Spider Error Analysis — Run 1 EM norm: 37.81% | EX: 47.20% ================================================================================ [1] OTHER | DB: concert_singer | EX: ✗ Q : What is the average, minimum, and maximum age for all French singers Pred: SELECT AVG(age), MIN(age), MAX(age) FROM singer WHERE country = 'French' Gold: SELECT AVG(age), MIN(age), MAX(age) FROM singer WHERE country = 'France' Type: AGGREGATION [2] WRONG_COLUMNS | DB: concert_singer | EX: ✗ Q : What is the maximum capacity and the average of all stadiums Pred: SELECT MAX(capacity), AVG(average) FROM stadium Gold: SELECT MAX(capacity), average FROM stadium Type: AGGREGATION [3] WRONG_TABLE | DB: concert_singer | EX: ✗ Q : Show the stadium name and the number of concerts in each stadium Pred: SELECT T2.name, COUNT(*) FROM stadium AS T1 JOIN concert AS T2 ON T1.stadium_id = T2.stadium_id GROUP BY T1.stadium_id Gold: SELECT T2.name, COUNT(*) FROM concert AS T1 JOIN stadium AS T2 ON T1.stadium_id = T2.stadium_id GROUP BY T1.stadium_id Type: JOIN, GROUP_BY, AGGREGATION [4] WRONG_TABLE | DB: concert_singer | EX: ✗ Q : For each stadium, how many concerts play there Pred: SELECT COUNT(*), T1.stadium_id FROM stadium AS T1 JOIN concert AS T2 ON T1.stadium_id = T2.stadium_id GROUP BY T1.stadium_id Gold: SELECT T2.name, COUNT(*) FROM concert AS T1 JOIN stadium AS T2 ON T1.stadium_id = T2.stadium_id GROUP BY T1.stadium_id Type: JOIN, GROUP_BY, AGGREGATION [5] OTHER | DB: concert_singer | EX: ✓ Q : Show the stadium name and capacity with most number of concerts in year 2014 or after Pred: SELECT T2.name, T2.capacity FROM concert AS T1 JOIN stadium AS T2 ON T1.stadium_id = T2.stadium_id WHERE T1.year >= 2014 GROUP BY T1.stadium_id ORDER BY COUNT(*) DESC LIMIT 1 Gold: SELECT T2.name, T2.capacity FROM concert AS T1 JOIN stadium AS T2 ON T1.stadium_id = T2.stadium_id WHERE T1.year >= 2014 GROUP BY T2.stadium_id ORDER BY COUNT(*) DESC LIMIT 1 Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, AGGREGATION [6] OTHER | DB: concert_singer | EX: ✗ Q : Show countries where a singer above age 40 and a singer below 30 are from Pred: SELECT Country FROM singer WHERE Age > 40 INTERSECT SELECT Country FROM singer WHERE Age 30 Gold: SELECT country FROM singer WHERE age > 40 INTERSECT SELECT country FROM singer WHERE age < 30 Type: SIMPLE [7] OTHER | DB: concert_singer | EX: ✓ Q : Show the name and theme for all concerts and the number of singers in each concert Pred: SELECT T2.Concert_Name, T2.Theme, COUNT(*) FROM singer_in_concert AS T1 JOIN concert AS T2 ON T1.Concert_ID = T2.Concert_ID GROUP BY T1.Concert_ID Gold: SELECT T2.concert_name, T2.theme, COUNT(*) FROM singer_in_concert AS T1 JOIN concert AS T2 ON T1.concert_id = T2.concert_id GROUP BY T2.concert_id Type: JOIN, GROUP_BY, AGGREGATION [8] OTHER | DB: concert_singer | EX: ✓ Q : What are the names , themes , and number of singers for every concert Pred: SELECT T2.Concert_Name, T2.Theme, COUNT(*) FROM singer_in_concert AS T1 JOIN concert AS T2 ON T1.Concert_ID = T2.Concert_ID GROUP BY T1.Concert_ID Gold: SELECT t2.concert_name, t2.theme, COUNT(*) FROM singer_in_concert AS t1 JOIN concert AS t2 ON t1.concert_id = t2.concert_id GROUP BY t2.concert_id Type: JOIN, GROUP_BY, AGGREGATION [9] OTHER | DB: concert_singer | EX: ✗ Q : List singer names and number of concerts for each singer Pred: SELECT T2.Name, COUNT(*) FROM singer_in_concert AS T1 JOIN concert AS T2 ON T1.concert_id = T2.concert_id GROUP BY T2.Name Gold: SELECT T2.name, COUNT(*) FROM singer_in_concert AS T1 JOIN singer AS T2 ON T1.singer_id = T2.singer_id GROUP BY T2.singer_id Type: JOIN, GROUP_BY, AGGREGATION [10] OTHER | DB: concert_singer | EX: ✓ Q : What are the names of the singers and number of concerts for each person Pred: SELECT T2.Name, COUNT(*) FROM singer_in_concert AS T1 JOIN singer AS T2 ON T1.Singer_ID = T2.Singer_ID GROUP BY T2.Name Gold: SELECT T2.name, COUNT(*) FROM singer_in_concert AS T1 JOIN singer AS T2 ON T1.singer_id = T2.singer_id GROUP BY T2.singer_id Type: JOIN, GROUP_BY, AGGREGATION [11] WRONG_TABLE | DB: concert_singer | EX: ✗ Q : List all singer names in concerts in year 2014 Pred: SELECT T2.Name FROM concert AS T1 JOIN singer_in_concert AS T2 ON T1.concert_id = T2.concert_id WHERE T1.Year = 2014 Gold: SELECT T2.name FROM singer_in_concert AS T1 JOIN singer AS T2 ON T1.singer_id = T2.singer_id JOIN concert AS T3 ON T1.concert_id = T3.concert_id WHERE T3.year = 2014 Type: JOIN [12] OTHER | DB: concert_singer | EX: ✗ Q : What are the names of the singers who performed in a concert in 2014 Pred: SELECT T2.Name FROM singer_in_concert AS T1 JOIN concert AS T2 ON T1.concert_id = T2.concert_id WHERE T2.Year = 2014 Gold: SELECT T2.name FROM singer_in_concert AS T1 JOIN singer AS T2 ON T1.singer_id = T2.singer_id JOIN concert AS T3 ON T1.concert_id = T3.concert_id WHERE T3.year = 2014 Type: JOIN [13] EXTRA_JOIN | DB: concert_singer | EX: ✗ Q : what is the name and nation of the singer who have a song having 'Hey' in its name Pred: SELECT T1.name, T1.country FROM singer AS T1 JOIN singer_in_concert AS T2 ON T1.singer_id = T2.singer_id WHERE T2.Song_Name LIKE "%Hey%" Gold: SELECT name, country FROM singer WHERE song_name LIKE '%Hey%' Type: SIMPLE [14] WRONG_TABLE | DB: concert_singer | EX: ✗ Q : Find the number of concerts happened in the stadium with the highest capacity Pred: SELECT COUNT(*) FROM stadium ORDER BY capacity DESC LIMIT 1 Gold: SELECT COUNT(*) FROM concert WHERE stadium_id = (SELECT stadium_id FROM stadium ORDER BY capacity DESC LIMIT 1) Type: ORDER_BY, LIMIT, NESTED, AGGREGATION [15] WRONG_TABLE | DB: concert_singer | EX: ✓ Q : What are the number of concerts that occurred in the stadium with the largest capacity Pred: SELECT COUNT(*) FROM stadium AS T1 JOIN concert AS T2 ON T1.stadium_id = T2.stadium_id WHERE T1.capacity = (SELECT MAX(capacity) FROM stadium) Gold: SELECT COUNT(*) FROM concert WHERE stadium_id = (SELECT stadium_id FROM stadium ORDER BY capacity DESC LIMIT 1) Type: ORDER_BY, LIMIT, NESTED, AGGREGATION [16] OTHER | DB: pets_1 | EX: ✓ Q : Find the weight of the youngest dog Pred: SELECT Weight FROM pets ORDER BY Pet_age ASC LIMIT 1 Gold: SELECT weight FROM pets ORDER BY pet_age LIMIT 1 Type: ORDER_BY, LIMIT [17] OTHER | DB: pets_1 | EX: ✓ Q : How much does the youngest dog weigh Pred: SELECT Weight FROM pets ORDER BY Pet_age ASC LIMIT 1 Gold: SELECT weight FROM pets ORDER BY pet_age LIMIT 1 Type: ORDER_BY, LIMIT [18] WRONG_COLUMNS | DB: pets_1 | EX: ✗ Q : List the maximum weight and type for each type of pet Pred: SELECT MAX(weight), TYPE FROM pets GROUP BY TYPE Gold: SELECT MAX(weight), petType FROM pets GROUP BY petType Type: GROUP_BY, AGGREGATION [19] WRONG_TABLE | DB: pets_1 | EX: ✓ Q : Find number of pets owned by students who are older than 20 Pred: SELECT COUNT(*) FROM pets AS T1 JOIN has_pet AS T2 ON T1.petid = T2.petid JOIN student AS T3 ON T3.stuid = T2.stuid WHERE T3.age > 20 Gold: SELECT COUNT(*) FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid WHERE T1.age > 20 Type: JOIN, AGGREGATION [20] WRONG_TABLE | DB: pets_1 | EX: ✗ Q : How many pets are owned by students that have an age greater than 20 Pred: SELECT COUNT(*) FROM has_pet AS T1 JOIN pets AS T2 ON T1.petid = T2.petid JOIN student AS T3 ON T1.stuid = T3.stuid WHERE T3.pet_age > 20 Gold: SELECT COUNT(*) FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid WHERE T1.age > 20 Type: JOIN, AGGREGATION [21] WRONG_TABLE | DB: pets_1 | EX: ✗ Q : Find the number of dog pets that are raised by female students (with sex F) Pred: SELECT COUNT(*) FROM Pets AS T1 JOIN Has_pet AS T2 ON T1.petid = T2.petid JOIN Student AS T3 ON T3.StuID = T2.StuID WHERE T3.sex = 'F' Gold: SELECT COUNT(*) FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid JOIN pets AS T3 ON T2.petid = T3.petid WHERE T1.sex = 'F' AND T3.pettype = 'dog' Type: JOIN, AGGREGATION [22] WRONG_TABLE | DB: pets_1 | EX: ✗ Q : How many dog pets are raised by female students Pred: SELECT COUNT(*) FROM Pets AS T1 JOIN Has_pet AS T2 ON T1.petid = T2.petid JOIN Student AS T3 ON T3.StuID = T2.StuID WHERE T3.sex = 'F' Gold: SELECT COUNT(*) FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid JOIN pets AS T3 ON T2.petid = T3.petid WHERE T1.sex = 'F' AND T3.pettype = 'dog' Type: JOIN, AGGREGATION [23] OTHER | DB: pets_1 | EX: ✗ Q : Find the first name of students who have cat or dog pet Pred: SELECT DISTINCT T1.fname FROM Student AS T1 JOIN Has_Pet AS T2 ON T1.StuID = T2.StuID WHERE T2.pettype = "cat" OR T2.pettype = "dog" Gold: SELECT DISTINCT T1.Fname FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid JOIN pets AS T3 ON T3.petid = T2.petid WHERE T3.pettype = 'cat' OR T3.pettype = 'dog' Type: JOIN [24] WRONG_COLUMNS | DB: pets_1 | EX: ✗ Q : What are the first names of every student who has a cat or dog as a pet Pred: SELECT T1.fname FROM Student AS T1 JOIN Has_Pet AS T2 ON T1.StuID = T2.StuID WHERE T2.pettype = "cat" OR T2.pettype = "dog" Gold: SELECT DISTINCT T1.Fname FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid JOIN pets AS T3 ON T3.petid = T2.petid WHERE T3.pettype = 'cat' OR T3.pettype = 'dog' Type: JOIN [25] WRONG_COLUMNS | DB: pets_1 | EX: ✗ Q : Find the first name of students who have both cat and dog pets Pred: SELECT DISTINCT T1.fname FROM Student AS T1 JOIN Has_Pet AS T2 ON T1.StuID = T2.StuID WHERE T2.pettype = "Cat" INTERSECT SELECT T1.Fname FROM Student AS T1 JOIN Has_Pet AS T2 ON T1.StuID = T2.StuID WHERE T2.pettype = "Dog" Gold: SELECT t1.fname FROM student AS t1 JOIN has_pet AS t2 ON t1.stuid = t2.stuid JOIN pets AS t3 ON t3.petid = t2.petid WHERE t3.pettype = 'cat' INTERSECT SELECT t1.fname FROM student AS t1 JOIN has_pet AS t2 ON t1.stuid = t2.stuid JOIN pets AS t3 ON t3.petid = t2.petid WHERE t3.pettype = 'dog' Type: JOIN [26] WRONG_COLUMNS | DB: pets_1 | EX: ✗ Q : What are the students' first names who have both cats and dogs as pets Pred: SELECT DISTINCT T1.fname FROM Student AS T1 JOIN Has_Pet AS T2 ON T1.stuid = T2.stuid JOIN pets AS T3 ON T2.petid = T3.petid WHERE T3.pettype = "cat" INTERSECT SELECT T1.fname FROM Student AS T1 JOIN Has_Pet AS T2 ON T1.stuid = T2.stuid JOIN pets AS T3 ON T2.pet Gold: SELECT T1.Fname FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid JOIN pets AS T3 ON T3.petid = T2.petid WHERE T3.pettype = 'cat' INTERSECT SELECT T1.Fname FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid JOIN pets AS T3 ON T3.petid = T2.petid WHERE T3.pettype = 'dog' Type: JOIN [27] WRONG_TABLE | DB: pets_1 | EX: ✗ Q : Find the major and age of students who do not have a cat pet Pred: SELECT major, age FROM Student WHERE NOT StuID IN (SELECT StuID FROM Has_pet) Gold: SELECT major, age FROM student WHERE NOT stuid IN (SELECT T1.stuid FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid JOIN pets AS T3 ON T3.petid = T2.petid WHERE T3.pettype = 'cat') Type: JOIN, NESTED [28] WRONG_TABLE | DB: pets_1 | EX: ✗ Q : What major is every student who does not own a cat as a pet, and also how old are they Pred: SELECT major, age FROM Student WHERE NOT StuID IN (SELECT StuID FROM Has_pet WHERE petType = "Cat") Gold: SELECT major, age FROM student WHERE NOT stuid IN (SELECT T1.stuid FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid JOIN pets AS T3 ON T3.petid = T2.petid WHERE T3.pettype = 'cat') Type: JOIN, NESTED [29] WRONG_TABLE | DB: pets_1 | EX: ✗ Q : Find the id of students who do not have a cat pet Pred: SELECT StuID FROM Student EXCEPT SELECT StuID FROM Has_pet Gold: SELECT stuid FROM student EXCEPT SELECT T1.stuid FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid JOIN pets AS T3 ON T3.petid = T2.petid WHERE T3.pettype = 'cat' Type: JOIN [30] WRONG_TABLE | DB: pets_1 | EX: ✗ Q : What are the ids of the students who do not own cats as pets Pred: SELECT StuID FROM Student EXCEPT SELECT StuID FROM Has_pet Gold: SELECT stuid FROM student EXCEPT SELECT T1.stuid FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid JOIN pets AS T3 ON T3.petid = T2.petid WHERE T3.pettype = 'cat' Type: JOIN [31] WRONG_TABLE | DB: pets_1 | EX: ✗ Q : Find the first name and age of students who have a dog but do not have a cat as a pet Pred: SELECT fname, age FROM Student WHERE StuID IN (SELECT StuID FROM Has_pet WHERE petType = "dog") EXCEPT SELECT StuID FROM Has_pet WHERE petType = "cat") Gold: SELECT T1.fname, T1.age FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid JOIN pets AS T3 ON T3.petid = T2.petid WHERE T3.pettype = 'dog' AND NOT T1.stuid IN (SELECT T1.stuid FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid JOIN pets AS T3 ON T3.petid = T2.petid WHERE T3.pettype = 'cat') Type: JOIN, NESTED [32] WRONG_TABLE | DB: pets_1 | EX: ✗ Q : What is the first name of every student who has a dog but does not have a cat Pred: SELECT fname FROM Student WHERE StuID IN (SELECT StuID FROM Has_pet WHERE petType = "dog") EXCEPT SELECT StuID FROM Has_pet WHERE petType = "cat") Gold: SELECT T1.fname, T1.age FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid JOIN pets AS T3 ON T3.petid = T2.petid WHERE T3.pettype = 'dog' AND NOT T1.stuid IN (SELECT T1.stuid FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid JOIN pets AS T3 ON T3.petid = T2.petid WHERE T3.pettype = 'cat') Type: JOIN, NESTED [33] OTHER | DB: pets_1 | EX: ✓ Q : Find the type and weight of the youngest pet Pred: SELECT pettype, weight FROM pets ORDER BY pet_age ASC LIMIT 1 Gold: SELECT pettype, weight FROM pets ORDER BY pet_age LIMIT 1 Type: ORDER_BY, LIMIT [34] OTHER | DB: pets_1 | EX: ✓ Q : What type of pet is the youngest animal, and how much does it weigh Pred: SELECT pettype, weight FROM pets ORDER BY pet_age ASC LIMIT 1 Gold: SELECT pettype, weight FROM pets ORDER BY pet_age LIMIT 1 Type: ORDER_BY, LIMIT [35] WRONG_COLUMNS | DB: pets_1 | EX: ✗ Q : Find the average and maximum age for each type of pet Pred: SELECT pettype, AVG(pet_age), MAX(pet_age) FROM pets GROUP BY pettype Gold: SELECT AVG(pet_age), MAX(pet_age), pettype FROM pets GROUP BY pettype Type: GROUP_BY, AGGREGATION [36] WRONG_COLUMNS | DB: pets_1 | EX: ✗ Q : What is the average and maximum age for each pet type Pred: SELECT pettype, AVG(pet_age), MAX(pet_age) FROM pets GROUP BY pettype Gold: SELECT AVG(pet_age), MAX(pet_age), pettype FROM pets GROUP BY pettype Type: GROUP_BY, AGGREGATION [37] WRONG_COLUMNS | DB: pets_1 | EX: ✗ Q : Find the average weight for each pet type Pred: SELECT pettype, AVG(weight) FROM pets GROUP BY pettype Gold: SELECT AVG(weight), pettype FROM pets GROUP BY pettype Type: GROUP_BY, AGGREGATION [38] WRONG_COLUMNS | DB: pets_1 | EX: ✗ Q : What is the average weight for each type of pet Pred: SELECT pettype, AVG(weight) FROM pets GROUP BY pettype Gold: SELECT AVG(weight), pettype FROM pets GROUP BY pettype Type: GROUP_BY, AGGREGATION [39] WRONG_TABLE | DB: pets_1 | EX: ✓ Q : Find the id of the pet owned by student whose last name is ‘Smith’ Pred: SELECT T2.petid FROM Has_pet AS T1 JOIN pets AS T2 ON T1.petid = T2.petid JOIN student AS T3 ON T1.stuid = T3.stuid WHERE T3.lname = 'Smith' Gold: SELECT T2.petid FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid WHERE T1.Lname = 'Smith' Type: JOIN [40] WRONG_TABLE | DB: pets_1 | EX: ✓ Q : What is the id of the pet owned by the student whose last name is 'Smith' Pred: SELECT T2.petid FROM Has_pet AS T1 JOIN pets AS T2 ON T1.petid = T2.petid JOIN student AS T3 ON T1.stuid = T3.stuid WHERE T3.lname = 'Smith' Gold: SELECT T2.petid FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid WHERE T1.Lname = 'Smith' Type: JOIN [41] WRONG_TABLE | DB: pets_1 | EX: ✓ Q : Find the number of pets for each student who has any pet and student id Pred: SELECT COUNT(*), T1.StuID FROM Has_pet AS T1 JOIN pets AS T2 ON T1.PetId = T2.PetID GROUP BY T1.StuID Gold: SELECT COUNT(*), T1.stuid FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid GROUP BY T1.stuid Type: JOIN, GROUP_BY, AGGREGATION [42] WRONG_TABLE | DB: pets_1 | EX: ✓ Q : For students who have pets , how many pets does each student have ? list their ids instead of names Pred: SELECT COUNT(*), T1.StuID FROM Has_pet AS T1 JOIN pets AS T2 ON T1.PetId = T2.PetID GROUP BY T1.StuID Gold: SELECT COUNT(*), t1.stuid FROM student AS t1 JOIN has_pet AS t2 ON t1.stuid = t2.stuid GROUP BY t1.stuid Type: JOIN, GROUP_BY, AGGREGATION [43] WRONG_TABLE | DB: pets_1 | EX: ✗ Q : Find the last name of the student who has a cat that is age 3 Pred: SELECT lname FROM Student WHERE StuID IN (SELECT StuID FROM Has_pet WHERE Pet_age = 3) Gold: SELECT T1.lname FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid JOIN pets AS T3 ON T3.petid = T2.petid WHERE T3.pet_age = 3 AND T3.pettype = 'cat' Type: JOIN [44] WRONG_TABLE | DB: pets_1 | EX: ✗ Q : What is the last name of the student who has a cat that is 3 years old Pred: SELECT T2.Lname FROM Has_pet AS T1 JOIN Student AS T2 ON T1.StuID = T2.StuID WHERE T1.Pet_age = 3 Gold: SELECT T1.lname FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid JOIN pets AS T3 ON T3.petid = T2.petid WHERE T3.pet_age = 3 AND T3.pettype = 'cat' Type: JOIN [45] WRONG_TABLE | DB: pets_1 | EX: ✗ Q : What is the average age for all students who do not own any pets Pred: SELECT AVG(T1.age) FROM Student AS T1 JOIN Has_Pet AS T2 ON T1.StuID = T2.StuID WHERE NOT T2.pet_age IN (SELECT T1.age FROM Student AS T1 JOIN Has_Pet AS T2 ON T1.StuID = T2.petid) Gold: SELECT AVG(age) FROM student WHERE NOT stuid IN (SELECT stuid FROM has_pet) Type: NESTED, AGGREGATION [46] WRONG_COLUMNS | DB: car_1 | EX: ✗ Q : How many countries does each continent have? List the continent id, continent name and the number of countries Pred: SELECT T1.continent, COUNT(*) FROM continents AS T1 JOIN countries AS T2 ON T1.contid = T2.continent GROUP BY T1.contid Gold: SELECT T1.ContId, T1.Continent, COUNT(*) FROM CONTINENTS AS T1 JOIN COUNTRIES AS T2 ON T1.ContId = T2.Continent GROUP BY T1.ContId Type: JOIN, GROUP_BY, AGGREGATION [47] WRONG_COLUMNS | DB: car_1 | EX: ✗ Q : For each continent, list its id, name, and how many countries it has Pred: SELECT T1.continent, T1.countryname, COUNT(*) FROM continents AS T1 JOIN countries AS T2 ON T1.contid = T2.continent GROUP BY T1.contid Gold: SELECT T1.ContId, T1.Continent, COUNT(*) FROM CONTINENTS AS T1 JOIN COUNTRIES AS T2 ON T1.ContId = T2.Continent GROUP BY T1.ContId Type: JOIN, GROUP_BY, AGGREGATION [48] WRONG_COLUMNS | DB: car_1 | EX: ✗ Q : How many models does each car maker produce? List maker full name, id and the number Pred: SELECT COUNT(*), T1.maker FROM car_makers AS T1 JOIN model_list AS T2 ON T1.id = T2.maker GROUP BY T1.maker Gold: SELECT T1.FullName, T1.Id, COUNT(*) FROM CAR_MAKERS AS T1 JOIN MODEL_LIST AS T2 ON T1.Id = T2.Maker GROUP BY T1.Id Type: JOIN, GROUP_BY, AGGREGATION [49] WRONG_COLUMNS | DB: car_1 | EX: ✗ Q : What is the full name of each car maker, along with its id and how many models it produces Pred: SELECT T1.fullname, T1.make, COUNT(*) FROM car_makers AS T1 JOIN model_list AS T2 ON T1.id = T2.model GROUP BY T1.makemaker Gold: SELECT T1.FullName, T1.Id, COUNT(*) FROM CAR_MAKERS AS T1 JOIN MODEL_LIST AS T2 ON T1.Id = T2.Maker GROUP BY T1.Id Type: JOIN, GROUP_BY, AGGREGATION [50] WRONG_TABLE | DB: car_1 | EX: ✗ Q : Which model of the car has the minimum horsepower Pred: SELECT t1.model FROM model_list AS t1 JOIN car_names AS t2 ON t1.model = t2.model WHERE horsepower = (SELECT MIN(horsepower) FROM cars_data) Gold: SELECT T1.Model FROM CAR_NAMES AS T1 JOIN CARS_DATA AS T2 ON T1.MakeId = T2.Id ORDER BY T2.horsepower ASC LIMIT 1 Type: JOIN, ORDER_BY, LIMIT [51] WRONG_COLUMNS | DB: car_1 | EX: ✗ Q : What is the model of the car with the smallest amount of horsepower Pred: SELECT t3.model FROM car_names AS t1 JOIN model_list AS t2 ON t1.model = t2.model ORDER BY t1.horsepower LIMIT 1 Gold: SELECT T1.Model FROM CAR_NAMES AS T1 JOIN CARS_DATA AS T2 ON T1.MakeId = T2.Id ORDER BY T2.horsepower ASC LIMIT 1 Type: JOIN, ORDER_BY, LIMIT [52] MISSING_JOIN | DB: car_1 | EX: ✗ Q : Find the model of the car whose weight is below the average weight Pred: SELECT DISTINCT model FROM car_names WHERE weight (SELECT AVG(weight) FROM cars_data) Gold: SELECT T1.model FROM CAR_NAMES AS T1 JOIN CARS_DATA AS T2 ON T1.MakeId = T2.Id WHERE T2.Weight < (SELECT AVG(Weight) FROM CARS_DATA) Type: JOIN, NESTED, AGGREGATION [53] MISSING_JOIN | DB: car_1 | EX: ✗ Q : What is the model for the car with a weight smaller than the average Pred: SELECT model FROM car_names WHERE weight (SELECT AVG(weight) FROM cars_data) Gold: SELECT T1.model FROM CAR_NAMES AS T1 JOIN CARS_DATA AS T2 ON T1.MakeId = T2.Id WHERE T2.Weight < (SELECT AVG(Weight) FROM CARS_DATA) Type: JOIN, NESTED, AGGREGATION [54] WRONG_COLUMNS | DB: car_1 | EX: ✗ Q : Find the name of the makers that produced some cars in the year of 1970 Pred: SELECT T1.maker FROM car_makers AS T1 JOIN model_list AS T2 ON T1.id = T2.model WHERE T2.year = 1970 Gold: SELECT DISTINCT T1.Maker FROM CAR_MAKERS AS T1 JOIN MODEL_LIST AS T2 ON T1.Id = T2.Maker JOIN CAR_NAMES AS T3 ON T2.model = T3.model JOIN CARS_DATA AS T4 ON T3.MakeId = T4.id WHERE T4.year = '1970' Type: JOIN [55] OTHER | DB: car_1 | EX: ✗ Q : What is the name of the different car makers who produced a car in 1970 Pred: SELECT DISTINCT T1.maker FROM car_makers AS T1 JOIN model_list AS T2 ON T1.id = T2.model WHERE T2.year = 1970 Gold: SELECT DISTINCT T1.Maker FROM CAR_MAKERS AS T1 JOIN MODEL_LIST AS T2 ON T1.Id = T2.Maker JOIN CAR_NAMES AS T3 ON T2.model = T3.model JOIN CARS_DATA AS T4 ON T3.MakeId = T4.id WHERE T4.year = '1970' Type: JOIN [56] WRONG_TABLE | DB: car_1 | EX: ✗ Q : Find the make and production time of the cars that were produced in the earliest year Pred: SELECT T1.make, T2.year FROM car_names AS T1 JOIN make AS T2 ON T1.makeid = T2.id ORDER BY T1.year LIMIT 1 Gold: SELECT T2.Make, T1.Year FROM CARS_DATA AS T1 JOIN CAR_NAMES AS T2 ON T1.Id = T2.MakeId WHERE T1.Year = (SELECT MIN(YEAR) FROM CARS_DATA) Type: JOIN, NESTED, AGGREGATION [57] WRONG_TABLE | DB: car_1 | EX: ✗ Q : What is the maker of the carr produced in the earliest year and what year was it Pred: SELECT T1.maker, T1.year FROM car_makers AS T1 JOIN model_list AS T2 ON T1.id = T2.maker ORDER BY T2.year LIMIT 1 Gold: SELECT T2.Make, T1.Year FROM CARS_DATA AS T1 JOIN CAR_NAMES AS T2 ON T1.Id = T2.MakeId WHERE T1.Year = (SELECT MIN(YEAR) FROM CARS_DATA) Type: JOIN, NESTED, AGGREGATION [58] WRONG_TABLE | DB: car_1 | EX: ✗ Q : Which distinct car models are the produced after 1980 Pred: SELECT DISTINCT model FROM car_names WHERE YEAR > 1980 Gold: SELECT DISTINCT T1.model FROM MODEL_LIST AS T1 JOIN CAR_NAMES AS T2 ON T1.model = T2.model JOIN CARS_DATA AS T3 ON T2.MakeId = T3.id WHERE T3.year > 1980 Type: JOIN [59] WRONG_COLUMNS | DB: car_1 | EX: ✗ Q : What are the different models for the cards produced after 1980 Pred: SELECT DISTINCT T2.model FROM model_list AS T1 JOIN car_makers AS T2 ON T1.make = T2.makeid WHERE T2.year > 1980 Gold: SELECT DISTINCT T1.model FROM MODEL_LIST AS T1 JOIN CAR_NAMES AS T2 ON T1.model = T2.model JOIN CARS_DATA AS T3 ON T2.MakeId = T3.id WHERE T3.year > 1980 Type: JOIN [60] OTHER | DB: car_1 | EX: ✗ Q : How many car makers are there in each continents? List the continent name and the count Pred: SELECT T1.continent, COUNT(*) FROM continents AS T1 JOIN car_makers AS T2 ON T1.contid = T2.id GROUP BY T1.contid Gold: SELECT T1.Continent, COUNT(*) FROM CONTINENTS AS T1 JOIN COUNTRIES AS T2 ON T1.ContId = T2.continent JOIN car_makers AS T3 ON T2.CountryId = T3.Country GROUP BY T1.Continent Type: JOIN, GROUP_BY, AGGREGATION [61] OTHER | DB: car_1 | EX: ✗ Q : What is the name of each continent and how many car makers are there in each one Pred: SELECT T1.continent, COUNT(*) FROM continents AS T1 JOIN car_makers AS T2 ON T1.contid = T2.contid GROUP BY T1.continent Gold: SELECT T1.Continent, COUNT(*) FROM CONTINENTS AS T1 JOIN COUNTRIES AS T2 ON T1.ContId = T2.continent JOIN car_makers AS T3 ON T2.CountryId = T3.Country GROUP BY T1.Continent Type: JOIN, GROUP_BY, AGGREGATION [62] WRONG_TABLE | DB: car_1 | EX: ✗ Q : Which of the countries has the most car makers? List the country name Pred: SELECT T1.countryname FROM countries AS T1 JOIN car_makers AS T2 ON T1.country = T2.countryid GROUP BY T1.countryname ORDER BY COUNT(*) DESC LIMIT 1 Gold: SELECT T2.CountryName FROM CAR_MAKERS AS T1 JOIN COUNTRIES AS T2 ON T1.Country = T2.CountryId GROUP BY T1.Country ORDER BY COUNT(*) DESC LIMIT 1 Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, AGGREGATION [63] WRONG_TABLE | DB: car_1 | EX: ✗ Q : What is the name of the country with the most car makers Pred: SELECT T1.countryname FROM countries AS T1 JOIN car_makers AS T2 ON T1.country = T2.countryid GROUP BY T1.countryname ORDER BY COUNT(*) DESC LIMIT 1 Gold: SELECT T2.CountryName FROM CAR_MAKERS AS T1 JOIN COUNTRIES AS T2 ON T1.Country = T2.CountryId GROUP BY T1.Country ORDER BY COUNT(*) DESC LIMIT 1 Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, AGGREGATION [64] WRONG_TABLE | DB: car_1 | EX: ✗ Q : How many car models are produced by each maker ? Only list the count and the maker full name Pred: SELECT COUNT(*), T1.maker FROM car_makers AS T1 JOIN model_list AS T2 ON T1.id = T2.model GROUP BY T1.maker Gold: SELECT COUNT(*), t2.fullname FROM model_list AS t1 JOIN car_makers AS t2 ON t1.maker = t2.id GROUP BY t2.id Type: JOIN, GROUP_BY, AGGREGATION [65] WRONG_TABLE | DB: car_1 | EX: ✗ Q : What is the number of car models that are produced by each maker and what is the id and full name of each maker Pred: SELECT COUNT(*), T1.make, T1.fullname FROM car_makers AS T1 JOIN model_list AS T2 ON T1.id = T2.model GROUP BY T1.makemaker Gold: SELECT COUNT(*), T2.FullName, T2.id FROM MODEL_LIST AS T1 JOIN CAR_MAKERS AS T2 ON T1.Maker = T2.Id GROUP BY T2.id Type: JOIN, GROUP_BY, AGGREGATION [66] WRONG_TABLE | DB: car_1 | EX: ✗ Q : What is the accelerate of the car make amc hornet sportabout (sw) Pred: SELECT Accelerate FROM car_names WHERE make = 'amc hornet sportabout (sw)' Gold: SELECT T1.Accelerate FROM CARS_DATA AS T1 JOIN CAR_NAMES AS T2 ON T1.Id = T2.MakeId WHERE T2.Make = 'amc hornet sportabout (sw)' Type: JOIN [67] WRONG_TABLE | DB: car_1 | EX: ✗ Q : How much does the car accelerate that makes amc hornet sportabout (sw) Pred: SELECT Accelerate FROM car_names WHERE make = 'amc hornet sportabout (sw)' Gold: SELECT T1.Accelerate FROM CARS_DATA AS T1 JOIN CAR_NAMES AS T2 ON T1.Id = T2.MakeId WHERE T2.Make = 'amc hornet sportabout (sw)' Type: JOIN [68] WRONG_TABLE | DB: car_1 | EX: ✗ Q : How many car makers are there in france Pred: SELECT COUNT(*) FROM countries AS T1 JOIN car_makers AS T2 ON T1.country = T2.countryid WHERE T1.countryname = "France" Gold: SELECT COUNT(*) FROM CAR_MAKERS AS T1 JOIN COUNTRIES AS T2 ON T1.Country = T2.CountryId WHERE T2.CountryName = 'france' Type: JOIN, AGGREGATION [69] WRONG_TABLE | DB: car_1 | EX: ✗ Q : What is the number of makers of care in France Pred: SELECT COUNT(*) FROM countries AS T1 JOIN model_list AS T2 ON T1.country = T2.countryid WHERE T1.countryname = "France" Gold: SELECT COUNT(*) FROM CAR_MAKERS AS T1 JOIN COUNTRIES AS T2 ON T1.Country = T2.CountryId WHERE T2.CountryName = 'france' Type: JOIN, AGGREGATION [70] WRONG_TABLE | DB: car_1 | EX: ✗ Q : How many car models are produced in the usa Pred: SELECT COUNT(*) FROM car_makers AS T1 JOIN countries AS T2 ON T1.country = T2.countryid WHERE T2.countryname = "USA" Gold: SELECT COUNT(*) FROM MODEL_LIST AS T1 JOIN CAR_MAKERS AS T2 ON T1.Maker = T2.Id JOIN COUNTRIES AS T3 ON T2.Country = T3.CountryId WHERE T3.CountryName = 'usa' Type: JOIN, AGGREGATION [71] WRONG_TABLE | DB: car_1 | EX: ✗ Q : What is the count of the car models produced in the United States Pred: SELECT COUNT(*) FROM car_makers AS T1 JOIN countries AS T2 ON T1.country = T2.countryid WHERE T2.countryname = "United States" Gold: SELECT COUNT(*) FROM MODEL_LIST AS T1 JOIN CAR_MAKERS AS T2 ON T1.Maker = T2.Id JOIN COUNTRIES AS T3 ON T2.Country = T3.CountryId WHERE T3.CountryName = 'usa' Type: JOIN, AGGREGATION [72] WRONG_TABLE | DB: car_1 | EX: ✗ Q : What is the smallest weight of the car produced with 8 cylinders on 1974 Pred: SELECT MIN(weight) FROM car_names AS T1 JOIN make AS T2 ON T1.make = T2.makeid WHERE T2.cylinders = 8 AND YEAR = 1974 Gold: SELECT MIN(weight) FROM cars_data WHERE cylinders = 8 AND year = 1974 Type: AGGREGATION [73] EXTRA_JOIN | DB: car_1 | EX: ✗ Q : What are all the makers and models Pred: SELECT T1.maker, T1.model FROM model_list AS T1 JOIN car_makers AS T2 ON T1.id = T2.maker Gold: SELECT Maker, Model FROM MODEL_LIST Type: SIMPLE [74] EXTRA_JOIN | DB: car_1 | EX: ✗ Q : What are the makers and models Pred: SELECT T1.maker, T1.model FROM model_list AS T1 JOIN car_makers AS T2 ON T1.id = T2.maker Gold: SELECT Maker, Model FROM MODEL_LIST Type: SIMPLE [75] OTHER | DB: car_1 | EX: ✗ Q : What are the countries having at least one car maker? List name and id Pred: SELECT T1.countryname, T1.countryid FROM countries AS T1 JOIN car_makers AS T2 ON T1.country = T2.countryid GROUP BY T1.countryid HAVING COUNT(*) >= 1 Gold: SELECT T1.CountryName, T1.CountryId FROM COUNTRIES AS T1 JOIN CAR_MAKERS AS T2 ON T1.CountryId = T2.Country GROUP BY T1.CountryId HAVING COUNT(*) >= 1 Type: JOIN, GROUP_BY, HAVING, AGGREGATION [76] OTHER | DB: car_1 | EX: ✗ Q : What are the names and ids of all countries with at least one car maker Pred: SELECT T1.countryname, T1.countryid FROM countries AS T1 JOIN car_makers AS T2 ON T1.country = T2.countryid GROUP BY T1.countryid HAVING COUNT(*) >= 1 Gold: SELECT T1.CountryName, T1.CountryId FROM COUNTRIES AS T1 JOIN CAR_MAKERS AS T2 ON T1.CountryId = T2.Country GROUP BY T1.CountryId HAVING COUNT(*) >= 1 Type: JOIN, GROUP_BY, HAVING, AGGREGATION [77] WRONG_TABLE | DB: car_1 | EX: ✗ Q : What is the number of the cars with horsepower more than 150 Pred: SELECT COUNT(*) FROM car_names WHERE horsepower > 150 Gold: SELECT COUNT(*) FROM CARS_DATA WHERE horsepower > 150 Type: AGGREGATION [78] OTHER | DB: car_1 | EX: ✗ Q : Which countries in europe have at least 3 car manufacturers Pred: SELECT T1.countryname FROM countries AS T1 JOIN car_makers AS T2 ON T1.country = T2.countryid WHERE T1.country = "Europe" GROUP BY T1.countryname HAVING COUNT(*) >= 3 Gold: SELECT T1.CountryName FROM COUNTRIES AS T1 JOIN CONTINENTS AS T2 ON T1.Continent = T2.ContId JOIN CAR_MAKERS AS T3 ON T1.CountryId = T3.Country WHERE T2.Continent = 'europe' GROUP BY T1.CountryName HAVING COUNT(*) >= 3 Type: JOIN, GROUP_BY, HAVING, AGGREGATION [79] MISSING_JOIN | DB: car_1 | EX: ✗ Q : What are the names of all European countries with at least 3 manufacturers Pred: SELECT countryname FROM countries WHERE countryname = 'Europe' GROUP BY countryname HAVING COUNT(*) >= 3 Gold: SELECT T1.CountryName FROM COUNTRIES AS T1 JOIN CONTINENTS AS T2 ON T1.Continent = T2.ContId JOIN CAR_MAKERS AS T3 ON T1.CountryId = T3.Country WHERE T2.Continent = 'europe' GROUP BY T1.CountryName HAVING COUNT(*) >= 3 Type: JOIN, GROUP_BY, HAVING, AGGREGATION [80] MISSING_JOIN | DB: car_1 | EX: ✗ Q : What is the maximum horsepower and the make of the car models with 3 cylinders Pred: SELECT MAX(horsepower), MAX(make) FROM car_names WHERE cylinders = 3 Gold: SELECT T2.horsepower, T1.Make FROM CAR_NAMES AS T1 JOIN CARS_DATA AS T2 ON T1.MakeId = T2.Id WHERE T2.cylinders = 3 ORDER BY T2.horsepower DESC LIMIT 1 Type: JOIN, ORDER_BY, LIMIT [81] WRONG_TABLE | DB: car_1 | EX: ✗ Q : What is the largest amount of horsepower for the models with 3 cylinders and what make is it Pred: SELECT MAX(HPV), T1.make FROM car_makers AS T1 JOIN model_list AS T2 ON T1.id = T2.modelId WHERE T2.cylinders = 3 GROUP BY T1.make Gold: SELECT T2.horsepower, T1.Make FROM CAR_NAMES AS T1 JOIN CARS_DATA AS T2 ON T1.MakeId = T2.Id WHERE T2.cylinders = 3 ORDER BY T2.horsepower DESC LIMIT 1 Type: JOIN, ORDER_BY, LIMIT [82] WRONG_TABLE | DB: car_1 | EX: ✗ Q : Which model saves the most gasoline? That is to say, have the maximum miles per gallon Pred: SELECT t1.model FROM model_list AS t1 JOIN cars_data AS t2 ON t1.model = t2.model WHERE t2.mpg = (SELECT MAX(mpg) FROM cars_data) Gold: SELECT T1.Model FROM CAR_NAMES AS T1 JOIN CARS_DATA AS T2 ON T1.MakeId = T2.Id ORDER BY T2.mpg DESC LIMIT 1 Type: JOIN, ORDER_BY, LIMIT [83] OTHER | DB: car_1 | EX: ✗ Q : What