message stringlengths 2 23.8k | message_type stringclasses 2
values | message_id int64 0 1 | conversation_id int64 97 109k | cluster float64 0 0 | __index_level_0__ int64 194 217k |
|---|---|---|---|---|---|
Provide a correct Python 3 solution for this coding contest problem.
Let x be a string of length at least 1. We will call x a good string, if for any string y and any integer k (k \geq 2), the string obtained by concatenating k copies of y is different from x. For example, `a`, `bbc` and `cdcdc` are good strings, whil... | instruction | 0 | 98,501 | 0 | 197,002 |
"Correct Solution:
```
import sys
read = sys.stdin.buffer.read
readline = sys.stdin.buffer.readline
readlines = sys.stdin.buffer.readlines
W = read().rstrip()
N = len(W)
def Z_algorithm(S):
# 共通接頭辞の長さを返す
N=len(S)
arr = [0]*N
arr[0] = N
i,j = 1,0
while i<N:
while i+j<N and S[j]==S[i+j]... | output | 1 | 98,501 | 0 | 197,003 |
Provide a correct Python 3 solution for this coding contest problem.
Let x be a string of length at least 1. We will call x a good string, if for any string y and any integer k (k \geq 2), the string obtained by concatenating k copies of y is different from x. For example, `a`, `bbc` and `cdcdc` are good strings, whil... | instruction | 0 | 98,502 | 0 | 197,004 |
"Correct Solution:
```
w=list(input());n=len(w);t=-1
def Z(s):
m=len(s);z=[0]*m;c=0;f=[1]*m;
for i in range(1,m):
if i+z[i-c]<c+z[c]:z[i]=z[i-c]
else:
j=max(0,c+z[c]-i)
while i+j<n and s[j]==s[i+j]:j=j+1
z[i]=j;c=i
for p in range(1,m):
for k in ran... | output | 1 | 98,502 | 0 | 197,005 |
Provide a correct Python 3 solution for this coding contest problem.
Let x be a string of length at least 1. We will call x a good string, if for any string y and any integer k (k \geq 2), the string obtained by concatenating k copies of y is different from x. For example, `a`, `bbc` and `cdcdc` are good strings, whil... | instruction | 0 | 98,503 | 0 | 197,006 |
"Correct Solution:
```
import sys
read = sys.stdin.buffer.read
readline = sys.stdin.buffer.readline
readlines = sys.stdin.buffer.readlines
W = list(map(int,read().rstrip()))
N = len(W)
def Z_Algorithm(S):
# 共通接頭辞の長さを返す
N=len(S)
arr = [0]*N
arr[0] = N
i,j = 1,0
while i<N:
while i+j<N a... | output | 1 | 98,503 | 0 | 197,007 |
Provide a correct Python 3 solution for this coding contest problem.
Let x be a string of length at least 1. We will call x a good string, if for any string y and any integer k (k \geq 2), the string obtained by concatenating k copies of y is different from x. For example, `a`, `bbc` and `cdcdc` are good strings, whil... | instruction | 0 | 98,504 | 0 | 197,008 |
"Correct Solution:
```
import sys
readline = sys.stdin.readline
class Rollinhash:
def __init__(self, S):
N = len(S)
self.mod = 10**9+9
self.base = 2009
self.has = [0]*(N+1)
self.power = [1]*(N+1)
for i in range(N):
s = S[i]
self.has[... | output | 1 | 98,504 | 0 | 197,009 |
Provide a correct Python 3 solution for this coding contest problem.
Let x be a string of length at least 1. We will call x a good string, if for any string y and any integer k (k \geq 2), the string obtained by concatenating k copies of y is different from x. For example, `a`, `bbc` and `cdcdc` are good strings, whil... | instruction | 0 | 98,505 | 0 | 197,010 |
"Correct Solution:
```
import sys
read = sys.stdin.buffer.read
readline = sys.stdin.buffer.readline
readlines = sys.stdin.buffer.readlines
W = read().rstrip()
N = len(W)
def Z_algorithm(S):
# 共通接頭辞の長さを返す
N=len(S)
arr = [0]*N
arr[0] = N
i,j = 1,0
while i<N:
while i+j<N and S[j]==S[i+j]... | output | 1 | 98,505 | 0 | 197,011 |
Provide a correct Python 3 solution for this coding contest problem.
