message stringlengths 2 23.8k | message_type stringclasses 2 values | message_id int64 0 1 | conversation_id int64 97 109k | cluster float64 0 0 | __index_level_0__ int64 194 217k |
|---|---|---|---|---|---|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A bitstring is a string that contains only the characters 0 and 1.
Koyomi Kanou is working hard towards her dream of becoming a writer. To practice, she decided to participate in the Binary Novel Writing Contest. The writing prompt for the contest consists of three bitstrings of length 2n. A valid novel for the contest is a bitstring of length at most 3n that contains at least two of the three given strings as subsequences.
Koyomi has just received the three prompt strings from the contest organizers. Help her write a valid novel for the contest.
A string a is a subsequence of a string b if a can be obtained from b by deletion of several (possibly, zero) characters.
Input
The first line contains a single integer t (1 ≤ t ≤ 10^4) — the number of test cases.
The first line of each test case contains a single integer n (1 ≤ n ≤ 10^5).
Each of the following three lines contains a bitstring of length 2n. It is guaranteed that these three strings are pairwise distinct.
It is guaranteed that the sum of n across all test cases does not exceed 10^5.
Output
For each test case, print a single line containing a bitstring of length at most 3n that has at least two of the given bitstrings as subsequences.
It can be proven that under the constraints of the problem, such a bitstring always exists.
If there are multiple possible answers, you may output any of them.
Example
Input
2
1
00
11
01
3
011001
111010
010001
Output
010
011001010
Note
In the first test case, the bitstrings 00 and 01 are subsequences of the output string: 010 and 010. Note that 11 is not a subsequence of the output string, but this is not required.
In the second test case all three input strings are subsequences of the output string: 011001010, 011001010 and 011001010.
Submitted Solution:
```
import sys
from sys import stdin
def solve(a,b,X):
ans = []
ca = [a[i] for i in range(len(a))]
cb = [b[i] for i in range(len(b))]
while len(ca) > 0 and len(cb) > 0:
if len(cb) == 0:
ans.append(ca[-1])
del ca[-1]
elif len(ca) == 0:
ans.append(cb[-1])
del cb[-1]
elif ca[-1] == cb[-1]:
ans.append(ca[-1])
del ca[-1]
del cb[-1]
else:
ans.append(X)
if ca[-1] == X:
del ca[-1]
else:
del cb[-1]
while len(ans) < 3*n:
ans.append("0")
ans.reverse()
return "".join(ans)
tt = int(stdin.readline())
for loop in range(tt):
n = int(stdin.readline())
s = [stdin.readline()[:-1] for i in range(3)]
lis = []
for i in range(3):
one = 0
zero = 0
for j in s[i]:
if j == "0":
zero += 1
else:
one += 1
if one < zero:
lis.append("1")
else:
lis.append("0")
flag = True
for i in range(3):
for j in range(i):
if lis[i] == lis[j] and flag:
print (solve(s[i],s[j],lis[i]))
flag = False
``` | instruction | 0 | 91,971 | 0 | 183,942 |
No | output | 1 | 91,971 | 0 | 183,943 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A bitstring is a string that contains only the characters 0 and 1.
Koyomi Kanou is working hard towards her dream of becoming a writer. To practice, she decided to participate in the Binary Novel Writing Contest. The writing prompt for the contest consists of three bitstrings of length 2n. A valid novel for the contest is a bitstring of length at most 3n that contains at least two of the three given strings as subsequences.
Koyomi has just received the three prompt strings from the contest organizers. Help her write a valid novel for the contest.
A string a is a subsequence of a string b if a can be obtained from b by deletion of several (possibly, zero) characters.
Input
The first line contains a single integer t (1 ≤ t ≤ 10^4) — the number of test cases.
The first line of each test case contains a single integer n (1 ≤ n ≤ 10^5).
Each of the following three lines contains a bitstring of length 2n. It is guaranteed that these three strings are pairwise distinct.
It is guaranteed that the sum of n across all test cases does not exceed 10^5.
Output
For each test case, print a single line containing a bitstring of length at most 3n that has at least two of the given bitstrings as subsequences.
It can be proven that under the constraints of the problem, such a bitstring always exists.
If there are multiple possible answers, you may output any of them.
Example
Input
2
1
00
11
01
3
011001
111010
010001
Output
010
011001010
Note
In the first test case, the bitstrings 00 and 01 are subsequences of the output string: 010 and 010. Note that 11 is not a subsequence of the output string, but this is not required.
In the second test case all three input strings are subsequences of the output string: 011001010, 011001010 and 011001010.
Submitted Solution:
```
tc = int(input())
for i in range(tc):
n = int(input())
s = [input() for _ in range(3)]
p = [0]*3
ans = ""
while True:
ones = []
zeroes = []
for i in range(3):
if p[i] == 2*n:
continue
if s[i][p[i]] == '1':
ones.append(i)
else:
zeroes.append(i)
if len(ones) > len(zeroes):
ans += '1'
for i in ones:
p[i] += 1
else:
ans += '0'
for i in zeroes:
p[i] += 1
if ((p[0] == 2*n) + (p[1] == 2*n) + (p[2] == 2*n)) >= 2:
break
print(ans)
#3 pointer trick in comments
``` | instruction | 0 | 91,972 | 0 | 183,944 |
No | output | 1 | 91,972 | 0 | 183,945 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A bitstring is a string that contains only the characters 0 and 1.
Koyomi Kanou is working hard towards her dream of becoming a writer. To practice, she decided to participate in the Binary Novel Writing Contest. The writing prompt for the contest consists of three bitstrings of length 2n. A valid novel for the contest is a bitstring of length at most 3n that contains at least two of the three given strings as subsequences.
Koyomi has just received the three prompt strings from the contest organizers. Help her write a valid novel for the contest.
A string a is a subsequence of a string b if a can be obtained from b by deletion of several (possibly, zero) characters.
Input
The first line contains a single integer t (1 ≤ t ≤ 10^4) — the number of test cases.
The first line of each test case contains a single integer n (1 ≤ n ≤ 10^5).
Each of the following three lines contains a bitstring of length 2n. It is guaranteed that these three strings are pairwise distinct.
It is guaranteed that the sum of n across all test cases does not exceed 10^5.
Output
For each test case, print a single line containing a bitstring of length at most 3n that has at least two of the given bitstrings as subsequences.
It can be proven that under the constraints of the problem, such a bitstring always exists.
If there are multiple possible answers, you may output any of them.
Example
Input
2
1
00
11
01
3
011001
111010
010001
Output
010
011001010
Note
In the first test case, the bitstrings 00 and 01 are subsequences of the output string: 010 and 010. Note that 11 is not a subsequence of the output string, but this is not required.
In the second test case all three input strings are subsequences of the output string: 011001010, 011001010 and 011001010.
Submitted Solution:
```
def sol(val,a,b):
i = 0;
j = 0;
f = 0;
while (j <len(b)):
z = val.find(b[j], i, len(val))
if z != -1:
i = z + 1
else:
return 1
break
j += 1
print(val)
for i in range(int(input())):
n=int(input())
a=input()
b=input()
c=input()
k=n*(3-2)
d=a
val=a[:]+b[-k:]
val1=a[:]+c[-k:]
val2=b[:]+c[-k:]
w=sol(val,a,b)
if w==1:
w=sol(val1,a,c)
elif w==1:
sol(val2,b,c)
``` | instruction | 0 | 91,973 | 0 | 183,946 |
No | output | 1 | 91,973 | 0 | 183,947 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A bitstring is a string that contains only the characters 0 and 1.
Koyomi Kanou is working hard towards her dream of becoming a writer. To practice, she decided to participate in the Binary Novel Writing Contest. The writing prompt for the contest consists of three bitstrings of length 2n. A valid novel for the contest is a bitstring of length at most 3n that contains at least two of the three given strings as subsequences.
Koyomi has just received the three prompt strings from the contest organizers. Help her write a valid novel for the contest.
A string a is a subsequence of a string b if a can be obtained from b by deletion of several (possibly, zero) characters.
Input
The first line contains a single integer t (1 ≤ t ≤ 10^4) — the number of test cases.
The first line of each test case contains a single integer n (1 ≤ n ≤ 10^5).
Each of the following three lines contains a bitstring of length 2n. It is guaranteed that these three strings are pairwise distinct.
It is guaranteed that the sum of n across all test cases does not exceed 10^5.
Output
For each test case, print a single line containing a bitstring of length at most 3n that has at least two of the given bitstrings as subsequences.
It can be proven that under the constraints of the problem, such a bitstring always exists.
If there are multiple possible answers, you may output any of them.
Example
Input
2
1
00
11
01
3
011001
111010
010001
Output
010
011001010
Note
In the first test case, the bitstrings 00 and 01 are subsequences of the output string: 010 and 010. Note that 11 is not a subsequence of the output string, but this is not required.
In the second test case all three input strings are subsequences of the output string: 011001010, 011001010 and 011001010.
Submitted Solution:
```
from sys import stdin, stdout
def count(s):
return sum(1 for c in s if c == '1')
def build(s1, s2, m):
i1 = 0
i2 = 0
answer = ''
while i1 < len(s1) and i2 < len(s2):
if s1[i1] == s2[i2]:
answer += s1[i1]
i1 += 1
i2 += 1
elif s1[i1] != m:
answer += s1[i1]
i1 += 1
else:
answer += s2[i2]
i2 += 1
return answer + s1[i1:] + s2[i2:]
n = int(stdin.readline())
for _ in range(n):
k = int(stdin.readline())
a = stdin.readline().strip()
b = stdin.readline().strip()
c = stdin.readline().strip()
arr0 = []
arr1 = []
for s in [a, b, c]:
if count(s) >= k:
arr1.append(s)
else:
arr0.append(s)
if len(arr0) > 1:
stdout.write(build(arr0[0], arr0[1], '0'))
else:
stdout.write(build(arr1[0], arr1[1], '1'))
``` | instruction | 0 | 91,974 | 0 | 183,948 |
No | output | 1 | 91,974 | 0 | 183,949 |
Provide a correct Python 3 solution for this coding contest problem.
Alice likes word "nineteen" very much. She has a string s and wants the string to contain as many such words as possible. For that reason she can rearrange the letters of the string.
For example, if she has string "xiineteenppnnnewtnee", she can get string "xnineteenppnineteenw", containing (the occurrences marked) two such words. More formally, word "nineteen" occurs in the string the number of times you can read it starting from some letter of the string. Of course, you shouldn't skip letters.
