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What si the youngest employee's first and last name?
-- Tables de la base de données (T-SQL) -- TABLE [artists] ( [id] NVARCHAR(MAX), [name] NVARCHAR(MAX) ); TABLE [albums] ( [id] INT, [title] NVARCHAR(MAX), [artist id] INT ); TABLE [employees] ( [id] INT, [last name] NVARCHAR(MAX), [first name] NVARCHAR(MAX), [title] NVARCHAR(MAX), ...
SELECT TOP 1 first_name, last_name FROM employees ORDER BY CASE WHEN birth_date IS NULL THEN 1 ELSE 0 END DESC, birth_date DESC
List top 10 employee work longest in the company. List employee's first and last name.
-- Tables de la base de données (T-SQL) -- TABLE [artists] ( [id] NVARCHAR(MAX), [name] NVARCHAR(MAX) ); TABLE [albums] ( [id] INT, [title] NVARCHAR(MAX), [artist id] INT ); TABLE [employees] ( [id] INT, [last name] NVARCHAR(MAX), [first name] NVARCHAR(MAX), [title] NVARCHAR(MAX), ...
SELECT TOP 10 first_name, last_name FROM employees ORDER BY CASE WHEN hire_date IS NULL THEN 1 ELSE 0 END, hire_date ASC
What are the first and last names of the top 10 longest-serving employees?
-- Tables de la base de données (T-SQL) -- TABLE [artists] ( [id] NVARCHAR(MAX), [name] NVARCHAR(MAX) ); TABLE [albums] ( [id] INT, [title] NVARCHAR(MAX), [artist id] INT ); TABLE [employees] ( [id] INT, [last name] NVARCHAR(MAX), [first name] NVARCHAR(MAX), [title] NVARCHAR(MAX), ...
SELECT TOP 10 first_name, last_name FROM employees ORDER BY CASE WHEN hire_date IS NULL THEN 1 ELSE 0 END, hire_date ASC
Find the number of employees whose title is IT Staff from each city?
-- Tables de la base de données (T-SQL) -- TABLE [artists] ( [id] NVARCHAR(MAX), [name] NVARCHAR(MAX) ); TABLE [albums] ( [id] INT, [title] NVARCHAR(MAX), [artist id] INT ); TABLE [employees] ( [id] INT, [last name] NVARCHAR(MAX), [first name] NVARCHAR(MAX), [title] NVARCHAR(MAX), ...
SELECT COUNT_BIG(*), city FROM employees WHERE title = 'IT Staff' GROUP BY city
How many employees who are IT staff are from each city?
-- Tables de la base de données (T-SQL) -- TABLE [artists] ( [id] NVARCHAR(MAX), [name] NVARCHAR(MAX) ); TABLE [albums] ( [id] INT, [title] NVARCHAR(MAX), [artist id] INT ); TABLE [employees] ( [id] INT, [last name] NVARCHAR(MAX), [first name] NVARCHAR(MAX), [title] NVARCHAR(MAX), ...
SELECT COUNT_BIG(*), city FROM employees WHERE title = 'IT Staff' GROUP BY city
Which employee manage most number of peoples? List employee's first and last name, and number of people report to that employee.
-- Tables de la base de données (T-SQL) -- TABLE [artists] ( [id] NVARCHAR(MAX), [name] NVARCHAR(MAX) ); TABLE [albums] ( [id] INT, [title] NVARCHAR(MAX), [artist id] INT ); TABLE [employees] ( [id] INT, [last name] NVARCHAR(MAX), [first name] NVARCHAR(MAX), [title] NVARCHAR(MAX), ...
SELECT TOP 1 T2.first_name, T2.last_name, COUNT_BIG(T1.reports_to) FROM employees AS T1 JOIN employees AS T2 ON T1.reports_to = T2.id GROUP BY T1.reports_to ORDER BY CASE WHEN COUNT_BIG(T1.reports_to) IS NULL THEN 1 ELSE 0 END DESC, COUNT_BIG(T1.reports_to) DESC
What are the first and last names of all the employees and how many people report to them?
-- Tables de la base de données (T-SQL) -- TABLE [artists] ( [id] NVARCHAR(MAX), [name] NVARCHAR(MAX) ); TABLE [albums] ( [id] INT, [title] NVARCHAR(MAX), [artist id] INT ); TABLE [employees] ( [id] INT, [last name] NVARCHAR(MAX), [first name] NVARCHAR(MAX), [title] NVARCHAR(MAX), ...
SELECT TOP 1 T2.first_name, T2.last_name, COUNT_BIG(T1.reports_to) FROM employees AS T1 JOIN employees AS T2 ON T1.reports_to = T2.id GROUP BY T1.reports_to ORDER BY CASE WHEN COUNT_BIG(T1.reports_to) IS NULL THEN 1 ELSE 0 END DESC, COUNT_BIG(T1.reports_to) DESC
How many orders does Lucas Mancini has?
-- Tables de la base de données (T-SQL) -- TABLE [artists] ( [id] NVARCHAR(MAX), [name] NVARCHAR(MAX) ); TABLE [albums] ( [id] INT, [title] NVARCHAR(MAX), [artist id] INT ); TABLE [employees] ( [id] INT, [last name] NVARCHAR(MAX), [first name] NVARCHAR(MAX), [title] NVARCHAR(MAX), ...
SELECT COUNT_BIG(*) FROM customers AS T1 JOIN invoices AS T2 ON T1.id = T2.customer_id WHERE T1.first_name = [Lucas] AND T1.last_name = [Mancini]
How many orders does Luca Mancini have in his invoices?
-- Tables de la base de données (T-SQL) -- TABLE [artists] ( [id] NVARCHAR(MAX), [name] NVARCHAR(MAX) ); TABLE [albums] ( [id] INT, [title] NVARCHAR(MAX), [artist id] INT ); TABLE [employees] ( [id] INT, [last name] NVARCHAR(MAX), [first name] NVARCHAR(MAX), [title] NVARCHAR(MAX), ...
SELECT COUNT_BIG(*) FROM customers AS T1 JOIN invoices AS T2 ON T1.id = T2.customer_id WHERE T1.first_name = [Lucas] AND T1.last_name = [Mancini]
What is the total amount of money spent by Lucas Mancini?
-- Tables de la base de données (T-SQL) -- TABLE [artists] ( [id] NVARCHAR(MAX), [name] NVARCHAR(MAX) ); TABLE [albums] ( [id] INT, [title] NVARCHAR(MAX), [artist id] INT ); TABLE [employees] ( [id] INT, [last name] NVARCHAR(MAX), [first name] NVARCHAR(MAX), [title] NVARCHAR(MAX), ...
SELECT SUM(T2.total) FROM customers AS T1 JOIN invoices AS T2 ON T1.id = T2.customer_id WHERE T1.first_name = [Lucas] AND T1.last_name = [Mancini]
How much money did Lucas Mancini spend?
-- Tables de la base de données (T-SQL) -- TABLE [artists] ( [id] NVARCHAR(MAX), [name] NVARCHAR(MAX) ); TABLE [albums] ( [id] INT, [title] NVARCHAR(MAX), [artist id] INT ); TABLE [employees] ( [id] INT, [last name] NVARCHAR(MAX), [first name] NVARCHAR(MAX), [title] NVARCHAR(MAX), ...
SELECT SUM(T2.total) FROM customers AS T1 JOIN invoices AS T2 ON T1.id = T2.customer_id WHERE T1.first_name = [Lucas] AND T1.last_name = [Mancini]
List all media types.