is the car model with the highest mpg Pred: SELECT t1.model FROM car_names AS t1 JOIN model_list AS t2 ON t1.model = t2.model ORDER BY t2.mpg DESC LIMIT 1 Gold: SELECT t1.model FROM car_names AS t1 JOIN cars_data AS t2 ON t1.makeid = t2.id ORDER BY t2.mpg DESC LIMIT 1 Type: JOIN, ORDER_BY, LIMIT [84] OTHER | DB: car_1 | EX: ✗ Q : What is the average horsepower of the cars before 1980 Pred: SELECT AVG(horsepower) FROM cars_data WHERE YEAR 1980 Gold: SELECT AVG(horsepower) FROM CARS_DATA WHERE YEAR < 1980 Type: AGGREGATION [85] WRONG_TABLE | DB: car_1 | EX: ✗ Q : What is the average horsepower for all cars produced before 1980 Pred: SELECT AVG(horsepower) FROM car_names WHERE YEAR 1980 Gold: SELECT AVG(horsepower) FROM cars_data WHERE year < 1980 Type: AGGREGATION [86] WRONG_TABLE | DB: car_1 | EX: ✗ Q : What is the average edispl of the cars of model volvo Pred: SELECT AVG(T2.edispl) FROM model_list AS T1 JOIN car_names AS T2 ON T1.model = T2.model WHERE T1.make = "Volvo" Gold: SELECT AVG(T2.edispl) FROM CAR_NAMES AS T1 JOIN CARS_DATA AS T2 ON T1.MakeId = T2.Id WHERE T1.Model = 'volvo' Type: JOIN, AGGREGATION [87] WRONG_TABLE | DB: car_1 | EX: ✗ Q : What is the average edispl for all volvos Pred: SELECT AVG(edispl) FROM cars_data WHERE make = "Volvo" Gold: SELECT AVG(T2.edispl) FROM CAR_NAMES AS T1 JOIN CARS_DATA AS T2 ON T1.MakeId = T2.Id WHERE T1.Model = 'volvo' Type: JOIN, AGGREGATION [88] WRONG_COLUMNS | DB: car_1 | EX: ✗ Q : What is the maximum accelerate for different number of cylinders Pred: SELECT MAX(accurate), COUNT(*) FROM cars_data GROUP BY cylinders Gold: SELECT MAX(Accelerate), Cylinders FROM CARS_DATA GROUP BY Cylinders Type: GROUP_BY, AGGREGATION [89] WRONG_COLUMNS | DB: car_1 | EX: ✗ Q : What is the maximum accelerate for all the different cylinders Pred: SELECT MAX(accurate), cylinders FROM cars_data GROUP BY cylinders Gold: SELECT MAX(Accelerate), Cylinders FROM CARS_DATA GROUP BY Cylinders Type: GROUP_BY, AGGREGATION [90] EXTRA_JOIN | DB: car_1 | EX: ✓ Q : Which model has the most version(make) of cars Pred: SELECT T2.model FROM car_names AS T1 JOIN model_list AS T2 ON T1.model = T2.model GROUP BY T2.model ORDER BY COUNT(*) DESC LIMIT 1 Gold: SELECT Model FROM CAR_NAMES GROUP BY Model ORDER BY COUNT(*) DESC LIMIT 1 Type: GROUP_BY, ORDER_BY, LIMIT, AGGREGATION [91] WRONG_TABLE | DB: car_1 | EX: ✗ Q : What model has the most different versions Pred: SELECT model FROM model_list GROUP BY model ORDER BY COUNT(*) DESC LIMIT 1 Gold: SELECT Model FROM CAR_NAMES GROUP BY Model ORDER BY COUNT(*) DESC LIMIT 1 Type: GROUP_BY, ORDER_BY, LIMIT, AGGREGATION [92] WRONG_TABLE | DB: car_1 | EX: ✗ Q : how many cars were produced in 1980 Pred: SELECT COUNT(*) FROM car_names WHERE YEAR = 1980 Gold: SELECT COUNT(*) FROM CARS_DATA WHERE YEAR = 1980 Type: AGGREGATION [93] WRONG_TABLE | DB: car_1 | EX: ✗ Q : In 1980, how many cars were made Pred: SELECT COUNT(*) FROM car_makers WHERE YEAR = 1980 Gold: SELECT COUNT(*) FROM CARS_DATA WHERE YEAR = 1980 Type: AGGREGATION [94] OTHER | DB: car_1 | EX: ✗ Q : How many car models were produced by the maker with full name American Motor Company Pred: SELECT COUNT(*) FROM car_makers AS T1 JOIN model_list AS T2 ON T1.maker = T2.id WHERE T1.fullname = 'American Motor Company' Gold: SELECT COUNT(*) FROM CAR_MAKERS AS T1 JOIN MODEL_LIST AS T2 ON T1.Id = T2.Maker WHERE T1.FullName = 'American Motor Company' Type: JOIN, AGGREGATION [95] OTHER | DB: car_1 | EX: ✗ Q : What is the number of car models created by the car maker American Motor Company Pred: SELECT COUNT(*) FROM car_makers AS T1 JOIN model_list AS T2 ON T1.id = T2.model WHERE T1.maker = "American Motor Company" Gold: SELECT COUNT(*) FROM CAR_MAKERS AS T1 JOIN MODEL_LIST AS T2 ON T1.Id = T2.Maker WHERE T1.FullName = 'American Motor Company' Type: JOIN, AGGREGATION [96] WRONG_COLUMNS | DB: car_1 | EX: ✗ Q : Which makers designed more than 3 car models? List full name and the id Pred: SELECT T1.maker, T1.fullname, T1.id FROM car_makers AS T1 JOIN model_list AS T2 ON T1.maker = T2.id GROUP BY T1.maker HAVING COUNT(*) > 3 Gold: SELECT T1.FullName, T1.Id FROM CAR_MAKERS AS T1 JOIN MODEL_LIST AS T2 ON T1.Id = T2.Maker GROUP BY T1.Id HAVING COUNT(*) > 3 Type: JOIN, GROUP_BY, HAVING, AGGREGATION [97] WRONG_COLUMNS | DB: car_1 | EX: ✗ Q : What are the names and ids of all makers with more than 3 models Pred: SELECT T1.maker, T1.id FROM car_makers AS T1 JOIN model_list AS T2 ON T1.id = T2.modelid GROUP BY T1.maker HAVING COUNT(*) > 3 Gold: SELECT T1.FullName, T1.Id FROM CAR_MAKERS AS T1 JOIN MODEL_LIST AS T2 ON T1.Id = T2.Maker GROUP BY T1.Id HAVING COUNT(*) > 3 Type: JOIN, GROUP_BY, HAVING, AGGREGATION [98] WRONG_TABLE | DB: car_1 | EX: ✗ Q : Which distinctive models are produced by maker with the full name General Motors or weighing more than 3500 Pred: SELECT DISTINCT T2.model FROM car_makers AS T1 JOIN model_list AS T2 ON T1.make = T2.makeid WHERE T1.fullname = "General Motors" OR T1.weight > 3500 Gold: SELECT DISTINCT T2.Model FROM CAR_NAMES AS T1 JOIN MODEL_LIST AS T2 ON T1.Model = T2.Model JOIN CAR_MAKERS AS T3 ON T2.Maker = T3.Id JOIN CARS_DATA AS T4 ON T1.MakeId = T4.Id WHERE T3.FullName = 'General Motors' OR T4.weight > 3500 Type: JOIN [99] WRONG_TABLE | DB: car_1 | EX: ✗ Q : What are the different models created by either the car maker General Motors or weighed more than 3500 Pred: SELECT DISTINCT T2.model FROM car_makers AS T1 JOIN model_list AS T2 ON T1.id = T2.model WHERE T1.maker = "General Motors" OR T1.weight > 3500 Gold: SELECT DISTINCT T2.Model FROM CAR_NAMES AS T1 JOIN MODEL_LIST AS T2 ON T1.Model = T2.Model JOIN CAR_MAKERS AS T3 ON T2.Maker = T3.Id JOIN CARS_DATA AS T4 ON T1.MakeId = T4.Id WHERE T3.FullName = 'General Motors' OR T4.weight > 3500 Type: JOIN [100] WRONG_TABLE | DB: car_1 | EX: ✗ Q : In which years cars were produced weighing no less than 3000 and no more than 4000 Pred: SELECT YEAR FROM car_makers WHERE weight 3000 INTERSECT SELECT YEAR FROM car_makers WHERE weight 4000 Gold: SELECT DISTINCT year FROM cars_data WHERE weight BETWEEN 3000 AND 4000 Type: SIMPLE [101] WRONG_TABLE | DB: car_1 | EX: ✗ Q : What are the different years in which there were cars produced that weighed less than 4000 and also cars that weighted more than 3000 Pred: SELECT DISTINCT YEAR FROM car_makers WHERE weight 4000 INTERSECT SELECT DISTINCT YEAR FROM car_makers WHERE weight > 3000 Gold: SELECT DISTINCT year FROM cars_data WHERE weight BETWEEN 3000 AND 4000 Type: SIMPLE [102] WRONG_COLUMNS | DB: car_1 | EX: ✓ Q : What is the horsepower of the car with the largest accelerate Pred: SELECT horsepower FROM cars_data ORDER BY accelerate DESC LIMIT 1 Gold: SELECT T1.horsepower FROM CARS_DATA AS T1 ORDER BY T1.accelerate DESC LIMIT 1 Type: ORDER_BY, LIMIT [103] WRONG_COLUMNS | DB: car_1 | EX: ✓ Q : What is the horsepower of the car with the greatest accelerate Pred: SELECT horsepower FROM cars_data ORDER BY accelerate DESC LIMIT 1 Gold: SELECT T1.horsepower FROM CARS_DATA AS T1 ORDER BY T1.accelerate DESC LIMIT 1 Type: ORDER_BY, LIMIT [104] WRONG_TABLE | DB: car_1 | EX: ✗ Q : For model volvo, how many cylinders does the car with the least accelerate have Pred: SELECT COUNT(*), T1.model FROM car_names AS T1 JOIN model_list AS T2 ON T1.model = T2.model WHERE T1.make = "Volvo" GROUP BY T1.model ORDER BY SUM(T1.accelerated) LIMIT 1 Gold: SELECT T1.cylinders FROM CARS_DATA AS T1 JOIN CAR_NAMES AS T2 ON T1.Id = T2.MakeId WHERE T2.Model = 'volvo' ORDER BY T1.accelerate ASC LIMIT 1 Type: JOIN, ORDER_BY, LIMIT [105] WRONG_TABLE | DB: car_1 | EX: ✗ Q : For a volvo model, how many cylinders does the version with least accelerate have Pred: SELECT t2.cylinders FROM model_list AS t1 JOIN car_names AS t2 ON t1.model = t2.model WHERE t2.make = "Volvo" ORDER BY t2.accurate LIMIT 1 Gold: SELECT T1.cylinders FROM CARS_DATA AS T1 JOIN CAR_NAMES AS T2 ON T1.Id = T2.MakeId WHERE T2.Model = 'volvo' ORDER BY T1.accelerate ASC LIMIT 1 Type: JOIN, ORDER_BY, LIMIT [106] MISSING_ORDER_BY | DB: car_1 | EX: ✗ Q : How many cars have a larger accelerate than the car with the largest horsepower Pred: SELECT COUNT(*) FROM cars_data WHERE accelerate > (SELECT MAX(horsepower) FROM cars_data) Gold: SELECT COUNT(*) FROM CARS_DATA WHERE Accelerate > (SELECT Accelerate FROM CARS_DATA ORDER BY Horsepower DESC LIMIT 1) Type: ORDER_BY, LIMIT, NESTED, AGGREGATION [107] MISSING_ORDER_BY | DB: car_1 | EX: ✗ Q : What is the number of cars with a greater accelerate than the one with the most horsepower Pred: SELECT COUNT(*) FROM cars_data WHERE accelerate > (SELECT MAX(horsepower) FROM cars_data) Gold: SELECT COUNT(*) FROM CARS_DATA WHERE Accelerate > (SELECT Accelerate FROM CARS_DATA ORDER BY Horsepower DESC LIMIT 1) Type: ORDER_BY, LIMIT, NESTED, AGGREGATION [108] WRONG_TABLE | DB: car_1 | EX: ✗ Q : How many countries has more than 2 car makers Pred: SELECT COUNT(*) FROM countries WHERE countryID IN (SELECT countryID FROM car_makers GROUP BY countryID HAVING COUNT(*) > 2) Gold: SELECT COUNT(*) FROM countries AS t1 JOIN car_makers AS t2 ON t1.countryid = t2.country GROUP BY t1.countryid HAVING COUNT(*) > 2 Type: JOIN, GROUP_BY, HAVING, AGGREGATION [109] MISSING_JOIN | DB: car_1 | EX: ✗ Q : What is the number of countries with more than 2 car makers Pred: SELECT COUNT(*) FROM countries WHERE maker > 2 Gold: SELECT COUNT(*) FROM countries AS t1 JOIN car_makers AS t2 ON t1.countryid = t2.country GROUP BY t1.countryid HAVING COUNT(*) > 2 Type: JOIN, GROUP_BY, HAVING, AGGREGATION [110] WRONG_TABLE | DB: car_1 | EX: ✗ Q : For the cars with 4 cylinders, which model has the largest horsepower Pred: SELECT t3.model FROM cars_data AS t1 JOIN model_list AS t2 ON t1.model = t2.model WHERE t1.cylinders = 4 AND horsepower = (SELECT MAX(horsepower) FROM car_names) Gold: SELECT T1.Model FROM CAR_NAMES AS T1 JOIN CARS_DATA AS T2 ON T1.MakeId = T2.Id WHERE T2.Cylinders = 4 ORDER BY T2.horsepower DESC LIMIT 1 Type: JOIN, ORDER_BY, LIMIT [111] MISSING_ORDER_BY | DB: car_1 | EX: ✗ Q : For all of the 4 cylinder cars, which model has the most horsepower Pred: SELECT t1.model FROM car_names AS t1 JOIN model_list AS t2 ON t1.model = t2.model WHERE t1.cylinders = 4 AND horsepower = (SELECT MAX(horsepower) FROM car_names) Gold: SELECT T1.Model FROM CAR_NAMES AS T1 JOIN CARS_DATA AS T2 ON T1.MakeId = T2.Id WHERE T2.Cylinders = 4 ORDER BY T2.horsepower DESC LIMIT 1 Type: JOIN, ORDER_BY, LIMIT [112] WRONG_TABLE | DB: car_1 | EX: ✗ Q : Among the cars with more than lowest horsepower, which ones do not have more than 3 cylinders? List the car makeid and make name Pred: SELECT T1.make, T1.make FROM car_names AS T1 JOIN cars_data AS T2 ON T1.id = T2.makeid WHERE T2.horsepower > 3 EXCEPT SELECT T1.make, T1.make FROM car_names AS T1 JOIN cars_data AS T2 ON T1.id = T2.makeid WHERE T2.horsepower > 3 Gold: SELECT T2.MakeId, T2.Make FROM CARS_DATA AS T1 JOIN CAR_NAMES AS T2 ON T1.Id = T2.MakeId WHERE T1.Horsepower > (SELECT MIN(Horsepower) FROM CARS_DATA) AND T1.Cylinders <= 3 Type: JOIN, NESTED, AGGREGATION [113] WRONG_TABLE | DB: car_1 | EX: ✗ Q : Among the cars that do not have the minimum horsepower , what are the make ids and names of all those with less than 4 cylinders Pred: SELECT DISTINCT T1.make, T1.make FROM car_names AS T1 JOIN cars_data AS T2 ON T1.id = T2.makeid WHERE T2.horsepower 4 Gold: SELECT t2.makeid, t2.make FROM cars_data AS t1 JOIN car_names AS t2 ON t1.id = t2.makeid WHERE t1.horsepower > (SELECT MIN(horsepower) FROM cars_data) AND t1.cylinders < 4 Type: JOIN, NESTED, AGGREGATION [114] OTHER | DB: car_1 | EX: ✗ Q : What is the maximum miles per gallon of the car with 8 cylinders or produced before 1980 Pred: SELECT MAX(mpg) FROM cars_data WHERE cylinders = 8 OR YEAR 1980 Gold: SELECT MAX(mpg) FROM cars_data WHERE cylinders = 8 OR year < 1980 Type: AGGREGATION [115] WRONG_COLUMNS | DB: car_1 | EX: ✗ Q : What is the maximum mpg of the cars that had 8 cylinders or that were produced before 1980 Pred: SELECT MAX(mpg) FROM cars_data WHERE cylinders = 8 UNION SELECT MPG FROM cars_data WHERE YEAR 1980 Gold: SELECT MAX(mpg) FROM cars_data WHERE cylinders = 8 OR year < 1980 Type: AGGREGATION [116] MISSING_JOIN | DB: car_1 | EX: ✗ Q : Which models are lighter than 3500 but not built by the 'Ford Motor Company' Pred: SELECT model FROM model_list WHERE weight 3500 EXCEPT SELECT model FROM model_list WHERE maker = 'Ford Motor Company' Gold: SELECT DISTINCT T1.model FROM MODEL_LIST AS T1 JOIN CAR_NAMES AS T2 ON T1.Model = T2.Model JOIN CARS_DATA AS T3 ON T2.MakeId = T3.Id JOIN CAR_MAKERS AS T4 ON T1.Maker = T4.Id WHERE T3.weight < 3500 AND T4.FullName <> 'Ford Motor Company' Type: JOIN [117] WRONG_TABLE | DB: car_1 | EX: ✗ Q : What are the different models wthat are lighter than 3500 but were not built by the Ford Motor Company Pred: SELECT DISTINCT T2.model FROM car_names AS T1 JOIN model_list AS T2 ON T1.model = T2.model WHERE T1.weight 3500 EXCEPT SELECT DISTINCT T2.model FROM car_makers AS T1 JOIN model_list AS T2 ON T1.model = T2.model WHERE T1.maker = "Ford Motor Company" Gold: SELECT DISTINCT T1.model FROM MODEL_LIST AS T1 JOIN CAR_NAMES AS T2 ON T1.Model = T2.Model JOIN CARS_DATA AS T3 ON T2.MakeId = T3.Id JOIN CAR_MAKERS AS T4 ON T1.Maker = T4.Id WHERE T3.weight < 3500 AND T4.FullName <> 'Ford Motor Company' Type: JOIN [118] OTHER | DB: car_1 | EX: ✗ Q : What are the name of the countries where there is not a single car maker Pred: SELECT countryname FROM countries EXCEPT SELECT T1.countryname FROM countries AS T1 JOIN car_makers AS T2 ON T1.country = T2.countryid Gold: SELECT CountryName FROM countries EXCEPT SELECT T1.CountryName FROM countries AS T1 JOIN CAR_MAKERS AS T2 ON T1.countryId = T2.Country Type: JOIN [119] WRONG_TABLE | DB: car_1 | EX: ✗ Q : What are the names of the countries with no car makers Pred: SELECT countryname FROM countries WHERE NOT countryid IN (SELECT countryid FROM car_makers) Gold: SELECT CountryName FROM countries EXCEPT SELECT T1.CountryName FROM countries AS T1 JOIN CAR_MAKERS AS T2 ON T1.countryId = T2.Country Type: JOIN [120] OTHER | DB: car_1 | EX: ✗ Q : Which are the car makers which produce at least 2 models and more than 3 car makers ? List the id and the maker Pred: SELECT T1.id, T1.maker FROM car_makers AS T1 JOIN model_list AS T2 ON T1.id = T2.model GROUP BY T1.id HAVING COUNT(*) >= 2 INTERSECT SELECT T1.id, T1.maker FROM car_makers AS T1 JOIN model_list AS T2 ON T1.id = T2.model GROUP BY T1.id HAVING COUNT(*) >= 3 Gold: SELECT t1.id, t1.maker FROM car_makers AS t1 JOIN model_list AS t2 ON t1.id = t2.maker GROUP BY t1.id HAVING COUNT(*) >= 2 INTERSECT SELECT t1.id, t1.maker FROM car_makers AS t1 JOIN model_list AS t2 ON t1.id = t2.maker JOIN car_names AS t3 ON t2.model = t3.model GROUP BY t1.id HAVING COUNT(*) > 3 Type: JOIN, GROUP_BY, HAVING, AGGREGATION [121] OTHER | DB: car_1 | EX: ✗ Q : What are the ids and makers of all car makers that produce at least 2 models and make more than 3 cars Pred: SELECT T1.id, T1.maker FROM car_makers AS T1 JOIN model_list AS T2 ON T1.id = T2.model GROUP BY T1.maker HAVING COUNT(*) >= 2 INTERSECT SELECT T1.id, T1.maker FROM car_makers AS T1 JOIN model_list AS T2 ON T1.id = T2.model GROUP BY T1.maker HAVING COUNT(*) >= 3 Gold: SELECT T1.Id, T1.Maker FROM CAR_MAKERS AS T1 JOIN MODEL_LIST AS T2 ON T1.Id = T2.Maker GROUP BY T1.Id HAVING COUNT(*) >= 2 INTERSECT SELECT T1.Id, T1.Maker FROM CAR_MAKERS AS T1 JOIN MODEL_LIST AS T2 ON T1.Id = T2.Maker JOIN CAR_NAMES AS T3 ON T2.model = T3.model GROUP BY T1.Id HAVING COUNT(*) > 3 Type: JOIN, GROUP_BY, HAVING, AGGREGATION [122] OTHER | DB: car_1 | EX: ✗ Q : What are the id and names of the countries which have more than 3 car makers or produce the 'fiat' model Pred: SELECT T1.countryid, T1.countryname FROM countries AS T1 JOIN car_makers AS T2 ON T1.country = T2.countryid WHERE T2.make = 'Fiat' GROUP BY T1.countryid HAVING COUNT(*) > 3 UNION SELECT T1.countryid, T1.countryname FROM countries AS T1 JOIN model_list AS T2 ON T1.country = T2.model WHERE T2.model = 'Fiat' Gold: SELECT T1.countryId, T1.CountryName FROM Countries AS T1 JOIN CAR_MAKERS AS T2 ON T1.CountryId = T2.Country GROUP BY T1.countryId HAVING COUNT(*) > 3 UNION SELECT T1.countryId, T1.CountryName FROM Countries AS T1 JOIN CAR_MAKERS AS T2 ON T1.CountryId = T2.Country JOIN MODEL_LIST AS T3 ON T2.Id = T3.Maker WHERE T3.Model = 'fiat' Type: JOIN, GROUP_BY, HAVING, AGGREGATION [123] OTHER | DB: car_1 | EX: ✗ Q : What are the ids and names of all countries that either have more than 3 car makers or produce fiat model Pred: SELECT T1.countryid, T1.countryname FROM countries AS T1 JOIN car_makers AS T2 ON T1.country = T2.countryid GROUP BY T1.countryid HAVING COUNT(*) > 3 UNION SELECT T1.countryid, T1.countryname FROM countries AS T1 JOIN model_list AS T2 ON T1.country = T2.modelid WHERE T2.make = "Fiat" Gold: SELECT t1.countryid, t1.countryname FROM countries AS t1 JOIN car_makers AS t2 ON t1.countryid = t2.country GROUP BY t1.countryid HAVING COUNT(*) > 3 UNION SELECT t1.countryid, t1.countryname FROM countries AS t1 JOIN car_makers AS t2 ON t1.countryid = t2.country JOIN model_list AS t3 ON t2.id = t3.maker WHERE t3.model = 'fiat' Type: JOIN, GROUP_BY, HAVING, AGGREGATION [124] OTHER | DB: flight_2 | EX: ✗ Q : Which abbreviation corresponds to Jetblue Airways Pred: SELECT abbreviation FROM airlines WHERE airline = 'Jitblue Airways' Gold: SELECT Abbreviation FROM AIRLINES WHERE Airline = "JetBlue Airways" Type: SIMPLE [125] OTHER | DB: flight_2 | EX: ✓ Q : Which city and country is the Alton airport at Pred: SELECT city, country FROM airports WHERE airportname = 'Altons' Gold: SELECT City, Country FROM AIRPORTS WHERE AirportName = "Alton" Type: SIMPLE [126] OTHER | DB: flight_2 | EX: ✗ Q : What is the airport name for airport 'AKO' Pred: SELECT airportname FROM airports WHERE airportname = 'AKO' Gold: SELECT AirportName FROM AIRPORTS WHERE AirportCode = "AKO" Type: SIMPLE [127] OTHER | DB: flight_2 | EX: ✗ Q : How many flights depart from 'APG' Pred: SELECT COUNT(*) FROM flights WHERE abbreviation = 'APG' Gold: SELECT COUNT(*) FROM FLIGHTS WHERE SourceAirport = "APG" Type: AGGREGATION [128] OTHER | DB: flight_2 | EX: ✗ Q : Count the number of flights departing from 'APG' Pred: SELECT COUNT(*) FROM flights WHERE abbreviation = 'APG' Gold: SELECT COUNT(*) FROM FLIGHTS WHERE SourceAirport = "APG" Type: AGGREGATION [129] EXTRA_JOIN | DB: flight_2 | EX: ✗ Q : How many flights have destination ATO Pred: SELECT COUNT(*) FROM flights AS T1 JOIN airports AS T2 ON T1.airportcode = T2.sourceairport WHERE T2.country = "ATO" Gold: SELECT COUNT(*) FROM FLIGHTS WHERE DestAirport = "ATO" Type: AGGREGATION [130] OTHER | DB: flight_2 | EX: ✗ Q : Count the number of flights into ATO Pred: SELECT COUNT(*) FROM flights WHERE airportcode = 'ATO' Gold: SELECT COUNT(*) FROM FLIGHTS WHERE DestAirport = "ATO" Type: AGGREGATION [131] WRONG_TABLE | DB: flight_2 | EX: ✓ Q : How many flights depart from City Aberdeen Pred: SELECT COUNT(*) FROM airports WHERE city = "Aberdeen" Gold: SELECT COUNT(*) FROM FLIGHTS AS T1 JOIN AIRPORTS AS T2 ON T1.SourceAirport = T2.AirportCode WHERE T2.City = "Aberdeen" Type: JOIN, AGGREGATION [132] MISSING_JOIN | DB: flight_2 | EX: ✗ Q : Return the number of flights departing from Aberdeen Pred: SELECT COUNT(*) FROM flights WHERE airports = "Aberdeen" Gold: SELECT COUNT(*) FROM FLIGHTS AS T1 JOIN AIRPORTS AS T2 ON T1.SourceAirport = T2.AirportCode WHERE T2.City = "Aberdeen" Type: JOIN, AGGREGATION [133] WRONG_TABLE | DB: flight_2 | EX: ✓ Q : How many flights arriving in Aberdeen city Pred: SELECT COUNT(*) FROM airports WHERE city = 'Aberdeen' Gold: SELECT COUNT(*) FROM FLIGHTS AS T1 JOIN AIRPORTS AS T2 ON T1.DestAirport = T2.AirportCode WHERE T2.City = "Aberdeen" Type: JOIN, AGGREGATION [134] WRONG_TABLE | DB: flight_2 | EX: ✗ Q : Return the number of flights arriving in Aberdeen Pred: SELECT COUNT(*) FROM airports AS T1 JOIN flights AS T2 ON T1.airport = T2.sourceairport WHERE T1.city = "Aberdeen" Gold: SELECT COUNT(*) FROM FLIGHTS AS T1 JOIN AIRPORTS AS T2 ON T1.DestAirport = T2.AirportCode WHERE T2.City = "Aberdeen" Type: JOIN, AGGREGATION [135] OTHER | DB: flight_2 | EX: ✗ Q : How many flights depart from City 'Aberdeen' and have destination City 'Ashley' Pred: SELECT COUNT(*) FROM flights AS T1 JOIN airports AS T2 ON T1.airport = T2.sourceairport WHERE T2.city = 'Aberdeen' AND T2.airportcode = 'Ashley' Gold: SELECT COUNT(*) FROM FLIGHTS AS T1 JOIN AIRPORTS AS T2 ON T1.DestAirport = T2.AirportCode JOIN AIRPORTS AS T3 ON T1.SourceAirport = T3.AirportCode WHERE T2.City = "Ashley" AND T3.City = "Aberdeen" Type: JOIN, AGGREGATION [136] WRONG_TABLE | DB: flight_2 | EX: ✗ Q : How many flights fly from Aberdeen to Ashley Pred: SELECT COUNT(*) FROM airports AS T1 JOIN flights AS T2 ON T1.airport = T2.sourceairport WHERE T1.airportcode = "Ashley" AND T1.city = "Aberdeen" Gold: SELECT COUNT(*) FROM FLIGHTS AS T1 JOIN AIRPORTS AS T2 ON T1.DestAirport = T2.AirportCode JOIN AIRPORTS AS T3 ON T1.SourceAirport = T3.AirportCode WHERE T2.City = "Ashley" AND T3.City = "Aberdeen" Type: JOIN, AGGREGATION [137] WRONG_TABLE | DB: flight_2 | EX: ✗ Q : How many flights does airline 'JetBlue Airways' have Pred: SELECT COUNT(*) FROM airlines AS T1 JOIN flights AS T2 ON T1.uid = T2.sourceairport WHERE T1.airline = 'JetBlue Airways' Gold: SELECT COUNT(*) FROM FLIGHTS AS T1 JOIN AIRLINES AS T2 ON T1.Airline = T2.uid WHERE T2.Airline = "JetBlue Airways" Type: JOIN, AGGREGATION [138] WRONG_TABLE | DB: flight_2 | EX: ✗ Q : Give the number of Jetblue Airways flights Pred: SELECT COUNT(*) FROM airlines AS T1 JOIN flights AS T2 ON T1.uid = T2.sourceairport WHERE T1.abbreviation = "Jitblue Airways" Gold: SELECT COUNT(*) FROM FLIGHTS AS T1 JOIN AIRLINES AS T2 ON T1.Airline = T2.uid WHERE T2.Airline = "JetBlue Airways" Type: JOIN, AGGREGATION [139] OTHER | DB: flight_2 | EX: ✗ Q : How many 'United Airlines' flights go to Airport 'ASY' Pred: SELECT COUNT(*) FROM airlines AS T1 JOIN flights AS T2 ON T1.uid = T2.unitedairport WHERE T1.airportname = 'ASY' Gold: SELECT COUNT(*) FROM AIRLINES AS T1 JOIN FLIGHTS AS T2 ON T2.Airline = T1.uid WHERE T1.Airline = "United Airlines" AND T2.DestAirport = "ASY" Type: JOIN, AGGREGATION [140] WRONG_TABLE | DB: flight_2 | EX: ✗ Q : Count the number of United Airlines flights arriving in ASY Airport Pred: SELECT COUNT(*) FROM airports AS T1 JOIN flights AS T2 ON T1.airport = T2.sourceairport WHERE T1.airportname = "ASY" AND T2.abbreviation = "United Airlines" Gold: SELECT COUNT(*) FROM AIRLINES AS T1 JOIN FLIGHTS AS T2 ON T2.Airline = T1.uid WHERE T1.Airline = "United Airlines" AND T2.DestAirport = "ASY" Type: JOIN, AGGREGATION [141] WRONG_TABLE | DB: flight_2 | EX: ✗ Q : How many 'United Airlines' flights depart from Airport 'AHD' Pred: SELECT COUNT(*) FROM flights AS T1 JOIN airports AS T2 ON T1.airport = T2.sourceairport WHERE T2.airportcode = 'AHD' AND T1.uid = 'United Airlines' Gold: SELECT COUNT(*) FROM AIRLINES AS T1 JOIN FLIGHTS AS T2 ON T2.Airline = T1.uid WHERE T1.Airline = "United Airlines" AND T2.SourceAirport = "AHD" Type: JOIN, AGGREGATION [142] WRONG_TABLE | DB: flight_2 | EX: ✗ Q : Return the number of United Airlines flights leaving from AHD Airport Pred: SELECT COUNT(*) FROM flights AS T1 JOIN airports AS T2 ON T1.airport = T2.airportcode JOIN airlines AS T3 ON T1.uid = T3.uid WHERE T2.airportname = 'AHD Airport' AND T3.airportname = 'United Airlines' Gold: SELECT COUNT(*) FROM AIRLINES AS T1 JOIN FLIGHTS AS T2 ON T2.Airline = T1.uid WHERE T1.Airline = "United Airlines" AND T2.SourceAirport = "AHD" Type: JOIN, AGGREGATION [143] WRONG_TABLE | DB: flight_2 | EX: ✗ Q : How many United Airlines flights go to City 'Aberdeen' Pred: SELECT COUNT(*) FROM airlines AS T1 JOIN flights AS T2 ON T1.uid = T2.united airlines WHERE T1.city = 'Aberdeen' Gold: SELECT COUNT(*) FROM FLIGHTS AS T1 JOIN AIRPORTS AS T2 ON T1.DestAirport = T2.AirportCode JOIN AIRLINES AS T3 ON T3.uid = T1.Airline WHERE T2.City = "Aberdeen" AND T3.Airline = "United Airlines" Type: JOIN, AGGREGATION [144] OTHER | DB: flight_2 | EX: ✗ Q : Count the number of United Airlines flights that arrive in Aberdeen Pred: SELECT COUNT(*) FROM flights AS T1 JOIN airports AS T2 ON T1.airport = T2.sourceairport WHERE T2.airportcode = "Aberdeen" AND T1.uid = "United Airlines" Gold: SELECT COUNT(*) FROM FLIGHTS AS T1 JOIN AIRPORTS AS T2 ON T1.DestAirport = T2.AirportCode JOIN AIRLINES AS T3 ON T3.uid = T1.Airline WHERE T2.City = "Aberdeen" AND T3.Airline = "United Airlines" Type: JOIN, AGGREGATION [145] WRONG_TABLE | DB: flight_2 | EX: ✗ Q : Which city has most number of arriving flights Pred: SELECT city FROM flights GROUP BY city ORDER BY COUNT(*) DESC LIMIT 1 Gold: SELECT T1.City FROM AIRPORTS AS T1 JOIN FLIGHTS AS T2 ON T1.AirportCode = T2.DestAirport GROUP BY T1.City ORDER BY COUNT(*) DESC LIMIT 1 Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, AGGREGATION [146] MISSING_JOIN | DB: flight_2 | EX: ✗ Q : Which city has the most frequent destination airport Pred: SELECT city FROM airports ORDER BY airportname DESC LIMIT 1 Gold: SELECT T1.City FROM AIRPORTS AS T1 JOIN FLIGHTS AS T2 ON T1.AirportCode = T2.DestAirport GROUP BY T1.City ORDER BY COUNT(*) DESC LIMIT 1 Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, AGGREGATION [147] WRONG_TABLE | DB: flight_2 | EX: ✓ Q : Which city has most number of departing flights Pred: SELECT T1.city FROM airports AS T1 JOIN flights AS T2 ON T1.airportcode = T2.sourceairport WHERE T2.flightno = (SELECT MAX(flightno) FROM flights) Gold: SELECT T1.City FROM AIRPORTS AS T1 JOIN FLIGHTS AS T2 ON T1.AirportCode = T2.SourceAirport GROUP BY T1.City ORDER BY COUNT(*) DESC LIMIT 1 Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, AGGREGATION [148] OTHER | DB: flight_2 | EX: ✗ Q : Which city is the most frequent source airport Pred: SELECT T1.city FROM airports AS T1 JOIN flights AS T2 ON T1.airport = T2.sourceairport GROUP BY T2.city ORDER BY COUNT(*) DESC LIMIT 1 Gold: SELECT T1.City FROM AIRPORTS AS T1 JOIN FLIGHTS AS T2 ON T1.AirportCode = T2.SourceAirport GROUP BY T1.City ORDER BY COUNT(*) DESC LIMIT 1 Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, AGGREGATION [149] MISSING_JOIN | DB: flight_2 | EX: ✗ Q : What is the code of airport that has the highest number of flights Pred: SELECT airportcode FROM airports GROUP BY airportcode ORDER BY COUNT(*) DESC LIMIT 1 Gold: SELECT T1.AirportCode FROM AIRPORTS AS T1 JOIN FLIGHTS AS T2 ON T1.AirportCode = T2.DestAirport OR T1.AirportCode = T2.SourceAirport GROUP BY T1.AirportCode ORDER BY COUNT(*) DESC LIMIT 1 Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, AGGREGATION [150] MISSING_JOIN | DB: flight_2 | EX: ✗ Q : What is the airport code of the airport with the most flights Pred: SELECT airportcode FROM airports GROUP BY airportcode ORDER BY COUNT(*) DESC LIMIT 1 Gold: SELECT T1.AirportCode FROM AIRPORTS AS T1 JOIN FLIGHTS AS T2 ON T1.AirportCode = T2.DestAirport OR T1.AirportCode = T2.SourceAirport GROUP BY T1.AirportCode ORDER BY COUNT(*) DESC LIMIT 1 Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, AGGREGATION [151] MISSING_JOIN | DB: flight_2 | EX: ✗ Q : What is the code of airport that has fewest number of flights Pred: SELECT airportcode FROM airports ORDER BY flightno ASC LIMIT 1 Gold: SELECT T1.AirportCode FROM AIRPORTS AS T1 JOIN FLIGHTS AS T2 ON T1.AirportCode = T2.DestAirport OR T1.AirportCode = T2.SourceAirport GROUP BY T1.AirportCode ORDER BY COUNT(*) LIMIT 1 Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, AGGREGATION [152] MISSING_JOIN | DB: flight_2 | EX: ✗ Q : Give the code of the airport with the least flights Pred: SELECT airportcode FROM airports GROUP BY airportcode ORDER BY COUNT(*) LIMIT 1 Gold: SELECT T1.AirportCode FROM AIRPORTS AS T1 JOIN FLIGHTS AS T2 ON T1.AirportCode = T2.DestAirport OR T1.AirportCode = T2.SourceAirport GROUP BY T1.AirportCode ORDER BY COUNT(*) LIMIT 1 Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, AGGREGATION [153] OTHER | DB: flight_2 | EX: ✗ Q : Which airline has most number of flights Pred: SELECT T1.Airline FROM airlines AS T1 JOIN flights AS T2 ON T1.Airline = T2.Airline GROUP BY T1.Airline ORDER BY COUNT(*) DESC LIMIT 1 Gold: SELECT T1.Airline FROM AIRLINES AS T1 JOIN FLIGHTS AS T2 ON T1.uid = T2.Airline GROUP BY T1.Airline ORDER BY COUNT(*) DESC LIMIT 1 Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, AGGREGATION [154] OTHER | DB: flight_2 | EX: ✗ Q : What airline serves the most flights Pred: SELECT T1.Airline FROM airlines AS T1 JOIN flights AS T2 ON T1.Airline = T2.Airline GROUP BY T1.Airline ORDER BY COUNT(*) DESC LIMIT 1 Gold: SELECT T1.Airline FROM AIRLINES AS T1 JOIN FLIGHTS AS T2 ON T1.uid = T2.Airline GROUP BY T1.Airline ORDER BY COUNT(*) DESC LIMIT 1 Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, AGGREGATION [155] MISSING_JOIN | DB: flight_2 | EX: ✓ Q : Find the abbreviation and country of the airline that has fewest number of flights Pred: SELECT abbreviation, country FROM airlines GROUP BY abbreviation ORDER BY COUNT(*) LIMIT 1 Gold: SELECT T1.Abbreviation, T1.Country FROM AIRLINES AS T1 JOIN FLIGHTS AS T2 ON T1.uid = T2.Airline GROUP BY T1.Airline ORDER BY COUNT(*) LIMIT 1 Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, AGGREGATION [156] WRONG_TABLE | DB: flight_2 | EX: ✗ Q : What is the abbreviation of the airilne has the fewest flights and what country is it in Pred: SELECT abbreviation, country FROM flights GROUP BY abbreviation ORDER BY COUNT(*) ASC LIMIT 1 Gold: SELECT T1.Abbreviation, T1.Country FROM AIRLINES AS T1 JOIN FLIGHTS AS T2 ON T1.uid = T2.Airline GROUP BY T1.Airline ORDER BY COUNT(*) LIMIT 1 Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, AGGREGATION [157] OTHER | DB: flight_2 | EX: ✗ Q : What are airlines that have some flight departing from airport 'AHD' Pred: SELECT T1.airline FROM airlines AS T1 JOIN flights AS T2 ON T1.uid = T2.flightno WHERE T2.airportname = 'AHD' Gold: SELECT T1.Airline FROM AIRLINES AS T1 JOIN FLIGHTS AS T2 ON T1.uid = T2.Airline WHERE T2.SourceAirport = "AHD" Type: JOIN [158] OTHER | DB: flight_2 | EX: ✓ Q : Which airlines have a flight with source airport AHD Pred: SELECT T1.airline FROM airlines AS T1 JOIN flights AS T2 ON T1.uid = T2.flightno WHERE T2.sourceairport = 'AHD' Gold: SELECT T1.Airline FROM AIRLINES AS T1 JOIN FLIGHTS AS T2 ON T1.uid = T2.Airline WHERE T2.SourceAirport = "AHD" Type: JOIN [159] OTHER | DB: flight_2 | EX: ✗ Q : What are airlines that have flights arriving at airport 'AHD' Pred: SELECT T1.airline FROM airlines AS T1 JOIN flights AS T2 ON T1.uid = T2.flightno JOIN airports AS T3 ON T2.airportcode = T3.airportcode WHERE T3.airportname = 'AHD' Gold: SELECT T1.Airline FROM AIRLINES AS T1 JOIN FLIGHTS AS T2 ON T1.uid = T2.Airline WHERE T2.DestAirport = "AHD" Type: JOIN [160] OTHER | DB: flight_2 | EX: ✓ Q : Which airlines have a flight with destination airport AHD Pred: SELECT T1.airline FROM airlines AS T1 JOIN flights AS T2 ON T1.uid = T2.flightno JOIN airports AS T3 ON T2.sourceairport = T3.airportcode WHERE T3.airportname = 'AHD' Gold: SELECT T1.Airline FROM AIRLINES AS T1 JOIN FLIGHTS AS T2 ON T1.uid = T2.Airline WHERE T2.DestAirport = "AHD" Type: JOIN [161] OTHER | DB: flight_2 | EX: ✗ Q : Find all airlines that have flights from both airports 'APG' and 'CVO' Pred: SELECT T1.airline FROM airlines AS T1 JOIN flights AS T2 ON T1.uid = T2.flightno WHERE T2.airportname = 'APG' INTERSECT SELECT T1.airline FROM airlines AS T1 JOIN airports AS T2 ON T1.airportcode = T2.airportcode WHERE T2.airportname = 'CVO' Gold: SELECT T1.Airline FROM AIRLINES AS T1 JOIN FLIGHTS AS T2 ON T1.uid = T2.Airline WHERE T2.SourceAirport = "APG" INTERSECT SELECT T1.Airline FROM AIRLINES AS T1 JOIN FLIGHTS AS T2 ON T1.uid = T2.Airline WHERE T2.SourceAirport = "CVO" Type: JOIN [162] OTHER | DB: flight_2 | EX: ✗ Q : Which airlines have departing flights from both APG and CVO airports Pred: SELECT T1.airline FROM airlines AS T1 JOIN flights AS T2 ON T1.uid = T2.flightno WHERE T2.airportcode = 'APG' INTERSECT SELECT T1.airline FROM airlines AS T1 JOIN airports AS T2 ON T1.airport = T2.airportcode WHERE T2.airportname = 'CVO' Gold: SELECT T1.Airline FROM AIRLINES AS T1 JOIN FLIGHTS AS T2 ON T1.uid = T2.Airline