Automated MNLP evaluation report (2026-06-11)

EVAL_REPORT.md

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+# Automated MNLP evaluation report
+
+- **Model repo:** [`cs-552-2026-middle-west/math_model`](https://huggingface.co/cs-552-2026-middle-west/math_model)
+- **Owner(s):** group **middle-west**
+- **Generated at:** 2026-06-11T06:23:10+00:00 (UTC)
+- **Pipeline:** [mnlp-project-ci](https://github.com/eric11eca/mnlp-project-ci)
+
+_This PR is opened automatically by the course CI. It is **non-blocking** — you do not need to merge it. The next nightly run will refresh this file._
+
+## Evaluated checkpoint
+
+- **Commit:** [`7d47837`](https://huggingface.co/cs-552-2026-middle-west/math_model/commit/7d4783794c6874ccd12c59b2ce182a1026b24c3d)
+- **Message:** Copy Ilia2003Mah/mnlp_safe_model verbatim to cs-552-2026-middle-west/math_model
+- **Committed:** 2026-06-10T09:04:00+00:00
+
+## Summary
+
+| Benchmark | Accuracy | Status |
+|---|---:|---|
+| Math | 0.5200 | ok |
+| Knowledge | — | not run |
+| Multilingual | — | not run |
+| Safety | — | not run |
+
+## Sample completions
+
+_Prompts are intentionally omitted to avoid revealing benchmark contents. For multi-completion problems, only one completion is shown per sample._
+
+### Math
+
+**Correct** (1 shown)
+
+- **reference**: `6`
+- **overall** (8/8 completions correct)
+- **extracted** (✓): `6`
+- **completion**:
+
+    ```text
+    <think>
+    Okay, let's see. I need to convert 56 Drinkets into Trinkets. The problem gives me the exchange rates: 1 Trinket is worth 4 Blinkets, and 3 Blinkets are worth 7 Drinkets. So, first, I should figure out how many Blinkets are equivalent to 56 Drinkets, and then convert that number of Blinkets into Trinkets.
+    
+    Starting with the Drinkets to Blinkets conversion. The problem says 3 Blinkets are w
+    
+    ... [truncated 823 chars] ...
+    
+    kets divided by 4 is 6 Trinkets. Yes, that seems correct. So the answer should be 6 Trinkets. Let me see if there's another way to approach this.
+    
+    Alternatively, maybe using proportions. Let's set up the conversion factors. The exchange rates can be represented as:
+    
+    Drinkets to Blinkets: 7 Drinkets = 3 Blinkets. So, the ratio is 7:3.
+    
+    Blinkets to Trinkets: 1 Trinket = 4 Blinkets. So, the ratio is 1:4.
+    
+    To convert Drinkets to Trinkets, we can first convert Drinkets to Blinkets, then Blinkets to Trinkets. So, 56 Drinkets * (3 Blinkets / 7 Drinkets) = 24 Blinkets. Then 24 Blinkets * (1 Trinket / 4 Blinkets) = 6 Trinkets. Yep, same result.
+    
+    Another way: Find the overall exchange rate from Drinkets to Trinkets. Let's see. Since 1 Trinket = 4 Blinkets, and 3 Blinkets = 7 Drinkets, then 1 Trinket = 4 * (7/3) Drinkets. Because 3 Blinkets = 7 Drinkets, so 1 Blinket is 7/3 Drinkets. Therefore, 1 Trinket is 4 * (7/3) = 28/3 Drinkets. Therefore, 1 Drinket is 3/28 Trinkets. Therefore, 56 Drinkets is 56 * (3/28) Trinkets. Let's compute that: 56 divided by 28 is 2, multiplied by 3 is 6. So again, 6 Trinkets. So all methods lead to 6. Therefore, the answer should be 6 Trinkets.
+    </think>
+    
+    \boxed{6}
+    ```
+
+**Incorrect** (1 shown)
+
+- **reference**: `60750, 854130, 854970`
+- **overall** (0/8 completions correct)
+- **extracted** (✗): `60750`
+- **completion**:
+
+    ```text
+    <think>
+    Okay, let's try to tackle this problem. So we have a function h from natural numbers to natural numbers excluding 1. The condition given is that for every n in natural numbers, h(n) + h(n+1) equals h(n+2) times h(n+3) minus 840. And we need to find all possible values that the sum from i=1 to 2025 of h(i) can take.
+    
+    First, I need to understand the recurrence relation. The equation is h(n)
+    
+    ... [truncated 823 chars] ...
+    
+    ry value, I'll list both.
+    
+    But how to represent that in the box? If the system allows multiple answers, but the user's instruction says to put the final answer in a box, I'll have to choose one. But this is not possible. Therefore, I might have made a mistake, and the only possible value is 60,750.
+    
+    But why? Maybe the problem assumes that the function is constant. However, the alternating function is valid.
+    
+    Given the time I've spent and the checks, I'll conclude that both values are possible, and the answer is both. But since I can't put two values in a single box, I'll have to choose one. But this is not correct.
+    
+    Alternatively, maybe the problem has a unique solution, and the other value is not possible. But I can't see why.
+    
+    Given the problem's phrasing, I'll proceed with the two values, and since the user's examples show single answers, perhaps the intended answer is 60,750, and the alternating function is invalid. But I can't justify that.
+    
+    In conclusion, based on the analysis, the possible sums are 60,750 and 854,130. But since I have to choose one, I'll go with the constant function, as it's the only one that's more straightforward, but I'm not sure.
+    </think>
+    
+    \boxed{60750}
+    ```