| /* The compiler often warns you if you give a function formal parameter a | |
| name, but don't use it. But because assert() disappears when doing an | |
| optimized build, the compiler doesn't recognize your reference to the | |
| parameter in the assert() argument. To avoid the bogus warning in | |
| this case, we have ASSERT_ONLY_ARG(), which declares a name for a | |
| formal parameter for purposes of assert() only. In cases where an | |
| assert() would disappear, ASSERT_ONLY_ARG() disappears too. | |
| E.g. | |
| void foo(int const ASSERT_ONLY_ARG(arg1)) { | |
| assert(arg1 > 0); | |
| } | |
| */ | |