message stringlengths 2 23.8k | message_type stringclasses 2 values | message_id int64 0 1 | conversation_id int64 97 109k | cluster float64 0 0 | __index_level_0__ int64 194 217k |
|---|---|---|---|---|---|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Kaavi, the mysterious fortune teller, deeply believes that one's fate is inevitable and unavoidable. Of course, she makes her living by predicting others' future. While doing divination, Kaavi believes that magic spells can provide great power for her to see the future.
<image>
Kaavi has a string T of length m and all the strings with the prefix T are magic spells. Kaavi also has a string S of length n and an empty string A.
During the divination, Kaavi needs to perform a sequence of operations. There are two different operations:
* Delete the first character of S and add it at the front of A.
* Delete the first character of S and add it at the back of A.
Kaavi can perform no more than n operations. To finish the divination, she wants to know the number of different operation sequences to make A a magic spell (i.e. with the prefix T). As her assistant, can you help her? The answer might be huge, so Kaavi only needs to know the answer modulo 998 244 353.
Two operation sequences are considered different if they are different in length or there exists an i that their i-th operation is different.
A substring is a contiguous sequence of characters within a string. A prefix of a string S is a substring of S that occurs at the beginning of S.
Input
The first line contains a string S of length n (1 ≤ n ≤ 3000).
The second line contains a string T of length m (1 ≤ m ≤ n).
Both strings contain only lowercase Latin letters.
Output
The output contains only one integer — the answer modulo 998 244 353.
Examples
Input
abab
ba
Output
12
Input
defineintlonglong
signedmain
Output
0
Input
rotator
rotator
Output
4
Input
cacdcdbbbb
bdcaccdbbb
Output
24
Note
The first test:
<image>
The red ones are the magic spells. In the first operation, Kaavi can either add the first character "a" at the front or the back of A, although the results are the same, they are considered as different operations. So the answer is 6×2=12.
Submitted Solution:
```
import os
import sys
#input = sys.stdin.buffer.readline
#sys.setrecursionlimit(int(3e5))
from collections import deque
from queue import PriorityQueue
import math
# list(map(int, input().split()))
#####################################################################################
class CF(object):
def __init__(self):
self.mod = 998244353
self.s = input()
self.t = input()
self.n = len(self.s)
self.dp = [[0]*(self.n+1) for _ in range(self.n +1)]
for i in range(len(self.s) + 1):
self.dp[0][i] = 1
for i in range(self.n):
if((i+1)<=len(self.t)):
if(self.s[i] == self.t[i]):
self.dp[i+1][0] += self.dp[i][0]
self.dp[i+1][0] %= self.mod
else:
self.dp[i+1][0] += self.dp[i][0]
self.dp[i+1][0] %= self.mod
for j in range(1, len(self.s) + 1):
if(j-1 < len(self.t)):
if(self.s[i] == self.t[j-1]):
self.dp[i+1][j-1] += self.dp[i][j]
self.dp[i+1][j-1] %= self.mod
else:
self.dp[i+1][j-1] += self.dp[i][j]
self.dp[i+1][j-1] %= self.mod
if(j+i < len(self.t)):
if(self.s[i] == self.t[j+i]):
self.dp[i+1][j] += self.dp[i][j]
self.dp[i+1][j] %= self.mod
else:
self.dp[i+1][j] += self.dp[i][j]
self.dp[i+1][j] %= self.mod
pass
pass
ans = 0
for i in range(len(self.t), len(self.s)+1):
ans += self.dp[i][0]
ans %= self.mod
print(ans)
#print(self.dp)
def main(self):
pass
if __name__ == "__main__":
cf = CF()
cf.main()
pass
``` | instruction | 0 | 54,925 | 0 | 109,850 |
Yes | output | 1 | 54,925 | 0 | 109,851 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Kaavi, the mysterious fortune teller, deeply believes that one's fate is inevitable and unavoidable. Of course, she makes her living by predicting others' future. While doing divination, Kaavi believes that magic spells can provide great power for her to see the future.
<image>
Kaavi has a string T of length m and all the strings with the prefix T are magic spells. Kaavi also has a string S of length n and an empty string A.
During the divination, Kaavi needs to perform a sequence of operations. There are two different operations:
* Delete the first character of S and add it at the front of A.
* Delete the first character of S and add it at the back of A.
Kaavi can perform no more than n operations. To finish the divination, she wants to know the number of different operation sequences to make A a magic spell (i.e. with the prefix T). As her assistant, can you help her? The answer might be huge, so Kaavi only needs to know the answer modulo 998 244 353.
Two operation sequences are considered different if they are different in length or there exists an i that their i-th operation is different.
A substring is a contiguous sequence of characters within a string. A prefix of a string S is a substring of S that occurs at the beginning of S.
Input
The first line contains a string S of length n (1 ≤ n ≤ 3000).
The second line contains a string T of length m (1 ≤ m ≤ n).
Both strings contain only lowercase Latin letters.
Output
The output contains only one integer — the answer modulo 998 244 353.
Examples
Input
abab
ba
Output
12
Input
defineintlonglong
signedmain
Output
0
Input
rotator
rotator
Output
4
Input
cacdcdbbbb
bdcaccdbbb
Output
24
Note
The first test:
<image>
The red ones are the magic spells. In the first operation, Kaavi can either add the first character "a" at the front or the back of A, although the results are the same, they are considered as different operations. So the answer is 6×2=12.
Submitted Solution:
```
import sys
from copy import copy, deepcopy
input = sys.stdin.readline
inf = 100000000000000000 # 1e17
mod = 998244353
S = input().strip()
n = len(S)
T = input().strip()
T = list(T)
num = len(T)
T.extend(["!"] * (n - len(T)))
f = [[0] * (n + 10) for i in range(n + 10)]
for i in range(n):
f[i][i - 1] = 1
f[i + 1][i] = 1
for i in range(n):
for l in range(n):
r = l + i
if r >= n:
break
if S[i] == T[r] or T[r] == "!":
f[l][r] += f[l][r - 1]
f[l][r] %= mod
if S[i] == T[l] or T[l] == "!":
f[l][r] += f[l + 1][r]
f[l][r] %= mod
ans = 0
for i in range(num - 1, n):
ans += (f[0][i])
ans %= mod
print(ans % mod)
``` | instruction | 0 | 54,926 | 0 | 109,852 |
Yes | output | 1 | 54,926 | 0 | 109,853 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Kaavi, the mysterious fortune teller, deeply believes that one's fate is inevitable and unavoidable. Of course, she makes her living by predicting others' future. While doing divination, Kaavi believes that magic spells can provide great power for her to see the future.
<image>
Kaavi has a string T of length m and all the strings with the prefix T are magic spells. Kaavi also has a string S of length n and an empty string A.
During the divination, Kaavi needs to perform a sequence of operations. There are two different operations:
* Delete the first character of S and add it at the front of A.
* Delete the first character of S and add it at the back of A.
Kaavi can perform no more than n operations. To finish the divination, she wants to know the number of different operation sequences to make A a magic spell (i.e. with the prefix T). As her assistant, can you help her? The answer might be huge, so Kaavi only needs to know the answer modulo 998 244 353.
Two operation sequences are considered different if they are different in length or there exists an i that their i-th operation is different.
A substring is a contiguous sequence of characters within a string. A prefix of a string S is a substring of S that occurs at the beginning of S.
Input
The first line contains a string S of length n (1 ≤ n ≤ 3000).
The second line contains a string T of length m (1 ≤ m ≤ n).
Both strings contain only lowercase Latin letters.
Output
The output contains only one integer — the answer modulo 998 244 353.
Examples
Input
abab
ba
Output
12
Input
defineintlonglong
signedmain
Output
0
Input
rotator
rotator
Output
4
Input
cacdcdbbbb
bdcaccdbbb
Output
24
Note
The first test:
<image>
The red ones are the magic spells. In the first operation, Kaavi can either add the first character "a" at the front or the back of A, although the results are the same, they are considered as different operations. So the answer is 6×2=12.
Submitted Solution:
```
import sys
input = sys.stdin.readline
sys.setrecursionlimit(10 ** 4)
s = input()
t = input()
MOD = 998244353
t = t + (len(s) - len(t)) * "?"
n = len(s)
dp = [[-1] * (n + 1) for i in range(n + 1)]
def solve(l, r):
if dp[l][r] != -1:
return dp[l][r]
times = r - l
if times == 1:
if s[0] == t[l] or t[l] == "?":
dp[l][r] = 2
else:
dp[l][r] = 0
return dp[l][r]
dp[l][r] = 0
if s[times - 1] == t[l] or t[l] == "?":
dp[l][r] += solve(l + 1, r)
if s[times - 1] == t[r - 1] or t[r - 1] == "?":
dp[l][r] += solve(l, r - 1)
dp[l][r] %= MOD
return dp[l][r]
ans = 0
solve(0, n)
for i in range(n):
if t[i] == "?":
ans += dp[0][i]
ans %= MOD
ans += dp[0][n]
ans %= MOD
print(ans)
``` | instruction | 0 | 54,927 | 0 | 109,854 |
No | output | 1 | 54,927 | 0 | 109,855 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Kaavi, the mysterious fortune teller, deeply believes that one's fate is inevitable and unavoidable. Of course, she makes her living by predicting others' future. While doing divination, Kaavi believes that magic spells can provide great power for her to see the future.
<image>
Kaavi has a string T of length m and all the strings with the prefix T are magic spells. Kaavi also has a string S of length n and an empty string A.
During the divination, Kaavi needs to perform a sequence of operations. There are two different operations:
* Delete the first character of S and add it at the front of A.
* Delete the first character of S and add it at the back of A.
Kaavi can perform no more than n operations. To finish the divination, she wants to know the number of different operation sequences to make A a magic spell (i.e. with the prefix T). As her assistant, can you help her? The answer might be huge, so Kaavi only needs to know the answer modulo 998 244 353.
Two operation sequences are considered different if they are different in length or there exists an i that their i-th operation is different.
A substring is a contiguous sequence of characters within a string. A prefix of a string S is a substring of S that occurs at the beginning of S.
Input
The first line contains a string S of length n (1 ≤ n ≤ 3000).
The second line contains a string T of length m (1 ≤ m ≤ n).
Both strings contain only lowercase Latin letters.
Output
The output contains only one integer — the answer modulo 998 244 353.
Examples
Input
abab
ba
Output
12
Input
defineintlonglong
signedmain
Output
0
Input
rotator
rotator
Output
4
Input
cacdcdbbbb
bdcaccdbbb
Output
24
Note
The first test:
<image>
The red ones are the magic spells. In the first operation, Kaavi can either add the first character "a" at the front or the back of A, although the results are the same, they are considered as different operations. So the answer is 6×2=12.
Submitted Solution:
```
import sys
from copy import copy, deepcopy
input = sys.stdin.readline
'''
n, m = map(int, input().split())
n = int(input())
A = list(map(int, input().split()))
S = input().strip()
for CASES in range(int(input())):
'''
inf = 100000000000000000 # 1e17
mod = 998244353
'''
# example input
abab
ba
'''
S = input().strip()
n = len(S)
T = input().strip()
T = list(T)
num = len(T)
T.extend(["!"] * (n - len(T)))
f = [[0] * (n + 10) for i in range(n + 10)]
for i in range(n):
f[i][i - 1] = 1
f[i + 1][i] = 1
for i in range(n):
for l in range(n):
r = l + i
if r >= n:
break
if S[i] == T[r] or T[r] == "!":
f[l][r] += f[l][r - 1]
if S[i] == T[l] or T[l] == "!":
f[l][r] += f[l + 1][r]
ans = 0
for i in range(num - 1, n):
ans += (f[0][i])
print(ans)
``` | instruction | 0 | 54,928 | 0 | 109,856 |
No | output | 1 | 54,928 | 0 | 109,857 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Kaavi, the mysterious fortune teller, deeply believes that one's fate is inevitable and unavoidable. Of course, she makes her living by predicting others' future. While doing divination, Kaavi believes that magic spells can provide great power for her to see the future.
<image>
Kaavi has a string T of length m and all the strings with the prefix T are magic spells. Kaavi also has a string S of length n and an empty string A.
During the divination, Kaavi needs to perform a sequence of operations. There are two different operations:
* Delete the first character of S and add it at the front of A.
* Delete the first character of S and add it at the back of A.
Kaavi can perform no more than n operations. To finish the divination, she wants to know the number of different operation sequences to make A a magic spell (i.e. with the prefix T). As her assistant, can you help her? The answer might be huge, so Kaavi only needs to know the answer modulo 998 244 353.
Two operation sequences are considered different if they are different in length or there exists an i that their i-th operation is different.
A substring is a contiguous sequence of characters within a string. A prefix of a string S is a substring of S that occurs at the beginning of S.
Input
The first line contains a string S of length n (1 ≤ n ≤ 3000).
The second line contains a string T of length m (1 ≤ m ≤ n).
Both strings contain only lowercase Latin letters.
Output
The output contains only one integer — the answer modulo 998 244 353.
Examples
Input
abab
ba
Output
12
Input
defineintlonglong
signedmain
Output
0
Input
rotator
rotator
Output
4
Input
cacdcdbbbb
bdcaccdbbb
Output
24
Note
The first test:
<image>
The red ones are the magic spells. In the first operation, Kaavi can either add the first character "a" at the front or the back of A, although the results are the same, they are considered as different operations. So the answer is 6×2=12.
