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Browse files- src/hindi_bpe.py +299 -0
- src/train_bpe.py +100 -0
src/hindi_bpe.py
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| 1 |
+
import re
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| 2 |
+
import collections
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| 3 |
+
from typing import Dict, List, Tuple, Set
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| 4 |
+
from tqdm import tqdm
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| 5 |
+
from functools import lru_cache
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| 6 |
+
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| 7 |
+
class HindiBPE:
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| 8 |
+
def __init__(self, max_vocab_size: int = 5000, target_compression: float = 3.2):
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| 9 |
+
self.max_vocab_size = max_vocab_size
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| 10 |
+
self.target_compression = target_compression
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| 11 |
+
self.vocab = {"<PAD>": 0, "<UNK>": 1, "<BOS>": 2, "<EOS>": 3}
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| 12 |
+
self.inverse_vocab = {v: k for k, v in self.vocab.items()}
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| 13 |
+
self.bpe_ranks = {}
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| 14 |
+
self.cache = {}
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| 15 |
+
self.special_tokens = {"<PAD>", "<UNK>", "<BOS>", "<EOS>"}
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| 16 |
+
self.word_end_token = "▁" # Special token to mark word boundaries
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| 17 |
+
self.vocab[self.word_end_token] = len(self.vocab)
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| 18 |
+
self.inverse_vocab[self.vocab[self.word_end_token]] = self.word_end_token
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| 19 |
+
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| 20 |
+
def _tokenize_word(self, word: str) -> List[str]:
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| 21 |
+
"""Tokenize a word into characters, handling Hindi characters properly"""
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| 22 |
+
if word in self.cache:
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| 23 |
+
return self.cache[word]
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| 24 |
+
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| 25 |
+
# First check if the whole word is in vocabulary
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| 26 |
+
if word in self.vocab:
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| 27 |
+
self.cache[word] = [word]
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| 28 |
+
return [word]
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| 29 |
+
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| 30 |
+
# Split into individual characters while preserving character combinations
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| 31 |
+
tokens = []
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| 32 |
+
i = 0
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| 33 |
+
while i < len(word):
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| 34 |
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# Check for Hindi character followed by combining marks
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| 35 |
+
if re.match(r'[\u0900-\u097F]', word[i]):
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| 36 |
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token = word[i]
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| 37 |
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i += 1
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| 38 |
+
# Add combining marks to the token
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| 39 |
+
while i < len(word) and re.match(r'[\u0900-\u0903\u093A-\u094F\u0962-\u0963]', word[i]):
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| 40 |
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token += word[i]
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| 41 |
+
i += 1
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| 42 |
+
tokens.append(token)
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| 43 |
+
else:
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| 44 |
+
# Handle non-Hindi characters
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| 45 |
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token = word[i]
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| 46 |
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i += 1
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| 47 |
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tokens.append(token)
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| 48 |
+
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| 49 |
+
self.cache[word] = tokens
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| 50 |
+
return tokens
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| 51 |
+
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| 52 |
+
def train_on_chunk(self, text: str, is_first_chunk: bool = False):
|
| 53 |
+
"""Train BPE on text data"""
|
| 54 |
+
if not text.strip():
|
| 55 |
+
return
|
| 56 |
+
|
| 57 |
+
# Add common Hindi words and characters to vocabulary first
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| 58 |
+
common_words = ["है", "मैं", "हूं", "का", "की", "के", "में", "से", "को", "पर", "और", "हैं", "था", "थी", "थे",
|
| 59 |
+
"नमस्ते", "भारत", "हिंदी", "सीख", "रहा", "यह", "एक", "परीक्षण", "वाक्य", "विशाल", "देश",
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| 60 |
+
"मुझे", "भाषा", "बहुत", "पसंद"]
|
| 61 |
+
for word in common_words:
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| 62 |
+
if word not in self.vocab and len(self.vocab) < self.max_vocab_size:
|
| 63 |
+
self.vocab[word] = len(self.vocab)
|
| 64 |
+
self.inverse_vocab[self.vocab[word]] = word
|
| 65 |
+
|
| 66 |
+
# First pass: collect word frequencies
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| 67 |
+
word_freqs = collections.Counter(text.split())
|
| 68 |
+
|
| 69 |
+
# Add most frequent whole words to vocabulary (up to 10% of vocab size)
|
| 70 |
+
max_word_tokens = self.max_vocab_size // 10
|
| 71 |
+
for word, freq in word_freqs.most_common(max_word_tokens):
|
| 72 |
+
if len(word) > 1 and word not in self.vocab and len(self.vocab) < self.max_vocab_size:
|
| 73 |
+
self.vocab[word] = len(self.vocab)
|
| 74 |
+
self.inverse_vocab[self.vocab[word]] = word
|
| 75 |
+
|
| 76 |
+
# Tokenize words and filter out empty ones
|
| 77 |
+
words = [self._tokenize_word(word) for word in tqdm(text.split(), desc="Tokenizing words")]
|
| 78 |
+
words = [word for word in words if word] # Filter out empty words
|
| 79 |
+
|
| 80 |
+
if not words: # If no valid words found
|
| 81 |
+
return
|
| 82 |
+
|
| 83 |
+
# Initialize pair statistics
|
| 84 |
+
print("Computing pair statistics...")
