Upload 71 files

.dockerignore

@@ -0,0 +1,8 @@
+__pycache__/
+*.pyc
+*.pyo
+*.pyd
+.env
+node_modules/
+.git
+.idea

.gitignore

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+# Ignore Python cache and environments
+__pycache__/
+*.pyc
+.env
+
+# Ignore node_modules and build files
+Frontend/react-app/node_modules/
+Frontend/react-app/build/
+
+# Ignore IDE and system files
+.idea/
+.vscode/
+*.log

Dockerfile

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+FROM python:3.13-slim
+
+
+# Create base working directory inside the container
+WORKDIR /app
+
+# Copy requirements file from your Backend folder
+COPY requirements.txt .
+
+# Install dependencies
+RUN pip install --no-cache-dir -r requirements.txt
+
+# Copy entire Backend folder to /app/Backend inside container
+COPY . /app
+
+RUN apt-get update && apt-get install -y ffmpeg
+
+# Expose the FastAPI port
+EXPOSE 7860
+
+CMD ["uvicorn", "main:app", "--host", "0.0.0.0", "--port", "7860"]

agents/feedback_agent.py

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+import sys
+import os
+import json
+import dspy
+from datetime import datetime
+
+# path setup
+sys.path.append(os.path.abspath(os.path.join(os.path.dirname(__file__), "../..")))
+
+from agents.routing_agent import route_query as math_agent
+
+FEEDBACK = os.path.join("data", "feedback_log.json")
+
+# DSPy setup
+lm = dspy.LM(
+    model="groq/llama-3.1-8b-instant",
+    api_key=os.getenv("GROQ_API_KEY")
+)
+
+dspy.settings.configure(lm=lm)
+
+
+class MathReasoner(dspy.Module):
+
+    def __init__(self):
+        super().__init__()
+        self.prog = dspy.ChainOfThought("question -> answer")
+
+    def forward(self, question):
+        return self.prog(question=question)
+
+
+# -------- DSPY HITL AGENT --------
+class ClarificationAgent(dspy.Module):
+
+    def __init__(self):
+        super().__init__()
+        self.generator = dspy.ChainOfThought("question -> clarification")
+
+    def forward(self, question):
+        return self.generator(question=question)
+
+
+clarifier = ClarificationAgent()
+
+
+def ask_for_clarification(question: str):
+
+    result = clarifier(question=question)
+
+    return result.clarification
+
+
+# -------- SAVE FEEDBACK (MEMORY) --------
+def save_feedback(
+    query: str,
+    answer: str,
+    feedback: str,
+    rating: str = None,
+    parsed_question: dict = None,
+    retrieved_context: str = None,
+    verifier_outcome: str = None
+):
+
+    entry = {
+        "timestamp": datetime.utcnow().isoformat(),
+        "original_input": query,
+        "parsed_question": parsed_question,
+        "retrieved_context": retrieved_context,
+        "final_answer": answer,
+        "verifier_outcome": verifier_outcome,
+        "user_feedback": feedback,
+        "rating": rating
+    }
+
+    if not os.path.exists(FEEDBACK):
+        with open(FEEDBACK, "w") as f:
+            json.dump([], f)
+
+    with open(FEEDBACK, "r+") as f:
+
+        data = json.load(f)
+        data.append(entry)
+
+        f.seek(0)
+        json.dump(data, f, indent=4)
+
+    print("🧠 Feedback stored in memory.")
+
+
+# -------- MEMORY RETRIEVAL --------
+def retrieve_similar(query: str):
+
+    if not os.path.exists(FEEDBACK):
+        return None
+
+    with open(FEEDBACK, "r") as f:
+        data = json.load(f)
+
+    for item in data:
+
+        if query.lower() in item["original_input"].lower():
+            return item
+
+    return None
+
+
+# -------- MODEL TUNING --------
+def tuning(query, incorrect_answer, rating: str = None):
+
+    example = [
+        dspy.Example(
+            question=query,
+            answer="its incorrect"
+        ).with_inputs("question"),
+    ]
+
+    def simple_metric(example, pred, trace=None):
+
+        try:
+            gold_answer = example.answer.lower().strip()
+            pred_answer = pred.answer.lower().strip()
+
+            return 1.0 if gold_answer == pred_answer else 0.0
+
+        except:
+            return 0.0
+
+
+    class MathAgentWrapper(dspy.Module):
+
+        def forward(self, question):
+
+            result = math_agent(question)
+
+            return dspy.Prediction(answer=result)
+
+
+    wrapper_model = MathAgentWrapper()
+
+    trainer = dspy.BootstrapFewShot(
+        metric=simple_metric,
+        max_bootstrapped_demos=1,
+        max_labeled_demos=1
+    )
+
+    trainer.compile(wrapper_model, trainset=example)
+
+    print("🧠 Model updated based on feedback.")
+
+
+# -------- ANSWER WITH MEMORY --------
+def answer(query: str):
+
+    memory = retrieve_similar(query)
+
+    if memory:
+        print("⚡ Using stored solution from memory.")
+        return memory["final_answer"]
+
+    result = math_agent(query)
+
+    return result

