message stringlengths 2 23.8k | message_type stringclasses 2
values | message_id int64 0 1 | conversation_id int64 97 109k | cluster float64 0 0 | __index_level_0__ int64 194 217k |
|---|---|---|---|---|---|
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given two strings s and t, each of length n and consisting of lowercase Latin alphabets. You want to make s equal to t.
You can perform the following operation on s any number of times to achieve it —
* Choose any substring of ... | instruction | 0 | 95,409 | 0 | 190,818 |
Tags: dp, strings
Correct Solution:
```
import os
### START FAST IO ###
os_input = os.read(0, int(1e7)).split()
os_input_pos = -1
answer_list = []
def read_s():
global os_input_pos
os_input_pos += 1
return os_input[os_input_pos].decode()
def read_i():
return int(read_s())
def write_s(v):
answer_list... | output | 1 | 95,409 | 0 | 190,819 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given two strings s and t, each of length n and consisting of lowercase Latin alphabets. You want to make s equal to t.
You can perform the following operation on s any number of times to achieve it —
* Choose any substring of ... | instruction | 0 | 95,410 | 0 | 190,820 |
Tags: dp, strings
Correct Solution:
```
import sys
int1 = lambda x: int(x) - 1
p2D = lambda x: print(*x, sep="\n")
def II(): return int(sys.stdin.readline())
def MI(): return map(int, sys.stdin.readline().split())
def LI(): return list(map(int, sys.stdin.readline().split()))
def LLI(rows_number): return [LI() for _ in... | output | 1 | 95,410 | 0 | 190,821 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given two strings s and t, each of length n and consisting of lowercase Latin alphabets. You want to make s equal to t.
You can perform the following operation on s any number of times to achieve it —
* Choose any substring of ... | instruction | 0 | 95,411 | 0 | 190,822 |
Tags: dp, strings
Correct Solution:
```
def num(c):return ord(c) - 97
import sys
input = sys.stdin.readline
for _ in range(int(input())):
n = int(input());s1 = input().strip();s2 = input().strip();char1 = [0] * 26;char2 = [0] * 26
for c in s1:char1[num(c)] += 1
for c in s2:char2[num(c)] += 1
if char1 !=... | output | 1 | 95,411 | 0 | 190,823 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given two strings s and t, each of length n and consisting of lowercase Latin alphabets. You want to make s equal to t.
You can perform the following operation on s any number of times to achieve it —
* Choose any substring of ... | instruction | 0 | 95,412 | 0 | 190,824 |
Tags: dp, strings
Correct Solution:
```
from bisect import *
from collections import *
from math import gcd,ceil,sqrt,floor,inf
from heapq import *
from itertools import *
from operator import add,mul,sub,xor,truediv,floordiv
from functools import *
#-------------------------------------------------------------------... | output | 1 | 95,412 | 0 | 190,825 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given two strings s and t, each of length n and consisting of lowercase Latin alphabets. You want to make s equal to t.
You can perform the following operation on s any number of times to achieve it —
* Choose any substring of ... | instruction | 0 | 95,413 | 0 | 190,826 |
Tags: dp, strings
Correct Solution:
```
def num(c):
return ord(c) - 97
import sys
input = sys.stdin.readline
t = int(input())
for _ in range(t):
n = int(input())
s1 = input().strip()
s2 = input().strip()
char1 = [0] * 26
char2 = [0] * 26
for c in s1:
char1[num(c)] += 1
for c i... | output | 1 | 95,413 | 0 | 190,827 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given two strings s and t, each of length n and consisting of lowercase Latin alphabets. You want to make s equal to t.
You can perform the following operation on s any number of times to achieve it —
* Choose any substring of ... | instruction | 0 | 95,414 | 0 | 190,828 |
Tags: dp, strings
Correct Solution:
```
def read_int():
return int(input())
def read_ints():
return map(int, input().split(' '))
t = read_int()
for case_num in range(t):
n = read_int()
cnt = [0 for i in range(26)]
ps = [[0 for j in range(n + 1)] for i in range(26)]
pt = [[0 for j in range(n ... | output | 1 | 95,414 | 0 | 190,829 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given two strings s and t, each of length n and consisting of lowercase Latin alphabets. You want to make s equal to t.