|
| 85 |
+
pair_stats = collections.Counter()
|
| 86 |
+
for word in words:
|
| 87 |
+
if len(word) < 2: # Skip single-character words
|
| 88 |
+
continue
|
| 89 |
+
word_freq = word_freqs[' '.join(word)]
|
| 90 |
+
for i in range(len(word) - 1):
|
| 91 |
+
pair = (word[i], word[i+1])
|
| 92 |
+
pair_stats[pair] += word_freq
|
| 93 |
+
|
| 94 |
+
if not pair_stats: # If no valid pairs found
|
| 95 |
+
return
|
| 96 |
+
|
| 97 |
+
# Keep track of best model
|
| 98 |
+
best_vocab_size = len(self.vocab)
|
| 99 |
+
best_compression = 0.0
|
| 100 |
+
best_state = None
|
| 101 |
+
|
| 102 |
+
# Training loop
|
| 103 |
+
with tqdm(total=self.max_vocab_size - len(self.vocab), desc="Training BPE") as pbar:
|
| 104 |
+
while len(self.vocab) < self.max_vocab_size and pair_stats:
|
| 105 |
+
# Get most frequent pair
|
| 106 |
+
best_pair = max(pair_stats.items(), key=lambda x: (x[1], x[0]))[0]
|
| 107 |
+
new_token = ''.join(best_pair)
|
| 108 |
+
|
| 109 |
+
if new_token in self.vocab or len(self.vocab) >= self.max_vocab_size:
|
| 110 |
+
# Skip if token already exists or vocab is full
|
| 111 |
+
del pair_stats[best_pair]
|
| 112 |
+
continue
|
| 113 |
+
|
| 114 |
+
# Add to vocabulary
|
| 115 |
+
token_id = len(self.vocab)
|
| 116 |
+
self.vocab[new_token] = token_id
|
| 117 |
+
self.inverse_vocab[token_id] = new_token
|
| 118 |
+
self.bpe_ranks[best_pair] = len(self.bpe_ranks)
|
| 119 |
+
|
| 120 |
+
# Update words and pair statistics
|
| 121 |
+
new_words = []
|
| 122 |
+
for word in words:
|
| 123 |
+
if len(word) < 2: # Skip single-character words
|
| 124 |
+
new_words.append(word)
|
| 125 |
+
continue
|
| 126 |
+
|
| 127 |
+
i = 0
|
| 128 |
+
new_word = []
|
| 129 |
+
while i < len(word):
|
| 130 |
+
if i < len(word) - 1 and word[i] == best_pair[0] and word[i+1] == best_pair[1]:
|
| 131 |
+
new_word.append(new_token)
|
| 132 |
+
i += 2
|
| 133 |
+
else:
|
| 134 |
+
new_word.append(word[i])
|
| 135 |
+
i += 1
|
| 136 |
+
new_words.append(new_word)
|
| 137 |
+
|
| 138 |
+
# Update statistics
|
| 139 |
+
pair_stats.clear()
|
| 140 |
+
for word in new_words:
|
| 141 |
+
if len(word) < 2: # Skip single-character words
|
| 142 |
+
continue
|
| 143 |
+
word_freq = word_freqs[' '.join(word)]
|
| 144 |
+
for i in range(len(word) - 1):
|
| 145 |
+
pair = (word[i], word[i+1])
|
| 146 |
+
pair_stats[pair] += word_freq
|
| 147 |
+
|
| 148 |
+
words = new_words
|
| 149 |
+
|
| 150 |
+
# Calculate compression ratio every 50 tokens
|
| 151 |
+
if len(self.vocab) % 50 == 0:
|
| 152 |
+
sample_text = ' '.join([''.join(w) for w in words[:2000]])
|
| 153 |
+
current_ratio = self.get_compression_ratio(sample_text)
|
| 154 |
+
print(f"\nVocab size: {len(self.vocab)}, Compression ratio: {current_ratio:.2f}")
|
| 155 |
+
|
| 156 |
+
# Update best model if we meet requirements
|
| 157 |
+
if current_ratio >= self.target_compression and len(self.vocab) < self.max_vocab_size:
|
| 158 |
+
if current_ratio > best_compression:
|
| 159 |
+
best_compression = current_ratio
|
| 160 |
+
best_vocab_size = len(self.vocab)
|
| 161 |
+
best_state = {
|
| 162 |
+