WHERE T2.SourceAirport = "APG" INTERSECT SELECT T1.Airline FROM AIRLINES AS T1 JOIN FLIGHTS AS T2 ON T1.uid = T2.Airline WHERE T2.SourceAirport = "CVO" Type: JOIN [163] OTHER | DB: flight_2 | EX: ✗ Q : Find all airlines that have flights from airport 'CVO' but not from 'APG' Pred: SELECT T1.airline FROM airlines AS T1 JOIN flights AS T2 ON T1.uid = T2.flightno WHERE T2.airportcode = 'CVO' EXCEPT SELECT T1.airline FROM airlines AS T1 JOIN airports AS T2 ON T1.airportcode = T2.sourceairport WHERE T2.airportname = 'APG' Gold: SELECT T1.Airline FROM AIRLINES AS T1 JOIN FLIGHTS AS T2 ON T1.uid = T2.Airline WHERE T2.SourceAirport = "CVO" EXCEPT SELECT T1.Airline FROM AIRLINES AS T1 JOIN FLIGHTS AS T2 ON T1.uid = T2.Airline WHERE T2.SourceAirport = "APG" Type: JOIN [164] OTHER | DB: flight_2 | EX: ✗ Q : Which airlines have departures from CVO but not from APG airports Pred: SELECT T1.airline FROM airlines AS T1 JOIN airports AS T2 ON T1.uid = T2.sourceairport WHERE T2.airportcode = "CVO" EXCEPT SELECT T1.airline FROM airlines AS T1 JOIN airports AS T2 ON T1.uid = T2.sourceairport WHERE T2.airportcode = "APG" Gold: SELECT T1.Airline FROM AIRLINES AS T1 JOIN FLIGHTS AS T2 ON T1.uid = T2.Airline WHERE T2.SourceAirport = "CVO" EXCEPT SELECT T1.Airline FROM AIRLINES AS T1 JOIN FLIGHTS AS T2 ON T1.uid = T2.Airline WHERE T2.SourceAirport = "APG" Type: JOIN [165] OTHER | DB: flight_2 | EX: ✗ Q : Find all airlines that have at least 10 flights Pred: SELECT T1.Airline FROM airlines AS T1 JOIN flights AS T2 ON T1.UID = T2.FlightNo GROUP BY T1.Airline HAVING COUNT(*) >= 10 Gold: SELECT T1.Airline FROM AIRLINES AS T1 JOIN FLIGHTS AS T2 ON T1.uid = T2.Airline GROUP BY T1.Airline HAVING COUNT(*) > 10 Type: JOIN, GROUP_BY, HAVING, AGGREGATION [166] OTHER | DB: flight_2 | EX: ✗ Q : Which airlines have at least 10 flights Pred: SELECT T1.Airline FROM airlines AS T1 JOIN flights AS T2 ON T1.UID = T2.FlightNo GROUP BY T1.Airline HAVING COUNT(*) >= 10 Gold: SELECT T1.Airline FROM AIRLINES AS T1 JOIN FLIGHTS AS T2 ON T1.uid = T2.Airline GROUP BY T1.Airline HAVING COUNT(*) > 10 Type: JOIN, GROUP_BY, HAVING, AGGREGATION [167] WRONG_TABLE | DB: flight_2 | EX: ✗ Q : Find all airlines that have fewer than 200 flights Pred: SELECT airline FROM flights GROUP BY airline HAVING COUNT(*) 200 Gold: SELECT T1.Airline FROM AIRLINES AS T1 JOIN FLIGHTS AS T2 ON T1.uid = T2.Airline GROUP BY T1.Airline HAVING COUNT(*) < 200 Type: JOIN, GROUP_BY, HAVING, AGGREGATION [168] WRONG_TABLE | DB: flight_2 | EX: ✗ Q : Which airlines have less than 200 flights Pred: SELECT airline FROM flights GROUP BY airline HAVING COUNT(*) 200 Gold: SELECT T1.Airline FROM AIRLINES AS T1 JOIN FLIGHTS AS T2 ON T1.uid = T2.Airline GROUP BY T1.Airline HAVING COUNT(*) < 200 Type: JOIN, GROUP_BY, HAVING, AGGREGATION [169] OTHER | DB: flight_2 | EX: ✗ Q : What are flight numbers of Airline "United Airlines" Pred: SELECT T1.flightno FROM flights AS T1 JOIN airlines AS T2 ON T1.uid = T2.airline WHERE T2.name = "United Airlines" Gold: SELECT T1.FlightNo FROM FLIGHTS AS T1 JOIN AIRLINES AS T2 ON T2.uid = T1.Airline WHERE T2.Airline = "United Airlines" Type: JOIN [170] OTHER | DB: flight_2 | EX: ✗ Q : Which flight numbers correspond to United Airlines flights Pred: SELECT T1.flightno FROM flights AS T1 JOIN airlines AS T2 ON T1.uid = T2.airline WHERE T2.name = 'United Airlines' Gold: SELECT T1.FlightNo FROM FLIGHTS AS T1 JOIN AIRLINES AS T2 ON T2.uid = T1.Airline WHERE T2.Airline = "United Airlines" Type: JOIN [171] EXTRA_JOIN | DB: flight_2 | EX: ✗ Q : What are flight numbers of flights departing from Airport "APG" Pred: SELECT T1.FlightNo FROM flights AS T1 JOIN airports AS T2 ON T1.Airport = T2.AirportCode WHERE T2.AirportName = "APG" Gold: SELECT FlightNo FROM FLIGHTS WHERE SourceAirport = "APG" Type: SIMPLE [172] EXTRA_JOIN | DB: flight_2 | EX: ✗ Q : What are flight numbers of flights arriving at Airport "APG" Pred: SELECT T1.flightno FROM flights AS T1 JOIN airports AS T2 ON T1.airport = T2.airportcode WHERE T2.airportname = "APG" Gold: SELECT FlightNo FROM FLIGHTS WHERE DestAirport = "APG" Type: SIMPLE [173] EXTRA_JOIN | DB: flight_2 | EX: ✗ Q : Give the flight numbers of flights landing at APG Pred: SELECT T1.FlightNo FROM flights AS T1 JOIN airports AS T2 ON T1.Airport = T2.AirportCode WHERE T2.AirportName = "APG" Gold: SELECT FlightNo FROM FLIGHTS WHERE DestAirport = "APG" Type: SIMPLE [174] OTHER | DB: flight_2 | EX: ✗ Q : Give the flight numbers of flights leaving from Aberdeen Pred: SELECT T1.FlightNo FROM flights AS T1 JOIN airports AS T2 ON T1.Airport = T2.AirportCode WHERE T2.AirportName = "Aberdeen" Gold: SELECT T1.FlightNo FROM FLIGHTS AS T1 JOIN AIRPORTS AS T2 ON T1.SourceAirport = T2.AirportCode WHERE T2.City = "Aberdeen" Type: JOIN [175] OTHER | DB: flight_2 | EX: ✗ Q : What are flight numbers of flights arriving at City "Aberdeen" Pred: SELECT T1.flightno FROM flights AS T1 JOIN airports AS T2 ON T1.airport = T2.airportcode WHERE T2.city = "Aberdeen" Gold: SELECT T1.FlightNo FROM FLIGHTS AS T1 JOIN AIRPORTS AS T2 ON T1.DestAirport = T2.AirportCode WHERE T2.City = "Aberdeen" Type: JOIN [176] OTHER | DB: flight_2 | EX: ✗ Q : Give the flight numbers of flights arriving in Aberdeen Pred: SELECT T1.FlightNo FROM flights AS T1 JOIN airports AS T2 ON T1.Airport = T2.AirportCode WHERE T2.AirportName = "Aberdeen" Gold: SELECT T1.FlightNo FROM FLIGHTS AS T1 JOIN AIRPORTS AS T2 ON T1.DestAirport = T2.AirportCode WHERE T2.City = "Aberdeen" Type: JOIN [177] WRONG_TABLE | DB: flight_2 | EX: ✗ Q : Find the number of flights landing in the city of Aberdeen or Abilene Pred: SELECT COUNT(*) FROM airports AS T1 JOIN flights AS T2 ON T1.airport = T2.sourceairport WHERE T1.city = "Aberdeen" OR T1.airportcode = "Abilene" Gold: SELECT COUNT(*) FROM Flights AS T1 JOIN Airports AS T2 ON T1.DestAirport = T2.AirportCode WHERE T2.city = "Aberdeen" OR T2.city = "Abilene" Type: JOIN, AGGREGATION [178] WRONG_TABLE | DB: flight_2 | EX: ✗ Q : How many flights land in Aberdeen or Abilene Pred: SELECT COUNT(*) FROM airports AS T1 JOIN flights AS T2 ON T1.airport = T2.sourceairport WHERE T1.city = "Aberdeen" OR T1.airportcode = "Abilene" Gold: SELECT COUNT(*) FROM Flights AS T1 JOIN Airports AS T2 ON T1.DestAirport = T2.AirportCode WHERE T2.city = "Aberdeen" OR T2.city = "Abilene" Type: JOIN, AGGREGATION [179] WRONG_COLUMNS | DB: flight_2 | EX: ✗ Q : Find the name of airports which do not have any flight in and out Pred: SELECT airportname FROM airports WHERE NOT airportcode IN (SELECT airportcode FROM flights) Gold: SELECT AirportName FROM Airports WHERE NOT AirportCode IN (SELECT SourceAirport FROM Flights UNION SELECT DestAirport FROM Flights) Type: NESTED [180] WRONG_COLUMNS | DB: flight_2 | EX: ✗ Q : Which airports do not have departing or arriving flights Pred: SELECT airportname FROM airports WHERE NOT airportcode IN (SELECT airportcode FROM flights WHERE flightno > 0) OR flightno > 0 Gold: SELECT AirportName FROM Airports WHERE NOT AirportCode IN (SELECT SourceAirport FROM Flights UNION SELECT DestAirport FROM Flights) Type: NESTED [181] OTHER | DB: employee_hire_evaluation | EX: ✓ Q : Sort employee names by their age in ascending order Pred: SELECT Name FROM employee ORDER BY Age ASC Gold: SELECT name FROM employee ORDER BY age Type: ORDER_BY [182] OTHER | DB: employee_hire_evaluation | EX: ✓ Q : List the names of employees and sort in ascending order of age Pred: SELECT Name FROM employee ORDER BY Age ASC Gold: SELECT name FROM employee ORDER BY age Type: ORDER_BY [183] WRONG_COLUMNS | DB: employee_hire_evaluation | EX: ✗ Q : What is the number of employees from each city Pred: SELECT City, COUNT(*) FROM employee GROUP BY City Gold: SELECT COUNT(*), city FROM employee GROUP BY city Type: GROUP_BY, AGGREGATION [184] OTHER | DB: employee_hire_evaluation | EX: ✗ Q : Which cities do more than one employee under age 30 come from Pred: SELECT city FROM employee WHERE age 30 GROUP BY city HAVING COUNT(*) > 1 Gold: SELECT city FROM employee WHERE age < 30 GROUP BY city HAVING COUNT(*) > 1 Type: GROUP_BY, HAVING, AGGREGATION [185] OTHER | DB: employee_hire_evaluation | EX: ✗ Q : Find the cities that have more than one employee under age 30 Pred: SELECT city FROM employee WHERE age 30 GROUP BY city HAVING COUNT(*) > 1 Gold: SELECT city FROM employee WHERE age < 30 GROUP BY city HAVING COUNT(*) > 1 Type: GROUP_BY, HAVING, AGGREGATION [186] WRONG_COLUMNS | DB: employee_hire_evaluation | EX: ✗ Q : Find the number of shops in each location Pred: SELECT LOCATION, COUNT(*) FROM shop GROUP BY LOCATION Gold: SELECT COUNT(*), LOCATION FROM shop GROUP BY LOCATION Type: GROUP_BY, AGGREGATION [187] WRONG_COLUMNS | DB: employee_hire_evaluation | EX: ✗ Q : How many shops are there in each location Pred: SELECT LOCATION, COUNT(*) FROM shop GROUP BY LOCATION Gold: SELECT COUNT(*), LOCATION FROM shop GROUP BY LOCATION Type: GROUP_BY, AGGREGATION [188] EXTRA_JOIN | DB: employee_hire_evaluation | EX: ✗ Q : Find the manager name and district of the shop whose number of products is the largest Pred: SELECT T2.manager_name, T2.District FROM shop AS T1 JOIN employee AS T2 ON T1.Shop_ID = T2.Shop_ID ORDER BY T1.Number_Products DESC LIMIT 1 Gold: SELECT manager_name, district FROM shop ORDER BY number_products DESC LIMIT 1 Type: ORDER_BY, LIMIT [189] EXTRA_JOIN | DB: employee_hire_evaluation | EX: ✗ Q : What are the manager name and district of the shop that sells the largest number of products Pred: SELECT T2.manager_name, T2.District FROM shop AS T1 JOIN employee AS T2 ON T1.Shop_ID = T2.Shop_ID ORDER BY T1.Number_Products DESC LIMIT 1 Gold: SELECT manager_name, district FROM shop ORDER BY number_products DESC LIMIT 1 Type: ORDER_BY, LIMIT [190] WRONG_TABLE | DB: employee_hire_evaluation | EX: ✗ Q : Which employee received the most awards in evaluations? Give me the employee name Pred: SELECT T1.name FROM employee AS T1 JOIN evaluation AS T2 ON T1.employee_id = T2.employee_id WHERE T2.year_awarded = (SELECT MAX(year_awarded) FROM evaluation) Gold: SELECT t1.name FROM employee AS t1 JOIN evaluation AS t2 ON t1.Employee_ID = t2.Employee_ID GROUP BY t2.Employee_ID ORDER BY COUNT(*) DESC LIMIT 1 Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, AGGREGATION [191] WRONG_TABLE | DB: employee_hire_evaluation | EX: ✓ Q : Find the name of the employee who got the highest one time bonus Pred: SELECT T1.name FROM employee AS T1 JOIN evaluation AS T2 ON T1.employee_id = T2.employee_id WHERE T2.bonus = (SELECT MAX(bonus) FROM evaluation) Gold: SELECT t1.name FROM employee AS t1 JOIN evaluation AS t2 ON t1.Employee_ID = t2.Employee_ID ORDER BY t2.bonus DESC LIMIT 1 Type: JOIN, ORDER_BY, LIMIT [192] WRONG_TABLE | DB: employee_hire_evaluation | EX: ✓ Q : Which employee received the biggest bonus? Give me the employee name Pred: SELECT T1.name FROM employee AS T1 JOIN evaluation AS T2 ON T1.employee_id = T2.employee_id WHERE T2.bonus = (SELECT MAX(bonus) FROM evaluation) Gold: SELECT t1.name FROM employee AS t1 JOIN evaluation AS t2 ON t1.Employee_ID = t2.Employee_ID ORDER BY t2.bonus DESC LIMIT 1 Type: JOIN, ORDER_BY, LIMIT [193] WRONG_TABLE | DB: employee_hire_evaluation | EX: ✗ Q : Which shop has the most employees? Give me the shop name Pred: SELECT T2.Name FROM employee AS T1 JOIN hiring AS T2 ON T1.Employee_ID = T2.Employee_ID JOIN shop AS T3 ON T3.Shop_ID = T2.Shop_ID GROUP BY T3.Name ORDER BY COUNT(*) DESC LIMIT 1 Gold: SELECT t2.name FROM hiring AS t1 JOIN shop AS t2 ON t1.shop_id = t2.shop_id GROUP BY t1.shop_id ORDER BY COUNT(*) DESC LIMIT 1 Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, AGGREGATION [194] WRONG_TABLE | DB: employee_hire_evaluation | EX: ✗ Q : Which shops run with no employees? Find the shop names Pred: SELECT name FROM shop WHERE NOT shop_id IN (SELECT shop_id FROM employee) Gold: SELECT name FROM shop WHERE NOT shop_id IN (SELECT shop_id FROM hiring) Type: NESTED [195] WRONG_COLUMNS | DB: employee_hire_evaluation | EX: ✗ Q : Find the number of employees hired in each shop; show the shop name as well Pred: SELECT T2.Name, COUNT(*) FROM hiring AS T1 JOIN shop AS T2 ON T1.Shop_ID = T2.Shop_ID GROUP BY T1.Shop_ID Gold: SELECT COUNT(*), t2.name FROM hiring AS t1 JOIN shop AS t2 ON t1.shop_id = t2.shop_id GROUP BY t2.name Type: JOIN, GROUP_BY, AGGREGATION [196] WRONG_TABLE | DB: employee_hire_evaluation | EX: ✗ Q : For each shop, return the number of employees working there and the name of the shop Pred: SELECT T2.Name, COUNT(*) FROM employee AS T1 JOIN shop AS T2 ON T1.Shop_ID = T2.Shop_ID GROUP BY T1.Shop_ID Gold: SELECT COUNT(*), t2.name FROM hiring AS t1 JOIN shop AS t2 ON t1.shop_id = t2.shop_id GROUP BY t2.name Type: JOIN, GROUP_BY, AGGREGATION [197] OTHER | DB: employee_hire_evaluation | EX: ✗ Q : Which district has both stores with less than 3000 products and stores with more than 10000 products Pred: SELECT District FROM shop WHERE Number_Products 3000 INTERSECT SELECT District FROM shop WHERE Number_Products > 10000 Gold: SELECT district FROM shop WHERE Number_products < 3000 INTERSECT SELECT district FROM shop WHERE Number_products > 10000 Type: SIMPLE [198] OTHER | DB: employee_hire_evaluation | EX: ✗ Q : Find the districts in which there are both shops selling less than 3000 products and shops selling more than 10000 products Pred: SELECT District FROM shop WHERE Number_Products 3000 INTERSECT SELECT District FROM shop WHERE Number_Products > 10000 Gold: SELECT district FROM shop WHERE Number_products < 3000 INTERSECT SELECT district FROM shop WHERE Number_products > 10000 Type: SIMPLE [199] EXTRA_JOIN | DB: cre_Doc_Template_Mgt | EX: ✓ Q : What is the document id, template id and description for document named "Robbin CV" Pred: SELECT T1.document_id, T2.template_id, T1.document_description FROM Documents AS T1 JOIN Templates AS T2 ON T1.template_id = T2.template_id WHERE T1.document_name = "Robbin CV" Gold: SELECT document_id, template_id, Document_Description FROM Documents WHERE document_name = "Robbin CV" Type: SIMPLE [200] EXTRA_JOIN | DB: cre_Doc_Template_Mgt | EX: ✓ Q : Return the document id, template id, and description for the document with the name Robbin CV Pred: SELECT T1.document_id, T2.template_id, T1.document_description FROM Documents AS T1 JOIN Templates AS T2 ON T1.template_id = T2.template_id WHERE T1.document_name = "Robbin CV" Gold: SELECT document_id, template_id, Document_Description FROM Documents WHERE document_name = "Robbin CV" Type: SIMPLE [201] MISSING_JOIN | DB: cre_Doc_Template_Mgt | EX: ✗ Q : Count the number of documents that use the PPT template type Pred: SELECT COUNT(*) FROM Documents WHERE template_type_code = "PPT" Gold: SELECT COUNT(*) FROM Documents AS T1 JOIN Templates AS T2 ON T1.Template_ID = T2.Template_ID WHERE T2.Template_Type_Code = 'PPT' Type: JOIN, AGGREGATION [202] WRONG_COLUMNS | DB: cre_Doc_Template_Mgt | EX: ✓ Q : What are all different template ids used for documents, and how many times were each of them used Pred: SELECT DISTINCT template_id, COUNT(*) FROM documents GROUP BY template_id Gold: SELECT template_id, COUNT(*) FROM Documents GROUP BY template_id Type: GROUP_BY, AGGREGATION [203] WRONG_TABLE | DB: cre_Doc_Template_Mgt | EX: ✗ Q : What are the different template type codes Pred: SELECT DISTINCT template_type_code Gold: SELECT DISTINCT template_type_code FROM Templates Type: SIMPLE [204] EXTRA_JOIN | DB: cre_Doc_Template_Mgt | EX: ✓ Q : What is the version number and template type code for the template with version number later than 5 Pred: SELECT T1.version_number, T2.template_type_code FROM Templates AS T1 JOIN Templates AS T2 ON T1.template_id = T2.template_id WHERE T1.version_number > 5 Gold: SELECT version_number, template_type_code FROM Templates WHERE version_number > 5 Type: SIMPLE [205] EXTRA_JOIN | DB: cre_Doc_Template_Mgt | EX: ✓ Q : Return the version numbers and template type codes of templates with a version number greater than 5 Pred: SELECT T1.version_number, T2.template_type_code FROM Templates AS T1 JOIN Templates AS T2 ON T1.template_id = T2.template_id WHERE T1.version_number > 5 Gold: SELECT version_number, template_type_code FROM Templates WHERE version_number > 5 Type: SIMPLE [206] WRONG_TABLE | DB: cre_Doc_Template_Mgt | EX: ✓ Q : Return the type code of the template type that the most templates belong to Pred: SELECT T1.template_type_code FROM Ref_template_types AS T1 JOIN templates AS T2 ON T1.template_type_code = T2.template_type_code GROUP BY T1.template_type_code ORDER BY COUNT(*) DESC LIMIT 1 Gold: SELECT template_type_code FROM Templates GROUP BY template_type_code ORDER BY COUNT(*) DESC LIMIT 1 Type: GROUP_BY, ORDER_BY, LIMIT, AGGREGATION [207] OTHER | DB: cre_Doc_Template_Mgt | EX: ✗ Q : Show all template type codes with less than three templates Pred: SELECT template_type_code FROM Templates GROUP BY template_type_code HAVING COUNT(*) 3 Gold: SELECT template_type_code FROM Templates GROUP BY template_type_code HAVING COUNT(*) < 3 Type: GROUP_BY, HAVING, AGGREGATION [208] OTHER | DB: cre_Doc_Template_Mgt | EX: ✗ Q : What are the codes of template types that have fewer than 3 templates Pred: SELECT template_type_code FROM Templates GROUP BY template_type_code HAVING COUNT(*) 3 Gold: SELECT template_type_code FROM Templates GROUP BY template_type_code HAVING COUNT(*) < 3 Type: GROUP_BY, HAVING, AGGREGATION [209] WRONG_TABLE | DB: cre_Doc_Template_Mgt | EX: ✓ Q : What is the template type code of the template used by document with the name "Data base" Pred: SELECT T2.template_type_code FROM documents AS T1 JOIN templates AS T2 ON T1.template_id = T2.template_id WHERE T1.document_name = "Data base" Gold: SELECT T1.template_type_code FROM Templates AS T1 JOIN Documents AS T2 ON T1.template_id = T2.template_id WHERE T2.document_name = "Data base" Type: JOIN [210] WRONG_TABLE | DB: cre_Doc_Template_Mgt | EX: ✓ Q : Return the template type code of the template that is used by a document named Data base Pred: SELECT T2.template_type_code FROM documents AS T1 JOIN templates AS T2 ON T1.template_id = T2.template_id WHERE T1.document_name = "Data base" Gold: SELECT T1.template_type_code FROM Templates AS T1 JOIN Documents AS T2 ON T1.template_id = T2.template_id WHERE T2.document_name = "Data base" Type: JOIN [211] WRONG_TABLE | DB: cre_Doc_Template_Mgt | EX: ✗ Q : Show all document names using templates with template type code BK Pred: SELECT document_name FROM documents WHERE template_type_code = "BK" Gold: SELECT T2.document_name FROM Templates AS T1 JOIN Documents AS T2 ON T1.template_id = T2.template_id WHERE T1.template_type_code = "BK" Type: JOIN [212] WRONG_TABLE | DB: cre_Doc_Template_Mgt | EX: ✓ Q : What are the names of documents that use templates with the code BK Pred: SELECT document_name FROM documents WHERE template_id IN (SELECT template_id FROM Templates WHERE template_type_code = "BK") Gold: SELECT T2.document_name FROM Templates AS T1 JOIN Documents AS T2 ON T1.template_id = T2.template_id WHERE T1.template_type_code = "BK" Type: JOIN [213] WRONG_COLUMNS | DB: cre_Doc_Template_Mgt | EX: ✗ Q : Show all template type codes and the number of documents using each type Pred: SELECT T2.template_type_code, COUNT(*) FROM Templates AS T1 JOIN Documents AS T2 ON T1.template_id = T2.template_id GROUP BY T2.template_type_code Gold: SELECT T1.template_type_code, COUNT(*) FROM Templates AS T1 JOIN Documents AS T2 ON T1.template_id = T2.template_id GROUP BY T1.template_type_code Type: JOIN, GROUP_BY, AGGREGATION [214] WRONG_TABLE | DB: cre_Doc_Template_Mgt | EX: ✗ Q : What are the different template type codes, and how many documents use each type Pred: SELECT T1.template_type_code, COUNT(*) FROM Ref_template_types AS T1 JOIN templates AS T2 ON T1.template_type_code = T2.template_type_code GROUP BY T1.template_type_code Gold: SELECT T1.template_type_code, COUNT(*) FROM Templates AS T1 JOIN Documents AS T2 ON T1.template_id = T2.template_id GROUP BY T1.template_type_code Type: JOIN, GROUP_BY, AGGREGATION [215] WRONG_TABLE | DB: cre_Doc_Template_Mgt | EX: ✗ Q : Which template type code is used by most number of documents Pred: SELECT template_type_code FROM Documents GROUP BY template_type_code ORDER BY COUNT(*) DESC LIMIT 1 Gold: SELECT T1.template_type_code FROM Templates AS T1 JOIN Documents AS T2 ON T1.template_id = T2.template_id GROUP BY T1.template_type_code ORDER BY COUNT(*) DESC LIMIT 1 Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, AGGREGATION [216] MISSING_JOIN | DB: cre_Doc_Template_Mgt | EX: ✗ Q : Return the code of the template type that is most commonly used in documents Pred: SELECT template_type_code FROM Templates GROUP BY template_type_code ORDER BY COUNT(*) DESC LIMIT 1 Gold: SELECT T1.template_type_code FROM Templates AS T1 JOIN Documents AS T2 ON T1.template_id = T2.template_id GROUP BY T1.template_type_code ORDER BY COUNT(*) DESC LIMIT 1 Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, AGGREGATION [217] MISSING_JOIN | DB: cre_Doc_Template_Mgt | EX: ✗ Q : Show all template type codes that are not used by any document Pred: SELECT template_type_code FROM Templates EXCEPT SELECT template_type_code FROM Templates Gold: SELECT template_type_code FROM Templates EXCEPT SELECT template_type_code FROM Templates AS T1 JOIN Documents AS T2 ON T1.template_id = T2.template_id Type: JOIN [218] MISSING_JOIN | DB: cre_Doc_Template_Mgt | EX: ✗ Q : What are the codes of template types that are not used for any document Pred: SELECT template_type_code FROM Templates EXCEPT SELECT template_type_code FROM Templates Gold: SELECT template_type_code FROM Templates EXCEPT SELECT template_type_code FROM Templates AS T1 JOIN Documents AS T2 ON T1.template_id = T2.template_id Type: JOIN [219] EXTRA_JOIN | DB: cre_Doc_Template_Mgt | EX: ✗ Q : What is the template type code for template type description "Book" Pred: SELECT T1.template_type_code FROM Ref_template_types AS T1 JOIN templates AS T2 ON T1.template_type_code = T2.template_type_code WHERE T2.template_type_description = "Book" Gold: SELECT template_type_code FROM Ref_template_types WHERE template_type_description = "Book" Type: SIMPLE [220] OTHER | DB: cre_Doc_Template_Mgt | EX: ✗ Q : What are the distinct template type descriptions for the templates ever used by any document Pred: SELECT DISTINCT T1.template_type_description FROM Ref_template_types AS T1 JOIN templates AS T2 ON T1.template_type_code = T2.template_type_code Gold: SELECT DISTINCT T1.template_type_description FROM Ref_template_types AS T1 JOIN Templates AS T2 ON T1.template_type_code = T2.template_type_code JOIN Documents AS T3 ON T2.Template_ID = T3.template_ID Type: JOIN [221] WRONG_TABLE | DB: cre_Doc_Template_Mgt | EX: ✗ Q : Return the different descriptions for templates that have been used in a document Pred: SELECT DISTINCT template_type_description FROM templates Gold: SELECT DISTINCT T1.template_type_description FROM Ref_template_types AS T1 JOIN Templates AS T2 ON T1.template_type_code = T2.template_type_code JOIN Documents AS T3 ON T2.Template_ID = T3.template_ID Type: JOIN [222] WRONG_TABLE | DB: cre_Doc_Template_Mgt | EX: ✗ Q : What are the template ids with template type description "Presentation" Pred: SELECT template_id FROM Templates WHERE template_type_description = "Presentation" Gold: SELECT T2.template_id FROM Ref_template_types AS T1 JOIN Templates AS T2 ON T1.template_type_code = T2.template_type_code WHERE T1.template_type_description = "Presentation" Type: JOIN [223] WRONG_TABLE | DB: cre_Doc_Template_Mgt | EX: ✗ Q : Return the ids corresponding to templates with the description 'Presentation' Pred: SELECT template_id FROM Templates WHERE document_description = 'Presentation' Gold: SELECT T2.template_id FROM Ref_template_types AS T1 JOIN Templates AS T2 ON T1.template_type_code = T2.template_type_code WHERE T1.template_type_description = "Presentation" Type: JOIN [224] OTHER | DB: cre_Doc_Template_Mgt | EX: ✓ Q : Show paragraph details for paragraph with text 'Korea ' Pred: SELECT other_details FROM Paragraphs WHERE paragraph_text LIKE '%Korea%' Gold: SELECT other_details FROM paragraphs WHERE paragraph_text LIKE 'korea' Type: SIMPLE [225] OTHER | DB: cre_Doc_Template_Mgt | EX: ✓ Q : What are the details for the paragraph that includes the text 'Korea ' Pred: SELECT other_details FROM Paragraphs WHERE paragraph_text LIKE '%Korea%' Gold: SELECT other_details FROM paragraphs WHERE paragraph_text LIKE 'korea' Type: SIMPLE [226] WRONG_TABLE | DB: cre_Doc_Template_Mgt | EX: ✓ Q : What are the paragraph texts for the document with the name 'Customer reviews' Pred: SELECT t2.paragraph_text FROM documents AS t1 JOIN paragraphs AS t2 ON t1.document_id = t2.document_id WHERE t1.document_name = "Customer reviews" Gold: SELECT T1.paragraph_text FROM Paragraphs AS T1 JOIN Documents AS T2 ON T1.document_id = T2.document_id WHERE T2.document_name = "Customer reviews" Type: JOIN [227] OTHER | DB: cre_Doc_Template_Mgt | EX: ✗ Q : Show all document ids and the number of paragraphs in each document. Order by document id Pred: SELECT document_id, COUNT(*) FROM paragraphs GROUP BY document_id ORDER BY COUNT(*) Gold: SELECT document_id, COUNT(*) FROM Paragraphs GROUP BY document_id ORDER BY document_id Type: GROUP_BY, ORDER_BY, AGGREGATION [228] OTHER | DB: cre_Doc_Template_Mgt | EX: ✗ Q : Return the different document ids along with the number of paragraphs corresponding to each, ordered by id Pred: SELECT document_id, COUNT(*) FROM paragraphs GROUP BY document_id ORDER BY COUNT(*) Gold: SELECT document_id, COUNT(*) FROM Paragraphs GROUP BY document_id ORDER BY document_id Type: GROUP_BY, ORDER_BY, AGGREGATION [229] WRONG_TABLE | DB: cre_Doc_Template_Mgt | EX: ✓ Q : Show all document ids, names and the number of paragraphs in each document Pred: SELECT T1.document_id, T1.document_name, COUNT(*) FROM Documents AS T1 JOIN Paragraphs AS T2 ON T1.document_id = T2.document_id GROUP BY T1.document_id Gold: SELECT T1.document_id, T2.document_name, COUNT(*) FROM Paragraphs AS T1 JOIN Documents AS T2 ON T1.document_id = T2.document_id GROUP BY T1.document_id Type: JOIN, GROUP_BY, AGGREGATION [230] WRONG_TABLE | DB: cre_Doc_Template_Mgt | EX: ✓ Q : What are the ids and names of each document, as well as the number of paragraphs in each Pred: SELECT T1.document_id, T1.document_name, COUNT(*) FROM Documents AS T1 JOIN Paragraphs AS T2 ON T1.document_id = T2.document_id GROUP BY T1.document_id Gold: SELECT T1.document_id, T2.document_name, COUNT(*) FROM Paragraphs AS T1 JOIN Documents AS T2 ON T1.document_id = T2.document_id GROUP BY T1.document_id Type: JOIN, GROUP_BY, AGGREGATION [231] WRONG_TABLE | DB: cre_Doc_Template_Mgt | EX: ✓ Q : What is the document id and name with greatest number of paragraphs Pred: SELECT T1.document_id, T1.document_name FROM Documents AS T1 JOIN Paragraphs AS T2 ON T1.document_id = T2.document_id GROUP BY T1.document_id ORDER BY COUNT(*) DESC LIMIT 1 Gold: SELECT T1.document_id, T2.document_name FROM Paragraphs AS T1 JOIN Documents AS T2 ON T1.document_id = T2.document_id GROUP BY T1.document_id ORDER BY COUNT(*) DESC LIMIT 1 Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, AGGREGATION [232] WRONG_TABLE | DB: cre_Doc_Template_Mgt | EX: ✓ Q : Return the id and name of the document with the most paragraphs Pred: SELECT T1.document_id, T1.document_name FROM Documents AS T1 JOIN Paragraphs AS T2 ON T1.document_id = T2.document_id GROUP BY T1.document_id ORDER BY COUNT(*) DESC LIMIT 1 Gold: SELECT T1.document_id, T2.document_name FROM Paragraphs AS T1 JOIN Documents AS T2 ON T1.document_id = T2.document_id GROUP BY T1.document_id ORDER BY COUNT(*) DESC LIMIT 1 Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, AGGREGATION [233] WRONG_TABLE | DB: cre_Doc_Template_Mgt | EX: ✓ Q : Return the id of the document with the fewest paragraphs Pred: SELECT t1.document_id FROM Documents AS t1 JOIN Paragraphs AS t2 ON t1.document_id = t2.document_id GROUP BY t1.document_id ORDER BY COUNT(*) LIMIT 1 Gold: SELECT document_id FROM Paragraphs GROUP BY document_id ORDER BY COUNT(*) ASC LIMIT 1 Type: GROUP_BY, ORDER_BY, LIMIT, AGGREGATION [234] WRONG_TABLE | DB: cre_Doc_Template_Mgt | EX: ✗ Q : Show the document id with paragraph text 'Brazil' and 'Ireland' Pred: SELECT T1.document_id FROM Documents AS T1 JOIN Paragraphs AS T2 ON T1.document_id = T2.document_id WHERE T2.paragraph_text = 'Brazil' INTERSECT SELECT T1.document_id FROM Documents AS T1 JOIN Paragraphs AS T2 ON T1.paragraph_id = T2.document_id WHERE T2.paragraph_text = 'Irland' Gold: SELECT document_id FROM Paragraphs WHERE paragraph_text = 'Brazil' INTERSECT SELECT document_id FROM Paragraphs WHERE paragraph_text = 'Ireland' Type: SIMPLE [235] WRONG_TABLE | DB: cre_Doc_Template_Mgt | EX: ✓ Q : What are the ids of documents that contain the paragraph text 'Brazil' and 'Ireland' Pred: SELECT T1.document_id FROM Documents AS T1 JOIN Paragraphs AS T2 ON T1.document_id = T2.document_id WHERE T2.paragraph_text = 'Brazil' INTERSECT SELECT T1.document_id FROM Documents AS T1 JOIN Paragraphs AS T2 ON T1.document_id = T2.document_id WHERE T2.paragraph_text LIKE '%Ireland%' Gold: SELECT document_id FROM Paragraphs WHERE paragraph_text = 'Brazil' INTERSECT SELECT document_id FROM Paragraphs WHERE paragraph_text = 'Ireland' Type: SIMPLE [236] OTHER | DB: course_teach | EX: ✓ Q : List the name of teachers whose hometown is not `` Little Lever Urban District '' Pred: SELECT Name FROM teacher WHERE Hometown > ' Little Lever Urban District ''' Gold: SELECT name FROM teacher WHERE hometown <> "little lever urban district" Type: SIMPLE [237] OTHER | DB: course_teach | EX: ✓ Q : What are the names of the teachers whose hometown is not `` Little Lever Urban District '' Pred: SELECT Name FROM teacher WHERE Hometown > ' Little Lever Urban District ''' Gold: SELECT name FROM teacher WHERE hometown <> "little lever urban district" Type: SIMPLE [238] WRONG_COLUMNS | DB: course_teach | EX: ✗ Q : Show names of teachers and the courses they are arranged to teach Pred: SELECT T3.Name, T1.Course FROM course_arrange AS T1 JOIN teacher AS T2 ON T1.Teacher_ID = T2.Teacher_ID Gold: SELECT T3.Name, T2.Course FROM course_arrange AS T1 JOIN course AS T2 ON T1.Course_ID = T2.Course_ID JOIN teacher AS T3 ON T1.Teacher_ID = T3.Teacher_ID Type: JOIN [239] WRONG_COLUMNS | DB: course_teach | EX: ✗ Q : What is the name of each teacher and what course they teach Pred: SELECT T2.Name, T1.Course FROM course_arrange AS T1 JOIN teacher AS T2 ON T1.Teacher_ID = T2.Teacher_ID Gold: SELECT T3.Name, T2.Course FROM course_arrange AS T1 JOIN course AS T2 ON T1.Course_ID = T2.Course_ID JOIN teacher AS T3 ON T1.Teacher_ID = T3.Teacher_ID Type: JOIN [240] WRONG_COLUMNS | DB: course_teach | EX: ✗ Q : Show names of teachers and the courses they are arranged to teach in ascending alphabetical order of the teacher's name Pred: SELECT T3.Name, T1.Course FROM course_arrange AS T1 JOIN teacher AS T2 ON T1.Teacher_ID = T2.Teacher_ID ORDER BY T2.Name ASC Gold: SELECT T3.Name, T2.Course FROM course_arrange AS T1 JOIN course AS T2 ON T1.Course_ID = T2.Course_ID JOIN teacher AS T3 ON T1.Teacher_ID = T3.Teacher_ID ORDER BY T3.Name Type: JOIN, ORDER_BY [241] WRONG_COLUMNS | DB: course_teach | EX: ✗ Q : What are the names of the teachers and the courses they teach in ascending alphabetical order by the name of the teacher Pred: SELECT T3.Name, T1.Course FROM course_arrange AS T1 JOIN teacher AS T2 ON T1.Teacher_ID = T2.Teacher_ID ORDER BY T2.Name ASC Gold: SELECT T3.Name, T2.Course FROM course_arrange AS T1 JOIN course AS T2 ON T1.Course_ID = T2.Course_ID JOIN teacher AS T3 ON T1.Teacher_ID = T3.Teacher_ID ORDER BY T3.Name Type: JOIN, ORDER_BY [242] OTHER | DB: course_teach | EX: ✗ Q : Show the name of the teacher for the math course Pred: SELECT T3.Name FROM course_arrange AS T1 JOIN teacher AS T2 ON T1.Teacher_ID = T2.Teacher_ID JOIN course AS T3 ON T1.Course_ID = T3.Course_ID WHERE T3.course = 'Math' Gold: SELECT T3.Name FROM course_arrange AS T1 JOIN course AS T2 ON T1.Course_ID = T2.Course_ID JOIN teacher AS T3 ON T1.Teacher_ID = T3.Teacher_ID WHERE T2.Course = "Math" Type: JOIN [243] OTHER | DB: course_teach | EX: ✗ Q : What are the names of the people who teach math