spider/t5-base/run_3/error_analysis.txt

Spider Error Analysis — Run 3
EM norm: 33.37% | EX: 43.33%
================================================================================

[1] OTHER | DB: concert_singer | EX: ✓
  Q   : What is the average, minimum, and maximum age of all singers from France
  Pred: SELECT AVG(age), MIN(age), MAX(age) FROM singer WHERE Country = "France"
  Gold: SELECT AVG(age), MIN(age), MAX(age) FROM singer WHERE country = 'France'
  Type: AGGREGATION

[2] OTHER | DB: concert_singer | EX: ✓
  Q   : What is the average, minimum, and maximum age for all French singers
  Pred: SELECT AVG(age), MIN(age), MAX(age) FROM singer WHERE country = "France"
  Gold: SELECT AVG(age), MIN(age), MAX(age) FROM singer WHERE country = 'France'
  Type: AGGREGATION

[3] WRONG_COLUMNS | DB: concert_singer | EX: ✗
  Q   : What is the maximum capacity and the average of all stadiums
  Pred: SELECT MAX(capacity), AVG(capacity) FROM stadium
  Gold: SELECT MAX(capacity), average FROM stadium
  Type: AGGREGATION

[4] OTHER | DB: concert_singer | EX: ✓
  Q   : Show the stadium name and the number of concerts in each stadium
  Pred: SELECT T2.Name, COUNT(*) FROM concert AS T1 JOIN stadium AS T2 ON T1.Stadium_ID = T2.Stadium_ID GROUP BY T2.Stadium_ID
  Gold: SELECT T2.name, COUNT(*) FROM concert AS T1 JOIN stadium AS T2 ON T1.stadium_id = T2.stadium_id GROUP BY T1.stadium_id
  Type: JOIN, GROUP_BY, AGGREGATION

[5] MISSING_JOIN | DB: concert_singer | EX: ✗
  Q   : For each stadium, how many concerts play there
  Pred: SELECT stadium_id, COUNT(*) FROM concert GROUP BY stadium_id
  Gold: SELECT T2.name, COUNT(*) FROM concert AS T1 JOIN stadium AS T2 ON T1.stadium_id = T2.stadium_id GROUP BY T1.stadium_id
  Type: JOIN, GROUP_BY, AGGREGATION

[6] WRONG_COLUMNS | DB: concert_singer | EX: ✗
  Q   : Show the stadium name and capacity with most number of concerts in year 2014 or after
  Pred: SELECT T1.name, T2.capacity FROM concert AS T1 JOIN stadium AS T2 ON T1.stadium_id = T2.stadium_id WHERE T1.year >= 2014 GROUP BY T1.stadium_id ORDER BY AVG(T1.capacity) DESC LIMIT 1
  Gold: SELECT T2.name, T2.capacity FROM concert AS T1 JOIN stadium AS T2 ON T1.stadium_id = T2.stadium_id WHERE T1.year >= 2014 GROUP BY T2.stadium_id ORDER BY COUNT(*) DESC LIMIT 1
  Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, AGGREGATION

[7] WRONG_TABLE | DB: concert_singer | EX: ✗
  Q   : What is the name and capacity of the stadium with the most concerts after 2013
  Pred: SELECT T1.name, T1.capacity FROM stadium AS T1 JOIN concert AS T2 ON T1.stadium_id = T2.stadium_id WHERE T2.year > 2013 GROUP BY T1.stadium_id ORDER BY AVG(T2.capacity) DESC LIMIT 1
  Gold: SELECT t2.name, t2.capacity FROM concert AS t1 JOIN stadium AS t2 ON t1.stadium_id = t2.stadium_id WHERE t1.year > 2013 GROUP BY t2.stadium_id ORDER BY COUNT(*) DESC LIMIT 1
  Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, AGGREGATION

[8] OTHER | DB: concert_singer | EX: ✗
  Q   : Show countries where a singer above age 40 and a singer below 30 are from
  Pred: SELECT Country FROM singer WHERE Age > 40 INTERSECT SELECT Country FROM singer WHERE Age  30
  Gold: SELECT country FROM singer WHERE age > 40 INTERSECT SELECT country FROM singer WHERE age < 30
  Type: SIMPLE

[9] WRONG_TABLE | DB: concert_singer | EX: ✓
  Q   : Show names for all stadiums except for stadiums having a concert in year 2014
  Pred: SELECT name FROM stadium EXCEPT SELECT T1.name FROM stadium AS T1 JOIN concert AS T2 ON T1.stadium_id = T2.stadium_id WHERE T2.year = 2014
  Gold: SELECT name FROM stadium EXCEPT SELECT T2.name FROM concert AS T1 JOIN stadium AS T2 ON T1.stadium_id = T2.stadium_id WHERE T1.year = 2014
  Type: JOIN

[10] WRONG_TABLE | DB: concert_singer | EX: ✗
  Q   : What are the names of all stadiums that did not have a concert in 2014
  Pred: SELECT T1.Name FROM stadium AS T1 JOIN concert AS T2 ON T1.Stadium_ID = T2.Stadium_ID WHERE T2.Year > 2014
  Gold: SELECT name FROM stadium EXCEPT SELECT T2.name FROM concert AS T1 JOIN stadium AS T2 ON T1.stadium_id = T2.stadium_id WHERE T1.year = 2014
  Type: JOIN

[11] WRONG_TABLE | DB: concert_singer | EX: ✗
  Q   : Show the name and theme for all concerts and the number of singers in each concert
  Pred: SELECT Concert_Name, Theme, COUNT(*) FROM concert GROUP BY Concert_Name
  Gold: SELECT T2.concert_name, T2.theme, COUNT(*) FROM singer_in_concert AS T1 JOIN concert AS T2 ON T1.concert_id = T2.concert_id GROUP BY T2.concert_id
  Type: JOIN, GROUP_BY, AGGREGATION

[12] WRONG_TABLE | DB: concert_singer | EX: ✗
  Q   : What are the names , themes , and number of singers for every concert
  Pred: SELECT concert_name, theme, COUNT(*) FROM concert GROUP BY concert_name
  Gold: SELECT t2.concert_name, t2.theme, COUNT(*) FROM singer_in_concert AS t1 JOIN concert AS t2 ON t1.concert_id = t2.concert_id GROUP BY t2.concert_id
  Type: JOIN, GROUP_BY, AGGREGATION

[13] WRONG_TABLE | DB: concert_singer | EX: ✗
  Q   : List singer names and number of concerts for each singer
  Pred: SELECT T1.Name, COUNT(*) FROM singer AS T1 JOIN concert AS T2 ON T1.Singer_ID = T2.Singer_ID GROUP BY T1.Singer_ID
  Gold: SELECT T2.name, COUNT(*) FROM singer_in_concert AS T1 JOIN singer AS T2 ON T1.singer_id = T2.singer_id GROUP BY T2.singer_id
  Type: JOIN, GROUP_BY, AGGREGATION

[14] WRONG_TABLE | DB: concert_singer | EX: ✗
  Q   : What are the names of the singers and number of concerts for each person
  Pred: SELECT T1.Name, COUNT(*) FROM singer AS T1 JOIN concert AS T2 ON T1.Singer_ID = T2.Singer_ID GROUP BY T1.Singer_ID
  Gold: SELECT T2.name, COUNT(*) FROM singer_in_concert AS T1 JOIN singer AS T2 ON T1.singer_id = T2.singer_id GROUP BY T2.singer_id
  Type: JOIN, GROUP_BY, AGGREGATION

[15] WRONG_TABLE | DB: concert_singer | EX: ✗
  Q   : List all singer names in concerts in year 2014
  Pred: SELECT T2.Name FROM concert AS T1 JOIN singer AS T2 ON T1.Singer_ID = T2.Singer_ID WHERE T1.Year = 2014
  Gold: SELECT T2.name FROM singer_in_concert AS T1 JOIN singer AS T2 ON T1.singer_id = T2.singer_id JOIN concert AS T3 ON T1.concert_id = T3.concert_id WHERE T3.year = 2014
  Type: JOIN

[16] WRONG_TABLE | DB: concert_singer | EX: ✗
  Q   : What are the names of the singers who performed in a concert in 2014
  Pred: SELECT T1.Name FROM singer AS T1 JOIN singer_in_concert AS T2 ON T1.Singer_ID = T2.Singer_ID WHERE T2.Year = 2014
  Gold: SELECT T2.name FROM singer_in_concert AS T1 JOIN singer AS T2 ON T1.singer_id = T2.singer_id JOIN concert AS T3 ON T1.concert_id = T3.concert_id WHERE T3.year = 2014
  Type: JOIN

[17] WRONG_COLUMNS | DB: concert_singer | EX: ✗
  Q   : Find the name and location of the stadiums which some concerts happened in the years of both 2014 and 2015
  Pred: SELECT T2.Name, T2.Location FROM concert AS T1 JOIN stadium AS T2 ON T1.Stadium_ID = T2.Stadium_ID WHERE T1.Year = 2014 INTERSECT SELECT T1.Name, T2.Location FROM concert AS T1 JOIN stadium AS T2 ON T1.Stadium_ID = T2.Stadium_ID WHERE T2.Year = 2015
  Gold: SELECT T2.name, T2.location FROM concert AS T1 JOIN stadium AS T2 ON T1.stadium_id = T2.stadium_id WHERE T1.Year = 2014 INTERSECT SELECT T2.name, T2.location FROM concert AS T1 JOIN stadium AS T2 ON T1.stadium_id = T2.stadium_id WHERE T1.Year = 2015
  Type: JOIN

[18] WRONG_TABLE | DB: concert_singer | EX: ✓
  Q   : What are the names and locations of the stadiums that had concerts that occurred in both 2014 and 2015
  Pred: SELECT T1.Name, T1.Location FROM stadium AS T1 JOIN concert AS T2 ON T1.Stadium_ID = T2.Stadium_ID WHERE T2.Year = 2014 INTERSECT SELECT T1.Name, T1.Location FROM stadium AS T1 JOIN concert AS T2 ON T1.Stadium_ID = T2.Stadium_ID WHERE T2.Year = 2015
  Gold: SELECT T2.name, T2.location FROM concert AS T1 JOIN stadium AS T2 ON T1.stadium_id = T2.stadium_id WHERE T1.Year = 2014 INTERSECT SELECT T2.name, T2.location FROM concert AS T1 JOIN stadium AS T2 ON T1.stadium_id = T2.stadium_id WHERE T1.Year = 2015
  Type: JOIN

[19] WRONG_TABLE | DB: concert_singer | EX: ✗
  Q   : Find the number of concerts happened in the stadium with the highest capacity
  Pred: SELECT COUNT(*) FROM stadium ORDER BY capacity DESC LIMIT 1
  Gold: SELECT COUNT(*) FROM concert WHERE stadium_id = (SELECT stadium_id FROM stadium ORDER BY capacity DESC LIMIT 1)
  Type: ORDER_BY, LIMIT, NESTED, AGGREGATION

[20] WRONG_TABLE | DB: concert_singer | EX: ✗
  Q   : What are the number of concerts that occurred in the stadium with the largest capacity
  Pred: SELECT COUNT(*) FROM stadium ORDER BY capacity DESC LIMIT 1
  Gold: SELECT COUNT(*) FROM concert WHERE stadium_id = (SELECT stadium_id FROM stadium ORDER BY capacity DESC LIMIT 1)
  Type: ORDER_BY, LIMIT, NESTED, AGGREGATION

[21] OTHER | DB: pets_1 | EX: ✗
  Q   : Find the weight of the youngest dog
  Pred: SELECT weight FROM pets ORDER BY pet_age DESC LIMIT 1
  Gold: SELECT weight FROM pets ORDER BY pet_age LIMIT 1
  Type: ORDER_BY, LIMIT

[22] OTHER | DB: pets_1 | EX: ✓
  Q   : How much does the youngest dog weigh
  Pred: SELECT weight FROM pets ORDER BY weight LIMIT 1
  Gold: SELECT weight FROM pets ORDER BY pet_age LIMIT 1
  Type: ORDER_BY, LIMIT

[23] WRONG_TABLE | DB: pets_1 | EX: ✗
  Q   : Find number of pets owned by students who are older than 20
  Pred: SELECT COUNT(*) FROM Has_pet WHERE age > 20
  Gold: SELECT COUNT(*) FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid WHERE T1.age > 20
  Type: JOIN, AGGREGATION

[24] WRONG_TABLE | DB: pets_1 | EX: ✗
  Q   : How many pets are owned by students that have an age greater than 20
  Pred: SELECT COUNT(*) FROM Has_pet AS T1 JOIN pets AS T2 ON T1.petid = T2.petid WHERE T1.age > 20
  Gold: SELECT COUNT(*) FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid WHERE T1.age > 20
  Type: JOIN, AGGREGATION

[25] WRONG_TABLE | DB: pets_1 | EX: ✗
  Q   : Find the number of dog pets that are raised by female students (with sex F)
  Pred: SELECT COUNT(*) FROM Has_pet AS T1 JOIN pets AS T2 ON T1.petid = T2.petid WHERE T1.sex = 'F' GROUP BY T1.sex
  Gold: SELECT COUNT(*) FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid JOIN pets AS T3 ON T2.petid = T3.petid WHERE T1.sex = 'F' AND T3.pettype = 'dog'
  Type: JOIN, AGGREGATION

[26] WRONG_TABLE | DB: pets_1 | EX: ✗
  Q   : How many dog pets are raised by female students
  Pred: SELECT COUNT(*) FROM Has_pet WHERE Sex = 'F'
  Gold: SELECT COUNT(*) FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid JOIN pets AS T3 ON T2.petid = T3.petid WHERE T1.sex = 'F' AND T3.pettype = 'dog'
  Type: JOIN, AGGREGATION

[27] MISSING_JOIN | DB: pets_1 | EX: ✗
  Q   : Find the first name of students who have cat or dog pet
  Pred: SELECT fname FROM Student WHERE pettype = 'Cat' OR pettype = 'Dog'
  Gold: SELECT DISTINCT T1.Fname FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid JOIN pets AS T3 ON T3.petid = T2.petid WHERE T3.pettype = 'cat' OR T3.pettype = 'dog'
  Type: JOIN

[28] WRONG_TABLE | DB: pets_1 | EX: ✓
  Q   : What are the first names of every student who has a cat or dog as a pet
  Pred: SELECT fname FROM Student WHERE StuID IN (SELECT StuID FROM Has_pet)
  Gold: SELECT DISTINCT T1.Fname FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid JOIN pets AS T3 ON T3.petid = T2.petid WHERE T3.pettype = 'cat' OR T3.pettype = 'dog'
  Type: JOIN

[29] MISSING_JOIN | DB: pets_1 | EX: ✗
  Q   : Find the first name of students who have both cat and dog pets
  Pred: SELECT fname FROM student WHERE pettype = 'Cat' INTERSECT SELECT lname FROM student WHERE pettype = 'Dog'
  Gold: SELECT t1.fname FROM student AS t1 JOIN has_pet AS t2 ON t1.stuid = t2.stuid JOIN pets AS t3 ON t3.petid = t2.petid WHERE t3.pettype = 'cat' INTERSECT SELECT t1.fname FROM student AS t1 JOIN has_pet AS t2 ON t1.stuid = t2.stuid JOIN pets AS t3 ON t3.petid = t2.petid WHERE t3.pettype = 'dog'
  Type: JOIN

[30] MISSING_JOIN | DB: pets_1 | EX: ✗
  Q   : What are the students' first names who have both cats and dogs as pets
  Pred: SELECT fname FROM student WHERE pettype = 'Cat' INTERSECT SELECT lname FROM student WHERE pettype = 'Dog'
  Gold: SELECT T1.Fname FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid JOIN pets AS T3 ON T3.petid = T2.petid WHERE T3.pettype = 'cat' INTERSECT SELECT T1.Fname FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid JOIN pets AS T3 ON T3.petid = T2.petid WHERE T3.pettype = 'dog'
  Type: JOIN

[31] WRONG_TABLE | DB: pets_1 | EX: ✗
  Q   : Find the major and age of students who do not have a cat pet
  Pred: SELECT major, age FROM Student WHERE NOT StuID IN (SELECT StuID FROM Has_pet)
  Gold: SELECT major, age FROM student WHERE NOT stuid IN (SELECT T1.stuid FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid JOIN pets AS T3 ON T3.petid = T2.petid WHERE T3.pettype = 'cat')
  Type: JOIN, NESTED

[32] WRONG_TABLE | DB: pets_1 | EX: ✗
  Q   : What major is every student who does not own a cat as a pet, and also how old are they
  Pred: SELECT major, age FROM Student WHERE NOT StuID IN (SELECT StuID FROM Has_pet)
  Gold: SELECT major, age FROM student WHERE NOT stuid IN (SELECT T1.stuid FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid JOIN pets AS T3 ON T3.petid = T2.petid WHERE T3.pettype = 'cat')
  Type: JOIN, NESTED

[33] WRONG_TABLE | DB: pets_1 | EX: ✗
  Q   : Find the id of students who do not have a cat pet
  Pred: SELECT StuID FROM Student EXCEPT SELECT StuID FROM Has_pet
  Gold: SELECT stuid FROM student EXCEPT SELECT T1.stuid FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid JOIN pets AS T3 ON T3.petid = T2.petid WHERE T3.pettype = 'cat'
  Type: JOIN

[34] WRONG_TABLE | DB: pets_1 | EX: ✗
  Q   : What are the ids of the students who do not own cats as pets
  Pred: SELECT StuID FROM Student EXCEPT SELECT StuID FROM Has_pet
  Gold: SELECT stuid FROM student EXCEPT SELECT T1.stuid FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid JOIN pets AS T3 ON T3.petid = T2.petid WHERE T3.pettype = 'cat'
  Type: JOIN

[35] WRONG_TABLE | DB: pets_1 | EX: ✗
  Q   : Find the first name and age of students who have a dog but do not have a cat as a pet
  Pred: SELECT fname, age FROM Student WHERE StuID IN (SELECT StuID FROM Has_pet)
  Gold: SELECT T1.fname, T1.age FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid JOIN pets AS T3 ON T3.petid = T2.petid WHERE T3.pettype = 'dog' AND NOT T1.stuid IN (SELECT T1.stuid FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid JOIN pets AS T3 ON T3.petid = T2.petid WHERE T3.pettype = 'cat')
  Type: JOIN, NESTED

[36] WRONG_TABLE | DB: pets_1 | EX: ✗
  Q   : What is the first name of every student who has a dog but does not have a cat
  Pred: SELECT fname FROM Student EXCEPT SELECT lname FROM Student WHERE StuID IN (SELECT StuID FROM Has_pet)
  Gold: SELECT T1.fname, T1.age FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid JOIN pets AS T3 ON T3.petid = T2.petid WHERE T3.pettype = 'dog' AND NOT T1.stuid IN (SELECT T1.stuid FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid JOIN pets AS T3 ON T3.petid = T2.petid WHERE T3.pettype = 'cat')
  Type: JOIN, NESTED

[37] OTHER | DB: pets_1 | EX: ✗
  Q   : Find the type and weight of the youngest pet
  Pred: SELECT pettype, weight FROM pets ORDER BY pet_age DESC LIMIT 1
  Gold: SELECT pettype, weight FROM pets ORDER BY pet_age LIMIT 1
  Type: ORDER_BY, LIMIT

[38] OTHER | DB: pets_1 | EX: ✗
  Q   : What type of pet is the youngest animal, and how much does it weigh
  Pred: SELECT pettype, weight FROM pets ORDER BY pet_age DESC LIMIT 1
  Gold: SELECT pettype, weight FROM pets ORDER BY pet_age LIMIT 1
  Type: ORDER_BY, LIMIT

[39] MISSING_GROUP_BY | DB: pets_1 | EX: ✗
  Q   : Find the average and maximum age for each type of pet
  Pred: SELECT AVG(pet_age), MAX(pet_age) FROM pets
  Gold: SELECT AVG(pet_age), MAX(pet_age), pettype FROM pets GROUP BY pettype
  Type: GROUP_BY, AGGREGATION

[40] MISSING_GROUP_BY | DB: pets_1 | EX: ✗
  Q   : What is the average and maximum age for each pet type
  Pred: SELECT AVG(pet_age), MAX(pet_age) FROM pets
  Gold: SELECT AVG(pet_age), MAX(pet_age), pettype FROM pets GROUP BY pettype
  Type: GROUP_BY, AGGREGATION

[41] WRONG_COLUMNS | DB: pets_1 | EX: ✗
  Q   : Find the average weight for each pet type
  Pred: SELECT pettype, AVG(weight) FROM pets GROUP BY pettype
  Gold: SELECT AVG(weight), pettype FROM pets GROUP BY pettype
  Type: GROUP_BY, AGGREGATION

[42] WRONG_COLUMNS | DB: pets_1 | EX: ✗
  Q   : What is the average weight for each type of pet
  Pred: SELECT pettype, AVG(weight) FROM pets GROUP BY pettype
  Gold: SELECT AVG(weight), pettype FROM pets GROUP BY pettype
  Type: GROUP_BY, AGGREGATION

[43] WRONG_TABLE | DB: pets_1 | EX: ✓
  Q   : Find the first name and age of students who have a pet
  Pred: SELECT fname, age FROM Student WHERE StuID IN (SELECT StuID FROM Has_pet)
  Gold: SELECT DISTINCT T1.fname, T1.age FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid
  Type: JOIN

[44] WRONG_TABLE | DB: pets_1 | EX: ✗
  Q   : What are the different first names and ages of the students who do have pets
  Pred: SELECT DISTINCT Fname, Age FROM Student WHERE NOT StuID IN (SELECT StuID FROM Has_pet)
  Gold: SELECT DISTINCT T1.fname, T1.age FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid
  Type: JOIN

[45] WRONG_TABLE | DB: pets_1 | EX: ✗
  Q   : Find the id of the pet owned by student whose last name is ‘Smith’
  Pred: SELECT t1.petid FROM Has_pet AS t1 JOIN pets AS t2 ON t1.petid = t2.petid WHERE t1.lname = 'Smith'
  Gold: SELECT T2.petid FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid WHERE T1.Lname = 'Smith'
  Type: JOIN

[46] WRONG_TABLE | DB: pets_1 | EX: ✗
  Q   : What is the id of the pet owned by the student whose last name is 'Smith'
  Pred: SELECT T1.petid FROM Has_pet AS T1 JOIN pets AS T2 ON T1.petid = T2.petid WHERE T2.lname = 'Smith'
  Gold: SELECT T2.petid FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid WHERE T1.Lname = 'Smith'
  Type: JOIN

[47] WRONG_TABLE | DB: pets_1 | EX: ✗
  Q   : Find the number of pets for each student who has any pet and student id
  Pred: SELECT COUNT(*), STUDENT FROM Has_pet GROUP BY STUDENT
  Gold: SELECT COUNT(*), T1.stuid FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid GROUP BY T1.stuid
  Type: JOIN, GROUP_BY, AGGREGATION

[48] WRONG_COLUMNS | DB: pets_1 | EX: ✗
  Q   : For students who have pets , how many pets does each student have ? list their ids instead of names
  Pred: SELECT COUNT(*) FROM Student AS T1 JOIN Has_pet AS T2 ON T1.StuID = T2.StuID GROUP BY T1.StuID
  Gold: SELECT COUNT(*), t1.stuid FROM student AS t1 JOIN has_pet AS t2 ON t1.stuid = t2.stuid GROUP BY t1.stuid
  Type: JOIN, GROUP_BY, AGGREGATION

[49] WRONG_TABLE | DB: pets_1 | EX: ✗
  Q   : Find the first name and gender of student who have more than one pet
  Pred: SELECT fname, sex FROM Student WHERE StuID IN (SELECT StuID FROM Has_pet)
  Gold: SELECT T1.fname, T1.sex FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid GROUP BY T1.stuid HAVING COUNT(*) > 1
  Type: JOIN, GROUP_BY, HAVING, AGGREGATION

[50] WRONG_TABLE | DB: pets_1 | EX: ✗
  Q   : What is the first name and gender of the all the students who have more than one pet
  Pred: SELECT fname, sex FROM Student WHERE StuID IN (SELECT StuID FROM Has_pet)
  Gold: SELECT T1.fname, T1.sex FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid GROUP BY T1.stuid HAVING COUNT(*) > 1
  Type: JOIN, GROUP_BY, HAVING, AGGREGATION

[51] MISSING_JOIN | DB: pets_1 | EX: ✗
  Q   : Find the last name of the student who has a cat that is age 3
  Pred: SELECT lname FROM Student WHERE age = 3
  Gold: SELECT T1.lname FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid JOIN pets AS T3 ON T3.petid = T2.petid WHERE T3.pet_age = 3 AND T3.pettype = 'cat'
  Type: JOIN

[52] MISSING_JOIN | DB: pets_1 | EX: ✗
  Q   : What is the last name of the student who has a cat that is 3 years old
  Pred: SELECT lname FROM Student WHERE age = 3
  Gold: SELECT T1.lname FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid JOIN pets AS T3 ON T3.petid = T2.petid WHERE T3.pet_age = 3 AND T3.pettype = 'cat'
  Type: JOIN

[53] WRONG_TABLE | DB: pets_1 | EX: ✗
  Q   : Find the average age of students who do not have any pet
  Pred: SELECT AVG(T1.age) FROM Student AS T1 JOIN Has_pet AS T2 ON T1.StuID = T2.StuID WHERE T2.petType = 'pet'
  Gold: SELECT AVG(age) FROM student WHERE NOT stuid IN (SELECT stuid FROM has_pet)
  Type: NESTED, AGGREGATION

[54] WRONG_TABLE | DB: pets_1 | EX: ✗
  Q   : What is the average age for all students who do not own any pets
  Pred: SELECT AVG(T1.age) FROM Student AS T1 JOIN has_pet AS T2 ON T1.StuID = T2.StuID WHERE T2.petType = 'pet'
  Gold: SELECT AVG(age) FROM student WHERE NOT stuid IN (SELECT stuid FROM has_pet)
  Type: NESTED, AGGREGATION

[55] WRONG_TABLE | DB: car_1 | EX: ✗
  Q   : How many countries does each continent have? List the continent id, continent name and the number of countries
  Pred: SELECT T1.contid, T1.contid, COUNT(*) FROM countries AS T1 JOIN continents AS T2 ON T1.contid = T2.contid GROUP BY T1.contid
  Gold: SELECT T1.ContId, T1.Continent, COUNT(*) FROM CONTINENTS AS T1 JOIN COUNTRIES AS T2 ON T1.ContId = T2.Continent GROUP BY T1.ContId
  Type: JOIN, GROUP_BY, AGGREGATION

[56] MISSING_JOIN | DB: car_1 | EX: ✗
  Q   : For each continent, list its id, name, and how many countries it has
  Pred: SELECT continent, countryname, COUNT(*) FROM continents GROUP BY continent
  Gold: SELECT T1.ContId, T1.Continent, COUNT(*) FROM CONTINENTS AS T1 JOIN COUNTRIES AS T2 ON T1.ContId = T2.Continent GROUP BY T1.ContId
  Type: JOIN, GROUP_BY, AGGREGATION

[57] MISSING_JOIN | DB: car_1 | EX: ✗
  Q   : How many models does each car maker produce? List maker full name, id and the number
  Pred: SELECT fullname, id, COUNT(*) FROM car_makers GROUP BY maker
  Gold: SELECT T1.FullName, T1.Id, COUNT(*) FROM CAR_MAKERS AS T1 JOIN MODEL_LIST AS T2 ON T1.Id = T2.Maker GROUP BY T1.Id
  Type: JOIN, GROUP_BY, AGGREGATION

[58] MISSING_JOIN | DB: car_1 | EX: ✗
  Q   : What is the full name of each car maker, along with its id and how many models it produces
  Pred: SELECT fullname, id, COUNT(*) FROM car_makers GROUP BY maker
  Gold: SELECT T1.FullName, T1.Id, COUNT(*) FROM CAR_MAKERS AS T1 JOIN MODEL_LIST AS T2 ON T1.Id = T2.Maker GROUP BY T1.Id
  Type: JOIN, GROUP_BY, AGGREGATION

[59] WRONG_COLUMNS | DB: car_1 | EX: ✗
  Q   : Which model of the car has the minimum horsepower
  Pred: SELECT DISTINCT t1.model FROM car_names AS t1 JOIN model_list AS t2 ON t1.model = t2.model ORDER BY horsepower LIMIT 1
  Gold: SELECT T1.Model FROM CAR_NAMES AS T1 JOIN CARS_DATA AS T2 ON T1.MakeId = T2.Id ORDER BY T2.horsepower ASC LIMIT 1
  Type: JOIN, ORDER_BY, LIMIT

[60] WRONG_COLUMNS | DB: car_1 | EX: ✗
  Q   : What is the model of the car with the smallest amount of horsepower
  Pred: SELECT DISTINCT t1.model FROM car_names AS t1 JOIN model_list AS t2 ON t1.model = t2.model ORDER BY horsepower LIMIT 1
  Gold: SELECT T1.Model FROM CAR_NAMES AS T1 JOIN CARS_DATA AS T2 ON T1.MakeId = T2.Id ORDER BY T2.horsepower ASC LIMIT 1
  Type: JOIN, ORDER_BY, LIMIT

[61] MISSING_JOIN | DB: car_1 | EX: ✗
  Q   : Find the model of the car whose weight is below the average weight
  Pred: SELECT model FROM car_names WHERE weight  (SELECT AVG(weight) FROM cars_data)
  Gold: SELECT T1.model FROM CAR_NAMES AS T1 JOIN CARS_DATA AS T2 ON T1.MakeId = T2.Id WHERE T2.Weight < (SELECT AVG(Weight) FROM CARS_DATA)
  Type: JOIN, NESTED, AGGREGATION

[62] MISSING_JOIN | DB: car_1 | EX: ✗
  Q   : What is the model for the car with a weight smaller than the average
  Pred: SELECT model FROM car_names WHERE weight  (SELECT AVG(weight) FROM cars_data)
  Gold: SELECT T1.model FROM CAR_NAMES AS T1 JOIN CARS_DATA AS T2 ON T1.MakeId = T2.Id WHERE T2.Weight < (SELECT AVG(Weight) FROM CARS_DATA)
  Type: JOIN, NESTED, AGGREGATION

[63] WRONG_COLUMNS | DB: car_1 | EX: ✗
  Q   : Find the name of the makers that produced some cars in the year of 1970
  Pred: SELECT T1.maker FROM car_makers AS T1 JOIN car_names AS T2 ON T1.id = T2.maker WHERE T2.year = 1970
  Gold: SELECT DISTINCT T1.Maker FROM CAR_MAKERS AS T1 JOIN MODEL_LIST AS T2 ON T1.Id = T2.Maker JOIN CAR_NAMES AS T3 ON T2.model = T3.model JOIN CARS_DATA AS T4 ON T3.MakeId = T4.id WHERE T4.year = '1970'
  Type: JOIN

[64] OTHER | DB: car_1 | EX: ✗
  Q   : What is the name of the different car makers who produced a car in 1970
  Pred: SELECT DISTINCT T1.maker FROM car_makers AS T1 JOIN car_names AS T2 ON T1.id = T2.maker WHERE T2.year = 1970
  Gold: SELECT DISTINCT T1.Maker FROM CAR_MAKERS AS T1 JOIN MODEL_LIST AS T2 ON T1.Id = T2.Maker JOIN CAR_NAMES AS T3 ON T2.model = T3.model JOIN CARS_DATA AS T4 ON T3.MakeId = T4.id WHERE T4.year = '1970'
  Type: JOIN

[65] WRONG_TABLE | DB: car_1 | EX: ✗
  Q   : Find the make and production time of the cars that were produced in the earliest year
  Pred: SELECT T1.make, T1.year FROM car_names AS T1 JOIN cars_data AS T2 ON T1.id = T2.makeid GROUP BY T1.year ORDER BY COUNT(*) DESC LIMIT 1
  Gold: SELECT T2.Make, T1.Year FROM CARS_DATA AS T1 JOIN CAR_NAMES AS T2 ON T1.Id = T2.MakeId WHERE T1.Year = (SELECT MIN(YEAR) FROM CARS_DATA)
  Type: JOIN, NESTED, AGGREGATION

[66] WRONG_TABLE | DB: car_1 | EX: ✗
  Q   : What is the maker of the carr produced in the earliest year and what year was it
  Pred: SELECT T1.maker, T1.year FROM car_makers AS T1 JOIN car_makers AS T2 ON T1.id = T2.maker GROUP BY T1.maker ORDER BY COUNT(*) DESC LIMIT 1
  Gold: SELECT T2.Make, T1.Year FROM CARS_DATA AS T1 JOIN CAR_NAMES AS T2 ON T1.Id = T2.MakeId WHERE T1.Year = (SELECT MIN(YEAR) FROM CARS_DATA)
  Type: JOIN, NESTED, AGGREGATION

[67] WRONG_TABLE | DB: car_1 | EX: ✗
  Q   : Which distinct car models are the produced after 1980
  Pred: SELECT DISTINCT model FROM car_names WHERE YEAR > 1980
  Gold: SELECT DISTINCT T1.model FROM MODEL_LIST AS T1 JOIN CAR_NAMES AS T2 ON T1.model = T2.model JOIN CARS_DATA AS T3 ON T2.MakeId = T3.id WHERE T3.year > 1980
  Type: JOIN

[68] OTHER | DB: car_1 | EX: ✗
  Q   : What are the different models for the cards produced after 1980
  Pred: SELECT DISTINCT T1.model FROM model_list AS T1 JOIN car_names AS T2 ON T1.model = T2.model WHERE T2.year > 1980
  Gold: SELECT DISTINCT T1.model FROM MODEL_LIST AS T1 JOIN CAR_NAMES AS T2 ON T1.model = T2.model JOIN CARS_DATA AS T3 ON T2.MakeId = T3.id WHERE T3.year > 1980
  Type: JOIN

[69] MISSING_JOIN | DB: car_1 | EX: ✗
  Q   : How many car makers are there in each continents? List the continent name and the count
  Pred: SELECT COUNT(*), continent FROM continents GROUP BY continent
  Gold: SELECT T1.Continent, COUNT(*) FROM CONTINENTS AS T1 JOIN COUNTRIES AS T2 ON T1.ContId = T2.continent JOIN car_makers AS T3 ON T2.CountryId = T3.Country GROUP BY T1.Continent
  Type: JOIN, GROUP_BY, AGGREGATION

[70] WRONG_TABLE | DB: car_1 | EX: ✗
  Q   : What is the name of each continent and how many car makers are there in each one
  Pred: SELECT continent, COUNT(*) FROM countries GROUP BY continent
  Gold: SELECT T1.Continent, COUNT(*) FROM CONTINENTS AS T1 JOIN COUNTRIES AS T2 ON T1.ContId = T2.continent JOIN car_makers AS T3 ON T2.CountryId = T3.Country GROUP BY T1.Continent
  Type: JOIN, GROUP_BY, AGGREGATION

[71] MISSING_JOIN | DB: car_1 | EX: ✗
  Q   : Which of the countries has the most car makers? List the country name
  Pred: SELECT countryname FROM car_makers GROUP BY countryname ORDER BY COUNT(*) DESC LIMIT 1
  Gold: SELECT T2.CountryName FROM CAR_MAKERS AS T1 JOIN COUNTRIES AS T2 ON T1.Country = T2.CountryId GROUP BY T1.Country ORDER BY COUNT(*) DESC LIMIT 1
  Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, AGGREGATION

[72] MISSING_JOIN | DB: car_1 | EX: ✗
  Q   : What is the name of the country with the most car makers
  Pred: SELECT countryname FROM car_makers GROUP BY countryname ORDER BY COUNT(*) DESC LIMIT 1
  Gold: SELECT T2.CountryName FROM CAR_MAKERS AS T1 JOIN COUNTRIES AS T2 ON T1.Country = T2.CountryId GROUP BY T1.Country ORDER BY COUNT(*) DESC LIMIT 1
  Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, AGGREGATION

[73] WRONG_TABLE | DB: car_1 | EX: ✗
  Q   : How many car models are produced by each maker ? Only list the count and the maker full name
  Pred: SELECT COUNT(*), T1.fullname FROM car_makers AS T1 JOIN model_list AS T2 ON T1.maker = T2.id GROUP BY T1.maker
  Gold: SELECT COUNT(*), t2.fullname FROM model_list AS t1 JOIN car_makers AS t2 ON t1.maker = t2.id GROUP BY t2.id
  Type: JOIN, GROUP_BY, AGGREGATION

[74] WRONG_TABLE | DB: car_1 | EX: ✗
  Q   : What is the number of car models that are produced by each maker and what is the id and full name of each maker
  Pred: SELECT COUNT(*), T1.id, T1.fullname FROM car_makers AS T1 JOIN model_list AS T2 ON T1.maker = T2.id GROUP BY T1.maker
  Gold: SELECT COUNT(*), T2.FullName, T2.id FROM MODEL_LIST AS T1 JOIN CAR_MAKERS AS T2 ON T1.Maker = T2.Id GROUP BY T2.id
  Type: JOIN, GROUP_BY, AGGREGATION

[75] WRONG_TABLE | DB: car_1 | EX: ✗
  Q   : What is the accelerate of the car make amc hornet sportabout (sw)
  Pred: SELECT accelerate FROM car_names WHERE make = "amc hornet sportabout" AND fullname = "sw"
  Gold: SELECT T1.Accelerate FROM CARS_DATA AS T1 JOIN CAR_NAMES AS T2 ON T1.Id = T2.MakeId WHERE T2.Make = 'amc hornet sportabout (sw)'
  Type: JOIN

[76] WRONG_COLUMNS | DB: car_1 | EX: ✗
  Q   : How much does the car accelerate that makes amc hornet sportabout (sw)
  Pred: SELECT COUNT(*) FROM cars_data AS T1 JOIN car_names AS T2 ON T1.id = T2.makeid WHERE T2.make = 'amc hornet sportabout' AND T2.powertrain = 'sw'
  Gold: SELECT T1.Accelerate FROM CARS_DATA AS T1 JOIN CAR_NAMES AS T2 ON T1.Id = T2.MakeId WHERE T2.Make = 'amc hornet sportabout (sw)'
  Type: JOIN

[77] MISSING_JOIN | DB: car_1 | EX: ✗
  Q   : How many car makers are there in france
  Pred: SELECT COUNT(*) FROM car_makers WHERE country = "France"
  Gold: SELECT COUNT(*) FROM CAR_MAKERS AS T1 JOIN COUNTRIES AS T2 ON T1.Country = T2.CountryId WHERE T2.CountryName = 'france'
  Type: JOIN, AGGREGATION

[78] WRONG_TABLE | DB: car_1 | EX: ✗
  Q   : What is the number of makers of care in France
  Pred: SELECT COUNT(*) FROM countries AS T1 JOIN car_makers AS T2 ON T1.country = T2.countryid WHERE T1.country = "France"
  Gold: SELECT COUNT(*) FROM CAR_MAKERS AS T1 JOIN COUNTRIES AS T2 ON T1.Country = T2.CountryId WHERE T2.CountryName = 'france'
  Type: JOIN, AGGREGATION

[79] WRONG_TABLE | DB: car_1 | EX: ✗
  Q   : How many car models are produced in the usa
  Pred: SELECT COUNT(*) FROM countries AS T1 JOIN car_makers AS T2 ON T1.country = T2.countryid WHERE T1.country = "USA"
  Gold: SELECT COUNT(*) FROM MODEL_LIST AS T1 JOIN CAR_MAKERS AS T2 ON T1.Maker = T2.Id JOIN COUNTRIES AS T3 ON T2.Country = T3.CountryId WHERE T3.CountryName = 'usa'
  Type: JOIN, AGGREGATION

[80] WRONG_TABLE | DB: car_1 | EX: ✗
  Q   : What is the count of the car models produced in the United States
  Pred: SELECT COUNT(*) FROM countries AS T1 JOIN car_makers AS T2 ON T1.country = T2.countryid WHERE T1.country = "United States"
  Gold: SELECT COUNT(*) FROM MODEL_LIST AS T1 JOIN CAR_MAKERS AS T2 ON T1.Maker = T2.Id JOIN COUNTRIES AS T3 ON T2.Country = T3.CountryId WHERE T3.CountryName = 'usa'
  Type: JOIN, AGGREGATION

[81] OTHER | DB: car_1 | EX: ✓
  Q   : What is the smallest weight of the car produced with 8 cylinders on 1974
  Pred: SELECT MIN(weight) FROM cars_data WHERE YEAR = 1974 AND cylinders = 8
  Gold: SELECT MIN(weight) FROM cars_data WHERE cylinders = 8 AND year = 1974
  Type: AGGREGATION

[82] WRONG_COLUMNS | DB: car_1 | EX: ✗
  Q   : What is the minimum weight of the car with 8 cylinders produced in 1974
  Pred: SELECT MIN(weight), cylinders FROM cars_data WHERE YEAR = 1974 AND cylinders = 8
  Gold: SELECT MIN(weight) FROM cars_data WHERE cylinders = 8 AND year = 1974
  Type: AGGREGATION

[83] EXTRA_JOIN | DB: car_1 | EX: ✗
  Q   : What are the makers and models
  Pred: SELECT T1.maker, T1.model FROM model_list AS T1 JOIN car_makers AS T2 ON T1.id = T2.maker
  Gold: SELECT Maker, Model FROM MODEL_LIST
  Type: SIMPLE

[84] WRONG_TABLE | DB: car_1 | EX: ✗
  Q   : What are the countries having at least one car maker? List name and id
  Pred: SELECT countryname, countryid FROM car_makers GROUP BY countryid HAVING COUNT(*) >= 1
  Gold: SELECT T1.CountryName, T1.CountryId FROM COUNTRIES AS T1 JOIN CAR_MAKERS AS T2 ON T1.CountryId = T2.Country GROUP BY T1.CountryId HAVING COUNT(*) >= 1
  Type: JOIN, GROUP_BY, HAVING, AGGREGATION