agents/math_solver.py

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+import re
+import sympy as sp
+
+def try_math_solver(query: str) -> str:
+    q = query.lower().strip()
+    # Remove filler words that confuse sympy
+    q = re.sub(r'\b(what is|calculate|find|compute|equals?|result of|area of|value of|solve)\b', '', q)
+    q = q.strip()
+
+    # Handle "where x = 5" style variable substitution
+    variables = dict(re.findall(r'(\w+)\s*=\s*([\d\.]+)', q))
+    for var in variables:
+        q = re.sub(rf"\b{var}\s*=\s*{variables[var]}\b", '', q)
+    q = re.sub(r'\bwhere\b', '', q)
+
+    # Handle patterns like “add 2 and 5”
+    patterns = [
+        (r'addition of (\d+(?:\.\d+)?) and (\d+(?:\.\d+)?)', r'(\1 + \2)'),
+        (r'add (\d+(?:\.\d+)?) and (\d+(?:\.\d+)?)', r'(\1 + \2)'),
+        (r'subtract (\d+(?:\.\d+)?) from (\d+(?:\.\d+)?)', r'(\2 - \1)'),
+        (r'subtract (\d+(?:\.\d+)?) and (\d+(?:\.\d+)?)', r'(\1 - \2)'),
+        (r'multiply (\d+(?:\.\d+)?) by (\d+(?:\.\d+)?)', r'(\1 * \2)'),
+        (r'divide (\d+(?:\.\d+)?) by (\d+(?:\.\d+)?)', r'(\1 / \2)'),
+        (r'(\d+(?:\.\d+)?) power (\d+(?:\.\d+)?)', r'(\1 ** \2)'),
+        (r'square root of (\d+(?:\.\d+)?)', r'sqrt(\1)'),
+    ]
+    for pat, repl in patterns:
+        q = re.sub(pat, repl, q)
+
+    # Replace simple words with symbols
+    replacements = {
+        "plus": "+", "minus": "-", "times": "*", "x": "*",
+        "mod": "%", "modulus": "%", "divided by": "/",
+        "power of": "**", "power": "**"
+    }
+    for word, sym in replacements.items():
+        q = re.sub(rf"\b{word}\b", sym, q)
+
+    # Remove assignments like “area =”
+    q = re.sub(r'\b\w+\s*=\s*', '', q).strip()
+
+    # Allow safe math functions
+    allowed_funcs = {
+        "sqrt": sp.sqrt, "sin": sp.sin, "cos": sp.cos, "tan": sp.tan,
+        "log": sp.log, "pi": sp.pi, "e": sp.E
+    }
+
+    try:
+        expr = sp.sympify(q, locals=allowed_funcs)
+        if variables:
+            subs = {sp.Symbol(k): float(v) for k, v in variables.items()}
+            expr = expr.subs(subs)
+        result = expr.evalf()
+        return f"The answer is {result}"
+    except Exception as e:
+        return f"Sorry, couldn't solve that expression. ({e})"
+
+
+if __name__ == "__main__":
+    tests = [
+        "addition of 2 and 5",
+        "add 10 and 20",
+        "what is 12 minus 5",
+        "multiply 6 by 3",
+        "divide 15 by 3",
+        "10 power 2",
+        "100 mod 3",
+        "square root of 81",
+        "2 + 5 * 3",
+        "area = pi * r^2 where r = 5"
+    ]
+    for t in tests:
+        print(f"{t} → {try_math_solver(t)}")
+

agents/parser_agent.py

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+import re
+
+
+def parse_problem(text: str):
+
+    cleaned_text = text.strip()
+    cleaned_text = re.sub(r"\s+", " ", cleaned_text)
+
+    # Extract variables
+    variables = list(set(re.findall(r"[a-zA-Z]", cleaned_text)))
+
+    # Extract constraints
+    constraints = re.findall(r"[a-zA-Z]\s*[><=]+\s*\d+", cleaned_text)
+
+    # Topic detection
+    topic = "general"
+
+    text_lower = cleaned_text.lower()
+
+    if "probability" in text_lower:
+        topic = "probability"
+
+    elif "matrix" in text_lower:
+        topic = "linear_algebra"
+
+    elif "derivative" in text_lower:
+        topic = "calculus"
+
+    elif "solve" in text_lower:
+        topic = "algebra"
+
+    # Check ambiguity
+    needs_clarification = False
+
+    if len(cleaned_text.split()) < 3:
+        needs_clarification = True
+
+    return {
+        "problem_text": cleaned_text,
+        "topic": topic,
+        "variables": variables,
+        "constraints": constraints,
+        "needs_clarification": needs_clarification
+    }

agents/routing_agent.py

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+from langchain_community.embeddings import HuggingFaceEmbeddings
+from langchain_community.vectorstores import FAISS
+from agents.math_solver import try_math_solver
+import os
+import re
+
+
+def route_query(query: str):
+    persist_dir = os.path.join("data", "embeddings")
+
+    # ✅ Load embeddings
+    embeddings = HuggingFaceEmbeddings(model_name="sentence-transformers/all-MiniLM-L6-v2")
+    vectordb = FAISS.load_local(persist_dir, embeddings, allow_dangerous_deserialization=True)
+
+    # ✅ Step 1: Search in FAISS
+    results = vectordb.similarity_search_with_score(query, k=1)
+
+    # ✅ If found in FAISS
+    if results and results[0][1] < 0.4:
+        print("📘 Answer is on data.txt")
+        return "KO"
+
+    else:
+        # ✅ Step 2: Try math solver
+        print("🧮 Not found in FAISS — trying math solver...")
+        solver_result = try_math_solver(query)
+        print(f"🧩 Solver result: {solver_result}")
+
+        # ✅ Check if math solver succeeded
+        if solver_result and not any(bad in solver_result.lower() for bad in [
+            "sorry", "couldn't", "could not", "error", "invalid", "failed"
+        ]):
+            print("✅ Math solver succeeded!")
+            return solver_result
+
+        # ✅ If not solved by FAISS or math solver → LLM
+        print("🌐 Not found anywhere — going for LLM")
+        return "LLM"

agents/vector_db.py

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+import warnings
+warnings.filterwarnings("ignore", category=UserWarning)
+
+import os
+from langchain_community.document_loaders import DirectoryLoader, TextLoader
+from langchain_text_splitters import RecursiveCharacterTextSplitter
+from langchain_community.embeddings import HuggingFaceEmbeddings
+from langchain_community.vectorstores import FAISS
+
+def create_text():
+    # Define paths
+    kb_path = os.path.join("data")  # your text files folder
+    persist_dir = os.path.join("data", "embeddings")
+
+    # if exist
+    os.makedirs(kb_path, exist_ok=True)
+    os.makedirs(persist_dir, exist_ok=True)
+
+    # Load all text files from folder
+    loader = DirectoryLoader(kb_path, glob="*.txt", loader_cls=TextLoader)
+    documents = loader.load()
+
+    if not documents:
+        print("⚠️ No text files found in data folder!")
+        return
+
+    # Split long text into chunks for embedding
+    text_splitter = RecursiveCharacterTextSplitter(chunk_size=1000, chunk_overlap=200)
+    chunks = text_splitter.split_documents(documents)
+
+    # Load embedding model
+    embeddings = HuggingFaceEmbeddings(model_name="sentence-transformers/all-MiniLM-L6-v2")
+
+    # Create FAISS vector DB from documents
+    vectordb = FAISS.from_documents(chunks, embeddings)
+
+    # Save it locally
+    vectordb.save_local(persist_dir)
+
+    print("vector database created", persist_dir)
+    return vectordb
+
+