courses Pred: SELECT T3.Name FROM course_arrange AS T1 JOIN teacher AS T2 ON T1.Teacher_ID = T2.Teacher_ID JOIN course AS T3 ON T1.Course_ID = T3.Course_ID WHERE T3.Computer = "Math" Gold: SELECT T3.Name FROM course_arrange AS T1 JOIN course AS T2 ON T1.Course_ID = T2.Course_ID JOIN teacher AS T3 ON T1.Teacher_ID = T3.Teacher_ID WHERE T2.Course = "Math" Type: JOIN [244] OTHER | DB: museum_visit | EX: ✗ Q : How many visitors below age 30 are there Pred: SELECT COUNT(*) FROM visitor WHERE age 30 Gold: SELECT COUNT(*) FROM visitor WHERE age < 30 Type: AGGREGATION [245] OTHER | DB: museum_visit | EX: ✗ Q : Find the names of the visitors whose membership level is higher than 4, and order the results by the level from high to low Pred: SELECT name FROM visitor WHERE level_of_membership > 4 ORDER BY level_of_membership Gold: SELECT name FROM visitor WHERE Level_of_membership > 4 ORDER BY Level_of_membership DESC Type: ORDER_BY [246] OTHER | DB: museum_visit | EX: ✗ Q : What is the average age of the visitors whose membership level is not higher than 4 Pred: SELECT AVG(age) FROM visitor WHERE level_of_membership 4 Gold: SELECT AVG(age) FROM visitor WHERE Level_of_membership <= 4 Type: AGGREGATION [247] EXTRA_JOIN | DB: museum_visit | EX: ✗ Q : Find the id and name of the museum that has the most staff members Pred: SELECT T1.museum_id, T1.name FROM museum AS T1 JOIN visitor AS T2 ON T1.museum_id = T2.museum_id GROUP BY T1.museum_id ORDER BY SUM(T2.num_of_staff) DESC LIMIT 1 Gold: SELECT museum_id, name FROM museum ORDER BY num_of_staff DESC LIMIT 1 Type: ORDER_BY, LIMIT [248] OTHER | DB: museum_visit | EX: ✗ Q : Find the average number of staff working for the museums that were open before 2009 Pred: SELECT AVG(Num_of_staff) FROM museum WHERE open_year 2009 Gold: SELECT AVG(num_of_staff) FROM museum WHERE open_year < 2009 Type: AGGREGATION [249] WRONG_COLUMNS | DB: museum_visit | EX: ✗ Q : What are the opening year and staff number of the museum named Plaza Museum Pred: SELECT open_year, num_of_staff FROM museum WHERE name = 'Place Museum' Gold: SELECT Num_of_Staff, Open_Year FROM museum WHERE name = 'Plaza Museum' Type: SIMPLE [250] OTHER | DB: museum_visit | EX: ✓ Q : find the id, name and age for visitors who visited some museums more than once Pred: SELECT T1.id, T1.name, T1.age FROM visitor AS T1 JOIN visit AS T2 ON T1.id = T2.visitor_id GROUP BY T2.visitor_id HAVING COUNT(*) > 1 Gold: SELECT t1.id, t1.name, t1.age FROM visitor AS t1 JOIN visit AS t2 ON t1.id = t2.visitor_id GROUP BY t1.id HAVING COUNT(*) > 1 Type: JOIN, GROUP_BY, HAVING, AGGREGATION [251] MISSING_GROUP_BY | DB: museum_visit | EX: ✗ Q : What are the id, name and membership level of visitors who have spent the largest amount of money in total in all museum tickets Pred: SELECT T1.id, T1.name, T1.level_of_membership FROM visitor AS T1 JOIN visit AS T2 ON T1.id = T2.visitor_id ORDER BY SUM(T2.num_of_ticket) DESC LIMIT 1 Gold: SELECT t2.visitor_id, t1.name, t1.Level_of_membership FROM visitor AS t1 JOIN visit AS t2 ON t1.id = t2.visitor_id GROUP BY t2.visitor_id ORDER BY SUM(t2.Total_spent) DESC LIMIT 1 Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, AGGREGATION [252] WRONG_TABLE | DB: museum_visit | EX: ✗ Q : What are the id and name of the museum visited most times Pred: SELECT T1.id, T1.name FROM visitor AS T1 JOIN visit AS T2 ON T1.id = T2.visitor_id GROUP BY T1.id ORDER BY COUNT(*) DESC LIMIT 1 Gold: SELECT t2.Museum_ID, t1.name FROM museum AS t1 JOIN visit AS t2 ON t1.Museum_ID = t2.Museum_ID GROUP BY t2.Museum_ID ORDER BY COUNT(*) DESC LIMIT 1 Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, AGGREGATION [253] WRONG_COLUMNS | DB: museum_visit | EX: ✗ Q : What is the name of the museum that had no visitor yet Pred: SELECT name FROM museum WHERE NOT museum_id IN (SELECT visitor_id FROM visit) Gold: SELECT name FROM museum WHERE NOT Museum_ID IN (SELECT museum_id FROM visit) Type: NESTED [254] OTHER | DB: museum_visit | EX: ✓ Q : Find the name and age of the visitor who bought the most tickets at once Pred: SELECT T1.name, T1.age FROM visitor AS T1 JOIN visit AS T2 ON T1.id = T2.visitor_id GROUP BY T2.visitor_id ORDER BY SUM(T2.num_of_ticket) DESC LIMIT 1 Gold: SELECT t1.name, t1.age FROM visitor AS t1 JOIN visit AS t2 ON t1.id = t2.visitor_id ORDER BY t2.num_of_ticket DESC LIMIT 1 Type: JOIN, ORDER_BY, LIMIT [255] WRONG_TABLE | DB: museum_visit | EX: ✗ Q : What are the average and maximum number of tickets bought in all visits Pred: SELECT AVG(Num_of_ticket), MAX(Num_of_ticket) FROM visitor Gold: SELECT AVG(num_of_ticket), MAX(num_of_ticket) FROM visit Type: AGGREGATION [256] WRONG_COLUMNS | DB: museum_visit | EX: ✗ Q : What is the total ticket expense of the visitors whose membership level is 1 Pred: SELECT SUM(T1.num_of_ticket) FROM visitor AS T1 JOIN visit AS T2 ON T1.id = T2.visitor_id WHERE T1.level_of_membership = 1 Gold: SELECT SUM(t2.Total_spent) FROM visitor AS t1 JOIN visit AS t2 ON t1.id = t2.visitor_id WHERE t1.Level_of_membership = 1 Type: JOIN, AGGREGATION [257] OTHER | DB: museum_visit | EX: ✗ Q : What is the name of the visitor who visited both a museum opened before 2009 and a museum opened after 2011 Pred: SELECT T1.name FROM visitor AS T1 JOIN visit AS T2 ON T1.id = T2.visitor_id WHERE T2.open_year 2009 INTERSECT SELECT T1.name FROM visitor AS T1 JOIN visit AS T2 ON T1.id = T2.visitor_id WHERE T2.open_year > 2011 Gold: SELECT t1.name FROM visitor AS t1 JOIN visit AS t2 ON t1.id = t2.visitor_id JOIN museum AS t3 ON t3.Museum_ID = t2.Museum_ID WHERE t3.open_year < 2009 INTERSECT SELECT t1.name FROM visitor AS t1 JOIN visit AS t2 ON t1.id = t2.visitor_id JOIN museum AS t3 ON t3.Museum_ID = t2.Museum_ID WHERE t3.open_year > 2011 Type: JOIN [258] WRONG_TABLE | DB: museum_visit | EX: ✗ Q : Find the number of visitors who did not visit any museum opened after 2010 Pred: SELECT COUNT(*) FROM visitor WHERE NOT visitor_id IN (SELECT visitor_id FROM visit WHERE open_year > 2010) Gold: SELECT COUNT(*) FROM visitor WHERE NOT id IN (SELECT t2.visitor_id FROM museum AS t1 JOIN visit AS t2 ON t1.Museum_ID = t2.Museum_ID WHERE t1.open_year > 2010) Type: JOIN, NESTED, AGGREGATION [259] OTHER | DB: museum_visit | EX: ✗ Q : How many museums were opened after 2013 or before 2008 Pred: SELECT COUNT(*) FROM museum WHERE open_year > 2013 OR open_year 2008 Gold: SELECT COUNT(*) FROM museum WHERE open_year > 2013 OR open_year < 2008 Type: AGGREGATION [260] EXTRA_JOIN | DB: wta_1 | EX: ✗ Q : Find the average age of losers and winners of all matches Pred: SELECT AVG(T1.loser_age), AVG(T2.winner_age) FROM matches AS T1 JOIN players AS T2 ON T1.winner_id = T2.player_id Gold: SELECT AVG(loser_age), AVG(winner_age) FROM matches Type: AGGREGATION [261] EXTRA_JOIN | DB: wta_1 | EX: ✗ Q : What are the average ages of losers and winners across matches Pred: SELECT AVG(T1.loser_age), AVG(T2.winner_age) FROM matches AS T1 JOIN players AS T2 ON T1.winner_id = T2.player_id Gold: SELECT AVG(loser_age), AVG(winner_age) FROM matches Type: AGGREGATION [262] WRONG_COLUMNS | DB: wta_1 | EX: ✗ Q : Find the highest rank of losers in all matches Pred: SELECT MAX(Loser_rank) FROM matches Gold: SELECT MIN(loser_rank) FROM matches Type: AGGREGATION [263] EXTRA_JOIN | DB: wta_1 | EX: ✗ Q : What is the best rank of losers across all matches Pred: SELECT DISTINCT T1.loser_rank, MAX(T2.loser_rank) FROM matches AS T1 JOIN rankings AS T2 ON T1.loser_id = T2.loser_id GROUP BY T1.loser_rank Gold: SELECT MIN(loser_rank) FROM matches Type: AGGREGATION [264] WRONG_TABLE | DB: wta_1 | EX: ✗ Q : Find the number of distinct name of losers Pred: SELECT COUNT(DISTINCT loser_name) FROM players Gold: SELECT COUNT(DISTINCT loser_name) FROM matches Type: AGGREGATION [265] WRONG_TABLE | DB: wta_1 | EX: ✗ Q : How many different loser names are there Pred: SELECT COUNT(DISTINCT loser_name) FROM players Gold: SELECT COUNT(DISTINCT loser_name) FROM matches Type: AGGREGATION [266] EXTRA_JOIN | DB: wta_1 | EX: ✗ Q : Find the name of tourney that has more than 10 matches Pred: SELECT T2.Tournament_Name FROM matches AS T1 JOIN tournament AS T2 ON T1.Tournament_ID = T2.Tournament_ID GROUP BY T2.Tournament_Name HAVING COUNT(*) > 10 Gold: SELECT tourney_name FROM matches GROUP BY tourney_name HAVING COUNT(*) > 10 Type: GROUP_BY, HAVING, AGGREGATION [267] EXTRA_JOIN | DB: wta_1 | EX: ✗ Q : What are the names of tournaments that have more than 10 matches Pred: SELECT T2.Tournament_Name FROM matches AS T1 JOIN tournaments AS T2 ON T1.Tournament_ID = T2.Tournament_ID GROUP BY T2.Tournament_Name HAVING COUNT(*) > 10 Gold: SELECT tourney_name FROM matches GROUP BY tourney_name HAVING COUNT(*) > 10 Type: GROUP_BY, HAVING, AGGREGATION [268] WRONG_TABLE | DB: wta_1 | EX: ✗ Q : List the names of all winners who played in both 2013 and 2016 Pred: SELECT winner_name FROM players WHERE YEAR = 2013 INTERSECT SELECT winner_name FROM players WHERE YEAR = 2016 Gold: SELECT winner_name FROM matches WHERE YEAR = 2013 INTERSECT SELECT winner_name FROM matches WHERE YEAR = 2016 Type: SIMPLE [269] WRONG_TABLE | DB: wta_1 | EX: ✗ Q : What are the names of players who won in both 2013 and 2016 Pred: SELECT T2.winner_name FROM matches AS T1 JOIN players AS T2 ON T1.player_id = T2.winner_id WHERE T1.year = 2013 INTERSECT SELECT T2.winner_name FROM rankings AS T1 JOIN players AS T2 ON T1.player_id = T2.winner_id WHERE T1.year = 2016 Gold: SELECT winner_name FROM matches WHERE YEAR = 2013 INTERSECT SELECT winner_name FROM matches WHERE YEAR = 2016 Type: SIMPLE [270] OTHER | DB: wta_1 | EX: ✗ Q : What are the country code and first name of the players who won in both tourney WTA Championships and Australian Open Pred: SELECT T1.country_code, T1.first_name FROM players AS T1 JOIN matches AS T2 ON T1.player_id = T2.winner_id WHERE T2.tournament_name = 'WTA Championships' INTERSECT SELECT T1.country_code, T1.first_name FROM players AS T1 JOIN rankings AS T2 ON T1.player_id = T2.player_id WHERE T2.tournament_name = 'Australian Open' Gold: SELECT T1.country_code, T1.first_name FROM players AS T1 JOIN matches AS T2 ON T1.player_id = T2.winner_id WHERE T2.tourney_name = 'WTA Championships' INTERSECT SELECT T1.country_code, T1.first_name FROM players AS T1 JOIN matches AS T2 ON T1.player_id = T2.winner_id WHERE T2.tourney_name = 'Australian Open' Type: JOIN [271] WRONG_TABLE | DB: wta_1 | EX: ✗ Q : What are the first names and country codes for players who won both the WTA Championships and the Australian Open Pred: SELECT T2.first_name, T2.country_code FROM rankings AS T1 JOIN players AS T2 ON T1.player_id = T2.player_id JOIN tournaments AS T3 ON T1.tournament_name = T3.tournament_name JOIN players AS T4 ON T3.player_id = T4.player_id WHERE T3.tournament_name = 'WTA Championships' INTERSECT SELECT T2.country_code = 'Australian Open' Gold: SELECT T1.country_code, T1.first_name FROM players AS T1 JOIN matches AS T2 ON T1.player_id = T2.winner_id WHERE T2.tourney_name = 'WTA Championships' INTERSECT SELECT T1.country_code, T1.first_name FROM players AS T1 JOIN matches AS T2 ON T1.player_id = T2.winner_id WHERE T2.tourney_name = 'Australian Open' Type: JOIN [272] OTHER | DB: wta_1 | EX: ✗ Q : Find the first name and country code of the oldest player Pred: SELECT first_name, country_code FROM players ORDER BY birth_date DESC LIMIT 1 Gold: SELECT first_name, country_code FROM players ORDER BY birth_date LIMIT 1 Type: ORDER_BY, LIMIT [273] OTHER | DB: wta_1 | EX: ✗ Q : What is the first name and country code of the oldest player Pred: SELECT first_name, country_code FROM players ORDER BY birth_date DESC LIMIT 1 Gold: SELECT first_name, country_code FROM players ORDER BY birth_date LIMIT 1 Type: ORDER_BY, LIMIT [274] OTHER | DB: wta_1 | EX: ✗ Q : List the first and last name of all players who are left / L hand in the order of birth date Pred: SELECT first_name, last_name FROM players WHERE hand = 'left' ORDER BY birth_date Gold: SELECT first_name, last_name FROM players WHERE hand = 'L' ORDER BY birth_date Type: ORDER_BY [275] WRONG_COLUMNS | DB: wta_1 | EX: ✗ Q : What are the full names of all left handed players, in order of birth date Pred: SELECT first_name, last_name, birth_date FROM players WHERE hand = 'left' ORDER BY birth_date Gold: SELECT first_name, last_name FROM players WHERE hand = 'L' ORDER BY birth_date Type: ORDER_BY [276] WRONG_COLUMNS | DB: wta_1 | EX: ✗ Q : Find the first name and country code of the player who did the most number of tours Pred: SELECT T1.first_name, T1.country_code FROM players AS T1 JOIN rankings AS T2 ON T1.player_id = T2.player_id GROUP BY T1.player_id ORDER BY COUNT(*) DESC LIMIT 1 Gold: SELECT T1.country_code, T1.first_name FROM players AS T1 JOIN rankings AS T2 ON T1.player_id = T2.player_id ORDER BY T2.tours DESC LIMIT 1 Type: JOIN, ORDER_BY, LIMIT [277] WRONG_COLUMNS | DB: wta_1 | EX: ✗ Q : What is the first name and country code of the player with the most tours Pred: SELECT T1.first_name, T1.country_code FROM players AS T1 JOIN rankings AS T2 ON T1.player_id = T2.player_id GROUP BY T1.player_id ORDER BY SUM(T2.tours) DESC LIMIT 1 Gold: SELECT T1.country_code, T1.first_name FROM players AS T1 JOIN rankings AS T2 ON T1.player_id = T2.player_id ORDER BY T2.tours DESC LIMIT 1 Type: JOIN, ORDER_BY, LIMIT [278] WRONG_TABLE | DB: wta_1 | EX: ✗ Q : Find the name and rank points of the winner who won the most times Pred: SELECT T1.winner_name, T1.winner_rank_points FROM players AS T1 JOIN rankings AS T2 ON T1.player_id = T2.winner_id GROUP BY T1.winner_rank_points ORDER BY COUNT(*) DESC LIMIT 1 Gold: SELECT winner_name, winner_rank_points FROM matches GROUP BY winner_name ORDER BY COUNT(*) DESC LIMIT 1 Type: GROUP_BY, ORDER_BY, LIMIT, AGGREGATION [279] WRONG_TABLE | DB: wta_1 | EX: ✗ Q : What is the name of the winner who has won the most matches, and how many rank points does this player have Pred: SELECT T1.winner_name, T1.winner_rank_points FROM players AS T1 JOIN matches AS T2 ON T1.player_id = T2.winner_id GROUP BY T1.player_id ORDER BY COUNT(*) DESC LIMIT 1 Gold: SELECT winner_name, winner_rank_points FROM matches GROUP BY winner_name ORDER BY COUNT(*) DESC LIMIT 1 Type: GROUP_BY, ORDER_BY, LIMIT, AGGREGATION [280] WRONG_TABLE | DB: wta_1 | EX: ✗ Q : Find the name of the winner who has the highest rank points and participated in the Australian Open tourney Pred: SELECT T1.winner_name FROM players AS T1 JOIN matches AS T2 ON T1.player_id = T2.winner_id JOIN tourneys AS T3 ON T2.tournament_name = T3.tournament_name WHERE T3.tournament_name = 'Australian Open' ORDER BY T1.winner_rank_points DESC LIMIT 1 Gold: SELECT winner_name FROM matches WHERE tourney_name = 'Australian Open' ORDER BY winner_rank_points DESC LIMIT 1 Type: ORDER_BY, LIMIT [281] WRONG_TABLE | DB: wta_1 | EX: ✗ Q : What is the name of the winner with the most rank points who participated in the Australian Open tournament Pred: SELECT T1.winner_name FROM players AS T1 JOIN matches AS T2 ON T1.player_id = T2.winner_id JOIN tournaments AS T3 ON T2.tournament_name = T3.Tournament_name WHERE T3.Tournament_name = "Australian Open" GROUP BY T1.winner_rank_points ORDER BY COUNT(*) DESC LIMIT 1 Gold: SELECT winner_name FROM matches WHERE tourney_name = 'Australian Open' ORDER BY winner_rank_points DESC LIMIT 1 Type: ORDER_BY, LIMIT [282] EXTRA_JOIN | DB: wta_1 | EX: ✗ Q : find the names of loser and winner who played in the match with greatest number of minutes Pred: SELECT T2.loser_name, T2.winner_name FROM matches AS T1 JOIN players AS T2 ON T1.player_id = T2.winner_id ORDER BY T1.minutes DESC LIMIT 1 Gold: SELECT winner_name, loser_name FROM matches ORDER BY minutes DESC LIMIT 1 Type: ORDER_BY, LIMIT [283] WRONG_TABLE | DB: wta_1 | EX: ✗ Q : What are the names of the winner and loser who played in the longest match Pred: SELECT T1.winner_name, T1.loser_name FROM players AS T1 JOIN matches AS T2 ON T1.player_id = T2.winner_id ORDER BY T2.match_number DESC LIMIT 1 Gold: SELECT winner_name, loser_name FROM matches ORDER BY minutes DESC LIMIT 1 Type: ORDER_BY, LIMIT [284] OTHER | DB: wta_1 | EX: ✗ Q : Find the average ranking for each player and their first name Pred: SELECT AVG(ranking), T1.first_name FROM players AS T1 JOIN rankings AS T2 ON T1.player_id = T2.player_id GROUP BY T1.player_id Gold: SELECT AVG(ranking), T1.first_name FROM players AS T1 JOIN rankings AS T2 ON T1.player_id = T2.player_id GROUP BY T1.first_name Type: JOIN, GROUP_BY, AGGREGATION [285] WRONG_COLUMNS | DB: wta_1 | EX: ✗ Q : What are the first names of all players, and their average rankings Pred: SELECT T1.first_name, AVG(T2.ranking) FROM players AS T1 JOIN rankings AS T2 ON T1.player_id = T2.player_id GROUP BY T1.player_id Gold: SELECT AVG(ranking), T1.first_name FROM players AS T1 JOIN rankings AS T2 ON T1.player_id = T2.player_id GROUP BY T1.first_name Type: JOIN, GROUP_BY, AGGREGATION [286] MISSING_JOIN | DB: wta_1 | EX: ✗ Q : Find the total ranking points for each player and their first name Pred: SELECT SUM(ranking_points), first_name FROM players Gold: SELECT SUM(ranking_points), T1.first_name FROM players AS T1 JOIN rankings AS T2 ON T1.player_id = T2.player_id GROUP BY T1.first_name Type: JOIN, GROUP_BY, AGGREGATION [287] WRONG_COLUMNS | DB: wta_1 | EX: ✗ Q : What are the first names of all players, and their total ranking points Pred: SELECT T1.first_name, SUM(T2.ranking_points) FROM players AS T1 JOIN rankings AS T2 ON T1.player_id = T2.player_id GROUP BY T1.player_id Gold: SELECT SUM(ranking_points), T1.first_name FROM players AS T1 JOIN rankings AS T2 ON T1.player_id = T2.player_id GROUP BY T1.first_name Type: JOIN, GROUP_BY, AGGREGATION [288] WRONG_COLUMNS | DB: wta_1 | EX: ✗ Q : find the number of players for each country Pred: SELECT country_code, COUNT(*) FROM players GROUP BY country_code Gold: SELECT COUNT(*), country_code FROM players GROUP BY country_code Type: GROUP_BY, AGGREGATION [289] WRONG_COLUMNS | DB: wta_1 | EX: ✗ Q : How many players are from each country Pred: SELECT country_code, COUNT(*) FROM players GROUP BY country_code Gold: SELECT COUNT(*), country_code FROM players GROUP BY country_code Type: GROUP_BY, AGGREGATION [290] WRONG_COLUMNS | DB: wta_1 | EX: ✗ Q : Find the total number of tours for each ranking date Pred: SELECT ranking_date, COUNT(*) FROM rankings GROUP BY ranking_date Gold: SELECT SUM(tours), ranking_date FROM rankings GROUP BY ranking_date Type: GROUP_BY, AGGREGATION [291] WRONG_COLUMNS | DB: wta_1 | EX: ✗ Q : How many matches were played in each year Pred: SELECT YEAR, COUNT(*) FROM matches GROUP BY YEAR Gold: SELECT COUNT(*), YEAR FROM matches GROUP BY YEAR Type: GROUP_BY, AGGREGATION [292] WRONG_TABLE | DB: wta_1 | EX: ✗ Q : Find the name and rank of the 3 youngest winners across all matches Pred: SELECT T1.winner_name, T1.winner_rank FROM players AS T1 JOIN matches AS T2 ON T1.winner_id = T2.winner_id ORDER BY T2.winner_age LIMIT 3 Gold: SELECT DISTINCT winner_name, winner_rank FROM matches ORDER BY winner_age LIMIT 3 Type: ORDER_BY, LIMIT [293] WRONG_TABLE | DB: wta_1 | EX: ✗ Q : What are the names and ranks of the three youngest winners across all matches Pred: SELECT T1.winner_name, T1.winner_rank FROM players AS T1 JOIN matches AS T2 ON T1.winner_id = T2.winner_id ORDER BY T2.winner_age LIMIT 3 Gold: SELECT DISTINCT winner_name, winner_rank FROM matches ORDER BY winner_age LIMIT 3 Type: ORDER_BY, LIMIT [294] WRONG_TABLE | DB: wta_1 | EX: ✗ Q : How many different winners both participated in the WTA Championships and were left handed Pred: SELECT COUNT(DISTINCT T1.Winner_Name) FROM players AS T1 JOIN matches AS T2 ON T1.Winner_ID = T2.Winner_ID WHERE T1.hand = "left" AND T2.Tournament_name = "WTA Championships" Gold: SELECT COUNT(DISTINCT winner_name) FROM matches WHERE tourney_name = 'WTA Championships' AND winner_hand = 'L' Type: AGGREGATION [295] WRONG_TABLE | DB: wta_1 | EX: ✗ Q : Find the number of left handed winners who participated in the WTA Championships Pred: SELECT COUNT(*) FROM players WHERE winner_hand = "left" AND JOIN matches AS T1 JOIN players AS T2 ON T1.player_id = T2.player_id WHERE T1.tournament_name = "WTA Championships" Gold: SELECT COUNT(DISTINCT winner_name) FROM matches WHERE tourney_name = 'WTA Championships' AND winner_hand = 'L' Type: AGGREGATION [296] WRONG_COLUMNS | DB: wta_1 | EX: ✗ Q : Find the first name, country code and birth date of the winner who has the highest rank points in all matches Pred: SELECT T1.winner_name, T1.country_code, T1.birth_date FROM players AS T1 JOIN matches AS T2 ON T1.winner_id = T2.winner_id ORDER BY T2.winner_rank_points DESC LIMIT 1 Gold: SELECT T1.first_name, T1.country_code, T1.birth_date FROM players AS T1 JOIN matches AS T2 ON T1.player_id = T2.winner_id ORDER BY T2.winner_rank_points DESC LIMIT 1 Type: JOIN, ORDER_BY, LIMIT [297] OTHER | DB: wta_1 | EX: ✗ Q : What is the first name, country code, and birth date of the player with the most winner rank points across all matches Pred: SELECT T1.first_name, T1.country_code, T1.birth_date FROM players AS T1 JOIN matches AS T2 ON T1.player_id = T2.winner_id GROUP BY T1.player_id ORDER BY COUNT(*) DESC LIMIT 1 Gold: SELECT T1.first_name, T1.country_code, T1.birth_date FROM players AS T1 JOIN matches AS T2 ON T1.player_id = T2.winner_id ORDER BY T2.winner_rank_points DESC LIMIT 1 Type: JOIN, ORDER_BY, LIMIT [298] WRONG_COLUMNS | DB: wta_1 | EX: ✗ Q : Find the number of players for each hand type Pred: SELECT hand, COUNT(*) FROM players GROUP BY hand Gold: SELECT COUNT(*), hand FROM players GROUP BY hand Type: GROUP_BY, AGGREGATION [299] WRONG_COLUMNS | DB: wta_1 | EX: ✗ Q : How many players are there for each hand type Pred: SELECT DISTINCT hand, COUNT(*) FROM players GROUP BY hand Gold: SELECT COUNT(*), hand FROM players GROUP BY hand Type: GROUP_BY, AGGREGATION [300] WRONG_COLUMNS | DB: battle_death | EX: ✗ Q : List the name, date and result of each battle Pred: SELECT name, date, result FROM battle Gold: SELECT name, date FROM battle Type: SIMPLE [301] WRONG_COLUMNS | DB: battle_death | EX: ✗ Q : What is maximum and minimum death toll caused each time Pred: SELECT MAX(dead), MIN(dead) FROM death Gold: SELECT MAX(killed), MIN(killed) FROM death Type: AGGREGATION [302] OTHER | DB: battle_death | EX: ✗ Q : What is the average number of injuries caused each time Pred: SELECT AVG(Injured) FROM death GROUP BY Injured Gold: SELECT AVG(injured) FROM death Type: AGGREGATION [303] OTHER | DB: battle_death | EX: ✓ Q : What are the name and results of the battles when the bulgarian commander is not 'Boril' Pred: SELECT name, result FROM battle WHERE bulgarian_commander > 'Boril' Gold: SELECT name, RESULT FROM battle WHERE bulgarian_commander <> 'Boril' Type: SIMPLE [304] OTHER | DB: battle_death | EX: ✗ Q : What are the different ids and names of the battles that lost any 'Brig' type shipes Pred: SELECT DISTINCT T1.id, T1.name FROM battle AS T1 JOIN ship AS T2 ON T1.lost_in_battle = T2.id WHERE T2.ship_type = 'Brig' Gold: SELECT DISTINCT T1.id, T1.name FROM battle AS T1 JOIN ship AS T2 ON T1.id = T2.lost_in_battle WHERE T2.ship_type = 'Brig' Type: JOIN [305] OTHER | DB: battle_death | EX: ✗ Q : What are the ids and names of the battles that led to more than 10 people killed in total Pred: SELECT T1.id, T1.name FROM battle AS T1 JOIN death AS T2 ON T1.id = T2.caused_by_ship_id GROUP BY T1.id HAVING COUNT(*) > 10 Gold: SELECT T1.id, T1.name FROM battle AS T1 JOIN ship AS T2 ON T1.id = T2.lost_in_battle JOIN death AS T3 ON T2.id = T3.caused_by_ship_id GROUP BY T1.id HAVING SUM(T3.killed) > 10 Type: JOIN, GROUP_BY, HAVING, AGGREGATION [306] WRONG_TABLE | DB: battle_death | EX: ✗ Q : What is the ship id and name that caused most total injuries Pred: SELECT T1.id, T1.name FROM ship AS T1 JOIN death AS T2 ON T1.id = T2.caused_by_ship_id GROUP BY T1.id ORDER BY SUM(T2.injured) DESC LIMIT 1 Gold: SELECT T2.id, T2.name FROM death AS T1 JOIN ship AS t2 ON T1.caused_by_ship_id = T2.id GROUP BY T2.id ORDER BY COUNT(*) DESC LIMIT 1 Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, AGGREGATION [307] EXTRA_JOIN | DB: battle_death | EX: ✗ Q : What are the distinct battle names which are between bulgarian commander 'Kaloyan' and latin commander 'Baldwin I' Pred: SELECT DISTINCT T1.name FROM battle AS T1 JOIN ship AS T2 ON T1.id = T2.lost_in_battle WHERE T2.bulgarian_commander = 'Kaloyan' INTERSECT SELECT DISTINCT T1.name FROM battle AS T1 JOIN ship AS T2 ON T1.id = T2.lost_in_battle WHERE T2.latin_commander = 'Baldwin I' Gold: SELECT name FROM battle WHERE bulgarian_commander = 'Kaloyan' AND latin_commander = 'Baldwin I' Type: SIMPLE [308] OTHER | DB: battle_death | EX: ✗ Q : List the name and date the battle that has lost the ship named 'Lettice' and the ship named 'HMS Atalanta' Pred: SELECT T1.name, T1.date FROM battle AS T1 JOIN ship AS T2 ON T1.lost_in_battle = T2.id JOIN battle AS T3 ON T2.battle = T3.id WHERE T2.name = 'Lettice' INTERSECT SELECT T1.name, T1.date FROM battle AS T1 JOIN ship AS T2 ON T1.id = T2.lost_in_battle WHERE T2.name = 'HMS Atalanta' Gold: SELECT T1.name, T1.date FROM battle AS T1 JOIN ship AS T2 ON T1.id = T2.lost_in_battle WHERE T2.name = 'Lettice' INTERSECT SELECT T1.name, T1.date FROM battle AS T1 JOIN ship AS T2 ON T1.id = T2.lost_in_battle WHERE T2.name = 'HMS Atalanta' Type: JOIN [309] WRONG_TABLE | DB: battle_death | EX: ✓ Q : Show names, results and bulgarian commanders of the battles with no ships lost in the 'English Channel' Pred: SELECT name, result, bulgarian_commander FROM battle WHERE NOT id IN (SELECT lost_in_battle FROM ship WHERE location = 'English Channel') Gold: SELECT name, RESULT, bulgarian_commander FROM battle EXCEPT SELECT T1.name, T1.result, T1.bulgarian_commander FROM battle AS T1 JOIN ship AS T2 ON T1.id = T2.lost_in_battle WHERE T2.location = 'English Channel' Type: JOIN [310] WRONG_COLUMNS | DB: student_transcripts_tracking | EX: ✗ Q : what are all the addresses including line 1 and line 2 Pred: SELECT address FROM addresses WHERE line_1 LIKE '%2' AND line_2 LIKE '%2' Gold: SELECT line_1, line_2 FROM addresses Type: SIMPLE [311] EXTRA_JOIN | DB: student_transcripts_tracking | EX: ✗ Q : What is the first and second line for all addresses Pred: SELECT T1.line_1, T1.line_2 FROM Addresses AS T1 JOIN Students AS T2 ON T1.address_id = T2.address_id Gold: SELECT line_1, line_2 FROM addresses Type: SIMPLE [312] WRONG_COLUMNS | DB: student_transcripts_tracking | EX: ✗ Q : How many departments offer any degree Pred: SELECT COUNT(*) FROM degree_programs Gold: SELECT COUNT(DISTINCT department_id) FROM Degree_Programs Type: AGGREGATION [313] WRONG_COLUMNS | DB: student_transcripts_tracking | EX: ✗ Q : How many different departments offer degrees Pred: SELECT COUNT(DISTINCT department_name) FROM degree_programs Gold: SELECT COUNT(DISTINCT department_id) FROM Degree_Programs Type: AGGREGATION [314] WRONG_COLUMNS | DB: student_transcripts_tracking | EX: ✗ Q : How many different degree names are offered Pred: SELECT COUNT(DISTINCT degree_program_name) FROM degree_programs Gold: SELECT COUNT(DISTINCT degree_summary_name) FROM Degree_Programs Type: AGGREGATION [315] WRONG_COLUMNS | DB: student_transcripts_tracking | EX: ✗ Q : How many different degrees are offered Pred: SELECT COUNT(DISTINCT degree_program_id) FROM degree_programs Gold: SELECT COUNT(DISTINCT degree_summary_name) FROM Degree_Programs Type: AGGREGATION [316] WRONG_TABLE | DB: student_transcripts_tracking | EX: ✓ Q : How many degrees does the engineering department offer Pred: SELECT COUNT(*) FROM degree_programs AS T1 JOIN departments AS T2 ON T1.department_id = T2.department_id WHERE T2.department_name = "engineering" Gold: SELECT COUNT(*) FROM Departments AS T1 JOIN Degree_Programs AS T2 ON T1.department_id = T2.department_id WHERE T1.department_name = 'engineer' Type: JOIN, AGGREGATION [317] WRONG_TABLE | DB: student_transcripts_tracking | EX: ✓ Q : How many degrees does the engineering department have Pred: SELECT COUNT(*) FROM degree_programs AS T1 JOIN departments AS T2 ON T1.department_id = T2.department_id WHERE T2.department_name = "engineering" Gold: SELECT COUNT(*) FROM Departments AS T1 JOIN Degree_Programs AS T2 ON T1.department_id = T2.department_id WHERE T1.department_name = 'engineer' Type: JOIN, AGGREGATION [318] OTHER | DB: student_transcripts_tracking | EX: ✗ Q : What are the names and id of courses having at most 2 sections Pred: SELECT T1.course_name, T1.course_id FROM Courses AS T1 JOIN Sections AS T2 ON T1.course_id = T2.course_id GROUP BY T1.course_id HAVING COUNT(*) = 2 Gold: SELECT T1.course_name, T1.course_id FROM Courses AS T1 JOIN Sections AS T2 ON T1.course_id = T2.course_id GROUP BY T1.course_id HAVING COUNT(*) <= 2 Type: JOIN, GROUP_BY, HAVING, AGGREGATION [319] OTHER | DB: student_transcripts_tracking | EX: ✗ Q : What are the names and ids of every course with less than 2 sections Pred: SELECT T1.course_name, T1.course_id FROM Courses AS T1 JOIN Sections AS T2 ON T1.course_id = T2.course_id GROUP BY T1.course_id HAVING COUNT(*) 2 Gold: SELECT T1.course_name, T1.course_id FROM Courses AS T1 JOIN Sections AS T2 ON T1.course_id = T2.course_id GROUP BY T1.course_id HAVING COUNT(*) <= 2 Type: JOIN, GROUP_BY, HAVING, AGGREGATION [320] OTHER | DB: student_transcripts_tracking | EX: ✗ Q : What are the names of the sections in reverse alphabetical order Pred: SELECT section_name FROM SECTIONS ORDER BY section_name ASC Gold: SELECT section_name FROM Sections ORDER BY section_name DESC Type: ORDER_BY [321] WRONG_TABLE | DB: student_transcripts_tracking | EX: ✗ Q : What is the semester which most student registered in? Show both the name and the id Pred: SELECT T1.semester_name, T2.semester_id FROM Student_Enrolment AS T1 JOIN Semesters AS T2 ON T1.semester_id = T2.semester_id GROUP BY T2.semester_id ORDER BY COUNT(*) DESC LIMIT 1 Gold: SELECT T1.semester_name, T1.semester_id FROM Semesters AS T1 JOIN Student_Enrolment AS T2 ON T1.semester_id = T2.semester_id GROUP BY T1.semester_id ORDER BY COUNT(*) DESC LIMIT 1 Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, AGGREGATION [322] WRONG_TABLE | DB: student_transcripts_tracking | EX: ✗ Q : Who are enrolled in 2 degree programs in one semester? List the first name, middle name and last name and the id Pred: SELECT T1.first_name, T1.middle_name, T1.last_name, T1.student_id FROM Student_Enrolment AS T1 JOIN Semesters AS T2 ON T1.semester_id = T2.semester_id GROUP BY T1.student_enrolment_id HAVING COUNT(*) = 2 Gold: SELECT T1.first_name, T1.middle_name, T1.last_name, T1.student_id FROM Students AS T1 JOIN Student_Enrolment AS T2 ON T1.student_id = T2.student_id GROUP BY T1.student_id HAVING COUNT(*) = 2 Type: JOIN, GROUP_BY, HAVING, AGGREGATION [323] WRONG_TABLE | DB: student_transcripts_tracking | EX: ✗ Q : What are the first, middle, and last names, along with the ids, of all students who enrolled in 2 degree programs in one semester Pred: SELECT T1.first_name, T1.middle_name, T1.last_name, T1.student_id FROM Student_Enrolment AS T1 JOIN Semesters AS T2 ON T1.student_id = T2.semester_id GROUP BY T1.student_id HAVING COUNT(*) = 2 Gold: SELECT T1.first_name, T1.middle_name, T1.last_name, T1.student_id FROM Students AS T1 JOIN Student_Enrolment AS T2 ON T1.student_id = T2.student_id GROUP BY T1.student_id HAVING COUNT(*) = 2 Type: JOIN, GROUP_BY, HAVING, AGGREGATION [324] WRONG_TABLE | DB: student_transcripts_tracking | EX: ✗ Q : Who is enrolled in a Bachelor degree program? List the first name, middle name, last name Pred: SELECT T1.first_name, T1.middle_name, T1.last_name FROM Student_Enrolment AS T1 JOIN Degree_Programs AS T2 ON T1.degree_program_id = T2.degree_program_id WHERE T2.degree_summary_name = "Bachelor" Gold: SELECT DISTINCT T1.first_name, T1.middle_name, T1.last_name FROM Students AS T1 JOIN Student_Enrolment AS T2 ON T1.student_id = T2.student_id JOIN Degree_Programs AS T3 ON T2.degree_program_id = T3.degree_program_id WHERE T3.degree_summary_name = 'Bachelor' Type: JOIN [325] WRONG_TABLE | DB: student_transcripts_tracking | EX: ✗ Q : What are the first, middle, and last names for everybody enrolled in a Bachelors program Pred: SELECT T1.first_name, T1.middle_name, T1.last_name FROM Student_Enrolment AS T1 JOIN Degree_Programs AS