-- Tables de la base de données (T-SQL) -- TABLE [artists] ( [id] NVARCHAR(MAX), [name] NVARCHAR(MAX) ); TABLE [albums] ( [id] INT, [title] NVARCHAR(MAX), [artist id] INT ); TABLE [employees] ( [id] INT, [last name] NVARCHAR(MAX), [first name] NVARCHAR(MAX), [title] NVARCHAR(MAX), ...
SELECT name FROM media_types
What are the names of all the media types?
-- Tables de la base de données (T-SQL) -- TABLE [artists] ( [id] NVARCHAR(MAX), [name] NVARCHAR(MAX) ); TABLE [albums] ( [id] INT, [title] NVARCHAR(MAX), [artist id] INT ); TABLE [employees] ( [id] INT, [last name] NVARCHAR(MAX), [first name] NVARCHAR(MAX), [title] NVARCHAR(MAX), ...
SELECT name FROM media_types
List all different genre types.
-- Tables de la base de données (T-SQL) -- TABLE [artists] ( [id] NVARCHAR(MAX), [name] NVARCHAR(MAX) ); TABLE [albums] ( [id] INT, [title] NVARCHAR(MAX), [artist id] INT ); TABLE [employees] ( [id] INT, [last name] NVARCHAR(MAX), [first name] NVARCHAR(MAX), [title] NVARCHAR(MAX), ...
SELECT DISTINCT name FROM genres
What are the different names of the genres?
-- Tables de la base de données (T-SQL) -- TABLE [artists] ( [id] NVARCHAR(MAX), [name] NVARCHAR(MAX) ); TABLE [albums] ( [id] INT, [title] NVARCHAR(MAX), [artist id] INT ); TABLE [employees] ( [id] INT, [last name] NVARCHAR(MAX), [first name] NVARCHAR(MAX), [title] NVARCHAR(MAX), ...
SELECT DISTINCT name FROM genres
List the name of all playlist.
-- Tables de la base de données (T-SQL) -- TABLE [artists] ( [id] NVARCHAR(MAX), [name] NVARCHAR(MAX) ); TABLE [albums] ( [id] INT, [title] NVARCHAR(MAX), [artist id] INT ); TABLE [employees] ( [id] INT, [last name] NVARCHAR(MAX), [first name] NVARCHAR(MAX), [title] NVARCHAR(MAX), ...
SELECT name FROM playlists
What are the names of all the playlists?
-- Tables de la base de données (T-SQL) -- TABLE [artists] ( [id] NVARCHAR(MAX), [name] NVARCHAR(MAX) ); TABLE [albums] ( [id] INT, [title] NVARCHAR(MAX), [artist id] INT ); TABLE [employees] ( [id] INT, [last name] NVARCHAR(MAX), [first name] NVARCHAR(MAX), [title] NVARCHAR(MAX), ...
SELECT name FROM playlists
Who is the composer of track Fast As a Shark?
-- Tables de la base de données (T-SQL) -- TABLE [artists] ( [id] NVARCHAR(MAX), [name] NVARCHAR(MAX) ); TABLE [albums] ( [id] INT, [title] NVARCHAR(MAX), [artist id] INT ); TABLE [employees] ( [id] INT, [last name] NVARCHAR(MAX), [first name] NVARCHAR(MAX), [title] NVARCHAR(MAX), ...
SELECT composer FROM tracks WHERE name = [Fast As a Shark]
What is the composer who created the track "Fast As a Shark"?
-- Tables de la base de données (T-SQL) -- TABLE [artists] ( [id] NVARCHAR(MAX), [name] NVARCHAR(MAX) ); TABLE [albums] ( [id] INT, [title] NVARCHAR(MAX), [artist id] INT ); TABLE [employees] ( [id] INT, [last name] NVARCHAR(MAX), [first name] NVARCHAR(MAX), [title] NVARCHAR(MAX), ...
SELECT composer FROM tracks WHERE name = [Fast As a Shark]
How long does track Fast As a Shark has?
-- Tables de la base de données (T-SQL) -- TABLE [artists] ( [id] NVARCHAR(MAX), [name] NVARCHAR(MAX) ); TABLE [albums] ( [id] INT, [title] NVARCHAR(MAX), [artist id] INT ); TABLE [employees] ( [id] INT, [last name] NVARCHAR(MAX), [first name] NVARCHAR(MAX), [title] NVARCHAR(MAX), ...
SELECT milliseconds FROM tracks WHERE name = [Fast As a Shark]
How many milliseconds long is Fast As a Shark?
-- Tables de la base de données (T-SQL) -- TABLE [artists] ( [id] NVARCHAR(MAX), [name] NVARCHAR(MAX) ); TABLE [albums] ( [id] INT, [title] NVARCHAR(MAX), [artist id] INT ); TABLE [employees] ( [id] INT, [last name] NVARCHAR(MAX), [first name] NVARCHAR(MAX), [title] NVARCHAR(MAX), ...
SELECT milliseconds FROM tracks WHERE name = [Fast As a Shark]
What is the name of tracks whose genre is Rock?
-- Tables de la base de données (T-SQL) -- TABLE [artists] ( [id] NVARCHAR(MAX), [name] NVARCHAR(MAX) ); TABLE [albums] ( [id] INT, [title] NVARCHAR(MAX), [artist id] INT ); TABLE [employees] ( [id] INT, [last name] NVARCHAR(MAX), [first name] NVARCHAR(MAX), [title] NVARCHAR(MAX), ...
SELECT T2.name FROM genres AS T1 JOIN tracks AS T2 ON T1.id = T2.genre_id WHERE T1.name = [Rock]
What is the name of all tracks in the Rock genre?
-- Tables de la base de données (T-SQL) -- TABLE [artists] ( [id] NVARCHAR(MAX), [name] NVARCHAR(MAX) ); TABLE [albums] ( [id] INT, [title] NVARCHAR(MAX), [artist id] INT ); TABLE [employees] ( [id] INT, [last name] NVARCHAR(MAX), [first name] NVARCHAR(MAX), [title] NVARCHAR(MAX), ...
SELECT T2.name FROM genres AS T1 JOIN tracks AS T2 ON T1.id = T2.genre_id WHERE T1.name = [Rock]
What is title of album which track Balls to the Wall belongs to?
-- Tables de la base de données (T-SQL) -- TABLE [artists] ( [id] NVARCHAR(MAX), [name] NVARCHAR(MAX) ); TABLE [albums] ( [id] INT, [title] NVARCHAR(MAX), [artist id] INT ); TABLE [employees] ( [id] INT, [last name] NVARCHAR(MAX), [first name] NVARCHAR(MAX), [title] NVARCHAR(MAX), ...
SELECT T1.title FROM albums AS T1 JOIN tracks AS T2 ON T1.id = T2.genre_id WHERE T2.name = [Balls to the Wall]
What is the name of the album that has the track Ball to the Wall?
-- Tables de la base de données (T-SQL) -- TABLE [artists] ( [id] NVARCHAR(MAX), [name] NVARCHAR(MAX) ); TABLE [albums] ( [id] INT, [title] NVARCHAR(MAX), [artist id] INT ); TABLE [employees] ( [id] INT, [last name] NVARCHAR(MAX), [first name] NVARCHAR(MAX), [title] NVARCHAR(MAX), ...
SELECT T1.title FROM albums AS T1 JOIN tracks AS T2 ON T1.id = T2.genre_id WHERE T2.name = [Balls to the Wall]
List name of all tracks in Balls to the Wall.