You can perform the following operation on s any number of times to achieve it —
* Choose any substring of ... | instruction | 0 | 95,415 | 0 | 190,830 |
Tags: dp, strings
Correct Solution:
```
INF = float('inf')
def solve():
N = int(input())
A = input().strip()
B = input().strip()
Acount = [[0] * 26 for _ in range(N + 1)]
Bcount = [[0] * 26 for _ in range(N + 1)]
for i in range(N - 1, -1, -1):
Acount[i][ord(A[i]) - ord('a')] += 1
... | output | 1 | 95,415 | 0 | 190,831 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given two strings s and t, each of length n and consisting of lowercase Latin alphabets. You want to make s equal to t.
You can perform the following operation on s any number of times... | instruction | 0 | 95,416 | 0 | 190,832 |
No | output | 1 | 95,416 | 0 | 190,833 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given two strings s and t, each of length n and consisting of lowercase Latin alphabets. You want to make s equal to t.
You can perform the following operation on s any number of times... | instruction | 0 | 95,417 | 0 | 190,834 |
No | output | 1 | 95,417 | 0 | 190,835 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given two strings s and t, each of length n and consisting of lowercase Latin alphabets. You want to make s equal to t.
You can perform the following operation on s any number of times... | instruction | 0 | 95,418 | 0 | 190,836 |
No | output | 1 | 95,418 | 0 | 190,837 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given two strings s and t, each of length n and consisting of lowercase Latin alphabets. You want to make s equal to t.
You can perform the following operation on s any number of times... | instruction | 0 | 95,419 | 0 | 190,838 |
No | output | 1 | 95,419 | 0 | 190,839 |
Provide tags and a correct Python 3 solution for this coding contest problem.
A bitstring is a string consisting only of the characters 0 and 1. A bitstring is called k-balanced if every substring of size k of this bitstring has an equal amount of 0 and 1 characters (k/2 of each).
You are given an integer k and a str... | instruction | 0 | 95,437 | 0 | 190,874 |
Tags: implementation, strings
Correct Solution:
```
gans = []
for _ in range(int(input())):
n, k = map(int, input().split())
u = list(input())
if u == ['?'] * n:
gans.append('YES')
continue
cnt1 = cnt0 = 0
for j in range(k):
ok1 = False
ok0 = False
for i in ra... | output | 1 | 95,437 | 0 | 190,875 |
Provide tags and a correct Python 3 solution for this coding contest problem.
A bitstring is a string consisting only of the characters 0 and 1. A bitstring is called k-balanced if every substring of size k of this bitstring has an equal amount of 0 and 1 characters (k/2 of each).
You are given an integer k and a str... | instruction | 0 | 95,438 | 0 | 190,876 |
Tags: implementation, strings
Correct Solution:
```
# cook your dish here
def checker(A,k):
tot=0
o,z=0,0
for i in range(k):
# tot+=A[i]
if A[i]==1:
o+=1
elif A[i]==-1:
z+=1
# if tot!=0:
# return False
if z>k//2 or o>k//2:
retu... | output | 1 | 95,438 | 0 | 190,877 |
Provide tags and a correct Python 3 solution for this coding contest problem.
A bitstring is a string consisting only of the characters 0 and 1. A bitstring is called k-balanced if every substring of size k of this bitstring has an equal amount of 0 and 1 characters (k/2 of each).
You are given an integer k and a str... | instruction | 0 | 95,439 | 0 | 190,878 |
Tags: implementation, strings
Correct Solution:
```
for _ in range(int(input())):
n,k = map(int,input().split())
s = list(str(input()))
tt = 0
c = 0
a = 0
aa = 0
bb = 0
for i in range(n):
if i+k<n and s[i+k] == "?":
if s[i]!="?":
s[i+k] = s[i]
... | output | 1 | 95,439 | 0 | 190,879 |
Provide tags and a correct Python 3 solution for this coding contest problem.
A bitstring is a string consisting only of the characters 0 and 1. A bitstring is called k-balanced if every substring of size k of this bitstring has an equal amount of 0 and 1 characters (k/2 of each).
You are given an integer k and a str... | instruction | 0 | 95,440 | 0 | 190,880 |
Tags: implementation, strings
Correct Solution:
```
#from math import *
from bisect import *
from collections import *
from decimal import *
def inp():
return int(input())
def st():
return input().rstrip('\n')
def lis():
return list(map(int,input().split()))
def ma():
return map(int,input().split())
t=i... | output | 1 | 95,440 | 0 | 190,881 |
Provide tags and a correct Python 3 solution for this coding contest problem.
