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AayushShah
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Univeral_SQL_Three_Datasets_Combined_WithText_IDs

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What are the average and minimum age of captains in different class?
SELECT AVG(age), MIN(age), CLASS FROM captain GROUP BY CLASS
CREATE TABLE captain (CLASS VARCHAR, age INTEGER)
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Find the captain rank that has some captains in both Cutter and Armed schooner classes.
SELECT rank FROM captain WHERE CLASS = 'Cutter' INTERSECT SELECT rank FROM captain WHERE CLASS = 'Armed schooner'
CREATE TABLE captain (rank VARCHAR, CLASS VARCHAR)
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Find the captain rank that has no captain in Third-rate ship of the line class.
SELECT rank FROM captain EXCEPT SELECT rank FROM captain WHERE CLASS = 'Third-rate ship of the line'
CREATE TABLE captain (rank VARCHAR, CLASS VARCHAR)
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What is the name of the youngest captain?
SELECT name FROM captain ORDER BY age LIMIT 1
CREATE TABLE captain (name VARCHAR, age VARCHAR)
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Find the name, type, and flag of the ship that is built in the most recent year.
SELECT name, TYPE, flag FROM ship ORDER BY built_year DESC LIMIT 1
CREATE TABLE ship (name VARCHAR, TYPE VARCHAR, flag VARCHAR, built_year VARCHAR)
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Group by ships by flag, and return number of ships that have each flag.
SELECT COUNT(*), flag FROM ship GROUP BY flag
CREATE TABLE ship (flag VARCHAR)
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Which flag is most widely used among all ships?
SELECT flag FROM ship GROUP BY flag ORDER BY COUNT(*) DESC LIMIT 1
CREATE TABLE ship (flag VARCHAR)
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List all ship names in the order of built year and class.
SELECT name FROM ship ORDER BY built_year, CLASS
CREATE TABLE ship (name VARCHAR, built_year VARCHAR, CLASS VARCHAR)
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Find the ship type that are used by both ships with Panama and Malta flags.
SELECT TYPE FROM ship WHERE flag = 'Panama' INTERSECT SELECT TYPE FROM ship WHERE flag = 'Malta'
CREATE TABLE ship (TYPE VARCHAR, flag VARCHAR)
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In which year were most of ships built?
SELECT built_year FROM ship GROUP BY built_year ORDER BY COUNT(*) DESC LIMIT 1
CREATE TABLE ship (built_year VARCHAR)
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Find the name of the ships that have more than one captain.
SELECT t1.name FROM ship AS t1 JOIN captain AS t2 ON t1.ship_id = t2.ship_id GROUP BY t2.ship_id HAVING COUNT(*) > 1
CREATE TABLE captain (ship_id VARCHAR); CREATE TABLE ship (name VARCHAR, ship_id VARCHAR)
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what are the names and classes of the ships that do not have any captain yet?
SELECT name, CLASS FROM ship WHERE NOT ship_id IN (SELECT ship_id FROM captain)
CREATE TABLE ship (name VARCHAR, CLASS VARCHAR, ship_id VARCHAR); CREATE TABLE captain (name VARCHAR, CLASS VARCHAR, ship_id VARCHAR)
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Find the name of the ship that is steered by the youngest captain.
SELECT t1.name FROM ship AS t1 JOIN captain AS t2 ON t1.ship_id = t2.ship_id ORDER BY t2.age LIMIT 1
CREATE TABLE ship (name VARCHAR, ship_id VARCHAR); CREATE TABLE captain (ship_id VARCHAR, age VARCHAR)
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Find the name and flag of ships that are not steered by any captain with Midshipman rank.
SELECT name, flag FROM ship WHERE NOT ship_id IN (SELECT ship_id FROM captain WHERE rank = 'Midshipman')
CREATE TABLE captain (name VARCHAR, flag VARCHAR, ship_id VARCHAR, rank VARCHAR); CREATE TABLE ship (name VARCHAR, flag VARCHAR, ship_id VARCHAR, rank VARCHAR)
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Find the name of the ships that are steered by both a captain with Midshipman rank and a captain with Lieutenant rank.