[85] WRONG_TABLE | DB: car_1 | EX: ✗
  Q   : What are the names and ids of all countries with at least one car maker
  Pred: SELECT countryname, countryid FROM car_makers GROUP BY countryid HAVING COUNT(*) >= 1
  Gold: SELECT T1.CountryName, T1.CountryId FROM COUNTRIES AS T1 JOIN CAR_MAKERS AS T2 ON T1.CountryId = T2.Country GROUP BY T1.CountryId HAVING COUNT(*) >= 1
  Type: JOIN, GROUP_BY, HAVING, AGGREGATION

[86] MISSING_JOIN | DB: car_1 | EX: ✗
  Q   : Which countries in europe have at least 3 car manufacturers
  Pred: SELECT countryname FROM countries WHERE continent = "Europe" GROUP BY countryname HAVING COUNT(*) >= 3
  Gold: SELECT T1.CountryName FROM COUNTRIES AS T1 JOIN CONTINENTS AS T2 ON T1.Continent = T2.ContId JOIN CAR_MAKERS AS T3 ON T1.CountryId = T3.Country WHERE T2.Continent = 'europe' GROUP BY T1.CountryName HAVING COUNT(*) >= 3
  Type: JOIN, GROUP_BY, HAVING, AGGREGATION

[87] MISSING_JOIN | DB: car_1 | EX: ✗
  Q   : What are the names of all European countries with at least 3 manufacturers
  Pred: SELECT countryname FROM countries WHERE continent = "Europe" GROUP BY countryname HAVING COUNT(*) >= 3
  Gold: SELECT T1.CountryName FROM COUNTRIES AS T1 JOIN CONTINENTS AS T2 ON T1.Continent = T2.ContId JOIN CAR_MAKERS AS T3 ON T1.CountryId = T3.Country WHERE T2.Continent = 'europe' GROUP BY T1.CountryName HAVING COUNT(*) >= 3
  Type: JOIN, GROUP_BY, HAVING, AGGREGATION

[88] WRONG_TABLE | DB: car_1 | EX: ✗
  Q   : What is the maximum horsepower and the make of the car models with 3 cylinders
  Pred: SELECT MAX(horsepower), MAX(make) FROM cars_data WHERE cylinders = 3
  Gold: SELECT T2.horsepower, T1.Make FROM CAR_NAMES AS T1 JOIN CARS_DATA AS T2 ON T1.MakeId = T2.Id WHERE T2.cylinders = 3 ORDER BY T2.horsepower DESC LIMIT 1
  Type: JOIN, ORDER_BY, LIMIT

[89] WRONG_TABLE | DB: car_1 | EX: ✗
  Q   : What is the largest amount of horsepower for the models with 3 cylinders and what make is it
  Pred: SELECT MAX(HP), MAKE FROM cars_data WHERE cylinders = 3 GROUP BY MAKE
  Gold: SELECT T2.horsepower, T1.Make FROM CAR_NAMES AS T1 JOIN CARS_DATA AS T2 ON T1.MakeId = T2.Id WHERE T2.cylinders = 3 ORDER BY T2.horsepower DESC LIMIT 1
  Type: JOIN, ORDER_BY, LIMIT

[90] WRONG_TABLE | DB: car_1 | EX: ✗
  Q   : Which model saves the most gasoline? That is to say, have the maximum miles per gallon
  Pred: SELECT DISTINCT t1.model FROM model_list AS t1 JOIN cars_data AS t2 ON t1.model = t2.model WHERE t2.mpg = (SELECT MAX(mpg) FROM cars_data)
  Gold: SELECT T1.Model FROM CAR_NAMES AS T1 JOIN CARS_DATA AS T2 ON T1.MakeId = T2.Id ORDER BY T2.mpg DESC LIMIT 1
  Type: JOIN, ORDER_BY, LIMIT

[91] WRONG_TABLE | DB: car_1 | EX: ✗
  Q   : What is the car model with the highest mpg
  Pred: SELECT DISTINCT T1.model FROM cars_data AS T1 JOIN model_list AS T2 ON T1.model = T2.model ORDER BY T2.mpg DESC LIMIT 1
  Gold: SELECT t1.model FROM car_names AS t1 JOIN cars_data AS t2 ON t1.makeid = t2.id ORDER BY t2.mpg DESC LIMIT 1
  Type: JOIN, ORDER_BY, LIMIT

[92] OTHER | DB: car_1 | EX: ✗
  Q   : What is the average horsepower of the cars before 1980
  Pred: SELECT AVG(horsepower) FROM cars_data WHERE YEAR  1980
  Gold: SELECT AVG(horsepower) FROM CARS_DATA WHERE YEAR < 1980
  Type: AGGREGATION

[93] OTHER | DB: car_1 | EX: ✗
  Q   : What is the average horsepower for all cars produced before 1980
  Pred: SELECT AVG(horsepower) FROM cars_data WHERE YEAR  1980
  Gold: SELECT AVG(horsepower) FROM cars_data WHERE year < 1980
  Type: AGGREGATION

[94] MISSING_JOIN | DB: car_1 | EX: ✗
  Q   : What is the average edispl of the cars of model volvo
  Pred: SELECT AVG(edispl) FROM car_names WHERE model = "Volvo"
  Gold: SELECT AVG(T2.edispl) FROM CAR_NAMES AS T1 JOIN CARS_DATA AS T2 ON T1.MakeId = T2.Id WHERE T1.Model = 'volvo'
  Type: JOIN, AGGREGATION

[95] WRONG_TABLE | DB: car_1 | EX: ✗
  Q   : What is the average edispl for all volvos
  Pred: SELECT AVG(edispl) FROM cars_data WHERE cylinders = 'Volvo'
  Gold: SELECT AVG(T2.edispl) FROM CAR_NAMES AS T1 JOIN CARS_DATA AS T2 ON T1.MakeId = T2.Id WHERE T1.Model = 'volvo'
  Type: JOIN, AGGREGATION

[96] WRONG_COLUMNS | DB: car_1 | EX: ✗
  Q   : What is the maximum accelerate for different number of cylinders
  Pred: SELECT MAX(accurate), COUNT(*) FROM cars_data GROUP BY cylinders
  Gold: SELECT MAX(Accelerate), Cylinders FROM CARS_DATA GROUP BY Cylinders
  Type: GROUP_BY, AGGREGATION

[97] MISSING_GROUP_BY | DB: car_1 | EX: ✗
  Q   : What is the maximum accelerate for all the different cylinders
  Pred: SELECT MAX(accurate) FROM cars_data
  Gold: SELECT MAX(Accelerate), Cylinders FROM CARS_DATA GROUP BY Cylinders
  Type: GROUP_BY, AGGREGATION

[98] WRONG_TABLE | DB: car_1 | EX: ✗
  Q   : Which model has the most version(make) of cars
  Pred: SELECT model FROM model_list GROUP BY model ORDER BY COUNT(*) DESC LIMIT 1
  Gold: SELECT Model FROM CAR_NAMES GROUP BY Model ORDER BY COUNT(*) DESC LIMIT 1
  Type: GROUP_BY, ORDER_BY, LIMIT, AGGREGATION

[99] WRONG_TABLE | DB: car_1 | EX: ✗
  Q   : What model has the most different versions
  Pred: SELECT model FROM model_list GROUP BY model ORDER BY COUNT(DISTINCT model) DESC LIMIT 1
  Gold: SELECT Model FROM CAR_NAMES GROUP BY Model ORDER BY COUNT(*) DESC LIMIT 1
  Type: GROUP_BY, ORDER_BY, LIMIT, AGGREGATION

[100] WRONG_TABLE | DB: car_1 | EX: ✗
  Q   : how many cars were produced in 1980
  Pred: SELECT COUNT(*) FROM car_names WHERE YEAR = 1980
  Gold: SELECT COUNT(*) FROM CARS_DATA WHERE YEAR = 1980
  Type: AGGREGATION

[101] WRONG_TABLE | DB: car_1 | EX: ✗
  Q   : In 1980, how many cars were made
  Pred: SELECT COUNT(*) FROM car_names WHERE YEAR = 1980
  Gold: SELECT COUNT(*) FROM CARS_DATA WHERE YEAR = 1980
  Type: AGGREGATION

[102] WRONG_TABLE | DB: car_1 | EX: ✗
  Q   : How many car models were produced by the maker with full name American Motor Company
  Pred: SELECT COUNT(*) FROM model_list AS T1 JOIN car_makers AS T2 ON T1.model = T2.model WHERE T2.maker = 'American Motor Company'
  Gold: SELECT COUNT(*) FROM CAR_MAKERS AS T1 JOIN MODEL_LIST AS T2 ON T1.Id = T2.Maker WHERE T1.FullName = 'American Motor Company'
  Type: JOIN, AGGREGATION

[103] WRONG_TABLE | DB: car_1 | EX: ✗
  Q   : What is the number of car models created by the car maker American Motor Company
  Pred: SELECT COUNT(*) FROM model_list AS T1 JOIN car_names AS T2 ON T1.model = T2.model WHERE T2.maker = 'American Motor Company'
  Gold: SELECT COUNT(*) FROM CAR_MAKERS AS T1 JOIN MODEL_LIST AS T2 ON T1.Id = T2.Maker WHERE T1.FullName = 'American Motor Company'
  Type: JOIN, AGGREGATION

[104] MISSING_JOIN | DB: car_1 | EX: ✗
  Q   : Which makers designed more than 3 car models? List full name and the id
  Pred: SELECT fullname, id FROM car_makers GROUP BY fullname HAVING COUNT(*) > 3
  Gold: SELECT T1.FullName, T1.Id FROM CAR_MAKERS AS T1 JOIN MODEL_LIST AS T2 ON T1.Id = T2.Maker GROUP BY T1.Id HAVING COUNT(*) > 3
  Type: JOIN, GROUP_BY, HAVING, AGGREGATION

[105] WRONG_COLUMNS | DB: car_1 | EX: ✗
  Q   : What are the names and ids of all makers with more than 3 models
  Pred: SELECT T1.maker, T1.id FROM car_makers AS T1 JOIN model_list AS T2 ON T1.maker = T2.id GROUP BY T1.maker HAVING COUNT(*) > 3
  Gold: SELECT T1.FullName, T1.Id FROM CAR_MAKERS AS T1 JOIN MODEL_LIST AS T2 ON T1.Id = T2.Maker GROUP BY T1.Id HAVING COUNT(*) > 3
  Type: JOIN, GROUP_BY, HAVING, AGGREGATION

[106] WRONG_TABLE | DB: car_1 | EX: ✗
  Q   : Which distinctive models are produced by maker with the full name General Motors or weighing more than 3500
  Pred: SELECT DISTINCT DISTINCT SELECT DISTINCT DISTINCT DISTINCT DISTINCT DISTINCT DISTINCT DISTINCT DISTINCT DISTINCT DISTINCT DISTINCT DISTINCT DISTINCT DISTINCT DISTINCT DISTINCT DISTINCT DISTINCT DISTINCT DISTINCT DISTINCT DISTINCT DISTINCT DISTINCT DISTIN
  Gold: SELECT DISTINCT T2.Model FROM CAR_NAMES AS T1 JOIN MODEL_LIST AS T2 ON T1.Model = T2.Model JOIN CAR_MAKERS AS T3 ON T2.Maker = T3.Id JOIN CARS_DATA AS T4 ON T1.MakeId = T4.Id WHERE T3.FullName = 'General Motors' OR T4.weight > 3500
  Type: JOIN

[107] WRONG_TABLE | DB: car_1 | EX: ✗
  Q   : What are the different models created by either the car maker General Motors or weighed more than 3500
  Pred: SELECT DISTINCT model FROM model_list WHERE maker = "General Motors" OR weight > 3500
  Gold: SELECT DISTINCT T2.Model FROM CAR_NAMES AS T1 JOIN MODEL_LIST AS T2 ON T1.Model = T2.Model JOIN CAR_MAKERS AS T3 ON T2.Maker = T3.Id JOIN CARS_DATA AS T4 ON T1.MakeId = T4.Id WHERE T3.FullName = 'General Motors' OR T4.weight > 3500
  Type: JOIN

[108] WRONG_TABLE | DB: car_1 | EX: ✗
  Q   : In which years cars were produced weighing no less than 3000 and no more than 4000
  Pred: SELECT YEAR FROM cars_data WHERE weight  3000 INTERSECT SELECT YEAR FROM car_names WHERE weight  4000
  Gold: SELECT DISTINCT year FROM cars_data WHERE weight BETWEEN 3000 AND 4000
  Type: SIMPLE

[109] WRONG_TABLE | DB: car_1 | EX: ✗
  Q   : What are the different years in which there were cars produced that weighed less than 4000 and also cars that weighted more than 3000
  Pred: SELECT DISTINCT YEAR FROM Car_Data WHERE Weight  4000 INTERSECT SELECT YEAR FROM Car_Names WHERE Weight > 3000
  Gold: SELECT DISTINCT year FROM cars_data WHERE weight BETWEEN 3000 AND 4000
  Type: SIMPLE

[110] WRONG_COLUMNS | DB: car_1 | EX: ✓
  Q   : What is the horsepower of the car with the largest accelerate
  Pred: SELECT horsepower FROM cars_data ORDER BY accelerate DESC LIMIT 1
  Gold: SELECT T1.horsepower FROM CARS_DATA AS T1 ORDER BY T1.accelerate DESC LIMIT 1
  Type: ORDER_BY, LIMIT

[111] WRONG_COLUMNS | DB: car_1 | EX: ✓
  Q   : What is the horsepower of the car with the greatest accelerate
  Pred: SELECT horsepower FROM cars_data ORDER BY accelerate DESC LIMIT 1
  Gold: SELECT T1.horsepower FROM CARS_DATA AS T1 ORDER BY T1.accelerate DESC LIMIT 1
  Type: ORDER_BY, LIMIT

[112] MISSING_ORDER_BY | DB: car_1 | EX: ✗
  Q   : For model volvo, how many cylinders does the car with the least accelerate have
  Pred: SELECT COUNT(*) FROM cars_data AS T1 JOIN model_list AS T2 ON T1.model = T2.model JOIN car_names AS T3 ON T2.model = T3.model WHERE T3.model = "Volvo" AND T3.accelerate = (SELECT MAX(accelerate) FROM cars_data)
  Gold: SELECT T1.cylinders FROM CARS_DATA AS T1 JOIN CAR_NAMES AS T2 ON T1.Id = T2.MakeId WHERE T2.Model = 'volvo' ORDER BY T1.accelerate ASC LIMIT 1
  Type: JOIN, ORDER_BY, LIMIT

[113] MISSING_ORDER_BY | DB: car_1 | EX: ✗
  Q   : For a volvo model, how many cylinders does the version with least accelerate have
  Pred: SELECT COUNT(*) FROM cars_data AS T1 JOIN model_list AS T2 ON T1.model = T2.model WHERE T2.model = "Volvo" AND T2.acceleration = (SELECT MAX(acceleration) FROM cars_data)
  Gold: SELECT T1.cylinders FROM CARS_DATA AS T1 JOIN CAR_NAMES AS T2 ON T1.Id = T2.MakeId WHERE T2.Model = 'volvo' ORDER BY T1.accelerate ASC LIMIT 1
  Type: JOIN, ORDER_BY, LIMIT

[114] MISSING_ORDER_BY | DB: car_1 | EX: ✗
  Q   : How many cars have a larger accelerate than the car with the largest horsepower
  Pred: SELECT COUNT(*) FROM cars_data WHERE horsepower > (SELECT MAX(horsepower) FROM cars_data)
  Gold: SELECT COUNT(*) FROM CARS_DATA WHERE Accelerate > (SELECT Accelerate FROM CARS_DATA ORDER BY Horsepower DESC LIMIT 1)
  Type: ORDER_BY, LIMIT, NESTED, AGGREGATION

[115] MISSING_ORDER_BY | DB: car_1 | EX: ✗
  Q   : What is the number of cars with a greater accelerate than the one with the most horsepower
  Pred: SELECT COUNT(*) FROM cars_data WHERE horsepower > (SELECT MAX(horsepower) FROM cars_data)
  Gold: SELECT COUNT(*) FROM CARS_DATA WHERE Accelerate > (SELECT Accelerate FROM CARS_DATA ORDER BY Horsepower DESC LIMIT 1)
  Type: ORDER_BY, LIMIT, NESTED, AGGREGATION

[116] MISSING_JOIN | DB: car_1 | EX: ✗
  Q   : How many countries has more than 2 car makers
  Pred: SELECT COUNT(*) FROM countries WHERE maker > 2
  Gold: SELECT COUNT(*) FROM countries AS t1 JOIN car_makers AS t2 ON t1.countryid = t2.country GROUP BY t1.countryid HAVING COUNT(*) > 2
  Type: JOIN, GROUP_BY, HAVING, AGGREGATION

[117] MISSING_JOIN | DB: car_1 | EX: ✗
  Q   : What is the number of countries with more than 2 car makers
  Pred: SELECT COUNT(*) FROM countries WHERE maker > 2
  Gold: SELECT COUNT(*) FROM countries AS t1 JOIN car_makers AS t2 ON t1.countryid = t2.country GROUP BY t1.countryid HAVING COUNT(*) > 2
  Type: JOIN, GROUP_BY, HAVING, AGGREGATION

[118] WRONG_COLUMNS | DB: car_1 | EX: ✗
  Q   : For the cars with 4 cylinders, which model has the largest horsepower
  Pred: SELECT DISTINCT t1.model FROM car_names AS t1 JOIN model_list AS t2 ON t1.model = t2.model WHERE t2.cylinders = 4 ORDER BY horsepower DESC LIMIT 1
  Gold: SELECT T1.Model FROM CAR_NAMES AS T1 JOIN CARS_DATA AS T2 ON T1.MakeId = T2.Id WHERE T2.Cylinders = 4 ORDER BY T2.horsepower DESC LIMIT 1
  Type: JOIN, ORDER_BY, LIMIT

[119] WRONG_COLUMNS | DB: car_1 | EX: ✗
  Q   : For all of the 4 cylinder cars, which model has the most horsepower
  Pred: SELECT DISTINCT T1.model FROM car_names AS T1 JOIN model_list AS T2 ON T1.model = T2.model WHERE T2.cylinders = 4 GROUP BY T1.model ORDER BY HAVING COUNT(*) DESC LIMIT 1
  Gold: SELECT T1.Model FROM CAR_NAMES AS T1 JOIN CARS_DATA AS T2 ON T1.MakeId = T2.Id WHERE T2.Cylinders = 4 ORDER BY T2.horsepower DESC LIMIT 1
  Type: JOIN, ORDER_BY, LIMIT

[120] WRONG_COLUMNS | DB: car_1 | EX: ✗
  Q   : Among the cars with more than lowest horsepower, which ones do not have more than 3 cylinders? List the car makeid and make name
  Pred: SELECT T1.makeid, T1.makename FROM cars_data AS T1 JOIN car_names AS T2 ON T1.id = T2.makeid WHERE T2.horsepower > (SELECT MIN(horsepower) FROM cars_data) AND T2.cylinders  3
  Gold: SELECT T2.MakeId, T2.Make FROM CARS_DATA AS T1 JOIN CAR_NAMES AS T2 ON T1.Id = T2.MakeId WHERE T1.Horsepower > (SELECT MIN(Horsepower) FROM CARS_DATA) AND T1.Cylinders <= 3
  Type: JOIN, NESTED, AGGREGATION

[121] MISSING_JOIN | DB: car_1 | EX: ✗
  Q   : Among the cars that do not have the minimum horsepower , what are the make ids and names of all those with less than 4 cylinders
  Pred: SELECT id, name FROM cars_data WHERE horsepower  4
  Gold: SELECT t2.makeid, t2.make FROM cars_data AS t1 JOIN car_names AS t2 ON t1.id = t2.makeid WHERE t1.horsepower > (SELECT MIN(horsepower) FROM cars_data) AND t1.cylinders < 4
  Type: JOIN, NESTED, AGGREGATION

[122] OTHER | DB: car_1 | EX: ✗
  Q   : What is the maximum miles per gallon of the car with 8 cylinders or produced before 1980
  Pred: SELECT MAX(mpg) FROM cars_data WHERE cylinders = 8 OR YEAR  1980
  Gold: SELECT MAX(mpg) FROM cars_data WHERE cylinders = 8 OR year < 1980
  Type: AGGREGATION

[123] OTHER | DB: car_1 | EX: ✗
  Q   : What is the maximum mpg of the cars that had 8 cylinders or that were produced before 1980
  Pred: SELECT MAX(mpg) FROM cars_data WHERE cylinders = 8 OR YEAR  1980
  Gold: SELECT MAX(mpg) FROM cars_data WHERE cylinders = 8 OR year < 1980
  Type: AGGREGATION

[124] MISSING_JOIN | DB: car_1 | EX: ✗
  Q   : Which models are lighter than 3500 but not built by the 'Ford Motor Company'
  Pred: SELECT model FROM model_list WHERE weight > 3500 EXCEPT SELECT model FROM model_list WHERE maker = 'Ford Motor Company'
  Gold: SELECT DISTINCT T1.model FROM MODEL_LIST AS T1 JOIN CAR_NAMES AS T2 ON T1.Model = T2.Model JOIN CARS_DATA AS T3 ON T2.MakeId = T3.Id JOIN CAR_MAKERS AS T4 ON T1.Maker = T4.Id WHERE T3.weight < 3500 AND T4.FullName <> 'Ford Motor Company'
  Type: JOIN

[125] MISSING_JOIN | DB: car_1 | EX: ✗
  Q   : What are the different models wthat are lighter than 3500 but were not built by the Ford Motor Company
  Pred: SELECT DISTINCT model FROM model_list WHERE weight > 3500 EXCEPT SELECT DISTINCT model FROM model_list WHERE maker = 'Ford Motor Company'
  Gold: SELECT DISTINCT T1.model FROM MODEL_LIST AS T1 JOIN CAR_NAMES AS T2 ON T1.Model = T2.Model JOIN CARS_DATA AS T3 ON T2.MakeId = T3.Id JOIN CAR_MAKERS AS T4 ON T1.Maker = T4.Id WHERE T3.weight < 3500 AND T4.FullName <> 'Ford Motor Company'
  Type: JOIN

[126] WRONG_TABLE | DB: car_1 | EX: ✗
  Q   : What are the name of the countries where there is not a single car maker
  Pred: SELECT countryname FROM countries WHERE NOT countryid IN (SELECT countryid FROM car_makers)
  Gold: SELECT CountryName FROM countries EXCEPT SELECT T1.CountryName FROM countries AS T1 JOIN CAR_MAKERS AS T2 ON T1.countryId = T2.Country
  Type: JOIN

[127] WRONG_TABLE | DB: car_1 | EX: ✗
  Q   : What are the names of the countries with no car makers
  Pred: SELECT countryname FROM countries WHERE NOT countryid IN (SELECT countryid FROM car_makers)
  Gold: SELECT CountryName FROM countries EXCEPT SELECT T1.CountryName FROM countries AS T1 JOIN CAR_MAKERS AS T2 ON T1.countryId = T2.Country
  Type: JOIN

[128] MISSING_JOIN | DB: car_1 | EX: ✗
  Q   : Which are the car makers which produce at least 2 models and more than 3 car makers ? List the id and the maker
  Pred: SELECT id, maker FROM car_makers GROUP BY id HAVING COUNT(*) >= 2
  Gold: SELECT t1.id, t1.maker FROM car_makers AS t1 JOIN model_list AS t2 ON t1.id = t2.maker GROUP BY t1.id HAVING COUNT(*) >= 2 INTERSECT SELECT t1.id, t1.maker FROM car_makers AS t1 JOIN model_list AS t2 ON t1.id = t2.maker JOIN car_names AS t3 ON t2.model = t3.model GROUP BY t1.id HAVING COUNT(*) > 3
  Type: JOIN, GROUP_BY, HAVING, AGGREGATION

[129] MISSING_JOIN | DB: car_1 | EX: ✗
  Q   : What are the ids and makers of all car makers that produce at least 2 models and make more than 3 cars
  Pred: SELECT id, maker FROM car_makers GROUP BY id HAVING COUNT(*) > 3
  Gold: SELECT T1.Id, T1.Maker FROM CAR_MAKERS AS T1 JOIN MODEL_LIST AS T2 ON T1.Id = T2.Maker GROUP BY T1.Id HAVING COUNT(*) >= 2 INTERSECT SELECT T1.Id, T1.Maker FROM CAR_MAKERS AS T1 JOIN MODEL_LIST AS T2 ON T1.Id = T2.Maker JOIN CAR_NAMES AS T3 ON T2.model = T3.model GROUP BY T1.Id HAVING COUNT(*) > 3
  Type: JOIN, GROUP_BY, HAVING, AGGREGATION

[130] MISSING_GROUP_BY | DB: car_1 | EX: ✗
  Q   : What are the id and names of the countries which have more than 3 car makers or produce the 'fiat' model
  Pred: SELECT T1.countryname, T1.countryid FROM countries AS T1 JOIN car_makers AS T2 ON T1.country = T2.countryid WHERE T2.maker > 3 OR T2.model = 'fiat'
  Gold: SELECT T1.countryId, T1.CountryName FROM Countries AS T1 JOIN CAR_MAKERS AS T2 ON T1.CountryId = T2.Country GROUP BY T1.countryId HAVING COUNT(*) > 3 UNION SELECT T1.countryId, T1.CountryName FROM Countries AS T1 JOIN CAR_MAKERS AS T2 ON T1.CountryId = T2.Country JOIN MODEL_LIST AS T3 ON T2.Id = T3.Maker WHERE T3.Model = 'fiat'
  Type: JOIN, GROUP_BY, HAVING, AGGREGATION

[131] MISSING_JOIN | DB: car_1 | EX: ✗
  Q   : What are the ids and names of all countries that either have more than 3 car makers or produce fiat model
  Pred: SELECT countryname FROM countries WHERE maker > 3 OR model = 'fiat'
  Gold: SELECT t1.countryid, t1.countryname FROM countries AS t1 JOIN car_makers AS t2 ON t1.countryid = t2.country GROUP BY t1.countryid HAVING COUNT(*) > 3 UNION SELECT t1.countryid, t1.countryname FROM countries AS t1 JOIN car_makers AS t2 ON t1.countryid = t2.country JOIN model_list AS t3 ON t2.id = t3.maker WHERE t3.model = 'fiat'
  Type: JOIN, GROUP_BY, HAVING, AGGREGATION

[132] OTHER | DB: flight_2 | EX: ✗
  Q   : What country is Jetblue Airways affiliated with
  Pred: SELECT country FROM airlines WHERE airline = 'Jetblue Airways'
  Gold: SELECT Country FROM AIRLINES WHERE Airline = "JetBlue Airways"
  Type: SIMPLE

[133] OTHER | DB: flight_2 | EX: ✗
  Q   : Which abbreviation corresponds to Jetblue Airways
  Pred: SELECT abbreviation FROM airlines WHERE airline = 'Jetblue Airways'
  Gold: SELECT Abbreviation FROM AIRLINES WHERE Airline = "JetBlue Airways"
  Type: SIMPLE

[134] OTHER | DB: flight_2 | EX: ✓
  Q   : What are the airline names and abbreviations for airlines in the USA
  Pred: SELECT airline, abbreviation FROM airlines WHERE country = 'USA'
  Gold: SELECT Airline, Abbreviation FROM AIRLINES WHERE Country = "USA"
  Type: SIMPLE

[135] OTHER | DB: flight_2 | EX: ✓
  Q   : Give the airport code and airport name corresonding to the city Anthony
  Pred: SELECT airportcode, airportname FROM airports WHERE city = "Antony"
  Gold: SELECT AirportCode, AirportName FROM AIRPORTS WHERE city = "Anthony"
  Type: SIMPLE

[136] OTHER | DB: flight_2 | EX: ✓
  Q   : Which airline has abbreviation 'UAL'
  Pred: SELECT airline FROM airlines WHERE abbreviation = 'UAL'
  Gold: SELECT Airline FROM AIRLINES WHERE Abbreviation = "UAL"
  Type: SIMPLE

[137] OTHER | DB: flight_2 | EX: ✓
  Q   : Give the airline with abbreviation 'UAL'
  Pred: SELECT airline FROM airlines WHERE abbreviation = 'UAL'
  Gold: SELECT Airline FROM AIRLINES WHERE Abbreviation = "UAL"
  Type: SIMPLE

[138] OTHER | DB: flight_2 | EX: ✓
  Q   : How many airlines are from USA
  Pred: SELECT COUNT(*) FROM airlines WHERE country = 'USA'
  Gold: SELECT COUNT(*) FROM AIRLINES WHERE Country = "USA"
  Type: AGGREGATION

[139] OTHER | DB: flight_2 | EX: ✓
  Q   : Return the number of airlines in the USA
  Pred: SELECT COUNT(*) FROM airlines WHERE country = 'USA'
  Gold: SELECT COUNT(*) FROM AIRLINES WHERE Country = "USA"
  Type: AGGREGATION

[140] OTHER | DB: flight_2 | EX: ✗
  Q   : What is the airport name for airport 'AKO'
  Pred: SELECT airportname FROM airports WHERE airportname = 'AKO'
  Gold: SELECT AirportName FROM AIRPORTS WHERE AirportCode = "AKO"
  Type: SIMPLE

[141] OTHER | DB: flight_2 | EX: ✓
  Q   : Return the name of the airport with code 'AKO'
  Pred: SELECT airportname FROM airports WHERE airportcode = 'AKO'
  Gold: SELECT AirportName FROM AIRPORTS WHERE AirportCode = "AKO"
  Type: SIMPLE

[142] OTHER | DB: flight_2 | EX: ✓
  Q   : What are airport names at City 'Aberdeen'
  Pred: SELECT airportname FROM airports WHERE city = 'Aberdeen'
  Gold: SELECT AirportName FROM AIRPORTS WHERE City = "Aberdeen"
  Type: SIMPLE

[143] OTHER | DB: flight_2 | EX: ✓
  Q   : How many flights depart from 'APG'
  Pred: SELECT COUNT(*) FROM flights WHERE sourceairport = 'APG'
  Gold: SELECT COUNT(*) FROM FLIGHTS WHERE SourceAirport = "APG"
  Type: AGGREGATION

[144] OTHER | DB: flight_2 | EX: ✓
  Q   : Count the number of flights departing from 'APG'
  Pred: SELECT COUNT(*) FROM flights WHERE sourceairport = 'APG'
  Gold: SELECT COUNT(*) FROM FLIGHTS WHERE SourceAirport = "APG"
  Type: AGGREGATION

[145] OTHER | DB: flight_2 | EX: ✓
  Q   : How many flights have destination ATO
  Pred: SELECT COUNT(*) FROM flights WHERE sourceairport = 'ATO'
  Gold: SELECT COUNT(*) FROM FLIGHTS WHERE DestAirport = "ATO"
  Type: AGGREGATION

[146] OTHER | DB: flight_2 | EX: ✓
  Q   : Count the number of flights into ATO
  Pred: SELECT COUNT(*) FROM flights WHERE sourceairport = 'ATO'
  Gold: SELECT COUNT(*) FROM FLIGHTS WHERE DestAirport = "ATO"
  Type: AGGREGATION

[147] MISSING_JOIN | DB: flight_2 | EX: ✓
  Q   : How many flights depart from City Aberdeen
  Pred: SELECT COUNT(*) FROM flights WHERE sourceairport = 'Aberdeen'
  Gold: SELECT COUNT(*) FROM FLIGHTS AS T1 JOIN AIRPORTS AS T2 ON T1.SourceAirport = T2.AirportCode WHERE T2.City = "Aberdeen"
  Type: JOIN, AGGREGATION

[148] MISSING_JOIN | DB: flight_2 | EX: ✓
  Q   : Return the number of flights departing from Aberdeen
  Pred: SELECT COUNT(*) FROM flights WHERE sourceairport = 'Aberdeen'
  Gold: SELECT COUNT(*) FROM FLIGHTS AS T1 JOIN AIRPORTS AS T2 ON T1.SourceAirport = T2.AirportCode WHERE T2.City = "Aberdeen"
  Type: JOIN, AGGREGATION

[149] WRONG_TABLE | DB: flight_2 | EX: ✓
  Q   : How many flights arriving in Aberdeen city
  Pred: SELECT COUNT(*) FROM airports WHERE city = "Aberdeen"
  Gold: SELECT COUNT(*) FROM FLIGHTS AS T1 JOIN AIRPORTS AS T2 ON T1.DestAirport = T2.AirportCode WHERE T2.City = "Aberdeen"
  Type: JOIN, AGGREGATION

[150] MISSING_JOIN | DB: flight_2 | EX: ✗
  Q   : Return the number of flights arriving in Aberdeen
  Pred: SELECT COUNT(*) FROM flights WHERE airportname = 'Aberdeen'
  Gold: SELECT COUNT(*) FROM FLIGHTS AS T1 JOIN AIRPORTS AS T2 ON T1.DestAirport = T2.AirportCode WHERE T2.City = "Aberdeen"
  Type: JOIN, AGGREGATION

[151] MISSING_JOIN | DB: flight_2 | EX: ✗
  Q   : How many flights depart from City 'Aberdeen' and have destination City 'Ashley'
  Pred: SELECT COUNT(*) FROM flights WHERE sourceairport = 'Aberdeen' AND destination = 'Ashley'
  Gold: SELECT COUNT(*) FROM FLIGHTS AS T1 JOIN AIRPORTS AS T2 ON T1.DestAirport = T2.AirportCode JOIN AIRPORTS AS T3 ON T1.SourceAirport = T3.AirportCode WHERE T2.City = "Ashley" AND T3.City = "Aberdeen"
  Type: JOIN, AGGREGATION

[152] MISSING_JOIN | DB: flight_2 | EX: ✓
  Q   : How many flights fly from Aberdeen to Ashley
  Pred: SELECT COUNT(*) FROM flights WHERE sourceairport = 'Aberdeen' AND flightno = 'Ashley'
  Gold: SELECT COUNT(*) FROM FLIGHTS AS T1 JOIN AIRPORTS AS T2 ON T1.DestAirport = T2.AirportCode JOIN AIRPORTS AS T3 ON T1.SourceAirport = T3.AirportCode WHERE T2.City = "Ashley" AND T3.City = "Aberdeen"
  Type: JOIN, AGGREGATION

[153] WRONG_TABLE | DB: flight_2 | EX: ✗
  Q   : How many flights does airline 'JetBlue Airways' have
  Pred: SELECT COUNT(*) FROM airlines AS T1 JOIN flights AS T2 ON T1.uid = T2.uid WHERE T1.abbreviation = 'JetBlue Airways'
  Gold: SELECT COUNT(*) FROM FLIGHTS AS T1 JOIN AIRLINES AS T2 ON T1.Airline = T2.uid WHERE T2.Airline = "JetBlue Airways"
  Type: JOIN, AGGREGATION

[154] OTHER | DB: flight_2 | EX: ✗
  Q   : Give the number of Jetblue Airways flights
  Pred: SELECT COUNT(*) FROM flights AS T1 JOIN flights AS T2 ON T1.airport = T2.sourceairport JOIN airlines AS T3 ON T2.uid = T3.uid WHERE T3.abbreviation = "Jetblue Airways"
  Gold: SELECT COUNT(*) FROM FLIGHTS AS T1 JOIN AIRLINES AS T2 ON T1.Airline = T2.uid WHERE T2.Airline = "JetBlue Airways"
  Type: JOIN, AGGREGATION

[155] WRONG_TABLE | DB: flight_2 | EX: ✓
  Q   : How many 'United Airlines' flights go to Airport 'ASY'
  Pred: SELECT COUNT(*) FROM flights WHERE airline = 'United Airlines' AND sourceairport = 'ASY'
  Gold: SELECT COUNT(*) FROM AIRLINES AS T1 JOIN FLIGHTS AS T2 ON T2.Airline = T1.uid WHERE T1.Airline = "United Airlines" AND T2.DestAirport = "ASY"
  Type: JOIN, AGGREGATION

[156] OTHER | DB: flight_2 | EX: ✗
  Q   : Count the number of United Airlines flights arriving in ASY Airport
  Pred: SELECT COUNT(*) FROM airlines AS T1 JOIN flights AS T2 ON T1.uid = T2.sourceairport WHERE T1.airportname = "ASY"
  Gold: SELECT COUNT(*) FROM AIRLINES AS T1 JOIN FLIGHTS AS T2 ON T2.Airline = T1.uid WHERE T1.Airline = "United Airlines" AND T2.DestAirport = "ASY"
  Type: JOIN, AGGREGATION

[157] WRONG_TABLE | DB: flight_2 | EX: ✓
  Q   : How many 'United Airlines' flights depart from Airport 'AHD'
  Pred: SELECT COUNT(*) FROM flights WHERE sourceairport = 'AHD' AND airline = 'United Airlines'
  Gold: SELECT COUNT(*) FROM AIRLINES AS T1 JOIN FLIGHTS AS T2 ON T2.Airline = T1.uid WHERE T1.Airline = "United Airlines" AND T2.SourceAirport = "AHD"
  Type: JOIN, AGGREGATION

[158] MISSING_JOIN | DB: flight_2 | EX: ✗
  Q   : Return the number of United Airlines flights leaving from AHD Airport
  Pred: SELECT COUNT(*) FROM airlines WHERE sourceairport = 'AHD'
  Gold: SELECT COUNT(*) FROM AIRLINES AS T1 JOIN FLIGHTS AS T2 ON T2.Airline = T1.uid WHERE T1.Airline = "United Airlines" AND T2.SourceAirport = "AHD"
  Type: JOIN, AGGREGATION

[159] WRONG_TABLE | DB: flight_2 | EX: ✗
  Q   : How many United Airlines flights go to City 'Aberdeen'
  Pred: SELECT COUNT(*) FROM airlines AS T1 JOIN flights AS T2 ON T1.uid = T2.flightno WHERE T2.city = 'Aberdeen'
  Gold: SELECT COUNT(*) FROM FLIGHTS AS T1 JOIN AIRPORTS AS T2 ON T1.DestAirport = T2.AirportCode JOIN AIRLINES AS T3 ON T3.uid = T1.Airline WHERE T2.City = "Aberdeen" AND T3.Airline = "United Airlines"
  Type: JOIN, AGGREGATION

[160] WRONG_TABLE | DB: flight_2 | EX: ✗
  Q   : Count the number of United Airlines flights that arrive in Aberdeen
  Pred: SELECT COUNT(*) FROM airlines AS T1 JOIN flights AS T2 ON T1.uid = T2.sourceairport JOIN airports AS T3 ON T2.airportcode = T3.airportcode WHERE T3.country = "Aberdeen" AND T3.country = "United Airlines"
  Gold: SELECT COUNT(*) FROM FLIGHTS AS T1 JOIN AIRPORTS AS T2 ON T1.DestAirport = T2.AirportCode JOIN AIRLINES AS T3 ON T3.uid = T1.Airline WHERE T2.City = "Aberdeen" AND T3.Airline = "United Airlines"
  Type: JOIN, AGGREGATION

[161] MISSING_JOIN | DB: flight_2 | EX: ✗
  Q   : Which city has most number of arriving flights
  Pred: SELECT city FROM airports GROUP BY city ORDER BY COUNT(*) DESC LIMIT 1
  Gold: SELECT T1.City FROM AIRPORTS AS T1 JOIN FLIGHTS AS T2 ON T1.AirportCode = T2.DestAirport GROUP BY T1.City ORDER BY COUNT(*) DESC LIMIT 1
  Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, AGGREGATION

[162] MISSING_JOIN | DB: flight_2 | EX: ✗
  Q   : Which city has the most frequent destination airport
  Pred: SELECT city FROM airports ORDER BY airportname DESC LIMIT 1
  Gold: SELECT T1.City FROM AIRPORTS AS T1 JOIN FLIGHTS AS T2 ON T1.AirportCode = T2.DestAirport GROUP BY T1.City ORDER BY COUNT(*) DESC LIMIT 1
  Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, AGGREGATION

[163] MISSING_JOIN | DB: flight_2 | EX: ✗
  Q   : Which city has most number of departing flights
  Pred: SELECT city FROM airports GROUP BY city ORDER BY COUNT(*) DESC LIMIT 1
  Gold: SELECT T1.City FROM AIRPORTS AS T1 JOIN FLIGHTS AS T2 ON T1.AirportCode = T2.SourceAirport GROUP BY T1.City ORDER BY COUNT(*) DESC LIMIT 1
  Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, AGGREGATION

[164] MISSING_JOIN | DB: flight_2 | EX: ✗
  Q   : Which city is the most frequent source airport
  Pred: SELECT city FROM airports ORDER BY city DESC LIMIT 1
  Gold: SELECT T1.City FROM AIRPORTS AS T1 JOIN FLIGHTS AS T2 ON T1.AirportCode = T2.SourceAirport GROUP BY T1.City ORDER BY COUNT(*) DESC LIMIT 1
  Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, AGGREGATION

[165] OTHER | DB: flight_2 | EX: ✗
  Q   : What is the code of airport that has the highest number of flights
  Pred: SELECT T1.airportcode FROM airports AS T1 JOIN flights AS T2 ON T1.airportcode = T2.airportcode GROUP BY T1.airportcode ORDER BY COUNT(*) DESC LIMIT 1
  Gold: SELECT T1.AirportCode FROM AIRPORTS AS T1 JOIN FLIGHTS AS T2 ON T1.AirportCode = T2.DestAirport OR T1.AirportCode = T2.SourceAirport GROUP BY T1.AirportCode ORDER BY COUNT(*) DESC LIMIT 1
  Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, AGGREGATION

[166] OTHER | DB: flight_2 | EX: ✗
  Q   : What is the airport code of the airport with the most flights
  Pred: SELECT T1.airportcode FROM airports AS T1 JOIN flights AS T2 ON T1.airportcode = T2.airportcode GROUP BY T1.airportcode ORDER BY COUNT(*) DESC LIMIT 1
  Gold: SELECT T1.AirportCode FROM AIRPORTS AS T1 JOIN FLIGHTS AS T2 ON T1.AirportCode = T2.DestAirport OR T1.AirportCode = T2.SourceAirport GROUP BY T1.AirportCode ORDER BY COUNT(*) DESC LIMIT 1
  Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, AGGREGATION

