| {"schema": 2, "epoch": 87587, "nonce": "2ee2e5bc37f2d9b4", "hotkey": "5CaXH581GtSjxFaFaJzSN35CyKzvFMQhRAxrNy6qmoztNiPz", "source_hash": "24837b9ae6895829747c5eb448673693fedbeb2e3e62a5ca170051a512053fc0", "weights_hash": "19aafcfeb694bb06e7fbbedbfd7fce6c50bd3389a57eeefd1b5d2e5475afdd62", "model_id": "router", "total_cost_usd": 0.00703403, "n_calls": 6, "call_log_hash": "b93c16e5b1a7a45cfc1312542c536ee79291924b573b417182cf87f0c7a782ae", "measurement": "1449fadb4821cadef93f7eecc8c3b040e2cd244e01a2607ea531e5f7055c38d8", "confined": true, "latency_s": 635.053, "tokens_in": 1896, "tokens_out": 51900, "results": [{"benchmark": "mmlu", "task_id": "mmlu-5278", "answer": "A", "cost_usd": 8.8e-06, "chosen_rung": 4, "rungs_used": [4], "distribution": [0.207086, 0.000509, 0.000469, 0.000617, 0.789611, 0.001308, 0.000401]}, {"benchmark": "mmlu", "task_id": "mmlu-12627", "answer": "C", "cost_usd": 6.18e-05, "chosen_rung": 4, "rungs_used": [4], "distribution": [0.003101, 7.1e-05, 6.4e-05, 9.2e-05, 0.996432, 0.000184, 5.5e-05]}, {"benchmark": "math", "task_id": "gsm8k-697", "answer": "- Great Grandma Jones has 3 children.\n- Each child has 3 children: \\(3 \\times 3 = 9\\) grandchildren.\n- Each grandchild has 3 babies: \\(9 \\times 3 = 27\\) great-grandbabies.\n\n27", "cost_usd": 8.22e-05, "chosen_rung": 4, "rungs_used": [4], "distribution": [0.060862, 0.000152, 0.000121, 0.000192, 0.938196, 0.000373, 0.000104]}, {"benchmark": "math", "task_id": "gsm8k-245", "answer": "The difference in snails is:\n\n32 \u2212 4 = 28\n\nLet each aquarium have \\(x\\) fish. Together, they have \\(2x\\) fish, and twice that amount is \\(4x\\).\n\nSo:\n\n\\(4x = 28\\)\n\n\\(x = 7\\)\n\n7", "cost_usd": 0.00011140000000000002, "chosen_rung": 4, "rungs_used": [4], "distribution": [0.009934, 9.8e-05, 8.7e-05, 0.000121, 0.989438, 0.000251, 7.1e-05]}, {"benchmark": "code", "task_id": "lcb-abc388_a", "answer": "import sys\n\ns = sys.stdin.readline().strip()\nprint(s[0] + \"UPC\")", "cost_usd": 3.6300000000000015e-05, "chosen_rung": 4, "rungs_used": [4], "distribution": [0.004002, 2e-05, 1.6e-05, 2.7e-05, 0.995859, 5.9e-05, 1.5e-05]}, {"benchmark": "code", "task_id": "lcb-abc400_d", "answer": "```python\nimport sys\nfrom collections import deque\n\n# Increase recursion depth just in case, though not strictly needed here\nsys.setrecursionlimit(2000)\n\ndef solve():\n # Read all input from stdin efficiently\n input_data = sys.stdin.read().split()\n if not input_data:\n return\n \n iterator = iter(input_data)\n try:\n H = int(next(iterator))\n W = int(next(iterator))\n grid = []\n for _ in range(H):\n grid.append(next(iterator))\n A = int(next(iterator)) - 1\n B = int(next(iterator)) - 1\n C = int(next(iterator)) - 1\n D = int(next(iterator)) - 1\n except StopIteration:\n return\n\n # Grid access: grid[r][c]\n # Coordinates are converted to 0-indexed.