Submitted Solution:
```
mod = 998244353
eps = 10**-9
def main():
import sys
input = sys.stdin.readline
S = input().rstrip('\n')
S = S[::-1]
T = input().rstrip('\n')
NS = len(S)
NT = len(T)
dp = [[0] * (NT+1) for _ in range(NS+1)]
dp[0][0] = 1
for i in range(NS):
s = S[i]
for j in range(NT+1):
# front
if j == 0:
if i != NS-1:
if T[0] == s:
dp[i+1][1] = (dp[i+1][1] + dp[i][0] + min(i, NS-NT))%mod
else:
if T[0] == s:
dp[i+1][-1] = (dp[i+1][-1] + dp[i][0])%mod
elif j == NT:
dp[i+1][j] = (dp[i+1][j] + dp[i][j])%mod
else:
if i != NS-1:
if s == T[j]:
dp[i+1][j+1] = (dp[i+1][j+1] + dp[i][j])%mod
else:
if s == T[j]:
dp[i + 1][-1] = (dp[i + 1][-1] + dp[i][j]) % mod
# back
k = NS - (i-j) - 1
if k >= NT:
if i != NS-1:
dp[i+1][j] = (dp[i+1][j] + dp[i][j])%mod
else:
dp[i + 1][-1] = (dp[i + 1][-1] + dp[i][j]) % mod
else:
if T[k] == s:
if i != NS-1:
dp[i + 1][j] = (dp[i + 1][j] + dp[i][j]) % mod
else:
dp[i + 1][-1] = (dp[i + 1][-1] + dp[i][j]) % mod
print(dp[-1][-1])
#[print(i, dp[i]) for i in range(NS+1)]
if __name__ == '__main__':
main()
``` | instruction | 0 | 54,929 | 0 | 109,858 |
No | output | 1 | 54,929 | 0 | 109,859 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Kaavi, the mysterious fortune teller, deeply believes that one's fate is inevitable and unavoidable. Of course, she makes her living by predicting others' future. While doing divination, Kaavi believes that magic spells can provide great power for her to see the future.
<image>
Kaavi has a string T of length m and all the strings with the prefix T are magic spells. Kaavi also has a string S of length n and an empty string A.
During the divination, Kaavi needs to perform a sequence of operations. There are two different operations:
* Delete the first character of S and add it at the front of A.
* Delete the first character of S and add it at the back of A.
Kaavi can perform no more than n operations. To finish the divination, she wants to know the number of different operation sequences to make A a magic spell (i.e. with the prefix T). As her assistant, can you help her? The answer might be huge, so Kaavi only needs to know the answer modulo 998 244 353.
Two operation sequences are considered different if they are different in length or there exists an i that their i-th operation is different.
A substring is a contiguous sequence of characters within a string. A prefix of a string S is a substring of S that occurs at the beginning of S.
Input
The first line contains a string S of length n (1 ≤ n ≤ 3000).
The second line contains a string T of length m (1 ≤ m ≤ n).
Both strings contain only lowercase Latin letters.
Output
The output contains only one integer — the answer modulo 998 244 353.
Examples
Input
abab
ba
Output
12
Input
defineintlonglong
signedmain
Output
0
Input
rotator
rotator
Output
4
Input
cacdcdbbbb
bdcaccdbbb
Output
24
Note
The first test:
<image>
The red ones are the magic spells. In the first operation, Kaavi can either add the first character "a" at the front or the back of A, although the results are the same, they are considered as different operations. So the answer is 6×2=12.
Submitted Solution:
```
mod = 998244353
eps = 10**-9
def main():
import sys
input = sys.stdin.readline
S = input().rstrip('\n')
S = S[::-1]
T = input().rstrip('\n')
NS = len(S)
NT = len(T)
dp = [[0] * (NT+1) for _ in range(NS+1)]
dp[0][0] = 1
for i in range(NS):
s = S[i]
for j in range(min(NT+1, i+1)):
# front
if j == 0:
if i != NS-1:
if T[0] == s:
dp[i+1][1] = (dp[i+1][1] + dp[i][0] + min(i, NS-NT))%mod
else:
dp[i+1][-1] = (dp[i+1][-1] + dp[i][0])%mod
elif j == NT:
dp[i+1][j] = (dp[i+1][j] + dp[i][j])%mod
else:
if i != NS-1:
if s == T[j]:
dp[i+1][j+1] = (dp[i+1][j+1] + dp[i][j])%mod
else:
dp[i + 1][-1] = (dp[i + 1][-1] + dp[i][j]) % mod
# back
k = NS - (i-j) - 1
if k >= NT:
if i != NS-1:
dp[i+1][j] = (dp[i+1][j] + dp[i][j])%mod
else:
dp[i + 1][-1] = (dp[i + 1][-1] + dp[i][j]) % mod
else:
if T[k] == s:
if i != NS-1:
dp[i + 1][j] = (dp[i + 1][j] + dp[i][j]) % mod
else:
dp[i + 1][-1] = (dp[i + 1][-1] + dp[i][j]) % mod
print(dp[-1][-1])
#[print(i, dp[i]) for i in range(NS+1)]
if __name__ == '__main__':
main()
``` | instruction | 0 | 54,930 | 0 | 109,860 |
No | output | 1 | 54,930 | 0 | 109,861 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Arkady's code contains n variables. Each variable has a unique name consisting of lowercase English letters only. One day Arkady decided to shorten his code.
He wants to replace each variable name with its non-empty prefix so that these new names are still unique (however, a new name of some variable can coincide with some old name of another or same variable). Among such possibilities he wants to find the way with the smallest possible total length of the new names.
A string a is a prefix of a string b if you can delete some (possibly none) characters from the end of b and obtain a.
Please find this minimum possible total length of new names.
Input
The first line contains a single integer n (1 ≤ n ≤ 10^5) — the number of variables.
The next n lines contain variable names, one per line. Each name is non-empty and contains only lowercase English letters. The total length of these strings is not greater than 10^5. The variable names are distinct.
Output
Print a single integer — the minimum possible total length of new variable names.
Examples
Input
3
codeforces
codehorses
code
Output
6
Input
5
abba
abb
ab
aa
aacada
Output
11
Input
3
telegram
digital
resistance
Output
3
Note
In the first example one of the best options is to shorten the names in the given order as "cod", "co", "c".
In the second example we can shorten the last name to "aac" and the first name to "a" without changing the other names.
Submitted Solution:
```
from sys import stdin,stdout
n=int(input())
a=stdin.readlines()
b={}
d={}
for i in range(len(a)):
b[a[i]]=len(a[i])-1
xx=list(set(sorted(b.values())))
aaa=[]
t=0
answer=0
for i in range(len(xx)):
for key, value in b.items():
if xx[i] == value:
aaa.append(key)
for i in range(len(aaa)):
ccc=aaa[i]
for j in range(1,len(ccc)):
try:
d[ccc[:j]]==1
except:
d[ccc[:j]]=1
answer+=j
break
print(answer)
``` | instruction | 0 | 55,372 | 0 | 110,744 |
No | output | 1 | 55,372 | 0 | 110,745 |
Provide a correct Python 3 solution for this coding contest problem.
Takahashi has a string S of length N consisting of digits from `0` through `9`.
He loves the prime number P. He wants to know how many non-empty (contiguous) substrings of S - there are N \times (N + 1) / 2 of them - are divisible by P when regarded as integers written in base ten.
Here substrings starting with a `0` also count, and substrings originated from different positions in S are distinguished, even if they are equal as strings or integers.
Compute this count to help Takahashi.
Constraints
* 1 \leq N \leq 2 \times 10^5
* S consists of digits.
* |S| = N
* 2 \leq P \leq 10000
* P is a prime number.
Input
Input is given from Standard Input in the following format:
N P
S
Output
Print the number of non-empty (contiguous) substrings of S that are divisible by P when regarded as an integer written in base ten.
Examples
Input
4 3
3543
Output
6
Input
4 2
2020
Output
10
Input
20 11
33883322005544116655
Output
68 | instruction | 0 | 55,390 | 0 | 110,780 |
"Correct Solution:
```
N, P = map(int, input().split())
S = input()
total = 0
if P == 2 or P == 5:
for i, s in enumerate(S):
if int(s) % P == 0:
total += i + 1
else:
counts = [0] * P
counts[0] = 1
h = 0
d = 1
for s in reversed(S):
m = int(s) * d % P
h = (h + m) % P
total += counts[h]
counts[h] += 1
d = (d * 10) % P
#print(counts)
print(total)
``` | output | 1 | 55,390 | 0 | 110,781 |
Provide a correct Python 3 solution for this coding contest problem.
Takahashi has a string S of length N consisting of digits from `0` through `9`.
He loves the prime number P. He wants to know how many non-empty (contiguous) substrings of S - there are N \times (N + 1) / 2 of them - are divisible by P when regarded as integers written in base ten.
Here substrings starting with a `0` also count, and substrings originated from different positions in S are distinguished, even if they are equal as strings or integers.
Compute this count to help Takahashi.
Constraints
* 1 \leq N \leq 2 \times 10^5
* S consists of digits.
* |S| = N
* 2 \leq P \leq 10000
* P is a prime number.
Input
Input is given from Standard Input in the following format:
N P
S
Output
Print the number of non-empty (contiguous) substrings of S that are divisible by P when regarded as an integer written in base ten.
Examples
Input
4 3
3543
Output
6
Input
4 2
2020
Output
10
Input
20 11
33883322005544116655
Output
68 | instruction | 0 | 55,391 | 0 | 110,782 |
"Correct Solution:
```
N, P = map(int, input().split())
S = input()
U = [0]*P
ans = 0
if P == 2 or P == 5:
for i in range(0, N):
if int(S[i])%P == 0:
ans += i+1
print (ans)
else:
t, s = 0, 1
for i in range(N-1, -1, -1):
t = (int(S[i])*s+t)%P
U[t] += 1
s = s*10%P
for u in U:
ans += u*(u-1)//2
ans += U[0]
print (ans)
``` | output | 1 | 55,391 | 0 | 110,783 |
Provide a correct Python 3 solution for this coding contest problem.
Takahashi has a string S of length N consisting of digits from `0` through `9`.
He loves the prime number P. He wants to know how many non-empty (contiguous) substrings of S - there are N \times (N + 1) / 2 of them - are divisible by P when regarded as integers written in base ten.
Here substrings starting with a `0` also count, and substrings originated from different positions in S are distinguished, even if they are equal as strings or integers.
Compute this count to help Takahashi.
Constraints
* 1 \leq N \leq 2 \times 10^5
* S consists of digits.
* |S| = N
* 2 \leq P \leq 10000
* P is a prime number.
Input
Input is given from Standard Input in the following format:
N P
S
Output
Print the number of non-empty (contiguous) substrings of S that are divisible by P when regarded as an integer written in base ten.
Examples
Input
4 3
3543
Output
6
Input
4 2
2020
Output
10
Input
20 11
33883322005544116655
Output
68 | instruction | 0 | 55,392 | 0 | 110,784 |
"Correct Solution:
```
N,P=map(int,input().split());S,a,i,j,c=list(map(int,input())),0,0,1,[1]+[0]*P
if 10%P:
for v in S[::-1]:i=(i+v*j)%P;j=j*10%P;a+=c[i];c[i]+=1
else:
for i,v in enumerate(S):
if v%P<1:a+=i+1
print(a)
``` | output | 1 | 55,392 | 0 | 110,785 |
Provide a correct Python 3 solution for this coding contest problem.
Takahashi has a string S of length N consisting of digits from `0` through `9`.
He loves the prime number P. He wants to know how many non-empty (contiguous) substrings of S - there are N \times (N + 1) / 2 of them - are divisible by P when regarded as integers written in base ten.
Here substrings starting with a `0` also count, and substrings originated from different positions in S are distinguished, even if they are equal as strings or integers.
Compute this count to help Takahashi.
Constraints
* 1 \leq N \leq 2 \times 10^5
* S consists of digits.
* |S| = N
* 2 \leq P \leq 10000
* P is a prime number.
Input
Input is given from Standard Input in the following format:
N P
S
Output
Print the number of non-empty (contiguous) substrings of S that are divisible by P when regarded as an integer written in base ten.
Examples
Input
4 3
3543
Output
6
Input
4 2
2020
Output
10
Input
20 11
33883322005544116655
Output
68 | instruction | 0 | 55,393 | 0 | 110,786 |
"Correct Solution:
```
p = int(input().split()[1])
s = input()
if 10 % p == 0:
r = sum(i for i, x in enumerate(s, 1) if int(x) % p == 0)
else:
d = [1] + [0] * (p - 1)
t, y = 0, 1
for x in reversed(s):
t = (t + int(x) * y) % p
d[t] += 1
y = y * 10 % p;
r = sum(i * i - i for i in d) // 2
print(r)
``` | output | 1 | 55,393 | 0 | 110,787 |
Provide a correct Python 3 solution for this coding contest problem.
Takahashi has a string S of length N consisting of digits from `0` through `9`.
He loves the prime number P. He wants to know how many non-empty (contiguous) substrings of S - there are N \times (N + 1) / 2 of them - are divisible by P when regarded as integers written in base ten.
Here substrings starting with a `0` also count, and substrings originated from different positions in S are distinguished, even if they are equal as strings or integers.
Compute this count to help Takahashi.
Constraints
* 1 \leq N \leq 2 \times 10^5
* S consists of digits.
* |S| = N
* 2 \leq P \leq 10000
* P is a prime number.
Input
Input is given from Standard Input in the following format:
N P
S
Output
Print the number of non-empty (contiguous) substrings of S that are divisible by P when regarded as an integer written in base ten.
Examples
Input
4 3
3543
Output
6
Input
4 2
2020
Output
10
Input
20 11
33883322005544116655
Output
68 | instruction | 0 | 55,394 | 0 | 110,788 |
"Correct Solution:
```
n,p=map(int,input().split())
S=input()[::-1]
ans=0
if p==2:
for i,s in enumerate(S):
if int(s)%2==0:
ans+=(n-i)
print(ans)
exit()
if p==5:
for i,s in enumerate(S):
if int(s)==0 or int(s)==5:
ans+=(n-i)
print(ans)
exit()
sd=0
d=1
count=[0]*(p+1)
count[0]+=1
for s in S:
sd+=int(s)*d
d*=10
sd%=p
d%=p
count[sd]+=1
for cnt in count:
ans+=cnt*(cnt-1)//2
print(ans)
``` | output | 1 | 55,394 | 0 | 110,789 |
Provide a correct Python 3 solution for this coding contest problem.
Takahashi has a string S of length N consisting of digits from `0` through `9`.
He loves the prime number P. He wants to know how many non-empty (contiguous) substrings of S - there are N \times (N + 1) / 2 of them - are divisible by P when regarded as integers written in base ten.
Here substrings starting with a `0` also count, and substrings originated from different positions in S are distinguished, even if they are equal as strings or integers.
Compute this count to help Takahashi.
Constraints
* 1 \leq N \leq 2 \times 10^5
* S consists of digits.
* |S| = N
* 2 \leq P \leq 10000
* P is a prime number.
Input
Input is given from Standard Input in the following format:
N P
S
Output
Print the number of non-empty (contiguous) substrings of S that are divisible by P when regarded as an integer written in base ten.
