元,小红付的钱都是 10 元,他至少付了( )张。", + "options": [ + + ], + "answer": "9", + "solution": "【分析】根据题意分析,小红付的钱都是 10 元的,所以小红付的钱是整十数,小红付的钱要超过买故事书的钱,则小红至少要付 90 元, 90 = 10 + 10 + 10 + 10 + 10 + 10 + 10 + 10 + 10,所以小红至少付了 9 张.\n【详解】 90 = 10 + 10 + 10 + 10 + 10 + 10 + 10 + 10 + 10 所以一套《儿童故事书》85元,小红付的钱都是10元,他至少付了9张。", + "knowledge_points": [ + "十元以上人民币的认识与计算" + ], + "source": "23-24一年级下·湖南邵阳·期末" + }, + { + "id": "67", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.65, + "question": "6元=( )角    4元2角=( )角 55角=( )元( )角    56分=( )角( )分", + "options": [ + + ], + "answer": "60;42;5;5;5;6", + "solution": "【分析】(1)根据元与角的进率,1元 = 10 角,进行单位换算即可;(2) 根据元与角的进率, 1 元 = 10 角,进行单位统一,计算即可;(3) 根据元与角的进率, 1 元 = 10 角,进行单位统一,计算即可;(4) 根据角与分的进率, 1 ~角 = 10 分,进行单位统一,计算即可.\n【详解】 (1) 1角 = 10 分, 6元 = 60 角;(2) 1 角 = 10 分, 4 元 = 40 角, 40 + 2 = 42 , 4 元 2 角 = 42 角;(3) 55 = 50 + 5, 1 角 = 10 分, 50 角 = 5 元, 55 角 = 5 元 5 角;(4) 56 = 50 + 6, 50 分 = 5 角, 56 分 = 5 角 6 分。", + "knowledge_points": [ + "元,角,分的认识及换算", + "十元以下人民币的认识与计算" + ], + "source": "22-23 一年级下·广东汕头·期末" + }, + { + "id": "68", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.85, + "question": "68。(23-24一年级下·广东江门·期末)50分=( )角    4元=( )角 5元2角=( )角     9元2角-2角=( )元", + "options": [ + + ], + "answer": "5;40;52;9", + "solution": "【分析】根据1角 = 10 分,1元 = 10 角换算,计算时,元\n和元相加减,角和角相加减.\n【详解】50分=5角;4元 = 40 角;5元2角 = 50 角 +2 角 = 52 角;9元2角-2角=9元。", + "knowledge_points": [ + "元,角,分的认识及换算", + "十元以下人民币的认识与计算" + ], + "source": "23-24一年级下·广东江门·期末" + }, + { + "id": "69", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.65, + "question": "( )张 2 元是 10 元。", + "options": [ + + ], + "answer": "5", + "solution": "【分析】根据题意分析, 10 = 2 + 2 + 2 + 2 + 2,所以 5 张 2 元是 10 元.\n【详解】5 张 2 元是 10 元。", + "knowledge_points": [ + "元,角,分的认识及换算" + ], + "source": "23-24 一年级下·广东江门·期末" + }, + { + "id": "70", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.85, + "question": "4 元 5 角等于( )角;76分等于( )角( )分。", + "options": [ + + ], + "answer": "4576", + "solution": "【分析】根据1元 = 10 角,1角 = 10 分换算计算即可.\n【详解】4元5角 = 40 角 +5 角 = 45 角;76 分 = 70 分 +6 分 = 7 角 6 分;4元5角等于45角;76分等于7角6分。", + "knowledge_points": [ + "元,角,分的认识及换算", + "十元以下人民币的认识与计算" + ], + "source": "23-24 一年级下·河北保定·期末" + }, + { + "id": "71", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.65, + "question": "8元 = ( )角 75角 = ( ) 元( )角 60角 = ( ) 元 8元9角 = ( )角", + "options": [ + + ], + "answer": "80;7;5;6;89", + "solution": "【分析】根据元与角之间的进率,1元 = 10 角,进行单位换算即可.\n【详解】 (1) 1元 = 10 角, 8元 = 80 角;(2) 1 元 = 10 角, 75 = 70 + 5 , 70 角 = 7 元,所以 75 角 = 7 元 5 角;(3) 1 元 = 10 角, 60 角 = 6 元;(4) 1 元 = 10 角, 8 元 = 80 角, 80 + 9 = 89,所以 8 元 9 角 = 89 角。", + "knowledge_points": [ + "元,角,分的认识及换算", + "十元以下人民币的认识与计算" + ], + "source": "23-24一年级下·湖南衡阳·期末" + }, + { + "id": "72", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.85, + "question": "30 角 = ( )元 70分=()角 58角 = ( ) 元( )角 2元4角 = ( )角", + "options": [ + + ], + "answer": "3;7;5;8;24", + "solution": "【分析】根据 1 元 = 10 角;1 角 = 10 分换算即可.\n【详解】30角 = 3 元;70分=7角;58角 = 50 角 +8 角 = 5 元8角;2元4角 = 20 角 +4角 = 24 角。", + "knowledge_points": [ + "元,角,分的认识及换算", + "十元以下人民币的认识与计算" + ], + "source": "23-24 一年级下·广西柳州·期末" + }, + { + "id": "73", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.85, + "question": "6 角 = ( ) 分 7元3角 = ( ) 角 2角 +8 角 =( )元", + "options": [ + + ], + "answer": "60;73;1", + "solution": "【分析】根据 1 元 = 10 角, 1 角 = 10 分换算,计算时同单位的相加减.\n【详解】6角 = 60 分;7元3角 = 70 角 +3角 = 73 角;2角+8角=10角=1元。", + "knowledge_points": [ + "元,角,分的认识及换算", + "十元以下人民币的认识与计算" + ], + "source": "23-24 一年级下·广东佛山·期末" + }, + { + "id": "74", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.65, + "question": "在括号里填上\"\u003e\" \"\u003c\"或\"=\"。2元()10角 100分()63角 5元4角()6元 7个+()9个一 10个+()100个一 3个十4个一( )40", + "options": [ + + ], + "answer": "\u003e;\u003c;\u003c;\u003e;=;\u003c", + "solution": "【分析】1元 = 10 角, 1角 = 10 分, 1元 = 100 分,几个十是几十,几个一是几, 10个十是 100 .\n【详解】2元 = 20 角,20角 \u003e10 角,2元 \u003e10 角;100 分 = 1 元,63角 = 60 角 + 3角 = 6 元3角,100分 \u003c 63 角;5元4角 = 50 角 +4 角 = 54 角,6元 = 60 角,5元4角 \u003c 6元;7个十=70,9个一=9,7个十\u003e9个一;10个十=100,100个一=100,10个十=100个一;3个十4个一= 30 + 4 =34 ,3个十4个一 \u003c 40", + "knowledge_points": [ + "100 以内数的比大小", + "100 以内数的组成", + "元,角,分的认识及换算" + ], + "source": "23-24 一年级下·福建龙岩·期末" + }, + { + "id": "75", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.65, + "question": "75。(23-24一年级下·山东济宁·期末)40角 = ( ) 元 5元6角 = ( ) 角 7角 +3 角 =( )元 60 分=( )角 1 元=( )分 45 角=( )元( )角", + "options": [ + + ], + "answer": "4;56;1;6;100;4;5", + "solution": "【分析】1元 = 10 角, 1 角 = 10 分, 1 元 = 100 角。据此换算单位即可.\n【详解】40角 = 4 元;5元6角 = 50 角 +6 角 = 56 角;7角 +3 角 = 10 角 = 1 元;60 分=6 角;1 元=100 分;45 角=40 角+5 角=4 元 5 角。", + "knowledge_points": [ + "元,角,分的认识及换算" + ], + "source": "23-24一年级下·山东济宁·期末" + }, + { + "id": "76", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.65, + "question": "一块橡皮 4 角钱,小宇用 1 元买了 1 块橡皮,还剩下( )钱。", + "options": [ + + ], + "answer": "6角", + "solution": "【分析】用原有的钱减去橡皮的价格,即可得到还剩的钱;根据元与角的进率,1 元 = 10 角,先将单位统一然后再进行计算.\n【详解】1元 = 10 角 10 - 4 = 6 (角) 所以一块橡皮 4 角钱,小宇用 1 元买了 1 块橡皮,还剩下 6 角。", + "knowledge_points": [ + "元,角,分的认识及换算", + "十元以下人民币的认识与计算" + ], + "source": "23-24 一年级下·山东济宁·期末" + }, + { + "id": "77", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.65, + "question": "7 元 3 角 = () 角 46元-9元=( )元 70角+26角=( )元( )角9角+1元=( )元()角", + "options": [ + + ], + "answer": "73;37;9;6;1;9", + "solution": "【分析】相同单位的直接相加减,不同单位的换算为统一单位再进行计算,1元=10角,据此即可计算.\n【详解】7元3角 = 7 元 +3 角 = 70 角 +3 角 = 73 角;46元 -9 元 = 37 元;70角 +26 角 = 96 角 = 90 角 +6 角 = 9 元 +6 角 = 9 元6角;9角 +1 元 = 1 元9角。", + "knowledge_points": [ + "元,角,分的认识及换算", + "十元以下人民币的认识与计算", + "十元以上人民币的认识与计算" + ], + "source": "23-24 一年级下·山东济宁·期末" + }, + { + "id": "78", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.85, + "question": "妈妈有 1 张![](images/33e6d987dd8519770a62a589a4cbd56f092be6837a11ac2522d62df6b1accc67.jpg),2张![](images/e3f03fa6b5547e2c9a6e8e81234cb1eb1c73e9155bb5970b2049d293c67df5b0.jpg),1张![](images/d558bf911c4e9bc2bc534912ba3d8a2057657810f8d7c5dc1b9928c52daf053f.jpg)\n正好买了一条鱼,这条鱼( )元( )角。", + "options": [ + + ], + "answer": "125", + "solution": "【分析】根据题意,将所有人民币的面值相加就是总面值。计算时元和元相加,角和角相加.\n【详解】10元+1元+1元+5角=12元5角", + "knowledge_points": [ + "十元以上人民币的认识与计算" + ], + "source": "23-24 一年级下·河北衡水·期末" + }, + { + "id": "79", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.65, + "question": "一个足球 30 元,如果付2张![](images/7aa7b04f3639c5d0d61359fe1704a6e50906bdac9d0b2c8ed30f6ff3813997fa.jpg) ,应找回( )元。", + "options": [ + + ], + "answer": "10", + "solution": "【分析】根据题意分析, 2 张 20 元是 40 元,用付的 40 元减去一个足球的钱,即可得到应找回的钱.\n【详解】 20 + 20 = 40 (元)40 - 30 = 10 (元)所以一个足球 30 元,如果付 2 张![](images/7aa7b04f3639c5d0d61359fe1704a6e50906bdac9d0b2c8ed30f6ff3813997fa.jpg),应找回10元。", + "knowledge_points": [ + "十元以上人民币的认识与计算" + ], + "source": "23-24 一年级下·山东济宁·期末" + }, + { + "id": "80", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.85, + "question": "5元8角=( )角 8角+4角=( )元( )角\n1元-6角=( )角 6元+4元2角=( )元( )角", + "options": [ + + ], + "answer": "58;1;2;4;10;2", + "solution": "【分析】根据 1 元 = 10 角换算,计算时元和元相加减,角和角相加减.\n【详解】5元8角 = 50 角 +8 角 = 58 角;8角+4角=12角=1元2角;1元-6角=10角-6角=4角;6元+4元2角=10元2角。", + "knowledge_points": [ + "元,角,分的认识及换算", + "十元以下人民币的认识与计算" + ], + "source": "23-24 一年级下·山东济宁·期末" + }, + { + "id": "81", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.65, + "question": "我会转化。38角 = ( ) 元( )角 60分 = ( )角 4角 = ( ) 分 9角 +5 角 = ( )元( )角", + "options": [ + + ], + "answer": "3;8;6;40;1;4", + "solution": "【分析】根据 1 元 = 10 角, 1 角 = 10 分及整数加减法的计算法则解答即可.\n【详解】38角 = 30 角 +8角 = 3 元8角 60分=6角 4角 = 40 分 9角 +5 角 = 14 角 = 10 角 +4 角 = 1 元4角", + "knowledge_points": [ + "元,角,分的认识及换算", + "十元以下人民币的认识与计算" + ], + "source": "23-24 一年级下·湖南湘西·期末" + }, + { + "id": "82", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.85, + "question": "1 张![](images/8444cbfd2a6c5d636a8aeaa2f84b9c74f094946a389806c858315bfdf8b623f1.jpg)\n可以换1张![](images/0576c8d379ecc6674909b55d6a187b2a53e0b4fb162ded1a410af1a0a73e9205.jpg) 和( )张![](images/6cbd6cfc7eb6cf6c7e456c8dc4181c6b93e688585df9bbfdde7bcd545c62d063.jpg)", + "options": [ + + ], + "answer": "3", + "solution": "【分析】1 张 50 人民币可以表示 5 张 10 元人民币, 1 张 20 元人民表示 2 张 10 元人民币。1 个 20 和 3 个 10 合起来是 50,再结合人民币面值进行解答即可.\n【详解】1 张50 人民币可以换1张 20 元人民和(3)张![](images/676c80cc96dd4568972773d55d22ab2050218cd093028f778f699211eca92353.jpg)", + "knowledge_points": [ + "元,角,分的认识及换算", + "十元以上人民币的认识与计算" + ], + "source": "23-24一年级下·山东临沂·期末" + }, + { + "id": "83", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.85, + "question": "5 元 2 角 = ( ) 角 3元6角+7角=( )元( )角", + "options": [ + + ], + "answer": "52;4;3", + "solution": "【分析】根据题意可知:根据 1 元 = 10 角将单位换算统一,然后再计算.\n【详解】5元2角 = 50 角 +2角 = 52 角 3元6角+7角=36角+7角=43角=4元3角", + "knowledge_points": [ + "元,角,分的认识及换算", + "十元以下人民币的认识与计算" + ], + "source": "23-24 一年级下·山东临沂·期末" + }, + { + "id": "84", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.65, + "question": "小明用一张 5 元钱买一根 2 元 5 角的冰棒,应找回( )钱。", + "options": [ + + ], + "answer": "2元5角", + "solution": "【分析】总钱数一冰棒的钱数 = 应找回的钱数,注意相同单位才能加减,角不够减时要拿出 1 元换成 10 角来减,据此得出结论即可.\n【详解】5元-2元5角=2元5角,故应找回2元5角钱。", + "knowledge_points": [ + "元,角,分的认识及换算", + "十元以下人民币的认识与计算" + ], + "source": "23-24 一年级下·河北邢台·期末" + }, + { + "id": "85", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.65, + "question": "填一填.\n20分=( )角 50角=( )元 4元8角 = ( )角5角6分 = ( )分 7元 = ( )角69角= ( )元( )角", + "options": [ + + ], + "answer": "2;5;48;56;70;6;9", + "solution": "【分析】1元 = 10 角, 1角 = 10 分。据此解答即可.\n【详解】20分=2角 50角=5元;4元8角 = 40 角 +8 角 = 48 角 5角6分 = 50 分+6分 = 56 分7元 = 70 角 69角 = 60 角 +9角 = 6 元9角", + "knowledge_points": [ + "元,角,分的认识及换算" + ], + "source": "23-24 一年级下·陕西安康·期末" + }, + { + "id": "86", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.65, + "question": "4 元 6 角 = ( ) 角 5 角 +8 元 = ( ) 元 ( ) 角 62角 = ( ) 元( )角7角 +9 角 = ( )元( )角 ", + "options": [ + + ], + "answer": "46;8;5;6;2;1;6", + "solution": "【分析】根据 1 元 = 10 角进行单位换算,然后得出结论即可.\n【详解】4元6角 = 46 角5角 +8 元 = 8 元5角 62角 = 6 元2角7角 +9 角 = 16 角 = 1 元6角 ", + "knowledge_points": [ + "元,角,分的认识及换算" + ], + "source": "23-24 一年级下·江西吉安·期末" + }, + { + "id": "87", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.85, + "question": "一张 100 元可以换( )张20元;可以换( )张50元和( )张10元。", + "options": [ + + ], + "answer": "5;1;5", + "solution": "【分析】用 1 张 100 元可以换几张 20 元,就看 100 里面有几个 20 即可;1 张 100 元可以换几张 50 元和几张 10 元,因为 100 = 50 + 10 + 10 + 10 + 10 + 10,所以可以换 1 张 50 元和 5 张 10 元.\n【详解】一张 100 元可以换 5 张 20 元;可以换 1 张 50 元和 5 张 10 元。", + "knowledge_points": [ + "元,角,分的认识及换算" + ], + "source": "23-24一年级下·河北廊坊·期末" + }, + { + "id": "88", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.85, + "question": "人民币的纸币都是形的,硬币都是形的。", + "options": [ + + ], + "answer": "长方,圆", + "solution": "【分析】根据长方形及圆形的特征来解决即可。长方形是长长方方的,由 4 条边围成,且对边一样长;圆形由一条曲线围成。![](images/bc22dae95cccc78fb7e94850c42f8c0316a968a44b0681345f31c1753e046283.jpg)这纸币是长方形;![](images/43d5cfd440241883d16ae59fa3169a3445cff94e01d99f1606dcf35b92970e94.jpg)这硬币是圆形.\n【详解】由题意分析得:人民币的纸币都是长方形的,硬币都是圆形的。", + "knowledge_points": [ + "长方形,正方形,三角形和圆的初步认识", + "十元以下人民币的认识与计算" + ], + "source": "22-23 一年级下·河南驻马店·期末" + }, + { + "id": "89", + "unit": "第五单元认识人民币", + "question_type": "判断题", + "difficulty": 0.65, + "question": "17 元 8 角 +19 角 = 36 元 8 角。( )", + "options": [ + + ], + "answer": "×", + "solution": "【分析】人民币之间进行加法计算时,元和元相加,角和角相加,相加满十角进为 1 元。题中 19 角先根据 1 元 = 10 角换算为几元几角再计算.\n【详解】19角=10角+9角=1元9角;17元8角+1元9角=18元17角=19元7角原题计算错误。故答案为: ×", + "knowledge_points": [ + "元,角,分的认识及换算", + "十元以上人民币的认识与计算" + ], + "source": "24-25 二年级上·河南商丘·期中" + }, + { + "id": "90", + "unit": "第五单元认识人民币", + "question_type": "判断题", + "difficulty": 0.85, + "question": "60 角等于 6 元。( )", + "options": [ + + ], + "answer": "√", + "solution": "【分析】根据1元 = 10 角进行单位换算即可.\n【详解】因为 1 元 = 10 角, 60 角里面有 6 个 10 角,所以 60 角等于 6 元,原题说法正确.\n故答案为: √", + "knowledge_points": [ + "元,角,分的认识及换算" + ], + "source": "24-25 二年级上·广东·期中" + }, + { + "id": "91", + "unit": "第五单元认识人民币", + "question_type": "判断题", + "difficulty": 0.85, + "question": "17 角减去 3 角等于 20 角。( )", + "options": [ + + ], + "answer": "×", + "solution": "【分析】根据减法的意义,用 17 角减去 3 角求出差,再与 20 角比较即可.\n【详解】 17 - 3 = 14 (角);14角!=20角,所以 17 角减去 3 角等于 14 角,原题说法错误。故答案为: ×", + "knowledge_points": [ + "十元以下人民币的认识与计算" + ], + "source": "24-25 二年级上·广东揭阳·期中" + }, + { + "id": "92", + "unit": "第五单元认识人民币", + "question_type": "判断题", + "difficulty": 0.85, + "question": "铅笔每支9角钱,小明付了1元,应找回1元。()", + "options": [ + + ], + "answer": "×", + "solution": "【分析】根据减法的意义,付出的钱数一铅笔的钱数 = 应找回的钱数,根据 1 元 = 10 角统一单位再计算.\n【详解】1元-9角 = 10 角-9角 = 1 角;铅笔每支 9 角钱,小明付了 1 元,应找回 1 角。原题说法错误。故答案为: ×\n![](images/1dc1e11f38bcb5da56d2eb552b01718857852cf38445b0dd90030657e068921e.jpg)", + "knowledge_points": [ + "元,角,分的认识及换算", + "十元以下人民币的认识与计算" + ], + "source": "23-24一年级下·河南漯河·期末" + }, + { + "id": "93", + "unit": "第五单元认识人民币", + "question_type": "判断题", + "difficulty": 0.65, + "question": "一张![](images/1dc1e11f38bcb5da56d2eb552b01718857852cf38445b0dd90030657e068921e.jpg)可以换5张![](images/96657b8a26fb04ef8d31278851c53b205b99124f2dd60cbbb4724758dd57f67a.jpg)", + "options": [ + + ], + "answer": "×", + "solution": "【分析】由 5 + 5 + 5 + 5 = 20,可知一张![](images/0d18eb08f005ce3c202abd7621504af39dce935c10b68e26ae294e19e54a517e.jpg)可以换 4 张![](images/96657b8a26fb04ef8d31278851c53b205b99124f2dd60cbbb4724758dd57f67a.jpg)的,据此判断即可.\n【详解】由分析可知:一张20元可以换4张5元原题说法错误。故答案为: ×", + "knowledge_points": [ + "元,角,分的认识及换算" + ], + "source": "23-24一年级下·江西吉安·期末" + }, + { + "id": "94", + "unit": "第五单元认识人民币", + "question_type": "判断题", + "difficulty": 0.65, + "question": "小力买一个篮球,需要98元,小力付给售货员两张50元,售货员应找回2元2角。( )", + "options": [ + + ], + "answer": "×", + "solution": "【分析】根据题意分析,两张 50 是 100 元,应找回的钱等于付给售货员的钱减去买篮球的钱.\n【详解】两张50是100元 100 - 98 = 2 (元)所以售货员应找回 2 元。故答案为: ×", + "knowledge_points": [ + "元,角,分的认识及换算", + "十元以上人民币的认识与计算" + ], + "source": "23-24一年级下·河南周口·期末" + }, + { + "id": "95", + "unit": "第五单元认识人民币", + "question_type": "判断题", + "difficulty": 0.65, + "question": "一张 10 元的可以换 2 张 5 元的,也可以换 5 张 2 元的。( )", + "options": [ + + ], + "answer": "√", + "solution": "【分析】根据题意分析,由 10 = 5 + 5,可知 10 元可以换 2 张 5 元的;由 10 = 2 + 2 + 2 + 2 + 2,可知 10 元可以换 5 张 2 元的.\n【详解】根据分析可知 10 元可以换 2 张 5 元的,也可以换 5 张 2 元的。故答案为: √", + "knowledge_points": [ + "元,角,分的认识及换算" + ], + "source": "23-24 一年级下·山东·期末" + }, + { + "id": "96", + "unit": "第五单元认识人民币", + "question_type": "判断题", + "difficulty": 0.65, + "question": "10 张 1 元的钱比 2张5元的钱多。( )", + "options": [ + + ], + "answer": "×", + "solution": "【分析】10 张 1 元是 10 元, 2 张 5 元是 5 + 5 = 10 元, 10 张 1 元的钱与 2 张 5 元的钱一样多.\n【详解】10 张 1 元的钱比 2 张 5 元的钱多,说法错误。故答案为: ×", + "knowledge_points": [ + "十元以下人民币的认识与计算" + ], + "source": "23-24 一年级下·山东临沂·期末" + }, + { + "id": "97", + "unit": "第五单元认识人民币", + "question_type": "判断题", + "difficulty": 0.85, + "question": "6 张 1 元和 4 张 5 角正好可以换 1 张 10 元。( )", + "options": [ + + ], + "answer": "×", + "solution": "【分析】根据题意可知: 6 张 1 元是 6 元, 4 张 5 角是 5 + 5 + 5 + 5 = 20 角 = 2 元,则 6 + 2 = 8 (元)\n【详解】由分析可得:6 张 1 元和 4 张 5 角正好可以换 8 张 1 元或者 1 张 5 元 3 张 1 元,原题说法不正确。故答案为: ×", + "knowledge_points": [ + "元,角,分的认识及换算", + "十元以下人民币的认识与计算" + ], + "source": "22-23一年级下·江西吉安·期末" + }, + { + "id": "98", + "unit": "第五单元认识人民币", + "question_type": "解答题", + "difficulty": 0.65, + "question": "李明买了一把尺子,付给售货员 5 元,找回 2 元 1 角。这把尺子几元几角。", + "options": [ + + ], + "answer": "2元9角", + "solution": "【分析】根据减法的意义,付给售货员的钱数一找回的钱数 = 尺子的价格。计算时,元和元相减,角和角相减,若不够减,则借 1 元为 10 角进行计算.\n【详解】5元-2元1角=4元10角-2元1角=2元9角答:这把尺子2元9角。", + "knowledge_points": [ + "十元以下人民币的认识与计算" + ], + "source": "24-25 二年级上·河南商丘·期中" + }, + { + "id": "99", + "unit": "第五单元认识人民币", + "question_type": "解答题", + "difficulty": 0.85, + "question": "妈妈抢了两个微信红包,一个红包 4 元,另一个红包 6 元,一共抢了几元。", + "options": [ + + ], + "answer": "10元", + "solution": "【分析】将妈妈抢的两个微信红包的价钱相加,即可得出妈妈一共抢了多少元.\n【详解】 4 + 6 = 10 (元);答:一共抢了 10 元。", + "knowledge_points": [ + "10 的加减法", + "十元以下人民币的认识与计算" + ], + "source": "23-24 二年级上·广东江门·期中" + }, + { + "id": "100", + "unit": "第五单元认识人民币", + "question_type": "解答题", + "difficulty": 0.65, + "question": "100。(22-23一年级下·江西吉安·期末)东东和西西在书店里都想买一本故事书,东东带的钱差10元3角,西西带的钱差4元7角,两人的钱合起来正好可以买一本故事书,买这本故事书需要多少钱。", + "options": [ + + ], + "answer": "15元", + "solution": "【分析】 东东差的钱就是西西带的钱,西西差的钱就是东东带的钱,即东东带了 4 元 7 角,西西带了 10 元 3 角。根据加法的意义,即可算出这本故事书的价格。注意根据 1 元 = 10 角进行单位换算.\n【详解】4元7角 +10 元3角 = 15 元;答:买这本故事书需要15元。", + "knowledge_points": [ + "十元以上人民币的认识与计算" + ], + "source": "22-23一年级下·江西吉安·期末" + }, + { + "id": "101", + "unit": "第五单元认识人民币", + "question_type": "选择题", + "difficulty": 0.65, + "question": "妈妈给小红买了一件新衣服,用了()。", + "options": [ + "A. 60 元", + "B. 60角", + "C. 60分" + ], + "answer": "A", + "solution": "【分析】 60角 = 6元, 60分 = 6 角,根据生活常识知一件衣服的价格大概几十元,据此得出结论即可.\n【详解】根据分析知:妈妈给小红买了一件新衣服,用了 60 元。故答案为:A", + "knowledge_points": [ + "元,角,分的认识及换算" + ], + "source": "22-23一年级下·江西吉安·期末" + }, + { + "id": "102", + "unit": "第五单元认识人民币", + "question_type": "选择题", + "difficulty": 0.65, + "question": "一辆玩具小汽车52元,买这辆小汽车时,付的都是10元人民币,至少要付()张。", + "options": [ + "A. 4", + "B. 5", + "C. 6" + ], + "answer": "C", + "solution": "【分析】 50 \u003c 52 \u003c 60, 6 张 10 元的是 60 元,要买 52 元的小汽车至少要付 6 张 10 元的人民币.\n【详解】 根据分析知:付的都是 10 元人民币,至少要付 6 张。 故答案为: C", + "knowledge_points": [ + "元,角,分的认识及换算" + ], + "source": "23-24一年级下·河南周口·期末" + }, + { + "id": "103", + "unit": "第五单元认识人民币", + "question_type": "选择题", + "difficulty": 0.65, + "question": "一支铅笔的价钱大约是 ( )。", + "options": [ + "A. 5元", + "B. 5角", + "C. 5 分" + ], + "answer": "B", + "solution": "【分析】根据生活常识可知,一支钢笔的价格大约是 5 元,一支铅笔的价格大概是 5 角,一个曲别针的价格大约是 5 分,据此得出结论即可.\n【详解】根据分析知:一支铅笔的价钱大约是 5 角。故答案为:B", + "knowledge_points": [ + "元,角,分的认识及换算" + ], + "source": "23-24 一年级下·河南周口·期末" + }, + { + "id": "104", + "unit": "第五单元认识人民币", + "question_type": "选择题", + "difficulty": 0.85, + "question": "阳阳买一个篮球,付![](images/9752b1a56a188d063ca8b65d9ee49a51593c0568c8bcdad4d1c3dca3371f8ea8.jpg)给售货员三张找回的钱比5元少。篮球的价格可能是 ( )。", + "options": [ + "A. 49元", + "B. 59 元", + "C. 69 元" + ], + "answer": "B", + "solution": "【分析】阳阳买了1个篮球付了三张![](images/ad0ec129ed10e55b6a60d556b6a7390204087f79a19317264d16221ce30a991f.jpg)5元少,说明篮球的价格小于60元,大于55元,据此解答即可.\n【详解】据分析可知:篮球的价格小于60元,大于55元。A。 49 元 \u003c 55 元,不符合题意;B. 55 元 \u003c 59 元 \u003c 60 元,符合题意;C. 69 元 \u003e60 元,不符合题意。故答案为: B", + "knowledge_points": [ + "100 以内数的比大小", + "十元以上人民币的认识与计算" + ], + "source": "23-24 一年级下·江西吉安·期末" + }, + { + "id": "105", + "unit": "第五单元认识人民币", + "question_type": "选择题", + "difficulty": 0.65, + "question": "一瓶牛奶的价钱是 35 ( )。", + "options": [ + "A. 元", + "B. 角", + "C. 分" + ], + "answer": "B", + "solution": "【分析】 根据生活实际,一瓶牛奶的价格比较便宜,根据1元 = 10 角, 1 角 = 10 分,结合数据 35,应该用角作单位比较合适,由此解答.\n【详解】A。35元大约是一个背包的价钱;不符合题意;B. 1 元 = 10 角;35 角 = 3 元 5 角,大约为一瓶牛奶的价格,符合题意;C. 1 角 = 10 分;35 分 = 3 角 5 分,大约为一支铅笔的价格,不符合题意。故答案为: B", + "knowledge_points": [ + "元,角,分的认识及换算" + ], + "source": "22-23一年级下·江西吉安·期末" + }, + { + "id": "106", + "unit": "第五单元认识人民币", + "question_type": "选择题", + "difficulty": 0.65, + "question": "明明有9张1元,3张5角,4张1角,他一共有()钱。", + "options": [ + "A. 10元6角", + "B. 10元9角", + "C. 11元" + ], + "answer": "B", + "solution": "【分析】9 张 1 元是 9 元, 3 张 5 角是 1 元 5 角, 4 张 1 角是4角;9元+1元5角+4角=10元9角。据此解答即可.\n【详解】由分析可得:明明有9张1元,3张5角,4张1角,他一共有10元9角钱。故答案为:B", + "knowledge_points": [ + "十元以下人民币的认识与计算" + ], + "source": "23-24一年级下·江西上饶·期末" + }, + { + "id": "107", + "unit": "第五单元认识人民币", + "question_type": "选择题", + "difficulty": 0.65, + "question": "![](images/9afe95f59750e0c1db382e405a50c4380df53fbb5f6de9197b63be71b1171d84.jpg)蛋糕,58元。妈妈带的都是![](images/c47c27c70aea1f7a34a798217e97aa30a89ff84b10679f2450ad33e35563f20e.jpg)的钱,买这个蛋糕至少要付()张![](images/66655c54ece39e4eea6eae38a9df61d5382832a644132e7e796d035729efa8c9.jpg)", + "options": [ + "A. 2", + "B. 3", + "C. 4" + ], + "answer": "B", + "solution": "【分析】 妈妈带的都是二十元,那么 1 张 20 元是 20 元,2 张 20 元是 20 + 20 = 40 元,3 张 20 元是 20 + 20 + 20 = 60 元, 60 \u003e 58,所以买这个蛋糕至少要付 3 张 20 元.\n【详解】 20 + 20 = 40 (元)20 + 20 + 20 = 60 (元)60 \u003e 58 买这个蛋糕至少要付3张20元。故答案为: B \n[点睛]解答此题的关键是先找出几个 20 的和比 58 大,然后再进一步解答。", + "knowledge_points": [ + "十元以上人民币的认识与计算" + ], + "source": "23-24 一年级下·湖南郴州·期末" + }, + { + "id": "108", + "unit": "第五单元认识人民币", + "question_type": "选择题", + "difficulty": 0.65, + "question": "用 10 元钱买两块 4 角的橡皮,应找回 ( )。", + "options": [ + "A. 9元2角", + "B. 2 元", + "C. 2角" + ], + "answer": "A", + "solution": "【分析】两块 4 角的橡皮应付 4 + 4 = 8 (角),总钱数一应付的钱数 = 找回的钱数,据此得出结论即可.\n【详解】 4 + 4 = 8 (角);10元-8角=9元2角;即应找回9元2角。故答案为: A", + "knowledge_points": [ + "十元以下人民币的认识与计算" + ], + "source": "23-24 一年级下·湖北黄冈·期末" + }, + { + "id": "109", + "unit": "第五单元认识人民币", + "question_type": "选择题", + "difficulty": 0.85, + "question": "一个书包 78 元,如果全用付钱,要付()张。", + "options": [ + "A. 7", + "B. 4", + "C. 3" + ], + "answer": "B", + "solution": "【分析】![](images/5cb576a982b08677b83a7fe46ea3f8cdf7b51dd9512c05ec7bb0e3dcac674f6d.jpg)这是一张20元的纸币;一个书包 78 元,那所付的钱就要大于或等于 78 元;据此算算几张 20 元的人民币会大于或等于 78 元;据此解决.\n【详解】20 + 20 = 40 (元)40 + 20 = 60 (元)60 + 20 = 80 (元)\n也就是4张20元的纸币是80元, 80 \u003e 78 ;即,一个书包 78 元,如果全用![](images/87bad0f238d1b0907543e54387c108a9cfc702d72f656ac733e7ddb119d29e53.jpg)付钱,要付4张。故答案为: B", + "knowledge_points": [ + "100 以内数的比大小", + "十元以上人民币的认识与计算" + ], + "source": "23-24 一年级下·湖北孝感·期末" + }, + { + "id": "110", + "unit": "第五单元认识人民币", + "question_type": "选择题", + "difficulty": 0.65, + "question": "一个书包的价格是 89 元。如果要买一个书包。全用 10 元一张的钱付款,至少要付()张。", + "options": [ + "A. 8", + "B. 9", + "C. 10" + ], + "answer": "B", + "solution": "【分析】根据题意,付出的钱数要大于 89 元。用加法计算出各选项付出的钱数是多少,选择大于 89 元且付出张数最少的.\n【详解】 A. 10元 + 10元 + 10元 + 10元 + 10元 + 10元 + 10元+10 元=80 元;80 元\u003c89 元,不够付;B. 10 元 + 10 元 + 10 元 + 10 元 + 10 元 + 10 元 + 10 元 + 10元+10元=90元;90元\u003e89元,够付;C. 10 元 + 10 元 + 10 元 + 10 元 + 10 元 + 10 元 + 10 元 + 10元 + 10 元 + 10 元 = 100 元;100 元 \u003e 89 元,够付。9 张 \u003c 10 张全用 10 元一张的钱付款,至少要付 9 张。故答案为: B", + "knowledge_points": [ + "十元以上人民币的认识与计算" + ], + "source": "23-24 一年级下·湖南张家界·期末" + }, + { + "id": "111", + "unit": "第五单元认识人民币", + "question_type": "选择题", + "difficulty": 0.85, + "question": "一瓶牛奶的价钱是 3 ( )。", + "options": [ + "A. 元", + "B. 角", + "C. 分" + ], + "answer": "A", + "solution": "【分析】像一块橡皮,一支铅笔的价格大约是几角钱;一瓶可乐,一瓶牛奶一般是几元钱;分这种钱币已经不怎么流通了;一瓶铁罐的可乐一般是3元,一瓶牛奶的价钱和一瓶可乐的价钱差不多,所以,要计量一瓶牛奶的价钱要用\u0027元\u0027做单位比较合适;据此解决.\n【详解】由题意分析得:一瓶牛奶的价钱是 3 元。故答案为: A", + "knowledge_points": [ + "元,角,分的认识及换算" + ], + "source": "23-24 一年级下·贵州铜仁·期末" + }, + { + "id": "112", + "unit": "第五单元认识人民币", + "question_type": "选择题", + "difficulty": 0.85, + "question": "一瓶大可乐的价格可能为()。", + "options": [ + "A. 7元2角", + "B. 7角2分", + "C. 72 元" + ], + "answer": "A", + "solution": "【分析】根据生活经验可知,一瓶小可乐的价钱一般是2到4元,一瓶大可乐的价格一般是6到8元;据此解决.\n【详解】由题意分析得:一瓶大可乐的价格可能为 7 元 2 角。故答案为: A", + "knowledge_points": [ + "元,角,分的认识及换算" + ], + "source": "23-24一年级下·黑龙江哈尔滨·期末" + }, + { + "id": "113", + "unit": "第五单元认识人民币", + "question_type": "选择题", + "difficulty": 0.85, + "question": "一个蛋糕 48 元,如果全付 20 元,最少需要付()张才能买下这个蛋糕。", + "options": [ + "A. 2", + "B. 3", + "C. 4" + ], + "answer": "B", + "solution": "【分析】全付 20 元,也就是付出的钱数要大于 48 且最接近 48,用加法计算出各选项付出的钱数,选择即可.\n【详解】A。20元+20元=40元;40元\u003c48元,不符合题意;B. 20 元 + 20 元 + 20 元 = 60 元;60 元 \u003e 48 元,且接近 48 元,符合题意;C. 20 元 + 20 元 + 20 元 + 20 元 = 80 元;80 元 \u003e 48 元,超出 48 元太多,不符合题意。所以最少需要付 3 张才能买下这个蛋糕。故答案为: B", + "knowledge_points": [ + "十元以上人民币的认识与计算" + ], + "source": "23-24一年级下·吉林四平·期末" + }, + { + "id": "114", + "unit": "第五单元认识人民币", + "question_type": "选择题", + "difficulty": 0.65, + "question": "妈妈购买标价是 13.80 元的毛巾,付了 20 元,应找回()。", + "options": [ + "A. 3元7角", + "B. 6元2角", + "C. 7元2角" + ], + "answer": "B", + "solution": "【分析】找回的钱 = 付出的钱 - 商品价钱。小数点前是元,小数点后第一位是角,第二位是分。1 元 = 10 角.\n【详解】付出:20元,商品价钱:13.80元,13.80元=13元 8 角, 1 元 = 10 角。找回:20元-13元8角,把20元分成19元和1元,19元- 13元=6元,1元-8角=2角,故:20元-13元8角=6元2角。故答案为: B", + "knowledge_points": [ + "十元以上人民币的认识与计算" + ], + "source": "23-24一年级下·广东汕头·期末" + }, + { + "id": "115", + "unit": "第五单元认识人民币", + "question_type": "选择题", + "difficulty": 0.85, + "question": "一瓶矿泉水的价格大约是()。", + "options": [ + "A. 2 分", + "B. 2角", + "C. 2元" + ], + "answer": "C", + "solution": "【分析】根据生活经验及数据的大小选择合适的答案,一瓶矿泉水的价格结合数据2用元比较合适。据此解答.\n【详解】一瓶矿泉水的价格大约是2元。 故答案为: C", + "knowledge_points": [ + "经济问题", + "元,角,分的认识及换算", + "十元以下人民币的认识与计算" + ], + "source": "23-24 一年级下·广东汕头·期末" + }, + { + "id": "116", + "unit": "第五单元认识人民币", + "question_type": "选择题", + "difficulty": 0.85, + "question": "16。(23-24一年级下·新疆克拉玛依·期末)10张![](images/362fbf0d49142efbaf5efe3c7d4fc7c69208c94c0f0fd5a05c8aa83bb9a205a3.jpg),可以换()张![](images/10d64537b77eba5a906137d158abbe4f3838015ca2cb52099238737fcdb8c31d.jpg)", + "options": [ + "A. 1", + "B. 2", + "C. 3" + ], + "answer": "A", + "solution": "【分析】根据题意可知 1 元 = 10 角,将单位换算统一对比即可.\n【详解】2 张 5 角是 1 元, 10 张 5 角可以分成 5 组 2 张,即 5 元。5元 = 5 元,即10张5角可以换1张5元。故答案为: A", + "knowledge_points": [ + "元,角,分的认识及换算", + "十元以下人民币的认识与计算" + ], + "source": "23-24一年级下·新疆克拉玛依·期末" + }, + { + "id": "117", + "unit": "第五单元认识人民币", + "question_type": "选择题", + "difficulty": 0.65, + "question": "乐乐用 10 元钱买一本故事书,找回 4 元 5 角钱,这本故事书是( )。", + "options": [ + "A. 4元5角", + "B. 5元5角", + "C. 6元5角" + ], + "answer": "B", + "solution": "【分析】商品价钱=付出的钱一找回的钱。1元=10角,10元-4元5角,10元分成9元和1元,9元-4元=5元,1元-5角=5角.\n【详解】10元-4元5角 = 5元5角 这本故事书5元5角。故答案为: B", + "knowledge_points": [ + "十元以下人民币的认识与计算" + ], + "source": "23-24一年级下·辽宁鞍山·期末" + }, + { + "id": "118", + "unit": "第五单元认识人民币", + "question_type": "选择题", + "difficulty": 0.65, + "question": "小明一家5个人坐公交车去动物园玩,车费每人1元,则共需支付车费()。", + "options": [ + "A. 1 张 5 角", + "B. 5 张 1 元", + "C. 5 张 5 元" + ], + "answer": "B", + "solution": "【分析】小明一家 5 个人坐公交车去动物园玩,车费每人 1 元,说明共需要 5 元, 5 张 1 元就是 5 元,据此解答.\n【详解】小明一家 5 个人坐公交车去动物园玩,车费每人 1 元,则共需支付车费 5 元,也就是 5 张 1 元。故答案为: B", + "knowledge_points": [ + "十元以下人民币的认识与计算" + ], + "source": "23-24一年级下·甘肃兰州·期末" + }, + { + "id": "119", + "unit": "第五单元认识人民币", + "question_type": "选择题", + "difficulty": 0.85, + "question": "下面钱数最多的是 ( )。", + "options": [ + "A. 3 张 5 元", + "B. 1 张 20 元", + "C. 10 张 1 元" + ], + "answer": "B", + "solution": "【分析】依次将各选项中人民币的面值相加计算出总面值,再根据整数比较大小的方法比较,选出最多的即可.\n【详解】A。 5元+5元+5元=15元;B. 1 张 20 元是 20 元;C. 1 元 +1 元 +1 元 +1 元 +1 元 +1 元 +1 元 +1 元 +1 元 = 10 元。20元\u003e15元\u003e10元,钱数最多的是 20 元。故答案为: B", + "knowledge_points": [ + "十元以下人民币的认识与计算", + "十元以上人民币的认识与计算" + ], + "source": "23-24 一年级下·河北保定·期末" + }, + { + "id": "120", + "unit": "第五单元认识人民币", + "question_type": "选择题", + "difficulty": 0.65, + "question": "一张![](images/19a6fe83b0180c432624b1ea30b9b7167bac2c4411f620315fcbf2ddd4b5e1d1.jpg)可以换()张![](images/cffd22472d0a6ad94df8cb4d9db0683e5a92b86ecdf6a17a6552242a0ab8514e.jpg)", + "options": [ + "A. 4", + "B. 2", + "C. 3" + ], + "answer": "B", + "solution": "【分析】10元+10元=20元,一张20元的可以换2张10元的,据此得出结论即可.\n【详解】根据分析知:一张![](images/d65953c7f0949d9f28dc26a100eec936bd30337c48d1999145387f0180a1dd13.jpg)可以换2张![](images/f598a0b8084e7ec26a2963d620912f436effdd7dda3768cbf96ab455da97fa8f.jpg)故答案为: B", + "knowledge_points": [ + "十元以上人民币的认识与计算" + ], + "source": "23-24 一年级下·甘肃平凉·期末" + }, + { + "id": "121", + "unit": "第五单元认识人民币", + "question_type": "选择题", + "difficulty": 0.85, + "question": "一块橡皮的价格大约是 ( )。", + "options": [ + "A. 9元", + "B. 8角", + "C. 7 分" + ], + "answer": "B", + "solution": "【分析】人民币的单位有:元,角,分。橡皮的价格较便宜,一般用角作单位,由此解答.\n【详解】A。9元大约为一本书的价格,不符合题意;B. 8角大约为一块橡皮的价格,符合题意;C. 7 分的价格买不了一块橡皮。一块橡皮的价格大约是 8 角。故答案为: B", + "knowledge_points": [ + "元,角,分的认识及换算" + ], + "source": "23-24 一年级下·湖南益阳·期末" + }, + { + "id": "122", + "unit": "第五单元认识人民币", + "question_type": "选择题", + "difficulty": 0.65, + "question": "下列说法正确的是 ( )。", + "options": [ + "A. \"44\"左边的\"4\"和右边的\"4\"意思相同", + "B. 十位上是 2 的两位数只有 9 个", + "C. 人民币的单位有元,角,分" + ], + "answer": "C", + "solution": "【分析】一个两位数左边的数位是十位,十位是几表示几个十,右边的数位是个位,个位是几表示几个一;十位上是 2 的数有 20, 21, 22, 23, 24, 25, 26, 27, 28, 29,共 10 个;人民币的单位有元,角,分;据此得出结论即可.\n【详解】A。 \"44\"左边的\"4\"表示 4 个十,右边的\"4\"表示 4 个一,原题结论错误,不符合题意;B. 十位上是 2 的数有 20, 21, 22, 23, 24, 25, 26, 27, 28, 29,共 10 个,原题结论错误,不符合题意;C. 人民币的单位有元,角,分。说法正确,符合题意。故答案为: C", + "knowledge_points": [ + "100以内数的组成", + "元,角,分的认识及换算" + ], + "source": "23-24 一年级下·山西太原·期末" + }, + { + "id": "123", + "unit": "第五单元认识人民币", + "question_type": "选择题", + "difficulty": 0.85, + "question": "一本故事书 32 元,如果全部用 10 元的人民币付钱,至少要付 ( ) 张。", + "options": [ + "A. 32", + "B. 4", + "C. 2" + ], + "answer": "B", + "solution": "【分析】根据题意,全付10元,也就是付出的钱数要大于或等于32元。32元里面有3个10元,剩下的2元还需要1张10元,共需要4张。由此解答.\n【详解】由分析可知,一本故事书 32 元,如果全部用 10 元的人民币付钱,至少需要付 4 张。故答案为: B", + "knowledge_points": [ + "十元以上人民币的认识与计算" + ], + "source": "23-24 一年级下·浙江温州·期末" + }, + { + "id": "124", + "unit": "第五单元认识人民币", + "question_type": "选择题", + "difficulty": 0.65, + "question": "一盒闽西八大干88元,妈妈带的全是20元的人民币,买这样的一盒至少要付()张。", + "options": [ + "A. 4", + "B. 5", + "C. 6", + "D. 8" + ], + "answer": "B", + "solution": "【分析】根据题意,全付20元,也就是付出的钱数要大于或等于 88 元。4 张 20 元是 80 元,不够付,所以应该再付 1 张.\n【详解】由分析可知,一盒闽西八大干 88 元,妈妈带的全是 20 元的人民币,买这样的一盒至少要付 5 张。故答案为: B", + "knowledge_points": [ + "十元以上人民币的认识与计算" + ], + "source": "23-24一年级下·福建龙岩·期末" + }, + { + "id": "125", + "unit": "第五单元认识人民币", + "question_type": "选择题", + "difficulty": 0.65, + "question": "一张 50 元可以换几张 20 元和几张 10 元。下面不可行的是 ( )。", + "options": [ + "A. 1, 2", + "B. 2, 1", + "C. 1, 3" + ], + "answer": "A", + "solution": "【分析】一张 50 元可以换 2 张 20 元和 1 张 10 元,也可以换 1 张 20 元和 3 张 10 元,据此得出结论即可.\n【详解】A。选项1张20元和2张10元是40元,符合题意;B。选项2张20元和1张10元是50元,不符合题意;C. 选项 1 张 20 元和 3 张 10 元是 50 元,不符合题意;故答案为:A", + "knowledge_points": [ + "十元以上人民币的认识与计算" + ], + "source": "23-24 一年级下·山东菏泽·期末" + }, + { + "id": "126", + "unit": "第五单元认识人民币", + "question_type": "选择题", + "difficulty": 0.85, + "question": "一本书 9 元 6 角,妈妈付了 10 元,应找回 ( )。", + "options": [ + "A. 1元4角", + "B. 4角", + "C. 4 分" + ], + "answer": "B", + "solution": "【分析】人民币的简单计算,元减元,角减角,若角不够减,则跟元借1,再根据1元=10角进行计算即可.\n【详解】10元-9元6角=4角;所以应找回 4 角。故答案为: B", + "knowledge_points": [ + "元,角,分的认识及换算", + "十元以下人民币的认识与计算" + ], + "source": "23-24 一年级下·河南三门峡·期末" + }, + { + "id": "127", + "unit": "第五单元认识人民币", + "question_type": "选择题", + "difficulty": 0.85, + "question": "一件普通上衣的价格可能是()。", + "options": [ + "A. 12 分", + "B. 36角", + "C. 48元" + ], + "answer": "C", + "solution": "【分析】本题考查人民币的认识。根据生活常识,结合实际要求,据此选择合适的单位.\n【详解】一件普通上衣的价格可能是 48 元。故答案为: C", + "knowledge_points": [ + "元,角,分的认识及换算" + ], + "source": "23-24 一年级下·河北邢台·期末" + }, + { + "id": "128", + "unit": "第五单元认识人民币", + "question_type": "选择题", + "difficulty": 0.85, + "question": "1 支水彩笔 3 元 2 角,小兰想买 3 支,至少需要带 ( ) 元。", + "options": [ + "A. 4", + "B. 9", + "C. 10" + ], + "answer": "C", + "solution": "【分析】根据题意可知:求出3支水彩笔一共多少元。然后再选项中选出要大于这三支共花的钱.\n【详解】3元2角+3元2角=6元4角;6元4角+3元2角=9元6角则至少带 10 元。故答案为: C", + "knowledge_points": [ + "十元以下人民币的认识与计算" + ], + "source": "23-24 一年级下·湖南株洲·期末" + }, + { + "id": "129", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.65, + "question": "1 元 -2 角 = ( )角 5角+6角=( )元( )角 6角7分 = ( ) 分 3元5角-9角 = ( )元( )角", + "options": [ + + ], + "answer": "8;1;1;67;2;6", + "solution": "【分析】(1)根据元和角的进率,1元 = 10 角,将单位统一,再进行相减;(2) 5 角和 6 角单位统一,计算出结果是 11 角,根据 10 角 = 1 元, 11 = 10 + 1,所以 11 角 = 1 元 1 角;(3) 根据角和分的进率, 1 角 = 10 分,换算即可;(4) 根据元和角的进率, 1 元 = 10 角,将单位统一,即 3 元 5 角 = 35 角,再进行相减, 35 - 9 = 26 角,把得到的结果根据 10 角 = 1 元换算即可.\n【详解】(1)1元 = 10 角, 10 - 2 = 8 角,所以1元-2角 = 8 角;(2) 5 角 + 6 角 = 11 角, 11 角 = 1 元 1 角,所以 5 角 + 6 角 = 1 元 1 角 (3) 6角 = 60 分, 60 + 7 = 67 分,所以 6 角 7 分 = 67 分;(4) 3元5角 = 35 角, 35 - 9 = 26 角, 26角 = 2 元6角。", + "knowledge_points": [ + "元,角,分的认识及换算", + "十元以下人民币的认识与计算" + ], + "source": "22-23 一年级下·江西吉安·期末" + }, + { + "id": "130", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.65, + "question": "在括号里填上合适的数。54角 = ( ) 元( )角 7元 = ( )角 40分=( )角 3元+5元2角=()元( )角", + "options": [ + + ], + "answer": "5;4;70;4;8;2", + "solution": "【分析】根据 1 元 = 10 角;1 角 = 10 分换算,计算时元和元相加,角和角相加.\n【详解】54角 = 5 元4角;7元 = 70 角;40分=4角;3元+5元2角=8元2角", + "knowledge_points": [ + "元,角,分的认识及换算", + "十元以下人民币的认识与计算" + ], + "source": "23-24 一年级下·河南周口·期末" + }, + { + "id": "131", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.65, + "question": "57 角 = ( ) 元( )角 80 分 = ( ) 角 2元5角-8角=( )角 4元-3角=( )元( )角", + "options": [ + + ], + "answer": "5;7;8;17;3;7", + "solution": "【分析】根据 1 元 = 10 角,1 角 = 10 分换算,计算时元和元相减,角和角相减,不够减时,退 1 元为 10 角进行计算。据此解答即可.\n【详解】57角 = 5 元7角;80分=8角;2元5角-8角=25角-8角=17角;4元-3角=3元10角-3角=3元7角", + "knowledge_points": [ + "元,角,分的认识及换算", + "十元以下人民币的认识与计算" + ], + "source": "22-23 一年级下·江西吉安·期末" + }, + { + "id": "132", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.85, + "question": "一张 50元可以换()张10元 30角 = () 元 6元 = () 角 1元4角 = () 角", + "options": [ + + ], + "answer": "5;3;60;14", + "solution": "【分析】根据 1 元 = 10 角,结合题干要求进行解答即可.\n【详解】一张50元可以换5张10元。30角 = 3元;6元 = 60 角;1元4角 = 14 角", + "knowledge_points": [ + "元,角,分的认识及换算" + ], + "source": "23-24 一年级下·海南省直辖县级单位·期末" + }, + { + "id": "133", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.65, + "question": "3 元=()角;1元 = () 分 65角 = () 元()角 8元+5元 = ()元", + "options": [ + + ], + "answer": "30;100;6;5;13", + "solution": "【分析】根据 1 元 = 10 角, 1 角 = 10 分, 1 元 = 100 分进行单位换算,然后得出结论即可.\n【详解】3元 = 30 角 1元 = 100 分;65角 = 6 元5角 8元 +5 元 = 13 元", + "knowledge_points": [ + "元,角,分的认识及换算" + ], + "source": "23-24 一年级下·广东汕尾·期末" + }, + { + "id": "134", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.85, + "question": "妈妈带了 10 元钱去买菜,买西红柿花了8元5角,找回()元()角。", + "options": [ + + ], + "answer": "1, 5", + "solution": "【分析】由题干可知总金额是 10 元,花了 8 元 5 角,相减即可得出答案.\n【详解】10元-8元5角=1元5角,即找回了1元5角.\n[点睛]掌握对人民币的认识和计算。", + "knowledge_points": [ + "十元以下人民币的认识与计算" + ], + "source": "23-24 一年级下·广西来宾·期末" + }, + { + "id": "135", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.85, + "question": "6 元 9 角 = ( )角 42角 = ( ) 元()角", + "options": [ + + ], + "answer": "69;4;2", + "solution": "【分析】根据 1 元 = 10 角,进行单位换算即可.\n【详解】6元 = 60 角, 6元 9 角 = 69 角 40 角 = 4 元, 42 角 = 4 元 2 角", + "knowledge_points": [ + "元,角,分的认识及换算" + ], + "source": "22-23 一年级下·新疆喀什·期末" + }, + { + "id": "136", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.85, + "question": "一张![](images/fce7c0ba0e66de0670e6e7a5cde5523fa21b96d7cab877401a28b75e52666483.jpg)的人民币可以兑换()张![](images/adee0f3e2eefd8edfa7706da3c0a8fe2729dbde31ec3f0ac3c26b6276b1099f9.jpg)的。", + "options": [ + + ], + "answer": "5", + "solution": "【分析】5 个 20 是 100,所以一张 100 元的人民币可以兑换 5 张 20 元.\n【详解】一张![](images/30f556c3087f945f9bb145b1fbb7915cf1bb172f1f0e278d7525762c9e282c07.jpg)的人民币可以兑换5张![](images/00ae17a14ce7a48aee1a4f092b6ad6237b492c7d9384d3cee68cb2a3856e0c6f.jpg)的。", + "knowledge_points": [ + "元,角,分的认识及换算" + ], + "source": "23-24一年级下·广东汕尾·期末" + }, + { + "id": "137", + "unit": "第五单元认识人民币", + "question_type": "判断题", + "difficulty": 0.85, + "question": "2 张 1 元,2 张 5角,5张1角组成4元。()", + "options": [ + + ], + "answer": "×", + "solution": "【分析】2 张 1 元是 2 元,2 张 5 角是 1 元,5 张 1 角是 5 角, 2 元 + 1 元 + 5 角 = 3 元 5 角,合起来组成 3 元 5 角;据此解决.\n【详解】由题意分析得:2 张 1 元,2 张 5 角,5 张 1 角组成 3 元 5 角;原说法错误。故答案为: ×", + "knowledge_points": [ + "十元以下人民币的认识与计算" + ], + "source": "23-24 一年级下·贵州黔东南·期末" + }, + { + "id": "138", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.85, + "question": "38。(23-24一年级下·山东临沂·期末)40角 = ( ) 元2元8角 = ( )角", + "options": [ + + ], + "answer": "4 ,28", + "solution": "【分析】根据1元 = 10 角换算即可.\n【详解】40角 = 4 元;2元8角 = 20 角 +8 角 = 28 角。", + "knowledge_points": [ + "元,角,分的认识及换算", + "十元以下人民币的认识与计算" + ], + "source": "23-24一年级下·山东临沂·期末" + }, + { + "id": "139", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.65, + "question": "在括号里填 \"\u003c\"\"=\"或 \" \u003e \" 。100( )98        36( )30+5        46角( )46元 58( )85          5元7角( )57角", + "options": [ + + ], + "answer": "\u003e;\u003e;\u003c;\u003c;=", + "solution": "【分析】比较数的大小时,位数多的数就大;位数相同比较最高位,最高位大的数就大;最高位相同比较下一位,直到比较出结果为止。第 1, 4 题直接比较;第 2 题计算出结果再比较;第 3, 5 题先统一单位再比较.\n【详解】 100 \u003e 98;30 + 5 = 35;36 \u003e 35,则 36 \u003e 30 + 5;1元 = 10 角;46角 = 4 元6角;4元6角 \u003c 46 元,则46角\u003c46元;58 \u003c 85, 5元7角 = 57 角。", + "knowledge_points": [ + "100 以内数的比大小", + "整十数加,减一位数", + "元,角,分的认识及换算" + ], + "source": "23-24 一年级下·山东临沂·期末" + }, + { + "id": "140", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.85, + "question": "在括号里填上合适的数。1元 = ( )角 27角 = () 元() 角", + "options": [ + + ], + "answer": "10;2;7", + "solution": "【分析】根据1元 = 10 角,换算填写即可.\n【详解】1元 = 10 角;27角 = 20 角 +7 角 = 2 元7角。", + "knowledge_points": [ + "元,角,分的认识及换算", + "十元以下人民币的认识与计算" + ], + "source": "23-24 一年级下·山西晋中·期末" + }, + { + "id": "141", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.85, + "question": "98 分=( )角()分。", + "options": [ + + ], + "answer": "9, 8", + "solution": "【分析】根据1角 = 10 分换算填写即可.\n【详解】98分 = 90 分 +8 分 = 9 角8分。", + "knowledge_points": [ + "元,角,分的认识及换算" + ], + "source": "23-24 一年级下·山东临沂·期末" + }, + { + "id": "142", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.85, + "question": "一支铅笔 5 角, 1 枚![](images/d34cc679c273f10d9dccf2c364e42b79ea43d2b7f47401eada43a39b0224dda2.jpg)可以买( )支这样的铅笔。", + "options": [ + + ], + "answer": "2", + "solution": "【分析】![](images/da295428ce0a09f9d33bf50a9526186b0c4e678e5ed8ed5cf5e08eaac1b9d900.jpg)这是一枚 1 元的硬币,2 个 5 角就是 10 角,即 1 元,所以,一枚 1 元的硬币可以买 2 支 5 角的铅笔。1元 = 10 角.\n【详解】5角+5角=10角;10角 = 1 元;1枚![](images/aec80962d0035f5401a1bf8f782ecfede0f18c86528fad25b304787a66b12944.jpg)可以买2支这样的铅笔。", + "knowledge_points": [ + "元,角,分的认识及换算", + "十元以下人民币的认识与计算" + ], + "source": "23-24一年级下·湖北孝感·期末" + }, + { + "id": "143", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.85, + "question": "4元6角 =( )角 68分=( )角( )分 7元5角+6角=( )元( )角 5元+2元2角 = ()元( )角", + "options": [ + + ], + "answer": "46;6;8;8;1;7;2", + "solution": "【分析】根据 1 元 = 10 角,1 角 = 10 分换算,计算时元和元相加,角和角相加,相加满 10 角进为 1 元.\n【详解】4元6角 = 40 角 +6角 = 46 角;68分 = 60 分+8分 = 6 角8分;7元5角+6角=8元1角;5元+2元2角=7元2角。", + "knowledge_points": [ + "元,角,分的认识及换算", + "十元以下人民币的认识与计算" + ], + "source": "23-24一年级下·湖北孝感·期末" + }, + { + "id": "144", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.85, + "question": "在括号里填上合适的数。3元5角 = ( )角 100分 = ( )元 6元+3元8角 = ( )元( )角", + "options": [ + + ], + "answer": "35;1;9;8", + "solution": "【分析】根据 1 元 = 10 角;1 元 = 100 分换算,计算时元和元相加,角和角相加.\n【详解】3元5角 = 30 角 +5 角 = 35 角;100分=1元;6元+3元8角=9元8角。", + "knowledge_points": [ + "元,角,分的认识及换算", + "十元以下人民币的认识与计算" + ], + "source": "23-24 一年级下·湖南张家界·期末" + }, + { + "id": "145", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.85, + "question": "3元=( )角 21角 = ( ) 元( )角", + "options": [ + + ], + "answer": "30;2;1", + "solution": "【分析】根据 1 元 = 10 角,可对每道题进行解答.\n【详解】3元 = 30 角, 21角 = 20 角 + 1角 = 2 元 1角。", + "knowledge_points": [ + "元,角,分的认识及换算" + ], + "source": "23-24一年级下·贵州黔西·期末" + }, + { + "id": "146", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.85, + "question": "8 元 = ( ) 角 90分 = ( ) 角 7元4角 = ( ) 角", + "options": [ + + ], + "answer": "80;9;74", + "solution": "【分析】根据 \"1 元 = 10 角, 1 角 = 10 分\" 及整数加减法的计算法则来解决此题.\n【详解】1元 = 10 角,故, 8元 = 80 角;10 分 = 1 角,故, 90 分 = 9 角;7元 = 70 角, 70 + 4 = 74,故, 7 元 4 角 = 74 角。", + "knowledge_points": [ + "整十数加,减一位数", + "元,角,分的认识及换算" + ], + "source": "23-24 一年级下·贵州铜仁·期末" + }, + { + "id": "147", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.85, + "question": "一张100元可以换( )张20元,一张10元可以换( )张5元,一张1元可以换( )张1角。", + "options": [ + + ], + "answer": "5;2;10", + "solution": "[analysis]5 个 20 是 100,则,一张 100 元的人民币可以换 5 张 20 元的;2 个 5 是 10,则,一张 10 元的人民币可以换 2 张 5 元的;1 元 = 10 角, 10 角里面有 10 个 1 角,也就是一张 1 元可以换 10 张 1 角;据此解决.\n【详解】由题意分析得:一张 100 元可以换 5 张 20 元,一张 10 元可以换 2 张 5 元,一张 1 元可以换 10 张 1 角。", + "knowledge_points": [ + "元,角,分的认识及换算", + "十元以下人民币的认识与计算", + "十元以上人民币的认识与计算" + ], + "source": "23-24一年级下·黑龙江哈尔滨·期末" + }, + { + "id": "148", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.85, + "question": "7 角 8 分 = ( )分 5元1角 = ( ) 角", + "options": [ + + ], + "answer": "78, 51", + "solution": "【分析】根据1元 = 10 角;1角 = 10 分换算即可.\n【详解】7角8分 = 70 分 +8 分 = 78 分;5元1角 = 50 角 +1 角 = 51 角。", + "knowledge_points": [ + "元,角,分的认识及换算", + "十元以下人民币的认识与计算" + ], + "source": "23-24 一年级下·甘肃天水·期末" + }, + { + "id": "149", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.85, + "question": "3 张 1 角的纸币和 2 张 5 角的纸币合起来是( )角。", + "options": [ + + ], + "answer": "13", + "solution": "【分析】根据题意可知: 3 张 1 角的纸币就是 3 角, 2 张 5 角的纸币就是 10 角, 3 张 1 角加上 2 张 5 角即可.\n【详解】 1 + 1 + 1=3 (角);5 + 5 = 10 (角);3 + 10 = 13 (角)所以3张1角的纸币和2张5角的纸币合起来是(13)角。", + "knowledge_points": [ + "元,角,分的认识及换算", + "十元以下人民币的认识与计算" + ], + "source": "23-24 一年级下·河北张家口·期末" + }, + { + "id": "150", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.85, + "question": "4元2角 =() 角 6角 +7角 =()元()角1元-6角 = ( ) 角 5角+1元=( )元角", + "options": [ + + ], + "answer": "42;1;3;4;1;5", + "solution": "【分析】根据\"1元=10角\"来换算单位,根据整数加减法的计算法则来计算;据此解决.\n【详解】4元 = 40 角, 40角 +2角 = 42角,故, 4元2角 = 42角;6角 +7 角 = 13 角,1元 = 10 角,13角 -10 角 = 3 角,故,6角+7角=1元3角;1元=10角,10角-6角=4角,故,1元-6角=4角;5角+1元=1元5角。", + "knowledge_points": [ + "元,角,分的认识及换算", + "十元以下人民币的认识与计算" + ], + "source": "23-24 一年级下·黑龙江哈尔滨·期末" + }, + { + "id": "151", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.85, + "question": "4 角 = ( ) 分 6元 = 60 角 5 元 4 角 = ( )角", + "options": [ + + ], + "answer": "40;6;54", + "solution": "【分析】根据1角 = 10 分,1元 = 10 角换算即可.\n【详解】4角 = 40 分;6元 = 60 角;5元4角 = 50 角 +4 角 = 54 角。", + "knowledge_points": [ + "元,角,分的认识及换算", + "十元以下人民币的认识与计算" + ], + "source": "23-24 一年级下·贵州铜仁·期末" + }, + { + "id": "152", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.85, + "question": "30 分=( )角 5元6角 = ( ) 角", + "options": [ + + ], + "answer": "3, 56", + "solution": "【分析】根据 1 元 = 10 角, 1 角 = 10 分换算即可.\n【详解】30分=3角;5元6角 = 50 角 +6角 = 56 角。", + "knowledge_points": [ + "元,角,分的认识及换算", + "十元以下人民币的认识与计算" + ], + "source": "23-24 一年级下·四川南充·期末" + }, + { + "id": "153", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.85, + "question": "在括号里填上\"\u003e\" \"\u003c\"或\"=\"。67( )7689( )8554+0( )50+44角6分( )4元6角", + "options": [ + + ], + "answer": "\u003c;\u003e;=;\u003c", + "solution": "【分析】先计算出每个算式的结果或先统一单位,然后比较大小即可。整数比较大小方法: ①位数多的数大于位数少的数;②位数相同的,先比较最高位上的数,最高位上大的,数就大,最高位数相同的,就比较下一位,以此类推。 1元 = 10 角, 1角 = 10 分.\n【详解】 67 \u003c 76;89 \u003e 85;54 + 0 = 54, 50 + 4 = 54 故 54 + 0 = 50 + 4;= 46 角,故, 4角6分 \u003c 4 元6角。", + "knowledge_points": [ + "100 以内数的比大小", + "整十数加,减一位数", + "元,角,分的认识及换算" + ], + "source": "23-24 一年级下·四川南充·期末" + }, + { + "id": "154", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.85, + "question": "4 元 = ( )角 18角 = ( ) 元()角 2角3分 = ( )分 8角+3角 = ( )元( )角", + "options": [ + + ], + "answer": "40;1;8;23;1;1", + "solution": "【分析】根据 1 元 = 10 角;1 角 = 10 分换算计算即可.\n【详解】4元 = 40 角;18角 = 10 角 +8 角 = 1 元8角;2角3分 = 20 分+3分 = 23 分;8角+3角=11角=1元1角。", + "knowledge_points": [ + "元,角,分的认识及换算", + "十元以下人民币的认识与计算" + ], + "source": "23-24 一年级下·吉林四平·期末" + }, + { + "id": "155", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.85, + "question": "30 分=( )角 7角 = ( ) 分 2 元 8 角 = ( ) 角", + "options": [ + + ], + "answer": "3;70;28", + "solution": "【分析】根据1元 = 10 角;1角 = 10 分换算即可.\n【详解】30分 = 3 角;7角 = 70 分;2元8角 = 20 角 +8 角 = 28 角。", + "knowledge_points": [ + "元,角,分的认识及换算", + "十元以下人民币的认识与计算" + ], + "source": "23-24 一年级下·广东汕头·期末" + }, + { + "id": "156", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.85, + "question": "39 角 = ( ) 元( )角 5角3分+7分 = ( )角", + "options": [ + + ], + "answer": "3;9;6", + "solution": "【分析】根据 1 元 = 10 角,1 角 = 10 分进行换算。计算时角和角相加,分和分相加,相加满 10 分进为 1 角.\n【详解】39角 = 30 角 +9 角 = 3 元9角;5角3分+7分=60分=6角", + "knowledge_points": [ + "元,角,分的认识及换算", + "十元以下人民币的认识与计算" + ], + "source": "23-24 一年级下·广东肇庆·期末" + }, + { + "id": "157", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.85, + "question": "5 元 = ( ) 角 9角 +50 角 = ( )元( )角", + "options": [ + + ], + "answer": "50;5;9", + "solution": "【分析】根据 1 元 = 10 角换算即可。计算时元和元相加,角和角相加.\n【详解】5元 = 50 角;9角+50角=9角+5元=5元9角。", + "knowledge_points": [ + "元,角,分的认识及换算", + "十元以下人民币的认识与计算" + ], + "source": "23-24 一年级下·山东济宁·期末" + }, + { + "id": "158", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.85, + "question": "在括号里填上合适的数。4元 = ( )角56角 = ( )元( )角 1米-40厘米=()厘米 10元-7元2角=()元()角", + "options": [ + + ], + "answer": "40;5;6;60;2;8", + "solution": "【分析】根据 1 元 = 10 角, 1 米 = 100 厘米,将单位换算统一.\n【详解】4元 = (40)角;56角 = 50 角 +6 角 = (5)元(6)角;1 米=100 厘米, 100 - 40 = 60 厘米,则 1 米-40 厘米=(60) 厘米;1元 = 10 角, 10 元 = 9 元 +10 角, 9 元 10 角 -7 元 2 角 = 2 元8角,则10元-7元2角 = (2)元(8)角。", + "knowledge_points": [ + "元,角,分的认识及换算", + "十元以下人民币的认识与计算" + ], + "source": "23-24 一年级下·山东济南·期末" + }, + { + "id": "159", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.65, + "question": "9 元 -2 元 4 角 = ( )元( )角 7元4角-1元2角 = ( )元( )角", + "options": [ + + ], + "answer": "6662", + "solution": "【分析】本题考查人民币的简单计算。1元 = 10 角,元减元,角减角,单位不同先换算成单位相同的再减.\n【详解】1元 = 10 角, 9 元 = 90 角, 2 元 4 角 = 20 角 + 4 角 = 24 角,9元-2元4角=90角-24角=66角,66角=60角+6角=6元6角。故: 9元-2元4角=6元6角。7元4角-1元2角=6元2角。", + "knowledge_points": [ + "十元以下人民币的认识与计算" + ], + "source": "23-24 一年级下·广东汕头·期末" + }, + { + "id": "160", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.85, + "question": "5 张 10 元, 1 张 5 元, 3 张 5 角,合起来是( )元( )角。", + "options": [ + + ], + "answer": "56;5", + "solution": "【分析】5 个 10 就是 50;5 + 5 + 5 = 15,则, 3 个 5 的和是 15;故,5 张 10 元就是 50 元,3 张 5 角就是 15 角(15 角 = 1 元(5 角), 然后把所有的钱数加起来,求出和,即可解决。1元 = 10 角.\n【详解】5 张 10 元就是 50 元, 3 张 5 角是 1 元 5 角;50元+5元+1元5角 = 55 元 +1 元 5 角 = 56 元 5 角;即,5张10元,1张5元,3张5角,合起来是56元5角。", + "knowledge_points": [ + "元,角,分的认识及换算", + "十元以下人民币的认识与计算" + ], + "source": "23-24 一年级下·山东济南·期末" + }, + { + "id": "161", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.65, + "question": "想一想,填一填。1元8角 = ( ) 角 43角 = ( )元( )角 11角一3角 = ( ) 角 5角 +8 角 = ( )元( )角", + "options": [ + + ], + "answer": "18;4;3;8;1;3", + "solution": "【分析】本题考查人民币的简单计算及换算。根据 1 元 = 10 角即可解答.\n【详解】1元8角 = 10 角 +8 角 = 18 角;43 角 = 40 角 +3 角 = 4 元 3 角;11角-3角=8角;5角+8角=13角=10角+3角=1元3角。", + "knowledge_points": [ + "元,角,分的认识及换算", + "十元以下人民币的认识与计算" + ], + "source": "23-24 一年级下·新疆克拉玛依·期末" + }, + { + "id": "162", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.85, + "question": "5 元 = ( )角( )张 50元=1 张 100元( )分=1角", + "options": [ + + ], + "answer": "50;2;10", + "solution": "【分析】1元 = 10 角;1角 = 10 分;2个50元是100元;据此解决此题即可.\n【详解】由题意分析得:1元 = 10 角,故, 5 元 = 50 角;2 张![](images/fe96317e802ef7f8ed33571e179a37d87453149bdd4057f9ae44ed1440f3764c.jpg)= 1 张![](images/99503fb531f9445c8f0aef446f9dc7ba555264221cc732804d74325dc86d300c.jpg);1 角 = 10 分,即, 10 分 = 1 角。", + "knowledge_points": [ + "元,角,分的认识及换算", + "十元以上人民币的认识与计算" + ], + "source": "23-24 一年级下·青海果洛·期末" + }, + { + "id": "163", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.65, + "question": "1 元 = ( )角 30角 = ( ) 元 1元5角 = ( )角 68角 = ( ) 元( )角", + "options": [ + + ], + "answer": "10;3;15;6;8", + "solution": "【分析】本题考查人民币的简单计算及换算。根据 1 元 = 10 角即可解答.\n【详解】1元 = 10 角;30角 = 10 角 + 10 角 + 10 角 = 3元;1元5角 = 10 角 +5角 = 15 角;68角=60角+8角=6元8角", + "knowledge_points": [ + "元,角,分的认识及换算", + "十元以下人民币的认识与计算" + ], + "source": "23-24 一年级下·辽宁鞍山·期末" + }, + { + "id": "164", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.65, + "question": "算一算,填一填。2元5角 = ( ) 角8元5角-3角 = ( ) 元()角 3元3角+7角=( )元13角=( )元( )角", + "options": [ + + ], + "answer": "25;8;2;4;1;3", + "solution": "【分析】1元 = 10 角,元与元相加减,角与角相加减,满 10 角换算成 1 元.\n【详解】2元5角 = 20 角 +5 角 = 25 角;8元5角-3角=8元2角;3元3角+7角=3元+10角=3元+1元=4元;13角 = 10 角 +3 角 = 1 元3角", + "knowledge_points": [ + "十元以下人民币的认识与计算" + ], + "source": "23-24 一年级下·浙江嘉兴·期末" + }, + { + "id": "165", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.85, + "question": "50 角 = ( ) 元 6角8分 = ( ) 分1元7角 = ( )角", + "options": [ + + ], + "answer": "5;68;17", + "solution": "【分析】根据 \"1 元 = 10 角, 1 角 = 10 分\" 及整数加减法的计算法则来解决此题.\n【详解】10角 = 1 元,故,50角 = 5 元;6角 = 60 分, 60分 + 8分 = 68分,故, 6角 8 分 = 68 分;1元 = 10 角, 10角 +7角 = 17角,故, 1元7角 = 17角。", + "knowledge_points": [ + "整十数加,减一位数", + "元,角,分的认识及换算" + ], + "source": "23-24 一年级下·浙江宁波·期末" + }, + { + "id": "166", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.65, + "question": "32 角 = ( ) 元( )角 5元 = ( )角 3.60元=( )元( )角 100分=( )角", + "options": [ + + ], + "answer": "3;2;50;3;6;10", + "solution": "【分析】1元 = 10角,1角 = 10分,1元 = 100分,根据元角分之间的进率换算单位即可。3.60元,点前边是元,后边是角.\n【详解】32角 = 30 角 +2 角 = 3 元2角;5元 = 50 角;3.60元=3元6角;100分=10角。", + "knowledge_points": [ + "元,角,分的认识及换算", + "十元以下人民币的认识与计算" + ], + "source": "23-24 一年级下·新疆昌吉·期末" + }, + { + "id": "167", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.65, + "question": "8元=( )角 12角 = ( ) 元( ) 角 6角 = ( )分 1元8角 +2 角 = ( )元", + "options": [ + + ], + "answer": "80;1;2;60;2", + "solution": "【分析】根据1元 = 10 角,1角 = 10 分进行单位换算,相同单位的可以直接加减,满十角要换算成 1 元,据此得出结论即可.\n【详解】8元 = 80 角 12角 = 1 元2角;6角 = 60 分 1元8角 +2 角 = 1 元10角 = 2 元", + "knowledge_points": [ + "元,角,分的认识及换算" + ], + "source": "23-24一年级下·甘肃平凉·期末" + }, + { + "id": "168", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.65, + "question": "4 元 9 角 = ( )角 84角 = ( ) 元( )角", + "options": [ + + ], + "answer": "49;8;4", + "solution": "【分析】本题考查人民币的换算。根据 1 元 = 10 角即可解答.\n【详解】4元9角 = 40 角 +9角 = 49 角;84角 = 80 角 +4 角 = 8 元4角。", + "knowledge_points": [ + "元,角,分的认识及换算" + ], + "source": "23-24 一年级下·河南周口·期末" + }, + { + "id": "169", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.85, + "question": "一张 100 元能换( ) 张 10 元,也可以换 ( ) 张 20 元。", + "options": [ + + ], + "answer": "10;5", + "solution": "【分析】人民币的兑换即总面值不变。10 张 10 元就是 100 元,5 张 20 元就是 100 元。由此解答.\n【详解】一张100元能换10张10元,也可以换5张20元。", + "knowledge_points": [ + "元,角,分的认识及换算" + ], + "source": "23-24 一年级下·山东菏泽·期末" + }, + { + "id": "170", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.65, + "question": "在括号里填上合适的数。39角 = ( ) 元( )角 26分 = ( )角( )分 6角+2元5角 = ( )元( )角 4元6角 = ( )角", + "options": [ + + ], + "answer": "3;9;2;6;3;1;46", + "solution": "【分析】根据1元 = 10 角,1角 = 10 分换算即可.\n【详解】39角 = 30 角 +9 角 = 3 元9角;26分 = 20 分 +6 分 = 2 角6分;6角+2元5角=2元+11角=2元+10角+1角=3元1角;4元6角 = 40 角 +6角 = 46 角。", + "knowledge_points": [ + "元,角,分的认识及换算", + "十元以下人民币的认识与计算" + ], + "source": "23-24 一年级下·山东菏泽·期末" + }, + { + "id": "171", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.85, + "question": "一张![](images/7eef42bd836f6684f1e366c9fb57a134744ca6574989e7fde2cd17981d8ea28d.jpg)可以换( )张![](images/82f5c6cf4e5f8585e680edf0321f09029aac96f8c7069fb36ebfb0548cd950c5.jpg)。一张![](images/e4c92dc622fb1b923a6227b1d63cb27495fbf108f25ea530da84ca9fb065c56e.jpg)可以换( )枚![](images/216e9ddf81b0bbb2ec925c757423ecb0a5b9bee179c46cae5b7195af4cbf8a8d.jpg)。", + "options": [ + + ], + "answer": "50;10", + "solution": "【分析】根据对人民币的认识可知, 50 个 1 元是 50 元;10 个 1 元是 10 元,由此解答.\n【详解】一张50元可以换50张一元。一张10元可以换 10 枚硬币。", + "knowledge_points": [ + "十元以上人民币的认识与计算" + ], + "source": "23-24 一年级下·山东菏泽·期末" + }, + { + "id": "172", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.85, + "question": "16 角 = ( ) 元( )角 2角 +8 角 = ( )元", + "options": [ + + ], + "answer": "1;6;1", + "solution": "【分析】根据 1 元 = 10 角换算,计算时元和元相加,角和角相加.\n【详解】16角 = 10 角 +6 角 = 1 元6角;2角+8角=10角=1元。", + "knowledge_points": [ + "元,角,分的认识及换算", + "十元以下人民币的认识与计算" + ], + "source": "23-24 一年级下·广东潮州·期末" + }, + { + "id": "173", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.65, + "question": "5 元 6 角 = ( )角 45角 = ( ) 元( )角 8元 = ( )角 3元-4角 = ( )元( )角", + "options": [ + + ], + "answer": "56;4;5;80;2;6", + "solution": "【分析】根据 1 元 = 10 角换算,计算时元和元相加减,角和角相加减.\n【详解】5元6角 = 50 角 +6 角 = 56 角;45角 = 40 角 +5 角 = 4 元 5 角;8元 = 80 角;3元-4角=30角-4角=26角=20角+6角=2元6角。", + "knowledge_points": [ + "元,角,分的认识及换算", + "十元以下人民币的认识与计算" + ], + "source": "23-24 一年级下·湖南益阳·期末" + }, + { + "id": "174", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.85, + "question": "8 元 4 角 = ( )角 26角 = ( ) 元( )角 8角一3角 =( )角 7元5角 +4角 = ( )元( )角", + "options": [ + + ], + "answer": "84;2;6;5;7;9", + "solution": "【分析】根据 1 元 = 10 角进行换算,计算时元和元相加减,角和角相加减.\n【详解】8元4角 = 80 角 +4 角 = 84 角;26角 = 20 角 +6角 = 2 元6角;8角-3角=5角;7元5角+4角=7元9角。", + "knowledge_points": [ + "元,角,分的认识及换算", + "十元以下人民币的认识与计算" + ], + "source": "23-24 一年级下·山东菏泽·期末" + }, + { + "id": "175", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.65, + "question": "1 元 = ( )角 6角9分 = ( )分", + "options": [ + + ], + "answer": "10;69", + "solution": "【分析】根据1元 = 10 角,1角 = 10 分换算单位即可.\n【详解】由分析可得:1元 = 10 角;6角9分 = 69 分", + "knowledge_points": [ + "元,角,分的认识及换算" + ], + "source": "23-24 一年级下·广东汕头·期末" + }, + { + "id": "176", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.85, + "question": "36 角 = ( ) 元( )角 8元 = ( )角 5角 +1 元 = ( )元( )角", + "options": [ + + ], + "answer": "3;6;80;1;5", + "solution": "【分析】根据 1 元 = 10 角进行换算,计算时元和元相加,角和角相加.\n【详解】36角 = 30 角 +6 角 = 3 元6角;8元=80角;5角+1元=1元5角。", + "knowledge_points": [ + "元,角,分的认识及换算", + "十元以下人民币的认识与计算" + ], + "source": "23-24 一年级下·江西赣州·期末" + }, + { + "id": "177", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.65, + "question": "3 元 4 角 = ( )角 7角+8角 = ( ) 元()角", + "options": [ + + ], + "answer": "34;1;5", + "solution": "【分析】1元 = 10 角,几元就是几十角;10 角 = 1 元,几十角就是几元,据此换算即可.\n【详解】3元4角 = 30 角 +4 角 = 34 角;7角+8角=15角=10角+5角=1元5角", + "knowledge_points": [ + "元,角,分的认识及换算", + "十元以下人民币的认识与计算" + ], + "source": "23-24 一年级下·湖南怀化·期末" + }, + { + "id": "178", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.85, + "question": "78。(23-24一年级下·新疆克孜勒苏·期末)一张1元可以换( )张5角,一张20元可以换( )张5元。", + "options": [ + + ], + "answer": "2;4", + "solution": "【分析】人民币的兑换即总面值不变。5角+5角=10角=1元;5元+5元+5元+5元=20元,由此解答.\n【详解】一张 1 元可以换 2 张 5 角,一张 20 元可以换 4 张 5 元。", + "knowledge_points": [ + "元,角,分的认识及换算", + "十元以下人民币的认识与计算", + "十元以上人民币的认识与计算" + ], + "source": "23-24一年级下·新疆克孜勒苏·期末" + }, + { + "id": "179", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.85, + "question": "80角 = ( ) 元 6角+9 角 = ( )元( )角 3元5角 = ( )角 5元5角-3元 = ( )元( )角", + "options": [ + + ], + "answer": "8;1;5;35;2;5", + "solution": "【分析】根据 1 元 = 10 角换算,计算时元和元相加减,角和角相加减.\n【详解】80角 = 8 元;6角+9角=15角=1元5角;3元5角 = 30 角 +5 角 = 35 角;5元5角-3元=2元5角。", + "knowledge_points": [ + "元,角,分的认识及换算", + "十元以下人民币的认识与计算" + ], + "source": "23-24一年级下·浙江台州·期末" + }, + { + "id": "180", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.85, + "question": "在括号里填上合适的数。32分=( )角( )分 9角+8角=( )元( )角", + "options": [ + + ], + "answer": "3;2;1;7", + "solution": "【分析】根据1元 = 10 角;1角 = 10 分换算即可.\n【详解】32分 = 30 分 +2 分 = 3 角2分;9角+8角=17角=1元7角。", + "knowledge_points": [ + "元,角,分的认识及换算", + "十元以下人民币的认识与计算" + ], + "source": "23-24 一年级下·福建龙岩·期末" + }, + { + "id": "181", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.85, + "question": "5 角 +9 角 = ( )元 ( )角 4 元 3 角 -2 元 = ( )元 ( )角", + "options": [ + + ], + "answer": "1;4;2;3", + "solution": "【分析】元与元相加减,角与角相加减,满10角换算成1元即可。1元 = 10 角.\n【详解】5角+9角=14角,14角=1元4角,即,5角+9角=1元4角;4元 -2 元 = 2 元,则,4元3角 -2 元 = 2 元3角。", + "knowledge_points": [ + "元,角,分的认识及换算", + "十元以下人民币的认识与计算" + ], + "source": "23-24 一年级下·浙江温州·期末" + }, + { + "id": "182", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.85, + "question": "7 元 4 角 = ( )角 50角 = ( ) 元 64分=( )角( )分 6元=( )角", + "options": [ + + ], + "answer": "74;5;6;4;60", + "solution": "【分析】根据1元 = 10 角;1角 = 10 分换算即可.\n【详解】7元4角 = 70 角 +4角 = 74 角;50角 = 5 元;64分=60分+4分=6角4分;6元 = 60 角。", + "knowledge_points": [ + "元,角,分的认识及换算", + "十元以下人民币的认识与计算" + ], + "source": "23-24 一年级下·山东济宁·期末" + }, + { + "id": "183", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.85, + "question": "8 元 5 角 = ( )角 36 角 = ( )元( )角 4角9分=( )分 15角+7角=( )元( )角", + "options": [ + + ], + "answer": "85;3;6;49;2;2", + "solution": "【分析】根据 1 元 = 10 角, 1 角 = 10 分,结合题干要求进行换算即可。进行简单的人民币计算时要注意,元加元,角加角,满十角变 1 元,据此解答即可.\n【详解】8元5角 = 85 角;36角=3元6角;4角9分 = 49 分;15角+7角=22角=2元2角", + "knowledge_points": [ + "元,角,分的认识及换算", + "十元以下人民币的认识与计算" + ], + "source": "23-24 一年级下·内蒙古鄂尔多斯·期末" + }, + { + "id": "184", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.85, + "question": "73 角 = ( ) 元( )角 6元6角 = ( )角 1元-3角=( )角 5元3角+4角=( )元( )角", + "options": [ + + ], + "answer": "7;3;66;7;5;7", + "solution": "【分析】根据1元 = 10 角进行单位换算即可。人民币简单计算,元加元,角加角,满十角变一元;元减元,角减角,若角不够减则借1元变10角再进行计算即可.\n【详解】73角 = 7 元3角;6元6角 = 66 角;1元=10角,10角-3角=7角,即1元-3角=7角;5元3角+4角=5元7角", + "knowledge_points": [ + "元,角,分的认识及换算", + "十元以下人民币的认识与计算" + ], + "source": "23-24 一年级下·湖南常德·期末" + }, + { + "id": "185", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.65, + "question": "5 元 = ( ) 角 40角 = ( ) 元 7角-1角 = ( ) 角 2元+3角 = ( )角", + "options": [ + + ], + "answer": "50;4;6;23", + "solution": "【分析】1元 = 10 角,据此换算单位,算式中单位不同的先换算单位再计算。如 2 元 +3 角 = 20 角 +3 角 = 23 角.\n【详解】根据分析知:5元 = 50 角 40 角 = 4 元;7角-1角=6角 2元+3角=23角", + "knowledge_points": [ + "元,角,分的认识及换算" + ], + "source": "23-24 一年级下·山东临沂·期末" + }, + { + "id": "186", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.65, + "question": "30 分=( )角 6元8角 = ( ) 角 35角 = ( ) 元()角", + "options": [ + + ], + "answer": "3;68;3;5", + "solution": "【分析】10分=1角,1元=10角,10角=1元,据此换算.\n【详解】30分=3角;6元8角 = 60 角 +8角 = 68 角;35角 = 30 角 +5 角 = 3 元5角", + "knowledge_points": [ + "元,角,分的认识及换算", + "十元以下人民币的认识与计算" + ], + "source": "23-24 一年级下·陕西安康·期末" + }, + { + "id": "187", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.85, + "question": "2 元 8 角 = ( )角 4元3角-2元 = ( )元( )角", + "options": [ + + ], + "answer": "28;2;3", + "solution": "【分析】根据 1 元 = 10 角换算,计算时元和元相减,角和角相减.\n【详解】2元8角 = 20 角 +8 角 = 28 角;4元3角-2元=2元3角。", + "knowledge_points": [ + "元,角,分的认识及换算", + "十元以下人民币的认识与计算" + ], + "source": "23-24 一年级下·河南三门峡·期末" + }, + { + "id": "188", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.85, + "question": "![](images/444109eb9b671068bd033e690d8b4e612c5384a8019e9d09d5b352ee543b8e58.jpg) ![](images/03dac2eb9ffebc403aadade9a9e62c827e0a6e53bd189989b1c0e90086e430ff.jpg) 上图中有一张( )元,一张( )角,合起来是( )元( )角。", + "options": [ + + ], + "answer": "20;5;20;5", + "solution": "【分析】题中左边是 20 元,右边是 5 角,计算时元和元相加,角和角相加.\n【详解】![](images/b1e1a24c44e745bb00445c95da0f5eb060ae0495e6b6da56ac0fe9a69e8ceea1.jpg) ![](images/cc45c846b0939b5fdc9d8e36f79b7d7b4cf6f386f699c2df89665a7eac40cc18.jpg) 上图中有一张 20 元,一张 5 角,合起来是 20 元 5 角。", + "knowledge_points": [ + "十元以下人民币的认识与计算", + "十元以上人民币的认识与计算" + ], + "source": "23-24 一年级下·河南三门峡·期末" + }, + { + "id": "189", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.65, + "question": "亮亮有 10 元钱,买零食花了 5 元 7 角,还剩( )元( )角。", + "options": [ + + ], + "answer": "4;3", + "solution": "【分析】本题考查人民币的计算。剩下的钱 = 付出的钱 - 商品价钱.\n【详解】付出 10 元,零食价钱: 5 元 7 角, 10 元 - 5 元 7 角 =4 元 3 角,所以还剩 4 元 3 角。", + "knowledge_points": [ + "十元以下人民币的认识与计算" + ], + "source": "23-24 一年级下·河北邢台·期末" + }, + { + "id": "190", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.65, + "question": "30 角 = ( )元 27角 = ( )元( )角", + "options": [ + + ], + "answer": "3;2;7", + "solution": "【分析】根据1元 = 10 角换算单位即可.\n【详解】30角 = 3 元;27角 = 2 元7角", + "knowledge_points": [ + "元,角,分的认识及换算" + ], + "source": "23-24 一年级下·河北邯郸·期末" + }, + { + "id": "191", + "unit": "第五单元认识人民币", + "question_type": "判断题", + "difficulty": 0.65, + "question": "小红买一本 16 元的故事书,她付了两张 8 元的人民币。( )", + "options": [ + + ], + "answer": "×", + "solution": "【分析】小红买一本 16 元的故事书,要付的人民币要符合两个条件,一个是付的人民币总值要大于等于 16,另一个要符合实际,也就是实际存在相应数值的人民币,据此解答即可.\n【详解】 8 + 8 = 16 (元) 小红买一本 16 元的故事书,应该付 16 元,但是小红她付了两张 8 元的人民币,人民币的面值没有 8 元,原题说法错误。故答案为: ×", + "knowledge_points": [ + "十元以下人民币的认识与计算", + "十元以上人民币的认识与计算" + ], + "source": "22-23一年级下·江西吉安·期末" + }, + { + "id": "192", + "unit": "第五单元认识人民币", + "question_type": "判断题", + "difficulty": 0.85, + "question": "1 元硬币可以换 10枚1角的硬币,也可以换2枚5角的硬币。()", + "options": [ + + ], + "answer": "√", + "solution": "【分析】根据人民币的认识知识, 1 元 = 10 角,所以 1 元硬币可以换 10 枚 1 角的硬币,也可以换 2 枚 5 角的硬币。据此解答即可.\n【详解】分析可知, 1 元硬币可以换 10 枚 1 角的硬币,也可以换 2 枚 5 角的硬币。所以原题说法正确.\n故答案为: √", + "knowledge_points": [ + "元,角,分的认识及换算" + ], + "source": "23-24 一年级下·河北廊坊·期末" + }, + { + "id": "193", + "unit": "第五单元认识人民币", + "question_type": "判断题", + "difficulty": 0.85, + "question": "小麦同学用一张20元,买了一本18元的书,收银员应给她找回2角钱。()", + "options": [ + + ], + "answer": "×", + "solution": "【分析】根据减法的意义,付出的钱数一书的钱数 = 应找回的钱数,由此计算解答.\n【详解】20 - 18 = 2 (元);收银员应给她找回2元钱,原题说法错误。故答案为: ×", + "knowledge_points": [ + "十元以上人民币的认识与计算" + ], + "source": "22-23一年级下·新疆喀什·期末" + }, + { + "id": "194", + "unit": "第五单元认识人民币", + "question_type": "判断题", + "difficulty": 0.65, + "question": "1张![](images/05a7ec7ac2778192abe994fc56852e61056e2ddd40aa6697c7662c259c34ea97.jpg)可以换3张![](images/895a53b9c4a1a3e6ea7731b6c4421dc98ce377acc63b4c720b606074f8446263.jpg)。", + "options": [ + + ], + "answer": "×", + "solution": "【分析】根据学生对人民币面值的认识,100 元等于 2 个 50 元,等于 10 个 10 元,等于 5 个 20 元,结合题干要求进行解答即可.\n【详解】1 张![](images/964bf3c5b4c4e725a711ae419b674f511afe652960aa6d7d27a154e3dcc3cec9.jpg)可以换2张![](images/5bf757ea01c69d0787faf3850d552d1a2b442a1d729d7fd7009768a34d870f93.jpg),原说法错误。故答案为: ×", + "knowledge_points": [ + "十元以上人民币的认识与计算" + ], + "source": "23-24一年级下·贵州铜仁·期末" + }, + { + "id": "195", + "unit": "第五单元认识人民币", + "question_type": "判断题", + "difficulty": 0.65, + "question": "5 元和 50 角同样多。( )", + "options": [ + + ], + "answer": "√", + "solution": "【分析】1元 = 10 角, 5 元 = 50 角,同样多指两个数相等,用 50 角和 50 角进行比较即可解答.\n【详解】1元 = 10 角, 5 元 = 50 角, 50 角 = 50 角,所以 5 元和 50 角同样多是正确的。故答案为: √", + "knowledge_points": [ + "元,角,分的认识及换算" + ], + "source": "23-24 一年级下·贵州铜仁·期末" + }, + { + "id": "196", + "unit": "第五单元认识人民币", + "question_type": "判断题", + "difficulty": 0.85, + "question": "一张20元可以换2张10元。()", + "options": [ + + ], + "answer": "√", + "solution": "【分析】10元+10元=20元,故,一张20元可以换2张10元.\n【详解】由题意分析得:一张 20 元可以换 2 张 10 元;此说法正确.\n故答案为:√", + "knowledge_points": [ + "元,角,分的认识及换算" + ], + "source": "23-24一年级下·广东汕头·期末" + }, + { + "id": "197", + "unit": "第五单元认识人民币", + "question_type": "判断题", + "difficulty": 0.85, + "question": "6 元 5 角 +4 角 = 6元9角。()", + "options": [ + + ], + "answer": "√", + "solution": "【分析】人民币之间进行计算时,元和元相加减,角和角相加减.\n【详解】6元5角+4角=6元9角。原题说法正确。故答案为:√", + "knowledge_points": [ + "十元以下人民币的认识与计算" + ], + "source": "23-24 一年级下·山东菏泽·期末" + }, + { + "id": "198", + "unit": "第五单元认识人民币", + "question_type": "判断题", + "difficulty": 0.85, + "question": "50 张 1 元人民币和 5 张 10 元人民币的面值相等。( )", + "options": [ + + ], + "answer": "√", + "solution": "【分析】50 张 1 元是 50 元, 5 张 10 元是 50 元,面值相等,由此解答.\n【详解】由分析可知, 50 张 1 元人民币和 5 张 10 元人民币的面值相等。原题说法正确。故答案为: √", + "knowledge_points": [ + "十元以下人民币的认识与计算", + "十元以上人民币的认识与计算" + ], + "source": "23-24 一年级下·广东潮州·期末" + }, + { + "id": "199", + "unit": "第五单元认识人民币", + "question_type": "计算题", + "difficulty": 0.65, + "question": "9 角 +7 角 =()8元9角+3角=()10元一4元5角 =()15元6角+7角=()", + "options": [ + + ], + "answer": "1元6角;9元2角;5元5角;16元3角", + "solution": "【分析】相同单位进行加减运算,角满 10 要按 10 角 = 1 元换算成元,做减法时可以先把 1 元换成 10 角再计算,据此得出结论即可.\n【详解】9角+7角=16角=1元6角;8元9角+3角=8元12角=9元2角;10元-4元5角=9元10角-4元5角=5元5角;15元6角+7角=15元13角=16元3角", + "knowledge_points": [ + "元,角,分的认识及换算" + ], + "source": "23-24 一年级下·山东菏泽·期末" + }, + { + "id": "200", + "unit": "第五单元认识人民币", + "question_type": "解答题", + "difficulty": 0.65, + "question": "![](images/c7fd4d25c71fc1bc49f487c8e69ff1e63524453ea53f6129633486329b278eba.jpg) 3元 ![](images/ccff51e05ae1ab5f68143fa1b4aff1c6fe01d2c3687aa9db1dae61752564c1f8.jpg) 6元8角 ![](images/0394890a09e50f60168488c1574e45d5bc56ffc2eb06559a3c2862c4ac6b1374.jpg) 5元5角 ![](images/1e0ef5dbe6af62a36080dd1f0b1fbc622c7c6b1f041dafe13ebe64eca3535a0b.jpg) 3元2角 (1) 买一支钢笔和一瓶墨水一共要花多少钱。(2) 买哪两种文具刚好花费 10 元。 请你算出来。", + "options": [ + + ], + "answer": "8元7角;文具盒和墨水", + "solution": "【分析】(1)把钢笔和墨水的价钱加起来即可;(2) 两种文具的价格相加得 10 的即可.\n【详解】(1) 5元5角+3元2角=8元7角;答:买一支钢笔和一瓶墨水一共要花 8 元 7 角。(2) 文具盒 6 元 8 角,墨水 3 元 2 角, 6 元 8 角 +3 元 2 角 = 10 (元)答:买文具盒和墨水刚好花费 10 元。", + "knowledge_points": [ + "十元以下人民币的认识与计算" + ], + "source": "23-24 一年级下·广东佛山·期末" + }, + { + "id": "201", + "unit": "第五单元认识人民币", + "question_type": "选择题", + "difficulty": 0.65, + "question": "一条毛巾10元,妈妈一共买了三条毛巾,付了两张20元人民币,应找回()。", + "options": [ + "A. 30元", + "B. 20元", + "C. 10元" + ], + "answer": "C", + "solution": "【分析】分别求出三条毛巾的价钱和妈妈付的钱数,然后用妈妈付的钱数减去三条毛巾的价钱即可求出应找回多少钱.\n【详解】10元+10元+10元=30元;20元+20元=40元;40元-30元=10元;应找回10元。故答案为:C", + "knowledge_points": [ + "十元以上人民币的认识与计算" + ], + "source": "23-24一年级下·河南濮阳·期末" + }, + { + "id": "202", + "unit": "第五单元认识人民币", + "question_type": "选择题", + "difficulty": 0.85, + "question": "一双![](images/858990731f033a6586b57db6216c27f1e14f4c9d90dd5b13e175f88245a6ede3.jpg)的价钱是()。", + "options": [ + "A. 30元", + "B. 30角", + "C. 30 分" + ], + "answer": "A", + "solution": "【分析】根据题意,一双鞋的价格结合数据的大小用元比较合适, 1 元 = 10 角, 30 角 = 3 元,大约是一个牙刷的价格, 30 分 = 3 角,大约是一颗糖的价格,据此解答.\n【详解】一双鞋的价钱是30元。故答案为:A", + "knowledge_points": [ + "经济问题", + "元,角,分的认识及换算" + ], + "source": "23-24一年级下·山东菏泽·期末" + }, + { + "id": "203", + "unit": "第五单元认识人民币", + "question_type": "选择题", + "difficulty": 0.65, + "question": "明明买一个文具盒,付了3张1元和2张10元,买文具盒一共花了()元。", + "options": [ + "A. 22", + "B. 23", + "C. 32" + ], + "answer": "B", + "solution": "【分析】3 张 1 元是 3 元, 2 张 10 元是 20 元,一共是 23 元,据此得出结论即可.\n【详解】1 + 1 + 1 + 10 + 10 = 23 (元);即买文件盒一共花了23元。故答案为:B", + "knowledge_points": [ + "十元以上人民币的认识与计算" + ], + "source": "23-24一年级下·河北邯郸·期末" + }, + { + "id": "204", + "unit": "第五单元认识人民币", + "question_type": "选择题", + "difficulty": 0.85, + "question": "一盒鲜牛奶的价格大约是7()。", + "options": [ + "A. 元", + "B. 角", + "C. 分" + ], + "answer": "A", + "solution": "【分析】本题考查人民币单位的认识。人民币的单位有:元,角,分,本题根据生活的常识即可解答.\n【详解】根据生活中的常识可以知道,一盒鲜牛奶的价格大约是7元。故答案为:A", + "knowledge_points": [ + "元,角,分的认识及换算" + ], + "source": "23-24一年级下·湖北襄阳·期末" + }, + { + "id": "205", + "unit": "第五单元认识人民币", + "question_type": "选择题", + "difficulty": 0.65, + "question": "一件![](images/01f8a0072488ec55305a9d49e6a13eca257fa6f2d1219f999fc6c013c8e88ab4.jpg)的价格是90()。", + "options": [ + "A. 元", + "B. 角", + "C. 分" + ], + "answer": "A", + "solution": "【分析】根据生活常识和对人民币单位的认识可知,2个练习本的价钱是1元,一件衣服的价格用元作单位比较合适,据此得出结论即可.\n【详解】根据分析知:一件![](images/b9aad5e832ad2c5341a5972eea326cc2ae5a919ea56635e0a08b1f1ce142165e.jpg)的价格是90元。故答案为:A", + "knowledge_points": [ + "元,角,分的认识及换算" + ], + "source": "23-24一年级下·福建三明·期末" + }, + { + "id": "206", + "unit": "第五单元认识人民币", + "question_type": "选择题", + "difficulty": 0.85, + "question": "4张1元纸币可以换()张5角纸币。", + "options": [ + "A. 4", + "B. 5", + "C. 8" + ], + "answer": "C", + "solution": "【分析】1 张 1 元纸币可以换 2 张 5 角的纸币, 4 张 1 元纸币可以换 8 张 5 角的纸币,据此解决.\n【详解】由题意分析得:4张1元纸币可以换8张5角纸币。故答案为:C", + "knowledge_points": [ + "元,角,分的认识及换算" + ], + "source": "23-24一年级下·河北邢台·期末" + }, + { + "id": "207", + "unit": "第五单元认识人民币", + "question_type": "选择题", + "difficulty": 0.65, + "question": "买一个铅笔盒付了1张![](images/83cf42b090d22064239aeae01d5b0bef8f0a04c9678cfd79b0496ddf0691add8.jpg)1张![](images/4b307cc5cafce712ea57edde01f119337d7924bf02e024d061925c17741ad8e9.jpg)", + "options": [ + "A. 26", + "B. 16", + "C. 36" + ], + "answer": "A", + "solution": "【分析】找回的钱不到 5 元,可能是 1 元,2 元,3 元或 4 元,用付的钱数分别减去这四种可能即可求解.\n【详解】20元+10元=30元;30元-1元=29元;30元-2元=28元;30元-3元=27元;30元-4元=26元;这个铅笔盒的价钱可能是26元或27元或28元或29元。故答案为:A", + "knowledge_points": [ + "十元以上人民币的认识与计算" + ], + "source": "23-24一年级下·河北邢台·期末" + }, + { + "id": "208", + "unit": "第五单元认识人民币", + "question_type": "选择题", + "difficulty": 0.65, + "question": "下面钱数最多的是()。", + "options": [ + "A. 2 张 10 元和 1 张 1 元", + "B. 5 张 1 元和 1 张 5 元", + "C. 1 张 10 元和 2 张 5 元" + ], + "answer": "A", + "solution": "【分析】分别计算出各个选项中的总钱数,然后比较大小得出结论即可.\n【详解】A。 10+10+1=21(元);B. 5×1+5=10(元);C. 10+5+5=20(元);21\u003e20\u003e10;钱数最多的是2张10元和1张1元。故答案为:A", + "knowledge_points": [ + "十元以上人民币的认识与计算" + ], + "source": "23-24一年级下·江西上饶·期末" + }, + { + "id": "209", + "unit": "第五单元认识人民币", + "question_type": "选择题", + "difficulty": 0.85, + "question": "一个计算器的价格大约是()。", + "options": [ + "A. 1角8分", + "B. 1元8角", + "C. 8元" + ], + "answer": "C", + "solution": "【分析】根据生活经验可知:一个计算器的价格大约在8元左右。据此解答即可.\n【详解】据分析可知:一个计算器的价格大约是8元。故答案为:C", + "knowledge_points": [ + "元,角,分的认识及换算", + "十元以下人民币的认识与计算" + ], + "source": "23-24一年级下·河南周口·期末" + }, + { + "id": "210", + "unit": "第五单元认识人民币", + "question_type": "选择题", + "difficulty": 0.65, + "question": "小兰买了一个钥匙扣,她给了售货员2张![](images/ebcd8f6a99b9583150f125bda582a3dd877a0e9d1154d2891e8a1890d4663d06.jpg),但是还差2元5角。这个钥匙扣的价格是()。", + "options": [ + "A. 42元5角", + "B. 17元5角", + "C. 22元5角" + ], + "answer": "A", + "solution": "【分析】用2张20元相加,再加2元5角即可求出这个钥匙扣的价格.\n【详解】20元+20元+2元5角=42元5角,这个钥匙扣的价格是42元5角。故答案为:A", + "knowledge_points": [ + "十元以上人民币的认识与计算" + ], + "source": "23-24一年级下·浙江宁波·期末" + }, + { + "id": "211", + "unit": "第五单元认识人民币", + "question_type": "选择题", + "difficulty": 0.65, + "question": "妈妈买一架玩具飞机正好付了 41 元,妈妈最多付了 ( ) 张 10 元。", + "options": [ + "A. 4", + "B. 5", + "C. 6" + ], + "answer": "A", + "solution": "【分析】求妈妈最多付了几张 10 元,就是求 41 元里面有几张 10 元。4 张 10 元是 40 元, 5 张 10 元是 50 元, 41 元里面最多有 4 张 10 元,由此解答.\n【详解】妈妈买一架玩具飞机正好付了41元,妈妈最多付了4张10元。故答案为:A", + "knowledge_points": [ + "十元以上人民币的认识与计算" + ], + "source": "23-24 一年级下·江西宜春·期末" + }, + { + "id": "212", + "unit": "第五单元认识人民币", + "question_type": "选择题", + "difficulty": 0.65, + "question": "王老师去体育商定买下边这个篮球,他不用找零的付钱方式是 ( )。![](images/9d331697e0f1710d5bc42b18f6a9e02f22adc04df7668a052ef63bd5be1733e8.jpg)单价:48元", + "options": [ + "A. 4 张 10 元,1 张 5 元,3 张 1 元", + "B. 1 张 50 元,8 张 1 元", + "C. 2 张 20 元,1 张 5 元,3 张 5 角" + ], + "answer": "A", + "solution": "【分析】篮球的价格是48元,分别计算出各个选项的钱数,然后得出结论即可.\n【详解】A。4张10元+1张5元+3张1元=48元,符合题意;B。1张50元+8张1元=58元,不符合题意;C。2张20元+1张5元+3张5角=46元5角,不符合题意;故答案为:A", + "knowledge_points": [ + "十元以上人民币的认识与计算" + ], + "source": "23-24 一年级下·河南郑州·期末" + }, + { + "id": "213", + "unit": "第五单元认识人民币", + "question_type": "选择题", + "difficulty": 0.65, + "question": "用下面给出的钱不能买的物品是 ( ).\n![](images/50b86109fcc0c555d7af4c32aa1f5fa4715074b5cbe4d91b909aab3a3b985722.jpg)\n![](images/259dce08b7404fe31090e23a158ae695b1db6526f043afb373736aae8b7fd7ae.jpg)\n![](images/5d7202838b815fc6bcde3b0f78607e4ea2645ae9a6ae6e6ff5bb507a51b3b8de.jpg)\n![](images/d13822e204669c94e3a839ffb25bc4cedaf737feb84cc9bf8625144e9d0c4287.jpg)", + "options": [ + "A. 文具盒 15元5角", + "B. 鞋子 45元5角", + "C. 玩具 30元8角" + ], + "answer": "B", + "solution": "【分析】根据题意,先用加法计算出总钱数是多少,不能买的也就是物品的价格超过总钱数的,由此解答.\n【详解】20元+20元+5元+1角+1角+1角=45元3角;A。45元3角\u003e15元5角,可以买;B。45元3角\u003c45元5角,不能买;C。45元3角\u003e30元8角,可以买。不能买的是鞋子。故答案为:B", + "knowledge_points": [ + "十元以下人民币的认识与计算", + "十元以上人民币的认识与计算" + ], + "source": "23-24一年级下·河南郑州·期末" + }, + { + "id": "214", + "unit": "第五单元认识人民币", + "question_type": "选择题", + "difficulty": 0.85, + "question": "14。(16-17一年级·全国·课后作业)2张1元,2张5角,5枚1角能组成()。", + "options": [ + "A. 3元", + "B. 3元5角", + "C. 4元" + ], + "answer": "B", + "solution": "【分析】根据1元 = 10 角,把所有的钱数相加即可解答.\n【详解】2张1元是2元,2张5角是10角也就是1元,5枚1角是5角;2元+1元+5角=3元5角。故答案为:B", + "knowledge_points": [ + "元,角,分的认识及换算" + ], + "source": "16-17一年级·全国·课后作业" + }, + { + "id": "215", + "unit": "第五单元认识人民币", + "question_type": "选择题", + "difficulty": 0.85, + "question": "5元1元1元1元5角正好能买下面哪个物品。 ( )", + "options": [ + "A. ![](images/513711808ef2f0180a74999383f91a975ca3531097d6bab3fdffdd0de30801b3.jpg) 2元5角", + "B. ![](images/5f6949ba5956430adb8e79eab887fca5f6640ce450dafd2d44dd07ec5ec9b420.jpg) 8元5角", + "C. ![](images/db2088a23b93d2f8559367ea077632ef728c8bded111909970993ea010fc492d.jpg) 5元" + ], + "answer": "B", + "solution": "【分析】根据题意,先求出人民币的总钱数,再逐项对照看哪件物品和总钱数一样即可解答.\n【详解】5+1+1+1=8(元),8元+5角=8元5角,跳绳是8元5角,所以正好买的是跳绳。故答案为:B", + "knowledge_points": [ + "十元以下人民币的认识与计算" + ], + "source": "23-24一年级下·河南郑州·期末" + }, + { + "id": "216", + "unit": "第五单元认识人民币", + "question_type": "选择题", + "difficulty": 0.85, + "question": "佳佳买下面其中 2 种文具,付款 20 元。( ) 没有买。", + "options": [ + "A. ![](images/63c0659640332530c39ad4cdb0aac8e172bf27436d7c72f36b9b899d229e9400.jpg) 15元", + "B. ![](images/cc9762c5e78416b9daaf3077079b094020d27c223449c1aede8febc19447742c.jpg) 8元", + "C. ![](images/6aa70352bfbee83e0abb1ed633fa89e8d5bcb492fc18a3368ed8ab5973183cfa.jpg) 10元" + ], + "answer": "A", + "solution": "【分析】根据题意可知,佳佳付款20元,则购买的2种文具的价格相加小于或等于20元。分别将每两种的文具相加计算,找出没有买的那种文具即可.\n【详解】15+8=23(元),23元\u003e20元;15+10=25(元),25元\u003e20元;8+10=18(元),18元\u003c20元。佳佳买的是彩笔和书,没有买铅笔盒。故答案为:A", + "knowledge_points": [ + "十元以上人民币的认识与计算" + ], + "source": "22-23 一年级下·重庆潼南·期末" + }, + { + "id": "217", + "unit": "第五单元认识人民币", + "question_type": "选择题", + "difficulty": 0.85, + "question": "买一个铅笔盒要 7 元 6 角,买一个卷笔刀要 6 元 7 角, ( ) 贵。", + "options": [ + "A. 一样", + "B. 铅笔盒", + "C. 卷笔刀" + ], + "answer": "B", + "solution": "【分析】将铅笔盒和卷笔刀的价格换算为统一单位后再按照整数比较大小的方法进行比较。几元几角换算为几十几角时,几元就是几十角,再加上几角就是几十几角。比较时,数位多的数就大;数位相同比较最高位,最高位大的数就大;最高位相同比较下一位,直到比较出结果为止.\n【详解】7元6角=76角;6元7角=67角;76角\u003e67角,则铅笔盒贵。故答案为:B", + "knowledge_points": [ + "元,角,分的认识及换算", + "十元以下人民币的认识与计算" + ], + "source": "22-23一年级下·浙江杭州·期末" + }, + { + "id": "218", + "unit": "第五单元认识人民币", + "question_type": "选择题", + "difficulty": 0.85, + "question": "18。(22-23一年级下·河北廊坊·期末)一件衬衫的价格是()。", + "options": [ + "A. 98 分", + "B. 98元", + "C. 9元8角" + ], + "answer": "B", + "solution": "【分析】人民币的单位有元,角,分,其中元是最大的单位,其次是角,最小的单位是分,可根据实际生活及数据选择合适的价格.\n【详解】A。98分=9角8分,不够买,不符合题意;B。98元,符合题意;C。9元8角,不够买,不符合题意。故答案为:B", + "knowledge_points": [ + "元,角,分的认识及换算" + ], + "source": "22-23一年级下·河北廊坊·期末" + }, + { + "id": "219", + "unit": "第五单元认识人民币", + "question_type": "选择题", + "difficulty": 0.85, + "question": "19。(22-23一年级下·广东汕头·期末)一瓶可口可乐的售价是()。", + "options": [ + "A. 3元5角", + "B. 3角5分", + "C. 35元" + ], + "answer": "A", + "solution": "【分析】联系生活实际,可口可乐是比较便宜的物品,价格大约在3元左右,据此分析各选项解答即可.\n【详解】A。3元5角符合可口可乐的价格;B。3角5分大约是一块橡皮的价格,不符合题意;C。35元大约为一个书包的价格,不符合题意。故答案为:A", + "knowledge_points": [ + "元,角,分的认识及换算" + ], + "source": "22-23一年级下·广东汕头·期末" + }, + { + "id": "220", + "unit": "第五单元认识人民币", + "question_type": "选择题", + "difficulty": 0.85, + "question": "20。(22-23一年级下·浙江台州·期末)一个背包的价钱大约是()。", + "options": [ + "A. 35元", + "B. 35角", + "C. 35 分" + ], + "answer": "A", + "solution": "【分析】根据生活实际,背包的价格较贵,一般用元作单位比较合适,由此解答.\n【详解】A。35元符合一个背包的价钱;B。35角=3元5角,大约为一支钢笔的价格,不符合题意;C。35分=3角5分,大约为一支铅笔的价格,不符合题意。故答案为:A", + "knowledge_points": [ + "元,角,分的认识及换算", + "十元以下人民币的认识与计算" + ], + "source": "22-23一年级下·浙江台州·期末" + }, + { + "id": "221", + "unit": "第五单元认识人民币", + "question_type": "选择题", + "difficulty": 0.85, + "question": "2元-3角 = ()。", + "options": [ + "A. 2元3角", + "B. 7角", + "C. 1元7角" + ], + "answer": "C", + "solution": "【分析】根据1元 = 10 角,换算为统一单位后,再计算解答即可.\n【详解】2元=20角;20角-3角=17角;17角=1元7角。故答案为:C", + "knowledge_points": [ + "元,角,分的认识及换算", + "十元以下人民币的认识与计算" + ], + "source": "22-23一年级下·河南周口·期末" + }, + { + "id": "222", + "unit": "第五单元认识人民币", + "question_type": "选择题", + "difficulty": 0.85, + "question": "浩浩带的钱正好够买一架 46 元的玩具飞机,浩浩最多带了 ( ) 张 10 元的纸币。", + "options": [ + "A. 3 张", + "B. 4 张", + "C. 5 张" + ], + "answer": "B", + "solution": "【分析】浩浩带的钱正好够买这架玩具飞机,求他最多带了几张 10 元的钱,就相当于求 46 里面有几个 10,据此解答即可.\n【详解】据分析可知:46里面有4个十,所以浩浩最多带了4张10元的纸币。故答案为:B", + "knowledge_points": [ + "元,角,分的认识及换算" + ], + "source": "23-24 一年级下·河北邢台·期中" + }, + { + "id": "223", + "unit": "第五单元认识人民币", + "question_type": "选择题", + "difficulty": 0.65, + "question": "一杯可乐6元8角,一个面包8元6角,()贵。", + "options": [ + "A. 可乐", + "B. 面包", + "C. 一样" + ], + "answer": "B", + "solution": "【分析】1元 = 10 角,将单位统一成角,然后比较。整数的大小比较:比较数的大小,先看数位的多少,数位多的数就大;数位相同,从高位开始比较,高位上的数大则这个数大;高位上的数相同,就比较下一位.\n【详解】6元8角=68角;8元6角=86角;68\u003c86;所以面包贵。故答案为:B", + "knowledge_points": [ + "100以内数的比大小", + "元,角,分的认识及换算", + "十元以下人民币的认识与计算" + ], + "source": "23-24一年级下·河北邢台·期中" + }, + { + "id": "224", + "unit": "第五单元认识人民币", + "question_type": "选择题", + "difficulty": 0.85, + "question": "东东买一个玩具,他给售货员10元,售货员找回他2元,这个玩具的售价是()。", + "options": [ + "A. 8元", + "B. 10元", + "C. 12元" + ], + "answer": "A", + "solution": "【分析】用给售货员的钱减去找回的钱,求出差,就是这个玩具的售价.\n【详解】10-2=8(元);即,这个玩具的售价是8元。故答案为:A", + "knowledge_points": [ + "十元以下人民币的认识与计算" + ], + "source": "17-18一年级下·河北沧州·期末" + }, + { + "id": "225", + "unit": "第五单元认识人民币", + "question_type": "选择题", + "difficulty": 0.85, + "question": "一件![](images/98016d539d79badb166c7ca25760a518a984c42e2e5eb1e347fc7e784610a928.jpg)", + "options": [ + "A. 80元", + "B. 80角", + "C. 80 分" + ], + "answer": "A", + "solution": "【分析】联系生活实际,衣服是较贵的物品,一般用元作单位比较合适,由此解答.\n【详解】A。80元,符合一件衣服的价格;B。80角=8元,大约为一本书的价格,不符合题意;C。80分=8角,大约为1支笔的价格,不符合题意。一件![](images/2188d6648272e3b6b58b44fb3d7a5ec02ed4bdb7295911ddfd24dc7375425859.jpg)的价格可能是80元。故答案为:A", + "knowledge_points": [ + "元,角,分的认识及换算" + ], + "source": "23-24 一年级下·河南新乡·期中" + }, + { + "id": "226", + "unit": "第五单元认识人民币", + "question_type": "选择题", + "difficulty": 0.85, + "question": "芳芳拿10元买了一个8元的笔袋,应找回()。", + "options": [ + "A. 2角", + "B. 18元", + "C. 2元" + ], + "answer": "C", + "solution": "【分析】根据题意:用芳芳共有的钱数减去笔袋的钱数即可.\n【详解】10-8=2(元);所以应找回2元。故答案为:C", + "knowledge_points": [ + "十元以下人民币的认识与计算" + ], + "source": "23-24一年级下·河南周口·期中" + }, + { + "id": "227", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.85, + "question": "一个篮球 52 元,全部付 10 元一张的钱,至少要付()张。", + "options": [ + + ], + "answer": "6", + "solution": "【分析】52元里面有5个10元,剩下的2元还需要1张10元,共需要付6张10元.\n【详解】一个篮球52元,全部付10元一张的钱,至少要付6张10元。", + "knowledge_points": [ + "十元以上人民币的认识与计算" + ], + "source": "23-24 一年级下·湖南株洲·期末" + }, + { + "id": "228", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.65, + "question": "6元8角 = ( ) 角 25角 = ( )元( )角 14元-5元 = ( )元 2角+7元3角 = ( )元( )角", + "options": [ + + ], + "answer": "68;2;5;9;7;5", + "solution": "【分析】根据1元 = 10 角换算后再计算,计算时元和元相加减,角和角相加减.\n【详解】6元8角=60角+8角=68角;25角=20角+5角=2元5角;14元-5元=9元;2角+7元3角=7元5角。", + "knowledge_points": [ + "元,角,分的认识及换算", + "十元以下人民币的认识与计算", + "十元以上人民币的认识与计算" + ], + "source": "23-24一年级下·湖南株洲·期末" + }, + { + "id": "229", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.65, + "question": "5元 = ( )角 9角 +5 角 = ( )元( )角70角 = ( )元 4元2角 +6 角 = ( )元( )角", + "options": [ + + ], + "answer": "50;1;4;7;4;8", + "solution": "【分析】1元 = 10 角,元和元相加,角和角相加,满10角时就用1元代替.\n【详解】5元=50角;9角+5角=14角=1元4角;70角=7元;4元2角+6角=4元8角。", + "knowledge_points": [ + "十元以下人民币的认识与计算" + ], + "source": "23-24一年级下·河北邢台·期末" + }, + { + "id": "230", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.65, + "question": "8元一2元5角 = ( )元( )角。", + "options": [ + + ], + "answer": "5;5", + "solution": "【分析】把 8 元看作 7 元和 1 元, 1 元 = 10 角, 7 元减 2 元等于 5 元, 10 角减 5 角等于 5 角,据此计算.\n【详解】8元-2元5角=5元5角。", + "knowledge_points": [ + "元,角,分的认识及换算", + "十元以下人民币的认识与计算" + ], + "source": "23-24一年级下·广西贵港·期末" + }, + { + "id": "231", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.65, + "question": "60分 = ( ) 角 35角 = ( )元( )角 1元 -3 角 = ( )角 4元8角 +4 元 = ( )元( )角", + "options": [ + + ], + "answer": "6;3;5;7;8;8", + "solution": "【分析】本题根据 1 元 = 10 角, 1 角 = 10 分进行换算,计算时元和元相加减,角和角相加减.\n【详解】60分=6角;35角=3元5角;1元-3角=10角-3角=7角;4元8角+4元=8元8角。", + "knowledge_points": [ + "元,角,分的认识及换算", + "十元以下人民币的认识与计算" + ], + "source": "23-24一年级下·江西萍乡·期末" + }, + { + "id": "232", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.85, + "question": "32.0923-24一年级下·湖南邵阳·期末)4元 = ( )角 90分 = ( )角\n1元3角 = ( ) 角 75角 = ( )元( )角", + "options": [ + + ], + "answer": "40;9;13;7;5", + "solution": "【分析】根据1元 = 10 角,1角 = 10 分,将单位换算统一即可.\n【详解】4元=40角;90分=9角;1元3角=10角+3角=13角;75角=70角+5角=7元5角。", + "knowledge_points": [ + "元,角,分的认识及换算", + "十元以下人民币的认识与计算" + ], + "source": "0923-24一年级下·湖南邵阳·期末" + }, + { + "id": "233", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.65, + "question": "1 支铅笔 5 角钱,用买 4 支铅笔的钱可以买 1 盒益智拼装积木,用买 5 盒益智拼装积木的钱可以买一个手摇卷笔刀,一个手摇卷笔刀( )元。", + "options": [ + + ], + "answer": "10", + "solution": "【分析】根据题意,用加法计算出 4 支铅笔的价格,也就是 1 盒积木的价格;再用加法计算出 5 盒积木的价格,也就是一个手摇卷笔刀的价格。计算后根据 1元 = 10角换算单位即可.\n【详解】5角+5角+5角+5角=20角=2元;2元+2元+2元+2元+2元=10元;一个手摇卷笔刀10元。", + "knowledge_points": [ + "元,角,分的认识及换算", + "十元以下人民币的认识与计算" + ], + "source": "23-24 一年级下·河南南阳·期末" + }, + { + "id": "234", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.65, + "question": "2 张 5 元和 1 张 5 角合起来是(),它比 10 元()(填\"大\"或\"小\")。", + "options": [ + + ], + "answer": "10元5角;大", + "solution": "【分析】先用加法求出2张5元和1张5角一共是多少钱,然后比较大小,即可解决.\n【详解】5元+5元=10元;10元+5角=10元5角;10元5角 \u003e10 元;即,2张5元和1张5角合起来是10元5角,它比10元大。", + "knowledge_points": [ + "100以内数的比大小", + "十元以下人民币的认识与计算" + ], + "source": "23-24一年级下·河北邢台·期末" + }, + { + "id": "235", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.65, + "question": "8角一3角 = ( )角5角 +9 角 = ( )元( )角 6元 +7 元 = ( )元1角 +5 元 = ( )元( )角", + "options": [ + + ], + "answer": "5;1;4;13;5;1", + "solution": "【分析】相同单位的直接计算,1元 = 10 角,满10角的要换算成元,据此得出结论即可.\n【详解】8角-3角=5角;5角+9角=14角=1元4角;6元+7元=13元;1角+5元=5元1角。", + "knowledge_points": [ + "元,角,分的认识及换算" + ], + "source": "23-24一年级下·河北邢台·期末" + }, + { + "id": "236", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.65, + "question": "一张![](images/6ae08212a60f4cf254284e6ef71226683c1ccb14538db392b3f0e0c2386ab417.jpg)\n可以换( )张![](images/f2cae12f2525c4adae87f1b2781f70dbd60189ba52d7b0d983eb6301bfcbd91a.jpg) \n 或( )张![](images/11d7252771594dd232b86d35be5f3f552da2676c0c4e6d702c1dcb271677ee42.jpg)", + "options": [ + + ], + "answer": "2;20", + "solution": "【分析】第一张人民币是 20 元,第二张人民币是 10 元,第三张人民币是 1 元,20 里面有 2 个十,20 里面有 20 个一,据此得出结论即可.\n【详解】根据分析知:一张20元可以换2张10元或20张1元。", + "knowledge_points": [ + "元,角,分的认识及换算" + ], + "source": "23-24 一年级下·河北邢台·期末" + }, + { + "id": "237", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.65, + "question": "小阳买文具用去3元5角,他付了5元,应找回( )。", + "options": [ + + ], + "answer": "1元5角", + "solution": "【分析】用付的钱数减用去的钱数即可求出应找回多少钱.\n【详解】5元-3元5角 = 1 元5角;小阳买文具用去3元5角,他付了5元,应找回1元5角。", + "knowledge_points": [ + "十元以下人民币的认识与计算" + ], + "source": "3-24一年级下·浙江·期末" + }, + { + "id": "238", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.85, + "question": "50分 = ( )角 76角=( )元( )角\n60角=( )元 2元-5角=( )角", + "options": [ + + ], + "answer": "5;7;6;6;15", + "solution": "【分析】根据 1 元 = 10 角, 1 角 = 10 分, 1 元 = 100 分进行单位换算,单位统一后再进行加减计算。据此解答.\n【详解】1角=10分,所以50分=5角;76角=70角+6角=7元6角;60角=6元;2元=20角,20角-5角=15角。", + "knowledge_points": [ + "元,角,分的认识及换算", + "十元以下人民币的认识与计算" + ], + "source": "23-24一年级下·广东江门·期末" + }, + { + "id": "239", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.65, + "question": "一块橡皮4角,用1元钱最多能买( )块橡皮,还剩( )角。", + "options": [ + + ], + "answer": "2;2", + "solution": "【分析】1元 = 10 角,用 1 元减 4 角,剩下的钱继续减 4 角,直到不够减为止,每减一次就是能买一块橡皮,据此得出结论即可.\n【详解】1元=10角,10角-4角-4角=6角-4角=2角,故用1元钱最多能买2块橡皮,还剩2角。", + "knowledge_points": [ + "元,角,分的认识及换算", + "十元以下人民币的认识与计算" + ], + "source": "23-24一年级下·湖北荆州·期末" + }, + { + "id": "240", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.65, + "question": "8元 = ( )角 46角 = ( )元( )角\n6角 +7 角 = ( )元( )角 5元6角一3角 = ( )元( )角", + "options": [ + + ], + "answer": "80;4;6;1;3;5;3", + "solution": "【分析】本题根据1元 = 10 角进行换算,计算时元和元相加减,角和角相加减.\n【详解】8元=80角;46角=40角+6角=4元6角;6角+7角=13角=1元3角;5元6角-3角=5元3角。", + "knowledge_points": [ + "元,角,分的认识及换算", + "十元以下人民币的认识与计算" + ], + "source": "23-24一年级下·江西上饶·期末" + }, + { + "id": "241", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.65, + "question": "6元 = ( )角 35角 = ( )元( )角\n30角 = ( )元7元3角 = ( )角 40分=( )角 92分=( )角( )分", + "options": [ + + ], + "answer": "60;3;5;3;73;4;9;2", + "solution": "【分析】本题根据1元 = 10 角;1角 = 10 分进行换算解答即可.\n【详解】6元=60角;35角=30角+5角=3元5角;30角=3元;7元3角=70角+3角=73角;40分=4角;92分=90分+2分=9角2分。", + "knowledge_points": [ + "元,角,分的认识及换算", + "十元以下人民币的认识与计算" + ], + "source": "23-24一年级下·河北唐山·期末" + }, + { + "id": "242", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.65, + "question": "一本练习本 8 角钱,买两本需要( )钱,如果付给售货员 2 元钱,应找回( )钱。", + "options": [ + + ], + "answer": "1元6角;4角", + "solution": "【分析】根据题意,两本的价格,也就是 2 个 8 角的和,用加法计算;根据减法的意义,付出的钱数一两本练习本的钱数 = 找回的钱数。先统一单位再计算.\n【详解】1元=10角;8角+8角=16角=1元6角;2元=20角;20角-16角=4角;买两本需要1元6角,如果付2元,应找回4角。", + "knowledge_points": [ + "元,角,分的认识及换算", + "十元以下人民币的认识与计算" + ], + "source": "23-24 一年级下·湖北随州·期末" + }, + { + "id": "243", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.85, + "question": "5元 = ( )角 1元-7角 = ( )角", + "options": [ + + ], + "answer": "50;3", + "solution": "【分析】根据\"1元=10角\"及整数加减法的计算法则来解决此题.\n【详解】1元=10角,5元=50角;10角-7角=3角,故1元-7角=3角。", + "knowledge_points": [ + "元,角,分的认识及换算", + "十元以下人民币的认识与计算" + ], + "source": "23-24一年级下·四川乐山·期末" + }, + { + "id": "244", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.65, + "question": "55角 = ( ) 元( )角 8角+2角 = ()元 8角 +7 角 = ( )元( )角 1元一6角 = ( )角", + "options": [ + + ], + "answer": "5;5;1;1;5;4", + "solution": "【分析】1元 = 10 角,据此换算单位,单位不同的要先换算成相同的单位再计算,如:1元 -6 角 = 10 角 -6 角 = 4 角.\n【详解】55角=5元5角;8角+2角=10角=1元;8角+7角=15角=1元5角;1元-6角=10角-6角=4角。", + "knowledge_points": [ + "元,角,分的认识及换算", + "十元以下人民币的认识与计算" + ], + "source": "23-24一年级下·浙江嘉兴·期末" + }, + { + "id": "245", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.85, + "question": "78角 = ( ) 元( )角 3元9角 = ()和( )角 1元 = ( )角 = ( )分", + "options": [ + + ], + "answer": "7;8;3元;9;10;100", + "solution": "【分析】本题根据1元 = 10 角;1角 = 10 分;1元 = 100 分,换算即可.