[{"task_id": "mmlu-8333", "model": "openai/gpt-5.6-luna", "prompt": "[MMLU]  Nathanson proposes a form of retributivism that requires all of the following except\nA) a list of crimes ranked according to their seriousness.\nB) a scale of punishments that correspond to the seriousness of certain crimes.\nC) treating criminals humanely.\nD) the death penalty for the most serious crimes.\n\nAnswer with the letter only.", "response": "D", "cost_usd": 4.11e-05, "tokens_in": 81, "tokens_out": 55, "latency_s": 4.476}, {"task_id": "mmlu-13551", "model": "openai/gpt-5.6-luna", "prompt": "[MMLU] Cultural restructuring has involved:\nA) regenerating cities in economic decline\nB) turning industrial landscapes into tourist attractions\nC) selling sites and images through the 'symbolic economy' of media advertising\nD) all of the above\n\nAnswer with the letter only.", "response": "D", "cost_usd": 9.300000000000002e-06, "tokens_in": 63, "tokens_out": 5, "latency_s": 0.781}, {"task_id": "gsm8k-766", "model": "openai/gpt-5.6-luna", "prompt": "Marissa bought a ball at the store for $20. If she had $80 on her and used the rest of the money to buy her brother Jimmy, candy bars sold at $5 each, how many candy bars did Marissa buy for Jimmy?\n\nReason step by step, then give the final answer as a single number.", "response": "Marissa had $80 and spent $20 on the ball:\n\n$80 - $20 = $60\n\nEach candy bar cost $5:\n\n$60 \u00f7 $5 = 12\n\n12", "cost_usd": 6.42e-05, "tokens_in": 72, "tokens_out": 95, "latency_s": 3.899}, {"task_id": "gsm8k-923", "model": "openai/gpt-5.6-luna", "prompt": "Lana is brewing cups of tea for her friends. She has 27 cups, and she divides these into 3 rows. In each row, she creates equal amounts of chamomile and mint tea cups. She then uses the remaining cups to brew a total of 15 cups of cinnamon tea. How many cups of mint tea are in each row?\n\nReason step by step, then give the final answer as a single number.", "response": "There are \\(27 - 15 = 12\\) cups for chamomile and mint tea.\n\nDividing these equally among 3 rows gives \\(12 \\div 3 = 4\\) cups per row.\n\nEach row has equal amounts of chamomile and mint tea, so \\(4 \\div 2 = 2\\) mint tea cups per row.\n\n2", "cost_usd": 0.00011840000000000002, "tokens_in": 92, "tokens_out": 182, "latency_s": 4.36}, {"task_id": "lcb-abc389_b", "model": "openai/gpt-5.6-luna", "prompt": "You are given an integer X not less than 2.\nFind the positive integer N such that N! = X.\nHere, N! denotes the factorial of N, and it is guaranteed that there is exactly one such N.\n\nInput\n\nThe input is given from Standard Input in the following format:\nX\n\nOutput\n\nPrint the answer.\n\nConstraints\n\n\n- 2 \\leq X \\leq 3 \\times 10^{18}\n- There is exactly one positive integer N such that N!=X.\n- All input values are integers.\n\nSample Input 1\n\n6\n\nSample Output 1\n\n3\r\n\nFrom 3!=3\\times2\\times1=6, print 3.\n\nSample Input 2\n\n2432902008176640000\n\nSample Output 2\n\n20\r\n\nFrom 20!=2432902008176640000, print 20.\n\nWrite a complete Python 3 program that reads from standard input and writes the answer to standard output. Output ONLY the program source, no prose and no code fences.", "response": "import sys\n\nx = int(sys.stdin.readline())\nn = 1\nfactorial = 1\n\nwhile factorial < x:\n    n += 1\n    factorial *= n\n\nprint(n)", "cost_usd": 4.8099999999999977e-05, "tokens_in": 217, "tokens_out": 44, "latency_s": 1.504}, {"task_id": "lcb-abc400_d", "model": "google/gemini-3.6-flash", "prompt": "Takahashi is about to go buy eel at a fish shop.