Spaces:
Sleeping
Sleeping
File size: 5,749 Bytes
2b747fd |
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 70 71 72 73 74 75 76 77 78 79 80 81 82 83 84 85 86 87 88 89 90 91 92 93 94 95 96 97 98 99 100 101 102 103 104 105 106 107 108 109 110 111 112 113 114 115 116 117 118 119 120 121 122 123 124 125 126 127 128 129 130 131 132 133 134 135 136 137 138 139 140 141 142 143 144 145 146 147 148 149 150 151 152 153 154 155 156 157 158 159 160 161 162 163 164 165 166 167 168 169 170 171 172 173 174 175 176 177 178 179 180 181 182 183 184 185 186 187 188 189 190 191 192 193 194 195 196 |
"""
Organization Code Generator - Creates unique, memorable codes for organizations
Format: [Initials(3)][Year(2)][Sequence(3)] = e.g., "FWL25001"
"""
from datetime import datetime
from sqlalchemy.orm import Session
from app.models.client import Client
from app.models.contractor import Contractor
def extract_initials(org_name: str, max_length: int = 3) -> str:
"""
Extract initials from organization name.
Rules:
- Take first letter of each word (up to max_length)
- If single word, take first max_length characters
- Convert to uppercase
- Remove special characters
Examples:
"FiberWorks Ltd" -> "FWL"
"TechInstall" -> "TEC"
"ABC Corp" -> "ABC"
"M" -> "M"
"""
# Remove special characters and extra spaces
cleaned = ''.join(c if c.isalnum() or c.isspace() else ' ' for c in org_name)
words = cleaned.split()
if not words:
return "ORG" # Fallback
# If multiple words, take first letter of each
if len(words) > 1:
initials = ''.join(word[0].upper() for word in words if word)[:max_length]
else:
# Single word: take first N characters
initials = words[0][:max_length].upper()
# Ensure minimum length of 1
return initials if initials else "ORG"
def find_next_sequence(prefix: str, year_suffix: str, db: Session) -> int:
"""
Find the next available sequence number for the given prefix+year.
Searches both clients and contractors tables for codes matching pattern.
Returns next available sequence number (1-999).
Args:
prefix: The initials prefix (e.g., "FWL")
year_suffix: Two-digit year (e.g., "25")
db: Database session
Returns:
Next available sequence number (1-999)
"""
pattern = f"{prefix}{year_suffix}%"
# Find all codes matching this pattern in both tables
client_codes = db.query(Client.swiftops_code).filter(
Client.swiftops_code.like(pattern)
).all()
contractor_codes = db.query(Contractor.swiftops_code).filter(
Contractor.swiftops_code.like(pattern)
).all()
# Extract sequence numbers
existing_sequences = set()
all_codes = [c[0] for c in client_codes] + [c[0] for c in contractor_codes]
for code in all_codes:
if code and len(code) >= 8: # Expected format: XXX25NNN
try:
# Extract last 3 digits
sequence = int(code[-3:])
existing_sequences.add(sequence)
except ValueError:
continue
# Find next available sequence (1-999)
for seq in range(1, 1000):
if seq not in existing_sequences:
return seq
# If all 999 slots are taken, raise error
raise ValueError(f"All sequence numbers exhausted for prefix {prefix}{year_suffix}")
def generate_org_code(org_name: str, db: Session) -> str:
"""
Generate a unique SwiftOps code for an organization.
Format: [Initials(3)][Year(2)][Sequence(3)]
Example: "FWL25001" for FiberWorks Ltd in 2025
Args:
org_name: The organization name
db: Database session for checking uniqueness
Returns:
Unique 8-character organization code
Raises:
ValueError: If unable to generate unique code
"""
# Extract initials (up to 3 characters)
initials = extract_initials(org_name, max_length=3)
# Get current year suffix (last 2 digits)
year_suffix = str(datetime.now().year)[-2:]
# Find next available sequence number
sequence = find_next_sequence(initials, year_suffix, db)
# Format code
code = f"{initials}{year_suffix}{sequence:03d}"
return code
def validate_org_code_format(code: str) -> bool:
"""
Validate that a code follows the expected format.
Format: [Initials(1-3)][Year(2)][Sequence(3)]
Length: 6-8 characters
Args:
code: The code to validate
Returns:
True if valid format, False otherwise
"""
if not code or not isinstance(code, str):
return False
# Length should be 6-8 characters
if not (6 <= len(code) <= 8):
return False
# Should be alphanumeric
if not code.isalnum():
return False
# Should be uppercase
if not code.isupper():
return False
# Last 3 characters should be digits
if not code[-3:].isdigit():
return False
# Characters before last 5 should be letters (initials)
if len(code) >= 5:
initials_part = code[:-5]
if initials_part and not initials_part.isalpha():
return False
return True
def is_code_available(code: str, db: Session, exclude_id: int = None, org_type: str = None) -> bool:
"""
Check if an organization code is available (not in use).
Args:
code: The code to check
db: Database session
exclude_id: Optional ID to exclude (for updates)
org_type: Optional org type filter ('client' or 'contractor')
Returns:
True if code is available, False if already in use
"""
# Check clients
if org_type != 'contractor':
query = db.query(Client).filter(Client.swiftops_code == code)
if exclude_id:
query = query.filter(Client.id != exclude_id)
if query.first():
return False
# Check contractors
if org_type != 'client':
query = db.query(Contractor).filter(Contractor.swiftops_code == code)
if exclude_id:
query = query.filter(Contractor.id != exclude_id)
if query.first():
return False
return True
|