| {"schema": 2, "epoch": 87615, "nonce": "94b180b7ca4ee184", "hotkey": "5GuVFWnG62s4r1AGAfrhhHBMnsMPMXKNxrmBpeJdFGyCQEaX", "source_hash": "24837b9ae6895829747c5eb448673693fedbeb2e3e62a5ca170051a512053fc0", "weights_hash": "095ffbac36e314358948a86370be2e0be5384b2278d5ee9bc924d7f155c7d474", "model_id": "router", "total_cost_usd": 0.0015864, "n_calls": 6, "call_log_hash": "26b84a511d8b31e11428199b61441c19a2086fd2e3ef25f4e4bd588e4612c1ff", "measurement": "1449fadb4821cadef93f7eecc8c3b040e2cd244e01a2607ea531e5f7055c38d8", "confined": true, "latency_s": 33.76, "tokens_in": 1638, "tokens_out": 2371, "results": [{"benchmark": "mmlu", "task_id": "mmlu-4007", "answer": "D", "cost_usd": 9.5e-06, "chosen_rung": 4, "rungs_used": [4], "distribution": [0.008476, 0.002288, 0.002164, 0.002166, 0.926983, 0.041693, 0.01623]}, {"benchmark": "mmlu", "task_id": "mmlu-7839", "answer": "B", "cost_usd": 9.000000000000002e-06, "chosen_rung": 4, "rungs_used": [4], "distribution": [0.015439, 0.004489, 0.004321, 0.004436, 0.825505, 0.114174, 0.031636]}, {"benchmark": "math", "task_id": "gsm8k-1025", "answer": "The twins found \\(30 + 30 = 60\\) eggs.\n\nThat leaves \\(100 - 60 = 40\\) eggs.\n\nThe friends found all but 10 of those, so \\(40 - 10 = 30\\).\n\n30", "cost_usd": 7.99e-05, "chosen_rung": 4, "rungs_used": [4], "distribution": [0.003421, 0.000822, 0.000732, 0.000718, 0.978529, 0.006248, 0.00953]}, {"benchmark": "math", "task_id": "gsm8k-840", "answer": "Each glue stick has 12 mm remaining according to its fraction:\n\n- First: \\(12 \\times \\frac{1}{6} = 2\\) mm \n- Second: \\(12 \\times \\frac{2}{3} = 8\\) mm \n- Third: \\(12 \\times \\frac{1}{2} = 6\\) mm \n\nTotal: \\(2 + 8 + 6 = 16\\) mm\n\n16", "cost_usd": 0.0001146, "chosen_rung": 4, "rungs_used": [4], "distribution": [0.009666, 0.002669, 0.002487, 0.002519, 0.898422, 0.039466, 0.044771]}, {"benchmark": "code", "task_id": "lcb-abc395_b", "answer": "n = int(input())\n\nfor i in range(n):\n row = []\n for j in range(n):\n layer = min(i + 1, j + 1, n - i, n - j)\n row.append('#' if layer % 2 == 1 else '.')\n print(''.join(row))", "cost_usd": 0.00019139999999999996, "chosen_rung": 4, "rungs_used": [4], "distribution": [0.007464, 0.001975, 0.001844, 0.001879, 0.9174, 0.0293, 0.040138]}, {"benchmark": "code", "task_id": "lcb-abc399_d", "answer": "import sys\n\ndef solve():\n data = list(map(int, sys.stdin.buffer.read().split()))\n t = data[0]\n idx = 1\n out = []\n\n for _ in range(t):\n n = data[idx]\n idx += 1\n a = data[idx:idx + 2 * n]\n idx += 2 * n\n\n first = [-1] * (n + 1)\n second = [-1] * (n + 1)\n\n for i, x in enumerate(a):\n if first[x] == -1:\n first[x] = i\n else:\n second[x] = i\n\n adjacent = [False] * (n + 1)\n for x in range(1, n + 1):\n adjacent[x] = (second[x] == first[x] + 1)\n\n pairs = set()\n\n for i in range(2 * n - 1):\n x, y = a[i], a[i + 1]\n if x == y or adjacent[x] or adjacent[y]:\n continue\n\n ox = second[x] if first[x] == i else first[x]\n oy = second[y] if first[y] == i + 1 else first[y]\n\n if abs(ox - oy) == 1:\n if x > y:\n x, y = y, x\n pairs.add(x * (n + 1) + y)\n\n out.append(str(len(pairs)))\n\n sys.stdout.write(\"\\n\".join(out))\n\nif __name__ == \"__main__\":\n solve()\n", "cost_usd": 0.0011819999999999999, "chosen_rung": 4, "rungs_used": [4], "distribution": [0.000497, 8.8e-05, 7.4e-05, 7.1e-05, 0.998512, 0.000345, 0.000413]}], "quote": {"measurement": "1449fadb4821cadef93f7eecc8c3b040e2cd244e01a2607ea531e5f7055c38d8", "report_data": "530419848e8b6f3f12e6b6f0aeb4ea32aac9c87a9dca8888c4ece035bf3bd270", "platform_sig": 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