-- Tables de la base de données (T-SQL) -- TABLE [artists] ( [id] NVARCHAR(MAX), [name] NVARCHAR(MAX) ); TABLE [albums] ( [id] INT, [title] NVARCHAR(MAX), [artist id] INT ); TABLE [employees] ( [id] INT, [last name] NVARCHAR(MAX), [first name] NVARCHAR(MAX), [title] NVARCHAR(MAX), ...
SELECT T2.name FROM albums AS T1 JOIN tracks AS T2 ON T1.id = T2.genre_id WHERE T1.title = [Balls to the Wall]
What is the name of all tracks in the album named Balls to the Wall?
-- Tables de la base de données (T-SQL) -- TABLE [artists] ( [id] NVARCHAR(MAX), [name] NVARCHAR(MAX) ); TABLE [albums] ( [id] INT, [title] NVARCHAR(MAX), [artist id] INT ); TABLE [employees] ( [id] INT, [last name] NVARCHAR(MAX), [first name] NVARCHAR(MAX), [title] NVARCHAR(MAX), ...
SELECT T2.name FROM albums AS T1 JOIN tracks AS T2 ON T1.id = T2.genre_id WHERE T1.title = [Balls to the Wall]
List title of albums have the number of tracks greater than 10.
-- Tables de la base de données (T-SQL) -- TABLE [artists] ( [id] NVARCHAR(MAX), [name] NVARCHAR(MAX) ); TABLE [albums] ( [id] INT, [title] NVARCHAR(MAX), [artist id] INT ); TABLE [employees] ( [id] INT, [last name] NVARCHAR(MAX), [first name] NVARCHAR(MAX), [title] NVARCHAR(MAX), ...
SELECT T1.title FROM albums AS T1 JOIN tracks AS T2 ON T1.id = T2.album_id GROUP BY T1.id HAVING COUNT_BIG(T1.id) > 10
What are the names of the albums that have more than 10 tracks?
-- Tables de la base de données (T-SQL) -- TABLE [artists] ( [id] NVARCHAR(MAX), [name] NVARCHAR(MAX) ); TABLE [albums] ( [id] INT, [title] NVARCHAR(MAX), [artist id] INT ); TABLE [employees] ( [id] INT, [last name] NVARCHAR(MAX), [first name] NVARCHAR(MAX), [title] NVARCHAR(MAX), ...
SELECT T1.title FROM albums AS T1 JOIN tracks AS T2 ON T1.id = T2.album_id GROUP BY T1.id HAVING COUNT_BIG(T1.id) > 10
List the name of tracks belongs to genre Rock and whose media type is MPEG audio file.
-- Tables de la base de données (T-SQL) -- TABLE [artists] ( [id] NVARCHAR(MAX), [name] NVARCHAR(MAX) ); TABLE [albums] ( [id] INT, [title] NVARCHAR(MAX), [artist id] INT ); TABLE [employees] ( [id] INT, [last name] NVARCHAR(MAX), [first name] NVARCHAR(MAX), [title] NVARCHAR(MAX), ...
SELECT T2.name FROM genres AS T1 JOIN tracks AS T2 ON T1.id = T2.genre_id JOIN media_types AS T3 ON T3.id = T2.media_type_id WHERE T1.name = [Rock] AND T3.name = [MPEG audio file]
What are the names of all Rock tracks that are stored on MPEG audio files?
-- Tables de la base de données (T-SQL) -- TABLE [artists] ( [id] NVARCHAR(MAX), [name] NVARCHAR(MAX) ); TABLE [albums] ( [id] INT, [title] NVARCHAR(MAX), [artist id] INT ); TABLE [employees] ( [id] INT, [last name] NVARCHAR(MAX), [first name] NVARCHAR(MAX), [title] NVARCHAR(MAX), ...
SELECT T2.name FROM genres AS T1 JOIN tracks AS T2 ON T1.id = T2.genre_id JOIN media_types AS T3 ON T3.id = T2.media_type_id WHERE T1.name = [Rock] AND T3.name = [MPEG audio file]
List the name of tracks belongs to genre Rock or media type is MPEG audio file.
-- Tables de la base de données (T-SQL) -- TABLE [artists] ( [id] NVARCHAR(MAX), [name] NVARCHAR(MAX) ); TABLE [albums] ( [id] INT, [title] NVARCHAR(MAX), [artist id] INT ); TABLE [employees] ( [id] INT, [last name] NVARCHAR(MAX), [first name] NVARCHAR(MAX), [title] NVARCHAR(MAX), ...
SELECT T2.name FROM genres AS T1 JOIN tracks AS T2 ON T1.id = T2.genre_id JOIN media_types AS T3 ON T3.id = T2.media_type_id WHERE T1.name = [Rock] OR T3.name = [MPEG audio file]
What are the names of all tracks that belong to the Rock genre and whose media type is MPEG?
-- Tables de la base de données (T-SQL) -- TABLE [artists] ( [id] NVARCHAR(MAX), [name] NVARCHAR(MAX) ); TABLE [albums] ( [id] INT, [title] NVARCHAR(MAX), [artist id] INT ); TABLE [employees] ( [id] INT, [last name] NVARCHAR(MAX), [first name] NVARCHAR(MAX), [title] NVARCHAR(MAX), ...
SELECT T2.name FROM genres AS T1 JOIN tracks AS T2 ON T1.id = T2.genre_id JOIN media_types AS T3 ON T3.id = T2.media_type_id WHERE T1.name = [Rock] OR T3.name = [MPEG audio file]
List the name of tracks belongs to genre Rock or genre Jazz.
-- Tables de la base de données (T-SQL) -- TABLE [artists] ( [id] NVARCHAR(MAX), [name] NVARCHAR(MAX) ); TABLE [albums] ( [id] INT, [title] NVARCHAR(MAX), [artist id] INT ); TABLE [employees] ( [id] INT, [last name] NVARCHAR(MAX), [first name] NVARCHAR(MAX), [title] NVARCHAR(MAX), ...
SELECT T2.name FROM genres AS T1 JOIN tracks AS T2 ON T1.id = T2.genre_id WHERE T1.name = [Rock] OR T1.name = [Jazz]
What are the names of the tracks that are Rock or Jazz songs?
-- Tables de la base de données (T-SQL) -- TABLE [artists] ( [id] NVARCHAR(MAX), [name] NVARCHAR(MAX) ); TABLE [albums] ( [id] INT, [title] NVARCHAR(MAX), [artist id] INT ); TABLE [employees] ( [id] INT, [last name] NVARCHAR(MAX), [first name] NVARCHAR(MAX), [title] NVARCHAR(MAX), ...
SELECT T2.name FROM genres AS T1 JOIN tracks AS T2 ON T1.id = T2.genre_id WHERE T1.name = [Rock] OR T1.name = [Jazz]
List the name of all tracks in the playlists of Movies.
-- Tables de la base de données (T-SQL) -- TABLE [artists] ( [id] NVARCHAR(MAX), [name] NVARCHAR(MAX) ); TABLE [albums] ( [id] INT, [title] NVARCHAR(MAX), [artist id] INT ); TABLE [employees] ( [id] INT, [last name] NVARCHAR(MAX), [first name] NVARCHAR(MAX), [title] NVARCHAR(MAX), ...
