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Find the policy types more than 4 customers use. Show their type code.
-- Tables de la base de données (T-SQL) -- TABLE [customers] ( [customer id] INT, [customer name] NVARCHAR(MAX) ); TABLE [services] ( [service id] INT, [service name] NVARCHAR(MAX) ); TABLE [claims] ( [claim id] INT, [fnol id] INT, [effective date] NVARCHAR(MAX) ); TABLE [settlements] ( ...
SELECT policy_type_code FROM available_policies GROUP BY policy_type_code HAVING COUNT_BIG(*) > 4
Find the total and average amount of settlements.
-- Tables de la base de données (T-SQL) -- TABLE [customers] ( [customer id] INT, [customer name] NVARCHAR(MAX) ); TABLE [services] ( [service id] INT, [service name] NVARCHAR(MAX) ); TABLE [claims] ( [claim id] INT, [fnol id] INT, [effective date] NVARCHAR(MAX) ); TABLE [settlements] ( ...
SELECT SUM(settlement_amount), AVG(settlement_amount) FROM settlements
Return the sum and average of all settlement amounts.
-- Tables de la base de données (T-SQL) -- TABLE [customers] ( [customer id] INT, [customer name] NVARCHAR(MAX) ); TABLE [services] ( [service id] INT, [service name] NVARCHAR(MAX) ); TABLE [claims] ( [claim id] INT, [fnol id] INT, [effective date] NVARCHAR(MAX) ); TABLE [settlements] ( ...
SELECT SUM(settlement_amount), AVG(settlement_amount) FROM settlements
Find the name of services that have been used for more than 2 times in first notification of loss.
-- Tables de la base de données (T-SQL) -- TABLE [customers] ( [customer id] INT, [customer name] NVARCHAR(MAX) ); TABLE [services] ( [service id] INT, [service name] NVARCHAR(MAX) ); TABLE [claims] ( [claim id] INT, [fnol id] INT, [effective date] NVARCHAR(MAX) ); TABLE [settlements] ( ...
SELECT t2.service_name FROM first_notification_of_loss AS t1 JOIN services AS t2 ON t1.service_id = t2.service_id GROUP BY t1.service_id HAVING COUNT_BIG(*) > 2
Which services have been used more than twice in first notification of loss? Return the service name.
-- Tables de la base de données (T-SQL) -- TABLE [customers] ( [customer id] INT, [customer name] NVARCHAR(MAX) ); TABLE [services] ( [service id] INT, [service name] NVARCHAR(MAX) ); TABLE [claims] ( [claim id] INT, [fnol id] INT, [effective date] NVARCHAR(MAX) ); TABLE [settlements] ( ...
SELECT t2.service_name FROM first_notification_of_loss AS t1 JOIN services AS t2 ON t1.service_id = t2.service_id GROUP BY t1.service_id HAVING COUNT_BIG(*) > 2
What is the effective date of the claim that has the largest amount of total settlement?
-- Tables de la base de données (T-SQL) -- TABLE [customers] ( [customer id] INT, [customer name] NVARCHAR(MAX) ); TABLE [services] ( [service id] INT, [service name] NVARCHAR(MAX) ); TABLE [claims] ( [claim id] INT, [fnol id] INT, [effective date] NVARCHAR(MAX) ); TABLE [settlements] ( ...
SELECT TOP 1 t1.Effective_Date FROM claims AS t1 JOIN settlements AS t2 ON t1.claim_id = t2.claim_id GROUP BY t1.claim_id ORDER BY CASE WHEN SUM(t2.settlement_amount) IS NULL THEN 1 ELSE 0 END DESC, SUM(t2.settlement_amount) DESC
Find the claim that has the largest total settlement amount. Return the effective date of the claim.
-- Tables de la base de données (T-SQL) -- TABLE [customers] ( [customer id] INT, [customer name] NVARCHAR(MAX) ); TABLE [services] ( [service id] INT, [service name] NVARCHAR(MAX) ); TABLE [claims] ( [claim id] INT, [fnol id] INT, [effective date] NVARCHAR(MAX) ); TABLE [settlements] ( ...
SELECT TOP 1 t1.Effective_Date FROM claims AS t1 JOIN settlements AS t2 ON t1.claim_id = t2.claim_id GROUP BY t1.claim_id ORDER BY CASE WHEN SUM(t2.settlement_amount) IS NULL THEN 1 ELSE 0 END DESC, SUM(t2.settlement_amount) DESC
How many policies are listed for the customer named "Dayana Robel"?
-- Tables de la base de données (T-SQL) -- TABLE [customers] ( [customer id] INT, [customer name] NVARCHAR(MAX) ); TABLE [services] ( [service id] INT, [service name] NVARCHAR(MAX) ); TABLE [claims] ( [claim id] INT, [fnol id] INT, [effective date] NVARCHAR(MAX) ); TABLE [settlements] ( ...
SELECT COUNT_BIG(*) FROM customers AS t1 JOIN customers_policies AS t2 ON t1.customer_id = t2.customer_id WHERE t1.customer_name = [Dayana Robel]
Count the total number of policies used by the customer named "Dayana Robel".
-- Tables de la base de données (T-SQL) -- TABLE [customers] ( [customer id] INT, [customer name] NVARCHAR(MAX) ); TABLE [services] ( [service id] INT, [service name] NVARCHAR(MAX) ); TABLE [claims] ( [claim id] INT, [fnol id] INT, [effective date] NVARCHAR(MAX) ); TABLE [settlements] ( ...
SELECT COUNT_BIG(*) FROM customers AS t1 JOIN customers_policies AS t2 ON t1.customer_id = t2.customer_id WHERE t1.customer_name = [Dayana Robel]
What is the name of the customer who has the most policies listed?
-- Tables de la base de données (T-SQL) -- TABLE [customers] ( [customer id] INT, [customer name] NVARCHAR(MAX) ); TABLE [services] ( [service id] INT, [service name] NVARCHAR(MAX) ); TABLE [claims] ( [claim id] INT, [fnol id] INT, [effective date] NVARCHAR(MAX) ); TABLE [settlements] ( ...
SELECT TOP 1 t1.customer_name FROM customers AS t1 JOIN customers_policies AS t2 ON t1.customer_id = t2.customer_id GROUP BY t1.customer_name ORDER BY CASE WHEN COUNT_BIG(*) IS NULL THEN 1 ELSE 0 END DESC, COUNT_BIG(*) DESC
Which customer uses the most policies? Give me the customer name.
-- Tables de la base de données (T-SQL) -- TABLE [customers] ( [customer id] INT, [customer name] NVARCHAR(MAX) ); TABLE [services] ( [service id] INT, [service name] NVARCHAR(MAX) ); TABLE [claims] ( [claim id] INT, [fnol id] INT, [effective date] NVARCHAR(MAX) ); TABLE [settlements] ( ...
SELECT TOP 1 t1.customer_name FROM customers AS t1 JOIN customers_policies AS t2 ON t1.customer_id = t2.customer_id GROUP BY t1.customer_name ORDER BY CASE WHEN COUNT_BIG(*) IS NULL THEN 1 ELSE 0 END DESC, COUNT_BIG(*) DESC
What are all the policy types of the customer named "Dayana Robel"?
-- Tables de la base de données (T-SQL) -- TABLE [customers] ( [customer id] INT, [customer name] NVARCHAR(MAX) ); TABLE [services] ( [service id] INT, [service name] NVARCHAR(MAX) ); TABLE [claims] ( [claim id] INT, [fnol id] INT, [effective date] NVARCHAR(MAX) ); TABLE [settlements] ( ...
SELECT DISTINCT t3.policy_type_code FROM customers AS t1 JOIN customers_policies AS t2 ON t1.customer_id = t2.customer_id JOIN available_policies AS t3 ON t2.policy_id = t3.policy_id WHERE t1.customer_name = [Dayana Robel]
Tell me the types of the policy used by the customer named "Dayana Robel".