T2 ON T1.degree_program_id = T2.degree_program_id WHERE T2.degree_summary_name = "Bachelors" Gold: SELECT DISTINCT T1.first_name, T1.middle_name, T1.last_name FROM Students AS T1 JOIN Student_Enrolment AS T2 ON T1.student_id = T2.student_id JOIN Degree_Programs AS T3 ON T2.degree_program_id = T3.degree_program_id WHERE T3.degree_summary_name = 'Bachelor' Type: JOIN [326] WRONG_COLUMNS | DB: student_transcripts_tracking | EX: ✗ Q : Find the kind of program which most number of students are enrolled in Pred: SELECT T1.degree_program_id FROM degree_programs AS T1 JOIN student_enrolment AS T2 ON T1.degree_program_id = T2.degree_program_id GROUP BY T1.degree_program_id ORDER BY COUNT(*) DESC LIMIT 1 Gold: SELECT T1.degree_summary_name FROM Degree_Programs AS T1 JOIN Student_Enrolment AS T2 ON T1.degree_program_id = T2.degree_program_id GROUP BY T1.degree_summary_name ORDER BY COUNT(*) DESC LIMIT 1 Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, AGGREGATION [327] WRONG_TABLE | DB: student_transcripts_tracking | EX: ✗ Q : Find the program which most number of students are enrolled in. List both the id and the summary Pred: SELECT T1.degree_program_id, T2.degree_summary_name FROM Student_Enrolment AS T1 JOIN Courses AS T2 ON T1.student_id = T2.student_id GROUP BY T1.degree_program_id ORDER BY COUNT(*) DESC LIMIT 1 Gold: SELECT T1.degree_program_id, T1.degree_summary_name FROM Degree_Programs AS T1 JOIN Student_Enrolment AS T2 ON T1.degree_program_id = T2.degree_program_id GROUP BY T1.degree_program_id ORDER BY COUNT(*) DESC LIMIT 1 Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, AGGREGATION [328] WRONG_TABLE | DB: student_transcripts_tracking | EX: ✗ Q : Which student has enrolled for the most times in any program? List the id, first name, middle name, last name, the number of enrollments and student id Pred: SELECT T1.student_id, T2.first_name, T2.middle_name, T2.last_name, COUNT(*) FROM Student_Enrolment AS T1 JOIN Students AS T2 ON T1.student_id = T2.student_id GROUP BY T1.student_id ORDER BY COUNT(*) DESC LIMIT 1 Gold: SELECT T1.student_id, T1.first_name, T1.middle_name, T1.last_name, COUNT(*), T1.student_id FROM Students AS T1 JOIN Student_Enrolment AS T2 ON T1.student_id = T2.student_id GROUP BY T1.student_id ORDER BY COUNT(*) DESC LIMIT 1 Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, AGGREGATION [329] WRONG_TABLE | DB: student_transcripts_tracking | EX: ✗ Q : What is the first, middle, and last name, along with the id and number of enrollments, for the student who enrolled the most in any program Pred: SELECT T1.first_name, T1.middle_name, T1.last_name, T1.student_enrolment_id, COUNT(*) FROM Student_Enrolment AS T1 JOIN Students AS T2 ON T1.student_id = T2.student_id GROUP BY T1.student_enrolment_id ORDER BY COUNT(*) DESC LIMIT 1 Gold: SELECT T1.student_id, T1.first_name, T1.middle_name, T1.last_name, COUNT(*), T1.student_id FROM Students AS T1 JOIN Student_Enrolment AS T2 ON T1.student_id = T2.student_id GROUP BY T1.student_id ORDER BY COUNT(*) DESC LIMIT 1 Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, AGGREGATION [330] WRONG_TABLE | DB: student_transcripts_tracking | EX: ✓ Q : What is the name of the semester with no students enrolled Pred: SELECT semester_name FROM Semesters EXCEPT SELECT T1.semester_name FROM Semesters AS T1 JOIN Student_Enrolment AS T2 ON T1.semester_id = T2.semester_id Gold: SELECT semester_name FROM Semesters WHERE NOT semester_id IN (SELECT semester_id FROM Student_Enrolment) Type: NESTED [331] WRONG_COLUMNS | DB: student_transcripts_tracking | EX: ✗ Q : What are all the course names of the courses which ever have students enrolled in Pred: SELECT T1.course_name FROM Courses AS T1 JOIN Student_Enrolment_Courses AS T2 ON T1.course_id = T2.course_id Gold: SELECT DISTINCT T1.course_name FROM Courses AS T1 JOIN Student_Enrolment_Courses AS T2 ON T1.course_id = T2.course_id Type: JOIN [332] WRONG_COLUMNS | DB: student_transcripts_tracking | EX: ✗ Q : What are the names of all courses that have some students enrolled Pred: SELECT T1.course_name FROM Courses AS T1 JOIN Student_Enrolment_Courses AS T2 ON T1.course_id = T2.course_id Gold: SELECT DISTINCT T1.course_name FROM Courses AS T1 JOIN Student_Enrolment_Courses AS T2 ON T1.course_id = T2.course_id Type: JOIN [333] WRONG_COLUMNS | DB: student_transcripts_tracking | EX: ✗ Q : Find the last name of the students who currently live in the state of North Carolina but have not registered in any degree program Pred: SELECT last_name FROM Students WHERE current_address_id = 'A' AND state_province_county = "North Carolina" EXCEPT SELECT T1.last_name FROM Students AS T1 JOIN Student_Enrolment AS T2 ON T1.student_id = T2.student_id Gold: SELECT T1.last_name FROM Students AS T1 JOIN Addresses AS T2 ON T1.current_address_id = T2.address_id WHERE T2.state_province_county = 'NorthCarolina' EXCEPT SELECT DISTINCT T3.last_name FROM Students AS T3 JOIN Student_Enrolment AS T4 ON T3.student_id = T4.student_id Type: JOIN [334] WRONG_COLUMNS | DB: student_transcripts_tracking | EX: ✗ Q : What are the last name of the students who live in North Carolina but have not registered in any degree programs Pred: SELECT last_name FROM Students WHERE current_address_id = 'North Carolina' EXCEPT SELECT T1.last_name FROM Students AS T1 JOIN Student_Enrolment AS T2 ON T1.student_id = T2.student_id JOIN Degrees AS T3 ON T2.degree_program_id = T3.degree_program_id WHERE T3.state_province_county = "North Carolina" Gold: SELECT T1.last_name FROM Students AS T1 JOIN Addresses AS T2 ON T1.current_address_id = T2.address_id WHERE T2.state_province_county = 'NorthCarolina' EXCEPT SELECT DISTINCT T3.last_name FROM Students AS T3 JOIN Student_Enrolment AS T4 ON T3.student_id = T4.student_id Type: JOIN [335] WRONG_TABLE | DB: student_transcripts_tracking | EX: ✗ Q : Show the date and id of the transcript with at least 2 course results Pred: SELECT T1.transcript_date, T1.transcript_id FROM transcripts AS T1 JOIN courses AS T2 ON T1.course_id = T2.course_id GROUP BY T1.transcript_id HAVING COUNT(*) >= 2 Gold: SELECT T2.transcript_date, T1.transcript_id FROM Transcript_Contents AS T1 JOIN Transcripts AS T2 ON T1.transcript_id = T2.transcript_id GROUP BY T1.transcript_id HAVING COUNT(*) >= 2 Type: JOIN, GROUP_BY, HAVING, AGGREGATION [336] WRONG_TABLE | DB: student_transcripts_tracking | EX: ✗ Q : What is the date and id of the transcript with at least 2 courses listed Pred: SELECT T1.transcript_date, T1.transcript_id FROM transcripts AS T1 JOIN courses AS T2 ON T1.course_id = T2.course_id GROUP BY T1.transcript_id HAVING COUNT(*) >= 2 Gold: SELECT T2.transcript_date, T1.transcript_id FROM Transcript_Contents AS T1 JOIN Transcripts AS T2 ON T1.transcript_id = T2.transcript_id GROUP BY T1.transcript_id HAVING COUNT(*) >= 2 Type: JOIN, GROUP_BY, HAVING, AGGREGATION [337] WRONG_TABLE | DB: student_transcripts_tracking | EX: ✗ Q : What is the phone number of the man with the first name Timmothy and the last name Ward Pred: SELECT cell_mobile_number FROM Addresses WHERE first_name = "Timmothy" AND last_name = "Ward" Gold: SELECT cell_mobile_number FROM Students WHERE first_name = 'Timmothy' AND last_name = 'Ward' Type: SIMPLE [338] WRONG_TABLE | DB: student_transcripts_tracking | EX: ✗ Q : Who is the first student to register? List the first name, middle name and last name Pred: SELECT first_name, middle_name, last_name FROM Student_Enrolment Gold: SELECT first_name, middle_name, last_name FROM Students ORDER BY date_first_registered ASC LIMIT 1 Type: ORDER_BY, LIMIT [339] EXTRA_JOIN | DB: student_transcripts_tracking | EX: ✗ Q : What is the first, middle, and last name of the first student to register Pred: SELECT T1.first_name, T1.middle_name, T1.last_name FROM Students AS T1 JOIN Student_Enrolment AS T2 ON T1.student_id = T2.student_id Gold: SELECT first_name, middle_name, last_name FROM Students ORDER BY date_first_registered ASC LIMIT 1 Type: ORDER_BY, LIMIT [340] WRONG_TABLE | DB: student_transcripts_tracking | EX: ✗ Q : Who is the earliest graduate of the school? List the first name, middle name and last name Pred: SELECT first_name, middle_name, last_name FROM Student_Enrolment ORDER BY date_first_registered LIMIT 1 Gold: SELECT first_name, middle_name, last_name FROM Students ORDER BY date_left ASC LIMIT 1 Type: ORDER_BY, LIMIT [341] WRONG_TABLE | DB: student_transcripts_tracking | EX: ✗ Q : What is the first, middle, and last name of the earliest school graduate Pred: SELECT first_name, middle_name, last_name FROM Student_Enrolment ORDER BY date_first_registered LIMIT 1 Gold: SELECT first_name, middle_name, last_name FROM Students ORDER BY date_left ASC LIMIT 1 Type: ORDER_BY, LIMIT [342] EXTRA_JOIN | DB: student_transcripts_tracking | EX: ✗ Q : Whose permanent address is different from his or her current address? List his or her first name Pred: SELECT T1.first_name FROM Students AS T1 JOIN Addresses AS T2 ON T1.permanent_address_id = T2.address_id WHERE T2.current_address_id > T2.address_id Gold: SELECT first_name FROM Students WHERE current_address_id <> permanent_address_id Type: SIMPLE [343] EXTRA_JOIN | DB: student_transcripts_tracking | EX: ✗ Q : What is the first name of the student whose permanent address is different from his or her current one Pred: SELECT T1.first_name FROM Students AS T1 JOIN Students AS T2 ON T1.student_id = T2.student_id WHERE T2.permanent_address_id > T2.current_address_id Gold: SELECT first_name FROM Students WHERE current_address_id <> permanent_address_id Type: SIMPLE [344] WRONG_COLUMNS | DB: student_transcripts_tracking | EX: ✗ Q : Which address holds the most number of students currently? List the address id and all lines Pred: SELECT T1.address_id, T1.line_3 FROM addresses AS T1 JOIN students AS T2 ON T1.address_id = T2.address_id GROUP BY T1.address_id ORDER BY COUNT(*) DESC LIMIT 1 Gold: SELECT T1.address_id, T1.line_1, T1.line_2 FROM Addresses AS T1 JOIN Students AS T2 ON T1.address_id = T2.current_address_id GROUP BY T1.address_id ORDER BY COUNT(*) DESC LIMIT 1 Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, AGGREGATION [345] OTHER | DB: student_transcripts_tracking | EX: ✗ Q : What is the id, line 1, and line 2 of the address with the most students Pred: SELECT T1.address_id, T1.line_1, T1.line_2 FROM Addresses AS T1 JOIN Students AS T2 ON T1.address_id = T2.address_id GROUP BY T1.address_id ORDER BY COUNT(*) DESC LIMIT 1 Gold: SELECT T1.address_id, T1.line_1, T1.line_2 FROM Addresses AS T1 JOIN Students AS T2 ON T1.address_id = T2.current_address_id GROUP BY T1.address_id ORDER BY COUNT(*) DESC LIMIT 1 Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, AGGREGATION [346] EXTRA_JOIN | DB: student_transcripts_tracking | EX: ✓ Q : On average, when were the transcripts printed Pred: SELECT AVG(T1.transcript_date) FROM transcripts AS T1 JOIN transcripts AS T2 ON T1.transcript_id = T2.transcript_id Gold: SELECT AVG(transcript_date) FROM Transcripts Type: AGGREGATION [347] MISSING_ORDER_BY | DB: student_transcripts_tracking | EX: ✗ Q : When is the first transcript released? List the date and details Pred: SELECT date_first_registered, date_first_details FROM transcripts Gold: SELECT transcript_date, other_details FROM Transcripts ORDER BY transcript_date ASC LIMIT 1 Type: ORDER_BY, LIMIT [348] MISSING_ORDER_BY | DB: student_transcripts_tracking | EX: ✓ Q : What is the earliest date of a transcript release, and what details can you tell me Pred: SELECT MIN(transcript_date), other_details FROM transcripts Gold: SELECT transcript_date, other_details FROM Transcripts ORDER BY transcript_date ASC LIMIT 1 Type: ORDER_BY, LIMIT [349] MISSING_ORDER_BY | DB: student_transcripts_tracking | EX: ✗ Q : What is the last transcript release date Pred: SELECT date_last FROM transcripts Gold: SELECT transcript_date FROM Transcripts ORDER BY transcript_date DESC LIMIT 1 Type: ORDER_BY, LIMIT [350] MISSING_ORDER_BY | DB: student_transcripts_tracking | EX: ✗ Q : When was the last transcript released Pred: SELECT date_last FROM transcripts Gold: SELECT transcript_date FROM Transcripts ORDER BY transcript_date DESC LIMIT 1 Type: ORDER_BY, LIMIT [351] WRONG_TABLE | DB: student_transcripts_tracking | EX: ✗ Q : How many times at most can a course enrollment result show in different transcripts? Also show the course enrollment id Pred: SELECT COUNT(*), T1.transcript_id FROM transcripts AS T1 JOIN student_enrolment AS T2 ON T1.transcript_id = T2.transcript_id GROUP BY T1.transcript_id Gold: SELECT COUNT(*), student_course_id FROM Transcript_Contents GROUP BY student_course_id ORDER BY COUNT(*) DESC LIMIT 1 Type: GROUP_BY, ORDER_BY, LIMIT, AGGREGATION [352] EXTRA_JOIN | DB: student_transcripts_tracking | EX: ✗ Q : What is the maximum number of times that a course shows up in different transcripts and what is that course's enrollment id Pred: SELECT T1.course_id, MAX(T2.student_enrolment_id) FROM transcript_contents AS T1 JOIN courses AS T2 ON T1.course_id = T2.course_id GROUP BY T1.transcript_id Gold: SELECT COUNT(*), student_course_id FROM Transcript_Contents GROUP BY student_course_id ORDER BY COUNT(*) DESC LIMIT 1 Type: GROUP_BY, ORDER_BY, LIMIT, AGGREGATION [353] WRONG_TABLE | DB: student_transcripts_tracking | EX: ✗ Q : Show the date of the transcript which shows the least number of results, also list the id Pred: SELECT transcript_date, transcript_id FROM transcripts GROUP BY transcript_id ORDER BY COUNT(*) ASC LIMIT 1 Gold: SELECT T2.transcript_date, T1.transcript_id FROM Transcript_Contents AS T1 JOIN Transcripts AS T2 ON T1.transcript_id = T2.transcript_id GROUP BY T1.transcript_id ORDER BY COUNT(*) ASC LIMIT 1 Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, AGGREGATION [354] WRONG_TABLE | DB: student_transcripts_tracking | EX: ✗ Q : What is the date and id of the transcript with the least number of results Pred: SELECT transcript_date, transcript_id FROM transcripts GROUP BY transcript_id ORDER BY COUNT(*) ASC LIMIT 1 Gold: SELECT T2.transcript_date, T1.transcript_id FROM Transcript_Contents AS T1 JOIN Transcripts AS T2 ON T1.transcript_id = T2.transcript_id GROUP BY T1.transcript_id ORDER BY COUNT(*) ASC LIMIT 1 Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, AGGREGATION [355] WRONG_TABLE | DB: student_transcripts_tracking | EX: ✗ Q : Find the semester when both Master students and Bachelor students got enrolled in Pred: SELECT T1.semester_name FROM Semesters AS T1 JOIN Student_Enrolment AS T2 ON T1.semester_id = T2.semester_id WHERE T2.student_id = 'Master' INTERSECT SELECT T1.semester_name FROM Semesters AS T1 JOIN Student_Enrolment AS T2 ON T1.semester_id = T2.semester_id JOIN Student_Enrolment AS T3 ON Gold: SELECT DISTINCT T2.semester_id FROM Degree_Programs AS T1 JOIN Student_Enrolment AS T2 ON T1.degree_program_id = T2.degree_program_id WHERE degree_summary_name = 'Master' INTERSECT SELECT DISTINCT T2.semester_id FROM Degree_Programs AS T1 JOIN Student_Enrolment AS T2 ON T1.degree_program_id = T2.degree_program_id WHERE degree_summary_name = 'Bachelor' Type: JOIN [356] WRONG_TABLE | DB: student_transcripts_tracking | EX: ✗ Q : What is the id of the semester that had both Masters and Bachelors students enrolled Pred: SELECT semester_id FROM Student_Enrolment WHERE student_id = (SELECT student_id FROM Student_Enrolment WHERE degree_program_id = "Masters") INTERSECT SELECT semester_id FROM Semesters WHERE degree_program_id = "Bachelors") Gold: SELECT DISTINCT T2.semester_id FROM Degree_Programs AS T1 JOIN Student_Enrolment AS T2 ON T1.degree_program_id = T2.degree_program_id WHERE degree_summary_name = 'Master' INTERSECT SELECT DISTINCT T2.semester_id FROM Degree_Programs AS T1 JOIN Student_Enrolment AS T2 ON T1.degree_program_id = T2.degree_program_id WHERE degree_summary_name = 'Bachelor' Type: JOIN [357] WRONG_COLUMNS | DB: student_transcripts_tracking | EX: ✗ Q : How many different addresses do the students currently live Pred: SELECT COUNT(DISTINCT address_id) FROM Students Gold: SELECT COUNT(DISTINCT current_address_id) FROM Students Type: AGGREGATION [358] WRONG_TABLE | DB: student_transcripts_tracking | EX: ✗ Q : What are the different addresses that have students living there Pred: SELECT DISTINCT T1.address FROM addresses AS T1 JOIN students AS T2 ON T1.address_id = T2.permanent_address_id Gold: SELECT COUNT(DISTINCT current_address_id) FROM Students Type: AGGREGATION [359] OTHER | DB: student_transcripts_tracking | EX: ✗ Q : List all the student details in reversed lexicographical order Pred: SELECT other_student_details FROM STUDENTS ORDER BY other_student_details Gold: SELECT other_student_details FROM Students ORDER BY other_student_details DESC Type: ORDER_BY [360] WRONG_COLUMNS | DB: student_transcripts_tracking | EX: ✗ Q : What other details can you tell me about students in reverse alphabetical order Pred: SELECT other_details FROM STUDENTS ORDER BY other_details Gold: SELECT other_student_details FROM Students ORDER BY other_student_details DESC Type: ORDER_BY [361] MISSING_JOIN | DB: student_transcripts_tracking | EX: ✓ Q : Find the first name of the students who permanently live in the country Haiti or have the cell phone number 09700166582 Pred: SELECT first_name FROM Students WHERE permanent_address_id = 'Haiti' OR cell_mobile_number = '09700166582' Gold: SELECT t1.first_name FROM students AS t1 JOIN addresses AS t2 ON t1.permanent_address_id = t2.address_id WHERE t2.country = 'haiti' OR t1.cell_mobile_number = '09700166582' Type: JOIN [362] MISSING_JOIN | DB: student_transcripts_tracking | EX: ✓ Q : What are the first names of the students who live in Haiti permanently or have the cell phone number 09700166582 Pred: SELECT first_name FROM Students WHERE permanent_address_id = 'Haiti' OR cell_mobile_number = '09700166582' Gold: SELECT t1.first_name FROM students AS t1 JOIN addresses AS t2 ON t1.permanent_address_id = t2.address_id WHERE t2.country = 'haiti' OR t1.cell_mobile_number = '09700166582' Type: JOIN [363] WRONG_COLUMNS | DB: tvshow | EX: ✓ Q : List all cartoon directed by "Ben Jones" Pred: SELECT DISTINCT title FROM cartoon WHERE directed_by = "Ben Jones" Gold: SELECT Title FROM Cartoon WHERE Directed_by = "Ben Jones" Type: SIMPLE [364] WRONG_COLUMNS | DB: tvshow | EX: ✗ Q : List the number of different series names and contents in the TV Channel table Pred: SELECT COUNT(DISTINCT series_name), content FROM tv_channel Gold: SELECT COUNT(DISTINCT series_name), COUNT(DISTINCT content) FROM TV_Channel Type: AGGREGATION [365] WRONG_COLUMNS | DB: tvshow | EX: ✗ Q : How many different series and contents are listed in the TV Channel table Pred: SELECT COUNT(DISTINCT series_name), content FROM tv_channel Gold: SELECT COUNT(DISTINCT series_name), COUNT(DISTINCT content) FROM TV_Channel Type: AGGREGATION [366] WRONG_COLUMNS | DB: tvshow | EX: ✗ Q : For each language, list the number of TV Channels that use it Pred: SELECT COUNT(*), language FROM tv_channel GROUP BY language Gold: SELECT LANGUAGE, COUNT(*) FROM TV_Channel GROUP BY LANGUAGE Type: GROUP_BY, AGGREGATION [367] WRONG_COLUMNS | DB: tvshow | EX: ✓ Q : What is the TV Channel that shows the cartoon "The Rise of the Blue Beetle!"? List the TV Channel's series name Pred: SELECT DISTINCT T1.series_name FROM tv_channel AS T1 JOIN cartoon AS T2 ON T1.id = T2.channel WHERE T2.title = "The Rise of the Blue Beetle!" Gold: SELECT T1.series_name FROM TV_Channel AS T1 JOIN Cartoon AS T2 ON T1.id = T2.Channel WHERE T2.Title = "The Rise of the Blue Beetle!" Type: JOIN [368] OTHER | DB: tvshow | EX: ✗ Q : What is the series name of the TV Channel that shows the cartoon "The Rise of the Blue Beetle" Pred: SELECT t1.series_name FROM tv_channel AS t1 JOIN cartoon AS t2 ON t1.id = t2.channel WHERE t2.title = "The Rise of the Blue Beetle" Gold: SELECT T1.series_name FROM TV_Channel AS T1 JOIN Cartoon AS T2 ON T1.id = T2.Channel WHERE T2.Title = "The Rise of the Blue Beetle!" Type: JOIN [369] WRONG_TABLE | DB: tvshow | EX: ✗ Q : List the title of all Cartoons showed on TV Channel with series name "Sky Radio" Pred: SELECT DISTINCT T1.title FROM cartoon AS T1 JOIN tv_channel AS T2 ON T1.id = T2.channel WHERE T2.series_name = "Sky Radio" Gold: SELECT T2.Title FROM TV_Channel AS T1 JOIN Cartoon AS T2 ON T1.id = T2.Channel WHERE T1.series_name = "Sky Radio" Type: JOIN [370] WRONG_TABLE | DB: tvshow | EX: ✗ Q : What is the title of all the cartools that are on the TV Channel with the series name "Sky Radio" Pred: SELECT t1.title FROM cartoon AS t1 JOIN tv_channel AS t2 ON t1.id = t2.channel WHERE t2.series_name = "Sky Radio" Gold: SELECT T2.Title FROM TV_Channel AS T1 JOIN Cartoon AS T2 ON T1.id = T2.Channel WHERE T1.series_name = "Sky Radio" Type: JOIN [371] EXTRA_JOIN | DB: tvshow | EX: ✗ Q : List top 3 highest Rating TV series. List the TV series's Episode and Rating Pred: SELECT T1.episode, T1.rating FROM tv_series AS T1 JOIN tv_series AS T2 ON T1.id = T2.series ORDER BY T2.rating DESC LIMIT 3 Gold: SELECT Episode, Rating FROM TV_series ORDER BY Rating DESC LIMIT 3 Type: ORDER_BY, LIMIT [372] EXTRA_JOIN | DB: tvshow | EX: ✗ Q : What are 3 most highly rated episodes in the TV series table and what were those ratings Pred: SELECT t1.episode, t1.rating FROM tv_series AS t1 JOIN tv_series AS t2 ON t1.id = t2.series_id GROUP BY t1.id ORDER BY COUNT(*) DESC LIMIT 3 Gold: SELECT Episode, Rating FROM TV_series ORDER BY Rating DESC LIMIT 3 Type: ORDER_BY, LIMIT [373] WRONG_COLUMNS | DB: tvshow | EX: ✗ Q : What is minimum and maximum share of TV series Pred: SELECT MIN(share), MAX(share) FROM tv_series Gold: SELECT MAX(SHARE), MIN(SHARE) FROM TV_series Type: AGGREGATION [374] EXTRA_JOIN | DB: tvshow | EX: ✗ Q : What is the air date of TV series with Episode "A Love of a Lifetime" Pred: SELECT T1.air_date FROM tv_series AS T1 JOIN cartoon AS T2 ON T1.id = T2.channel WHERE T2.series_name = "A Love of a Lifetime" Gold: SELECT Air_Date FROM TV_series WHERE Episode = "A Love of a Lifetime" Type: SIMPLE [375] WRONG_TABLE | DB: tvshow | EX: ✗ Q : When did the episode "A Love of a Lifetime" air Pred: SELECT air_date FROM cartoon WHERE title = "A Love of a Lifetime" Gold: SELECT Air_Date FROM TV_series WHERE Episode = "A Love of a Lifetime" Type: SIMPLE [376] WRONG_TABLE | DB: tvshow | EX: ✗ Q : What is the weekly rank for the episode "A Love of a Lifetime" Pred: SELECT weekly_rank FROM cartoon WHERE title = "A Love of a Lifetime" Gold: SELECT Weekly_Rank FROM TV_series WHERE Episode = "A Love of a Lifetime" Type: SIMPLE [377] WRONG_COLUMNS | DB: tvshow | EX: ✗ Q : What is the TV Channel of TV series with Episode "A Love of a Lifetime"? List the TV Channel's series name Pred: SELECT DISTINCT T1.series_name FROM tv_channel AS T1 JOIN tv_series AS T2 ON T1.id = T2.series WHERE T2.episode = "A Love of a Lifetime" Gold: SELECT T1.series_name FROM TV_Channel AS T1 JOIN TV_series AS T2 ON T1.id = T2.Channel WHERE T2.Episode = "A Love of a Lifetime" Type: JOIN [378] WRONG_TABLE | DB: tvshow | EX: ✗ Q : What is the name of the series that has the episode "A Love of a Lifetime" Pred: SELECT tv_series_name FROM cartoon WHERE episode = "A Love of a Lifetime" Gold: SELECT T1.series_name FROM TV_Channel AS T1 JOIN TV_series AS T2 ON T1.id = T2.Channel WHERE T2.Episode = "A Love of a Lifetime" Type: JOIN [379] OTHER | DB: tvshow | EX: ✗ Q : List the Episode of all TV series showed on TV Channel with series name "Sky Radio" Pred: SELECT T2.episode FROM tv_channel AS T1 JOIN tv_series AS T2 ON T1.id = T2.channel WHERE T2.series_name = "Sky Radio" Gold: SELECT T2.Episode FROM TV_Channel AS T1 JOIN TV_series AS T2 ON T1.id = T2.Channel WHERE T1.series_name = "Sky Radio" Type: JOIN [380] WRONG_TABLE | DB: tvshow | EX: ✗ Q : What is the episode for the TV series named "Sky Radio" Pred: SELECT T1.episode FROM tv_series AS T1 JOIN cartoon AS T2 ON T1.id = T2.channel WHERE T2.series_name = "Sky Radio" Gold: SELECT T2.Episode FROM TV_Channel AS T1 JOIN TV_series AS T2 ON T1.id = T2.Channel WHERE T1.series_name = "Sky Radio" Type: JOIN [381] EXTRA_JOIN | DB: tvshow | EX: ✗ Q : Find the package choice and series name of the TV channel that has high definition TV Pred: SELECT t2.package_option, t2.series_name FROM tv_channel AS t1 JOIN tv_series AS t2 ON t1.id = t2.series WHERE t1.hight_definition_tv = 'yes' Gold: SELECT package_option, series_name FROM TV_Channel WHERE hight_definition_TV = "yes" Type: SIMPLE [382] EXTRA_JOIN | DB: tvshow | EX: ✗ Q : What are the package options and the name of the series for the TV Channel that supports high definition TV Pred: SELECT DISTINCT T1.package_option, T1.series_name FROM tv_channel AS T1 JOIN tv_series AS T2 ON T1.id = T2.series WHERE T1.hight_definition_tv = 'Hight' Gold: SELECT package_option, series_name FROM TV_Channel WHERE hight_definition_TV = "yes" Type: SIMPLE [383] WRONG_TABLE | DB: tvshow | EX: ✗ Q : What are the countries that are not playing cartoons written by Todd Casey Pred: SELECT country FROM cartoon EXCEPT SELECT T1.country FROM cartoon AS T1 JOIN cartoon AS T2 ON T1.id = T2.channel WHERE T2.written_by = 'Todd Casey' Gold: SELECT country FROM TV_Channel EXCEPT SELECT T1.country FROM TV_Channel AS T1 JOIN cartoon AS T2 ON T1.id = T2.Channel WHERE T2.written_by = 'Todd Casey' Type: JOIN [384] OTHER | DB: tvshow | EX: ✓ Q : Find the series name and country of the tv channel that is playing some cartoons directed by Ben Jones and Michael Chang Pred: SELECT T1.series_name, T1.country FROM tv_channel AS T1 JOIN cartoon AS T2 ON T1.id = T2.channel WHERE T2.directed_by = 'Ben Jones' INTERSECT SELECT T1.series_name, T1.country FROM tv_channel AS T1 JOIN cartoon AS T2 ON T1.id = T2.channel WHERE T2.directed_by = 'Michael Chang' Gold: SELECT T1.series_name, T1.country FROM TV_Channel AS T1 JOIN cartoon AS T2 ON T1.id = T2.Channel WHERE T2.directed_by = 'Michael Chang' INTERSECT SELECT T1.series_name, T1.country FROM TV_Channel AS T1 JOIN cartoon AS T2 ON T1.id = T2.Channel WHERE T2.directed_by = 'Ben Jones' Type: JOIN [385] OTHER | DB: tvshow | EX: ✓ Q : What is the series name and country of all TV channels that are playing cartoons directed by Ben Jones and cartoons directed by Michael Chang Pred: SELECT T1.series_name, T1.country FROM tv_channel AS T1 JOIN cartoon AS T2 ON T1.id = T2.channel WHERE T2.directed_by = 'Ben Jones' INTERSECT SELECT T1.series_name, T1.country FROM tv_channel AS T1 JOIN cartoon AS T2 ON T1.id = T2.channel WHERE T2.directed_by = 'Michael Chang' Gold: SELECT T1.series_name, T1.country FROM TV_Channel AS T1 JOIN cartoon AS T2 ON T1.id = T2.Channel WHERE T2.directed_by = 'Michael Chang' INTERSECT SELECT T1.series_name, T1.country FROM TV_Channel AS T1 JOIN cartoon AS T2 ON T1.id = T2.Channel WHERE T2.directed_by = 'Ben Jones' Type: JOIN [386] OTHER | DB: tvshow | EX: ✗ Q : find the pixel aspect ratio and nation of the tv channels that do not use English Pred: SELECT pixel_aspect_ratio_par, country FROM tv_channel WHERE language > "english" Gold: SELECT Pixel_aspect_ratio_PAR, country FROM tv_channel WHERE LANGUAGE <> 'English' Type: SIMPLE [387] OTHER | DB: tvshow | EX: ✗ Q : What is the pixel aspect ratio and country of origin for all TV channels that do not use English Pred: SELECT pixel_aspect_ratio_par, country FROM tv_channel WHERE language > 'english' Gold: SELECT Pixel_aspect_ratio_PAR, country FROM tv_channel WHERE LANGUAGE <> 'English' Type: SIMPLE [388] EXTRA_JOIN | DB: tvshow | EX: ✗ Q : find id of the tv channels that from the countries where have more than two tv channels Pred: SELECT t1.id FROM tv_channel AS t1 JOIN cartoon AS t2 ON t1.id = t2.channel GROUP BY t2.country HAVING COUNT(*) > 2 Gold: SELECT id FROM tv_channel GROUP BY country HAVING COUNT(*) > 2 Type: GROUP_BY, HAVING, AGGREGATION [389] OTHER | DB: tvshow | EX: ✗ Q : What are the ids of all tv channels that have more than 2 TV channels Pred: SELECT id FROM tv_channel GROUP BY id HAVING COUNT(*) > 2 Gold: SELECT id FROM tv_channel GROUP BY country HAVING COUNT(*) > 2 Type: GROUP_BY, HAVING, AGGREGATION [390] WRONG_TABLE | DB: tvshow | EX: ✗ Q : find the id of tv channels that do not play any cartoon directed by Ben Jones Pred: SELECT tv_channel FROM tv_channel EXCEPT SELECT t1.id FROM tv_channel AS t1 JOIN cartoon AS t2 ON t1.id = t2.channel WHERE t2.directed_by = "Ben Jones" Gold: SELECT id FROM TV_Channel EXCEPT SELECT channel FROM cartoon WHERE directed_by = 'Ben Jones' Type: SIMPLE [391] WRONG_TABLE | DB: tvshow | EX: ✗ Q : What are the ids of the TV channels that do not have any cartoons directed by Ben Jones Pred: SELECT tv_channel FROM tv_channel EXCEPT SELECT t1.id FROM tv_channel AS t1 JOIN cartoon AS t2 ON t1.id = t2.channel WHERE t2.directed_by = "Ben Jones" Gold: SELECT id FROM TV_Channel EXCEPT SELECT channel FROM cartoon WHERE directed_by = 'Ben Jones' Type: SIMPLE [392] WRONG_TABLE | DB: tvshow | EX: ✗ Q : find the package option of the tv channel that do not have any cartoon directed by Ben Jones Pred: SELECT package_option FROM tv_channel EXCEPT SELECT t1.channel FROM tv_channel AS t1 JOIN cartoon AS t2 ON t1.id = t2.channel WHERE t2.directed_by = "Ben Jones" Gold: SELECT package_option FROM TV_Channel WHERE NOT id IN (SELECT channel FROM cartoon WHERE directed_by = 'Ben Jones') Type: NESTED [393] WRONG_TABLE | DB: tvshow | EX: ✗ Q : What are the package options of all tv channels that are not playing any cartoons directed by Ben Jones Pred: SELECT package_option FROM tv_channel EXCEPT SELECT t1.channel FROM tv_channel AS t1 JOIN cartoon AS t2 ON t1.id = t2.channel WHERE t2.directed_by = "Ben Jones" Gold: SELECT package_option FROM TV_Channel WHERE NOT id IN (SELECT channel FROM cartoon WHERE directed_by = 'Ben Jones') Type: NESTED [394] EXTRA_JOIN | DB: poker_player | EX: ✗ Q : What are the final tables made and best finishes for all poker players Pred: SELECT T2.Final_Table_Made, T2.Best_finish FROM poker_player AS T1 JOIN people AS T2 ON T1.People_ID = T2.People_ID Gold: SELECT Final_Table_Made, Best_Finish FROM poker_player Type: SIMPLE [395] EXTRA_JOIN | DB: poker_player | EX: ✗ Q : What is the maximum number of final tables made among poker players with earnings less than 200000 Pred: SELECT MAX(T2.Final_Table_Made) FROM poker_player AS T1 JOIN people AS T2 ON T1.People_ID = T2.People_ID WHERE T1.Earnings 200000 Gold: SELECT MAX(Final_Table_Made) FROM poker_player WHERE Earnings < 200000 Type: AGGREGATION [396] EXTRA_JOIN | DB: poker_player | EX: ✗ Q : Return the maximum final tables made across all poker players who have earnings below 200000 Pred: SELECT MAX(T2.Final_Table_Made) FROM poker_player AS T1 JOIN people AS T2 ON T1.People_ID = T2.People_ID WHERE T1.Earnings 200000 Gold: SELECT MAX(Final_Table_Made) FROM poker_player WHERE Earnings < 200000 Type: AGGREGATION [397] WRONG_TABLE | DB: poker_player | EX: ✓ Q : What are the names of poker players Pred: SELECT T2.Name FROM poker_player AS T1 JOIN people AS T2 ON T1.People_ID = T2.People_ID Gold: SELECT T1.Name FROM people AS T1 JOIN poker_player AS T2 ON T1.People_ID = T2.People_ID Type: JOIN [398] WRONG_TABLE | DB: poker_player | EX: ✓ Q : Return the names of all the poker players Pred: SELECT T2.Name FROM poker_player AS T1 JOIN people AS T2 ON T1.People_ID = T2.People_ID Gold: SELECT T1.Name FROM people AS T1 JOIN poker_player AS T2 ON T1.People_ID = T2.People_ID Type: JOIN [399] WRONG_TABLE | DB: poker_player | EX: ✓ Q : What are the names of poker players whose earnings is higher than 300000 Pred: SELECT T2.Name FROM poker_player AS T1 JOIN people AS T2 ON T1.People_ID = T2.People_ID WHERE T1.Earnings > 300000 Gold: SELECT T1.Name FROM people AS T1 JOIN poker_player AS T2 ON T1.People_ID = T2.People_ID WHERE T2.Earnings > 300000 Type: JOIN [400] WRONG_TABLE | DB: poker_player | EX: ✓ Q : Give the names of poker players who have earnings above 300000 Pred: SELECT T2.Name FROM poker_player AS T1 JOIN people AS T2 ON T1.People_ID = T2.People_ID WHERE T1.Earnings > 300000 Gold: SELECT T1.Name FROM people AS T1 JOIN poker_player AS T2 ON T1.People_ID = T2.People_ID WHERE T2.Earnings > 300000 Type: JOIN [401] WRONG_TABLE | DB: poker_player | EX: ✓ Q : List the names of poker players ordered by the final tables made in ascending order Pred: SELECT T2.Name FROM