A bitstring is a string consisting only of the characters 0 and 1. A bitstring is called k-balanced if every substring of size k of this bitstring has an equal amount of 0 and 1 characters (k/2 of each).
You are given an integer k and a str... | instruction | 0 | 95,441 | 0 | 190,882 |
Tags: implementation, strings
Correct Solution:
```
'''
Auther: ghoshashis545 Ashis Ghosh
College: jalpaiguri Govt Enggineering College
'''
from os import path
import sys
from heapq import heappush,heappop
from functools import cmp_to_key as ctk
from collections import deque,defaultdict as dd
from bisect impo... | output | 1 | 95,441 | 0 | 190,883 |
Provide tags and a correct Python 3 solution for this coding contest problem.
A bitstring is a string consisting only of the characters 0 and 1. A bitstring is called k-balanced if every substring of size k of this bitstring has an equal amount of 0 and 1 characters (k/2 of each).
You are given an integer k and a str... | instruction | 0 | 95,442 | 0 | 190,884 |
Tags: implementation, strings
Correct Solution:
```
"""
Satwik_Tiwari ;) .
6th Sept , 2020 - Sunday
"""
#===============================================================================================
#importing some useful libraries.
from __future__ import division, print_function
from fractions import Frac... | output | 1 | 95,442 | 0 | 190,885 |
Provide tags and a correct Python 3 solution for this coding contest problem.
A bitstring is a string consisting only of the characters 0 and 1. A bitstring is called k-balanced if every substring of size k of this bitstring has an equal amount of 0 and 1 characters (k/2 of each).
You are given an integer k and a str... | instruction | 0 | 95,443 | 0 | 190,886 |
Tags: implementation, strings
Correct Solution:
```
import os
import sys
from io import BytesIO, IOBase
# region fastio
BUFSIZE = 8192
class FastIO(IOBase):
newlines = 0
def __init__(self, file):
self._fd = file.fileno()
self.buffer = BytesIO()
self.writable = "x" in file.mode or "r" not in file.mode
self.w... | output | 1 | 95,443 | 0 | 190,887 |
Provide tags and a correct Python 3 solution for this coding contest problem.
A bitstring is a string consisting only of the characters 0 and 1. A bitstring is called k-balanced if every substring of size k of this bitstring has an equal amount of 0 and 1 characters (k/2 of each).
You are given an integer k and a str... | instruction | 0 | 95,444 | 0 | 190,888 |
Tags: implementation, strings
Correct Solution:
```
def cktrue(n,k,s1):
G={'1':0,'0':0,'?':0}
for j in range(k):
i=s1[j]
G[i]=G[i]+1
if (G['0']>k//2 or G['1']>k//2):
return 0
for i in range(k,n):
G[s1[i-k]]=G[s1[i-k]]-1
G[s1[i]]=G[s1[i]]+1
if (G['0']>k//... | output | 1 | 95,444 | 0 | 190,889 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A bitstring is a string consisting only of the characters 0 and 1. A bitstring is called k-balanced if every substring of size k of this bitstring has an equal amount of 0 and 1 characters (k/2 ... | instruction | 0 | 95,445 | 0 | 190,890 |
Yes | output | 1 | 95,445 | 0 | 190,891 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A bitstring is a string consisting only of the characters 0 and 1. A bitstring is called k-balanced if every substring of size k of this bitstring has an equal amount of 0 and 1 characters (k/2 ... | instruction | 0 | 95,446 | 0 | 190,892 |
Yes | output | 1 | 95,446 | 0 | 190,893 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A bitstring is a string consisting only of the characters 0 and 1. A bitstring is called k-balanced if every substring of size k of this bitstring has an equal amount of 0 and 1 characters (k/2 ... | instruction | 0 | 95,447 | 0 | 190,894 |
Yes | output | 1 | 95,447 | 0 | 190,895 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A bitstring is a string consisting only of the characters 0 and 1. A bitstring is called k-balanced if every substring of size k of this bitstring has an equal amount of 0 and 1 characters (k/2 ... | instruction | 0 | 95,448 | 0 | 190,896 |
Yes | output | 1 | 95,448 | 0 | 190,897 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A bitstring is a string consisting only of the characters 0 and 1. A bitstring is called k-balanced if every substring of size k of this bitstring has an equal amount of 0 and 1 characters (k/2 ... | instruction | 0 | 95,449 | 0 | 190,898 |