-- Tables de la base de données (T-SQL) -- TABLE [customers] ( [customer id] INT, [customer name] NVARCHAR(MAX) ); TABLE [services] ( [service id] INT, [service name] NVARCHAR(MAX) ); TABLE [claims] ( [claim id] INT, [fnol id] INT, [effective date] NVARCHAR(MAX) ); TABLE [settlements] ( ...
SELECT DISTINCT t3.policy_type_code FROM customers AS t1 JOIN customers_policies AS t2 ON t1.customer_id = t2.customer_id JOIN available_policies AS t3 ON t2.policy_id = t3.policy_id WHERE t1.customer_name = [Dayana Robel]
What are all the policy types of the customer that has the most policies listed?
-- Tables de la base de données (T-SQL) -- TABLE [customers] ( [customer id] INT, [customer name] NVARCHAR(MAX) ); TABLE [services] ( [service id] INT, [service name] NVARCHAR(MAX) ); TABLE [claims] ( [claim id] INT, [fnol id] INT, [effective date] NVARCHAR(MAX) ); TABLE [settlements] ( ...
SELECT DISTINCT t3.policy_type_code FROM customers AS t1 JOIN customers_policies AS t2 ON t1.customer_id = t2.customer_id JOIN available_policies AS t3 ON t2.policy_id = t3.policy_id WHERE t1.customer_name = (SELECT TOP 1 t1.customer_name FROM customers AS t1 JOIN customers_policies AS t2 ON t1.customer_id = t2.custome...
List all the policy types used by the customer enrolled in the most policies.
-- Tables de la base de données (T-SQL) -- TABLE [customers] ( [customer id] INT, [customer name] NVARCHAR(MAX) ); TABLE [services] ( [service id] INT, [service name] NVARCHAR(MAX) ); TABLE [claims] ( [claim id] INT, [fnol id] INT, [effective date] NVARCHAR(MAX) ); TABLE [settlements] ( ...
SELECT DISTINCT t3.policy_type_code FROM customers AS t1 JOIN customers_policies AS t2 ON t1.customer_id = t2.customer_id JOIN available_policies AS t3 ON t2.policy_id = t3.policy_id WHERE t1.customer_name = (SELECT TOP 1 t1.customer_name FROM customers AS t1 JOIN customers_policies AS t2 ON t1.customer_id = t2.custome...
List all the services in the alphabetical order.
-- Tables de la base de données (T-SQL) -- TABLE [customers] ( [customer id] INT, [customer name] NVARCHAR(MAX) ); TABLE [services] ( [service id] INT, [service name] NVARCHAR(MAX) ); TABLE [claims] ( [claim id] INT, [fnol id] INT, [effective date] NVARCHAR(MAX) ); TABLE [settlements] ( ...
SELECT service_name FROM services ORDER BY CASE WHEN service_name IS NULL THEN 1 ELSE 0 END, service_name
Give me a list of all the service names sorted alphabetically.
-- Tables de la base de données (T-SQL) -- TABLE [customers] ( [customer id] INT, [customer name] NVARCHAR(MAX) ); TABLE [services] ( [service id] INT, [service name] NVARCHAR(MAX) ); TABLE [claims] ( [claim id] INT, [fnol id] INT, [effective date] NVARCHAR(MAX) ); TABLE [settlements] ( ...
SELECT service_name FROM services ORDER BY CASE WHEN service_name IS NULL THEN 1 ELSE 0 END, service_name
How many services are there?
-- Tables de la base de données (T-SQL) -- TABLE [customers] ( [customer id] INT, [customer name] NVARCHAR(MAX) ); TABLE [services] ( [service id] INT, [service name] NVARCHAR(MAX) ); TABLE [claims] ( [claim id] INT, [fnol id] INT, [effective date] NVARCHAR(MAX) ); TABLE [settlements] ( ...
SELECT COUNT_BIG(*) FROM services
Count the total number of available services.
-- Tables de la base de données (T-SQL) -- TABLE [customers] ( [customer id] INT, [customer name] NVARCHAR(MAX) ); TABLE [services] ( [service id] INT, [service name] NVARCHAR(MAX) ); TABLE [claims] ( [claim id] INT, [fnol id] INT, [effective date] NVARCHAR(MAX) ); TABLE [settlements] ( ...
SELECT COUNT_BIG(*) FROM services
Find the names of users who do not have a first notification of loss record.
-- Tables de la base de données (T-SQL) -- TABLE [customers] ( [customer id] INT, [customer name] NVARCHAR(MAX) ); TABLE [services] ( [service id] INT, [service name] NVARCHAR(MAX) ); TABLE [claims] ( [claim id] INT, [fnol id] INT, [effective date] NVARCHAR(MAX) ); TABLE [settlements] ( ...
SELECT customer_name FROM customers EXCEPT SELECT t1.customer_name FROM customers AS t1 JOIN first_notification_of_loss AS t2 ON t1.customer_id = t2.customer_id
Which customers do not have a first notification of loss record? Give me the customer names.
-- Tables de la base de données (T-SQL) -- TABLE [customers] ( [customer id] INT, [customer name] NVARCHAR(MAX) ); TABLE [services] ( [service id] INT, [service name] NVARCHAR(MAX) ); TABLE [claims] ( [claim id] INT, [fnol id] INT, [effective date] NVARCHAR(MAX) ); TABLE [settlements] ( ...
SELECT customer_name FROM customers EXCEPT SELECT t1.customer_name FROM customers AS t1 JOIN first_notification_of_loss AS t2 ON t1.customer_id = t2.customer_id
Find the names of customers who have used either the service "Close a policy" or the service "Upgrade a policy".
-- Tables de la base de données (T-SQL) -- TABLE [customers] ( [customer id] INT, [customer name] NVARCHAR(MAX) ); TABLE [services] ( [service id] INT, [service name] NVARCHAR(MAX) ); TABLE [claims] ( [claim id] INT, [fnol id] INT, [effective date] NVARCHAR(MAX) ); TABLE [settlements] ( ...
SELECT t1.customer_name FROM customers AS t1 JOIN first_notification_of_loss AS t2 ON t1.customer_id = t2.customer_id JOIN services AS t3 ON t2.service_id = t3.service_id WHERE t3.service_name = [Close a policy] OR t3.service_name = [Upgrade a policy]
Which customers have used the service named "Close a policy" or "Upgrade a policy"? Give me the customer names.
-- Tables de la base de données (T-SQL) -- TABLE [customers] ( [customer id] INT, [customer name] NVARCHAR(MAX) ); TABLE [services] ( [service id] INT, [service name] NVARCHAR(MAX) ); TABLE [claims] ( [claim id] INT, [fnol id] INT, [effective date] NVARCHAR(MAX) ); TABLE [settlements] ( ...
SELECT t1.customer_name FROM customers AS t1 JOIN first_notification_of_loss AS t2 ON t1.customer_id = t2.customer_id JOIN services AS t3 ON t2.service_id = t3.service_id WHERE t3.service_name = [Close a policy] OR t3.service_name = [Upgrade a policy]
Find the names of customers who have used both the service "Close a policy" and the service "New policy application".
-- Tables de la base de données (T-SQL) -- TABLE [customers] ( [customer id] INT, [customer name] NVARCHAR(MAX) ); TABLE [services] ( [service id] INT, [service name] NVARCHAR(MAX) ); TABLE [claims] ( [claim id] INT, [fnol id] INT, [effective date] NVARCHAR(MAX) ); TABLE [settlements] ( ...
SELECT t1.customer_name FROM customers AS t1 JOIN first_notification_of_loss AS t2 ON t1.customer_id = t2.customer_id JOIN services AS t3 ON t2.service_id = t3.service_id WHERE t3.service_name = [Close a policy] INTERSECT SELECT t1.customer_name FROM customers AS t1 JOIN first_notification_of_loss AS t2 ON t1.customer_...
Which customers have used both the service named "Close a policy" and the service named "Upgrade a policy"? Give me the customer names.