Help her to find the maximum number of "nineteen"s that she can get in her string.
Input
The first line contains a non-empty string s, consisting only of lowercase English letters. The length of string s doesn't exceed 100.
Output
Print a single integer — the maximum number of "nineteen"s that she can get in her string.
Examples
Input
nniinneetteeeenn
Output
2
Input
nneteenabcnneteenabcnneteenabcnneteenabcnneteenabcii
Output
2
Input
nineteenineteen
Output
2 | instruction | 0 | 92,098 | 0 | 184,196 |
"Correct Solution:
```
s=input('')
count=0
n=0;i=0;e=0;t=0;
for j in s:
if(j=='n'):
n+=1
elif(j=='i'):
i+=1
elif(j=='e'):
e+=1
elif(j=='t'):
t+=1
# print(n,i,t,e)
if(n>=3 and i>=1 and t>=1 and e>=3):
c=True
n=n-3;
i=i-1
t=t-1
e=e-3
count+=1
while(c!=False):
n=n-2;
i=i-1
t=t-1
e=e-3
if(n<0 or i<0 or t<0 or e<0):
c=False
else:
# print(n,i,t,e)
count+=1
print(count)
``` | output | 1 | 92,098 | 0 | 184,197 |
Provide a correct Python 3 solution for this coding contest problem.
Alice likes word "nineteen" very much. She has a string s and wants the string to contain as many such words as possible. For that reason she can rearrange the letters of the string.
For example, if she has string "xiineteenppnnnewtnee", she can get string "xnineteenppnineteenw", containing (the occurrences marked) two such words. More formally, word "nineteen" occurs in the string the number of times you can read it starting from some letter of the string. Of course, you shouldn't skip letters.
Help her to find the maximum number of "nineteen"s that she can get in her string.
Input
The first line contains a non-empty string s, consisting only of lowercase English letters. The length of string s doesn't exceed 100.
Output
Print a single integer — the maximum number of "nineteen"s that she can get in her string.
Examples
Input
nniinneetteeeenn
Output
2
Input
nneteenabcnneteenabcnneteenabcnneteenabcnneteenabcii
Output
2
Input
nineteenineteen
Output
2 | instruction | 0 | 92,099 | 0 | 184,198 |
"Correct Solution:
```
#With Me
s= input().count
print(max(0, min((s("n")-1)//2, s("i"), s("e")//3, s("t"))))
``` | output | 1 | 92,099 | 0 | 184,199 |
Provide a correct Python 3 solution for this coding contest problem.
Alice likes word "nineteen" very much. She has a string s and wants the string to contain as many such words as possible. For that reason she can rearrange the letters of the string.
For example, if she has string "xiineteenppnnnewtnee", she can get string "xnineteenppnineteenw", containing (the occurrences marked) two such words. More formally, word "nineteen" occurs in the string the number of times you can read it starting from some letter of the string. Of course, you shouldn't skip letters.
Help her to find the maximum number of "nineteen"s that she can get in her string.
Input
The first line contains a non-empty string s, consisting only of lowercase English letters. The length of string s doesn't exceed 100.
Output
Print a single integer — the maximum number of "nineteen"s that she can get in her string.
Examples
Input
nniinneetteeeenn
Output
2
Input
nneteenabcnneteenabcnneteenabcnneteenabcnneteenabcii
Output
2
Input
nineteenineteen
Output
2 | instruction | 0 | 92,100 | 0 | 184,200 |
"Correct Solution:
```
s = input()
d = {}
for i in s:
if i in d.keys():
d[i] += 1
else:
d[i] = 1
if "n" not in d.keys() or "i" not in d.keys() or "e" not in d.keys() or "t" not in d.keys():
print(0)
else:
x = min(d["i"] , d["t"])
y = min((d["n"] - 1) // 2 , d["e"] // 3)
print(min(x , y))
``` | output | 1 | 92,100 | 0 | 184,201 |
Provide a correct Python 3 solution for this coding contest problem.
Alice likes word "nineteen" very much. She has a string s and wants the string to contain as many such words as possible. For that reason she can rearrange the letters of the string.
For example, if she has string "xiineteenppnnnewtnee", she can get string "xnineteenppnineteenw", containing (the occurrences marked) two such words. More formally, word "nineteen" occurs in the string the number of times you can read it starting from some letter of the string. Of course, you shouldn't skip letters.
Help her to find the maximum number of "nineteen"s that she can get in her string.
Input
The first line contains a non-empty string s, consisting only of lowercase English letters. The length of string s doesn't exceed 100.
Output
Print a single integer — the maximum number of "nineteen"s that she can get in her string.
Examples
Input
nniinneetteeeenn
Output
2
Input
nneteenabcnneteenabcnneteenabcnneteenabcnneteenabcii
Output
2
Input
nineteenineteen
Output
2 | instruction | 0 | 92,101 | 0 | 184,202 |
"Correct Solution:
```
word = input()
if word.count('n') > 1:
ns = 1 + (word.count('n') - 3) // 2
else:
ns = 0
lst = [ns, word.count('e') // 3, word.count('i'), word.count('t')]
print(min(lst))
``` | output | 1 | 92,101 | 0 | 184,203 |
Provide a correct Python 3 solution for this coding contest problem.
Alice likes word "nineteen" very much. She has a string s and wants the string to contain as many such words as possible. For that reason she can rearrange the letters of the string.
For example, if she has string "xiineteenppnnnewtnee", she can get string "xnineteenppnineteenw", containing (the occurrences marked) two such words. More formally, word "nineteen" occurs in the string the number of times you can read it starting from some letter of the string. Of course, you shouldn't skip letters.
Help her to find the maximum number of "nineteen"s that she can get in her string.
Input
The first line contains a non-empty string s, consisting only of lowercase English letters. The length of string s doesn't exceed 100.
Output
Print a single integer — the maximum number of "nineteen"s that she can get in her string.
Examples
Input
nniinneetteeeenn
Output
2
Input
nneteenabcnneteenabcnneteenabcnneteenabcnneteenabcii
Output
2
Input
nineteenineteen
Output
2 | instruction | 0 | 92,102 | 0 | 184,204 |
"Correct Solution:
```
s=input()
vl={"n":-1,"i":0,"e":0,"t":0}
for i in s:
if i in vl:
vl[i]+=1
vl["e"]/=3
vl["n"]/=2
m=100000
for i in vl.values():
m=min(m,i)
print(int(m))
``` | output | 1 | 92,102 | 0 | 184,205 |
Provide a correct Python 3 solution for this coding contest problem.
Alice likes word "nineteen" very much. She has a string s and wants the string to contain as many such words as possible. For that reason she can rearrange the letters of the string.
For example, if she has string "xiineteenppnnnewtnee", she can get string "xnineteenppnineteenw", containing (the occurrences marked) two such words. More formally, word "nineteen" occurs in the string the number of times you can read it starting from some letter of the string. Of course, you shouldn't skip letters.
Help her to find the maximum number of "nineteen"s that she can get in her string.
Input
The first line contains a non-empty string s, consisting only of lowercase English letters. The length of string s doesn't exceed 100.
Output
Print a single integer — the maximum number of "nineteen"s that she can get in her string.
Examples
Input
nniinneetteeeenn
Output
2
Input
nneteenabcnneteenabcnneteenabcnneteenabcnneteenabcii
Output
2
Input
nineteenineteen
Output
2 | instruction | 0 | 92,103 | 0 | 184,206 |
"Correct Solution:
```
import sys
s = input().strip()
inpDict = {}
for c in s:
inpDict[c] = inpDict.get(c,0) + 1
nn = "nineteen"
nDict = {}
for c in nn:
nDict[c] = nDict.get(c,0) + 1
m = sys.maxsize
for c in nDict.keys():
if(c != 'n'):
m = min(m, inpDict.get(c,0)//nDict[c])
if((inpDict.get('n',0)-1)//2 >= m):
if(m>=0):
print(m)
else:
print(0)
else:
x = (inpDict.get('n',0)-1)//2
if(x>=0):
print(x)
else:
print(0)
``` | output | 1 | 92,103 | 0 | 184,207 |
Provide a correct Python 3 solution for this coding contest problem.
Alice likes word "nineteen" very much. She has a string s and wants the string to contain as many such words as possible. For that reason she can rearrange the letters of the string.
For example, if she has string "xiineteenppnnnewtnee", she can get string "xnineteenppnineteenw", containing (the occurrences marked) two such words. More formally, word "nineteen" occurs in the string the number of times you can read it starting from some letter of the string. Of course, you shouldn't skip letters.
Help her to find the maximum number of "nineteen"s that she can get in her string.
Input
The first line contains a non-empty string s, consisting only of lowercase English letters. The length of string s doesn't exceed 100.
Output
Print a single integer — the maximum number of "nineteen"s that she can get in her string.
Examples
Input
nniinneetteeeenn
Output
2
Input
nneteenabcnneteenabcnneteenabcnneteenabcnneteenabcii
Output
2
Input
nineteenineteen
Output
2 | instruction | 0 | 92,104 | 0 | 184,208 |
"Correct Solution:
```
entrada=input()
n=0
e=0
i=0
t=0
for k in range (len(entrada)):
if entrada[k]=="n":
n+=1
if entrada[k]=="e":
e+=1
if entrada[k]=="i":
i+=1
if entrada[k]=="t":
t+=1
if n%2==0:
n-=1
n=((n-3)//2)+1
if n==-1:
n=0
e=e//3
def fmenor(a,b,c,d):
menor:None
if a<=b and a<=c and a<=d:
menor=a
elif b<=a and b<=c and b<=d:
menor=b
elif c<=d and c<=a and c<=b:
menor=c
else:
menor=d
return menor
print(fmenor(n,e,i,t))
``` | output | 1 | 92,104 | 0 | 184,209 |
Provide a correct Python 3 solution for this coding contest problem.
Alice likes word "nineteen" very much. She has a string s and wants the string to contain as many such words as possible. For that reason she can rearrange the letters of the string.
For example, if she has string "xiineteenppnnnewtnee", she can get string "xnineteenppnineteenw", containing (the occurrences marked) two such words. More formally, word "nineteen" occurs in the string the number of times you can read it starting from some letter of the string. Of course, you shouldn't skip letters.
Help her to find the maximum number of "nineteen"s that she can get in her string.
Input
The first line contains a non-empty string s, consisting only of lowercase English letters. The length of string s doesn't exceed 100.
