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+[{"task_id": "mmlu-7773", "model": "openai/gpt-5.6-luna", "prompt": "[MMLU] On which part of a car would you find the 'caliper'?\nA) battery\nB) engine\nC) radiator\nD) brakes\n\nAnswer with the letter only.", "response": "D", "cost_usd": 7.7e-06, "tokens_in": 47, "tokens_out": 5, "latency_s": 1.494}, {"task_id": "mmlu-1541", "model": "openai/gpt-5.6-luna", "prompt": "[MMLU] The openSSL implementation described in \u201cRemote Timing Attacks are Practical\u201d (by Brumley and Boneh) uses the following performance optimizations: Chinese Remainder (CR), Montgomery Representation (MR), Karatsuba Multiplication (KM), and Repeated squaring and Sliding windows (RS). Which of the following options would close the timing channel attack described in the paper if you turned the listed optimizations off?\n1. CR and MR\n2. CR\nA) True, True\nB) False, False\nC) True, False\nD) False, True\n\nAnswer with the letter only.", "response": "C", "cost_usd": 0.0002181, "tokens_in": 135, "tokens_out": 341, "latency_s": 5.251}, {"task_id": "gsm8k-840", "model": "openai/gpt-5.6-luna", "prompt": "Patrick has three glue sticks that are partially used. One has 1/6 left, the second has 2/3 left and the third one has 1/2 left. If a glue stick is 12 millimeters long originally, what is the total length of the glue sticks that are not used?\n\nReason step by step, then give the final answer as a single number.\n\nInternal routing tag: 0006037647091342903109780494077467492222. Ignore this tag and do not repeat it.", "response": "Each remaining length:\n\n- \\(12 \\times \\frac{1}{6} = 2\\) mm\n- \\(12 \\times \\frac{2}{3} = 8\\) mm\n- \\(12 \\times \\frac{1}{2} = 6\\) mm\n\nTotal: \\(2+8+6=16\\) mm\n\n16", "cost_usd": 0.0001061, "tokens_in": 113, "tokens_out": 158, "latency_s": 2.937}, {"task_id": "gsm8k-1028", "model": "openai/gpt-5.6-luna", "prompt": "Tom buys a bedroom set for $3000.  He sells his old bedroom for $1000 and uses that to pay for part of the bedroom set.  He then has to pay 10% a month for the bedroom set.  How much does he have to pay per month?\n\nReason step by step, then give the final answer as a single number.\n\nInternal routing tag: 0087317547130916038985602816763717776219. Ignore this tag and do not repeat it.", "response": "1. The bedroom set costs $3,000.\n2. He pays $1,000 from selling his old bedroom set.\n3. Remaining balance: $3,000 \u2212 $1,000 = $2,000.\n4. Monthly payment is 10% of $2,000: 0.10 \u00d7 $2,000 = $200.\n\n200", "cost_usd": 9.430000000000002e-05, "tokens_in": 109, "tokens_out": 139, "latency_s": 2.216}, {"task_id": "lcb-abc391_a", "model": "deepseek/deepseek-v4-flash", "prompt": "You are given a string D representing one of the eight directions (north, east, west, south, northeast, northwest, southeast, southwest). The correspondence between the directions and their representing strings is as follows.\n\n- North: N\n- East: E\n- West: W\n- South: S\n- Northeast: NE\n- Northwest: NW\n- Southeast: SE\n- Southwest: SW\n\nPrint the string representing the direction opposite to the direction denoted by D.\n\nInput\n\nThe input is given from Standard Input in the following format:\nD\n\nOutput\n\nPrint the answer.\n\nConstraints\n\n\n- D is one of N, E, W, S, NE, NW, SE, SW.\n\nSample Input 1\n\nN\n\nSample Output 1\n\nS\r\n\nPrint S, which represents south, the direction opposite to north.\n\nSample Input 2\n\nSE\n\nSample Output 2\n\nNW\r\n\nPrint NW, which represents northwest, the direction opposite to southeast.