agents/web_agent.py

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+from utils.mcp_client import run_math_agent
+def answer_from_web(query):
+    return run_math_agent(query)

data/__init__.py

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+# This file makes Python treat this directory as a package

data/data.txt

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+Q: What is the Pythagoras theorem?
+A: In a right-angled triangle, the square of the hypotenuse is equal to the sum of the squares of the other two sides. Mathematically: a² + b² = c².
+
+Q: What is the quadratic formula?
+A: For a quadratic equation ax² + bx + c = 0, the roots are given by: x = (-b ± √(b² - 4ac)) / 2a.
+
+Q: What is the derivative of x²?
+A: The derivative of x² with respect to x is 2x.
+
+Q: What is the integral of x²?
+A: The integral of x² with respect to x is (x³ / 3) + C, where C is the constant of integration.
+
+Q: What is the area of a circle?
+A: The area of a circle is given by A = πr², where r is the radius.
+
+Q: What is the circumference of a circle?
+A: The circumference of a circle is given by C = 2πr, where r is the radius.
+
+Q: What is the slope of a line passing through points (x1, y1) and (x2, y2)?
+A: The slope is given by m = (y2 - y1) / (x2 - x1).
+
+Q: What is the formula for simple interest?
+A: Simple Interest = (Principal × Rate × Time) / 100.
+
+Q: What is the formula for compound interest?
+A: Compound Interest = Principal × (1 + Rate/100)^Time - Principal.
+
+Q: What is the derivative of sin(x)?
+A: The derivative of sin(x) is cos(x).
+
+Q: What is the derivative of cos(x)?
+A: The derivative of cos(x) is -sin(x).
+
+Q: What is the integral of sin(x)?
+A: The integral of sin(x) is -cos(x) + C.
+
+Q: What is the integral of cos(x)?
+A: The integral of cos(x) is sin(x) + C.
+
+Q: What is the distance formula in coordinate geometry?
+A: The distance between points (x1, y1) and (x2, y2) is √((x2 - x1)² + (y2 - y1)²).
+
+Q: What is the midpoint formula?
+A: The midpoint of a line joining (x1, y1) and (x2, y2) is ((x1 + x2)/2, (y1 + y2)/2).
+
+Q: What is the sum of the first n natural numbers?
+A: The sum is given by S = n(n + 1)/2.
+
+Q: What is the sum of the first n even numbers?
+A: The sum is n(n + 1).
+
+Q: What is the sum of the first n odd numbers?
+A: The sum is n².
+
+Q: What is the formula for the area of a triangle?
+A: Area = ½ × base × height.
+
+Q: What is the trigonometric identity involving sin²(x) and cos²(x)?
+A: sin²(x) + cos²(x) = 1.
+
+Q: What is the binomial theorem?
+A: The binomial theorem states that (a + b)^n = Σ [nCk * a^(n-k) * b^k], where the summation runs from k = 0 to n.
+
+Q: What is the limit of sin(x)/x as x approaches 0?
+A: The limit of sin(x)/x as x → 0 is 1.
+
+Q: What is the derivative of e^x?
+A: The derivative of e^x with respect to x is e^x.
+
+Q: What is the derivative of ln(x)?
+A: The derivative of ln(x) with respect to x is 1/x.
+
+Q: What is the area under y = x between 0 and 2?
+A: The area is ∫(0 to 2) x dx = [x² / 2]₀² = 2.
+
+Q: What is the perimeter of a rectangle?
+A: The perimeter of a rectangle is 2 × (length + width).
+
+Q: What is the formula for volume of a sphere?
+A: Volume = (4/3)πr³.
+
+Q: What is the surface area of a sphere?
+A: Surface Area = 4πr².
+
+Q: What is the mean of numbers 4, 8, and 12?
+A: Mean = (4 + 8 + 12) / 3 = 8.
+
+Q: What is the median of the numbers 3, 5, 7, 9, 11?
+A: The median is 7.
+
+Q: What is the mode of the numbers 2, 3, 3, 5, 7?
+A: The mode is 3.

data/embeddings/index.pkl

@@ -0,0 +1,3 @@
+version https://git-lfs.github.com/spec/v1
+oid sha256:2cf3b3fcdfb8202be6e4a12816b8b4ce8f98abb6c763a74de741d4aa3151394c
+size 4343

