exemplos em Python

.gitignore

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+venv_coding/

1_Python_coding.ipynb

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+{
+ "cells": [
+  {
+   "attachments": {},
+   "cell_type": "markdown",
+   "metadata": {},
+   "source": [
+    "<h1 align=\"center\"><font color=\"yellow\">Python coding</font></h1>"
+   ]
+  },
+  {
+   "attachments": {},
+   "cell_type": "markdown",
+   "metadata": {},
+   "source": [
+    "<font color=\"yellow\">Data Scientist.: Dr.Eddy Giusepe Chirinos Isidro</font>"
+   ]
+  },
+  {
+   "attachments": {},
+   "cell_type": "markdown",
+   "metadata": {},
+   "source": [
+    "# <font color=\"red\">Exemplo 1</font>"
+   ]
+  },
+  {
+   "attachments": {},
+   "cell_type": "markdown",
+   "metadata": {},
+   "source": [
+    "Dado um ano, informe se é um ano bissexto (lead)."
+   ]
+  },
+  {
+   "cell_type": "code",
+   "execution_count": 23,
+   "metadata": {},
+   "outputs": [
+    {
+     "data": {
+      "text/plain": [
+       "False"
+      ]
+     },
+     "execution_count": 23,
+     "metadata": {},
+     "output_type": "execute_result"
+    }
+   ],
+   "source": [
+    "def is_leap(year: int):\n",
+    "    if (year % 4 == 0 and year % 100 != 0) or (year % 400 == 0):\n",
+    "        return True\n",
+    "    else: \n",
+    "        return False\n",
+    "\n",
+    "is_leap(2015)"
+   ]
+  },
+  {
+   "attachments": {},
+   "cell_type": "markdown",
+   "metadata": {},
+   "source": [
+    "# <font color=\"red\">Exemplo 2</font>"
+   ]
+  },
+  {
+   "attachments": {},
+   "cell_type": "markdown",
+   "metadata": {},
+   "source": [
+    "Encontre a diferença entre o quadrado da soma e a soma dos quadrados dos primeiros N números naturais"
+   ]
+  },
+  {
+   "cell_type": "code",
+   "execution_count": 31,
+   "metadata": {},
+   "outputs": [
+    {
+     "name": "stdout",
+     "output_type": "stream",
+     "text": [
+      "4\n"
+     ]
+    }
+   ],
+   "source": [
+    "def square(x):\n",
+    "    return x ** 2\n",
+    "\n",
+    "\n",
+    "def dif_square(n):\n",
+    "    return sum(range(n + 1)) ** 2 - sum(map(lambda x: x**2, range(n + 1)))\n",
+    "\n",
+    "\n",
+    "print(dif_square(2))"
+   ]
+  },
+  {
+   "attachments": {},
+   "cell_type": "markdown",
+   "metadata": {},
+   "source": [
+    "# <font color=\"red\">Exemplo 3</font>"
+   ]
+  },
+  {
+   "attachments": {},
+   "cell_type": "markdown",
+   "metadata": {},
+   "source": [
+    "Um [número de Armstrong](https://en.wikipedia.org/wiki/Narcissistic_number) é um número que é a soma de seus próprios dígitos, cada um elevado à potência do número de dígitos.\n",
+    "\n",
+    "Por exemplo: \n",
+    "\n",
+    "* $9 = 9^1 = 9$\n",
+    "\n",
+    "* $153 =1^3 + 5^3 + 3^3 = 153$ "
+   ]
+  },
+  {
+   "cell_type": "code",
+   "execution_count": 33,
+   "metadata": {},
+   "outputs": [
+    {
+     "name": "stdout",
+     "output_type": "stream",
+     "text": [
+      "True\n"
+     ]
+    }
+   ],
+   "source": [
+    "def armstrong(number: int):\n",
+    "    sum = 0\n",
+    "    temp = number\n",
+    "    order = len(str(number))\n",
+    "\n",
+    "    while temp > 0:\n",
+    "        digit = temp % 10\n",
+    "        sum += digit ** order\n",
+    "        temp //= 10 # temp = temp // 10\n",
+    "\n",
+    "    return True if sum == number else False\n",
+    "\n",
+    "\n",
+    "\n",
+    "print(armstrong(153))"
+   ]
+  },
+  {
+   "attachments": {},
+   "cell_type": "markdown",
+   "metadata": {},
+   "source": [
+    "# <font color=\"red\">Exemplo 4</font>"
+   ]
+  },
+  {
+   "attachments": {},
+   "cell_type": "markdown",
+   "metadata": {},
+   "source": [
+    "Exibir os primeiros N números na ordem inversa."
+   ]
+  },
+  {
+   "cell_type": "code",
