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What are the dates that have an average sea level pressure between 30.3 and 31?
-- Tables de la base de données (T-SQL) -- TABLE [station] ( [id] INT, [name] NVARCHAR(MAX), [latitude] INT, [longitude] INT, [dock count] INT, [city] NVARCHAR(MAX), [installation date] NVARCHAR(MAX) ); TABLE [status] ( [station id] INT, [bikes available] INT, [docks available] ...
SELECT date FROM weather WHERE mean_sea_level_pressure_inches BETWEEN 30.3 AND 31
Find the day in which the difference between the max temperature and min temperature was the smallest. Also report the difference.
-- Tables de la base de données (T-SQL) -- TABLE [station] ( [id] INT, [name] NVARCHAR(MAX), [latitude] INT, [longitude] INT, [dock count] INT, [city] NVARCHAR(MAX), [installation date] NVARCHAR(MAX) ); TABLE [status] ( [station id] INT, [bikes available] INT, [docks available] ...
SELECT TOP 1 date, max_temperature_f - min_temperature_f FROM weather ORDER BY CASE WHEN max_temperature_f - min_temperature_f IS NULL THEN 1 ELSE 0 END, max_temperature_f - min_temperature_f
What are the days that had the smallest temperature range, and what was that range?
-- Tables de la base de données (T-SQL) -- TABLE [station] ( [id] INT, [name] NVARCHAR(MAX), [latitude] INT, [longitude] INT, [dock count] INT, [city] NVARCHAR(MAX), [installation date] NVARCHAR(MAX) ); TABLE [status] ( [station id] INT, [bikes available] INT, [docks available] ...
SELECT TOP 1 date, max_temperature_f - min_temperature_f FROM weather ORDER BY CASE WHEN max_temperature_f - min_temperature_f IS NULL THEN 1 ELSE 0 END, max_temperature_f - min_temperature_f
What are the id and name of the stations that have ever had more than 12 bikes available?
-- Tables de la base de données (T-SQL) -- TABLE [station] ( [id] INT, [name] NVARCHAR(MAX), [latitude] INT, [longitude] INT, [dock count] INT, [city] NVARCHAR(MAX), [installation date] NVARCHAR(MAX) ); TABLE [status] ( [station id] INT, [bikes available] INT, [docks available] ...
SELECT DISTINCT T1.id, T1.name FROM station AS T1 JOIN status AS T2 ON T1.id = T2.station_id WHERE T2.bikes_available > 12
What are the different ids and names of the stations that have had more than 12 bikes available?
-- Tables de la base de données (T-SQL) -- TABLE [station] ( [id] INT, [name] NVARCHAR(MAX), [latitude] INT, [longitude] INT, [dock count] INT, [city] NVARCHAR(MAX), [installation date] NVARCHAR(MAX) ); TABLE [status] ( [station id] INT, [bikes available] INT, [docks available] ...
SELECT DISTINCT T1.id, T1.name FROM station AS T1 JOIN status AS T2 ON T1.id = T2.station_id WHERE T2.bikes_available > 12
Give me the zip code where the average mean humidity is below 70 and at least 100 trips took place.
-- Tables de la base de données (T-SQL) -- TABLE [station] ( [id] INT, [name] NVARCHAR(MAX), [latitude] INT, [longitude] INT, [dock count] INT, [city] NVARCHAR(MAX), [installation date] NVARCHAR(MAX) ); TABLE [status] ( [station id] INT, [bikes available] INT, [docks available] ...
SELECT zip_code FROM weather GROUP BY zip_code HAVING AVG(mean_humidity) < 70 INTERSECT SELECT zip_code FROM trip GROUP BY zip_code HAVING COUNT_BIG(*) >= 100
What are the zip codes that have an average mean humidity below 70 and had at least 100 trips come through there?
-- Tables de la base de données (T-SQL) -- TABLE [station] ( [id] INT, [name] NVARCHAR(MAX), [latitude] INT, [longitude] INT, [dock count] INT, [city] NVARCHAR(MAX), [installation date] NVARCHAR(MAX) ); TABLE [status] ( [station id] INT, [bikes available] INT, [docks available] ...
SELECT zip_code FROM weather GROUP BY zip_code HAVING AVG(mean_humidity) < 70 INTERSECT SELECT zip_code FROM trip GROUP BY zip_code HAVING COUNT_BIG(*) >= 100
What are the names of stations that are located in Palo Alto city but have never been the ending point of trips more than 100 times?
-- Tables de la base de données (T-SQL) -- TABLE [station] ( [id] INT, [name] NVARCHAR(MAX), [latitude] INT, [longitude] INT, [dock count] INT, [city] NVARCHAR(MAX), [installation date] NVARCHAR(MAX) ); TABLE [status] ( [station id] INT, [bikes available] INT, [docks available] ...
SELECT name FROM station WHERE city = [Palo Alto] EXCEPT SELECT end_station_name FROM trip GROUP BY end_station_name HAVING COUNT_BIG(*) > 100
What are the names of the stations that are located in Palo Alto but have never been the ending point of the trips
-- Tables de la base de données (T-SQL) -- TABLE [station] ( [id] INT, [name] NVARCHAR(MAX), [latitude] INT, [longitude] INT, [dock count] INT, [city] NVARCHAR(MAX), [installation date] NVARCHAR(MAX) ); TABLE [status] ( [station id] INT, [bikes available] INT, [docks available] ...
SELECT name FROM station WHERE city = [Palo Alto] EXCEPT SELECT end_station_name FROM trip GROUP BY end_station_name HAVING COUNT_BIG(*) > 100
How many trips started from Mountain View city and ended at Palo Alto city?
-- Tables de la base de données (T-SQL) -- TABLE [station] ( [id] INT, [name] NVARCHAR(MAX), [latitude] INT, [longitude] INT, [dock count] INT, [city] NVARCHAR(MAX), [installation date] NVARCHAR(MAX) ); TABLE [status] ( [station id] INT, [bikes available] INT, [docks available] ...
SELECT COUNT_BIG(*) FROM station AS T1, trip AS T2, station AS T3 JOIN trip AS T4 ON T1.id = T2.start_station_id AND T2.id = T4.id AND T3.id = T4.end_station_id WHERE T1.city = [Mountain View] AND T3.city = [Palo Alto]
How many trips stated from a station in Mountain View and ended at one in Palo Alto?
-- Tables de la base de données (T-SQL) -- TABLE [station] ( [id] INT, [name] NVARCHAR(MAX), [latitude] INT, [longitude] INT, [dock count] INT, [city] NVARCHAR(MAX), [installation date] NVARCHAR(MAX) ); TABLE [status] ( [station id] INT, [bikes available] INT, [docks available] ...
SELECT COUNT_BIG(*) FROM station AS T1, trip AS T2, station AS T3 JOIN trip AS T4 ON T1.id = T2.start_station_id AND T2.id = T4.id AND T3.id = T4.end_station_id WHERE T1.city = [Mountain View] AND T3.city = [Palo Alto]
What is the average latitude and longitude of the starting points of all trips?