-- Tables de la base de données (T-SQL) -- TABLE [customers] ( [customer id] INT, [customer name] NVARCHAR(MAX) ); TABLE [services] ( [service id] INT, [service name] NVARCHAR(MAX) ); TABLE [claims] ( [claim id] INT, [fnol id] INT, [effective date] NVARCHAR(MAX) ); TABLE [settlements] ( ...
SELECT t1.customer_name FROM customers AS t1 JOIN first_notification_of_loss AS t2 ON t1.customer_id = t2.customer_id JOIN services AS t3 ON t2.service_id = t3.service_id WHERE t3.service_name = [Close a policy] INTERSECT SELECT t1.customer_name FROM customers AS t1 JOIN first_notification_of_loss AS t2 ON t1.customer_...
Find the IDs of customers whose name contains "Diana".
-- Tables de la base de données (T-SQL) -- TABLE [customers] ( [customer id] INT, [customer name] NVARCHAR(MAX) ); TABLE [services] ( [service id] INT, [service name] NVARCHAR(MAX) ); TABLE [claims] ( [claim id] INT, [fnol id] INT, [effective date] NVARCHAR(MAX) ); TABLE [settlements] ( ...
SELECT customer_id FROM customers WHERE customer_name LIKE [%Diana%]
What are the IDs of customers who have "Diana" in part of their names?
-- Tables de la base de données (T-SQL) -- TABLE [customers] ( [customer id] INT, [customer name] NVARCHAR(MAX) ); TABLE [services] ( [service id] INT, [service name] NVARCHAR(MAX) ); TABLE [claims] ( [claim id] INT, [fnol id] INT, [effective date] NVARCHAR(MAX) ); TABLE [settlements] ( ...
SELECT customer_id FROM customers WHERE customer_name LIKE [%Diana%]
What are the maximum and minimum settlement amount on record?
-- Tables de la base de données (T-SQL) -- TABLE [customers] ( [customer id] INT, [customer name] NVARCHAR(MAX) ); TABLE [services] ( [service id] INT, [service name] NVARCHAR(MAX) ); TABLE [claims] ( [claim id] INT, [fnol id] INT, [effective date] NVARCHAR(MAX) ); TABLE [settlements] ( ...
SELECT MAX(settlement_amount), MIN(settlement_amount) FROM settlements
Find the maximum and minimum settlement amount.
-- Tables de la base de données (T-SQL) -- TABLE [customers] ( [customer id] INT, [customer name] NVARCHAR(MAX) ); TABLE [services] ( [service id] INT, [service name] NVARCHAR(MAX) ); TABLE [claims] ( [claim id] INT, [fnol id] INT, [effective date] NVARCHAR(MAX) ); TABLE [settlements] ( ...
SELECT MAX(settlement_amount), MIN(settlement_amount) FROM settlements
List all the customers in increasing order of IDs.
-- Tables de la base de données (T-SQL) -- TABLE [customers] ( [customer id] INT, [customer name] NVARCHAR(MAX) ); TABLE [services] ( [service id] INT, [service name] NVARCHAR(MAX) ); TABLE [claims] ( [claim id] INT, [fnol id] INT, [effective date] NVARCHAR(MAX) ); TABLE [settlements] ( ...
SELECT customer_id, customer_name FROM customers ORDER BY CASE WHEN customer_id IS NULL THEN 1 ELSE 0 END, customer_id ASC
What is the ordered list of customer ids?
-- Tables de la base de données (T-SQL) -- TABLE [customers] ( [customer id] INT, [customer name] NVARCHAR(MAX) ); TABLE [services] ( [service id] INT, [service name] NVARCHAR(MAX) ); TABLE [claims] ( [claim id] INT, [fnol id] INT, [effective date] NVARCHAR(MAX) ); TABLE [settlements] ( ...
SELECT customer_id, customer_name FROM customers ORDER BY CASE WHEN customer_id IS NULL THEN 1 ELSE 0 END, customer_id ASC
Retrieve the open and close dates of all the policies associated with the customer whose name contains "Diana"
-- Tables de la base de données (T-SQL) -- TABLE [customers] ( [customer id] INT, [customer name] NVARCHAR(MAX) ); TABLE [services] ( [service id] INT, [service name] NVARCHAR(MAX) ); TABLE [claims] ( [claim id] INT, [fnol id] INT, [effective date] NVARCHAR(MAX) ); TABLE [settlements] ( ...
SELECT t2.date_opened, t2.date_closed FROM customers AS t1 JOIN customers_policies AS t2 ON t1.customer_id = t2.customer_id WHERE t1.customer_name LIKE [%Diana%]
What are the open and close dates of all the policies used by the customer who have "Diana" in part of their names?
-- Tables de la base de données (T-SQL) -- TABLE [customers] ( [customer id] INT, [customer name] NVARCHAR(MAX) ); TABLE [services] ( [service id] INT, [service name] NVARCHAR(MAX) ); TABLE [claims] ( [claim id] INT, [fnol id] INT, [effective date] NVARCHAR(MAX) ); TABLE [settlements] ( ...
SELECT t2.date_opened, t2.date_closed FROM customers AS t1 JOIN customers_policies AS t2 ON t1.customer_id = t2.customer_id WHERE t1.customer_name LIKE [%Diana%]
How many kinds of enzymes are there?
-- Tables de la base de données (T-SQL) -- TABLE [medicine] ( [id] INT, [name] NVARCHAR(MAX), [trade name] NVARCHAR(MAX), [fda approved] NVARCHAR(MAX) ); TABLE [enzyme] ( [id] INT, [name] NVARCHAR(MAX), [location] NVARCHAR(MAX), [product] NVARCHAR(MAX), [chromosome] NVARCHAR(MAX), ...
SELECT COUNT_BIG(*) FROM enzyme
What is the total count of enzymes?
-- Tables de la base de données (T-SQL) -- TABLE [medicine] ( [id] INT, [name] NVARCHAR(MAX), [trade name] NVARCHAR(MAX), [fda approved] NVARCHAR(MAX) ); TABLE [enzyme] ( [id] INT, [name] NVARCHAR(MAX), [location] NVARCHAR(MAX), [product] NVARCHAR(MAX), [chromosome] NVARCHAR(MAX), ...
SELECT COUNT_BIG(*) FROM enzyme
List the name of enzymes in descending lexicographical order.
-- Tables de la base de données (T-SQL) -- TABLE [medicine] ( [id] INT, [name] NVARCHAR(MAX), [trade name] NVARCHAR(MAX), [fda approved] NVARCHAR(MAX) ); TABLE [enzyme] ( [id] INT, [name] NVARCHAR(MAX), [location] NVARCHAR(MAX), [product] NVARCHAR(MAX), [chromosome] NVARCHAR(MAX), ...
SELECT name FROM enzyme ORDER BY CASE WHEN name IS NULL THEN 1 ELSE 0 END DESC, name DESC
What are the names of enzymes in descending order?
-- Tables de la base de données (T-SQL) -- TABLE [medicine] ( [id] INT, [name] NVARCHAR(MAX), [trade name] NVARCHAR(MAX), [fda approved] NVARCHAR(MAX) ); TABLE [enzyme] ( [id] INT, [name] NVARCHAR(MAX), [location] NVARCHAR(MAX), [product] NVARCHAR(MAX), [chromosome] NVARCHAR(MAX), ...
SELECT name FROM enzyme ORDER BY CASE WHEN name IS NULL THEN 1 ELSE 0 END DESC, name DESC
List the names and the locations that the enzymes can make an effect.
-- Tables de la base de données (T-SQL) -- TABLE [medicine] ( [id] INT, [name] NVARCHAR(MAX), [trade name] NVARCHAR(MAX), [fda approved] NVARCHAR(MAX) ); TABLE [enzyme] ( [id] INT, [name] NVARCHAR(MAX), [location] NVARCHAR(MAX), [product] NVARCHAR(MAX), [chromosome] NVARCHAR(MAX), ...
SELECT name, LOCATION FROM enzyme
What are the names and locations of all enzymes listed?