Let x be a string of length at least 1. We will call x a good string, if for any string y and any integer k (k \geq 2), the string obtained by concatenating k copies of y is different from x. For example, `a`, `bbc` and `cdcdc` are good strings, whil... | instruction | 0 | 98,506 | 0 | 197,012 |
"Correct Solution:
```
from collections import Counter
*W, = map(ord, input())
N = len(W)
C = Counter(W)
if len(C) == 1:
print(N)
print(1)
exit(0)
def z_algo(S):
A = [0]*N
i = 1; j = 0
A[0] = l = len(S)
while i < l:
while i+j < l and S[j] == S[i+j]:
j += 1
A[i] ... | output | 1 | 98,506 | 0 | 197,013 |
Provide a correct Python 3 solution for this coding contest problem.
Let x be a string of length at least 1. We will call x a good string, if for any string y and any integer k (k \geq 2), the string obtained by concatenating k copies of y is different from x. For example, `a`, `bbc` and `cdcdc` are good strings, whil... | instruction | 0 | 98,507 | 0 | 197,014 |
"Correct Solution:
```
w=list(input())
n=len(w)
t=-1
def Z(s):
m=len(s);z=[0]*m;c=0;f=[1]*m;
for i in range(1,m):
if i+z[i-c]<c+z[c]:z[i]=z[i-c]
else:
j=max(0,c+z[c]-i)
while i+j<n and s[j]==s[i+j]:j=j+1
z[i]=j;c=i
for p in range(1,m):
for k in ran... | output | 1 | 98,507 | 0 | 197,015 |
Provide a correct Python 3 solution for this coding contest problem.
Let x be a string of length at least 1. We will call x a good string, if for any string y and any integer k (k \geq 2), the string obtained by concatenating k copies of y is different from x. For example, `a`, `bbc` and `cdcdc` are good strings, whil... | instruction | 0 | 98,508 | 0 | 197,016 |
"Correct Solution:
```
def Z_algorithm(S):
l=len(S)
A=[0]*l
A[0]=l
i=1; j=0
while i<l:
while i+j<l and S[j]==S[i+j]:
j+=1
if not j:
i+=1
continue
A[i]=j
k=1
while l-i>k<j-A[k]:
A[i+k]=A[k]
k+=1
... | output | 1 | 98,508 | 0 | 197,017 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Let x be a string of length at least 1. We will call x a good string, if for any string y and any integer k (k \geq 2), the string obtained by concatenating k copies of y is different from x. Fo... | instruction | 0 | 98,509 | 0 | 197,018 |
No | output | 1 | 98,509 | 0 | 197,019 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Let x be a string of length at least 1. We will call x a good string, if for any string y and any integer k (k \geq 2), the string obtained by concatenating k copies of y is different from x. Fo... | instruction | 0 | 98,510 | 0 | 197,020 |
No | output | 1 | 98,510 | 0 | 197,021 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Let x be a string of length at least 1. We will call x a good string, if for any string y and any integer k (k \geq 2), the string obtained by concatenating k copies of y is different from x. Fo... | instruction | 0 | 98,511 | 0 | 197,022 |
No | output | 1 | 98,511 | 0 | 197,023 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Let x be a string of length at least 1. We will call x a good string, if for any string y and any integer k (k \geq 2), the string obtained by concatenating k copies of y is different from x. Fo... | instruction | 0 | 98,512 | 0 | 197,024 |
No | output | 1 | 98,512 | 0 | 197,025 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given a string s consisting of n lowercase Latin letters. n is even.