Examples
Input
4 3
3543
Output
6
Input
4 2
2020
Output
10
Input
20 11
33883322005544116655
Output
68 | instruction | 0 | 55,395 | 0 | 110,790 |
"Correct Solution:
```
from collections import Counter
N, P = map(int, input().split())
S = input()
cnt = 0
if P in [2, 5]:
for i, s in enumerate(S):
if int(s) % P == 0:
cnt += (i + 1)
else:
T = [0] * (N + 1)
mods = Counter({0: 1})
for i, s in enumerate(reversed(S)):
T[N - 1 - i] = (T[N - i] + int(s) * pow(10, i, P)) % P
mods[T[N - 1 - i]] += 1
for t in T:
mods[t] -= 1
cnt += mods[t]
print(cnt)
``` | output | 1 | 55,395 | 0 | 110,791 |
Provide a correct Python 3 solution for this coding contest problem.
Takahashi has a string S of length N consisting of digits from `0` through `9`.
He loves the prime number P. He wants to know how many non-empty (contiguous) substrings of S - there are N \times (N + 1) / 2 of them - are divisible by P when regarded as integers written in base ten.
Here substrings starting with a `0` also count, and substrings originated from different positions in S are distinguished, even if they are equal as strings or integers.
Compute this count to help Takahashi.
Constraints
* 1 \leq N \leq 2 \times 10^5
* S consists of digits.
* |S| = N
* 2 \leq P \leq 10000
* P is a prime number.
Input
Input is given from Standard Input in the following format:
N P
S
Output
Print the number of non-empty (contiguous) substrings of S that are divisible by P when regarded as an integer written in base ten.
Examples
Input
4 3
3543
Output
6
Input
4 2
2020
Output
10
Input
20 11
33883322005544116655
Output
68 | instruction | 0 | 55,396 | 0 | 110,792 |
"Correct Solution:
```
n, p = map(int, input().split())
s = list(map(int, list(input())))[::-1]
div = [0 for _ in range(p)]
su = 0
for i in range(n):
su = (su + s[i] * pow(10, i, p)) % p
div[su] += 1
cnt = 0
if p in [2, 5]:
if p == 2:
ok = [0, 2, 4, 6, 8]
else:
ok = [0, 5]
for i in range(len(s)):
if s[i] in ok:
cnt += n - i
else:
for i in range(len(div)):
x = div[i]
if i == 0:
y = x * (x + 1) // 2
else:
y = x * (x - 1) // 2
cnt += y
print(cnt)
``` | output | 1 | 55,396 | 0 | 110,793 |
Provide a correct Python 3 solution for this coding contest problem.
Takahashi has a string S of length N consisting of digits from `0` through `9`.
He loves the prime number P. He wants to know how many non-empty (contiguous) substrings of S - there are N \times (N + 1) / 2 of them - are divisible by P when regarded as integers written in base ten.
Here substrings starting with a `0` also count, and substrings originated from different positions in S are distinguished, even if they are equal as strings or integers.
Compute this count to help Takahashi.
Constraints
* 1 \leq N \leq 2 \times 10^5
* S consists of digits.
* |S| = N
* 2 \leq P \leq 10000
* P is a prime number.
Input
Input is given from Standard Input in the following format:
N P
S
Output
Print the number of non-empty (contiguous) substrings of S that are divisible by P when regarded as an integer written in base ten.
Examples
Input
4 3
3543
Output
6
Input
4 2
2020
Output
10
Input
20 11
33883322005544116655
Output
68 | instruction | 0 | 55,397 | 0 | 110,794 |
"Correct Solution:
```
# E - Divisible Substring
N,P = map(int,input().split())
S = input()
ans = 0
if P==2 or P==5:
for i in range(N):
if int(S[i])%P==0:
ans += i+1
else:
l = [1]+[0]*(P-1)
tmp = 0
r10 = 1
for i in range(N-1,-1,-1):
tmp = (r10*int(S[i])+tmp)%P
l[tmp] += 1
r10 = (r10*10)%P
for x in l:
ans += x*(x-1)//2
print(ans)
``` | output | 1 | 55,397 | 0 | 110,795 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Takahashi has a string S of length N consisting of digits from `0` through `9`.
He loves the prime number P. He wants to know how many non-empty (contiguous) substrings of S - there are N \times (N + 1) / 2 of them - are divisible by P when regarded as integers written in base ten.
Here substrings starting with a `0` also count, and substrings originated from different positions in S are distinguished, even if they are equal as strings or integers.
Compute this count to help Takahashi.
Constraints
* 1 \leq N \leq 2 \times 10^5
* S consists of digits.
* |S| = N
* 2 \leq P \leq 10000
* P is a prime number.
Input
Input is given from Standard Input in the following format:
N P
S
Output
Print the number of non-empty (contiguous) substrings of S that are divisible by P when regarded as an integer written in base ten.
Examples
Input
4 3
3543
Output
6
Input
4 2
2020
Output
10
Input
20 11
33883322005544116655
Output
68
Submitted Solution:
```
import sys;input=sys.stdin.readline
N, P = map(int, input().split())
S=input().strip()
if P in {2, 5}:
r=0
for i in range(N):
if not int(S[i])%P:
r+=i+1
print(r)
else:
S = S[::-1]
r=0
from collections import defaultdict
d=defaultdict(int)
d[0] += 1
R=0
X=1
for i in range(N):
r += int(S[i])*X
R += d[r%P]
X = (X*10)%P
d[r%P]+=1
print(R)
``` | instruction | 0 | 55,399 | 0 | 110,798 |
Yes | output | 1 | 55,399 | 0 | 110,799 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Takahashi has a string S of length N consisting of digits from `0` through `9`.
He loves the prime number P. He wants to know how many non-empty (contiguous) substrings of S - there are N \times (N + 1) / 2 of them - are divisible by P when regarded as integers written in base ten.
Here substrings starting with a `0` also count, and substrings originated from different positions in S are distinguished, even if they are equal as strings or integers.
Compute this count to help Takahashi.
Constraints
* 1 \leq N \leq 2 \times 10^5
* S consists of digits.
* |S| = N
* 2 \leq P \leq 10000
* P is a prime number.
Input
Input is given from Standard Input in the following format:
N P
S
Output
Print the number of non-empty (contiguous) substrings of S that are divisible by P when regarded as an integer written in base ten.
Examples
Input
4 3
3543
Output
6
Input
4 2
2020
Output
10
Input
20 11
33883322005544116655
Output
68
Submitted Solution:
```
n,m=map(int,input().split());s=input();l=[0]*m;a,t,p=0,0,1
if 10%m:
for i in s[::-1]:l[t%m]+=1;t+=int(i)*p;a+=l[t%m];p=p*10%m
else:a=sum(i+1 for i in range(n) if int(s[i])%m<1)
print(a)
``` | instruction | 0 | 55,400 | 0 | 110,800 |
Yes | output | 1 | 55,400 | 0 | 110,801 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Takahashi has a string S of length N consisting of digits from `0` through `9`.
He loves the prime number P. He wants to know how many non-empty (contiguous) substrings of S - there are N \times (N + 1) / 2 of them - are divisible by P when regarded as integers written in base ten.
Here substrings starting with a `0` also count, and substrings originated from different positions in S are distinguished, even if they are equal as strings or integers.
Compute this count to help Takahashi.
Constraints
* 1 \leq N \leq 2 \times 10^5
* S consists of digits.
* |S| = N
* 2 \leq P \leq 10000
* P is a prime number.
Input
Input is given from Standard Input in the following format:
N P
S
Output
Print the number of non-empty (contiguous) substrings of S that are divisible by P when regarded as an integer written in base ten.
Examples
Input
4 3
3543
Output
6
Input
4 2
2020
Output
10
Input
20 11
33883322005544116655
Output
68
Submitted Solution:
```
n, p = [int(_) for _ in input().split()]
s = input()
if p == 2 or p == 5:
ans = 0
for i in range(n):
if int(s[i]) % p == 0:
ans += i+1
print(ans)
exit()
t = [0 for i in range(n+1)]
P = [0 for i in range(p)]
P[0] += 1
d = 1
for i in range(1, n+1):
t[i] = (t[i-1]+int(s[n-i])*d) % p
P[t[i]] += 1
d = d*10 % p
ans = 0
for c in P:
ans += c*(c-1)//2
# print(t)
print(ans)
``` | instruction | 0 | 55,401 | 0 | 110,802 |
Yes | output | 1 | 55,401 | 0 | 110,803 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Takahashi has a string S of length N consisting of digits from `0` through `9`.
He loves the prime number P. He wants to know how many non-empty (contiguous) substrings of S - there are N \times (N + 1) / 2 of them - are divisible by P when regarded as integers written in base ten.
Here substrings starting with a `0` also count, and substrings originated from different positions in S are distinguished, even if they are equal as strings or integers.
Compute this count to help Takahashi.
Constraints
* 1 \leq N \leq 2 \times 10^5
* S consists of digits.
* |S| = N
* 2 \leq P \leq 10000
* P is a prime number.
Input
Input is given from Standard Input in the following format:
N P
S
Output
Print the number of non-empty (contiguous) substrings of S that are divisible by P when regarded as an integer written in base ten.
Examples
Input
4 3
3543
Output
6
Input
4 2
2020
Output
10
Input
20 11
33883322005544116655
Output
68
Submitted Solution:
```
N,P = map(int, input().split())
S = input()
L = [0]*P
num = 0
for i in range(N-1, -1, -1):
num += int(S[i])*pow(10, N-1-i, P)
num %= P
L[num] += 1
ans = L[0]
for i in range(P):
ans += L[i]*(L[i]-1)//2
print(ans)
``` | instruction | 0 | 55,402 | 0 | 110,804 |
No | output | 1 | 55,402 | 0 | 110,805 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Takahashi has a string S of length N consisting of digits from `0` through `9`.
He loves the prime number P. He wants to know how many non-empty (contiguous) substrings of S - there are N \times (N + 1) / 2 of them - are divisible by P when regarded as integers written in base ten.
Here substrings starting with a `0` also count, and substrings originated from different positions in S are distinguished, even if they are equal as strings or integers.
Compute this count to help Takahashi.
Constraints
* 1 \leq N \leq 2 \times 10^5
* S consists of digits.
* |S| = N
* 2 \leq P \leq 10000
* P is a prime number.
Input
Input is given from Standard Input in the following format:
N P
S
Output
Print the number of non-empty (contiguous) substrings of S that are divisible by P when regarded as an integer written in base ten.
Examples
Input
4 3
3543
Output
6
Input
4 2
2020
Output
10
Input
20 11
33883322005544116655
Output
68
Submitted Solution:
```
N,P = list(map(lambda x:int(x),input().split(" ")))
S = input()
count=0
store=[0]*P
if P in [2,5]:
for i in range(N):
if int(S[i])%P==0:
count+=(i+1)
print(count)
else:
for i in range(N):
num = int(S[i:])
store[num%P]+=1
for i in range(P):
count += store[i]*(store[i]-1)/2
count += store[0]
#print(store)
print(int(count))
``` | instruction | 0 | 55,403 | 0 | 110,806 |
No | output | 1 | 55,403 | 0 | 110,807 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Takahashi has a string S of length N consisting of digits from `0` through `9`.
He loves the prime number P. He wants to know how many non-empty (contiguous) substrings of S - there are N \times (N + 1) / 2 of them - are divisible by P when regarded as integers written in base ten.
Here substrings starting with a `0` also count, and substrings originated from different positions in S are distinguished, even if they are equal as strings or integers.
Compute this count to help Takahashi.
Constraints
* 1 \leq N \leq 2 \times 10^5
* S consists of digits.
* |S| = N
* 2 \leq P \leq 10000
* P is a prime number.
Input
Input is given from Standard Input in the following format:
N P
S
Output
Print the number of non-empty (contiguous) substrings of S that are divisible by P when regarded as an integer written in base ten.
Examples
Input
4 3
3543
Output
6
Input
4 2
2020
Output
10
Input
20 11
33883322005544116655
Output
68
Submitted Solution:
```
a = input().split(" ")
a[1] = int(a[1])
num = input()
k = [0]
flag = 1
count_k = [0]
for i in range(int(a[0])):
for p in range(len(k)):
s = num[k[p]:(i+1)]
if(int(s) % a[1] == 0):
count_k[p] += 1
flag = 0
for j in range(k[p], i+1):
if(int(num[j:(i+1)]) % a[1] == 0):
k[p] = j
if(flag == 1):
for j in range(i+1):
s = num[j:(i+1)]
if(int(s) % a[1] == 0):
k.append(1)
count_k.append(1)
flag = 1
count = 0
for i in count_k:
count += i * (i+1) / 2
print(int(count))
``` | instruction | 0 | 55,405 | 0 | 110,810 |
No | output | 1 | 55,405 | 0 | 110,811 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given two strings s and t consisting of lowercase Latin letters. Also you have a string z which is initially empty. You want string z to be equal to string t. You can perform the following operation to achieve this: append any subsequence of s at the end of string z. A subsequence is a sequence that can be derived from the given sequence by deleting zero or more elements without changing the order of the remaining elements. For example, if z = ac, s = abcde, you may turn z into following strings in one operation:
1. z = acace (if we choose subsequence ace);
2. z = acbcd (if we choose subsequence bcd);
3. z = acbce (if we choose subsequence bce).
Note that after this operation string s doesn't change.
Calculate the minimum number of such operations to turn string z into string t.
Input
The first line contains the integer T (1 ≤ T ≤ 100) — the number of test cases.
The first line of each testcase contains one string s (1 ≤ |s| ≤ 10^5) consisting of lowercase Latin letters.
The second line of each testcase contains one string t (1 ≤ |t| ≤ 10^5) consisting of lowercase Latin letters.
It is guaranteed that the total length of all strings s and t in the input does not exceed 2 ⋅ 10^5.
Output
For each testcase, print one integer — the minimum number of operations to turn string z into string t. If it's impossible print -1.
