Create README.md

README.md

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+---
+license: cc-by-4.0
+language:
+- en
+base_model:
+- nvidia/OpenReasoning-Nemotron-1.5B
+pipeline_tag: text-generation
+library_name: transformers.js
+tags:
+- nvidia
+- code
+---
+
+# OpenReasoning-Nemotron-1.5B Overview
+
+## Usage (Transformers.js)
+
+If you haven't already, you can install the [Transformers.js](https://huggingface.co/docs/transformers.js) JavaScript library from [NPM](https://www.npmjs.com/package/@huggingface/transformers) using:
+```bash
+npm i @huggingface/transformers
+```
+
+You can then generate text as follows:
+```js
+import { pipeline, TextStreamer } from "@huggingface/transformers";
+
+// Create a text generation pipeline
+const generator = await pipeline(
+  "text-generation",
+  "onnx-community/OpenReasoning-Nemotron-1.5B-ONNX",
+  { dtype: "q4", device: "webgpu" },
+);
+
+// Define the list of messages
+const prompt = "x^2 + 2x - 8 = 0";
+const messages = [
+  { role: "user", content: `Solve the following math problem. Make sure to put the answer (and only answer) inside \\boxed{}.\n\n${prompt}` },
+];
+
+// Generate a response
+const output = await generator(messages, {
+    max_new_tokens: 4096,
+    streamer: new TextStreamer(generator.tokenizer, { skip_prompt: true, skip_special_tokens: true}),
+});
+console.log(output[0].generated_text.at(-1).content);
+```
+
+<details>
+
+<summary>See example output</summary>
+
+```
+<think>
+I have this equation: \( x^2 + 2x - 8 = 0 \). It's a quadratic equation, and I need to solve for x. The general form is \( ax^2 + bx + c = 0 \), so here a = 1, b = 2, c = -8.
+
+I can use the quadratic formula: \( x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \).
+
+Plugging in the values: b = 2, so -b = -2; c = -8, so -4ac = -4(1)(-8) = 32.
+
+The discriminant D = b^2 - 4ac = (2)^2 - 4(1)(-8) = 4 + 32 = 36.
+
+Since D is positive, there are two real solutions.
+
+x = [-b ± sqrt(D)] / (2a) = [-2 ± sqrt(36)] / 2 = [-2 ± 6]/2.
+
+Now, two cases:
+
+First, with +: (-2 + 6)/2 = 4/2 = 2.
+
+Second, with -: (-2 - 6)/2 = (-8)/2 = -4.
+
+So, x = 2 or x = -4.
+
+I could also factor this. Since it's (x^2 + 2x - 8) = 0.
+
+I need two numbers that multiply to -8 and add to 2. 4 and -2: 4 * -2 = -8, 4 + (-2) = 2. Yes, so (x + 4)(x - 2) = 0? Let me check.
+
+(x + 4)(x - 2) = x^2 - 2x + 4x - 8 = x^2 + 2x - 8. Yes, perfect.
+
+So, (x + 4)(x - 2) = 0, so x = -4 or x = 2.
+
+Same as before.
+
+The problem says "solve the following math problem" and gives the equation, but it has an equal sign, so it's an equation to solve.
+
+But in the text, it says "x^2 + 2x - 8 = 0", so it's clear.
+
+Now, it says "make sure to put the answer (and only answer) inside \boxed{}."
+
+So, I need to present the answer. Since there are two solutions, I should box both.
+
+But typically, we might write x = 2 or x = -4.
+
+Since it's an equation, the solution set is {-4, 2}.
+
+But I think for the box, I should write the values.
+
+Looking back at the problem, it says "x^2 + 2x - 8 = 0", and it's written with the equal sign, so it's an equation.
+
+But in the instruction, it says "solve", so I need to find x.
+
+Perhaps I should write the solutions.
+
+Maybe they want the answer as a pair or something.
+
+Another thought: sometimes in multiple choice, but here it's not multiple choice.
+
+The problem is given as is, so I think I need to provide the solutions.