SELECT t1.name FROM ship AS t1 JOIN captain AS t2 ON t1.ship_id = t2.ship_id WHERE t2.rank = 'Midshipman' INTERSECT SELECT t1.name FROM ship AS t1 JOIN captain AS t2 ON t1.ship_id = t2.ship_id WHERE t2.rank = 'Lieutenant'
CREATE TABLE ship (name VARCHAR, ship_id VARCHAR); CREATE TABLE captain (ship_id VARCHAR, rank VARCHAR)
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What is id of the city that hosted events in the most recent year?
SELECT host_city FROM hosting_city ORDER BY YEAR DESC LIMIT 1
CREATE TABLE hosting_city (host_city VARCHAR, YEAR VARCHAR)
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Find the match ids of the cities that hosted competition "1994 FIFA World Cup qualification"?
SELECT match_id FROM MATCH WHERE competition = "1994 FIFA World Cup qualification"
CREATE TABLE MATCH (match_id VARCHAR, competition VARCHAR)
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Find the cities which were once a host city after 2010?
SELECT T1.city FROM city AS T1 JOIN hosting_city AS T2 ON T1.city_id = T2.host_city WHERE T2.year > 2010
CREATE TABLE city (city VARCHAR, city_id VARCHAR); CREATE TABLE hosting_city (host_city VARCHAR, year INTEGER)
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Which city has hosted the most events?
SELECT T1.city FROM city AS T1 JOIN hosting_city AS T2 ON T1.city_id = T2.host_city GROUP BY T2.host_city ORDER BY COUNT(*) DESC LIMIT 1
CREATE TABLE city (city VARCHAR, city_id VARCHAR); CREATE TABLE hosting_city (host_city VARCHAR)
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What is the venue of the competition "1994 FIFA World Cup qualification" hosted by "Nanjing ( Jiangsu )"?
SELECT T3.venue FROM city AS T1 JOIN hosting_city AS T2 ON T1.city_id = T2.host_city JOIN MATCH AS T3 ON T2.match_id = T3.match_id WHERE T1.city = "Nanjing ( Jiangsu )" AND T3.competition = "1994 FIFA World Cup qualification"
CREATE TABLE city (city_id VARCHAR, city VARCHAR); CREATE TABLE MATCH (venue VARCHAR, match_id VARCHAR, competition VARCHAR); CREATE TABLE hosting_city (host_city VARCHAR, match_id VARCHAR)
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Give me the temperature of Shanghai in January.
SELECT T2.Jan FROM city AS T1 JOIN temperature AS T2 ON T1.city_id = T2.city_id WHERE T1.city = "Shanghai"
CREATE TABLE city (city_id VARCHAR, city VARCHAR); CREATE TABLE temperature (Jan VARCHAR, city_id VARCHAR)
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What is the host year of city "Taizhou ( Zhejiang )"?
SELECT T2.year FROM city AS T1 JOIN hosting_city AS T2 ON T1.city_id = T2.host_city WHERE T1.city = "Taizhou ( Zhejiang )"
CREATE TABLE city (city_id VARCHAR, city VARCHAR); CREATE TABLE hosting_city (year VARCHAR, host_city VARCHAR)
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Which three cities have the largest regional population?
SELECT city FROM city ORDER BY regional_population DESC LIMIT 3
CREATE TABLE city (city VARCHAR, regional_population VARCHAR)
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Which city has the lowest GDP? Please list the city name and its GDP.
SELECT city, GDP FROM city ORDER BY GDP LIMIT 1
CREATE TABLE city (city VARCHAR, GDP VARCHAR)
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Which city has the highest temperature in February?
SELECT T1.city FROM city AS T1 JOIN temperature AS T2 ON T1.city_id = T2.city_id ORDER BY T2.Feb DESC LIMIT 1
CREATE TABLE city (city VARCHAR, city_id VARCHAR); CREATE TABLE temperature (city_id VARCHAR, Feb VARCHAR)
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Give me a list of cities whose temperature in March is lower than that in July or higher than that in Oct?