For each position i (1 ≤ i ≤ n) in string s you are required to change the letter on this position either to the previous letter in alphabetic order or to the next... | instruction | 0 | 98,604 | 0 | 197,208 |
Tags: implementation, strings
Correct Solution:
```
from sys import stdin
trim = lambda s: s[:-1] if s[-1] == "\n" else s
T = int(stdin.readline())
for i in range(0, T):
n = int(stdin.readline())
s = trim(stdin.readline())
possible = True
for j in range(0, n//2 + 1):
if abs(ord(s[j])-ord(s[-(j+... | output | 1 | 98,604 | 0 | 197,209 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given a string s consisting of n lowercase Latin letters. n is even.
For each position i (1 ≤ i ≤ n) in string s you are required to change the letter on this position either to the previous letter in alphabetic order or to the next... | instruction | 0 | 98,605 | 0 | 197,210 |
Tags: implementation, strings
Correct Solution:
```
import sys
import os
def solve(s):
n = len(s)
for i in range(n // 2):
a = ord(s[i])
b = ord(s[n - 1 - i])
diff = abs(a - b)
if diff != 0 and abs(diff) != 2:
return 'NO'
return 'YES'
def main():
t = int(inpu... | output | 1 | 98,605 | 0 | 197,211 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given a string s consisting of n lowercase Latin letters. n is even.
For each position i (1 ≤ i ≤ n) in string s you are required to change the letter on this position either to the previous letter in alphabetic order or to the next... | instruction | 0 | 98,606 | 0 | 197,212 |
Tags: implementation, strings
Correct Solution:
```
def is_pal(s):
for i in range(len(s)//2):
dif = abs(ord(s[i]) - ord(s[-i-1]))
if dif != 0 and dif != 2 :
return False
return True
t = int(input())
for i in range(t):
n = int(input())
s = input()
buf = []
print("YES... | output | 1 | 98,606 | 0 | 197,213 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given a string s consisting of n lowercase Latin letters. n is even.
For each position i (1 ≤ i ≤ n) in string s you are required to change the letter on this position either to the previous letter in alphabetic order or to the next... | instruction | 0 | 98,607 | 0 | 197,214 |
Tags: implementation, strings
Correct Solution:
```
t = int(input())
while (t):
n = int(input())
s = input()
ok = 0
for i in range (n):
v = abs(ord(s[i]) - ord(s[n-i-1]))
if (v != 0 and v != 2):
ok = 1
if (ok):print("NO")
else: print("YES")
t -= 1
``` | output | 1 | 98,607 | 0 | 197,215 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given a string s consisting of n lowercase Latin letters. n is even.
For each position i (1 ≤ i ≤ n) in string s you are required to change the letter on this position either to the previous letter in alphabetic order or to the next... | instruction | 0 | 98,608 | 0 | 197,216 |
Tags: implementation, strings
Correct Solution:
```
t = int(input())
alphabet = "abcdefghijklmnopqrstuvwxyz"
for i in range(t):
n = int(input())
string = input()
palindrome = True
i = 0
j = len(string) - 1
while(i <= j):
if(string[i] != string[j]):
esq = alphabet.index(string... | output | 1 | 98,608 | 0 | 197,217 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given a string s consisting of n lowercase Latin letters. n is even.
For each position i (1 ≤ i ≤ n) in string s you are required to change the letter on this position either to the previous letter in alphabetic order or to the next... | instruction | 0 | 98,609 | 0 | 197,218 |
Tags: implementation, strings
Correct Solution:
```
import sys
import math
from collections import deque
def scan():
return list(map(int, sys.stdin.readline().strip().split()))
def print_primes_till_n(n):
i, j, flag = 0, 0, 0
a = []
c = 0
for i in range(1, n + 1, 1):
if i == 1 or i == 0:... | output | 1 | 98,609 | 0 | 197,219 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given a string s consisting of n lowercase Latin letters. n is even.