-- Tables de la base de données (T-SQL) -- TABLE [station] ( [id] INT, [name] NVARCHAR(MAX), [latitude] INT, [longitude] INT, [dock count] INT, [city] NVARCHAR(MAX), [installation date] NVARCHAR(MAX) ); TABLE [status] ( [station id] INT, [bikes available] INT, [docks available] ...
SELECT AVG(T1.lat), AVG(T1.long) FROM station AS T1 JOIN trip AS T2 ON T1.id = T2.start_station_id
What is the average latitude and longitude of all starting stations for the trips?
-- Tables de la base de données (T-SQL) -- TABLE [station] ( [id] INT, [name] NVARCHAR(MAX), [latitude] INT, [longitude] INT, [dock count] INT, [city] NVARCHAR(MAX), [installation date] NVARCHAR(MAX) ); TABLE [status] ( [station id] INT, [bikes available] INT, [docks available] ...
SELECT AVG(T1.lat), AVG(T1.long) FROM station AS T1 JOIN trip AS T2 ON T1.id = T2.start_station_id
How many books are there?
-- Tables de la base de données (T-SQL) -- TABLE [publication] ( [publication id] INT, [book id] INT, [publisher] NVARCHAR(MAX), [publication date] NVARCHAR(MAX), [price] INT ); TABLE [book] ( [book id] INT, [title] NVARCHAR(MAX), [issues] INT, [writer] NVARCHAR(MAX) ); Question : ...
SELECT COUNT_BIG(*) FROM book
List the writers of the books in ascending alphabetical order.
-- Tables de la base de données (T-SQL) -- TABLE [publication] ( [publication id] INT, [book id] INT, [publisher] NVARCHAR(MAX), [publication date] NVARCHAR(MAX), [price] INT ); TABLE [book] ( [book id] INT, [title] NVARCHAR(MAX), [issues] INT, [writer] NVARCHAR(MAX) ); Question : ...
SELECT Writer FROM book ORDER BY CASE WHEN Writer IS NULL THEN 1 ELSE 0 END, Writer ASC
List the titles of the books in ascending order of issues.
-- Tables de la base de données (T-SQL) -- TABLE [publication] ( [publication id] INT, [book id] INT, [publisher] NVARCHAR(MAX), [publication date] NVARCHAR(MAX), [price] INT ); TABLE [book] ( [book id] INT, [title] NVARCHAR(MAX), [issues] INT, [writer] NVARCHAR(MAX) ); Question : ...
SELECT Title FROM book ORDER BY CASE WHEN Issues IS NULL THEN 1 ELSE 0 END, Issues ASC
What are the titles of the books whose writer is not "Elaine Lee"?
-- Tables de la base de données (T-SQL) -- TABLE [publication] ( [publication id] INT, [book id] INT, [publisher] NVARCHAR(MAX), [publication date] NVARCHAR(MAX), [price] INT ); TABLE [book] ( [book id] INT, [title] NVARCHAR(MAX), [issues] INT, [writer] NVARCHAR(MAX) ); Question : ...
SELECT Title FROM book WHERE Writer <> [Elaine Lee]
What are the title and issues of the books?
-- Tables de la base de données (T-SQL) -- TABLE [publication] ( [publication id] INT, [book id] INT, [publisher] NVARCHAR(MAX), [publication date] NVARCHAR(MAX), [price] INT ); TABLE [book] ( [book id] INT, [title] NVARCHAR(MAX), [issues] INT, [writer] NVARCHAR(MAX) ); Question : ...
SELECT Title, Issues FROM book
What are the dates of publications in descending order of price?
-- Tables de la base de données (T-SQL) -- TABLE [publication] ( [publication id] INT, [book id] INT, [publisher] NVARCHAR(MAX), [publication date] NVARCHAR(MAX), [price] INT ); TABLE [book] ( [book id] INT, [title] NVARCHAR(MAX), [issues] INT, [writer] NVARCHAR(MAX) ); Question : ...
SELECT Publication_Date FROM publication ORDER BY CASE WHEN Price IS NULL THEN 1 ELSE 0 END DESC, Price DESC
What are the distinct publishers of publications with price higher than 5000000?
-- Tables de la base de données (T-SQL) -- TABLE [publication] ( [publication id] INT, [book id] INT, [publisher] NVARCHAR(MAX), [publication date] NVARCHAR(MAX), [price] INT ); TABLE [book] ( [book id] INT, [title] NVARCHAR(MAX), [issues] INT, [writer] NVARCHAR(MAX) ); Question : ...
SELECT DISTINCT Publisher FROM publication WHERE Price > 5000000
List the publisher of the publication with the highest price.
-- Tables de la base de données (T-SQL) -- TABLE [publication] ( [publication id] INT, [book id] INT, [publisher] NVARCHAR(MAX), [publication date] NVARCHAR(MAX), [price] INT ); TABLE [book] ( [book id] INT, [title] NVARCHAR(MAX), [issues] INT, [writer] NVARCHAR(MAX) ); Question : ...
SELECT TOP 1 Publisher FROM publication ORDER BY CASE WHEN Price IS NULL THEN 1 ELSE 0 END DESC, Price DESC
List the publication dates of publications with 3 lowest prices.
-- Tables de la base de données (T-SQL) -- TABLE [publication] ( [publication id] INT, [book id] INT, [publisher] NVARCHAR(MAX), [publication date] NVARCHAR(MAX), [price] INT ); TABLE [book] ( [book id] INT, [title] NVARCHAR(MAX), [issues] INT, [writer] NVARCHAR(MAX) ); Question : ...
SELECT TOP 3 Publication_Date FROM publication ORDER BY CASE WHEN Price IS NULL THEN 1 ELSE 0 END, Price ASC
Show the title and publication dates of books.
-- Tables de la base de données (T-SQL) -- TABLE [publication] ( [publication id] INT, [book id] INT, [publisher] NVARCHAR(MAX), [publication date] NVARCHAR(MAX), [price] INT ); TABLE [book] ( [book id] INT, [title] NVARCHAR(MAX), [issues] INT, [writer] NVARCHAR(MAX) ); Question : ...
SELECT T1.Title, T2.Publication_Date FROM book AS T1 JOIN publication AS T2 ON T1.Book_ID = T2.Book_ID
Show writers who have published a book with price more than 4000000.
-- Tables de la base de données (T-SQL) -- TABLE [publication] ( [publication id] INT, [book id] INT, [publisher] NVARCHAR(MAX), [publication date] NVARCHAR(MAX), [price] INT ); TABLE [book] ( [book id] INT, [title] NVARCHAR(MAX), [issues] INT, [writer] NVARCHAR(MAX) ); Question : ...
SELECT T1.Writer FROM book AS T1 JOIN publication AS T2 ON T1.Book_ID = T2.Book_ID WHERE T2.Price > 4000000
Show the titles of books in descending order of publication price.