data/feedback_log.json

@@ -0,0 +1,171 @@
+[
+    {
+        "timestamp": "2025-10-28T23:44:33.438347",
+        "query": "What is the integral of sin(x)?",
+        "answer": "WEB",
+        "feedback": "Incorrect \u2014 the correct answer is -cos(x) + C"
+    },
+    {
+        "timestamp": "2025-10-28T23:47:37.610680",
+        "query": "What is the integral of sin(x)?",
+        "answer": "WEB",
+        "feedback": "Incorrect \u2014 the correct answer is -cos(x) + C"
+    },
+    {
+        "timestamp": "2025-10-28T23:50:34.812828",
+        "query": "What is the integral of sin(x)?",
+        "answer": "WEB",
+        "feedback": "Incorrect \u2014 the correct answer is -cos(x) + C"
+    },
+    {
+        "timestamp": "2025-10-28T23:52:07.815951",
+        "query": "What is the integral of sin(x)?",
+        "answer": "WEB",
+        "feedback": "Incorrect \u2014 the correct answer is -cos(x) + C"
+    },
+    {
+        "timestamp": "2025-10-28T23:55:11.166467",
+        "query": "What is the integral of sin(x)?",
+        "answer": "WEB",
+        "feedback": "Incorrect \u2014 the correct answer is -cos(x) + C"
+    },
+    {
+        "timestamp": "2025-10-28T23:58:22.966961",
+        "query": "What is the integral of sin(x)?",
+        "answer": "WEB",
+        "feedback": "Incorrect \u2014 the correct answer is -cos(x) + C"
+    },
+    {
+        "timestamp": "2025-10-28T23:59:57.870620",
+        "query": "What is the integral of sin(x)?",
+        "answer": "WEB",
+        "feedback": "Incorrect \u2014 the correct answer is -cos(x) + C"
+    },
+    {
+        "timestamp": "2025-10-29T00:01:47.611761",
+        "query": "What is the integral of sin(x)?",
+        "answer": "WEB",
+        "feedback": "Incorrect \u2014 the correct answer is -cos(x) + C"
+    },
+    {
+        "timestamp": "2025-10-29T00:03:41.277987",
+        "query": "What is the integral of sin(x)?",
+        "answer": "WEB",
+        "feedback": "Incorrect \u2014 the correct answer is -cos(x) + C"
+    },
+    {
+        "timestamp": "2025-10-29T00:13:19.920208",
+        "query": "What is the integral of sin(x)?",
+        "answer": "WEB",
+        "feedback": "Incorrect \u2014 the correct answer is -cos(x) + C"
+    },
+    {
+        "timestamp": "2025-10-29T00:15:51.787155",
+        "query": "What is the integral of sin(x)?",
+        "answer": "WEB",
+        "feedback": "Incorrect \u2014 the correct answer is -cos(x) + C"
+    },
+    {
+        "timestamp": "2025-10-29T00:17:35.253793",
+        "query": "What is the integral of sin(x)?",
+        "answer": "WEB",
+        "feedback": "Incorrect \u2014 the correct answer is -cos(x) + C"
+    },
+    {
+        "timestamp": "2025-10-29T00:20:26.191961",
+        "query": "What is the integral of sin(x)?",
+        "answer": "WEB",
+        "feedback": "Incorrect \u2014 the correct answer is -cos(x) + C"
+    },
+    {
+        "timestamp": "2025-10-29T00:21:49.889546",
+        "query": "What is the integral of sin(x)?",
+        "answer": "WEB",
+        "feedback": "Incorrect \u2014 the correct answer is -cos(x) + C"
+    },
+    {
+        "timestamp": "2025-10-29T00:29:02.417399",
+        "query": "What is the integral of sin(x)?",
+        "answer": "WEB",
+        "feedback": "Incorrect \u2014 the correct answer is -cos(x) + C"
+    },
+    {
+        "timestamp": "2025-10-29T00:30:43.568817",
+        "query": "What is the integral of sin(x)?",
+        "answer": "WEB",
+        "feedback": "Incorrect \u2014 the correct answer is -cos(x) + C"
+    },
+    {
+        "timestamp": "2025-10-29T10:11:22.019712",
+        "query": "What is the integral of sin(x)?",
+        "answer": "WEB",
+        "feedback": "Incorrect \u2014 the correct answer is -cos(x) + C"
+    },
+    {
+        "timestamp": "2025-10-29T11:35:41.805717",
+        "query": "integration of sin(x)",
+        "answer": "The integral of sin(x) sin ( x ) with respect to x x is \u2212cos(x) - cos ( x ) . \u2212cos(x)+C - cos ( x ) + C. sin(x) s i n \u2061 ( x ) Mathematically, this is written as **\u222b sin x dx = -cos x + C**, were, C is the integration constant. * \u222b sin x dx = -cos x + C, where C is the constant of integration. \u222b sin x dx = -cos x + C -cos x + C = \u222b sin x dx **Answer:** \u222b sin x cos x dx = (-cos 2x)/4 + C \u222b sin u (1/2) du = (1/2) (-cos u) + C (as the integration of sin x is -cos x) **Answer:**  \u222b x sin (x2) dx = (-cos x2)/2+C The integral of sin x is -cos x + C. Substituting u = 3x back, we get \u222b sin 3x dx = (1/3) (-cos (3x)) + C. Integral of sin(x)\nblackpenredpen\n1380000 subscribers\n1082 likes\n200320 views\n22 Feb 2015\nThe integral of sin(x) is just -cos(x)+C because the derivative of -cos(x) is sin(x).\n\nCheck out my 100 integrals for more calculus integral practice problems. https://youtu.be/dgm4-3-Iv3s?si=lTybJlpTMFdQINXr\n----------------------------------------\n\ud83d\udecd  Shop my math t-shirt & hoodies: amzn.to/3qBeuw6\n\ud83d\udcaa Get my math notes by becoming a patron:  https://www.patreon.com/blackpenredpen\n#blackpenredpen #math #calculus #apcalculus\n57 comments\n Our rough (rough!) conversion to Plain English is: The integral of sin(x) multiplies our intended path length (from 0 to x) by a percentage. # Integral of Sin x * What is Integral of Sin x? * Integral of Sin x From 0 to \u03c0 * Integral of Sin x From 0 to \u03c0/2 ## ****What is Integral of Sin x?**** The integral of the sine function, \u222b sin(x) dx, is equal to -cos(x) + C, where C is the constant of integration. Integral of sin(x) dx = -\u222b du Integral of sin(x) dx = -u + C Integral of sin(x) dx = -cos(x) + C ## ****Integral of Sin x From 0 to**** \u03c0 ## ****Integral of Sin x From 0 to**** \u03c0****/2**** ****Example 7: Find integral of x sin 2x dx**** ****Example 8: Find integral of sin x cos 2x****",
+        "feedback": "please give in 50 words"
+    },
+    {
+        "timestamp": "2025-10-29T19:15:40.383977",
+        "query": "What is the integral of sin(x)?",
+        "answer": "WEB",
+        "feedback": "Incorrect \u2014 the correct answer is -cos(x) + C"
+    },
+    {
+        "query": "derivative of sin(x)",