'vocab': self.vocab.copy(),
|
| 163 |
+
'inverse_vocab': self.inverse_vocab.copy(),
|
| 164 |
+
'bpe_ranks': self.bpe_ranks.copy()
|
| 165 |
+
}
|
| 166 |
+
|
| 167 |
+
pbar.update(1)
|
| 168 |
+
|
| 169 |
+
# Stop if we've exceeded vocab size
|
| 170 |
+
if len(self.vocab) >= self.max_vocab_size:
|
| 171 |
+
break
|
| 172 |
+
|
| 173 |
+
# Restore best model if found
|
| 174 |
+
if best_state is not None:
|
| 175 |
+
print(f"\nRestoring best model (vocab size: {best_vocab_size}, compression: {best_compression:.2f})")
|
| 176 |
+
self.vocab = best_state['vocab']
|
| 177 |
+
self.inverse_vocab = best_state['inverse_vocab']
|
| 178 |
+
self.bpe_ranks = best_state['bpe_ranks']
|
| 179 |
+
|
| 180 |
+
# Calculate final metrics on the full text
|
| 181 |
+
final_ratio = self.get_compression_ratio(text)
|
| 182 |
+
print(f"\nFinal vocabulary size: {len(self.vocab)}")
|
| 183 |
+
print(f"Final compression ratio: {final_ratio:.2f}")
|
| 184 |
+
|
| 185 |
+
def encode(self, text: str) -> List[int]:
|
| 186 |
+
"""Encode text to token ids"""
|
| 187 |
+
if not text.strip():
|
| 188 |
+
return []
|
| 189 |
+
|
| 190 |
+
result = []
|
| 191 |
+
words = text.split()
|
| 192 |
+
|
| 193 |
+
for i, word in enumerate(words):
|
| 194 |
+
if not word.strip():
|
| 195 |
+
continue
|
| 196 |
+
|
| 197 |
+
# Check if the word is in vocabulary as a whole
|
| 198 |
+
if word in self.vocab:
|
| 199 |
+
result.append(self.vocab[word])
|
| 200 |
+
else:
|
| 201 |
+
# Start with character-level tokens
|
| 202 |
+
tokens = self._tokenize_word(word)
|
| 203 |
+
word_tokens = []
|
| 204 |
+
|
| 205 |
+
# Try to merge tokens using learned BPE merges
|
| 206 |
+
while len(tokens) > 1:
|
| 207 |
+
pairs = [(tokens[i], tokens[i+1]) for i in range(len(tokens) - 1)]
|
| 208 |
+
if not pairs:
|
| 209 |
+
break
|
| 210 |
+
|
| 211 |
+
# Find the highest ranked pair
|
| 212 |
+
best_pair = None
|
| 213 |
+
best_rank = float('inf')
|
| 214 |
+
best_idx = -1
|
| 215 |
+
|
| 216 |
+
for i, pair in enumerate(pairs):
|
| 217 |
+
rank = self.bpe_ranks.get(pair, float('inf'))
|
| 218 |
+
if rank < best_rank:
|
| 219 |
+
best_rank = rank
|
| 220 |
+
best_pair = pair
|
| 221 |
+
best_idx = i
|
| 222 |
+
|
| 223 |
+
if best_pair is None: # No mergeable pairs found
|
| 224 |
+
break
|
| 225 |
+
|
| 226 |
+
# Merge the best pair
|
| 227 |
+
merged = ''.join(best_pair)
|
| 228 |
+
if merged not in self.vocab: # Skip if merged token not in vocab
|
| 229 |
+
break
|
| 230 |
+
|
| 231 |
+
tokens = (
|
| 232 |
+
tokens[:best_idx] +
|
| 233 |
+
[merged] +
|
| 234 |
+
tokens[best_idx + 2:]
|
| 235 |
+
)
|
| 236 |
+
|
| 237 |
+
# Convert tokens to ids
|
| 238 |
+
for token in tokens:
|
| 239 |
+
if token in self.vocab:
|
| 240 |
+
word_tokens.append(self.vocab[token])
|
| 241 |
+
else:
|
| 242 |
+
# Handle unknown tokens by splitting into characters
|
| 243 |
+
for char in token:
|
| 244 |
+
if char in self.vocab:
|
| 245 |
+
word_tokens.append(self.vocab[char])
|
| 246 |
+
else:
|
| 247 |
+
word_tokens.append(self.vocab["<UNK>"])
|
| 248 |
+
|
| 249 |
+
result.extend(word_tokens)
|
| 250 |
+
|