SELECT T1.city FROM city AS T1 JOIN temperature AS T2 ON T1.city_id = T2.city_id WHERE T2.Mar < T2.Jul OR T2.Mar > T2.Oct
CREATE TABLE city (city VARCHAR, city_id VARCHAR); CREATE TABLE temperature (city_id VARCHAR, Mar VARCHAR, Jul VARCHAR, Oct VARCHAR)
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Give me a list of cities whose temperature in Mar is lower than that in July and which have also served as host cities?
SELECT T1.city FROM city AS T1 JOIN temperature AS T2 ON T1.city_id = T2.city_id WHERE T2.Mar < T2.Jul INTERSECT SELECT T3.city FROM city AS T3 JOIN hosting_city AS T4 ON T3.city_id = T4.host_city
CREATE TABLE city (city VARCHAR, city_id VARCHAR); CREATE TABLE hosting_city (host_city VARCHAR); CREATE TABLE temperature (city_id VARCHAR, Mar INTEGER, Jul VARCHAR)
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Give me a list of cities whose temperature in Mar is lower than that in Dec and which have never been host cities.
SELECT T1.city FROM city AS T1 JOIN temperature AS T2 ON T1.city_id = T2.city_id WHERE T2.Mar < T2.Dec EXCEPT SELECT T3.city FROM city AS T3 JOIN hosting_city AS T4 ON T3.city_id = T4.host_city
CREATE TABLE city (city VARCHAR, city_id VARCHAR); CREATE TABLE hosting_city (host_city VARCHAR); CREATE TABLE temperature (city_id VARCHAR, Mar INTEGER, Dec VARCHAR)
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Give me a list of cities whose temperature in Feb is higher than that in Jun or cities that were once host cities?
SELECT T1.city FROM city AS T1 JOIN temperature AS T2 ON T1.city_id = T2.city_id WHERE T2.Feb > T2.Jun UNION SELECT T3.city FROM city AS T3 JOIN hosting_city AS T4 ON T3.city_id = T4.host_city
CREATE TABLE city (city VARCHAR, city_id VARCHAR); CREATE TABLE hosting_city (host_city VARCHAR); CREATE TABLE temperature (city_id VARCHAR, Feb INTEGER, Jun VARCHAR)
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Please give me a list of cities whose regional population is over 10000000.
SELECT city FROM city WHERE regional_population > 10000000
CREATE TABLE city (city VARCHAR, regional_population INTEGER)
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Please give me a list of cities whose regional population is over 8000000 or under 5000000.
SELECT city FROM city WHERE regional_population > 10000000 UNION SELECT city FROM city WHERE regional_population < 5000000
CREATE TABLE city (city VARCHAR, regional_population INTEGER)
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Find the number of matches in different competitions.
SELECT COUNT(*), Competition FROM MATCH GROUP BY Competition
CREATE TABLE MATCH (Competition VARCHAR)
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List venues of all matches in the order of their dates starting from the most recent one.
SELECT venue FROM MATCH ORDER BY date DESC
CREATE TABLE MATCH (venue VARCHAR, date VARCHAR)
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what is the GDP of the city with the largest population.
SELECT gdp FROM city ORDER BY Regional_Population DESC LIMIT 1
CREATE TABLE city (gdp VARCHAR, Regional_Population VARCHAR)
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What are the GDP and population of the city that already served as a host more than once?
SELECT t1.gdp, t1.Regional_Population FROM city AS T1 JOIN hosting_city AS T2 ON T1.city_id = T2.host_city GROUP BY t2.Host_City HAVING COUNT(*) > 1
CREATE TABLE hosting_city (host_city VARCHAR); CREATE TABLE city (city_id VARCHAR)
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List every individual's first name, middle name and last name in alphabetical order by last name.
SELECT individual_first_name, individual_middle_name, individual_last_name FROM individuals ORDER BY individual_last_name
CREATE TABLE individuals (individual_first_name VARCHAR, individual_middle_name VARCHAR, individual_last_name VARCHAR)
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List all the types of forms.