Output
Print a single integer — the maximum number of "nineteen"s that she can get in her string.
Examples
Input
nniinneetteeeenn
Output
2
Input
nneteenabcnneteenabcnneteenabcnneteenabcnneteenabcii
Output
2
Input
nineteenineteen
Output
2 | instruction | 0 | 92,105 | 0 | 184,210 |
"Correct Solution:
```
str = list(input())
cntN = max((str.count('n') - 3) // 2 + 1, 0)
cntI = max(str.count('i') // 1, 0)
cntE = max(str.count('e') // 3, 0)
cntT = max(str.count('t') // 1, 0)
print(min(cntN, cntI, cntE, cntT))
``` | output | 1 | 92,105 | 0 | 184,211 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Alice likes word "nineteen" very much. She has a string s and wants the string to contain as many such words as possible. For that reason she can rearrange the letters of the string.
For example, if she has string "xiineteenppnnnewtnee", she can get string "xnineteenppnineteenw", containing (the occurrences marked) two such words. More formally, word "nineteen" occurs in the string the number of times you can read it starting from some letter of the string. Of course, you shouldn't skip letters.
Help her to find the maximum number of "nineteen"s that she can get in her string.
Input
The first line contains a non-empty string s, consisting only of lowercase English letters. The length of string s doesn't exceed 100.
Output
Print a single integer — the maximum number of "nineteen"s that she can get in her string.
Examples
Input
nniinneetteeeenn
Output
2
Input
nneteenabcnneteenabcnneteenabcnneteenabcnneteenabcii
Output
2
Input
nineteenineteen
Output
2
Submitted Solution:
```
n,c=input(),0
nc=n.count('n')
#print(nc)
if(nc>=3):
c=1
nc-=3
print(min(nc//2+c,n.count('i'),n.count('t'),n.count('e')//3))
else:
print('0')
``` | instruction | 0 | 92,106 | 0 | 184,212 |
Yes | output | 1 | 92,106 | 0 | 184,213 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Alice likes word "nineteen" very much. She has a string s and wants the string to contain as many such words as possible. For that reason she can rearrange the letters of the string.
For example, if she has string "xiineteenppnnnewtnee", she can get string "xnineteenppnineteenw", containing (the occurrences marked) two such words. More formally, word "nineteen" occurs in the string the number of times you can read it starting from some letter of the string. Of course, you shouldn't skip letters.
Help her to find the maximum number of "nineteen"s that she can get in her string.
Input
The first line contains a non-empty string s, consisting only of lowercase English letters. The length of string s doesn't exceed 100.
Output
Print a single integer — the maximum number of "nineteen"s that she can get in her string.
Examples
Input
nniinneetteeeenn
Output
2
Input
nneteenabcnneteenabcnneteenabcnneteenabcnneteenabcii
Output
2
Input
nineteenineteen
Output
2
Submitted Solution:
```
from collections import Counter
s = input()
a = Counter('nineteen')
c = Counter(s)
set_ = {'n', 'i', 'e', 't'}
ans = 100
for el in set_:
if el != 'n':
ans = min(ans, s.count(el) // a[el])
else:
ans = min(ans, max(0, (s.count('n') - 1) // 2))
print(ans)
``` | instruction | 0 | 92,107 | 0 | 184,214 |
Yes | output | 1 | 92,107 | 0 | 184,215 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Alice likes word "nineteen" very much. She has a string s and wants the string to contain as many such words as possible. For that reason she can rearrange the letters of the string.
For example, if she has string "xiineteenppnnnewtnee", she can get string "xnineteenppnineteenw", containing (the occurrences marked) two such words. More formally, word "nineteen" occurs in the string the number of times you can read it starting from some letter of the string. Of course, you shouldn't skip letters.
Help her to find the maximum number of "nineteen"s that she can get in her string.
Input
The first line contains a non-empty string s, consisting only of lowercase English letters. The length of string s doesn't exceed 100.
Output
Print a single integer — the maximum number of "nineteen"s that she can get in her string.
Examples
Input
nniinneetteeeenn
Output
2
Input
nneteenabcnneteenabcnneteenabcnneteenabcnneteenabcii
Output
2
Input
nineteenineteen
Output
2
Submitted Solution:
```
import math
s = input()
n_count = s.count("n")
e_count = s.count("e")
n = math.floor((n_count - 1) / 2)
e = math.floor(e_count/3)
i = s.count("i")
t = s.count("t")
print(max(min(n,i,t,e),0))
``` | instruction | 0 | 92,108 | 0 | 184,216 |
Yes | output | 1 | 92,108 | 0 | 184,217 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Alice likes word "nineteen" very much. She has a string s and wants the string to contain as many such words as possible. For that reason she can rearrange the letters of the string.
For example, if she has string "xiineteenppnnnewtnee", she can get string "xnineteenppnineteenw", containing (the occurrences marked) two such words. More formally, word "nineteen" occurs in the string the number of times you can read it starting from some letter of the string. Of course, you shouldn't skip letters.
Help her to find the maximum number of "nineteen"s that she can get in her string.
Input
The first line contains a non-empty string s, consisting only of lowercase English letters. The length of string s doesn't exceed 100.
Output
Print a single integer — the maximum number of "nineteen"s that she can get in her string.
Examples
Input
nniinneetteeeenn
Output
2
Input
nneteenabcnneteenabcnneteenabcnneteenabcnneteenabcii
Output
2
Input
nineteenineteen
Output
2
Submitted Solution:
```
from typing import Dict
#nineteen
def count_9teen(string : str) -> int:
if len(string) < 8:
return 0
count = 0
letter_count = init_9teen_counter()
original_count = get_9teen_letter_count()
for c in string:
if c in letter_count:
letter_count[c] = letter_count[c] + 1
counts = [letter_count[c]//original_count[c] for c in 'iet']
if letter_count['n'] >= 3:
counts.append( 1+ (letter_count['n']-3)//2)
else:
counts.append(0)
return min(counts)
def init_9teen_counter() -> Dict[chr, int]:
letter_count = {}
letter_count['i'] = 0
letter_count['n'] = 0
letter_count['e'] = 0
letter_count['t'] = 0
return letter_count
def get_9teen_letter_count()-> Dict[chr, int]:
letter_count={}
letter_count['i'] = 1
letter_count['n'] = 3
letter_count['e'] = 3
letter_count['t'] = 1
return letter_count
if __name__ =='__main__':
string = input()
print(count_9teen(string))
``` | instruction | 0 | 92,109 | 0 | 184,218 |
Yes | output | 1 | 92,109 | 0 | 184,219 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Alice likes word "nineteen" very much. She has a string s and wants the string to contain as many such words as possible. For that reason she can rearrange the letters of the string.
For example, if she has string "xiineteenppnnnewtnee", she can get string "xnineteenppnineteenw", containing (the occurrences marked) two such words. More formally, word "nineteen" occurs in the string the number of times you can read it starting from some letter of the string. Of course, you shouldn't skip letters.
Help her to find the maximum number of "nineteen"s that she can get in her string.
Input
The first line contains a non-empty string s, consisting only of lowercase English letters. The length of string s doesn't exceed 100.
Output
Print a single integer — the maximum number of "nineteen"s that she can get in her string.
Examples
Input
nniinneetteeeenn
Output
2
Input
nneteenabcnneteenabcnneteenabcnneteenabcnneteenabcii
Output
2
Input
nineteenineteen
Output
2
Submitted Solution:
```
x=input()
c=["n","i","e","t"]
z=[0,0,0,0]
v=0
for i in x:
if i==c[0]:
z[0]=z[0]+1
elif i==c[1]:
z[1]=z[1]+1
elif i==c[2]:
z[2]=z[2]+1
elif i==c[3]:
z[3]=z[3]+1
if z[0]%2!=0 and z[0]!=1:
z[0]=z[0]
while True:
z[1]=z[1]-1
z[2]=z[2]-3
z[3]=z[3]-1
if z[1]<0 or z[2]<0 or z[3]<0 or z[0]<3 :
break
else:
v=v+1
print(v)
``` | instruction | 0 | 92,110 | 0 | 184,220 |
No | output | 1 | 92,110 | 0 | 184,221 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Alice likes word "nineteen" very much. She has a string s and wants the string to contain as many such words as possible. For that reason she can rearrange the letters of the string.
For example, if she has string "xiineteenppnnnewtnee", she can get string "xnineteenppnineteenw", containing (the occurrences marked) two such words. More formally, word "nineteen" occurs in the string the number of times you can read it starting from some letter of the string. Of course, you shouldn't skip letters.
Help her to find the maximum number of "nineteen"s that she can get in her string.
Input
The first line contains a non-empty string s, consisting only of lowercase English letters. The length of string s doesn't exceed 100.
Output
Print a single integer — the maximum number of "nineteen"s that she can get in her string.
Examples
Input
nniinneetteeeenn
Output
2
Input
nneteenabcnneteenabcnneteenabcnneteenabcnneteenabcii
Output
2
Input
nineteenineteen
Output
2
Submitted Solution:
```
s=input()
n = s.count('n')
i = s.count('i')
e = s.count('e')
t = s.count('t')
#print(str(n)+" "+str(i)+" "+str(e)+" "+str(t))
if e-n==1:
n=e
if i<1 or n<3 or e<3 or t<1:
print(0)
else:
x = min(n,e)
y = min(i,t)
if x<y:
y = min(i,t,3)
#print(z)
for j in range(y,0,-1):
if 3*j<=x:
print(int(j))
break
``` | instruction | 0 | 92,111 | 0 | 184,222 |
No | output | 1 | 92,111 | 0 | 184,223 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Alice likes word "nineteen" very much. She has a string s and wants the string to contain as many such words as possible. For that reason she can rearrange the letters of the string.
For example, if she has string "xiineteenppnnnewtnee", she can get string "xnineteenppnineteenw", containing (the occurrences marked) two such words. More formally, word "nineteen" occurs in the string the number of times you can read it starting from some letter of the string. Of course, you shouldn't skip letters.
Help her to find the maximum number of "nineteen"s that she can get in her string.
Input
The first line contains a non-empty string s, consisting only of lowercase English letters. The length of string s doesn't exceed 100.
Output
Print a single integer — the maximum number of "nineteen"s that she can get in her string.