+        "answer": "The derivative of the sine function, sin\u2061(x), is the cosine function, cos\u2061(x). Mathematically, if f(x)=sin(x), then f\u2032(x)=cos\u2061(x). This result Here also we are going to prove the derivative of sin x to be -cos x using the first principle. The derivative of sin x is cos x. Thus, we have proved that the derivative of sin x is cos x. Therefore, the derivative of sin is cos x and is proved by using the quotient rule. Derivative of Sin x Worksheet Therefore, the derivative of sin x is cos x. * The derivative of sin x is cos x. Thus, the derivative of sin 3x is 3 cos 3x. Therefore, the derivative of sin x by first principle is cos x. We know that the derivative of sin x is cos x. So the derivative of sin x2 using this and using the chain rule is cos x2\u00b7 d/dx(x2). ## Derivative of sin x using the First Principle Method f\u2019(x) = limh\u21920 [sin x cos h + cos x sin h \u2013 sin x]/h f\u2019(x) = limh\u21920 [-sin x(1-cosh) + cos x sin h]/h sin (0/2)) + cos x (1) f\u2019(x) = \u2013 sin x(0) + cos x Thus, the derivative of sin x is cos x, is derived. ### Derivative of Sin x Examples Now, we have to find the derivative of sin (x+1), using the 1st principle. Hence, the derivative of sin (x+1), with respect to x is cos (x+1). Find the derivative of sin 2x. **To find:** derivative of sin 2x. Hence, the derivative of sin 2x is 2 cos 2x. ddx[sinx]=cosx Certainly, by the limit definition of the derivative, we know that ddx[sinx]=limh\u21920sin(x+h)\u2212sin(x)h ddx[sinx]=limh\u21920sinxcosh+cosxsinh\u2212sinxh Seeing all of the components of a similar limit in our expression for the derivative, (i.e., there is a sinh in the numerator, an h in the denominator, and both of these are inside a limit as h\u21920), we use algebra and the limit laws to reveal this known limit in our expression: ddx[sinx]=limh\u21920[cosxsinhh+sinxcosh\u2212sinxh]=limh\u21920[cosx\u22c5sinhh+sinxcosh\u2212sinxh]=limh\u21920cosx\u22c5limh\u21920sinhh+limh\u21920sinxcosh\u2212sinxh Note, the first limit in the last line above is of an expression that does not depend on h, and hence effectively the limit of a constant. ddx[sinx]=cosx+limh\u21920sinxcosh\u2212sinxh Pulling out the common factor of sinx in the remaining limit and splitting the resulting product with the limit laws again, we see another familiar limit -- one we which we know equals zero... ddx[sinx]=cosx+limh\u21920sinx(cosh\u22121)h=cosx+[limh\u21920sinx]\u22c5[limh\u21920cosh\u22121h]=cosx+sinx\u22c50=cosx d/dx(sin x) = \u03c0/180 cos x \"\"\" Which seems to suggest that the d/dx sin(x) is not equal to the cos(x) when degrees are used. That a constant must",
+        "feedback": "its cos(x)+c"
+    },
+    {
+        "query": "derivative of sin(x)",
+        "answer": "The derivative of the sine function, sin\u2061(x), is the cosine function, cos\u2061(x). Mathematically, if f(x)=sin(x), then f\u2032(x)=cos\u2061(x). This result Here also we are going to prove the derivative of sin x to be -cos x using the first principle. The derivative of sin x is cos x. Thus, we have proved that the derivative of sin x is cos x. Therefore, the derivative of sin is cos x and is proved by using the quotient rule. Derivative of Sin x Worksheet Therefore, the derivative of sin x is cos x. * The derivative of sin x is cos x. Thus, the derivative of sin 3x is 3 cos 3x. Therefore, the derivative of sin x by first principle is cos x. We know that the derivative of sin x is cos x. So the derivative of sin x2 using this and using the chain rule is cos x2\u00b7 d/dx(x2). ## Derivative of sin x using the First Principle Method f\u2019(x) = limh\u21920 [sin x cos h + cos x sin h \u2013 sin x]/h f\u2019(x) = limh\u21920 [-sin x(1-cosh) + cos x sin h]/h sin (0/2)) + cos x (1) f\u2019(x) = \u2013 sin x(0) + cos x Thus, the derivative of sin x is cos x, is derived. ### Derivative of Sin x Examples Now, we have to find the derivative of sin (x+1), using the 1st principle. Hence, the derivative of sin (x+1), with respect to x is cos (x+1). Find the derivative of sin 2x. **To find:** derivative of sin 2x. Hence, the derivative of sin 2x is 2 cos 2x. ddx[sinx]=cosx Certainly, by the limit definition of the derivative, we know that ddx[sinx]=limh\u21920sin(x+h)\u2212sin(x)h ddx[sinx]=limh\u21920sinxcosh+cosxsinh\u2212sinxh Seeing all of the components of a similar limit in our expression for the derivative, (i.e., there is a sinh in the numerator, an h in the denominator, and both of these are inside a limit as h\u21920), we use algebra and the limit laws to reveal this known limit in our expression: ddx[sinx]=limh\u21920[cosxsinhh+sinxcosh\u2212sinxh]=limh\u21920[cosx\u22c5sinhh+sinxcosh\u2212sinxh]=limh\u21920cosx\u22c5limh\u21920sinhh+limh\u21920sinxcosh\u2212sinxh Note, the first limit in the last line above is of an expression that does not depend on h, and hence effectively the limit of a constant. ddx[sinx]=cosx+limh\u21920sinxcosh\u2212sinxh Pulling out the common factor of sinx in the remaining limit and splitting the resulting product with the limit laws again, we see another familiar limit -- one we which we know equals zero... ddx[sinx]=cosx+limh\u21920sinx(cosh\u22121)h=cosx+[limh\u21920sinx]\u22c5[limh\u21920cosh\u22121h]=cosx+sinx\u22c50=cosx d/dx(sin x) = \u03c0/180 cos x \"\"\" Which seems to suggest that the d/dx sin(x) is not equal to the cos(x) when degrees are used. That a constant must",
+        "feedback": "its cos(x)+c",
+        "rating": null
+    },
+    {
+        "query": "derivative of sinx",
+        "answer": "The derivative of sin x is cos x, which is the rate of change of the sine function at any given point. Here also we are going to prove the derivative of sin x to be -cos x using the first principle. The derivative of sin x is cos x. Thus, we have proved that the derivative of sin x is cos x. Therefore, the derivative of sin is cos x and is proved by using the quotient rule. Derivative of Sin x Worksheet Therefore, the derivative of sin x is cos x. * The derivative of sin x is cos x. Thus, the derivative of sin 3x is 3 cos 3x. Therefore, the derivative of sin x by first principle is cos x. We know that the derivative of sin x is cos x. So the derivative of sin x2 using this and using the chain rule is cos x2\u00b7 d/dx(x2). ## Derivative of sin x using the First Principle Method f\u2019(x) = limh\u21920 [sin x cos h + cos x sin h \u2013 sin x]/h f\u2019(x) = limh\u21920 [-sin x(1-cosh) + cos x sin h]/h sin (0/2)) + cos x (1) f\u2019(x) = \u2013 sin x(0) + cos