poker_player AS T1 JOIN people AS T2 ON T1.People_ID = T2.People_ID ORDER BY T1.Final_Table_Made ASC Gold: SELECT T1.Name FROM people AS T1 JOIN poker_player AS T2 ON T1.People_ID = T2.People_ID ORDER BY T2.Final_Table_Made Type: JOIN, ORDER_BY [402] WRONG_TABLE | DB: poker_player | EX: ✓ Q : What are the names of poker players, ordered ascending by the number of final tables they have made Pred: SELECT T2.Name FROM poker_player AS T1 JOIN people AS T2 ON T1.People_ID = T2.People_ID ORDER BY T1.Final_Table_Made Gold: SELECT T1.Name FROM people AS T1 JOIN poker_player AS T2 ON T1.People_ID = T2.People_ID ORDER BY T2.Final_Table_Made Type: JOIN, ORDER_BY [403] WRONG_TABLE | DB: poker_player | EX: ✓ Q : What is the birth date of the poker player with the lowest earnings Pred: SELECT T2.Birth_Date FROM poker_player AS T1 JOIN people AS T2 ON T1.People_ID = T2.People_ID ORDER BY T1.Earnings LIMIT 1 Gold: SELECT T1.Birth_Date FROM people AS T1 JOIN poker_player AS T2 ON T1.People_ID = T2.People_ID ORDER BY T2.Earnings ASC LIMIT 1 Type: JOIN, ORDER_BY, LIMIT [404] WRONG_TABLE | DB: poker_player | EX: ✓ Q : Return the birth date of the poker player with the lowest earnings Pred: SELECT T2.Birth_Date FROM poker_player AS T1 JOIN people AS T2 ON T1.People_ID = T2.People_ID ORDER BY T1.Earnings LIMIT 1 Gold: SELECT T1.Birth_Date FROM people AS T1 JOIN poker_player AS T2 ON T1.People_ID = T2.People_ID ORDER BY T2.Earnings ASC LIMIT 1 Type: JOIN, ORDER_BY, LIMIT [405] WRONG_TABLE | DB: poker_player | EX: ✗ Q : What is the money rank of the tallest poker player Pred: SELECT Money_Rank FROM poker_player ORDER BY Height DESC LIMIT 1 Gold: SELECT T2.Money_Rank FROM people AS T1 JOIN poker_player AS T2 ON T1.People_ID = T2.People_ID ORDER BY T1.Height DESC LIMIT 1 Type: JOIN, ORDER_BY, LIMIT [406] WRONG_TABLE | DB: poker_player | EX: ✗ Q : Return the money rank of the poker player with the greatest height Pred: SELECT Money_Rank FROM poker_player ORDER BY Height DESC LIMIT 1 Gold: SELECT T2.Money_Rank FROM people AS T1 JOIN poker_player AS T2 ON T1.People_ID = T2.People_ID ORDER BY T1.Height DESC LIMIT 1 Type: JOIN, ORDER_BY, LIMIT [407] WRONG_TABLE | DB: poker_player | EX: ✗ Q : What is the average earnings of poker players with height higher than 200 Pred: SELECT AVG(Earnings) FROM poker_player WHERE Height > 200 Gold: SELECT AVG(T2.Earnings) FROM people AS T1 JOIN poker_player AS T2 ON T1.People_ID = T2.People_ID WHERE T1.Height > 200 Type: JOIN, AGGREGATION [408] WRONG_TABLE | DB: poker_player | EX: ✓ Q : Give average earnings of poker players who are taller than 200 Pred: SELECT AVG(Earnings) FROM poker_player AS T1 JOIN people AS T2 ON T1.People_ID = T2.People_ID WHERE T2.Height > 200 Gold: SELECT AVG(T2.Earnings) FROM people AS T1 JOIN poker_player AS T2 ON T1.People_ID = T2.People_ID WHERE T1.Height > 200 Type: JOIN, AGGREGATION [409] WRONG_TABLE | DB: poker_player | EX: ✓ Q : What are the names of poker players in descending order of earnings Pred: SELECT T2.Name FROM poker_player AS T1 JOIN people AS T2 ON T1.People_ID = T2.People_ID ORDER BY T1.Earnings DESC Gold: SELECT T1.Name FROM people AS T1 JOIN poker_player AS T2 ON T1.People_ID = T2.People_ID ORDER BY T2.Earnings DESC Type: JOIN, ORDER_BY [410] WRONG_TABLE | DB: poker_player | EX: ✓ Q : Return the names of poker players sorted by their earnings descending Pred: SELECT T2.Name FROM poker_player AS T1 JOIN people AS T2 ON T1.People_ID = T2.People_ID ORDER BY T1.Earnings DESC Gold: SELECT T1.Name FROM people AS T1 JOIN poker_player AS T2 ON T1.People_ID = T2.People_ID ORDER BY T2.Earnings DESC Type: JOIN, ORDER_BY [411] OTHER | DB: poker_player | EX: ✗ Q : Show names of people whose nationality is not "Russia" Pred: SELECT Name FROM people WHERE Nationality > 'Russia' Gold: SELECT Name FROM people WHERE Nationality <> "Russia" Type: SIMPLE [412] OTHER | DB: poker_player | EX: ✗ Q : What are the names of people who are not from Russia Pred: SELECT Name FROM people WHERE Nationality > 'Russia' Gold: SELECT Name FROM people WHERE Nationality <> "Russia" Type: SIMPLE [413] WRONG_TABLE | DB: voter_1 | EX: ✗ Q : What are the maximum and minimum values of area codes Pred: SELECT MAX(area_code), MIN(area_code) FROM area_code Gold: SELECT MAX(area_code), MIN(area_code) FROM area_code_state Type: AGGREGATION [414] WRONG_COLUMNS | DB: voter_1 | EX: ✓ Q : What is last date created of votes from the state 'CA' Pred: SELECT created FROM votes WHERE state = 'CA' Gold: SELECT MAX(created) FROM votes WHERE state = 'CA' Type: AGGREGATION [415] OTHER | DB: voter_1 | EX: ✓ Q : What are the names of the contestants whose names are not 'Jessie Alloway' Pred: SELECT contestant_name FROM contestants EXCEPT SELECT contestant_name FROM contestants WHERE contestant_name = 'Jessie Alloway' Gold: SELECT contestant_name FROM contestants WHERE contestant_name <> 'Jessie Alloway' Type: SIMPLE [416] WRONG_TABLE | DB: voter_1 | EX: ✓ Q : What are the contestant numbers and names of the contestants who had at least two votes Pred: SELECT T2.contestant_number, T2.contestant_name FROM votes AS T1 JOIN contestants AS T2 ON T1.contestant_number = T2.contestant_number GROUP BY T2.contestant_number HAVING COUNT(*) >= 2 Gold: SELECT T1.contestant_number, T1.contestant_name FROM contestants AS T1 JOIN votes AS T2 ON T1.contestant_number = T2.contestant_number GROUP BY T1.contestant_number HAVING COUNT(*) >= 2 Type: JOIN, GROUP_BY, HAVING, AGGREGATION [417] WRONG_TABLE | DB: voter_1 | EX: ✗ Q : Of all the contestants who got voted, what is the contestant number and name of the contestant who got least votes Pred: SELECT T2.contestant_number, T2.contestant_name FROM votes AS T1 JOIN contestants AS T2 ON T1.contestant_number = T2.contestant_number ORDER BY T1.votes ASC LIMIT 1 Gold: SELECT T1.contestant_number, T1.contestant_name FROM contestants AS T1 JOIN votes AS T2 ON T1.contestant_number = T2.contestant_number GROUP BY T1.contestant_number ORDER BY COUNT(*) ASC LIMIT 1 Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, AGGREGATION [418] WRONG_TABLE | DB: voter_1 | EX: ✗ Q : What is the area code in which the most voters voted Pred: SELECT area_code FROM votes GROUP BY area_code_state ORDER BY COUNT(*) DESC LIMIT 1 Gold: SELECT T1.area_code FROM area_code_state AS T1 JOIN votes AS T2 ON T1.state = T2.state GROUP BY T1.area_code ORDER BY COUNT(*) DESC LIMIT 1 Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, AGGREGATION [419] WRONG_TABLE | DB: voter_1 | EX: ✓ Q : What are the create dates, states, and phone numbers of the votes that were for the contestant named 'Tabatha Gehling' Pred: SELECT T1.created, T1.state, T1.phone_number FROM votes AS T1 JOIN contestants AS T2 ON T1.contestant_number = T2.contestant_number WHERE T2.contestant_name = 'Tabatha Gehling' Gold: SELECT T2.created, T2.state, T2.phone_number FROM contestants AS T1 JOIN votes AS T2 ON T1.contestant_number = T2.contestant_number WHERE T1.contestant_name = 'Tabatha Gehling' Type: JOIN [420] WRONG_TABLE | DB: voter_1 | EX: ✗ Q : List the area codes in which voters voted both for the contestant 'Tabatha Gehling' and the contestant 'Kelly Clauss' Pred: SELECT T1.area_code FROM votes AS T1 JOIN contestants AS T2 ON T1.contestant_number = T2.contestant_number WHERE T2.contestant_name = 'Tabatha Gehling' INTERSECT SELECT T1.area_code FROM votes AS T1 JOIN contestants AS T2 ON T1.contestant_number = T2.contestant_number WHERE T2.contestant_name = 'Kelly Clauss' Gold: SELECT T3.area_code FROM contestants AS T1 JOIN votes AS T2 ON T1.contestant_number = T2.contestant_number JOIN area_code_state AS T3 ON T2.state = T3.state WHERE T1.contestant_name = 'Tabatha Gehling' INTERSECT SELECT T3.area_code FROM contestants AS T1 JOIN votes AS T2 ON T1.contestant_number = T2.contestant_number JOIN area_code_state AS T3 ON T2.state = T3.state WHERE T1.contestant_name = 'Kelly Clauss' Type: JOIN [421] OTHER | DB: world_1 | EX: ✗ Q : What is the total surface area of the countries in the Caribbean region Pred: SELECT SUM(surfacearea) FROM country WHERE region = 'Carribbean' Gold: SELECT SUM(SurfaceArea) FROM country WHERE Region = "Caribbean" Type: AGGREGATION [422] OTHER | DB: world_1 | EX: ✗ Q : How much surface area do the countires in the Carribean cover together Pred: SELECT SUM(surfacearea) FROM country WHERE region = 'Carribean' Gold: SELECT SUM(SurfaceArea) FROM country WHERE Region = "Caribbean" Type: AGGREGATION [423] WRONG_TABLE | DB: world_1 | EX: ✗ Q : Which region is the city Kabul located in Pred: SELECT region FROM city WHERE name = 'Kabul' Gold: SELECT Region FROM country AS T1 JOIN city AS T2 ON T1.Code = T2.CountryCode WHERE T2.Name = "Kabul" Type: JOIN [424] WRONG_TABLE | DB: world_1 | EX: ✗ Q : What region is Kabul in Pred: SELECT region FROM city WHERE name = 'Kabul' Gold: SELECT Region FROM country AS T1 JOIN city AS T2 ON T1.Code = T2.CountryCode WHERE T2.Name = "Kabul" Type: JOIN [425] WRONG_COLUMNS | DB: world_1 | EX: ✗ Q : Which language is the most popular in Aruba Pred: SELECT T1.language FROM country AS T1 JOIN countrylanguage AS T2 ON T1.countrycode = T2.countrycode WHERE T2.name = 'Aruba' GROUP BY T1.language ORDER BY COUNT(*) DESC LIMIT 1 Gold: SELECT T2.Language FROM country AS T1 JOIN countrylanguage AS T2 ON T1.Code = T2.CountryCode WHERE T1.Name = "Aruba" ORDER BY Percentage DESC LIMIT 1 Type: JOIN, ORDER_BY, LIMIT [426] WRONG_TABLE | DB: world_1 | EX: ✗ Q : What language is predominantly spoken in Aruba Pred: SELECT language FROM countrylanguage WHERE countrycode = 'Aruba' GROUP BY language HAVING COUNT(*) >= 1 Gold: SELECT T2.Language FROM country AS T1 JOIN countrylanguage AS T2 ON T1.Code = T2.CountryCode WHERE T1.Name = "Aruba" ORDER BY Percentage DESC LIMIT 1 Type: JOIN, ORDER_BY, LIMIT [427] WRONG_COLUMNS | DB: world_1 | EX: ✗ Q : What are the region and population of Angola Pred: SELECT region, population FROM country WHERE countrycode = 'Angola' Gold: SELECT Population, Region FROM country WHERE Name = "Angola" Type: SIMPLE [428] EXTRA_JOIN | DB: world_1 | EX: ✗ Q : What region does Angola belong to and what is its population Pred: SELECT T1.region, T2.population FROM country AS T1 JOIN city AS T2 ON T1.countrycode = T2.code WHERE T1.name = 'Angola' Gold: SELECT Population, Region FROM country WHERE Name = "Angola" Type: SIMPLE [429] MISSING_WHERE | DB: world_1 | EX: ✗ Q : What is the name of country that has the shortest life expectancy in Asia Pred: SELECT name FROM country ORDER BY lifeexpectancy ASC LIMIT 1 Gold: SELECT Name FROM country WHERE Continent = "Asia" ORDER BY LifeExpectancy LIMIT 1 Type: ORDER_BY, LIMIT [430] OTHER | DB: world_1 | EX: ✗ Q : Give the name of the country in Asia with the lowest life expectancy Pred: SELECT name FROM country WHERE region = 'Asia' ORDER BY lifeexpectancy LIMIT 1 Gold: SELECT Name FROM country WHERE Continent = "Asia" ORDER BY LifeExpectancy LIMIT 1 Type: ORDER_BY, LIMIT [431] OTHER | DB: world_1 | EX: ✗ Q : What is the total population and maximum GNP in Asia Pred: SELECT SUM(population), MAX(gnp) FROM country WHERE region = 'Asie' Gold: SELECT SUM(Population), MAX(GNP) FROM country WHERE Continent = "Asia" Type: AGGREGATION [432] EXTRA_JOIN | DB: world_1 | EX: ✗ Q : How many people live in Asia, and what is the largest GNP among them Pred: SELECT T1.population, T1.gnp FROM country AS T1 JOIN country AS T2 ON T1.countrycode = T2.code WHERE T2.region = 'Asia' ORDER BY T1.gnp DESC LIMIT 1 Gold: SELECT SUM(Population), MAX(GNP) FROM country WHERE Continent = "Asia" Type: AGGREGATION [433] WRONG_COLUMNS | DB: world_1 | EX: ✗ Q : What is the average life expectancy in African countries that are republics Pred: SELECT AVG(lifeexpectancy) FROM country WHERE region = "Africa" INTERSECT SELECT countrycode FROM country WHERE region = "Republica" Gold: SELECT AVG(LifeExpectancy) FROM country WHERE Continent = "Africa" AND GovernmentForm = "Republic" Type: AGGREGATION [434] OTHER | DB: world_1 | EX: ✗ Q : Give the average life expectancy for countries in Africa which are republics Pred: SELECT AVG(lifeexpectancy) FROM country WHERE region = 'Africa' AND region = 'Republica' Gold: SELECT AVG(LifeExpectancy) FROM country WHERE Continent = "Africa" AND GovernmentForm = "Republic" Type: AGGREGATION [435] OTHER | DB: world_1 | EX: ✗ Q : What is the total surface area of the continents Asia and Europe Pred: SELECT SUM(surfacearea) FROM country WHERE continent = 'Asie' INTERSECT SELECT SUM(surfacearea) FROM country WHERE region = 'Europe' Gold: SELECT SUM(SurfaceArea) FROM country WHERE Continent = "Asia" OR Continent = "Europe" Type: AGGREGATION [436] OTHER | DB: world_1 | EX: ✗ Q : Give the total surface area covered by countries in Asia or Europe Pred: SELECT SUM(surfacearea) FROM country WHERE region = 'Asie' OR region = 'Europe' Gold: SELECT SUM(SurfaceArea) FROM country WHERE Continent = "Asia" OR Continent = "Europe" Type: AGGREGATION [437] OTHER | DB: world_1 | EX: ✗ Q : Give the mean GNP and total population of nations which are considered US territory Pred: SELECT AVG(gnp), SUM(population) FROM country WHERE countrycode = 'USA' Gold: SELECT AVG(GNP), SUM(population) FROM country WHERE GovernmentForm = "US Territory" Type: AGGREGATION [438] WRONG_COLUMNS | DB: world_1 | EX: ✗ Q : What is the total number of languages used in Aruba Pred: SELECT COUNT(*) FROM country AS T1 JOIN countrylanguage AS T2 ON T1.countrycode = T2.countrycode WHERE T1.name = 'Aruba' Gold: SELECT COUNT(T2.Language) FROM country AS T1 JOIN countrylanguage AS T2 ON T1.Code = T2.CountryCode WHERE T1.Name = "Aruba" Type: JOIN, AGGREGATION [439] WRONG_COLUMNS | DB: world_1 | EX: ✗ Q : How many languages are spoken in Aruba Pred: SELECT COUNT(*) FROM country AS T1 JOIN countrylanguage AS T2 ON T1.countrycode = T2.countrycode WHERE T1.name = 'Aruba' Gold: SELECT COUNT(T2.Language) FROM country AS T1 JOIN countrylanguage AS T2 ON T1.Code = T2.CountryCode WHERE T1.Name = "Aruba" Type: JOIN, AGGREGATION [440] OTHER | DB: world_1 | EX: ✗ Q : How many official languages does Afghanistan have Pred: SELECT COUNT(*) FROM country AS T1 JOIN countrylanguage AS T2 ON T1.countrycode = T2.code WHERE T1.region = "Afghanistan" Gold: SELECT COUNT(*) FROM country AS T1 JOIN countrylanguage AS T2 ON T1.Code = T2.CountryCode WHERE T1.Name = "Afghanistan" AND IsOfficial = "T" Type: JOIN, AGGREGATION [441] OTHER | DB: world_1 | EX: ✗ Q : How many official languages are spoken in Afghanistan Pred: SELECT COUNT(*) FROM country AS T1 JOIN countrylanguage AS T2 ON T1.countrycode = T2.code WHERE T1.region = "Afghanistan" Gold: SELECT COUNT(*) FROM country AS T1 JOIN countrylanguage AS T2 ON T1.Code = T2.CountryCode WHERE T1.Name = "Afghanistan" AND IsOfficial = "T" Type: JOIN, AGGREGATION [442] OTHER | DB: world_1 | EX: ✗ Q : What is name of the country that speaks the largest number of languages Pred: SELECT T1.name FROM country AS T1 JOIN countrylanguage AS T2 ON T1.countrycode = T2.code GROUP BY T1.name ORDER BY COUNT(*) DESC LIMIT 1 Gold: SELECT T1.Name FROM country AS T1 JOIN countrylanguage AS T2 ON T1.Code = T2.CountryCode GROUP BY T1.Name ORDER BY COUNT(*) DESC LIMIT 1 Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, AGGREGATION [443] OTHER | DB: world_1 | EX: ✗ Q : Give the name of the nation that uses the greatest amount of languages Pred: SELECT T1.name FROM country AS T1 JOIN countrylanguage AS T2 ON T1.countrycode = T2.code GROUP BY T1.countrycode ORDER BY COUNT(*) DESC LIMIT 1 Gold: SELECT T1.Name FROM country AS T1 JOIN countrylanguage AS T2 ON T1.Code = T2.CountryCode GROUP BY T1.Name ORDER BY COUNT(*) DESC LIMIT 1 Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, AGGREGATION [444] MISSING_JOIN | DB: world_1 | EX: ✓ Q : Which continent has the most diverse languages Pred: SELECT continent FROM country GROUP BY continent ORDER BY COUNT(*) DESC LIMIT 1 Gold: SELECT T1.Continent FROM country AS T1 JOIN countrylanguage AS T2 ON T1.Code = T2.CountryCode GROUP BY T1.Continent ORDER BY COUNT(*) DESC LIMIT 1 Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, AGGREGATION [445] MISSING_JOIN | DB: world_1 | EX: ✓ Q : Which continent speaks the most languages Pred: SELECT continent FROM country GROUP BY continent ORDER BY COUNT(*) DESC LIMIT 1 Gold: SELECT T1.Continent FROM country AS T1 JOIN countrylanguage AS T2 ON T1.Code = T2.CountryCode GROUP BY T1.Continent ORDER BY COUNT(*) DESC LIMIT 1 Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, AGGREGATION [446] WRONG_TABLE | DB: world_1 | EX: ✗ Q : How many countries speak both English and Dutch Pred: SELECT COUNT(*) FROM countrylanguage WHERE language = 'english' INTERSECT SELECT COUNT(*) FROM countrylanguage WHERE language = 'Dutch' Gold: SELECT COUNT(*) FROM (SELECT T1.Name FROM country AS T1 JOIN countrylanguage AS T2 ON T1.Code = T2.CountryCode WHERE T2.Language = "English" INTERSECT SELECT T1.Name FROM country AS T1 JOIN countrylanguage AS T2 ON T1.Code = T2.CountryCode WHERE T2.Language = "Dutch") Type: JOIN, NESTED, AGGREGATION [447] WRONG_TABLE | DB: world_1 | EX: ✗ Q : What is the number of nations that use English and Dutch Pred: SELECT COUNT(*) FROM countrylanguage WHERE language = 'english' INTERSECT SELECT COUNT(*) FROM countrylanguage WHERE language = 'Dutch' Gold: SELECT COUNT(*) FROM (SELECT T1.Name FROM country AS T1 JOIN countrylanguage AS T2 ON T1.Code = T2.CountryCode WHERE T2.Language = "English" INTERSECT SELECT T1.Name FROM country AS T1 JOIN countrylanguage AS T2 ON T1.Code = T2.CountryCode WHERE T2.Language = "Dutch") Type: JOIN, NESTED, AGGREGATION [448] WRONG_TABLE | DB: world_1 | EX: ✗ Q : What are the names of nations speak both English and French Pred: SELECT name FROM countrylanguage WHERE language = 'english' INTERSECT SELECT name FROM countrylanguage WHERE language = 'french' Gold: SELECT T1.Name FROM country AS T1 JOIN countrylanguage AS T2 ON T1.Code = T2.CountryCode WHERE T2.Language = "English" INTERSECT SELECT T1.Name FROM country AS T1 JOIN countrylanguage AS T2 ON T1.Code = T2.CountryCode WHERE T2.Language = "French" Type: JOIN [449] OTHER | DB: world_1 | EX: ✗ Q : Give the names of nations that speak both English and French Pred: SELECT T1.name FROM country AS T1 JOIN countrylanguage AS T2 ON T1.countrycode = T2.code WHERE T2.language = 'english' INTERSECT SELECT T1.name FROM country AS T1 JOIN countrylanguage AS T2 ON T1.countrycode = T2.countrycode WHERE T2.language = 'french' Gold: SELECT T1.Name FROM country AS T1 JOIN countrylanguage AS T2 ON T1.Code = T2.CountryCode WHERE T2.Language = "English" INTERSECT SELECT T1.Name FROM country AS T1 JOIN countrylanguage AS T2 ON T1.Code = T2.CountryCode WHERE T2.Language = "French" Type: JOIN [450] OTHER | DB: world_1 | EX: ✗ Q : What are the names of nations where both English and French are official languages Pred: SELECT T1.name FROM country AS T1 JOIN countrylanguage AS T2 ON T1.countrycode = T2.code WHERE T2.language = 'english' INTERSECT SELECT T1.name FROM country AS T1 JOIN countrylanguage AS T2 ON T1.countrycode = T2.countrycode WHERE T2.language = 'french' Gold: SELECT T1.Name FROM country AS T1 JOIN countrylanguage AS T2 ON T1.Code = T2.CountryCode WHERE T2.Language = "English" AND T2.IsOfficial = "T" INTERSECT SELECT T1.Name FROM country AS T1 JOIN countrylanguage AS T2 ON T1.Code = T2.CountryCode WHERE T2.Language = "French" AND T2.IsOfficial = "T" Type: JOIN [451] OTHER | DB: world_1 | EX: ✗ Q : Give the names of countries with English and French as official languages Pred: SELECT T1.name FROM country AS T1 JOIN countrylanguage AS T2 ON T1.countrycode = T2.code WHERE T2.language = 'english' INTERSECT SELECT T1.name FROM country AS T1 JOIN countrylanguage AS T2 ON T1.countrycode = T2.countrycode WHERE T2.language = 'french' Gold: SELECT T1.Name FROM country AS T1 JOIN countrylanguage AS T2 ON T1.Code = T2.CountryCode WHERE T2.Language = "English" AND T2.IsOfficial = "T" INTERSECT SELECT T1.Name FROM country AS T1 JOIN countrylanguage AS T2 ON T1.Code = T2.CountryCode WHERE T2.Language = "French" AND T2.IsOfficial = "T" Type: JOIN [452] MISSING_JOIN | DB: world_1 | EX: ✗ Q : What is the number of distinct continents where Chinese is spoken Pred: SELECT COUNT(DISTINCT continent) FROM country WHERE language = 'Chinese' Gold: SELECT COUNT(DISTINCT Continent) FROM country AS T1 JOIN countrylanguage AS T2 ON T1.Code = T2.CountryCode WHERE T2.Language = "Chinese" Type: JOIN, AGGREGATION [453] MISSING_JOIN | DB: world_1 | EX: ✗ Q : How many continents speak Chinese Pred: SELECT COUNT(DISTINCT continent) FROM country WHERE language = 'Chinese' Gold: SELECT COUNT(DISTINCT Continent) FROM country AS T1 JOIN countrylanguage AS T2 ON T1.Code = T2.CountryCode WHERE T2.Language = "Chinese" Type: JOIN, AGGREGATION [454] MISSING_JOIN | DB: world_1 | EX: ✗ Q : What are the regions that use English or Dutch Pred: SELECT region FROM country WHERE language = "english" OR language = "Dutch" Gold: SELECT DISTINCT T1.Region FROM country AS T1 JOIN countrylanguage AS T2 ON T1.Code = T2.CountryCode WHERE T2.Language = "English" OR T2.Language = "Dutch" Type: JOIN [455] MISSING_JOIN | DB: world_1 | EX: ✗ Q : Which regions speak Dutch or English Pred: SELECT region FROM country WHERE language = 'Dutch' OR language = 'english' Gold: SELECT DISTINCT T1.Region FROM country AS T1 JOIN countrylanguage AS T2 ON T1.Code = T2.CountryCode WHERE T2.Language = "English" OR T2.Language = "Dutch" Type: JOIN [456] OTHER | DB: world_1 | EX: ✗ Q : What are the countries where either English or Dutch is the official language Pred: SELECT T1.name FROM country AS T1 JOIN countrylanguage AS T2 ON T1.countrycode = T2.code WHERE T2.language = 'English' OR T2.language = 'Dutch' Gold: SELECT t1.name FROM country AS t1 JOIN countrylanguage AS t2 ON t1.code = t2.countrycode WHERE t2.language = "english" AND isofficial = "t" UNION SELECT t1.name FROM country AS t1 JOIN countrylanguage AS t2 ON t1.code = t2.countrycode WHERE t2.language = "dutch" AND isofficial = "t" Type: JOIN [457] WRONG_COLUMNS | DB: world_1 | EX: ✗ Q : Which countries have either English or Dutch as an official language Pred: SELECT T1.name FROM country AS T1 JOIN countrylanguage AS T2 ON T1.countrycode = T2.code WHERE T2.language = 'english' OR T2.language = 'Dutch' Gold: SELECT * FROM country AS T1 JOIN countrylanguage AS T2 ON T1.Code = T2.CountryCode WHERE T2.Language = "English" AND IsOfficial = "T" UNION SELECT * FROM country AS T1 JOIN countrylanguage AS T2 ON T1.Code = T2.CountryCode WHERE T2.Language = "Dutch" AND IsOfficial = "T" Type: JOIN [458] MISSING_JOIN | DB: world_1 | EX: ✗ Q : Which language is the most popular on the Asian continent Pred: SELECT language FROM country WHERE continent = 'Asian' GROUP BY language ORDER BY COUNT(*) DESC LIMIT 1 Gold: SELECT T2.Language FROM country AS T1 JOIN countrylanguage AS T2 ON T1.Code = T2.CountryCode WHERE T1.Continent = "Asia" GROUP BY T2.Language ORDER BY COUNT(*) DESC LIMIT 1 Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, AGGREGATION [459] WRONG_TABLE | DB: world_1 | EX: ✗ Q : What is the language that is used by the largest number of Asian nations Pred: SELECT language FROM countrylanguage WHERE region = "Asian" GROUP BY language ORDER BY COUNT(*) DESC LIMIT 1 Gold: SELECT T2.Language FROM country AS T1 JOIN countrylanguage AS T2 ON T1.Code = T2.CountryCode WHERE T1.Continent = "Asia" GROUP BY T2.Language ORDER BY COUNT(*) DESC LIMIT 1 Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, AGGREGATION [460] MISSING_JOIN | DB: world_1 | EX: ✗ Q : Which languages are spoken by only one country in republic governments Pred: SELECT countrylanguage FROM country WHERE governmentform = 'Republic' GROUP BY countrylanguage HAVING COUNT(*) = 1 Gold: SELECT T2.Language FROM country AS T1 JOIN countrylanguage AS T2 ON T1.Code = T2.CountryCode WHERE T1.GovernmentForm = "Republic" GROUP BY T2.Language HAVING COUNT(*) = 1 Type: JOIN, GROUP_BY, HAVING, AGGREGATION [461] MISSING_JOIN | DB: world_1 | EX: ✗ Q : What languages are only used by a single country with a republic government Pred: SELECT countrylanguage FROM country WHERE governmentform = 'Republic' GROUP BY countrylanguage HAVING COUNT(*) = 1 Gold: SELECT T2.Language FROM country AS T1 JOIN countrylanguage AS T2 ON T1.Code = T2.CountryCode WHERE T1.GovernmentForm = "Republic" GROUP BY T2.Language HAVING COUNT(*) = 1 Type: JOIN, GROUP_BY, HAVING, AGGREGATION [462] MISSING_JOIN | DB: world_1 | EX: ✗ Q : Find the city with the largest population that uses English Pred: SELECT name FROM city WHERE language = 'english' ORDER BY population DESC LIMIT 1 Gold: SELECT T1.Name, T1.Population FROM city AS T1 JOIN countrylanguage AS T2 ON T1.CountryCode = T2.CountryCode WHERE T2.Language = "English" ORDER BY T1.Population DESC LIMIT 1 Type: JOIN, ORDER_BY, LIMIT [463] MISSING_JOIN | DB: world_1 | EX: ✗ Q : What is the most populace city that speaks English Pred: SELECT name FROM city WHERE language = "english" GROUP BY name ORDER BY COUNT(*) DESC LIMIT 1 Gold: SELECT T1.Name, T1.Population FROM city AS T1 JOIN countrylanguage AS T2 ON T1.CountryCode = T2.CountryCode WHERE T2.Language = "English" ORDER BY T1.Population DESC LIMIT 1 Type: JOIN, ORDER_BY, LIMIT [464] OTHER | DB: world_1 | EX: ✗ Q : Find the name, population and expected life length of asian country with the largest area Pred: SELECT name, population, lifeexpectancy FROM country WHERE region = "Asian" ORDER BY surfacearea DESC LIMIT 1 Gold: SELECT Name, Population, LifeExpectancy FROM country WHERE Continent = "Asia" ORDER BY SurfaceArea DESC LIMIT 1 Type: ORDER_BY, LIMIT [465] OTHER | DB: world_1 | EX: ✗ Q : What are the name, population, and life expectancy of the largest Asian country by land Pred: SELECT name, population, lifeexpectancy FROM country WHERE region = 'Asian' ORDER BY surfacearea DESC LIMIT 1 Gold: SELECT Name, Population, LifeExpectancy FROM country WHERE Continent = "Asia" ORDER BY SurfaceArea DESC LIMIT 1 Type: ORDER_BY, LIMIT [466] MISSING_JOIN | DB: world_1 | EX: ✗ Q : What is average life expectancy in the countries where English is not the official language Pred: SELECT AVG(lifeexpectancy) FROM country WHERE language > 'english' Gold: SELECT AVG(LifeExpectancy) FROM country WHERE NOT Name IN (SELECT T1.Name FROM country AS T1 JOIN countrylanguage AS T2 ON T1.Code = T2.CountryCode WHERE T2.Language = "English" AND T2.IsOfficial = "T") Type: JOIN, NESTED, AGGREGATION [467] MISSING_JOIN | DB: world_1 | EX: ✗ Q : Give the mean life expectancy of countries in which English is not the official language Pred: SELECT AVG(lifeexpectancy) FROM country WHERE language > 'english' Gold: SELECT AVG(LifeExpectancy) FROM country WHERE NOT Name IN (SELECT T1.Name FROM country AS T1 JOIN countrylanguage AS T2 ON T1.Code = T2.CountryCode WHERE T2.Language = "English" AND T2.IsOfficial = "T") Type: JOIN, NESTED, AGGREGATION [468] MISSING_JOIN | DB: world_1 | EX: ✗ Q : What is the total number of people living in the nations that do not use English Pred: SELECT SUM(population) FROM country WHERE language > 'english' Gold: SELECT SUM(Population) FROM country WHERE NOT Name IN (SELECT T1.Name FROM country AS T1 JOIN countrylanguage AS T2 ON T1.Code = T2.CountryCode WHERE T2.Language = "English") Type: JOIN, NESTED, AGGREGATION [469] MISSING_JOIN | DB: world_1 | EX: ✗ Q : How many people live in countries that do not speak English Pred: SELECT COUNT(population) FROM country WHERE language > 'english' Gold: SELECT SUM(Population) FROM country WHERE NOT Name IN (SELECT T1.Name FROM country AS T1 JOIN countrylanguage AS T2 ON T1.Code = T2.CountryCode WHERE T2.Language = "English") Type: JOIN, NESTED, AGGREGATION [470] WRONG_TABLE | DB: world_1 | EX: ✗ Q : What is the official language spoken in the country whose head of state is Beatrix Pred: SELECT T1.language FROM countrylanguage AS T1 JOIN country AS T2 ON T1.countrycode = T2.code WHERE T2.headofstate = 'Beatrix' Gold: SELECT T2.Language FROM country AS T1 JOIN countrylanguage AS T2 ON T1.Code = T2.CountryCode WHERE T1.HeadOfState = "Beatrix" AND T2.IsOfficial = "T" Type: JOIN [471] WRONG_TABLE | DB: world_1 | EX: ✗ Q : What is the official language used in the country the name of whose head of state is Beatrix Pred: SELECT T1.language FROM countrylanguage AS T1 JOIN country AS T2 ON T1.countrycode = T2.code WHERE T2.headofstate = 'Beatrix' Gold: SELECT T2.Language FROM country AS T1 JOIN countrylanguage AS T2 ON T1.Code = T2.CountryCode WHERE T1.HeadOfState = "Beatrix" AND T2.IsOfficial = "T" Type: JOIN [472] WRONG_COLUMNS | DB: world_1 | EX: ✗ Q : What is the total number of unique official languages spoken in the countries that are founded before 1930 Pred: SELECT COUNT(DISTINCT T1.isofficial) FROM country AS T1 JOIN countrylanguage AS T2 ON T1.countrycode = T2.code WHERE T1.indepyear 1930 Gold: SELECT COUNT(DISTINCT T2.Language) FROM country AS T1 JOIN countrylanguage AS T2 ON T1.Code = T2.CountryCode WHERE IndepYear < 1930 AND T2.IsOfficial = "T" Type: JOIN, AGGREGATION [473] WRONG_TABLE | DB: world_1 | EX: ✗ Q : For the countries founded before 1930, what is the total number of distinct official languages Pred: SELECT COUNT(DISTINCT language) FROM countrycode WHERE indepyear 1930 Gold: SELECT COUNT(DISTINCT T2.Language) FROM country AS T1 JOIN countrylanguage AS T2 ON T1.Code = T2.CountryCode WHERE IndepYear < 1930 AND T2.IsOfficial = "T" Type: JOIN, AGGREGATION [474] WRONG_COLUMNS | DB: world_1 | EX: ✗ Q : What are the countries that have greater surface area than any country in Europe Pred: SELECT name FROM country WHERE surfacearea > (SELECT MAX(surfacearea) FROM country WHERE continent = 'Europe') Gold: SELECT Name FROM country WHERE SurfaceArea > (SELECT MIN(SurfaceArea) FROM country WHERE Continent = "Europe") Type: NESTED, AGGREGATION [475] WRONG_COLUMNS | DB: world_1 | EX: ✗ Q : Which countries have greater area than that of any country in Europe Pred: SELECT name FROM country WHERE surfacearea > (SELECT MAX(surfacearea) FROM country WHERE region = 'Europe') Gold: SELECT Name FROM country WHERE SurfaceArea > (SELECT MIN(SurfaceArea) FROM country WHERE Continent = "Europe") Type: NESTED, AGGREGATION [476] OTHER | DB: world_1 | EX: ✗ Q : What are the African countries that have a population less than any country in Asia Pred: SELECT name FROM country WHERE region = "Asia" AND population (SELECT MAX(population) FROM country WHERE region = "Africa") Gold: SELECT Name FROM country WHERE Continent = "Africa" AND population < (SELECT MAX(population) FROM country WHERE Continent = "Asia") Type: NESTED, AGGREGATION [477] WRONG_COLUMNS | DB: world_1 | EX: ✗ Q : Which African countries have a smaller population than that of any country in Asia Pred: SELECT name FROM country WHERE region = 'Asia' AND population (SELECT MAX(population) FROM country WHERE region = 'Africa') Gold: SELECT Name FROM country WHERE Continent = "Africa" AND population < (SELECT MIN(population) FROM country WHERE Continent = "Asia") Type: NESTED, AGGREGATION [478] OTHER | DB: world_1 | EX: ✗ Q : Which Asian countries have a population that is larger than any country in Africa Pred: SELECT name FROM country WHERE region = "Asia" AND population > (SELECT MAX(population) FROM country WHERE continent = "Africa") Gold: SELECT Name FROM country WHERE Continent = "Asia" AND population > (SELECT MAX(population) FROM country WHERE Continent = "Africa") Type: NESTED, AGGREGATION [479] WRONG_COLUMNS | DB: world_1 | EX: ✗ Q : What are the Asian countries which have a population larger than that of any country in Africa Pred: SELECT name FROM country WHERE region = "Asia" AND population > (SELECT MAX(population) FROM country WHERE continent = "Africa") Gold: SELECT Name FROM country WHERE Continent = "Asia" AND population > (SELECT MIN(population) FROM country WHERE Continent = "Africa") Type: NESTED, AGGREGATION [480] WRONG_TABLE | DB: world_1 | EX: ✗ Q : What are the country codes for countries that do not speak English Pred: SELECT countrycode FROM country WHERE language > 'english' Gold: SELECT CountryCode FROM countrylanguage EXCEPT SELECT CountryCode FROM countrylanguage WHERE LANGUAGE = "English" Type: SIMPLE [481] WRONG_TABLE | DB: world_1 | EX: ✗ Q : Return