Examples
Input
nniinneetteeeenn
Output
2
Input
nneteenabcnneteenabcnneteenabcnneteenabcnneteenabcii
Output
2
Input
nineteenineteen
Output
2
Submitted Solution:
```
s = str(input())
nn = 0
ii = 0
ee = 0
tt = 0
for i in range(0,len(s)):
if s[i] == 'i':
ii += 1
elif s[i] == 'n':
nn += 1
elif s[i] == 'e':
ee += 1
elif s[i] == 't':
tt += 1
nn //= 3
ee //= 3
print(min(nn, min(ii, min(ee, tt))));
``` | instruction | 0 | 92,112 | 0 | 184,224 |
No | output | 1 | 92,112 | 0 | 184,225 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Alice likes word "nineteen" very much. She has a string s and wants the string to contain as many such words as possible. For that reason she can rearrange the letters of the string.
For example, if she has string "xiineteenppnnnewtnee", she can get string "xnineteenppnineteenw", containing (the occurrences marked) two such words. More formally, word "nineteen" occurs in the string the number of times you can read it starting from some letter of the string. Of course, you shouldn't skip letters.
Help her to find the maximum number of "nineteen"s that she can get in her string.
Input
The first line contains a non-empty string s, consisting only of lowercase English letters. The length of string s doesn't exceed 100.
Output
Print a single integer — the maximum number of "nineteen"s that she can get in her string.
Examples
Input
nniinneetteeeenn
Output
2
Input
nneteenabcnneteenabcnneteenabcnneteenabcnneteenabcii
Output
2
Input
nineteenineteen
Output
2
Submitted Solution:
```
# -*- coding: utf-8 -*-
"""
Created on Mon Nov 25 18:57:03 2019
@author: Lenovo
"""
al=['n','i','e','t']
ac=[3,1,3,1]
cl=[]
str=input()
for i in range(len(al)):
ca=(str.count(al[i]))
if ca%3==2 and i==0:
ca+=1
cl.append(ca//ac[i])
print(min(cl))
``` | instruction | 0 | 92,113 | 0 | 184,226 |
No | output | 1 | 92,113 | 0 | 184,227 |
Provide a correct Python 3 solution for this coding contest problem.
Takahashi loves palindromes. Non-palindromic strings are unacceptable to him. Each time he hugs a string, he can change one of its characters to any character of his choice.
Given is a string S. Find the minimum number of hugs needed to make S palindromic.
Constraints
* S is a string consisting of lowercase English letters.
* The length of S is between 1 and 100 (inclusive).
Input
Input is given from Standard Input in the following format:
S
Output
Print the minimum number of hugs needed to make S palindromic.
Examples
Input
redcoder
Output
1
Input
vvvvvv
Output
0
Input
abcdabc
Output
2 | instruction | 0 | 92,417 | 0 | 184,834 |
"Correct Solution:
```
s = input()
print(sum(1 for a, b in zip(s, reversed(s)) if a != b) // 2)
``` | output | 1 | 92,417 | 0 | 184,835 |
Provide a correct Python 3 solution for this coding contest problem.
Takahashi loves palindromes. Non-palindromic strings are unacceptable to him. Each time he hugs a string, he can change one of its characters to any character of his choice.
Given is a string S. Find the minimum number of hugs needed to make S palindromic.
Constraints
* S is a string consisting of lowercase English letters.
* The length of S is between 1 and 100 (inclusive).
Input
Input is given from Standard Input in the following format:
S
Output
Print the minimum number of hugs needed to make S palindromic.
Examples
Input
redcoder
Output
1
Input
vvvvvv
Output
0
Input
abcdabc
Output
2 | instruction | 0 | 92,418 | 0 | 184,836 |
"Correct Solution:
```
A=input()
c=0
B=A[::-1]
for i in range(len(A)):
if A[i]!=B[i]:
c+=1
print(c//2)
``` | output | 1 | 92,418 | 0 | 184,837 |
Provide a correct Python 3 solution for this coding contest problem.
Takahashi loves palindromes. Non-palindromic strings are unacceptable to him. Each time he hugs a string, he can change one of its characters to any character of his choice.
Given is a string S. Find the minimum number of hugs needed to make S palindromic.
Constraints
* S is a string consisting of lowercase English letters.
* The length of S is between 1 and 100 (inclusive).
Input
Input is given from Standard Input in the following format:
S
Output
Print the minimum number of hugs needed to make S palindromic.
Examples
Input
redcoder
Output
1
Input
vvvvvv
Output
0
Input
abcdabc
Output
2 | instruction | 0 | 92,419 | 0 | 184,838 |
"Correct Solution:
```
s=input()
l=len(s)
x=0
for i in range(l//2):
if s[i]!=s[l-i-1]:
x+=1
print(x)
``` | output | 1 | 92,419 | 0 | 184,839 |
Provide a correct Python 3 solution for this coding contest problem.
Takahashi loves palindromes. Non-palindromic strings are unacceptable to him. Each time he hugs a string, he can change one of its characters to any character of his choice.
Given is a string S. Find the minimum number of hugs needed to make S palindromic.
Constraints
* S is a string consisting of lowercase English letters.
* The length of S is between 1 and 100 (inclusive).
Input
Input is given from Standard Input in the following format:
S
Output
Print the minimum number of hugs needed to make S palindromic.
Examples
Input
redcoder
Output
1
Input
vvvvvv
Output
0
Input
abcdabc
Output
2 | instruction | 0 | 92,420 | 0 | 184,840 |
"Correct Solution:
```
s = input()
t = 0
for i in range(len(s)//2):
if s[i] != s[-(i+1)]:
t += 1
print(t)
``` | output | 1 | 92,420 | 0 | 184,841 |
Provide a correct Python 3 solution for this coding contest problem.
Takahashi loves palindromes. Non-palindromic strings are unacceptable to him. Each time he hugs a string, he can change one of its characters to any character of his choice.
Given is a string S. Find the minimum number of hugs needed to make S palindromic.
Constraints
* S is a string consisting of lowercase English letters.
* The length of S is between 1 and 100 (inclusive).
Input
Input is given from Standard Input in the following format:
S
Output
Print the minimum number of hugs needed to make S palindromic.
Examples
Input
redcoder
Output
1
Input
vvvvvv
Output
0
Input
abcdabc
Output
2 | instruction | 0 | 92,421 | 0 | 184,842 |
"Correct Solution:
```
S=input()
a=0
for i in range(len(S)//2):a+=S[i]!=S[-1-i]
print(a)
``` | output | 1 | 92,421 | 0 | 184,843 |
Provide a correct Python 3 solution for this coding contest problem.
Takahashi loves palindromes. Non-palindromic strings are unacceptable to him. Each time he hugs a string, he can change one of its characters to any character of his choice.
Given is a string S. Find the minimum number of hugs needed to make S palindromic.
Constraints
* S is a string consisting of lowercase English letters.
* The length of S is between 1 and 100 (inclusive).
Input
Input is given from Standard Input in the following format:
S
Output
Print the minimum number of hugs needed to make S palindromic.
Examples
Input
redcoder
Output
1
Input
vvvvvv
Output
0
Input
abcdabc
Output
2 | instruction | 0 | 92,422 | 0 | 184,844 |
"Correct Solution:
```
s=input()
n=len(s)
sm=0
for i in range(n//2):
sm+=(s[i]!=s[n-i-1])
print(sm)
``` | output | 1 | 92,422 | 0 | 184,845 |
Provide a correct Python 3 solution for this coding contest problem.
Takahashi loves palindromes. Non-palindromic strings are unacceptable to him. Each time he hugs a string, he can change one of its characters to any character of his choice.
Given is a string S. Find the minimum number of hugs needed to make S palindromic.
Constraints
* S is a string consisting of lowercase English letters.
* The length of S is between 1 and 100 (inclusive).
Input
Input is given from Standard Input in the following format:
S
Output
Print the minimum number of hugs needed to make S palindromic.
Examples
Input
redcoder
Output
1
Input
vvvvvv
Output
0
Input
abcdabc
Output
2 | instruction | 0 | 92,423 | 0 | 184,846 |
"Correct Solution:
```
S = input()
c = 0
for i in range(int(len(S)/2)):
if S[i] != S[-i-1]:
c += 1
print(c)
``` | output | 1 | 92,423 | 0 | 184,847 |
Provide a correct Python 3 solution for this coding contest problem.
Takahashi loves palindromes. Non-palindromic strings are unacceptable to him. Each time he hugs a string, he can change one of its characters to any character of his choice.
Given is a string S. Find the minimum number of hugs needed to make S palindromic.
Constraints
* S is a string consisting of lowercase English letters.
* The length of S is between 1 and 100 (inclusive).
Input
Input is given from Standard Input in the following format:
S
Output
Print the minimum number of hugs needed to make S palindromic.
Examples
Input
redcoder
Output
1
Input
vvvvvv
Output
0
Input
abcdabc
Output
2 | instruction | 0 | 92,424 | 0 | 184,848 |
"Correct Solution:
```
s=input()
l=len(s)
ct=0
for i in range(l//2):
if s[i]!=s[l-1-i]:
ct+=1
print(ct)
``` | output | 1 | 92,424 | 0 | 184,849 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Let's say string s has period k if s_i = s_{i + k} for all i from 1 to |s| - k (|s| means length of string s) and k is the minimum positive integer with this property.
Some examples of a period: for s="0101" the period is k=2, for s="0000" the period is k=1, for s="010" the period is k=2, for s="0011" the period is k=4.
You are given string t consisting only of 0's and 1's and you need to find such string s that:
1. String s consists only of 0's and 1's;
2. The length of s doesn't exceed 2 ⋅ |t|;
3. String t is a subsequence of string s;
4. String s has smallest possible period among all strings that meet conditions 1—3.
Let us recall that t is a subsequence of s if t can be derived from s by deleting zero or more elements (any) without changing the order of the remaining elements. For example, t="011" is a subsequence of s="10101".
Input
The first line contains single integer T (1 ≤ T ≤ 100) — the number of test cases.
Next T lines contain test cases — one per line. Each line contains string t (1 ≤ |t| ≤ 100) consisting only of 0's and 1's.
Output
Print one string for each test case — string s you needed to find. If there are multiple solutions print any one of them.
Example
Input
4
00
01
111
110
Output
00
01
11111
1010
Note
In the first and second test cases, s = t since it's already one of the optimal solutions. Answers have periods equal to 1 and 2, respectively.