SELECT DISTINCT form_type_code FROM forms
CREATE TABLE forms (form_type_code VARCHAR)
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Find the name of the most popular party form.
SELECT t1.form_name FROM forms AS t1 JOIN party_forms AS t2 ON t1.form_id = t2.form_id GROUP BY t2.form_id ORDER BY COUNT(*) DESC LIMIT 1
CREATE TABLE party_forms (form_id VARCHAR); CREATE TABLE forms (form_name VARCHAR, form_id VARCHAR)
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Find the payment method and phone of the party with email "enrico09@example.com".
SELECT payment_method_code, party_phone FROM parties WHERE party_email = "enrico09@example.com"
CREATE TABLE parties (payment_method_code VARCHAR, party_phone VARCHAR, party_email VARCHAR)
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Find the emails of parties with the most popular party form.
SELECT t1.party_email FROM parties AS t1 JOIN party_forms AS t2 ON t1.party_id = t2.party_id WHERE t2.form_id = (SELECT form_id FROM party_forms GROUP BY form_id ORDER BY COUNT(*) DESC LIMIT 1)
CREATE TABLE party_forms (form_id VARCHAR); CREATE TABLE parties (party_email VARCHAR, party_id VARCHAR); CREATE TABLE party_forms (party_id VARCHAR, form_id VARCHAR)
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List all the name of organizations in order of the date formed.
SELECT organization_name FROM organizations ORDER BY date_formed
CREATE TABLE organizations (organization_name VARCHAR, date_formed VARCHAR)
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Find the name of the youngest organization.
SELECT organization_name FROM organizations ORDER BY date_formed DESC LIMIT 1
CREATE TABLE organizations (organization_name VARCHAR, date_formed VARCHAR)
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Find the last name of the latest contact individual of the organization "Labour Party".
SELECT t3.individual_last_name FROM organizations AS t1 JOIN organization_contact_individuals AS t2 ON t1.organization_id = t2.organization_id JOIN individuals AS t3 ON t2.individual_id = t3.individual_id WHERE t1.organization_name = "Labour Party" ORDER BY t2.date_contact_to DESC LIMIT 1
CREATE TABLE organizations (organization_id VARCHAR, organization_name VARCHAR); CREATE TABLE individuals (individual_last_name VARCHAR, individual_id VARCHAR); CREATE TABLE organization_contact_individuals (organization_id VARCHAR, individual_id VARCHAR, date_contact_to VARCHAR)
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Find the last name of the first ever contact person of the organization with the highest UK Vat number.
SELECT t3.individual_last_name FROM organizations AS t1 JOIN organization_contact_individuals AS t2 ON t1.organization_id = t2.organization_id JOIN individuals AS t3 ON t2.individual_id = t3.individual_id WHERE t1.uk_vat_number = (SELECT MAX(uk_vat_number) FROM organizations) ORDER BY t2.date_contact_to LIMIT 1
CREATE TABLE organizations (uk_vat_number INTEGER); CREATE TABLE individuals (individual_last_name VARCHAR, individual_id VARCHAR); CREATE TABLE organizations (organization_id VARCHAR, uk_vat_number INTEGER); CREATE TABLE organization_contact_individuals (organization_id VARCHAR, individual_id VARCHAR, date_contact_to VARCHAR)
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Find name of the services that has never been used.
SELECT service_name FROM services EXCEPT SELECT t1.service_name FROM services AS t1 JOIN party_services AS t2 ON t1.service_id = t2.service_id
CREATE TABLE services (service_name VARCHAR); CREATE TABLE party_services (service_id VARCHAR); CREATE TABLE services (service_name VARCHAR, service_id VARCHAR)
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Find the name of all the cities and states.
SELECT town_city FROM addresses UNION SELECT state_province_county FROM addresses
CREATE TABLE addresses (town_city VARCHAR, state_province_county VARCHAR)
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How many cities are there in state "Colorado"?
SELECT COUNT(*) FROM addresses WHERE state_province_county = "Colorado"
CREATE TABLE addresses (state_province_county VARCHAR)
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Find the payment method code used by more than 3 parties.