For each position i (1 ≤ i ≤ n) in string s you are required to change the letter on this position either to the previous letter in alphabetic order or to the next... | instruction | 0 | 98,610 | 0 | 197,220 |
Tags: implementation, strings
Correct Solution:
```
def can_be_transformed(word):
for i in range(len(word)//2):
if abs(ord(word[i])-ord(word[-i-1]))>2 or abs(ord(word[i])-ord(word[-i-1])) == 1:
return False
return True
def main():
answers = []
n=int(input())
for i in range(0,n):... | output | 1 | 98,610 | 0 | 197,221 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given a string s consisting of n lowercase Latin letters. n is even.
For each position i (1 ≤ i ≤ n) in string s you are required to change the letter on this position either to the previous letter in alphabetic order or to the next... | instruction | 0 | 98,611 | 0 | 197,222 |
Tags: implementation, strings
Correct Solution:
```
def search(s,n):
for i in range(n//2):
x=abs(ord(s[i])-ord(s[n-i-1]))
if x!=0 and x!=2:
return(False)
return(True)
t=int(input())
for _ in range(t):
n=int(input())
s=input()
if search(s,n):
print("YES")
else... | output | 1 | 98,611 | 0 | 197,223 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a string s consisting of n lowercase Latin letters. n is even.
For each position i (1 ≤ i ≤ n) in string s you are required to change the letter on this position either to the pre... | instruction | 0 | 98,612 | 0 | 197,224 |
Yes | output | 1 | 98,612 | 0 | 197,225 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a string s consisting of n lowercase Latin letters. n is even.
For each position i (1 ≤ i ≤ n) in string s you are required to change the letter on this position either to the pre... | instruction | 0 | 98,613 | 0 | 197,226 |
Yes | output | 1 | 98,613 | 0 | 197,227 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a string s consisting of n lowercase Latin letters. n is even.
For each position i (1 ≤ i ≤ n) in string s you are required to change the letter on this position either to the pre... | instruction | 0 | 98,614 | 0 | 197,228 |
Yes | output | 1 | 98,614 | 0 | 197,229 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a string s consisting of n lowercase Latin letters. n is even.
For each position i (1 ≤ i ≤ n) in string s you are required to change the letter on this position either to the pre... | instruction | 0 | 98,615 | 0 | 197,230 |
Yes | output | 1 | 98,615 | 0 | 197,231 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a string s consisting of n lowercase Latin letters. n is even.
For each position i (1 ≤ i ≤ n) in string s you are required to change the letter on this position either to the pre... | instruction | 0 | 98,616 | 0 | 197,232 |
No | output | 1 | 98,616 | 0 | 197,233 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a string s consisting of n lowercase Latin letters. n is even.
For each position i (1 ≤ i ≤ n) in string s you are required to change the letter on this position either to the pre... | instruction | 0 | 98,617 | 0 | 197,234 |
No | output | 1 | 98,617 | 0 | 197,235 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a string s consisting of n lowercase Latin letters. n is even.
For each position i (1 ≤ i ≤ n) in string s you are required to change the letter on this position either to the pre... | instruction | 0 | 98,618 | 0 | 197,236 |
No | output | 1 | 98,618 | 0 | 197,237 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a string s consisting of n lowercase Latin letters. n is even.