\n【详解】78角=70角+8角=7元8角;3元9角=3元和9角;1元=10角=100分。", + "knowledge_points": [ + "元,角,分的认识及换算" + ], + "source": "23-24一年级下·福建福州·期末" + }, + { + "id": "246", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.85, + "question": "妈妈有一张![](images/4b6a4f05898ea20147c4438460369b669e4ddd14afbf4d09fb8073ed9c999067.jpg)\n和三张![](images/e7f141b204c32e074116caab278c344365896d7d070eacb33e55d59b4a4f8a95.jpg) ,妈妈一共有( )元。", + "options": [ + + ], + "answer": "65", + "solution": "【分析】求一共有多少用加法计算,每张都是以元为单位,将每张的面额相加即可求出妈妈一共有多少元.\n【详解】50+5+5+5=65(元);妈妈一共有65元。", + "knowledge_points": [ + "十元以上人民币的认识与计算" + ], + "source": "23-24 一年级下·河南周口·期末" + }, + { + "id": "247", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.85, + "question": "7角 +5 角 = ( )元( )角 46角 = ( )元() 角", + "options": [ + + ], + "answer": "1;2;4;6", + "solution": "【分析】人民币的简单计算:元加元,角加角,满十角变一元,再根据1元=10角结合题干要求进行解答即可.\n【详解】7角+5角=12角=1元2角;46角=4元6角。", + "knowledge_points": [ + "元,角,分的认识及换算", + "十元以下人民币的认识与计算" + ], + "source": "23-24一年级下·福建福州·期末" + }, + { + "id": "248", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.65, + "question": "5元6角 = ( )角 41角 = ( )元( )角60分 = ( ) 角 8角+9角 = ( )元( )角", + "options": [ + + ], + "answer": "56;4;1;6;1;7", + "solution": "【分析】根据1元 = 10 角;1角 = 10 分及整数加减法的计算法则解答即可.\n【详解】5元6角=50角+6角=56角;41角=40角+1角=4元1角;60分=6角;8角+9角=17角=1元7角。", + "knowledge_points": [ + "元,角,分的认识及换算", + "十元以下人民币的认识与计算" + ], + "source": "23-24一年级下·福建福州·期末" + }, + { + "id": "249", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.85, + "question": "用心算.\n2元-6角 = ( )元( )角 9角 +5 角 = ( )元( )角\n8 + ( ) = 6034 - 4 = ( ) + 5 \n( ) + 40 = 70 ( ) - 10 = 20", + "options": [ + + ], + "answer": "1;4;1;4;52;25;30;30", + "solution": "【分析】①和②根据1元 = 10 角,即可解答。(1) 将 2 元换算成 20 角,再减去 6 角,即 20 角 - 6 角 = 14 角 = 1 元 4 角,满 10 角需转换成 1 元即可;(2) 9角 + 5角 = 14角 = 1元 4角,满 10角需转换成 1 元即可。③④⑤ 根据和一加数 = 另一个加数即可解答。⑥ 根据差 + 减数 = 被减数即可解答.\n【详解】2元-6角=1元4角;9角+5角=1元4角;60-8=52,则8+(52)=60;34-4=30,30-5=25,则34-4=(25)+5;70-40=30,则(30)+40=70;20+10=30,则(30)-10=20。", + "knowledge_points": [ + "元,角,分的认识及换算", + "十元以下人民币的认识与计算" + ], + "source": "23-24一年级下·江西宜春·期末" + }, + { + "id": "250", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.85, + "question": "3元 = () 角 60角 = ( )元\n45角 = ( )元( )角 1元8角 = ( )角", + "options": [ + + ], + "answer": "30;6;4;5;18", + "solution": "【分析】根据\"1元 = 10 角\"及整数加减法的计算法则来完成此题即可.\n【详解】3元=30角;60角=6元;45角=40角+5角=4元5角;1元8角=10角+8角=18角。", + "knowledge_points": [ + "元,角,分的认识及换算" + ], + "source": "22-23一年级下·河北保定·期末" + }, + { + "id": "251", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.85, + "question": "在括号里填上合适的数。39角 = ( )元( )角 4元6角 = ( )角 6角 +2 元5角 = ( )元( )角", + "options": [ + + ], + "answer": "3;9;46;3;1", + "solution": "【分析】根据 1 元 = 10 角, 1 角 = 10 分即可解答。将 39 角分成 30 角 + 9 角,将 4 元换算成 40 角,再加上 6 角。6 角 + 5 角 = 11 角 = 1 元 1 角,满 10 角需转换成 1 元, 1 元 1 角中的 1 元加上 2 元即可.\n【详解】39角=3元9角;4元6角=40角+6角=46角;6角+2元5角=2元11角=3元1角。", + "knowledge_points": [ + "元,角,分的认识及换算", + "十元以下人民币的认识与计算" + ], + "source": "23-24一年级下·河南郑州·期末" + }, + { + "id": "252", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.65, + "question": "4元 = ( )角 6元5角 = ( )角\n3元 +6 角 = ( )元( )角 48分 = ( )角( )分", + "options": [ + + ], + "answer": "40;65;3;6;4;8", + "solution": "【分析】本题根据 1 元 = 10 角;1 角 = 10 分进行换算,加法计算时,元和元相加,角和角相加。几元几角换算为角时,几元就是几十角,再加上几角就是几十几角;几十几分换算为几角几分时,几十分就是几角,剩下的就是几分.\n【详解】4元=40角;6元5角=65角;3元+6角=3元6角;48分=4角8分。", + "knowledge_points": [ + "元,角,分的认识及换算", + "十元以下人民币的认识与计算" + ], + "source": "23-24一年级下·福建福州·期末" + }, + { + "id": "253", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.65, + "question": "填空.\n60角 = ( )元 4元8角 = ( )角 1元 = ( )分 24分 = ( )角( )分", + "options": [ + + ], + "answer": "6;48;100;2;4", + "solution": "【分析】第1题:10角 = 1 元,则60角 = 6 元;第2题:1元 = 10 角;4元 = 40 角;4元8角 = 40 角 +8 角 = 48 角;第3题:1元 = 100 分;第4题:1角 = 10 分;24分 = 20 分 +4 分;24分 = 2 角4分.\n【详解】60角=6元;4元8角=48角;1元=100分;24分=2角4分。", + "knowledge_points": [ + "元,角,分的认识及换算", + "十元以下人民币的认识与计算" + ], + "source": "23-24一年级下·河南周口·期末" + }, + { + "id": "254", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.65, + "question": "1 张![](images/36dc561ae0cc6f394c29ae71ff52507ef45ad927da45c21c14c3d115042d85d6.jpg)\n可以换( )张![](images/9425f0369029cf5d9313ecb9c3a3c02ad05b2585ab98325920070c44fb05ee7d.jpg).\n1 张100元可以换( )张![](images/ff6ad136e93c154fa64fc01d3e8975c63dc460ff74243de91096b8666e21c06f.jpg)\n和( )张![](images/d79342b79870db91649d7ceac9c5cfcbf37ce304e98bbc303a2c2ad1bfc5b663.jpg)", + "options": [ + + ], + "answer": "2;1;8", + "solution": "【分析】几个十就是几十,20里面有2个十;100可以分成20和80,80里面有8个10,据此计算并填空.\n【详解】10元+10元=20元;1张20元可以换2张10元;20元+10元+10元+10元+10元+10元+10元+10元+10元=100元;1张100元可以换1张20元和8张10元(答案不唯一)。", + "knowledge_points": [ + "十元以上人民币的认识与计算" + ], + "source": "23-24 一年级下·河南周口·期末" + }, + { + "id": "255", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.85, + "question": "1元 = ( )角 26角 = ( )元( )角", + "options": [ + + ], + "answer": "10;2;6", + "solution": "【分析】1元 = 10 角,几元就等于几十角,据此换算解答.\n【详解】1元=10角;26角=20角+6角=2元6角。", + "knowledge_points": [ + "元,角,分的认识及换算", + "十元以下人民币的认识与计算" + ], + "source": "23-24一年级下·河南郑州·期末" + }, + { + "id": "256", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.65, + "question": "一元一元地数,10个一元是( )元;十元十元地数,( )个十元是一百元。", + "options": [ + + ], + "answer": "10或十;10", + "solution": "【分析】10个一元是10元,10个十元是一百元,据此得出结论即可.\n【详解】一元一元地数,10个一元是10元;十元十元地数,10个十元是一百元。", + "knowledge_points": [ + "元,角,分的认识及换算" + ], + "source": "23-24一年级下·河南郑州·期末" + }, + { + "id": "257", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.65, + "question": "3元5角 = ( ) 角 14角 +6 角 = (20 ) 元 48角 = ( ) 元( )角 5元一5角 = ( ) 元( )角", + "options": [ + + ], + "answer": "35;2;4;8;4;5", + "solution": "【分析】1元 = 10 角,几元就等于几十角,据此换算解答.\n【详解】3元5角=30角+5角=35角;14角+6角=20角=2元;48角=40角+8角=4元8角;5元-5角=50角-5角=45角=4元5角。", + "knowledge_points": [ + "元,角,分的认识及换算", + "十元以下人民币的认识与计算" + ], + "source": "23-24一年级下·河南郑州·期末" + }, + { + "id": "258", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.85, + "question": "7角 = ( ) 分5元3角 = ( ) 角1元 = ( ) 角 = ( )分", + "options": [ + + ], + "answer": "70;53;10;100", + "solution": "【分析】根据\"1元 = 10 角,1角 = 10 分,1元 = 100 分\"来解决此题.\n【详解】7角=70分;5元3角=50角+3角=53角;1元=10角=100分。", + "knowledge_points": [ + "元,角,分的认识及换算" + ], + "source": "22-23一年级下·重庆潼南·期末" + }, + { + "id": "259", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.85, + "question": "4元 = ( )角 18角 = ( )元( )角\n60分 = ( )角 7元2角 = ( )角", + "options": [ + + ], + "answer": "40;1;8;6;72", + "solution": "【分析】根据 1 元 = 10 角, 1 角 = 10 分即可解答。将 18 角分成 10 角 +8 角,将 7 元换算成 70 角,再加上 2 角.\n【详解】4元=40角;18角=1元8角;60分=6角;7元2角=70角+2角=72角。", + "knowledge_points": [ + "元,角,分的认识及换算" + ], + "source": "22-23一年级下·河北廊坊·期末" + }, + { + "id": "260", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.85, + "question": "8元 = ( )角 7角+9角 = ( )元( )角", + "options": [ + + ], + "answer": "80;1;6", + "solution": "【分析】根据\"1元 = 10 角\"及整数加减法的计算法则来解决此题.\n【详解】8元=80角;7角+9角=16角=1元6角。", + "knowledge_points": [ + "不退位减法(20以内)", + "7,6加几的进位加法", + "元,角,分的认识及换算" + ], + "source": "23-24一年级下·河南郑州·期末" + }, + { + "id": "261", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.85, + "question": "9元 = ( ) 角 24角 = ( )元( )角 30角 = ( ) 元 1元9角 = ( )角", + "options": [ + + ], + "answer": "90;2;4;3;19", + "solution": "【分析】根据\"1元=10角\"及整数加减法计算法则来解决此题.\n【详解】9元=90角;24角=2元4角;30角=3元;1元9角=19角。", + "knowledge_points": [ + "元,角,分的认识及换算" + ], + "source": "22-23一年级下·江西九江·期末" + }, + { + "id": "262", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.85, + "question": "8元 = ( )角 40分 = ( )角 5角+1元 8角 = ( )元( )角", + "options": [ + + ], + "answer": "80;4;2;3", + "solution": "【分析】根据1元 = 10 角,1角 = 10 分,结合题干要求进行解答。人民币的简单计算,元加元,角加角,满十角变一元.\n【详解】8元=80角;40分=4角;5角+1元8角=5角+18角=23角=2元3角。", + "knowledge_points": [ + "元,角,分的认识及换算", + "十元以下人民币的认识与计算" + ], + "source": "22-23一年级下·河南许昌·期末" + }, + { + "id": "263", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.65, + "question": "1 张![](images/8e30d29a875d3b33df215741352706d0113eacd4395c07fbc0f2114e0517ad30.jpg)\n可以换4张![](images/580bd6d32c783314a756335285d12a3e8492856a5ba31ca97948c25ad5d25b6e.jpg)\n和()张![](images/e848dab395575e891aa5e0cf8466f9d1640ef1d70a5f897e4ebf6369a20ecb01.jpg)", + "options": [ + + ], + "answer": "4;2", + "solution": "【分析】人民币的兑换即保持总面值不变。4 张 10 元也就是 40 元,根据 10 + 10 + 10 + 10 + 5 + 5 = 50(元),得出结论即可.\n【详解】4张10元是40元,40+5+5=50(元),故1张50元可以换4张10元和2张5元。", + "knowledge_points": [ + "元,角,分的认识及换算" + ], + "source": "22-23 一年级下·重庆潼南·期末" + }, + { + "id": "264", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.65, + "question": "3元2角 = () 角 1元 = ( )分 2元6角 +3 元 = ( )元()角", + "options": [ + + ], + "answer": "32;100;5;6", + "solution": "【分析】第 1 题:几元几角换算为几十几角时,几元就是几十角,再加上几角就是几十几角;3 元 2 角 = 32 角;第2题:1元 = 100 分;第3题:元和元相加,角和角相加。2元6角 +3 元 = 5 元6角.\n【详解】3元2角=32角;1元=100分;2元6角+3元=5元6角。", + "knowledge_points": [ + "元,角,分的认识及换算", + "十元以下人民币的认识与计算" + ], + "source": "22-23一年级下·浙江杭州·期末" + }, + { + "id": "265", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.85, + "question": "65。(22-23一年级下·江西九江·期末)一张![](images/58bd98e52a72183127eac70658342925a83ce5a5d613dbfc79bee2764b90c125.jpg)\n可以换( )张![](images/8b7ca17f38e92f7fba14ed26e01460e4f03555c0e6d7b6dda1d7d1df40098ca8.jpg)。", + "options": [ + + ], + "answer": "4", + "solution": "【分析】根据人民币面值的认识,5+5+5+5=20(元),所以一张20元可以换4张5元.\n【详解】由分析可知:一张20元可以换4张5元。", + "knowledge_points": [ + "元,角,分的认识及换算" + ], + "source": "22-23一年级下·江西九江·期末" + }, + { + "id": "266", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.85, + "question": "有一些5角纸币,两张两张地数,数了3次,还余下1张,这些纸币一共是( )钱。", + "options": [ + + ], + "answer": "3元5角", + "solution": "【分析】两张两张地数,2 张 5 角是 1 元,所以一次是 1 元,数了 3 次,一共是 3 元,还余下 1 张则还余 5 角,将 3 元和 5 角相加即可.\n【详解】数3次是3元,还余下5角;3元+5角=3元5角,所以这些纸币一共是3元5角。", + "knowledge_points": [ + "十元以下人民币的认识与计算" + ], + "source": "22-23一年级下·河北廊坊·期末" + }, + { + "id": "267", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.85, + "question": "浩浩用 3 张 1 元和 1 张 5 角买了一个羽毛球,这个羽毛球的价格是( )元( )角。", + "options": [ + + ], + "answer": "35", + "solution": "【分析】根据题意,将所有人民币的面值相加就是总面值。元和元相加,角和角相加,相加满十角进为一元.\n【详解】1元+1元+1元+5角=3元5角;浩浩用3张1元和1张5角买了一个羽毛球,这个羽毛球的价格是3元5角。", + "knowledge_points": [ + "十元以下人民币的认识与计算" + ], + "source": "23-24一年级下·河北邢台·期中" + }, + { + "id": "268", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.65, + "question": "8 元 = ( )角 16 角 = ( )元( )角 40 角 =( )元2元4角 = ( )角", + "options": [ + + ], + "answer": "80;1;6;4;24", + "solution": "【分析】1元 = 10 角,即10角 = 1 元,几元就等于几十角,几十角就等于几元。据此换算单位即可.\n【详解】8元=80角;16角=10角+6角=1元6角;40角=4元;2元4角=20角+4角=24角。", + "knowledge_points": [ + "元,角,分的认识及换算", + "十元以下人民币的认识与计算" + ], + "source": "22-23 一年级下·福建龙岩·期末" + }, + { + "id": "269", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.85, + "question": "15角 = ( )元( )角 70角 = ( )元", + "options": [ + + ], + "answer": "1;5;7", + "solution": "【分析】本题根据 1 元 = 10 角换算。几十几角换算为几元几角时,几十角就是几元,剩下的就是几角.\n【详解】15角=1元5角;70角=7元。", + "knowledge_points": [ + "元,角,分的认识及换算" + ], + "source": "22-23一年级下·河北邢台·期末" + }, + { + "id": "270", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.85, + "question": "30角 = ( ) 元 64角 = ( )元( )角 7元9角 = ( ) 角58分 = ( )角( )分", + "options": [ + + ], + "answer": "3;6;4;79;5;8", + "solution": "【分析】根据\"1元 = 10 角,1角 = 10 分\"及整数加减法的计算法则来解决此题.\n【详解】10角=1元,30角=3元;60角=6元,64角=6元4角;7元9角=79角;58分=5角8分。", + "knowledge_points": [ + "整十数加,减一位数", + "两位数与整十数的减法", + "元,角,分的认识及换算" + ], + "source": "23-24一年级下·全国·期末" + }, + { + "id": "271", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.85, + "question": "30角 = ( ) 元 4元7角 = ( )角 60分 = ( )角", + "options": [ + + ], + "answer": "3;47;6", + "solution": "【分析】根据1元 = 10 角,1角 = 10 分,进行换算即可.\n【详解】30角=3元;4元=40角,4元7角=47角;60分=6角。", + "knowledge_points": [ + "元,角,分的认识及换算" + ], + "source": "20-21一年级下·河北廊坊·期末" + }, + { + "id": "272", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.65, + "question": "9元5角 = ( ) 角 1元 = ()分\n68角 = ( )元( )角 40分 = ( )角", + "options": [ + + ], + "answer": "95;100;6;8;4", + "solution": "【分析】1元 = 10 角, 1角 = 10 分, 1元 = 100 分。几元几角换算为几十几角时,几元就是几十角,再加上几角就是几十几角;几十几角换算为几元几角时,几十角就是几元,剩下的就是几角.\n【详解】9元5角=95角;1元=100分;68角=6元8角;40分=4角。", + "knowledge_points": [ + "元,角,分的认识及换算" + ], + "source": "22-23一年级下·河北廊坊·期末" + }, + { + "id": "273", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.85, + "question": "一个足球 30 元,如果都付![](images/f030df21db8434679f82feb60bc136f139b54cc78f39889fc42bb13d163b67e3.jpg),需要( )张;如果付2张![](images/3bbfb86de054bbdda4f2f77643b627839de86c139e4845d7dd0a145864df64ef.jpg) ,应找回( )元。", + "options": [ + + ], + "answer": "3;10", + "solution": "【分析】30 里面有 3 个 10,所以需要 3 张 10 元;2 张 20 元就是 40 元。付出的钱减去一个足球的钱,求出差,就是应找回的钱.\n【详解】20元+20元=40元;40-30=10元;即一个足球30元,如果都付![](images/51592a4fb47b1a5ab3b092f0b4559719c78494907ae25ce01ed299f42bcbef69.jpg),需要3张;如果付2张![](images/3bbfb86de054bbdda4f2f77643b627839de86c139e4845d7dd0a145864df64ef.jpg),应找回10元。", + "knowledge_points": [ + "十元以上人民币的认识与计算" + ], + "source": "20-21一年级下·河北廊坊·期末" + }, + { + "id": "274", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.65, + "question": "30角 = ( ) 元 74角 = ( )元( )角 7元9角 = ( ) 角 68分 = ( )角( )分", + "options": [ + + ], + "answer": "3;7;4;79;6;8", + "solution": "【分析】1元 = 10 角, 1角 = 10 分;先按进率换算单位即可.\n【详解】30角=3元;74角=7元4角;7元9角=79角;68分=6角8分。", + "knowledge_points": [ + "元,角,分的认识及换算" + ], + "source": "20-21一年级下·河北廊坊·期末" + }, + { + "id": "275", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.85, + "question": "4元5角 = ( ) 角 71角 = ( )元( )角", + "options": [ + + ], + "answer": "45;7;1", + "solution": "【分析】根据 1 元 = 10 角,将元化成角或将角化成元角即可.\n【详解】4元5角=40角+5角=45角;71角=70角+1角=7元1角。", + "knowledge_points": [ + "元,角,分的认识及换算" + ], + "source": "22-23一年级下·河北廊坊·期末" + }, + { + "id": "276", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.85, + "question": "填一填.\n1元 = ( )角 1角 = ( )分 30分 = ( )角50角 = ( )元\n4元 = ( )角 9角 = ( )分 60角 = ( )元8元 = ( )角", + "options": [ + + ], + "answer": "10;10;3;5;40;90;6;80", + "solution": "【分析】本题根据1元 = 10 角;1角 = 10 分换算填写即可.\n【详解】1元=10角;1角=10分;30分=3角;50角=5元;4元=40角;9角=90分;60角=6元;8元=80角。", + "knowledge_points": [ + "元,角,分的认识及换算" + ], + "source": "23-24 一年级下·全国·假期作业" + }, + { + "id": "277", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.65, + "question": "看图填空.\n![](images/ce2d4b800337f00f4f87983daa3c5e8440e75b666285a534d42814c354682bd5.jpg)\n5角\n![](images/24a9ad803dbf4b8de25662c5be7d6634da131cb378d350d6c7bded28474b6e44.jpg)\n8角\n![](images/498d74bd5a9036b38fb416abeef9e15ea2688a6f378d5d38dbaa0db1a1734bee.jpg)\n6角\n![](images/469ad898ef23e681bb8423c652ab84ac6e1b1b0d42f8ee7da9d4556323bc181a.jpg)\n1元2角\n(1)1元钱可以买( )块橡皮;买2个卷笔刀要付( )元( )角.\n(2)买1把直尺,付了1元钱,应该找回()钱.\n(3)用1元3角正好可以买( )和( ).\n(4)买1把直尺和1支铅笔共需( )角,合( )元( )角。", + "options": [ + + ], + "answer": "2;2;4;2角;橡皮,直尺;14;1;4", + "solution": "【分析】根据题图,1元=10角。(1) 橡皮5角,1元里有2个5角;卷笔刀1元2角,2个是2元4角;(2) 用付的钱数-直尺的钱数=找回的钱数;(3) 1元3角=13角,找出相加等于13角的物品;(4) 直尺的钱数+铅笔的钱数=总钱数.\n【详解】(1) 5角+5角=10角=1元;1元2角+1元2角=2元4角;(2) 10角-8角=2角;(3) 5角+8角=13角=1元3角;(4) 8角+6角=14角=1元4角。", + "knowledge_points": [ + "经济问题", + "元,角,分的认识及换算", + "十元以下人民币的认识与计算" + ], + "source": "23-24一年级下·全国·假期作业" + }, + { + "id": "278", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.65, + "question": "用 10 元钱正好可以买( )和( )或者( )和( ).\n1![](images/371462e499b6f2d5fb02f931b4021a119d4d7bcc037ae28bdc7d09a86d73032a.jpg)\n2元\n2![](images/18391de784f2ccaefa407e5a0f65c9a5d587ddba496a973b2e3a3059817d610c.jpg)\n7元\n3![](images/c24225a882af6dc5a4f4b7aa5738c69e90246f33fc0e1f7755fedd4c59997e4c.jpg)\n8元\n4![](images/dad71e8ac7e2395187c884e6fd9cdb1ddfb0ff731a4fb11b26f93b5bd6d556fb.jpg)\n5元\n5拼图\n3元", + "options": [ + + ], + "answer": "1;3;2;5", + "solution": "【分析】根据 2+8=10(元),7+3=10(元),得出10元刚好能买哪两样.\n【详解】2+8=10(元),7+3=10(元),故用10元钱正好可以买①和③或者②和⑤。", + "knowledge_points": [ + "十元以下人民币的认识与计算" + ], + "source": "23-24 一年级下·全国·假期作业" + }, + { + "id": "279", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.85, + "question": "一张10元的人民币可以换成( )张1元的人民币;一张100元的人民币可以换成( )张10元的人民币。", + "options": [ + + ], + "answer": "10;10", + "solution": "【分析】10 个 1 是 10, 10 个 10 是 100;据此解答.\n【详解】一张10元的人民币可以换成10张1元的人民币;一张100元的人民币可以换成10张10元的人民币。", + "knowledge_points": [ + "100以内数的组成", + "十元以上人民币的认识与计算" + ], + "source": "22-23一年级下·贵州铜仁·期末" + }, + { + "id": "280", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.65, + "question": "在()里填上\"\u003e\"\"\u003c\"或\"=\" .\n57( )756元( )5元9角 42角( )50分\n90( )891元8角( )18角 4角+6角( )10元", + "options": [ + + ], + "answer": "\u003c;\u003e;\u003e;\u003e;=;\u003c", + "solution": "【分析】整数比大小先比数位再比高位;含算式的先算结果再比;单位不统一先化成相同单位。1元=10角,1角=10分.\n【详解】57\u003c75;6元=60角,5元9角=59角,所以6元\u003e5元9角;50分=5角,所以42角\u003e50分;90\u003e89;1元8角=18角;4角+6角=10角=1元,所以4角+6角\u003c10元。", + "knowledge_points": [ + "100以内数的比大小", + "元,角,分的认识及换算", + "十元以下人民币的认识与计算" + ], + "source": "23-24一年级下·河北邢台·期中" + }, + { + "id": "281", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.85, + "question": "81。(22-23一年级下·福建龙岩·期末)一张![](images/0722f50013f4cb541834492ee3524279f4db391b7e0ceb0fda42c6d8f311bed6.jpg)\n可以换( )张![](images/4da920c61be7dca0e5d5d2fa9f267ddfcb18185d0b11de4b60fc2bdc18965fd1.jpg)\n元,也可以换( )张![](images/8f1a3a6b9520e9d177d767e90072d5b6f6fb141f051d69d562abd9c01f253713.jpg)", + "options": [ + + ], + "answer": "10;100", + "solution": "【分析】10个十是100,100个一也是100,据此解答.\n【详解】一张100元可以换10张10元,也可以换100张1元。", + "knowledge_points": [ + "元,角,分的认识及换算", + "十元以上人民币的认识与计算" + ], + "source": "22-23一年级下·福建龙岩·期末" + }, + { + "id": "282", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.85, + "question": "一张100元可以换( )张20元或( )张10元。", + "options": [ + + ], + "answer": "5;10", + "solution": "【分析】人民币互换保持总面值不变。1张100元=5张20元=10张10元.\n【详解】一张100元可以换5张20元或10张10元。", + "knowledge_points": [ + "元,角,分的认识及换算", + "十元以上人民币的认识与计算" + ], + "source": "22-23一年级下·浙江绍兴·期末" + }, + { + "id": "283", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.85, + "question": "100分 = ( )元 50角 = ( )元\n2元6角 = ( ) 角 78角 = ( )元", + "options": [ + + ], + "answer": "1;5;26;7元8角", + "solution": "【分析】根据1元=10角,1角=10分,1元=100分,先统一单位换算.\n【详解】100分=1元;50角=5元;2元6角=26角;78角=7元8角。", + "knowledge_points": [ + "元,角,分的认识及换算" + ], + "source": "23-24一年级下·新疆和田·期中" + }, + { + "id": "284", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.65, + "question": "4角 = ( ) 分 3元 = ( )角 ( )元 = 60角 5元4角 = ( ) 角", + "options": [ + + ], + "answer": "40;30;6;54", + "solution": "【分析】1元=10角,1角=10分,根据单位换算解决.\n【详解】4角=40分;3元=30角;6元=60角;5元4角=54角。", + "knowledge_points": [ + "元,角,分的认识及换算" + ], + "source": "23-24一年级下·河南新乡·期中" + }, + { + "id": "285", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.85, + "question": "一个布娃娃 48 元,小芳带的钱正好可以买这个布娃娃。小朋友们猜一猜,小芳最多带了( )张 10 元的人民币。", + "options": [ + + ], + "answer": "4", + "solution": "【分析】48里面有4个十8个一,48里面最多有4个十,所以最多带4张10元.\n【详解】小芳最多带了4张10元的人民币。", + "knowledge_points": [ + "十元以上人民币的认识与计算" + ], + "source": "23-24 一年级下·河南新乡·期中" + }, + { + "id": "286", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.85, + "question": "一块橡皮5角,小刚买了两块,他要付( )元给营业员。", + "options": [ + + ], + "answer": "1", + "solution": "【分析】10角=1元,两块橡皮共10角,换算成元即可.\n【详解】5角+5角=10角;10角=1元;他要付1元。", + "knowledge_points": [ + "元,角,分的认识及换算", + "十元以下人民币的认识与计算" + ], + "source": "23-24一年级下·河南新乡·期中" + }, + { + "id": "287", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.85, + "question": "3元 = ( )角,20分 = ( )角。", + "options": [ + + ], + "answer": "30;2", + "solution": "【分析】1元=10角,1角=10分,据此换算.\n【详解】3元=30角;20分=2角。", + "knowledge_points": [ + "元,角,分的认识及换算" + ], + "source": "23-24一年级下·四川绵阳·期中" + }, + { + "id": "288", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.85, + "question": "1元 = ( )角 10分 = ( )角\n2元3角 = ( ) 角 58角 = ( )元( )角", + "options": [ + + ], + "answer": "10;1;23;5;8", + "solution": "【分析】根据1元=10角,1角=10分换算即可.\n【详解】1元=10角;10分=1角;2元3角=23角;58角=5元8角。", + "knowledge_points": [ + "元,角,分的认识及换算" + ], + "source": "23-24一年级下·贵州黔南·期中" + }, + { + "id": "289", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.65, + "question": "2 张 1 元的人民币和 4 张 5 角的人民币合起来是( )元。一张 20 元的人民币能换( )张 5 元的人民币,也能换( )张 10 元的人民币。", + "options": [ + + ], + "answer": "4;4;2", + "solution": "【分析】2张1元是2元,4张5角是2元,合起来是4元;20元可分成4个5元或2个10元.\n【详解】5+5+5+5=20(元);10+10=20(元);合起来是4元;20元能换4张5元,也能换2张10元。", + "knowledge_points": [ + "元,角,分的认识及换算", + "十元以上人民币的认识与计算" + ], + "source": "22-23 二年级上·河南驻马店·期中" + }, + { + "id": "290", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.85, + "question": "8元 = ( ) 角 3角 = ()分 20角 = ()元 46角 = ( ) 元( )角", + "options": [ + + ], + "answer": "80;30;2;4;6", + "solution": "【分析】根据1元=10角,1角=10分换算.\n【详解】8元=80角;3角=30分;20角=2元;46角=4元6角。", + "knowledge_points": [ + "元,角,分的认识及换算" + ], + "source": "22-23 二年级上·广东梅州·期中" + }, + { + "id": "291", + "unit": "第五单元认识人民币", + "question_type": "判断题", + "difficulty": 0.65, + "question": "8.00 元表示 800 元,能买一件羽绒服。( )", + "options": [ + + ], + "answer": "×", + "solution": "【分析】8.00表示8元,一件羽绒服的价格大概几百元,据此得出结论即可.\n【详解】8.00元表示8元,不能买一件羽绒服,原题结论错误。故答案为: ×", + "knowledge_points": [ + "元,角,分的认识及换算" + ], + "source": "23-24 一年级下·山东·期末" + }, + { + "id": "292", + "unit": "第五单元认识人民币", + "question_type": "判断题", + "difficulty": 0.85, + "question": "人民币的最小面值是1元。()", + "options": [ + + ], + "answer": "×", + "solution": "【分析】人民币面值中最小的是1分,不是1元.\n【详解】人民币的最小面值是1分,原题结论错误。故答案为: ×", + "knowledge_points": [ + "元,角,分的认识及换算" + ], + "source": "23-24一年级下·河北邢台·期末" + }, + { + "id": "293", + "unit": "第五单元认识人民币", + "question_type": "判断题", + "difficulty": 0.65, + "question": "1.90元是1元90角。()", + "options": [ + + ], + "answer": "×", + "solution": "【分析】小数点后第一位是角,第二位是分;1.90元表示1元9角0分.\n【详解】1.90元是1元9角,原题结论错误。故答案为: ×", + "knowledge_points": [ + "元,角,分的认识及换算" + ], + "source": "23-24一年级下·河北邢台·期末" + }, + { + "id": "294", + "unit": "第五单元认识人民币", + "question_type": "判断题", + "difficulty": 0.65, + "question": "一个![](images/e2bf2b413c9629940a3f002357706ba1ae56f98ed88d730ae66265c635739531.jpg)4角,小明有1元钱,他能买3个![](images/03e945e4dfbd5ae25ff6cfec0323346d81b2d7a24a5b1cfb2a792b6d90cde04c.jpg)。( )", + "options": [ + + ], + "answer": "×", + "solution": "【分析】1元=10角,每个4角,10角最多买2个还剩2角.\n【详解】10角-4角=6角;6角-4角=2角;所以最多买2个,原题错误。故答案为: ×", + "knowledge_points": [ + "元,角,分的认识及换算", + "十元以下人民币的认识与计算" + ], + "source": "23-24一年级下·河北邢台·期末" + }, + { + "id": "295", + "unit": "第五单元认识人民币", + "question_type": "判断题", + "difficulty": 0.65, + "question": "妈妈买了 2 支标价 8.50 元的牙刷,一共应付给 17 元。( )", + "options": [ + + ], + "answer": "√", + "solution": "【分析】8.50元表示8元5角,两支相加,角满十进1元.\n【详解】8元5角+8元5角=17元;原题说法正确。故答案为:√", + "knowledge_points": [ + "十元以下人民币的认识与计算" + ], + "source": "22-23一年级下·广东汕头·期末" + }, + { + "id": "296", + "unit": "第五单元认识人民币", + "question_type": "判断题", + "difficulty": 0.65, + "question": "一张50元可以换5张10元,也可以换50枚1元硬币。( )", + "options": [ + + ], + "answer": "√", + "solution": "【分析】人民币兑换总面值不变,50里面有5个十也有50个一.\n【详解】一张50元可以换5张10元,也可以换50枚1元硬币。原题说法正确。故答案为:√", + "knowledge_points": [ + "100以内数的组成", + "元,角,分的认识及换算" + ], + "source": "22-23一年级下·河北廊坊·期末" + }, + { + "id": "297", + "unit": "第五单元认识人民币", + "question_type": "计算题", + "difficulty": 0.85, + "question": "算一算.\n7元8角一8角 = ( )元\n9角 +5 角 = ( )元( )角\n4元5角 +3 角 = ( )元( )角\n5元8角 +2 元 = ( )元( )角\n3元6角一2角 = ( )元( )角\n3元6角一2元 = ( )元( )角", + "options": [ + + ], + "answer": "7;1;4;4;8;7;8;3;4;1;6", + "solution": "【分析】人民币计算:元和元相加减,角和角相加减;角相加满十角进1元;角相减不够时向元借1元=10角.\n【详解】7元8角-8角=7元;9角+5角=14角=1元4角;4元5角+3角=4元8角;5元8角+2元=7元8角;3元6角-2角=3元4角;3元6角-2元=1元6角。", + "knowledge_points": [ + "元,角,分的认识及换算", + "十元以下人民币的认识与计算" + ], + "source": "23-24一年级下·全国·假期作业" + }, + { + "id": "298", + "unit": "第五单元认识人民币", + "question_type": "作图题", + "difficulty": 0.85, + "question": "圈出购物时应付的钱.\n![](images/212821.png)", + "options": [ + + ], + "answer": "见详解", + "solution": "【分析】题中笔记本价格为6元8角,付出的钱数为6元8角即可。计算时元和元相加,角和角相加.\n【详解】可以付1张5元,1张1元,1张5角,3枚1角。即5元+1元+5角+1角+1角+1角=6元8角;作图如下:![](images/88061efd248e9fc76a2dd9b445ef0c5c5a72c170c975b582123b470c8b811cb1.jpg)(画法不唯一)", + "knowledge_points": [ + "十元以下人民币的认识与计算" + ], + "source": "23-24一年级下·河南周口·期末" + }, + { + "id": "299", + "unit": "第五单元认识人民币", + "question_type": "解答题", + "difficulty": 0.94, + "question": "买一盒陀螺烟花需要 6 元,小明付出了 10 元,应找回多少钱。\n口答:应找回()元。", + "options": [ + + ], + "answer": "4;4元", + "solution": "【分析】付出的钱数-烟花的钱数=应找回的钱数.\n【详解】10-6=4(元);答:应找回4元钱。", + "knowledge_points": [ + "十元以下人民币的认识与计算" + ], + "source": "23-24 一年级下·福建福州·期中" + }, + { + "id": "300", + "unit": "第五单元认识人民币", + "question_type": "解答题", + "difficulty": 0.85, + "question": "购物.\n![](images/213501.png)", + "options": [ + + ], + "answer": "10粒;2元;3包;3元", + "solution": "【分析】(1) 1元=10角,求1元能买多少粒扣子就是1元里有几个1角;(2) 买4块橡皮是4个5角相加再换算;(3) 先算欣欣带了多少钱,再依次减4元,减了几次就是能买几包,最后剩下的钱就是还剩多少钱.\n【详解】(1) 1元=10角,10角能买10粒扣子。答:1元能买10粒![](images/3801b6e7448a56ec14992eae2f8f2e4082673dd0ac0c9f7e6266bb7f4ca85ca5.jpg)\n(2) 5角+5角+5角+5角=20角=2元。答:买4块橡皮需要付2元.\n(3) 5元+5元+5元=15元;15-4=11(元);11-4=7(元);7-4=3(元),减了3次4元。答:她能买3包饼干,还剩3元。", + "knowledge_points": [ + "元,角,分的认识及换算", + "十元以下人民币的认识与计算", + "十元以上人民币的认识与计算" + ], + "source": "23-24一年级下·河南周口·期中" + }, + { + "id": "301", + "unit": "第五单元认识人民币", + "question_type": "选择题", + "difficulty": 0.85, + "question": "飞机的价钱是多少。 ( )![](images/8a74a393e6bb83795c5af9c226683790ee39bce79c96bdab72cb4fae7bb63037.jpg)\n买这架飞机我付了2张找回的钱比10元多,比20元少。", + "options": [ + "A. 74元", + "B. 84 元", + "C. 94 元" + ], + "answer": "B", + "solution": "【分析】根据题意,付了 2 张 50 元,也就是 50 元 + 50 元 = 100 元。找回的钱比 10 元多,比 20 元少。如果找回的是 10 元,100 元里去掉 1 个 10 元,还剩 90 元;如果找回的是 20元,100 元里去掉一个 20 元,还剩 80 元。所以飞机的价钱应该在 80 元至 90 元之间,由此找到符合题意的数即可.\n【详解】A。 74 \u003c 80 \u003c 90,不符合题意;B. 80 \u003c 84 \u003c 90,符合题意;C. 94 \u003e 90 \u003e 80,不符合题意。飞机的价钱是 84 元。故答案为: B", + "knowledge_points": [ + "100 以内数的比大小", + "十元以上人民币的认识与计算" + ], + "source": "23-24 一年级下·全国·课后作业" + }, + { + "id": "302", + "unit": "第五单元认识人民币", + "question_type": "选择题", + "difficulty": 0.85, + "question": "一张![](images/df776982a26d4b786fc0a24923a06e569773e34e119ab07957f3cf0c8cbd461f.jpg)可以换一张![](images/adcc316f1ba69b3dfbc117a277c22988be17012f5f75ebc68b37d882dd9f8852.jpg)\n和()张![](images/aa4a6a0e814ee306a9fefef9b893bd8b0c4952d3f9826b382d595edad162a699.jpg)", + "options": [ + "A. 10", + "B. 15", + "C. 20" + ], + "answer": "A", + "solution": "【分析】根据题意,兑换即价值不变。50 元 + 50 元 = 100元,也就是 2 张 50 元可以换 1 张 100 元。已经换了 1 张 50元了,剩下的就是 50 元换为 5 元,看有几个 5 元即可.\n【详解】5元+5元+5元+5元+5元+5元+5元+5元+5元+5元=50元所以一张100元可以换一张![](images/548d92ad79ad158007697369ed614d211c27ca931297b748524a1538ca78bb14.jpg)\n和10张![](images/26f03d5575637b606ac56a8e4ed3cdf636ea811fdc3b2ddfb83475152be77b6d.jpg)故答案为: A", + "knowledge_points": [ + "元,角,分的认识及换算" + ], + "source": "23-24 一年级下·全国·课后作业" + }, + { + "id": "303", + "unit": "第五单元认识人民币", + "question_type": "选择题", + "difficulty": 0.85, + "question": "下面和 1 元硬币钱数不相等的是 ( )。", + "options": [ + "A. 2 枚 5 角硬币", + "B. 10 枚 1 角硬币", + "C. 5 枚 2 分硬币" + ], + "answer": "C", + "solution": "【分析】根据 1 元 = 10 角, 1 角 = 10 分,逐项分析选项中的人民币数值即可解答.\n【详解】A。 2 枚 5 角硬币, 5 + 5 = 10 (角), 和 1 元相等;B. 10 枚 1 角硬币, 10 个 1 角是 10 角,和 1 元相等;C. 5 枚 2 分硬币是 10 分, 10 分 = 1 角,和 1 元不相等;故答案为: C", + "knowledge_points": [ + "元,角,分的认识及换算" + ], + "source": "23-24 一年级下·全国·课后作业" + }, + { + "id": "304", + "unit": "第五单元认识人民币", + "question_type": "选择题", + "difficulty": 0.85, + "question": "一瓶果汁卖4()。", + "options": [ + "A. 元", + "B. 角", + "C. 分" + ], + "answer": "A", + "solution": "【分析】中华人民共和国的法定货币是人民币,元角分是货币单位,根据生活经验解答问题.\n【详解】果汁属于稍贵点的物品,应该用元做单位。故答案为:A", + "knowledge_points": [ + "元,角,分的认识及换算" + ], + "source": "23-24 二年级上·广东韶关·期末" + }, + { + "id": "305", + "unit": "第五单元认识人民币", + "question_type": "选择题", + "difficulty": 0.85, + "question": "妈妈买了 2 盒牛奶,每盒 4 元。如果付的都是 5 元的人民币,那么妈妈要付 ()张。", + "options": [ + "A. 2", + "B. 3", + "C. 4" + ], + "answer": "A", + "solution": "【分析】先求出需要付多少钱,然后算出几个5元才够付这些钱.\n【详解】 4 + 4 = 8 (元)5 + 5 = 10 (元);8元\u003c10元;妈妈要付2张。故答案为: A", + "knowledge_points": [ + "十元以下人民币的认识与计算" + ], + "source": "23-24 二年级上·河南周口·期末" + }, + { + "id": "306", + "unit": "第五单元认识人民币", + "question_type": "选择题", + "difficulty": 0.85, + "question": "一支圆珠笔的价格大约是 ( )。", + "options": [ + "A. 3 分", + "B. 3角", + "C. 30角", + "D. 30 元" + ], + "answer": "C", + "solution": "【分析】联系生活实际,圆珠笔是比较便宜的物品,价格大约在 3 元左右,据此分析各选项解答即可.\n【详解】A。3分的价格买不了一支笔,不符合题意;B. 3 角大约为一块橡皮的价格,不符合题意;C. 30 角 = 3 元,大约为一支圆珠笔的价格,符合题意;D. 30 元大约为 1 个书包的价格,不符合题意。一支圆珠笔的价格大约是 30 角。故答案为: C", + "knowledge_points": [ + "元,角,分的认识及换算" + ], + "source": "23-24 二年级上·福建泉州·期末" + }, + { + "id": "307", + "unit": "第五单元认识人民币", + "question_type": "选择题", + "difficulty": 0.85, + "question": "如图,一个书包的价格可能是 ( ).\n![](images/4a7683c543282ea72d4796abbdb37a3e013eb376d0bb0906e853c076a50f8424.jpg)", + "options": [ + "A. 98分", + "B. 98角", + "C. 98元" + ], + "answer": "C", + "solution": "【分析】联系生活实际,书包是较贵的物品,一般用元作单位较合适,据此解答即可.\n【详解】A。98分=9角8分,不适合作为书包的价钱;B. 98 角 = 9 元 8 角,不适合作为书包的价钱;C. 98 元,适合作为书包的价钱;因此一个书包的价格可能是 98 元。故答案为: C", + "knowledge_points": [ + "元,角,分的认识及换算" + ], + "source": "22-23一年级下·浙江温州·期末" + }, + { + "id": "308", + "unit": "第五单元认识人民币", + "question_type": "选择题", + "difficulty": 0.85, + "question": "妈妈买苹果用去 8 元,买西瓜用去 9 元,一共用去 ( )。", + "options": [ + "A. 17元", + "B. 1元7角", + "C. 7元1角" + ], + "answer": "A", + "solution": "【分析】根据题意,要求一共用了多少钱,用买苹果的钱加上买西瓜的钱就是一共花的钱.\n【详解】 8 + 9 = 17 (元)一共用去 17 元。故答案为: A", + "knowledge_points": [ + "9加几的进位加法", + "十元以上人民币的认识与计算" + ], + "source": "21-22 一年级下·广东佛山·期末" + }, + { + "id": "309", + "unit": "第五单元认识人民币", + "question_type": "选择题", + "difficulty": 0.85, + "question": "达瓦买铅笔需要 8 角,他给售货员 1 元,应该找回 ( )。", + "options": [ + "A. 1元8角", + "B. 2角", + "C. 2 分" + ], + "answer": "B", + "solution": "【分析】根据1元 = 10 角,先将货币单位统一,再根据减\n法的意义,列式解答即可.\n【详解】1元 = 10 角;10角-8角 = 2 角;所以,应找回2角。故答案为: B", + "knowledge_points": [ + "十元以下人民币的认识与计算" + ], + "source": "22-23 一年级下·全国·单元测试" + }, + { + "id": "310", + "unit": "第五单元认识人民币", + "question_type": "选择题", + "difficulty": 0.85, + "question": "小红买一本故事书,付了一张10元,售货员说还少了1元5角,这书的价钱是()。", + "options": [ + "A. 11元5角", + "B. 8元5角", + "C. 9元5角" + ], + "answer": "A", + "solution": "【分析】根据题意,用付出的钱加上少了的钱,即可解答.\n【详解】10元+1元5角=11元5角;故答案为:A", + "knowledge_points": [ + "十元以上人民币的认识与计算" + ], + "source": "22-23 一年级下·全国·单元测试" + }, + { + "id": "311", + "unit": "第五单元认识人民币", + "question_type": "选择题", + "difficulty": 0.65, + "question": "琪琪买了一样东西,刚好用去了 27 元,她买的是 ( )。", + "options": [ + "A. ![](images/5c2057012c662eb6909cb670eb77d6d586470d52641e30e3f372f3c1b088f186.jpg)\n饼干4元", + "B. ![](images/4dc9212cca7175bd40e27e78ce8019629d67f2ce3eb7f8a50d0a08d12ecc6d70.jpg)\n巧克力9元", + "C. ![](images/6f65d06535f7f964d1f77e02d5417a4d9211d3f6bd96945054eafbad48f18896.jpg)\n蛋糕 5元" + ], + "answer": "B", + "solution": "【分析】根据人民币及其常用单位和计算即可解答.\n【详解】A。饼干价格为4元,但是几袋饼干的价格都不能正好是27元,所以A不对;B. 巧克力的价格为 9 元,可以算出她买了 3 块巧克力。9+9+9=27 (元)C。 蛋糕的价格为 5 元,同理几个蛋糕的价格也不能正好是 27 元,所以 C 不对。故答案为: B", + "knowledge_points": [ + "十元以下人民币的认识与计算", + "十元以上人民币的认识与计算" + ], + "source": "22-23一年级下·全国·单元测试" + }, + { + "id": "312", + "unit": "第五单元认识人民币", + "question_type": "选择题", + "difficulty": 0.65, + "question": "买 1 顶帽子要 16 元,可以怎样付钱。 ( )", + "options": [ + "A. 1 张 10 元 +6 张 1 元", + "B. 1 张 10 元 +1 张6元", + "C. 2 张 5 元 +2 张 3 元" + ], + "answer": "A", + "solution": "【分析】根据人民币的面值和数量计算,够 16 元即可.\n【详解】A。1张10元和6张1元刚好是16元,正确;B. 人民币中没有 6 元的面值,错误;C. 人民币中没有 3 元的面值,错误。故答案为:A", + "knowledge_points": [ + "十元以上人民币的认识与计算" + ], + "source": "20-21 二年级上·广东韶关·期末" + }, + { + "id": "313", + "unit": "第五单元认识人民币", + "question_type": "选择题", + "difficulty": 0.65, + "question": "一盒彩笔 10 元 5 角,下列付钱方法中,最简便的是 ( )。", + "options": [ + "A. 1 张 10 元和 1 张 5 角", + "B. 10 张 1 元和 5张1角", + "C. 2 张 5 元和 1 张 5 角" + ], + "answer": "A", + "solution": "【分析】总钱数是 10 元 5 角,并且张数最少即可.\n【详解】一盒彩笔 10 元 5 角,下列付钱方法中,最简便的是 1 张 10 元和 1 张 5 角。故答案为:A", + "knowledge_points": [ + "十元以上人民币的认识与计算" + ], + "source": "22-23 二年级上·广东揭阳·期中" + }, + { + "id": "314", + "unit": "第五单元认识人民币", + "question_type": "选择题", + "difficulty": 0.85, + "question": "小兰去文具店买一支铅笔,付了1元,售货员找回4角,这支铅笔的价钱是()。", + "options": [ + "A. 4角", + "B. 6角", + "C. 1元4角" + ], + "answer": "B", + "solution": "【分析】用小兰付的钱减去找回的钱就是这支铅笔的价钱.\n【详解】1元 = 10 角;10角-4角=6角;故答案为: B", + "knowledge_points": [ + "元,角,分的认识及换算", + "十元以下人民币的认识与计算" + ], + "source": "20-21一年级下·河北保定·期末" + }, + { + "id": "315", + "unit": "第五单元认识人民币", + "question_type": "选择题", + "difficulty": 0.65, + "question": "在超市里买 4 袋饼干要付 8 元,买 8 袋饼干要付 ( ) 元。", + "options": [ + "A. 16", + "B. 12", + "C. 4" + ], + "answer": "A", + "solution": "【分析】根据题意,先看看 8 里面有几个 4,就表示一袋饼干多少元,再根据买 8 袋即要付 8 个几元,据此解答.\n【详解】因为8里有2个4,所以一袋饼干2元, 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 = 4 + 2 + 2 + 2 + 2 + 2 + 2 = 6 + 2 + 2 + 2 + 2 + 2 = 8 + 2 + 2 + 2 + 2 = 10 + 2 + 2 + 2 = 12 + 2 + 2 = 14 + 2 = 16(元)所以买 8 袋饼干要付 16 元。故答案为: A", + "knowledge_points": [ + "十元以上人民币的认识与计算" + ], + "source": "21-22 一年级下·湖北孝感·期末" + }, + { + "id": "316", + "unit": "第五单元认识人民币", + "question_type": "选择题", + "difficulty": 0.65, + "question": "一个书包的售价是53元,下面的付钱方法正确的是()。", + "options": [ + "A. 5 张 10 元和 1 张 5 元", + "B. 3 张 20 元和 3 张 1 元", + "C. 1 张 50 元和 3 张 1 元" + ], + "answer": "C", + "solution": "【分析】写出三个选项中支付的人民币数额,如果够应付的钱数,或者找回钱数正确,那么付钱方法就正确,由此求解.\n【详解】A。5张10元和1张5元是55元,钱数多了,所以A的支付方法不正确;B. 3 张 20 元和 3 张 1 元是 63 元,钱数多了,所以 B 的支付方法不正确;C. 1 张 50 元和 3 张 1 元是 53 元,正好是 53 元,所以 C 的支付方法正确。 故答案为: C", + "knowledge_points": [ + "十元以上人民币的认识与计算" + ], + "source": "21-22 一年级下·浙江温州·期末" + }, + { + "id": "317", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.85, + "question": "在括号里填\"\u003e\"或\"\u003c\"或\"=\".\n13角( )15分 14角( )1元4角 4元3角( )45角\n30角()30分 3元9角()4元 9元+12角()10元", + "options": [ + + ], + "answer": "\u003e;=;\u003c;\u003e;\u003c;\u003e", + "solution": "【分析】本题根据 1 元 = 10 角;1 角 = 10 分换算后再计算比较大小即可.\n【详解】15分=1角5分;13角\u003e1角5分,则13角\u003e15分;14角 = 1 元4角;45角 = 4 元5角;4元3角 \u003c 4 元5角,则4元3角 \u003c 45 角;30 分=3 角;30 角\u003e3 角,则 30 角\u003e30 分;3元9角\u003c4元;12角 = 1 元2角;9元 +1 元2角 = 10 元2角;10元2角\u003e10元,则9元+12角\u003e10元。", + "knowledge_points": [ + "元,角,分的认识及换算", + "十元以下人民币的认识与计算", + "十元以上人民币的认识与计算" + ], + "source": "23-24一年级下·河南周口·期中" + }, + { + "id": "318", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.65, + "question": "在括号里填上\"\u003c \",\"\u003e\"或\" = \".\n80( )7847( )7410角( )1元5角( )60分", + "options": [ + + ], + "answer": "\u003e;\u003c;=;\u003c", + "solution": "【分析】两位数比较大小时,先从十位比起,十位上的哪个数大哪个数就大,十位相同,再比较个位,个位上哪个数大哪个就大,1元=10角,1角=10分,先统一单位后再进行比大小,据此解答.\n【详解】(1)80 十位上是 8,78 的十位是 7,8 大于 7,故填空为:80(\u003e)78;(2) 47 十位上是 4, 74 十位上是 7, 4 小于 7,故填空为: 47(\u003c) 74;(3) 10角 = 1 元,故填空为:10角 (=) 1元;(4) 5角 = 50 分, 50 小于 60,故填空为: 5角 (\u003c) 60 分;", + "knowledge_points": [ + "100以内数的比大小", + "元,角,分的认识及换算" + ], + "source": "22-23 一年级下·广西贵港·期中" + }, + { + "id": "319", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.85, + "question": "9 角 +3 角 = ( ) 元( )角。", + "options": [ + + ], + "answer": "12", + "solution": "【分析】根据 1 元 = 10 角进行计算,满十角则变 1 元,据此解答即可.\n【详解】9角+3角=12角;12角 = 1 元2角,所以9角+3角=1元2角", + "knowledge_points": [ + "元,角,分的认识及换算", + "十元以下人民币的认识与计算" + ], + "source": "23-24 二年级上·河南许昌·期末" + }, + { + "id": "320", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.85, + "question": "一张 20 元 = ( )张10元=( )张1元 3元=( )角", + "options": [ + + ], + "answer": "2;20;30", + "solution": "【分析】人民币换算时价值不变。10元+10元=20元,共2张10元;1元+1元+1元+1元+1元+1元+1元+1元+1元+1元+1元+1元+1元+1元+1元+1元+1元+1元=20元,共20张1元。1元=10角,3元=30角.\n【详解】一张20元 = 2 张10元 = 20 张1元;3元 = 30 角", + "knowledge_points": [ + "元,角,分的认识及换算", + "十元以上人民币的认识与计算" + ], + "source": "22-23 一年级下·河北保定·期中" + }, + { + "id": "321", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.65, + "question": "算一算.\n4角7分 = ( )分 82角 = ( )元( )角16角-6角 =()角 = ( ) 元\n9角 +5 角 = ( )元( )角 4角 +4 元5角 = ( )元( )角", + "options": [ + + ], + "answer": "47;8;2;10;1;1;4;4;9", + "solution": "【分析】1角 = 10 分, 1元 = 10 角,据此计算填空即可.\n【详解】4角 = 40 分,所以4角7分 = 47 分;82角 = 80 角 +2 角 = 8 元2角;16角-6角 = 10 角 = 1 元;9角+5角=14角=1元4角;4角+4元5角=4元9角。", + "knowledge_points": [ + "元,角,分的认识及换算" + ], + "source": "23-24 一年级下·全国·课后作业" + }, + { + "id": "322", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.85, + "question": "填一填.\n1元 = ( )角 30分 = ( )角 6角 = ( )分\n50角 = ( ) 元 30角 = ( ) 元 7元 = ( ) 角", + "options": [ + + ], + "answer": "10;3;60;5;3;70", + "solution": "【分析】1元 = 10 角, 1角 = 10 分,据此换算并填空.\n【详解】1元 = 10 角;30分=3角;6角 = 60 分;50角 = 5 元;30角 = 3 元;7元 = 70 角", + "knowledge_points": [ + "元,角,分的认识及换算" + ], + "source": "23-24 一年级下·全国·课后作业" + }, + { + "id": "323", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.85, + "question": "1 张![](images/575b3541f1e6197a6a758dbbae116128a586b7b6cebb13a29ac6c8932d678104.jpg)可以换( )张![](images/c0dd046612011025093c3dab0ddb50f79e92b5a09285ca7a550266c48e5eae73.jpg)和( )张![](images/94744de360e4fab26e352b8ee5326020d45b6380ea5a4ec71693731286a876ad.jpg)。", + "options": [ + + ], + "answer": "1, 5", + "solution": "【分析】人民币换算时总价值不变。因为换的钱里要有 50 和 10 元的,50 元 + 10 元 + 10 元 + 10 元 + 10 元 = 100 元,由此解答.\n【详解】1 张100元可以换1张50元和5张10元", + "knowledge_points": [ + "元,角,分的认识及换算", + "十元以上人民币的认识与计算" + ], + "source": "23-24 一年级下·全国·课后作业" + }, + { + "id": "324", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.85, + "question": "1 张![](images/b974be3c31891dc60f7e87445476d7d430c5100fe6332a9c5be29a3db14c6376.jpg)\n可以换( )张![](images/8a88850a6d3e01613af0caf2f7fd11092871d073ce69ba8fc3275c056e5c0085.jpg)\n和( )张![](images/53b9ed78409d65c30e73fd8ae028e90e726a9fb56a16937d62d9127b642b6ca9.jpg)", + "options": [ + + ], + "answer": "2;2", + "solution": "【分析】2 张 20 元是 40 元,2 张 5 元是 10 元,合起来是 50 元,据此填空.\n【详解】1 张50元可以换2张20元和2张10元 (答案不唯一)", + "knowledge_points": [ + "十元以上人民币的认识与计算" + ], + "source": "17-18 一年级下·全国·单元测试" + }, + { + "id": "325", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.85, + "question": "想一想,填一填.\n4元 = ( )角 80分 = ( )角 39角 = ( ) 元( )角 7元8角 = ( )角\n20.50 元=( )元( )角", + "options": [ + + ], + "answer": "40;8;3;9;78;20;5", + "solution": "【分析】本题根据 1 元 = 10 角, 1 角 = 10 分进行换算解答。几十几角换算为几元几角时,几十角就是几元,剩余的就是几角;几元几角换算为几十几角时,几元就是几十角,再加上几角就是几十几角;20.5 元,\".\"前边的是元,后边的是角.\n【详解】4元 = 40 角;80分 = 8 角;39角 = 3 元9角;7元8角 = 78 角20.50元 = 20 元5角", + "knowledge_points": [ + "元,角,分的认识及换算" + ], + "source": "23-24一年级下·全国·课后作业" + }, + { + "id": "326", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.65, + "question": "1 张 10 元可以换成( )张 2 元,也可以换成( )张 1 元。", + "options": [ + + ], + "answer": "5;10", + "solution": "【分析】(1)求 10 里面有多少个 2,据此解答。(2) 求 10 里面有多少个 1,据此解答.\n【详解】 (1) 10÷2 = 5 (张)1 张 10 元可以换成 (5) 张 2 元;(2) 10×1 = 10 (张)也可以换成(10)张1元。", + "knowledge_points": [ + "十元以下人民币的认识与计算" + ], + "source": "23-24 二年级上·广东梅州·期末" + }, + { + "id": "327", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.85, + "question": "5角8分=( )分 83角 = ( ) 元( ) 角", + "options": [ + + ], + "answer": "58;8;3", + "solution": "【分析】根据\"1元=10角,1角=10分\"来换算单位即可.\n【详解】5角 = 50 分, 50 + 8 = 58,故, 5角8分 = 58 分;80角 = 8 元, 83 - 80 = 3,故, 83角 = 8 元3角。", + "knowledge_points": [ + "元,角,分的认识及换算" + ], + "source": "23-24 二年级上·广东梅州·期末" + }, + { + "id": "328", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.85, + "question": "1 张 1 元能换( )张 5 角,能换( )张 1 角。", + "options": [ + + ], + "answer": "2;10", + "solution": "【分析】根据 1 元 = 10 角可知, 1 元可以换 10 张 1 角;因为 10 角 = 5 角 + 5 角,所以 1 元可以换 2 张 5 角,据此解答即可.\n【详解】1 张 1 元能换(2)张 5 角,能换(10)张 1 角。", + "knowledge_points": [ + "元,角,分的认识及换算" + ], + "source": "22-23 一年级下·新疆巴音郭楞·期中" + }, + { + "id": "329", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.85, + "question": "在括号里填上合适的数.\n1元 = ( )角 20分 = ( )角\n1角 = ( )分 50角 = ( )元\n4元8角 = ( ) 角 27角 = ( )元( )角", + "options": [ + + ], + "answer": "10;2;10;5;48;2;7", + "solution": "【分析】由题意可知,根据 1 元 = 10 角, 1 角 = 10 分, 1 元 = 100 分,即可完成此题.\n【详解】1元 = (10)角 20分 = (2)角;1 角 = (10) 分 50 角 = (5) 元;4元8角 = (48) 角 27角 = (2) 元 (7) 角", + "knowledge_points": [ + "元,角,分的认识及换算" + ], + "source": "22-23一年级下·新疆巴音郭楞·期中" + }, + { + "id": "330", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.85, + "question": "一张100元可以换( )张10元;1张50元可以换3张10元和( )张20元", + "options": [ + + ], + "answer": "10;1", + "solution": "【分析】由题意可知, 100 里面有 10 个 10,则 100 元可以换取 10 张 10 元的, 3 张 10 元就是 30 元, 50 - 30 = 20,则 20 元里面有 1 张 20 元,据此解答即可.\n【详解】一张100元可以换(10)张10元;1 张50元 可以换3张10元 和 (1)张20元。", + "knowledge_points": [ + "十元以上人民币的认识与计算" + ], + "source": "22-23一年级下·浙江温州·期末" + }, + { + "id": "331", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.85, + "question": "31。(22-23一年级下·浙江杭州·期末)一个足球69元,小明:\"我带的钱正好够买一个,我最多带了( )张10元.\"小红:\"我买足球付的钱全是10元的,我付了( )张.\"", + "options": [ + + ], + "answer": "6;7", + "solution": "【分析】由题意可知,一个足球 69 元,小明带的钱正好够买一个足球,因为 60 元 + 9 元 = 69 元,所以 69 元里最多有 6 张 10 元;小红付的钱全是 10 元的,如果付 6 张 10 元,那就是 60 元,不够买一个足球,如果付 7 张 10 元,那就是 70元,买一个足球就够了,所以小红付了 7 张 10 元,据此解答即可.\n【详解】一个足球 69 元,小明:\"我带的钱正好够买一个,我最多带了 (6) 张 10 元.\"小红:\"我买足球付的钱全是 10 元的,我付了 (7) 张.\"", + "knowledge_points": [ + "元,角,分的认识及换算", + "十元以上人民币的认识与计算" + ], + "source": "22-23一年级下·浙江杭州·期末" + }, + { + "id": "332", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.65, + "question": "32。(22-23一年级下·浙江绍兴·期末)1元 = ( )角 38角 = ( ) 元( ) 角( )角 = 50 分 6 角 +7 角 = ( )元 ( )角 1元-7角 = ( ) 角 6元5角+3元9角 = ( ) 元( )角", + "options": [ + + ], + "answer": "10;3;8;5;1;3;3;10;4", + "solution": "【分析】1元 = 10 角,1角 = 10 分,据此换算即可.\n【详解】1元 = 10 角;38角 = 3 元8角;5角 = 50 分;6角+7角=1元3角;1元-7角=3角;6元5角+3元9角=10元4角", + "knowledge_points": [ + "元,角,分的认识及换算", + "十元以下人民币的认识与计算" + ], + "source": "22-23一年级下·浙江绍兴·期末" + }, + { + "id": "333", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.85, + "question": "小明用一元钱买了一支铅笔,还找回 4 角,这支铅笔( )角。", + "options": [ + + ], + "answer": "6", + "solution": "【分析】求这支铅笔的价钱,用一元钱减去找回的 4 角即可,注意单位统一为 \"角\".\n【详解】1元 = 10 角;10角-4角=6角,这支铅笔 6 角。", + "knowledge_points": [ + "元,角,分的认识及换算", + "十元以下人民币的认识与计算" + ], + "source": "22-23 一年级下·浙江绍兴·期末" + }, + { + "id": "334", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.85, + "question": "100 张 1 元的人民币是( )元。", + "options": [ + + ], + "answer": "100", + "solution": "【分析】100 张 1 元的人民币是多少元,根据数的组成即 100 个一是 100,由此解答.\n【详解】由分析得:100 张 1 元的人民币是 100 元。", + "knowledge_points": [ + "100以内数的组成", + "十元以上人民币的认识与计算" + ], + "source": "22-23 二年级下·全国·随堂练习" + }, + { + "id": "335", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.85, + "question": "1 张![](images/a963e6fdfd5f226a98a23ddea890c4f937aaf02a3f246512f25e1feace7c19db.jpg)\n可以换( )张![](images/386a2a786df64ccb6866a9761d1a92a9429f65f5aeda0e27132bdd61ecadce29.jpg)或\n( )枚![](images/8847891bc873753cf76202b66ec6a4fe258121a10eff77d7b50916abe18d7f6d.jpg)。", + "options": [ + + ], + "answer": "5;1", + "solution": "【分析】根据对人民币面值的认识,结合对 10 以内整数的认识:5 里面有 5 个一,据此进行解答即可.\n【详解】1 张5角可以换1角(5) 张或5角(1) 枚。", + "knowledge_points": [ + "元,角,分的认识及换算" + ], + "source": "22-23 一年级下·全国·随堂练习" + }, + { + "id": "336", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.65, + "question": "想一想,填一填.\n4元5角 = ( ) 角 68角 = ( ) 元( )角3元4角 = ( ) 角\n39角 = ( ) 元( )角 7元2角 = ( ) 角3角5分 = ( ) 分", + "options": [ + + ], + "answer": "45;6;8;34;3;9;72;35", + "solution": "【分析】根据1元 = 10 角,1角 = 10 分进行单位换算即可.\n【详解】4元5角 = 45 角;68角 = 6 元8角;3元4角 = 34 角;39角 = 3 元9角;7元2角 = 72 角;3角5分=35分", + "knowledge_points": [ + "元,角,分的认识及换算" + ], + "source": "22-23 一年级下·全国·随堂练习" + }, + { + "id": "337", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.85, + "question": "1 枚![](images/7af35e4324f6c95336a4339bc99aaf8b8536453b74accd133f8567e5aec94174.jpg)可以换( )张![](images/21fd40748eba46348fc8e5a784a2947a9008107c32f4330bc6463abcb3922dec.jpg)或( )枚![](images/8f5427762c7a6d0a2ed08d8b68257393c3ea9902bb5a7601deeb4db5342b53a1.jpg)", + "options": [ + + ], + "answer": "5;50", + "solution": "【分析】人民币间的换算即保持总面额不变。5个1角是5角;50个1分是5角,由此解答.\n【详解】1枚5角可以换5张1角或50枚1分。", + "knowledge_points": [ + "元,角,分的认识及换算" + ], + "source": "22-23 一年级下·全国·随堂练习" + }, + { + "id": "338", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.85, + "question": "一张 20 元可以换( )张 10 元,也可以换( )张 5 元。", + "options": [ + + ], + "answer": "2;4", + "solution": "【分析】根据对人民币面值的认识,结合20以内整数的组成:20里面有2个十,20里面有4个5,据此解答即可.\n【详解】一张20元可以换2张10元,也可以换4张5元。", + "knowledge_points": [ + "元,角,分的认识及换算" + ], + "source": "18-19 一年级下·云南曲靖·期中" + }, + { + "id": "339", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.85, + "question": "一张100元可以换( )张50元,也可以换( )张10元。", + "options": [ + + ], + "answer": "2;10", + "solution": "【分析】人民币间的互换即总面值保持不变即可。50元+50元=100元;10元+10元+10元+10元+10元+10元+10元+10元+10元=100元,由此解答.\n【详解】一张 100 元可以换 2 张 50 元,也可以换 10 张 10 元。", + "knowledge_points": [ + "元,角,分的认识及换算", + "十元以上人民币的认识与计算" + ], + "source": "22-23一年级下·全国·随堂练习" + }, + { + "id": "340", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.85, + "question": "40。(22-23一年级下·全国·随堂练习)( )个十是100,一张100元可以换( )张10元;( )个50是100,一张100元可以换( )张50元。", + "options": [ + + ], + "answer": "10;10;2;2", + "solution": "【分析】根据 100 里面有 10 个十和 100 里面有 2 个 50 进行解答即可.\n【详解】10个十是100,一张100元可以换10张10元;2个50是100,一张100元可以换2张50元。", + "knowledge_points": [ + "元,角,分的认识及换算" + ], + "source": "22-23一年级下·全国·随堂练习" + }, + { + "id": "341", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.85, + "question": "( )个十是 20,一张 20 元可以换( )张 10 元;( )个十是 50,一张 50 元可以换( )张 10 元。", + "options": [ + + ], + "answer": "2;2;5;5", + "solution": "【分析】根据人民币的面值,结合20以内整数组成:20里面有2个十,50里面有5个十,据此解答即可.\n【详解】2个十是20,一张20元可以换2张10元;5个十是50,一张50元可以换5张10元。", + "knowledge_points": [ + "100以内数的组成", + "元,角,分的认识及换算" + ], + "source": "22-23一年级下·全国·随堂练习" + }, + { + "id": "342", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.85, + "question": "( )个一是 5,一张 5 元可以换( )张 1 元;( )个一是 10,一张 10 元可以换( )张 1 元。", + "options": [ + + ], + "answer": "5;5;10;10", + "solution": "【分析】根据 10 以内整数的组成可知: 5 里面有 5 个一, 10 里面有 10 个一,据此解答即可.\n【详解】5个一是5,一张5元可以换5张1元;10个一是10,一张 10 元可以换 10 张 1 元。", + "knowledge_points": [ + "20以内数的组成", + "元,角,分的认识及换算" + ], + "source": "22-23一年级下·全国·随堂练习" + }, + { + "id": "343", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.65, + "question": "一张 100 元币可以换()张50元币和( )张10元币;一张50元币可以换( )张20元币和( )张5元币。", + "options": [ + + ], + "answer": "1;5;2;2", + "solution": "【分析】人民币间的互换即总面值保持不变即可.\n【详解】100元 = 50 元 + 10 元 + 10 元 + 10 元 + 10 元 + 10 元;50元 = 20 元 + 20 元 + 5 元 + 5 元;50 元 = 20 元 + 5 元 + 5 元 + 5 元 + 5 元 + 5 元。一张 100 元币可以换 1 张 50 元币和 5 张 10 元币;一张 50 元币可以换 2 张 20 元币和 2 张 5 元币。", + "knowledge_points": [ + "十元以下人民币的认识与计算", + "十元以上人民币的认识与计算" + ], + "source": "22-23 一年级·全国·假期作业" + }, + { + "id": "344", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.65, + "question": "一个热水瓶78元。如果都付10元一张的人民币,至少要付( )张;如果都付20元一张的人民币,至少要付( )张。", + "options": [ + + ], + "answer": "8;4", + "solution": "【分析】只要总钱数大于78元,并且接近78元即可.\n【详解】10元+10元+10元+10元+10元+10元+10元+10元=80元;20元+20元+20元+20元=80元。80元大于78元且接近78元。一个热水瓶 78 元。如果都付 10 元一张的人民币,至少要付 8 张;如果都付 20 元一张的人民币,至少要付 4 张。", + "knowledge_points": [ + "十元以上人民币的认识与计算" + ], + "source": "22-23一年级·全国·假期作业" + }, + { + "id": "345", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.65, + "question": "8 元 = ( )角 75角=( )元( )角 4元8角=( )角 70角=( )元", + "options": [ + + ], + "answer": "80;7;5;48;7", + "solution": "【分析】1元 = 10 角,几元就是几十角,据此换算即可.\n【详解】8元 = 80 角;75角 = 7 元5角;4元8角 = 48 角;70角 = 7 元", + "knowledge_points": [ + "元,角,分的认识及换算" + ], + "source": "21-22 一年级下·广东佛山·期末" + }, + { + "id": "346", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.85, + "question": "买一个35元的玩具,要付()张![](images/ac8ee3416c270af5642c13f457a11679ed1fe282e052a2062c6dcfe88a134e73.jpg)\n和()张![](images/9a482b25a5abbac3aaace0c36a9ed9344578f819dd937ed067f6b3d6e154ae45.jpg)。", + "options": [ + + ], + "answer": "3;5", + "solution": "【分析】根据对人民币面值的认识,结合题干要求,人民币面值合起来等于35元即可.\n【详解】买一个35元的玩具,要付3张![](images/ca63e7ef7f72c0bb5542845cfc4867d76c949481131f241785b494a2bc92952c.jpg)\n和5张![](images/4e7d460ac030be39e36b2d6312d8c227ef510283fdfcd7a8761f41f65a527a82.jpg)", + "knowledge_points": [ + "十元以上人民币的认识与计算" + ], + "source": "21-22 一年级下·广东佛山·期末" + }, + { + "id": "347", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.85, + "question": "50 角 = () 元 4 角 =()分 3元5角+5角=()元 32分=() 元() 分", + "options": [ + + ], + "answer": "5;40;4;3;2", + "solution": "【分析】根据 1 元 = 10 角, 1 角 = 10 分,进行单位换算即可.\n【详解】50角 = 5 元;4角 = 40 分;5角+5角=10角,10角=1元,所以3元5角+5角=4元;30 分=3 角,所以 32 分=3 角 2 分", + "knowledge_points": [ + "元,角,分的认识及换算", + "十元以下人民币的认识与计算" + ], + "source": "21-22 一年级下·广东佛山·期末" + }, + { + "id": "348", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.65, + "question": "3 元 =()角 4元8角 = () 角 56分 = () 角 分 15元-8元 = () 元", + "options": [ + + ], + "answer": "30;48;5;6;7", + "solution": "【分析】根据1元 = 10 角;1角 = 10 分进行换算;几元几角换算成角时,几元就是几十角,再加上几角就是几十几角;几十几分换算成几角几分时,几十几分中的几十分就是几角,几角和剩下的几分合在一起就是几角几分。计算时,单位相同时直接计算,如元和元相加减,角和角相加减.\n【详解】3元 = 30 角;4元8角 = 48 角;56分=5角6分;15元-8元=7元", + "knowledge_points": [ + "元,角,分的认识及换算", + "十元以下人民币的认识与计算", + "十元以上人民币的认识与计算" + ], + "source": "21-22 一年级下·广东广州·期末" + }, + { + "id": "349", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.85, + "question": "5 元 3 角 = ( )角 1元7角+4角=( )元( )角", + "options": [ + + ], + "answer": "53;2;1", + "solution": "【分析】根据 1 元 = 10 角进行换算;几元几角换算成角时,几元就是几十角,再加上几角就是几十几角。单位相同时直接计算,如元和元相加,角和角相加,若角相加满十则进为一元.\n【详解】由分析得:5元3角 = 53 角;1元7角 +4 角 = 2 元 1 角", + "knowledge_points": [ + "元,角,分的认识及换算", + "十元以下人民币的认识与计算" + ], + "source": "21-22 一年级下·广东广州·期末" + }, + { + "id": "350", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.85, + "question": "50。(21-22一年级下·广东佛山·期末)20角i( )元60分=( )角34角 = ( ) 元( )角 6元4角-3元( )元( )角", + "options": [ + + ], + "answer": "2;6;3;4;3;4", + "solution": "【分析】根据 1 元 = 10 角;1 角 = 10 分进行换算;几十几角换算成几元几角时,几十几角中的几十角就是几元,几\n元和剩下的几角合在一起就是几元几角。计算时,单位相同时直接计算,如元和元相加减,角和角相加减.\n【详解】20角 = 2 元;60分 = 6 角;34角 = 3 元4角;6元4角 -3 元 = 3 元4角", + "knowledge_points": [ + "元,角,分的认识及换算", + "十元以下人民币的认识与计算" + ], + "source": "21-22一年级下·广东佛山·期末" + }, + { + "id": "351", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.85, + "question": "51。(22-23一年级下·全国·课前预习)1角 = ( )分 20\n分 = ( ) 角 1 元 = ( ) 角\n10角 = ( ) 元40角 = ( ) 元5元 = ( ) 角", + "options": [ + + ], + "answer": "10;2;10;1;4;50", + "solution": "【分析】根据1元 = 10 角,1角 = 10 分进行解答即可.\n【详解】1角 = 10 分;20分=2角;1元=10角;10角 = 1 元;40角 = 4 元;5元 = 50 角", + "knowledge_points": [ + "元,角,分的认识及换算" + ], + "source": "22-23一年级下·全国·课前预习" + }, + { + "id": "352", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.94, + "question": "1 角 = ( ) 分 40角 = ( ) 元5元 = ( ) 角", + "options": [ + + ], + "answer": "10;4;50", + "solution": "【分析】根据1元 = 10 角,1角 = 10 分进行单位换算即可.\n【详解】1角 = 10 分;40角 = 4 元;5元=50角", + "knowledge_points": [ + "元,角,分的认识及换算" + ], + "source": "22-23 一年级下·全国·课前预习" + }, + { + "id": "353", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.65, + "question": "解决人民币的问题,列算式时,每个数都必须带( );单位不一样的,先( ), 然后元和元相加减,角和角相加减,分和分相加减。", + "options": [ + + ], + "answer": "单位,统一单位", + "solution": "【详解】解决人民币的问题,列算式时,每个数必须带单位。例如:6角+3角=9角。单位不一样的,先统一单位,然后元和元相加减,角和角相加减,分和分相加减。例如:求1元比5角多多少。1元=10角,10角-5角=5角,所以1元比5角多5角。", + "knowledge_points": [ + "元,角,分的认识及换算", + "十元以下人民币的认识与计算" + ], + "source": "22-23 一年级下·全国·课前预习" + }, + { + "id": "354", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.85, + "question": "\n![](images/5ba84218af1d10be1b34242c7399234d666356cc15fe487b4d8d2b0018dc0cb9.jpg)\n![](images/4b96db791b16b8229e0e9ce253566375d0e27d1349f46725f4e92754fae0c7bb.jpg)\n![](images/90f4d6f7d3913bf7100065e2d7bf701340ab3272f1319d6b07e99e5e7b85784f.jpg)\n1元可以换( )个1角,再加上2个1角是( )角,所以1元2角 = ( ) 角。", + "options": [ + + ], + "answer": "10;12;12", + "solution": "【分析】根据 1 元 = 10 角,再结合题干要求进行解答即可.\n【详解】1元可以换(10)个1角,再加上2个1角是(12)角,所以1元2角 = (12) 角。", + "knowledge_points": [ + "元,角,分的认识及换算" + ], + "source": "22-23 一年级下·全国·课前预习" + }, + { + "id": "355", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.85, + "question": "8 元 +5 角 = ( )元( )角 12元-7元 = ( )元 8元+9角=( )元( )角 6元5角-5角=( )元 3元5角 +1 角 = ( )元( )角 8元7角-5角 = ( )元( )角 7元3角+3角 = ( )元( )角", + "options": [ + + ], + "answer": "85;5;8;9;6;3;6;8;2;7;6", + "solution": "【分析】根据题意,元与元相加或相减,角与角相加或相减计算即可\n【详解】8元+5角=8元5角;12元-7元=5元;8元+9角=8元9角;6元5角-5角=6元;3元5角+1角=3元6角;8元7角-5角=8元2角;7元3角+3角=7元6角", + "knowledge_points": [ + "十元以下人民币的认识与计算", + "十元以上人民币的认识与计算" + ], + "source": "21-22 一年级下·全国·单元测试" + }, + { + "id": "356", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.85, + "question": "2 角 = ( ) 分 1元5角 = ( )角 65角 = ( ) 元( )角 38角 = ( ) 元( )角", + "options": [ + + ], + "answer": "20;15;6;5;3;8", + "solution": "【分析】本题可根据1元 = 10 角,1角 = 10 分来计算解答.\n【详解】2角 = 20 分;1元5角 = 15 角;65角 = 6 元5角;38角 = 3 元8角", + "knowledge_points": [ + "元,角,分的认识及换算" + ], + "source": "21-22 一年级下·全国·单元测试" + }, + { + "id": "357", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.85, + "question": "一件上衣的价钱约为 50( ),一支铅笔的价钱约为 8( )。", + "options": [ + + ], + "answer": "元角", + "solution": "【分析】根据生活经验,衣服的价格一般用元作单位,一支铅笔的价格一般用角作单位.\n【详解】一件上衣的价钱约为 50 元,一支铅笔的价钱约为 8 角。", + "knowledge_points": [ + "元,角,分的认识及换算" + ], + "source": "21-22 一年级下·全国·单元测试" + }, + { + "id": "358", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.65, + "question": "10元能换( )张1元的,还可以换( )张5角的。", + "options": [ + + ], + "answer": "10;20", + "solution": "【分析】根据题意,几张 1 元的相加为 10 元,几张 5 角的相加为 10 元,计算即可.\n【详解】1元+1元+1元+1元+1元+1元+1元+1元+1元+1元=10元;5角+5角+5角+5角+5角+5角+5角+5角+5角+5角+5角+5角+5角+5角+5角+5角+5角+5角+5角+5角+5角+5角+5角+5角+5角+5角=10元。10元能换10张1元的,还可以换20张5角的。", + "knowledge_points": [ + "十元以下人民币的认识与计算" + ], + "source": "21-22一年级下·全国·单元测试" + }, + { + "id": "359", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.65, + "question": "75 角 = ( ) 元( )角 3元8角 = ( )角", + "options": [ + + ], + "answer": "7;5;38", + "solution": "【分析】根据人民币元,角,分换算口诀公式:1 元 = 10 角,1 角 = 10 分,1 元 = 100 分,即可得出答案.\n【详解】75角 = (7) 元(5)角;3元8角 = (38) 角", + "knowledge_points": [ + "元,角,分的认识及换算" + ], + "source": "22-23 一年级下·全国·单元测试" + }, + { + "id": "360", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.85, + "question": "买一个角,付出 1 元,应找回( ).\n![](images/f00828b0b0c953c7b25ee986b426c01c42e78cad54491f24b70980709463d6e6.jpg)\n要4角", + "options": [ + + ], + "answer": "6角", + "solution": "【分析】1元 = 10 角,用了 4 角,用付的钱数减去要用去的钱数即可解答.\n【详解】 10 - 4 = 6 (角)故应找回6角。", + "knowledge_points": [ + "元,角,分的认识及换算", + "十元以下人民币的认识与计算" + ], + "source": "22-23 一年级下·全国·单元测试" + }, + { + "id": "361", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.85, + "question": "一张 20 元可以换( )张 5 元,也可以换( )张 1 元。", + "options": [ + + ], + "answer": "4;20", + "solution": "【分析】 5 + 5 + 5 + 5 = 20,即,1 张 20 元的人民币可以换 4 张 5 元的;20 里面有 20 个 1,故,一张 20 元的人民币可以换 20 张 1 元的;据此填空.\n【详解】由题意知 1 张 20 元的人民币可以换 4 张 5 元的;也可以换 20 张 1 元的。", + "knowledge_points": [ + "元,角,分的认识及换算" + ], + "source": "22-23 一年级下·全国·单元测试" + }, + { + "id": "362", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.65, + "question": "26 角 = ( ) 元( )角 50分=( )角5元8角=( )角", + "options": [ + + ], + "answer": "2;6;5;58", + "solution": "【分析】根据 1 元 = 10 角, 1 角 = 10 分,解答此题即可.\n【详解】26角 = 2 元6角;50分 = 5 角;5元8角 = 58 角", + "knowledge_points": [ + "元,角,分的认识及换算", + "十元以下人民币的认识与计算" + ], + "source": "22-23 一年级下·全国·单元测试" + }, + { + "id": "363", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.65, + "question": "王老师有 10 元,买一本书还差 1 元 2 角,这本书的价格是( )。", + "options": [ + + ], + "answer": "11元2角", + "solution": "【分析】根据人民币及其常用单位和计算即可解答.\n【详解】王老师有 10 元,买一本书还差 1 元 2 角,说明王老师的钱不够这本书的价格,要加上差的那一部分,所以要用加法计算,即:10 元 + 1 元 2 角 = 11 元 2 角所以这本书的价格是 11 元 2 角。", + "knowledge_points": [ + "十元以下人民币的认识与计算", + "十元以上人民币的认识与计算" + ], + "source": "22-23 一年级下·全国·单元测试" + }, + { + "id": "364", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.65, + "question": "100 张 10 元是( )元,100 张 100 元是( )元。", + "options": [ + + ], + "answer": "1000;10000", + "solution": "【分析】根据 10 个一百是一千, 100 个一百是一万,解答此题即可.\n【详解】100 张 10 元是 1000 元,100 张 100 元是 10000 元。", + "knowledge_points": [ + "十元以上人民币的认识与计算" + ], + "source": "人教版数学一年级下册第五单元《认识人民币》单元测试卷" + }, + { + "id": "365", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.65, + "question": "小明的存钱罐里有 1 元和 5 角的硬币若干枚。他想买一盒 6 元的水彩笔,有种不同的付钱方法。", + "options": [ + + ], + "answer": "7", + "solution": "【分析】分类讨论,只要总钱数是6元即可.\n【详解】第一种:6枚1元,第二种:1枚1元10枚5角,第三种:2枚1元8枚5角,第四种:3枚1元6枚5角,第五种:4枚1元4枚5角,第六种:5枚1元2枚5角,第七种:12枚5角,所以有 7 种不同的付钱方法。", + "knowledge_points": [ + "排列组合问题", + "搭配问题", + "元,角,分的认识及换算" + ], + "source": "21-22 六年级上·山东德州·期末" + }, + { + "id": "366", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.65, + "question": "我会填一填.\n9角=( )分 56角=( )元( )角\n3元5角=( )角 9元4角=( )角\n1张5角+2张1角+1张1角=( )角\n2张5角+3张5角+4张2角=( )元( )角", + "options": [ + + ], + "answer": "90;5;6;35;94;8;3", + "solution": "【分析】根据 1 元 = 10 角, 1 角 = 10 分,解答此题即可.\n【详解】9角 = 90 分;56角=5元6角;3元5角 = 35 角;9元4角 = 94 角;1 张 5 角 +2 张 1 角 +1 张 1 角 =8 角;2 张 5 角 +3 张 5 角 +4 张 2 角 = 3 元 3 角", + "knowledge_points": [ + "元,角,分的认识及换算", + "十元以下人民币的认识与计算" + ], + "source": "21-22 二年级上·广东河源·期末" + }, + { + "id": "367", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.85, + "question": "2 元 4 角 = ( )角 56分 = () 角( )分 1元4角+6角=()元 2元4角+3元2角=()元( )角", + "options": [ + + ], + "answer": "24;5;6;2;5;6", + "solution": "【分析】10角 = 1 元, 10分 = 1 角,据此解答.\n【详解】2元4角 = 24 角,56分 = 5 角6分;1元4角+6角=2元,2元4角+3元2角=5元6角。", + "knowledge_points": [ + "元,角,分的认识及换算", + "十元以下人民币的认识与计算" + ], + "source": "20-21 一年级下·河北保定·期末" + }, + { + "id": "368", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.65, + "question": "一张![](images/f6ba5f29c9a0ce9ab88c5750f1d4baaeb2c4e7553c49749e8217532ed49697c6.jpg)\n的人民币可以换( )张![](images/fbc20f1dfa370e40443d2de180ffe23b81154e290f17c7148ac1b956f9b8cf35.jpg)的和( )张![](images/36b3e574ac4df40d878304cb6b1e9b368f6386221693a2dd78535d42005e8433.jpg)的。", + "options": [ + + ], + "answer": "2;1", + "solution": "【分析】根据人民币的面值,50元 = 20 元 + 20 元 + 10 元,据此解答.\n【详解】一张 50 元的人民币,可以换 2 张 20 元和 1 张 10 元的人民币。(答案不唯一)", + "knowledge_points": [ + "元,角,分的认识及换算" + ], + "source": "20-21 一年级下·贵州六盘水·期末" + }, + { + "id": "369", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.65, + "question": "16 元 -4 元 5 角 = ( ) 元 ( ) 角。", + "options": [ + + ], + "answer": "11;5", + "solution": "【分析】根据 1 元 = 10 角,将 16 元换算为 15 元 10 角,进行计算即可.\n【详解】16元一4元5角 = 11 元5角。", + "knowledge_points": [ + "十元以上人民币的认识与计算" + ], + "source": "20-21 一年级下·贵州六盘水·期末" + }, + { + "id": "370", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.65, + "question": "5 角 +8 角 = ( )元( )角 9 元 -5 元 = ( )元 1 张 100 元可以换( )张 20 元", + "options": [ + + ], + "answer": "1;3;4;5", + "solution": "【分析】 (1) (2) 先计算出结果,再根据 1元 = 10 角,进行换算即可。(3) 根据人民币的面值, 5 张 20 元是 100 元,由此解答.\n【详解】5角+8角=13角=1元3角 9元-5元=4元1张100元可以换5张20元", + "knowledge_points": [ + "元,角,分的认识及换算" + ], + "source": "21-22 一年级下·广东江门·期末" + }, + { + "id": "371", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.65, + "question": "明明有4张1元,1张5角,1张2角可以组成( )元( )角 = ()角。", + "options": [ + + ], + "answer": "4;7;47", + "solution": "【分析】4 张 1 元是 4 元, 1 张 5 角和 1 张 2 角合起来是 7 角,且 1 元 = 10 角,据此解答.\n【详解】明明有4张1元,1张5角,1张2角可以组成(4) 元 (7) 角 = (47) 角。", + "knowledge_points": [ + "元,角,分的认识及换算", + "十元以下人民币的认识与计算" + ], + "source": "21-22一年级下·黑龙江双鸭山·期末" + }, + { + "id": "372", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.65, + "question": "一张50元的人民币可以换( )张10元的人民币;一张10元的人民币可以换( )张5元的人民币,也可以换( )张1元的人民币。", + "options": [ + + ], + "answer": "5或五;2或二;10或十", + "solution": "【分析】50里面有5个10,所以一张50元可以换5张10元的,10里面有2个5,所以一张10元可以换2张5元,10里面有10个1,所以一张10元可以换10张1元,据此解答.\n【详解】一张50元的人民币可以换(5)张10元的人民币;一张10元的人民币可以换(2)张5元的人民币,也可以换(10)张1元的人民币。", + "knowledge_points": [ + "十元以下人民币的认识与计算", + "十元以上人民币的认识与计算" + ], + "source": "21-22一年级下·黑龙江双鸭山·期末" + }, + { + "id": "373", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.65, + "question": "6 元 +5 角 = ( )元( )角 1 元 -7 角 = ( )角 6元9角-5角 = ( ) 元( )角 9角+8角 = ( ) 元( )角", + "options": [ + + ], + "answer": "6;3;6;1;7", + "solution": "【分析】根据 1 元 = 10 角解答此题即可.\n【详解】6元+5角=6元5角;1元-7角=10角-7角=3角;6元9角-5角=6元4角;9角 + 8角 = 17角 = 1元 7角", + "knowledge_points": [ + "十元以下人民币的认识与计算" + ], + "source": "21-22 一年级下·重庆大渡口·期末" + }, + { + "id": "374", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.85, + "question": "3 元 = ( )角 5 元 6 角 = ( )角\n4元+5角=( )元( )角 28角=( )元( )角", + "options": [ + + ], + "answer": "30;56;4;5;2;8", + "solution": "【分析】根据 1 元 = 10 角进行单位换算即可.\n【详解】3元 = 30 角;5元6角 = 56 角;4元+5角=4元5角;28角= 2元8角", + "knowledge_points": [ + "元,角,分的认识及换算", + "十元以下人民币的认识与计算" + ], + "source": "21-22 一年级下·河南郑州·期末" + }, + { + "id": "375", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.85, + "question": "小雨买巧克力花了 6 元 2 角,她付给售货员 6 元 5 角,应找回( )角。", + "options": [ + + ], + "answer": "3", + "solution": "【分析】根据付的钱数减去商品的价格,等于找回的钱数,据此解答即可.\n【详解】6元5角-6元2角=3角应找回3角。", + "knowledge_points": [ + "十元以下人民币的认识与计算" + ], + "source": "21-22 一年级下·四川广元·期末" + }, + { + "id": "376", + "unit": "第五单元认识人民币", + "question_type": "判断题", + "difficulty": 0.65, + "question": "3 元 -1 元 5 角 = 2 元 5 角。( )", + "options": [ + + ], + "answer": "×", + "solution": "【分析】3元等于2元10角,再用2元10角减1元5角,相同单位相减即可.\n【详解】2元10角减1元5角 = 1 元5角,此说法错误。故答案为: ×", + "knowledge_points": [ + "元,角,分的认识及换算" + ], + "source": "23-24 二年级上·广东韶关·期末" + }, + { + "id": "377", + "unit": "第五单元认识人民币", + "question_type": "判断题", + "difficulty": 0.85, + "question": "一张 20 元人民币可以换 4 张 5 元或 2 张 10 元。( )", + "options": [ + + ], + "answer": "√", + "solution": "【分析】由题意可知,因为 20 = 10 + 10 , 20 里面有 2 个 10,所以 1 张 20 元可以换 2 张 10 元;又因为 20 = 5 + 5 + 5 + 5 , 20 里面有 4 个 5,所以 1 张 20 元能换 4 张 5 元,据此解答即可.\n【详解】一张 20 元人民币可以换 4 张 5 元或 2 张 10 元。故答案为: √", + "knowledge_points": [ + "元,角,分的认识及换算" + ], + "source": "23-24 二年级上·河南驻马店·期中" + }, + { + "id": "378", + "unit": "第五单元认识人民币", + "question_type": "判断题", + "difficulty": 0.85, + "question": "1 元 2 角就是 12 角。", + "options": [ + + ], + "answer": "√", + "solution": "【分析】由题意可知, 1 元 2 角 = 1 元 + 2 角, 1 元 = 10 角,所以 1 元 2 角 = 10 角 + 2 角, 1 元 2 角 = 12 角,据此解答即可.\n【详解】1元2角就是12角。故答案为: √", + "knowledge_points": [ + "元,角,分的认识及换算" + ], + "source": "22-23 一年级下·浙江绍兴·期末" + }, + { + "id": "379", + "unit": "第五单元认识人民币", + "question_type": "判断题", + "difficulty": 0.85, + "question": "5 枚 1 角硬币和 1 枚 5 角硬币一样多。( )", + "options": [ + + ], + "answer": "√", + "solution": "【分析】5枚1角的是5角,1枚5角的也是5角,据此解答即可.\n【详解】5枚1角硬币和1枚5角硬币一样多,原题说法正确。故答案为: √", + "knowledge_points": [ + "十元以下人民币的认识与计算" + ], + "source": "23-24 二年级上·全国·期中" + }, + { + "id": "380", + "unit": "第五单元认识人民币", + "question_type": "判断题", + "difficulty": 0.85, + "question": "用 2 张 5 角可以换 10 张 1 角。( )", + "options": [ + + ], + "answer": "√", + "solution": "【分析】算算 2 张 5 角是多少钱,再算算 10 张 1 角是多少钱,如果它们的钱数相等,就可以互换.\n【详解】5角+5角=10角,1角+1角+1角+1角+1角+1角+1角+1角+1角=10角,所以用 2 张 5 角可以换 10 张 1 角,所以这句话正确。故答案为: √ 。", + "knowledge_points": [ + "元,角,分的认识及换算" + ], + "source": "22-23一年级下·全国·单元测试" + }, + { + "id": "381", + "unit": "第五单元认识人民币", + "question_type": "判断题", + "difficulty": 0.65, + "question": "从 1 元和 5 元的纸币中拿走 10 元,共有 3 种不同的拿法。( )", + "options": [ + + ], + "answer": "√", + "solution": "【分析】根据人民币面值进行组合即可,所拿的人民币面值总和等于 10 元即可.\n【详解】第一种:10 张 1 元;第二种:2张5元;第三种: 5 张 1 元和 1 张 5 元。所以一共有 3 种不同的拿法。原题说法正确。故答案为: √", + "knowledge_points": [ + "元,角,分的认识及换算" + ], + "source": "22-23 二年级上·贵州铜仁·期末" + }, + { + "id": "382", + "unit": "第五单元认识人民币", + "question_type": "判断题", + "difficulty": 0.65, + "question": "10 张 2 角和 4 张 5 角的钱数一样多。( )", + "options": [ + + ], + "answer": "√", + "solution": "【分析】计算出 10 张 2 角和 4 张 5 角分别是多少钱,然后作比较即可.\n【详解】10 张 2 角 = 20 角;4 张 5 角 = 20 角;20角 = 20 角;即 10 张 2 角和 4 张 5 角的钱数一样多,原题说法正确。故答案为: √", + "knowledge_points": [ + "十元以下人民币的认识与计算" + ], + "source": "21-22 二年级上·广东河源·期末" + }, + { + "id": "383", + "unit": "第五单元认识人民币", + "question_type": "判断题", + "difficulty": 0.65, + "question": "一个羽毛球 2 元 5 角,付了 2 张 2 元,应找回 5 角。( )", + "options": [ + + ], + "answer": "×", + "solution": "【分析】根据 1 元 = 10 角,解答此题即可.\n【详解】2元+2元-2元5角=1元5角;所以一个羽毛球 2 元 5 角,付了 2 张 2 元,应找回 1 元 5 角,原题说法错误。故答案为: ×", + "knowledge_points": [ + "元,角,分的认识及换算", + "十元以下人民币的认识与计算" + ], + "source": "22-23 二年级上·广东揭阳·期中" + }, + { + "id": "384", + "unit": "第五单元认识人民币", + "question_type": "判断题", + "difficulty": 0.85, + "question": "小明买铅笔花了 3 元 5 角,小红买铅笔花了 35 角,小明花的钱比小红花的钱少。( )", + "options": [ + + ], + "answer": "×", + "solution": "【分析】10角 = 1 元,将单位统一后作比较即可.\n【详解】35角 = 3 元5角,所以小明花的钱和小红花的钱一样多。故答案为: ×", + "knowledge_points": [ + "元,角,分的认识及换算" + ], + "source": "20-21 一年级下·河北保定·期末" + }, + { + "id": "385", + "unit": "第五单元认识人民币", + "question_type": "判断题", + "difficulty": 0.85, + "question": "一张 100 元人民币,可以换 100 张 1 元人民币。( )", + "options": [ + + ], + "answer": "√", + "solution": "【分析】根据人民币的面值,只要总钱数保持不变即可.\n【详解】100 个 1 元是 100 元,所以一张 100 元人民币,可以换 100 张 1 元人民币,这句话是正确的。故答案为: √", + "knowledge_points": [ + "元,角,分的认识及换算" + ], + "source": "21-22 一年级下·湖南娄底·期末" + }, + { + "id": "386", + "unit": "第五单元认识人民币", + "question_type": "计算题", + "difficulty": 0.65, + "question": "算一算.\n9元-2元 = () 5角+1元3角 =() 7角 +6 角 =() 8元 +9 元 =()\n6元5角-5角 =() 3元2角-2元=()", + "options": [ + + ], + "answer": "7元;1元8角;1元3角;17元;6元;1元2角", + "solution": "【分析】本题计算时可根据元加,减元,角加,减角,满十角进1元,不够十角借一元来计算。1元=10角.\n【详解】9元-2元=7元;5角+1元3角=1元8角;7角+6角=13角=1元3角;8元+9元=17元;6元5角-5角=6元;3元2角-2元=1元2角。", + "knowledge_points": [ + "十元以下人民币的认识与计算", + "十元以上人民币的认识与计算" + ], + "source": "22-23 一年级下·全国·课前预习" + }, + { + "id": "387", + "unit": "第五单元认识人民币", + "question_type": "解答题", + "difficulty": 0.85, + "question": "一把剪刀 5 元,一把尺子9角,拿10元钱买一把剪刀和一把尺子,还剩多少钱。", + "options": [ + + ], + "answer": "4元1角", + "solution": "【分析】先用加法把一把剪刀和一把尺子的价钱加起来,求出要花的钱,再用 10 元钱减去要花的钱,求出差,即可解决.\n【详解】5元+9角=5元9角;10元-5元9角=4元1角,答:还剩 4 元 1 角。", + "knowledge_points": [ + "十元以下人民币的认识与计算" + ], + "source": "23-24 二年级上·河南许昌·期末" + }, + { + "id": "388", + "unit": "第五单元认识人民币", + "question_type": "解答题", + "difficulty": 0.85, + "question": "亮亮买 1 个乒乓球和1个羽毛球,一共花了8元。毛毛买1个乒乓球和2个羽毛球,一共花了13元。一个羽毛球多少元。", + "options": [ + + ], + "answer": "5元", + "solution": "【分析】根据题意可知,用 13 元买的东西比 8 元买的东西多 1 个羽毛球,所以用 13 - 8 计算即可求出羽毛球的价格.\n【详解】 13 - 8 = 5 (元)答:一个羽毛球 5 元。", + "knowledge_points": [ + "十元以上人民币的认识与计算" + ], + "source": "23-24 一年级下·全国·课后作业" + }, + { + "id": "389", + "unit": "第五单元认识人民币", + "question_type": "解答题", + "difficulty": 0.85, + "question": "一个 8元5角,一支 1元。买1个 和一支 共需要多少钱。\n答:一共要()。", + "options": [ + + ], + "answer": "9元5角", + "solution": "【分析】由题意可知,一个 8元5角,一支 1元。问题是买 1 个 和一支 一共需要多少钱,那就把这两个物品的价钱加起来,据此解答即可.\n【详解】8元5角 +1 元 = 9 元5角,答:买 1 个 和一支 一共需要 9 元 5 角。", + "knowledge_points": [ + "十元以下人民币的认识与计算" + ], + "source": "22-23一年级下·浙江温州·期末" + }, + { + "id": "390", + "unit": "第五单元认识人民币", + "question_type": "解答题", + "difficulty": 0.85, + "question": "90。(22-23一年级下·全国·随堂练习)明明买两种商品,正好花了10元,他可能买了什么。买了多少。\n![](images/9e07fc6162a7a6e643a8a05358d31fb65991598c245b9877670c59c1c36153f3.jpg)\n3元\n![](images/93f2812a2f67aee543356489c01ec3b705ae06c2dbad576e14e54a477ff10e68.jpg)\n4元\n![](images/8e2982ea5f5fad8e991aea6b6538a210ddfb54b690a7a62b63abb50bb5948a30.jpg)\n7元\n![](images/6edb41f6cda2b23c425e726461291e604e56bf60cfdfcb39cece1af669f298fc.jpg)\n6元", + "options": [ + + ], + "answer": "一个羽毛球和一支钢笔(或一根跳绳和一个放大镜)", + "solution": "【分析】根据物品的价钱,找出价钱相加等于 10 元的所有物品即可,本题答案不唯一.\n【详解】 3 + 7 = 10 (元)答:他可能买了一个羽毛球和一支钢笔。4 + 6 = 10 (元)答:他可能买了一根跳绳和一个放大镜。", + "knowledge_points": [ + "10 的加减法", + "十元以上人民币的认识与计算" + ], + "source": "22-23一年级下·全国·随堂练习" + }, + { + "id": "391", + "unit": "第五单元认识人民币", + "question_type": "解答题", + "difficulty": 0.65, + "question": "买一个冰激凌和一杯可乐一共要用多少钱。\n![](images/a066082827fce32e7bc4622fde5f85e96890b40bbc6882bd8dc7ca9955d4b225.jpg)\n3元5角\n![](images/5d38be789c6c226b4586ffb74f434c696d6f389d0329ff1208fa4d28b2dcd67d.jpg)\n4元8角", + "options": [ + + ], + "answer": "8元3角", + "solution": "【分析】将一个冰激凌和一杯可乐的价钱相加,即可得出一共要用多少钱。计算时注意,元和元相加,角和角相加,满十角变一元,再和元相加,据此解答即可.\n【详解】3元5角+4元8角=8元3角,答:一共要用 8 元 3 角钱。", + "knowledge_points": [ + "十元以下人民币的认识与计算" + ], + "source": "22-23一年级下·全国·随堂练习" + }, + { + "id": "392", + "unit": "第五单元认识人民币", + "question_type": "解答题", + "difficulty": 0.85, + "question": "92。(22-23一年级下·全国·随堂练习)小军有1张5元,8张1元,一个5角和7个1角,买一辆![](images/af00c6cb4f50b7cbce14c563f296c49a8aaaff35c3215fea59935cdcf2684f76.jpg)\n怎样付钱最简便。\n![](images/26b006f907f115bb17a3f695ec46b4c7579657a96ebf42b954a0f08dbdc1d259.jpg)\n8元7角", + "options": [ + + ], + "answer": "1 张 5 元,3 张 1 元,1 枚 5 角,2 枚 1 角", + "solution": "【分析】题中小汽车是 8 元 7 角,想付钱最简单,即付的钱数正好,付的张数最少,由此解答.\n【详解】5元+1元+1元+1元+5角+1角+1角=8元7角,![](images/27b123f270608ba1ed4ad1d24ccc698ba78c4b98b9896a5013f3236eab88868c.jpg)\n可以付1张5元,3张1元,1枚5角和 2 枚 1 角。", + "knowledge_points": [ + "十元以下人民币的认识与计算" + ], + "source": "22-23一年级下·全国·随堂练习" + }, + { + "id": "393", + "unit": "第五单元认识人民币", + "question_type": "解答题", + "difficulty": 0.4, + "question": "丫丫有1角,5角和1元硬币共10枚,每种硬币至少有1枚。那么丫丫硬币最多有多少元。最少有多少元。", + "options": [ + + ], + "answer": "最多8.6元;最少2.3元", + "solution": "【分析】因为每种硬币至少有 1 枚,要使钱数最多,就让 1 元的硬币尽量多, 1 角和 5 角的硬币各 1 枚;要使钱数最少,就让 1 角的硬币尽量多, 1 元和 5 角的硬币各一枚;据此解答即可.\n【详解】钱最多:8枚1元,1枚5角,一枚1角,8元+5角 +1 角 = 8 元 6 角,共 8.6 元;钱最少: 1 枚 1 元, 1 枚 5 角, 8 枚 1 角, 1 元 + 5 角 + 8 角 = 2 元 3 角,共 2.3 元。答:丫丫硬币最多有8.6元,最少有2.3元。", + "knowledge_points": [ + "十元以下人民币的认识与计算" + ], + "source": "22-23 五年级上·河北保定·期末" + }, + { + "id": "394", + "unit": "第五单元认识人民币", + "question_type": "解答题", + "difficulty": 0.85, + "question": "\n![](images/789e5f5b2cc0138e48e9bc7dab5fd1ab5baf0799696cd9f5c9393879d64f88af.jpg)\n带10元钱,够吗。", + "options": [ + + ], + "answer": "够", + "solution": "【分析】根据题意先用加法计算出买一支画笔和一个笔记本共花了多少钱,再和 10 元进行比较,如果小于或者等于 10 元就够,大于 10 则不够.\n【详解】 6 + 3 = 9 (元);9元\u003c10元;答:带 10 元钱,够。", + "knowledge_points": [ + "图文问题", + "10以内数的比大小", + "十元以下人民币的认识与计算" + ], + "source": "21-22 一年级下·广东佛山·期末" + }, + { + "id": "395", + "unit": "第五单元认识人民币", + "question_type": "解答题", + "difficulty": 0.65, + "question": "\n![](images/6f2cdd6f232d37b95fa0d49a2f751930487478ed84b6dc10581c2acbd6e133cf.jpg)\n3元7角\n![](images/931e520401aead1c6ed49fcaa3a710bdfefea68e92913765589944098ca86b88.jpg)\n2元2角\n![](images/2671e6046b4b4f029036af5ef97445e346fc11f7cbbdd3be8ccf73763e4137a6.jpg)\n3元\n(1) 买一盒牙膏和买一块香皂一共多少钱。\n(2) 买一把牙刷比买一盒牙膏便宜多少钱。", + "options": [ + + ], + "answer": "6元7角;1元5角", + "solution": "【分析】(1)将一盒牙膏和一块香皂的价钱相加,即可得出答案。(2) 用一盒牙膏的价钱减去一把牙刷的价钱,即可得出答案.\n【详解】 (1) 3元7角+3元=6元7角答:买一盒牙膏和买一块香皂一共 6 元 7 角。(2) 3元7角-2元2角=1元5角答:买一把牙刷比买一盒牙膏便宜 1 元 5 角。", + "knowledge_points": [ + "十元以下人民币的认识与计算" + ], + "source": "22-23 一年级下·全国·课前预习" + }, + { + "id": "396", + "unit": "第五单元认识人民币", + "question_type": "解答题", + "difficulty": 0.65, + "question": "96。(21-22一年级下·全国·单元测试)\n![](images/535bfd2047e175415b23c8308cb53c4153997552d447fb77ab7619da523cab7e.jpg)\n![](images/787f5ec43daabfa19fb86df06e5e0c1a421c3bd34b76a26073c2d27130e60c48.jpg)\n![](images/a23d52bd8494fec674f72b6ec599b1d2250aed6cf2adcb2aa38fd669aa431969.jpg)\n![](images/980b937b5b4b3dacecd9a283c8ef4d526f90d3714d88539bec4d6e6f08039329.jpg)\n(1) 买一只玩具兔和七巧板,一共要 ( ) 元 ( ) 角.\n(2) 小明买了一个魔方,营业员找回他 2 元。他付了 ( ) 元.\n(3) 小芳用 17 元正好买了两件玩具,她买了哪两种玩具。", + "options": [ + + ], + "answer": "13;5;10;魔方和玩具兔", + "solution": "【分析】本题综合考查学生用所学知识解决生活中的购物问题,要求学生读懂题意,正确列式并进行计算.\n【详解】 (1) 9元+4元5角=13元5角;答:一共要 13 元 5 角。(2) 13 - 9 = 4 (元)答:一个玩具娃娃比一只玩具免责 4 元。(3) 8 + 2 = 10 (元)答:他付了 10 元。(4) 8 + 9 = 17 (元)答:她买了一个魔方和一只玩具兔。", + "knowledge_points": [ + "十元以下人民币的认识与计算", + "十元以上人民币的认识与计算", + "用七巧板拼图形" + ], + "source": "21-22一年级下·全国·单元测试" + }, + { + "id": "397", + "unit": "第五单元认识人民币", + "question_type": "解答题", + "difficulty": 0.85, + "question": "小彩的储蓄罐里有一些1角,5角的硬币,她要用5角钱买一块橡皮,可以怎样拿。有几种拿法。", + "options": [ + + ], + "answer": "5枚1角和1枚5角;2种", + "solution": "[analysis]要用 5 角买橡皮,只要拿出来的硬币凑够 5 角即可.\n【详解】第一种:可以拿5枚1角硬币;第二种:可以拿 1 枚 5 角硬币。答:可以拿 5 枚 1 角或者 1 枚 5 角,有 2 种拿法。", + "knowledge_points": [ + "十元以下人民币的认识与计算" + ], + "source": "21-22 一年级下·全国·单元测试" + }, + { + "id": "398", + "unit": "第五单元认识人民币", + "question_type": "解答题", + "difficulty": 0.65, + "question": "98。(21-22一年级下·全国·单元测试)丫丫有5角,1角,1元的纸币若干张,她去由于邮局寄信,邮局工作人员告诉她。她邮寄的信件要1元邮票。丫丫可以怎样付钱。", + "options": [ + + ], + "answer": "2 张 5 角,1 张 1 元,10 张 1 角,1 张 5 角和 5 张 1 角", + "solution": "【分析】因为她有的纸币数量为若干张,所以只要金额相加等于 1 元即可.\n【详解】1元 = 10 角;如果用 5 角的, 5 角 +5 角 = 10 角 = 1 元,可以用 2 张 5 角;如果用 1 元的,可以用 1 张 1 元的;如果用1角的,1角+1角+1角+1角+1角+1角+1角+1角+1角+1角=10角=1元,可以用10张1角的。如果用 5 角和 1 角的, 5 角 +1 角 +1 角 +1 角 +1 角 +1 角 = 10 角 = 1 元,可以用 1 张 5 角和 5 张 1 角的。答:丫丫可以用2张5角或者1张1元或者10张1角或者1张5角和5张1角来付钱。", + "knowledge_points": [ + "十元以下人民币的认识与计算" + ], + "source": "21-22一年级下·全国·单元测试" + }, + { + "id": "399", + "unit": "第五单元认识人民币", + "question_type": "解答题", + "difficulty": 0.65, + "question": "99。(22-23一年级下·全国·单元测试)笑笑用一张![](images/85cddd97825848643487e4a67585b568dee88dae2ca5856d66fb1b4a4c0bf116.jpg)\n和一张![](images/1f922cdb9a5ceeb81737618fa28adf40b215c91fcaa5f0e5687ad7f3f88c0a96.jpg)刚好能买6本笔记本,平均每本笔记本多少元。", + "options": [ + + ], + "answer": "5元", + "solution": "【分析】先计算出笑笑一共用了多少钱,再根据买笔记本的数量,就可以计算出平均每本笔记本多少元.\n【详解】 20 + 10 = 30 (元)5 + 5 + 5 + 5 + 5 + 5 = 30 (元)答:平均每本笔记本 5 元。", + "knowledge_points": [ + "整数平均分的意义及应用", + "十元以上人民币的认识与计算" + ], + "source": "22-23一年级下·全国·单元测试" + }, + { + "id": "400", + "unit": "第五单元认识人民币", + "question_type": "解答题", + "difficulty": 0.85, + "question": "圆珠笔 6 角钱一支,付出 1 元钱,找回多少钱。", + "options": [ + + ], + "answer": "4角", + "solution": "[analysis]根据题意,付出 1 元,圆珠笔 6 角钱,要求找回多少,需列减法算式计算.\n【详解】1元 = 10 角,10角-6角=4角,答:找回4角钱。", + "knowledge_points": [ + "元,角,分的认识及换算", + "十元以下人民币的认识与计算" + ], + "source": "22-23一年级下·全国·单元测试" + }, + { + "id": "401", + "unit": "第五单元认识人民币", + "question_type": "选择题", + "difficulty": 0.85, + "question": "笑笑买一块橡皮用了 5 角,买一个笔记本用了 8 元,一共用了 ( )。", + "options": [ + "A. 13元", + "B. 8元5角", + "C. 13角" + ], + "answer": "B", + "solution": "【分析】把两件商品的价格相加即可.\n【详解】5角+8元=8元5角;一共用了 8 元 5 角。故答案为: B", + "knowledge_points": [ + "十元以下人民币的认识与计算" + ], + "source": "21-22 一年级下·四川广元·期末" + }, + { + "id": "402", + "unit": "第五单元认识人民币", + "question_type": "选择题", + "difficulty": 0.65, + "question": "一个文具盒的价钱为()。", + "options": [ + "A. 80 分", + "B. 80角", + "C. 3角5分" + ], + "answer": "B", + "solution": "【分析】根据生活经验以及数据的大小,选择合适的计量单位,即可解答.\n【详解】一个文具盒的价钱为 80 角,即 8 元;故答案为: B", + "knowledge_points": [ + "元,角,分的认识及换算" + ], + "source": "20-21一年级下·青海玉树·期末" + }, + { + "id": "403", + "unit": "第五单元认识人民币", + "question_type": "选择题", + "difficulty": 0.65, + "question": "小美带的钱都是 10 元的,至少应该付 ( ) 张 10 元.\n![](images/f3fb667fcda427dd7959015e0892dcae05c3bd1f2cfd2d7ea99277dcbc42e176.jpg)\n58元", + "options": [ + "A. 5", + "B. 6", + "C. 8" + ], + "answer": "B", + "solution": "【分析】58元可以看成50元和8元,50元需要付5张10元,8元需要付1张10元,据此解答.\n【详解】小美要买 58 元的东西,她带的钱都是 10 元的,所以至少应该付 6 张 10 元。故答案为: B", + "knowledge_points": [ + "十元以上人民币的认识与计算" + ], + "source": "20-21一年级下·河北张家口·期末" + }, + { + "id": "404", + "unit": "第五单元认识人民币", + "question_type": "选择题", + "difficulty": 0.85, + "question": "一个书包大约 ( )。", + "options": [ + "A. 2元", + "B. 50 元", + "C. 15角" + ], + "answer": "B", + "solution": "【分析】根据生活经验,对人民币单位的认识和数据大小,结合题中选项进行选择.\n【详解】根据生活经验:一个书包大约 50 元;故答案为:B", + "knowledge_points": [ + "元,角,分的认识及换算" + ], + "source": "21-22 一年级下·浙江温州·期中" + }, + { + "id": "405", + "unit": "第五单元认识人民币", + "question_type": "选择题", + "difficulty": 0.85, + "question": "小红买一本故事书,付了一张 中人,售货员说还少了1元5角,这书的价钱是()。", + "options": [ + "A. 11元5角", + "B. 8元5角", + "C. 9元5角", + "D. 10元5角" + ], + "answer": "A", + "solution": "【分析】根据题意,用付出的钱加上少了的钱,即可解答.\n【详解】10元+1元5角=11元5角;故答案为: A", + "knowledge_points": [ + "十元以上人民币的认识与计算" + ], + "source": "20-21一年级下·河南信阳·期末" + }, + { + "id": "406", + "unit": "第五单元认识人民币", + "question_type": "选择题", + "difficulty": 0.65, + "question": "一张 10 元可以换 ( ) 张 5 元的。", + "options": [ + "A. 2", + "B. 5", + "C. 10" + ], + "answer": "A", + "solution": "【分析】根据人民币各面值之间的关系 10 元 = 5 元 +5 元,换算即可.\n【详解】一张 10 元可以换 2 张 5 元的。故答案为: A", + "knowledge_points": [ + "元,角,分的认识及换算", + "十元以下人民币的认识与计算" + ], + "source": "21-22一年级下·河南信阳·期末" + }, + { + "id": "407", + "unit": "第五单元认识人民币", + "question_type": "选择题", + "difficulty": 0.85, + "question": "妈妈买了一件衣服,付了一张![](images/07bd09eba11bee26db8c22b512a27b95af7775944360a192b2fc11a2b39ea7b4.jpg),一张![](images/2c891bda8f675b3cfc8963ef30429d5ada6c9fe99c462eed781e544dcf20fb4f.jpg)\n和6张![](images/f6092ff0ffde51d826c43c79fdfbd43d747c46188088bd8f18cc83df28fb716e.jpg),这件衣服的价钱是()元。", + "options": [ + "A. 76", + "B. 58", + "C. 13" + ], + "answer": "A", + "solution": "【分析】由题可知,将题中的人民币相加即可解答.\n【详解】 20 + 50 + 6 = 76 (元);故答案为: A", + "knowledge_points": [ + "十元以上人民币的认识与计算" + ], + "source": "21-22 一年级下·河北张家口·期末" + }, + { + "id": "408", + "unit": "第五单元认识人民币", + "question_type": "选择题", + "difficulty": 0.65, + "question": "豆豆买了一支笔,花了 7 角钱,他付出 1 元钱,应该找回 ( )。", + "options": [ + "A. 3元", + "B. 1元7角", + "C. 3角" + ], + "answer": "C", + "solution": "【分析】由题可知,豆豆买一支笔花了 7 角钱,他付出 1 元钱,求应该找回的钱数,先对人民币元和角进行换算,然后再用减法计算即可.\n【详解】1元 = 10 角;10 - 7 = 3 (角),故答案为: C", + "knowledge_points": [ + "元,角,分的认识及换算", + "十元以下人民币的认识与计算" + ], + "source": "21-22 一年级下·山东临沂·期末" + }, + { + "id": "409", + "unit": "第五单元认识人民币", + "question_type": "选择题", + "difficulty": 0.65, + "question": "一张![](images/3b3761673ea3398778f9091fffe982448830922a6dd307cd87cf1669157c8a43.jpg)\n可以换()![](images/68a385328a8b4bd2ab68c9ebdded27154e2e5ad1feab40da7a68a12a57d6e787.jpg)\n。", + "options": [ + "A. 2 张", + "B. 4 张", + "C. 5 张" + ], + "answer": "B", + "solution": "【分析】根据减法的意义,用 20 连续减去 5,能减去几次就表示可以换几张 5 元.\n【详解】 20 - 5 = 15 (元)15 - 5 = 10 (元)10 - 5 = 5 (元)5 - 5 = 0 (元)所以,一张 20 元可以换 4 张 5 元。故答案为: B.", + "knowledge_points": [ + "十元以下人民币的认识与计算", + "十元以上人民币的认识与计算", + "连减(20以内)" + ], + "source": "21-22一年级下·贵州铜仁·期末" + }, + { + "id": "410", + "unit": "第五单元认识人民币", + "question_type": "选择题", + "difficulty": 0.85, + "question": "一块橡皮擦 2 角, 1 元可以买 ( ) 块这样的橡皮擦。", + "options": [ + "A. 2", + "B. 5", + "C. 10" + ], + "answer": "B", + "solution": "【分析】根据1元 = 10 角,解答此题即可.\n【详解】1元 = 10 角;2角+2角+2角+2角+2角=10角=1元所以1元可以买5块橡皮擦。故答案为: B", + "knowledge_points": [ + "元,角,分的认识及换算", + "十元以下人民币的认识与计算" + ], + "source": "21-22 一年级下·四川自贡·期末" + }, + { + "id": "411", + "unit": "第五单元认识人民币", + "question_type": "选择题", + "difficulty": 0.65, + "question": "11。(21-22一年级下·四川自贡·期末)3张1角和2张5角合起来是()。", + "options": [ + "A. 8角", + "B. 1元1角", + "C. 1元3角" + ], + "answer": "C", + "solution": "【分析】3 张 1 角的是 3 角, 10 角是 1 元,加起来即可解答.\n【详解】1角+1角+1角+5角+5角;= 3 角 +5 角 +5 角;= 8 角 +5 角 \n= 1 元 3 角,所以3张1角和2张5角合起来是1元3角。故答案为: C.", + "knowledge_points": [ + "元,角,分的认识及换算", + "十元以下人民币的认识与计算" + ], + "source": "21-22一年级下·四川自贡·期末" + }, + { + "id": "412", + "unit": "第五单元认识人民币", + "question_type": "选择题", + "difficulty": 0.65, + "question": "妈妈给小华7元,爸爸给小华4元,小华一共有()元。", + "options": [ + "A. 3元", + "B. 7元4角", + "C. 11元" + ], + "answer": "C", + "solution": "【分析】用妈妈给的钱数加上爸爸给的钱数即可.\n【详解】 7 + 4 = 11 (元)故答案为: C", + "knowledge_points": [ + "7,6加几的进位加法", + "十元以上人民币的认识与计算" + ], + "source": "21-22一年级下·湖北黄冈·期末" + }, + { + "id": "413", + "unit": "第五单元认识人民币", + "question_type": "选择题", + "difficulty": 0.65, + "question": "一块蛋糕 1 元,一根火腿肠 5 元 1 角,蛋糕比火腿肠 ( )。", + "options": [ + "A. 便宜 1 元 4 角", + "B. 贵 1 元 4 角", + "C. 便宜 4 元 1 角" + ], + "answer": "C", + "solution": "【分析】从题干可知:一块蛋糕 1 元,一根火腿肠 5 元 1 角,所以火腿肠的价钱比蛋糕贵,据此列式解答即可得出答案.\n【详解】5元1角- 1元=4元1角所以,蛋糕比火腿肠便宜4元1角。故答案为:C.", + "knowledge_points": [ + "十元以下人民币的认识与计算" + ], + "source": "21-22一年级下·河南南阳·期末" + }, + { + "id": "414", + "unit": "第五单元认识人民币", + "question_type": "选择题", + "difficulty": 0.85, + "question": "一个汉堡的价格大约是()。", + "options": [ + "A. 9角", + "B. 90元", + "C. 9元" + ], + "answer": "C", + "solution": "【分析】根据生活实际及对人民币的认识,选择即可.\n【详解】一个汉堡的价格大约是9元;故答案为: C", + "knowledge_points": [ + "元,角,分的认识及换算" + ], + "source": "21-22 一年级下·青海西宁·期末" + }, + { + "id": "415", + "unit": "第五单元认识人民币", + "question_type": "选择题", + "difficulty": 0.65, + "question": "买一件衣服,我付了 2 张,找回的钱比 10 元少。这件衣服的价格是 ( )。", + "options": [ + "A. 98元", + "B. 43元", + "C. 90元" + ], + "answer": "A", + "solution": "【分析】2 张 50 元是 100 元,找回的钱比 10 元少。假设找回的钱是 10 元,用减法计算出假设的衣服的价格,衣服的实际价格比计算出价格要多一些,比较选项选择即可.\n【详解】 100 - 10 = 90 (元)因为找回的钱比 10 元少,所以这件衣服的价格应该大于 90 元。故答案为:A", + "knowledge_points": [ + "十元以上人民币的认识与计算" + ], + "source": "21-22 一年级下·湖北孝感·期末" + }, + { + "id": "416", + "unit": "第五单元认识人民币", + "question_type": "选择题", + "difficulty": 0.65, + "question": "买一个文具袋花了 6 ( )。", + "options": [ + "A. 元", + "B. 角", + "C. 分" + ], + "answer": "A", + "solution": "【分析】结合实际生活中物品的价格可解题.\n【详解】实际生活中,一个文具袋大概价格是6元。故答案为: A", + "knowledge_points": [ + "元,角,分的认识及换算" + ], + "source": "21-22 一年级下·江西赣州·期末" + }, + { + "id": "417", + "unit": "第五单元认识人民币", + "question_type": "选择题", + "difficulty": 0.65, + "question": "小丽用 10 元钱买了一本书,找回 1 元 5 角,这本书需要 ( ) 钱。", + "options": [ + "A. 9元5角", + "B. 8元5角", + "C. 11元5角" + ], + "answer": "B", + "solution": "【分析】用小丽花的钱减去找回的钱,即可得出买这本书需要多少钱.\n【详解】 10 - 1 元5角 = 8 元5角,所以,这本书需要 8 元 5 角。故答案为: B.", + "knowledge_points": [ + "十元以下人民币的认识与计算" + ], + "source": "21-22 一年级下·江西赣州·期末" + }, + { + "id": "418", + "unit": "第五单元认识人民币", + "question_type": "选择题", + "difficulty": 0.65, + "question": "东东买一本《数学天地》,付了2张20元的人民币,找回的钱比5元多,比10少。这本书的价格可能是()。", + "options": [ + "A. 28元", + "B. 32元", + "C. 36 元" + ], + "answer": "B", + "solution": "【分析】根据题意东东付了 2 张 20 元的人民币,即 40 元,再根据找回的钱比 5 元多,比 10 元少解答即可.\n【详解】 40 - 5 = 35 (元)40 - 10 = 30 (元)即这本书的价格比 30 元多,比 35 元少,所以符合这一价格的是 B 选项。故答案为: B", + "knowledge_points": [ + "100 以内数的比大小", + "十元以上人民币的认识与计算" + ], + "source": "21-22一年级下·河南南阳·期末" + }, + { + "id": "419", + "unit": "第五单元认识人民币", + "question_type": "选择题", + "difficulty": 0.65, + "question": "亮亮带 10 元钱,要买 4 本 3 元的笔记本,钱够吗。 ( )。", + "options": [ + "A. 够", + "B. 不够", + "C. 不能确定" + ], + "answer": "B", + "solution": "【分析】用连加的方法求出 4 本书的钱数,再与 10 元比较即可.\n【详解】 3 + 3 + 3 + 3 = 12 (元);12元\u003e10元,不够。故答案为: B", + "knowledge_points": [ + "20以内数的比大小", + "同数连加的应用", + "十元以上人民币的认识与计算" + ], + "source": "21-22 一年级下·河南南阳·期末" + }, + { + "id": "420", + "unit": "第五单元认识人民币", + "question_type": "选择题", + "difficulty": 0.65, + "question": "买这个书包付了 4张20元,找回的钱比10元少。这个书包的价钱是多少。()\n![](images/4965003fa741356b001f665f22f03b25616e6c494dee9f2c1f0fa7ab4e6c50c5.jpg)", + "options": [ + "A. 42 元", + "B. 72 元", + "C. 82 元" + ], + "answer": "B", + "solution": "【分析】4 张 20 元合起来是 80 元,又因为找回的钱数比 10元少,所以书包的价钱要大于 70 元,小于 80 元。结合选项即可得出答案.\n【详解】4 张 20 元 = 80 元,因为找回的钱比 10 元少,所以书包的价钱比 70 元多,比 80 元少。这个书包的价钱最有可能是 72 元。故答案为: B.", + "knowledge_points": [ + "100以内数的比大小" + ], + "source": "21-22 一年级下·河南信阳·期末" + }, + { + "id": "421", + "unit": "第五单元认识人民币", + "question_type": "选择题", + "difficulty": 0.85, + "question": "达瓦买铅笔需要 8 角,他给售货员 1 元,应该找回 ( )。", + "options": [ + "A. 1 元 8 角", + "B. 2角", + "C. 2 分", + "D. 1元2角" + ], + "answer": "B", + "solution": "【分析】根据 1 元 = 10 角,先将货币单位统一,再根据减法的意义,列式解答即可.\n【详解】1元 = 10 角;10角-8角=2角;所以,应找回2角。故答案为: B.", + "knowledge_points": [ + "元,角,分的认识及换算", + "十元以下人民币的认识与计算" + ], + "source": "21-22 一年级下·西藏那曲·期末" + }, + { + "id": "422", + "unit": "第五单元认识人民币", + "question_type": "选择题", + "difficulty": 0.65, + "question": "一块橡皮擦的价格是8角钱,小军给售货员5元,应找回()。", + "options": [ + "A. 1元", + "B. 4元2角", + "C. 3元2角" + ], + "answer": "B", + "solution": "【分析】一块橡皮擦的价格是8角钱,小军给售货员5元,应找回50角-8角=4元2角.\n【详解】5元 = 50 角;50角-8角=42角;所以,应找回4元2角。故答案为: B.", + "knowledge_points": [ + "元,角,分的认识及换算", + "十元以下人民币的认识与计算" + ], + "source": "21-22一年级下·全国·单元测试" + }, + { + "id": "423", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.65, + "question": "7元=( )角 30 分 = ( ) 角6元4角 = ( )角", + "options": [ + + ], + "answer": "70364", + "solution": "【分析】根据1元 = 10 角,1角 = 10 分,换算单位即可.\n【详解】7元=70角 30分=3角 6元=60角,6元4角=64角", + "knowledge_points": [ + "元,角,分的认识及换算" + ], + "source": "21-22一年级下·湖南怀化·期末" + }, + { + "id": "424", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.65, + "question": "一块橡皮5角,1元钱能买( )块。小红买一本书,付款10元,还差3元5角,书的价格是( )元( )角。", + "options": [ + + ], + "answer": "2;13;5", + "solution": "【分析】根据人民币间的单位换算:1元 = 10 角,计算即可。书的价格用已付的价格加还差的钱数即可.\n【详解】1元 = 10 角;5角+5角=10角;10元+3元5角=13元5角;所以 1 元钱能买 2 块橡皮;书的价钱是 13 元 5 角。", + "knowledge_points": [ + "十元以下人民币的认识与计算", + "十元以上人民币的认识与计算" + ], + "source": "21-22一年级下·湖北随州·期末" + }, + { + "id": "425", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.85, + "question": "50 角 = ( ) 元 6元 4 角 = ( ) 角", + "options": [ + + ], + "answer": "5, 64", + "solution": "【分析】根据1元 = 10 角,1角 = 10 分进行单位换算即可.\n【详解】50角 = 5 元 6元 = 60 角,6元4角 = 64 角", + "knowledge_points": [ + "元,角,分的认识及换算" + ], + "source": "20-21 一年级下·湖北十堰·期末" + }, + { + "id": "426", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.65, + "question": "7 元 8 角 = ( ) 角 1元5角-8角 = ( )角", + "options": [ + + ], + "answer": "78;7", + "solution": "【分析】1元 = 10 角,据此单位换算,再计算解题.