[167] MISSING_JOIN | DB: flight_2 | EX: ✗
  Q   : What is the code of airport that has fewest number of flights
  Pred: SELECT airportcode FROM airports GROUP BY airportcode ORDER BY COUNT(*) ASC LIMIT 1
  Gold: SELECT T1.AirportCode FROM AIRPORTS AS T1 JOIN FLIGHTS AS T2 ON T1.AirportCode = T2.DestAirport OR T1.AirportCode = T2.SourceAirport GROUP BY T1.AirportCode ORDER BY COUNT(*) LIMIT 1
  Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, AGGREGATION

[168] MISSING_JOIN | DB: flight_2 | EX: ✗
  Q   : Give the code of the airport with the least flights
  Pred: SELECT airportcode FROM airports ORDER BY COUNT(*) LIMIT 1
  Gold: SELECT T1.AirportCode FROM AIRPORTS AS T1 JOIN FLIGHTS AS T2 ON T1.AirportCode = T2.DestAirport OR T1.AirportCode = T2.SourceAirport GROUP BY T1.AirportCode ORDER BY COUNT(*) LIMIT 1
  Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, AGGREGATION

[169] WRONG_TABLE | DB: flight_2 | EX: ✗
  Q   : Which airline has most number of flights
  Pred: SELECT airline FROM flights GROUP BY airline ORDER BY COUNT(*) DESC LIMIT 1
  Gold: SELECT T1.Airline FROM AIRLINES AS T1 JOIN FLIGHTS AS T2 ON T1.uid = T2.Airline GROUP BY T1.Airline ORDER BY COUNT(*) DESC LIMIT 1
  Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, AGGREGATION

[170] WRONG_TABLE | DB: flight_2 | EX: ✗
  Q   : What airline serves the most flights
  Pred: SELECT airline FROM flights GROUP BY airline ORDER BY COUNT(*) DESC LIMIT 1
  Gold: SELECT T1.Airline FROM AIRLINES AS T1 JOIN FLIGHTS AS T2 ON T1.uid = T2.Airline GROUP BY T1.Airline ORDER BY COUNT(*) DESC LIMIT 1
  Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, AGGREGATION

[171] MISSING_JOIN | DB: flight_2 | EX: ✗
  Q   : Find the abbreviation and country of the airline that has fewest number of flights
  Pred: SELECT abbreviation, country FROM airlines ORDER BY COUNT(*) LIMIT 1
  Gold: SELECT T1.Abbreviation, T1.Country FROM AIRLINES AS T1 JOIN FLIGHTS AS T2 ON T1.uid = T2.Airline GROUP BY T1.Airline ORDER BY COUNT(*) LIMIT 1
  Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, AGGREGATION

[172] WRONG_TABLE | DB: flight_2 | EX: ✗
  Q   : What is the abbreviation of the airilne has the fewest flights and what country is it in
  Pred: SELECT abbreviation, country FROM airports ORDER BY COUNT(*) LIMIT 1
  Gold: SELECT T1.Abbreviation, T1.Country FROM AIRLINES AS T1 JOIN FLIGHTS AS T2 ON T1.uid = T2.Airline GROUP BY T1.Airline ORDER BY COUNT(*) LIMIT 1
  Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, AGGREGATION

[173] OTHER | DB: flight_2 | EX: ✗
  Q   : What are airlines that have some flight departing from airport 'AHD'
  Pred: SELECT T1.airline FROM airlines AS T1 JOIN flights AS T2 ON T1.uid = T2.airportcode WHERE T2.sourceairport = 'AHD'
  Gold: SELECT T1.Airline FROM AIRLINES AS T1 JOIN FLIGHTS AS T2 ON T1.uid = T2.Airline WHERE T2.SourceAirport = "AHD"
  Type: JOIN

[174] WRONG_TABLE | DB: flight_2 | EX: ✗
  Q   : Which airlines have a flight with source airport AHD
  Pred: SELECT T1.airline FROM flights AS T1 JOIN flights AS T2 ON T1.sourceairport = T2.airportcode WHERE T2.sourceairport = 'AHD'
  Gold: SELECT T1.Airline FROM AIRLINES AS T1 JOIN FLIGHTS AS T2 ON T1.uid = T2.Airline WHERE T2.SourceAirport = "AHD"
  Type: JOIN

[175] WRONG_TABLE | DB: flight_2 | EX: ✗
  Q   : What are airlines that have flights arriving at airport 'AHD'
  Pred: SELECT T1.airline FROM airports AS T1 JOIN flights AS T2 ON T1.airportcode = T2.sourceairport WHERE T1.airportname = 'AHD'
  Gold: SELECT T1.Airline FROM AIRLINES AS T1 JOIN FLIGHTS AS T2 ON T1.uid = T2.Airline WHERE T2.DestAirport = "AHD"
  Type: JOIN

[176] OTHER | DB: flight_2 | EX: ✓
  Q   : Which airlines have a flight with destination airport AHD
  Pred: SELECT T1.airline FROM airlines AS T1 JOIN flights AS T2 ON T1.uid = T2.flightno WHERE T2.sourceairport = 'AHD'
  Gold: SELECT T1.Airline FROM AIRLINES AS T1 JOIN FLIGHTS AS T2 ON T1.uid = T2.Airline WHERE T2.DestAirport = "AHD"
  Type: JOIN

[177] WRONG_TABLE | DB: flight_2 | EX: ✗
  Q   : Find all airlines that have flights from both airports 'APG' and 'CVO'
  Pred: SELECT T1.airline FROM flights AS T1 JOIN airports AS T2 ON T1.airportcode = T2.airportcode WHERE T2.sourceairport = 'APG' INTERSECT SELECT T1.airline FROM flights AS T1 JOIN airports AS T2 ON T1.airportcode = T2.airportcode WHERE T2.sourceairport = 'CVO'
  Gold: SELECT T1.Airline FROM AIRLINES AS T1 JOIN FLIGHTS AS T2 ON T1.uid = T2.Airline WHERE T2.SourceAirport = "APG" INTERSECT SELECT T1.Airline FROM AIRLINES AS T1 JOIN FLIGHTS AS T2 ON T1.uid = T2.Airline WHERE T2.SourceAirport = "CVO"
  Type: JOIN

[178] WRONG_TABLE | DB: flight_2 | EX: ✓
  Q   : Which airlines have departing flights from both APG and CVO airports
  Pred: SELECT airline FROM flights WHERE sourceairport = 'APG' INTERSECT SELECT airline FROM flights WHERE sourceairport = 'CVO'
  Gold: SELECT T1.Airline FROM AIRLINES AS T1 JOIN FLIGHTS AS T2 ON T1.uid = T2.Airline WHERE T2.SourceAirport = "APG" INTERSECT SELECT T1.Airline FROM AIRLINES AS T1 JOIN FLIGHTS AS T2 ON T1.uid = T2.Airline WHERE T2.SourceAirport = "CVO"
  Type: JOIN

[179] WRONG_TABLE | DB: flight_2 | EX: ✗
  Q   : Find all airlines that have flights from airport 'CVO' but not from 'APG'
  Pred: SELECT T1.airline FROM airlines AS T1 JOIN flights AS T2 ON T1.uid = T2.airportcode WHERE T2.sourceairport = 'CVO' EXCEPT SELECT T1.airline FROM flights AS T1 JOIN airports AS T2 ON T1.airportcode = T2.airportcode WHERE T2.sourceairport = 'APG'
  Gold: SELECT T1.Airline FROM AIRLINES AS T1 JOIN FLIGHTS AS T2 ON T1.uid = T2.Airline WHERE T2.SourceAirport = "CVO" EXCEPT SELECT T1.Airline FROM AIRLINES AS T1 JOIN FLIGHTS AS T2 ON T1.uid = T2.Airline WHERE T2.SourceAirport = "APG"
  Type: JOIN

[180] OTHER | DB: flight_2 | EX: ✗
  Q   : Which airlines have departures from CVO but not from APG airports
  Pred: SELECT T1.airline FROM airlines AS T1 JOIN flights AS T2 ON T1.uid = T2.flightno WHERE T2.sourceairport = 'CVO' EXCEPT SELECT T1.airline FROM airlines AS T1 JOIN airports AS T2 ON T1.airportcode = T2.airportcode WHERE T2.airportname = 'APG'
  Gold: SELECT T1.Airline FROM AIRLINES AS T1 JOIN FLIGHTS AS T2 ON T1.uid = T2.Airline WHERE T2.SourceAirport = "CVO" EXCEPT SELECT T1.Airline FROM AIRLINES AS T1 JOIN FLIGHTS AS T2 ON T1.uid = T2.Airline WHERE T2.SourceAirport = "APG"
  Type: JOIN

[181] WRONG_TABLE | DB: flight_2 | EX: ✗
  Q   : Find all airlines that have at least 10 flights
  Pred: SELECT airline FROM flights GROUP BY airline HAVING COUNT(*) >= 10
  Gold: SELECT T1.Airline FROM AIRLINES AS T1 JOIN FLIGHTS AS T2 ON T1.uid = T2.Airline GROUP BY T1.Airline HAVING COUNT(*) > 10
  Type: JOIN, GROUP_BY, HAVING, AGGREGATION

[182] WRONG_TABLE | DB: flight_2 | EX: ✗
  Q   : Which airlines have at least 10 flights
  Pred: SELECT airline FROM flights GROUP BY airline HAVING COUNT(*) >= 10
  Gold: SELECT T1.Airline FROM AIRLINES AS T1 JOIN FLIGHTS AS T2 ON T1.uid = T2.Airline GROUP BY T1.Airline HAVING COUNT(*) > 10
  Type: JOIN, GROUP_BY, HAVING, AGGREGATION

[183] WRONG_TABLE | DB: flight_2 | EX: ✗
  Q   : Find all airlines that have fewer than 200 flights
  Pred: SELECT airline FROM flights GROUP BY airline HAVING COUNT(*)  200
  Gold: SELECT T1.Airline FROM AIRLINES AS T1 JOIN FLIGHTS AS T2 ON T1.uid = T2.Airline GROUP BY T1.Airline HAVING COUNT(*) < 200
  Type: JOIN, GROUP_BY, HAVING, AGGREGATION

[184] WRONG_TABLE | DB: flight_2 | EX: ✗
  Q   : Which airlines have less than 200 flights
  Pred: SELECT airline FROM flights GROUP BY airline HAVING COUNT(*)  200
  Gold: SELECT T1.Airline FROM AIRLINES AS T1 JOIN FLIGHTS AS T2 ON T1.uid = T2.Airline GROUP BY T1.Airline HAVING COUNT(*) < 200
  Type: JOIN, GROUP_BY, HAVING, AGGREGATION

[185] MISSING_JOIN | DB: flight_2 | EX: ✗
  Q   : What are flight numbers of Airline "United Airlines"
  Pred: SELECT flightno FROM flights WHERE airline = "United Airlines"
  Gold: SELECT T1.FlightNo FROM FLIGHTS AS T1 JOIN AIRLINES AS T2 ON T2.uid = T1.Airline WHERE T2.Airline = "United Airlines"
  Type: JOIN

[186] MISSING_JOIN | DB: flight_2 | EX: ✗
  Q   : Which flight numbers correspond to United Airlines flights
  Pred: SELECT flightno FROM flights WHERE airline = 'United Airlines'
  Gold: SELECT T1.FlightNo FROM FLIGHTS AS T1 JOIN AIRLINES AS T2 ON T2.uid = T1.Airline WHERE T2.Airline = "United Airlines"
  Type: JOIN

[187] OTHER | DB: flight_2 | EX: ✓
  Q   : Give the flight numbers of flights leaving from APG
  Pred: SELECT flightno FROM flights WHERE sourceairport = 'APG'
  Gold: SELECT FlightNo FROM FLIGHTS WHERE SourceAirport = "APG"
  Type: SIMPLE

[188] OTHER | DB: flight_2 | EX: ✓
  Q   : What are flight numbers of flights arriving at Airport "APG"
  Pred: SELECT flightno FROM flights WHERE sourceairport = "APG"
  Gold: SELECT FlightNo FROM FLIGHTS WHERE DestAirport = "APG"
  Type: SIMPLE

[189] OTHER | DB: flight_2 | EX: ✓
  Q   : Give the flight numbers of flights landing at APG
  Pred: SELECT flightno FROM flights WHERE sourceairport = 'APG'
  Gold: SELECT FlightNo FROM FLIGHTS WHERE DestAirport = "APG"
  Type: SIMPLE

[190] MISSING_JOIN | DB: flight_2 | EX: ✓
  Q   : What are flight numbers of flights departing from City "Aberdeen "
  Pred: SELECT flightno FROM flights WHERE sourceairport = "Aberdeen"
  Gold: SELECT T1.FlightNo FROM FLIGHTS AS T1 JOIN AIRPORTS AS T2 ON T1.SourceAirport = T2.AirportCode WHERE T2.City = "Aberdeen"
  Type: JOIN

[191] MISSING_JOIN | DB: flight_2 | EX: ✓
  Q   : Give the flight numbers of flights leaving from Aberdeen
  Pred: SELECT flightno FROM flights WHERE sourceairport = 'Aberdeen'
  Gold: SELECT T1.FlightNo FROM FLIGHTS AS T1 JOIN AIRPORTS AS T2 ON T1.SourceAirport = T2.AirportCode WHERE T2.City = "Aberdeen"
  Type: JOIN

[192] WRONG_TABLE | DB: flight_2 | EX: ✗
  Q   : What are flight numbers of flights arriving at City "Aberdeen"
  Pred: SELECT flightno FROM airports WHERE city = "Aberdeen"
  Gold: SELECT T1.FlightNo FROM FLIGHTS AS T1 JOIN AIRPORTS AS T2 ON T1.DestAirport = T2.AirportCode WHERE T2.City = "Aberdeen"
  Type: JOIN

[193] MISSING_JOIN | DB: flight_2 | EX: ✓
  Q   : Give the flight numbers of flights arriving in Aberdeen
  Pred: SELECT flightno FROM flights WHERE sourceairport = 'Aberdeen'
  Gold: SELECT T1.FlightNo FROM FLIGHTS AS T1 JOIN AIRPORTS AS T2 ON T1.DestAirport = T2.AirportCode WHERE T2.City = "Aberdeen"
  Type: JOIN

[194] WRONG_TABLE | DB: flight_2 | EX: ✓
  Q   : Find the number of flights landing in the city of Aberdeen or Abilene
  Pred: SELECT COUNT(*) FROM airports WHERE city = "Aberdeen" OR airportname = "Abilene"
  Gold: SELECT COUNT(*) FROM Flights AS T1 JOIN Airports AS T2 ON T1.DestAirport = T2.AirportCode WHERE T2.city = "Aberdeen" OR T2.city = "Abilene"
  Type: JOIN, AGGREGATION

[195] MISSING_JOIN | DB: flight_2 | EX: ✓
  Q   : How many flights land in Aberdeen or Abilene
  Pred: SELECT COUNT(*) FROM flights WHERE sourceairport = 'Aberdeen' OR sourceairport = 'Abilene'
  Gold: SELECT COUNT(*) FROM Flights AS T1 JOIN Airports AS T2 ON T1.DestAirport = T2.AirportCode WHERE T2.city = "Aberdeen" OR T2.city = "Abilene"
  Type: JOIN, AGGREGATION

[196] WRONG_COLUMNS | DB: flight_2 | EX: ✗
  Q   : Find the name of airports which do not have any flight in and out
  Pred: SELECT airportname FROM airports WHERE NOT airportcode IN (SELECT airportcode FROM flights)
  Gold: SELECT AirportName FROM Airports WHERE NOT AirportCode IN (SELECT SourceAirport FROM Flights UNION SELECT DestAirport FROM Flights)
  Type: NESTED

[197] WRONG_TABLE | DB: flight_2 | EX: ✗
  Q   : Which airports do not have departing or arriving flights
  Pred: SELECT airportname FROM airports EXCEPT SELECT T1.airportname FROM airports AS T1 JOIN flights AS T2 ON T1.airportcode = T2.airportcode WHERE T2.flightno = 'departing' OR T2.flightno = 'arriving'
  Gold: SELECT AirportName FROM Airports WHERE NOT AirportCode IN (SELECT SourceAirport FROM Flights UNION SELECT DestAirport FROM Flights)
  Type: NESTED

[198] OTHER | DB: employee_hire_evaluation | EX: ✓
  Q   : Sort employee names by their age in ascending order
  Pred: SELECT name FROM employee ORDER BY age ASC
  Gold: SELECT name FROM employee ORDER BY age
  Type: ORDER_BY

[199] OTHER | DB: employee_hire_evaluation | EX: ✓
  Q   : List the names of employees and sort in ascending order of age
  Pred: SELECT name FROM employee ORDER BY age ASC
  Gold: SELECT name FROM employee ORDER BY age
  Type: ORDER_BY

[200] WRONG_COLUMNS | DB: employee_hire_evaluation | EX: ✗
  Q   : Count the number of employees for each city
  Pred: SELECT city, COUNT(*) FROM employee GROUP BY city
  Gold: SELECT COUNT(*), city FROM employee GROUP BY city
  Type: GROUP_BY, AGGREGATION

[201] OTHER | DB: employee_hire_evaluation | EX: ✗
  Q   : Which cities do more than one employee under age 30 come from
  Pred: SELECT city FROM employee WHERE age > 30 GROUP BY city HAVING COUNT(*) > 1
  Gold: SELECT city FROM employee WHERE age < 30 GROUP BY city HAVING COUNT(*) > 1
  Type: GROUP_BY, HAVING, AGGREGATION

[202] OTHER | DB: employee_hire_evaluation | EX: ✗
  Q   : Find the cities that have more than one employee under age 30
  Pred: SELECT city FROM employee WHERE age > 30 GROUP BY city HAVING COUNT(*) > 1
  Gold: SELECT city FROM employee WHERE age < 30 GROUP BY city HAVING COUNT(*) > 1
  Type: GROUP_BY, HAVING, AGGREGATION

[203] WRONG_COLUMNS | DB: employee_hire_evaluation | EX: ✗
  Q   : How many shops are there in each location
  Pred: SELECT Location, COUNT(*) FROM shop GROUP BY Location
  Gold: SELECT COUNT(*), LOCATION FROM shop GROUP BY LOCATION
  Type: GROUP_BY, AGGREGATION

[204] OTHER | DB: employee_hire_evaluation | EX: ✓
  Q   : find the name of employee who was awarded the most times in the evaluation
  Pred: SELECT T1.name FROM employee AS T1 JOIN evaluation AS T2 ON T1.employee_id = T2.employee_id GROUP BY T1.employee_id ORDER BY COUNT(*) DESC LIMIT 1
  Gold: SELECT t1.name FROM employee AS t1 JOIN evaluation AS t2 ON t1.Employee_ID = t2.Employee_ID GROUP BY t2.Employee_ID ORDER BY COUNT(*) DESC LIMIT 1
  Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, AGGREGATION

[205] OTHER | DB: employee_hire_evaluation | EX: ✓
  Q   : Which employee received the most awards in evaluations? Give me the employee name
  Pred: SELECT T1.name FROM employee AS T1 JOIN evaluation AS T2 ON T1.employee_id = T2.employee_id GROUP BY T1.name ORDER BY COUNT(*) DESC LIMIT 1
  Gold: SELECT t1.name FROM employee AS t1 JOIN evaluation AS t2 ON t1.Employee_ID = t2.Employee_ID GROUP BY t2.Employee_ID ORDER BY COUNT(*) DESC LIMIT 1
  Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, AGGREGATION

[206] WRONG_TABLE | DB: employee_hire_evaluation | EX: ✗
  Q   : What is the name of the shop that is hiring the largest number of employees
  Pred: SELECT T1.name FROM employee AS T1 JOIN hiring AS T2 ON T1.employee_id = T2.employee_id GROUP BY T1.shop_id ORDER BY COUNT(*) DESC LIMIT 1
  Gold: SELECT t2.name FROM hiring AS t1 JOIN shop AS t2 ON t1.shop_id = t2.shop_id GROUP BY t1.shop_id ORDER BY COUNT(*) DESC LIMIT 1
  Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, AGGREGATION

[207] WRONG_TABLE | DB: employee_hire_evaluation | EX: ✗
  Q   : Which shop has the most employees? Give me the shop name
  Pred: SELECT T1.name FROM employee AS T1 JOIN shop AS T2 ON T1.shop_id = T2.shop_id GROUP BY T1.shop_id ORDER BY COUNT(*) DESC LIMIT 1
  Gold: SELECT t2.name FROM hiring AS t1 JOIN shop AS t2 ON t1.shop_id = t2.shop_id GROUP BY t1.shop_id ORDER BY COUNT(*) DESC LIMIT 1
  Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, AGGREGATION

[208] WRONG_TABLE | DB: employee_hire_evaluation | EX: ✗
  Q   : Find the number of employees hired in each shop; show the shop name as well
  Pred: SELECT COUNT(*), T1.name FROM employee AS T1 JOIN hiring AS T2 ON T1.employee_id = T2.employee_id GROUP BY T1.shop_id
  Gold: SELECT COUNT(*), t2.name FROM hiring AS t1 JOIN shop AS t2 ON t1.shop_id = t2.shop_id GROUP BY t2.name
  Type: JOIN, GROUP_BY, AGGREGATION

[209] WRONG_TABLE | DB: employee_hire_evaluation | EX: ✗
  Q   : For each shop, return the number of employees working there and the name of the shop
  Pred: SELECT COUNT(*), T1.name FROM shop AS T1 JOIN employee AS T2 ON T1.shop_id = T2.shop_id GROUP BY T1.shop_id
  Gold: SELECT COUNT(*), t2.name FROM hiring AS t1 JOIN shop AS t2 ON t1.shop_id = t2.shop_id GROUP BY t2.name
  Type: JOIN, GROUP_BY, AGGREGATION

[210] OTHER | DB: employee_hire_evaluation | EX: ✗
  Q   : Which district has both stores with less than 3000 products and stores with more than 10000 products
  Pred: SELECT District FROM shop WHERE Number_Products  3000 INTERSECT SELECT District FROM shop WHERE Number_Products > 10000
  Gold: SELECT district FROM shop WHERE Number_products < 3000 INTERSECT SELECT district FROM shop WHERE Number_products > 10000
  Type: SIMPLE

[211] OTHER | DB: employee_hire_evaluation | EX: ✗
  Q   : Find the districts in which there are both shops selling less than 3000 products and shops selling more than 10000 products
  Pred: SELECT District FROM shop WHERE Number_Products  3000 INTERSECT SELECT District FROM shop WHERE Number_Products > 10000
  Gold: SELECT district FROM shop WHERE Number_products < 3000 INTERSECT SELECT district FROM shop WHERE Number_products > 10000
  Type: SIMPLE

[212] OTHER | DB: cre_Doc_Template_Mgt | EX: ✓
  Q   : What is the document name and template id for document with description with the letter 'w' in it
  Pred: SELECT document_name, template_id FROM documents WHERE document_description LIKE '%w%'
  Gold: SELECT document_name, template_id FROM Documents WHERE Document_Description LIKE "%w%"
  Type: SIMPLE

[213] WRONG_COLUMNS | DB: cre_Doc_Template_Mgt | EX: ✗
  Q   : How many different templates do all document use
  Pred: SELECT COUNT(DISTINCT template_type_code) FROM documents
  Gold: SELECT COUNT(DISTINCT template_id) FROM Documents
  Type: AGGREGATION

[214] MISSING_JOIN | DB: cre_Doc_Template_Mgt | EX: ✗
  Q   : How many documents are using the template with type code 'PPT'
  Pred: SELECT COUNT(*) FROM documents WHERE template_type_code = 'PPT'
  Gold: SELECT COUNT(*) FROM Documents AS T1 JOIN Templates AS T2 ON T1.Template_ID = T2.Template_ID WHERE T2.Template_Type_Code = 'PPT'
  Type: JOIN, AGGREGATION

[215] MISSING_JOIN | DB: cre_Doc_Template_Mgt | EX: ✗
  Q   : Count the number of documents that use the PPT template type
  Pred: SELECT COUNT(*) FROM documents WHERE template_type_code = "PPT"
  Gold: SELECT COUNT(*) FROM Documents AS T1 JOIN Templates AS T2 ON T1.Template_ID = T2.Template_ID WHERE T2.Template_Type_Code = 'PPT'
  Type: JOIN, AGGREGATION

[216] WRONG_COLUMNS | DB: cre_Doc_Template_Mgt | EX: ✓
  Q   : What are all different template ids used for documents, and how many times were each of them used
  Pred: SELECT DISTINCT template_id, COUNT(*) FROM documents GROUP BY template_id
  Gold: SELECT template_id, COUNT(*) FROM Documents GROUP BY template_id
  Type: GROUP_BY, AGGREGATION

[217] WRONG_TABLE | DB: cre_Doc_Template_Mgt | EX: ✗
  Q   : What is the id and type code for the template used by the most documents
  Pred: SELECT template_id, template_type_code FROM templates GROUP BY template_id ORDER BY COUNT(*) DESC LIMIT 1
  Gold: SELECT T1.template_id, T2.Template_Type_Code FROM Documents AS T1 JOIN Templates AS T2 ON T1.template_id = T2.template_id GROUP BY T1.template_id ORDER BY COUNT(*) DESC LIMIT 1
  Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, AGGREGATION

[218] WRONG_TABLE | DB: cre_Doc_Template_Mgt | EX: ✗
  Q   : Return the id and type code of the template that is used for the greatest number of documents
  Pred: SELECT template_id, template_type_code FROM templates GROUP BY template_id ORDER BY COUNT(*) DESC LIMIT 1
  Gold: SELECT T1.template_id, T2.Template_Type_Code FROM Documents AS T1 JOIN Templates AS T2 ON T1.template_id = T2.template_id GROUP BY T1.template_id ORDER BY COUNT(*) DESC LIMIT 1
  Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, AGGREGATION

[219] WRONG_TABLE | DB: cre_Doc_Template_Mgt | EX: ✗
  Q   : What are the template ids of any templates used in more than a single document
  Pred: SELECT template_id FROM templates GROUP BY template_id HAVING COUNT(*) > 1
  Gold: SELECT template_id FROM Documents GROUP BY template_id HAVING COUNT(*) > 1
  Type: GROUP_BY, HAVING, AGGREGATION

[220] EXTRA_JOIN | DB: cre_Doc_Template_Mgt | EX: ✓
  Q   : What is the version number and template type code for the template with version number later than 5
  Pred: SELECT T2.version_number, T2.template_type_code FROM templates AS T1 JOIN templates AS T2 ON T1.template_id = T2.template_id WHERE T1.version_number > 5
  Gold: SELECT version_number, template_type_code FROM Templates WHERE version_number > 5
  Type: SIMPLE

[221] OTHER | DB: cre_Doc_Template_Mgt | EX: ✗
  Q   : Show all template type codes with less than three templates
  Pred: SELECT template_type_code FROM templates GROUP BY template_type_code HAVING COUNT(*)  3
  Gold: SELECT template_type_code FROM Templates GROUP BY template_type_code HAVING COUNT(*) < 3
  Type: GROUP_BY, HAVING, AGGREGATION

[222] OTHER | DB: cre_Doc_Template_Mgt | EX: ✗
  Q   : What are the codes of template types that have fewer than 3 templates
  Pred: SELECT template_type_code FROM templates GROUP BY template_type_code HAVING COUNT(*)  3
  Gold: SELECT template_type_code FROM Templates GROUP BY template_type_code HAVING COUNT(*) < 3
  Type: GROUP_BY, HAVING, AGGREGATION

[223] WRONG_COLUMNS | DB: cre_Doc_Template_Mgt | EX: ✗
  Q   : Return the lowest version number, along with its corresponding template type code
  Pred: SELECT version_number, template_type_code FROM templates GROUP BY template_type_code ORDER BY COUNT(*) LIMIT 1
  Gold: SELECT MIN(Version_Number), template_type_code FROM Templates
  Type: AGGREGATION

[224] MISSING_JOIN | DB: cre_Doc_Template_Mgt | EX: ✗
  Q   : What is the template type code of the template used by document with the name "Data base"
  Pred: SELECT template_type_code FROM templates WHERE document_name = "Data base"
  Gold: SELECT T1.template_type_code FROM Templates AS T1 JOIN Documents AS T2 ON T1.template_id = T2.template_id WHERE T2.document_name = "Data base"
  Type: JOIN

[225] MISSING_JOIN | DB: cre_Doc_Template_Mgt | EX: ✗
  Q   : Return the template type code of the template that is used by a document named Data base
  Pred: SELECT template_type_code FROM templates WHERE document_name = "Data base"
  Gold: SELECT T1.template_type_code FROM Templates AS T1 JOIN Documents AS T2 ON T1.template_id = T2.template_id WHERE T2.document_name = "Data base"
  Type: JOIN

[226] WRONG_TABLE | DB: cre_Doc_Template_Mgt | EX: ✗
  Q   : Show all document names using templates with template type code BK
  Pred: SELECT document_name FROM documents WHERE template_type_code = "BK"
  Gold: SELECT T2.document_name FROM Templates AS T1 JOIN Documents AS T2 ON T1.template_id = T2.template_id WHERE T1.template_type_code = "BK"
  Type: JOIN

[227] WRONG_TABLE | DB: cre_Doc_Template_Mgt | EX: ✗
  Q   : What are the names of documents that use templates with the code BK
  Pred: SELECT document_name FROM documents WHERE template_type_code = "BK"
  Gold: SELECT T2.document_name FROM Templates AS T1 JOIN Documents AS T2 ON T1.template_id = T2.template_id WHERE T1.template_type_code = "BK"
  Type: JOIN

[228] MISSING_JOIN | DB: cre_Doc_Template_Mgt | EX: ✗
  Q   : Show all template type codes and the number of documents using each type
  Pred: SELECT template_type_code, COUNT(*) FROM templates GROUP BY template_type_code
  Gold: SELECT T1.template_type_code, COUNT(*) FROM Templates AS T1 JOIN Documents AS T2 ON T1.template_id = T2.template_id GROUP BY T1.template_type_code
  Type: JOIN, GROUP_BY, AGGREGATION

[229] MISSING_JOIN | DB: cre_Doc_Template_Mgt | EX: ✗
  Q   : What are the different template type codes, and how many documents use each type
  Pred: SELECT template_type_code, COUNT(*) FROM templates GROUP BY template_type_code
  Gold: SELECT T1.template_type_code, COUNT(*) FROM Templates AS T1 JOIN Documents AS T2 ON T1.template_id = T2.template_id GROUP BY T1.template_type_code
  Type: JOIN, GROUP_BY, AGGREGATION

[230] MISSING_JOIN | DB: cre_Doc_Template_Mgt | EX: ✗
  Q   : Which template type code is used by most number of documents
  Pred: SELECT template_type_code FROM templates GROUP BY template_type_code ORDER BY COUNT(*) DESC LIMIT 1
  Gold: SELECT T1.template_type_code FROM Templates AS T1 JOIN Documents AS T2 ON T1.template_id = T2.template_id GROUP BY T1.template_type_code ORDER BY COUNT(*) DESC LIMIT 1
  Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, AGGREGATION

[231] MISSING_JOIN | DB: cre_Doc_Template_Mgt | EX: ✗
  Q   : Return the code of the template type that is most commonly used in documents
  Pred: SELECT template_type_code FROM templates GROUP BY template_type_code ORDER BY COUNT(*) DESC LIMIT 1
  Gold: SELECT T1.template_type_code FROM Templates AS T1 JOIN Documents AS T2 ON T1.template_id = T2.template_id GROUP BY T1.template_type_code ORDER BY COUNT(*) DESC LIMIT 1
  Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, AGGREGATION

[232] WRONG_TABLE | DB: cre_Doc_Template_Mgt | EX: ✗
  Q   : Show all template type codes that are not used by any document
  Pred: SELECT template_type_code FROM templates EXCEPT SELECT template_type_code FROM documents
  Gold: SELECT template_type_code FROM Templates EXCEPT SELECT template_type_code FROM Templates AS T1 JOIN Documents AS T2 ON T1.template_id = T2.template_id
  Type: JOIN

[233] MISSING_JOIN | DB: cre_Doc_Template_Mgt | EX: ✗
  Q   : What are the codes of template types that are not used for any document
  Pred: SELECT template_type_code FROM templates EXCEPT SELECT template_type_code FROM templates
  Gold: SELECT template_type_code FROM Templates EXCEPT SELECT template_type_code FROM Templates AS T1 JOIN Documents AS T2 ON T1.template_id = T2.template_id
  Type: JOIN

[234] WRONG_TABLE | DB: cre_Doc_Template_Mgt | EX: ✗
  Q   : Show all template type codes and descriptions
  Pred: SELECT template_type_code, template_type_description FROM templates
  Gold: SELECT template_type_code, template_type_description FROM Ref_template_types
  Type: SIMPLE

[235] WRONG_TABLE | DB: cre_Doc_Template_Mgt | EX: ✗
  Q   : What are the type codes and descriptions for all template types
  Pred: SELECT template_type_code, template_type_description FROM templates
  Gold: SELECT template_type_code, template_type_description FROM Ref_template_types
  Type: SIMPLE

[236] WRONG_TABLE | DB: cre_Doc_Template_Mgt | EX: ✗
  Q   : What is the template type descriptions for template type code "AD"
  Pred: SELECT template_type_description FROM templates WHERE template_type_code = "AD"
  Gold: SELECT template_type_description FROM Ref_template_types WHERE template_type_code = "AD"
  Type: SIMPLE

[237] WRONG_TABLE | DB: cre_Doc_Template_Mgt | EX: ✗
  Q   : Return the template type description of the template type with the code AD
  Pred: SELECT template_type_description FROM templates WHERE template_type_code = "AD"
  Gold: SELECT template_type_description FROM Ref_template_types WHERE template_type_code = "AD"
  Type: SIMPLE

[238] WRONG_TABLE | DB: cre_Doc_Template_Mgt | EX: ✗
  Q   : What are the distinct template type descriptions for the templates ever used by any document
  Pred: SELECT DISTINCT template_type_description FROM templates
  Gold: SELECT DISTINCT T1.template_type_description FROM Ref_template_types AS T1 JOIN Templates AS T2 ON T1.template_type_code = T2.template_type_code JOIN Documents AS T3 ON T2.Template_ID = T3.template_ID
  Type: JOIN

[239] WRONG_TABLE | DB: cre_Doc_Template_Mgt | EX: ✗
  Q   : Return the different descriptions for templates that have been used in a document
  Pred: SELECT DISTINCT template_description FROM templates
  Gold: SELECT DISTINCT T1.template_type_description FROM Ref_template_types AS T1 JOIN Templates AS T2 ON T1.template_type_code = T2.template_type_code JOIN Documents AS T3 ON T2.Template_ID = T3.template_ID
  Type: JOIN

[240] WRONG_TABLE | DB: cre_Doc_Template_Mgt | EX: ✗
  Q   : What are the template ids with template type description "Presentation"
  Pred: SELECT template_id FROM templates WHERE template_type_description = "Presentation"
  Gold: SELECT T2.template_id FROM Ref_template_types AS T1 JOIN Templates AS T2 ON T1.template_type_code = T2.template_type_code WHERE T1.template_type_description = "Presentation"
  Type: JOIN

[241] WRONG_TABLE | DB: cre_Doc_Template_Mgt | EX: ✗
  Q   : Return the ids corresponding to templates with the description 'Presentation'
  Pred: SELECT template_id FROM templates WHERE template_description = 'Presentation'
  Gold: SELECT T2.template_id FROM Ref_template_types AS T1 JOIN Templates AS T2 ON T1.template_type_code = T2.template_type_code WHERE T1.template_type_description = "Presentation"
  Type: JOIN

[242] OTHER | DB: cre_Doc_Template_Mgt | EX: ✓
  Q   : Show paragraph details for paragraph with text 'Korea '
  Pred: SELECT other_details FROM paragraphs WHERE paragraph_text = 'Korea'
  Gold: SELECT other_details FROM paragraphs WHERE paragraph_text LIKE 'korea'
  Type: SIMPLE

[243] OTHER | DB: cre_Doc_Template_Mgt | EX: ✓
  Q   : What are the details for the paragraph that includes the text 'Korea '
  Pred: SELECT other_details FROM paragraphs WHERE paragraph_text LIKE "%Korea%"
  Gold: SELECT other_details FROM paragraphs WHERE paragraph_text LIKE 'korea'
  Type: SIMPLE

[244] MISSING_JOIN | DB: cre_Doc_Template_Mgt | EX: ✗
  Q   : Show all paragraph ids and texts for the document with name 'Welcome to NY'
  Pred: SELECT document_id, paragraph_text FROM paragraphs WHERE document_name = 'Welcome to NY'
  Gold: SELECT T1.paragraph_id, T1.paragraph_text FROM Paragraphs AS T1 JOIN Documents AS T2 ON T1.document_id = T2.document_id WHERE T2.Document_Name = 'Welcome to NY'
  Type: JOIN

[245] MISSING_JOIN | DB: cre_Doc_Template_Mgt | EX: ✗
  Q   : What are the ids and texts of paragraphs in the document titled 'Welcome to NY'
  Pred: SELECT paragraph_id, paragraph_text FROM paragraphs WHERE document_name = 'Welcome to NY'
  Gold: SELECT T1.paragraph_id, T1.paragraph_text FROM Paragraphs AS T1 JOIN Documents AS T2 ON T1.document_id = T2.document_id WHERE T2.Document_Name = 'Welcome to NY'
  Type: JOIN

[246] MISSING_JOIN | DB: cre_Doc_Template_Mgt | EX: ✗
  Q   : Show all paragraph texts for the document "Customer reviews"
  Pred: SELECT paragraph_text FROM paragraphs WHERE document_name = "Customer reviews"
  Gold: SELECT T1.paragraph_text FROM Paragraphs AS T1 JOIN Documents AS T2 ON T1.document_id = T2.document_id WHERE T2.document_name = "Customer reviews"
  Type: JOIN

[247] MISSING_JOIN | DB: cre_Doc_Template_Mgt | EX: ✗
  Q   : What are the paragraph texts for the document with the name 'Customer reviews'
  Pred: SELECT paragraph_text FROM paragraphs WHERE document_name = 'Customer reviews'
  Gold: SELECT T1.paragraph_text FROM Paragraphs AS T1 JOIN Documents AS T2 ON T1.document_id = T2.document_id WHERE T2.document_name = "Customer reviews"
  Type: JOIN

[248] MISSING_ORDER_BY | DB: cre_Doc_Template_Mgt | EX: ✗
  Q   : Show all document ids and the number of paragraphs in each document. Order by document id
  Pred: SELECT document_id, COUNT(*) FROM paragraphs GROUP BY document_id
  Gold: SELECT document_id, COUNT(*) FROM Paragraphs GROUP BY document_id ORDER BY document_id
  Type: GROUP_BY, ORDER_BY, AGGREGATION

[249] MISSING_GROUP_BY | DB: cre_Doc_Template_Mgt | EX: ✗
  Q   : Return the different document ids along with the number of paragraphs corresponding to each, ordered by id
  Pred: SELECT document_id, COUNT(*) FROM paragraphs ORDER BY document_id
  Gold: SELECT document_id, COUNT(*) FROM Paragraphs GROUP BY document_id ORDER BY document_id
  Type: GROUP_BY, ORDER_BY, AGGREGATION

[250] MISSING_JOIN | DB: cre_Doc_Template_Mgt | EX: ✗
  Q   : Show all document ids, names and the number of paragraphs in each document
  Pred: SELECT Document_ID, Document_Name, COUNT(*) FROM paragraphs GROUP BY Document_ID
  Gold: SELECT T1.document_id, T2.document_name, COUNT(*) FROM Paragraphs AS T1 JOIN Documents AS T2 ON T1.document_id = T2.document_id GROUP BY T1.document_id
  Type: JOIN, GROUP_BY, AGGREGATION

[251] MISSING_JOIN | DB: cre_Doc_Template_Mgt | EX: ✗
  Q   : What are the ids and names of each document, as well as the number of paragraphs in each
  Pred: SELECT document_id, document_name, COUNT(*) FROM paragraphs GROUP BY document_id
  Gold: SELECT T1.document_id, T2.document_name, COUNT(*) FROM Paragraphs AS T1 JOIN Documents AS T2 ON T1.document_id = T2.document_id GROUP BY T1.document_id
  Type: JOIN, GROUP_BY, AGGREGATION

[252] MISSING_JOIN | DB: cre_Doc_Template_Mgt | EX: ✗
  Q   : What is the document id and name with greatest number of paragraphs
  Pred: SELECT document_id, document_name FROM paragraphs GROUP BY document_id ORDER BY COUNT(*) DESC LIMIT 1
  Gold: SELECT T1.document_id, T2.document_name FROM Paragraphs AS T1 JOIN Documents AS T2 ON T1.document_id = T2.document_id GROUP BY T1.document_id ORDER BY COUNT(*) DESC LIMIT 1
  Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, AGGREGATION

[253] MISSING_JOIN | DB: cre_Doc_Template_Mgt | EX: ✗
  Q   : Return the id and name of the document with the most paragraphs
  Pred: SELECT document_id, document_name FROM paragraphs GROUP BY document_id ORDER BY COUNT(*) DESC LIMIT 1
  Gold: SELECT T1.document_id, T2.document_name FROM Paragraphs AS T1 JOIN Documents AS T2 ON T1.document_id = T2.document_id GROUP BY T1.document_id ORDER BY COUNT(*) DESC LIMIT 1
  Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, AGGREGATION

[254] OTHER | DB: cre_Doc_Template_Mgt | EX: ✓
  Q   : What is the document id with least number of paragraphs
  Pred: SELECT document_id FROM paragraphs GROUP BY document_id ORDER BY COUNT(*) LIMIT 1
  Gold: SELECT document_id FROM Paragraphs GROUP BY document_id ORDER BY COUNT(*) ASC LIMIT 1
  Type: GROUP_BY, ORDER_BY, LIMIT, AGGREGATION

