message stringlengths 2 23.8k | message_type stringclasses 2
values | message_id int64 0 1 | conversation_id int64 97 109k | cluster float64 0 0 | __index_level_0__ int64 194 217k |
|---|---|---|---|---|---|
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given a string s consisting of lowercase English letters and a number k. Let's call a string consisting of lowercase English letters beautiful if the number of occurrences of each letter in that string is divisible by k. You are aske... | instruction | 0 | 62,513 | 0 | 125,026 |
Tags: binary search, brute force, constructive algorithms, greedy, strings
Correct Solution:
```
rn=lambda:int(input())
rns=lambda:map(int,input().split())
rl=lambda:list(map(int,input().split()))
rs=lambda:input()
YN=lambda x:print('YES') if x else print('NO')
mod=10**9+7
from collections import Counter
def solve(n,k... | output | 1 | 62,513 | 0 | 125,027 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given a string s consisting of lowercase English letters and a number k. Let's call a string consisting of lowercase English letters beautiful if the number of occurrences of each letter in that string is divisible by k. You are aske... | instruction | 0 | 62,514 | 0 | 125,028 |
Tags: binary search, brute force, constructive algorithms, greedy, strings
Correct Solution:
```
#------------------------template--------------------------#
import os
import sys
from math import *
from collections import *
# from fractions import *
from heapq import*
from bisect import *
from io import BytesIO, IOBase... | output | 1 | 62,514 | 0 | 125,029 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given a string s consisting of lowercase English letters and a number k. Let's call a string consisting of lowercase English letters beautiful if the number of occurrences of each letter in that string is divisible by k. You are aske... | instruction | 0 | 62,515 | 0 | 125,030 |
Tags: binary search, brute force, constructive algorithms, greedy, strings
Correct Solution:
```
from bisect import *
from collections import *
from math import gcd,ceil,sqrt,floor,inf
from heapq import *
from itertools import *
from operator import add,mul,sub,xor,truediv,floordiv
from functools import *
#----------... | output | 1 | 62,515 | 0 | 125,031 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given a string s consisting of lowercase English letters and a number k. Let's call a string consisting of lowercase English letters beautiful if the number of occurrences of each letter in that string is divisible by k. You are aske... | instruction | 0 | 62,516 | 0 | 125,032 |
Tags: binary search, brute force, constructive algorithms, greedy, strings
Correct Solution:
```
"""
#If FastIO not needed, use this and don't forget to strip
#import sys, math
#input = sys.stdin.readline
"""
import os, sys, heapq as h, time
from io import BytesIO, IOBase
from types import GeneratorType
from bisect im... | output | 1 | 62,516 | 0 | 125,033 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given a string s consisting of lowercase English letters and a number k. Let's call a string consisting of lowercase English letters beautiful if the number of occurrences of each letter in that string is divisible by k. You are aske... | instruction | 0 | 62,517 | 0 | 125,034 |
Tags: binary search, brute force, constructive algorithms, greedy, strings
Correct Solution:
```
def solve():
for i in range(int(input())):
n, k = map(int, input().split());s = input().strip()
if k == 1:print(s);continue
if n % k != 0:print(-1);continue
want = [0]*26;need = 0;i = 0;best = -1;A = ord('a')
for... | output | 1 | 62,517 | 0 | 125,035 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given a string s consisting of lowercase English letters and a number k. Let's call a string consisting of lowercase English letters beautiful if the number of occurrences of each letter in that string is divisible by k. You are aske... | instruction | 0 | 62,518 | 0 | 125,036 |
Tags: binary search, brute force, constructive algorithms, greedy, strings
Correct Solution:
```
from collections import Counter
for _ in range(int(input())):
n, k = map(int, input().split())
s = input()
if n % k:
print(-1)
elif k == 1:
print(s)
else:
stat = Counter(s)
... | output | 1 | 62,518 | 0 | 125,037 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a string s consisting of lowercase English letters and a number k. Let's call a string consisting of lowercase English letters beautiful if the number of occurrences of each letter... | instruction | 0 | 62,519 | 0 | 125,038 |
