| using namespace std; | |
| int main() { | |
| ios::sync_with_stdio(false); | |
| cin.tie(0); | |
| int n; | |
| cin >> n; | |
| if (n == 1) { | |
| cout << "1 1\n"; | |
| return 0; | |
| } | |
| vector<int> pos_of_val(n + 1, 0); | |
| vector<int> val_at_pos(n + 1, 0); | |
| // Find positions of 1 and 2 | |
| for (int i = 1; i <= n; ++i) { | |
| cout << "0"; | |
| for (int j = 1; j <= n; ++j) { | |
| if (j == i) cout << " 2"; | |
| else cout << " 1"; | |
| } | |
| cout << endl; | |
| cout.flush(); | |
| int a; | |
| cin >> a; | |
| if (a == 0) { | |
| pos_of_val[1] = i; | |
| val_at_pos[i] = 1; | |
| } else if (a == 2) { | |
| pos_of_val[2] = i; | |
| val_at_pos[i] = 2; | |
| } | |
| } | |
| vector<int> unknown; | |
| for (int i = 1; i <= n; ++i) { | |
| if (val_at_pos[i] == 0) { | |
| unknown.push_back(i); | |
| } | |
| } | |
| // Determine the remaining values 3..n | |
| for (int v = 3; v <= n; ++v) { | |
| int k = v - 1; // number of known values | |
| vector<int> U = unknown; | |
| while (U.size() > 1) { | |
| int mid = U.size() / 2; | |
| vector<int> L(U.begin(), U.begin() + mid); | |
| vector<int> R(U.begin() + mid, U.end()); | |
| vector<int> q(n + 1, 1); // filler = 1 | |
| for (int val = 1; val < v; ++val) { | |
| q[pos_of_val[val]] = val; | |
| } | |
| for (int p : L) { | |
| q[p] = v; | |
| } | |
| cout << "0"; | |
| for (int i = 1; i <= n; ++i) { | |
| cout << " " << q[i]; | |
| } | |
| cout << endl; | |
| cout.flush(); | |
| int a; | |
| cin >> a; | |
| if (a == k + 1) { | |
| U = L; | |
| } else { | |
| U = R; | |
| } | |
| } | |
| int p = U[0]; | |
| pos_of_val[v] = p; | |
| val_at_pos[p] = v; | |
| unknown.erase(find(unknown.begin(), unknown.end(), p)); | |
| } | |
| cout << "1"; | |
| for (int i = 1; i <= n; ++i) { | |
| cout << " " << val_at_pos[i]; | |
| } | |
| cout << endl; | |
| cout.flush(); | |
| return 0; | |
| } |