SELECT payment_method_code FROM parties GROUP BY payment_method_code HAVING COUNT(*) > 3
CREATE TABLE parties (payment_method_code VARCHAR)
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Find the name of organizations whose names contain "Party".
SELECT organization_name FROM organizations WHERE organization_name LIKE "%Party%"
CREATE TABLE organizations (organization_name VARCHAR)
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How many distinct payment methods are used by parties?
SELECT COUNT(DISTINCT payment_method_code) FROM parties
CREATE TABLE parties (payment_method_code VARCHAR)
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Which is the email of the party that has used the services the most number of times?
SELECT t1.party_email FROM parties AS t1 JOIN party_services AS t2 ON t1.party_id = t2.customer_id GROUP BY t1.party_email ORDER BY COUNT(*) DESC LIMIT 1
CREATE TABLE parties (party_email VARCHAR, party_id VARCHAR); CREATE TABLE party_services (customer_id VARCHAR)
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Which state can address "6862 Kaitlyn Knolls" possibly be in?
SELECT state_province_county FROM addresses WHERE line_1_number_building LIKE "%6862 Kaitlyn Knolls%"
CREATE TABLE addresses (state_province_county VARCHAR, line_1_number_building VARCHAR)
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What is the name of organization that has the greatest number of contact individuals?
SELECT t1.organization_name FROM organizations AS t1 JOIN organization_contact_individuals AS t2 ON t1.organization_id = t2.organization_id GROUP BY t1.organization_name ORDER BY COUNT(*) DESC LIMIT 1
CREATE TABLE organization_contact_individuals (organization_id VARCHAR); CREATE TABLE organizations (organization_name VARCHAR, organization_id VARCHAR)
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Find the last name of the individuals that have been contact individuals of an organization.
SELECT DISTINCT t1.individual_last_name FROM individuals AS t1 JOIN organization_contact_individuals AS t2 ON t1.individual_id = t2.individual_id
CREATE TABLE individuals (individual_last_name VARCHAR, individual_id VARCHAR); CREATE TABLE organization_contact_individuals (individual_id VARCHAR)
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How many drivers are there?
SELECT COUNT(*) FROM driver
CREATE TABLE driver (Id VARCHAR)
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Show the name, home city, and age for all drivers.
SELECT name, home_city, age FROM driver
CREATE TABLE driver (name VARCHAR, home_city VARCHAR, age VARCHAR)
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Show the party and the number of drivers in each party.
SELECT party, COUNT(*) FROM driver GROUP BY party
CREATE TABLE driver (party VARCHAR)
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Show the name of drivers in descending order of age.
SELECT name FROM driver ORDER BY age DESC
CREATE TABLE driver (name VARCHAR, age VARCHAR)
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Show all different home cities.
SELECT DISTINCT home_city FROM driver
CREATE TABLE driver (home_city VARCHAR)
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Show the home city with the most number of drivers.
SELECT home_city FROM driver GROUP BY home_city ORDER BY COUNT(*) DESC LIMIT 1
CREATE TABLE driver (home_city VARCHAR)
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Show the party with drivers from Hartford and drivers older than 40.
SELECT party FROM driver WHERE home_city = 'Hartford' AND age > 40
CREATE TABLE driver (party VARCHAR, home_city VARCHAR, age VARCHAR)
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Show home city where at least two drivers older than 40 are from.
SELECT home_city FROM driver WHERE age > 40 GROUP BY home_city HAVING COUNT(*) >= 2
CREATE TABLE driver (home_city VARCHAR, age INTEGER)
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Show all home cities except for those having a driver older than 40.
SELECT home_city FROM driver EXCEPT SELECT home_city FROM driver WHERE age > 40
CREATE TABLE driver (home_city VARCHAR, age INTEGER)
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Show the names of the drivers without a school bus.
SELECT name FROM driver WHERE NOT driver_id IN (SELECT driver_id FROM school_bus)
CREATE TABLE school_bus (name VARCHAR, driver_id VARCHAR); CREATE TABLE driver (name VARCHAR, driver_id VARCHAR)
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Show the types of schools that have two schools.