[255] OTHER | DB: cre_Doc_Template_Mgt | EX: ✗
  Q   : What is the document id with 1 to 2 paragraphs
  Pred: SELECT document_id FROM paragraphs GROUP BY document_id HAVING COUNT(*) >= 1
  Gold: SELECT document_id FROM Paragraphs GROUP BY document_id HAVING COUNT(*) BETWEEN 1 AND 2
  Type: GROUP_BY, HAVING, AGGREGATION

[256] OTHER | DB: course_teach | EX: ✓
  Q   : List the name of teachers whose hometown is not `` Little Lever Urban District ''
  Pred: SELECT Name FROM teacher WHERE Hometown > ''
  Gold: SELECT name FROM teacher WHERE hometown <> "little lever urban district"
  Type: SIMPLE

[257] OTHER | DB: course_teach | EX: ✗
  Q   : What are the names of the teachers whose hometown is not `` Little Lever Urban District ''
  Pred: SELECT Name FROM teacher WHERE Hometown >  Little Lever Urban District ''
  Gold: SELECT name FROM teacher WHERE hometown <> "little lever urban district"
  Type: SIMPLE

[258] OTHER | DB: course_teach | EX: ✓
  Q   : What is the hometown of the youngest teacher
  Pred: SELECT hometown FROM teacher ORDER BY age LIMIT 1
  Gold: SELECT Hometown FROM teacher ORDER BY Age ASC LIMIT 1
  Type: ORDER_BY, LIMIT

[259] EXTRA_JOIN | DB: course_teach | EX: ✗
  Q   : Where is the youngest teacher from
  Pred: SELECT T1.Hometown FROM teacher AS T1 JOIN course_arrange AS T2 ON T1.teacher_id = T2.teacher_id GROUP BY T1.teacher_id ORDER BY COUNT(*) DESC LIMIT 1
  Gold: SELECT Hometown FROM teacher ORDER BY Age ASC LIMIT 1
  Type: ORDER_BY, LIMIT

[260] WRONG_COLUMNS | DB: course_teach | EX: ✗
  Q   : Show names of teachers and the courses they are arranged to teach
  Pred: SELECT T1.Name, T2.Course FROM course_arrange AS T1 JOIN teacher AS T2 ON T1.Teacher_ID = T2.Teacher_ID
  Gold: SELECT T3.Name, T2.Course FROM course_arrange AS T1 JOIN course AS T2 ON T1.Course_ID = T2.Course_ID JOIN teacher AS T3 ON T1.Teacher_ID = T3.Teacher_ID
  Type: JOIN

[261] WRONG_TABLE | DB: course_teach | EX: ✗
  Q   : What is the name of each teacher and what course they teach
  Pred: SELECT T1.Name, T2.Course FROM course AS T1 JOIN teacher AS T2 ON T1.Teacher_ID = T2.Teacher_ID
  Gold: SELECT T3.Name, T2.Course FROM course_arrange AS T1 JOIN course AS T2 ON T1.Course_ID = T2.Course_ID JOIN teacher AS T3 ON T1.Teacher_ID = T3.Teacher_ID
  Type: JOIN

[262] WRONG_TABLE | DB: course_teach | EX: ✗
  Q   : Show names of teachers and the courses they are arranged to teach in ascending alphabetical order of the teacher's name
  Pred: SELECT T1.Name, T2.Name FROM course AS T1 JOIN teacher AS T2 ON T1.Teacher_ID = T2.Teacher_ID ORDER BY T2.Name
  Gold: SELECT T3.Name, T2.Course FROM course_arrange AS T1 JOIN course AS T2 ON T1.Course_ID = T2.Course_ID JOIN teacher AS T3 ON T1.Teacher_ID = T3.Teacher_ID ORDER BY T3.Name
  Type: JOIN, ORDER_BY

[263] WRONG_TABLE | DB: course_teach | EX: ✗
  Q   : What are the names of the teachers and the courses they teach in ascending alphabetical order by the name of the teacher
  Pred: SELECT Name, Course FROM teacher ORDER BY Name ASC
  Gold: SELECT T3.Name, T2.Course FROM course_arrange AS T1 JOIN course AS T2 ON T1.Course_ID = T2.Course_ID JOIN teacher AS T3 ON T1.Teacher_ID = T3.Teacher_ID ORDER BY T3.Name
  Type: JOIN, ORDER_BY

[264] WRONG_TABLE | DB: course_teach | EX: ✗
  Q   : Show the name of the teacher for the math course
  Pred: SELECT Name FROM teacher WHERE Course = 'Math'
  Gold: SELECT T3.Name FROM course_arrange AS T1 JOIN course AS T2 ON T1.Course_ID = T2.Course_ID JOIN teacher AS T3 ON T1.Teacher_ID = T3.Teacher_ID WHERE T2.Course = "Math"
  Type: JOIN

[265] WRONG_TABLE | DB: course_teach | EX: ✗
  Q   : What are the names of the people who teach math courses
  Pred: SELECT Name FROM teacher WHERE Name = "Math"
  Gold: SELECT T3.Name FROM course_arrange AS T1 JOIN course AS T2 ON T1.Course_ID = T2.Course_ID JOIN teacher AS T3 ON T1.Teacher_ID = T3.Teacher_ID WHERE T2.Course = "Math"
  Type: JOIN

[266] WRONG_TABLE | DB: course_teach | EX: ✗
  Q   : Show names of teachers and the number of courses they teach
  Pred: SELECT T2.Name, COUNT(*) FROM course AS T1 JOIN teacher AS T2 ON T1.Teacher_ID = T2.Teacher_ID
  Gold: SELECT T2.Name, COUNT(*) FROM course_arrange AS T1 JOIN teacher AS T2 ON T1.Teacher_ID = T2.Teacher_ID GROUP BY T2.Name
  Type: JOIN, GROUP_BY, AGGREGATION

[267] WRONG_TABLE | DB: course_teach | EX: ✗
  Q   : What are the names of the teachers and how many courses do they teach
  Pred: SELECT T2.Name, COUNT(*) FROM course AS T1 JOIN teacher AS T2 ON T1.Teacher_ID = T2.Teacher_ID
  Gold: SELECT T2.Name, COUNT(*) FROM course_arrange AS T1 JOIN teacher AS T2 ON T1.Teacher_ID = T2.Teacher_ID GROUP BY T2.Name
  Type: JOIN, GROUP_BY, AGGREGATION

[268] WRONG_TABLE | DB: course_teach | EX: ✗
  Q   : Show names of teachers that teach at least two courses
  Pred: SELECT Name FROM teacher GROUP BY Name HAVING COUNT(*) >= 2
  Gold: SELECT T2.Name FROM course_arrange AS T1 JOIN teacher AS T2 ON T1.Teacher_ID = T2.Teacher_ID GROUP BY T2.Name HAVING COUNT(*) >= 2
  Type: JOIN, GROUP_BY, HAVING, AGGREGATION

[269] WRONG_TABLE | DB: course_teach | EX: ✗
  Q   : What are the names of the teachers who teach at least two courses
  Pred: SELECT Name FROM teacher GROUP BY Name HAVING COUNT(*) >= 2
  Gold: SELECT T2.Name FROM course_arrange AS T1 JOIN teacher AS T2 ON T1.Teacher_ID = T2.Teacher_ID GROUP BY T2.Name HAVING COUNT(*) >= 2
  Type: JOIN, GROUP_BY, HAVING, AGGREGATION

[270] OTHER | DB: museum_visit | EX: ✗
  Q   : How many visitors below age 30 are there
  Pred: SELECT COUNT(*) FROM visitor WHERE age  30
  Gold: SELECT COUNT(*) FROM visitor WHERE age < 30
  Type: AGGREGATION

[271] OTHER | DB: museum_visit | EX: ✗
  Q   : Find the names of the visitors whose membership level is higher than 4, and order the results by the level from high to low
  Pred: SELECT name FROM visitor WHERE level_of_membership > 4 ORDER BY level_of_membership
  Gold: SELECT name FROM visitor WHERE Level_of_membership > 4 ORDER BY Level_of_membership DESC
  Type: ORDER_BY

[272] OTHER | DB: museum_visit | EX: ✗
  Q   : What is the average age of the visitors whose membership level is not higher than 4
  Pred: SELECT AVG(age) FROM visitor WHERE level_of_membership  4
  Gold: SELECT AVG(age) FROM visitor WHERE Level_of_membership <= 4
  Type: AGGREGATION

[273] OTHER | DB: museum_visit | EX: ✗
  Q   : Find the name and membership level of the visitors whose membership level is higher than 4, and sort by their age from old to young
  Pred: SELECT name, level_of_membership FROM visitor WHERE level_of_membership > 4 ORDER BY age
  Gold: SELECT name, Level_of_membership FROM visitor WHERE Level_of_membership > 4 ORDER BY age DESC
  Type: ORDER_BY

[274] OTHER | DB: museum_visit | EX: ✗
  Q   : Find the average number of staff working for the museums that were open before 2009
  Pred: SELECT AVG(num_of_staff) FROM museum WHERE open_year  2009
  Gold: SELECT AVG(num_of_staff) FROM museum WHERE open_year < 2009
  Type: AGGREGATION

[275] WRONG_COLUMNS | DB: museum_visit | EX: ✗
  Q   : What are the opening year and staff number of the museum named Plaza Museum
  Pred: SELECT open_year, num_of_staff FROM museum WHERE name = "Plaza Museum"
  Gold: SELECT Num_of_Staff, Open_Year FROM museum WHERE name = 'Plaza Museum'
  Type: SIMPLE

[276] OTHER | DB: museum_visit | EX: ✗
  Q   : find the id, name and age for visitors who visited some museums more than once
  Pred: SELECT T1.id, T1.name, T1.age FROM visitor AS T1 JOIN visit AS T2 ON T1.visitor_id = T2.visitor_id GROUP BY T1.id HAVING COUNT(*) > 1
  Gold: SELECT t1.id, t1.name, t1.age FROM visitor AS t1 JOIN visit AS t2 ON t1.id = t2.visitor_id GROUP BY t1.id HAVING COUNT(*) > 1
  Type: JOIN, GROUP_BY, HAVING, AGGREGATION

[277] WRONG_COLUMNS | DB: museum_visit | EX: ✗
  Q   : What are the id, name and membership level of visitors who have spent the largest amount of money in total in all museum tickets
  Pred: SELECT T1.id, T1.name, T1.level_of_membership FROM visitor AS T1 JOIN visit AS T2 ON T1.visitor_id = T2.visitor_id GROUP BY T1.id ORDER BY SUM(T2.total_spent) DESC LIMIT 1
  Gold: SELECT t2.visitor_id, t1.name, t1.Level_of_membership FROM visitor AS t1 JOIN visit AS t2 ON t1.id = t2.visitor_id GROUP BY t2.visitor_id ORDER BY SUM(t2.Total_spent) DESC LIMIT 1
  Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, AGGREGATION

[278] WRONG_COLUMNS | DB: museum_visit | EX: ✓
  Q   : What are the id and name of the museum visited most times
  Pred: SELECT T1.museum_id, T1.name FROM museum AS T1 JOIN visit AS T2 ON T1.museum_id = T2.museum_id GROUP BY T1.museum_id ORDER BY COUNT(*) DESC LIMIT 1
  Gold: SELECT t2.Museum_ID, t1.name FROM museum AS t1 JOIN visit AS t2 ON t1.Museum_ID = t2.Museum_ID GROUP BY t2.Museum_ID ORDER BY COUNT(*) DESC LIMIT 1
  Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, AGGREGATION

[279] OTHER | DB: museum_visit | EX: ✗
  Q   : What is the name of the museum that had no visitor yet
  Pred: SELECT name FROM museum WHERE NOT id IN (SELECT museum_id FROM visit)
  Gold: SELECT name FROM museum WHERE NOT Museum_ID IN (SELECT museum_id FROM visit)
  Type: NESTED

[280] MISSING_JOIN | DB: museum_visit | EX: ✗
  Q   : Find the name and age of the visitor who bought the most tickets at once
  Pred: SELECT name, age FROM visitor ORDER BY num_of_ticket DESC LIMIT 1
  Gold: SELECT t1.name, t1.age FROM visitor AS t1 JOIN visit AS t2 ON t1.id = t2.visitor_id ORDER BY t2.num_of_ticket DESC LIMIT 1
  Type: JOIN, ORDER_BY, LIMIT

[281] OTHER | DB: museum_visit | EX: ✗
  Q   : What is the total ticket expense of the visitors whose membership level is 1
  Pred: SELECT SUM(T2.Total_Spent) FROM visitor AS T1 JOIN visit AS T2 ON T1.Visitor_ID = T2.Visitor_ID WHERE T1.Level_of_Membership = 1
  Gold: SELECT SUM(t2.Total_spent) FROM visitor AS t1 JOIN visit AS t2 ON t1.id = t2.visitor_id WHERE t1.Level_of_membership = 1
  Type: JOIN, AGGREGATION

[282] OTHER | DB: museum_visit | EX: ✗
  Q   : What is the name of the visitor who visited both a museum opened before 2009 and a museum opened after 2011
  Pred: SELECT T1.name FROM visitor AS T1 JOIN visit AS T2 ON T1.id = T2.visitor_id WHERE T2.open_year  2009 INTERSECT SELECT T1.name FROM visitor AS T1 JOIN museum AS T2 ON T1.museum_id = T2.museum_id WHERE T2.open_year > 2011
  Gold: SELECT t1.name FROM visitor AS t1 JOIN visit AS t2 ON t1.id = t2.visitor_id JOIN museum AS t3 ON t3.Museum_ID = t2.Museum_ID WHERE t3.open_year < 2009 INTERSECT SELECT t1.name FROM visitor AS t1 JOIN visit AS t2 ON t1.id = t2.visitor_id JOIN museum AS t3 ON t3.Museum_ID = t2.Museum_ID WHERE t3.open_year > 2011
  Type: JOIN

[283] WRONG_TABLE | DB: museum_visit | EX: ✗
  Q   : Find the number of visitors who did not visit any museum opened after 2010
  Pred: SELECT COUNT(*) FROM visitor WHERE NOT visitor_id IN (SELECT visitor_id FROM visit WHERE open_year > 2010)
  Gold: SELECT COUNT(*) FROM visitor WHERE NOT id IN (SELECT t2.visitor_id FROM museum AS t1 JOIN visit AS t2 ON t1.Museum_ID = t2.Museum_ID WHERE t1.open_year > 2010)
  Type: JOIN, NESTED, AGGREGATION

[284] OTHER | DB: museum_visit | EX: ✗
  Q   : How many museums were opened after 2013 or before 2008
  Pred: SELECT COUNT(*) FROM museum WHERE open_year > 2013 OR open_year  2008
  Gold: SELECT COUNT(*) FROM museum WHERE open_year > 2013 OR open_year < 2008
  Type: AGGREGATION

[285] EXTRA_JOIN | DB: wta_1 | EX: ✗
  Q   : List the first name and birth date of all players from the country with code USA
  Pred: SELECT T1.first_name, T1.birth_date FROM players AS T1 JOIN rankings AS T2 ON T1.player_id = T2.player_id WHERE T2.country_code = "USA"
  Gold: SELECT first_name, birth_date FROM players WHERE country_code = 'USA'
  Type: SIMPLE

[286] EXTRA_JOIN | DB: wta_1 | EX: ✗
  Q   : What are the first names and birth dates of players from the USA
  Pred: SELECT T1.first_name, T1.birth_date FROM players AS T1 JOIN rankings AS T2 ON T1.player_id = T2.player_id WHERE T2.country_code = "USA"
  Gold: SELECT first_name, birth_date FROM players WHERE country_code = 'USA'
  Type: SIMPLE

[287] WRONG_COLUMNS | DB: wta_1 | EX: ✗
  Q   : Find the highest rank of losers in all matches
  Pred: SELECT MAX(loser_rank) FROM matches GROUP BY MAX(loser_rank)
  Gold: SELECT MIN(loser_rank) FROM matches
  Type: AGGREGATION

[288] EXTRA_JOIN | DB: wta_1 | EX: ✗
  Q   : What is the best rank of losers across all matches
  Pred: SELECT T1.loser_rank, MAX(T2.loser_rank) FROM matches AS T1 JOIN matches AS T2 ON T1.loser_id = T2.player_id GROUP BY T1.loser_rank
  Gold: SELECT MIN(loser_rank) FROM matches
  Type: AGGREGATION

[289] WRONG_TABLE | DB: wta_1 | EX: ✗
  Q   : What are the names of players who won in both 2013 and 2016
  Pred: SELECT T1.winner_name FROM players AS T1 JOIN rankings AS T2 ON T1.player_id = T2.player_id WHERE T2.year = 2013 INTERSECT SELECT T1.winner_name FROM players AS T1 JOIN rankings AS T2 ON T1.player_id = T2.player_id WHERE T2.year = 2016
  Gold: SELECT winner_name FROM matches WHERE YEAR = 2013 INTERSECT SELECT winner_name FROM matches WHERE YEAR = 2016
  Type: SIMPLE

[290] OTHER | DB: wta_1 | EX: ✗
  Q   : What are the country code and first name of the players who won in both tourney WTA Championships and Australian Open
  Pred: SELECT T1.country_code, T1.first_name FROM players AS T1 JOIN rankings AS T2 ON T1.player_id = T2.player_id WHERE T2.tournament = "WTA Championships" INTERSECT SELECT T1.country_code, T1.first_name FROM players AS T1 JOIN rankings AS T2 ON T1.player_id = T2.player_id WHERE T2.tournament = "Australian Open"
  Gold: SELECT T1.country_code, T1.first_name FROM players AS T1 JOIN matches AS T2 ON T1.player_id = T2.winner_id WHERE T2.tourney_name = 'WTA Championships' INTERSECT SELECT T1.country_code, T1.first_name FROM players AS T1 JOIN matches AS T2 ON T1.player_id = T2.winner_id WHERE T2.tourney_name = 'Australian Open'
  Type: JOIN

[291] WRONG_COLUMNS | DB: wta_1 | EX: ✗
  Q   : What are the first names and country codes for players who won both the WTA Championships and the Australian Open
  Pred: SELECT T1.first_name, T1.country_code FROM players AS T1 JOIN rankings AS T2 ON T1.player_id = T2.player_id WHERE T2.winner_name = 'WTA Championships' INTERSECT SELECT T1.first_name, T1.country_code FROM players AS T1 JOIN rankings AS T2 ON T1.player_id = T2.player_id WHERE T2.winner_name = 'Australian Open'
  Gold: SELECT T1.country_code, T1.first_name FROM players AS T1 JOIN matches AS T2 ON T1.player_id = T2.winner_id WHERE T2.tourney_name = 'WTA Championships' INTERSECT SELECT T1.country_code, T1.first_name FROM players AS T1 JOIN matches AS T2 ON T1.player_id = T2.winner_id WHERE T2.tourney_name = 'Australian Open'
  Type: JOIN

[292] OTHER | DB: wta_1 | EX: ✗
  Q   : Find the first name and country code of the oldest player
  Pred: SELECT first_name, country_code FROM players ORDER BY birth_date DESC LIMIT 1
  Gold: SELECT first_name, country_code FROM players ORDER BY birth_date LIMIT 1
  Type: ORDER_BY, LIMIT

[293] OTHER | DB: wta_1 | EX: ✗
  Q   : What is the first name and country code of the oldest player
  Pred: SELECT first_name, country_code FROM players ORDER BY birth_date DESC LIMIT 1
  Gold: SELECT first_name, country_code FROM players ORDER BY birth_date LIMIT 1
  Type: ORDER_BY, LIMIT

[294] WRONG_COLUMNS | DB: wta_1 | EX: ✗
  Q   : What are the full names of all players, sorted by birth date
  Pred: SELECT first_name, last_name, birth_date FROM players ORDER BY birth_date
  Gold: SELECT first_name, last_name FROM players ORDER BY birth_date
  Type: ORDER_BY

[295] MISSING_ORDER_BY | DB: wta_1 | EX: ✗
  Q   : List the first and last name of all players who are left / L hand in the order of birth date
  Pred: SELECT first_name, last_name FROM players WHERE hand = 'left' OR birth_date = (SELECT birth_date FROM players WHERE hand = 'L')
  Gold: SELECT first_name, last_name FROM players WHERE hand = 'L' ORDER BY birth_date
  Type: ORDER_BY

[296] OTHER | DB: wta_1 | EX: ✗
  Q   : What are the full names of all left handed players, in order of birth date
  Pred: SELECT first_name, last_name FROM players WHERE hand = 'left' ORDER BY birth_date
  Gold: SELECT first_name, last_name FROM players WHERE hand = 'L' ORDER BY birth_date
  Type: ORDER_BY

[297] WRONG_COLUMNS | DB: wta_1 | EX: ✗
  Q   : Find the first name and country code of the player who did the most number of tours
  Pred: SELECT T1.first_name, T1.country_code FROM players AS T1 JOIN rankings AS T2 ON T1.player_id = T2.player_id GROUP BY T1.player_id ORDER BY COUNT(*) DESC LIMIT 1
  Gold: SELECT T1.country_code, T1.first_name FROM players AS T1 JOIN rankings AS T2 ON T1.player_id = T2.player_id ORDER BY T2.tours DESC LIMIT 1
  Type: JOIN, ORDER_BY, LIMIT

[298] WRONG_TABLE | DB: wta_1 | EX: ✗
  Q   : What is the first name and country code of the player with the most tours
  Pred: SELECT T1.first_name, T1.country_code FROM rankings AS T1 JOIN players AS T2 ON T1.player_id = T2.player_id GROUP BY T1.player_id ORDER BY COUNT(*) DESC LIMIT 1
  Gold: SELECT T1.country_code, T1.first_name FROM players AS T1 JOIN rankings AS T2 ON T1.player_id = T2.player_id ORDER BY T2.tours DESC LIMIT 1
  Type: JOIN, ORDER_BY, LIMIT

[299] WRONG_COLUMNS | DB: wta_1 | EX: ✗
  Q   : What is the name of the winner who has won the most matches, and how many rank points does this player have
  Pred: SELECT winner_name, COUNT(*) FROM matches GROUP BY winner_name ORDER BY COUNT(*) DESC LIMIT 1
  Gold: SELECT winner_name, winner_rank_points FROM matches GROUP BY winner_name ORDER BY COUNT(*) DESC LIMIT 1
  Type: GROUP_BY, ORDER_BY, LIMIT, AGGREGATION

[300] WRONG_TABLE | DB: wta_1 | EX: ✗
  Q   : Find the name of the winner who has the highest rank points and participated in the Australian Open tourney
  Pred: SELECT T1.winner_name FROM players AS T1 JOIN rankings AS T2 ON T1.player_id = T2.player_id WHERE T2.rank_points = (SELECT MAX(winner_rank_points) FROM rankings AS T3 JOIN players AS T4 ON T3.player_id = T4.player_id WHERE T4.rank_points = 'Australian Open')
  Gold: SELECT winner_name FROM matches WHERE tourney_name = 'Australian Open' ORDER BY winner_rank_points DESC LIMIT 1
  Type: ORDER_BY, LIMIT

[301] OTHER | DB: wta_1 | EX: ✓
  Q   : What is the name of the winner with the most rank points who participated in the Australian Open tournament
  Pred: SELECT winner_name FROM matches WHERE tourney_name = 'Australian Open' GROUP BY winner_name ORDER BY COUNT(*) DESC LIMIT 1
  Gold: SELECT winner_name FROM matches WHERE tourney_name = 'Australian Open' ORDER BY winner_rank_points DESC LIMIT 1
  Type: ORDER_BY, LIMIT

[302] EXTRA_JOIN | DB: wta_1 | EX: ✗
  Q   : find the names of loser and winner who played in the match with greatest number of minutes
  Pred: SELECT T1.loser_name, T1.winner_name FROM matches AS T1 JOIN players AS T2 ON T1.player_id = T2.player_id GROUP BY T1.loser_name ORDER BY COUNT(*) DESC LIMIT 1
  Gold: SELECT winner_name, loser_name FROM matches ORDER BY minutes DESC LIMIT 1
  Type: ORDER_BY, LIMIT

[303] EXTRA_JOIN | DB: wta_1 | EX: ✗
  Q   : What are the names of the winner and loser who played in the longest match
  Pred: SELECT T1.winner_name, T1.loser_name FROM matches AS T1 JOIN matches AS T2 ON T1.player_id = T2.player_id ORDER BY T2.best_of DESC LIMIT 1
  Gold: SELECT winner_name, loser_name FROM matches ORDER BY minutes DESC LIMIT 1
  Type: ORDER_BY, LIMIT

[304] MISSING_JOIN | DB: wta_1 | EX: ✗
  Q   : Find the average ranking for each player and their first name
  Pred: SELECT AVG(Ranking), first_name FROM Players GROUP BY first_name
  Gold: SELECT AVG(ranking), T1.first_name FROM players AS T1 JOIN rankings AS T2 ON T1.player_id = T2.player_id GROUP BY T1.first_name
  Type: JOIN, GROUP_BY, AGGREGATION

[305] WRONG_TABLE | DB: wta_1 | EX: ✗
  Q   : What are the first names of all players, and their average rankings
  Pred: SELECT T1.first_name, AVG(T2.ranking_points) FROM rankings AS T1 JOIN players AS T2 ON T1.player_id = T2.player_id
  Gold: SELECT AVG(ranking), T1.first_name FROM players AS T1 JOIN rankings AS T2 ON T1.player_id = T2.player_id GROUP BY T1.first_name
  Type: JOIN, GROUP_BY, AGGREGATION

[306] OTHER | DB: wta_1 | EX: ✗
  Q   : Find the total ranking points for each player and their first name
  Pred: SELECT SUM(Ranking_Points), T1.first_name FROM players AS T1 JOIN rankings AS T2 ON T1.player_id = T2.player_id GROUP BY T1.player_id
  Gold: SELECT SUM(ranking_points), T1.first_name FROM players AS T1 JOIN rankings AS T2 ON T1.player_id = T2.player_id GROUP BY T1.first_name
  Type: JOIN, GROUP_BY, AGGREGATION

[307] WRONG_TABLE | DB: wta_1 | EX: ✗
  Q   : What are the first names of all players, and their total ranking points
  Pred: SELECT T1.first_name, SUM(T2.ranking_points) FROM rankings AS T1 JOIN players AS T2 ON T1.player_id = T2.player_id
  Gold: SELECT SUM(ranking_points), T1.first_name FROM players AS T1 JOIN rankings AS T2 ON T1.player_id = T2.player_id GROUP BY T1.first_name
  Type: JOIN, GROUP_BY, AGGREGATION

[308] WRONG_COLUMNS | DB: wta_1 | EX: ✗
  Q   : find the number of players for each country
  Pred: SELECT country_code, COUNT(*) FROM players GROUP BY country_code
  Gold: SELECT COUNT(*), country_code FROM players GROUP BY country_code
  Type: GROUP_BY, AGGREGATION

[309] WRONG_COLUMNS | DB: wta_1 | EX: ✗
  Q   : How many players are from each country
  Pred: SELECT country_code, COUNT(*) FROM players GROUP BY country_code
  Gold: SELECT COUNT(*), country_code FROM players GROUP BY country_code
  Type: GROUP_BY, AGGREGATION

[310] WRONG_COLUMNS | DB: wta_1 | EX: ✗
  Q   : Find the total number of tours for each ranking date
  Pred: SELECT COUNT(*), ranking_date FROM rankings GROUP BY ranking_date
  Gold: SELECT SUM(tours), ranking_date FROM rankings GROUP BY ranking_date
  Type: GROUP_BY, AGGREGATION

[311] WRONG_COLUMNS | DB: wta_1 | EX: ✗
  Q   : How many total tours were there for each ranking date
  Pred: SELECT ranking_date, COUNT(*) FROM rankings GROUP BY ranking_date
  Gold: SELECT SUM(tours), ranking_date FROM rankings GROUP BY ranking_date
  Type: GROUP_BY, AGGREGATION

[312] WRONG_COLUMNS | DB: wta_1 | EX: ✗
  Q   : Find the name and rank of the 3 youngest winners across all matches
  Pred: SELECT winner_name, winner_rank FROM matches ORDER BY winner_age DESC LIMIT 3
  Gold: SELECT DISTINCT winner_name, winner_rank FROM matches ORDER BY winner_age LIMIT 3
  Type: ORDER_BY, LIMIT

[313] WRONG_COLUMNS | DB: wta_1 | EX: ✓
  Q   : What are the names and ranks of the three youngest winners across all matches
  Pred: SELECT winner_name, winner_rank FROM matches ORDER BY winner_age ASC LIMIT 3
  Gold: SELECT DISTINCT winner_name, winner_rank FROM matches ORDER BY winner_age LIMIT 3
  Type: ORDER_BY, LIMIT

[314] WRONG_TABLE | DB: wta_1 | EX: ✗
  Q   : How many different winners both participated in the WTA Championships and were left handed
  Pred: SELECT COUNT(DISTINCT winner_hand) FROM players WHERE winner_entry = 'WTA Championships' AND winner_hand = 'left'
  Gold: SELECT COUNT(DISTINCT winner_name) FROM matches WHERE tourney_name = 'WTA Championships' AND winner_hand = 'L'
  Type: AGGREGATION

[315] WRONG_TABLE | DB: wta_1 | EX: ✗
  Q   : Find the number of left handed winners who participated in the WTA Championships
  Pred: SELECT COUNT(*) FROM players WHERE winner_hand = 'left' AND winner_entry = 'WTA Championships'
  Gold: SELECT COUNT(DISTINCT winner_name) FROM matches WHERE tourney_name = 'WTA Championships' AND winner_hand = 'L'
  Type: AGGREGATION

[316] WRONG_TABLE | DB: wta_1 | EX: ✗
  Q   : Find the first name, country code and birth date of the winner who has the highest rank points in all matches
  Pred: SELECT T1.winner_name, T1.country_code, T1.birth_date FROM matches AS T1 JOIN rankings AS T2 ON T1.winner_id = T2.winner_id GROUP BY T1.winner_id ORDER BY COUNT(*) DESC LIMIT 1
  Gold: SELECT T1.first_name, T1.country_code, T1.birth_date FROM players AS T1 JOIN matches AS T2 ON T1.player_id = T2.winner_id ORDER BY T2.winner_rank_points DESC LIMIT 1
  Type: JOIN, ORDER_BY, LIMIT

[317] OTHER | DB: wta_1 | EX: ✗
  Q   : What is the first name, country code, and birth date of the player with the most winner rank points across all matches
  Pred: SELECT T1.first_name, T1.country_code, T1.birth_date FROM players AS T1 JOIN rankings AS T2 ON T1.player_id = T2.player_id GROUP BY T1.player_id ORDER BY COUNT(*) DESC LIMIT 1
  Gold: SELECT T1.first_name, T1.country_code, T1.birth_date FROM players AS T1 JOIN matches AS T2 ON T1.player_id = T2.winner_id ORDER BY T2.winner_rank_points DESC LIMIT 1
  Type: JOIN, ORDER_BY, LIMIT

[318] OTHER | DB: battle_death | EX: ✗
  Q   : How many ships ended up being 'Captured'
  Pred: SELECT COUNT(*) FROM ship WHERE result = 'Captured'
  Gold: SELECT COUNT(*) FROM ship WHERE disposition_of_ship = 'Captured'
  Type: AGGREGATION

[319] WRONG_COLUMNS | DB: battle_death | EX: ✗
  Q   : List the name, date and result of each battle
  Pred: SELECT name, date, result FROM battle
  Gold: SELECT name, date FROM battle
  Type: SIMPLE

[320] WRONG_COLUMNS | DB: battle_death | EX: ✗
  Q   : What is maximum and minimum death toll caused each time
  Pred: SELECT MAX(tonnage), MIN(tonnage), MIN(tonnage) FROM death
  Gold: SELECT MAX(killed), MIN(killed) FROM death
  Type: AGGREGATION

[321] WRONG_COLUMNS | DB: battle_death | EX: ✗
  Q   : What is the average number of injuries caused each time
  Pred: SELECT AVG(injured), COUNT(*) FROM death GROUP BY AVG(injured)
  Gold: SELECT AVG(injured) FROM death
  Type: AGGREGATION

[322] WRONG_COLUMNS | DB: battle_death | EX: ✗
  Q   : What are the death and injury situations caused by the ship with tonnage 't'
  Pred: SELECT T1.death, T1.injured FROM death AS T1 JOIN ship AS T2 ON T1.caused_by_ship_id = T2.id WHERE T2.tonnage = 't'
  Gold: SELECT T1.killed, T1.injured FROM death AS T1 JOIN ship AS t2 ON T1.caused_by_ship_id = T2.id WHERE T2.tonnage = 't'
  Type: JOIN

[323] OTHER | DB: battle_death | EX: ✓
  Q   : What are the name and results of the battles when the bulgarian commander is not 'Boril'
  Pred: SELECT name, result FROM battle WHERE bulgarian_commander > 'Boril'
  Gold: SELECT name, RESULT FROM battle WHERE bulgarian_commander <> 'Boril'
  Type: SIMPLE

[324] OTHER | DB: battle_death | EX: ✗
  Q   : What are the different ids and names of the battles that lost any 'Brig' type shipes
  Pred: SELECT DISTINCT T1.id, T1.name FROM battle AS T1 JOIN ship AS T2 ON T1.lost_in_battle = T2.id WHERE T2.ship_type = 'Brig'
  Gold: SELECT DISTINCT T1.id, T1.name FROM battle AS T1 JOIN ship AS T2 ON T1.id = T2.lost_in_battle WHERE T2.ship_type = 'Brig'
  Type: JOIN

[325] MISSING_JOIN | DB: battle_death | EX: ✗
  Q   : What are the ids and names of the battles that led to more than 10 people killed in total
  Pred: SELECT id, name FROM battle WHERE result = 10
  Gold: SELECT T1.id, T1.name FROM battle AS T1 JOIN ship AS T2 ON T1.id = T2.lost_in_battle JOIN death AS T3 ON T2.id = T3.caused_by_ship_id GROUP BY T1.id HAVING SUM(T3.killed) > 10
  Type: JOIN, GROUP_BY, HAVING, AGGREGATION

[326] WRONG_TABLE | DB: battle_death | EX: ✓
  Q   : What is the ship id and name that caused most total injuries
  Pred: SELECT T1.id, T1.name FROM ship AS T1 JOIN death AS T2 ON T1.id = T2.caused_by_ship_id GROUP BY T1.id ORDER BY COUNT(*) DESC LIMIT 1
  Gold: SELECT T2.id, T2.name FROM death AS T1 JOIN ship AS t2 ON T1.caused_by_ship_id = T2.id GROUP BY T2.id ORDER BY COUNT(*) DESC LIMIT 1
  Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, AGGREGATION

[327] WRONG_COLUMNS | DB: battle_death | EX: ✓
  Q   : What are the distinct battle names which are between bulgarian commander 'Kaloyan' and latin commander 'Baldwin I'
  Pred: SELECT DISTINCT name FROM battle WHERE bulgarian_commander = 'Kaloyan' INTERSECT SELECT DISTINCT name FROM battle WHERE latin_commander = 'Baldwin I'
  Gold: SELECT name FROM battle WHERE bulgarian_commander = 'Kaloyan' AND latin_commander = 'Baldwin I'
  Type: SIMPLE

[328] WRONG_COLUMNS | DB: battle_death | EX: ✗
  Q   : How many battles did not lose any ship with tonnage '225'
  Pred: SELECT COUNT(*) FROM battle WHERE NOT id IN (SELECT id FROM ship WHERE tonnage  225)
  Gold: SELECT COUNT(*) FROM battle WHERE NOT id IN (SELECT lost_in_battle FROM ship WHERE tonnage = '225')
  Type: NESTED, AGGREGATION

[329] MISSING_JOIN | DB: battle_death | EX: ✗
  Q   : List the name and date the battle that has lost the ship named 'Lettice' and the ship named 'HMS Atalanta'
  Pred: SELECT name, date FROM battle WHERE ship_type = 'Lettice' INTERSECT SELECT name, date FROM battle WHERE ship_type = 'HMS Atalanta'
  Gold: SELECT T1.name, T1.date FROM battle AS T1 JOIN ship AS T2 ON T1.id = T2.lost_in_battle WHERE T2.name = 'Lettice' INTERSECT SELECT T1.name, T1.date FROM battle AS T1 JOIN ship AS T2 ON T1.id = T2.lost_in_battle WHERE T2.name = 'HMS Atalanta'
  Type: JOIN

[330] WRONG_TABLE | DB: battle_death | EX: ✓
  Q   : Show names, results and bulgarian commanders of the battles with no ships lost in the 'English Channel'
  Pred: SELECT name, result, bulgarian_commander FROM battle WHERE NOT id IN (SELECT lost_in_battle FROM ship WHERE location = 'English Channel')
  Gold: SELECT name, RESULT, bulgarian_commander FROM battle EXCEPT SELECT T1.name, T1.result, T1.bulgarian_commander FROM battle AS T1 JOIN ship AS T2 ON T1.id = T2.lost_in_battle WHERE T2.location = 'English Channel'
  Type: JOIN

[331] WRONG_COLUMNS | DB: student_transcripts_tracking | EX: ✗
  Q   : what are all the addresses including line 1 and line 2
  Pred: SELECT address_id FROM addresses WHERE line_1 INTERSECT SELECT address_id FROM addresses WHERE line_2
  Gold: SELECT line_1, line_2 FROM addresses
  Type: SIMPLE

[332] EXTRA_JOIN | DB: student_transcripts_tracking | EX: ✓
  Q   : What is the first and second line for all addresses
  Pred: SELECT T1.line_1, T1.line_2 FROM addresses AS T1 JOIN addresses AS T2 ON T1.address_id = T2.address_id
  Gold: SELECT line_1, line_2 FROM addresses
  Type: SIMPLE

[333] OTHER | DB: student_transcripts_tracking | EX: ✓
  Q   : How is the math course described
  Pred: SELECT course_description FROM Courses WHERE course_name = "math"
  Gold: SELECT course_description FROM Courses WHERE course_name = 'math'
  Type: SIMPLE

[334] OTHER | DB: student_transcripts_tracking | EX: ✓
  Q   : What are the descriptions for all the math courses
  Pred: SELECT course_description FROM Courses WHERE course_name = "math"
  Gold: SELECT course_description FROM Courses WHERE course_name = 'math'
  Type: SIMPLE

[335] OTHER | DB: student_transcripts_tracking | EX: ✓
  Q   : What is the zip code of the address in the city Port Chelsea
  Pred: SELECT zip_postcode FROM addresses WHERE city = "Port Chelsea"
  Gold: SELECT zip_postcode FROM Addresses WHERE city = 'Port Chelsea'
  Type: SIMPLE

[336] OTHER | DB: student_transcripts_tracking | EX: ✓
  Q   : What is the zip code for Port Chelsea
  Pred: SELECT zip_postcode FROM addresses WHERE city = "Port Chelsea"
  Gold: SELECT zip_postcode FROM Addresses WHERE city = 'Port Chelsea'
  Type: SIMPLE

[337] WRONG_TABLE | DB: student_transcripts_tracking | EX: ✓
  Q   : Which department offers the most number of degrees? List department name and id
  Pred: SELECT T1.department_name, T1.department_id FROM departments AS T1 JOIN degree_programs AS T2 ON T1.department_id = T2.department_id GROUP BY T1.department_name ORDER BY COUNT(*) DESC LIMIT 1
  Gold: SELECT T2.department_name, T1.department_id FROM Degree_Programs AS T1 JOIN Departments AS T2 ON T1.department_id = T2.department_id GROUP BY T1.department_id ORDER BY COUNT(*) DESC LIMIT 1
  Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, AGGREGATION

[338] WRONG_TABLE | DB: student_transcripts_tracking | EX: ✓
  Q   : What is the name and id of the department with the most number of degrees
  Pred: SELECT T1.department_name, T1.department_id FROM departments AS T1 JOIN degree_programs AS T2 ON T1.department_id = T2.department_id GROUP BY T1.department_id ORDER BY COUNT(*) DESC LIMIT 1
  Gold: SELECT t2.department_name, t1.department_id FROM degree_programs AS t1 JOIN departments AS t2 ON t1.department_id = t2.department_id GROUP BY t1.department_id ORDER BY COUNT(*) DESC LIMIT 1
  Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, AGGREGATION

[339] WRONG_COLUMNS | DB: student_transcripts_tracking | EX: ✗
  Q   : How many different departments offer degrees
  Pred: SELECT COUNT(DISTINCT department_name) FROM degree_programs
  Gold: SELECT COUNT(DISTINCT department_id) FROM Degree_Programs
  Type: AGGREGATION

[340] WRONG_TABLE | DB: student_transcripts_tracking | EX: ✗
  Q   : How many different degrees are offered
  Pred: SELECT COUNT(DISTINCT degree_program_id) FROM degrees
  Gold: SELECT COUNT(DISTINCT degree_summary_name) FROM Degree_Programs
  Type: AGGREGATION

[341] OTHER | DB: student_transcripts_tracking | EX: ✓
  Q   : How many degrees does the engineering department offer
  Pred: SELECT COUNT(*) FROM departments AS T1 JOIN degree_programs AS T2 ON T1.department_id = T2.department_id WHERE T1.department_name = "engineering"
  Gold: SELECT COUNT(*) FROM Departments AS T1 JOIN Degree_Programs AS T2 ON T1.department_id = T2.department_id WHERE T1.department_name = 'engineer'
  Type: JOIN, AGGREGATION

[342] OTHER | DB: student_transcripts_tracking | EX: ✓
  Q   : How many degrees does the engineering department have
  Pred: SELECT COUNT(*) FROM departments AS T1 JOIN degree_programs AS T2 ON T1.department_id = T2.department_id WHERE T1.department_name = "engineering"
  Gold: SELECT COUNT(*) FROM Departments AS T1 JOIN Degree_Programs AS T2 ON T1.department_id = T2.department_id WHERE T1.department_name = 'engineer'
  Type: JOIN, AGGREGATION