-- Tables de la base de données (T-SQL) -- TABLE [medicine] ( [id] INT, [name] NVARCHAR(MAX), [trade name] NVARCHAR(MAX), [fda approved] NVARCHAR(MAX) ); TABLE [enzyme] ( [id] INT, [name] NVARCHAR(MAX), [location] NVARCHAR(MAX), [product] NVARCHAR(MAX), [chromosome] NVARCHAR(MAX), ...
SELECT name, LOCATION FROM enzyme
What is the maximum Online Mendelian Inheritance in Man (OMIM) value of the enzymes?
-- Tables de la base de données (T-SQL) -- TABLE [medicine] ( [id] INT, [name] NVARCHAR(MAX), [trade name] NVARCHAR(MAX), [fda approved] NVARCHAR(MAX) ); TABLE [enzyme] ( [id] INT, [name] NVARCHAR(MAX), [location] NVARCHAR(MAX), [product] NVARCHAR(MAX), [chromosome] NVARCHAR(MAX), ...
SELECT MAX(OMIM) FROM enzyme
What is the maximum OMIM value in the database?
-- Tables de la base de données (T-SQL) -- TABLE [medicine] ( [id] INT, [name] NVARCHAR(MAX), [trade name] NVARCHAR(MAX), [fda approved] NVARCHAR(MAX) ); TABLE [enzyme] ( [id] INT, [name] NVARCHAR(MAX), [location] NVARCHAR(MAX), [product] NVARCHAR(MAX), [chromosome] NVARCHAR(MAX), ...
SELECT MAX(OMIM) FROM enzyme
What is the product, chromosome and porphyria related to the enzymes which take effect at the location 'Cytosol'?
-- Tables de la base de données (T-SQL) -- TABLE [medicine] ( [id] INT, [name] NVARCHAR(MAX), [trade name] NVARCHAR(MAX), [fda approved] NVARCHAR(MAX) ); TABLE [enzyme] ( [id] INT, [name] NVARCHAR(MAX), [location] NVARCHAR(MAX), [product] NVARCHAR(MAX), [chromosome] NVARCHAR(MAX), ...
SELECT product, chromosome, porphyria FROM enzyme WHERE LOCATION = 'Cytosol'
What is the product, chromosome, and porphyria of the enzymes located at 'Cytosol'?
-- Tables de la base de données (T-SQL) -- TABLE [medicine] ( [id] INT, [name] NVARCHAR(MAX), [trade name] NVARCHAR(MAX), [fda approved] NVARCHAR(MAX) ); TABLE [enzyme] ( [id] INT, [name] NVARCHAR(MAX), [location] NVARCHAR(MAX), [product] NVARCHAR(MAX), [chromosome] NVARCHAR(MAX), ...
SELECT product, chromosome, porphyria FROM enzyme WHERE LOCATION = 'Cytosol'
What are the names of enzymes who does not produce 'Heme'?
-- Tables de la base de données (T-SQL) -- TABLE [medicine] ( [id] INT, [name] NVARCHAR(MAX), [trade name] NVARCHAR(MAX), [fda approved] NVARCHAR(MAX) ); TABLE [enzyme] ( [id] INT, [name] NVARCHAR(MAX), [location] NVARCHAR(MAX), [product] NVARCHAR(MAX), [chromosome] NVARCHAR(MAX), ...
SELECT name FROM enzyme WHERE product <> 'Heme'
What are the names of enzymes whose product is not 'Heme'?
-- Tables de la base de données (T-SQL) -- TABLE [medicine] ( [id] INT, [name] NVARCHAR(MAX), [trade name] NVARCHAR(MAX), [fda approved] NVARCHAR(MAX) ); TABLE [enzyme] ( [id] INT, [name] NVARCHAR(MAX), [location] NVARCHAR(MAX), [product] NVARCHAR(MAX), [chromosome] NVARCHAR(MAX), ...
SELECT name FROM enzyme WHERE product <> 'Heme'
What are the names and trade names of the medicines which has 'Yes' value in the FDA record?
-- Tables de la base de données (T-SQL) -- TABLE [medicine] ( [id] INT, [name] NVARCHAR(MAX), [trade name] NVARCHAR(MAX), [fda approved] NVARCHAR(MAX) ); TABLE [enzyme] ( [id] INT, [name] NVARCHAR(MAX), [location] NVARCHAR(MAX), [product] NVARCHAR(MAX), [chromosome] NVARCHAR(MAX), ...
SELECT name, trade_name FROM medicine WHERE FDA_approved = 'Yes'
What are the names and trade names of the medcines that are FDA approved?
-- Tables de la base de données (T-SQL) -- TABLE [medicine] ( [id] INT, [name] NVARCHAR(MAX), [trade name] NVARCHAR(MAX), [fda approved] NVARCHAR(MAX) ); TABLE [enzyme] ( [id] INT, [name] NVARCHAR(MAX), [location] NVARCHAR(MAX), [product] NVARCHAR(MAX), [chromosome] NVARCHAR(MAX), ...
SELECT name, trade_name FROM medicine WHERE FDA_approved = 'Yes'
What are the names of enzymes in the medicine named 'Amisulpride' that can serve as an 'inhibitor'?
-- Tables de la base de données (T-SQL) -- TABLE [medicine] ( [id] INT, [name] NVARCHAR(MAX), [trade name] NVARCHAR(MAX), [fda approved] NVARCHAR(MAX) ); TABLE [enzyme] ( [id] INT, [name] NVARCHAR(MAX), [location] NVARCHAR(MAX), [product] NVARCHAR(MAX), [chromosome] NVARCHAR(MAX), ...
SELECT T1.name FROM enzyme AS T1 JOIN medicine_enzyme_interaction AS T2 ON T1.id = T2.enzyme_id JOIN medicine AS T3 ON T2.medicine_id = T3.id WHERE T3.name = 'Amisulpride' AND T2.interaction_type = 'inhibitor'
What are the names of the enzymes used in the medicine Amisulpride that acts as inhibitors?
-- Tables de la base de données (T-SQL) -- TABLE [medicine] ( [id] INT, [name] NVARCHAR(MAX), [trade name] NVARCHAR(MAX), [fda approved] NVARCHAR(MAX) ); TABLE [enzyme] ( [id] INT, [name] NVARCHAR(MAX), [location] NVARCHAR(MAX), [product] NVARCHAR(MAX), [chromosome] NVARCHAR(MAX), ...
SELECT T1.name FROM enzyme AS T1 JOIN medicine_enzyme_interaction AS T2 ON T1.id = T2.enzyme_id JOIN medicine AS T3 ON T2.medicine_id = T3.id WHERE T3.name = 'Amisulpride' AND T2.interaction_type = 'inhibitor'
What are the ids and names of the medicine that can interact with two or more enzymes?
-- Tables de la base de données (T-SQL) -- TABLE [medicine] ( [id] INT, [name] NVARCHAR(MAX), [trade name] NVARCHAR(MAX), [fda approved] NVARCHAR(MAX) ); TABLE [enzyme] ( [id] INT, [name] NVARCHAR(MAX), [location] NVARCHAR(MAX), [product] NVARCHAR(MAX), [chromosome] NVARCHAR(MAX), ...
SELECT T1.id, T1.Name FROM medicine AS T1 JOIN medicine_enzyme_interaction AS T2 ON T2.medicine_id = T1.id GROUP BY T1.id HAVING COUNT_BIG(*) >= 2
For every medicine id, what are the names of the medicines that can interact with more than one enzyme?
-- Tables de la base de données (T-SQL) -- TABLE [medicine] ( [id] INT, [name] NVARCHAR(MAX), [trade name] NVARCHAR(MAX), [fda approved] NVARCHAR(MAX) ); TABLE [enzyme] ( [id] INT, [name] NVARCHAR(MAX), [location] NVARCHAR(MAX), [product] NVARCHAR(MAX), [chromosome] NVARCHAR(MAX), ...
SELECT T1.id, T1.Name FROM medicine AS T1 JOIN medicine_enzyme_interaction AS T2 ON T2.medicine_id = T1.id GROUP BY T1.id HAVING COUNT_BIG(*) >= 2
What are the ids, names and FDA approval status of medicines in descending order of the number of enzymes that it can interact with.