-- Tables de la base de données (T-SQL) -- TABLE [publication] ( [publication id] INT, [book id] INT, [publisher] NVARCHAR(MAX), [publication date] NVARCHAR(MAX), [price] INT ); TABLE [book] ( [book id] INT, [title] NVARCHAR(MAX), [issues] INT, [writer] NVARCHAR(MAX) ); Question : ...
SELECT T1.Title FROM book AS T1 JOIN publication AS T2 ON T1.Book_ID = T2.Book_ID ORDER BY CASE WHEN T2.Price IS NULL THEN 1 ELSE 0 END DESC, T2.Price DESC
Show publishers that have more than one publication.
-- Tables de la base de données (T-SQL) -- TABLE [publication] ( [publication id] INT, [book id] INT, [publisher] NVARCHAR(MAX), [publication date] NVARCHAR(MAX), [price] INT ); TABLE [book] ( [book id] INT, [title] NVARCHAR(MAX), [issues] INT, [writer] NVARCHAR(MAX) ); Question : ...
SELECT Publisher FROM publication GROUP BY Publisher HAVING COUNT_BIG(*) > 1
Show different publishers together with the number of publications they have.
-- Tables de la base de données (T-SQL) -- TABLE [publication] ( [publication id] INT, [book id] INT, [publisher] NVARCHAR(MAX), [publication date] NVARCHAR(MAX), [price] INT ); TABLE [book] ( [book id] INT, [title] NVARCHAR(MAX), [issues] INT, [writer] NVARCHAR(MAX) ); Question : ...
SELECT Publisher, COUNT_BIG(*) FROM publication GROUP BY Publisher
Please show the most common publication date.
-- Tables de la base de données (T-SQL) -- TABLE [publication] ( [publication id] INT, [book id] INT, [publisher] NVARCHAR(MAX), [publication date] NVARCHAR(MAX), [price] INT ); TABLE [book] ( [book id] INT, [title] NVARCHAR(MAX), [issues] INT, [writer] NVARCHAR(MAX) ); Question : ...
SELECT TOP 1 Publication_Date FROM publication GROUP BY Publication_Date ORDER BY CASE WHEN COUNT_BIG(*) IS NULL THEN 1 ELSE 0 END DESC, COUNT_BIG(*) DESC
List the writers who have written more than one book.
-- Tables de la base de données (T-SQL) -- TABLE [publication] ( [publication id] INT, [book id] INT, [publisher] NVARCHAR(MAX), [publication date] NVARCHAR(MAX), [price] INT ); TABLE [book] ( [book id] INT, [title] NVARCHAR(MAX), [issues] INT, [writer] NVARCHAR(MAX) ); Question : ...
SELECT Writer FROM book GROUP BY Writer HAVING COUNT_BIG(*) > 1
List the titles of books that are not published.
-- Tables de la base de données (T-SQL) -- TABLE [publication] ( [publication id] INT, [book id] INT, [publisher] NVARCHAR(MAX), [publication date] NVARCHAR(MAX), [price] INT ); TABLE [book] ( [book id] INT, [title] NVARCHAR(MAX), [issues] INT, [writer] NVARCHAR(MAX) ); Question : ...
SELECT Title FROM book WHERE NOT Book_ID IN (SELECT Book_ID FROM publication)
Show the publishers that have publications with price higher than 10000000 and publications with price lower than 5000000.
-- Tables de la base de données (T-SQL) -- TABLE [publication] ( [publication id] INT, [book id] INT, [publisher] NVARCHAR(MAX), [publication date] NVARCHAR(MAX), [price] INT ); TABLE [book] ( [book id] INT, [title] NVARCHAR(MAX), [issues] INT, [writer] NVARCHAR(MAX) ); Question : ...
SELECT Publisher FROM publication WHERE Price > 10000000 INTERSECT SELECT Publisher FROM publication WHERE Price < 5000000
What is the number of distinct publication dates?
-- Tables de la base de données (T-SQL) -- TABLE [publication] ( [publication id] INT, [book id] INT, [publisher] NVARCHAR(MAX), [publication date] NVARCHAR(MAX), [price] INT ); TABLE [book] ( [book id] INT, [title] NVARCHAR(MAX), [issues] INT, [writer] NVARCHAR(MAX) ); Question : ...
SELECT COUNT_BIG(DISTINCT Publication_Date) FROM publication
How many distinct publication dates are there in our record?
-- Tables de la base de données (T-SQL) -- TABLE [publication] ( [publication id] INT, [book id] INT, [publisher] NVARCHAR(MAX), [publication date] NVARCHAR(MAX), [price] INT ); TABLE [book] ( [book id] INT, [title] NVARCHAR(MAX), [issues] INT, [writer] NVARCHAR(MAX) ); Question : ...
SELECT COUNT_BIG(DISTINCT Publication_Date) FROM publication
Show the prices of publications whose publisher is either "Person" or "Wiley"
-- Tables de la base de données (T-SQL) -- TABLE [publication] ( [publication id] INT, [book id] INT, [publisher] NVARCHAR(MAX), [publication date] NVARCHAR(MAX), [price] INT ); TABLE [book] ( [book id] INT, [title] NVARCHAR(MAX), [issues] INT, [writer] NVARCHAR(MAX) ); Question : ...
SELECT Price FROM publication WHERE Publisher = [Person] OR Publisher = [Wiley]
How many actors are there?
-- Tables de la base de données (T-SQL) -- TABLE [musical] ( [musical id] INT, [name] NVARCHAR(MAX), [year] INT, [award] NVARCHAR(MAX), [category] NVARCHAR(MAX), [nominee] NVARCHAR(MAX), [result] NVARCHAR(MAX) ); TABLE [actor] ( [actor id] INT, [name] NVARCHAR(MAX), [musical id]...
SELECT COUNT_BIG(*) FROM actor
Count the number of actors.
-- Tables de la base de données (T-SQL) -- TABLE [musical] ( [musical id] INT, [name] NVARCHAR(MAX), [year] INT, [award] NVARCHAR(MAX), [category] NVARCHAR(MAX), [nominee] NVARCHAR(MAX), [result] NVARCHAR(MAX) ); TABLE [actor] ( [actor id] INT, [name] NVARCHAR(MAX), [musical id]...
SELECT COUNT_BIG(*) FROM actor
List the name of actors in ascending alphabetical order.
-- Tables de la base de données (T-SQL) -- TABLE [musical] ( [musical id] INT, [name] NVARCHAR(MAX), [year] INT, [award] NVARCHAR(MAX), [category] NVARCHAR(MAX), [nominee] NVARCHAR(MAX), [result] NVARCHAR(MAX) ); TABLE [actor] ( [actor id] INT, [name] NVARCHAR(MAX), [musical id]...
SELECT Name FROM actor ORDER BY CASE WHEN Name IS NULL THEN 1 ELSE 0 END, Name ASC
What are the names of actors, ordered alphabetically?