In the third test case, there are shorter optimal solutions, but it's okay since we don't need to minimize the string s. String s has period equal to 1. | instruction | 0 | 92,774 | 0 | 185,548 |
Tags: constructive algorithms, strings
Correct Solution:
```
t = int(input())
for ii in range(t):
t = input()
if t == '0' * len(t) or t == '1' * len(t):
print(t)
else:
print('01' * len(t))
``` | output | 1 | 92,774 | 0 | 185,549 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Let's say string s has period k if s_i = s_{i + k} for all i from 1 to |s| - k (|s| means length of string s) and k is the minimum positive integer with this property.
Some examples of a period: for s="0101" the period is k=2, for s="0000" the period is k=1, for s="010" the period is k=2, for s="0011" the period is k=4.
You are given string t consisting only of 0's and 1's and you need to find such string s that:
1. String s consists only of 0's and 1's;
2. The length of s doesn't exceed 2 ⋅ |t|;
3. String t is a subsequence of string s;
4. String s has smallest possible period among all strings that meet conditions 1—3.
Let us recall that t is a subsequence of s if t can be derived from s by deleting zero or more elements (any) without changing the order of the remaining elements. For example, t="011" is a subsequence of s="10101".
Input
The first line contains single integer T (1 ≤ T ≤ 100) — the number of test cases.
Next T lines contain test cases — one per line. Each line contains string t (1 ≤ |t| ≤ 100) consisting only of 0's and 1's.
Output
Print one string for each test case — string s you needed to find. If there are multiple solutions print any one of them.
Example
Input
4
00
01
111
110
Output
00
01
11111
1010
Note
In the first and second test cases, s = t since it's already one of the optimal solutions. Answers have periods equal to 1 and 2, respectively.
In the third test case, there are shorter optimal solutions, but it's okay since we don't need to minimize the string s. String s has period equal to 1. | instruction | 0 | 92,775 | 0 | 185,550 |
Tags: constructive algorithms, strings
Correct Solution:
```
import os
import sys
from io import BytesIO, IOBase
def main():
T = int(input())
for _ in range(T) :
t = input()
isEqual = True
for i in range (len(t)-1):
if t[i] != t[i+1]:
isEqual = False
break
if isEqual:
print (t)
else:
output = ""
for i in range (len(t)-1):
if t[i] == t[i+1]:
output += t[i]
if t[i] == "0":
output += "1"
else:
output += "0"
else:
output += t[i]
output += t[len(t)-1]
print (output)
# region fastio
BUFSIZE = 8192
class FastIO(IOBase):
newlines = 0
def __init__(self, file):
self._fd = file.fileno()
self.buffer = BytesIO()
self.writable = "x" in file.mode or "r" not in file.mode
self.write = lambda s: self.buffer.write(s.encode()) if self.writable else None
def read(self):
if self.buffer.tell():
return self.buffer.read().decode("ascii")
return os.read(self._fd, os.fstat(self._fd).st_size).decode("ascii")
def readline(self):
while self.newlines == 0:
b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
self.newlines = b.count(b"\n") + (not b)
ptr = self.buffer.tell()
self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
self.newlines -= 1
return self.buffer.readline().decode("ascii")
def flush(self):
if self.writable:
os.write(self._fd, self.buffer.getvalue())
self.buffer.truncate(0), self.buffer.seek(0)
def print(*args, sep=" ", end="\n", file=sys.stdout, flush=False):
at_start = True
for x in args:
if not at_start:
file.write(sep)
file.write(str(x))
at_start = False
file.write(end)
if flush:
file.flush()
sys.stdin, sys.stdout = FastIO(sys.stdin), FastIO(sys.stdout)
input = lambda: sys.stdin.readline().rstrip("\r\n")
# endregion
sys.setrecursionlimit(10000)
if __name__ == "__main__":
main()
``` | output | 1 | 92,775 | 0 | 185,551 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Let's say string s has period k if s_i = s_{i + k} for all i from 1 to |s| - k (|s| means length of string s) and k is the minimum positive integer with this property.
Some examples of a period: for s="0101" the period is k=2, for s="0000" the period is k=1, for s="010" the period is k=2, for s="0011" the period is k=4.
You are given string t consisting only of 0's and 1's and you need to find such string s that:
1. String s consists only of 0's and 1's;
2. The length of s doesn't exceed 2 ⋅ |t|;
3. String t is a subsequence of string s;
4. String s has smallest possible period among all strings that meet conditions 1—3.
Let us recall that t is a subsequence of s if t can be derived from s by deleting zero or more elements (any) without changing the order of the remaining elements. For example, t="011" is a subsequence of s="10101".
Input
The first line contains single integer T (1 ≤ T ≤ 100) — the number of test cases.
Next T lines contain test cases — one per line. Each line contains string t (1 ≤ |t| ≤ 100) consisting only of 0's and 1's.
Output
Print one string for each test case — string s you needed to find. If there are multiple solutions print any one of them.
Example
Input
4
00
01
111
110
Output
00
01
11111
1010
Note
In the first and second test cases, s = t since it's already one of the optimal solutions. Answers have periods equal to 1 and 2, respectively.
In the third test case, there are shorter optimal solutions, but it's okay since we don't need to minimize the string s. String s has period equal to 1. | instruction | 0 | 92,776 | 0 | 185,552 |
Tags: constructive algorithms, strings
Correct Solution:
```
from collections import Counter
t=int(input())
for _ in range(t):
s=input()
dic=Counter(s)
if '0' not in dic:
print(s)
elif '1' not in dic:
print(s)
else:
front=s[0]
ans=""
if(front=='1'):
ans = "10"
for i in range(1,len(s)):
ans += "10"
print(ans)
else:
ans="01"
for i in range(1,len(s)):
ans += "01"
print(ans)
``` | output | 1 | 92,776 | 0 | 185,553 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Let's say string s has period k if s_i = s_{i + k} for all i from 1 to |s| - k (|s| means length of string s) and k is the minimum positive integer with this property.
Some examples of a period: for s="0101" the period is k=2, for s="0000" the period is k=1, for s="010" the period is k=2, for s="0011" the period is k=4.
You are given string t consisting only of 0's and 1's and you need to find such string s that:
1. String s consists only of 0's and 1's;
2. The length of s doesn't exceed 2 ⋅ |t|;
3. String t is a subsequence of string s;
4. String s has smallest possible period among all strings that meet conditions 1—3.
Let us recall that t is a subsequence of s if t can be derived from s by deleting zero or more elements (any) without changing the order of the remaining elements. For example, t="011" is a subsequence of s="10101".
Input
The first line contains single integer T (1 ≤ T ≤ 100) — the number of test cases.
Next T lines contain test cases — one per line. Each line contains string t (1 ≤ |t| ≤ 100) consisting only of 0's and 1's.
Output
Print one string for each test case — string s you needed to find. If there are multiple solutions print any one of them.
Example
Input
4
00
01
111
110
Output
00
01
11111
1010
Note
In the first and second test cases, s = t since it's already one of the optimal solutions. Answers have periods equal to 1 and 2, respectively.
In the third test case, there are shorter optimal solutions, but it's okay since we don't need to minimize the string s. String s has period equal to 1. | instruction | 0 | 92,777 | 0 | 185,554 |
Tags: constructive algorithms, strings
Correct Solution:
```
cases = int(input())
for i in range(cases):
t = list(input())
if len(set(t)) == 1:
print("".join(t))
else:
t = [int(q) for q in t]
n = []
for j in range(len(t)-1):
if t[j] == t[j+1]:
n.append(t[j])
n.append(1-t[j])
else:
n.append(t[j])
n.append(t[len(t)-1])
#n.append(1-t[len(t)-1])
st = ""
for j in n:
st += str(j)
print(st)
``` | output | 1 | 92,777 | 0 | 185,555 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Let's say string s has period k if s_i = s_{i + k} for all i from 1 to |s| - k (|s| means length of string s) and k is the minimum positive integer with this property.
Some examples of a period: for s="0101" the period is k=2, for s="0000" the period is k=1, for s="010" the period is k=2, for s="0011" the period is k=4.
You are given string t consisting only of 0's and 1's and you need to find such string s that:
1. String s consists only of 0's and 1's;
2. The length of s doesn't exceed 2 ⋅ |t|;
3. String t is a subsequence of string s;
4. String s has smallest possible period among all strings that meet conditions 1—3.
Let us recall that t is a subsequence of s if t can be derived from s by deleting zero or more elements (any) without changing the order of the remaining elements. For example, t="011" is a subsequence of s="10101".
Input
The first line contains single integer T (1 ≤ T ≤ 100) — the number of test cases.
Next T lines contain test cases — one per line. Each line contains string t (1 ≤ |t| ≤ 100) consisting only of 0's and 1's.
Output
Print one string for each test case — string s you needed to find. If there are multiple solutions print any one of them.
Example
Input
4
00
01
111
110
Output
00
01
11111
1010
Note
In the first and second test cases, s = t since it's already one of the optimal solutions. Answers have periods equal to 1 and 2, respectively.
In the third test case, there are shorter optimal solutions, but it's okay since we don't need to minimize the string s. String s has period equal to 1. | instruction | 0 | 92,778 | 0 | 185,556 |
Tags: constructive algorithms, strings
Correct Solution:
```
for _ in range(int(input())):
t=input()
z = t.count('0')
o = t.count('1')
import re
if z == 0 or o == 0:
print(t)
continue
if z > o:
while "00" in t:
t = re.sub("00", "010", t)
while "11" in t:
t = re.sub("11", "101", t)
print(t)
else:
while "00" in t:
t = re.sub("00", "010", t)
while "11" in t:
t = re.sub("11", "101", t)
print(t)
``` | output | 1 | 92,778 | 0 | 185,557 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Let's say string s has period k if s_i = s_{i + k} for all i from 1 to |s| - k (|s| means length of string s) and k is the minimum positive integer with this property.
Some examples of a period: for s="0101" the period is k=2, for s="0000" the period is k=1, for s="010" the period is k=2, for s="0011" the period is k=4.
You are given string t consisting only of 0's and 1's and you need to find such string s that:
1. String s consists only of 0's and 1's;
2. The length of s doesn't exceed 2 ⋅ |t|;
3. String t is a subsequence of string s;
4. String s has smallest possible period among all strings that meet conditions 1—3.
Let us recall that t is a subsequence of s if t can be derived from s by deleting zero or more elements (any) without changing the order of the remaining elements. For example, t="011" is a subsequence of s="10101".
Input
The first line contains single integer T (1 ≤ T ≤ 100) — the number of test cases.
Next T lines contain test cases — one per line. Each line contains string t (1 ≤ |t| ≤ 100) consisting only of 0's and 1's.