[343] OTHER | DB: student_transcripts_tracking | EX: ✗
  Q   : What are the names and id of courses having at most 2 sections
  Pred: SELECT T1.course_name, T1.course_id FROM courses AS T1 JOIN sections AS T2 ON T1.course_id = T2.course_id GROUP BY T1.course_id HAVING COUNT(*) >= 2
  Gold: SELECT T1.course_name, T1.course_id FROM Courses AS T1 JOIN Sections AS T2 ON T1.course_id = T2.course_id GROUP BY T1.course_id HAVING COUNT(*) <= 2
  Type: JOIN, GROUP_BY, HAVING, AGGREGATION

[344] OTHER | DB: student_transcripts_tracking | EX: ✗
  Q   : What are the names and ids of every course with less than 2 sections
  Pred: SELECT T1.course_name, T1.course_id FROM Courses AS T1 JOIN Sections AS T2 ON T1.course_id = T2.course_id GROUP BY T1.course_id HAVING COUNT(*)  2
  Gold: SELECT T1.course_name, T1.course_id FROM Courses AS T1 JOIN Sections AS T2 ON T1.course_id = T2.course_id GROUP BY T1.course_id HAVING COUNT(*) <= 2
  Type: JOIN, GROUP_BY, HAVING, AGGREGATION

[345] OTHER | DB: student_transcripts_tracking | EX: ✗
  Q   : List the section_name in reversed lexicographical order
  Pred: SELECT section_name FROM sections ORDER BY section_name
  Gold: SELECT section_name FROM Sections ORDER BY section_name DESC
  Type: ORDER_BY

[346] OTHER | DB: student_transcripts_tracking | EX: ✗
  Q   : What are the names of the sections in reverse alphabetical order
  Pred: SELECT section_name FROM sections ORDER BY section_name
  Gold: SELECT section_name FROM Sections ORDER BY section_name DESC
  Type: ORDER_BY

[347] OTHER | DB: student_transcripts_tracking | EX: ✓
  Q   : What is the semester which most student registered in? Show both the name and the id
  Pred: SELECT T1.semester_name, T1.semester_id FROM semesters AS T1 JOIN student_enrolment AS T2 ON T1.semester_id = T2.semester_id GROUP BY T1.semester_name ORDER BY COUNT(*) DESC LIMIT 1
  Gold: SELECT T1.semester_name, T1.semester_id FROM Semesters AS T1 JOIN Student_Enrolment AS T2 ON T1.semester_id = T2.semester_id GROUP BY T1.semester_id ORDER BY COUNT(*) DESC LIMIT 1
  Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, AGGREGATION

[348] WRONG_TABLE | DB: student_transcripts_tracking | EX: ✗
  Q   : Who are enrolled in 2 degree programs in one semester? List the first name, middle name and last name and the id
  Pred: SELECT T1.first_name, T1.middle_name, T1.last_name, T1.student_id, T1.semester_id FROM student_enrolment AS T1 JOIN semesters AS T2 ON T1.semester_id = T2.semester_id GROUP BY T1.semester_id HAVING COUNT(*) = 2
  Gold: SELECT T1.first_name, T1.middle_name, T1.last_name, T1.student_id FROM Students AS T1 JOIN Student_Enrolment AS T2 ON T1.student_id = T2.student_id GROUP BY T1.student_id HAVING COUNT(*) = 2
  Type: JOIN, GROUP_BY, HAVING, AGGREGATION

[349] WRONG_TABLE | DB: student_transcripts_tracking | EX: ✗
  Q   : Who is enrolled in a Bachelor degree program? List the first name, middle name, last name
  Pred: SELECT first_name, middle_name, last_name FROM Student_Enrolment WHERE degree_program_id = "Bachelor"
  Gold: SELECT DISTINCT T1.first_name, T1.middle_name, T1.last_name FROM Students AS T1 JOIN Student_Enrolment AS T2 ON T1.student_id = T2.student_id JOIN Degree_Programs AS T3 ON T2.degree_program_id = T3.degree_program_id WHERE T3.degree_summary_name = 'Bachelor'
  Type: JOIN

[350] WRONG_TABLE | DB: student_transcripts_tracking | EX: ✗
  Q   : What are the first, middle, and last names for everybody enrolled in a Bachelors program
  Pred: SELECT first_name, middle_name, last_name FROM Student_Enrolment WHERE degree_program_id = "Bachelors"
  Gold: SELECT DISTINCT T1.first_name, T1.middle_name, T1.last_name FROM Students AS T1 JOIN Student_Enrolment AS T2 ON T1.student_id = T2.student_id JOIN Degree_Programs AS T3 ON T2.degree_program_id = T3.degree_program_id WHERE T3.degree_summary_name = 'Bachelor'
  Type: JOIN

[351] WRONG_TABLE | DB: student_transcripts_tracking | EX: ✗
  Q   : Find the kind of program which most number of students are enrolled in
  Pred: SELECT degree_program_id FROM student_enrolment GROUP BY degree_program_id ORDER BY COUNT(*) DESC LIMIT 1
  Gold: SELECT T1.degree_summary_name FROM Degree_Programs AS T1 JOIN Student_Enrolment AS T2 ON T1.degree_program_id = T2.degree_program_id GROUP BY T1.degree_summary_name ORDER BY COUNT(*) DESC LIMIT 1
  Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, AGGREGATION

[352] WRONG_TABLE | DB: student_transcripts_tracking | EX: ✗
  Q   : What is the degree summary name that has the most number of students enrolled
  Pred: SELECT degree_summary_name FROM student_enrolment GROUP BY degree_summary_name ORDER BY COUNT(*) DESC LIMIT 1
  Gold: SELECT T1.degree_summary_name FROM Degree_Programs AS T1 JOIN Student_Enrolment AS T2 ON T1.degree_program_id = T2.degree_program_id GROUP BY T1.degree_summary_name ORDER BY COUNT(*) DESC LIMIT 1
  Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, AGGREGATION

[353] WRONG_TABLE | DB: student_transcripts_tracking | EX: ✗
  Q   : Find the program which most number of students are enrolled in. List both the id and the summary
  Pred: SELECT T1.degree_program_id, T1.degree_summary_name FROM student_enrolment AS T1 JOIN degree_programs AS T2 ON T1.degree_program_id = T2.degree_program_id GROUP BY T1.degree_program_id ORDER BY COUNT(*) DESC LIMIT 1
  Gold: SELECT T1.degree_program_id, T1.degree_summary_name FROM Degree_Programs AS T1 JOIN Student_Enrolment AS T2 ON T1.degree_program_id = T2.degree_program_id GROUP BY T1.degree_program_id ORDER BY COUNT(*) DESC LIMIT 1
  Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, AGGREGATION

[354] WRONG_TABLE | DB: student_transcripts_tracking | EX: ✗
  Q   : What is the program id and the summary of the degree that has the most students enrolled
  Pred: SELECT degree_program_id, degree_summary_name FROM student_enrolment GROUP BY degree_program_id ORDER BY COUNT(*) DESC LIMIT 1
  Gold: SELECT T1.degree_program_id, T1.degree_summary_name FROM Degree_Programs AS T1 JOIN Student_Enrolment AS T2 ON T1.degree_program_id = T2.degree_program_id GROUP BY T1.degree_program_id ORDER BY COUNT(*) DESC LIMIT 1
  Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, AGGREGATION

[355] WRONG_TABLE | DB: student_transcripts_tracking | EX: ✗
  Q   : Which student has enrolled for the most times in any program? List the id, first name, middle name, last name, the number of enrollments and student id
  Pred: SELECT T1.student_id, T1.first_name, T1.mid_name, T1.last_name, COUNT(*) FROM Student_Enrolment AS T1 JOIN Students AS T2 ON T1.student_id = T2.student_id GROUP BY T1.student_id ORDER BY COUNT(*) DESC LIMIT 1
  Gold: SELECT T1.student_id, T1.first_name, T1.middle_name, T1.last_name, COUNT(*), T1.student_id FROM Students AS T1 JOIN Student_Enrolment AS T2 ON T1.student_id = T2.student_id GROUP BY T1.student_id ORDER BY COUNT(*) DESC LIMIT 1
  Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, AGGREGATION

[356] WRONG_TABLE | DB: student_transcripts_tracking | EX: ✗
  Q   : What is the first, middle, and last name, along with the id and number of enrollments, for the student who enrolled the most in any program
  Pred: SELECT T1.first_name, T1.midnight_name, T1.last_name, T1.student_id, COUNT(*) FROM Student_Enrolment AS T1 JOIN Students AS T2 ON T1.student_id = T2.student_id GROUP BY T1.student_id ORDER BY COUNT(*) DESC LIMIT 1
  Gold: SELECT T1.student_id, T1.first_name, T1.middle_name, T1.last_name, COUNT(*), T1.student_id FROM Students AS T1 JOIN Student_Enrolment AS T2 ON T1.student_id = T2.student_id GROUP BY T1.student_id ORDER BY COUNT(*) DESC LIMIT 1
  Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, AGGREGATION

[357] WRONG_TABLE | DB: student_transcripts_tracking | EX: ✗
  Q   : What is the name of the semester with no students enrolled
  Pred: SELECT T1.semester_name FROM semesters AS T1 JOIN student_enrolment AS T2 ON T1.semester_id = T2.semester_id GROUP BY T1.semester_name HAVING COUNT(*) >= 1
  Gold: SELECT semester_name FROM Semesters WHERE NOT semester_id IN (SELECT semester_id FROM Student_Enrolment)
  Type: NESTED

[358] WRONG_COLUMNS | DB: student_transcripts_tracking | EX: ✗
  Q   : What are all the course names of the courses which ever have students enrolled in
  Pred: SELECT T1.course_name FROM courses AS T1 JOIN student_enrolment_courses AS T2 ON T1.course_id = T2.course_id
  Gold: SELECT DISTINCT T1.course_name FROM Courses AS T1 JOIN Student_Enrolment_Courses AS T2 ON T1.course_id = T2.course_id
  Type: JOIN

[359] WRONG_COLUMNS | DB: student_transcripts_tracking | EX: ✗
  Q   : What are the names of all courses that have some students enrolled
  Pred: SELECT T1.course_name FROM courses AS T1 JOIN student_enrolment_courses AS T2 ON T1.course_id = T2.course_id
  Gold: SELECT DISTINCT T1.course_name FROM Courses AS T1 JOIN Student_Enrolment_Courses AS T2 ON T1.course_id = T2.course_id
  Type: JOIN

[360] WRONG_COLUMNS | DB: student_transcripts_tracking | EX: ✗
  Q   : Find the last name of the students who currently live in the state of North Carolina but have not registered in any degree program
  Pred: SELECT T1.last_name FROM students AS T1 JOIN student_enrolment AS T2 ON T1.student_id = T2.student_id WHERE T2.state_province_county = "North Carolina" EXCEPT SELECT T1.last_name FROM students AS T1 JOIN degree_programs AS T2 ON T1.degree_program_id = T2.degree_program_id
  Gold: SELECT T1.last_name FROM Students AS T1 JOIN Addresses AS T2 ON T1.current_address_id = T2.address_id WHERE T2.state_province_county = 'NorthCarolina' EXCEPT SELECT DISTINCT T3.last_name FROM Students AS T3 JOIN Student_Enrolment AS T4 ON T3.student_id = T4.student_id
  Type: JOIN

[361] WRONG_COLUMNS | DB: student_transcripts_tracking | EX: ✗
  Q   : What are the last name of the students who live in North Carolina but have not registered in any degree programs
  Pred: SELECT last_name FROM students WHERE city = "North Carolina" EXCEPT SELECT T1.last_name FROM students AS T1 JOIN student_enrolment AS T2 ON T1.student_id = T2.student_id JOIN degrees AS T3 ON T2.degree_program_id = T3.degree_program_id WHERE T3.state_province_county = "North Carolina"
  Gold: SELECT T1.last_name FROM Students AS T1 JOIN Addresses AS T2 ON T1.current_address_id = T2.address_id WHERE T2.state_province_county = 'NorthCarolina' EXCEPT SELECT DISTINCT T3.last_name FROM Students AS T3 JOIN Student_Enrolment AS T4 ON T3.student_id = T4.student_id
  Type: JOIN

[362] WRONG_TABLE | DB: student_transcripts_tracking | EX: ✓
  Q   : Show the date and id of the transcript with at least 2 course results
  Pred: SELECT T1.transcript_date, T1.transcript_id FROM transcripts AS T1 JOIN transcript_contents AS T2 ON T1.transcript_id = T2.transcript_id GROUP BY T1.transcript_id HAVING COUNT(*) >= 2
  Gold: SELECT T2.transcript_date, T1.transcript_id FROM Transcript_Contents AS T1 JOIN Transcripts AS T2 ON T1.transcript_id = T2.transcript_id GROUP BY T1.transcript_id HAVING COUNT(*) >= 2
  Type: JOIN, GROUP_BY, HAVING, AGGREGATION

[363] WRONG_TABLE | DB: student_transcripts_tracking | EX: ✗
  Q   : What is the date and id of the transcript with at least 2 courses listed
  Pred: SELECT T1.transcript_date, T1.transcript_id FROM transcripts AS T1 JOIN courses AS T2 ON T1.course_id = T2.course_id GROUP BY T1.course_id HAVING COUNT(*) >= 2
  Gold: SELECT T2.transcript_date, T1.transcript_id FROM Transcript_Contents AS T1 JOIN Transcripts AS T2 ON T1.transcript_id = T2.transcript_id GROUP BY T1.transcript_id HAVING COUNT(*) >= 2
  Type: JOIN, GROUP_BY, HAVING, AGGREGATION

[364] WRONG_TABLE | DB: student_transcripts_tracking | EX: ✗
  Q   : What is the phone number of the man with the first name Timmothy and the last name Ward
  Pred: SELECT cell_mobile_number FROM addresses WHERE first_name = "Timmothy" AND last_name = "Ward"
  Gold: SELECT cell_mobile_number FROM Students WHERE first_name = 'Timmothy' AND last_name = 'Ward'
  Type: SIMPLE

[365] OTHER | DB: student_transcripts_tracking | EX: ✗
  Q   : What is the mobile phone number of the student named Timmothy Ward
  Pred: SELECT cell_mobile_number FROM Students WHERE first_name = "Timmothy" AND last_name = "Ward"
  Gold: SELECT cell_mobile_number FROM students WHERE first_name = 'timmothy' AND last_name = 'ward'
  Type: SIMPLE

[366] MISSING_ORDER_BY | DB: student_transcripts_tracking | EX: ✗
  Q   : Who is the first student to register? List the first name, middle name and last name
  Pred: SELECT first_name, middle_name, last_name FROM Students GROUP BY date_first_registered
  Gold: SELECT first_name, middle_name, last_name FROM Students ORDER BY date_first_registered ASC LIMIT 1
  Type: ORDER_BY, LIMIT

[367] OTHER | DB: student_transcripts_tracking | EX: ✗
  Q   : What is the first, middle, and last name of the first student to register
  Pred: SELECT first_name, middle_name, last_name FROM students ORDER BY date_first_registered DESC LIMIT 1
  Gold: SELECT first_name, middle_name, last_name FROM Students ORDER BY date_first_registered ASC LIMIT 1
  Type: ORDER_BY, LIMIT

[368] OTHER | DB: student_transcripts_tracking | EX: ✗
  Q   : Who is the earliest graduate of the school? List the first name, middle name and last name
  Pred: SELECT first_name, middle_name, last_name FROM students ORDER BY date_first_registered DESC LIMIT 1
  Gold: SELECT first_name, middle_name, last_name FROM Students ORDER BY date_left ASC LIMIT 1
  Type: ORDER_BY, LIMIT

[369] OTHER | DB: student_transcripts_tracking | EX: ✗
  Q   : What is the first, middle, and last name of the earliest school graduate
  Pred: SELECT first_name, middle_name, last_name FROM students ORDER BY date_first_registered DESC LIMIT 1
  Gold: SELECT first_name, middle_name, last_name FROM Students ORDER BY date_left ASC LIMIT 1
  Type: ORDER_BY, LIMIT

[370] WRONG_TABLE | DB: student_transcripts_tracking | EX: ✗
  Q   : Whose permanent address is different from his or her current address? List his or her first name
  Pred: SELECT first_name FROM addresses WHERE permanent_address_id > 'current'
  Gold: SELECT first_name FROM Students WHERE current_address_id <> permanent_address_id
  Type: SIMPLE

[371] WRONG_COLUMNS | DB: student_transcripts_tracking | EX: ✗
  Q   : What is the first name of the student whose permanent address is different from his or her current one
  Pred: SELECT first_name FROM Students WHERE permanent_address_id > (SELECT permanent_address_id FROM Students)
  Gold: SELECT first_name FROM Students WHERE current_address_id <> permanent_address_id
  Type: SIMPLE

[372] WRONG_COLUMNS | DB: student_transcripts_tracking | EX: ✗
  Q   : Which address holds the most number of students currently? List the address id and all lines
  Pred: SELECT T1.address_id, T2.line_3 FROM addresses AS T1 JOIN students AS T2 ON T1.address_id = T2.address_id GROUP BY T1.address_id ORDER BY COUNT(*) DESC LIMIT 1
  Gold: SELECT T1.address_id, T1.line_1, T1.line_2 FROM Addresses AS T1 JOIN Students AS T2 ON T1.address_id = T2.current_address_id GROUP BY T1.address_id ORDER BY COUNT(*) DESC LIMIT 1
  Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, AGGREGATION

[373] OTHER | DB: student_transcripts_tracking | EX: ✗
  Q   : What is the id, line 1, and line 2 of the address with the most students
  Pred: SELECT T1.address_id, T1.line_1, T1.line_2 FROM addresses AS T1 JOIN students AS T2 ON T1.address_id = T2.address_id GROUP BY T1.address_id ORDER BY COUNT(*) DESC LIMIT 1
  Gold: SELECT T1.address_id, T1.line_1, T1.line_2 FROM Addresses AS T1 JOIN Students AS T2 ON T1.address_id = T2.current_address_id GROUP BY T1.address_id ORDER BY COUNT(*) DESC LIMIT 1
  Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, AGGREGATION

[374] MISSING_ORDER_BY | DB: student_transcripts_tracking | EX: ✗
  Q   : When is the first transcript released? List the date and details
  Pred: SELECT date_first_registered, other_details FROM transcripts
  Gold: SELECT transcript_date, other_details FROM Transcripts ORDER BY transcript_date ASC LIMIT 1
  Type: ORDER_BY, LIMIT

[375] WRONG_COLUMNS | DB: student_transcripts_tracking | EX: ✗
  Q   : What is the earliest date of a transcript release, and what details can you tell me
  Pred: SELECT date_first_registered, other_details FROM transcripts GROUP BY date_date ORDER BY COUNT(*) DESC LIMIT 1
  Gold: SELECT transcript_date, other_details FROM Transcripts ORDER BY transcript_date ASC LIMIT 1
  Type: ORDER_BY, LIMIT

[376] WRONG_COLUMNS | DB: student_transcripts_tracking | EX: ✗
  Q   : What is the last transcript release date
  Pred: SELECT date_left FROM transcripts ORDER BY date_left DESC LIMIT 1
  Gold: SELECT transcript_date FROM Transcripts ORDER BY transcript_date DESC LIMIT 1
  Type: ORDER_BY, LIMIT

[377] EXTRA_JOIN | DB: student_transcripts_tracking | EX: ✓
  Q   : When was the last transcript released
  Pred: SELECT T1.transcript_date FROM transcripts AS T1 JOIN transcripts AS T2 ON T1.transcript_id = T2.transcript_id GROUP BY T1.transcript_date ORDER BY COUNT(*) DESC LIMIT 1
  Gold: SELECT transcript_date FROM Transcripts ORDER BY transcript_date DESC LIMIT 1
  Type: ORDER_BY, LIMIT

[378] WRONG_TABLE | DB: student_transcripts_tracking | EX: ✗
  Q   : How many times at most can a course enrollment result show in different transcripts? Also show the course enrollment id
  Pred: SELECT COUNT(*), T1.course_id FROM transcripts AS T1 JOIN student_enrolment_courses AS T2 ON T1.course_id = T2.course_id GROUP BY T1.course_id
  Gold: SELECT COUNT(*), student_course_id FROM Transcript_Contents GROUP BY student_course_id ORDER BY COUNT(*) DESC LIMIT 1
  Type: GROUP_BY, ORDER_BY, LIMIT, AGGREGATION

[379] WRONG_TABLE | DB: student_transcripts_tracking | EX: ✗
  Q   : What is the maximum number of times that a course shows up in different transcripts and what is that course's enrollment id
  Pred: SELECT MAX(T1.transcript_id), T1.student_enrolment_id FROM transcripts AS T1 JOIN student_enrolment_courses AS T2 ON T1.transcript_id = T2.transcript_id GROUP BY T1.transcript_id
  Gold: SELECT COUNT(*), student_course_id FROM Transcript_Contents GROUP BY student_course_id ORDER BY COUNT(*) DESC LIMIT 1
  Type: GROUP_BY, ORDER_BY, LIMIT, AGGREGATION

[380] WRONG_TABLE | DB: student_transcripts_tracking | EX: ✗
  Q   : Show the date of the transcript which shows the least number of results, also list the id
  Pred: SELECT transcript_date, transcript_id FROM transcripts ORDER BY transcript_date LIMIT 1
  Gold: SELECT T2.transcript_date, T1.transcript_id FROM Transcript_Contents AS T1 JOIN Transcripts AS T2 ON T1.transcript_id = T2.transcript_id GROUP BY T1.transcript_id ORDER BY COUNT(*) ASC LIMIT 1
  Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, AGGREGATION

[381] WRONG_TABLE | DB: student_transcripts_tracking | EX: ✗
  Q   : What is the date and id of the transcript with the least number of results
  Pred: SELECT transcript_date, transcript_id FROM transcripts ORDER BY transcript_date LIMIT 1
  Gold: SELECT T2.transcript_date, T1.transcript_id FROM Transcript_Contents AS T1 JOIN Transcripts AS T2 ON T1.transcript_id = T2.transcript_id GROUP BY T1.transcript_id ORDER BY COUNT(*) ASC LIMIT 1
  Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, AGGREGATION

[382] WRONG_TABLE | DB: student_transcripts_tracking | EX: ✗
  Q   : Find the semester when both Master students and Bachelor students got enrolled in
  Pred: SELECT T1.semester_name FROM semesters AS T1 JOIN student_enrolment AS T2 ON T1.semester_id = T2.semester_id WHERE T2.semester_name = "Master" INTERSECT SELECT T1.semester_name FROM semesters AS T1 JOIN student_enrolment AS T2 ON T1.semester_id = T2.semester_id WHERE T2.semester_id
  Gold: SELECT DISTINCT T2.semester_id FROM Degree_Programs AS T1 JOIN Student_Enrolment AS T2 ON T1.degree_program_id = T2.degree_program_id WHERE degree_summary_name = 'Master' INTERSECT SELECT DISTINCT T2.semester_id FROM Degree_Programs AS T1 JOIN Student_Enrolment AS T2 ON T1.degree_program_id = T2.degree_program_id WHERE degree_summary_name = 'Bachelor'
  Type: JOIN

[383] WRONG_TABLE | DB: student_transcripts_tracking | EX: ✗
  Q   : What is the id of the semester that had both Masters and Bachelors students enrolled
  Pred: SELECT semester_id FROM student_enrolment WHERE semester_name = "Masters" INTERSECT SELECT semester_id FROM student_enrolment WHERE semester_name = "Bachelors"
  Gold: SELECT DISTINCT T2.semester_id FROM Degree_Programs AS T1 JOIN Student_Enrolment AS T2 ON T1.degree_program_id = T2.degree_program_id WHERE degree_summary_name = 'Master' INTERSECT SELECT DISTINCT T2.semester_id FROM Degree_Programs AS T1 JOIN Student_Enrolment AS T2 ON T1.degree_program_id = T2.degree_program_id WHERE degree_summary_name = 'Bachelor'
  Type: JOIN

[384] WRONG_TABLE | DB: student_transcripts_tracking | EX: ✗
  Q   : How many different addresses do the students currently live
  Pred: SELECT COUNT(DISTINCT current_address_id) FROM addresses
  Gold: SELECT COUNT(DISTINCT current_address_id) FROM Students
  Type: AGGREGATION

[385] WRONG_TABLE | DB: student_transcripts_tracking | EX: ✗
  Q   : What are the different addresses that have students living there
  Pred: SELECT DISTINCT address_id FROM addresses
  Gold: SELECT COUNT(DISTINCT current_address_id) FROM Students
  Type: AGGREGATION

[386] WRONG_COLUMNS | DB: student_transcripts_tracking | EX: ✗
  Q   : List all the student details in reversed lexicographical order
  Pred: SELECT Other_Students FROM Students ORDER BY Other_Students
  Gold: SELECT other_student_details FROM Students ORDER BY other_student_details DESC
  Type: ORDER_BY

[387] OTHER | DB: student_transcripts_tracking | EX: ✗
  Q   : What other details can you tell me about students in reverse alphabetical order
  Pred: SELECT other_student_details FROM students ORDER BY other_student_details
  Gold: SELECT other_student_details FROM Students ORDER BY other_student_details DESC
  Type: ORDER_BY

[388] OTHER | DB: student_transcripts_tracking | EX: ✗
  Q   : Describe the section h
  Pred: SELECT section_description FROM sections WHERE section_name = "H"
  Gold: SELECT section_description FROM Sections WHERE section_name = 'h'
  Type: SIMPLE

[389] OTHER | DB: student_transcripts_tracking | EX: ✓
  Q   : What is the description for the section named h
  Pred: SELECT section_description FROM sections WHERE section_name = "h"
  Gold: SELECT section_description FROM Sections WHERE section_name = 'h'
  Type: SIMPLE

[390] MISSING_JOIN | DB: student_transcripts_tracking | EX: ✓
  Q   : Find the first name of the students who permanently live in the country Haiti or have the cell phone number 09700166582
  Pred: SELECT first_name FROM Students WHERE permanent_address_id = 'Haiti' OR cell_mobile_number = '09700166582'
  Gold: SELECT t1.first_name FROM students AS t1 JOIN addresses AS t2 ON t1.permanent_address_id = t2.address_id WHERE t2.country = 'haiti' OR t1.cell_mobile_number = '09700166582'
  Type: JOIN

[391] MISSING_JOIN | DB: student_transcripts_tracking | EX: ✗
  Q   : What are the first names of the students who live in Haiti permanently or have the cell phone number 09700166582
  Pred: SELECT first_name FROM Students WHERE address = "Haiti" OR cell_mobile_number = "09700166582"
  Gold: SELECT t1.first_name FROM students AS t1 JOIN addresses AS t2 ON t1.permanent_address_id = t2.address_id WHERE t2.country = 'haiti' OR t1.cell_mobile_number = '09700166582'
  Type: JOIN

[392] WRONG_COLUMNS | DB: tvshow | EX: ✗
  Q   : List all cartoon directed by "Ben Jones"
  Pred: SELECT directed_by FROM cartoon WHERE directed_by = "Ben Jones"
  Gold: SELECT Title FROM Cartoon WHERE Directed_by = "Ben Jones"
  Type: SIMPLE

[393] OTHER | DB: tvshow | EX: ✗
  Q   : What is the number of cartoones written by Joseph Kuhr
  Pred: SELECT COUNT(*) FROM cartoon WHERE written_by = "Joseph" AND written_by = "Kuhr"
  Gold: SELECT COUNT(*) FROM Cartoon WHERE Written_by = "Joseph Kuhr"
  Type: AGGREGATION

[394] OTHER | DB: tvshow | EX: ✗
  Q   : What is the name and directors of all the cartoons that are ordered by air date
  Pred: SELECT title, directed_by FROM cartoon ORDER BY air_date
  Gold: SELECT title, Directed_by FROM Cartoon ORDER BY Original_air_date
  Type: ORDER_BY

[395] WRONG_COLUMNS | DB: tvshow | EX: ✗
  Q   : List the number of different series names and contents in the TV Channel table
  Pred: SELECT COUNT(DISTINCT series_name), content FROM tv_channel
  Gold: SELECT COUNT(DISTINCT series_name), COUNT(DISTINCT content) FROM TV_Channel
  Type: AGGREGATION

[396] OTHER | DB: tvshow | EX: ✗
  Q   : How many TV Channel using language English
  Pred: SELECT COUNT(*) FROM tv_channel WHERE language = 'english'
  Gold: SELECT COUNT(*) FROM TV_Channel WHERE LANGUAGE = "English"
  Type: AGGREGATION

[397] OTHER | DB: tvshow | EX: ✗
  Q   : How many TV Channels use the English language
  Pred: SELECT COUNT(*) FROM tv_channel WHERE language = 'english'
  Gold: SELECT COUNT(*) FROM TV_Channel WHERE LANGUAGE = "English"
  Type: AGGREGATION

[398] OTHER | DB: tvshow | EX: ✗
  Q   : What is the series name of the TV Channel that shows the cartoon "The Rise of the Blue Beetle"
  Pred: SELECT T1.series_name FROM tv_channel AS T1 JOIN cartoon AS T2 ON T1.id = T2.channel WHERE T2.title = "The Rise of the Blue Beetle"
  Gold: SELECT T1.series_name FROM TV_Channel AS T1 JOIN Cartoon AS T2 ON T1.id = T2.Channel WHERE T2.Title = "The Rise of the Blue Beetle!"
  Type: JOIN

[399] WRONG_TABLE | DB: tvshow | EX: ✗
  Q   : List the title of all Cartoons showed on TV Channel with series name "Sky Radio"
  Pred: SELECT T1.title FROM cartoon AS T1 JOIN tv_series AS T2 ON T1.channel = T2.id WHERE T2.series_name = "Sky Radio"
  Gold: SELECT T2.Title FROM TV_Channel AS T1 JOIN Cartoon AS T2 ON T1.id = T2.Channel WHERE T1.series_name = "Sky Radio"
  Type: JOIN

[400] WRONG_TABLE | DB: tvshow | EX: ✗
  Q   : What is the title of all the cartools that are on the TV Channel with the series name "Sky Radio"
  Pred: SELECT T1.title FROM cartoon AS T1 JOIN tv_series AS T2 ON T1.id = T2.channel WHERE T2.series_name = "Sky Radio"
  Gold: SELECT T2.Title FROM TV_Channel AS T1 JOIN Cartoon AS T2 ON T1.id = T2.Channel WHERE T1.series_name = "Sky Radio"
  Type: JOIN

[401] EXTRA_JOIN | DB: tvshow | EX: ✗
  Q   : List top 3 highest Rating TV series. List the TV series's Episode and Rating
  Pred: SELECT T1.episode, T1.rating FROM tv_series AS T1 JOIN tv_series AS T2 ON T1.id = T2.channel GROUP BY T1.id ORDER BY COUNT(*) DESC LIMIT 3
  Gold: SELECT Episode, Rating FROM TV_series ORDER BY Rating DESC LIMIT 3
  Type: ORDER_BY, LIMIT

[402] OTHER | DB: tvshow | EX: ✗
  Q   : What are 3 most highly rated episodes in the TV series table and what were those ratings
  Pred: SELECT episode, rating FROM tv_series GROUP BY episode ORDER BY COUNT(*) DESC LIMIT 3
  Gold: SELECT Episode, Rating FROM TV_series ORDER BY Rating DESC LIMIT 3
  Type: ORDER_BY, LIMIT

[403] WRONG_COLUMNS | DB: tvshow | EX: ✗
  Q   : What is minimum and maximum share of TV series
  Pred: SELECT MIN(share), MAX(share) FROM tv_series
  Gold: SELECT MAX(SHARE), MIN(SHARE) FROM TV_series
  Type: AGGREGATION

[404] WRONG_TABLE | DB: tvshow | EX: ✗
  Q   : What is the TV Channel of TV series with Episode "A Love of a Lifetime"? List the TV Channel's series name
  Pred: SELECT T2.series_name FROM tv_series AS T1 JOIN cartoon AS T2 ON T1.id = T2.channel WHERE T1.episode = "A Love of a Lifetime"
  Gold: SELECT T1.series_name FROM TV_Channel AS T1 JOIN TV_series AS T2 ON T1.id = T2.Channel WHERE T2.Episode = "A Love of a Lifetime"
  Type: JOIN

[405] WRONG_TABLE | DB: tvshow | EX: ✗
  Q   : What is the name of the series that has the episode "A Love of a Lifetime"
  Pred: SELECT series_name FROM tv_series WHERE episode = "A Love of a Lifetime"
  Gold: SELECT T1.series_name FROM TV_Channel AS T1 JOIN TV_series AS T2 ON T1.id = T2.Channel WHERE T2.Episode = "A Love of a Lifetime"
  Type: JOIN

[406] WRONG_TABLE | DB: tvshow | EX: ✗
  Q   : List the Episode of all TV series showed on TV Channel with series name "Sky Radio"
  Pred: SELECT Episode FROM tv_series WHERE Channel = "Sky Radio"
  Gold: SELECT T2.Episode FROM TV_Channel AS T1 JOIN TV_series AS T2 ON T1.id = T2.Channel WHERE T1.series_name = "Sky Radio"
  Type: JOIN

[407] WRONG_TABLE | DB: tvshow | EX: ✗
  Q   : What is the episode for the TV series named "Sky Radio"
  Pred: SELECT episode FROM tv_series WHERE series_name = "Sky Radio"
  Gold: SELECT T2.Episode FROM TV_Channel AS T1 JOIN TV_series AS T2 ON T1.id = T2.Channel WHERE T1.series_name = "Sky Radio"
  Type: JOIN

[408] OTHER | DB: tvshow | EX: ✗
  Q   : Find the package choice and series name of the TV channel that has high definition TV
  Pred: SELECT package_option, series_name FROM tv_channel WHERE hight_definition_tv = 'High'
  Gold: SELECT package_option, series_name FROM TV_Channel WHERE hight_definition_TV = "yes"
  Type: SIMPLE

[409] OTHER | DB: tvshow | EX: ✓
  Q   : What are the package options and the name of the series for the TV Channel that supports high definition TV
  Pred: SELECT package_option, series_name FROM tv_channel WHERE hight_definition_tv = 'yes'
  Gold: SELECT package_option, series_name FROM TV_Channel WHERE hight_definition_TV = "yes"
  Type: SIMPLE

[410] MISSING_JOIN | DB: tvshow | EX: ✗
  Q   : which countries' tv channels are playing some cartoon written by Todd Casey
  Pred: SELECT country FROM tv_channel WHERE written_by = 'Todd Casey'
  Gold: SELECT T1.country FROM TV_Channel AS T1 JOIN cartoon AS T2 ON T1.id = T2.Channel WHERE T2.written_by = 'Todd Casey'
  Type: JOIN

[411] WRONG_TABLE | DB: tvshow | EX: ✗
  Q   : What are the countries that have cartoons on TV that were written by Todd Casey
  Pred: SELECT country FROM cartoon WHERE written_by = 'Todd Casey'
  Gold: SELECT T1.country FROM TV_Channel AS T1 JOIN cartoon AS T2 ON T1.id = T2.Channel WHERE T2.written_by = 'Todd Casey'
  Type: JOIN

[412] WRONG_TABLE | DB: tvshow | EX: ✗
  Q   : which countries' tv channels are not playing any cartoon written by Todd Casey
  Pred: SELECT country FROM tv_channel WHERE NOT id IN (SELECT country FROM cartoon WHERE written_by = 'Todd Casey')
  Gold: SELECT country FROM TV_Channel EXCEPT SELECT T1.country FROM TV_Channel AS T1 JOIN cartoon AS T2 ON T1.id = T2.Channel WHERE T2.written_by = 'Todd Casey'
  Type: JOIN

[413] WRONG_TABLE | DB: tvshow | EX: ✗
  Q   : What are the countries that are not playing cartoons written by Todd Casey
  Pred: SELECT country FROM tv_channel WHERE NOT id IN (SELECT country FROM cartoon WHERE written_by = "Todd Casey")
  Gold: SELECT country FROM TV_Channel EXCEPT SELECT T1.country FROM TV_Channel AS T1 JOIN cartoon AS T2 ON T1.id = T2.Channel WHERE T2.written_by = 'Todd Casey'
  Type: JOIN

[414] OTHER | DB: tvshow | EX: ✗
  Q   : Find the series name and country of the tv channel that is playing some cartoons directed by Ben Jones and Michael Chang
  Pred: SELECT T1.series_name, T1.country FROM tv_channel AS T1 JOIN cartoon AS T2 ON T1.id = T2.channel WHERE T2.directed_by = 'Ben Jones' AND T2.directed_by = 'Michael Chang'
  Gold: SELECT T1.series_name, T1.country FROM TV_Channel AS T1 JOIN cartoon AS T2 ON T1.id = T2.Channel WHERE T2.directed_by = 'Michael Chang' INTERSECT SELECT T1.series_name, T1.country FROM TV_Channel AS T1 JOIN cartoon AS T2 ON T1.id = T2.Channel WHERE T2.directed_by = 'Ben Jones'
  Type: JOIN

[415] OTHER | DB: tvshow | EX: ✓
  Q   : What is the series name and country of all TV channels that are playing cartoons directed by Ben Jones and cartoons directed by Michael Chang
  Pred: SELECT T1.series_name, T1.country FROM tv_channel AS T1 JOIN cartoon AS T2 ON T1.id = T2.channel WHERE T2.directed_by = 'Ben Jones' INTERSECT SELECT T1.series_name, T1.country FROM tv_channel AS T1 JOIN cartoon AS T2 ON T1.id = T2.channel WHERE T2.directed_by = 'Michael Chang'
  Gold: SELECT T1.series_name, T1.country FROM TV_Channel AS T1 JOIN cartoon AS T2 ON T1.id = T2.Channel WHERE T2.directed_by = 'Michael Chang' INTERSECT SELECT T1.series_name, T1.country FROM TV_Channel AS T1 JOIN cartoon AS T2 ON T1.id = T2.Channel WHERE T2.directed_by = 'Ben Jones'
  Type: JOIN

[416] OTHER | DB: tvshow | EX: ✗
  Q   : find the pixel aspect ratio and nation of the tv channels that do not use English
  Pred: SELECT pixel_aspect_ratio_par, country FROM tv_channel WHERE language > 'english'
  Gold: SELECT Pixel_aspect_ratio_PAR, country FROM tv_channel WHERE LANGUAGE <> 'English'
  Type: SIMPLE

[417] OTHER | DB: tvshow | EX: ✗
  Q   : What is the pixel aspect ratio and country of origin for all TV channels that do not use English
  Pred: SELECT pixel_aspect_ratio_par, country FROM tv_channel WHERE language > 'english'
  Gold: SELECT Pixel_aspect_ratio_PAR, country FROM tv_channel WHERE LANGUAGE <> 'English'
  Type: SIMPLE

[418] OTHER | DB: tvshow | EX: ✗
  Q   : find id of the tv channels that from the countries where have more than two tv channels
  Pred: SELECT id FROM tv_channel WHERE country = "U.S." GROUP BY country HAVING COUNT(*) > 2
  Gold: SELECT id FROM tv_channel GROUP BY country HAVING COUNT(*) > 2
  Type: GROUP_BY, HAVING, AGGREGATION

[419] OTHER | DB: tvshow | EX: ✗
  Q   : What are the ids of all tv channels that have more than 2 TV channels
  Pred: SELECT id FROM tv_channel GROUP BY id HAVING COUNT(*) > 2
  Gold: SELECT id FROM tv_channel GROUP BY country HAVING COUNT(*) > 2
  Type: GROUP_BY, HAVING, AGGREGATION

[420] WRONG_TABLE | DB: tvshow | EX: ✗
  Q   : find the id of tv channels that do not play any cartoon directed by Ben Jones
  Pred: SELECT tv_channel FROM cartoon EXCEPT SELECT tv_channel FROM cartoon WHERE directed_by = 'Ben Jones'
  Gold: SELECT id FROM TV_Channel EXCEPT SELECT channel FROM cartoon WHERE directed_by = 'Ben Jones'
  Type: SIMPLE

[421] WRONG_TABLE | DB: tvshow | EX: ✗
  Q   : What are the ids of the TV channels that do not have any cartoons directed by Ben Jones
  Pred: SELECT tv_channel FROM cartoon EXCEPT SELECT tv_channel FROM cartoon WHERE directed_by = 'Ben Jones'
  Gold: SELECT id FROM TV_Channel EXCEPT SELECT channel FROM cartoon WHERE directed_by = 'Ben Jones'
  Type: SIMPLE

[422] WRONG_COLUMNS | DB: tvshow | EX: ✗
  Q   : find the package option of the tv channel that do not have any cartoon directed by Ben Jones
  Pred: SELECT package_option FROM tv_channel WHERE NOT id IN (SELECT id FROM cartoon WHERE directed_by = "Ben Jones")
  Gold: SELECT package_option FROM TV_Channel WHERE NOT id IN (SELECT channel FROM cartoon WHERE directed_by = 'Ben Jones')
  Type: NESTED

[423] OTHER | DB: poker_player | EX: ✗
  Q   : What is the maximum number of final tables made among poker players with earnings less than 200000
  Pred: SELECT MAX(Final_Table_Made) FROM poker_player WHERE earnings  200000
  Gold: SELECT MAX(Final_Table_Made) FROM poker_player WHERE Earnings < 200000
  Type: AGGREGATION

[424] OTHER | DB: poker_player | EX: ✗
  Q   : Return the maximum final tables made across all poker players who have earnings below 200000
  Pred: SELECT MAX(Final_Table_Made) FROM poker_player WHERE earnings  200000
  Gold: SELECT MAX(Final_Table_Made) FROM poker_player WHERE Earnings < 200000
  Type: AGGREGATION

[425] MISSING_JOIN | DB: poker_player | EX: ✗
  Q   : What are the names of poker players
  Pred: SELECT Name FROM people
  Gold: SELECT T1.Name FROM people AS T1 JOIN poker_player AS T2 ON T1.People_ID = T2.People_ID
  Type: JOIN

[426] WRONG_TABLE | DB: poker_player | EX: ✗
  Q   : What are the names of poker players whose earnings is higher than 300000
  Pred: SELECT Name FROM poker_player WHERE Earnings > 300000
  Gold: SELECT T1.Name FROM people AS T1 JOIN poker_player AS T2 ON T1.People_ID = T2.People_ID WHERE T2.Earnings > 300000
  Type: JOIN