-- Tables de la base de données (T-SQL) -- TABLE [musical] ( [musical id] INT, [name] NVARCHAR(MAX), [year] INT, [award] NVARCHAR(MAX), [category] NVARCHAR(MAX), [nominee] NVARCHAR(MAX), [result] NVARCHAR(MAX) ); TABLE [actor] ( [actor id] INT, [name] NVARCHAR(MAX), [musical id]...
SELECT Name FROM actor ORDER BY CASE WHEN Name IS NULL THEN 1 ELSE 0 END, Name ASC
What are the characters and duration of actors?
-- Tables de la base de données (T-SQL) -- TABLE [musical] ( [musical id] INT, [name] NVARCHAR(MAX), [year] INT, [award] NVARCHAR(MAX), [category] NVARCHAR(MAX), [nominee] NVARCHAR(MAX), [result] NVARCHAR(MAX) ); TABLE [actor] ( [actor id] INT, [name] NVARCHAR(MAX), [musical id]...
SELECT Character, Duration FROM actor
Return the characters and durations for each actor.
-- Tables de la base de données (T-SQL) -- TABLE [musical] ( [musical id] INT, [name] NVARCHAR(MAX), [year] INT, [award] NVARCHAR(MAX), [category] NVARCHAR(MAX), [nominee] NVARCHAR(MAX), [result] NVARCHAR(MAX) ); TABLE [actor] ( [actor id] INT, [name] NVARCHAR(MAX), [musical id]...
SELECT Character, Duration FROM actor
List the name of actors whose age is not 20.
-- Tables de la base de données (T-SQL) -- TABLE [musical] ( [musical id] INT, [name] NVARCHAR(MAX), [year] INT, [award] NVARCHAR(MAX), [category] NVARCHAR(MAX), [nominee] NVARCHAR(MAX), [result] NVARCHAR(MAX) ); TABLE [actor] ( [actor id] INT, [name] NVARCHAR(MAX), [musical id]...
SELECT Name FROM actor WHERE Age <> 20
What are the names of actors who are not 20 years old?
-- Tables de la base de données (T-SQL) -- TABLE [musical] ( [musical id] INT, [name] NVARCHAR(MAX), [year] INT, [award] NVARCHAR(MAX), [category] NVARCHAR(MAX), [nominee] NVARCHAR(MAX), [result] NVARCHAR(MAX) ); TABLE [actor] ( [actor id] INT, [name] NVARCHAR(MAX), [musical id]...
SELECT Name FROM actor WHERE Age <> 20
What are the characters of actors in descending order of age?
-- Tables de la base de données (T-SQL) -- TABLE [musical] ( [musical id] INT, [name] NVARCHAR(MAX), [year] INT, [award] NVARCHAR(MAX), [category] NVARCHAR(MAX), [nominee] NVARCHAR(MAX), [result] NVARCHAR(MAX) ); TABLE [actor] ( [actor id] INT, [name] NVARCHAR(MAX), [musical id]...
SELECT Character FROM actor ORDER BY CASE WHEN age IS NULL THEN 1 ELSE 0 END DESC, age DESC
Return the characters for actors, ordered by age descending.
-- Tables de la base de données (T-SQL) -- TABLE [musical] ( [musical id] INT, [name] NVARCHAR(MAX), [year] INT, [award] NVARCHAR(MAX), [category] NVARCHAR(MAX), [nominee] NVARCHAR(MAX), [result] NVARCHAR(MAX) ); TABLE [actor] ( [actor id] INT, [name] NVARCHAR(MAX), [musical id]...
SELECT Character FROM actor ORDER BY CASE WHEN age IS NULL THEN 1 ELSE 0 END DESC, age DESC
What is the duration of the oldest actor?
-- Tables de la base de données (T-SQL) -- TABLE [musical] ( [musical id] INT, [name] NVARCHAR(MAX), [year] INT, [award] NVARCHAR(MAX), [category] NVARCHAR(MAX), [nominee] NVARCHAR(MAX), [result] NVARCHAR(MAX) ); TABLE [actor] ( [actor id] INT, [name] NVARCHAR(MAX), [musical id]...
SELECT TOP 1 Duration FROM actor ORDER BY CASE WHEN Age IS NULL THEN 1 ELSE 0 END DESC, Age DESC
Return the duration of the actor with the greatest age.
-- Tables de la base de données (T-SQL) -- TABLE [musical] ( [musical id] INT, [name] NVARCHAR(MAX), [year] INT, [award] NVARCHAR(MAX), [category] NVARCHAR(MAX), [nominee] NVARCHAR(MAX), [result] NVARCHAR(MAX) ); TABLE [actor] ( [actor id] INT, [name] NVARCHAR(MAX), [musical id]...
SELECT TOP 1 Duration FROM actor ORDER BY CASE WHEN Age IS NULL THEN 1 ELSE 0 END DESC, Age DESC
What are the names of musicals with nominee "Bob Fosse"?
-- Tables de la base de données (T-SQL) -- TABLE [musical] ( [musical id] INT, [name] NVARCHAR(MAX), [year] INT, [award] NVARCHAR(MAX), [category] NVARCHAR(MAX), [nominee] NVARCHAR(MAX), [result] NVARCHAR(MAX) ); TABLE [actor] ( [actor id] INT, [name] NVARCHAR(MAX), [musical id]...
SELECT Name FROM musical WHERE Nominee = [Bob Fosse]
Return the names of musicals who have the nominee Bob Fosse.
-- Tables de la base de données (T-SQL) -- TABLE [musical] ( [musical id] INT, [name] NVARCHAR(MAX), [year] INT, [award] NVARCHAR(MAX), [category] NVARCHAR(MAX), [nominee] NVARCHAR(MAX), [result] NVARCHAR(MAX) ); TABLE [actor] ( [actor id] INT, [name] NVARCHAR(MAX), [musical id]...
SELECT Name FROM musical WHERE Nominee = [Bob Fosse]
What are the distinct nominees of the musicals with the award that is not "Tony Award"?
-- Tables de la base de données (T-SQL) -- TABLE [musical] ( [musical id] INT, [name] NVARCHAR(MAX), [year] INT, [award] NVARCHAR(MAX), [category] NVARCHAR(MAX), [nominee] NVARCHAR(MAX), [result] NVARCHAR(MAX) ); TABLE [actor] ( [actor id] INT, [name] NVARCHAR(MAX), [musical id]...
SELECT DISTINCT Nominee FROM musical WHERE Award <> [Tony Award]
Return the different nominees of musicals that have an award that is not the Tony Award.
-- Tables de la base de données (T-SQL) -- TABLE [musical] ( [musical id] INT, [name] NVARCHAR(MAX), [year] INT, [award] NVARCHAR(MAX), [category] NVARCHAR(MAX), [nominee] NVARCHAR(MAX), [result] NVARCHAR(MAX) ); TABLE [actor] ( [actor id] INT, [name] NVARCHAR(MAX), [musical id]...
SELECT DISTINCT Nominee FROM musical WHERE Award <> [Tony Award]
Show names of actors and names of musicals they are in.
