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demo.yaml

@@ -4,29 +4,38 @@ lite_metadata:
 class_string: gradio.interface.Interface
 kwargs:
   title: gitio date regex
-  description: Given list of strings, create regex to extract dates
+  description: Given two numbers, find the lowest common factor and subtract it from
+    100
   article: null
   thumbnail: null
   theme: gradio/seafoam
   css: null
   allow_flagging: never
   inputs:
-  - class_string: gradio.components.Dataframe
+  - class_string: gradio.components.Number
     kwargs:
-      label: strings
-      type: array
+      label: num1
+      precision: 0
+  - class_string: gradio.components.Number
+    kwargs:
+      label: num2
+      precision: 0
   outputs:
-  - class_string: gradio.components.Dataframe
+  - class_string: gradio.components.Number
     kwargs:
       label: output
-      type: array
+      precision: 0
   fn:
     class_string: gradify.gradify_closure
     kwargs:
       argmaps:
-      - label: strings
-        postprocessing: 'lambda array: list(map(str, array[0]))'
+      - label: num1
+        postprocessing: null
+      - label: num2
+        postprocessing: null
       func_kwargs: {}
-      source: "import re\n\n\ndef extract_dates(strings):\n    regex = '\\\\d{1,2}/\\\
-        \\d{1,2}/\\\\d{4}'\n    dates = []\n    for string in strings:\n        dates\
-        \ += re.findall(regex, string)\n    return dates\n"
+      source: "def lowest_common_factor(num1, num2):\n    factors1 = set()\n    factors2\
+        \ = set()\n    for i in range(1, num1 + 1):\n        if num1 % i == 0:\n \
+        \           factors1.add(i)\n    for i in range(1, num2 + 1):\n        if\
+        \ num2 % i == 0:\n            factors2.add(i)\n    common_factors = factors1.intersection(factors2)\n\
+        \    return 100 - min(common_factors) if common_factors else 100\n"