+   "execution_count": 42,
+   "metadata": {},
+   "outputs": [
+    {
+     "name": "stdout",
+     "output_type": "stream",
+     "text": [
+      "8 7 6 5 4 3 2 1 "
+     ]
+    }
+   ],
+   "source": [
+    "N = int(input(\"Digita um número Inteiro N: \"))\n",
+    "\n",
+    "for i in range(N, 0, -1):\n",
+    "    print(i, end=\" \")\n"
+   ]
+  },
+  {
+   "attachments": {},
+   "cell_type": "markdown",
+   "metadata": {},
+   "source": [
+    "Soma dos primeiros N números."
+   ]
+  },
+  {
+   "cell_type": "code",
+   "execution_count": 45,
+   "metadata": {},
+   "outputs": [
+    {
+     "name": "stdout",
+     "output_type": "stream",
+     "text": [
+      "55\n"
+     ]
+    }
+   ],
+   "source": [
+    "N = int(input(\"Digita um número inteiro N: \"))\n",
+    "\n",
+    "sum = 0\n",
+    "for i in range(0, N + 1): # Também: for i in range(N, 0, -1):\n",
+    "    sum = sum + i \n",
+    "\n",
+    "print(sum)"
+   ]
+  },
+  {
+   "attachments": {},
+   "cell_type": "markdown",
+   "metadata": {},
+   "source": [
+    "É um ano bissexto."
+   ]
+  },
+  {
+   "cell_type": "code",
+   "execution_count": 47,
+   "metadata": {},
+   "outputs": [
+    {
+     "name": "stdout",
+     "output_type": "stream",
+     "text": [
+      "1996 é ano bissexto.\n"
+     ]
+    }
+   ],
+   "source": [
+    "year = int(input(\"Digita o Ano para verificar se é bissexto:\"))\n",
+    "\n",
+    "if (year % 400 == 0):\n",
+    "    print(str(year) + \" é ano bissexto.\")\n",
+    "\n",
+    "elif (year % 4 == 0 and year % 100 != 0):\n",
+    "    print(str(year) + \" é ano bissexto.\")\n",
+    "\n",
+    "else:\n",
+    "    print(str(year) + \" não é ano bissexto.\")\n"
+   ]
+  },
+  {
+   "attachments": {},
+   "cell_type": "markdown",
+   "metadata": {},
+   "source": [
+    "Verifique se o número fornecido é um número primo ou não."
+   ]
+  },
+  {
+   "cell_type": "code",
+   "execution_count": 63,
+   "metadata": {},
+   "outputs": [
+    {
+     "name": "stdout",
+     "output_type": "stream",
+     "text": [
+      "3 é um número primo.\n"
+     ]
+    }
+   ],
+   "source": [
+    "num = int(input(\"Digita um número Inteiro: \"))\n",
+    "\n",
+    "\n",
+    "count = 0\n",
+    "for i in range(2,int(num/2) + 1):\n",
+    "    if(num % i == 0):\n",
+    "        count = count + 1\n",
+    "\n",
+    "\n",
+    "if((count == 0) and (num > 1)):\n",
+    "    print(str(num) + \" é um número primo.\")\n",
+    "else:\n",
+    "    print(str(num) + \" não é um número primo.\")"
+   ]
+  },
+  {
+   "attachments": {},
+   "cell_type": "markdown",
+   "metadata": {},
+   "source": [
+    "Soma dos dígitos de um número."
+   ]
+  },
+  {
+   "cell_type": "code",
+   "execution_count": 68,
+   "metadata": {},
+   "outputs": [
+    {
+     "name": "stdout",
+     "output_type": "stream",
+     "text": [
+      "3\n"
+     ]
+    }
+   ],
+   "source": [
+    "n = int(input(\"Digita um número inteiro: \"))\n",
+    "\n",
+    "sum = 0\n",
+    "\n",
+    "while (n != 0):\n",
+    "    sum = sum + n % 10\n",
+    "    n = n // 10\n",
+    "\n",
+    "print(sum)"
+   ]
+  },
+  {
+   "cell_type": "code",
+   "execution_count": null,
+   "metadata": {},
+   "outputs": [],
+   "source": []
+  }
+ ],
+ "metadata": {
+  "kernelspec": {
+   "display_name": "venv_coding",
+   "language": "python",
+   "name": "python3"
+  },
+  "language_info": {
+   "codemirror_mode": {
+    "name": "ipython",
+    "version": 3
+   },
+   "file_extension": ".py",
+   "mimetype": "text/x-python",
+   "name": "python",
+   "nbconvert_exporter": "python",
+   "pygments_lexer": "ipython3",
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+  },
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+ },
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+}