x Thus, the derivative of sin x is cos x, is derived. ### Derivative of Sin x Examples Now, we have to find the derivative of sin (x+1), using the 1st principle. Hence, the derivative of sin (x+1), with respect to x is cos (x+1). Find the derivative of sin 2x. **To find:** derivative of sin 2x. Hence, the derivative of sin 2x is 2 cos 2x. : r/calculus : r/calculus Image 1: r/calculus icon Go to calculus r/calculus Image 3: r/calculus iconr/calculus Welcome to r/calculus - a space for learning calculus and related disciplines. We learned in class that the derivative of sin(x) is cos(x). New to Reddit? * Reddit reReddit: Top posts of October 6, 2016 * * * * Reddit reReddit: Top posts of October 2016 * * * * Reddit reReddit: Top posts of 2016 * * * * Reddit Meta * Games * Gaming News & Discussion * Other Games * Action Movies & Series * Animated Movies & Series * Comedy Movies & Series * Romance Movies & Series * Superhero Movies & Series * About Reddit * Best of Reddit ddx[sinx]=cosx Certainly, by the limit definition of the derivative, we know that ddx[sinx]=limh\u21920sin(x+h)\u2212sin(x)h ddx[sinx]=limh\u21920sinxcosh+cosxsinh\u2212sinxh Seeing all of the components of a similar limit in our expression for the derivative, (i.e., there is a sinh in the numerator, an h in the denominator, and both of these are inside a limit as h\u21920), we use algebra and the limit laws to reveal this known limit in our expression: ddx[sinx]=limh\u21920[cosxsinhh+sinxcosh\u2212sinxh]=limh\u21920[cosx\u22c5sinhh+sinxcosh\u2212sinxh]=limh\u21920cosx\u22c5limh\u21920sinhh+limh\u21920sinxcosh\u2212sinxh Note, the first limit in the last line above is of an expression that does not depend on h, and hence effectively the limit of a constant. ddx[sinx]=cosx+limh\u21920sinxcosh\u2212sinxh Pulling out the common factor of sinx in the remaining limit and splitting the resulting product with the limit laws again, we see another familiar limit -- one we which we know equals zero... ddx[sinx]=cosx+limh\u21920sinx(cosh\u22121)h=cosx+[limh\u21920sinx]\u22c5[limh\u21920cosh\u22121h]=cosx+sinx\u22c50=cosx",
+        "feedback": "good",
+        "rating": null
+    },
+    {
+        "query": "derivative of sinx",
+        "answer": "The derivative of sin x is cos x, which is the rate of change of the sine function at any given point. Here also we are going to prove the derivative of sin x to be -cos x using the first principle. The derivative of sin x is cos x. Thus, we have proved that the derivative of sin x is cos x. Therefore, the derivative of sin is cos x and is proved by using the quotient rule. Derivative of Sin x Worksheet Therefore, the derivative of sin x is cos x. * The derivative of sin x is cos x. Thus, the derivative of sin 3x is 3 cos 3x. Therefore, the derivative of sin x by first principle is cos x. We know that the derivative of sin x is cos x. So the derivative of sin x2 using this and using the chain rule is cos x2\u00b7 d/dx(x2). ## Derivative of sin x using the First Principle Method f\u2019(x) = limh\u21920 [sin x cos h + cos x sin h \u2013 sin x]/h f\u2019(x) = limh\u21920 [-sin x(1-cosh) + cos x sin h]/h sin (0/2)) + cos x (1) f\u2019(x) = \u2013 sin x(0) + cos x Thus, the derivative of sin x is cos x, is derived. ### Derivative of Sin x Examples Now, we have to find the derivative of sin (x+1), using the 1st principle. Hence, the derivative of sin (x+1), with respect to x is cos (x+1). Find the derivative of sin 2x. **To find:** derivative of sin 2x. Hence, the derivative of sin 2x is 2 cos 2x. : r/calculus : r/calculus Image 1: r/calculus icon Go to calculus r/calculus Image 3: r/calculus iconr/calculus Welcome to r/calculus - a space for learning calculus and related disciplines. We learned in class that the derivative of sin(x) is cos(x). New to Reddit? * Reddit reReddit: Top posts of October 6, 2016 * * * * Reddit reReddit: Top posts of October 2016 * * * * Reddit reReddit: Top posts of 2016 * * * * Reddit Meta * Games * Gaming News & Discussion * Other Games * Action Movies & Series * Animated Movies & Series * Comedy Movies & Series * Romance Movies & Series * Superhero Movies & Series * About Reddit * Best of Reddit ddx[sinx]=cosx Certainly, by the limit definition of the derivative, we know that ddx[sinx]=limh\u21920sin(x+h)\u2212sin(x)h ddx[sinx]=limh\u21920sinxcosh+cosxsinh\u2212sinxh Seeing all of the components of a similar limit in our expression for the derivative, (i.e., there is a sinh in the numerator, an h in the denominator, and both of these are inside a limit as h\u21920), we use algebra and the limit laws to reveal this known limit in our expression: ddx[sinx]=limh\u21920[cosxsinhh+sinxcosh\u2212sinxh]=limh\u21920[cosx\u22c5sinhh+sinxcosh\u2212sinxh]=limh\u21920cosx\u22c5limh\u21920sinhh+limh\u21920sinxcosh\u2212sinxh Note, the first limit in the last line above is of an expression that does not depend on h, and hence effectively the limit of a constant. ddx[sinx]=cosx+limh\u21920sinxcosh\u2212sinxh Pulling out the common factor of sinx in the remaining limit and splitting the resulting product with the limit laws again, we see another familiar limit -- one we which we know equals zero... ddx[sinx]=cosx+limh\u21920sinx(cosh\u22121)h=cosx+[limh\u21920sinx]\u22c5[limh\u21920cosh\u22121h]=cosx+sinx\u22c50=cosx",
+        "feedback": "good",
+        "rating": null
+    },
+    {
+        "query": "derivative of sinx",
