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+[{"task_id": "mmlu-9691", "model": "openai/gpt-5.6-luna", "prompt": "[MMLU] Prenatal programming:\n\nA) Explains the rise in obesity in the pre-school years\nB) May be effected through the epigenetic effects of intrauterine nutritional inadequacy\nC) Causes high blood pressure in young children\nD) Only affects low birth weight children\n\nAnswer with the letter only.", "response": "B", "cost_usd": 1.02e-05, "tokens_in": 72, "tokens_out": 5, "latency_s": 1.854}, {"task_id": "mmlu-7826", "model": "openai/gpt-5.6-luna", "prompt": "[MMLU] Which of the following is the best description of traditional phonics instruction?\nA) Students study lists of high-frequency words in order to increase reading speed and comprehension.\nB) Students are taught individual letter sounds first, followed by letter combination sounds and the rules of putting these combinations together to make words.\nC) Students are immersed in written language, and encouraged to decode entire words using context clues.\nD) Students analyze patterns of organization and syntax as a way of learning to recognize common structures.\n\nAnswer with the letter only.", "response": "B", "cost_usd": 1.4299999999999999e-05, "tokens_in": 113, "tokens_out": 5, "latency_s": 0.789}, {"task_id": "gsm8k-128", "model": "openai/gpt-5.6-luna", "prompt": "Well's mother sells watermelons, peppers, and oranges at the local store. A watermelon costs three times what each pepper costs. An orange costs 5 less than what a watermelon cost. Dillon is sent to the store to buy 4 watermelons, 20 peppers, and 10 oranges. What's the total amount of money he will spend if each pepper costs 15$?\n\nReason step by step, then give the final answer as a single number.", "response": "Each pepper costs $15.\n\n- Watermelon: \\(3 \\times 15 = \\$45\\)\n- Orange: \\(45 - 5 = \\$40\\)\n- 4 watermelons: \\(4 \\times 45 = \\$180\\)\n- 20 peppers: \\(20 \\times 15 = \\$300\\)\n- 10 oranges: \\(10 \\times 40 = \\$400\\)\n\nTotal: \\(180 + 300 + 400 = 880\\)\n\n880", "cost_usd": 0.00011559999999999999, "tokens_in": 100, "tokens_out": 176, "latency_s": 4.14}, {"task_id": "gsm8k-430", "model": "openai/gpt-5.6-luna", "prompt": "Charlotte went into the kitchen supply store knowing she wanted a set of pot and pans for $120.00, a set of mixing bowls for $20.00 and 5 separate utensils at $5.00 each.  At check out, the clerk told her everything was 20% off.  How much was her order?\n\nReason step by step, then give the final answer as a single number.", "response": "- Pots and pans: $120.00  \n- Mixing bowls: $20.00  \n- Utensils: 5 \u00d7 $5.00 = $25.00  \n- Total before discount: $120 + $20 + $25 = $165.00  \n- 20% discount: $165 \u00d7 0.20 = $33.00  \n- Final cost: $165 \u2212 $33 = $132.00  \n\n132.00", "cost_usd": 0.00010840000000000003, "tokens_in": 88, "tokens_out": 166, "latency_s": 3.979}, {"task_id": "lcb-abc392_a", "model": "openai/gpt-5.6-luna", "prompt": "You are given a sequence of integers A = (A_1, A_2, A_3).\r\nLet B = (B_1, B_2, B_3) be any permutation of A.\r\nDetermine whether it is possible that B_1 \\times B_2 = B_3.\n\nInput\n\nThe input is given from Standard Input in the following format:\nA_1 A_2 A_3\n\nOutput\n\nIf it is possible that B_1 \\times B_2 = B_3, print Yes; otherwise, print No.\n\nConstraints\n\n\n- All input values are integers.\n- 1 \\le A_1, A_2, A_3 \\le 100\n\nSample Input 1\n\n3 15 5\n\nSample Output 1\n\nYes\r\n\nHere, A=(3,15,5).\r\nBy rearranging it as B=(3,5,15), we can satisfy B_1 \\times B_2 = B_3.\n\nSample Input 2\n\n5 3 2\n\nSample Output 2\n\nNo\r\n\nNo permutation of B satisfies B_1 \\times B_2 = B_3.\n\nWrite a complete Python 3 program that reads from standard input and writes the answer to standard output. Output ONLY the program source, no prose and no code fences.", "response": "import sys\nfrom itertools import permutations\n\na = list(map(int, sys.stdin.read().split()))\n\nfor b1, b2, b3 in permutations(a):\n    if b1 * b2 == b3:\n        print(\"Yes\")\n        break\nelse:\n    print(\"No\")", "cost_usd": 6.550000000000002e-05, "tokens_in": 277, "tokens_out": 63, "latency_s": 1.225}, {"task_id": "lcb-abc388_c", "model": "openai/gpt-5.6-luna", "prompt": "There are N mochi (rice cakes) arranged in ascending order of size.\r\nThe size of the i-th mochi (1 \\leq i \\leq N) is A_i.\nGiven two mochi A and B, with sizes a and b respectively, you can make one kagamimochi (a stacked rice cake) by placing mochi A on top of mochi B if and only if a is at most half of b.\nYou choose two mochi out of the N mochi, and place one on top of the other to form one kagamimochi.\nFind how many different kinds of kagamimochi can be made.\nTwo kagamimochi are distinguished if at least one of the mochi is different, even if the sizes of the mochi are the same.\n\nInput\n\nThe input is given from Standard Input in the following format:\nN\r\nA_1 A_2 \\cdots A_N\n\nOutput\n\nPrint the number of different kinds of kagamimochi that can be made.\n\nConstraints\n\n\n- 2 \\leq N \\leq 5 \\times 10^5\n- 1 \\leq A_i \\leq 10^9 \\ (1 \\leq i \\leq N)\n- A_i \\leq A_{i+1} \\ (1 \\leq i < N)\n- All input values are integers.\n\nSample Input 1\n\n6\r\n2 3 4 4 7 10\n\nSample Output 1\n\n8\r\n\nThe sizes of the given mochi are as follows:\n\nIn this case, you can make the following eight kinds of kagamimochi:\n\nNote that there are two kinds of kagamimochi where a mochi of size 4 is topped by a mochi of size 2, and two kinds where a mochi of size 10 is topped by a mochi of size 4.\n\nSample Input 2\n\n3\r\n387 388 389\n\nSample Output 2\n\n0\r\n\nIt is possible that you cannot make any kagamimochi.\n\nSample Input 3\n\n32\r\n1 2 4 5 8 10 12 16 19 25 33 40 50 64 87 101 149 175 202 211 278 314 355 405 412 420 442 481 512 582 600 641\n\nSample Output 3\n\n388\n\nWrite a complete Python 3 program that reads from standard input and writes the answer to standard output. Output ONLY the program source, no prose and no code fences.", "response": "import sys\nfrom bisect import bisect_right\n\ndef main():\n    input = sys.stdin.buffer.readline\n    n = int(input())\n    a = list(map(int, input().split()))\n\n    ans = 0\n    for x in a:\n        ans += bisect_right(a, x // 2)\n\n    print(ans)\n\nif __name__ == \"__main__\":\n    main()\n", "cost_usd": 0.00030619999999999996, "tokens_in": 542, "tokens_out": 420, "latency_s": 5.389}]