spider/t5-base/run_1/error_analysis.txt

Spider Error Analysis — Run 1
EM norm: 37.81% | EX: 47.20%
================================================================================

[1] OTHER | DB: concert_singer | EX: ✗
  Q   : What is the average, minimum, and maximum age for all French singers
  Pred: SELECT AVG(age), MIN(age), MAX(age) FROM singer WHERE country = 'French'
  Gold: SELECT AVG(age), MIN(age), MAX(age) FROM singer WHERE country = 'France'
  Type: AGGREGATION

[2] WRONG_COLUMNS | DB: concert_singer | EX: ✗
  Q   : What is the maximum capacity and the average of all stadiums
  Pred: SELECT MAX(capacity), AVG(average) FROM stadium
  Gold: SELECT MAX(capacity), average FROM stadium
  Type: AGGREGATION

[3] WRONG_TABLE | DB: concert_singer | EX: ✗
  Q   : Show the stadium name and the number of concerts in each stadium
  Pred: SELECT T2.name, COUNT(*) FROM stadium AS T1 JOIN concert AS T2 ON T1.stadium_id = T2.stadium_id GROUP BY T1.stadium_id
  Gold: SELECT T2.name, COUNT(*) FROM concert AS T1 JOIN stadium AS T2 ON T1.stadium_id = T2.stadium_id GROUP BY T1.stadium_id
  Type: JOIN, GROUP_BY, AGGREGATION

[4] WRONG_TABLE | DB: concert_singer | EX: ✗
  Q   : For each stadium, how many concerts play there
  Pred: SELECT COUNT(*), T1.stadium_id FROM stadium AS T1 JOIN concert AS T2 ON T1.stadium_id = T2.stadium_id GROUP BY T1.stadium_id
  Gold: SELECT T2.name, COUNT(*) FROM concert AS T1 JOIN stadium AS T2 ON T1.stadium_id = T2.stadium_id GROUP BY T1.stadium_id
  Type: JOIN, GROUP_BY, AGGREGATION

[5] OTHER | DB: concert_singer | EX: ✓
  Q   : Show the stadium name and capacity with most number of concerts in year 2014 or after
  Pred: SELECT T2.name, T2.capacity FROM concert AS T1 JOIN stadium AS T2 ON T1.stadium_id = T2.stadium_id WHERE T1.year >= 2014 GROUP BY T1.stadium_id ORDER BY COUNT(*) DESC LIMIT 1
  Gold: SELECT T2.name, T2.capacity FROM concert AS T1 JOIN stadium AS T2 ON T1.stadium_id = T2.stadium_id WHERE T1.year >= 2014 GROUP BY T2.stadium_id ORDER BY COUNT(*) DESC LIMIT 1
  Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, AGGREGATION

[6] OTHER | DB: concert_singer | EX: ✗
  Q   : Show countries where a singer above age 40 and a singer below 30 are from
  Pred: SELECT Country FROM singer WHERE Age > 40 INTERSECT SELECT Country FROM singer WHERE Age  30
  Gold: SELECT country FROM singer WHERE age > 40 INTERSECT SELECT country FROM singer WHERE age < 30
  Type: SIMPLE

[7] OTHER | DB: concert_singer | EX: ✓
  Q   : Show the name and theme for all concerts and the number of singers in each concert
  Pred: SELECT T2.Concert_Name, T2.Theme, COUNT(*) FROM singer_in_concert AS T1 JOIN concert AS T2 ON T1.Concert_ID = T2.Concert_ID GROUP BY T1.Concert_ID
  Gold: SELECT T2.concert_name, T2.theme, COUNT(*) FROM singer_in_concert AS T1 JOIN concert AS T2 ON T1.concert_id = T2.concert_id GROUP BY T2.concert_id
  Type: JOIN, GROUP_BY, AGGREGATION

[8] OTHER | DB: concert_singer | EX: ✓
  Q   : What are the names , themes , and number of singers for every concert
  Pred: SELECT T2.Concert_Name, T2.Theme, COUNT(*) FROM singer_in_concert AS T1 JOIN concert AS T2 ON T1.Concert_ID = T2.Concert_ID GROUP BY T1.Concert_ID
  Gold: SELECT t2.concert_name, t2.theme, COUNT(*) FROM singer_in_concert AS t1 JOIN concert AS t2 ON t1.concert_id = t2.concert_id GROUP BY t2.concert_id
  Type: JOIN, GROUP_BY, AGGREGATION

[9] OTHER | DB: concert_singer | EX: ✗
  Q   : List singer names and number of concerts for each singer
  Pred: SELECT T2.Name, COUNT(*) FROM singer_in_concert AS T1 JOIN concert AS T2 ON T1.concert_id = T2.concert_id GROUP BY T2.Name
  Gold: SELECT T2.name, COUNT(*) FROM singer_in_concert AS T1 JOIN singer AS T2 ON T1.singer_id = T2.singer_id GROUP BY T2.singer_id
  Type: JOIN, GROUP_BY, AGGREGATION

[10] OTHER | DB: concert_singer | EX: ✓
  Q   : What are the names of the singers and number of concerts for each person
  Pred: SELECT T2.Name, COUNT(*) FROM singer_in_concert AS T1 JOIN singer AS T2 ON T1.Singer_ID = T2.Singer_ID GROUP BY T2.Name
  Gold: SELECT T2.name, COUNT(*) FROM singer_in_concert AS T1 JOIN singer AS T2 ON T1.singer_id = T2.singer_id GROUP BY T2.singer_id
  Type: JOIN, GROUP_BY, AGGREGATION

[11] WRONG_TABLE | DB: concert_singer | EX: ✗
  Q   : List all singer names in concerts in year 2014
  Pred: SELECT T2.Name FROM concert AS T1 JOIN singer_in_concert AS T2 ON T1.concert_id = T2.concert_id WHERE T1.Year = 2014
  Gold: SELECT T2.name FROM singer_in_concert AS T1 JOIN singer AS T2 ON T1.singer_id = T2.singer_id JOIN concert AS T3 ON T1.concert_id = T3.concert_id WHERE T3.year = 2014
  Type: JOIN

[12] OTHER | DB: concert_singer | EX: ✗
  Q   : What are the names of the singers who performed in a concert in 2014
  Pred: SELECT T2.Name FROM singer_in_concert AS T1 JOIN concert AS T2 ON T1.concert_id = T2.concert_id WHERE T2.Year = 2014
  Gold: SELECT T2.name FROM singer_in_concert AS T1 JOIN singer AS T2 ON T1.singer_id = T2.singer_id JOIN concert AS T3 ON T1.concert_id = T3.concert_id WHERE T3.year = 2014
  Type: JOIN

[13] EXTRA_JOIN | DB: concert_singer | EX: ✗
  Q   : what is the name and nation of the singer who have a song having 'Hey' in its name
  Pred: SELECT T1.name, T1.country FROM singer AS T1 JOIN singer_in_concert AS T2 ON T1.singer_id = T2.singer_id WHERE T2.Song_Name LIKE "%Hey%"
  Gold: SELECT name, country FROM singer WHERE song_name LIKE '%Hey%'
  Type: SIMPLE

[14] WRONG_TABLE | DB: concert_singer | EX: ✗
  Q   : Find the number of concerts happened in the stadium with the highest capacity
  Pred: SELECT COUNT(*) FROM stadium ORDER BY capacity DESC LIMIT 1
  Gold: SELECT COUNT(*) FROM concert WHERE stadium_id = (SELECT stadium_id FROM stadium ORDER BY capacity DESC LIMIT 1)
  Type: ORDER_BY, LIMIT, NESTED, AGGREGATION

[15] WRONG_TABLE | DB: concert_singer | EX: ✓
  Q   : What are the number of concerts that occurred in the stadium with the largest capacity
  Pred: SELECT COUNT(*) FROM stadium AS T1 JOIN concert AS T2 ON T1.stadium_id = T2.stadium_id WHERE T1.capacity = (SELECT MAX(capacity) FROM stadium)
  Gold: SELECT COUNT(*) FROM concert WHERE stadium_id = (SELECT stadium_id FROM stadium ORDER BY capacity DESC LIMIT 1)
  Type: ORDER_BY, LIMIT, NESTED, AGGREGATION

[16] OTHER | DB: pets_1 | EX: ✓
  Q   : Find the weight of the youngest dog
  Pred: SELECT Weight FROM pets ORDER BY Pet_age ASC LIMIT 1
  Gold: SELECT weight FROM pets ORDER BY pet_age LIMIT 1
  Type: ORDER_BY, LIMIT

[17] OTHER | DB: pets_1 | EX: ✓
  Q   : How much does the youngest dog weigh
  Pred: SELECT Weight FROM pets ORDER BY Pet_age ASC LIMIT 1
  Gold: SELECT weight FROM pets ORDER BY pet_age LIMIT 1
  Type: ORDER_BY, LIMIT

[18] WRONG_COLUMNS | DB: pets_1 | EX: ✗
  Q   : List the maximum weight and type for each type of pet
  Pred: SELECT MAX(weight), TYPE FROM pets GROUP BY TYPE
  Gold: SELECT MAX(weight), petType FROM pets GROUP BY petType
  Type: GROUP_BY, AGGREGATION

[19] WRONG_TABLE | DB: pets_1 | EX: ✓
  Q   : Find number of pets owned by students who are older than 20
  Pred: SELECT COUNT(*) FROM pets AS T1 JOIN has_pet AS T2 ON T1.petid = T2.petid JOIN student AS T3 ON T3.stuid = T2.stuid WHERE T3.age > 20
  Gold: SELECT COUNT(*) FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid WHERE T1.age > 20
  Type: JOIN, AGGREGATION

[20] WRONG_TABLE | DB: pets_1 | EX: ✗
  Q   : How many pets are owned by students that have an age greater than 20
  Pred: SELECT COUNT(*) FROM has_pet AS T1 JOIN pets AS T2 ON T1.petid = T2.petid JOIN student AS T3 ON T1.stuid = T3.stuid WHERE T3.pet_age > 20
  Gold: SELECT COUNT(*) FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid WHERE T1.age > 20
  Type: JOIN, AGGREGATION

[21] WRONG_TABLE | DB: pets_1 | EX: ✗
  Q   : Find the number of dog pets that are raised by female students (with sex F)
  Pred: SELECT COUNT(*) FROM Pets AS T1 JOIN Has_pet AS T2 ON T1.petid = T2.petid JOIN Student AS T3 ON T3.StuID = T2.StuID WHERE T3.sex = 'F'
  Gold: SELECT COUNT(*) FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid JOIN pets AS T3 ON T2.petid = T3.petid WHERE T1.sex = 'F' AND T3.pettype = 'dog'
  Type: JOIN, AGGREGATION

[22] WRONG_TABLE | DB: pets_1 | EX: ✗
  Q   : How many dog pets are raised by female students
  Pred: SELECT COUNT(*) FROM Pets AS T1 JOIN Has_pet AS T2 ON T1.petid = T2.petid JOIN Student AS T3 ON T3.StuID = T2.StuID WHERE T3.sex = 'F'
  Gold: SELECT COUNT(*) FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid JOIN pets AS T3 ON T2.petid = T3.petid WHERE T1.sex = 'F' AND T3.pettype = 'dog'
  Type: JOIN, AGGREGATION

[23] OTHER | DB: pets_1 | EX: ✗
  Q   : Find the first name of students who have cat or dog pet
  Pred: SELECT DISTINCT T1.fname FROM Student AS T1 JOIN Has_Pet AS T2 ON T1.StuID = T2.StuID WHERE T2.pettype = "cat" OR T2.pettype = "dog"
  Gold: SELECT DISTINCT T1.Fname FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid JOIN pets AS T3 ON T3.petid = T2.petid WHERE T3.pettype = 'cat' OR T3.pettype = 'dog'
  Type: JOIN

[24] WRONG_COLUMNS | DB: pets_1 | EX: ✗
  Q   : What are the first names of every student who has a cat or dog as a pet
  Pred: SELECT T1.fname FROM Student AS T1 JOIN Has_Pet AS T2 ON T1.StuID = T2.StuID WHERE T2.pettype = "cat" OR T2.pettype = "dog"
  Gold: SELECT DISTINCT T1.Fname FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid JOIN pets AS T3 ON T3.petid = T2.petid WHERE T3.pettype = 'cat' OR T3.pettype = 'dog'
  Type: JOIN

[25] WRONG_COLUMNS | DB: pets_1 | EX: ✗
  Q   : Find the first name of students who have both cat and dog pets
  Pred: SELECT DISTINCT T1.fname FROM Student AS T1 JOIN Has_Pet AS T2 ON T1.StuID = T2.StuID WHERE T2.pettype = "Cat" INTERSECT SELECT T1.Fname FROM Student AS T1 JOIN Has_Pet AS T2 ON T1.StuID = T2.StuID WHERE T2.pettype = "Dog"
  Gold: SELECT t1.fname FROM student AS t1 JOIN has_pet AS t2 ON t1.stuid = t2.stuid JOIN pets AS t3 ON t3.petid = t2.petid WHERE t3.pettype = 'cat' INTERSECT SELECT t1.fname FROM student AS t1 JOIN has_pet AS t2 ON t1.stuid = t2.stuid JOIN pets AS t3 ON t3.petid = t2.petid WHERE t3.pettype = 'dog'
  Type: JOIN

[26] WRONG_COLUMNS | DB: pets_1 | EX: ✗
  Q   : What are the students' first names who have both cats and dogs as pets
  Pred: SELECT DISTINCT T1.fname FROM Student AS T1 JOIN Has_Pet AS T2 ON T1.stuid = T2.stuid JOIN pets AS T3 ON T2.petid = T3.petid WHERE T3.pettype = "cat" INTERSECT SELECT T1.fname FROM Student AS T1 JOIN Has_Pet AS T2 ON T1.stuid = T2.stuid JOIN pets AS T3 ON T2.pet
  Gold: SELECT T1.Fname FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid JOIN pets AS T3 ON T3.petid = T2.petid WHERE T3.pettype = 'cat' INTERSECT SELECT T1.Fname FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid JOIN pets AS T3 ON T3.petid = T2.petid WHERE T3.pettype = 'dog'
  Type: JOIN

[27] WRONG_TABLE | DB: pets_1 | EX: ✗
  Q   : Find the major and age of students who do not have a cat pet
  Pred: SELECT major, age FROM Student WHERE NOT StuID IN (SELECT StuID FROM Has_pet)
  Gold: SELECT major, age FROM student WHERE NOT stuid IN (SELECT T1.stuid FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid JOIN pets AS T3 ON T3.petid = T2.petid WHERE T3.pettype = 'cat')
  Type: JOIN, NESTED

[28] WRONG_TABLE | DB: pets_1 | EX: ✗
  Q   : What major is every student who does not own a cat as a pet, and also how old are they
  Pred: SELECT major, age FROM Student WHERE NOT StuID IN (SELECT StuID FROM Has_pet WHERE petType = "Cat")
  Gold: SELECT major, age FROM student WHERE NOT stuid IN (SELECT T1.stuid FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid JOIN pets AS T3 ON T3.petid = T2.petid WHERE T3.pettype = 'cat')
  Type: JOIN, NESTED

[29] WRONG_TABLE | DB: pets_1 | EX: ✗
  Q   : Find the id of students who do not have a cat pet
  Pred: SELECT StuID FROM Student EXCEPT SELECT StuID FROM Has_pet
  Gold: SELECT stuid FROM student EXCEPT SELECT T1.stuid FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid JOIN pets AS T3 ON T3.petid = T2.petid WHERE T3.pettype = 'cat'
  Type: JOIN

[30] WRONG_TABLE | DB: pets_1 | EX: ✗
  Q   : What are the ids of the students who do not own cats as pets
  Pred: SELECT StuID FROM Student EXCEPT SELECT StuID FROM Has_pet
  Gold: SELECT stuid FROM student EXCEPT SELECT T1.stuid FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid JOIN pets AS T3 ON T3.petid = T2.petid WHERE T3.pettype = 'cat'
  Type: JOIN

[31] WRONG_TABLE | DB: pets_1 | EX: ✗
  Q   : Find the first name and age of students who have a dog but do not have a cat as a pet
  Pred: SELECT fname, age FROM Student WHERE StuID IN (SELECT StuID FROM Has_pet WHERE petType = "dog") EXCEPT SELECT StuID FROM Has_pet WHERE petType = "cat")
  Gold: SELECT T1.fname, T1.age FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid JOIN pets AS T3 ON T3.petid = T2.petid WHERE T3.pettype = 'dog' AND NOT T1.stuid IN (SELECT T1.stuid FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid JOIN pets AS T3 ON T3.petid = T2.petid WHERE T3.pettype = 'cat')
  Type: JOIN, NESTED

[32] WRONG_TABLE | DB: pets_1 | EX: ✗
  Q   : What is the first name of every student who has a dog but does not have a cat
  Pred: SELECT fname FROM Student WHERE StuID IN (SELECT StuID FROM Has_pet WHERE petType = "dog") EXCEPT SELECT StuID FROM Has_pet WHERE petType = "cat")
  Gold: SELECT T1.fname, T1.age FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid JOIN pets AS T3 ON T3.petid = T2.petid WHERE T3.pettype = 'dog' AND NOT T1.stuid IN (SELECT T1.stuid FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid JOIN pets AS T3 ON T3.petid = T2.petid WHERE T3.pettype = 'cat')
  Type: JOIN, NESTED

[33] OTHER | DB: pets_1 | EX: ✓
  Q   : Find the type and weight of the youngest pet
  Pred: SELECT pettype, weight FROM pets ORDER BY pet_age ASC LIMIT 1
  Gold: SELECT pettype, weight FROM pets ORDER BY pet_age LIMIT 1
  Type: ORDER_BY, LIMIT

[34] OTHER | DB: pets_1 | EX: ✓
  Q   : What type of pet is the youngest animal, and how much does it weigh
  Pred: SELECT pettype, weight FROM pets ORDER BY pet_age ASC LIMIT 1
  Gold: SELECT pettype, weight FROM pets ORDER BY pet_age LIMIT 1
  Type: ORDER_BY, LIMIT

[35] WRONG_COLUMNS | DB: pets_1 | EX: ✗
  Q   : Find the average and maximum age for each type of pet
  Pred: SELECT pettype, AVG(pet_age), MAX(pet_age) FROM pets GROUP BY pettype
  Gold: SELECT AVG(pet_age), MAX(pet_age), pettype FROM pets GROUP BY pettype
  Type: GROUP_BY, AGGREGATION

[36] WRONG_COLUMNS | DB: pets_1 | EX: ✗
  Q   : What is the average and maximum age for each pet type
  Pred: SELECT pettype, AVG(pet_age), MAX(pet_age) FROM pets GROUP BY pettype
  Gold: SELECT AVG(pet_age), MAX(pet_age), pettype FROM pets GROUP BY pettype
  Type: GROUP_BY, AGGREGATION

[37] WRONG_COLUMNS | DB: pets_1 | EX: ✗
  Q   : Find the average weight for each pet type
  Pred: SELECT pettype, AVG(weight) FROM pets GROUP BY pettype
  Gold: SELECT AVG(weight), pettype FROM pets GROUP BY pettype
  Type: GROUP_BY, AGGREGATION

[38] WRONG_COLUMNS | DB: pets_1 | EX: ✗
  Q   : What is the average weight for each type of pet
  Pred: SELECT pettype, AVG(weight) FROM pets GROUP BY pettype
  Gold: SELECT AVG(weight), pettype FROM pets GROUP BY pettype
  Type: GROUP_BY, AGGREGATION

[39] WRONG_TABLE | DB: pets_1 | EX: ✓
  Q   : Find the id of the pet owned by student whose last name is ‘Smith’
  Pred: SELECT T2.petid FROM Has_pet AS T1 JOIN pets AS T2 ON T1.petid = T2.petid JOIN student AS T3 ON T1.stuid = T3.stuid WHERE T3.lname = 'Smith'
  Gold: SELECT T2.petid FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid WHERE T1.Lname = 'Smith'
  Type: JOIN

[40] WRONG_TABLE | DB: pets_1 | EX: ✓
  Q   : What is the id of the pet owned by the student whose last name is 'Smith'
  Pred: SELECT T2.petid FROM Has_pet AS T1 JOIN pets AS T2 ON T1.petid = T2.petid JOIN student AS T3 ON T1.stuid = T3.stuid WHERE T3.lname = 'Smith'
  Gold: SELECT T2.petid FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid WHERE T1.Lname = 'Smith'
  Type: JOIN

[41] WRONG_TABLE | DB: pets_1 | EX: ✓
  Q   : Find the number of pets for each student who has any pet and student id
  Pred: SELECT COUNT(*), T1.StuID FROM Has_pet AS T1 JOIN pets AS T2 ON T1.PetId = T2.PetID GROUP BY T1.StuID
  Gold: SELECT COUNT(*), T1.stuid FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid GROUP BY T1.stuid
  Type: JOIN, GROUP_BY, AGGREGATION

[42] WRONG_TABLE | DB: pets_1 | EX: ✓
  Q   : For students who have pets , how many pets does each student have ? list their ids instead of names
  Pred: SELECT COUNT(*), T1.StuID FROM Has_pet AS T1 JOIN pets AS T2 ON T1.PetId = T2.PetID GROUP BY T1.StuID
  Gold: SELECT COUNT(*), t1.stuid FROM student AS t1 JOIN has_pet AS t2 ON t1.stuid = t2.stuid GROUP BY t1.stuid
  Type: JOIN, GROUP_BY, AGGREGATION

[43] WRONG_TABLE | DB: pets_1 | EX: ✗
  Q   : Find the last name of the student who has a cat that is age 3
  Pred: SELECT lname FROM Student WHERE StuID IN (SELECT StuID FROM Has_pet WHERE Pet_age = 3)
  Gold: SELECT T1.lname FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid JOIN pets AS T3 ON T3.petid = T2.petid WHERE T3.pet_age = 3 AND T3.pettype = 'cat'
  Type: JOIN

[44] WRONG_TABLE | DB: pets_1 | EX: ✗
  Q   : What is the last name of the student who has a cat that is 3 years old
  Pred: SELECT T2.Lname FROM Has_pet AS T1 JOIN Student AS T2 ON T1.StuID = T2.StuID WHERE T1.Pet_age = 3
  Gold: SELECT T1.lname FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid JOIN pets AS T3 ON T3.petid = T2.petid WHERE T3.pet_age = 3 AND T3.pettype = 'cat'
  Type: JOIN

[45] WRONG_TABLE | DB: pets_1 | EX: ✗
  Q   : What is the average age for all students who do not own any pets
  Pred: SELECT AVG(T1.age) FROM Student AS T1 JOIN Has_Pet AS T2 ON T1.StuID = T2.StuID WHERE NOT T2.pet_age IN (SELECT T1.age FROM Student AS T1 JOIN Has_Pet AS T2 ON T1.StuID = T2.petid)
  Gold: SELECT AVG(age) FROM student WHERE NOT stuid IN (SELECT stuid FROM has_pet)
  Type: NESTED, AGGREGATION

[46] WRONG_COLUMNS | DB: car_1 | EX: ✗
  Q   : How many countries does each continent have? List the continent id, continent name and the number of countries
  Pred: SELECT T1.continent, COUNT(*) FROM continents AS T1 JOIN countries AS T2 ON T1.contid = T2.continent GROUP BY T1.contid
  Gold: SELECT T1.ContId, T1.Continent, COUNT(*) FROM CONTINENTS AS T1 JOIN COUNTRIES AS T2 ON T1.ContId = T2.Continent GROUP BY T1.ContId
  Type: JOIN, GROUP_BY, AGGREGATION

[47] WRONG_COLUMNS | DB: car_1 | EX: ✗
  Q   : For each continent, list its id, name, and how many countries it has
  Pred: SELECT T1.continent, T1.countryname, COUNT(*) FROM continents AS T1 JOIN countries AS T2 ON T1.contid = T2.continent GROUP BY T1.contid
  Gold: SELECT T1.ContId, T1.Continent, COUNT(*) FROM CONTINENTS AS T1 JOIN COUNTRIES AS T2 ON T1.ContId = T2.Continent GROUP BY T1.ContId
  Type: JOIN, GROUP_BY, AGGREGATION

[48] WRONG_COLUMNS | DB: car_1 | EX: ✗
  Q   : How many models does each car maker produce? List maker full name, id and the number
  Pred: SELECT COUNT(*), T1.maker FROM car_makers AS T1 JOIN model_list AS T2 ON T1.id = T2.maker GROUP BY T1.maker
  Gold: SELECT T1.FullName, T1.Id, COUNT(*) FROM CAR_MAKERS AS T1 JOIN MODEL_LIST AS T2 ON T1.Id = T2.Maker GROUP BY T1.Id
  Type: JOIN, GROUP_BY, AGGREGATION

[49] WRONG_COLUMNS | DB: car_1 | EX: ✗
  Q   : What is the full name of each car maker, along with its id and how many models it produces
  Pred: SELECT T1.fullname, T1.make, COUNT(*) FROM car_makers AS T1 JOIN model_list AS T2 ON T1.id = T2.model GROUP BY T1.makemaker
  Gold: SELECT T1.FullName, T1.Id, COUNT(*) FROM CAR_MAKERS AS T1 JOIN MODEL_LIST AS T2 ON T1.Id = T2.Maker GROUP BY T1.Id
  Type: JOIN, GROUP_BY, AGGREGATION

[50] WRONG_TABLE | DB: car_1 | EX: ✗
  Q   : Which model of the car has the minimum horsepower
  Pred: SELECT t1.model FROM model_list AS t1 JOIN car_names AS t2 ON t1.model = t2.model WHERE horsepower = (SELECT MIN(horsepower) FROM cars_data)
  Gold: SELECT T1.Model FROM CAR_NAMES AS T1 JOIN CARS_DATA AS T2 ON T1.MakeId = T2.Id ORDER BY T2.horsepower ASC LIMIT 1
  Type: JOIN, ORDER_BY, LIMIT

[51] WRONG_COLUMNS | DB: car_1 | EX: ✗
  Q   : What is the model of the car with the smallest amount of horsepower
  Pred: SELECT t3.model FROM car_names AS t1 JOIN model_list AS t2 ON t1.model = t2.model ORDER BY t1.horsepower LIMIT 1
  Gold: SELECT T1.Model FROM CAR_NAMES AS T1 JOIN CARS_DATA AS T2 ON T1.MakeId = T2.Id ORDER BY T2.horsepower ASC LIMIT 1
  Type: JOIN, ORDER_BY, LIMIT

[52] MISSING_JOIN | DB: car_1 | EX: ✗
  Q   : Find the model of the car whose weight is below the average weight
  Pred: SELECT DISTINCT model FROM car_names WHERE weight  (SELECT AVG(weight) FROM cars_data)
  Gold: SELECT T1.model FROM CAR_NAMES AS T1 JOIN CARS_DATA AS T2 ON T1.MakeId = T2.Id WHERE T2.Weight < (SELECT AVG(Weight) FROM CARS_DATA)
  Type: JOIN, NESTED, AGGREGATION

[53] MISSING_JOIN | DB: car_1 | EX: ✗
  Q   : What is the model for the car with a weight smaller than the average
  Pred: SELECT model FROM car_names WHERE weight  (SELECT AVG(weight) FROM cars_data)
  Gold: SELECT T1.model FROM CAR_NAMES AS T1 JOIN CARS_DATA AS T2 ON T1.MakeId = T2.Id WHERE T2.Weight < (SELECT AVG(Weight) FROM CARS_DATA)
  Type: JOIN, NESTED, AGGREGATION

[54] WRONG_COLUMNS | DB: car_1 | EX: ✗
  Q   : Find the name of the makers that produced some cars in the year of 1970
  Pred: SELECT T1.maker FROM car_makers AS T1 JOIN model_list AS T2 ON T1.id = T2.model WHERE T2.year = 1970
  Gold: SELECT DISTINCT T1.Maker FROM CAR_MAKERS AS T1 JOIN MODEL_LIST AS T2 ON T1.Id = T2.Maker JOIN CAR_NAMES AS T3 ON T2.model = T3.model JOIN CARS_DATA AS T4 ON T3.MakeId = T4.id WHERE T4.year = '1970'
  Type: JOIN

[55] OTHER | DB: car_1 | EX: ✗
  Q   : What is the name of the different car makers who produced a car in 1970
  Pred: SELECT DISTINCT T1.maker FROM car_makers AS T1 JOIN model_list AS T2 ON T1.id = T2.model WHERE T2.year = 1970
  Gold: SELECT DISTINCT T1.Maker FROM CAR_MAKERS AS T1 JOIN MODEL_LIST AS T2 ON T1.Id = T2.Maker JOIN CAR_NAMES AS T3 ON T2.model = T3.model JOIN CARS_DATA AS T4 ON T3.MakeId = T4.id WHERE T4.year = '1970'
  Type: JOIN

[56] WRONG_TABLE | DB: car_1 | EX: ✗
  Q   : Find the make and production time of the cars that were produced in the earliest year
  Pred: SELECT T1.make, T2.year FROM car_names AS T1 JOIN make AS T2 ON T1.makeid = T2.id ORDER BY T1.year LIMIT 1
  Gold: SELECT T2.Make, T1.Year FROM CARS_DATA AS T1 JOIN CAR_NAMES AS T2 ON T1.Id = T2.MakeId WHERE T1.Year = (SELECT MIN(YEAR) FROM CARS_DATA)
  Type: JOIN, NESTED, AGGREGATION

[57] WRONG_TABLE | DB: car_1 | EX: ✗
  Q   : What is the maker of the carr produced in the earliest year and what year was it
  Pred: SELECT T1.maker, T1.year FROM car_makers AS T1 JOIN model_list AS T2 ON T1.id = T2.maker ORDER BY T2.year LIMIT 1
  Gold: SELECT T2.Make, T1.Year FROM CARS_DATA AS T1 JOIN CAR_NAMES AS T2 ON T1.Id = T2.MakeId WHERE T1.Year = (SELECT MIN(YEAR) FROM CARS_DATA)
  Type: JOIN, NESTED, AGGREGATION

[58] WRONG_TABLE | DB: car_1 | EX: ✗
  Q   : Which distinct car models are the produced after 1980
  Pred: SELECT DISTINCT model FROM car_names WHERE YEAR > 1980
  Gold: SELECT DISTINCT T1.model FROM MODEL_LIST AS T1 JOIN CAR_NAMES AS T2 ON T1.model = T2.model JOIN CARS_DATA AS T3 ON T2.MakeId = T3.id WHERE T3.year > 1980
  Type: JOIN

[59] WRONG_COLUMNS | DB: car_1 | EX: ✗
  Q   : What are the different models for the cards produced after 1980
  Pred: SELECT DISTINCT T2.model FROM model_list AS T1 JOIN car_makers AS T2 ON T1.make = T2.makeid WHERE T2.year > 1980
  Gold: SELECT DISTINCT T1.model FROM MODEL_LIST AS T1 JOIN CAR_NAMES AS T2 ON T1.model = T2.model JOIN CARS_DATA AS T3 ON T2.MakeId = T3.id WHERE T3.year > 1980
  Type: JOIN

[60] OTHER | DB: car_1 | EX: ✗
  Q   : How many car makers are there in each continents? List the continent name and the count
  Pred: SELECT T1.continent, COUNT(*) FROM continents AS T1 JOIN car_makers AS T2 ON T1.contid = T2.id GROUP BY T1.contid
  Gold: SELECT T1.Continent, COUNT(*) FROM CONTINENTS AS T1 JOIN COUNTRIES AS T2 ON T1.ContId = T2.continent JOIN car_makers AS T3 ON T2.CountryId = T3.Country GROUP BY T1.Continent
  Type: JOIN, GROUP_BY, AGGREGATION

[61] OTHER | DB: car_1 | EX: ✗
  Q   : What is the name of each continent and how many car makers are there in each one
  Pred: SELECT T1.continent, COUNT(*) FROM continents AS T1 JOIN car_makers AS T2 ON T1.contid = T2.contid GROUP BY T1.continent
  Gold: SELECT T1.Continent, COUNT(*) FROM CONTINENTS AS T1 JOIN COUNTRIES AS T2 ON T1.ContId = T2.continent JOIN car_makers AS T3 ON T2.CountryId = T3.Country GROUP BY T1.Continent
  Type: JOIN, GROUP_BY, AGGREGATION

[62] WRONG_TABLE | DB: car_1 | EX: ✗
  Q   : Which of the countries has the most car makers? List the country name
  Pred: SELECT T1.countryname FROM countries AS T1 JOIN car_makers AS T2 ON T1.country = T2.countryid GROUP BY T1.countryname ORDER BY COUNT(*) DESC LIMIT 1
  Gold: SELECT T2.CountryName FROM CAR_MAKERS AS T1 JOIN COUNTRIES AS T2 ON T1.Country = T2.CountryId GROUP BY T1.Country ORDER BY COUNT(*) DESC LIMIT 1
  Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, AGGREGATION

[63] WRONG_TABLE | DB: car_1 | EX: ✗
  Q   : What is the name of the country with the most car makers
  Pred: SELECT T1.countryname FROM countries AS T1 JOIN car_makers AS T2 ON T1.country = T2.countryid GROUP BY T1.countryname ORDER BY COUNT(*) DESC LIMIT 1
  Gold: SELECT T2.CountryName FROM CAR_MAKERS AS T1 JOIN COUNTRIES AS T2 ON T1.Country = T2.CountryId GROUP BY T1.Country ORDER BY COUNT(*) DESC LIMIT 1
  Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, AGGREGATION

[64] WRONG_TABLE | DB: car_1 | EX: ✗
  Q   : How many car models are produced by each maker ? Only list the count and the maker full name
  Pred: SELECT COUNT(*), T1.maker FROM car_makers AS T1 JOIN model_list AS T2 ON T1.id = T2.model GROUP BY T1.maker
  Gold: SELECT COUNT(*), t2.fullname FROM model_list AS t1 JOIN car_makers AS t2 ON t1.maker = t2.id GROUP BY t2.id
  Type: JOIN, GROUP_BY, AGGREGATION

[65] WRONG_TABLE | DB: car_1 | EX: ✗
  Q   : What is the number of car models that are produced by each maker and what is the id and full name of each maker
  Pred: SELECT COUNT(*), T1.make, T1.fullname FROM car_makers AS T1 JOIN model_list AS T2 ON T1.id = T2.model GROUP BY T1.makemaker
  Gold: SELECT COUNT(*), T2.FullName, T2.id FROM MODEL_LIST AS T1 JOIN CAR_MAKERS AS T2 ON T1.Maker = T2.Id GROUP BY T2.id
  Type: JOIN, GROUP_BY, AGGREGATION

[66] WRONG_TABLE | DB: car_1 | EX: ✗
  Q   : What is the accelerate of the car make amc hornet sportabout (sw)
  Pred: SELECT Accelerate FROM car_names WHERE make = 'amc hornet sportabout (sw)'
  Gold: SELECT T1.Accelerate FROM CARS_DATA AS T1 JOIN CAR_NAMES AS T2 ON T1.Id = T2.MakeId WHERE T2.Make = 'amc hornet sportabout (sw)'
  Type: JOIN

[67] WRONG_TABLE | DB: car_1 | EX: ✗
  Q   : How much does the car accelerate that makes amc hornet sportabout (sw)
  Pred: SELECT Accelerate FROM car_names WHERE make = 'amc hornet sportabout (sw)'
  Gold: SELECT T1.Accelerate FROM CARS_DATA AS T1 JOIN CAR_NAMES AS T2 ON T1.Id = T2.MakeId WHERE T2.Make = 'amc hornet sportabout (sw)'
  Type: JOIN

[68] WRONG_TABLE | DB: car_1 | EX: ✗
  Q   : How many car makers are there in france
  Pred: SELECT COUNT(*) FROM countries AS T1 JOIN car_makers AS T2 ON T1.country = T2.countryid WHERE T1.countryname = "France"
  Gold: SELECT COUNT(*) FROM CAR_MAKERS AS T1 JOIN COUNTRIES AS T2 ON T1.Country = T2.CountryId WHERE T2.CountryName = 'france'
  Type: JOIN, AGGREGATION

[69] WRONG_TABLE | DB: car_1 | EX: ✗
  Q   : What is the number of makers of care in France
  Pred: SELECT COUNT(*) FROM countries AS T1 JOIN model_list AS T2 ON T1.country = T2.countryid WHERE T1.countryname = "France"
  Gold: SELECT COUNT(*) FROM CAR_MAKERS AS T1 JOIN COUNTRIES AS T2 ON T1.Country = T2.CountryId WHERE T2.CountryName = 'france'
  Type: JOIN, AGGREGATION

[70] WRONG_TABLE | DB: car_1 | EX: ✗
  Q   : How many car models are produced in the usa
  Pred: SELECT COUNT(*) FROM car_makers AS T1 JOIN countries AS T2 ON T1.country = T2.countryid WHERE T2.countryname = "USA"
  Gold: SELECT COUNT(*) FROM MODEL_LIST AS T1 JOIN CAR_MAKERS AS T2 ON T1.Maker = T2.Id JOIN COUNTRIES AS T3 ON T2.Country = T3.CountryId WHERE T3.CountryName = 'usa'
  Type: JOIN, AGGREGATION

[71] WRONG_TABLE | DB: car_1 | EX: ✗
  Q   : What is the count of the car models produced in the United States
  Pred: SELECT COUNT(*) FROM car_makers AS T1 JOIN countries AS T2 ON T1.country = T2.countryid WHERE T2.countryname = "United States"
  Gold: SELECT COUNT(*) FROM MODEL_LIST AS T1 JOIN CAR_MAKERS AS T2 ON T1.Maker = T2.Id JOIN COUNTRIES AS T3 ON T2.Country = T3.CountryId WHERE T3.CountryName = 'usa'
  Type: JOIN, AGGREGATION

[72] WRONG_TABLE | DB: car_1 | EX: ✗
  Q   : What is the smallest weight of the car produced with 8 cylinders on 1974
  Pred: SELECT MIN(weight) FROM car_names AS T1 JOIN make AS T2 ON T1.make = T2.makeid WHERE T2.cylinders = 8 AND YEAR = 1974
  Gold: SELECT MIN(weight) FROM cars_data WHERE cylinders = 8 AND year = 1974
  Type: AGGREGATION

[73] EXTRA_JOIN | DB: car_1 | EX: ✗
  Q   : What are all the makers and models
  Pred: SELECT T1.maker, T1.model FROM model_list AS T1 JOIN car_makers AS T2 ON T1.id = T2.maker
  Gold: SELECT Maker, Model FROM MODEL_LIST
  Type: SIMPLE

[74] EXTRA_JOIN | DB: car_1 | EX: ✗
  Q   : What are the makers and models
  Pred: SELECT T1.maker, T1.model FROM model_list AS T1 JOIN car_makers AS T2 ON T1.id = T2.maker
  Gold: SELECT Maker, Model FROM MODEL_LIST
  Type: SIMPLE

[75] OTHER | DB: car_1 | EX: ✗
  Q   : What are the countries having at least one car maker? List name and id
  Pred: SELECT T1.countryname, T1.countryid FROM countries AS T1 JOIN car_makers AS T2 ON T1.country = T2.countryid GROUP BY T1.countryid HAVING COUNT(*) >= 1
  Gold: SELECT T1.CountryName, T1.CountryId FROM COUNTRIES AS T1 JOIN CAR_MAKERS AS T2 ON T1.CountryId = T2.Country GROUP BY T1.CountryId HAVING COUNT(*) >= 1
  Type: JOIN, GROUP_BY, HAVING, AGGREGATION

[76] OTHER | DB: car_1 | EX: ✗
  Q   : What are the names and ids of all countries with at least one car maker
  Pred: SELECT T1.countryname, T1.countryid FROM countries AS T1 JOIN car_makers AS T2 ON T1.country = T2.countryid GROUP BY T1.countryid HAVING COUNT(*) >= 1
  Gold: SELECT T1.CountryName, T1.CountryId FROM COUNTRIES AS T1 JOIN CAR_MAKERS AS T2 ON T1.CountryId = T2.Country GROUP BY T1.CountryId HAVING COUNT(*) >= 1
  Type: JOIN, GROUP_BY, HAVING, AGGREGATION

[77] WRONG_TABLE | DB: car_1 | EX: ✗
  Q   : What is the number of the cars with horsepower more than 150
  Pred: SELECT COUNT(*) FROM car_names WHERE horsepower > 150
  Gold: SELECT COUNT(*) FROM CARS_DATA WHERE horsepower > 150
  Type: AGGREGATION

[78] OTHER | DB: car_1 | EX: ✗
  Q   : Which countries in europe have at least 3 car manufacturers
  Pred: SELECT T1.countryname FROM countries AS T1 JOIN car_makers AS T2 ON T1.country = T2.countryid WHERE T1.country = "Europe" GROUP BY T1.countryname HAVING COUNT(*) >= 3
  Gold: SELECT T1.CountryName FROM COUNTRIES AS T1 JOIN CONTINENTS AS T2 ON T1.Continent = T2.ContId JOIN CAR_MAKERS AS T3 ON T1.CountryId = T3.Country WHERE T2.Continent = 'europe' GROUP BY T1.CountryName HAVING COUNT(*) >= 3
  Type: JOIN, GROUP_BY, HAVING, AGGREGATION

[79] MISSING_JOIN | DB: car_1 | EX: ✗
  Q   : What are the names of all European countries with at least 3 manufacturers
  Pred: SELECT countryname FROM countries WHERE countryname = 'Europe' GROUP BY countryname HAVING COUNT(*) >= 3
  Gold: SELECT T1.CountryName FROM COUNTRIES AS T1 JOIN CONTINENTS AS T2 ON T1.Continent = T2.ContId JOIN CAR_MAKERS AS T3 ON T1.CountryId = T3.Country WHERE T2.Continent = 'europe' GROUP BY T1.CountryName HAVING COUNT(*) >= 3
  Type: JOIN, GROUP_BY, HAVING, AGGREGATION