Example
Input
3
aabce
ace
abacaba
aax
ty
yyt
Output
1
-1
3 | instruction | 0 | 55,716 | 0 | 111,432 |
Tags: dp, greedy, strings
Correct Solution:
```
import math,string,itertools,fractions,heapq,collections,re,array,bisect,copy
cases = int(input().strip())
for case in range(cases):
s = list(input().strip())
t = list(input().strip())
ss = set(s)
tt = list(set(t))
can = True
for i in range(len(tt)):
if not tt[i] in ss:
can = False
if not can:
print(-1)
else:
n = len(s)
nxt = [{} for i in range(n)]
for i in range(n - 1, -1, -1):
if i + 1 < n:
for (k, v) in nxt[i + 1].items():
nxt[i][k] = v
nxt[i][s[i]] = i
ans = 1
pos = 0
for i in range(len(t)):
if pos >= n or not(t[i] in nxt[pos]):
pos = 0
ans += 1
pos = nxt[pos][t[i]] + 1
print(ans)
``` | output | 1 | 55,716 | 0 | 111,433 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given two strings s and t consisting of lowercase Latin letters. Also you have a string z which is initially empty. You want string z to be equal to string t. You can perform the following operation to achieve this: append any subsequence of s at the end of string z. A subsequence is a sequence that can be derived from the given sequence by deleting zero or more elements without changing the order of the remaining elements. For example, if z = ac, s = abcde, you may turn z into following strings in one operation:
1. z = acace (if we choose subsequence ace);
2. z = acbcd (if we choose subsequence bcd);
3. z = acbce (if we choose subsequence bce).
Note that after this operation string s doesn't change.
Calculate the minimum number of such operations to turn string z into string t.
Input
The first line contains the integer T (1 ≤ T ≤ 100) — the number of test cases.
The first line of each testcase contains one string s (1 ≤ |s| ≤ 10^5) consisting of lowercase Latin letters.
The second line of each testcase contains one string t (1 ≤ |t| ≤ 10^5) consisting of lowercase Latin letters.
It is guaranteed that the total length of all strings s and t in the input does not exceed 2 ⋅ 10^5.
Output
For each testcase, print one integer — the minimum number of operations to turn string z into string t. If it's impossible print -1.
Example
Input
3
aabce
ace
abacaba
aax
ty
yyt
Output
1
-1
3 | instruction | 0 | 55,717 | 0 | 111,434 |
Tags: dp, greedy, strings
Correct Solution:
```
from sys import stdin
from bisect import bisect
t = int(stdin.readline())
for i in range(t):
s = stdin.readline().strip()
t = stdin.readline().strip()
if not set(t) <= set(s):
print(-1)
continue
p = [[] for i in range(26)]
for i, c in enumerate(s):
j = ord(c) - ord("a")
p[j].append(i)
# print(p)
x = 0
ops = 0
while x < len(t):
# print("x = ", x)
k = -1
while x < len(t):
c = ord(t[x]) - ord("a")
idx = bisect(p[c], k)
if idx == len(p[c]):
break
k = p[c][idx]
x += 1
ops += 1
print(ops)
``` | output | 1 | 55,717 | 0 | 111,435 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given two strings s and t consisting of lowercase Latin letters. Also you have a string z which is initially empty. You want string z to be equal to string t. You can perform the following operation to achieve this: append any subsequence of s at the end of string z. A subsequence is a sequence that can be derived from the given sequence by deleting zero or more elements without changing the order of the remaining elements. For example, if z = ac, s = abcde, you may turn z into following strings in one operation:
1. z = acace (if we choose subsequence ace);
2. z = acbcd (if we choose subsequence bcd);
3. z = acbce (if we choose subsequence bce).
Note that after this operation string s doesn't change.
Calculate the minimum number of such operations to turn string z into string t.
Input
The first line contains the integer T (1 ≤ T ≤ 100) — the number of test cases.
The first line of each testcase contains one string s (1 ≤ |s| ≤ 10^5) consisting of lowercase Latin letters.
The second line of each testcase contains one string t (1 ≤ |t| ≤ 10^5) consisting of lowercase Latin letters.
It is guaranteed that the total length of all strings s and t in the input does not exceed 2 ⋅ 10^5.
Output
For each testcase, print one integer — the minimum number of operations to turn string z into string t. If it's impossible print -1.
Example
Input
3
aabce
ace
abacaba
aax
ty
yyt
Output
1
-1
3 | instruction | 0 | 55,718 | 0 | 111,436 |
Tags: dp, greedy, strings
Correct Solution:
```
from bisect import bisect_right
for _ in range(int(input())) :
s = input()
t = input()
pre = {i : [] for i in range(26)}; a = ord('a')
for i in range(len(s)) :
pre[ord(s[i]) - a].append(i)
ans = 1; last = -1
for i in t :
n = ord(i) - a
if pre[n] == [] :
ans = -1
break
else :
w = bisect_right(pre[n], last)
if w >= len(pre[n]) :
ans += 1
last = pre[n][0]
else :
last = pre[n][w]
print(ans)
``` | output | 1 | 55,718 | 0 | 111,437 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given two strings s and t consisting of lowercase Latin letters. Also you have a string z which is initially empty. You want string z to be equal to string t. You can perform the following operation to achieve this: append any subsequence of s at the end of string z. A subsequence is a sequence that can be derived from the given sequence by deleting zero or more elements without changing the order of the remaining elements. For example, if z = ac, s = abcde, you may turn z into following strings in one operation:
1. z = acace (if we choose subsequence ace);
2. z = acbcd (if we choose subsequence bcd);
3. z = acbce (if we choose subsequence bce).
Note that after this operation string s doesn't change.
Calculate the minimum number of such operations to turn string z into string t.
Input
The first line contains the integer T (1 ≤ T ≤ 100) — the number of test cases.
The first line of each testcase contains one string s (1 ≤ |s| ≤ 10^5) consisting of lowercase Latin letters.
The second line of each testcase contains one string t (1 ≤ |t| ≤ 10^5) consisting of lowercase Latin letters.
It is guaranteed that the total length of all strings s and t in the input does not exceed 2 ⋅ 10^5.
Output
For each testcase, print one integer — the minimum number of operations to turn string z into string t. If it's impossible print -1.
Example
Input
3
aabce
ace
abacaba
aax
ty
yyt
Output
1
-1
3 | instruction | 0 | 55,719 | 0 | 111,438 |
Tags: dp, greedy, strings
Correct Solution:
```
import bisect,sys
input = sys.stdin.readline
t = int(input())
for testcase in range(t):
s = list(input())
t = list(input())
idx = [[] for i in range(30)]
for i in range(len(s)-1):
s[i] = ord(s[i])
idx[s[i]-97].append(i)
now = -1
res = 1
for i in range(len(t)-1):
p = ord(t[i])-97
if len(idx[p]) == 0:
res = -1
break
k = bisect.bisect_right(idx[p],now)
if k == len(idx[p]):
res += 1
now = idx[p][0]
else:
now = idx[p][k]
print(res)
``` | output | 1 | 55,719 | 0 | 111,439 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given two strings s and t consisting of lowercase Latin letters. Also you have a string z which is initially empty. You want string z to be equal to string t. You can perform the following operation to achieve this: append any subsequence of s at the end of string z. A subsequence is a sequence that can be derived from the given sequence by deleting zero or more elements without changing the order of the remaining elements. For example, if z = ac, s = abcde, you may turn z into following strings in one operation:
1. z = acace (if we choose subsequence ace);
2. z = acbcd (if we choose subsequence bcd);
3. z = acbce (if we choose subsequence bce).
Note that after this operation string s doesn't change.
Calculate the minimum number of such operations to turn string z into string t.
Input
The first line contains the integer T (1 ≤ T ≤ 100) — the number of test cases.
The first line of each testcase contains one string s (1 ≤ |s| ≤ 10^5) consisting of lowercase Latin letters.
The second line of each testcase contains one string t (1 ≤ |t| ≤ 10^5) consisting of lowercase Latin letters.
It is guaranteed that the total length of all strings s and t in the input does not exceed 2 ⋅ 10^5.
Output
For each testcase, print one integer — the minimum number of operations to turn string z into string t. If it's impossible print -1.
Example
Input
3
aabce
ace
abacaba
aax
ty
yyt
Output
1
-1
3 | instruction | 0 | 55,720 | 0 | 111,440 |
Tags: dp, greedy, strings
Correct Solution:
```
from bisect import bisect_right
def solve(s, t):
pos = [[] for _ in range(26)]
for i, c in enumerate(s):
x = ord(c) - ord('a')
pos[x].append(i)
cur = -1
ans = 1
for i, c in enumerate(t):
x = ord(c) - ord('a')
if pos[x] == []:
print(-1)
return
it = bisect_right(pos[x], cur)
if it == len(pos[x]):
it = 0
ans += 1
cur = pos[x][it]
print(ans)
def main():
tc = int(input())
for _ in range(tc):
s = input()
t = input()
solve(s, t)
if __name__ == "__main__":
main()
``` | output | 1 | 55,720 | 0 | 111,441 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given two strings s and t consisting of lowercase Latin letters. Also you have a string z which is initially empty. You want string z to be equal to string t. You can perform the following operation to achieve this: append any subsequence of s at the end of string z. A subsequence is a sequence that can be derived from the given sequence by deleting zero or more elements without changing the order of the remaining elements. For example, if z = ac, s = abcde, you may turn z into following strings in one operation:
1. z = acace (if we choose subsequence ace);
2. z = acbcd (if we choose subsequence bcd);
3. z = acbce (if we choose subsequence bce).
Note that after this operation string s doesn't change.
Calculate the minimum number of such operations to turn string z into string t.
Input
The first line contains the integer T (1 ≤ T ≤ 100) — the number of test cases.
The first line of each testcase contains one string s (1 ≤ |s| ≤ 10^5) consisting of lowercase Latin letters.
The second line of each testcase contains one string t (1 ≤ |t| ≤ 10^5) consisting of lowercase Latin letters.
It is guaranteed that the total length of all strings s and t in the input does not exceed 2 ⋅ 10^5.
Output
For each testcase, print one integer — the minimum number of operations to turn string z into string t. If it's impossible print -1.
Example
Input
3
aabce
ace
abacaba
aax
ty
yyt
Output
1
-1
3 | instruction | 0 | 55,721 | 0 | 111,442 |
Tags: dp, greedy, strings
Correct Solution:
```
import bisect
t = int(input())
for _ in range(t):
s=input()
t=input()
f=[list() for _ in range(26)]
orda=ord('a')
for i in range(len(s)):
f[ord(s[i])-orda].append(i)
ans=0
idx=10**9
for i in range(len(t)):
search=ord(t[i])-orda
if f[search] == list():
ans=-1
break
nidx=bisect.bisect_right(f[search], idx)
if nidx<len(f[search]):
idx = f[search][nidx]
else:
ans+=1
idx=f[search][0]
print(ans)
``` | output | 1 | 55,721 | 0 | 111,443 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given two strings s and t consisting of lowercase Latin letters. Also you have a string z which is initially empty. You want string z to be equal to string t. You can perform the following operation to achieve this: append any subsequence of s at the end of string z. A subsequence is a sequence that can be derived from the given sequence by deleting zero or more elements without changing the order of the remaining elements. For example, if z = ac, s = abcde, you may turn z into following strings in one operation:
1. z = acace (if we choose subsequence ace);
2. z = acbcd (if we choose subsequence bcd);
3. z = acbce (if we choose subsequence bce).
Note that after this operation string s doesn't change.
Calculate the minimum number of such operations to turn string z into string t.
Input
The first line contains the integer T (1 ≤ T ≤ 100) — the number of test cases.
The first line of each testcase contains one string s (1 ≤ |s| ≤ 10^5) consisting of lowercase Latin letters.
The second line of each testcase contains one string t (1 ≤ |t| ≤ 10^5) consisting of lowercase Latin letters.
It is guaranteed that the total length of all strings s and t in the input does not exceed 2 ⋅ 10^5.
Output
For each testcase, print one integer — the minimum number of operations to turn string z into string t. If it's impossible print -1.
Example
Input
3
aabce
ace
abacaba
aax
ty
yyt
Output
1
-1
3 | instruction | 0 | 55,722 | 0 | 111,444 |
Tags: dp, greedy, strings
Correct Solution:
```
import sys
from bisect import bisect_left
from collections import defaultdict
for _ in range(int(input())):
s = input()
t = input()
inds = defaultdict(list)
for i in range(len(s)):
inds[s[i]].append(i)
cnt = 1
ti = 0
si = 0
for ti in range(len(t)):
if t[ti] not in inds:
print(-1)
break
ci = bisect_left(inds[t[ti]], si)
if ci != len(inds[t[ti]]):
si = inds[t[ti]][ci] + 1
else:
si = inds[t[ti]][0] + 1
cnt += 1
else:
print(cnt)
``` | output | 1 | 55,722 | 0 | 111,445 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given two strings s and t consisting of lowercase Latin letters. Also you have a string z which is initially empty. You want string z to be equal to string t. You can perform the following operation to achieve this: append any subsequence of s at the end of string z. A subsequence is a sequence that can be derived from the given sequence by deleting zero or more elements without changing the order of the remaining elements. For example, if z = ac, s = abcde, you may turn z into following strings in one operation:
1. z = acace (if we choose subsequence ace);
2. z = acbcd (if we choose subsequence bcd);
3. z = acbce (if we choose subsequence bce).
Note that after this operation string s doesn't change.
Calculate the minimum number of such operations to turn string z into string t.
Input
The first line contains the integer T (1 ≤ T ≤ 100) — the number of test cases.
The first line of each testcase contains one string s (1 ≤ |s| ≤ 10^5) consisting of lowercase Latin letters.
The second line of each testcase contains one string t (1 ≤ |t| ≤ 10^5) consisting of lowercase Latin letters.
It is guaranteed that the total length of all strings s and t in the input does not exceed 2 ⋅ 10^5.
Output
For each testcase, print one integer — the minimum number of operations to turn string z into string t. If it's impossible print -1.