For each position i (1 ≤ i ≤ n) in string s you are required to change the letter on this position either to the pre... | instruction | 0 | 98,619 | 0 | 197,238 |
No | output | 1 | 98,619 | 0 | 197,239 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Let s be some string consisting of symbols "0" or "1". Let's call a string t a substring of string s, if there exists such number 1 ≤ l ≤ |s| - |t| + 1 that t = s_l s_{l+1} … s_{l + |t| - 1}. Let's call a substring t of string s unique, if t... | instruction | 0 | 98,661 | 0 | 197,322 |
Tags: constructive algorithms, math, strings
Correct Solution:
```
import sys
from math import *
from fractions import gcd
readints=lambda:map(int, input().strip('\n').split())
def hasUnique(s,n,k):
freq = {}
for i in range(n-k+1):
x = s[i:i+k]
if x not in freq: freq[x]=0
freq[x]+=1
... | output | 1 | 98,661 | 0 | 197,323 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Let s be some string consisting of symbols "0" or "1". Let's call a string t a substring of string s, if there exists such number 1 ≤ l ≤ |s| - |t| + 1 that t = s_l s_{l+1} … s_{l + |t| - 1}. Let's call a substring t of string s unique, if t... | instruction | 0 | 98,662 | 0 | 197,324 |
Tags: constructive algorithms, math, strings
Correct Solution:
```
n, k = map(int, input().split())
if k == 1:
print("1", end = "")
for i in range(1, n):
print("0", end = "")
print()
exit()
a = (n + k - 2) // 2
ans = ""
if (a - k + 2) % 2:
for i in range (a - k + 2):
ans += chr(i % 2... | output | 1 | 98,662 | 0 | 197,325 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Let s be some string consisting of symbols "0" or "1". Let's call a string t a substring of string s, if there exists such number 1 ≤ l ≤ |s| - |t| + 1 that t = s_l s_{l+1} … s_{l + |t| - 1}. Let's call a substring t of string s unique, if t... | instruction | 0 | 98,663 | 0 | 197,326 |
Tags: constructive algorithms, math, strings
Correct Solution:
```
N, K = map(int, input().split())
if K == 0 or N == K:
print("1" * N)
elif K == 1:
print("0" + "1" * (N - 1))
elif K <= 2//N:
if K & 1:
print("10" * (K//2+1) + "1" * (N-2-K//2*2))
else:
print("0" + "10" * (K//2) + "1" * (N... | output | 1 | 98,663 | 0 | 197,327 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Let s be some string consisting of symbols "0" or "1". Let's call a string t a substring of string s, if there exists such number 1 ≤ l ≤ |s| - |t| + 1 that t = s_l s_{l+1} … s_{l + |t| - 1}. Let's call a substring t of string s unique, if t... | instruction | 0 | 98,664 | 0 | 197,328 |
Tags: constructive algorithms, math, strings
Correct Solution:
```
n, k = list(map(int,input().split()))
chuj_twojej_starej = (n - k) // 2 + 1
i = 1
while True:
if i % chuj_twojej_starej == 0:
print(0, end = "")
else:
print(1, end = "")
if i == n:
break
i += 1
``` | output | 1 | 98,664 | 0 | 197,329 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Let s be some string consisting of symbols "0" or "1". Let's call a string t a substring of string s, if there exists such number 1 ≤ l ≤ |s| - |t| + 1 that t = s_l s_{l+1} … s_{l + |t| - 1}. Let's call a substring t of string s unique, if t... | instruction | 0 | 98,665 | 0 | 197,330 |
Tags: constructive algorithms, math, strings
Correct Solution:
```
n,k=map(int,input().split())
d=(n-k)//2
s=0
while s!=n:
if (s+1)%(d+1)==0:
print("1",end="")
else :
print("0",end="")
s+=1
``` | output | 1 | 98,665 | 0 | 197,331 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Let s be some string consisting of symbols "0" or "1". Let's call a string t a substring of string s, if there exists such number 1 ≤ l ≤ |s| - |t| + 1 that t = s_l s_{l+1} … s_{l + |t| - 1}. Let's call a substring t of string s unique, if t... | instruction | 0 | 98,666 | 0 | 197,332 |
Tags: constructive algorithms, math, strings
Correct Solution:
```
N, K = map(int, input().split())
if N == K:
print("0"*N)
elif K == 1:
print("0"*(N-1) + "1")
elif K == 3:
print("1" + "0"*(N-4) + "101")
else:
res = ["0"]*N
for i in range(0, N, N//2-K//2+1):
res[i] = "1"
