| {"schema": 2, "epoch": 87661, "nonce": "46ae7f164515ed25", "hotkey": "5GuVFWnG62s4r1AGAfrhhHBMnsMPMXKNxrmBpeJdFGyCQEaX", "source_hash": "24837b9ae6895829747c5eb448673693fedbeb2e3e62a5ca170051a512053fc0", "weights_hash": "095ffbac36e314358948a86370be2e0be5384b2278d5ee9bc924d7f155c7d474", "model_id": "router", "total_cost_usd": 0.0363816, "n_calls": 6, "call_log_hash": "55564007d46a2cc1ad0f8c07fff9b51eae6b5d126bced8084e44fb2c393738da", "measurement": "1449fadb4821cadef93f7eecc8c3b040e2cd244e01a2607ea531e5f7055c38d8", "confined": true, "latency_s": 34.538, "tokens_in": 2147, "tokens_out": 4855, "results": [{"benchmark": "mmlu", "task_id": "mmlu-4686", "answer": "C", "cost_usd": 0.000804, "chosen_rung": 6, "rungs_used": [6], "distribution": [0.019366, 0.006933, 0.006848, 0.007096, 0.353368, 0.18173, 0.424659]}, {"benchmark": "mmlu", "task_id": "mmlu-9033", "answer": "C", "cost_usd": 1.4400000000000025e-05, "chosen_rung": 4, "rungs_used": [4], "distribution": [0.014982, 0.00424, 0.004144, 0.004277, 0.829753, 0.124385, 0.01822]}, {"benchmark": "math", "task_id": "gsm8k-1136", "answer": "2 dozen = 24 marbles. \nBob originally had \\(60 - 24 = 36\\) marbles. \nAfter losing 10, he has \\(36 - 10 = 26\\) marbles.\n\n26", "cost_usd": 6.619999999999998e-05, "chosen_rung": 4, "rungs_used": [4], "distribution": [0.004478, 0.001112, 0.000988, 0.000988, 0.960692, 0.0091, 0.022643]}, {"benchmark": "math", "task_id": "gsm8k-901", "answer": "- The pot holds 8 child-sized bowls of soup.\n- The two adults eat 2 \u00d7 2 = 4 child-sized bowls.\n- Leftover soup: 8 \u2212 4 = 4 child-sized bowls.\n- Shared between two children: 4 \u00f7 2 = 2 bowls each.\n\n2", "cost_usd": 0.00012130000000000008, "chosen_rung": 4, "rungs_used": [4], "distribution": [0.002919, 0.000692, 0.000606, 0.000599, 0.982398, 0.005037, 0.007748]}, {"benchmark": "code", "task_id": "lcb-abc396_a", "answer": "import sys\n\ndef main():\n data = list(map(int, sys.stdin.read().split()))\n n = data[0]\n a = data[1:1 + n]\n\n for i in range(n - 2):\n if a[i] == a[i + 1] == a[i + 2]:\n print(\"Yes\")\n return\n\n print(\"No\")\n\nif __name__ == \"__main__\":\n main()\n", "cost_usd": 0.00010019999999999994, "chosen_rung": 4, "rungs_used": [4], "distribution": [0.002752, 0.000674, 0.00059, 0.00058, 0.915053, 0.003451, 0.076899]}, {"benchmark": "code", "task_id": "lcb-abc400_d", "answer": "def solve():\n import sys\n from collections import deque\n\n input = sys.stdin.read\n data = input().split()\n if not data:\n return\n\n H = int(data[0])\n W = int(data[1])\n grid = data[2:2+H]\n A = int(data[2+H]) - 1\n B = int(data[2+H+1]) - 1\n C = int(data[2+H+2]) - 1\n D = int(data[2+H+3]) - 1\n\n dist = [[float('inf')] * W for _ in range(H)]\n dist[A][B] = 0\n\n q = deque([(A, B)])\n\n while q:\n r, c = q.popleft()\n d = dist[r][c]\n\n if r == C and c == D:\n print(d)\n return\n\n # 0-cost moves (adjacent roads)\n for dr, dc in ((-1, 0), (1, 0), (0, -1), (0, 1)):\n nr, nc = r + dr, c + dc\n if 0 <= nr < H and 0 <= nc < W and grid[nr][nc] == '.':\n if d < dist[nr][nc]:\n dist[nr][nc] = d\n q.appendleft((nr, nc))\n\n # 1-cost moves (kicks can reach any cell in 5x5 area around (r,c) except corners with dist > 2? No, 5x5 subgrid)\n # Specifically, for |dr| <= 2 and |dc| <= 2:\n for dr in range(-2, 3):\n for dc in range(-2, 3):\n if abs(dr) + abs(dc) == 4: # corners like (2,2) are not reachable in 1 kick? Wait, let's check:\n continue\n nr, nc = r + dr, c + dc\n if 0 <= nr < H and 0 <= nc < W:\n if d + 1 < dist[nr][nc]:\n dist[nr][nc] = d + 1\n q.append((nr, nc))\n\nsolve()", "cost_usd": 0.0352755, "chosen_rung": 5, "rungs_used": [5], "distribution": [0.003914, 0.001721, 0.002135, 0.002377, 0.003852, 0.981493, 0.004508]}], "quote": {"measurement": "1449fadb4821cadef93f7eecc8c3b040e2cd244e01a2607ea531e5f7055c38d8", "report_data": "94010dfd88504d2b0a98a10f7426dc22e4835814a9eade224c5fe444f69e0ccc", "platform_sig": 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