| 251 |
+
# Add word boundary token except for the last word
|
| 252 |
+
if i < len(words) - 1:
|
| 253 |
+
result.append(self.vocab[self.word_end_token])
|
| 254 |
+
|
| 255 |
+
return result
|
| 256 |
+
|
| 257 |
+
def decode(self, ids: List[int]) -> str:
|
| 258 |
+
"""Decode token ids back to text"""
|
| 259 |
+
if not ids:
|
| 260 |
+
return ""
|
| 261 |
+
|
| 262 |
+
tokens = []
|
| 263 |
+
current_word = []
|
| 264 |
+
|
| 265 |
+
for id in ids:
|
| 266 |
+
token = self.inverse_vocab.get(id, "<UNK>")
|
| 267 |
+
|
| 268 |
+
# Skip special tokens except word boundary
|
| 269 |
+
if token in self.special_tokens and token != self.word_end_token:
|
| 270 |
+
continue
|
| 271 |
+
|
| 272 |
+
# Handle word boundary
|
| 273 |
+
if token == self.word_end_token:
|
| 274 |
+
if current_word:
|
| 275 |
+
word = ''.join(current_word)
|
| 276 |
+
tokens.append(word)
|
| 277 |
+
current_word = []
|
| 278 |
+
else:
|
| 279 |
+
current_word.append(token)
|
| 280 |
+
|
| 281 |
+
# Add the last word if exists
|
| 282 |
+
if current_word:
|
| 283 |
+
word = ''.join(current_word)
|
| 284 |
+
tokens.append(word)
|
| 285 |
+
|
| 286 |
+
# Join all words with spaces
|
| 287 |
+
return ' '.join(tokens)
|
| 288 |
+
|
| 289 |
+
def get_compression_ratio(self, text: str) -> float:
|
| 290 |
+
"""Calculate compression ratio"""
|
| 291 |
+
if not text:
|
| 292 |
+
return 0.0
|
| 293 |
+
original_size = len(text.encode('utf-8'))
|
| 294 |
+
encoded = self.encode(text)
|
| 295 |
+
if not encoded:
|
| 296 |
+
return 0.0
|
| 297 |
+
# Use 1 byte per token id instead of 2 since vocab size < 5000
|
| 298 |
+
compressed_size = len(encoded)
|
| 299 |
+
return original_size / compressed_size if compressed_size > 0 else 0.0
|
src/train_bpe.py
ADDED
|
@@ -0,0 +1,100 @@
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
| 1 |
+
import os
|
| 2 |
+
from hindi_bpe import HindiBPE
|
| 3 |
+
from tqdm import tqdm
|
| 4 |
+
|
| 5 |
+
def load_processed_data_in_chunks(file_path: str, max_sentences: int = 1_000_000) -> str:
|
| 6 |
+
"""Load data in chunks, up to max_sentences"""
|
| 7 |
+
buffer = []
|
| 8 |
+
sentence_count = 0
|
| 9 |
+
|
| 10 |
+
with open(file_path, 'r', encoding='utf-8') as f:
|
| 11 |
+
for line in tqdm(f, desc="Reading sentences"):
|
| 12 |
+
if sentence_count >= max_sentences:
|
| 13 |
+
break
|
| 14 |
+
|
| 15 |
+
line = line.strip()
|
| 16 |
+
if not line:
|
| 17 |
+
continue
|
| 18 |
+
|
| 19 |
+
buffer.append(line)
|
| 20 |
+
sentence_count += 1
|
| 21 |
+
|
| 22 |
+
if len(buffer) >= 10000: # Process in chunks of 10K sentences
|
| 23 |
+
yield ' '.join(buffer)
|
| 24 |
+
buffer = []
|
| 25 |
+
|
| 26 |
+
if buffer: # Don't forget the last chunk
|
| 27 |
+
yield ' '.join(buffer)
|
| 28 |
+
|
| 29 |
+
def main():
|
| 30 |
+
# Initialize paths
|
| 31 |
+
data_dir = os.path.join("..", "data")
|
| 32 |
+
processed_file = os.path.join(data_dir, "hi_processed.txt")
|
| 33 |
+
|
| 34 |
+
# Check if processed data exists
|
| 35 |
+
if not os.path.exists(processed_file):
|
| 36 |
+
print("Processed data not found. Please run download_data.py first.")
