Automated MNLP evaluation report (2026-06-11)

EVAL_REPORT.md

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+# Automated MNLP evaluation report
+
+- **Model repo:** [`cs-552-2026-camykaz/math_model`](https://huggingface.co/cs-552-2026-camykaz/math_model)
+- **Owner(s):** group **camykaz**
+- **Generated at:** 2026-06-11T06:23:10+00:00 (UTC)
+- **Pipeline:** [mnlp-project-ci](https://github.com/eric11eca/mnlp-project-ci)
+
+_This PR is opened automatically by the course CI. It is **non-blocking** — you do not need to merge it. The next nightly run will refresh this file._
+
+## Evaluated checkpoint
+
+- **Commit:** [`cc7a572`](https://huggingface.co/cs-552-2026-camykaz/math_model/commit/cc7a572d698cb4899527567350c6317c5a0751b7)
+- **Message:** Upload v7 checkpoint 2400 math model
+- **Committed:** 2026-06-06T21:39:38+00:00
+
+## Summary
+
+| Benchmark | Accuracy | Status |
+|---|---:|---|
+| Math | 0.5200 | ok |
+| Knowledge | — | not run |
+| Multilingual | — | not run |
+| Safety | — | not run |
+
+## Sample completions
+
+_Prompts are intentionally omitted to avoid revealing benchmark contents. For multi-completion problems, only one completion is shown per sample._
+
+### Math
+
+**Correct** (1 shown)
+
+- **reference**: `6`
+- **overall** (8/8 completions correct)
+- **extracted** (✓): `6`
+- **completion**:
+
+    ```text
+    Okay, so I need to figure out how many Trinkets are equivalent to 56 Drinkets. Let me start by understanding the problem step by step. 
+    
+    First, the exchange rates are given: 1 Trinket is worth 4 Blinkets, and 3 Blinkets are worth 7 Drinkets. So, I need to convert Drinkets to Blinkets first, and then Blinkets to Trinkets. That seems like a two-step conversion. Let me write down the exchange rates a
+    
+    ... [truncated 823 chars] ...
+    
+    e just check once again.
+    
+    If 6 Trinkets are equal to 6*4=24 Blinkets. And 24 Blinkets are equal to 24*(7/3) Drinkets, which is 24*(7/3)=56 Drinkets. Yes, that's exactly 56 Drinkets. So, that checks out. Therefore, the answer is 6 Trinkets.
+    
+    **Final Answer**
+    The number of Trinkets in 56 Drinkets is \boxed{6}.
+    </think>
+    
+    To express 56 Drinkets in Trinkets, we need to convert Drinkets to Blinkets and then Blinkets to Trinkets. 
+    
+    First, convert Drinkets to Blinkets using the exchange rate \(3 \text{ Blinkets} = 7 \text{ Drinkets}\). To find the number of Blinkets in 1 Drinket, we use the rate:
+    \[
+    1 \text{ Drinket} = \frac{3 \text{ Blinkets}}{7 \text{ Drinkets}} = \frac{3}{7} \text{ Blinkets}
+    \]
+    Next, convert 56 Drinkets to Blinkets:
+    \[
+    56 \text{ Drinkets} \times \frac{3}{7} \text{ Blinkets/Drinket} = \frac{56 \times 3}{7} \text{ Blinkets} = \frac{168}{7} \text{ Blinkets} = 24 \text{ Blinkets}
+    \]
+    
+    Now, convert Blinkets to Trinkets using the exchange rate \(1 \text{ Trinket} = 4 \text{ Blinkets}\):
+    \[
+    24 \text{ Blinkets} \times \frac{1 \text{ Trinket}}{4 \text{ Blinkets}} = \frac{24}{4} \text{ Trinkets} = 6 \text{ Trinkets}
+    \]
+    
+    Thus, the number of Trinkets in 56 Drinkets is \(\boxed{6}\).
+    ```
+
+**Incorrect** (1 shown)
+
+- **reference**: `60750, 854130, 854970`
+- **overall** (0/8 completions correct)
+- **extracted** (✗): `854130`
+- **completion**:
+
+    ```text
+    Okay, let's see. I need to solve this problem where there's a function h from natural numbers to natural numbers excluding 1, and it satisfies the equation h(n) + h(n+1) = h(n+2)h(n+3) - 840 for every natural number n. Then, I have to determine all possible values that the sum from i=1 to 2025 of h(i) can take. Hmm, interesting.
+    
+    First, let me parse the problem again. The function h maps natural n
+    
+    ... [truncated 822 chars] ...
+    
+    = 2025 \times 30 = 60750
+         \]
+    
+    2. **Periodic Alternating Solutions:**
+       - Consider the sequences that alternate between 2 and 842. For example:
+         \[
+         h(1) = 2, \quad h(2) = 842, \quad h(3) = 2, \quad h(4) = 842, \quad \ldots
+         \]
+         - Check the recurrence relation:
+           \[
+           h(1) + h(2) = 2 + 842 = 844
+           \]
+           \[
+           h(3)h(4) = 2 \cdot 842 = 1684 \implies 844 = 1684 - 840 = 844
+           \]
+         - This is valid. The sum for this alternating sequence is:
+           \[
+           \sum_{i=1}^{2025} h(i) = 1013 \times 2 + 1012 \times 842 = 2026 + 852104 = 854130
+           \]
+         - Similarly, if the sequence starts with 842:
+           \[
+           h(1) = 842, \quad h(2) = 2, \quad h(3) = 842, \quad h(4) = 2, \quad \ldots
+           \]
+           The sum is the same:
+           \[
+           \sum_{i=1}^{2025} h(i) = 1013 \times 842 + 1012 \times 2 = 854130
+           \]
+    
+    3. **Other Potential Solutions:**
+       - Other potential solutions, such as starting with 30 and 2 or 842 and 2, were found to be invalid due to the recurrence relation constraints.
+    
+    ### Conclusion:
+    The only possible values for the sum \( \sum_{i=1}^{2025} h(i) \) are:
+    \[
+    \boxed{60750} \quad \text{and} \quad \boxed{854130}
+    \]
+    ```