-- Tables de la base de données (T-SQL) -- TABLE [musical] ( [musical id] INT, [name] NVARCHAR(MAX), [year] INT, [award] NVARCHAR(MAX), [category] NVARCHAR(MAX), [nominee] NVARCHAR(MAX), [result] NVARCHAR(MAX) ); TABLE [actor] ( [actor id] INT, [name] NVARCHAR(MAX), [musical id]...
SELECT T1.Name, T2.Name FROM actor AS T1 JOIN musical AS T2 ON T1.Musical_ID = T2.Musical_ID
What are the names of actors and the musicals that they are in?
-- Tables de la base de données (T-SQL) -- TABLE [musical] ( [musical id] INT, [name] NVARCHAR(MAX), [year] INT, [award] NVARCHAR(MAX), [category] NVARCHAR(MAX), [nominee] NVARCHAR(MAX), [result] NVARCHAR(MAX) ); TABLE [actor] ( [actor id] INT, [name] NVARCHAR(MAX), [musical id]...
SELECT T1.Name, T2.Name FROM actor AS T1 JOIN musical AS T2 ON T1.Musical_ID = T2.Musical_ID
Show names of actors that have appeared in musical with name "The Phantom of the Opera".
-- Tables de la base de données (T-SQL) -- TABLE [musical] ( [musical id] INT, [name] NVARCHAR(MAX), [year] INT, [award] NVARCHAR(MAX), [category] NVARCHAR(MAX), [nominee] NVARCHAR(MAX), [result] NVARCHAR(MAX) ); TABLE [actor] ( [actor id] INT, [name] NVARCHAR(MAX), [musical id]...
SELECT T1.Name FROM actor AS T1 JOIN musical AS T2 ON T1.Musical_ID = T2.Musical_ID WHERE T2.Name = [The Phantom of the Opera]
What are the names of actors who have been in the musical titled The Phantom of the Opera?
-- Tables de la base de données (T-SQL) -- TABLE [musical] ( [musical id] INT, [name] NVARCHAR(MAX), [year] INT, [award] NVARCHAR(MAX), [category] NVARCHAR(MAX), [nominee] NVARCHAR(MAX), [result] NVARCHAR(MAX) ); TABLE [actor] ( [actor id] INT, [name] NVARCHAR(MAX), [musical id]...
SELECT T1.Name FROM actor AS T1 JOIN musical AS T2 ON T1.Musical_ID = T2.Musical_ID WHERE T2.Name = [The Phantom of the Opera]
Show names of actors in descending order of the year their musical is awarded.
-- Tables de la base de données (T-SQL) -- TABLE [musical] ( [musical id] INT, [name] NVARCHAR(MAX), [year] INT, [award] NVARCHAR(MAX), [category] NVARCHAR(MAX), [nominee] NVARCHAR(MAX), [result] NVARCHAR(MAX) ); TABLE [actor] ( [actor id] INT, [name] NVARCHAR(MAX), [musical id]...
SELECT T1.Name FROM actor AS T1 JOIN musical AS T2 ON T1.Musical_ID = T2.Musical_ID ORDER BY CASE WHEN T2.Year IS NULL THEN 1 ELSE 0 END DESC, T2.Year DESC
What are the names of actors ordered descending by the year in which their musical was awarded?
-- Tables de la base de données (T-SQL) -- TABLE [musical] ( [musical id] INT, [name] NVARCHAR(MAX), [year] INT, [award] NVARCHAR(MAX), [category] NVARCHAR(MAX), [nominee] NVARCHAR(MAX), [result] NVARCHAR(MAX) ); TABLE [actor] ( [actor id] INT, [name] NVARCHAR(MAX), [musical id]...
SELECT T1.Name FROM actor AS T1 JOIN musical AS T2 ON T1.Musical_ID = T2.Musical_ID ORDER BY CASE WHEN T2.Year IS NULL THEN 1 ELSE 0 END DESC, T2.Year DESC
Show names of musicals and the number of actors who have appeared in the musicals.
-- Tables de la base de données (T-SQL) -- TABLE [musical] ( [musical id] INT, [name] NVARCHAR(MAX), [year] INT, [award] NVARCHAR(MAX), [category] NVARCHAR(MAX), [nominee] NVARCHAR(MAX), [result] NVARCHAR(MAX) ); TABLE [actor] ( [actor id] INT, [name] NVARCHAR(MAX), [musical id]...
SELECT T2.Name, COUNT_BIG(*) FROM actor AS T1 JOIN musical AS T2 ON T1.Musical_ID = T2.Musical_ID GROUP BY T1.Musical_ID
How many actors have appeared in each musical?
-- Tables de la base de données (T-SQL) -- TABLE [musical] ( [musical id] INT, [name] NVARCHAR(MAX), [year] INT, [award] NVARCHAR(MAX), [category] NVARCHAR(MAX), [nominee] NVARCHAR(MAX), [result] NVARCHAR(MAX) ); TABLE [actor] ( [actor id] INT, [name] NVARCHAR(MAX), [musical id]...
SELECT T2.Name, COUNT_BIG(*) FROM actor AS T1 JOIN musical AS T2 ON T1.Musical_ID = T2.Musical_ID GROUP BY T1.Musical_ID
Show names of musicals which have at least three actors.
-- Tables de la base de données (T-SQL) -- TABLE [musical] ( [musical id] INT, [name] NVARCHAR(MAX), [year] INT, [award] NVARCHAR(MAX), [category] NVARCHAR(MAX), [nominee] NVARCHAR(MAX), [result] NVARCHAR(MAX) ); TABLE [actor] ( [actor id] INT, [name] NVARCHAR(MAX), [musical id]...
SELECT T2.Name FROM actor AS T1 JOIN musical AS T2 ON T1.Musical_ID = T2.Musical_ID GROUP BY T1.Musical_ID HAVING COUNT_BIG(*) >= 3
What are the names of musicals who have at 3 or more actors?
-- Tables de la base de données (T-SQL) -- TABLE [musical] ( [musical id] INT, [name] NVARCHAR(MAX), [year] INT, [award] NVARCHAR(MAX), [category] NVARCHAR(MAX), [nominee] NVARCHAR(MAX), [result] NVARCHAR(MAX) ); TABLE [actor] ( [actor id] INT, [name] NVARCHAR(MAX), [musical id]...
SELECT T2.Name FROM actor AS T1 JOIN musical AS T2 ON T1.Musical_ID = T2.Musical_ID GROUP BY T1.Musical_ID HAVING COUNT_BIG(*) >= 3
Show different nominees and the number of musicals they have been nominated.
-- Tables de la base de données (T-SQL) -- TABLE [musical] ( [musical id] INT, [name] NVARCHAR(MAX), [year] INT, [award] NVARCHAR(MAX), [category] NVARCHAR(MAX), [nominee] NVARCHAR(MAX), [result] NVARCHAR(MAX) ); TABLE [actor] ( [actor id] INT, [name] NVARCHAR(MAX), [musical id]...