-- Tables de la base de données (T-SQL) -- TABLE [medicine] ( [id] INT, [name] NVARCHAR(MAX), [trade name] NVARCHAR(MAX), [fda approved] NVARCHAR(MAX) ); TABLE [enzyme] ( [id] INT, [name] NVARCHAR(MAX), [location] NVARCHAR(MAX), [product] NVARCHAR(MAX), [chromosome] NVARCHAR(MAX), ...
SELECT T1.id, T1.Name, T1.FDA_approved FROM medicine AS T1 JOIN medicine_enzyme_interaction AS T2 ON T2.medicine_id = T1.id GROUP BY T1.id ORDER BY CASE WHEN COUNT_BIG(*) IS NULL THEN 1 ELSE 0 END DESC, COUNT_BIG(*) DESC
What are the ids, names, and FDA approval status for medicines ordered by descending number of possible enzyme interactions?
-- Tables de la base de données (T-SQL) -- TABLE [medicine] ( [id] INT, [name] NVARCHAR(MAX), [trade name] NVARCHAR(MAX), [fda approved] NVARCHAR(MAX) ); TABLE [enzyme] ( [id] INT, [name] NVARCHAR(MAX), [location] NVARCHAR(MAX), [product] NVARCHAR(MAX), [chromosome] NVARCHAR(MAX), ...
SELECT T1.id, T1.Name, T1.FDA_approved FROM medicine AS T1 JOIN medicine_enzyme_interaction AS T2 ON T2.medicine_id = T1.id GROUP BY T1.id ORDER BY CASE WHEN COUNT_BIG(*) IS NULL THEN 1 ELSE 0 END DESC, COUNT_BIG(*) DESC
What is the id and name of the enzyme with most number of medicines that can interact as 'activator'?
-- Tables de la base de données (T-SQL) -- TABLE [medicine] ( [id] INT, [name] NVARCHAR(MAX), [trade name] NVARCHAR(MAX), [fda approved] NVARCHAR(MAX) ); TABLE [enzyme] ( [id] INT, [name] NVARCHAR(MAX), [location] NVARCHAR(MAX), [product] NVARCHAR(MAX), [chromosome] NVARCHAR(MAX), ...
SELECT TOP 1 T1.id, T1.name FROM enzyme AS T1 JOIN medicine_enzyme_interaction AS T2 ON T1.id = T2.enzyme_id WHERE T2.interaction_type = 'activitor' GROUP BY T1.id ORDER BY CASE WHEN COUNT_BIG(*) IS NULL THEN 1 ELSE 0 END DESC, COUNT_BIG(*) DESC
What is the id and name of the enzyme that can interact with the most medicines as an activator?
-- Tables de la base de données (T-SQL) -- TABLE [medicine] ( [id] INT, [name] NVARCHAR(MAX), [trade name] NVARCHAR(MAX), [fda approved] NVARCHAR(MAX) ); TABLE [enzyme] ( [id] INT, [name] NVARCHAR(MAX), [location] NVARCHAR(MAX), [product] NVARCHAR(MAX), [chromosome] NVARCHAR(MAX), ...
SELECT TOP 1 T1.id, T1.name FROM enzyme AS T1 JOIN medicine_enzyme_interaction AS T2 ON T1.id = T2.enzyme_id WHERE T2.interaction_type = 'activitor' GROUP BY T1.id ORDER BY CASE WHEN COUNT_BIG(*) IS NULL THEN 1 ELSE 0 END DESC, COUNT_BIG(*) DESC
What is the interaction type of the enzyme named 'ALA synthase' and the medicine named 'Aripiprazole'?
-- Tables de la base de données (T-SQL) -- TABLE [medicine] ( [id] INT, [name] NVARCHAR(MAX), [trade name] NVARCHAR(MAX), [fda approved] NVARCHAR(MAX) ); TABLE [enzyme] ( [id] INT, [name] NVARCHAR(MAX), [location] NVARCHAR(MAX), [product] NVARCHAR(MAX), [chromosome] NVARCHAR(MAX), ...
SELECT T1.interaction_type FROM medicine_enzyme_interaction AS T1 JOIN medicine AS T2 ON T1.medicine_id = T2.id JOIN enzyme AS T3 ON T1.enzyme_id = T3.id WHERE T3.name = 'ALA synthase' AND T2.name = 'Aripiprazole'
What is the type of interaction for the enzyme named 'ALA synthase' and the medicine named 'Aripiprazole'?
-- Tables de la base de données (T-SQL) -- TABLE [medicine] ( [id] INT, [name] NVARCHAR(MAX), [trade name] NVARCHAR(MAX), [fda approved] NVARCHAR(MAX) ); TABLE [enzyme] ( [id] INT, [name] NVARCHAR(MAX), [location] NVARCHAR(MAX), [product] NVARCHAR(MAX), [chromosome] NVARCHAR(MAX), ...
SELECT T1.interaction_type FROM medicine_enzyme_interaction AS T1 JOIN medicine AS T2 ON T1.medicine_id = T2.id JOIN enzyme AS T3 ON T1.enzyme_id = T3.id WHERE T3.name = 'ALA synthase' AND T2.name = 'Aripiprazole'
What is the most common interaction type between enzymes and medicine? And how many are there?
-- Tables de la base de données (T-SQL) -- TABLE [medicine] ( [id] INT, [name] NVARCHAR(MAX), [trade name] NVARCHAR(MAX), [fda approved] NVARCHAR(MAX) ); TABLE [enzyme] ( [id] INT, [name] NVARCHAR(MAX), [location] NVARCHAR(MAX), [product] NVARCHAR(MAX), [chromosome] NVARCHAR(MAX), ...
SELECT TOP 1 interaction_type, COUNT_BIG(*) FROM medicine_enzyme_interaction GROUP BY interaction_type ORDER BY CASE WHEN COUNT_BIG(*) IS NULL THEN 1 ELSE 0 END DESC, COUNT_BIG(*) DESC
What are the most common types of interactions between enzymes and medicine, and how many types are there?
-- Tables de la base de données (T-SQL) -- TABLE [medicine] ( [id] INT, [name] NVARCHAR(MAX), [trade name] NVARCHAR(MAX), [fda approved] NVARCHAR(MAX) ); TABLE [enzyme] ( [id] INT, [name] NVARCHAR(MAX), [location] NVARCHAR(MAX), [product] NVARCHAR(MAX), [chromosome] NVARCHAR(MAX), ...
SELECT TOP 1 interaction_type, COUNT_BIG(*) FROM medicine_enzyme_interaction GROUP BY interaction_type ORDER BY CASE WHEN COUNT_BIG(*) IS NULL THEN 1 ELSE 0 END DESC, COUNT_BIG(*) DESC
How many medicines have the FDA approval status 'No' ?
-- Tables de la base de données (T-SQL) -- TABLE [medicine] ( [id] INT, [name] NVARCHAR(MAX), [trade name] NVARCHAR(MAX), [fda approved] NVARCHAR(MAX) ); TABLE [enzyme] ( [id] INT, [name] NVARCHAR(MAX), [location] NVARCHAR(MAX), [product] NVARCHAR(MAX), [chromosome] NVARCHAR(MAX), ...
SELECT COUNT_BIG(*) FROM medicine WHERE FDA_approved = 'No'
How many medicines were not approved by the FDA?
-- Tables de la base de données (T-SQL) -- TABLE [medicine] ( [id] INT, [name] NVARCHAR(MAX), [trade name] NVARCHAR(MAX), [fda approved] NVARCHAR(MAX) ); TABLE [enzyme] ( [id] INT, [name] NVARCHAR(MAX), [location] NVARCHAR(MAX), [product] NVARCHAR(MAX), [chromosome] NVARCHAR(MAX), ...
SELECT COUNT_BIG(*) FROM medicine WHERE FDA_approved = 'No'
How many enzymes do not have any interactions?