+        "answer": "The derivative of sin x is cos x, which is the rate of change of the sine function at any given point. Here also we are going to prove the derivative of sin x to be -cos x using the first principle. The derivative of sin x is cos x. Thus, we have proved that the derivative of sin x is cos x. Therefore, the derivative of sin is cos x and is proved by using the quotient rule. Derivative of Sin x Worksheet Therefore, the derivative of sin x is cos x. * The derivative of sin x is cos x. Thus, the derivative of sin 3x is 3 cos 3x. Therefore, the derivative of sin x by first principle is cos x. We know that the derivative of sin x is cos x. So the derivative of sin x2 using this and using the chain rule is cos x2\u00b7 d/dx(x2). ## Derivative of sin x using the First Principle Method f\u2019(x) = limh\u21920 [sin x cos h + cos x sin h \u2013 sin x]/h f\u2019(x) = limh\u21920 [-sin x(1-cosh) + cos x sin h]/h sin (0/2)) + cos x (1) f\u2019(x) = \u2013 sin x(0) + cos x Thus, the derivative of sin x is cos x, is derived. ### Derivative of Sin x Examples Now, we have to find the derivative of sin (x+1), using the 1st principle. Hence, the derivative of sin (x+1), with respect to x is cos (x+1). Find the derivative of sin 2x. **To find:** derivative of sin 2x. Hence, the derivative of sin 2x is 2 cos 2x. : r/calculus : r/calculus Image 1: r/calculus icon Go to calculus r/calculus Image 3: r/calculus iconr/calculus Welcome to r/calculus - a space for learning calculus and related disciplines. We learned in class that the derivative of sin(x) is cos(x). New to Reddit? * Reddit reReddit: Top posts of October 6, 2016 * * * * Reddit reReddit: Top posts of October 2016 * * * * Reddit reReddit: Top posts of 2016 * * * * Reddit Meta * Games * Gaming News & Discussion * Other Games * Action Movies & Series * Animated Movies & Series * Comedy Movies & Series * Romance Movies & Series * Superhero Movies & Series * About Reddit * Best of Reddit ddx[sinx]=cosx Certainly, by the limit definition of the derivative, we know that ddx[sinx]=limh\u21920sin(x+h)\u2212sin(x)h ddx[sinx]=limh\u21920sinxcosh+cosxsinh\u2212sinxh Seeing all of the components of a similar limit in our expression for the derivative, (i.e., there is a sinh in the numerator, an h in the denominator, and both of these are inside a limit as h\u21920), we use algebra and the limit laws to reveal this known limit in our expression: ddx[sinx]=limh\u21920[cosxsinhh+sinxcosh\u2212sinxh]=limh\u21920[cosx\u22c5sinhh+sinxcosh\u2212sinxh]=limh\u21920cosx\u22c5limh\u21920sinhh+limh\u21920sinxcosh\u2212sinxh Note, the first limit in the last line above is of an expression that does not depend on h, and hence effectively the limit of a constant. ddx[sinx]=cosx+limh\u21920sinxcosh\u2212sinxh Pulling out the common factor of sinx in the remaining limit and splitting the resulting product with the limit laws again, we see another familiar limit -- one we which we know equals zero... ddx[sinx]=cosx+limh\u21920sinx(cosh\u22121)h=cosx+[limh\u21920sinx]\u22c5[limh\u21920cosh\u22121h]=cosx+sinx\u22c50=cosx",
+        "feedback": "its too long!",
+        "rating": null
+    },
+    {
+        "query": "derivative of sinx",
+        "answer": "The derivative of sin x is the rate of change with respect to angle ie, x. The resultant of the derivative of sin x is cos x. Here also we are going to prove the derivative of sin x to be -cos x using the first principle. The derivative of sin x is cos x. Thus, we have proved that the derivative of sin x is cos x. Therefore, the derivative of sin is cos x and is proved by using the quotient rule. Derivative of Sin x Worksheet Therefore, the derivative of sin x is cos x. * The derivative of sin x is cos x. Thus, the derivative of sin 3x is 3 cos 3x. Therefore, the derivative of sin x by first principle is cos x. We know that the derivative of sin x is cos x. So the derivative of sin x2 using this and using the chain rule is cos x2\u00b7 d/dx(x2). The derivative of sin(x) is cos(x). Why? The derivative of any given function is simply the slope of the tangent line to original function ## Derivative of sin x using the First Principle Method f\u2019(x) = limh\u21920 [sin x cos h + cos x sin h \u2013 sin x]/h f\u2019(x) = limh\u21920 [-sin x(1-cosh) + cos x sin h]/h sin (0/2)) + cos x (1) f\u2019(x) = \u2013 sin x(0) + cos x Thus, the derivative of sin x is cos x, is derived. ### Derivative of Sin x Examples Now, we have to find the derivative of sin (x+1), using the 1st principle. Hence, the derivative of sin (x+1), with respect to x is cos (x+1). Find the derivative of sin 2x. **To find:** derivative of sin 2x. Hence, the derivative of sin 2x is 2 cos 2x. : r/calculus : r/calculus Image 1: r/calculus icon Go to calculus r/calculus Image 3: r/calculus iconr/calculus Welcome to r/calculus - a space for learning calculus and related disciplines. We learned in class that the derivative of sin(x) is cos(x). New to Reddit? *   Reddit reReddit: Top posts of October 6, 2016 * * * *   Reddit reReddit: Top posts of October 2016 * * * *   Reddit reReddit: Top posts of 2016 * * * *   Reddit Meta *   Games  *   Gaming News & Discussion *   Other Games *   Action Movies & Series *   Animated Movies & Series *   Comedy Movies & Series *   Romance Movies & Series *   Superhero Movies & Series *   About Reddit *   Best of Reddit",
+        "feedback": "liitle bit small",
+        "rating": null
+    },
+    {
+        "timestamp": "2026-03-07T18:08:36.330731",
+        "original_input": "WHAT IS DERIVATIVE OF SINX",
+        "parsed_question": null,
+        "retrieved_context": null,
+        "final_answer": "Derivative of Sine Function\n\nAssumptions\n- The function is f(x) = sin(x)\n- The variable x is a real number\n\nStep 1\nTo find the derivative of sin(x), we will use the definition of a derivative as a limit.\nf'(x) = lim(h -> 0) [f(x + h) - f(x)]/h\n\nStep 2\nWe will apply the definition to the sine function, using the angle addition formula for sine.\nf'(x) = lim(h -> 0) [sin(x + h) - sin(x)]/h\n\nStep 3\nUsing the angle addition formula for sine, we can rewrite sin(x + h) as sin(x)cos(h) + cos(x)sin(h).\nf'(x) = lim(h -> 0) [sin(x)cos(h) + cos(x)sin(h) - sin(x)]/h\n\nStep 4\nWe can simplify the expression by canceling out sin(x) and dividing the numerator and denominator by h.\nf'(x) = lim(h -> 0) [cos(h) + cos(x)sin(h)/h - 1]/1\n\nStep 5\nAs h approaches 0, cos(h) approaches 1 and sin(h)/h approaches 1.\nf'(x) = 1",
+        "verifier_outcome": null,
+        "user_feedback": "THE ANSWER SHOULD BE COSX",
+        "rating": "negative"
+    },
+    {
+        "timestamp": "2026-03-07T18:09:56.957106",
+        "original_input": "integration of sinx",
+        "parsed_question": null,
+        "retrieved_context": null,
+        "final_answer": "Integration of Sine Function\n\nAssumptions\nThe function to be integrated is sin(x).\nThe variable of integration is x.\n\nStep 1\nTo integrate sin(x), we can use the basic integration rule.\n\u222bsin(x) dx = -cos(x)\n\nStep 2\nWe can verify this result by differentiating the result from step 1.\nd(-cos(x))/dx = sin(x)\n\nFinal Answer\n\u222bsin(x) dx = -cos(x)",
+        "verifier_outcome": null,
+        "user_feedback": "Good",
+        "rating": "positive"
+    }
+]