[80] MISSING_JOIN | DB: car_1 | EX: ✗
  Q   : What is the maximum horsepower and the make of the car models with 3 cylinders
  Pred: SELECT MAX(horsepower), MAX(make) FROM car_names WHERE cylinders = 3
  Gold: SELECT T2.horsepower, T1.Make FROM CAR_NAMES AS T1 JOIN CARS_DATA AS T2 ON T1.MakeId = T2.Id WHERE T2.cylinders = 3 ORDER BY T2.horsepower DESC LIMIT 1
  Type: JOIN, ORDER_BY, LIMIT

[81] WRONG_TABLE | DB: car_1 | EX: ✗
  Q   : What is the largest amount of horsepower for the models with 3 cylinders and what make is it
  Pred: SELECT MAX(HPV), T1.make FROM car_makers AS T1 JOIN model_list AS T2 ON T1.id = T2.modelId WHERE T2.cylinders = 3 GROUP BY T1.make
  Gold: SELECT T2.horsepower, T1.Make FROM CAR_NAMES AS T1 JOIN CARS_DATA AS T2 ON T1.MakeId = T2.Id WHERE T2.cylinders = 3 ORDER BY T2.horsepower DESC LIMIT 1
  Type: JOIN, ORDER_BY, LIMIT

[82] WRONG_TABLE | DB: car_1 | EX: ✗
  Q   : Which model saves the most gasoline? That is to say, have the maximum miles per gallon
  Pred: SELECT t1.model FROM model_list AS t1 JOIN cars_data AS t2 ON t1.model = t2.model WHERE t2.mpg = (SELECT MAX(mpg) FROM cars_data)
  Gold: SELECT T1.Model FROM CAR_NAMES AS T1 JOIN CARS_DATA AS T2 ON T1.MakeId = T2.Id ORDER BY T2.mpg DESC LIMIT 1
  Type: JOIN, ORDER_BY, LIMIT

[83] OTHER | DB: car_1 | EX: ✗
  Q   : What is the car model with the highest mpg
  Pred: SELECT t1.model FROM car_names AS t1 JOIN model_list AS t2 ON t1.model = t2.model ORDER BY t2.mpg DESC LIMIT 1
  Gold: SELECT t1.model FROM car_names AS t1 JOIN cars_data AS t2 ON t1.makeid = t2.id ORDER BY t2.mpg DESC LIMIT 1
  Type: JOIN, ORDER_BY, LIMIT

[84] OTHER | DB: car_1 | EX: ✗
  Q   : What is the average horsepower of the cars before 1980
  Pred: SELECT AVG(horsepower) FROM cars_data WHERE YEAR  1980
  Gold: SELECT AVG(horsepower) FROM CARS_DATA WHERE YEAR < 1980
  Type: AGGREGATION

[85] WRONG_TABLE | DB: car_1 | EX: ✗
  Q   : What is the average horsepower for all cars produced before 1980
  Pred: SELECT AVG(horsepower) FROM car_names WHERE YEAR  1980
  Gold: SELECT AVG(horsepower) FROM cars_data WHERE year < 1980
  Type: AGGREGATION

[86] WRONG_TABLE | DB: car_1 | EX: ✗
  Q   : What is the average edispl of the cars of model volvo
  Pred: SELECT AVG(T2.edispl) FROM model_list AS T1 JOIN car_names AS T2 ON T1.model = T2.model WHERE T1.make = "Volvo"
  Gold: SELECT AVG(T2.edispl) FROM CAR_NAMES AS T1 JOIN CARS_DATA AS T2 ON T1.MakeId = T2.Id WHERE T1.Model = 'volvo'
  Type: JOIN, AGGREGATION

[87] WRONG_TABLE | DB: car_1 | EX: ✗
  Q   : What is the average edispl for all volvos
  Pred: SELECT AVG(edispl) FROM cars_data WHERE make = "Volvo"
  Gold: SELECT AVG(T2.edispl) FROM CAR_NAMES AS T1 JOIN CARS_DATA AS T2 ON T1.MakeId = T2.Id WHERE T1.Model = 'volvo'
  Type: JOIN, AGGREGATION

[88] WRONG_COLUMNS | DB: car_1 | EX: ✗
  Q   : What is the maximum accelerate for different number of cylinders
  Pred: SELECT MAX(accurate), COUNT(*) FROM cars_data GROUP BY cylinders
  Gold: SELECT MAX(Accelerate), Cylinders FROM CARS_DATA GROUP BY Cylinders
  Type: GROUP_BY, AGGREGATION

[89] WRONG_COLUMNS | DB: car_1 | EX: ✗
  Q   : What is the maximum accelerate for all the different cylinders
  Pred: SELECT MAX(accurate), cylinders FROM cars_data GROUP BY cylinders
  Gold: SELECT MAX(Accelerate), Cylinders FROM CARS_DATA GROUP BY Cylinders
  Type: GROUP_BY, AGGREGATION

[90] EXTRA_JOIN | DB: car_1 | EX: ✓
  Q   : Which model has the most version(make) of cars
  Pred: SELECT T2.model FROM car_names AS T1 JOIN model_list AS T2 ON T1.model = T2.model GROUP BY T2.model ORDER BY COUNT(*) DESC LIMIT 1
  Gold: SELECT Model FROM CAR_NAMES GROUP BY Model ORDER BY COUNT(*) DESC LIMIT 1
  Type: GROUP_BY, ORDER_BY, LIMIT, AGGREGATION

[91] WRONG_TABLE | DB: car_1 | EX: ✗
  Q   : What model has the most different versions
  Pred: SELECT model FROM model_list GROUP BY model ORDER BY COUNT(*) DESC LIMIT 1
  Gold: SELECT Model FROM CAR_NAMES GROUP BY Model ORDER BY COUNT(*) DESC LIMIT 1
  Type: GROUP_BY, ORDER_BY, LIMIT, AGGREGATION

[92] WRONG_TABLE | DB: car_1 | EX: ✗
  Q   : how many cars were produced in 1980
  Pred: SELECT COUNT(*) FROM car_names WHERE YEAR = 1980
  Gold: SELECT COUNT(*) FROM CARS_DATA WHERE YEAR = 1980
  Type: AGGREGATION

[93] WRONG_TABLE | DB: car_1 | EX: ✗
  Q   : In 1980, how many cars were made
  Pred: SELECT COUNT(*) FROM car_makers WHERE YEAR = 1980
  Gold: SELECT COUNT(*) FROM CARS_DATA WHERE YEAR = 1980
  Type: AGGREGATION

[94] OTHER | DB: car_1 | EX: ✗
  Q   : How many car models were produced by the maker with full name American Motor Company
  Pred: SELECT COUNT(*) FROM car_makers AS T1 JOIN model_list AS T2 ON T1.maker = T2.id WHERE T1.fullname = 'American Motor Company'
  Gold: SELECT COUNT(*) FROM CAR_MAKERS AS T1 JOIN MODEL_LIST AS T2 ON T1.Id = T2.Maker WHERE T1.FullName = 'American Motor Company'
  Type: JOIN, AGGREGATION

[95] OTHER | DB: car_1 | EX: ✗
  Q   : What is the number of car models created by the car maker American Motor Company
  Pred: SELECT COUNT(*) FROM car_makers AS T1 JOIN model_list AS T2 ON T1.id = T2.model WHERE T1.maker = "American Motor Company"
  Gold: SELECT COUNT(*) FROM CAR_MAKERS AS T1 JOIN MODEL_LIST AS T2 ON T1.Id = T2.Maker WHERE T1.FullName = 'American Motor Company'
  Type: JOIN, AGGREGATION

[96] WRONG_COLUMNS | DB: car_1 | EX: ✗
  Q   : Which makers designed more than 3 car models? List full name and the id
  Pred: SELECT T1.maker, T1.fullname, T1.id FROM car_makers AS T1 JOIN model_list AS T2 ON T1.maker = T2.id GROUP BY T1.maker HAVING COUNT(*) > 3
  Gold: SELECT T1.FullName, T1.Id FROM CAR_MAKERS AS T1 JOIN MODEL_LIST AS T2 ON T1.Id = T2.Maker GROUP BY T1.Id HAVING COUNT(*) > 3
  Type: JOIN, GROUP_BY, HAVING, AGGREGATION

[97] WRONG_COLUMNS | DB: car_1 | EX: ✗
  Q   : What are the names and ids of all makers with more than 3 models
  Pred: SELECT T1.maker, T1.id FROM car_makers AS T1 JOIN model_list AS T2 ON T1.id = T2.modelid GROUP BY T1.maker HAVING COUNT(*) > 3
  Gold: SELECT T1.FullName, T1.Id FROM CAR_MAKERS AS T1 JOIN MODEL_LIST AS T2 ON T1.Id = T2.Maker GROUP BY T1.Id HAVING COUNT(*) > 3
  Type: JOIN, GROUP_BY, HAVING, AGGREGATION

[98] WRONG_TABLE | DB: car_1 | EX: ✗
  Q   : Which distinctive models are produced by maker with the full name General Motors or weighing more than 3500
  Pred: SELECT DISTINCT T2.model FROM car_makers AS T1 JOIN model_list AS T2 ON T1.make = T2.makeid WHERE T1.fullname = "General Motors" OR T1.weight > 3500
  Gold: SELECT DISTINCT T2.Model FROM CAR_NAMES AS T1 JOIN MODEL_LIST AS T2 ON T1.Model = T2.Model JOIN CAR_MAKERS AS T3 ON T2.Maker = T3.Id JOIN CARS_DATA AS T4 ON T1.MakeId = T4.Id WHERE T3.FullName = 'General Motors' OR T4.weight > 3500
  Type: JOIN

[99] WRONG_TABLE | DB: car_1 | EX: ✗
  Q   : What are the different models created by either the car maker General Motors or weighed more than 3500
  Pred: SELECT DISTINCT T2.model FROM car_makers AS T1 JOIN model_list AS T2 ON T1.id = T2.model WHERE T1.maker = "General Motors" OR T1.weight > 3500
  Gold: SELECT DISTINCT T2.Model FROM CAR_NAMES AS T1 JOIN MODEL_LIST AS T2 ON T1.Model = T2.Model JOIN CAR_MAKERS AS T3 ON T2.Maker = T3.Id JOIN CARS_DATA AS T4 ON T1.MakeId = T4.Id WHERE T3.FullName = 'General Motors' OR T4.weight > 3500
  Type: JOIN

[100] WRONG_TABLE | DB: car_1 | EX: ✗
  Q   : In which years cars were produced weighing no less than 3000 and no more than 4000
  Pred: SELECT YEAR FROM car_makers WHERE weight  3000 INTERSECT SELECT YEAR FROM car_makers WHERE weight  4000
  Gold: SELECT DISTINCT year FROM cars_data WHERE weight BETWEEN 3000 AND 4000
  Type: SIMPLE

[101] WRONG_TABLE | DB: car_1 | EX: ✗
  Q   : What are the different years in which there were cars produced that weighed less than 4000 and also cars that weighted more than 3000
  Pred: SELECT DISTINCT YEAR FROM car_makers WHERE weight  4000 INTERSECT SELECT DISTINCT YEAR FROM car_makers WHERE weight > 3000
  Gold: SELECT DISTINCT year FROM cars_data WHERE weight BETWEEN 3000 AND 4000
  Type: SIMPLE

[102] WRONG_COLUMNS | DB: car_1 | EX: ✓
  Q   : What is the horsepower of the car with the largest accelerate
  Pred: SELECT horsepower FROM cars_data ORDER BY accelerate DESC LIMIT 1
  Gold: SELECT T1.horsepower FROM CARS_DATA AS T1 ORDER BY T1.accelerate DESC LIMIT 1
  Type: ORDER_BY, LIMIT

[103] WRONG_COLUMNS | DB: car_1 | EX: ✓
  Q   : What is the horsepower of the car with the greatest accelerate
  Pred: SELECT horsepower FROM cars_data ORDER BY accelerate DESC LIMIT 1
  Gold: SELECT T1.horsepower FROM CARS_DATA AS T1 ORDER BY T1.accelerate DESC LIMIT 1
  Type: ORDER_BY, LIMIT

[104] WRONG_TABLE | DB: car_1 | EX: ✗
  Q   : For model volvo, how many cylinders does the car with the least accelerate have
  Pred: SELECT COUNT(*), T1.model FROM car_names AS T1 JOIN model_list AS T2 ON T1.model = T2.model WHERE T1.make = "Volvo" GROUP BY T1.model ORDER BY SUM(T1.accelerated) LIMIT 1
  Gold: SELECT T1.cylinders FROM CARS_DATA AS T1 JOIN CAR_NAMES AS T2 ON T1.Id = T2.MakeId WHERE T2.Model = 'volvo' ORDER BY T1.accelerate ASC LIMIT 1
  Type: JOIN, ORDER_BY, LIMIT

[105] WRONG_TABLE | DB: car_1 | EX: ✗
  Q   : For a volvo model, how many cylinders does the version with least accelerate have
  Pred: SELECT t2.cylinders FROM model_list AS t1 JOIN car_names AS t2 ON t1.model = t2.model WHERE t2.make = "Volvo" ORDER BY t2.accurate LIMIT 1
  Gold: SELECT T1.cylinders FROM CARS_DATA AS T1 JOIN CAR_NAMES AS T2 ON T1.Id = T2.MakeId WHERE T2.Model = 'volvo' ORDER BY T1.accelerate ASC LIMIT 1
  Type: JOIN, ORDER_BY, LIMIT

[106] MISSING_ORDER_BY | DB: car_1 | EX: ✗
  Q   : How many cars have a larger accelerate than the car with the largest horsepower
  Pred: SELECT COUNT(*) FROM cars_data WHERE accelerate > (SELECT MAX(horsepower) FROM cars_data)
  Gold: SELECT COUNT(*) FROM CARS_DATA WHERE Accelerate > (SELECT Accelerate FROM CARS_DATA ORDER BY Horsepower DESC LIMIT 1)
  Type: ORDER_BY, LIMIT, NESTED, AGGREGATION

[107] MISSING_ORDER_BY | DB: car_1 | EX: ✗
  Q   : What is the number of cars with a greater accelerate than the one with the most horsepower
  Pred: SELECT COUNT(*) FROM cars_data WHERE accelerate > (SELECT MAX(horsepower) FROM cars_data)
  Gold: SELECT COUNT(*) FROM CARS_DATA WHERE Accelerate > (SELECT Accelerate FROM CARS_DATA ORDER BY Horsepower DESC LIMIT 1)
  Type: ORDER_BY, LIMIT, NESTED, AGGREGATION

[108] WRONG_TABLE | DB: car_1 | EX: ✗
  Q   : How many countries has more than 2 car makers
  Pred: SELECT COUNT(*) FROM countries WHERE countryID IN (SELECT countryID FROM car_makers GROUP BY countryID HAVING COUNT(*) > 2)
  Gold: SELECT COUNT(*) FROM countries AS t1 JOIN car_makers AS t2 ON t1.countryid = t2.country GROUP BY t1.countryid HAVING COUNT(*) > 2
  Type: JOIN, GROUP_BY, HAVING, AGGREGATION

[109] MISSING_JOIN | DB: car_1 | EX: ✗
  Q   : What is the number of countries with more than 2 car makers
  Pred: SELECT COUNT(*) FROM countries WHERE maker > 2
  Gold: SELECT COUNT(*) FROM countries AS t1 JOIN car_makers AS t2 ON t1.countryid = t2.country GROUP BY t1.countryid HAVING COUNT(*) > 2
  Type: JOIN, GROUP_BY, HAVING, AGGREGATION

[110] WRONG_TABLE | DB: car_1 | EX: ✗
  Q   : For the cars with 4 cylinders, which model has the largest horsepower
  Pred: SELECT t3.model FROM cars_data AS t1 JOIN model_list AS t2 ON t1.model = t2.model WHERE t1.cylinders = 4 AND horsepower = (SELECT MAX(horsepower) FROM car_names)
  Gold: SELECT T1.Model FROM CAR_NAMES AS T1 JOIN CARS_DATA AS T2 ON T1.MakeId = T2.Id WHERE T2.Cylinders = 4 ORDER BY T2.horsepower DESC LIMIT 1
  Type: JOIN, ORDER_BY, LIMIT

[111] MISSING_ORDER_BY | DB: car_1 | EX: ✗
  Q   : For all of the 4 cylinder cars, which model has the most horsepower
  Pred: SELECT t1.model FROM car_names AS t1 JOIN model_list AS t2 ON t1.model = t2.model WHERE t1.cylinders = 4 AND horsepower = (SELECT MAX(horsepower) FROM car_names)
  Gold: SELECT T1.Model FROM CAR_NAMES AS T1 JOIN CARS_DATA AS T2 ON T1.MakeId = T2.Id WHERE T2.Cylinders = 4 ORDER BY T2.horsepower DESC LIMIT 1
  Type: JOIN, ORDER_BY, LIMIT

[112] WRONG_TABLE | DB: car_1 | EX: ✗
  Q   : Among the cars with more than lowest horsepower, which ones do not have more than 3 cylinders? List the car makeid and make name
  Pred: SELECT T1.make, T1.make FROM car_names AS T1 JOIN cars_data AS T2 ON T1.id = T2.makeid WHERE T2.horsepower > 3 EXCEPT SELECT T1.make, T1.make FROM car_names AS T1 JOIN cars_data AS T2 ON T1.id = T2.makeid WHERE T2.horsepower > 3
  Gold: SELECT T2.MakeId, T2.Make FROM CARS_DATA AS T1 JOIN CAR_NAMES AS T2 ON T1.Id = T2.MakeId WHERE T1.Horsepower > (SELECT MIN(Horsepower) FROM CARS_DATA) AND T1.Cylinders <= 3
  Type: JOIN, NESTED, AGGREGATION

[113] WRONG_TABLE | DB: car_1 | EX: ✗
  Q   : Among the cars that do not have the minimum horsepower , what are the make ids and names of all those with less than 4 cylinders
  Pred: SELECT DISTINCT T1.make, T1.make FROM car_names AS T1 JOIN cars_data AS T2 ON T1.id = T2.makeid WHERE T2.horsepower  4
  Gold: SELECT t2.makeid, t2.make FROM cars_data AS t1 JOIN car_names AS t2 ON t1.id = t2.makeid WHERE t1.horsepower > (SELECT MIN(horsepower) FROM cars_data) AND t1.cylinders < 4
  Type: JOIN, NESTED, AGGREGATION

[114] OTHER | DB: car_1 | EX: ✗
  Q   : What is the maximum miles per gallon of the car with 8 cylinders or produced before 1980
  Pred: SELECT MAX(mpg) FROM cars_data WHERE cylinders = 8 OR YEAR  1980
  Gold: SELECT MAX(mpg) FROM cars_data WHERE cylinders = 8 OR year < 1980
  Type: AGGREGATION

[115] WRONG_COLUMNS | DB: car_1 | EX: ✗
  Q   : What is the maximum mpg of the cars that had 8 cylinders or that were produced before 1980
  Pred: SELECT MAX(mpg) FROM cars_data WHERE cylinders = 8 UNION SELECT MPG FROM cars_data WHERE YEAR  1980
  Gold: SELECT MAX(mpg) FROM cars_data WHERE cylinders = 8 OR year < 1980
  Type: AGGREGATION

[116] MISSING_JOIN | DB: car_1 | EX: ✗
  Q   : Which models are lighter than 3500 but not built by the 'Ford Motor Company'
  Pred: SELECT model FROM model_list WHERE weight  3500 EXCEPT SELECT model FROM model_list WHERE maker = 'Ford Motor Company'
  Gold: SELECT DISTINCT T1.model FROM MODEL_LIST AS T1 JOIN CAR_NAMES AS T2 ON T1.Model = T2.Model JOIN CARS_DATA AS T3 ON T2.MakeId = T3.Id JOIN CAR_MAKERS AS T4 ON T1.Maker = T4.Id WHERE T3.weight < 3500 AND T4.FullName <> 'Ford Motor Company'
  Type: JOIN

[117] WRONG_TABLE | DB: car_1 | EX: ✗
  Q   : What are the different models wthat are lighter than 3500 but were not built by the Ford Motor Company
  Pred: SELECT DISTINCT T2.model FROM car_names AS T1 JOIN model_list AS T2 ON T1.model = T2.model WHERE T1.weight  3500 EXCEPT SELECT DISTINCT T2.model FROM car_makers AS T1 JOIN model_list AS T2 ON T1.model = T2.model WHERE T1.maker = "Ford Motor Company"
  Gold: SELECT DISTINCT T1.model FROM MODEL_LIST AS T1 JOIN CAR_NAMES AS T2 ON T1.Model = T2.Model JOIN CARS_DATA AS T3 ON T2.MakeId = T3.Id JOIN CAR_MAKERS AS T4 ON T1.Maker = T4.Id WHERE T3.weight < 3500 AND T4.FullName <> 'Ford Motor Company'
  Type: JOIN

[118] OTHER | DB: car_1 | EX: ✗
  Q   : What are the name of the countries where there is not a single car maker
  Pred: SELECT countryname FROM countries EXCEPT SELECT T1.countryname FROM countries AS T1 JOIN car_makers AS T2 ON T1.country = T2.countryid
  Gold: SELECT CountryName FROM countries EXCEPT SELECT T1.CountryName FROM countries AS T1 JOIN CAR_MAKERS AS T2 ON T1.countryId = T2.Country
  Type: JOIN

[119] WRONG_TABLE | DB: car_1 | EX: ✗
  Q   : What are the names of the countries with no car makers
  Pred: SELECT countryname FROM countries WHERE NOT countryid IN (SELECT countryid FROM car_makers)
  Gold: SELECT CountryName FROM countries EXCEPT SELECT T1.CountryName FROM countries AS T1 JOIN CAR_MAKERS AS T2 ON T1.countryId = T2.Country
  Type: JOIN

[120] OTHER | DB: car_1 | EX: ✗
  Q   : Which are the car makers which produce at least 2 models and more than 3 car makers ? List the id and the maker
  Pred: SELECT T1.id, T1.maker FROM car_makers AS T1 JOIN model_list AS T2 ON T1.id = T2.model GROUP BY T1.id HAVING COUNT(*) >= 2 INTERSECT SELECT T1.id, T1.maker FROM car_makers AS T1 JOIN model_list AS T2 ON T1.id = T2.model GROUP BY T1.id HAVING COUNT(*) >= 3
  Gold: SELECT t1.id, t1.maker FROM car_makers AS t1 JOIN model_list AS t2 ON t1.id = t2.maker GROUP BY t1.id HAVING COUNT(*) >= 2 INTERSECT SELECT t1.id, t1.maker FROM car_makers AS t1 JOIN model_list AS t2 ON t1.id = t2.maker JOIN car_names AS t3 ON t2.model = t3.model GROUP BY t1.id HAVING COUNT(*) > 3
  Type: JOIN, GROUP_BY, HAVING, AGGREGATION

[121] OTHER | DB: car_1 | EX: ✗
  Q   : What are the ids and makers of all car makers that produce at least 2 models and make more than 3 cars
  Pred: SELECT T1.id, T1.maker FROM car_makers AS T1 JOIN model_list AS T2 ON T1.id = T2.model GROUP BY T1.maker HAVING COUNT(*) >= 2 INTERSECT SELECT T1.id, T1.maker FROM car_makers AS T1 JOIN model_list AS T2 ON T1.id = T2.model GROUP BY T1.maker HAVING COUNT(*) >= 3
  Gold: SELECT T1.Id, T1.Maker FROM CAR_MAKERS AS T1 JOIN MODEL_LIST AS T2 ON T1.Id = T2.Maker GROUP BY T1.Id HAVING COUNT(*) >= 2 INTERSECT SELECT T1.Id, T1.Maker FROM CAR_MAKERS AS T1 JOIN MODEL_LIST AS T2 ON T1.Id = T2.Maker JOIN CAR_NAMES AS T3 ON T2.model = T3.model GROUP BY T1.Id HAVING COUNT(*) > 3
  Type: JOIN, GROUP_BY, HAVING, AGGREGATION

[122] OTHER | DB: car_1 | EX: ✗
  Q   : What are the id and names of the countries which have more than 3 car makers or produce the 'fiat' model
  Pred: SELECT T1.countryid, T1.countryname FROM countries AS T1 JOIN car_makers AS T2 ON T1.country = T2.countryid WHERE T2.make = 'Fiat' GROUP BY T1.countryid HAVING COUNT(*) > 3 UNION SELECT T1.countryid, T1.countryname FROM countries AS T1 JOIN model_list AS T2 ON T1.country = T2.model WHERE T2.model = 'Fiat'
  Gold: SELECT T1.countryId, T1.CountryName FROM Countries AS T1 JOIN CAR_MAKERS AS T2 ON T1.CountryId = T2.Country GROUP BY T1.countryId HAVING COUNT(*) > 3 UNION SELECT T1.countryId, T1.CountryName FROM Countries AS T1 JOIN CAR_MAKERS AS T2 ON T1.CountryId = T2.Country JOIN MODEL_LIST AS T3 ON T2.Id = T3.Maker WHERE T3.Model = 'fiat'
  Type: JOIN, GROUP_BY, HAVING, AGGREGATION

[123] OTHER | DB: car_1 | EX: ✗
  Q   : What are the ids and names of all countries that either have more than 3 car makers or produce fiat model
  Pred: SELECT T1.countryid, T1.countryname FROM countries AS T1 JOIN car_makers AS T2 ON T1.country = T2.countryid GROUP BY T1.countryid HAVING COUNT(*) > 3 UNION SELECT T1.countryid, T1.countryname FROM countries AS T1 JOIN model_list AS T2 ON T1.country = T2.modelid WHERE T2.make = "Fiat"
  Gold: SELECT t1.countryid, t1.countryname FROM countries AS t1 JOIN car_makers AS t2 ON t1.countryid = t2.country GROUP BY t1.countryid HAVING COUNT(*) > 3 UNION SELECT t1.countryid, t1.countryname FROM countries AS t1 JOIN car_makers AS t2 ON t1.countryid = t2.country JOIN model_list AS t3 ON t2.id = t3.maker WHERE t3.model = 'fiat'
  Type: JOIN, GROUP_BY, HAVING, AGGREGATION

[124] OTHER | DB: flight_2 | EX: ✗
  Q   : Which abbreviation corresponds to Jetblue Airways
  Pred: SELECT abbreviation FROM airlines WHERE airline = 'Jitblue Airways'
  Gold: SELECT Abbreviation FROM AIRLINES WHERE Airline = "JetBlue Airways"
  Type: SIMPLE

[125] OTHER | DB: flight_2 | EX: ✓
  Q   : Which city and country is the Alton airport at
  Pred: SELECT city, country FROM airports WHERE airportname = 'Altons'
  Gold: SELECT City, Country FROM AIRPORTS WHERE AirportName = "Alton"
  Type: SIMPLE

[126] OTHER | DB: flight_2 | EX: ✗
  Q   : What is the airport name for airport 'AKO'
  Pred: SELECT airportname FROM airports WHERE airportname = 'AKO'
  Gold: SELECT AirportName FROM AIRPORTS WHERE AirportCode = "AKO"
  Type: SIMPLE

[127] OTHER | DB: flight_2 | EX: ✗
  Q   : How many flights depart from 'APG'
  Pred: SELECT COUNT(*) FROM flights WHERE abbreviation = 'APG'
  Gold: SELECT COUNT(*) FROM FLIGHTS WHERE SourceAirport = "APG"
  Type: AGGREGATION

[128] OTHER | DB: flight_2 | EX: ✗
  Q   : Count the number of flights departing from 'APG'
  Pred: SELECT COUNT(*) FROM flights WHERE abbreviation = 'APG'
  Gold: SELECT COUNT(*) FROM FLIGHTS WHERE SourceAirport = "APG"
  Type: AGGREGATION

[129] EXTRA_JOIN | DB: flight_2 | EX: ✗
  Q   : How many flights have destination ATO
  Pred: SELECT COUNT(*) FROM flights AS T1 JOIN airports AS T2 ON T1.airportcode = T2.sourceairport WHERE T2.country = "ATO"
  Gold: SELECT COUNT(*) FROM FLIGHTS WHERE DestAirport = "ATO"
  Type: AGGREGATION

[130] OTHER | DB: flight_2 | EX: ✗
  Q   : Count the number of flights into ATO
  Pred: SELECT COUNT(*) FROM flights WHERE airportcode = 'ATO'
  Gold: SELECT COUNT(*) FROM FLIGHTS WHERE DestAirport = "ATO"
  Type: AGGREGATION

[131] WRONG_TABLE | DB: flight_2 | EX: ✓
  Q   : How many flights depart from City Aberdeen
  Pred: SELECT COUNT(*) FROM airports WHERE city = "Aberdeen"
  Gold: SELECT COUNT(*) FROM FLIGHTS AS T1 JOIN AIRPORTS AS T2 ON T1.SourceAirport = T2.AirportCode WHERE T2.City = "Aberdeen"
  Type: JOIN, AGGREGATION

[132] MISSING_JOIN | DB: flight_2 | EX: ✗
  Q   : Return the number of flights departing from Aberdeen
  Pred: SELECT COUNT(*) FROM flights WHERE airports = "Aberdeen"
  Gold: SELECT COUNT(*) FROM FLIGHTS AS T1 JOIN AIRPORTS AS T2 ON T1.SourceAirport = T2.AirportCode WHERE T2.City = "Aberdeen"
  Type: JOIN, AGGREGATION

[133] WRONG_TABLE | DB: flight_2 | EX: ✓
  Q   : How many flights arriving in Aberdeen city
  Pred: SELECT COUNT(*) FROM airports WHERE city = 'Aberdeen'
  Gold: SELECT COUNT(*) FROM FLIGHTS AS T1 JOIN AIRPORTS AS T2 ON T1.DestAirport = T2.AirportCode WHERE T2.City = "Aberdeen"
  Type: JOIN, AGGREGATION

[134] WRONG_TABLE | DB: flight_2 | EX: ✗
  Q   : Return the number of flights arriving in Aberdeen
  Pred: SELECT COUNT(*) FROM airports AS T1 JOIN flights AS T2 ON T1.airport = T2.sourceairport WHERE T1.city = "Aberdeen"
  Gold: SELECT COUNT(*) FROM FLIGHTS AS T1 JOIN AIRPORTS AS T2 ON T1.DestAirport = T2.AirportCode WHERE T2.City = "Aberdeen"
  Type: JOIN, AGGREGATION

[135] OTHER | DB: flight_2 | EX: ✗
  Q   : How many flights depart from City 'Aberdeen' and have destination City 'Ashley'
  Pred: SELECT COUNT(*) FROM flights AS T1 JOIN airports AS T2 ON T1.airport = T2.sourceairport WHERE T2.city = 'Aberdeen' AND T2.airportcode = 'Ashley'
  Gold: SELECT COUNT(*) FROM FLIGHTS AS T1 JOIN AIRPORTS AS T2 ON T1.DestAirport = T2.AirportCode JOIN AIRPORTS AS T3 ON T1.SourceAirport = T3.AirportCode WHERE T2.City = "Ashley" AND T3.City = "Aberdeen"
  Type: JOIN, AGGREGATION

[136] WRONG_TABLE | DB: flight_2 | EX: ✗
  Q   : How many flights fly from Aberdeen to Ashley
  Pred: SELECT COUNT(*) FROM airports AS T1 JOIN flights AS T2 ON T1.airport = T2.sourceairport WHERE T1.airportcode = "Ashley" AND T1.city = "Aberdeen"
  Gold: SELECT COUNT(*) FROM FLIGHTS AS T1 JOIN AIRPORTS AS T2 ON T1.DestAirport = T2.AirportCode JOIN AIRPORTS AS T3 ON T1.SourceAirport = T3.AirportCode WHERE T2.City = "Ashley" AND T3.City = "Aberdeen"
  Type: JOIN, AGGREGATION

[137] WRONG_TABLE | DB: flight_2 | EX: ✗
  Q   : How many flights does airline 'JetBlue Airways' have
  Pred: SELECT COUNT(*) FROM airlines AS T1 JOIN flights AS T2 ON T1.uid = T2.sourceairport WHERE T1.airline = 'JetBlue Airways'
  Gold: SELECT COUNT(*) FROM FLIGHTS AS T1 JOIN AIRLINES AS T2 ON T1.Airline = T2.uid WHERE T2.Airline = "JetBlue Airways"
  Type: JOIN, AGGREGATION

[138] WRONG_TABLE | DB: flight_2 | EX: ✗
  Q   : Give the number of Jetblue Airways flights
  Pred: SELECT COUNT(*) FROM airlines AS T1 JOIN flights AS T2 ON T1.uid = T2.sourceairport WHERE T1.abbreviation = "Jitblue Airways"
  Gold: SELECT COUNT(*) FROM FLIGHTS AS T1 JOIN AIRLINES AS T2 ON T1.Airline = T2.uid WHERE T2.Airline = "JetBlue Airways"
  Type: JOIN, AGGREGATION

[139] OTHER | DB: flight_2 | EX: ✗
  Q   : How many 'United Airlines' flights go to Airport 'ASY'
  Pred: SELECT COUNT(*) FROM airlines AS T1 JOIN flights AS T2 ON T1.uid = T2.unitedairport WHERE T1.airportname = 'ASY'
  Gold: SELECT COUNT(*) FROM AIRLINES AS T1 JOIN FLIGHTS AS T2 ON T2.Airline = T1.uid WHERE T1.Airline = "United Airlines" AND T2.DestAirport = "ASY"
  Type: JOIN, AGGREGATION

[140] WRONG_TABLE | DB: flight_2 | EX: ✗
  Q   : Count the number of United Airlines flights arriving in ASY Airport
  Pred: SELECT COUNT(*) FROM airports AS T1 JOIN flights AS T2 ON T1.airport = T2.sourceairport WHERE T1.airportname = "ASY" AND T2.abbreviation = "United Airlines"
  Gold: SELECT COUNT(*) FROM AIRLINES AS T1 JOIN FLIGHTS AS T2 ON T2.Airline = T1.uid WHERE T1.Airline = "United Airlines" AND T2.DestAirport = "ASY"
  Type: JOIN, AGGREGATION

[141] WRONG_TABLE | DB: flight_2 | EX: ✗
  Q   : How many 'United Airlines' flights depart from Airport 'AHD'
  Pred: SELECT COUNT(*) FROM flights AS T1 JOIN airports AS T2 ON T1.airport = T2.sourceairport WHERE T2.airportcode = 'AHD' AND T1.uid = 'United Airlines'
  Gold: SELECT COUNT(*) FROM AIRLINES AS T1 JOIN FLIGHTS AS T2 ON T2.Airline = T1.uid WHERE T1.Airline = "United Airlines" AND T2.SourceAirport = "AHD"
  Type: JOIN, AGGREGATION

[142] WRONG_TABLE | DB: flight_2 | EX: ✗
  Q   : Return the number of United Airlines flights leaving from AHD Airport
  Pred: SELECT COUNT(*) FROM flights AS T1 JOIN airports AS T2 ON T1.airport = T2.airportcode JOIN airlines AS T3 ON T1.uid = T3.uid WHERE T2.airportname = 'AHD Airport' AND T3.airportname = 'United Airlines'
  Gold: SELECT COUNT(*) FROM AIRLINES AS T1 JOIN FLIGHTS AS T2 ON T2.Airline = T1.uid WHERE T1.Airline = "United Airlines" AND T2.SourceAirport = "AHD"
  Type: JOIN, AGGREGATION

[143] WRONG_TABLE | DB: flight_2 | EX: ✗
  Q   : How many United Airlines flights go to City 'Aberdeen'
  Pred: SELECT COUNT(*) FROM airlines AS T1 JOIN flights AS T2 ON T1.uid = T2.united airlines WHERE T1.city = 'Aberdeen'
  Gold: SELECT COUNT(*) FROM FLIGHTS AS T1 JOIN AIRPORTS AS T2 ON T1.DestAirport = T2.AirportCode JOIN AIRLINES AS T3 ON T3.uid = T1.Airline WHERE T2.City = "Aberdeen" AND T3.Airline = "United Airlines"
  Type: JOIN, AGGREGATION

[144] OTHER | DB: flight_2 | EX: ✗
  Q   : Count the number of United Airlines flights that arrive in Aberdeen
  Pred: SELECT COUNT(*) FROM flights AS T1 JOIN airports AS T2 ON T1.airport = T2.sourceairport WHERE T2.airportcode = "Aberdeen" AND T1.uid = "United Airlines"
  Gold: SELECT COUNT(*) FROM FLIGHTS AS T1 JOIN AIRPORTS AS T2 ON T1.DestAirport = T2.AirportCode JOIN AIRLINES AS T3 ON T3.uid = T1.Airline WHERE T2.City = "Aberdeen" AND T3.Airline = "United Airlines"
  Type: JOIN, AGGREGATION

[145] WRONG_TABLE | DB: flight_2 | EX: ✗
  Q   : Which city has most number of arriving flights
  Pred: SELECT city FROM flights GROUP BY city ORDER BY COUNT(*) DESC LIMIT 1
  Gold: SELECT T1.City FROM AIRPORTS AS T1 JOIN FLIGHTS AS T2 ON T1.AirportCode = T2.DestAirport GROUP BY T1.City ORDER BY COUNT(*) DESC LIMIT 1
  Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, AGGREGATION

[146] MISSING_JOIN | DB: flight_2 | EX: ✗
  Q   : Which city has the most frequent destination airport
  Pred: SELECT city FROM airports ORDER BY airportname DESC LIMIT 1
  Gold: SELECT T1.City FROM AIRPORTS AS T1 JOIN FLIGHTS AS T2 ON T1.AirportCode = T2.DestAirport GROUP BY T1.City ORDER BY COUNT(*) DESC LIMIT 1
  Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, AGGREGATION

[147] WRONG_TABLE | DB: flight_2 | EX: ✓
  Q   : Which city has most number of departing flights
  Pred: SELECT T1.city FROM airports AS T1 JOIN flights AS T2 ON T1.airportcode = T2.sourceairport WHERE T2.flightno = (SELECT MAX(flightno) FROM flights)
  Gold: SELECT T1.City FROM AIRPORTS AS T1 JOIN FLIGHTS AS T2 ON T1.AirportCode = T2.SourceAirport GROUP BY T1.City ORDER BY COUNT(*) DESC LIMIT 1
  Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, AGGREGATION

[148] OTHER | DB: flight_2 | EX: ✗
  Q   : Which city is the most frequent source airport
  Pred: SELECT T1.city FROM airports AS T1 JOIN flights AS T2 ON T1.airport = T2.sourceairport GROUP BY T2.city ORDER BY COUNT(*) DESC LIMIT 1
  Gold: SELECT T1.City FROM AIRPORTS AS T1 JOIN FLIGHTS AS T2 ON T1.AirportCode = T2.SourceAirport GROUP BY T1.City ORDER BY COUNT(*) DESC LIMIT 1
  Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, AGGREGATION

[149] MISSING_JOIN | DB: flight_2 | EX: ✗
  Q   : What is the code of airport that has the highest number of flights
  Pred: SELECT airportcode FROM airports GROUP BY airportcode ORDER BY COUNT(*) DESC LIMIT 1
  Gold: SELECT T1.AirportCode FROM AIRPORTS AS T1 JOIN FLIGHTS AS T2 ON T1.AirportCode = T2.DestAirport OR T1.AirportCode = T2.SourceAirport GROUP BY T1.AirportCode ORDER BY COUNT(*) DESC LIMIT 1
  Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, AGGREGATION

[150] MISSING_JOIN | DB: flight_2 | EX: ✗
  Q   : What is the airport code of the airport with the most flights
  Pred: SELECT airportcode FROM airports GROUP BY airportcode ORDER BY COUNT(*) DESC LIMIT 1
  Gold: SELECT T1.AirportCode FROM AIRPORTS AS T1 JOIN FLIGHTS AS T2 ON T1.AirportCode = T2.DestAirport OR T1.AirportCode = T2.SourceAirport GROUP BY T1.AirportCode ORDER BY COUNT(*) DESC LIMIT 1
  Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, AGGREGATION

[151] MISSING_JOIN | DB: flight_2 | EX: ✗
  Q   : What is the code of airport that has fewest number of flights
  Pred: SELECT airportcode FROM airports ORDER BY flightno ASC LIMIT 1
  Gold: SELECT T1.AirportCode FROM AIRPORTS AS T1 JOIN FLIGHTS AS T2 ON T1.AirportCode = T2.DestAirport OR T1.AirportCode = T2.SourceAirport GROUP BY T1.AirportCode ORDER BY COUNT(*) LIMIT 1
  Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, AGGREGATION

[152] MISSING_JOIN | DB: flight_2 | EX: ✗
  Q   : Give the code of the airport with the least flights
  Pred: SELECT airportcode FROM airports GROUP BY airportcode ORDER BY COUNT(*) LIMIT 1
  Gold: SELECT T1.AirportCode FROM AIRPORTS AS T1 JOIN FLIGHTS AS T2 ON T1.AirportCode = T2.DestAirport OR T1.AirportCode = T2.SourceAirport GROUP BY T1.AirportCode ORDER BY COUNT(*) LIMIT 1
  Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, AGGREGATION

[153] OTHER | DB: flight_2 | EX: ✗
  Q   : Which airline has most number of flights
  Pred: SELECT T1.Airline FROM airlines AS T1 JOIN flights AS T2 ON T1.Airline = T2.Airline GROUP BY T1.Airline ORDER BY COUNT(*) DESC LIMIT 1
  Gold: SELECT T1.Airline FROM AIRLINES AS T1 JOIN FLIGHTS AS T2 ON T1.uid = T2.Airline GROUP BY T1.Airline ORDER BY COUNT(*) DESC LIMIT 1
  Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, AGGREGATION