SELECT TYPE FROM school GROUP BY TYPE HAVING COUNT(*) = 2
CREATE TABLE school (TYPE VARCHAR)
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Show the school name and driver name for all school buses.
SELECT T2.school, T3.name FROM school_bus AS T1 JOIN school AS T2 ON T1.school_id = T2.school_id JOIN driver AS T3 ON T1.driver_id = T3.driver_id
CREATE TABLE school (school VARCHAR, school_id VARCHAR); CREATE TABLE school_bus (school_id VARCHAR, driver_id VARCHAR); CREATE TABLE driver (name VARCHAR, driver_id VARCHAR)
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What is the maximum, minimum and average years spent working on a school bus?
SELECT MAX(years_working), MIN(years_working), AVG(years_working) FROM school_bus
CREATE TABLE school_bus (years_working INTEGER)
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Show the school name and type for schools without a school bus.
SELECT school, TYPE FROM school WHERE NOT school_id IN (SELECT school_id FROM school_bus)
CREATE TABLE school_bus (school VARCHAR, TYPE VARCHAR, school_id VARCHAR); CREATE TABLE school (school VARCHAR, TYPE VARCHAR, school_id VARCHAR)
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Show the type of school and the number of buses for each type.
SELECT T2.type, COUNT(*) FROM school_bus AS T1 JOIN school AS T2 ON T1.school_id = T2.school_id GROUP BY T2.type
CREATE TABLE school (type VARCHAR, school_id VARCHAR); CREATE TABLE school_bus (school_id VARCHAR)
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How many drivers are from Hartford city or younger than 40?
SELECT COUNT(*) FROM driver WHERE home_city = 'Hartford' OR age < 40
CREATE TABLE driver (home_city VARCHAR, age VARCHAR)
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List names for drivers from Hartford city and younger than 40.
SELECT name FROM driver WHERE home_city = 'Hartford' AND age < 40
CREATE TABLE driver (name VARCHAR, home_city VARCHAR, age VARCHAR)
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find the name of driver who is driving the school bus with the longest working history.
SELECT t1.name FROM driver AS t1 JOIN school_bus AS t2 ON t1.driver_id = t2.driver_id ORDER BY years_working DESC LIMIT 1
CREATE TABLE school_bus (driver_id VARCHAR); CREATE TABLE driver (name VARCHAR, driver_id VARCHAR)
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How many flights have a velocity larger than 200?
SELECT COUNT(*) FROM flight WHERE velocity > 200
CREATE TABLE flight (velocity INTEGER)
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List the vehicle flight number, date and pilot of all the flights, ordered by altitude.
SELECT vehicle_flight_number, date, pilot FROM flight ORDER BY altitude
CREATE TABLE flight (vehicle_flight_number VARCHAR, date VARCHAR, pilot VARCHAR, altitude VARCHAR)
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List the id, country, city and name of the airports ordered alphabetically by the name.
SELECT id, country, city, name FROM airport ORDER BY name
CREATE TABLE airport (id VARCHAR, country VARCHAR, city VARCHAR, name VARCHAR)
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What is maximum group equity shareholding of the companies?
SELECT MAX(group_equity_shareholding) FROM operate_company
CREATE TABLE operate_company (group_equity_shareholding INTEGER)
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What is the velocity of the pilot named 'Thompson'?
SELECT AVG(velocity) FROM flight WHERE pilot = 'Thompson'
CREATE TABLE flight (velocity INTEGER, pilot VARCHAR)
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What are the names and types of the companies that have ever operated a flight?
SELECT T1.name, T1.type FROM operate_company AS T1 JOIN flight AS t2 ON T1.id = T2.company_id
CREATE TABLE operate_company (name VARCHAR, type VARCHAR, id VARCHAR); CREATE TABLE flight (Id VARCHAR)
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What are the names of the airports which are not in the country 'Iceland'?
SELECT name FROM airport WHERE country <> 'Iceland'
CREATE TABLE airport (name VARCHAR, country VARCHAR)
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What are the distinct types of the companies that have operated any flights with velocity less than 200?