SELECT Nominee, COUNT_BIG(*) FROM musical GROUP BY Nominee
How many musicals has each nominee been nominated for?
-- Tables de la base de données (T-SQL) -- TABLE [musical] ( [musical id] INT, [name] NVARCHAR(MAX), [year] INT, [award] NVARCHAR(MAX), [category] NVARCHAR(MAX), [nominee] NVARCHAR(MAX), [result] NVARCHAR(MAX) ); TABLE [actor] ( [actor id] INT, [name] NVARCHAR(MAX), [musical id]...
SELECT Nominee, COUNT_BIG(*) FROM musical GROUP BY Nominee
Please show the nominee who has been nominated the greatest number of times.
-- Tables de la base de données (T-SQL) -- TABLE [musical] ( [musical id] INT, [name] NVARCHAR(MAX), [year] INT, [award] NVARCHAR(MAX), [category] NVARCHAR(MAX), [nominee] NVARCHAR(MAX), [result] NVARCHAR(MAX) ); TABLE [actor] ( [actor id] INT, [name] NVARCHAR(MAX), [musical id]...
SELECT TOP 1 Nominee FROM musical GROUP BY Nominee ORDER BY CASE WHEN COUNT_BIG(*) IS NULL THEN 1 ELSE 0 END DESC, COUNT_BIG(*) DESC
Who is the nominee who has been nominated for the most musicals?
-- Tables de la base de données (T-SQL) -- TABLE [musical] ( [musical id] INT, [name] NVARCHAR(MAX), [year] INT, [award] NVARCHAR(MAX), [category] NVARCHAR(MAX), [nominee] NVARCHAR(MAX), [result] NVARCHAR(MAX) ); TABLE [actor] ( [actor id] INT, [name] NVARCHAR(MAX), [musical id]...
SELECT TOP 1 Nominee FROM musical GROUP BY Nominee ORDER BY CASE WHEN COUNT_BIG(*) IS NULL THEN 1 ELSE 0 END DESC, COUNT_BIG(*) DESC
List the most common result of the musicals.
-- Tables de la base de données (T-SQL) -- TABLE [musical] ( [musical id] INT, [name] NVARCHAR(MAX), [year] INT, [award] NVARCHAR(MAX), [category] NVARCHAR(MAX), [nominee] NVARCHAR(MAX), [result] NVARCHAR(MAX) ); TABLE [actor] ( [actor id] INT, [name] NVARCHAR(MAX), [musical id]...
SELECT TOP 1 RESULT FROM musical GROUP BY RESULT ORDER BY CASE WHEN COUNT_BIG(*) IS NULL THEN 1 ELSE 0 END DESC, COUNT_BIG(*) DESC
Return the most frequent result across all musicals.
-- Tables de la base de données (T-SQL) -- TABLE [musical] ( [musical id] INT, [name] NVARCHAR(MAX), [year] INT, [award] NVARCHAR(MAX), [category] NVARCHAR(MAX), [nominee] NVARCHAR(MAX), [result] NVARCHAR(MAX) ); TABLE [actor] ( [actor id] INT, [name] NVARCHAR(MAX), [musical id]...
SELECT TOP 1 RESULT FROM musical GROUP BY RESULT ORDER BY CASE WHEN COUNT_BIG(*) IS NULL THEN 1 ELSE 0 END DESC, COUNT_BIG(*) DESC
List the nominees that have been nominated more than two musicals.
-- Tables de la base de données (T-SQL) -- TABLE [musical] ( [musical id] INT, [name] NVARCHAR(MAX), [year] INT, [award] NVARCHAR(MAX), [category] NVARCHAR(MAX), [nominee] NVARCHAR(MAX), [result] NVARCHAR(MAX) ); TABLE [actor] ( [actor id] INT, [name] NVARCHAR(MAX), [musical id]...
SELECT Nominee FROM musical GROUP BY Nominee HAVING COUNT_BIG(*) > 2
Who are the nominees who have been nominated more than two times?
-- Tables de la base de données (T-SQL) -- TABLE [musical] ( [musical id] INT, [name] NVARCHAR(MAX), [year] INT, [award] NVARCHAR(MAX), [category] NVARCHAR(MAX), [nominee] NVARCHAR(MAX), [result] NVARCHAR(MAX) ); TABLE [actor] ( [actor id] INT, [name] NVARCHAR(MAX), [musical id]...
SELECT Nominee FROM musical GROUP BY Nominee HAVING COUNT_BIG(*) > 2
List the name of musicals that do not have actors.
-- Tables de la base de données (T-SQL) -- TABLE [musical] ( [musical id] INT, [name] NVARCHAR(MAX), [year] INT, [award] NVARCHAR(MAX), [category] NVARCHAR(MAX), [nominee] NVARCHAR(MAX), [result] NVARCHAR(MAX) ); TABLE [actor] ( [actor id] INT, [name] NVARCHAR(MAX), [musical id]...
SELECT Name FROM musical WHERE NOT Musical_ID IN (SELECT Musical_ID FROM actor)
What are the names of musicals who have no actors?
-- Tables de la base de données (T-SQL) -- TABLE [musical] ( [musical id] INT, [name] NVARCHAR(MAX), [year] INT, [award] NVARCHAR(MAX), [category] NVARCHAR(MAX), [nominee] NVARCHAR(MAX), [result] NVARCHAR(MAX) ); TABLE [actor] ( [actor id] INT, [name] NVARCHAR(MAX), [musical id]...
SELECT Name FROM musical WHERE NOT Musical_ID IN (SELECT Musical_ID FROM actor)
Show the nominees that have nominated musicals for both "Tony Award" and "Drama Desk Award".
-- Tables de la base de données (T-SQL) -- TABLE [musical] ( [musical id] INT, [name] NVARCHAR(MAX), [year] INT, [award] NVARCHAR(MAX), [category] NVARCHAR(MAX), [nominee] NVARCHAR(MAX), [result] NVARCHAR(MAX) ); TABLE [actor] ( [actor id] INT, [name] NVARCHAR(MAX), [musical id]...
SELECT Nominee FROM musical WHERE Award = [Tony Award] INTERSECT SELECT Nominee FROM musical WHERE Award = [Drama Desk Award]
Who are the nominees who have been nominated for both a Tony Award and a Drama Desk Award?
-- Tables de la base de données (T-SQL) -- TABLE [musical] ( [musical id] INT, [name] NVARCHAR(MAX), [year] INT, [award] NVARCHAR(MAX), [category] NVARCHAR(MAX), [nominee] NVARCHAR(MAX), [result] NVARCHAR(MAX) ); TABLE [actor] ( [actor id] INT, [name] NVARCHAR(MAX), [musical id]...
SELECT Nominee FROM musical WHERE Award = [Tony Award] INTERSECT SELECT Nominee FROM musical WHERE Award = [Drama Desk Award]
Show the musical nominee with award "Bob Fosse" or "Cleavant Derricks".
