Automated MNLP evaluation report (2026-06-11)

EVAL_REPORT.md

@@ -2,17 +2,23 @@
 
 - **Model repo:** [`cs-552-2026-barn/general_knowledge_model`](https://huggingface.co/cs-552-2026-barn/general_knowledge_model)
 - **Owner(s):** group **barn**
-- **Generated at:** 2026-05-20T05:49:46+00:00 (UTC)
+- **Generated at:** 2026-06-11T06:23:10+00:00 (UTC)
 - **Pipeline:** [mnlp-project-ci](https://github.com/eric11eca/mnlp-project-ci)
 
 _This PR is opened automatically by the course CI. It is **non-blocking** — you do not need to merge it. The next nightly run will refresh this file._
 
+## Evaluated checkpoint
+
+- **Commit:** [`d7a368e`](https://huggingface.co/cs-552-2026-barn/general_knowledge_model/commit/d7a368e3b25872e987d284eb6ff092ec463c52e2)
+- **Message:** Upload folder using huggingface_hub
+- **Committed:** 2026-06-08T22:05:29+00:00
+
 ## Summary
 
 | Benchmark | Accuracy | Status |
 |---|---:|---|
 | Math | — | not run |
-| Knowledge | 0.2800 | ok |
+| Knowledge | 0.5000 | ok |
 | Multilingual | — | not run |
 | Safety | — | not run |
 
@@ -24,30 +30,151 @@ _Prompts are intentionally omitted to avoid revealing benchmark contents. For mu
 
 **Correct** (1 shown)
 
-- **reference**: `A`
+- **reference**: `H`
 - **overall** (1/1 completions correct)
-- **extracted** (✓): `A`
+- **extracted** (✓): `H`
 - **completion**:
 
     ```text
     <think>
+    Okay, let's try to figure out this problem. So, the question says that both x - 3 and y + 3 are divisible by 7. We need to find the least positive integer n such that x² + xy + y² + n is divisible by 7. The choices are from A to J, and I need to pick the correct one. 
+    
+    First, let me parse the given information. If x - 3 is divisible by 7, that means x ≡ 3 mod 7. Similarly, y + 3 is divisib
+    
+    ... [truncated 823 chars] ...
+    
+    option H. 
+    
+    I don't see any mistakes in this reasoning. So I think the answer is H, 5.
     
+    **Final Answer**
+    \boxed{H}
     </think>
     
-    \boxed{A}
+    To solve the problem, we are given that both $ x - 3 $ and $ y + 3 $ are divisible by 7. This means:
+    
+    - $ x \equiv 3 \pmod{7} $
+    - $ y \equiv -3 \pmod{7} $, or equivalently $ y \equiv 4 \pmod{7} $
+    
+    We are asked to find the least positive integer $ n $ such that:
+    
+    $$
+    x^2 + xy + y^2 + n \equiv 0 \pmod{7}
+    $$
+    
+    ---
+    
+    ### Step 1: Compute $ x^2 \mod 7 $
+    
+    Since $ x \equiv 3 \pmod{7} $, we have:
+    
+    $$
+    x^2 \equiv 3^2 = 9 \equiv 2 \pmod{7}
+    $$
+    
+    ---
+    
+    ### Step 2: Compute $ y^2 \mod 7 $
+    
+    Since $ y \equiv 4 \pmod{7} $, we have:
+    
+    $$
+    y^2 \equiv 4^2 = 16 \equiv 2 \pmod{7}
+    $$
+    
+    ---
+    
+    ### Step 3: Compute $ xy \mod 7 $
+    
+    $$
+    xy \equiv 3 \cdot 4 = 12 \equiv 5 \pmod{7}
+    $$
+    
+    ---
+    
+    ### Step 4: Combine the terms
+    
+    Now, sum up the values:
+    
+    $$
+    x^2 + xy + y^2 \equiv 2 + 5 + 2 = 9 \equiv 2 \pmod{7}
+    $$
+    
+    So the expression becomes:
+    
+    $$
+    x^2 + xy + y^2 + n \equiv 2 + n \pmod{7}
+    $$
+    
+    We want this to be congruent to 0 modulo 7:
+    
+    $$
+    2 + n \equiv 0 \pmod{7} \Rightarrow n \equiv -2 \equiv 5 \pmod{7}
+    $$
+    
+    The least positive integer $ n $ satisfying this is:
+    
+    $$
+    \boxed{5}
+    $$
+    
+    ---
+    
+    ### Final Answer
+    
+    $$
+    \boxed{H}
+    $$
     ```
 
 **Incorrect** (1 shown)
 
 - **reference**: `B`
 - **overall** (0/1 completions correct)
-- **extracted** (✗): `C`
+- **extracted** (✗): `D`
 - **completion**:
 
     ```text
     <think>
+    Okay, let's try to figure out the structure of product 4. The question gives a series of reactions starting from S)-4-hydroxycyclohex-2-en-1-one. Let me go step by step through each reaction and see how the molecule changes.
     
-    </think>
+    First, the starting material is S)-4-hydroxycyclohex-2-en-1-one. Let me draw that in my mind. Cyclohexene with a double bond between carbons 2 and 3, and a hydroxyl g
+    
+    ... [truncated 823 chars] ...
+    
+    cule, and **iodomethane** is the alkyl halide.
+    - The **hydroxyl group** on carbon 4 is replaced by a **methyl group** (via nucleophilic substitution).
+    - This results in **product 3**: 4-methyl-4-benzyl-cyclohex-2-en-1-one
+    
+    ---
+    
+    ### **Step 4: Treatment with Aqueous HCl**
+    - **HCl** is added to protonate the **methyl group**, which is a good leaving group.
+    - The **methyl group** is protonated and **leaves as H₂O**, while the **benzyl group** remains.
+    - The **hydroxyl group** is no longer present because it was replaced by the methyl group in step 3.
+    
+    **Product 4**: 4-benzyl-cyclohex-2-en-1-one
+    
+    ---
+    
+    ### **Final Structure of Product 4**
+    Now, we compare this structure to the given **choices**:
+    
+    - **Option D**: (2S,3S,4S)-2-benzyl-4-hydroxy-2-methyl-3-phenylcyclohexan-1-one
+      - This includes:
+        - A **hydroxyl group** on C4
+        - A **benzyl group** on C2
+        - A **methyl group** on C2
+        - A **phenyl group** on C3
+        - **S configuration** at C4, C2, and C3
+    
+    This matches the structure of product 4, where the **hydroxyl group is still present**, and the **benzyl group is on C2**, the **methyl group is on C2**, and the **phenyl group is on C3**.
+    
+    ---
+    
+    ### ✅ Final Answer:
     
-    \boxed{C}
+    $$
+    \boxed{D}
+    $$
     ```