Example
Input
3
aabce
ace
abacaba
aax
ty
yyt
Output
1
-1
3 | instruction | 0 | 55,723 | 0 | 111,446 |
Tags: dp, greedy, strings
Correct Solution:
```
from bisect import bisect_left
t = int(input())
for _ in range(t):
s = input()
t = input()
d = {}
for i in range(len(s)):
if s[i] not in d:
d[s[i]] = []
d[s[i]].append(i)
ans = 1
j = 0
for i in range(len(t)):
if t[i] not in d:
print(-1)
break
nxt = bisect_left(d[t[i]], j)
if nxt != len(d[t[i]]):
j = d[t[i]][nxt] + 1
else:
j = d[t[i]][0] + 1
ans += 1
else:
print(ans)
``` | output | 1 | 55,723 | 0 | 111,447 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given two strings s and t consisting of lowercase Latin letters. Also you have a string z which is initially empty. You want string z to be equal to string t. You can perform the following operation to achieve this: append any subsequence of s at the end of string z. A subsequence is a sequence that can be derived from the given sequence by deleting zero or more elements without changing the order of the remaining elements. For example, if z = ac, s = abcde, you may turn z into following strings in one operation:
1. z = acace (if we choose subsequence ace);
2. z = acbcd (if we choose subsequence bcd);
3. z = acbce (if we choose subsequence bce).
Note that after this operation string s doesn't change.
Calculate the minimum number of such operations to turn string z into string t.
Input
The first line contains the integer T (1 ≤ T ≤ 100) — the number of test cases.
The first line of each testcase contains one string s (1 ≤ |s| ≤ 10^5) consisting of lowercase Latin letters.
The second line of each testcase contains one string t (1 ≤ |t| ≤ 10^5) consisting of lowercase Latin letters.
It is guaranteed that the total length of all strings s and t in the input does not exceed 2 ⋅ 10^5.
Output
For each testcase, print one integer — the minimum number of operations to turn string z into string t. If it's impossible print -1.
Example
Input
3
aabce
ace
abacaba
aax
ty
yyt
Output
1
-1
3
Submitted Solution:
```
import sys, bisect; input = sys.stdin.readline; t = int(input())
while t:
t-=1; s1 = input().strip(); s2 = input().strip(); locations = {}
for i in range(len(s1)):
if s1[i] in locations: locations[s1[i]].append(i)
else: locations[s1[i]] = [i]
a = i = len(s1);j = len(s2)-1; ans = 1
while j>=0:
if s2[j] not in locations: ans = -1; break
i = bisect.bisect_right(locations[s2[j]], i)-1
if i<0: i = a; ans += 1
else: i = locations[s2[j]][i]-1; j-=1
print(ans)
``` | instruction | 0 | 55,724 | 0 | 111,448 |
Yes | output | 1 | 55,724 | 0 | 111,449 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given two strings s and t consisting of lowercase Latin letters. Also you have a string z which is initially empty. You want string z to be equal to string t. You can perform the following operation to achieve this: append any subsequence of s at the end of string z. A subsequence is a sequence that can be derived from the given sequence by deleting zero or more elements without changing the order of the remaining elements. For example, if z = ac, s = abcde, you may turn z into following strings in one operation:
1. z = acace (if we choose subsequence ace);
2. z = acbcd (if we choose subsequence bcd);
3. z = acbce (if we choose subsequence bce).
Note that after this operation string s doesn't change.
Calculate the minimum number of such operations to turn string z into string t.
Input
The first line contains the integer T (1 ≤ T ≤ 100) — the number of test cases.
The first line of each testcase contains one string s (1 ≤ |s| ≤ 10^5) consisting of lowercase Latin letters.
The second line of each testcase contains one string t (1 ≤ |t| ≤ 10^5) consisting of lowercase Latin letters.
It is guaranteed that the total length of all strings s and t in the input does not exceed 2 ⋅ 10^5.
Output
For each testcase, print one integer — the minimum number of operations to turn string z into string t. If it's impossible print -1.
Example
Input
3
aabce
ace
abacaba
aax
ty
yyt
Output
1
-1
3
Submitted Solution:
```
def search_just_greater(arr, target):
if target >= arr[-1]:
return -1
low = 0
high = len(arr) - 1
while low < high:
mid = low + (high - low) // 2
if arr[mid] <= target:
low = mid + 1
else:
high = mid
# if arr[low] <= target:
# return -1
return low
if __name__ == "__main__":
for _ in range(int(input())):
s = list(input())
t = list(input())
positions = []
for i in range(26):
positions.append([])
for i in range(len(s)):
positions[ord(s[i]) - 97].append(i)
pointer = -1
bufferEmpty = True
ans = 0
for i in range(len(t)):
cur = ord(t[i]) - 97
if len(positions[cur]) == 0:
ans = -1
break
newptr = search_just_greater(positions[cur], pointer)
if newptr == -1:
ans += 1
newptr = search_just_greater(positions[cur], -1)
# else:
if i == len(t) - 1:
ans += 1
# break
pointer = positions[cur][newptr]
# if ans == -1:
# print(ans)
# continue
# # if not bufferEmpty:
# # ans += 1
print(ans)
``` | instruction | 0 | 55,725 | 0 | 111,450 |
Yes | output | 1 | 55,725 | 0 | 111,451 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given two strings s and t consisting of lowercase Latin letters. Also you have a string z which is initially empty. You want string z to be equal to string t. You can perform the following operation to achieve this: append any subsequence of s at the end of string z. A subsequence is a sequence that can be derived from the given sequence by deleting zero or more elements without changing the order of the remaining elements. For example, if z = ac, s = abcde, you may turn z into following strings in one operation:
1. z = acace (if we choose subsequence ace);
2. z = acbcd (if we choose subsequence bcd);
3. z = acbce (if we choose subsequence bce).
Note that after this operation string s doesn't change.
Calculate the minimum number of such operations to turn string z into string t.
Input
The first line contains the integer T (1 ≤ T ≤ 100) — the number of test cases.
The first line of each testcase contains one string s (1 ≤ |s| ≤ 10^5) consisting of lowercase Latin letters.
The second line of each testcase contains one string t (1 ≤ |t| ≤ 10^5) consisting of lowercase Latin letters.
It is guaranteed that the total length of all strings s and t in the input does not exceed 2 ⋅ 10^5.
Output
For each testcase, print one integer — the minimum number of operations to turn string z into string t. If it's impossible print -1.
Example
Input
3
aabce
ace
abacaba
aax
ty
yyt
Output
1
-1
3
Submitted Solution:
```
# from debug import debug
import sys
import bisect
# sys.setrecursionlimit(int(1e6))
input = sys.stdin.readline
# inf = int(1e10)
# recursion code....
# def rec(s1, s2, i, j, g):
# if j<0:
# return 1
# if i<0 and g == 0:
# return 0
# if i<0:
# i = len(s1)-1
# g = 0
# while i>=0 and j>=0:
# if s1[i] == s2[j]:
# j-=1
# g = 1
# i-=1
# val = rec(s1,s2,i,j,g)
# if val:
# return 1+val
# return 0
t = int(input())
while t:
t-=1
s1 = input().strip()
s2 = input().strip()
locations = {}
for i in range(len(s1)):
if s1[i] in locations:
locations[s1[i]].append(i)
else:
locations[s1[i]] = [i]
a,b = len(s1), len(s2)-1
i, j = a, b
g = 0
ans = 1
out = 0
while j>=0:
if s2[j] not in locations:
ans = -1
break
i = bisect.bisect_right(locations[s2[j]], i)-1
if i<0:
i = a
ans += 1
else:
i = locations[s2[j]][i]-1
j-=1
print(ans)
``` | instruction | 0 | 55,726 | 0 | 111,452 |
Yes | output | 1 | 55,726 | 0 | 111,453 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given two strings s and t consisting of lowercase Latin letters. Also you have a string z which is initially empty. You want string z to be equal to string t. You can perform the following operation to achieve this: append any subsequence of s at the end of string z. A subsequence is a sequence that can be derived from the given sequence by deleting zero or more elements without changing the order of the remaining elements. For example, if z = ac, s = abcde, you may turn z into following strings in one operation:
1. z = acace (if we choose subsequence ace);
2. z = acbcd (if we choose subsequence bcd);
3. z = acbce (if we choose subsequence bce).
Note that after this operation string s doesn't change.
Calculate the minimum number of such operations to turn string z into string t.
Input
The first line contains the integer T (1 ≤ T ≤ 100) — the number of test cases.
The first line of each testcase contains one string s (1 ≤ |s| ≤ 10^5) consisting of lowercase Latin letters.
The second line of each testcase contains one string t (1 ≤ |t| ≤ 10^5) consisting of lowercase Latin letters.
It is guaranteed that the total length of all strings s and t in the input does not exceed 2 ⋅ 10^5.
Output
For each testcase, print one integer — the minimum number of operations to turn string z into string t. If it's impossible print -1.
Example
Input
3
aabce
ace
abacaba
aax
ty
yyt
Output
1
-1
3
Submitted Solution:
```
import math
import bisect
from collections import defaultdict
for _ in range(int(input())):
s = input()
t = input()
n = len(s)
d = defaultdict(list)
ans = 1
for i in range(n):
d[s[i]].append(i)
k = 0
curr = -1
#print(d)
while(k != len(t)):
if len(d[t[k]]) == 0:
ans = -1
break
curr = bisect.bisect(d[t[k]],curr)
#print(curr)
if curr>= len(d[t[k]]):
curr = -1
ans += 1
else:
curr = d[t[k]][curr]
k += 1
#print(curr)
print(ans)
``` | instruction | 0 | 55,727 | 0 | 111,454 |
Yes | output | 1 | 55,727 | 0 | 111,455 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given two strings s and t consisting of lowercase Latin letters. Also you have a string z which is initially empty. You want string z to be equal to string t. You can perform the following operation to achieve this: append any subsequence of s at the end of string z. A subsequence is a sequence that can be derived from the given sequence by deleting zero or more elements without changing the order of the remaining elements. For example, if z = ac, s = abcde, you may turn z into following strings in one operation:
1. z = acace (if we choose subsequence ace);
2. z = acbcd (if we choose subsequence bcd);
3. z = acbce (if we choose subsequence bce).
Note that after this operation string s doesn't change.
Calculate the minimum number of such operations to turn string z into string t.
Input
The first line contains the integer T (1 ≤ T ≤ 100) — the number of test cases.
The first line of each testcase contains one string s (1 ≤ |s| ≤ 10^5) consisting of lowercase Latin letters.
The second line of each testcase contains one string t (1 ≤ |t| ≤ 10^5) consisting of lowercase Latin letters.
It is guaranteed that the total length of all strings s and t in the input does not exceed 2 ⋅ 10^5.
Output
For each testcase, print one integer — the minimum number of operations to turn string z into string t. If it's impossible print -1.
Example
Input
3
aabce
ace
abacaba
aax
ty
yyt
Output
1
-1
3
Submitted Solution:
```
import sys
import math
input = sys.stdin.readline
from functools import cmp_to_key;
def pi():
return(int(input()))
def pl():
return(int(input(), 16))
def ti():
return(list(map(int,input().split())))
def ts():
s = input()
return(list(s[:len(s) - 1]))
def invr():
return(map(int,input().split()))
f = [];
def factMod(n,m):
global f;
f = [1 for i in range(n+1)];
f[0] = 1;
for i in range(1,n+1):
f[i] = (f[i-1]*i)%m;
def fact(n):
global f;
f = [1 for i in range(n)];
for i in range(1,n):
f[i] = f[i-1]*i;
def fast_mod_exp(a,b,m):
res = 1;
while b > 0:
if b & 1:
res = (res*a)%m;
a = (a*a)%m;
b = b >> 1;
return res;
def inverseMod(n,m):
return fast_mod_exp(n,m-2,m);
def ncrMod(n,r,m):
if r == 0: return 1;
if n < r: return 0;
return ((f[n]*inverseMod(f[n-r],m))%m*inverseMod(f[r],m))%m;
def ncr(n,r):
if r == 0: return 1;
if n < r: return 0;
return (f[n])/(f[r]*f[n-r]);
def nc2(n):
return (n*(n-1))/2;
def main():
C();
a = [[-1 for j in range(26)] for i in range(100005)];
def C():
T = int(input());
while T > 0:
T -= 1;
s = ts();
t = ts();
x = [[] for i in range(26)]
res = 1;
for i in range(len(s)):
index = ord(s[i])-ord('a');
x[index].append(i);
for i in range(len(t)):
index = ord(t[i])-ord('a');
if len(x[index]) == 0:
res = 0;
break;
if res == 0:
print(-1);
continue;
for i in range(len(s)):
for j in range(26):
if len(x[j]) > 0:
if j != ord(s[i])-ord('a'): a[i][j] = x[j][0];
else: a[i][j] = x[j][1] if len(x[j]) > 1 else -1;
x[ord(s[i])-ord('a')].pop(0);
curr = 0;
count = 0;
p = 0;
while p < len(t):
if curr >= len(s):
curr = 0;
count += 1;
if t[p] == s[curr]:
p += 1;
curr += 1;
continue;
if a[curr][ord(t[p])-ord('a')] != -1:
curr = a[curr][ord(t[p])-ord('a')]+1;
p += 1;
continue;
count += 1;
curr = 0;
print(count+1);
main();
``` | instruction | 0 | 55,728 | 0 | 111,456 |
No | output | 1 | 55,728 | 0 | 111,457 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given two strings s and t consisting of lowercase Latin letters. Also you have a string z which is initially empty. You want string z to be equal to string t. You can perform the following operation to achieve this: append any subsequence of s at the end of string z. A subsequence is a sequence that can be derived from the given sequence by deleting zero or more elements without changing the order of the remaining elements. For example, if z = ac, s = abcde, you may turn z into following strings in one operation:
1. z = acace (if we choose subsequence ace);
2. z = acbcd (if we choose subsequence bcd);
3. z = acbce (if we choose subsequence bce).
Note that after this operation string s doesn't change.
Calculate the minimum number of such operations to turn string z into string t.
Input
The first line contains the integer T (1 ≤ T ≤ 100) — the number of test cases.
The first line of each testcase contains one string s (1 ≤ |s| ≤ 10^5) consisting of lowercase Latin letters.
The second line of each testcase contains one string t (1 ≤ |t| ≤ 10^5) consisting of lowercase Latin letters.
It is guaranteed that the total length of all strings s and t in the input does not exceed 2 ⋅ 10^5.
Output
For each testcase, print one integer — the minimum number of operations to turn string z into string t. If it's impossible print -1.