SELECT DISTINCT T1.type FROM operate_company AS T1 JOIN flight AS t2 ON T1.id = T2.company_id WHERE T2.velocity < 200
CREATE TABLE flight (Id VARCHAR); CREATE TABLE operate_company (type VARCHAR, id VARCHAR)
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What are the ids and names of the companies that operated more than one flight?
SELECT T1.id, T1.name FROM operate_company AS T1 JOIN flight AS t2 ON T1.id = T2.company_id GROUP BY T1.id HAVING COUNT(*) > 1
CREATE TABLE flight (Id VARCHAR); CREATE TABLE operate_company (id VARCHAR, name VARCHAR)
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What is the id, name and IATA code of the airport that had most number of flights?
SELECT T1.id, T1.name, T1.IATA FROM airport AS T1 JOIN flight AS T2 ON T1.id = T2.airport_id GROUP BY T2.id ORDER BY COUNT(*) DESC LIMIT 1
CREATE TABLE airport (id VARCHAR, name VARCHAR, IATA VARCHAR); CREATE TABLE flight (id VARCHAR, airport_id VARCHAR)
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What are the different pilot names who had piloted a flight in the country 'United States' or in the airport named 'Billund Airport'?
SELECT DISTINCT T2.pilot FROM airport AS T1 JOIN flight AS T2 ON T1.id = T2.airport_id WHERE T1.country = 'United States' OR T1.name = 'Billund Airport'
CREATE TABLE airport (id VARCHAR, country VARCHAR, name VARCHAR); CREATE TABLE flight (pilot VARCHAR, airport_id VARCHAR)
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What is the most common company type, and how many are there?
SELECT TYPE, COUNT(*) FROM operate_company GROUP BY TYPE ORDER BY COUNT(*) DESC LIMIT 1
CREATE TABLE operate_company (TYPE VARCHAR)
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How many airports haven't the pilot 'Thompson' driven an aircraft?
SELECT COUNT(*) FROM airport WHERE NOT id IN (SELECT airport_id FROM flight WHERE pilot = 'Thompson')
CREATE TABLE airport (id VARCHAR, airport_id VARCHAR, pilot VARCHAR); CREATE TABLE flight (id VARCHAR, airport_id VARCHAR, pilot VARCHAR)
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List the name of the pilots who have flied for both a company that mainly provide 'Cargo' services and a company that runs 'Catering services' activities.
SELECT T2.pilot FROM operate_company AS T1 JOIN flight AS t2 ON T1.id = T2.company_id WHERE T1.principal_activities = 'Cargo' INTERSECT SELECT T2.pilot FROM operate_company AS T1 JOIN flight AS t2 ON T1.id = T2.company_id WHERE T1.principal_activities = 'Catering services'
CREATE TABLE operate_company (id VARCHAR, principal_activities VARCHAR); CREATE TABLE flight (Id VARCHAR)
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Which of the airport names contains the word 'international'?
SELECT name FROM airport WHERE name LIKE '%international%'
CREATE TABLE airport (name VARCHAR)
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How many companies operates airlines in each airport?
SELECT T3.id, COUNT(*) FROM operate_company AS T1 JOIN flight AS t2 ON T1.id = T2.company_id JOIN airport AS T3 ON T2.airport_id = T3.id GROUP BY T3.id
CREATE TABLE airport (id VARCHAR); CREATE TABLE flight (Id VARCHAR); CREATE TABLE operate_company (id VARCHAR)
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how many airports are there in each country?
SELECT COUNT(*), country FROM airport GROUP BY country
CREATE TABLE airport (country VARCHAR)
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which countries have more than 2 airports?
SELECT country FROM airport GROUP BY country HAVING COUNT(*) > 2
CREATE TABLE airport (country VARCHAR)
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which pilot is in charge of the most number of flights?
SELECT pilot FROM flight GROUP BY pilot ORDER BY COUNT(*) DESC LIMIT 1
CREATE TABLE flight (pilot VARCHAR)
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Show all account ids and account details.