[427] MISSING_JOIN | DB: poker_player | EX: ✗
  Q   : List the names of poker players ordered by the final tables made in ascending order
  Pred: SELECT Name FROM people ORDER BY Final_Table_Made ASC
  Gold: SELECT T1.Name FROM people AS T1 JOIN poker_player AS T2 ON T1.People_ID = T2.People_ID ORDER BY T2.Final_Table_Made
  Type: JOIN, ORDER_BY

[428] MISSING_JOIN | DB: poker_player | EX: ✗
  Q   : What are the names of poker players, ordered ascending by the number of final tables they have made
  Pred: SELECT Name FROM people ORDER BY Final_Table_Made ASC
  Gold: SELECT T1.Name FROM people AS T1 JOIN poker_player AS T2 ON T1.People_ID = T2.People_ID ORDER BY T2.Final_Table_Made
  Type: JOIN, ORDER_BY

[429] WRONG_TABLE | DB: poker_player | EX: ✗
  Q   : What is the birth date of the poker player with the lowest earnings
  Pred: SELECT Birth_Date FROM poker_player ORDER BY Earnings LIMIT 1
  Gold: SELECT T1.Birth_Date FROM people AS T1 JOIN poker_player AS T2 ON T1.People_ID = T2.People_ID ORDER BY T2.Earnings ASC LIMIT 1
  Type: JOIN, ORDER_BY, LIMIT

[430] WRONG_TABLE | DB: poker_player | EX: ✗
  Q   : Return the birth date of the poker player with the lowest earnings
  Pred: SELECT Birth_Date FROM poker_player ORDER BY Earnings LIMIT 1
  Gold: SELECT T1.Birth_Date FROM people AS T1 JOIN poker_player AS T2 ON T1.People_ID = T2.People_ID ORDER BY T2.Earnings ASC LIMIT 1
  Type: JOIN, ORDER_BY, LIMIT

[431] MISSING_JOIN | DB: poker_player | EX: ✗
  Q   : What is the money rank of the tallest poker player
  Pred: SELECT Money_Rank FROM people ORDER BY Height DESC LIMIT 1
  Gold: SELECT T2.Money_Rank FROM people AS T1 JOIN poker_player AS T2 ON T1.People_ID = T2.People_ID ORDER BY T1.Height DESC LIMIT 1
  Type: JOIN, ORDER_BY, LIMIT

[432] WRONG_TABLE | DB: poker_player | EX: ✗
  Q   : Return the money rank of the poker player with the greatest height
  Pred: SELECT Money_Rank FROM poker_player ORDER BY Height DESC LIMIT 1
  Gold: SELECT T2.Money_Rank FROM people AS T1 JOIN poker_player AS T2 ON T1.People_ID = T2.People_ID ORDER BY T1.Height DESC LIMIT 1
  Type: JOIN, ORDER_BY, LIMIT

[433] WRONG_TABLE | DB: poker_player | EX: ✗
  Q   : What is the average earnings of poker players with height higher than 200
  Pred: SELECT AVG(Earnings) FROM poker_player WHERE Height > 200
  Gold: SELECT AVG(T2.Earnings) FROM people AS T1 JOIN poker_player AS T2 ON T1.People_ID = T2.People_ID WHERE T1.Height > 200
  Type: JOIN, AGGREGATION

[434] WRONG_TABLE | DB: poker_player | EX: ✗
  Q   : Give average earnings of poker players who are taller than 200
  Pred: SELECT AVG(Earnings) FROM poker_player WHERE Height > 200
  Gold: SELECT AVG(T2.Earnings) FROM people AS T1 JOIN poker_player AS T2 ON T1.People_ID = T2.People_ID WHERE T1.Height > 200
  Type: JOIN, AGGREGATION

[435] WRONG_TABLE | DB: poker_player | EX: ✗
  Q   : What are the names of poker players in descending order of earnings
  Pred: SELECT Name FROM poker_player ORDER BY Earnings DESC
  Gold: SELECT T1.Name FROM people AS T1 JOIN poker_player AS T2 ON T1.People_ID = T2.People_ID ORDER BY T2.Earnings DESC
  Type: JOIN, ORDER_BY

[436] WRONG_TABLE | DB: poker_player | EX: ✗
  Q   : Return the names of poker players sorted by their earnings descending
  Pred: SELECT Name FROM poker_player ORDER BY Earnings DESC
  Gold: SELECT T1.Name FROM people AS T1 JOIN poker_player AS T2 ON T1.People_ID = T2.People_ID ORDER BY T2.Earnings DESC
  Type: JOIN, ORDER_BY

[437] OTHER | DB: poker_player | EX: ✓
  Q   : What are the names and birth dates of people, ordered by their names in alphabetical order
  Pred: SELECT Name, Birth_Date FROM people ORDER BY Name
  Gold: SELECT Name, Birth_Date FROM people ORDER BY Name ASC
  Type: ORDER_BY

[438] OTHER | DB: poker_player | EX: ✗
  Q   : Show names of people whose nationality is not "Russia"
  Pred: SELECT Name FROM people WHERE Nationality > "Russia"
  Gold: SELECT Name FROM people WHERE Nationality <> "Russia"
  Type: SIMPLE

[439] OTHER | DB: poker_player | EX: ✗
  Q   : What are the names of people who are not from Russia
  Pred: SELECT Name FROM people WHERE Nationality > 'Russia'
  Gold: SELECT Name FROM people WHERE Nationality <> "Russia"
  Type: SIMPLE

[440] WRONG_COLUMNS | DB: voter_1 | EX: ✓
  Q   : What is last date created of votes from the state 'CA'
  Pred: SELECT Created FROM votes WHERE state = 'CA'
  Gold: SELECT MAX(created) FROM votes WHERE state = 'CA'
  Type: AGGREGATION

[441] EXTRA_JOIN | DB: voter_1 | EX: ✗
  Q   : What are the names of the contestants whose names are not 'Jessie Alloway'
  Pred: SELECT T1.contestant_name FROM contestants AS T1 JOIN votes AS T2 ON T1.contestant_number = T2.contestant_number WHERE T2.contestant_name > "Jessie Alloway"
  Gold: SELECT contestant_name FROM contestants WHERE contestant_name <> 'Jessie Alloway'
  Type: SIMPLE

[442] MISSING_JOIN | DB: voter_1 | EX: ✗
  Q   : What are the contestant numbers and names of the contestants who had at least two votes
  Pred: SELECT contestant_number, contestant_name FROM contestants WHERE created = '0' GROUP BY contestant_number HAVING COUNT(*) >= 2
  Gold: SELECT T1.contestant_number, T1.contestant_name FROM contestants AS T1 JOIN votes AS T2 ON T1.contestant_number = T2.contestant_number GROUP BY T1.contestant_number HAVING COUNT(*) >= 2
  Type: JOIN, GROUP_BY, HAVING, AGGREGATION

[443] OTHER | DB: voter_1 | EX: ✓
  Q   : Of all the contestants who got voted, what is the contestant number and name of the contestant who got least votes
  Pred: SELECT T1.contestant_number, T1.contestant_name FROM contestants AS T1 JOIN votes AS T2 ON T1.contestant_number = T2.contestant_number GROUP BY T1.contestant_number ORDER BY COUNT(*) LIMIT 1
  Gold: SELECT T1.contestant_number, T1.contestant_name FROM contestants AS T1 JOIN votes AS T2 ON T1.contestant_number = T2.contestant_number GROUP BY T1.contestant_number ORDER BY COUNT(*) ASC LIMIT 1
  Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, AGGREGATION

[444] WRONG_TABLE | DB: voter_1 | EX: ✗
  Q   : What is the area code in which the most voters voted
  Pred: SELECT area_code FROM votes GROUP BY area_code ORDER BY COUNT(*) DESC LIMIT 1
  Gold: SELECT T1.area_code FROM area_code_state AS T1 JOIN votes AS T2 ON T1.state = T2.state GROUP BY T1.area_code ORDER BY COUNT(*) DESC LIMIT 1
  Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, AGGREGATION

[445] WRONG_TABLE | DB: voter_1 | EX: ✗
  Q   : What are the create dates, states, and phone numbers of the votes that were for the contestant named 'Tabatha Gehling'
  Pred: SELECT created, state, phone_number FROM votes WHERE contestant_name = 'Tabatha Gehling'
  Gold: SELECT T2.created, T2.state, T2.phone_number FROM contestants AS T1 JOIN votes AS T2 ON T1.contestant_number = T2.contestant_number WHERE T1.contestant_name = 'Tabatha Gehling'
  Type: JOIN

[446] WRONG_TABLE | DB: voter_1 | EX: ✗
  Q   : List the area codes in which voters voted both for the contestant 'Tabatha Gehling' and the contestant 'Kelly Clauss'
  Pred: SELECT T1.area_code FROM votes AS T1 JOIN contestants AS T2 ON T1.contestant_number = T2.contestant_number WHERE T2.contestant_name = 'Tabatha Gehling' INTERSECT SELECT T1.area_code FROM votes AS T1 JOIN contestants AS T2 ON T1.contestant_number = T2.contestant_number WHERE T2.contestant_name = 'Kelly Clauss'
  Gold: SELECT T3.area_code FROM contestants AS T1 JOIN votes AS T2 ON T1.contestant_number = T2.contestant_number JOIN area_code_state AS T3 ON T2.state = T3.state WHERE T1.contestant_name = 'Tabatha Gehling' INTERSECT SELECT T3.area_code FROM contestants AS T1 JOIN votes AS T2 ON T1.contestant_number = T2.contestant_number JOIN area_code_state AS T3 ON T2.state = T3.state WHERE T1.contestant_name = 'Kelly Clauss'
  Type: JOIN

[447] EXTRA_JOIN | DB: voter_1 | EX: ✗
  Q   : Return the names of the contestants whose names contain the substring 'Al'
  Pred: SELECT T1.contestant_name FROM contestants AS T1 JOIN votes AS T2 ON T1.contestant_number = T2.contestant_number WHERE T2.contestant_name LIKE '%Al%'
  Gold: SELECT contestant_name FROM contestants WHERE contestant_name LIKE "%al%"
  Type: SIMPLE

[448] OTHER | DB: world_1 | EX: ✓
  Q   : How many countries have a republic as their form of government
  Pred: SELECT COUNT(*) FROM country WHERE governmentform = 'Republic'
  Gold: SELECT COUNT(*) FROM country WHERE GovernmentForm = "Republic"
  Type: AGGREGATION

[449] OTHER | DB: world_1 | EX: ✓
  Q   : How many countries have governments that are republics
  Pred: SELECT COUNT(*) FROM country WHERE governmentform = 'Republic'
  Gold: SELECT COUNT(*) FROM country WHERE GovernmentForm = "Republic"
  Type: AGGREGATION

[450] OTHER | DB: world_1 | EX: ✗
  Q   : What is the total surface area of the countries in the Caribbean region
  Pred: SELECT SUM(surfacearea) FROM country WHERE region = "Cararibbean"
  Gold: SELECT SUM(SurfaceArea) FROM country WHERE Region = "Caribbean"
  Type: AGGREGATION

[451] WRONG_COLUMNS | DB: world_1 | EX: ✗
  Q   : How much surface area do the countires in the Carribean cover together
  Pred: SELECT COUNT(*) FROM country WHERE region = "Carribean"
  Gold: SELECT SUM(SurfaceArea) FROM country WHERE Region = "Caribbean"
  Type: AGGREGATION

[452] WRONG_TABLE | DB: world_1 | EX: ✗
  Q   : Which region is the city Kabul located in
  Pred: SELECT region FROM city WHERE name = "Kabul"
  Gold: SELECT Region FROM country AS T1 JOIN city AS T2 ON T1.Code = T2.CountryCode WHERE T2.Name = "Kabul"
  Type: JOIN

[453] MISSING_JOIN | DB: world_1 | EX: ✗
  Q   : What region is Kabul in
  Pred: SELECT region FROM country WHERE localname = "Kabul"
  Gold: SELECT Region FROM country AS T1 JOIN city AS T2 ON T1.Code = T2.CountryCode WHERE T2.Name = "Kabul"
  Type: JOIN

[454] WRONG_TABLE | DB: world_1 | EX: ✗
  Q   : Which language is the most popular in Aruba
  Pred: SELECT language FROM countrylanguage WHERE localname = "Aruba" GROUP BY language ORDER BY COUNT(*) DESC LIMIT 1
  Gold: SELECT T2.Language FROM country AS T1 JOIN countrylanguage AS T2 ON T1.Code = T2.CountryCode WHERE T1.Name = "Aruba" ORDER BY Percentage DESC LIMIT 1
  Type: JOIN, ORDER_BY, LIMIT

[455] WRONG_TABLE | DB: world_1 | EX: ✗
  Q   : What language is predominantly spoken in Aruba
  Pred: SELECT language FROM countrylanguage WHERE isofficial = 'Aruba'
  Gold: SELECT T2.Language FROM country AS T1 JOIN countrylanguage AS T2 ON T1.Code = T2.CountryCode WHERE T1.Name = "Aruba" ORDER BY Percentage DESC LIMIT 1
  Type: JOIN, ORDER_BY, LIMIT

[456] OTHER | DB: world_1 | EX: ✓
  Q   : What are the population and life expectancies in Brazil
  Pred: SELECT population, lifeexpectancy FROM country WHERE name = 'Brazil'
  Gold: SELECT Population, LifeExpectancy FROM country WHERE Name = "Brazil"
  Type: SIMPLE

[457] OTHER | DB: world_1 | EX: ✓
  Q   : Give me Brazil’s population and life expectancies
  Pred: SELECT population, lifeexpectancy FROM country WHERE name = 'Brazil'
  Gold: SELECT Population, LifeExpectancy FROM country WHERE Name = "Brazil"
  Type: SIMPLE

[458] WRONG_COLUMNS | DB: world_1 | EX: ✗
  Q   : What are the region and population of Angola
  Pred: SELECT region, population FROM country WHERE name = "Angola"
  Gold: SELECT Population, Region FROM country WHERE Name = "Angola"
  Type: SIMPLE

[459] WRONG_COLUMNS | DB: world_1 | EX: ✗
  Q   : What region does Angola belong to and what is its population
  Pred: SELECT Region, Population FROM country WHERE Name = "Angola"
  Gold: SELECT Population, Region FROM country WHERE Name = "Angola"
  Type: SIMPLE

[460] OTHER | DB: world_1 | EX: ✗
  Q   : How long is the people’s average life expectancy in Central Africa
  Pred: SELECT AVG(lifeexpectancy) FROM country WHERE continent = "Central Africa"
  Gold: SELECT AVG(LifeExpectancy) FROM country WHERE Region = "Central Africa"
  Type: AGGREGATION

[461] EXTRA_JOIN | DB: world_1 | EX: ✗
  Q   : What is the name of country that has the shortest life expectancy in Asia
  Pred: SELECT T1.name FROM country AS T1 JOIN country AS T2 ON T1.code = T2.countrycode WHERE T2.region = "Asia" AND T2.lifeexpectancy = 'LivingExpectancy' AND T2.region = "Asia"
  Gold: SELECT Name FROM country WHERE Continent = "Asia" ORDER BY LifeExpectancy LIMIT 1
  Type: ORDER_BY, LIMIT

[462] OTHER | DB: world_1 | EX: ✗
  Q   : Give the name of the country in Asia with the lowest life expectancy
  Pred: SELECT name FROM country WHERE region = "Asia" ORDER BY lifeexpectancy LIMIT 1
  Gold: SELECT Name FROM country WHERE Continent = "Asia" ORDER BY LifeExpectancy LIMIT 1
  Type: ORDER_BY, LIMIT

[463] OTHER | DB: world_1 | EX: ✗
  Q   : What is the total population and maximum GNP in Asia
  Pred: SELECT SUM(population), MAX(gNP) FROM country WHERE region = "Asia"
  Gold: SELECT SUM(Population), MAX(GNP) FROM country WHERE Continent = "Asia"
  Type: AGGREGATION

[464] WRONG_COLUMNS | DB: world_1 | EX: ✗
  Q   : How many people live in Asia, and what is the largest GNP among them
  Pred: SELECT COUNT(*), GNP FROM country WHERE continent = "Asia" GROUP BY GNP ORDER BY COUNT(*) DESC LIMIT 1
  Gold: SELECT SUM(Population), MAX(GNP) FROM country WHERE Continent = "Asia"
  Type: AGGREGATION

[465] OTHER | DB: world_1 | EX: ✗
  Q   : What is the average life expectancy in African countries that are republics
  Pred: SELECT AVG(lifeexpectancy) FROM country WHERE continent = "Africa" AND countrycode = "Republic"
  Gold: SELECT AVG(LifeExpectancy) FROM country WHERE Continent = "Africa" AND GovernmentForm = "Republic"
  Type: AGGREGATION

[466] OTHER | DB: world_1 | EX: ✗
  Q   : Give the average life expectancy for countries in Africa which are republics
  Pred: SELECT AVG(lifeexpectancy) FROM country WHERE continent = "Africa" AND countrycode = "Republic"
  Gold: SELECT AVG(LifeExpectancy) FROM country WHERE Continent = "Africa" AND GovernmentForm = "Republic"
  Type: AGGREGATION

[467] OTHER | DB: world_1 | EX: ✗
  Q   : What is the total surface area of the continents Asia and Europe
  Pred: SELECT SUM(surfacearea) FROM country WHERE continent = "Asia" INTERSECT SELECT SUM(surfacearea) FROM country WHERE continent = "Europe"
  Gold: SELECT SUM(SurfaceArea) FROM country WHERE Continent = "Asia" OR Continent = "Europe"
  Type: AGGREGATION

[468] OTHER | DB: world_1 | EX: ✗
  Q   : Give the total surface area covered by countries in Asia or Europe
  Pred: SELECT SUM(surfacearea) FROM country WHERE region = "Asia" OR region = "Europe"
  Gold: SELECT SUM(SurfaceArea) FROM country WHERE Continent = "Asia" OR Continent = "Europe"
  Type: AGGREGATION

[469] WRONG_COLUMNS | DB: world_1 | EX: ✗
  Q   : How many people live in Gelderland district
  Pred: SELECT COUNT(*) FROM city WHERE district = "Gelderland"
  Gold: SELECT SUM(Population) FROM city WHERE District = "Gelderland"
  Type: AGGREGATION

[470] OTHER | DB: world_1 | EX: ✗
  Q   : What is the average GNP and total population in all nations whose government is US territory
  Pred: SELECT AVG(GNP), SUM(population) FROM country WHERE governmentform = 'US'
  Gold: SELECT AVG(GNP), SUM(population) FROM country WHERE GovernmentForm = "US Territory"
  Type: AGGREGATION

[471] WRONG_COLUMNS | DB: world_1 | EX: ✗
  Q   : Give the mean GNP and total population of nations which are considered US territory
  Pred: SELECT SUM(GNP), SUM(population) FROM country WHERE gnpold = 'US'
  Gold: SELECT AVG(GNP), SUM(population) FROM country WHERE GovernmentForm = "US Territory"
  Type: AGGREGATION

[472] WRONG_COLUMNS | DB: world_1 | EX: ✗
  Q   : How many type of governments are in Africa
  Pred: SELECT COUNT(*) FROM country WHERE continent = "Africa"
  Gold: SELECT COUNT(DISTINCT GovernmentForm) FROM country WHERE Continent = "Africa"
  Type: AGGREGATION

[473] WRONG_TABLE | DB: world_1 | EX: ✗
  Q   : What is the total number of languages used in Aruba
  Pred: SELECT COUNT(*) FROM countrylanguage WHERE localname = "Aruba"
  Gold: SELECT COUNT(T2.Language) FROM country AS T1 JOIN countrylanguage AS T2 ON T1.Code = T2.CountryCode WHERE T1.Name = "Aruba"
  Type: JOIN, AGGREGATION

[474] WRONG_TABLE | DB: world_1 | EX: ✗
  Q   : How many languages are spoken in Aruba
  Pred: SELECT COUNT(*) FROM countrylanguage WHERE localname = "Aruba"
  Gold: SELECT COUNT(T2.Language) FROM country AS T1 JOIN countrylanguage AS T2 ON T1.Code = T2.CountryCode WHERE T1.Name = "Aruba"
  Type: JOIN, AGGREGATION

[475] WRONG_TABLE | DB: world_1 | EX: ✗
  Q   : How many official languages does Afghanistan have
  Pred: SELECT COUNT(*) FROM countrylanguage WHERE isofficial = 'Afghanistan'
  Gold: SELECT COUNT(*) FROM country AS T1 JOIN countrylanguage AS T2 ON T1.Code = T2.CountryCode WHERE T1.Name = "Afghanistan" AND IsOfficial = "T"
  Type: JOIN, AGGREGATION

[476] WRONG_TABLE | DB: world_1 | EX: ✗
  Q   : How many official languages are spoken in Afghanistan
  Pred: SELECT COUNT(*) FROM countrylanguage WHERE isofficial = 'Afghanistan'
  Gold: SELECT COUNT(*) FROM country AS T1 JOIN countrylanguage AS T2 ON T1.Code = T2.CountryCode WHERE T1.Name = "Afghanistan" AND IsOfficial = "T"
  Type: JOIN, AGGREGATION

[477] OTHER | DB: world_1 | EX: ✗
  Q   : What is name of the country that speaks the largest number of languages
  Pred: SELECT T1.name FROM country AS T1 JOIN countrylanguage AS T2 ON T1.countrycode = T2.code GROUP BY T1.countrycode ORDER BY COUNT(*) DESC LIMIT 1
  Gold: SELECT T1.Name FROM country AS T1 JOIN countrylanguage AS T2 ON T1.Code = T2.CountryCode GROUP BY T1.Name ORDER BY COUNT(*) DESC LIMIT 1
  Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, AGGREGATION

[478] OTHER | DB: world_1 | EX: ✗
  Q   : Give the name of the nation that uses the greatest amount of languages
  Pred: SELECT T1.name FROM country AS T1 JOIN countrylanguage AS T2 ON T1.countrycode = T2.countrycode GROUP BY T1.countrycode ORDER BY COUNT(*) DESC LIMIT 1
  Gold: SELECT T1.Name FROM country AS T1 JOIN countrylanguage AS T2 ON T1.Code = T2.CountryCode GROUP BY T1.Name ORDER BY COUNT(*) DESC LIMIT 1
  Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, AGGREGATION

[479] MISSING_JOIN | DB: world_1 | EX: ✓
  Q   : Which continent has the most diverse languages
  Pred: SELECT continent FROM country GROUP BY continent ORDER BY COUNT(*) DESC LIMIT 1
  Gold: SELECT T1.Continent FROM country AS T1 JOIN countrylanguage AS T2 ON T1.Code = T2.CountryCode GROUP BY T1.Continent ORDER BY COUNT(*) DESC LIMIT 1
  Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, AGGREGATION

[480] MISSING_JOIN | DB: world_1 | EX: ✓
  Q   : Which continent speaks the most languages
  Pred: SELECT continent FROM country GROUP BY continent ORDER BY COUNT(*) DESC LIMIT 1
  Gold: SELECT T1.Continent FROM country AS T1 JOIN countrylanguage AS T2 ON T1.Code = T2.CountryCode GROUP BY T1.Continent ORDER BY COUNT(*) DESC LIMIT 1
  Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, AGGREGATION

[481] WRONG_TABLE | DB: world_1 | EX: ✗
  Q   : How many countries speak both English and Dutch
  Pred: SELECT COUNT(*) FROM countrylanguage WHERE language = 'English' INTERSECT SELECT COUNT(*) FROM countrylanguage WHERE language = 'Dutch'
  Gold: SELECT COUNT(*) FROM (SELECT T1.Name FROM country AS T1 JOIN countrylanguage AS T2 ON T1.Code = T2.CountryCode WHERE T2.Language = "English" INTERSECT SELECT T1.Name FROM country AS T1 JOIN countrylanguage AS T2 ON T1.Code = T2.CountryCode WHERE T2.Language = "Dutch")
  Type: JOIN, NESTED, AGGREGATION

[482] WRONG_TABLE | DB: world_1 | EX: ✗
  Q   : What is the number of nations that use English and Dutch
  Pred: SELECT COUNT(*) FROM countrylanguage WHERE language = 'English' INTERSECT SELECT COUNT(*) FROM country WHERE language = 'Dutch'
  Gold: SELECT COUNT(*) FROM (SELECT T1.Name FROM country AS T1 JOIN countrylanguage AS T2 ON T1.Code = T2.CountryCode WHERE T2.Language = "English" INTERSECT SELECT T1.Name FROM country AS T1 JOIN countrylanguage AS T2 ON T1.Code = T2.CountryCode WHERE T2.Language = "Dutch")
  Type: JOIN, NESTED, AGGREGATION

[483] OTHER | DB: world_1 | EX: ✗
  Q   : What are the names of nations speak both English and French
  Pred: SELECT T1.name FROM country AS T1 JOIN countrylanguage AS T2 ON T1.countrycode = T2.code WHERE T2.language = 'English' INTERSECT SELECT T1.name FROM country AS T1 JOIN countrylanguage AS T2 ON T1.countrycode = T2.countrycode WHERE T2.language = 'French'
  Gold: SELECT T1.Name FROM country AS T1 JOIN countrylanguage AS T2 ON T1.Code = T2.CountryCode WHERE T2.Language = "English" INTERSECT SELECT T1.Name FROM country AS T1 JOIN countrylanguage AS T2 ON T1.Code = T2.CountryCode WHERE T2.Language = "French"
  Type: JOIN

[484] OTHER | DB: world_1 | EX: ✗
  Q   : Give the names of nations that speak both English and French
  Pred: SELECT T1.name FROM country AS T1 JOIN countrylanguage AS T2 ON T1.countrycode = T2.code WHERE T2.language = 'English' INTERSECT SELECT T1.name FROM country AS T1 JOIN countrylanguage AS T2 ON T1.countrycode = T2.countrycode WHERE T2.language = 'French'
  Gold: SELECT T1.Name FROM country AS T1 JOIN countrylanguage AS T2 ON T1.Code = T2.CountryCode WHERE T2.Language = "English" INTERSECT SELECT T1.Name FROM country AS T1 JOIN countrylanguage AS T2 ON T1.Code = T2.CountryCode WHERE T2.Language = "French"
  Type: JOIN

[485] OTHER | DB: world_1 | EX: ✗
  Q   : What are the names of nations where both English and French are official languages
  Pred: SELECT T1.name FROM country AS T1 JOIN countrylanguage AS T2 ON T1.countrycode = T2.code WHERE T2.language = 'English' INTERSECT SELECT T1.name FROM country AS T1 JOIN countrylanguage AS T2 ON T1.countrycode = T2.countrycode WHERE T2.language = 'French'
  Gold: SELECT T1.Name FROM country AS T1 JOIN countrylanguage AS T2 ON T1.Code = T2.CountryCode WHERE T2.Language = "English" AND T2.IsOfficial = "T" INTERSECT SELECT T1.Name FROM country AS T1 JOIN countrylanguage AS T2 ON T1.Code = T2.CountryCode WHERE T2.Language = "French" AND T2.IsOfficial = "T"
  Type: JOIN

[486] OTHER | DB: world_1 | EX: ✗
  Q   : Give the names of countries with English and French as official languages
  Pred: SELECT T1.name FROM country AS T1 JOIN countrylanguage AS T2 ON T1.countrycode = T2.code WHERE T2.language = 'English' INTERSECT SELECT T1.name FROM country AS T1 JOIN countrylanguage AS T2 ON T1.countrycode = T2.countrycode WHERE T2.language = 'French'
  Gold: SELECT T1.Name FROM country AS T1 JOIN countrylanguage AS T2 ON T1.Code = T2.CountryCode WHERE T2.Language = "English" AND T2.IsOfficial = "T" INTERSECT SELECT T1.Name FROM country AS T1 JOIN countrylanguage AS T2 ON T1.Code = T2.CountryCode WHERE T2.Language = "French" AND T2.IsOfficial = "T"
  Type: JOIN

[487] MISSING_JOIN | DB: world_1 | EX: ✗
  Q   : What is the number of distinct continents where Chinese is spoken
  Pred: SELECT COUNT(DISTINCT continent) FROM country WHERE language = 'Chinese'
  Gold: SELECT COUNT(DISTINCT Continent) FROM country AS T1 JOIN countrylanguage AS T2 ON T1.Code = T2.CountryCode WHERE T2.Language = "Chinese"
  Type: JOIN, AGGREGATION

[488] MISSING_JOIN | DB: world_1 | EX: ✗
  Q   : How many continents speak Chinese
  Pred: SELECT COUNT(*) FROM country WHERE language = 'Chinese'
  Gold: SELECT COUNT(DISTINCT Continent) FROM country AS T1 JOIN countrylanguage AS T2 ON T1.Code = T2.CountryCode WHERE T2.Language = "Chinese"
  Type: JOIN, AGGREGATION

[489] MISSING_JOIN | DB: world_1 | EX: ✗
  Q   : What are the regions that use English or Dutch
  Pred: SELECT region FROM country WHERE language = 'English' OR language = 'Dutch'
  Gold: SELECT DISTINCT T1.Region FROM country AS T1 JOIN countrylanguage AS T2 ON T1.Code = T2.CountryCode WHERE T2.Language = "English" OR T2.Language = "Dutch"
  Type: JOIN

[490] MISSING_JOIN | DB: world_1 | EX: ✗
  Q   : Which regions speak Dutch or English
  Pred: SELECT Region FROM country WHERE Language = "Dutch" OR Language = "Englisch"
  Gold: SELECT DISTINCT T1.Region FROM country AS T1 JOIN countrylanguage AS T2 ON T1.Code = T2.CountryCode WHERE T2.Language = "English" OR T2.Language = "Dutch"
  Type: JOIN

[491] WRONG_TABLE | DB: world_1 | EX: ✓
  Q   : What are the countries where either English or Dutch is the official language
  Pred: SELECT countrycode FROM countrylanguage WHERE isofficial = 'English' OR isofficial = 'Dutch'
  Gold: SELECT t1.name FROM country AS t1 JOIN countrylanguage AS t2 ON t1.code = t2.countrycode WHERE t2.language = "english" AND isofficial = "t" UNION SELECT t1.name FROM country AS t1 JOIN countrylanguage AS t2 ON t1.code = t2.countrycode WHERE t2.language = "dutch" AND isofficial = "t"
  Type: JOIN

[492] WRONG_TABLE | DB: world_1 | EX: ✗
  Q   : Which countries have either English or Dutch as an official language
  Pred: SELECT countrycode FROM countrylanguage WHERE isofficial = 'English' OR isofficial = 'Dutch'
  Gold: SELECT * FROM country AS T1 JOIN countrylanguage AS T2 ON T1.Code = T2.CountryCode WHERE T2.Language = "English" AND IsOfficial = "T" UNION SELECT * FROM country AS T1 JOIN countrylanguage AS T2 ON T1.Code = T2.CountryCode WHERE T2.Language = "Dutch" AND IsOfficial = "T"
  Type: JOIN

[493] MISSING_JOIN | DB: world_1 | EX: ✗
  Q   : Which language is the most popular on the Asian continent
  Pred: SELECT language FROM country WHERE continent = "Asia" GROUP BY language ORDER BY COUNT(*) DESC LIMIT 1
  Gold: SELECT T2.Language FROM country AS T1 JOIN countrylanguage AS T2 ON T1.Code = T2.CountryCode WHERE T1.Continent = "Asia" GROUP BY T2.Language ORDER BY COUNT(*) DESC LIMIT 1
  Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, AGGREGATION

[494] WRONG_TABLE | DB: world_1 | EX: ✗
  Q   : What is the language that is used by the largest number of Asian nations
  Pred: SELECT language FROM countrylanguage WHERE region = "asia" GROUP BY language ORDER BY COUNT(*) DESC LIMIT 1
  Gold: SELECT T2.Language FROM country AS T1 JOIN countrylanguage AS T2 ON T1.Code = T2.CountryCode WHERE T1.Continent = "Asia" GROUP BY T2.Language ORDER BY COUNT(*) DESC LIMIT 1
  Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, AGGREGATION

[495] WRONG_TABLE | DB: world_1 | EX: ✗
  Q   : Which languages are spoken by only one country in republic governments
  Pred: SELECT language FROM countrylanguage WHERE governmentform = 'Republic' GROUP BY language HAVING COUNT(*) = 1
  Gold: SELECT T2.Language FROM country AS T1 JOIN countrylanguage AS T2 ON T1.Code = T2.CountryCode WHERE T1.GovernmentForm = "Republic" GROUP BY T2.Language HAVING COUNT(*) = 1
  Type: JOIN, GROUP_BY, HAVING, AGGREGATION

[496] WRONG_TABLE | DB: world_1 | EX: ✗
  Q   : What languages are only used by a single country with a republic government
  Pred: SELECT language FROM countrylanguage WHERE governmentform = 'Republic'
  Gold: SELECT T2.Language FROM country AS T1 JOIN countrylanguage AS T2 ON T1.Code = T2.CountryCode WHERE T1.GovernmentForm = "Republic" GROUP BY T2.Language HAVING COUNT(*) = 1
  Type: JOIN, GROUP_BY, HAVING, AGGREGATION

[497] MISSING_JOIN | DB: world_1 | EX: ✗
  Q   : Find the city with the largest population that uses English
  Pred: SELECT name FROM city WHERE language = 'english' GROUP BY name ORDER BY COUNT(*) DESC LIMIT 1
  Gold: SELECT T1.Name, T1.Population FROM city AS T1 JOIN countrylanguage AS T2 ON T1.CountryCode = T2.CountryCode WHERE T2.Language = "English" ORDER BY T1.Population DESC LIMIT 1
  Type: JOIN, ORDER_BY, LIMIT

[498] MISSING_JOIN | DB: world_1 | EX: ✗
  Q   : What is the most populace city that speaks English
  Pred: SELECT name FROM city WHERE language = 'english' GROUP BY name ORDER BY COUNT(*) DESC LIMIT 1
  Gold: SELECT T1.Name, T1.Population FROM city AS T1 JOIN countrylanguage AS T2 ON T1.CountryCode = T2.CountryCode WHERE T2.Language = "English" ORDER BY T1.Population DESC LIMIT 1
  Type: JOIN, ORDER_BY, LIMIT

[499] OTHER | DB: world_1 | EX: ✗
  Q   : Find the name, population and expected life length of asian country with the largest area
  Pred: SELECT name, population, lifeexpectancy FROM country WHERE region = "Asian" ORDER BY surfacearea DESC LIMIT 1
  Gold: SELECT Name, Population, LifeExpectancy FROM country WHERE Continent = "Asia" ORDER BY SurfaceArea DESC LIMIT 1
  Type: ORDER_BY, LIMIT

[500] OTHER | DB: world_1 | EX: ✗
  Q   : What are the name, population, and life expectancy of the largest Asian country by land
  Pred: SELECT name, population, lifeexpectancy FROM country WHERE region = 'Asia' ORDER BY surfacearea DESC LIMIT 1
  Gold: SELECT Name, Population, LifeExpectancy FROM country WHERE Continent = "Asia" ORDER BY SurfaceArea DESC LIMIT 1
  Type: ORDER_BY, LIMIT

[501] WRONG_TABLE | DB: world_1 | EX: ✗
  Q   : What is average life expectancy in the countries where English is not the official language
  Pred: SELECT AVG(lifeexpectancy) FROM countrylanguage WHERE isofficial = 'English'
  Gold: SELECT AVG(LifeExpectancy) FROM country WHERE NOT Name IN (SELECT T1.Name FROM country AS T1 JOIN countrylanguage AS T2 ON T1.Code = T2.CountryCode WHERE T2.Language = "English" AND T2.IsOfficial = "T")
  Type: JOIN, NESTED, AGGREGATION

[502] MISSING_JOIN | DB: world_1 | EX: ✗
  Q   : Give the mean life expectancy of countries in which English is not the official language
  Pred: SELECT MAX(lifeexpectancy) FROM country WHERE isofficial = 'English'
  Gold: SELECT AVG(LifeExpectancy) FROM country WHERE NOT Name IN (SELECT T1.Name FROM country AS T1 JOIN countrylanguage AS T2 ON T1.Code = T2.CountryCode WHERE T2.Language = "English" AND T2.IsOfficial = "T")
  Type: JOIN, NESTED, AGGREGATION

[503] MISSING_JOIN | DB: world_1 | EX: ✗
  Q   : What is the total number of people living in the nations that do not use English
  Pred: SELECT SUM(population) FROM country WHERE language > 'english'
  Gold: SELECT SUM(Population) FROM country WHERE NOT Name IN (SELECT T1.Name FROM country AS T1 JOIN countrylanguage AS T2 ON T1.Code = T2.CountryCode WHERE T2.Language = "English")
  Type: JOIN, NESTED, AGGREGATION

[504] MISSING_JOIN | DB: world_1 | EX: ✗
  Q   : How many people live in countries that do not speak English
  Pred: SELECT COUNT(*) FROM country WHERE language > 'english'
  Gold: SELECT SUM(Population) FROM country WHERE NOT Name IN (SELECT T1.Name FROM country AS T1 JOIN countrylanguage AS T2 ON T1.Code = T2.CountryCode WHERE T2.Language = "English")
  Type: JOIN, NESTED, AGGREGATION

[505] WRONG_TABLE | DB: world_1 | EX: ✗
  Q   : What is the official language spoken in the country whose head of state is Beatrix
  Pred: SELECT language FROM countrylanguage WHERE headofstate = 'Beatrix'
  Gold: SELECT T2.Language FROM country AS T1 JOIN countrylanguage AS T2 ON T1.Code = T2.CountryCode WHERE T1.HeadOfState = "Beatrix" AND T2.IsOfficial = "T"
  Type: JOIN

[506] OTHER | DB: world_1 | EX: ✗
  Q   : What is the official language used in the country the name of whose head of state is Beatrix
  Pred: SELECT T2.language FROM country AS T1 JOIN countrylanguage AS T2 ON T1.countrycode = T2.code WHERE T1.name = "Beatrix"
  Gold: SELECT T2.Language FROM country AS T1 JOIN countrylanguage AS T2 ON T1.Code = T2.CountryCode WHERE T1.HeadOfState = "Beatrix" AND T2.IsOfficial = "T"
  Type: JOIN

[507] WRONG_TABLE | DB: world_1 | EX: ✗
  Q   : What is the total number of unique official languages spoken in the countries that are founded before 1930
  Pred: SELECT COUNT(DISTINCT isofficial) FROM countrylanguage WHERE countrycode  1930
  Gold: SELECT COUNT(DISTINCT T2.Language) FROM country AS T1 JOIN countrylanguage AS T2 ON T1.Code = T2.CountryCode WHERE IndepYear < 1930 AND T2.IsOfficial = "T"
  Type: JOIN, AGGREGATION

[508] WRONG_TABLE | DB: world_1 | EX: ✗
  Q   : For the countries founded before 1930, what is the total number of distinct official languages
  Pred: SELECT COUNT(DISTINCT language) FROM countrycode WHERE indepyear  1930
  Gold: SELECT COUNT(DISTINCT T2.Language) FROM country AS T1 JOIN countrylanguage AS T2 ON T1.Code = T2.CountryCode WHERE IndepYear < 1930 AND T2.IsOfficial = "T"
  Type: JOIN, AGGREGATION

[509] WRONG_COLUMNS | DB: world_1 | EX: ✗
  Q   : What are the countries that have greater surface area than any country in Europe
  Pred: SELECT country FROM country WHERE surfacearea > (SELECT MAX(surfacearea) FROM country WHERE continent = 'Europe')
  Gold: SELECT Name FROM country WHERE SurfaceArea > (SELECT MIN(SurfaceArea) FROM country WHERE Continent = "Europe")
  Type: NESTED, AGGREGATION

[510] WRONG_COLUMNS | DB: world_1 | EX: ✗
  Q   : Which countries have greater area than that of any country in Europe
  Pred: SELECT name FROM country WHERE surfacearea > (SELECT MAX(surfacearea) FROM country WHERE continent = 'Europe')
  Gold: SELECT Name FROM country WHERE SurfaceArea > (SELECT MIN(SurfaceArea) FROM country WHERE Continent = "Europe")
  Type: NESTED, AGGREGATION

[511] EXTRA_JOIN | DB: world_1 | EX: ✗
  Q   : What are the African countries that have a population less than any country in Asia
  Pred: SELECT name FROM country WHERE continent = "Africa" EXCEPT SELECT T1.name FROM country AS T1 JOIN country AS T2 ON T1.code = T2.countrycode WHERE continent = "Asia"
  Gold: SELECT Name FROM country WHERE Continent = "Africa" AND population < (SELECT MAX(population) FROM country WHERE Continent = "Asia")
  Type: NESTED, AGGREGATION

[512] EXTRA_JOIN | DB: world_1 | EX: ✗
  Q   : Which African countries have a smaller population than that of any country in Asia
  Pred: SELECT name FROM country WHERE continent = "Africa" EXCEPT SELECT T1.name FROM country AS T1 JOIN country AS T2 ON T1.code = T2.countrycode WHERE continent = "Asia"
  Gold: SELECT Name FROM country WHERE Continent = "Africa" AND population < (SELECT MIN(population) FROM country WHERE Continent = "Asia")
  Type: NESTED, AGGREGATION

[513] EXTRA_JOIN | DB: world_1 | EX: ✗
  Q   : Which Asian countries have a population that is larger than any country in Africa
  Pred: SELECT T1.name FROM country AS T1 JOIN country AS T2 ON T1.code = T2.countrycode WHERE T2.name = 'Asia' AND T2.population > (SELECT MAX(population) FROM country WHERE continent = 'Africa')
  Gold: SELECT Name FROM country WHERE Continent = "Asia" AND population > (SELECT MAX(population) FROM country WHERE Continent = "Africa")
  Type: NESTED, AGGREGATION