Example
Input
3
aabce
ace
abacaba
aax
ty
yyt
Output
1
-1
3
Submitted Solution:
```
# -*- coding: utf-8 -*-
import sys
from collections import Counter
def input(): return sys.stdin.readline().strip()
def list2d(a, b, c): return [[c] * b for i in range(a)]
def list3d(a, b, c, d): return [[[d] * c for j in range(b)] for i in range(a)]
def list4d(a, b, c, d, e): return [[[[e] * d for j in range(c)] for j in range(b)] for i in range(a)]
def ceil(x, y=1): return int(-(-x // y))
def INT(): return int(input())
def MAP(): return map(int, input().split())
def LIST(N=None): return list(MAP()) if N is None else [INT() for i in range(N)]
def Yes(): print('Yes')
def No(): print('No')
def YES(): print('YES')
def NO(): print('NO')
# sys.setrecursionlimit(10 ** 9)
INF = 10 ** 18
MOD = 10 ** 9 + 7
for _ in range(INT()):
S = [ord(c) - 97 for c in input()]
T = [ord(c) - 97 for c in input()]
N = len(S)
M = len(T)
C1 = Counter(S)
C2 = Counter(T)
for k, v in C2.items():
if C1[k] == 0:
print(-1)
break
else:
acc = list2d(26, N+1, INF)
for i, c in enumerate(S):
acc[c][i] = 1
for i in range(26):
for j in range(N-1, -1, -1):
if acc[i][j] == 1:
acc[i][j] = j
else:
acc[i][j] = acc[i][j+1]
cnt = 0
j = 0
for i, c in enumerate(T):
if j == 0:
cnt += 1
if acc[c][j] == INF:
j = 0
elif acc[c][j] == j:
j += 1
else:
j = acc[c][j] + 1
if j == N:
j = 0
print(cnt)
``` | instruction | 0 | 55,729 | 0 | 111,458 |
No | output | 1 | 55,729 | 0 | 111,459 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given two strings s and t consisting of lowercase Latin letters. Also you have a string z which is initially empty. You want string z to be equal to string t. You can perform the following operation to achieve this: append any subsequence of s at the end of string z. A subsequence is a sequence that can be derived from the given sequence by deleting zero or more elements without changing the order of the remaining elements. For example, if z = ac, s = abcde, you may turn z into following strings in one operation:
1. z = acace (if we choose subsequence ace);
2. z = acbcd (if we choose subsequence bcd);
3. z = acbce (if we choose subsequence bce).
Note that after this operation string s doesn't change.
Calculate the minimum number of such operations to turn string z into string t.
Input
The first line contains the integer T (1 ≤ T ≤ 100) — the number of test cases.
The first line of each testcase contains one string s (1 ≤ |s| ≤ 10^5) consisting of lowercase Latin letters.
The second line of each testcase contains one string t (1 ≤ |t| ≤ 10^5) consisting of lowercase Latin letters.
It is guaranteed that the total length of all strings s and t in the input does not exceed 2 ⋅ 10^5.
Output
For each testcase, print one integer — the minimum number of operations to turn string z into string t. If it's impossible print -1.
Example
Input
3
aabce
ace
abacaba
aax
ty
yyt
Output
1
-1
3
Submitted Solution:
```
from collections import defaultdict, deque
#input = sys.stdin.readline
for _ in range(int(input())):
s = input()
t = input()
d = defaultdict(deque)
used = defaultdict(deque)
for i in range(len(s)):
d[s[i]].append(i)
exitf = False
for i in t:
if not len(d[i]):
exitf = True
if exitf:
print(-1)
continue
count = 0
i = 0
prev = -1
while i < len(t):
if len(d[t[i]]) and d[t[i]][0] > prev:
prev = d[t[i]].popleft()
used[t[i]].append(prev)
i+=1
else:
prev = -1
count+=1
for tup in used.items():
while len(tup[1]):
d[tup[0]].appendleft(tup[1].pop())
print(count+1)
``` | instruction | 0 | 55,730 | 0 | 111,460 |
No | output | 1 | 55,730 | 0 | 111,461 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given two strings s and t consisting of lowercase Latin letters. Also you have a string z which is initially empty. You want string z to be equal to string t. You can perform the following operation to achieve this: append any subsequence of s at the end of string z. A subsequence is a sequence that can be derived from the given sequence by deleting zero or more elements without changing the order of the remaining elements. For example, if z = ac, s = abcde, you may turn z into following strings in one operation:
1. z = acace (if we choose subsequence ace);
2. z = acbcd (if we choose subsequence bcd);
3. z = acbce (if we choose subsequence bce).
Note that after this operation string s doesn't change.
Calculate the minimum number of such operations to turn string z into string t.
Input
The first line contains the integer T (1 ≤ T ≤ 100) — the number of test cases.
The first line of each testcase contains one string s (1 ≤ |s| ≤ 10^5) consisting of lowercase Latin letters.
The second line of each testcase contains one string t (1 ≤ |t| ≤ 10^5) consisting of lowercase Latin letters.
It is guaranteed that the total length of all strings s and t in the input does not exceed 2 ⋅ 10^5.
Output
For each testcase, print one integer — the minimum number of operations to turn string z into string t. If it's impossible print -1.
Example
Input
3
aabce
ace
abacaba
aax
ty
yyt
Output
1
-1
3
Submitted Solution:
```
import sys
import bisect
q=int(input())
while q:
s=input()
t=input()
l=-1
ch=0
cnt=1
d={i:[] for i in range(26)}
ind=0
for i in s:
d[ord(i)-97].append(ind)
ind+=1
for i in t:
if d[ord(i)-97]==[]:
print(-1)
ch=1
break
else:
p=bisect.bisect_right(d[ord(i)-97],l)
if p>=len(d[ord(i)-97]):
cnt+=1
else:
l=d[ord(i)-97][p]
if ch==0:
print(cnt)
q-=1
``` | instruction | 0 | 55,731 | 0 | 111,462 |
No | output | 1 | 55,731 | 0 | 111,463 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Kaavi, the mysterious fortune teller, deeply believes that one's fate is inevitable and unavoidable. Of course, she makes her living by predicting others' future. While doing divination, Kaavi believes that magic spells can provide great power for her to see the future.
<image>
Kaavi has a string T of length m and all the strings with the prefix T are magic spells. Kaavi also has a string S of length n and an empty string A.
During the divination, Kaavi needs to perform a sequence of operations. There are two different operations:
* Delete the first character of S and add it at the front of A.
* Delete the first character of S and add it at the back of A.
Kaavi can perform no more than n operations. To finish the divination, she wants to know the number of different operation sequences to make A a magic spell (i.e. with the prefix T). As her assistant, can you help her? The answer might be huge, so Kaavi only needs to know the answer modulo 998 244 353.
Two operation sequences are considered different if they are different in length or there exists an i that their i-th operation is different.
A substring is a contiguous sequence of characters within a string. A prefix of a string S is a substring of S that occurs at the beginning of S.
Input
The first line contains a string S of length n (1 ≤ n ≤ 3000).
The second line contains a string T of length m (1 ≤ m ≤ n).
Both strings contain only lowercase Latin letters.
Output
The output contains only one integer — the answer modulo 998 244 353.
Examples
Input
abab
ba
Output
12
Input
defineintlonglong
signedmain
Output
0
Input
rotator
rotator
Output
4
Input
cacdcdbbbb
bdcaccdbbb
Output
24
Note
The first test:
<image>
The red ones are the magic spells. In the first operation, Kaavi can either add the first character "a" at the front or the back of A, although the results are the same, they are considered as different operations. So the answer is 6×2=12. | instruction | 0 | 55,749 | 0 | 111,498 |
Tags: dp, strings
Correct Solution:
```
import sys
input = sys.stdin.readline
sys.setrecursionlimit(10 ** 5)
s = input()[:-1]
t = input()[:-1]
MOD = 998244353
r_lim = len(t)
n = len(s)
dp = [[0] * (n + 1) for i in range(n + 1)]
for length in range(1, n + 1):
for l in range(n + 1):
r = l + length
if r > n:
break
if length == 1:
if l >= r_lim or s[0] == t[l]:
dp[l][r] = 2
else:
dp[l][r] = 0
continue
if l >= r_lim or s[length - 1] == t[l]:
dp[l][r] += dp[l + 1][r]
dp[l][r] %= MOD
if r - 1 >= r_lim or s[length - 1] == t[r - 1]:
dp[l][r] += dp[l][r - 1]
dp[l][r] %= MOD
ans = 0
for i in range(r_lim, n + 1):
ans += dp[0][i]
ans %= MOD
print(ans)
``` | output | 1 | 55,749 | 0 | 111,499 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Kaavi, the mysterious fortune teller, deeply believes that one's fate is inevitable and unavoidable. Of course, she makes her living by predicting others' future. While doing divination, Kaavi believes that magic spells can provide great power for her to see the future.
<image>
Kaavi has a string T of length m and all the strings with the prefix T are magic spells. Kaavi also has a string S of length n and an empty string A.
During the divination, Kaavi needs to perform a sequence of operations. There are two different operations:
* Delete the first character of S and add it at the front of A.
* Delete the first character of S and add it at the back of A.
Kaavi can perform no more than n operations. To finish the divination, she wants to know the number of different operation sequences to make A a magic spell (i.e. with the prefix T). As her assistant, can you help her? The answer might be huge, so Kaavi only needs to know the answer modulo 998 244 353.
Two operation sequences are considered different if they are different in length or there exists an i that their i-th operation is different.
A substring is a contiguous sequence of characters within a string. A prefix of a string S is a substring of S that occurs at the beginning of S.
Input
The first line contains a string S of length n (1 ≤ n ≤ 3000).
The second line contains a string T of length m (1 ≤ m ≤ n).
Both strings contain only lowercase Latin letters.
Output
The output contains only one integer — the answer modulo 998 244 353.
Examples
Input
abab
ba
Output
12
Input
defineintlonglong
signedmain
Output
0
Input
rotator
rotator
Output
4
Input
cacdcdbbbb
bdcaccdbbb
Output
24
Note
The first test:
<image>
The red ones are the magic spells. In the first operation, Kaavi can either add the first character "a" at the front or the back of A, although the results are the same, they are considered as different operations. So the answer is 6×2=12. | instruction | 0 | 55,750 | 0 | 111,500 |
Tags: dp, strings
Correct Solution:
```
import sys, inspect
strings = iter(sys.stdin.read().split())
mod = 998244353
def main():
s,t = next(strings), next(strings)
n, m = len(s), len(t)
dp = [j==0 for j in range(m+1)]
f = lambda j: (
(n-i+1 if i>=m else (s[i]==t[j+i] and dp[j])) if j==0 else
(2*dp[j] + (s[i]==t[j-1] and dp[j-1])) if j==m else
((s[i]==t[j-1] and dp[j-1]) + ((i+j>=m or s[i]==t[j+i]) and dp[j]))
) % mod
for i in range(n-1, 0, -1):
dp = [f(j) for j in range(m+1)]
ans = sum(2*dp[j] for j in range(m+1) if j==m or s[0]==t[j]) % mod
print(ans)
return
main()
def F(S,T):
global s, t, n, m
s,t,n,m = S,T,len(S),len(T)
# start with A='s[0]' either matching some t[j] or being wasted in the tail (j=m)
ans = sum(2*f(1,j) for j in range(m+1) if j==m or t[j]==s[0])
return ans%mod
def f(i, j):
# 1<=i<=n ; 0<=j<=m
# answer given that s[:i] was already used into A and A[j:j+i][:m] matches t[j:j+i]
#print('{}{} <- {}'.format(' '*len(inspect.stack(0)), t[j:j+i], s[i:]))
if i==n:
ans = j==0
elif j==0:
if i>=m:
ans = n-i+1 # stop anywhere
else:
ans = s[i]==t[j+i] and f(i+1, j) # back
elif j<m:
ans = 0
ans += (s[i]==t[j-1]) and f(i+1, j-1) # front
ans += (i+j>=m or s[i]==t[j+i]) and f(i+1, j) # back
elif j==m:
ans = 2*f(i+1, j) # Waste s[i], front-back
ans += s[i]==t[j-1] and f(i+1, j-1) # front
#print('{}{}'.format(' '*len(inspect.stack(0)), ans))
return ans%mod
``` | output | 1 | 55,750 | 0 | 111,501 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Kaavi, the mysterious fortune teller, deeply believes that one's fate is inevitable and unavoidable. Of course, she makes her living by predicting others' future. While doing divination, Kaavi believes that magic spells can provide great power for her to see the future.
<image>
Kaavi has a string T of length m and all the strings with the prefix T are magic spells. Kaavi also has a string S of length n and an empty string A.
During the divination, Kaavi needs to perform a sequence of operations. There are two different operations:
* Delete the first character of S and add it at the front of A.
* Delete the first character of S and add it at the back of A.
Kaavi can perform no more than n operations. To finish the divination, she wants to know the number of different operation sequences to make A a magic spell (i.e. with the prefix T). As her assistant, can you help her? The answer might be huge, so Kaavi only needs to know the answer modulo 998 244 353.
Two operation sequences are considered different if they are different in length or there exists an i that their i-th operation is different.
A substring is a contiguous sequence of characters within a string. A prefix of a string S is a substring of S that occurs at the beginning of S.
Input
The first line contains a string S of length n (1 ≤ n ≤ 3000).
The second line contains a string T of length m (1 ≤ m ≤ n).
Both strings contain only lowercase Latin letters.
Output
The output contains only one integer — the answer modulo 998 244 353.
Examples
Input
abab
ba
Output
12
Input
defineintlonglong
signedmain
Output
0
Input
rotator
rotator
Output
4
Input
cacdcdbbbb
bdcaccdbbb
Output
24
Note
The first test:
<image>
The red ones are the magic spells. In the first operation, Kaavi can either add the first character "a" at the front or the back of A, although the results are the same, they are considered as different operations. So the answer is 6×2=12. | instruction | 0 | 55,751 | 0 | 111,502 |
Tags: dp, strings
Correct Solution:
```
# -*- coding:utf-8 -*-
"""
created by shuangquan.huang at 2020/7/1
"""
import collections
import time
import os
import sys
import bisect
import heapq
from typing import List
MOD = 998244353
def solve(s, t):
n, m = len(s), len(t)
dp = [[0 for _ in range(m+1)] for _ in range(n+1)]
dp[n][0] = 1
for i in range(n-1, 0, -1):
for j in range(m+1):
if j == 0:
if i >= m:
dp[i][0] = n - i + 1
elif s[i] == t[i]:
dp[i][0] = dp[i+1][0]
elif j == m:
dp[i][m] = 2 * dp[i+1][m] % MOD
if s[i] == t[m-1]:
dp[i][m] = (dp[i][m] + dp[i+1][m-1]) % MOD
else:
if i + j >= m or s[i] == t[i+j]:
dp[i][j] = dp[i+1][j]
if s[i] == t[j-1]:
dp[i][j] = (dp[i][j] + dp[i+1][j-1]) % MOD
ans = dp[1][m]
for i in range(m):
if t[i] == s[0]:
ans = (ans + dp[1][i]) % MOD
ans *= 2
ans %= MOD
return ans
if __name__ == '__main__':
s = input()
t = input()
print(solve(s, t))
``` | output | 1 | 55,751 | 0 | 111,503 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Kaavi, the mysterious fortune teller, deeply believes that one's fate is inevitable and unavoidable. Of course, she makes her living by predicting others' future. While doing divination, Kaavi believes that magic spells can provide great power for her to see the future.