\n【详解】7元 = 70 角,70角+8角=78角,所以,7元8角 = 78 角;10角+5角=15角,15角-8角=7角,所以,1元5角-8角 = 7 角", + "knowledge_points": [ + "元,角,分的认识及换算", + "十元以下人民币的认识与计算" + ], + "source": "21-22 一年级下·广东汕尾·期末" + }, + { + "id": "427", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.65, + "question": "38 分=( )角( )分。", + "options": [ + + ], + "answer": "3;8", + "solution": "【分析】根据\"1角=10分\"可知,38分=3角8分.\n【详解】根据分析可知,38分=3角8分", + "knowledge_points": [ + "元,角,分的认识及换算" + ], + "source": "21-22 四年级下·广西贵港·期末" + }, + { + "id": "428", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.85, + "question": "5 元 5 角 = ( )角 76角 = ( ) 元()角", + "options": [ + + ], + "answer": "55;7;6", + "solution": "【分析】根据1元 = 10 角,进行换算即可.\n【详解】5元5角 = 50 角 +5角 = 55 角 76角 = 7 元6角", + "knowledge_points": [ + "元,角,分的认识及换算" + ], + "source": "21-22 一年级下·广西玉林·期末" + }, + { + "id": "429", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.65, + "question": "单位换算.\n4元 = ( )角30分 = ( )角1元 = ( )分 10角 = ( ) 元2元5角 = ( ) 角26分 = ( ) 角( )分", + "options": [ + + ], + "answer": "40;3;100;1;25;2;6", + "solution": "【分析】根据1元 = 10 角,1角 = 1 分进行单位换算即可.\n【详解】4元 = 40 角 30分 = 3 角 1元 = 10 角 = 100 分 10角 = 1 元2元5角 = 20 角 +5 角 = 25 角26分 = 2 角6分", + "knowledge_points": [ + "元,角,分的认识及换算" + ], + "source": "20-21 一年级下·天津红桥·期末" + }, + { + "id": "430", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.85, + "question": "8 元 = ( )角 12角 = () 元()角 70角 = ()元 1元6角 = ()角", + "options": [ + + ], + "answer": "80;1;2;7;16", + "solution": "【分析】根据 1 元 = 1 角,几元就是几十角,几十角就是几元,几元几角转换成角时,先将几元想成几十角,再加上几角,由此解答.\n【详解】8元 = 80 角 12角 = 1 元2角 70角 = 7 元 1元6角 = 10 角 +6 角 = 16 角", + "knowledge_points": [ + "元,角,分的认识及换算" + ], + "source": "21-22 一年级下·黑龙江鸡西·期末" + }, + { + "id": "431", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.65, + "question": "在括号里填上\"\u003e\"\"\u003c\"或\"=\".\n6元()60角 9元8角()9角8分 67角()6元9角 7角6分()76分", + "options": [ + + ], + "answer": "=;\u003e;\u003c;=", + "solution": "【分析】根据 1 元 = 10 角, 1 角 = 10 分,将单位换算统一后,再进行比较即可.\n【详解】6元=60角 8角=80分,80分\u003e8分,9元8角\u003e9角8分 6元9角 = 69 角, 67 角 \u003c 6 元 9 角 7 角 6 分 = 76 分", + "knowledge_points": [ + "元,角,分的认识及换算" + ], + "source": "20-21一年级下·青海玉树·期末" + }, + { + "id": "432", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.65, + "question": "1元-4角 = ()角 3角 +7角 = () 元 2角 +30分 = ()角", + "options": [ + + ], + "answer": "6;1;5", + "solution": "【分析】根据 1 元 = 10 角, 1 角 = 10 分解答此题即可.\n【详解】1元-4角 = 6 角;3角+7角=1元;30分=3角,2角+30分=5角", + "knowledge_points": [ + "元,角,分的认识及换算", + "十元以下人民币的认识与计算" + ], + "source": "21-22一年级下·浙江杭州·期末" + }, + { + "id": "433", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.65, + "question": "在 100 分,7 元 3 角,90 角,80 分中,最小的是()。", + "options": [ + + ], + "answer": "80分", + "solution": "【分析】根据 1 元 = 10 角, 1 角 = 10 分,解答此题即可.\n【详解】7元3角 = 730 分;90角 = 900 分;因为90角 \u003e7 元3角 \u003e100 分 \u003e80 分,所以最小的是80分。", + "knowledge_points": [ + "元,角,分的认识及换算" + ], + "source": "21-22 一年级下·浙江杭州·期末" + }, + { + "id": "434", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.65, + "question": "在横线填上 \"\u003e\"\"\u003c\" 或 \"=\" .\n30角()3元 5角()5元 9元3角()7元9角", + "options": [ + + ], + "answer": "=;\u003c;\u003e", + "solution": "【分析】根据 1 元 = 10 角解答此题即可.\n【详解】30角 = 3 元;50角 = 5 元, 5 \u003c 50,所以 5 角 \u003c 5 元;9元3角 \u003e7 元9角", + "knowledge_points": [ + "100以内数的比大小", + "元,角,分的认识及换算" + ], + "source": "21-22一年级下·浙江杭州·期末" + }, + { + "id": "435", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.65, + "question": "5 元 = ( ) 角 3元6角-3角 = ( )元( )角", + "options": [ + + ], + "answer": "50;3;3", + "solution": "【分析】根据1元 = 10 角,解答此题即可.\n【详解】5元 = 50 角;3元6角-3角=3元3角", + "knowledge_points": [ + "元,角,分的认识及换算", + "十元以下人民币的认识与计算" + ], + "source": "21-22 一年级下·广东阳江·期末" + }, + { + "id": "436", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.65, + "question": "算一算.\n2元6角 = ( )角 25角 = ( )元( )角\n3元 = ( )角 5角 +7 角 = ( )角", + "options": [ + + ], + "answer": "26;2;5;30;12", + "solution": "【分析】根据\"1元 = 10 角\"解答此题即可.\n【详解】2元6角 = (26)角 25角 = (2)元(5)角 3元 = (30)角 5角+7角 = (12)角", + "knowledge_points": [ + "元,角,分的认识及换算", + "十元以下人民币的认识与计算" + ], + "source": "21-22 一年级下·浙江温州·期中" + }, + { + "id": "437", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.65, + "question": "7 元=( )角 35角 = ( ) 元( )角", + "options": [ + + ], + "answer": "70;3;5", + "solution": "【分析】根据\"1元 = 10 角\"解答此题即可.\n【详解】7元 = 70 角 35角 = 3 元5角", + "knowledge_points": [ + "元,角,分的认识及换算" + ], + "source": "21-22 一年级下·贵州遵义·期末" + }, + { + "id": "438", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.65, + "question": "38。(20-21一年级下·江西赣州·期末)8元 = ( )角 46角 = ( ) 元( ) 角", + "options": [ + + ], + "answer": "80;4;6", + "solution": "【分析】根据\"1元 = 10 角\"解答即可.\n【详解】8元 = 80 角 46角 = 4 元6角", + "knowledge_points": [ + "元,角,分的认识及换算" + ], + "source": "20-21一年级下·江西赣州·期末" + }, + { + "id": "439", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.65, + "question": "换一换,填一填.\n5元 = ( )角45角 = ( )元( )角20角 = ( )元\n3元8角 =( )角4元5角-3元 = ( )元( )角", + "options": [ + + ], + "answer": "50;4;5;2;38;1;5", + "solution": "【分析】根据 \"1 元 = 10 角\" 来解决换算的问题;计算时,同单位上的数进行计算即可.\n【详解】5元 = (50) 角 45角 = (4) 元(5)角 20角 = (2) 元 3元8角 = (38) 角 4元5角-3元 = (1) 元 (5) 角", + "knowledge_points": [ + "元,角,分的认识及换算", + "十元以下人民币的认识与计算" + ], + "source": "21-22 一年级下·四川眉山·期末" + }, + { + "id": "440", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.65, + "question": "括号里填合适的数.\n40角 = ( ) 元 39分 = ()角()分\n1元4角 +6 角 = ( )元6元7角 = ( )角", + "options": [ + + ], + "answer": "4;3;9;2;67", + "solution": "【分析】根据1元 = 10 角,1角 = 10 分,进行换算即可.\n【详解】40角 = 4 元 39分 = 3 角9分 1元4角 +6 角 = 1 元10角 = 2 元6元7角 = 67 角", + "knowledge_points": [ + "元,角,分的认识及换算" + ], + "source": "21-22 一年级下·西藏林芝·期末" + }, + { + "id": "441", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.65, + "question": "7 元 = ( )角 1 元 5角 = ( ) 角 5元5角 +5 角 = ()元", + "options": [ + + ], + "answer": "70;15;6", + "solution": "【分析】1元 = 10 角,据此解答即可.\n【详解】7元 = 70 角;1元5角 = 15 角;5元 5角 + 5角 = 6元", + "knowledge_points": [ + "元,角,分的认识及换算", + "十元以下人民币的认识与计算" + ], + "source": "21-22 一年级下·江西上饶·期末" + }, + { + "id": "442", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.65, + "question": "6 元 = ( ) 角 2 元 8 角 = ( ) 角", + "options": [ + + ], + "answer": "60;28", + "solution": "【分析】由于 \"1 元 = 10 角\",第一个 6 元有 6 个 10 角;第二个: 2 元有 2 个 10 角,再加上 8 角即可.\n【详解】6元 = (60)角2元8角 = (28)角", + "knowledge_points": [ + "元,角,分的认识及换算" + ], + "source": "20-21 一年级下·广东江门·期末" + }, + { + "id": "443", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.65, + "question": "24 角 = ( ) 元( )角 5角 +1 元4角 = ( )元( )角", + "options": [ + + ], + "answer": "2;4;1;9", + "solution": "【分析】10个1角是1元,据此解答.\n【详解】24角 = 2 元4角;5角+1元4角=1元9角", + "knowledge_points": [ + "元,角,分的认识及换算", + "十元以下人民币的认识与计算" + ], + "source": "20-21 一年级下·湖北鄂州·期末" + }, + { + "id": "444", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.85, + "question": "5 个 2 角一共是( )角,可换成( )元。", + "options": [ + + ], + "answer": "10;1", + "solution": "【分析】将5个2角加起来即可求解.\n【详解】 2 + 2 + 2 + 2 + 2 = 10 (角)10角 = 1 元,所以 5 个 2 角一共是 10 角,可换成 1 元。", + "knowledge_points": [ + "元,角,分的认识及换算", + "十元以下人民币的认识与计算" + ], + "source": "20-21 一年级下·湖北鄂州·期末" + }, + { + "id": "445", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.65, + "question": "8 元 = ( )角 90角 = ( )元 33角 = ( ) 元( )角 2元-4角 = ( )角", + "options": [ + + ], + "answer": "80;9;3;3;16", + "solution": "【分析】根据 \"1 元 = 10 角\" 解答即可,计算时,把单位统一.\n【详解】8元 = (80)角 90角 = (9)元 33角 = (3)元(3)角2元-4角 = (16)角", + "knowledge_points": [ + "元,角,分的认识及换算", + "十元以下人民币的认识与计算" + ], + "source": "21-22 一年级下·湖南岳阳·期末" + }, + { + "id": "446", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.65, + "question": "1 角 = ( )分 26角 = ( ) 元( )角 5元 = ( ) 角 13元9角-8元 = ( ) 元( )角", + "options": [ + + ], + "answer": "10;2;6;50;5;9", + "solution": "【分析】根据 1 元 = 10 角,1 角 = 10 分进行单位转化即可。元数减元数,角数减角数,据此进行计算即可.\n【详解】1角 = 10 分;26角 = 2 元6角;5元=50角;13元9角-8元=5元9角。", + "knowledge_points": [ + "元,角,分的认识及换算", + "十元以上人民币的认识与计算" + ], + "source": "21-22 一年级下·贵州铜仁·期末" + }, + { + "id": "447", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.65, + "question": "填一填.\n8角-6角 = ( )角9角 +7 角 = ( )元( )角 6元+5元=( )元 5角+2元8角=( )元( )角", + "options": [ + + ], + "answer": "2;1;6;11;3;3", + "solution": "【分析】元数加元数,角数加角数,再根据 10 角 = 1 元,把高级单位化成低级单位要乘单位间的进率,把低级单位化成高级单位要除以单位间的进率,据此解答即可.\n【详解】8角一6角 = 2 角;9角 +7 角 = 16 角, 16角 = 1 元 6 角,所以 9 角 +7 角 = 1 元 6 角。 \n6元+5元=11元;5角 +8 角 = 13 角,13角 = 1 元3角,1元3角 +2 元 = 3 元3角,所以5角 +2 元8角 = 3 元3角", + "knowledge_points": [ + "元,角,分的认识及换算", + "十元以下人民币的认识与计算", + "十元以上人民币的认识与计算" + ], + "source": "21-22 一年级下·浙江台州·期末" + }, + { + "id": "448", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.65, + "question": "48。(20-21一年级下·山东济宁·期末)2元 = ( )角 35角 = ( ) 元( )角 1元6角 = ( )角 4元+3元 = ( )元", + "options": [ + + ], + "answer": "20;3;5;16;7", + "solution": "【分析】根据1元 = 10 角,解答此题即可.\n【详解】2元 = 20 角 35角 = 3 元 5角1元6角 = 16 角 4元 +3 元 = 7 元", + "knowledge_points": [ + "元,角,分的认识及换算", + "十元以下人民币的认识与计算" + ], + "source": "20-21一年级下·山东济宁·期末" + }, + { + "id": "449", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.65, + "question": "43 角 = ( ) 元( )角 元2角-5角 = () 角 6角 +3 元2角 = ( )元( )角5元5角 = ( )角", + "options": [ + + ], + "answer": "4;3;7;3;8;55", + "solution": "【分析】根据 1 元 = 10 角进行单位换算即可.\n【详解】43角 = 4 元3角1元2角 -5 角 = 7 角;6角+3元2角=3元8角 5元5角=55角", + "knowledge_points": [ + "元,角,分的认识及换算" + ], + "source": "20-21 一年级下·河南信阳·期末" + }, + { + "id": "450", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.85, + "question": "7 元 = ( )角 36角 = ( ) 元()角 6元3角 = ( ) 角 50角 = ( ) 元", + "options": [ + + ], + "answer": "70;3;6;63;5", + "solution": "【分析】根据 1 元 = 10 角, 1 角 = 10 分,进行单位换算即可.\n【详解】7元 = 70 角 36角 = 30 角 +6 角 = 3 元6角 6元 = 60 角,6元3角 = 63 角 50角 = 5 元", + "knowledge_points": [ + "元,角,分的认识及换算" + ], + "source": "21-22 一年级下·河北张家口·期末" + }, + { + "id": "451", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.65, + "question": "算一算,填上合适的数.\n1元一3角 = ( ) 角 9角 +8 角 = ()元()角 \n18元-9元=( )元 1元2角+8角=( )元", + "options": [ + + ], + "answer": "7;1;7;9;2", + "solution": "【分析】1元 = 10 角,据此进行加减计算即可.\n【详解】1元 = 10 角, 10 - 3 = 7 (角);9角 +8角 = 17角 = 1 元 7 角;18元-9元 = 9 元;1元2角+8角 = 2 元", + "knowledge_points": [ + "元,角,分的认识及换算", + "十元以下人民币的认识与计算" + ], + "source": "21-22 一年级下·山东临沂·期末" + }, + { + "id": "452", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.85, + "question": "5元=( )角 47角 = ( ) 元( ) 角", + "options": [ + + ], + "answer": "50;4;7", + "solution": "【分析】1元 = 10 角,由此进行单位换算即可.\n【详解】由分析可知,5元 = 50 角;47角等于4元7角。", + "knowledge_points": [ + "元,角,分的认识及换算" + ], + "source": "21-22一年级下·山东临沂·期末" + }, + { + "id": "453", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.85, + "question": "1 元 = ( )角 85分 = ( ) 角( )分 50角 = ( ) 元4元1角 = ( )角", + "options": [ + + ], + "answer": "10;8;5;5;41", + "solution": "【分析】根据\"1元 = 10 角\"解答即可.\n【详解】1元 = (10)角85分 = (8)角(5)分50角 = (5)元4元1角 = (41)角", + "knowledge_points": [ + "元,角,分的认识及换算" + ], + "source": "20-21 一年级下·河南三门峡·期末" + }, + { + "id": "454", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.65, + "question": "一张20元的人民币可以换( )张5元的人民币;把其中一张5元的人民币可以换成5角的人民币,可以换( )张。", + "options": [ + + ], + "answer": "4或四;10或十", + "solution": "【分析】根据 \"20 元 = 5 元 + 5 元 + 5 元 + 5 元\" 和 \"1 元 = 10 角\" 解答即可.\n【详解】一张20元的人民币可以换4张5元的人民币;把其中一张 5 元的人民币可以换成 5 角的人民币,可以换 10 张。", + "knowledge_points": [ + "元,角,分的认识及换算", + "十元以下人民币的认识与计算", + "十元以上人民币的认识与计算" + ], + "source": "21-22一年级下·四川德阳·期末" + }, + { + "id": "455", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.65, + "question": "55。(21-22一年级下·广东阳江·期末)7元 = ( )角 83角 = ( ) 元( ) 角 4元5角 = ( ) 角 1元 = ( )角 = ( )分", + "options": [ + + ], + "answer": "70;8;3;45;10;100", + "solution": "【分析】元与角之间的进率是 10,角与分之间的进率也是 10,即 1 元 = 10 角, 1 角 = 10 分, 1 元 = 100 分,据此解答.\n【详解】(1)7元是7个10角,即70角,所以7元 = 70 角;(2) 83 角是 8 个 1 元和 3 个 1 角,所以 83 角 = 8 元 3 角;(3) 4元5角是4个1元和5个1角,即45角,所以4元5角 = 45 角;(4) 1 元 = 10 角 = 100 分。", + "knowledge_points": [ + "元,角,分的认识及换算" + ], + "source": "21-22一年级下·广东阳江·期末" + }, + { + "id": "456", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.65, + "question": "5元6角 = () 角 28角 = () 元角 10分 = () 角 2元 = () 角", + "options": [ + + ], + "answer": "56;2;8;1;20", + "solution": "【分析】元与角之间的进率是 10,角与分之间的进率也是 10,即 1 元 = 10 角, 1 角 = 10 分;据此解答.\n【详解】(1)5元6角 = 50 角 + 6 角 = 56 角,所以 5 元 6 角 = 56 角;(2) 28 角 = 20 角 + 8 角 = 2 元 8 角,所以 28 角 = 2 元 8 角;(3) 10 分 = 1 角;(4) 2元 = 20 角。", + "knowledge_points": [ + "元,角,分的认识及换算" + ], + "source": "21-22一年级下·北京西城·期末" + }, + { + "id": "457", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.65, + "question": "( )张![](images/015a87592368fd852a781d4a2dfd7276ac2184c2aa4bdb92cade393a174e5892.jpg) \n可以换1张![](images/11431439d21a9988dec547f07fc4e78c80e9b68a8af5af9f2c543c273d48d20e.jpg)", + "options": [ + + ], + "answer": "4", + "solution": "【分析】根据20里面有4个5,进行解答即可.\n【详解】 5 + 5 + 5 + 5 = 20 (元);所以,4 张 5 元可以换 1 张 20 元。", + "knowledge_points": [ + "连加(20以内)", + "十元以上人民币的认识与计算" + ], + "source": "21-22一年级下·浙江台州·期末" + }, + { + "id": "458", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.65, + "question": "10 元 -6 元 = ( )元 6元5角+3角=( )元( )角", + "options": [ + + ], + "answer": "4;6;8", + "solution": "【分析】单位相同的两个数可直接进行加减计算,据此解答.\n【详解】 (1) 10元-6元=4元;(2) 6元5角+3角=6元8角。", + "knowledge_points": [ + "十元以下人民币的认识与计算" + ], + "source": "21-22 一年级下·山东菏泽·期末" + }, + { + "id": "459", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.65, + "question": "填一填.\n( )分=6角 5元=( )角 28角 = ( ) 元( )角5角2分 = ( )分", + "options": [ + + ], + "answer": "60;50;2;8;52", + "solution": "【分析】根据 1 元 = 10 角 = 100 分, 1 角 = 10 分,据此解答即可.\n【详解】10分=1角,即60分=6角;1元=10角,即5元=50角;20角 = 2 元,即28角 = 2 元8角;5角 = 50 分,即5角2分 = 52 分", + "knowledge_points": [ + "元,角,分的认识及换算", + "十元以下人民币的认识与计算" + ], + "source": "21-22 一年级下·四川自贡·期末" + }, + { + "id": "460", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.65, + "question": "小刚有 10 元钱,买一个本子 2 元 5 角钱,买两个同样的本子后还剩( )元。", + "options": [ + + ], + "answer": "5或五", + "solution": "【分析】根据题意,先算出买2个本子需要多少钱,再用10元减去买2个本子需要的钱,即可得出答案。在计算时要注意\"满十角变一元\".\n【详解】2元5角+2元5角=5元 10 - 5 = 5 (元)所以,买两个同样的本子后还剩5元。", + "knowledge_points": [ + "元,角,分的认识及换算", + "十元以下人民币的认识与计算" + ], + "source": "21-22 一年级下·山西阳泉·期末" + }, + { + "id": "461", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.65, + "question": "7角+9角=( )元( )角 1元-6角 = ( )角", + "options": [ + + ], + "answer": "1;6;4", + "solution": "【分析】根据元与角的换算:1元 = 10 角,进行解答即可.\n【详解】7角+9角=16角,16角=1元6角;1元 = 10 角,则 1 元 -6 角 = 10 角 -6 角 = 4 角", + "knowledge_points": [ + "元,角,分的认识及换算", + "十元以下人民币的认识与计算" + ], + "source": "21-22一年级下·湖南怀化·期末" + }, + { + "id": "462", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.65, + "question": "一个书包 49 元,妈妈带 5 张 10 元,能买到书包吗。 ( ) (填能不能)。", + "options": [ + + ], + "answer": "能", + "solution": "【分析】将妈妈带的钱与书包的价格进行比较即可.\n【详解】 10 + 10 + 10 + 10 + 10 = 50 (元)50 \u003e 49,所以能够买到书包。", + "knowledge_points": [ + "100 以内数的比大小", + "十元以上人民币的认识与计算" + ], + "source": "21-22 一年级下·湖南怀化·期末" + }, + { + "id": "463", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.65, + "question": "6 元 4 角 +3 元 6 角=()。", + "options": [ + + ], + "answer": "10;82", + "solution": "【分析】元与角之间的进率是 10,即 1 元 = 10 角,据此解答.\n【详解】(1)6元4角+3元6角中,6元+3元=9元,4角+6角=10角=1元,9元再加1元是10元,所以6元4角+3元6角=10元;(2) 8元2角中, 8元是80角,再加2角是82角,所以8元2角=82角。", + "knowledge_points": [ + "元,角,分的认识及换算" + ], + "source": "21-22 一年级下·云南保山·期末" + }, + { + "id": "464", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.65, + "question": "84 角 = ( ) 元( )角 5元5角 = () 角", + "options": [ + + ], + "answer": "8;4;55", + "solution": "【分析】元与角之间的进率是 10,即 1 元 = 10 角,据此解答.\n【详解】(1)84角 = 80 角 +4 角 = 8 元 +4 角 = 8 元4角;(2) 5元5角 = 50 角 +5角 = 55角", + "knowledge_points": [ + "元,角,分的认识及换算" + ], + "source": "21-22 一年级下·湖北黄冈·期末" + }, + { + "id": "465", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.65, + "question": "6 元 3 角 = ( ) 角 9元-70角 = ( )元", + "options": [ + + ], + "answer": "63;2", + "solution": "【分析】根据元与角的换算:1 元 = 10 角进行解答即可.\n【详解】6元 = 60 角,所以6元3角 = 63 角;9元 = 90 角, 90角 -70 角 = 20 角, 20角 = 2 元,所以9元 -70 角 = 2 元。", + "knowledge_points": [ + "元,角,分的认识及换算", + "十元以下人民币的认识与计算" + ], + "source": "21-22 一年级下·山东临沂·期末" + }, + { + "id": "466", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.65, + "question": "1 元 = ( ) 角 15 角 = ( )元( )角 60 角 = ( )元 100分=( )角 1角=( )分 2元7角=( )角", + "options": [ + + ], + "answer": "10;1;5;6;10;10;27", + "solution": "【分析】根据1元 = 10 角 = 100 分进行换算即可得出答案.\n【详解】1元 = 10 角 15角 = 1 元5角 60角 = 6 元;100分=10角 1角=10分 2元7角=27角", + "knowledge_points": [ + "元,角,分的认识及换算" + ], + "source": "21-22 一年级下·吉林·期末" + }, + { + "id": "467", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.65, + "question": "3元=( )角 20角 = ( ) 元;7角 +8 角 = ( )元( )角 2角 +1 元3角 = ( )元( )角", + "options": [ + + ], + "answer": "30;2;1;5;1;5", + "solution": "[analysis]元与角之间的进率是 10,角与分之间的进率也是 10,即 1 元 = 10 角, 1 角 = 10 分,据此解答。(1) 3元是3个10角,即30角;(2) 20角是2个1元,即2元;(3) 7角 + 8角 = 15角 = 1元 5角;(4) 2角 +1元3角 = 1元 +5角 = 1元5角.\n【详解】 (1) 3元 = 30 角(2) 20 角 = 2 元 (3) 7角 + 8角 = 1元 5角 (4) 2角 +1 元 3 角 = 1 元 5 角", + "knowledge_points": [ + "元,角,分的认识及换算" + ], + "source": "21-22一年级下·湖南常德·期末" + }, + { + "id": "468", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.65, + "question": "6 元 8 角 = ( )角 43角 = ( ) 元( )角", + "options": [ + + ], + "answer": "68;4;3", + "solution": "【分析】根据 1 元 = 10 角进行单位换算,据此即可得出答案.\n【详解】6元8角 = 68 角;43角 = 4 元3角", + "knowledge_points": [ + "元,角,分的认识及换算" + ], + "source": "21-22 一年级下·湖北随州·期末" + }, + { + "id": "469", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.85, + "question": "69 角= ( ) 元( )角 7 角 +6 角 = ( )元( )角", + "options": [ + + ], + "answer": "6;9;1;3", + "solution": "【分析】根据 1 元 = 10 角,换算即可.\n【详解】69角 = 10 角 +10 角 +10 角 +10 角 +10 角 +9角 = 6元9角;7角+6角=13角=10角+3角=1元3角", + "knowledge_points": [ + "元,角,分的认识及换算" + ], + "source": "21-22 一年级下·青海西宁·期末" + }, + { + "id": "470", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.65, + "question": "7 元 2 角 = ( ) 角 48角 = ( )元( )角 9角-2角 = ( )角5角 +1 元6角 = ()元()角", + "options": [ + + ], + "answer": "72;4;8;7;2;1", + "solution": "【分析】元与角之间的进率是 10,角与分之间的进率也是10,即 1 元 = 10 角, 1 角 = 10 分。(1) 7元2角中,7元即是70角,再加上2角,是72角;(2) 48角里面有4个10角和1个8角,也就是4个1元和1个8角,即4元8角;(3) 9角 -2 角 = 7 角;(4) 5角 +1 元 6角中, 5角 +6角 = 11角,即 1 元 1 角,再加 1 元是 2 元 1 角.\n【详解】根据分析可知:(1) 7元2角 = 72 角;(2) 48 角 = 4 元 8 角;(3) 9角 -2 角 = 7 角;(4) 5角 +1 元 6 角 = 2 元 1 角。", + "knowledge_points": [ + "元,角,分的认识及换算" + ], + "source": "21-22 一年级下·河南南阳·期末" + }, + { + "id": "471", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.65, + "question": "一个文具盒7元,", + "options": [ + + ], + "answer": "13", + "solution": "【分析】用妈妈付的 20 元钱减去一个文具盒的价钱,据此即可得出应找回多少元.\n【详解】 20 - 7 = 13 (元);所以,应找回13元。", + "knowledge_points": [ + "减法表(20以内)", + "十元以上人民币的认识与计算" + ], + "source": "21-22一年级下·福建三明·期末" + }, + { + "id": "472", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.65, + "question": "3 元 6 角 = ( ) 角 27 分=( )角( )分", + "options": [ + + ], + "answer": "36;2;7", + "solution": "【分析】一元 = 10 角,一角 = 10 分,由此进行解答即可.\n【详解】3元 = 30 角,所以3元6角 = 36 角;一角 = 10 分,所以 27 分 = 2 角 7 分", + "knowledge_points": [ + "元,角,分的认识及换算" + ], + "source": "21-22 一年级下·福建三明·期末" + }, + { + "id": "473", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.65, + "question": "3 元 8 角 = ( ) 角 7角+5角=( )元( )角", + "options": [ + + ], + "answer": "38;1;2", + "solution": "【分析】根据 1 元 = 10 角,进行换算即可.\n【详解】3元 = 30 角,所以 3 元 8 角 = 38 角。7角+5角=12角,12角=1元2角。", + "knowledge_points": [ + "元,角,分的认识及换算", + "十元以下人民币的认识与计算" + ], + "source": "21-22 一年级下·西藏那曲·期末" + }, + { + "id": "474", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.85, + "question": "在()里填上元或角.\n一支铅笔5();一瓶可乐3( );一个书包35();一块橡皮擦4( )。", + "options": [ + + ], + "answer": "角;元;元;角", + "solution": "【分析】根据生活经验,对元,角和数据的大小认识可知:一支铅笔 5 角,一瓶可乐 3 元,一个书包 35 元,一块橡皮擦 4 角.\n【详解】一支铅笔5角;一瓶可乐3元;一个书包 35 元;一块橡皮擦 4 角。", + "knowledge_points": [ + "元,角,分的认识及换算" + ], + "source": "20-21一年级下·海南省直辖县级单位·期末" + }, + { + "id": "475", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.65, + "question": "2元9角=( )角 20分=()角 7角 +5 角 = ( )元( )角 4元 +1 元2角 = ( )元()角", + "options": [ + + ], + "answer": "29;2;1;2;5;2", + "solution": "【分析】元与角之间的进率是 10,角与分之间的进率也是 10,即 1 元 = 10 角, 1 角 = 10 分。(1) 2元9角里面有2个1元,也就是有2个10角,即20角,再加9角,是29角;(2) 20 分里面有 2 个 10 分,也就是 2 个 1 角,即 2 角;(3) 7 角 +5 角,共 12 角,也就是 1 个 10 角加 2 角,即 1 元 2 角;(4) 4元 +1 元 2 角, 4 元加 1 元是 5 元,再加 2 角,是 5元2角.\n【详解】 (1) 2元9角 = 29 角(2) 20 分 = 2 角 (3) 7角 + 5角 = 1元 2角 (4) 4 元 + 1 元 2 角 = 5 元 2 角", + "knowledge_points": [ + "元,角,分的认识及换算" + ], + "source": "21-22一年级下·湖北孝感·期末" + }, + { + "id": "476", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.65, + "question": "3 元 = ( )角 50角 = ( ) 元 4元7角 = ( ) 角 1元 = ( )分", + "options": [ + + ], + "answer": "30;5;47100", + "solution": "【分析】元与角之间的进率是 10,角与分之间的进率也是 10,元与分之间的进率是 100,即 1 元 = 10 角, 1 角 = 10 分,1元 = 100 分;(1) 3元里面有3个1元,也就是有3个10角,即30角;(2) 50角里面有5个10角,也就是5个1元,即5元;(3) 4元7角中, 4元里面有4个1元,也就是4个10角,即40角,再加上7角,是47角;(4) 1 元里面有 10 角,也就是 100 分.\n【详解】 (1) 3元 = 30 角(2) 50 角 = 5 元 (3) 4元7角 = 47 角 (4) 1 元 = 100 分", + "knowledge_points": [ + "元,角,分的认识及换算" + ], + "source": "21-22 一年级下·江西赣州·期末" + }, + { + "id": "477", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.65, + "question": "30 分 = ( )角 9分+7分=( )角( )分3元9角 = ( ) 角 34角 = ( ) 元( )角", + "options": [ + + ], + "answer": "3;1;6;39;3;4", + "solution": "【分析】元与角之间的进率是 10,角与分之间的进率也是 10,即 1 元 = 10 角, 1 角 = 10 分,据此解答。(1) 30 分 = 10 分 + 10 分 + 10 分 = 1 角 + 1 角 + 1 角 = 3 角 (2) 9 分 + 7 分 = 16 分 = 10 分 + 6 分 = 1 角 + 6 分 = 1 角 + 6 分 (3) 3元9角 = 3 元 + 9 角 = 30 角 + 9 角 = 39 角 (4) 34角 = 30 角 +4 角 = 3 元 +4 角 = 3 元 4 角\n【详解】 (1) 30 分 = 3 角(2) 9 分 + 7 分 = 1 角 6 分 (3) 3元9角 = 39 角 (4) 34角 = 3 元 4角", + "knowledge_points": [ + "元,角,分的认识及换算" + ], + "source": "21-22 一年级下·河南南阳·期末" + }, + { + "id": "478", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.85, + "question": "3 元 = ( ) 角 4 元+2元5角 = ( ) 元( )角", + "options": [ + + ], + "answer": "30;6;5", + "solution": "【分析】根据元和角之间的关系 10 角等于 1 元进行换算即可.\n【详解】3元 = 30 角;4元+2元5角=6元5角", + "knowledge_points": [ + "元,角,分的认识及换算", + "十元以下人民币的认识与计算" + ], + "source": "21-22 一年级下·贵州铜仁·期末" + }, + { + "id": "479", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.65, + "question": "8 元=()角 26角 = () 元( )角 70角 = ( )元 3元9角 = ( )角", + "options": [ + + ], + "answer": "80;2;6;7;39", + "solution": "【分析】根据人民币元和角之间的换算关系(1 元 = 10 角)进行计算.\n【详解】8元 = (80)角;26角 = (2)元(6)角;70角= (7)元;3元9角 = (39) 角", + "knowledge_points": [ + "元,角,分的认识及换算" + ], + "source": "21-22 一年级下·河南信阳·期末" + }, + { + "id": "480", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.85, + "question": "一盒橡皮泥价钱是14.65( );一瓶可乐的价钱是3( )。", + "options": [ + + ], + "answer": "元;元", + "solution": "【分析】 本题主要考察对人民币常用单位的理解。日常生活中,物品价值较高时通常用\"元\"作为单位。橡皮泥价格14.65和可乐价格3都符合用\"元\"表示的常见范围.\n【详解】 根据生活常识,橡皮泥和可乐的价格都在几元到几十元之间,所以都应填写\"元\"。", + "knowledge_points": [ + "元,角,分的认识及换算" + ], + "source": "21-22 一年级下·全国·单元测试" + }, + { + "id": "481", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.65, + "question": "一张 50 元可以换( )张 10 元;一张 10 元可以换 ( )张 5 元;一张 5 元可以换 ( )张 2 元;一张 2 元可以换 ( )张 10 元。)张2元和( )张1元。", + "options": [ + + ], + "answer": "5;2;2;1", + "solution": "【分析】 本题考察不同面额人民币之间的换算关系,需要根据人民币的实际面值进行计算.\n【详解】 50元 / 10元/张 = 5张;10元 / 5元/张 = 2张;5元 / 2元/张 = 2张。1元,但题目要求恰好能换的张数,所以是2张2元;2元 / 1元/张 = 2张。", + "knowledge_points": [ + "元,角,分的认识及换算", + "十元以下人民币的认识与计算", + "十元以上人民币的认识与计算" + ], + "source": "21-22 一年级下·全国·单元测试" + }, + { + "id": "482", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.65, + "question": "6 元 = ( ) 角 3 元 5 角 = ( ) 角 40角 = ( ) 元 87角 = ( ) 元( )角", + "options": [ + + ], + "answer": "60;35;4;8;7", + "solution": "【分析】 本题考察元与角之间的单位换算,牢记1元 = 10角是解题关键.\n【详解】 6元 = 6×10角 = 60角;3元5角 = 3×10角 + 5角 = 35角;40角 = 40÷10 = 4元;87角 = 80角 + 7角 = 8元7角。", + "knowledge_points": [ + "元,角,分的认识及换算" + ], + "source": "21-22 一年级下·全国·单元测试" + }, + { + "id": "483", + "unit": "第五单元认识人民币", + "question_type": "填空题", + "difficulty": 0.85, + "question": "在括号里填上 \"\u003e\" \"\u003c\" 或 \"=\".\n1元( )9角 78( )873元5角( )35元", + "options": [ + + ], + "answer": "\u003e;\u003c;\u003c", + "solution": "【分析】 本题包含两种比较:人民币单位的比较和数字大小的比较,需要统一单位后再进行比较.\n【详解】 1元 = 10角,所以1元 \u003e 9角;78和87都是两位数,十位上7 \u003c 8,所以78 \u003c 87;3元5角 \u003c 4元,而35元远大于4元,所以3元5角 \u003c 35元。", + "knowledge_points": [ + "100以内数的比大小", + "元,角,分的认识及换算" + ], + "source": "21-22 一年级下·全国·单元测试" + }, + { + "id": "484", + "unit": "第五单元认识人民币", + "question_type": "判断题", + "difficulty": 0.65, + "question": "1 张 50 元可以换 2张20元和2张5元的人民币。()", + "options": [ + + ], + "answer": "√", + "solution": "【分析】将 2 张 20 元和 2 张 5 元相加得到的结果与 1 张 50 元比较即可.\n【详解】20元+20元+5元+5元= 40 元 + 5 元 + 5 元 = 45 元 + 5 元= 50 元,故答案为: √ 。", + "knowledge_points": [ + "十元以上人民币的认识与计算" + ], + "source": "20-21 一年级下·湖北十堰·期末" + }, + { + "id": "485", + "unit": "第五单元认识人民币", + "question_type": "判断题", + "difficulty": 0.85, + "question": "36 分 = 3 角 6 分。( )", + "options": [ + + ], + "answer": "√", + "solution": "【分析】根据 1 角 = 10 分,将 36 角换算单位即可解答.\n【详解】由分析可知: 36 分 = 30 分 + 6 分 = 3 角 6 分 故答案为: √", + "knowledge_points": [ + "元,角,分的认识及换算" + ], + "source": "21-22 一年级下·陕西渭南·期末" + }, + { + "id": "486", + "unit": "第五单元认识人民币", + "question_type": "判断题", + "difficulty": 0.85, + "question": "45 角和 5 元 3 角比, 45 角多。( )", + "options": [ + + ], + "answer": "×", + "solution": "【分析】根据l元 = 10 角,解答此题即可.\n【详解】5元3角 = 53 角, 45 \u003c 53 所以45角和5元3角比,45角少;所以题干说法是错误的。故答案为: ×", + "knowledge_points": [ + "元,角,分的认识及换算" + ], + "source": "20-21 一年级下·青海玉树·期末" + }, + { + "id": "487", + "unit": "第五单元认识人民币", + "question_type": "判断题", + "difficulty": 0.65, + "question": "一张5元的纸币和5枚1元的硬币同样多。( )", + "options": [ + + ], + "answer": "√", + "solution": "【分析】一张5元的纸币表示5元,5枚1元的硬币表示5元,所以它们所表示的面值一样多,据此进行判断即可.\n【详解】一张 5 元的纸币和 5 枚 1 元的硬币同样多,原题说法正确.\n故答案为: √", + "knowledge_points": [ + "元,角,分的认识及换算", + "十元以下人民币的认识与计算" + ], + "source": "21-22一年级下·湖北省直辖县级单位·期末" + }, + { + "id": "488", + "unit": "第五单元认识人民币", + "question_type": "判断题", + "difficulty": 0.85, + "question": "88。(21-22一年级下·河北张家口·期末)1块橡皮5角,1支圆珠笔 1 元,橡皮比圆珠笔贵。()", + "options": [ + + ], + "answer": "×", + "solution": "【分析】根据 1 元 = 10 角,将单位换算统一后再比较,即可判断.\n【详解】1元 = 10 角;10角 \u003e5 角\n所以橡皮比圆珠笔便宜;故答案为: ×", + "knowledge_points": [ + "元,角,分的认识及换算" + ], + "source": "21-22一年级下·河北张家口·期末" + }, + { + "id": "489", + "unit": "第五单元认识人民币", + "question_type": "判断题", + "difficulty": 0.65, + "question": "一张1元的人民币可以换2张5角的人民币。()", + "options": [ + + ], + "answer": "√", + "solution": "【分析】根据\"1元 = 10 角\"解答即可.\n【详解】1元 = 5 角 +5角,所以原说法正确。故答案为: √", + "knowledge_points": [ + "元,角,分的认识及换算" + ], + "source": "20-21一年级下·河南三门峡·期末" + }, + { + "id": "490", + "unit": "第五单元认识人民币", + "question_type": "判断题", + "difficulty": 0.85, + "question": "2 元 7 角是 2.7 角。( )", + "options": [ + + ], + "answer": "×", + "solution": "【分析】根据 1 元 = 10 角,据此解答即可.\n【详解】2元7角 = 27 角,原题说法错误.\n故答案为: ×", + "knowledge_points": [ + "元,角,分的认识及换算" + ], + "source": "20-21一年级下·云南保山·期末" + }, + { + "id": "491", + "unit": "第五单元认识人民币", + "question_type": "判断题", + "difficulty": 0.65, + "question": "9角 \u003e1 元。()", + "options": [ + + ], + "answer": "×", + "solution": "【分析】根据对人民币的认识以及换算即可解答.\n【详解】1元 = 10 角,10角 \u003e9 角,所以9角 \u003c 1 元.\n故答案为: ×", + "knowledge_points": [ + "元,角,分的认识及换算" + ], + "source": "21-22一年级下·湖南常德·期末" + }, + { + "id": "492", + "unit": "第五单元认识人民币", + "question_type": "判断题", + "difficulty": 0.85, + "question": "100 角 \u003e10 元。( )", + "options": [ + + ], + "answer": "×", + "solution": "【分析】根据角与元的换算可解答此题.\n【详解】10角 = 1 元,100角 = 10 元。故答案为: ×", + "knowledge_points": [ + "元,角,分的认识及换算", + "十元以上人民币的认识与计算" + ], + "source": "21-22 一年级下·湖北孝感·期末" + }, + { + "id": "493", + "unit": "第五单元认识人民币", + "question_type": "判断题", + "difficulty": 0.94, + "question": "常用的人民币单位有元,角,分。( )", + "options": [ + + ], + "answer": "√", + "solution": "【分析】根据人民币的认识可解答此题.\n【详解】常用的人民币单位有元,角,分不常用,故答案为: ×", + "knowledge_points": [ + "元,角,分的认识及换算" + ], + "source": "21-22 一年级下·全国·单元测试" + }, + { + "id": "494", + "unit": "第五单元认识人民币", + "question_type": "计算题", + "difficulty": 0.65, + "question": "计算.\n5角+9角 = () ()元-8角 = 15 () 元-6元 =()", + "options": [ + + ], + "answer": "1元4角;2角;9元", + "solution": "【分析】10角 = 1 元,据此计算即可.\n【详解】5角+9角=1元4角;1元-8角=2角;15元-6元=9元", + "knowledge_points": [ + "十元以下人民币的认识与计算", + "十元以上人民币的认识与计算" + ], + "source": "21-22 一年级下·福建龙岩·期末" + }, + { + "id": "495", + "unit": "第五单元认识人民币", + "question_type": "计算题", + "difficulty": 0.65, + "question": "计算下面各题.\n1元-3角 = ( ) 角 3元-8角 = ( ) 元( )角 \n9角 +3 角 = ( )元( )角 20元一7元 = ( )元 \n4角+3元6角 = ( ) 元8角+4元 = ( ) 元( )角 \n7元一2元7角 = ( ) 元( )角", + "options": [ + + ], + "answer": "7;2;2;1;2;13;4;4;8;4;3", + "solution": "【分析】 本题考查人民币的简单计算。解题时需注意:1元=10角。进行加减运算时,相同单位的数相加减,当\"角\"满10时,要向\"元\"进1;不够减时,可从\"元\"借1当10角。有的题目需要统一单位再计算.\n【详解】1元 - 3角 = 10角 - 3角 = 7角;3元 - 8角 = 2元10角 - 8角 = 2元2角;9角 + 3角 = 12角 = 1元2角;20元 - 7元 = 13元;4角 + 3元6角 = 3元10角 = 4元;8角 + 4元 = 4元8角;7元 - 2元7角 = 6元10角 - 2元7角 = 4元3角。", + "knowledge_points": [ + "十元以下人民币的认识与计算" + ], + "source": "21-22 一年级下·全国·单元测试" + }, + { + "id": "496", + "unit": "第五单元认识人民币", + "question_type": "解答题", + "difficulty": 0.65, + "question": "小明带了 10 元钱到超市,买了一个 5 元的毽子和一副 1 元 3 角的尺子,他一共花多少钱。", + "options": [ + + ], + "answer": "6元3角", + "solution": "【分析】把尺子的价钱和尺子的价钱相加即可,据此即可解答.\n【详解】5元+1元3角=6元3角,答:他一共花了 6 元 3 角钱。", + "knowledge_points": [ + "十元以下人民币的认识与计算" + ], + "source": "21-22 一年级下·福建泉州·期末" + }, + { + "id": "497", + "unit": "第五单元认识人民币", + "question_type": "解答题", + "difficulty": 0.65, + "question": "购物.\n![](images/c14d4312c6058b69da2ac993f46bbad07859dc3dfd6cd6d755c7d7af32cd27e5.jpg)\n(1)5元正好可以买哪两样物品。(列式表示) \n(2)小红拿1元钱,买一条冰棍和一个雪糕,够吗。(在正确答案括号里打\"√\")答:够( ),不够( ).\n(3)你能提出什么数学问题。列式解决。", + "options": [ + + ], + "answer": "2 + 3 = 5(元);不够;(√) 买一瓶果汁和一条冰棍,一共需要多少钱。3元+5角=3元5角 (答案不唯一)", + "solution": "【分析】(1)结合价目表上各种物品的价钱,矿泉水和果汁的价钱和起来刚好是 5 元,据此列式解答即可;(2) 先算出买一条冰棍和一个雪糕的价钱,再跟 1 元进行比较即可得出答案;(3) 根据价目表,结合学过的数学知识,提出问题并解决问题即可.\n【详解】 (1) 2 + 3 = 5 (元)答: 5 元正好可以买一瓶矿泉水和一瓶果汁。(2) 5 + 8 = 13 (角)13角 = 1 元3角,1元3角 \u003e 1 元答:够 ( ),不够 (√)。(3) 买一瓶果汁和一条冰棍,一共需要多少钱。3元+5角=3元5角,答:一共需要 3 元 5 角钱。(答案不唯一)", + "knowledge_points": [ + "经济问题", + "十元以下人民币的认识与计算" + ], + "source": "21-22一年级下·广东江门·期末" + }, + { + "id": "498", + "unit": "第五单元认识人民币", + "question_type": "解答题", + "difficulty": 0.65, + "question": "98。(21-22一年级下·西藏林芝·期末)付一张50元和一张10元的人民币,正好能买一个书包,这个书包多少钱。", + "options": [ + + ], + "answer": "60元", + "solution": "【分析】用 50 元加 10 元就是这个书包的钱数,用加法计算即可.\n【详解】 50 + 10 = 60 (元)答:这个书包 60 元钱。", + "knowledge_points": [ + "十元以上人民币的认识与计算" + ], + "source": "21-22一年级下·西藏林芝·期末" + }, + { + "id": "499", + "unit": "第五单元认识人民币", + "question_type": "解答题", + "difficulty": 0.65, + "question": "小小商店.\n![](images/df8b1f368d801c9a16f1de518d646f13331f463421707bc66fa64855c5c5961d.jpg)\n(1) 铅笔盒和尺子,一共用了多少钱。 \n(2) 钢笔比铅笔贵多少多少钱。 \n(3) 50 元买 5 支钢笔够吗。 \n(4) 你还能提出其他数学问题并解答吗。", + "options": [ + + ], + "answer": "7元5角;6元3角 够 铅笔盒和橡皮,一共用了多少钱。;7 元 (答案不唯一)", + "solution": "【分析】(1)用铅笔盒单价加尺子单价,加法计算即可;(2) 用钢笔单价减铅笔单价,减法计算即可;(3) 连续 5 个 9 相加,得出结果与 50 比较大小,若是小于 50,就够;若是大于 50,就不够,据此解答;(4) 只要符合题意即可,答案不唯一.\n【详解】 (1) 6元5角 +1 元 = 7 元5角,答:一共用了 7 元 5 角钱。(2) 9元-2元7角=6元3角答:钢笔比铅笔贵 6 元 3 角钱.\n(3) 50 元 \u003e 45元,够。答: 50 元买 5 支笔够。(4) 铅笔盒和橡皮,一共用了多少钱。6元5角+5角=7元,答:一共用了 7 元钱。(答案不唯一)", + "knowledge_points": [ + "经济问题", + "\"提问题\"\"填条件\"问题", + "十元以下人民币的认识与计算" + ], + "source": "20-21一年级下·湖北鄂州·期末" + }, + { + "id": "500", + "unit": "第五单元认识人民币", + "question_type": "解答题", + "difficulty": 0.65, + "question": "一支钢笔 3 元 6 角,一个橡皮擦 1 元,我付 5 元钱买这两样商品,够吗。", + "options": [ + + ], + "answer": "够", + "solution": "【分析】先算出一支钢笔和一块橡皮擦一共多少钱,再与5元比较即可.\n【详解】3元6角 +1 元 = 4 元6角;5元\u003e4元6角;答:够。", + "knowledge_points": [ + "十元以下人民币的认识与计算" + ], + "source": "21-22一年级下·湖北黄冈·期末" + } +] \ No newline at end of file diff --git "a/\344\270\200\345\271\264\347\272\247\351\242\230\351\233\206/\344\270\200\345\271\264\347\272\247\344\270\213/\344\270\200\345\271\264\347\272\247\344\270\213\347\254\254\345\205\255\345\215\225\345\205\203100\344\273\245\345\206\205\347\232\204\345\212\240\346\263\225\345\222\214\345\207\217\346\263\225.json" "b/\344\270\200\345\271\264\347\272\247\351\242\230\351\233\206/\344\270\200\345\271\264\347\272\247\344\270\213/\344\270\200\345\271\264\347\272\247\344\270\213\347\254\254\345\205\255\345\215\225\345\205\203100\344\273\245\345\206\205\347\232\204\345\212\240\346\263\225\345\222\214\345\207\217\346\263\225.json" new file mode 100644 index 0000000000000000000000000000000000000000..1304012de2f1a649ab336d238d0c2604e59336f5 --- /dev/null +++ "b/\344\270\200\345\271\264\347\272\247\351\242\230\351\233\206/\344\270\200\345\271\264\347\272\247\344\270\213/\344\270\200\345\271\264\347\272\247\344\270\213\347\254\254\345\205\255\345\215\225\345\205\203100\344\273\245\345\206\205\347\232\204\345\212\240\346\263\225\345\222\214\345\207\217\346\263\225.json" @@ -0,0 +1,7765 @@ +[ + { + "id": "1", + "unit": "第六单元100以内的加法和减法1", + "question_type": "选择题", + "difficulty": 0.85, + "question": "有一个人花 10 元买一块布, 20 元卖出, 30 元又买回来,最后又以 35 元卖出去了,在买卖过程中这个人 ( )。", + "options": [ + "A. 亏了 15 元", + "B. 赚了 15 元", + "C. 亏了 35 元", + "D. 赚了 35 元" + ], + "answer": "B", + "solution": "【分析】根据题意可知:赚的钱等于用售价减去进价,分别计算出每次卖出这块布赚的钱数,最后用加法计算出两次赚的钱数之和.\n【详解】 20 - 10 = 10 (元);35 - 30 = 5 (元);10 + 5 = 15 (元),则在买卖过程中这个人赚了15元。故答案为: B", + "knowledge_points": [ + "整十数之间的加减法", + "两位数与整十数的减法" + ], + "source": "24-25 二年级上·浙江温州·期末" + }, + { + "id": "2", + "unit": "第六单元100以内的加法和减法1", + "question_type": "选择题", + "difficulty": 0.65, + "question": "乐乐今年 10 岁,妈妈今年 36 岁, 10 年后,妈妈比乐乐大 ( ) 岁。", + "options": [ + "A. 46", + "B. 36", + "C. 26" + ], + "answer": "C", + "solution": "【分析】根据年龄差不变可知,今年妈妈比乐乐大几岁, 10 年后还是大几岁,则用妈妈今年的年龄减乐乐今年的年龄 = 妈妈比乐乐大的岁数.\n【详解】36-10=26(岁),乐乐今年10岁,妈妈今年36岁,10年后,妈妈比乐乐大26岁。故答案为:C", + "knowledge_points": [ + "两位数与整十数的减法" + ], + "source": "24-25 二年级上·广东汕头·期中" + }, + { + "id": "3", + "unit": "第六单元100以内的加法和减法1", + "question_type": "选择题", + "difficulty": 0.85, + "question": "明明买一个书包花了58元,付的全部是![](images/fbaf74244a2d1f375d21b61d6ed2ee7967c67ef99f8c22f21e1af7a15076d347.jpg)的人民币,他至少要付()张。", + "options": [ + "A. 5", + "B. 6", + "C. 7" + ], + "answer": "B", + "solution": "【分析】根据题意,分别用加法计算出各选项付出的钱数是多少,选择大于或等于58元,且付出张数最少的即可.\n【详解】A. 10 + 10 + 10 + 10 + 10 = 50 (元);50 < 58,不够付;B. 10 + 10 + 10 + 10 + 10 + 10 = 60 (元);60 > 58,够付;C. 10 + 10 + 10 + 10 + 10 + 10 + 10 = 70 (元);70 > 58,够付;6 张 < 7 张,则他至少要付6张。故答案为: B", + "knowledge_points": [ + "100 以内数的比大小", + "整十数之间的加减法", + "十元以上人民币的认识与计算" + ], + "source": "24-25 二年级上·河南商丘·期中" + }, + { + "id": "4", + "unit": "第六单元100以内的加法和减法1", + "question_type": "选择题", + "difficulty": 0.85, + "question": "体育室里有 24 个篮球, , 体育室有多少个足球。 如果列式为 24 + 3,应该选择条件 ( )。", + "options": [ + "A. 足球比篮球多 3 个", + "B. 足球比篮球少 3 个", + "C. 排球比篮球多 3 个" + ], + "answer": "A", + "solution": "【分析】根据题意,篮球有 24 个,求有多少个足球,列式为 24 + 3,求比一个数多几的数是多少,用加法计算,也就是加的 3 是足球比篮球多的数量,由此解答.\n【详解】A. 足球比篮球多 3 个,足球的数量为 24 + 3,符合题意;B. 足球比篮球少 3 个,足球的数量为 24 - 3,不符合题意;C. 排球比篮球多 3 个,与足球的数量无关,不符合题意。所以应该选择的条件是足球比篮球多 3 个。故答案为: A", + "knowledge_points": [ + "两位数与一位数的加法(不进位)", + "两位数与一位数的减法(不退位)" + ], + "source": "24-25 二年级上·河南南阳·期中" + }, + { + "id": "5", + "unit": "第六单元100以内的加法和减法1", + "question_type": "选择题", + "difficulty": 0.85, + "question": "足球 58 元,比篮球贵 13 元,排球比足球便宜 8 元,买一个排球多少钱。 解决 \"买一个排球多少钱\" 这个问题,要用到的信息是 ( )。", + "options": [ + "A. 58元,8元", + "B. 58元,13元", + "C. 13元,8元", + "D. 58元,8元,13元" + ], + "answer": "A", + "solution": "【分析】根据题意,排球比足球便宜8元,则用足球的价格减排球比足球便宜的价格 = 排球的价格.\n【详解】由分析列式为:58-8=50(元),也就是解决\"买一个排球多少钱\"这个问题,要用到的信息是58元,8元。故答案为:A", + "knowledge_points": [ + "两位数与一位数的减法(不退位)" + ], + "source": "24-25 二年级上·广东东莞·期中" + }, + { + "id": "6", + "unit": "第六单元100以内的加法和减法1", + "question_type": "选择题", + "difficulty": 0.65, + "question": "小华买了一个 33 元的文具盒,找回了 7 元,小华付了 ( ) 元给营业员。", + "options": [ + "A. 40", + "B. 26", + "C. 27" + ], + "answer": "A", + "solution": "【分析】根据加法的意义,文具盒的钱数 + 找回的钱数 = 小华付出的钱数.\n【详解】 33 + 7 = 40 (元),小华付了40元给营业员。故答案为: A", + "knowledge_points": [ + "一位数与两位数的进位加法" + ], + "source": "24-25 二年级上·广东东莞·期中" + }, + { + "id": "7", + "unit": "第六单元100以内的加法和减法1", + "question_type": "选择题", + "difficulty": 0.65, + "question": "假期时体验生活,娟娟卖了 36 件小玩具,(),依依卖了多少件小玩具。如果解决这个问题列式为 36 + 9 = 45 (件),那么应补充的信息为()。", + "options": [ + "A. 依依卖了 9 件小玩具", + "B. 依依比娟娟多卖了 9 件小玩具", + "C. 依依比娟娟少卖了 9 件小玩具" + ], + "answer": "B", + "solution": "【分析】由题可知,依依卖了多少件小玩具。列式是:36 +9=45(件),其中36是娟娟卖了的小玩具的件数,36+9表示比36多9的数,即依依卖了的小玩具的数量,所以需要补充的信息是依依比娟娟多卖了9件小玩具,据此解答即可.\n【详解】由分析可得,假期时体验生活,娟娟卖了 36 件小玩具,(),依依卖了多少件小玩具。如果解决这个问题列式为 36 + 9 = 45 (件),那么应补充的信息为依依比娟娟多卖了 9 件小玩具。故答案为: B", + "knowledge_points": [ + "\"提问题\"\"填条件\"问题", + "一位数与两位数的进位加法" + ], + "source": "24-25 二年级上·宁夏中卫·期中" + }, + { + "id": "8", + "unit": "第六单元100以内的加法和减法1", + "question_type": "选择题", + "difficulty": 0.65, + "question": "小马在计算 56 + 40 时,把 40 看成了 4,接下来 ( ) , 能使结果计算正确。", + "options": [ + "A. 再加 10", + "B. 再加 36", + "C. 再减 36" + ], + "answer": "B", + "solution": "【分析】根据题意可知:先分别计算出正确算式和不正确算式的答案。然后将求出的正确结果和不正确结果进行相减求出差,加数+加数 = 和,加数越大则和就越大,把40看成了4,即把和算少了,若想结果正确即把不正确算式的结果需再加上正确结果和不正确结果的差.\n【详解】 56 + 40 = 96;56 + 4 = 60;96 - 60 = 36;60 + 36 = 96; 则再加 36 能使结果计算正确。故答案为: B", + "knowledge_points": [ + "两位数与整十数的加法", + "两位数与整十数的减法", + "一位数与两位数的进位加法", + "错中求解问题(加减法)" + ], + "source": "24-25 二年级上·山东济南·期中" + }, + { + "id": "9", + "unit": "第六单元100以内的加法和减法1", + "question_type": "选择题", + "difficulty": 0.85, + "question": "足球 58 元,比篮球贵 13 元,排球比足球便宜 8 元,买一个排球多少钱。解决\"买一个排球多少钱\"这个问题,要用到的信息是()。", + "options": [ + "A. 58元;8元", + "B. 58元;13元", + "C. 13元;8元" + ], + "answer": "A", + "solution": "【分析】求比一个数少几的数是多少,用这个数减少的数计算,即足球的价格减排球比足球便宜的钱数 = 排球的价格,由此解答.\n【详解】由分析列式为:58-8=50(元),解决\"买一个排球多少钱\"这个问题,要用到的信息是58元和8元。故答案为:A", + "knowledge_points": [ + "两位数与一位数的减法(不退位)" + ], + "source": "24-25 二年级上·山东济南·期中" + }, + { + "id": "10", + "unit": "第六单元100以内的加法和减法1", + "question_type": "选择题", + "difficulty": 0.85, + "question": "当当计算 40-20 时,算成 40 + 20,这样算出的结果比正确结果 ( )。", + "options": [ + "A. 多 20", + "B. 多 40", + "C. 少 20" + ], + "answer": "B", + "solution": "【分析】根据整数加,减法的计算方法,分别计算出 40 - 20 和 40 + 20 的值,再作差即可.\n【详解】 40 - 20 = 20;40 + 20 = 60;60 - 20 = 40;所以当当计算 40 - 20 时,算成 40 + 20,这样算出的结果比正确结果多 40 。故答案为: B", + "knowledge_points": [ + "整十数之间的加减法" + ], + "source": "24-25 二年级上·河北·期中" + }, + { + "id": "11", + "unit": "第六单元100以内的加法和减法1", + "question_type": "选择题", + "difficulty": 0.65, + "question": "爸爸今年 35 岁,小丽今年 8 岁, 10 年后爸爸比小丽大 ( ) 岁。", + "options": [ + "A. 27", + "B. 37", + "C. 32" + ], + "answer": "A", + "solution": "【分析】根据年龄差不变可知,今年爸爸比小丽大几岁,10年后还是大几岁。用爸爸今年的年龄减小丽今年的年龄=爸爸比小丽大的岁数.\n【详解】35-8=27(岁),10年后爸爸比小丽大27岁。故答案为:A", + "knowledge_points": [ + "一位数与两位数的退位减法", + "年龄问题" + ], + "source": "23-24 二年级上·山西晋中·期中" + }, + { + "id": "12", + "unit": "第六单元100以内的加法和减法1", + "question_type": "选择题", + "difficulty": 0.85, + "question": "篮球运动可以促进耐力,弹跳灵敏度等运动素质的发展。体育用品店搞促销,现在每个篮球优惠8元出售,原来一个篮球45元。现在每个篮球的价钱是多少元。列式正确的是()。", + "options": [ + "A. 45 + 8", + "B. 8 + 45", + "C. 45 - 8" + ], + "answer": "C", + "solution": "【分析】根据减法的意义,用篮球原来的价钱减去 8 元即可求出篮球现在的价钱,据此列式计算即可.\n【详解】 45 - 8 = 37 (元),所以求现在每个篮球的价钱是多少元。列式正确的是:45 - 8。故答案为: C", + "knowledge_points": [ + "一位数与两位数的退位减法", + "促销问题" + ], + "source": "23-24 二年级上·河南南阳·期中" + }, + { + "id": "13", + "unit": "第六单元100以内的加法和减法1", + "question_type": "选择题", + "difficulty": 0.85, + "question": "最大的两位数和最小的两位数的差是 ( )。", + "options": [ + "A. 10", + "B. 89", + "C. 99" + ], + "answer": "B", + "solution": "【分析】最大的两位数是99,最小的两位数是10,根据减法的意义,用99-10即可求出最大的两位数和最小的两位数的差,据此解答即可.\n【详解】最大的两位数是99,最小的两位数是10。99-10=89,所以最大的两位数和最小的两位数的差是89。故答案为:B", + "knowledge_points": [ + "100 以内数的比大小", + "100 以内数的组成", + "两位数与整十数的减法" + ], + "source": "23-24 二年级上·山东济宁·期中" + }, + { + "id": "14", + "unit": "第六单元100以内的加法和减法1", + "question_type": "选择题", + "difficulty": 0.65, + "question": "公园里有杨树 74 棵,比柳树少7棵,公园里的柳树有()棵。", + "options": [ + "A. 67", + "B. 81", + "C. 73" + ], + "answer": "B", + "solution": "【分析】已知一个数比另一个数少几,求另一个数,用这个数加少的数计算,即杨树的数量 + 杨树比柳树少的数量 = 柳树的数量.\n【详解】 74 + 7 = 81 (棵),公园里的柳树有 81 棵。故答案为: B", + "knowledge_points": [ + "一位数与两位数的进位加法" + ], + "source": "23-24 二年级上·河南驻马店·期中" + }, + { + "id": "15", + "unit": "第六单元100以内的加法和减法1", + "question_type": "选择题", + "difficulty": 0.65, + "question": "姑姑今年 36 岁,小丽今年9岁,5年后姑姑比小丽大()。", + "options": [ + "A. 27", + "B. 22", + "C. 14" + ], + "answer": "A", + "solution": "【分析】5年后姑姑比小丽大的岁数和今年姑姑比小丽大的岁数是不变的,用今年姑姑的年龄减去今年小丽的年龄即可解答.\n【详解】 36 - 9 = 27 (岁),5年后姑姑比小丽大27岁。故答案为: A", + "knowledge_points": [ + "一位数与两位数的退位减法", + "年龄问题" + ], + "source": "23-24 二年级上·河南驻马店·期中" + }, + { + "id": "16", + "unit": "第六单元100以内的加法和减法1", + "question_type": "选择题", + "difficulty": 0.65, + "question": "下面算式 ( ) 的得数比 60 大。", + "options": [ + "A. 29 + 30", + "B. 85-7", + "C. 63-10" + ], + "answer": "B", + "solution": "【分析】先根据 100 以内加减法的计算法则,计算出各选项算式的得数,再将各得数与 60 比较大小即可.\n【详解】A. 29 + 30 = 59, 59 < 60;B. 85 - 7 = 78, 78 > 60;C. 63 - 10 = 53, 53 < 60 。故答案为: B", + "knowledge_points": [ + "100 以内数的比大小", + "两位数与整十数的加法", + "两位数与整十数的减法", + "一位数与两位数的退位减法" + ], + "source": "23-24 二年级上·甘肃庆阳·期中" + }, + { + "id": "17", + "unit": "第六单元100以内的加法和减法1", + "question_type": "选择题", + "difficulty": 0.85, + "question": "折纸船。小华折了26只纸船,小林比小华多折了8只,小林折了()只纸船。", + "options": [ + "A. 18", + "B. 32", + "C. 34" + ], + "answer": "C", + "solution": "【分析】根据加法的意义,用小华折的纸船数量加上8即可求出小林折的纸船数量.\n【详解】 26 + 8 = 34 (只),所以小林折了 34 只纸船。故答案为: C", + "knowledge_points": [ + "一位数与两位数的进位加法" + ], + "source": "23-24 二年级上·山东济宁·期中" + }, + { + "id": "18", + "unit": "第六单元100以内的加法和减法1", + "question_type": "选择题", + "difficulty": 0.65, + "question": "妈妈今年 45 岁,儿子今年 8 岁, 10 年后,妈妈比儿子大 ( ) 岁。", + "options": [ + "A. 17", + "B. 27", + "C. 37" + ], + "answer": "C", + "solution": "【分析】两人的年龄差是不变的。因此用妈妈今年的年龄减去儿子今年的年龄求出年龄差,也就是10年后妈妈比儿子大的岁数.\n【详解】 45 - 8 = 37 (岁),即,妈妈今年 45 岁,儿子今年 8 岁, 10 年后,妈妈比儿子大37岁。故答案为: C", + "knowledge_points": [ + "一位数与两位数的退位减法", + "年龄问题" + ], + "source": "23-24 二年级上·云南玉溪·期中" + }, + { + "id": "19", + "unit": "第六单元100以内的加法和减法1", + "question_type": "选择题", + "difficulty": 0.85, + "question": "一盒巧克力有 24 块,我送给爷爷 5 块,奶奶 5 块,还剩下多少块。 可以这样列式( )。", + "options": [ + "A. 24 - 5", + "B. 24 - (5 + 5)", + "C. 24 - 5 + 5" + ], + "answer": "B", + "solution": "【分析】根据题意,巧克力的总数量减送给爷爷的数量减送给奶奶的数量 = 还剩的数量;或者先用加法计算出一共送给爷爷和奶奶多少块,再用总数量减去一共送给爷爷奶奶的数量,就是还剩的数量.\n【详解】A.24-5,只计算出送出5块后还剩多少块,还有另外送出的5块没有减去,不符合题意;B.24-(5+5),5+5表示一共送给爷爷奶奶的数量,24再减去这个结果,就是还剩的数量,符合题意;C.24-5+5表示24块里送出去了5块后,又加上了5块,与题意不符。所以列式应为:24-(5+5)。故答案为:B", + "knowledge_points": [ + "一位数与两位数的退位减法", + "100以内数的加减混合运算", + "带有小括号的混合运算" + ], + "source": "23-24 二年级上·云南文山·期中" + }, + { + "id": "20", + "unit": "第六单元100以内的加法和减法1", + "question_type": "填空题", + "difficulty": 0.65, + "question": "35比20多( );比12多6的数是( )。", + "options": [], + "answer": "15;18", + "solution": "【分析】问谁比谁多,就用大数减小数计算即可,35比20多多少,用 35 - 20,比 12 多 6 的数是什么,就用 12 + 6,据此回答.\n【详解】 35 - 20 = 15;12 + 6 = 18,35 比 20 多 15;比 12 多 6 的数是 18 。", + "knowledge_points": [ + "不进位加法(20以内)", + "两位数与整十数的减法" + ], + "source": "24-25一年级下·广东韶关·期末" + }, + { + "id": "21", + "unit": "第六单元100以内的加法和减法1", + "question_type": "填空题", + "difficulty": 0.85, + "question": "在括号里填上 \">\" \"<\" 或 \"=\" .\n\n12 - 8 ( ) 5\n10 + 3 ( ) 14\n28 - 8 ( ) 10 + 8\n79 - 70 ( ) 8\n11 + 8 ( ) 19\n30 + 3 ( ) 34 - 4", + "options": [], + "answer": "<;<;>;>;=;>", + "solution": "【分析】比较数字的大小,首先要将需要计算的算式计算出来,其次要区分大小等于号,再进行数字大小的比较即可.\n【详解】12-8=4,4<5,所以12-8<5;10+3=13,13<14,所以10+3<14;28-8=20,10+8=18,20>18,所以28-8>10+8;79-70=9,9>8,所以79-70>8;11+8=19,19=19,所以11+8=19;30+3=33,34-4=30,33>30,所以30+3>34-4。", + "knowledge_points": [ + "100 以内数的比大小", + "不退位减法(20 以内)", + "两位数与一位数的加法(不进位)", + "两位数与整十数的减法" + ], + "source": "24-25 一年级下·河北石家庄·期中" + }, + { + "id": "22", + "unit": "第六单元100以内的加法和减法1", + "question_type": "填空题", + "difficulty": 0.85, + "question": "20 个苹果,每 10 个装一袋,可以装满( )袋。", + "options": [], + "answer": "2", + "solution": "【分析】要求将 20 个苹果,每 10 个装一袋,用总数减去每袋的个数,一直减到0,减去了几个10,就是可以装几袋.\n【详解】 20 - 10 = 10 (个), 10 - 10 = 0 (个),因此,20个苹果,每10个装一袋,可以装满2袋。", + "knowledge_points": [ + "两位数与整十数的减法", + "100以内数的连减运算" + ], + "source": "24-25 一年级下·湖南郴州·期中" + }, + { + "id": "23", + "unit": "第六单元100以内的加法和减法1", + "question_type": "填空题", + "difficulty": 0.65, + "question": "二班投票选班长,小明得 15 票,小红得 9 票,小丽得 6 票,总票数是( )票。", + "options": [], + "answer": "30", + "solution": "【分析】根据小明的得票数 + 小红的得票数 + 小丽的得票数 = 总票数的数量,列出算式算出答案即可解答.\n【详解】 15 + 9 + 6 = 24 + 6 = 30 (票),所以,总票数是30票。", + "knowledge_points": [ + "一位数与两位数的进位加法", + "100 以内数的连加运算" + ], + "source": "24-25 二年级下·湖南岳阳·期中" + }, + { + "id": "24", + "unit": "第六单元100以内的加法和减法1", + "question_type": "填空题", + "difficulty": 0.65, + "question": "在括号里填上\">\" \"<\"或\"=\" .\n14 - 9 ( ) 4\n40 + 8 ( ) 84\n56 - 6 ( ) 62 - 2\n63 - 3 ( ) 33\n16 - 7 ( ) 9\n99 + 9 ( ) 100", + "options": [], + "answer": ">;<;<;>;=;>", + "solution": "【分析】根据题意,分别算出等号左右两边的得数,再比较大小即可.\n【详解】14-9=5,5>4,故:14-9>4;40+8=48,48<84,故:40+8<84;56-6=50,62-2=60,50<60,故:56-6<62-2;63-3=60,60>33,故:63-3>33;16-7=9,9=9,故:16-7=9;99+9=108,108>100,故:99+9>100。", + "knowledge_points": [ + "100 以内数的比大小", + "十几减 9 的退位减法", + "整十数加,减一位数", + "两位数与一位数的减法(不退位)" + ], + "source": "24-25 一年级下·广东江门·期中" + }, + { + "id": "25", + "unit": "第六单元100以内的加法和减法1", + "question_type": "填空题", + "difficulty": 0.85, + "question": "在括号里填上\">\" \"<\"或\"=\" .\n18( )20\n12 + 7( )9\n12( )5+6\n15-4( )10\n9+8( )18+9", + "options": [], + "answer": "<;>;>;<", + "solution": "【分析】分别计算出各算式的答案,然后进行比较.\n【详解】18<20;12+7=19,19>9,则12+7>9;5+6=11,12>11,则12>5+6;15-4=11,11>10,则15-4>10;9+8=17,18+9=27,17<27,则9+8<18+9。", + "knowledge_points": [ + "不退位减法(20以内)", + "9加几的进位加法", + "8加几的进位加法", + "5~2加几的进位加法" + ], + "source": "24-25 一年级上·四川乐山·期末" + }, + { + "id": "26", + "unit": "第六单元100以内的加法和减法1", + "question_type": "填空题", + "difficulty": 0.85, + "question": "按规律填数:10,19,28,( ),( ),55。", + "options": [], + "answer": "37;46", + "solution": "【分析】根据数据可知,规律为从左往右依次的多9,据此解答.\n【详解】10+9=19;19+9=28;28+9=37;37+9=46;10,19,28,37,46,55。", + "knowledge_points": [ + "一位数与两位数的进位加法", + "整数排列的规律" + ], + "source": "20-21 二年级上·湖南长沙·期末" + }, + { + "id": "27", + "unit": "第六单元100以内的加法和减法1", + "question_type": "填空题", + "difficulty": 0.85, + "question": "比 41 少 20 的数是( )。", + "options": [], + "answer": "21", + "solution": "【分析】根据求比一个数少几的数,用减法计算.\n【详解】 41 - 20 = 21,则比 41 少 20 的数是 21。", + "knowledge_points": [ + "两位数与整十数的减法" + ], + "source": "24-25 二年级上·陕西西安·期末" + }, + { + "id": "28", + "unit": "第六单元100以内的加法和减法1", + "question_type": "填空题", + "difficulty": 0.85, + "question": "比 48 多 8 的数是( );40 比 54 少( )。", + "options": [], + "answer": "56;14", + "solution": "【分析】求比一个数多几的数,用加法列式解决;求一个数比另一个数少多少,用减法列式解决.\n【详解】 48 + 8 = 56;54 - 40 = 14;即,比 48 多 8 的数是 56;40 比 54 少 14。", + "knowledge_points": [ + "两位数与整十数的减法", + "一位数与两位数的进位加法" + ], + "source": "24-25 二年级上·福建福州·期末" + }, + { + "id": "29", + "unit": "第六单元100以内的加法和减法1", + "question_type": "填空题", + "difficulty": 0.65, + "question": "计算 43-□, 当□里最小填( )时,这是一道退位减法题,差是( )。", + "options": [], + "answer": "4;39", + "solution": "【分析】要使得 \"43- □ \" 是一道退位减法题,则 □ 里的数需要大于 3,而大于 3 且是最小的数是 4;故, □ 里最小填 4;然后用 43 - 4 求出差即可.\n【详解】由题意分析得:43 - 4 = 39;即,计算 43 - □ ,当□里最小填 4 时,这是一道退位减法题,差是 39。", + "knowledge_points": [ + "一位数与两位数的退位减法" + ], + "source": "24-25 二年级上·内蒙古巴彦淖尔·期末" + }, + { + "id": "30", + "unit": "第六单元100以内的加法和减法1", + "question_type": "填空题", + "difficulty": 0.65, + "question": "一本故事书 28 元,乐乐积攒的钱买这本书还差 9 元,乐乐积攒了( )元。", + "options": [], + "answer": "19", + "solution": "【分析】根据题意,用故事书的价格减去 9 元即可求出乐乐已经攒了多少钱.\n【详解】 28 - 9 = 19 (元),一本故事书 28 元,乐乐积攒的钱买这本书还差 9 元,乐乐积攒了 19 元。", + "knowledge_points": [ + "一位数与两位数的退位减法" + ], + "source": "24-25 二年级上·河南郑州·期中" + }, + { + "id": "31", + "unit": "第六单元100以内的加法和减法1", + "question_type": "填空题", + "difficulty": 0.85, + "question": "口算 40 + 25 时,可以先算 40 + 20 = 60,再算( )。", + "options": [], + "answer": "60 + 5 = 65", + "solution": "【分析】口算 40 + 25 时,可以把 25 分成 20 和 5,先算两个整十数的和: 40 + 20 = 60,再算 60 + 5 = 65 .\n【详解】口算 40 + 25 时,可以先算 40 + 20 = 60,再算 60 + 5 = 65 。", + "knowledge_points": [ + "两位数与整十数的加法" + ], + "source": "24-25 三年级上·湖北襄阳·期中" + }, + { + "id": "32", + "unit": "第六单元100以内的加法和减法1", + "question_type": "填空题", + "difficulty": 0.65, + "question": "一个数比 27 大 20,这个数是( ),比这个数小5的数是( )。", + "options": [], + "answer": "47;42", + "solution": "【分析】求比一个数大多少的数用加法计算;求比一个数小多少的数用减法计算.\n【详解】 27 + 20 = 47;47 - 5 = 42;一个数比 27 大 20,这个数是 47,比这个数小 5 的数是 42。", + "knowledge_points": [ + "两位数与整十数的加法", + "两位数与一位数的减法(不退位)" + ], + "source": "24-25 二年级上·河南三门峡·期中" + }, + { + "id": "33", + "unit": "第六单元100以内的加法和减法1", + "question_type": "填空题", + "difficulty": 0.65, + "question": "比 84 多 7 的数是( );比 23 少 6 的数是( )。", + "options": [], + "answer": "91;17", + "solution": "【分析】求比一个数多几的数是多少,用这个数加多的数计算;求比一个数少几的数是多少,用这个数减少的数计算.\n【详解】 84 + 7 = 91;23 - 6 = 17;比 84 多 7 的数是 91;比 23 少 6 的数是 17 。", + "knowledge_points": [ + "一位数与两位数的进位加法", + "一位数与两位数的退位减法" + ], + "source": "24-25 二年级上·贵州六盘水·期中" + }, + { + "id": "34", + "unit": "第六单元100以内的加法和减法1", + "question_type": "填空题", + "difficulty": 0.65, + "question": "比 75 少 8 的数是( ), ( )比 56 多 9。", + "options": [], + "answer": "67;65", + "solution": "【分析】求比一个数少几的数是多少,用这个数减少的数计算;求比一个数多几的数是多少,用这个数加多的数计算.\n【详解】 75 - 8 = 67;56 + 9 = 65;比 75 少 8 的数是 67, 65 比 56 多 9。", + "knowledge_points": [ + "一位数与两位数的进位加法", + "一位数与两位数的退位减法" + ], + "source": "24-25 二年级上·湖南衡阳·期中" + }, + { + "id": "35", + "unit": "第六单元100以内的加法和减法1", + "question_type": "填空题", + "difficulty": 0.85, + "question": "按规律填数.\n(1)9, 11, 13, 15, ( ), ( ), ( )。 \n(2)34,30,26,22,( ),( ),( )。", + "options": [], + "answer": "17;19;21;18;14;10", + "solution": "【分析】(1)该组规律为:从左到右数字依次加 2。(2) 该组规律为:从左到右数字依次减 4 .\n【详解】 (1) 15 + 2 = 17;17 + 2 = 19;19 + 2 = 21填数如下:9,11,13,15,(17),(19),(21)。(2) 22 - 4 = 18;18 - 4 = 14;14 - 4 = 10则填数如下:34,30,26,22,18;14;10。", + "knowledge_points": [ + "一位数与两位数的进位加法", + "一位数与两位数的退位减法" + ], + "source": "24-25 二年级上·河南郑州·期中" + }, + { + "id": "36", + "unit": "第六单元100以内的加法和减法1", + "question_type": "填空题", + "difficulty": 0.65, + "question": "如果 4 □ +7 是一道进位加法,方框里最小可以填( ), 如果 3 □ -7 是一道退位减法,方框里最大可以填( )。", + "options": [], + "answer": "3;6", + "solution": "【分析】加法计算时,相同数位对齐,从个位算起,个位若相加满十向十位进1;减法计算时,相同数位对齐,从个位算起,个位若不够减则从十位退1作十进行计算。4□+7要为进位加法,则个位的和最小为10;3□-7要为退位减法,则个位应为小于7的数,最大的是比7小1的数.\n【详解】4□+7=10,即10-7=3;7-1=6;如果4□+7是一道进位加法,方框里最小可以填3,如果3□-7是一道退位减法,方框里最大可以填6。", + "knowledge_points": [ + "一位数与两位数的进位加法", + "一位数与两位数的退位减法" + ], + "source": "22-23 二年级上·浙江绍兴·期中" + }, + { + "id": "37", + "unit": "第六单元100以内的加法和减法1", + "question_type": "填空题", + "difficulty": 0.85, + "question": "比 57 多 30 的数是( )。", + "options": [], + "answer": "87", + "solution": "【分析】求比一个数多几的数是多少,用这个数加多的数计算.\n【详解】 57 + 30 = 87;比57多30的数是87。", + "knowledge_points": [ + "两位数与整十数的加法" + ], + "source": "24-25 二年级上·陕西西安·期中" + }, + { + "id": "38", + "unit": "第六单元100以内的加法和减法1", + "question_type": "填空题", + "difficulty": 0.85, + "question": "比 50 少 6 的数是( ), 50 比一个数少 6,这个数是( )。", + "options": [], + "answer": "44,56", + "solution": "【分析】求比一个数少几的数是多少,用减法计算;50比一个数少6,也就是这个数比50多6,求比一个数多\n几的数是多少,用加法计算.\n【详解】 50 - 6 = 44;50 + 6 = 56;所以比 50 少 6 的数是 44, 50 比一个数少 6,这个数是 56。", + "knowledge_points": [ + "整十数加,减一位数", + "一位数与两位数的退位减法" + ], + "source": "24-25 二年级上·云南红河·期中" + }, + { + "id": "39", + "unit": "第六单元100以内的加法和减法1", + "question_type": "填空题", + "difficulty": 0.85, + "question": "20 比 63 少( ),比 63 多 20 的数是( )。", + "options": [], + "answer": "43;83", + "solution": "【分析】求一个数比另一个数少多少,用减法计算;求比一个数多几的数是多少,用加法计算.\n【详解】 63 - 20 = 43;63 + 20 = 83;所以 20 比 63 少 43,比 63 多 20 的数是 83。", + "knowledge_points": [ + "两位数与整十数的加法", + "两位数与整十数的减法" + ], + "source": "23-24 二年级上·广东珠海·期中" + }, + { + "id": "40", + "unit": "第六单元100以内的加法和减法1", + "question_type": "填空题", + "difficulty": 0.85, + "question": "典典买1双鞋子,要付56元,他只有40元,还差( )元。", + "options": [], + "answer": "16", + "solution": "【分析】用这双鞋子的钱数减去典典现有的钱数,即可计算出还差多少元.\n【详解】 56 - 40 = 16 (元),还差 16 元。", + "knowledge_points": [ + "两位数与整十数的减法" + ], + "source": "23-24二年级上·甘肃武威·期中" + }, + { + "id": "41", + "unit": "第六单元100以内的加法和减法1", + "question_type": "填空题", + "difficulty": 0.85, + "question": "有56人来参加会议,会议室里有50把椅子,还需要( )把椅子。", + "options": [], + "answer": "6", + "solution": "【分析】用参加会议的总人数减去已有的椅子数量,求出差,就是还需要的椅子数量.\n【详解】 56 - 50 = 6 (把),即,有 56 人来参加会议,会议室里有 50 把椅子,还需要 6 把椅子。", + "knowledge_points": [ + "两位数与整十数的减法" + ], + "source": "23-24一年级下·江西吉安·期末" + }, + { + "id": "42", + "unit": "第六单元100以内的加法和减法1", + "question_type": "填空题", + "difficulty": 0.65, + "question": "\"双十一\"期间,乐乐的妈妈准备在网上给他买一套彩绘读本。店家推出了\"每套读本优惠8元\"的活动,这样原来56元一套的彩绘读本现在只需要( )元。", + "options": [], + "answer": "48", + "solution": "【分析】根据减法的意义,用彩绘读本原来的价钱减去 8 元即可求出彩绘读本现在的价钱,据此解答即可.\n【详解】 56 - 8 = 48 (元),所以店家推出了\"每套读本优惠8元\"的活动,这样原来,56元一套的彩绘读本现在只需要48元。", + "knowledge_points": [ + "一位数与两位数的退位减法", + "促销问题" + ], + "source": "23-24 二年级上·湖南湘西·期末" + }, + { + "id": "43", + "unit": "第六单元100以内的加法和减法1", + "question_type": "填空题", + "difficulty": 0.85, + "question": "妹妹有 9 块巧克力,姐姐有 27 块巧克力,姐姐给妹妹( )块,两人就同样多了。", + "options": [], + "answer": "9", + "solution": "【分析】先用姐姐的巧克力数量减去妹妹的巧克力数量,求出差,再把差平均分成 2 份,其中的一份给妹妹,两人的巧克力数量就会同样多.\n【详解】 27 - 9 = 18 (块),18 块 = 9 块 +9 块,也就是把 18 块巧克力平均分成 2 份,每份是 9 块,即,妹妹有 9 块巧克力,姐姐有 27 块巧克力,姐姐给妹妹 9 块,两人就同样多了。", + "knowledge_points": [ + "9加几的进位加法", + "一位数与两位数的退位减法" + ], + "source": "23-24 二年级上·湖南邵阳·期中" + }, + { + "id": "44", + "unit": "第六单元100以内的加法和减法1", + "question_type": "填空题", + "difficulty": 0.65, + "question": "比 56 多 7 的数是( );38 比( )多 9。", + "options": [], + "answer": "63,29", + "solution": "【分析】求比一个数多几的数是多少,用加法计算;已知一个数比另一个数多几,求另一个数是多少,用减法计算.\n【详解】 56 + 7 = 63;38 - 9 = 29;所以比 56 多 7 的数是 63;38 比 29 多 9 。", + "knowledge_points": [ + "一位数与两位数的进位加法", + "一位数与两位数的退位减法" + ], + "source": "23-24 二年级上·江西九江·期中" + }, + { + "id": "45", + "unit": "第六单元100以内的加法和减法1", + "question_type": "填空题", + "difficulty": 0.85, + "question": "二年级同学去看电影,买了45张票,后来退了8张,有( )位同学看了电影。", + "options": [], + "answer": "37", + "solution": "【分析】用一开始买的张数减后来退的张数就是用了的张数,也就是看电影的人数.\n【详解】 45 - 8 = 37 (位);有 37 位同学看了电影。", + "knowledge_points": [ + "一位数与两位数的退位减法" + ], + "source": "22-23 二年级上·浙江温州·期中" + }, + { + "id": "46", + "unit": "第六单元100以内的加法和减法1", + "question_type": "填空题", + "difficulty": 0.85, + "question": "比 19 少 5 的数是( ), 30 比一个数少 5,这个数是( )。", + "options": [], + "answer": "14;35", + "solution": "【分析】求比 19 少 5 的数是多少,用 19 减去 5 即可得出答案;求比 30 多 5 的数是多少,用 30 加上 5 即可得出答案.\n【详解】据分析可知: 19 - 5 = 14 。 30 + 5 = 35;比 19 少 5 的数是 14, 30 比一个数少 5,这个数是 35.\n[点睛]考查两位数与一位数之间的计算和运算关系。", + "knowledge_points": [ + "两位数与一位数的加法(不进位)", + "两位数与一位数的减法(不退位)" + ], + "source": "23-24 二年级上·河南南阳·期中" + }, + { + "id": "47", + "unit": "第六单元100以内的加法和减法1", + "question_type": "填空题", + "difficulty": 0.65, + "question": "比最大的两位数少20 的数是( )。比 45 多 7 的数是( )。", + "options": [], + "answer": "79;52", + "solution": "【分析】最大的两位数是 99,求比最大的两位数少 20 的数是多少,用 99 减 20 进行计算;求比 45 多 7 的数是多少,用 45 加 7 进行计算.\n【详解】 99 - 20 = 79;45 + 7 = 52;所以比最大的两位数少 20 的数是 79。比 45 多 7 的数是 52。", + "knowledge_points": [ + "100 以内数的比大小", + "100 以内数的组成", + "两位数与整十数的减法", + "一位数与两位数的进位加法" + ], + "source": "23-24 二年级上·河南驻马店·期中" + }, + { + "id": "48", + "unit": "第六单元100以内的加法和减法1", + "question_type": "填空题", + "difficulty": 0.65, + "question": "比 51 少 20 的数是( ), 比 36 多 40 的数是( )。", + "options": [], + "answer": "31;76", + "solution": "【分析】求比 51 少 20 的数是多少,用减法计算.\n求比 36 多 40 的数是多少,用加法计算.\n【详解】 51 - 20 = 31;36 + 40 = 76;比51少20的数是31,比36多40的数是76。", + "knowledge_points": [ + "两位数与整十数的加法", + "两位数与整十数的减法" + ], + "source": "23-24 二年级上·河南濮阳·期中" + }, + { + "id": "49", + "unit": "第六单元100以内的加法和减法1", + "question_type": "填空题", + "difficulty": 0.65, + "question": "最大的两位数减去最小的两位数,差是( )。", + "options": [], + "answer": "89", + "solution": "【分析】最大的两位数是99,最小的两位数是10,用99减10即可求解.\n【详解】99-10=89;最大的两位数减去最小的两位数,差是89。", + "knowledge_points": [ + "100以内数的比大小", + "两位数与整十数的减法" + ], + "source": "23-24 二年级上·山东临沂·期中" + }, + { + "id": "50", + "unit": "第六单元100以内的加法和减法1", + "question_type": "填空题", + "difficulty": 0.65, + "question": "如果 5 □ + 6 是一道进位加法,方框里最小填( );如果 7 □ - 8 是一道退位减法,方框里最大填( )。", + "options": [], + "answer": "4;7", + "solution": "【分析】根据百以内进位加法的计算方法,想要使5□+6是一道进位加法题,则6与□里的数字之和要大于或等于10,据此解答;根据百以内退位减法的计算方法,想要使7□-8是一道退位减法题,则□必须小于8,据此解答.\n【详解】10-6=4;所以如果5□+6是一道进位加法,方框里最小填4;如果7□-8是一道退位减法,方框里最大填7。", + "knowledge_points": [ + "一位数与两位数的进位加法", + "一位数与两位数的退位减法" + ], + "source": "23-24 二年级上·河北邢台·期中" + }, + { + "id": "51", + "unit": "第六单元100以内的加法和减法1", + "question_type": "填空题", + "difficulty": 0.85, + "question": "比 74 少 8 的数是( );( )比 42 多 9。", + "options": [], + "answer": "66;51", + "solution": "【分析】要求比74少8的数是多少,根据减法的意义,用74-8进行解答即可。要求谁比42多9,即求比42多9的数是多少,根据加法的意义,用42+9进行解答即可.\n【详解】74-8=66,所以比74少8的数是66。42+9=51,所以51比42多9。", + "knowledge_points": [ + "一位数与两位数的进位加法", + "一位数与两位数的退位减法" + ], + "source": "23-24 二年级上·河南郑州·期中" + }, + { + "id": "52", + "unit": "第六单元100以内的加法和减法1", + "question_type": "填空题", + "difficulty": 0.65, + "question": "小红有 23 本童话书,比欢欢少 8 本,欢欢有( )本童话书。", + "options": [], + "answer": "31", + "solution": "【分析】用小红的数量加小红比欢欢少的数量即可求出欢欢有多少本童话书.\n【详解】 23 + 8 = 31 (本);欢欢有31本童话书。", + "knowledge_points": [ + "一位数与两位数的进位加法" + ], + "source": "23-24 二年级上·陕西安康·期中" + }, + { + "id": "53", + "unit": "第六单元100以内的加法和减法1", + "question_type": "填空题", + "difficulty": 0.85, + "question": "最大的两位数比最小的两位数多( ), 最大的两位数比最大的一位数多( )。", + "options": [], + "answer": "89;90", + "solution": "【分析】最大的两位数是99,最小的两位数是10,最大的一位数是9。求一个数比另一个数多几,用这个数减另一个数计算.\n【详解】99-10=89;99-9=90。最大的两位数比最小的两位数多89,最大的两位数比最大的一位数多90。", + "knowledge_points": [ + "两位数与一位数的减法(不退位)", + "两位数与整十数的减法" + ], + "source": "22-23 二年级上·浙江·期中" + }, + { + "id": "54", + "unit": "第六单元100以内的加法和减法1", + "question_type": "填空题", + "difficulty": 0.65, + "question": "中秋节商店促销,每个商品优惠9元出售。现在每个书包( )元,每个闹钟( )元.\n![](images/7fcda840bccb76cabdf9ee1ceaf2dc388aa200582e4b15d1a394eb68a81f0e3b.jpg) \n56元\n![](images/116b150801fe54a6d601d8c3b745f0046cd55220a997608682357997a32a9b3a.jpg) \n35元", + "options": [], + "answer": "47;26", + "solution": "【分析】用物品原来的价钱减优惠的价钱即可求出现在的价钱.\n【详解】56-9=47(元);35-9=26(元);现在每个书包47元,每个闹钟26元。", + "knowledge_points": [ + "图文问题", + "一位数与两位数的退位减法", + "促销问题" + ], + "source": "23-24 二年级上·山东济宁·期中" + }, + { + "id": "55", + "unit": "第六单元100以内的加法和减法1", + "question_type": "填空题", + "difficulty": 0.85, + "question": "小芳拍了 40 下球,小军拍的比小芳少,小强拍的比小芳多。小军最多拍了( )下,小强最少拍了( )下。", + "options": [], + "answer": "39;41", + "solution": "【分析】小军拍得比小芳少,最多比小芳少1下,小军最多拍了40-1=39(下);小强拍得比小芳多,最少比小芳多1下,小强最少拍了40+1=41(下).\n【详解】40-1=39(下);40+1=41(下)。小军最多拍了39下,小强最少拍了41下。", + "knowledge_points": [ + "整十数加,减一位数" + ], + "source": "23-24 二年级上·河南洛阳·期中" + }, + { + "id": "56", + "unit": "第六单元100以内的加法和减法1", + "question_type": "填空题", + "difficulty": 0.65, + "question": "一辆摇摆车 46 元,比一辆滑板车便宜 7 元,一辆滑板车( )元。", + "options": [], + "answer": "53", + "solution": "【分析】已知一个数比另一个数少几,求另一个数,用这个数加少的数计算.\n【详解】 46 + 7 = 53 (元);一辆摇摆车 46 元,比一辆滑板车便宜 7 元,一辆滑板车 53 元。", + "knowledge_points": [ + "一位数与两位数的进位加法" + ], + "source": "23-24 二年级上·广东江门·期中" + }, + { + "id": "57", + "unit": "第六单元100以内的加法和减法1", + "question_type": "填空题", + "difficulty": 0.85, + "question": "在括号里填上\">\" \"<\"或\"=\" .\n53-9( )45\n63( )66-30\n4元( )35角\n34-7( )28\n38( )74-40\n5元7角( )57角", + "options": [], + "answer": "<;>;<;>;=", + "solution": "【分析】先计算出每个算式的结果或先统一单位,然后比较大小即可。1元=10角.\n【详解】53-9=44,故53-9<45;66-30=36,故63>66-30;4元=40角,故4元>35角;34-7=27,故34-7<28;74-40=34,故38>74-40;5元7角=57角。", + "knowledge_points": [ + "100 以内数的比大小", + "两位数与整十数的减法", + "一位数与两位数的退位减法", + "元,角,分的认识及换算" + ], + "source": "23-24一年级下·湖南长沙·期末" + }, + { + "id": "58", + "unit": "第六单元100以内的加法和减法1", + "question_type": "填空题", + "difficulty": 0.85, + "question": "在括号里填上\">\" \"<\"或\"=\" .\n66( )45\n16-9( )8\n8角( )7角9分\n45( )36+9\n30+52( )82-30\n53角( )3元5角", + "options": [], + "answer": ">;<;>;=;>;>", + "solution": "【分析】先计算出每个算式的结果或先统一单位,然后比较大小即可。1角=10分,1元=10角.\n【详解】66>45;16-9=7,故16-9<8;8角=80分,7角9分=79分,故8角>7角9分;36+9=45,即45=36+9;30+52=82,82-30=52,故30+52>82-30;3元5角=35角,故53角>3元5角。", + "knowledge_points": [ + "100 以内数的比大小", + "两位数与整十数的减法", + "一位数与两位数的进位加法", + "元,角,分的认识及换算" + ], + "source": "23-24 一年级下·河南濮阳·期末" + }, + { + "id": "59", + "unit": "第六单元100以内的加法和减法1", + "question_type": "判断题", + "difficulty": 0.85, + "question": "有31个苹果, 10个装一兜,能装满4兜。( )", + "options": [], + "answer": "×", + "solution": "【分析】根据题意,31个苹果每10个装一兜,可用减法计算,用总数减去每兜的个数,一直减到0,减去了几个10,就是可以装几兜.\n【详解】 31 - 10 = 21 (个),21 - 10 = 11(个),11 - 10 = 1 (个),一共装满了 3 兜,还剩余 1 个,不够 4 兜。故答案为: ×", + "knowledge_points": [ + "两位数与整十数的减法" + ], + "source": "24-25一年级下·河北·期中" + }, + { + "id": "60", + "unit": "第六单元100以内的加法和减法1", + "question_type": "判断题", + "difficulty": 0.85, + "question": "最小的两位数与最大的两位数相差 89。( )", + "options": [], + "answer": "√", + "solution": "【分析】根据题意可知:最小的两位数是 10,最大的两位数是 99,求两者相差多少,用大的数减去小的数即可.\n【详解】最小的两位数是 10,最大的两位数是 99.99 - 10 = 89;则最小的两位数与最大的两位数相差 89,原题说法正确。故答案为: √", + "knowledge_points": [ + "两位数与整十数的减法" + ], + "source": "13-14 一年级下·全国·课后作业" + }, + { + "id": "61", + "unit": "第六单元100以内的加法和减法1", + "question_type": "判断题", + "difficulty": 0.85, + "question": "最大的两位数和最小的两位数相差 10。( )", + "options": [], + "answer": "×", + "solution": "【分析】一个两位数,从右往左依次为个位,十位。最大的两位数也就是十位和个位都是9,是99;最小的两位数,十位是1,个位是0,是10,相减即可求出相差多少.\n【详解】99-10=89;最大的两位数和最小的两位数相差89,原题说法错误。故答案为:×", + "knowledge_points": [ + "100以内数的组成", + "两位数与整十数的减法" + ], + "source": "23-24 二年级上·湖南湘西·期末" + }, + { + "id": "62", + "unit": "第六单元100以内的加法和减法1", + "question_type": "判断题", + "difficulty": 0.85, + "question": "最大的两位数减去最小的两位数,差是 80 。()", + "options": [], + "answer": "×", + "solution": "【分析】根据对数的认识可知,最大的两位数是 99,最小的两位数是 10,相减即可求出差.\n【详解】 99 - 10 = 89;最大的两位数减去最小的两位数,差是 89,原题说法错误。故答案为: ×", + "knowledge_points": [ + "两位数与整十数的减法" + ], + "source": "24-25 二年级上·湖南衡阳·期中" + }, + { + "id": "63", + "unit": "第六单元100以内的加法和减法1", + "question_type": "判断题", + "difficulty": 0.65, + "question": "最大的两位数比最大的一位数多 9。( )", + "options": [], + "answer": "×", + "solution": "【分析】最大的两位数是 99,最大的一位数是 9,根据减法的意义,用最大的两位数减去最大的一位数求出差,再与 9 比较即可.\n【详解】最大的两位数是99,最大的一位数是 9.99 - 9 = 90;所以最大的两位数比最大的一位数多 90,原题说法错误。故答案为: ×", + "knowledge_points": [ + "100以内数的比大小", + "100以内数的组成", + "两位数与一位数的减法(不退位)" + ], + "source": "24-25 二年级上·内蒙古鄂尔多斯·期中" + }, + { + "id": "64", + "unit": "第六单元100以内的加法和减法1", + "question_type": "判断题", + "difficulty": 0.65, + "question": "两位数减一位数的差一定还是两位数。( )", + "options": [], + "answer": "×", + "solution": "【分析】两位数减一位数,从个位开始作差,个位不够减就向十位借1当十;两位数减一位数,结果不一定是两位数,据此可得出答案.\n【详解】两位数减一位数的差不一定还是两位数。如:10-9 = 1,是两位数减一位数,差是一位数。原题说法错误。故答案为: ×", + "knowledge_points": [ + "10 的加减法", + "两位数与一位数的减法(不退位)", + "一位数与两位数的退位减法" + ], + "source": "23-24 二年级上·河北邢台·期中" + }, + { + "id": "65", + "unit": "第六单元100以内的加法和减法1", + "question_type": "判断题", + "difficulty": 0.65, + "question": "超市店庆大促销活动,每个足球优惠 7 元,原价 56 元的足球,现价 51 元。( )", + "options": [], + "answer": "×", + "solution": "【分析】根据减法的意义,用足球的原价减去 7 元,即可计算出足球的现价,再与 51 元比较即可.\n【详解】56 - 7 = 49 (元);49 < 51;所以超市店庆大促销活动,每个足球优惠7元,原价56元的足球,现价49元。原题干说法错误。", + "knowledge_points": [ + "一位数与两位数的退位减法", + "促销问题" + ], + "source": "23-24 二年级上·河南驻马店·期中" + }, + { + "id": "66", + "unit": "第六单元100以内的加法和减法1", + "question_type": "计算题", + "difficulty": 0.85, + "question": "直接写得数.\n12 - 7 =()41 + 5 =()86 - 20 =()7 + 33 + 20 =()88 + 6 =()30 - 3 =()68 - 29 =()23 + 8 - 10 =()", + "options": [], + "answer": "5;46;66;60;94;27;39;21", + "solution": "【分析】本题考查 100 以内数的加减法计算,涵盖了 20 以内退位减法,两位数加减一位数,两位数加减整十数,两位数减两位数的退位减法,以及加减混合运算,需要掌握不同类型加减法的计算法则,准确计算出结果.\n【详解】12 - 7 退位减法,结果是 5;41 + 5 个位相加,结果是 46;86 - 20 十位相减,结果是 66;7 + 33 + 20 从左往右算,7+33=40,40+20=60;88 + 6 个位满十进一,结果是 94;30 - 3 退位减法,结果是 27;68 - 29 个位不够减借位,结果是 39;23 + 8 - 10 从左往右算,23+8=31,31-10=21", + "knowledge_points": [ + "两位数与两位数的进位加法", + "两位数与两位数的退位减法", + "100以内数的加减混合运算" + ], + "source": "24-25 一年级下·福建莆田·期末" + }, + { + "id": "67", + "unit": "第六单元100以内的加法和减法1", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式计算.\n![](images/0fa0ef4362b7a41390313aaf6e250aee4cfa4c3739cb8bf196b6f4daedbc34e4.jpg)\n□ ○ □ = □ (个)", + "options": [], + "answer": "15+5=20", + "solution": "【分析】把左边的苹果数量与右边的数量加起来,求出和,就是一共的苹果数量.\n【详解】由题意分析得;15 + 5 = 20 (个)", + "knowledge_points": [ + "图文问题", + "一位数与两位数的进位加法" + ], + "source": "2024一年级上·全国·专题练习" + }, + { + "id": "68", + "unit": "第六单元100以内的加法和减法1", + "question_type": "计算题", + "difficulty": 0.85, + "question": "直接写得数.\n5 + 31 =() 68 - 3 =()", + "options": [], + "answer": "36;65", + "solution": "【分析】本题考查两位数与一位数的直接加减运算。第一题是加法,将个位与个位相加,十位数字保持不变;第二题是减法,将个位与个位相减,十位数字保持不变。这两题都不涉及进位或退位.\n【详解】5 + 31:把31拆成30和1,先算5+1=6,再算6+30=36。或直接列竖式计算,个位5+1=6,十位0+3=3,合起来是36.68 - 3:把68拆成60和8,先算8-3=5,再算60+5=65。或直接列竖式计算,个位8-3=5,十位6保持不变,结果是65。", + "knowledge_points": [ + "两位数与一位数的加法(不进位)", + "两位数与一位数的减法(不退位)" + ], + "source": "2024 二年级上·全国·专题练习" + }, + { + "id": "69", + "unit": "第六单元100以内的加法和减法1", + "question_type": "计算题", + "difficulty": 0.85, + "question": "直接写出得数.\n63 + 5 =() 20 + 7 = () 58 - 8 =() 72 - 40 =()15 - 9 =() 36 + 8 =() 20 + 30 =() 30 - 5 =()", + "options": [], + "answer": "68;27;50;32;6;44;50;25", + "solution": "【分析】本题考查100以内数的加减法口算,涵盖了不进位加法,进位加法,不退位减法和退位减法等多种类型。计算时需注意:加法要看清是否需要进位,减法要看清是否需要退位。对于整十数加减,可以直接计算十位上的数字.\n【详解】计算63加5,个位相加得8,十位不变,结果为68;20加7直接相加得27;58减8,个位相减为0,十位不变,结果为50;72减40,十位相减得3,个位不变,结果为32;15减9,个位不够减需从十位借1,结果为6;36加8,个位相加满十向十位进1,结果为44;20加30,整十数相加结果为50;30减5,个位不够减需从十位借1,结果为25。", + "knowledge_points": [ + "十几减 9 的退位减法", + "两位数与整十数的减法", + "一位数与两位数的进位加法", + "一位数与两位数的退位减法" + ], + "source": "23-24 二年级上·广东珠海·期中" + }, + { + "id": "70", + "unit": "第六单元100以内的加法和减法1", + "question_type": "计算题", + "difficulty": 0.85, + "question": "直接写出得数.\n65 - 30 =() 42 + 8 =() 60 - 9 =() 27 + 30 =()\n40 + 15 =() 98 - 80 = ()36 + 6 = 85 - 50 =()", + "options": [], + "answer": "35;50;51;57;55;18;42;35", + "solution": "【分析】本题考查100以内数的加减法口算,包括两位数与整十数的加减,一位数与两位数的进位加法与退位减法。计算时需注意:加法要判断是否进位,减法要判断是否退位;与整十数相加减时,可先计算十位上的数字.\n【详解】 65减30,十位6减3得3,个位5不变,结果为35;42加8,个位2加8得10,向十位进1,结果为50;60减9,个位0减9不够,从十位退1作10,结果为51;27加30,十位2加3得5,个位7不变,结果为57;40加15,十位4加1得5,个位0加5得5,结果为55;98减80,十位9减8得1,个位8减0得8,结果为18;36加6,个位6加6得12,向十位进1,结果为42;85减50,十位8减5得3,个位5不变,结果为35。", + "knowledge_points": [ + "两位数与整十数的加法", + "两位数与整十数的减法", + "一位数与两位数的进位加法", + "一位数与两位数的退位减法" + ], + "source": "24-25 二年级上·青海果洛·期中" + }, + { + "id": "71", + "unit": "第六单元100以内的加法和减法1", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式计算.\n![](images/c1355262b78e16c5363c60c13e26fc36a082f9d7a98b8e82f259c40fae617b80.jpg)\n□ ○ □ = □ (朵)", + "options": [], + "answer": "18+5=23", + "solution": "【分析】根据加法的意义,用红花的朵数加上黄花比红花多的朵数即可求出黄花的朵数,据此解答即可.\n【详解】 18 + 5 = 23 (朵)所以黄花有 23 朵。", + "knowledge_points": [ + "图文问题", + "一位数与两位数的进位加法" + ], + "source": "23-24 二年级上·河北邯郸·期中" + }, + { + "id": "72", + "unit": "第六单元100以内的加法和减法1", + "question_type": "计算题", + "difficulty": 0.85, + "question": "我加上 8 就是 52,我是多少。", + "options": [], + "answer": "44", + "solution": "【分析】加数加加数 = 和,和 - 加数 = 另一个加数。根据加减法各部分间的关系,一个数加上 8 是 52,用 52 减 8 即可求出这个数.\n【详解】 52 - 8 = 44", + "knowledge_points": [ + "一位数与两位数的退位减法", + "加,减法的意义", + "和各部分间的关系" + ], + "source": "23-24 二年级上·河北邯郸·期中" + }, + { + "id": "73", + "unit": "第六单元100以内的加法和减法1", + "question_type": "计算题", + "difficulty": 0.85, + "question": "口算.\n18 - 7 = ()\n8 + 20 = ()\n48 - 9 = ()\n56 - (3 + 27) =()\n65 - 6 = ()\n15 - 9 = ()\n28 + 4 = ()\n20 - (16 - 9) =()", + "options": [], + "answer": "11;28;39;26;59;6;32;13", + "solution": "【分析】本题考查20和100以内数的加减法口算,包括简单的不退位减法,进位加法,退位减法以及带小括号的两步混合运算。计算时需注意运算顺序,有括号的要先算括号里的;减法要判断是否退位,加法要判断是否进位.\n【详解】 18减7直接口算得11;8加20得28;48减9,个位8减9不够从十位借1,得39;56减括号里3加27的和,先算括号得30,再用56减30得26;65减6,个位5减6不够从十位借1,得59;15减9,个位5减9不够从十位借1,得6;28加4,个位满十向十位进1,得32;20减括号里16减9的差,先算括号得7,再用20减7得13。", + "knowledge_points": [ + "不退位减法(20以内)", + "一位数与两位数的进位加法", + "一位数与两位数的退位减法", + "带有小括号的混合运算" + ], + "source": "23-24 一年级下·湖南长沙·期末" + }, + { + "id": "74", + "unit": "第六单元100以内的加法和减法1", + "question_type": "解答题", + "difficulty": 0.65, + "question": "小明和小芳一起跳绳,小明跳了 72 下,小芳跳了 50 下。小芳再跳多少下就和小明跳的一样多。", + "options": [], + "answer": "22下", + "solution": "【分析】根据题意可知,小明跳的下数减去小芳跳的下数,等于小芳再跳多少下就和小明跳的一样多,据此解答.\n【详解】根据分析可得:72 - 50 = 22 (下);答:小芳再跳 22 下就和小明跳的一样多。", + "knowledge_points": [ + "两位数与整十数的减法" + ], + "source": "24-25一年级下·山东济南·期中" + }, + { + "id": "75", + "unit": "第六单元100以内的加法和减法1", + "question_type": "解答题", + "difficulty": 0.4, + "question": "红红写作业,写语文作业用去规定时间的一半,写数学作业用去剩下时间的一半,最后5分钟完成了朗读作业,红红完成全部作业一共要多少分钟。", + "options": [], + "answer": "20分钟", + "solution": "【分析】写数学作业用去剩下时间的一半,最后 5 分钟完成了朗读作业,所以写数学作业也用去 5 分钟。用倒推的方法先求出写语文作业之后剩下的时间,写语文作业用去规定时间的一半,所以写语文作业之后剩下的时间和写语文作业的时间一样,相加即可求解.\n【详解】 5 + 5 = 10 (分钟)10 + 10 = 20 (分钟)答:红红完成全部作业一共要 20 分钟。", + "knowledge_points": [ + "倒推问题" + ], + "source": "23-24 二年级上·浙江杭州·期末" + }, + { + "id": "76", + "unit": "第六单元100以内的加法和减法1", + "question_type": "解答题", + "difficulty": 0.65, + "question": "一本故事书有 60 页,第一天看了 24 页,第二天比第一天少看了 4 页,第二天看了多少页。 两天共看了多少页。", + "options": [], + "answer": "20页;44页", + "solution": "【分析】用第一天看的页数减去4即可求出第二天看了多少页;把第一天和第二天看的页数相加即可求出两天共看了多少页.\n【详解】24-4=20(页);24+20=44(页)。答:第二天看了20页;两天共看了44页。", + "knowledge_points": [ + "两位数与整十数的加法", + "两位数与一位数的减法(不退位)" + ], + "source": "23-24 二年级上·福建福州·期末" + }, + { + "id": "77", + "unit": "第六单元100以内的加法和减法1", + "question_type": "解答题", + "difficulty": 0.85, + "question": "小兰有多少张邮票。\n\n![](images/55765314b1884e9f442db472eaf3410e21dd89e300ceb14665bd11d1f7d6e351.jpg)\n\n小强:我有28张邮票.\n\n![](images/4b27bfc0c29d63b32976f32880b5ca7de8337c821ad22a3bef4b011a67fd0aa1.jpg)\n\n小兰:我比你多6张。", + "options": [], + "answer": "34张", + "solution": "【分析】小强有28张邮票,小兰比小强多6张,求小兰有几张邮票,用加法列式计算.\n【详解】28+6=34(张)。答:小兰有34张邮票。", + "knowledge_points": [ + "图文问题", + "一位数与两位数的进位加法" + ], + "source": "23-24 二年级上·福建福州·期末" + }, + { + "id": "78", + "unit": "第六单元100以内的加法和减法1", + "question_type": "解答题", + "difficulty": 0.85, + "question": "买早餐.\n\n![](images/134248.png)", + "options": [], + "answer": "12+7=19;15-4=11", + "solution": "【分析】根据题意可知:求男生一共花的钱数。用男生吃面条的单价加牛奶的单价即可。求女生还剩多少钱。用女生有的钱数减去果汁的单价即可.\n【详解】 12 + 7 = 19 (元)答:一共花了 19 元。15 - 4 = 11(元);答:还剩 11 元。", + "knowledge_points": [ + "不退位减法(20以内)", + "7,6加几的进位加法" + ], + "source": "2024一年级上·全国·专题练习" + }, + { + "id": "79", + "unit": "第六单元100以内的加法和减法1", + "question_type": "解答题", + "difficulty": 0.85, + "question": "学校买来羽毛球 40 个,比乒乓球少 12 个,乒乓球的个数比篮球多 20 个。乒乓球有多少个。 篮球有多少个。", + "options": [], + "answer": "52个;32个", + "solution": "【分析】根据题意可知:求比一个数比另一个数少多少,求另一个数,用一个数加上少的数量即可;,根据一个数比另一个数多几,求另一个数,用一个数减去比另一个数多的数.\n【详解】 40 + 12 = 52 (个);52 - 20 = 32 (个);答:乒乓球有 52 个,篮球有 32 个。", + "knowledge_points": [ + "两位数与整十数的加法", + "两位数与整十数的减法" + ], + "source": "24-25 二年级上·山东济南·期中" + }, + { + "id": "80", + "unit": "第六单元100以内的加法和减法1", + "question_type": "解答题", + "difficulty": 0.65, + "question": "在北京天安门广场,巨型花篮里的\"红石榴\"格外引人注目。果果家有一棵石榴树,结出大,小两种石榴共56颗。大石榴有30颗,小石榴有多少颗。", + "options": [], + "answer": "26颗", + "solution": "【分析】用结出大,小石榴一共的颗数减大石榴的颗数即可求出小石榴有多少颗.\n【详解】 56 - 30 = 26 (颗);答:小石榴有 26 颗。", + "knowledge_points": [ + "两位数与整十数的减法" + ], + "source": "24-25 二年级上·河南三门峡·期中" + }, + { + "id": "81", + "unit": "第六单元100以内的加法和减法1", + "question_type": "解答题", + "difficulty": 0.85, + "question": "小美用一根彩带做蝴蝶结,用去 70 厘米后,还剩 26 厘米。这根彩带原来长多少。", + "options": [], + "answer": "96厘米", + "solution": "【分析】根据加法的意义,将用去的长度加上还剩的长度即可求出这根彩带的原长,据此解答即可.\n【详解】 70 + 26 = 96 (厘米);答:这根彩带原来长 96 厘米。", + "knowledge_points": [ + "两位数与整十数的加法" + ], + "source": "24-25 二年级上·广东汕头·期中" + }, + { + "id": "82", + "unit": "第六单元100以内的加法和减法1", + "question_type": "解答题", + "difficulty": 0.65, + "question": "上手工课,一班用了 25 张纸,比二班少用 8 张,二班用了多少张。", + "options": [], + "answer": "33张", + "solution": "【分析】用一班用的数量加一班比二班少用的数量即可求出二班用了多少张.\n【详解】 25 + 8 = 33 (张);答:二班用了 33 张。", + "knowledge_points": [ + "一位数与两位数的进位加法" + ], + "source": "24-25 二年级上·云南红河·期中" + }, + { + "id": "83", + "unit": "第六单元100以内的加法和减法1", + "question_type": "解答题", + "difficulty": 0.85, + "question": "东圳水库具有灌溉,防洪,发电,养殖,游览等作用,素有莆田人民的 \"大水缸\"之称。水库正常蓄水位为 81 米,死水位高 50 米,东圳水库正常蓄水位比死水位高多少米。", + "options": [], + "answer": "31米", + "solution": "【分析】用正常蓄水位的高度减死水位高度即可求出东圳水库正常蓄水位比死水位高多少米.\n【详解】 81 - 50 = 31 (米);答:东圳水库正常蓄水位比死水位高 31 米。", + "knowledge_points": [ + "两位数与整十数的减法" + ], + "source": "24-25 二年级上·福建莆田·期中" + }, + { + "id": "84", + "unit": "第六单元100以内的加法和减法1", + "question_type": "解答题", + "difficulty": 0.85, + "question": "一个足球 43 元,乐乐想买一个足球,还差 5 元。乐乐带了多少元。", + "options": [], + "answer": "38元", + "solution": "【分析】根据减法的意义,用一个足球的价钱减去乐乐还差的钱数即可求出乐乐带的钱数,据此解答即可.\n【详解】 43 - 5 = 38 (元);答:乐乐带了 38 元。", + "knowledge_points": [ + "一位数与两位数的退位减法" + ], + "source": "23-24 二年级上·广东珠海·期中" + }, + { + "id": "85", + "unit": "第六单元100以内的加法和减法1", + "question_type": "解答题", + "difficulty": 0.85, + "question": "草地上有 40 只羊,羊的只数比牛多 7 只,牛有多少只。 羊和牛一共有多少只。", + "options": [], + "answer": "33只;73只", + "solution": "【分析】用羊的只数减去 7 只,求出差,即可计算出牛的数量;再用牛的数量加上羊的数量,求出和,即可解答.\n【详解】 40 - 7 = 33 (只)33 + 40 = 73 (只)答:牛有 33 只;羊和牛一共有 73 只。", + "knowledge_points": [ + "两位数与整十数的加法", + "一位数与两位数的退位减法" + ], + "source": "23-24 二年级上·湖北黄石·期中" + }, + { + "id": "86", + "unit": "第六单元100以内的加法和减法1", + "question_type": "解答题", + "difficulty": 0.85, + "question": "下面是李龙家种植果树的情况.\n\n![](images/134703.png)", + "options": [], + "answer": "48棵;31棵", + "solution": "【分析】(1)求苹果树和梨树一共多少棵,就是求两个数的和,用加法列式计算;(2) 求桃树比梨树少多少棵,就是求两个数的差,用减法列式计算;据此解决\n【详解】 (1) 40 + 8 = 48 (棵)答:苹果树和梨树一共 48 棵。(2) 40 - 9 = 31 (棵)答:桃树比梨树少 31 棵。", + "knowledge_points": [ + "整十数加,减一位数", + "一位数与两位数的退位减法" + ], + "source": "23-24 二年级上·贵州黔南·期中" + }, + { + "id": "87", + "unit": "第六单元100以内的加法和减法1", + "question_type": "解答题", + "difficulty": 0.65, + "question": "奶奶家养了白兔 34只,黑兔比白兔多8只,黑兔有多少只。", + "options": [], + "answer": "42只", + "solution": "【分析】用白兔的只数加黑兔比白兔多的只数即可求出黑兔有多少只.\n【详解】 34 + 8 = 42 (只)答:黑兔有 42 只。", + "knowledge_points": [ + "一位数与两位数的进位加法" + ], + "source": "23-24 二年级上·山东临沂·期中" + }, + { + "id": "88", + "unit": "第六单元100以内的加法和减法1", + "question_type": "解答题", + "difficulty": 0.65, + "question": "县运动会即将举行,学校打算为学校足球队的男生女生们准备一套新的服装。已知足球队有女生 21 人,比男生少 9 人,学校足球队有男生多少人。一共要准备多少套服装。", + "options": [], + "answer": "30人;51套", + "solution": "【分析】根据加法的意义,用学校足球队女生的人数加上 9 求出学校足球队男生的人数,每人需要准备 1 套服装,用女生人数加上男生人数求出学校足球队的总人数,也就是需要准备服装的总数量,据此解答即可.\n【详解】 21 + 9 = 30 (人)21 + 30 = 51 (人);51人需要准备51套服装。答:学校足球队有男生30人;一共要准备51套服装。", + "knowledge_points": [ + "两位数与整十数的加法", + "一位数与两位数的进位加法" + ], + "source": "23-24 二年级上·山东日照·期中" + }, + { + "id": "89", + "unit": "第六单元100以内的加法和减法1", + "question_type": "解答题", + "difficulty": 0.65, + "question": "本届运动会,驻马店代表团共派出 1050 名运动员参加,其中青少年竞技组参加项目 18 个,学生组参加项目 6 个。在此次省运会上驻马店代表团参加了多少个项目。", + "options": [], + "answer": "24 个", + "solution": "【分析】把青少年竞技组、学生组参加的项目个数加起来,即可解答.\n【详解】18+6=24(个)。答:在此次省运会上驻马店代表团参加了24个项目。", + "knowledge_points": [ + "一位数与两位数的进位加法" + ], + "source": "23-24 二年级上·河南驻马店·期中" + }, + { + "id": "90", + "unit": "第六单元100以内的加法和减法1", + "question_type": "解答题", + "difficulty": 0.85, + "question": "两只海龟下蛋。第一只下了 86 个蛋,第二只比第一只多下了 9 个。第二只海龟下了多少个蛋。", + "options": [], + "answer": "95个", + "solution": "【分析】求比一个数多几的数是多少,用这个数加多的数计算,即第一只下蛋的数量 + 第二只比第一只多下的数量 = 第二只下蛋的数量.\n【详解】 86 + 9 = 95 (个);答:第二只海龟下了95个蛋。", + "knowledge_points": [ + "一位数与两位数的进位加法" + ], + "source": "23-24 二年级上·河南南阳·期中" + }, + { + "id": "91", + "unit": "第六单元100以内的加法和减法1", + "question_type": "解答题", + "difficulty": 0.65, + "question": "小白兔拔了 45 根胡萝卜,小灰兔比小白兔少拔了 9 根,小灰兔拔了多少根胡萝卜。", + "options": [], + "answer": "36根", + "solution": "【分析】用小白兔拔胡萝卜的数量减去小灰兔比小白兔少拔的数量,即可求出小灰兔拔了多少根胡萝卜。据此解答.\n【详解】 45 - 9 = 36 (根);答:小灰兔拔了 36 根胡萝卜.\n[点睛]本题主要考查了 100 以内减法的实际应用,求比一个数少几的数是多少,用减法计算。", + "knowledge_points": [ + "一位数与两位数的退位减法" + ], + "source": "23-24 二年级上·山东济宁·期中" + }, + { + "id": "92", + "unit": "第六单元100以内的加法和减法1", + "question_type": "解答题", + "difficulty": 0.85, + "question": "学校买来白粉笔 50盒,彩色粉笔20盒,一共买来多少盒粉笔。用去5盒彩色粉笔,彩色粉笔还剩下多少盒。", + "options": [], + "answer": "70盒;15盒", + "solution": "【分析】求一共买来多少盒粉笔,用加法计算,即白粉笔的盒数 + 彩色粉笔的盒数 = 粉笔的总盒数;求还剩多少盒粉色彩笔,用减法计算,即买来彩色粉笔的总盒数 - 用去的盒数 = 还剩的盒数.\n【详解】 50 + 20 = 70 (盒)20 - 5 = 15 (盒)答:一共买来 70 盒粉笔。彩色粉笔还剩下 15 盒。", + "knowledge_points": [ + "整十数之间的加减法", + "一位数与两位数的退位减法" + ], + "source": "22-23 二年级上·河南南阳·期中" + }, + { + "id": "93", + "unit": "第六单元100以内的加法和减法1", + "question_type": "解答题", + "difficulty": 0.85, + "question": "小明今年 9 岁,妈妈比小明大 26 岁,妈妈今年几岁。", + "options": [], + "answer": "35岁", + "solution": "【分析】求比一个数大的数,用加法计算,妈妈的岁数=小明的岁数+妈妈比小明大的岁数.\n【详解】9+26=35(岁)。答:妈妈今年35岁。", + "knowledge_points": [ + "一位数与两位数的进位加法" + ], + "source": "23-24 二年级上·浙江温州·期中" + }, + { + "id": "94", + "unit": "第六单元100以内的加法和减法1", + "question_type": "解答题", + "difficulty": 0.65, + "question": "果园里有桃树 63 棵,梨树比桃树多 9 棵,梨树有多少棵。", + "options": [], + "answer": "72棵", + "solution": "【分析】求比一个数多几的数是多少,用这个数加多的数计算,即桃树的数量 + 梨树比桃树多的数量 = 梨树的数量.\n【详解】 63 + 9 = 72 (棵)答:梨树有 72 棵。", + "knowledge_points": [ + "一位数与两位数的进位加法" + ], + "source": "23-24 二年级上·广东江门·期中" + }, + { + "id": "95", + "unit": "第六单元100以内的加法和减法1", + "question_type": "解答题", + "difficulty": 0.85, + "question": "小林在看绘本,第一周看了16页,第二周比第一周多看了5页,他第二周看了多少页。", + "options": [], + "answer": "21页", + "solution": "【分析】第二周看的页数 = 第一周看的页数 + 第二周比第一周多看的页数;据此解决.\n【详解】 16 + 5 = 21 (页)答:他第二周看了 21 页。", + "knowledge_points": [ + "一位数与两位数的进位加法" + ], + "source": "23-24 二年级上·广东汕头·期中" + }, + { + "id": "96", + "unit": "第六单元100以内的加法和减法1", + "question_type": "解答题", + "difficulty": 0.85, + "question": "4 月 23 日是世界读书日,第二届全民阅读大会在浙江杭州开幕。为响应全民阅读的倡导,一年级 (1) 班语文兴趣小组购入故事书,文艺书,画册三种书,每种书 8 本,一共有多少本。", + "options": [], + "answer": "24本", + "solution": "【分析】求一共有多少本,用加法计算,即故事书的数量 + 文艺书的数量 + 画册的数量 = 书的总数量.\n【详解】 8 + 8 + 8 = 24 (本)答:一共有 24 本。", + "knowledge_points": [ + "100以内数的连加运算" + ], + "source": "23-24 一年级下·河北保定·期末" + }, + { + "id": "97", + "unit": "第六单元100以内的加法和减法1", + "question_type": "解答题", + "difficulty": 0.85, + "question": "李老师家买了56个苹果,吃了15天后,还剩下5个苹果。李老师家15天吃了多少个苹果。", + "options": [], + "answer": "51个", + "solution": "【分析】用买了的苹果总数量减去还剩的数量,求出差,就是吃了的苹果数量.\n【详解】 56 - 5 = 51 (个)答:李老师家15天吃了51个苹果。", + "knowledge_points": [ + "两位数与一位数的减法(不退位)" + ], + "source": "23-24一年级下·江西吉安·期末" + }, + { + "id": "98", + "unit": "第六单元100以内的加法和减法1", + "question_type": "解答题", + "difficulty": 0.65, + "question": "车上原来有 58 个乘客,到站下去 20 人,又上来了 8 人,现在车上有多少人。", + "options": [], + "answer": "46人", + "solution": "【分析】先根据减法的意义,用车上原来有的总人数减去到站下车的人数,再根据加法的意义,再加上又上来的人数即可求出现在车上有的人数,据此解答即可.\n【详解】 58 - 20 + 8 = 38 + 8 = 46 (人);答:现在车上有 46 人。", + "knowledge_points": [ + "100以内数的加减混合运算" + ], + "source": "23-24 一年级下·河南濮阳·期末" + }, + { + "id": "99", + "unit": "第六单元100以内的加法和减法1", + "question_type": "解答题", + "difficulty": 0.65, + "question": "从树上摘了 20 个苹果,树上还剩 35 个苹果,树上原来有多少个苹果。", + "options": [], + "answer": "55个", + "solution": "【分析】根据题意分析,用树上剩下的苹果的数量加上树上摘下的苹果的数量,即可得到树上原来有的苹果的数量.\n【详解】 20 + 35 = 55 (个)答:树上原来有 55 个苹果。", + "knowledge_points": [ + "两位数与整十数的加法" + ], + "source": "23-24 一年级下·河南濮阳·期末" + }, + { + "id": "100", + "unit": "第六单元100以内的加法和减法1", + "question_type": "解答题", + "difficulty": 0.65, + "question": "做一个毽子要用 4 根羽毛,现在有 23 根羽毛,最多可以做几个毽子。", + "options": [], + "answer": "5个", + "solution": "【分析】总共的羽毛数量连续减 4,每减一次就能做一个毽子,直到不能减,然后得出结论即可.\n【详解】 23 - 4 = 19 (根), 19 - 4 = 15 (根), 15 - 4 = 11(根), 11 - 4 = 7 (根), 7 - 4 = 3 (根)答:最多可以做5个毽子。", + "knowledge_points": [ + "100以内数的连减运算" + ], + "source": "23-24一年级下·湖南长沙·期末" + }, + { + "id": "101", + "unit": "第六单元100以内的加法和减法2", + "question_type": "选择题", + "difficulty": 0.94, + "question": "用\" 37 + 4 \"能解决的问题是()。", + "options": [ + "A. 一个布娃娃 37 元,一个文具盒 4 元,布娃娃比文具盒贵多少元。", + "B. 兰兰有 37 本练习本,送给丽丽 4 本,兰兰还有多少本练习本。", + "C. 停车场有 37 辆汽车,又来了 4 辆,停车场现在有多少辆车。" + ], + "answer": "C", + "solution": "【分析】(1)布娃娃比文具盒贵多少元,用较大的数减较小的数即可;(2)兰兰送出去了4本练习本,那么兰兰手中的练习本数量减少,最终兰兰剩下的练习本数量用总数减送出去的数量即可;(3)求停车场中车辆的总数,用加法,据此解答.\n【详解】A.布娃娃比文具盒贵:37-4=33(元);B.兰兰还有练习册:37-4=33(本);C.停车场现在有车:37+4=41(辆);故答案为:C", + "knowledge_points": [ + "\"提问题\" \"填条件\" 问题" + ], + "source": "23-24一年级下·河南漯河·期末" + }, + { + "id": "102", + "unit": "第六单元100以内的加法和减法2", + "question_type": "选择题", + "difficulty": 0.65, + "question": "小丽有 14 个苹果,小明有 10 个苹果,小丽再给小明 ( ) 个苹果,两人的苹果就一样多。", + "options": [ + "A. 4", + "B. 2", + "C. 3" + ], + "answer": "B", + "solution": "【分析】根据题意,先计算出小丽比小明多几个苹果,再将多出的苹果分成两部分数量一样多,则两人的苹果就一样多。据此解答.\n【详解】 14 - 10 = 4 (个);4 可以分成 2 和 2;14 - 2 = 12 (个);10 + 2 = 12 (个);由此可知,小丽再给小明 2 个苹果,两人的苹果就一样多。故答案为: B", + "knowledge_points": [ + "和差倍问题,两位数与整十数的减法" + ], + "source": "23-24一年级下·河南漯河·期末" + }, + { + "id": "103", + "unit": "第六单元100以内的加法和减法2", + "question_type": "选择题", + "difficulty": 0.85, + "question": "在算式60 + (30 - 20) 中,先 算 ( ) 。", + "options": [ + "A. 60 + 30", + "B. 30 - 20", + "C. 60 - 10" + ], + "answer": "B", + "solution": "【分析】有小括号的混合运算,先算小括号里的,再算小括号外的,由此算式 60 + (30 - 20) 先算小括号里的减法,即先算 30 - 20,由此解答.\n【详解】在算式 60 + (30 - 20) 中,先算 30 - 20;故答案为: B", + "knowledge_points": [ + "带有小括号的混合运算" + ], + "source": "23-24 一年级下·河南漯河·期末" + }, + { + "id": "104", + "unit": "第六单元100以内的加法和减法2", + "question_type": "选择题", + "difficulty": 0.85, + "question": "30 连续减 5,要减 ( ) 次才得 0 。", + "options": [ + "A. 7", + "B. 5", + "C. 6" + ], + "answer": "C", + "solution": "【分析】根据减法的意义,用 30 依次减去 5,直到减到 0为止,据此解答即可.\n【详解】 30 - 5 - 5 - 5 - 5 - 5 - 5 = 0 所以30连续减5,要减6次才得0。故答案为: C", + "knowledge_points": [ + "100以内数的连减运算" + ], + "source": "23-24 一年级下·河南濮阳·期末" + }, + { + "id": "105", + "unit": "第六单元100以内的加法和减法2", + "question_type": "选择题", + "difficulty": 0.65, + "question": "有 52 个西瓜,王大伯每次能运 9 个,他至少要运 ( ) 次才能运完。", + "options": [ + "A. 5", + "B. 6", + "C. 7" + ], + "answer": "B", + "solution": "【分析】用 52 连续减 9,减到不能减为止,最后有剩余,还需要运一次,用减的次数加 1 即可求出至少要运多少次才能运完.\n【详解】 52 - 9 - 9 - 9 - 9 - 9 = 7 (个)5 + 1 = 6 (次)他至少要运 6 次才能运完。故答案为: B", + "knowledge_points": [ + "100以内数的连减运算" + ], + "source": "23-24 一年级下·福建漳州·期末" + }, + { + "id": "106", + "unit": "第六单元100以内的加法和减法2", + "question_type": "选择题", + "difficulty": 0.85, + "question": "明明做了 20 朵红花,16 朵黄花,芳芳想要超过明明,她至少要做()朵花。", + "options": [ + "A. 37", + "B. 36", + "C. 26" + ], + "answer": "A", + "solution": "【分析】先把明明做了的红花数量与黄花数量加起来,求出和,再加上 1,求出和,就是芳芳至少要做的花数量.\n【详解】 20 + 16 + 1= 36 + 1 = 37(朵)即,明明做了 20 朵红花,16 朵黄花,芳芳想要超过明明,她至少要做 37 朵花。故答案为: A", + "knowledge_points": [ + "100 以内数的连加运算" + ], + "source": "23-24 一年级下·贵州铜仁·期末" + }, + { + "id": "107", + "unit": "第六单元100以内的加法和减法2", + "question_type": "选择题", + "difficulty": 0.65, + "question": "30 个苹果, 8 个装一袋,可以装满 ( ) 袋。", + "options": [ + "A. 3", + "B. 4", + "C. 5" + ], + "answer": "A", + "solution": "【分析】根据减法的意义,用苹果的总数量 30 个依次减去每袋能装的数量 8 个,直到减不动为止,减了几次就是最多可以装满几袋,剩下的减不动的数就是还剩下的苹果的数量.\n【详解】 30 - 8 - 8 - 8 = 6 (个)一共减了 3 次,也就是可以装满 3 袋,还剩下 6 个苹果。故答案为: A", + "knowledge_points": [ + "100 以内数的连减运算" + ], + "source": "23-24 一年级下·四川乐山·期末" + }, + { + "id": "108", + "unit": "第六单元100以内的加法和减法2", + "question_type": "选择题", + "difficulty": 0.65, + "question": "计算 32 - 7 时,小丽先算 32 - 2 = 30,再算 30 - 5 = 25,下面的小棒图与小丽算法相同的是 ( )。", + "options": [ + "A. ![](images/114402.png)", + "B. ![](images/afc9f3e2a840e9a162a4dc798b8e4c2676a4e152f26757229b2e642adb3fd8e1.jpg)", + "C. ![](images/26b847e39990bf6665d4d09ac1187d8447e049a7d4f2d8ae2e15f086ba72c5f0.jpg)" + ], + "answer": "C", + "solution": "【分析】由题可知,计算32-7时,将7分成了2和5,先计算出了32-2的结果,再用求出的结果减5即可.\n【详解】A.把32分成了10和22,先算10-7=3,再算3+22=25,与题意不符;B.把32分成了20和12,先算12-7=5,再算20+5=25,与题意不符;C.把7分成了2和5,先算32-2=30;再算30-5=25,与题意相符;与小丽算法相同的是![](images/b3468ca0c55691f69fc2afb9cac2df6d4344f84a881c4b0813fe6960c66c9de8.jpg)。故答案为:C", + "knowledge_points": [ + "一位数与两位数的退位减法" + ], + "source": "23-24 一年级下·福建福州·期末" + }, + { + "id": "109", + "unit": "第六单元100以内的加法和减法2", + "question_type": "选择题", + "difficulty": 0.65, + "question": "悦悦买了 23 个不同口味的糕点,每 5 个装一盒,可以装满 ( ) 个盒子。", + "options": [ + "A. 3", + "B. 4", + "C. 5" + ], + "answer": "B", + "solution": "【分析】根据题意,用糕点的总数量23个,依次减去每盒装的数量5个,减到最后的数量不够装满1盒为止,减了几次5就能装满几个盒子.\n【详解】23-5=18;18-5=13;13-5=8;8-5=3。减了4次5,可以装满4个盒子。故答案为:B", + "knowledge_points": [ + "100 以内数的连减运算" + ], + "source": "23-24 一年级下·河南郑州·期末" + }, + { + "id": "110", + "unit": "第六单元100以内的加法和减法2", + "question_type": "选择题", + "difficulty": 0.65, + "question": "悦悦3人游完开封府后,每人点了一份灌汤包,他们一共花了多少钱。下列表述方式错误的是().