Output
Print one string for each test case — string s you needed to find. If there are multiple solutions print any one of them.
Example
Input
4
00
01
111
110
Output
00
01
11111
1010
Note
In the first and second test cases, s = t since it's already one of the optimal solutions. Answers have periods equal to 1 and 2, respectively.
In the third test case, there are shorter optimal solutions, but it's okay since we don't need to minimize the string s. String s has period equal to 1. | instruction | 0 | 92,779 | 0 | 185,558 |
Tags: constructive algorithms, strings
Correct Solution:
```
from sys import stdin, stdout
from math import *
from heapq import *
from collections import *
def main():
ntest=int(stdin.readline())
for testcase in range(ntest):
t=stdin.readline().strip()
s=[]
if len(set(t))==2:
s=['01']*len(t)
else:
s=[t]
stdout.write("%s\n"%("".join(s)))
return 0
if __name__ == "__main__":
main()
``` | output | 1 | 92,779 | 0 | 185,559 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Let's say string s has period k if s_i = s_{i + k} for all i from 1 to |s| - k (|s| means length of string s) and k is the minimum positive integer with this property.
Some examples of a period: for s="0101" the period is k=2, for s="0000" the period is k=1, for s="010" the period is k=2, for s="0011" the period is k=4.
You are given string t consisting only of 0's and 1's and you need to find such string s that:
1. String s consists only of 0's and 1's;
2. The length of s doesn't exceed 2 ⋅ |t|;
3. String t is a subsequence of string s;
4. String s has smallest possible period among all strings that meet conditions 1—3.
Let us recall that t is a subsequence of s if t can be derived from s by deleting zero or more elements (any) without changing the order of the remaining elements. For example, t="011" is a subsequence of s="10101".
Input
The first line contains single integer T (1 ≤ T ≤ 100) — the number of test cases.
Next T lines contain test cases — one per line. Each line contains string t (1 ≤ |t| ≤ 100) consisting only of 0's and 1's.
Output
Print one string for each test case — string s you needed to find. If there are multiple solutions print any one of them.
Example
Input
4
00
01
111
110
Output
00
01
11111
1010
Note
In the first and second test cases, s = t since it's already one of the optimal solutions. Answers have periods equal to 1 and 2, respectively.
In the third test case, there are shorter optimal solutions, but it's okay since we don't need to minimize the string s. String s has period equal to 1. | instruction | 0 | 92,780 | 0 | 185,560 |
Tags: constructive algorithms, strings
Correct Solution:
```
def main():
for _ in range(int(input())):
t=list(input())
l=[t[0]]
if(t.count('0')>0 and t.count('1')>0):
for i in range(1,len(t)):
if(l[len(l)-1]=='0' and t[i]=='0'):
l.append('1')
l.append('0')
elif(l[len(l)-1]=='1' and t[i]=='1'):
l.append('0')
l.append('1')
elif(l[len(l)-1]=='0' and t[i]=='1'):
l.append('1')
else:
l.append('0')
print("".join(l))
else:
print("".join(t))
main()
``` | output | 1 | 92,780 | 0 | 185,561 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Let's say string s has period k if s_i = s_{i + k} for all i from 1 to |s| - k (|s| means length of string s) and k is the minimum positive integer with this property.
Some examples of a period: for s="0101" the period is k=2, for s="0000" the period is k=1, for s="010" the period is k=2, for s="0011" the period is k=4.
You are given string t consisting only of 0's and 1's and you need to find such string s that:
1. String s consists only of 0's and 1's;
2. The length of s doesn't exceed 2 ⋅ |t|;
3. String t is a subsequence of string s;
4. String s has smallest possible period among all strings that meet conditions 1—3.
Let us recall that t is a subsequence of s if t can be derived from s by deleting zero or more elements (any) without changing the order of the remaining elements. For example, t="011" is a subsequence of s="10101".
Input
The first line contains single integer T (1 ≤ T ≤ 100) — the number of test cases.
Next T lines contain test cases — one per line. Each line contains string t (1 ≤ |t| ≤ 100) consisting only of 0's and 1's.
Output
Print one string for each test case — string s you needed to find. If there are multiple solutions print any one of them.
Example
Input
4
00
01
111
110
Output
00
01
11111
1010
Note
In the first and second test cases, s = t since it's already one of the optimal solutions. Answers have periods equal to 1 and 2, respectively.
In the third test case, there are shorter optimal solutions, but it's okay since we don't need to minimize the string s. String s has period equal to 1. | instruction | 0 | 92,781 | 0 | 185,562 |
Tags: constructive algorithms, strings
Correct Solution:
```
import sys
input = sys.stdin.readline
############ ---- USER DEFINED INPUT FUNCTIONS ---- ############
def inp():
return(int(input()))
def inlt():
return(list(map(int,input().split())))
def insr():
s = input()
return(s[:len(s) - 1])
def invr():
return(map(int,input().split()))
################################################################
############ ---- THE ACTUAL CODE STARTS BELOW ---- ############
t = inp()
for _ in range(t):
s = input().rstrip()
has = True
l = s[0]
for i in range(1,len(s)):
if l != s[i]:
has = False
break
if has:
print(s)
else:
ans = []
for i in range(len(s)):
ans.append('1')
ans.append('0')
print(''.join(ans))
``` | output | 1 | 92,781 | 0 | 185,563 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Let's say string s has period k if s_i = s_{i + k} for all i from 1 to |s| - k (|s| means length of string s) and k is the minimum positive integer with this property.
Some examples of a period: for s="0101" the period is k=2, for s="0000" the period is k=1, for s="010" the period is k=2, for s="0011" the period is k=4.
You are given string t consisting only of 0's and 1's and you need to find such string s that:
1. String s consists only of 0's and 1's;
2. The length of s doesn't exceed 2 ⋅ |t|;
3. String t is a subsequence of string s;
4. String s has smallest possible period among all strings that meet conditions 1—3.
Let us recall that t is a subsequence of s if t can be derived from s by deleting zero or more elements (any) without changing the order of the remaining elements. For example, t="011" is a subsequence of s="10101".
Input
The first line contains single integer T (1 ≤ T ≤ 100) — the number of test cases.
Next T lines contain test cases — one per line. Each line contains string t (1 ≤ |t| ≤ 100) consisting only of 0's and 1's.
Output
Print one string for each test case — string s you needed to find. If there are multiple solutions print any one of them.
Example
Input
4
00
01
111
110
Output
00
01
11111
1010
Note
In the first and second test cases, s = t since it's already one of the optimal solutions. Answers have periods equal to 1 and 2, respectively.
In the third test case, there are shorter optimal solutions, but it's okay since we don't need to minimize the string s. String s has period equal to 1.
Submitted Solution:
```
T = int(input())
for times in range(T):
s = input()
if(s.find('1')!=-1 and s.find('0') != -1):
print("10" * len(s))
else:
print(s)
``` | instruction | 0 | 92,782 | 0 | 185,564 |
Yes | output | 1 | 92,782 | 0 | 185,565 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Let's say string s has period k if s_i = s_{i + k} for all i from 1 to |s| - k (|s| means length of string s) and k is the minimum positive integer with this property.
Some examples of a period: for s="0101" the period is k=2, for s="0000" the period is k=1, for s="010" the period is k=2, for s="0011" the period is k=4.
You are given string t consisting only of 0's and 1's and you need to find such string s that:
1. String s consists only of 0's and 1's;
2. The length of s doesn't exceed 2 ⋅ |t|;
3. String t is a subsequence of string s;
4. String s has smallest possible period among all strings that meet conditions 1—3.
Let us recall that t is a subsequence of s if t can be derived from s by deleting zero or more elements (any) without changing the order of the remaining elements. For example, t="011" is a subsequence of s="10101".
Input
The first line contains single integer T (1 ≤ T ≤ 100) — the number of test cases.
Next T lines contain test cases — one per line. Each line contains string t (1 ≤ |t| ≤ 100) consisting only of 0's and 1's.
Output
Print one string for each test case — string s you needed to find. If there are multiple solutions print any one of them.
Example
Input
4
00
01
111
110
Output
00
01
11111
1010
Note
In the first and second test cases, s = t since it's already one of the optimal solutions. Answers have periods equal to 1 and 2, respectively.
In the third test case, there are shorter optimal solutions, but it's okay since we don't need to minimize the string s. String s has period equal to 1.
Submitted Solution:
```
from collections import Counter
T = int(input())
ss = []
for _ in range(T):
ss.append(input())
for s in ss:
counter = Counter(s)
if counter["1"] > 0 and counter["0"] > 0:
if s[0] == "1":
print("".join(["1", "0"] * len(s)))
else:
print("".join(["0", "1"] * len(s)))
else:
print(s)
``` | instruction | 0 | 92,783 | 0 | 185,566 |
Yes | output | 1 | 92,783 | 0 | 185,567 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Let's say string s has period k if s_i = s_{i + k} for all i from 1 to |s| - k (|s| means length of string s) and k is the minimum positive integer with this property.
Some examples of a period: for s="0101" the period is k=2, for s="0000" the period is k=1, for s="010" the period is k=2, for s="0011" the period is k=4.
You are given string t consisting only of 0's and 1's and you need to find such string s that:
1. String s consists only of 0's and 1's;
2. The length of s doesn't exceed 2 ⋅ |t|;
3. String t is a subsequence of string s;
4. String s has smallest possible period among all strings that meet conditions 1—3.
Let us recall that t is a subsequence of s if t can be derived from s by deleting zero or more elements (any) without changing the order of the remaining elements. For example, t="011" is a subsequence of s="10101".
Input
The first line contains single integer T (1 ≤ T ≤ 100) — the number of test cases.
Next T lines contain test cases — one per line. Each line contains string t (1 ≤ |t| ≤ 100) consisting only of 0's and 1's.
Output
Print one string for each test case — string s you needed to find. If there are multiple solutions print any one of them.
Example
Input
4
00
01
111
110
Output
00
01
11111
1010
Note
In the first and second test cases, s = t since it's already one of the optimal solutions. Answers have periods equal to 1 and 2, respectively.
In the third test case, there are shorter optimal solutions, but it's okay since we don't need to minimize the string s. String s has period equal to 1.