SELECT T1.name FROM tracks AS T1 JOIN playlist_tracks AS T2 ON T1.id = T2.track_id JOIN playlists AS T3 ON T3.id = T2.playlist_id WHERE T3.name = [Movies]
What are the names of all tracks that are on playlists titled Movies?
-- Tables de la base de données (T-SQL) -- TABLE [artists] ( [id] NVARCHAR(MAX), [name] NVARCHAR(MAX) ); TABLE [albums] ( [id] INT, [title] NVARCHAR(MAX), [artist id] INT ); TABLE [employees] ( [id] INT, [last name] NVARCHAR(MAX), [first name] NVARCHAR(MAX), [title] NVARCHAR(MAX), ...
SELECT T1.name FROM tracks AS T1 JOIN playlist_tracks AS T2 ON T1.id = T2.track_id JOIN playlists AS T3 ON T3.id = T2.playlist_id WHERE T3.name = [Movies]
List the name of playlist which has number of tracks greater than 100.
-- Tables de la base de données (T-SQL) -- TABLE [artists] ( [id] NVARCHAR(MAX), [name] NVARCHAR(MAX) ); TABLE [albums] ( [id] INT, [title] NVARCHAR(MAX), [artist id] INT ); TABLE [employees] ( [id] INT, [last name] NVARCHAR(MAX), [first name] NVARCHAR(MAX), [title] NVARCHAR(MAX), ...
SELECT T2.name FROM playlist_tracks AS T1 JOIN playlists AS T2 ON T2.id = T1.playlist_id GROUP BY T1.playlist_id HAVING COUNT_BIG(T1.track_id) > 100
What are the names of all playlists that have more than 100 tracks?
-- Tables de la base de données (T-SQL) -- TABLE [artists] ( [id] NVARCHAR(MAX), [name] NVARCHAR(MAX) ); TABLE [albums] ( [id] INT, [title] NVARCHAR(MAX), [artist id] INT ); TABLE [employees] ( [id] INT, [last name] NVARCHAR(MAX), [first name] NVARCHAR(MAX), [title] NVARCHAR(MAX), ...
SELECT T2.name FROM playlist_tracks AS T1 JOIN playlists AS T2 ON T2.id = T1.playlist_id GROUP BY T1.playlist_id HAVING COUNT_BIG(T1.track_id) > 100
List all tracks bought by customer Daan Peeters.
-- Tables de la base de données (T-SQL) -- TABLE [artists] ( [id] NVARCHAR(MAX), [name] NVARCHAR(MAX) ); TABLE [albums] ( [id] INT, [title] NVARCHAR(MAX), [artist id] INT ); TABLE [employees] ( [id] INT, [last name] NVARCHAR(MAX), [first name] NVARCHAR(MAX), [title] NVARCHAR(MAX), ...
SELECT T1.name FROM tracks AS T1 JOIN invoice_lines AS T2 ON T1.id = T2.track_id JOIN invoices AS T3 ON T3.id = T2.invoice_id JOIN customers AS T4 ON T4.id = T3.customer_id WHERE T4.first_name = [Daan] AND T4.last_name = [Peeters]
What are the tracks that Dean Peeters bought?
-- Tables de la base de données (T-SQL) -- TABLE [artists] ( [id] NVARCHAR(MAX), [name] NVARCHAR(MAX) ); TABLE [albums] ( [id] INT, [title] NVARCHAR(MAX), [artist id] INT ); TABLE [employees] ( [id] INT, [last name] NVARCHAR(MAX), [first name] NVARCHAR(MAX), [title] NVARCHAR(MAX), ...
SELECT T1.name FROM tracks AS T1 JOIN invoice_lines AS T2 ON T1.id = T2.track_id JOIN invoices AS T3 ON T3.id = T2.invoice_id JOIN customers AS T4 ON T4.id = T3.customer_id WHERE T4.first_name = [Daan] AND T4.last_name = [Peeters]
How much is the track Fast As a Shark?
-- Tables de la base de données (T-SQL) -- TABLE [artists] ( [id] NVARCHAR(MAX), [name] NVARCHAR(MAX) ); TABLE [albums] ( [id] INT, [title] NVARCHAR(MAX), [artist id] INT ); TABLE [employees] ( [id] INT, [last name] NVARCHAR(MAX), [first name] NVARCHAR(MAX), [title] NVARCHAR(MAX), ...
SELECT unit_price FROM tracks WHERE name = [Fast As a Shark]
What is the unit price of the tune "Fast As a Shark"?
-- Tables de la base de données (T-SQL) -- TABLE [artists] ( [id] NVARCHAR(MAX), [name] NVARCHAR(MAX) ); TABLE [albums] ( [id] INT, [title] NVARCHAR(MAX), [artist id] INT ); TABLE [employees] ( [id] INT, [last name] NVARCHAR(MAX), [first name] NVARCHAR(MAX), [title] NVARCHAR(MAX), ...
SELECT unit_price FROM tracks WHERE name = [Fast As a Shark]
Find the name of tracks which are in Movies playlist but not in music playlist.
-- Tables de la base de données (T-SQL) -- TABLE [artists] ( [id] NVARCHAR(MAX), [name] NVARCHAR(MAX) ); TABLE [albums] ( [id] INT, [title] NVARCHAR(MAX), [artist id] INT ); TABLE [employees] ( [id] INT, [last name] NVARCHAR(MAX), [first name] NVARCHAR(MAX), [title] NVARCHAR(MAX), ...
SELECT T1.name FROM tracks AS T1 JOIN playlist_tracks AS T2 ON T1.id = T2.track_id JOIN playlists AS T3 ON T2.playlist_id = T3.id WHERE T3.name = 'Movies' EXCEPT SELECT T1.name FROM tracks AS T1 JOIN playlist_tracks AS T2 ON T1.id = T2.track_id JOIN playlists AS T3 ON T2.playlist_id = T3.id WHERE T3.name = 'Music'
What are the names of all tracks that are on the Movies playlist but not in the music playlist?
-- Tables de la base de données (T-SQL) -- TABLE [artists] ( [id] NVARCHAR(MAX), [name] NVARCHAR(MAX) ); TABLE [albums] ( [id] INT, [title] NVARCHAR(MAX), [artist id] INT ); TABLE [employees] ( [id] INT, [last name] NVARCHAR(MAX), [first name] NVARCHAR(MAX), [title] NVARCHAR(MAX), ...
SELECT T1.name FROM tracks AS T1 JOIN playlist_tracks AS T2 ON T1.id = T2.track_id JOIN playlists AS T3 ON T2.playlist_id = T3.id WHERE T3.name = 'Movies' EXCEPT SELECT T1.name FROM tracks AS T1 JOIN playlist_tracks AS T2 ON T1.id = T2.track_id JOIN playlists AS T3 ON T2.playlist_id = T3.id WHERE T3.name = 'Music'
Find the name of tracks which are in both Movies and music playlists.
-- Tables de la base de données (T-SQL) -- TABLE [artists] ( [id] NVARCHAR(MAX), [name] NVARCHAR(MAX) ); TABLE [albums] ( [id] INT, [title] NVARCHAR(MAX), [artist id] INT ); TABLE [employees] ( [id] INT, [last name] NVARCHAR(MAX), [first name] NVARCHAR(MAX), [title] NVARCHAR(MAX), ...