\n\n # Find connected components of '.' cells\n # comp_id[r][c] stores the component ID for cell (r, c), -1 if wall\n comp_id = [[-1] * W for _ in range(H)]\n comps = [] # List of lists of encoded coordinates (r * W + c)\n comp_cnt = 0\n \n # Directions: Up, Down, Left, Right\n dirs = [(-1, 0), (1, 0), (0, -1), (0, 1)]\n \n # Identify connected components\n for r in range(H):\n for c in range(W):\n if grid[r][c] == '.' and comp_id[r][c] == -1:\n # BFS to find the component\n q = deque([(r, c)])\n comp_id[r][c] = comp_cnt\n current_comp = [r * W + c]\n \n while q:\n cr, cc = q.popleft()\n for dr, dc in dirs:\n nr, nc = cr + dr, cc + dc\n if 0 <= nr < H and 0 <= nc < W:\n if grid[nr][nc] == '.' and comp_id[nr][nc] == -1:\n comp_id[nr][nc] = comp_cnt\n q.append((nr, nc))\n current_comp.append(nr * W + nc)\n \n comps.append(current_comp)\n comp_cnt += 1\n\n start_comp = comp_id[A][B]\n target_comp = comp_id[C][D]\n \n # If start and target are in the same component, 0 kicks needed\n if start_comp == target_comp:\n print(0)\n return\n \n # BFS for kicks\n # dist[i] stores min kicks to reach component i\n dist = [-1] * comp_cnt\n dist[start_comp] = 0\n queue = deque([start_comp])\n \n # Track processed walls to avoid redundant work\n # A wall is processed when we determine it can be turned into a road\n # by a kick from a reachable component.\n wall_visited = [[False] * W for _ in range(H)]\n \n while queue:\n curr_comp = queue.popleft()\n d = dist[curr_comp]\n \n if curr_comp == target_comp:\n print(d)\n return\n \n # Iterate all cells in current component\n # We check cells to see if they can trigger a kick that reaches new components.\n # A kick from cell (r, c) in direction (dr, dc) affects cells at distance 1 and 2.\n # If those cells are walls, they become roads, potentially connecting to other components.\n for encoded in comps[curr_comp]:\n r = encoded // W\n c = encoded % W\n \n for dr, dc in dirs:\n # Check cell at distance 1\n r1, c1 = r + dr, c + dc\n if 0 <= r1 < H and 0 <= c1 < W:\n if grid[r1][c1] == '#' and not wall_visited[r1][c1]:\n wall_visited[r1][c1] = True\n # Process wall: check its neighbors\n # If a neighbor is a road, it belongs to some component.\n # That component becomes reachable with d + 1 kicks.\n for ndr, ndc in dirs:\n nr, nc = r1 + ndr, c1 + ndc\n if 0 <= nr < H and 0 <= nc < W:\n if grid[nr][nc] == '.':\n nid = comp_id[nr][nc]\n if dist[nid] == -1:\n dist[nid] = d + 1\n queue.append(nid)\n \n # Check cell at distance 2\n r2, c2 = r + 2*dr, c + 2*dc\n if 0 <= r2 < H and 0 <= c2 < W:\n if grid[r2][c2] == '#' and not wall_visited[r2][c2]:\n wall_visited[r2][c2] = True\n # Process wall\n for ndr, ndc in dirs:\n nr, nc = r2 + ndr, c2 + ndc\n if 0 <= nr < H and 0 <= nc < W:\n if grid[nr][nc] == '.':\n nid = comp_id[nr][nc]\n if dist[nid] == -1:\n dist[nid] = d + 1\n queue.append(nid)\n\n # If target is unreachable (should not happen based on problem constraints usually)\n if dist[target_comp] != -1:\n print(dist[target_comp])\n else:\n print(-1)\n\nif __name__ == '__main__':\n solve()\n```", "cost_usd": 0.00673353, "chosen_rung": 0, "rungs_used": [0], "distribution": [0.997247, 2.1e-05, 1.4e-05, 2e-05, 0.002637, 4.7e-05, 1.4e-05]}], "quote": {"measurement": "1449fadb4821cadef93f7eecc8c3b040e2cd244e01a2607ea531e5f7055c38d8", "report_data": "d240e84344e3678936896924b54298efafbc8d3c4904fa4c2535d0bce8355130", "platform_sig": 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