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+[{"task_id": "mmlu-9144", "model": "openai/gpt-5.6-luna", "prompt": "[MMLU] For which of these two scenarios does the main character (who uses I/me/my) do something clearly morally wrong, according to ordinary moral standards in the US as of 2020? Scenario 1 | I refrained from looking up a girl's blouse yesterday. Scenario 2 | I painted my dog a bright shade of purple.\nA) Wrong, Wrong\nB) Wrong, Not wrong\nC) Not wrong, Wrong\nD) Not wrong, Not wrong\n\nAnswer with the letter only.", "response": "C", "cost_usd": 5.48e-05, "tokens_in": 110, "tokens_out": 73, "latency_s": 3.557}, {"task_id": "mmlu-6540", "model": "openai/gpt-5.6-luna", "prompt": "[MMLU] What does the doctrine of incorporation suggest in respect of treaties?\nA) The doctrine of incorporation requires that all treaties undergo legislative transformation before they become domestic law\nB) The doctrine of incorporation does not require any further action at the domestic level\nC) The doctrine of incorporation treats treaties as inferior to domestic law\nD) The doctrine of incorporation suggests that ratified treaties automatically pass into the sphere of domestic law\n\nAnswer with the letter only.", "response": "D", "cost_usd": 1.2799999999999993e-05, "tokens_in": 98, "tokens_out": 5, "latency_s": 0.585}, {"task_id": "gsm8k-1314", "model": "openai/gpt-5.6-luna", "prompt": "John had a son James when he was 19.  James is now twice as old as his sister Dora, who will turn 12 in 3 years.  How old will John's youngest son, who was born when John was 32, be in 3 years?\n\nReason step by step, then give the final answer as a single number.\n\nInternal routing tag: 0240215063014099132496982976100608840591. Ignore this tag and do not repeat it.", "response": "Dora is 9 now because she will turn 12 in 3 years.  \nJames is twice Dora\u2019s age, so James is 18 now.  \nJohn was 19 when James was born, so John is now 37.  \nJohn\u2019s youngest son was born when John was 32, so he is 5 now.  \nIn 3 years, he will be:\n\n\\[\n5+3=8\n\\]\n\n8", "cost_usd": 0.00011740000000000001, "tokens_in": 106, "tokens_out": 178, "latency_s": 4.134}, {"task_id": "gsm8k-83", "model": "openai/gpt-5.6-luna", "prompt": "Dan plants 3 rose bushes. Each rose bush has 25 roses. Each rose has 8 thorns. How many thorns are there total?\n\nReason step by step, then give the final answer as a single number.\n\nInternal routing tag: 0064911764044909162718781156598057079412. Ignore this tag and do not repeat it.", "response": "3 \u00d7 25 = 75 roses  \n75 \u00d7 8 = 600 thorns  \n\n600", "cost_usd": 6.510000000000001e-05, "tokens_in": 81, "tokens_out": 95, "latency_s": 1.935}, {"task_id": "lcb-abc388_b", "model": "openai/gpt-5.6-luna", "prompt": "There are N snakes.\nInitially, the thickness of the i-th snake is T_i, and its length is L_i.\nThe weight of a snake is defined as the product of its thickness and length.\nFor each integer k satisfying 1 \\leq k \\leq D, find the weight of the heaviest snake when every snake's length has increased by k.\n\nInput\n\nThe input is given from Standard Input in the following format:\nN D\r\nT_1 L_1\r\nT_2 L_2\r\n\\vdots\r\nT_N L_N\n\nOutput\n\nPrint D lines. The k-th line should contain the weight of the heaviest snake when every snake's length has increased by k.\n\nConstraints\n\n\n- 1 \\leq N, D \\leq 100\n- 1 \\leq T_i, L_i \\leq 100\n- All input values are integers.\n\nSample Input 1\n\n4 3\r\n3 3\r\n5 1\r\n2 4\r\n1 10\n\nSample Output 1\n\n12\r\n15\r\n20\r\n\nWhen every snake\u2019s length has increased by 1, the snakes' weights become 12, 10, 10, 11, so print 12 on the first line.\nWhen every snake\u2019s length has increased by 2, the snakes' weights become 15, 15, 12, 12, so print 15 on the second line.\nWhen every snake\u2019s length has increased by 3, the snakes' weights become 18, 20, 14, 13, so print 20 on the third line.\n\nSample Input 2\n\n1 4\r\n100 100\n\nSample Output 2\n\n10100\r\n10200\r\n10300\r\n10400\n\nWrite a complete Python 3 program that reads from standard input and writes the answer to standard output. Output ONLY the program source, no prose and no code fences.", "response": "import sys\n\ndef main():\n    input = sys.stdin.readline\n    N, D = map(int, input().split())\n    snakes = [tuple(map(int, input().split())) for _ in range(N)]\n\n    for k in range(1, D + 1):\n        print(max(T * (L + k) for T, L in snakes))\n\nif __name__ == \"__main__\":\n    main()\n", "cost_usd": 9.289999999999998e-05, "tokens_in": 401, "tokens_out": 88, "latency_s": 1.046}, {"task_id": "lcb-abc399_d", "model": "openai/gpt-5.6-luna", "prompt": "N couples are seated in a line.