<image>
Kaavi has a string T of length m and all the strings with the prefix T are magic spells. Kaavi also has a string S of length n and an empty string A.
During the divination, Kaavi needs to perform a sequence of operations. There are two different operations:
* Delete the first character of S and add it at the front of A.
* Delete the first character of S and add it at the back of A.
Kaavi can perform no more than n operations. To finish the divination, she wants to know the number of different operation sequences to make A a magic spell (i.e. with the prefix T). As her assistant, can you help her? The answer might be huge, so Kaavi only needs to know the answer modulo 998 244 353.
Two operation sequences are considered different if they are different in length or there exists an i that their i-th operation is different.
A substring is a contiguous sequence of characters within a string. A prefix of a string S is a substring of S that occurs at the beginning of S.
Input
The first line contains a string S of length n (1 ≤ n ≤ 3000).
The second line contains a string T of length m (1 ≤ m ≤ n).
Both strings contain only lowercase Latin letters.
Output
The output contains only one integer — the answer modulo 998 244 353.
Examples
Input
abab
ba
Output
12
Input
defineintlonglong
signedmain
Output
0
Input
rotator
rotator
Output
4
Input
cacdcdbbbb
bdcaccdbbb
Output
24
Note
The first test:
<image>
The red ones are the magic spells. In the first operation, Kaavi can either add the first character "a" at the front or the back of A, although the results are the same, they are considered as different operations. So the answer is 6×2=12. | instruction | 0 | 55,752 | 0 | 111,504 |
Tags: dp, strings
Correct Solution:
```
S = input()
T = input()
b = 998244353
n, m = len(S), len(T)
S = '7' + S # 1-indexing
T = '7' + T
f = [[0 for _ in range(n + 1)] for _ in range(n + 1)]
for i in range(m, n + 1):
if i > m or S[i] == T[m]:
f[i][0] = 1
if S[i] == T[1]:
f[i][1] = 1
for i in reversed(range(2, n + 1)):
for j in range(0, n - i + 2):
if j >= m or T[j + 1] == S[i - 1]:
f[i - 1][j + 1] = (f[i - 1][j + 1] + f[i][j]) % b
x = j + i - 1
if x > m or S[i - 1] == T[x]:
f[i - 1][j] = (f[i - 1][j] + f[i][j]) % b
ans = 0
for i in range(n + 1):
ans = (ans + f[1][i]) % b
print(ans)
``` | output | 1 | 55,752 | 0 | 111,505 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Kaavi, the mysterious fortune teller, deeply believes that one's fate is inevitable and unavoidable. Of course, she makes her living by predicting others' future. While doing divination, Kaavi believes that magic spells can provide great power for her to see the future.
<image>
Kaavi has a string T of length m and all the strings with the prefix T are magic spells. Kaavi also has a string S of length n and an empty string A.
During the divination, Kaavi needs to perform a sequence of operations. There are two different operations:
* Delete the first character of S and add it at the front of A.
* Delete the first character of S and add it at the back of A.
Kaavi can perform no more than n operations. To finish the divination, she wants to know the number of different operation sequences to make A a magic spell (i.e. with the prefix T). As her assistant, can you help her? The answer might be huge, so Kaavi only needs to know the answer modulo 998 244 353.
Two operation sequences are considered different if they are different in length or there exists an i that their i-th operation is different.
A substring is a contiguous sequence of characters within a string. A prefix of a string S is a substring of S that occurs at the beginning of S.
Input
The first line contains a string S of length n (1 ≤ n ≤ 3000).
The second line contains a string T of length m (1 ≤ m ≤ n).
Both strings contain only lowercase Latin letters.
Output
The output contains only one integer — the answer modulo 998 244 353.
Examples
Input
abab
ba
Output
12
Input
defineintlonglong
signedmain
Output
0
Input
rotator
rotator
Output
4
Input
cacdcdbbbb
bdcaccdbbb
Output
24
Note
The first test:
<image>
The red ones are the magic spells. In the first operation, Kaavi can either add the first character "a" at the front or the back of A, although the results are the same, they are considered as different operations. So the answer is 6×2=12. | instruction | 0 | 55,753 | 0 | 111,506 |
Tags: dp, strings
Correct Solution:
```
import sys
from array import array # noqa: F401
from typing import List, Tuple, TypeVar, Generic, Sequence, Union # noqa: F401
def input():
return sys.stdin.buffer.readline().decode('utf-8')
def solve():
s, t = input().rstrip(), '*' + input().rstrip()
n, m = len(s), len(t)
mod = 998244353
dp = [array('i', [0]) * (n + 2) for _ in range(n + 2)]
for i in range(1, n + 2):
dp[i][i - 1] = 1
for slen, c in enumerate(s):
for i, j in zip(range(n + 2), range(slen, n + 2)):
if 0 < i < m and t[i] == c or m <= i <= n:
dp[i][j] += dp[i + 1][j]
if dp[i][j] >= mod:
dp[i][j] -= mod
if 0 < j < m and t[j] == c or m <= j <= n:
dp[i][j] += dp[i][j - 1]
if dp[i][j] >= mod:
dp[i][j] -= mod
print(sum(dp[1][m - 1:]) % mod)
if __name__ == '__main__':
solve()
``` | output | 1 | 55,753 | 0 | 111,507 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Kaavi, the mysterious fortune teller, deeply believes that one's fate is inevitable and unavoidable. Of course, she makes her living by predicting others' future. While doing divination, Kaavi believes that magic spells can provide great power for her to see the future.
<image>
Kaavi has a string T of length m and all the strings with the prefix T are magic spells. Kaavi also has a string S of length n and an empty string A.
During the divination, Kaavi needs to perform a sequence of operations. There are two different operations:
* Delete the first character of S and add it at the front of A.
* Delete the first character of S and add it at the back of A.
Kaavi can perform no more than n operations. To finish the divination, she wants to know the number of different operation sequences to make A a magic spell (i.e. with the prefix T). As her assistant, can you help her? The answer might be huge, so Kaavi only needs to know the answer modulo 998 244 353.
Two operation sequences are considered different if they are different in length or there exists an i that their i-th operation is different.
A substring is a contiguous sequence of characters within a string. A prefix of a string S is a substring of S that occurs at the beginning of S.
Input
The first line contains a string S of length n (1 ≤ n ≤ 3000).
The second line contains a string T of length m (1 ≤ m ≤ n).
Both strings contain only lowercase Latin letters.
Output
The output contains only one integer — the answer modulo 998 244 353.
Examples
Input
abab
ba
Output
12
Input
defineintlonglong
signedmain
Output
0
Input
rotator
rotator
Output
4
Input
cacdcdbbbb
bdcaccdbbb
Output
24
Note
The first test:
<image>
The red ones are the magic spells. In the first operation, Kaavi can either add the first character "a" at the front or the back of A, although the results are the same, they are considered as different operations. So the answer is 6×2=12. | instruction | 0 | 55,754 | 0 | 111,508 |
Tags: dp, strings
Correct Solution:
```
def power(x, y, p):
res = 1 # Initialize result
# Update x if it is more
# than or equal to p
x = x % p
if (x == 0):
return 0
while (y > 0):
# If y is odd, multiply
# x with result
if ((y & 1) == 1):
res = (res * x) % p
# y must be even now
y = y >> 1 # y = y/2
x = (x * x) % p
return res
p=998244353
s=input()
t=input()
n=len(s)
m=len(t)
dp=[[0 for j in range(m)] for i in range(n)]
for j in range(m):
if s[0]==t[j]:
dp[0][j]=2
for i in range(1,n):
for j in range(m):
if s[i]==t[j]:
if j==(m-1):
dp[i][j]+=power(2,i,p)
else:
dp[i][j]+=dp[i-1][j+1]
if (i+j)>=m or s[i]==t[i+j]:
dp[i][j]+=dp[i-1][j]
dp[i][j]=dp[i][j]%p
ans=0
for i in range(m-1,n):
ans+=dp[i][0]
ans=ans%p
print(ans)
print()
``` | output | 1 | 55,754 | 0 | 111,509 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Kaavi, the mysterious fortune teller, deeply believes that one's fate is inevitable and unavoidable. Of course, she makes her living by predicting others' future. While doing divination, Kaavi believes that magic spells can provide great power for her to see the future.
<image>
Kaavi has a string T of length m and all the strings with the prefix T are magic spells. Kaavi also has a string S of length n and an empty string A.
During the divination, Kaavi needs to perform a sequence of operations. There are two different operations:
* Delete the first character of S and add it at the front of A.
* Delete the first character of S and add it at the back of A.
Kaavi can perform no more than n operations. To finish the divination, she wants to know the number of different operation sequences to make A a magic spell (i.e. with the prefix T). As her assistant, can you help her? The answer might be huge, so Kaavi only needs to know the answer modulo 998 244 353.
Two operation sequences are considered different if they are different in length or there exists an i that their i-th operation is different.
A substring is a contiguous sequence of characters within a string. A prefix of a string S is a substring of S that occurs at the beginning of S.
Input
The first line contains a string S of length n (1 ≤ n ≤ 3000).
The second line contains a string T of length m (1 ≤ m ≤ n).
Both strings contain only lowercase Latin letters.
Output
The output contains only one integer — the answer modulo 998 244 353.
Examples
Input
abab
ba
Output
12
Input
defineintlonglong
signedmain
Output
0
Input
rotator
rotator
Output
4
Input
cacdcdbbbb
bdcaccdbbb
Output
24
Note
The first test:
<image>
The red ones are the magic spells. In the first operation, Kaavi can either add the first character "a" at the front or the back of A, although the results are the same, they are considered as different operations. So the answer is 6×2=12. | instruction | 0 | 55,755 | 0 | 111,510 |
Tags: dp, strings
Correct Solution:
```
# import sys
# input = sys.stdin.readline
def dp(S,T,n,m,mod):
mp = modPower(n,mod)
rows, cols = n, n
dp = [([0] * cols) for _ in range(rows)]
for j in range(n):
if j<m:
c = int(S[0]==T[j])
dp[0][j] = 2*c
else:
dp[0][j] = 2
for i in range(1,n):
for j in range(n-i):
if(i+j<m):
dp[i][j] = (dp[i-1][j]*int(S[i]==T[i+j]) + dp[i-1][j+1]*int(S[i]==T[j]))%mod
elif(i+j>=m and j<m):
dp[i][j] = (dp[i-1][j+1]*int(S[i]==T[j]) + dp[i-1][j])%mod
else:
dp[i][j] = mp[i+1]
r = 0
for i in range(m-1,n):
r += dp[i][0]%mod
return r%mod
def modPower(n,mod):
mp = [0]*n
mp[0]=1
for i in range(1,n):
mp[i] = int((2*mp[i-1])%mod)
return mp
def solu(S,T,n,m):
mod = 998244353
dpr = dp(S,T,n,m,mod)
return dpr
def printMatrix(des,m):
print(des)
for i in range(len(m)):
print(*m[i])
S = input()
T = input()
n = len(S)
m = len(T)
mod = 998244353
dpr = dp(S,T,n,m,mod)
print(dpr)
``` | output | 1 | 55,755 | 0 | 111,511 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Kaavi, the mysterious fortune teller, deeply believes that one's fate is inevitable and unavoidable. Of course, she makes her living by predicting others' future. While doing divination, Kaavi believes that magic spells can provide great power for her to see the future.
<image>
Kaavi has a string T of length m and all the strings with the prefix T are magic spells. Kaavi also has a string S of length n and an empty string A.
During the divination, Kaavi needs to perform a sequence of operations. There are two different operations:
* Delete the first character of S and add it at the front of A.
* Delete the first character of S and add it at the back of A.
Kaavi can perform no more than n operations. To finish the divination, she wants to know the number of different operation sequences to make A a magic spell (i.e. with the prefix T). As her assistant, can you help her? The answer might be huge, so Kaavi only needs to know the answer modulo 998 244 353.
Two operation sequences are considered different if they are different in length or there exists an i that their i-th operation is different.
A substring is a contiguous sequence of characters within a string. A prefix of a string S is a substring of S that occurs at the beginning of S.
Input
The first line contains a string S of length n (1 ≤ n ≤ 3000).
The second line contains a string T of length m (1 ≤ m ≤ n).
Both strings contain only lowercase Latin letters.
Output
The output contains only one integer — the answer modulo 998 244 353.
Examples
Input
abab
ba
Output
12
Input
defineintlonglong
signedmain
Output
0
Input
rotator
rotator
Output
4
Input
cacdcdbbbb
bdcaccdbbb
Output
24
Note
The first test:
<image>
The red ones are the magic spells. In the first operation, Kaavi can either add the first character "a" at the front or the back of A, although the results are the same, they are considered as different operations. So the answer is 6×2=12. | instruction | 0 | 55,756 | 0 | 111,512 |
Tags: dp, strings
Correct Solution:
```
S = input()
T = input()
base = 998244353
dp = [[0 for _ in range(len(S) + 1)] for _ in range(len(S) + 1)]
for j in range(1, len(S) + 1):
if (j > len(T)) or (S[0] == T[j - 1]):
dp[1][j] = 2
for i in range(2, len(S) + 1):
for j in range(1, len(S) - i + 1 + 1):
if (j > len(T)) or (S[i - 1] == T[j - 1]):
dp[i][j] = (dp[i][j] + dp[i - 1][j + 1]) % base
if (j + i - 1 > len(T)) or (S[i - 1] == T[j + i - 1 - 1]):
dp[i][j] = (dp[i][j] + dp[i - 1][j]) % base
ans = 0
for i in range(len(T), len(S) + 1):
ans = (ans + dp[i][1]) % base
print(ans)
``` | output | 1 | 55,756 | 0 | 111,513 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Kaavi, the mysterious fortune teller, deeply believes that one's fate is inevitable and unavoidable. Of course, she makes her living by predicting others' future. While doing divination, Kaavi believes that magic spells can provide great power for her to see the future.