Yes | output | 1 | 62,519 | 0 | 125,039 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a string s consisting of lowercase English letters and a number k. Let's call a string consisting of lowercase English letters beautiful if the number of occurrences of each letter... | instruction | 0 | 62,520 | 0 | 125,040 |
Yes | output | 1 | 62,520 | 0 | 125,041 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a string s consisting of lowercase English letters and a number k. Let's call a string consisting of lowercase English letters beautiful if the number of occurrences of each letter... | instruction | 0 | 62,521 | 0 | 125,042 |
Yes | output | 1 | 62,521 | 0 | 125,043 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a string s consisting of lowercase English letters and a number k. Let's call a string consisting of lowercase English letters beautiful if the number of occurrences of each letter... | instruction | 0 | 62,522 | 0 | 125,044 |
Yes | output | 1 | 62,522 | 0 | 125,045 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a string s consisting of lowercase English letters and a number k. Let's call a string consisting of lowercase English letters beautiful if the number of occurrences of each letter... | instruction | 0 | 62,523 | 0 | 125,046 |
No | output | 1 | 62,523 | 0 | 125,047 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a string s consisting of lowercase English letters and a number k. Let's call a string consisting of lowercase English letters beautiful if the number of occurrences of each letter... | instruction | 0 | 62,524 | 0 | 125,048 |
No | output | 1 | 62,524 | 0 | 125,049 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a string s consisting of lowercase English letters and a number k. Let's call a string consisting of lowercase English letters beautiful if the number of occurrences of each letter... | instruction | 0 | 62,525 | 0 | 125,050 |
No | output | 1 | 62,525 | 0 | 125,051 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a string s consisting of lowercase English letters and a number k. Let's call a string consisting of lowercase English letters beautiful if the number of occurrences of each letter... | instruction | 0 | 62,526 | 0 | 125,052 |
No | output | 1 | 62,526 | 0 | 125,053 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Given a string s, determine if it contains any palindrome of length exactly 100 as a subsequence. If it has any, print any one of them. If it doesn't have any, print a palindrome that is a subsequence of s and is as long as possible.
Input
... | instruction | 0 | 62,629 | 0 | 125,258 |
Tags: constructive algorithms, dp
Correct Solution:
```
def p2(a):
n = len(a)
last = [[-1] * 26 for _ in range(n)]
last[0][ord(a[0])-97] = 0
for i in range(1, n):
for j in range(26):
last[i][j] = last[i-1][j]
last[i][ord(a[i]) - 97] = i
dp = [''] * n
for i in range(n-... | output | 1 | 62,629 | 0 | 125,259 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Given a string s, determine if it contains any palindrome of length exactly 100 as a subsequence. If it has any, print any one of them. If it doesn't have any, print a palindrome that is a subsequence of s and is as long as possible.
Input
... | instruction | 0 | 62,630 | 0 | 125,260 |
Tags: constructive algorithms, dp
Correct Solution:
```
import sys
import math
def II():
return int(sys.stdin.readline())
def LI():
return list(map(int, sys.stdin.readline().split()))
def MI():
return map(int, sys.stdin.readline().split())
def SI():
return sys.stdin.readline().strip()
def FACT(n, mod):
s... | output | 1 | 62,630 | 0 | 125,261 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Given a string s, determine if it contains any palindrome of length exactly 100 as a subsequence. If it has any, print any one of them. If it doesn't have any, print a palindrome that is a subsequence of s and is as long as possible.
Input
... | instruction | 0 | 62,631 | 0 | 125,262 |
Tags: constructive algorithms, dp
Correct Solution:
```
from collections import defaultdict
s = input()
n = len(s)
if n >= 2600:
print(s[0] * 100)
elif n > 2574:
count = defaultdict(int)
for l in s:
count[l] += 1
max_l = s[0]
for l, c in count.items():
if c >= 100:
max_... | output | 1 | 62,631 | 0 | 125,263 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Given a string s, determine if it contains any palindrome of length exactly 100 as a subsequence. If it has any, print any one of them. If it doesn't have any, print a palindrome that is a subsequence of s and is as long as possible.