SELECT T1.name FROM tracks AS T1 JOIN playlist_tracks AS T2 ON T1.id = T2.track_id JOIN playlists AS T3 ON T2.playlist_id = T3.id WHERE T3.name = 'Movies' INTERSECT SELECT T1.name FROM tracks AS T1 JOIN playlist_tracks AS T2 ON T1.id = T2.track_id JOIN playlists AS T3 ON T2.playlist_id = T3.id WHERE T3.name = 'Music'
What are the names of all the tracks that are in both the Movies and music playlists?
-- Tables de la base de données (T-SQL) -- TABLE [artists] ( [id] NVARCHAR(MAX), [name] NVARCHAR(MAX) ); TABLE [albums] ( [id] INT, [title] NVARCHAR(MAX), [artist id] INT ); TABLE [employees] ( [id] INT, [last name] NVARCHAR(MAX), [first name] NVARCHAR(MAX), [title] NVARCHAR(MAX), ...
SELECT T1.name FROM tracks AS T1 JOIN playlist_tracks AS T2 ON T1.id = T2.track_id JOIN playlists AS T3 ON T2.playlist_id = T3.id WHERE T3.name = 'Movies' INTERSECT SELECT T1.name FROM tracks AS T1 JOIN playlist_tracks AS T2 ON T1.id = T2.track_id JOIN playlists AS T3 ON T2.playlist_id = T3.id WHERE T3.name = 'Music'
Find number of tracks in each genre?
-- Tables de la base de données (T-SQL) -- TABLE [artists] ( [id] NVARCHAR(MAX), [name] NVARCHAR(MAX) ); TABLE [albums] ( [id] INT, [title] NVARCHAR(MAX), [artist id] INT ); TABLE [employees] ( [id] INT, [last name] NVARCHAR(MAX), [first name] NVARCHAR(MAX), [title] NVARCHAR(MAX), ...
SELECT COUNT_BIG(*), T1.name FROM genres AS T1 JOIN tracks AS T2 ON T1.id = T2.genre_id GROUP BY T1.name
How many tracks are in each genre?
-- Tables de la base de données (T-SQL) -- TABLE [artists] ( [id] NVARCHAR(MAX), [name] NVARCHAR(MAX) ); TABLE [albums] ( [id] INT, [title] NVARCHAR(MAX), [artist id] INT ); TABLE [employees] ( [id] INT, [last name] NVARCHAR(MAX), [first name] NVARCHAR(MAX), [title] NVARCHAR(MAX), ...
SELECT COUNT_BIG(*), T1.name FROM genres AS T1 JOIN tracks AS T2 ON T1.id = T2.genre_id GROUP BY T1.name
How many editors are there?
-- Tables de la base de données (T-SQL) -- TABLE [journal] ( [journal id] INT, [date] NVARCHAR(MAX), [theme] NVARCHAR(MAX), [sales] INT ); TABLE [editor] ( [editor id] INT, [name] NVARCHAR(MAX), [age] INT ); Question : How many editors are there?
SELECT COUNT_BIG(*) FROM editor
List the names of editors in ascending order of age.
-- Tables de la base de données (T-SQL) -- TABLE [journal] ( [journal id] INT, [date] NVARCHAR(MAX), [theme] NVARCHAR(MAX), [sales] INT ); TABLE [editor] ( [editor id] INT, [name] NVARCHAR(MAX), [age] INT ); Question : List the names of editors in ascending order of age.
SELECT Name FROM editor ORDER BY CASE WHEN Age IS NULL THEN 1 ELSE 0 END, Age ASC
What are the names and ages of editors?
-- Tables de la base de données (T-SQL) -- TABLE [journal] ( [journal id] INT, [date] NVARCHAR(MAX), [theme] NVARCHAR(MAX), [sales] INT ); TABLE [editor] ( [editor id] INT, [name] NVARCHAR(MAX), [age] INT ); Question : What are the names and ages of editors?
SELECT Name, Age FROM editor
List the names of editors who are older than 25.
-- Tables de la base de données (T-SQL) -- TABLE [journal] ( [journal id] INT, [date] NVARCHAR(MAX), [theme] NVARCHAR(MAX), [sales] INT ); TABLE [editor] ( [editor id] INT, [name] NVARCHAR(MAX), [age] INT ); Question : List the names of editors who are older than 25.
SELECT Name FROM editor WHERE Age > 25
Show the names of editors of age either 24 or 25.
-- Tables de la base de données (T-SQL) -- TABLE [journal] ( [journal id] INT, [date] NVARCHAR(MAX), [theme] NVARCHAR(MAX), [sales] INT ); TABLE [editor] ( [editor id] INT, [name] NVARCHAR(MAX), [age] INT ); Question : Show the names of editors of age either 24 or 25.
SELECT Name FROM editor WHERE Age = 24 OR Age = 25
What is the name of the youngest editor?
-- Tables de la base de données (T-SQL) -- TABLE [journal] ( [journal id] INT, [date] NVARCHAR(MAX), [theme] NVARCHAR(MAX), [sales] INT ); TABLE [editor] ( [editor id] INT, [name] NVARCHAR(MAX), [age] INT ); Question : What is the name of the youngest editor?
SELECT TOP 1 Name FROM editor ORDER BY CASE WHEN Age IS NULL THEN 1 ELSE 0 END, Age ASC
What are the different ages of editors? Show each age along with the number of editors of that age.
-- Tables de la base de données (T-SQL) -- TABLE [journal] ( [journal id] INT, [date] NVARCHAR(MAX), [theme] NVARCHAR(MAX), [sales] INT ); TABLE [editor] ( [editor id] INT, [name] NVARCHAR(MAX), [age] INT ); Question : What are the different ages of editors? Show each age along with the nu...
SELECT Age, COUNT_BIG(*) FROM editor GROUP BY Age
Please show the most common age of editors.
-- Tables de la base de données (T-SQL) -- TABLE [journal] ( [journal id] INT, [date] NVARCHAR(MAX), [theme] NVARCHAR(MAX), [sales] INT ); TABLE [editor] ( [editor id] INT, [name] NVARCHAR(MAX), [age] INT ); Question : Please show the most common age of editors.
SELECT TOP 1 Age FROM editor GROUP BY Age ORDER BY CASE WHEN COUNT_BIG(*) IS NULL THEN 1 ELSE 0 END DESC, COUNT_BIG(*) DESC
Show the distinct themes of journals.
-- Tables de la base de données (T-SQL) -- TABLE [journal] ( [journal id] INT, [date] NVARCHAR(MAX), [theme] NVARCHAR(MAX), [sales] INT ); TABLE [editor] ( [editor id] INT, [name] NVARCHAR(MAX), [age] INT ); Question : Show the distinct themes of journals.
SELECT DISTINCT Theme FROM journal
Show the names of editors and the theme of journals for which they serve on committees.
-- Tables de la base de données (T-SQL) -- TABLE [journal] ( [journal id] INT, [date] NVARCHAR(MAX), [theme] NVARCHAR(MAX), [sales] INT ); TABLE [editor] ( [editor id] INT, [name] NVARCHAR(MAX), [age] INT ); Question : Show the names of editors and the theme of journals for which they serv...
SELECT T2.Name, T3.Theme FROM journal_committee AS T1 JOIN editor AS T2 ON T1.Editor_ID = T2.Editor_ID JOIN journal AS T3 ON T1.Journal_ID = T3.Journal_ID
For each journal_committee, find the editor name and the journal theme.
-- Tables de la base de données (T-SQL) -- TABLE [journal] ( [journal id] INT, [date] NVARCHAR(MAX), [theme] NVARCHAR(MAX), [sales] INT ); TABLE [editor] ( [editor id] INT, [name] NVARCHAR(MAX), [age] INT ); Question : For each journal_committee, find the editor name and the journal theme.