\n\n![](images/50c97a8396420032c16cf665c902e346b3daea02e9319b6b5e175a91ee0e1fdc.jpg)", + "options": [ + "A. 20 + 20 + 20 = 60 (元)", + "B. 20 + 3 = 23 (元)", + "C. | 份数 | 1 | 2 | 3 |\n| ------ | ---- | ---- | ---- |\n| 总钱数 | 20 | 40 | 60 |" + ], + "answer": "B", + "solution": "【分析】根据加法的意义,求出3份灌汤包的价钱即可,据此逐项分析解答.\n【详解】A.20+20+20=60(元),列式正确;B.20+3=23(元),列式错误,加数不为3;C.\n\n| 份数 | 1 | 2 | 3 |\n| ------ | ---- | ---- | ---- |\n| 总钱数 | 20 | 40 | 60 |\n\n由表可知,1份灌汤包20元,2份灌汤包40元,3份灌汤包60元,表述正确。故答案为:B", + "knowledge_points": [ + "经济问题,整十数之间的加减法" + ], + "source": "23-24一年级下·河南郑州·期末" + }, + { + "id": "111", + "unit": "第六单元100以内的加法和减法2", + "question_type": "选择题", + "difficulty": 0.65, + "question": "悦悦拿了 2 张 20 元购买 \"开封府\" 门票,找回的钱比 5 元多,比 10 元少,开封府的票价是 ( )。", + "options": [ + "A. 32元", + "B. 38元", + "C. 30元" + ], + "answer": "A", + "solution": "【分析】根据题意,先用加法计算出悦悦一共拿了多少钱,再用拿的钱数分别减去5元和10元,求出找回5元、10元时的价格分别是多少,实际找回的钱数比5元多、比10元少,也就是票价在求出的两个价格区间内,由此解答.\n【详解】20+20=40(元);40-5=35(元);40-10=30(元),票价大于30元,小于35元。A.30<32<35,符合题意;B.30<35<38,不符合题意;C.30=30<35,不符合题意。开封府的票价是32元。故答案为:A", + "knowledge_points": [ + "100 以内数的比大小,整十数之间的加减法,一位数与两位数的退位减法,十元以上人民币的认识与计算" + ], + "source": "23-24 一年级下·河南郑州·期末" + }, + { + "id": "112", + "unit": "第六单元100以内的加法和减法2", + "question_type": "选择题", + "difficulty": 0.65, + "question": "下面算式中,得数比 48 少一些的是 ( )。", + "options": [ + "A. 84-30", + "B. 36 - 20", + "C. 39 + 5" + ], + "answer": "C", + "solution": "【分析】根据整数加减法的计算法则,依次计算出各算式的结果,再找出比48少一些的数即可.\n【详解】A.84-30=54;54比48多一些;B.36-20=16;16比48少得多;C.39+5=44;44比48少一些。得数比48少一些的是39+5。故答案为:C", + "knowledge_points": [ + "数的相对大小关系,两位数与整十数的减法,一位数与两位数的进位加法" + ], + "source": "23-24 一年级下·河南南阳·期末" + }, + { + "id": "113", + "unit": "第六单元100以内的加法和减法2", + "question_type": "选择题", + "difficulty": 0.65, + "question": "妈妈买了一个书包,\n\n付了3张 20,找回的钱比5元多,比10元少。书包的价格可能是()元。", + "options": [ + "A. 55", + "B. 53", + "C. 50" + ], + "answer": "B", + "solution": "【分析】根据题意,先用加法计算出妈妈付了多少钱。再用付出的钱数分别减去5元和10元,求出找回5元和10元时的价格是多少。实际找回的钱数比5元多、比10元少,也就是书包的价格在求出的两个价格区间内,由此解答.\n【详解】20+20+20=60(元);60-5=55(元);60-10=50(元)。书包的价格大于50元小于55元。A.50<55=55,不符合题意;B.50<53<55,符合题意;C.50=50<55,不符合题意。书包的价格可能是53元。故答案为:B", + "knowledge_points": [ + "100 以内数的比大小,整十数之间的加减法,一位数与两位数的退位减法,十元以上人民币的认识与计算" + ], + "source": "23-24 一年级下·湖北黄石·期末" + }, + { + "id": "114", + "unit": "第六单元100以内的加法和减法2", + "question_type": "选择题", + "difficulty": 0.65, + "question": "算式 5 和 2 可以直接相加的算式是 ( )。", + "options": [ + "A. 32 + 50", + "B. 53 - 20", + "C. 23 + 50" + ], + "answer": "C", + "solution": "【分析】从右起,第一位是个位,第二位是十位。整数加法计算时,个位和个位相加,十位和十位相加.\n【详解】A.32+50,2在个位,5在十位,不能直接相加;B.53-20,是减法,5和2相减;C.23+50,5和2都在十位,可以直接相加。故答案为:C", + "knowledge_points": [ + "两位数与整十数的加法" + ], + "source": "23-24 一年级下·福建莆田·期末" + }, + { + "id": "115", + "unit": "第六单元100以内的加法和减法2", + "question_type": "选择题", + "difficulty": 0.85, + "question": "小红和4个好朋友,每人有4张贺卡,他们一共有()张贺卡。", + "options": [ + "A. 16", + "B. 20", + "C. 9" + ], + "answer": "B", + "solution": "【分析】要求小红和 4 个好朋友一共有多少张贺卡,根据加法的意义,用 4 + 4 + 4 + 4 + 4 进行解答即可.\n【详解】 4 + 4 + 4 + 4 + 4= 8 + 8 + 4 = 16 + 4 = 20 (张)所以,他们一共有 20 张贺卡。故答案为: B", + "knowledge_points": [ + "连加 (20 以内)" + ], + "source": "23-24 一年级下·河南三门峡·期末" + }, + { + "id": "116", + "unit": "第六单元100以内的加法和减法2", + "question_type": "选择题", + "difficulty": 0.85, + "question": "46比()多7。", + "options": [ + "A. 39", + "B. 53", + "C. 37" + ], + "answer": "A", + "solution": "【分析】要求 46 比谁多 7,即求比 46 少 7 的数是多少,根据减法的意义,用 46-7 进行解答即可.\n【详解】 46 - 7 = 39,所以 46 比 39 多 7。故答案为: A", + "knowledge_points": [ + "一位数与两位数的退位减法" + ], + "source": "23-24一年级下·河南三门峡·期末" + }, + { + "id": "117", + "unit": "第六单元100以内的加法和减法2", + "question_type": "填空题", + "difficulty": 0.65, + "question": "比60大18的数是( );85和9相差( );15比9多( ),7比11少( )。", + "options": [], + "answer": "78;76;6;4", + "solution": "【分析】求比一个数大几的数是多少,用这个数加大的数计算;求两个数相差多少,用减法计算;求一个数比另一个数多几,用这个数减另一个数计算;求一个数比另一个数少几,用另一个数减这个数计算.\n【详解】60+18=78;85-9=76;15-9=6;11-7=4。比60大18的数是78;85和9相差76;15比9多6,7比11少4。", + "knowledge_points": [ + "十几减 9 的退位减法,十几减 7,6 的退位减法,两位数与整十数的加法,一位数与两位数的退位减法" + ], + "source": "23-24 一年级下·河北保定·期末" + }, + { + "id": "118", + "unit": "第六单元100以内的加法和减法2", + "question_type": "填空题", + "difficulty": 0.85, + "question": "65 前面第 6 个数是( ), 76 后面的第 4 个数是( )。", + "options": [], + "answer": "59;80", + "solution": "【分析】求 65 前面第 6 个数,用减法计算;求 76 后面的第 4 个数,用加法计算.\n【详解】 65 - 6 = 59;76 + 4 = 80;所以 65 前面第 6 个数是 59, 76 后面的第 4 个数是 80。", + "knowledge_points": [ + "一位数与两位数的进位加法,一位数与两位数的退位减法" + ], + "source": "23-24 一年级下·福建莆田·期末" + }, + { + "id": "119", + "unit": "第六单元100以内的加法和减法2", + "question_type": "填空题", + "difficulty": 0.85, + "question": "乐乐买了一本故事书,第一天看了 9 页,第三天是从第 21 页开始看的,那么第二天他看了( )页。", + "options": [], + "answer": "11", + "solution": "【分析】据题意,先用第三天开始看的页数减去 1,求出第一天和第二天一共看的页数,然后用第一天和第二天一共看的页数减去第一天看的页数,即可求出第二天看了多少页.\n【详解】 21 - 1 = 20 (页)20 - 9 = 11 (页)所以第二天他看了 11 页。", + "knowledge_points": [ + "两位数与一位数的减法(不退位),一位数与两位数的退位减法" + ], + "source": "23-24一年级下·福建莆田·期末" + }, + { + "id": "120", + "unit": "第六单元100以内的加法和减法2", + "question_type": "填空题", + "difficulty": 0.85, + "question": "在括号里填上 \">\" \"<\" 或 \"=\".\n50 - 3 ( ) 28 + 20\n35 + 5 ( ) 80 - 40\n72 - 8 ( ) 70 - 9\n63 + 6 ( ) 70 + 0\n5元( )4元+5角\n10元()9元3角+1元", + "options": [], + "answer": "<;=;>;<;>", + "solution": "【分析】先计算出每个算式的结果或先统一单位,然后比较大小即可.\n【详解】50-3=47,28+20=48,故50-3<28+20;35+5=40,80-40=40,故35+5=80-40;72-8=64,70-9=61,故72-8>70-9;63+6=69,70+0=70,故63+6<70+0;5元=50角,4元+5角=45角,故5元>4元+5角;9元3角+1元=10元3角,故10元<9元3角+1元。", + "knowledge_points": [ + "100 以内数的比大小,一位数与两位数的进位加法,一位数与两位数的退位减法,元,角,分的认识及换算" + ], + "source": "23-24 一年级下·江西吉安·期末" + }, + { + "id": "121", + "unit": "第六单元100以内的加法和减法2", + "question_type": "填空题", + "difficulty": 0.85, + "question": "38 比 8 多( ), 5 比 22 少( )。", + "options": [], + "answer": "30;17", + "solution": "【分析】求一个数比另一个数多(少)多少,用减法列式计算.\n【详解】 38 - 8 = 30;22 - 5 = 17;即, 38 比 8 多 30, 5 比 22 少 17。", + "knowledge_points": [ + "两位数与一位数的减法(不退位),一位数与两位数的退位减法" + ], + "source": "23-24 一年级下·江西吉安·期末" + }, + { + "id": "122", + "unit": "第六单元100以内的加法和减法2", + "question_type": "填空题", + "difficulty": 0.85, + "question": "54比30多( ),4比77少( )。", + "options": [], + "answer": "24;73", + "solution": "【分析】求一个数比另一个数多或者少多少都是减法去求,也就是用多的减去少的,据此解答即可.\n【详解】 54 - 30 = 24;77 - 4 = 73;所以54比30多24,4比77少 73", + "knowledge_points": [ + "两位数与一位数的减法(不退位),两位数与整十数的减法" + ], + "source": "23-24一年级下·河南濮阳·期末" + }, + { + "id": "123", + "unit": "第六单元100以内的加法和减法2", + "question_type": "填空题", + "difficulty": 0.65, + "question": "在括号里填上\">\" \"<\"或\"=\" .\n40 + 13 ( ) 66 - 20\n72 + 7 ( ) 86 - 6\n50 + 30 ( ) 98\n30角( )2元8角\n7角+9角( )2元-4角\n1元30分( )2元", + "options": [], + "answer": ">;<;<;>;=;<", + "solution": "【分析】根据整数加减法的计算法则,依次计算出各算式的结果再比较大小。人民币的题目根据1元=10角,1角=10分先统一单位再计算比较.\n【详解】40+13=53;66-20=46;53>46,则40+13>66-20;72+7=79;86-6=80;79<80,则72+7<86-6;50+30=80;80<98,则50+30<98;2元8角=28角;30角>28角,则30角>2元8角;7角+9角=16角;2元-4角=16角;16角=16角,则7角+9角=2元-4角;1元30分=13角;2元=20角;13角<20角,则1元30分<2元。", + "knowledge_points": [ + "100以内数的比大小,两位数与整十数的减法,元,角,分的认识及换算,十元以下人民币的认识与计算" + ], + "source": "23-24 一年级下·福建漳州·期末" + }, + { + "id": "124", + "unit": "第六单元100以内的加法和减法2", + "question_type": "填空题", + "difficulty": 0.65, + "question": "在括号里填上\">\" \"<\"或\"=\" .\n\n58 ( ) 40 + 12\n7 + 30 ( ) 40\n45 - 20 ( ) 38\n53 + 9 ( ) 61 - 8\n40 + 28 ( ) 30 + 50\n98 - 30 ( ) 60 + 8", + "options": [], + "answer": ">;<;<;>;=", + "solution": "【分析】分别计算出各算式的结果,再比较大小.\n【详解】(1)40+12=52,58>52,即58>40+12;(2)7+30=37,37<40,所以7+30<40;(3)45-20=25,25<38,所以45-20<38;(4)53+9=62,61-8=53,62>53,所以53+9>61-8;(5)40+28=68,30+50=80,68<80,所以40+28<30+50;(6)98-30=68,60+8=68,68=68,所以98-30=60+8。", + "knowledge_points": [ + "两位数与整十数的加法,两位数与整十数的减法,一位数与两位数的进位加法,一位数与两位数的退位减法" + ], + "source": "23-24 一年级下·河南郑州·期末" + }, + { + "id": "125", + "unit": "第六单元100以内的加法和减法2", + "question_type": "填空题", + "difficulty": 0.85, + "question": "明明用☆表示10,用△表示1,那么☆+☆+△=( )。", + "options": [], + "answer": "21", + "solution": "【分析】根据题意,将☆和△所表示的数代入到算式中,计算出结果即可.\n【详解】10+10+1=21;明明用☆表示10,用△表示1,那么☆+☆+△=21。", + "knowledge_points": [ + "100以内数的连加运算" + ], + "source": "23-24 一年级下·浙江嘉兴·期末" + }, + { + "id": "126", + "unit": "第六单元100以内的加法和减法2", + "question_type": "填空题", + "difficulty": 0.65, + "question": "问诊台有 32 人排队咨询,从前往后数李阿姨排第 8,她后面有( )人。", + "options": [], + "answer": "24", + "solution": "【分析】由题可知,从前往后数李阿姨排第 8,所以李阿姨前面包括李阿姨本人一共有 8 人,再根据减法的意义,用排队的总人数减去 8 人即可求出李阿姨后面的人数.\n【详解】 32 - 8 = 24 (人)所以她后面有 24 人。", + "knowledge_points": [ + "一位数与两位数的退位减法,前,后位置" + ], + "source": "23-24 一年级下·河南南阳·期末" + }, + { + "id": "127", + "unit": "第六单元100以内的加法和减法2", + "question_type": "填空题", + "difficulty": 0.65, + "question": "十位上是 7 的最大两位数与最小两位数相差( )。", + "options": [], + "answer": "9", + "solution": "【分析】十位上是 7 的最大两位数是 79,十位上是 7 的最小两位数是 70,求它们之间的差用减法计算,据此解答即可.\n【详解】十位上是 7 的最大两位数是 79,十位上是 7 的最\n小两位数是 70 。 79 - 70 = 9所以十位上是 7 的最大两位数与最小两位数相差 9 。", + "knowledge_points": [ + "两位数与整十数的减法" + ], + "source": "23-24 一年级下·河南南阳·期末" + }, + { + "id": "128", + "unit": "第六单元100以内的加法和减法2", + "question_type": "填空题", + "difficulty": 0.65, + "question": "在括号里填上合适的数.\n( ) + 8 = 56 ( ) - 40 = 15\n25 + 8 = ( ) + 916 + ( ) = 28 - ( )", + "options": [], + "answer": "48;55;24;10;2", + "solution": "【分析】根据和减一个加数=另一个加数;减数+差=被减数计算即可。最后一题,两侧算式的结果相同即可,可使结果都为26.\n【详解】56-8=48,则48+8=56;40+15=55;则55-40=15;25+8=33;33-9=24,则25+8=24+9;16+10=28-2=26。(答案不唯一)", + "knowledge_points": [ + "两位数与整十数的减法,一位数与两位数的进位加法,一位数与两位数的退位减法" + ], + "source": "23-24 一年级下·湖北黄石·期末" + }, + { + "id": "129", + "unit": "第六单元100以内的加法和减法2", + "question_type": "填空题", + "difficulty": 0.85, + "question": "阳阳有 40 枚邮票,新新有 34 枚邮票,阳阳给新新( )枚后两人就同样多。", + "options": [], + "answer": "3", + "solution": "【分析】已知阳阳有 40 枚邮票,新新有 34 枚邮票,相减即可知阳阳比新新多几枚,多出来的邮票分成相等的两份,其中一份的数量就是阳阳需要给新新的邮票数量.\n【详解】 40 - 34 = 6 (枚)3 + 3 = 6 (枚);阳阳比新新多 6 枚,分成相等的两份就是一份 3 枚。阳阳有 40 枚邮票,新新有 34 枚邮票,阳阳给新新 3 枚后两人就同样多。", + "knowledge_points": [ + "两位数与两位数的退位减法" + ], + "source": "23-24 一年级下·湖北黄石·期末" + }, + { + "id": "130", + "unit": "第六单元100以内的加法和减法2", + "question_type": "填空题", + "difficulty": 0.85, + "question": "20 比 54 少( ), ( )比 50 多 9 。", + "options": [], + "answer": "34;59", + "solution": "【分析】求一个数比另一个数少多少,用减法计算;求比一个数多几的数是多少,用加法计算即可.\n【详解】 54 - 20 = 34;50 + 9 = 59;所以 20 比 54 少 34, 59 比 50 多 9。", + "knowledge_points": [ + "整十数加,减一位数,两位数与整十数的减法" + ], + "source": "23-24 一年级下·湖北黄石·期末" + }, + { + "id": "131", + "unit": "第六单元100以内的加法和减法2", + "question_type": "填空题", + "difficulty": 0.65, + "question": "32比8多( );45比( )少7。", + "options": [], + "answer": "24;52", + "solution": "【分析】求一个数比另一个数多多少,用减法计算;已知一个数比另一个数少几,求另一个数是多少,用加法计算.\n【详解】 32 - 8 = 24;45 + 7 = 52;所以 32 比 8 多 24;45 比 52 少 7。", + "knowledge_points": [ + "一位数与两位数的进位加法,一位数与两位数的退位减法" + ], + "source": "23-24 一年级下·湖北黄冈·期末" + }, + { + "id": "132", + "unit": "第六单元100以内的加法和减法2", + "question_type": "填空题", + "difficulty": 0.85, + "question": "在括号填上\">\" \"<\"或\"=\" .\n9个十( )9个一\n69+30( )69+3\n50分( )5元\n3分+7分( )1角\n83( )38\n4元8角( )45角", + "options": [], + "answer": ">;>;<;=;>", + "solution": "【分析】先计算出每个算式的结果或先统一单位,然后比较大小即可。整数比较大小方法: ①位数多的数大于位数少的数;②位数相同的,先比较最高位上的数,最高位上大的,数就大,最高位数相同的,就比较下一位,以此类推。1元 = 10 角, 1 元 = 100 分, 1 角 = 10 分.\n【详解】9个十是90,9个一是9,故,9个十>9个一;69 + 30 = 99, 69 + 3 = 72,故, 69 + 30 > 69 + 3;1元 = 100 分,故, 50 分 < 5 元;3分+7分=10分,10分=1角,故,3分+7分=1角;83 > 38 \n4元8角 = 48 角,故, 4元8角 > 45 角。", + "knowledge_points": [ + "100以内数的比大小,100以内数的组成,一位数与两位数的进位加法,元,角,分的认识及换算" + ], + "source": "23-24 一年级下·贵州铜仁·期末" + }, + { + "id": "133", + "unit": "第六单元100以内的加法和减法2", + "question_type": "填空题", + "difficulty": 0.85, + "question": "比 45 多 8 的数是( ), 它的相邻数是( )和( )。", + "options": [], + "answer": "53;52;54", + "solution": "【分析】比 45 多 8,就是 45 + 8,结果是 53,再写出与 53 相邻的数即可.\n【详解】 45 + 8 = 53;所以比 45 多 8 的数是 53,它的相邻数是 52 和 54。", + "knowledge_points": [ + "100 以内数的排序,一位数与两位数的进位加法,相邻的数" + ], + "source": "23-24 一年级下·贵州铜仁·期末" + }, + { + "id": "134", + "unit": "第六单元100以内的加法和减法2", + "question_type": "填空题", + "difficulty": 0.85, + "question": "8 连续加 8,写出每次加得的和。8, ( ), ( ), ( ), ( )。", + "options": [], + "answer": "16;24;32;40", + "solution": "【分析】根据加法的意义,结合题干要求列式解答即可.\n【详解】 8 + 8 = 16;16 + 8 = 24;24 + 8 = 32;32 + 8 = 40;所以这列数字为:8,16,24,32,40。", + "knowledge_points": [ + "一位数与两位数的进位加法" + ], + "source": "23-24 一年级下·河南三门峡·期末" + }, + { + "id": "135", + "unit": "第六单元100以内的加法和减法2", + "question_type": "填空题", + "difficulty": 0.65, + "question": "在括号里填上\">\" \"<\"或\"=\" .\n15 - 7 ( ) 8\n11 - 6 ( ) 6\n45 + 7 ( ) 50\n74 ( ) 64 + 9\n58 - 20 ( ) 48\n68 - 5 ( ) 63", + "options": [], + "answer": "=;<;>;<;=", + "solution": "【分析】比较数的大小,先看位数的多少,位数多的数就大;如果位数相同,从最高位开始比较,最高位上的数大\n则这个数大,最高位上的数相同,就比较下一位,依次类推.\n含有算式的大小比较,可以先计算出每个算式的结果,再比较大小.\n【详解】 15 - 7 = 8,所以 15 - 7 = 8;\n11 - 6 = 5,所以 11 - 6 < 6;45 + 7 = 52,所以 45 + 7 > 50;64 + 9 = 73,所以 74 > 64 + 9;58 - 20 = 38,所以 58 - 20 < 48;68 - 5 = 63,所以 68 - 5 = 63 。", + "knowledge_points": [ + "十几减 7,6 的退位减法,两位数与一位数的减法(不退位),两位数与整十数的减法,一位数与两位数的进位加法" + ], + "source": "23-24 一年级下·四川乐山·期末" + }, + { + "id": "136", + "unit": "第六单元100以内的加法和减法2", + "question_type": "填空题", + "difficulty": 0.85, + "question": "7 个十和 4 个一组成的数是( ),这个数再添 6 个一就是( )。", + "options": [], + "answer": "74;80", + "solution": "【分析】7个十是70,4个一是4,组成的数是74;74再添6 个一是多少,就是求 74 加 6 等于多少;据此解决.\n【详解】 74 + 6 = 80;即, 7 个十和 4 个一组成的数是 74,这个数再添 6 个一就是 80。", + "knowledge_points": [ + "100以内数的组成,一位数与两位数的进位加法" + ], + "source": "23-24 一年级下·四川乐山·期末" + }, + { + "id": "137", + "unit": "第六单元100以内的加法和减法2", + "question_type": "填空题", + "difficulty": 0.85, + "question": "比 60 大 18 的数是( ), 85 和 9 相差( )。", + "options": [], + "answer": "78;76", + "solution": "【分析】求比一个数大几的数是多少,用加法列式计算;求两个数相差多少,用减法列式计算;据此解决.\n【详解】 60 + 18 = 78;85 - 9 = 76;即,比60大18的数是78,85和9相差 76。", + "knowledge_points": [ + "两位数与整十数的加法,一位数与两位数的退位减法" + ], + "source": "23-24 一年级下·湖南长沙·期末" + }, + { + "id": "138", + "unit": "第六单元100以内的加法和减法2", + "question_type": "填空题", + "difficulty": 0.65, + "question": "□ + 28 < 34 , □ 里最大可以填( )。", + "options": [], + "answer": "5", + "solution": "【分析】比 34 小的数有 33,32,31。其中最大的是 33,也就是左侧算式结果是 33 时, □ 里的数最大.\n【详解】 □ + 28 = 33 ,28后边的第5个数是33,也就是5+28=33<34,□里最大可以填5。", + "knowledge_points": [ + "100 以内数的比大小,一位数与两位数的进位加法" + ], + "source": "23-24 一年级下·福建福州·期末" + }, + { + "id": "139", + "unit": "第六单元100以内的加法和减法2", + "question_type": "填空题", + "difficulty": 0.85, + "question": "比 15 少 6 的数是( ), 67 比 60 多( )。", + "options": [], + "answer": "9;7", + "solution": "【分析】求比一个数少几的数是多少,用减法计算;求一个数比另一个数多多少,用减法计算即可.\n【详解】 15 - 6 = 967 - 60 = 7;所以比 15 少 6 的数是 9, 67 比 60 多 7。", + "knowledge_points": [ + "十几减7,6的退位减法,两位数与整十数的减法" + ], + "source": "23-24 一年级下·河南郑州·期末" + }, + { + "id": "140", + "unit": "第六单元100以内的加法和减法2", + "question_type": "填空题", + "difficulty": 0.85, + "question": "\"只有河南·戏剧幻城\"是一座由五十六个小方格组成的,共有 21 个大大小小的剧场,可以同时容纳近万人.\n(1)横线上写的数写作( ).\n(2)与 21 相邻的两个数是( )和( ), 这两个数的和是( )", + "options": [], + "answer": "56;20;22;42", + "solution": "【分析】(1)一个整数,从右往左依次为个位,十位写数时从高位写起,几十就在十位写几,几就在个位写几;(2) 与 21 相邻的数也就是它前边的一个数,和它后边的一个数,根据数的顺序 1, 2, 3。19, 20, 21, 22。找到对应的数,它们的和用加法计算.\n【详解】(1)横线上写的数写作56。(2) 20 + 22 = 42;与 21 相邻的两个数是 20 和 22,这两个数的和是 42。", + "knowledge_points": [ + "100以内数的读,写法,100以内数的排序,两位数与整十数的加法,相邻的数" + ], + "source": "23-24 一年级下·河南郑州·期末" + }, + { + "id": "141", + "unit": "第六单元100以内的加法和减法2", + "question_type": "填空题", + "difficulty": 0.65, + "question": "在括号里填上\">\" \"<\"或\"=\" .\n26( )19+8\n93-7( )35+50\n52-9( )54-8\n43( )36+8\n87-40( )77-9\n53+9( )7+55", + "options": [], + "answer": "<;>;<;<;=;>", + "solution": "【分析】根据整数加减法的计算法则,依次计算出各算式的结果再比较大小。比较时,位数多的数就大;位数相同比较最高位,最高位大的数就大;最高位相同比较下一位,直到比较出结果为止。人民币的题目计算时元和元相加减,角和角相加减,根据1元=10角统一单位再比较.\n【详解】 19 + 8 = 27;26 < 27,则 26 < 19 + 8;93 - 7 = 86;35 + 50 = 85;86 > 85,则 93 - 7 > 35 + 50;52 - 9 = 43;54 - 8 = 46;43 < 46,则 52 - 9 < 54 - 8;36 + 8 = 44;43 < 44,则 43 < 36 + 8; 87 - 40 = 47;77 - 9 = 68;47 < 68,则 87 - 40 < 77 - 9; 53 + 9 = 62;7 + 55 = 62;62 = 62,则 53 + 9 = 7 + 55;", + "knowledge_points": [ + "100 以内数的比大小,一位数与两位数的进位加法,一位数与两位数的退位减法,十元以下人民币的认识与计算" + ], + "source": "23-24 一年级下·河南南阳·期末" + }, + { + "id": "142", + "unit": "第六单元100以内的加法和减法2", + "question_type": "填空题", + "difficulty": 0.65, + "question": "李甜甜在计算 58 加一位数时,把一位数加在了 58 的十位上,结果得 98,正确的结果是( )。", + "options": [], + "answer": "62", + "solution": "【分析】根据题意,把一位数加在了十位上,原来十位上的 5 变成了 9,用减法计算出加在十位上的数是几,再用 58\n加上这个一位数计算出正确结果即可.\n【详解】 9 - 5 = 4;58 + 4 = 62;李甜甜在计算 58 加一位数时,把一位数加在了 58 的十位上,结果得 98,正确的结果是 62 。", + "knowledge_points": [ + "一位数与两位数的进位加法" + ], + "source": "23-24 一年级下·河南南阳·期末" + }, + { + "id": "143", + "unit": "第六单元100以内的加法和减法2", + "question_type": "填空题", + "difficulty": 0.65, + "question": "方方今年 6 岁,妈妈今年 32 岁, 4 年后妈妈比方方大( )岁。", + "options": [], + "answer": "26", + "solution": "【分析】根据题意,两人的年龄差是不变的,4年后妈妈比方方大几岁,与今年相同。所以用今年妈妈的年龄减今年方方的年龄即可.\n【详解】32-6=26(岁);所以4年后妈妈比方方大26岁。", + "knowledge_points": [ + "一位数与两位数的退位减法,年龄问题" + ], + "source": "23-24 一年级下·河南南阳·期末" + }, + { + "id": "144", + "unit": "第六单元100以内的加法和减法2", + "question_type": "填空题", + "difficulty": 0.65, + "question": "5比72少( );94比50多( )。", + "options": [], + "answer": "67;44", + "solution": "【分析】求一个数比另一个数多或者少多少都是减法去求,也就是用多的减去少的。据此解答即可.\n【详解】 72 - 5 = 67;94 - 50 = 44;所以5比72少67;94比50多44。", + "knowledge_points": [ + "两位数与整十数的减法,一位数与两位数的退位减法" + ], + "source": "23-24一年级下·河南南阳·期末" + }, + { + "id": "145", + "unit": "第六单元100以内的加法和减法2", + "question_type": "填空题", + "difficulty": 0.65, + "question": "在括号中填上最大的数.\n( )+9<17\n18+5<27-( )\n59>20+( )", + "options": [], + "answer": "7;3;38", + "solution": "【分析】第 1 题:比 17 小的数有 16 , 15, 14。最大的是 16,也就是左侧算式结果为 16 即可;第2题:右侧算式结果大于左侧,要想括号里填的数最大,则右侧的结果是比左侧结果大1的数;第3题:比59小的数有58,57,56。最大的是58,也就是右侧算式结果为58即可.\n【详解】 ( ) +9 = 16,即 16 - 9 = 7, 7 + 9 < 17,括号里最大填 7;18 + 5 = 23;23 + 1 = 24;27 前边的第 3 个数是 24,也就是 27 - 3 = 24;18 + 5 < 27 - 3,括号里最大填 3;20 + () = 58,即 58 - 20 = 38, 59 > 20 + 38,括号里最大填 38。", + "knowledge_points": [ + "100 以内数的比大小,十几减 9 的退位减法,两位数与整十数的减法,一位数与两位数的进位加法" + ], + "source": "23-24 一年级下·湖北黄石·期末" + }, + { + "id": "146", + "unit": "第六单元100以内的加法和减法2", + "question_type": "填空题", + "difficulty": 0.65, + "question": "在括号里填上\">\" \"<\"或\"=\" .\n54+9( )4+59\n87-6( )86-7\n100分( )1元\n67-9( )67-8\n20+6( )6+20\n6元5角+7角( )7元", + "options": [], + "answer": "=;>;=;<;=;>", + "solution": "【分析】两位数比较大小,十位上大的数就大,如果十位上的数相同,个位上大的数就大。含有算式的大小比较,可以先计算出每个算式的结果,再比较大小。单位不相同的两个数比较大小,先根据 1 元 = 10 角,1 元 = 100 分,统一单位后再比较即可。计算时元和元相加减,角和角相加减.\n【详解】 54 + 9 = 63, 4 + 59 = 63,所以 54 + 9 = 4 + 59;87 - 6 = 81, 86 - 7 = 79,所以 87 - 6 > 86 - 7;100分=1元;67 - 9 = 58, 67 - 8 = 59,所以 67 - 9 < 67 - 8;20 + 6 = 26, 6 + 20 = 26,所以 20 + 6 = 6 + 20;6元5角 +7 角 = 65 角 +7 角 = 72 角 = 70 角 +2 角 = 7 元2角,所以6元5角 +7 角 >7 元。", + "knowledge_points": [ + "整十数加,减一位数,一位数与两位数的进位加法,一位数与两位数的退位减法,元,角,分的认识及换算" + ], + "source": "23-24一年级下·湖北黄石·期末" + }, + { + "id": "147", + "unit": "第六单元100以内的加法和减法2", + "question_type": "填空题", + "difficulty": 0.65, + "question": "小红折了 32 只千纸鹤, 6 只穿成一串可以穿成( )串,还剩( )只。", + "options": [], + "answer": "5;2", + "solution": "【分析】根据题意,用千纸鹤的总数量32只,依次减去每串的数量6只,减到最后的数量不够穿成一串为止,减了几次6就能穿几串,最后的得数就是还剩的数量.\n【详解】32-6=26;26-6=20;20-6=14;14-6=8;8-6=2。小红折了32只千纸鹤,6只穿成一串可以穿成5串,还剩2只。", + "knowledge_points": [ + "100以内数的连减运算" + ], + "source": "23-24 一年级下·湖北黄石·期末" + }, + { + "id": "148", + "unit": "第六单元100以内的加法和减法2", + "question_type": "填空题", + "difficulty": 0.85, + "question": "我会比较。(在括号里填上\">\" \"<\"或\"=\")\n98-30( )65\n33+7( )7+33\n28+40( )26+60\n50角( )8元\n4角( )50分\n89个一( )10个十", + "options": [], + "answer": ">;=;<;<;<;<", + "solution": "【分析】先计算出每个算式的结果或先统一单位,然后比较大小即可。1元=10角,1角=10分.\n【详解】98-30=68,故98-30>65;33+7=40,7+33=40,故33+7=7+33;28+40=68,26+60=86,故28+40<26+60;8元=80角,故50角<8元;4角=40分,故4角<50分;89个一是89,10个十是100,故89个一<10个十。", + "knowledge_points": [ + "100以内数的比大小,两位数与整十数的减法,一位数与两位数的进位加法,元,角,分的认识及换算" + ], + "source": "23-24 一年级下·福建莆田·期末" + }, + { + "id": "149", + "unit": "第六单元100以内的加法和减法2", + "question_type": "填空题", + "difficulty": 0.65, + "question": "按规律填数.\n(1)21, 24, 27, ( ), ( ).\n(2)90, 85, 80, ( ), ( )。", + "options": [], + "answer": "30;33;75;70", + "solution": "【分析】 (1) 27 - 24 = 3, 24 - 21 = 3,规律是:依次加 3;(2) 90 - 85 = 5, 85 - 80 = 5,规律是:依次减 5.\n【详解】 (1) 27 + 3 = 30, 30 + 3 = 33;21, 24, 27, 30, 33。(2) 80 - 5 = 75, 75 - 5 = 70;90, 85, 80, 75, 70。", + "knowledge_points": [ + "整数排列的规律" + ], + "source": "23-24 一年级下·福建莆田·期末" + }, + { + "id": "150", + "unit": "第六单元100以内的加法和减法2", + "question_type": "填空题", + "difficulty": 0.65, + "question": "在括号里填上\"+\"或\"-\".\n47( )7=40\n16( )8=8\n83( )6=89\n58( )6=64\n75( )5=80\n66( )20=46", + "options": [], + "answer": "-;-;+;+;+;-", + "solution": "【分析】算式中若等号右侧的数比左侧的数大或相等可试填\"+\";若等号右侧的数比左侧第一个数小,可试填\"-\".\n【详解】47-7=40;16-8=8;83+6=89;58+6=64;75+5=80;66-20=46。", + "knowledge_points": [ + "十几减8的退位减法,两位数与一位数的加法(不进位),两位数与整十数的减法,一位数与两位数的进位加法" + ], + "source": "23-24一年级下·广东汕头·期末" + }, + { + "id": "151", + "unit": "第六单元100以内的加法和减法2", + "question_type": "填空题", + "difficulty": 0.65, + "question": "在括号里填上\">\" \"<\"或\"=\".\n47 + 40 ( ) 51\n60 - 30 ( ) 90\n3 角 ( ) 30 分\n80 - 30 ( ) 60\n35 + 4 ( ) 39\n9 元 + 4 角 ( ) 10 元", + "options": [], + "answer": ">;<;=;<;=;<", + "solution": "【分析】整数的大小比较:比较数的大小,先看位数的多少,位数多的数就大;位数相同,从高位开始比较,高位上的数大则这个数大,高位上的数相同,就比较下一位。含有算式的大小比较,可以先计算出每个算式的结果,再比较大小;单位不统一时,先化成相同单位,再比较大小。1角=10分,1元=10角.\n【详解】47+40=87,故47+40>51;60-30=30,故60-30<90;3角=30分;80-30=50,故80-30<60;35+4=39,故35+4=39;9元+4角=94角,10元=100角,故9元+4角<10元。", + "knowledge_points": [ + "100 以内数的比大小,整十数之间的加减法,两位数与整十数的加法,元,角,分的认识及换算" + ], + "source": "23-24 一年级下·广东汕头·期末" + }, + { + "id": "152", + "unit": "第六单元100以内的加法和减法2", + "question_type": "填空题", + "difficulty": 0.85, + "question": "小东,小红,小丹他们在折纸星星,每人都折了 20 个,他们一共折了 ( )个纸星星。", + "options": [], + "answer": "60", + "solution": "【分析】将三人折的数量相加即可求出一共折的数量.\n【详解】 20 + 20 + 20 = 60 (个);他们一共折了 60 个纸星星。", + "knowledge_points": [ + "整十数之间的加减法" + ], + "source": "23-24 一年级下·广东汕头·期末" + }, + { + "id": "153", + "unit": "第六单元100以内的加法和减法2", + "question_type": "填空题", + "difficulty": 0.65, + "question": "比 56 多 9 的数是( );9 比 22 少( )。", + "options": [], + "answer": "65;13", + "solution": "【分析】求比一个数多几的数是多少,用这个数加多的数计算;求一个数比另一个数少几,用另一个数减这个数计算.\n【详解】56+9=65;22-9=13;比56多9的数是65;9比22少13。", + "knowledge_points": [ + "一位数与两位数的进位加法,一位数与两位数的退位减法" + ], + "source": "23-24 一年级下·广东汕头·期末" + }, + { + "id": "154", + "unit": "第六单元100以内的加法和减法2", + "question_type": "填空题", + "difficulty": 0.65, + "question": "有 27 块饼干, 5 块装一盒,能装满( )盒,还剩( )块。", + "options": [], + "answer": "5;2", + "solution": "【分析】根据题意,用饼干的总数量27块,依次减去每盒的数量5块,减到最后的数量不够装满一盒为止,减了几次5就能装满几盒,最后的得数就是还剩的数量.\n【详解】27-5=22;22-5=17;17-5=12;12-5=7;7-5=2。有27块饼干,5块装一盒,能装满5盒,还剩2块。", + "knowledge_points": [ + "100以内数的连减运算" + ], + "source": "23-24 一年级下·山东临沂·期末" + }, + { + "id": "155", + "unit": "第六单元100以内的加法和减法2", + "question_type": "填空题", + "difficulty": 0.65, + "question": "比 45 少 3 的数是( ), 28 比( )少 8。", + "options": [], + "answer": "42;36", + "solution": "【分析】求比一个数少几的数是多少,用这个数减少的数计算;已知一个数比另一个数少几,求另一个数,用这个数加少的数计算.\n【详解】45-3=42;28+8=36;比45少3的数是42,28比36少8。", + "knowledge_points": [ + "两位数与一位数的减法(不退位),一位数与两位数的进位加法" + ], + "source": "23-24 一年级下·山东临沂·期末" + }, + { + "id": "156", + "unit": "第六单元100以内的加法和减法2", + "question_type": "填空题", + "difficulty": 0.65, + "question": "猜一猜,填一填。我比 25 多 7,我是 ( );我比 25 少 7,我是 ( );42 比我大 20,我是 ( );我比最大的两位数小 8,我是 ( )。", + "options": [], + "answer": "32;18;22;91", + "solution": "【分析】求比一个数多多少的数用加法计算。求比一个数少多少的数用减法计算。已知一个数比另一个数大多少,求另一个数用减法计算。最大的两位数是 99,用 99 减 8 即可求解.\n【详解】 25 + 7 = 32;25 - 7 = 18;42 - 20 = 22;99 - 8 = 91;我比 25 多 7,我是 32;我比 25 少 7,我是 18;42 比我大 20,我是 22;我比最大的两位数小 8,我是 91。", + "knowledge_points": [ + "两位数与一位数的减法(不退位),两位数与整十数的减法,一位数与两位数的进位加法,一位数与两位数的退位减法" + ], + "source": "23-24一年级下·安徽淮南·期末" + }, + { + "id": "157", + "unit": "第六单元100以内的加法和减法2", + "question_type": "填空题", + "difficulty": 0.65, + "question": "40 里面有( )个十;2个一和6个十合起来是( );80前面的第一个数是( ),后面的第一个数是( )。", + "options": [], + "answer": "4;62;79;81", + "solution": "【分析】几十里面就有几个十;几个十是几十,几个一是几,合起来是几十几;80前面的第一个数,是比它小1的数,用减法计算;后面的第一个数是比它大 1 的数,用加法计算.\n【详解】2 个一是 2, 6 个十是 60,合起来是 62.80 - 1 = 79;80 + 1 = 81;40 里面有 4 个十;2 个一和 6 个十合起来是 62;80 前面的第一个数是 79,后面的第一个数是 81。", + "knowledge_points": [ + "100 以内数的组成,整十数加,减一位数,一位数与两位数的退位减法" + ], + "source": "23-24 一年级下·安徽淮南·期末" + }, + { + "id": "158", + "unit": "第六单元100以内的加法和减法2", + "question_type": "判断题", + "difficulty": 0.85, + "question": "计算 13 - (6 + 4) 时,应先计算减法,再计算加法。( )", + "options": [], + "answer": "×", + "solution": "【分析】含有小括号的混合运算,先算小括号里面,再算小括号外面的.\n【详解】由题意分析得:计算 13 - (6 + 4) 时,应先计算加法,再计算减法;原说法错误。故答案为: ×", + "knowledge_points": [ + "带有小括号的混合运算" + ], + "source": "23-24 一年级下·江西吉安·期末" + }, + { + "id": "159", + "unit": "第六单元100以内的加法和减法2", + "question_type": "判断题", + "difficulty": 0.65, + "question": "计算 78- (40-30) 时,既可以先算 78 - 40,也可以先算 40 - 30 。()", + "options": [], + "answer": "×", + "solution": "【分析】在一个有括号的算式里,要先算小括号里的,再算中括号里的,最后算括号外的.\n【详解】计算 78-(40-30)时,要先算括号里 40-30,然后再算括号外;不可以先算 78-40。故答案为: ×", + "knowledge_points": [ + "带有小括号的混合运算" + ], + "source": "23-24 一年级下·河南濮阳·期末" + }, + { + "id": "160", + "unit": "第六单元100以内的加法和减法2", + "question_type": "判断题", + "difficulty": 0.85, + "question": "被减数和减数都是90,差是 0 ( )", + "options": [], + "answer": "√", + "solution": "【分析】被减数减减数=差,据此计算得出结论即可.\n【详解】由题意可知:被减数和减数都是90。即:90-90=0,原题说法正确。故答案为:√", + "knowledge_points": [ + "两位数与整十数的减法" + ], + "source": "23-24 一年级下·河南三门峡·期末" + }, + { + "id": "161", + "unit": "第六单元100以内的加法和减法2", + "question_type": "计算题", + "difficulty": 0.85, + "question": "直接写出得数.\n13 - 6 = 14 + 9 = 4 + 40 = 10 + 70 = \n55 + 5 = 32 - 7 = 46 - 20 = 72 - 9 = \n14 + 6 + 42 = 52 + 40 - 7 = \n90 - (70 - 30) = 28 + (56 - 50) = ", + "options": [], + "answer": "7;23;44;80;60;25;26;63;62;85;50;34", + "solution": "【分析】 本题考查100以内数的加减法,包括不进位加,进位加,不退位减,退位减,连加连减及带小括号的两步运算。计算时要遵循运算顺序,有括号先算括号内;注意加减法中的进位与退位.\n【详解】 13减6得7;14加9得23;4加40得44;10加70得80;55加5得60;32减7得25;46减20得26;72减9得63;14加6再加42,先算14加6得20,再加42得62;52加40减7,先算52加40得92,再减7得85;90减括号里70减30的差,先算括号得40,再减得50;28加括号里56减50的差,先算括号得6,再加得34。", + "knowledge_points": [ + "整十数之间的加减法,一位数与两位数的进位加法,一位数与两位数的退位减法,带有小括号的混合运算" + ], + "source": "23-24 一年级下·河南郑州·期末" + }, + { + "id": "162", + "unit": "第六单元100以内的加法和减法2", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式计算.\n![](images/a30246aed203f2d20767549894b47bb2363912a2e2d4750df6c68ae5f8c1ccaa.jpg)\n□○□=□ (个)", + "options": [], + "answer": "32 + 10 = 42", + "solution": "【分析】把左边的桃子数量与右边的数量加起来,求出和,即可解决.\n【详解】由题意分析得:32 + 10 = 42 (个)", + "knowledge_points": [ + "图文问题,两位数与整十数的加法" + ], + "source": "23-24 一年级下·江西吉安·期末" + }, + { + "id": "163", + "unit": "第六单元100以内的加法和减法2", + "question_type": "计算题", + "difficulty": 0.85, + "question": "直接写出得数.\n92 - 50 = 75 - 30 = 80 - (33 - 3) =\n61 - (34 + 6) = 6 + 54 + 20 = 21 - 8 + 7 =", + "options": [], + "answer": "42;45;50;21;80;20", + "solution": "【分析】 本题主要考察100以内数的减法,连加和加减混合运算,特别包含带有小括号的运算。计算时需遵循\"有括号先算括号里\"的规则,再进行括号外的运算.\n【详解】 92减50得42;75减30得45;80减括号里33减3的差,先算括号得30,再减得50;61减括号里34加6的和,先算括号得40,再减得21;6加54再加20,先算6加54得60,再加20得80;21减8再加7,先算21减8得13,再加7得20。", + "knowledge_points": [ + "两位数与整十数的减法,100以内数的连加运算,100以内数的加减混合运算,带有小括号的混合运算" + ], + "source": "23-24 一年级下·江西吉安·期末" + }, + { + "id": "164", + "unit": "第六单元100以内的加法和减法2", + "question_type": "计算题", + "difficulty": 0.85, + "question": "直接写出得数.\n18 - 9 = 35 - 7 = 30 - 6 = 49 + 8 =\n39 + 2 = 45 - 2 = 36 + 8 = 40 + 50 =", + "options": [], + "answer": "9;28;24;57;41;43;44;90", + "solution": "【分析】 本题考查20和100以内数的加减法口算,包括退位减法,进位加法以及整十数加法。关键在于熟练掌握退位减时\"借1当10\"和进位加时\"满10进1\"的计算方法.\n【详解】 18减9得9;35减7得28;30减6得24;49加8得57;39加2得41;45减2得43;36加8得44;40加50得90。", + "knowledge_points": [ + "十几减 9 的退位减法,整十数之间的加减法,一位数与两位数的进位加法,一位数与两位数的退位减法" + ], + "source": "23-24 一年级下·江西吉安·期末" + }, + { + "id": "165", + "unit": "第六单元100以内的加法和减法2", + "question_type": "计算题", + "difficulty": 0.65, + "question": "看图列式计算.\n![](images/e2ae748d1b6fbb15f8654dc50f41c5933194e5651cb03c11df8ac6ee0e027bb9.jpg)\n□○□=□ (支)", + "options": [], + "answer": "30 - 4 = 26", + "solution": "【分析】根据减法的意义,用铅笔的总数量减去右边铅笔的数量即可求出左边文具盒里铅笔的数量,据此解答即可.\n【详解】 30 - 4 = 26 (支)所以左边文具盒里有 26 支铅笔。", + "knowledge_points": [ + "图文问题,一位数与两位数的退位减法" + ], + "source": "23-24 一年级下·河南濮阳·期末" + }, + { + "id": "166", + "unit": "第六单元100以内的加法和减法2", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式计算.\n![](images/b227d9e2967557ae8d9e9a6ea918b3de40a3d18644cc74db74456f27802c365e.jpg)\n□○□=□ (元)", + "options": [], + "answer": "86 - 30 = 56", + "solution": "【分析】用总钱数减去一顶帽子的钱数,求出差,就是一件上衣的钱数.\n【详解】由题意分析得:86 - 30 = 56 (元)", + "knowledge_points": [ + "图文问题,两位数与整十数的减法" + ], + "source": "23-24 一年级下·河南濮阳·期末" + }, + { + "id": "167", + "unit": "第六单元100以内的加法和减法2", + "question_type": "计算题", + "difficulty": 0.65, + "question": "看图列式计算.\n![](images/b8234f4b354b6fd6880025407f5fd4e89f64ccb7c969cc81589677b4cd3ee13a.jpg)\n□○□=□ (元)", + "options": [], + "answer": "70 + 22 = 92", + "solution": "【分析】根据题意分析,大括号下面打问号求的是总和,用左边书包的价格加上右边文具盒的价格即可.\n【详解】 70 + 22 = 92 (元)", + "knowledge_points": [ + "两位数与整十数的加法" + ], + "source": "23-24 一年级下·河南濮阳·期末" + }, + { + "id": "168", + "unit": "第六单元100以内的加法和减法2", + "question_type": "计算题", + "difficulty": 0.65, + "question": "直接写得数.\n15 - 8 = 26 - 7 = 5 + 30 = 30 + 60 = 24 + 50 = 59 + 9 = 64 - 20 = 78 - 5 = 16 - 9 + 2 = 45 - (38 - 8) =", + "options": [], + "answer": "7;19;35;90;74;68;44;73;9;15", + "solution": "【分析】 本题考查100以内数的加减法口算,涵盖退位减法,不进位加法,整十数加法以及含括号的混合运算。计算时需注意:减法判断是否退位,加法判断是否进位;有括号的要先算括号内;加减混合运算需按顺序计算.\n【详解】 15减8得7;26减7得19;5加30得35;30加60得90;24加50得74;59加9,个位满十向十位进1,得68;64减20得44;78减5得73;16减9再加2,先算16减9得7,再加2得9;45减括号里38减8的差,先算括号得30,再减得15。", + "knowledge_points": [ + "两位数与整十数的加法,两位数与整十数的减法,一位数与两位数的退位减法,100以内数的加减混合运算" + ], + "source": "23-24 一年级下·河南濮阳·期末" + }, + { + "id": "169", + "unit": "第六单元100以内的加法和减法2", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式计算.\n![](images/293e37444b07ec1978bdcfb34e27ecb7f0486f9dc4b70ee5361fc808551d95da.jpg)\n□○□=□ (朵)", + "options": [], + "answer": "43 - 10 = 33", + "solution": "【分析】根据减法的意义,总数量 43 朵,减去被拿走的 10 朵,得数就是还剩的数量.\n【详解】 43 - 10 = 33 (朵);还剩 33 朵。", + "knowledge_points": [ + "图文问题,两位数与整十数的减法" + ], + "source": "23-24 一年级下·福建福州·期末" + }, + { + "id": "170", + "unit": "第六单元100以内的加法和减法2", + "question_type": "计算题", + "difficulty": 0.65, + "question": "看图列式计算.\n![](images/f9b6d9220e6ba694e8913e918d4b3170e6d4c25768dbfafeaaebf679d000a702.jpg)\n□○□=□ (颗)", + "options": [], + "answer": "9 + 16 = 25", + "solution": "【分析】左边有 9 颗豆子,右边有 16 颗,求一共有多少颗,根据加法的意义,左边的数量 + 右边的数量 = 总数量.\n【详解】 9 + 16 = 25 (颗)一共有 25 颗。", + "knowledge_points": [ + "图文问题", + "一位数与两位数的进位加法" + ], + "source": "23-24 一年级下·福建福州·期末" + }, + { + "id": "171", + "unit": "第六单元100以内的加法和减法2", + "question_type": "计算题", + "difficulty": 0.85, + "question": "计算.\n40 + 28 - 50 = 50 + 14 - 8 = 56 - 7 - 20 =\n24 + (26 + 4) = 45 - (38 - 30) = 30 + (26 - 7) =", + "options": [], + "answer": "18;56;29;54;37;49", + "solution": "【分析】 本题主要考查100以内数的加减混合运算,特别包含带有小括号的运算。计算时需严格遵守运算顺序:没有括号的从左到右依次计算,有括号的要先算括号里面的,再算括号外面的.\n【详解】 40加28减50,先算40加28得68,再减50得18;50加14减8,先算50加14得64,再减8得56;56减7再减20,先算56减7得49,再减20得29;24加括号里26加4的和,先算括号得30,再加得54;45减括号里38减30的差,先算括号得8,再减得37;30加括号里26减7的差,先算括号得19,再加得49。", + "knowledge_points": [ + "100 以内数的加减混合运算", + "带有小括号的混合运算" + ], + "source": "23-24 一年级下·江西鹰潭·期末" + }, + { + "id": "172", + "unit": "第六单元100以内的加法和减法2", + "question_type": "计算题", + "difficulty": 0.65, + "question": "算一算.\n26 + 4 + 60 = 76 - 50 + 6 = 45 - (16 + 4) = 60 - (50 - 30) = 9 + (27 - 20) = 54 - 9 - 9 =", + "options": [], + "answer": "90;32;25;40;16;36", + "solution": "【分析】 本题考查100以内的加减混合运算及带括号的运算。计算时需遵循规则:没有括号的从左到右依次计算;有括号的先算括号内,再算括号外。同时需注意加法中的进位和减法中的退位.\n【详解】 26加4再加60,先算26加4得30,再加60得90;76减50再加6,先算76减50得26,再加6得32;45减括号里16加4的和,先算括号得20,再减得25;60减括号里50减30的差,先算括号得20,再减得40;9加括号里27减20的差,先算括号得7,再加得16;54减9再减9,先算54减9得45,再减9得36。", + "knowledge_points": [ + "一位数与两位数的进位加法", + "一位数与两位数的退位减法", + "100 以内数的加减混合运算", + "带有小括号的混合运算" + ], + "source": "23-24 一年级下·湖北黄冈·期末" + }, + { + "id": "173", + "unit": "第六单元100以内的加法和减法2", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式计算.\n![](images/d427b7af900d48599b3ed8be73b32aef71ed9759977bc4f1de737ca8f0c78478.jpg)\n□○□○□=□ (元)", + "options": [], + "answer": "52 - 10 - 8 = 34", + "solution": "【分析】用总钱数先减去一个笔盒的钱数,求出差,再减去一瓶墨水的钱数,求出差,就是一个书包的钱数.\n【详解】由题意分析得:52 - 10 - 8 = 42 - 8 = 34 (元)", + "knowledge_points": [ + "图文问题", + "100以内数的连减运算" + ], + "source": "23-24 一年级下·贵州铜仁·期末" + }, + { + "id": "174", + "unit": "第六单元100以内的加法和减法2", + "question_type": "计算题", + "difficulty": 0.65, + "question": "我会看图列式计算.\n![](images/ae7b7f38636f0df56e3ef34bd3827242e8fc6507c6a27803387174aacb19b9dc.jpg)\n□○□=□ (个)", + "options": [], + "answer": "15 + 7 = 22", + "solution": "【分析】左边足球的数量 + 右边排球的数量 = 球的总数量,据此列式计算即可.\n【详解】 15 + 7 = 22 (个)", + "knowledge_points": [ + "一位数与两位数的进位加法" + ], + "source": "23-24 一年级下·湖南长沙·期末" + }, + { + "id": "175", + "unit": "第六单元100以内的加法和减法2", + "question_type": "计算题", + "difficulty": 0.65, + "question": "我会看图列式计算.\n![](images/ab9dbd29782bad2e9ff17b361d543d7a2272f986a1f642be579f8c5d60c54f4f.jpg)\n□○□=□ (个)", + "options": [], + "answer": "76 - 20 = 56", + "solution": "【分析】总共的水果数量减苹果的数量=梨的数量,据此列式计算即可.\n【详解】76-20=56(个)", + "knowledge_points": [ + "图文问题", + "两位数与整十数的减法" + ], + "source": "23-24 一年级下·湖南长沙·期末" + }, + { + "id": "176", + "unit": "第六单元100以内的加法和减法2", + "question_type": "计算题", + "difficulty": 0.85, + "question": "算一算.\n7 + 8 = 9 + 3 = 2 + 34 = 63 + 7 = 52 = 50 + ()\n18 - 9 = 90 - 40 = 55 - 5 = 14 - 5 = 4 + ( ) = 15", + "options": [], + "answer": "15;12;36;70;2;9;50;50;9;11", + "solution": "【分析】 本题考查20以内和100以内数的加减法口算,以及简单的填空题。包括20以内的进位加法,退位减法,两位数与一位数的加法(含进位)和减法(不退位),整十数加减法,以及一道数的组成和一道括号填空.\n【详解】 7加8得15;9加3得12;2加34得36;63加7得70;52由50和2组成,故50加2得52;18减9得9;90减40得50;55减5得50;14减5得9;要使4加括号等于15,括号里应填11。", + "knowledge_points": [ + "十几减 5~2 的退位减法", + "整十数之间的加减法", + "两位数与一位数的减法(不退位)", + "一位数与两位数的进位加法" + ], + "source": "23-24 一年级下·福建福州·期末" + }, + { + "id": "177", + "unit": "第六单元100以内的加法和减法2", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式计算.\n![](images/a99d6555e25011ffbd59b5f28d00de6f037387960f8750e10b91c6210af620a8.jpg)\n□○□=□ (个)", + "options": [], + "answer": "35 - 7 = 28", + "solution": "【分析】根据减法的意义,用☆的总数量减去左边☆的数量即可求出右边箱子里☆的数量,据此解答即可.\n【详解】 35 - 7 = 28 (个)所以右边箱子里有 28 个☆。", + "knowledge_points": [ + "图文问题", + "一位数与两位数的退位减法" + ], + "source": "23-24 一年级下·河南南阳·期末" + }, + { + "id": "178", + "unit": "第六单元100以内的加法和减法2", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式计算.\n![](images/ca0d8c1c2e9e5a28fa2fba93e6e78db0b3972137bca474df269f7a57e1dab31e.jpg)\n□○□=□ (个)", + "options": [], + "answer": "64 - 5 = 59", + "solution": "【分析】根据减法的意义,用苹果的总数量减去左边苹果的数量即可求出右边筐子里苹果的数量,据此解答即可.\n【详解】 64 - 5 = 59 (个)所以右边筐子里有 59 个苹果。", + "knowledge_points": [ + "图文问题", + "一位数与两位数的退位减法" + ], + "source": "23-24 一年级下·河南南阳·期末" + }, + { + "id": "179", + "unit": "第六单元100以内的加法和减法2", + "question_type": "计算题", + "difficulty": 0.85, + "question": "直接写出得数.\n45 + 8 = 81 - 9 = 38 - 7 = 50 - 8 + 3 =\n3 + 85 = 55 + 6 = 89 + 3 = 66 + (15 - 7) =", + "options": [], + "answer": "53;72;31;45;88;61;92;74", + "solution": "【分析】 本题考查100以内数的加减法口算,包括不进位加法,进位加法,不退位减法,退位减法以及带括号的混合运算。计算时需注意:加法判断是否进位,减法判断是否退位;有括号的题要先算括号内的运算,再进行括号外的计算.\n【详解】 45加8得53;81减9得72;38减7得31;50减8再加3,先算50减8得42,再加3得45;3加85得88;55加6得61;89加3得92;66加括号里15减7的差,先算括号得8,再加得74。", + "knowledge_points": [ + "两位数与一位数的加法(不进位)", + "一位数与两位数的进位加法", + "一位数与两位数的退位减法", + "100 以内数的加减混合运算" + ], + "source": "23-24 一年级下·湖北黄石·期末" + }, + { + "id": "180", + "unit": "第六单元100以内的加法和减法2", + "question_type": "计算题", + "difficulty": 0.85, + "question": "计算.\n57 - 5 + 30 = 40 + 36 - 7 = 23 + (14 - 4) = 30 + (11 - 5) =", + "options": [], + "answer": "82;69;33;36", + "solution": "【分析】100以内加减混合运算中,没有括号时,从左到右依次计算;有括号时,先算括号里面的,再算括号外面的.\n【详解】57-5+30=52+30=82;40+36-7=76-7=69;23+(14-4)=23+10=33;30+(11-5)=30+6=36。", + "knowledge_points": [ + "100以内数的加减混合运算", + "带有小括号的混合 运算" + ], + "source": "23-24 一年级下·湖北孝感·期末" + }, + { + "id": "181", + "unit": "第六单元100以内的加法和减法2", + "question_type": "计算题", + "difficulty": 0.85, + "question": "算一算.\n22 ── -7 ──> [ ] ── +30 ──> [ ] ── -9 ──> [ ] ── -20 ──> [ ] ── -4 ──> [ ]\n21 ── +30 ──> [ ] ── -6 ──> [ ] ── +8 ──> [ ] ── -30 ──> [ ] ── +5 ──> [ ]", + "options": [], + "answer": "15;45;36;16;12;51;45;53;23;28", + "solution": "【分析】我们根据第一个箭头上的运算符号和数进行相应的运算得到第二个数,再依次计算即可.\n【详解】22-7=15;15+30=45;45-9=36;36-20=16;16-4=12;21+30=51;51-6=45;45+8=53;53-30=23;23+5=28。填空如下:![](images/57f3ec7c5195e838eba3e9b8b020f656d1393c3b0cb7eaf3583d5f4b4decfb9c.jpg)", + "knowledge_points": [ + "两位数与一位数的加法(不进位)", + "两位数与整十数的加法", + "两位数与整十数的减法", + "一位数与两位数的退位减法" + ], + "source": "23-24 一年级下·湖北孝感·期末" + }, + { + "id": "182", + "unit": "第六单元100以内的加法和减法2", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看谁算的都对!\n25 + 8 = 10 + 36 = 60 - 10 = 50 - (30 + 20) =\n62 - 9 = 7 + 33 = 86 - 7 = 87 - (17 - 9) =", + "options": [], + "answer": "33;46;50;0;53;40;79;79", + "solution": "【分析】 本题考查100以内数的加减法口算,包括进位加法,退位减法,整十数减法以及含括号的混合运算。计算时需注意:加法要判断进位,减法要判断退位;有括号的题要先算括号内.\n【详解】 25加8得33;10加36得46;60减10得50;50减括号里30加20的和,先算括号得50,再减得0;62减9得53;7加33得40;86减7得79;87减括号里17减9的差,先算括号得8,再减得79。", + "knowledge_points": [ + "整十数之间的加减法", + "一位数与两位数的进位加法", + "一位数与两位数的退位减法" + ], + "source": "23-24 一年级下·湖北恩施·期末" + }, + { + "id": "183", + "unit": "第六单元100以内的加法和减法2", + "question_type": "计算题", + "difficulty": 0.85, + "question": "直接写出得数.\n60 - 5 = 18 + 7 = 15 - 6 = 3 + 4 + 20 = 98 - 6 = 26 + 50 =\n56 + 5 = 58 - 8 + 45 = 76 - 7 = 39 - 6 = 71 + 8 = 90 - (46 - 6) =", + "options": [], + "answer": "55;25;9;27;92;76;61;95;69;33;79;50", + "solution": "【分析】 本题考查100以内的口算,题型多样,包括退位减法,进位加法,连加,加减混合运算及带括号的运算。计算时需遵循相应顺序,并注意进位与退位.\n【详解】 60减5得55;18加7得25;15减6得9;3加4再加20,先算3加4得7,再加20得27;98减6得92;26加50得76;56加5得61;58减8再加45,先算58减8得50,再加45得95;76减7得69;39减6得33;71加8得79;90减括号里46减6的差,先算括号得40,再减得50。", + "knowledge_points": [ + "一位数与两位数的进位加法", + "一位数与两位数的退位减法", + "100以内数的加减混合运算", + "带有小括号的混合运算" + ], + "source": "23-24 一年级下·湖南岳阳·期末" + }, + { + "id": "184", + "unit": "第六单元100以内的加法和减法2", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式计算.\n![](images/f69bd30eb19515dc70b9fea5b0acbad871162d523b5f868ecc8a2fcf3efdc1a5.jpg)\n□○□=□ (个)", + "options": [], + "answer": "37 + 6 = 43", + "solution": "【分析】根据加法的意义,用左边筐子里苹果的数量加上右边苹果的数量即可求出苹果的总数量,据此解答即可.\n【详解】 37 + 6 = 43 (个)所以一共有 43 个苹果。", + "knowledge_points": [ + "图文问题", + "一位数与两位数的进位加法" + ], + "source": "23-24 一年级下·河南南阳·期末" + }, + { + "id": "185", + "unit": "第六单元100以内的加法和减法2", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式计算.\n![](images/147009b0f8d10cf34b3e4b1ab6824c2c226ddfab71366e4406e5f6abee377b52.jpg)\n□○□=□ (只)", + "options": [], + "answer": "35 - 6 = 29", + "solution": "【分析】根据减法的意义,用兔子的总数量减去右边兔子的数量即可求出左边房子里兔子的数量,据此解答即可.\n【详解】 35 - 6 = 29 (只);所以左边房子里有 29 只兔子。", + "knowledge_points": [ + "图文问题", + "一位数与两位数的退位减法" + ], + "source": "23-24 一年级下·河南南阳·期末" + }, + { + "id": "186", + "unit": "第六单元100以内的加法和减法2", + "question_type": "解答题", + "difficulty": 0.65, + "question": "32 个桃子, 9 个装满一篮.\n![](images/8b36be673cd20cc948987f5656b81936006a7c435c0f19d18638964ceef28ed0.jpg)", + "options": [], + "answer": "3篮", + "solution": "【分析】有 32 个桃子, 9 个装满一篮,能装满几篮。 只需\n要求出 32 里有几个 9 即可,可连续减 9,能减几次,就有几个 9 .\n【详解】 32 - 9 = 23 (个)23 - 9 = 14 (个)14 - 9 = 5 (个)答:能装满 3 篮。", + "knowledge_points": [ + "十几减 9 的退位减法", + "一位数与两位数的退位减法" + ], + "source": "23-24 一年级下·江西吉安·期末" + }, + { + "id": "187", + "unit": "第六单元100以内的加法和减法2", + "question_type": "解答题", + "difficulty": 0.65, + "question": "天天和红红看一本同样的书.\n![](images/14d164c2f71bab98b09c251714017d5947f0a6a48553935a69d232df2cf4b0d7.jpg)\n(1) 这本书一共有多少页。\n(2) 天天比红红多看了多少页。", + "options": [], + "answer": "53页;25页", + "solution": "【分析】(1)用天天已经看的页数加上没看的页数,即可求出这本书一共有多少页(2) 用天天已经看的页数减去红红已经看的页数,即可求出天天比红红多看了多少页.\n【详解】 (1) 45 + 8 = 53 (页)答:这本书一共有53页。(2) 45 - 20 = 25 (页)答:天天比红红多看了 25 页。", + "knowledge_points": [ + "两位数与整十数的减法", + "一位数与两位数的进位加法" + ], + "source": "23-24 一年级下·江西吉安·期末" + }, + { + "id": "188", + "unit": "第六单元100以内的加法和减法2", + "question_type": "解答题", + "difficulty": 0.85, + "question": "三个小朋友投沙包比赛.\n![](images/131059.png)\n(1) 小丽比小亮多投了 5 分米,小丽投了多少分米。\n(2) 小明和小亮一共投了多少分米。", + "options": [], + "answer": "43分米;78分米", + "solution": "【分析】(1)用小亮投的长度加上 5 分米,求出和,就是小丽投了多少分米.\n(2) 求小明和小亮一共投了多少分米,就是求两个数的和,用加法列式解决.\n【详解】 (1) 38 + 5 = 43 (分米)答:小丽投了 43 分米。(2) 40 + 38 = 78 (分米)答:小明和小亮一共投了 78 分米。", + "knowledge_points": [ + "两位数与整十数的加法", + "一位数与两位数的进位加法" + ], + "source": "23-24 一年级下·江西吉安·期末" + }, + { + "id": "189", + "unit": "第六单元100以内的加法和减法2", + "question_type": "解答题", + "difficulty": 0.65, + "question": "学校有 33 个足球, 5 个装一筐,可以装满几筐。 还剩下几个。", + "options": [], + "answer": "6筐;3个", + "solution": "【分析】根据减法的意义,用足球的总数量33个依次减去每筐能装的数量5个,直到减不动为止,减了几次就是最多可以装满几筐,剩下的减不动的数就是还剩下的足球的数量.\n【详解】33-5-5-5-5-5-5=3(个)。一共减了6次,所以可以装满6筐,还剩下3个。答:可以装满6筐,还剩下3个。", + "knowledge_points": [ + "100以内数的连减运算" + ], + "source": "23-24 一年级下·河南濮阳·期末" + }, + { + "id": "190", + "unit": "第六单元100以内的加法和减法2", + "question_type": "解答题", + "difficulty": 0.65, + "question": "吃松果。小灰和小白一共还有多少个松果。小白:我吃了20个松果,还剩9个松果。小灰:小白我吃了8个松果,还剩26个松果。□ ○ □ = □ (个)答:小灰和小白一共还有 ()个松果。", + "options": [], + "answer": "9 + 26 = 35;35", + "solution": "【分析】求一共还有多少个松果,用加法计算,即小灰还剩的松果数量 + 小白还剩的松果数量 = 它们一共还有的松果数量.\n【详解】 9 + 26 = 35 (个)答:小灰和小白一共还有 35 个松果。", + "knowledge_points": [ + "图文问题", + "一位数与两位数的进位加法" + ], + "source": "23-24 一年级下·福建福州·期末" + }, + { + "id": "191", + "unit": "第六单元100以内的加法和减法2", + "question_type": "解答题", + "difficulty": 0.85, + "question": "学校买来28个![](images/89ff7a10dc1a2b959ae522ca4c50a7a29cfe4161f99c7eb1369af42db041affd.jpg),一(1)班借走4个,一(2)班借走6个,还剩多少个。", + "options": [], + "answer": "18个", + "solution": "【分析】用学校买来的数量减去一(1)班和一(2)班一共借走的数量,即可求出还剩多少个.\n【详解】28-(4+6)=28-10=18(个)。答:还剩18个。", + "knowledge_points": [ + "带有小括号的混合运算" + ], + "source": "23-24一年级下·浙江嘉兴·期末" + }, + { + "id": "192", + "unit": "第六单元100以内的加法和减法2", + "question_type": "解答题", + "difficulty": 0.65, + "question": "天天和阳阳一起做了58个风车,其中彩色的有8个,天天做了30个,阳阳做了多少个。", + "options": [], + "answer": "28个", + "solution": "【分析】根据题意,用天天和阳阳一起做的风车的总数减去天天做的风车的数量,即可求出阳阳做了多少个。用减法列式计算.\n【详解】 58 - 30 = 28 (个)答:阳阳做了 28 个。", + "knowledge_points": [ + "两位数与整十数的减法" + ], + "source": "23-24 一年级下·浙江嘉兴·期末" + }, + { + "id": "193", + "unit": "第六单元100以内的加法和减法2", + "question_type": "解答题", + "difficulty": 0.65, + "question": "明明有 27 只恐龙玩具, 5 只装一袋,可以装满几袋。 还剩几只。 请你在下面先圈一圈,再算一算.\n![](images/2c6ee6d6d4d56cf66e41b288423ea1f4e3bcd36bd33c80a698f4c52ff07bff2a.jpg)\n列式:答:可以装满()袋,还剩()只。", + "options": [], + "answer": "图见详解;27-5-5-5-5-5=2(只);5;2", + "solution": "【分析】5 只恐龙玩具圈一个圈,一共能圈 5 个圈。根据减法的意义,用恐龙玩具的总数量 27 只依次减去每袋能装的数量 5 只,直到减不动为止,减了几次就是最多可以装满几袋,剩下的减不动的数就是还剩下的恐龙玩具的数量.\n【详解】作图如下:![](images/1a431a6a3c05239b93ab04b1e2a2a79564f5c1b2a8c691804f819d315c12a9e9.jpg)列式: 27 - 5 - 5 - 5 - 5 - 5 = 2 (只)一共减了 5 次,所以可以装满 5 袋,还剩下 2 只。答:可以装满 5 袋,还剩 2 只。", + "knowledge_points": [ + "图文问题", + "100以内数的连减运算" + ], + "source": "23-24一年级下·山西晋中·期末" + }, + { + "id": "194", + "unit": "第六单元100以内的加法和减法2", + "question_type": "解答题", + "difficulty": 0.65, + "question": "捡贝壳比赛.\n![](images/131349.png)\n(1) 捡到的贝壳个数越多名次越好,请把他们的名次填在上面的表中.\n(2) 王力比小欣多捡了多少个贝壳。", + "options": [], + "answer": "第二名;第四名;第一名;第三名;69个", + "solution": "【分析】(1)两位数比较大小,十位上大的数就大,如果十位上的数相同,个位上大的数就大。据此将各数排序即可;(2) 根据减法的意义,用王力捡的贝壳的数量减去小欣捡的贝壳的数量即可求出王力比小欣多捡的贝壳的数量.\n【详解】 (1) 81 > 76 > 60 > 7填空如下:\n\n| 姓名 | 王力 | 小欣 | 张强 | 小文 |\n| ---- | ------ | ------ | ------ | ------ |\n| 个数 | 76个 | 7个 | 81个 | 60个 |\n| 名次 | 第二名 | 第四名 | 第一名 | 第三名 |\n\n(2) 76 - 7 = 69 (个)答:王力比小欣多捡了 69 个贝壳。", + "knowledge_points": [ + "100 以内数的比大小", + "一位数与两位数的退位减法" + ], + "source": "23-24 一年级下·湖北孝感·期末" + }, + { + "id": "195", + "unit": "第六单元100以内的加法和减法2", + "question_type": "解答题", + "difficulty": 0.65, + "question": "购物.\n![](images/a916b1ebb5cf8c0b81d5f567af8a999a.png)\n(1) 毛笔比帽子便宜多少钱。\n(2) 买 4 个羽毛球需要多少钱。\n(3) 你还能提出其他数学问题并解答吗。", + "options": [], + "answer": "5元4角;16元;台灯比篮球贵多少元,15元", + "solution": "【分析】(1)根据减法的意义,帽子的价格减毛笔的价格=毛笔比帽子便宜的钱数,计算时元和元相减,角和角相减;(2)每个羽毛球的价格相加4次,就是4个羽毛球需要的钱数;(3)提出的问题符合题意即可,可提出台灯比篮球贵多少元。用减法计算.\n【详解】(1)13元4角-8元=5元4角。答:毛笔比帽子便宜5元4角。(2)4+4+4+4=16(元)。答:买4个羽毛球需要16元钱。(3)台灯比篮球贵多少元。(答案不唯一)55-40=15(元)。答:台灯比篮球贵15元。", + "knowledge_points": [ + "\"提问题\"\"填条件\"问题", + "连加(20以内)", + "两位数与整十数的减法", + "十元以上人民币的认识与计算" + ], + "source": "23-24一年级下·河南南阳·期末" + }, + { + "id": "196", + "unit": "第六单元100以内的加法和减法2", + "question_type": "解答题", + "difficulty": 0.85, + "question": "我国首艘国产航母山东号在某次演习中,甲板上停了36架舰载机,从甲板上起飞9架舰载机后,甲板上还剩多少架。", + "options": [], + "answer": "27架", + "solution": "【分析】根据减法的意义,甲板上停的舰载机的总数量减起飞的数量=甲板上还剩的舰载机数量.\n【详解】36-9=27(架)。答:甲板上还剩27架。", + "knowledge_points": [ + "一位数与两位数的退位减法" + ], + "source": "23-24一年级下·河南南阳·期末" + }, + { + "id": "197", + "unit": "第六单元100以内的加法和减法2", + "question_type": "解答题", + "difficulty": 0.65, + "question": "明明第一个月存了 5 元钱,计划以后每个月都比前一个月多存 2 元钱, 4 个月一共可以存多少钱。", + "options": [], + "answer": "32元", + "solution": "【分析】用这个月的钱数加 2 即可得到下一个月的钱数,分别计算出每个月存的钱数,然后将 4 个月的相加即可求出 4 个月一共可以存多少钱.\n【详解】 5 + 2 = 7 (元)7 + 2 = 9 (元)9 + 2 = 11 (元)5 + 7 + 9 + 11 = 32 (元)答: 4 个月一共可以存 32 元钱。", + "knowledge_points": [ + "100 以内数的连加运算" + ], + "source": "23-24一年级下·山东济南·期末" + }, + { + "id": "198", + "unit": "第六单元100以内的加法和减法2", + "question_type": "解答题", + "difficulty": 0.65, + "question": "教室里原有30人,出去了8人,又进来5人。教室里现在有多少人。", + "options": [], + "answer": "27人", + "solution": "【分析】原有的人数减去出去的人数,再加上进来的人数即可得到现在的人数.\n【详解】 30 - 8 + 5 = 27 (人)答:教室里现在有 27 人。", + "knowledge_points": [ + "100以内数的加减混合运算" + ], + "source": "23-24一年级下·江西鹰潭·期末" + }, + { + "id": "199", + "unit": "第六单元100以内的加法和减法2", + "question_type": "解答题", + "difficulty": 0.65, + "question": "一(1)班图书角一共有 84 本书,其中故事书有 40 本,今天借出 5 本书,图书角还剩多少本书。", + "options": [], + "answer": "79本", + "solution": "【分析】求还剩多少本书,用减法计算,即图书的总数量减借出的数量=还剩的数量.\n【详解】 84 - 5 = 79 (本);答:图书角还剩 79 本书。", + "knowledge_points": [ + "一位数与两位数的退位减法" + ], + "source": "23-24 一年级下·江西鹰潭·期末" + }, + { + "id": "200", + "unit": "第六单元100以内的加法和减法2", + "question_type": "解答题", + "difficulty": 0.65, + "question": "小红看一本书,看了 62 页,还有 20 页没看,这本书一共有多少页。", + "options": [], + "answer": "82页", + "solution": "【分析】用看了的页数加还没看的页数即可求出这本书一共有多少页.\n【详解】 62 + 20 = 82 (页);答:这本书一共有82页。", + "knowledge_points": [ + "两位数与整十数的加法" + ], + "source": "23-24一年级下·广东汕头·期末" + }, + { + "id": "201", + "unit": "第六单元100以内的加法和减法3", + "question_type": "选择题", + "difficulty": 0.65, + "question": "有 5 位老师和 42 名学生去看表演,其中有 30 名男同学,女同学有多少名。 正确的列式为 ( )。", + "options": [ + "A. 5 + 42 - 30", + "B. 42 - 30", + "C. 5 + 42 + 30" + ], + "answer": "B", + "solution": "【分析】根据题意,用学生的总人数减去其中的男同学的人数,即可求出女同学的人数.\n【详解】 42 - 30 = 12 (名)所以女同学有 12 名。故答案为: B", + "knowledge_points": [ + "两位数与整十数的减法" + ], + "source": "23-24一年级下·河南南阳·期末" + }, + { + "id": "202", + "unit": "第六单元100以内的加法和减法3", + "question_type": "选择题", + "difficulty": 0.85, + "question": "有 20 个梨, 30 个桃,65 个苹果,其中苹果比梨多 ( ) 个。", + "options": [ + "A. 15", + "B. 45", + "C. 35", + "D. 20" + ], + "answer": "B", + "solution": "【分析】求苹果比梨多几个,根据减法的意义,苹果的数量减梨的数量=苹果比梨多的数量.\n【详解】65-20=45(个)。苹果比梨多45个。故答案为:B", + "knowledge_points": [ + "两位数与整十数的减法" + ], + "source": "23-24一年级下·山东临沂·期末" + }, + { + "id": "203", + "unit": "第六单元100以内的加法和减法3", + "question_type": "选择题", + "difficulty": 0.65, + "question": "蛋糕房做了 28 个蛋挞,每 8 个装一盒,能装满 ( ) 盒。", + "options": [ + "A. 4", + "B. 3", + "C. 2" + ], + "answer": "B", + "solution": "【分析】根据题意,用蛋挞的总数量依次减去 8,减到最后的数量不够装满一盒为止,减了几次 8 就能装满几盒.\n【详解】 28 - 8 = 20 (个)20 - 8 = 12 (个)12 - 8 = 4 (个)减了 3 次 8,能装满 3 盒。故答案为: B", + "knowledge_points": [ + "十几减8的退位减法", + "两位数与一位数的减法(不退位)", + "一位数与两位数的退位减法" + ], + "source": "23-24一年级下·山西长治·期末" + }, + { + "id": "204", + "unit": "第六单元100以内的加法和减法3", + "question_type": "选择题", + "difficulty": 0.65, + "question": "七巧板的价钱是( )。![](images/46caf9c29b09c85111b7bfa4b2157b69.png)买这副七巧板,我用了3张10元纸币,找回了5元。", + "options": [ + "A. 15元", + "B. 25元", + "C. 30元" + ], + "answer": "B", + "solution": "【分析】根据题意,先用加法计算出一共付出了多少钱,再减去找回的钱数,就是七巧板的价钱.\n【详解】 10 + 10 + 10 = 30 (元)30 - 5 = 25 (元)七巧板的价钱是 25 元。故答案为: B", + "knowledge_points": [ + "整十数之间的加减法", + "一位数与两位数的退位减法", + "十元以上人民币的认识与计算", + "用七巧板拼图形" + ], + "source": "23-24 一年级下·山西长治·期末" + }, + { + "id": "205", + "unit": "第六单元100以内的加法和减法3", + "question_type": "选择题", + "difficulty": 0.85, + "question": "小宇看一本70页的书,第一天看了20页,第二天看了30页,还剩多少页没有看。 下面列式错误的是 ( )。", + "options": [ + "A. 70 - 20 - 30", + "B. 70 - 20 + 30", + "C. 70 - (20+30)" + ], + "answer": "B", + "solution": "【分析】用整本书的总页数先减去第一天看了的页数,求出差,再减去第二天看了的页数,求出差,就是还剩没看的页数;也可以先用加法计算两天一共看了多少页,然后用总页数减去看了的页数,求出差,就是还剩没看的页数;据此解决.\n【详解】由题意分析得:小宇看一本70页的书,第一天看了20页,第二天看了30页,还剩多少页没有看。可以这样列式计算: 70 - 20 - 30或 70 - (20 + 30);但这样列式 (70 - 20 + 30) 是错误的。故答案为: B", + "knowledge_points": [ + "100以内数的连减运算", + "100以内数的加减混合运算", + "带有小括号的混合运算" + ], + "source": "23-24一年级下·湖北武汉·期末" + }, + { + "id": "206", + "unit": "第六单元100以内的加法和减法3", + "question_type": "选择题", + "difficulty": 0.85, + "question": "妈妈买肉花了 10 元,买梨花了 7 元,妈妈拿了 20 元钱,应找回 ( )。", + "options": [ + "A. 10元", + "B. 3元", + "C. 17元" + ], + "answer": "B", + "solution": "【分析】根据减法的意义,妈妈拿的钱数减买梨花的钱数减买肉花的钱数=应找回的钱数.\n【详解】20-7-10=3(元)。应找回3元。故答案为:B", + "knowledge_points": [ + "100 以内数的连减运算" + ], + "source": "23-24 一年级下·河南商丘·期末" + }, + { + "id": "207", + "unit": "第六单元100以内的加法和减法3", + "question_type": "选择题", + "difficulty": 0.65, + "question": "□ + 8 < 49 , □ 里最大填 ( )。", + "options": [ + "A. 40", + "B. 41", + "C. 30" + ], + "answer": "A", + "solution": "【分析】根据题意分析,要想□+8<49,□里填最大的数,那□+8就要最大,但要小于49,所以□+8=48,所以□=48-8=40.\n【详解】48-8=40。故答案为:A", + "knowledge_points": [ + "两位数与一位数的减法(不退位)" + ], + "source": "23-24 一年级下·湖南邵阳·期末" + }, + { + "id": "208", + "unit": "第六单元100以内的加法和减法3", + "question_type": "选择题", + "difficulty": 0.65, + "question": "小丽做了 30 朵红花和 15 朵黄花,小林至少要做 ( ) 朵花才能超过小丽。", + "options": [ + "A. 44", + "B. 45", + "C. 46" + ], + "answer": "C", + "solution": "【分析】先求出小丽做的花的总数,即 30 + 15 = 45 (朵),要想小林做的花的数量超过小丽,那小林做的花的数量就得比 45 大,所以至少得做 46 朵.\n【详解】 30 + 15 = 45 (朵)44 < 45, 45 = 45, 46 > 45;所以小林至少要做 46 朵花才能超过小丽。故答案为: C", + "knowledge_points": [ + "两位数与整十数的加法" + ], + "source": "23-24一年级下·湖南邵阳·期末" + }, + { + "id": "209", + "unit": "第六单元100以内的加法和减法3", + "question_type": "选择题", + "difficulty": 0.85, + "question": "算式中 4 和 5 能直接相加的是 ( )。", + "options": [ + "A. 25 + 4", + "B. 34 + 50", + "C. 47 + 5" + ], + "answer": "A", + "solution": "【分析】计算整数加法时,相同数位上的数可以直接相加,不同数位上的数不能直接相加,由此解答.\n【详解】A.25+4:5在个位,4在个位,可以直接相加;B.34+50:4在个位,5在十位,不能直接相加;C.47+5:4在十位,5在个位,不能直接相加。算式中4和5能直接相加的是25+4。故答案为:A", + "knowledge_points": [ + "两位数与一位数的加法(不进位)", + "两位数与整十数的加法", + "一位数与两位数的进位加法" + ], + "source": "23-24 一年级下·吉林·期末" + }, + { + "id": "210", + "unit": "第六单元100以内的加法和减法3", + "question_type": "选择题", + "difficulty": 0.85, + "question": "一顶帽子 10 元,妈妈用 50 元买了 3 顶帽子,应找回 ( ) 元。", + "options": [ + "A. 20", + "B. 40", + "C. 30" + ], + "answer": "A", + "solution": "【分析】根据题意,先用加法计算出3顶帽子一共需要多少钱,再用妈妈带的钱数减帽子的总钱数=应找回的钱数.\n【详解】 10 + 10 + 10 = 30 (元)50 - 30 = 20 (元)应找回20元。故答案为: A", + "knowledge_points": [ + "整十数之间的加减法", + "十元以上人民币的认识与计算" + ], + "source": "23-24一年级下·河南信阳·期末" + }, + { + "id": "211", + "unit": "第六单元100以内的加法和减法3", + "question_type": "填空题", + "difficulty": 0.85, + "question": "和 90 相邻的数是( )和( ),它们都是( )位数。", + "options": [], + "answer": "89;91;两", + "solution": "【分析】相邻的两个数相差 1,左边的数比右边的数小 1,右边的数比左边的数大 1;一个整数,有几个数字组成就是几位数;据此解决.\n【详解】 90 - 1 = 8990 + 1 = 91;即,和 90 相邻的数是 89 和 91,它们都是两位数。", + "knowledge_points": [ + "100以内数的排序", + "100以内数的组成", + "整十数加,减一位数", + "一位数与两位数的退位减法", + "相邻的数" + ], + "source": "23-24 一年级下·湖北武汉·期末" + }, + { + "id": "212", + "unit": "第六单元100以内的加法和减法3", + "question_type": "填空题", + "difficulty": 0.65, + "question": "在 ( ) 填上 '>' '<' 或 '=' .\n45( ) 54\n58-20( ) 38\n2元1角-9角( )1元5角", + "options": [], + "answer": "<;=;<", + "solution": "【分析】比较数的大小时,位数多的数就大;位数相同比较最高位,最高位大的数就大;最高位相同比较下一位,直到比较出结果为止。第1题:直接比较;第2题:计算出结果再比较;第3题:根据1元=10角统一单位后计算再比较.\n【详解】45<54;58-20=38;2元1角=1元+11角;1元11角-9角=1元2角=12角;1元5角=15角;12角<15角,则2元1角-9角<1元5角。", + "knowledge_points": [ + "100以内数的比大小", + "两位数与整十数的减法", + "元,角,分的认识及换算", + "十元以下人民币的认识与计算" + ], + "source": "23-24 一年级下·山东临沂·期末" + }, + { + "id": "213", + "unit": "第六单元100以内的加法和减法3", + "question_type": "填空题", + "difficulty": 0.85, + "question": "有48颗珠子,每10颗穿一串,最多可以穿( )串。", + "options": [], + "answer": "4", + "solution": "【分析】根据题意,用珠子的总数量 48 颗,依次减去每串的数量 10 颗,减到最后的数量不够一串为止,减了几次 10,就能穿几串.\n【详解】 48 - 10 = 38 (颗)38 - 10 = 28 (颗)28 - 10 = 18 (颗)18 - 10 = 8 (颗)有 48 颗珠子,每 10 颗穿一串,最多可以穿 4 串。", + "knowledge_points": [ + "两位数与整十数的减法" + ], + "source": "23-24一年级下·广东汕头·期末" + }, + { + "id": "214", + "unit": "第六单元100以内的加法和减法3", + "question_type": "填空题", + "difficulty": 0.65, + "question": "在()里填\">\"\"<\"或\"=\".\n72-9( )63\n53( )39+10\n61+9( )59+9\n1元( )1角\n4个十( )4个一\n5个十( )51", + "options": [], + "answer": "=;>;>;>;<", + "solution": "【分析】整数的大小比较:比较数的大小,先看位数的多少,位数多的数就大;位数相同,从高位开始比较,高位上的数大则这个数大,高位上的数相同,就比较下一位。几个十就是几十,几个一就是几。含有算式的大小比较,可以先计算出每个算式的结果,再比较大小;单位不统一时,先化成相同单位,再比较大小。1元=10角.\n【详解】72-9=63,所以72-9=63;39+10=49,所以53>39+10;61+9=70,59+9=68,所以61+9>59+9;1元=10角,所以1元>1角;4个十是40,4个一是4,所以4个十>4个一;5个十是50,所以5个十<51。", + "knowledge_points": [ + "100 以内数的比大小", + "100 以内数的组成", + "一位数与两位数的退位减法", + "元,角,分的认识及换算" + ], + "source": "23-24一年级下·湖南岳阳·期末" + }, + { + "id": "215", + "unit": "第六单元100以内的加法和减法3", + "question_type": "填空题", + "difficulty": 0.85, + "question": "43 比 20 多( );比 77 少 5 的数是( )。", + "options": [], + "answer": "23;72", + "solution": "【分析】求一个数比另一个数多几,用这个数减多的数计算;求比一个数少几的数是多少,用这个数减少的数计算.\n【详解】 43 - 20 = 23;77 - 5 = 72;43 比 20 多 23;比 77 少 5 的数是 72。", + "knowledge_points": [ + "两位数与一位数的减法(不退位)", + "两位数与整十数的减法" + ], + "source": "23-24 一年级下·湖南岳阳·期末" + }, + { + "id": "216", + "unit": "第六单元100以内的加法和减法3", + "question_type": "填空题", + "difficulty": 0.85, + "question": "( )+30=62\n90-( )=60\n( )+6=20-6", + "options": [], + "answer": "32;30;8", + "solution": "【分析】根据和减一个加数=另一个加数;被减数减差=减数计算即可.\n【详解】62-30=32,则32+30=62;90-60=30,则90-30=60;20-6=14;14-6=8,则8+6=20-6。", + "knowledge_points": [ + "十几减 7,6 的退位减法", + "整十数之间的加减法", + "两位数与整十数的减法", + "一位数与两位数的退位减法" + ], + "source": "23-24 一年级下·湖北恩施·期末" + }, + { + "id": "217", + "unit": "第六单元100以内的加法和减法3", + "question_type": "填空题", + "difficulty": 0.65, + "question": "兰兰看一本故事书,第一天看了 10 页,第二天看了 25 页,第三天兰兰应从第( )页开始看。", + "options": [], + "answer": "36", + "solution": "【分析】先算出兰兰第一天和第二天一共看了多少页,然后从下一页看起即可.\n【详解】 10 + 25 = 35 (页)35 + 1 = 36 (页)第三天兰兰应从第36页开始看。", + "knowledge_points": [ + "两位数与一位数的加法(不进位)", + "两位数与整十数的加法" + ], + "source": "23-24 一年级下·河南周口·期末" + }, + { + "id": "218", + "unit": "第六单元100以内的加法和减法3", + "question_type": "填空题", + "difficulty": 0.65, + "question": "在括号里填上\">\" \"<\"或\"=\".\n3元( )2元9角\n9元( )9角9分\n3元5角( )53角\n60+7( )67\n23-20( )32-20\n54+7( )54-7", + "options": [], + "answer": ">;>;<;=;<;>", + "solution": "【分析】根据整数加减法的计算法则,依次计算出各算式的结果再比较大小。比较时,位数多的数就大;位数相同比较最高位,最高位大的数就大;最高位相同比较下一位,直到比较出结果为止。人民币的题目先统一单位再比较.\n【详解】1元 = 10 角;3元 = 30 角;2元9角 = 29 角;30角 > 29 角,则3元 > 2 元9角;9元 >1 元;1元 = 100 分;9角9分 = 99 分;100分 >99 分,则9元 >9 角9分;3元5角 = 35 角;35角 < 53 角,则3元5角 < 53 角;60 + 7 = 67;23 - 20 = 3;32 - 20 = 12;3 < 12,则 23 - 20 < 32 - 20; 54 + 7 = 61;54 - 7 = 47;61 > 47,则 54 + 7 > 54 - 7 。", + "knowledge_points": [ + "100 以内数的比大小", + "一位数与两位数的进位加法", + "一位数与两位数的退位减法", + "元,角,分的认识及换算" + ], + "source": "23-24 一年级下·福建漳州·期末" + }, + { + "id": "219", + "unit": "第六单元100以内的加法和减法3", + "question_type": "填空题", + "difficulty": 0.85, + "question": "在括号里填上\">\"\"<\"或\"=\".\n52( )60-9\n99-20( )79\n46+4( )40\n74-8( )73-6\n89( )30+55\n60+10( )70", + "options": [], + "answer": ">;=;>;<;>;=", + "solution": "【分析】先计算出每个算式的结果,然后比较大小即可。整数比较大小方法: ①位数多的数大于位数少的数;②位数相同的,先比较最高位上的数,最高位上大的,数就大,最高位数相同的,就比较下一位,以此类推.\n【详解】 60 - 9 = 51,故, 52 > 60 - 9;99 - 20 = 79;46 + 4 = 50,故, 46 + 4 > 40;74 - 8 = 66, 73 - 6 = 67,故, 74 - 8 < 73 - 6;30 + 55 = 85,故, 89 > 30 + 55;60 + 10 = 70 。", + "knowledge_points": [ + "100以内数的比大小", + "两位数与整十数的减法", + "一位数与两位数的进位加法", + "一位数与两位数的退位减法" + ], + "source": "23-24一年级下·湖北黄冈·期末" + }, + { + "id": "220", + "unit": "第六单元100以内的加法和减法3", + "question_type": "填空题", + "difficulty": 0.65, + "question": "一堆小球,十个十个地数,数了 5 次多 6 个,五个五个地数,可以数( )次多( )个。", + "options": [], + "answer": "11;1", + "solution": "【分析】根据题意,先用加法计算出一共有多少个小球,\n再用小球的总数量依次减去 5,减了几次 5 就是可以数几次,最后的得数就是还多的数量.\n【详解】 10 + 10 + 10 + 10 + 10 + 6 = 56 (个)一堆小球,十个十个地数,数了 5 次多 6 个,五个五个地数,可以数 11 次多 1 个。", + "knowledge_points": [ + "100以内数的连加运算", + "100以内数的连减运算" + ], + "source": "23-24 一年级下·湖北黄冈·期末" + }, + { + "id": "221", + "unit": "第六单元100以内的加法和减法3", + "question_type": "填空题", + "difficulty": 0.85, + "question": "在括号里填上\">\" \"<\"或\"=\".\n78-40( )74\n26+7( )36-7\n5角( )5元\n3元9角( )4元", + "options": [], + "answer": "<;>;<;<", + "solution": "【分析】先计算出每个算式的结果或先统一单位,然后比较大小即可。整数比较大小方法:①位数多的数大于位数少的数;②位数相同的,先比较最高位上的数,最高位上大的,数就大,最高位数相同的,就比较下一位,以此类推。1元=10角.\n【详解】78-40=38,故78-40<74;26+7=33,36-7=29,故26+7>36-7;5元=50角,故5角<5元;3元9角=39角,4元=40角,故3元9角<4元。", + "knowledge_points": [ + "100 以内数的比大小", + "一位数与两位数的进位加法", + "一位数与两位数的退位减法", + "元,角,分的认识及换算" + ], + "source": "23-24 一年级下·山东菏泽·期末" + }, + { + "id": "222", + "unit": "第六单元100以内的加法和减法3", + "question_type": "填空题", + "difficulty": 0.85, + "question": "在括号里填上合适的数.\n7+( )=14\n15-( )=6\n9+5=( )-3\n( )-7=9\n99-( )=9\n78-( )=76-6", + "options": [], + "answer": "7;9;17;16;90;8", + "solution": "【分析】根据被减数减减数=差,加数加加数=和,结合加法和减法互为逆运算,结合题干要求进行解答即可.\n【详解】14-7=7,所以7+7=14,括号内填7;15-6=9,所以15-9=6,括号内填9;9+5=14,14+3=17,所以9+5=17-3,括号内填17;9+7=16,所以16-7=9,括号内填16;99-9=90,所以99-90=9,括号内填90;76-6=70,78-70=8,所以78-8=76-6,括号内填8。", + "knowledge_points": [ + "9 加几的进位加法", + "7,6 加几的进位加法", + "两位数与一位数的减法(不退位)", + "两位数与整十数的减法" + ], + "source": "23-24 一年级下·河南南阳·期末" + }, + { + "id": "223", + "unit": "第六单元100以内的加法和减法3", + "question_type": "填空题", + "difficulty": 0.85, + "question": "12比5多( );6比15少( );比79多1的数是( )。", + "options": [], + "answer": "7;9;80", + "solution": "【分析】求一个数比另一个数多(少)多少,用减法列式计算;求比一个数多几的数是多少,用加法列式计算.\n【详解】12-5=7;15-6=9;79+1=80。即,12比5多7;6比15少9;比79多1的数是80。", + "knowledge_points": [ + "十几减 7,6 的退位减法", + "十几减 5 ~ 2 的退位减法", + "一位数与两位数的进位加法" + ], + "source": "23-24一年级下·河南南阳·期末" + }, + { + "id": "224", + "unit": "第六单元100以内的加法和减法3", + "question_type": "填空题", + "difficulty": 0.65, + "question": "李叔叔买了3盒月饼,每盒8个,一共买了( )个月饼。", + "options": [], + "answer": "24", + "solution": "【分析】求一共买了多少个月饼,用加法计算,即将 3 盒月饼的数量依次相加即可.\n【详解】 8 + 8 + 8 = 24 (个)李叔叔买了3盒月饼,每盒8个,一共买了24个月饼。", + "knowledge_points": [ + "100 以内数的连加运算" + ], + "source": "23-24一年级下·山东菏泽·期末" + }, + { + "id": "225", + "unit": "第六单元100以内的加法和减法3", + "question_type": "填空题", + "difficulty": 0.65, + "question": "在括号里填\">\"\"<\"或\"=\".\n85( )58\n3角5分( )3元5角\n13-7( )7\n99( )100\n79角( )7元9角\n26+50( )31", + "options": [], + "answer": ">;<;<;<;=;>", + "solution": "【分析】(1)数比较大小:数位不同,数位多的那个数就大,数位相同从最高位开始比,最高位哪个数字大,这个数就大;(2) 根据元,角,分之间的进率, 1 元 = 10 角, 1 角 = 10 分,将单位统一后再进行比较;(3) 将 13 - 7 的结果计算出来,再与 7 进行比较;(4) 数比较大小:数位不同,数位多的那个数就大,数位相同从最高位开始比,最高位哪个数字大,这个数就大;(5) 根据元,角之间的进率, 1 元 = 10 角,将单位统一后再进行比较;(6) 将 26 + 50 的结果计算出来,再与 31 进行比较即可.\n【详解】 (1) 85 最高位是 8, 58 最高位是 5, 8 > 5,所以 85 > 58;(2) 1 元 = 10 角, 3 元 = 30 角, 30 + 5 = 35 (角), 3 角 5 分 < 35 角,所以 3 角 5 分 < 3 元 5 角;(3) 13 - 7 = 6, 6 < 7,所以 13 - 7 < 7;(4) 99 是两位数, 100 是三位数,三位数要大于两位数,所以 99 < 100;(5) 1 元 = 10 角, 7 元 = 70 角, 70 + 9 = 79 (角), 79 角 = 79 角,所以 7 元 9 角 = 79 角;(6) 26 + 50 = 76, 76 > 31,所以 26 + 50 > 31 。", + "knowledge_points": [ + "100 以内数的比大小", + "十几减 7,6 的退位减法", + "两位数与整十数的加法", + "元,角,分的认识及换算" + ], + "source": "23-24一年级下·山东菏泽·期末" + }, + { + "id": "226", + "unit": "第六单元100以内的加法和减法3", + "question_type": "填空题", + "difficulty": 0.65, + "question": "( )比 7 多 56,15比( )多6,( )减去8是38。", + "options": [], + "answer": "63;9;46", + "solution": "【分析】求比一个数多几的数是多少,用这个数加多的数计算;已知一个数比另一个数多几,求另一个数,用这个数减多的数计算;已知一个数减另一个数得几,求这个数用另一个数加得数计算.\n【详解】7+56=63;15-6=9;8+38=46;63比7多56,15比9多6,46减去8是38。", + "knowledge_points": [ + "十几减 7,6 的退位减法", + "一位数与两位数的进位加法" + ], + "source": "23-24 一年级下·山东菏泽·期末" + }, + { + "id": "227", + "unit": "第六单元100以内的加法和减法3", + "question_type": "填空题", + "difficulty": 0.85, + "question": "60 比( )大 1,比 50 小 3 的数是( )。", + "options": [], + "answer": "59;47", + "solution": "【分析】据题意可知,求 60 比多少大 1,可用 60 减去 1 即可得出答案;求比 50 小 3 的数是多少,可用 50 减去 3 即可得出答案.\n【详解】 60 - 1 = 59;50 - 3 = 4760 比 59 大 1,比 50 小 3 的数是 47 。", + "knowledge_points": [ + "两位数与一位数的减法(不退位)" + ], + "source": "23-24 一年级下·湖南邵阳·期末" + }, + { + "id": "228", + "unit": "第六单元100以内的加法和减法3", + "question_type": "填空题", + "difficulty": 0.65, + "question": "15 比 9 多( );比43少3的数是( );( )比28少20;36比( )多6。", + "options": [], + "answer": "6;40;8;30", + "solution": "【分析】求一个数比另一个数多多少,用这个数减另一个数计算;求比一个数少几的数是多少,用这个数减少的数计算;已知一个数比另一个数多几,求另一个数,用这个数减多的数计算.\n【详解】15-9=6;43-3=40;28-20=8;36-6=30;15比9多6;比43少3的数是40;8比28少20;36比30多6。", + "knowledge_points": [ + "十几减9的退位减法", + "两位数与一位数的减法(不退位)", + "两位数与整十数的减法" + ], + "source": "23-24 一年级下·四川凉山·期末" + }, + { + "id": "229", + "unit": "第六单元100以内的加法和减法3", + "question_type": "填空题", + "difficulty": 0.65, + "question": "小明和小雨共折了 27 朵花,其中有 6 朵红花,小雨折了 9 朵花,小明折了 ( )朵花。", + "options": [], + "answer": "18", + "solution": "【分析】根据减法的意义,小明和小雨一共折的数量减小雨折的数量=小明折的数量.\n【详解】27-9=18(朵)。小明和小雨共折了27朵花,其中有6朵红花,小雨折了9朵花,小明折了18朵花。", + "knowledge_points": [ + "一位数与两位数的退位减法" + ], + "source": "23-24 一年级下·四川凉山·期末" + }, + { + "id": "230", + "unit": "第六单元100以内的加法和减法3", + "question_type": "填空题", + "difficulty": 0.65, + "question": "在括号里填上\">\" \"<\"或\"=\".\n7+8( )16\n76-6( )70\n4元2角( )42元\n46-7( )40\n54+9( )65-8\n3元( )30角", + "options": [], + "answer": "<;=;<;<;>;=", + "solution": "【分析】根据整数加减法的计算法则,依次计算出各算式的结果再比较大小。比较时,位数多的数就大;位数相同比较最高位,最高位大的数就大;最高位相同比较下一位,直到比较出结果为止。人民币的题目先统一单位再比较.\n【详解】 7 + 8 = 15;15 < 16,则 7 + 8 < 16;76 - 6 = 70;4元2角<42元;46 - 7 = 39;39 < 40,则 46 - 7 < 40;54 + 9 = 63;65 - 8 = 57;63 > 57,则 54 + 9 > 65 - 8;1元 = 10 角,则 3 元 = 30 角。", + "knowledge_points": [ + "100 以内数的比大小", + "一位数与两位数的进位加法", + "一位数与两位数的退位减法", + "元,角,分的认识及换算" + ], + "source": "23-24 一年级下·河南商丘·期末" + }, + { + "id": "231", + "unit": "第六单元100以内的加法和减法3", + "question_type": "填空题", + "difficulty": 0.65, + "question": "在括号里填上 \">\" \"<\" 或 \"=\".\n39-4( )36\n68-40( )28\n76-8( )67\n87-30( )49\n94-7( )88\n53-9( )45", + "options": [], + "answer": "<;=;>;<;<;<", + "solution": "【分析】根据整数加减法的计算法则,依次计算出各算式的结果再比较大小。比较时,位数多的数就大;位数相同比较最高位,最高位大的数就大;最高位相同比较下一位,直到比较出结果为止.\n【详解】 39 - 4 = 35;35 < 36,则 39 - 4 < 36;68 - 40 = 28;76 - 8 = 68;68 > 67,则 76 - 8 > 67;87 - 30 = 57;57 > 49,则 87 - 30 > 49; 94 - 7 = 87;87 < 88,则 94 - 7 < 88;53 - 9 = 44;44 < 45,则 53 - 9 < 45 。", + "knowledge_points": [ + "100 以内数的比大小", + "两位数与一位数的减法(不退位)", + "两位数与整十数的减法", + "一位数与两位数的退位减法" + ], + "source": "23-24 一年级下·河南商丘·期末" + }, + { + "id": "232", + "unit": "第六单元100以内的加法和减法3", + "question_type": "填空题", + "difficulty": 0.65, + "question": "有 49 个苹果,每 10 个装一箱,可以装满( )箱。", + "options": [], + "answer": "4", + "solution": "【分析】根据题意,用苹果的总数量依次减去 10,减到最后的数量不够装满 1 箱为止,减了几次 10 就能装满几箱.\n【详解】 49 - 10 = 39 (个)39 - 10 = 29 (个)29 - 10 = 19 (个)19 - 10 = 9 (个)有 49 个苹果,每 10 个装一箱,可以装满 4 箱。", + "knowledge_points": [ + "两位数与整十数的减法" + ], + "source": "23-24 一年级下·河南商丘·期末" + }, + { + "id": "233", + "unit": "第六单元100以内的加法和减法3", + "question_type": "填空题", + "difficulty": 0.65, + "question": "在括号里填上\">\" \"<\"或\"=\".\n83( )38\n9个十( )9个一\n27+5( )30+2\n50分( )5元\n69+30( )69+3\n56-6-20( )56", + "options": [], + "answer": ">;>;=;<;>;<", + "solution": "【分析】(1)数比较大小:数位不同,数位多的那个数就大,数位相同从最高位开始比,最高位哪个数字大,这个数就大;(2)先将数写出来,然后再按照数的比较大小方法进行比较即可;(3)将27+5和30+2的结果计算出来,再进行比较即可;(4)根据元,角,分之间的进率,1元=10角,1角=10分,进行单位统一,再进行比较;(5)将69+30和69+3的结果计算出来,再进行比较即可;(6)将56-6-20的结果计算出来,再进行比较即可.\n【详解】(1)83最高位是8,38最高位是3,8>3,所以83>38;(2)9个十是90,9个一是9,90>9,所以9个十>9个一;(3)27+5=32,30+2=32,32=32,所以27+5=30+2;(4)1角=10分,则50分=5角,1元=10角,则5元=50角,5角<50角,所以50分<5元;(5)69+30=99,69+3=72,99>72,所以69+30>69+3;(6)56-6-20=30,30<56,所以56-6-20<56。", + "knowledge_points": [ + "100 以内数的比大小", + "两位数与整十数的加法", + "一位数与两位数的进位加法", + "元,角,分的认识及换算" + ], + "source": "23-24一年级下·河南信阳·期末" + }, + { + "id": "234", + "unit": "第六单元100以内的加法和减法3", + "question_type": "填空题", + "difficulty": 0.65, + "question": "在括号里填上合适的数.\n35 + ( ) = 42 ( ) - 40 = 15\n37 + ( ) = 45 - 5 ( ) + 20 = 56", + "options": [], + "answer": "7;55;3;36", + "solution": "【分析】第1题:35后面的数依次为:36,37,38,39,40,41,42,也就是往后数7个数是42,即35+7=42;第2题:根据减数+差=被减数计算;第3题:先计算出右侧算式的结果,再看37往后数几个数是这个结果,就是加上几;第4题:根据和减一个加数=另一个加数计算.\n【详解】35+7=42;40+15=55,则55-40=15;45-5=40;37往后数3个数是40,即37+3=45-5;56-20=36,则36+20=56。", + "knowledge_points": [ + "两位数与一位数的减法(不退位)", + "两位数与整十数的减法", + "一位数与两位数的进位加法" + ], + "source": "23-24 一年级下·吉林·期末" + }, + { + "id": "235", + "unit": "第六单元100以内的加法和减法3", + "question_type": "填空题", + "difficulty": 0.65, + "question": "有 46 块月饼,每 10 块装一盒,最多能装满( )盒。再拿来( )块月饼就正好装满 5 盒。", + "options": [], + "answer": "4;4", + "solution": "【分析】根据题意,月饼的总数量依次减去 10,减到最后的数量不够装满 1 盒为止,减了几次 10 就能装满几盒;要想装满 5 盒,若只差 1 盒,则将剩余的月饼数量凑成 10 块;若差 2 盒,则剩余的数量凑成 10 块后再加上 1 盒的块数。由此解答.\n【详解】 46 - 10 = 36 (块);36 - 10 = 26 (块);26 - 10 = 16 (块);16 - 10 = 6 (块);减了4次10,能装满4盒,还差1盒够5盒,将剩余的数量凑成10块即可。 10 - 6 = 4 (块);有46块月饼,每10块装一盒,最多能装满4盒。再拿来4块月饼就正好装满5盒。", + "knowledge_points": [ + "两位数与整十数的减法" + ], + "source": "23-24 一年级下·吉林·期末" + }, + { + "id": "236", + "unit": "第六单元100以内的加法和减法3", + "question_type": "填空题", + "difficulty": 0.65, + "question": "一张 20 元可以换( )张 5 元,一张 100 元可以换( )张 20 元。", + "options": [], + "answer": "4;5", + "solution": "【分析】用 1 张 20 元可以换几张 5 元,就看 20 里面有几个 5 即可。用 1 张 100 元可以换几张 20 元,就看 100 里面有几个 20 即可.\n【详解】 5 + 5 + 5 + 5 = 20 (元)20 + 20 + 20 + 20 + 20 = 100 (元)所以一张 20 元可以换 4 张 5 元,一张 100 元可以换 5 张 20 元。", + "knowledge_points": [ + "100以内数的连加运算", + "十元以上人民币的认识与计算" + ], + "source": "23-24一年级下·广东佛山·期末" + }, + { + "id": "237", + "unit": "第六单元100以内的加法和减法3", + "question_type": "填空题", + "difficulty": 0.65, + "question": "在括号里填上 '>' '<' 或 '='.\n54-9( )55\n58+6( )64\n88-8( )80\n2元( )19角\n8角+3角( )1元\n3元-2元5角( )2元", + "options": [], + "answer": "<;=;>;>;>;<", + "solution": "【分析】根据整数加减法的计算法则,依次计算出各算式的结果再比较大小。比较时,位数多的数就大;位数相同比较最高位,最高位大的数就大;最高位相同比较下一位,直到比较出结果为止。人民币的题目先统一单位再计算比较.\n【详解】54-9=45;45<55,则54-9<55;58+6=64;88-8=80;1元=10角;2元=20角;20角>19角,则2元>19角;8角+3角=11角;11角>10角,则8角+3角>1元;3元-2元5角=5角;2元=20角;5角<20角,则3元-2元5角<2元。", + "knowledge_points": [ + "100以内数的比大小", + "一位数与两位数的进位加法", + "一位数与两位数的退位减法", + "十元以下人民币的认识与计算" + ], + "source": "23-24 一年级下·山西长治·期末" + }, + { + "id": "238", + "unit": "第六单元100以内的加法和减法3", + "question_type": "填空题", + "difficulty": 0.65, + "question": "弟弟有12块乐高,哥哥再给弟弟6块后,两人就同样多,哥哥原有( )块乐高。", + "options": [], + "answer": "24", + "solution": "【分析】根据题意,哥哥给弟弟 6 块后,他们同样多。用弟弟的数量 + 哥哥给弟弟的数量,计算出此时弟弟有多少块,也就是哥哥此时有多少块,再加上哥哥给弟弟的数量,就是哥哥原有的数量.\n【详解】 12 + 6 = 18 (块)18 + 6 = 24 (块)弟弟有 12 块乐高,哥哥再给弟弟 6 块后,两人就同样多,哥哥原有 24 块乐高。", + "knowledge_points": [ + "不进位加法(20以内)", + "一位数与两位数的进位加法" + ], + "source": "23-24一年级下·山西长治·期末" + }, + { + "id": "239", + "unit": "第六单元100以内的加法和减法3", + "question_type": "填空题", + "difficulty": 0.85, + "question": "在括号里填上合适的数.\n13+( )=19\n40-( )=30\n10+( )=18+20\n50-40>( )\n( )+7<24\n22-( )>15", + "options": [], + "answer": "6;10;28;9;16;6", + "solution": "【分析】根据\"加数=和减另一个加数,减数=被减数减差\"及整数加减法的计算法则和整数比较大小的方法来解决此题。整数比较大小方法:①位数多的数大于位数少的数;②位数相同的,先比较最高位上的数,最高位上大的,数就大,最高位数相同的,就比较下一位,以此类推.\n【详解】19-13=6,故13+6=19;40-30=10,故40-10=30;18+20=38,38-10=28,故10+28=18+20;50-40=10,10>9,故50-40>9;16+7=23,23<24,故16+7<24;22-6=16,16>15,故22-6>15。(后3个空,答案不唯一)", + "knowledge_points": [ + "100 以内数的比大小", + "整十数之间的加减法", + "两位数与整十数的减法", + "一位数与两位数的进位加法" + ], + "source": "23-24 一年级下·湖北武汉·期末" + }, + { + "id": "240", + "unit": "第六单元100以内的加法和减法3", + "question_type": "填空题", + "difficulty": 0.85, + "question": "在括号里填上\">\" \"<\"或\"=\".\n79( )59-20\n78-30( )30+8\n36+9( )63+9\n10角( )100分\n4元5角( )45角\n1元-3角( )7元", + "options": [], + "answer": ">;>;<;=;=;<", + "solution": "【分析】先计算出每个算式的结果或先统一单位,然后比较大小即可。整数比较大小方法:①位数多的数大于位数少的数;②位数相同的,先比较最高位上的数,最高位上大的,数就大,最高位数相同的,就比较下一位,以此类推。1角=10分,1元=10角.\n【详解】59-20=39,故79>59-20;78-30=48,30+8=38,故78-30>30+8;36+9=45,63+9=72,故36+9<63+9;1角=10分,故10角=100分;4元5角=45角;1元=10角,10角-3角=7角,故1元-3角<7元。", + "knowledge_points": [ + "100 以内数的比大小", + "两位数与整十数的减法", + "一位数与两位数的进位加法", + "元,角,分的认识及换算" + ], + "source": "23-24 一年级下·湖北武汉·期末" + }, + { + "id": "241", + "unit": "第六单元100以内的加法和减法3", + "question_type": "填空题", + "difficulty": 0.65, + "question": "在括号里填上 \">\" \"<\" 或 \"=\" .\n78( )87\n20+9( )30\n73-3( )70\n93( )69\n19-4( )14\n11-9( )11-8", + "options": [], + "answer": "<;<;=;>;>;<", + "solution": "【分析】(1)数比较大小:数位不同,数位多的那个数就大,数位相同从最高位开始比,最高位哪个数字大,这个数就大;(2)将20+9的结果计算出来与30进行比较即可;(3)将73-3的结果计算出来与70进行比较即可;(4)数比较大小:数位不同,数位多的那个数就大,数位相同从最高位开始比,最高位哪个数字大,这个数就大;(5)将19-4的结果计算出来与14进行比较即可;(6)将11-9和11-8的结果计算出来,再进行比较即可.\n【详解】(1)78最高位是7,87最高位是8,7<8,所以78<87;(2)20+9=29,29<30,所以20+9<30;(3)73-3=70,70=70,所以73-3=70;(4)93最高位是9,69最高位是6,9>6,所以93>69;(5)19-4=15,15>14,所以19-4>14;(6)11-9=2,11-8=3,2<3,所以11-9<11-8。", + "knowledge_points": [ + "100 以内数的比大小", + "十几减 9 的退位减法", + "十几减 8 的退位减法", + "两位数与一位数的减法(不退位)" + ], + "source": "23-24 一年级下·河南南阳·期末" + }, + { + "id": "242", + "unit": "第六单元100以内的加法和减法3", + "question_type": "填空题", + "difficulty": 0.65, + "question": "和是 73,一个加数是 8,另一个加数是( )。", + "options": [], + "answer": "65", + "solution": "【分析】加法算式为加数加加数=和,求其中一个加数可用和减一个加数=另一个加数计算.\n【详解】73-8=65。和是73,一个加数是8,另一个加数是65。", + "knowledge_points": [ + "一位数与两位数的退位减法" + ], + "source": "23-24 一年级下·湖北黄冈·期末" + }, + { + "id": "243", + "unit": "第六单元100以内的加法和减法3", + "question_type": "填空题", + "difficulty": 0.85, + "question": "在括号里填上合适的数.\n7+( )=53\n64-( )=20\n( )-8=51\n( )+( )=60\n( )<80+9\n53>( )>42\n40=46-( )\n28+( )=28-( )", + "options": [], + "answer": "46;44;59;30;30;80;50;6;0;0", + "solution": "【分析】据题意可知,题目中出现加减法的计算,已知加数与和求另一个加数,用和减去已知加数即可;已知被减数和差,用被减数减去差即可得出减数;已知减数与差,两者相加即可得出被减数,再按照加减法的计算法则进行计算即可.\n【详解】7+46=53;64-44=20;59-8=51;30+30=60;80<89,括号内填80;53>50>42;40=46-6;28+0=28-0。", + "knowledge_points": [ + "一位数与两位数的进位加法", + "一位数与两位数的退位减法" + ], + "source": "23-24 一年级下·四川凉山·期末" + }, + { + "id": "244", + "unit": "第六单元100以内的加法和减法3", + "question_type": "填空题", + "difficulty": 0.65, + "question": "在括号里填上\">\"\"<\"或\"=\".\n55+3( )83\n45+1( )52-6\n3张5元( )2张10元\n86-30( )86-50\n40个一( )4个十\n5元6角+9角( )7元-6角", + "options": [], + "answer": "<;=;<;>;=;>", + "solution": "【分析】单位不统一的根据单位间的进率先换算统一单位,1元=10角;有算式大小的比较要先计算出得数,再比较得数的大小;比较大小时,数位多的数就大;数位相同比较最高位,最高位大的数就大;最高位相同比较下一位,依次类推,直到比较出结果为止。据此解答即可.\n【详解】55+3=58,58<83,故55+3<83;45+1=46,52-6=46,46=46,故45+1=52-6;3张5元是15元,2张10元是20元,15<20,故3张5元<2张10元;86-30=56,86-50=36,56>36,故86-30>86-50;40个一是40,4个十是40,40=40,故40个一=4个十;5元6角+9角=56角+9角=65角,7元-6角=70角-6角=64角,65>64,故5元6角+9角>7元-6角。", + "knowledge_points": [ + "100 以内数的比大小", + "一位数与两位数的进位加法", + "一位数与两位数的退位减法", + "十元以下人民币的认识与计算" + ], + "source": "23-24一年级下·四川凉山·期末" + }, + { + "id": "245", + "unit": "第六单元100以内的加法和减法3", + "question_type": "填空题", + "difficulty": 0.65, + "question": "计算 12 - 9 时,可以这样想:先算 ( ) - 9 = 1,再算 1 + () = ();也可以这样想:因为 9 + ( ) = 12,所以 12 - 9 =( ) 。计算 45 + 20 时,可以这样想:先算( ),再算( )。", + "options": [], + "answer": "10;2;3;3;3;40 + 20 = 60;60 + 5 = 65", + "solution": "【分析】计算 12 - 9 时,可将 12 分成 10 和 2,先计算出 10 -9 的结果,再和 2 相加即可;也可以想 9 和 1 合起来就是 10,再加 2 就是 12,也就是 9 和 3 合起来是 12,则 12 减 9 就等于 3;计算 45 + 20 时,可将 45 分成 40 和 5,先计算出 40 + 20 的和,再加上 5 即可.\n【详解】计算 12 - 9 时,可以这样想:先算 10 - 9 = 1,再算 1 + 2 = 3;也可以这样想:因为 9 + 3 = 12,所以 12 - 9 = 3 。计算 45 + 20 时,可以这样想:先算 40 + 20 = 60,再算 60 + 5 = 65 。", + "knowledge_points": [ + "十几减9的退位减法", + "两位数与整十数的加法" + ], + "source": "23-24 一年级下·四川凉山·期末" + }, + { + "id": "246", + "unit": "第六单元100以内的加法和减法3", + "question_type": "填空题", + "difficulty": 0.65, + "question": "两个加数都是 20,和是( );被减数是65,减数是7,差是( )。", + "options": [], + "answer": "40;58", + "solution": "【分析】加法算式为:加数加加数 = 和;减法算式为:被减数 - 减数 = 差,由此代入计算.\n【详解】 20 + 20 = 40;65 - 7 = 58两个加数都是 20,和是 40;被减数是 65,减数是 7,差是 58。", + "knowledge_points": [ + "整十数之间的加减法", + "一位数与两位数的退位减法" + ], + "source": "23-24 一年级下·四川凉山·期末" + }, + { + "id": "247", + "unit": "第六单元100以内的加法和减法3", + "question_type": "填空题", + "difficulty": 0.85, + "question": "括号藏着几。\n( )-30=7\n47+( )=67\n( )+( )=66", + "options": [], + "answer": "37;20;30;36", + "solution": "【分析】第1题:根据减数 + 差 = 被减数计算;第2题:47里面有4个十和7个一,67里面有6个十和7个一,47再加上2个十就是67,也就是再加上20是67;第3题:两个数相加的结果是66即可,答案不唯一.\n【详解】 30 + 7 = 37,则 37 - 30 = 747 + 20 = 67;30 + 36 = 66 。(答案不唯一)", + "knowledge_points": [ + "两位数与整十数的加法", + "两位数与整十数的减法" + ], + "source": "23-24 一年级下·河北石家庄·期末" + }, + { + "id": "248", + "unit": "第六单元100以内的加法和减法3", + "question_type": "填空题", + "difficulty": 0.65, + "question": "在括号里填上合适的数.\n40+( )=60\n( )+6=53\n( )-30=5\n7+( )=17\n( )-8=16\n25+20=5+( )", + "options": [], + "answer": "20;47;35;10;24;40", + "solution": "【分析】根据和减一个加数=另一个加数;减数加差=被减数计算即可.\n【详解】60-40=20,则40+20=60;53-6=47,则47+6=53;30+5=35,则35-30=5;17-7=10,则7+10=17;8+16=24,则24-8=16;25+20=45;45-5=40,则25+20=5+40。", + "knowledge_points": [ + "整十数之间的加减法", + "一位数与两位数的进位加法", + "一位数与两位数的退位减法" + ], + "source": "23-24 一年级下·河南商丘·期末" + }, + { + "id": "249", + "unit": "第六单元100以内的加法和减法3", + "question_type": "填空题", + "difficulty": 0.85, + "question": "一个两位数,十位上是最大的一位数,个位上是 2,这个数是( ),与它相邻的两个数是( )和( )。", + "options": [], + "answer": "92;91;93", + "solution": "【分析】一个两位数,从右往左依次为个位,十位。最大的一位数是 9,由此将数字写在对应数位上即可。与它相邻的数,也就是比它小 1 的数,用这个数 -1 计算,和比它大 1 的数,用这个数 +1 计算.\n【详解】 92 - 1 = 91;92 + 1 = 93;一个两位数,十位上是最大的一位数,个位上是 2,这个数是 92,与它相邻的两个数是 91 和 93。", + "knowledge_points": [ + "100 以内数的组成", + "两位数与一位数的加法(不进位)", + "两位数与一位数的减法(不退位)", + "相邻的数" + ], + "source": "23-24一年级下·河南商丘·期末" + }, + { + "id": "250", + "unit": "第六单元100以内的加法和减法3", + "question_type": "填空题", + "difficulty": 0.65, + "question": "在 ( ) 里填上相同的数.\n30 - ( ) = ( ) + 2436 + ( ) = 46 - ( )", + "options": [], + "answer": "3;3;5;5", + "solution": "【分析】第 1 题: 30 减去这个数等于 24 加上这个数,也就是 30 比 24 多的数等于这两个相同数的和;第2题:36加上这个数等于46减去这个数,也就是46比36 多的数等于这两个相同数的和.\n【详解】30 倒着数 6 个数是 24,也就是 30 比 24 多 6;6 = 3 + 3,即 30 - 3 = 3 + 24 = 27;46 倒着数 10 个数是 36,也就是 46 比 36 多 10;10 = 5 + 5,即 36 + 5 = 46 - 5 = 41 。", + "knowledge_points": [ + "两位数与一位数的加法(不进位)", + "两位数与一位数的减法(不退位)", + "一位数与两位数的进位加法", + "一位数与两位数的退位减法" + ], + "source": "23-24 一年级下·广东佛山·期末" + }, + { + "id": "251", + "unit": "第六单元100以内的加法和减法3", + "question_type": "填空题", + "difficulty": 0.65, + "question": "括号里最大能填几。\n( )-9<11\n76>( )+70\n6+( )<19", + "options": [], + "answer": "19;5;12", + "solution": "【分析】因为11+9=20,所以空格里最大的即为比20小1的数,20-1=19;因为76>70+5,76>( )+70中括号里最大填5;因为6+12=18<19,所以6+( )<19中括号里最大填12.\n【详解】19-9<11;76>5+70;6+12<19。", + "knowledge_points": [ + "100 以内数的比大小", + "不退位减法(20 以内)", + "两位数与整十数的减法", + "一位数与两位数的进位加法" + ], + "source": "22-23 一年级下·广东汕头·期末" + }, + { + "id": "252", + "unit": "第六单元100以内的加法和减法3", + "question_type": "填空题", + "difficulty": 0.65, + "question": "比最小的两位数多 1 的数是( ),少 1 的数是( ),这两个数的和是( )。", + "options": [], + "answer": "11;9;20", + "solution": "【分析】最小的两位数是10,求比最小的两位数多1的数是多少,用加法计算;求比最小的两位数少1的数是多少,用减法计算;求这两个数的和是多少,用加法计算,据此解答即可.\n【详解】最小的两位数是10。10+1=11;10-1=9;11+9=20。所以比最小的两位数多1的数是11,少1的数是9,这两个数的和是20。", + "knowledge_points": [ + "100 以内数的比大小", + "10 的加减法", + "不进位加法 (20 以内)", + "一位数与两位数的进位加法" + ], + "source": "22-23 一年级下·广东汕头·期末" + }, + { + "id": "253", + "unit": "第六单元100以内的加法和减法3", + "question_type": "判断题", + "difficulty": 0.65, + "question": "○+35=△+41,○>△( )", + "options": [], + "answer": "√", + "solution": "【分析】根据题意,两个算式都是加法算式,结果相等,则比较其中一个加数的大小,一个加数大,另一个加数就小,或者举例子代入算式解答.\n【详解】35<41,则○>△。例如:○+35=△+41=42;35再往后数7个数就是42,也就是7+35=42;41再往后数1个数就是42,也就是1+41=42;7>1,即○>△。原题说法正确。故答案为:√", + "knowledge_points": [ + "100以内数的比大小", + "两位数与一位数的加法(不进位)", + "一位数与两位数的进位加法" + ], + "source": "23-24 一年级下·河南周口·期末" + }, + { + "id": "254", + "unit": "第六单元100以内的加法和减法3", + "question_type": "判断题", + "difficulty": 0.65, + "question": "86 减去 8 个十还剩 6 个一。( )", + "options": [], + "answer": "√", + "solution": "【分析】8个十是80,6个一是6,用86减去80即可求解.\n【详解】86 - 80 = 6;86 减去 8 个十还剩 6 个一。原题说法正确。故答案为: √", + "knowledge_points": [ + "100以内数的组成", + "两位数与整十数的减法" + ], + "source": "23-24一年级下·河南周口·期末" + }, + { + "id": "255", + "unit": "第六单元100以内的加法和减法3", + "question_type": "判断题", + "difficulty": 0.85, + "question": "52 - 4 - 3 与 52 -(4+3) 的运算顺序和结果都一样。()", + "options": [], + "answer": "×", + "solution": "【分析】只有加减法的混合运算,从左往右计算;含有括号的混合运算,先算小括号里面的,再算小括号外面的.\n【详解】52-4-3=48-3=45;52-(4+3)=52-7=45;即,52-4-3与52-(4+3)的运算顺序不同,但结果一样;原题说法错误。故答案为:×", + "knowledge_points": [ + "100以内数的连减运算", + "带有小括号的混合运算" + ], + "source": "23-24 一年级下·山东菏泽·期末" + }, + { + "id": "256", + "unit": "第六单元100以内的加法和减法3", + "question_type": "判断题", + "difficulty": 0.65, + "question": "我有 17 元,妹妹有 9 元,我给她 8 元后我们两人同样多。( )", + "options": [], + "answer": "×", + "solution": "【分析】先用减法求出我给妹妹 8 元后我还剩多少元,再用加法求出我给妹妹 8 元后妹妹现在有多少元,最后比较我和妹妹现在的钱数是否同样多即可判断.\n【详解】 17 - 8 = 9 (元)9 + 8 = 17 (元)我给妹妹 8 元后,此时我有 9 元,妹妹有 17 元,我和妹妹的钱不是同样多,原题说法错误。故答案为: ×", + "knowledge_points": [ + "9加几的进位加法", + "一位数与两位数的退位减法" + ], + "source": "23-24 一年级下·湖北黄冈·期末" + }, + { + "id": "257", + "unit": "第六单元100以内的加法和减法3", + "question_type": "判断题", + "difficulty": 0.65, + "question": "有 26 个球,每 6 个装一盒,可以装满 5 盒。( )", + "options": [], + "answer": "×", + "solution": "【分析】根据题意,球的总数量依次减去 6,减到最后的数量不够装满 1 盒为止,减了几次 6 就是能装满几盒.\n【详解】 26 - 6 = 20 (个);20 - 6 = 14 (个);14 - 6 = 8 (个)8 - 6 = 2 ( 个);减了 4 次 6。可以装满 4 盒。原题说法错误。故答案为: ×", + "knowledge_points": [ + "十几减 7,6 的退位减法", + "两位数与一位数的减法(不退位)" + ], + "source": "23-24 一年级下·山东菏泽·期末" + }, + { + "id": "258", + "unit": "第六单元100以内的加法和减法3", + "question_type": "判断题", + "difficulty": 0.85, + "question": "算式里如果有小括号,一定要先算小括号里面的。( )", + "options": [], + "answer": "√", + "solution": "【详解】算式里如果有小括号,一定要先算小括号里面的。例如:在 28 - (4 + 6) 中,要先算小括号里面的 4 + 6 = 10,再算小括号外面的 28 - 10 = 18 。原题说法正确。故答案为: √", + "knowledge_points": [ + "带有小括号的混合运算" + ], + "source": "23-24 一年级下·吉林·期末" + }, + { + "id": "259", + "unit": "第六单元100以内的加法和减法3", + "question_type": "判断题", + "difficulty": 0.85, + "question": "34 比 7 多 27;比 27 多 7 的数是 34, 34 和 27 相差 7。( )", + "options": [], + "answer": "√", + "solution": "【分析】据题意可知,比较34与7之间的关系,可用减法进行计算,34减去7得出结果,再根据题目要求进行各数字之间的比较,即可得出答案.\n【详解】34-7=27;27+7=34;34-27=7。所以34比7多27,比27多7的数是34,34和27相差7是正确的。故答案为:√", + "knowledge_points": [ + "一位数与两位数的退位减法" + ], + "source": "23-24一年级下·吉林·期末" + }, + { + "id": "260", + "unit": "第六单元100以内的加法和减法3", + "question_type": "计算题", + "difficulty": 0.85, + "question": "口算.\n3 + 60 = 37 - 7 = 43 - (3 + 27) = 43 - 3 - 3 =\n34 + 7 = 76 - 3 = 34 + 8 + 50 = 76 - (6 + 4) =", + "options": [], + "answer": "63;30;13;37;41;73;92;66", + "solution": "【分析】 本题考查100以内数的加减法口算,包含不进位加,进位加,不退位减,连加,连减及带括号的混合运算。计算时需遵循运算顺序,有括号的先算括号内.\n【详解】 3加60得63;37减7得30;43减括号里3加27的和,先算括号得30,再减得13;43减3再减3,先算43减3得40,再减3得37;34加7得41;76减3得73;34加8再加50,先算34加8得42,再加50得92;76减括号里6加4的和,先算括号得10,再减得66。", + "knowledge_points": [ + "一位数与两位数的进位加法", + "100 以内数的连加运算", + "100 以内数的连减运算", + "带有小括号的混合运算" + ], + "source": "23-24 一年级下·湖北武汉·期末" + }, + { + "id": "261", + "unit": "第六单元100以内的加法和减法3", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列算式.\n![](images/75f56a0d1079170dc321351f77d26363.png)\n□○□=□(只)", + "options": [], + "answer": "32 + 5 = 37", + "solution": "【分析】左边 32 只,右边 5 只,左右两边相加即可求出总只数.\n【详解】 32 + 5 = 37 (只)一共37只。", + "knowledge_points": [ + "图文问题", + "两位数与一位数的加法(不进位)" + ], + "source": "23-24 一年级下·山东济南·期末" + }, + { + "id": "262", + "unit": "第六单元100以内的加法和减法3", + "question_type": "计算题", + "difficulty": 0.65, + "question": "我会看图列式计算.\n![](images/5e6caf3e00fa8636bb60ad3d807764b2.png)\n□○□=□(个)", + "options": [], + "answer": "8 + 27 = 35", + "solution": "【分析】左边有 8 个球,右边有 27 个,求一共有多少个球,根据加法的意义,左边的数量 + 右边的数量 = 总数量.\n【详解】 8 + 27 = 35 (个)一共有 35 个球。", + "knowledge_points": [ + "图文问题", + "一位数与两位数的进位加法" + ], + "source": "23-24 一年级下·湖南岳阳·期末" + }, + { + "id": "263", + "unit": "第六单元100以内的加法和减法3", + "question_type": "计算题", + "difficulty": 0.65, + "question": "直接写得数.\n8 + 54 = 62 - 40 = 50 - 6 = 45 + 40 - 20 =\n39 - 4 = 92 - 8 = 7 + 37 = 5角 + 7角 + 1元 =", + "options": [], + "answer": "62;22;44;65;35;84;44;2元2角或22角", + "solution": "【分析】 本题考查100以内数的加减法及人民币的简单计算。前七题为数的运算,需注意进位加法和退位减法;最后一题为人民币计算,需先统一单位再相加.\n【详解】 8加54得62;62减40得22;50减6得44;45加40再减20,先算45加40得85,再减20得65;39减4得35;92减8得84;7加37得44;5角加7角得12角,再加1元(10角)共22角,也可表示为2元2角。", + "knowledge_points": [ + "两位数与整十数的减法", + "一位数与两位数的进位加法", + "一位数与两位数的退位减法", + "十元以下人民币的认识与计算" + ], + "source": "23-24 一年级下·河南周口·期末" + }, + { + "id": "264", + "unit": "第六单元100以内的加法和减法3", + "question_type": "计算题", + "difficulty": 0.85, + "question": "计算.\n47 - 30 + 5 = 58 - 10 - 9 = 61 - 5 + 10 =\n26 + (7 + 2) = 36 + (16 - 6) = 87 - (60 - 50) =", + "options": [], + "answer": "22;39;66;35;46;77", + "solution": "【分析】 本题考查100以内数的加减混合运算,特别强调带有小括号的运算顺序。计算时必须先完成括号内的计算,再进行括号外的运算.\n【详解】 47减30再加5,先算47减30得17,再加5得22;58减10再减9,先算58减10得48,再减9得39;61减5再加10,先算61减5得56,再加10得66;26加括号里7加2的和,先算括号得9,再加得35;36加括号里16减6的差,先算括号得10,再加得46;87减括号里60减50的差,先算括号得10,再减得77。", + "knowledge_points": [ + "100 以内数的加减混合运算", + "带有小括号的混合运算" + ], + "source": "23-24 一年级下·河南信阳·期末" + }, + { + "id": "265", + "unit": "第六单元100以内的加法和减法3", + "question_type": "计算题", + "difficulty": 0.65, + "question": "想一想先算什么,再计算出结果.\n47 - (24 + 6) = 73 - (28 - 20) = 68 + (15 - 9) =", + "options": [], + "answer": "17;65;74", + "solution": "【分析】整数混合运算,如果只有加减法,按照从左到右的顺序计算;有括号的要先算括号里面的,再算括号外面的。第一题先算括号里面的加法,再算括号外面的减法;第二题先算括号里面的减法,再算括号外面的减法;第三题先算括号里面的减法,再算括号外面的加法.\n【详解】47-(24+6)=47-30=17;73-(28-20)=73-8=65;68+(15-9)=68+6=74。", + "knowledge_points": [ + "两位数与两位数的不退位减法", + "一位数与两位数的进位加法", + "一位数与两位数的退位减法", + "带有小括号的混合运算" + ], + "source": "23-24 一年级下·吉林·期末" + }, + { + "id": "266", + "unit": "第六单元100以内的加法和减法3", + "question_type": "计算题", + "difficulty": 0.85, + "question": "直接写得数.\n43 - 5 = 80 - 30 = 36 + 50 = 60 - 40 + 30 =\n61 - 10 = 50 + 48 = 20 + 70 = 27 + 30 + 8 =", + "options": [], + "answer": "38;50;86;50;51;98;90;65", + "solution": "【分析】 本题考查100以内数的加减法口算,包括退位减法,整十数加减,两位数加减整十数,加减混合运算及连加运算。关键点是掌握退位减法和整十数加减的简化算法.\n【详解】 43减5得38;80减30得50;36加50得86;60减40再加30,先算60减40得20,再加30得50;61减10得51;50加48得98;20加70得90;27加30再加8,先算27加30得57,再加8得65。", + "knowledge_points": [ + "整十数之间的加减法", + "两位数与整十数的减法", + "一位数与两位数的退位减法", + "100以内数的连加运算" + ], + "source": "23-24 一年级下·河南周口·期末" + }, + { + "id": "267", + "unit": "第六单元100以内的加法和减法3", + "question_type": "计算题", + "difficulty": 0.65, + "question": "看图列式计算.\n![](images/1e2a33d95470eda688e62399ab27b6d2.png)\n□○□=□(个)", + "options": [], + "answer": "73 - 8 = 65", + "solution": "【分析】一共有 73 个,右边有 8 个,求左边有多少个,用减法计算,即总数量 - 右边的数量 = 左边的数量.\n【详解】 73 - 8 = 65 (个);左边有 65 个。", + "knowledge_points": [ + "图文问题", + "一位数与两位数的退位减法" + ], + "source": "23-24 一年级下·山西长治·期末" + }, + { + "id": "268", + "unit": "第六单元100以内的加法和减法3", + "question_type": "计算题", + "difficulty": 0.85, + "question": "直接写得数.\n36 - 6 = 50 - 30 = 20 + 8 = 20 + 50 =\n29 - 7 = 83 - 80 = 18 - 3 = 12 - 9 =", + "options": [], + "answer": "30;20;28;70;22;3;15;3", + "solution": "【分析】 本题考查20和100以内简单的加减法口算,包含不退位减法,退位减法,整十数减法和加法。需要根据题目类型运用相应方法.\n【详解】 36减6得30;50减30得20;20加8得28;20加50得70;29减7得22;83减80得3;18减3得15;12减9得3。", + "knowledge_points": [ + "不退位减法(20以内)", + "十几减9的退位减法", + "两位数与一位数的减法(不退位)", + "两位数与整十数的减法" + ], + "source": "23-24 一年级下·山西长治·期末" + }, + { + "id": "269", + "unit": "第六单元100以内的加法和减法3", + "question_type": "计算题", + "difficulty": 0.85, + "question": "直接写得数.\n7 - 2 = 0 + 5 = 11 - 3 = 6 + 5 - 5 = \n10 + 6 = 17 - 9 = 33 - 30 = 13 + 7 - 9 = \n70 + 10 = 64 - 4 = 5 + 35 = 60 - (16 + 4) =", + "options": [], + "answer": "5;5;8;6;16;8;3;11;80;60;40;40", + "solution": "【分析】 本题考查20和100以内数的加减法口算,题型包括简单减法,加减混合及带括号运算。需注意运算顺序,并熟练进行整十数加减.\n【详解】 7减2得5;0加5得5;11减3得8;6加5再减5,先算6加5得11,再减5得6;10加6得16;17减9得8;33减30得3;13加7再减9,先算13加7得20,再减9得11;70加10得80;64减4得60;5加35得40;60减括号里16加4的和,先算括号得20,再减得40。", + "knowledge_points": [ + "整十数之间的加减法", + "两位数与一位数的减法(不退位)", + "一位数与两位数的进位加法", + "带有小括号的混合运算" + ], + "source": "23-24 一年级下·湖北武汉·期末" + }, + { + "id": "270", + "unit": "第六单元100以内的加法和减法3", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式计算.\n![](images/b5d0042113e8646484e0af7b6837ab0e.png)\n□○□=□(个)", + "options": [], + "answer": "32 - 4 = 28", + "solution": "【分析】用苹果的总数量减去左边的数量,求出差,就是右边篮子里的苹果数量.\n【详解】由题意分析得:32 - 4 = 28 (个)篮子里有 28 个苹果。", + "knowledge_points": [ + "图文问题", + "一位数与两位数的退位减法" + ], + "source": "23-24 一年级下·山东菏泽·期末" + }, + { + "id": "271", + "unit": "第六单元100以内的加法和减法3", + "question_type": "计算题", + "difficulty": 0.85, + "question": "直接写得数.