Input
... | instruction | 0 | 62,632 | 0 | 125,264 |
Tags: constructive algorithms, dp
Correct Solution:
```
def p2(a):
n = len(a)
last = [[0] * 26 for _ in range(n)]
last[0][ord(a[0])-97] = 0
for i in range(1, n):
for j in range(26):
last[i][j] = last[i-1][j]
last[i][ord(a[i])-97] = i
dp = [''] * n
for i in range(n-1, -1, -1):
for j in rang... | output | 1 | 62,632 | 0 | 125,265 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Given a string s, determine if it contains any palindrome of length exactly 100 as a subsequence. If it has any, print any one of them. If it doesn't have any, print a palindrome that is a subse... | instruction | 0 | 62,633 | 0 | 125,266 |
No | output | 1 | 62,633 | 0 | 125,267 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Given a string s, determine if it contains any palindrome of length exactly 100 as a subsequence. If it has any, print any one of them. If it doesn't have any, print a palindrome that is a subse... | instruction | 0 | 62,634 | 0 | 125,268 |
No | output | 1 | 62,634 | 0 | 125,269 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Given a string s, determine if it contains any palindrome of length exactly 100 as a subsequence. If it has any, print any one of them. If it doesn't have any, print a palindrome that is a subse... | instruction | 0 | 62,635 | 0 | 125,270 |
No | output | 1 | 62,635 | 0 | 125,271 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Given a string s, determine if it contains any palindrome of length exactly 100 as a subsequence. If it has any, print any one of them. If it doesn't have any, print a palindrome that is a subse... | instruction | 0 | 62,636 | 0 | 125,272 |
No | output | 1 | 62,636 | 0 | 125,273 |
Provide tags and a correct Python 3 solution for this coding contest problem.
We call a string good, if after merging all the consecutive equal characters, the resulting string is palindrome. For example, "aabba" is good, because after the merging step it will become "aba".
Given a string, you have to find two values... | instruction | 0 | 62,687 | 0 | 125,374 |
Tags: math
Correct Solution:
```
s = input()
odd = 0
even = 0
cntE = [0, 0]
cntO = [0, 0]
for i in range(len(s)):
cur = 0 + int(s[i] == 'b')
odd += 1
if i % 2 == 0:
odd += cntE[cur]
even += cntO[cur]
cntE[cur] += 1
else:
odd += cntO[cur]
even += cntE[cur]
... | output | 1 | 62,687 | 0 | 125,375 |
Provide tags and a correct Python 3 solution for this coding contest problem.
We call a string good, if after merging all the consecutive equal characters, the resulting string is palindrome. For example, "aabba" is good, because after the merging step it will become "aba".
Given a string, you have to find two values... | instruction | 0 | 62,688 | 0 | 125,376 |
Tags: math
Correct Solution:
```
def R(): return map(int, input().split())
def I(): return int(input())
def S(): return str(input())
def L(): return list(R())
from collections import Counter
import math
import sys
from itertools import permutations
import bisect
mod=10**9+7
#print(bisect.bisect_right([1,2,3],2... | output | 1 | 62,688 | 0 | 125,377 |
Provide tags and a correct Python 3 solution for this coding contest problem.
We call a string good, if after merging all the consecutive equal characters, the resulting string is palindrome. For example, "aabba" is good, because after the merging step it will become "aba".
Given a string, you have to find two values... | instruction | 0 | 62,689 | 0 | 125,378 |
Tags: math
Correct Solution:
```
s = input()
a = []
for c in s:
a.append(ord(c) - ord('a'))
cnt = [[0, 0], [0, 0]]
ans = [0, 0]
for i in range(len(a)):
cnt[a[i]][i % 2] += 1
ans[0] += cnt[a[i]][i % 2]
ans[1] += cnt[a[i]][1 - i % 2]
print(ans[1], ans[0])
``` | output | 1 | 62,689 | 0 | 125,379 |
Provide tags and a correct Python 3 solution for this coding contest problem.
We call a string good, if after merging all the consecutive equal characters, the resulting string is palindrome. For example, "aabba" is good, because after the merging step it will become "aba".