SELECT T2.Name, T3.Theme FROM journal_committee AS T1 JOIN editor AS T2 ON T1.Editor_ID = T2.Editor_ID JOIN journal AS T3 ON T1.Journal_ID = T3.Journal_ID
Show the names and ages of editors and the theme of journals for which they serve on committees, in ascending alphabetical order of theme.
-- Tables de la base de données (T-SQL) -- TABLE [journal] ( [journal id] INT, [date] NVARCHAR(MAX), [theme] NVARCHAR(MAX), [sales] INT ); TABLE [editor] ( [editor id] INT, [name] NVARCHAR(MAX), [age] INT ); Question : Show the names and ages of editors and the theme of journals for which ...
SELECT T2.Name, T2.age, T3.Theme FROM journal_committee AS T1 JOIN editor AS T2 ON T1.Editor_ID = T2.Editor_ID JOIN journal AS T3 ON T1.Journal_ID = T3.Journal_ID ORDER BY CASE WHEN T3.Theme IS NULL THEN 1 ELSE 0 END, T3.Theme ASC
Show the names of editors that are on the committee of journals with sales bigger than 3000.
-- Tables de la base de données (T-SQL) -- TABLE [journal] ( [journal id] INT, [date] NVARCHAR(MAX), [theme] NVARCHAR(MAX), [sales] INT ); TABLE [editor] ( [editor id] INT, [name] NVARCHAR(MAX), [age] INT ); Question : Show the names of editors that are on the committee of journals with sa...
SELECT T2.Name FROM journal_committee AS T1 JOIN editor AS T2 ON T1.Editor_ID = T2.Editor_ID JOIN journal AS T3 ON T1.Journal_ID = T3.Journal_ID WHERE T3.Sales > 3000
Show the id, name of each editor and the number of journal committees they are on.
-- Tables de la base de données (T-SQL) -- TABLE [journal] ( [journal id] INT, [date] NVARCHAR(MAX), [theme] NVARCHAR(MAX), [sales] INT ); TABLE [editor] ( [editor id] INT, [name] NVARCHAR(MAX), [age] INT ); Question : Show the id, name of each editor and the number of journal committees t...
SELECT T1.editor_id, T1.Name, COUNT_BIG(*) FROM editor AS T1 JOIN journal_committee AS T2 ON T1.Editor_ID = T2.Editor_ID GROUP BY T1.editor_id
Show the names of editors that are on at least two journal committees.
-- Tables de la base de données (T-SQL) -- TABLE [journal] ( [journal id] INT, [date] NVARCHAR(MAX), [theme] NVARCHAR(MAX), [sales] INT ); TABLE [editor] ( [editor id] INT, [name] NVARCHAR(MAX), [age] INT ); Question : Show the names of editors that are on at least two journal committees.
SELECT T1.Name FROM editor AS T1 JOIN journal_committee AS T2 ON T1.Editor_ID = T2.Editor_ID GROUP BY T1.Name HAVING COUNT_BIG(*) >= 2
List the names of editors that are not on any journal committee.
-- Tables de la base de données (T-SQL) -- TABLE [journal] ( [journal id] INT, [date] NVARCHAR(MAX), [theme] NVARCHAR(MAX), [sales] INT ); TABLE [editor] ( [editor id] INT, [name] NVARCHAR(MAX), [age] INT ); Question : List the names of editors that are not on any journal committee.
SELECT Name FROM editor WHERE NOT editor_id IN (SELECT editor_id FROM journal_committee)
List the date, theme and sales of the journal which did not have any of the listed editors serving on committee.
-- Tables de la base de données (T-SQL) -- TABLE [journal] ( [journal id] INT, [date] NVARCHAR(MAX), [theme] NVARCHAR(MAX), [sales] INT ); TABLE [editor] ( [editor id] INT, [name] NVARCHAR(MAX), [age] INT ); Question : List the date, theme and sales of the journal which did not have any of...
SELECT date, theme, sales FROM journal EXCEPT SELECT T1.date, T1.theme, T1.sales FROM journal AS T1 JOIN journal_committee AS T2 ON T1.journal_ID = T2.journal_ID
What is the average sales of the journals that have an editor whose work type is 'Photo'?
-- Tables de la base de données (T-SQL) -- TABLE [journal] ( [journal id] INT, [date] NVARCHAR(MAX), [theme] NVARCHAR(MAX), [sales] INT ); TABLE [editor] ( [editor id] INT, [name] NVARCHAR(MAX), [age] INT ); Question : What is the average sales of the journals that have an editor whose wor...
SELECT AVG(T1.sales) FROM journal AS T1 JOIN journal_committee AS T2 ON T1.journal_ID = T2.journal_ID WHERE T2.work_type = 'Photo'
How many accounts do we have?
-- Tables de la base de données (T-SQL) -- TABLE [accounts] ( [account id] INT, [customer id] INT, [account name] NVARCHAR(MAX), [other account details] NVARCHAR(MAX) ); TABLE [customers] ( [customer id] INT, [customer first name] NVARCHAR(MAX), [customer last name] NVARCHAR(MAX), [cust...
SELECT COUNT_BIG(*) FROM Accounts
Count the number of accounts.
-- Tables de la base de données (T-SQL) -- TABLE [accounts] ( [account id] INT, [customer id] INT, [account name] NVARCHAR(MAX), [other account details] NVARCHAR(MAX) ); TABLE [customers] ( [customer id] INT, [customer first name] NVARCHAR(MAX), [customer last name] NVARCHAR(MAX), [cust...
SELECT COUNT_BIG(*) FROM Accounts
Show ids, customer ids, names for all accounts.
-- Tables de la base de données (T-SQL) -- TABLE [accounts] ( [account id] INT, [customer id] INT, [account name] NVARCHAR(MAX), [other account details] NVARCHAR(MAX) ); TABLE [customers] ( [customer id] INT, [customer first name] NVARCHAR(MAX), [customer last name] NVARCHAR(MAX), [cust...
SELECT account_id, customer_id, account_name FROM Accounts
What are the account ids, customer ids, and account names for all the accounts?
-- Tables de la base de données (T-SQL) -- TABLE [accounts] ( [account id] INT, [customer id] INT, [account name] NVARCHAR(MAX), [other account details] NVARCHAR(MAX) ); TABLE [customers] ( [customer id] INT, [customer first name] NVARCHAR(MAX), [customer last name] NVARCHAR(MAX), [cust...
SELECT account_id, customer_id, account_name FROM Accounts
Show other account details for account with name 338.
-- Tables de la base de données (T-SQL) -- TABLE [accounts] ( [account id] INT, [customer id] INT, [account name] NVARCHAR(MAX), [other account details] NVARCHAR(MAX) ); TABLE [customers] ( [customer id] INT, [customer first name] NVARCHAR(MAX), [customer last name] NVARCHAR(MAX), [cust...
SELECT other_account_details FROM Accounts WHERE account_name = [338]
What are the other account details for the account with the name 338?
-- Tables de la base de données (T-SQL) -- TABLE [accounts] ( [account id] INT, [customer id] INT, [account name] NVARCHAR(MAX), [other account details] NVARCHAR(MAX) ); TABLE [customers] ( [customer id] INT, [customer first name] NVARCHAR(MAX), [customer last name] NVARCHAR(MAX), [cust...
SELECT other_account_details FROM Accounts WHERE account_name = [338]
What is the first name, last name, and phone of the customer with account name 162?