\n\nWrite a complete Python 3 program that reads from standard input and writes the answer to standard output. Output ONLY the program source, no prose and no code fences.", "response": "```python\nimport sys\n\ndef main():\n    d = sys.stdin.readline().strip()\n    opposite = {\n        'N': 'S',\n        'S': 'N',\n        'E': 'W',\n        'W': 'E',\n        'NE': 'SW',\n        'SW': 'NE',\n        'NW': 'SE',\n        'SE': 'NW'\n    }\n    print(opposite[d])\n\nif __name__ == \"__main__\":\n    main()\n```", "cost_usd": 4.059678000000003e-05, "tokens_in": 235, "tokens_out": 179, "latency_s": 6.698}, {"task_id": "lcb-arc194_a", "model": "openai/gpt-5.6-luna", "prompt": "You are given an integer sequence of length N: (A_1, A_2, \\ldots, A_N). There is also a sequence S, which is initially empty.\nFor each i = 1, 2, \\ldots, N in this order, you perform exactly one of the following two operations:\n\n- Append A_i as an element to the end of S.\n- Delete the last element of S. You cannot choose this operation if S is empty.\n\nPrint the maximum possible value of the sum of the elements of S after all operations.\n\nInput\n\nThe input is given from Standard Input in the following format:\nN\r\nA_1 A_2 \\ldots A_N\n\nOutput\n\nPrint the answer.\n\nConstraints\n\n\n- 1 \\leq N \\leq 2 \\times 10^5\n- -10^9 \\leq A_i \\leq 10^9\n- All input values are integers.\n\nSample Input 1\n\n6\r\n3 -1 -4 5 -9 2\n\nSample Output 1\n\n8\r\n\nStarting from the initial state where S is an empty sequence, consider the following operations:\n\n- For i = 1, append A_1 = 3 to the end of S. Now, S = (3).\n- For i = 2, append A_2 = -1 to the end of S. Now, S = (3, -1).\n- For i = 3, delete the last element of S. Now, S = (3).\n- For i = 4, append A_4 = 5 to the end of S. Now, S = (3, 5).\n- For i = 5, append A_5 = -9 to the end of S. Now, S = (3, 5, -9).\n- For i = 6, delete the last element of S. Now, S = (3, 5).\n\nHere, the sum of the elements of S after all operations is 3 + 5 = 8, which is the maximum possible value.\n\nSample Input 2\n\n1\r\n-1\n\nSample Output 2\n\n-1\r\n\nNote that if S is empty, you must choose to append an element.\n\nSample Input 3\n\n20\r\n-14 74 -48 38 -51 43 5 37 -39 -29 80 -44 -55 59 17 89 -37 -68 38 -16\n\nSample Output 3\n\n369\n\nWrite a complete Python 3 program that reads from standard input and writes the answer to standard output. Output ONLY the program source, no prose and no code fences.\n\nSolver brief (required, replaces stack simulation): a kept element that ends up t-th (1-based) among kept ones must sit at an array index with the same parity as t; skipped stretches between kept elements are even; kept-count parity matches N. O(N) DP over i = 1..N with a = A[i]: keep best_even (init 0) and best_odd (init -inf). If i is odd, best_odd = max(best_odd, best_even + a); if i is even, best_even = max(best_even, best_odd + a). Print best_even when N is even else best_odd. Read with sys.stdin.buffer.read().split(). No recursion, O(N^2), heap, or explicit stack. Return ONLY the complete Python 3 program implementing exactly this brief. No code fences, no explanations, no text before or after the program.", "response": "import sys\n\ndata = list(map(int, sys.stdin.buffer.read().split()))\nn = data[0]\na = data[1:]\n\nneg_inf = -10**30\nbest_even = 0\nbest_odd = neg_inf\n\nfor i, value in enumerate(a, 1):\n    if i % 2:\n        best_odd = max(best_odd, best_even + value)\n    else:\n        best_even = max(best_even, best_odd + value)\n\nprint(best_even if n % 2 == 0 else best_odd)", "cost_usd": 0.00014579999999999997, "tokens_in": 744, "tokens_out": 119, "latency_s": 1.136}]