{"schema": 2, "epoch": 87553, "nonce": "dac12bc035b4a4a6", "hotkey": "5CaXH581GtSjxFaFaJzSN35CyKzvFMQhRAxrNy6qmoztNiPz", "source_hash": "24837b9ae6895829747c5eb448673693fedbeb2e3e62a5ca170051a512053fc0", "weights_hash": "19aafcfeb694bb06e7fbbedbfd7fce6c50bd3389a57eeefd1b5d2e5475afdd62", "model_id": "router", "total_cost_usd": 0.0009135500000000001, "n_calls": 6, "call_log_hash": "67619cdf756c5f74641f3e6cf269c89a38a81811c30ad38a3c1fa57bd49b356c", "measurement": "1449fadb4821cadef93f7eecc8c3b040e2cd244e01a2607ea531e5f7055c38d8", "confined": true, "latency_s": 21.162, "tokens_in": 1058, "tokens_out": 1701, "results": [{"benchmark": "mmlu", "task_id": "mmlu-13580", "answer": "D", "cost_usd": 1.16e-05, "chosen_rung": 4, "rungs_used": [4], "distribution": [7.3e-05, 8e-06, 8e-06, 1.2e-05, 0.999868, 2.3e-05, 7e-06]}, {"benchmark": "mmlu", "task_id": "mmlu-8601", "answer": "D", "cost_usd": 6.015e-05, "chosen_rung": 0, "rungs_used": [0], "distribution": [0.799019, 0.000635, 0.000489, 0.00072, 0.197276, 0.001348, 0.000513]}, {"benchmark": "math", "task_id": "gsm8k-727", "answer": "1. Students\u2019 cars: \\(64 \\times 4 = 256\\) windows.  \n2. Hannah smashes one-quarter: \\(256 \\div 4 = 64\\) windows.  \n3. Teachers\u2019 cars: \\(32 \\times 2 = 64\\) windows.  \n4. Hannah smashes three-quarters: \\(64 \\times \\frac{3}{4} = 48\\) windows.  \n5. Total: \\(64 + 48 = 112\\).\n\n112", "cost_usd": 0.00011480000000000001, "chosen_rung": 4, "rungs_used": [4], "distribution": [0.010373, 6.1e-05, 4.7e-05, 8.4e-05, 0.989221, 0.00017, 4.5e-05]}, {"benchmark": "math", "task_id": "gsm8k-20", "answer": "- Initially, there are 10 liters of orange drink, with \\(\\frac{2}{3}\\) water.\n- Spilling 1 liter leaves \\(9\\) liters of orange drink.\n- Water in the remaining orange drink: \\(\\frac{2}{3}\\times 9=6\\) liters.\n- The pineapple drink contains \\(15\\times\\frac{3}{5}=9\\) liters of water.\n- Total water: \\(6+9=15\\) liters.\n\n15", "cost_usd": 0.0001161, "chosen_rung": 4, "rungs_used": [4], "distribution": [0.001101, 3.2e-05, 2.8e-05, 4.2e-05, 0.998684, 8.9e-05, 2.3e-05]}, {"benchmark": "code", "task_id": "lcb-abc398_a", "answer": "n = int(input())\nif n % 2:\n    s = ['-'] * n\n    s[n // 2] = '='\nelse:\n    s = ['-'] * n\n    s[n // 2 - 1] = s[n // 2] = '='\nprint(''.join(s))", "cost_usd": 9.230000000000002e-05, "chosen_rung": 4, "rungs_used": [4], "distribution": [0.017201, 3.4e-05, 2.5e-05, 4.5e-05, 0.982587, 8.6e-05, 2.3e-05]}, {"benchmark": "code", "task_id": "lcb-abc392_d", "answer": "import sys\n\ndef main():\n    data = list(map(int, sys.stdin.buffer.read().split()))\n    it = iter(data)\n    n = next(it)\n\n    ks = [0] * n\n    values = {}\n\n    for i in range(n):\n        k = next(it)\n        ks[i] = k\n        counts = {}\n        for _ in range(k):\n            x = next(it)\n            counts[x] = counts.get(x, 0) + 1\n        for x, c in counts.items():\n            values.setdefault(x, []).append((i, c))\n\n    probabilities = [[0.0] * n for _ in range(n)]\n\n    for entries in values.values():\n        m = len(entries)\n        for a in range(m):\n            i, ci = entries[a]\n            for b in range(a):\n                j, cj = entries[b]\n                probabilities[i][j] += ci * cj / (ks[i] * ks[j])\n\n    answer = 0.0\n    for i in range(n):\n        for j in range(i):\n            if probabilities[i][j] > answer:\n                answer = probabilities[i][j]\n\n    print(\"{:.15f}\".format(answer))\n\nif __name__ == \"__main__\":\n    main()\n", "cost_usd": 0.0005186, "chosen_rung": 4, "rungs_used": [4], "distribution": [0.004944, 2.8e-05, 2.4e-05, 3.7e-05, 0.994864, 8.2e-05, 2.1e-05]}], "quote": {"measurement": "1449fadb4821cadef93f7eecc8c3b040e2cd244e01a2607ea531e5f7055c38d8", "report_data": "6f8364efc5a4add815fdeb5bee03680f98b056756f5898a01aa6a7fd84e28be7", "platform_sig": 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