\n14 - 6 = 47 - 5 = 48 + 8 = 14 - 6 + 7 =\n54 + 30 = 60 + 37 = 36 - 9 = 15 - (4 + 6) =", + "options": [], + "answer": "8;42;56;15;84;97;27;5", + "solution": "【分析】 本题考查100以内数的加减法口算,包括退位减法,不进位减法,进位加法,整十数加法及带括号的混合运算。需注意进位,退位及运算顺序.\n【详解】 14减6得8;47减5得42;48加8得56;14减6再加7,先算14减6得8,再加7得15;54加30得84;60加37得97;36减9得27;15减括号里4加6的和,先算括号得10,再减得5。", + "knowledge_points": [ + "两位数与整十数的加法", + "两位数与一位数的减法(不退位)", + "一位数与两位数的进位加法", + "一位数与两位数的退位减法" + ], + "source": "23-24 一年级下·山东菏泽·期末" + }, + { + "id": "272", + "unit": "第六单元100以内的加法和减法3", + "question_type": "计算题", + "difficulty": 0.85, + "question": "计算小能手.\n6 + 38 = 45 - 10 = 85 + 10 = 18 - 9 = 48 + 2 =\n74 + 6 = 90 - 40 = 35 + 8 = 3 + 26 = 47 + 30 =\n56 - 20 = 5 + 45 = 76 - 30 = 46 - 6 = 77 - 7 =", + "options": [], + "answer": "44;35;95;9;50;80;50;43;29;77;36;50;46;40;70", + "solution": "【分析】 本题为综合性口算题,考查100以内数的加减法,包括进位加,不退位加,退位减,整十数加减等。需根据题目特点选择合适方法.\n【详解】 6加38得44;45减10得35;85加10得95;18减9得9;48加2得50;74加6得80;90减40得50;35加8得43;3加26得29;47加30得77;56减20得36;5加45得50;76减30得46;46减6得40;77减7得70。", + "knowledge_points": [ + "十几减 9 的退位减法", + "两位数与一位数的减法(不退位)", + "两位数与整十数的减法", + "一位数与两位数的进位加法" + ], + "source": "23-24 一年级下·山东临沂·期末" + }, + { + "id": "273", + "unit": "第六单元100以内的加法和减法3", + "question_type": "计算题", + "difficulty": 0.65, + "question": "看图列式.\n![](images/e5ed6f011177e631a5b49561e9c38c6b.png)\n□ ○ □ = □ (个)", + "options": [], + "answer": "35 + 6 = 41", + "solution": "【分析】由图可知,左边篮子里有 35 个水果,右边有 6 个水果,求一共有多少个。用加法列式计算.\n【详解】 35 + 6 = 41 (个)", + "knowledge_points": [ + "图文问题", + "一位数与两位数的进位加法" + ], + "source": "23-24 一年级下·四川凉山·期末" + }, + { + "id": "274", + "unit": "第六单元100以内的加法和减法3", + "question_type": "计算题", + "difficulty": 0.65, + "question": "看图列式计算.\n![](images/a4597b2da8b35aa94992ae2710affbf9.png)\n□ ○ □ = □ (只)", + "options": [], + "answer": "21 - 3 = 18", + "solution": "【分析】一共有 21 只小狗,右边有 3 只,求左边有多少只,用减法计算,即总数量 - 右边的数量 = 左边的数量.\n【详解】 21 - 3 = 18 (只)左边有 18 只。", + "knowledge_points": [ + "图文问题", + "一位数与两位数的退位减法" + ], + "source": "23-24 一年级下·河南商丘·期末" + }, + { + "id": "275", + "unit": "第六单元100以内的加法和减法3", + "question_type": "计算题", + "difficulty": 0.65, + "question": "看图列式计算.\n![](images/1f41e380314840609883ec5c5f993d80.png)\n□ ○ □ = □ (个)", + "options": [], + "answer": "38 + 5 = 43", + "solution": "【分析】左边有 38 个苹果,右边有 5 个,求一共有多少个苹果,用加法计算,即左边的数量 + 右边的数量 = 总数量.\n【详解】 38 + 5 = 43 (个)一共有 43 个苹果。", + "knowledge_points": [ + "图文问题", + "一位数与两位数的进位加法" + ], + "source": "23-24 一年级下·河南商丘·期末" + }, + { + "id": "276", + "unit": "第六单元100以内的加法和减法3", + "question_type": "计算题", + "difficulty": 0.85, + "question": "我会算.\n14 - 6 = 50 - 20 = 45 - 9 = 37 + (11 - 4) =\n15 + 40 = 54 - 7 = 5 + 37 = 25 + 30 - 6 =", + "options": [], + "answer": "8;30;36;44;55;47;42;49", + "solution": "【分析】 本题考查20和100以内数的加减法,包括退位减法,整十数减法,进位加法及带括号的混合运算。需注意退位减的计算方法和括号的运算顺序.\n【详解】 14减6得8;50减20得30;45减9得36;37加括号里11减4的差,先算括号得7,再加得44;15加40得55;54减7得47;5加37得42;25加30再减6,先算25加30得55,再减6得49。", + "knowledge_points": [ + "十几减 7,6 的退位减法", + "一位数与两位数的进位加法", + "一位数与两位数的退位减法", + "带有小括号的混合运算" + ], + "source": "23-24 一年级下·河南商丘·期末" + }, + { + "id": "277", + "unit": "第六单元100以内的加法和减法3", + "question_type": "计算题", + "difficulty": 0.65, + "question": "算一算.\n18 + 50 - 7 = 80 - 60 + 35 = 63 - (76 - 70) =", + "options": [], + "answer": "61;55;57", + "solution": "【分析】100以内的加减混合运算中,没有括号时,从左到右依次计算;有括号时,先算括号里面的,再算括号外面的.\n【详解】18+50-7=68-7=61;80-60+35=20+35=55;63-(76-70)=63-6=57。", + "knowledge_points": [ + "100 以内数的加减混合运算", + "带有小括号的混合运算" + ], + "source": "22-23 一年级下·广东汕头·期末" + }, + { + "id": "278", + "unit": "第六单元100以内的加法和减法3", + "question_type": "计算题", + "difficulty": 0.85, + "question": "算一算.\n20 + 7 = 30 - 20 = 90 + 9 = 60 - 30 = 24 + 6 =\n51 + 8 = 7 + 83 = 85 - 5 = 90 - 70 = 45 + 20 =\n96 - 7 = 65 + 20 =", + "options": [], + "answer": "27;10;99;30;30;59;90;80;20;65;89;85", + "solution": "【分析】 本题考查100以内数的加减法口算,包括整十数加减一位数,两位数加减整十数,进位加法及退位减法。需根据题目灵活运用口算方法.\n【详解】 20加7得27;30减20得10;90加9得99;60减30得30;24加6得30;51加8得59;7加83得90;85减5得80;90减70得20;45加20得65;96减7得89;65加20得85。", + "knowledge_points": [ + "整十数加,减一位数", + "两位数与整十数的加法", + "一位数与两位数的进位加法", + "一位数与两位数的退位减法" + ], + "source": "22-23 一年级下·广东汕头·期末" + }, + { + "id": "279", + "unit": "第六单元100以内的加法和减法3", + "question_type": "解答题", + "difficulty": 0.85, + "question": "小卡摘了 36 个桃子,小卡送 3 个桃子给小丁,它俩的桃子就同样多。小丁摘了多少个桃子。 答:小丁摘了()个桃子。", + "options": [], + "answer": "30个", + "solution": "【分析】用小卡摘了的桃子数量减去送给小丁的 3 个,求出差,就是他俩现在各自的数量,再减去 3 个,求出差,就是小丁摘了的桃子数量.\n【详解】 36 - 3 - 3 = 33 - 3 = 30 (个)答:小丁摘了 30 个桃子。", + "knowledge_points": [ + "100以内数的连减运算" + ], + "source": "23-24 一年级下·湖北武汉·期末" + }, + { + "id": "280", + "unit": "第六单元100以内的加法和减法3", + "question_type": "解答题", + "difficulty": 0.85, + "question": "小勇读一本 70 页的书,第一天读了 7 页,第二天读了 18 页。第三天要从第几页开始读。答:第三天要从第()页开始读。", + "options": [], + "answer": "26页", + "solution": "【分析】先用加法把第一天读了的页数与第二天读了的页数加起来,求出和,再加上 1,求出和,就是第三天开始读的页数.\n【详解】 7 + 18 + 1 = 25 + 1 = 26 (页)答:第三天要从第 26 页开始读。", + "knowledge_points": [ + "100 以内数的连加运算" + ], + "source": "23-24 一年级下·湖北武汉·期末" + }, + { + "id": "281", + "unit": "第六单元100以内的加法和减法3", + "question_type": "解答题", + "difficulty": 0.65, + "question": "汽车站有46辆,第一次开走了7辆,第二次开走13辆,还剩多少辆。", + "options": [], + "answer": "26辆", + "solution": "【分析】根据题意,可以先计算出两次一共开走了多少辆,再用原有的数量减去开走的总数量,就是还剩的数量。即原有的数量减(第一次开走的数量+第二次开走的数量)=还剩的数量.\n【详解】46-(7+13)=46-20=26(辆)。答:还剩26辆。", + "knowledge_points": [ + "两位数与整十数的减法", + "带有小括号的混合运算" + ], + "source": "23-24一年级下·广东汕头·期末" + }, + { + "id": "282", + "unit": "第六单元100以内的加法和减法3", + "question_type": "解答题", + "difficulty": 0.65, + "question": "小花说回收旧电池箱子里有 35 节旧电池,小涛说我要放进 7 节,回收箱里现在有多少节旧电池。", + "options": [], + "answer": "42节", + "solution": "【分析】根据加法的意义,原有电池的数量 + 又放进去的数量 = 现在的数量,由此解答.\n【详解】 35 + 7 = 42 (节)答:回收箱里现在有 42 节旧电池。", + "knowledge_points": [ + "一位数与两位数的进位加法" + ], + "source": "23-24 一年级下·河南周口·期末" + }, + { + "id": "283", + "unit": "第六单元100以内的加法和减法3", + "question_type": "解答题", + "difficulty": 0.65, + "question": "有 37 颗珠子, 8 颗穿成一串,最多可以穿几串。 还剩几颗。", + "options": [], + "answer": "4串;5颗", + "solution": "【分析】用珠子的总数连续减去每串珠子的数量,算一算最多可以减几次,减了几次就表示最多可以穿几串,最后不够减的数量就是还剩的颗数.\n【详解】 37 - 8 = 29 (颗)29 - 8 = 21 (颗)21 - 8 = 13 (颗) 13 - 8 = 5 (颗)答:最多可以穿 4 串;还剩 5 颗。", + "knowledge_points": [ + "十几减8的退位减法", + "一位数与两位数的退位减法" + ], + "source": "23-24 一年级下·湖北黄冈·期末" + }, + { + "id": "284", + "unit": "第六单元100以内的加法和减法3", + "question_type": "解答题", + "difficulty": 0.65, + "question": "车上原来有 32 人,下来了 6 人,又上去了 5 人。现在车上有多少人。", + "options": [], + "answer": "31人", + "solution": "【分析】根据题意,下来的人数要减去,又上去的人数要加上。即原来的人数减下来的人数+又上去的人数=现在的人数.\n【详解】32-6+5=31(人)。答:现在车上有31人。", + "knowledge_points": [ + "100以内数的加减混合运算" + ], + "source": "23-24 一年级下·山东菏泽·期末" + }, + { + "id": "285", + "unit": "第六单元100以内的加法和减法3", + "question_type": "解答题", + "difficulty": 0.65, + "question": "同学们收集大树的叶子,一 (1) 班收集了 42 种,一 (2) 班收集的比一 (1)班少7种,一(2)班收集了多少种叶子。", + "options": [], + "answer": "35种", + "solution": "【分析】求比一个数少几的数是多少,用减法计算。即一(1)班收集的种类减一(2)班比一(1)班少收集的种类=一(2)班收集的种类.\n【详解】42-7=35(种)。答:一(2)班收集了35种叶子。", + "knowledge_points": [ + "一位数与两位数的退位减法" + ], + "source": "23-24 一年级下·山东菏泽·期末" + }, + { + "id": "286", + "unit": "第六单元100以内的加法和减法3", + "question_type": "解答题", + "difficulty": 0.85, + "question": "我手里有30份问卷,班里有45名学生,每人一份问卷,还差几份。", + "options": [], + "answer": "15份", + "solution": "【分析】求还差的数量,用减法计算,即一共需要的数量减已经有的数量=还差的数量.\n【详解】45-30=15(份)。答:还差15份。", + "knowledge_points": [ + "两位数与整十数的减法" + ], + "source": "23-24一年级下·河南商丘·期末" + }, + { + "id": "287", + "unit": "第六单元100以内的加法和减法3", + "question_type": "解答题", + "difficulty": 0.65, + "question": "军军买一本课外书用了 46 元,找回 4 元,军军付了多少元。", + "options": [], + "answer": "50元", + "solution": "【分析】根据加法的意义,买课外书用的钱数 + 找回的钱数 = 付出的钱数,由此解答.\n【详解】 46 + 4 = 50 (元)答:军军付了 50 元。", + "knowledge_points": [ + "一位数与两位数的进位加法" + ], + "source": "23-24 一年级下·河南周口·期末" + }, + { + "id": "288", + "unit": "第六单元100以内的加法和减法3", + "question_type": "解答题", + "difficulty": 0.65, + "question": "有 3 名老师和 38 名同学去看电影。其中女同学有 20 名。男同学有多少名。", + "options": [], + "answer": "18名", + "solution": "【分析】学生总数减去女同学的人数即可得到男同学的人数.\n【详解】 38 - 20 = 18 (名)答:男同学有 18 名。", + "knowledge_points": [ + "两位数与整十数的减法" + ], + "source": "23-24 一年级下·山东临沂·期末" + }, + { + "id": "289", + "unit": "第六单元100以内的加法和减法3", + "question_type": "解答题", + "difficulty": 0.85, + "question": "小朋友分点心。桌子上有 3 个盘子,每个盘子里放 7 块点心,每个小朋友分一块点心,分给 20 个小朋友,够吗。", + "options": [], + "answer": "够", + "solution": "【分析】每个盘子里放 7 块点心,先用加法求出 3 盘这样的一共有几块,然后与小朋友的数量比较大小,即可解决.\n【详解】 7 + 7 + 7 = 14 + 7 = 21 (块)21 > 20;答:每个小朋友分一块点心,分给 20 个小朋友,够。", + "knowledge_points": [ + "100以内数的比大小", + "100以内数的连加运算" + ], + "source": "23-24一年级下·山东菏泽·期末" + }, + { + "id": "290", + "unit": "第六单元100以内的加法和减法3", + "question_type": "解答题", + "difficulty": 0.85, + "question": "一年级一班已经领了49条红领巾,如果每人1条,还差5条,一年级一班有多少人。", + "options": [], + "answer": "54人", + "solution": "【分析】把已领的红领巾数量与还差的数量加起来,求出和,即可解决.\n【详解】 49 + 5 = 54 (人)答:一年级一班有 54 人。", + "knowledge_points": [ + "一位数与两位数的进位加法" + ], + "source": "23-24一年级下·山东菏泽·期末" + }, + { + "id": "291", + "unit": "第六单元100以内的加法和减法3", + "question_type": "解答题", + "difficulty": 0.65, + "question": "一年级二班有25名男同学,20名女同学,刘老师要带领同学乘坐大巴车去科技馆,能坐得下吗。核载45人", + "options": [], + "answer": "坐不下", + "solution": "【分析】先用加法把男同学和女同学的人数加起来,求出和,再加上 1(一位老师),求出和,最后与大巴车核载人数比较大小,即可解决.\n【详解】 25 + 20 + 1 = 45 + 1 = 46 (人) 46 > 45答:大巴车坐不下全部人。", + "knowledge_points": [ + "100以内数的比大小", + "100以内数的连加运算" + ], + "source": "23-24一年级下·湖北黄冈·期末" + }, + { + "id": "292", + "unit": "第六单元100以内的加法和减法3", + "question_type": "解答题", + "difficulty": 0.65, + "question": "一本书有 80 页,冬冬第一天看了 20 页,第二天看的比第一天多 8 页,冬冬两天一共看了多少页。", + "options": [], + "answer": "48页", + "solution": "【分析】先用第一天看的页数加上第二天比第一天多看的页数求出第二天看了多少页,再用第一天看的页数加上第二天看的页数,即可求出两天一共看了多少页.\n【详解】 20 + 8 = 28 (页)20 + 28 = 48 (页)答:冬冬两天一共看了 48 页。", + "knowledge_points": [ + "两位数与一位数的加法(不进位)", + "两位数与整十数的加法" + ], + "source": "23-24一年级下·湖北黄冈·期末" + }, + { + "id": "293", + "unit": "第六单元100以内的加法和减法3", + "question_type": "解答题", + "difficulty": 0.65, + "question": "丽丽有 16 张贺卡,比玲玲多 8 张,她们一共有多少张贺卡。", + "options": [], + "answer": "24张", + "solution": "【分析】根据题意,先用丽丽贺卡的数量减玲玲多的数量,求出玲玲有多少张贺卡,再将她们贺卡的数量相加就是总数量.\n【详解】16-8=8(张);16+8=24(张)。答:她们一共有24张贺卡。", + "knowledge_points": [ + "十几减 8 的退位减法", + "一位数与两位数的进位加法" + ], + "source": "23-24 一年级下·山东菏泽·期末" + }, + { + "id": "294", + "unit": "第六单元100以内的加法和减法3", + "question_type": "解答题", + "difficulty": 0.85, + "question": "二年级一班得了 13面流动红旗,二班比一班多得了2面,二班得了多少面。(先画图表示,再列式解答)", + "options": [], + "answer": "见详解", + "solution": "【分析】已知二班比一班多得了 2 面,根据加法的意义,用 13 + 2 进行解答即可.\n【详解】![](images/0a798ed0a1758404b37e1d1151adc17e.png) 13 + 2 = 15 (面)答:二班得了 15 面。", + "knowledge_points": [ + "不进位加法(20以内)" + ], + "source": "23-24 二年级上·福建莆田·期中" + }, + { + "id": "295", + "unit": "第六单元100以内的加法和减法3", + "question_type": "解答题", + "difficulty": 0.65, + "question": "水果店有一些苹果,卖掉8筐后,还比西瓜多5筐,其中西瓜有25筐。水果店原来有多少筐苹果。", + "options": [], + "answer": "38筐", + "solution": "【分析】根据题意,先用西瓜的筐数加卖掉8筐后苹果比西瓜多的筐数,求出现在有多少筐苹果,再加上卖掉的数量,就是原来的数量.\n【详解】现在苹果的筐数:25+5=30(筐);原来苹果的筐数:30+8=38(筐)。答:水果店原来有38筐苹果。", + "knowledge_points": [ + "整十数加,减一位数", + "一位数与两位数的进位加法" + ], + "source": "23-24一年级下·江西抚州·期末" + }, + { + "id": "296", + "unit": "第六单元100以内的加法和减法3", + "question_type": "解答题", + "difficulty": 0.65, + "question": "小明家养了 23 只鸡和 7 只鹅,养的鸡比鹅多多少只。", + "options": [], + "answer": "16只", + "solution": "【分析】求一个数比另一个数多多少,用减法计算,即鸡的数量减鹅的数量=鸡比鹅多的数量.\n【详解】23-7=16(只)。答:养的鸡比鹅多16只。", + "knowledge_points": [ + "一位数与两位数的退位减法" + ], + "source": "23-24 一年级下·四川凉山·期末" + }, + { + "id": "297", + "unit": "第六单元100以内的加法和减法3", + "question_type": "解答题", + "difficulty": 0.65, + "question": "小红买故事书花了 23 元,还剩 9 元,小红原来有多少元钱。", + "options": [], + "answer": "32元", + "solution": "【分析】求原来有多少钱,用加法计算,即花了的钱数 + 还剩的钱数 = 原来的钱数.\n【详解】 23 + 9 = 32 (元)答:小红原来有 32 元钱。", + "knowledge_points": [ + "一位数与两位数的进位加法" + ], + "source": "23-24一年级下·河南商丘·期末" + }, + { + "id": "298", + "unit": "第六单元100以内的加法和减法3", + "question_type": "解答题", + "difficulty": 0.65, + "question": "车上原来有 28 人,到广场站下去了9人,又上来了7人。车上现在有多少人。", + "options": [], + "answer": "26人", + "solution": "【分析】根据题意,下去的人数要减去,又上来的人数要加上。即原来的人数减下去的人数+又上来的人数=现在的人数.\n【详解】28-9+7=26(人)。答:车上现在有26人。", + "knowledge_points": [ + "100以内数的加减混合运算" + ], + "source": "23-24 一年级下·河南信阳·期末" + }, + { + "id": "299", + "unit": "第六单元100以内的加法和减法3", + "question_type": "解答题", + "difficulty": 0.85, + "question": "小方看一本故事书,已经看了 50 页,还有 30 页没有看,这本故事书一共有多少页。", + "options": [], + "answer": "80页", + "solution": "【分析】求一共有多少页,用加法计算,即已经看了的页数 + 还没看的页数 = 总页数.\n【详解】 50 + 30 = 80 (页)答:这本故事书一共有 80 页。", + "knowledge_points": [ + "整十数之间的加减法" + ], + "source": "23-24 一年级下·河南信阳·期末" + }, + { + "id": "300", + "unit": "第六单元100以内的加法和减法3", + "question_type": "解答题", + "difficulty": 0.85, + "question": "工人要做56把团扇,4人一起做,已经做了40把,还要做多少把。", + "options": [], + "answer": "16把", + "solution": "【分析】求还要做几把,用减法计算,即要做的总数量减已经做了的数量=还要做的数量.\n【详解】56-40=16(把)。答:还要做16把。", + "knowledge_points": [ + "两位数与整十数的减法" + ], + "source": "23-24一年级下·湖南常德·期末" + }, + { + "id": "301", + "unit": "第六单元100以内的加法和减法4", + "question_type": "选择题", + "difficulty": 0.65, + "question": "33个苹果,每人分5个,可以分给()人,还剩()个。", + "options": [ + "A. 6, 3", + "B. 5, 3", + "C. 4, 3" + ], + "answer": "A", + "solution": "【分析】由题可知, 33 里面有几个 5,就是可以分给几个人,还剩几就是还剩几个苹果,据此解答.\n【详解】 33 - 5 - 5 - 5 - 5 - 5 - 5= 28 - 5 - 5 - 5 - 5 - 5 = 23 - 5 - 5 - 5 - 5 = 18 - 5 - 5 - 5 = 13 - 5 - 5 = 8 - 5 = 3 (个) 由此可知, 33里面有6个5,还剩下3,即33个苹果,每人分5个,可以分给6人,还剩3个。故答案为: A", + "knowledge_points": [ + "一位数与两位数的退位减法", + "100以内数的连减运算" + ], + "source": "23-24一年级下·河南南阳·期末" + }, + { + "id": "302", + "unit": "第六单元100以内的加法和减法4", + "question_type": "选择题", + "difficulty": 0.65, + "question": "兰兰有 14 张贴纸,小军有 10 张贴纸,兰兰送给小军 ( ) 张贴纸,两人的贴纸就一样多。", + "options": [ + "A. 4", + "B. 2", + "C. 10" + ], + "answer": "B", + "solution": "【分析】先根据减法的意义,用兰兰的贴纸数减去小军的贴纸数求出差,再把这个差平均分成两份,其中1份送给小军,两人的贴纸就一样多。据此解答即可.\n【详解】 14 - 10 = 4 (张)2 + 2 = 4 (张)所以兰兰送给小军 2 张贴纸,两人的贴纸就一样多。故答案为: B", + "knowledge_points": [ + "5 以内数的加法", + "两位数与整十数的减法" + ], + "source": "22-23一年级下·广东汕头·期末" + }, + { + "id": "303", + "unit": "第六单元100以内的加法和减法4", + "question_type": "选择题", + "difficulty": 0.85, + "question": "阳阳要买一个闹钟,给了售货员 20 元,找回了 3 元,这个闹钟的价格是 ( )。", + "options": [ + "A. 17元", + "B. 20元3角", + "C. 23元" + ], + "answer": "A", + "solution": "【分析】根据减法的意义,给售货员的钱数减找回的钱数=闹钟的价格,由此解答.\n【详解】20-3=17(元)。这个闹钟的价格是17元。故答案为:A", + "knowledge_points": [ + "一位数与两位数的退位减法" + ], + "source": "23-24 一年级下·山东日照·期末" + }, + { + "id": "304", + "unit": "第六单元100以内的加法和减法4", + "question_type": "选择题", + "difficulty": 0.65, + "question": "如果 3 □ +7 是一道进位加法, □ 里最小可以填 ( )。", + "options": [ + "A. 3", + "B. 4", + "C. 5" + ], + "answer": "A", + "solution": "【分析】本题根据竖式计算的法则来解答即可。相同数位对齐,从个位算起,个位相加满十,向十位进1。由此可知,□+7的和要大于或等于10,最小为10,根据和减一个加数=另一个加数计算即可.\n【详解】10-7=3;□里最小可以填3。故答案为:A", + "knowledge_points": [ + "一位数与两位数的进位加法" + ], + "source": "23-24 一年级下·福建福州·期末" + }, + { + "id": "305", + "unit": "第六单元100以内的加法和减法4", + "question_type": "选择题", + "difficulty": 0.85, + "question": "平平买了 18 支铅笔,还剩几支。缺少的信息是()。", + "options": [ + "A. 又买了 8 支铅笔", + "B. 用了 8 块橡皮", + "C. 分给小刚 8 支铅笔" + ], + "answer": "C", + "solution": "【分析】求还剩多少,用减法计算,需要知道的信息有原来的数量,和去掉的数量。题中平平原来有18支铅笔,则选择出去掉的数量即可.\n【详解】A.又买了8支铅笔,表示在18支笔的基础上再加8支,可求出现在一共有多少支,用18+8计算,与题意不符;B.用了8块橡皮,和铅笔的数量无关,与题意不符;C.分给小刚8支,也就是去掉了8支,用18-8计算,与题意相符。缺少的信息是分给小刚8支铅笔。故答案为:C", + "knowledge_points": [ + "\"提问题\"\"填条件\"问题", + "不退位减法(20以内)" + ], + "source": "23-24一年级下·福建福州·期末" + }, + { + "id": "306", + "unit": "第六单元100以内的加法和减法4", + "question_type": "选择题", + "difficulty": 0.85, + "question": "有 78 支铅笔, 10 支装 1 盒,能装满 ( ) 盒。", + "options": [ + "A. 10", + "B. 8", + "C. 7" + ], + "answer": "C", + "solution": "【分析】根据题意,用总数连续减 10,最后不够减 10 的不能装满一盒,据此解答.\n【详解】根据分析, 78 - 10 = 68 (支)68 - 10 = 58 (支)58 - 10 = 48 (支)48 - 10 = 38 (支)38 - 10 = 28 (支)28 - 10 = 18 (支)18 - 10 = 8 (支)有 78 支铅笔, 10 支装 1 盒,能装满 7 盒。故答案为: C", + "knowledge_points": [ + "两位数与整十数的减法" + ], + "source": "23-24 一年级下·广东江门·期末" + }, + { + "id": "307", + "unit": "第六单元100以内的加法和减法4", + "question_type": "选择题", + "difficulty": 0.65, + "question": "买一件衣服付了80元,找回的钱比 4 元少,衣服的价格可能是()元。", + "options": [ + "A. 76", + "B. 84", + "C. 79" + ], + "answer": "C", + "solution": "【分析】根据付的钱数减衣服的价格=找回的钱数,找回的钱比4元少,80-4=76(元),那么衣服的价格应大于76元又小于80元,据此解答.\n【详解】A.衣服的价格应大于76元,不符合题意;B.84>80,衣服的价格应小于80元,不符合题意;C.76<79<80,符合题意。故答案为:C", + "knowledge_points": [ + "100 以内数的比大小", + "一位数与两位数的退位减法", + "十元以上人民币的认识与计算" + ], + "source": "23-24 一年级下·湖南湘西·期末" + }, + { + "id": "308", + "unit": "第六单元100以内的加法和减法4", + "question_type": "选择题", + "difficulty": 0.65, + "question": "如果4□-6是一道退位减法,□里最大可以填( )。", + "options": [ + "A. 5", + "B. 6", + "C. 7" + ], + "answer": "A", + "solution": "【分析】减法计算时,相同数位对齐,从个位算起,个位不够减从十位退1作十进行计算。这道题是退位减法,也就是□减6不够减,即□小于6,最大是比6小1的数。由此解答.\n【详解】6-1=5;□里最大可以填5。故答案为:A", + "knowledge_points": [ + "一位数与两位数的退位减法" + ], + "source": "23-24 一年级下·湖南湘西·期末" + }, + { + "id": "309", + "unit": "第六单元100以内的加法和减法4", + "question_type": "选择题", + "difficulty": 0.65, + "question": "与算式 50 - 9 - 6 的计算结果不同的是 ( )。", + "options": [ + "A. 50 - 6 - 9", + "B. 50 - (9 - 6)", + "C. 50 - (9 + 6)" + ], + "answer": "B", + "solution": "【分析】整数混合运算中只有加减法,从左往右依次计算;有括号先算括号里面的再算括号外面的,由此计算出各算式的结果选择即可.\n【详解】50-9-6=41-6=35;A.50-6-9=44-9=35;B.50-(9-6)=50-3=47;C.50-(9+6)=50-15=35。与算式50-9-6的计算结果不同的是50-(9-6)。故答案为:B", + "knowledge_points": [ + "100以内数的连减运算", + "带有小括号的混合运算" + ], + "source": "23-24 一年级下·湖南湘西·期末" + }, + { + "id": "310", + "unit": "第六单元100以内的加法和减法4", + "question_type": "选择题", + "difficulty": 0.65, + "question": "奶奶今年 67 岁,安安今年 6 岁, 2 年后奶奶比安安大 ( ) 岁。", + "options": [ + "A. 64 岁", + "B. 61岁", + "C. 63岁" + ], + "answer": "B", + "solution": "【分析】两人相差的年龄是不变的,奶奶的年龄减安安的年龄=奶奶比安安大的岁数,据此得出结论即可.\n【详解】67-6=61(岁)。即2年后奶奶比安安大61岁。故答案为:B", + "knowledge_points": [ + "两位数与一位数的减法(不退位)" + ], + "source": "23-24 一年级下·山东临沂·期末" + }, + { + "id": "311", + "unit": "第六单元100以内的加法和减法4", + "question_type": "选择题", + "difficulty": 0.65, + "question": "水果超市有 74 篷苹果,上午卖了 30 箍,下午卖了 20 箍,还剩下多少筐。 不正确的算式是 ( )。", + "options": [ + "A. 74 - 30 - 20", + "B. 74 - (30 + 20)", + "C. 74 - 30 + 20" + ], + "answer": "C", + "solution": "【分析】根据题意,可用苹果的总数量减上午卖了的数量减下午卖了的数量=还剩的数量,或者用苹果的总数量减(上午卖了的数量+下午卖了的数量)=还剩的数量,由此解答.\n【详解】由分析列式为:74-30-20=44-20=24(筐)或74-(30+20)=74-50=24(筐)。还剩下24筐。列式不正确的是74-30+20。故答案为:C", + "knowledge_points": [ + "100 以内数的连减运算", + "带有小括号的混合运算" + ], + "source": "23-24 一年级下·贵州铜仁·期末" + }, + { + "id": "312", + "unit": "第六单元100以内的加法和减法4", + "question_type": "填空题", + "difficulty": 0.65, + "question": "在括号里填上 \">\" \"<\" 或 \"=\" .\n52-8( )45\n65-5( )70\n63( )66-30\n11元( )12角\n40角( )2元\n1元( )100分", + "options": [], + "answer": "<;<;>;>;=", + "solution": "【分析】根据整数加减法的计算法则依次计算出各算式的结果再比较大小。比较时,位数多的数就大;位数相同比较最高位,最高位大的数就大;最高位相同比较下一位,直到比较出结果为止。人民币的题目先统一单位再比较.\n【详解】52-8=44;44<45,则52-8<45;65-5=60;60<70,则65-5<70;66-30=36;63>36,则63>66-30;1元=10角;12角=1元2角;11元>1元2角,则11元>12角;40角=4元;4元>2元,则40角>2元;1元=100分。", + "knowledge_points": [ + "100 以内数的比大小", + "两位数与一位数的减法(不退位)", + "一位数与两位数的退位减法", + "元,角,分的认识及换算" + ], + "source": "23-24一年级下·山东日照·期末" + }, + { + "id": "313", + "unit": "第六单元100以内的加法和减法4", + "question_type": "填空题", + "difficulty": 0.85, + "question": "比 30 多 7 的数是( ), 比 21 少 9 的数是( )。", + "options": [], + "answer": "37;12", + "solution": "【分析】求比一个数多几的数是多少,用这个数加多的数计算;求比一个数少几的数是多少,用这个数减少的数计算.\n【详解】30+7=37;21-9=12;比30多7的数是37,比21少9的数是12。", + "knowledge_points": [ + "整十数加,减一位数", + "一位数与两位数的退位减法" + ], + "source": "23-24 一年级下·山东日照·期末" + }, + { + "id": "314", + "unit": "第六单元100以内的加法和减法4", + "question_type": "填空题", + "difficulty": 0.85, + "question": "在括号里填上合适的数.\n( )-20=4\n9+( )=49\n( )+( )=50", + "options": [], + "answer": "24;40;20;30", + "solution": "【分析】根据减数+差=被减数;和减一个加数=另一个加数计算;最后一题两数相加的和是50即可.\n【详解】20+4=24,则24-20=4;49-9=40,则9+40=49;20+30=50。(答案不唯一)", + "knowledge_points": [ + "整十数之间的加减法", + "两位数与一位数的减法(不退位)", + "两位数与整十数的减法" + ], + "source": "23-24 一年级下·福建福州·期末" + }, + { + "id": "315", + "unit": "第六单元100以内的加法和减法4", + "question_type": "填空题", + "difficulty": 0.85, + "question": "49 颗珠子,每 10 个穿一串,能穿( )串。", + "options": [], + "answer": "4", + "solution": "【分析】根据题意,用珠子的总数量依次减去 10,减到最后的数量不够串成一串为止,减了几次 10 就是能穿几串.\n【详解】 49 - 10 = 39 (个);39 - 10 = 29 (个);29 - 10;= 19 (个);19 - 10 = 9 (个)减了4次 10;49颗珠子,每10个穿一串,能穿4串。", + "knowledge_points": [ + "两位数与整十数的减法" + ], + "source": "23-24 一年级下·广东江门·期末" + }, + { + "id": "316", + "unit": "第六单元100以内的加法和减法4", + "question_type": "填空题", + "difficulty": 0.65, + "question": "在括号里填上\">\" \"<\"或\"=\".\n10元()9元9角 5元()50角 46-9()38", + "options": [], + "answer": ">;=;<", + "solution": "【分析】据题意可知,题目要求进行大小的比较。人民币的面值是元角分,1元=10角,1角=10分,就可以换算出元和角的数量关系;先计算两位数减去一位数,再与后面的数进行比较;即可得出答案.\n【详解】9元9角差1角才是10元;5元可以换算成50角;46-9=37,再与38进行比较。10元>9元9角;5元=50角;46-9<38。", + "knowledge_points": [ + "100以内数的比大小", + "元,角,分的认识及换算" + ], + "source": "23-24 一年级下·河北保定·期末" + }, + { + "id": "317", + "unit": "第六单元100以内的加法和减法4", + "question_type": "填空题", + "difficulty": 0.65, + "question": "在括号里填上 \">\" \"<\" 或 \"=\" .\n58-20( )39\n7+63( )79\n15-9( )0+8\n66-2( )68\n78-8( )60\n6个一和1个十( )61\n67元-50元( )27元\n36角+20角( )6元", + "options": [], + "answer": "<;<;<;<;>;<;<", + "solution": "【分析】根据整数加减法的计算法则,依次计算出各算式的结果再比较大小。比较时,位数多的数就大;位数相同;比较最高位,最高位大的数就大;最高位相同比较下一位,直到比较出结果为止。第 6 题根据数的组成写出数字再比较;第7,8题先计算出结果,再根据1元 = 10 角统一单位比较.\n【详解】 58 - 20 = 38;38 < 39,则 58 - 20 < 39;7 + 63 = 70;70 < 79,则 7 + 63 < 79;15 - 9 = 6;0 + 8 = 8;6 < 8,则 15 - 9 < 0 + 8;66 - 2 = 64;64 < 68,则 66 - 2 < 68;78 - 8 = 70;70 > 60,则 78 - 8 > 60;6 个一是 6, 1 个十是 10,合起来是 16;16 < 61,则 6 个一和 1 个十 < 61;67 元 - 50 元 = 17 元;17 元 < 27 元,则 67 元 - 50 元 < 27 元;36角+20角=56角;6元=60角;56角<60角,则36角+20角<6元。", + "knowledge_points": [ + "100 以内数的比大小", + "两位数与整十数的减法", + "一位数与两位数的进位加法", + "元,角,分的认识及换算" + ], + "source": "23-24一年级下·山东济宁·期末" + }, + { + "id": "318", + "unit": "第六单元100以内的加法和减法4", + "question_type": "填空题", + "difficulty": 0.85, + "question": "个位上的数是 6,十位上的数是 5,这个数是( ), 再添上 4 个一是( )。", + "options": [], + "answer": "56;60", + "solution": "【分析】个位上的数是 6 表示 6 个一,十位上的数是 5 表示 5 个十,合起来是 56;4 个一是 4, 56 再添上 4 个一是 56 + 4 = 60 .\n【详解】由分析可知:个位上的数是 6,十位上的数是 5,这个数是 56,再添上 4 个一是 60 。", + "knowledge_points": [ + "100以内数的组成", + "一位数与两位数的进位加法" + ], + "source": "23-24 一年级下·山东济宁·期末" + }, + { + "id": "319", + "unit": "第六单元100以内的加法和减法4", + "question_type": "填空题", + "difficulty": 0.65, + "question": "在括号里填上合适的数.\n35 + () > 4070 - () < 62\n82 - () = 7235 + () = 35 - ()", + "options": [], + "answer": "6;9;10;0;0", + "solution": "【分析】第 1 题:左侧算式结果大于 40 即可,比 40 大的数有 41, 42, 43。 可使结果为 41;第2题:左侧算式结果小于62即可,比62小的数有61, 60, 59。可使结果为 61;第3题:82里有8个十和2个一,72里有7个十和2个一,82里减去1个十就是72,也就是减去10是72;第4题:35加上这个数等于35减去这个数,也就是这个数的存在不影响算式的结果,这个数是0.\n【详解】35 正着数 6 个数是 41,即 35 + 6 > 40;(答案不唯一)70 倒着数 9 个数是 61,即 70 - 9 < 62;(答案不唯一)82 - 10 = 72;35 + 0 = 35 - 0 。", + "knowledge_points": [ + "100 以内数的比大小", + "两位数与整十数的减法", + "一位数与两位数的进位加法", + "一位数与两位数的退位减法" + ], + "source": "23-24 一年级下·河南南阳·期末" + }, + { + "id": "320", + "unit": "第六单元100以内的加法和减法4", + "question_type": "填空题", + "difficulty": 0.65, + "question": "学校合唱队队员站成 3 排照相,第一排站了 10 人,第二排和第三排依次多站了 5 人,学校合唱队一共有()人。", + "options": [], + "answer": "45", + "solution": "【分析】根据题意,第一排站了 10 人,第二排和第三排依次多战 5 人,第一排的人数 +5 = 第二排的人数,第二排的人数 +5 = 第三排的人数,然后第一排的人数 + 第二排的人数 + 第三排的人数 = 一共的人数,据此解答.\n【详解】第二排: 10 + 5 = 15 (人)第三排: 15 + 5 = 20 (人)一共: 10 + 15 + 20 = 45 (人)学校合唱队队员站成 3 排照相,第一排站了 10 人,第二排和第三排依次多站了 5 人,学校合唱队一共有(45)人。", + "knowledge_points": [ + "整十数加,减一位数", + "100以内数的连加运算" + ], + "source": "23-24 一年级下·山东济南·期末" + }, + { + "id": "321", + "unit": "第六单元100以内的加法和减法4", + "question_type": "填空题", + "difficulty": 0.65, + "question": "84 是由( )个十和( )个一组成的;6 个一和 3 个十合起来是( ), 它与最小的两位数相差( )。", + "options": [], + "answer": "8;4;36;26", + "solution": "【分析】一个两位数,从右往左依次为个位,十位。十位是几就有几个十,个位是几就有几个一。几个十就是几十,几个一就是几,合起来就是几十几。最小的两位数是 10,它们的差用减法计算.\n【详解】 36 - 10 = 26;84是由8个十和4个一组成的;6个一和3个十合起来是36,它与最小的两位数相差 26。", + "knowledge_points": [ + "100以内数的组成", + "两位数与整十数的减法" + ], + "source": "23-24 一年级下·湖南衡阳·期末" + }, + { + "id": "322", + "unit": "第六单元100以内的加法和减法4", + "question_type": "填空题", + "difficulty": 0.65, + "question": "有 38 个羽毛球, 10 个装一筒,可以装满( )筒,再添加( )个羽毛球,又可以装满一筒。", + "options": [], + "answer": "3;2", + "solution": "【分析】根据题意,羽毛球的总数量依次减去 10,减到最后的数量不够装满一筒为止,减了几次 10 就是能装满几筒。一筒的数量一最后剩下的数量,就是要添上的数量.\n【详解】 38 - 10 = 28 (个);28 - 10 = 18 (个)18 - 10 = 8 (个)10 - 8 = 2 (个) 。有 38 个羽毛球, 10 个装一筒,可以装满 3 筒,再添加 2 个羽毛球,又可以装满一筒。", + "knowledge_points": [ + "两位数与整十数的减法" + ], + "source": "23-24 一年级下·湖南湘西·期末" + }, + { + "id": "323", + "unit": "第六单元100以内的加法和减法4", + "question_type": "填空题", + "difficulty": 0.65, + "question": "80 前面的一个数是( );58 后面的第 5 个数是( )。", + "options": [], + "answer": "79;63", + "solution": "【分析】80前面的一个数也就是比它小1的数,用减法计算;58后面的第5个数,也就是比它大5的数,用加法计算.\n【详解】 80 - 1 = 79;58 + 5 = 63;80前面的一个数是79;58后面的第5个数是63。", + "knowledge_points": [ + "一位数与两位数的进位加法", + "一位数与两位数的退位减法" + ], + "source": "23-24 一年级下·山东日照·期末" + }, + { + "id": "324", + "unit": "第六单元100以内的加法和减法4", + "question_type": "填空题", + "difficulty": 0.85, + "question": "26 - ☆ = 20+☆ ,算式中的☆表示同一个数,这个数是( )。", + "options": [], + "answer": "3", + "solution": "【分析】根据题意,26减去这个数等于20加上这个数,那么26减去20的差就是两个☆的和,把这个和分成两个相同的数即可,由此解答.\n【详解】26-20=6;6可以分成3和3。即26-3=20+3=23。26-☆=20+☆,算式中的☆表示同一个数,这个数是3。", + "knowledge_points": [ + "整十数加,减一位数", + "两位数与一位数的减法(不退位)" + ], + "source": "23-24一年级下·广西柳州·期末" + }, + { + "id": "325", + "unit": "第六单元100以内的加法和减法4", + "question_type": "填空题", + "difficulty": 0.65, + "question": "芳芳原来有( )枚邮票.\n![](images/b7136660e9103d0d155f5364cd00e74025e776547d272458bd7b8d65fe65f863.jpg)", + "options": [], + "answer": "21", + "solution": "【分析】根据题意,芳芳给平平3枚,他们的邮票数量就同样多,由此用平平邮票的数量加芳芳给平平的数量,求出一样多时邮票的数量。再加上给平平的数量就是原来芳芳邮票的数量.\n【详解】15+3=18(枚);18+3=21(枚)。芳芳原来有21枚邮票。", + "knowledge_points": [ + "不进位加法(20以内)", + "一位数与两位数的进位加法" + ], + "source": "23-24 一年级下·广东佛山·期末" + }, + { + "id": "326", + "unit": "第六单元100以内的加法和减法4", + "question_type": "填空题", + "difficulty": 0.65, + "question": "在括号里填上 \">\" \"<\" 或 \"=\" .\n35+4( )40\n54( )64-10\n1元5角( )9角+7角", + "options": [], + "answer": "<;=;<", + "solution": "【分析】根据整数加减法的计算法则,依次计算出各算式的结果再比较大小。比较时,位数多的数就大;位数相同比较最高位,最高位大的数就大;最高位相同比较下一位,直到比较出结果为止。人民币的题目先统一单位再比较.\n【详解】 35 + 4 = 39;39 < 40,则 35 + 4 < 40; 54 = 64 - 10; 1元 = 10 角;1元5角 = 15 角;9角 +7 角 = 16 角;15角 < 16角,则1元5角 < 9 角 +7 角。", + "knowledge_points": [ + "100 以内数的比大小", + "两位数与一位数的加法(不进位)", + "两位数与整十数的减法", + "元,角,分的认识及换算" + ], + "source": "23-24 一年级下·广东佛山·期末" + }, + { + "id": "327", + "unit": "第六单元100以内的加法和减法4", + "question_type": "填空题", + "difficulty": 0.65, + "question": "有 26 个气球, 5 个捆成一束,可以捆成( )束,还剩( )个。", + "options": [], + "answer": "5;1", + "solution": "【分析】根据题意,用气球的总数量依次减去 5,减到最后的数量不够捆成一束为止,减了几次 5 就是能捆成几束,最后的得数就是还剩的数量.\n【详解】 26 - 5 = 21 (个);21 - 5 = 16 (个);16 - 5 = 11 (个);11-5=6(个);6 - 5 = 1 (个)。有 26 个气球, 5 个捆成一束,可以捆成 5 束,还剩 1 个。", + "knowledge_points": [ + "十几减 5 ~ 2 的退位减法", + "一位数与两位数的退位减法" + ], + "source": "23-24 一年级下·广东佛山·期末" + }, + { + "id": "328", + "unit": "第六单元100以内的加法和减法4", + "question_type": "填空题", + "difficulty": 0.85, + "question": "20 比 37 少( ),比20多9的数是( )。", + "options": [], + "answer": "17;29", + "solution": "【分析】求一个数比另一个数少多少,用另一个数减这个数计算;求比一个数多几的数是多少,用这个数加多的数计算.\n【详解】37-20=17;20+9=29;20比37少17,比20多9的数是29。", + "knowledge_points": [ + "整十数加,减一位数", + "两位数与整十数的减法" + ], + "source": "23-24 一年级下·广东佛山·期末" + }, + { + "id": "329", + "unit": "第六单元100以内的加法和减法4", + "question_type": "填空题", + "difficulty": 0.85, + "question": "在括号里填上 \">\" \"<\" 或 \"=\" .\n70 + 20()8949 + 9()501元( )100分 5元( )63角", + "options": [], + "answer": ">;>;=;<", + "solution": "【分析】1元 = 10 角, 1角 = 10 分, 1元 = 100 分,单位换算后再比较大小;整十数加减整十数,直接将十位上的数字相加减,再在计算的结果末尾添上一个0;两位数加一位数的进位加法,用个位上的数加一位数后,还要加上整十数分别计算出结果后再比较大小.\n【详解】 70 + 20 = 90,所以 70 + 20 > 89;49 + 9 = 58,所以 49 + 9 > 50;1元 = 100 分;5元=50角,所以5元<63角", + "knowledge_points": [ + "100 以内数的比大小", + "一位数与两位数的进位加法", + "元,角,分的认识及换算" + ], + "source": "23-24 一年级下·江西赣州·期末" + }, + { + "id": "330", + "unit": "第六单元100以内的加法和减法4", + "question_type": "填空题", + "difficulty": 0.65, + "question": "在括号里填上\">\" \"<\"或\"=\".\n74( )47\n26+9( )29+6\n43-3( )42-3\n50元( )50角\n6元+6角( )12元\n53角( )5元3角", + "options": [], + "answer": ">;=;>;<;<;=", + "solution": "【分析】根据整数加减法的计算法则,依次计算出各算式的结果再比较大小。比较时,位数多的数就大;位数相同比较最高位,最高位大的数就大;最高位相同比较下一位,直到比较出结果为止。人民币的题目先统一单位再比较.\n【详解】74和47都是两位数,十位7>4,则74>47;26+9=35;29+6=35;35=35,则26+9=29+6;43-3=40;42-3=39;40>39,则43-3>42-3;10角=1元;50角=5元;50元>5元,则50元>50角;6元+6角=66角;66角<120角;120角=12元,则6元+6角<12元;53角=5元3角。", + "knowledge_points": [ + "100 以内数的比大小", + "一位数与两位数的进位加法", + "一位数与两位数的退位减法", + "元,角,分的认识及换算" + ], + "source": "23-24 一年级下·福建福州·期末" + }, + { + "id": "331", + "unit": "第六单元100以内的加法和减法4", + "question_type": "填空题", + "difficulty": 0.65, + "question": "40 - 7 = ( ), 想: 0 减 7 不够减,先算( ), 再算( )。", + "options": [], + "answer": "33;10 - 7 = 3;30 + 3 = 33", + "solution": "【分析】两位数减一位数,从个位算起,0 减 7 不够减,向十位借 1,先算 10 - 7 = 3,再算 30 + 3 = 33,所以 40 - 7 = 33 .\n【详解】由分析可得: 40 - 7 = 33,想:0减7不够减,先算 10 - 7 = 3,再算 30 + 3 = 33 。", + "knowledge_points": [ + "一位数与两位数的退位减法" + ], + "source": "23-24 一年级下·福建龙岩·期末" + }, + { + "id": "332", + "unit": "第六单元100以内的加法和减法4", + "question_type": "填空题", + "difficulty": 0.65, + "question": "在括号里填上\">\"\"<\"或\"=\".\n56+40( )69\n66-30( )63\n1元6角( )18角\n42+8( )8+42\n89-70( )9\n5元6角( )5角6分", + "options": [], + "answer": ">;<;<;=;>", + "solution": "【分析】根据整数加减法的计算法则依次计算出各算式的结果再比较大小。比较时,位数多的数就大;位数相同比较最高位,最高位大的数就大;最高位相同比较下一位,直到比较出结果为止。人民币的题目先统一单位再比较.\n【详解】56+40=96,所以56+40>69;66-30=36,所以66-30<63;1元6角=16角,所以1元6角<18角;42+8=50,8+42=50,所以42+8=8+42;89-70=19,所以89-70>9;5元6角=56角,5角6分<56角,所以5元6角>5角6分。", + "knowledge_points": [ + "100 以内数的比大小", + "两位数与整十数的减法", + "一位数与两位数的进位加法", + "元,角,分的认识及换算" + ], + "source": "23-24一年级下·山东济宁·期末" + }, + { + "id": "333", + "unit": "第六单元100以内的加法和减法4", + "question_type": "填空题", + "difficulty": 0.65, + "question": "6 比 30 少( ),比36多8的数是( )。", + "options": [], + "answer": "24;44", + "solution": "【分析】求 6 比 30 少多少,用 30 减 6 即可;求比 36 多 8 的数,用 36 加 8 即可.\n【详解】 30 - 6 = 24, 36 + 8 = 44.6 比 30 少 24,比 36 多 8 的数是 44。", + "knowledge_points": [ + "一位数与两位数的进位加法", + "一位数与两位数的退位减法" + ], + "source": "23-24 一年级下·山东济宁·期末" + }, + { + "id": "334", + "unit": "第六单元100以内的加法和减法4", + "question_type": "填空题", + "difficulty": 0.65, + "question": "58 块饼干, 10 块装一袋,可以装满( )袋,还多( )块。", + "options": [], + "answer": "5;8", + "solution": "【分析】饼干的总数依次减去每袋饼干的块数,减的次数表示能装满的袋数,剩下的表示还多的块数.\n【详解】 58 - 10 = 48 (块), 48 - 10 = 38 (块), 38 - 10 = 28 (块), 28 - 10 = 18 (块), 18 - 10 = 8 (块)。58块饼干,10块装一袋,可以装满5袋,还多8块。", + "knowledge_points": [ + "两位数与整十数的减法" + ], + "source": "23-24 一年级下·山东济宁·期末" + }, + { + "id": "335", + "unit": "第六单元100以内的加法和减法4", + "question_type": "填空题", + "difficulty": 0.65, + "question": "乐乐在做一道数学题时,因为自己的马虎,把一个数加 5 做成了减 5,结果得 68,正确的结果应该是( )。", + "options": [], + "answer": "78", + "solution": "【分析】先根据被减数减减数=差,用68+5求出错误算式的被减数也就是正确算式的一个加数是多少,再用这个加数加上5即可求出正确的结果.\n【详解】68+5=73;73+5=78;所以正确的结果应该是78。", + "knowledge_points": [ + "两位数与一位数的加法(不进位)", + "一位数与两位数的进位加法" + ], + "source": "23-24 一年级下·贵州铜仁·期末" + }, + { + "id": "336", + "unit": "第六单元100以内的加法和减法4", + "question_type": "填空题", + "difficulty": 0.65, + "question": "在括号里填上\">\"\"<\"或\"=\".\n3 + 58 () 628元5角 () 85角 65 + 7 () 65 - 7", + "options": [], + "answer": "<;=;>", + "solution": "【分析】根据整数加减法的计算法则依次计算出各算式的结果再比较大小。比较时,位数多的数就大;位数相同比较最高位,最高位大的数就大;最高位相同比较下一位,直到比较出结果为止。人民币的题目先统一单位再比较.\n【详解】 3 + 58 = 61,所以 3 + 58 < 62;8元5角 = 80 角 +5 角 = 85 角;65 + 7 = 72, 65 - 7 = 58,所以 65 + 7 > 65 - 7 。", + "knowledge_points": [ + "100 以内数的比大小", + "一位数与两位数的进位加法", + "一位数与两位数的退位减法", + "元,角,分的认识及换算" + ], + "source": "23-24一年级下·贵州铜仁·期末" + }, + { + "id": "337", + "unit": "第六单元100以内的加法和减法4", + "question_type": "填空题", + "difficulty": 0.65, + "question": "65 比( )少 8,比 65 少 8 的数是( )。", + "options": [], + "answer": "73;57", + "solution": "【分析】已知一个数比另一个数少几,求另一个数是多少,用加法计算;求比一个数少几的数是多少,用减法计算即可.\n【详解】 65 + 8 = 73;65 - 8 = 57;所以 65 比 73 少 8,比 65 少 8 的数是 57 。", + "knowledge_points": [ + "一位数与两位数的进位加法", + "一位数与两位数的退位减法" + ], + "source": "23-24 一年级下·贵州铜仁·期末" + }, + { + "id": "338", + "unit": "第六单元100以内的加法和减法4", + "question_type": "填空题", + "difficulty": 0.65, + "question": "填一填.\n12-5=( )\n( )+6=12\n3+( )=11\n( )-6=8\n24-7=( )\n( )-10=8", + "options": [], + "answer": "7;6;8;14;17;18", + "solution": "【分析】根据和减一个加数=另一个加数;减数加差=被减数计算即可.\n【详解】12-5=7;12-6=6,则6+6=12;11-3=8,则3+8=11;6+8=14,则14-6=8;24-7=17;10+8=18,则18-10=8。", + "knowledge_points": [ + "十几减 5 ~ 2 的退位减法", + "7,6 加几的进位加法", + "一位数与两位数的退位减法" + ], + "source": "23-24 一年级下·广东江门·期末" + }, + { + "id": "339", + "unit": "第六单元100以内的加法和减法4", + "question_type": "填空题", + "difficulty": 0.65, + "question": "32比24多( ),56比( )少4。", + "options": [], + "answer": "8;60", + "solution": "【分析】求32比24多几,用减法计算;已知一个数比另一个数少几,求另一个数,用这个数加少的数计算.\n【详解】32-24=8;56+4=60。32比24多8,56比60少4。", + "knowledge_points": [ + "数 100 以内的数", + "一位数与两位数的进位加法" + ], + "source": "23-24一年级下·广东江门·期末" + }, + { + "id": "340", + "unit": "第六单元100以内的加法和减法4", + "question_type": "填空题", + "difficulty": 0.85, + "question": "36 连续减 4:36,32,28,( ),( )。", + "options": [], + "answer": "24;20", + "solution": "【分析】根据题意,36连续减4,也就是在前一个数的基础上依次减4,根据整数减法的计算法则,依次计算出所得的结果填写即可.\n【详解】36-4=32;32-4=28;28-4=24;24-4=20。36连续减4:36,32,28,24,20。", + "knowledge_points": [ + "两位数与一位数的减法(不退位)", + "一位数与两位数的退位减法", + "连加,连减同数问题" + ], + "source": "23-24 一年级下·广东江门·期末" + }, + { + "id": "341", + "unit": "第六单元100以内的加法和减法4", + "question_type": "填空题", + "difficulty": 0.65, + "question": "在下面的括号里填上合适的数.\n79 - () = 7040 + () = 7818 - () = 9", + "options": [], + "answer": "9;38;9", + "solution": "【分析】根据被减数减差=减数;和减一个加数=另一个加数,计算即可.\n【详解】79-70=9,则79-9=70;78-40=38,则40+38=78;18-9=9。", + "knowledge_points": [ + "十几减 9 的退位减法", + "两位数与整十数的加法", + "两位数与一位数的减法(不退位)", + "两位数与整十数的减法" + ], + "source": "23-24 一年级下·山东济宁·期末" + }, + { + "id": "342", + "unit": "第六单元100以内的加法和减法4", + "question_type": "填空题", + "difficulty": 0.65, + "question": "在括号里填上\">\" \"<\"或\"=\" .\n59+4( )66\n98-30( )68\n9元1角( )10元\n95-8( )85\n66+20( )96\n5元4角( )9角7分", + "options": [], + "answer": "<;=;<;>;<;>", + "solution": "【分析】根据整数加减法的计算法则,依次计算出各算式的结果再比较大小,比较时,位数多的数就大;位数相同比较最高位,最高位大的数就大;最高位相同比较下一位,直到比较出结果为止。人民币的题目先统一单位再比较.\n【详解】59+4=63;63<66,则59+4<66;98-30=68;1元=10角;9元1角=91角;10元=100角;91角<100角,则9元1角<10元;95-8=87;87>85,则95-8>85;66+20=86;86<96,则66+20<96;5元4角>1元;1元=100分;9角7分=97分;100分>97分,则5元4角>9角7分。", + "knowledge_points": [ + "100 以内数的比大小", + "一位数与两位数的进位加法", + "一位数与两位数的退位减法", + "元,角,分的认识及换算" + ], + "source": "23-24一年级下·山东济宁·期末" + }, + { + "id": "343", + "unit": "第六单元100以内的加法和减法4", + "question_type": "填空题", + "difficulty": 0.65, + "question": "在括号里填上\">\"\"<\"或\"=\" .\n43-9( )33\n7元8分( )78角\n1元( )10角\n56+8( )70\n6元-4角( )5元4角", + "options": [], + "answer": ">;<;=;<;>", + "solution": "【分析】(1) 将 43 - 9 的结果计算出来,再与 33 进行比较即可;(2) 根据元与角,角与分的进率, 1 元 = 10 角, 1 角 = 10 分,单位统一再进行比较即可;(3) 根据元与角的进率, 1 元 = 10 角,单位统一再进行比较即可;(4) 将 56 + 8 的结果计算出来,再与 70 进行比较即可;(5) 根据元与角的进率, 1 元 = 10 角,单位统一后计算出来再进行比较即可.\n【详解】 (1) 43 - 9 = 34, 34 > 33,所以 43 - 9 > 33;(2) 78角 = 7元 8角, 8角 = 80分, 8分 < 80分,即 7 元 8 分 < 7 元 8 角,所以 7 元 8 分 < 78角;(3) 1元 = 10 角, 10角 = 10 角,所以1元 = 10 角;(4) 56 + 8 = 64, 64 < 70,所以 56 + 8 < 70;(5) 6元 = 60 角, 60角 -4 角 = 56 角, 5元4角 = 54 角,56角 >54 角,所以 6 元 -4 角 >5 元 4 角。", + "knowledge_points": [ + "一位数与两位数的进位加法", + "一位数与两位数的退位减法", + "元,角,分的认识及换算", + "十元以下人民币的认识与计算" + ], + "source": "23-24一年级下·河北邢台·期末" + }, + { + "id": "344", + "unit": "第六单元100以内的加法和减法4", + "question_type": "填空题", + "difficulty": 0.65, + "question": "在括号里填上\">\"\"<\"或\"=\" .\n45( )50\n36+0( )36-0\n60-50( )60-5\n2元( )20角\n5元-10角( )3元\n3+5( )1+5", + "options": [], + "answer": "<;=;<;=;>", + "solution": "【分析】先把括号两边的算式计算出结果,再比较大小,1元 = 10 角,单位不统一时,先统一单位后再计算,最后再进行比较大小,比较大小时,先看数位,数位多的那个数就大,数位相同时,从最高位比起,最高位哪个数大哪个数就大,最高位相同时,依次比较下一位,直到比出大小为止,据此解答.\n【详解】(1)45 十位是 4,50 十位是 5,4 小于 5,填空为:45 (<) 50;(2) 36 + 0 = 36, 36 - 0 = 36,填空为: 36 + 0 (=) 36- 0;(3) 60 - 50 = 10, 60 - 5 = 55, 10 小于 55,填空为: 60- 50(<) 60 - 5;(4) 2元 = 20 角,填空为: 2元 (=) 20角;(5) 5元-10角 = 40角 = 4元,4元大于3元,填空为:5元-10角(>)3元;(6) 3 + 5 = 8, 1×5 = 5, 8 大于 5,填空为: 3 + 5 (> ) 1×5;", + "knowledge_points": [ + "100 以内数的比大小", + "整十数之间的加减法", + "一位数与两位数的退位减法", + "元,角,分的认识及换算" + ], + "source": "23-24一年级下·山东济南·期末" + }, + { + "id": "345", + "unit": "第六单元100以内的加法和减法4", + "question_type": "填空题", + "difficulty": 0.65, + "question": "76 个羽毛球,每 10 个装一盒,可以装满( )盒,还剩( )个。", + "options": [], + "answer": "7;6", + "solution": "【分析】用羽毛球的总数连续减去一盒装的个数,直到得数小于10,减去几个10,就能装满几盒,差即为还剩的个数.\n【详解】76-10-10-10-10-10-10=6(个)。连续减去7个10,所以可以装满7盒;所以76个羽毛球,每10个装一盒,可以装满7盒,还剩6个。", + "knowledge_points": [ + "100以内数的连减运算" + ], + "source": "23-24 一年级下·湖南衡阳·期末" + }, + { + "id": "346", + "unit": "第六单元100以内的加法和减法4", + "question_type": "填空题", + "difficulty": 0.65, + "question": "在下面的横线上填上合适的数,在括号里填上 \">\" \"<\" 或 \"=\" .\n23+( )=33\n94-( )=88\n( )+30=78\n17-9( )10\n26+40( )30\n86-60( )26", + "options": [], + "answer": "10;6;48;<;>;=", + "solution": "【分析】第 1 题: 23 里面有 2 个十和 3 个一, 33 里面有 3 个十和 3 个一, 23 再加上 1 个十就是 33,也就是再加上 10 是 33;第2题:94倒着数6个数就是88,也就是94减6就是88;第3题:30里面有3个十,78里面有7个十和8个一,30再加上 4 个十和 8 个一是 78,也就是再加上 48 是 78;第4,5,6题根据整数加减法的计算法则,依次计算出结果再比较大小。比较时,位数多的数就大;位数相同比较最高位,最高位大的数就大;最高位相同比较下一位,直到比较出结果为止.\n【详解】 23 + 10 = 33;94 - 6 = 88;48 + 30 = 78;17 - 9 = 8;8 < 10,则 17 - 9 < 10;26 + 40 = 66;66 > 30,则 26 + 40 > 30;86 - 60 = 26 。", + "knowledge_points": [ + "100以内数的比大小", + "十几减9的退位减法", + "两位数与整十数的加法", + "两位数与整十数的减法" + ], + "source": "23-24 一年级下·湖南衡阳·期末" + }, + { + "id": "347", + "unit": "第六单元100以内的加法和减法4", + "question_type": "填空题", + "difficulty": 0.65, + "question": "比 26 多 4 的数是( );比 38 少 2 的数是( );60 比 40 多( )。", + "options": [], + "answer": "30;36;20", + "solution": "【分析】(1)求比一个数多多少的数是多少,用加法计算;(2) 求比一个数少多少的数是多少,用减法计算;(3) 求大数比小数多多少用减法计算.\n【详解】 (1) 26 + 4 = 30(2) 38 - 2 = 36 (3) 60 - 40 = 20\n所以比 26 多 4 的数是 30;比 38 少 2 的数是 36;60 比 40 多 20。", + "knowledge_points": [ + "整十数之间的加减法", + "两位数与一位数的减法(不退位)", + "一位数与两位数的进位加法" + ], + "source": "23-24 一年级下·湖南衡阳·期末" + }, + { + "id": "348", + "unit": "第六单元100以内的加法和减法4", + "question_type": "填空题", + "difficulty": 0.85, + "question": "在括号里填上\">\" \"<\"或\"=\" .\n67-30( )35\n69( )29+40\n99( )100\n88( )65+8\n100( )10+10\n1元( )9角8分", + "options": [], + "answer": ">;=;<;>;>;>", + "solution": "【分析】有算式先算出算式的得数,再根据100以内数的大小比较方法:先看十位上的数,十位上的数大这个数就大;十位上的数相同再比较个位上的数,个位上的数大这个数就大。1元=10角,先进行单位换算,再进行比较大小.\n【详解】67-30=37,37>35,所以67-30>35;29+40=69,所以69=29+40;99<100;65+8=73,88>73,所以88>65+8;10+10=20,100>20,所以100>10+10;1元=10角,10角>9角8分,所以1元>9角8分。", + "knowledge_points": [ + "100 以内数的比大小", + "两位数与整十数的减法", + "一位数与两位数的进位加法", + "元,角,分的认识及换算" + ], + "source": "23-24一年级下·山东临沂·期末" + }, + { + "id": "349", + "unit": "第六单元100以内的加法和减法4", + "question_type": "填空题", + "difficulty": 0.65, + "question": "62 比 4 多( ), 50 比 84 少( )。", + "options": [], + "answer": "58;34", + "solution": "【分析】求一个数比另一个数多多少,用这个数减去另一个数计算;求一个数比另一个数少多少,用另一个数减去这个数计算.\n【详解】 62 - 4 = 58;84 - 50 = 34;62 比 4 多 58, 50 比 84 少 34。", + "knowledge_points": [ + "两位数与整十数的减法", + "一位数与两位数的退位减法" + ], + "source": "23-24 一年级下·山东济宁·期末" + }, + { + "id": "350", + "unit": "第六单元100以内的加法和减法4", + "question_type": "填空题", + "difficulty": 0.65, + "question": "在括号里填上\">\" \"<\"或\"=\" .\n53+5( )43\n24( )35-4\n23+9( )25+6\n10角( )1元2角\n13元( )10元+3角\n49-4-9( )49-(4+9)", + "options": [], + "answer": ">;<;>;<;>;=", + "solution": "【分析】根据整数加减法的计算法则依次计算出各算式的结果再比较大小。比较时,位数多的数就大;位数相同比较最高位,最高位大的数就大;最高位相同比较下一位,直到比较出结果为止。人民币的题目先统一单位再比较.\n【详解】53+5=58,所以53+5>43;35-4=31,所以24<35-4;23+9=32,25+6=31,所以23+9>25+6;1元2角=12角,所以10角<1元2角;10元+3角=10元3角,13元>10元3角,所以13元>10元+3角;49-4-9=45-9=36,49-(4+9)=49-13=36,所以49-4-9=49-(4+9)。", + "knowledge_points": [ + "100以内数的比大小", + "两位数与一位数的加法(不进位)", + "100以内数的连减运算", + "十元以上人民币的认识与计算" + ], + "source": "23-24一年级下·湖南湘西·期末" + }, + { + "id": "351", + "unit": "第六单元100以内的加法和减法4", + "question_type": "填空题", + "difficulty": 0.65, + "question": "按规律填一填.\n(1)5,10,15,20,( ),( ).\n(2)83,79,75,71,( ),( ),( )。", + "options": [], + "answer": "25;30;67;63;59", + "solution": "【分析】根据题目所给的相邻两个数找出规律,然后进行填数即可;(1) 这一排数字逐个加 5;(2) 这一排数字逐个减 4.\n【详解】 (1) 20 + 5 = 25;25 + 5 = 30;所以是 5, 10, 15, 20, 25, 30;(2) 71 - 4 = 67;67 - 4 = 63;63 - 4 = 59;所以是 83, 79, 75, 71, 67, 63, 59。", + "knowledge_points": [ + "两位数与一位数的加法(不进位)", + "一位数与两位数的进位加法", + "一位数与两位数的退位减法", + "整数排列的规律" + ], + "source": "23-24一年级下·湖南湘西·期末" + }, + { + "id": "352", + "unit": "第六单元100以内的加法和减法4", + "question_type": "填空题", + "difficulty": 0.65, + "question": "填空.\n100、37、46、87、5\n(1)上面的数中个位上是7的数是( )。十位上是7的数是( ).\n(2)上面的数中最接近70的数是( ).\n(3)上面的数从小到大排列是( )<()<()<()<()。", + "options": [], + "answer": "37;75;68;4;37;68;75;100", + "solution": "【分析】(1)根据整数的数位顺序可知,从右边起第一位是个位,第二位是十位;(2)上面的数中最接近70的数应先看十位是6或7的数,有68和75,分别算出与70的差,选择差最小的数即可;(3)三位数大于两位数,两位数大于一位数。相同数位,先比较十位,十位大的数大,十位相同比较个位,个位大的数大.\n【详解】(1)上面的数中个位上是7的数是37。十位上是7的数是75。(2)75-70=5,70-68=2。上面的数中最接近70的数是68。(3)上面的数从小到大排列是4<37<68<75<100。", + "knowledge_points": [ + "100 以内数的比大小", + "100 以内数的组成", + "两位数与整十数的减法", + "两位数与两位数的退位减法" + ], + "source": "23-24 一年级下·山东临沂·期末" + }, + { + "id": "353", + "unit": "第六单元100以内的加法和减法4", + "question_type": "填空题", + "difficulty": 0.65, + "question": "按规律填数.\n(1)19,16,13,10,( ),( ).\n(2)30, 35, 40, ( ), ( ), 55。", + "options": [], + "answer": "7;4;45;50", + "solution": "【分析】(1)19-16=3,16-13=3,13-10=3,规律为:依次减3;(2)35-30=5,40-35=5,40和55之间隔了两个数,相差10,规律为:依次加5.\n【详解】(1)10-3=7,7-3=4。19,16,13,10,7,4。(2)40+5=45,45+5=50。30,35,40,45,50,55。", + "knowledge_points": [ + "不退位减法(20以内)", + "一位数与两位数的进位加法", + "整数排列的规律" + ], + "source": "23-24 一年级下·山东临沂·期末" + }, + { + "id": "354", + "unit": "第六单元100以内的加法和减法4", + "question_type": "填空题", + "difficulty": 0.65, + "question": "填写合适的\">\"\"<\"或\"=\" .\n2元1角( )21角\n5元2角( )6元\n45角( )4元6角\n45+20( )65\n23( )32\n47+20( )27+40", + "options": [], + "answer": "=;<;<;=;<;=", + "solution": "【分析】单位不同的先根据1元=10角换算成相同的单位再比较大小,如:2元1角=21角;有算式的先计算出结果然后再比较大小.\n【详解】2元1角=21角;5元2角=52角,6元=60角,52<60,故5元2角<6元;4元6角=46角,45<46,故45角<4元6角;45+20=65;23<32;47+20=67,27+40=67,67=67,故47+20=27+40。", + "knowledge_points": [ + "100 以内数的比大小", + "元,角,分的认识及换算" + ], + "source": "23-24一年级下·山东临沂·期末" + }, + { + "id": "355", + "unit": "第六单元100以内的加法和减法4", + "question_type": "填空题", + "difficulty": 0.65, + "question": "在括号里填上 \"+\" 或 \"-\" .\n88( )9=79\n36( )30=66\n50( )40=10\n76( )20=56\n47( )8=55\n68( )9=59\n27( )7=34\n60( )30=30", + "options": [], + "answer": "-;+;-;-;+;-;+;-", + "solution": "【分析】加数加加数=和,被减数减减数=差.\n【详解】88-9=79;36+30=66;50-40=10;76-20=56;47+8=55;68-9=59;27+7=34;60-30=30。", + "knowledge_points": [ + "整十数之间的加减法", + "两位数与整十数的加法", + "两位数与整十数的减法", + "一位数与两位数的退位减法" + ], + "source": "23-24 一年级下·贵州铜仁·期末" + }, + { + "id": "356", + "unit": "第六单元100以内的加法和减法4", + "question_type": "判断题", + "difficulty": 0.65, + "question": "一共有 30 个球,每盒装 7 个,最多可以装满 4 盒。( )", + "options": [], + "answer": "√", + "solution": "【分析】根据题意,用球的总数量依次减去 7,减到最后的数量不够装满 1 盒为止,减了几次 7 就能装满几盒.\n【详解】 30 - 7 = 23 (个);23 - 7 = 16 (个);16 - 7 =9 (个);9 - 7 = 2 (个)一共有 30 个球,每盒装 7 个,最多可以装满 4 盒。原题说法正确。故答案为: √", + "knowledge_points": [ + "十几减 7,6 的退位减法", + "一位数与两位数的退位减法" + ], + "source": "23-24 一年级下·河南·期末" + }, + { + "id": "357", + "unit": "第六单元100以内的加法和减法4", + "question_type": "判断题", + "difficulty": 0.65, + "question": "35+ (8-6) 与 35+8-6 的结果相等。( )", + "options": [], + "answer": "√", + "solution": "【分析】整数混合运算中,只有加减法的算式从左往右计算;有括号的先算括号里面的,再算括号外面的,由此计算出结果判断即可.\n【详解】35+(8-6)=35+2=37;35+8-6=43-6=37。35+(8-6)与35+8-6的结果相等。原题说法正确。故答案为:√", + "knowledge_points": [ + "100 以内数的加减混合运算", + "带有小括号的混合运算" + ], + "source": "23-24一年级下·广西柳州·期末" + }, + { + "id": "358", + "unit": "第六单元100以内的加法和减法4", + "question_type": "判断题", + "difficulty": 0.65, + "question": "摆小棒计算 35 + 20 和 35 + 2 时,摆法一样。( )", + "options": [], + "answer": "×", + "solution": "【分析】一捆小棒表示 1 个十,一根小棒表示 1 个一。摆小棒计算 35 + 20 应摆 3 捆小棒 5 根小棒 +2 捆小棒,摆小棒计算 35 + 2 应摆 3 捆小棒 5 根小棒 +2 根小棒,摆法不一样.\n【详解】摆小棒计算 35 + 20 和 35 + 2 时,摆法一样,说法错误。故答案为: ×", + "knowledge_points": [ + "100 以内数的组成", + "两位数与一位数的加法(不进位)", + "两位数与整十数的加法" + ], + "source": "23-24 一年级下·山东临沂·期末" + }, + { + "id": "359", + "unit": "第六单元100以内的加法和减法4", + "question_type": "判断题", + "difficulty": 0.85, + "question": "被减数是 65,减数是 30,差是 35。( )", + "options": [], + "answer": "√", + "solution": "【分析】根据被减数减减数=差,代入数值即可求出差是多少,再看差是否是35即可.\n【详解】65-30=35;所以被减数是65,减数是30,差是35。原题说法正确。故答案为:√", + "knowledge_points": [ + "两位数与整十数的减法" + ], + "source": "23-24 一年级下·贵州铜仁·期末" + }, + { + "id": "360", + "unit": "第六单元100以内的加法和减法4", + "question_type": "计算题", + "difficulty": 0.85, + "question": "直接写得数.\n9 + 6 + 7 = 73 - (28 - 20) = 50 + 27 - 60 =\n52 - 7 - 30 = 53 - (18 + 2) = 82 - (26 - 20) =", + "options": [], + "answer": "22;65;17;15;33;76", + "solution": "【分析】本题考查100以内数的连加,连减,加减混合及带括号的混合运算。计算时必须严格遵守运算顺序:连加连减从左到右;有括号的先算括号内,再算括号外.\n【详解】9加6再加7,先算9加6得15,再加7得22;73减括号里28减20的差,先算括号得8,再减得65;50加27再减60,先算50加27得77,再减60得17;52减7再减30,先算52减7得45,再减30得15;53减括号里18加2的和,先算括号得20,再减得33;82减括号里26减20的差,先算括号得6,再减得76。", + "knowledge_points": [ + "100以内数的连加运算", + "100以内数的连减运算", + "100以内数的加减混合运算", + "带有小括号的混合运算" + ], + "source": "23-24 一年级下·广东江门·期末" + }, + { + "id": "361", + "unit": "第六单元100以内的加法和减法4", + "question_type": "计算题", + "difficulty": 0.65, + "question": "看图列式计算.\n![](images/d26204081db81e42515b77cdf3f7ab5ee11a3aa887037aa340bf911a6668b7a4.jpg)\n□ ○ □ = □ (只)", + "options": [], + "answer": "42 - 10 = 32", + "solution": "【分析】数出左边小鸡的数量,用总数减去左边部分数量,即可得到右边部分的数量.\n【详解】 42 - 10 = 32 (只)所以右边房子中有32只小鸡。", + "knowledge_points": [ + "两位数与整十数的减法" + ], + "source": "23-24 一年级下·山东济宁·期末" + }, + { + "id": "362", + "unit": "第六单元100以内的加法和减法4", + "question_type": "计算题", + "difficulty": 0.85, + "question": "算一算.\n12 - 6 = 32 + 50 = 33 + 7 = 60 - 30 =\n13 + 80 = 70 + 29 = 9 + 27 = 67 - 4 =\n75 - (15 - 7) =", + "options": [], + "answer": "6;82;40;30;93;99;36;63;67", + "solution": "【分析】本题考查100以内数的加减法口算,包含退位减法,整十数加减,不进位加法,进位加法及带括号的减法。需注意进退位规则及括号的优先级.\n【详解】12减6得6;32加50得82;33加7得40;60减30得30;13加80得93;70加29得99;9加27得36;67减4得63;75减括号里15减7的差,先算括号得8,再减得67。", + "knowledge_points": [ + "十几减 7,6 的退位减法", + "整十数之间的加减法", + "一位数与两位数的进位加法", + "带有小括号的混合运算" + ], + "source": "23-24 一年级下·江西抚州·期末" + }, + { + "id": "363", + "unit": "第六单元100以内的加法和减法4", + "question_type": "计算题", + "difficulty": 0.85, + "question": "我会看图列式.\n![](images/b4e8b56d81c3ec7df90f89e9b539780df0789b46cdad078512978867eec6bb94.jpg)\n38元\n![](images/7b510fd69e421bc611379de36d28a50ab4ed6988753780b35056ea98f1fc1ddb.jpg)\n50元\n□ ○ □ = □ (元)", + "options": [], + "answer": "38 + 50 = 88", + "solution": "【分析】求一共多少元,用加法计算,即足球的钱数 + 篮球的钱数 = 总钱数.\n【详解】 38 + 50 = 88 (元)一共88元。", + "knowledge_points": [ + "图文问题", + "两位数与整十数的加法" + ], + "source": "23-24 一年级下·广东佛山·期末" + }, + { + "id": "364", + "unit": "第六单元100以内的加法和减法4", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式计算.\n![](images/2e528be3b8edffb992d4504fad2a579ba8c755f6f3a840bcf471885058aeb402.jpg)\n□ ○ □ = □ ()", + "options": [], + "answer": "20+26=46", + "solution": "【分析】据题意可知,小动物玩偶分别是 20 元和 26 元,两个小玩偶的价格相加即可得出总金额.\n【详解】据分析可得列式: 20 + 26 = 46 (元)。", + "knowledge_points": [ + "两位数与两位数的不进位加法" + ], + "source": "23-24 一年级下·福建福州·期末" + }, + { + "id": "365", + "unit": "第六单元100以内的加法和减法4", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式计算.\n![](images/e5c74b143d2873026a839a2d75134373932d26752acef11c1c8a021ab82b25cf.jpg)\n□ ○ □ = □ ()", + "options": [], + "answer": "36-8=28", + "solution": "【分析】据题意可知,两个物品的总数为 36 支,数一数其中一个的数量为 8 支,两者相减即可知另一个物品有多少.\n【详解】根据分析可得列式: 36 - 8 = 28 (支)。", + "knowledge_points": [ + "一位数与两位数的退位减法" + ], + "source": "23-24 一年级下·福建福州·期末" + }, + { + "id": "366", + "unit": "第六单元100以内的加法和减法4", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式计算.\n![](images/f336b1335963c60b8f3f59f20ba96b32ed4012c6ccfd91abbc1115b973e18002.jpg)\n□ ○ □ = □ (根)", + "options": [], + "answer": "33 + 30 = 63", + "solution": "【分析】一捆小棒表示 1 个十,一根小棒表示 1 个一,左边的小棒共有 33 根,右边有 30 根小棒;左边的加上右边的即可解答.\n【详解】 33 + 30 = 63 (根)", + "knowledge_points": [ + "图文问题", + "两位数与整十数的加法" + ], + "source": "23-24 一年级下·福建龙岩·期末" + }, + { + "id": "367", + "unit": "第六单元100以内的加法和减法4", + "question_type": "计算题", + "difficulty": 0.65, + "question": "看图列式计算.\n![](images/0ea8777866041b85edcc92a82cd471520068bd245265dab998f77943f3fbf2f7.jpg)\n□ ○ □ = □ (元)", + "options": [], + "answer": "26 + 5 = 31", + "solution": "【分析】题中书包26元,钢笔5元,求一共多少元,根据加法的意义,书包的钱数加钢笔的钱数=一共的钱数.\n【详解】26+5=31(元)。一共31元。", + "knowledge_points": [ + "图文问题", + "一位数与两位数的进位加法" + ], + "source": "23-24 一年级下·河北衡水·期末" + }, + { + "id": "368", + "unit": "第六单元100以内的加法和减法4", + "question_type": "计算题", + "difficulty": 0.65, + "question": "看图列式计算.\n![](images/e77d64a9bcf17df12a7cdb89b5c2688a3a03c409263233d4a38ee06fdc763177.jpg)\n□ ○ □ = □ (个)", + "options": [], + "answer": "36 + 9 = 45", + "solution": "【分析】左边有 36 个苹果,右边有 9 个苹果,求一共有多少个苹果,根据加法的意义,左边的数量 + 右边的数量 =总数量.\n【详解】 36 + 9 = 45 (个)一共有 45 个苹果。", + "knowledge_points": [ + "图文问题", + "一位数与两位数的进位加法" + ], + "source": "23-24 一年级下·山东济宁·期末" + }, + { + "id": "369", + "unit": "第六单元100以内的加法和减法4", + "question_type": "计算题", + "difficulty": 0.65, + "question": "看图列式计算.\n![](images/ee88f01fb7ac17b0adfb30d23f80517bc46e40aa16270060ee9bbfdf276036c7.jpg)\n□ ○ □ = □ ()", + "options": [], + "answer": "36-9=27", + "solution": "【分析】由图可知,一共有 36 瓶水,右边有 9 瓶水,根据减法的意义,用水的总数量减去右边水的数量即可求出左边箱子里水的数量.\n【详解】 36 - 9 = 27 (瓶)所以左边箱子里有 27 瓶水。", + "knowledge_points": [ + "图文问题", + "一位数与两位数的退位减法" + ], + "source": "23-24 一年级下·湖南湘西·期末" + }, + { + "id": "370", + "unit": "第六单元100以内的加法和减法4", + "question_type": "计算题", + "difficulty": 0.65, + "question": "看图列式计算.\n![](images/42da4cd53dc4aabbc643524a1944f2d14a10668284cdea994937620ab02d8b4e.jpg)\n□ ○ □ = □ ()", + "options": [], + "answer": "47-7=40", + "solution": "【分析】根据减法的意义,用小白菜的总数量 47 棵减去右边小白菜的数量 7 棵即可求出左边篮子里的小白菜的数量.\n【详解】 47 - 7 = 40 (棵)所以左边篮子里有 40 棵小白菜。", + "knowledge_points": [ + "图文问题", + "两位数与一位数的减法(不退位)" + ], + "source": "23-24 一年级下·湖南湘西·期末" + }, + { + "id": "371", + "unit": "第六单元100以内的加法和减法4", + "question_type": "计算题", + "difficulty": 0.65, + "question": "看图列式计算.\n![](images/d3cb99e857376f730f074a3e173b970b4470047fa21a42d2bf7f0ad335ed094d.jpg)\n□ ○ □ = □ ()", + "options": [], + "answer": "47+7=54", + "solution": "【分析】箱子里的数量加上箱子外的数量即可.\n【详解】 47 + 7 = 54 (个)", + "knowledge_points": [ + "图文问题", + "一位数与两位数的进位加法" + ], + "source": "23-24 一年级下·山东济宁·期末" + }, + { + "id": "372", + "unit": "第六单元100以内的加法和减法4", + "question_type": "计算题", + "difficulty": 0.65, + "question": "看图列式计算.\n![](images/87924a2753958f171d4d62d77a38a7db630c6915f72fee9906d1255f961d8c64.jpg)\n□ ○ □ = □ ()", + "options": [], + "answer": "34-5=29", + "solution": "【分析】用总数减去右边的根数即可得到左边的数量.\n【详解】 34 - 5 = 29 (根)", + "knowledge_points": [ + "图文问题", + "一位数与两位数的退位减法" + ], + "source": "23-24 一年级下·山东济宁·期末" + }, + { + "id": "373", + "unit": "第六单元100以内的加法和减法4", + "question_type": "计算题", + "difficulty": 0.65, + "question": "我能算得对又快.\n72 - 2 - 30 = 57 - (4 + 26) = 6 + 58 = 50 + 32 =\n92 - 7 = 27 - 7 + 5 = 50 + (30 - 8) =", + "options": [], + "answer": "40;27;64;82;85;25;72", + "solution": "【分析】本题考查100以内数的加减法口算,包括连减,带括号的混合运算,不进位加法,进位加法及不退位减法。计算时需注意运算顺序,有括号的要先算括号内.\n【详解】72减2再减30,先算72减2得70,再减30得40;57减括号里4加26的和,先算括号得30,再减得27;6加58得64;50加32得82;92减7得85;27减7再加5,先算27减7得20,再加5得25;50加括号里30减8的差,先算括号得22,再加得72。", + "knowledge_points": [ + "一位数与两位数的退位减法", + "100 以内数的连加运算", + "带有小括号的混合运算" + ], + "source": "23-24 一年级下·山东济宁·期末" + }, + { + "id": "374", + "unit": "第六单元100以内的加法和减法4", + "question_type": "计算题", + "difficulty": 0.65, + "question": "看图写算式.\n![](images/dc34921c4ccfc9de0f8879261411af0dcf0e344a0dade2fa00ce407246481a26.jpg)\n□ ○ □ = □ (人)", + "options": [], + "answer": "58 + 6 = 64", + "solution": "【分析】由图可知,根据加法的意义,用左边公交车里的人数加上右边小汽车里的人数即可求出总人数,据此解答即可.\n【详解】 58 + 6 = 64 (人)所以一共有 64 人。", + "knowledge_points": [ + "图文问题", + "一位数与两位数的进位加法" + ], + "source": "23-24 一年级下·贵州铜仁·期末" + }, + { + "id": "375", + "unit": "第六单元100以内的加法和减法4", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图写算式.\n![](images/23946b0e63ea58f9db994ace42e49e1848f3459b45ea47c4975214b8242d94cc.jpg)\n□ ○ □ = □ (元)", + "options": [], + "answer": "85 - 40 = 45", + "solution": "【分析】用一套衣服的价钱减去上衣的价钱,即为所求的裙子的价钱.\n【详解】 85 - 40 = 45 (元)裙子的价钱为 45 元。", + "knowledge_points": [ + "图文问题", + "两位数与整十数的减法" + ], + "source": "23-24 一年级下·贵州铜仁·期末" + }, + { + "id": "376", + "unit": "第六单元100以内的加法和减法4", + "question_type": "计算题", + "difficulty": 0.65, + "question": "看图写算式.\n48个苹果 30个苹果\n![](images/48a5268cd17b278670734d74157e8f26b3a72c47e6abd6159db9678cd390aed7.jpg)\n。个苹果\n□ ○ □ = □ (个)", + "options": [], + "answer": "48 + 30 = 78", + "solution": "【分析】由图可知,根据加法的意义,用左边的 48 个苹果加上右边的 30 个苹果即可求出一共有多少个苹果.\n【详解】 48 + 30 = 78 (个)所以一共有 78 个苹果。", + "knowledge_points": [ + "图文问题", + "两位数与整十数的加法" + ], + "source": "23-24 一年级下·贵州铜仁·期末" + }, + { + "id": "377", + "unit": "第六单元100以内的加法和减法4", + "question_type": "计算题", + "difficulty": 0.65, + "question": "看图写算式.\n![](images/d6f5abb9068bb3eb728c84f689c143c6f8be1818842f9d09eb7741b766225c32.jpg)\n79根\n![](images/86e513bcf6d909a93ee704cbb14391108c5e5ee5065e78d24ee2a9b104564a43.jpg)", + "options": [], + "answer": "79 - 20 = 59", + "solution": "【分析】一捆小棒表示 1 个十,用总数减去右边的两捆小棒即可得到左边的.\n【详解】 79 - 20 = 59 (根)", + "knowledge_points": [ + "图文问题", + "两位数与整十数的减法" + ], + "source": "23-24 一年级下·贵州铜仁·期末" + }, + { + "id": "378", + "unit": "第六单元100以内的加法和减法4", + "question_type": "解答题", + "difficulty": 0.65, + "question": "有 34 个胡萝卜,每 8 个装 1 袋,能装几袋。", + "options": [], + "answer": "4袋", + "solution": "【分析】根据减法的意义,胡萝卜的总数量依次减去每袋装的 8 个,减到最后的数量不够装满 1 袋为止,减了几次 8 就是能装几袋.\n【详解】 34 - 8 = 26 (个);26-8=18(个);18 - 8 = 10 (个);10 - 8 = 2 (个)。答:能装 4 袋。", + "knowledge_points": [ + "不退位减法(20以内)", + "一位数与两位数的退位减法" + ], + "source": "23-24 一年级下·山东日照·期末" + }, + { + "id": "379", + "unit": "第六单元100以内的加法和减法4", + "question_type": "解答题", + "difficulty": 0.65, + "question": "三名老师带领 48 个学生一起出去游玩,每人分1瓶矿泉水,50瓶够吗。", + "options": [], + "answer": "不够", + "solution": "【分析】根据题意,先用加法计算出老师和学生一共有多少人,再和矿泉水的数量比较大小。人数大于矿泉水的数量不够,小于或等于够.\n【详解】 3 + 48 = 51 (人);51 > 50;答: 50 瓶不够。", + "knowledge_points": [ + "100 以内数的比大小", + "一位数与两位数的进位加法" + ], + "source": "23-24 一年级下·山东日照·期末" + }, + { + "id": "380", + "unit": "第六单元100以内的加法和减法4", + "question_type": "解答题", + "difficulty": 0.85, + "question": "水果店运进36箱苹果,上午卖出10箱,下午卖出9箱。水果店还剩下多少箱苹果。", + "options": [], + "answer": "17箱", + "solution": "【分析】根据题意,苹果的总数量减上午卖出的数量减下午卖出的数量=还剩的数量,由此解答.\n【详解】36-10-9=17(箱)。答:水果店还剩下17箱苹果。", + "knowledge_points": [ + "100以内数的连减运算" + ], + "source": "23-24一年级下·福建福州·期末" + }, + { + "id": "381", + "unit": "第六单元100以内的加法和减法4", + "question_type": "解答题", + "difficulty": 0.65, + "question": "爸爸 38 岁,小红 8 岁,小红比爸爸少多少岁。\n□ ○ □ = □ (岁) 答:小红比爸爸少()岁。", + "options": [], + "answer": "30岁", + "solution": "【分析】要求小红比爸爸少多少岁,用爸爸的年龄减去小红的年龄即可得解.\n【详解】 38 - 8 = 30 (岁)答:小红比爸爸少 30 岁。", + "knowledge_points": [ + "两位数与一位数的减法(不退位)" + ], + "source": "22-23一年级下·广东汕尾·期中" + }, + { + "id": "382", + "unit": "第六单元100以内的加法和减法4", + "question_type": "解答题", + "difficulty": 0.65, + "question": "车上原来有26人,到车站下去6人,又上来4人,现在车上有多少人。\n□ ○ □ ○ □ = □ (人);口答:现在车上有 ()人。", + "options": [], + "answer": "24人", + "solution": "【分析】根据题意,用车上原来的人数减去下去的人数,可得出还剩多少人,再加上又上来的人数就是现在的人数.\n【详解】 26 - 6 + 4 = 24 (人)答:现在车上有 24 人。", + "knowledge_points": [ + "100以内数的加减混合运算" + ], + "source": "23-24一年级下·山东济宁·期末" + }, + { + "id": "383", + "unit": "第六单元100以内的加法和减法4", + "question_type": "解答题", + "difficulty": 0.65, + "question": "体育室一共有 88 根跳绳,一班借走 30 根,二班借走 40 根,还剩多少根。\n□ ○ □ ○ □ = □ (根) 口答:还剩 □ 根。", + "options": [], + "answer": "18根", + "solution": "【分析】根据减法的意义,用跳绳的总数量减去一班借走的跳绳的数量,再减去二班借走的跳绳的数量即可求出还剩下的跳绳的数量.\n【详解】 88 - 30 - 40= 58 - 40 = 18 (根) 口答:还剩 18 根。", + "knowledge_points": [ + "100以内数的连减运算" + ], + "source": "23-24 一年级下·山东济宁·期末" + }, + { + "id": "384", + "unit": "第六单元100以内的加法和减法4", + "question_type": "解答题", + "difficulty": 0.65, + "question": "爸爸今年 40 岁,小明今年 8 岁,爸爸和小明相差多少岁。\n□ ○ □ ○ □ = □ (岁) 答:爸爸和小明相差 ( ) 岁。", + "options": [], + "answer": "32岁", + "solution": "【分析】根据减法的意义,爸爸今年的年龄减小明今年的年龄=爸爸和小明相差的年龄.\n【详解】40-8=32(岁)。答:爸爸和小明相差32岁。", + "knowledge_points": [ + "一位数与两位数的退位减法" + ], + "source": "23-24 一年级下·山东济南·期末" + }, + { + "id": "385", + "unit": "第六单元100以内的加法和减法4", + "question_type": "解答题", + "difficulty": 0.65, + "question": "一根彩带用去了 43米,还剩下8米,这根彩带原来有多少米。\n□ ○ □ ○ □ = □ (米) 答:这根彩带原来 米。", + "options": [], + "answer": "51米", + "solution": "【分析】根据加法的意义,用去的长度 + 还剩的长度 = 原来的长度,由此解答.\n【详解】 43 + 8 = 51 (米);答:这根彩带原来有 51 米。", + "knowledge_points": [ + "一位数与两位数的进位加法" + ], + "source": "23-24 一年级下·湖南衡阳·期末" + }, + { + "id": "386", + "unit": "第六单元100以内的加法和减法4", + "question_type": "解答题", + "difficulty": 0.65, + "question": "3 个小朋友一起折纸船,每人折了 7 个,一共折了多少个纸船。\n□ ○ □ ○ □ = □ (个) 答:一共折了 个纸船。", + "options": [], + "answer": "21个", + "solution": "【分析】根据题意,每人折 7 个, 3 个小朋友折纸船的总数量,也就是 3 个 7 的和,用加法计算.\n【详解】 7 + 7 + 7 = 21 (个);答:一共折了 21 个纸船。", + "knowledge_points": [ + "100以内数的连加运算" + ], + "source": "23-24 一年级下·湖南衡阳·期末" + }, + { + "id": "387", + "unit": "第六单元100以内的加法和减法4", + "question_type": "解答题", + "difficulty": 0.65, + "question": "图书角原来有 45 本漫画书,上午借出 5 本,下午又还回 3 本,图书角现在有多少本漫画书。\n□ ○ □ ○ □ = □ (本) 答:图书角现在有 本漫画书。", + "options": [], + "answer": "43本", + "solution": "【分析】用图书角原有的漫画书数量,减去借出的漫画书数量,加上还回来的漫画书的数量,即可得到图书角现在的漫画书数量.\n【详解】 45 - 5 + 3 = 43 (本);答:图书角现在有 43 本漫画书。", + "knowledge_points": [ + "100 以内数的加减混合运算" + ], + "source": "23-24 一年级下·湖南衡阳·期末" + }, + { + "id": "388", + "unit": "第六单元100以内的加法和减法4", + "question_type": "解答题", + "difficulty": 0.65, + "question": "我国的传统节日端午节有赛龙舟和吃粽子的习俗。妈妈做了27个粽子,每袋装7个。最多可以装满几袋。还剩多少个粽子。", + "options": [], + "answer": "3袋;6个", + "solution": "【分析】根据减法的意义,用粽子的总数量 27 个依次减去每袋能装的数量 7 个,直到减不动为止,减了几次就是最多可以装满几袋,剩下的减不动的数就是还剩下的粽子的数量.\n【详解】 27 - 7 = 20 (个)20 - 7 = 13 (个)13 - 7 = 6 (个)一共减了 3 次,所以最多可以装满 3 袋,还剩下 6 个。答:最多可以装满 3 袋,还剩下 6 个粽子。", + "knowledge_points": [ + "十几减 7,6 的退位减法", + "两位数与一位数的减法(不退位)", + "一位数与两位数的退位减法" + ], + "source": "23-24一年级下·湖南湘西·期末" + }, + { + "id": "389", + "unit": "第六单元100以内的加法和减法4", + "question_type": "解答题", + "difficulty": 0.65, + "question": "植树节到了, (2) 班 42 名同学每人要种植一棵小树苗,已经种植了 3 棵杨树苗和 7 棵柳树苗。还要种植多少棵小树苗。", + "options": [], + "answer": "32棵", + "solution": "【分析】42 名同学每人要种植一棵小树苗,则一共要种植 42 棵小树苗。方法一:根据减法的意义,用要种植小树苗的总数量依次减去已经种植了的杨树苗的数量和柳树苗的数量即可求出还要种植小树苗的数量;方法二:先根据加法的意义,用已经种植了的杨树苗的数量加上柳树苗的数量求出已经种植了的小树苗的数量,再根据减法的意义,用一共要种植的小树苗的总数量减去已经种植了的小树苗的数量即可求出还要种植的小树苗的数量.\n【详解】方法一:42-3-7= 39 - 7 = 32 (棵) 方法二: 42 - (3 + 7)= 42 - 10 = 32 (棵) 答:还要种植 32 棵小树苗。", + "knowledge_points": [ + "100 以内数的连减运算", + "带有小括号的混合运算" + ], + "source": "23-24一年级下·湖南湘西·期末" + }, + { + "id": "390", + "unit": "第六单元100以内的加法和减法4", + "question_type": "解答题", + "difficulty": 0.65, + "question": "笑笑有 17 张卡片,淘淘有 20 张卡片,两人一共有多少张卡片。", + "options": [], + "answer": "37张", + "solution": "【分析】根据加法的意义,用笑笑有的卡片数加上淘淘有的卡片数即可求出两人卡片的总数量,据此解答即可.\n【详解】 17 + 20 = 37 (张)答:两人一共有 37 张卡片。", + "knowledge_points": [ + "两位数与整十数的加法" + ], + "source": "22-23一年级下·广东汕头·期末" + }, + { + "id": "391", + "unit": "第六单元100以内的加法和减法4", + "question_type": "解答题", + "difficulty": 0.85, + "question": "学校图书角共有 80 本书,其中故事书有 30 本。昨天借出去 9 本书,图书角还剩多少本书。", + "options": [], + "answer": "71本", + "solution": "【分析】根据减法的意义,书的总数量减借出的数量=还剩的数量,由此解答.\n【详解】80-9=71(本)。答:图书角还剩71本书。", + "knowledge_points": [ + "一位数与两位数的退位减法" + ], + "source": "23-24一年级下·贵州铜仁·期末" + }, + { + "id": "392", + "unit": "第六单元100以内的加法和减法4", + "question_type": "解答题", + "difficulty": 0.65, + "question": "操场上有 26 个同学,他们玩了 10 分钟,其中男同学有 7 人,女同学有多少人。\n□ ○ □ = □ (人) 答:女同学有()人。", + "options": [], + "answer": "19人", + "solution": "【分析】根据题意,用操场上有的人数减男同学的人数=女同学的人数,据此解答.\n【详解】26-7=19(人)。答:女同学有19人。", + "knowledge_points": [ + "一位数与两位数的退位减法" + ], + "source": "23-24 一年级下·广东江门·期末" + }, + { + "id": "393", + "unit": "第六单元100以内的加法和减法4", + "question_type": "解答题", + "difficulty": 0.65, + "question": "小红家养了 60 只白兔和8只黑兔,白兔比黑兔多几只。\n□ ○ □= □ () 答:白兔比黑兔多()只。", + "options": [], + "answer": "52只", + "solution": "【分析】求一个数比另一个数多多少,用减法计算。即白兔的数量减黑兔的数量=白兔比黑兔多的数量.\n【详解】60-8=52(只)。答:白兔比黑兔多52只。", + "knowledge_points": [ + "一位数与两位数的退位减法" + ], + "source": "23-24 一年级下·广东江门·期末" + }, + { + "id": "394", + "unit": "第六单元100以内的加法和减法4", + "question_type": "解答题", + "difficulty": 0.85, + "question": "王老师要做 46 朵纸花,已经做了 20 朵,还有多少朵没有做。\n□ ○ □ = □ () 答:还有()朵花没有做。", + "options": [], + "answer": "26朵", + "solution": "【分析】根据题意,用需要做的数量减已经做的数量=还有没有做的数量,据此解答.\n【详解】根据分析: 46 - 20 = 26 (朵)答:还有 26 朵花没有做。", + "knowledge_points": [ + "两位数与整十数的减法" + ], + "source": "23-24 一年级下·广东江门·期末" + }, + { + "id": "395", + "unit": "第六单元100以内的加法和减法4", + "question_type": "解答题", + "difficulty": 0.85, + "question": "公交车上原来有 65 个乘客,到站后下车了 22 人,又上来 28 人,现在车上有多少人。\n□ ○ □ ○ □ = □ (人) 答:现在车上有 ( ) 人。", + "options": [], + "answer": "71人", + "solution": "【分析】据题意可知,车上原来有 65 人,走了 22 人,相减即可知车上还剩多少人,又上来了 28 人,用剩余人数加上新来的就可得出车上有多少人.\n【详解】 65 - 22 + 28 = 71 (人)答:现在车上有 71 人。", + "knowledge_points": [ + "100以内数的加减混合运算" + ], + "source": "23-24 一年级下·山东济南·期末" + }, + { + "id": "396", + "unit": "第六单元100以内的加法和减法4", + "question_type": "解答题", + "difficulty": 0.65, + "question": "公交车上原有 34 人,下去 9 人,上来 5 人。公交车上现在有多少人。\n□ ○ □ ○ □ = □ (人)", + "options": [], + "answer": "30人", + "solution": "【分析】根据题意,原有的人数减回去的人数加又上来的人数 = 现在的人数,由此解答.\n【详解】 34 - 9 + 5 = 30 (人)答:公交车上现在有 30 人。", + "knowledge_points": [ + "100以内数的加减混合运算" + ], + "source": "23-24 一年级下·山东临沂·期末" + }, + { + "id": "397", + "unit": "第六单元100以内的加法和减法4", + "question_type": "解答题", + "difficulty": 0.85, + "question": "学校合唱队有男生 40 人,女生 65 人,女生比男生多多少人。\n□ ○ □ = □ ()", + "options": [], + "answer": "25人", + "solution": "【分析】要求女生比男生多多少人,用女生的人数减去男生的人数,即可得出答案.\n【详解】 65 - 40 = 25 (人)答:女生比男生多 25 人。", + "knowledge_points": [ + "两位数与整十数的减法" + ], + "source": "23-24 一年级下·山东临沂·期末" + }, + { + "id": "398", + "unit": "第六单元100以内的加法和减法4", + "question_type": "解答题", + "difficulty": 0.65, + "question": "原来有多少份宣传单。\n![](images/f34b1cc4ada87d177c2d5fe4fb0732bd6675c231427bd12209e6f1bc916b9771.jpg)\n防溺水宣传单已经发了38份,还剩6份。□ ○ □ = □(份)", + "options": [], + "answer": "44份", + "solution": "【分析】根据加法的意义,已经发了的数量 + 还剩的数量 = 原来的数量,由此解答.\n【详解】 38 + 6 = 44 (份)答:原来有 44 份宣传单。", + "knowledge_points": [ + "图文问题", + "一位数与两位数的进位加法" + ], + "source": "23-24一年级下·河北衡水·期末" + }, + { + "id": "399", + "unit": "第六单元100以内的加法和减法4", + "question_type": "解答题", + "difficulty": 0.65, + "question": "超市进行促销活动,买一箱 20 盒装的牛奶赠 4 盒,妈妈买了 2 箱。一共可以买到多少盒牛奶。\n![](images/e9832655eab63413873337657337d028.png)", + "options": [], + "answer": "48盒", + "solution": "【分析】根据题意,每箱有 20 盒,买两箱也就是 2 个 20 盒,用加法计算;一箱赠 4 盒,两箱赠的也就是 2 个 4 盒,用加法计算。计算出结果相加就是一共买到牛奶的盒数.\n【详解】两箱牛奶: 20 + 20 = 40 (盒)赠的牛奶: 4 + 4 = 8 (盒)一共的数量: 40 + 8 = 48 (盒)答:一共可以买到 48 盒牛奶。", + "knowledge_points": [ + "整十数加,减一位数", + "整十数之间的加减法", + "促销问题" + ], + "source": "23-24一年级下·山东临沂·期末" + }, + { + "id": "400", + "unit": "第六单元100以内的加法和减法4", + "question_type": "解答题", + "difficulty": 0.65, + "question": "小明买了一个书包和一本笔记本。一共花了 55 元,书包 40 元,笔记本多少元。", + "options": [], + "answer": "15元", + "solution": "【分析】花的总钱数减去书包的价钱即可得到笔记本的价钱.\n【详解】 55 - 40 = 15 (元)答:笔记本 15 元。", + "knowledge_points": [ + "两位数与整十数的减法" + ], + "source": "23-24一年级下·山东临沂·期末" + }, + { + "id": "401", + "unit": "第六单元100以内的加法和减法5", + "question_type": "选择题", + "difficulty": 0.65, + "question": "公交车上原有34人,下去了9人,上来了5人。公交车上现在有()人。", + "options": [ + "A. 48", + "B. 38", + "C. 30" + ], + "answer": "C", + "solution": "【分析】公交车上现在的人数 = 公交车上原有的人数 - 去的人数 + 又上来的人数。代入数据计算即可得解.\n【详解】 34 - 9 + 5 = 25 + 5 = 30 ( 人) 即公交车上现在有 30 人。故答案为: C", + "knowledge_points": [ + "100以内数的加减混合运算" + ], + "source": "23-24一年级下·江西赣州·期末" + }, + { + "id": "402", + "unit": "第六单元100以内的加法和减法5", + "question_type": "选择题", + "difficulty": 0.65, + "question": "如果每10朵做一个花环,最多能做()个。", + "options": [ + "A. 3", + "B. 4", + "C. 5" + ], + "answer": "A", + "solution": "【分析】根据题意,用花朵的总数量依次减去 10,减到最后的数量不够做成一个花环为止,减了几次 10 就是能做几个.\n【详解】 34 - 10 = 24 (朵);24 - 10 = 14 (朵);14 - 10 = 4 (朵)减了3次10,最多能做3个。故答案为:A", + "knowledge_points": [ + "两位数与整十数的减法" + ], + "source": "23-24一年级下·山东临沂·期末" + }, + { + "id": "403", + "unit": "第六单元100以内的加法和减法5", + "question_type": "选择题", + "difficulty": 0.65, + "question": "一共有 30 颗糖果,还剩多少颗。解答算式 30 - (9 + 6) = 15 (颗),横线上的条件可能是 ( )。", + "options": [ + "A. 丫丫上午吃了9颗,下午比上午多吃了6颗", + "B. 贝贝吃了9颗,皮皮吃了6颗", + "C. 分给悠悠 9 颗,又买来 6 颗" + ], + "answer": "B", + "solution": "【分析】求还剩多少颗,用糖果的总数量减去掉的数量=还剩的数量,9+6表示去掉的这一部分的总和,由此分析各选项即可.\n【详解】A.丫丫上午吃的数量+下午比上午多吃的数量=下午吃的数量,用9+6表示,求还剩多少,应该用总数量减上午吃的数量减下午吃的数量,列式应为30-9-(9+6),与题意不符;B.贝贝吃的数量+皮皮吃的数量=吃了的总数量,用总数量减他们吃的总数量=还剩的数量,列式为30-(9+6),与题意相符;C.总数量减分给悠悠的数量+又买来的数量=现在的数量,列式为30-9+6,与题意不符合。横线上的条件可能是:贝贝吃了9颗,皮皮吃了6颗。故答案为:B", + "knowledge_points": [ + "\"提问题\"\"填条件\"问题", + "100以内数的加减混合运算", + "带有小括号的混合运算" + ], + "source": "23-24 一年级下·浙江杭州·期末" + }, + { + "id": "404", + "unit": "第六单元100以内的加法和减法5", + "question_type": "选择题", + "difficulty": 0.85, + "question": "下面算式得数比 60 小的是 ( )。", + "options": [ + "A. 90 - 30", + "B. 60 + 9", + "C. 83 - 30" + ], + "answer": "C", + "solution": "【分析】分别计算出结果后与60比较大小。整十数加减整十数,直接将十位上的数字相加减,再在计算的结果末尾添上一个0;整十数加一位数,把这个一位数写在整十数的个位上面,十位上的数不变;两位数减整十数,在两位数的十位上减几,个位上的数不变.\n【详解】A.90-30=60,60=60,则不符合题意;B.60+9=69,69>60,则不符合题意;C.83-30=53,53<60,符合题意。故答案为:C", + "knowledge_points": [ + "100 以内数的比大小", + "整十数加,减一位数", + "整十数之间的加减法", + "两位数与整十数的减法" + ], + "source": "23-24 一年级下·浙江杭州·期末" + }, + { + "id": "405", + "unit": "第六单元100以内的加法和减法5", + "question_type": "选择题", + "difficulty": 0.85, + "question": "一个书包 20 元多一些,妈妈付给营业员阿姨 50 元,应找回()。", + "options": [ + "A. 30元", + "B. 30 元少一些", + "C. 30 元多一些" + ], + "answer": "B", + "solution": "【分析】 50 - 20 = 30 (元),也就是当一个书包 20 元时,付 50 元,应找回的钱是 30 元;而当一个书包比 20 元多一些时,付 50 元,应找回的钱会比 30 元要少一些;据此解决.\n【详解】由题意分析得:一个书包 20 元多一些,妈妈付给营业员阿姨 50 元,应找回 30 元少一些。故答案为: B", + "knowledge_points": [ + "100以内数加减法的估算" + ], + "source": "23-24 二年级上·福建莆田·期末" + }, + { + "id": "406", + "unit": "第六单元100以内的加法和减法5", + "question_type": "选择题", + "difficulty": 0.85, + "question": "求 44 比 3 多几。 正确的列式是 ( )。", + "options": [ + "A. 44 + 3 = 47", + "B. 44 - 3 = 41", + "C. 41 + 3 = 44" + ], + "answer": "B", + "solution": "【分析】求一个数比另一个数多几,就用一个数减去另一个数,求出差,即可解决.\n【详解】由题意分析得:求 44 比 3 多几。 正确的列式是 (44 - 3 = 41) 。故答案为: B", + "knowledge_points": [ + "两位数与一位数的减法(不退位)" + ], + "source": "23-24 一年级下·福建福州·期末" + }, + { + "id": "407", + "unit": "第六单元100以内的加法和减法5", + "question_type": "选择题", + "difficulty": 0.85, + "question": "得数大于 50 的算式是 ( )。", + "options": [ + "A. 43 + 6", + "B. 54 - 8", + "C. 87 - 30" + ], + "answer": "C", + "solution": "【分析】先按照整数加减法的计算法则,算出每一个算式的得数,然后找出得数大于50的,即可解决.\n【详解】A.43+6=49,49<50;B.54-8=46,46<50;C.87-30=57,57>50;即,得数大于50的算式是(87-30)。故答案为:C", + "knowledge_points": [ + "100 以内数的比大小", + "两位数与一位数的加法(不进位)", + "两位数与整十数的减法", + "一位数与两位数的退位减法" + ], + "source": "23-24 一年级下·湖南邵阳·期末" + }, + { + "id": "408", + "unit": "第六单元100以内的加法和减法5", + "question_type": "选择题", + "difficulty": 0.85, + "question": "36 与 7 的和是 ( )。", + "options": [ + "A. 30", + "B. 29", + "C. 43" + ], + "answer": "C", + "solution": "【分析】求两个数的和是多少,用加法列式解决.\n【详解】 36 + 7 = 43即,36与7的和是 43 。故答案为: C", + "knowledge_points": [ + "一位数与两位数的进位加法" + ], + "source": "22-23 一年级下·江西吉安·期末" + }, + { + "id": "409", + "unit": "第六单元100以内的加法和减法5", + "question_type": "选择题", + "difficulty": 0.65, + "question": "有一盒饼干,第一次吃了 5 块,第二次吃了 7 块,还剩 30 块。这盒饼干原来有 ( ) 块。", + "options": [ + "A. 12", + "B. 40", + "C. 42" + ], + "answer": "C", + "solution": "【分析】用第一次吃的数量加上第二次吃的数量,再加上还剩的数量,即可求出这盒饼干原来有多少块.\n【详解】 5 + 7 + 30 = 42 (块)所以这盒饼干原来有 42 块。故答案为: C", + "knowledge_points": [ + "100 以内数的连加运算" + ], + "source": "23-24一年级下·江西吉安·期末" + }, + { + "id": "410", + "unit": "第六单元100以内的加法和减法5", + "question_type": "选择题", + "difficulty": 0.85, + "question": "下面算式中的 \"3\"和\"5\"能直接相加的是()。", + "options": [ + "A. 37 + 5", + "B. 37 + 50", + "C. 57 + 3" + ], + "answer": "B", + "solution": "【分析】根据百以内加法的计算方法,只有相同数位上的数才能直接相加,据此解答.\n【详解】A.37+5,37的3在十位上,5在个位上,不能直接相加;B.37+50,37的3在十位上,5在十位上,可以直接相加;C.57+3,57的5在十位上,3在个位上,不能直接相加。三个选项中,只有算式37+50中的\"3\"和\"5\"是相同的计数单位,可以直接相加。故答案为:B", + "knowledge_points": [ + "两位数与整十数的加法", + "一位数与两位数的进位加法" + ], + "source": "23-24 一年级下·河北廊坊·期末" + }, + { + "id": "411", + "unit": "第六单元100以内的加法和减法5", + "question_type": "选择题", + "difficulty": 0.65, + "question": "下面算式中,与 80 - 50 - 10 计算结果相等的是 ( )。", + "options": [ + "A. 80 - (50 - 10)", + "B. 80 - (50 +10)", + "C. 80+ (50-10)" + ], + "answer": "B", + "solution": "【分析】先算出80-50-10的结果,再算出各选项的结果,选择结果相同的即可。有括号要先算括号里面的,没有括号按从左往右的顺序计算.\n【详解】80-50-10=30-10=20;A.80-(50-10)=80-40=40;B.80-(50+10)=80-60=20;C.80+(50-10)=80+40=120。故答案为:B", + "knowledge_points": [ + "整十数之间的加减法", + "100 以内数的连减运算", + "带有小括号的混合运算" + ], + "source": "23-24 一年级下·贵州六盘水·期末" + }, + { + "id": "412", + "unit": "第六单元100以内的加法和减法5", + "question_type": "填空题", + "difficulty": 0.85, + "question": "73 块饼干,每 10 块装 1 袋,可以装满( )袋,还剩( )块。", + "options": [], + "answer": "7;3", + "solution": "【分析】根据题意,用饼干的总数量依次减去 10,减到最后的数量不够装满 1 袋为止,减了几次 10 就是能装满几袋,最后的得数就是还剩的数量.\n【详解】 73 - 10 = 63 (块);63 - 10 = 53 (块)53 - 10 = 43 (块)43 - 10 = 33 (块)33 - 10 = 23 (块)23 - 10 = 13 (块)\n13 - 10 = 3 (块)。73块饼干,每10块装1袋,可以装满7袋,还剩3块。", + "knowledge_points": [ + "两位数与整十数的减法" + ], + "source": "23-24一年级下·贵州铜仁·期末" + }, + { + "id": "413", + "unit": "第六单元100以内的加法和减法5", + "question_type": "填空题", + "difficulty": 0.65, + "question": "在括号里最大能填几。\n47-( )>39\n( )+78<80\n89-( )>88-9\n50+( )<48+9", + "options": [], + "answer": "7;1;9;6", + "solution": "【分析】两位数加一位数的进位加法,在用个位上的数加一位数后,还要加上整十数;两位数减一位数的退位减法,把两位数分成几个十和十几,用十几减一位数,再用几十加上所得的差,据此结合题干要求进行解答即可.\n【详解】47-7=40,40>39,所以47-7>39,括号内最大填7;1+78=79,79<80,所以1+78<80,括号内最大填1;88-9=79,89-9=80,80>79,所以89-9>88-9,括号内最大填9;48+9=57,56<57,所以50+6<48+9,括号内最大填6。", + "knowledge_points": [ + "100 以内数的比大小", + "一位数与两位数的进位加法", + "一位数与两位数的退位减法" + ], + "source": "23-24 一年级下·浙江杭州·期末" + }, + { + "id": "414", + "unit": "第六单元100以内的加法和减法5", + "question_type": "填空题", + "difficulty": 0.65, + "question": "在括号里填上\">\" \"<\"或\"=\".\n35+6( )35+8\n72-5( )72-6\n1个十和3个一( )3个十\n3元6角( )4元\n5元3角( )6元\n10+5( )85-(10-5)", + "options": [], + "answer": "<;>;<;<;<;<", + "solution": "【分析】有算式先算出算式的得数,再比较大小。1元=10角,单位换算后再比较大小.\n【详解】35+6=41,35+8=43,所以35+6<35+8;72-5=67,72-6=66,所以72-5>72-6;1个十和3个一是13,3个十是30,所以1个十和3个一<3个十;3元6角<4元;5元3角<6元;10+5=15,85-(10-5)=80,所以10+5<85-(10-5)。", + "knowledge_points": [ + "100以内数的比大小", + "100以内数的组成", + "一位数与两位数的进位加法", + "元,角,分的认识及换算" + ], + "source": "23-24一年级下·浙江杭州·期末" + }, + { + "id": "415", + "unit": "第六单元100以内的加法和减法5", + "question_type": "填空题", + "difficulty": 0.65, + "question": "一本书一共50页,小明第一天看了5页,第二天看了8页,这本书他还剩( )页没看,第三天从( )页开始看。", + "options": [], + "answer": "37;14", + "solution": "【分析】根据题意,这本书的总页数减第一天看的页数减第二天看的页数=剩下没看的页数;小明第三天开始看的页数=第一天看的页数+第二天看的页数+1.\n【详解】50-5-8=37(页);5+8+1=14(页)。一本书一共50页,小明第一天看了5页,第二天看了8页,这本书他还剩37页没看,第三天从14页开始看。", + "knowledge_points": [ + "连加(20以内)", + "100以内数的连减运算" + ], + "source": "23-24一年级下·浙江杭州·期末" + }, + { + "id": "416", + "unit": "第六单元100以内的加法和减法5", + "question_type": "填空题", + "difficulty": 0.85, + "question": "如果 6 □ - 4 是退位减法, □ 里最小填( ), □ 最大填( )。", + "options": [], + "answer": "0;3", + "solution": "【分析】根据整数减法运算,计算时要注意相同数位对齐,减法则从个位开始计算,当不够减时,则向高位借1当十,再进行计算。所以退位减法中被减数个位上的数字要比减数小。据此解答即可.\n【详解】如果 6 □ - 4 是退位减法, □ 里的数要小于 4,最小填 0 , □ 最大填 3 。", + "knowledge_points": [ + "一位数与两位数的退位减法" + ], + "source": "23-24 一年级下·浙江杭州·期末" + }, + { + "id": "417", + "unit": "第六单元100以内的加法和减法5", + "question_type": "填空题", + "difficulty": 0.65, + "question": "79( )97\n80-3( )53\n42+9( )53-4\n56-20( )36\n38+9( )67-20\n10元( )7角+3角", + "options": [], + "answer": "<;>;>;=;=;>", + "solution": "【分析】100 以内数的大小比较,三位数大于两位数,两位数比较,十位上大的数就大;如果十位上的数相同,个位上大的数就大;两位数减整十数,在两位数的十位上减几,个位上的数不变;两位数减一位数的退位减法,把两位数分成几个十和十几,用十几减一位数,再用几十加上所得的差。两位数加一位数的进位加法,用个位上的数加一位数后,还要加上整十数。1元=10角,单位换算后再比较大小.\n【详解】 79 < 97;80 - 3 = 77, 77 > 53,所以 80 - 3 > 53;42 + 9 = 51, 53 - 4 = 49, 51 > 49,所以 42 + 9 > 53 - 4;56 - 20 = 36;38 + 9 = 47, 67 - 20 = 47, 47 = 47,所以 38 + 9 = 67 - 20;7角+3角=10角=1元,10元>1元,所以10元>7角+3角。", + "knowledge_points": [ + "100 以内数的比大小", + "一位数与两位数的进位加法", + "一位数与两位数的退位减法", + "元,角,分的认识及换算" + ], + "source": "23-24一年级下·浙江·期末" + }, + { + "id": "418", + "unit": "第六单元100以内的加法和减法5", + "question_type": "填空题", + "difficulty": 0.65, + "question": "在括号里填上\">\" \"<\"或\"=\".\n100( )45\n6( )12-5\n10+9( )17-2\n68( )86\n48( )38+10\n34+8( )8+34", + "options": [], + "answer": ">;<;>;<;=", + "solution": "【分析】整数比较大小,位数多的数大,位数相同时从最高位开始比较;有算式的比较大小,先计算出算式的结果,然后再按照整数比较大小的方法进行比较.\n【详解】100>45;12-5=7,6<7,所以6<12-5;10+9=19,17-2=15,19>15,所以10+9>17-2;68<86;48=38+10;34+8=8+34。", + "knowledge_points": [ + "100 以内数的比大小", + "两位数与整十数的加法", + "一位数与两位数的进位加法" + ], + "source": "23-24 一年级下·广东河源·期末" + }, + { + "id": "419", + "unit": "第六单元100以内的加法和减法5", + "question_type": "填空题", + "difficulty": 0.85, + "question": "比 69 多 20 的数是( ), 比 38 少 30 的数是( )。", + "options": [], + "answer": "89;8", + "solution": "【分析】求比一个数多几的数,用这个数加多的数计算;求比一个数少几的数,用这个数减少的数计算.\n【详解】69+20=89;38-30=8;比69多20的数是89,比38少30的数是8。", + "knowledge_points": [ + "两位数与整十数的加法", + "两位数与整十数的减法" + ], + "source": "23-24 一年级下·山东临沂·期末" + }, + { + "id": "420", + "unit": "第六单元100以内的加法和减法5", + "question_type": "填空题", + "difficulty": 0.85, + "question": "一个两位数,十位上是 6,个位上的数比十位上的数小 2,这个两位数是( ), 与它相邻的两个数分别是( )和( )。", + "options": [], + "answer": "64;63;65", + "solution": "【分析】一个两位数,从右往左依次为个位,十位。十位上的数 -2= 个位上的数,再将数字写在相应数位上即可。它的相邻数也就是比它小 1 的数,用它 -1 计算,和比它大 1 的数,用它 +1 计算.\n【详解】个位: 6 - 2 = 4,十位是6,组成的数是64.64 - 1 = 63;64 + 1 = 65一个两位数,十位上是 6,个位上的数比十位上的数小 2,这个两位数是 64,与它相邻的两个数分别是 63 和 65 。", + "knowledge_points": [ + "100 以内数的组成", + "两位数与一位数的加法(不进位)", + "两位数与一位数的减法(不退位)", + "相邻的数" + ], + "source": "23-24 一年级下·河北邢台·期末" + }, + { + "id": "421", + "unit": "第六单元100以内的加法和减法5", + "question_type": "填空题", + "difficulty": 0.65, + "question": "比 38 多 5 的数是( ), ( )比 67 少 20。", + "options": [], + "answer": "43;47", + "solution": "【分析】求比一个数多几的数是多少,用加法进行计算;求比一个数少几的数是多少,用减法进行计算.\n【详解】 38 + 5 = 43;67 - 20 = 47所以比 38 多 5 的数是 43, 47 比 67 少 20。", + "knowledge_points": [ + "两位数与整十数的减法", + "一位数与两位数的进位加法" + ], + "source": "22-23一年级下·江西吉安·期末" + }, + { + "id": "422", + "unit": "第六单元100以内的加法和减法5", + "question_type": "填空题", + "difficulty": 0.85, + "question": "在括号里填上\">\"\"<\"或\"=\".\n53+6( )6+53\n19角( )2元\n46+20( )46-20\n43-6( )34-6", + "options": [], + "answer": "=;<;>", + "solution": "【分析】先计算出每个算式的结果或先统一单位,然后比较大小即可。1元=10角.\n【详解】53+6=59,6+53=59,故53+6=6+53;2元=20角,故19角<2元;46+20=66,46-20=26,故46+20>46-20;43-6=37,34-6=28,故43-6>34-6。", + "knowledge_points": [ + "100 以内数的比大小", + "两位数与整十数的减法", + "一位数与两位数的退位减法", + "元,角,分的认识及换算" + ], + "source": "23-24一年级下·湖南邵阳·期末" + }, + { + "id": "423", + "unit": "第六单元100以内的加法和减法5", + "question_type": "填空题", + "difficulty": 0.65, + "question": "30比64少( );25比( )多8。", + "options": [], + "answer": "34;17", + "solution": "【分析】求一个数比另一个数少几,用另一个数减这个数计算;已知一个数比另一个数多几,求另一个数,用这个数减多的数计算.\n【详解】64-30=34;25-8=17;30比64少34,25比17多8。", + "knowledge_points": [ + "两位数与整十数的减法", + "一位数与两位数的退位减法" + ], + "source": "23-24一年级下·浙江杭州·期末" + }, + { + "id": "424", + "unit": "第六单元100以内的加法和减法5", + "question_type": "填空题", + "difficulty": 0.85, + "question": "87-7( )87\n56( )36+3\n54-9( )50\n4+35( )75\n42-6( )44\n84-4( )45\n57-7( )46+4\n4元( )30角", + "options": [], + "answer": "<;>;<;<;<;>;=;>", + "solution": "【分析】有算式先算出算式的得数,再根据 100 以内整数比较大小:先看十位上的数,十位上的数大这个数就大;十位上的数相同再比较个位上的数,个位上的数大这个数就大。根据 1 元 = 10 角,先进行单位换算,再进行比较大小.\n【详解】 87 - 7 = 80 , 80 < 87,所以 87 - 7 < 87;36 + 3 = 39, 56 > 39,所以 56 > 36 + 3;54 - 9 = 45, 45 < 50,所以 54 - 9 < 50;4 + 35 = 39, 39 < 75,所以 4 + 35 < 75;42 - 6 = 36, 36 < 44,所以 42 - 6 < 44;84 - 4 = 80, 80 > 45,所以 84 - 4 > 45;57 - 7 = 50, 46 + 4 = 50,所以 57 - 7 = 46 + 4;4元 = 40 角, 40角 > 30 角,所以 4 元 > 30 角", + "knowledge_points": [ + "100 以内数的比大小", + "两位数与一位数的减法(不退位)", + "一位数与两位数的进位加法", + "元,角,分的认识及换算" + ], + "source": "23-24一年级下·陕西安康·期末" + }, + { + "id": "425", + "unit": "第六单元100以内的加法和减法5", + "question_type": "填空题", + "difficulty": 0.85, + "question": "在( )里填上合适的数.\n( )-30=26\n10+( )=42\n( )+9=35\n( )+5=42\n53+( )<63\n( )-6<60", + "options": [], + "answer": "56;32;26;37;9;24", + "solution": "【分析】根据\"被减数 = 差 + 减数,加数 = 和 - 另一个加数\"及整数加减法的计算法则和整数比较大小的方法来解决此题.\n【详解】 26 + 30 = 56,故, 56 - 30 = 2642 - 10 = 32,故, 10 + 32 = 4235 - 9 = 26,故, 26 + 9 = 35;42 - 5 = 37,故, 37 + 5 = 42;53 + 9 = 62,故, 53 + 9 < 63;24 - 6 = 18,故, 24 - 6 < 60 。 (后 2 小题答案不唯一)", + "knowledge_points": [ + "两位数与整十数的加法", + "两位数与整十数的减法", + "一位数与两位数的进位加法", + "一位数与两位数的退位减法" + ], + "source": "22-23 一年级下·河南驻马店·期末" + }, + { + "id": "426", + "unit": "第六单元100以内的加法和减法5", + "question_type": "填空题", + "difficulty": 0.85, + "question": "5角=( )分\n2元=( )角\n65角-20角=( )角\n76角=( )元( )角\n3元-6角=( )角", + "options": [], + "answer": "50;20;45;7;6;24", + "solution": "【分析】根据\"1元=10角,1角=10分\"及整数加减法的计算法则来解决此题.\n【详解】1角=10分,故5角=50分;1元=10角,故2元=20角;65角-20角=45角;70角=7元,76-70=6,故76角=7元6角;3元=30角,30-6=24,故3元-6角=24角。", + "knowledge_points": [ + "两位数与整十数的减法", + "一位数与两位数的退位减法", + "元,角,分的认识及换算" + ], + "source": "22-23 一年级下·河南驻马店·期末" + }, + { + "id": "427", + "unit": "第六单元100以内的加法和减法5", + "question_type": "填空题", + "difficulty": 0.65, + "question": "在括号里填上\">\" \"<\"或\"=\".\n44-4( )44\n56-30( )86\n41+4( )45\n67-8( )69\n76-70( )5\n27-7( )27+7\n4元( )3元8角\n20角( )2元\n5元-3角( )2元", + "options": [], + "answer": "<;<;=;<;>;<;>;=;>", + "solution": "【分析】(1)将 44 - 4 的结果计算出来,再与 44 比较即可;(2) 将 56 - 30 的结果计算出来,再与 86 比较即可;(3) 将 41 + 4 的结果计算出来,再与 45 比较即可;(4) 将 67 - 8 的结果计算出来,再与 69 比较即可;(5) 将 76 - 70 的结果计算出来,再与 5 比较即可;(6) 将 27 - 7 和 27 + 7 的结果计算出来,再进行比较即可;(7) 根据元和角的进率, 1 元 = 10 角,将单位统一再进行比较即可;(8) 根据元和角的进率, 1 元 = 10 角,将单位统一再进行比较即可;(9) 根据元和角的进率, 1 元 = 10 角,将单位统一进行计算,再进行比较即可.\n【详解】 (1) 44 - 4 = 40, 40 < 44,所以 44 - 4 < 44;(2) 56 - 30 = 26, 26 < 86,所以 56 - 30 < 86 \n(3) 41 + 4 = 45, 45 = 45,所以 41 + 4 = 45;(4) 67 - 8 = 59, , 59 < 69,所以 67 - 8 < 69;(5) 76 - 70 = 6, 6 > 5,所以 76 - 70 > 5;(6) 27 - 7 = 20, 27 + 7 = 34, 20 < 34,所以 27 - 7 < 27 + 7;(7) 4元 = 40 角, 3 元 8 角 = 38 角, 40 角 > 38 角,所以 4 元 > 3 元 8 角;(8) 2 元 = 20 角, 20 角 = 20 角,所以 2 元 = 20 角;(9) 5元 = 50 角, 50 角 -3 角 = 47 角, 2 元 = 20 角, 47 角 > 20 角,所以 5 元 -3 角 > 2 元。", + "knowledge_points": [ + "两位数与一位数的减法(不退位)", + "两位数与整十数的减法", + "一位数与两位数的进位加法", + "元,角,分的认识及换算" + ], + "source": "23-24一年级下·福建福州·期末" + }, + { + "id": "428", + "unit": "第六单元100以内的加法和减法5", + "question_type": "填空题", + "difficulty": 0.85, + "question": "在括号里填上\">\"\"<\"或\"=\".\n2元-3角()13角 64 + 20 ()86100()10个十", + "options": [], + "answer": ">;<;=", + "solution": "【分析】先计算出每个算式的结果或先统一单位,然后比较大小即可。整数比较大小方法:①位数多的数大于位数少的数;②位数相同的,先比较最高位上的数,最高位上大的,数就大,最高位数相同的,就比较下一位,以此类推.\n【详解】2元=20角,20角-3角=17角,故2元-3角>13角;64+20=84,故64+20<86;10个十是100,即100=10个十。", + "knowledge_points": [ + "100 以内数的比大小", + "100 以内数的组成", + "两位数与整十数的加法", + "元,角,分的认识及换算" + ], + "source": "22-23一年级下·江西吉安·期末" + }, + { + "id": "429", + "unit": "第六单元100以内的加法和减法5", + "question_type": "填空题", + "difficulty": 0.85, + "question": "两个加数都是 50,和是( )。被减数和减数都是 20,差是( )。", + "options": [], + "answer": "100;0", + "solution": "【分析】根据\"加数+加数=和,被减数-减数=差\"来解决此题.\n【详解】 50 + 50 = 100;20 - 20 = 0;即,两个加数都是 50,和是 100。被减数和减数都是 20,差是 0。", + "knowledge_points": [ + "整十数之间的加减法" + ], + "source": "22-23 一年级下·江西吉安·期末" + }, + { + "id": "430", + "unit": "第六单元100以内的加法和减法5", + "question_type": "填空题", + "difficulty": 0.65, + "question": "( )比 45 多10,51比9多( )。", + "options": [], + "answer": "55;42", + "solution": "【分析】比一个数多几的数用加法计算,一个数比另一个多几用减法计算,据此得出结论即可.\n【详解】 45 + 10 = 55, 51 - 9 = 42,故55比45多10,51比9多42。", + "knowledge_points": [ + "两位数与整十数的加法", + "一位数与两位数的退位减法" + ], + "source": "22-23 一年级下·江西吉安·期末" + }, + { + "id": "431", + "unit": "第六单元100以内的加法和减法5", + "question_type": "填空题", + "difficulty": 0.85, + "question": "被减数是 56,减数是 8,差是( )。", + "options": [], + "answer": "48", + "solution": "【分析】根据被减数减减数=差即可解答.\n【详解】56-8=48;则被减数是56,减数是8,差是48。", + "knowledge_points": [ + "一位数与两位数的退位减法" + ], + "source": "22-23 一年级下·江西吉安·期末" + }, + { + "id": "432", + "unit": "第六单元100以内的加法和减法5", + "question_type": "填空题", + "difficulty": 0.65, + "question": "在括号里填上\">\"\"<\"或\"=\".\n12-8( )13-9\n8个十( )9个一\n54+9( )54-9\n23角( )2元\n70分( )7角\n2元4角( )4元2角", + "options": [], + "answer": "=;>;>;>;=;<", + "solution": "【分析】有算式的先计算出算式的结果再比较大小;单位不同的先换算成相同的单位再比较大小.\n【详解】12-8=4,13-9=4,故12-8=13-9;8个十是80,9个一是9,80>9,故8个十>9个一;54+9=63,54-9=45,63>45,故54+9>54-9;2元=20角,23角>20角,故23角>2元;1角=10分,故70分=7角;2元4角=24角,4元2角=42角,24角<42角,故2元4角<4元2角。", + "knowledge_points": [ + "100 以内数的比大小", + "100 以内数的组成", + "一位数与两位数的退位减法", + "元,角,分的认识及换算" + ], + "source": "23-24一年级下·河北廊坊·期末" + }, + { + "id": "433", + "unit": "第六单元100以内的加法和减法5", + "question_type": "填空题", + "difficulty": 0.65, + "question": "在括号里填上\">\" \"<\"或\"=\".\n43+9( )6290 分( )1 元 26+9( )41-6\n80( )51+308元7角( )78角 3角+4元( )3元4角", + "options": [], + "answer": "<;<;=;<;>;>", + "solution": "【分析】有算式的先计算出算式的结果再比较大小;单位不同的先换算成相同的单位再比较大小.\n【详解】43+9=52,52<62,故43+9<62;1元=100分,90<100,故90分<1元;26+9=35,41-6=35,故26+9=41-6;51+30=81,80<81,故80<51+30;8元7角=87角,87>78,故8元7角>78角;3角+4元=43角,3元4角=34角,43>34,故3角+4元>3元4角。", + "knowledge_points": [ + "100 以内数的比大小", + "一位数与两位数的进位加法", + "一位数与两位数的退位减法", + "元,角,分的认识及换算" + ], + "source": "22-23 一年级下·江西吉安·期末" + }, + { + "id": "434", + "unit": "第六单元100以内的加法和减法5", + "question_type": "填空题", + "difficulty": 0.65, + "question": "有一筐鸡蛋,如果 10 个 10 个地数,数了 4 次多 5 个,这筐鸡蛋有( )个。", + "options": [], + "answer": "45", + "solution": "【分析】先用加法计算出 4 个 10 的和是多少,再加上 5 个,即可计算出这筐鸡蛋有多少个.\n【详解】 10 + 10 + 10 + 10 + 5 = 45 (个);所以这筐鸡蛋有 45 个。", + "knowledge_points": [ + "100以内数的连加运算" + ], + "source": "23-24 一年级下·贵州六盘水·期末" + }, + { + "id": "435", + "unit": "第六单元100以内的加法和减法5", + "question_type": "填空题", + "difficulty": 0.65, + "question": "在括号里填上\">\"\"<\"或\"=\".\n62-2( )585元1分( )5元1角\n86-80( )86-853+7( )37+5", + "options": [], + "answer": ">;<;<;>", + "solution": "【分析】两位数比较大小,十位上大的数就大,如果十位上的数相同,个位上大的数就大;含有算式的大小比较,可以先计算出每个算式的结果,再比较大小。人民币的题目先统一单位再比较.\n【详解】 62 - 2 = 60 , 60 > 58,所以 62 - 2 > 58;1角 = 10 分, 1分 < 1 角,所以5元1分 < 5 元1角;86 - 80 = 6, 86 - 8 = 78, 6 < 78,所以 86 - 80 < 86 - 8;53 + 7 = 60, 37 + 5 = 42,所以 53 + 7 > 37 + 5 。", + "knowledge_points": [ + "100以内数的比大小", + "两位数与整十数的减法", + "一位数与两位数的进位加法", + "元,角,分的认识及换算" + ], + "source": "23-24一年级下·贵州六盘水·期末" + }, + { + "id": "436", + "unit": "第六单元100以内的加法和减法5", + "question_type": "填空题", + "difficulty": 0.65, + "question": "妈妈买了 86 颗糖果,每10颗糖果装一盒,可以装满( )盒,还剩( )颗。", + "options": [], + "answer": "8;6", + "solution": "【分析】用总数量依次减10,直到减不动为止,减几次就是装满几盒,最后减不着的就是剩下的数量。据此得出结论即可.\n【详解】 86 - 10 = 76 (颗)76 - 10 = 66 (颗)66 - 10 = 56 (颗)56 - 10 = 46 (颗)46 - 10 = 36 (颗)36 - 10 = 26 (颗)26 - 10 = 16 (颗)16 - 10 = 6 (颗);故可以装满 8 盒,还剩下 6 颗。", + "knowledge_points": [ + "两位数与整十数的减法" + ], + "source": "23-24 一年级下·江西上饶·期末" + }, + { + "id": "437", + "unit": "第六单元100以内的加法和减法5", + "question_type": "填空题", + "difficulty": 0.85, + "question": "70 比 40 多( ), 9 比 31 少( )。", + "options": [], + "answer": "30;22", + "solution": "【分析】求一个数比另一个数多(少)多少,用减法列式计算.\n【详解】 70 - 40 = 30;31 - 9 = 22;即,70比40多30,9比31少22。", + "knowledge_points": [ + "整十数之间的加减法", + "一位数与两位数的退位 减法" + ], + "source": "23-24 一年级下·江西上饶·期末" + }, + { + "id": "438", + "unit": "第六单元100以内的加法和减法5", + "question_type": "填空题", + "difficulty": 0.85, + "question": "一根电线长 1 米,第一次用去 25 厘米,第二次用去 30 厘米。这根电线比原来短了( )厘米。", + "options": [], + "answer": "55", + "solution": "【分析】要求这根电线比原来短几厘米,即求两次用去了多少厘米,根据加法的意义,用 25 + 30 进行解答即可.\n【详解】 25 + 30 = 55 (厘米)所以这根电线比原来短了 55 厘米。", + "knowledge_points": [ + "两位数与整十数的加法" + ], + "source": "22-23 二年级上·福建莆田·期末" + }, + { + "id": "439", + "unit": "第六单元100以内的加法和减法5", + "question_type": "填空题", + "difficulty": 0.65, + "question": "姐姐有 26 本漫画书,送给妹妹 4 本后,姐妹俩的本数就一样多,原来姐姐的漫画书比妹妹多( )本,原来妹妹有( )本漫画书。", + "options": [], + "answer": "8;18", + "solution": "【分析】姐姐拿出来的本数加妹妹得到的本数 = 姐姐比妹妹多的本数,姐姐的本数 - 姐姐比妹妹多的本数 = 妹妹原有的本数,据此得出结论即可.\n【详解】 4 + 4 = 8 (本)26 - 8 = 18 (本)故原来姐姐的漫画书比妹妹多 8 本,原来妹妹有 18 本漫画书。", + "knowledge_points": [ + "一位数与两位数的退位减法" + ], + "source": "23-24 二年级上·福建莆田·期末" + }, + { + "id": "440", + "unit": "第六单元100以内的加法和减法5", + "question_type": "填空题", + "difficulty": 0.65, + "question": "在括号里填上\">\" \"<\"或\"=\".