Given a string, you have to find two values... | instruction | 0 | 62,690 | 0 | 125,380 |
Tags: math
Correct Solution:
```
s = input()
cntodda = 0
cntoddb = 0
cntevena =0
cntevenb = 0
evencnt = 0
oddcnt = 0
for i in range(len(s)):
oddcnt += 1
if i%2 == 0:
if s[i]=='a':
evencnt += cntodda
oddcnt += cntevena
else:
evencnt += cntoddb
o... | output | 1 | 62,690 | 0 | 125,381 |
Provide tags and a correct Python 3 solution for this coding contest problem.
We call a string good, if after merging all the consecutive equal characters, the resulting string is palindrome. For example, "aabba" is good, because after the merging step it will become "aba".
Given a string, you have to find two values... | instruction | 0 | 62,691 | 0 | 125,382 |
Tags: math
Correct Solution:
```
cnt = [[0 for col in range(2)] for row in range(2)]
ans = [0 for col in range(2)]
strx = input()
length = len(strx)
for i in range(length):
if(strx[i]=='a'):
cnt[0][i & 1]=cnt[0][i & 1]+1
ans[0]+=cnt[0][i & 1 ^ 1]
ans[1]+=cnt[0][i & 1]
else:
cnt[1... | output | 1 | 62,691 | 0 | 125,383 |
Provide tags and a correct Python 3 solution for this coding contest problem.
We call a string good, if after merging all the consecutive equal characters, the resulting string is palindrome. For example, "aabba" is good, because after the merging step it will become "aba".
Given a string, you have to find two values... | instruction | 0 | 62,692 | 0 | 125,384 |
Tags: math
Correct Solution:
```
string=input()
length=len(string)
goodbad=[[1, 0, 0, 0] for x in range(length)]
#good odd
#bad odd
#good even
#bad even
for i in range(length-1):
if string[i]==string[i+1]:
goodbad[i+1][0]+=goodbad[i][2]
goodbad[i+1][2]+=goodbad[i][0]
goodbad[i+1][1]+=goodb... | output | 1 | 62,692 | 0 | 125,385 |
Provide tags and a correct Python 3 solution for this coding contest problem.
We call a string good, if after merging all the consecutive equal characters, the resulting string is palindrome. For example, "aabba" is good, because after the merging step it will become "aba".
Given a string, you have to find two values... | instruction | 0 | 62,693 | 0 | 125,386 |
Tags: math
Correct Solution:
```
import sys
input=sys.stdin.readline
s=input().rstrip()
n=len(s)
pos_a_odd=0
pos_a_even=0
pos_b_odd=0
pos_b_even=0
ans_even,ans_odd=0,0
for i in range(n):
if s[i]=="a":
if i%2:
pos_a_odd+=1
ans_odd+=pos_a_odd
ans_even+=pos_a_even
el... | output | 1 | 62,693 | 0 | 125,387 |
Provide tags and a correct Python 3 solution for this coding contest problem.
We call a string good, if after merging all the consecutive equal characters, the resulting string is palindrome. For example, "aabba" is good, because after the merging step it will become "aba".
Given a string, you have to find two values... | instruction | 0 | 62,694 | 0 | 125,388 |
Tags: math
Correct Solution:
```
s = input()
m = [2*[0] for _ in range(2)]
odd, even = 0, 0
for i in range(len(s)):
m[1 if s[i] == 'a' else 0][i % 2] += 1
odd += m[1 if s[i] == 'a' else 0][i % 2]
even += m[1 if s[i] == 'a' else 0][not (i % 2)]
print(even, odd)
``` | output | 1 | 62,694 | 0 | 125,389 |
Evaluate the correctness of the submitted Python 2 solution to the coding contest problem. Provide a "Yes" or "No" response.