[154] OTHER | DB: flight_2 | EX: ✗
  Q   : What airline serves the most flights
  Pred: SELECT T1.Airline FROM airlines AS T1 JOIN flights AS T2 ON T1.Airline = T2.Airline GROUP BY T1.Airline ORDER BY COUNT(*) DESC LIMIT 1
  Gold: SELECT T1.Airline FROM AIRLINES AS T1 JOIN FLIGHTS AS T2 ON T1.uid = T2.Airline GROUP BY T1.Airline ORDER BY COUNT(*) DESC LIMIT 1
  Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, AGGREGATION

[155] MISSING_JOIN | DB: flight_2 | EX: ✓
  Q   : Find the abbreviation and country of the airline that has fewest number of flights
  Pred: SELECT abbreviation, country FROM airlines GROUP BY abbreviation ORDER BY COUNT(*) LIMIT 1
  Gold: SELECT T1.Abbreviation, T1.Country FROM AIRLINES AS T1 JOIN FLIGHTS AS T2 ON T1.uid = T2.Airline GROUP BY T1.Airline ORDER BY COUNT(*) LIMIT 1
  Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, AGGREGATION

[156] WRONG_TABLE | DB: flight_2 | EX: ✗
  Q   : What is the abbreviation of the airilne has the fewest flights and what country is it in
  Pred: SELECT abbreviation, country FROM flights GROUP BY abbreviation ORDER BY COUNT(*) ASC LIMIT 1
  Gold: SELECT T1.Abbreviation, T1.Country FROM AIRLINES AS T1 JOIN FLIGHTS AS T2 ON T1.uid = T2.Airline GROUP BY T1.Airline ORDER BY COUNT(*) LIMIT 1
  Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, AGGREGATION

[157] OTHER | DB: flight_2 | EX: ✗
  Q   : What are airlines that have some flight departing from airport 'AHD'
  Pred: SELECT T1.airline FROM airlines AS T1 JOIN flights AS T2 ON T1.uid = T2.flightno WHERE T2.airportname = 'AHD'
  Gold: SELECT T1.Airline FROM AIRLINES AS T1 JOIN FLIGHTS AS T2 ON T1.uid = T2.Airline WHERE T2.SourceAirport = "AHD"
  Type: JOIN

[158] OTHER | DB: flight_2 | EX: ✓
  Q   : Which airlines have a flight with source airport AHD
  Pred: SELECT T1.airline FROM airlines AS T1 JOIN flights AS T2 ON T1.uid = T2.flightno WHERE T2.sourceairport = 'AHD'
  Gold: SELECT T1.Airline FROM AIRLINES AS T1 JOIN FLIGHTS AS T2 ON T1.uid = T2.Airline WHERE T2.SourceAirport = "AHD"
  Type: JOIN

[159] OTHER | DB: flight_2 | EX: ✗
  Q   : What are airlines that have flights arriving at airport 'AHD'
  Pred: SELECT T1.airline FROM airlines AS T1 JOIN flights AS T2 ON T1.uid = T2.flightno JOIN airports AS T3 ON T2.airportcode = T3.airportcode WHERE T3.airportname = 'AHD'
  Gold: SELECT T1.Airline FROM AIRLINES AS T1 JOIN FLIGHTS AS T2 ON T1.uid = T2.Airline WHERE T2.DestAirport = "AHD"
  Type: JOIN

[160] OTHER | DB: flight_2 | EX: ✓
  Q   : Which airlines have a flight with destination airport AHD
  Pred: SELECT T1.airline FROM airlines AS T1 JOIN flights AS T2 ON T1.uid = T2.flightno JOIN airports AS T3 ON T2.sourceairport = T3.airportcode WHERE T3.airportname = 'AHD'
  Gold: SELECT T1.Airline FROM AIRLINES AS T1 JOIN FLIGHTS AS T2 ON T1.uid = T2.Airline WHERE T2.DestAirport = "AHD"
  Type: JOIN

[161] OTHER | DB: flight_2 | EX: ✗
  Q   : Find all airlines that have flights from both airports 'APG' and 'CVO'
  Pred: SELECT T1.airline FROM airlines AS T1 JOIN flights AS T2 ON T1.uid = T2.flightno WHERE T2.airportname = 'APG' INTERSECT SELECT T1.airline FROM airlines AS T1 JOIN airports AS T2 ON T1.airportcode = T2.airportcode WHERE T2.airportname = 'CVO'
  Gold: SELECT T1.Airline FROM AIRLINES AS T1 JOIN FLIGHTS AS T2 ON T1.uid = T2.Airline WHERE T2.SourceAirport = "APG" INTERSECT SELECT T1.Airline FROM AIRLINES AS T1 JOIN FLIGHTS AS T2 ON T1.uid = T2.Airline WHERE T2.SourceAirport = "CVO"
  Type: JOIN

[162] OTHER | DB: flight_2 | EX: ✗
  Q   : Which airlines have departing flights from both APG and CVO airports
  Pred: SELECT T1.airline FROM airlines AS T1 JOIN flights AS T2 ON T1.uid = T2.flightno WHERE T2.airportcode = 'APG' INTERSECT SELECT T1.airline FROM airlines AS T1 JOIN airports AS T2 ON T1.airport = T2.airportcode WHERE T2.airportname = 'CVO'
  Gold: SELECT T1.Airline FROM AIRLINES AS T1 JOIN FLIGHTS AS T2 ON T1.uid = T2.Airline WHERE T2.SourceAirport = "APG" INTERSECT SELECT T1.Airline FROM AIRLINES AS T1 JOIN FLIGHTS AS T2 ON T1.uid = T2.Airline WHERE T2.SourceAirport = "CVO"
  Type: JOIN

[163] OTHER | DB: flight_2 | EX: ✗
  Q   : Find all airlines that have flights from airport 'CVO' but not from 'APG'
  Pred: SELECT T1.airline FROM airlines AS T1 JOIN flights AS T2 ON T1.uid = T2.flightno WHERE T2.airportcode = 'CVO' EXCEPT SELECT T1.airline FROM airlines AS T1 JOIN airports AS T2 ON T1.airportcode = T2.sourceairport WHERE T2.airportname = 'APG'
  Gold: SELECT T1.Airline FROM AIRLINES AS T1 JOIN FLIGHTS AS T2 ON T1.uid = T2.Airline WHERE T2.SourceAirport = "CVO" EXCEPT SELECT T1.Airline FROM AIRLINES AS T1 JOIN FLIGHTS AS T2 ON T1.uid = T2.Airline WHERE T2.SourceAirport = "APG"
  Type: JOIN

[164] OTHER | DB: flight_2 | EX: ✗
  Q   : Which airlines have departures from CVO but not from APG airports
  Pred: SELECT T1.airline FROM airlines AS T1 JOIN airports AS T2 ON T1.uid = T2.sourceairport WHERE T2.airportcode = "CVO" EXCEPT SELECT T1.airline FROM airlines AS T1 JOIN airports AS T2 ON T1.uid = T2.sourceairport WHERE T2.airportcode = "APG"
  Gold: SELECT T1.Airline FROM AIRLINES AS T1 JOIN FLIGHTS AS T2 ON T1.uid = T2.Airline WHERE T2.SourceAirport = "CVO" EXCEPT SELECT T1.Airline FROM AIRLINES AS T1 JOIN FLIGHTS AS T2 ON T1.uid = T2.Airline WHERE T2.SourceAirport = "APG"
  Type: JOIN

[165] OTHER | DB: flight_2 | EX: ✗
  Q   : Find all airlines that have at least 10 flights
  Pred: SELECT T1.Airline FROM airlines AS T1 JOIN flights AS T2 ON T1.UID = T2.FlightNo GROUP BY T1.Airline HAVING COUNT(*) >= 10
  Gold: SELECT T1.Airline FROM AIRLINES AS T1 JOIN FLIGHTS AS T2 ON T1.uid = T2.Airline GROUP BY T1.Airline HAVING COUNT(*) > 10
  Type: JOIN, GROUP_BY, HAVING, AGGREGATION

[166] OTHER | DB: flight_2 | EX: ✗
  Q   : Which airlines have at least 10 flights
  Pred: SELECT T1.Airline FROM airlines AS T1 JOIN flights AS T2 ON T1.UID = T2.FlightNo GROUP BY T1.Airline HAVING COUNT(*) >= 10
  Gold: SELECT T1.Airline FROM AIRLINES AS T1 JOIN FLIGHTS AS T2 ON T1.uid = T2.Airline GROUP BY T1.Airline HAVING COUNT(*) > 10
  Type: JOIN, GROUP_BY, HAVING, AGGREGATION

[167] WRONG_TABLE | DB: flight_2 | EX: ✗
  Q   : Find all airlines that have fewer than 200 flights
  Pred: SELECT airline FROM flights GROUP BY airline HAVING COUNT(*)  200
  Gold: SELECT T1.Airline FROM AIRLINES AS T1 JOIN FLIGHTS AS T2 ON T1.uid = T2.Airline GROUP BY T1.Airline HAVING COUNT(*) < 200
  Type: JOIN, GROUP_BY, HAVING, AGGREGATION

[168] WRONG_TABLE | DB: flight_2 | EX: ✗
  Q   : Which airlines have less than 200 flights
  Pred: SELECT airline FROM flights GROUP BY airline HAVING COUNT(*)  200
  Gold: SELECT T1.Airline FROM AIRLINES AS T1 JOIN FLIGHTS AS T2 ON T1.uid = T2.Airline GROUP BY T1.Airline HAVING COUNT(*) < 200
  Type: JOIN, GROUP_BY, HAVING, AGGREGATION

[169] OTHER | DB: flight_2 | EX: ✗
  Q   : What are flight numbers of Airline "United Airlines"
  Pred: SELECT T1.flightno FROM flights AS T1 JOIN airlines AS T2 ON T1.uid = T2.airline WHERE T2.name = "United Airlines"
  Gold: SELECT T1.FlightNo FROM FLIGHTS AS T1 JOIN AIRLINES AS T2 ON T2.uid = T1.Airline WHERE T2.Airline = "United Airlines"
  Type: JOIN

[170] OTHER | DB: flight_2 | EX: ✗
  Q   : Which flight numbers correspond to United Airlines flights
  Pred: SELECT T1.flightno FROM flights AS T1 JOIN airlines AS T2 ON T1.uid = T2.airline WHERE T2.name = 'United Airlines'
  Gold: SELECT T1.FlightNo FROM FLIGHTS AS T1 JOIN AIRLINES AS T2 ON T2.uid = T1.Airline WHERE T2.Airline = "United Airlines"
  Type: JOIN

[171] EXTRA_JOIN | DB: flight_2 | EX: ✗
  Q   : What are flight numbers of flights departing from Airport "APG"
  Pred: SELECT T1.FlightNo FROM flights AS T1 JOIN airports AS T2 ON T1.Airport = T2.AirportCode WHERE T2.AirportName = "APG"
  Gold: SELECT FlightNo FROM FLIGHTS WHERE SourceAirport = "APG"
  Type: SIMPLE

[172] EXTRA_JOIN | DB: flight_2 | EX: ✗
  Q   : What are flight numbers of flights arriving at Airport "APG"
  Pred: SELECT T1.flightno FROM flights AS T1 JOIN airports AS T2 ON T1.airport = T2.airportcode WHERE T2.airportname = "APG"
  Gold: SELECT FlightNo FROM FLIGHTS WHERE DestAirport = "APG"
  Type: SIMPLE

[173] EXTRA_JOIN | DB: flight_2 | EX: ✗
  Q   : Give the flight numbers of flights landing at APG
  Pred: SELECT T1.FlightNo FROM flights AS T1 JOIN airports AS T2 ON T1.Airport = T2.AirportCode WHERE T2.AirportName = "APG"
  Gold: SELECT FlightNo FROM FLIGHTS WHERE DestAirport = "APG"
  Type: SIMPLE

[174] OTHER | DB: flight_2 | EX: ✗
  Q   : Give the flight numbers of flights leaving from Aberdeen
  Pred: SELECT T1.FlightNo FROM flights AS T1 JOIN airports AS T2 ON T1.Airport = T2.AirportCode WHERE T2.AirportName = "Aberdeen"
  Gold: SELECT T1.FlightNo FROM FLIGHTS AS T1 JOIN AIRPORTS AS T2 ON T1.SourceAirport = T2.AirportCode WHERE T2.City = "Aberdeen"
  Type: JOIN

[175] OTHER | DB: flight_2 | EX: ✗
  Q   : What are flight numbers of flights arriving at City "Aberdeen"
  Pred: SELECT T1.flightno FROM flights AS T1 JOIN airports AS T2 ON T1.airport = T2.airportcode WHERE T2.city = "Aberdeen"
  Gold: SELECT T1.FlightNo FROM FLIGHTS AS T1 JOIN AIRPORTS AS T2 ON T1.DestAirport = T2.AirportCode WHERE T2.City = "Aberdeen"
  Type: JOIN

[176] OTHER | DB: flight_2 | EX: ✗
  Q   : Give the flight numbers of flights arriving in Aberdeen
  Pred: SELECT T1.FlightNo FROM flights AS T1 JOIN airports AS T2 ON T1.Airport = T2.AirportCode WHERE T2.AirportName = "Aberdeen"
  Gold: SELECT T1.FlightNo FROM FLIGHTS AS T1 JOIN AIRPORTS AS T2 ON T1.DestAirport = T2.AirportCode WHERE T2.City = "Aberdeen"
  Type: JOIN

[177] WRONG_TABLE | DB: flight_2 | EX: ✗
  Q   : Find the number of flights landing in the city of Aberdeen or Abilene
  Pred: SELECT COUNT(*) FROM airports AS T1 JOIN flights AS T2 ON T1.airport = T2.sourceairport WHERE T1.city = "Aberdeen" OR T1.airportcode = "Abilene"
  Gold: SELECT COUNT(*) FROM Flights AS T1 JOIN Airports AS T2 ON T1.DestAirport = T2.AirportCode WHERE T2.city = "Aberdeen" OR T2.city = "Abilene"
  Type: JOIN, AGGREGATION

[178] WRONG_TABLE | DB: flight_2 | EX: ✗
  Q   : How many flights land in Aberdeen or Abilene
  Pred: SELECT COUNT(*) FROM airports AS T1 JOIN flights AS T2 ON T1.airport = T2.sourceairport WHERE T1.city = "Aberdeen" OR T1.airportcode = "Abilene"
  Gold: SELECT COUNT(*) FROM Flights AS T1 JOIN Airports AS T2 ON T1.DestAirport = T2.AirportCode WHERE T2.city = "Aberdeen" OR T2.city = "Abilene"
  Type: JOIN, AGGREGATION

[179] WRONG_COLUMNS | DB: flight_2 | EX: ✗
  Q   : Find the name of airports which do not have any flight in and out
  Pred: SELECT airportname FROM airports WHERE NOT airportcode IN (SELECT airportcode FROM flights)
  Gold: SELECT AirportName FROM Airports WHERE NOT AirportCode IN (SELECT SourceAirport FROM Flights UNION SELECT DestAirport FROM Flights)
  Type: NESTED

[180] WRONG_COLUMNS | DB: flight_2 | EX: ✗
  Q   : Which airports do not have departing or arriving flights
  Pred: SELECT airportname FROM airports WHERE NOT airportcode IN (SELECT airportcode FROM flights WHERE flightno > 0) OR flightno > 0
  Gold: SELECT AirportName FROM Airports WHERE NOT AirportCode IN (SELECT SourceAirport FROM Flights UNION SELECT DestAirport FROM Flights)
  Type: NESTED

[181] OTHER | DB: employee_hire_evaluation | EX: ✓
  Q   : Sort employee names by their age in ascending order
  Pred: SELECT Name FROM employee ORDER BY Age ASC
  Gold: SELECT name FROM employee ORDER BY age
  Type: ORDER_BY

[182] OTHER | DB: employee_hire_evaluation | EX: ✓
  Q   : List the names of employees and sort in ascending order of age
  Pred: SELECT Name FROM employee ORDER BY Age ASC
  Gold: SELECT name FROM employee ORDER BY age
  Type: ORDER_BY

[183] WRONG_COLUMNS | DB: employee_hire_evaluation | EX: ✗
  Q   : What is the number of employees from each city
  Pred: SELECT City, COUNT(*) FROM employee GROUP BY City
  Gold: SELECT COUNT(*), city FROM employee GROUP BY city
  Type: GROUP_BY, AGGREGATION

[184] OTHER | DB: employee_hire_evaluation | EX: ✗
  Q   : Which cities do more than one employee under age 30 come from
  Pred: SELECT city FROM employee WHERE age  30 GROUP BY city HAVING COUNT(*) > 1
  Gold: SELECT city FROM employee WHERE age < 30 GROUP BY city HAVING COUNT(*) > 1
  Type: GROUP_BY, HAVING, AGGREGATION

[185] OTHER | DB: employee_hire_evaluation | EX: ✗
  Q   : Find the cities that have more than one employee under age 30
  Pred: SELECT city FROM employee WHERE age  30 GROUP BY city HAVING COUNT(*) > 1
  Gold: SELECT city FROM employee WHERE age < 30 GROUP BY city HAVING COUNT(*) > 1
  Type: GROUP_BY, HAVING, AGGREGATION

[186] WRONG_COLUMNS | DB: employee_hire_evaluation | EX: ✗
  Q   : Find the number of shops in each location
  Pred: SELECT LOCATION, COUNT(*) FROM shop GROUP BY LOCATION
  Gold: SELECT COUNT(*), LOCATION FROM shop GROUP BY LOCATION
  Type: GROUP_BY, AGGREGATION

[187] WRONG_COLUMNS | DB: employee_hire_evaluation | EX: ✗
  Q   : How many shops are there in each location
  Pred: SELECT LOCATION, COUNT(*) FROM shop GROUP BY LOCATION
  Gold: SELECT COUNT(*), LOCATION FROM shop GROUP BY LOCATION
  Type: GROUP_BY, AGGREGATION

[188] EXTRA_JOIN | DB: employee_hire_evaluation | EX: ✗
  Q   : Find the manager name and district of the shop whose number of products is the largest
  Pred: SELECT T2.manager_name, T2.District FROM shop AS T1 JOIN employee AS T2 ON T1.Shop_ID = T2.Shop_ID ORDER BY T1.Number_Products DESC LIMIT 1
  Gold: SELECT manager_name, district FROM shop ORDER BY number_products DESC LIMIT 1
  Type: ORDER_BY, LIMIT

[189] EXTRA_JOIN | DB: employee_hire_evaluation | EX: ✗
  Q   : What are the manager name and district of the shop that sells the largest number of products
  Pred: SELECT T2.manager_name, T2.District FROM shop AS T1 JOIN employee AS T2 ON T1.Shop_ID = T2.Shop_ID ORDER BY T1.Number_Products DESC LIMIT 1
  Gold: SELECT manager_name, district FROM shop ORDER BY number_products DESC LIMIT 1
  Type: ORDER_BY, LIMIT

[190] WRONG_TABLE | DB: employee_hire_evaluation | EX: ✗
  Q   : Which employee received the most awards in evaluations? Give me the employee name
  Pred: SELECT T1.name FROM employee AS T1 JOIN evaluation AS T2 ON T1.employee_id = T2.employee_id WHERE T2.year_awarded = (SELECT MAX(year_awarded) FROM evaluation)
  Gold: SELECT t1.name FROM employee AS t1 JOIN evaluation AS t2 ON t1.Employee_ID = t2.Employee_ID GROUP BY t2.Employee_ID ORDER BY COUNT(*) DESC LIMIT 1
  Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, AGGREGATION

[191] WRONG_TABLE | DB: employee_hire_evaluation | EX: ✓
  Q   : Find the name of the employee who got the highest one time bonus
  Pred: SELECT T1.name FROM employee AS T1 JOIN evaluation AS T2 ON T1.employee_id = T2.employee_id WHERE T2.bonus = (SELECT MAX(bonus) FROM evaluation)
  Gold: SELECT t1.name FROM employee AS t1 JOIN evaluation AS t2 ON t1.Employee_ID = t2.Employee_ID ORDER BY t2.bonus DESC LIMIT 1
  Type: JOIN, ORDER_BY, LIMIT

[192] WRONG_TABLE | DB: employee_hire_evaluation | EX: ✓
  Q   : Which employee received the biggest bonus? Give me the employee name
  Pred: SELECT T1.name FROM employee AS T1 JOIN evaluation AS T2 ON T1.employee_id = T2.employee_id WHERE T2.bonus = (SELECT MAX(bonus) FROM evaluation)
  Gold: SELECT t1.name FROM employee AS t1 JOIN evaluation AS t2 ON t1.Employee_ID = t2.Employee_ID ORDER BY t2.bonus DESC LIMIT 1
  Type: JOIN, ORDER_BY, LIMIT

[193] WRONG_TABLE | DB: employee_hire_evaluation | EX: ✗
  Q   : Which shop has the most employees? Give me the shop name
  Pred: SELECT T2.Name FROM employee AS T1 JOIN hiring AS T2 ON T1.Employee_ID = T2.Employee_ID JOIN shop AS T3 ON T3.Shop_ID = T2.Shop_ID GROUP BY T3.Name ORDER BY COUNT(*) DESC LIMIT 1
  Gold: SELECT t2.name FROM hiring AS t1 JOIN shop AS t2 ON t1.shop_id = t2.shop_id GROUP BY t1.shop_id ORDER BY COUNT(*) DESC LIMIT 1
  Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, AGGREGATION

[194] WRONG_TABLE | DB: employee_hire_evaluation | EX: ✗
  Q   : Which shops run with no employees? Find the shop names
  Pred: SELECT name FROM shop WHERE NOT shop_id IN (SELECT shop_id FROM employee)
  Gold: SELECT name FROM shop WHERE NOT shop_id IN (SELECT shop_id FROM hiring)
  Type: NESTED

[195] WRONG_COLUMNS | DB: employee_hire_evaluation | EX: ✗
  Q   : Find the number of employees hired in each shop; show the shop name as well
  Pred: SELECT T2.Name, COUNT(*) FROM hiring AS T1 JOIN shop AS T2 ON T1.Shop_ID = T2.Shop_ID GROUP BY T1.Shop_ID
  Gold: SELECT COUNT(*), t2.name FROM hiring AS t1 JOIN shop AS t2 ON t1.shop_id = t2.shop_id GROUP BY t2.name
  Type: JOIN, GROUP_BY, AGGREGATION

[196] WRONG_TABLE | DB: employee_hire_evaluation | EX: ✗
  Q   : For each shop, return the number of employees working there and the name of the shop
  Pred: SELECT T2.Name, COUNT(*) FROM employee AS T1 JOIN shop AS T2 ON T1.Shop_ID = T2.Shop_ID GROUP BY T1.Shop_ID
  Gold: SELECT COUNT(*), t2.name FROM hiring AS t1 JOIN shop AS t2 ON t1.shop_id = t2.shop_id GROUP BY t2.name
  Type: JOIN, GROUP_BY, AGGREGATION

[197] OTHER | DB: employee_hire_evaluation | EX: ✗
  Q   : Which district has both stores with less than 3000 products and stores with more than 10000 products
  Pred: SELECT District FROM shop WHERE Number_Products  3000 INTERSECT SELECT District FROM shop WHERE Number_Products > 10000
  Gold: SELECT district FROM shop WHERE Number_products < 3000 INTERSECT SELECT district FROM shop WHERE Number_products > 10000
  Type: SIMPLE

[198] OTHER | DB: employee_hire_evaluation | EX: ✗
  Q   : Find the districts in which there are both shops selling less than 3000 products and shops selling more than 10000 products
  Pred: SELECT District FROM shop WHERE Number_Products  3000 INTERSECT SELECT District FROM shop WHERE Number_Products > 10000
  Gold: SELECT district FROM shop WHERE Number_products < 3000 INTERSECT SELECT district FROM shop WHERE Number_products > 10000
  Type: SIMPLE

[199] EXTRA_JOIN | DB: cre_Doc_Template_Mgt | EX: ✓
  Q   : What is the document id, template id and description for document named "Robbin CV"
  Pred: SELECT T1.document_id, T2.template_id, T1.document_description FROM Documents AS T1 JOIN Templates AS T2 ON T1.template_id = T2.template_id WHERE T1.document_name = "Robbin CV"
  Gold: SELECT document_id, template_id, Document_Description FROM Documents WHERE document_name = "Robbin CV"
  Type: SIMPLE

[200] EXTRA_JOIN | DB: cre_Doc_Template_Mgt | EX: ✓
  Q   : Return the document id, template id, and description for the document with the name Robbin CV
  Pred: SELECT T1.document_id, T2.template_id, T1.document_description FROM Documents AS T1 JOIN Templates AS T2 ON T1.template_id = T2.template_id WHERE T1.document_name = "Robbin CV"
  Gold: SELECT document_id, template_id, Document_Description FROM Documents WHERE document_name = "Robbin CV"
  Type: SIMPLE

[201] MISSING_JOIN | DB: cre_Doc_Template_Mgt | EX: ✗
  Q   : Count the number of documents that use the PPT template type
  Pred: SELECT COUNT(*) FROM Documents WHERE template_type_code = "PPT"
  Gold: SELECT COUNT(*) FROM Documents AS T1 JOIN Templates AS T2 ON T1.Template_ID = T2.Template_ID WHERE T2.Template_Type_Code = 'PPT'
  Type: JOIN, AGGREGATION

[202] WRONG_COLUMNS | DB: cre_Doc_Template_Mgt | EX: ✓
  Q   : What are all different template ids used for documents, and how many times were each of them used
  Pred: SELECT DISTINCT template_id, COUNT(*) FROM documents GROUP BY template_id
  Gold: SELECT template_id, COUNT(*) FROM Documents GROUP BY template_id
  Type: GROUP_BY, AGGREGATION

[203] WRONG_TABLE | DB: cre_Doc_Template_Mgt | EX: ✗
  Q   : What are the different template type codes
  Pred: SELECT DISTINCT template_type_code
  Gold: SELECT DISTINCT template_type_code FROM Templates
  Type: SIMPLE

[204] EXTRA_JOIN | DB: cre_Doc_Template_Mgt | EX: ✓
  Q   : What is the version number and template type code for the template with version number later than 5
  Pred: SELECT T1.version_number, T2.template_type_code FROM Templates AS T1 JOIN Templates AS T2 ON T1.template_id = T2.template_id WHERE T1.version_number > 5
  Gold: SELECT version_number, template_type_code FROM Templates WHERE version_number > 5
  Type: SIMPLE

[205] EXTRA_JOIN | DB: cre_Doc_Template_Mgt | EX: ✓
  Q   : Return the version numbers and template type codes of templates with a version number greater than 5
  Pred: SELECT T1.version_number, T2.template_type_code FROM Templates AS T1 JOIN Templates AS T2 ON T1.template_id = T2.template_id WHERE T1.version_number > 5
  Gold: SELECT version_number, template_type_code FROM Templates WHERE version_number > 5
  Type: SIMPLE

[206] WRONG_TABLE | DB: cre_Doc_Template_Mgt | EX: ✓
  Q   : Return the type code of the template type that the most templates belong to
  Pred: SELECT T1.template_type_code FROM Ref_template_types AS T1 JOIN templates AS T2 ON T1.template_type_code = T2.template_type_code GROUP BY T1.template_type_code ORDER BY COUNT(*) DESC LIMIT 1
  Gold: SELECT template_type_code FROM Templates GROUP BY template_type_code ORDER BY COUNT(*) DESC LIMIT 1
  Type: GROUP_BY, ORDER_BY, LIMIT, AGGREGATION

[207] OTHER | DB: cre_Doc_Template_Mgt | EX: ✗
  Q   : Show all template type codes with less than three templates
  Pred: SELECT template_type_code FROM Templates GROUP BY template_type_code HAVING COUNT(*)  3
  Gold: SELECT template_type_code FROM Templates GROUP BY template_type_code HAVING COUNT(*) < 3
  Type: GROUP_BY, HAVING, AGGREGATION

[208] OTHER | DB: cre_Doc_Template_Mgt | EX: ✗
  Q   : What are the codes of template types that have fewer than 3 templates
  Pred: SELECT template_type_code FROM Templates GROUP BY template_type_code HAVING COUNT(*)  3
  Gold: SELECT template_type_code FROM Templates GROUP BY template_type_code HAVING COUNT(*) < 3
  Type: GROUP_BY, HAVING, AGGREGATION

[209] WRONG_TABLE | DB: cre_Doc_Template_Mgt | EX: ✓
  Q   : What is the template type code of the template used by document with the name "Data base"
  Pred: SELECT T2.template_type_code FROM documents AS T1 JOIN templates AS T2 ON T1.template_id = T2.template_id WHERE T1.document_name = "Data base"
  Gold: SELECT T1.template_type_code FROM Templates AS T1 JOIN Documents AS T2 ON T1.template_id = T2.template_id WHERE T2.document_name = "Data base"
  Type: JOIN

[210] WRONG_TABLE | DB: cre_Doc_Template_Mgt | EX: ✓
  Q   : Return the template type code of the template that is used by a document named Data base
  Pred: SELECT T2.template_type_code FROM documents AS T1 JOIN templates AS T2 ON T1.template_id = T2.template_id WHERE T1.document_name = "Data base"
  Gold: SELECT T1.template_type_code FROM Templates AS T1 JOIN Documents AS T2 ON T1.template_id = T2.template_id WHERE T2.document_name = "Data base"
  Type: JOIN

[211] WRONG_TABLE | DB: cre_Doc_Template_Mgt | EX: ✗
  Q   : Show all document names using templates with template type code BK
  Pred: SELECT document_name FROM documents WHERE template_type_code = "BK"
  Gold: SELECT T2.document_name FROM Templates AS T1 JOIN Documents AS T2 ON T1.template_id = T2.template_id WHERE T1.template_type_code = "BK"
  Type: JOIN

[212] WRONG_TABLE | DB: cre_Doc_Template_Mgt | EX: ✓
  Q   : What are the names of documents that use templates with the code BK
  Pred: SELECT document_name FROM documents WHERE template_id IN (SELECT template_id FROM Templates WHERE template_type_code = "BK")
  Gold: SELECT T2.document_name FROM Templates AS T1 JOIN Documents AS T2 ON T1.template_id = T2.template_id WHERE T1.template_type_code = "BK"
  Type: JOIN

[213] WRONG_COLUMNS | DB: cre_Doc_Template_Mgt | EX: ✗
  Q   : Show all template type codes and the number of documents using each type
  Pred: SELECT T2.template_type_code, COUNT(*) FROM Templates AS T1 JOIN Documents AS T2 ON T1.template_id = T2.template_id GROUP BY T2.template_type_code
  Gold: SELECT T1.template_type_code, COUNT(*) FROM Templates AS T1 JOIN Documents AS T2 ON T1.template_id = T2.template_id GROUP BY T1.template_type_code
  Type: JOIN, GROUP_BY, AGGREGATION

[214] WRONG_TABLE | DB: cre_Doc_Template_Mgt | EX: ✗
  Q   : What are the different template type codes, and how many documents use each type
  Pred: SELECT T1.template_type_code, COUNT(*) FROM Ref_template_types AS T1 JOIN templates AS T2 ON T1.template_type_code = T2.template_type_code GROUP BY T1.template_type_code
  Gold: SELECT T1.template_type_code, COUNT(*) FROM Templates AS T1 JOIN Documents AS T2 ON T1.template_id = T2.template_id GROUP BY T1.template_type_code
  Type: JOIN, GROUP_BY, AGGREGATION

[215] WRONG_TABLE | DB: cre_Doc_Template_Mgt | EX: ✗
  Q   : Which template type code is used by most number of documents
  Pred: SELECT template_type_code FROM Documents GROUP BY template_type_code ORDER BY COUNT(*) DESC LIMIT 1
  Gold: SELECT T1.template_type_code FROM Templates AS T1 JOIN Documents AS T2 ON T1.template_id = T2.template_id GROUP BY T1.template_type_code ORDER BY COUNT(*) DESC LIMIT 1
  Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, AGGREGATION

[216] MISSING_JOIN | DB: cre_Doc_Template_Mgt | EX: ✗
  Q   : Return the code of the template type that is most commonly used in documents
  Pred: SELECT template_type_code FROM Templates GROUP BY template_type_code ORDER BY COUNT(*) DESC LIMIT 1
  Gold: SELECT T1.template_type_code FROM Templates AS T1 JOIN Documents AS T2 ON T1.template_id = T2.template_id GROUP BY T1.template_type_code ORDER BY COUNT(*) DESC LIMIT 1
  Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, AGGREGATION

[217] MISSING_JOIN | DB: cre_Doc_Template_Mgt | EX: ✗
  Q   : Show all template type codes that are not used by any document
  Pred: SELECT template_type_code FROM Templates EXCEPT SELECT template_type_code FROM Templates
  Gold: SELECT template_type_code FROM Templates EXCEPT SELECT template_type_code FROM Templates AS T1 JOIN Documents AS T2 ON T1.template_id = T2.template_id
  Type: JOIN

[218] MISSING_JOIN | DB: cre_Doc_Template_Mgt | EX: ✗
  Q   : What are the codes of template types that are not used for any document
  Pred: SELECT template_type_code FROM Templates EXCEPT SELECT template_type_code FROM Templates
  Gold: SELECT template_type_code FROM Templates EXCEPT SELECT template_type_code FROM Templates AS T1 JOIN Documents AS T2 ON T1.template_id = T2.template_id
  Type: JOIN

[219] EXTRA_JOIN | DB: cre_Doc_Template_Mgt | EX: ✗
  Q   : What is the template type code for template type description "Book"
  Pred: SELECT T1.template_type_code FROM Ref_template_types AS T1 JOIN templates AS T2 ON T1.template_type_code = T2.template_type_code WHERE T2.template_type_description = "Book"
  Gold: SELECT template_type_code FROM Ref_template_types WHERE template_type_description = "Book"
  Type: SIMPLE

[220] OTHER | DB: cre_Doc_Template_Mgt | EX: ✗
  Q   : What are the distinct template type descriptions for the templates ever used by any document
  Pred: SELECT DISTINCT T1.template_type_description FROM Ref_template_types AS T1 JOIN templates AS T2 ON T1.template_type_code = T2.template_type_code
  Gold: SELECT DISTINCT T1.template_type_description FROM Ref_template_types AS T1 JOIN Templates AS T2 ON T1.template_type_code = T2.template_type_code JOIN Documents AS T3 ON T2.Template_ID = T3.template_ID
  Type: JOIN

[221] WRONG_TABLE | DB: cre_Doc_Template_Mgt | EX: ✗
  Q   : Return the different descriptions for templates that have been used in a document
  Pred: SELECT DISTINCT template_type_description FROM templates
  Gold: SELECT DISTINCT T1.template_type_description FROM Ref_template_types AS T1 JOIN Templates AS T2 ON T1.template_type_code = T2.template_type_code JOIN Documents AS T3 ON T2.Template_ID = T3.template_ID
  Type: JOIN

[222] WRONG_TABLE | DB: cre_Doc_Template_Mgt | EX: ✗
  Q   : What are the template ids with template type description "Presentation"
  Pred: SELECT template_id FROM Templates WHERE template_type_description = "Presentation"
  Gold: SELECT T2.template_id FROM Ref_template_types AS T1 JOIN Templates AS T2 ON T1.template_type_code = T2.template_type_code WHERE T1.template_type_description = "Presentation"
  Type: JOIN

[223] WRONG_TABLE | DB: cre_Doc_Template_Mgt | EX: ✗
  Q   : Return the ids corresponding to templates with the description 'Presentation'
  Pred: SELECT template_id FROM Templates WHERE document_description = 'Presentation'
  Gold: SELECT T2.template_id FROM Ref_template_types AS T1 JOIN Templates AS T2 ON T1.template_type_code = T2.template_type_code WHERE T1.template_type_description = "Presentation"
  Type: JOIN

[224] OTHER | DB: cre_Doc_Template_Mgt | EX: ✓
  Q   : Show paragraph details for paragraph with text 'Korea '
  Pred: SELECT other_details FROM Paragraphs WHERE paragraph_text LIKE '%Korea%'
  Gold: SELECT other_details FROM paragraphs WHERE paragraph_text LIKE 'korea'
  Type: SIMPLE

[225] OTHER | DB: cre_Doc_Template_Mgt | EX: ✓
  Q   : What are the details for the paragraph that includes the text 'Korea '
  Pred: SELECT other_details FROM Paragraphs WHERE paragraph_text LIKE '%Korea%'
  Gold: SELECT other_details FROM paragraphs WHERE paragraph_text LIKE 'korea'
  Type: SIMPLE

[226] WRONG_TABLE | DB: cre_Doc_Template_Mgt | EX: ✓
  Q   : What are the paragraph texts for the document with the name 'Customer reviews'
  Pred: SELECT t2.paragraph_text FROM documents AS t1 JOIN paragraphs AS t2 ON t1.document_id = t2.document_id WHERE t1.document_name = "Customer reviews"
  Gold: SELECT T1.paragraph_text FROM Paragraphs AS T1 JOIN Documents AS T2 ON T1.document_id = T2.document_id WHERE T2.document_name = "Customer reviews"
  Type: JOIN

[227] OTHER | DB: cre_Doc_Template_Mgt | EX: ✗
  Q   : Show all document ids and the number of paragraphs in each document. Order by document id
  Pred: SELECT document_id, COUNT(*) FROM paragraphs GROUP BY document_id ORDER BY COUNT(*)
  Gold: SELECT document_id, COUNT(*) FROM Paragraphs GROUP BY document_id ORDER BY document_id
  Type: GROUP_BY, ORDER_BY, AGGREGATION

[228] OTHER | DB: cre_Doc_Template_Mgt | EX: ✗
  Q   : Return the different document ids along with the number of paragraphs corresponding to each, ordered by id
  Pred: SELECT document_id, COUNT(*) FROM paragraphs GROUP BY document_id ORDER BY COUNT(*)
  Gold: SELECT document_id, COUNT(*) FROM Paragraphs GROUP BY document_id ORDER BY document_id
  Type: GROUP_BY, ORDER_BY, AGGREGATION

[229] WRONG_TABLE | DB: cre_Doc_Template_Mgt | EX: ✓
  Q   : Show all document ids, names and the number of paragraphs in each document
  Pred: SELECT T1.document_id, T1.document_name, COUNT(*) FROM Documents AS T1 JOIN Paragraphs AS T2 ON T1.document_id = T2.document_id GROUP BY T1.document_id
  Gold: SELECT T1.document_id, T2.document_name, COUNT(*) FROM Paragraphs AS T1 JOIN Documents AS T2 ON T1.document_id = T2.document_id GROUP BY T1.document_id
  Type: JOIN, GROUP_BY, AGGREGATION

[230] WRONG_TABLE | DB: cre_Doc_Template_Mgt | EX: ✓
  Q   : What are the ids and names of each document, as well as the number of paragraphs in each
  Pred: SELECT T1.document_id, T1.document_name, COUNT(*) FROM Documents AS T1 JOIN Paragraphs AS T2 ON T1.document_id = T2.document_id GROUP BY T1.document_id
  Gold: SELECT T1.document_id, T2.document_name, COUNT(*) FROM Paragraphs AS T1 JOIN Documents AS T2 ON T1.document_id = T2.document_id GROUP BY T1.document_id
  Type: JOIN, GROUP_BY, AGGREGATION

[231] WRONG_TABLE | DB: cre_Doc_Template_Mgt | EX: ✓
  Q   : What is the document id and name with greatest number of paragraphs
  Pred: SELECT T1.document_id, T1.document_name FROM Documents AS T1 JOIN Paragraphs AS T2 ON T1.document_id = T2.document_id GROUP BY T1.document_id ORDER BY COUNT(*) DESC LIMIT 1
  Gold: SELECT T1.document_id, T2.document_name FROM Paragraphs AS T1 JOIN Documents AS T2 ON T1.document_id = T2.document_id GROUP BY T1.document_id ORDER BY COUNT(*) DESC LIMIT 1
  Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, AGGREGATION

[232] WRONG_TABLE | DB: cre_Doc_Template_Mgt | EX: ✓
  Q   : Return the id and name of the document with the most paragraphs
  Pred: SELECT T1.document_id, T1.document_name FROM Documents AS T1 JOIN Paragraphs AS T2 ON T1.document_id = T2.document_id GROUP BY T1.document_id ORDER BY COUNT(*) DESC LIMIT 1
  Gold: SELECT T1.document_id, T2.document_name FROM Paragraphs AS T1 JOIN Documents AS T2 ON T1.document_id = T2.document_id GROUP BY T1.document_id ORDER BY COUNT(*) DESC LIMIT 1
  Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, AGGREGATION

[233] WRONG_TABLE | DB: cre_Doc_Template_Mgt | EX: ✓
  Q   : Return the id of the document with the fewest paragraphs
  Pred: SELECT t1.document_id FROM Documents AS t1 JOIN Paragraphs AS t2 ON t1.document_id = t2.document_id GROUP BY t1.document_id ORDER BY COUNT(*) LIMIT 1
  Gold: SELECT document_id FROM Paragraphs GROUP BY document_id ORDER BY COUNT(*) ASC LIMIT 1
  Type: GROUP_BY, ORDER_BY, LIMIT, AGGREGATION

[234] WRONG_TABLE | DB: cre_Doc_Template_Mgt | EX: ✗
  Q   : Show the document id with paragraph text 'Brazil' and 'Ireland'
  Pred: SELECT T1.document_id FROM Documents AS T1 JOIN Paragraphs AS T2 ON T1.document_id = T2.document_id WHERE T2.paragraph_text = 'Brazil' INTERSECT SELECT T1.document_id FROM Documents AS T1 JOIN Paragraphs AS T2 ON T1.paragraph_id = T2.document_id WHERE T2.paragraph_text = 'Irland'
  Gold: SELECT document_id FROM Paragraphs WHERE paragraph_text = 'Brazil' INTERSECT SELECT document_id FROM Paragraphs WHERE paragraph_text = 'Ireland'
  Type: SIMPLE

