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Create app.py
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app.py
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import math
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import pandas as pd
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import gradio as gr
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def emi_calc(P, annual_rate, years):
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# Validate inputs
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if P is None or P <= 0:
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return "Enter valid principal.", pd.DataFrame()
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if annual_rate is None or annual_rate < 0:
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return "Enter valid rate.", pd.DataFrame()
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if years is None or years <= 0:
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return "Enter valid tenure.", pd.DataFrame()
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# Convert
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P = float(P)
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r = (float(annual_rate) / 100.0) / 12.0
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n = int(round(float(years) * 12))
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if n <= 0:
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return "Tenure is too small.", pd.DataFrame()
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# EMI formula
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if r == 0:
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emi = P / n
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else:
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emi = P * r * ((1 + r) ** n) / (((1 + r) ** n) - 1)
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total = emi * n
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interest_total = total - P
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md = (
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f"### Results\n"
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f"- Monthly EMI: ₹{emi:,.2f}\n"
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f"- Total Interest: ₹{interest_total:,.2f}\n"
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f"- Total Payable: ₹{total:,.2f}\n"
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f"- Tenure: {n} months"
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)
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# Amortization schedule
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bal = P
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rows = []
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for m in range(1, n + 1):
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interest = bal * r
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principal = emi - interest
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# Adjust last month to avoid tiny rounding balance
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if m == n:
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principal = bal
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emi_last = principal + interest
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bal = 0.0
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rows.append([m, round(emi_last, 2), round(principal, 2), round(interest, 2), round(bal, 2)])
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break
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bal -= principal
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rows.append([m, round(emi, 2), round(principal, 2), round(interest, 2), round(bal, 2)])
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df = pd.DataFrame(rows, columns=["Month", "EMI", "Principal Paid", "Interest Paid", "Balance"])
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return md, df
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with gr.Blocks(title="Loan EMI Calculator") as demo:
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gr.Markdown("## Simple Loan EMI Calculator")
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with gr.Row():
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P = gr.Number(label="Loan Amount (₹)", value=500000, precision=0)
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rate = gr.Number(label="Annual Interest Rate (%)", value=9.0, precision=2)
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years = gr.Number(label="Tenure (Years)", value=5, precision=2)
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btn = gr.Button("Calculate")
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out_md = gr.Markdown()
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out_df = gr.Dataframe(interactive=False)
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btn.click(emi_calc, inputs=[P, rate, years], outputs=[out_md, out_df])
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demo.launch()
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