SELECT account_id, account_details FROM Accounts
CREATE TABLE Accounts (account_id VARCHAR, account_details VARCHAR)
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How many statements do we have?
SELECT COUNT(*) FROM Statements
CREATE TABLE Statements (Id VARCHAR)
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List all statement ids and statement details.
SELECT STATEMENT_ID, statement_details FROM Statements
CREATE TABLE Statements (STATEMENT_ID VARCHAR, statement_details VARCHAR)
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Show statement id, statement detail, account detail for accounts.
SELECT T1.statement_id, T2.statement_details, T1.account_details FROM Accounts AS T1 JOIN Statements AS T2 ON T1.statement_id = T2.statement_id
CREATE TABLE Accounts (statement_id VARCHAR, account_details VARCHAR); CREATE TABLE Statements (statement_details VARCHAR, statement_id VARCHAR)
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[ 3, 23143, 14196, 332, 5411, 5540, 297, 834, 23, 26, 6, 332, 4416, 5540, 297, 834, 221, 5756, 7, 6, 332, 5411, 9, 75, 13362, 834, 221, 5756, 7, 21680, 6288, 7, 6157, 332, 536, 3, 15355, 3162, 16836, 7, 6157, 332, 357, 9191, 332, ...
Show all statement id and the number of accounts for each statement.
SELECT STATEMENT_ID, COUNT(*) FROM Accounts GROUP BY STATEMENT_ID
CREATE TABLE Accounts (STATEMENT_ID VARCHAR)
[ 32100, 32106, 32105, 205, 4386, 6048, 332, 17098, 6288, 7, 41, 4209, 6048, 11810, 834, 4309, 584, 4280, 28027, 61, 3, 32105, 32106, 32107, 32106, 3111, 66, 2493, 3, 23, 26, 11, 8, 381, 13, 3744, 21, 284, 2493, 5, 1, 0, 0, 0, 0, ...
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Show the statement id and the statement detail for the statement with most number of accounts.
SELECT T1.statement_id, T2.statement_details FROM Accounts AS T1 JOIN Statements AS T2 ON T1.statement_id = T2.statement_id GROUP BY T1.statement_id ORDER BY COUNT(*) DESC LIMIT 1
CREATE TABLE Accounts (statement_id VARCHAR); CREATE TABLE Statements (statement_details VARCHAR, statement_id VARCHAR)
[ 32100, 32106, 32105, 205, 4386, 6048, 332, 17098, 6288, 7, 41, 5540, 297, 834, 23, 26, 584, 4280, 28027, 61, 3, 32105, 32106, 32102, 205, 4386, 6048, 332, 17098, 16836, 7, 41, 5540, 297, 834, 221, 5756, 7, 584, 4280, 28027, 6, 2493,...
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[ 3, 23143, 14196, 332, 5411, 5540, 297, 834, 23, 26, 6, 332, 4416, 5540, 297, 834, 221, 5756, 7, 21680, 6288, 7, 6157, 332, 536, 3, 15355, 3162, 16836, 7, 6157, 332, 357, 9191, 332, 5411, 5540, 297, 834, 23, 26, 3274, 332, 4416, ...
Show the number of documents.
SELECT COUNT(*) FROM Documents
CREATE TABLE Documents (Id VARCHAR)
[ 32100, 32106, 32105, 205, 4386, 6048, 332, 17098, 11167, 7, 41, 196, 26, 584, 4280, 28027, 61, 3, 32105, 32106, 32107, 32106, 3111, 8, 381, 13, 2691, 5, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0,...
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List the document type code, document name, and document description for the document with name 'Noel CV' or name 'King Book'.
SELECT document_type_code, document_name, document_description FROM Documents WHERE document_name = 'Noel CV' OR document_name = 'King Book'
CREATE TABLE Documents (document_type_code VARCHAR, document_name VARCHAR, document_description VARCHAR)
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Show the ids and names of all documents.
SELECT document_id, document_name FROM Documents
CREATE TABLE Documents (document_id VARCHAR, document_name VARCHAR)
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