[514] EXTRA_JOIN | DB: world_1 | EX: ✗
  Q   : What are the Asian countries which have a population larger than that of any country in Africa
  Pred: SELECT name FROM country WHERE continent = "Asia" EXCEPT SELECT T1.name FROM country AS T1 JOIN country AS T2 ON T1.code = T2.countrycode WHERE continent = "Africa"
  Gold: SELECT Name FROM country WHERE Continent = "Asia" AND population > (SELECT MIN(population) FROM country WHERE Continent = "Africa")
  Type: NESTED, AGGREGATION

[515] WRONG_TABLE | DB: world_1 | EX: ✗
  Q   : What are the country codes for countries that do not speak English
  Pred: SELECT countrycode FROM country WHERE language > 'english'
  Gold: SELECT CountryCode FROM countrylanguage EXCEPT SELECT CountryCode FROM countrylanguage WHERE LANGUAGE = "English"
  Type: SIMPLE

[516] WRONG_TABLE | DB: world_1 | EX: ✗
  Q   : Return the country codes for countries that do not speak English
  Pred: SELECT countrycode FROM country WHERE language > 'english'
  Gold: SELECT CountryCode FROM countrylanguage EXCEPT SELECT CountryCode FROM countrylanguage WHERE LANGUAGE = "English"
  Type: SIMPLE

[517] WRONG_TABLE | DB: world_1 | EX: ✗
  Q   : What are the country codes of countries where people use languages other than English
  Pred: SELECT countrycode FROM country WHERE language > "english"
  Gold: SELECT DISTINCT CountryCode FROM countrylanguage WHERE LANGUAGE <> "English"
  Type: SIMPLE

[518] WRONG_TABLE | DB: world_1 | EX: ✗
  Q   : Give the country codes for countries in which people speak langauges that are not English
  Pred: SELECT countrycode FROM country WHERE language > 'english'
  Gold: SELECT DISTINCT CountryCode FROM countrylanguage WHERE LANGUAGE <> "English"
  Type: SIMPLE

[519] WRONG_TABLE | DB: world_1 | EX: ✗
  Q   : What are the codes of the countries that do not speak English and whose government forms are not Republic
  Pred: SELECT countrycode FROM country WHERE language > 'English' AND governmentform > 'Republic'
  Gold: SELECT Code FROM country WHERE GovernmentForm <> "Republic" EXCEPT SELECT CountryCode FROM countrylanguage WHERE LANGUAGE = "English"
  Type: SIMPLE

[520] WRONG_TABLE | DB: world_1 | EX: ✗
  Q   : Return the codes of countries that do not speak English and do not have Republics for governments
  Pred: SELECT countrycode FROM country WHERE language > 'English' INTERSECT SELECT countrycode FROM country WHERE governmentform = 'Republic'
  Gold: SELECT Code FROM country WHERE GovernmentForm <> "Republic" EXCEPT SELECT CountryCode FROM countrylanguage WHERE LANGUAGE = "English"
  Type: SIMPLE

[521] WRONG_COLUMNS | DB: world_1 | EX: ✗
  Q   : Which cities are in European countries where English is not the official language
  Pred: SELECT T2.name FROM country AS T1 JOIN countrylanguage AS T2 ON T1.countrycode = T2.code WHERE T1.language > 'English'
  Gold: SELECT DISTINCT T2.Name FROM country AS T1 JOIN city AS T2 ON T2.CountryCode = T1.Code WHERE T1.Continent = 'Europe' AND NOT T1.Name IN (SELECT T3.Name FROM country AS T3 JOIN countrylanguage AS T4 ON T3.Code = T4.CountryCode WHERE T4.IsOfficial = 'T' AND T4.Language = 'English')
  Type: JOIN, NESTED

[522] WRONG_COLUMNS | DB: world_1 | EX: ✗
  Q   : What are the names of cities in Europe for which English is not the official language
  Pred: SELECT T2.name FROM country AS T1 JOIN countrylanguage AS T2 ON T1.countrycode = T2.code WHERE T1.language > 'English'
  Gold: SELECT DISTINCT T2.Name FROM country AS T1 JOIN city AS T2 ON T2.CountryCode = T1.Code WHERE T1.Continent = 'Europe' AND NOT T1.Name IN (SELECT T3.Name FROM country AS T3 JOIN countrylanguage AS T4 ON T3.Code = T4.CountryCode WHERE T4.IsOfficial = 'T' AND T4.Language = 'English')
  Type: JOIN, NESTED

[523] WRONG_TABLE | DB: world_1 | EX: ✗
  Q   : Which unique cities are in Asian countries where Chinese is the official language
  Pred: SELECT DISTINCT T1.name FROM city AS T1 JOIN countrylanguage AS T2 ON T1.countrycode = T2.code WHERE T2.language = 'Chinese'
  Gold: SELECT DISTINCT t3.name FROM country AS t1 JOIN countrylanguage AS t2 ON t1.code = t2.countrycode JOIN city AS t3 ON t1.code = t3.countrycode WHERE t2.isofficial = 't' AND t2.language = 'chinese' AND t1.continent = "asia"
  Type: JOIN

[524] WRONG_COLUMNS | DB: world_1 | EX: ✗
  Q   : Return the different names of cities that are in Asia and for which Chinese is the official language
  Pred: SELECT DISTINCT T1.name FROM country AS T1 JOIN countrylanguage AS T2 ON T1.countrycode = T2.code WHERE T2.language = "Chinese" AND T2.code = "Asia"
  Gold: SELECT DISTINCT T3.Name FROM country AS T1 JOIN countrylanguage AS T2 ON T1.Code = T2.CountryCode JOIN city AS T3 ON T1.Code = T3.CountryCode WHERE T2.IsOfficial = 'T' AND T2.Language = 'Chinese' AND T1.Continent = "Asia"
  Type: JOIN

[525] WRONG_COLUMNS | DB: world_1 | EX: ✗
  Q   : What are the name, independence year, and surface area of the country with the smallest population
  Pred: SELECT name, indepyear, surfacearea FROM country ORDER BY population LIMIT 1
  Gold: SELECT Name, SurfaceArea, IndepYear FROM country ORDER BY Population LIMIT 1
  Type: ORDER_BY, LIMIT

[526] WRONG_COLUMNS | DB: world_1 | EX: ✗
  Q   : Give the name, year of independence, and surface area of the country that has the lowest population
  Pred: SELECT name, indepyear, surfacearea FROM country ORDER BY population LIMIT 1
  Gold: SELECT Name, SurfaceArea, IndepYear FROM country ORDER BY Population LIMIT 1
  Type: ORDER_BY, LIMIT

[527] WRONG_COLUMNS | DB: world_1 | EX: ✗
  Q   : What are the population, name and leader of the country with the largest area
  Pred: SELECT population, name, headofstate FROM country ORDER BY surfacearea DESC LIMIT 1
  Gold: SELECT Name, population, HeadOfState FROM country ORDER BY SurfaceArea DESC LIMIT 1
  Type: ORDER_BY, LIMIT

[528] WRONG_COLUMNS | DB: world_1 | EX: ✗
  Q   : Return the country name and the numbers of languages spoken for each country that speaks at least 3 languages
  Pred: SELECT T1.name, COUNT(*), T2.language FROM country AS T1 JOIN countrylanguage AS T2 ON T1.countrycode = T2.code GROUP BY T2.language HAVING COUNT(*) >= 3
  Gold: SELECT COUNT(T2.Language), T1.Name FROM country AS T1 JOIN countrylanguage AS T2 ON T1.Code = T2.CountryCode GROUP BY T1.Name HAVING COUNT(*) > 2
  Type: JOIN, GROUP_BY, HAVING, AGGREGATION

[529] WRONG_COLUMNS | DB: world_1 | EX: ✗
  Q   : What are the names of countries that speak more than 2 languages, as well as how many languages they speak
  Pred: SELECT T1.name, COUNT(*) FROM country AS T1 JOIN countrylanguage AS T2 ON T1.code = T2.countrycode GROUP BY T1.code HAVING COUNT(*) > 2
  Gold: SELECT COUNT(T2.Language), T1.Name FROM country AS T1 JOIN countrylanguage AS T2 ON T1.Code = T2.CountryCode GROUP BY T1.Name HAVING COUNT(*) > 2
  Type: JOIN, GROUP_BY, HAVING, AGGREGATION

[530] MISSING_WHERE | DB: world_1 | EX: ✗
  Q   : Find the number of cities in each district whose population is greater than the average population of cities
  Pred: SELECT district, COUNT(*) FROM city GROUP BY district HAVING AVG(population) > (SELECT AVG(population) FROM city)
  Gold: SELECT COUNT(*), District FROM city WHERE Population > (SELECT AVG(Population) FROM city) GROUP BY District
  Type: GROUP_BY, NESTED, AGGREGATION

[531] MISSING_GROUP_BY | DB: world_1 | EX: ✗
  Q   : How many cities in each district have a population that is above the average population across all cities
  Pred: SELECT COUNT(*), district FROM city WHERE population > (SELECT AVG(population) FROM city)
  Gold: SELECT COUNT(*), District FROM city WHERE Population > (SELECT AVG(Population) FROM city) GROUP BY District
  Type: GROUP_BY, NESTED, AGGREGATION

[532] MISSING_GROUP_BY | DB: world_1 | EX: ✗
  Q   : Find the government form name and total population for each government form whose average life expectancy is longer than 72
  Pred: SELECT governmentform, SUM(population) FROM country WHERE lifeexpectancy > 72
  Gold: SELECT SUM(Population), GovernmentForm FROM country GROUP BY GovernmentForm HAVING AVG(LifeExpectancy) > 72
  Type: GROUP_BY, HAVING, AGGREGATION

[533] MISSING_GROUP_BY | DB: world_1 | EX: ✗
  Q   : What are the different government forms and what is the total population of each for government forms that have an average life expectancy greater than 72
  Pred: SELECT governmentform, SUM(population) FROM country WHERE lifeexpectancy > 72
  Gold: SELECT SUM(Population), GovernmentForm FROM country GROUP BY GovernmentForm HAVING AVG(LifeExpectancy) > 72
  Type: GROUP_BY, HAVING, AGGREGATION

[534] MISSING_GROUP_BY | DB: world_1 | EX: ✗
  Q   : Find the average life expectancy and total population for each continent where the average life expectancy is shorter than 72
  Pred: SELECT AVG(lifeexpectancy), SUM(population), continent FROM country WHERE average lifeexpectancy  72
  Gold: SELECT SUM(Population), AVG(LifeExpectancy), Continent FROM country GROUP BY Continent HAVING AVG(LifeExpectancy) < 72
  Type: GROUP_BY, HAVING, AGGREGATION

[535] MISSING_GROUP_BY | DB: world_1 | EX: ✗
  Q   : What are the different continents and the total popuation and average life expectancy corresponding to each, for continents that have an average life expectancy less than 72
  Pred: SELECT continent, AVG(lifeexpectancy), SUM(population), AVG(lifeexpectancy) FROM country WHERE population  72
  Gold: SELECT SUM(Population), AVG(LifeExpectancy), Continent FROM country GROUP BY Continent HAVING AVG(LifeExpectancy) < 72
  Type: GROUP_BY, HAVING, AGGREGATION

[536] EXTRA_JOIN | DB: world_1 | EX: ✗
  Q   : What are the names and areas of countries with the top 5 largest area
  Pred: SELECT T2.name, T2.surfacearea FROM country AS T1 JOIN country AS T2 ON T1.code = T2.code GROUP BY T1.code ORDER BY COUNT(*) DESC LIMIT 5
  Gold: SELECT Name, SurfaceArea FROM country ORDER BY SurfaceArea DESC LIMIT 5
  Type: ORDER_BY, LIMIT

[537] OTHER | DB: world_1 | EX: ✓
  Q   : What are the names of the nations with the 3 lowest populations
  Pred: SELECT name FROM country ORDER BY population LIMIT 3
  Gold: SELECT Name FROM country ORDER BY Population ASC LIMIT 3
  Type: ORDER_BY, LIMIT

[538] OTHER | DB: world_1 | EX: ✓
  Q   : Return the names of the 3 countries with the fewest people
  Pred: SELECT name FROM country ORDER BY population LIMIT 3
  Gold: SELECT Name FROM country ORDER BY Population ASC LIMIT 3
  Type: ORDER_BY, LIMIT

[539] OTHER | DB: world_1 | EX: ✓
  Q   : What are the names of the countries that are in the continent of Europe and have a population of 80000
  Pred: SELECT name FROM country WHERE continent = "Europe" AND population = 80000
  Gold: SELECT Name FROM country WHERE continent = "Europe" AND Population = "80000"
  Type: SIMPLE

[540] OTHER | DB: world_1 | EX: ✓
  Q   : Give the names of countries that are in Europe and have a population equal to 80000
  Pred: SELECT name FROM country WHERE continent = "Europe" AND population = 80000
  Gold: SELECT Name FROM country WHERE continent = "Europe" AND Population = "80000"
  Type: SIMPLE

[541] OTHER | DB: world_1 | EX: ✗
  Q   : What is the total population and average area of countries in the continent of North America whose area is bigger than 3000
  Pred: SELECT SUM(population), AVG(surfacearea) FROM country WHERE continent = "North America" GROUP BY continent HAVING AVG(surfacearea) > 3000
  Gold: SELECT SUM(population), AVG(surfacearea) FROM country WHERE continent = "north america" AND surfacearea > 3000
  Type: AGGREGATION

[542] OTHER | DB: world_1 | EX: ✗
  Q   : Give the total population and average surface area corresponding to countries in North America that have a surface area greater than 3000
  Pred: SELECT SUM(population), AVG(surfacearea) FROM country WHERE continent = 'North America' AND surfacearea > 3000
  Gold: SELECT SUM(population), AVG(surfacearea) FROM country WHERE continent = "north america" AND surfacearea > 3000
  Type: AGGREGATION

[543] WRONG_TABLE | DB: world_1 | EX: ✗
  Q   : What is the language spoken by the largest percentage of people in each country
  Pred: SELECT countrylanguage, percentage FROM country GROUP BY countrycode ORDER BY COUNT(*) DESC LIMIT 1
  Gold: SELECT LANGUAGE, CountryCode, MAX(Percentage) FROM countrylanguage GROUP BY CountryCode
  Type: GROUP_BY, AGGREGATION

[544] WRONG_COLUMNS | DB: world_1 | EX: ✗
  Q   : What are the country codes of the different countries, and what are the languages spoken by the greatest percentage of people for each
  Pred: SELECT countrycode, language FROM countrylanguage GROUP BY countrycode ORDER BY COUNT(*) DESC LIMIT 1
  Gold: SELECT LANGUAGE, CountryCode, MAX(Percentage) FROM countrylanguage GROUP BY CountryCode
  Type: GROUP_BY, AGGREGATION

[545] WRONG_COLUMNS | DB: world_1 | EX: ✗
  Q   : What is the total number of countries where Spanish is spoken by the largest percentage of people
  Pred: SELECT COUNT(*), countrycode FROM countrylanguage WHERE language = "Spanish" GROUP BY countrycode ORDER BY COUNT(*) DESC LIMIT 1
  Gold: SELECT COUNT(*), MAX(Percentage) FROM countrylanguage WHERE LANGUAGE = "Spanish" GROUP BY CountryCode
  Type: GROUP_BY, AGGREGATION

[546] WRONG_COLUMNS | DB: world_1 | EX: ✗
  Q   : Count the number of countries for which Spanish is the predominantly spoken language
  Pred: SELECT COUNT(*) FROM countrylanguage WHERE language = "Spanish" GROUP BY countrycode ORDER BY COUNT(*) DESC LIMIT 1
  Gold: SELECT COUNT(*), MAX(Percentage) FROM countrylanguage WHERE LANGUAGE = "Spanish" GROUP BY CountryCode
  Type: GROUP_BY, AGGREGATION

[547] MISSING_GROUP_BY | DB: world_1 | EX: ✗
  Q   : What are the codes of countries where Spanish is spoken by the largest percentage of people
  Pred: SELECT countrycode FROM countrylanguage WHERE language = 'Spanish' ORDER BY percentage DESC LIMIT 1
  Gold: SELECT CountryCode, MAX(Percentage) FROM countrylanguage WHERE LANGUAGE = "Spanish" GROUP BY CountryCode
  Type: GROUP_BY, AGGREGATION

[548] WRONG_TABLE | DB: world_1 | EX: ✗
  Q   : Return the codes of countries for which Spanish is the predominantly spoken language
  Pred: SELECT countrycode FROM country WHERE language = "Spanish" GROUP BY countrycode ORDER BY COUNT(*) DESC LIMIT 1
  Gold: SELECT CountryCode, MAX(Percentage) FROM countrylanguage WHERE LANGUAGE = "Spanish" GROUP BY CountryCode
  Type: GROUP_BY, AGGREGATION

[549] OTHER | DB: orchestra | EX: ✓
  Q   : What are the names of conductors, ordered by age
  Pred: SELECT Name FROM conductor ORDER BY Age
  Gold: SELECT Name FROM conductor ORDER BY Age ASC
  Type: ORDER_BY

[550] OTHER | DB: orchestra | EX: ✗
  Q   : What are the names of conductors whose nationalities are not "USA"
  Pred: SELECT Name FROM conductor WHERE Nationality > "USA"
  Gold: SELECT Name FROM conductor WHERE Nationality <> 'USA'
  Type: SIMPLE

[551] OTHER | DB: orchestra | EX: ✗
  Q   : Return the names of conductors that do not have the nationality "USA"
  Pred: SELECT Name FROM conductor WHERE Nationality > "USA"
  Gold: SELECT Name FROM conductor WHERE Nationality <> 'USA'
  Type: SIMPLE

[552] OTHER | DB: orchestra | EX: ✗
  Q   : What are the maximum and minimum share of performances whose type is not "Live final"
  Pred: SELECT MAX(Share), MIN(Share) FROM performance WHERE TYPE > "Live final"
  Gold: SELECT MAX(SHARE), MIN(SHARE) FROM performance WHERE TYPE <> "Live final"
  Type: AGGREGATION

[553] OTHER | DB: orchestra | EX: ✗
  Q   : Return the maximum and minimum shares for performances that do not have the type "Live final"
  Pred: SELECT MAX(Share), MIN(Share) FROM performance WHERE TYPE > "Live final"
  Gold: SELECT MAX(SHARE), MIN(SHARE) FROM performance WHERE TYPE <> "Live final"
  Type: AGGREGATION

[554] WRONG_COLUMNS | DB: orchestra | EX: ✗
  Q   : Show the names of conductors and the orchestras they have conducted
  Pred: SELECT T1.name, T1.orchestra FROM conductor AS T1 JOIN orchestra AS T2 ON T1.orchestra_id = T2.orchestra_id
  Gold: SELECT T1.Name, T2.Orchestra FROM conductor AS T1 JOIN orchestra AS T2 ON T1.Conductor_ID = T2.Conductor_ID
  Type: JOIN

[555] WRONG_COLUMNS | DB: orchestra | EX: ✗
  Q   : What are the names of conductors as well as the corresonding orchestras that they have conducted
  Pred: SELECT T1.name, T1.name FROM conductor AS T1 JOIN orchestra AS T2 ON T1.conductor_id = T2.orchestra_id
  Gold: SELECT T1.Name, T2.Orchestra FROM conductor AS T1 JOIN orchestra AS T2 ON T1.Conductor_ID = T2.Conductor_ID
  Type: JOIN

[556] OTHER | DB: orchestra | EX: ✗
  Q   : Show the names of conductors that have conducted more than one orchestras
  Pred: SELECT T1.name FROM conductor AS T1 JOIN performance AS T2 ON T1.conductor_id = T2.conductor_id GROUP BY T1.conductor_id HAVING COUNT(*) > 1
  Gold: SELECT T1.Name FROM conductor AS T1 JOIN orchestra AS T2 ON T1.Conductor_ID = T2.Conductor_ID GROUP BY T2.Conductor_ID HAVING COUNT(*) > 1
  Type: JOIN, GROUP_BY, HAVING, AGGREGATION

[557] OTHER | DB: orchestra | EX: ✓
  Q   : What are the names of conductors who have conducted at more than one orchestra
  Pred: SELECT T1.name FROM conductor AS T1 JOIN orchestra AS T2 ON T1.conductor_id = T2.conductor_id GROUP BY T1.conductor_id HAVING COUNT(*) > 1
  Gold: SELECT T1.Name FROM conductor AS T1 JOIN orchestra AS T2 ON T1.Conductor_ID = T2.Conductor_ID GROUP BY T2.Conductor_ID HAVING COUNT(*) > 1
  Type: JOIN, GROUP_BY, HAVING, AGGREGATION

[558] OTHER | DB: orchestra | EX: ✗
  Q   : Show the name of the conductor that has conducted the most number of orchestras
  Pred: SELECT T1.name FROM conductor AS T1 JOIN performance AS T2 ON T1.conductor_id = T2.conductor_id GROUP BY T1.conductor_id ORDER BY COUNT(*) DESC LIMIT 1
  Gold: SELECT T1.Name FROM conductor AS T1 JOIN orchestra AS T2 ON T1.Conductor_ID = T2.Conductor_ID GROUP BY T2.Conductor_ID ORDER BY COUNT(*) DESC LIMIT 1
  Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, AGGREGATION

[559] OTHER | DB: orchestra | EX: ✓
  Q   : What is the name of the conductor who has conducted the most orchestras
  Pred: SELECT T1.name FROM conductor AS T1 JOIN orchestra AS T2 ON T1.conductor_id = T2.conductor_id GROUP BY T1.conductor_id ORDER BY COUNT(*) DESC LIMIT 1
  Gold: SELECT T1.Name FROM conductor AS T1 JOIN orchestra AS T2 ON T1.Conductor_ID = T2.Conductor_ID GROUP BY T2.Conductor_ID ORDER BY COUNT(*) DESC LIMIT 1
  Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, AGGREGATION

[560] WRONG_TABLE | DB: orchestra | EX: ✓
  Q   : Please show the name of the conductor that has conducted orchestras founded after 2008
  Pred: SELECT T2.Name FROM orchestra AS T1 JOIN conductor AS T2 ON T1.Conductor_ID = T2.Conductor_ID WHERE T1.Year_of_founded > 2008
  Gold: SELECT T1.Name FROM conductor AS T1 JOIN orchestra AS T2 ON T1.Conductor_ID = T2.Conductor_ID WHERE Year_of_Founded > 2008
  Type: JOIN

[561] MISSING_JOIN | DB: orchestra | EX: ✗
  Q   : What are the names of conductors who have conducted orchestras founded after the year 2008
  Pred: SELECT Name FROM conductor WHERE YEAR_of_founded > 2008
  Gold: SELECT T1.Name FROM conductor AS T1 JOIN orchestra AS T2 ON T1.Conductor_ID = T2.Conductor_ID WHERE Year_of_Founded > 2008
  Type: JOIN

[562] MISSING_GROUP_BY | DB: orchestra | EX: ✗
  Q   : Please show the record formats of orchestras in ascending order of count
  Pred: SELECT Major_Record_Format FROM orchestra ORDER BY Major_Record_Format ASC
  Gold: SELECT Major_Record_Format FROM orchestra GROUP BY Major_Record_Format ORDER BY COUNT(*) ASC
  Type: GROUP_BY, ORDER_BY, AGGREGATION

[563] MISSING_GROUP_BY | DB: orchestra | EX: ✗
  Q   : What are the major record formats of orchestras, sorted by their frequency
  Pred: SELECT Major_Record_format FROM orchestra ORDER BY Major_Record_format
  Gold: SELECT Major_Record_Format FROM orchestra GROUP BY Major_Record_Format ORDER BY COUNT(*) ASC
  Type: GROUP_BY, ORDER_BY, AGGREGATION

[564] EXTRA_JOIN | DB: orchestra | EX: ✗
  Q   : List the names of orchestras that have no performance
  Pred: SELECT orchestra FROM orchestra EXCEPT SELECT T1.orchestra FROM performance AS T1 JOIN orchestra AS T2 ON T1.orchestra_id = T2.orchestra_id
  Gold: SELECT Orchestra FROM orchestra WHERE NOT Orchestra_ID IN (SELECT Orchestra_ID FROM performance)
  Type: NESTED

[565] MISSING_WHERE | DB: orchestra | EX: ✗
  Q   : What are the orchestras that do not have any performances
  Pred: SELECT Orchestra FROM orchestra EXCEPT SELECT Orchestra FROM performance
  Gold: SELECT Orchestra FROM orchestra WHERE NOT Orchestra_ID IN (SELECT Orchestra_ID FROM performance)
  Type: NESTED

[566] WRONG_TABLE | DB: orchestra | EX: ✗
  Q   : Show the record companies shared by orchestras founded before 2003 and after 2003
  Pred: SELECT Record_Company FROM orchestra WHERE YEAR_Of_Founded  2003 INTERSECT SELECT Record_Company FROM performance WHERE YEAR_Of_Founded > 2003
  Gold: SELECT Record_Company FROM orchestra WHERE Year_of_Founded < 2003 INTERSECT SELECT Record_Company FROM orchestra WHERE Year_of_Founded > 2003
  Type: SIMPLE

[567] OTHER | DB: orchestra | EX: ✗
  Q   : What are the record companies that are used by both orchestras founded before 2003 and those founded after 2003
  Pred: SELECT record_company FROM orchestra WHERE YEAR_of_founded  2003 INTERSECT SELECT record_company FROM orchestra WHERE YEAR_of_founded > 2003
  Gold: SELECT Record_Company FROM orchestra WHERE Year_of_Founded < 2003 INTERSECT SELECT Record_Company FROM orchestra WHERE Year_of_Founded > 2003
  Type: SIMPLE

[568] OTHER | DB: orchestra | EX: ✗
  Q   : Count the number of orchestras that have CD or DVD as their record format
  Pred: SELECT COUNT(*) FROM orchestra WHERE record_format = 'CD' OR record_format = 'DVD'
  Gold: SELECT COUNT(*) FROM orchestra WHERE Major_Record_Format = "CD" OR Major_Record_Format = "DVD"
  Type: AGGREGATION

[569] MISSING_JOIN | DB: orchestra | EX: ✗
  Q   : Show the years in which orchestras that have given more than one performance are founded
  Pred: SELECT year_of_founded FROM orchestra GROUP BY year_of_founded HAVING COUNT(*) > 1
  Gold: SELECT Year_of_Founded FROM orchestra AS T1 JOIN performance AS T2 ON T1.Orchestra_ID = T2.Orchestra_ID GROUP BY T2.Orchestra_ID HAVING COUNT(*) > 1
  Type: JOIN, GROUP_BY, HAVING, AGGREGATION

[570] MISSING_JOIN | DB: orchestra | EX: ✗
  Q   : What are years of founding for orchestras that have had more than a single performance
  Pred: SELECT year_of_founded FROM orchestra GROUP BY year_of_founded HAVING COUNT(*) > 1
  Gold: SELECT Year_of_Founded FROM orchestra AS T1 JOIN performance AS T2 ON T1.Orchestra_ID = T2.Orchestra_ID GROUP BY T2.Orchestra_ID HAVING COUNT(*) > 1
  Type: JOIN, GROUP_BY, HAVING, AGGREGATION

[571] WRONG_COLUMNS | DB: network_1 | EX: ✗
  Q   : What is the grade of each high schooler
  Pred: SELECT DISTINCT grade FROM highschooler
  Gold: SELECT grade FROM Highschooler
  Type: SIMPLE

[572] WRONG_COLUMNS | DB: network_1 | EX: ✗
  Q   : What is Kyle's id
  Pred: SELECT student_id FROM highschooler WHERE name = "Kyle"
  Gold: SELECT ID FROM Highschooler WHERE name = "Kyle"
  Type: SIMPLE

[573] WRONG_COLUMNS | DB: network_1 | EX: ✓
  Q   : Show me all grades that have at least 4 students
  Pred: SELECT DISTINCT grade FROM highschooler GROUP BY grade HAVING COUNT(*) >= 4
  Gold: SELECT grade FROM Highschooler GROUP BY grade HAVING COUNT(*) >= 4
  Type: GROUP_BY, HAVING, AGGREGATION

[574] WRONG_COLUMNS | DB: network_1 | EX: ✗
  Q   : Show the student IDs and numbers of friends corresponding to each
  Pred: SELECT student_id, friend_id FROM friend GROUP BY friend_id
  Gold: SELECT student_id, COUNT(*) FROM Friend GROUP BY student_id
  Type: GROUP_BY, AGGREGATION

[575] EXTRA_JOIN | DB: network_1 | EX: ✗
  Q   : How many friends does each student have
  Pred: SELECT COUNT(*), T1.friend_id FROM friend AS T1 JOIN likes AS T2 ON T1.student_id = T2.liked_id GROUP BY T1.student_id
  Gold: SELECT student_id, COUNT(*) FROM Friend GROUP BY student_id
  Type: GROUP_BY, AGGREGATION

[576] WRONG_TABLE | DB: network_1 | EX: ✗
  Q   : Show the names of high school students and their corresponding number of friends
  Pred: SELECT name, COUNT(*) FROM highschooler GROUP BY name
  Gold: SELECT T2.name, COUNT(*) FROM Friend AS T1 JOIN Highschooler AS T2 ON T1.student_id = T2.id GROUP BY T1.student_id
  Type: JOIN, GROUP_BY, AGGREGATION

[577] WRONG_TABLE | DB: network_1 | EX: ✗
  Q   : What are the names of the high schoolers and how many friends does each have
  Pred: SELECT name, COUNT(*) FROM highschooler GROUP BY name
  Gold: SELECT T2.name, COUNT(*) FROM Friend AS T1 JOIN Highschooler AS T2 ON T1.student_id = T2.id GROUP BY T1.student_id
  Type: JOIN, GROUP_BY, AGGREGATION

[578] WRONG_TABLE | DB: network_1 | EX: ✗
  Q   : What is the name of the high schooler who has the greatest number of friends
  Pred: SELECT name FROM highschooler ORDER BY friend_id DESC LIMIT 1
  Gold: SELECT T2.name FROM Friend AS T1 JOIN Highschooler AS T2 ON T1.student_id = T2.id GROUP BY T1.student_id ORDER BY COUNT(*) DESC LIMIT 1
  Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, AGGREGATION

[579] WRONG_TABLE | DB: network_1 | EX: ✗
  Q   : Return the name of the high school student with the most friends
  Pred: SELECT name FROM highschooler ORDER BY friend_id DESC LIMIT 1
  Gold: SELECT T2.name FROM Friend AS T1 JOIN Highschooler AS T2 ON T1.student_id = T2.id GROUP BY T1.student_id ORDER BY COUNT(*) DESC LIMIT 1
  Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, AGGREGATION

[580] WRONG_TABLE | DB: network_1 | EX: ✗
  Q   : Show the names of high schoolers who have at least 3 friends
  Pred: SELECT name FROM highschooler GROUP BY name HAVING COUNT(*) >= 3
  Gold: SELECT T2.name FROM Friend AS T1 JOIN Highschooler AS T2 ON T1.student_id = T2.id GROUP BY T1.student_id HAVING COUNT(*) >= 3
  Type: JOIN, GROUP_BY, HAVING, AGGREGATION

[581] WRONG_TABLE | DB: network_1 | EX: ✗
  Q   : What are the names of high schoolers who have 3 or more friends
  Pred: SELECT name FROM highschooler GROUP BY name HAVING COUNT(*) >= 3
  Gold: SELECT T2.name FROM Friend AS T1 JOIN Highschooler AS T2 ON T1.student_id = T2.id GROUP BY T1.student_id HAVING COUNT(*) >= 3
  Type: JOIN, GROUP_BY, HAVING, AGGREGATION

[582] WRONG_COLUMNS | DB: network_1 | EX: ✗
  Q   : Show the names of all of the high schooler Kyle's friends
  Pred: SELECT name FROM friend AS T1 JOIN highschooler AS T2 ON T1.id = T2.friend_id WHERE T2.name = 'Kyle'
  Gold: SELECT T3.name FROM Friend AS T1 JOIN Highschooler AS T2 ON T1.student_id = T2.id JOIN Highschooler AS T3 ON T1.friend_id = T3.id WHERE T2.name = "Kyle"
  Type: JOIN

[583] WRONG_COLUMNS | DB: network_1 | EX: ✗
  Q   : Return the names of friends of the high school student Kyle
  Pred: SELECT T1.name FROM friend AS T1 JOIN highschooler AS T2 ON T1.friend_id = T2.friend_id WHERE T2.student_id = 'Kyle'
  Gold: SELECT T3.name FROM Friend AS T1 JOIN Highschooler AS T2 ON T1.student_id = T2.id JOIN Highschooler AS T3 ON T1.friend_id = T3.id WHERE T2.name = "Kyle"
  Type: JOIN

[584] OTHER | DB: network_1 | EX: ✗
  Q   : How many friends does the high school student Kyle have
  Pred: SELECT COUNT(*) FROM friend AS T1 JOIN highschooler AS T2 ON T1.id = T2.friend_id WHERE T2.name = "Kyle"
  Gold: SELECT COUNT(*) FROM Friend AS T1 JOIN Highschooler AS T2 ON T1.student_id = T2.id WHERE T2.name = "Kyle"
  Type: JOIN, AGGREGATION

[585] OTHER | DB: network_1 | EX: ✗
  Q   : Count the number of friends Kyle has
  Pred: SELECT COUNT(*) FROM friend AS T1 JOIN friend AS T2 ON T1.friend_id = T2.friend_id WHERE T2.name = "Kyle"
  Gold: SELECT COUNT(*) FROM Friend AS T1 JOIN Highschooler AS T2 ON T1.student_id = T2.id WHERE T2.name = "Kyle"
  Type: JOIN, AGGREGATION

[586] WRONG_TABLE | DB: network_1 | EX: ✗
  Q   : Show ids of all students who do not have any friends
  Pred: SELECT student_id FROM friend EXCEPT SELECT student_id FROM friend
  Gold: SELECT id FROM Highschooler EXCEPT SELECT student_id FROM Friend
  Type: SIMPLE

[587] WRONG_COLUMNS | DB: network_1 | EX: ✗
  Q   : What are the ids of high school students who do not have friends
  Pred: SELECT student_id FROM friend EXCEPT SELECT student_id FROM highschooler
  Gold: SELECT id FROM Highschooler EXCEPT SELECT student_id FROM Friend
  Type: SIMPLE

[588] MISSING_JOIN | DB: network_1 | EX: ✗
  Q   : Show names of all high school students who do not have any friends
  Pred: SELECT name FROM highschooler WHERE NOT student_id IN (SELECT student_id FROM friend)
  Gold: SELECT name FROM Highschooler EXCEPT SELECT T2.name FROM Friend AS T1 JOIN Highschooler AS T2 ON T1.student_id = T2.id
  Type: JOIN

[589] WRONG_TABLE | DB: network_1 | EX: ✗
  Q   : What are the names of students who have no friends
  Pred: SELECT name FROM students WHERE NOT student_id IN (SELECT student_id FROM friend)
  Gold: SELECT name FROM Highschooler EXCEPT SELECT T2.name FROM Friend AS T1 JOIN Highschooler AS T2 ON T1.student_id = T2.id
  Type: JOIN

[590] WRONG_COLUMNS | DB: network_1 | EX: ✗
  Q   : Show the ids of high schoolers who have friends and are also liked by someone else
  Pred: SELECT id FROM friend EXCEPT SELECT id FROM likes
  Gold: SELECT student_id FROM Friend INTERSECT SELECT liked_id FROM Likes
  Type: SIMPLE

[591] WRONG_COLUMNS | DB: network_1 | EX: ✗
  Q   : What are the ids of students who both have friends and are liked
  Pred: SELECT student_id FROM friend INTERSECT SELECT student_id FROM likes
  Gold: SELECT student_id FROM Friend INTERSECT SELECT liked_id FROM Likes
  Type: SIMPLE

[592] WRONG_TABLE | DB: network_1 | EX: ✗
  Q   : Show name of all students who have some friends and also are liked by someone else
  Pred: SELECT T1.name FROM friend AS T1 JOIN likes AS T2 ON T1.student_id = T2.liked_id GROUP BY T1.student_id HAVING COUNT(*) >= 1
  Gold: SELECT T2.name FROM Friend AS T1 JOIN Highschooler AS T2 ON T1.student_id = T2.id INTERSECT SELECT T2.name FROM Likes AS T1 JOIN Highschooler AS T2 ON T1.liked_id = T2.id
  Type: JOIN

[593] WRONG_TABLE | DB: network_1 | EX: ✗
  Q   : What are the names of high schoolers who both have friends and are liked
  Pred: SELECT T1.name FROM highschooler AS T1 JOIN friend AS T2 ON T1.id = T2.friend_id JOIN likes AS T3 ON T2.liked_id = T3.liked_id
  Gold: SELECT T2.name FROM Friend AS T1 JOIN Highschooler AS T2 ON T1.student_id = T2.id INTERSECT SELECT T2.name FROM Likes AS T1 JOIN Highschooler AS T2 ON T1.liked_id = T2.id
  Type: JOIN

[594] WRONG_COLUMNS | DB: network_1 | EX: ✗
  Q   : Count the number of likes for each student id
  Pred: SELECT COUNT(*), liked_id FROM likes GROUP BY student_id
  Gold: SELECT student_id, COUNT(*) FROM Likes GROUP BY student_id
  Type: GROUP_BY, AGGREGATION

[595] WRONG_COLUMNS | DB: network_1 | EX: ✗
  Q   : How many likes correspond to each student id
  Pred: SELECT COUNT(*), liked_id FROM likes GROUP BY liked_id
  Gold: SELECT student_id, COUNT(*) FROM Likes GROUP BY student_id
  Type: GROUP_BY, AGGREGATION

[596] WRONG_TABLE | DB: network_1 | EX: ✗
  Q   : Show the names of high schoolers who have likes, and numbers of likes for each
  Pred: SELECT name, COUNT(*) FROM highschooler GROUP BY name
  Gold: SELECT T2.name, COUNT(*) FROM Likes AS T1 JOIN Highschooler AS T2 ON T1.student_id = T2.id GROUP BY T1.student_id
  Type: JOIN, GROUP_BY, AGGREGATION

[597] WRONG_TABLE | DB: network_1 | EX: ✗
  Q   : What are the names of high schoolers who have likes, and how many likes does each have
  Pred: SELECT name, COUNT(*) FROM highschooler GROUP BY name
  Gold: SELECT T2.name, COUNT(*) FROM Likes AS T1 JOIN Highschooler AS T2 ON T1.student_id = T2.id GROUP BY T1.student_id
  Type: JOIN, GROUP_BY, AGGREGATION

[598] WRONG_TABLE | DB: network_1 | EX: ✗
  Q   : What is the name of the high schooler who has the greatest number of likes
  Pred: SELECT name FROM highschooler ORDER BY liked_id DESC LIMIT 1
  Gold: SELECT T2.name FROM Likes AS T1 JOIN Highschooler AS T2 ON T1.student_id = T2.id GROUP BY T1.student_id ORDER BY COUNT(*) DESC LIMIT 1
  Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, AGGREGATION

[599] WRONG_COLUMNS | DB: network_1 | EX: ✗
  Q   : Give the name of the student with the most likes
  Pred: SELECT T1.name FROM likes AS T1 JOIN friend AS T2 ON T1.student_id = T2.student_id GROUP BY T1.student_id ORDER BY COUNT(*) DESC LIMIT 1
  Gold: SELECT T2.name FROM Likes AS T1 JOIN Highschooler AS T2 ON T1.student_id = T2.id GROUP BY T1.student_id ORDER BY COUNT(*) DESC LIMIT 1
  Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, AGGREGATION

[600] MISSING_JOIN | DB: network_1 | EX: ✗
  Q   : Show the names of students who have at least 2 likes
  Pred: SELECT Name FROM likes GROUP BY Name HAVING COUNT(*) >= 2
  Gold: SELECT T2.name FROM Likes AS T1 JOIN Highschooler AS T2 ON T1.student_id = T2.id GROUP BY T1.student_id HAVING COUNT(*) >= 2
  Type: JOIN, GROUP_BY, HAVING, AGGREGATION

[601] MISSING_JOIN | DB: network_1 | EX: ✗
  Q   : What are the names of students who have 2 or more likes
  Pred: SELECT name FROM likes GROUP BY student_id HAVING COUNT(*) >= 2
  Gold: SELECT T2.name FROM Likes AS T1 JOIN Highschooler AS T2 ON T1.student_id = T2.id GROUP BY T1.student_id HAVING COUNT(*) >= 2
  Type: JOIN, GROUP_BY, HAVING, AGGREGATION

[602] WRONG_TABLE | DB: network_1 | EX: ✗
  Q   : Show the names of students who have a grade higher than 5 and have at least 2 friends
  Pred: SELECT name FROM highschooler WHERE grade > 5 AND friend_id > 2
  Gold: SELECT T2.name FROM Friend AS T1 JOIN Highschooler AS T2 ON T1.student_id = T2.id WHERE T2.grade > 5 GROUP BY T1.student_id HAVING COUNT(*) >= 2
  Type: JOIN, GROUP_BY, HAVING, AGGREGATION

[603] WRONG_TABLE | DB: network_1 | EX: ✗
  Q   : What are the names of high schoolers who have a grade of over 5 and have 2 or more friends
  Pred: SELECT name FROM highschooler WHERE grade > 5 INTERSECT SELECT name FROM friend WHERE grade > 2
  Gold: SELECT T2.name FROM Friend AS T1 JOIN Highschooler AS T2 ON T1.student_id = T2.id WHERE T2.grade > 5 GROUP BY T1.student_id HAVING COUNT(*) >= 2
  Type: JOIN, GROUP_BY, HAVING, AGGREGATION

[604] OTHER | DB: network_1 | EX: ✗
  Q   : How many likes does Kyle have
  Pred: SELECT COUNT(*) FROM likes AS T1 JOIN friend AS T2 ON T1.liked_id = T2.liked_id WHERE T2.name = "Kyle"
  Gold: SELECT COUNT(*) FROM Likes AS T1 JOIN Highschooler AS T2 ON T1.student_id = T2.id WHERE T2.name = "Kyle"
  Type: JOIN, AGGREGATION