[235] WRONG_TABLE | DB: cre_Doc_Template_Mgt | EX: ✓
  Q   : What are the ids of documents that contain the paragraph text 'Brazil' and 'Ireland'
  Pred: SELECT T1.document_id FROM Documents AS T1 JOIN Paragraphs AS T2 ON T1.document_id = T2.document_id WHERE T2.paragraph_text = 'Brazil' INTERSECT SELECT T1.document_id FROM Documents AS T1 JOIN Paragraphs AS T2 ON T1.document_id = T2.document_id WHERE T2.paragraph_text LIKE '%Ireland%'
  Gold: SELECT document_id FROM Paragraphs WHERE paragraph_text = 'Brazil' INTERSECT SELECT document_id FROM Paragraphs WHERE paragraph_text = 'Ireland'
  Type: SIMPLE

[236] OTHER | DB: course_teach | EX: ✓
  Q   : List the name of teachers whose hometown is not `` Little Lever Urban District ''
  Pred: SELECT Name FROM teacher WHERE Hometown > ' Little Lever Urban District '''
  Gold: SELECT name FROM teacher WHERE hometown <> "little lever urban district"
  Type: SIMPLE

[237] OTHER | DB: course_teach | EX: ✓
  Q   : What are the names of the teachers whose hometown is not `` Little Lever Urban District ''
  Pred: SELECT Name FROM teacher WHERE Hometown > ' Little Lever Urban District '''
  Gold: SELECT name FROM teacher WHERE hometown <> "little lever urban district"
  Type: SIMPLE

[238] WRONG_COLUMNS | DB: course_teach | EX: ✗
  Q   : Show names of teachers and the courses they are arranged to teach
  Pred: SELECT T3.Name, T1.Course FROM course_arrange AS T1 JOIN teacher AS T2 ON T1.Teacher_ID = T2.Teacher_ID
  Gold: SELECT T3.Name, T2.Course FROM course_arrange AS T1 JOIN course AS T2 ON T1.Course_ID = T2.Course_ID JOIN teacher AS T3 ON T1.Teacher_ID = T3.Teacher_ID
  Type: JOIN

[239] WRONG_COLUMNS | DB: course_teach | EX: ✗
  Q   : What is the name of each teacher and what course they teach
  Pred: SELECT T2.Name, T1.Course FROM course_arrange AS T1 JOIN teacher AS T2 ON T1.Teacher_ID = T2.Teacher_ID
  Gold: SELECT T3.Name, T2.Course FROM course_arrange AS T1 JOIN course AS T2 ON T1.Course_ID = T2.Course_ID JOIN teacher AS T3 ON T1.Teacher_ID = T3.Teacher_ID
  Type: JOIN

[240] WRONG_COLUMNS | DB: course_teach | EX: ✗
  Q   : Show names of teachers and the courses they are arranged to teach in ascending alphabetical order of the teacher's name
  Pred: SELECT T3.Name, T1.Course FROM course_arrange AS T1 JOIN teacher AS T2 ON T1.Teacher_ID = T2.Teacher_ID ORDER BY T2.Name ASC
  Gold: SELECT T3.Name, T2.Course FROM course_arrange AS T1 JOIN course AS T2 ON T1.Course_ID = T2.Course_ID JOIN teacher AS T3 ON T1.Teacher_ID = T3.Teacher_ID ORDER BY T3.Name
  Type: JOIN, ORDER_BY

[241] WRONG_COLUMNS | DB: course_teach | EX: ✗
  Q   : What are the names of the teachers and the courses they teach in ascending alphabetical order by the name of the teacher
  Pred: SELECT T3.Name, T1.Course FROM course_arrange AS T1 JOIN teacher AS T2 ON T1.Teacher_ID = T2.Teacher_ID ORDER BY T2.Name ASC
  Gold: SELECT T3.Name, T2.Course FROM course_arrange AS T1 JOIN course AS T2 ON T1.Course_ID = T2.Course_ID JOIN teacher AS T3 ON T1.Teacher_ID = T3.Teacher_ID ORDER BY T3.Name
  Type: JOIN, ORDER_BY

[242] OTHER | DB: course_teach | EX: ✗
  Q   : Show the name of the teacher for the math course
  Pred: SELECT T3.Name FROM course_arrange AS T1 JOIN teacher AS T2 ON T1.Teacher_ID = T2.Teacher_ID JOIN course AS T3 ON T1.Course_ID = T3.Course_ID WHERE T3.course = 'Math'
  Gold: SELECT T3.Name FROM course_arrange AS T1 JOIN course AS T2 ON T1.Course_ID = T2.Course_ID JOIN teacher AS T3 ON T1.Teacher_ID = T3.Teacher_ID WHERE T2.Course = "Math"
  Type: JOIN

[243] OTHER | DB: course_teach | EX: ✗
  Q   : What are the names of the people who teach math courses
  Pred: SELECT T3.Name FROM course_arrange AS T1 JOIN teacher AS T2 ON T1.Teacher_ID = T2.Teacher_ID JOIN course AS T3 ON T1.Course_ID = T3.Course_ID WHERE T3.Computer = "Math"
  Gold: SELECT T3.Name FROM course_arrange AS T1 JOIN course AS T2 ON T1.Course_ID = T2.Course_ID JOIN teacher AS T3 ON T1.Teacher_ID = T3.Teacher_ID WHERE T2.Course = "Math"
  Type: JOIN

[244] OTHER | DB: museum_visit | EX: ✗
  Q   : How many visitors below age 30 are there
  Pred: SELECT COUNT(*) FROM visitor WHERE age  30
  Gold: SELECT COUNT(*) FROM visitor WHERE age < 30
  Type: AGGREGATION

[245] OTHER | DB: museum_visit | EX: ✗
  Q   : Find the names of the visitors whose membership level is higher than 4, and order the results by the level from high to low
  Pred: SELECT name FROM visitor WHERE level_of_membership > 4 ORDER BY level_of_membership
  Gold: SELECT name FROM visitor WHERE Level_of_membership > 4 ORDER BY Level_of_membership DESC
  Type: ORDER_BY

[246] OTHER | DB: museum_visit | EX: ✗
  Q   : What is the average age of the visitors whose membership level is not higher than 4
  Pred: SELECT AVG(age) FROM visitor WHERE level_of_membership  4
  Gold: SELECT AVG(age) FROM visitor WHERE Level_of_membership <= 4
  Type: AGGREGATION

[247] EXTRA_JOIN | DB: museum_visit | EX: ✗
  Q   : Find the id and name of the museum that has the most staff members
  Pred: SELECT T1.museum_id, T1.name FROM museum AS T1 JOIN visitor AS T2 ON T1.museum_id = T2.museum_id GROUP BY T1.museum_id ORDER BY SUM(T2.num_of_staff) DESC LIMIT 1
  Gold: SELECT museum_id, name FROM museum ORDER BY num_of_staff DESC LIMIT 1
  Type: ORDER_BY, LIMIT

[248] OTHER | DB: museum_visit | EX: ✗
  Q   : Find the average number of staff working for the museums that were open before 2009
  Pred: SELECT AVG(Num_of_staff) FROM museum WHERE open_year  2009
  Gold: SELECT AVG(num_of_staff) FROM museum WHERE open_year < 2009
  Type: AGGREGATION

[249] WRONG_COLUMNS | DB: museum_visit | EX: ✗
  Q   : What are the opening year and staff number of the museum named Plaza Museum
  Pred: SELECT open_year, num_of_staff FROM museum WHERE name = 'Place Museum'
  Gold: SELECT Num_of_Staff, Open_Year FROM museum WHERE name = 'Plaza Museum'
  Type: SIMPLE

[250] OTHER | DB: museum_visit | EX: ✓
  Q   : find the id, name and age for visitors who visited some museums more than once
  Pred: SELECT T1.id, T1.name, T1.age FROM visitor AS T1 JOIN visit AS T2 ON T1.id = T2.visitor_id GROUP BY T2.visitor_id HAVING COUNT(*) > 1
  Gold: SELECT t1.id, t1.name, t1.age FROM visitor AS t1 JOIN visit AS t2 ON t1.id = t2.visitor_id GROUP BY t1.id HAVING COUNT(*) > 1
  Type: JOIN, GROUP_BY, HAVING, AGGREGATION

[251] MISSING_GROUP_BY | DB: museum_visit | EX: ✗
  Q   : What are the id, name and membership level of visitors who have spent the largest amount of money in total in all museum tickets
  Pred: SELECT T1.id, T1.name, T1.level_of_membership FROM visitor AS T1 JOIN visit AS T2 ON T1.id = T2.visitor_id ORDER BY SUM(T2.num_of_ticket) DESC LIMIT 1
  Gold: SELECT t2.visitor_id, t1.name, t1.Level_of_membership FROM visitor AS t1 JOIN visit AS t2 ON t1.id = t2.visitor_id GROUP BY t2.visitor_id ORDER BY SUM(t2.Total_spent) DESC LIMIT 1
  Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, AGGREGATION

[252] WRONG_TABLE | DB: museum_visit | EX: ✗
  Q   : What are the id and name of the museum visited most times
  Pred: SELECT T1.id, T1.name FROM visitor AS T1 JOIN visit AS T2 ON T1.id = T2.visitor_id GROUP BY T1.id ORDER BY COUNT(*) DESC LIMIT 1
  Gold: SELECT t2.Museum_ID, t1.name FROM museum AS t1 JOIN visit AS t2 ON t1.Museum_ID = t2.Museum_ID GROUP BY t2.Museum_ID ORDER BY COUNT(*) DESC LIMIT 1
  Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, AGGREGATION

[253] WRONG_COLUMNS | DB: museum_visit | EX: ✗
  Q   : What is the name of the museum that had no visitor yet
  Pred: SELECT name FROM museum WHERE NOT museum_id IN (SELECT visitor_id FROM visit)
  Gold: SELECT name FROM museum WHERE NOT Museum_ID IN (SELECT museum_id FROM visit)
  Type: NESTED

[254] OTHER | DB: museum_visit | EX: ✓
  Q   : Find the name and age of the visitor who bought the most tickets at once
  Pred: SELECT T1.name, T1.age FROM visitor AS T1 JOIN visit AS T2 ON T1.id = T2.visitor_id GROUP BY T2.visitor_id ORDER BY SUM(T2.num_of_ticket) DESC LIMIT 1
  Gold: SELECT t1.name, t1.age FROM visitor AS t1 JOIN visit AS t2 ON t1.id = t2.visitor_id ORDER BY t2.num_of_ticket DESC LIMIT 1
  Type: JOIN, ORDER_BY, LIMIT

[255] WRONG_TABLE | DB: museum_visit | EX: ✗
  Q   : What are the average and maximum number of tickets bought in all visits
  Pred: SELECT AVG(Num_of_ticket), MAX(Num_of_ticket) FROM visitor
  Gold: SELECT AVG(num_of_ticket), MAX(num_of_ticket) FROM visit
  Type: AGGREGATION

[256] WRONG_COLUMNS | DB: museum_visit | EX: ✗
  Q   : What is the total ticket expense of the visitors whose membership level is 1
  Pred: SELECT SUM(T1.num_of_ticket) FROM visitor AS T1 JOIN visit AS T2 ON T1.id = T2.visitor_id WHERE T1.level_of_membership = 1
  Gold: SELECT SUM(t2.Total_spent) FROM visitor AS t1 JOIN visit AS t2 ON t1.id = t2.visitor_id WHERE t1.Level_of_membership = 1
  Type: JOIN, AGGREGATION

[257] OTHER | DB: museum_visit | EX: ✗
  Q   : What is the name of the visitor who visited both a museum opened before 2009 and a museum opened after 2011
  Pred: SELECT T1.name FROM visitor AS T1 JOIN visit AS T2 ON T1.id = T2.visitor_id WHERE T2.open_year  2009 INTERSECT SELECT T1.name FROM visitor AS T1 JOIN visit AS T2 ON T1.id = T2.visitor_id WHERE T2.open_year > 2011
  Gold: SELECT t1.name FROM visitor AS t1 JOIN visit AS t2 ON t1.id = t2.visitor_id JOIN museum AS t3 ON t3.Museum_ID = t2.Museum_ID WHERE t3.open_year < 2009 INTERSECT SELECT t1.name FROM visitor AS t1 JOIN visit AS t2 ON t1.id = t2.visitor_id JOIN museum AS t3 ON t3.Museum_ID = t2.Museum_ID WHERE t3.open_year > 2011
  Type: JOIN

[258] WRONG_TABLE | DB: museum_visit | EX: ✗
  Q   : Find the number of visitors who did not visit any museum opened after 2010
  Pred: SELECT COUNT(*) FROM visitor WHERE NOT visitor_id IN (SELECT visitor_id FROM visit WHERE open_year > 2010)
  Gold: SELECT COUNT(*) FROM visitor WHERE NOT id IN (SELECT t2.visitor_id FROM museum AS t1 JOIN visit AS t2 ON t1.Museum_ID = t2.Museum_ID WHERE t1.open_year > 2010)
  Type: JOIN, NESTED, AGGREGATION

[259] OTHER | DB: museum_visit | EX: ✗
  Q   : How many museums were opened after 2013 or before 2008
  Pred: SELECT COUNT(*) FROM museum WHERE open_year > 2013 OR open_year  2008
  Gold: SELECT COUNT(*) FROM museum WHERE open_year > 2013 OR open_year < 2008
  Type: AGGREGATION

[260] EXTRA_JOIN | DB: wta_1 | EX: ✗
  Q   : Find the average age of losers and winners of all matches
  Pred: SELECT AVG(T1.loser_age), AVG(T2.winner_age) FROM matches AS T1 JOIN players AS T2 ON T1.winner_id = T2.player_id
  Gold: SELECT AVG(loser_age), AVG(winner_age) FROM matches
  Type: AGGREGATION

[261] EXTRA_JOIN | DB: wta_1 | EX: ✗
  Q   : What are the average ages of losers and winners across matches
  Pred: SELECT AVG(T1.loser_age), AVG(T2.winner_age) FROM matches AS T1 JOIN players AS T2 ON T1.winner_id = T2.player_id
  Gold: SELECT AVG(loser_age), AVG(winner_age) FROM matches
  Type: AGGREGATION

[262] WRONG_COLUMNS | DB: wta_1 | EX: ✗
  Q   : Find the highest rank of losers in all matches
  Pred: SELECT MAX(Loser_rank) FROM matches
  Gold: SELECT MIN(loser_rank) FROM matches
  Type: AGGREGATION

[263] EXTRA_JOIN | DB: wta_1 | EX: ✗
  Q   : What is the best rank of losers across all matches
  Pred: SELECT DISTINCT T1.loser_rank, MAX(T2.loser_rank) FROM matches AS T1 JOIN rankings AS T2 ON T1.loser_id = T2.loser_id GROUP BY T1.loser_rank
  Gold: SELECT MIN(loser_rank) FROM matches
  Type: AGGREGATION

[264] WRONG_TABLE | DB: wta_1 | EX: ✗
  Q   : Find the number of distinct name of losers
  Pred: SELECT COUNT(DISTINCT loser_name) FROM players
  Gold: SELECT COUNT(DISTINCT loser_name) FROM matches
  Type: AGGREGATION

[265] WRONG_TABLE | DB: wta_1 | EX: ✗
  Q   : How many different loser names are there
  Pred: SELECT COUNT(DISTINCT loser_name) FROM players
  Gold: SELECT COUNT(DISTINCT loser_name) FROM matches
  Type: AGGREGATION

[266] EXTRA_JOIN | DB: wta_1 | EX: ✗
  Q   : Find the name of tourney that has more than 10 matches
  Pred: SELECT T2.Tournament_Name FROM matches AS T1 JOIN tournament AS T2 ON T1.Tournament_ID = T2.Tournament_ID GROUP BY T2.Tournament_Name HAVING COUNT(*) > 10
  Gold: SELECT tourney_name FROM matches GROUP BY tourney_name HAVING COUNT(*) > 10
  Type: GROUP_BY, HAVING, AGGREGATION

[267] EXTRA_JOIN | DB: wta_1 | EX: ✗
  Q   : What are the names of tournaments that have more than 10 matches
  Pred: SELECT T2.Tournament_Name FROM matches AS T1 JOIN tournaments AS T2 ON T1.Tournament_ID = T2.Tournament_ID GROUP BY T2.Tournament_Name HAVING COUNT(*) > 10
  Gold: SELECT tourney_name FROM matches GROUP BY tourney_name HAVING COUNT(*) > 10
  Type: GROUP_BY, HAVING, AGGREGATION

[268] WRONG_TABLE | DB: wta_1 | EX: ✗
  Q   : List the names of all winners who played in both 2013 and 2016
  Pred: SELECT winner_name FROM players WHERE YEAR = 2013 INTERSECT SELECT winner_name FROM players WHERE YEAR = 2016
  Gold: SELECT winner_name FROM matches WHERE YEAR = 2013 INTERSECT SELECT winner_name FROM matches WHERE YEAR = 2016
  Type: SIMPLE

[269] WRONG_TABLE | DB: wta_1 | EX: ✗
  Q   : What are the names of players who won in both 2013 and 2016
  Pred: SELECT T2.winner_name FROM matches AS T1 JOIN players AS T2 ON T1.player_id = T2.winner_id WHERE T1.year = 2013 INTERSECT SELECT T2.winner_name FROM rankings AS T1 JOIN players AS T2 ON T1.player_id = T2.winner_id WHERE T1.year = 2016
  Gold: SELECT winner_name FROM matches WHERE YEAR = 2013 INTERSECT SELECT winner_name FROM matches WHERE YEAR = 2016
  Type: SIMPLE

[270] OTHER | DB: wta_1 | EX: ✗
  Q   : What are the country code and first name of the players who won in both tourney WTA Championships and Australian Open
  Pred: SELECT T1.country_code, T1.first_name FROM players AS T1 JOIN matches AS T2 ON T1.player_id = T2.winner_id WHERE T2.tournament_name = 'WTA Championships' INTERSECT SELECT T1.country_code, T1.first_name FROM players AS T1 JOIN rankings AS T2 ON T1.player_id = T2.player_id WHERE T2.tournament_name = 'Australian Open'
  Gold: SELECT T1.country_code, T1.first_name FROM players AS T1 JOIN matches AS T2 ON T1.player_id = T2.winner_id WHERE T2.tourney_name = 'WTA Championships' INTERSECT SELECT T1.country_code, T1.first_name FROM players AS T1 JOIN matches AS T2 ON T1.player_id = T2.winner_id WHERE T2.tourney_name = 'Australian Open'
  Type: JOIN

[271] WRONG_TABLE | DB: wta_1 | EX: ✗
  Q   : What are the first names and country codes for players who won both the WTA Championships and the Australian Open
  Pred: SELECT T2.first_name, T2.country_code FROM rankings AS T1 JOIN players AS T2 ON T1.player_id = T2.player_id JOIN tournaments AS T3 ON T1.tournament_name = T3.tournament_name JOIN players AS T4 ON T3.player_id = T4.player_id WHERE T3.tournament_name = 'WTA Championships' INTERSECT SELECT T2.country_code = 'Australian Open'
  Gold: SELECT T1.country_code, T1.first_name FROM players AS T1 JOIN matches AS T2 ON T1.player_id = T2.winner_id WHERE T2.tourney_name = 'WTA Championships' INTERSECT SELECT T1.country_code, T1.first_name FROM players AS T1 JOIN matches AS T2 ON T1.player_id = T2.winner_id WHERE T2.tourney_name = 'Australian Open'
  Type: JOIN

[272] OTHER | DB: wta_1 | EX: ✗
  Q   : Find the first name and country code of the oldest player
  Pred: SELECT first_name, country_code FROM players ORDER BY birth_date DESC LIMIT 1
  Gold: SELECT first_name, country_code FROM players ORDER BY birth_date LIMIT 1
  Type: ORDER_BY, LIMIT

[273] OTHER | DB: wta_1 | EX: ✗
  Q   : What is the first name and country code of the oldest player
  Pred: SELECT first_name, country_code FROM players ORDER BY birth_date DESC LIMIT 1
  Gold: SELECT first_name, country_code FROM players ORDER BY birth_date LIMIT 1
  Type: ORDER_BY, LIMIT

[274] OTHER | DB: wta_1 | EX: ✗
  Q   : List the first and last name of all players who are left / L hand in the order of birth date
  Pred: SELECT first_name, last_name FROM players WHERE hand = 'left' ORDER BY birth_date
  Gold: SELECT first_name, last_name FROM players WHERE hand = 'L' ORDER BY birth_date
  Type: ORDER_BY

[275] WRONG_COLUMNS | DB: wta_1 | EX: ✗
  Q   : What are the full names of all left handed players, in order of birth date
  Pred: SELECT first_name, last_name, birth_date FROM players WHERE hand = 'left' ORDER BY birth_date
  Gold: SELECT first_name, last_name FROM players WHERE hand = 'L' ORDER BY birth_date
  Type: ORDER_BY

[276] WRONG_COLUMNS | DB: wta_1 | EX: ✗
  Q   : Find the first name and country code of the player who did the most number of tours
  Pred: SELECT T1.first_name, T1.country_code FROM players AS T1 JOIN rankings AS T2 ON T1.player_id = T2.player_id GROUP BY T1.player_id ORDER BY COUNT(*) DESC LIMIT 1
  Gold: SELECT T1.country_code, T1.first_name FROM players AS T1 JOIN rankings AS T2 ON T1.player_id = T2.player_id ORDER BY T2.tours DESC LIMIT 1
  Type: JOIN, ORDER_BY, LIMIT

[277] WRONG_COLUMNS | DB: wta_1 | EX: ✗
  Q   : What is the first name and country code of the player with the most tours
  Pred: SELECT T1.first_name, T1.country_code FROM players AS T1 JOIN rankings AS T2 ON T1.player_id = T2.player_id GROUP BY T1.player_id ORDER BY SUM(T2.tours) DESC LIMIT 1
  Gold: SELECT T1.country_code, T1.first_name FROM players AS T1 JOIN rankings AS T2 ON T1.player_id = T2.player_id ORDER BY T2.tours DESC LIMIT 1
  Type: JOIN, ORDER_BY, LIMIT

[278] WRONG_TABLE | DB: wta_1 | EX: ✗
  Q   : Find the name and rank points of the winner who won the most times
  Pred: SELECT T1.winner_name, T1.winner_rank_points FROM players AS T1 JOIN rankings AS T2 ON T1.player_id = T2.winner_id GROUP BY T1.winner_rank_points ORDER BY COUNT(*) DESC LIMIT 1
  Gold: SELECT winner_name, winner_rank_points FROM matches GROUP BY winner_name ORDER BY COUNT(*) DESC LIMIT 1
  Type: GROUP_BY, ORDER_BY, LIMIT, AGGREGATION

[279] WRONG_TABLE | DB: wta_1 | EX: ✗
  Q   : What is the name of the winner who has won the most matches, and how many rank points does this player have
  Pred: SELECT T1.winner_name, T1.winner_rank_points FROM players AS T1 JOIN matches AS T2 ON T1.player_id = T2.winner_id GROUP BY T1.player_id ORDER BY COUNT(*) DESC LIMIT 1
  Gold: SELECT winner_name, winner_rank_points FROM matches GROUP BY winner_name ORDER BY COUNT(*) DESC LIMIT 1
  Type: GROUP_BY, ORDER_BY, LIMIT, AGGREGATION

[280] WRONG_TABLE | DB: wta_1 | EX: ✗
  Q   : Find the name of the winner who has the highest rank points and participated in the Australian Open tourney
  Pred: SELECT T1.winner_name FROM players AS T1 JOIN matches AS T2 ON T1.player_id = T2.winner_id JOIN tourneys AS T3 ON T2.tournament_name = T3.tournament_name WHERE T3.tournament_name = 'Australian Open' ORDER BY T1.winner_rank_points DESC LIMIT 1
  Gold: SELECT winner_name FROM matches WHERE tourney_name = 'Australian Open' ORDER BY winner_rank_points DESC LIMIT 1
  Type: ORDER_BY, LIMIT

[281] WRONG_TABLE | DB: wta_1 | EX: ✗
  Q   : What is the name of the winner with the most rank points who participated in the Australian Open tournament
  Pred: SELECT T1.winner_name FROM players AS T1 JOIN matches AS T2 ON T1.player_id = T2.winner_id JOIN tournaments AS T3 ON T2.tournament_name = T3.Tournament_name WHERE T3.Tournament_name = "Australian Open" GROUP BY T1.winner_rank_points ORDER BY COUNT(*) DESC LIMIT 1
  Gold: SELECT winner_name FROM matches WHERE tourney_name = 'Australian Open' ORDER BY winner_rank_points DESC LIMIT 1
  Type: ORDER_BY, LIMIT

[282] EXTRA_JOIN | DB: wta_1 | EX: ✗
  Q   : find the names of loser and winner who played in the match with greatest number of minutes
  Pred: SELECT T2.loser_name, T2.winner_name FROM matches AS T1 JOIN players AS T2 ON T1.player_id = T2.winner_id ORDER BY T1.minutes DESC LIMIT 1
  Gold: SELECT winner_name, loser_name FROM matches ORDER BY minutes DESC LIMIT 1
  Type: ORDER_BY, LIMIT

[283] WRONG_TABLE | DB: wta_1 | EX: ✗
  Q   : What are the names of the winner and loser who played in the longest match
  Pred: SELECT T1.winner_name, T1.loser_name FROM players AS T1 JOIN matches AS T2 ON T1.player_id = T2.winner_id ORDER BY T2.match_number DESC LIMIT 1
  Gold: SELECT winner_name, loser_name FROM matches ORDER BY minutes DESC LIMIT 1
  Type: ORDER_BY, LIMIT

[284] OTHER | DB: wta_1 | EX: ✗
  Q   : Find the average ranking for each player and their first name
  Pred: SELECT AVG(ranking), T1.first_name FROM players AS T1 JOIN rankings AS T2 ON T1.player_id = T2.player_id GROUP BY T1.player_id
  Gold: SELECT AVG(ranking), T1.first_name FROM players AS T1 JOIN rankings AS T2 ON T1.player_id = T2.player_id GROUP BY T1.first_name
  Type: JOIN, GROUP_BY, AGGREGATION

[285] WRONG_COLUMNS | DB: wta_1 | EX: ✗
  Q   : What are the first names of all players, and their average rankings
  Pred: SELECT T1.first_name, AVG(T2.ranking) FROM players AS T1 JOIN rankings AS T2 ON T1.player_id = T2.player_id GROUP BY T1.player_id
  Gold: SELECT AVG(ranking), T1.first_name FROM players AS T1 JOIN rankings AS T2 ON T1.player_id = T2.player_id GROUP BY T1.first_name
  Type: JOIN, GROUP_BY, AGGREGATION

[286] MISSING_JOIN | DB: wta_1 | EX: ✗
  Q   : Find the total ranking points for each player and their first name
  Pred: SELECT SUM(ranking_points), first_name FROM players
  Gold: SELECT SUM(ranking_points), T1.first_name FROM players AS T1 JOIN rankings AS T2 ON T1.player_id = T2.player_id GROUP BY T1.first_name
  Type: JOIN, GROUP_BY, AGGREGATION

[287] WRONG_COLUMNS | DB: wta_1 | EX: ✗
  Q   : What are the first names of all players, and their total ranking points
  Pred: SELECT T1.first_name, SUM(T2.ranking_points) FROM players AS T1 JOIN rankings AS T2 ON T1.player_id = T2.player_id GROUP BY T1.player_id
  Gold: SELECT SUM(ranking_points), T1.first_name FROM players AS T1 JOIN rankings AS T2 ON T1.player_id = T2.player_id GROUP BY T1.first_name
  Type: JOIN, GROUP_BY, AGGREGATION

[288] WRONG_COLUMNS | DB: wta_1 | EX: ✗
  Q   : find the number of players for each country
  Pred: SELECT country_code, COUNT(*) FROM players GROUP BY country_code
  Gold: SELECT COUNT(*), country_code FROM players GROUP BY country_code
  Type: GROUP_BY, AGGREGATION

[289] WRONG_COLUMNS | DB: wta_1 | EX: ✗
  Q   : How many players are from each country
  Pred: SELECT country_code, COUNT(*) FROM players GROUP BY country_code
  Gold: SELECT COUNT(*), country_code FROM players GROUP BY country_code
  Type: GROUP_BY, AGGREGATION

[290] WRONG_COLUMNS | DB: wta_1 | EX: ✗
  Q   : Find the total number of tours for each ranking date
  Pred: SELECT ranking_date, COUNT(*) FROM rankings GROUP BY ranking_date
  Gold: SELECT SUM(tours), ranking_date FROM rankings GROUP BY ranking_date
  Type: GROUP_BY, AGGREGATION

[291] WRONG_COLUMNS | DB: wta_1 | EX: ✗
  Q   : How many matches were played in each year
  Pred: SELECT YEAR, COUNT(*) FROM matches GROUP BY YEAR
  Gold: SELECT COUNT(*), YEAR FROM matches GROUP BY YEAR
  Type: GROUP_BY, AGGREGATION

[292] WRONG_TABLE | DB: wta_1 | EX: ✗
  Q   : Find the name and rank of the 3 youngest winners across all matches
  Pred: SELECT T1.winner_name, T1.winner_rank FROM players AS T1 JOIN matches AS T2 ON T1.winner_id = T2.winner_id ORDER BY T2.winner_age LIMIT 3
  Gold: SELECT DISTINCT winner_name, winner_rank FROM matches ORDER BY winner_age LIMIT 3
  Type: ORDER_BY, LIMIT

[293] WRONG_TABLE | DB: wta_1 | EX: ✗
  Q   : What are the names and ranks of the three youngest winners across all matches
  Pred: SELECT T1.winner_name, T1.winner_rank FROM players AS T1 JOIN matches AS T2 ON T1.winner_id = T2.winner_id ORDER BY T2.winner_age LIMIT 3
  Gold: SELECT DISTINCT winner_name, winner_rank FROM matches ORDER BY winner_age LIMIT 3
  Type: ORDER_BY, LIMIT

[294] WRONG_TABLE | DB: wta_1 | EX: ✗
  Q   : How many different winners both participated in the WTA Championships and were left handed
  Pred: SELECT COUNT(DISTINCT T1.Winner_Name) FROM players AS T1 JOIN matches AS T2 ON T1.Winner_ID = T2.Winner_ID WHERE T1.hand = "left" AND T2.Tournament_name = "WTA Championships"
  Gold: SELECT COUNT(DISTINCT winner_name) FROM matches WHERE tourney_name = 'WTA Championships' AND winner_hand = 'L'
  Type: AGGREGATION

[295] WRONG_TABLE | DB: wta_1 | EX: ✗
  Q   : Find the number of left handed winners who participated in the WTA Championships
  Pred: SELECT COUNT(*) FROM players WHERE winner_hand = "left" AND JOIN matches AS T1 JOIN players AS T2 ON T1.player_id = T2.player_id WHERE T1.tournament_name = "WTA Championships"
  Gold: SELECT COUNT(DISTINCT winner_name) FROM matches WHERE tourney_name = 'WTA Championships' AND winner_hand = 'L'
  Type: AGGREGATION

[296] WRONG_COLUMNS | DB: wta_1 | EX: ✗
  Q   : Find the first name, country code and birth date of the winner who has the highest rank points in all matches
  Pred: SELECT T1.winner_name, T1.country_code, T1.birth_date FROM players AS T1 JOIN matches AS T2 ON T1.winner_id = T2.winner_id ORDER BY T2.winner_rank_points DESC LIMIT 1
  Gold: SELECT T1.first_name, T1.country_code, T1.birth_date FROM players AS T1 JOIN matches AS T2 ON T1.player_id = T2.winner_id ORDER BY T2.winner_rank_points DESC LIMIT 1
  Type: JOIN, ORDER_BY, LIMIT

[297] OTHER | DB: wta_1 | EX: ✗
  Q   : What is the first name, country code, and birth date of the player with the most winner rank points across all matches
  Pred: SELECT T1.first_name, T1.country_code, T1.birth_date FROM players AS T1 JOIN matches AS T2 ON T1.player_id = T2.winner_id GROUP BY T1.player_id ORDER BY COUNT(*) DESC LIMIT 1
  Gold: SELECT T1.first_name, T1.country_code, T1.birth_date FROM players AS T1 JOIN matches AS T2 ON T1.player_id = T2.winner_id ORDER BY T2.winner_rank_points DESC LIMIT 1
  Type: JOIN, ORDER_BY, LIMIT

[298] WRONG_COLUMNS | DB: wta_1 | EX: ✗
  Q   : Find the number of players for each hand type
  Pred: SELECT hand, COUNT(*) FROM players GROUP BY hand
  Gold: SELECT COUNT(*), hand FROM players GROUP BY hand
  Type: GROUP_BY, AGGREGATION

[299] WRONG_COLUMNS | DB: wta_1 | EX: ✗
  Q   : How many players are there for each hand type
  Pred: SELECT DISTINCT hand, COUNT(*) FROM players GROUP BY hand
  Gold: SELECT COUNT(*), hand FROM players GROUP BY hand
  Type: GROUP_BY, AGGREGATION

[300] WRONG_COLUMNS | DB: battle_death | EX: ✗
  Q   : List the name, date and result of each battle
  Pred: SELECT name, date, result FROM battle
  Gold: SELECT name, date FROM battle
  Type: SIMPLE

[301] WRONG_COLUMNS | DB: battle_death | EX: ✗
  Q   : What is maximum and minimum death toll caused each time
  Pred: SELECT MAX(dead), MIN(dead) FROM death
  Gold: SELECT MAX(killed), MIN(killed) FROM death
  Type: AGGREGATION

[302] OTHER | DB: battle_death | EX: ✗
  Q   : What is the average number of injuries caused each time
  Pred: SELECT AVG(Injured) FROM death GROUP BY Injured
  Gold: SELECT AVG(injured) FROM death
  Type: AGGREGATION

[303] OTHER | DB: battle_death | EX: ✓
  Q   : What are the name and results of the battles when the bulgarian commander is not 'Boril'
  Pred: SELECT name, result FROM battle WHERE bulgarian_commander > 'Boril'
  Gold: SELECT name, RESULT FROM battle WHERE bulgarian_commander <> 'Boril'
  Type: SIMPLE

[304] OTHER | DB: battle_death | EX: ✗
  Q   : What are the different ids and names of the battles that lost any 'Brig' type shipes
  Pred: SELECT DISTINCT T1.id, T1.name FROM battle AS T1 JOIN ship AS T2 ON T1.lost_in_battle = T2.id WHERE T2.ship_type = 'Brig'
  Gold: SELECT DISTINCT T1.id, T1.name FROM battle AS T1 JOIN ship AS T2 ON T1.id = T2.lost_in_battle WHERE T2.ship_type = 'Brig'
  Type: JOIN

[305] OTHER | DB: battle_death | EX: ✗
  Q   : What are the ids and names of the battles that led to more than 10 people killed in total
  Pred: SELECT T1.id, T1.name FROM battle AS T1 JOIN death AS T2 ON T1.id = T2.caused_by_ship_id GROUP BY T1.id HAVING COUNT(*) > 10
  Gold: SELECT T1.id, T1.name FROM battle AS T1 JOIN ship AS T2 ON T1.id = T2.lost_in_battle JOIN death AS T3 ON T2.id = T3.caused_by_ship_id GROUP BY T1.id HAVING SUM(T3.killed) > 10
  Type: JOIN, GROUP_BY, HAVING, AGGREGATION

[306] WRONG_TABLE | DB: battle_death | EX: ✗
  Q   : What is the ship id and name that caused most total injuries
  Pred: SELECT T1.id, T1.name FROM ship AS T1 JOIN death AS T2 ON T1.id = T2.caused_by_ship_id GROUP BY T1.id ORDER BY SUM(T2.injured) DESC LIMIT 1
  Gold: SELECT T2.id, T2.name FROM death AS T1 JOIN ship AS t2 ON T1.caused_by_ship_id = T2.id GROUP BY T2.id ORDER BY COUNT(*) DESC LIMIT 1
  Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, AGGREGATION

[307] EXTRA_JOIN | DB: battle_death | EX: ✗
  Q   : What are the distinct battle names which are between bulgarian commander 'Kaloyan' and latin commander 'Baldwin I'
  Pred: SELECT DISTINCT T1.name FROM battle AS T1 JOIN ship AS T2 ON T1.id = T2.lost_in_battle WHERE T2.bulgarian_commander = 'Kaloyan' INTERSECT SELECT DISTINCT T1.name FROM battle AS T1 JOIN ship AS T2 ON T1.id = T2.lost_in_battle WHERE T2.latin_commander = 'Baldwin I'
  Gold: SELECT name FROM battle WHERE bulgarian_commander = 'Kaloyan' AND latin_commander = 'Baldwin I'
  Type: SIMPLE

[308] OTHER | DB: battle_death | EX: ✗
  Q   : List the name and date the battle that has lost the ship named 'Lettice' and the ship named 'HMS Atalanta'
  Pred: SELECT T1.name, T1.date FROM battle AS T1 JOIN ship AS T2 ON T1.lost_in_battle = T2.id JOIN battle AS T3 ON T2.battle = T3.id WHERE T2.name = 'Lettice' INTERSECT SELECT T1.name, T1.date FROM battle AS T1 JOIN ship AS T2 ON T1.id = T2.lost_in_battle WHERE T2.name = 'HMS Atalanta'
  Gold: SELECT T1.name, T1.date FROM battle AS T1 JOIN ship AS T2 ON T1.id = T2.lost_in_battle WHERE T2.name = 'Lettice' INTERSECT SELECT T1.name, T1.date FROM battle AS T1 JOIN ship AS T2 ON T1.id = T2.lost_in_battle WHERE T2.name = 'HMS Atalanta'
  Type: JOIN

[309] WRONG_TABLE | DB: battle_death | EX: ✓
  Q   : Show names, results and bulgarian commanders of the battles with no ships lost in the 'English Channel'
  Pred: SELECT name, result, bulgarian_commander FROM battle WHERE NOT id IN (SELECT lost_in_battle FROM ship WHERE location = 'English Channel')
  Gold: SELECT name, RESULT, bulgarian_commander FROM battle EXCEPT SELECT T1.name, T1.result, T1.bulgarian_commander FROM battle AS T1 JOIN ship AS T2 ON T1.id = T2.lost_in_battle WHERE T2.location = 'English Channel'
  Type: JOIN

[310] WRONG_COLUMNS | DB: student_transcripts_tracking | EX: ✗
  Q   : what are all the addresses including line 1 and line 2
  Pred: SELECT address FROM addresses WHERE line_1 LIKE '%2' AND line_2 LIKE '%2'
  Gold: SELECT line_1, line_2 FROM addresses
  Type: SIMPLE

[311] EXTRA_JOIN | DB: student_transcripts_tracking | EX: ✗
  Q   : What is the first and second line for all addresses
  Pred: SELECT T1.line_1, T1.line_2 FROM Addresses AS T1 JOIN Students AS T2 ON T1.address_id = T2.address_id
  Gold: SELECT line_1, line_2 FROM addresses
  Type: SIMPLE

[312] WRONG_COLUMNS | DB: student_transcripts_tracking | EX: ✗
  Q   : How many departments offer any degree
  Pred: SELECT COUNT(*) FROM degree_programs
  Gold: SELECT COUNT(DISTINCT department_id) FROM Degree_Programs
  Type: AGGREGATION

[313] WRONG_COLUMNS | DB: student_transcripts_tracking | EX: ✗
  Q   : How many different departments offer degrees
  Pred: SELECT COUNT(DISTINCT department_name) FROM degree_programs
  Gold: SELECT COUNT(DISTINCT department_id) FROM Degree_Programs
  Type: AGGREGATION

[314] WRONG_COLUMNS | DB: student_transcripts_tracking | EX: ✗
  Q   : How many different degree names are offered
  Pred: SELECT COUNT(DISTINCT degree_program_name) FROM degree_programs
  Gold: SELECT COUNT(DISTINCT degree_summary_name) FROM Degree_Programs
  Type: AGGREGATION

[315] WRONG_COLUMNS | DB: student_transcripts_tracking | EX: ✗
  Q   : How many different degrees are offered
  Pred: SELECT COUNT(DISTINCT degree_program_id) FROM degree_programs
  Gold: SELECT COUNT(DISTINCT degree_summary_name) FROM Degree_Programs
  Type: AGGREGATION

[316] WRONG_TABLE | DB: student_transcripts_tracking | EX: ✓
  Q   : How many degrees does the engineering department offer
  Pred: SELECT COUNT(*) FROM degree_programs AS T1 JOIN departments AS T2 ON T1.department_id = T2.department_id WHERE T2.department_name = "engineering"
  Gold: SELECT COUNT(*) FROM Departments AS T1 JOIN Degree_Programs AS T2 ON T1.department_id = T2.department_id WHERE T1.department_name = 'engineer'
  Type: JOIN, AGGREGATION

[317] WRONG_TABLE | DB: student_transcripts_tracking | EX: ✓
  Q   : How many degrees does the engineering department have
  Pred: SELECT COUNT(*) FROM degree_programs AS T1 JOIN departments AS T2 ON T1.department_id = T2.department_id WHERE T2.department_name = "engineering"
  Gold: SELECT COUNT(*) FROM Departments AS T1 JOIN Degree_Programs AS T2 ON T1.department_id = T2.department_id WHERE T1.department_name = 'engineer'
  Type: JOIN, AGGREGATION

