README.md

---
license: bsd-3-clause
language:
  - en
  - zh
base_model:
  - HuggingFaceTB/SmolLM3-3B
pipeline_tag: text-generation
tags:
  - HuggingFaceTB
  - SmolLM3-3B
---

# SmolLM3-3B-Int8

This version of SmolLM3-3B has been converted to run on the Axera NPU using **w8a16** quantization.

Compatible with Pulsar2 version: 4.1

## Convert tools links:

For those who are interested in model conversion, you can try to export axmodel through the original repo:
- https://huggingface.co/HuggingFaceTB/SmolLM3-3B

- [Github for SmolLM3-3B.axera](https://github.com/AXERA-TECH/SmolLM3-3B.axera)

- [Pulsar2 Link, How to Convert LLM from Huggingface to axmodel](https://pulsar2-docs.readthedocs.io/en/latest/appendix/build_llm.html)

## Support Platform
- AX650
  - [M4N-Dock(爱芯派Pro)](https://wiki.sipeed.com/hardware/zh/maixIV/m4ndock/m4ndock.html)

## How to use

Download all files from this repository to the device.

**Using AX650 Board**

```bash
ai@ai-bj ~/yongqiang/push_hugging_face/SmolLM3-3B $ tree -L 1
.
├── config.json
├── infer_axmodel.py
├── README.md
├── smollm3_axmodel
├── smolvlm3_tokenizer
└── utils

3 directories, 3 files
```

#### Inference with AX650 Host, such as M4N-Dock(爱芯派Pro) or AX650N DEMO Board

input text:

```
帮我求解函数y=3x^2+1的导数.
```

log information(including the thinking process):

```bash
$ python3 infer_axmodel.py -q "帮我求解函数y=3x^2+1的导数." # 默认开启 think
...
Model loaded successfully!
slice_indices: [0, 1, 2]
Slice prefill done: 0
Slice prefill done: 1
Slice prefill done: 2
answer >> <think>
Okay, so I need to find the derivative of the function y = 3x² + 1. Hmm, let me think about how to approach this. I remember that when taking derivatives, we use the^@ power rule. The power rule says that if you have a function like x^n, its derivative is n*x^(n-1). Right? So, for each term in the function, I can apply this rule.

First, let's break down the function into its components. The function is 3x^@² + 1. The first term is 3x², and the second term is 1. The constant term 1 doesn't have an x in it, so when I take the derivative of 1, it should be 0 because the derivative of a constant is zero. That part seems straightforward^@.

Now, the main part is the term 3x². Here, the coefficient is 3, and the exponent is 2. Applying the power rule, the derivative of x² is 2x. But since there's a coefficient 3 in front of the x², I need to multiply^@ the derivative of the function by that coefficient. So, 3 times the derivative of x², which is 2x. That gives me 3*2x = 6x. So the derivative of 3x² is 6x.

Putting it all together, the derivative of the entire function^@ y = 3x² + 1 should be the derivative of 3x² plus the derivative of 1. The derivative of 3x² is 6x, and the derivative of 1 is 0. Therefore, the derivative of the whole function is 6x + 0,^@ which simplifies to 6x.

Wait, let me double-check that. If I have a function like 3x², the derivative is 6x. Let me verify that with the power rule. The power rule states that if you have a function f(x) = ax^n, then f'(^@x) = a*n*x^(n-1). In this case, a is 3 and n is 2. So f'(x) = 3*2*x^(2-1) = 6x. Yes, that's correct. So the derivative of 3x² is indeed ^@6x. And the derivative of the constant 1 is 0. So combining those, the derivative of the entire function is 6x. That seems right.

Is there anything else I need to consider here? Maybe I should check if there are any other terms or if I missed any steps. The original^@ function is a simple polynomial, so there shouldn't be any hidden complexities here. The power rule applies straightforwardly to each term. Since there are no other terms besides the 3x² and the constant, the process is complete.

Another way to think about it is to consider the limit definition of a derivative.^@ If I were to use the limit definition, the derivative of 3x² + 1 would be the limit as h approaches 0 of [ (3(x+h)² + 1) - (3x² + 1) ] / h. Simplifying that expression would lead me through the^@ same steps as before, but since I already applied the power rule, I can be confident that the result is correct.

Therefore, after going through the process step by step, I can be sure that the derivative of y = 3x² + 1 is indeed 6x. There's no mistake^@ in the calculation, and all the steps follow logically from the power rule. So the final answer is 6x.

Just to recap, the key steps were:

1. Identify the function: 3x² + 1.
2. Apply the power rule to each term.
3. For the term^@ 3x², the derivative is 3*2x^(2-1) = 6x.
4. For the term 1, the derivative is 0.
5. Combine the derivatives: 6x + 0 = 6x.

Yes, that all checks out. I^@ think that's thorough enough. I don't see any errors in this reasoning. Therefore, the derivative of the function y = 3x² + 1 is 6x.

**Final Answer**
The derivative of the function \( y = 3x^2 + 1 \) is \(\boxed{6x}\).
</think>
To find the derivative of the function \( y = 3x^2 + 1 \), we can use the power rule of differentiation. The power rule states that if we have a function of the form \( ax^n \), its derivative is \( a \cdot^@ n \cdot x^{n-1} \).

1. **Identify the terms in the function:**
   - The first term is \( 3x^2 \).
   - The second term is \( 1 \).

2. **Apply the power rule to each term:**
  ^@ - For the term \( 3x^2 \):
     - The coefficient \( a \) is 3.
     - The exponent \( n \) is 2.
     - The derivative is \( 3 \cdot 2 \cdot x^{2-1} = 6x \).
^@   - For the term \( 1 \):
     - The derivative of a constant is 0.

3. **Combine the results:**
   - The derivative of \( 3x^2 \) is \( 6x \).
   - The derivative of \( 1 \) is \( ^@0 \).

4. **Final result:**
   - The derivative of the entire function \( 3x^2 + 1 \) is \( 6x + 0 = 6x \).

Thus, the derivative of the function \( y = 3x^2 + 1^@ \) is \( 6x \).

\[
\boxed{6x}
\]
```