[605] OTHER | DB: network_1 | EX: ✗
  Q   : Return the number of likes that the high schooler named Kyle has
  Pred: SELECT COUNT(*) FROM likes AS T1 JOIN highschooler AS T2 ON T1.id = T2.liked_id WHERE T2.name = 'Kyle'
  Gold: SELECT COUNT(*) FROM Likes AS T1 JOIN Highschooler AS T2 ON T1.student_id = T2.id WHERE T2.name = "Kyle"
  Type: JOIN, AGGREGATION

[606] WRONG_TABLE | DB: network_1 | EX: ✗
  Q   : Find the average grade of all students who have some friends
  Pred: SELECT AVG(grade) FROM friend
  Gold: SELECT AVG(grade) FROM Highschooler WHERE id IN (SELECT T1.student_id FROM Friend AS T1 JOIN Highschooler AS T2 ON T1.student_id = T2.id)
  Type: JOIN, NESTED, AGGREGATION

[607] WRONG_TABLE | DB: network_1 | EX: ✗
  Q   : What is the average grade of students who have friends
  Pred: SELECT AVG(grade) FROM friend
  Gold: SELECT AVG(grade) FROM Highschooler WHERE id IN (SELECT T1.student_id FROM Friend AS T1 JOIN Highschooler AS T2 ON T1.student_id = T2.id)
  Type: JOIN, NESTED, AGGREGATION

[608] WRONG_TABLE | DB: network_1 | EX: ✗
  Q   : Find the minimum grade of students who have no friends
  Pred: SELECT MIN(grade) FROM friend WHERE NOT student_id IN (SELECT student_id FROM friend)
  Gold: SELECT MIN(grade) FROM Highschooler WHERE NOT id IN (SELECT T1.student_id FROM Friend AS T1 JOIN Highschooler AS T2 ON T1.student_id = T2.id)
  Type: JOIN, NESTED, AGGREGATION

[609] WRONG_TABLE | DB: network_1 | EX: ✗
  Q   : What is the lowest grade of students who do not have any friends
  Pred: SELECT MIN(grade) FROM student WHERE NOT student_id IN (SELECT student_id FROM friend)
  Gold: SELECT MIN(grade) FROM Highschooler WHERE NOT id IN (SELECT T1.student_id FROM Friend AS T1 JOIN Highschooler AS T2 ON T1.student_id = T2.id)
  Type: JOIN, NESTED, AGGREGATION

[610] WRONG_TABLE | DB: dog_kennels | EX: ✗
  Q   : Which states have both owners and professionals living there
  Pred: SELECT state FROM professionals GROUP BY state HAVING COUNT(*) = 1
  Gold: SELECT state FROM Owners INTERSECT SELECT state FROM Professionals
  Type: SIMPLE

[611] WRONG_TABLE | DB: dog_kennels | EX: ✗
  Q   : Find the states where both owners and professionals live
  Pred: SELECT state FROM professionals GROUP BY state HAVING COUNT(*) = 1
  Gold: SELECT state FROM Owners INTERSECT SELECT state FROM Professionals
  Type: SIMPLE

[612] WRONG_TABLE | DB: dog_kennels | EX: ✗
  Q   : What is the average age of the dogs who have gone through any treatments
  Pred: SELECT AVG(age) FROM dogs
  Gold: SELECT AVG(age) FROM Dogs WHERE dog_id IN (SELECT dog_id FROM Treatments)
  Type: NESTED, AGGREGATION

[613] WRONG_TABLE | DB: dog_kennels | EX: ✗
  Q   : Find the average age of the dogs who went through treatments
  Pred: SELECT AVG(age) FROM dogs
  Gold: SELECT AVG(age) FROM Dogs WHERE dog_id IN (SELECT dog_id FROM Treatments)
  Type: NESTED, AGGREGATION

[614] MISSING_GROUP_BY | DB: dog_kennels | EX: ✗
  Q   : Which professionals live in the state of Indiana or have done treatment on more than 2 treatments? List his or her id, last name and cell phone
  Pred: SELECT T1.professional_id, T1.last_name, T2.home_phone FROM professionals AS T1 JOIN treatments AS T2 ON T1.professional_id = T2.professional_id WHERE T2.state = "Indiana" OR T2.cost_of_treatment > 2
  Gold: SELECT professional_id, last_name, cell_number FROM Professionals WHERE state = 'Indiana' UNION SELECT T1.professional_id, T1.last_name, T1.cell_number FROM Professionals AS T1 JOIN Treatments AS T2 ON T1.professional_id = T2.professional_id GROUP BY T1.professional_id HAVING COUNT(*) > 2
  Type: JOIN, GROUP_BY, HAVING, AGGREGATION

[615] MISSING_GROUP_BY | DB: dog_kennels | EX: ✗
  Q   : Find the id, last name and cell phone of the professionals who live in the state of Indiana or have performed more than two treatments
  Pred: SELECT T1.professional_id, T1.last_name, T1.home_phone FROM professionals AS T1 JOIN treatments AS T2 ON T1.professional_id = T2.professional_id WHERE T2.state = "Indiana" OR T2.state > 2
  Gold: SELECT professional_id, last_name, cell_number FROM Professionals WHERE state = 'Indiana' UNION SELECT T1.professional_id, T1.last_name, T1.cell_number FROM Professionals AS T1 JOIN Treatments AS T2 ON T1.professional_id = T2.professional_id GROUP BY T1.professional_id HAVING COUNT(*) > 2
  Type: JOIN, GROUP_BY, HAVING, AGGREGATION

[616] WRONG_TABLE | DB: dog_kennels | EX: ✗
  Q   : Which dogs have not cost their owner more than 1000 for treatment ? List the dog names
  Pred: SELECT T1.name FROM owners AS T1 JOIN treatments AS T2 ON T1.owner_id = T2.owner_id WHERE T2.cost_of_treatment  1000
  Gold: SELECT name FROM dogs WHERE NOT dog_id IN (SELECT dog_id FROM treatments GROUP BY dog_id HAVING SUM(cost_of_treatment) > 1000)
  Type: GROUP_BY, HAVING, NESTED, AGGREGATION

[617] WRONG_TABLE | DB: dog_kennels | EX: ✗
  Q   : What are the names of the dogs for which the owner has not spend more than 1000 for treatment
  Pred: SELECT T1.name FROM dogs AS T1 JOIN treatments AS T2 ON T1.dog_id = T2.dog_id WHERE T2.cost_of_treatment  1000
  Gold: SELECT name FROM dogs WHERE NOT dog_id IN (SELECT dog_id FROM treatments GROUP BY dog_id HAVING SUM(cost_of_treatment) > 1000)
  Type: GROUP_BY, HAVING, NESTED, AGGREGATION

[618] WRONG_TABLE | DB: dog_kennels | EX: ✗
  Q   : Which first names are used for professionals or owners but are not used as dog names
  Pred: SELECT first_name FROM professionals EXCEPT SELECT t1.first_name FROM owners AS t1 JOIN dogs AS t2 ON t1.owner_id = t2.owner_id
  Gold: SELECT first_name FROM Professionals UNION SELECT first_name FROM Owners EXCEPT SELECT name FROM Dogs
  Type: SIMPLE

[619] WRONG_TABLE | DB: dog_kennels | EX: ✗
  Q   : Find the first names that are used for professionals or owners but are not used as dog names
  Pred: SELECT first_name FROM professionals EXCEPT SELECT t1.first_name FROM owners AS t1 JOIN dogs AS t2 ON t1.owner_id = t2.owner_id JOIN treatments AS t3 ON t2.professional_id = t3.professional_id
  Gold: SELECT first_name FROM Professionals UNION SELECT first_name FROM Owners EXCEPT SELECT name FROM Dogs
  Type: SIMPLE

[620] WRONG_TABLE | DB: dog_kennels | EX: ✗
  Q   : Which professional did not operate any treatment on dogs? List the professional's id, role and email
  Pred: SELECT professional_id, role_code, email_address FROM treatments WHERE NOT professional_id IN (SELECT professional_id FROM treatments WHERE dog_id = 'Dog')
  Gold: SELECT professional_id, role_code, email_address FROM Professionals EXCEPT SELECT T1.professional_id, T1.role_code, T1.email_address FROM Professionals AS T1 JOIN Treatments AS T2 ON T1.professional_id = T2.professional_id
  Type: JOIN

[621] WRONG_COLUMNS | DB: dog_kennels | EX: ✗
  Q   : Give me the id, role and email of the professionals who did not perform any treatment on dogs
  Pred: SELECT T1.professional_id, T1.role_code, T1.email_address FROM professionals AS T1 JOIN treatments AS T2 ON T1.professional_id = T2.professional_id GROUP BY T1.professional_id HAVING COUNT(*) >= 1
  Gold: SELECT professional_id, role_code, email_address FROM Professionals EXCEPT SELECT T1.professional_id, T1.role_code, T1.email_address FROM Professionals AS T1 JOIN Treatments AS T2 ON T1.professional_id = T2.professional_id
  Type: JOIN

[622] WRONG_TABLE | DB: dog_kennels | EX: ✓
  Q   : Which owner owns the most dogs? List the owner id, first name and last name
  Pred: SELECT T1.owner_id, T1.first_name, T1.last_name FROM owners AS T1 JOIN dogs AS T2 ON T1.owner_id = T2.owner_id GROUP BY T1.owner_id ORDER BY COUNT(*) DESC LIMIT 1
  Gold: SELECT T1.owner_id, T2.first_name, T2.last_name FROM Dogs AS T1 JOIN Owners AS T2 ON T1.owner_id = T2.owner_id GROUP BY T1.owner_id ORDER BY COUNT(*) DESC LIMIT 1
  Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, AGGREGATION

[623] WRONG_TABLE | DB: dog_kennels | EX: ✓
  Q   : Return the owner id, first name and last name of the owner who has the most dogs
  Pred: SELECT T1.owner_id, T1.first_name, T1.last_name FROM owners AS T1 JOIN dogs AS T2 ON T1.owner_id = T2.owner_id GROUP BY T1.owner_id ORDER BY COUNT(*) DESC LIMIT 1
  Gold: SELECT T1.owner_id, T2.first_name, T2.last_name FROM Dogs AS T1 JOIN Owners AS T2 ON T1.owner_id = T2.owner_id GROUP BY T1.owner_id ORDER BY COUNT(*) DESC LIMIT 1
  Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, AGGREGATION

[624] WRONG_TABLE | DB: dog_kennels | EX: ✗
  Q   : Which professionals have done at least two treatments? List the professional's id, role, and first name
  Pred: SELECT professional_id, role_code, first_name FROM treatments GROUP BY professional_id HAVING COUNT(*) >= 2
  Gold: SELECT T1.professional_id, T1.role_code, T1.first_name FROM Professionals AS T1 JOIN Treatments AS T2 ON T1.professional_id = T2.professional_id GROUP BY T1.professional_id HAVING COUNT(*) >= 2
  Type: JOIN, GROUP_BY, HAVING, AGGREGATION

[625] MISSING_JOIN | DB: dog_kennels | EX: ✗
  Q   : What are the id, role, and first name of the professionals who have performed two or more treatments
  Pred: SELECT professional_id, role_code, first_name FROM professionals GROUP BY professional_id HAVING COUNT(*) >= 2
  Gold: SELECT T1.professional_id, T1.role_code, T1.first_name FROM Professionals AS T1 JOIN Treatments AS T2 ON T1.professional_id = T2.professional_id GROUP BY T1.professional_id HAVING COUNT(*) >= 2
  Type: JOIN, GROUP_BY, HAVING, AGGREGATION

[626] MISSING_JOIN | DB: dog_kennels | EX: ✓
  Q   : What is the name of the breed with the most dogs
  Pred: SELECT breed_name FROM breeds GROUP BY breed_code ORDER BY COUNT(*) DESC LIMIT 1
  Gold: SELECT T1.breed_name FROM Breeds AS T1 JOIN Dogs AS T2 ON T1.breed_code = T2.breed_code GROUP BY T1.breed_name ORDER BY COUNT(*) DESC LIMIT 1
  Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, AGGREGATION

[627] OTHER | DB: dog_kennels | EX: ✓
  Q   : Which breed do the most dogs have? Give me the breed name
  Pred: SELECT T1.breed_name FROM breeds AS T1 JOIN dogs AS T2 ON T1.breed_code = T2.breed_code GROUP BY T1.breed_code ORDER BY COUNT(*) DESC LIMIT 1
  Gold: SELECT T1.breed_name FROM Breeds AS T1 JOIN Dogs AS T2 ON T1.breed_code = T2.breed_code GROUP BY T1.breed_name ORDER BY COUNT(*) DESC LIMIT 1
  Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, AGGREGATION

[628] OTHER | DB: dog_kennels | EX: ✗
  Q   : Which owner has paid for the most treatments on his or her dogs? List the owner id and last name
  Pred: SELECT T1.owner_id, T1.last_name FROM owners AS T1 JOIN treatments AS T2 ON T1.owner_id = T2.owner_id GROUP BY T1.owner_id ORDER BY COUNT(*) DESC LIMIT 1
  Gold: SELECT T1.owner_id, T1.last_name FROM Owners AS T1 JOIN Dogs AS T2 ON T1.owner_id = T2.owner_id JOIN Treatments AS T3 ON T2.dog_id = T3.dog_id GROUP BY T1.owner_id ORDER BY COUNT(*) DESC LIMIT 1
  Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, AGGREGATION

[629] OTHER | DB: dog_kennels | EX: ✗
  Q   : Tell me the owner id and last name of the owner who spent the most on treatments of his or her dogs
  Pred: SELECT T1.owner_id, T1.last_name FROM owners AS T1 JOIN treatments AS T2 ON T1.owner_id = T2.owner_id GROUP BY T1.owner_id ORDER BY COUNT(*) DESC LIMIT 1
  Gold: SELECT T1.owner_id, T1.last_name FROM Owners AS T1 JOIN Dogs AS T2 ON T1.owner_id = T2.owner_id JOIN Treatments AS T3 ON T2.dog_id = T3.dog_id GROUP BY T1.owner_id ORDER BY COUNT(*) DESC LIMIT 1
  Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, AGGREGATION

[630] WRONG_TABLE | DB: dog_kennels | EX: ✗
  Q   : What is the description of the treatment type that costs the least money in total
  Pred: SELECT treatment_type_description FROM treatments ORDER BY cost_of_treatment LIMIT 1
  Gold: SELECT T1.treatment_type_description FROM Treatment_types AS T1 JOIN Treatments AS T2 ON T1.treatment_type_code = T2.treatment_type_code GROUP BY T1.treatment_type_code ORDER BY SUM(cost_of_treatment) ASC LIMIT 1
  Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, AGGREGATION

[631] WRONG_TABLE | DB: dog_kennels | EX: ✗
  Q   : Give me the description of the treatment type whose total cost is the lowest
  Pred: SELECT treatment_type_description FROM treatments ORDER BY cost_of_treatment LIMIT 1
  Gold: SELECT T1.treatment_type_description FROM Treatment_types AS T1 JOIN Treatments AS T2 ON T1.treatment_type_code = T2.treatment_type_code GROUP BY T1.treatment_type_code ORDER BY SUM(cost_of_treatment) ASC LIMIT 1
  Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, AGGREGATION

[632] OTHER | DB: dog_kennels | EX: ✗
  Q   : Which owner has paid the largest amount of money in total for their dogs? Show the owner id and zip code
  Pred: SELECT T1.owner_id, T1.zip_code FROM owners AS T1 JOIN dogs AS T2 ON T1.owner_id = T2.owner_id GROUP BY T1.owner_id ORDER BY SUM(T2.charge_amount) DESC LIMIT 1
  Gold: SELECT T1.owner_id, T1.zip_code FROM Owners AS T1 JOIN Dogs AS T2 ON T1.owner_id = T2.owner_id JOIN Treatments AS T3 ON T2.dog_id = T3.dog_id GROUP BY T1.owner_id ORDER BY SUM(T3.cost_of_treatment) DESC LIMIT 1
  Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, AGGREGATION

[633] OTHER | DB: dog_kennels | EX: ✗
  Q   : Find the owner id and zip code of the owner who spent the most money in total for his or her dogs
  Pred: SELECT T1.owner_id, T1.zip_code FROM owners AS T1 JOIN dogs AS T2 ON T1.owner_id = T2.owner_id GROUP BY T1.owner_id ORDER BY SUM(T2.charge_amount) DESC LIMIT 1
  Gold: SELECT T1.owner_id, T1.zip_code FROM Owners AS T1 JOIN Dogs AS T2 ON T1.owner_id = T2.owner_id JOIN Treatments AS T3 ON T2.dog_id = T3.dog_id GROUP BY T1.owner_id ORDER BY SUM(T3.cost_of_treatment) DESC LIMIT 1
  Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, AGGREGATION

[634] WRONG_TABLE | DB: dog_kennels | EX: ✗
  Q   : Which professionals have done at least two types of treatments? List the professional id and cell phone
  Pred: SELECT professional_id, cell_number FROM treatments GROUP BY professional_id HAVING COUNT(*) >= 2
  Gold: SELECT T1.professional_id, T1.cell_number FROM Professionals AS T1 JOIN Treatments AS T2 ON T1.professional_id = T2.professional_id GROUP BY T1.professional_id HAVING COUNT(*) >= 2
  Type: JOIN, GROUP_BY, HAVING, AGGREGATION

[635] WRONG_TABLE | DB: dog_kennels | EX: ✗
  Q   : Find the id and cell phone of the professionals who operate two or more types of treatments
  Pred: SELECT professional_id, cell_number FROM treatments GROUP BY professional_id HAVING COUNT(*) >= 2
  Gold: SELECT T1.professional_id, T1.cell_number FROM Professionals AS T1 JOIN Treatments AS T2 ON T1.professional_id = T2.professional_id GROUP BY T1.professional_id HAVING COUNT(*) >= 2
  Type: JOIN, GROUP_BY, HAVING, AGGREGATION

[636] WRONG_COLUMNS | DB: dog_kennels | EX: ✗
  Q   : What are the first name and last name of the professionals who have done treatment with cost below average
  Pred: SELECT T1.first_name, T1.last_name FROM professionals AS T1 JOIN treatments AS T2 ON T1.professional_id = T2.professional_id WHERE T2.cost_of_treatment  (SELECT AVG(cost_of_treatment) FROM treatments)
  Gold: SELECT DISTINCT T1.first_name, T1.last_name FROM Professionals AS T1 JOIN Treatments AS T2 ON TRUE WHERE cost_of_treatment < (SELECT AVG(cost_of_treatment) FROM Treatments)
  Type: JOIN, NESTED, AGGREGATION

[637] WRONG_COLUMNS | DB: dog_kennels | EX: ✗
  Q   : Which professionals have operated a treatment that costs less than the average? Give me theor first names and last names
  Pred: SELECT T1.first_name, T1.last_name FROM professionals AS T1 JOIN treatments AS T2 ON T1.professional_id = T2.professional_id WHERE T2.cost_of_treatment  (SELECT AVG(cost_of_treatment) FROM treatments)
  Gold: SELECT DISTINCT T1.first_name, T1.last_name FROM Professionals AS T1 JOIN Treatments AS T2 ON TRUE WHERE cost_of_treatment < (SELECT AVG(cost_of_treatment) FROM Treatments)
  Type: JOIN, NESTED, AGGREGATION

[638] MISSING_JOIN | DB: dog_kennels | EX: ✗
  Q   : List the date of each treatment, together with the first name of the professional who operated it
  Pred: SELECT date_of_treatment, first_name FROM treatments GROUP BY date_of_treatment ORDER BY COUNT(*) DESC LIMIT 1
  Gold: SELECT T1.date_of_treatment, T2.first_name FROM Treatments AS T1 JOIN Professionals AS T2 ON T1.professional_id = T2.professional_id
  Type: JOIN

[639] WRONG_COLUMNS | DB: dog_kennels | EX: ✗
  Q   : What are the date and the operating professional's first name of each treatment
  Pred: SELECT T1.date_of_treatment, T1.first_name FROM treatments AS T1 JOIN professionals AS T2 ON T1.professional_id = T2.professional_id
  Gold: SELECT T1.date_of_treatment, T2.first_name FROM Treatments AS T1 JOIN Professionals AS T2 ON T1.professional_id = T2.professional_id
  Type: JOIN

[640] WRONG_COLUMNS | DB: dog_kennels | EX: ✗
  Q   : List the cost of each treatment and the corresponding treatment type description
  Pred: SELECT T1.cost_of_treatment, T1.treatment_type_description FROM treatments AS T1 JOIN treatment_types AS T2 ON T1.treatment_type_code = T2.treatment_type_code
  Gold: SELECT T1.cost_of_treatment, T2.treatment_type_description FROM Treatments AS T1 JOIN treatment_types AS T2 ON T1.treatment_type_code = T2.treatment_type_code
  Type: JOIN

[641] WRONG_COLUMNS | DB: dog_kennels | EX: ✗
  Q   : What are the cost and treatment type description of each treatment
  Pred: SELECT T1.cost_of_treatment, T1.treatment_type_description FROM treatments AS T1 JOIN treatment_types AS T2 ON T1.treatment_type_code = T2.treatment_type_code
  Gold: SELECT T1.cost_of_treatment, T2.treatment_type_description FROM Treatments AS T1 JOIN treatment_types AS T2 ON T1.treatment_type_code = T2.treatment_type_code
  Type: JOIN

[642] WRONG_COLUMNS | DB: dog_kennels | EX: ✗
  Q   : List each owner's first name, last name, and the size of his for her dog
  Pred: SELECT T1.first_name, T1.last_name, T1.size_code FROM owners AS T1 JOIN dogs AS T2 ON T1.owner_id = T2.owner_id GROUP BY T1.owner_id
  Gold: SELECT T1.first_name, T1.last_name, T2.size_code FROM Owners AS T1 JOIN Dogs AS T2 ON T1.owner_id = T2.owner_id
  Type: JOIN

[643] WRONG_COLUMNS | DB: dog_kennels | EX: ✗
  Q   : What are each owner's first name, last name, and the size of their dog
  Pred: SELECT T1.first_name, T1.last_name, T1.size_code FROM owners AS T1 JOIN dogs AS T2 ON T1.owner_id = T2.owner_id GROUP BY T1.owner_id
  Gold: SELECT T1.first_name, T1.last_name, T2.size_code FROM Owners AS T1 JOIN Dogs AS T2 ON T1.owner_id = T2.owner_id
  Type: JOIN

[644] WRONG_COLUMNS | DB: dog_kennels | EX: ✗
  Q   : List pairs of the owner's first name and the dogs's name
  Pred: SELECT T1.first_name, T1.last_name FROM owners AS T1 JOIN dogs AS T2 ON T1.owner_id = T2.owner_id
  Gold: SELECT T1.first_name, T2.name FROM Owners AS T1 JOIN Dogs AS T2 ON T1.owner_id = T2.owner_id
  Type: JOIN

[645] WRONG_COLUMNS | DB: dog_kennels | EX: ✗
  Q   : What are each owner's first name and their dogs's name
  Pred: SELECT T1.first_name, T1.last_name FROM owners AS T1 JOIN dogs AS T2 ON T1.owner_id = T2.owner_id
  Gold: SELECT T1.first_name, T2.name FROM Owners AS T1 JOIN Dogs AS T2 ON T1.owner_id = T2.owner_id
  Type: JOIN

[646] MISSING_JOIN | DB: dog_kennels | EX: ✗
  Q   : List the names of the dogs of the rarest breed and the treatment dates of them
  Pred: SELECT name, date_of_treatment FROM dogs ORDER BY date_adopted DESC LIMIT 1
  Gold: SELECT T1.name, T2.date_of_treatment FROM Dogs AS T1 JOIN Treatments AS T2 ON T1.dog_id = T2.dog_id WHERE T1.breed_code = (SELECT breed_code FROM Dogs GROUP BY breed_code ORDER BY COUNT(*) ASC LIMIT 1)
  Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, NESTED, AGGREGATION

[647] MISSING_JOIN | DB: dog_kennels | EX: ✗
  Q   : Which dogs are of the rarest breed? Show their names and treatment dates
  Pred: SELECT name, date_adopted FROM dogs ORDER BY date_adopted DESC LIMIT 1
  Gold: SELECT T1.name, T2.date_of_treatment FROM Dogs AS T1 JOIN Treatments AS T2 ON T1.dog_id = T2.dog_id WHERE T1.breed_code = (SELECT breed_code FROM Dogs GROUP BY breed_code ORDER BY COUNT(*) ASC LIMIT 1)
  Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, NESTED, AGGREGATION

[648] WRONG_COLUMNS | DB: dog_kennels | EX: ✗
  Q   : Which dogs are owned by someone who lives in Virginia? List the owner's first name and the dog's name
  Pred: SELECT T1.first_name, T1.last_name FROM owners AS T1 JOIN dogs AS T2 ON T1.owner_id = T2.owner_id WHERE T1.city = "Virginia"
  Gold: SELECT T1.first_name, T2.name FROM Owners AS T1 JOIN Dogs AS T2 ON T1.owner_id = T2.owner_id WHERE T1.state = 'Virginia'
  Type: JOIN

[649] MISSING_JOIN | DB: dog_kennels | EX: ✗
  Q   : Find the first names of owners living in Virginia and the names of dogs they own
  Pred: SELECT first_name, last_name FROM owners WHERE city = "Virginia"
  Gold: SELECT T1.first_name, T2.name FROM Owners AS T1 JOIN Dogs AS T2 ON T1.owner_id = T2.owner_id WHERE T1.state = 'Virginia'
  Type: JOIN

[650] MISSING_JOIN | DB: dog_kennels | EX: ✗
  Q   : What are the arriving date and the departing date of the dogs who have gone through a treatment
  Pred: SELECT date_arrived, date_departed FROM Dogs
  Gold: SELECT DISTINCT T1.date_arrived, T1.date_departed FROM Dogs AS T1 JOIN Treatments AS T2 ON T1.dog_id = T2.dog_id
  Type: JOIN

[651] WRONG_TABLE | DB: dog_kennels | EX: ✗
  Q   : Find the arriving date and the departing date of the dogs that received a treatment
  Pred: SELECT date_arrived, date_departed FROM treatments
  Gold: SELECT DISTINCT T1.date_arrived, T1.date_departed FROM Dogs AS T1 JOIN Treatments AS T2 ON T1.dog_id = T2.dog_id
  Type: JOIN

[652] MISSING_JOIN | DB: dog_kennels | EX: ✗
  Q   : List the last name of the owner owning the youngest dog
  Pred: SELECT last_name FROM owners WHERE age = (SELECT MIN(age) FROM dogs)
  Gold: SELECT T1.last_name FROM Owners AS T1 JOIN Dogs AS T2 ON T1.owner_id = T2.owner_id WHERE T2.age = (SELECT MAX(age) FROM Dogs)
  Type: JOIN, NESTED, AGGREGATION

[653] WRONG_COLUMNS | DB: dog_kennels | EX: ✗
  Q   : Who owns the youngest dog? Give me his or her last name
  Pred: SELECT T1.last_name FROM owners AS T1 JOIN dogs AS T2 ON T1.owner_id = T2.owner_id WHERE T2.age = (SELECT MIN(age) FROM dogs)
  Gold: SELECT T1.last_name FROM Owners AS T1 JOIN Dogs AS T2 ON T1.owner_id = T2.owner_id WHERE T2.age = (SELECT MAX(age) FROM Dogs)
  Type: JOIN, NESTED, AGGREGATION

[654] OTHER | DB: dog_kennels | EX: ✓
  Q   : List the emails of the professionals who live in the state of Hawaii or the state of Wisconsin
  Pred: SELECT email_address FROM professionals WHERE state = "Hawaii" OR state = "Wisconsin"
  Gold: SELECT email_address FROM Professionals WHERE state = 'Hawaii' OR state = 'Wisconsin'
  Type: SIMPLE

[655] OTHER | DB: dog_kennels | EX: ✓
  Q   : What are the emails of the professionals living in either the state of Hawaii or the state of Wisconsin
  Pred: SELECT email_address FROM professionals WHERE state = "Hawaii" OR state = "Wisconsin"
  Gold: SELECT email_address FROM Professionals WHERE state = 'Hawaii' OR state = 'Wisconsin'
  Type: SIMPLE

[656] WRONG_TABLE | DB: dog_kennels | EX: ✗
  Q   : How many dogs went through any treatments
  Pred: SELECT COUNT(*) FROM dogs
  Gold: SELECT COUNT(DISTINCT dog_id) FROM Treatments
  Type: AGGREGATION

[657] WRONG_TABLE | DB: dog_kennels | EX: ✗
  Q   : Count the number of dogs that went through a treatment
  Pred: SELECT COUNT(*) FROM dogs AS T1 JOIN treatments AS T2 ON T1.dog_id = T2.dog_id
  Gold: SELECT COUNT(DISTINCT dog_id) FROM Treatments
  Type: AGGREGATION

[658] WRONG_COLUMNS | DB: dog_kennels | EX: ✗
  Q   : How many professionals have performed any treatment to dogs
  Pred: SELECT COUNT(*) FROM treatments WHERE professional_id IN (SELECT professional_id FROM treatments)
  Gold: SELECT COUNT(DISTINCT professional_id) FROM Treatments
  Type: AGGREGATION

[659] EXTRA_JOIN | DB: dog_kennels | EX: ✗
  Q   : Find the number of professionals who have ever treated dogs
  Pred: SELECT COUNT(*) FROM treatments AS T1 JOIN professionals AS T2 ON T1.professional_id = T2.professional_id GROUP BY T1.professional_id
  Gold: SELECT COUNT(DISTINCT professional_id) FROM Treatments
  Type: AGGREGATION

[660] OTHER | DB: dog_kennels | EX: ✗
  Q   : How many dogs have an age below the average
  Pred: SELECT COUNT(*) FROM dogs WHERE age  (SELECT AVG(age) FROM dogs)
  Gold: SELECT COUNT(*) FROM Dogs WHERE age < (SELECT AVG(age) FROM Dogs)
  Type: NESTED, AGGREGATION

[661] OTHER | DB: dog_kennels | EX: ✗
  Q   : Count the number of dogs of an age below the average
  Pred: SELECT COUNT(*) FROM dogs WHERE age  (SELECT AVG(age) FROM dogs)
  Gold: SELECT COUNT(*) FROM Dogs WHERE age < (SELECT AVG(age) FROM Dogs)
  Type: NESTED, AGGREGATION

[662] WRONG_COLUMNS | DB: dog_kennels | EX: ✗
  Q   : How much does the most recent treatment cost
  Pred: SELECT date_of_treatment, cost_of_treatment FROM treatments ORDER BY date_of_treatment DESC LIMIT 1
  Gold: SELECT cost_of_treatment FROM Treatments ORDER BY date_of_treatment DESC LIMIT 1
  Type: ORDER_BY, LIMIT

[663] OTHER | DB: dog_kennels | EX: ✗
  Q   : List the dog name, age and weight of the dogs who have been abandoned? 1 stands for yes, and 0 stands for no
  Pred: SELECT name, age, weight FROM dogs WHERE abandoned_yn = 1 AND 0
  Gold: SELECT name, age, weight FROM Dogs WHERE abandoned_yn = 1
  Type: SIMPLE

[664] OTHER | DB: dog_kennels | EX: ✗
  Q   : What are the dog name, age and weight of the dogs that were abandoned? Note that 1 stands for yes, and 0 stands for no in the tables
  Pred: SELECT name, age, weight FROM dogs WHERE abandoned_yn = 1 AND 0
  Gold: SELECT name, age, weight FROM Dogs WHERE abandoned_yn = 1
  Type: SIMPLE

[665] WRONG_COLUMNS | DB: dog_kennels | EX: ✓
  Q   : What is the age of the oldest dog
  Pred: SELECT age FROM dogs ORDER BY age DESC LIMIT 1
  Gold: SELECT MAX(age) FROM Dogs
  Type: AGGREGATION

[666] WRONG_COLUMNS | DB: dog_kennels | EX: ✓
  Q   : Tell me the age of the oldest dog
  Pred: SELECT age FROM dogs ORDER BY age DESC LIMIT 1
  Gold: SELECT MAX(age) FROM Dogs
  Type: AGGREGATION

[667] WRONG_COLUMNS | DB: dog_kennels | EX: ✗
  Q   : How much does the most expensive charge type costs
  Pred: SELECT charge_type, COUNT(*) FROM charges GROUP BY charge_type ORDER BY COUNT(*) DESC LIMIT 1
  Gold: SELECT MAX(charge_amount) FROM Charges
  Type: AGGREGATION

[668] WRONG_COLUMNS | DB: dog_kennels | EX: ✓
  Q   : What is the charge amount of the most expensive charge type
  Pred: SELECT charge_amount FROM charges ORDER BY charge_type DESC LIMIT 1
  Gold: SELECT MAX(charge_amount) FROM Charges
  Type: AGGREGATION

[669] WRONG_TABLE | DB: dog_kennels | EX: ✗
  Q   : What are all the possible breed type and size type combinations
  Pred: SELECT breed_code, size_code FROM breeds
  Gold: SELECT DISTINCT breed_code, size_code FROM dogs
  Type: SIMPLE

[670] MISSING_JOIN | DB: dog_kennels | EX: ✗
  Q   : List the first name of all the professionals along with the description of the treatment they have done
  Pred: SELECT first_name, last_name FROM professionals ORDER BY cost_of_treatment DESC LIMIT 1
  Gold: SELECT DISTINCT T1.first_name, T3.treatment_type_description FROM professionals AS T1 JOIN Treatments AS T2 ON T1.professional_id = T2.professional_id JOIN Treatment_types AS T3 ON T2.treatment_type_code = T3.treatment_type_code
  Type: JOIN

[671] WRONG_COLUMNS | DB: dog_kennels | EX: ✗
  Q   : What are each professional's first name and description of the treatment they have performed
  Pred: SELECT T1.first_name, T2.treatment_type_description FROM professionals AS T1 JOIN treatments AS T2 ON T1.professional_id = T2.professional_id
  Gold: SELECT DISTINCT T1.first_name, T3.treatment_type_description FROM professionals AS T1 JOIN Treatments AS T2 ON T1.professional_id = T2.professional_id JOIN Treatment_types AS T3 ON T2.treatment_type_code = T3.treatment_type_code
  Type: JOIN

[672] OTHER | DB: singer | EX: ✗
  Q   : List the name of singers whose citizenship is not "France"
  Pred: SELECT Name FROM singer WHERE Citizenship > "France"
  Gold: SELECT Name FROM singer WHERE Citizenship <> "France"
  Type: SIMPLE

[673] OTHER | DB: singer | EX: ✗
  Q   : What are the names of the singers who are not French citizens
  Pred: SELECT Name FROM singer WHERE Citizenship > 'France'
  Gold: SELECT Name FROM singer WHERE Citizenship <> "France"
  Type: SIMPLE

[674] WRONG_COLUMNS | DB: singer | EX: ✗
  Q   : Show different citizenships and the maximum net worth of singers of each citizenship
  Pred: SELECT Citizens, MAX(Net_Worth_millions) FROM singer GROUP BY Citizens
  Gold: SELECT Citizenship, MAX(Net_Worth_Millions) FROM singer GROUP BY Citizenship
  Type: GROUP_BY, AGGREGATION

[675] MISSING_GROUP_BY | DB: singer | EX: ✗
  Q   : For each citizenship, what is the maximum net worth
  Pred: SELECT Citizenship, MAX(Net_Worth_Millions) FROM singer
  Gold: SELECT Citizenship, MAX(Net_Worth_Millions) FROM singer GROUP BY Citizenship
  Type: GROUP_BY, AGGREGATION

[676] WRONG_TABLE | DB: singer | EX: ✗
  Q   : Show titles of songs and names of singers
  Pred: SELECT T1.Title, T1.Name FROM song AS T1 JOIN singer AS T2 ON T1.Singer_ID = T2.Singer_ID
  Gold: SELECT T2.Title, T1.Name FROM singer AS T1 JOIN song AS T2 ON T1.Singer_ID = T2.Singer_ID
  Type: JOIN

[677] WRONG_TABLE | DB: singer | EX: ✗
  Q   : What are the song titles and singer names
  Pred: SELECT T1.title, T1.name FROM song AS T1 JOIN singer AS T2 ON T1.singer_id = T2.singer_id
  Gold: SELECT T2.Title, T1.Name FROM singer AS T1 JOIN song AS T2 ON T1.Singer_ID = T2.Singer_ID
  Type: JOIN

[678] MISSING_JOIN | DB: singer | EX: ✗
  Q   : Show distinct names of singers that have songs with sales more than 300000
  Pred: SELECT DISTINCT Name FROM singer WHERE Sales > 300000
  Gold: SELECT DISTINCT T1.Name FROM singer AS T1 JOIN song AS T2 ON T1.Singer_ID = T2.Singer_ID WHERE T2.Sales > 300000
  Type: JOIN

[679] WRONG_TABLE | DB: singer | EX: ✗
  Q   : what are the different names of the singers that have sales more than 300000
  Pred: SELECT DISTINCT T1.Name FROM song AS T1 JOIN singer AS T2 ON T1.Singer_ID = T2.Singer_ID WHERE T2.Sales > 300000
  Gold: SELECT DISTINCT T1.Name FROM singer AS T1 JOIN song AS T2 ON T1.Singer_ID = T2.Singer_ID WHERE T2.Sales > 300000
  Type: JOIN

[680] MISSING_JOIN | DB: singer | EX: ✗
  Q   : Show the names of singers that have more than one song
  Pred: SELECT Name FROM singer GROUP BY Name HAVING COUNT(*) > 1
  Gold: SELECT T1.Name FROM singer AS T1 JOIN song AS T2 ON T1.Singer_ID = T2.Singer_ID GROUP BY T1.Name HAVING COUNT(*) > 1
  Type: JOIN, GROUP_BY, HAVING, AGGREGATION

[681] MISSING_JOIN | DB: singer | EX: ✗
  Q   : What are the names of the singers that have more than one songs
  Pred: SELECT Name FROM singer GROUP BY Name HAVING COUNT(*) > 1
  Gold: SELECT T1.Name FROM singer AS T1 JOIN song AS T2 ON T1.Singer_ID = T2.Singer_ID GROUP BY T1.Name HAVING COUNT(*) > 1
  Type: JOIN, GROUP_BY, HAVING, AGGREGATION

[682] WRONG_TABLE | DB: singer | EX: ✗
  Q   : Show the names of singers and the total sales of their songs
  Pred: SELECT Name, SUM(Sales) FROM song
  Gold: SELECT T1.Name, SUM(T2.Sales) FROM singer AS T1 JOIN song AS T2 ON T1.Singer_ID = T2.Singer_ID GROUP BY T1.Name
  Type: JOIN, GROUP_BY, AGGREGATION

[683] WRONG_TABLE | DB: singer | EX: ✗
  Q   : For each singer name, what is the total sales for their songs
  Pred: SELECT Name, SUM(Sales) FROM song GROUP BY Name
  Gold: SELECT T1.Name, SUM(T2.Sales) FROM singer AS T1 JOIN song AS T2 ON T1.Singer_ID = T2.Singer_ID GROUP BY T1.Name
  Type: JOIN, GROUP_BY, AGGREGATION

[684] WRONG_TABLE | DB: singer | EX: ✗
  Q   : What is the sname of every sing that does not have any song
  Pred: SELECT T2.Name FROM song AS T1 JOIN singer AS T2 ON T1.Singer_ID = T2.Singer_ID GROUP BY T1.Singer_ID HAVING COUNT(*) = 1
  Gold: SELECT Name FROM singer WHERE NOT Singer_ID IN (SELECT Singer_ID FROM song)
  Type: NESTED

[685] OTHER | DB: singer | EX: ✗
  Q   : Show the citizenship shared by singers with birth year before 1945 and after 1955
  Pred: SELECT citizenship FROM singer WHERE birth_year  1945 INTERSECT SELECT citizenship FROM singer WHERE birth_year > 1955
  Gold: SELECT Citizenship FROM singer WHERE Birth_Year < 1945 INTERSECT SELECT Citizenship FROM singer WHERE Birth_Year > 1955
  Type: SIMPLE

[686] OTHER | DB: singer | EX: ✗
  Q   : What are the citizenships that are shared by singers with a birth year before 1945 and after 1955
  Pred: SELECT Citizenship FROM singer WHERE Birth_Year  1945 INTERSECT SELECT Citizenship FROM singer WHERE Birth_Year > 1955
  Gold: SELECT Citizenship FROM singer WHERE Birth_Year < 1945 INTERSECT SELECT Citizenship FROM singer WHERE Birth_Year > 1955
  Type: SIMPLE

[687] WRONG_TABLE | DB: real_estate_properties | EX: ✓
  Q   : What is the feature type name of feature AirCon
  Pred: SELECT t1.feature_type_name FROM Ref_Feature_Types AS t1 JOIN other_available_features AS t2 ON t1.feature_type_code = t2.feature_type_code WHERE t2.feature_name = "AirCon"
  Gold: SELECT T2.feature_type_name FROM Other_Available_Features AS T1 JOIN Ref_Feature_Types AS T2 ON T1.feature_type_code = T2.feature_type_code WHERE T1.feature_name = "AirCon"
  Type: JOIN

[688] MISSING_JOIN | DB: real_estate_properties | EX: ✗
  Q   : Show the property type descriptions of properties belonging to that code
  Pred: SELECT property_type_description FROM properties WHERE property_type_code = "Property_Type_Code"
  Gold: SELECT T2.property_type_description FROM Properties AS T1 JOIN Ref_Property_Types AS T2 ON T1.property_type_code = T2.property_type_code GROUP BY T1.property_type_code
  Type: JOIN, GROUP_BY

[689] OTHER | DB: real_estate_properties | EX: ✗
  Q   : What are the names of properties that are either houses or apartments with more than 1 room
  Pred: SELECT property_name FROM properties WHERE property_address = 'House' OR property_address = 'Apartment' GROUP BY property_name HAVING COUNT(*) > 1
  Gold: SELECT property_name FROM Properties WHERE property_type_code = "House" UNION SELECT property_name FROM Properties WHERE property_type_code = "Apartment" AND room_count > 1
  Type: SIMPLE