[318] OTHER | DB: student_transcripts_tracking | EX: ✗
  Q   : What are the names and id of courses having at most 2 sections
  Pred: SELECT T1.course_name, T1.course_id FROM Courses AS T1 JOIN Sections AS T2 ON T1.course_id = T2.course_id GROUP BY T1.course_id HAVING COUNT(*) = 2
  Gold: SELECT T1.course_name, T1.course_id FROM Courses AS T1 JOIN Sections AS T2 ON T1.course_id = T2.course_id GROUP BY T1.course_id HAVING COUNT(*) <= 2
  Type: JOIN, GROUP_BY, HAVING, AGGREGATION

[319] OTHER | DB: student_transcripts_tracking | EX: ✗
  Q   : What are the names and ids of every course with less than 2 sections
  Pred: SELECT T1.course_name, T1.course_id FROM Courses AS T1 JOIN Sections AS T2 ON T1.course_id = T2.course_id GROUP BY T1.course_id HAVING COUNT(*)  2
  Gold: SELECT T1.course_name, T1.course_id FROM Courses AS T1 JOIN Sections AS T2 ON T1.course_id = T2.course_id GROUP BY T1.course_id HAVING COUNT(*) <= 2
  Type: JOIN, GROUP_BY, HAVING, AGGREGATION

[320] OTHER | DB: student_transcripts_tracking | EX: ✗
  Q   : What are the names of the sections in reverse alphabetical order
  Pred: SELECT section_name FROM SECTIONS ORDER BY section_name ASC
  Gold: SELECT section_name FROM Sections ORDER BY section_name DESC
  Type: ORDER_BY

[321] WRONG_TABLE | DB: student_transcripts_tracking | EX: ✗
  Q   : What is the semester which most student registered in? Show both the name and the id
  Pred: SELECT T1.semester_name, T2.semester_id FROM Student_Enrolment AS T1 JOIN Semesters AS T2 ON T1.semester_id = T2.semester_id GROUP BY T2.semester_id ORDER BY COUNT(*) DESC LIMIT 1
  Gold: SELECT T1.semester_name, T1.semester_id FROM Semesters AS T1 JOIN Student_Enrolment AS T2 ON T1.semester_id = T2.semester_id GROUP BY T1.semester_id ORDER BY COUNT(*) DESC LIMIT 1
  Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, AGGREGATION

[322] WRONG_TABLE | DB: student_transcripts_tracking | EX: ✗
  Q   : Who are enrolled in 2 degree programs in one semester? List the first name, middle name and last name and the id
  Pred: SELECT T1.first_name, T1.middle_name, T1.last_name, T1.student_id FROM Student_Enrolment AS T1 JOIN Semesters AS T2 ON T1.semester_id = T2.semester_id GROUP BY T1.student_enrolment_id HAVING COUNT(*) = 2
  Gold: SELECT T1.first_name, T1.middle_name, T1.last_name, T1.student_id FROM Students AS T1 JOIN Student_Enrolment AS T2 ON T1.student_id = T2.student_id GROUP BY T1.student_id HAVING COUNT(*) = 2
  Type: JOIN, GROUP_BY, HAVING, AGGREGATION

[323] WRONG_TABLE | DB: student_transcripts_tracking | EX: ✗
  Q   : What are the first, middle, and last names, along with the ids, of all students who enrolled in 2 degree programs in one semester
  Pred: SELECT T1.first_name, T1.middle_name, T1.last_name, T1.student_id FROM Student_Enrolment AS T1 JOIN Semesters AS T2 ON T1.student_id = T2.semester_id GROUP BY T1.student_id HAVING COUNT(*) = 2
  Gold: SELECT T1.first_name, T1.middle_name, T1.last_name, T1.student_id FROM Students AS T1 JOIN Student_Enrolment AS T2 ON T1.student_id = T2.student_id GROUP BY T1.student_id HAVING COUNT(*) = 2
  Type: JOIN, GROUP_BY, HAVING, AGGREGATION

[324] WRONG_TABLE | DB: student_transcripts_tracking | EX: ✗
  Q   : Who is enrolled in a Bachelor degree program? List the first name, middle name, last name
  Pred: SELECT T1.first_name, T1.middle_name, T1.last_name FROM Student_Enrolment AS T1 JOIN Degree_Programs AS T2 ON T1.degree_program_id = T2.degree_program_id WHERE T2.degree_summary_name = "Bachelor"
  Gold: SELECT DISTINCT T1.first_name, T1.middle_name, T1.last_name FROM Students AS T1 JOIN Student_Enrolment AS T2 ON T1.student_id = T2.student_id JOIN Degree_Programs AS T3 ON T2.degree_program_id = T3.degree_program_id WHERE T3.degree_summary_name = 'Bachelor'
  Type: JOIN

[325] WRONG_TABLE | DB: student_transcripts_tracking | EX: ✗
  Q   : What are the first, middle, and last names for everybody enrolled in a Bachelors program
  Pred: SELECT T1.first_name, T1.middle_name, T1.last_name FROM Student_Enrolment AS T1 JOIN Degree_Programs AS T2 ON T1.degree_program_id = T2.degree_program_id WHERE T2.degree_summary_name = "Bachelors"
  Gold: SELECT DISTINCT T1.first_name, T1.middle_name, T1.last_name FROM Students AS T1 JOIN Student_Enrolment AS T2 ON T1.student_id = T2.student_id JOIN Degree_Programs AS T3 ON T2.degree_program_id = T3.degree_program_id WHERE T3.degree_summary_name = 'Bachelor'
  Type: JOIN

[326] WRONG_COLUMNS | DB: student_transcripts_tracking | EX: ✗
  Q   : Find the kind of program which most number of students are enrolled in
  Pred: SELECT T1.degree_program_id FROM degree_programs AS T1 JOIN student_enrolment AS T2 ON T1.degree_program_id = T2.degree_program_id GROUP BY T1.degree_program_id ORDER BY COUNT(*) DESC LIMIT 1
  Gold: SELECT T1.degree_summary_name FROM Degree_Programs AS T1 JOIN Student_Enrolment AS T2 ON T1.degree_program_id = T2.degree_program_id GROUP BY T1.degree_summary_name ORDER BY COUNT(*) DESC LIMIT 1
  Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, AGGREGATION

[327] WRONG_TABLE | DB: student_transcripts_tracking | EX: ✗
  Q   : Find the program which most number of students are enrolled in. List both the id and the summary
  Pred: SELECT T1.degree_program_id, T2.degree_summary_name FROM Student_Enrolment AS T1 JOIN Courses AS T2 ON T1.student_id = T2.student_id GROUP BY T1.degree_program_id ORDER BY COUNT(*) DESC LIMIT 1
  Gold: SELECT T1.degree_program_id, T1.degree_summary_name FROM Degree_Programs AS T1 JOIN Student_Enrolment AS T2 ON T1.degree_program_id = T2.degree_program_id GROUP BY T1.degree_program_id ORDER BY COUNT(*) DESC LIMIT 1
  Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, AGGREGATION

[328] WRONG_TABLE | DB: student_transcripts_tracking | EX: ✗
  Q   : Which student has enrolled for the most times in any program? List the id, first name, middle name, last name, the number of enrollments and student id
  Pred: SELECT T1.student_id, T2.first_name, T2.middle_name, T2.last_name, COUNT(*) FROM Student_Enrolment AS T1 JOIN Students AS T2 ON T1.student_id = T2.student_id GROUP BY T1.student_id ORDER BY COUNT(*) DESC LIMIT 1
  Gold: SELECT T1.student_id, T1.first_name, T1.middle_name, T1.last_name, COUNT(*), T1.student_id FROM Students AS T1 JOIN Student_Enrolment AS T2 ON T1.student_id = T2.student_id GROUP BY T1.student_id ORDER BY COUNT(*) DESC LIMIT 1
  Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, AGGREGATION

[329] WRONG_TABLE | DB: student_transcripts_tracking | EX: ✗
  Q   : What is the first, middle, and last name, along with the id and number of enrollments, for the student who enrolled the most in any program
  Pred: SELECT T1.first_name, T1.middle_name, T1.last_name, T1.student_enrolment_id, COUNT(*) FROM Student_Enrolment AS T1 JOIN Students AS T2 ON T1.student_id = T2.student_id GROUP BY T1.student_enrolment_id ORDER BY COUNT(*) DESC LIMIT 1
  Gold: SELECT T1.student_id, T1.first_name, T1.middle_name, T1.last_name, COUNT(*), T1.student_id FROM Students AS T1 JOIN Student_Enrolment AS T2 ON T1.student_id = T2.student_id GROUP BY T1.student_id ORDER BY COUNT(*) DESC LIMIT 1
  Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, AGGREGATION

[330] WRONG_TABLE | DB: student_transcripts_tracking | EX: ✓
  Q   : What is the name of the semester with no students enrolled
  Pred: SELECT semester_name FROM Semesters EXCEPT SELECT T1.semester_name FROM Semesters AS T1 JOIN Student_Enrolment AS T2 ON T1.semester_id = T2.semester_id
  Gold: SELECT semester_name FROM Semesters WHERE NOT semester_id IN (SELECT semester_id FROM Student_Enrolment)
  Type: NESTED

[331] WRONG_COLUMNS | DB: student_transcripts_tracking | EX: ✗
  Q   : What are all the course names of the courses which ever have students enrolled in
  Pred: SELECT T1.course_name FROM Courses AS T1 JOIN Student_Enrolment_Courses AS T2 ON T1.course_id = T2.course_id
  Gold: SELECT DISTINCT T1.course_name FROM Courses AS T1 JOIN Student_Enrolment_Courses AS T2 ON T1.course_id = T2.course_id
  Type: JOIN

[332] WRONG_COLUMNS | DB: student_transcripts_tracking | EX: ✗
  Q   : What are the names of all courses that have some students enrolled
  Pred: SELECT T1.course_name FROM Courses AS T1 JOIN Student_Enrolment_Courses AS T2 ON T1.course_id = T2.course_id
  Gold: SELECT DISTINCT T1.course_name FROM Courses AS T1 JOIN Student_Enrolment_Courses AS T2 ON T1.course_id = T2.course_id
  Type: JOIN

[333] WRONG_COLUMNS | DB: student_transcripts_tracking | EX: ✗
  Q   : Find the last name of the students who currently live in the state of North Carolina but have not registered in any degree program
  Pred: SELECT last_name FROM Students WHERE current_address_id = 'A' AND state_province_county = "North Carolina" EXCEPT SELECT T1.last_name FROM Students AS T1 JOIN Student_Enrolment AS T2 ON T1.student_id = T2.student_id
  Gold: SELECT T1.last_name FROM Students AS T1 JOIN Addresses AS T2 ON T1.current_address_id = T2.address_id WHERE T2.state_province_county = 'NorthCarolina' EXCEPT SELECT DISTINCT T3.last_name FROM Students AS T3 JOIN Student_Enrolment AS T4 ON T3.student_id = T4.student_id
  Type: JOIN

[334] WRONG_COLUMNS | DB: student_transcripts_tracking | EX: ✗
  Q   : What are the last name of the students who live in North Carolina but have not registered in any degree programs
  Pred: SELECT last_name FROM Students WHERE current_address_id = 'North Carolina' EXCEPT SELECT T1.last_name FROM Students AS T1 JOIN Student_Enrolment AS T2 ON T1.student_id = T2.student_id JOIN Degrees AS T3 ON T2.degree_program_id = T3.degree_program_id WHERE T3.state_province_county = "North Carolina"
  Gold: SELECT T1.last_name FROM Students AS T1 JOIN Addresses AS T2 ON T1.current_address_id = T2.address_id WHERE T2.state_province_county = 'NorthCarolina' EXCEPT SELECT DISTINCT T3.last_name FROM Students AS T3 JOIN Student_Enrolment AS T4 ON T3.student_id = T4.student_id
  Type: JOIN

[335] WRONG_TABLE | DB: student_transcripts_tracking | EX: ✗
  Q   : Show the date and id of the transcript with at least 2 course results
  Pred: SELECT T1.transcript_date, T1.transcript_id FROM transcripts AS T1 JOIN courses AS T2 ON T1.course_id = T2.course_id GROUP BY T1.transcript_id HAVING COUNT(*) >= 2
  Gold: SELECT T2.transcript_date, T1.transcript_id FROM Transcript_Contents AS T1 JOIN Transcripts AS T2 ON T1.transcript_id = T2.transcript_id GROUP BY T1.transcript_id HAVING COUNT(*) >= 2
  Type: JOIN, GROUP_BY, HAVING, AGGREGATION

[336] WRONG_TABLE | DB: student_transcripts_tracking | EX: ✗
  Q   : What is the date and id of the transcript with at least 2 courses listed
  Pred: SELECT T1.transcript_date, T1.transcript_id FROM transcripts AS T1 JOIN courses AS T2 ON T1.course_id = T2.course_id GROUP BY T1.transcript_id HAVING COUNT(*) >= 2
  Gold: SELECT T2.transcript_date, T1.transcript_id FROM Transcript_Contents AS T1 JOIN Transcripts AS T2 ON T1.transcript_id = T2.transcript_id GROUP BY T1.transcript_id HAVING COUNT(*) >= 2
  Type: JOIN, GROUP_BY, HAVING, AGGREGATION

[337] WRONG_TABLE | DB: student_transcripts_tracking | EX: ✗
  Q   : What is the phone number of the man with the first name Timmothy and the last name Ward
  Pred: SELECT cell_mobile_number FROM Addresses WHERE first_name = "Timmothy" AND last_name = "Ward"
  Gold: SELECT cell_mobile_number FROM Students WHERE first_name = 'Timmothy' AND last_name = 'Ward'
  Type: SIMPLE

[338] WRONG_TABLE | DB: student_transcripts_tracking | EX: ✗
  Q   : Who is the first student to register? List the first name, middle name and last name
  Pred: SELECT first_name, middle_name, last_name FROM Student_Enrolment
  Gold: SELECT first_name, middle_name, last_name FROM Students ORDER BY date_first_registered ASC LIMIT 1
  Type: ORDER_BY, LIMIT

[339] EXTRA_JOIN | DB: student_transcripts_tracking | EX: ✗
  Q   : What is the first, middle, and last name of the first student to register
  Pred: SELECT T1.first_name, T1.middle_name, T1.last_name FROM Students AS T1 JOIN Student_Enrolment AS T2 ON T1.student_id = T2.student_id
  Gold: SELECT first_name, middle_name, last_name FROM Students ORDER BY date_first_registered ASC LIMIT 1
  Type: ORDER_BY, LIMIT

[340] WRONG_TABLE | DB: student_transcripts_tracking | EX: ✗
  Q   : Who is the earliest graduate of the school? List the first name, middle name and last name
  Pred: SELECT first_name, middle_name, last_name FROM Student_Enrolment ORDER BY date_first_registered LIMIT 1
  Gold: SELECT first_name, middle_name, last_name FROM Students ORDER BY date_left ASC LIMIT 1
  Type: ORDER_BY, LIMIT

[341] WRONG_TABLE | DB: student_transcripts_tracking | EX: ✗
  Q   : What is the first, middle, and last name of the earliest school graduate
  Pred: SELECT first_name, middle_name, last_name FROM Student_Enrolment ORDER BY date_first_registered LIMIT 1
  Gold: SELECT first_name, middle_name, last_name FROM Students ORDER BY date_left ASC LIMIT 1
  Type: ORDER_BY, LIMIT

[342] EXTRA_JOIN | DB: student_transcripts_tracking | EX: ✗
  Q   : Whose permanent address is different from his or her current address? List his or her first name
  Pred: SELECT T1.first_name FROM Students AS T1 JOIN Addresses AS T2 ON T1.permanent_address_id = T2.address_id WHERE T2.current_address_id > T2.address_id
  Gold: SELECT first_name FROM Students WHERE current_address_id <> permanent_address_id
  Type: SIMPLE

[343] EXTRA_JOIN | DB: student_transcripts_tracking | EX: ✗
  Q   : What is the first name of the student whose permanent address is different from his or her current one
  Pred: SELECT T1.first_name FROM Students AS T1 JOIN Students AS T2 ON T1.student_id = T2.student_id WHERE T2.permanent_address_id > T2.current_address_id
  Gold: SELECT first_name FROM Students WHERE current_address_id <> permanent_address_id
  Type: SIMPLE

[344] WRONG_COLUMNS | DB: student_transcripts_tracking | EX: ✗
  Q   : Which address holds the most number of students currently? List the address id and all lines
  Pred: SELECT T1.address_id, T1.line_3 FROM addresses AS T1 JOIN students AS T2 ON T1.address_id = T2.address_id GROUP BY T1.address_id ORDER BY COUNT(*) DESC LIMIT 1
  Gold: SELECT T1.address_id, T1.line_1, T1.line_2 FROM Addresses AS T1 JOIN Students AS T2 ON T1.address_id = T2.current_address_id GROUP BY T1.address_id ORDER BY COUNT(*) DESC LIMIT 1
  Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, AGGREGATION

[345] OTHER | DB: student_transcripts_tracking | EX: ✗
  Q   : What is the id, line 1, and line 2 of the address with the most students
  Pred: SELECT T1.address_id, T1.line_1, T1.line_2 FROM Addresses AS T1 JOIN Students AS T2 ON T1.address_id = T2.address_id GROUP BY T1.address_id ORDER BY COUNT(*) DESC LIMIT 1
  Gold: SELECT T1.address_id, T1.line_1, T1.line_2 FROM Addresses AS T1 JOIN Students AS T2 ON T1.address_id = T2.current_address_id GROUP BY T1.address_id ORDER BY COUNT(*) DESC LIMIT 1
  Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, AGGREGATION

[346] EXTRA_JOIN | DB: student_transcripts_tracking | EX: ✓
  Q   : On average, when were the transcripts printed
  Pred: SELECT AVG(T1.transcript_date) FROM transcripts AS T1 JOIN transcripts AS T2 ON T1.transcript_id = T2.transcript_id
  Gold: SELECT AVG(transcript_date) FROM Transcripts
  Type: AGGREGATION

[347] MISSING_ORDER_BY | DB: student_transcripts_tracking | EX: ✗
  Q   : When is the first transcript released? List the date and details
  Pred: SELECT date_first_registered, date_first_details FROM transcripts
  Gold: SELECT transcript_date, other_details FROM Transcripts ORDER BY transcript_date ASC LIMIT 1
  Type: ORDER_BY, LIMIT

[348] MISSING_ORDER_BY | DB: student_transcripts_tracking | EX: ✓
  Q   : What is the earliest date of a transcript release, and what details can you tell me
  Pred: SELECT MIN(transcript_date), other_details FROM transcripts
  Gold: SELECT transcript_date, other_details FROM Transcripts ORDER BY transcript_date ASC LIMIT 1
  Type: ORDER_BY, LIMIT

[349] MISSING_ORDER_BY | DB: student_transcripts_tracking | EX: ✗
  Q   : What is the last transcript release date
  Pred: SELECT date_last FROM transcripts
  Gold: SELECT transcript_date FROM Transcripts ORDER BY transcript_date DESC LIMIT 1
  Type: ORDER_BY, LIMIT

[350] MISSING_ORDER_BY | DB: student_transcripts_tracking | EX: ✗
  Q   : When was the last transcript released
  Pred: SELECT date_last FROM transcripts
  Gold: SELECT transcript_date FROM Transcripts ORDER BY transcript_date DESC LIMIT 1
  Type: ORDER_BY, LIMIT

[351] WRONG_TABLE | DB: student_transcripts_tracking | EX: ✗
  Q   : How many times at most can a course enrollment result show in different transcripts? Also show the course enrollment id
  Pred: SELECT COUNT(*), T1.transcript_id FROM transcripts AS T1 JOIN student_enrolment AS T2 ON T1.transcript_id = T2.transcript_id GROUP BY T1.transcript_id
  Gold: SELECT COUNT(*), student_course_id FROM Transcript_Contents GROUP BY student_course_id ORDER BY COUNT(*) DESC LIMIT 1
  Type: GROUP_BY, ORDER_BY, LIMIT, AGGREGATION

[352] EXTRA_JOIN | DB: student_transcripts_tracking | EX: ✗
  Q   : What is the maximum number of times that a course shows up in different transcripts and what is that course's enrollment id
  Pred: SELECT T1.course_id, MAX(T2.student_enrolment_id) FROM transcript_contents AS T1 JOIN courses AS T2 ON T1.course_id = T2.course_id GROUP BY T1.transcript_id
  Gold: SELECT COUNT(*), student_course_id FROM Transcript_Contents GROUP BY student_course_id ORDER BY COUNT(*) DESC LIMIT 1
  Type: GROUP_BY, ORDER_BY, LIMIT, AGGREGATION

[353] WRONG_TABLE | DB: student_transcripts_tracking | EX: ✗
  Q   : Show the date of the transcript which shows the least number of results, also list the id
  Pred: SELECT transcript_date, transcript_id FROM transcripts GROUP BY transcript_id ORDER BY COUNT(*) ASC LIMIT 1
  Gold: SELECT T2.transcript_date, T1.transcript_id FROM Transcript_Contents AS T1 JOIN Transcripts AS T2 ON T1.transcript_id = T2.transcript_id GROUP BY T1.transcript_id ORDER BY COUNT(*) ASC LIMIT 1
  Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, AGGREGATION

[354] WRONG_TABLE | DB: student_transcripts_tracking | EX: ✗
  Q   : What is the date and id of the transcript with the least number of results
  Pred: SELECT transcript_date, transcript_id FROM transcripts GROUP BY transcript_id ORDER BY COUNT(*) ASC LIMIT 1
  Gold: SELECT T2.transcript_date, T1.transcript_id FROM Transcript_Contents AS T1 JOIN Transcripts AS T2 ON T1.transcript_id = T2.transcript_id GROUP BY T1.transcript_id ORDER BY COUNT(*) ASC LIMIT 1
  Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, AGGREGATION

[355] WRONG_TABLE | DB: student_transcripts_tracking | EX: ✗
  Q   : Find the semester when both Master students and Bachelor students got enrolled in
  Pred: SELECT T1.semester_name FROM Semesters AS T1 JOIN Student_Enrolment AS T2 ON T1.semester_id = T2.semester_id WHERE T2.student_id = 'Master' INTERSECT SELECT T1.semester_name FROM Semesters AS T1 JOIN Student_Enrolment AS T2 ON T1.semester_id = T2.semester_id JOIN Student_Enrolment AS T3 ON
  Gold: SELECT DISTINCT T2.semester_id FROM Degree_Programs AS T1 JOIN Student_Enrolment AS T2 ON T1.degree_program_id = T2.degree_program_id WHERE degree_summary_name = 'Master' INTERSECT SELECT DISTINCT T2.semester_id FROM Degree_Programs AS T1 JOIN Student_Enrolment AS T2 ON T1.degree_program_id = T2.degree_program_id WHERE degree_summary_name = 'Bachelor'
  Type: JOIN

[356] WRONG_TABLE | DB: student_transcripts_tracking | EX: ✗
  Q   : What is the id of the semester that had both Masters and Bachelors students enrolled
  Pred: SELECT semester_id FROM Student_Enrolment WHERE student_id = (SELECT student_id FROM Student_Enrolment WHERE degree_program_id = "Masters") INTERSECT SELECT semester_id FROM Semesters WHERE degree_program_id = "Bachelors")
  Gold: SELECT DISTINCT T2.semester_id FROM Degree_Programs AS T1 JOIN Student_Enrolment AS T2 ON T1.degree_program_id = T2.degree_program_id WHERE degree_summary_name = 'Master' INTERSECT SELECT DISTINCT T2.semester_id FROM Degree_Programs AS T1 JOIN Student_Enrolment AS T2 ON T1.degree_program_id = T2.degree_program_id WHERE degree_summary_name = 'Bachelor'
  Type: JOIN

[357] WRONG_COLUMNS | DB: student_transcripts_tracking | EX: ✗
  Q   : How many different addresses do the students currently live
  Pred: SELECT COUNT(DISTINCT address_id) FROM Students
  Gold: SELECT COUNT(DISTINCT current_address_id) FROM Students
  Type: AGGREGATION

[358] WRONG_TABLE | DB: student_transcripts_tracking | EX: ✗
  Q   : What are the different addresses that have students living there
  Pred: SELECT DISTINCT T1.address FROM addresses AS T1 JOIN students AS T2 ON T1.address_id = T2.permanent_address_id
  Gold: SELECT COUNT(DISTINCT current_address_id) FROM Students
  Type: AGGREGATION

[359] OTHER | DB: student_transcripts_tracking | EX: ✗
  Q   : List all the student details in reversed lexicographical order
  Pred: SELECT other_student_details FROM STUDENTS ORDER BY other_student_details
  Gold: SELECT other_student_details FROM Students ORDER BY other_student_details DESC
  Type: ORDER_BY

[360] WRONG_COLUMNS | DB: student_transcripts_tracking | EX: ✗
  Q   : What other details can you tell me about students in reverse alphabetical order
  Pred: SELECT other_details FROM STUDENTS ORDER BY other_details
  Gold: SELECT other_student_details FROM Students ORDER BY other_student_details DESC
  Type: ORDER_BY

[361] MISSING_JOIN | DB: student_transcripts_tracking | EX: ✓
  Q   : Find the first name of the students who permanently live in the country Haiti or have the cell phone number 09700166582
  Pred: SELECT first_name FROM Students WHERE permanent_address_id = 'Haiti' OR cell_mobile_number = '09700166582'
  Gold: SELECT t1.first_name FROM students AS t1 JOIN addresses AS t2 ON t1.permanent_address_id = t2.address_id WHERE t2.country = 'haiti' OR t1.cell_mobile_number = '09700166582'
  Type: JOIN

[362] MISSING_JOIN | DB: student_transcripts_tracking | EX: ✓
  Q   : What are the first names of the students who live in Haiti permanently or have the cell phone number 09700166582
  Pred: SELECT first_name FROM Students WHERE permanent_address_id = 'Haiti' OR cell_mobile_number = '09700166582'
  Gold: SELECT t1.first_name FROM students AS t1 JOIN addresses AS t2 ON t1.permanent_address_id = t2.address_id WHERE t2.country = 'haiti' OR t1.cell_mobile_number = '09700166582'
  Type: JOIN

[363] WRONG_COLUMNS | DB: tvshow | EX: ✓
  Q   : List all cartoon directed by "Ben Jones"
  Pred: SELECT DISTINCT title FROM cartoon WHERE directed_by = "Ben Jones"
  Gold: SELECT Title FROM Cartoon WHERE Directed_by = "Ben Jones"
  Type: SIMPLE

[364] WRONG_COLUMNS | DB: tvshow | EX: ✗
  Q   : List the number of different series names and contents in the TV Channel table
  Pred: SELECT COUNT(DISTINCT series_name), content FROM tv_channel
  Gold: SELECT COUNT(DISTINCT series_name), COUNT(DISTINCT content) FROM TV_Channel
  Type: AGGREGATION

[365] WRONG_COLUMNS | DB: tvshow | EX: ✗
  Q   : How many different series and contents are listed in the TV Channel table
  Pred: SELECT COUNT(DISTINCT series_name), content FROM tv_channel
  Gold: SELECT COUNT(DISTINCT series_name), COUNT(DISTINCT content) FROM TV_Channel
  Type: AGGREGATION

[366] WRONG_COLUMNS | DB: tvshow | EX: ✗
  Q   : For each language, list the number of TV Channels that use it
  Pred: SELECT COUNT(*), language FROM tv_channel GROUP BY language
  Gold: SELECT LANGUAGE, COUNT(*) FROM TV_Channel GROUP BY LANGUAGE
  Type: GROUP_BY, AGGREGATION

[367] WRONG_COLUMNS | DB: tvshow | EX: ✓
  Q   : What is the TV Channel that shows the cartoon "The Rise of the Blue Beetle!"? List the TV Channel's series name
  Pred: SELECT DISTINCT T1.series_name FROM tv_channel AS T1 JOIN cartoon AS T2 ON T1.id = T2.channel WHERE T2.title = "The Rise of the Blue Beetle!"
  Gold: SELECT T1.series_name FROM TV_Channel AS T1 JOIN Cartoon AS T2 ON T1.id = T2.Channel WHERE T2.Title = "The Rise of the Blue Beetle!"
  Type: JOIN

[368] OTHER | DB: tvshow | EX: ✗
  Q   : What is the series name of the TV Channel that shows the cartoon "The Rise of the Blue Beetle"
  Pred: SELECT t1.series_name FROM tv_channel AS t1 JOIN cartoon AS t2 ON t1.id = t2.channel WHERE t2.title = "The Rise of the Blue Beetle"
  Gold: SELECT T1.series_name FROM TV_Channel AS T1 JOIN Cartoon AS T2 ON T1.id = T2.Channel WHERE T2.Title = "The Rise of the Blue Beetle!"
  Type: JOIN

[369] WRONG_TABLE | DB: tvshow | EX: ✗
  Q   : List the title of all Cartoons showed on TV Channel with series name "Sky Radio"
  Pred: SELECT DISTINCT T1.title FROM cartoon AS T1 JOIN tv_channel AS T2 ON T1.id = T2.channel WHERE T2.series_name = "Sky Radio"
  Gold: SELECT T2.Title FROM TV_Channel AS T1 JOIN Cartoon AS T2 ON T1.id = T2.Channel WHERE T1.series_name = "Sky Radio"
  Type: JOIN

[370] WRONG_TABLE | DB: tvshow | EX: ✗
  Q   : What is the title of all the cartools that are on the TV Channel with the series name "Sky Radio"
  Pred: SELECT t1.title FROM cartoon AS t1 JOIN tv_channel AS t2 ON t1.id = t2.channel WHERE t2.series_name = "Sky Radio"
  Gold: SELECT T2.Title FROM TV_Channel AS T1 JOIN Cartoon AS T2 ON T1.id = T2.Channel WHERE T1.series_name = "Sky Radio"
  Type: JOIN

[371] EXTRA_JOIN | DB: tvshow | EX: ✗
  Q   : List top 3 highest Rating TV series. List the TV series's Episode and Rating
  Pred: SELECT T1.episode, T1.rating FROM tv_series AS T1 JOIN tv_series AS T2 ON T1.id = T2.series ORDER BY T2.rating DESC LIMIT 3
  Gold: SELECT Episode, Rating FROM TV_series ORDER BY Rating DESC LIMIT 3
  Type: ORDER_BY, LIMIT

[372] EXTRA_JOIN | DB: tvshow | EX: ✗
  Q   : What are 3 most highly rated episodes in the TV series table and what were those ratings
  Pred: SELECT t1.episode, t1.rating FROM tv_series AS t1 JOIN tv_series AS t2 ON t1.id = t2.series_id GROUP BY t1.id ORDER BY COUNT(*) DESC LIMIT 3
  Gold: SELECT Episode, Rating FROM TV_series ORDER BY Rating DESC LIMIT 3
  Type: ORDER_BY, LIMIT

[373] WRONG_COLUMNS | DB: tvshow | EX: ✗
  Q   : What is minimum and maximum share of TV series
  Pred: SELECT MIN(share), MAX(share) FROM tv_series
  Gold: SELECT MAX(SHARE), MIN(SHARE) FROM TV_series
  Type: AGGREGATION

[374] EXTRA_JOIN | DB: tvshow | EX: ✗
  Q   : What is the air date of TV series with Episode "A Love of a Lifetime"
  Pred: SELECT T1.air_date FROM tv_series AS T1 JOIN cartoon AS T2 ON T1.id = T2.channel WHERE T2.series_name = "A Love of a Lifetime"
  Gold: SELECT Air_Date FROM TV_series WHERE Episode = "A Love of a Lifetime"
  Type: SIMPLE

[375] WRONG_TABLE | DB: tvshow | EX: ✗
  Q   : When did the episode "A Love of a Lifetime" air
  Pred: SELECT air_date FROM cartoon WHERE title = "A Love of a Lifetime"
  Gold: SELECT Air_Date FROM TV_series WHERE Episode = "A Love of a Lifetime"
  Type: SIMPLE

[376] WRONG_TABLE | DB: tvshow | EX: ✗
  Q   : What is the weekly rank for the episode "A Love of a Lifetime"
  Pred: SELECT weekly_rank FROM cartoon WHERE title = "A Love of a Lifetime"
  Gold: SELECT Weekly_Rank FROM TV_series WHERE Episode = "A Love of a Lifetime"
  Type: SIMPLE

[377] WRONG_COLUMNS | DB: tvshow | EX: ✗
  Q   : What is the TV Channel of TV series with Episode "A Love of a Lifetime"? List the TV Channel's series name
  Pred: SELECT DISTINCT T1.series_name FROM tv_channel AS T1 JOIN tv_series AS T2 ON T1.id = T2.series WHERE T2.episode = "A Love of a Lifetime"
  Gold: SELECT T1.series_name FROM TV_Channel AS T1 JOIN TV_series AS T2 ON T1.id = T2.Channel WHERE T2.Episode = "A Love of a Lifetime"
  Type: JOIN

[378] WRONG_TABLE | DB: tvshow | EX: ✗
  Q   : What is the name of the series that has the episode "A Love of a Lifetime"
  Pred: SELECT tv_series_name FROM cartoon WHERE episode = "A Love of a Lifetime"
  Gold: SELECT T1.series_name FROM TV_Channel AS T1 JOIN TV_series AS T2 ON T1.id = T2.Channel WHERE T2.Episode = "A Love of a Lifetime"
  Type: JOIN

[379] OTHER | DB: tvshow | EX: ✗
  Q   : List the Episode of all TV series showed on TV Channel with series name "Sky Radio"
  Pred: SELECT T2.episode FROM tv_channel AS T1 JOIN tv_series AS T2 ON T1.id = T2.channel WHERE T2.series_name = "Sky Radio"
  Gold: SELECT T2.Episode FROM TV_Channel AS T1 JOIN TV_series AS T2 ON T1.id = T2.Channel WHERE T1.series_name = "Sky Radio"
  Type: JOIN

[380] WRONG_TABLE | DB: tvshow | EX: ✗
  Q   : What is the episode for the TV series named "Sky Radio"
  Pred: SELECT T1.episode FROM tv_series AS T1 JOIN cartoon AS T2 ON T1.id = T2.channel WHERE T2.series_name = "Sky Radio"
  Gold: SELECT T2.Episode FROM TV_Channel AS T1 JOIN TV_series AS T2 ON T1.id = T2.Channel WHERE T1.series_name = "Sky Radio"
  Type: JOIN

[381] EXTRA_JOIN | DB: tvshow | EX: ✗
  Q   : Find the package choice and series name of the TV channel that has high definition TV
  Pred: SELECT t2.package_option, t2.series_name FROM tv_channel AS t1 JOIN tv_series AS t2 ON t1.id = t2.series WHERE t1.hight_definition_tv = 'yes'
  Gold: SELECT package_option, series_name FROM TV_Channel WHERE hight_definition_TV = "yes"
  Type: SIMPLE

[382] EXTRA_JOIN | DB: tvshow | EX: ✗
  Q   : What are the package options and the name of the series for the TV Channel that supports high definition TV
  Pred: SELECT DISTINCT T1.package_option, T1.series_name FROM tv_channel AS T1 JOIN tv_series AS T2 ON T1.id = T2.series WHERE T1.hight_definition_tv = 'Hight'
  Gold: SELECT package_option, series_name FROM TV_Channel WHERE hight_definition_TV = "yes"
  Type: SIMPLE

[383] WRONG_TABLE | DB: tvshow | EX: ✗
  Q   : What are the countries that are not playing cartoons written by Todd Casey
  Pred: SELECT country FROM cartoon EXCEPT SELECT T1.country FROM cartoon AS T1 JOIN cartoon AS T2 ON T1.id = T2.channel WHERE T2.written_by = 'Todd Casey'
  Gold: SELECT country FROM TV_Channel EXCEPT SELECT T1.country FROM TV_Channel AS T1 JOIN cartoon AS T2 ON T1.id = T2.Channel WHERE T2.written_by = 'Todd Casey'
  Type: JOIN

[384] OTHER | DB: tvshow | EX: ✓
  Q   : Find the series name and country of the tv channel that is playing some cartoons directed by Ben Jones and Michael Chang
  Pred: SELECT T1.series_name, T1.country FROM tv_channel AS T1 JOIN cartoon AS T2 ON T1.id = T2.channel WHERE T2.directed_by = 'Ben Jones' INTERSECT SELECT T1.series_name, T1.country FROM tv_channel AS T1 JOIN cartoon AS T2 ON T1.id = T2.channel WHERE T2.directed_by = 'Michael Chang'
  Gold: SELECT T1.series_name, T1.country FROM TV_Channel AS T1 JOIN cartoon AS T2 ON T1.id = T2.Channel WHERE T2.directed_by = 'Michael Chang' INTERSECT SELECT T1.series_name, T1.country FROM TV_Channel AS T1 JOIN cartoon AS T2 ON T1.id = T2.Channel WHERE T2.directed_by = 'Ben Jones'
  Type: JOIN

[385] OTHER | DB: tvshow | EX: ✓
  Q   : What is the series name and country of all TV channels that are playing cartoons directed by Ben Jones and cartoons directed by Michael Chang
  Pred: SELECT T1.series_name, T1.country FROM tv_channel AS T1 JOIN cartoon AS T2 ON T1.id = T2.channel WHERE T2.directed_by = 'Ben Jones' INTERSECT SELECT T1.series_name, T1.country FROM tv_channel AS T1 JOIN cartoon AS T2 ON T1.id = T2.channel WHERE T2.directed_by = 'Michael Chang'
  Gold: SELECT T1.series_name, T1.country FROM TV_Channel AS T1 JOIN cartoon AS T2 ON T1.id = T2.Channel WHERE T2.directed_by = 'Michael Chang' INTERSECT SELECT T1.series_name, T1.country FROM TV_Channel AS T1 JOIN cartoon AS T2 ON T1.id = T2.Channel WHERE T2.directed_by = 'Ben Jones'
  Type: JOIN

[386] OTHER | DB: tvshow | EX: ✗
  Q   : find the pixel aspect ratio and nation of the tv channels that do not use English
  Pred: SELECT pixel_aspect_ratio_par, country FROM tv_channel WHERE language > "english"
  Gold: SELECT Pixel_aspect_ratio_PAR, country FROM tv_channel WHERE LANGUAGE <> 'English'
  Type: SIMPLE

[387] OTHER | DB: tvshow | EX: ✗
  Q   : What is the pixel aspect ratio and country of origin for all TV channels that do not use English
  Pred: SELECT pixel_aspect_ratio_par, country FROM tv_channel WHERE language > 'english'
  Gold: SELECT Pixel_aspect_ratio_PAR, country FROM tv_channel WHERE LANGUAGE <> 'English'
  Type: SIMPLE

[388] EXTRA_JOIN | DB: tvshow | EX: ✗
  Q   : find id of the tv channels that from the countries where have more than two tv channels
  Pred: SELECT t1.id FROM tv_channel AS t1 JOIN cartoon AS t2 ON t1.id = t2.channel GROUP BY t2.country HAVING COUNT(*) > 2
  Gold: SELECT id FROM tv_channel GROUP BY country HAVING COUNT(*) > 2
  Type: GROUP_BY, HAVING, AGGREGATION

[389] OTHER | DB: tvshow | EX: ✗
  Q   : What are the ids of all tv channels that have more than 2 TV channels
  Pred: SELECT id FROM tv_channel GROUP BY id HAVING COUNT(*) > 2
  Gold: SELECT id FROM tv_channel GROUP BY country HAVING COUNT(*) > 2
  Type: GROUP_BY, HAVING, AGGREGATION

[390] WRONG_TABLE | DB: tvshow | EX: ✗
  Q   : find the id of tv channels that do not play any cartoon directed by Ben Jones
  Pred: SELECT tv_channel FROM tv_channel EXCEPT SELECT t1.id FROM tv_channel AS t1 JOIN cartoon AS t2 ON t1.id = t2.channel WHERE t2.directed_by = "Ben Jones"
  Gold: SELECT id FROM TV_Channel EXCEPT SELECT channel FROM cartoon WHERE directed_by = 'Ben Jones'
  Type: SIMPLE

[391] WRONG_TABLE | DB: tvshow | EX: ✗
  Q   : What are the ids of the TV channels that do not have any cartoons directed by Ben Jones
  Pred: SELECT tv_channel FROM tv_channel EXCEPT SELECT t1.id FROM tv_channel AS t1 JOIN cartoon AS t2 ON t1.id = t2.channel WHERE t2.directed_by = "Ben Jones"
  Gold: SELECT id FROM TV_Channel EXCEPT SELECT channel FROM cartoon WHERE directed_by = 'Ben Jones'
  Type: SIMPLE

[392] WRONG_TABLE | DB: tvshow | EX: ✗
  Q   : find the package option of the tv channel that do not have any cartoon directed by Ben Jones
  Pred: SELECT package_option FROM tv_channel EXCEPT SELECT t1.channel FROM tv_channel AS t1 JOIN cartoon AS t2 ON t1.id = t2.channel WHERE t2.directed_by = "Ben Jones"
  Gold: SELECT package_option FROM TV_Channel WHERE NOT id IN (SELECT channel FROM cartoon WHERE directed_by = 'Ben Jones')
  Type: NESTED

[393] WRONG_TABLE | DB: tvshow | EX: ✗
  Q   : What are the package options of all tv channels that are not playing any cartoons directed by Ben Jones
  Pred: SELECT package_option FROM tv_channel EXCEPT SELECT t1.channel FROM tv_channel AS t1 JOIN cartoon AS t2 ON t1.id = t2.channel WHERE t2.directed_by = "Ben Jones"
  Gold: SELECT package_option FROM TV_Channel WHERE NOT id IN (SELECT channel FROM cartoon WHERE directed_by = 'Ben Jones')
  Type: NESTED

[394] EXTRA_JOIN | DB: poker_player | EX: ✗
  Q   : What are the final tables made and best finishes for all poker players
  Pred: SELECT T2.Final_Table_Made, T2.Best_finish FROM poker_player AS T1 JOIN people AS T2 ON T1.People_ID = T2.People_ID
  Gold: SELECT Final_Table_Made, Best_Finish FROM poker_player
  Type: SIMPLE

