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8e5ba9e | 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 70 71 72 73 74 75 76 77 78 79 80 81 82 83 84 85 86 87 88 89 90 91 92 93 94 95 96 97 98 99 100 101 102 103 104 105 106 107 108 109 110 111 112 113 114 115 116 117 118 119 120 121 122 123 124 125 126 127 128 129 130 131 132 133 134 135 136 137 138 139 140 141 142 143 144 145 146 147 148 149 150 151 152 153 154 155 156 157 158 159 160 161 162 163 164 165 166 167 168 169 170 171 172 173 174 175 176 177 | """Kirchhoff-Love rectangular plate solvers with Navier series solutions.
Two configurations:
- Simply supported on all edges + uniform pressure
- Clamped on all edges + uniform pressure
The simply supported case uses the exact Navier double Fourier series.
The clamped case uses tabulated coefficients from Timoshenko & Woinowsky-Krieger.
Assumptions (Kirchhoff-Love theory):
- Thin plate (t << a, b)
- Small deflections (w << t)
- Linear elasticity
- Homogeneous, isotropic material
Reference: Timoshenko, S.P. & Woinowsky-Krieger, S.,
"Theory of Plates and Shells", 2nd Ed.
"""
import math
from typing import Any
import numpy as np
from src.data.schema import SolutionResult
from src.data.solvers.base import AnalyticalSolver
class SimplySupported_UniformPressure(AnalyticalSolver):
"""Simply supported rectangular plate under uniform pressure q.
Uses Navier's double Fourier series solution (exact):
w(x,y) = sum_m sum_n [a_mn * sin(m*pi*x/a) * sin(n*pi*y/b)]
where a_mn = 16*q / (pi^6 * D * m*n * (m^2/a^2 + n^2/b^2)^2)
for odd m, n only.
Max deflection at center (a/2, b/2):
w_max = sum of a_mn * sin(m*pi/2) * sin(n*pi/2)
Max bending stress from max moment:
M_x_max at center, sigma = 6*M_x / t^2
"""
N_TERMS = 50 # Fourier series terms (converges well by ~20)
@property
def config_id(self) -> str:
return "plate_ss_uniform"
@property
def problem_family(self) -> str:
return "plate"
def solve(self, params: dict[str, Any]) -> SolutionResult:
a = params["length_a"]
b = params["length_b"]
t = params["thickness"]
E = params["elastic_modulus"]
nu = params["poisson_ratio"]
sigma_y = params["yield_strength"]
q = params["pressure"]
D = E * t**3 / (12.0 * (1.0 - nu**2))
w_max = 0.0
Mx_max = 0.0
My_max = 0.0
for m in range(1, self.N_TERMS + 1, 2): # odd m only
for n in range(1, self.N_TERMS + 1, 2): # odd n only
denom = (m**2 / a**2 + n**2 / b**2) ** 2
# Fourier coefficient
a_mn = 16.0 * q / (math.pi**6 * D * m * n * denom)
# Deflection at center: sin(m*pi/2) * sin(n*pi/2)
sign_w = math.sin(m * math.pi / 2) * math.sin(n * math.pi / 2)
w_max += a_mn * sign_w
# Bending moments at center
# M_x = -D * (d2w/dx2 + nu * d2w/dy2)
factor_x = (m * math.pi / a) ** 2 + nu * (n * math.pi / b) ** 2
factor_y = nu * (m * math.pi / a) ** 2 + (n * math.pi / b) ** 2
Mx_max += a_mn * factor_x * sign_w
My_max += a_mn * factor_y * sign_w
# Convert moment to stress: sigma = 6*M / t^2 (plate bending formula)
Mx_max *= D # a_mn already divided by D, so Mx = D * sum(a_mn * factor * sign)
My_max *= D
sigma_x = 6.0 * abs(Mx_max) / t**2
sigma_y_stress = 6.0 * abs(My_max) / t**2
max_stress = max(sigma_x, sigma_y_stress)
return SolutionResult.from_stress(max_stress, abs(w_max), sigma_y)
class Clamped_UniformPressure(AnalyticalSolver):
"""Clamped rectangular plate under uniform pressure q.
No exact Fourier series exists for clamped edges. Uses interpolated
coefficients from Timoshenko Table 35 (pp. 202):
w_max = alpha * q * a^4 / D
M_max = beta * q * a^2
where alpha and beta depend on the aspect ratio b/a.
For b/a >= 1 (a is the shorter side), standard tabulated values apply.
Reference values (b/a -> alpha, beta_center, beta_edge):
1.0 -> 0.00126, 0.0231, 0.0513
1.2 -> 0.00172, 0.0299, 0.0639
1.4 -> 0.00207, 0.0349, 0.0726
1.6 -> 0.00230, 0.0381, 0.0780
1.8 -> 0.00245, 0.0401, 0.0812
2.0 -> 0.00254, 0.0412, 0.0829
inf -> 0.00260, 0.0417, 0.0833
"""
# Tabulated coefficients: (b/a, alpha, beta_edge)
# beta_edge gives max stress at mid-edge (clamped), which exceeds center stress
_TABLE = np.array([
[1.0, 0.00126, 0.0513],
[1.2, 0.00172, 0.0639],
[1.4, 0.00207, 0.0726],
[1.6, 0.00230, 0.0780],
[1.8, 0.00245, 0.0812],
[2.0, 0.00254, 0.0829],
[3.0, 0.00260, 0.0833], # approaches infinite strip
[5.0, 0.00260, 0.0833],
])
@property
def config_id(self) -> str:
return "plate_fixed_uniform"
@property
def problem_family(self) -> str:
return "plate"
def solve(self, params: dict[str, Any]) -> SolutionResult:
a_dim = params["length_a"]
b_dim = params["length_b"]
t = params["thickness"]
E = params["elastic_modulus"]
nu = params["poisson_ratio"]
sigma_y = params["yield_strength"]
q = params["pressure"]
# Ensure a <= b (a is the shorter side for table lookup)
if a_dim > b_dim:
a, b = b_dim, a_dim
else:
a, b = a_dim, b_dim
D = E * t**3 / (12.0 * (1.0 - nu**2))
ratio = b / a
# Interpolate coefficients from table
alpha = float(np.interp(ratio, self._TABLE[:, 0], self._TABLE[:, 1]))
beta = float(np.interp(ratio, self._TABLE[:, 0], self._TABLE[:, 2]))
max_deflection = alpha * q * a**4 / D
# beta is the moment coefficient: M_max = beta * q * a^2
# Bending stress: sigma = 6*M / t^2
max_stress = 6.0 * beta * q * a**2 / t**2
return SolutionResult.from_stress(max_stress, abs(max_deflection), sigma_y)
PLATE_SOLVERS: dict[str, type[AnalyticalSolver]] = {
"plate_ss_uniform": SimplySupported_UniformPressure,
"plate_fixed_uniform": Clamped_UniformPressure,
}
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