-- Tables de la base de données (T-SQL) -- TABLE [medicine] ( [id] INT, [name] NVARCHAR(MAX), [trade name] NVARCHAR(MAX), [fda approved] NVARCHAR(MAX) ); TABLE [enzyme] ( [id] INT, [name] NVARCHAR(MAX), [location] NVARCHAR(MAX), [product] NVARCHAR(MAX), [chromosome] NVARCHAR(MAX), ...
SELECT COUNT_BIG(*) FROM enzyme WHERE NOT id IN (SELECT enzyme_id FROM medicine_enzyme_interaction)
What is the count of enzymes without any interactions?
-- Tables de la base de données (T-SQL) -- TABLE [medicine] ( [id] INT, [name] NVARCHAR(MAX), [trade name] NVARCHAR(MAX), [fda approved] NVARCHAR(MAX) ); TABLE [enzyme] ( [id] INT, [name] NVARCHAR(MAX), [location] NVARCHAR(MAX), [product] NVARCHAR(MAX), [chromosome] NVARCHAR(MAX), ...
SELECT COUNT_BIG(*) FROM enzyme WHERE NOT id IN (SELECT enzyme_id FROM medicine_enzyme_interaction)
What is the id and trade name of the medicines can interact with at least 3 enzymes?
-- Tables de la base de données (T-SQL) -- TABLE [medicine] ( [id] INT, [name] NVARCHAR(MAX), [trade name] NVARCHAR(MAX), [fda approved] NVARCHAR(MAX) ); TABLE [enzyme] ( [id] INT, [name] NVARCHAR(MAX), [location] NVARCHAR(MAX), [product] NVARCHAR(MAX), [chromosome] NVARCHAR(MAX), ...
SELECT T1.id, T1.trade_name FROM medicine AS T1 JOIN medicine_enzyme_interaction AS T2 ON T2.medicine_id = T1.id GROUP BY T1.id HAVING COUNT_BIG(*) >= 3
What are the ids and trade names of the medicine that can interact with at least 3 enzymes?
-- Tables de la base de données (T-SQL) -- TABLE [medicine] ( [id] INT, [name] NVARCHAR(MAX), [trade name] NVARCHAR(MAX), [fda approved] NVARCHAR(MAX) ); TABLE [enzyme] ( [id] INT, [name] NVARCHAR(MAX), [location] NVARCHAR(MAX), [product] NVARCHAR(MAX), [chromosome] NVARCHAR(MAX), ...
SELECT T1.id, T1.trade_name FROM medicine AS T1 JOIN medicine_enzyme_interaction AS T2 ON T2.medicine_id = T1.id GROUP BY T1.id HAVING COUNT_BIG(*) >= 3
What are the distinct name, location and products of the enzymes which has any 'inhibitor' interaction?
-- Tables de la base de données (T-SQL) -- TABLE [medicine] ( [id] INT, [name] NVARCHAR(MAX), [trade name] NVARCHAR(MAX), [fda approved] NVARCHAR(MAX) ); TABLE [enzyme] ( [id] INT, [name] NVARCHAR(MAX), [location] NVARCHAR(MAX), [product] NVARCHAR(MAX), [chromosome] NVARCHAR(MAX), ...
SELECT DISTINCT T1.name, T1.location, T1.product FROM enzyme AS T1 JOIN medicine_enzyme_interaction AS T2 ON T2.enzyme_id = T1.id WHERE T2.interaction_type = 'inhibitor'
What are the different names, locations, and products of the enzymes that are capable inhibitor interactions?
-- Tables de la base de données (T-SQL) -- TABLE [medicine] ( [id] INT, [name] NVARCHAR(MAX), [trade name] NVARCHAR(MAX), [fda approved] NVARCHAR(MAX) ); TABLE [enzyme] ( [id] INT, [name] NVARCHAR(MAX), [location] NVARCHAR(MAX), [product] NVARCHAR(MAX), [chromosome] NVARCHAR(MAX), ...
SELECT DISTINCT T1.name, T1.location, T1.product FROM enzyme AS T1 JOIN medicine_enzyme_interaction AS T2 ON T2.enzyme_id = T1.id WHERE T2.interaction_type = 'inhibitor'
List the medicine name and trade name which can both interact as 'inhibitor' and 'activitor' with enzymes.
-- Tables de la base de données (T-SQL) -- TABLE [medicine] ( [id] INT, [name] NVARCHAR(MAX), [trade name] NVARCHAR(MAX), [fda approved] NVARCHAR(MAX) ); TABLE [enzyme] ( [id] INT, [name] NVARCHAR(MAX), [location] NVARCHAR(MAX), [product] NVARCHAR(MAX), [chromosome] NVARCHAR(MAX), ...
SELECT T1.name, T1.trade_name FROM medicine AS T1 JOIN medicine_enzyme_interaction AS T2 ON T2.medicine_id = T1.id WHERE interaction_type = 'inhibitor' INTERSECT SELECT T1.name, T1.trade_name FROM medicine AS T1 JOIN medicine_enzyme_interaction AS T2 ON T2.medicine_id = T1.id WHERE interaction_type = 'activitor'
What are the medicine and trade names that can interact as an inhibitor and activitor with enzymes?
-- Tables de la base de données (T-SQL) -- TABLE [medicine] ( [id] INT, [name] NVARCHAR(MAX), [trade name] NVARCHAR(MAX), [fda approved] NVARCHAR(MAX) ); TABLE [enzyme] ( [id] INT, [name] NVARCHAR(MAX), [location] NVARCHAR(MAX), [product] NVARCHAR(MAX), [chromosome] NVARCHAR(MAX), ...
SELECT T1.name, T1.trade_name FROM medicine AS T1 JOIN medicine_enzyme_interaction AS T2 ON T2.medicine_id = T1.id WHERE interaction_type = 'inhibitor' INTERSECT SELECT T1.name, T1.trade_name FROM medicine AS T1 JOIN medicine_enzyme_interaction AS T2 ON T2.medicine_id = T1.id WHERE interaction_type = 'activitor'
Show the medicine names and trade names that cannot interact with the enzyme with product 'Heme'.
-- Tables de la base de données (T-SQL) -- TABLE [medicine] ( [id] INT, [name] NVARCHAR(MAX), [trade name] NVARCHAR(MAX), [fda approved] NVARCHAR(MAX) ); TABLE [enzyme] ( [id] INT, [name] NVARCHAR(MAX), [location] NVARCHAR(MAX), [product] NVARCHAR(MAX), [chromosome] NVARCHAR(MAX), ...
SELECT name, trade_name FROM medicine EXCEPT SELECT T1.name, T1.trade_name FROM medicine AS T1 JOIN medicine_enzyme_interaction AS T2 ON T2.medicine_id = T1.id JOIN enzyme AS T3 ON T3.id = T2.enzyme_id WHERE T3.product = 'Protoporphyrinogen IX'
What are the medicine and trade names that cannot interact with the enzyme with the product 'Heme'?
-- Tables de la base de données (T-SQL) -- TABLE [medicine] ( [id] INT, [name] NVARCHAR(MAX), [trade name] NVARCHAR(MAX), [fda approved] NVARCHAR(MAX) ); TABLE [enzyme] ( [id] INT, [name] NVARCHAR(MAX), [location] NVARCHAR(MAX), [product] NVARCHAR(MAX), [chromosome] NVARCHAR(MAX), ...
SELECT name, trade_name FROM medicine EXCEPT SELECT T1.name, T1.trade_name FROM medicine AS T1 JOIN medicine_enzyme_interaction AS T2 ON T2.medicine_id = T1.id JOIN enzyme AS T3 ON T3.id = T2.enzyme_id WHERE T3.product = 'Protoporphyrinogen IX'
How many distinct FDA approval statuses are there for the medicines?
-- Tables de la base de données (T-SQL) -- TABLE [medicine] ( [id] INT, [name] NVARCHAR(MAX), [trade name] NVARCHAR(MAX), [fda approved] NVARCHAR(MAX) ); TABLE [enzyme] ( [id] INT, [name] NVARCHAR(MAX), [location] NVARCHAR(MAX), [product] NVARCHAR(MAX), [chromosome] NVARCHAR(MAX), ...
