| {"schema": 2, "epoch": 87662, "nonce": "31a860bf93f8eb16", "hotkey": "5GuVFWnG62s4r1AGAfrhhHBMnsMPMXKNxrmBpeJdFGyCQEaX", "source_hash": "24837b9ae6895829747c5eb448673693fedbeb2e3e62a5ca170051a512053fc0", "weights_hash": "095ffbac36e314358948a86370be2e0be5384b2278d5ee9bc924d7f155c7d474", "model_id": "router", "total_cost_usd": 0.06434, "n_calls": 6, "call_log_hash": "728e5f3eb55982140759190fc1fc6902fff41c1db504f46919f335f59664c752", "measurement": "1449fadb4821cadef93f7eecc8c3b040e2cd244e01a2607ea531e5f7055c38d8", "confined": true, "latency_s": 47.374, "tokens_in": 2109, "tokens_out": 8591, "results": [{"benchmark": "mmlu", "task_id": "mmlu-11128", "answer": "D", "cost_usd": 2.82e-05, "chosen_rung": 4, "rungs_used": [4], "distribution": [0.00622, 0.001526, 0.001442, 0.001457, 0.955112, 0.030759, 0.003484]}, {"benchmark": "mmlu", "task_id": "mmlu-6051", "answer": "D", "cost_usd": 2.82e-05, "chosen_rung": 4, "rungs_used": [4], "distribution": [0.004455, 0.001154, 0.00103, 0.001011, 0.948825, 0.008046, 0.035478]}, {"benchmark": "math", "task_id": "gsm8k-730", "answer": "Parker needs \\(4 \\times 30 = 120\\) pieces of gum.\n\nEach pack has 15 pieces, so \\(120 \\div 15 = 8\\).\n\n8", "cost_usd": 5.379999999999999e-05, "chosen_rung": 4, "rungs_used": [4], "distribution": [0.006521, 0.00172, 0.001545, 0.001551, 0.925869, 0.016368, 0.046428]}, {"benchmark": "math", "task_id": "gsm8k-678", "answer": "1. Karen earns twice Lorie\u2019s $10 per hour: \\(2 \\times 10 = 20\\) dollars per hour. \n2. In two days, she works \\(3 \\times 2 = 6\\) hours. \n3. Her total earnings are \\(20 \\times 6 = 120\\).\n\n120", "cost_usd": 8.519999999999998e-05, "chosen_rung": 4, "rungs_used": [4], "distribution": [0.011409, 0.003159, 0.002976, 0.00303, 0.88907, 0.053387, 0.036969]}, {"benchmark": "code", "task_id": "lcb-abc391_a", "answer": "d = input().strip()\n\nopposite = {\n \"N\": \"S\",\n \"S\": \"N\",\n \"E\": \"W\",\n \"W\": \"E\",\n \"NE\": \"SW\",\n \"SW\": \"NE\",\n \"NW\": \"SE\",\n \"SE\": \"NW\",\n}\n\nprint(opposite[d])", "cost_usd": 6.91e-05, "chosen_rung": 4, "rungs_used": [4], "distribution": [0.003511, 0.000745, 0.000701, 0.000703, 0.978712, 0.014107, 0.001521]}, {"benchmark": "code", "task_id": "lcb-abc400_d", "answer": "import sys\nfrom collections import deque\n\ndef main():\n input = sys.stdin.read\n data = input().split()\n if not data:\n return\n \n H = int(data[0])\n W = int(data[1])\n \n grid_flat = []\n idx = 2\n for _ in range(H):\n grid_flat.extend(data[idx])\n idx += 1\n \n A = int(data[idx]) - 1\n B = int(data[idx+1]) - 1\n C = int(data[idx+2]) - 1\n D = int(data[idx+3]) - 1\n \n start_idx = A * W + B\n target_idx = C * W + D\n \n grid_is_dot = [c == '.' for c in grid_flat]\n \n OFFSETS_1 = []\n for dr in range(-2, 3):\n for dc in range(-2, 3):\n if abs(dr) + abs(dc) == 4 or (dr == 0 and dc == 0):\n continue\n is_cleared = (dr == 0 or dc == 0)\n OFFSETS_1.append((dr, dc, is_cleared))\n \n INF = 10**9\n dist = [INF] * (H * W)\n dist[start_idx] = 0\n \n q = deque([start_idx])\n \n while q:\n curr = q.popleft()\n d = dist[curr]\n \n if curr == target_idx:\n print(d)\n return\n \n r = curr // W\n c = curr % W\n \n # 0-cost moves (adjacent roads)\n for dr, dc in ((-1, 0), (1, 0), (0, -1), (0, 1)):\n nr, nc = r + dr, c + dc\n if 0 <= nr < H and 0 <= nc < W:\n nidx = nr * W + nc\n if grid_is_dot[nidx] and dist[nidx] > d:\n dist[nidx] = d\n q.appendleft(nidx)\n \n # 1-cost moves (front kick)\n d_next = d + 1\n for dr, dc, is_cleared in OFFSETS_1:\n nr, nc = r + dr, c + dc\n if 0 <= nr < H and 0 <= nc < W:\n nidx = nr * W + nc\n if (is_cleared or grid_is_dot[nidx]) and dist[nidx] > d_next:\n dist[nidx] = d_next\n q.append(nidx)\n\nif __name__ == '__main__':\n main()", "cost_usd": 0.0640755, "chosen_rung": 5, "rungs_used": [5], "distribution": [0.003914, 0.001721, 0.002135, 0.002377, 0.003852, 0.981493, 0.004508]}], "quote": {"measurement": "1449fadb4821cadef93f7eecc8c3b040e2cd244e01a2607ea531e5f7055c38d8", "report_data": "b3f665d7fc7ca60415762047d06818d462fcbc1ead9479dedeeaa3c9feb8e35e", "platform_sig": 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