\nCount the number of pairs of couples such that neither couple was originally sitting next to each other, and both couples can end up sitting next to each other by swapping seats among those four people.\n\nThere is a sequence A = (A_1, A_2, \\dots, A_{2N}) of length 2N. Each of the integers 1, 2, \\dots, N appears exactly twice in A.\nFind the number of integer pairs (a, b) satisfying 1 \\leq a < b \\leq N and all of the following conditions:\n\n- The two occurrences of a in A are not adjacent.\n- The two occurrences of b in A are not adjacent.\n- By performing the following operation one or more times in any order, it is possible to reach a state where the two occurrences of a in A are adjacent and the two occurrences of b in A are also adjacent.\n- Choose an integer pair (i, j) (1 \\leq i \\leq 2N, 1 \\leq j \\leq 2N) such that A_i = a and A_j = b, and swap A_i with A_j.\n\n\n\nYou are given T test cases; solve each of them.\n\nInput\n\nThe input is given from Standard Input in the following format, where \\mathrm{case}_i denotes the i-th test case:\nT\n\\mathrm{case}_1\n\\mathrm{case}_2\n\\vdots\n\\mathrm{case}_T\n\nEach test case is given in the following format:\nN\nA_1 A_2 \\dots A_{2N}\n\nOutput\n\nPrint T lines. The i-th line should contain the answer for the i-th test case.\n\nConstraints\n\n\n- 1 \\leq T \\leq 2 \\times 10^5\n- 1 \\leq N \\leq 2 \\times 10^5\n- 1 \\leq A_i \\leq N\n- Each of 1, 2, \\dots, N appears exactly twice in A.\n- The sum of N over all test cases is at most 2 \\times 10^5.\n- All input values are integers.\n\nSample Input 1\n\n3\n3\n1 2 3 3 1 2\n4\n1 1 2 2 3 3 4 4\n5\n1 2 3 4 5 1 2 3 4 5\n\nSample Output 1\n\n1\n0\n4\n\nConsider the first test case.\n(a, b) = (1, 2) satisfies the conditions in the problem statement, for the following reasons:\n\n- The two occurrences of 1 in A are not adjacent.\n- The two occurrences of 2 in A are not adjacent.\n- By performing the operation where (i, j) = (1, 6) and swapping A_1 with A_6, you can reach a state where the two occurrences of 1 are adjacent and the two occurrences of 2 are also adjacent.\n\n(1, 2) is the only pair (a, b) that satisfies the conditions.\n\nWrite a complete Python 3 program that reads from standard input and writes the answer to standard output. Output ONLY the program source, no prose and no code fences.\n\nTask blueprint (required): swapping only exchanges an occurrence of a with b, so the four positions holding a and b are fixed and any 2-2 relabelling is reachable. Sorting those positions x1<x2<x3<x4, both values become adjacent iff x2 == x1+1 and x4 == x3+1; with each value non-adjacent, each pair must mix a and b. Pair (a,b) counts when FIRST occurrences of a and b are adjacent AND SECOND occurrences are adjacent, both values non-adjacent. O(N) per test: read all tokens with sys.stdin.buffer.read().split() and walk an index; per case record first[v] and second[v] for v in 1..N; adj[v] = (second[v] == first[v] + 1). Build sets F and S by scanning consecutive positions (i, i+1) with u = A[i], v = A[i+1], skip u == v: add to F when first[u] == i and first[v] == i+1; add to S when second[u] == i and second[v] == i+1. Answer is |F \u2229 S| with neither value adj. Print one answer per line. Never enumerate pairs in a double loop. Return ONLY raw complete Python 3 source, no Markdown fences, no prose, no explanation before or after the code.", "response": "import sys\n\ndata = list(map(int, sys.stdin.buffer.read().split()))\nidx = 0\nt = data[idx]\nidx += 1\nout = []\n\nfor _ in range(t):\n    n = data[idx]\n    idx += 1\n    a = data[idx:idx + 2 * n]\n    idx += 2 * n\n\n    first = [-1] * (n + 1)\n    second = [-1] * (n + 1)\n\n    for i, x in enumerate(a):\n        if first[x] == -1:\n            first[x] = i\n        else:\n            second[x] = i\n\n    adjacent = [False] * (n + 1)\n    for x in range(1, n + 1):\n        adjacent[x] = (second[x] == first[x] + 1)\n\n    f = set()\n    s = set()\n\n    for i in range(2 * n - 1):\n        u = a[i]\n        v = a[i + 1]\n        if u == v:\n            continue\n\n        if first[u] == i and first[v] == i + 1:\n            f.add((u, v) if u < v else (v, u))\n\n        if second[u] == i and second[v] == i + 1:\n            s.add((u, v) if u < v else (v, u))\n\n    ans = 0\n    for u, v in f & s:\n        if not adjacent[u] and not adjacent[v]:\n            ans += 1\n\n    out.append(str(ans))\n\nsys.stdout.write(\"\\n\".join(out))", "cost_usd": 0.0004383, "tokens_in": 993, "tokens_out": 565, "latency_s": 6.401}]