Submitted Solution:
```
t= int(input())
def inv(ch):
return '1' if ch=='0' else '0'
for i in range(t):
s=input()
if len(s)==2:
print(s)
else:
stri=''
temp= True
for i in range(len(s)-1):
if(s[i]!=s[i+1]):
temp=False
if temp==True:
print(s+s)
else:
for i in range(len(s)-1):
stri+= s[i]
if s[i]==s[i+1]:
stri+= inv(s[i])
c=len(s)-1
stri+=s[c]
if(len(stri)%2==1):
stri+= inv(s[c])
print(stri)
``` | instruction | 0 | 92,784 | 0 | 185,568 |
Yes | output | 1 | 92,784 | 0 | 185,569 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Let's say string s has period k if s_i = s_{i + k} for all i from 1 to |s| - k (|s| means length of string s) and k is the minimum positive integer with this property.
Some examples of a period: for s="0101" the period is k=2, for s="0000" the period is k=1, for s="010" the period is k=2, for s="0011" the period is k=4.
You are given string t consisting only of 0's and 1's and you need to find such string s that:
1. String s consists only of 0's and 1's;
2. The length of s doesn't exceed 2 ⋅ |t|;
3. String t is a subsequence of string s;
4. String s has smallest possible period among all strings that meet conditions 1—3.
Let us recall that t is a subsequence of s if t can be derived from s by deleting zero or more elements (any) without changing the order of the remaining elements. For example, t="011" is a subsequence of s="10101".
Input
The first line contains single integer T (1 ≤ T ≤ 100) — the number of test cases.
Next T lines contain test cases — one per line. Each line contains string t (1 ≤ |t| ≤ 100) consisting only of 0's and 1's.
Output
Print one string for each test case — string s you needed to find. If there are multiple solutions print any one of them.
Example
Input
4
00
01
111
110
Output
00
01
11111
1010
Note
In the first and second test cases, s = t since it's already one of the optimal solutions. Answers have periods equal to 1 and 2, respectively.
In the third test case, there are shorter optimal solutions, but it's okay since we don't need to minimize the string s. String s has period equal to 1.
Submitted Solution:
```
for _ in range(int(input())):
t = input()
flag = t.count('1') and t.count('0')
if flag:
print(len(t)*'10')
else:
print(t)
``` | instruction | 0 | 92,785 | 0 | 185,570 |
Yes | output | 1 | 92,785 | 0 | 185,571 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Let's say string s has period k if s_i = s_{i + k} for all i from 1 to |s| - k (|s| means length of string s) and k is the minimum positive integer with this property.
Some examples of a period: for s="0101" the period is k=2, for s="0000" the period is k=1, for s="010" the period is k=2, for s="0011" the period is k=4.
You are given string t consisting only of 0's and 1's and you need to find such string s that:
1. String s consists only of 0's and 1's;
2. The length of s doesn't exceed 2 ⋅ |t|;
3. String t is a subsequence of string s;
4. String s has smallest possible period among all strings that meet conditions 1—3.
Let us recall that t is a subsequence of s if t can be derived from s by deleting zero or more elements (any) without changing the order of the remaining elements. For example, t="011" is a subsequence of s="10101".
Input
The first line contains single integer T (1 ≤ T ≤ 100) — the number of test cases.
Next T lines contain test cases — one per line. Each line contains string t (1 ≤ |t| ≤ 100) consisting only of 0's and 1's.
Output
Print one string for each test case — string s you needed to find. If there are multiple solutions print any one of them.
Example
Input
4
00
01
111
110
Output
00
01
11111
1010
Note
In the first and second test cases, s = t since it's already one of the optimal solutions. Answers have periods equal to 1 and 2, respectively.
In the third test case, there are shorter optimal solutions, but it's okay since we don't need to minimize the string s. String s has period equal to 1.
Submitted Solution:
```
for i in range(int(input())):
a=input()
print(a*2)
``` | instruction | 0 | 92,786 | 0 | 185,572 |
No | output | 1 | 92,786 | 0 | 185,573 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Let's say string s has period k if s_i = s_{i + k} for all i from 1 to |s| - k (|s| means length of string s) and k is the minimum positive integer with this property.
Some examples of a period: for s="0101" the period is k=2, for s="0000" the period is k=1, for s="010" the period is k=2, for s="0011" the period is k=4.
You are given string t consisting only of 0's and 1's and you need to find such string s that:
1. String s consists only of 0's and 1's;
2. The length of s doesn't exceed 2 ⋅ |t|;
3. String t is a subsequence of string s;
4. String s has smallest possible period among all strings that meet conditions 1—3.
Let us recall that t is a subsequence of s if t can be derived from s by deleting zero or more elements (any) without changing the order of the remaining elements. For example, t="011" is a subsequence of s="10101".
Input
The first line contains single integer T (1 ≤ T ≤ 100) — the number of test cases.
Next T lines contain test cases — one per line. Each line contains string t (1 ≤ |t| ≤ 100) consisting only of 0's and 1's.
Output
Print one string for each test case — string s you needed to find. If there are multiple solutions print any one of them.
Example
Input
4
00
01
111
110
Output
00
01
11111
1010
Note
In the first and second test cases, s = t since it's already one of the optimal solutions. Answers have periods equal to 1 and 2, respectively.
In the third test case, there are shorter optimal solutions, but it's okay since we don't need to minimize the string s. String s has period equal to 1.
Submitted Solution:
```
t=int(input())
while t:
t-=1
string=input()
ans=""
for i in range(len(string)-1):
if string[i]+string[i+1]=="00":
ans+=string[i]+"1"
elif string[i]+string[i+1]=="11":
ans+=string[i]+"0"
else:
ans+=string[i]
ans+=string[-1]
print(ans)
``` | instruction | 0 | 92,787 | 0 | 185,574 |
No | output | 1 | 92,787 | 0 | 185,575 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Let's say string s has period k if s_i = s_{i + k} for all i from 1 to |s| - k (|s| means length of string s) and k is the minimum positive integer with this property.
Some examples of a period: for s="0101" the period is k=2, for s="0000" the period is k=1, for s="010" the period is k=2, for s="0011" the period is k=4.
You are given string t consisting only of 0's and 1's and you need to find such string s that:
1. String s consists only of 0's and 1's;
2. The length of s doesn't exceed 2 ⋅ |t|;
3. String t is a subsequence of string s;
4. String s has smallest possible period among all strings that meet conditions 1—3.
Let us recall that t is a subsequence of s if t can be derived from s by deleting zero or more elements (any) without changing the order of the remaining elements. For example, t="011" is a subsequence of s="10101".
Input
The first line contains single integer T (1 ≤ T ≤ 100) — the number of test cases.
Next T lines contain test cases — one per line. Each line contains string t (1 ≤ |t| ≤ 100) consisting only of 0's and 1's.
Output
Print one string for each test case — string s you needed to find. If there are multiple solutions print any one of them.
Example
Input
4
00
01
111
110
Output
00
01
11111
1010
Note
In the first and second test cases, s = t since it's already one of the optimal solutions. Answers have periods equal to 1 and 2, respectively.
In the third test case, there are shorter optimal solutions, but it's okay since we don't need to minimize the string s. String s has period equal to 1.
Submitted Solution:
```
t=int(input())
for i in range(t):
s=input()
arr=[]
if(len(s)==1 or len(s)==2):
print(s)
else:
a=s[0]
b="0"
if(a=="0"):
b="1"
for j in range(len(s)):
arr.append(a)
arr.append(b)
print(*arr,sep="")
``` | instruction | 0 | 92,788 | 0 | 185,576 |
No | output | 1 | 92,788 | 0 | 185,577 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Let's say string s has period k if s_i = s_{i + k} for all i from 1 to |s| - k (|s| means length of string s) and k is the minimum positive integer with this property.
Some examples of a period: for s="0101" the period is k=2, for s="0000" the period is k=1, for s="010" the period is k=2, for s="0011" the period is k=4.
You are given string t consisting only of 0's and 1's and you need to find such string s that:
1. String s consists only of 0's and 1's;
2. The length of s doesn't exceed 2 ⋅ |t|;
3. String t is a subsequence of string s;
4. String s has smallest possible period among all strings that meet conditions 1—3.
Let us recall that t is a subsequence of s if t can be derived from s by deleting zero or more elements (any) without changing the order of the remaining elements. For example, t="011" is a subsequence of s="10101".
Input
The first line contains single integer T (1 ≤ T ≤ 100) — the number of test cases.
Next T lines contain test cases — one per line. Each line contains string t (1 ≤ |t| ≤ 100) consisting only of 0's and 1's.
Output
Print one string for each test case — string s you needed to find. If there are multiple solutions print any one of them.
Example
Input
4
00
01
111
110
Output
00
01
11111
1010
Note
In the first and second test cases, s = t since it's already one of the optimal solutions. Answers have periods equal to 1 and 2, respectively.
In the third test case, there are shorter optimal solutions, but it's okay since we don't need to minimize the string s. String s has period equal to 1.
Submitted Solution:
```
for _ in range(int(input())):
t=input()
n=len(t)
n1=t.count('1')
n0=n-n1
if n1==0 or n0==0:
print(t)
else:
k=max(n1,n0)
if k==n//2:
k+=1
print('10'*k)
``` | instruction | 0 | 92,789 | 0 | 185,578 |
No | output | 1 | 92,789 | 0 | 185,579 |
Provide tags and a correct Python 3 solution for this coding contest problem.
A string b is a subsequence of a string a if b can be obtained from a by deletion of several (possibly, zero or all) characters. For example, "xy" is a subsequence of "xzyw" and "xy", but not "yx".
You are given a string a. Your task is to reorder the characters of a so that "trygub" is not a subsequence of the resulting string.
In other words, you should find a string b which is a permutation of symbols of the string a and "trygub" is not a subsequence of b.
We have a truly marvelous proof that any string can be arranged not to contain "trygub" as a subsequence, but this problem statement is too short to contain it.
Input
The first line contains a single integer t (1≤ t≤ 100) — the number of test cases.
The first line of each test case contains a single integer n (1≤ n≤ 200) — the length of a.
The next line contains the string a of length n, consisting of lowercase English letters.
Output
For each test case, output a string b of length n which is a permutation of characters of the string a, and such that "trygub" is not a subsequence of it.
If there exist multiple possible strings b, you can print any.
Example
Input
3
11
antontrygub
15
bestcoordinator
19
trywatchinggurabruh
Output
bugyrtnotna
bestcoordinator
bruhtrywatchinggura
Note
In the first test case, "bugyrtnotna" does not contain "trygub" as a subsequence. It does contain the letters of "trygub", but not in the correct order, so it is not a subsequence.
In the second test case, we did not change the order of characters because it is not needed.