\n93-30( )6046-7( )4064+8( )72-3\n2元8角( )30角 8角+9角( )1元5角 43-5( )40", + "options": [], + "answer": ">;<;>;<;>;<", + "solution": "【分析】根据整数加减法的计算法则依次计算出各算式的结果再比较大小。比较时,位数多的数就大;位数相同比较最高位,最高位大的数就大;最高位相同比较下一位,直到比较出结果为止。人民币的题目先统一单位再比较,1元=10角.\n【详解】 93 - 30 = 63, 63 > 60,所以 93 - 30 > 60;46 - 7 = 39, 39 < 40,所以 46 - 7 < 40;64 + 8 = 72, 72 - 3 = 69, 72 > 69,所以 64 + 8 > 72 - 3;2元8角 = 20 角 +8 角 = 28 角, 28 角 <30 角,所以 2 元 8 角 <30 角;8角+9角=1元7角,1元7角>1元5角,所以8角+9角>1元5角;43 - 5 = 38, 38 < 40,所以 43 - 5 < 40 。", + "knowledge_points": [ + "两位数与整十数的减法", + "一位数与两位数的进位加法", + "一位数与两位数的退位减法", + "十元以下人民币的认识与计算" + ], + "source": "23-24 一年级下·陕西安康·期末" + }, + { + "id": "441", + "unit": "第六单元100以内的加法和减法5", + "question_type": "填空题", + "difficulty": 0.85, + "question": "一个加数是55,另一个加数是8,它们的和是( ),它们的和前面的一个数是( )。", + "options": [], + "answer": "63;62", + "solution": "【分析】根据加数加加数=和,将数据代入即可。要求它们和前面的一个数是多少,即求比它们和少1的数是多少,根据减法的意义,列式解答即可.\n【详解】55+8=63;63-1=62。一个加数是55,另一个加数是8,它们的和是63,它们的和前面的一个数是62。", + "knowledge_points": [ + "两位数与一位数的减法(不退位)", + "一位数与两位数的进位加法" + ], + "source": "22-23一年级下·河南驻马店·期末" + }, + { + "id": "442", + "unit": "第六单元100以内的加法和减法5", + "question_type": "填空题", + "difficulty": 0.85, + "question": "从53开始连续加 4,写出每次的和:53,57,( ),( ),( )。", + "options": [], + "answer": "61;65;69", + "solution": "【分析】按顺序依次加上 4,然后根据整数加法计算法则,求出和,即可解决.\n【详解】 57 + 4 = 61, 61 + 4 = 65, 65 + 4 = 69,即,从 53 开始连续加 4,写出每次的和:53, 57, 61, 65, 69。 ", + "knowledge_points": [ + "两位数与一位数的加法(不进位)", + "一位数与两位数的进位加法" + ], + "source": "23-24一年级下·福建福州·期末" + }, + { + "id": "443", + "unit": "第六单元100以内的加法和减法5", + "question_type": "填空题", + "difficulty": 0.65, + "question": "56 比 10 多( ), 4 比 42 少( )。", + "options": [], + "answer": "46;38", + "solution": "【分析】求一个数比另一个多(少)多少,用减法列式计算.\n【详解】56-10=46;42-4=38。即,56比10多46,4比42少38。", + "knowledge_points": [ + "两位数与整十数的减法", + "一位数与两位数的退位减法" + ], + "source": "23-24 一年级下·福建福州·期末" + }, + { + "id": "444", + "unit": "第六单元100以内的加法和减法5", + "question_type": "填空题", + "difficulty": 0.85, + "question": "按规律继续写下去。 \n15,20,25,( )。 \n64,56,48,40,( )。", + "options": [], + "answer": "30;32", + "solution": "【分析】观察第一列数字可知:15和20相差5,20和25相差5,所以这列数字从左往右依次增加5;观察第二列数字可知:64和56相差8,56和48相差8,48和40相差8,所以这列数字从左往右依次减少8,据此解答即可.\n【详解】 25 + 5 = 30,所以这列数字是:15,20,25,30.40 - 8 = 32,所以这列数字是:64,56,48,40,32。", + "knowledge_points": [ + "一位数与两位数的进位加法", + "一位数与两位数的退位减法", + "整数排列的规律" + ], + "source": "23-24 一年级下·湖南邵阳·期末" + }, + { + "id": "445", + "unit": "第六单元100以内的加法和减法5", + "question_type": "填空题", + "difficulty": 0.85, + "question": "在括号里填上\">\"\"<\"或\"=\".\n48( )84\n9个十( )9个一\n37+6( )40+1\n50角( )5元\n30分( )2角9分\n4元3角-2元( )2元", + "options": [], + "answer": "<;>;>;=;>;>", + "solution": "【分析】比较数的大小,先看位数的多少,位数多的数就大;有算式的先计算再比较。1元=10角,1角=10分.\n【详解】48<84;9个十>9个一;37+6=43,40+1=41,43>41,则37+6>40+1;50角=5元;2角9分=29分,30>29,则30分>2角9分;4元3角-2元=2元3角,2元3角>2元,则4元3角-2元>2元。", + "knowledge_points": [ + "整十数加,减一位数", + "一位数与两位数的进位加法", + "元,角,分的认识及换算", + "十元以下人民币的认识与计算" + ], + "source": "22-23一年级下·江西吉安·期末" + }, + { + "id": "446", + "unit": "第六单元100以内的加法和减法5", + "question_type": "填空题", + "difficulty": 0.85, + "question": "( )比 29 大 7;比 43 少 20 的数是( )。", + "options": [], + "answer": "36;23", + "solution": "【分析】要求比 29 大 7 的数是多少,根据加法的意义,用 29 + 7 进行解答即可。要求比 43 少 20 的数是多少,根据减法的意义,用 43-20 进行解答即可.\n【详解】 29 + 7 = 36,所以36比29大7;43 - 20 = 23,所以比 43 少 20 的数是 23 。", + "knowledge_points": [ + "两位数与整十数的减法", + "一位数与两位数的进位加法" + ], + "source": "23-24 一年级下·江西吉安·期末" + }, + { + "id": "447", + "unit": "第六单元100以内的加法和减法5", + "question_type": "填空题", + "difficulty": 0.85, + "question": "在括号里填上 \">\" \"<\" 或 \"=\" 。100个一( )10个十 87角( )7元8角 72-9( )64+3", + "options": [], + "answer": "=;>;<", + "solution": "【分析】根据 100 以内整数的组成可知: 100 个一是 100, 10 个十是 100,据此解答即可。根据 1 元 = 10 角先进行单位换算,再比较大小。有算式先算出算式的得数,再根据 100 以内整数比较大小:先看十位上的数,十位上的数大这个数就大;十位上的数相同再比较个位上的数,个位上的数大这个数就大.\n【详解】100 个一是 100,10 个十是 100,所以 100 个一=10 个十;7元8角 = 78 角, 87 角 > 78 角,所以 87 角 > 7 元 8 角;72 - 9 = 63, 64 + 3 = 67, 63 < 67,所以 72 - 9 < 64 + 3 。", + "knowledge_points": [ + "100 以内数的比大小", + "100 以内数的组成", + "一位数与两位数的退位减法", + "元,角,分的认识及换算" + ], + "source": "23-24 一年级下·江西吉安·期末" + }, + { + "id": "448", + "unit": "第六单元100以内的加法和减法5", + "question_type": "填空题", + "difficulty": 0.65, + "question": "妈妈买了 27 个苹果, 5 个苹果装一盘,可以装满( )盘,还剩( )个。", + "options": [], + "answer": "5;2", + "solution": "【分析】根据减法的意义,从苹果的总个数中连续减去 5 个,直到不够减;减了几次就是可以装满的盘数,不够减的数即为剩余的个数,据此解答.\n【详解】 27 - 5 - 5 - 5 - 5 - 5 = 2 (个)减了5次,可以装满5盘,还剩下2个。", + "knowledge_points": [ + "100以内数的连减运算" + ], + "source": "22-23 一年级下·江西吉安·期末" + }, + { + "id": "449", + "unit": "第六单元100以内的加法和减法5", + "question_type": "填空题", + "difficulty": 0.65, + "question": "括号里最大能填几。\n21 - () > 1219 > 6 + ()\n4 + 15 > ( ) + 718 - ( ) > 11 + 2", + "options": [], + "answer": "8;12;11;4", + "solution": "【分析】有算式的先算出算式的结果,再根据整数比较大小的方法解答.\n【详解】21-12=9,9-1=8,故21-8>12;19-6=13,13-1=12,故19>6+12;4+15=19,19-7=12,12-1=11,故4+15>11+7;11+2=13,18-13=5,5-1=4,故18-4>11+2。", + "knowledge_points": [ + "20 以内数的比大小", + "不进位加法(20 以内)", + "不退位减法(20 以内)", + "一位数与两位数的退位减法" + ], + "source": "23-24一年级下·江西上饶·期末" + }, + { + "id": "450", + "unit": "第六单元100以内的加法和减法5", + "question_type": "填空题", + "difficulty": 0.85, + "question": "在横线里填\">\" \"<\" 或 \"=\".\n49( )94\n15-7( )7\n75-6( )15\n57( )48\n12+30( )52\n63-5( )58", + "options": [], + "answer": "<;>;>;>;<;=", + "solution": "【分析】算式先计算出得数,再按100以内数的大小比较方法比较.\n【详解】49<94;15-7=8,8>7,所以15-7>7;75-6=69,69>15,所以75-6>15;57>48;12+30=42,42<52,所以12+30<52;63-5=58。", + "knowledge_points": [ + "100 以内数的比大小", + "两位数与整十数的加法", + "一位数与两位数的退位减法" + ], + "source": "23-24 一年级下·海南省直辖县级单位·期末" + }, + { + "id": "451", + "unit": "第六单元100以内的加法和减法5", + "question_type": "填空题", + "difficulty": 0.65, + "question": "比一比。(在横线里填上 \">\" \"<\" 或 \"=\" .\n34+4( )78\n67( )42+40\n66-1( )66-10\n20+35( )20+25\n50分( )5角\n7元5角( )5元7角", + "options": [], + "answer": "<;<;>;>;=;>", + "solution": "【分析】根据整数加减法的计算法则,依次计算出各算式的结果再比较大小。比较时,位数多的数就大;位数相同比较最高位,最高位大的数就大;最高位相同比较下一位,直到比较出结果为止。人民币的题目先统一单位再比较.\n【详解】34+4=38;38<78,则34+4<78;42+40=82;67<82,则67<42+40;66-1=65;66-10=56;65>56,则66-1>66-10;20+35=55;20+25=45;55>45,则20+35>20+25;1角=10分,则50分=5角;7元5角=75角;5元7角=57角;75角>57角,则7元5角>5元7角。", + "knowledge_points": [ + "100 以内数的比大小", + "两位数与一位数的加法(不进位)", + "两位数与整十数的减法", + "元,角,分的认识及换算" + ], + "source": "23-24 一年级下·广东汕尾·期末" + }, + { + "id": "452", + "unit": "第六单元100以内的加法和减法5", + "question_type": "填空题", + "difficulty": 0.85, + "question": "计算 50 - (18 + 2)\n时,先算()法,再算()法,得数是()。", + "options": [], + "answer": "加;减;30", + "solution": "【分析】100 以内加减法混合运算中,若没有括号,则从左往右计算;若有括号,先算括号里面的,再算括号外面的,由此解答.\n【详解】 50 - (18 + 2)= 50 - 20 = 30;计算 50 - (18 + 2) 时,先算加法,再算减法,得数是 30 。", + "knowledge_points": [ + "带有小括号的混合运算" + ], + "source": "23-24 一年级下·广东汕尾·期末" + }, + { + "id": "453", + "unit": "第六单元100以内的加法和减法5", + "question_type": "填空题", + "difficulty": 0.65, + "question": "在括号里填上\">\"\"<\"或\"=\"。\n38角( )3元8角\n2个十( )8个一\n4元5分( )4元5角\n55-3( )55-30\n25+50( )26+50\n19-9( )48-40", + "options": [], + "answer": "=;>;<;>;<;>", + "solution": "【分析】含有算式的,分别计算出算式的结果,再比较大小;单位不统一的,先化成相同单位,再比较大小,1元=10角,1角=10分.\n【详解】38角=3元8角;2个十是20,8个一是8,20>8,所以2个十>8个一;4元5分<4元5角;55-3=52,55-30=25,52>25,所以55-3>55-30;25+50=75,26+50=76,75<76,所以25+50<26+50;19-9=10,48-40=8,10>8,所以19-9>48-40。", + "knowledge_points": [ + "100以内数的比大小", + "两位数与整十数的加法", + "两位数与整十数的减法", + "元,角,分的认识及换算" + ], + "source": "23-24一年级下·湖南郴州·期末" + }, + { + "id": "454", + "unit": "第六单元100以内的加法和减法5", + "question_type": "填空题", + "difficulty": 0.85, + "question": "比 69 多 20 的数是( ), 比 83 少 7 的数是( )。", + "options": [], + "answer": "89;76", + "solution": "【分析】要求比 69 多 20 的数是多少,根据加法的意义,用 69 + 20 进行解答即可;要求比 83 少 7 的数是多少,根据减法的意义,用 83-7 进行解答即可.\n【详解】 69 + 20 = 89,所以比 69 多 20 的数是 89;83 - 7 = 76,所以比 83 少 7 的数是 76 。", + "knowledge_points": [ + "两位数与整十数的加法", + "一位数与两位数的退位减法" + ], + "source": "23-24 一年级下·甘肃平凉·期末" + }, + { + "id": "455", + "unit": "第六单元100以内的加法和减法5", + "question_type": "判断题", + "difficulty": 0.85, + "question": "\"35-4\"的得数的十位上的数是 2。( )", + "options": [], + "answer": "×", + "solution": "【分析】根据 100 以内数的减法计算方法,直接计算出 \"35 -4\"的得数,再看得数的十位上的数是否是 2 即可。35 个位上的 5 减 4 够减,不用从十位退一当十,据此计算即可.\n【详解】 35 - 4 = 31;所以 \"35-4\"的得数的十位上的数是 3 。原题说法错误。故答案为: ×", + "knowledge_points": [ + "两位数与一位数的减法(不退位)" + ], + "source": "23-24一年级下·陕西安康·期末" + }, + { + "id": "456", + "unit": "第六单元100以内的加法和减法5", + "question_type": "判断题", + "difficulty": 0.85, + "question": "最大的两位数比最小的一位数少 1 。( )", + "options": [], + "answer": "×", + "solution": "【分析】最大的两位数是 99,最小的一位数是 1,把两数相减,求出差,即可判断对错.\n【详解】 99 - 1 = 98;即,最大的两位数比最小的一位数少98;原说法错误。故答案为: ×", + "knowledge_points": [ + "100以内数的比大小", + "两位数与一位数的减法(不退位)" + ], + "source": "23-24 一年级下·陕西·期末" + }, + { + "id": "457", + "unit": "第六单元100以内的加法和减法5", + "question_type": "判断题", + "difficulty": 0.85, + "question": "与76相邻的两个数是77和88。()", + "options": [], + "answer": "×", + "solution": "【分析】要求与 76 相邻的两个数是多少,即求比 76 多 1 和少 1 的数分别是多少.\n【详解】 76 - 1 = 75;76 + 1 = 77;所以与 76 相邻的两个数是 75 和 77。原题说法错误。故答案为: ×", + "knowledge_points": [ + "两位数与一位数的减法(不退位)", + "相邻的数" + ], + "source": "23-24一年级下·陕西安康·期末" + }, + { + "id": "458", + "unit": "第六单元100以内的加法和减法5", + "question_type": "判断题", + "difficulty": 0.85, + "question": "56颗珠子,每 10颗串一串,可以串 6 串。( )", + "options": [], + "answer": "×", + "solution": "【分析】用56连续减去10,算一算56里面最多可以减去几个10,减了几个10,就表示最多可以串几串珠子;据此解决.\n【详解】56-10=46;46-10=36;36-10=26;26-10=16;16-10=6。即,56里面最多可以减去5个10,故,56颗珠子,每10颗串一串,可以串5串;原说法错误。故答案为:×", + "knowledge_points": [ + "两位数与整十数的减法" + ], + "source": "22-23一年级下·河南驻马店·期末" + }, + { + "id": "459", + "unit": "第六单元100以内的加法和减法5", + "question_type": "判断题", + "difficulty": 0.65, + "question": "52 - 6 > 50 - 40 。()", + "options": [], + "answer": "√", + "solution": "【分析】根据100以内减法的计算方法,分别计算出每个算式的结果,再比较即可.\n【详解】52-6=46;50-40=10;46>10;所以52-6>50-40。原题干说法正确。故答案为:√", + "knowledge_points": [ + "100 以内数的比大小", + "整十数之间的加减法", + "一位数与两位数的退位减法" + ], + "source": "23-24 一年级下·河北廊坊·期末" + }, + { + "id": "460", + "unit": "第六单元100以内的加法和减法5", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式计算.\n![](images/353e53184bc1af4932c1ef6f3deee563df2280d1d393850ee1797a23b56e9d4f.jpg)\n□○□=□(支)", + "options": [], + "answer": "23 - 4 = 19", + "solution": "【分析】共 23 支笔,盒子外面有 4 支,用总数减去盒子外面的支数即可求出盒子里面的支数.\n【详解】由题意分析得:23 - 4 = 19 (支)", + "knowledge_points": [ + "图文问题", + "一位数与两位数的退位减法" + ], + "source": "23-24 一年级下·河南信阳·期末" + }, + { + "id": "461", + "unit": "第六单元100以内的加法和减法5", + "question_type": "计算题", + "difficulty": 0.65, + "question": "看图列式计算.\n![](images/29542f9385497aa21b7f11492ce31d40b86407ecc3c5d220e62358c12b23c007.jpg)\n□○□=□()", + "options": [], + "answer": "25 + 7 = 32", + "solution": "【分析】左边有 25 个,右边有 7 个,求一共有多少个,根据加法的意义,把两边的个数相加求出总数.\n【详解】 25 + 7 = 32 (个)一共有 32 个。", + "knowledge_points": [ + "图文问题", + "一位数与两位数的进位加法" + ], + "source": "23-24 一年级下·河南信阳·期末" + }, + { + "id": "462", + "unit": "第六单元100以内的加法和减法5", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式计算.\n![](images/b051b6b3531fddd0f77401c6ea7b5cc173ad201e6b82b0cacdbdee9cb59b2973.jpg)\n□○□=□()", + "options": [], + "answer": "24 - 6 = 18", + "solution": "【分析】共 24 个,盒子外面有 6 个,用总数减去盒子外面的个数即可求出盒子里面的个数.\n【详解】 24 - 6 = 18 (个)", + "knowledge_points": [ + "图文问题", + "一位数与两位数的退位减法" + ], + "source": "23-24 一年级下·河南信阳·期末" + }, + { + "id": "463", + "unit": "第六单元100以内的加法和减法5", + "question_type": "计算题", + "difficulty": 0.85, + "question": "我会列式.\n![](images/d3047f7833ae506b77a163a61e3d409b60aee276790a6a91adee41769da5b114.jpg)", + "options": [], + "answer": "35 - 5 = 30", + "solution": "【分析】根据题图,总人数35人一右边的小朋友人数5人 = 左边房子里面的人数,据此解答.\n【详解】根据分析: 35 - 5 = 30 (人)\n房子里面有30人。", + "knowledge_points": [ + "两位数与一位数的减法(不退位)" + ], + "source": "23-24 一年级下·江西赣州·期末" + }, + { + "id": "464", + "unit": "第六单元100以内的加法和减法5", + "question_type": "计算题", + "difficulty": 0.65, + "question": "看图列式计算.\n![](images/9cd9b8675b61692fef502f5955beb7609e7c036d8ee479b6486a8f6034200f5a.jpg)\n□○□=□()", + "options": [], + "answer": "29-9=20", + "solution": "【分析】由图可知,一共有 29 支铅笔,右边有 9 支,求左边盒子里有多少支。用减法列式计算.\n【详解】 29 - 9 = 20 (支)", + "knowledge_points": [ + "图文问题", + "两位数与一位数的减法(不退位)" + ], + "source": "23-24 一年级下·山东临沂·期末" + }, + { + "id": "465", + "unit": "第六单元100以内的加法和减法5", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式.\n![](images/dc1ae2f3d3640d133c97d7e39637946e.png)\n□○□=□()", + "options": [], + "answer": "56 - 20 = 36", + "solution": "【分析】短袖的单价=总钱数减裙子的单价,将数据代入,即可得出答案.\n【详解】56-20=36(元)", + "knowledge_points": [ + "图文问题", + "两位数与整十数的减法" + ], + "source": "23-24 一年级下·浙江杭州·期末" + }, + { + "id": "466", + "unit": "第六单元100以内的加法和减法5", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式计算.\n![](images/ee22acdab459bd650476f9c7d5ef6cef99cde0dcd1f0e50ae188ceeabbff8c6e.jpg)\n□○□=□()", + "options": [], + "answer": "29 + 3 = 32", + "solution": "【分析】中巴车可以乘坐 29 人,小轿车可以乘坐 3 人,相加即可求出两辆车一共可以坐的人数.\n【详解】 29 + 3 = 32 (人);一共可以坐 32 人。", + "knowledge_points": [ + "图文问题", + "一位数与两位数的进位加法" + ], + "source": "23-24 一年级下·河南信阳·期末" + }, + { + "id": "467", + "unit": "第六单元100以内的加法和减法5", + "question_type": "计算题", + "difficulty": 0.65, + "question": "计算.\n25 + 30 + 7 = 59 - (34 - 4) = 86 - (16 +4) =37 - 9 + 4 =48 + (12 - 7) =92 - 9 - 20 =", + "options": [], + "answer": "62;29;66;32;53;63", + "solution": "【分析】整数的运算顺序:连加,连减,加减混合的算式,从左往右依次算起;有小括号的要先算小括号里的.\n【详解】25+30+7=62;59-(34-4)=59-30=29;86-(16+4)=86-20=66;37-9+4=28+4=32;48+(12-7)=48+5=53;92-9-20=83-20=63。", + "knowledge_points": [ + "100以内数的连加运算", + "100以内数的连减运算", + "100以内数的加减混合运算", + "带有小括号的混合运算" + ], + "source": "23-24 一年级下·江西吉安·期末" + }, + { + "id": "468", + "unit": "第六单元100以内的加法和减法5", + "question_type": "计算题", + "difficulty": 0.65, + "question": "直接写得数.\n84 - 60 = 20 + 40 = 25 + 9 = 40 - 10 = 28 - 8 = 40 + 33 = 28 + 30 = 14 - 5 = 43 + 7 = 80 + 5 = 6 + 32 = 17 - 8 =", + "options": [], + "answer": "24;60;34;30;20;73;58;9;50;85;38;9", + "solution": "【分析】本题考查100以内数的加减法口算,包括两位数与整十数的加减,整十数之间的加减,一位数与两位数的进位加法以及20以内的退位减法。计算时需根据题目类型灵活运用口算方法.\n【详解】84减60得24;20加40得60;25加9得34;40减10得30;28减8得20;40加33得73;28加30得58;14减5得9;43加7得50;80加5得85;6加32得38;17减8得9。", + "knowledge_points": [ + "两位数与整十数的加法", + "两位数与整十数的减法", + "一位数与两位数的进位加法" + ], + "source": "23-24 一年级下·河北廊坊·期末" + }, + { + "id": "469", + "unit": "第六单元100以内的加法和减法5", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式计算.\n![](images/26f4d35ebbbe42413b05997b5876c56d1cd850d158da39e9a59ef15f31b96b4c.jpg)\n□○□=□()", + "options": [], + "answer": "22 + 5 = 27", + "solution": "【分析】把左边梨的数量与右边的数量加起来,求出和,就是梨的总数量.\n【详解】由题意分析得:22 + 5 = 27 (个)", + "knowledge_points": [ + "图文问题", + "两位数与一位数的加法(不进位)" + ], + "source": "22-23 一年级下·河南驻马店·期末" + }, + { + "id": "470", + "unit": "第六单元100以内的加法和减法5", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式计算.\n![](images/9f1d05daaf6a23d5370fab2342ba4cf91b183a52ea43b5356444e017478f2568.jpg)\n□○□=□()", + "options": [], + "answer": "26 - 6 = 20", + "solution": "【分析】用苹果的总数量减去右边的数量,求出差,就是左边篮子里的数量.\n【详解】由题意分析得:26 - 6 = 20 (个)", + "knowledge_points": [ + "图文问题", + "两位数与一位数的减法(不退位)" + ], + "source": "22-23 一年级下·河南驻马店·期末" + }, + { + "id": "471", + "unit": "第六单元100以内的加法和减法5", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式计算.\n![](images/ccbca87e26bd90607c531202b765180163008e9c4cc6db05ca4c043f20b6946a.jpg)\n□○□=□()", + "options": [], + "answer": "25 - 8 = 17", + "solution": "【分析】用铅笔的总数量减去左边的数量,求出差,就是右边盒子里的铅笔数量.\n【详解】由题意分析得:25 - 8 = 17 (支)", + "knowledge_points": [ + "一位数与两位数的退位减法" + ], + "source": "23-24 一年级下·贵州六盘水·期末" + }, + { + "id": "472", + "unit": "第六单元100以内的加法和减法5", + "question_type": "解答题", + "difficulty": 0.85, + "question": "买一本故事书和一支水性笔,一共需要多少元钱。故事书:21元,水性笔:2元\n□○□=□()", + "options": [], + "answer": "23元", + "solution": "【分析】根据题意,将故事书的钱数和水性笔的钱数相加,就是一共需要的钱数.\n【详解】 21 + 2 = 23 (元)答:一共需要 23 元钱。", + "knowledge_points": [ + "图文问题", + "两位数与一位数的加法(不进位)" + ], + "source": "23-24一年级下·河北保定·期末" + }, + { + "id": "473", + "unit": "第六单元100以内的加法和减法5", + "question_type": "解答题", + "difficulty": 0.85, + "question": "学校新购进 20 个足球,一年级分了 4 个足球,其余的分给了二年级,二年级分了多少个足球。", + "options": [], + "answer": "16个", + "solution": "【分析】根据题意,足球的总数量减去分给一年级的数量,剩下的就是分给二年级的数量.\n【详解】 20 - 4 = 16 (个)答:二年级分了 16 个足球。", + "knowledge_points": [ + "一位数与两位数的退位减法" + ], + "source": "23-24 二年级下·甘肃平凉·期末" + }, + { + "id": "474", + "unit": "第六单元100以内的加法和减法5", + "question_type": "解答题", + "difficulty": 0.85, + "question": "这本书一共有多少页。我已经看了13页,还有20页没有看.\n□○□=□()", + "options": [], + "answer": "33页", + "solution": "【分析】根据加法的意义,已经看了的页数 + 还没看的页数 = 这本书的页数,由此解答.\n【详解】 13 + 20 = 33 (页)答:这本书一共有 33 页。", + "knowledge_points": [ + "图文问题", + "两位数与整十数的加法" + ], + "source": "23-24 一年级下·山东临沂·期末" + }, + { + "id": "475", + "unit": "第六单元100以内的加法和减法5", + "question_type": "解答题", + "difficulty": 0.65, + "question": "妈妈买了 3 袋饼干,每袋有 8 块。妈妈一共买了多少块饼干。", + "options": [], + "answer": "24块", + "solution": "【分析】要求妈妈一共买了多少块饼干,即求3袋饼干一共有多少块,根据加法的意义,用 8 + 8 + 8 进行解答即可.\n【详解】 8 + 8 + 8;= 16 + 8 = 24 (块) 答:妈妈一共买了 24 块饼干。", + "knowledge_points": [ + "连加 (20 以内)" + ], + "source": "22-23 一年级下·江西吉安·期末" + }, + { + "id": "476", + "unit": "第六单元100以内的加法和减法5", + "question_type": "解答题", + "difficulty": 0.85, + "question": "李阿姨在书店买了一本 12 元的《儿童漫画》和一本 7 元的《故事大王》。付了 20 元,应找回多少元。", + "options": [], + "answer": "1元", + "solution": "【分析】要求李阿姨应找回多少元,根据减法的意义,用李阿姨付的钱减去买的两本书的价钱,即可得出答案.\n【详解】 20 - 7 - 12 = 13 - 12 = 1 ( 元) 答:应找回 1 元。", + "knowledge_points": [ + "连减 (20以内)" + ], + "source": "22-23一年级下·江西吉安·期末" + }, + { + "id": "477", + "unit": "第六单元100以内的加法和减法5", + "question_type": "解答题", + "difficulty": 0.85, + "question": "图书角现在还剩多少本书。\n![](images/663be3e079dbb1fdfd1074db5664192dc840ac8138811990761f6853533a0413.jpg)\n□○□=□()", + "options": [], + "answer": "42本", + "solution": "【分析】根据减法的意义,图书角原有图书的本数减借走的本数 = 图书角现在还剩下的本数.\n【详解】 48 - 6 = 42 (本)答:图书角现在还剩 42 本书。", + "knowledge_points": [ + "图文问题", + "两位数与一位数的减法(不退位)" + ], + "source": "23-24 一年级下·浙江·期末" + }, + { + "id": "478", + "unit": "第六单元100以内的加法和减法5", + "question_type": "解答题", + "difficulty": 0.85, + "question": "学校图书馆有一些故事书,被借走一些后还剩30本,借出的数量和剩下的数量一样多,学校原来有故事书多少本。", + "options": [], + "answer": "60本", + "solution": "【分析】根据题意,借走的和剩下的数量同样多,都是 30 本,求原来的数量,根据加法的意义,借走的数量 + 剩下的数量 = 原来的数量.\n【详解】 30 + 30 = 60 (本)答:学校原来有故事书 60 本。", + "knowledge_points": [ + "整十数之间的加减法" + ], + "source": "23-24一年级下·广东河源·期末" + }, + { + "id": "479", + "unit": "第六单元100以内的加法和减法5", + "question_type": "解答题", + "difficulty": 0.65, + "question": "小明要写 60 个大字,他上午写了 30 个,下午写了 20 个,还要写几个。", + "options": [], + "answer": "10个", + "solution": "【分析】总共要写的字数减上午写的字数减下午写的字数=还要写的字数,据此得出结论即可.\n【详解】 60 - 30 - 20 = 30 - 20 = 10 ( 个) 答:还要写 10 个。", + "knowledge_points": [ + "100以内数的连减运算" + ], + "source": "22-23 一年级下·河南驻马店·期末" + }, + { + "id": "480", + "unit": "第六单元100以内的加法和减法5", + "question_type": "解答题", + "difficulty": 0.65, + "question": "一年级同学们做游戏。一年级有35个同学,14个同学在跳绳,6个同学在丢沙包,其余同学在拍球。(1) 跳绳的同学比丢沙包的同学多几个人。 (2) 跳绳的同学和丢沙包的同学共多少个人。 (3) 拍球的同学有几个。", + "options": [], + "answer": "8个;20个;15个", + "solution": "【分析】(1)用跳绳的数量减去丢沙包的数量,即可求出跳绳的同学比丢沙包的同学多几个人。(2) 用跳绳的数量加丢沙包的数量,即可求出跳绳的同学和丢沙包的同学共多少个人。(3) 用总的同学数量减去跳绳的同学和丢沙包的同学数量,即可求出拍球的同学有几个.\n【详解】 (1) 14 - 6 = 8 (个);答:跳绳的同学比丢沙包的同学多 8 个人。(2) 14 + 6 = 20 (个)答:跳绳的同学和丢沙包的同学共 20 个人。(3) 35 - 20 = 15 (个)答:拍球的同学有 15 个。", + "knowledge_points": [ + "十几减 7,6 的退位减法", + "两位数与整十数的减法", + "一位数与两位数的进位加法" + ], + "source": "22-23一年级下·河南驻马店·期末" + }, + { + "id": "481", + "unit": "第六单元100以内的加法和减法5", + "question_type": "解答题", + "difficulty": 0.65, + "question": "水果店原来有 52 箱水果,卖了 20 箱水果,又进货 8 箱。水果店现在有多少箱水果。口答:水果店现在有()箱水果。", + "options": [], + "answer": "40箱", + "solution": "【分析】卖出 20 箱水果,表示水果的数量减少 20 箱,又进货 8 箱,表示水果的数量增加 8 箱,要求水果店现在有多少箱水果,根据整数加减法运算,用 52 - 20 + 8 进行解答即可.\n【详解】 52 - 20 + 8 = 32 + 8 = 40 (箱) 答:水果店现在有 40 箱水果。", + "knowledge_points": [ + "100 以内数的加减混合运算" + ], + "source": "22-23一年级下·江西吉安·期末" + }, + { + "id": "482", + "unit": "第六单元100以内的加法和减法5", + "question_type": "解答题", + "difficulty": 0.65, + "question": "一共有 30 瓶饮料,有 7 瓶山楂饮料,丽丽拿走了 6 瓶,还剩下多少瓶饮料。", + "options": [], + "answer": "24瓶", + "solution": "【分析】饮料的总数量减拿走的数量=剩下的数量,据此列式解答即可.\n【详解】30-6=24(瓶)。答:还剩下24瓶饮料。", + "knowledge_points": [ + "整十数加,减一位数" + ], + "source": "23-24 一年级下·江西吉安·期末" + }, + { + "id": "483", + "unit": "第六单元100以内的加法和减法5", + "question_type": "解答题", + "difficulty": 0.65, + "question": "树上原来有 32 只鸟,飞走了 20 只,又飞来了 10 只,树上现在有多少只鸟。", + "options": [], + "answer": "22只", + "solution": "【分析】用树上原有的鸟的数量减去飞走的鸟的数量再加上又飞来的鸟的数量,即可求出树上现在有的鸟的数量.\n【详解】 32 - 20 + 10 = 22 (只)答:树上现在有 22 只鸟。", + "knowledge_points": [ + "100 以内数的加减混合运算" + ], + "source": "23-24 一年级下·贵州六盘水·期末" + }, + { + "id": "484", + "unit": "第六单元100以内的加法和减法5", + "question_type": "解答题", + "difficulty": 0.65, + "question": "妈妈买了 27 个苹果, 9 个装一袋,可以装几袋。", + "options": [], + "answer": "3袋", + "solution": "【分析】要求可以装几袋,需计算 27 里面有几个 9,用 27 连减 9 即可得解,减了几次就是可以装几袋.\n【详解】 27 - 9 - 9 - 9 = 0 (袋)减了 3 次,所以可以装 3 袋。答:可以装 3 袋。", + "knowledge_points": [ + "100 以内数的连减运算" + ], + "source": "23-24 一年级下·贵州六盘水·期末" + }, + { + "id": "485", + "unit": "第六单元100以内的加法和减法5", + "question_type": "解答题", + "difficulty": 0.85, + "question": "在弯腰行动中,王兰捡了20个废弃物,李明捡了42个废弃物,王兰和李明一共捡了多少个废弃物。", + "options": [], + "answer": "62个", + "solution": "【分析】求王兰和李明一共捡了多少个废弃物,就是求两个数的和,用加法列式计算.\n【详解】 20 + 42 = 62 (个)答:王兰和李明一共捡了 62 个废弃物。", + "knowledge_points": [ + "两位数与整十数的加法" + ], + "source": "23-24 一年级下·江西上饶·期末" + }, + { + "id": "486", + "unit": "第六单元100以内的加法和减法5", + "question_type": "解答题", + "difficulty": 0.85, + "question": "明明做了 20 道口算题,丽丽做了 38 道口算题,明明再做多少道口算题就和丽丽同样多了。", + "options": [], + "answer": "18道", + "solution": "【分析】根据减法的意义,丽丽做的数量减明明做的数量=和丽丽做的同样多时,明明要再做的数量.\n【详解】 38 - 20 = 18 (道);答:明明再做 18 道口算题就和丽丽同样多了。", + "knowledge_points": [ + "两位数与整十数的减法" + ], + "source": "23-24 一年级下·甘肃平凉·期末" + }, + { + "id": "487", + "unit": "第六单元100以内的加法和减法5", + "question_type": "解答题", + "difficulty": 0.65, + "question": "王奶奶家养了一些鸡和鸭,一共有 24 只,其中鸡有 8 只,鸭有多少只。", + "options": [], + "answer": "16只", + "solution": "【分析】根据减法的意义,鸡和鸭的总数量减鸡的数量=鸭的数量.\n【详解】 24 - 8 = 16 (只)答:鸭有 16 只。", + "knowledge_points": [ + "一位数与两位数的退位减法" + ], + "source": "23-24 一年级下·甘肃平凉·期末" + }, + { + "id": "488", + "unit": "第六单元100以内的加法和减法5", + "question_type": "解答题", + "difficulty": 0.85, + "question": "3 只小兔采蘑菇,每只小兔采 20 朵蘑菇,它们一共采了多少朵蘑菇。", + "options": [], + "answer": "60朵", + "solution": "【分析】根据题意,每只小兔采 20 朵, 3 只小兔采的数量为 3 个 20 朵,用加法即可计算出总数量.\n【详解】 20 + 20 + 20 = 60 (朵)答:它们一共采了 60 朵蘑菇。", + "knowledge_points": [ + "整十数之间的加减法" + ], + "source": "23-24 一年级下·甘肃平凉·期末" + }, + { + "id": "489", + "unit": "第六单元100以内的加法和减法5", + "question_type": "解答题", + "difficulty": 0.65, + "question": "小芳折了 26 朵花,小丽折了 9 朵花和 10 只纸鹤。小芳比小丽多折了多少朵花。口答:小芳比小丽多折了 ( ) 朵花。", + "options": [], + "answer": "17朵", + "solution": "【分析】小芳折的花的数量减小丽折的花的数量=小芳比小丽多折的花的数量,据此列式解答即可.\n【详解】26-9=17(朵)。答:小芳比小丽多折了17朵花。", + "knowledge_points": [ + "一位数与两位数的退位减法" + ], + "source": "22-23 一年级下·江西吉安·期末" + }, + { + "id": "490", + "unit": "第六单元100以内的加法和减法5", + "question_type": "解答题", + "difficulty": 0.65, + "question": "小兰和小林都想买一个篮球。小兰单独买还缺26元,小林单独买缺30元,她们的钱合起来正好够买。买这个篮球需要多少钱。", + "options": [], + "answer": "56元", + "solution": "【分析】因为她们的钱合起来正好够买,所以知两人缺的钱数的和即为篮球的价钱。根据加法的意义,用 26 + 30 进行解答即可.\n【详解】 26 + 30 = 56 (元)答:买这个篮球需要 56 元钱。", + "knowledge_points": [ + "两位数与整十数的加法" + ], + "source": "23-24一年级下·湖南邵阳·期末" + }, + { + "id": "491", + "unit": "第六单元100以内的加法和减法5", + "question_type": "解答题", + "difficulty": 0.85, + "question": "小玉今年 8 岁,妈妈今年 33 岁, 10 年后妈妈比小玉大几岁。", + "options": [], + "answer": "25岁", + "solution": "【分析】妈妈的年龄与小玉的年龄差不变,用妈妈今年的年龄减去小玉今年的年龄即可.\n【详解】 33 - 8 = 25 (岁)答: 10 年后妈妈比小玉大 25 岁。", + "knowledge_points": [ + "一位数与两位数的退位减法" + ], + "source": "22-23一年级下·江西吉安·期末" + }, + { + "id": "492", + "unit": "第六单元100以内的加法和减法5", + "question_type": "解答题", + "difficulty": 0.85, + "question": "同学们要做 56 朵花,已经做了 40 朵,还要做多少朵。", + "options": [], + "answer": "16朵", + "solution": "【分析】用要做的花的总数量减去已经做了的数量,求出差,就是还要做的数量.\n【详解】 56 - 40 = 16 (朵)答:还要做 16 朵。", + "knowledge_points": [ + "两位数与整十数的减法" + ], + "source": "22-23 一年级下·江西吉安·期末" + }, + { + "id": "493", + "unit": "第六单元100以内的加法和减法5", + "question_type": "解答题", + "difficulty": 0.85, + "question": "老师有85元钱,买铅笔用去了35元,买作业本又用去了40元,老师一共用去了多少元钱。", + "options": [], + "answer": "75元", + "solution": "【分析】买铅笔用去的钱数加买作业本用去的钱数 = 老师一共用去的钱数,据此列式解答即可.\n【详解】 35 + 40 = 75 (元)答:老师一共用去 75 元。", + "knowledge_points": [ + "两位数与整十数的加法" + ], + "source": "22-23一年级下·江西吉安·期末" + }, + { + "id": "494", + "unit": "第六单元100以内的加法和减法5", + "question_type": "解答题", + "difficulty": 0.85, + "question": "思源学校一 (1) 班男生有 32 人,女生比男生少 3 人,女生有多少人。", + "options": [], + "answer": "29人", + "solution": "【分析】男生人数减女生比男生少的人数=女生人数,据此列式解答即可.\n【详解】32-3=29(人)。答:女生有29人。", + "knowledge_points": [ + "一位数与两位数的退位减法" + ], + "source": "22-23 一年级下·江西吉安·期末" + }, + { + "id": "495", + "unit": "第六单元100以内的加法和减法5", + "question_type": "解答题", + "difficulty": 0.65, + "question": "公交车上原有34人,到站后下去7人,又上来5人,公交车上现在有多少人。", + "options": [], + "answer": "32人", + "solution": "【分析】用公交车上原有的人数减去到站后下去的人数,再加又上来的人数,即可求出公交车上现有的人数,据此解答.\n【详解】 34 - 7 + 5= 27 + 5 = 32 (人) 答:公交车上现在有 32 人。", + "knowledge_points": [ + "100以内数的加减混合运算" + ], + "source": "23-24一年级下·河北廊坊·期末" + }, + { + "id": "496", + "unit": "第六单元100以内的加法和减法5", + "question_type": "解答题", + "difficulty": 0.65, + "question": "王雨看一本故事书,从第一页看起。第一天看了25页,第二天看了30页,第三天要从第几页开始看。", + "options": [], + "answer": "56页", + "solution": "【分析】第一天看的页数 + 第二天看的页数 = 看完的页数,第三天要从看完的页数下一页开始看,据此得出结论即可.\n【详解】 25 + 30 + 1 = 55 + 1 = 56 (页) 答:第三天要从第 56 页开始看。", + "knowledge_points": [ + "100以内数的连加运算" + ], + "source": "23-24一年级下·江西上饶·期末" + }, + { + "id": "497", + "unit": "第六单元100以内的加法和减法5", + "question_type": "解答题", + "difficulty": 0.85, + "question": "学校原有67盒粉笔,分给一班7盒,分给二班6盒,还剩多少盒粉笔。", + "options": [], + "answer": "54盒", + "solution": "【分析】用学校原有粉笔的盒数减去分给一班的盒数,再减去分给二班的盒数,即可计算出还剩多少盒粉笔.\n【详解】 67 - 7 - 6 = 60 - 6 = 54 (盒) 答:还剩 54 盒粉笔。", + "knowledge_points": [ + "100以内数的连减运算" + ], + "source": "23-24一年级下·海南省直辖县级单位·期末" + }, + { + "id": "498", + "unit": "第六单元100以内的加法和减法5", + "question_type": "解答题", + "difficulty": 0.85, + "question": "袋子里原来有32块饼干,小东吃了7块后,还剩多少块。", + "options": [], + "answer": "25块", + "solution": "【分析】用原来有饼干的数量减去小东吃的数量,即可求出还剩多少块.\n【详解】 32 - 7 = 25 (块)答:还剩 25 块。", + "knowledge_points": [ + "一位数与两位数的退位减法" + ], + "source": "23-24一年级下·海南省直辖县级单位·期末" + }, + { + "id": "499", + "unit": "第六单元100以内的加法和减法5", + "question_type": "解答题", + "difficulty": 0.85, + "question": "一(1)班有38人。如果每人分 1 个苹果,还差 9 个苹果。一共有多少个苹果。", + "options": [], + "answer": "29个", + "solution": "【分析】一共 38 人,也就是需要 38 个苹果,根据减法的意义,需要的苹果数量 - 还差的数量 = 已经有的数量.\n【详解】 38 - 9 = 29 (个)答:一共有 29 个苹果。", + "knowledge_points": [ + "一位数与两位数的退位减法" + ], + "source": "23-24一年级下·湖北黄冈·期末" + }, + { + "id": "500", + "unit": "第六单元100以内的加法和减法5", + "question_type": "解答题", + "difficulty": 0.65, + "question": "小刚原来有35颗糖果,送给小丽10颗后,两人的糖果同样多。小丽原来比小刚少多少颗糖果。", + "options": [], + "answer": "20颗", + "solution": "【分析】小刚送给小丽 10 颗后,两人的糖果同样多,说明小刚原来比小丽多 10 + 10 = 20 (颗), 与小刚原有多少颗糖果没有关系,这是一个多余条件.\n【详解】 10 + 10 = 20 (颗)答:小丽原来比小刚少 20 颗糖果。", + "knowledge_points": [ + "整十数之间的加减法" + ], + "source": "23-24二年级上·全国·课后作业" + } +] \ No newline at end of file diff --git "a/\344\270\200\345\271\264\347\272\247\351\242\230\351\233\206/\344\270\200\345\271\264\347\272\247\344\270\213/\344\270\200\345\271\264\347\272\247\344\270\213\347\254\254\345\233\233\345\215\225\345\205\203100\344\273\245\345\206\205\346\225\260\347\232\204\350\256\244\350\257\206.json" "b/\344\270\200\345\271\264\347\272\247\351\242\230\351\233\206/\344\270\200\345\271\264\347\272\247\344\270\213/\344\270\200\345\271\264\347\272\247\344\270\213\347\254\254\345\233\233\345\215\225\345\205\203100\344\273\245\345\206\205\346\225\260\347\232\204\350\256\244\350\257\206.json" new file mode 100644 index 0000000000000000000000000000000000000000..d6a118ae11612ad98ec18fb6081d7f2d0b21265f --- /dev/null +++ "b/\344\270\200\345\271\264\347\272\247\351\242\230\351\233\206/\344\270\200\345\271\264\347\272\247\344\270\213/\344\270\200\345\271\264\347\272\247\344\270\213\347\254\254\345\233\233\345\215\225\345\205\203100\344\273\245\345\206\205\346\225\260\347\232\204\350\256\244\350\257\206.json" @@ -0,0 +1,8560 @@ +[ + { + "id": "1", + "unit": "第四单元100以内数的认识1", + "question_type": "选择题", + "difficulty": 0.65, + "question": "\"六一\"儿童节,到游乐园玩的人非常多,兵兵在排队购票,排在他前面的有69人,兵兵排在第()位。", + "options": [ + "A. 69", + "B. 70", + "C. 71" + ], + "answer": "B", + "solution": "【分析】根据题意可知,兵兵前面有 69 人,所以乒乓就排在 69 的后面。所以用 69 + 1 即可解答.\n【详解】 69 + 1 = 70 (位)所以兵兵排在第 70 位;故答案为: B", + "knowledge_points": [ + "100以内数的排序" + ], + "source": "24-25一年级下·广东东莞·期末" + }, + { + "id": "2", + "unit": "第四单元100以内数的认识1", + "question_type": "选择题", + "difficulty": 0.85, + "question": "盒子里有 28 个红球,蓝球比红球多得多,蓝球可能有()个。", + "options": [ + "A. 20", + "B. 32", + "C. 67" + ], + "answer": "C", + "solution": "【分析】描述数的大小关系的方法:通过比较具体数,用\"多一些\"\"少一些\"描述相差较小的两个数;用\"多得多\"\"少得多\"描述相差较大的两个数。据此找出比28多得多的数,即可解决.\n【详解】A。20个比28个少一些,不符合题意;B. 32 个比 28 个多一些,不符合题意;C. 67 个比 28 个多得多,符合题意;即,盒子里有 28 个红球,蓝球比红球多得多,蓝球可能有 67 个。故答案为: C", + "knowledge_points": [ + "数的相对大小关系" + ], + "source": "23-24 二年级上·浙江绍兴·期末" + }, + { + "id": "3", + "unit": "第四单元100以内数的认识1", + "question_type": "选择题", + "difficulty": 0.65, + "question": "有一个两位数,十位上的数字比个位上的数字大,且两个数位上的数字之和是最大的一位数,这个数可能是 ( )。", + "options": [ + "A. 73", + "B. 45", + "C. 63" + ], + "answer": "C", + "solution": "【分析】一个两位数,从右往左数,第一位是个位,第二位是十位.\n10 以内数大小关系为: 0 \u003c 1 \u003c 2 \u003c 3 \u003c 4 \u003c 5 \u003c 6 \u003c 7 \u003c 8 \u003c 9\u003c 10。将两个数字相加和应该是 9\n【详解】A。 7 \u003e 3,但是 7 + 3 = 10,不符合;B. 4 + 5 = 9,但是 4 \u003c 5,不符合;C. 6 \u003e 3, 6 + 3 = 9,符合。这个数可能是 63。故答案为: C", + "knowledge_points": [ + "10以内数的比大小", + "100以内数的组成", + "8,9的加减法" + ], + "source": "24-25 二年级上·福建莆田·期中" + }, + { + "id": "4", + "unit": "第四单元100以内数的认识1", + "question_type": "选择题", + "difficulty": 0.85, + "question": "十位是 4 的两位数有()个。", + "options": [ + "A. 9", + "B. 10", + "C. 11" + ], + "answer": "B", + "solution": "【分析】一个两位数,从右往左数,第一位是个位,第二位是十位。把十位是 4 的两位数一一例举出来,然后数一数,即可解决.\n【详解】由题意分析得:十位是 4 的两位数有:40,41,42,43,44,45,46,47,48,49,一共10个。故答案为: B", + "knowledge_points": [ + "100 以内数的组成" + ], + "source": "23-24 一年级下·江西吉安·期末" + }, + { + "id": "5", + "unit": "第四单元100以内数的认识1", + "question_type": "选择题", + "difficulty": 0.85, + "question": "83 前面的第四个数是( )。", + "options": [ + "A. 80", + "B. 79", + "C. 78" + ], + "answer": "B", + "solution": "【分析】从 83 开始,一个一个的往前数,即可找出 83 前面的第四个数是几.\n【详解】由题意分析得:83, 82, 81, 80, 79, 78。 即, 83 前面的第四个数是 79 。故答案为: B", + "knowledge_points": [ + "数 100 以内的数", + "100 以内数的排序" + ], + "source": "23-24 一年级下·江西吉安·期末" + }, + { + "id": "6", + "unit": "第四单元100以内数的认识1", + "question_type": "选择题", + "difficulty": 0.85, + "question": "23 比 90 ( )。", + "options": [ + "A. 多一些", + "B. 少一些", + "C. 少得多" + ], + "answer": "C", + "solution": "【分析】描述数的大小关系的方法:通过比较具体数,用\"多一些\"\"少一些\"描述相差较小的两个数;用\"多得多\"\"少得多\"描述相差较大的两个数。据此解决.\n【详解】由题意分析得:23 与 90 相差较大,且 23 比 90 小,故, 23 比 90 少得多。故答案为: C", + "knowledge_points": [ + "数的相对大小关系" + ], + "source": "23-24一年级下·江西吉安·期末" + }, + { + "id": "7", + "unit": "第四单元100以内数的认识1", + "question_type": "选择题", + "difficulty": 0.65, + "question": "在一次AI即人工智能比赛中,梦之队获得了92分,扬帆队获得了85分,扬帆队得分比梦之队()。", + "options": [ + "A. 少一些", + "B. 少得多", + "C. 多一些" + ], + "answer": "A", + "solution": "【分析】比较两个数的多少时,如果两个数的大小比较接近,就说大数比小数多一些,或小数比大数少一些;如果两个数的大小相差很多,就说大数比小数多得多,或小数比大数少得多.\n【详解】85 比 92 少一些,所以扬帆队得分比梦之队少一些。故答案为: A", + "knowledge_points": [ + "数的相对大小关系" + ], + "source": "23-24一年级下·福建漳州·期末" + }, + { + "id": "8", + "unit": "第四单元100以内数的认识1", + "question_type": "选择题", + "difficulty": 0.85, + "question": "根据百数表的排列规律,下图中☆代表的数是 ( )。![](images/f787ca9fe40d8d4046b6dd6875416d28ee2020b4dbacc7e661b92a76f3d181ef.jpg)", + "options": [ + "A. 44", + "B. 64", + "C. 66" + ], + "answer": "B", + "solution": "【分析】在百数表上,相邻的两个数,下面的这个数比上面的这个数大 10,左边这个数比右边这个数小 1;据此解决.\n【详解】 55 + 10 = 65;65 - 1 = 64 即,根据百数表的排列规律,下图中☆代表的数(64)。![](images/66df726f76a2018cd1ca5c58e871a00e05c5e25bbb1b6d5c8bb0c59c85112952.jpg)故答案为: B", + "knowledge_points": [ + "百数表" + ], + "source": "23-24 一年级下·贵州铜仁·期末" + }, + { + "id": "9", + "unit": "第四单元100以内数的认识1", + "question_type": "选择题", + "difficulty": 0.85, + "question": "70 前面的第 3 个数是 ( )。", + "options": [ + "A. 73", + "B. 68", + "C. 67" + ], + "answer": "C", + "solution": "【分析】从 70 开始,一个一个地往前数,即可找出 70 前面的第 3 个数是多少;据此解决.\n【详解】由题意分析得: 70, 69, 68, 67, 66, 。 即, 70 前面的第 3 个数是 (67)。故答案为: C", + "knowledge_points": [ + "数 100 以内的数", + "100 以内数的排序" + ], + "source": "23-24 一年级下·贵州铜仁·期末" + }, + { + "id": "10", + "unit": "第四单元100以内数的认识1", + "question_type": "选择题", + "difficulty": 0.85, + "question": "小芳和小明玩拍球。小芳说:\"我拍了50下.\"小明说:\"我拍的比你少一些.\"小明可能拍了多少下。()", + "options": [ + "A. 12", + "B. 47", + "C. 52" + ], + "answer": "B", + "solution": "【分析】描述数的大小关系的方法:通过比较具体数,用\"多一些\"\"少一些\"描述相差较小的两个数;用\"多得多\"\"少得多\"描述相差较大的两个数。据此找出比50少一些的数,即可解决.\n【详解】A。12比50少得多;B. 47 比 50 少一些;C. 52 比 50 多一些;即,小芳和小明玩拍球。小芳说:\"我拍了 50 下.\"小明说:\"我拍的比你少一些.\"小明可能拍了 47 下。故答案为: B", + "knowledge_points": [ + "数的相对大小关系" + ], + "source": "23-24 一年级下·四川乐山·期末" + }, + { + "id": "11", + "unit": "第四单元100以内数的认识1", + "question_type": "选择题", + "difficulty": 0.65, + "question": "- (1) 班有两位老师和 40 个小朋友,每人发一个苹果,买 ( ) 笛比较合适。![](images/6aa29ce70659304b507b446da743e6ec22828e8f014f78b8f9a7a552bfdee4fa.jpg)![](images/092754b4c03eff1c20369907930bfc8ad0537f5de3b5c07f03a35564f13b73af.jpg)![](images/9875bcd95cf4c14bdf68574ce413347766e0a3d492ea6dd00913ed638c3e5d5d.jpg)", + "options": [ + "A. 图1", + "B. 图2", + "C. 图3" + ], + "answer": "C", + "solution": "【分析】根据题意,先用加法计算出老师和小朋友一共有多少人,再和每筐苹果的数量比较大小,选择苹果的数量大于或等于人数的比较合适.\n【详解】 2 + 40 = 42 (人)A。 40 \u003c 42,不符合题意;B. 41 \u003c 42,不符合题意;C. 60 \u003e 42,符合题意;买![](images/5db51ec41aa33d8d3b1d88f3bd2f646f46da428dc45ed96571f89e7c3e766984.jpg)筐比较合适。故答案为: C", + "knowledge_points": [ + "100以内数的比大小", + "整十数加", + "减一位数" + ], + "source": "23-24 一年级下·福建福州·期末" + }, + { + "id": "12", + "unit": "第四单元100以内数的认识1", + "question_type": "选择题", + "difficulty": 0.85, + "question": "下图是从百数表中取出的一部分,其中 ☆ 和 ○ 分别代表的数是 ( )。![](images/6ec4b2610431cfe134b551ed2fb15e82b7bd410fc8d3e73845b6fbc40c813034.jpg)", + "options": [ + "A. 44, 46", + "B. 34, 56", + "C. 36, 54" + ], + "answer": "B", + "solution": "【分析】百数表中,相邻的两个数,左边这个数比右边这个数小 1,右边这个数比左边这个数大 1;上边这个数比下边这个数小 10,下边这个数比上边这个数大 10,由此解答.\n【详解】由分析填写如下:![](images/83e1a497d374127e83dd24a81922590878591c852095140fff00f248fa37a525.jpg)☆和○分别代表的数是34,56。故答案为: B", + "knowledge_points": [ + "百数表" + ], + "source": "23-24 一年级下·河南南阳·期末" + }, + { + "id": "13", + "unit": "第四单元100以内数的认识1", + "question_type": "选择题", + "difficulty": 0.85, + "question": "在 75,62,28,90,19,48,54这些数中,大于50的有()个。", + "options": [ + "A. 4", + "B. 5", + "C. 6" + ], + "answer": "A", + "solution": "【分析】两位数比较大小时,十位大的数就大;十位相同比较个位,个位大的数就大。由此找出比 50 大的数,数出个数即可.\n【详解】 75 \u003e 50;62 \u003e 50;28 \u003c 50;90 \u003e 50;19 \u003c 50;48\u003c 50;54\u003e50 .\n在 75,62,28,90,19,48,54 这些数中,大于 50 的有 75, 62, 90, 54,共 4 个。故答案为:A", + "knowledge_points": [ + "100以内数的比大小" + ], + "source": "23-24 一年级下·湖北黄石·期末" + }, + { + "id": "14", + "unit": "第四单元100以内数的认识1", + "question_type": "选择题", + "difficulty": 0.85, + "question": "李伯伯写了 40 副对联,张伯伯写的比李伯伯多得多,张伯伯可能写了 ( ) 副对联。", + "options": [ + "A. 24", + "B. 43", + "C. 78" + ], + "answer": "C", + "solution": "【分析】比较两个数的多少时,如果两个数的大小比较接近,就说大数比小数多一些,或小数比大数少一些;如果两个数的大小相差很多,就说大数比小数多得多,或小数比大数少得多。由此找出比40多得多的数即可.\n【详解】A。24比40少得多;B. 43 比 40 多一些;C. 78 比 40 多得多。张伯伯可能写了78副对联。故答案为: C", + "knowledge_points": [ + "数的相对大小关系" + ], + "source": "23-24 一年级下·湖北黄石·期末" + }, + { + "id": "15", + "unit": "第四单元100以内数的认识1", + "question_type": "选择题", + "difficulty": 0.65, + "question": "古人用豆子来计数,如果用 μ 表示 24,那么 μ 表示的数 ()。", + "options": [ + "A. 10", + "B. 37", + "C. 73" + ], + "answer": "B", + "solution": "【分析】用 • • • 表示 24,说明 1 个大豆子表示 10 , 1 个小豆子表示 1 。那么 表示的数是 37.\n【详解】古人用豆子来计数,如果用 μ 表示 24,那么表示的数是 37。故答案为: B", + "knowledge_points": [ + "100 以内数的组成" + ], + "source": "23-24 一年级下·江西鹰潭·期末" + }, + { + "id": "16", + "unit": "第四单元100以内数的认识1", + "question_type": "选择题", + "difficulty": 0.65, + "question": "小明有 56 本故事书,小丽比小明的多得多,小丽有 ( ) 本故事书。", + "options": [ + "A. 59", + "B. 27", + "C. 90" + ], + "answer": "C", + "solution": "【分析】小丽比小明的多得多,选择比56多得多的数即可.\n【详解】A。59比56多一些,排除;B. 27 比 56 少得多,排除;C. 90 比 56 多得多,正确。故答案为: C", + "knowledge_points": [ + "数的相对大小关系" + ], + "source": "23-24 一年级下·江西鹰潭·期末" + }, + { + "id": "17", + "unit": "第四单元100以内数的认识1", + "question_type": "选择题", + "difficulty": 0.85, + "question": " 2 □ \u003c 25 , □ 中可以填的数字是 ( )。", + "options": [ + "A. 4", + "B. 5", + "C. 6" + ], + "answer": "A", + "solution": "【分析】题中数字都是两位数,比较大小时,十位大的数就大;十位相同比较个位,个位大的数就大。两数十位相同,整体左边的数小于右边的数,则左边个位上的数一定小于右边个位上的数,由此解答.\n【详解】由分析可知,□中的数字要比5小。A。 4 \u003c 5,符合题意;B. 5 = 5,不符合题意;C. 6 \u003e 5,不符合题意。2 □ \u003c 25, □ 中可以填的数字是 4 。故答案为: A", + "knowledge_points": [ + "100 以内数的比大小" + ], + "source": "23-24 一年级下·江西鹰潭·期末" + }, + { + "id": "18", + "unit": "第四单元100以内数的认识1", + "question_type": "选择题", + "difficulty": 0.65, + "question": "十位上的数字比个位上的数字大 \"1\" 的两位数一共有 ( ) 个。", + "options": [ + "A. 10", + "B. 9", + "C. 8" + ], + "answer": "B", + "solution": "【分析】一个两位数,从右往左数,第一位是个位,第二位是十位;据此列举出十位上的数字比个位上的数字大\"1\"的两位数,即可解决.\n【详解】十位上的数字比个位上的数字大 \"1\" 的两位数有: 10, 21, 32, 43, 54, 65, 76, 87, 98;一共有 9 个。故答案为: B", + "knowledge_points": [ + "100以内数的组成" + ], + "source": "23-24 一年级下·福建莆田·期末" + }, + { + "id": "19", + "unit": "第四单元100以内数的认识1", + "question_type": "选择题", + "difficulty": 0.65, + "question": "跳绳被称为\"最完美的长高运动\"。一年级男生 1 分钟跳绳标准: 99 下及以上就可以评为优秀,小东的成绩比 99 下少一些,小东可能跳 ( ) 下。", + "options": [ + "A. 40", + "B. 100", + "C. 90" + ], + "answer": "C", + "solution": "【分析】小东的成绩比 99 次少一些,找出比 99 少一些的数即可.\n【详解】A。40比99少很多,排除;B. 100 比 99 多一些,排除;C. 90 比 99 少一些,正确。故答案为: C", + "knowledge_points": [ + "100以内数的比大小", + "数的相对大小关系" + ], + "source": "23-24 一年级下·福建莆田·期末" + }, + { + "id": "20", + "unit": "第四单元100以内数的认识1", + "question_type": "选择题", + "difficulty": 0.85, + "question": "下列各数中, ( ) 比 80 大,比 85 小。", + "options": [ + "A. 82", + "B. 63", + "C. 87" + ], + "answer": "A", + "solution": "【分析】两位数比较大小,十位上大的数就大,如果十位上的数相同,个位上大的数就大。据此将各选项中的数分别与 80 和 85 比较大小即可.\n【详解】A。 80 \u003c 82 \u003c 85,符合题意;B. 63 \u003c 80,不符合题意;C. 87 \u003e 85,不符合题意。故答案为: A", + "knowledge_points": [ + "100以内数的比大小" + ], + "source": "23-24 一年级下·湖北黄冈·期末" + }, + { + "id": "21", + "unit": "第四单元100以内数的认识1", + "question_type": "选择题", + "difficulty": 0.85, + "question": "红球有 68 个,蓝球有 20 个,黄球有 18 个, ( ) 比黄球多得多。", + "options": [ + "A. 红球", + "B. 蓝球", + "C. 黄球" + ], + "answer": "A", + "solution": "【分析】比较两个数的多少时,如果两个数的大小比较接近,就说大数比小数多一些,或小数比大数少一些;如果两个数的大小相差很多,就说大数比小数多得多,或小数比大数少得多。据此解答即可.\n【详解】68比18多得多,20比18多一些。所以红球有 68 个,蓝球有 20 个,黄球有 18 个,红球比黄球多得多。故答案为: A", + "knowledge_points": [ + "数的相对大小关系" + ], + "source": "23-24 一年级下·湖北黄冈·期末" + }, + { + "id": "22", + "unit": "第四单元100以内数的认识1", + "question_type": "选择题", + "difficulty": 0.85, + "question": "一个两位数,它个位数字比十位数字多 5,这个数可能是 ( )。", + "options": [ + "A. 94", + "B. 49", + "C. 29" + ], + "answer": "B", + "solution": "【分析】一个两位数从右往左依次是个位,十位,找出个位数字比十位数字多 5 的选项即可.\n【详解】A。94的个位数字是4,十位数字是9,十位数字比个位数字多5,不符合题意;B. 49 的个位数字是 9,十位数字是 4,个位数字比十位数字多 5,符合题意;C. 29 的个位数字是 9,十位数字是 2,个位数字比十位数字多 7,不符合题意。故答案为: B", + "knowledge_points": [ + "100以内数的组成" + ], + "source": "23-24 一年级下·河南三门峡·期末" + }, + { + "id": "23", + "unit": "第四单元100以内数的认识1", + "question_type": "选择题", + "difficulty": 0.85, + "question": "从右起,第三位是 ( ) 位。", + "options": [ + "A. 个", + "B. 十", + "C. 百" + ], + "answer": "C", + "solution": "【分析】一个数右起第一位是个位,右起第二位是十位,右起第三位是百位,据此解答即可.\n【详解】由分析可得,从右起,第三位是百位。故答案为:C", + "knowledge_points": [ + "100以内数的组成" + ], + "source": "23-24 一年级下·河南三门峡·期末" + }, + { + "id": "24", + "unit": "第四单元100以内数的认识1", + "question_type": "选择题", + "difficulty": 0.65, + "question": "果果用☆表示 10,用△表示 1,下面表示的数中最大的是 ( )。", + "options": [ + "A. ☆☆☆△△", + "B. ☆☆☆☆△", + "C. ☆☆△△△" + ], + "answer": "B", + "solution": "【分析】根据题意,用 Δ 表示 10,用 △ 表示 1,据此先看出各个选项的表示的得数,再根据 100 以内数的大小比较方法:先看十位上的数,十位上的数大这个数就大;十位上的数相同再比较个位上的数,个位上的数大这个数就大。据此解答即可.\n【详解】A。 ☆☆☆△△表示3个十和2个一,表示的数是 32;B. ☆☆☆☆△表示 4 个十和 1 个一,表示的数是 41;C. ☆☆△△△表示 2 个十和 3 个一,表示的数是 23;23 \u003c 32 \u003c 41表示的数中最大的是 41 。故答案为: B", + "knowledge_points": [ + "100以内数的比大小", + "100以内数的组成" + ], + "source": "23-24 一年级下·湖北武汉·期末" + }, + { + "id": "25", + "unit": "第四单元100以内数的认识1", + "question_type": "选择题", + "difficulty": 0.85, + "question": "下面的数中,比 98 少得多的数是 ( )。", + "options": [ + "A. 96", + "B. 100", + "C. 48" + ], + "answer": "C", + "solution": "【分析】比较两个数的多少时,如果两个数的大小比较接近,就说大数比小数多一些,或小数比大数少一些;如果两个数的大小相差很多,就说大数比小数多得多,或小数比大数少得多.\n【详解】A。96比98少一些;B. 100 比 98 多一些;C. 48 比 98 少得多。比98少得多的数是48。故答案为: C", + "knowledge_points": [ + "数的相对大小关系" + ], + "source": "23-24 一年级下·广东汕头·期末" + }, + { + "id": "26", + "unit": "第四单元100以内数的认识1", + "question_type": "选择题", + "difficulty": 0.85, + "question": "在 5,15,46,57,85中,个位上是5的数有()个。", + "options": [ + "A. 2", + "B. 3", + "C. 4" + ], + "answer": "B", + "solution": "【分析】一个整数,从右往左依次为个位,十位。由此找出个位是 5 的数,数出个数即可.\n【详解】在 5,15,46,57,85 中,个位上是 5 的数有5,15,85,共3个。故答案为: B", + "knowledge_points": [ + "100以内数的组成" + ], + "source": "23-24 一年级下·安徽淮南·期末" + }, + { + "id": "27", + "unit": "第四单元100以内数的认识1", + "question_type": "选择题", + "difficulty": 0.65, + "question": "1-80 这些数中,个位上是 5 的数有 ( ) 个,十位上是 5 的数有 ( ) 个。", + "options": [ + "A. 6; 10", + "B. 8; 10", + "C. 10; 8", + "D. 20; 8" + ], + "answer": "B", + "solution": "【分析】1-80 这些数中,个位上是 5 的数有5,15,25,35,45,55,65,75,共8个;十位上是5的数有 50,51,52,53,54,55,56,57,58,59,共 10 个,据此解答.\n【详解】1- 80 这些数中,个位上是 5 的数有 8 个,十位上是 5 的数有 10 个。故答案为: B", + "knowledge_points": [ + "100以内数的组成" + ], + "source": "23-24 一年级下·山东济南·期末" + }, + { + "id": "28", + "unit": "第四单元100以内数的认识1", + "question_type": "选择题", + "difficulty": 0.65, + "question": "小欣抓了一把花生,比 60 粒多一些,比 100 粒少的多,可能抓了 ( ) 粒。", + "options": [ + "A. 58 粒", + "B. 64 粒", + "C. 99 粒", + "D. 85 粒" + ], + "answer": "B", + "solution": "【分析】比较两个数的多少时,如果两个数的大小比较接近,就说大数比小数多一些,或小数比大数少一些;如果两个数的大小相差很多,就说大数比小数多得多,或小数比大数少得多。找出比60多一些,比100少得多的数即可.\n【详解】A。58比60少,不符合;B. 64 比 60 多一些,比 100 少得多,符合;C. 99 比 60 多得多,比 100 少一些,不符合;D. 85 比 60 多一些,比 100 少一些,不符合。小欣可能抓了 64 粒。故答案为: B", + "knowledge_points": [ + "数的相对大小关系" + ], + "source": "23-24 一年级下·山东济南·期末" + }, + { + "id": "29", + "unit": "第四单元100以内数的认识1", + "question_type": "选择题", + "difficulty": 0.85, + "question": "下面 ( ) 中的数字 \"8\"表示 8 个一。", + "options": [ + "A. 82", + "B. 89", + "C. 78", + "D. 87" + ], + "answer": "C", + "solution": "【分析】一个两位数,从右往左数,第一位是个位,个位上是几表示几个一;第二位是十位,十位上是几表示几个十.\n【详解】A。82中的数字\"8\"表示8个十;B. 89 中的数字 \"8\" 表示 8 个十;C. 78 中的数字 \"8\" 表示 8 个一;D. 87 中的数字 \"8\" 表示 8 个十。故答案为: C", + "knowledge_points": [ + "100以内数的组成" + ], + "source": "23-24 一年级下·山东济南·期末" + }, + { + "id": "30", + "unit": "第四单元100以内数的认识1", + "question_type": "选择题", + "difficulty": 0.85, + "question": "下面各数中,十位上的数字比个位上的数字大3的数是()。", + "options": [ + "A. 36", + "B. 85", + "C. 58" + ], + "answer": "B", + "solution": "【分析】一个两位数,从右往左依次为个位,十位。十位比个位大 3 的数,用十位一个位 = 3,计算选择即可.\n【详解】A。 6 - 3 = 3,十位比个位小3,不符合题意;B. 8 - 5 = 3,十位比个位大 3,符合题意;C. 8 - 5 = 3,十位比个位小 3,不符合题意。十位上的数字比个位上的数字大 3 的数是 85 。故答案为: B", + "knowledge_points": [ + "100以内数的组成" + ], + "source": "23-24 一年级下·湖南岳阳·期末" + }, + { + "id": "31", + "unit": "第四单元100以内数的认识1", + "question_type": "选择题", + "difficulty": 0.85, + "question": "23 后面的第七个数是()。", + "options": [ + "A. 16", + "B. 31", + "C. 30" + ], + "answer": "C", + "solution": "【分析】根据数的顺序一个一个地往后数,23 后面依次为 24, 25, 26, 27, 28, 29, 30, 31。找出第七个数即可.\n【详解】由分析可知, 23 后面的第七个数是 30 。故答案为: C", + "knowledge_points": [ + "数 100 以内的数", + "100 以内数的排序" + ], + "source": "23-24 一年级下·河南周口·期末" + }, + { + "id": "32", + "unit": "第四单元100以内数的认识1", + "question_type": "选择题", + "difficulty": 0.65, + "question": "在 56,63 和 54 中,最接近 60 的数是 ( )。", + "options": [ + "A. 56", + "B. 63", + "C. 54" + ], + "answer": "B", + "solution": "【分析】数一数每个数和 60 之间有几个数,数越少则越接近.\n【详解】A。56和60之间有57,58,59,共3个;B。63和60之间有61,62,共2个;C. 54 和 60 之间有 55,56,57,58,59,共 5 个。5 \u003e 3 \u003e 2 所以最接近 60 的数是 63。故答案为: B", + "knowledge_points": [ + "100以内数的排序" + ], + "source": "23-24 一年级下·河南周口·期末" + }, + { + "id": "33", + "unit": "第四单元100以内数的认识1", + "question_type": "选择题", + "difficulty": 0.85, + "question": "由 8 个一和 7 个十组成的数是 ( )。", + "options": [ + "A. 15", + "B. 87", + "C. 78" + ], + "answer": "C", + "solution": "【分析】几个十就是几十,几个一就是几。8个一是8,7个十是70,合起来是78.\n【详解】由 8 个一和 7 个十组成的数是 78 。故答案为: C", + "knowledge_points": [ + "100以内数的组成" + ], + "source": "23-24 一年级下·河南周口·期末" + }, + { + "id": "34", + "unit": "第四单元100以内数的认识1", + "question_type": "选择题", + "difficulty": 0.85, + "question": "下面和 80 最接近的数是 ( )。", + "options": [ + "A. 81", + "B. 76", + "C. 75", + "D. 70" + ], + "answer": "A", + "solution": "【分析】根据题意,依次数出各数和 80 之间间隔几个数字,间隔的数字越少就越接近.\n【详解】A。81前边的一个数就是80,没有间隔数字;B. 76 和 80 之间间隔的数有: 77, 78, 79,共 3 个数字;C. 75 和 80 之间间隔的数有: 76, 77, 78, 79,共 4 个数字;D. 70 和 80 之间间隔的数有: 71, 72, 73, 74, 75, 76, 77, 78, 79,共 9 个数字;所以和 80 最接近的数是 81。故答案为: A", + "knowledge_points": [ + "数 100 以内的数" + ], + "source": "23-24 一年级下·福建漳州·期末" + }, + { + "id": "35", + "unit": "第四单元100以内数的认识1", + "question_type": "填空题", + "difficulty": 0.85, + "question": "用 5 个珠子在下图的计数器上表示数,最大的数是( ), 最小的数是( )。![](images/950f6e7d93e952bd3016bd8033e41b660d680c4be7d9a485b9cfc9da92c00313.jpg)", + "options": [ + + ], + "answer": "505", + "solution": "【分析】表示最大的数时要把珠子尽可能的放在最高位十位上,十位上可以放五颗,一颗珠子代表十,个位上不放,为最大数;表示最小的数时,应该把珠子尽可能的放在低位上,把五颗珠子放在个位上,一颗珠子代表一,为最小数,即可解答.\n【详解】![](images/dad48c9be495a745b6beaa73b07385a5876ba34a145f04211a9d449aa7c6a7e0.jpg)如上图,十位上 5 颗珠子,为最大数,是 50。![](images/46ff8d592dd51739fe211a3a7b7c1d5c9cb1a4f6f00a19fa61953ac9c1e75896.jpg)如上图,个位上 5 颗珠子,为最小数,是 5。因此,用 5 个珠子在计数器上表示数,最大的数是 50,最小的数是 5。", + "knowledge_points": [ + "100以内数的组成" + ], + "source": "24-25 一年级下·福建莆田·期末" + }, + { + "id": "36", + "unit": "第四单元100以内数的认识1", + "question_type": "填空题", + "difficulty": 0.94, + "question": "一个两位数,个位上是 8,十位上的数比 8 小 4,这个数是( )。", + "options": [ + + ], + "answer": "48", + "solution": "【分析】先求十位上的数字,已知十位上的数比 8 小 4,那么十位上的数用 8 减 4,等于 4;两位数的个位上是 8,十位上是 4,所以这个数是 48,据此即可解答.\n【详解】根据分析可知,一个两位数,个位上是 8,十位上的数比 8 小 4,这个数是 48 。", + "knowledge_points": [ + "100以内数的组成" + ], + "source": "24-25 一年级下·湖北襄阳·期末" + }, + { + "id": "37", + "unit": "第四单元100以内数的认识1", + "question_type": "填空题", + "difficulty": 0.85, + "question": "一个数的个位上是 5,十位上是 7,这个数是( ), 它里面有( )个十和( )个一。", + "options": [ + + ], + "answer": "7575", + "solution": "【分析】一个两位数,从右往左依次是个位,十位,十位上是几就表示几个十,个位上是几就表示几个一,据此解答即可.\n【详解】一个数的个位上是 5,十位上是 7,这个数是 75,它里面有 7 个十和 5 个一。", + "knowledge_points": [ + "100以内数的组成" + ], + "source": "24-25 二年级下·黑龙江佳木斯·期中" + }, + { + "id": "38", + "unit": "第四单元100以内数的认识1", + "question_type": "填空题", + "difficulty": 0.65, + "question": "用 4,5,6 组成两位数,每个两位数的个位数和十位数不能一样,能组成( )个,其中最大的数是( )。", + "options": [ + + ], + "answer": "665", + "solution": "【分析】每个数字都可以作为十位数字,先确定一个十位数字,个位上有两个数字可以选择,这样写出所有组成的两位数,然后判断最大的数即可。组成的数有 45,46,54,56,64,65,能组成 6 个,将它们作比较即可求出最大的数.\n【详解】 65 \u003e 64 \u003e 56 \u003e 54 \u003e 46 \u003e 45 用 4,5,6 组成两位数,每个两位数的个位数和十位数不能一样,能组成 6 个,其中最大的数是 65。", + "knowledge_points": [ + "100以内数的比大小", + "100以内数的组成" + ], + "source": "22-23 二年级上·河南南阳·期中" + }, + { + "id": "39", + "unit": "第四单元100以内数的认识1", + "question_type": "填空题", + "difficulty": 0.65, + "question": "23 是( )位数,个位上是( ), 十位上是( )。", + "options": [ + + ], + "answer": "两 32", + "solution": "【分析】数位是指写数时,把数字并列排成横列,一个数字占有一个位置,这些位置,都叫做数位。一个两位数,从右向左依次为个位,十位;十位上是几,表示几个十,个位上是几,表示几个一,据此解答.\n【详解】23是两位数,个位上是3,十位上是2。", + "knowledge_points": [ + "100以内数的读,写法", + "100以内数的组成" + ], + "source": "23-24 一年级下·河南漯河·期末" + }, + { + "id": "40", + "unit": "第四单元100以内数的认识1", + "question_type": "填空题", + "difficulty": 0.85, + "question": "2024年6月10日,漳浦县\"梁鹿杯\"龙舟比赛时隔36年后再次在绥安镇启动,36支代表队为我们呈现了一场精彩的龙舟盛宴。36是( )位数,6在( )位,表示( )个( ),36的前面是( ),后面是( )。", + "options": [ + + ], + "answer": "两个 个 63537", + "solution": "【分析】一个整数,从右往左依次为个位,十位,十位是几表示几个十,个位是几表示几个一,有几个数字就是几位数。根据 100 以内数的顺序: 1, 2, 3。34, 35, 36, 37, 38。找出 36 前面和后面的数即可.\n【详解】2024年6月10日,漳浦县\"梁鹿杯\"龙舟比赛时隔36年后再次在绥安镇启动,36支代表队为我们呈现了一场精彩的龙舟盛宴。36是两位数,6在个位,表示6个一,36的前面是35,后面37。", + "knowledge_points": [ + "100以内数的排序", + "100以内数的组成" + ], + "source": "23-24一年级下·福建漳州·期末" + }, + { + "id": "41", + "unit": "第四单元100以内数的认识1", + "question_type": "填空题", + "difficulty": 0.65, + "question": "从 48 数到 53,一共数了( )个数。", + "options": [ + + ], + "answer": "6", + "solution": "【分析】从 48 开始数到 53,要包括开始和结束的数。即 48, 49, 50, 51, 52, 53,共 6 个数,由此解答.\n【详解】由分析可知:从 48 数到 53,一共数了 6 个数。", + "knowledge_points": [ + "数 100 以内的数" + ], + "source": "23-24 一年级下·河南漯河·期末" + }, + { + "id": "42", + "unit": "第四单元100以内数的认识1", + "question_type": "填空题", + "difficulty": 0.85, + "question": "51 前面第三个数是( )。", + "options": [ + + ], + "answer": "48", + "solution": "【分析】按照 100 以内数的排序,一个一个地数, 51 前面的第一个数是 50,第二个数是 49,第三个数是 48,由此解答.\n【详解】由分析可知,51前面第三个数是 48 。", + "knowledge_points": [ + "数 100 以内的数" + ], + "source": "23-24 一年级下·河南漯河·期末" + }, + { + "id": "43", + "unit": "第四单元100以内数的认识1", + "question_type": "填空题", + "difficulty": 0.85, + "question": "如果今天是 7 月 8 日,再过 3 天是( )月( )日。", + "options": [ + + ], + "answer": "711", + "solution": "【分析】根据题意,如果今天是 7 月 8 日,再过 3 天是即从 8 日开始,往后数 3 天,依次是 9 日, 10 日, 11 日,由此解答.\n【详解】由分析可知:如果今天是 7 月 8 日,再过 3 天是 7 月 11 日。", + "knowledge_points": [ + "数 100 以内的数", + "年,月,日时间的推算" + ], + "source": "23-24 一年级下·河南漯河·期末" + }, + { + "id": "44", + "unit": "第四单元100以内数的认识1", + "question_type": "填空题", + "difficulty": 0.85, + "question": "54 读作( ),它的十位上的数字是( ),个位上的数字是( )。与它相邻的数是( )和( )。", + "options": [ + + ], + "answer": "五十四 545355", + "solution": "【分析】一个两位数,从右往左依次为个位,十位。读数时从高位读起,十位是几读作几十,个位是几读作几。它的相邻数也就是它前边的一个数和它后边的一个数,根据数的顺序 1, 2, 3。52, 53, 54, 55, 56。找出对应的数即可.\n【详解】54 读作五十四,它的十位上的数字是 5,个位上的数字是 4。与它相邻的数是 53 和 55。", + "knowledge_points": [ + "100以内数的读,写法", + "100以内数的排序", + "100以内数的组成", + "相邻的数" + ], + "source": "23-24 一年级下·河北保定·期末" + }, + { + "id": "45", + "unit": "第四单元100以内数的认识1", + "question_type": "填空题", + "difficulty": 0.85, + "question": "\"二七纪念塔\"位于郑州市二七广场,塔高63米,共14层。其中63是由( )个十和( )个一组成。", + "options": [ + + ], + "answer": "63", + "solution": "【分析】一个两位数,从右往左依次为个位,十位。十位是几就有几个十,个位是几就有几个一,由此解答.\n【详解】\"二七纪念塔\"位于郑州市二七广场,塔高63米,共14层。其中63是由6个十和3个一组成。", + "knowledge_points": [ + "100以内数的组成" + ], + "source": "23-24 一年级下·河南郑州·期末" + }, + { + "id": "46", + "unit": "第四单元100以内数的认识1", + "question_type": "填空题", + "difficulty": 0.85, + "question": "个位上是 2,十位上是 6,这个数是( ), 和这个数相邻的两个数是( )和( )。", + "options": [ + + ], + "answer": "626163", + "solution": "【分析】在数位顺序表中,个位上的数字是几就代表几个一,十位上的数字是几就代表有几个十。题目中说个位上是 2 就代表 2 个 1,十位上是 6,就代表有 6 个十,合起来就是 62,再写出与它相邻的数即可.\n【详解】 60 + 2 = 62,所以个位上是 2,十位上是 6,这个数是 62,和 62 相邻的两个数是 61 和 63。", + "knowledge_points": [ + "100以内数的排序", + "100以内数的组成", + "相邻的数" + ], + "source": "23-24 一年级下·江西吉安·期末" + }, + { + "id": "47", + "unit": "第四单元100以内数的认识1", + "question_type": "填空题", + "difficulty": 0.85, + "question": "50 后面第 6 个数是( ), 和 80 相邻的两个数是( )和( )。", + "options": [ + + ], + "answer": "567981", + "solution": "【分析】从 50 开始,一个一个地往后数,即可找出 50 后面第 6 个数是几;从 75 到 85,一个一个地数一数,即可知道与 80 相邻的数有哪些.\n【详解】50,51,52,53,54,55,56,57。75,76,77,78,79,80,81,82,83,84,85。所以 50 后面第 6 个数是 56,和 80 相邻的两个数是 79 和 81。", + "knowledge_points": [ + "数 100 以内的数", + "相邻的数" + ], + "source": "23-24 一年级下·河南濮阳·期末" + }, + { + "id": "48", + "unit": "第四单元100以内数的认识1", + "question_type": "填空题", + "difficulty": 0.85, + "question": "一个两位数,个位上的数字是 7,十位上的数字比个位上的数字小 4,这个两位数是( )。", + "options": [ + + ], + "answer": "37", + "solution": "【分析】一个两位数,从右往左数,第一位是个位,第二位是十位。已知个位上的数字是多少,用减法即可求出十位上的数字是多少,据此解答即可.\n【详解】 7 - 4 = 3 所以这个两位数是 37 。", + "knowledge_points": [ + "100以内数的组成" + ], + "source": "23-24 一年级下·河南濮阳·期末" + }, + { + "id": "49", + "unit": "第四单元100以内数的认识1", + "question_type": "填空题", + "difficulty": 0.85, + "question": "3 个十和 8 个一合起来是( ),56 里面有( )个十和( )个( )。", + "options": [ + + ], + "answer": "3856", + "solution": "【分析】一个两位数,从右往左数,第一位是个位,个位上的数表示几个一;第二位是十位,十位上的数表示几个十。据此解答即可.\n【详解】3个十和8个一合起来是38,56里面有5个十和6个一。", + "knowledge_points": [ + "100以内数的组成" + ], + "source": "23-24 一年级下·河南濮阳·期末" + }, + { + "id": "50", + "unit": "第四单元100以内数的认识1", + "question_type": "填空题", + "difficulty": 0.65, + "question": "如果用 □ □ ○ 表示 21,那么 □ ○ ○ 可以表示( )。", + "options": [ + + ], + "answer": "12", + "solution": "【分析】根据题意可知,一个 □ 表示一个十,一个 ○ 表示一个一,所以 □ ○ ○ 表示 1 个十和 2 个一,即 12.\n【详解】如果用□□○表示21,那么□○○可以表示12。", + "knowledge_points": [ + "100以内数的组成" + ], + "source": "23-24 一年级下·福建漳州·期末" + }, + { + "id": "51", + "unit": "第四单元100以内数的认识1", + "question_type": "填空题", + "difficulty": 0.85, + "question": "由( )个十和( )个一组成的数是 54。", + "options": [ + + ], + "answer": "54", + "solution": "【分析】一个两位数,从右往左依次为个位,十位。十位是几就有几个十,个位是几就有几个一,由此解答.\n【详解】由分析可知:由5个十和4个一组成的数是 54", + "knowledge_points": [ + "100以内数的组成" + ], + "source": "23-24 一年级下·福建福州·期末" + }, + { + "id": "52", + "unit": "第四单元100以内数的认识1", + "question_type": "填空题", + "difficulty": 0.85, + "question": "83 和 78 这两个数, ( ) 更接近 80。", + "options": [ + + ], + "answer": "78", + "solution": "【分析】相邻的两个数相差 1,前一个数比后一个数少 1,后一个数比前一个数多 1;78 是 80 前面第二个数, 83 是 80后面第三个数,根据两个数的差越小,表示这两个数越接近。所以 78 最接近 80,由此解答.\n【详解】83和78这两个数,78更接近 80 。", + "knowledge_points": [ + "数 100 以内的数", + "100 以内数的估计" + ], + "source": "23-24一年级下·浙江嘉兴·期末" + }, + { + "id": "53", + "unit": "第四单元100以内数的认识1", + "question_type": "填空题", + "difficulty": 0.65, + "question": "一个两位数,十位上的数是 5,个位上的数字比十位上的数字小 3,这个数是( )。", + "options": [ + + ], + "answer": "52", + "solution": "【分析】一个两位数,从右往左依次为个位,十位。十位是5,个位比十位小3,个位为5-3,由此计算写数即可.\n【详解】 5 - 3 = 2一个两位数,十位上的数是 5,个位上的数字比十位上的数字小 3,这个数是 52 。", + "knowledge_points": [ + "100以内数的读,写法", + "100以内数的组成" + ], + "source": "23-24一年级下·浙江嘉兴·期末" + }, + { + "id": "54", + "unit": "第四单元100以内数的认识1", + "question_type": "填空题", + "difficulty": 0.85, + "question": "70 里面有( )个十,与它相邻的两个数是( )和( )。", + "options": [ + + ], + "answer": "76971", + "solution": "【分析】几十里面就有几个十。与 70 相邻的数也就是它前边的一个数和它后边的一个数。根据数的顺序 1, 2, 3。68, 69, 70, 71, 。找到符合题意的数.\n【详解】70里面有7个十,与它相邻的两个数是69和71。", + "knowledge_points": [ + "100以内数的排序", + "100以内数的组成", + "相邻的数" + ], + "source": "23-24 一年级下·浙江嘉兴·期末" + }, + { + "id": "55", + "unit": "第四单元100以内数的认识1", + "question_type": "填空题", + "difficulty": 0.85, + "question": "由 3 个一和 6 个十组成的数是( ),在 99 这个数中,右边的 9 表示 9 个( )。", + "options": [ + + ], + "answer": "63 一", + "solution": "【分析】一个两位数,从右往左数,第一位是个位,个位上的数表示几个一;第二位是十位,十位上的数表示几个十。据此解答即可.\n【详解】由分析可得,由 3 个一和 6 个十组成的数是 63,在 99 这个数中,右边的 9 表示 9 个一。", + "knowledge_points": [ + "100以内数的组成" + ], + "source": "23-24 一年级下·山西晋中·期末" + }, + { + "id": "56", + "unit": "第四单元100以内数的认识1", + "question_type": "填空题", + "difficulty": 0.85, + "question": "64 的十位是( ),表示( )个( );个位是( ),表示( )个( )。", + "options": [ + + ], + "answer": "66 十 44 一", + "solution": "【分析】一个两位数,从右往左依次为个位,十位。十位是几就有几个十,个位是几就有几个一,由此解答.\n【详解】64 的十位是 6,表示 6 个十;个位是 4,表示 4 个一。", + "knowledge_points": [ + "100以内数的组成" + ], + "source": "23-24 一年级下·湖北黄石·期末" + }, + { + "id": "57", + "unit": "第四单元100以内数的认识1", + "question_type": "填空题", + "difficulty": 0.65, + "question": "个位上是 7,十位上是 4,这个数是( ), 再添上 1 个十是( )。", + "options": [ + + ], + "answer": "4757", + "solution": "【分析】从右起第一位是个位,第二位是十位.\n【详解】个位上是 7,十位上是 4,这个数是 47, 47 + 10 = 57,再添上 1 个十是 57。", + "knowledge_points": [ + "100以内数的组成" + ], + "source": "23-24 一年级下·江西鹰潭·期末" + }, + { + "id": "58", + "unit": "第四单元100以内数的认识1", + "question_type": "填空题", + "difficulty": 0.65, + "question": "用 6 个 ○ 能摆出( )个不同的两位数,其中最大的是( ), 最小的是( )。", + "options": [ + + ], + "answer": "66015", + "solution": "【分析】把6个 ○ 摆在十位上,摆出的两位数是60;把 5 个 ○ 摆在十位上, 1 个 ○ 摆在个位上,摆出的两位数是 51;把 4 个 ○ 摆在十位上, 2 个 ○ 摆在个位上,摆出的两位数是 42;把 3 个 ○ 摆在十位上, 3 个 ○ 摆在个位上,摆出的两位数是 33;把2个 ○ 摆在十位上,4个 ○ 摆在个位上,摆出的两位数是 24;把 1 个 ○ 摆在十位上, 5 个 ○ 摆在个位上,摆出的两位数是 15;一共摆出 6 个不同的两位数。然后比较大小,找出最大的数和最小的数,即可解决.\n【详解】用6个 ○ 摆出不同的两位数有:60, 51, 42, 33, 24, 15;60 \u003e 51 \u003e 42 \u003e 33 \u003e 24 \u003e 15\n即,用 6 个 ○ 能摆出 6 个不同的两位数,其中最大的是60,最小的是 15。", + "knowledge_points": [ + "100以内数的比大小", + "100以内数的组成" + ], + "source": "23-24 一年级下·贵州铜仁·期末" + }, + { + "id": "59", + "unit": "第四单元100以内数的认识1", + "question_type": "填空题", + "difficulty": 0.85, + "question": "一个数由 8 个一和 9 个十组成,这个数是( ), 它再添上( )个一,就是最小的三位数。", + "options": [ + + ], + "answer": "982", + "solution": "【分析】8 个一是 8, 9 个十是 90,组成的数是 98。最小的三位数是 100;98,99,100,即 98 往后再数 2 就是 100,也就是 98 再添上 2 个一,就是最小的三位数.\n【详解】由题意分析得:一个数由 8 个一和 9 个十组成,这个数是 98,它再添上 2 个一,就是最小的三位数。", + "knowledge_points": [ + "数 100 以内的数", + "100 以内数的组成" + ], + "source": "23-24 一年级下·贵州铜仁·期末" + }, + { + "id": "60", + "unit": "第四单元100以内数的认识1", + "question_type": "填空题", + "difficulty": 0.65, + "question": "- (1) 班的学生人数在 30 ~ 40 之间,十位上的数字与个位上的数字的和是 9 , - (1) 班共有学生( )人。", + "options": [ + + ], + "answer": "36", + "solution": "【分析】根据题意分析,一(1)班的学生人数在 30~ 40 之间,所以学生人数的十位上的数字是3,用9减去十位上的数字即可得到个位上的数字,据此解答即可.\n【详解】 9 - 3 = 6\n所以这个数十位上数字是 3,个位上数字是 6,这个数是 36,所以一 (1) 班共有学生 36 人。", + "knowledge_points": [ + "100以内数的组成" + ], + "source": "23-24 一年级下·福建福州·期末" + }, + { + "id": "61", + "unit": "第四单元100以内数的认识1", + "question_type": "填空题", + "difficulty": 0.65, + "question": "一个两位数,个位上是 8,十位上是 4,这个两位数是( ), 与它最接近的整十数是( )。", + "options": [ + + ], + "answer": "4850", + "solution": "【分析】一个两位数,从右往左数,第一位是个位,第二位是十位,所以个位上是 8,十位上是 4 的两位数是 48;从 40 开始数数数到 50,与哪个整十数最接近则之间的数最少,据此解答.\n【详解】40,41,42,43,44,45,46,47,48,49,50。 所以一个两位数,个位上是 8,十位上是 4,这个两位数是 48,与它最接近的整十数是 50 。", + "knowledge_points": [ + "100以内数的排序", + "100以内数的组成" + ], + "source": "23-24 一年级下·湖北黄石·期末" + }, + { + "id": "62", + "unit": "第四单元100以内数的认识1", + "question_type": "填空题", + "difficulty": 0.65, + "question": "49 里有( )个十和( )个一,和它相邻的两个数是( )和( )。", + "options": [ + + ], + "answer": "494850", + "solution": "【分析】从右起第一位是个位,第二位是十位,个位是几表示有几个一,十位是几表示有几个十。求相邻的数用 49 分别加 1 和减 1 即可.\n【详解】 49 + 1 = 50, 49 - 1 = 48;49 里有 4 个十和 9 个一,和它相邻的两个数是 50 和 48。", + "knowledge_points": [ + "100 以内数的排序", + "100 以内数的组成", + "相邻的数" + ], + "source": "23-24 一年级下·江西鹰潭·期末" + }, + { + "id": "63", + "unit": "第四单元100以内数的认识1", + "question_type": "填空题", + "difficulty": 0.65, + "question": "有 38 个羽毛球,每10 个装一筒,可以装满( )筒;如果每 5 个装一筒,可以装满( )筒。", + "options": [ + + ], + "answer": "37", + "solution": "【分析】38 里有 3 个十和 8 个一,每 10 个装一筒,可以装满 3 筒;如果每 5 个装一筒, 5 + 5 + 5 + 5 + 5 + 5 + 5 = 35,可以装满 7 筒,还剩 3 个.\n【详解】有 38 个羽毛球,每 10 个装一筒,可以装满 3 筒;如果每 5 个装一筒,可以装满 7 筒。", + "knowledge_points": [ + "100以内数的组成" + ], + "source": "23-24 一年级下·福建莆田·期末" + }, + { + "id": "64", + "unit": "第四单元100以内数的认识1", + "question_type": "填空题", + "difficulty": 0.65, + "question": "一个两位数的个位和十位上的数字合起来是 13,这个两位数最大是( ), 最小是( )。", + "options": [ + + ], + "answer": "9449", + "solution": "【分析】两位数比较大小,十位上大的数就大,如果十位上的数相同,个位上大的数就大。这个两位数最大十位上要是 9,则个位上是 13 减 9 的得数;这个两位数十位上不能是 0,也不能是 1,因为如果是 1,个位上就是 13 - 1 = 12,而个位上最大是 9,所以十位上最小是 13 - 9 = 4 。据此解答即可.\n【详解】十位上的数是 9,个位上的数是: 13 - 9 = 4 。所以这个两位数最大是 94;十位上的数是: 13 - 9 = 4,个位上的数是 9 。所以这个两位数最小是 49 。", + "knowledge_points": [ + "100以内数的比大小", + "100以内数的组成" + ], + "source": "23-24 一年级下·湖北孝感·期末" + }, + { + "id": "65", + "unit": "第四单元100以内数的认识1", + "question_type": "填空题", + "difficulty": 0.85, + "question": "9 个一和 2 个十合起来是( ),与它相邻的两个数分别是( )和()。", + "options": [ + + ], + "answer": "293028", + "solution": "【分析】数 100 以内的数,100 以内数的组成,相邻的数 【分析】一个两位数,从右往左数,第一位是个位,个位上的数表示几个一;第二位是十位,十位上的数表示几个十,所以 9 个一和 2 个十合起来是 29;从 20 到 30,一个一个地数一数,即可知道与 29 相邻的数有哪些.\n【详解】20,21,22,23,24,25,26,27,28,29,30。所以 9 个一和 2 个十合起来是 29,与它相邻的两个数分别是 30 和 28。", + "knowledge_points": [ + "数 100 以内的数", + "100 以内数的组成", + "相邻的数" + ], + "source": "23-24 一年级下·湖北孝感·期末" + }, + { + "id": "66", + "unit": "第四单元100以内数的认识1", + "question_type": "填空题", + "difficulty": 0.85, + "question": "一个一个地数, 78后面第三个数是( )。", + "options": [ + + ], + "answer": "81", + "solution": "【分析】根据 100 以内整数的排序,按照顺序数一数,即可得出 78 后面的第三个数是多少.\n【详解】78,79,80,81,所以一个一个地数,78后面第三个数是81。", + "knowledge_points": [ + "100以内数的排序" + ], + "source": "23-24 一年级下·湖北武汉·期末" + }, + { + "id": "67", + "unit": "第四单元100以内数的认识1", + "question_type": "填空题", + "difficulty": 0.85, + "question": "2021 年是中国共产党建党 100 周年。横线上的数读作: ( );我们的祖国有五十六个民族。横线上的数写作: ( )。", + "options": [ + + ], + "answer": "一百 56", + "solution": "【分析】一个三位数,从右往左依次为个位,十位,百位,读数时从高位读起,百位是几读作几百,十位是几读作几十,个位是几读作几,末尾不管有几个0都不读;写数时从高位写起,几十就在十位写几,几就在个位写几.\n【详解】2021年是中国共产党建党100周年。横线上的数\n读作:一百;我们的祖国有五十六个民族。横线上的数写作:56。", + "knowledge_points": [ + "100以内数的读,写法" + ], + "source": "23-24 一年级下·湖北恩施·期末" + }, + { + "id": "68", + "unit": "第四单元100以内数的认识1", + "question_type": "填空题", + "difficulty": 0.85, + "question": "一个两位数,个位上的数是 3,十位上的数比个位上的数大 2,这个数是( );一个两位数,个位和十位上的数相同,这个两位数可能是( )。", + "options": [ + + ], + "answer": "5311,22,33,44,55,66,77,88,99", + "solution": "【分析】一个两位数,从右往左数,第一位是个位,第二位是十位;个位上的数是 3,十位上的数比个位上的数大 2, 3 + 2 = 5,即,十位上是 5,组成的两位数是 53;一个两位数,个位和十位上的数相同,这个两位数可能是 11,22,33,44,55,66,77,88,99;据此解答即可.\n【详解】由分析可得,一个两位数,个位上的数是 3,十位上的数比个位上的数大 2,这个数是 53;一个两位数,个位和十位上的数相同,这个两位数可能是", + "knowledge_points": [ + "100以内数的组成" + ], + "source": "23-24 一年级下·湖北黄冈·期末" + }, + { + "id": "69", + "unit": "第四单元100以内数的认识1", + "question_type": "填空题", + "difficulty": 0.85, + "question": "在 78,69,63 中,最接近 70 的是( ),最接近 80 的是 ( )。", + "options": [ + + ], + "answer": "6978", + "solution": "【分析】从 63 开始数数数到 80,与哪个数最接近则它们之间的数最少,据此解答.\n【详解】63,64,65,66,67,68,69,70,71,72,73,74,75,76,77,78,79,80.\n所以在78,69,63中,最接近70的是69,最接近80的是78", + "knowledge_points": [ + "数 100 以内的数" + ], + "source": "23-24 一年级下·湖北黄冈·期末" + }, + { + "id": "70", + "unit": "第四单元100以内数的认识1", + "question_type": "填空题", + "difficulty": 0.85, + "question": "36 里面 \"6\"在--位上,十位上的 3 表示 3 个--。", + "options": [ + + ], + "answer": "个位 十", + "solution": "【分析】一个两位数从右往左依次是个位,十位,个位上的数字是几就表示几个一,十位上的数字是几就表示几个十.\n【详解】由分析可知: 36 里面 \"6\"在个位上,十位上的 3 表示 3 个十。", + "knowledge_points": [ + "100以内数的组成" + ], + "source": "23-24 一年级下·湖北黄冈·期末" + }, + { + "id": "71", + "unit": "第四单元100以内数的认识1", + "question_type": "填空题", + "difficulty": 0.85, + "question": "43 前面的第 3 个数是( ),68 后面的第 4 个数是( )。", + "options": [ + + ], + "answer": "4072", + "solution": "【分析】从 43 开始,一个一个的往前数,即可找出 43 前面的第 3 个数是几;从 68 开始,一个一个的往后数,即可找出 68 后面的第 4 个数是几;据此解答即可.\n【详解】43,42,41,40,39。68,69,70,71,72。所以 43 前面的第 3 个数是 40, 68 后面的第 4 个数是 72。", + "knowledge_points": [ + "数100以内的数" + ], + "source": "23-24 一年级下·河南三门峡·期末" + }, + { + "id": "72", + "unit": "第四单元100以内数的认识1", + "question_type": "填空题", + "difficulty": 0.65, + "question": "89 是一个( )位数,再添上1是( )个十,是( )。", + "options": [ + + ], + "answer": "两 990", + "solution": "【分析】一个数由几个数字组成就是几位数;89 再添上 1,也就是再往后数一个数,是 90,一个两位数,从右起第一位是个位,第二位是十位,十位上是几就是有几个十,由此解答.\n【详解】89 是一个两位数,再添上 1 是 9 个十,是 90。", + "knowledge_points": [ + "数 100 以内的数", + "100 以内数的组成" + ], + "source": "23-24 一年级下·河南三门峡·期末" + }, + { + "id": "73", + "unit": "第四单元100以内数的认识1", + "question_type": "填空题", + "difficulty": 0.65, + "question": "100 里面有( )个一,有( )个十;与69相邻的两个数是( )和( )。", + "options": [ + + ], + "answer": "100106870", + "solution": "【分析】根据整数的组成可知,一百里面有 100 个一, 10 个十;从 60 到 70,一个一个地数一数,即可知道与 69 相邻的数有哪些.\n【详解】60,61,62,63,64,65,66,67,68,69,70。所以 100 里面有 100 个一,有 10 个十;与 69 相邻的两个数是 68 和 70。", + "knowledge_points": [ + "数 100 以内的数", + "100 以内数的组成", + "相邻的数" + ], + "source": "23-24 一年级下·河南三门峡·期末" + }, + { + "id": "74", + "unit": "第四单元100以内数的认识1", + "question_type": "填空题", + "difficulty": 0.85, + "question": "100 里面有-个十;5 个十和 6 个一合起来是-。", + "options": [ + + ], + "answer": "1056", + "solution": "【分析】几个十就是几十,几个一就是几,10个十是 100 。整数的写法:从高位到低位,一级一级地写,哪一个数位上一个单位也没有,就在那个数位上写 0.\n【详解】100里面有10个十;5个十和6个一合起来是 56", + "knowledge_points": [ + "100以内数的读,写法", + "100以内数的组成" + ], + "source": "23-24 一年级下·山东济南·期末" + }, + { + "id": "75", + "unit": "第四单元100以内数的认识1", + "question_type": "填空题", + "difficulty": 0.65, + "question": "74 再添上( )个一就是 100 了。", + "options": [ + + ], + "answer": "26", + "solution": "【分析】一个整数,从右往左依次为个位,十位,百位。百位是几就有几个百,十位是几就有几个十,个位是几就有几个一;几百里面有几十个十;一个数是几就有几个一。74里面有7个十和4个一;100里面有10个十;4个一和6个一合起来是 1 个十, 7 个十和 2 个十合起来是 9 个十, 1个十和 9 个十合起来是 10 个十,也就是一共加上了 2 个十和6个一,由此解答.\n【详解】2个十是20,6个一是6,合起来是26,26里面有26个一。由分析可知,74 再添上 26 个一就是 100 了。", + "knowledge_points": [ + "100以内数的组成" + ], + "source": "23-24 一年级下·河南周口·期末" + }, + { + "id": "76", + "unit": "第四单元100以内数的认识1", + "question_type": "填空题", + "difficulty": 0.85, + "question": "一个两位数,个位与十位上的数字相同,像这样的两位数共有( )个,其中最大的是( ),最小的是( )。", + "options": [ + + ], + "answer": "99911", + "solution": "【分析】一个两位数,从右往左依次为个位,十位。两位数的十位最少是 1,个位和十位相同的数有 11, 22, 33, 44, 55, 66, 77, 88, 99;比较它们的大小,都是两位数,十位大的数就大;十位相同比较个位,个位大的数就大.\n【详解】 99 \u003e 88 \u003e 77 \u003e 66 \u003e 55 \u003e 44 \u003e 33 \u003e 22 \u003e 11一个两位数,个位与十位上的数字相同,像这样的两位数共有 9 个,其中最大的是 99,最小的是 11。", + "knowledge_points": [ + "100以内数的比大小", + "100以内数的组成" + ], + "source": "23-24一年级下·山西长治·期末" + }, + { + "id": "77", + "unit": "第四单元100以内数的认识1", + "question_type": "填空题", + "difficulty": 0.85, + "question": "7 个十和 4 个一是( )。58 里面有( )个十和( )个一。", + "options": [ + + ], + "answer": "7458", + "solution": "【分析】几个十就是几十,几个一就是几,合起来就是几十几。一个两位数,从右往左依次为个位,十位,十位是几就有几个十,个位是几就有几个一.\n【详解】7个十是70,4个一是4,合起来是74.7个十和4个一是74.58里面有5个十和8个一。", + "knowledge_points": [ + "100以内数的组成" + ], + "source": "23-24 一年级下·河南周口·期末" + }, + { + "id": "78", + "unit": "第四单元100以内数的认识1", + "question_type": "填空题", + "difficulty": 0.85, + "question": "一个两位数,个位上是 7,十位上是 8,这个数是( ), 读作( )。", + "options": [ + + ], + "answer": "87 八十七", + "solution": "【分析】一个两位数,从右往左数,第一位是个位,第二位是十位;读一个两位数时,先读十位上的数,读作几十,再读个位数的数,读作几,个位数若是 0,不用读出来.\n【详解】由题意分析得:一个两位数,个位上是 7,十位上是 8,这个数是 87,读作:八十七。", + "knowledge_points": [ + "100以内数的读,写法", + "100以内数的组成" + ], + "source": "23-24 一年级下·山东菏泽·期末" + }, + { + "id": "79", + "unit": "第四单元100以内数的认识1", + "question_type": "填空题", + "difficulty": 0.85, + "question": "4 个十和 2 个一组成( );86 里面有( )个一和( )个十,它前面的第 3 个数是( )。", + "options": [ + + ], + "answer": "426883", + "solution": "【分析】从右边起第一位是个位,个位上是几就表示是几个一,第二位是十位,十位上是几就表示几个十,再结合 100 以内整数的排序进行解答即可.\n【详解】4个十是40,2个一是2,组成的数是42;86 的个位上是 6,十位上是 8,所以 86 里面有 6 个一和 8 个十, 86 前面的数是 85,84,83,所以它前面的第 3 个数是 83。", + "knowledge_points": [ + "100以内数的排序", + "100以内数的组成" + ], + "source": "23-24 一年级下·河南南阳·期末" + }, + { + "id": "80", + "unit": "第四单元100以内数的认识1", + "question_type": "填空题", + "difficulty": 0.85, + "question": "写出 4 个十位上是 6 的两位数: ( )。", + "options": [ + + ], + "answer": "60,61,62,63", + "solution": "【分析】一个两位数,从右往左依次为个位,十位。十位是6的数有:60,61,62,63,64,65,66,67,68,69,写出任意4个即可.\n【详解】写出 4 个十位上是 6 的两位数:60,61,62,63。(答案不唯一)", + "knowledge_points": [ + "100以内数的组成" + ], + "source": "23-24 一年级下·河南商丘·期末" + }, + { + "id": "81", + "unit": "第四单元100以内数的认识1", + "question_type": "填空题", + "difficulty": 0.85, + "question": "76 里面有( )个十和( )个一,由 4 个一和 8 个十组成的数是( )。", + "options": [ + + ], + "answer": "7684", + "solution": "【分析】一个两位数,从右往左依次为个位,十位。十位是几就有几个十,个位是几就有几个一。几个十就是几十,几个一就是几,合起来就是几十几.\n【详解】4个一是4,8个十是80,合起来是84.76里面有7个十和6个一,由4个一和8个十组成的数是 84。", + "knowledge_points": [ + "100以内数的组成" + ], + "source": "23-24 一年级下·河南商丘·期末" + }, + { + "id": "82", + "unit": "第四单元100以内数的认识1", + "question_type": "填空题", + "difficulty": 0.65, + "question": "56 颗珠子, 10 颗穿一串,能穿( )串;如果 5 颗穿一串,这些珠子能穿( )串。", + "options": [ + + ], + "answer": "511", + "solution": "【分析】56里面有5个十和6个一组成,故,10颗穿一串,56颗珠子能穿5串,还剩下6颗;1 个 10 里面有 2 个 5,则 5 个 10 里面就有 10 个 5;剩下的 6 颗珠子可以分成 5 颗和 1 颗;10 + 1 = 11,所以, 5 颗穿一串, 56 颗珠子能穿 11 串,还剩下 1 颗;据此解决.\n【详解】由题意分析得:56颗珠子,10颗穿一串,能穿5串;如果5颗穿一串,这些珠子能穿11串。", + "knowledge_points": [ + "100以内数的组成" + ], + "source": "23-24 一年级下·河南南阳·期末" + }, + { + "id": "83", + "unit": "第四单元100以内数的认识1", + "question_type": "填空题", + "difficulty": 0.65, + "question": "爷爷今年的年龄比59岁大,比64岁小,且个位上是 1,爷爷今年的年龄是( )岁。", + "options": [ + + ], + "answer": "61", + "solution": "【分析】根据对 100 以内数的认识可知,比 59 大比 64 小的数有: 60, 61, 62, 63。一个两位数,从右往左依次为个位,十位,这些数中个位是 1 的数是 61,由此解答.\n【详解】爷爷今年的年龄比 59 岁大,比 64 岁小,且个位上是 1,爷爷今年的年龄是 61 岁。", + "knowledge_points": [ + "100以内数的比大小", + "100以内数的组成" + ], + "source": "23-24 一年级下·河南周口·期末" + }, + { + "id": "84", + "unit": "第四单元100以内数的认识1", + "question_type": "填空题", + "difficulty": 0.85, + "question": "一个一个地数, 45 后面第2个数是( );十个十个地数,30后面第2个数是( )。", + "options": [ + + ], + "answer": "4750", + "solution": "【分析】一个一个地数,也就是后一个数比前一个数多 1, 45 后面第 1 个数是 46,第 2 个数是 47;十个十个地数,也就是后一个数比前一个数多 10, 30 后面第 1 个数是 40,第 2 个数是 50.\n【详解】一个一个地数, 45 后面第 2 个数是 47;十个十个地数, 30 后面第 2 个数是 50。", + "knowledge_points": [ + "数100以内的数" + ], + "source": "23-24 一年级下·山西长治·期末" + }, + { + "id": "85", + "unit": "第四单元100以内数的认识1", + "question_type": "填空题", + "difficulty": 0.65, + "question": "从计数器中拿走 2颗珠子后,计数器能表示的最大数是( ), 最小数是( )。", + "options": [ + + ], + "answer": "3214", + "solution": "【分析】在计数器上,十位上有几颗珠子表示几个十,个位上有几颗珠子表示几个一。从计数器中拿走 2 颗珠子,要想表示的数最大,需要从个位上拿走 2 颗珠子,此时表示的数是 32;要想表示的数最小,需要从十位上拿走 2 颗珠子,此时表示的数是 14.\n【详解】由分析可知:从计数器中拿走 2 颗珠子后,计数器能表示的最大数是 32,最小数是14。", + "knowledge_points": [ + "100以内数的组成" + ], + "source": "23-24 一年级下·福建漳州·期末" + }, + { + "id": "86", + "unit": "第四单元100以内数的认识1", + "question_type": "判断题", + "difficulty": 0.94, + "question": "60 后面连续的两个数是61,62。()", + "options": [ + + ], + "answer": "V", + "solution": "【分析】根据数的顺序,后一个数比前一个数大 1,据此解答.\n【详解】 60 + 1 = 61, 61 + 1 = 62;因此,60 后面连续的两个数是 61,62。故答案为: V", + "knowledge_points": [ + "100以内数的排序", + "相邻的数" + ], + "source": "24-25一年级下·山东日照·期末" + }, + { + "id": "87", + "unit": "第四单元100以内数的认识1", + "question_type": "判断题", + "difficulty": 0.94, + "question": "77 中左边的 \"7\"表示 7 个一。( )", + "options": [ + + ], + "answer": "×", + "solution": "【分析】两位数的左边是十位,十位上是几表示几个十,个位上是几表示几个一,据此解答.\n【详解】根据分析知:77 是一个两位数,77 中左边的 \"7\"表示 7 个十。故答案为: ×", + "knowledge_points": [ + "100以内数的组成" + ], + "source": "24-25 一年级下·山东日照·期末" + }, + { + "id": "88", + "unit": "第四单元100以内数的认识1", + "question_type": "判断题", + "difficulty": 0.85, + "question": "用数字 5,3,0 能组成 4 个十位和个位不同的两位数。( )", + "options": [ + + ], + "answer": "√", + "solution": "【分析】从 5,3,0 中选择 2 个数组成一个两位数,保证它的个位和十位不相同且 0 不能放在十位,组成的两位数有:53,50,35,30,据此判断.\n【详解】由分析可得:用数字 5,3,0 能组成 4 个十位和个位不同的两位数。原题说法正确。故答案为: √", + "knowledge_points": [ + "100以内数的组成" + ], + "source": "23-24 二年级上·重庆秀山·期末" + }, + { + "id": "89", + "unit": "第四单元100以内数的认识1", + "question_type": "判断题", + "difficulty": 0.85, + "question": "比 60 大,比 70 小的两位数有 10 个。( )", + "options": [ + + ], + "answer": "×", + "solution": "【分析】比60大,比70小的两位数有 61,62,63,64,65,66,67,68,69,共9个,据此判断即可.\n【详解】由分析可知:比60大,比70小的两位数有9个,原题说法错误。故答案为: ×", + "knowledge_points": [ + "100以内数的比大小" + ], + "source": "23-24 一年级下·江西吉安·期末" + }, + { + "id": "90", + "unit": "第四单元100以内数的认识1", + "question_type": "判断题", + "difficulty": 0.65, + "question": "用 5 个圆片可以摆出 6 个不同的两位数。()", + "options": [ + + ], + "answer": "×", + "solution": "【分析】用 5 个圆片可以摆出不同的两位数,十位上分别是 5,4,3,2,1,对应个位上依次是 0,1,2,3,4,共可以摆出 5 个不同的两位数,据此解答即可。注意十位上不能为 0 .\n【详解】由分析可得,用 5 个圆片可以摆出不同的两位数有:50,41,32,23,14 共 5 个,原题说法错误。故答案为: ×", + "knowledge_points": [ + "100以内数的组成" + ], + "source": "23-24 一年级下·河南三门峡·期末" + }, + { + "id": "91", + "unit": "第四单元100以内数的认识1", + "question_type": "判断题", + "difficulty": 0.85, + "question": "3 个一和 8 个十组成的数是 38。( )", + "options": [ + + ], + "answer": "×", + "solution": "【分析】3个一是3,8个十是80,合起来是83,由此判断.\n【详解】由分析可知, 3 个一和 8 个十组成的数是 83,原题说法错误。故答案为: ×", + "knowledge_points": [ + "100以内数的组成" + ], + "source": "23-24 一年级下·广东汕头·期末" + }, + { + "id": "92", + "unit": "第四单元100以内数的认识1", + "question_type": "判断题", + "difficulty": 0.85, + "question": "在百数表中,十位上是 8 的两位数一共 10 个。( )", + "options": [ + + ], + "answer": "√", + "solution": "【分析】一个两位数,从右往左依次为个位,十位。百数表中,十位是8的两位数,个位可以是0至9,依次为80,81,82,83,84,85,86,87,88,89,由此解答.\n【详解】由分析可知,在百数表中,十位上是 8 的两位数一共 10 个。原题说法正确。故答案为: √", + "knowledge_points": [ + "100以内数的组成", + "百数表" + ], + "source": "23-24 一年级下·广东汕头·期末" + }, + { + "id": "93", + "unit": "第四单元100以内数的认识1", + "question_type": "判断题", + "difficulty": 0.65, + "question": "一年级一班有 40 人,一年级二班的人数与一年级一班的人数差不多,一年级二班可能有 60 人。( )", + "options": [ + + ], + "answer": "×", + "solution": "【分析】根据题意分析,一年级一班有 40 人,二班的人数与一班的人数差不多,即与 40 这个数字差不多大小即可, 60 相比较 40 而言应该是多一些,不能说差不多.\n【详解】60比40多一些,所以一年级二班的人数不可能有60人。故答案为: ×", + "knowledge_points": [ + "数的相对大小关系" + ], + "source": "23-24一年级下·河南周口·期末" + }, + { + "id": "94", + "unit": "第四单元100以内数的认识1", + "question_type": "判断题", + "difficulty": 0.85, + "question": "59 和 45 中的 \"5\"表示的意义相同。( )", + "options": [ + + ], + "answer": "×", + "solution": "【分析】一个两位数,从右往左依次为个位,十位。十位是几表示几个十,个位是几表示几个一,由此解答.\n【详解】59中的5在十位表示5个十,45中的5在个位表示5个一,两个\"5\"表示的意义不同。原题说法错误。故答案为: ×", + "knowledge_points": [ + "100以内数的组成" + ], + "source": "23-24 一年级下·河南周口·期末" + }, + { + "id": "95", + "unit": "第四单元100以内数的认识1", + "question_type": "计算题", + "difficulty": 0.65, + "question": "我会看图列式计算。![](images/099a4a8eaf01f1774c019ee40bee63f3aef950408a463e50da768b927e0b8f45.jpg)![](images/1e4500678abacdeba613516ef0171e4a4683ff688fc1d6f262027b6bf68256cb.jpg)", + "options": [ + + ], + "answer": "20 + 6 = 26 (个)", + "solution": "【分析】从图上可得:已知左边有 20 个苹果,右边有 6 个苹果,要求一共有多少个苹果,根据加法的意义,用 20 + 6 进行解答即可.\n【详解】 20 + 6 = 26 (个)所以一共有 26 个苹果。", + "knowledge_points": [ + "整十数加", + "减一位数" + ], + "source": "24-25 一年级下·江西九江·期中" + }, + { + "id": "96", + "unit": "第四单元100以内数的认识1", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式计算。![](images/4a53e3bff3b27f00be28ac5773e9227bc7155d9bce5a016947bdb3ac180e88cc.jpg)□ ○ □ = □ (个)", + "options": [ + + ], + "answer": "20 + 6 = 26", + "solution": "【分析】左边有 20 个苹果,右边有 6 个苹果,求一共有多少个苹果,用加法计算,即左边的数量 + 右边的数量 = 总数量.\n【详解】 20 + 6 = 26 (个)一共有 26 个苹果。", + "knowledge_points": [ + "图文问题", + "整十数加", + "减一位数" + ], + "source": "23-24 一年级下·河北保定·期末" + }, + { + "id": "97", + "unit": "第四单元100以内数的认识1", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式计算。![](images/833ae1e617c3f83433fc87dcd2a39ed8ba5e8785f21be28c7d6f45815ed2694c.jpg)![](images/4447bcaa59c4101ad5da5e3bfc89d8bea5aac185028905072a42757c051207ee.jpg)", + "options": [ + + ], + "answer": "30 + 6 = 36", + "solution": "【分析】把左边的足球数量与右边的数量加起来,求出和,就是足球的总数量.\n【详解】由题意分析得: 30 + 6 = 36 (个)", + "knowledge_points": [ + "图文问题", + "整十数加", + "减一位数" + ], + "source": "23-24 一年级下·江西南昌·期末" + }, + { + "id": "98", + "unit": "第四单元100以内数的认识1", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式计算。![](images/0b4af5e6262bdc72d8fcc76018862ab1263590154021745d506a99cd470541a8.jpg)![](images/f5493bd40a9d1768f87a2158ecd2039cf9ffb908fd773389d7c5361802dd2115.jpg)", + "options": [ + + ], + "answer": "40 + 6 = 46", + "solution": "【分析】左边有 40 个,右边有 6 个,求一共有多少个,用加法计算,即左边的数量 + 右边的数量 = 总数量.\n【详解】 40 + 6 = 46 (个)一共有 46 个。", + "knowledge_points": [ + "图文问题", + "整十数加", + "减一位数" + ], + "source": "23-24 一年级下·福建漳州·期末" + }, + { + "id": "99", + "unit": "第四单元100以内数的认识1", + "question_type": "解答题", + "difficulty": 0.85, + "question": "明明读了 57 页书,小刚比明明少读了7页,小刚读了多少页。", + "options": [ + + ], + "answer": "50页", + "solution": "【分析】求比一个数少几的数是多少,用这个数减去少的数计算,即明明读书的页数一小刚比明明少读的页数=小刚读书的页数.\n【详解】 57 - 7 = 50 (页)答:小刚读了 50 页。", + "knowledge_points": [ + "两位数与一位数的减法(不退位)" + ], + "source": "23-24 二年级上·新疆和田·期中" + }, + { + "id": "100", + "unit": "第四单元100以内数的认识1", + "question_type": "解答题", + "difficulty": 0.85, + "question": "- (1) 班有 50 人交了数学作业,还有 3 人没交,这个班一共有多少人。 □O□=□ (人)", + "options": [ + + ], + "answer": "50+3 = 53;53 人", + "solution": "【分析】求一共有多少人,用加法计算,即交作业的人数 + 没交的人数 = 总人数.\n【详解】50 + 3 = 53 (人)答:这个班一共有53人。", + "knowledge_points": [ + "整十数加", + "减一位数" + ], + "source": "23-24一年级下·山西长治·期末" + }, + { + "id": "101", + "unit": "第四单元100以内数的认识2", + "question_type": "选择题", + "difficulty": 0.85, + "question": "一个两位数,个位上的数和十位上的数合起来是 10,这个两位数最大是 ( )。", + "options": [ + "A. 19", + "B. 91", + "C. 99" + ], + "answer": "B", + "solution": "【分析】根据选项中给出的数,先找出个位上的数与十位上的数加起来等于 10 的,然后找出这个两位数是最大的,即可解决.\n【详解】A。 1 + 9 = 10,即,19,个位上的数和十位上的数合起来是 10;B. 9 + 1 = 10,即, 91,个位上的数和十位上的数合起来是 10;C. 9 + 9 = 18,即, 99,个位上的数和十位上的数合起来不是 10;91 \u003e 18一个两位数,个位上的数和十位上的数合起来是 10,这个两位数最大是 91。故答案为: B", + "knowledge_points": [ + "100以内数的比大小", + "100以内数的组成" + ], + "source": "23-24一年级下·湖北武汉·期末" + }, + { + "id": "102", + "unit": "第四单元100以内数的认识2", + "question_type": "选择题", + "difficulty": 0.85, + "question": "苹果可能有 ( ) 个.\n\n![](images/ebc2e61c7523729702ad22a79ef5cbb8d9eafd9eacdef66fc40feb74b7604fbf.jpg)", + "options": [ + "A. 8", + "B. 38", + "C. 98" + ], + "answer": "B", + "solution": "【分析】两数相差较大时,可以说\"多得多\"和\"少得多\";两数相差较小时,可以说\"少一些\"或\"多一些\"。左边这筐苹果比右边这筐苹果少一些,找出比44个少一些的数量,即可解决.\n【详解】A。8个比44个少得多,不符合题意;B. 38 个比 44 个少一些,符合题意;C. 98 个比 44 个多得多,不符合题意;即,苹果可能有 38 个。![](images/ebc2e61c7523729702ad22a79ef5cbb8d9eafd9eacdef66fc40feb74b7604fbf.jpg)故答案为: B", + "knowledge_points": [ + "数的相对大小关系" + ], + "source": "23-24 一年级下·湖北武汉·期末" + }, + { + "id": "103", + "unit": "第四单元100以内数的认识2", + "question_type": "选择题", + "difficulty": 0.65, + "question": "桃子有 35 个,如果桃子比橘子多一些,那么橘子可能有 ( ) 个。", + "options": [ + "A. 30", + "B. 40", + "C. 15" + ], + "answer": "A", + "solution": "【分析】描述数的大小关系的方法:通过比较具体数,用\"多一些\" \"少一些\"描述相差较小的两个数;用\"多得多\" \"少得多\"描述相差较大的两个数。 桃子有 35 个,桃子比橘子多一些,也就是橘子比桃子少一些;找出比 35 个少一些的数,即可解决此题。 \n【详解】A。35个比30个多一些,也就是30个比35个少一些,符合题意;B. 35 个比 40 个少一些,也就是 40 个比 35 个多一些,不符合题意;C. 35 个比 15 个多得多,也就是 15 个比 35 个少得多,不符合题意;即,桃子有 35 个,如果桃子比橘子多一些,那么橘子可能有 30 个。故答案为:A", + "knowledge_points": [ + "数的相对大小关系" + ], + "source": "23-24 一年级下·山东菏泽·期末" + }, + { + "id": "104", + "unit": "第四单元100以内数的认识2", + "question_type": "选择题", + "difficulty": 0.85, + "question": "比 90 少得多的数是 ( )。", + "options": [ + "A. 88", + "B. 15", + "C. 100" + ], + "answer": "B", + "solution": "【分析】比较两个数的多少时,如果两个数的大小比较接近,就说大数比小数多一些,或小数比大数少一些;如果两个数的大小相差很多,就说大数比小数多得多,或小数比大数少得多。由此找出比90少得多的数即可.\n【详解】A。88比90少一些;B. 15 比 90 少得多;C. 100 比 90 多一些。比 90 少得多的数是 15。故答案为: B", + "knowledge_points": [ + "数的相对大小关系" + ], + "source": "23-24 一年级下·湖北黄冈·期末" + }, + { + "id": "105", + "unit": "第四单元100以内数的认识2", + "question_type": "选择题", + "difficulty": 0.85, + "question": "下面最接近 80 的数是 ( )。", + "options": [ + "A. 78", + "B. 85", + "C. 88" + ], + "answer": "A", + "solution": "【分析】根据题意,依次数出各数和 80 之间间隔几个数,间隔的数字越少越接近,由此解答.\n【详解】A。78和80之间间隔的数字有:79,共1个;B. 85 和 80 之间间隔的数字有: 81, 82, 83, 84,共 4 个;C. 88 和 80 之间间隔的数字有:81, 82, 83, 84, 85, 86, 87,共 7 个。间隔数字最少的是 78,也就是最接近 80 的数是 78。故答案为:A", + "knowledge_points": [ + "数 100 以内的数" + ], + "source": "23-24 一年级下·湖北黄冈·期末" + }, + { + "id": "106", + "unit": "第四单元100以内数的认识2", + "question_type": "选择题", + "difficulty": 0.65, + "question": "十位上是 7 的两位数有 ( ) 个。", + "options": [ + "A. 9", + "B. 10", + "C. 11" + ], + "answer": "B", + "solution": "【分析】十位上是 7 的两位数有70,71,72,73,74,75,76,77,78,79,一共10个.\n【详解】由分析可知,十位上是 7 的两位数有 10 个。故答案为: B", + "knowledge_points": [ + "100以内数的读,写法", + "100以内数的组成" + ], + "source": "23-24 一年级下·山东菏泽·期末" + }, + { + "id": "107", + "unit": "第四单元100以内数的认识2", + "question_type": "选择题", + "difficulty": 0.85, + "question": "苹果有 92 个,桃有 6 个,桃的个数比苹果的个数 ( )。", + "options": [ + "A. 多得多", + "B. 少一些", + "C. 少得多" + ], + "answer": "C", + "solution": "【分析】比较两个数的多少时,如果两个数的大小比较接近,就说大数比小数多一些,或小数比大数少一些;如果两个数的大小相差很多,就说大数比小数多得多,或小数比大数少得多。由此解答.\n【详解】由分析可知,6和92相差很多。6比92少得多。桃的个数比苹果的个数少得多。故答案为: C", + "knowledge_points": [ + "数的相对大小关系" + ], + "source": "23-24 一年级下·山东菏泽·期末" + }, + { + "id": "108", + "unit": "第四单元100以内数的认识2", + "question_type": "选择题", + "difficulty": 0.65, + "question": "一条裙子 35 元,一件上衣比一条裙子贵得多,一件上衣可能是 ( ) 元。", + "options": [ + "A. 18", + "B. 38", + "C. 78" + ], + "answer": "C", + "solution": "【分析】根据题意,一条裙子35元,一件上衣比一条裙子贵得多。18比35小,则18比35少一些,35接近38,则38比35多一些,38与78相差很多,则78比35多的多。据此解答.\n【详解】A。18比35少一些,不正确 B. 38 比 35 多一些,不正确 C. 78 比 35 多的多因为一件上衣比一条裙子贵得多,所以一件上衣可能是 78 元。故答案为: C", + "knowledge_points": [ + "100以内数的比大小", + "数的相对大小关系" + ], + "source": "23-24 一年级下·四川凉山·期末" + }, + { + "id": "109", + "unit": "第四单元100以内数的认识2", + "question_type": "选择题", + "difficulty": 0.65, + "question": "妈妈的年龄比80少得多,比16多得多,比40少一些,妈妈()岁。", + "options": [ + "A. 75", + "B. 37", + "C. 41" + ], + "answer": "B", + "solution": "【分析】比较两个数的多少时,如果两个数的大小比较接近,就说大数比小数多一些,或小数比大数少一些;如果两个数的大小相差很多,就说大数比小数多得多,或小数比大数少得多。由此找出比80少得多,比16多得多,比40少一些的数.\n【详解】A。75比80少一些;比16多得多;比40多得多;不符合题意;B. 37 比 80 少得多;比 16 多得多;比 40 少一些,符合题意;C. 41 比 80 少得多;比 16 多得多;比 40 多一些,不符合题意。妈妈37岁。故答案为: B", + "knowledge_points": [ + "数的相对大小关系" + ], + "source": "23-24一年级下·吉林·期末" + }, + { + "id": "110", + "unit": "第四单元100以内数的认识2", + "question_type": "选择题", + "difficulty": 0.65, + "question": "十位上是9的两位数有()个。", + "options": [ + "A. 9", + "B. 10", + "C. 11" + ], + "answer": "B", + "solution": "【分析】十位上是 9,个位上的数是 0 至 9 的数都可以,写出所有十位上是 9 的两位数,数一数即可.\n【详解】十位上是 9 的两位数有90,91,92,99,94,95,96,97,98,99,共10个。故答案为: B", + "knowledge_points": [ + "100以内数的组成" + ], + "source": "20-21一年级下·湖北荆门·期末" + }, + { + "id": "111", + "unit": "第四单元100以内数的认识2", + "question_type": "选择题", + "difficulty": 0.85, + "question": "一本故事书的页数比 60 少,比 55 多,这本书可能有 ( ) 页。", + "options": [ + "A. 63", + "B. 34", + "C. 57" + ], + "answer": "C", + "solution": "【分析】根据 100 以内数的比较大小的方法,找出选项中比 55 大, 60 小的数解答即可.\n【详解】A。 63 \u003e 60,不符合题意;B. 34 \u003c 55,不符合题意;C. 55 \u003c 57 \u003c 60,符合题意。故答案为: C", + "knowledge_points": [ + "100以内数的比大小" + ], + "source": "22-23一年级下·广东汕头·期末" + }, + { + "id": "112", + "unit": "第四单元100以内数的认识2", + "question_type": "选择题", + "difficulty": 0.85, + "question": "6月5日是世界环境日,小思捡了41个瓶子,小维捡的比小思多得多,小维捡了()个。", + "options": [ + "A. 12", + "B. 56", + "C. 98" + ], + "answer": "C", + "solution": "【分析】比较两个数的多少时,如果两个数的大小比较接近,就说大数比小数多一些,或小数比大数少一些;如果两个数的大小相差很多,就说大数比小数多得多,或小数比大数少得多。由此找出比41多得多的数即可.\n【详解】A。12比41小得多;B. 56 比 41 多一些;C. 98 比 41 多得多。小维捡了98个。故答案为: C", + "knowledge_points": [ + "数的相对大小关系" + ], + "source": "23-24一年级下·广西柳州·期末" + }, + { + "id": "113", + "unit": "第四单元100以内数的认识2", + "question_type": "选择题", + "difficulty": 0.85, + "question": "下面选项中,表示的数最大的是 ( ).\n\nA.\n\n![](images/9f9e3072c748bbbb60c5e7063967646061774313aef7d7df5d9772971e6d82ea.jpg)\n\nB.\n\n![](images/97050af71e5a4b36f54b887df26828273ec615eaf5faa97c70b669629ea1e2d2.jpg)\n\nC.\n\n![](images/f8bf41d278a583c07e096eb0ee642573708dceb57af3c30f01004f0de6b5c52a.jpg)", + "options": [ + "A. ", + "B. ", + "C. " + ], + "answer": "B", + "solution": "【分析】据题意可知,判断数值的大小,根据图片中算盘显示 A 示的数值,数一下个位和十位分别有几个珠子,对应位数写出即可,木棒一捆是 10 根,共四捆,再数一数未成捆的木棒,相加即可得出答案。考查学生对于数值的比较.\n【详解】A。个位数是4十位数是4,数值为44;B. 个位数是 3 十位数是 6,数值为 63;C. 40 + 16 根共计 56 根。表示的数最大的是 63 。故答案为: B.", + "knowledge_points": [ + "100以内数的比大小" + ], + "source": "23-24 一年级下·广西柳州·期末" + }, + { + "id": "114", + "unit": "第四单元100以内数的认识2", + "question_type": "选择题", + "difficulty": 0.85, + "question": "个位上是 7 的数是 ( )。", + "options": [ + "A. 73", + "B. 87", + "C. 70" + ], + "answer": "B", + "solution": "【分析】一个两位数,从右往左依次为个位,十位,由此找出个位上是 7 的数即可.\n【详解】A。73十位是7,个位是3;B. 87 十位是 8,个位是 7;C. 70 十位是 7,个位是 0 。个位上是 7 的数是 87。故答案为: B", + "knowledge_points": [ + "100以内数的组成" + ], + "source": "23-24 一年级下·广东江门·期末" + }, + { + "id": "115", + "unit": "第四单元100以内数的认识2", + "question_type": "选择题", + "difficulty": 0.85, + "question": "苹果 75 个,梨 5 个,苹果比梨 ( )。", + "options": [ + "A. 多得多", + "B. 多一些", + "C. 少得多" + ], + "answer": "A", + "solution": "【分析】比较两个数的多少时,如果两个数的大小比较接近,就说大数比小数多一些,或小数比大数少一些;如果两个数的大小相差很多,就说大数比小数多得多,或小数比大数少得多。由此解答.\n【详解】由分析可知, 75 和 5 相差很多, 75 比 5 多得多。苹果比梨多得多。故答案为:A", + "knowledge_points": [ + "数的相对大小关系" + ], + "source": "23-24 一年级下·广东江门·期末" + }, + { + "id": "116", + "unit": "第四单元100以内数的认识2", + "question_type": "选择题", + "difficulty": 0.85, + "question": "60 里面有()个十。", + "options": [ + "A. 6", + "B. 5", + "C. 7" + ], + "answer": "A", + "solution": "【分析】根据题意及两位数的组成,十位上是几就表示几个十,个位上是几就表示几个一,据此解答.\n【详解】根据分析:60 里面有(6)个十。故答案为: A", + "knowledge_points": [ + "100以内数的组成" + ], + "source": "23-24 一年级下·广东江门·期末" + }, + { + "id": "117", + "unit": "第四单元100以内数的认识2", + "question_type": "选择题", + "difficulty": 0.85, + "question": "如图,下边的箱子里可能有 ( ) 袋牛奶.\n\n![](images/a2c548ec0c872bc17aa5e52a5d30a959566e9a3f6e5dc8e683a783bcf2036c14.jpg)", + "options": [ + "A. 50", + "B. 10", + "C. 90" + ], + "answer": "A", + "solution": "【分析】由图可知,右边的箱子里有 82 袋牛奶,左边的箱子里牛奶数量比右边的要少一些,也就是找到比 82 少一些的数即可.\n【详解】A。50比82少一些;B. 10 比 82 少得多;C. 90 比 82 多一些。箱子里可能有 50 袋牛奶。故答案为: A", + "knowledge_points": [ + "数的相对大小关系" + ], + "source": "23-24 一年级下·河北衡水·期末" + }, + { + "id": "118", + "unit": "第四单元100以内数的认识2", + "question_type": "选择题", + "difficulty": 0.85, + "question": "下面各数中的\"3\"与35中的\"3\"表示的意思相同的是()。", + "options": [ + "A. 3", + "B. 37", + "C. 93" + ], + "answer": "B", + "solution": "【分析】一个整数,从右往左依次为个位,十位。