Automated MNLP evaluation report (2026-06-01)

EVAL_REPORT.md

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+# Automated MNLP evaluation report
+
+- **Model repo:** [`cs-552-2026-baseline/math_model`](https://huggingface.co/cs-552-2026-baseline/math_model)
+- **Owner(s):** group **baseline**
+- **Generated at:** 2026-06-01T06:13:57+00:00 (UTC)
+- **Pipeline:** [mnlp-project-ci](https://github.com/eric11eca/mnlp-project-ci)
+
+_This PR is opened automatically by the course CI. It is **non-blocking** — you do not need to merge it. The next nightly run will refresh this file._
+
+## Summary
+
+| Benchmark | Accuracy | Status |
+|---|---:|---|
+| Math | 0.1600 | ok |
+| Knowledge | — | not run |
+| Multilingual | — | not run |
+| Safety | — | not run |
+
+## Sample completions
+
+_Prompts are intentionally omitted to avoid revealing benchmark contents. For multi-completion problems, only one completion is shown per sample._
+
+### Math
+
+**Correct** (1 shown)
+
+- **reference**: `4`
+- **overall** (8/8 completions correct)
+- **extracted** (✓): `4`
+- **completion**:
+
+    ```text
+    <think>
+    Okay, so I need to solve the equation 10^x minus 10 equals 9990. Let me write that down first: 10^x - 10 = 9990. Hmm, let me think about how to approach this. 
+    
+    First, maybe I should isolate the term with the exponent. That means I need to get 10^x by itself on one side of the equation. So, if I add 10 to both sides, that should cancel out the -10 on the left. Let me try that:
+    
+    10^x - 10 +
+    
+    ... [truncated 823 chars] ...
+    
+    t the original problem is written as 10^x − 10 = 9990. The way it's written, it's 10^x minus 10, not 10^(x - 10). So unless there's some parentheses I'm missing, but the standard order of operations would make it 10^x - 10. 
+    
+    So, yeah, I think that's correct. 
+    
+    Another thought: sometimes when dealing with exponents, people might confuse the order of operations. But in this case, since there's no parentheses, it's definitely 10^x minus 10. 
+    
+    So, conclusion: x = 4. 
+    
+    **Final Answer**
+    The solution is \boxed{4}.
+    </think>
+    
+    To solve the equation:
+    
+    $$
+    10^x - 10 = 9990
+    $$
+    
+    ---
+    
+    ### Step 1: Isolate the Exponential Term
+    
+    We start by isolating the term with the exponent $10^x$:
+    
+    $$
+    10^x - 10 = 9990
+    $$
+    
+    Add 10 to both sides:
+    
+    $$
+    10^x = 9990 + 10 = 10000
+    $$
+    
+    ---
+    
+    ### Step 2: Solve for $x$
+    
+    Now, we need to find the value of $x$ such that:
+    
+    $$
+    10^x = 10000
+    $$
+    
+    We recognize that:
+    
+    $$
+    10^4 = 10000
+    $$
+    
+    So, the exponent $x$ must be:
+    
+    $$
+    x = 4
+    $$
+    
+    ---
+    
+    ### Step 3: Verify the Solution
+    
+    Substitute $x = 4$ back into the original equation:
+    
+    $$
+    10^4 - 10 = 10000 - 10 = 9990
+    $$
+    
+    This matches the right-hand side of the equation, confirming that the solution is correct.
+    
+    ---
+    
+    ### Final Answer
+    
+    $$
+    \boxed{4}
+    $$
+    ```
+
+**Incorrect** (1 shown)
+
+- **reference**: `\frac{270}7\text{ degrees}`
+- **overall** (0/8 completions correct)
+- **extracted** (✗): `<no answer>`
+- **completion**:
+
+    ```text
+    <think>
+    Okay, so I need to find the measure of angle BAC in this figure where there's a square and a regular heptagon sharing the side AD. Let me try to visualize the Asymptote figure first. 
+    
+    From the Asymptote code, it seems that there's a regular heptagon and a square sharing the side AD. The square is probably attached to the heptagon along side AD. The points are labeled A, B, C, D, and other
+    
+    ... [truncated 823 chars] ...
+    
+    le 360/7°. Therefore, coordinates of B are (-sin(360/7°), -cos(360/7°)).
+    
+    Wait, because cos(180° + α) = -cos(α), sin(180° + α) = -sin(α). So, if α = 360/7°, then coordinates are (-cos(α), -sin(α)).
+    
+    So, coordinates of B: (-cos(360/7°), -sin(360/7°)).
+    
+    So, now we have coordinates for points A, B, C.
+    
+    Point A: (-sin(3θ), cos(4θ)) where θ = 360/7°.
+    
+    Point B: (-cos(α), -sin(α)) where α = 360/7°.
+    
+    Point C: (-sin(3θ), cos(4θ)).
+    
+    Wait, hold on. Wait, point C is at (-sin(3θ), cos(4θ)), and point A is at (-sin(3θ), cos(4θ))? Wait, no. Wait, earlier I said point C is at (-sin(3θ), cos(4θ)), but point A is at (-sin(3θ), cos(3θ))? Wait, no. Wait, let me check again.
+    
+    Earlier, coordinates of A: (-sin(3θ), cos(3θ)) where θ = 360/7°, right? Because angle of A is 90° + 3θ, which is 90° + 3*(360/7°). Then, coordinates of A are (cos(90° + 3θ), sin(90° + 3θ)) which is (-sin(3θ), cos(3θ)).
+    
+    Similarly, coordinates of point C: (-sin(3θ), cos(4θ)).
+    
+    So, point A and point C have the same x-coordinate: -sin(3θ), but different y-coordinates: cos(3θ) and cos(4θ). 
+    
+    Point B is at (-cos(α), -sin(α)) where α = 360/7°.
+    
+    So, to find angle BAC, which is the angle at point A between points B, A, and C.
+    
+    So, angle B
+    ```