In the third test case, "bruhtrywatchinggura" does contain "trygu" as a subsequence, but not "trygub". | instruction | 0 | 92,842 | 0 | 185,684 |
Tags: constructive algorithms, sortings
Correct Solution:
```
from sys import stdin
def main():
input = lambda: stdin.readline()[:-1]
T = int(input())
for _ in [0] * T:
N = int(input())
A = input()
ans = "".join(sorted(A))
print(ans)
main()
``` | output | 1 | 92,842 | 0 | 185,685 |
Provide tags and a correct Python 3 solution for this coding contest problem.
A string b is a subsequence of a string a if b can be obtained from a by deletion of several (possibly, zero or all) characters. For example, "xy" is a subsequence of "xzyw" and "xy", but not "yx".
You are given a string a. Your task is to reorder the characters of a so that "trygub" is not a subsequence of the resulting string.
In other words, you should find a string b which is a permutation of symbols of the string a and "trygub" is not a subsequence of b.
We have a truly marvelous proof that any string can be arranged not to contain "trygub" as a subsequence, but this problem statement is too short to contain it.
Input
The first line contains a single integer t (1≤ t≤ 100) — the number of test cases.
The first line of each test case contains a single integer n (1≤ n≤ 200) — the length of a.
The next line contains the string a of length n, consisting of lowercase English letters.
Output
For each test case, output a string b of length n which is a permutation of characters of the string a, and such that "trygub" is not a subsequence of it.
If there exist multiple possible strings b, you can print any.
Example
Input
3
11
antontrygub
15
bestcoordinator
19
trywatchinggurabruh
Output
bugyrtnotna
bestcoordinator
bruhtrywatchinggura
Note
In the first test case, "bugyrtnotna" does not contain "trygub" as a subsequence. It does contain the letters of "trygub", but not in the correct order, so it is not a subsequence.
In the second test case, we did not change the order of characters because it is not needed.
In the third test case, "bruhtrywatchinggura" does contain "trygu" as a subsequence, but not "trygub". | instruction | 0 | 92,843 | 0 | 185,686 |
Tags: constructive algorithms, sortings
Correct Solution:
```
from sys import stdout,stdin,maxsize
from collections import defaultdict,deque
import math
import bisect
t=int(stdin.readline())
for _ in range(t):
n=int(stdin.readline())
#n,m=map(int,stdin.readline().split())
#l=list(map(int,stdin.readline().split()))
s=input()
print(''.join(sorted(s)))
``` | output | 1 | 92,843 | 0 | 185,687 |
Provide tags and a correct Python 3 solution for this coding contest problem.
A string b is a subsequence of a string a if b can be obtained from a by deletion of several (possibly, zero or all) characters. For example, "xy" is a subsequence of "xzyw" and "xy", but not "yx".
You are given a string a. Your task is to reorder the characters of a so that "trygub" is not a subsequence of the resulting string.
In other words, you should find a string b which is a permutation of symbols of the string a and "trygub" is not a subsequence of b.
We have a truly marvelous proof that any string can be arranged not to contain "trygub" as a subsequence, but this problem statement is too short to contain it.
Input
The first line contains a single integer t (1≤ t≤ 100) — the number of test cases.
The first line of each test case contains a single integer n (1≤ n≤ 200) — the length of a.
The next line contains the string a of length n, consisting of lowercase English letters.
Output
For each test case, output a string b of length n which is a permutation of characters of the string a, and such that "trygub" is not a subsequence of it.
If there exist multiple possible strings b, you can print any.
Example
Input
3
11
antontrygub
15
bestcoordinator
19
trywatchinggurabruh
Output
bugyrtnotna
bestcoordinator
bruhtrywatchinggura
Note
In the first test case, "bugyrtnotna" does not contain "trygub" as a subsequence. It does contain the letters of "trygub", but not in the correct order, so it is not a subsequence.
In the second test case, we did not change the order of characters because it is not needed.
In the third test case, "bruhtrywatchinggura" does contain "trygu" as a subsequence, but not "trygub". | instruction | 0 | 92,844 | 0 | 185,688 |
Tags: constructive algorithms, sortings
Correct Solution:
```
y122=int(input())
for _ in range(y122):
s=input()
s=input()
s=sorted(s)
print("".join(s))
``` | output | 1 | 92,844 | 0 | 185,689 |
Provide tags and a correct Python 3 solution for this coding contest problem.
A string b is a subsequence of a string a if b can be obtained from a by deletion of several (possibly, zero or all) characters. For example, "xy" is a subsequence of "xzyw" and "xy", but not "yx".
You are given a string a. Your task is to reorder the characters of a so that "trygub" is not a subsequence of the resulting string.
In other words, you should find a string b which is a permutation of symbols of the string a and "trygub" is not a subsequence of b.
We have a truly marvelous proof that any string can be arranged not to contain "trygub" as a subsequence, but this problem statement is too short to contain it.
Input
The first line contains a single integer t (1≤ t≤ 100) — the number of test cases.
The first line of each test case contains a single integer n (1≤ n≤ 200) — the length of a.
The next line contains the string a of length n, consisting of lowercase English letters.
Output
For each test case, output a string b of length n which is a permutation of characters of the string a, and such that "trygub" is not a subsequence of it.
If there exist multiple possible strings b, you can print any.
Example
Input
3
11
antontrygub
15
bestcoordinator
19
trywatchinggurabruh
Output
bugyrtnotna
bestcoordinator
bruhtrywatchinggura
Note
In the first test case, "bugyrtnotna" does not contain "trygub" as a subsequence. It does contain the letters of "trygub", but not in the correct order, so it is not a subsequence.
In the second test case, we did not change the order of characters because it is not needed.
In the third test case, "bruhtrywatchinggura" does contain "trygu" as a subsequence, but not "trygub". | instruction | 0 | 92,845 | 0 | 185,690 |
Tags: constructive algorithms, sortings
Correct Solution:
```
t=int(input())
for _ in range(t):
n=int(input())
s=str(input())
countt=0
countr=0
st=""
for i in range(n):
if(s[i]=="t"):
countt+=1
elif(s[i]=="r"):
countr+=1
else:
st+=s[i]
k=countr*"r"+st+countt*"t"
print(k)
``` | output | 1 | 92,845 | 0 | 185,691 |
Provide tags and a correct Python 3 solution for this coding contest problem.
A string b is a subsequence of a string a if b can be obtained from a by deletion of several (possibly, zero or all) characters. For example, "xy" is a subsequence of "xzyw" and "xy", but not "yx".
You are given a string a. Your task is to reorder the characters of a so that "trygub" is not a subsequence of the resulting string.
In other words, you should find a string b which is a permutation of symbols of the string a and "trygub" is not a subsequence of b.
We have a truly marvelous proof that any string can be arranged not to contain "trygub" as a subsequence, but this problem statement is too short to contain it.
Input
The first line contains a single integer t (1≤ t≤ 100) — the number of test cases.
The first line of each test case contains a single integer n (1≤ n≤ 200) — the length of a.
The next line contains the string a of length n, consisting of lowercase English letters.
Output
For each test case, output a string b of length n which is a permutation of characters of the string a, and such that "trygub" is not a subsequence of it.
If there exist multiple possible strings b, you can print any.
Example
Input
3
11
antontrygub
15
bestcoordinator
19
trywatchinggurabruh
Output
bugyrtnotna
bestcoordinator
bruhtrywatchinggura
Note
In the first test case, "bugyrtnotna" does not contain "trygub" as a subsequence. It does contain the letters of "trygub", but not in the correct order, so it is not a subsequence.
In the second test case, we did not change the order of characters because it is not needed.
In the third test case, "bruhtrywatchinggura" does contain "trygu" as a subsequence, but not "trygub". | instruction | 0 | 92,846 | 0 | 185,692 |
Tags: constructive algorithms, sortings
Correct Solution:
```
from collections import Counter
for y in range(int(input())):
n=int(input())
s=input()
dic=Counter(s)
#print(dic)
for i in dic:
if i!='t' and i!='r' and i!='y' and i!='g' and i!='u' and i!='b':
print(i*dic[i],end="")
print('r'*dic['r']+'t'*dic['t']+'g'*dic['g']+'y'*dic['y']+'b'*dic['b']+'u'*dic['u'])
``` | output | 1 | 92,846 | 0 | 185,693 |
Provide tags and a correct Python 3 solution for this coding contest problem.
A string b is a subsequence of a string a if b can be obtained from a by deletion of several (possibly, zero or all) characters. For example, "xy" is a subsequence of "xzyw" and "xy", but not "yx".
You are given a string a. Your task is to reorder the characters of a so that "trygub" is not a subsequence of the resulting string.
In other words, you should find a string b which is a permutation of symbols of the string a and "trygub" is not a subsequence of b.
We have a truly marvelous proof that any string can be arranged not to contain "trygub" as a subsequence, but this problem statement is too short to contain it.
Input
The first line contains a single integer t (1≤ t≤ 100) — the number of test cases.
The first line of each test case contains a single integer n (1≤ n≤ 200) — the length of a.
The next line contains the string a of length n, consisting of lowercase English letters.
Output
For each test case, output a string b of length n which is a permutation of characters of the string a, and such that "trygub" is not a subsequence of it.
If there exist multiple possible strings b, you can print any.
Example
Input
3
11
antontrygub
15
bestcoordinator
19
trywatchinggurabruh
Output
bugyrtnotna
bestcoordinator
bruhtrywatchinggura
Note
In the first test case, "bugyrtnotna" does not contain "trygub" as a subsequence. It does contain the letters of "trygub", but not in the correct order, so it is not a subsequence.
In the second test case, we did not change the order of characters because it is not needed.
In the third test case, "bruhtrywatchinggura" does contain "trygu" as a subsequence, but not "trygub". | instruction | 0 | 92,847 | 0 | 185,694 |
Tags: constructive algorithms, sortings
Correct Solution:
```
t = int(input())
for j in range(0,t):
s = int(input())
inp = []
inp_str = input()
for i in inp_str:
inp.append(i)
l2 = ['r','y','g','u','b']
matched = False
m = '*'
for i in l2:
for k in inp:
if i==k:
matched = True
m = i
break
if matched==True:
break
count = 0
if matched==False:
print(inp_str)
else:
for i in range(0,s):
if inp[i]==m:
count+=1
inp[i] = '.'
for i in range(0,count):
print(m,end='')
for i in inp:
if i!='.':
print(i,end='')
print()
``` | output | 1 | 92,847 | 0 | 185,695 |
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