+
+Perhaps I can write x = 2 or x = -4.
+
+But for the box, I need to put only the answer.
+
+Maybe list the values.
+
+I recall that in some contexts, they might expect the answer in a specific format.
+
+Since it's a quadratic, and I solved it, I think it's fine.
+
+But let me see the equation again: "x^2 + 2x - 8 = 0"
+
+And it has the equal sign, so it's clear.
+
+Perhaps I should write the answer as x = -4 or x = 2.
+
+But for the box, I need to put it neatly.
+
+Since it's "only answer", perhaps I should write the values.
+
+Another idea: sometimes they write the solution set.
+
+But I think for this, it's straightforward.
+
+I can write the answer as 2 and -4.
+
+But let me confirm if I did it right.
+
+x^2 + 2x - 8 = 0
+
+At x=2: 4 + 4 - 8 = 0, yes.
+
+x=-4: 16 - 8 - 8 = 16 - 16 = 0, yes.
+
+So correct.
+
+Now, for the box, I think I should write the solutions.
+
+Perhaps they want the answer in a box, so I'll write x = -4 \text{ or } x = 2.
+
+But the instruction says "only answer", so maybe just the values.
+
+I think it's fine.
+
+Since it's a math problem, and I need to box the final answer.
+
+I recall that in some platforms, they might expect the answer as a set or something.
+
+But I think for simplicity, I'll write the solutions.
+
+Perhaps I can write "x = -4 or x = 2".
+
+But let me see the format.
+
+Another thought: the equation is written with the equal sign, so it's an equation, and I solved it.
+
+But in the answer, I need to present x.
+
+I think I'm overcomplicating.
+
+I'll box the values.
+
+So, the solutions are x = -4 and x = 2.
+
+So, for the box, I'll put -4 and 2.
+
+But to be clear, I can write "x = -4 \text{ or } x = 2".
+
+But since it says "only answer", perhaps just the numbers.
+
+I think it's acceptable.
+
+I can write the solution set: \{-4, 2\}.
+
+But that might be too formal.
+
+In many contexts, they just list the values.
+
+Since it's a quadratic, and I found the roots.
+
+I think I'll go with x = -4 or x = 2.
+
+But for the box, I need to put it inside.
+
+Perhaps the problem expects me to write the answer as per the equation.
+
+Another idea: maybe they want the answer in a specific order, like ascending order.
+
+So, -4 and 2.
+
+So, I'll write -4 and 2.
+
+But to be precise, I'll include the variable.
+
+I think for the box, I'll put the values.
+
+Let me see similar problems.
+
+I recall that in some cases, they write "x = \text{value}".
+
+But here, since there are two, I need to specify.
+
+Perhaps I can write "x = -4 \text{ or } x = 2".
+
+But for the box, I'll put that.
+
+The instruction says "put the answer (and only answer) inside \boxed{}", so I think I should put the solution.
+
+Perhaps they expect the answer as a number, but there are two.
+
+Unless I made a mistake.
+
+The equation is x^2 + 2x - 8 = 0, which is correct.
+
+Maybe it's part of a larger problem, but no, it's given as is.
+
+Perhaps I need to solve for x, and the answer is the values.
+
+I think I'm fine.
+
+So, I'll box the solutions.
+
+So, the answer is x = -4 or x = 2.
+
+For the box, I'll write \boxed{-4} and \boxed{2}, but that might be for separate boxes, but it's one answer.
+
+I think it's better to write it as a pair or something.
+
+I can write "x = -4 \text{ and } x = 2" but "and" might imply both, but it's or.
+
+In math, it's clear.
+
+To avoid confusion, I'll write the solution set.
+
+So, \boxed{\{-4, 2\}}.
+
+That might be acceptable.
+
+Since it's an equation, the solution is the set of x that satisfy it.
+
+I think that's fine.
+
+Some people write "x = -4 or x = 2".
+
+But for the box, I'll put the set.
+
+I recall that in some textbooks, they list the values.
