| import torch |
| from numba import njit |
|
|
| from modules import shared |
|
|
|
|
| def process_llamacpp_cache(model, new_sequence, past_sequence): |
| if len(past_sequence) == 0 or len(new_sequence) == 0: |
| return past_sequence |
|
|
| i1, i2, j1, j2 = find_longest_common_substring_indices(past_sequence, new_sequence) |
| overlap_length = i2 - i1 + 1 |
|
|
| |
| |
| if i1 > 0 and overlap_length > 0.2 * len(new_sequence): |
|
|
| new_sequence = torch.tensor(new_sequence) |
| past_sequence = torch.tensor(past_sequence) |
|
|
| prefix_length = find_prefix_length(past_sequence[:i1], new_sequence[:j1]) |
| sink_length = max(prefix_length, shared.args.attention_sink_size) |
| removed_length = i1 - sink_length |
|
|
| if removed_length <= 0: |
| return past_sequence.tolist() |
|
|
| matching_prefix = past_sequence[:prefix_length] |
| removed_chunk = past_sequence[sink_length:i1] |
| overlapping_sequence = new_sequence[j1:j2 + 1] |
| added_chunk = new_sequence[j2 + 1:] |
|
|
| |
| |
|
|
| print() |
| print('MATCHING PREFIX=', repr(shared.tokenizer.decode(matching_prefix))) |
| print('ADDED CHUNK=', repr(shared.tokenizer.decode(added_chunk))) |
| print('REMOVED CHUNK=', repr(shared.tokenizer.decode(removed_chunk))) |
| print('REMOVED LENGTH=', removed_length) |
| print() |
|
|
| |
| |
| model._ctx.kv_cache_seq_rm(0, sink_length, sink_length + removed_length) |
| model._ctx.kv_cache_seq_shift(0, sink_length + removed_length, -1, -removed_length) |
|
|
| new_sequence = new_sequence.tolist() |
| model.input_ids[:j2 + 1] = new_sequence[:j2 + 1] |
| model.n_tokens = j2 + 1 |
|
|
| return new_sequence[:j2 + 1] |
| else: |
| return past_sequence |
|
|
|
|
| def find_prefix_length(past_seq, seq_tensor): |
| ''' |
| Given two torch tensors, finds the length of the longest |
| common prefix between the two. |
| ''' |
| min_length = min(past_seq.shape[0], seq_tensor.shape[0]) |
| indices = torch.nonzero(~torch.eq(past_seq[:min_length], seq_tensor[:min_length])) |
| if len(indices) > 0: |
| prefix_length = indices[0].item() |
| else: |
| prefix_length = min_length |
|
|
| return prefix_length |
|
|
|
|
| @njit |
| def find_longest_common_substring_indices(list1, list2): |
| ''' |
| Given two lists, solves the Longest Common Substring problem. |
| |
| It returns the indices where the substring starts and ends in |
| s1 and s2. |
| |
| Example: |
| |
| ir, jr, ir2, jr2 = find_longest_common_substring_indices(s1, s2) |
| print(s1[ir:jr + 1]) |
| print(s2[ir2:jr2 + 1]) |
| |
| Adapted from |
| https://rosettacode.org/wiki/Longest_common_substring#Python |
| ''' |
|
|
| len_list1, len_list2 = len(list1), len(list2) |
| start_index_list1, end_index_list1 = 0, -1 |
| start_index_list2, end_index_list2 = 0, -1 |
|
|
| |
| for index1 in range(0, len_list1): |
| try: |
| index2 = list2.index(list1[index1]) |
| except: |
| continue |
|
|
| while index2 >= 0: |
| temp_index1, temp_index2 = index1, index2 |
| while temp_index1 < len_list1 and temp_index2 < len_list2 and list2[temp_index2] == list1[temp_index1]: |
| if temp_index1 - index1 >= end_index_list1 - start_index_list1: |
| start_index_list1, end_index_list1 = index1, temp_index1 |
| start_index_list2, end_index_list2 = index2, temp_index2 |
|
|
| temp_index1 += 1 |
| temp_index2 += 1 |
| try: |
| index2 = list2.index(list1[index1], index2 + 1) |
| except: |
| break |
|
|
| return start_index_list1, end_index_list1, start_index_list2, end_index_list2 |
|
|