[395] EXTRA_JOIN | DB: poker_player | EX: ✗
  Q   : What is the maximum number of final tables made among poker players with earnings less than 200000
  Pred: SELECT MAX(T2.Final_Table_Made) FROM poker_player AS T1 JOIN people AS T2 ON T1.People_ID = T2.People_ID WHERE T1.Earnings  200000
  Gold: SELECT MAX(Final_Table_Made) FROM poker_player WHERE Earnings < 200000
  Type: AGGREGATION

[396] EXTRA_JOIN | DB: poker_player | EX: ✗
  Q   : Return the maximum final tables made across all poker players who have earnings below 200000
  Pred: SELECT MAX(T2.Final_Table_Made) FROM poker_player AS T1 JOIN people AS T2 ON T1.People_ID = T2.People_ID WHERE T1.Earnings  200000
  Gold: SELECT MAX(Final_Table_Made) FROM poker_player WHERE Earnings < 200000
  Type: AGGREGATION

[397] WRONG_TABLE | DB: poker_player | EX: ✓
  Q   : What are the names of poker players
  Pred: SELECT T2.Name FROM poker_player AS T1 JOIN people AS T2 ON T1.People_ID = T2.People_ID
  Gold: SELECT T1.Name FROM people AS T1 JOIN poker_player AS T2 ON T1.People_ID = T2.People_ID
  Type: JOIN

[398] WRONG_TABLE | DB: poker_player | EX: ✓
  Q   : Return the names of all the poker players
  Pred: SELECT T2.Name FROM poker_player AS T1 JOIN people AS T2 ON T1.People_ID = T2.People_ID
  Gold: SELECT T1.Name FROM people AS T1 JOIN poker_player AS T2 ON T1.People_ID = T2.People_ID
  Type: JOIN

[399] WRONG_TABLE | DB: poker_player | EX: ✓
  Q   : What are the names of poker players whose earnings is higher than 300000
  Pred: SELECT T2.Name FROM poker_player AS T1 JOIN people AS T2 ON T1.People_ID = T2.People_ID WHERE T1.Earnings > 300000
  Gold: SELECT T1.Name FROM people AS T1 JOIN poker_player AS T2 ON T1.People_ID = T2.People_ID WHERE T2.Earnings > 300000
  Type: JOIN

[400] WRONG_TABLE | DB: poker_player | EX: ✓
  Q   : Give the names of poker players who have earnings above 300000
  Pred: SELECT T2.Name FROM poker_player AS T1 JOIN people AS T2 ON T1.People_ID = T2.People_ID WHERE T1.Earnings > 300000
  Gold: SELECT T1.Name FROM people AS T1 JOIN poker_player AS T2 ON T1.People_ID = T2.People_ID WHERE T2.Earnings > 300000
  Type: JOIN

[401] WRONG_TABLE | DB: poker_player | EX: ✓
  Q   : List the names of poker players ordered by the final tables made in ascending order
  Pred: SELECT T2.Name FROM poker_player AS T1 JOIN people AS T2 ON T1.People_ID = T2.People_ID ORDER BY T1.Final_Table_Made ASC
  Gold: SELECT T1.Name FROM people AS T1 JOIN poker_player AS T2 ON T1.People_ID = T2.People_ID ORDER BY T2.Final_Table_Made
  Type: JOIN, ORDER_BY

[402] WRONG_TABLE | DB: poker_player | EX: ✓
  Q   : What are the names of poker players, ordered ascending by the number of final tables they have made
  Pred: SELECT T2.Name FROM poker_player AS T1 JOIN people AS T2 ON T1.People_ID = T2.People_ID ORDER BY T1.Final_Table_Made
  Gold: SELECT T1.Name FROM people AS T1 JOIN poker_player AS T2 ON T1.People_ID = T2.People_ID ORDER BY T2.Final_Table_Made
  Type: JOIN, ORDER_BY

[403] WRONG_TABLE | DB: poker_player | EX: ✓
  Q   : What is the birth date of the poker player with the lowest earnings
  Pred: SELECT T2.Birth_Date FROM poker_player AS T1 JOIN people AS T2 ON T1.People_ID = T2.People_ID ORDER BY T1.Earnings LIMIT 1
  Gold: SELECT T1.Birth_Date FROM people AS T1 JOIN poker_player AS T2 ON T1.People_ID = T2.People_ID ORDER BY T2.Earnings ASC LIMIT 1
  Type: JOIN, ORDER_BY, LIMIT

[404] WRONG_TABLE | DB: poker_player | EX: ✓
  Q   : Return the birth date of the poker player with the lowest earnings
  Pred: SELECT T2.Birth_Date FROM poker_player AS T1 JOIN people AS T2 ON T1.People_ID = T2.People_ID ORDER BY T1.Earnings LIMIT 1
  Gold: SELECT T1.Birth_Date FROM people AS T1 JOIN poker_player AS T2 ON T1.People_ID = T2.People_ID ORDER BY T2.Earnings ASC LIMIT 1
  Type: JOIN, ORDER_BY, LIMIT

[405] WRONG_TABLE | DB: poker_player | EX: ✗
  Q   : What is the money rank of the tallest poker player
  Pred: SELECT Money_Rank FROM poker_player ORDER BY Height DESC LIMIT 1
  Gold: SELECT T2.Money_Rank FROM people AS T1 JOIN poker_player AS T2 ON T1.People_ID = T2.People_ID ORDER BY T1.Height DESC LIMIT 1
  Type: JOIN, ORDER_BY, LIMIT

[406] WRONG_TABLE | DB: poker_player | EX: ✗
  Q   : Return the money rank of the poker player with the greatest height
  Pred: SELECT Money_Rank FROM poker_player ORDER BY Height DESC LIMIT 1
  Gold: SELECT T2.Money_Rank FROM people AS T1 JOIN poker_player AS T2 ON T1.People_ID = T2.People_ID ORDER BY T1.Height DESC LIMIT 1
  Type: JOIN, ORDER_BY, LIMIT

[407] WRONG_TABLE | DB: poker_player | EX: ✗
  Q   : What is the average earnings of poker players with height higher than 200
  Pred: SELECT AVG(Earnings) FROM poker_player WHERE Height > 200
  Gold: SELECT AVG(T2.Earnings) FROM people AS T1 JOIN poker_player AS T2 ON T1.People_ID = T2.People_ID WHERE T1.Height > 200
  Type: JOIN, AGGREGATION

[408] WRONG_TABLE | DB: poker_player | EX: ✓
  Q   : Give average earnings of poker players who are taller than 200
  Pred: SELECT AVG(Earnings) FROM poker_player AS T1 JOIN people AS T2 ON T1.People_ID = T2.People_ID WHERE T2.Height > 200
  Gold: SELECT AVG(T2.Earnings) FROM people AS T1 JOIN poker_player AS T2 ON T1.People_ID = T2.People_ID WHERE T1.Height > 200
  Type: JOIN, AGGREGATION

[409] WRONG_TABLE | DB: poker_player | EX: ✓
  Q   : What are the names of poker players in descending order of earnings
  Pred: SELECT T2.Name FROM poker_player AS T1 JOIN people AS T2 ON T1.People_ID = T2.People_ID ORDER BY T1.Earnings DESC
  Gold: SELECT T1.Name FROM people AS T1 JOIN poker_player AS T2 ON T1.People_ID = T2.People_ID ORDER BY T2.Earnings DESC
  Type: JOIN, ORDER_BY

[410] WRONG_TABLE | DB: poker_player | EX: ✓
  Q   : Return the names of poker players sorted by their earnings descending
  Pred: SELECT T2.Name FROM poker_player AS T1 JOIN people AS T2 ON T1.People_ID = T2.People_ID ORDER BY T1.Earnings DESC
  Gold: SELECT T1.Name FROM people AS T1 JOIN poker_player AS T2 ON T1.People_ID = T2.People_ID ORDER BY T2.Earnings DESC
  Type: JOIN, ORDER_BY

[411] OTHER | DB: poker_player | EX: ✗
  Q   : Show names of people whose nationality is not "Russia"
  Pred: SELECT Name FROM people WHERE Nationality > 'Russia'
  Gold: SELECT Name FROM people WHERE Nationality <> "Russia"
  Type: SIMPLE

[412] OTHER | DB: poker_player | EX: ✗
  Q   : What are the names of people who are not from Russia
  Pred: SELECT Name FROM people WHERE Nationality > 'Russia'
  Gold: SELECT Name FROM people WHERE Nationality <> "Russia"
  Type: SIMPLE

[413] WRONG_TABLE | DB: voter_1 | EX: ✗
  Q   : What are the maximum and minimum values of area codes
  Pred: SELECT MAX(area_code), MIN(area_code) FROM area_code
  Gold: SELECT MAX(area_code), MIN(area_code) FROM area_code_state
  Type: AGGREGATION

[414] WRONG_COLUMNS | DB: voter_1 | EX: ✓
  Q   : What is last date created of votes from the state 'CA'
  Pred: SELECT created FROM votes WHERE state = 'CA'
  Gold: SELECT MAX(created) FROM votes WHERE state = 'CA'
  Type: AGGREGATION

[415] OTHER | DB: voter_1 | EX: ✓
  Q   : What are the names of the contestants whose names are not 'Jessie Alloway'
  Pred: SELECT contestant_name FROM contestants EXCEPT SELECT contestant_name FROM contestants WHERE contestant_name = 'Jessie Alloway'
  Gold: SELECT contestant_name FROM contestants WHERE contestant_name <> 'Jessie Alloway'
  Type: SIMPLE

[416] WRONG_TABLE | DB: voter_1 | EX: ✓
  Q   : What are the contestant numbers and names of the contestants who had at least two votes
  Pred: SELECT T2.contestant_number, T2.contestant_name FROM votes AS T1 JOIN contestants AS T2 ON T1.contestant_number = T2.contestant_number GROUP BY T2.contestant_number HAVING COUNT(*) >= 2
  Gold: SELECT T1.contestant_number, T1.contestant_name FROM contestants AS T1 JOIN votes AS T2 ON T1.contestant_number = T2.contestant_number GROUP BY T1.contestant_number HAVING COUNT(*) >= 2
  Type: JOIN, GROUP_BY, HAVING, AGGREGATION

[417] WRONG_TABLE | DB: voter_1 | EX: ✗
  Q   : Of all the contestants who got voted, what is the contestant number and name of the contestant who got least votes
  Pred: SELECT T2.contestant_number, T2.contestant_name FROM votes AS T1 JOIN contestants AS T2 ON T1.contestant_number = T2.contestant_number ORDER BY T1.votes ASC LIMIT 1
  Gold: SELECT T1.contestant_number, T1.contestant_name FROM contestants AS T1 JOIN votes AS T2 ON T1.contestant_number = T2.contestant_number GROUP BY T1.contestant_number ORDER BY COUNT(*) ASC LIMIT 1
  Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, AGGREGATION

[418] WRONG_TABLE | DB: voter_1 | EX: ✗
  Q   : What is the area code in which the most voters voted
  Pred: SELECT area_code FROM votes GROUP BY area_code_state ORDER BY COUNT(*) DESC LIMIT 1
  Gold: SELECT T1.area_code FROM area_code_state AS T1 JOIN votes AS T2 ON T1.state = T2.state GROUP BY T1.area_code ORDER BY COUNT(*) DESC LIMIT 1
  Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, AGGREGATION

[419] WRONG_TABLE | DB: voter_1 | EX: ✓
  Q   : What are the create dates, states, and phone numbers of the votes that were for the contestant named 'Tabatha Gehling'
  Pred: SELECT T1.created, T1.state, T1.phone_number FROM votes AS T1 JOIN contestants AS T2 ON T1.contestant_number = T2.contestant_number WHERE T2.contestant_name = 'Tabatha Gehling'
  Gold: SELECT T2.created, T2.state, T2.phone_number FROM contestants AS T1 JOIN votes AS T2 ON T1.contestant_number = T2.contestant_number WHERE T1.contestant_name = 'Tabatha Gehling'
  Type: JOIN

[420] WRONG_TABLE | DB: voter_1 | EX: ✗
  Q   : List the area codes in which voters voted both for the contestant 'Tabatha Gehling' and the contestant 'Kelly Clauss'
  Pred: SELECT T1.area_code FROM votes AS T1 JOIN contestants AS T2 ON T1.contestant_number = T2.contestant_number WHERE T2.contestant_name = 'Tabatha Gehling' INTERSECT SELECT T1.area_code FROM votes AS T1 JOIN contestants AS T2 ON T1.contestant_number = T2.contestant_number WHERE T2.contestant_name = 'Kelly Clauss'
  Gold: SELECT T3.area_code FROM contestants AS T1 JOIN votes AS T2 ON T1.contestant_number = T2.contestant_number JOIN area_code_state AS T3 ON T2.state = T3.state WHERE T1.contestant_name = 'Tabatha Gehling' INTERSECT SELECT T3.area_code FROM contestants AS T1 JOIN votes AS T2 ON T1.contestant_number = T2.contestant_number JOIN area_code_state AS T3 ON T2.state = T3.state WHERE T1.contestant_name = 'Kelly Clauss'
  Type: JOIN

[421] OTHER | DB: world_1 | EX: ✗
  Q   : What is the total surface area of the countries in the Caribbean region
  Pred: SELECT SUM(surfacearea) FROM country WHERE region = 'Carribbean'
  Gold: SELECT SUM(SurfaceArea) FROM country WHERE Region = "Caribbean"
  Type: AGGREGATION

[422] OTHER | DB: world_1 | EX: ✗
  Q   : How much surface area do the countires in the Carribean cover together
  Pred: SELECT SUM(surfacearea) FROM country WHERE region = 'Carribean'
  Gold: SELECT SUM(SurfaceArea) FROM country WHERE Region = "Caribbean"
  Type: AGGREGATION

[423] WRONG_TABLE | DB: world_1 | EX: ✗
  Q   : Which region is the city Kabul located in
  Pred: SELECT region FROM city WHERE name = 'Kabul'
  Gold: SELECT Region FROM country AS T1 JOIN city AS T2 ON T1.Code = T2.CountryCode WHERE T2.Name = "Kabul"
  Type: JOIN

[424] WRONG_TABLE | DB: world_1 | EX: ✗
  Q   : What region is Kabul in
  Pred: SELECT region FROM city WHERE name = 'Kabul'
  Gold: SELECT Region FROM country AS T1 JOIN city AS T2 ON T1.Code = T2.CountryCode WHERE T2.Name = "Kabul"
  Type: JOIN

[425] WRONG_COLUMNS | DB: world_1 | EX: ✗
  Q   : Which language is the most popular in Aruba
  Pred: SELECT T1.language FROM country AS T1 JOIN countrylanguage AS T2 ON T1.countrycode = T2.countrycode WHERE T2.name = 'Aruba' GROUP BY T1.language ORDER BY COUNT(*) DESC LIMIT 1
  Gold: SELECT T2.Language FROM country AS T1 JOIN countrylanguage AS T2 ON T1.Code = T2.CountryCode WHERE T1.Name = "Aruba" ORDER BY Percentage DESC LIMIT 1
  Type: JOIN, ORDER_BY, LIMIT

[426] WRONG_TABLE | DB: world_1 | EX: ✗
  Q   : What language is predominantly spoken in Aruba
  Pred: SELECT language FROM countrylanguage WHERE countrycode = 'Aruba' GROUP BY language HAVING COUNT(*) >= 1
  Gold: SELECT T2.Language FROM country AS T1 JOIN countrylanguage AS T2 ON T1.Code = T2.CountryCode WHERE T1.Name = "Aruba" ORDER BY Percentage DESC LIMIT 1
  Type: JOIN, ORDER_BY, LIMIT

[427] WRONG_COLUMNS | DB: world_1 | EX: ✗
  Q   : What are the region and population of Angola
  Pred: SELECT region, population FROM country WHERE countrycode = 'Angola'
  Gold: SELECT Population, Region FROM country WHERE Name = "Angola"
  Type: SIMPLE

[428] EXTRA_JOIN | DB: world_1 | EX: ✗
  Q   : What region does Angola belong to and what is its population
  Pred: SELECT T1.region, T2.population FROM country AS T1 JOIN city AS T2 ON T1.countrycode = T2.code WHERE T1.name = 'Angola'
  Gold: SELECT Population, Region FROM country WHERE Name = "Angola"
  Type: SIMPLE

[429] MISSING_WHERE | DB: world_1 | EX: ✗
  Q   : What is the name of country that has the shortest life expectancy in Asia
  Pred: SELECT name FROM country ORDER BY lifeexpectancy ASC LIMIT 1
  Gold: SELECT Name FROM country WHERE Continent = "Asia" ORDER BY LifeExpectancy LIMIT 1
  Type: ORDER_BY, LIMIT

[430] OTHER | DB: world_1 | EX: ✗
  Q   : Give the name of the country in Asia with the lowest life expectancy
  Pred: SELECT name FROM country WHERE region = 'Asia' ORDER BY lifeexpectancy LIMIT 1
  Gold: SELECT Name FROM country WHERE Continent = "Asia" ORDER BY LifeExpectancy LIMIT 1
  Type: ORDER_BY, LIMIT

[431] OTHER | DB: world_1 | EX: ✗
  Q   : What is the total population and maximum GNP in Asia
  Pred: SELECT SUM(population), MAX(gnp) FROM country WHERE region = 'Asie'
  Gold: SELECT SUM(Population), MAX(GNP) FROM country WHERE Continent = "Asia"
  Type: AGGREGATION

[432] EXTRA_JOIN | DB: world_1 | EX: ✗
  Q   : How many people live in Asia, and what is the largest GNP among them
  Pred: SELECT T1.population, T1.gnp FROM country AS T1 JOIN country AS T2 ON T1.countrycode = T2.code WHERE T2.region = 'Asia' ORDER BY T1.gnp DESC LIMIT 1
  Gold: SELECT SUM(Population), MAX(GNP) FROM country WHERE Continent = "Asia"
  Type: AGGREGATION

[433] WRONG_COLUMNS | DB: world_1 | EX: ✗
  Q   : What is the average life expectancy in African countries that are republics
  Pred: SELECT AVG(lifeexpectancy) FROM country WHERE region = "Africa" INTERSECT SELECT countrycode FROM country WHERE region = "Republica"
  Gold: SELECT AVG(LifeExpectancy) FROM country WHERE Continent = "Africa" AND GovernmentForm = "Republic"
  Type: AGGREGATION

[434] OTHER | DB: world_1 | EX: ✗
  Q   : Give the average life expectancy for countries in Africa which are republics
  Pred: SELECT AVG(lifeexpectancy) FROM country WHERE region = 'Africa' AND region = 'Republica'
  Gold: SELECT AVG(LifeExpectancy) FROM country WHERE Continent = "Africa" AND GovernmentForm = "Republic"
  Type: AGGREGATION

[435] OTHER | DB: world_1 | EX: ✗
  Q   : What is the total surface area of the continents Asia and Europe
  Pred: SELECT SUM(surfacearea) FROM country WHERE continent = 'Asie' INTERSECT SELECT SUM(surfacearea) FROM country WHERE region = 'Europe'
  Gold: SELECT SUM(SurfaceArea) FROM country WHERE Continent = "Asia" OR Continent = "Europe"
  Type: AGGREGATION

[436] OTHER | DB: world_1 | EX: ✗
  Q   : Give the total surface area covered by countries in Asia or Europe
  Pred: SELECT SUM(surfacearea) FROM country WHERE region = 'Asie' OR region = 'Europe'
  Gold: SELECT SUM(SurfaceArea) FROM country WHERE Continent = "Asia" OR Continent = "Europe"
  Type: AGGREGATION

[437] OTHER | DB: world_1 | EX: ✗
  Q   : Give the mean GNP and total population of nations which are considered US territory
  Pred: SELECT AVG(gnp), SUM(population) FROM country WHERE countrycode = 'USA'
  Gold: SELECT AVG(GNP), SUM(population) FROM country WHERE GovernmentForm = "US Territory"
  Type: AGGREGATION

[438] WRONG_COLUMNS | DB: world_1 | EX: ✗
  Q   : What is the total number of languages used in Aruba
  Pred: SELECT COUNT(*) FROM country AS T1 JOIN countrylanguage AS T2 ON T1.countrycode = T2.countrycode WHERE T1.name = 'Aruba'
  Gold: SELECT COUNT(T2.Language) FROM country AS T1 JOIN countrylanguage AS T2 ON T1.Code = T2.CountryCode WHERE T1.Name = "Aruba"
  Type: JOIN, AGGREGATION

[439] WRONG_COLUMNS | DB: world_1 | EX: ✗
  Q   : How many languages are spoken in Aruba
  Pred: SELECT COUNT(*) FROM country AS T1 JOIN countrylanguage AS T2 ON T1.countrycode = T2.countrycode WHERE T1.name = 'Aruba'
  Gold: SELECT COUNT(T2.Language) FROM country AS T1 JOIN countrylanguage AS T2 ON T1.Code = T2.CountryCode WHERE T1.Name = "Aruba"
  Type: JOIN, AGGREGATION

[440] OTHER | DB: world_1 | EX: ✗
  Q   : How many official languages does Afghanistan have
  Pred: SELECT COUNT(*) FROM country AS T1 JOIN countrylanguage AS T2 ON T1.countrycode = T2.code WHERE T1.region = "Afghanistan"
  Gold: SELECT COUNT(*) FROM country AS T1 JOIN countrylanguage AS T2 ON T1.Code = T2.CountryCode WHERE T1.Name = "Afghanistan" AND IsOfficial = "T"
  Type: JOIN, AGGREGATION

[441] OTHER | DB: world_1 | EX: ✗
  Q   : How many official languages are spoken in Afghanistan
  Pred: SELECT COUNT(*) FROM country AS T1 JOIN countrylanguage AS T2 ON T1.countrycode = T2.code WHERE T1.region = "Afghanistan"
  Gold: SELECT COUNT(*) FROM country AS T1 JOIN countrylanguage AS T2 ON T1.Code = T2.CountryCode WHERE T1.Name = "Afghanistan" AND IsOfficial = "T"
  Type: JOIN, AGGREGATION

[442] OTHER | DB: world_1 | EX: ✗
  Q   : What is name of the country that speaks the largest number of languages
  Pred: SELECT T1.name FROM country AS T1 JOIN countrylanguage AS T2 ON T1.countrycode = T2.code GROUP BY T1.name ORDER BY COUNT(*) DESC LIMIT 1
  Gold: SELECT T1.Name FROM country AS T1 JOIN countrylanguage AS T2 ON T1.Code = T2.CountryCode GROUP BY T1.Name ORDER BY COUNT(*) DESC LIMIT 1
  Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, AGGREGATION

[443] OTHER | DB: world_1 | EX: ✗
  Q   : Give the name of the nation that uses the greatest amount of languages
  Pred: SELECT T1.name FROM country AS T1 JOIN countrylanguage AS T2 ON T1.countrycode = T2.code GROUP BY T1.countrycode ORDER BY COUNT(*) DESC LIMIT 1
  Gold: SELECT T1.Name FROM country AS T1 JOIN countrylanguage AS T2 ON T1.Code = T2.CountryCode GROUP BY T1.Name ORDER BY COUNT(*) DESC LIMIT 1
  Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, AGGREGATION

[444] MISSING_JOIN | DB: world_1 | EX: ✓
  Q   : Which continent has the most diverse languages
  Pred: SELECT continent FROM country GROUP BY continent ORDER BY COUNT(*) DESC LIMIT 1
  Gold: SELECT T1.Continent FROM country AS T1 JOIN countrylanguage AS T2 ON T1.Code = T2.CountryCode GROUP BY T1.Continent ORDER BY COUNT(*) DESC LIMIT 1
  Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, AGGREGATION

[445] MISSING_JOIN | DB: world_1 | EX: ✓
  Q   : Which continent speaks the most languages
  Pred: SELECT continent FROM country GROUP BY continent ORDER BY COUNT(*) DESC LIMIT 1
  Gold: SELECT T1.Continent FROM country AS T1 JOIN countrylanguage AS T2 ON T1.Code = T2.CountryCode GROUP BY T1.Continent ORDER BY COUNT(*) DESC LIMIT 1
  Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, AGGREGATION

[446] WRONG_TABLE | DB: world_1 | EX: ✗
  Q   : How many countries speak both English and Dutch
  Pred: SELECT COUNT(*) FROM countrylanguage WHERE language = 'english' INTERSECT SELECT COUNT(*) FROM countrylanguage WHERE language = 'Dutch'
  Gold: SELECT COUNT(*) FROM (SELECT T1.Name FROM country AS T1 JOIN countrylanguage AS T2 ON T1.Code = T2.CountryCode WHERE T2.Language = "English" INTERSECT SELECT T1.Name FROM country AS T1 JOIN countrylanguage AS T2 ON T1.Code = T2.CountryCode WHERE T2.Language = "Dutch")
  Type: JOIN, NESTED, AGGREGATION

[447] WRONG_TABLE | DB: world_1 | EX: ✗
  Q   : What is the number of nations that use English and Dutch
  Pred: SELECT COUNT(*) FROM countrylanguage WHERE language = 'english' INTERSECT SELECT COUNT(*) FROM countrylanguage WHERE language = 'Dutch'
  Gold: SELECT COUNT(*) FROM (SELECT T1.Name FROM country AS T1 JOIN countrylanguage AS T2 ON T1.Code = T2.CountryCode WHERE T2.Language = "English" INTERSECT SELECT T1.Name FROM country AS T1 JOIN countrylanguage AS T2 ON T1.Code = T2.CountryCode WHERE T2.Language = "Dutch")
  Type: JOIN, NESTED, AGGREGATION

[448] WRONG_TABLE | DB: world_1 | EX: ✗
  Q   : What are the names of nations speak both English and French
  Pred: SELECT name FROM countrylanguage WHERE language = 'english' INTERSECT SELECT name FROM countrylanguage WHERE language = 'french'
  Gold: SELECT T1.Name FROM country AS T1 JOIN countrylanguage AS T2 ON T1.Code = T2.CountryCode WHERE T2.Language = "English" INTERSECT SELECT T1.Name FROM country AS T1 JOIN countrylanguage AS T2 ON T1.Code = T2.CountryCode WHERE T2.Language = "French"
  Type: JOIN

[449] OTHER | DB: world_1 | EX: ✗
  Q   : Give the names of nations that speak both English and French
  Pred: SELECT T1.name FROM country AS T1 JOIN countrylanguage AS T2 ON T1.countrycode = T2.code WHERE T2.language = 'english' INTERSECT SELECT T1.name FROM country AS T1 JOIN countrylanguage AS T2 ON T1.countrycode = T2.countrycode WHERE T2.language = 'french'
  Gold: SELECT T1.Name FROM country AS T1 JOIN countrylanguage AS T2 ON T1.Code = T2.CountryCode WHERE T2.Language = "English" INTERSECT SELECT T1.Name FROM country AS T1 JOIN countrylanguage AS T2 ON T1.Code = T2.CountryCode WHERE T2.Language = "French"
  Type: JOIN

[450] OTHER | DB: world_1 | EX: ✗
  Q   : What are the names of nations where both English and French are official languages
  Pred: SELECT T1.name FROM country AS T1 JOIN countrylanguage AS T2 ON T1.countrycode = T2.code WHERE T2.language = 'english' INTERSECT SELECT T1.name FROM country AS T1 JOIN countrylanguage AS T2 ON T1.countrycode = T2.countrycode WHERE T2.language = 'french'
  Gold: SELECT T1.Name FROM country AS T1 JOIN countrylanguage AS T2 ON T1.Code = T2.CountryCode WHERE T2.Language = "English" AND T2.IsOfficial = "T" INTERSECT SELECT T1.Name FROM country AS T1 JOIN countrylanguage AS T2 ON T1.Code = T2.CountryCode WHERE T2.Language = "French" AND T2.IsOfficial = "T"
  Type: JOIN

[451] OTHER | DB: world_1 | EX: ✗
  Q   : Give the names of countries with English and French as official languages
  Pred: SELECT T1.name FROM country AS T1 JOIN countrylanguage AS T2 ON T1.countrycode = T2.code WHERE T2.language = 'english' INTERSECT SELECT T1.name FROM country AS T1 JOIN countrylanguage AS T2 ON T1.countrycode = T2.countrycode WHERE T2.language = 'french'
  Gold: SELECT T1.Name FROM country AS T1 JOIN countrylanguage AS T2 ON T1.Code = T2.CountryCode WHERE T2.Language = "English" AND T2.IsOfficial = "T" INTERSECT SELECT T1.Name FROM country AS T1 JOIN countrylanguage AS T2 ON T1.Code = T2.CountryCode WHERE T2.Language = "French" AND T2.IsOfficial = "T"
  Type: JOIN

[452] MISSING_JOIN | DB: world_1 | EX: ✗
  Q   : What is the number of distinct continents where Chinese is spoken
  Pred: SELECT COUNT(DISTINCT continent) FROM country WHERE language = 'Chinese'
  Gold: SELECT COUNT(DISTINCT Continent) FROM country AS T1 JOIN countrylanguage AS T2 ON T1.Code = T2.CountryCode WHERE T2.Language = "Chinese"
  Type: JOIN, AGGREGATION

[453] MISSING_JOIN | DB: world_1 | EX: ✗
  Q   : How many continents speak Chinese
  Pred: SELECT COUNT(DISTINCT continent) FROM country WHERE language = 'Chinese'
  Gold: SELECT COUNT(DISTINCT Continent) FROM country AS T1 JOIN countrylanguage AS T2 ON T1.Code = T2.CountryCode WHERE T2.Language = "Chinese"
  Type: JOIN, AGGREGATION

[454] MISSING_JOIN | DB: world_1 | EX: ✗
  Q   : What are the regions that use English or Dutch
  Pred: SELECT region FROM country WHERE language = "english" OR language = "Dutch"
  Gold: SELECT DISTINCT T1.Region FROM country AS T1 JOIN countrylanguage AS T2 ON T1.Code = T2.CountryCode WHERE T2.Language = "English" OR T2.Language = "Dutch"
  Type: JOIN

[455] MISSING_JOIN | DB: world_1 | EX: ✗
  Q   : Which regions speak Dutch or English
  Pred: SELECT region FROM country WHERE language = 'Dutch' OR language = 'english'
  Gold: SELECT DISTINCT T1.Region FROM country AS T1 JOIN countrylanguage AS T2 ON T1.Code = T2.CountryCode WHERE T2.Language = "English" OR T2.Language = "Dutch"
  Type: JOIN

[456] OTHER | DB: world_1 | EX: ✗
  Q   : What are the countries where either English or Dutch is the official language
  Pred: SELECT T1.name FROM country AS T1 JOIN countrylanguage AS T2 ON T1.countrycode = T2.code WHERE T2.language = 'English' OR T2.language = 'Dutch'
  Gold: SELECT t1.name FROM country AS t1 JOIN countrylanguage AS t2 ON t1.code = t2.countrycode WHERE t2.language = "english" AND isofficial = "t" UNION SELECT t1.name FROM country AS t1 JOIN countrylanguage AS t2 ON t1.code = t2.countrycode WHERE t2.language = "dutch" AND isofficial = "t"
  Type: JOIN

[457] WRONG_COLUMNS | DB: world_1 | EX: ✗
  Q   : Which countries have either English or Dutch as an official language
  Pred: SELECT T1.name FROM country AS T1 JOIN countrylanguage AS T2 ON T1.countrycode = T2.code WHERE T2.language = 'english' OR T2.language = 'Dutch'
  Gold: SELECT * FROM country AS T1 JOIN countrylanguage AS T2 ON T1.Code = T2.CountryCode WHERE T2.Language = "English" AND IsOfficial = "T" UNION SELECT * FROM country AS T1 JOIN countrylanguage AS T2 ON T1.Code = T2.CountryCode WHERE T2.Language = "Dutch" AND IsOfficial = "T"
  Type: JOIN

[458] MISSING_JOIN | DB: world_1 | EX: ✗
  Q   : Which language is the most popular on the Asian continent
  Pred: SELECT language FROM country WHERE continent = 'Asian' GROUP BY language ORDER BY COUNT(*) DESC LIMIT 1
  Gold: SELECT T2.Language FROM country AS T1 JOIN countrylanguage AS T2 ON T1.Code = T2.CountryCode WHERE T1.Continent = "Asia" GROUP BY T2.Language ORDER BY COUNT(*) DESC LIMIT 1
  Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, AGGREGATION

[459] WRONG_TABLE | DB: world_1 | EX: ✗
  Q   : What is the language that is used by the largest number of Asian nations
  Pred: SELECT language FROM countrylanguage WHERE region = "Asian" GROUP BY language ORDER BY COUNT(*) DESC LIMIT 1
  Gold: SELECT T2.Language FROM country AS T1 JOIN countrylanguage AS T2 ON T1.Code = T2.CountryCode WHERE T1.Continent = "Asia" GROUP BY T2.Language ORDER BY COUNT(*) DESC LIMIT 1
  Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, AGGREGATION

[460] MISSING_JOIN | DB: world_1 | EX: ✗
  Q   : Which languages are spoken by only one country in republic governments
  Pred: SELECT countrylanguage FROM country WHERE governmentform = 'Republic' GROUP BY countrylanguage HAVING COUNT(*) = 1
  Gold: SELECT T2.Language FROM country AS T1 JOIN countrylanguage AS T2 ON T1.Code = T2.CountryCode WHERE T1.GovernmentForm = "Republic" GROUP BY T2.Language HAVING COUNT(*) = 1
  Type: JOIN, GROUP_BY, HAVING, AGGREGATION

[461] MISSING_JOIN | DB: world_1 | EX: ✗
  Q   : What languages are only used by a single country with a republic government
  Pred: SELECT countrylanguage FROM country WHERE governmentform = 'Republic' GROUP BY countrylanguage HAVING COUNT(*) = 1
  Gold: SELECT T2.Language FROM country AS T1 JOIN countrylanguage AS T2 ON T1.Code = T2.CountryCode WHERE T1.GovernmentForm = "Republic" GROUP BY T2.Language HAVING COUNT(*) = 1
  Type: JOIN, GROUP_BY, HAVING, AGGREGATION

[462] MISSING_JOIN | DB: world_1 | EX: ✗
  Q   : Find the city with the largest population that uses English
  Pred: SELECT name FROM city WHERE language = 'english' ORDER BY population DESC LIMIT 1
  Gold: SELECT T1.Name, T1.Population FROM city AS T1 JOIN countrylanguage AS T2 ON T1.CountryCode = T2.CountryCode WHERE T2.Language = "English" ORDER BY T1.Population DESC LIMIT 1
  Type: JOIN, ORDER_BY, LIMIT

[463] MISSING_JOIN | DB: world_1 | EX: ✗
  Q   : What is the most populace city that speaks English
  Pred: SELECT name FROM city WHERE language = "english" GROUP BY name ORDER BY COUNT(*) DESC LIMIT 1
  Gold: SELECT T1.Name, T1.Population FROM city AS T1 JOIN countrylanguage AS T2 ON T1.CountryCode = T2.CountryCode WHERE T2.Language = "English" ORDER BY T1.Population DESC LIMIT 1
  Type: JOIN, ORDER_BY, LIMIT

[464] OTHER | DB: world_1 | EX: ✗
  Q   : Find the name, population and expected life length of asian country with the largest area
  Pred: SELECT name, population, lifeexpectancy FROM country WHERE region = "Asian" ORDER BY surfacearea DESC LIMIT 1
  Gold: SELECT Name, Population, LifeExpectancy FROM country WHERE Continent = "Asia" ORDER BY SurfaceArea DESC LIMIT 1
  Type: ORDER_BY, LIMIT

[465] OTHER | DB: world_1 | EX: ✗
  Q   : What are the name, population, and life expectancy of the largest Asian country by land
  Pred: SELECT name, population, lifeexpectancy FROM country WHERE region = 'Asian' ORDER BY surfacearea DESC LIMIT 1
  Gold: SELECT Name, Population, LifeExpectancy FROM country WHERE Continent = "Asia" ORDER BY SurfaceArea DESC LIMIT 1
  Type: ORDER_BY, LIMIT

[466] MISSING_JOIN | DB: world_1 | EX: ✗
  Q   : What is average life expectancy in the countries where English is not the official language
  Pred: SELECT AVG(lifeexpectancy) FROM country WHERE language > 'english'
  Gold: SELECT AVG(LifeExpectancy) FROM country WHERE NOT Name IN (SELECT T1.Name FROM country AS T1 JOIN countrylanguage AS T2 ON T1.Code = T2.CountryCode WHERE T2.Language = "English" AND T2.IsOfficial = "T")
  Type: JOIN, NESTED, AGGREGATION

[467] MISSING_JOIN | DB: world_1 | EX: ✗
  Q   : Give the mean life expectancy of countries in which English is not the official language
  Pred: SELECT AVG(lifeexpectancy) FROM country WHERE language > 'english'
  Gold: SELECT AVG(LifeExpectancy) FROM country WHERE NOT Name IN (SELECT T1.Name FROM country AS T1 JOIN countrylanguage AS T2 ON T1.Code = T2.CountryCode WHERE T2.Language = "English" AND T2.IsOfficial = "T")
  Type: JOIN, NESTED, AGGREGATION

[468] MISSING_JOIN | DB: world_1 | EX: ✗
  Q   : What is the total number of people living in the nations that do not use English
  Pred: SELECT SUM(population) FROM country WHERE language > 'english'
  Gold: SELECT SUM(Population) FROM country WHERE NOT Name IN (SELECT T1.Name FROM country AS T1 JOIN countrylanguage AS T2 ON T1.Code = T2.CountryCode WHERE T2.Language = "English")
  Type: JOIN, NESTED, AGGREGATION

[469] MISSING_JOIN | DB: world_1 | EX: ✗
  Q   : How many people live in countries that do not speak English
  Pred: SELECT COUNT(population) FROM country WHERE language > 'english'
  Gold: SELECT SUM(Population) FROM country WHERE NOT Name IN (SELECT T1.Name FROM country AS T1 JOIN countrylanguage AS T2 ON T1.Code = T2.CountryCode WHERE T2.Language = "English")
  Type: JOIN, NESTED, AGGREGATION

[470] WRONG_TABLE | DB: world_1 | EX: ✗
  Q   : What is the official language spoken in the country whose head of state is Beatrix
  Pred: SELECT T1.language FROM countrylanguage AS T1 JOIN country AS T2 ON T1.countrycode = T2.code WHERE T2.headofstate = 'Beatrix'
  Gold: SELECT T2.Language FROM country AS T1 JOIN countrylanguage AS T2 ON T1.Code = T2.CountryCode WHERE T1.HeadOfState = "Beatrix" AND T2.IsOfficial = "T"
  Type: JOIN

[471] WRONG_TABLE | DB: world_1 | EX: ✗
  Q   : What is the official language used in the country the name of whose head of state is Beatrix
  Pred: SELECT T1.language FROM countrylanguage AS T1 JOIN country AS T2 ON T1.countrycode = T2.code WHERE T2.headofstate = 'Beatrix'
  Gold: SELECT T2.Language FROM country AS T1 JOIN countrylanguage AS T2 ON T1.Code = T2.CountryCode WHERE T1.HeadOfState = "Beatrix" AND T2.IsOfficial = "T"
  Type: JOIN

[472] WRONG_COLUMNS | DB: world_1 | EX: ✗
  Q   : What is the total number of unique official languages spoken in the countries that are founded before 1930
  Pred: SELECT COUNT(DISTINCT T1.isofficial) FROM country AS T1 JOIN countrylanguage AS T2 ON T1.countrycode = T2.code WHERE T1.indepyear  1930
  Gold: SELECT COUNT(DISTINCT T2.Language) FROM country AS T1 JOIN countrylanguage AS T2 ON T1.Code = T2.CountryCode WHERE IndepYear < 1930 AND T2.IsOfficial = "T"
  Type: JOIN, AGGREGATION

[473] WRONG_TABLE | DB: world_1 | EX: ✗
  Q   : For the countries founded before 1930, what is the total number of distinct official languages
  Pred: SELECT COUNT(DISTINCT language) FROM countrycode WHERE indepyear  1930
  Gold: SELECT COUNT(DISTINCT T2.Language) FROM country AS T1 JOIN countrylanguage AS T2 ON T1.Code = T2.CountryCode WHERE IndepYear < 1930 AND T2.IsOfficial = "T"
  Type: JOIN, AGGREGATION

[474] WRONG_COLUMNS | DB: world_1 | EX: ✗
  Q   : What are the countries that have greater surface area than any country in Europe
  Pred: SELECT name FROM country WHERE surfacearea > (SELECT MAX(surfacearea) FROM country WHERE continent = 'Europe')
  Gold: SELECT Name FROM country WHERE SurfaceArea > (SELECT MIN(SurfaceArea) FROM country WHERE Continent = "Europe")
  Type: NESTED, AGGREGATION

[475] WRONG_COLUMNS | DB: world_1 | EX: ✗
  Q   : Which countries have greater area than that of any country in Europe
  Pred: SELECT name FROM country WHERE surfacearea > (SELECT MAX(surfacearea) FROM country WHERE region = 'Europe')
  Gold: SELECT Name FROM country WHERE SurfaceArea > (SELECT MIN(SurfaceArea) FROM country WHERE Continent = "Europe")
  Type: NESTED, AGGREGATION

[476] OTHER | DB: world_1 | EX: ✗
  Q   : What are the African countries that have a population less than any country in Asia
  Pred: SELECT name FROM country WHERE region = "Asia" AND population  (SELECT MAX(population) FROM country WHERE region = "Africa")
  Gold: SELECT Name FROM country WHERE Continent = "Africa" AND population < (SELECT MAX(population) FROM country WHERE Continent = "Asia")
  Type: NESTED, AGGREGATION