+
+I think I'll do \boxed{-4} and \boxed{2}, but that's two boxes, but the instruction says "inside \boxed{}", singular, so one box.
+
+So, I need one box.
+
+So, \boxed{\text{ } -4 \text{ and } 2 \text{ }} or something.
+
+To be neat, I'll write \boxed{-4, 2}.
+
+But it might not be clear.
+
+I can write "x = -4 \text{ or } x = 2" inside the box.
+
+But that might be messy.
+
+Another idea: since it's a quadratic, and I solved it, I can just state the roots.
+
+I think for this context, it's okay.
+
+Perhaps the problem is to find x, and I have it.
+
+I'll go with \boxed{-4} and \boxed{2}, but since it's one answer, I'll put both in one box.
+
+So, \boxed{-4 \text{ and } 2}.
+
+To make it look better, \boxed{2,\ -4}.
+
+But I think it's fine.
+
+I recall that in the quadratic formula, I got x = [-2 ± 6]/2, which is 4/2=2 and -8/2=-4, so the values are 2 and -4.
+
+So, I'll box 2 and -4.
+
+But to specify, I'll write the solutions.
+
+I think I'm ready.
+
+So, the answer is x = -4 or x = 2.
+
+For the box, I'll put \boxed{-4} and \boxed{2}, but that's two boxes.
+
+The instruction says "inside \boxed{}", so one box.
+
+So, I'll write \boxed{\text{ } -4 \text{ and } 2 \text{ }}.
+
+To save space, \boxed{-4, 2}.
+
+I think that's acceptable.
+
+Some platforms use that.
+
+So, I'll do that.
+
+But let me confirm the equation once more.
+
+x^2 + 2x - 8 = 0.
+
+Multiply both sides by 4 to make it easier, but no need.
+
+Or, complete the square.
+
+x^2 + 2x = 8, then (x+1)^2 -1 =8, so (x+1)^2 =9, so x+1 = ±3, so x=2 or x=-4. Same thing.
+
+So, no issue.
+
+Therefore, the solutions are x = -4 and x = 2.
+
+So, for the box, I'll put \boxed{-4} and \boxed{2}, but since it's one answer, I'll put both in one box.
+
+Perhaps \boxed{2,\ -4}.
+
+I think it's fine.
+
+I'll write the answer as -4 and 2.
+
+So, \boxed{-4 \text{ and } 2}
+
+But to be precise, I'll use the set notation.
+
+I think for this level, it's okay.
+
+Another thought: the problem says "solve", and in some contexts, they might expect the answer as a number, but here there are two, so I need to include both.
+
+Perhaps they want the product or sum, but no, it says solve the equation.
+
+So, I think I'm good.
+
+I'll go with \boxed{-4} and \boxed{2}, but since it's one box, I'll write \boxed{2,\ -4}.
+
+Yes.
+
+So, the final answer is 2 and -4.
+
+To match the format, I'll put it as such.
+</think>
+The equation to solve is \(x^2 + 2x - 8 = 0\).
+
+This is a quadratic equation in the form \(ax^2 + bx + c = 0\), where \(a = 1\), \(b = 2\), and \(c = -8\).
+
+The solutions are found using the quadratic formula:
+\[
+x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}
+\]
+
+Substitute the values:
+\[
+x = \frac{-2 \pm \sqrt{2^2 - 4(1)(-8)}}{2(1)} = \frac{-2 \pm \sqrt{4 + 32}}{2} = \frac{-2 \pm \sqrt{36}}{2} = \frac{-2 \pm 6}{2}
+\]
+
+This gives two solutions:
+- \(x = \frac{-2 + 6}{2} = \frac{4}{2} = 2\)
+- \(x = \frac{-2 - 6}{2} = \frac{-8}{2} = -4\)
+
+Thus, the solutions are \(x = -4\) and \(x = 2\).
+
+The answer is presented as the values of \(x\) that satisfy the equation.
+
+\boxed{-4,\ 2}
+
+```
+
+</details>
+