<image>
Kaavi has a string T of length m and all the strings with the prefix T are magic spells. Kaavi also has a string S of length n and an empty string A.
During the divination, Kaavi needs to perform a sequence of operations. There are two different operations:
* Delete the first character of S and add it at the front of A.
* Delete the first character of S and add it at the back of A.
Kaavi can perform no more than n operations. To finish the divination, she wants to know the number of different operation sequences to make A a magic spell (i.e. with the prefix T). As her assistant, can you help her? The answer might be huge, so Kaavi only needs to know the answer modulo 998 244 353.
Two operation sequences are considered different if they are different in length or there exists an i that their i-th operation is different.
A substring is a contiguous sequence of characters within a string. A prefix of a string S is a substring of S that occurs at the beginning of S.
Input
The first line contains a string S of length n (1 ≤ n ≤ 3000).
The second line contains a string T of length m (1 ≤ m ≤ n).
Both strings contain only lowercase Latin letters.
Output
The output contains only one integer — the answer modulo 998 244 353.
Examples
Input
abab
ba
Output
12
Input
defineintlonglong
signedmain
Output
0
Input
rotator
rotator
Output
4
Input
cacdcdbbbb
bdcaccdbbb
Output
24
Note
The first test:
<image>
The red ones are the magic spells. In the first operation, Kaavi can either add the first character "a" at the front or the back of A, although the results are the same, they are considered as different operations. So the answer is 6×2=12.
Submitted Solution:
```
mod = 998244353
eps = 10**-9
def main():
import sys
input = sys.stdin.readline
S = input().rstrip('\n')
S = S[::-1]
T = input().rstrip('\n')
NS = len(S)
NT = len(T)
dp = [[0] * (NT+1) for _ in range(NS+1)]
dp[0][0] = 1
for i in range(NS):
s = S[i]
for j in range(NT+1):
# front
if j == 0:
if i != NS-1:
if T[0] == s and dp[i][0]:
dp[i+1][1] = (dp[i+1][1] + dp[i][0] + min(i, NS-NT))%mod
else:
if T[0] == s and dp[i][0]:
dp[i+1][-1] = (dp[i+1][-1] + dp[i][0] + NS-NT)%mod
elif j == NT:
dp[i+1][j] = (dp[i+1][j] + dp[i][j])%mod
else:
if i != NS-1:
if s == T[j]:
dp[i+1][j+1] = (dp[i+1][j+1] + dp[i][j])%mod
else:
if s == T[j]:
dp[i + 1][-1] = (dp[i + 1][-1] + dp[i][j]) % mod
# back
k = NS - (i-j) - 1
if k >= NT:
dp[i+1][j] = (dp[i+1][j] + dp[i][j])%mod
else:
if T[k] == s:
if i != NS-1:
dp[i + 1][j] = (dp[i + 1][j] + dp[i][j]) % mod
else:
dp[i + 1][-1] = (dp[i + 1][-1] + dp[i][j]) % mod
if k == 0 and dp[i][j]:
dp[i+1][-1] = (dp[i+1][-1] + (NS-NT))%mod
print(dp[-1][-1]%mod)
#[print(i, dp[i]) for i in range(NS+1)]
if __name__ == '__main__':
main()
``` | instruction | 0 | 55,757 | 0 | 111,514 |
Yes | output | 1 | 55,757 | 0 | 111,515 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Kaavi, the mysterious fortune teller, deeply believes that one's fate is inevitable and unavoidable. Of course, she makes her living by predicting others' future. While doing divination, Kaavi believes that magic spells can provide great power for her to see the future.
<image>
Kaavi has a string T of length m and all the strings with the prefix T are magic spells. Kaavi also has a string S of length n and an empty string A.
During the divination, Kaavi needs to perform a sequence of operations. There are two different operations:
* Delete the first character of S and add it at the front of A.
* Delete the first character of S and add it at the back of A.
Kaavi can perform no more than n operations. To finish the divination, she wants to know the number of different operation sequences to make A a magic spell (i.e. with the prefix T). As her assistant, can you help her? The answer might be huge, so Kaavi only needs to know the answer modulo 998 244 353.
Two operation sequences are considered different if they are different in length or there exists an i that their i-th operation is different.
A substring is a contiguous sequence of characters within a string. A prefix of a string S is a substring of S that occurs at the beginning of S.
Input
The first line contains a string S of length n (1 ≤ n ≤ 3000).
The second line contains a string T of length m (1 ≤ m ≤ n).
Both strings contain only lowercase Latin letters.
Output
The output contains only one integer — the answer modulo 998 244 353.
Examples
Input
abab
ba
Output
12
Input
defineintlonglong
signedmain
Output
0
Input
rotator
rotator
Output
4
Input
cacdcdbbbb
bdcaccdbbb
Output
24
Note
The first test:
<image>
The red ones are the magic spells. In the first operation, Kaavi can either add the first character "a" at the front or the back of A, although the results are the same, they are considered as different operations. So the answer is 6×2=12.
Submitted Solution:
```
import io
import os
import sys
# sys.stdin = open('input.txt', 'r')
# sys.stdout = open('output.txt', 'w')
fileno = sys.stdin.fileno()
input = io.BytesIO(
os.read(fileno, os.fstat(fileno).st_size)
).readline
MOD = 998_244_353
S = input().strip().decode('utf8')
T = input().strip().decode('utf8')
N = len(S)
M = len(T)
D = [
[0 for j in range(M)] for i in range(N)
]
for j in range(M):
if S[0] == T[j]:
D[0][j] = 2
for i in range(1, N):
for j in range(M):
# left operation
if S[i] == T[j]:
if j != M - 1:
D[i][j] = D[i-1][j+1]
else:
D[i][j] = pow(2, i, MOD)
# right operation
if i + j >= M or S[i] == T[i+j]:
D[i][j] += D[i-1][j]
D[i][j] %= MOD
ans = 0
for i in range(M - 1, N):
ans += D[i][0]
ans %= MOD
print(ans)
``` | instruction | 0 | 55,759 | 0 | 111,518 |
Yes | output | 1 | 55,759 | 0 | 111,519 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Kaavi, the mysterious fortune teller, deeply believes that one's fate is inevitable and unavoidable. Of course, she makes her living by predicting others' future. While doing divination, Kaavi believes that magic spells can provide great power for her to see the future.
<image>
Kaavi has a string T of length m and all the strings with the prefix T are magic spells. Kaavi also has a string S of length n and an empty string A.
During the divination, Kaavi needs to perform a sequence of operations. There are two different operations:
* Delete the first character of S and add it at the front of A.
* Delete the first character of S and add it at the back of A.
Kaavi can perform no more than n operations. To finish the divination, she wants to know the number of different operation sequences to make A a magic spell (i.e. with the prefix T). As her assistant, can you help her? The answer might be huge, so Kaavi only needs to know the answer modulo 998 244 353.
Two operation sequences are considered different if they are different in length or there exists an i that their i-th operation is different.
A substring is a contiguous sequence of characters within a string. A prefix of a string S is a substring of S that occurs at the beginning of S.
Input
The first line contains a string S of length n (1 ≤ n ≤ 3000).
The second line contains a string T of length m (1 ≤ m ≤ n).
Both strings contain only lowercase Latin letters.
Output
The output contains only one integer — the answer modulo 998 244 353.
Examples
Input
abab
ba
Output
12
Input
defineintlonglong
signedmain
Output
0
Input
rotator
rotator
Output
4
Input
cacdcdbbbb
bdcaccdbbb
Output
24
Note
The first test:
<image>
The red ones are the magic spells. In the first operation, Kaavi can either add the first character "a" at the front or the back of A, although the results are the same, they are considered as different operations. So the answer is 6×2=12.
Submitted Solution:
```
import sys
from copy import copy, deepcopy
input = sys.stdin.readline
inf = 100000000000000000 # 1e17
mod = 998244353
S = input().strip()
n = len(S)
T = input().strip()
T = list(T)
num = len(T)
T.extend(["!"] * (n - len(T)))
f = [[0] * (n + 10) for i in range(n + 10)]
for i in range(n):
f[i][i - 1] = 1
f[i + 1][i] = 1
for i in range(n):
for l in range(n):
r = l + i
if r >= n:
break
if S[i] == T[r] or T[r] == "!":
f[l][r] += f[l][r - 1]
f[l][r] %= mod
if S[i] == T[l] or T[l] == "!":
f[l][r] += f[l + 1][r]
f[l][r] %= mod
ans = 0
for i in range(num - 1, n):
ans += (f[0][i])
ans %= mod
print(ans % mod)
``` | instruction | 0 | 55,760 | 0 | 111,520 |
Yes | output | 1 | 55,760 | 0 | 111,521 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Kaavi, the mysterious fortune teller, deeply believes that one's fate is inevitable and unavoidable. Of course, she makes her living by predicting others' future. While doing divination, Kaavi believes that magic spells can provide great power for her to see the future.
<image>
Kaavi has a string T of length m and all the strings with the prefix T are magic spells. Kaavi also has a string S of length n and an empty string A.
During the divination, Kaavi needs to perform a sequence of operations. There are two different operations:
* Delete the first character of S and add it at the front of A.
* Delete the first character of S and add it at the back of A.
Kaavi can perform no more than n operations. To finish the divination, she wants to know the number of different operation sequences to make A a magic spell (i.e. with the prefix T). As her assistant, can you help her? The answer might be huge, so Kaavi only needs to know the answer modulo 998 244 353.
Two operation sequences are considered different if they are different in length or there exists an i that their i-th operation is different.
A substring is a contiguous sequence of characters within a string. A prefix of a string S is a substring of S that occurs at the beginning of S.
Input
The first line contains a string S of length n (1 ≤ n ≤ 3000).
The second line contains a string T of length m (1 ≤ m ≤ n).
Both strings contain only lowercase Latin letters.
Output
The output contains only one integer — the answer modulo 998 244 353.
Examples
Input
abab
ba
Output
12
Input
defineintlonglong
signedmain
Output
0
Input
rotator
rotator
Output
4
Input
cacdcdbbbb
bdcaccdbbb
Output
24
Note
The first test:
<image>
The red ones are the magic spells. In the first operation, Kaavi can either add the first character "a" at the front or the back of A, although the results are the same, they are considered as different operations. So the answer is 6×2=12.
Submitted Solution:
```
mod = 998244353
eps = 10**-9
def main():
import sys
input = sys.stdin.readline
S = input().rstrip('\n')
S = S[::-1]
T = input().rstrip('\n')
NS = len(S)
NT = len(T)
dp = [[0] * (NT+1) for _ in range(NS+1)]
dp[0][0] = 1
for i in range(NS):
s = S[i]
for j in range(min(NT+1, i+1)):
# front
if j == 0:
if i != NS-1:
if T[0] == s:
dp[i+1][1] = (dp[i][0] + min(i, NS-NT))%mod
else:
dp[i+1][-1] = (dp[i+1][-1] + dp[i][0])%mod
elif j == NT:
dp[i+1][j] = (dp[i+1][j] + dp[i][j])%mod
else:
if i != NS-1:
if s == T[j]:
dp[i+1][j+1] = (dp[i+1][j+1] + dp[i][j])%mod
else:
dp[i + 1][-1] = (dp[i + 1][-1] + dp[i][j]) % mod
# back
k = NS - (i-j) - 1
if k >= NT:
dp[i+1][j] = (dp[i+1][j] + dp[i][j])%mod
else:
if T[k] == s:
if i != NS-1:
dp[i + 1][j] = (dp[i + 1][j] + dp[i][j]) % mod
else:
dp[i + 1][-1] = (dp[i + 1][-1] + dp[i][j]) % mod
print(dp[-1][-1])
#[print(i, dp[i]) for i in range(NS+1)]
if __name__ == '__main__':
main()
``` | instruction | 0 | 55,761 | 0 | 111,522 |
No | output | 1 | 55,761 | 0 | 111,523 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Kaavi, the mysterious fortune teller, deeply believes that one's fate is inevitable and unavoidable. Of course, she makes her living by predicting others' future. While doing divination, Kaavi believes that magic spells can provide great power for her to see the future.
<image>
Kaavi has a string T of length m and all the strings with the prefix T are magic spells. Kaavi also has a string S of length n and an empty string A.
During the divination, Kaavi needs to perform a sequence of operations. There are two different operations:
* Delete the first character of S and add it at the front of A.
* Delete the first character of S and add it at the back of A.
Kaavi can perform no more than n operations. To finish the divination, she wants to know the number of different operation sequences to make A a magic spell (i.e. with the prefix T). As her assistant, can you help her? The answer might be huge, so Kaavi only needs to know the answer modulo 998 244 353.
Two operation sequences are considered different if they are different in length or there exists an i that their i-th operation is different.
A substring is a contiguous sequence of characters within a string. A prefix of a string S is a substring of S that occurs at the beginning of S.
Input
The first line contains a string S of length n (1 ≤ n ≤ 3000).
The second line contains a string T of length m (1 ≤ m ≤ n).
Both strings contain only lowercase Latin letters.
Output
The output contains only one integer — the answer modulo 998 244 353.
Examples
Input
abab
ba
Output
12
Input
defineintlonglong
signedmain
Output
0
Input
rotator
rotator
Output
4
Input
cacdcdbbbb
bdcaccdbbb
Output
24
Note
The first test:
<image>
The red ones are the magic spells. In the first operation, Kaavi can either add the first character "a" at the front or the back of A, although the results are the same, they are considered as different operations. So the answer is 6×2=12.
Submitted Solution:
```
#f
# Fri Oct 02 2020 16:47:22 GMT+0300 (Москва, стандартное время)
``` | instruction | 0 | 55,762 | 0 | 111,524 |
No | output | 1 | 55,762 | 0 | 111,525 |
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