-- Tables de la base de données (T-SQL) -- TABLE [accounts] ( [account id] INT, [customer id] INT, [account name] NVARCHAR(MAX), [other account details] NVARCHAR(MAX) ); TABLE [customers] ( [customer id] INT, [customer first name] NVARCHAR(MAX), [customer last name] NVARCHAR(MAX), [cust...
SELECT T2.customer_first_name, T2.customer_last_name, T2.customer_phone FROM Accounts AS T1 JOIN Customers AS T2 ON T1.customer_id = T2.customer_id WHERE T1.account_name = [162]
Give the full name and phone of the customer who has the account name 162.
-- Tables de la base de données (T-SQL) -- TABLE [accounts] ( [account id] INT, [customer id] INT, [account name] NVARCHAR(MAX), [other account details] NVARCHAR(MAX) ); TABLE [customers] ( [customer id] INT, [customer first name] NVARCHAR(MAX), [customer last name] NVARCHAR(MAX), [cust...
SELECT T2.customer_first_name, T2.customer_last_name, T2.customer_phone FROM Accounts AS T1 JOIN Customers AS T2 ON T1.customer_id = T2.customer_id WHERE T1.account_name = [162]
How many accounts does the customer with first name Art and last name Turcotte have?
-- Tables de la base de données (T-SQL) -- TABLE [accounts] ( [account id] INT, [customer id] INT, [account name] NVARCHAR(MAX), [other account details] NVARCHAR(MAX) ); TABLE [customers] ( [customer id] INT, [customer first name] NVARCHAR(MAX), [customer last name] NVARCHAR(MAX), [cust...
SELECT COUNT_BIG(*) FROM Accounts AS T1 JOIN Customers AS T2 ON T1.customer_id = T2.customer_id WHERE T2.customer_first_name = [Art] AND T2.customer_last_name = [Turcotte]
Return the number of accounts that the customer with the first name Art and last name Turcotte has.
-- Tables de la base de données (T-SQL) -- TABLE [accounts] ( [account id] INT, [customer id] INT, [account name] NVARCHAR(MAX), [other account details] NVARCHAR(MAX) ); TABLE [customers] ( [customer id] INT, [customer first name] NVARCHAR(MAX), [customer last name] NVARCHAR(MAX), [cust...
SELECT COUNT_BIG(*) FROM Accounts AS T1 JOIN Customers AS T2 ON T1.customer_id = T2.customer_id WHERE T2.customer_first_name = [Art] AND T2.customer_last_name = [Turcotte]
Show all customer ids and the number of accounts for each customer.
-- Tables de la base de données (T-SQL) -- TABLE [accounts] ( [account id] INT, [customer id] INT, [account name] NVARCHAR(MAX), [other account details] NVARCHAR(MAX) ); TABLE [customers] ( [customer id] INT, [customer first name] NVARCHAR(MAX), [customer last name] NVARCHAR(MAX), [cust...
SELECT customer_id, COUNT_BIG(*) FROM Accounts GROUP BY customer_id
How many accounts are there for each customer id?
-- Tables de la base de données (T-SQL) -- TABLE [accounts] ( [account id] INT, [customer id] INT, [account name] NVARCHAR(MAX), [other account details] NVARCHAR(MAX) ); TABLE [customers] ( [customer id] INT, [customer first name] NVARCHAR(MAX), [customer last name] NVARCHAR(MAX), [cust...
SELECT customer_id, COUNT_BIG(*) FROM Accounts GROUP BY customer_id
Show the customer id and number of accounts with most accounts.
-- Tables de la base de données (T-SQL) -- TABLE [accounts] ( [account id] INT, [customer id] INT, [account name] NVARCHAR(MAX), [other account details] NVARCHAR(MAX) ); TABLE [customers] ( [customer id] INT, [customer first name] NVARCHAR(MAX), [customer last name] NVARCHAR(MAX), [cust...
SELECT TOP 1 customer_id, COUNT_BIG(*) FROM Accounts GROUP BY customer_id ORDER BY CASE WHEN COUNT_BIG(*) IS NULL THEN 1 ELSE 0 END DESC, COUNT_BIG(*) DESC
What is the customer id of the customer with the most accounts, and how many accounts does this person have?
-- Tables de la base de données (T-SQL) -- TABLE [accounts] ( [account id] INT, [customer id] INT, [account name] NVARCHAR(MAX), [other account details] NVARCHAR(MAX) ); TABLE [customers] ( [customer id] INT, [customer first name] NVARCHAR(MAX), [customer last name] NVARCHAR(MAX), [cust...
SELECT TOP 1 customer_id, COUNT_BIG(*) FROM Accounts GROUP BY customer_id ORDER BY CASE WHEN COUNT_BIG(*) IS NULL THEN 1 ELSE 0 END DESC, COUNT_BIG(*) DESC
What is the customer first, last name and id with least number of accounts.
-- Tables de la base de données (T-SQL) -- TABLE [accounts] ( [account id] INT, [customer id] INT, [account name] NVARCHAR(MAX), [other account details] NVARCHAR(MAX) ); TABLE [customers] ( [customer id] INT, [customer first name] NVARCHAR(MAX), [customer last name] NVARCHAR(MAX), [cust...
SELECT TOP 1 T2.customer_first_name, T2.customer_last_name, T1.customer_id FROM Accounts AS T1 JOIN Customers AS T2 ON T1.customer_id = T2.customer_id GROUP BY T1.customer_id ORDER BY CASE WHEN COUNT_BIG(*) IS NULL THEN 1 ELSE 0 END, COUNT_BIG(*) ASC
Give the full name and customer id of the customer with the fewest accounts.
-- Tables de la base de données (T-SQL) -- TABLE [accounts] ( [account id] INT, [customer id] INT, [account name] NVARCHAR(MAX), [other account details] NVARCHAR(MAX) ); TABLE [customers] ( [customer id] INT, [customer first name] NVARCHAR(MAX), [customer last name] NVARCHAR(MAX), [cust...
SELECT TOP 1 T2.customer_first_name, T2.customer_last_name, T1.customer_id FROM Accounts AS T1 JOIN Customers AS T2 ON T1.customer_id = T2.customer_id GROUP BY T1.customer_id ORDER BY CASE WHEN COUNT_BIG(*) IS NULL THEN 1 ELSE 0 END, COUNT_BIG(*) ASC
Show the number of all customers without an account.
-- Tables de la base de données (T-SQL) -- TABLE [accounts] ( [account id] INT, [customer id] INT, [account name] NVARCHAR(MAX), [other account details] NVARCHAR(MAX) ); TABLE [customers] ( [customer id] INT, [customer first name] NVARCHAR(MAX), [customer last name] NVARCHAR(MAX), [cust...
SELECT COUNT_BIG(*) FROM Customers WHERE NOT customer_id IN (SELECT customer_id FROM Accounts)
How many customers do not have an account?
-- Tables de la base de données (T-SQL) -- TABLE [accounts] ( [account id] INT, [customer id] INT, [account name] NVARCHAR(MAX), [other account details] NVARCHAR(MAX) ); TABLE [customers] ( [customer id] INT, [customer first name] NVARCHAR(MAX), [customer last name] NVARCHAR(MAX), [cust...
SELECT COUNT_BIG(*) FROM Customers WHERE NOT customer_id IN (SELECT customer_id FROM Accounts)
Show the first names and last names of customers without any account.