We call a string good, if after merging all the consecutive equal characters, the resulting string is palindrome. For example, "aabba" is good, because after the merging step it will become "aba... | instruction | 0 | 62,695 | 0 | 125,390 |
Yes | output | 1 | 62,695 | 0 | 125,391 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
We call a string good, if after merging all the consecutive equal characters, the resulting string is palindrome. For example, "aabba" is good, because after the merging step it will become "aba... | instruction | 0 | 62,696 | 0 | 125,392 |
Yes | output | 1 | 62,696 | 0 | 125,393 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
We call a string good, if after merging all the consecutive equal characters, the resulting string is palindrome. For example, "aabba" is good, because after the merging step it will become "aba... | instruction | 0 | 62,697 | 0 | 125,394 |
Yes | output | 1 | 62,697 | 0 | 125,395 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
We call a string good, if after merging all the consecutive equal characters, the resulting string is palindrome. For example, "aabba" is good, because after the merging step it will become "aba... | instruction | 0 | 62,698 | 0 | 125,396 |
Yes | output | 1 | 62,698 | 0 | 125,397 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
We call a string good, if after merging all the consecutive equal characters, the resulting string is palindrome. For example, "aabba" is good, because after the merging step it will become "aba... | instruction | 0 | 62,699 | 0 | 125,398 |
Yes | output | 1 | 62,699 | 0 | 125,399 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
We call a string good, if after merging all the consecutive equal characters, the resulting string is palindrome. For example, "aabba" is good, because after the merging step it will become "aba... | instruction | 0 | 62,700 | 0 | 125,400 |
No | output | 1 | 62,700 | 0 | 125,401 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
We call a string good, if after merging all the consecutive equal characters, the resulting string is palindrome. For example, "aabba" is good, because after the merging step it will become "aba... | instruction | 0 | 62,701 | 0 | 125,402 |
No | output | 1 | 62,701 | 0 | 125,403 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
We call a string good, if after merging all the consecutive equal characters, the resulting string is palindrome. For example, "aabba" is good, because after the merging step it will become "aba... | instruction | 0 | 62,702 | 0 | 125,404 |
No | output | 1 | 62,702 | 0 | 125,405 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
We call a string good, if after merging all the consecutive equal characters, the resulting string is palindrome. For example, "aabba" is good, because after the merging step it will become "aba... | instruction | 0 | 62,703 | 0 | 125,406 |
No | output | 1 | 62,703 | 0 | 125,407 |
Provide tags and a correct Python 3 solution for this coding contest problem.
A string is binary, if it consists only of characters "0" and "1".
String v is a substring of string w if it has a non-zero length and can be read starting from some position in string w. For example, string "010" has six substrings: "0", "... | instruction | 0 | 63,402 | 0 | 126,804 |
Tags: binary search, brute force, dp, math, strings, two pointers
Correct Solution:
```
k=int(input())
s=input()
n=len(s)
i1=0
dp=[0]*(n)
cnt=0
ind=[0]
if k==0:
ocnt=0
ans=0
for i in range(n):
if s[i]=='0':
ocnt+=1
else:
ans += max((ocnt*(ocnt+1))//2,0)
... | output | 1 | 63,402 | 0 | 126,805 |
Provide tags and a correct Python 3 solution for this coding contest problem.
A string is binary, if it consists only of characters "0" and "1".
String v is a substring of string w if it has a non-zero length and can be read starting from some position in string w. For example, string "010" has six substrings: "0", "... | instruction | 0 | 63,403 | 0 | 126,806 |
Tags: binary search, brute force, dp, math, strings, two pointers
Correct Solution:
```
k = int(input())
d = [0]*1000001
d[0] = 1
s = 0
for c in input():
s += int(c)
d[s] += 1
res = 0
if k == 0:
for i in range(k, s+1):
res += (d[i]-1)*d[i]//2
else:
for i in range(k, s+1):
res += d[i]*d[i... | output | 1 | 63,403 | 0 | 126,807 |
Provide tags and a correct Python 3 solution for this coding contest problem.
A string is binary, if it consists only of characters "0" and "1".
String v is a substring of string w if it has a non-zero length and can be read starting from some position in string w. For example, string "010" has six substrings: "0", "... | instruction | 0 | 63,404 | 0 | 126,808 |
Tags: binary search, brute force, dp, math, strings, two pointers
Correct Solution:
```
n = int(input())
s = input()
a = [len(x)+1 for x in s.split('1')]
if n == 0:
print(sum(x *(x-1) // 2 for x in a))
else:
print(sum(a * b for (a, b) in zip(a, a[n:])))
``` | output | 1 | 63,404 | 0 | 126,809 |
Provide tags and a correct Python 3 solution for this coding contest problem.
A string is binary, if it consists only of characters "0" and "1".