SELECT COUNT_BIG(DISTINCT FDA_approved) FROM medicine
How many different FDA approval statuses exist for medicines?
-- Tables de la base de données (T-SQL) -- TABLE [medicine] ( [id] INT, [name] NVARCHAR(MAX), [trade name] NVARCHAR(MAX), [fda approved] NVARCHAR(MAX) ); TABLE [enzyme] ( [id] INT, [name] NVARCHAR(MAX), [location] NVARCHAR(MAX), [product] NVARCHAR(MAX), [chromosome] NVARCHAR(MAX), ...
SELECT COUNT_BIG(DISTINCT FDA_approved) FROM medicine
Which enzyme names have the substring "ALA"?
-- Tables de la base de données (T-SQL) -- TABLE [medicine] ( [id] INT, [name] NVARCHAR(MAX), [trade name] NVARCHAR(MAX), [fda approved] NVARCHAR(MAX) ); TABLE [enzyme] ( [id] INT, [name] NVARCHAR(MAX), [location] NVARCHAR(MAX), [product] NVARCHAR(MAX), [chromosome] NVARCHAR(MAX), ...
SELECT name FROM enzyme WHERE name LIKE [%ALA%]
What are the names of enzymes that include the string 'ALA'?
-- Tables de la base de données (T-SQL) -- TABLE [medicine] ( [id] INT, [name] NVARCHAR(MAX), [trade name] NVARCHAR(MAX), [fda approved] NVARCHAR(MAX) ); TABLE [enzyme] ( [id] INT, [name] NVARCHAR(MAX), [location] NVARCHAR(MAX), [product] NVARCHAR(MAX), [chromosome] NVARCHAR(MAX), ...
SELECT name FROM enzyme WHERE name LIKE [%ALA%]
find the number of medicines offered by each trade.
-- Tables de la base de données (T-SQL) -- TABLE [medicine] ( [id] INT, [name] NVARCHAR(MAX), [trade name] NVARCHAR(MAX), [fda approved] NVARCHAR(MAX) ); TABLE [enzyme] ( [id] INT, [name] NVARCHAR(MAX), [location] NVARCHAR(MAX), [product] NVARCHAR(MAX), [chromosome] NVARCHAR(MAX), ...
SELECT trade_name, COUNT_BIG(*) FROM medicine GROUP BY trade_name
How many medicines are offered by each trade name?
-- Tables de la base de données (T-SQL) -- TABLE [medicine] ( [id] INT, [name] NVARCHAR(MAX), [trade name] NVARCHAR(MAX), [fda approved] NVARCHAR(MAX) ); TABLE [enzyme] ( [id] INT, [name] NVARCHAR(MAX), [location] NVARCHAR(MAX), [product] NVARCHAR(MAX), [chromosome] NVARCHAR(MAX), ...
SELECT trade_name, COUNT_BIG(*) FROM medicine GROUP BY trade_name
List all schools and their nicknames in the order of founded year.
-- Tables de la base de données (T-SQL) -- TABLE [university] ( [school id] INT, [school] NVARCHAR(MAX), [location] NVARCHAR(MAX), [founded] INT, [affiliation] NVARCHAR(MAX), [enrollment] INT, [nickname] NVARCHAR(MAX), [primary conference] NVARCHAR(MAX) ); Question : List all schools an...
SELECT school, nickname FROM university ORDER BY CASE WHEN founded IS NULL THEN 1 ELSE 0 END, founded
What are the different schools and their nicknames, ordered by their founding years?
-- Tables de la base de données (T-SQL) -- TABLE [university] ( [school id] INT, [school] NVARCHAR(MAX), [location] NVARCHAR(MAX), [founded] INT, [affiliation] NVARCHAR(MAX), [enrollment] INT, [nickname] NVARCHAR(MAX), [primary conference] NVARCHAR(MAX) ); Question : What are the differ...
SELECT school, nickname FROM university ORDER BY CASE WHEN founded IS NULL THEN 1 ELSE 0 END, founded
List all public schools and their locations.
-- Tables de la base de données (T-SQL) -- TABLE [university] ( [school id] INT, [school] NVARCHAR(MAX), [location] NVARCHAR(MAX), [founded] INT, [affiliation] NVARCHAR(MAX), [enrollment] INT, [nickname] NVARCHAR(MAX), [primary conference] NVARCHAR(MAX) ); Question : List all public sch...
SELECT school, LOCATION FROM university WHERE affiliation = 'Public'
What are the public schools and what are their locations?
-- Tables de la base de données (T-SQL) -- TABLE [university] ( [school id] INT, [school] NVARCHAR(MAX), [location] NVARCHAR(MAX), [founded] INT, [affiliation] NVARCHAR(MAX), [enrollment] INT, [nickname] NVARCHAR(MAX), [primary conference] NVARCHAR(MAX) ); Question : What are the public...
SELECT school, LOCATION FROM university WHERE affiliation = 'Public'
When was the school with the largest enrollment founded?
-- Tables de la base de données (T-SQL) -- TABLE [university] ( [school id] INT, [school] NVARCHAR(MAX), [location] NVARCHAR(MAX), [founded] INT, [affiliation] NVARCHAR(MAX), [enrollment] INT, [nickname] NVARCHAR(MAX), [primary conference] NVARCHAR(MAX) ); Question : When was the school...
SELECT TOP 1 founded FROM university ORDER BY CASE WHEN enrollment IS NULL THEN 1 ELSE 0 END DESC, enrollment DESC
Return the founded year for the school with the largest enrollment.
-- Tables de la base de données (T-SQL) -- TABLE [university] ( [school id] INT, [school] NVARCHAR(MAX), [location] NVARCHAR(MAX), [founded] INT, [affiliation] NVARCHAR(MAX), [enrollment] INT, [nickname] NVARCHAR(MAX), [primary conference] NVARCHAR(MAX) ); Question : Return the founded ...
SELECT TOP 1 founded FROM university ORDER BY CASE WHEN enrollment IS NULL THEN 1 ELSE 0 END DESC, enrollment DESC
Find the founded year of the newest non public school.
-- Tables de la base de données (T-SQL) -- TABLE [university] ( [school id] INT, [school] NVARCHAR(MAX), [location] NVARCHAR(MAX), [founded] INT, [affiliation] NVARCHAR(MAX), [enrollment] INT, [nickname] NVARCHAR(MAX), [primary conference] NVARCHAR(MAX) ); Question : Find the founded ye...
SELECT TOP 1 founded FROM university WHERE affiliation <> 'Public' ORDER BY CASE WHEN founded IS NULL THEN 1 ELSE 0 END DESC, founded DESC
What is the founded year of the non public school that was founded most recently?
-- Tables de la base de données (T-SQL) -- TABLE [university] ( [school id] INT, [school] NVARCHAR(MAX), [location] NVARCHAR(MAX), [founded] INT, [affiliation] NVARCHAR(MAX), [enrollment] INT, [nickname] NVARCHAR(MAX), [primary conference] NVARCHAR(MAX) ); Question : What is the founded...
SELECT TOP 1 founded FROM university WHERE affiliation <> 'Public' ORDER BY CASE WHEN founded IS NULL THEN 1 ELSE 0 END DESC, founded DESC
How many schools are in the basketball match?
-- Tables de la base de données (T-SQL) -- TABLE [university] ( [school id] INT, [school] NVARCHAR(MAX), [location] NVARCHAR(MAX), [founded] INT, [affiliation] NVARCHAR(MAX), [enrollment] INT, [nickname] NVARCHAR(MAX), [primary conference] NVARCHAR(MAX) ); Question : How many schools ar...
SELECT COUNT_BIG(DISTINCT school_id) FROM basketball_match
Count the number of schools that have had basketball matches.
-- Tables de la base de données (T-SQL) -- TABLE [university] ( [school id] INT, [school] NVARCHAR(MAX), [location] NVARCHAR(MAX), [founded] INT, [affiliation] NVARCHAR(MAX), [enrollment] INT, [nickname] NVARCHAR(MAX), [primary conference] NVARCHAR(MAX) ); Question : Count the number of...
