| {"schema": 2, "epoch": 87741, "nonce": "48e52e0eb75ef128", "hotkey": "5GuVFWnG62s4r1AGAfrhhHBMnsMPMXKNxrmBpeJdFGyCQEaX", "source_hash": "24837b9ae6895829747c5eb448673693fedbeb2e3e62a5ca170051a512053fc0", "weights_hash": "5f15eca0fad82272932867103208e68aff1869ae29090d5296d01e247cbbe561", "model_id": "router", "total_cost_usd": 0.006815168, "n_calls": 7, "call_log_hash": "1d510f6a37049cdb265b56821e482f97cd53012822ca9178c8a84d3dd2807119", "measurement": "1449fadb4821cadef93f7eecc8c3b040e2cd244e01a2607ea531e5f7055c38d8", "confined": true, "latency_s": 252.794, "tokens_in": 3238, "tokens_out": 32461, "results": [{"benchmark": "mmlu", "task_id": "mmlu-9164", "answer": "A", "cost_usd": 3.43e-05, "chosen_rung": 4, "rungs_used": [4], "distribution": [0.0, 0.0, 0.0, 0.0, 1.0, 0.0, 0.0]}, {"benchmark": "mmlu", "task_id": "mmlu-8564", "answer": "B", "cost_usd": 1.48e-05, "chosen_rung": 4, "rungs_used": [4], "distribution": [0.0, 0.0, 0.0, 0.0, 1.0, 0.0, 0.0]}, {"benchmark": "math", "task_id": "gsm8k-663", "answer": "Total delivered to A and C: 198 + 209 = 407. \nDelivered to B: 600 \u2212 407 = 193.\n\n193", "cost_usd": 5.47e-05, "chosen_rung": 4, "rungs_used": [4], "distribution": [0.0, 0.0, 0.0, 0.0, 1.0, 0.0, 0.0]}, {"benchmark": "math", "task_id": "gsm8k-513", "answer": "20% of $500 = $100, so she had $400 left. \n25% of $400 = $100, so she had $300 left.\n\n300", "cost_usd": 5.950000000000001e-05, "chosen_rung": 4, "rungs_used": [4], "distribution": [0.0, 0.0, 0.0, 0.0, 1.0, 0.0, 0.0]}, {"benchmark": "code", "task_id": "lcb-abc388_b", "answer": "import sys\n\ndef main():\n input = sys.stdin.readline\n n, d = map(int, input().split())\n snakes = [tuple(map(int, input().split())) for _ in range(n)]\n\n for k in range(1, d + 1):\n print(max(t * (l + k) for t, l in snakes))\n\nif __name__ == \"__main__\":\n main()\n", "cost_usd": 9.289999999999998e-05, "chosen_rung": 4, "rungs_used": [4], "distribution": [0.0, 0.0, 0.0, 0.0, 1.0, 0.0, 0.0]}, {"benchmark": "code", "task_id": "lcb-abc400_d", "answer": "```python\nimport sys\nfrom collections import deque\n\ndef solve() -> None:\n input = sys.stdin.readline\n H, W = map(int, input().split())\n grid = [list(input().strip()) for _ in range(H)]\n A, B, C, D = map(int, input().split())\n A -= 1\n B -= 1\n C -= 1\n D -= 1\n\n INF = 10 ** 9\n dist = [[INF] * W for _ in range(H)]\n dq = deque()\n dist[A][B] = 0\n dq.appendleft((A, B))\n\n dirs = [(1, 0), (-1, 0), (0, 1), (0, -1)]\n\n while dq:\n i, j = dq.popleft()\n d = dist[i][j]\n\n # 0\u2011cost moves to adjacent road cells\n for di, dj in dirs:\n ni, nj = i + di, j + dj\n if 0 <= ni < H and 0 <= nj < W:\n # cell is a road if it is '.' or has already been broken\n if grid[ni][nj] == '.' or dist[ni][nj] != INF:\n if dist[ni][nj] > d:\n dist[ni][nj] = d\n dq.appendleft((ni, nj))\n\n # 1\u2011cost kicks: break walls at distance 1 and 2\n for di, dj in dirs:\n # step 1\n ni1, nj1 = i + di, j + dj\n if 0 <= ni1 < H and 0 <= nj1 < W:\n if grid[ni1][nj1] == '#' and dist[ni1][nj1] > d + 1:\n dist[ni1][nj1] = d + 1\n dq.append((ni1, nj1))\n # step 2\n ni2, nj2 = i + 2 * di, j + 2 * dj\n if 0 <= ni2 < H and 0 <= nj2 < W:\n if grid[ni2][nj2] == '#' and dist[ni2][nj2] > d + 1:\n dist[ni2][nj2] = d + 1\n dq.append((ni2, nj2))\n\n print(dist[C][D])\n\nif __name__ == \"__main__\":\n solve()\n```", "cost_usd": 0.006558968, "chosen_rung": 0, "rungs_used": [0, 1], "distribution": [0.999998, 0.0, 0.0, 0.0, 1e-06, 0.0, 0.0]}], "quote": {"measurement": "1449fadb4821cadef93f7eecc8c3b040e2cd244e01a2607ea531e5f7055c38d8", "report_data": "ec0d6c1d5f77c965f963081969aca474b81ae124f860e399dfe89b97db716c1a", "platform_sig": 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