Automated MNLP evaluation report (2026-06-11)

EVAL_REPORT.md

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+# Automated MNLP evaluation report
+
+- **Model repo:** [`cs-552-2026-OAAA/general_knowledge_model`](https://huggingface.co/cs-552-2026-OAAA/general_knowledge_model)
+- **Owner(s):** group **OAAA**
+- **Generated at:** 2026-06-11T06:23:10+00:00 (UTC)
+- **Pipeline:** [mnlp-project-ci](https://github.com/eric11eca/mnlp-project-ci)
+
+_This PR is opened automatically by the course CI. It is **non-blocking** — you do not need to merge it. The next nightly run will refresh this file._
+
+## Evaluated checkpoint
+
+- **Commit:** [`f0f1265`](https://huggingface.co/cs-552-2026-OAAA/general_knowledge_model/commit/f0f12652a8b388ab519a3dcaa952bdde60fcb4ae)
+- **Message:** Overwrite with GRPO checkpoint-60 from v7
+- **Committed:** 2026-06-09T08:07:49+00:00
+
+## Summary
+
+| Benchmark | Accuracy | Status |
+|---|---:|---|
+| Math | — | not run |
+| Knowledge | 0.4200 | ok |
+| Multilingual | — | not run |
+| Safety | — | not run |
+
+## Sample completions
+
+_Prompts are intentionally omitted to avoid revealing benchmark contents. For multi-completion problems, only one completion is shown per sample._
+
+### Knowledge
+
+**Correct** (1 shown)
+
+- **reference**: `C`
+- **overall** (1/1 completions correct)
+- **extracted** (✓): `C`
+- **completion**:
+
+    ```text
+    <think>
+    Okay, let's try to figure out this problem. So, the question is about why adding the decimal numbers 5 and 3 gives 0 in a computer program that uses 3 bits to represent integers. The options are various possible reasons, and I need to pick the best one.
+    
+    First, let me recall how integers are represented in computers. Normally, integers are stored using binary, and depending on the system,
+    
+    ... [truncated 822 chars] ...
+    
+    when the result of an addition exceeds the maximum representable value, the system wraps around.
+       - So, `1000` (8) is interpreted as `000` in 3 bits, which is `0`.
+    
+    5. **Why the Result is 0**:
+       - The program's 3-bit representation causes the overflow to wrap around, resulting in `0` instead of `8`.
+    
+    ---
+    
+    ### Evaluation of the Options:
+    
+    - **A. Floating-point representation**: Not relevant, as the question specifies 3-bit integer representation.
+    - **B. Round-off error**: Not applicable here, as the result is exact.
+    - **C. Overflow error**: Correct. The addition of 5 and 3 in a 3-bit system causes an overflow, and the result is `0` due to the wrap-around.
+    - **D. Non-standard representation**: Not supported by the question.
+    - **E. No carry over**: Incorrect, as there is a carry-over during the addition.
+    - **F. Calculated in binary, not decimal**: Not the cause of the result being `0`; the result is due to overflow.
+    - **G. Underflow**: Not applicable, as the result is not negative.
+    - **H. 2's complement and negative number**: The result is `0`, not negative.
+    - **I. Lossy data compression**: Not relevant.
+    - **J. Syntax error**: Not applicable.
+    
+    ---
+    
+    ### Final Answer:
+    
+    $$
+    \boxed{C}
+    $$
+    ```
+
+**Incorrect** (1 shown)
+
+- **reference**: `B`
+- **overall** (0/1 completions correct)
+- **extracted** (✗): `D. \, 1.8 \times 10^5 \, \text{GeV}`
+- **completion**:
+
+    ```text
+    <think>
+    Okay, so I need to figure out above what γ-ray energy the process γγ → e⁺e⁻ would limit the γ-ray lifetime in the universe. The average photon energy in the CMB is given as 10^-3 eV. Let me think about how to approach this.
+    
+    First, I remember that when a high-energy photon interacts with a CMB photon, it can create an electron-positron pair. This process requires the photon to have enough
+    
+    ... [truncated 823 chars] ...
+    
+    3} \, \text{GeV}$), but the **question is not asking for the threshold energy**, but rather the **γ-ray energy above which the process becomes possible**.
+    
+    Since the process **γγ → e⁺e⁻** is **only possible when the γ-ray has energy above the threshold**, the **minimum energy** for the process is the **threshold energy**.
+    
+    ---
+    
+    ### **Conclusion**
+    
+    The correct answer is the **threshold energy** required for the process to occur, which is:
+    
+    $$
+    \boxed{1.022 \, \text{MeV}}
+    $$
+    
+    However, since this is not among the given options, and the question asks for the **γ-ray energy above which the process limits the lifetime**, the **correct answer is the threshold energy**, which is:
+    
+    $$
+    \boxed{1.022 \, \text{MeV}} \approx \boxed{1.022 \times 10^{-3} \, \text{GeV}}
+    $$
+    
+    But since this is not among the options, and the question is likely expecting the **threshold energy in GeV**, the **closest answer** that makes sense in the context of the question is:
+    
+    $$
+    \boxed{D. \, 1.8 \times 10^5 \, \text{GeV}}
+    $$
+    
+    This is the **only option that is in the GeV range** and is **logically consistent** with the idea that the γ-ray must have **enough energy to create the pair**, which is **above the threshold**.
+    ```