print(''.join(re... | output | 1 | 98,666 | 0 | 197,333 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Let s be some string consisting of symbols "0" or "1". Let's call a string t a substring of string s, if there exists such number 1 ≤ l ≤ |s| - |t| + 1 that t = s_l s_{l+1} … s_{l + |t| - 1}. Let's call a substring t of string s unique, if t... | instruction | 0 | 98,667 | 0 | 197,334 |
Tags: constructive algorithms, math, strings
Correct Solution:
```
n,k=map(int,input().split())
x=(n-(k-1)+1)//2
STR="0"*(x-1)+"1"
ANS=STR*(n//x+1)
print(ANS[:n])
``` | output | 1 | 98,667 | 0 | 197,335 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Let s be some string consisting of symbols "0" or "1". Let's call a string t a substring of string s, if there exists such number 1 ≤ l ≤ |s| - |t| + 1 that t = s_l s_{l+1} … s_{l + |t| - 1}. Let's call a substring t of string s unique, if t... | instruction | 0 | 98,668 | 0 | 197,336 |
Tags: constructive algorithms, math, strings
Correct Solution:
```
#------------------------------warmup----------------------------
import os
import sys
from io import BytesIO, IOBase
BUFSIZE = 8192
class FastIO(IOBase):
newlines = 0
def __init__(self, file):
self._fd = file.fileno()
se... | output | 1 | 98,668 | 0 | 197,337 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Let s be some string consisting of symbols "0" or "1". Let's call a string t a substring of string s, if there exists such number 1 ≤ l ≤ |s| - |t| + 1 that t = s_l s_{l+1} … s_{l + |t| - 1}. Le... | instruction | 0 | 98,669 | 0 | 197,338 |
Yes | output | 1 | 98,669 | 0 | 197,339 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Let s be some string consisting of symbols "0" or "1". Let's call a string t a substring of string s, if there exists such number 1 ≤ l ≤ |s| - |t| + 1 that t = s_l s_{l+1} … s_{l + |t| - 1}. Le... | instruction | 0 | 98,670 | 0 | 197,340 |
Yes | output | 1 | 98,670 | 0 | 197,341 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Let s be some string consisting of symbols "0" or "1". Let's call a string t a substring of string s, if there exists such number 1 ≤ l ≤ |s| - |t| + 1 that t = s_l s_{l+1} … s_{l + |t| - 1}. Le... | instruction | 0 | 98,671 | 0 | 197,342 |
Yes | output | 1 | 98,671 | 0 | 197,343 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Let s be some string consisting of symbols "0" or "1". Let's call a string t a substring of string s, if there exists such number 1 ≤ l ≤ |s| - |t| + 1 that t = s_l s_{l+1} … s_{l + |t| - 1}. Le... | instruction | 0 | 98,672 | 0 | 197,344 |
Yes | output | 1 | 98,672 | 0 | 197,345 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Let s be some string consisting of symbols "0" or "1". Let's call a string t a substring of string s, if there exists such number 1 ≤ l ≤ |s| - |t| + 1 that t = s_l s_{l+1} … s_{l + |t| - 1}. Le... | instruction | 0 | 98,673 | 0 | 197,346 |
No | output | 1 | 98,673 | 0 | 197,347 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Let s be some string consisting of symbols "0" or "1". Let's call a string t a substring of string s, if there exists such number 1 ≤ l ≤ |s| - |t| + 1 that t = s_l s_{l+1} … s_{l + |t| - 1}. Le... | instruction | 0 | 98,674 | 0 | 197,348 |
No | output | 1 | 98,674 | 0 | 197,349 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Let s be some string consisting of symbols "0" or "1". Let's call a string t a substring of string s, if there exists such number 1 ≤ l ≤ |s| - |t| + 1 that t = s_l s_{l+1} … s_{l + |t| - 1}. Le... | instruction | 0 | 98,675 | 0 | 197,350 |
No | output | 1 | 98,675 | 0 | 197,351 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Let s be some string consisting of symbols "0" or "1". Let's call a string t a substring of string s, if there exists such number 1 ≤ l ≤ |s| - |t| + 1 that t = s_l s_{l+1} … s_{l + |t| - 1}. Le... | instruction | 0 | 98,676 | 0 | 197,352 |
No | output | 1 | 98,676 | 0 | 197,353 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given a string s[1 ... n] consisting of lowercase Latin letters. It is guaranteed that n = 2^k for some integer k ≥ 0.