\nThe town where he lives is divided into a grid of H rows and W columns. Each cell is either a road or a wall.\r\nLet us denote the cell at the i-th row from the top (1\\leq i \\leq H) and the j-th column from the left (1\\leq j \\leq W) as cell (i,j).\r\nInformation about each cell is given by H strings S_1,S_2,\\ldots,S_H, each of length W. Specifically, if the j-th character of S_i (1\\leq i \\leq H,1\\leq j\\leq W) is ., cell (i,j) is a road; if it is #, cell (i,j) is a wall.\nHe can repeatedly perform the following two types of actions in any order:\n\n- Move to an adjacent cell (up, down, left, or right) that is within the town and is a road.\n- Choose one of the four directions (up, down, left, or right) and perform a front kick in that direction.\r\n  When he performs a front kick, for each of the cells at most 2 steps away in that direction from the cell he is currently in, if that cell is a wall, it becomes a road.\r\n  If some of the cells at most 2 steps away are outside the town, a front kick can still be performed, but anything outside the town does not change.\n\nHe starts in cell (A,B), and he wants to move to the fish shop in cell (C,D).\r\nIt is guaranteed that both the cell where he starts and the cell with the fish shop are roads.\r\nFind the minimum number of front kicks he needs in order to reach the fish shop.\n\nInput\n\nThe input is given from Standard Input in the following format:\nH W\r\nS_1\r\nS_2\r\n\\vdots\r\nS_H\r\nA B C D\n\nOutput\n\nPrint the minimum number of front kicks needed for Takahashi to reach the fish shop.\n\nConstraints\n\n\n- 1\\leq H\\leq 1000\n- 1\\leq W\\leq 1000\n- Each S_i is a string of length W consisting of . and #.\n- 1\\leq A,C\\leq H\n- 1\\leq B,D\\leq W\n- (A,B)\\neq (C,D)\n- H, W, A, B, C, and D are integers.\n- The cell where Takahashi starts and the cell with the fish shop are roads.\n\nSample Input 1\n\n10 10\r\n..........\r\n#########.\r\n#.......#.\r\n#..####.#.\r\n##....#.#.\r\n#####.#.#.\r\n.##.#.#.#.\r\n###.#.#.#.\r\n###.#.#.#.\r\n#.....#...\r\n1 1 7 1\n\nSample Output 1\n\n1\r\n\nTakahashi starts in cell (1,1).\r\nBy repeatedly moving to adjacent road cells, he can reach cell (7,4).\r\nIf he performs a front kick to the left from cell (7,4), cells (7,3) and (7,2) turn from walls to roads.\r\nThen, by continuing to move through road cells (including those that have become roads), he can reach the fish shop in cell (7,1).\nIn this case, the number of front kicks performed is 1, and it is impossible to reach the fish shop without performing any front kicks, so print 1.\n\nSample Input 2\n\n2 2\r\n.#\r\n#.\r\n1 1 2 2\n\nSample Output 2\n\n1\r\n\nTakahashi starts in cell (1,1).\r\nWhen he performs a front kick to the right, cell (1,2) turns from a wall to a road.\r\nThe cell two steps to the right of (1,1) is outside the town, so it does not change.\r\nThen, he can move to cell (1,2) and then to the fish shop in cell (2,2).\nIn this case, the number of front kicks performed is 1, and it is impossible to reach the fish shop without performing any front kicks, so print 1.\n\nSample Input 3\n\n1 3\r\n.#.\r\n1 1 1 3\n\nSample Output 3\n\n1\r\n\nWhen performing a front kick, it is fine if the fish shop\u2019s cell is within the cells that could be turned into a road. Specifically, the fish shop\u2019s cell is a road from the beginning, so it remains unchanged; particularly, the shop is not destroyed by the front kick.