十位是几表示几个十,个位是几表示几个一,由此解答.\n【详解】35中的3在十位,表示3个十;A. 3 在个位,表示 3 个一;B. 37 中的 3 在十位,表示 3 个十;C. 93 中的 3 在个位,表示 3 个一。37 与 35 中的 \"3\"表示的意思相同。故答案为: B", + "knowledge_points": [ + "100以内数的组成" + ], + "source": "23-24 一年级下·湖南湘西·期末" + }, + { + "id": "119", + "unit": "第四单元100以内数的认识2", + "question_type": "选择题", + "difficulty": 0.85, + "question": "典典的书比 30 本多得多,典典可能有 ( ) 本书。", + "options": [ + "A. 25", + "B. 48", + "C. 88" + ], + "answer": "C", + "solution": "【分析】比较两个数的多少时,如果两个数的大小比较接近,就说大数比小数多一些,或小数比大数少一些;如果两个数的大小相差很多,就说大数比小数多得多,或小数比大数少得多。由此找出比 30 多得多的数.\n【详解】A。25比30少一些;B. 48 比 30 多一些;C. 88 比 30 多得多。典典可能有 88 本书。故答案为: C", + "knowledge_points": [ + "数的相对大小关系" + ], + "source": "23-24 一年级下·湖南湘西·期末" + }, + { + "id": "120", + "unit": "第四单元100以内数的认识2", + "question_type": "选择题", + "difficulty": 0.65, + "question": "喵喵钓了 25 条鱼,咪咪钓的鱼比它少一些,咪咪可能钓了多少条鱼 ( )。", + "options": [ + "A. 21 条", + "B. 7条", + "C. 29条" + ], + "answer": "A", + "solution": "【分析】两个数相差较多时用多得多,少得多来描述;两个数相差较少时用多一些,少一些来描述,据此得出结论即可.\n【详解】A。选项21比25少一些,符合题意;B. 选项 7 比 25 少得多,不符合题意;C. 选项 29 比 25 多一些,不符合题意;故答案为:A", + "knowledge_points": [ + "数的相对大小关系" + ], + "source": "23-24 一年级下·山东临沂·期末" + }, + { + "id": "121", + "unit": "第四单元100以内数的认识2", + "question_type": "选择题", + "difficulty": 0.85, + "question": "从右边起第 ( ) 位是百位。", + "options": [ + "A. 一", + "B. 二", + "C. 三" + ], + "answer": "C", + "solution": "【分析】从右起第一位是个位,第二位是十位,第三位是百位.\n【详解】从右边起第三位是百位。故答案为: C", + "knowledge_points": [ + "100以内数的组成", + "认识百位" + ], + "source": "23-24 一年级下·山东济宁·期末" + }, + { + "id": "122", + "unit": "第四单元100以内数的认识2", + "question_type": "选择题", + "difficulty": 0.65, + "question": "一个数个位上的数字是 2,十位上的数字比个位上的数字多 5,这个数是 ( ) 。", + "options": [ + "A. 52", + "B. 72", + "C. 27" + ], + "answer": "B", + "solution": "【分析】个位上的数字是 2,十位上的数字比个位上的数字多 5,十位: 2 + 5 = 7,这个数是 72 .\n【详解】一个数个位上的数字是 2,十位上的数字比个位上的数字多 5,这个数是 72 。故答案为: B", + "knowledge_points": [ + "100以内数的组成" + ], + "source": "23-24 一年级下·贵州铜仁·期末" + }, + { + "id": "123", + "unit": "第四单元100以内数的认识2", + "question_type": "选择题", + "difficulty": 0.65, + "question": "下面和 90 最接近的数是 ( )。", + "options": [ + "A. 88", + "B. 95", + "C. 99" + ], + "answer": "A", + "solution": "【分析】从 88 开始数到 99,选项中的哪个数与 90 最接近则之间的数最少,据此解答.\n【详解】88,89,90,91,92,93,94,95,96,97,98,99A。 数出 88 和 90 之间有 1 个数;B. 数出 90 和 95 之间有 4 个数;C. 数出 90 和 99 之间有 8 个数。 所以和 90 最接近的数是 88。故答案为: A", + "knowledge_points": [ + "数 100 以内的数" + ], + "source": "23-24 一年级下·河北保定·期末" + }, + { + "id": "124", + "unit": "第四单元100以内数的认识2", + "question_type": "选择题", + "difficulty": 0.85, + "question": "个位上是 2 的数是 ( )。", + "options": [ + "A. 25", + "B. 32", + "C. 29" + ], + "answer": "B", + "solution": "【分析】一个两位数,从右往左依次为个位,十位,由此找出个位上是 2 的数即可.\n【详解】A。25十位是2,个位是5,不符合题意;B. 32 十位是 3,个位是 2,符合题意;C. 29 十位是 2,个位是 9,不符合题意。个位上是 2 的数是 32。故答案为: B", + "knowledge_points": [ + "100以内数的组成" + ], + "source": "23-24 一年级下·山东临沂·期末" + }, + { + "id": "125", + "unit": "第四单元100以内数的认识2", + "question_type": "选择题", + "difficulty": 0.65, + "question": "合唱队的人数最接近 60 人,合唱队可能有 ( ) 人。", + "options": [ + "A. 38", + "B. 48", + "C. 58", + "D. 68" + ], + "answer": "C", + "solution": "【分析】数数时越靠近 60 的数越接近 60,如 58 比 56 更接近 60, 62 比 64 更接近 60,据此得出结论即可.\n【详解】根据分析知,在 38,48,58,68 中最接近 60 的是 58,即合唱队可能有 58 人。故答案为: C", + "knowledge_points": [ + "100以内数的排序" + ], + "source": "23-24 一年级下·河北邢台·期末" + }, + { + "id": "126", + "unit": "第四单元100以内数的认识2", + "question_type": "选择题", + "difficulty": 0.65, + "question": "一个两位数,从左边数,第一位是 ( )。", + "options": [ + "A. 个位", + "B. 十位", + "C. 百位" + ], + "answer": "B", + "solution": "【分析】在数位顺序表中,从右边起第一位是个位,第二位是十位,第三位是百位.\n【详解】一个两位数,从右边起第一位是个位,第二位是十位;那从左边起第一位是十位,第二位是个位。故答案为: B", + "knowledge_points": [ + "100 以内数的组成", + "认识百位" + ], + "source": "23-24 一年级下·河北邢台·期末" + }, + { + "id": "127", + "unit": "第四单元100以内数的认识2", + "question_type": "选择题", + "difficulty": 0.85, + "question": "66 这个数,左边的6表示6个()。", + "options": [ + "A. 一", + "B. 十", + "C. 百" + ], + "answer": "B", + "solution": "【分析】一个两位数,从右往左依次为个位,十位。十位是几表示几个十,个位是几表示几个一,由此解答.\n【详解】66 这个数,左边的 6 在十位,表示 6 个十。故答案为:B", + "knowledge_points": [ + "100以内数的组成" + ], + "source": "23-24 一年级下·广东河源·期末" + }, + { + "id": "128", + "unit": "第四单元100以内数的认识2", + "question_type": "填空题", + "difficulty": 0.85, + "question": "97 里面有( )个十和( )个一,一个一个地数,它后面第 3 个数是( )。", + "options": [ + + ], + "answer": "9;7;100", + "solution": "【分析】一个两位数,从右往左数,第一位是个位,表示几个一;第二位是十位,表示几个十.\n从 97 开始,一个一个地往后数 3 个数,即可知道 97 后面第 3 个数是几;据此解决.\n【详解】由题意分析得:97, 98, 99, 100;即, 97 里面有 9 个十和 7 个一,一个一个地数,它后面第 3 个数是 100。", + "knowledge_points": [ + "数 100 以内的数", + "100 以内数的组成" + ], + "source": "23-24 一年级下·湖北武汉·期末" + }, + { + "id": "129", + "unit": "第四单元100以内数的认识2", + "question_type": "填空题", + "difficulty": 0.85, + "question": "有 60 个学生和 4 个老师。每人一瓶矿泉水, 65 瓶够吗。 ( ) (填 \"够\" 或 \"不够\")。", + "options": [ + + ], + "answer": "够", + "solution": "【分析】先用加法求出学生和老师一共有多少人,然后与矿泉水的瓶数比较大小,即可解决此题.\n【详解】 60 + 4 = 64 (人) 64 \u003c 65即,有 60 个学生和 4 个老师。每人一瓶矿泉水, 65 瓶够。", + "knowledge_points": [ + "100以内数的比大小", + "整十数加,减一位数" + ], + "source": "23-24一年级下·河南南阳·期末" + }, + { + "id": "130", + "unit": "第四单元100以内数的认识2", + "question_type": "填空题", + "difficulty": 0.85, + "question": "在 98,16,49,58这四个数中,( )比50大得多,( )比50大一些,( )比 50 小得多, ( )最接近 50 。", + "options": [ + + ], + "answer": "98;58;16;49", + "solution": "【分析】描述数的大小关系的方法:通过比较具体数,用\"大一些\"\"小一些\"描述相差较小的两个数;用\"大得多\"\"小得多\"描述相差较大的两个数;当两个数的差越小时,表示这两个数越接近;据此解决.\n【详解】由题意分析得:在 98,16,49,58 这四个数中, 98 比 50 大得多, 58 比 50 大一些, 16 比 50 小得多, 49 最接近 50。", + "knowledge_points": [ + "数的相对大小关系" + ], + "source": "23-24 一年级下·山东菏泽·期末" + }, + { + "id": "131", + "unit": "第四单元100以内数的认识2", + "question_type": "填空题", + "difficulty": 0.85, + "question": "79 里面有( )个一和( )个十,与它相邻的整数是( )和( )。", + "options": [ + + ], + "answer": "9;7;78;80", + "solution": "【分析】一个两位数,从右往左数,第一位是个位,表示几个一;第二位是十位,表示几个十;相邻的两个数相差 1,右边的数比左边的数大 1,左边的数比右边的数小 1;据此解决.\n【详解】由题意分析得:79 - 1 = 7879 + 1 = 80 即, 79里面有9个一和7个十,与它相邻的整数是78和 80。 ", + "knowledge_points": [ + "100以内数的排序", + "100以内数的组成", + "相邻的数" + ], + "source": "23-24 一年级下·湖北黄冈·期末" + }, + { + "id": "132", + "unit": "第四单元100以内数的认识2", + "question_type": "填空题", + "difficulty": 0.85, + "question": "一个两位数,个位上和十位上的数都是 7,这个两位数是( ), 这个数读作( )。", + "options": [ + + ], + "answer": "77;七十七", + "solution": "【分析】先将这个数写出来,再进行读作;数的读作:从高位到低位,一级一级地读,每一级末尾的 0 都不读出来,其他数位连续几个 0 都只读一个零.\n【详解】个位上和十位上的数都是 7,这个两位数是 77;77 读作:七十七所以一个两位数,个位上和十位上的数都是 7,这个两位数是 77,这个数读作七十七。", + "knowledge_points": [ + "100以内数的读,写法", + "100以内数的组成" + ], + "source": "23-24 一年级下·山东菏泽·期末" + }, + { + "id": "133", + "unit": "第四单元100以内数的认识2", + "question_type": "填空题", + "difficulty": 0.65, + "question": "从 boxed1 boxed0 boxed7 这三张卡片中,选两张组成一个两位数,其中最大的是( ),最小的是()。", + "options": [ + + ], + "answer": "71;10", + "solution": "【分析】一个两位数,从右往左依次为个位,十位。组成最大的两位数时,将较大的两个数从大到小依次写在十位和个位;组成最小的两位数时,0不能在最高位,将较小的1写在十位,剩余两个数中最小的数写在个位.\n【详解】 0 \u003c 1 \u003c 7 从 107 这三张卡片中,选两张组成一个两位数,其中最大的是 71,最小的是 10 。", + "knowledge_points": [ + "100以内数的比大小", + "100以内数的组成" + ], + "source": "23-24 一年级下·四川凉山·期末" + }, + { + "id": "134", + "unit": "第四单元100以内数的认识2", + "question_type": "填空题", + "difficulty": 0.85, + "question": "一个一个地数, 20前面 4 个数是( ), 56 后面第 4 个数是( ), 从 30 数到35,一共数了( )个数。", + "options": [ + + ], + "answer": "19,18,17,16;60;6", + "solution": "【分析】一个一个地数,也就是前一个数比后一个数少 1,后一个数比前一个数大 1 。根据数的顺序可知, 20 前面的 4 个数依次为 19, 18, 17, 16;56 后面的第 1 个数是 57;第 2 个数是 58;第 3 个数是 59;第 4 个数是 60;从 30 数到 35,包含 30 和 35,依次为 30, 31, 32, 33, 34, 35,有 6 个数.\n【详解】一个一个地数,20前面4个数是19, 18, 17, 16, 56 后面第 4 个数是 60,从 30 数到 35,一共数了 6 个数。", + "knowledge_points": [ + "数 100 以内的数", + "100 以内数的排序" + ], + "source": "23-24 一年级下·四川凉山·期末" + }, + { + "id": "135", + "unit": "第四单元100以内数的认识2", + "question_type": "填空题", + "difficulty": 0.85, + "question": "84 是由( )个十和( )个一组成的;一个两位数,个位上是 5,十位上的数比个位上的数少3,这个数是( )。", + "options": [ + + ], + "answer": "8;4;25", + "solution": "【分析】据题意可知,题目中是一个两位数,按照从左往右的顺序,分别是十位和个位,数字在那个数位上即代表有几个几,如: 8 在十位,即代表有 8 个十;已知个位是 5,十位比个位少 3,可用个位数减 3 即可知十位的多少.\n【详解】84是有8个十和4个一组成的;一个两位数,个位上是5,十位上的数比个位上的数少3,这个数是25。", + "knowledge_points": [ + "100以内数的组成" + ], + "source": "23-24 一年级下·四川凉山·期末" + }, + { + "id": "136", + "unit": "第四单元100以内数的认识2", + "question_type": "填空题", + "difficulty": 0.85, + "question": "最大 的两位数是( ), 它再添上( )就是 100,十位上是 5,个位上是 7 的数是( )。", + "options": [ + + ], + "answer": "99;1;57", + "solution": "【分析】一个两位数,从右往左依次是个位,十位。每个数位上最大的数是 9,因此最大的两位数是 99,数数时,从小到大依次为 1,2,3。98,99,100。可知 99 后面的一个数是 100,也就是再添上 1 就是 100;十位上是 5,个位上是 7 的数是 57.\n【详解】由分析可知:最大的两位数是 99,它再添上 1 就是 100,十位上是 5,个位上是 7 的数是 57。", + "knowledge_points": [ + "数 100 以内的数", + "100 以内数的组成" + ], + "source": "23-24 一年级下·湖南邵阳·期末" + }, + { + "id": "137", + "unit": "第四单元100以内数的认识2", + "question_type": "填空题", + "difficulty": 0.65, + "question": "一个数的个位上的数是 4,十位上的数是 8,这个数是( ),读作( ),再加上( )个一,就是九个( )。", + "options": [ + + ], + "answer": "84;八十四;6;十", + "solution": "【分析】一个两位数,从右往左依次为个位,十位,由此将数字写在对应数位上即可;读数时从高位读起,十位是几读作几十,个位是几读作几;十位是几就有几个十,个位是几就有几个一;再加上几个一,也就是再往后数几个数,由此数数解答即可.\n【详解】84 后面的数依次为:85,86,87,88,89,90;再往后数 6 个数是 90。一个数的个位上的数是 4,十位上的数是 8,这个数是 84,读作八十四,再加上 6 个一,就是九个十。", + "knowledge_points": [ + "数 100 以内的数", + "100 以内数的读,写法", + "100以内数的组成" + ], + "source": "23-24一年级下·吉林·期末" + }, + { + "id": "138", + "unit": "第四单元100以内数的认识2", + "question_type": "填空题", + "difficulty": 0.85, + "question": "4 个一和 2 个十合起来是( )。36 里面有( )个十和( )个一。", + "options": [ + + ], + "answer": "24;3;6", + "solution": "【分析】据题意可知,组成的数最高位是十位,所以是一个 2 位数,按照从左往右的顺序分别是十个,已知十位是 2 个位是 4,即可得出组成的数;数字在那个数位上即代表有几个几,如: 3 在十位,即代表有 3 个十,依次即可得出答案.\n【详解】4 个一和 2 个十合起来是 (24) 。36 里面有 (3)个十和 (6) 个一。", + "knowledge_points": [ + "100以内数的读,写法", + "100以内数的组成" + ], + "source": "23-24 一年级下·河南信阳·期末" + }, + { + "id": "139", + "unit": "第四单元100以内数的认识2", + "question_type": "填空题", + "difficulty": 0.65, + "question": "在百数表中,一共有( )个两位数。", + "options": [ + + ], + "answer": "90", + "solution": "【分析】百数表中,两位数是从 10 到 99。据此解答.\n【详解】 99 - 10 + 1= 89 + 1= 90 在百数表中,一共有90个两位数。", + "knowledge_points": [ + "数 100 以内的数", + "100 以内数的组成", + "百数表" + ], + "source": "23-24 一年级下·湖南常德·期末" + }, + { + "id": "140", + "unit": "第四单元100以内数的认识2", + "question_type": "填空题", + "difficulty": 0.85, + "question": "一个两位数,它的最高位是( )位,最低位是( )位。", + "options": [ + + ], + "answer": "十;个", + "solution": "【分析】一个两位数,从右往左依次为个位,十位。最左边的数位是最高位,最右边的数位是最低位,由此解答.\n【详解】一个两位数,它的最高位是十位,最低位是个位。例如:89 的 8 在最高位,是十位;9 在最低位,是个位。", + "knowledge_points": [ + "100以内数的组成" + ], + "source": "23-24 一年级下·广东江门·期末" + }, + { + "id": "141", + "unit": "第四单元100以内数的认识2", + "question_type": "填空题", + "difficulty": 0.85, + "question": "大于 49 小于 53 的数有( )。", + "options": [ + + ], + "answer": "50,51,52", + "solution": "【分析】据题意可知,数一数大于 49 小于 53 的数,从 49 开始数,数到 53 停止,中间出现的整数就是答案.\n【详解】49,50,51,52,53大于49小于53的数有50,51,52。", + "knowledge_points": [ + "100以内数的比大小" + ], + "source": "23-24 一年级下·河北保定·期末" + }, + { + "id": "142", + "unit": "第四单元100以内数的认识2", + "question_type": "填空题", + "difficulty": 0.85, + "question": "个位上是 3,十位上是 8,这个数是( );读作( )。", + "options": [ + + ], + "answer": "83;八十三", + "solution": "【分析】一个整数,从右往左依次为个位,十位。由此将数字写在对应数位上即可;读数时从高位读起,十位是几读作几十,个位是几读作几.\n【详解】个位上是 3,十位上是 8,这个数是 83;读作八十三。", + "knowledge_points": [ + "100以内数的读,写法" + ], + "source": "23-24 一年级下·河北保定·期末" + }, + { + "id": "143", + "unit": "第四单元100以内数的认识2", + "question_type": "填空题", + "difficulty": 0.85, + "question": "与 67 接近的一个整十数是( ),与这个整十数相邻的两个数是( )和( )。", + "options": [ + + ], + "answer": "70;69;71", + "solution": "【分析】根据数的顺序:1,2,3。60, 61, 62, 63, 64, 65, 66, 67, 68, 69, 70, 71, 72 , 73。可知, 67前边的第7个数是60, 67后边的第3个数 是 70, 70 和 67 之间间隔的数少,所以最接近的整十数是 70。与 70 相邻的数也就是它两侧的数,由此找到对应的数.\n【详解】与 67 接近的一个整十数是 70,与这个整十数相邻的两个数是 69 和 71 。", + "knowledge_points": [ + "数 100 以内的数", + "100 以内数的排序", + "相邻的数" + ], + "source": "23-24一年级下·河南南阳·期末" + }, + { + "id": "144", + "unit": "第四单元100以内数的认识2", + "question_type": "填空题", + "difficulty": 0.85, + "question": "一个两位数,十位上的数字是 2,个位上的数字比十位上的数字大 6,这个两位数是( )。", + "options": [ + + ], + "answer": "28", + "solution": "【分析】一个两位数,从右往左依次为个位,十位。十位上的数十个位上比十位上大的数 = 个位上的数,再将数字写在相应数位即可.\n【详解】 2 + 6 = 8,十位是2,个位是8。一个两位数,十位上的数字是 2,个位上的数字比十位上的数字大 6,这个两位数是 28。", + "knowledge_points": [ + "100以内数的组成" + ], + "source": "23-24 一年级下·湖南湘西·期末" + }, + { + "id": "145", + "unit": "第四单元100以内数的认识2", + "question_type": "填空题", + "difficulty": 0.85, + "question": "7 个十和 8 个一组成 的数是( );45 里面有( )个一和( )个十。", + "options": [ + + ], + "answer": "78;5;4", + "solution": "【分析】7个十是70,8个一是8,组成的数是78;一个两位数,十位上的数是几,就表示有几个十,个位上的数是几,就表示有几个一,据此填空.\n【详解】由分析可得, 7 个十和 8 个一组成的数是 78;45里面有 5 个一和 4 个十。", + "knowledge_points": [ + "100以内数的组成" + ], + "source": "23-24 一年级下·湖南湘西·期末" + }, + { + "id": "146", + "unit": "第四单元100以内数的认识2", + "question_type": "填空题", + "difficulty": 0.65, + "question": "找规律填数。(1)25,( ),35,( ),45,( )。 (2)( ),99,( ),97,( )。", + "options": [ + + ], + "answer": "30;40;50;100;98;96", + "solution": "【分析】根据题目所给数字的规律填写即可;(1) 从小到大的顺序,五个五个地数的;(2) 从大到小的顺序,一个一个地数的.\n【详解】(1)五个五个地数:25,30,35,40,45,50;(2) 一个一个地数: 100, 99, 98, 97, 96。", + "knowledge_points": [ + "数 100 以内的数", + "整数排列的规律" + ], + "source": "22-23 一年级下·广东汕头·期末" + }, + { + "id": "147", + "unit": "第四单元100以内数的认识2", + "question_type": "填空题", + "difficulty": 0.65, + "question": "一个两位数,十位上的数字是最大的一位数,个位上的数字是 0,这个两位数是( )。", + "options": [ + + ], + "answer": "90", + "solution": "【分析】一个两位数,从右往左依次为个位,十位。十位上的数字是最大的一位数,也就是9,个位上的数字是0,合起来是90,据此解答即可.\n【详解】由分析可得,一个两位数,十位上的数字是最大的一位数,个位上的数字是0,这个两位数是90。", + "knowledge_points": [ + "100以内数的组成" + ], + "source": "22-23 一年级下·广东汕头·期末" + }, + { + "id": "148", + "unit": "第四单元100以内数的认识2", + "question_type": "填空题", + "difficulty": 0.65, + "question": "四十六写作( ),它的最高位上是( ),表示( )个( )。", + "options": [ + + ], + "answer": "46;4;4;十", + "solution": "【分析】根据 100 以内整数的写法,四十六的十位上是 4,个位上是 6,据此即可写出此数。一个两位数,从右往左依次为个位,十位,最高位为十位,十位上的数表示几个十,个位上的数表示几个一.\n【详解】由分析可得,四十六写作 46,它的最高位上是 4,表示 4 个十。", + "knowledge_points": [ + "100以内数的读,写法", + "100以内数的组成" + ], + "source": "22-23 一年级下·广东汕头·期末" + }, + { + "id": "149", + "unit": "第四单元100以内数的认识2", + "question_type": "填空题", + "difficulty": 0.85, + "question": "数数时,十个十个地数, 70 后面的一个数是( )。", + "options": [ + + ], + "answer": "80", + "solution": "【分析】根据题意,十个十个地数,找出 70 后面的一个数即可.\n【详解】十个十个地数:10, 20, 30, 40, 50, 60, 70, 80, 90;所以十个十个地数,70 后面的一个数是 80。", + "knowledge_points": [ + "数 100 以内的数" + ], + "source": "23-24 一年级下·山东日照·期末" + }, + { + "id": "150", + "unit": "第四单元100以内数的认识2", + "question_type": "填空题", + "difficulty": 0.65, + "question": "港珠澳大桥全长55千米.\"55\"读作:( ),左边的\"5\"表示5个( ),右\n边的\"5\"表示5个( )。", + "options": [ + + ], + "answer": "五十五;十;一", + "solution": "【分析】两位数右边的数位是个位,左边的数位是十位;两位数十位上的数表示几个十,读作几十;个位上的数表示几个一,读作几。据此得出结论即可.\n【详解】根据分析知:\"55\"读作:五十五,左边的 \"5\"表示 5 个十,右边的 \"5\"表示 5 个一。", + "knowledge_points": [ + "100以内数的组成" + ], + "source": "23-24一年级下·江西赣州·期末" + }, + { + "id": "151", + "unit": "第四单元100以内数的认识2", + "question_type": "填空题", + "difficulty": 0.85, + "question": "在79,82,23,44这些数中,单数有( )个;比 80 多一些的数是( );比60少得多的数是( );最接近80的数是( )。", + "options": [ + + ], + "answer": "2;82;23;79", + "solution": "【分析】一个两位数,从右往左依次为个位,十位。个位是1,3,5,7,9的数是单数,即79和23是单数;比较两个数的多少时,如果两个数的大小比较接近,就说大数比小数多一些,或小数比大数少一些;如果两个数的大小相差很多,就说大数比小数多得多,或小数比大数少得多。由此找出比80多一些的数,比60少得多的数;根据数的顺序可知,79后边的数就是80,也就是最接近80.\n【详解】79比80少一些;82比80多一些;23和44比80少得多;79和82比60多一些;44比60少一些;23比60少得多。在 79,82,23,44 这些数中,单数有 2 个;比 80 多一些的数是 82;比 60 少得多的数是 23;最接近 80 的数是 79。", + "knowledge_points": [ + "100 以内数的排序", + "数的相对大小关系", + "100 以内数的组成" + ], + "source": "23-24一年级下·福建福州·期末" + }, + { + "id": "152", + "unit": "第四单元100以内数的认识2", + "question_type": "填空题", + "difficulty": 0.65, + "question": "72 的十位上是( ), 表示( )个十;它的个位上是( ), 表示( )个一。", + "options": [ + + ], + "answer": "7;7;2;2", + "solution": "【分析】从右起,第一位是个位,第二位是十位。个位上是几就表示几个一,十位上是几就表示几个十.\n【详解】72 的十位上是 7,表示 7 个十;它的个位上是 2,表示 2 个一。", + "knowledge_points": [ + "100以内数的组成" + ], + "source": "23-24 一年级下·山东济宁·期末" + }, + { + "id": "153", + "unit": "第四单元100以内数的认识2", + "question_type": "填空题", + "difficulty": 0.85, + "question": "68 里面有( )个十和( )个一;由 4 个一和 5 个十组成的数是( )。", + "options": [ + + ], + "answer": "6;8;54", + "solution": "【分析】从右边起第一位是个位,第二位是十位;十位上的数字上是几就表示几个十,个位上的数字是几就表示几个一.\n【详解】由分析可知:68里面有6个十和8个一;由4个一和5个十组成的数是54", + "knowledge_points": [ + "100以内数的组成" + ], + "source": "23-24 一年级下·山东济宁·期末" + }, + { + "id": "154", + "unit": "第四单元100以内数的认识2", + "question_type": "填空题", + "difficulty": 0.85, + "question": "6 个一和 5 个十组成的数是( ),读作( )。", + "options": [ + + ], + "answer": "56;五十六", + "solution": "【分析】一个整数,从右往左依次为个位,十位写数时从高位写起,有几个十就在十位写几,有几个一就在个位写几;读数时从高位读起,几个十读作几十,几个一读作几.\n【详解】6个一和5个十组成的数是56,读作五十六。", + "knowledge_points": [ + "100以内数的读,写法", + "100以内数的组成" + ], + "source": "23-24 一年级下·广东江门·期末" + }, + { + "id": "155", + "unit": "第四单元100以内数的认识2", + "question_type": "填空题", + "difficulty": 0.85, + "question": "78 里面有( )个一和( )个十,和它相邻的两个数是( )和( )。", + "options": [ + + ], + "answer": "8;7;77;79", + "solution": "【分析】一个两位数,从右往左数,第一位是个位,个位上的数表示几个一;第二位是十位,十位上的数表示几个十。从 70 到 80,一个一个地数一数,即可知道与 78 相邻的数有哪些.\n【详解】70,71,72,73,74,75,76,77,78,79,80。所以 78 里面有 8 个一和 7 个十,和它相邻的两个数是 77 和79。", + "knowledge_points": [ + "数 100 以内的数", + "100 以内数的组成", + "相邻的数" + ], + "source": "23-24 一年级下·山东济宁·期末" + }, + { + "id": "156", + "unit": "第四单元100以内数的认识2", + "question_type": "填空题", + "difficulty": 0.85, + "question": "从 1 到 100,一共有 ( )个双数,有 ( )个单数。", + "options": [ + + ], + "answer": "50;50", + "solution": "【分析】个位上是 0,2,4,6,8 的数是双数,个位上是 1,3,5,7,9 的数是单数,从 1 数到 100,一共有 100 个数字,1 是单数,2 是双数,3 是单数,4 是双数。99 是单数,100 是双数,这些数是一个单数一个双数的顺序排列的,最后一个是双数,所以这里单数和双数的数量相等,据此解答.\n【详解】从 1 到 100,一共有 (50) 个双数,有 (50) 个单数。", + "knowledge_points": [ + "数 100 以内的数" + ], + "source": "23-24 一年级下·山东济南·期末" + }, + { + "id": "157", + "unit": "第四单元100以内数的认识2", + "question_type": "填空题", + "difficulty": 0.65, + "question": "看图写数.\n\n![](images/75eee7a835abb2298585d76db8a202a34778a48aa1c77c1418e6a3b05b8efcd9.jpg)()\n\n![](images/572ccefb5c976dad91e060b22a44ac7916281f22ddfe21389fa5456364a67461.jpg) ()\n\n![](images/0b3ab2e38ade8a636bb6bf936deeab59ef99814374c77f2006d25eac6cdafd0f.jpg) ()\n\n( ) ( ) ( )", + "options": [ + + ], + "answer": "33;60;100", + "solution": "【分析】一捆表示 10,一根表示 1,有 3 捆就是 30,有三根就是 3;百位上没有珠子就不写,十位上有 6 个珠子就是六十,个位没有就写零;百位上有一个珠子就是一百,十位和个位没有就写零,据此解答.\n【详解】填空如下:\n\n![](images/82212b8e6c45b8c0a7970d79224a4752b3e8bcd2170e32aa9d6b437de1c6edbd.jpg)", + "knowledge_points": [ + "100以内数的组成" + ], + "source": "23-24 一年级下·山东济南·期末" + }, + { + "id": "158", + "unit": "第四单元100以内数的认识2", + "question_type": "填空题", + "difficulty": 0.85, + "question": "50 添上( )个十是 80, 3 个一和 8 个十合起来是( )。", + "options": [ + + ], + "answer": "3;83", + "solution": "【分析】50里面有5个十,80里面有8个十,所以50添上3个十是80.3 个一就是在数位的个位上写 3, 8 个十就是在十位上写 8,这个数是 83.\n【详解】据分析可知:50 添上 3 个十是 80;3个一是3,8个十是80,所以合起来是83。", + "knowledge_points": [ + "100以内数的组成" + ], + "source": "23-24 一年级下·山东临沂·期末" + }, + { + "id": "159", + "unit": "第四单元100以内数的认识2", + "question_type": "填空题", + "difficulty": 0.85, + "question": "与59相邻的两个数是( )和( );65与73之间有( )个数。", + "options": [ + + ], + "answer": "58;60;7", + "solution": "【分析】与 59 相邻的数,也就是它两侧的数。根据数的顺序:1,2,3。57,58,59,60。找出对应数字即可;65和73之间的数有:66,67,68,69,70,71,72,数出个数即可.\n【详解】与 59 相邻的两个数是 58 和 60;65 与 73 之间有 7 个数。", + "knowledge_points": [ + "数 100 以内的数", + "100 以内数的排序", + "相邻的数" + ], + "source": "23-24 一年级下·河北衡水·期末" + }, + { + "id": "160", + "unit": "第四单元100以内数的认识2", + "question_type": "填空题", + "difficulty": 0.85, + "question": "在 8,37,74,68,93中,最大的数是( ),十位上是3的数是( )。", + "options": [ + + ], + "answer": "93;37", + "solution": "【分析】整数的大小比较先比较数位,数位多的数就大,数位相同比较最高位,最高位大的数就大;最高位相同比较下一位,直到比较出结果为止;一个两位数左起第一位是十位,第二位是个位,据此解答.\n【详解】 93 \u003e 74 \u003e 68 \u003e 37 \u003e 8在 8,37,74,68,93 中,最大的数是 93,十位上是 3 的数是 37。", + "knowledge_points": [ + "100以内数的比大小", + "100以内数的组成" + ], + "source": "23-24一年级下·河北衡水·期末" + }, + { + "id": "161", + "unit": "第四单元100以内数的认识2", + "question_type": "填空题", + "difficulty": 0.85, + "question": "78 里面有( )个十和( )个一;( )个十是 100。", + "options": [ + + ], + "answer": "7;8;10", + "solution": "【分析】一个两位数,十位上的数字是几表示几个十,个位上的数字是几表示几个一;十个十个地数,10个十是 100.\n【详解】由分析可知:78 里面有 7 个十和 8 个一;10 个十是 100 。", + "knowledge_points": [ + "100以内数的组成" + ], + "source": "23-24 一年级下·山东济宁·期末" + }, + { + "id": "162", + "unit": "第四单元100以内数的认识2", + "question_type": "填空题", + "difficulty": 0.65, + "question": "7 颗珠子能组成( )(1)个不同的两位数,其中最大的两位数是 ( ) , 最小的两位数是( )。", + "options": [ + + ], + "answer": "7;70;16", + "solution": "【分析】用7颗珠子在计数器上能摆成的两位数有:16, 25, 34, 43, 52, 61, 70,共 7 个。再将这数比较大小,相同数位,先比较十位,十位大的数大,十位相同比较个位,个位大的数大.\n【详解】 70 \u003e 61 \u003e 52 \u003e 43 \u003e 34 \u003e 25 \u003e 167颗珠子能组成7个不同的两位数,其中最大的两位数是70,最小的两位数是 16 。", + "knowledge_points": [ + "100 以内数的比大小", + "100 以内数的组成" + ], + "source": "23-24 一年级下·山东临沂·期末" + }, + { + "id": "163", + "unit": "第四单元100以内数的认识2", + "question_type": "填空题", + "difficulty": 0.65, + "question": "由 5 个一和 6 个十组成的数是( )。由5个十和6个一组成的数是( )。", + "options": [ + + ], + "answer": "65;56", + "solution": "【分析】在数位顺序表中,从右边起第一位是个位,第二位是十位,第三位是百位;个位上数字是几表示几个一;十位上数字是几表示几个十,百位上数字是几表示几个百。 \n【详解】5 个一和 6 个十:十位上数字是 6,个位上数字是 5,这个数是 65;5个十和6个一:十位上数字是5,个位上数字是6,这个数是56。", + "knowledge_points": [ + "100以内数的组成" + ], + "source": "23-24 一年级下·山东临沂·期末" + }, + { + "id": "164", + "unit": "第四单元100以内数的认识2", + "question_type": "填空题", + "difficulty": 0.65, + "question": "个位上是 9,十位上是 5 的数是( ), 与它相邻的两个数分别是( )和( )。", + "options": [ + + ], + "answer": "59;58;60", + "solution": "【分析】从右起第一位是个位,第二位是十位。求相邻的数就是比这个数多1和少1即可.\n【详解】个位上是 9,十位上是 5 的数是 59,与它相邻的两个数分别是 58 和 60 。", + "knowledge_points": [ + "100 以内数的排序", + "100 以内数的组成", + "相邻的数" + ], + "source": "23-24 一年级下·山东济宁·期末" + }, + { + "id": "165", + "unit": "第四单元100以内数的认识2", + "question_type": "填空题", + "difficulty": 0.65, + "question": "97 是由( )个十和( )个一组成的。与它相邻的两个数分别是( )和( )。", + "options": [ + + ], + "answer": "9;7;96;98", + "solution": "【分析】一个两位数,从右往左数,第一位是个位,个位上的数表示几个一;第二位是十位,十位上的数表示几个十。从 97 开始往前数,一个一个的数,97 前面是 96;从 97 开始往后数,一个一个的数,97 后面是 98,所以与 97 相邻的两个数是 96 和 98.\n【详解】由分析可得,97是由9个十和7个一组成的。与它相邻的两个数分别是96和98。", + "knowledge_points": [ + "数 100 以内的数", + "100 以内数的组成", + "相邻的数" + ], + "source": "23-24 一年级下·贵州铜仁·期末" + }, + { + "id": "166", + "unit": "第四单元100以内数的认识2", + "question_type": "填空题", + "difficulty": 0.85, + "question": "7 个十是( );68里面有( )个十和( )个一。", + "options": [ + + ], + "answer": "70或七十;6;8", + "solution": "【分析】几个十组成的数就是几十;一个两位数,从右往左依次为个位,十位,十位是几就有几个十,个位是几就有几个一.\n【详解】7个十是70;68里面有6个十和8个一。", + "knowledge_points": [ + "100以内数的读,写法", + "100以内数的组成" + ], + "source": "23-24 一年级下·河北保定·期末" + }, + { + "id": "167", + "unit": "第四单元100以内数的认识2", + "question_type": "填空题", + "difficulty": 0.94, + "question": "98 读作: ( ) 一百写作:( )。", + "options": [ + + ], + "answer": "九十八;100", + "solution": "【分析】两位数十位上的数表示几个十,就读作几十,个位上的数表示几个一,读作几;从高位起按照数位顺序,一级一级往下写,最高位是百位,百位上是 1,十位,个位都是 0.\n【详解】98读作:九十八,一百写作:100。", + "knowledge_points": [ + "100以内数的读,写法" + ], + "source": "23-24 一年级下·广东河源·期末" + }, + { + "id": "168", + "unit": "第四单元100以内数的认识2", + "question_type": "填空题", + "difficulty": 0.85, + "question": "和70相邻的两个数是( )和( )。60前面一个数是( )。", + "options": [ + + ], + "answer": "69;71;59", + "solution": "【分析】要求和 70 相邻的两个数分别是多少,即求比 70 多 1 和少 1 的数分别是多少.\n【详解】要求 60 前面一个数是多少,即求比 60 少 1 的数是多少即可.\n和 70 相邻的两个数是 69 和 71.60前面的一个数是59。", + "knowledge_points": [ + "100以内数的比大小", + "相邻的数" + ], + "source": "23-24 一年级下·山东临沂·期末" + }, + { + "id": "169", + "unit": "第四单元100以内数的认识2", + "question_type": "填空题", + "difficulty": 0.85, + "question": "5 个十和 6 个一组成的数是( ),读作( )。", + "options": [ + + ], + "answer": "56;五十六", + "solution": "【分析】从右边起第一位是个位,第二位是十位,据此结合题干要求即可写出此数。十位上是几,就读几十,个位上是几,就读几,据此即可读出此数.\n【详解】5个十和6个一组成的数是56,读作:五十六。", + "knowledge_points": [ + "100以内数的读,写法", + "100以内数的组成" + ], + "source": "22-23 一年级下·江西吉安·期末" + }, + { + "id": "170", + "unit": "第四单元100以内数的认识2", + "question_type": "填空题", + "difficulty": 0.85, + "question": "10 个十是( ), 60里面有( )个十。", + "options": [ + + ], + "answer": "100;6", + "solution": "【分析】根据 100 以内数的组成可知: 10 个十是 100 。从右边起第一位是个位,第二位是十位,十位上是几,就表示有几个十,据此解答即可.\n【详解】10个十是100,60里面有6个十。", + "knowledge_points": [ + "100以内数的组成" + ], + "source": "23-24 一年级下·湖南邵阳·期末" + }, + { + "id": "171", + "unit": "第四单元100以内数的认识2", + "question_type": "填空题", + "difficulty": 0.85, + "question": "一个数比 50 大比 60 小,十位和个位上的数字相差 2,这个数可能是( ), 也可能是( )。", + "options": [ + + ], + "answer": "53;57", + "solution": "【分析】依据 100 以内数的比较大小可知:比 50 大比 60 小的两位数十位上是 5,并且 5 - 3 = 2 , 7 - 5 = 2,这个两位数可能是 53 或 57 .\n【详解】比 50 大比 60 小的两位数十位上是 5,因为十位和个位上的数字相差 2,所以个位上的数可能是 5 - 3 = 2 , 7 - 5 = 2,这个两位数可能是 53 或 57。", + "knowledge_points": [ + "100以内数的组成" + ], + "source": "23-24一年级下·浙江杭州·期末" + }, + { + "id": "172", + "unit": "第四单元100以内数的认识2", + "question_type": "填空题", + "difficulty": 0.85, + "question": "49 与 52 这两个数, ( )更接近 50,它与 50 相差( )。", + "options": [ + + ], + "answer": "49;1", + "solution": "【分析】根据100以内数的顺序:1,2,3。49, 50, 51, 52。 可知, 49 后面就是 50, 52 和 50 之间间隔了 51,所以 49 更接近 50;49 往后数 1 个数就是 50,也就是它们之间相差 1.\n【详解】根据 100 以内数的顺序可知: 49 与 52 这两个数, 49 更接近 50,它与 50 相差 1 。", + "knowledge_points": [ + "100以内数的排序" + ], + "source": "23-24 一年级下·浙江·期末" + }, + { + "id": "173", + "unit": "第四单元100以内数的认识2", + "question_type": "填空题", + "difficulty": 0.85, + "question": "一个两位数,个位上的数字是 6,十位上的数字比个数上的数字少 2,这个数是( ), 和它相邻的两个数是( )和( )。", + "options": [ + + ], + "answer": "46;45;47", + "solution": "【分析】这个数个位数字是 6,十位数字 = 个位数字 - 2 = 4,这个两位数是 46;相邻的自然数相差 1,与 46 相邻的两个数分别是 46 - 1 与 46 + 1 .\n【详解】 6 - 2 = 4,十位数字是 4,个位数字是 6,这个数是 46;46 - 1 = 45;46 + 1 = 47所以,一个两位数,个位上的数字是 6,十位上的数字比个数上的数字少 2,这个数是 46,和它相邻的两个数是 45 和47。", + "knowledge_points": [ + "100以内数的读,写法", + "100以内数的比大小", + "100以内数的组成", + "相邻的数" + ], + "source": "23-24 一年级下·浙江·期末" + }, + { + "id": "174", + "unit": "第四单元100以内数的认识2", + "question_type": "填空题", + "difficulty": 0.85, + "question": "最大的两位数的个位和十位上的数字都是,这个数是。", + "options": [ + + ], + "answer": "9;99", + "solution": "【分析】一个最大的几位数,就有几个 9 组成,故,最大的两位数就有 2 个 9 组成,也就是 99;据此解决.\n【详解】由题意分析得:最大的两位数的个位和十位上的数字都是 9,这个数是 99 。", + "knowledge_points": [ + "100以内数的比大小", + "100以内数的组成" + ], + "source": "22-23一年级下·河南驻马店·期末" + }, + { + "id": "175", + "unit": "第四单元100以内数的认识2", + "question_type": "填空题", + "difficulty": 0.65, + "question": "62颗珠子, 10颗装一袋,可以装满( )袋,还剩( )颗。", + "options": [ + + ], + "answer": "6;2", + "solution": "【分析】62里面有6个十,2个一,10颗装一袋,可以装满 6 袋,还剩下 2 颗。也可以用珠子的总数量连续减 10,直到不够减,减几次就是装几袋,不够减的就是剩下的,据此得出结论即可.\n【详解】根据分析知:62颗珠子,10颗装一袋,可以装满6袋,还剩2颗。 ", + "knowledge_points": [ + "100以内数的组成" + ], + "source": "22-23 一年级下·江西吉安·期末" + }, + { + "id": "176", + "unit": "第四单元100以内数的认识2", + "question_type": "填空题", + "difficulty": 0.65, + "question": "在 63,36,70,27,这四个数中,个位上是 6 的数是( ),它是由( )个十和( )个一组成的。", + "options": [ + + ], + "answer": "36;3;6", + "solution": "【分析】一个两位数,左边的数位是十位,十位是几表示几个十,右边的数位是个位,个位是几表示几个一,据此得出结论即可.\n【详解】根据分析知:在 63,36,70,27,这四个数中,个位上是 6 的数是 36,它是由3个十和6个一组成的。", + "knowledge_points": [ + "100以内数的组成" + ], + "source": "22-23 一年级下·江西吉安·期末" + }, + { + "id": "177", + "unit": "第四单元100以内数的认识2", + "question_type": "判断题", + "difficulty": 0.85, + "question": "从 25 数到 31,一共数了 6 个数。( )", + "options": [ + "√", + "*" + ], + "answer": "×", + "solution": "【分析】从 25 开始,一个一个地数,一直数到 31,即可知道一共有几个数.\n【详解】由题意分析得:25, 26, 27, 28, 29, 30, 31;即,从 25 数到 31,一共数了 7 个数;原题说法错误。故答案为: ×", + "knowledge_points": [ + "数 100 以内的数" + ], + "source": "23-24一年级下·河南南阳·期末" + }, + { + "id": "178", + "unit": "第四单元100以内数的认识2", + "question_type": "判断题", + "difficulty": 0.65, + "question": "用 5 个 bullet , 分别放在十位和个位上,可以表示6个不同的两位数。()", + "options": [ + "√", + "*" + ], + "answer": "×", + "solution": "【分析】用 5 个 bullet ,分别放在十位和个位上,把摆出不同的两位数一一列举出来,然后数一数一共有几个,即可解决.\n【详解】把 1 个 bullet 放在十位, 4 个 bullet 放在个位上,组成的数是 14;把 2 个 bullet 放在十位, 3 个 bullet 放在个位上,组成的数是 23;把3个 bullet 放在十位,2个 bullet 放在个位上,组成的数是32;把 4 个 bullet 放在十位, 1 个 bullet 放在个位上,组成的数是 41;把 5 个 bullet 放在十位, 0 个 bullet 放在个位上,组成的数是 50;即,用 5 个 bullet , 分别放在十位和个位上,可以表示 5 个不同的两位数;原题说法不正确。故答案为: ×", + "knowledge_points": [ + "100以内数的组成" + ], + "source": "23-24 一年级下·山东菏泽·期末" + }, + { + "id": "179", + "unit": "第四单元100以内数的认识2", + "question_type": "判断题", + "difficulty": 0.85, + "question": "94 和 64 中的两个\"4\"表示的意义相同。()", + "options": [ + "√", + "*" + ], + "answer": "√", + "solution": "【分析】一个两位数,从右往左数,第一位是个位,表示几个一;第二位是十位,表示几个十;据此解决.\n【详解】由题意分析得:94 中的 \"4\" 在个位上,表示 4 个一;64 中的 \"4\" 在也在个位上,表示 4 个一;即,94和64中的两个\"4\"表示的意义相同。故答案为: √", + "knowledge_points": [ + "100以内数的组成" + ], + "source": "23-24 一年级下·湖北黄冈·期末" + }, + { + "id": "180", + "unit": "第四单元100以内数的认识2", + "question_type": "判断题", + "difficulty": 0.85, + "question": "比 78 大且比 83 小的数有 5 个。( )", + "options": [ + "√", + "*" + ], + "answer": "×", + "solution": "【分析】从 78 开始,一个一个地数,一直数到 83,看看 78 和 83 之间 (不包含 78 和 83) 有几个数,即可解决此题.\n【详解】由题意分析得:78, 79, 80, 81, 82, 83;即,比78大且比83小的数有4个;原题说法错。故答案为: ×", + "knowledge_points": [ + "数 100 以内的数", + "100 以内数的比大小" + ], + "source": "23-24 一年级下·湖北黄冈·期末" + }, + { + "id": "181", + "unit": "第四单元100以内数的认识2", + "question_type": "判断题", + "difficulty": 0.65, + "question": "43 和 49 之间有 6 个数。( )", + "options": [ + "√", + "*" + ], + "answer": "×", + "solution": "【分析】根据题意,43和49之间有44,45,46,47,48, 5个数.\n【详解】43和49之间有6个数。原题说法错误。 故答案为: ×", + "knowledge_points": [ + "数 100 以内的数", + "100 以内数的排序" + ], + "source": "23-24 一年级下·四川凉山·期末" + }, + { + "id": "182", + "unit": "第四单元100以内数的认识2", + "question_type": "判断题", + "difficulty": 0.85, + "question": "一个数的个位和十位上的数合起来是 8,这个数一定是 17。( )", + "options": [ + "√", + "*" + ], + "answer": "×", + "solution": "【分析】一个两位数,从右往左依次为个位,十位,个位和十位上的数合起来是 8 。 8 = 1 + 7 = 2 + 6 = 3 + 5 = 4 + 4 = 5 + 3 = 6 + 2 = 7 + 1 = 8 + 0,由此按数位写出数字即可.\n【详解】一个数的个位和十位上的数合起来是 8,这个数可能是 17, 26, 35, 44, 53, 62, 71, 80。原题说法错误。故答案为: ×", + "knowledge_points": [ + "100以内数的组成" + ], + "source": "23-24 一年级下·吉林·期末" + }, + { + "id": "183", + "unit": "第四单元100以内数的认识2", + "question_type": "判断题", + "difficulty": 0.85, + "question": "小玲拍球 40 下,小亮拍的比小玲多得多。小亮拍的是 \"37,45,82\"三个数中的 82 下。( )", + "options": [ + "√", + "*" + ], + "answer": "√", + "solution": "【分析】比较两个数的多少时,如果两个数的大小比较接近,就说大数比小数多一些,或小数比大数少一些;如果两个数的大小相差很多,就说大数比小数多得多,或小数比大数少得多。由此找出比40多得多的数即可.\n【详解】37 比 40 少一些;45 比 40 多一些;82 比 40 多得多。小亮拍了 82 下。原题说法正确。故答案为: √", + "knowledge_points": [ + "数的相对大小关系" + ], + "source": "23-24 一年级下·河南南阳·期末" + }, + { + "id": "184", + "unit": "第四单元100以内数的认识2", + "question_type": "判断题", + "difficulty": 0.85, + "question": "读,写两位数时,都要从个位起。( )", + "options": [ + "√", + "*" + ], + "answer": "×", + "solution": "【分析】一个两位数,从右往左依次为个位,十位,读数时从高位读起,十位是几读作几十,个位是几读作几;写数时从高位写起,有几个十就在十位写几,有几个一就在个位写几,由此解答.\n【详解】由分析可知,读,写两位数时,都要从高位起。例如:98 读作九十八;六十写作 60。原题说法错误。故答案为: ×", + "knowledge_points": [ + "100以内数的读,写法" + ], + "source": "23-24 一年级下·河南南阳·期末" + }, + { + "id": "185", + "unit": "第四单元100以内数的认识2", + "question_type": "判断题", + "difficulty": 0.65, + "question": "用2颗珠子在计数器上表示比 100 小的数,有 3 个不同的数。( )", + "options": [ + "√", + "*" + ], + "answer": "√", + "solution": "【分析】根据题意,要组成比 100 小的数, 100 是最小的三位数,也就是可以组成两位数和一位数。十位拨 2 颗珠子,组成 20;十位拨 1 颗珠子,个位拨 1 颗珠子,组成 11;个位拨 2 颗珠子,组成 2,由此解答.\n【详解】由分析可知,用 2 颗珠子在计数器上表示比 100 小的数,有 20 , 11 和 2,共 3 个不同的数,原题说法正确。故答案为: √", + "knowledge_points": [ + "100以内数的比大小", + "100以内数的组成" + ], + "source": "23-24 一年级下·广西柳州·期末" + }, + { + "id": "186", + "unit": "第四单元100以内数的认识2", + "question_type": "判断题", + "difficulty": 0.85, + "question": "最小的三位数比最大的两位数少 1。( )", + "options": [ + "√", + "*" + ], + "answer": "×", + "solution": "【分析】比较数的大小时,位数多的数就大,也就是三位数大于两位数。最小的三位数是 100,最大的两位数是 99,99 往后数一个数就是 100,也就是 100 比 99 大 1.\n【详解】由分析可知,最小的三位数比最大的两位数大 1,原题说法错误。故答案为: ×", + "knowledge_points": [ + "数 100 以内的数", + "100 以内数的比大小" + ], + "source": "23-24 一年级下·广西柳州·期末" + }, + { + "id": "187", + "unit": "第四单元100以内数的认识2", + "question_type": "判断题", + "difficulty": 0.85, + "question": "96 和 69 两个数中的 6 表示的意义一样。( )", + "options": [ + "√", + "*" + ], + "answer": "×", + "solution": "【分析】一个两位数,从右往左依次为个位,十位。十位是几表示几个十,个位是几表示几个一,由此解答.\n【详解】96中的6在个位表示6个一;69中的6在十位表示6个十。96和69两个数中的6表示的意义不一样。原题说法错误。故答案为: ×", + "knowledge_points": [ + "100以内数的组成" + ], + "source": "23-24 一年级下·广西柳州·期末" + }, + { + "id": "188", + "unit": "第四单元100以内数的认识2", + "question_type": "判断题", + "difficulty": 0.85, + "question": "个位上是 1,十位上是 8,这个数是 18。( )", + "options": [ + "√", + "*" + ], + "answer": "×", + "solution": "【分析】根据题意,从右边起,第一位是个位,第二位是十位。,两位数的写法,从最高位写起,十位上是几就写几,个位上是几就写几,最高位不能是0,根据数的组成,十位上是几表示几个十,个位上是几表示几个一,据此解答.\n【详解】根据题意:个位上是 1,十位上是 8,这个数是 81,原题说法错误。故答案为: ×", + "knowledge_points": [ + "100以内数的读,写法", + "100以内数的组成" + ], + "source": "23-24 一年级下·广东江门·期末" + }, + { + "id": "189", + "unit": "第四单元100以内数的认识2", + "question_type": "判断题", + "difficulty": 0.85, + "question": "爷爷今年 76 岁,我今年 8 岁,我的岁数比爷爷小一些。( )", + "options": [ + "√", + "*" + ], + "answer": "×", + "solution": "【分析】比较两个数的多少时,如果两个数的大小比较接近,则这两个数的大小相等。近,就说大数比小数多一些,或小数比大数少一些;如果两个数的大小相差很多,就说大数比小数多得多,或小数比大数少得多。由此解答.\n【详解】由分析可知, 76 和 8 相差很多。8 比 76 小得多。爷爷今年 76 岁,我今年 8 岁,我的岁数比爷爷小得多。原题说法错误。故答案为: ×", + "knowledge_points": [ + "数的相对大小关系" + ], + "source": "23-24 一年级下·河北保定·期末" + }, + { + "id": "190", + "unit": "第四单元100以内数的认识2", + "question_type": "判断题", + "difficulty": 0.85, + "question": "41 和 50 之间的数有 9 个。( )", + "options": [ + "√", + "*" + ], + "answer": "×", + "solution": "【分析】根据数的顺序,从 41 开始一个一个地数,数到 50,再数出 41 和 50 之间有几个数。从 41 到 50 依次为:41, 42, 43, 44, 45, 46, 47, 48, 49, 50,由此解答.\n【详解】由分析可知,41 和 50 之间的数有42, 43, 44, 45, 46, 47, 48, 49,共 8 个。原题说法错误。故答案为: ×", + "knowledge_points": [ + "数 100 以内的数", + "100 以内数的排序" + ], + "source": "23-24 一年级下·河北保定·期末" + }, + { + "id": "191", + "unit": "第四单元100以内数的认识2", + "question_type": "判断题", + "difficulty": 0.85, + "question": "58和85中的两个8表示的意义相同。()", + "options": [ + "√", + "*" + ], + "answer": "×", + "solution": "【分析】一个两位数,从右往左依次为个位,十位。十位是几表示几个十,个位是几表示几个一,由此解答.\n【详解】58中的8在个位表示8个一,85中的8在十位表示8个十。两个8表示的意义不同,原题说法错误。故答案为: ×", + "knowledge_points": [ + "100以内数的组成" + ], + "source": "23-24一年级下·河北邢台·期末" + }, + { + "id": "192", + "unit": "第四单元100以内数的认识2", + "question_type": "判断题", + "difficulty": 0.85, + "question": "一个一个地,从 43数到50,一共数了5个数。()", + "options": [ + "√", + "*" + ], + "answer": "×", + "solution": "【分析】从 43 数到 50,包括 43 和 50,依次为43, 44, 45, 46, 47, 48, 49, 50,由此数出数量即可.\n【详解】由分析可知,一个一个地,从 43 数到 50,一共数了 8 个数,原题说法错误。故答案为: ×", + "knowledge_points": [ + "数 100 以内的数" + ], + "source": "23-24 一年级下·广东河源·期末" + }, + { + "id": "193", + "unit": "第四单元100以内数的认识2", + "question_type": "判断题", + "difficulty": 0.85, + "question": "69 里的 \"9\"与 96 里的 \"9\"意义相同。( )", + "options": [ + "√", + "*" + ], + "answer": "×", + "solution": "【分析】一个两位数,从右往左依次为个位,十位。十位上的数表示几个十,个位上的数表示几个一,由此解答.\n【详解】69里的\"9\"在个位表示9个一,96里的\"9\"在十位表示9个十,表示的意义不同。原题说法错误。故答案为: ×", + "knowledge_points": [ + "100以内数的组成" + ], + "source": "23-24 一年级下·广东河源·期末" + }, + { + "id": "194", + "unit": "第四单元100以内数的认识2", + "question_type": "判断题", + "difficulty": 0.85, + "question": "个位上是 4,十位上是 7,这个数是 74。( )", + "options": [ + "√", + "*" + ], + "answer": "√", + "solution": "【分析】一个两位数,从右往左数,第一位是个位,第二位是十位;据此组数.\n【详解】由题意分析得:个位上是 4,十位上是 7,这个数是 74;此说法正确。故答案为: √。", + "knowledge_points": [ + "100以内数的组成" + ], + "source": "23-24 一年级下·广东河源·期末" + }, + { + "id": "195", + "unit": "第四单元100以内数的认识2", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式计算.\n\n![](images/92513e7be81f5d79919c85e79af5f77d56cae6b2c5c0be2b334303dc34bd9d4a.jpg)\n\n![](images/8bd476e9c0399f3c4cca88068308b82c95fb24991530aae5c260c0835bff199d.jpg)(个)", + "options": [ + + ], + "answer": "20 + 6 = 26", + "solution": "【分析】根据图片信息可以知道,左边篮子里有 20 个,右边有 6 个,题目意思是问一共有多少个,所以用加法求解即可.\n【详解】看图可知,左边数量为 20 个,右边有 3 + 3 = 6 (个), 所以一共有: 20 + 6 = 26 (个)。", + "knowledge_points": [ + "整十数加,减一位数" + ], + "source": "23-24一年级下·河北邢台·期末" + }, + { + "id": "196", + "unit": "第四单元100以内数的认识2", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式计算.\n\n![](images/ae2d6f4cfc1a0d2bc9bdc955398614cc1876639efc601c432b32680cd5621ce0.jpg)\n\n![](images/25e638441d9cc1589eefc3f5effad24c432f9cdbc33f19627cfad0854e5473cb.jpg)", + "options": [ + + ], + "answer": "30 + 6 = 36", + "solution": "【分析】把左边的球数量与右边的数量加起来,求出和,就是球的总数量.\n【详解】由题意分析得: 30 + 6 = 36 (个)一共36个球。", + "knowledge_points": [ + "图文问题", + "整十数加,减一位数" + ], + "source": "23-24 一年级下·湖北武汉·期末" + }, + { + "id": "197", + "unit": "第四单元100以内数的认识2", + "question_type": "计算题", + "difficulty": 0.85, + "question": "我会看图列式计算.\n\n![](images/9c8ea90d722bff27b7d448d0e1bdd39ef2f058a078e4083bf83488f0878cf169.jpg)\n\n![](images/e1e70cc8bc5809418e241f9c7cae51080921ff33bd99c9e2260c30e8c1c6e167.jpg)", + "options": [ + + ], + "answer": "30 + 8 = 38", + "solution": "【分析】把左边的小刀数量与右边的数量加起来,求出和,就是小刀的总数量.\n【详解】由题意分析得: 30 + 8 = 38 (把)", + "knowledge_points": [ + "图文问题", + "整十数加,减一位数" + ], + "source": "23-24 一年级下·河南南阳·期末" + }, + { + "id": "198", + "unit": "第四单元100以内数的认识2", + "question_type": "计算题", + "difficulty": 0.85, + "question": "我会列式.\n\n![](images/320d74250960b0ab2330bfd2b145d05562628f5ff81bf347365670cceee824a7.jpg)\n\n![](images/bc91881ad47de21fd2a2fdb902aac201b09705808f4cd0e1bf1331b3f0cc4ced.jpg)", + "options": [ + + ], + "answer": "20 + 6 = 26", + "solution": "【分析】根据题意,用左边的鸡蛋数量 20 个 + 右边的鸡蛋数量 6 个 = 鸡蛋总数量,据此解答.\n【详解】根据分析: 20 + 6 = 26 (个)一共有 26 个鸡蛋。", + "knowledge_points": [ + "整十数加,减一位数" + ], + "source": "23-24 一年级下·江西赣州·期末" + }, + { + "id": "199", + "unit": "第四单元100以内数的认识2", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式.\n\n![](images/7bca3a838e0aaa8f9eca68825fe30d276fcef9719cf34ab31de63b241b25ff52.jpg)\n\n![](images/977b5f73aad32852014b32f182de92a5857caa56bd2bc791569480f9c1b123ba.jpg)", + "options": [ + + ], + "answer": "50 + 4 = 54", + "solution": "【分析】左边有 50 个包子,右边有 4 个,求一共有多少个,根据加法的意义,左边的数量 + 右边的数量 = 总数量.\n【详解】 50 + 4 = 54 (个)一共有 54 个。", + "knowledge_points": [ + "图文问题", + "整十数加,减一位数" + ], + "source": "23-24 一年级下·浙江杭州·期末" + }, + { + "id": "200", + "unit": "第四单元100以内数的认识2", + "question_type": "解答题", + "difficulty": 0.65, + "question": "用 5 个 bullet 能摆出 ( )个不同的两位数,按从小到大的顺序写在下面。", + "options": [ + + ], + "answer": "5;14 \u003c 23 \u003c 32 \u003c 41 \u003c 50", + "solution": "【分析】 5 = 0 + 5 = 1 + 4 = 2 + 3,可据此在十位和个位上分别摆上 bullet , 因为 0 不能在两位数的十位上,所以用 5 个 bullet 能摆出 5 个不同的两位数;再按照 100 以内数的大小比较方法:先看十位上的数,十位上的数大这个数就大;十位上的数相同再比较个位上的数,个位上的数大这个数就大。据此进行排序即可.\n【详解】用5个●能摆出不同的两位数有:50,41,32,23,14共5个;从小到大的排列为: 14 \u003c 23 \u003c 32 \u003c 41 \u003c 50 。", + "knowledge_points": [ + "100以内数的排序", + "100以内数的组成" + ], + "source": "23-24 一年级下·浙江·期末" + }, + { + "id": "201", + "unit": "第四单元100以内数的认识3", + "question_type": "选择题", + "difficulty": 0.85, + "question": "60 前面的第五个数是()。", + "options": [ + "A. 55", + "B. 56", + "C. 57" + ], + "answer": "A", + "solution": "【分析】根据数 100 以内的数可知, 60 前面第一个数是59,第二个数是 58,第三个数是 57,第四个数是 56,第五个数是 55,由此解答即可.\n【详解】据分析可知:60前面的第五个数是55。故答案为:A", + "knowledge_points": [ + "数 100 以内的数" + ], + "source": "23-24 一年级下·陕西安康·期末" + }, + { + "id": "202", + "unit": "第四单元100以内数的认识3", + "question_type": "选择题", + "difficulty": 0.85, + "question": "80 比 ( ) 少一些。", + "options": [ + "A. 70", + "B. 90", + "C. 100" + ], + "answer": "B", + "solution": "【分析】比较两个数的多少时,如果两个数的大小比较接近,就说大数比小数多一些,或小数比大数少一些;如果两个数的大小相差很多,就说大数比小数多得多,或小数比大数少得多。据此解答即可.\n【详解】A。80比70多一些,不符合题意;B. 80 比 90 少一些,符合题意;C. 80 比 100 少得多,不符合题意故答案为: B.", + "knowledge_points": [ + "数的相对大小关系" + ], + "source": "23-24一年级下·陕西安康·期末" + }, + { + "id": "203", + "unit": "第四单元100以内数的认识3", + "question_type": "选择题", + "difficulty": 0.65, + "question": "一个两位数,十位上的数字比个位上的数字大 6,这个数可能是 ( )。", + "options": [ + "A. 17", + "B. 72", + "C. 82" + ], + "answer": "C", + "solution": "【分析】一个两位数,从右往左数,第一位是个位;第二位是十位;找出十位上的数字比个位上的数字大 6 的,即可解答.\n【详解】A。17个位数是7,十位数是1, 7 - 1 = 6,即,个位上的数字比十位上的数字大6,不符合题意;B. 72 个位数是 2,十位数是 7, 7 - 2 = 5,即,十位上的数字比个位上的数字大 5,不符合题意;C. 82 个位数是 2,十位数是 8, 8 - 2 = 6,即,十位上的数字比个位上的数字大 6,符合题意。 所以一个两位数,十位上的数字比个位上的数字大 6,这个数字可能是 82 。 故答案为: C.", + "knowledge_points": [ + "100以内数的组成" + ], + "source": "23-24 一年级下·陕西安康·期末" + }, + { + "id": "204", + "unit": "第四单元100以内数的认识3", + "question_type": "选择题", + "difficulty": 0.85, + "question": "在 58 中,\"8\" 在 ( ) 。", + "options": [ + "A. 个位上", + "B. 十位上", + "C. 百位上" + ], + "answer": "A", + "solution": "【分析】一个两位数,从右边起第一位是个位,第二位是十位,\"8\"在个位上,表示 8 个一。据此解答即可.\n【详解】由分析可得,在58中,\"8\"在个位上。故答案为:A.", + "knowledge_points": [ + "100以内数的组成", + "认识百位" + ], + "source": "23-24 一年级下·陕西安康·期末" + }, + { + "id": "205", + "unit": "第四单元100以内数的认识3", + "question_type": "选择题", + "difficulty": 0.85, + "question": "妈妈今年 39 岁,爸爸的年龄和妈妈差不多,爸爸今年可能 ( ) 岁。", + "options": [ + "A. 30", + "B. 41", + "C. 49" + ], + "answer": "B", + "solution": "【分析】描述数的大小关系的方法:通过比较具体数,用 \"多一些\" \"少一些\"描述相差较小的两个数;用\"多得多\" \"少得多\"描述相差较大的两个数,用\"差不多\"描述两个数很接近。据此找出与39差不多的数,即可解决.\n【详解】A。30比39少一些,不符合题意;B. 41 与 39 差不多,符合题意;C. 49 比 39 多一些,不符合题意;即,妈妈今年 39 岁,爸爸的年龄和妈妈差不多,爸爸今年可能 41 岁。故答案为: B.", + "knowledge_points": [ + "数的相对大小关系" + ], + "source": "23-24 一年级下·福建福州·期末" + }, + { + "id": "206", + "unit": "第四单元100以内数的认识3", + "question_type": "选择题", + "difficulty": 0.85, + "question": "军军折了 50 颗星星,明明比他折得多得多,明明可能折了 ( )。", + "options": [ + "A. 90", + "B. 48", + "C. 10" + ], + "answer": "A", + "solution": "【分析】根据数的相对大小可知:比较两个数的多少时,如果两个数的大小比较接近,就说大数比小数多一些,或小数比大数少一些;如果两个数的大小相差很多,就说大数比小数多得多,或小数比大数少得多.\n【详解】A。90比50多的多,符合题意。 B. 48 比 50 少一些,不符合题意。 C. 10 比 50 少的多,不符合题意。故答案为:A.", + "knowledge_points": [ + "数的相对大小关系" + ], + "source": "22-23一年级下·江西吉安·期末" + }, + { + "id": "207", + "unit": "第四单元100以内数的认识3", + "question_type": "选择题", + "difficulty": 0.65, + "question": "99 后面的一个数是几。 ( )", + "options": [ + "A. 98", + "B. 99", + "C. 100" + ], + "answer": "C", + "solution": "【分析】一个数后面的一个数就是比这个数多一的数,也是数数时的下一个数,据此得出结论即可.\n【详解】根据分析知:99后面的一个数是100。故答案为: C.", + "knowledge_points": [ + "数 100 以内的数" + ], + "source": "23-24 一年级下·河南周口·期末" + }, + { + "id": "208", + "unit": "第四单元100以内数的认识3", + "question_type": "选择题", + "difficulty": 0.65, + "question": "乐乐折了 38 个星星,兰兰比他折的多得多,兰兰可能折了 ( ) 个星星。", + "options": [ + "A. 90", + "B. 40", + "C. 10" + ], + "answer": "A", + "solution": "【分析】比较两个数的多少时,如果两个数的大小比较接近,就说大数比小数多一些,或小数比大数少一些;如果两个数的大小相差很多,就说大数比小数多得多,或小数比大数少得多。据此解答即可.\n【详解】A。90比38多得多,符合题意;B. 40 比 38 多一些,不符合题意;C. 10 比 38 少得多,不符合题意。答案为: A.", + "knowledge_points": [ + "数的相对大小关系" + ], + "source": "22-23 一年级下·江西吉安·期末" + }, + { + "id": "209", + "unit": "第四单元100以内数的认识3", + "question_type": "选择题", + "difficulty": 0.65, + "question": "小月养的蚕宝宝比 32 只少一些,她可能养了 ( ) 只。", + "options": [ + "A. 15", + "B. 29", + "C. 58" + ], + "answer": "B", + "solution": "【分析】两数相差较多时用少得多,多得多来描述,两数相差较少时用少一些,多一些来描述,据此得出结论即可.\n【详解】A。15比32少得多,不符合题意;B. 29 比 32 少一些,符合题意;C. 58 比 32 多得多,不符合题意。故答案为: B", + "knowledge_points": [ + "数的相对大小关系" + ], + "source": "23-24 一年级下·江西上饶·期末" + }, + { + "id": "210", + "unit": "第四单元100以内数的认识3", + "question_type": "选择题", + "difficulty": 0.85, + "question": "个位和十位数字相同的两位数有 ( ) 个。", + "options": [ + "A. 6", + "B. 9", + "C. 10" + ], + "answer": "B", + "solution": "【分析】一个两位数,从右往左依次为个位,十位。十位和个位相同的两位数有11, 22, 33, 44, 55, 66, 77, 88, 99,数出数量即可.\n【详解】由分析可知,个位和十位数字相同的两位数有 9 个。故答案为: B.", + "knowledge_points": [ + "100以内数的组成" + ], + "source": "17-18 一年级下·河北·期末" + }, + { + "id": "211", + "unit": "第四单元100以内数的认识3", + "question_type": "选择题", + "difficulty": 0.85, + "question": "比 79 大的数是 ( )。", + "options": [ + "A. 76", + "B. 89", + "C. 69" + ], + "answer": "B", + "solution": "【分析】两位数比较大小时,十位大的数就大;十位相同比较个位,个位大的数就大,由此解答.\n【详解】A。 76 \u003c 79;B. 89 \u003e 79;C. 69 \u003c 79 。比 79 大的数是 89。故答案为: B.", + "knowledge_points": [ + "100以内数的比大小" + ], + "source": "22-23 一年级下·新疆喀什·期末" + }, + { + "id": "212", + "unit": "第四单元100以内数的认识3", + "question_type": "选择题", + "difficulty": 0.85, + "question": "抓一把花生有 20 粒,抓一把黄豆要比花生多得多,抓一把黄豆可能有 ( ) 粒。", + "options": [ + "A. 18", + "B. 21", + "C. 68" + ], + "answer": "C", + "solution": "【分析】比较两个数的多少时,如果两个数的大小比较接近,就说大数比小数多一些,或小数比大数少一些;如果两个数的大小相差很多,就说大数比小数多得多,或小数比大数少得多。由此找出比 20 多得多的数即可.\n【详解】A。18比20少一些,不符合题意;B. 21 比 20 多一些,不符合题意;C. 68 比 20 多得多,符合题意。抓一把黄豆可能有 68 粒。故答案为: C.", + "knowledge_points": [ + "数的相对大小关系" + ], + "source": "23-24 一年级下·河北唐山·期末" + }, + { + "id": "213", + "unit": "第四单元100以内数的认识3", + "question_type": "选择题", + "difficulty": 0.65, + "question": "用 7 颗珠子在计数器上拨出一个两位数。下面正确的是 ( )。", + "options": [ + "A. 7", + "B. 34", + "C. 72" + ], + "answer": "B", + "solution": "【分析】一个两位数的左边数位是十位,右边数位是个位,用 7 颗珠子在计数器上拨出一个两位数,则个位数字与十位数字的和是 7,据此得出结论即可.\n【详解】A。选项是一位数,不符合题意;B. 选项 3 + 4 = 7,符合题意;C. 选项 7 + 2 = 9,不符合题意;故答案为: B.", + "knowledge_points": [ + "100以内数的组成" + ], + "source": "23-24 一年级下·湖北黄冈·期末" + }, + { + "id": "214", + "unit": "第四单元100以内数的认识3", + "question_type": "选择题", + "difficulty": 0.85, + "question": "小明有连环画 27 本,故事书比连环画多一些,故事书可能有 ( ) 本。", + "options": [ + "A. 23", + "B. 31", + "C. 76" + ], + "answer": "B", + "solution": "【分析】比较两个数的多少时,如果两个数的大小比较接近,就说大数比小数多一些,或小数比大数少一些;如果两个数的大小相差很多,就说大数比小数多得多,或小数比大数少得多。由此找出比 27 多一些的数即可.\n【详解】A。23比27少一些,不符合题意;B. 31 比 27 多一些,符合题意;C. 76 比 27 多得多,不符合题意。故事书可能有 31 本。故答案为: B.", + "knowledge_points": [ + "数的相对大小关系" + ], + "source": "23-24 一年级下·湖北黄冈·期末" + }, + { + "id": "215", + "unit": "第四单元100以内数的认识3", + "question_type": "选择题", + "difficulty": 0.85, + "question": "大于 45 而小于 50 的数一共有()个。", + "options": [ + "A. 4", + "B. 5", + "C. 6" + ], + "answer": "A", + "solution": "【分析】大于 45 小于 50 的数,也就是它们之间的数,用数一数的方法解答即可.\n【详解】大于 45 小于 50 的数有 46, 47, 48, 49,共 4 个数。故答案为: A.", + "knowledge_points": [ + "数 100 以内的数", + "100 以内数的比大小" + ], + "source": "23-24 一年级下·湖北黄冈·期末" + }, + { + "id": "216", + "unit": "第四单元100以内数的认识3", + "question_type": "选择题", + "difficulty": 0.85, + "question": "笑笑喜欢读书,她今天读《我身边的大自然》这本书,从第 14 页读到了第 26页,共读了()页。", + "options": [ + "A. 12", + "B. 13", + "C. 14" + ], + "answer": "B", + "solution": "【分析】根据题意,从 14 数到 26,数了多少个数就是读了多少页。依次为14, 15, 16, 17, 18, 19, 20, 21, 22, 23, 24, 25, 26。由此解答.\n【详解】由分析可知,从 14 到 26 一共数了 13 个数,也就是共读了 13 页。故答案为: B.", + "knowledge_points": [ + "数 100 以内的数" + ], + "source": "23-24 一年级下·广西柳州·期末" + }, + { + "id": "217", + "unit": "第四单元100以内数的认识3", + "question_type": "选择题", + "difficulty": 0.85, + "question": "最小的两位数是 ( )。", + "options": [ + "A. 10", + "B. 11", + "C. 99" + ], + "answer": "A", + "solution": "【分析】一个两位数,从右往左依次为个位,十位。最小的两位数,十位最小为 1,个位最小为 0,由此解答.\n【详解】由分析可知,最小的两位数是 10 。故答案为: A.", + "knowledge_points": [ + "100以内数的比大小", + "100以内数的组成" + ], + "source": "14-15 一年级下·全国·课后作业" + }, + { + "id": "218", + "unit": "第四单元100以内数的认识3", + "question_type": "选择题", + "difficulty": 0.65, + "question": "小红和她的 2 个好朋友每人买了 5 本练习本,她们一共买了 ( ) 本练习本。", + "options": [ + "A. 10", + "B. 15", + "C. 8" + ], + "answer": "B", + "solution": "【分析】小红和她的 2 个好朋友一个是 3 个人,一个人买的练习本的数量 + 一个人买的练习本的数量 + 一个人买的练习本的数量 = 一共买的练习本的数量,据此得出结论即可.\n【详解】 5 + 5 + 5 = 10 + 5= 15 (本) 即她们一共买了15本练习本。故答案为: B.", + "knowledge_points": [ + "连加 (20 以内)" + ], + "source": "23-24一年级下·湖北孝感·期末" + }, + { + "id": "219", + "unit": "第四单元100以内数的认识3", + "question_type": "选择题", + "difficulty": 0.85, + "question": "一(4)班师生共36人去春游,坐()车比较合适。", + "options": [ + "A. 37 座的", + "B. 28 座的", + "C. 50 座的" + ], + "answer": "A", + "solution": "【分析】选择的车要能坐下 36 个人,且不要空太多座位的最合适,各选项和 36 进行比较即可.\n【详解】A。 37 \u003e 36,只空1个座位,最合适;B. 28 \u003c 36,坐不下,不合适;C. 50 \u003e 36,但是空太多座位,不合适。故答案为: A.", + "knowledge_points": [ + "100以内数的比大小" + ], + "source": "23-24一年级下·湖南张家界·期末" + }, + { + "id": "220", + "unit": "第四单元100以内数的认识3", + "question_type": "选择题", + "difficulty": 0.65, + "question": "在计数器上拨 3 颗珠子,可以表示的两位数中,最小的是 ( )。", + "options": [ + "A. 3", + "B. 12", + "C. 30" + ], + "answer": "B", + "solution": "【分析】一个两位数,从右往左依次为个位,十位。十位是几表示几个十,个位是几表示几个一。要表示最小的两位数,十位最少拨 1 颗珠子,剩余的拨在个位。即 1 个十和 2 个一,合起来是 12.\n【详解】由分析可知,在计数器上拨 3 颗珠子,可以表示的两位数中,最小的是 12。故答案为: B.", + "knowledge_points": [ + "100以内数的比大小", + "100以内数的组成" + ], + "source": "23-24 一年级下·湖南张家界·期末" + }, + { + "id": "221", + "unit": "第四单元100以内数的认识3", + "question_type": "选择题", + "difficulty": 0.65, + "question": "一个两位数,个位和十位上的数相同,但比 42 大得多,这个数可能是 ( )。", + "options": [ + "A. 33", + "B. 88", + "C. 98" + ], + "answer": "B", + "solution": "【分析】由题意可知,这个数个位和十位上的数相同,且比 42 大得多,则这个数与 42 的差很大,据此即可解答.\n【详解】A。33比42小一些;B. 88 比 42 大得多;C. 98 比 42 大得多,但 92 的个位和十位上的数不相同。这个数可能是 88。故答案为: B.", + "knowledge_points": [ + "数的相对大小关系", + "100以内数的组成" + ], + "source": "23-24 一年级下·贵州黔西·期末" + }, + { + "id": "222", + "unit": "第四单元100以内数的认识3", + "question_type": "选择题", + "difficulty": 0.85, + "question": "49 后面的一个数是 ( )。", + "options": [ + "A. 48", + "B. 50", + "C. 51" + ], + "answer": "B", + "solution": "【分析】48,49,50,51,即,49前面的一个数是48,49后面的一个数是50;据此解决.\n【详解】由题意分析得:49 后面的一个数是 50。故答案为: B.", + "knowledge_points": [ + "100以内数的排序" + ], + "source": "22-23 一年级下·甘肃天水·期中" + }, + { + "id": "223", + "unit": "第四单元100以内数的认识3", + "question_type": "选择题", + "difficulty": 0.65, + "question": "有一个数,比 74 少得多,这个数可能是 ( )。", + "options": [ + "A. 80", + "B. 68", + "C. 34" + ], + "answer": "C", + "solution": "【分析】数的相对大小关系可以通过使用\"多一些,少一些,多得多,少得多\"等表达方式来描述。这些表达方式帮助我们理解两个数之间的相对大小差异。例如:当两个数的差距较大时,我们可以用\"多得多\"和\"少得多\"来描述。例如,数字100比23大很多,可以说100比23大得多;同样地,23比100小很多,可以说23比100少得多。当两个数的差距较小时,我们使用\"多一些\"和\"少一些\"来描述。例如数字100比91大一点,可以说100比91大一些;而91比100小一点,可以说91比100少一些。这个数比74少得多,各选项依次和74进行比较即可.\n【详解】A。 80 \u003e 74,依题意不符,错误;B. 68 \u003c 74,是比 74 少一些,不是少得多,错误;C. 34 \u003c 74,比 74 少得多,正确。故答案为: C.", + "knowledge_points": [ + "100以内数的比大小", + "数的相对大小关系" + ], + "source": "22-23一年级下·甘肃天水·期中" + }, + { + "id": "224", + "unit": "第四单元100以内数的认识3", + "question_type": "填空题", + "difficulty": 0.85, + "question": "98 个位上是( ),表示( ),十位上是( ),表示( ),再添( )个一就是一百了。", + "options": [ + + ], + "answer": "8;8个一;9;9个十;2", + "solution": "【分析】从右边起第一位是个位,个位上是几,就表示几个一,第二位是十位,十位上是几,就表示几个十,据此结合题干要求进行解答即可.\n【详解】98 个位上是 8,表示 8 个一,十位上是 9,表示 9 个十,再添 2 个一就是一百了。", + "knowledge_points": [ + "100以内数的组成" + ], + "source": "23-24 一年级下·河北廊坊·期末" + }, + { + "id": "225", + "unit": "第四单元100以内数的认识3", + "question_type": "填空题", + "difficulty": 0.65, + "question": "个位上是 9 的两位数有( )个,十位上是 9 的两位数有( )个。", + "options": [ + + ], + "answer": "9;10", + "solution": "【分析】个位上是 9 的两位数有19, 29, 39, 49, 59, 69, 79, 89, 99 共 9 个;十位上是 9 的两位数有 90, 91, 92, 93, 94, 95, 96, 97, 98, 99 共 10 个\n【详解】由分析可知:个位上是 9 的两位数有 9 个,十位上是 9 的两位数有 10 个。", + "knowledge_points": [ + "100以内数的组成" + ], + "source": "23-24 一年级下·江西上饶·期末" + }, + { + "id": "226", + "unit": "第四单元100以内数的认识3", + "question_type": "填空题", + "difficulty": 0.85, + "question": "和70相邻的两个数是( )和( )。", + "options": [ + + ], + "answer": "69;71", + "solution": "【分析】相邻的两个数相差 1,前一个数比后一个数少 1,后一个数比前一个数多 1;据此解决.\n【详解】由题意分析得:70 - 1 = 69 ,70 + 1 = 71即,和 70 相邻的两个数是 69 和 71。", + "knowledge_points": [ + "100以内数的排序", + "相邻的数" + ], + "source": "23-24一年级下·陕西安康·期末" + }, + { + "id": "227", + "unit": "第四单元100以内数的认识3", + "question_type": "填空题", + "difficulty": 0.85, + "question": "爷爷现在的岁数是由 2 个一和 6 个十组成的两位数,爷爷现在( )岁。", + "options": [ + + ], + "answer": "62", + "solution": "【分析】两位数的写法:有几个十就在十位上写几,有几个一就在个位上写几。哪一位上一个计数单位也没有,就写 0 占位,据此解答即可.\n【详解】爷爷现在的岁数是由 2 个一和 6 个十组成的两位数,爷爷现在 62 岁。", + "knowledge_points": [ + "100以内数的读,写法", + "100以内数的组成" + ], + "source": "23-24 一年级下·陕西安康·期末" + }, + { + "id": "228", + "unit": "第四单元100以内数的认识3", + "question_type": "填空题", + "difficulty": 0.65, + "question": "一个两位数从左边起第一位是 8,第二位是 3,这个数是( )。", + "options": [ + + ], + "answer": "83", + "solution": "【分析】一个两位数,从左边起第一位是十位,第二位是个位。即十位是 8,个位是 3,这个数是 83.\n【详解】由分析可知:一个两位数从左边起第一位是 8,第二位是 3,这个数是 83。", + "knowledge_points": [ + "100以内数的组成" + ], + "source": "22-23 一年级下·河南驻马店·期末" + }, + { + "id": "229", + "unit": "第四单元100以内数的认识3", + "question_type": "填空题", + "difficulty": 0.65, + "question": "47 读作( ),它是由()个十和()个一组成,再添上()个一就是 50。", + "options": [ + + ], + "answer": "四十七;4;7;3", + "solution": "【分析】读一个两位数,先读十位上的数,读作几十;再读个位数的数,读作几。一个两位数,从右往左数,第一位是个位,表示几个一;第二位是十位,表示几个十。从 47 开始,一个一个地往后数,一直数到 50,看看 47 后面数了几个数,就表示添上几个一就是 50.\n【详解】由题意分析得:47, 48, 49, 50;即, 47 读作:四十七,它是由 4 个十和 7 个一组成,再添上 3 个一就是 50。", + "knowledge_points": [ + "数 100 以内的数", + "100 以内数的读,写法", + "100 以内数的组成" + ], + "source": "23-24 一年级下·福建福州·期末" + }, + { + "id": "230", + "unit": "第四单元100以内数的认识3", + "question_type": "填空题", + "difficulty": 0.85, + "question": "68前面的一个数是( ),后面的一个数是( )。", + "options": [ + + ], + "answer": "67;69", + "solution": "【分析】相邻的两个数相差 1,前一个数比后一个数少 1,后一个数比前一个数多 1;据此解决.\n【详解】 68 - 1 = 67;68 + 1 = 69 即, 68前面的一个数是 67,后面的一个数是 69。", + "knowledge_points": [ + "100以内数的排序" + ], + "source": "22-23一年级下·江西吉安·期末" + }, + { + "id": "231", + "unit": "第四单元100以内数的认识3", + "question_type": "填空题", + "difficulty": 0.65, + "question": "和 59 相邻的两个数是( )和( )。80 比( )大 1,比( )小 1 。", + "options": [ + + ], + "answer": "58;60;79;81", + "solution": "【分析】与一个数相邻的两个数是数数时排在它前面一个和后面一个数;计算一个数比几大 1 用减法,计算一个数比几小 1 用加法,据此得出结论即可.\n【详解】 80 - 1 = 79, 80 + 1 = 81,故和 59 相邻的两个数是 58 和 60.80 比 79 大 1,比 81 小 1。", + "knowledge_points": [ + "100以内数的排序", + "相邻的数" + ], + "source": "22-23一年级下·江西吉安·期末" + }, + { + "id": "232", + "unit": "第四单元100以内数的认识3", + "question_type": "填空题", + "difficulty": 0.65, + "question": "在 58,67,71,78,89这几个数中,最接近60的数是( ),最接近70的数是( ),最接近90的数是( )。", + "options": [ + + ], + "answer": "58;71;89", + "solution": "【分析】从 58 开始数数数到 90,与哪个数最接近则之间的数最少,据此解答.\n【详解】从58到90依次是58,59,60,61,62,63,64,65,66,67,68,69,70,71,72,73,74,75,76,77,78,79,80,81,82,83,84,85,86,87,88,89,90。所以在 58,67,71,78,89 这几个数中,最接近 60 的数是58,最接近 70 的数是 71,最接近 90 的数是 89。", + "knowledge_points": [ + "数 100 以内的数", + "100 以内数的比大小", + "100 以内数的排序" + ], + "source": "23-24 一年级下·河南周口·期末" + }, + { + "id": "233", + "unit": "第四单元100以内数的认识3", + "question_type": "填空题", + "difficulty": 0.65, + "question": "43前面第5个数是( ), 它和43之间有( )个数。", + "options": [ + + ], + "answer": "38;4", + "solution": "【分析】根据 100 以内数的排序即可解答, 100 以内数的排序,每相邻的数都相差 1,据此解答.\n【详解】43前面的数依次是42,41,40,39,38,37。所以43前面第5个数是38;38 和 43 之间有 39,40,41,42,一共有 4 个数。", + "knowledge_points": [ + "100以内数的排序" + ], + "source": "22-23一年级下·江西吉安·期末" + }, + { + "id": "234", + "unit": "第四单元100以内数的认识3", + "question_type": "填空题", + "difficulty": 0.65, + "question": "一个数个位上的数是5,十位上的数比它多4,这个数是( ),再添上( )个一就是100。", + "options": [ + + ], + "answer": "95;5", + "solution": "【分析】一个两位数,从右往左依次为个位,十位,十位上的数表示几个十,个位上的数表示几个一。先求出这个数十位上的数是多少,再写出这个数即可。求这个数再添上几个一就是 100,从这个数的下一位开始一个一个地往后数,数到 100 为止,求出数了几下即可.\n【详解】 5 + 4 = 9 所以这个数是 95;从 95 数到 100 依次是:96,97,98,99,100,所以再添上 5 个一就是 100。", + "knowledge_points": [ + "数 100 以内的数", + "100以内数的组成" + ], + "source": "22-23一年级下·江西吉安·期末" + }, + { + "id": "235", + "unit": "第四单元100以内数的认识3", + "question_type": "填空题", + "difficulty": 0.85, + "question": "88 是一个( )位数,左边的 8 在( )位,表示( )个( )。", + "options": [ + + ], + "answer": "两;十;8;十", + "solution": "【分析】一个数由几个数字组成就是几位数。一个两位数,从右往左数,第一位是个位,个位上的数表示几个一;第二位是十位,十位上的数表示几个十。据此解答即可.\n【详解】由分析可得, 88 是一个两位数,左边的 8 在十位,表示 8 个十。", + "knowledge_points": [ + "100以内数的组成" + ], + "source": "22-23 一年级下·江西吉安·期末" + }, + { + "id": "236", + "unit": "第四单元100以内数的认识3", + "question_type": "填空题", + "difficulty": 0.85, + "question": "一个数从右边起,第一位是( )位,第( )位是百位,读数和写数都是从( )位起。", + "options": [ + + ], + "answer": "个;三;高", + "solution": "【分析】一个数从右边起第一位是个位,第二位是十位,第三位是百位。例如 100,从右往左,第一个 0 在个位,第二个 0 在十位,1 在百位。读数和写数都从高位起。据此解答即可.\n【详解】由分析可得,一个数从右边起,第一位是个位,第三位是百位,读数和写数都是从高位起。", + "knowledge_points": [ + "100以内数的读,写法", + "100以内数的组成", + "认识百位" + ], + "source": "22-23 一年级下·江西吉安·期末" + }, + { + "id": "237", + "unit": "第四单元100以内数的认识3", + "question_type": "填空题", + "difficulty": 0.65, + "question": "52 前面第三个数是( ), 后面第 4 个数是( )。", + "options": [ + + ], + "answer": "49;56", + "solution": "【分析】52前面第三个数是几,就是从52往前倒数3个数,52后面第4个数是几,就是从52往后数4个数,即可解答.\n【详解】52前面第三个数是49,后面第4个数是56", + "knowledge_points": [ + "数 100 以内的数" + ], + "source": "23-24 一年级下·河北廊坊·期末" + }, + { + "id": "238", + "unit": "第四单元100以内数的认识3", + "question_type": "填空题", + "difficulty": 0.85, + "question": "比 30 大比 38 小的数有( )个。", + "options": [ + + ], + "answer": "7", + "solution": "【分析】根据题意,数数时,一个一个地数,从前向后按照一定的顺序数数.\n【详解】比30大比38小的数有 31,32,33,34,35,36,37,一共7个。", + "knowledge_points": [ + "数 100 以内的数", + "100 以内数的比大小" + ], + "source": "23-24 一年级下·河北廊坊·期末" + }, + { + "id": "239", + "unit": "第四单元100以内数的认识3", + "question_type": "填空题", + "difficulty": 0.85, + "question": "观察百数表。 58 下面是( ),58 前面是( )。\u003ctable\u003e\u003ctr\u003e\u003ctd\u003e\u003c/td\u003e\u003ctd\u003e58\u003c/td\u003e\u003c/tr\u003e\u003ctr\u003e\u003ctd\u003e\u003c/td\u003e\u003ctd\u003e\u003c/td\u003e\u003c/tr\u003e\u003c/table\u003e", + "options": [ + + ], + "answer": "68;57", + "solution": "【分析】根据百数表中数的变化规律,前面的数比后面的数小 1,上面的数比下面的数小 10,根据规律填空即可.\n【详解】据分析可知,58 下面是 68,58 前面是 57。", + "knowledge_points": [ + "百数表" + ], + "source": "23-24 一年级下·河北廊坊·期末" + }, + { + "id": "240", + "unit": "第四单元100以内数的认识3", + "question_type": "填空题", + "difficulty": 0.65, + "question": "5 个十和 9 个一合起来是( ),与它相邻的两个数是( )和( )。", + "options": [ + + ], + "answer": "59;58;60", + "solution": "【分析】一个两位数左边的数位是十位,右边的数位是个位,5个十表示十位是5,9个一表示个位是9,这个数是59;与一个数相邻的两个数就是数数时排在它前面一个数和它后面一个数,据此得出结论即可.\n【详解】5个十和9个一合起来是59,与它相邻的两个数是58和60。", + "knowledge_points": [ + "100以内数的排序", + "100以内数的组成", + "相邻的数" + ], + "source": "18-19 一年级下·湖南湘西·期末" + }, + { + "id": "241", + "unit": "第四单元100以内数的认识3", + "question_type": "填空题", + "difficulty": 0.65, + "question": "38 读作( ),由( )个十和( )个一组成,与它相邻的两个数是( )和( )。", + "options": [ + + ], + "answer": "三十八;3;8;37;39", + "solution": "【分析】一个两位数的读法,先读十位上的数,十位上的数读作几十;再读个位上的数,个位上的数读作几。一个两位数,从右往左数,第一位是个位,个位上的数表示几个一;第二位是十位,十位上的数表示几个十。从 30 到 40,一个一个地数一数,即可知道与 38 相邻的数有哪些.\n【详解】由分析可得, 38 读作三十八,由 3 个十和 8 个一组成,与它相邻的两个数是 37 和 39。", + "knowledge_points": [ + "100以内数的读,写法", + "100以内数的排序", + "100以内数的组成", + "相邻的数" + ], + "source": "23-24 一年级下·贵州六盘水·期末" + }, + { + "id": "242", + "unit": "第四单元100以内数的认识3", + "question_type": "填空题", + "difficulty": 0.85, + "question": "( )个十是 60,再添上( )个十和( )个一就是 83。", + "options": [ + + ], + "answer": "6;2;3", + "solution": "【分析】几十里面就有几个十,故60里面有6个十;83里面有8个十和3个一,8个十减6个十等于2个十,故,6个十再添上2个十和3个一,就是83;据此解决.\n【详解】由题意分析得:6个十是60,再添上2个十和3个一就是83。", + "knowledge_points": [ + "100以内数的组成" + ], + "source": "23-24 一年级下·江西上饶·期末" + }, + { + "id": "243", + "unit": "第四单元100以内数的认识3", + "question_type": "填空题", + "difficulty": 0.85, + "question": "用5个 bullet 在\u003ctable\u003e\u003ctr\u003e\u003ctd\u003e十位\u003c/td\u003e\u003ctd\u003e个位\u003c/td\u003e\u003c/tr\u003e\u003ctr\u003e\u003ctd\u003e\u003c/td\u003e\u003ctd\u003e\u003c/td\u003e\u003c/tr\u003e\u003c/table\u003e里摆数,能摆出( )个不同的两位数,其中最小的两位数是( )。", + "options": [ + + ], + "answer": "5;14", + "solution": "【分析】用 5 个●在 十位 \n 个位里摆数,摆出不同的两位数,可以这样摆:(1) 十位上摆 1 个 bullet , 个位上摆 4 个 bullet , 组成的数是 14;(2) 十位上摆 2 个 bullet , 个位上摆 3 个 bullet , 组成的数是 23;(3) 十位上摆 3 个 bullet , 个位上摆 2 个 bullet , 组成的数是 32;(4) 十位上摆 4 个 bullet , 个位上摆 1 个 bullet , 组成的数是 41;(5) 十位上摆 5 个 bullet , 个位上摆 0 个 bullet , 组成的数是 50;一共 5 个;据此解决.\n【详解】由题意分析得:用 5 个 bullet 在\u003ctable\u003e\u003ctr\u003e\u003ctd\u003e十位\u003c/td\u003e\u003ctd\u003e个位\u003c/td\u003e\u003c/tr\u003e\u003ctr\u003e\u003ctd\u003e\u003c/td\u003e\u003ctd\u003e\u003c/td\u003e\u003c/tr\u003e\u003c/table\u003e里摆数,能摆出 5 个不同的两位数,其中最小的两位数是 14 。", + "knowledge_points": [ + "100 以内数的比大小", + "100 以内数的组成", + "摆数问题" + ], + "source": "23-24一年级下·江西上饶·期末" + }, + { + "id": "244", + "unit": "第四单元100以内数的认识3", + "question_type": "填空题", + "difficulty": 0.85, + "question": "52 里面有( )个十和( )个一;68 里有( )十和( )个一。", + "options": [ + + ], + "answer": "5;2;6;8", + "solution": "【分析】52 的十位上是 5,个位上是 2,所以 52 里面有 5 个十和 2 个一;68 的十位上是 6,个位上是 8,所以 68 里面有 6 个十和 8 个一.\n【详解】52里面有5个十和2个一;68里面有6个十和8个一。", + "knowledge_points": [ + "100以内数的组成" + ], + "source": "23-24 一年级下·江西上饶·期末" + }, + { + "id": "245", + "unit": "第四单元100以内数的认识3", + "question_type": "填空题", + "difficulty": 0.85, + "question": "一个两位数,个位上的数是 9,十位上的数比个位上的数小 3,这个数是 ( ) ,和这个数相邻的两个数分别是( )和( )。", + "options": [ + + ], + "answer": "69;68;70", + "solution": "【分析】一个两位数,从右往左数,第一位是个位,第二位是十位;个位上的数是 9,十位上的数比个位上的数小 3 , 9 - 3 = 6,即,十位上是 6,组成的两位数是 69;相邻的两个数相差 1,左边数比右边数小 1,右边数比左边数大 1,故, 69 左边的这个数是 68,右边的这个数是 70;据此解决.\n【详解】由题意分析得:一个两位数,个位上的数是 9,十位上的数比个位上的数小 3,这个数是 69,和这个数相邻的两个数分别是 68 和 70。", + "knowledge_points": [ + "100 以内数的排序", + "100 以内数的组成", + "相邻的数" + ], + "source": "23-24 一年级下·江西上饶·期末" + }, + { + "id": "246", + "unit": "第四单元100以内数的认识3", + "question_type": "填空题", + "difficulty": 0.85, + "question": "27 是一个( )位数,个位是( ), 十位是( )。", + "options": [ + + ], + "answer": "两;7;2", + "solution": "【分析】一个两位数,从右向左数:第一位是个位,第二位是十位,所以 27 的个位数是 7,十位数是 2.\n【详解】由分析可知: 27 是一个两位数,个位是 7,十位是 2。", + "knowledge_points": [ + "100以内数的组成" + ], + "source": "23-24 一年级下·江西上饶·期末" + }, + { + "id": "247", + "unit": "第四单元100以内数的认识3", + "question_type": "填空题", + "difficulty": 0.85, + "question": "80里面有个十。6个十和9个一组成( )。", + "options": [ + + ], + "answer": "8;69", + "solution": "【分析】一个两位数,十位上的数表示几个十,个位上的数表示几个一,据此解答即可.\n【详解】80里面有8个十。6个十和9个一组成69。", + "knowledge_points": [ + "100以内数的组成" + ], + "source": "23-24一年级下·广东汕尾·期末" + }, + { + "id": "248", + "unit": "第四单元100以内数的认识3", + "question_type": "填空题", + "difficulty": 0.65, + "question": "60 里面有( )个十;7 个一和 6 个十合起来是( )。", + "options": [ + + ], + "answer": "6;67", + "solution": "【分析】一个两位数,左边的数位是十位,十位是几表示几个十,右边的数位是个位,个位是几表示几个一,据此得出结论即可.\n【详解】根据分析知:60里面有6个十;7个一和6个十合起来是67。", + "knowledge_points": [ + "100以内数的组成" + ], + "source": "23-24 一年级下·湖北黄冈·期末" + }, + { + "id": "249", + "unit": "第四单元100以内数的认识3", + "question_type": "填空题", + "difficulty": 0.85, + "question": "由 5 个一, 7 个十组成的数是( )。", + "options": [ + + ], + "answer": "75", + "solution": "【分析】一个整数,从右往左依次为个位,十位。几个一就是几,几个十就是几十,然后合起来组数即可.\n【详解】由 5 个一, 7 个十组成的数是 75。", + "knowledge_points": [ + "100以内数的读,写法", + "100以内数的组成" + ], + "source": "22-23 一年级下·新疆喀什·期末" + }, + { + "id": "250", + "unit": "第四单元100以内数的认识3", + "question_type": "填空题", + "difficulty": 0.85, + "question": "38 的( )位上是 \"3\",表示 3 个( )。", + "options": [ + + ], + "answer": "十;十", + "solution": "【分析】一个两位数,从右往左依次为个位,十位。十位是几表示几个十,个位是几表示几个一,由此解答.\n【详解】38 的十位上是 \"3\",表示 3 个十。", + "knowledge_points": [ + "100以内数的组成" + ], + "source": "23-24 一年级下·河北唐山·期末" + }, + { + "id": "251", + "unit": "第四单元100以内数的认识3", + "question_type": "填空题", + "difficulty": 0.85, + "question": "看图写数.\n ![](images/5be12299ef4c581f1dcc43e4ba16e8e8.png)", + "options": [ + + ], + "answer": "35;40", + "solution": "【分析】一个整数,从右往左依次为个位,十位写数时从高位写起,有几个十就在十位写几,有几个一就在个位写几,哪一位上一个也没有就写0占位。图1:有3个十和5个一,写作35;图2:有4个十,写作 40 \n【详解】由分析填写如下:![](images/5be12299ef4c581f1dcc43e4ba16e8e8.png)35和40", + "knowledge_points": [ + "100以内数的读,写法", + "100以内数的组成" + ], + "source": "23-24 一年级下·甘肃平凉·期末" + }, + { + "id": "252", + "unit": "第四单元100以内数的认识3", + "question_type": "填空题", + "difficulty": 0.85, + "question": "29 前面第二个数是( )。", + "options": [ + + ], + "answer": "27", + "solution": "【分析】29 前面的第二个数,也就是从 29 开始倒着数,第一个数是 28,第二个数是 27,由此解答.\n【详解】29前面第二个数是27。", + "knowledge_points": [ + "100以内数的排序" + ], + "source": "23-24 一年级下·甘肃平凉·期末" + }, + { + "id": "253", + "unit": "第四单元100以内数的认识3", + "question_type": "填空题", + "difficulty": 0.85, + "question": "个位上是 6,十位上是 9 的数是() , 读作:()。73 里面有()个十和()个一。", + "options": [ + + ], + "answer": "96;九十六;7;3", + "solution": "【分析】从右边起第一位是个位,个位上是几,就表示几个一,第二位是十位,十位上是几,就表示几个十。读数要从最高位读起,十位上是几就读几十,个位上是几就是几,末尾的 0 不读.\n【详解】个位上是 6,十位上是 9 的数是 96,读作:九十六。73 里面有 7 个十和 3 个一。", + "knowledge_points": [ + "100以内数的读,写法", + "100以内数的组成" + ], + "source": "23-24 一年级下·海南省直辖县级单位·期末" + }, + { + "id": "254", + "unit": "第四单元100以内数的认识3", + "question_type": "填空题", + "difficulty": 0.85, + "question": "梨有 48 个,苹果的个数比梨多,橘子的个数比梨少,苹果最少有( )个,橘子最多有( )个。", + "options": [ + + ], + "answer": "49;47", + "solution": "【分析】梨有 48 个,苹果的个数比梨多,也就是苹果的个数比 48 个多;比 48 大,且是最小的数就是 49,故,苹果最少有 49 个;梨有 48 个,橘子的个数比梨少,也就是梨的个数比 48 个少;比 48 小,且是最大的数就是 47,故,梨最少有 47 个;据此解决.\n【详解】由题意分析得:梨有 48 个,苹果的个数比梨多,橘子的个数比梨少,苹果最少有 49 个,橘子最多有 47 个。", + "knowledge_points": [ + "100以内数的比大小" + ], + "source": "23-24 二年级上·全国·课后作业" + }, + { + "id": "255", + "unit": "第四单元100以内数的认识3", + "question_type": "填空题", + "difficulty": 0.85, + "question": "在 49,58,63,77,82,90这几个数中,最接近60的是( ),最接近80的是( )。", + "options": [ + + ], + "answer": "58;82", + "solution": "【分析】根据 100 以内数的顺序可知,题中数字与 60,80 从小到大排列如下: 49,58,60,63,77,80,82,90.60 两侧的数是 58 和 63, 80 两侧的数是 77 和 82,依次数出间隔几个数字,间隔数字最少的最接近.\n【详解】58和60之间间隔的数字有59,共1个数;63 和 60 之间间隔的数字有 61, 62,共 2 个数;77 和 80 之间间隔的数字有 78, 79,共 2 个数;82 和 80 之间间隔的数字有 81,共 1 个数。在 49,58,63,77,82,90 这几个数中,最接近 60 的是 58,最接近 80 的是 82。", + "knowledge_points": [ + "数 100 以内的数", + "100 以内数的排序" + ], + "source": "23-24一年级下·广西来宾·期末" + }, + { + "id": "256", + "unit": "第四单元100以内数的认识3", + "question_type": "填空题", + "difficulty": 0.85, + "question": "按规律填一填。 73,75,77,79,( ),( ),( )。", + "options": [ + + ], + "answer": "81;83;85", + "solution": "【分析】从73开始,两个两个地数,数到85,据此填空.\n【详解】按规律填一填。73,75,77,79,81,83,85。", + "knowledge_points": [ + "数 100 以内的数" + ], + "source": "22-23一年级下·新疆喀什·期末" + }, + { + "id": "257", + "unit": "第四单元100以内数的认识3", + "question_type": "填空题", + "difficulty": 0.65, + "question": "一个数的个位是 7,十位上是 9,这个数是( )。", + "options": [ + + ], + "answer": "97", + "solution": "【分析】一个两位数,左边的数位是十位,十位上的数表示几个十,右边的数位是个位,个位上的数表示几个一,据此得出结论即可.\n【详解】一个数的个位是 7,十位上是 9,这个数是 97 。", + "knowledge_points": [ + "100以内数的组成" + ], + "source": "23-24 一年级下·广东汕尾·期末" + }, + { + "id": "258", + "unit": "第四单元100以内数的认识3", + "question_type": "填空题", + "difficulty": 0.65, + "question": "7 个一和 9 个十合起来是( ),和它相邻的两个数是( )和( )。", + "options": [ + + ], + "answer": "97;96;98", + "solution": "【分析】7 个一是 7, 9 个十是 90,合起来是 97;相邻的两个数分别是比 97 多 1,少 1 的数.\n【详解】7 个一和 9 个十合起来是 97,和它相邻的两个数是 96 和 98。", + "knowledge_points": [ + "100以内数的排序", + "100以内数的组成", + "相邻的数" + ], + "source": "23-24 一年级下·湖南郴州·期末" + }, + { + "id": "259", + "unit": "第四单元100以内数的认识3", + "question_type": "填空题", + "difficulty": 0.65, + "question": "按规律填数.\n (1)2, 6, 10, ( ), 18, 22, ( )。 (2)90, 85, 80, ( ), 70, ( ), 60。", + "options": [ + + ], + "answer": "14;26 75;65", + "solution": "【分析】(1)从 2 开始,4 个 4 个的数,然后填入缺少的数。(2) 从 90 开始, 5 个 5 个倒着数,然后填入缺少的数。 \n【详解】 (1) 2, 6, 10, 14, 18, 22, 26。 (2) 90, 85, 80, 75, 70, 65, 60。", + "knowledge_points": [ + "数 100 以内的数", + "整数排列的规律" + ], + "source": "23-24 一年级下·湖北黄冈·期末" + }, + { + "id": "260", + "unit": "第四单元100以内数的认识3", + "question_type": "填空题", + "difficulty": 0.85, + "question": "十位上是 7,个位上是 5 的数是( )。", + "options": [ + + ], + "answer": "75", + "solution": "【分析】根据对 100 以内整数的认识求解,即从右边起,第一位是个位,第二位是十位。十位上是 7 表示 7 个十,个位上是 5 表示 5 个一,组成 75.\n【详解】十位上是 7,个位上是 5 的数是 75 。", + "knowledge_points": [ + "100以内数的读,写法", + "100以内数的组成" + ], + "source": "22-23 一年级下·河南周口·期中" + }, + { + "id": "261", + "unit": "第四单元100以内数的认识3", + "question_type": "填空题", + "difficulty": 0.85, + "question": "100 的最高位是( )位;1 在( )位上,表示( )个( )。", + "options": [ + + ], + "answer": "百;百;1;百", + "solution": "【分析】根据数位顺序表,从右到左,依次是个位,十位,百位,千位,万位,。,相对应的计数单位分别是个,十,百,千,万,。,据此解答即可.\n【详解】由分析可知, 100 的最高位是百位, 1 在百位上,表示 1 个百。", + "knowledge_points": [ + "100以内数的组成" + ], + "source": "23-24 一年级下·河南南阳·期末" + }, + { + "id": "262", + "unit": "第四单元100以内数的认识3", + "question_type": "填空题", + "difficulty": 0.65, + "question": "一个两位数,十位上的数比个位上的数大 4,个位上的数比 1 小,这个两位数是( ) , 读作( )。", + "options": [ + + ], + "answer": "40;四十", + "solution": "【分析】本题考查了两位数的组成,一个两位数,个位上的数比 1 小,说明个位上的数是 0,十位上的数比个位上的数大 4,说明十位上的数是 4 + 0 = 4,所以这个两位数是由 4 个十和 0 个一组成的,即 40 。两位数的读法,十位是几就读几十,个位是几就读几,是零则不读。据此解答。本题的解答关键是确定十位和个位上的数分别是多少.\n【详解】由分析可知,一个两位数,十位上的数比个位上的数大 4,个位上的数比 1 小,这个两位数是 40,读作四十。", + "knowledge_points": [ + "100以内数的读,写法", + "100以内数的组成" + ], + "source": "23-24 一年级下·河南南阳·期末" + }, + { + "id": "263", + "unit": "第四单元100以内数的认识3", + "question_type": "填空题", + "difficulty": 0.85, + "question": "一个数由 8 个一, 4 个十组成,这个数是( )。", + "options": [ + + ], + "answer": "48", + "solution": "【分析】一个整数,从右往左依次为个位,十位。几个一就是几,几个十就是几十,然后合起来组数即可.\n【详解】一个数由 8 个一, 4 个十组成,这个数是 48", + "knowledge_points": [ + "100以内数的组成" + ], + "source": "23-24 一年级下·山东临沂·期末" + }, + { + "id": "264", + "unit": "第四单元100以内数的认识3", + "question_type": "填空题", + "difficulty": 0.85, + "question": "接着六十九,写出后面连续的四个数( )()()()。", + "options": [ + + ], + "answer": "七十一;七十二;七十三", + "solution": "【分析】六十九后面连续的四个数,也就是一个一个地数,往后数 4 个即可.\n【详解】接着六十九,写出后面连续的四个数(七十)(七十一) (七十二) (七十三)。", + "knowledge_points": [ + "数 100 以内的数" + ], + "source": "23-24 一年级下·山东临沂·期末" + }, + { + "id": "265", + "unit": "第四单元100以内数的认识3", + "question_type": "填空题", + "difficulty": 0.85, + "question": "3 个十和 4 个一合起来是( ),读作( )。", + "options": [ + + ], + "answer": "34;三十四", + "solution": "【分析】3个十是30,4个一是4,合起来是34。从右往左依次是个位,十位。读数时,从高位读起,十位是几读作几十,个位是几读作几.\n【详解】3个十和4个一合起来是34,读作三十四。", + "knowledge_points": [ + "100以内数的读,写法", + "100以内数的组成" + ], + "source": "23-24 一年级下·四川乐山·期末" + }, + { + "id": "266", + "unit": "第四单元100以内数的认识3", + "question_type": "填空题", + "difficulty": 0.65, + "question": "在括号里填上\"\u003e\" \"\u003c\"或\"=\".\n 18( )8117-9( )91个十( )10个一 12( )2043 + 3( )343个十( )2个十和9个一", + "options": [ + + ], + "answer": "\u003c;\u003c;=;\u003c;\u003e;\u003e", + "solution": "【分析】相同数位,先比较十位,十位大的数大,十位相同比较个位,个位大的数大。有算式的先算出结果再进行比较。十位上是几就读几十,个位上是几就读几.\n【详解】 18 \u003c 81;17 - 9 = 8 , 8 \u003c 9 , 17 - 9 \u003c 9;1个十=10, 10 个一=10, 1 个十=10 个一;12 \u003c 20;43 + 3 = 46, 46 \u003e 34, 43 + 3 \u003e 34;3 个十 = 30, 2个十和 9 个一=29, 30\u003e29, 3 个十\u003e2 个十和 9 个一", + "knowledge_points": [ + "100 以内数的比大小", + "100 以内数的组成" + ], + "source": "22-23 一年级下·江西宜春·期中" + }, + { + "id": "267", + "unit": "第四单元100以内数的认识3", + "question_type": "填空题", + "difficulty": 0.65, + "question": "一个两位数,十位上的数是 4,个位上的数是 9,这个数是( ), 与这个数相邻的两个数分别是( )和( )。", + "options": [ + + ], + "answer": "49;48;50", + "solution": "【分析】一个两位数,左边的数位是十位,右边的数位是个位,与一个数相邻的两个数是数数时排在这个数前面和后面的两个数,据此得出结论即可.\n【详解】根据分析知:一个两位数,十位上的数是 4,个位上的数是 9,这个数是 49,与这个数相邻的两个数分别是 48 和 50。", + "knowledge_points": [ + "100以内数的排序", + "100以内数的组成", + "相邻的数" + ], + "source": "23-24一年级下·湖北孝感·期末" + }, + { + "id": "268", + "unit": "第四单元100以内数的认识3", + "question_type": "填空题", + "difficulty": 0.65, + "question": "在 7, 59, 60, 71 和 100 中,最小的数是( ), ( )比 60 少得多, ( )比 60 大一些, ( )比 60 大得多。", + "options": [ + + ], + "answer": "7;7;71;100", + "solution": "【分析】体会少得多,多得多的意义,比较数的大小,先看位数的多少,位数多的数就大,位数相同,从高位比较,高位上的数大则这个数大,高位上的数相同,就比较下一单位.\n【详解】 7 \u003c 59 \u003c 60 \u003c 71 \u003c 100,在 7, 59, 60, 71 和 100 中,最小的数是 7, 7 比 60 少得多, 71 比 60 大一些, 100 比 60大得多。", + "knowledge_points": [ + "100以内数的比大小", + "数的相对大小关系" + ], + "source": "23-24一年级下·贵州黔西·期末" + }, + { + "id": "269", + "unit": "第四单元100以内数的认识3", + "question_type": "填空题", + "difficulty": 0.65, + "question": "在括号里填上 \"\u003e\" \"\u003c\" 或 \"=\" 。32( )2389( )909-2( )85分( )1元 6( ) 5 + 07+20( )57-30", + "options": [ + + ], + "answer": "\u003e;\u003c;\u003c;\u003c;\u003e;=", + "solution": "【分析】先计算出各个算式的结果,再根据比较数的大小,先看位数的多少,位数多的数就大,位数相同,从高位比较,高位上的数大则这个数大,高位上的数相同,就比较下一位。1元 = 100分.\n【详解】 32 \u003e 23;89 \u003c90;9 - 2 = 7 \u003c 8;5分\u003c1 元;6 \u003e 5 + 0 = 5;7 + 20 = 57 - 30 。", + "knowledge_points": [ + "100 以内数的比大小", + "元,角,分的认识及换算" + ], + "source": "23-24 一年级下·贵州黔西·期末" + }, + { + "id": "270", + "unit": "第四单元100以内数的认识3", + "question_type": "填空题", + "difficulty": 0.85, + "question": "一个两位数,个位上是 9,十位上是 1,这个数是( );56 是由( )个一和( )个十组成的。", + "options": [ + + ], + "answer": "19;6;5", + "solution": "【分析】一个两位数,从右往左依次为个位,十位。十位是几表示几个十,个位是几表示几个一,由此解答.\n【详解】一个两位数,个位上是 9,十位上是 1,这个数是 19;56 是由 6 个一和 5 个十组成的。", + "knowledge_points": [ + "100以内数的组成" + ], + "source": "23-24 一年级下·贵州铜仁·期末" + }, + { + "id": "271", + "unit": "第四单元100以内数的认识3", + "question_type": "填空题", + "difficulty": 0.85, + "question": "59 是由( )个十和( )个一组成的;3个一和6个十合起来是( )。", + "options": [ + + ], + "answer": "5;9;63", + "solution": "【分析】一个两位数,从右往左数,第一位是个位,表示几个一,第二位是十位,表示几个十;几个一就是几,几个十就是几十,然后合起来组数即可.\n【详解】由题意分析得:59是由5个十和9个一组成的;3个一和6个十合起来是63。", + "knowledge_points": [ + "100以内数的组成" + ], + "source": "23-24 一年级下·吉林四平·期末" + }, + { + "id": "272", + "unit": "第四单元100以内数的认识3", + "question_type": "判断题", + "difficulty": 0.85, + "question": "在 38,43,100 中, 38比100少得多,43比38多一些。()", + "options": [ + + ], + "answer": "√", + "solution": "【分析】描述数的大小关系的方法:通过比较具体数,用\"多一些\"\"少一些\"描述相差较小的两个数;用\"多得多\"\"少得多\"描述相差较大的两个数,根据100以内数的相对大小,结合题干要求进行解答即可.\n【详解】据分析可知: 38 比 100 少得多, 43 比 38 多一些。 原题说法正确。故答案为: √", + "knowledge_points": [ + "数的相对大小关系" + ], + "source": "23-24一年级下·陕西安康·期末" + }, + { + "id": "273", + "unit": "第四单元100以内数的认识3", + "question_type": "判断题", + "difficulty": 0.85, + "question": "68 中的 8 比 6 多。", + "options": [ + + ], + "answer": "×", + "solution": "【分析】从右边起第一位是个位,第二位是十位,个位上是几就表示几个一,十位上是几就表示几个十,据此据此结合题干要求进行解答即可.\n【详解】68 中的 8 表示 8 个一, 6 表示 6 个十, 60 比 8 多。 原题说法错误。 故答案为: ×", + "knowledge_points": [ + "100以内数的组成" + ], + "source": "22-23 一年级下·河南驻马店·期末" + }, + { + "id": "274", + "unit": "第四单元100以内数的认识3", + "question_type": "判断题", + "difficulty": 0.85, + "question": "从80数到90,一共数了10个数。( )", + "options": [ + + ], + "answer": "×", + "solution": "【分析】一个一个地数,从 80 数到 90,一共数了 80,81,82,83,84,85,86,87,88,89,90,共 11 个数,据此解答即可.\n【详解】据分析可知:从 80 数到 90,一共数了 11 个数。原题说法错误。故答案为: ×", + "knowledge_points": [ + "数 100 以内的数" + ], + "source": "22-23一年级下·江西吉安·期末" + }, + { + "id": "275", + "unit": "第四单元100以内数的认识3", + "question_type": "判断题", + "difficulty": 0.85, + "question": "50 比 45 多得多。( )", + "options": [ + + ], + "answer": "×", + "solution": "【分析】描述数的大小关系的方法:通过比较具体数,用\"多一些\"\"少一些\"描述相差较小的两个数;用\"多得多\"\"少得多\"描述相差较大的两个数;据此解决此题.\n【详解】由题意分析得:\n50 比 45 相差较小,所以, 50 比 45 多一些;原说法错误。故答案为: ×", + "knowledge_points": [ + "数的相对大小关系" + ], + "source": "22-23一年级下·江西吉安·期末" + }, + { + "id": "276", + "unit": "第四单元100以内数的认识3", + "question_type": "判断题", + "difficulty": 0.85, + "question": "82 中的 \"8\" 在十位上,表示 8 个十。( )", + "options": [ + + ], + "answer": "√", + "solution": "【分析】一个两位数,从右往左数,第一位是个位,个位上的数表示几个一;第二位是十位,十位上的数表示几个十;据此解决.\n【详解】由题意分析得:82 中的 \"8\" 在十位上,表示 8 个十;此说法正确。故答案为: √", + "knowledge_points": [ + "100以内数的组成" + ], + "source": "22-23 一年级下·江西吉安·期末" + }, + { + "id": "277", + "unit": "第四单元100以内数的认识3", + "question_type": "判断题", + "difficulty": 0.85, + "question": "88 这个数中 2 个 8 表示的意义不同。( )", + "options": [ + + ], + "answer": "√", + "solution": "【分析】一个两位数,从右往左数,第一位是个位,个位上的数表示几个一;第二位是十位,十位上的数表示几个十;据此解决.\n【详解】88 这个数中,左边的 8,表示 8 个十,右边的 8,表示 8 个一, 2 个 8 表示的意义不同;原说法正确。故答案为: √", + "knowledge_points": [ + "100以内数的组成" + ], + "source": "22-23一年级下·江西吉安·期末" + }, + { + "id": "278", + "unit": "第四单元100以内数的认识3", + "question_type": "判断题", + "difficulty": 0.65, + "question": "比 30 多 4 的数是34。()", + "options": [ + + ], + "answer": "√", + "solution": "【分析】计算比一个数多几,用这个数加几即可,据此得出结论.\n【详解】 30 + 4 = 34,即比 30 多 4 的数是 34,结论正确。故答案为: √", + "knowledge_points": [ + "整十数加,减一位数" + ], + "source": "23-24 一年级下·河南周口·期末" + }, + { + "id": "279", + "unit": "第四单元100以内数的认识3", + "question_type": "判断题", + "difficulty": 0.85, + "question": "个位上是 5,十位上是 6,这个数是 65。( )", + "options": [ + + ], + "answer": "√", + "solution": "【分析】一个两位数,从右数,第一位是个位,第二位是十位,据此写出此数再进行判断即可.\n【详解】由分析可得,个位上是 5,十位上是 6,这个数是 65 。原题说法正确。故答案为: √", + "knowledge_points": [ + "100以内数的组成" + ], + "source": "23-24 一年级下·河南周口·期末" + }, + { + "id": "280", + "unit": "第四单元100以内数的认识3", + "question_type": "判断题", + "difficulty": 0.85, + "question": "老师请 28 号至 35 号同学上台表演,她一共叫了 8 位同学。( )", + "options": [ + + ], + "answer": "√", + "solution": "【分析】按照 100 以内整数的排序,数一数 28 至 35 一共有多少个数,即可得出老师一共叫了多少位同学.\n【详解】28,29,30,31,32,33,34,35一共有8个数,所以老师一共叫了8位同学。原题说法正确。故答案为: √", + "knowledge_points": [ + "数 100 以内的数" + ], + "source": "22-23一年级下·江西吉安·期末" + }, + { + "id": "281", + "unit": "第四单元100以内数的认识3", + "question_type": "判断题", + "difficulty": 0.85, + "question": "五十七写作 57。( )", + "options": [ + + ], + "answer": "√", + "solution": "【分析】100以内数的读,写法\n【详解】五十七写作57。原题说法正确。故答案为: √", + "knowledge_points": [ + "100以内数的读,写法" + ], + "source": "22-23 一年级下·广东汕尾·期中" + }, + { + "id": "282", + "unit": "第四单元100以内数的认识3", + "question_type": "判断题", + "difficulty": 0.85, + "question": "个位是 3,十位是 8,这个数是 38。( )", + "options": [ + + ], + "answer": "×", + "solution": "【分析】根据题意,从右边起,第一位是个位,第二位是十位。, 两位数的写法,从最高位写起,十位上是几就写几,个位上是几就写几,最高位不能是 0,根据数的组成,十位上是几表示几个十,个位上是几表示几个一,据此解答.\n【详解】根据分析:个位是 3,十位是 8,这个数是 83。原题说法错误。故答案为: ×", + "knowledge_points": [ + "100以内数的读,写法", + "100以内数的组成" + ], + "source": "22-23 一年级下·广东汕尾·期中" + }, + { + "id": "283", + "unit": "第四单元100以内数的认识3", + "question_type": "判断题", + "difficulty": 0.85, + "question": "66 个位上的数和十位上的数表示的意义相同。( )", + "options": [ + + ], + "answer": "×", + "solution": "【分析】一个两位数,从右往左数,第一位是个位,个位上的数表示几个一;第二位是十位,十位上的数表示几个十。据此解答即可.\n【详解】66个位上的数是\"6\",表示6个一,十位上的数也是 \"6\",表示 6 个十,表示的意义不相同。原题说法错误。故答案为: ×", + "knowledge_points": [ + "100以内数的组成" + ], + "source": "22-23 一年级下·广东汕尾·期中" + }, + { + "id": "284", + "unit": "第四单元100以内数的认识3", + "question_type": "判断题", + "difficulty": 0.65, + "question": "最接近 80 的整数只有一个,这个数是81。()", + "options": [ + + ], + "answer": "×", + "solution": "【分析】根据每相邻的两个自然数之间相差1,最接近80的整数,要考虑 80 前后的整数,通过一个个的数数78, 79, 80, 81, 82,可得 80 前面的整数是 79,后面的整数是数是 81.\n【详解】最接近 80 的整数有两个,分别是 79 和 81。故答案为: ×", + "knowledge_points": [ + "100以内数的排序" + ], + "source": "23-24 一年级下·湖南益阳·期末" + }, + { + "id": "285", + "unit": "第四单元100以内数的认识3", + "question_type": "判断题", + "difficulty": 0.85, + "question": "35和53两个数中的\"5\"表示的意义一样。()", + "options": [ + + ], + "answer": "×", + "solution": "【分析】一个两位数,十位上的数表示几个十,个位上的数表示几个一,在数字 35 中,\"5\"位于个位,表示 5 个一。而在数字 53 中,\"5\"位于十位,表示 5 个十。因此,虽然两个数字中都有\"5\",但它们所处的数位不同,表示的意义也不同.\n【详解】由分析可知:在数字 35 中,\"5\"位于个位,表示 5 个一。而在数字 53 中,\"5\"位于十位,表示 5 个十,表示的意义不一样;故答案为: ×", + "knowledge_points": [ + "100以内数的组成" + ], + "source": "22-23 一年级下·新疆喀什·期末" + }, + { + "id": "286", + "unit": "第四单元100以内数的认识3", + "question_type": "判断题", + "difficulty": 0.85, + "question": "一个数从右边起,第二位是十位。( )", + "options": [ + + ], + "answer": "√", + "solution": "【详解】一个数从右边起,第一位是个位,第二位是十位。例如:87,7 在个位,8 在十位。原题说法正确。故答案为: √", + "knowledge_points": [ + "100以内数的组成" + ], + "source": "22-23 一年级下·新疆喀什·期末" + }, + { + "id": "287", + "unit": "第四单元100以内数的认识3", + "question_type": "判断题", + "difficulty": 0.85, + "question": "20个一和2个十一样大。( )", + "options": [ + + ], + "answer": "√", + "solution": "【分析】根据题意,20个一是20;2个十是20,两者相等.\n【详解】20 个一是 20;2 个十是 20,所以 20 个一和 2 个十一样大,原说法正确。故答案为: √", + "knowledge_points": [ + "20以内数的组成" + ], + "source": "23-24 一年级下·湖南郴州·期末" + }, + { + "id": "288", + "unit": "第四单元100以内数的认识3", + "question_type": "判断题", + "difficulty": 0.85, + "question": "我们学校的学生人数比我们班的学生人数少得多。()", + "options": [ + + ], + "answer": "×", + "solution": "【分析】比较两个数的多少时,如果两个数的大小比较接近,就说大数比小数多一些,或小数比大数少一些;如果两个数的大小相差很多,就说大数比小数多得多,或小数比大数少得多。学校有很多班,人数应该比一个班的人数多得多,由此解答.\n【详解】由分析可知,我们学校的学生人数比我们班的学生人数多得多。原题说法错误。故答案为: ×", + "knowledge_points": [ + "数的相对大小关系" + ], + "source": "23-24 一年级下·河南南阳·期末" + }, + { + "id": "289", + "unit": "第四单元100以内数的认识3", + "question_type": "判断题", + "difficulty": 0.85, + "question": "比 20 大得多,比 100 小的数是 22。( )", + "options": [ + + ], + "answer": "×", + "solution": "【分析】比较两个数的多少时,如果两个数的大小比较接近,就说大数比小数多一些,或小数比大数少一些;如果两个数的大小相差很多,就说大数比小数多得多,或小数比大数少得多。由此解答.\n【详解】由分析可知, 22 比 20 大一些, 22 比 100 小的多。 原题说法错误。故答案为: ×", + "knowledge_points": [ + "100以内数的比大小", + "数的相对大小关系" + ], + "source": "23-24 一年级下·山东临沂·期末" + }, + { + "id": "290", + "unit": "第四单元100以内数的认识3", + "question_type": "判断题", + "difficulty": 0.85, + "question": "九十三写作 903。( )", + "options": [ + + ], + "answer": "×", + "solution": "【分析】一个整数,从右往左依次为个位,十位写数时从高位写起,几十就在十位写几,几就在个位写几,哪一位上一个也没有就写 0 占位,由此解答.\n【详解】由分析可知,九十三写作 93,原题说法错误。故答案为: ×", + "knowledge_points": [ + "100以内数的读,写法" + ], + "source": "23-24 一年级下·山东临沂·期末" + }, + { + "id": "291", + "unit": "第四单元100以内数的认识3", + "question_type": "判断题", + "difficulty": 0.85, + "question": "一个数个位上是 8,十位上是比 8 小 3 的数,这个数是 83。( )", + "options": [ + + ], + "answer": "×", + "solution": "【分析】一个两位数,从右往左依次为个位,十位。个位上是 8,十位上的数 = 个位上的数 -3,再由此写出数字即可.\n【详解】 8 - 3 = 5,十位是 5 。一个数个位上是 8,十位上是比 8 小 3 的数,这个数是 58 。原题说法错误。故答案为: ×", + "knowledge_points": [ + "100以内数的组成" + ], + "source": "23-24 一年级下·山东临沂·期末" + }, + { + "id": "292", + "unit": "第四单元100以内数的认识3", + "question_type": "判断题", + "difficulty": 0.65, + "question": "一个一个地数, 67后面的第5个数是72。( )", + "options": [ + + ], + "answer": "√", + "solution": "【分析】一个一个地数, 67 后面的第 1 个数是 68,第 2 个数是 69,第 3 个数是 70,第 4 个数是 71,第 5 个数是 72, 。, 据此得出结论即可.\n【详解】根据分析知:一个一个地数,67 后面的第 5 个数是 72,说法正确。故答案为: √", + "knowledge_points": [ + "数 100 以内的数" + ], + "source": "23-24一年级下·湖北孝感·期末" + }, + { + "id": "293", + "unit": "第四单元100以内数的认识3", + "question_type": "判断题", + "difficulty": 0.65, + "question": "一个一个地数, 31 的前一个数是 21。( )", + "options": [ + + ], + "answer": "×", + "solution": "【分析】相邻的两个数相差 1,所以 31 前面的数比 31 少 1,所以应该是 31 - 1 = 30,据此解答即可.\n【详解】 31 - 1 = 30,一个一个地数, 31 的前一个数是 30,原题说法错误。故答案为: ×", + "knowledge_points": [ + "100以内数的排序" + ], + "source": "23-24 一年级下·贵州黔西·期末" + }, + { + "id": "294", + "unit": "第四单元100以内数的认识3", + "question_type": "判断题", + "difficulty": 0.85, + "question": "与 78 相邻的两个数是 76 和 77。( )", + "options": [ + + ], + "answer": "×", + "solution": "【分析】一个一个地数一数,即可知道与 78 相邻的两个数分别是多少.\n【详解】由题意分析得: 76, 77, 78, 79, 80;即,与 78 相邻的两个数是 77 和 79;原说法错误。故答案为: ×", + "knowledge_points": [ + "100以内数的排序", + "相邻的数" + ], + "source": "22-23一年级下·甘肃天水·期中" + }, + { + "id": "295", + "unit": "第四单元100以内数的认识3", + "question_type": "判断题", + "difficulty": 0.85, + "question": "38 后面的第 5 个数是 43 ( )", + "options": [ + + ], + "answer": "√", + "solution": "【分析】从 38 开始,一个一个地数一数,数出 38 后面的第 5 个数,即可知道是哪个数;据此解决.\n【详解】由题意分析得:38,39,40,41,42,43;即,38后面的第5个数是43;此说法正确。故答案为: √", + "knowledge_points": [ + "数 100 以内的数" + ], + "source": "22-23 一年级下·甘肃天水·期中" + }, + { + "id": "296", + "unit": "第四单元100以内数的认识3", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式计算.\n![](images/00b257323a797753221159767dee2ba12b35286601f375ea38166cbb745386a2.jpg)\n![](images/0c099114edc172aedaa824a37d3bcaf7823973b95b5994934cce10e344838026.jpg)", + "options": [ + + ], + "answer": "2 + 20 = 22", + "solution": "【分析】左边有 2 棵白菜,右边有 20 棵白菜,求一共有多少棵白菜,根据加法的意义,左边的数量 + 右边的数量 = 总数量.\n【详解】 2 + 20 = 22(棵)一共有 22 棵白菜。", + "knowledge_points": [ + "图文问题", + "整十数加,减一位数" + ], + "source": "23-24 一年级下·甘肃平凉·期末" + }, + { + "id": "297", + "unit": "第四单元100以内数的认识3", + "question_type": "解答题", + "difficulty": 0.65, + "question": "写一写,读一读,画一画.\n![](images/501730b820bb357ecdf87df4c3e8d551.png)", + "options": [ + + ], + "answer": "48;四十八;62;六十二;画图见详解;一百", + "solution": "【分析】4 捆小棒表示 4 个十, 8 根小棒表示 8 个一,这个数是 48;计数器的十位上有 6 颗珠子,表示 6 个十,个位上有 2 颗珠子,表示 2 个一,这个数是 62;在计数器的百位上画 1 颗珠子,表示 1 个百是 100;读数时,十位上是几就读几十,个位上是几就读几.\n【详解】![](images/cc526103315bff10dcd97a5a339181ec.png)", + "knowledge_points": [ + "100以内数的读,写法", + "100以内数的组成" + ], + "source": "23-24一年级下·河北廊坊·期末" + }, + { + "id": "298", + "unit": "第四单元100以内数的认识3", + "question_type": "解答题", + "difficulty": 0.65, + "question": "小芳有文艺书 20 本,科普书 8 本,两种书一共有多少本。", + "options": [ + + ], + "answer": "28 本", + "solution": "【分析】文艺书的本数加上科普书的本数即可.\n【详解】 20 + 8 = 28 (本) 答:两种书一共有 28 本。", + "knowledge_points": [ + "整十数加,减一位数" + ], + "source": "22-23一年级下·江西宜春·期中" + }, + { + "id": "299", + "unit": "第四单元100以内数的认识3", + "question_type": "填空题", + "difficulty": 0.65, + "question": "49 添上 1 是( )个十,10个十是( )。", + "options": [ + + ], + "answer": "5100或一百", + "solution": "【分析】添就是加的意思, 49 + 1 = 50,几十就有几个十, 50 是 5 个十;10 个十是一百.\n【详解】49 添上 1 是 5 个十, 10 个十是一百。", + "knowledge_points": [ + "100以内数的组成" + ], + "source": "23-24 一年级下·湖南张家界·期末" + }, + { + "id": "300", + "unit": "第四单元100以内数的认识3", + "question_type": "填空题", + "difficulty": 0.65, + "question": "在 79,97,72,27这四个数中,最接近 80 的数是( ), 个位上是 7 的数是( )和( )。", + "options": [ + + ], + "answer": "79;97;27", + "solution": "【分析】两个数的差越小,表示这两个越接近;79 与 80 的差是 1,相差最小,即,这些数中,最接近 80 的数是 79。一个两位数,从右往左数,第一位是个位,第二位是十位;据此解决.\n【详解】由题意分析得:在 79,97,72,27 这四个数中,最接近 80 的数是 79,个位上是 7 的数是 97 和 27。", + "knowledge_points": [ + "100以内数的排序", + "100以内数的组成" + ], + "source": "23-24 一年级下·广东汕头·期末" + }, + { + "id": "301", + "unit": "第四单元100以内数的认识4", + "question_type": "选择题", + "difficulty": 0.85, + "question": "小明有 30 枚邮票,小红的邮票比他多一些,小红可能有 ( ) 枚邮票。", + "options": [ + "A. 26", + "B. 38", + "C. 67" + ], + "answer": "B", + "solution": "【分析】比较两个数的多少时,如果两个数的大小比较接近,就说大数比小数多一些,或小数比大数少一些;如果两个数的大小相差很多,就说大数比小数多得多,或小数比大数少得多。由此找出比30多一些的数即可.\n【详解】A。 26比30少一些,不符合题意;B. 38 比 30 多一些,符合题意;C. 67 比 30 多得多,不符合题意。小红可能有 38 枚邮票。故答案为: B", + "knowledge_points": [ + "数的相对大小关系" + ], + "source": "22-23一年级下·江西宜春·期中" + }, + { + "id": "302", + "unit": "第四单元100以内数的认识4", + "question_type": "选择题", + "difficulty": 0.65, + "question": "如图是百数表的一部分, ☆表示多少。 ( )\n\u003ctable\u003e\u003ctr\u003e\u003ctd\u003e35\u003c/td\u003e\u003ctd\u003e36\u003c/td\u003e\u003ctd\u003e37\u003c/td\u003e\u003ctd\u003e38\u003c/td\u003e\u003ctd\u003e39\u003c/td\u003e\u003c/tr\u003e\u003ctr\u003e\u003ctd\u003e45\u003c/td\u003e\u003ctd\u003e\u003c/td\u003e\u003ctd\u003e\u003c/td\u003e\u003ctd\u003e\u003c/td\u003e\u003ctd\u003e\u003c/td\u003e\u003c/tr\u003e\u003ctr\u003e\u003ctd\u003e55\u003c/td\u003e\u003ctd\u003e\u003c/td\u003e\u003ctd\u003e\u003c/td\u003e\u003ctd\u003e☆\u003c/td\u003e\u003ctd\u003e\u003c/td\u003e\u003c/tr\u003e\u003c/table\u003e", + "options": [ + "A. 40", + "B. 48", + "C. 58" + ], + "answer": "C", + "solution": "【分析】百数表中,上下相邻的两个数相差 10,左右相邻的两个数相差 1。本题考查百数表,掌握百数表的数的规律和数的顺序.\n【详解】35 + 10 = 45,45 + 10 = 55,55 + 1 = 56,56 + 1 = 57,57 + 1 = 58。☆表示 58。故答案为: C", + "knowledge_points": [ + "百数表" + ], + "source": "23-24 一年级下·江苏徐州·期末" + }, + { + "id": "303", + "unit": "第四单元100以内数的认识4", + "question_type": "选择题", + "difficulty": 0.85, + "question": "十位上是 6 的两位数有 ( ) 个。", + "options": [ + "A. 8", + "B. 10", + "C. 9" + ], + "answer": "B", + "solution": "【分析】一个两位数,从左往右数,第一位是个位,第二位是十位;据此列举出十位上是 6 的两位数即可解决.\n【详解】十位上是 6 的两位数有: 60,61,62,63,64,65,66,67,68,69,共10个。故答案为: B", + "knowledge_points": [ + "100以内数的组成" + ], + "source": "23-24 一年级下·黑龙江哈尔滨·期末" + }, + { + "id": "304", + "unit": "第四单元100以内数的认识4", + "question_type": "选择题", + "difficulty": 0.85, + "question": "红花有 89 朵,紫花比红花少得多。紫花可能有 ( )。", + "options": [ + "A. 25 朵", + "B. 87 朵", + "C. 90 朵" + ], + "answer": "A", + "solution": "【分析】比较两个数的多少时,如果两个数的大小比较接近,就说大数比小数多一些,或小数比大数少一些;如果两个数的大小相差很多,就说大数比小数多得多,或小数比大数少得多。由此找出比 89 少得多的数即可.\n【详解】A。25比89少得多;B. 87 比 89 少一些;C. 90 比 89 多一些。紫花可能有25朵。故答案为: A", + "knowledge_points": [ + "数的相对大小关系" + ], + "source": "23-24 一年级下·黑龙江哈尔滨·期末" + }, + { + "id": "305", + "unit": "第四单元100以内数的认识4", + "question_type": "选择题", + "difficulty": 0.85, + "question": "下面 ( ) 中的 \u00276\u0027表示 6 个十。", + "options": [ + "A. 6", + "B. 63", + "C. 56" + ], + "answer": "B", + "solution": "【分析】一个整数,从右往左依次为个位,十位,十位是几表示几个十,个位是几表示几个一,由此解答.\n【详解】A。 6在个位,表示6个一;B. 63 中的 \u00276\u0027在十位,表示 6 个十;C. 56 中的 \u00276\u0027 在个位,表示 6 个一。63 中的 \u00276\u0027 表示 6 个十故答案为: B", + "knowledge_points": [ + "100以内数的组成" + ], + "source": "23-24 一年级下·贵州铜仁·期末" + }, + { + "id": "306", + "unit": "第四单元100以内数的认识4", + "question_type": "选择题", + "difficulty": 0.85, + "question": "小华有 56 本课外书,小轩有 27 本课外书,小敏有 9 本课外书,小华的课外书比小敏的课外书()。", + "options": [ + "A. 多得多", + "B. 多一些", + "C. 少得多" + ], + "answer": "A", + "solution": "【分析】比较两个数的多少时,如果两个数的大小比较接近,就说大数比小数多一些,或小数比大数少一些;如果两个数的大小相差很多,就说大数比小数多得多,或小数比大数少得多。由此解答.\n【详解】56比9多得多,也就是小华的课外书比小敏的课外书多得多。故答案为: A", + "knowledge_points": [ + "数的相对大小关系" + ], + "source": "23-24 一年级下·贵州铜仁·期末" + }, + { + "id": "307", + "unit": "第四单元100以内数的认识4", + "question_type": "选择题", + "difficulty": 0.85, + "question": "下面各数中的 \u00273\u0027与 \u002734\u0027中 \u00273\u0027表示的意义相同的是 ( )。", + "options": [ + "A. 3", + "B. 31", + "C. 53" + ], + "answer": "B", + "solution": "【分析】100 以内的整数,从右往左数,第一位是个位,表示几个一;第二位是十位,表示几个十;第三位是百位,表示几个百;据此解决.\n【详解】\u002734\u0027中\u00273\u0027表示3个十;A. \u00273\u0027表示 3 个一;B. \u002731\u0027中 \u00273\u0027表示 3 个十;C. \u002753\u0027中 \u00273\u0027表示 3 个一;即,\u002731\u0027中的\u00273\u0027与\u002734\u0027中\u00273\u0027表示的意义相同。故答案为: B", + "knowledge_points": [ + "100以内数的组成" + ], + "source": "23-24 一年级下·四川南充·期末" + }, + { + "id": "308", + "unit": "第四单元100以内数的认识4", + "question_type": "选择题", + "difficulty": 0.85, + "question": "妈妈买了 25 个草莓,买的蓝莓的个数比草莓多得多,蓝莓可能有 ( ) 个。", + "options": [ + "A. 10", + "B. 32", + "C. 78" + ], + "answer": "C", + "solution": "【分析】比较两个数的多少时,如果两个数的大小比较接近,就说大数比小数多一些,或小数比大数少一些;如果两个数的大小相差很多,就说大数比小数多得多,或小数比大数少得多。由此找出比 25 多得多的数.\n【详解】A。 10比25少得多;B. 32 比 25 多一些;C. 78 比 25 多得多。蓝莓可能有 78 个。故答案为: C", + "knowledge_points": [ + "数的相对大小关系" + ], + "source": "23-24 一年级下·四川南充·期末" + }, + { + "id": "309", + "unit": "第四单元100以内数的认识4", + "question_type": "选择题", + "difficulty": 0.85, + "question": "二年级植树 95 棵,一年级比二年级少一些,一年级可能植树 ( ) 棵。", + "options": [ + "A. 50", + "B. 100", + "C. 90" + ], + "answer": "C", + "solution": "【分析】比较两个数的多少时,如果两个数的大小比较接近,就说大数比小数多一些,或小数比大数少一些;如果两个数的大小相差很多,就说大数比小数多得多,或小数比大数少得多。由此找出比95少一些的数即可.\n【详解】A。50比95少得多;B. 100 比 95 多一些;C. 90 比 95 少一些。一年级可能植树90棵。故答案为: C", + "knowledge_points": [ + "数的相对大小关系" + ], + "source": "23-24 一年级下·吉林四平·期末" + }, + { + "id": "310", + "unit": "第四单元100以内数的认识4", + "question_type": "选择题", + "difficulty": 0.85, + "question": "下面三个数中, ( ) 比 20 大,比 25 小。", + "options": [ + "A. 16", + "B. 23", + "C. 45" + ], + "answer": "B", + "solution": "【分析】整数比较大小方法: ①位数多的数大于位数少的数;②位数相同的,先比较最高位上的数,最高位上大的,数就大,最高位数相同的,就比较下一位,以此类推。据此找出比 20 大,比 25 小的数即可.\n【详解】A。 16 \u003c 20,不符合题意;B. 20 \u003c 23 \u003c 25,符合题意;C. 45 \u003e 25,不符合题意;即,23比20大,比25小。故答案为: B", + "knowledge_points": [ + "100以内数的比大小" + ], + "source": "23-24 一年级下·吉林四平·期末" + }, + { + "id": "311", + "unit": "第四单元100以内数的认识4", + "question_type": "选择题", + "difficulty": 0.85, + "question": "用 ![f37319d11afc5054bcfb62f3fc701dcf](imagesf37319d11afc5054bcfb62f3fc701dcf.png)表示1,用 ![](images/6fbcd67dfa1ffc64de5281b595aeb26607dc19621ef4739c2558a2764214d9e8.jpg) 表示 10, ![](images/a4c3b82652c2f5c4ed07714a401c3c0c075449bec3820555a7dde464e99417d4.jpg) 表示()。", + "options": [ + "A. 32", + "B. 23", + "C. 62" + ], + "answer": "A", + "solution": "【分析】由题意可知,有 3 个十和 2 个一。3 个十是 30 , 2 个一是 2,合起来是 32,由此解答.\n【详解】用 表示1,用 表示10,上图表示32。![](images/10fb985659278e605c11fda95732a68ab0055e8b06a3d70d3afa731ca30d34fb.jpg)故答案为:A", + "knowledge_points": [ + "100以内数的组成" + ], + "source": "23-24一年级下·广东深圳·期末" + }, + { + "id": "312", + "unit": "第四单元100以内数的认识4", + "question_type": "选择题", + "difficulty": 0.65, + "question": "李大爷家养鸭 48 只,养鸡 6 只,鸭的只数比鸡 ( )。", + "options": [ + "A. 多一些", + "B. 多得多", + "C. 少得多" + ], + "answer": "B", + "solution": "【分析】鸭有48只,鸡有6只,两位数大于一位数,可以知道鸭比鸡多,用鸭的数量减去鸡的数量,可以知道是多得多.\n【详解】鸭有 48 只,鸡有 6 只, 48 - 6 = 42 (只), 鸭比鸡多 42 只,鸭的只数比鸡多得多。 A. 鸭的只数比鸡多一些,错误;B. 鸭的只数比鸡多得多,正确;C. 鸭的只数比鸡少得多,错误。故答案为: B", + "knowledge_points": [ + "数的相对大小关系" + ], + "source": "23-24 一年级下·广东汕头·期末" + }, + { + "id": "313", + "unit": "第四单元100以内数的认识4", + "question_type": "选择题", + "difficulty": 0.85, + "question": "比 70 大,比 80 小,个位上是 6 的数是 ( )。", + "options": [ + "A. 66", + "B. 76", + "C. 75" + ], + "answer": "B", + "solution": "【分析】一个两位数,从右往左数,第一位是个位,第二位是十位;整数比较大小方法: ①位数多的数大于位数少的数;②位数相同的,先比较最高位上的数,最高位上大的,数就大,最高位数相同的,就比较下一位,以此类推;据此解决此题.\n【详解】A。 66 \u003c 70,不符合题意;B. 70 \u003c 76 \u003c 80,且 76 的个位上是 6,符合题意;C. 70 \u003c 75 \u003c 80,但 75 的个位上不是 6,不符合题意;即,比 70 大,比 80 小,个位上是 6 的数是 76。故答案为: B", + "knowledge_points": [ + "100以内数的比大小", + "100以内数的组成" + ], + "source": "23-24 一年级下·山东济南·期末" + }, + { + "id": "314", + "unit": "第四单元100以内数的认识4", + "question_type": "选择题", + "difficulty": 0.85, + "question": "丽丽的爸爸今年 37 岁,兰兰的爸爸和他岁数差不多,兰兰的爸爸今年不可能 ( ) 岁。", + "options": [ + "A. 39", + "B. 35", + "C. 28" + ], + "answer": "C", + "solution": "【分析】根据数的相对大小可知:比较两个数的多少时,如果两个数的大小比较接近,可说两者差不多,也可说大数比小数多一些,或小数比大数少一些;如果两个数的大小相差很多,就说大数比小数多得多,或小数比大数少得多。兰兰的爸爸和丽丽的爸爸岁数差不多,也就是找到比37相差多的数.\n【详解】A。 39比37多一些,不符合题意;B. 35 比 37 少一些,不符合题意;C. 28 比 37 少得多,符合题意。故答案为: C", + "knowledge_points": [ + "数的相对大小关系" + ], + "source": "23-24一年级下·新疆克拉玛依·期末" + }, + { + "id": "315", + "unit": "第四单元100以内数的认识4", + "question_type": "选择题", + "difficulty": 0.85, + "question": "十位上是 3,个位上是 2,这个数是 ( )。", + "options": [ + "A. 23", + "B. 32", + "C. 6" + ], + "answer": "B", + "solution": "【分析】一个两位数,从右往左数,第一位是个位,第二位是十位;据此组数.\n【详解】由题意分析得:十位上是 3,个位上是 2,这个数是 32 。故答案为: B", + "knowledge_points": [ + "100以内数的组成" + ], + "source": "23-24 一年级下·广东汕头·期末" + }, + { + "id": "316", + "unit": "第四单元100以内数的认识4", + "question_type": "选择题", + "difficulty": 0.85, + "question": "一个一个地数, 49后面的数是 ( )", + "options": [ + "A. 48", + "B. 50", + "C. 51" + ], + "answer": "B", + "solution": "【分析】一个一个地数,也就是后面的数比前面的数大 1。依次为 1, 2, 3。48, 49, 50。由此找到符合题意的数即可.\n【详解】一个一个地数,49后面的数是 50 。故答案为: B", + "knowledge_points": [ + "数 100 以内的数" + ], + "source": "23-24一年级下·广东汕头·期末" + }, + { + "id": "317", + "unit": "第四单元100以内数的认识4", + "question_type": "选择题", + "difficulty": 0.85, + "question": "50个草莓正好装满一篮,如果用这个篮子放梨,能放多少个。 ( )", + "options": [ + "A. 比 50 少一些", + "B. 比 50 多一些", + "C. 比 50 少得多" + ], + "answer": "C", + "solution": "【分析】比较两个数的多少时,如果两个数的大小比较接近,就说大数比小数多一些,或小数比大数少一些;如果两个数的大小相差很多,就说大数比小数多得多,或小数比大数少得多。根据生活经验可知,梨比草莓大得多,所以篮子放梨的个数就比草莓的个数少得多.\n【详解】由分析可知,如果用这个篮子放梨,能放的个数比 50 少得多。故答案为: C", + "knowledge_points": [ + "数的相对大小关系" + ], + "source": "23-24一年级下·广西玉林·期末" + }, + { + "id": "318", + "unit": "第四单元100以内数的认识4", + "question_type": "选择题", + "difficulty": 0.65, + "question": "一个两位数,个位上的数字是 6,这个数可能是 ( )。", + "options": [ + "A. 6", + "B. 60", + "C. 66" + ], + "answer": "C", + "solution": "【分析】一个两位数从右边起,第一位是个位,第二位是十位,据此解答.\n【详解】A。 6是一位数;B. 60 的十位上是 6;C. 66 的十位数字,个位数字都是 6;故答案为: C", + "knowledge_points": [ + "100以内数的组成" + ], + "source": "23-24 一年级下·浙江嘉兴·期末" + }, + { + "id": "319", + "unit": "第四单元100以内数的认识4", + "question_type": "选择题", + "difficulty": 0.85, + "question": "红球有 55 个,黄球比红球多得多,黄球可能是 ( )。", + "options": [ + "A. 99", + "B. 13", + "C. 60" + ], + "answer": "A", + "solution": "【分析】比较两个数的多少时,如果两个数的大小比较接近,就说大数比小数多一些,或小数比大数少一些;如果两个数的大小相差很多,就说大数比小数多得多,或小数比大数少得多。由此找出比 55 多得多的数.\n【详解】A。 99比55多得多;B. 13 比 55 少得多;C. 60 比 55 多一些。黄球可能有 99 个。故答案为: A", + "knowledge_points": [ + "数的相对大小关系" + ], + "source": "23-24 一年级下·浙江嘉兴·期末" + }, + { + "id": "320", + "unit": "第四单元100以内数的认识4", + "question_type": "选择题", + "difficulty": 0.85, + "question": "下面的数最接近 70 的是 ( )。", + "options": [ + "A. 6个十和9个一", + "B. 72", + "C. 7 个一和1个十" + ], + "answer": "A", + "solution": "【分析】几个十就是几十,几个一就是几;先组数,然后找出与 70 相差最小的;两数差越小,表示两数越最接近;据此解决.\n【详解】A。 6个十和9个一是69,69与70是相邻的两个数,69与70相差1;B. 72 与 70 中间隔着 71, 72 与 70 相差 2;C. 7 个一和 1 个十是 17, 17 接近 20, 20 与 70 相差 50,那么 17 与 70 相差 50 多;1 \u003c 2 \u003c 50,即,最接近 70 的是 (6 个十和 9 个一)。故答案为: A", + "knowledge_points": [ + "100以内数的比大小", + "100以内数的排序", + "100以内数的组成", + "100以内数加减法的估算" + ], + "source": "23-24 一年级下·浙江宁波·期末" + }, + { + "id": "321", + "unit": "第四单元100以内数的认识4", + "question_type": "选择题", + "difficulty": 0.85, + "question": "一只青蛙吃的虫子比 25 只多得多,它可能吃了 ( ) 只虫子。", + "options": [ + "A. 24", + "B. 30", + "C. 80" + ], + "answer": "C", + "solution": "【分析】描述数的大小关系的方法:通过比较具体数,用\u0027多一些\u0027\u0027少一些\u0027描述相差较小的两个数;用\u0027多得多\u0027\u0027少得多\u0027描述相差较大的两个数。据此找出比25多得多的数,即可解决.\n【详解】A。 24比25少一些;B. 30 比 25 多一些;C. 80 比 25 多得多;即,一只青蛙吃的虫子比 25 只多得多,它可能吃了 80 只虫子。故答案为: C", + "knowledge_points": [ + "数的相对大小关系" + ], + "source": "23-24 一年级下·广东汕头·期末" + }, + { + "id": "322", + "unit": "第四单元100以内数的认识4", + "question_type": "选择题", + "difficulty": 0.65, + "question": "在用计数器计算\u002784-50\u0027时,拨出\u002784\u0027后,要从十位上拨走()颗珠子。", + "options": [ + "A. 4", + "B. 5", + "C. 8" + ], + "answer": "B", + "solution": "【分析】84-50,减去50,就是减去5个十,十位上5颗珠子表示5个十,要从十位上拨走5颗珠子.\n【详解】在用计数器计算 \u002784-50\u0027时,拨出 \u002784\u0027后,要从十位上拨走 5 颗珠子。故答案为: B", + "knowledge_points": [ + "100以内数的组成" + ], + "source": "23-24一年级下·广东广州·期末" + }, + { + "id": "323", + "unit": "第四单元100以内数的认识4", + "question_type": "选择题", + "difficulty": 0.85, + "question": "明明有 76 本科技书,丽丽的科技书比明明少一些,丽丽可能有 ( ) 本科技书。", + "options": [ + "A. 60", + "B. 71", + "C. 79" + ], + "answer": "B", + "solution": "【分析】比较两个数的多少时,如果两个数的大小比较接近,就说大数比小数多一些,或小数比大数少一些;如果两个数的大小相差很多,就说大数比小数多得多,或小数比大数少得多。由此找出比 76 少一些的数即可.\n【详解】A。 60比76少得多,不符合题意;B. 71 比 76 少一些,符合题意;C. 79 比 76 多一些,不符合题意。丽丽可能有 71 本科技书故答案为: B", + "knowledge_points": [ + "数的相对大小关系" + ], + "source": "23-24 一年级下·广东广州·期末" + }, + { + "id": "324", + "unit": "第四单元100以内数的认识4", + "question_type": "选择题", + "difficulty": 0.65, + "question": "用 4,5,6 这三个数可以组成 ( ) 个不同的两位数。", + "options": [ + "A. 9", + "B. 7", + "C. 3", + "D. 6" + ], + "answer": "D", + "solution": "【分析】首先应确定该两位数十位上的数字,根据此题十位数可以是 4,5,6,当十位数是 4 时,可以组成 45,46,当十位数是 5 时,可以组成 54,56,当十位数是 6 时,可以组成 64,65,因此这三个数可以组成 45,46,54,56,64,65,共可以组成 6 组不同的两位数。解答此题在列举这些两位数时,要按照一定的顺序写,不要重复写或者漏写.\n【详解】用4,5,6三个数可以组成 45,46,54,56,64,65,一共可以组成 6 组不同的两位数。故答案为:D", + "knowledge_points": [ + "搭配问题", + "100以内数的组成" + ], + "source": "23-24一年级下·广东肇庆·期末" + }, + { + "id": "325", + "unit": "第四单元100以内数的认识4", + "question_type": "选择题", + "difficulty": 0.85, + "question": "个位上是 1 的两位数一共有 ( ) 个。", + "options": [ + "A. 7", + "B. 8", + "C. 9", + "D. 10" + ], + "answer": "C", + "solution": "【分析】一个两位数,从右往左数,第一位是个位,第二位是十位;把个位上是 1 的两位数一一列举出来,然后数一数,即可解决.\n【详解】由题意分析得:个位上是 1 的两位数有: 11,21,31,41,51,61,71,81,91,一共有 9 个;故答案为: C", + "knowledge_points": [ + "100以内数的组成" + ], + "source": "23-24 一年级下·广东肇庆·期末" + }, + { + "id": "326", + "unit": "第四单元100以内数的认识4", + "question_type": "选择题", + "difficulty": 0.85, + "question": "![](images/70d1736acef1162cfcf21698d004dfefa6e6b1aa6b11cfd03674d4c275b724d1.jpg) 的价格比 40元多得多,书包得价格可能是()元。", + "options": [ + "A. 35元", + "B. 45 元", + "C. 75 元" + ], + "answer": "C", + "solution": "【分析】描述数的大小关系的方法:通过比较具体数,用\u0027多一些\u0027\u0027少一些\u0027描述相差较小的两个数;用\u0027多得多\u0027\u0027少得多\u0027描述相差较大的两个数。据此找出比40元多得多的价钱,即可解决.\n【详解】A。 35元比40元少一些;B. 45 元比 40 元多一些;C. 75 元比 40 元多得多;即,书包的价格可能是 75 元。故答案为: C", + "knowledge_points": [ + "数的相对大小关系" + ], + "source": "23-24一年级下·江西九江·期末" + }, + { + "id": "327", + "unit": "第四单元100以内数的认识4", + "question_type": "选择题", + "difficulty": 0.85, + "question": "从 68 数到 75,一共数了 ( ) 个数。", + "options": [ + "A. 7", + "B. 8", + "C. 9" + ], + "answer": "B", + "solution": "【分析】根据题意,从 68 数到 75,包括 68 和 75,依次为 68,69,70,71,72,73,74,75,由此解答.\n【详解】由分析可知,从 68 数到 75,一共数了 8 个数。故答案为: B", + "knowledge_points": [ + "数 100 以内的数" + ], + "source": "23-24一年级下·山东菏泽·期末" + }, + { + "id": "328", + "unit": "第四单元100以内数的认识4", + "question_type": "选择题", + "difficulty": 0.85, + "question": "一本漫画书的价格比 40 元少得多,它的价格可能是 ( )。", + "options": [ + "A. 45元", + "B. 90元", + "C. 11元" + ], + "answer": "C", + "solution": "【分析】描述数的大小关系的方法:通过比较具体数,用\u0027多一些\u0027\u0027少一些\u0027描述相差较小的两个数;用\u0027多得多\u0027 \u0027少得多\u0027描述相差较大的两个数。据此找到比40元少得多的钱数,即可解决.\n【详解】A。 45元比40元多一些;B. 90 元比 40 元多得多;C. 11元比40元少得多;即,一本漫画书的价格比 40 元少得多,它的价格可能是 11 元。故答案为: C", + "knowledge_points": [ + "数的相对大小关系" + ], + "source": "23-24 一年级下·山东菏泽·期末" + }, + { + "id": "329", + "unit": "第四单元100以内数的认识4", + "question_type": "选择题", + "difficulty": 0.85, + "question": "下面的两位数中,个位上的数字比十位上的数字大 3 的数是 ( )。", + "options": [ + "A. 36", + "B. 63", + "C. 33" + ], + "answer": "A", + "solution": "【分析】一个两位数,从右往左数,第一位是个位,第二位是十位;据此找出个位上的数字比十位上的数字大 3 的数,即可解决.\n【详解】A。 36个位是6,十位是3, 6 \u003e 3 , 6 - 3 = 3,个位上的数字比十位上的数字大3,符合题意;B. 63 个位是 3,十位是 6, 3 \u003c 6,个位上的数字比十位上的数字小,不符合题意;C. 33 个位是 3,十位是 3, 3 = 3,个位上的数字比十位上的数字相等,不符合题意;即,个位上的数字比十位上的数字大 3 的数是 36。故答案为: A", + "knowledge_points": [ + "7 以内数的比大小", + "100 以内数的组成", + "6 的加减法" + ], + "source": "23-24 一年级下·山东菏泽·期末" + }, + { + "id": "330", + "unit": "第四单元100以内数的认识4", + "question_type": "选择题", + "difficulty": 0.85, + "question": "我们已经认识的数中,比 30 大,比 40 小的数,一共有 ( ) 个。", + "options": [ + "A. 8", + "B. 9", + "C. 10" + ], + "answer": "B", + "solution": "【分析】根据题意,比 30 大,比 40 小的数,也就是它们之间的数,有 31, 32, 33, 34, 35, 36, 37, 38, 39,由此解答.\n【详解】由分析可知,比 30 大,比 40 小的数,一共有 9 个。故答案为: B.", + "knowledge_points": [ + "数 100 以内的数", + "100 以内数的比大小" + ], + "source": "23-24 一年级下·山东菏泽·期末" + }, + { + "id": "331", + "unit": "第四单元100以内数的认识4", + "question_type": "选择题", + "difficulty": 0.65, + "question": "一个数在 40 和 50 之间,而且个位上的数字比十位上的数字大 3,这个数是 ( )。", + "options": [ + "A. 74", + "B. 53", + "C. 47" + ], + "answer": "C", + "solution": "【分析】一个数在 40 和 50 之间,则这个数十位上的数是 4,个位上数字比十位上的数字大3,也就是7,这个数是 47,据此得出结论即可.\n【详解】根据分析知:一个数在 40 和 50 之间,而且个位上的数字比十位上的数字大 3,这个数是 47 。故答案为: C", + "knowledge_points": [ + "100以内数的排序", + "100以内数的组成" + ], + "source": "23-24一年级下·山东菏泽·期末" + }, + { + "id": "332", + "unit": "第四单元100以内数的认识4", + "question_type": "选择题", + "difficulty": 0.65, + "question": "与58最接近的整十数是( )。", + "options": [ + "A. 60", + "B. 55", + "C. 50" + ], + "answer": "A", + "solution": "【分析】从 50 开始数数, 50, 51, 52, 53, 54, 55, 56, 57, 58, 59, 60。分别看 60,55,50与58相差几个数,进而判断最接近58的整十数.\n【详解】A。 60与58之间只有59一个数。 B. 55 个位不是 0,不是整十数,不符合;C. 50 与 58 之间有 51, 52, 53, 54, 55, 56, 57, 7 个数。 故答案为:A", + "knowledge_points": [ + "数 100 以内的数", + "100 以内数的比大小" + ], + "source": "23-24 一年级下·山东菏泽·期末" + }, + { + "id": "333", + "unit": "第四单元100以内数的认识4", + "question_type": "选择题", + "difficulty": 0.85, + "question": "明明有 20 本书,乐乐的书比明明的书少一些,乐乐可能有 ( ) 本书。", + "options": [ + "A. 5", + "B. 18", + "C. 28" + ], + "answer": "B", + "solution": "【分析】描述数的大小关系的方法:通过比较具体数,用\u0027多一些\u0027\u0027少一些\u0027描述相差较小的两个数;用\u0027多得多\u0027\u0027少得多\u0027描述相差较大的两个数。据此找出比20少一些的数,即可解决.\n【详解】A。 5比20少得多,不符合题意;B. 18 比 20 少一些,符合题意;C. 28 比 20 多一些,不符合题意;即,明明有 20 本书,乐乐的书比明明的书少一些,乐乐可能有 18 本书。故答案为: B", + "knowledge_points": [ + "数的相对大小关系" + ], + "source": "23-24 一年级下·山东菏泽·期末" + }, + { + "id": "334", + "unit": "第四单元100以内数的认识4", + "question_type": "选择题", + "difficulty": 0.85, + "question": "妈妈为丽丽制作了一些生日饼干。饼干的块数比 76 少一些,比 24 多得多,妈妈可能制作了 ( ) 块饼干。", + "options": [ + "A. 35", + "B. 68", + "C. 90" + ], + "answer": "B", + "solution": "【分析】描述数的大小关系的方法:通过比较具体数,用\u0027多一些\u0027\u0027少一些\u0027描述相差较小的两个数;用\u0027多得多\u0027\u0027少得多\u0027描述相差较大的两个数。据此找出比 76 少一些,比 24 多得多的数,即可解决.\n【详解】A。 35比76少得多,35比24多一些,不符合题意;B. 68 比 76 少一些, 68 比 24 多得多,符合题意;C. 90 比 76 多一些, 90 比 24 多得多,不符合题意;即,妈妈为丽丽制作了一些生日饼干。饼干的块数比 76 少一些,比 24 多得多,妈妈可能制作了 68 块饼干。故答案为: B", + "knowledge_points": [ + "数的相对大小关系" + ], + "source": "23-24一年级下·河北衡水·期末" + }, + { + "id": "335", + "unit": "第四单元100以内数的认识4", + "question_type": "选择题", + "difficulty": 0.85, + "question": "用 ![47ab3432c845eeeb8f008b2dd53f84f5eb11d0fd7e0e285c2c9b56b7636e2d3a](images\\47ab3432c845eeeb8f008b2dd53f84f5eb11d0fd7e0e285c2c9b56b7636e2d3a.jpg)表示10,用 ![3a1811ff13b3cd94e52d1b5bbeb55c4ec6718391da70735b2a5452cb16f997bb](images\\3a1811ff13b3cd94e52d1b5bbeb55c4ec6718391da70735b2a5452cb16f997bb.jpg)表示 1,下图中比 50 大的是 ( )。", + "options": [ + "A. ![](images/eae17d118c96082e6f27b53a7adeed5e21665b8eba580b35b5f19726c1e509a0.jpg)", + "B. ![](images/8b55b319c9c7909d404b8d8b15b4c67f8a02dbfe512892e4165e36b91667880b.jpg)", + "C. ![](images/b4c9da4edeba46195ad5b1d1e82dd0c7d277cfc8b8bd89d02f9c6d70e31e242f.jpg)" + ], + "answer": "A", + "solution": "【分析】先根据\u0027用 ![](images/47ab3432c845eeeb8f008b2dd53f84f5eb11d0fd7e0e285c2c9b56b7636e2d3a.jpg) 表示 10,用 ![](images/3a1811ff13b3cd94e52d1b5bbeb55c4ec6718391da70735b2a5452cb16f997bb.jpg) 表示 1\u0027写出选项中的每一个数,然后与 50 比较大小,找出符合题意的即可.\n【详解】A。 ![eae17d118c96082e6f27b53a7adeed5e21665b8eba580b35b5f19726c1e509a0](imageseae17d118c96082e6f27b53a7adeed5e21665b8eba580b35b5f19726c1e509a0.jpg),此图表示52, 52 \u003e 50,符合题意;B. ![8b55b319c9c7909d404b8d8b15b4c67f8a02dbfe512892e4165e36b91667880b](images\\8b55b319c9c7909d404b8d8b15b4c67f8a02dbfe512892e4165e36b91667880b.jpg),此图表示 25, 25\u003c50,不符合题意;C. ![b4c9da4edeba46195ad5b1d1e82dd0c7d277cfc8b8bd89d02f9c6d70e31e242f](imagesb4c9da4edeba46195ad5b1d1e82dd0c7d277cfc8b8bd89d02f9c6d70e31e242f.jpg)此图表示 31, 31 \u003c 50,不符合题意;即,用 ![47ab3432c845eeeb8f008b2dd53f84f5eb11d0fd7e0e285c2c9b56b7636e2d3a](images\\47ab3432c845eeeb8f008b2dd53f84f5eb11d0fd7e0e285c2c9b56b7636e2d3a.jpg)表示10,用 ![3a1811ff13b3cd94e52d1b5bbeb55c4ec6718391da70735b2a5452cb16f997bb](images\\3a1811ff13b3cd94e52d1b5bbeb55c4ec6718391da70735b2a5452cb16f997bb.jpg)表示1,比50大的是 ![eae17d118c96082e6f27b53a7adeed5e21665b8eba580b35b5f19726c1e509a0](imageseae17d118c96082e6f27b53a7adeed5e21665b8eba580b35b5f19726c1e509a0.jpg).\n故答案为: A", + "knowledge_points": [ + "100以内数的比大小", + "100以内数的组成" + ], + "source": "23-24一年级下·河北保定·期末" + }, + { + "id": "336", + "unit": "第四单元100以内数的认识4", + "question_type": "选择题", + "difficulty": 0.85, + "question": "爷爷今年80岁,小明的年龄比爷爷小得多,小明可能()岁。", + "options": [ + "A. 70", + "B. 65", + "C. 12" + ], + "answer": "C", + "solution": "【分析】描述数的大小关系的方法:通过比较具体数,用\u0027多一些\u0027\u0027少一些\u0027描述相差较小的两个数;用\u0027多得多\u0027\u0027少得多\u0027描述相差较大的两个数。据此找出比80小得多的数,即可解决.\n【详解】A。 70比80小一些,不符合题意;B. 65 比 80 小一些,不符合题意;C. 12 比 80 小得多,符合题意;即,小明可能 12 岁.\n故答案为: C", + "knowledge_points": [ + "数的相对大小关系" + ], + "source": "23-24一年级下·河南周口·期末" + }, + { + "id": "337", + "unit": "第四单元100以内数的认识4", + "question_type": "选择题", + "difficulty": 0.85, + "question": "87 的最高位是 ( ) 位。", + "options": [ + "A. 个", + "B. 十", + "C. 百" + ], + "answer": "B", + "solution": "【分析】从右边起第一位是个位,第二位是十位,据此解答即可.\n【详解】87 的最高位是十位。故答案为:B", + "knowledge_points": [ + "100以内数的组成" + ], + "source": "23-24 一年级下·河南周口·期末" + }, + { + "id": "338", + "unit": "第四单元100以内数的认识4", + "question_type": "选择题", + "difficulty": 0.65, + "question": "4 个十和 5 个一加上 2 个十,结果是 ( )。", + "options": [ + "A. 65", + "B. 60", + "C. 52" + ], + "answer": "A", + "solution": "【分析】本题考查数的组成。从右边起,第一位是个位,第二位是十位。有几个十就在十位上写几,有几个一就在个位上写几.\n【详解】4个十加上2个十是6个十,是60,5个一是5, 60 + 5 = 65 。故答案为: A", + "knowledge_points": [ + "100以内数的组成" + ], + "source": "23-24 一年级下·河南周口·期末" + }, + { + "id": "339", + "unit": "第四单元100以内数的认识4", + "question_type": "填空题", + "difficulty": 0.65, + "question": "98 再加上( )个一就是 10 个十了。", + "options": [ + + ], + "answer": "2", + "solution": "【分析】10个十是100, 98 + 2 = 100,再加上2个一就是100.\n【详解】98再加上2个一就是10个十了。", + "knowledge_points": [ + "100以内数的组成", + "一位数与两位数的进位加法" + ], + "source": "22-23 一年级下·江西宜春·期中" + }, + { + "id": "340", + "unit": "第四单元100以内数的认识4", + "question_type": "填空题", + "difficulty": 0.85, + "question": "个位是 9,十位是 8,这个数是( ), 它后面的数是( )。", + "options": [ + + ], + "answer": "89;90", + "solution": "【分析】从右边起第一位是个位,个位上的数表示几个一,第二位是十位,十位上的数表示几个十。后面的数用这个数加 1 即可.\n【详解】个位是 9,十位是 8,这个数是 89, 89 + 1 = 90,它后面的数是 90。", + "knowledge_points": [ + "100以内数的排序", + "100以内数的组成" + ], + "source": "22-23 一年级下·江西宜春·期中" + }, + { + "id": "341", + "unit": "第四单元100以内数的认识4", + "question_type": "填空题", + "difficulty": 0.85, + "question": "65 是( )位数,十位上的 6 表示( )个( )。", + "options": [ + + ], + "answer": "两;6;十", + "solution": "【分析】65有两个数字,是两位数。一个两位数,从右往左数,第一位是个位,个位上的数表示几个一;第二位是十位,十位上的数表示几个十.\n【详解】65是两位数,十位上的6表示6个十。", + "knowledge_points": [ + "100以内数的组成" + ], + "source": "22-23 一年级下·江西宜春·期中" + }, + { + "id": "342", + "unit": "第四单元100以内数的认识4", + "question_type": "填空题", + "difficulty": 0.85, + "question": "爷爷的年龄是一个两位数,它的个位是8,十位是6,爷爷今年( )岁。", + "options": [ + + ], + "answer": "68", + "solution": "【分析】一个两位数,从右往左依次为个位,十位,由此按数位顺序写数即可.\n【详解】爷爷的年龄是一个两位数,它的个位是 8,十位是 6,爷爷今年 68 岁。", + "knowledge_points": [ + "100以内数的读,写法", + "100以内数的组成" + ], + "source": "22-23一年级下·广西柳州·期中" + }, + { + "id": "343", + "unit": "第四单元100以内数的认识4", + "question_type": "填空题", + "difficulty": 0.85, + "question": "52 是由( )个十和( )个一组成的。", + "options": [ + + ], + "answer": "5;2", + "solution": "【分析】一个两位数,从右到左数,第一位是个位,个位上是几就表示几个一,第二位是十位,十位上是几就表示几个十.\n【详解】52是由(5)个十和(2)个一组成的。", + "knowledge_points": [ + "100以内数的组成" + ], + "source": "22-23 一年级下·广西柳州·期中" + }, + { + "id": "344", + "unit": "第四单元100以内数的认识4", + "question_type": "填空题", + "difficulty": 0.85, + "question": "3 个一和 6 个十合起来是( ),一个数的十位上是 3,个位上是 6,这个数是( )。", + "options": [ + + ], + "answer": "63;36", + "solution": "【分析】根据整数的数位顺序可知,从右边起第一位是个位,个位上的数表示几个一,第二位是十位,十位上的数表示几个十.\n【详解】3 个一和 6 个十合起来是 63,一个数的十位上是 3,个位上是 6,这个数是 36 。", + "knowledge_points": [ + "100以内数的组成" + ], + "source": "23-24 一年级下·贵州铜仁·期末" + }, + { + "id": "345", + "unit": "第四单元100以内数的认识4", + "question_type": "填空题", + "difficulty": 0.85, + "question": "个位上的数是 7,十位上的数是 5,这个数是( ), 至少再添上( )个一就是整十数。", + "options": [ + + ], + "answer": "57;3", + "solution": "【分析】一个两位数,从右往左依次为个位,十位,十位上的数表示几个十,个位上的数表示几个一。个位是7表示7个一,十位是5表示5个十,这个数是57,57再添上3个一就是60,也就是再添上3个一就是整十数.\n【详解】个位上的数是 7,十位上的数是 5,这个数是 57,至少再添上 3 个一就是整十数。", + "knowledge_points": [ + "100以内数的组成" + ], + "source": "23-24 一年级下·甘肃天水·期末" + }, + { + "id": "346", + "unit": "第四单元100以内数的认识4", + "question_type": "填空题", + "difficulty": 0.85, + "question": "100 里有( )个十或( )个一;8 个一和 6 个十组成( )。", + "options": [ + + ], + "answer": "10;100;68", + "solution": "【分析】1 个十是 10, 2 个十是 20, 3 个十是 30, 。, 8 个十是 80, 9 个十是 90, 10 个十是 100(哪一位满十要向前一位进 1),所以,100 里面有 10 个十。一个整数是几,这个整数可以看作有几个一组成。一个两位数,从右往左数,第一位是个位;第二位是十位;几个十就是几十,几个一就是几;故,8个一和6个十组成68;据此解决.\n【详解】由题意分析得:100 里有 10 个十或 100 个一;8 个一和 6 个十组成 68。", + "knowledge_points": [ + "100以内数的组成" + ], + "source": "23-24 一年级下·广东揭阳·期末" + }, + { + "id": "347", + "unit": "第四单元100以内数的认识4", + "question_type": "填空题", + "difficulty": 0.85, + "question": "在 74,81,68,90 这四个数中,十位上是 8 的数是( ), 最大的数是( ), 最接近 70 的数是( )。", + "options": [ + + ], + "answer": "81;90;68", + "solution": "【分析】一个两位数,从右往左依次为个位,十位,由此可知十位是 8 的数是 81;比较数的大小时,十位大的数就大;十位相同比较个位,个位大的数就大,由此找出最大的数即可;68 往后数第 2 个数是 70,也就是最接近 70.\n【详解】68 \u003c 74 \u003c 81 \u003c 90 在 74,81,68,90 这四个数中,十位上是 8 的数是 81,最大的数是 90,最接近 70 的数是 68。", + "knowledge_points": [ + "100以内数的比大小", + "100以内数的排序", + "100以内数的组成" + ], + "source": "23-24 一年级下·广东深圳·期末" + }, + { + "id": "348", + "unit": "第四单元100以内数的认识4", + "question_type": "填空题", + "difficulty": 0.85, + "question": "22 是( )位数,左边的 \u00272\u0027 表示( )个( ), 右边的 2 表示( )个( )。", + "options": [ + + ], + "answer": "两;2;十;2;一", + "solution": "【分析】先数一数 22 有几位数,一个两位数,从右到左,第一位是个位,个位上是几,就表示几个一,第二位是十位,十位上是几就表示几个十.\n【详解】22是(两)位数,左边的\u00272\u0027表示(2)个(十),右边的2表示(2)个(一)。", + "knowledge_points": [ + "100以内数的组成" + ], + "source": "23-24 一年级下·新疆克拉玛依·期末" + }, + { + "id": "349", + "unit": "第四单元100以内数的认识4", + "question_type": "填空题", + "difficulty": 0.85, + "question": "( )个十和( )个一合起来是 73。", + "options": [ + + ], + "answer": "7;3", + "solution": "【分析】一个两位数,从右到左,第一位是个位,个位上是几,就表示几个一,第二位是十位,十位上是几就表示几个十.\n【详解】(7)个十和(3)个一合起来是 73 。", + "knowledge_points": [ + "100以内数的组成" + ], + "source": "23-24 一年级下·新疆克拉玛依·期末" + }, + { + "id": "350", + "unit": "第四单元100以内数的认识4", + "question_type": "填空题", + "difficulty": 0.65, + "question": "一个数的个位上是 5,十位上是 3,这个数写作( ), 读作( )。", + "options": [ + + ], + "answer": "35;三十五", + "solution": "【分析】从右起,第一位是个位,第二位是十位。读数时,从高位读起.\n【详解】一个数的个位上是 5,十位上是 3,这个数写作 35,读作三十五。", + "knowledge_points": [ + "100以内数的读,写法", + "100以内数的组成" + ], + "source": "23-24 一年级下·新疆克拉玛依·期末" + }, + { + "id": "351", + "unit": "第四单元100以内数的认识4", + "question_type": "填空题", + "difficulty": 0.85, + "question": "56 中的 \u00275\u0027 在( )位上,表示 5 个( ), \u00276\u0027 在( )位上,表示 6 个( )。", + "options": [ + + ], + "answer": "十;十;个;一", + "solution": "【分析】一个两位数,左边是十位,右边是个位,十位上是几就表示几个十,个位上是几就表示几个一,据此解答.\n【详解】56 的十位是 5,个位是 6,填空如下: 56 中的 \u00275\u0027 在 (十) 位上,表示 5 个 (十), \u00276\u0027 在 (个) 位上,表示 6 个 (一) 。", + "knowledge_points": [ + "100以内数的组成" + ], + "source": "23-24 一年级下·广东梅州·期末" + }, + { + "id": "352", + "unit": "第四单元100以内数的认识4", + "question_type": "填空题", + "difficulty": 0.65, + "question": "一个两位数,个位上的数和十位上的数都是 4,这个数写作( );由 9 个一和 6 个十组成的数写作( ),读作( )。", + "options": [ + + ], + "answer": "44;69;六十九", + "solution": "【分析】从右起,第一位是个位,第二位是十位,读数时从高位读起.\n【详解】一个两位数,个位上的数和十位上的数都是 4,这个数写作 44;由 9 个一和 6 个十组成的数写作 69,读作六十九。", + "knowledge_points": [ + "100以内数的读,写法", + "100以内数的组成" + ], + "source": "23-24 一年级下·广东汕头·期末" + }, + { + "id": "353", + "unit": "第四单元100以内数的认识4", + "question_type": "填空题", + "difficulty": 0.85, + "question": "一个两位数,个位上是6,十位上的数是4,这个数是( )。", + "options": [ + + ], + "answer": "46", + "solution": "【分析】一个两位数,从右往左依次为个位,十位,由此按数位顺序写数即可.\n【详解】一个两位数,个位上是 6,十位上的数是 4,这个数是 46 。", + "knowledge_points": [ + "100以内数的组成" + ], + "source": "23-24 一年级下·江西赣州·期末" + }, + { + "id": "354", + "unit": "第四单元100以内数的认识4", + "question_type": "填空题", + "difficulty": 0.65, + "question": "38 是由( )个一和( )个十组成的,百位上的数是 1,个位和十位上的数都是 0,这个数是( ), 读作( )。", + "options": [ + + ], + "answer": "8;3;100;一百", + "solution": "【分析】从右起,第一位是个位,第二位是十位,第三位是百位。个位上是几就有几个一,十位上是几就有几个十,读数时从高位读起.\n【详解】38是由8个一和3个十组成的,百位上的数是1,个位和十位上的数都是0,这个数是100,读作一百。", + "knowledge_points": [ + "100 以内数的读,写法", + "100 以内数的组成", + "认识百位" + ], + "source": "23-24 一年级下·广东汕头·期末" + }, + { + "id": "355", + "unit": "第四单元100以内数的认识4", + "question_type": "填空题", + "difficulty": 0.85, + "question": "从 80 写到 100,一共写了( )个 8。", + "options": [ + + ], + "answer": "12", + "solution": "【分析】我们从 80 写到 100,然后再数一数一共写了几个数字 8.\n【详解】80,81,82,83,84,85,86,87,88,89,90,91,92,93,94,95,96,97,98,99,100。则一共写了 12 个。", + "knowledge_points": [ + "数一数", + "数100以内的数" + ], + "source": "23-24 一年级下·山东济南·期末" + }, + { + "id": "356", + "unit": "第四单元100以内数的认识4", + "question_type": "填空题", + "difficulty": 0.85, + "question": "最大的一位数与两位数中最大的整十数的和是( ),差是( )。", + "options": [ + + ], + "answer": "99;81", + "solution": "【分析】根据题意可知:最大的一位数是 9,这最大的两位整十数,即 9 个十, 90,然后两者相加和即可求出两者的和和差.\n【详解】9 + 90 = 99,90 - 9 = 81 则最大的一位数与两位数中最大的整十数的和是 (99), 差是 (81) 。", + "knowledge_points": [ + "100以内数的组成", + "整十数加,减一位数" + ], + "source": "23-24 一年级下·山东济南·期末" + }, + { + "id": "357", + "unit": "第四单元100以内数的认识4", + "question_type": "填空题", + "difficulty": 0.85, + "question": "由 9 个一, 7 个十组成的数是( ) , 和它相邻的两个数是( )和( )。", + "options": [ + + ], + "answer": "79;78;80", + "solution": "【分析】一个两位数,从右到左,第一位是个位,个位上是几,就表示几个一,第二位是十位,十位上是几就表示几个十,则写作:79。与之相邻的数一个比它少 1,一个比它多 1 .\n【详解】比 79 少 1 的数是 78,比 79 多 1 的数是 80。由 9 个一, 7 个十组成的数是 (79), 和它相邻的两个数是 (78) 和 (80) 。", + "knowledge_points": [ + "100以内数的排序", + "100以内数的组成", + "相邻的数" + ], + "source": "23-24 一年级下·山东济南·期末" + }, + { + "id": "358", + "unit": "第四单元100以内数的认识4", + "question_type": "填空题", + "difficulty": 0.85, + "question": "79 读作( );六十三写作( )。", + "options": [ + + ], + "answer": "七十九;63", + "solution": "【分析】一个两位数,从右往左依次为个位,十位。读数时从高位读起,十位是几读作几十,个位是几读作几;写数时从高位写起,几十就在十位写几,几就在个位写几.\n【详解】79 读作七十九;六十三写作 63。", + "knowledge_points": [ + "100以内数的读,写法" + ], + "source": "23-24 一年级下·广东梅州·期末" + }, + { + "id": "359", + "unit": "第四单元100以内数的认识4", + "question_type": "填空题", + "difficulty": 0.65, + "question": "最大的两位数是( ), 最小的一位数是( )。", + "options": [ + + ], + "answer": "99;1", + "solution": "【分析】最大的两位数十位和个位上都是最大的一位数,即十位和个位都是 9.10 以内数大小关系为: 0 \u003c 1 \u003c 2 \u003c 3 \u003c 4 \u003c 5 \u003c 6 \u003c 7 \u003c 8 \u003c 9 \u003c 10,最小的一位数是 1.\n【详解】最大的两位数是 99,最小的一位数是 1。", + "knowledge_points": [ + "100以内数的比大小", + "100以内数的组成" + ], + "source": "23-24 一年级下·广东梅州·期末" + }, + { + "id": "360", + "unit": "第四单元100以内数的认识4", + "question_type": "填空题", + "difficulty": 0.85, + "question": "68 的个位上是( ), 十位上是( )。", + "options": [ + + ], + "answer": "8;6", + "solution": "【分析】一个两位数,从右往左数,第一位是个位,第二位是十位,由此解答.\n【详解】68 的个位上是 8,十位上是 6。", + "knowledge_points": [ + "100以内数的组成" + ], + "source": "23-24 一年级下·广东梅州·期末" + }, + { + "id": "361", + "unit": "第四单元100以内数的认识4", + "question_type": "填空题", + "difficulty": 0.85, + "question": "4 个十是( ),9 个十是( ),100 里面有( )个十。", + "options": [ + + ], + "answer": "40;90;10", + "solution": "【分析】几个十就是几十。10个一是10,10个十是100,据此填空.\n【详解】4个十是40,9个十是90,100里面有10个十。", + "knowledge_points": [ + "100以内数的组成" + ], + "source": "23-24 一年级下·广东梅州·期末" + }, + { + "id": "362", + "unit": "第四单元100以内数的认识4", + "question_type": "填空题", + "difficulty": 0.65, + "question": "一个两位数,个位和十位上的数字都是 9,这个数是( ), 和这个数相邻的两个数是( )和( )。", + "options": [ + + ], + "answer": "99;98;100", + "solution": "【分析】从右起,第一位是个位,第二位是十位。相邻的数用这个数加 1,减 1 即可.\n【详解】一个两位数,个位和十位上的数字都是 9,这个数是 99.99 + 1 = 100 , 99 - 1 = 98,和这个数相邻的两个数是 98 和 100。", + "knowledge_points": [ + "100以内数的排序", + "100以内数的组成", + "相邻的数" + ], + "source": "23-24 一年级下·辽宁鞍山·期末" + }, + { + "id": "363", + "unit": "第四单元100以内数的认识4", + "question_type": "填空题", + "difficulty": 0.65, + "question": "60 里面有( )个十, ( )个十是一百。个位是 8 的最大两位数是( ), 最小两位数是( )。", + "options": [ + + ], + "answer": "6;10;98;18", + "solution": "【分析】十位上是几就是几十,10个十是 100.10 以内数大小关系为: 0 \u003c 1 \u003c 2 \u003c 3 \u003c 4 \u003c 5 \u003c 6 \u003c 7 \u003c 8 \u003c 9 \u003c 10。个位上是 8,最大时十位上是 9,最小时十位上是 1 .\n【详解】60 里面有 6 个十, 10 个十是一百。个位是 8 的最大两位数是 98,最小两位数是 18。", + "knowledge_points": [ + "100 以内数的比大小", + "100 以内数的组成" + ], + "source": "23-24 一年级下·湖南怀化·期末" + }, + { + "id": "364", + "unit": "第四单元100以内数的认识4", + "question_type": "填空题", + "difficulty": 0.65, + "question": "一个一个地数,和 79 相邻的两个数分别是( )和( )。", + "options": [ + + ], + "answer": "78;80", + "solution": "【分析】相邻的自然数相差 1,与 79 相邻的两个数分别是比79多1和比79少1,据此解答.\n【详解】填空如下:一个一个地数,和 79 相邻的两个数分别是 (78) 和 (80)。", + "knowledge_points": [ + "数 100 以内的数", + "相邻的数" + ], + "source": "23-24 一年级下·浙江嘉兴·期末" + }, + { + "id": "365", + "unit": "第四单元100以内数的认识4", + "question_type": "填空题", + "difficulty": 0.85, + "question": "数学课本的页数是一个两位数,其中十位上是最大的一位数,个位上的数比十位上的数小 3,这个两位数是( ), 它是由( )个十和( )个一组成的。", + "options": [ + + ], + "answer": "96;9;6", + "solution": "【分析】一个两位数,从右往左依次为个位,十位。十位是几表示几个十,个位是几表示几个一。十位是最大的一位数,也就是 9,十位上的数 -3 计算出个位上的数即可.\n【详解】9 - 3 = 6 数学课本的页数是一个两位数,其中十位上是最大的一位数,个位上的数比十位上的数小 3,这个两位数是 96,它是由 9 个十和 6 个一组成的。", + "knowledge_points": [ + "100以内数的组成" + ], + "source": "23-24 一年级下·山东济宁·期末" + }, + { + "id": "366", + "unit": "第四单元100以内数的认识4", + "question_type": "填空题", + "difficulty": 0.85, + "question": "5 个十和 7 个一组成( ),和它相邻的两个数是( )( )。", + "options": [ + + ], + "answer": "57;56;58", + "solution": "【分析】一个两位数,从右往左依次为个位,十位。写数时从高位写起,有几个十就在十位写几,有几个一就在个位写几。它的相邻数,根据数的顺序找出它两侧的数即可.\n【详解】5个十和7个一组成57,和它相邻的两个数是56和58。", + "knowledge_points": [ + "100以内数的排序", + "100以内数的组成", + "相邻的数" + ], + "source": "23-24 一年级下·山东济宁·期末" + }, + { + "id": "367", + "unit": "第四单元100以内数的认识4", + "question_type": "填空题", + "difficulty": 0.85, + "question": "56 里的 \u00275\u0027 在( )位,表示5个( )。", + "options": [ + + ], + "answer": "十;十", + "solution": "【分析】一个两位数,从右往左数,第一位是个位,表示几个一,第二位是十位,表示几个十;据此解决.\n【详解】由题意分析得:56里的\u00275\u0027在十位,表示5个十。", + "knowledge_points": [ + "100以内数的组成" + ], + "source": "23-24 一年级下·广东汕头·期末" + }, + { + "id": "368", + "unit": "第四单元100以内数的认识4", + "question_type": "填空题", + "difficulty": 0.94, + "question": "一个一个地数, 30前面的一个数是( ), 99 后面的一个数是( )。", + "options": [ + + ], + "answer": "29;100", + "solution": "【分析】先到 29,再到 30,所以 30 前面的一个数是 29;99 然后到 100,所以 99 后面的一个数是 100.\n【详解】一个一个地数,30前面的一个数是29,99后面的一个数是 100。", + "knowledge_points": [ + "100以内数的排序" + ], + "source": "23-24 一年级下·广东广州·期末" + }, + { + "id": "369", + "unit": "第四单元100以内数的认识4", + "question_type": "填空题", + "difficulty": 0.65, + "question": "从 2,3,9 中选两个数字组成一个两位数,其中最大的( ), 最小的是( ), 最接近 30 的数是( )。", + "options": [ + + ], + "answer": "93;23;29", + "solution": "【分析】组成两位数时,将其中一个数写在十位,另外两个数分别写在个位。组成的数有 23, 29, 32, 39, 92, 93,再比较大小即可。100以内数的大小比较,三位数大于两位数,两位数比较,十位上大的数就大;如果十位上的数相同,个位上大的数就大。29往后数一个数就是30,所以最接近30.\n【详解】23 \u003c 29 \u003c 32 \u003c 39 \u003c 92 \u003c 93 从 2,3,9 中选两个数字组成一个两位数,其中最大的 93,最小的是23,最接近30的数是29。", + "knowledge_points": [ + "100以内数的比大小", + "100以内数的排序", + "100以内数的组成" + ], + "source": "23-24 一年级下·广东肇庆·期末" + }, + { + "id": "370", + "unit": "第四单元100以内数的认识4", + "question_type": "选择题", + "difficulty": 0.65, + "question": "一个数从右边起第一位是9,第二位是3,这个数是( ),读作( )。", + "options": [ + "A. 39", + "B. 三十九", + "C. 93" + ], + "answer": "A", + "solution": "【分析】从右边起第一位是个位,第二位是十位,读数时从高位读起;据此解答.\n【详解】一个数从右边起第一位是 9,第二位是 3,这个数是 39,读作三十九。", + "knowledge_points": [ + "100以内数的读,写法", + "100以内数的组成" + ], + "source": "23-24 一年级下·广东肇庆·期末" + }, + { + "id": "371", + "unit": "第四单元100以内数的认识4", + "question_type": "选择题", + "difficulty": 0.65, + "question": "一个两位数,十位上是 7,个位上的数比十位上的数多 2,这个两位数是( ), 与它相邻的两个数是( )和( )。", + "options": [ + "A. 74;73;75", + "B. 53;52;54", + "C. 79;78;80" + ], + "answer": "C", + "solution": "【分析】一个两位数,从右往左数,第一位是个位,第二位是十位;先求出个位数,再组数。相邻的两个数,左边的数比右边的数小 1,右边的数比左边的数大 1;据此解决.\n【详解】7 + 2 = 979 往前数一个数是 78,往后数 1 个数是 80;即,一个两位数,十位上是 7,个位上的数比十位上的数多 2,这个两位数是 79,与它相邻的两个数是 78 和 80 。", + "knowledge_points": [ + "100以内数的排序", + "100以内数的组成", + "8,9的加减法", + "相邻的数" + ], + "source": "23-24 一年级下·山东菏泽·期末" + }, + { + "id": "372", + "unit": "第四单元100以内数的认识4", + "question_type": "填空题", + "difficulty": 0.65, + "question": "一个两位数,个位上和十位上的数都是 9,这个数比 100 少( )。", + "options": [ + + ], + "answer": "1", + "solution": "【分析】根据 100 以内整数的写法,先得出这个两位数是多少,再根据对 100 以内整数的认识,即可得出的这个数比 100 少多少.\n【详解】一个两位数,个位上和十位上的数都是 9,这个两位数是 99.99 比 100 少 1。", + "knowledge_points": [ + "数 100 以内的数", + "100 以内数的组成" + ], + "source": "23-24 一年级下·山东菏泽·期末" + }, + { + "id": "373", + "unit": "第四单元100以内数的认识4", + "question_type": "填空题", + "difficulty": 0.65, + "question": "67 里面的 \u00276\u0027 在( )位上,表示( )个( ), \u00277\u0027 在( )位上,表示( )个( )。", + "options": [ + + ], + "answer": "十;6;十;个;7;一", + "solution": "【分析】从右起,第一位是个位,第二位是十位。两位数十位上的数表示几个十,个位上的数表示几个一.\n【详解】67里面的\u00276\u0027在十位上,表示6个十,\u00277\u0027在个位上,表示 7 个一。", + "knowledge_points": [ + "100以内数的组成" + ], + "source": "23-24 一年级下·江西九江·期末" + }, + { + "id": "374", + "unit": "第四单元100以内数的认识4", + "question_type": "填空题", + "difficulty": 0.85, + "question": "6 个一和 4 个百组成的数是( ),与这个数相邻的两个数是( )和( )。", + "options": [ + + ], + "answer": "406;405;407", + "solution": "【分析】由 6 个一和 4 个百三组成的数是三位数,百位上写 4,十位上写 0,个位上写 6,据此写数;相邻的两个自然数相差 1,前一个自然数 +1 = 后一个相邻的自然数,据此解答.\n【详解】(1)由 6 个一和 4 个百三组成的数是三位数,百位上写 4,十位上写 0,个位上写 6,所以此数为 406;(2) 相邻的两个自然数相差 1, 406 前面的数为 406 - 1 = 405;(3) 相邻的两个自然数相差 1, 406 后面的数为 406 + 1 = 407。所以与这个数相邻的两个数是 405 和 407.\n[点睛]本题考查了数的组成和数的顺序。", + "knowledge_points": [ + "100以内数的排序", + "100以内数的组成" + ], + "source": "23-24 二年级下·河北保定·期末" + }, + { + "id": "375", + "unit": "第四单元100以内数的认识4", + "question_type": "填空题", + "difficulty": 0.65, + "question": "个位上是 6,十位上是 3 的两位数是( ), 再添( )个一是 40 。", + "options": [ + + ], + "answer": "36;4", + "solution": "【分析】一个两位数,左边的数位是十位,右边的数位是个位,个位是6再添4个就满十进一,十位变成4,也就是40,据此得出结论即可.\n【详解】根据分析知:个位上是 6,十位上是 3 的两位数是 36,再添 4 个一是 40。", + "knowledge_points": [ + "100以内数的组成" + ], + "source": "23-24 一年级下·广东韶关·期末" + }, + { + "id": "376", + "unit": "第四单元100以内数的认识4", + "question_type": "填空题", + "difficulty": 0.85, + "question": "88 这个两位数,个位上的 8 表示( ), 十位上的 8 表示( )。", + "options": [ + + ], + "answer": "8个一;8个十", + "solution": "【分析】88 左边是十位,十位是几表示几个十,右边是个位,个位是几表示几个一,据此解答.\n【详解】由分析可得:88 这个两位数,个位上的 8 表示 (8 个一), 十位上的 8 表示 (8 个十)。", + "knowledge_points": [ + "100以内数的组成" + ], + "source": "23-24 一年级下·河南周口·期末" + }, + { + "id": "377", + "unit": "第四单元100以内数的认识4", + "question_type": "填空题", + "difficulty": 0.85, + "question": "5 个一和 7 个十组成( );10 个十是( )。", + "options": [ + + ], + "answer": "75;100", + "solution": "【分析】一个两位数,从右往左数,第一位是个位,第二位是十位;据此组数。5个一是5,7个十是70,组成75;1个十是10,2个十是 20, 3个十是30, 。, 8个十是80, 9个十是90, 10个十是 100(满十向前一位进 1),据此解决.\n【详解】由题意分析得:5 个一和 7 个十组成 75;10 个十是 100。", + "knowledge_points": [ + "100以内数的组成" + ], + "source": "23-24 一年级下·河南周口·期末" + }, + { + "id": "378", + "unit": "第四单元100以内数的认识4", + "question_type": "填空题", + "difficulty": 0.85, + "question": "十位上是 6,个位上的数比十位上多 2,这个数是( ), 与它最接近的整十数是( )。", + "options": [ + + ], + "answer": "68;70", + "solution": "【分析】一个两位数,从右往左依次为个位,十位。用十位上的数加 2 计算出个位上的数,再写出数字即可。根据数的顺序找出最接近的整十数即可.\n【详解】6 + 2 = 8 十位上是 6,个位上的数比十位上多 2,这个数是 68.68 后边的第二个数就是 70,也就是与它最接近的整十数是 70 。", + "knowledge_points": [ + "100以内数的排序", + "100以内数的组成" + ], + "source": "23-24 一年级下·江西九江·期末" + }, + { + "id": "379", + "unit": "第四单元100以内数的认识4", + "question_type": "填空题", + "difficulty": 0.85, + "question": "91 中的 \u00271\u0027 在( )位上,表示 1 个( );\u00279\u0027在( )位上,表示 9 个( )。", + "options": [ + + ], + "answer": "个;一;十;十", + "solution": "【分析】一个两位数,从右往左数,第一位是个位,表示几个一;第二位是十位,表示几个十.\n【详解】由题意分析得: 91 中的 \u00271\u0027 在个位上,表示 1 个一;\u00279\u0027 在十位上,表示 9 个十。", + "knowledge_points": [ + "100以内数的组成" + ], + "source": "23-24 一年级下·河北保定·期末" + }, + { + "id": "380", + "unit": "第四单元100以内数的认识4", + "question_type": "填空题", + "difficulty": 0.65, + "question": "64 读作( ),它的十位上的数字是( ), 表示( )个( ), 个位上的数字是( ), 表示( )个( )。", + "options": [ + + ], + "answer": "六十四;6;6;十;4;4;一", + "solution": "【分析】一个两位数,左边的数位是十位,十位是几就读几十表示几个十,右边的数位是个位,个位是几就读几表示几个一。整数的读法:从高位到低位,一级一级地读,每一级末尾的0都不读出来,其余数位连续几个0都只读一个零.\n【详解】根据分析知:64 读作六十四,它的十位上的数字是 6,表示 6 个十,个位上的数字是 4,表示 4 个一。", + "knowledge_points": [ + "100以内数的读,写法", + "100以内数的组成" + ], + "source": "23-24 一年级下·新疆克孜勒苏·期末" + }, + { + "id": "381", + "unit": "第四单元100以内数的认识4", + "question_type": "填空题", + "difficulty": 0.85, + "question": "在 58,68,59,26,60 这些数中,最大的数是( ) , 最小的数是( )。", + "options": [ + + ], + "answer": "68;26", + "solution": "【分析】比较数的大小时,都是两位数,十位大的数就大;十位相同比较个位,个位大的数就大,由此解答.\n【详解】68 \u003e 60 \u003e 59 \u003e 58 \u003e 26 在 58,68,59,26,60 这些数中,最大的数是 68,最小的数是 26。", + "knowledge_points": [ + "100以内数的比大小" + ], + "source": "23-24 一年级下·山东菏泽·期末" + }, + { + "id": "382", + "unit": "第四单元100以内数的认识4", + "question_type": "填空题", + "difficulty": 0.85, + "question": "70 再添加( )个十就是 100;八十九写作( )。", + "options": [ + + ], + "answer": "3;89", + "solution": "【分析】一个两位数,从右往左依次为个位,十位。十位是几表示几个十,个位是几表示几个一。70 里面有 7 个十,100 里面有 10 个十,70 再添上 3 个十就是 100;写数时从高位写起,几十就在十位写几,几就在个位写几.\n【详解】70再添加3个十就是100;八十九写作89。", + "knowledge_points": [ + "100以内数的读,写法", + "100以内数的组成" + ], + "source": "23-24 一年级下·山东菏泽·期末" + }, + { + "id": "383", + "unit": "第四单元100以内数的认识4", + "question_type": "填空题", + "difficulty": 0.85, + "question": "73 是由( )个十和( )个一组成的,与它相邻的数是( )和( )。", + "options": [ + + ], + "answer": "7;3;74;72", + "solution": "【分析】一个两位数,从右往左数,第一位是个位,表示几个一,第二位是十位,表示几个十;相邻的两个数相差 1,右边这个数比左边这个数大 1;左边这个数比右边这个数小 1;据此解决.\n【详解】73 + 1 = 74,73 - 1 = 7273是由7个十和3个一组成的,与它相邻的数是74和72。", + "knowledge_points": [ + "100以内数的排序", + "100以内数的组成", + "相邻的数" + ], + "source": "23-24 一年级下·山东菏泽·期末" + }, + { + "id": "384", + "unit": "第四单元100以内数的认识4", + "question_type": "填空题", + "difficulty": 0.85, + "question": "9 个十和 4 个一组成 的数是( ),它再加上( )个一就是 100。", + "options": [ + + ], + "answer": "94;6", + "solution": "【分析】一个两位数,从右往左数,第一位是个位,第二位是十位,几个一就是几,几个十就是几十;据此组数。即,9个十是90,4个一是4,组成的数是94;94,95,96,97,98,99,100,也就是 94 再往后数 6 个数就是 100,即 94 再加上 6 个一就是 100.\n【详解】由题意分析得: 9个十和4个一组成的数是94,它再加上6个一就是100。", + "knowledge_points": [ + "数 100 以内的数", + "100 以内数的组成" + ], + "source": "23-24 一年级下·山东菏泽·期末" + }, + { + "id": "385", + "unit": "第四单元100以内数的认识4", + "question_type": "判断题", + "difficulty": 0.85, + "question": "在计数器上,从右边起,第一位是个位,第二位是十位,第三位是百位。( )", + "options": [ + "A. 对", + "B. 错" + ], + "answer": "A", + "solution": "【详解】由题意分析得:在计数器上,从右边起,第一位是个位,第二位是十位,第三位是百位(如下图);此说法正确。 ![](images/b54708c940c7dcd800bc8c89419290a523ea7fd4f78c91041417ec5a6d8aedbb.jpg)故答案为:√", + "knowledge_points": [ + "100以内数的组成", + "认识百位" + ], + "source": "22-23一年级下·云南保山·期中" + }, + { + "id": "386", + "unit": "第四单元100以内数的认识4", + "question_type": "判断题", + "difficulty": 0.85, + "question": "5个十和2个一合起来是52。( )", + "options": [ + "A. 对", + "B. 错" + ], + "answer": "A", + "solution": "【分析】写数是从高位写起,几十就在十位上写几,几就在个位上写几,哪个数位上 1 个计数单位也没有,就在这一位上写 0 .\n【详解】由分析可得:5个十和2个一合起来是52,原题说法正确。故答案为:√", + "knowledge_points": [ + "100以内数的读,写法", + "100以内数的组成" + ], + "source": "23-24一年级下·吉林白城·期中" + }, + { + "id": "387", + "unit": "第四单元100以内数的认识4", + "question_type": "判断题", + "difficulty": 0.85, + "question": "81后面第5个数是 86。( )", + "options": [ + "A. 对", + "B. 错" + ], + "answer": "A", + "solution": "【分析】一个一个地数一数,即可知道 81 后面第 5 个数是多少.\n【详解】由题意分析得: 81,82,83,84,85,86;即,81后面第5个数是86;此说法正确。故答案为: √", + "knowledge_points": [ + "数 100 以内的数" + ], + "source": "23-24一年级下·黑龙江哈尔滨·期末" + }, + { + "id": "388", + "unit": "第四单元100以内数的认识4", + "question_type": "判断题", + "difficulty": 0.85, + "question": "77 中的两个 \u00277\u0027 表示的意义相同。( )", + "options": [ + "A. 对", + "B. 错" + ], + "answer": "B", + "solution": "【分析】一个两位数,从右往左数,第一位是个位,表示几个一;第二位是十位;表示几个十;据此解决.\n【详解】由题意分析得:77 中,左边的 \u00277\u0027表示 7 个十,右边的 \u00277\u0027表示 7 个一,两个 \u00277\u0027表示的意义不一样;原题说法错误。故答案为: ×", + "knowledge_points": [ + "100以内数的组成" + ], + "source": "18-19 一年级下·北京·期中" + }, + { + "id": "389", + "unit": "第四单元100以内数的认识4", + "question_type": "判断题", + "difficulty": 0.85, + "question": "96 读作:九十六。( )", + "options": [ + "A. 对", + "B. 错" + ], + "answer": "A", + "solution": "【分析】读一个两位数,先读十位上的数,读作几十,再读个位上的数,读作几;据此解决.\n【详解】由题意分析得:96 读作:九十六;此读法正确。故答案为: √", + "knowledge_points": [ + "100以内数的读,写法" + ], + "source": "23-24 一年级下·黑龙江哈尔滨·期末" + }, + { + "id": "390", + "unit": "第四单元100以内数的认识4", + "question_type": "判断题", + "difficulty": 0.65, + "question": "一个两位数,个位上的数是 9,十位上的数是 2,这个数写作 92。( )", + "options": [ + "A. 对", + "B. 错" + ], + "answer": "B", + "solution": "【分析】从右起,第一位是个位,第二位是十位.\n【详解】一个两位数,个位上的数是 9,十位上的数是 2,这个数写作 92 是错误的,应该写作 29。故答案为: ×", + "knowledge_points": [ + "100以内数的读,写法" + ], + "source": "23-24一年级下·广东汕头·期末" + }, + { + "id": "391", + "unit": "第四单元100以内数的认识4", + "question_type": "判断题", + "difficulty": 0.65, + "question": "从 20 开始一个一个地数,数到 30,一共数了 10 个数。( )", + "options": [ + "A. 对", + "B. 错" + ], + "answer": "B", + "solution": "【分析】从 20 开始一个一个地数, 20,21,22,23,24,25,26,27,28,29,30,共11个数.\n【详解】从 20 开始一个一个地数,数到 30,一共数了 11 个数。原题说法错误。故答案为: ×", + "knowledge_points": [ + "数 100 以内的数", + "100 以内数的排序" + ], + "source": "23-24一年级下·广东汕头·期末" + }, + { + "id": "392", + "unit": "第四单元100以内数的认识4", + "question_type": "判断题", + "difficulty": 0.85, + "question": "82 后面连续的五个数是 82,83,84,85,86。( )", + "options": [ + "A. 对", + "B. 错" + ], + "answer": "B", + "solution": "【分析】82 的后面一个数是 83, 83 的后面一个数是 84, 84 的后面一个数是 85, 85 的后面一个数是 86, 86 的后面一个数是 87,也就是 82 后面连续的五个数是 83,84,85,86,87;据此判断.\n【详解】由题意分析得;82 后面连续的五个数是 83,84,85,86,87;原说法错误。故答案为: ×", + "knowledge_points": [ + "数100以内的数" + ], + "source": "23-24 一年级下·广东肇庆·期末" + }, + { + "id": "393", + "unit": "第四单元100以内数的认识4", + "question_type": "判断题", + "difficulty": 0.85, + "question": "一个一个地数,七十九后面第五个数是八十四。( )", + "options": [ + "A. 对", + "B. 错" + ], + "answer": "A", + "solution": "【分析】一个一个地数,也就是后一个数比前一个数多一。由此数数即可.\n【详解】七十九后面第一个数是八十,第二个数是八十一,第三个数是八十二,第四个数是八十三,第五个数是八十四。原题说法正确。故答案为: √", + "knowledge_points": [ + "数 100 以内的数" + ], + "source": "23-24 一年级下·山东菏泽·期末" + }, + { + "id": "394", + "unit": "第四单元100以内数的认识4", + "question_type": "判断题", + "difficulty": 0.85, + "question": "77 里面的两个 \u00277\u0027表示的意义是一样的。( )", + "options": [ + "A. 对", + "B. 错" + ], + "answer": "B", + "solution": "【分析】一个两位数,从右往左依次为个位,十位。十位是几表示几个十,个位是几表示几个一,由此解答.\n【详解】77 从左数第一个 \u00277\u0027 在十位,表示 7 个十,第二个 \u00277\u0027 在个位,表示 7 个一,两个 \u00277\u0027 表示的意义不一样,原题说法错误。故答案为: ×", + "knowledge_points": [ + "100以内数的组成" + ], + "source": "23-24一年级下·山东菏泽·期末" + }, + { + "id": "395", + "unit": "第四单元100以内数的认识4", + "question_type": "判断题", + "difficulty": 0.85, + "question": "79 和 83 两个数中, 83 更接近 80。( )", + "options": [ + "A. 对", + "B. 错" + ], + "answer": "B", + "solution": "【分析】先算出 79 和 83 与 83 分别相差多少,差值越小,则越接近 80,据此解答即可.\n【详解】79 和 80 相差 1, 83 和 80 相差 3, 1 \u003c 3,所以 79 更接近 80。原题说法错误。故答案为: ×", + "knowledge_points": [ + "100以内数的排序" + ], + "source": "23-24一年级下·河北保定·期末" + }, + { + "id": "396", + "unit": "第四单元100以内数的认识4", + "question_type": "判断题", + "difficulty": 0.85, + "question": "76 读作七十六。( )", + "options": [ + "A. 对", + "B. 错" + ], + "answer": "A", + "solution": "【分析】100 以内整数的读法,十位上是几就读几十,个位上是几就读几,据此解答即可.\n【详解】76 读作:七十六,原题说法正确。故答案为:√", + "knowledge_points": [ + "100以内数的读,写法" + ], + "source": "23-24 一年级下·河北保定·期末" + }, + { + "id": "397", + "unit": "第四单元100以内数的认识4", + "question_type": "计算题", + "difficulty": 0.65, + "question": "列式并计算.\n![](images/d60d10f58c9e32fcec4d518306f344ef4f2f6dd1fb96cf1829cd7c4a7d6714a2.jpg) ![](images/d567e362b2daf276cbec8758b8f997557905eaeb05ff6141791fbc5c2e92860a.jpg)", + "options": [ + + ], + "answer": "50 + 4 = 54", + "solution": "【分析】根据题意,把左边的数量和右边的数量加起来,结果就是总数量.\n【详解】 ![](images/f85dbf71c70f9d5df4fe74d1d8eb7ef8ddf698df18259efe80d49db3f6010dea.jpg)50 + 4 = 54 (个) (答案不唯一)", + "knowledge_points": [ + "图文问题" + ], + "source": "23-24 一年级下·贵州铜仁·期末" + }, + { + "id": "398", + "unit": "第四单元100以内数的认识4", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式.\n![](images/efdc817e935ed82567f11716dfbf329e3b60149e105fc85bfecedd014258425c.jpg) ![](images/bbd3eab98924d5e2a7431b2242406a37803ea14bd1e6ea4b05e30d214d33b038.jpg)", + "options": [ + + ], + "answer": "20 + 6 = 26", + "solution": "【分析】左边 20 个,右边 6 个,左右两边相加即可求出总个数.\n【详解】20 + 6 = 26 (个)", + "knowledge_points": [ + "图文问题", + "整十数加,减一位数" + ], + "source": "23-24 一年级下·山东济宁·期末" + }, + { + "id": "399", + "unit": "第四单元100以内数的认识4", + "question_type": "计算题", + "difficulty": 0.85, + "question": "看图列式计算.\n![](images/f385ca917de0f2d18d738989f0a045c5473f82d9a1cc1652e5deccd9e7fbe5bc.jpg) ![](images/ce4eb81b527ffbbe2b3671eec1f3faa5dff9234d73294acd1c9442d05a38d021.jpg)", + "options": [ + + ], + "answer": "45 - 5 = 40", + "solution": "【分析】一共有 45 个,右边有 5 个,求左边的数量,根据减法的意义,总数量一右边的数量 = 左边的数量.\n【详解】45 - 5 = 40 (个)左边有 40 个。", + "knowledge_points": [ + "图文问题", + "两位数与一位数的减法(不退位)" + ], + "source": "23-24 一年级下·山东菏泽·期末" + }, + { + "id": "400", + "unit": "第四单元100以内数的认识4", + "question_type": "解答题", + "difficulty": 0.85, + "question": "学校举行运动会,有40位学生和5位老师,每人一瓶矿泉水,50瓶够吗。", + "options": [ + + ], + "answer": "够", + "solution": "【分析】先用加法把学生人数与老师人数加起来,求出和,再比较大小,即可解决.\n【详解】40 + 5 = 45 (位),50 \u003e 45答:每人一瓶矿泉水, 50 瓶够。", + "knowledge_points": [ + "100 以内数的比大小", + "整十数加,减一位数" + ], + "source": "23-24 一年级下·河南周口·期末" + }, + { + "id": "401", + "unit": "第四单元100以内数的认识5", + "question_type": "选择题", + "difficulty": 0.3, + "question": "七十六写作()。", + "options": [ + "A. 706", + "B. 67", + "C. 76" + ], + "answer": "C", + "solution": "【分析】一个两位数,左边的数位是十位,读几十就在十位写几,右边的数位是个位,读几就在个位写几.\n【详解】七十六的十位是7,个位是6,因此写作76。", + "knowledge_points": [ + "数的写法" + ], + "source": "" + }, + { + "id": "402", + "unit": "第四单元100以内数的认识5", + "question_type": "选择题", + "difficulty": 0.3, + "question": "下列各数个位上是5的两位数是()。", + "options": [ + "A. 5", + "B. 15", + "C. 50" + ], + "answer": "B", + "solution": "【分析】一个两位数,从右边起第一位是个位,第二位是十位.\n【详解】A。5是一位数;B。15的个位是5;C。50的个位是0。因此个位上是5的两位数是15。", + "knowledge_points": [ + "数位的认识" + ], + "source": "" + }, + { + "id": "403", + "unit": "第四单元100以内数的认识5", + "question_type": "选择题", + "difficulty": 0.3, + "question": "下面各数中,十位上的数字比个位上的数字大1的数是()。", + "options": [ + "A. 34", + "B. 67", + "C. 98" + ], + "answer": "C", + "solution": "【分析】分别计算每个数十位与个位的差,找出十位比个位大1的数.\n【详解】A。4-3=1,个位比十位大1;B。7-6=1,个位比十位大1;C。9-8=1,十位比个位大1。", + "knowledge_points": [ + "数位的大小比较" + ], + "source": "" + }, + { + "id": "404", + "unit": "第四单元100以内数的认识5", + "question_type": "选择题", + "difficulty": 0.3, + "question": "在我们已经认识的数中,比79大,比90小的数一共有()个。", + "options": [ + "A. 12", + "B. 11", + "C. 10" + ], + "answer": "C", + "solution": "【分析】列举出所有比79大且比90小的整数.\n【详解】符合条件的数有:80,81,82,83,84,85,86,87,88,89,共10个。", + "knowledge_points": [ + "数的顺序" + ], + "source": "" + }, + { + "id": "405", + "unit": "第四单元100以内数的认识5", + "question_type": "选择题", + "difficulty": 0.3, + "question": "下面最接近80的数是()。", + "options": [ + "A. 68", + "B. 82", + "C. 79" + ], + "answer": "C", + "solution": "【分析】分别计算各数与80的差值,差值最小的数最接近80.\n【详解】A。80-68=12;B。82-80=2;C。80-79=1。因此79最接近80。", + "knowledge_points": [ + "数的接近程度" + ], + "source": "" + }, + { + "id": "406", + "unit": "第四单元100以内数的认识5", + "question_type": "选择题", + "difficulty": 0.6, + "question": "一个数,比20多得多,比60少一些,这个数在下图的()处.\n![](images/8fe94fa90b0e1ffeabfeb0e467d724f39abe373b556d2bafb32ffdf841c8c171.jpg)", + "options": [ + "A. 点A", + "B. 点B", + "C. 点C" + ], + "answer": "C", + "solution": "【分析】根据\u0027多得多\u0027\u0027少一些\u0027的含义,结合数轴上的位置判断.\n【详解】点A比20多一些,比60少得多;点B比20多一些,比60少得多;点C比20多得多,比60少一些,符合题意。", + "knowledge_points": [ + "数的相对大小" + ], + "source": "" + }, + { + "id": "407", + "unit": "第四单元100以内数的认识5", + "question_type": "选择题", + "difficulty": 0.3, + "question": "66中右边的\u00276\u0027表示()。", + "options": [ + "A. 6个十", + "B. 6个一", + "C. 66个一" + ], + "answer": "B", + "solution": "【分析】一个两位数,从右起第一位是个位,表示几个一;第二位是十位,表示几个十.\n【详解】66中右边的6在个位,表示6个一。", + "knowledge_points": [ + "数位的意义" + ], + "source": "" + }, + { + "id": "408", + "unit": "第四单元100以内数的认识5", + "question_type": "选择题", + "difficulty": 0.3, + "question": "小白兔采了45朵蘑菇,小灰兔采的数量和小白兔差不多。小灰兔可能采了()朵。", + "options": [ + "A. 42", + "B. 25", + "C. 78" + ], + "answer": "A", + "solution": "【分析】\u0027差不多\u0027表示两数相差很小,找出与45接近的数.\n【详解】A。42与45相差3,差不多;B。25比45少得多;C。78比45多得多。", + "knowledge_points": [ + "数的相对大小" + ], + "source": "" + }, + { + "id": "409", + "unit": "第四单元100以内数的认识5", + "question_type": "选择题", + "difficulty": 0.3, + "question": "在56这个数中,\u00275\u0027表示5个()。", + "options": [ + "A. 一", + "B. 十", + "C. 百" + ], + "answer": "B", + "solution": "【分析】一个两位数,十位上的数表示几个十.\n【详解】56的5在十位,表示5个十。", + "knowledge_points": [ + "数位的意义" + ], + "source": "" + }, + { + "id": "410", + "unit": "第四单元100以内数的认识5", + "question_type": "选择题", + "difficulty": 0.6, + "question": "一个两位数,比80少得多,比20多一些,这个数可能是()。", + "options": [ + "A. 72", + "B. 17", + "C. 26" + ], + "answer": "C", + "solution": "【分析】根据\u0027少得多\u0027\u0027多一些\u0027的含义,逐一判断选项.\n【详解】A。72比80少一些,比20多得多;B。17比80少得多,比20少一些;C。26比80少得多,比20多一些。", + "knowledge_points": [ + "数的相对大小" + ], + "source": "" + }, + { + "id": "411", + "unit": "第四单元100以内数的认识5", + "question_type": "选择题", + "difficulty": 0.6, + "question": "一个两位数,比80少得多,比20多一些,这个数可能是()。", + "options": [ + "A. 72", + "B. 17", + "C. 25" + ], + "answer": "C", + "solution": "【分析】根据\u0027少得多\u0027\u0027多一些\u0027的含义,逐一判断选项.\n【详解】A。72比80少一些;B。17比20少一些;C。25比80少得多,比20多一些。", + "knowledge_points": [ + "数的相对大小" + ], + "source": "" + }, + { + "id": "412", + "unit": "第四单元100以内数的认识5", + "question_type": "选择题", + "difficulty": 0.6, + "question": "在计数器上可以用同样多的珠子表示的是()。", + "options": [ + "A. 45和35", + "B. 50和15", + "C. 26和80" + ], + "answer": "C", + "solution": "【分析】在计数器上,十位和个位上的珠子数之和相等的两个数,用的珠子总数相同.\n【详解】A。4+5=9,3+5=8,不相等;B。5+0=5,1+5=6,不相等;C。2+6=8,8+0=8,相等。", + "knowledge_points": [ + "计数器表示数" + ], + "source": "" + }, + { + "id": "413", + "unit": "第四单元100以内数的认识5", + "question_type": "选择题", + "difficulty": 0.3, + "question": "小军做了27道口算题,小方做的比他多得多,小方可能做了()道。", + "options": [ + "A. 22", + "B. 30", + "C. 58" + ], + "answer": "C", + "solution": "【分析】\u0027多得多\u0027表示远大于27的数.\n【详解】A。22比27少;B。30比27多一些;C。58比27多得多。", + "knowledge_points": [ + "数的相对大小" + ], + "source": "" + }, + { + "id": "414", + "unit": "第四单元100以内数的认识5", + "question_type": "选择题", + "difficulty": 0.3, + "question": "2023年跳水世界杯比赛,中国获得了11枚奖牌,英国获得了7枚奖牌。中国比英国获得的奖牌()。", + "options": [ + "A. 多一些", + "B. 多得多", + "C. 少一些", + "D. 少得多" + ], + "answer": "A", + "solution": "【分析】两数相差不大时,用\u0027多一些\u0027\u0027少一些\u0027描述.\n【详解】11比7多一些,因此中国比英国获得的奖牌多一些。", + "knowledge_points": [ + "数的相对大小" + ], + "source": "" + }, + { + "id": "415", + "unit": "第四单元100以内数的认识5", + "question_type": "选择题", + "difficulty": 0.3, + "question": "用△表示十,用○表示一,下边的图形表示().\n![](images/c2f7ec29cd2e7c499262ff11f32368d9eea962ed46619b0fcce83c8c39ff3803.jpg)", + "options": [ + "A. 14", + "B. 24", + "C. 41", + "D. 42" + ], + "answer": "C", + "solution": "【分析】图中△有4个,表示4个十;○有1个,表示1个一.\n【详解】4个十和1个一组成41。", + "knowledge_points": [ + "数的组成" + ], + "source": "" + }, + { + "id": "416", + "unit": "第四单元100以内数的认识5", + "question_type": "选择题", + "difficulty": 0.6, + "question": "下图是百数表的一部分,○代表的数是().\n\u003ctable\u003e\u003ctr\u003e\u003ctd\u003e\u003c/td\u003e\u003ctd\u003e○\u003c/td\u003e\u003c/tr\u003e\u003ctr\u003e\u003ctd\u003e\u003c/td\u003e\u003ctd\u003e56\u003c/td\u003e\u003c/tr\u003e\u003c/table\u003e", + "options": [ + "A. 46", + "B. 54", + "C. 55", + "D. 66" + ], + "answer": "A", + "solution": "【分析】百数表中,同一行相邻两数差1,同一列相邻两数差10.\n【详解】○在56的左边,因此○=56-10=46。", + "knowledge_points": [ + "百数表的规律" + ], + "source": "" + }, + { + "id": "417", + "unit": "第四单元100以内数的认识5", + "question_type": "选择题", + "difficulty": 0.3, + "question": "读数和写数都从()起。", + "options": [ + "A. 右边", + "B. 百位", + "C. 十位", + "D. 高位" + ], + "answer": "D", + "solution": "【分析】读数和写数都是从最高位开始.\n【详解】读数和写数都从高位起。", + "knowledge_points": [ + "读数和写数的规则" + ], + "source": "" + }, + { + "id": "418", + "unit": "第四单元100以内数的认识5", + "question_type": "选择题", + "difficulty": 0.3, + "question": "小刚拍了89个,小丽拍了20个,小刚拍的球比小丽拍的()。", + "options": [ + "A. 多一些", + "B. 多得多", + "C. 少得多" + ], + "answer": "B", + "solution": "【分析】两数相差很大时,用\u0027多得多\u0027\u0027少得多\u0027描述.\n【详解】89比20多得多。", + "knowledge_points": [ + "数的相对大小" + ], + "source": "" + }, + { + "id": "419", + "unit": "第四单元100以内数的认识5", + "question_type": "选择题", + "difficulty": 0.6, + "question": "()比最大的两位数小,但比94大,而且最接近100。", + "options": [ + "A. 99", + "B. 98", + "C. 94", + "D. 97" + ], + "answer": "B", + "solution": "【分析】最大的两位数是99,找出比94大且最接近100的数.\n【详解】98比99小,比94大,且最接近100。", + "knowledge_points": [ + "数的大小与接近程度" + ], + "source": "" + }, + { + "id": "420", + "unit": "第四单元100以内数的认识5", + "question_type": "选择题", + "difficulty": 0.6, + "question": "用5个在数位顺序表中摆数,能摆出()个不同的两位数.\n\u003ctable\u003e\u003ctr\u003e\u003ctd\u003e十位\u003c/td\u003e\u003ctd\u003e个位\u003c/td\u003e\u003c/tr\u003e\u003ctr\u003e\u003ctd\u003e\u003c/td\u003e\u003ctd\u003e\u003c/td\u003e\u003c/tr\u003e\u003c/table\u003e", + "options": [ + "A. 5", + "B. 6", + "C. 7" + ], + "answer": "A", + "solution": "【分析】5个珠子全用,摆出的两位数有:14,23,32,41,50.\n【详解】共能摆出5个不同的两位数。", + "knowledge_points": [ + "数的组成与排列" + ], + "source": "" + }, + { + "id": "421", + "unit": "第四单元100以内数的认识5", + "question_type": "选择题", + "difficulty": 0.3, + "question": "十位上的数字和个位上的数字相同的两位数一共有()个。", + "options": [ + "A. 10", + "B. 9", + "C. 8" + ], + "answer": "B", + "solution": "【分析】列举所有十位和个位相同的两位数.\n【详解】有11,22,33,44,55,66,77,88,99,共9个。", + "knowledge_points": [ + "数的特征" + ], + "source": "" + }, + { + "id": "422", + "unit": "第四单元100以内数的认识5", + "question_type": "选择题", + "difficulty": 0.3, + "question": "红花有29朵,黄花比红花多得多,黄花可能有()朵。", + "options": [ + "A. 98", + "B. 32", + "C. 6" + ], + "answer": "A", + "solution": "【分析】\u0027多得多\u0027表示远大于29的数.\n【详解】A。98比29多得多;B。32比29多一些;C。6比29少得多。", + "knowledge_points": [ + "数的相对大小" + ], + "source": "" + }, + { + "id": "423", + "unit": "第四单元100以内数的认识5", + "question_type": "选择题", + "difficulty": 0.3, + "question": "按照65,55,45,35。的顺序接着数,35后面的第一个数是()。", + "options": [ + "A. 5", + "B. 15", + "C. 25" + ], + "answer": "C", + "solution": "【分析】观察数列,每次减少10.\n【详解】35-10=25,因此35后面的第一个数是25。", + "knowledge_points": [ + "数的规律" + ], + "source": "" + }, + { + "id": "424", + "unit": "第四单元100以内数的认识5", + "question_type": "选择题", + "difficulty": 0.3, + "question": "比83大比88小的数有()个。", + "options": [ + "A. 4", + "B. 5", + "C. 6" + ], + "answer": "A", + "solution": "【分析】列举出所有比83大且比88小的整数.\n【详解】符合条件的数有:84,85,86,87,共4个。", + "knowledge_points": [ + "数的顺序" + ], + "source": "" + }, + { + "id": "425", + "unit": "第四单元100以内数的认识5", + "question_type": "选择题", + "difficulty": 0.3, + "question": "小亮吃了28个饺子,小明比小亮吃得多一些,小明可能吃了()个饺子。", + "options": [ + "A. 20", + "B. 25", + "C. 30" + ], + "answer": "C", + "solution": "【分析】\u0027多一些\u0027表示比28稍大且相差不大的数.\n【详解】A。20比28少一些;B。25比28少一些;C。30比28多一些。", + "knowledge_points": [ + "数的相对大小" + ], + "source": "" + }, + { + "id": "426", + "unit": "第四单元100以内数的认识5", + "question_type": "选择题", + "difficulty": 0.3, + "question": "猴妈妈摘了72个桃子,小猴子摘的桃子比猴妈妈少一些,小猴子摘了()个桃子。", + "options": [ + "A. 82", + "B. 28", + "C. 65" + ], + "answer": "C", + "solution": "【分析】\u0027少一些\u0027表示比72稍小且相差不大的数.\n【详解】A。82比72多一些;B。28比72少得多;C。65比72少一些。", + "knowledge_points": [ + "数的相对大小" + ], + "source": "" + }, + { + "id": "427", + "unit": "第四单元100以内数的认识5", + "question_type": "选择题", + "difficulty": 0.6, + "question": "4个圆片可以摆出()个不同的两位数。", + "options": [ + "A. 4", + "B. 5", + "C. 6" + ], + "answer": "A", + "solution": "【分析】4个圆片全用,摆出的两位数有:13,22,31,40.\n【详解】共能摆出4个不同的两位数。", + "knowledge_points": [ + "数的组成与排列" + ], + "source": "" + }, + { + "id": "428", + "unit": "第四单元100以内数的认识5", + "question_type": "选择题", + "difficulty": 0.6, + "question": "下列各数中,最接近60的是().\n![](images/50f2920fb142ce4dfe6f446ae46e781841bdc76dda772eb2f15e429919aa2a2d.jpg)", + "options": [ + "A. ①", + "B. ②", + "C. ③", + "D. ④" + ], + "answer": "C", + "solution": "【分析】观察数轴,找出与60间隔最少的点.\n【详解】①距离60有9格;②距离60有3格;③刚好在60上;④距离60有8格。因此③最接近60。", + "knowledge_points": [ + "数的接近程度" + ], + "source": "" + }, + { + "id": "429", + "unit": "第四单元100以内数的认识5", + "question_type": "选择题", + "difficulty": 0.3, + "question": "公交车上的乘客中有26人是\u0027扫码支付\u0027,投币的乘客比\u0027扫码支付\u0027的乘客少一些。投币的乘客可能有()人。", + "options": [ + "A. 30", + "B. 27", + "C. 20" + ], + "answer": "C", + "solution": "【分析】\u0027少一些\u0027表示比26稍小且相差不大的数.\n【详解】A。30比26多一些;B。27比26多一些;C。20比26少一些。", + "knowledge_points": [ + "数的相对大小" + ], + "source": "" + }, + { + "id": "430", + "unit": "第四单元100以内数的认识5", + "question_type": "选择题", + "difficulty": 0.3, + "question": "下面各数中的\u00275\u0027与52中的\u00275\u0027表示意义相同的是()。", + "options": [ + "A. 25", + "B. 58", + "C. 85" + ], + "answer": "B", + "solution": "【分析】52中的\u00275\u0027在十位,表示5个十.\n【详解】A。25的\u00275\u0027在个位;B。58的\u00275\u0027在十位;C。85的\u00275\u0027在个位。", + "knowledge_points": [ + "数位的意义" + ], + "source": "" + }, + { + "id": "431", + "unit": "第四单元100以内数的认识5", + "question_type": "选择题", + "difficulty": 0.3, + "question": "红花有40朵,红花比黄花少得多,黄花有()朵。", + "options": [ + "A. 9", + "B. 50", + "C. 90" + ], + "answer": "C", + "solution": "【分析】\u0027少得多\u0027表示黄花远大于40.\n【详解】A。40比9多得多;B。40比50少一些;C。40比90少得多。", + "knowledge_points": [ + "数的相对大小" + ], + "source": "" + }, + { + "id": "432", + "unit": "第四单元100以内数的认识5", + "question_type": "选择题", + "difficulty": 0.3, + "question": "二年级可能有()人.\n![](images/9640443a7fba6c972bf6db970f71f14c7abb81099e583ad80428b4057096bf90.jpg)", + "options": [ + "A. 47人", + "B. 52人", + "C. 86人" + ], + "answer": "C", + "solution": "【分析】图中提示\u0027比50人多得多\u0027,找出远大于50的数.\n【详解】A。47比50少一些;B。52比50多一些;C。86比50多得多。", + "knowledge_points": [ + "数的相对大小" + ], + "source": "" + }, + { + "id": "433", + "unit": "第四单元100以内数的认识5", + "question_type": "选择题", + "difficulty": 0.3, + "question": "红红有7块糖,明明的糖比红红多很多,明明有()块糖。", + "options": [ + "A. 9", + "B. 6", + "C. 38" + ], + "answer": "C", + "solution": "【分析】\u0027多很多\u0027表示远大于7的数.\n【详解】A。9比7多一些;B。6比7少一些;C。38比7多得多。", + "knowledge_points": [ + "数的相对大小" + ], + "source": "" + }, + { + "id": "434", + "unit": "第四单元100以内数的认识5", + "question_type": "选择题", + "difficulty": 0.3, + "question": "33这个数字中,哪个3大()。", + "options": [ + "A. 十位上的3", + "B. 个位上的3", + "C. 一样大" + ], + "answer": "A", + "solution": "【分析】十位上的3表示3个十,个位上的3表示3个一.\n【详解】3个十大于3个一,因此十位上的3大。", + "knowledge_points": [ + "数位的意义" + ], + "source": "" + }, + { + "id": "435", + "unit": "第四单元100以内数的认识5", + "question_type": "填空题", + "difficulty": 0.3, + "question": "七十六写作( ),53读作( )。", + "options": [ + + ], + "answer": "76;五十三", + "solution": "【分析】写数从高位起,几十就在十位写几,几就在个位写几;读数时先读十位是几十,再读个位是几.\n【详解】七十六写作76;53读作五十三。", + "knowledge_points": [ + "数的读写" + ], + "source": "" + }, + { + "id": "436", + "unit": "第四单元100以内数的认识5", + "question_type": "填空题", + "difficulty": 0.3, + "question": "与87相邻的两个数是( )和( )。", + "options": [ + + ], + "answer": "86;88", + "solution": "【分析】相邻的两个数相差1.\n【详解】87-1=86,87+1=88。", + "knowledge_points": [ + "相邻数" + ], + "source": "" + }, + { + "id": "437", + "unit": "第四单元100以内数的认识5", + "question_type": "填空题", + "difficulty": 0.3, + "question": "个位上的数是8,十位上的数是9,这个数是( )。", + "options": [ + + ], + "answer": "98", + "solution": "【分析】十位是9,个位是8,组成的数是98.\n【详解】这个数是98。", + "knowledge_points": [ + "数的组成" + ], + "source": "" + }, + { + "id": "438", + "unit": "第四单元100以内数的认识5", + "question_type": "填空题", + "difficulty": 0.65, + "question": "一个两位数,十位上是最大的一位数,个位上的数与十位上的数相差5,这个两位数是( )。", + "options": [ + + ], + "answer": "94", + "solution": "【分析】最大的一位数是9,个位比十位小5,因此个位是9-5=4.\n【详解】这个两位数是94。", + "knowledge_points": [ + "数的组成与计算" + ], + "source": "" + }, + { + "id": "439", + "unit": "第四单元100以内数的认识5", + "question_type": "填空题", + "difficulty": 0.3, + "question": "99是一个( )位数,十位上的\"9\"表示()。", + "options": [ + + ], + "answer": "两;9个十", + "solution": "【分析】99有两个数字,是两位数;十位上的9表示9个十.\n【详解】99是两位数,十位上的\"9\"表示9个十。", + "knowledge_points": [ + "数位与计数单位" + ], + "source": "" + }, + { + "id": "440", + "unit": "第四单元100以内数的认识5", + "question_type": "填空题", + "difficulty": 0.3, + "question": "个位上是7,十位上是5的数是( );36是( )和( )中间的数。", + "options": [ + + ], + "answer": "57;35;37", + "solution": "【分析】十位是5,个位是7,组成的数是57;36的前一个数是35,后一个数是37.\n【详解】个位上是7,十位上是5的数是57;36是35和37中间的数。", + "knowledge_points": [ + "数的组成与相邻数" + ], + "source": "" + }, + { + "id": "441", + "unit": "第四单元100以内数的认识5", + "question_type": "填空题", + "difficulty": 0.3, + "question": "个位上是9的最大两位数和最小两位数是( )和( )。", + "options": [ + + ], + "answer": "99;19", + "solution": "【分析】个位是9的最大两位数是99,最小两位数是19.\n【详解】个位上是9的最大两位数是99,最小两位数是19。", + "knowledge_points": [ + "数的特征" + ], + "source": "" + }, + { + "id": "442", + "unit": "第四单元100以内数的认识5", + "question_type": "填空题", + "difficulty": 0.3, + "question": "一个两位数,十位上是8,个位上的数字比十位上的数字小2,这个数是( )。", + "options": [ + + ], + "answer": "86", + "solution": "【分析】个位数字=8-2=6,因此这个数是86.\n【详解】这个数是86。", + "knowledge_points": [ + "数的组成与计算" + ], + "source": "" + }, + { + "id": "443", + "unit": "第四单元100以内数的认识5", + "question_type": "填空题", + "difficulty": 0.3, + "question": "如图,这个数写作( ),读作( ),它里面有( )个十和( )个一,再添上4是( ).\n![](images/fa4d012e92f352cb0331d2717165f471936d16381867784c3bb3cf9d5f23b5e0.jpg)", + "options": [ + + ], + "answer": "36;三十六;3;6;40", + "solution": "【分析】图中有3捆小棒(每捆10根)和6根单根,表示3个十和6个一,合起来是36;36+4=40.\n【详解】这个数写作36,读作三十六,它里面有3个十和6个一,再添上4是40。", + "knowledge_points": [ + "数的读写,组成与加法" + ], + "source": "" + }, + { + "id": "444", + "unit": "第四单元100以内数的认识5", + "question_type": "填空题", + "difficulty": 0.3, + "question": "王爷爷的年龄是一个两位数,个位上的数字是最大的一位数,十位上是7,王爷爷的年龄是( )岁。这个数读作( ),和这个数相邻的两个数分别是( )和( )。", + "options": [ + + ], + "answer": "79;七十九;78;80", + "solution": "【分析】最大的一位数是9,因此这个两位数是79;79读作七十九;相邻的数是78和80.\n【详解】王爷爷的年龄是79岁,读作七十九,相邻的两个数是78和80。", + "knowledge_points": [ + "数的组成,读写与相邻数" + ], + "source": "" + }, + { + "id": "445", + "unit": "第四单元100以内数的认识5", + "question_type": "填空题", + "difficulty": 0.3, + "question": "按规律填数.\n(1)12,14,16,18,( ),( ).\n(2)70,65,60,55,( ),( )。", + "options": [ + + ], + "answer": "20;22;50;45", + "solution": "【分析】(1)每次增加2;(2)每次减少5.\n【详解】(1)18+2=20,20+2=22;(2)55-5=50,50-5=45。", + "knowledge_points": [ + "数的规律" + ], + "source": "" + }, + { + "id": "446", + "unit": "第四单元100以内数的认识5", + "question_type": "填空题", + "difficulty": 0.3, + "question": "78十位上的7表示( )个( ),个位上的8表示( )个( )。", + "options": [ + + ], + "answer": "7;十;8;一", + "solution": "【分析】十位上的数表示几个十,个位上的数表示几个一.\n【详解】78十位上的7表示7个十,个位上的8表示8个一。", + "knowledge_points": [ + "数位的意义" + ], + "source": "" + }, + { + "id": "447", + "unit": "第四单元100以内数的认识5", + "question_type": "填空题", + "difficulty": 0.65, + "question": "一个两位数,从右边起,第一位上的数是8,第二位上的数是5,这个两位数是( 58 )与它最接近的整十数是( )。", + "options": [ + + ], + "answer": "58;60", + "solution": "【分析】从右起第一位是个位,第二位是十位,因此这个数是58;与58最接近的整十数是60.\n【详解】这个两位数是58,与它最接近的整十数是60。", + "knowledge_points": [ + "数的组成与接近的整十数" + ], + "source": "" + }, + { + "id": "448", + "unit": "第四单元100以内数的认识5", + "question_type": "填空题", + "difficulty": 0.3, + "question": "![](images/da98ef174070cd006d210e6be701d41e36b4c7b89908b2e35044f20757b95aee.jpg) 在十位上加1个珠子后,表示的数是( )。", + "options": [ + + ], + "answer": "52", + "solution": "【分析】原计数器表示42(4个十和2个一),十位加1个珠子后变成5个十和2个一,即52.\n【详解】在十位上加1个珠子后,表示的数是52。", + "knowledge_points": [ + "计数器的使用" + ], + "source": "" + }, + { + "id": "449", + "unit": "第四单元100以内数的认识5", + "question_type": "填空题", + "difficulty": 0.3, + "question": "填一填.\n![](images/bba1c76feed7cbe833d066a8a9e5999dceabddfcc66e7c7be9731d7c214e2de2.jpg)\n( )个十和( )个一是( )。", + "options": [ + + ], + "answer": "3;6;36", + "solution": "【分析】图中有3捆小棒(每捆10根)和6根单根,表示3个十和6个一,合起来是36.\n【详解】3个十和6个一是36。", + "knowledge_points": [ + "数的组成" + ], + "source": "" + }, + { + "id": "450", + "unit": "第四单元100以内数的认识5", + "question_type": "填空题", + "difficulty": 0.3, + "question": "一个两位数,个位上是3,十位是2,这个数是( )。", + "options": [ + + ], + "answer": "23", + "solution": "【分析】十位是2,个位是3,组成的数是23.\n【详解】这个数是23。", + "knowledge_points": [ + "数的组成" + ], + "source": "" + }, + { + "id": "451", + "unit": "第四单元100以内数的认识5", + "question_type": "填空题", + "difficulty": 0.3, + "question": "5个十和6个一组成( );100里面有( )个十。", + "options": [ + + ], + "answer": "56;10", + "solution": "【分析】5个十是50,6个一是6,合起来是56;10个十是100.\n【详解】5个十和6个一组成56;100里面有10个十。", + "knowledge_points": [ + "数的组成" + ], + "source": "" + }, + { + "id": "452", + "unit": "第四单元100以内数的认识5", + "question_type": "填空题", + "difficulty": 0.3, + "question": "十位上是2的两位数有( )个。", + "options": [ + + ], + "answer": "10", + "solution": "【分析】十位是2的两位数从20到29,共10个.\n【详解】十位上是2的两位数有10个。", + "knowledge_points": [ + "数的特征" + ], + "source": "" + }, + { + "id": "453", + "unit": "第四单元100以内数的认识5", + "question_type": "填空题", + "difficulty": 0.65, + "question": "在51,83,100,62,9这些数中:一位数是( ),( )是三位数,两位数有( )个。把它们按从小到大的顺序排列是( )。", + "options": [ + + ], + "answer": "9;100;3;9\u003c51\u003c62\u003c83\u003c100", + "solution": "【分析】一位数只有一个数字;三位数有三个数字;两位数有两个数字。比较大小后排列.\n【详解】一位数是9;100是三位数;两位数有51,83,62,共3个;从小到大排列为9\u003c51\u003c62\u003c83\u003c100。", + "knowledge_points": [ + "数的分类与大小比较" + ], + "source": "" + }, + { + "id": "454", + "unit": "第四单元100以内数的认识5", + "question_type": "填空题", + "difficulty": 0.3, + "question": "6个十和5个一合成( ),读作( )。", + "options": [ + + ], + "answer": "65;六十五", + "solution": "【分析】6个十是60,5个一是5,合起来是65;读作六十五.\n【详解】6个十和5个一合成65,读作六十五。", + "knowledge_points": [ + "数的组成与读写" + ], + "source": "" + }, + { + "id": "455", + "unit": "第四单元100以内数的认识5", + "question_type": "填空题", + "difficulty": 0.3, + "question": "中华民族是由( )个民族组成的大家庭。这个数是由5个( )和6个( )组成。", + "options": [ + + ], + "answer": "56;十;一", + "solution": "【分析】56由5个十和6个一组成.\n【详解】中华民族是由56个民族组成的大家庭。这个数是由5个十和6个一组成。", + "knowledge_points": [ + "数的组成" + ], + "source": "" + }, + { + "id": "456", + "unit": "第四单元100以内数的认识5", + "question_type": "填空题", + "difficulty": 0.3, + "question": "一个两位数,个位上的数字是7,十位上的数字与个位上的数字相同,这个数是( );像前面这样的个位上的数字与十位上的数字相同的两位数一共有( )个。", + "options": [ + + ], + "answer": "77;9", + "solution": "【分析】十位和个位都是7的数是77;个位与十位相同的两位数有11,22,33,44,55,66,77,88,99,共9个.\n【详解】这个数是77;这样的两位数一共有9个。", + "knowledge_points": [ + "数的特征" + ], + "source": "" + }, + { + "id": "457", + "unit": "第四单元100以内数的认识5", + "question_type": "填空题", + "difficulty": 0.65, + "question": "在72,13,30,9,38,25中,最大的数是( ),比30小的数有( )个。把这些数从大到小顺序排一排:( )\u003e( )\u003e( )\u003e( )\u003e( )\u003e( )。", + "options": [ + + ], + "answer": "72;3;72;38;30;25;13;9", + "solution": "【分析】先找出最大的数,再找出比30小的数(13,9,25),最后从大到小排列.\n【详解】最大的数是72;比30小的数有13,9,25,共3个;从大到小排列为72\u003e38\u003e30\u003e25\u003e13\u003e9。", + "knowledge_points": [ + "数的大小比较" + ], + "source": "" + }, + { + "id": "458", + "unit": "第四单元100以内数的认识5", + "question_type": "填空题", + "difficulty": 0.3, + "question": "8个一和6个十组成( ),和它相邻的数是( )和( )。", + "options": [ + + ], + "answer": "68;67;69", + "solution": "【分析】6个十是60,8个一是8,合起来是68;相邻的数是67和69.\n【详解】8个一和6个十组成68,和它相邻的数是67和69。", + "knowledge_points": [ + "数的组成与相邻数" + ], + "source": "" + }, + { + "id": "459", + "unit": "第四单元100以内数的认识5", + "question_type": "填空题", + "difficulty": 0.65, + "question": "从1写到100,一共写了( )个\"8\"。", + "options": [ + + ], + "answer": "20", + "solution": "【分析】列举含8的数:8,18,28,38,48,58,68,78,80,81,82,83,84,85,86,87,88,89,98,其中88有两个8,共20个.\n【详解】从1写到100,一共写了20个\"8\"。", + "knowledge_points": [ + "数的计数" + ], + "source": "" + }, + { + "id": "460", + "unit": "第四单元100以内数的认识5", + "question_type": "填空题", + "difficulty": 0.3, + "question": "9个十和6个一组成的数是( ),它往后数4个数是( )。", + "options": [ + + ], + "answer": "96;100", + "solution": "【分析】9个十是90,6个一是6,合起来是96;96往后数4个数是97,98,99,100.\n【详解】9个十和6个一组成的数是96,它往后数4个数是100。", + "knowledge_points": [ + "数的组成与顺序" + ], + "source": "" + }, + { + "id": "461", + "unit": "第四单元100以内数的认识5", + "question_type": "填空题", + "difficulty": 0.3, + "question": "5个一和9个十合起来是( ),它再添上( )个一就是100。", + "options": [ + + ], + "answer": "95;5", + "solution": "【分析】9个十是90,5个一是5,合起来是95;95+5=100.\n【详解】5个一和9个十合起来是95,它再添上5个一就是100。", + "knowledge_points": [ + "数的组成与加法" + ], + "source": "" + }, + { + "id": "462", + "unit": "第四单元100以内数的认识5", + "question_type": "填空题", + "difficulty": 0.3, + "question": "99是一个( )位数,左边的\"9\"表示( )个( )。", + "options": [ + + ], + "answer": "两;9;十", + "solution": "【分析】99有两个数字,是两位数;左边的9在十位,表示9个十.\n【详解】99是一个两位数,左边的\"9\"表示9个十。", + "knowledge_points": [ + "数位与计数单位" + ], + "source": "" + }, + { + "id": "463", + "unit": "第四单元100以内数的认识5", + "question_type": "填空题", + "difficulty": 0.65, + "question": "一个两位数,个位上是3,十位上是9,这个数再添上( )是100;100里面有( )个十;有( )个一。", + "options": [ + + ], + "answer": "7;10;100", + "solution": "【分析】这个两位数是93,93+7=100;100里面有10个十,有100个一.\n【详解】这个数再添上7是100;100里面有10个十;有100个一。", + "knowledge_points": [ + "数的组成与加法" + ], + "source": "" + }, + { + "id": "464", + "unit": "第四单元100以内数的认识5", + "question_type": "填空题", + "difficulty": 0.3, + "question": "84里面有( )个十和( )个一;100里面有( )个十。", + "options": [ + + ], + "answer": "8;4;10", + "solution": "【分析】84的十位是8,表示8个十;个位是4,表示4个一;100里面有10个十.\n【详解】84里面有8个十和4个一;100里面有10个十。", + "knowledge_points": [ + "数的组成" + ], + "source": "" + }, + { + "id": "465", + "unit": "第四单元100以内数的认识5", + "question_type": "填空题", + "difficulty": 0.3, + "question": "60里面有( )个十;3个一和8个十合起来是( )。", + "options": [ + + ], + "answer": "6;83", + "solution": "【分析】60里面有6个十;8个十是80,加上3个一是83.\n【详解】60里面有6个十;3个一和8个十合起来是83。", + "knowledge_points": [ + "数的组成" + ], + "source": "" + }, + { + "id": "466", + "unit": "第四单元100以内数的认识5", + "question_type": "填空题", + "difficulty": 0.65, + "question": "在24,59,98,44,72这几个数中,与60最接近的数是(),把这几个数按从大到小的顺序排列( )。", + "options": [ + + ], + "answer": "59;98\u003e72\u003e59\u003e44\u003e24", + "solution": "【分析】与60最接近的数是59;从大到小排列为98,72,59,44,24.\n【详解】与60最接近的数是59;从大到小排列为98\u003e72\u003e59\u003e44\u003e24。", + "knowledge_points": [ + "数的接近程度与大小比较" + ], + "source": "" + }, + { + "id": "467", + "unit": "第四单元100以内数的认识5", + "question_type": "填空题", + "difficulty": 0.3, + "question": "由8个一和9个十组成的数是( ),与它相邻的两个数是( )和( )。", + "options": [ + + ], + "answer": "98;97;99", + "solution": "【分析】9个十是90,8个一是8,合起来是98;相邻的数是97和99.\n【详解】这个数是98,与它相邻的两个数是97和99。", + "knowledge_points": [ + "数的组成与相邻数" + ], + "source": "" + }, + { + "id": "468", + "unit": "第四单元100以内数的认识5", + "question_type": "填空题", + "difficulty": 0.3, + "question": "十位上是6,个位上是1,这个数是( )。", + "options": [ + + ], + "answer": "61", + "solution": "【分析】十位是6,个位是1,组成的数是61.\n【详解】这个数是61。", + "knowledge_points": [ + "数的组成" + ], + "source": "" + }, + { + "id": "469", + "unit": "第四单元100以内数的认识5", + "question_type": "填空题", + "difficulty": 0.65, + "question": "一个两位数的个位和十位上的数合起来是11,这个两位数最大是( ),最小是( )。", + "options": [ + + ], + "answer": "92;29", + "solution": "【分析】两数和为11,最大时十位取9(个位为2),组成92;最小时十位取2(个位为9),组成29.\n【详解】这个两位数最大是92,最小是29。", + "knowledge_points": [ + "数的组成与大小" + ], + "source": "" + }, + { + "id": "470", + "unit": "第四单元100以内数的认识5", + "question_type": "填空题", + "difficulty": 0.65, + "question": "十位上的数比个位上的数多8,这个两位数可能是()。", + "options": [ + + ], + "answer": "80或91", + "solution": "【分析】十位比个位多8,可能的情况:十位是8,个位是0(80);十位是9,个位是1(91).\n【详解】这个两位数可能是80或91。", + "knowledge_points": [ + "数的组成" + ], + "source": "" + }, + { + "id": "471", + "unit": "第四单元100以内数的认识5", + "question_type": "填空题", + "difficulty": 0.3, + "question": "4个十和5个一合起来是( ),32中的\"3\"在( )位上,表示3个( )。", + "options": [ + + ], + "answer": "45;十;十", + "solution": "【分析】4个十是40,5个一是5,合起来是45;32的\"3\"在十位,表示3个十.\n【详解】4个十和5个一合起来是45;32中的\"3\"在十位上,表示3个十。", + "knowledge_points": [ + "数的组成与数位意义" + ], + "source": "" + }, + { + "id": "472", + "unit": "第四单元100以内数的认识5", + "question_type": "填空题", + "difficulty": 0.3, + "question": "个位上是6的最大两位数是( 96 ),最小两位数是( 16 )。", + "options": [ + + ], + "answer": "96;16", + "solution": "【分析】个位是6的最大两位数是96,最小两位数是16.\n【详解】个位上是6的最大两位数是96,最小两位数是16。", + "knowledge_points": [ + "数的特征" + ], + "source": "" + }, + { + "id": "473", + "unit": "第四单元100以内数的认识5", + "question_type": "填空题", + "difficulty": 0.3, + "question": "一个两位数,个位上是0,十位上是8,这个数是( ),和它相邻的两个数是( )和( )。", + "options": [ + + ], + "answer": "80;79;81", + "solution": "【分析】十位是8,个位是0,组成的数是80;相邻的数是79和81.\n【详解】这个数是80,和它相邻的两个数是79和81。", + "knowledge_points": [ + "数的组成与相邻数" + ], + "source": "" + }, + { + "id": "474", + "unit": "第四单元100以内数的认识5", + "question_type": "填空题", + "difficulty": 0.3, + "question": "一个一个地数。82前面第5个数是( 77 )。", + "options": [ + + ], + "answer": "77", + "solution": "【分析】从82往前数5个数:81,80,79,78,77.\n【详解】82前面第5个数是77。", + "knowledge_points": [ + "数的顺序" + ], + "source": "" + }, + { + "id": "475", + "unit": "第四单元100以内数的认识5", + "question_type": "填空题", + "difficulty": 0.65, + "question": "一个数,十位上是8,个位上的数字比十位上的数字少5,则这个数是( ),读作( ),它里面有( )个一和( )个十。", + "options": [ + + ], + "answer": "83;八十三;3;8", + "solution": "【分析】个位数字=8-5=3,因此这个数是83;83读作八十三;它由8个十和3个一组成.\n【详解】这个数是83,读作八十三,它里面有3个一和8个十。", + "knowledge_points": [ + "数的组成,读写与数位意义" + ], + "source": "" + }, + { + "id": "476", + "unit": "第四单元100以内数的认识5", + "question_type": "填空题", + "difficulty": 0.3, + "question": "与75相邻的数是( )和( )。", + "options": [ + + ], + "answer": "74;76", + "solution": "【分析】相邻的两个数相差1.\n【详解】75-1=74,75+1=76。", + "knowledge_points": [ + "相邻数" + ], + "source": "" + }, + { + "id": "477", + "unit": "第四单元100以内数的认识5", + "question_type": "填空题", + "difficulty": 0.3, + "question": "个位上是1,十位上是6,这个数是( );9个十是( )。", + "options": [ + + ], + "answer": "61;90", + "solution": "【分析】十位是6,个位是1,组成的数是61;9个十是90.\n【详解】这个数是61;9个十是90。", + "knowledge_points": [ + "数的组成" + ], + "source": "" + }, + { + "id": "478", + "unit": "第四单元100以内数的认识5", + "question_type": "填空题", + "difficulty": 0.3, + "question": "一个数由5个十和4个一组成,这个数是( ),读作( )。", + "options": [ + + ], + "answer": "54;五十四", + "solution": "【分析】5个十是50,4个一是4,合起来是54;读作五十四.\n【详解】这个数是54,读作五十四。", + "knowledge_points": [ + "数的组成与读写" + ], + "source": "" + }, + { + "id": "479", + "unit": "第四单元100以内数的认识5", + "question_type": "填空题", + "difficulty": 0.3, + "question": "69读作:( ),它是由6个( )和9个( )组成的。", + "options": [ + + ], + "answer": "六十九;十;一", + "solution": "【分析】69读作六十九;6在十位表示6个十,9在个位表示9个一.\n【详解】69读作六十九,它是由6个十和9个一组成的。", + "knowledge_points": [ + "数的读写与组成" + ], + "source": "" + }, + { + "id": "480", + "unit": "第四单元100以内数的认识5", + "question_type": "填空题", + "difficulty": 0.3, + "question": "中华人民共和国有56个民族组成,56是由( )个十和( )个一组成的。", + "options": [ + + ], + "answer": "5;6", + "solution": "【分析】56的十位是5,表示5个十;个位是6,表示6个一.\n【详解】56是由5个十和6个一组成的。", + "knowledge_points": [ + "数的组成" + ], + "source": "" + }, + { + "id": "481", + "unit": "第四单元100以内数的认识5", + "question_type": "填空题", + "difficulty": 0.3, + "question": "在45,78,37,51,10中,( )比40多得多,( )比40少一些。", + "options": [ + + ], + "answer": "78;37", + "solution": "【分析】78比40大很多;37比40稍小.\n【详解】78比40多得多;37比40少一些。", + "knowledge_points": [ + "数的相对大小" + ], + "source": "" + }, + { + "id": "482", + "unit": "第四单元100以内数的认识5", + "question_type": "填空题", + "difficulty": 0.3, + "question": "在47,58,63这三个数中,最接近60的是( )。", + "options": [ + + ], + "answer": "58", + "solution": "【分析】分别计算各数与60的差:60-47=13,60-58=2,63-60=3.\n【详解】差最小的是58,因此最接近60的数是58。", + "knowledge_points": [ + "数的接近程度" + ], + "source": "" + }, + { + "id": "483", + "unit": "第四单元100以内数的认识5", + "question_type": "填空题", + "difficulty": 0.3, + "question": "8个一和4个十合起来是( ),这个数读作( )。", + "options": [ + + ], + "answer": "48;四十八", + "solution": "【分析】4个十是40,8个一是8,合起来是48;读作四十八.\n【详解】8个一和4个十合起来是48,读作四十八。", + "knowledge_points": [ + "数的组成与读写" + ], + "source": "" + }, + { + "id": "484", + "unit": "第四单元100以内数的认识5", + "question_type": "填空题", + "difficulty": 0.65, + "question": "一个两位数,个位和十位上的数合起来是12,这个数最大是( ),最小是( )。", + "options": [ + + ], + "answer": "93;39", + "solution": "【分析】两数和为12,最大时十位取9(个位为3),组成93;最小时十位取3(个位为9),组成39.\n【详解】这个数最大是93,最小是39。", + "knowledge_points": [ + "数的组成与大小" + ], + "source": "" + }, + { + "id": "485", + "unit": "第四单元100以内数的认识5", + "question_type": "填空题", + "difficulty": 0.65, + "question": "一个两位数,十位上是最大的一位数,个位上的数比十位上的数少7,这个两位数是( ),比这个数多8的数是( )。", + "options": [ + + ], + "answer": "92;100", + "solution": "【分析】最大的一位数是9,个位=9-7=2,因此这个数是92;92+8=100.\n【详解】这个两位数是92,比这个数多8的数是100。", + "knowledge_points": [ + "数的组成与加法" + ], + "source": "" + }, + { + "id": "486", + "unit": "第四单元100以内数的认识5", + "question_type": "填空题", + "difficulty": 0.65, + "question": "有一个两位数,十位上的数字比个位上的数字大9,这个数是( )。", + "options": [ + + ], + "answer": "90", + "solution": "【分析】十位比个位大9,十位最大为9,则个位为0,因此这个数是90.\n【详解】这个两位数是90。", + "knowledge_points": [ + "数的组成" + ], + "source": "" + }, + { + "id": "487", + "unit": "第四单元100以内数的认识5", + "question_type": "判断题", + "difficulty": 0.3, + "question": "77这个数,个位上的\"7\"和十位上的\"7\"表示意义不同。( )", + "options": [ + + ], + "answer": "√", + "solution": "【分析】个位上的7表示7个一,十位上的7表示7个十,意义不同.\n【详解】原说法正确。", + "knowledge_points": [ + "数位的意义" + ], + "source": "" + }, + { + "id": "488", + "unit": "第四单元100以内数的认识5", + "question_type": "判断题", + "difficulty": 0.3, + "question": "9个一,7个十组成的数是97。()", + "options": [ + + ], + "answer": "×", + "solution": "【分析】9个一是9,7个十是70,合起来是79.\n【详解】组成的数是79,原说法错误。", + "knowledge_points": [ + "数的组成" + ], + "source": "" + }, + { + "id": "489", + "unit": "第四单元100以内数的认识5", + "question_type": "判断题", + "difficulty": 0.3, + "question": "5个十和50同样大。()", + "options": [ + + ], + "answer": "√", + "solution": "【分析】5个十就是50.\n【详解】5个十和50相等,原说法正确。", + "knowledge_points": [ + "数的组成" + ], + "source": "" + }, + { + "id": "490", + "unit": "第四单元100以内数的认识5", + "question_type": "判断题", + "difficulty": 0.3, + "question": "77和82之间有6个数。( )", + "options": [ + + ], + "answer": "×", + "solution": "【分析】77和82之间的数有78,79,80,81,共4个.\n【详解】之间有4个数,原说法错误。", + "knowledge_points": [ + "数的顺序" + ], + "source": "" + }, + { + "id": "491", + "unit": "第四单元100以内数的认识5", + "question_type": "判断题", + "difficulty": 0.3, + "question": "26的个位上的数字比十位上的数字小4。( )", + "options": [ + + ], + "answer": "×", + "solution": "【分析】个位6比十位2大4.\n【详解】个位比十位大4,原说法错误。", + "knowledge_points": [ + "数位的大小比较" + ], + "source": "" + }, + { + "id": "492", + "unit": "第四单元100以内数的认识5", + "question_type": "判断题", + "difficulty": 0.3, + "question": "十个十个地数,70后面的数是71。( )", + "options": [ + + ], + "answer": "×", + "solution": "【分析】十个十个地数,70后面是80.\n【详解】70后面的数是80,原说法错误。", + "knowledge_points": [ + "数的顺序" + ], + "source": "" + }, + { + "id": "493", + "unit": "第四单元100以内数的认识5", + "question_type": "判断题", + "difficulty": 0.3, + "question": "比30大得多,比80少一些的数是38。( )", + "options": [ + + ], + "answer": "×", + "solution": "【分析】38比30大一些,比80少得多.\n【详解】38不符合\"大得多\"和\"少一些\",原说法错误。", + "knowledge_points": [ + "数的相对大小" + ], + "source": "" + }, + { + "id": "494", + "unit": "第四单元100以内数的认识5", + "question_type": "判断题", + "difficulty": 0.3, + "question": "六十四这个数写作46。( )", + "options": [ + + ], + "answer": "×", + "solution": "【分析】六十四写作64.\n【详解】原写法错误。", + "knowledge_points": [ + "数的写法" + ], + "source": "" + }, + { + "id": "495", + "unit": "第四单元100以内数的认识5", + "question_type": "判断题", + "difficulty": 0.3, + "question": "一个两位数,十位上是几,就表示有几个十。( )", + "options": [ + + ], + "answer": "√", + "solution": "【分析】十位上的数表示几个十.\n【详解】原说法正确。", + "knowledge_points": [ + "数位的意义" + ], + "source": "" + }, + { + "id": "496", + "unit": "第四单元100以内数的认识5", + "question_type": "判断题", + "difficulty": 0.3, + "question": "一个两位数,十位上的数字和个位上的数字相同,并且它们的和为6,这个两位数是66。( )", + "options": [ + + ], + "answer": "×", + "solution": "【分析】两数相同且和为6,每个数是3,因此这个两位数是33.\n【详解】这个两位数是33,原说法错误。", + "knowledge_points": [ + "数的组成" + ], + "source": "" + }, + { + "id": "497", + "unit": "第四单元100以内数的认识5", + "question_type": "判断题", + "difficulty": 0.3, + "question": "体育室有4个篮球和38个小足球,小足球个数比篮球少得多。( )", + "options": [ + + ], + "answer": "×", + "solution": "【分析】38比4多得多,因此小足球比篮球多得多.\n【详解】原说法错误。", + "knowledge_points": [ + "数的相对大小" + ], + "source": "" + }, + { + "id": "498", + "unit": "第四单元100以内数的认识5", + "question_type": "计算题", + "difficulty": 0.3, + "question": "看图列式计算.\n![](images/19d0278c32ca9231d8fab6187e774a2114e1d3ba0852dcf3bdccf66e1215bc7d.jpg)\n![](images/42d1410a11cbe2c77e42b6030d06eaca5fcc2fdcf002099b6a49ca90704800eb.jpg)", + "options": [ + + ], + "answer": "28-8=20", + "solution": "【分析】总共有28个桃子,右边有8个,求左边篮子里有多少个.\n【详解】28-8=20(个),左边篮子里有20个桃子。", + "knowledge_points": [ + "减法应用" + ], + "source": "" + }, + { + "id": "499", + "unit": "第四单元100以内数的认识5", + "question_type": "计算题", + "difficulty": 0.3, + "question": "列算式.\n![](images/5645c0db1b43c286b1b3bb29f76221baf85d7dc140332fc3e3a2839212976fd9.jpg)\n![](images/b4222f5e91f418eae6d17fdfb3988a2de7f65771fda32e9f7152631c4afe5ff1.jpg)", + "options": [ + + ], + "answer": "34-4=30", + "solution": "【分析】总共有34个桃子,右边有4个,求左边有多少个.\n【详解】34-4=30(个),左边有30个。", + "knowledge_points": [ + "减法应用" + ], + "source": "" + }, + { + "id": "500", + "unit": "第四单元100以内数的认识5", + "question_type": "计算题", + "difficulty": 0.3, + "question": "看图列式计算.\n![](images/e45d304d56b744a4f78126b083cef0a7a4bb2f52b4f5a98b4c5941bbca457c05.jpg)\n![](images/db53f8f6adf30659440ffa6bccb65e868b1eda6fa2a79fadc51cbc10c13ca50b.jpg)", + "options": [ + + ], + "answer": "60+6=66", + "solution": "【分析】左边箱子里有60个苹果,右边有6个,求总共有多少个.\n【详解】60+6=66(个),总共有66个苹果。", + "knowledge_points": [ + "加法应用" + ], + "source": "" + } +] \ No newline at end of file