the country codes for countries that do not speak English Pred: SELECT countrycode FROM country WHERE language > 'english' Gold: SELECT CountryCode FROM countrylanguage EXCEPT SELECT CountryCode FROM countrylanguage WHERE LANGUAGE = "English" Type: SIMPLE [482] WRONG_TABLE | DB: world_1 | EX: ✗ Q : What are the country codes of countries where people use languages other than English Pred: SELECT countrycode FROM country WHERE language > 'english' Gold: SELECT DISTINCT CountryCode FROM countrylanguage WHERE LANGUAGE <> "English" Type: SIMPLE [483] WRONG_COLUMNS | DB: world_1 | EX: ✗ Q : Give the country codes for countries in which people speak langauges that are not English Pred: SELECT countrycode FROM countrylanguage WHERE language > 'english' Gold: SELECT DISTINCT CountryCode FROM countrylanguage WHERE LANGUAGE <> "English" Type: SIMPLE [484] WRONG_TABLE | DB: world_1 | EX: ✗ Q : What are the codes of the countries that do not speak English and whose government forms are not Republic Pred: SELECT countrycode FROM country WHERE language > 'english' AND governmentform > 'Republic' Gold: SELECT Code FROM country WHERE GovernmentForm <> "Republic" EXCEPT SELECT CountryCode FROM countrylanguage WHERE LANGUAGE = "English" Type: SIMPLE [485] WRONG_TABLE | DB: world_1 | EX: ✗ Q : Return the codes of countries that do not speak English and do not have Republics for governments Pred: SELECT countrycode FROM country WHERE language > 'english' EXCEPT SELECT countrycode FROM country WHERE governmentform = 'Republic' Gold: SELECT Code FROM country WHERE GovernmentForm <> "Republic" EXCEPT SELECT CountryCode FROM countrylanguage WHERE LANGUAGE = "English" Type: SIMPLE [486] WRONG_TABLE | DB: world_1 | EX: ✗ Q : Which cities are in European countries where English is not the official language Pred: SELECT T1.name FROM city AS T1 JOIN country AS T2 ON T1.countrycode = T2.code WHERE T2.language = 'European' EXCEPT SELECT T1.name FROM city AS T1 JOIN countrylanguage AS T2 ON T1.countrycode = T2.countrycode WHERE T2.language = 'english' Gold: SELECT DISTINCT T2.Name FROM country AS T1 JOIN city AS T2 ON T2.CountryCode = T1.Code WHERE T1.Continent = 'Europe' AND NOT T1.Name IN (SELECT T3.Name FROM country AS T3 JOIN countrylanguage AS T4 ON T3.Code = T4.CountryCode WHERE T4.IsOfficial = 'T' AND T4.Language = 'English') Type: JOIN, NESTED [487] WRONG_TABLE | DB: world_1 | EX: ✗ Q : What are the names of cities in Europe for which English is not the official language Pred: SELECT DISTINCT T1.localname FROM city AS T1 JOIN country AS T2 ON T1.countrycode = T2.code WHERE T2.name = 'Europe' AND T2.language > 'english' Gold: SELECT DISTINCT T2.Name FROM country AS T1 JOIN city AS T2 ON T2.CountryCode = T1.Code WHERE T1.Continent = 'Europe' AND NOT T1.Name IN (SELECT T3.Name FROM country AS T3 JOIN countrylanguage AS T4 ON T3.Code = T4.CountryCode WHERE T4.IsOfficial = 'T' AND T4.Language = 'English') Type: JOIN, NESTED [488] WRONG_TABLE | DB: world_1 | EX: ✗ Q : Which unique cities are in Asian countries where Chinese is the official language Pred: SELECT DISTINCT T1.name FROM city AS T1 JOIN country AS T2 ON T1.countrycode = T2.code JOIN countrylanguage AS T3 ON T2.countrycode = T3.countrycode WHERE T3.language = 'Chinese' Gold: SELECT DISTINCT t3.name FROM country AS t1 JOIN countrylanguage AS t2 ON t1.code = t2.countrycode JOIN city AS t3 ON t1.code = t3.countrycode WHERE t2.isofficial = 't' AND t2.language = 'chinese' AND t1.continent = "asia" Type: JOIN [489] WRONG_TABLE | DB: world_1 | EX: ✗ Q : Return the different names of cities that are in Asia and for which Chinese is the official language Pred: SELECT DISTINCT T1.localname FROM city AS T1 JOIN country AS T2 ON T1.countrycode = T2.code WHERE T2.region = "Asia" AND T2.language = "Chinese" Gold: SELECT DISTINCT T3.Name FROM country AS T1 JOIN countrylanguage AS T2 ON T1.Code = T2.CountryCode JOIN city AS T3 ON T1.Code = T3.CountryCode WHERE T2.IsOfficial = 'T' AND T2.Language = 'Chinese' AND T1.Continent = "Asia" Type: JOIN [490] WRONG_COLUMNS | DB: world_1 | EX: ✗ Q : What are the name, independence year, and surface area of the country with the smallest population Pred: SELECT name, indepyear, surfacearea FROM country ORDER BY population ASC LIMIT 1 Gold: SELECT Name, SurfaceArea, IndepYear FROM country ORDER BY Population LIMIT 1 Type: ORDER_BY, LIMIT [491] WRONG_COLUMNS | DB: world_1 | EX: ✗ Q : Give the name, year of independence, and surface area of the country that has the lowest population Pred: SELECT name, indepyear, surfacearea FROM country ORDER BY population LIMIT 1 Gold: SELECT Name, SurfaceArea, IndepYear FROM country ORDER BY Population LIMIT 1 Type: ORDER_BY, LIMIT [492] WRONG_COLUMNS | DB: world_1 | EX: ✗ Q : What are the population, name and leader of the country with the largest area Pred: SELECT population, name, headofstate FROM country ORDER BY surfacearea DESC LIMIT 1 Gold: SELECT Name, population, HeadOfState FROM country ORDER BY SurfaceArea DESC LIMIT 1 Type: ORDER_BY, LIMIT [493] WRONG_COLUMNS | DB: world_1 | EX: ✗ Q : Return the country name and the numbers of languages spoken for each country that speaks at least 3 languages Pred: SELECT T1.name, COUNT(*), T1.countrycode FROM country AS T1 JOIN countrylanguage AS T2 ON T1.countrycode = T2.code GROUP BY T1.countrycode HAVING COUNT(*) >= 3 Gold: SELECT COUNT(T2.Language), T1.Name FROM country AS T1 JOIN countrylanguage AS T2 ON T1.Code = T2.CountryCode GROUP BY T1.Name HAVING COUNT(*) > 2 Type: JOIN, GROUP_BY, HAVING, AGGREGATION [494] WRONG_COLUMNS | DB: world_1 | EX: ✗ Q : What are the names of countries that speak more than 2 languages, as well as how many languages they speak Pred: SELECT T1.name, COUNT(*) FROM country AS T1 JOIN countrylanguage AS T2 ON T1.countrycode = T2.code GROUP BY T1.countrycode HAVING COUNT(*) > 2 Gold: SELECT COUNT(T2.Language), T1.Name FROM country AS T1 JOIN countrylanguage AS T2 ON T1.Code = T2.CountryCode GROUP BY T1.Name HAVING COUNT(*) > 2 Type: JOIN, GROUP_BY, HAVING, AGGREGATION [495] MISSING_GROUP_BY | DB: world_1 | EX: ✗ Q : Find the number of cities in each district whose population is greater than the average population of cities Pred: SELECT COUNT(*), district FROM city WHERE population > (SELECT AVG(population) FROM city) Gold: SELECT COUNT(*), District FROM city WHERE Population > (SELECT AVG(Population) FROM city) GROUP BY District Type: GROUP_BY, NESTED, AGGREGATION [496] MISSING_GROUP_BY | DB: world_1 | EX: ✗ Q : How many cities in each district have a population that is above the average population across all cities Pred: SELECT COUNT(*), district FROM city WHERE population > (SELECT AVG(population) FROM city) Gold: SELECT COUNT(*), District FROM city WHERE Population > (SELECT AVG(Population) FROM city) GROUP BY District Type: GROUP_BY, NESTED, AGGREGATION [497] WRONG_COLUMNS | DB: world_1 | EX: ✗ Q : Find the government form name and total population for each government form whose average life expectancy is longer than 72 Pred: SELECT governmentform, SUM(population) FROM country WHERE lifeexpectancy > 72 GROUP BY governmentform Gold: SELECT SUM(Population), GovernmentForm FROM country GROUP BY GovernmentForm HAVING AVG(LifeExpectancy) > 72 Type: GROUP_BY, HAVING, AGGREGATION [498] WRONG_COLUMNS | DB: world_1 | EX: ✗ Q : What are the different government forms and what is the total population of each for government forms that have an average life expectancy greater than 72 Pred: SELECT governmentform, SUM(population) FROM country WHERE lifeexpectancy > 72 GROUP BY governmentform Gold: SELECT SUM(Population), GovernmentForm FROM country GROUP BY GovernmentForm HAVING AVG(LifeExpectancy) > 72 Type: GROUP_BY, HAVING, AGGREGATION [499] WRONG_COLUMNS | DB: world_1 | EX: ✗ Q : Find the average life expectancy and total population for each continent where the average life expectancy is shorter than 72 Pred: SELECT AVG(lifeexpectancy), SUM(population) FROM country WHERE lifeexpectancy 72 GROUP BY continent Gold: SELECT SUM(Population), AVG(LifeExpectancy), Continent FROM country GROUP BY Continent HAVING AVG(LifeExpectancy) < 72 Type: GROUP_BY, HAVING, AGGREGATION [500] WRONG_COLUMNS | DB: world_1 | EX: ✗ Q : What are the different continents and the total popuation and average life expectancy corresponding to each, for continents that have an average life expectancy less than 72 Pred: SELECT continent, AVG(lifeexpectancy), SUM(population) FROM country GROUP BY continent HAVING AVG(lifeexpectancy) 72 Gold: SELECT SUM(Population), AVG(LifeExpectancy), Continent FROM country GROUP BY Continent HAVING AVG(LifeExpectancy) < 72 Type: GROUP_BY, HAVING, AGGREGATION [501] WRONG_COLUMNS | DB: world_1 | EX: ✗ Q : What are the names and areas of countries with the top 5 largest area Pred: SELECT name, area FROM country ORDER BY surfacearea DESC LIMIT 5 Gold: SELECT Name, SurfaceArea FROM country ORDER BY SurfaceArea DESC LIMIT 5 Type: ORDER_BY, LIMIT [502] OTHER | DB: world_1 | EX: ✗ Q : Return the names and surface areas of the 5 largest countries Pred: SELECT name, surfacearea FROM country ORDER BY population DESC LIMIT 5 Gold: SELECT Name, SurfaceArea FROM country ORDER BY SurfaceArea DESC LIMIT 5 Type: ORDER_BY, LIMIT [503] OTHER | DB: world_1 | EX: ✗ Q : how many countries are in Asia Pred: SELECT COUNT(*) FROM country WHERE region = 'Asia' Gold: SELECT COUNT(*) FROM country WHERE continent = "Asia" Type: AGGREGATION [504] OTHER | DB: world_1 | EX: ✗ Q : Count the number of countries in Asia Pred: SELECT COUNT(*) FROM country WHERE region = 'Asie' Gold: SELECT COUNT(*) FROM country WHERE continent = "Asia" Type: AGGREGATION [505] OTHER | DB: world_1 | EX: ✓ Q : What are the names of the countries that are in the continent of Europe and have a population of 80000 Pred: SELECT name FROM country WHERE continent = 'Europe' AND population = 80000 Gold: SELECT Name FROM country WHERE continent = "Europe" AND Population = "80000" Type: SIMPLE [506] OTHER | DB: world_1 | EX: ✓ Q : Give the names of countries that are in Europe and have a population equal to 80000 Pred: SELECT name FROM country WHERE continent = 'Europe' AND population = 80000 Gold: SELECT Name FROM country WHERE continent = "Europe" AND Population = "80000" Type: SIMPLE [507] OTHER | DB: world_1 | EX: ✗ Q : Give the total population and average surface area corresponding to countries in North America that have a surface area greater than 3000 Pred: SELECT SUM(population), AVG(surfacearea) FROM country WHERE region = 'North America' AND surfacearea > 3000 Gold: SELECT SUM(population), AVG(surfacearea) FROM country WHERE continent = "north america" AND surfacearea > 3000 Type: AGGREGATION [508] WRONG_TABLE | DB: world_1 | EX: ✗ Q : What is the language spoken by the largest percentage of people in each country Pred: SELECT countrylanguage, MAX(Percentage) FROM country AS T1 JOIN countryAS T2 ON T1.countrycode = T2.code GROUP BY countrycode Gold: SELECT LANGUAGE, CountryCode, MAX(Percentage) FROM countrylanguage GROUP BY CountryCode Type: GROUP_BY, AGGREGATION [509] WRONG_TABLE | DB: world_1 | EX: ✗ Q : What are the country codes of the different countries, and what are the languages spoken by the greatest percentage of people for each Pred: SELECT countrycode, T1.language, MAX(T1.population) FROM country AS T1 JOIN countrylanguage AS T2 ON T1.countrycode = T2.code GROUP BY T1.countrycode Gold: SELECT LANGUAGE, CountryCode, MAX(Percentage) FROM countrylanguage GROUP BY CountryCode Type: GROUP_BY, AGGREGATION [510] WRONG_TABLE | DB: world_1 | EX: ✗ Q : What is the total number of countries where Spanish is spoken by the largest percentage of people Pred: SELECT COUNT(*) FROM country AS T1 JOIN countrylanguage AS T2 ON T1.countrycode = T2.code WHERE T2.language = 'Spanish' ORDER BY percentage DESC LIMIT 1 Gold: SELECT COUNT(*), MAX(Percentage) FROM countrylanguage WHERE LANGUAGE = "Spanish" GROUP BY CountryCode Type: GROUP_BY, AGGREGATION [511] WRONG_TABLE | DB: world_1 | EX: ✗ Q : Count the number of countries for which Spanish is the predominantly spoken language Pred: SELECT COUNT(*) FROM country WHERE language = 'Spanish' Gold: SELECT COUNT(*), MAX(Percentage) FROM countrylanguage WHERE LANGUAGE = "Spanish" GROUP BY CountryCode Type: GROUP_BY, AGGREGATION [512] WRONG_TABLE | DB: world_1 | EX: ✗ Q : What are the codes of countries where Spanish is spoken by the largest percentage of people Pred: SELECT T1.countrycode FROM country AS T1 JOIN countrylanguage AS T2 ON T1.countrycode = T2.code WHERE T2.language = 'Spanish' ORDER BY T1.population DESC LIMIT 1 Gold: SELECT CountryCode, MAX(Percentage) FROM countrylanguage WHERE LANGUAGE = "Spanish" GROUP BY CountryCode Type: GROUP_BY, AGGREGATION [513] WRONG_TABLE | DB: world_1 | EX: ✗ Q : Return the codes of countries for which Spanish is the predominantly spoken language Pred: SELECT T1.countrycode FROM country AS T1 JOIN countrylanguage AS T2 ON T1.countrycode = T2.code WHERE T2.language = 'Spanish' Gold: SELECT CountryCode, MAX(Percentage) FROM countrylanguage WHERE LANGUAGE = "Spanish" GROUP BY CountryCode Type: GROUP_BY, AGGREGATION [514] OTHER | DB: orchestra | EX: ✓ Q : What are the names of conductors, ordered by age Pred: SELECT Name FROM conductor ORDER BY Age Gold: SELECT Name FROM conductor ORDER BY Age ASC Type: ORDER_BY [515] OTHER | DB: orchestra | EX: ✗ Q : What are the names of conductors whose nationalities are not "USA" Pred: SELECT Name FROM conductor WHERE Nationality > "USA" Gold: SELECT Name FROM conductor WHERE Nationality <> 'USA' Type: SIMPLE [516] OTHER | DB: orchestra | EX: ✗ Q : Return the names of conductors that do not have the nationality "USA" Pred: SELECT Name FROM conductor WHERE Nationality > "USA" Gold: SELECT Name FROM conductor WHERE Nationality <> 'USA' Type: SIMPLE [517] OTHER | DB: orchestra | EX: ✗ Q : What are the maximum and minimum share of performances whose type is not "Live final" Pred: SELECT MAX(Share), MIN(Share) FROM performance WHERE TYPE > "Live final" Gold: SELECT MAX(SHARE), MIN(SHARE) FROM performance WHERE TYPE <> "Live final" Type: AGGREGATION [518] WRONG_TABLE | DB: orchestra | EX: ✓ Q : Return the maximum and minimum shares for performances that do not have the type "Live final" Pred: SELECT MAX(Share), MIN(Share) FROM performance WHERE NOT Performance_ID IN (SELECT Performance_ID FROM show WHERE Type > "Live final") Gold: SELECT MAX(SHARE), MIN(SHARE) FROM performance WHERE TYPE <> "Live final" Type: AGGREGATION [519] WRONG_TABLE | DB: orchestra | EX: ✗ Q : What is the name of the conductor who has worked the greatest number of years Pred: SELECT T2.name FROM orchestra AS T1 JOIN conductor AS T2 ON T1.conductor_id = T2.conductor_id GROUP BY T2.conductor_id ORDER BY COUNT(*) DESC LIMIT 1 Gold: SELECT Name FROM conductor ORDER BY Year_of_Work DESC LIMIT 1 Type: ORDER_BY, LIMIT [520] WRONG_TABLE | DB: orchestra | EX: ✗ Q : Show the names of conductors and the orchestras they have conducted Pred: SELECT T3.Name, T2.Orchestra FROM performance AS T1 JOIN orchestra AS T2 ON T1.Orchestra_ID = T2.Orchestra_ID JOIN conductor AS T3 ON T1.Conductor_ID = T3.Conductor_ID Gold: SELECT T1.Name, T2.Orchestra FROM conductor AS T1 JOIN orchestra AS T2 ON T1.Conductor_ID = T2.Conductor_ID Type: JOIN [521] WRONG_TABLE | DB: orchestra | EX: ✗ Q : What are the names of conductors as well as the corresonding orchestras that they have conducted Pred: SELECT T3.Name, T2.Orchestra FROM performance AS T1 JOIN orchestra AS T2 ON T1.Orchestra_ID = T2.Orchestra_ID JOIN conductor AS T3 ON T1.Conductor_ID = T3.Conductor_ID Gold: SELECT T1.Name, T2.Orchestra FROM conductor AS T1 JOIN orchestra AS T2 ON T1.Conductor_ID = T2.Conductor_ID Type: JOIN [522] OTHER | DB: orchestra | EX: ✓ Q : Show the names of conductors that have conducted more than one orchestras Pred: SELECT T1.name FROM conductor AS T1 JOIN orchestra AS T2 ON T1.conductor_id = T2.conductor_id GROUP BY T1.conductor_id HAVING COUNT(*) > 1 Gold: SELECT T1.Name FROM conductor AS T1 JOIN orchestra AS T2 ON T1.Conductor_ID = T2.Conductor_ID GROUP BY T2.Conductor_ID HAVING COUNT(*) > 1 Type: JOIN, GROUP_BY, HAVING, AGGREGATION [523] OTHER | DB: orchestra | EX: ✓ Q : What are the names of conductors who have conducted at more than one orchestra Pred: SELECT T1.name FROM conductor AS T1 JOIN orchestra AS T2 ON T1.conductor_id = T2.conductor_id GROUP BY T1.conductor_id HAVING COUNT(*) > 1 Gold: SELECT T1.Name FROM conductor AS T1 JOIN orchestra AS T2 ON T1.Conductor_ID = T2.Conductor_ID GROUP BY T2.Conductor_ID HAVING COUNT(*) > 1 Type: JOIN, GROUP_BY, HAVING, AGGREGATION [524] WRONG_TABLE | DB: orchestra | EX: ✗ Q : Show the name of the conductor that has conducted the most number of orchestras Pred: SELECT T2.name FROM performance AS T1 JOIN conductor AS T2 ON T1.conductor_id = T2.conductor_id GROUP BY T2.conductor_id ORDER BY COUNT(*) DESC LIMIT 1 Gold: SELECT T1.Name FROM conductor AS T1 JOIN orchestra AS T2 ON T1.Conductor_ID = T2.Conductor_ID GROUP BY T2.Conductor_ID ORDER BY COUNT(*) DESC LIMIT 1 Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, AGGREGATION [525] WRONG_TABLE | DB: orchestra | EX: ✓ Q : What is the name of the conductor who has conducted the most orchestras Pred: SELECT T2.name FROM orchestra AS T1 JOIN conductor AS T2 ON T1.conductor_id = T2.conductor_id GROUP BY T2.conductor_id ORDER BY COUNT(*) DESC LIMIT 1 Gold: SELECT T1.Name FROM conductor AS T1 JOIN orchestra AS T2 ON T1.Conductor_ID = T2.Conductor_ID GROUP BY T2.Conductor_ID ORDER BY COUNT(*) DESC LIMIT 1 Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, AGGREGATION [526] WRONG_TABLE | DB: orchestra | EX: ✓ Q : Please show the name of the conductor that has conducted orchestras founded after 2008 Pred: SELECT T2.name FROM orchestra AS T1 JOIN conductor AS T2 ON T1.conductor_id = T2.conductor_id WHERE T1.year_of_founded > 2008 Gold: SELECT T1.Name FROM conductor AS T1 JOIN orchestra AS T2 ON T1.Conductor_ID = T2.Conductor_ID WHERE Year_of_Founded > 2008 Type: JOIN [527] WRONG_TABLE | DB: orchestra | EX: ✓ Q : What are the names of conductors who have conducted orchestras founded after the year 2008 Pred: SELECT T2.name FROM orchestra AS T1 JOIN conductor AS T2 ON T1.conductor_id = T2.conductor_id WHERE T1.year_of_founded > 2008 Gold: SELECT T1.Name FROM conductor AS T1 JOIN orchestra AS T2 ON T1.Conductor_ID = T2.Conductor_ID WHERE Year_of_Founded > 2008 Type: JOIN [528] WRONG_COLUMNS | DB: orchestra | EX: ✗ Q : How many orchestras does each record company manage Pred: SELECT COUNT(*), record_company FROM orchestra GROUP BY record_company Gold: SELECT Record_Company, COUNT(*) FROM orchestra GROUP BY Record_Company Type: GROUP_BY, AGGREGATION [529] MISSING_GROUP_BY | DB: orchestra | EX: ✗ Q : Please show the record formats of orchestras in ascending order of count Pred: SELECT Major_Record_Format FROM orchestra ORDER BY COUNT(*) ASC Gold: SELECT Major_Record_Format FROM orchestra GROUP BY Major_Record_Format ORDER BY COUNT(*) ASC Type: GROUP_BY, ORDER_BY, AGGREGATION [530] MISSING_GROUP_BY | DB: orchestra | EX: ✗ Q : What are the major record formats of orchestras, sorted by their frequency Pred: SELECT Major_Record_format FROM orchestra ORDER BY Major_Record_format Gold: SELECT Major_Record_Format FROM orchestra GROUP BY Major_Record_Format ORDER BY COUNT(*) ASC Type: GROUP_BY, ORDER_BY, AGGREGATION [531] WRONG_COLUMNS | DB: orchestra | EX: ✗ Q : List the names of orchestras that have no performance Pred: SELECT Name FROM orchestra WHERE NOT Orchestra_ID IN (SELECT Orchestra_ID FROM performance) Gold: SELECT Orchestra FROM orchestra WHERE NOT Orchestra_ID IN (SELECT Orchestra_ID FROM performance) Type: NESTED [532] OTHER | DB: orchestra | EX: ✗ Q : Show the record companies shared by orchestras founded before 2003 and after 2003 Pred: SELECT Record_Company FROM orchestra WHERE YEAR_of_founded 2003 INTERSECT SELECT Record_Company FROM orchestra WHERE YEAR_of_founded > 2003 Gold: SELECT Record_Company FROM orchestra WHERE Year_of_Founded < 2003 INTERSECT SELECT Record_Company FROM orchestra WHERE Year_of_Founded > 2003 Type: SIMPLE [533] OTHER | DB: orchestra | EX: ✗ Q : What are the record companies that are used by both orchestras founded before 2003 and those founded after 2003 Pred: SELECT record_company FROM orchestra WHERE YEAR_of_founded 2003 INTERSECT SELECT record_company FROM orchestra WHERE YEAR_of_founded > 2003 Gold: SELECT Record_Company FROM orchestra WHERE Year_of_Founded < 2003 INTERSECT SELECT Record_Company FROM orchestra WHERE Year_of_Founded > 2003 Type: SIMPLE [534] WRONG_COLUMNS | DB: orchestra | EX: ✓ Q : Show the years in which orchestras that have given more than one performance are founded Pred: SELECT T1.Year_of_founded FROM orchestra AS T1 JOIN performance AS T2 ON T1.Orchestra_ID = T2.Orchestra_ID GROUP BY T1.Orchestra_ID HAVING COUNT(*) > 1 Gold: SELECT Year_of_Founded FROM orchestra AS T1 JOIN performance AS T2 ON T1.Orchestra_ID = T2.Orchestra_ID GROUP BY T2.Orchestra_ID HAVING COUNT(*) > 1 Type: JOIN, GROUP_BY, HAVING, AGGREGATION [535] MISSING_JOIN | DB: orchestra | EX: ✗ Q : What are years of founding for orchestras that have had more than a single performance Pred: SELECT YEAR_of_founded FROM orchestra GROUP BY YEAR_of_founded HAVING COUNT(*) > 1 Gold: SELECT Year_of_Founded FROM orchestra AS T1 JOIN performance AS T2 ON T1.Orchestra_ID = T2.Orchestra_ID GROUP BY T2.Orchestra_ID HAVING COUNT(*) > 1 Type: JOIN, GROUP_BY, HAVING, AGGREGATION [536] WRONG_COLUMNS | DB: network_1 | EX: ✗ Q : What grade is Kyle in Pred: SELECT grading FROM highschooler WHERE name = 'Kyle' Gold: SELECT grade FROM Highschooler WHERE name = "Kyle" Type: SIMPLE [537] WRONG_COLUMNS | DB: network_1 | EX: ✗ Q : What is Kyle's id Pred: SELECT student_id FROM highschooler WHERE name = 'Kyle' Gold: SELECT ID FROM Highschooler WHERE name = "Kyle" Type: SIMPLE [538] EXTRA_JOIN | DB: network_1 | EX: ✗ Q : How many friends does each student have Pred: SELECT COUNT(*) FROM friend AS T1 JOIN student AS T2 ON T1.student_id = T2.id GROUP BY T2.student_id Gold: SELECT student_id, COUNT(*) FROM Friend GROUP BY student_id Type: GROUP_BY, AGGREGATION [539] WRONG_TABLE | DB: network_1 | EX: ✗ Q : Show the names of high school students and their corresponding number of friends Pred: SELECT T2.name, COUNT(*) FROM highschooler AS T1 JOIN friend AS T2 ON T1.id = T2.friend_id JOIN student AS T3 ON T1.student_id = T3.id GROUP BY T3.student_id Gold: SELECT T2.name, COUNT(*) FROM Friend AS T1 JOIN Highschooler AS T2 ON T1.student_id = T2.id GROUP BY T1.student_id Type: JOIN, GROUP_BY, AGGREGATION [540] WRONG_TABLE | DB: network_1 | EX: ✗ Q : What are the names of the high schoolers and how many friends does each have Pred: SELECT COUNT(*), T1.name FROM highschooler AS T1 JOIN friend AS T2 ON T1.id = T2.friend_id GROUP BY T1.id Gold: SELECT T2.name, COUNT(*) FROM Friend AS T1 JOIN Highschooler AS T2 ON T1.student_id = T2.id GROUP BY T1.student_id Type: JOIN, GROUP_BY, AGGREGATION [541] WRONG_TABLE | DB: network_1 | EX: ✗ Q : What is the name of the high schooler who has the greatest number of friends Pred: SELECT T1.name FROM highschooler AS T1 JOIN friend AS T2 ON T1.id = T2.friend_id GROUP BY T1.id ORDER BY COUNT(*) DESC LIMIT 1 Gold: SELECT T2.name FROM Friend AS T1 JOIN Highschooler AS T2 ON T1.student_id = T2.id GROUP BY T1.student_id ORDER BY COUNT(*) DESC LIMIT 1 Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, AGGREGATION [542] WRONG_TABLE | DB: network_1 | EX: ✗ Q : Return the name of the high school student with the most friends Pred: SELECT T1.name FROM highschooler AS T1 JOIN friend AS T2 ON T1.id = T2.friend_id GROUP BY T2.friend_id ORDER BY COUNT(*) DESC LIMIT 1 Gold: SELECT T2.name FROM Friend AS T1 JOIN Highschooler AS T2 ON T1.student_id = T2.id GROUP BY T1.student_id ORDER BY COUNT(*) DESC LIMIT 1 Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, AGGREGATION [543] WRONG_TABLE | DB: network_1 | EX: ✗ Q : Show the names of high schoolers who have at least 3 friends Pred: SELECT T1.name FROM highschooler AS T1 JOIN friend AS T2 ON T1.id = T2.friend_id GROUP BY T2.friend_id HAVING COUNT(*) >= 3 Gold: SELECT T2.name FROM Friend AS T1 JOIN Highschooler AS T2 ON T1.student_id = T2.id GROUP BY T1.student_id HAVING COUNT(*) >= 3 Type: JOIN, GROUP_BY, HAVING, AGGREGATION [544] WRONG_TABLE | DB: network_1 | EX: ✗ Q : What are the names of high schoolers who have 3 or more friends Pred: SELECT T1.name FROM highschooler AS T1 JOIN friend AS T2 ON T1.id = T2.friend_id GROUP BY T2.friend_id HAVING COUNT(*) >= 3 Gold: SELECT T2.name FROM Friend AS T1 JOIN Highschooler AS T2 ON T1.student_id = T2.id GROUP BY T1.student_id HAVING COUNT(*) >= 3 Type: JOIN, GROUP_BY, HAVING, AGGREGATION [545] WRONG_TABLE | DB: network_1 | EX: ✗ Q : Show the names of all of the high schooler Kyle's friends Pred: SELECT T3.name FROM highschooler AS T1 JOIN friend AS T2 ON T1.id = T2.friend_id JOIN likes AS T3 ON T2.liked_id = T3.id JOIN student AS T4 ON T3.student_id = T4.id WHERE T1.name = 'Kyle' Gold: SELECT T3.name FROM Friend AS T1 JOIN Highschooler AS T2 ON T1.student_id = T2.id JOIN Highschooler AS T3 ON T1.friend_id = T3.id WHERE T2.name = "Kyle" Type: JOIN [546] WRONG_TABLE | DB: network_1 | EX: ✗ Q : Return the names of friends of the high school student Kyle Pred: SELECT T2.name FROM highschooler AS T1 JOIN friend AS T2 ON T1.id = T2.friend_id WHERE T1.id = "Kyle" Gold: SELECT T3.name FROM Friend AS T1 JOIN Highschooler AS T2 ON T1.student_id = T2.id JOIN Highschooler AS T3 ON T1.friend_id = T3.id WHERE T2.name = "Kyle" Type: JOIN [547] OTHER | DB: network_1 | EX: ✗ Q : How many friends does the high school student Kyle have Pred: SELECT COUNT(*) FROM friend AS T1 JOIN student AS T2 ON T1.student_id = T2.id WHERE T2.name = "Kyle" Gold: SELECT COUNT(*) FROM Friend AS T1 JOIN Highschooler AS T2 ON T1.student_id = T2.id WHERE T2.name = "Kyle" Type: JOIN, AGGREGATION [548] MISSING_JOIN | DB: network_1 | EX: ✗ Q : Count the number of friends Kyle has Pred: SELECT COUNT(*) FROM friend WHERE name = 'Kyle' Gold: SELECT COUNT(*) FROM Friend AS T1 JOIN Highschooler AS T2 ON T1.student_id = T2.id WHERE T2.name = "Kyle" Type: JOIN, AGGREGATION [549] WRONG_COLUMNS | DB: network_1 | EX: ✗ Q : Show ids of all students who do not have any friends Pred: SELECT student_id FROM friend EXCEPT SELECT student_id FROM highschooler Gold: SELECT id FROM Highschooler EXCEPT SELECT student_id FROM Friend Type: SIMPLE [550] WRONG_COLUMNS | DB: network_1 | EX: ✗ Q : What are the ids of high school students who do not have friends Pred: SELECT student_id FROM friend EXCEPT SELECT student_id FROM highschooler Gold: SELECT id FROM Highschooler EXCEPT SELECT student_id FROM Friend Type: SIMPLE [551] MISSING_JOIN | DB: network_1 | EX: ✗ Q : Show names of all high school students who do not have any friends Pred: SELECT name FROM highschooler WHERE NOT student_id IN (SELECT student_id FROM friend) Gold: SELECT name FROM Highschooler EXCEPT SELECT T2.name FROM Friend AS T1 JOIN Highschooler AS T2 ON T1.student_id = T2.id Type: JOIN [552] WRONG_TABLE | DB: network_1 | EX: ✗ Q : What are the names of students who have no friends Pred: SELECT name FROM student WHERE NOT student_id IN (SELECT student_id FROM friend) Gold: SELECT name FROM Highschooler EXCEPT SELECT T2.name FROM Friend AS T1 JOIN Highschooler AS T2 ON T1.student_id = T2.id Type: JOIN [553] WRONG_TABLE | DB: network_1 | EX: ✓ Q : Show the ids of high schoolers who have friends and are also liked by someone else Pred: SELECT T1.id FROM highschooler AS T1 JOIN friend AS T2 ON T1.id = T2.friend_id INTERSECT SELECT T1.id FROM highschooler AS T1 JOIN likes AS T2 ON T1.id = T2.liked_id Gold: SELECT student_id FROM Friend INTERSECT SELECT liked_id FROM Likes Type: SIMPLE [554] WRONG_TABLE | DB: network_1 | EX: ✗ Q : What are the ids of students who both have friends and are liked Pred: SELECT T1.id FROM student AS T1 JOIN friend AS T2 ON T1.id = T2.friend_id INTERSECT SELECT T1.id FROM student AS T1 JOIN likes AS T2 ON T1.id = T2.liked_id Gold: SELECT student_id FROM Friend INTERSECT SELECT liked_id FROM Likes Type: SIMPLE [555] WRONG_TABLE | DB: network_1 | EX: ✗ Q : Show name of all students who have some friends and also are liked by someone else Pred: SELECT T1.name FROM highschooler AS T1 JOIN friend AS T2 ON T1.id = T2.friend_id JOIN likes AS T3 ON T2.liked_id = T3.id Gold: SELECT T2.name FROM Friend AS T1 JOIN Highschooler AS T2 ON T1.student_id = T2.id INTERSECT SELECT T2.name FROM Likes AS T1 JOIN Highschooler AS T2 ON T1.liked_id = T2.id Type: JOIN [556] WRONG_TABLE | DB: network_1 | EX: ✓ Q : What are the names of high schoolers who both have friends and are liked Pred: SELECT T1.name FROM highschooler AS T1 JOIN friend AS T2 ON T1.id = T2.friend_id INTERSECT SELECT T1.name FROM highschooler AS T1 JOIN likes AS T2 ON T1.id = T2.liked_id Gold: SELECT T2.name FROM Friend AS T1 JOIN Highschooler AS T2 ON T1.student_id = T2.id INTERSECT SELECT T2.name FROM Likes AS T1 JOIN Highschooler AS T2 ON T1.liked_id = T2.id Type: JOIN [557] WRONG_COLUMNS | DB: network_1 | EX: ✗ Q : Count the number of likes for each student id Pred: SELECT COUNT(*), student_id FROM likes GROUP BY student_id Gold: SELECT student_id, COUNT(*) FROM Likes GROUP BY student_id Type: GROUP_BY, AGGREGATION [558] WRONG_TABLE | DB: network_1 | EX: ✗ Q : Show the names of high schoolers who have likes, and numbers of likes for each Pred: SELECT T1.name, COUNT(*) FROM highschooler AS T1 JOIN likes AS T2 ON T1.id = T2.liked_id GROUP BY T1.id Gold: SELECT T2.name, COUNT(*) FROM Likes AS T1 JOIN Highschooler AS T2 ON T1.student_id = T2.id GROUP BY T1.student_id Type: JOIN, GROUP_BY, AGGREGATION [559] WRONG_TABLE | DB: network_1 | EX: ✗ Q : What are the names of high schoolers who have likes, and how many likes does each have Pred: SELECT T1.name, COUNT(*) FROM highschooler AS T1 JOIN likes AS T2 ON T1.id = T2.liked_id GROUP BY T1.id Gold: SELECT T2.name, COUNT(*) FROM Likes AS T1 JOIN Highschooler AS T2 ON T1.student_id = T2.id GROUP BY T1.student_id Type: JOIN, GROUP_BY, AGGREGATION [560] WRONG_TABLE | DB: network_1 | EX: ✗ Q : What is the name of the high schooler who has the greatest number of likes Pred: SELECT T1.name FROM highschooler AS T1 JOIN likes AS T2 ON T1.id = T2.liked_id GROUP BY T1.id ORDER BY COUNT(*) DESC LIMIT 1 Gold: SELECT T2.name FROM Likes AS T1 JOIN Highschooler AS T2 ON T1.student_id = T2.id GROUP BY T1.student_id ORDER BY COUNT(*) DESC LIMIT 1 Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, AGGREGATION [561] OTHER | DB: network_1 | EX: ✗ Q : Give the name of the student with the most likes Pred: SELECT T2.name FROM likes AS T1 JOIN student AS T2 ON T1.student_id = T2.id GROUP BY T1.student_id ORDER BY COUNT(*) DESC LIMIT 1 Gold: SELECT T2.name FROM Likes AS T1 JOIN Highschooler AS T2 ON T1.student_id = T2.id GROUP BY T1.student_id ORDER BY COUNT(*) DESC LIMIT 1 Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, AGGREGATION [562] OTHER | DB: network_1 | EX: ✗ Q : Show the names of students who have at least 2 likes Pred: SELECT T2.name FROM likes AS T1 JOIN student AS T2 ON T1.student_id = T2.id GROUP BY T2.student_id HAVING COUNT(*) >= 2 Gold: SELECT T2.name FROM Likes AS T1 JOIN Highschooler AS T2 ON T1.student_id = T2.id GROUP BY T1.student_id HAVING COUNT(*) >= 2 Type: JOIN, GROUP_BY, HAVING, AGGREGATION [563] OTHER | DB: network_1 | EX: ✗ Q : What are the names of students who have 2 or more likes Pred: SELECT T2.name FROM likes AS T1 JOIN student AS T2 ON T1.student_id = T2.id GROUP BY T2.student_id HAVING COUNT(*) >= 2 Gold: SELECT T2.name FROM Likes AS T1 JOIN Highschooler AS T2 ON T1.student_id = T2.id GROUP BY T1.student_id HAVING COUNT(*) >= 2 Type: JOIN, GROUP_BY, HAVING, AGGREGATION [564] WRONG_TABLE | DB: network_1 | EX: ✗ Q : Show the names of students who have a grade higher than 5 and have at least 2 friends Pred: SELECT T2.name FROM highschooler AS T1 JOIN friend AS T2 ON T1.id = T2.friend_id JOIN student AS T3 ON T1.id = T3.student_id WHERE T1.grade > 5 GROUP BY T3.id HAVING COUNT(*) >= 2 Gold: SELECT T2.name FROM Friend AS T1 JOIN Highschooler AS T2 ON T1.student_id = T2.id WHERE T2.grade > 5 GROUP BY T1.student_id HAVING COUNT(*) >= 2 Type: JOIN, GROUP_BY, HAVING, AGGREGATION [565] WRONG_TABLE | DB: network_1 | EX: ✗ Q : What are the names of high schoolers who have a grade of over 5 and have 2 or more friends Pred: SELECT T2.name FROM highschooler AS T1 JOIN friend AS T2 ON T1.id = T2.friend_id WHERE T1.grade > 5 GROUP BY T2.name HAVING COUNT(*) >= 2 Gold: SELECT T2.name FROM Friend AS T1 JOIN Highschooler AS T2 ON T1.student_id = T2.id WHERE T2.grade > 5 GROUP BY T1.student_id HAVING COUNT(*) >= 2 Type: JOIN, GROUP_BY, HAVING, AGGREGATION [566] OTHER | DB: network_1 | EX: ✗ Q : How many likes does Kyle have Pred: SELECT COUNT(*) FROM likes AS T1 JOIN student AS T2 ON T1.student_id = T2.id WHERE T2.name = "Kyle" Gold: SELECT COUNT(*) FROM Likes AS T1 JOIN Highschooler AS T2 ON T1.student_id = T2.id WHERE T2.name = "Kyle" Type: JOIN, AGGREGATION [567] OTHER | DB: network_1 | EX: ✗ Q : Return the number of likes that the high schooler named Kyle has Pred: SELECT COUNT(*) FROM likes AS T1 JOIN highschooler AS T2 ON T1.id = T2.highschooler_id WHERE T2.name = "Kyle" Gold: SELECT COUNT(*) FROM Likes AS T1 JOIN Highschooler AS T2 ON T1.student_id = T2.id WHERE T2.name = "Kyle" Type: JOIN, AGGREGATION [568] WRONG_TABLE | DB: network_1 | EX: ✗ Q : Find the average grade of all students who have some friends Pred: SELECT AVG(T2.grade) FROM highschooler AS T1 JOIN friend AS T2 ON T1.id = T2.friend_id Gold: SELECT AVG(grade) FROM Highschooler WHERE id IN (SELECT T1.student_id FROM Friend AS T1 JOIN Highschooler AS T2 ON T1.student_id = T2.id) Type: JOIN, NESTED, AGGREGATION [569] WRONG_TABLE | DB: network_1 | EX: ✗ Q : What is the average grade of students who have friends Pred: SELECT AVG(T2.grade) FROM highschooler AS T1 JOIN friend AS T2 ON T1.id = T2.friend_id Gold: SELECT AVG(grade) FROM Highschooler WHERE id IN (SELECT T1.student_id FROM Friend AS T1 JOIN Highschooler AS T2 ON T1.student_id = T2.id) Type: JOIN, NESTED, AGGREGATION [570] MISSING_JOIN | DB: network_1 | EX: ✗ Q : Find the minimum grade of students who have no friends Pred: SELECT MIN(grade) FROM highschooler WHERE NOT student_id IN (SELECT student_id FROM friend) Gold: SELECT MIN(grade) FROM Highschooler WHERE NOT id IN (SELECT T1.student_id FROM Friend AS T1 JOIN Highschooler AS T2 ON T1.student_id = T2.id) Type: JOIN, NESTED, AGGREGATION [571] WRONG_TABLE | DB: network_1 | EX: ✗ Q : What is the lowest grade of students who do not have any friends Pred: SELECT MIN(grade) FROM student WHERE NOT student_id IN (SELECT student_id FROM friend) Gold: SELECT MIN(grade) FROM Highschooler WHERE NOT id IN (SELECT T1.student_id FROM Friend AS T1 JOIN Highschooler AS T2 ON T1.student_id = T2.id) Type: JOIN, NESTED, AGGREGATION [572] OTHER | DB: dog_kennels | EX: ✓ Q : Which states have both owners and professionals living there Pred: SELECT state FROM professionals INTERSECT SELECT state FROM owners GROUP BY state Gold: SELECT state FROM Owners INTERSECT SELECT state FROM Professionals Type: SIMPLE [573] OTHER | DB: dog_kennels | EX: ✓ Q : Find the states where both owners and professionals live Pred: SELECT state FROM professionals INTERSECT SELECT state FROM owners Gold: SELECT state FROM Owners INTERSECT SELECT state FROM Professionals Type: SIMPLE [574] WRONG_TABLE | DB: dog_kennels | EX: ✗ Q : What is the average age of the dogs who have gone through any treatments Pred: SELECT AVG(T2.age) FROM treatments AS T1 JOIN dogs AS T2 ON T1.dog_id = T2.dog_id Gold: SELECT AVG(age) FROM Dogs WHERE dog_id IN (SELECT dog_id FROM Treatments) Type: NESTED, AGGREGATION [575] WRONG_TABLE | DB: dog_kennels | EX: ✗ Q : Find the average age of the dogs who went through treatments Pred: SELECT AVG(T2.age) FROM treatments AS T1 JOIN dogs AS T2 ON T1.dog_id = T2.dog_id Gold: SELECT AVG(age) FROM Dogs WHERE dog_id IN (SELECT dog_id FROM Treatments) Type: NESTED, AGGREGATION [576] WRONG_COLUMNS | DB: dog_kennels | EX: ✗ Q : Which professionals live in the state of Indiana or have done treatment on more than 2 treatments? List his or her id, last name and cell phone Pred: SELECT T1.professional_id, T1.last_name, T1.cell_number FROM professionals AS T1 JOIN treatments AS T2 ON T1.professional_id = T2.professional_id WHERE T1.state = "Indiana" GROUP BY T1.professional_id HAVING COUNT(*) > 2 Gold: SELECT professional_id, last_name, cell_number FROM Professionals WHERE state = 'Indiana' UNION SELECT T1.professional_id, T1.last_name, T1.cell_number FROM Professionals AS T1 JOIN Treatments AS T2 ON T1.professional_id = T2.professional_id GROUP BY T1.professional_id HAVING COUNT(*) > 2 Type: JOIN, GROUP_BY, HAVING, AGGREGATION [577] WRONG_COLUMNS | DB: dog_kennels | EX: ✗ Q : Find the id, last name and cell phone of the professionals who live in the state of Indiana or have performed more than two treatments Pred: SELECT T1.professional_id, T1.last_name, T1.cell_number FROM professionals AS T1 JOIN treatments AS T2 ON T1.professional_id = T2.professional_id WHERE T1.state = "Indiana" GROUP BY T1.professional_id HAVING COUNT(*) > 2 Gold: SELECT professional_id, last_name, cell_number FROM Professionals WHERE state = 'Indiana' UNION SELECT T1.professional_id, T1.last_name, T1.cell_number FROM Professionals AS T1 JOIN Treatments AS T2 ON T1.professional_id = T2.professional_id GROUP BY T1.professional_id HAVING COUNT(*) > 2 Type: JOIN, GROUP_BY, HAVING, AGGREGATION [578] WRONG_TABLE | DB: dog_kennels | EX: ✓ Q : Which dogs have not cost their owner more than 1000 for treatment ? List the dog names Pred: SELECT name FROM dogs EXCEPT SELECT T1.name FROM dogs AS T1 JOIN treatments AS T2 ON T1.dog_id = T2.dog_id GROUP BY T1.name HAVING SUM(T2.cost_of_treatment) > 1000 Gold: SELECT name FROM dogs WHERE NOT dog_id IN (SELECT dog_id FROM treatments GROUP BY dog_id HAVING SUM(cost_of_treatment) > 1000) Type: GROUP_BY, HAVING, NESTED, AGGREGATION [579] WRONG_TABLE | DB: dog_kennels | EX: ✗ Q : What are the names of the dogs for which the owner has not spend more than 1000 for treatment Pred: SELECT T2.name FROM owners AS T1 JOIN dogs AS T2 ON T1.owner_id = T2.owner_id GROUP BY T1.owner_id HAVING SUM(T1.cost_of_treatment) > 1000 Gold: SELECT name FROM dogs WHERE NOT dog_id IN (SELECT dog_id FROM treatments GROUP BY dog_id HAVING SUM(cost_of_treatment) > 1000) Type: GROUP_BY, HAVING, NESTED, AGGREGATION [580] WRONG_COLUMNS | DB: dog_kennels | EX: ✗ Q : Which first names are used for professionals or owners but are not used as dog names Pred: SELECT first_name FROM professionals UNION SELECT first_name FROM owners EXCEPT SELECT first_name FROM dogs Gold: SELECT first_name FROM Professionals UNION SELECT first_name FROM Owners EXCEPT SELECT name FROM Dogs Type: SIMPLE [581] WRONG_COLUMNS | DB: dog_kennels | EX: ✗ Q : Find the first names that are used for professionals or owners but are not used as dog names Pred: SELECT first_name FROM professionals UNION SELECT first_name FROM owners EXCEPT SELECT first_name FROM dogs Gold: SELECT first_name FROM Professionals UNION SELECT first_name FROM Owners EXCEPT SELECT name FROM Dogs Type: SIMPLE [582] WRONG_TABLE | DB: dog_kennels | EX: ✓ Q : Which professional did not operate any treatment on dogs? List the professional's id, role and email Pred: SELECT professional_id, role_code, email_address FROM professionals WHERE NOT professional_id IN (SELECT professional_id FROM treatments) Gold: SELECT professional_id, role_code, email_address FROM Professionals EXCEPT SELECT T1.professional_id, T1.role_code, T1.email_address FROM Professionals AS T1 JOIN Treatments AS T2 ON T1.professional_id = T2.professional_id Type: JOIN [583] WRONG_COLUMNS | DB: dog_kennels | EX: ✗ Q : Give me the id, role and email of the professionals who did not perform any treatment on dogs Pred: SELECT professional_id, role_code, email_address FROM professionals EXCEPT SELECT T1.professional_id, T1.role_code FROM professionals AS T1 JOIN treatments AS T2 ON T1.professional_id = T2.professional_id WHERE T2.dog_id = 1 Gold: SELECT professional_id, role_code, email_address FROM Professionals EXCEPT SELECT T1.professional_id, T1.role_code, T1.email_address FROM Professionals AS T1 JOIN Treatments AS T2 ON T1.professional_id = T2.professional_id Type: JOIN [584] WRONG_TABLE | DB: dog_kennels | EX: ✗ Q : Which owner owns the most dogs? List the owner id, first name and last name Pred: SELECT T1.owner_id, T2.first_name, T2.last_name FROM owners AS T1 JOIN dogs AS T2 ON T1.owner_id = T2.owner_id GROUP BY T1.owner_id ORDER BY COUNT(*) DESC LIMIT 1 Gold: SELECT T1.owner_id, T2.first_name, T2.last_name FROM Dogs AS T1 JOIN Owners AS T2 ON T1.owner_id = T2.owner_id GROUP BY T1.owner_id ORDER BY COUNT(*) DESC LIMIT 1 Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, AGGREGATION [585] WRONG_TABLE | DB: dog_kennels | EX: ✗ Q : Return the owner id, first name and last name of the owner who has the most dogs Pred: SELECT T1.owner_id, T2.first_name, T2.last_name FROM owners AS T1 JOIN dogs AS T2 ON T1.owner_id = T2.owner_id GROUP BY T1.owner_id ORDER BY COUNT(*) DESC LIMIT 1 Gold: SELECT T1.owner_id, T2.first_name, T2.last_name FROM Dogs AS T1 JOIN Owners AS T2 ON T1.owner_id = T2.owner_id GROUP BY T1.owner_id ORDER BY COUNT(*) DESC LIMIT 1 Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, AGGREGATION [586] WRONG_TABLE | DB: dog_kennels | EX: ✗ Q : Which professionals have done at least two treatments? List the professional's id, role, and first name Pred: SELECT T1.professional_id, T1.role_code, T2.first_name FROM treatments AS T1 JOIN professionals AS T2 ON T1.professional_id = T2.professional_id GROUP BY T1.professional_id HAVING COUNT(*) >= 2 Gold: SELECT T1.professional_id, T1.role_code, T1.first_name FROM Professionals AS T1 JOIN Treatments AS T2 ON T1.professional_id = T2.professional_id GROUP BY T1.professional_id HAVING COUNT(*) >= 2 Type: JOIN, GROUP_BY, HAVING, AGGREGATION [587] WRONG_COLUMNS | DB: dog_kennels | EX: ✗ Q : What are the id, role, and first name of the professionals who have performed two or more treatments Pred: SELECT T1.professional_id, T1.role_code, T2.first_name FROM professionals AS T1 JOIN treatments AS T2 ON T1.professional_id = T2.professional_id GROUP BY T1.professional_id HAVING COUNT(*) >= 2 Gold: SELECT T1.professional_id, T1.role_code, T1.first_name FROM Professionals AS T1 JOIN Treatments AS T2 ON T1.professional_id = T2.professional_id GROUP BY T1.professional_id HAVING COUNT(*) >= 2 Type: JOIN, GROUP_BY, HAVING, AGGREGATION [588] MISSING_JOIN | DB: dog_kennels | EX: ✓ Q : What is the name of the breed with the most dogs Pred: SELECT breed_name FROM breeds GROUP BY breed_code ORDER BY COUNT(*) DESC LIMIT 1 Gold: SELECT T1.breed_name FROM Breeds AS T1 JOIN Dogs AS T2 ON T1.breed_code = T2.breed_code GROUP BY T1.breed_name ORDER BY COUNT(*) DESC LIMIT 1 Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, AGGREGATION [589] WRONG_TABLE | DB: dog_kennels | EX: ✗ Q : Which breed do the most dogs have? Give me the breed name Pred: SELECT breed_name FROM dogs GROUP BY breed_code ORDER BY COUNT(*) DESC LIMIT 1 Gold: SELECT T1.breed_name FROM Breeds AS T1 JOIN Dogs AS T2 ON T1.breed_code = T2.breed_code GROUP BY T1.breed_name ORDER BY COUNT(*) DESC LIMIT 1 Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, AGGREGATION [590] WRONG_COLUMNS | DB: dog_kennels | EX: ✗ Q : Which owner has paid for the most treatments on his or her dogs? List the owner id and last name Pred: SELECT T1.owner_id, T2.last_name FROM owners AS T1 JOIN treatments AS T2 ON T1.owner_id = T2.owner_id GROUP BY T1.owner_id ORDER BY COUNT(*) DESC LIMIT 1 Gold: SELECT T1.owner_id, T1.last_name FROM Owners AS T1 JOIN Dogs AS T2 ON T1.owner_id = T2.owner_id JOIN Treatments AS T3 ON T2.dog_id = T3.dog_id GROUP BY T1.owner_id ORDER BY COUNT(*) DESC LIMIT 1 Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, AGGREGATION [591] OTHER | DB: dog_kennels | EX: ✗ Q : Tell me the owner id and last name of the owner who spent the most on treatments of his or her dogs Pred: SELECT T1.owner_id, T1.last_name FROM owners AS T1 JOIN treatments AS T2 ON T1.owner_id = T2.owner_id GROUP BY T1.owner_id ORDER BY SUM(T2.cost_of_treatment) DESC LIMIT 1 Gold: SELECT T1.owner_id, T1.last_name FROM Owners AS T1 JOIN Dogs AS T2 ON T1.owner_id = T2.owner_id JOIN Treatments AS T3 ON T2.dog_id = T3.dog_id GROUP BY T1.owner_id ORDER BY COUNT(*) DESC LIMIT 1 Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, AGGREGATION [592] OTHER | DB: dog_kennels | EX: ✗ Q : What is the description of the treatment type that costs the least money in total Pred: SELECT T1.treatment_type_description FROM treatment_types AS T1 JOIN charges AS T2 ON T1.treatment_type_code = T2.treatment_type_code GROUP BY T1.treatment_type_code ORDER BY SUM(T2.charge_amount) ASC LIMIT 1 Gold: SELECT T1.treatment_type_description FROM Treatment_types AS T1 JOIN Treatments AS T2 ON T1.treatment_type_code = T2.treatment_type_code GROUP BY T1.treatment_type_code ORDER BY SUM(cost_of_treatment) ASC LIMIT 1 Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, AGGREGATION [593] OTHER | DB: dog_kennels | EX: ✗ Q : Give me the description of the treatment type whose total cost is the lowest Pred: SELECT T1.treatment_type_description FROM treatment_types AS T1 JOIN charges AS T2 ON T1.treatment_type_code = T2.treatment_type_code GROUP BY T1.treatment_type_code ORDER BY SUM(T2.cost_of_treatment) ASC LIMIT 1 Gold: SELECT T1.treatment_type_description FROM Treatment_types AS T1 JOIN Treatments AS T2 ON T1.treatment_type_code = T2.treatment_type_code GROUP BY T1.treatment_type_code ORDER BY SUM(cost_of_treatment) ASC LIMIT 1 Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, AGGREGATION [594] OTHER | DB: dog_kennels | EX: ✗ Q : Which owner has paid the largest amount of money in total for their dogs? Show the owner id and zip code Pred: SELECT T1.owner_id, T1.zip_code FROM owners AS T1 JOIN charges AS T2 ON T1.owner_id = T2.owner_id GROUP BY T1.owner_id ORDER BY SUM(T2.charge_amount) DESC LIMIT 1 Gold: SELECT T1.owner_id, T1.zip_code FROM Owners AS T1 JOIN Dogs AS T2 ON T1.owner_id = T2.owner_id JOIN Treatments AS T3 ON T2.dog_id = T3.dog_id GROUP BY T1.owner_id ORDER BY SUM(T3.cost_of_treatment) DESC LIMIT 1 Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, AGGREGATION [595] OTHER | DB: dog_kennels | EX: ✗ Q : Find the owner id and zip code of the owner who spent the most money in total for his or her dogs Pred: SELECT T1.owner_id, T1.zip_code FROM owners AS T1 JOIN charges AS T2 ON T1.owner_id = T2.owner_id GROUP BY T1.owner_id ORDER BY SUM(T2.charge_amount) DESC LIMIT 1 Gold: SELECT T1.owner_id, T1.zip_code FROM Owners AS T1 JOIN Dogs AS T2 ON T1.owner_id = T2.owner_id JOIN Treatments AS T3 ON T2.dog_id = T3.dog_id GROUP BY T1.owner_id ORDER BY SUM(T3.cost_of_treatment) DESC LIMIT 1 Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, AGGREGATION [596] WRONG_TABLE | DB: dog_kennels | EX: ✓ Q : Which professionals have done at least two types of treatments? List the professional id and cell phone Pred: SELECT T1.professional_id, T2.cell_number FROM treatments AS T1 JOIN professionals AS T2 ON T1.professional_id = T2.professional_id GROUP BY T1.professional_id HAVING COUNT(*) >= 2 Gold: SELECT T1.professional_id, T1.cell_number FROM Professionals AS T1 JOIN Treatments AS T2 ON T1.professional_id = T2.professional_id GROUP BY T1.professional_id HAVING COUNT(*) >= 2 Type: JOIN, GROUP_BY, HAVING, AGGREGATION [597] WRONG_TABLE | DB: dog_kennels | EX: ✗ Q : What are the first name and last name of the professionals who have done treatment with cost below average Pred: SELECT T2.first_name, T2.last_name FROM treatments AS T1 JOIN professionals AS T2 ON T1.professional_id = T2.professional_id WHERE T1.cost_of_treatment (SELECT AVG(cost_of_treatment) FROM treatments) Gold: SELECT DISTINCT T1.first_name, T1.last_name FROM Professionals AS T1 JOIN Treatments AS T2 ON TRUE WHERE cost_of_treatment < (SELECT AVG(cost_of_treatment) FROM Treatments) Type: JOIN, NESTED, AGGREGATION [598] WRONG_COLUMNS | DB: dog_kennels | EX: ✗ Q : Which professionals have operated a treatment that costs less than the average? Give me theor first names and last names Pred: SELECT T1.first_name, T1.last_name FROM professionals AS T1 JOIN treatments AS T2 ON T1.professional_id = T2.professional_id WHERE T2.cost_of_treatment (SELECT AVG(cost_of_treatment) FROM treatments) Gold: SELECT DISTINCT T1.first_name, T1.last_name FROM Professionals AS T1 JOIN Treatments AS T2 ON TRUE WHERE cost_of_treatment < (SELECT AVG(cost_of_treatment) FROM Treatments) Type: JOIN, NESTED, AGGREGATION [599] WRONG_TABLE | DB: dog_kennels | EX: ✗ Q : List the date of each treatment, together with the first name of the professional who operated it Pred: SELECT T1.date_of_treatment, T2.first_name FROM professionals AS T1 JOIN treatments AS T2 ON T1.professional_id = T2.professional_id Gold: SELECT T1.date_of_treatment, T2.first_name FROM Treatments AS T1 JOIN Professionals AS T2 ON T1.professional_id = T2.professional_id Type: JOIN [600] WRONG_TABLE | DB: dog_kennels | EX: ✓ Q : What are the date and the operating professional's first name of each treatment Pred: SELECT date_of_treatment, first_name FROM professionals AS T1 JOIN treatments AS T2 ON T1.professional_id = T2.professional_id Gold: SELECT T1.date_of_treatment, T2.first_name FROM Treatments AS T1 JOIN Professionals AS T2 ON T1.professional_id = T2.professional_id Type: JOIN [601] WRONG_TABLE | DB: dog_kennels | EX: ✗ Q : List each owner's first name, last name, and the size of his for her dog Pred: SELECT T2.first_name, T2.last_name, T2.size_code FROM dogs AS T1 JOIN owners AS T2 ON T1.owner_id = T2.owner_id JOIN sizes AS T3 ON T1.size_code = T3.size_code Gold: SELECT T1.first_name, T1.last_name, T2.size_code FROM Owners AS T1 JOIN Dogs AS T2 ON T1.owner_id = T2.owner_id Type: JOIN [602] WRONG_TABLE | DB: dog_kennels | EX: ✓ Q : What are each owner's first name, last name, and the size of their dog Pred: SELECT T2.first_name, T2.last_name, T3.size_code FROM dogs AS T1 JOIN owners AS T2 ON T1.owner_id = T2.owner_id JOIN sizes AS T3 ON T1.size_code = T3.size_code Gold: SELECT T1.first_name, T1.last_name, T2.size_code FROM Owners AS T1 JOIN Dogs AS T2 ON T1.owner_id = T2.owner_id Type: JOIN [603] WRONG_TABLE | DB: dog_kennels | EX: ✗ Q : List pairs of the owner's first name and the dogs's name Pred: SELECT T2.first_name, T2.last_name FROM dogs AS T1 JOIN owners AS T2 ON T1.owner_id = T2.owner_id Gold: SELECT T1.first_name, T2.name FROM Owners AS T1 JOIN Dogs AS T2 ON T1.owner_id = T2.owner_id Type: JOIN [604] WRONG_TABLE | DB: dog_kennels | EX: ✗ Q : What are each owner's first name and their dogs's name Pred: SELECT T2.first_name, T2.last_name FROM dogs AS T1 JOIN owners AS T2 ON T1.owner_id = T2.owner_id Gold: SELECT T1.first_name, T2.name FROM Owners AS T1 JOIN Dogs AS T2 ON T1.owner_id = T2.owner_id Type: JOIN [605] MISSING_GROUP_BY | DB: dog_kennels | EX: ✗ Q : List the names of the dogs of the rarest breed and the treatment dates of them Pred: SELECT T2.name, T1.date_of_treatment FROM dogs AS T1 JOIN treatments AS T2 ON T1.dog_id = T2.dog_id WHERE T1.breed_code = (SELECT breed_code FROM dogs AS T3 JOIN treatments AS T4 ON T3.treatment_type_code = T4.treatment_type_code WHERE breed_name = "rast") Gold: SELECT T1.name, T2.date_of_treatment FROM Dogs AS T1 JOIN Treatments AS T2 ON T1.dog_id = T2.dog_id WHERE T1.breed_code = (SELECT breed_code FROM Dogs GROUP BY breed_code ORDER BY COUNT(*) ASC LIMIT 1) Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, NESTED, AGGREGATION [606] WRONG_TABLE | DB: dog_kennels | EX: ✗ Q : Which dogs are of the rarest breed? Show their names and treatment dates Pred: SELECT T1.name, T2.date_of_treatment FROM dogs AS T1 JOIN treatments AS T2 ON T1.dog_id = T2.dog_id WHERE T1.breed_code = (SELECT breed_code FROM breeds AS T3 JOIN treatments AS T4 ON T3.breed_code = T4.breed_code ORDER BY T3.date_of_treatment DESC LIMIT 1) Gold: SELECT T1.name, T2.date_of_treatment FROM Dogs AS T1 JOIN Treatments AS T2 ON T1.dog_id = T2.dog_id WHERE T1.breed_code = (SELECT breed_code FROM Dogs GROUP BY breed_code ORDER BY COUNT(*) ASC LIMIT 1) Type: JOIN, GROUP_BY, ORDER_BY, LIMIT, NESTED, AGGREGATION [607] WRONG_COLUMNS | DB: dog_kennels | EX: ✗ Q : Which dogs are owned by someone who lives in Virginia? List the owner's first name and the dog's name Pred: SELECT T2.first_name, T2.name FROM owners AS T1 JOIN dogs AS T2 ON T1.owner_id = T2.owner_id WHERE T1.state = "Virginia" Gold: SELECT T1.first_name, T2.name FROM Owners AS T1 JOIN Dogs AS T2 ON T1.owner_id = T2.owner_id WHERE T1.state = 'Virginia' Type: JOIN [608] WRONG_COLUMNS | DB: dog_kennels | EX: ✗ Q : Find the first names of owners living in Virginia and the names of dogs they own Pred: SELECT DISTINCT T1.first_name, T2.last_name FROM owners AS T1 JOIN dogs AS T2 ON T1.owner_id = T2.owner_id WHERE T1.state = "Virginia" Gold: SELECT T1.first_name, T2.name FROM Owners AS T1 JOIN Dogs AS T2 ON T1.owner_id = T2.owner_id WHERE T1.state = 'Virginia' Type: JOIN [609] MISSING_JOIN | DB: dog_kennels | EX: ✗ Q : What are the arriving date and the departing date of the dogs who have gone through a treatment Pred: SELECT date_arrived, date_departed FROM dogs Gold: SELECT DISTINCT T1.date_arrived, T1.date_departed FROM Dogs AS T1 JOIN Treatments AS T2 ON T1.dog_id = T2.dog_id Type: JOIN [610] WRONG_TABLE | DB: dog_kennels | EX: ✗ Q : Find the arriving date and the departing date of the dogs that received a treatment Pred: SELECT date_arrived, date_departed FROM treatments Gold: SELECT DISTINCT T1.date_arrived, T1.date_departed FROM Dogs AS T1 JOIN Treatments AS T2 ON T1.dog_id = T2.dog_id Type: JOIN [611] WRONG_TABLE | DB: dog_kennels | EX: ✗ Q : List the last name of the owner owning the youngest dog Pred: SELECT last_name FROM owners ORDER BY age LIMIT 1 Gold: SELECT T1.last_name FROM Owners AS T1 JOIN Dogs AS T2 ON T1.owner_id = T2.owner_id WHERE T2.age = (SELECT MAX(age) FROM Dogs) Type: JOIN, NESTED, AGGREGATION [612] WRONG_TABLE | DB: dog_kennels | EX: ✗ Q : Who owns the youngest dog? Give me his or her last name Pred: SELECT last_name FROM dogs ORDER BY age LIMIT 1 Gold: SELECT T1.last_name FROM Owners AS T1 JOIN Dogs AS T2 ON T1.owner_id = T2.owner_id WHERE T2.age = (SELECT MAX(age) FROM Dogs) Type: JOIN, NESTED, AGGREGATION [613] WRONG_COLUMNS | DB: dog_kennels | EX: ✗ Q : How many dogs went through any treatments Pred: SELECT COUNT(*) FROM treatments Gold: SELECT COUNT(DISTINCT dog_id) FROM Treatments Type: AGGREGATION [614] WRONG_COLUMNS | DB: dog_kennels | EX: ✗ Q : Count the number of dogs that went through a treatment Pred: SELECT COUNT(*) FROM treatments Gold: SELECT COUNT(DISTINCT dog_id) FROM Treatments Type: AGGREGATION [615] WRONG_TABLE | DB: dog_kennels | EX: ✗ Q : How many professionals have performed any treatment to dogs Pred: SELECT COUNT(*) FROM treatments WHERE professional_id IN (SELECT professional_id FROM dogs) Gold: SELECT COUNT(DISTINCT professional_id) FROM Treatments Type: AGGREGATION [616] WRONG_COLUMNS | DB: dog_kennels | EX: ✗ Q : Which professionals live in a city containing the substring 'West'? List his or her role, street, city and state Pred: SELECT role, street, city, state FROM Professionals WHERE city LIKE 'West%' Gold: SELECT role_code, street, city, state FROM professionals WHERE city LIKE '%West%' Type: SIMPLE [617] WRONG_COLUMNS | DB: dog_kennels | EX: ✗ Q : Find the role, street, city and state of the professionals living in a city that contains the substring 'West' Pred: SELECT role, street, city, state FROM professionals WHERE city LIKE 'West%' Gold: SELECT role_code, street, city, state FROM professionals WHERE city LIKE '%West%' Type: SIMPLE [618] OTHER | DB: dog_kennels | EX: ✓ Q : Which owners live in the state whose name contains the substring 'North'? List his first name, last name and email Pred: SELECT first_name, last_name, email_address FROM owners WHERE state LIKE 'North%' Gold: SELECT first_name, last_name, email_address FROM Owners WHERE state LIKE '%North%' Type: SIMPLE [619] OTHER | DB: dog_kennels | EX: ✗ Q : How many dogs have an age below the average Pred: SELECT COUNT(*) FROM dogs WHERE age (SELECT AVG(age) FROM dogs) Gold: SELECT COUNT(*) FROM Dogs WHERE age < (SELECT AVG(age) FROM Dogs) Type: NESTED, AGGREGATION [620] OTHER | DB: dog_kennels | EX: ✗ Q : Count the number of dogs of an age below the average Pred: SELECT COUNT(*) FROM dogs WHERE age (SELECT AVG(age) FROM dogs) Gold: SELECT COUNT(*) FROM Dogs WHERE age < (SELECT AVG(age) FROM Dogs) Type: NESTED, AGGREGATION [621] WRONG_TABLE | DB: dog_kennels | EX: ✗ Q : How many owners temporarily do not have any dogs Pred: SELECT COUNT(*) FROM owners WHERE date_departed > "null" Gold: SELECT COUNT(*) FROM Owners WHERE NOT owner_id IN (SELECT owner_id FROM Dogs) Type: NESTED, AGGREGATION [622] OTHER | DB: dog_kennels | EX: ✓ Q : List the dog name, age and weight of the dogs who have been abandoned? 1 stands for yes, and 0 stands for no Pred: SELECT name, age, weight FROM dogs WHERE abandoned_yn = 1 AND 0 = 0 Gold: SELECT name, age, weight FROM Dogs WHERE abandoned_yn = 1 Type: SIMPLE [623] OTHER | DB: dog_kennels | EX: ✗ Q : What are the dog name, age and weight of the dogs that were abandoned? Note that 1 stands for yes, and 0 stands for no in the tables Pred: SELECT name, age, weight FROM dogs WHERE abandoned_yn = 1 UNION SELECT name, age, weight FROM dogs WHERE abandoned_yn = 0 Gold: SELECT name, age, weight FROM Dogs WHERE abandoned_yn = 1 Type: SIMPLE [624] WRONG_COLUMNS | DB: dog_kennels | EX: ✗ Q : What is the age of the oldest dog Pred: SELECT age FROM dogs ORDER BY date_of_birth LIMIT 1 Gold: SELECT MAX(age) FROM Dogs Type: AGGREGATION [625] WRONG_COLUMNS | DB: dog_kennels | EX: ✗ Q : Tell me the age of the oldest dog Pred: SELECT age FROM dogs ORDER BY date_of_birth LIMIT 1 Gold: SELECT MAX(age) FROM Dogs Type: AGGREGATION [626] OTHER | DB: dog_kennels | EX: ✓ Q : How much does each charge type costs? List both charge type and amount Pred: SELECT charge_type, charge_amount FROM charges GROUP BY charge_type Gold: SELECT charge_type, charge_amount FROM Charges Type: SIMPLE [627] WRONG_COLUMNS | DB: dog_kennels | EX: ✓ Q : How much does the most expensive charge type costs Pred: SELECT charge_amount FROM charges ORDER BY charge_type DESC LIMIT 1 Gold: SELECT MAX(charge_amount) FROM Charges Type: AGGREGATION [628] WRONG_COLUMNS | DB: dog_kennels | EX: ✓ Q : What is the charge amount of the most expensive charge type Pred: SELECT charge_amount FROM charges ORDER BY charge_type DESC LIMIT 1 Gold: SELECT MAX(charge_amount) FROM Charges Type: AGGREGATION [629] WRONG_TABLE | DB: dog_kennels | EX: ✗ Q : What are all the possible breed type and size type combinations Pred: SELECT DISTINCT breed_code, size_code FROM sizes Gold: SELECT DISTINCT breed_code, size_code FROM dogs Type: SIMPLE [630] WRONG_COLUMNS | DB: dog_kennels | EX: ✗ Q : List the first name of all the professionals along with the description of the treatment they have done Pred: SELECT T1.first_name, T2.treatment_type_description FROM professionals AS T1 JOIN treatments AS T2 ON T1.professional_id = T2.professional_id Gold: SELECT DISTINCT T1.first_name, T3.treatment_type_description FROM professionals AS T1 JOIN Treatments AS T2 ON T1.professional_id = T2.professional_id JOIN Treatment_types AS T3 ON T2.treatment_type_code = T3.treatment_type_code Type: JOIN [631] WRONG_COLUMNS | DB: dog_kennels | EX: ✗ Q : What are each professional's first name and description of the treatment they have performed Pred: SELECT T1.first_name, T1.treatment_type_description FROM professionals AS T1 JOIN treatments AS T2 ON T1.professional_id = T2.professional_id Gold: SELECT DISTINCT T1.first_name, T3.treatment_type_description FROM professionals AS T1 JOIN Treatments AS T2 ON T1.professional_id = T2.professional_id JOIN Treatment_types AS T3 ON T2.treatment_type_code = T3.treatment_type_code Type: JOIN [632] OTHER | DB: singer | EX: ✗ Q : List the name of singers whose citizenship is not "France" Pred: SELECT Name FROM singer WHERE Citizenship > "France" Gold: SELECT Name FROM singer WHERE Citizenship <> "France" Type: SIMPLE [633] OTHER | DB: singer | EX: ✗ Q : What are the names of the singers who are not French citizens Pred: SELECT Name FROM singer WHERE Citizenship > 'French' Gold: SELECT Name FROM singer WHERE Citizenship <> "France" Type: SIMPLE [634] EXTRA_JOIN | DB: singer | EX: ✗ Q : What is the name of the singer who is worth the most Pred: SELECT T2.Name FROM singer AS T1 JOIN song AS T2 ON T1.Singer_ID = T2.Singer_ID ORDER BY net_worth_millions DESC LIMIT 1 Gold: SELECT Name FROM singer ORDER BY Net_Worth_Millions DESC LIMIT 1 Type: ORDER_BY, LIMIT [635] WRONG_TABLE | DB: singer | EX: ✗ Q : Show titles of songs and names of singers Pred: SELECT T3.Title, T2.Name FROM song AS T1 JOIN singer AS T2 ON T1.Singer_ID = T2.Singer_ID Gold: SELECT T2.Title, T1.Name FROM singer AS T1 JOIN song AS T2 ON T1.Singer_ID = T2.Singer_ID Type: JOIN [636] WRONG_TABLE | DB: singer | EX: ✗ Q : What are the song titles and singer names Pred: SELECT T2.Title, T1.Name FROM song AS T1 JOIN singer AS T2 ON T1.Singer_ID = T2.Singer_ID Gold: SELECT T2.Title, T1.Name FROM singer AS T1 JOIN song AS T2 ON T1.Singer_ID = T2.Singer_ID Type: JOIN [637] MISSING_JOIN | DB: singer | EX: ✗ Q : For each singer name, what is the total sales for their songs Pred: SELECT SUM(Sales) FROM singer Gold: SELECT T1.Name, SUM(T2.Sales) FROM singer AS T1 JOIN song AS T2 ON T1.Singer_ID = T2.Singer_ID GROUP BY T1.Name Type: JOIN, GROUP_BY, AGGREGATION [638] WRONG_COLUMNS | DB: singer | EX: ✗ Q : What is the sname of every sing that does not have any song Pred: SELECT name FROM singer WHERE NOT song_id IN (SELECT song_id FROM song) Gold: SELECT Name FROM singer WHERE NOT Singer_ID IN (SELECT Singer_ID FROM song) Type: NESTED [639] OTHER | DB: singer | EX: ✗ Q : Show the citizenship shared by singers with birth year before 1945 and after 1955 Pred: SELECT Citizenship FROM singer WHERE Birth_year 1945 INTERSECT SELECT Citizenship FROM singer WHERE Birth_year > 1955 Gold: SELECT Citizenship FROM singer WHERE Birth_Year < 1945 INTERSECT SELECT Citizenship FROM singer WHERE Birth_Year > 1955 Type: SIMPLE [640] OTHER | DB: singer | EX: ✗ Q : What are the citizenships that are shared by singers with a birth year before 1945 and after 1955 Pred: SELECT Citizenship FROM singer WHERE Birth_year 1945 INTERSECT SELECT Citizenship FROM singer WHERE Birth_year > 1955 Gold: SELECT Citizenship FROM singer WHERE Birth_Year < 1945 INTERSECT SELECT Citizenship FROM singer WHERE Birth_Year > 1955 Type: SIMPLE [641] WRONG_TABLE | DB: real_estate_properties | EX: ✗ Q : What is the feature type name of feature AirCon Pred: SELECT T1.feature_type_name FROM Ref_Feature_Types AS T1 JOIN Ref_Feature_Types AS T2 ON T1.feature_type_code = T2.feature_type_code WHERE T2.feature_name = "AirCon" Gold: SELECT T2.feature_type_name FROM Other_Available_Features AS T1 JOIN Ref_Feature_Types AS T2 ON T1.feature_type_code = T2.feature_type_code WHERE T1.feature_name = "AirCon" Type: JOIN [642] WRONG_TABLE | DB: real_estate_properties | EX: ✗ Q : Show the property type descriptions of properties belonging to that code Pred: SELECT T1.property_type_description FROM Ref_Property_Types AS T1 JOIN Properties AS T2 ON T1.property_type_code = T2.property_type_code Gold: SELECT T2.property_type_description FROM Properties AS T1 JOIN Ref_Property_Types AS T2 ON T1.property_type_code = T2.property_type_code GROUP BY T1.property_type_code Type: JOIN, GROUP_BY [643] OTHER | DB: real_estate_properties | EX: ✗ Q : What are the names of properties that are either houses or apartments with more than 1 room Pred: SELECT property_name FROM Properties WHERE room_count > 1 AND property_name = 'House' OR room_count > 1 UNION SELECT property_name FROM Properties WHERE property_type_code = 'Apartment' Gold: SELECT property_name FROM Properties WHERE property_type_code = "House" UNION SELECT property_name FROM Properties WHERE property_type_code = "Apartment" AND room_count > 1 Type: SIMPLE