[477] WRONG_COLUMNS | DB: world_1 | EX: ✗
  Q   : Which African countries have a smaller population than that of any country in Asia
  Pred: SELECT name FROM country WHERE region = 'Asia' AND population  (SELECT MAX(population) FROM country WHERE region = 'Africa')
  Gold: SELECT Name FROM country WHERE Continent = "Africa" AND population < (SELECT MIN(population) FROM country WHERE Continent = "Asia")
  Type: NESTED, AGGREGATION

[478] OTHER | DB: world_1 | EX: ✗
  Q   : Which Asian countries have a population that is larger than any country in Africa
  Pred: SELECT name FROM country WHERE region = "Asia" AND population > (SELECT MAX(population) FROM country WHERE continent = "Africa")
  Gold: SELECT Name FROM country WHERE Continent = "Asia" AND population > (SELECT MAX(population) FROM country WHERE Continent = "Africa")
  Type: NESTED, AGGREGATION

[479] WRONG_COLUMNS | DB: world_1 | EX: ✗
  Q   : What are the Asian countries which have a population larger than that of any country in Africa
  Pred: SELECT name FROM country WHERE region = "Asia" AND population > (SELECT MAX(population) FROM country WHERE continent = "Africa")
  Gold: SELECT Name FROM country WHERE Continent = "Asia" AND population > (SELECT MIN(population) FROM country WHERE Continent = "Africa")
  Type: NESTED, AGGREGATION

[480] WRONG_TABLE | DB: world_1 | EX: ✗
  Q   : What are the country codes for countries that do not speak English
  Pred: SELECT countrycode FROM country WHERE language > 'english'
  Gold: SELECT CountryCode FROM countrylanguage EXCEPT SELECT CountryCode FROM countrylanguage WHERE LANGUAGE = "English"
  Type: SIMPLE

[481] WRONG_TABLE | DB: world_1 | EX: ✗
  Q   : Return the country codes for countries that do not speak English
  Pred: SELECT countrycode FROM country WHERE language > 'english'
  Gold: SELECT CountryCode FROM countrylanguage EXCEPT SELECT CountryCode FROM countrylanguage WHERE LANGUAGE = "English"
  Type: SIMPLE

[482] WRONG_TABLE | DB: world_1 | EX: ✗
  Q   : What are the country codes of countries where people use languages other than English
  Pred: SELECT countrycode FROM country WHERE language > 'english'
  Gold: SELECT DISTINCT CountryCode FROM countrylanguage WHERE LANGUAGE <> "English"
  Type: SIMPLE

[483] WRONG_COLUMNS | DB: world_1 | EX: ✗
  Q   : Give the country codes for countries in which people speak langauges that are not English
  Pred: SELECT countrycode FROM countrylanguage WHERE language > 'english'
  Gold: SELECT DISTINCT CountryCode FROM countrylanguage WHERE LANGUAGE <> "English"
  Type: SIMPLE

[484] WRONG_TABLE | DB: world_1 | EX: ✗
  Q   : What are the codes of the countries that do not speak English and whose government forms are not Republic
  Pred: SELECT countrycode FROM country WHERE language > 'english' AND governmentform > 'Republic'
  Gold: SELECT Code FROM country WHERE GovernmentForm <> "Republic" EXCEPT SELECT CountryCode FROM countrylanguage WHERE LANGUAGE = "English"
  Type: SIMPLE

[485] WRONG_TABLE | DB: world_1 | EX: ✗
  Q   : Return the codes of countries that do not speak English and do not have Republics for governments
  Pred: SELECT countrycode FROM country WHERE language > 'english' EXCEPT SELECT countrycode FROM country WHERE governmentform = 'Republic'
  Gold: SELECT Code FROM country WHERE GovernmentForm <> "Republic" EXCEPT SELECT CountryCode FROM countrylanguage WHERE LANGUAGE = "English"
  Type: SIMPLE

[486] WRONG_TABLE | DB: world_1 | EX: ✗
  Q   : Which cities are in European countries where English is not the official language
  Pred: SELECT T1.name FROM city AS T1 JOIN country AS T2 ON T1.countrycode = T2.code WHERE T2.language = 'European' EXCEPT SELECT T1.name FROM city AS T1 JOIN countrylanguage AS T2 ON T1.countrycode = T2.countrycode WHERE T2.language = 'english'
  Gold: SELECT DISTINCT T2.Name FROM country AS T1 JOIN city AS T2 ON T2.CountryCode = T1.Code WHERE T1.Continent = 'Europe' AND NOT T1.Name IN (SELECT T3.Name FROM country AS T3 JOIN countrylanguage AS T4 ON T3.Code = T4.CountryCode WHERE T4.IsOfficial = 'T' AND T4.Language = 'English')
  Type: JOIN, NESTED

[487] WRONG_TABLE | DB: world_1 | EX: ✗
  Q   : What are the names of cities in Europe for which English is not the official language
  Pred: SELECT DISTINCT T1.localname FROM city AS T1 JOIN country AS T2 ON T1.countrycode = T2.code WHERE T2.name = 'Europe' AND T2.language > 'english'
  Gold: SELECT DISTINCT T2.Name FROM country AS T1 JOIN city AS T2 ON T2.CountryCode = T1.Code WHERE T1.Continent = 'Europe' AND NOT T1.Name IN (SELECT T3.Name FROM country AS T3 JOIN countrylanguage AS T4 ON T3.Code = T4.CountryCode WHERE T4.IsOfficial = 'T' AND T4.Language = 'English')
  Type: JOIN, NESTED

[488] WRONG_TABLE | DB: world_1 | EX: ✗
  Q   : Which unique cities are in Asian countries where Chinese is the official language
  Pred: SELECT DISTINCT T1.name FROM city AS T1 JOIN country AS T2 ON T1.countrycode = T2.code JOIN countrylanguage AS T3 ON T2.countrycode = T3.countrycode WHERE T3.language = 'Chinese'
  Gold: SELECT DISTINCT t3.name FROM country AS t1 JOIN countrylanguage AS t2 ON t1.code = t2.countrycode JOIN city AS t3 ON t1.code = t3.countrycode WHERE t2.isofficial = 't' AND t2.language = 'chinese' AND t1.continent = "asia"
  Type: JOIN

[489] WRONG_TABLE | DB: world_1 | EX: ✗
  Q   : Return the different names of cities that are in Asia and for which Chinese is the official language
  Pred: SELECT DISTINCT T1.localname FROM city AS T1 JOIN country AS T2 ON T1.countrycode = T2.code WHERE T2.region = "Asia" AND T2.language = "Chinese"
  Gold: SELECT DISTINCT T3.Name FROM country AS T1 JOIN countrylanguage AS T2 ON T1.Code = T2.CountryCode JOIN city AS T3 ON T1.Code = T3.CountryCode WHERE T2.IsOfficial = 'T' AND T2.Language = 'Chinese' AND T1.Continent = "Asia"
  Type: JOIN

[490] WRONG_COLUMNS | DB: world_1 | EX: ✗
  Q   : What are the name, independence year, and surface area of the country with the smallest population
  Pred: SELECT name, indepyear, surfacearea FROM country ORDER BY population ASC LIMIT 1
  Gold: SELECT Name, SurfaceArea, IndepYear FROM country ORDER BY Population LIMIT 1
  Type: ORDER_BY, LIMIT

[491] WRONG_COLUMNS | DB: world_1 | EX: ✗
  Q   : Give the name, year of independence, and surface area of the country that has the lowest population
  Pred: SELECT name, indepyear, surfacearea FROM country ORDER BY population LIMIT 1
  Gold: SELECT Name, SurfaceArea, IndepYear FROM country ORDER BY Population LIMIT 1
  Type: ORDER_BY, LIMIT

[492] WRONG_COLUMNS | DB: world_1 | EX: ✗
  Q   : What are the population, name and leader of the country with the largest area
  Pred: SELECT population, name, headofstate FROM country ORDER BY surfacearea DESC LIMIT 1
  Gold: SELECT Name, population, HeadOfState FROM country ORDER BY SurfaceArea DESC LIMIT 1
  Type: ORDER_BY, LIMIT

[493] WRONG_COLUMNS | DB: world_1 | EX: ✗
  Q   : Return the country name and the numbers of languages spoken for each country that speaks at least 3 languages
  Pred: SELECT T1.name, COUNT(*), T1.countrycode FROM country AS T1 JOIN countrylanguage AS T2 ON T1.countrycode = T2.code GROUP BY T1.countrycode HAVING COUNT(*) >= 3
  Gold: SELECT COUNT(T2.Language), T1.Name FROM country AS T1 JOIN countrylanguage AS T2 ON T1.Code = T2.CountryCode GROUP BY T1.Name HAVING COUNT(*) > 2
  Type: JOIN, GROUP_BY, HAVING, AGGREGATION

[494] WRONG_COLUMNS | DB: world_1 | EX: ✗
  Q   : What are the names of countries that speak more than 2 languages, as well as how many languages they speak
  Pred: SELECT T1.name, COUNT(*) FROM country AS T1 JOIN countrylanguage AS T2 ON T1.countrycode = T2.code GROUP BY T1.countrycode HAVING COUNT(*) > 2
  Gold: SELECT COUNT(T2.Language), T1.Name FROM country AS T1 JOIN countrylanguage AS T2 ON T1.Code = T2.CountryCode GROUP BY T1.Name HAVING COUNT(*) > 2
  Type: JOIN, GROUP_BY, HAVING, AGGREGATION

[495] MISSING_GROUP_BY | DB: world_1 | EX: ✗
  Q   : Find the number of cities in each district whose population is greater than the average population of cities
  Pred: SELECT COUNT(*), district FROM city WHERE population > (SELECT AVG(population) FROM city)
  Gold: SELECT COUNT(*), District FROM city WHERE Population > (SELECT AVG(Population) FROM city) GROUP BY District
  Type: GROUP_BY, NESTED, AGGREGATION

[496] MISSING_GROUP_BY | DB: world_1 | EX: ✗
  Q   : How many cities in each district have a population that is above the average population across all cities
  Pred: SELECT COUNT(*), district FROM city WHERE population > (SELECT AVG(population) FROM city)
  Gold: SELECT COUNT(*), District FROM city WHERE Population > (SELECT AVG(Population) FROM city) GROUP BY District
  Type: GROUP_BY, NESTED, AGGREGATION

[497] WRONG_COLUMNS | DB: world_1 | EX: ✗
  Q   : Find the government form name and total population for each government form whose average life expectancy is longer than 72
  Pred: SELECT governmentform, SUM(population) FROM country WHERE lifeexpectancy > 72 GROUP BY governmentform
  Gold: SELECT SUM(Population), GovernmentForm FROM country GROUP BY GovernmentForm HAVING AVG(LifeExpectancy) > 72
  Type: GROUP_BY, HAVING, AGGREGATION

[498] WRONG_COLUMNS | DB: world_1 | EX: ✗
  Q   : What are the different government forms and what is the total population of each for government forms that have an average life expectancy greater than 72
  Pred: SELECT governmentform, SUM(population) FROM country WHERE lifeexpectancy > 72 GROUP BY governmentform
  Gold: SELECT SUM(Population), GovernmentForm FROM country GROUP BY GovernmentForm HAVING AVG(LifeExpectancy) > 72
  Type: GROUP_BY, HAVING, AGGREGATION

[499] WRONG_COLUMNS | DB: world_1 | EX: ✗
  Q   : Find the average life expectancy and total population for each continent where the average life expectancy is shorter than 72
  Pred: SELECT AVG(lifeexpectancy), SUM(population) FROM country WHERE lifeexpectancy  72 GROUP BY continent
  Gold: SELECT SUM(Population), AVG(LifeExpectancy), Continent FROM country GROUP BY Continent HAVING AVG(LifeExpectancy) < 72
  Type: GROUP_BY, HAVING, AGGREGATION

[500] WRONG_COLUMNS | DB: world_1 | EX: ✗
  Q   : What are the different continents and the total popuation and average life expectancy corresponding to each, for continents that have an average life expectancy less than 72
  Pred: SELECT continent, AVG(lifeexpectancy), SUM(population) FROM country GROUP BY continent HAVING AVG(lifeexpectancy)  72
  Gold: SELECT SUM(Population), AVG(LifeExpectancy), Continent FROM country GROUP BY Continent HAVING AVG(LifeExpectancy) < 72
  Type: GROUP_BY, HAVING, AGGREGATION

[501] WRONG_COLUMNS | DB: world_1 | EX: ✗
  Q   : What are the names and areas of countries with the top 5 largest area
  Pred: SELECT name, area FROM country ORDER BY surfacearea DESC LIMIT 5
  Gold: SELECT Name, SurfaceArea FROM country ORDER BY SurfaceArea DESC LIMIT 5
  Type: ORDER_BY, LIMIT

[502] OTHER | DB: world_1 | EX: ✗
  Q   : Return the names and surface areas of the 5 largest countries
  Pred: SELECT name, surfacearea FROM country ORDER BY population DESC LIMIT 5
  Gold: SELECT Name, SurfaceArea FROM country ORDER BY SurfaceArea DESC LIMIT 5
  Type: ORDER_BY, LIMIT

[503] OTHER | DB: world_1 | EX: ✗
  Q   : how many countries are in Asia
  Pred: SELECT COUNT(*) FROM country WHERE region = 'Asia'
  Gold: SELECT COUNT(*) FROM country WHERE continent = "Asia"
  Type: AGGREGATION

[504] OTHER | DB: world_1 | EX: ✗
  Q   : Count the number of countries in Asia
  Pred: SELECT COUNT(*) FROM country WHERE region = 'Asie'
  Gold: SELECT COUNT(*) FROM country WHERE continent = "Asia"
  Type: AGGREGATION

[505] OTHER | DB: world_1 | EX: ✓
  Q   : What are the names of the countries that are in the continent of Europe and have a population of 80000
  Pred: SELECT name FROM country WHERE continent = 'Europe' AND population = 80000
  Gold: SELECT Name FROM country WHERE continent = "Europe" AND Population = "80000"
  Type: SIMPLE

[506] OTHER | DB: world_1 | EX: ✓
  Q   : Give the names of countries that are in Europe and have a population equal to 80000
  Pred: SELECT name FROM country WHERE continent = 'Europe' AND population = 80000
  Gold: SELECT Name FROM country WHERE continent = "Europe" AND Population = "80000"
  Type: SIMPLE

[507] OTHER | DB: world_1 | EX: ✗
  Q   : Give the total population and average surface area corresponding to countries in North America that have a surface area greater than 3000
  Pred: SELECT SUM(population), AVG(surfacearea) FROM country WHERE region = 'North America' AND surfacearea > 3000
  Gold: SELECT SUM(population), AVG(surfacearea) FROM country WHERE continent = "north america" AND surfacearea > 3000
  Type: AGGREGATION

[508] WRONG_TABLE | DB: world_1 | EX: ✗
  Q   : What is the language spoken by the largest percentage of people in each country
  Pred: SELECT countrylanguage, MAX(Percentage) FROM country AS T1 JOIN countryAS T2 ON T1.countrycode = T2.code GROUP BY countrycode
  Gold: SELECT LANGUAGE, CountryCode, MAX(Percentage) FROM countrylanguage GROUP BY CountryCode
  Type: GROUP_BY, AGGREGATION

[509] WRONG_TABLE | DB: world_1 | EX: ✗
  Q   : What are the country codes of the different countries, and what are the languages spoken by the greatest percentage of people for each
  Pred: SELECT countrycode, T1.language, MAX(T1.population) FROM country AS T1 JOIN countrylanguage AS T2 ON T1.countrycode = T2.code GROUP BY T1.countrycode
  Gold: SELECT LANGUAGE, CountryCode, MAX(Percentage) FROM countrylanguage GROUP BY CountryCode
  Type: GROUP_BY, AGGREGATION

[510] WRONG_TABLE | DB: world_1 | EX: ✗
  Q   : What is the total number of countries where Spanish is spoken by the largest percentage of people
  Pred: SELECT COUNT(*) FROM country AS T1 JOIN countrylanguage AS T2 ON T1.countrycode = T2.code WHERE T2.language = 'Spanish' ORDER BY percentage DESC LIMIT 1
  Gold: SELECT COUNT(*), MAX(Percentage) FROM countrylanguage WHERE LANGUAGE = "Spanish" GROUP BY CountryCode
  Type: GROUP_BY, AGGREGATION

[511] WRONG_TABLE | DB: world_1 | EX: ✗
  Q   : Count the number of countries for which Spanish is the predominantly spoken language
  Pred: SELECT COUNT(*) FROM country WHERE language = 'Spanish'
  Gold: SELECT COUNT(*), MAX(Percentage) FROM countrylanguage WHERE LANGUAGE = "Spanish" GROUP BY CountryCode
  Type: GROUP_BY, AGGREGATION

[512] WRONG_TABLE | DB: world_1 | EX: ✗
  Q   : What are the codes of countries where Spanish is spoken by the largest percentage of people
  Pred: SELECT T1.countrycode FROM country AS T1 JOIN countrylanguage AS T2 ON T1.countrycode = T2.code WHERE T2.language = 'Spanish' ORDER BY T1.population DESC LIMIT 1
  Gold: SELECT CountryCode, MAX(Percentage) FROM countrylanguage WHERE LANGUAGE = "Spanish" GROUP BY CountryCode
  Type: GROUP_BY, AGGREGATION

[513] WRONG_TABLE | DB: world_1 | EX: ✗
  Q   : Return the codes of countries for which Spanish is the predominantly spoken language
  Pred: SELECT T1.countrycode FROM country AS T1 JOIN countrylanguage AS T2 ON T1.countrycode = T2.code WHERE T2.language = 'Spanish'
  Gold: SELECT CountryCode, MAX(Percentage) FROM countrylanguage WHERE LANGUAGE = "Spanish" GROUP BY CountryCode
  Type: GROUP_BY, AGGREGATION

[514] OTHER | DB: orchestra | EX: ✓
  Q   : What are the names of conductors, ordered by age
  Pred: SELECT Name FROM conductor ORDER BY Age
  Gold: SELECT Name FROM conductor ORDER BY Age ASC
  Type: ORDER_BY

[515] OTHER | DB: orchestra | EX: ✗
  Q   : What are the names of conductors whose nationalities are not "USA"
  Pred: SELECT Name FROM conductor WHERE Nationality > "USA"
  Gold: SELECT Name FROM conductor WHERE Nationality <> 'USA'
  Type: SIMPLE

[516] OTHER | DB: orchestra | EX: ✗
  Q   : Return the names of conductors that do not have the nationality "USA"
  Pred: SELECT Name FROM conductor WHERE Nationality > "USA"
  Gold: SELECT Name FROM conductor WHERE Nationality <> 'USA'
  Type: SIMPLE

[517] OTHER | DB: orchestra | EX: ✗
  Q   : What are the maximum and minimum share of performances whose type is not "Live final"
  Pred: SELECT MAX(Share), MIN(Share) FROM performance WHERE TYPE > "Live final"
  Gold: SELECT MAX(SHARE), MIN(SHARE) FROM performance WHERE TYPE <> "Live final"
  Type: AGGREGATION

[518] WRONG_TABLE | DB: orchestra | EX: ✓
  Q   : Return the maximum and minimum shares for performances that do not have the type "Live final"
  Pred: SELECT MAX(Share), MIN(Share) FROM performance WHERE NOT Performance_ID IN (SELECT Performance_ID FROM show WHERE Type > "Live final")
  Gold: SELECT MAX(SHARE), MIN(SHARE) FROM performance WHERE TYPE <> "Live final"
  Type: AGGREGATION

[519] WRONG_TABLE | DB: orchestra | EX: ✗
  Q   : What is the name of the conductor who has worked the greatest number of years
  Pred: SELECT T2.name FROM orchestra AS T1 JOIN conductor AS T2 ON T1.conductor_id = T2.conductor_id GROUP BY T2.conductor_id ORDER BY COUNT(*) DESC LIMIT 1
  Gold: SELECT Name FROM conductor ORDER BY Year_of_Work DESC LIMIT 1
  Type: ORDER_BY, LIMIT

[520] WRONG_TABLE | DB: orchestra | EX: ✗
  Q   : Show the names of conductors and the orchestras they have conducted
  Pred: SELECT T3.Name, T2.Orchestra FROM performance AS T1 JOIN orchestra AS T2 ON T1.Orchestra_ID = T2.Orchestra_ID JOIN conductor AS T3 ON T1.Conductor_ID = T3.Conductor_ID
  Gold: SELECT T1.Name, T2.Orchestra FROM conductor AS T1 JOIN orchestra AS T2 ON T1.Conductor_ID = T2.Conductor_ID
  Type: JOIN

[521] WRONG_TABLE | DB: orchestra | EX: ✗
  Q   : What are the names of conductors as well as the corresonding orchestras that they have conducted
  Pred: SELECT T3.Name, T2.Orchestra FROM performance AS T1 JOIN orchestra AS T2 ON T1.Orchestra_ID = T2.Orchestra_ID JOIN conductor AS T3 ON T1.Conductor_ID = T3.Conductor_ID
  Gold: SELECT T1.Name, T2.Orchestra FROM conductor AS T1 JOIN orchestra AS T2 ON T1.Conductor_ID = T2.Conductor_ID
  Type: JOIN

[522] OTHER | DB: orchestra | EX: ✓
  Q   : Show the names of conductors that have conducted more than one orchestras
  Pred: SELECT T1.name FROM conductor AS T1 JOIN orchestra AS T2 ON T1.conductor_id = T2.conductor_id GROUP BY T1.conductor_id HAVING COUNT(*) > 1
  Gold: SELECT T1.Name FROM conductor AS T1 JOIN orchestra AS T2 ON T1.Conductor_ID = T2.Conductor_ID GROUP BY T2.Conductor_ID HAVING COUNT(*) > 1
  Type: JOIN, GROUP_BY, HAVING, AGGREGATION

[523] OTHER | DB: orchestra | EX: ✓
  Q   : What are the names of conductors who have conducted at more than one orchestra
  Pred: SELECT T1.name FROM conductor AS T1 JOIN orchestra AS T2 ON T1.conductor_id = T2.conductor_id GROUP BY T1.conductor_id HAVING COUNT(*) > 1
  Gold: SELECT T1.Name FROM conductor AS T1 JOIN orchestra AS T2 ON T1.Conductor_ID = T2.Conductor_ID GROUP BY T2.Conductor_ID HAVING COUNT(*) > 1
  Type: JOIN, GROUP_BY, HAVING, AGGREGATION

[524] WRONG_TABLE | DB: orchestra | EX: ✗
  Q   : Show the name of the conductor that has conducted the most number of orchestras
  Pred: SELECT T2.name FROM performance AS T1 JOIN conductor AS T2 ON T1.conductor_id = T2.conductor_id GROUP BY T2.conductor_id ORDER BY COUNT(*) DESC LIMIT 1
  Gold: SELECT T1.Name FROM conductor AS T1 JOIN orchestra AS T2 ON T1.Conductor_ID = T2.Conductor_ID GROUP BY T2.Conductor_ID ORDER BY COUNT(*) DESC LIMIT 1
  Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, AGGREGATION

[525] WRONG_TABLE | DB: orchestra | EX: ✓
  Q   : What is the name of the conductor who has conducted the most orchestras
  Pred: SELECT T2.name FROM orchestra AS T1 JOIN conductor AS T2 ON T1.conductor_id = T2.conductor_id GROUP BY T2.conductor_id ORDER BY COUNT(*) DESC LIMIT 1
  Gold: SELECT T1.Name FROM conductor AS T1 JOIN orchestra AS T2 ON T1.Conductor_ID = T2.Conductor_ID GROUP BY T2.Conductor_ID ORDER BY COUNT(*) DESC LIMIT 1
  Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, AGGREGATION

[526] WRONG_TABLE | DB: orchestra | EX: ✓
  Q   : Please show the name of the conductor that has conducted orchestras founded after 2008
  Pred: SELECT T2.name FROM orchestra AS T1 JOIN conductor AS T2 ON T1.conductor_id = T2.conductor_id WHERE T1.year_of_founded > 2008
  Gold: SELECT T1.Name FROM conductor AS T1 JOIN orchestra AS T2 ON T1.Conductor_ID = T2.Conductor_ID WHERE Year_of_Founded > 2008
  Type: JOIN

[527] WRONG_TABLE | DB: orchestra | EX: ✓
  Q   : What are the names of conductors who have conducted orchestras founded after the year 2008
  Pred: SELECT T2.name FROM orchestra AS T1 JOIN conductor AS T2 ON T1.conductor_id = T2.conductor_id WHERE T1.year_of_founded > 2008
  Gold: SELECT T1.Name FROM conductor AS T1 JOIN orchestra AS T2 ON T1.Conductor_ID = T2.Conductor_ID WHERE Year_of_Founded > 2008
  Type: JOIN

[528] WRONG_COLUMNS | DB: orchestra | EX: ✗
  Q   : How many orchestras does each record company manage
  Pred: SELECT COUNT(*), record_company FROM orchestra GROUP BY record_company
  Gold: SELECT Record_Company, COUNT(*) FROM orchestra GROUP BY Record_Company
  Type: GROUP_BY, AGGREGATION

[529] MISSING_GROUP_BY | DB: orchestra | EX: ✗
  Q   : Please show the record formats of orchestras in ascending order of count
  Pred: SELECT Major_Record_Format FROM orchestra ORDER BY COUNT(*) ASC
  Gold: SELECT Major_Record_Format FROM orchestra GROUP BY Major_Record_Format ORDER BY COUNT(*) ASC
  Type: GROUP_BY, ORDER_BY, AGGREGATION

[530] MISSING_GROUP_BY | DB: orchestra | EX: ✗
  Q   : What are the major record formats of orchestras, sorted by their frequency
  Pred: SELECT Major_Record_format FROM orchestra ORDER BY Major_Record_format
  Gold: SELECT Major_Record_Format FROM orchestra GROUP BY Major_Record_Format ORDER BY COUNT(*) ASC
  Type: GROUP_BY, ORDER_BY, AGGREGATION

[531] WRONG_COLUMNS | DB: orchestra | EX: ✗
  Q   : List the names of orchestras that have no performance
  Pred: SELECT Name FROM orchestra WHERE NOT Orchestra_ID IN (SELECT Orchestra_ID FROM performance)
  Gold: SELECT Orchestra FROM orchestra WHERE NOT Orchestra_ID IN (SELECT Orchestra_ID FROM performance)
  Type: NESTED

[532] OTHER | DB: orchestra | EX: ✗
  Q   : Show the record companies shared by orchestras founded before 2003 and after 2003
  Pred: SELECT Record_Company FROM orchestra WHERE YEAR_of_founded  2003 INTERSECT SELECT Record_Company FROM orchestra WHERE YEAR_of_founded > 2003
  Gold: SELECT Record_Company FROM orchestra WHERE Year_of_Founded < 2003 INTERSECT SELECT Record_Company FROM orchestra WHERE Year_of_Founded > 2003
  Type: SIMPLE

[533] OTHER | DB: orchestra | EX: ✗
  Q   : What are the record companies that are used by both orchestras founded before 2003 and those founded after 2003
  Pred: SELECT record_company FROM orchestra WHERE YEAR_of_founded  2003 INTERSECT SELECT record_company FROM orchestra WHERE YEAR_of_founded > 2003
  Gold: SELECT Record_Company FROM orchestra WHERE Year_of_Founded < 2003 INTERSECT SELECT Record_Company FROM orchestra WHERE Year_of_Founded > 2003
  Type: SIMPLE

[534] WRONG_COLUMNS | DB: orchestra | EX: ✓
  Q   : Show the years in which orchestras that have given more than one performance are founded
  Pred: SELECT T1.Year_of_founded FROM orchestra AS T1 JOIN performance AS T2 ON T1.Orchestra_ID = T2.Orchestra_ID GROUP BY T1.Orchestra_ID HAVING COUNT(*) > 1
  Gold: SELECT Year_of_Founded FROM orchestra AS T1 JOIN performance AS T2 ON T1.Orchestra_ID = T2.Orchestra_ID GROUP BY T2.Orchestra_ID HAVING COUNT(*) > 1
  Type: JOIN, GROUP_BY, HAVING, AGGREGATION

[535] MISSING_JOIN | DB: orchestra | EX: ✗
  Q   : What are years of founding for orchestras that have had more than a single performance
  Pred: SELECT YEAR_of_founded FROM orchestra GROUP BY YEAR_of_founded HAVING COUNT(*) > 1
  Gold: SELECT Year_of_Founded FROM orchestra AS T1 JOIN performance AS T2 ON T1.Orchestra_ID = T2.Orchestra_ID GROUP BY T2.Orchestra_ID HAVING COUNT(*) > 1
  Type: JOIN, GROUP_BY, HAVING, AGGREGATION

[536] WRONG_COLUMNS | DB: network_1 | EX: ✗
  Q   : What grade is Kyle in
  Pred: SELECT grading FROM highschooler WHERE name = 'Kyle'
  Gold: SELECT grade FROM Highschooler WHERE name = "Kyle"
  Type: SIMPLE

[537] WRONG_COLUMNS | DB: network_1 | EX: ✗
  Q   : What is Kyle's id
  Pred: SELECT student_id FROM highschooler WHERE name = 'Kyle'
  Gold: SELECT ID FROM Highschooler WHERE name = "Kyle"
  Type: SIMPLE

[538] EXTRA_JOIN | DB: network_1 | EX: ✗
  Q   : How many friends does each student have
  Pred: SELECT COUNT(*) FROM friend AS T1 JOIN student AS T2 ON T1.student_id = T2.id GROUP BY T2.student_id
  Gold: SELECT student_id, COUNT(*) FROM Friend GROUP BY student_id
  Type: GROUP_BY, AGGREGATION

[539] WRONG_TABLE | DB: network_1 | EX: ✗
  Q   : Show the names of high school students and their corresponding number of friends
  Pred: SELECT T2.name, COUNT(*) FROM highschooler AS T1 JOIN friend AS T2 ON T1.id = T2.friend_id JOIN student AS T3 ON T1.student_id = T3.id GROUP BY T3.student_id
  Gold: SELECT T2.name, COUNT(*) FROM Friend AS T1 JOIN Highschooler AS T2 ON T1.student_id = T2.id GROUP BY T1.student_id
  Type: JOIN, GROUP_BY, AGGREGATION

[540] WRONG_TABLE | DB: network_1 | EX: ✗
  Q   : What are the names of the high schoolers and how many friends does each have
  Pred: SELECT COUNT(*), T1.name FROM highschooler AS T1 JOIN friend AS T2 ON T1.id = T2.friend_id GROUP BY T1.id
  Gold: SELECT T2.name, COUNT(*) FROM Friend AS T1 JOIN Highschooler AS T2 ON T1.student_id = T2.id GROUP BY T1.student_id
  Type: JOIN, GROUP_BY, AGGREGATION

[541] WRONG_TABLE | DB: network_1 | EX: ✗
  Q   : What is the name of the high schooler who has the greatest number of friends
  Pred: SELECT T1.name FROM highschooler AS T1 JOIN friend AS T2 ON T1.id = T2.friend_id GROUP BY T1.id ORDER BY COUNT(*) DESC LIMIT 1
  Gold: SELECT T2.name FROM Friend AS T1 JOIN Highschooler AS T2 ON T1.student_id = T2.id GROUP BY T1.student_id ORDER BY COUNT(*) DESC LIMIT 1
  Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, AGGREGATION

[542] WRONG_TABLE | DB: network_1 | EX: ✗
  Q   : Return the name of the high school student with the most friends
  Pred: SELECT T1.name FROM highschooler AS T1 JOIN friend AS T2 ON T1.id = T2.friend_id GROUP BY T2.friend_id ORDER BY COUNT(*) DESC LIMIT 1
  Gold: SELECT T2.name FROM Friend AS T1 JOIN Highschooler AS T2 ON T1.student_id = T2.id GROUP BY T1.student_id ORDER BY COUNT(*) DESC LIMIT 1
  Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, AGGREGATION

[543] WRONG_TABLE | DB: network_1 | EX: ✗
  Q   : Show the names of high schoolers who have at least 3 friends
  Pred: SELECT T1.name FROM highschooler AS T1 JOIN friend AS T2 ON T1.id = T2.friend_id GROUP BY T2.friend_id HAVING COUNT(*) >= 3
  Gold: SELECT T2.name FROM Friend AS T1 JOIN Highschooler AS T2 ON T1.student_id = T2.id GROUP BY T1.student_id HAVING COUNT(*) >= 3
  Type: JOIN, GROUP_BY, HAVING, AGGREGATION

[544] WRONG_TABLE | DB: network_1 | EX: ✗
  Q   : What are the names of high schoolers who have 3 or more friends
  Pred: SELECT T1.name FROM highschooler AS T1 JOIN friend AS T2 ON T1.id = T2.friend_id GROUP BY T2.friend_id HAVING COUNT(*) >= 3
  Gold: SELECT T2.name FROM Friend AS T1 JOIN Highschooler AS T2 ON T1.student_id = T2.id GROUP BY T1.student_id HAVING COUNT(*) >= 3
  Type: JOIN, GROUP_BY, HAVING, AGGREGATION

[545] WRONG_TABLE | DB: network_1 | EX: ✗
  Q   : Show the names of all of the high schooler Kyle's friends
  Pred: SELECT T3.name FROM highschooler AS T1 JOIN friend AS T2 ON T1.id = T2.friend_id JOIN likes AS T3 ON T2.liked_id = T3.id JOIN student AS T4 ON T3.student_id = T4.id WHERE T1.name = 'Kyle'
  Gold: SELECT T3.name FROM Friend AS T1 JOIN Highschooler AS T2 ON T1.student_id = T2.id JOIN Highschooler AS T3 ON T1.friend_id = T3.id WHERE T2.name = "Kyle"
  Type: JOIN

[546] WRONG_TABLE | DB: network_1 | EX: ✗
  Q   : Return the names of friends of the high school student Kyle
  Pred: SELECT T2.name FROM highschooler AS T1 JOIN friend AS T2 ON T1.id = T2.friend_id WHERE T1.id = "Kyle"
  Gold: SELECT T3.name FROM Friend AS T1 JOIN Highschooler AS T2 ON T1.student_id = T2.id JOIN Highschooler AS T3 ON T1.friend_id = T3.id WHERE T2.name = "Kyle"
  Type: JOIN

[547] OTHER | DB: network_1 | EX: ✗
  Q   : How many friends does the high school student Kyle have
  Pred: SELECT COUNT(*) FROM friend AS T1 JOIN student AS T2 ON T1.student_id = T2.id WHERE T2.name = "Kyle"
  Gold: SELECT COUNT(*) FROM Friend AS T1 JOIN Highschooler AS T2 ON T1.student_id = T2.id WHERE T2.name = "Kyle"
  Type: JOIN, AGGREGATION

[548] MISSING_JOIN | DB: network_1 | EX: ✗
  Q   : Count the number of friends Kyle has
  Pred: SELECT COUNT(*) FROM friend WHERE name = 'Kyle'
  Gold: SELECT COUNT(*) FROM Friend AS T1 JOIN Highschooler AS T2 ON T1.student_id = T2.id WHERE T2.name = "Kyle"
  Type: JOIN, AGGREGATION

[549] WRONG_COLUMNS | DB: network_1 | EX: ✗
  Q   : Show ids of all students who do not have any friends
  Pred: SELECT student_id FROM friend EXCEPT SELECT student_id FROM highschooler
  Gold: SELECT id FROM Highschooler EXCEPT SELECT student_id FROM Friend
  Type: SIMPLE

[550] WRONG_COLUMNS | DB: network_1 | EX: ✗
  Q   : What are the ids of high school students who do not have friends
  Pred: SELECT student_id FROM friend EXCEPT SELECT student_id FROM highschooler
  Gold: SELECT id FROM Highschooler EXCEPT SELECT student_id FROM Friend
  Type: SIMPLE

[551] MISSING_JOIN | DB: network_1 | EX: ✗
  Q   : Show names of all high school students who do not have any friends
  Pred: SELECT name FROM highschooler WHERE NOT student_id IN (SELECT student_id FROM friend)
  Gold: SELECT name FROM Highschooler EXCEPT SELECT T2.name FROM Friend AS T1 JOIN Highschooler AS T2 ON T1.student_id = T2.id
  Type: JOIN

[552] WRONG_TABLE | DB: network_1 | EX: ✗
  Q   : What are the names of students who have no friends
  Pred: SELECT name FROM student WHERE NOT student_id IN (SELECT student_id FROM friend)
  Gold: SELECT name FROM Highschooler EXCEPT SELECT T2.name FROM Friend AS T1 JOIN Highschooler AS T2 ON T1.student_id = T2.id
  Type: JOIN

[553] WRONG_TABLE | DB: network_1 | EX: ✓
  Q   : Show the ids of high schoolers who have friends and are also liked by someone else
  Pred: SELECT T1.id FROM highschooler AS T1 JOIN friend AS T2 ON T1.id = T2.friend_id INTERSECT SELECT T1.id FROM highschooler AS T1 JOIN likes AS T2 ON T1.id = T2.liked_id
  Gold: SELECT student_id FROM Friend INTERSECT SELECT liked_id FROM Likes
  Type: SIMPLE

[554] WRONG_TABLE | DB: network_1 | EX: ✗
  Q   : What are the ids of students who both have friends and are liked
  Pred: SELECT T1.id FROM student AS T1 JOIN friend AS T2 ON T1.id = T2.friend_id INTERSECT SELECT T1.id FROM student AS T1 JOIN likes AS T2 ON T1.id = T2.liked_id
  Gold: SELECT student_id FROM Friend INTERSECT SELECT liked_id FROM Likes
  Type: SIMPLE

[555] WRONG_TABLE | DB: network_1 | EX: ✗
  Q   : Show name of all students who have some friends and also are liked by someone else
  Pred: SELECT T1.name FROM highschooler AS T1 JOIN friend AS T2 ON T1.id = T2.friend_id JOIN likes AS T3 ON T2.liked_id = T3.id
  Gold: SELECT T2.name FROM Friend AS T1 JOIN Highschooler AS T2 ON T1.student_id = T2.id INTERSECT SELECT T2.name FROM Likes AS T1 JOIN Highschooler AS T2 ON T1.liked_id = T2.id
  Type: JOIN

[556] WRONG_TABLE | DB: network_1 | EX: ✓
  Q   : What are the names of high schoolers who both have friends and are liked
  Pred: SELECT T1.name FROM highschooler AS T1 JOIN friend AS T2 ON T1.id = T2.friend_id INTERSECT SELECT T1.name FROM highschooler AS T1 JOIN likes AS T2 ON T1.id = T2.liked_id
  Gold: SELECT T2.name FROM Friend AS T1 JOIN Highschooler AS T2 ON T1.student_id = T2.id INTERSECT SELECT T2.name FROM Likes AS T1 JOIN Highschooler AS T2 ON T1.liked_id = T2.id
  Type: JOIN

[557] WRONG_COLUMNS | DB: network_1 | EX: ✗
  Q   : Count the number of likes for each student id
  Pred: SELECT COUNT(*), student_id FROM likes GROUP BY student_id
  Gold: SELECT student_id, COUNT(*) FROM Likes GROUP BY student_id
  Type: GROUP_BY, AGGREGATION

[558] WRONG_TABLE | DB: network_1 | EX: ✗
  Q   : Show the names of high schoolers who have likes, and numbers of likes for each
  Pred: SELECT T1.name, COUNT(*) FROM highschooler AS T1 JOIN likes AS T2 ON T1.id = T2.liked_id GROUP BY T1.id
  Gold: SELECT T2.name, COUNT(*) FROM Likes AS T1 JOIN Highschooler AS T2 ON T1.student_id = T2.id GROUP BY T1.student_id
  Type: JOIN, GROUP_BY, AGGREGATION

[559] WRONG_TABLE | DB: network_1 | EX: ✗
  Q   : What are the names of high schoolers who have likes, and how many likes does each have
  Pred: SELECT T1.name, COUNT(*) FROM highschooler AS T1 JOIN likes AS T2 ON T1.id = T2.liked_id GROUP BY T1.id
  Gold: SELECT T2.name, COUNT(*) FROM Likes AS T1 JOIN Highschooler AS T2 ON T1.student_id = T2.id GROUP BY T1.student_id
  Type: JOIN, GROUP_BY, AGGREGATION

[560] WRONG_TABLE | DB: network_1 | EX: ✗
  Q   : What is the name of the high schooler who has the greatest number of likes
  Pred: SELECT T1.name FROM highschooler AS T1 JOIN likes AS T2 ON T1.id = T2.liked_id GROUP BY T1.id ORDER BY COUNT(*) DESC LIMIT 1
  Gold: SELECT T2.name FROM Likes AS T1 JOIN Highschooler AS T2 ON T1.student_id = T2.id GROUP BY T1.student_id ORDER BY COUNT(*) DESC LIMIT 1
  Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, AGGREGATION

[561] OTHER | DB: network_1 | EX: ✗
  Q   : Give the name of the student with the most likes
  Pred: SELECT T2.name FROM likes AS T1 JOIN student AS T2 ON T1.student_id = T2.id GROUP BY T1.student_id ORDER BY COUNT(*) DESC LIMIT 1
  Gold: SELECT T2.name FROM Likes AS T1 JOIN Highschooler AS T2 ON T1.student_id = T2.id GROUP BY T1.student_id ORDER BY COUNT(*) DESC LIMIT 1
  Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, AGGREGATION

[562] OTHER | DB: network_1 | EX: ✗
  Q   : Show the names of students who have at least 2 likes
  Pred: SELECT T2.name FROM likes AS T1 JOIN student AS T2 ON T1.student_id = T2.id GROUP BY T2.student_id HAVING COUNT(*) >= 2
  Gold: SELECT T2.name FROM Likes AS T1 JOIN Highschooler AS T2 ON T1.student_id = T2.id GROUP BY T1.student_id HAVING COUNT(*) >= 2
  Type: JOIN, GROUP_BY, HAVING, AGGREGATION