-- Tables de la base de données (T-SQL) -- TABLE [musical] ( [musical id] INT, [name] NVARCHAR(MAX), [year] INT, [award] NVARCHAR(MAX), [category] NVARCHAR(MAX), [nominee] NVARCHAR(MAX), [result] NVARCHAR(MAX) ); TABLE [actor] ( [actor id] INT, [name] NVARCHAR(MAX), [musical id]...
SELECT Nominee FROM musical WHERE Award = [Tony Award] OR Award = [Cleavant Derricks]
Who are the nominees who were nominated for either of the Bob Fosse or Cleavant Derricks awards?
-- Tables de la base de données (T-SQL) -- TABLE [musical] ( [musical id] INT, [name] NVARCHAR(MAX), [year] INT, [award] NVARCHAR(MAX), [category] NVARCHAR(MAX), [nominee] NVARCHAR(MAX), [result] NVARCHAR(MAX) ); TABLE [actor] ( [actor id] INT, [name] NVARCHAR(MAX), [musical id]...
SELECT Nominee FROM musical WHERE Award = [Tony Award] OR Award = [Cleavant Derricks]
Find the emails of the user named "Mary".
-- Tables de la base de données (T-SQL) -- TABLE [follows] ( [user id] INT, [follower id] INT ); TABLE [tweets] ( [id] INT, [user id] INT, [text] NVARCHAR(MAX), [create date] NVARCHAR(MAX) ); Question : Find the emails of the user named "Mary".
SELECT email FROM user_profiles WHERE name = 'Mary'
What is the partition id of the user named "Iron Man".
-- Tables de la base de données (T-SQL) -- TABLE [follows] ( [user id] INT, [follower id] INT ); TABLE [tweets] ( [id] INT, [user id] INT, [text] NVARCHAR(MAX), [create date] NVARCHAR(MAX) ); Question : What is the partition id of the user named "Iron Man".
SELECT partitionid FROM user_profiles WHERE name = 'Iron Man'
How many users are there?
-- Tables de la base de données (T-SQL) -- TABLE [follows] ( [user id] INT, [follower id] INT ); TABLE [tweets] ( [id] INT, [user id] INT, [text] NVARCHAR(MAX), [create date] NVARCHAR(MAX) ); Question : How many users are there?
SELECT COUNT_BIG(*) FROM user_profiles
How many followers does each user have?
-- Tables de la base de données (T-SQL) -- TABLE [follows] ( [user id] INT, [follower id] INT ); TABLE [tweets] ( [id] INT, [user id] INT, [text] NVARCHAR(MAX), [create date] NVARCHAR(MAX) ); Question : How many followers does each user have?
SELECT COUNT_BIG(*) FROM follows
Find the number of followers for each user.
-- Tables de la base de données (T-SQL) -- TABLE [follows] ( [user id] INT, [follower id] INT ); TABLE [tweets] ( [id] INT, [user id] INT, [text] NVARCHAR(MAX), [create date] NVARCHAR(MAX) ); Question : Find the number of followers for each user.
SELECT COUNT_BIG(*) FROM follows GROUP BY f1
Find the number of tweets in record.
-- Tables de la base de données (T-SQL) -- TABLE [follows] ( [user id] INT, [follower id] INT ); TABLE [tweets] ( [id] INT, [user id] INT, [text] NVARCHAR(MAX), [create date] NVARCHAR(MAX) ); Question : Find the number of tweets in record.
SELECT COUNT_BIG(*) FROM tweets
Find the number of users who posted some tweets.
-- Tables de la base de données (T-SQL) -- TABLE [follows] ( [user id] INT, [follower id] INT ); TABLE [tweets] ( [id] INT, [user id] INT, [text] NVARCHAR(MAX), [create date] NVARCHAR(MAX) ); Question : Find the number of users who posted some tweets.
SELECT COUNT_BIG(DISTINCT UID) FROM tweets
Find the name and email of the user whose name contains the word ‘Swift’.
-- Tables de la base de données (T-SQL) -- TABLE [follows] ( [user id] INT, [follower id] INT ); TABLE [tweets] ( [id] INT, [user id] INT, [text] NVARCHAR(MAX), [create date] NVARCHAR(MAX) ); Question : Find the name and email of the user whose name contains the word ‘Swift’.
SELECT name, email FROM user_profiles WHERE name LIKE '%Swift%'
Find the names of users whose emails contain ‘superstar’ or ‘edu’.
-- Tables de la base de données (T-SQL) -- TABLE [follows] ( [user id] INT, [follower id] INT ); TABLE [tweets] ( [id] INT, [user id] INT, [text] NVARCHAR(MAX), [create date] NVARCHAR(MAX) ); Question : Find the names of users whose emails contain ‘superstar’ or ‘edu’.
SELECT name FROM user_profiles WHERE email LIKE '%superstar%' OR email LIKE '%edu%'
Return the text of tweets about the topic 'intern'.
-- Tables de la base de données (T-SQL) -- TABLE [follows] ( [user id] INT, [follower id] INT ); TABLE [tweets] ( [id] INT, [user id] INT, [text] NVARCHAR(MAX), [create date] NVARCHAR(MAX) ); Question : Return the text of tweets about the topic 'intern'.
SELECT text FROM tweets WHERE text LIKE '%intern%'
Find the name and email of the users who have more than 1000 followers.
-- Tables de la base de données (T-SQL) -- TABLE [follows] ( [user id] INT, [follower id] INT ); TABLE [tweets] ( [id] INT, [user id] INT, [text] NVARCHAR(MAX), [create date] NVARCHAR(MAX) ); Question : Find the name and email of the users who have more than 1000 followers.
SELECT name, email FROM user_profiles WHERE followers > 1000
Find the names of the users whose number of followers is greater than that of the user named "Tyler Swift".
-- Tables de la base de données (T-SQL) -- TABLE [follows] ( [user id] INT, [follower id] INT ); TABLE [tweets] ( [id] INT, [user id] INT, [text] NVARCHAR(MAX), [create date] NVARCHAR(MAX) ); Question : Find the names of the users whose number of followers is greater than that of the user name...
SELECT T1.name FROM user_profiles AS T1 JOIN follows AS T2 ON T1.uid = T2.f1 GROUP BY T2.f1 HAVING COUNT_BIG(*) > (SELECT COUNT_BIG(*) FROM user_profiles AS T1 JOIN follows AS T2 ON T1.uid = T2.f1 WHERE T1.name = 'Tyler Swift')
Find the name and email for the users who have more than one follower.
-- Tables de la base de données (T-SQL) -- TABLE [follows] ( [user id] INT, [follower id] INT ); TABLE [tweets] ( [id] INT, [user id] INT, [text] NVARCHAR(MAX), [create date] NVARCHAR(MAX) ); Question : Find the name and email for the users who have more than one follower.
SELECT T1.name, T1.email FROM user_profiles AS T1 JOIN follows AS T2 ON T1.uid = T2.f1 GROUP BY T2.f1 HAVING COUNT_BIG(*) > 1
Find the names of users who have more than one tweet.
