"""Figure 1A data and analysis: informative 1H shift differences are too small for DFT to resolve. Loads per-site 1H shift spread across the Goodman CP3 stereoisomers and classifies each site against the experimental noise floor (0.02 ppm) and DFT's resolving power (0.10 ppm); ~36% fall in between. Data: `goodman2009_cp3.xlsx` (Goodman, J. Org. Chem. 2009, 74, 4597), shipped alongside. Plotting is in the figure notebook. """ import os import numpy as np import pandas as pd HERE = os.path.dirname(os.path.abspath(__file__)) CP3_XLSX = os.path.join(HERE, "..", "..", "data", "cp3", "goodman2009_cp3.xlsx") # accuracy thresholds in ppm: the experimental noise floor, the DFT resolving limit, and the cutoff # above which a variation counts as large. These define the zones a site's variation falls into. EXPERIMENTAL_LIMIT = 0.02 DFT_LIMIT = 0.10 LARGE_VARIATION = 0.30 def load_variations(path=CP3_XLSX, nucleus="H"): """The per-site chemical-shift standard deviations across the CP3 stereoisomers for one nucleus ("H" or "C"), as a 1D array of finite values (ppm).""" df = pd.read_excel(path) x = df[df["nucleus"] == nucleus]["stdev"].to_numpy(dtype=float) return x[np.isfinite(x)] def _zone(value): """Classify one variation (ppm) into its accuracy zone: within experimental noise, informative but below the DFT resolving limit, resolvable by DFT, or large.""" if value < EXPERIMENTAL_LIMIT: return "below_experimental" if value < DFT_LIMIT: return "below_dft" if value < LARGE_VARIATION: return "dft_zone" return "large" def fraction_below_dft(variations, lo=EXPERIMENTAL_LIMIT, hi=DFT_LIMIT, bins=30): """The fraction of the variation histogram's area between the experimental floor and the DFT limit: the sites whose shift variation is informative but too small for DFT to resolve (the paper's 36%). Computed as histogram area in [lo, hi] over total area, splitting the bins that straddle a boundary, exactly as the figure does.""" edges = np.linspace(0.0, float(variations.max()), bins + 1) counts, edge = np.histogram(variations, bins=edges) total = window = 0.0 for height, left, right in zip(counts, edge[:-1], edge[1:]): total += height * (right - left) overlap = max(0.0, min(right, hi) - max(left, lo)) window += height * overlap return window / total if total > 0 else float("nan")