use the parameter `--disable-think` to disable the thinking process:

```sh
$ python3 infer_axmodel.py -q "帮我求解函数y=3x^2+1的导数." --disable-think

Model loaded successfully!
slice_indices: [0]
Slice prefill done: 0
answer >> 要求解函数 \( y = 3x^2 + 1 \) 的导数，我们可以使用导数的基本规则。

函数导数的导数可以通过导数的导数规则来求解。对于多项式^@函数，导数可以通过导数的导数规则来求解。对于函数 \( y = 3x^2 + 1 \)，我们可以逐步求导：

1. **求导函数 \( y = 3x^2 \)**:
   根据导数的导^@数规则，导数规则中对于 \( x^n \) 的导数规则，导数规则为：
   \[
   \frac{d}{dx} (x^n) = n x^{n-1}
   \]
   在这里，\( n = 2^@ \)，所以：
   \[
   \frac{d}{dx} (3x^2) = 3 \cdot \frac{d}{dx} (x^2) = 3 \cdot 2x^{2-1} = 6x
   \]

2. **求^@导数规则中的常数项**:
   对于常数项 \( 1 \)，其导数为零，因为导数规则中常数项的导数为零：
   \[
   \frac{d}{dx} (1) = 0
   \]

将^@以上结果结合起来，我们得到：
\[
\frac{d}{dx} (y) = \frac{d}{dx} (3x^2 + 1) = 6x + 0 = 6x
\]

因此，函数 \( y = 3x^2 +^@ 1 \) 的导数为：
\[
\frac{dy}{dx} = 6x
\]

所以，求解函数 \( y = 3x^2 + 1 \) 的导数，我们得到：
\[
\frac{d}{dx} (3x^^@2 + 1) = 6x
\]

```