data/parsed/03b7e3b6-f742-4668-8238-f329df6ce0c7.json

@@ -0,0 +1,22 @@
+{
+    "problem_text": "what is derivative of sinx",
+    "topic": "calculus",
+    "variables": [
+        "v",
+        "s",
+        "t",
+        "f",
+        "x",
+        "w",
+        "a",
+        "o",
+        "d",
+        "n",
+        "e",
+        "i",
+        "h",
+        "r"
+    ],
+    "constraints": [],
+    "needs_clarification": false
+}

docker-compose.yml

@@ -0,0 +1,27 @@
+services:
+  backend:
+    build: .
+    ports:
+      - "8000:8000"
+    environment:
+      - PORT=8000
+    command: uvicorn main:app --host 0.0.0.0 --port 8000
+
+
+  frontend:
+    build:
+      context: ./Frontend/react-app
+      dockerfile: Dockerfile
+    ports:
+      - "3000:80"
+
+  backend_v2:
+    build:
+      context: .
+      dockerfile: Dockerfile.v2
+    container_name: math_agent_v2
+    ports:
+      - "8080:8000"
+    environment:
+      - PORT=8000
+    command: uvicorn main:app --host 0.0.0.0 --port 7860

main.py

@@ -0,0 +1,36 @@
+import os
+os.environ["USE_TF"] = "0"
+import sys
+
+# Add the current directory to Python path so Backend imports work
+current_dir = os.path.dirname(os.path.abspath(__file__))
+sys.path.insert(0, current_dir)
+
+from fastapi import FastAPI
+from fastapi.middleware.cors import CORSMiddleware
+from router.rag_router import router as rag_router
+from router.feedback_router import router as feedback_router
+app = FastAPI(
+    title="Math Routing Agent ",
+    description="Hello",
+    version="1.0.0"
+)
+
+app.add_middleware(
+    CORSMiddleware,
+    allow_origins=["*"],  # you can restrict this later to your React app
+    allow_credentials=True,
+    allow_methods=["*"],
+    allow_headers=["*"],
+)
+#Routers
+app.include_router(rag_router, prefix="/api/query", tags=["RAG Router"])
+app.include_router(feedback_router, prefix="/api/feedback", tags=["Feedback Router"])
+# Endpoint
+@app.get("/")
+async def root():
+    return {"message": "Math Routing Agent API is on"}
+
+if __name__ == "__main__":
+    import uvicorn
+    uvicorn.run("main:app", host="0.0.0.0", port=7860, reload=True)

router/__init__.py

@@ -0,0 +1 @@
+# This file makes Python treat this directory as a package