String v is a substring of string w if it has a non-zero length and can be read starting from some position in string w. For example, string "010" has six substrings: "0", "... | instruction | 0 | 63,405 | 0 | 126,810 |
Tags: binary search, brute force, dp, math, strings, two pointers
Correct Solution:
```
import math,string,itertools,fractions,heapq,collections,re,array,bisect,sys,copy,functools
# import time,random,resource
# sys.setrecursionlimit(10**6)
inf = 10**20
eps = 1.0 / 10**10
mod = 10**9+7
mod2 = 998244353
dd = [(-1,0),(0... | output | 1 | 63,405 | 0 | 126,811 |
Provide tags and a correct Python 3 solution for this coding contest problem.
A string is binary, if it consists only of characters "0" and "1".
String v is a substring of string w if it has a non-zero length and can be read starting from some position in string w. For example, string "010" has six substrings: "0", "... | instruction | 0 | 63,406 | 0 | 126,812 |
Tags: binary search, brute force, dp, math, strings, two pointers
Correct Solution:
```
k=int(input())
s=input()
ans,z=0,0
dp=[1]+[0]*10**6
for c in s:
if c=='1':z+=1
if z>=k:ans+=dp[z-k]
dp[z]+=1
print(ans)
``` | output | 1 | 63,406 | 0 | 126,813 |
Provide tags and a correct Python 3 solution for this coding contest problem.
A string is binary, if it consists only of characters "0" and "1".
String v is a substring of string w if it has a non-zero length and can be read starting from some position in string w. For example, string "010" has six substrings: "0", "... | instruction | 0 | 63,407 | 0 | 126,814 |
Tags: binary search, brute force, dp, math, strings, two pointers
Correct Solution:
```
k = int(input())
s = input()
n = len(s)
a = [0]*n
dict = {}
count = 0
for i in range(n):
if s[i] == "1":
count+=1
if count in dict:
dict[count]+=1
else:
dict[count] = 1
# print(dict)
ans = 0
coun... | output | 1 | 63,407 | 0 | 126,815 |
Provide tags and a correct Python 3 solution for this coding contest problem.
A string is binary, if it consists only of characters "0" and "1".
String v is a substring of string w if it has a non-zero length and can be read starting from some position in string w. For example, string "010" has six substrings: "0", "... | instruction | 0 | 63,408 | 0 | 126,816 |
Tags: binary search, brute force, dp, math, strings, two pointers
Correct Solution:
```
k = int(input())
s= (input())
n = len(s)
count = [0]*(n+1)
count[0]+=1
ini = 0
if(k==0):
ans =0
ini =0
s= s+"1"
for i in range(n+1):
if( s[i] == "1"):
ans =ans+ ini*(ini+1)//2
ini... | output | 1 | 63,408 | 0 | 126,817 |
Provide tags and a correct Python 3 solution for this coding contest problem.
A string is binary, if it consists only of characters "0" and "1".
String v is a substring of string w if it has a non-zero length and can be read starting from some position in string w. For example, string "010" has six substrings: "0", "... | instruction | 0 | 63,409 | 0 | 126,818 |
Tags: binary search, brute force, dp, math, strings, two pointers
Correct Solution:
```
import sys
input=sys.stdin.readline
a=int(input())
s=input()
ans=[]
count=0
for i in range(len(s)):
if(s[i]=='0'):
count+=1
else:
ans.append(count)
count=0
ans.append(count)
if(a==0):
total=0
... | output | 1 | 63,409 | 0 | 126,819 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A string is binary, if it consists only of characters "0" and "1".
String v is a substring of string w if it has a non-zero length and can be read starting from some position in string w. For e... | instruction | 0 | 63,410 | 0 | 126,820 |
Yes | output | 1 | 63,410 | 0 | 126,821 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A string is binary, if it consists only of characters "0" and "1".
String v is a substring of string w if it has a non-zero length and can be read starting from some position in string w. For e... | instruction | 0 | 63,411 | 0 | 126,822 |
Yes | output | 1 | 63,411 | 0 | 126,823 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A string is binary, if it consists only of characters "0" and "1".
String v is a substring of string w if it has a non-zero length and can be read starting from some position in string w. For e... | instruction | 0 | 63,412 | 0 | 126,824 |
Yes | output | 1 | 63,412 | 0 | 126,825 |
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