\n\nSample Input 4\n\n20 20\r\n####################\r\n##...##....###...###\r\n#.....#.....#.....##\r\n#..#..#..#..#..#..##\r\n#..#..#....##..#####\r\n#.....#.....#..#####\r\n#.....#..#..#..#..##\r\n#..#..#.....#.....##\r\n#..#..#....###...###\r\n####################\r\n####################\r\n##..#..##...###...##\r\n##..#..#.....#.....#\r\n##..#..#..#..#..#..#\r\n##..#..#..#..#..#..#\r\n##.....#..#..#..#..#\r\n###....#..#..#..#..#\r\n#####..#.....#.....#\r\n#####..##...###...##\r\n####################\r\n3 3 18 18\n\nSample Output 4\n\n3\n\nWrite a complete Python 3 program that reads from standard input and writes the answer to standard output. Output ONLY the program source, no prose and no code fences.", "response": "To find the minimum number of front kicks Takahashi needs to reach the fish shop, we can model this as a shortest path problem on a grid using **0-1 BFS (Deque)**.\n\n### Key Idea\n1. **0-cost moves**: Takahashi can move to any orthogonally adjacent cell $(r', c')$ if it is already a road (`.`).\n2. **1-cost moves (Front Kick)**: From a cell $(r, c)$, Takahashi can perform a front kick in any of the 4 cardinal directions (up, down, left, right). This turns the walls in the next 1 or 2 steps in that direction into roads. \n\nBy kicking in a direction, he creates a 2-cell bridge of roads. From these newly created road cells, he can step into any adjacent existing road cells. Across all 4 kick directions, any cell $(r', c')$ within a $5 \\times 5$ bounding box centered at $(r, c)$ (i.e., $|r - r'| \\le 2$ and $|c - c'| \\le 2$) can be reached with **1 kick**, provided that $(r', c')$ is inside the grid bounds.\n\nThus:\n- Moving to an adjacent road cell costs `0`.\n- Moving to any cell in the $5 \\times 5$ box around the current cell costs `1` (which acts as performing 1 kick).\n\n### Python 3 Source Code\n\n```python\nimport sys\nfrom collections import deque\n\ndef solve():\n    input = sys.stdin.read\n    data = input().split()\n    \n    H = int(data[0])\n    W = int(data[1])\n    \n    grid = data[2:2+H]\n    \n    A = int(data[2+H]) - 1\n    B = int(data[2+H+1]) - 1\n    C = int(data[2+H+2]) - 1\n    D = int(data[2+H+3]) - 1\n\n    dist = [[float('inf')] * W for _ in range(H)]\n    dist[A][B] = 0\n    \n    q = deque([(A, B)])\n    \n    while q:\n        r, c = q.popleft()\n        d = dist[r][c]\n        \n        if r == C and c == D:\n            print(d)\n            return\n\n        # 0-cost transitions: adjacent road cells\n        for dr, dc in [(-1, 0), (1, 0), (0, -1), (0, 1)]:\n            nr, nc = r + dr, c + dc\n            if 0 <= nr < H and 0 <= nc < W:\n                if grid[nr][nc] == '.' and dist[nr][nc] > d:\n                    dist[nr][nc] = d\n                    q.appendleft((nr, nc))\n\n        # 1-cost transitions: any cell in the 5x5 area centered at (r, c)\n        for dr in range(-2, 3):\n            for dc in range(-2, 3):\n                if dr == 0 and dc == 0:\n                    continue\n                nr, nc = r + dr, c + dc\n                if 0 <= nr < H and 0 <= nc < W:\n                    if dist[nr][nc] > d + 1:\n                        dist[nr][nc] = d + 1\n                        q.append((nr, nc))\n\nif __name__ == '__main__':\n    solve()\n```", "cost_usd": 0.0354975, "tokens_in": 1310, "tokens_out": 4471, "latency_s": 22.287}]