No | output | 1 | 95,449 | 0 | 190,899 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A bitstring is a string consisting only of the characters 0 and 1. A bitstring is called k-balanced if every substring of size k of this bitstring has an equal amount of 0 and 1 characters (k/2 ... | instruction | 0 | 95,450 | 0 | 190,900 |
No | output | 1 | 95,450 | 0 | 190,901 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A bitstring is a string consisting only of the characters 0 and 1. A bitstring is called k-balanced if every substring of size k of this bitstring has an equal amount of 0 and 1 characters (k/2 ... | instruction | 0 | 95,451 | 0 | 190,902 |
No | output | 1 | 95,451 | 0 | 190,903 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A bitstring is a string consisting only of the characters 0 and 1. A bitstring is called k-balanced if every substring of size k of this bitstring has an equal amount of 0 and 1 characters (k/2 ... | instruction | 0 | 95,452 | 0 | 190,904 |
No | output | 1 | 95,452 | 0 | 190,905 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
After getting kicked out of her reporting job for not knowing the alphabet, Bessie has decided to attend school at the Fillet and Eggs Eater Academy. She has been making good progress with her s... | instruction | 0 | 95,703 | 0 | 191,406 |
No | output | 1 | 95,703 | 0 | 191,407 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
After getting kicked out of her reporting job for not knowing the alphabet, Bessie has decided to attend school at the Fillet and Eggs Eater Academy. She has been making good progress with her s... | instruction | 0 | 95,704 | 0 | 191,408 |
No | output | 1 | 95,704 | 0 | 191,409 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
After getting kicked out of her reporting job for not knowing the alphabet, Bessie has decided to attend school at the Fillet and Eggs Eater Academy. She has been making good progress with her s... | instruction | 0 | 95,705 | 0 | 191,410 |
No | output | 1 | 95,705 | 0 | 191,411 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Alice has a string consisting of characters 'A', 'B' and 'C'. Bob can use the following transitions on any substring of our string in any order any number of times:
* A <image> BC
* B <image> AC
* C <image> AB
* AAA <image> empty s... | instruction | 0 | 95,814 | 0 | 191,628 |
Tags: constructive algorithms, implementation, strings
Correct Solution:
```
# python3
import sys
def read_all_following_lines():
lines = sys.stdin.readlines()
return (tuple(map(int, line.split())) for line in lines)
class AbcString(object):
def __init__(self, string):
self.prefix_bc = [0]
... | output | 1 | 95,814 | 0 | 191,629 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Alice has a string consisting of characters 'A', 'B' and 'C'. Bob can use the following transitions on any substring of our string in any order any number of times:
* A <image> BC
* B <image> AC
* C <image> AB
* AAA <image> empty s... | instruction | 0 | 95,815 | 0 | 191,630 |
Tags: constructive algorithms, implementation, strings
Correct Solution:
```
def main():
s, t = input(), input()
s_info, t_info = fast_counter(s), fast_counter(t)
queries = int(input())
answer = ''
for _ in range(queries):
l1, r1, l2, r2 = map(int, input().split())
l1, l2 = l1 -... | output | 1 | 95,815 | 0 | 191,631 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Alice has a string consisting of characters 'A', 'B' and 'C'. Bob can use the following transitions on any substring of our string in any order any number of times:
* A <image> BC
* B <image> AC
* C <image> AB
* AAA <image> empty s... | instruction | 0 | 95,816 | 0 | 191,632 |
Tags: constructive algorithms, implementation, strings
Correct Solution:
```
def read():
s = input()
l = len(s)
r = [[0] * (l + 1), [0] * (l + 1)]
for i in range(l):
r[0][i + 1] = (r[0][i] + 1) * (s[i] == 'A')
r[1][i + 1] = r[1][i] + (s[i] != 'A')
return r
s, t = read(), read()
q = i... | output | 1 | 95,816 | 0 | 191,633 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Alice has a string consisting of characters 'A', 'B' and 'C'. Bob can use the following transitions on any substring of our string in any order any number of times:
