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md/test/kLZsLlIpDU/kLZsLlIpDU.md
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Binary files a/md/test/kLZsLlIpDU/kLZsLlIpDU.md and b/md/test/kLZsLlIpDU/kLZsLlIpDU.md differ
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md/train/66H4g_OHdnl/66H4g_OHdnl.md
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@@ -461,7 +461,7 @@ $$
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\sum _ { l = 1 } ^ { L } \| \mathbf { W } _ { l } \| _ { F } ^ { 2 } \geq \sum _ { l = 1 } ^ { L - 2 } \| \mathbf { W } _ { l } \| _ { F } ^ { 2 } + 2 \sum _ { j = 1 } ^ { m } | w _ { L , j } | \ \| \mathbf { w } _ { L - 1 , j } \| _ { 2 } ,
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$$
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where the equality is achieved with the scaling choice αj =
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Now, let us consider a modified version of the problem, where the unit norm equality constraint is relaxed as $\| \mathbf { w } _ { L - 1 , j } \| _ { 2 } \leq 1$ . Let us also assume that for a certain index $j$ , we obtain $\| \mathbf { w } _ { L - 1 , j } \| _ { 2 } <$ 1 with $w _ { L , j } \neq 0$ as an optimal solution. This shows that the unit norm inequality constraint is not active for ${ \bf w } _ { L - 1 , j }$ , and hence removing the constraint for ${ \bf w } _ { L - 1 , j }$ will not change the optimal solution. However, when we remove the constraint, $\| \mathbf { w } _ { L - 1 , j } \| _ { 2 } \to \bar { \infty }$ reduces the objective value since it yields $w _ { L , j } = 0$ . Therefore, we have a contradiction, which proves that all the constraints that correspond to a nonzero $w _ { L , j }$ must be active for an optimal solution. This also shows that replacing $\| \mathbf { w } _ { L - 1 , j } \| _ { 2 } = 1$ with $\| \tilde { \mathbf { w } } _ { L - 1 , j } \| _ { 2 } \leq 1$ does not change the solution to the problem.
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\sum _ { l = 1 } ^ { L } \| \mathbf { W } _ { l } \| _ { F } ^ { 2 } \geq \sum _ { l = 1 } ^ { L - 2 } \| \mathbf { W } _ { l } \| _ { F } ^ { 2 } + 2 \sum _ { j = 1 } ^ { m } | w _ { L , j } | \ \| \mathbf { w } _ { L - 1 , j } \| _ { 2 } ,
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$$
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where the equality is achieved with the scaling choice αj = |wL,j |kwL−1,jk2 is used. Since the scaling operation does not change the right-hand side of the inequality, we can set $\| \mathbf { w } _ { L - 1 , j } \| _ { 2 } = 1 , \forall j$ . Therefore, the right-hand side becomes $\| \mathbf { w } _ { L } \| _ { 1 }$ .
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Now, let us consider a modified version of the problem, where the unit norm equality constraint is relaxed as $\| \mathbf { w } _ { L - 1 , j } \| _ { 2 } \leq 1$ . Let us also assume that for a certain index $j$ , we obtain $\| \mathbf { w } _ { L - 1 , j } \| _ { 2 } <$ 1 with $w _ { L , j } \neq 0$ as an optimal solution. This shows that the unit norm inequality constraint is not active for ${ \bf w } _ { L - 1 , j }$ , and hence removing the constraint for ${ \bf w } _ { L - 1 , j }$ will not change the optimal solution. However, when we remove the constraint, $\| \mathbf { w } _ { L - 1 , j } \| _ { 2 } \to \bar { \infty }$ reduces the objective value since it yields $w _ { L , j } = 0$ . Therefore, we have a contradiction, which proves that all the constraints that correspond to a nonzero $w _ { L , j }$ must be active for an optimal solution. This also shows that replacing $\| \mathbf { w } _ { L - 1 , j } \| _ { 2 } = 1$ with $\| \tilde { \mathbf { w } } _ { L - 1 , j } \| _ { 2 } \leq 1$ does not change the solution to the problem.
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md/train/ujmgfuxSLrO/ujmgfuxSLrO.md
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@@ -48,7 +48,7 @@ $$
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\mathbf { Y } ^ { l } = \left\{ \begin{array} { l l } { \mathcal { F } \left( \mathbf { X } , \mathbf { W } ^ { l } , \mathbf { b } ^ { l } , g ^ { l } \right) , } & { l = 1 } \\ { \mathcal { F } \left( \mathcal { H } \left( \mathbf { X } , \mathbf { Y } ^ { l - 1 } \right) , \mathbf { W } ^ { l } , \mathbf { b } ^ { l } , g ^ { l } \right) , } & { \mathrm { O t h e r w i s e } } \end{array} \right.
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$$
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where $\mathbf { W } ^ { l } = \left\{ \mathbf { W } _ { 1 } ^ { l } , \cdot \cdot \cdot , \mathbf { W } _ { g ^ { l } } ^ { l } \right\}$ and $\mathbf { b } ^ { l } = \left\{ \mathbf { b } _ { 1 } ^ { l } , \cdot \cdot \cdot , \mathbf { b } _ { g ^ { l } } ^ { l } \right\}$ are the learnable weights and biases of group linear transformation $\mathcal { F }$ with $g ^ { l }$ groups at the $l$ -th layer. Briefly, the $\mathcal { F }$ function takes the input $\mathbf { X }$ |