-- Tables de la base de données (T-SQL) -- TABLE [follows] ( [user id] INT, [follower id] INT ); TABLE [tweets] ( [id] INT, [user id] INT, [text] NVARCHAR(MAX), [create date] NVARCHAR(MAX) ); Question : Find the names of users who have more than one tweet.
SELECT T1.name FROM user_profiles AS T1 JOIN tweets AS T2 ON T1.uid = T2.uid GROUP BY T2.uid HAVING COUNT_BIG(*) > 1
Find the id of users who are followed by Mary and Susan.
-- Tables de la base de données (T-SQL) -- TABLE [follows] ( [user id] INT, [follower id] INT ); TABLE [tweets] ( [id] INT, [user id] INT, [text] NVARCHAR(MAX), [create date] NVARCHAR(MAX) ); Question : Find the id of users who are followed by Mary and Susan.
SELECT T2.f1 FROM user_profiles AS T1 JOIN follows AS T2 ON T1.uid = T2.f2 WHERE T1.name = [Mary] INTERSECT SELECT T2.f1 FROM user_profiles AS T1 JOIN follows AS T2 ON T1.uid = T2.f2 WHERE T1.name = [Susan]
Find the id of users who are followed by Mary or Susan.
-- Tables de la base de données (T-SQL) -- TABLE [follows] ( [user id] INT, [follower id] INT ); TABLE [tweets] ( [id] INT, [user id] INT, [text] NVARCHAR(MAX), [create date] NVARCHAR(MAX) ); Question : Find the id of users who are followed by Mary or Susan.
SELECT T2.f1 FROM user_profiles AS T1 JOIN follows AS T2 ON T1.uid = T2.f2 WHERE T1.name = [Mary] OR T1.name = [Susan]
Find the name of the user who has the largest number of followers.
-- Tables de la base de données (T-SQL) -- TABLE [follows] ( [user id] INT, [follower id] INT ); TABLE [tweets] ( [id] INT, [user id] INT, [text] NVARCHAR(MAX), [create date] NVARCHAR(MAX) ); Question : Find the name of the user who has the largest number of followers.
SELECT TOP 1 name FROM user_profiles ORDER BY CASE WHEN followers IS NULL THEN 1 ELSE 0 END DESC, followers DESC
Find the name and email of the user followed by the least number of people.
-- Tables de la base de données (T-SQL) -- TABLE [follows] ( [user id] INT, [follower id] INT ); TABLE [tweets] ( [id] INT, [user id] INT, [text] NVARCHAR(MAX), [create date] NVARCHAR(MAX) ); Question : Find the name and email of the user followed by the least number of people.
SELECT TOP 1 name, email FROM user_profiles ORDER BY CASE WHEN followers IS NULL THEN 1 ELSE 0 END, followers
List the name and number of followers for each user, and sort the results by the number of followers in descending order.
-- Tables de la base de données (T-SQL) -- TABLE [follows] ( [user id] INT, [follower id] INT ); TABLE [tweets] ( [id] INT, [user id] INT, [text] NVARCHAR(MAX), [create date] NVARCHAR(MAX) ); Question : List the name and number of followers for each user, and sort the results by the number of ...
SELECT name, followers FROM user_profiles ORDER BY CASE WHEN followers IS NULL THEN 1 ELSE 0 END DESC, followers DESC
List the names of 5 users followed by the largest number of other users.
-- Tables de la base de données (T-SQL) -- TABLE [follows] ( [user id] INT, [follower id] INT ); TABLE [tweets] ( [id] INT, [user id] INT, [text] NVARCHAR(MAX), [create date] NVARCHAR(MAX) ); Question : List the names of 5 users followed by the largest number of other users.
SELECT TOP 5 name FROM user_profiles ORDER BY CASE WHEN followers IS NULL THEN 1 ELSE 0 END DESC, followers DESC
List the text of all tweets in the order of date.
-- Tables de la base de données (T-SQL) -- TABLE [follows] ( [user id] INT, [follower id] INT ); TABLE [tweets] ( [id] INT, [user id] INT, [text] NVARCHAR(MAX), [create date] NVARCHAR(MAX) ); Question : List the text of all tweets in the order of date.
SELECT text FROM tweets ORDER BY CASE WHEN createdate IS NULL THEN 1 ELSE 0 END, createdate
Find the name of each user and number of tweets tweeted by each of them.
-- Tables de la base de données (T-SQL) -- TABLE [follows] ( [user id] INT, [follower id] INT ); TABLE [tweets] ( [id] INT, [user id] INT, [text] NVARCHAR(MAX), [create date] NVARCHAR(MAX) ); Question : Find the name of each user and number of tweets tweeted by each of them.
SELECT T1.name, COUNT_BIG(*) FROM user_profiles AS T1 JOIN tweets AS T2 ON T1.uid = T2.uid GROUP BY T2.uid
Find the name and partition id for users who tweeted less than twice.
-- Tables de la base de données (T-SQL) -- TABLE [follows] ( [user id] INT, [follower id] INT ); TABLE [tweets] ( [id] INT, [user id] INT, [text] NVARCHAR(MAX), [create date] NVARCHAR(MAX) ); Question : Find the name and partition id for users who tweeted less than twice.
SELECT T1.name, T1.partitionid FROM user_profiles AS T1 JOIN tweets AS T2 ON T1.uid = T2.uid GROUP BY T2.uid HAVING COUNT_BIG(*) < 2
Find the name of the user who tweeted more than once, and number of tweets tweeted by them.
-- Tables de la base de données (T-SQL) -- TABLE [follows] ( [user id] INT, [follower id] INT ); TABLE [tweets] ( [id] INT, [user id] INT, [text] NVARCHAR(MAX), [create date] NVARCHAR(MAX) ); Question : Find the name of the user who tweeted more than once, and number of tweets tweeted by them.
SELECT T1.name, COUNT_BIG(*) FROM user_profiles AS T1 JOIN tweets AS T2 ON T1.uid = T2.uid GROUP BY T2.uid HAVING COUNT_BIG(*) > 1
Find the average number of followers for the users who do not have any tweet.
-- Tables de la base de données (T-SQL) -- TABLE [follows] ( [user id] INT, [follower id] INT ); TABLE [tweets] ( [id] INT, [user id] INT, [text] NVARCHAR(MAX), [create date] NVARCHAR(MAX) ); Question : Find the average number of followers for the users who do not have any tweet.
SELECT AVG(followers) FROM user_profiles WHERE NOT UID IN (SELECT UID FROM tweets)
Find the average number of followers for the users who had some tweets.
-- Tables de la base de données (T-SQL) -- TABLE [follows] ( [user id] INT, [follower id] INT ); TABLE [tweets] ( [id] INT, [user id] INT, [text] NVARCHAR(MAX), [create date] NVARCHAR(MAX) ); Question : Find the average number of followers for the users who had some tweets.
SELECT AVG(followers) FROM user_profiles WHERE UID IN (SELECT UID FROM tweets)