* A <image> BC
* B <image> AC
* C <image> AB
* AAA <image> empty s... | instruction | 0 | 95,817 | 0 | 191,634 |
Tags: constructive algorithms, implementation, strings
Correct Solution:
```
def main():
s, t = input(), input()
s_info, t_info = fast_counter(s), fast_counter(t)
queries = int(input())
answer = ''
for _ in range(queries):
l1, r1, l2, r2 = map(int, input().split())
l1, l2 = l1 -... | output | 1 | 95,817 | 0 | 191,635 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Alice has a string consisting of characters 'A', 'B' and 'C'. Bob can use the following transitions on any substring of our string in any order any number of times:
* A <image> BC
* B <image> AC
* C <image> AB
* AAA <image> empty s... | instruction | 0 | 95,818 | 0 | 191,636 |
Tags: constructive algorithms, implementation, strings
Correct Solution:
```
def pref_counts(string, char):
result = [0]
for c in string:
result.append(result[-1] + (c == char))
return result
def left_counts(string, char):
result = [0]
for c in string:
result.append(result[-1] + 1 i... | output | 1 | 95,818 | 0 | 191,637 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Alice has a string consisting of characters 'A', 'B' and 'C'. Bob can use the following transitions on any substring of our string in any order any number of times:
* A <image> BC
* B <ima... | instruction | 0 | 95,819 | 0 | 191,638 |
No | output | 1 | 95,819 | 0 | 191,639 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Alice has a string consisting of characters 'A', 'B' and 'C'. Bob can use the following transitions on any substring of our string in any order any number of times:
* A <image> BC
* B <ima... | instruction | 0 | 95,820 | 0 | 191,640 |
No | output | 1 | 95,820 | 0 | 191,641 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Alice has a string consisting of characters 'A', 'B' and 'C'. Bob can use the following transitions on any substring of our string in any order any number of times:
* A <image> BC
* B <ima... | instruction | 0 | 95,821 | 0 | 191,642 |
No | output | 1 | 95,821 | 0 | 191,643 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Alice has a string consisting of characters 'A', 'B' and 'C'. Bob can use the following transitions on any substring of our string in any order any number of times:
* A <image> BC
* B <ima... | instruction | 0 | 95,822 | 0 | 191,644 |
No | output | 1 | 95,822 | 0 | 191,645 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given a string s consisting of n lowercase Latin letters. Polycarp wants to remove exactly k characters (k ≤ n) from the string s. Polycarp uses the following algorithm k times:
* if there is at least one letter 'a', remove the le... | instruction | 0 | 95,840 | 0 | 191,680 |
Tags: implementation
Correct Solution:
```
n,k = map(int,input().split(' '))
s = input()
z = 1
l = [0]*(26)
for i in range(0,len(s)):
l[ord(s[i])-97] = l[ord(s[i])-97]+1
for i in range(0,26):
c = chr(97+i)
z = 1
if k==0:
break
if s.find(c)!=-1:
if l[i]<=k and l[i]!=0:
s ... | output | 1 | 95,840 | 0 | 191,681 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given a string s consisting of n lowercase Latin letters. Polycarp wants to remove exactly k characters (k ≤ n) from the string s. Polycarp uses the following algorithm k times:
* if there is at least one letter 'a', remove the le... | instruction | 0 | 95,841 | 0 | 191,682 |
Tags: implementation
Correct Solution:
```
#!/usr/bin/env python3
#
# FILE: 999C.py
#
# @author: Arafat Hasan Jenin <opendoor.arafat[at]gmail[dot]com>
#
# LINK: http://codeforces.com/contest/999/problem/C
#
# DATE CREATED: 22-06-18 16:19:52 (+06)
# LAST MODIFIED: 23-06-18 02:31:13 (+06)
#
# VERDICT:
#
# DEVELOPMENT HIS... | output | 1 | 95,841 | 0 | 191,683 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given a string s consisting of n lowercase Latin letters. Polycarp wants to remove exactly k characters (k ≤ n) from the string s. Polycarp uses the following algorithm k times:
* if there is at least one letter 'a', remove the le... | instruction | 0 | 95,843 | 0 | 191,686 |
Tags: implementation
Correct Solution:
```
n=0
k=0
def reducedString(s:str):
alphabetList = []
index = 0
while index<26:
alphabetList.append(0)
index += 1
index = 0
#count how many of each character there are in the string