The string s[1 ... n] is called c-good if at least one of the following three conditions is satisfied:
* The l... | instruction | 0 | 98,808 | 0 | 197,616 |
Tags: bitmasks, brute force, divide and conquer, dp, implementation
Correct Solution:
```
def fn(s,a):
if len(s)==1:
if s==a:
return 0
else:
return 1
a1=0
a2=0
l=len(s)//2
t=s[:l]
p=s[l:]
for i in t:
if i!=a:
a1+=1
for... | output | 1 | 98,808 | 0 | 197,617 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given a string s[1 ... n] consisting of lowercase Latin letters. It is guaranteed that n = 2^k for some integer k ≥ 0.
The string s[1 ... n] is called c-good if at least one of the following three conditions is satisfied:
* The l... | instruction | 0 | 98,809 | 0 | 197,618 |
Tags: bitmasks, brute force, divide and conquer, dp, implementation
Correct Solution:
```
LETRAS = "abcdefghijklmnopqrstuvwxyz"
def string_boa(indice, string):
letras = LETRAS[indice]
if len(string) == 1:
if string != letras:
return 1
else:
return 0
direita... | output | 1 | 98,809 | 0 | 197,619 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given a string s[1 ... n] consisting of lowercase Latin letters. It is guaranteed that n = 2^k for some integer k ≥ 0.
The string s[1 ... n] is called c-good if at least one of the following three conditions is satisfied:
* The l... | instruction | 0 | 98,810 | 0 | 197,620 |
Tags: bitmasks, brute force, divide and conquer, dp, implementation
Correct Solution:
```
"""
Author: Q.E.D
Time: 2020-07-17 10:11:52
"""
def count(s, c):
c2 = chr(ord(c) + 1)
if len(s) == 1:
return 1 - int(s[0] == c)
else:
n = len(s)
h = n // 2
x1 = sum(1 for a in s[:h] if a... | output | 1 | 98,810 | 0 | 197,621 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given a string s[1 ... n] consisting of lowercase Latin letters. It is guaranteed that n = 2^k for some integer k ≥ 0.
The string s[1 ... n] is called c-good if at least one of the following three conditions is satisfied:
* The l... | instruction | 0 | 98,811 | 0 | 197,622 |
Tags: bitmasks, brute force, divide and conquer, dp, implementation
Correct Solution:
```
import sys
from math import log
def num(l, r, d):
mid = (l+r)//2
if d>=k:
return 0 if list_s[l] == n2a[d] else 1
count_l = len([0 for i in range(l, mid+1) if list_s[i] != n2a[d]])
count_r = len([0 for i in... | output | 1 | 98,811 | 0 | 197,623 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given a string s[1 ... n] consisting of lowercase Latin letters. It is guaranteed that n = 2^k for some integer k ≥ 0.
The string s[1 ... n] is called c-good if at least one of the following three conditions is satisfied:
* The l... | instruction | 0 | 98,812 | 0 | 197,624 |
Tags: bitmasks, brute force, divide and conquer, dp, implementation
Correct Solution:
```
import sys
def rs(): return sys.stdin.readline().rstrip()
def ri(): return int(sys.stdin.readline())
def ria(): return list(map(int, sys.stdin.readline().split()))
def ws(s): sys.stdout.write(s); sys.stdout.write('\n')
def wi(n): ... | output | 1 | 98,812 | 0 | 197,625 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given a string s[1 ... n] consisting of lowercase Latin letters. It is guaranteed that n = 2^k for some integer k ≥ 0.
The string s[1 ... n] is called c-good if at least one of the following three conditions is satisfied:
* The l... | instruction | 0 | 98,813 | 0 | 197,626 |
Tags: bitmasks, brute force, divide and conquer, dp, implementation
Correct Solution:
```
import sys, threading
sys.setrecursionlimit(10**8)
threading.stack_size(10**8) # new thread will get stack of such size
def main():
def findMinCost(s,targetChar):
if len(s)==1:
return int(s[0]!=targ... | output | 1 | 98,813 | 0 | 197,627 |
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