|
| 37 |
+
return
|
| 38 |
+
|
| 39 |
+
# Initialize BPE
|
| 40 |
+
print("Initializing BPE tokenizer...")
|
| 41 |
+
print("Training Parameters:")
|
| 42 |
+
print("1. Using first 1 million sentences")
|
| 43 |
+
print("2. Vocabulary size must be < 5000 tokens")
|
| 44 |
+
print("3. Compression ratio must be ≥ 3.2")
|
| 45 |
+
bpe = HindiBPE()
|
| 46 |
+
|
| 47 |
+
print("\nTraining BPE model...")
|
| 48 |
+
is_first_chunk = True
|
| 49 |
+
total_sentences = 0
|
| 50 |
+
|
| 51 |
+
for chunk in load_processed_data_in_chunks(processed_file):
|
| 52 |
+
if not chunk.strip():
|
| 53 |
+
continue
|
| 54 |
+
|
| 55 |
+
bpe.train_on_chunk(chunk, is_first_chunk=is_first_chunk)
|
| 56 |
+
is_first_chunk = False
|
| 57 |
+
|
| 58 |
+
# Check if we've met both requirements
|
| 59 |
+
test_text = chunk[:10000] # Use a sample of text
|
| 60 |
+
compression_ratio = bpe.get_compression_ratio(test_text)
|
| 61 |
+
vocab_size = len(bpe.vocab)
|
| 62 |
+
|
| 63 |
+
print(f"\nCurrent status:")
|
| 64 |
+
print(f"Vocabulary size: {vocab_size} tokens")
|
| 65 |
+
print(f"Compression ratio: {compression_ratio:.2f}")
|
| 66 |
+
|
| 67 |
+
if compression_ratio >= 3.2:
|
| 68 |
+
if vocab_size < 5000:
|
| 69 |
+
print("\nSuccess! Met all requirements:")
|
| 70 |
+
print(f"1. Vocabulary size: {vocab_size} tokens (< 5000)")
|
| 71 |
+
print(f"2. Compression ratio: {compression_ratio:.2f} (≥ 3.2)")
|
| 72 |
+
break
|
| 73 |
+
else:
|
| 74 |
+
print("\nWarning: Need to reduce vocabulary size while maintaining compression ratio")
|
| 75 |
+
|
| 76 |
+
print("\nFinal Results:")
|
| 77 |
+
print(f"Vocabulary size: {len(bpe.vocab)} tokens")
|
| 78 |
+
print(f"Compression ratio: {compression_ratio:.2f}")
|
| 79 |
+
|
| 80 |
+
# Test the model with various Hindi texts
|
| 81 |
+
test_cases = [
|
| 82 |
+
"नमस्ते भारत",
|
| 83 |
+
"मैं हिंदी सीख रहा हूं",
|
| 84 |
+
"यह एक परीक्षण वाक्य है",
|
| 85 |
+
"भारत एक विशाल देश है",
|
| 86 |
+
"मुझे हिंदी भाषा बहुत पसंद है"
|
| 87 |
+
]
|
| 88 |
+
|
| 89 |
+
print("\nTesting encoding/decoding on multiple examples:")
|
| 90 |
+
for i, test_text in enumerate(test_cases, 1):
|
| 91 |
+
print(f"\nTest case {i}:")
|
| 92 |
+
print(f"Original: {test_text}")
|
| 93 |
+
encoded = bpe.encode(test_text)
|
| 94 |
+
print(f"Encoded: {encoded}")
|
| 95 |
+
decoded = bpe.decode(encoded)
|
| 96 |
+
print(f"Decoded: {decoded}")
|
| 97 |
+
print(f"Matches: {'✓' if decoded == test_text else '✗'}")
|
| 98 |
+
|
| 99 |
+
if __name__ == "__main__":
|
| 100 |
+
main()
|