SELECT COUNT_BIG(DISTINCT school_id) FROM basketball_match
What is the highest acc percent score in the competition?
-- Tables de la base de données (T-SQL) -- TABLE [university] ( [school id] INT, [school] NVARCHAR(MAX), [location] NVARCHAR(MAX), [founded] INT, [affiliation] NVARCHAR(MAX), [enrollment] INT, [nickname] NVARCHAR(MAX), [primary conference] NVARCHAR(MAX) ); Question : What is the highest...
SELECT TOP 1 acc_percent FROM basketball_match ORDER BY CASE WHEN acc_percent IS NULL THEN 1 ELSE 0 END DESC, acc_percent DESC
Return the highest acc percent across all basketball matches.
-- Tables de la base de données (T-SQL) -- TABLE [university] ( [school id] INT, [school] NVARCHAR(MAX), [location] NVARCHAR(MAX), [founded] INT, [affiliation] NVARCHAR(MAX), [enrollment] INT, [nickname] NVARCHAR(MAX), [primary conference] NVARCHAR(MAX) ); Question : Return the highest ...
SELECT TOP 1 acc_percent FROM basketball_match ORDER BY CASE WHEN acc_percent IS NULL THEN 1 ELSE 0 END DESC, acc_percent DESC
What is the primary conference of the school that has the lowest acc percent score in the competition?
-- Tables de la base de données (T-SQL) -- TABLE [university] ( [school id] INT, [school] NVARCHAR(MAX), [location] NVARCHAR(MAX), [founded] INT, [affiliation] NVARCHAR(MAX), [enrollment] INT, [nickname] NVARCHAR(MAX), [primary conference] NVARCHAR(MAX) ); Question : What is the primary...
SELECT TOP 1 t1.Primary_conference FROM university AS t1 JOIN basketball_match AS t2 ON t1.school_id = t2.school_id ORDER BY CASE WHEN t2.acc_percent IS NULL THEN 1 ELSE 0 END, t2.acc_percent
Return the primary conference of the school with the lowest acc percentage score.
-- Tables de la base de données (T-SQL) -- TABLE [university] ( [school id] INT, [school] NVARCHAR(MAX), [location] NVARCHAR(MAX), [founded] INT, [affiliation] NVARCHAR(MAX), [enrollment] INT, [nickname] NVARCHAR(MAX), [primary conference] NVARCHAR(MAX) ); Question : Return the primary ...
SELECT TOP 1 t1.Primary_conference FROM university AS t1 JOIN basketball_match AS t2 ON t1.school_id = t2.school_id ORDER BY CASE WHEN t2.acc_percent IS NULL THEN 1 ELSE 0 END, t2.acc_percent
What is the team name and acc regular season score of the school that was founded for the longest time?
-- Tables de la base de données (T-SQL) -- TABLE [university] ( [school id] INT, [school] NVARCHAR(MAX), [location] NVARCHAR(MAX), [founded] INT, [affiliation] NVARCHAR(MAX), [enrollment] INT, [nickname] NVARCHAR(MAX), [primary conference] NVARCHAR(MAX) ); Question : What is the team na...
SELECT TOP 1 t2.team_name, t2.ACC_Regular_Season FROM university AS t1 JOIN basketball_match AS t2 ON t1.school_id = t2.school_id ORDER BY CASE WHEN t1.founded IS NULL THEN 1 ELSE 0 END, t1.founded
Return the name of the team and the acc during the regular season for the school that was founded the earliest.
-- Tables de la base de données (T-SQL) -- TABLE [university] ( [school id] INT, [school] NVARCHAR(MAX), [location] NVARCHAR(MAX), [founded] INT, [affiliation] NVARCHAR(MAX), [enrollment] INT, [nickname] NVARCHAR(MAX), [primary conference] NVARCHAR(MAX) ); Question : Return the name of ...
SELECT TOP 1 t2.team_name, t2.ACC_Regular_Season FROM university AS t1 JOIN basketball_match AS t2 ON t1.school_id = t2.school_id ORDER BY CASE WHEN t1.founded IS NULL THEN 1 ELSE 0 END, t1.founded
Find the location and all games score of the school that has Clemson as its team name.
-- Tables de la base de données (T-SQL) -- TABLE [university] ( [school id] INT, [school] NVARCHAR(MAX), [location] NVARCHAR(MAX), [founded] INT, [affiliation] NVARCHAR(MAX), [enrollment] INT, [nickname] NVARCHAR(MAX), [primary conference] NVARCHAR(MAX) ); Question : Find the location a...
SELECT t2.All_Games, t1.location FROM university AS t1 JOIN basketball_match AS t2 ON t1.school_id = t2.school_id WHERE team_name = 'Clemson'
What are the all games score and location of the school called Clemson?
-- Tables de la base de données (T-SQL) -- TABLE [university] ( [school id] INT, [school] NVARCHAR(MAX), [location] NVARCHAR(MAX), [founded] INT, [affiliation] NVARCHAR(MAX), [enrollment] INT, [nickname] NVARCHAR(MAX), [primary conference] NVARCHAR(MAX) ); Question : What are the all ga...
SELECT t2.All_Games, t1.location FROM university AS t1 JOIN basketball_match AS t2 ON t1.school_id = t2.school_id WHERE team_name = 'Clemson'
What are the average enrollment size of the universities that are founded before 1850?
-- Tables de la base de données (T-SQL) -- TABLE [university] ( [school id] INT, [school] NVARCHAR(MAX), [location] NVARCHAR(MAX), [founded] INT, [affiliation] NVARCHAR(MAX), [enrollment] INT, [nickname] NVARCHAR(MAX), [primary conference] NVARCHAR(MAX) ); Question : What are the averag...
SELECT AVG(enrollment) FROM university WHERE founded < 1850
Return the average enrollment of universities founded before 1850.
-- Tables de la base de données (T-SQL) -- TABLE [university] ( [school id] INT, [school] NVARCHAR(MAX), [location] NVARCHAR(MAX), [founded] INT, [affiliation] NVARCHAR(MAX), [enrollment] INT, [nickname] NVARCHAR(MAX), [primary conference] NVARCHAR(MAX) ); Question : Return the average ...
SELECT AVG(enrollment) FROM university WHERE founded < 1850
Show the enrollment and primary_conference of the oldest college.
-- Tables de la base de données (T-SQL) -- TABLE [university] ( [school id] INT, [school] NVARCHAR(MAX), [location] NVARCHAR(MAX), [founded] INT, [affiliation] NVARCHAR(MAX), [enrollment] INT, [nickname] NVARCHAR(MAX), [primary conference] NVARCHAR(MAX) ); Question : Show the enrollment...
SELECT TOP 1 enrollment, primary_conference FROM university ORDER BY CASE WHEN founded IS NULL THEN 1 ELSE 0 END, founded
What are the enrollment and primary conference for the university which was founded the earliest?
-- Tables de la base de données (T-SQL) -- TABLE [university] ( [school id] INT, [school] NVARCHAR(MAX), [location] NVARCHAR(MAX), [founded] INT, [affiliation] NVARCHAR(MAX), [enrollment] INT, [nickname] NVARCHAR(MAX), [primary conference] NVARCHAR(MAX) ); Question : What are the enroll...
SELECT TOP 1 enrollment, primary_conference FROM university ORDER BY CASE WHEN founded IS NULL THEN 1 ELSE 0 END, founded
What is the total and minimum enrollment of all schools?
-- Tables de la base de données (T-SQL) -- TABLE [university] ( [school id] INT, [school] NVARCHAR(MAX), [location] NVARCHAR(MAX), [founded] INT, [affiliation] NVARCHAR(MAX), [enrollment] INT, [nickname] NVARCHAR(MAX), [primary conference] NVARCHAR(MAX) ); Question : What is the total a...
SELECT SUM(enrollment), MIN(enrollment) FROM university