| {"schema": 2, "epoch": 87557, "nonce": "b3954efd5f6efd7e", "hotkey": "5CaXH581GtSjxFaFaJzSN35CyKzvFMQhRAxrNy6qmoztNiPz", "source_hash": "24837b9ae6895829747c5eb448673693fedbeb2e3e62a5ca170051a512053fc0", "weights_hash": "19aafcfeb694bb06e7fbbedbfd7fce6c50bd3389a57eeefd1b5d2e5475afdd62", "model_id": "router", "total_cost_usd": 0.0029937500000000003, "n_calls": 6, "call_log_hash": "3541a78b501466ee15af55717d791befbdb38dfb538f26755acae69b20d65666", "measurement": "1449fadb4821cadef93f7eecc8c3b040e2cd244e01a2607ea531e5f7055c38d8", "confined": true, "latency_s": 138.263, "tokens_in": 1248, "tokens_out": 21370, "results": [{"benchmark": "mmlu", "task_id": "mmlu-4925", "answer": "C", "cost_usd": 7.2000000000000005e-06, "chosen_rung": 4, "rungs_used": [4], "distribution": [0.227438, 0.000549, 0.000478, 0.000642, 0.769304, 0.001177, 0.000412]}, {"benchmark": "mmlu", "task_id": "mmlu-8832", "answer": "C", "cost_usd": 4.831e-05, "chosen_rung": 0, "rungs_used": [0], "distribution": [0.866292, 0.000549, 0.000414, 0.000605, 0.130563, 0.001136, 0.000442]}, {"benchmark": "math", "task_id": "gsm8k-661", "answer": "1. The more expensive coffee costs \\(5 \\times 1.20 = 6\\) dollars per pound.\n2. For 7 days, Roger needs 7 pounds: \\(7 \\times 6 = 42\\) dollars.\n3. Add the $2 donut: \\(42 + 2 = 44\\).\n\n44", "cost_usd": 9.610000000000002e-05, "chosen_rung": 4, "rungs_used": [4], "distribution": [0.000256, 1.4e-05, 1.3e-05, 2.1e-05, 0.999638, 4.6e-05, 1.2e-05]}, {"benchmark": "math", "task_id": "gsm8k-626", "answer": "20 kb/s \u00d7 3600 s/hour = 72,000 kb/hour \n72,000 kb/hour \u00f7 1000 kb/Mb = 72 Mb/hour \n\n72", "cost_usd": 6.460000000000003e-05, "chosen_rung": 4, "rungs_used": [4], "distribution": [0.347303, 0.000481, 0.000397, 0.000531, 0.649721, 0.001196, 0.000371]}, {"benchmark": "code", "task_id": "lcb-abc392_a", "answer": "import itertools\nimport sys\n\na = list(map(int, sys.stdin.read().split()))\n\nfor b in itertools.permutations(a):\n if b[0] * b[1] == b[2]:\n print(\"Yes\")\n break\nelse:\n print(\"No\")", "cost_usd": 6.49e-05, "chosen_rung": 4, "rungs_used": [4], "distribution": [0.009879, 3.6e-05, 2.8e-05, 4.4e-05, 0.989899, 9.3e-05, 2.2e-05]}, {"benchmark": "code", "task_id": "lcb-abc388_c", "answer": "```python\nimport sys\n\ndef main():\n # Read all input from standard input at once\n input_data = sys.stdin.read().split()\n \n if not input_data:\n return\n\n # The first token is N\n N = int(input_data[0])\n \n # The next N tokens are the sizes of the mochi A_1, ..., A_N\n # We convert them to integers.\n # We assume the input is well-formed as per constraints.\n # Slicing input_data[1:N+1] extracts the relevant tokens.\n if len(input_data) < N + 1:\n A = list(map(int, input_data[1:]))\n else:\n A = list(map(int, input_data[1:N+1]))\n \n # Clear input_data to free up memory\n del input_data\n \n ans = 0\n ptr = 0\n n_len = len(A)\n \n # The array A is sorted in non-decreasing order as per problem statement.\n # We iterate through each mochi considering it as the bottom one (index j).\n # We need to count the number of mochi (index i) that can be placed on top.\n # The condition is A[i] <= A[j] / 2.\n # Since A is sorted, the valid indices i will always form a prefix of the array.\n # We maintain a pointer 'ptr' which indicates the number of elements satisfying the condition.\n \n for j in range(n_len):\n # Calculate the maximum size allowed for the top mochi\n # Using bitwise shift for integer division by 2\n target = A[j] >> 1\n \n # Advance ptr while the element at ptr is within the allowed size.\n # ptr acts as the count of valid top mochi for the current bottom mochi.\n # Since A[j] is non-decreasing, target is non-decreasing, so ptr only moves forward.\n while ptr < n_len and A[ptr] <= target:\n ptr += 1\n \n # Add the number of valid top mochi to the answer\n ans += ptr\n \n print(ans)\n\nif __name__ == '__main__':\n main()\n```", "cost_usd": 0.00271264, "chosen_rung": 0, "rungs_used": [0], "distribution": [0.996716, 2.2e-05, 1.6e-05, 2.1e-05, 0.003166, 4.6e-05, 1.3e-05]}], "quote": {"measurement": "1449fadb4821cadef93f7eecc8c3b040e2cd244e01a2607ea531e5f7055c38d8", "report_data": "f313ecde3039f762df52e4292a46937014faa97a98616c3764eae05d465c65cb", "platform_sig": 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