while index<n:
# print(ord(s[index])-ord('a'))... | output | 1 | 95,843 | 0 | 191,687 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given a string s consisting of n lowercase Latin letters. Polycarp wants to remove exactly k characters (k ≤ n) from the string s. Polycarp uses the following algorithm k times:
* if there is at least one letter 'a', remove the le... | instruction | 0 | 95,844 | 0 | 191,688 |
Tags: implementation
Correct Solution:
```
lower = [chr(i) for i in range(97,123)]
temp = input()
l = int(temp.split(" ")[0])
k = int(temp.split(" ")[1])
s = list((input()))
m = dict()
for i in range(l):
m[s[i]] = m.get(s[i],0)+1
m = sorted(m.items(),key=lambda d:d[0])
num = 0
for i in range(len(m)):
num = nu... | output | 1 | 95,844 | 0 | 191,689 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given a string s consisting of n lowercase Latin letters. Polycarp wants to remove exactly k characters (k ≤ n) from the string s. Polycarp uses the following algorithm k times:
* if there is at least one letter 'a', remove the le... | instruction | 0 | 95,845 | 0 | 191,690 |
Tags: implementation
Correct Solution:
```
n, k = map(int, input().split())
s = input()
cnt = [0 for i in range(26)]
for i in s:
cnt[ord(i) - ord("a")] += 1
# print("cnt =", cnt)
total = 0
cnt2 = [0 for i in range(26)]
for i in range(26):
if total + cnt[i] <= k:
cnt2[i] = cnt[i]
total += cnt[i]
... | output | 1 | 95,845 | 0 | 191,691 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given a string s consisting of n lowercase Latin letters. Polycarp wants to remove exactly k characters (k ≤ n) from the string s. Polycarp uses the following algorithm k times:
* if there is at least one letter 'a', remove the le... | instruction | 0 | 95,846 | 0 | 191,692 |
Tags: implementation
Correct Solution:
```
from string import ascii_lowercase
from collections import Counter, OrderedDict
def go():
n, k = (int(i) for i in input().split(' '))
s = [i for i in input()]
if n <= k:
return ''
c = dict(Counter(s))
new = OrderedDict()
t = 0
for i in ascii... | output | 1 | 95,846 | 0 | 191,693 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a string s consisting of n lowercase Latin letters. Polycarp wants to remove exactly k characters (k ≤ n) from the string s. Polycarp uses the following algorithm k times:
* if ... | instruction | 0 | 95,852 | 0 | 191,704 |
No | output | 1 | 95,852 | 0 | 191,705 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a string s consisting of n lowercase Latin letters. Polycarp wants to remove exactly k characters (k ≤ n) from the string s. Polycarp uses the following algorithm k times:
* if ... | instruction | 0 | 95,853 | 0 | 191,706 |
No | output | 1 | 95,853 | 0 | 191,707 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a string s consisting of n lowercase Latin letters. Polycarp wants to remove exactly k characters (k ≤ n) from the string s. Polycarp uses the following algorithm k times:
* if ... | instruction | 0 | 95,854 | 0 | 191,708 |
No | output | 1 | 95,854 | 0 | 191,709 |
Provide a correct Python 3 solution for this coding contest problem.
You are given a string S consisting of digits between `1` and `9`, inclusive. You can insert the letter `+` into some of the positions (possibly none) between two letters in this string. Here, `+` must not occur consecutively after insertion.
All st... | instruction | 0 | 95,966 | 0 | 191,932 |
"Correct Solution:
```
def bfs(s: str, n: int, i: int, j: int, k: int):
return k+int(s[j:]) if i==n-1 else bfs(s,n,i+1,i+1,k+int(s[j:i+1]))+bfs(s,n,i+1,j,k)
s=input()
n=len(s)
print(bfs(s,n,0,0,0))
``` | output | 1 | 95,966 | 0 | 191,933 |
Provide a correct Python 3 solution for this coding contest problem.
You are given a string S consisting of digits between `1` and `9`, inclusive. You can insert the letter `+` into some of the positions (possibly none) between two letters in this string. Here, `+` must not occur consecutively after insertion.
All st... | instruction | 0 | 95,967 | 0 | 191,934 |
"Correct Solution:
```
S = input()
l = len(S)
ans = 0
for i in range(l):
for j in range(i+1,l+1):
temp = int(S[i:j])
ans += temp * max(1,pow(2,i-1)) * max(1,pow(2,l-j-1))
print(ans)
``` | output | 1 | 95,967 | 0 | 191,935 |
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