[563] OTHER | DB: network_1 | EX: ✗
  Q   : What are the names of students who have 2 or more likes
  Pred: SELECT T2.name FROM likes AS T1 JOIN student AS T2 ON T1.student_id = T2.id GROUP BY T2.student_id HAVING COUNT(*) >= 2
  Gold: SELECT T2.name FROM Likes AS T1 JOIN Highschooler AS T2 ON T1.student_id = T2.id GROUP BY T1.student_id HAVING COUNT(*) >= 2
  Type: JOIN, GROUP_BY, HAVING, AGGREGATION

[564] WRONG_TABLE | DB: network_1 | EX: ✗
  Q   : Show the names of students who have a grade higher than 5 and have at least 2 friends
  Pred: SELECT T2.name FROM highschooler AS T1 JOIN friend AS T2 ON T1.id = T2.friend_id JOIN student AS T3 ON T1.id = T3.student_id WHERE T1.grade > 5 GROUP BY T3.id HAVING COUNT(*) >= 2
  Gold: SELECT T2.name FROM Friend AS T1 JOIN Highschooler AS T2 ON T1.student_id = T2.id WHERE T2.grade > 5 GROUP BY T1.student_id HAVING COUNT(*) >= 2
  Type: JOIN, GROUP_BY, HAVING, AGGREGATION

[565] WRONG_TABLE | DB: network_1 | EX: ✗
  Q   : What are the names of high schoolers who have a grade of over 5 and have 2 or more friends
  Pred: SELECT T2.name FROM highschooler AS T1 JOIN friend AS T2 ON T1.id = T2.friend_id WHERE T1.grade > 5 GROUP BY T2.name HAVING COUNT(*) >= 2
  Gold: SELECT T2.name FROM Friend AS T1 JOIN Highschooler AS T2 ON T1.student_id = T2.id WHERE T2.grade > 5 GROUP BY T1.student_id HAVING COUNT(*) >= 2
  Type: JOIN, GROUP_BY, HAVING, AGGREGATION

[566] OTHER | DB: network_1 | EX: ✗
  Q   : How many likes does Kyle have
  Pred: SELECT COUNT(*) FROM likes AS T1 JOIN student AS T2 ON T1.student_id = T2.id WHERE T2.name = "Kyle"
  Gold: SELECT COUNT(*) FROM Likes AS T1 JOIN Highschooler AS T2 ON T1.student_id = T2.id WHERE T2.name = "Kyle"
  Type: JOIN, AGGREGATION

[567] OTHER | DB: network_1 | EX: ✗
  Q   : Return the number of likes that the high schooler named Kyle has
  Pred: SELECT COUNT(*) FROM likes AS T1 JOIN highschooler AS T2 ON T1.id = T2.highschooler_id WHERE T2.name = "Kyle"
  Gold: SELECT COUNT(*) FROM Likes AS T1 JOIN Highschooler AS T2 ON T1.student_id = T2.id WHERE T2.name = "Kyle"
  Type: JOIN, AGGREGATION

[568] WRONG_TABLE | DB: network_1 | EX: ✗
  Q   : Find the average grade of all students who have some friends
  Pred: SELECT AVG(T2.grade) FROM highschooler AS T1 JOIN friend AS T2 ON T1.id = T2.friend_id
  Gold: SELECT AVG(grade) FROM Highschooler WHERE id IN (SELECT T1.student_id FROM Friend AS T1 JOIN Highschooler AS T2 ON T1.student_id = T2.id)
  Type: JOIN, NESTED, AGGREGATION

[569] WRONG_TABLE | DB: network_1 | EX: ✗
  Q   : What is the average grade of students who have friends
  Pred: SELECT AVG(T2.grade) FROM highschooler AS T1 JOIN friend AS T2 ON T1.id = T2.friend_id
  Gold: SELECT AVG(grade) FROM Highschooler WHERE id IN (SELECT T1.student_id FROM Friend AS T1 JOIN Highschooler AS T2 ON T1.student_id = T2.id)
  Type: JOIN, NESTED, AGGREGATION

[570] MISSING_JOIN | DB: network_1 | EX: ✗
  Q   : Find the minimum grade of students who have no friends
  Pred: SELECT MIN(grade) FROM highschooler WHERE NOT student_id IN (SELECT student_id FROM friend)
  Gold: SELECT MIN(grade) FROM Highschooler WHERE NOT id IN (SELECT T1.student_id FROM Friend AS T1 JOIN Highschooler AS T2 ON T1.student_id = T2.id)
  Type: JOIN, NESTED, AGGREGATION

[571] WRONG_TABLE | DB: network_1 | EX: ✗
  Q   : What is the lowest grade of students who do not have any friends
  Pred: SELECT MIN(grade) FROM student WHERE NOT student_id IN (SELECT student_id FROM friend)
  Gold: SELECT MIN(grade) FROM Highschooler WHERE NOT id IN (SELECT T1.student_id FROM Friend AS T1 JOIN Highschooler AS T2 ON T1.student_id = T2.id)
  Type: JOIN, NESTED, AGGREGATION

[572] OTHER | DB: dog_kennels | EX: ✓
  Q   : Which states have both owners and professionals living there
  Pred: SELECT state FROM professionals INTERSECT SELECT state FROM owners GROUP BY state
  Gold: SELECT state FROM Owners INTERSECT SELECT state FROM Professionals
  Type: SIMPLE

[573] OTHER | DB: dog_kennels | EX: ✓
  Q   : Find the states where both owners and professionals live
  Pred: SELECT state FROM professionals INTERSECT SELECT state FROM owners
  Gold: SELECT state FROM Owners INTERSECT SELECT state FROM Professionals
  Type: SIMPLE

[574] WRONG_TABLE | DB: dog_kennels | EX: ✗
  Q   : What is the average age of the dogs who have gone through any treatments
  Pred: SELECT AVG(T2.age) FROM treatments AS T1 JOIN dogs AS T2 ON T1.dog_id = T2.dog_id
  Gold: SELECT AVG(age) FROM Dogs WHERE dog_id IN (SELECT dog_id FROM Treatments)
  Type: NESTED, AGGREGATION

[575] WRONG_TABLE | DB: dog_kennels | EX: ✗
  Q   : Find the average age of the dogs who went through treatments
  Pred: SELECT AVG(T2.age) FROM treatments AS T1 JOIN dogs AS T2 ON T1.dog_id = T2.dog_id
  Gold: SELECT AVG(age) FROM Dogs WHERE dog_id IN (SELECT dog_id FROM Treatments)
  Type: NESTED, AGGREGATION

[576] WRONG_COLUMNS | DB: dog_kennels | EX: ✗
  Q   : Which professionals live in the state of Indiana or have done treatment on more than 2 treatments? List his or her id, last name and cell phone
  Pred: SELECT T1.professional_id, T1.last_name, T1.cell_number FROM professionals AS T1 JOIN treatments AS T2 ON T1.professional_id = T2.professional_id WHERE T1.state = "Indiana" GROUP BY T1.professional_id HAVING COUNT(*) > 2
  Gold: SELECT professional_id, last_name, cell_number FROM Professionals WHERE state = 'Indiana' UNION SELECT T1.professional_id, T1.last_name, T1.cell_number FROM Professionals AS T1 JOIN Treatments AS T2 ON T1.professional_id = T2.professional_id GROUP BY T1.professional_id HAVING COUNT(*) > 2
  Type: JOIN, GROUP_BY, HAVING, AGGREGATION

[577] WRONG_COLUMNS | DB: dog_kennels | EX: ✗
  Q   : Find the id, last name and cell phone of the professionals who live in the state of Indiana or have performed more than two treatments
  Pred: SELECT T1.professional_id, T1.last_name, T1.cell_number FROM professionals AS T1 JOIN treatments AS T2 ON T1.professional_id = T2.professional_id WHERE T1.state = "Indiana" GROUP BY T1.professional_id HAVING COUNT(*) > 2
  Gold: SELECT professional_id, last_name, cell_number FROM Professionals WHERE state = 'Indiana' UNION SELECT T1.professional_id, T1.last_name, T1.cell_number FROM Professionals AS T1 JOIN Treatments AS T2 ON T1.professional_id = T2.professional_id GROUP BY T1.professional_id HAVING COUNT(*) > 2
  Type: JOIN, GROUP_BY, HAVING, AGGREGATION

[578] WRONG_TABLE | DB: dog_kennels | EX: ✓
  Q   : Which dogs have not cost their owner more than 1000 for treatment ? List the dog names
  Pred: SELECT name FROM dogs EXCEPT SELECT T1.name FROM dogs AS T1 JOIN treatments AS T2 ON T1.dog_id = T2.dog_id GROUP BY T1.name HAVING SUM(T2.cost_of_treatment) > 1000
  Gold: SELECT name FROM dogs WHERE NOT dog_id IN (SELECT dog_id FROM treatments GROUP BY dog_id HAVING SUM(cost_of_treatment) > 1000)
  Type: GROUP_BY, HAVING, NESTED, AGGREGATION

[579] WRONG_TABLE | DB: dog_kennels | EX: ✗
  Q   : What are the names of the dogs for which the owner has not spend more than 1000 for treatment
  Pred: SELECT T2.name FROM owners AS T1 JOIN dogs AS T2 ON T1.owner_id = T2.owner_id GROUP BY T1.owner_id HAVING SUM(T1.cost_of_treatment) > 1000
  Gold: SELECT name FROM dogs WHERE NOT dog_id IN (SELECT dog_id FROM treatments GROUP BY dog_id HAVING SUM(cost_of_treatment) > 1000)
  Type: GROUP_BY, HAVING, NESTED, AGGREGATION

[580] WRONG_COLUMNS | DB: dog_kennels | EX: ✗
  Q   : Which first names are used for professionals or owners but are not used as dog names
  Pred: SELECT first_name FROM professionals UNION SELECT first_name FROM owners EXCEPT SELECT first_name FROM dogs
  Gold: SELECT first_name FROM Professionals UNION SELECT first_name FROM Owners EXCEPT SELECT name FROM Dogs
  Type: SIMPLE

[581] WRONG_COLUMNS | DB: dog_kennels | EX: ✗
  Q   : Find the first names that are used for professionals or owners but are not used as dog names
  Pred: SELECT first_name FROM professionals UNION SELECT first_name FROM owners EXCEPT SELECT first_name FROM dogs
  Gold: SELECT first_name FROM Professionals UNION SELECT first_name FROM Owners EXCEPT SELECT name FROM Dogs
  Type: SIMPLE

[582] WRONG_TABLE | DB: dog_kennels | EX: ✓
  Q   : Which professional did not operate any treatment on dogs? List the professional's id, role and email
  Pred: SELECT professional_id, role_code, email_address FROM professionals WHERE NOT professional_id IN (SELECT professional_id FROM treatments)
  Gold: SELECT professional_id, role_code, email_address FROM Professionals EXCEPT SELECT T1.professional_id, T1.role_code, T1.email_address FROM Professionals AS T1 JOIN Treatments AS T2 ON T1.professional_id = T2.professional_id
  Type: JOIN

[583] WRONG_COLUMNS | DB: dog_kennels | EX: ✗
  Q   : Give me the id, role and email of the professionals who did not perform any treatment on dogs
  Pred: SELECT professional_id, role_code, email_address FROM professionals EXCEPT SELECT T1.professional_id, T1.role_code FROM professionals AS T1 JOIN treatments AS T2 ON T1.professional_id = T2.professional_id WHERE T2.dog_id = 1
  Gold: SELECT professional_id, role_code, email_address FROM Professionals EXCEPT SELECT T1.professional_id, T1.role_code, T1.email_address FROM Professionals AS T1 JOIN Treatments AS T2 ON T1.professional_id = T2.professional_id
  Type: JOIN

[584] WRONG_TABLE | DB: dog_kennels | EX: ✗
  Q   : Which owner owns the most dogs? List the owner id, first name and last name
  Pred: SELECT T1.owner_id, T2.first_name, T2.last_name FROM owners AS T1 JOIN dogs AS T2 ON T1.owner_id = T2.owner_id GROUP BY T1.owner_id ORDER BY COUNT(*) DESC LIMIT 1
  Gold: SELECT T1.owner_id, T2.first_name, T2.last_name FROM Dogs AS T1 JOIN Owners AS T2 ON T1.owner_id = T2.owner_id GROUP BY T1.owner_id ORDER BY COUNT(*) DESC LIMIT 1
  Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, AGGREGATION

[585] WRONG_TABLE | DB: dog_kennels | EX: ✗
  Q   : Return the owner id, first name and last name of the owner who has the most dogs
  Pred: SELECT T1.owner_id, T2.first_name, T2.last_name FROM owners AS T1 JOIN dogs AS T2 ON T1.owner_id = T2.owner_id GROUP BY T1.owner_id ORDER BY COUNT(*) DESC LIMIT 1
  Gold: SELECT T1.owner_id, T2.first_name, T2.last_name FROM Dogs AS T1 JOIN Owners AS T2 ON T1.owner_id = T2.owner_id GROUP BY T1.owner_id ORDER BY COUNT(*) DESC LIMIT 1
  Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, AGGREGATION

[586] WRONG_TABLE | DB: dog_kennels | EX: ✗
  Q   : Which professionals have done at least two treatments? List the professional's id, role, and first name
  Pred: SELECT T1.professional_id, T1.role_code, T2.first_name FROM treatments AS T1 JOIN professionals AS T2 ON T1.professional_id = T2.professional_id GROUP BY T1.professional_id HAVING COUNT(*) >= 2
  Gold: SELECT T1.professional_id, T1.role_code, T1.first_name FROM Professionals AS T1 JOIN Treatments AS T2 ON T1.professional_id = T2.professional_id GROUP BY T1.professional_id HAVING COUNT(*) >= 2
  Type: JOIN, GROUP_BY, HAVING, AGGREGATION

[587] WRONG_COLUMNS | DB: dog_kennels | EX: ✗
  Q   : What are the id, role, and first name of the professionals who have performed two or more treatments
  Pred: SELECT T1.professional_id, T1.role_code, T2.first_name FROM professionals AS T1 JOIN treatments AS T2 ON T1.professional_id = T2.professional_id GROUP BY T1.professional_id HAVING COUNT(*) >= 2
  Gold: SELECT T1.professional_id, T1.role_code, T1.first_name FROM Professionals AS T1 JOIN Treatments AS T2 ON T1.professional_id = T2.professional_id GROUP BY T1.professional_id HAVING COUNT(*) >= 2
  Type: JOIN, GROUP_BY, HAVING, AGGREGATION

[588] MISSING_JOIN | DB: dog_kennels | EX: ✓
  Q   : What is the name of the breed with the most dogs
  Pred: SELECT breed_name FROM breeds GROUP BY breed_code ORDER BY COUNT(*) DESC LIMIT 1
  Gold: SELECT T1.breed_name FROM Breeds AS T1 JOIN Dogs AS T2 ON T1.breed_code = T2.breed_code GROUP BY T1.breed_name ORDER BY COUNT(*) DESC LIMIT 1
  Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, AGGREGATION

[589] WRONG_TABLE | DB: dog_kennels | EX: ✗
  Q   : Which breed do the most dogs have? Give me the breed name
  Pred: SELECT breed_name FROM dogs GROUP BY breed_code ORDER BY COUNT(*) DESC LIMIT 1
  Gold: SELECT T1.breed_name FROM Breeds AS T1 JOIN Dogs AS T2 ON T1.breed_code = T2.breed_code GROUP BY T1.breed_name ORDER BY COUNT(*) DESC LIMIT 1
  Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, AGGREGATION

[590] WRONG_COLUMNS | DB: dog_kennels | EX: ✗
  Q   : Which owner has paid for the most treatments on his or her dogs? List the owner id and last name
  Pred: SELECT T1.owner_id, T2.last_name FROM owners AS T1 JOIN treatments AS T2 ON T1.owner_id = T2.owner_id GROUP BY T1.owner_id ORDER BY COUNT(*) DESC LIMIT 1
  Gold: SELECT T1.owner_id, T1.last_name FROM Owners AS T1 JOIN Dogs AS T2 ON T1.owner_id = T2.owner_id JOIN Treatments AS T3 ON T2.dog_id = T3.dog_id GROUP BY T1.owner_id ORDER BY COUNT(*) DESC LIMIT 1
  Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, AGGREGATION

[591] OTHER | DB: dog_kennels | EX: ✗
  Q   : Tell me the owner id and last name of the owner who spent the most on treatments of his or her dogs
  Pred: SELECT T1.owner_id, T1.last_name FROM owners AS T1 JOIN treatments AS T2 ON T1.owner_id = T2.owner_id GROUP BY T1.owner_id ORDER BY SUM(T2.cost_of_treatment) DESC LIMIT 1
  Gold: SELECT T1.owner_id, T1.last_name FROM Owners AS T1 JOIN Dogs AS T2 ON T1.owner_id = T2.owner_id JOIN Treatments AS T3 ON T2.dog_id = T3.dog_id GROUP BY T1.owner_id ORDER BY COUNT(*) DESC LIMIT 1
  Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, AGGREGATION

[592] OTHER | DB: dog_kennels | EX: ✗
  Q   : What is the description of the treatment type that costs the least money in total
  Pred: SELECT T1.treatment_type_description FROM treatment_types AS T1 JOIN charges AS T2 ON T1.treatment_type_code = T2.treatment_type_code GROUP BY T1.treatment_type_code ORDER BY SUM(T2.charge_amount) ASC LIMIT 1
  Gold: SELECT T1.treatment_type_description FROM Treatment_types AS T1 JOIN Treatments AS T2 ON T1.treatment_type_code = T2.treatment_type_code GROUP BY T1.treatment_type_code ORDER BY SUM(cost_of_treatment) ASC LIMIT 1
  Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, AGGREGATION

[593] OTHER | DB: dog_kennels | EX: ✗
  Q   : Give me the description of the treatment type whose total cost is the lowest
  Pred: SELECT T1.treatment_type_description FROM treatment_types AS T1 JOIN charges AS T2 ON T1.treatment_type_code = T2.treatment_type_code GROUP BY T1.treatment_type_code ORDER BY SUM(T2.cost_of_treatment) ASC LIMIT 1
  Gold: SELECT T1.treatment_type_description FROM Treatment_types AS T1 JOIN Treatments AS T2 ON T1.treatment_type_code = T2.treatment_type_code GROUP BY T1.treatment_type_code ORDER BY SUM(cost_of_treatment) ASC LIMIT 1
  Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, AGGREGATION

[594] OTHER | DB: dog_kennels | EX: ✗
  Q   : Which owner has paid the largest amount of money in total for their dogs? Show the owner id and zip code
  Pred: SELECT T1.owner_id, T1.zip_code FROM owners AS T1 JOIN charges AS T2 ON T1.owner_id = T2.owner_id GROUP BY T1.owner_id ORDER BY SUM(T2.charge_amount) DESC LIMIT 1
  Gold: SELECT T1.owner_id, T1.zip_code FROM Owners AS T1 JOIN Dogs AS T2 ON T1.owner_id = T2.owner_id JOIN Treatments AS T3 ON T2.dog_id = T3.dog_id GROUP BY T1.owner_id ORDER BY SUM(T3.cost_of_treatment) DESC LIMIT 1
  Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, AGGREGATION

[595] OTHER | DB: dog_kennels | EX: ✗
  Q   : Find the owner id and zip code of the owner who spent the most money in total for his or her dogs
  Pred: SELECT T1.owner_id, T1.zip_code FROM owners AS T1 JOIN charges AS T2 ON T1.owner_id = T2.owner_id GROUP BY T1.owner_id ORDER BY SUM(T2.charge_amount) DESC LIMIT 1
  Gold: SELECT T1.owner_id, T1.zip_code FROM Owners AS T1 JOIN Dogs AS T2 ON T1.owner_id = T2.owner_id JOIN Treatments AS T3 ON T2.dog_id = T3.dog_id GROUP BY T1.owner_id ORDER BY SUM(T3.cost_of_treatment) DESC LIMIT 1
  Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, AGGREGATION

[596] WRONG_TABLE | DB: dog_kennels | EX: ✓
  Q   : Which professionals have done at least two types of treatments? List the professional id and cell phone
  Pred: SELECT T1.professional_id, T2.cell_number FROM treatments AS T1 JOIN professionals AS T2 ON T1.professional_id = T2.professional_id GROUP BY T1.professional_id HAVING COUNT(*) >= 2
  Gold: SELECT T1.professional_id, T1.cell_number FROM Professionals AS T1 JOIN Treatments AS T2 ON T1.professional_id = T2.professional_id GROUP BY T1.professional_id HAVING COUNT(*) >= 2
  Type: JOIN, GROUP_BY, HAVING, AGGREGATION

[597] WRONG_TABLE | DB: dog_kennels | EX: ✗
  Q   : What are the first name and last name of the professionals who have done treatment with cost below average
  Pred: SELECT T2.first_name, T2.last_name FROM treatments AS T1 JOIN professionals AS T2 ON T1.professional_id = T2.professional_id WHERE T1.cost_of_treatment  (SELECT AVG(cost_of_treatment) FROM treatments)
  Gold: SELECT DISTINCT T1.first_name, T1.last_name FROM Professionals AS T1 JOIN Treatments AS T2 ON TRUE WHERE cost_of_treatment < (SELECT AVG(cost_of_treatment) FROM Treatments)
  Type: JOIN, NESTED, AGGREGATION

[598] WRONG_COLUMNS | DB: dog_kennels | EX: ✗
  Q   : Which professionals have operated a treatment that costs less than the average? Give me theor first names and last names
  Pred: SELECT T1.first_name, T1.last_name FROM professionals AS T1 JOIN treatments AS T2 ON T1.professional_id = T2.professional_id WHERE T2.cost_of_treatment  (SELECT AVG(cost_of_treatment) FROM treatments)
  Gold: SELECT DISTINCT T1.first_name, T1.last_name FROM Professionals AS T1 JOIN Treatments AS T2 ON TRUE WHERE cost_of_treatment < (SELECT AVG(cost_of_treatment) FROM Treatments)
  Type: JOIN, NESTED, AGGREGATION

[599] WRONG_TABLE | DB: dog_kennels | EX: ✗
  Q   : List the date of each treatment, together with the first name of the professional who operated it
  Pred: SELECT T1.date_of_treatment, T2.first_name FROM professionals AS T1 JOIN treatments AS T2 ON T1.professional_id = T2.professional_id
  Gold: SELECT T1.date_of_treatment, T2.first_name FROM Treatments AS T1 JOIN Professionals AS T2 ON T1.professional_id = T2.professional_id
  Type: JOIN

[600] WRONG_TABLE | DB: dog_kennels | EX: ✓
  Q   : What are the date and the operating professional's first name of each treatment
  Pred: SELECT date_of_treatment, first_name FROM professionals AS T1 JOIN treatments AS T2 ON T1.professional_id = T2.professional_id
  Gold: SELECT T1.date_of_treatment, T2.first_name FROM Treatments AS T1 JOIN Professionals AS T2 ON T1.professional_id = T2.professional_id
  Type: JOIN

[601] WRONG_TABLE | DB: dog_kennels | EX: ✗
  Q   : List each owner's first name, last name, and the size of his for her dog
  Pred: SELECT T2.first_name, T2.last_name, T2.size_code FROM dogs AS T1 JOIN owners AS T2 ON T1.owner_id = T2.owner_id JOIN sizes AS T3 ON T1.size_code = T3.size_code
  Gold: SELECT T1.first_name, T1.last_name, T2.size_code FROM Owners AS T1 JOIN Dogs AS T2 ON T1.owner_id = T2.owner_id
  Type: JOIN

[602] WRONG_TABLE | DB: dog_kennels | EX: ✓
  Q   : What are each owner's first name, last name, and the size of their dog
  Pred: SELECT T2.first_name, T2.last_name, T3.size_code FROM dogs AS T1 JOIN owners AS T2 ON T1.owner_id = T2.owner_id JOIN sizes AS T3 ON T1.size_code = T3.size_code
  Gold: SELECT T1.first_name, T1.last_name, T2.size_code FROM Owners AS T1 JOIN Dogs AS T2 ON T1.owner_id = T2.owner_id
  Type: JOIN

[603] WRONG_TABLE | DB: dog_kennels | EX: ✗
  Q   : List pairs of the owner's first name and the dogs's name
  Pred: SELECT T2.first_name, T2.last_name FROM dogs AS T1 JOIN owners AS T2 ON T1.owner_id = T2.owner_id
  Gold: SELECT T1.first_name, T2.name FROM Owners AS T1 JOIN Dogs AS T2 ON T1.owner_id = T2.owner_id
  Type: JOIN

[604] WRONG_TABLE | DB: dog_kennels | EX: ✗
  Q   : What are each owner's first name and their dogs's name
  Pred: SELECT T2.first_name, T2.last_name FROM dogs AS T1 JOIN owners AS T2 ON T1.owner_id = T2.owner_id
  Gold: SELECT T1.first_name, T2.name FROM Owners AS T1 JOIN Dogs AS T2 ON T1.owner_id = T2.owner_id
  Type: JOIN

[605] MISSING_GROUP_BY | DB: dog_kennels | EX: ✗
  Q   : List the names of the dogs of the rarest breed and the treatment dates of them
  Pred: SELECT T2.name, T1.date_of_treatment FROM dogs AS T1 JOIN treatments AS T2 ON T1.dog_id = T2.dog_id WHERE T1.breed_code = (SELECT breed_code FROM dogs AS T3 JOIN treatments AS T4 ON T3.treatment_type_code = T4.treatment_type_code WHERE breed_name = "rast")
  Gold: SELECT T1.name, T2.date_of_treatment FROM Dogs AS T1 JOIN Treatments AS T2 ON T1.dog_id = T2.dog_id WHERE T1.breed_code = (SELECT breed_code FROM Dogs GROUP BY breed_code ORDER BY COUNT(*) ASC LIMIT 1)
  Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, NESTED, AGGREGATION

[606] WRONG_TABLE | DB: dog_kennels | EX: ✗
  Q   : Which dogs are of the rarest breed? Show their names and treatment dates
  Pred: SELECT T1.name, T2.date_of_treatment FROM dogs AS T1 JOIN treatments AS T2 ON T1.dog_id = T2.dog_id WHERE T1.breed_code = (SELECT breed_code FROM breeds AS T3 JOIN treatments AS T4 ON T3.breed_code = T4.breed_code ORDER BY T3.date_of_treatment DESC LIMIT 1)
  Gold: SELECT T1.name, T2.date_of_treatment FROM Dogs AS T1 JOIN Treatments AS T2 ON T1.dog_id = T2.dog_id WHERE T1.breed_code = (SELECT breed_code FROM Dogs GROUP BY breed_code ORDER BY COUNT(*) ASC LIMIT 1)
  Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, NESTED, AGGREGATION

[607] WRONG_COLUMNS | DB: dog_kennels | EX: ✗
  Q   : Which dogs are owned by someone who lives in Virginia? List the owner's first name and the dog's name
  Pred: SELECT T2.first_name, T2.name FROM owners AS T1 JOIN dogs AS T2 ON T1.owner_id = T2.owner_id WHERE T1.state = "Virginia"
  Gold: SELECT T1.first_name, T2.name FROM Owners AS T1 JOIN Dogs AS T2 ON T1.owner_id = T2.owner_id WHERE T1.state = 'Virginia'
  Type: JOIN

[608] WRONG_COLUMNS | DB: dog_kennels | EX: ✗
  Q   : Find the first names of owners living in Virginia and the names of dogs they own
  Pred: SELECT DISTINCT T1.first_name, T2.last_name FROM owners AS T1 JOIN dogs AS T2 ON T1.owner_id = T2.owner_id WHERE T1.state = "Virginia"
  Gold: SELECT T1.first_name, T2.name FROM Owners AS T1 JOIN Dogs AS T2 ON T1.owner_id = T2.owner_id WHERE T1.state = 'Virginia'
  Type: JOIN

[609] MISSING_JOIN | DB: dog_kennels | EX: ✗
  Q   : What are the arriving date and the departing date of the dogs who have gone through a treatment
  Pred: SELECT date_arrived, date_departed FROM dogs
  Gold: SELECT DISTINCT T1.date_arrived, T1.date_departed FROM Dogs AS T1 JOIN Treatments AS T2 ON T1.dog_id = T2.dog_id
  Type: JOIN

[610] WRONG_TABLE | DB: dog_kennels | EX: ✗
  Q   : Find the arriving date and the departing date of the dogs that received a treatment
  Pred: SELECT date_arrived, date_departed FROM treatments
  Gold: SELECT DISTINCT T1.date_arrived, T1.date_departed FROM Dogs AS T1 JOIN Treatments AS T2 ON T1.dog_id = T2.dog_id
  Type: JOIN

[611] WRONG_TABLE | DB: dog_kennels | EX: ✗
  Q   : List the last name of the owner owning the youngest dog
  Pred: SELECT last_name FROM owners ORDER BY age LIMIT 1
  Gold: SELECT T1.last_name FROM Owners AS T1 JOIN Dogs AS T2 ON T1.owner_id = T2.owner_id WHERE T2.age = (SELECT MAX(age) FROM Dogs)
  Type: JOIN, NESTED, AGGREGATION

[612] WRONG_TABLE | DB: dog_kennels | EX: ✗
  Q   : Who owns the youngest dog? Give me his or her last name
  Pred: SELECT last_name FROM dogs ORDER BY age LIMIT 1
  Gold: SELECT T1.last_name FROM Owners AS T1 JOIN Dogs AS T2 ON T1.owner_id = T2.owner_id WHERE T2.age = (SELECT MAX(age) FROM Dogs)
  Type: JOIN, NESTED, AGGREGATION

[613] WRONG_COLUMNS | DB: dog_kennels | EX: ✗
  Q   : How many dogs went through any treatments
  Pred: SELECT COUNT(*) FROM treatments
  Gold: SELECT COUNT(DISTINCT dog_id) FROM Treatments
  Type: AGGREGATION

[614] WRONG_COLUMNS | DB: dog_kennels | EX: ✗
  Q   : Count the number of dogs that went through a treatment
  Pred: SELECT COUNT(*) FROM treatments
  Gold: SELECT COUNT(DISTINCT dog_id) FROM Treatments
  Type: AGGREGATION

[615] WRONG_TABLE | DB: dog_kennels | EX: ✗
  Q   : How many professionals have performed any treatment to dogs
  Pred: SELECT COUNT(*) FROM treatments WHERE professional_id IN (SELECT professional_id FROM dogs)
  Gold: SELECT COUNT(DISTINCT professional_id) FROM Treatments
  Type: AGGREGATION

[616] WRONG_COLUMNS | DB: dog_kennels | EX: ✗
  Q   : Which professionals live in a city containing the substring 'West'? List his or her role, street, city and state
  Pred: SELECT role, street, city, state FROM Professionals WHERE city LIKE 'West%'
  Gold: SELECT role_code, street, city, state FROM professionals WHERE city LIKE '%West%'
  Type: SIMPLE

[617] WRONG_COLUMNS | DB: dog_kennels | EX: ✗
  Q   : Find the role, street, city and state of the professionals living in a city that contains the substring 'West'
  Pred: SELECT role, street, city, state FROM professionals WHERE city LIKE 'West%'
  Gold: SELECT role_code, street, city, state FROM professionals WHERE city LIKE '%West%'
  Type: SIMPLE

[618] OTHER | DB: dog_kennels | EX: ✓
  Q   : Which owners live in the state whose name contains the substring 'North'? List his first name, last name and email
  Pred: SELECT first_name, last_name, email_address FROM owners WHERE state LIKE 'North%'
  Gold: SELECT first_name, last_name, email_address FROM Owners WHERE state LIKE '%North%'
  Type: SIMPLE

[619] OTHER | DB: dog_kennels | EX: ✗
  Q   : How many dogs have an age below the average
  Pred: SELECT COUNT(*) FROM dogs WHERE age  (SELECT AVG(age) FROM dogs)
  Gold: SELECT COUNT(*) FROM Dogs WHERE age < (SELECT AVG(age) FROM Dogs)
  Type: NESTED, AGGREGATION

[620] OTHER | DB: dog_kennels | EX: ✗
  Q   : Count the number of dogs of an age below the average
  Pred: SELECT COUNT(*) FROM dogs WHERE age  (SELECT AVG(age) FROM dogs)
  Gold: SELECT COUNT(*) FROM Dogs WHERE age < (SELECT AVG(age) FROM Dogs)
  Type: NESTED, AGGREGATION

[621] WRONG_TABLE | DB: dog_kennels | EX: ✗
  Q   : How many owners temporarily do not have any dogs
  Pred: SELECT COUNT(*) FROM owners WHERE date_departed > "null"
  Gold: SELECT COUNT(*) FROM Owners WHERE NOT owner_id IN (SELECT owner_id FROM Dogs)
  Type: NESTED, AGGREGATION

[622] OTHER | DB: dog_kennels | EX: ✓
  Q   : List the dog name, age and weight of the dogs who have been abandoned? 1 stands for yes, and 0 stands for no
  Pred: SELECT name, age, weight FROM dogs WHERE abandoned_yn = 1 AND 0 = 0
  Gold: SELECT name, age, weight FROM Dogs WHERE abandoned_yn = 1
  Type: SIMPLE

[623] OTHER | DB: dog_kennels | EX: ✗
  Q   : What are the dog name, age and weight of the dogs that were abandoned? Note that 1 stands for yes, and 0 stands for no in the tables
  Pred: SELECT name, age, weight FROM dogs WHERE abandoned_yn = 1 UNION SELECT name, age, weight FROM dogs WHERE abandoned_yn = 0
  Gold: SELECT name, age, weight FROM Dogs WHERE abandoned_yn = 1
  Type: SIMPLE

[624] WRONG_COLUMNS | DB: dog_kennels | EX: ✗
  Q   : What is the age of the oldest dog
  Pred: SELECT age FROM dogs ORDER BY date_of_birth LIMIT 1
  Gold: SELECT MAX(age) FROM Dogs
  Type: AGGREGATION

[625] WRONG_COLUMNS | DB: dog_kennels | EX: ✗
  Q   : Tell me the age of the oldest dog
  Pred: SELECT age FROM dogs ORDER BY date_of_birth LIMIT 1
  Gold: SELECT MAX(age) FROM Dogs
  Type: AGGREGATION

[626] OTHER | DB: dog_kennels | EX: ✓
  Q   : How much does each charge type costs? List both charge type and amount
  Pred: SELECT charge_type, charge_amount FROM charges GROUP BY charge_type
  Gold: SELECT charge_type, charge_amount FROM Charges
  Type: SIMPLE

[627] WRONG_COLUMNS | DB: dog_kennels | EX: ✓
  Q   : How much does the most expensive charge type costs
  Pred: SELECT charge_amount FROM charges ORDER BY charge_type DESC LIMIT 1
  Gold: SELECT MAX(charge_amount) FROM Charges
  Type: AGGREGATION

[628] WRONG_COLUMNS | DB: dog_kennels | EX: ✓
  Q   : What is the charge amount of the most expensive charge type
  Pred: SELECT charge_amount FROM charges ORDER BY charge_type DESC LIMIT 1
  Gold: SELECT MAX(charge_amount) FROM Charges
  Type: AGGREGATION

[629] WRONG_TABLE | DB: dog_kennels | EX: ✗
  Q   : What are all the possible breed type and size type combinations
  Pred: SELECT DISTINCT breed_code, size_code FROM sizes
  Gold: SELECT DISTINCT breed_code, size_code FROM dogs
  Type: SIMPLE

[630] WRONG_COLUMNS | DB: dog_kennels | EX: ✗
  Q   : List the first name of all the professionals along with the description of the treatment they have done
  Pred: SELECT T1.first_name, T2.treatment_type_description FROM professionals AS T1 JOIN treatments AS T2 ON T1.professional_id = T2.professional_id
  Gold: SELECT DISTINCT T1.first_name, T3.treatment_type_description FROM professionals AS T1 JOIN Treatments AS T2 ON T1.professional_id = T2.professional_id JOIN Treatment_types AS T3 ON T2.treatment_type_code = T3.treatment_type_code
  Type: JOIN

[631] WRONG_COLUMNS | DB: dog_kennels | EX: ✗
  Q   : What are each professional's first name and description of the treatment they have performed
  Pred: SELECT T1.first_name, T1.treatment_type_description FROM professionals AS T1 JOIN treatments AS T2 ON T1.professional_id = T2.professional_id
  Gold: SELECT DISTINCT T1.first_name, T3.treatment_type_description FROM professionals AS T1 JOIN Treatments AS T2 ON T1.professional_id = T2.professional_id JOIN Treatment_types AS T3 ON T2.treatment_type_code = T3.treatment_type_code
  Type: JOIN

[632] OTHER | DB: singer | EX: ✗
  Q   : List the name of singers whose citizenship is not "France"
  Pred: SELECT Name FROM singer WHERE Citizenship > "France"
  Gold: SELECT Name FROM singer WHERE Citizenship <> "France"
  Type: SIMPLE

[633] OTHER | DB: singer | EX: ✗
  Q   : What are the names of the singers who are not French citizens
  Pred: SELECT Name FROM singer WHERE Citizenship > 'French'
  Gold: SELECT Name FROM singer WHERE Citizenship <> "France"
  Type: SIMPLE

[634] EXTRA_JOIN | DB: singer | EX: ✗
  Q   : What is the name of the singer who is worth the most
  Pred: SELECT T2.Name FROM singer AS T1 JOIN song AS T2 ON T1.Singer_ID = T2.Singer_ID ORDER BY net_worth_millions DESC LIMIT 1
  Gold: SELECT Name FROM singer ORDER BY Net_Worth_Millions DESC LIMIT 1
  Type: ORDER_BY, LIMIT

[635] WRONG_TABLE | DB: singer | EX: ✗
  Q   : Show titles of songs and names of singers
  Pred: SELECT T3.Title, T2.Name FROM song AS T1 JOIN singer AS T2 ON T1.Singer_ID = T2.Singer_ID
  Gold: SELECT T2.Title, T1.Name FROM singer AS T1 JOIN song AS T2 ON T1.Singer_ID = T2.Singer_ID
  Type: JOIN

[636] WRONG_TABLE | DB: singer | EX: ✗
  Q   : What are the song titles and singer names
  Pred: SELECT T2.Title, T1.Name FROM song AS T1 JOIN singer AS T2 ON T1.Singer_ID = T2.Singer_ID
  Gold: SELECT T2.Title, T1.Name FROM singer AS T1 JOIN song AS T2 ON T1.Singer_ID = T2.Singer_ID
  Type: JOIN

[637] MISSING_JOIN | DB: singer | EX: ✗
  Q   : For each singer name, what is the total sales for their songs
  Pred: SELECT SUM(Sales) FROM singer
  Gold: SELECT T1.Name, SUM(T2.Sales) FROM singer AS T1 JOIN song AS T2 ON T1.Singer_ID = T2.Singer_ID GROUP BY T1.Name
  Type: JOIN, GROUP_BY, AGGREGATION

[638] WRONG_COLUMNS | DB: singer | EX: ✗
  Q   : What is the sname of every sing that does not have any song
  Pred: SELECT name FROM singer WHERE NOT song_id IN (SELECT song_id FROM song)
  Gold: SELECT Name FROM singer WHERE NOT Singer_ID IN (SELECT Singer_ID FROM song)
  Type: NESTED

[639] OTHER | DB: singer | EX: ✗
  Q   : Show the citizenship shared by singers with birth year before 1945 and after 1955
  Pred: SELECT Citizenship FROM singer WHERE Birth_year  1945 INTERSECT SELECT Citizenship FROM singer WHERE Birth_year > 1955
  Gold: SELECT Citizenship FROM singer WHERE Birth_Year < 1945 INTERSECT SELECT Citizenship FROM singer WHERE Birth_Year > 1955
  Type: SIMPLE

[640] OTHER | DB: singer | EX: ✗
  Q   : What are the citizenships that are shared by singers with a birth year before 1945 and after 1955
  Pred: SELECT Citizenship FROM singer WHERE Birth_year  1945 INTERSECT SELECT Citizenship FROM singer WHERE Birth_year > 1955
  Gold: SELECT Citizenship FROM singer WHERE Birth_Year < 1945 INTERSECT SELECT Citizenship FROM singer WHERE Birth_Year > 1955
  Type: SIMPLE

[641] WRONG_TABLE | DB: real_estate_properties | EX: ✗
  Q   : What is the feature type name of feature AirCon
  Pred: SELECT T1.feature_type_name FROM Ref_Feature_Types AS T1 JOIN Ref_Feature_Types AS T2 ON T1.feature_type_code = T2.feature_type_code WHERE T2.feature_name = "AirCon"
  Gold: SELECT T2.feature_type_name FROM Other_Available_Features AS T1 JOIN Ref_Feature_Types AS T2 ON T1.feature_type_code = T2.feature_type_code WHERE T1.feature_name = "AirCon"
  Type: JOIN

[642] WRONG_TABLE | DB: real_estate_properties | EX: ✗
  Q   : Show the property type descriptions of properties belonging to that code
  Pred: SELECT T1.property_type_description FROM Ref_Property_Types AS T1 JOIN Properties AS T2 ON T1.property_type_code = T2.property_type_code
  Gold: SELECT T2.property_type_description FROM Properties AS T1 JOIN Ref_Property_Types AS T2 ON T1.property_type_code = T2.property_type_code GROUP BY T1.property_type_code
  Type: JOIN, GROUP_BY

[643] OTHER | DB: real_estate_properties | EX: ✗
  Q   : What are the names of properties that are either houses or apartments with more than 1 room
  Pred: SELECT property_name FROM Properties WHERE room_count > 1 AND property_name = 'House' OR room_count > 1 UNION SELECT property_name FROM Properties WHERE property_type_code = 'Apartment'
  Gold: SELECT property_name FROM Properties WHERE property_type_code = "House" UNION SELECT property_name FROM Properties WHERE property_type_code = "Apartment" AND room_count > 1
  Type: SIMPLE