-- Tables de la base de données (T-SQL) -- TABLE [accounts] ( [account id] INT, [customer id] INT, [account name] NVARCHAR(MAX), [other account details] NVARCHAR(MAX) ); TABLE [customers] ( [customer id] INT, [customer first name] NVARCHAR(MAX), [customer last name] NVARCHAR(MAX), [cust...
SELECT customer_first_name, customer_last_name FROM Customers EXCEPT SELECT T1.customer_first_name, T1.customer_last_name FROM Customers AS T1 JOIN Accounts AS T2 ON T1.customer_id = T2.customer_id
What are the full names of customers who do not have any accounts?
-- Tables de la base de données (T-SQL) -- TABLE [accounts] ( [account id] INT, [customer id] INT, [account name] NVARCHAR(MAX), [other account details] NVARCHAR(MAX) ); TABLE [customers] ( [customer id] INT, [customer first name] NVARCHAR(MAX), [customer last name] NVARCHAR(MAX), [cust...
SELECT customer_first_name, customer_last_name FROM Customers EXCEPT SELECT T1.customer_first_name, T1.customer_last_name FROM Customers AS T1 JOIN Accounts AS T2 ON T1.customer_id = T2.customer_id
Show distinct first and last names for all customers with an account.
-- Tables de la base de données (T-SQL) -- TABLE [accounts] ( [account id] INT, [customer id] INT, [account name] NVARCHAR(MAX), [other account details] NVARCHAR(MAX) ); TABLE [customers] ( [customer id] INT, [customer first name] NVARCHAR(MAX), [customer last name] NVARCHAR(MAX), [cust...
SELECT DISTINCT T1.customer_first_name, T1.customer_last_name FROM Customers AS T1 JOIN Accounts AS T2 ON T1.customer_id = T2.customer_id
What are the full names of customers who have accounts?
-- Tables de la base de données (T-SQL) -- TABLE [accounts] ( [account id] INT, [customer id] INT, [account name] NVARCHAR(MAX), [other account details] NVARCHAR(MAX) ); TABLE [customers] ( [customer id] INT, [customer first name] NVARCHAR(MAX), [customer last name] NVARCHAR(MAX), [cust...
SELECT DISTINCT T1.customer_first_name, T1.customer_last_name FROM Customers AS T1 JOIN Accounts AS T2 ON T1.customer_id = T2.customer_id
How many customers have an account?
-- Tables de la base de données (T-SQL) -- TABLE [accounts] ( [account id] INT, [customer id] INT, [account name] NVARCHAR(MAX), [other account details] NVARCHAR(MAX) ); TABLE [customers] ( [customer id] INT, [customer first name] NVARCHAR(MAX), [customer last name] NVARCHAR(MAX), [cust...
SELECT COUNT_BIG(DISTINCT customer_id) FROM Accounts
Count the number of customers who hold an account.
-- Tables de la base de données (T-SQL) -- TABLE [accounts] ( [account id] INT, [customer id] INT, [account name] NVARCHAR(MAX), [other account details] NVARCHAR(MAX) ); TABLE [customers] ( [customer id] INT, [customer first name] NVARCHAR(MAX), [customer last name] NVARCHAR(MAX), [cust...
SELECT COUNT_BIG(DISTINCT customer_id) FROM Accounts
How many customers do we have?
-- Tables de la base de données (T-SQL) -- TABLE [accounts] ( [account id] INT, [customer id] INT, [account name] NVARCHAR(MAX), [other account details] NVARCHAR(MAX) ); TABLE [customers] ( [customer id] INT, [customer first name] NVARCHAR(MAX), [customer last name] NVARCHAR(MAX), [cust...
SELECT COUNT_BIG(*) FROM Customers
Count the number of customers.
-- Tables de la base de données (T-SQL) -- TABLE [accounts] ( [account id] INT, [customer id] INT, [account name] NVARCHAR(MAX), [other account details] NVARCHAR(MAX) ); TABLE [customers] ( [customer id] INT, [customer first name] NVARCHAR(MAX), [customer last name] NVARCHAR(MAX), [cust...
SELECT COUNT_BIG(*) FROM Customers
Show ids, first names, last names, and phones for all customers.
-- Tables de la base de données (T-SQL) -- TABLE [accounts] ( [account id] INT, [customer id] INT, [account name] NVARCHAR(MAX), [other account details] NVARCHAR(MAX) ); TABLE [customers] ( [customer id] INT, [customer first name] NVARCHAR(MAX), [customer last name] NVARCHAR(MAX), [cust...
SELECT customer_id, customer_first_name, customer_last_name, customer_phone FROM Customers
What are the ids, full names, and phones of each customer?
-- Tables de la base de données (T-SQL) -- TABLE [accounts] ( [account id] INT, [customer id] INT, [account name] NVARCHAR(MAX), [other account details] NVARCHAR(MAX) ); TABLE [customers] ( [customer id] INT, [customer first name] NVARCHAR(MAX), [customer last name] NVARCHAR(MAX), [cust...
SELECT customer_id, customer_first_name, customer_last_name, customer_phone FROM Customers
What is the phone and email for customer with first name Aniyah and last name Feest?
-- Tables de la base de données (T-SQL) -- TABLE [accounts] ( [account id] INT, [customer id] INT, [account name] NVARCHAR(MAX), [other account details] NVARCHAR(MAX) ); TABLE [customers] ( [customer id] INT, [customer first name] NVARCHAR(MAX), [customer last name] NVARCHAR(MAX), [cust...
SELECT customer_phone, customer_email FROM Customers WHERE customer_first_name = [Aniyah] AND customer_last_name = [Feest]
Return the phone and email of the customer with the first name Aniyah and last name Feest.
-- Tables de la base de données (T-SQL) -- TABLE [accounts] ( [account id] INT, [customer id] INT, [account name] NVARCHAR(MAX), [other account details] NVARCHAR(MAX) ); TABLE [customers] ( [customer id] INT, [customer first name] NVARCHAR(MAX), [customer last name] NVARCHAR(MAX), [cust...
SELECT customer_phone, customer_email FROM Customers WHERE customer_first_name = [Aniyah] AND customer_last_name = [Feest]
Show the number of customer cards.
-- Tables de la base de données (T-SQL) -- TABLE [accounts] ( [account id] INT, [customer id] INT, [account name] NVARCHAR(MAX), [other account details] NVARCHAR(MAX) ); TABLE [customers] ( [customer id] INT, [customer first name] NVARCHAR(MAX), [customer last name] NVARCHAR(MAX), [cust...
SELECT COUNT_BIG(*) FROM Customers_cards
How many customer cards are there?
-- Tables de la base de données (T-SQL) -- TABLE [accounts] ( [account id] INT, [customer id] INT, [account name] NVARCHAR(MAX), [other account details] NVARCHAR(MAX) ); TABLE [customers] ( [customer id] INT, [customer first name] NVARCHAR(MAX), [customer last name] NVARCHAR(MAX), [cust...
SELECT COUNT_BIG(*) FROM Customers_cards
Show ids, customer ids, card type codes, card numbers for all cards.
-- Tables de la base de données (T-SQL) -- TABLE [accounts] ( [account id] INT, [customer id] INT, [account name] NVARCHAR(MAX), [other account details] NVARCHAR(MAX) ); TABLE [customers] ( [customer id] INT, [customer first name] NVARCHAR(MAX), [customer last name] NVARCHAR(MAX), [cust...
SELECT card_id, customer_id, card_type_code, card_number FROM Customers_cards