message stringlengths 2 30.5k | message_type stringclasses 2 values | message_id int64 0 1 | conversation_id int64 237 109k | cluster float64 10 10 | __index_level_0__ int64 474 217k |
|---|---|---|---|---|---|
Provide a correct Python 3 solution for this coding contest problem.
We have had record hot temperatures this summer. To avoid heat stroke, you decided to buy a quantity of drinking water at the nearby supermarket. Two types of bottled water, 1 and 0.5 liter, are on sale at respective prices there. You have a definite quantity in your mind, but are willing to buy a quantity larger than that if: no combination of these bottles meets the quantity, or, the total price becomes lower.
Given the prices for each bottle of water and the total quantity needed, make a program to seek the lowest price to buy greater than or equal to the quantity required.
Input
The input is given in the following format.
$A$ $B$ $X$
The first line provides the prices for a 1-liter bottle $A$ ($1\leq A \leq 1000$), 500-milliliter bottle $B$ ($1 \leq B \leq 1000$), and the total water quantity needed $X$ ($1 \leq X \leq 20000$). All these values are given as integers, and the quantity of water in milliliters.
Output
Output the total price.
Examples
Input
180 100 2400
Output
460
Input
200 90 2018
Output
450 | instruction | 0 | 108,570 | 10 | 217,140 |
"Correct Solution:
```
a,b,x=map(int,input().split())
pay=0
if a//2<b:
if x==1000:
pay=a
elif x==500:
if b>a:
pay=a
else:
pay=b
else:
aa=x//1000
aaa=x%1000
if aaa>500:
pay=(aa+1)*a
elif aaa==0:
pay=aa*a
else:
pay=aa*a+b
else:
if x==500:
pay=b
else:
bb=x//500
bbb=x%500
if bbb==0:
pay=bb*b
else:
pay=(bb+1)*b
print(pay)
``` | output | 1 | 108,570 | 10 | 217,141 |
Provide a correct Python 3 solution for this coding contest problem.
We have had record hot temperatures this summer. To avoid heat stroke, you decided to buy a quantity of drinking water at the nearby supermarket. Two types of bottled water, 1 and 0.5 liter, are on sale at respective prices there. You have a definite quantity in your mind, but are willing to buy a quantity larger than that if: no combination of these bottles meets the quantity, or, the total price becomes lower.
Given the prices for each bottle of water and the total quantity needed, make a program to seek the lowest price to buy greater than or equal to the quantity required.
Input
The input is given in the following format.
$A$ $B$ $X$
The first line provides the prices for a 1-liter bottle $A$ ($1\leq A \leq 1000$), 500-milliliter bottle $B$ ($1 \leq B \leq 1000$), and the total water quantity needed $X$ ($1 \leq X \leq 20000$). All these values are given as integers, and the quantity of water in milliliters.
Output
Output the total price.
Examples
Input
180 100 2400
Output
460
Input
200 90 2018
Output
450 | instruction | 0 | 108,571 | 10 | 217,142 |
"Correct Solution:
```
a,b,x = list(map(int, input().split()))
t = a * (x // 1000) + b * -(-(x % 1000) // 500)
print(min(a * -(-x // 1000), b * -(-x // 500), t))
``` | output | 1 | 108,571 | 10 | 217,143 |
Provide a correct Python 3 solution for this coding contest problem.
We have had record hot temperatures this summer. To avoid heat stroke, you decided to buy a quantity of drinking water at the nearby supermarket. Two types of bottled water, 1 and 0.5 liter, are on sale at respective prices there. You have a definite quantity in your mind, but are willing to buy a quantity larger than that if: no combination of these bottles meets the quantity, or, the total price becomes lower.
Given the prices for each bottle of water and the total quantity needed, make a program to seek the lowest price to buy greater than or equal to the quantity required.
Input
The input is given in the following format.
$A$ $B$ $X$
The first line provides the prices for a 1-liter bottle $A$ ($1\leq A \leq 1000$), 500-milliliter bottle $B$ ($1 \leq B \leq 1000$), and the total water quantity needed $X$ ($1 \leq X \leq 20000$). All these values are given as integers, and the quantity of water in milliliters.
Output
Output the total price.
Examples
Input
180 100 2400
Output
460
Input
200 90 2018
Output
450 | instruction | 0 | 108,572 | 10 | 217,144 |
"Correct Solution:
```
A, B, X = map(int, input().split())
A = min(A, B * 2)
B = min(A, B)
n = -(-X // 500)
print(n // 2 * A + n % 2 * B)
``` | output | 1 | 108,572 | 10 | 217,145 |
Provide a correct Python 3 solution for this coding contest problem.
We have had record hot temperatures this summer. To avoid heat stroke, you decided to buy a quantity of drinking water at the nearby supermarket. Two types of bottled water, 1 and 0.5 liter, are on sale at respective prices there. You have a definite quantity in your mind, but are willing to buy a quantity larger than that if: no combination of these bottles meets the quantity, or, the total price becomes lower.
Given the prices for each bottle of water and the total quantity needed, make a program to seek the lowest price to buy greater than or equal to the quantity required.
Input
The input is given in the following format.
$A$ $B$ $X$
The first line provides the prices for a 1-liter bottle $A$ ($1\leq A \leq 1000$), 500-milliliter bottle $B$ ($1 \leq B \leq 1000$), and the total water quantity needed $X$ ($1 \leq X \leq 20000$). All these values are given as integers, and the quantity of water in milliliters.
Output
Output the total price.
Examples
Input
180 100 2400
Output
460
Input
200 90 2018
Output
450 | instruction | 0 | 108,573 | 10 | 217,146 |
"Correct Solution:
```
#標準入力
a,b,c = map(int,input().split())
#必要量を500で割った商を出力する
i = c // 500
#商が500で割り切れないなら個数を1足す
if c % 500 != 0:i += 1
#aよりb*2のほうが小さいなら1Lを買わないで500mlで個数を買った計算にしaの方が大きいなら両方を買う計算をする
if a >= b * 2:print(b * i)
elif a < b and c <= 1000:print(a)
else:print((i // 2) * a + (i % 2) * b)
``` | output | 1 | 108,573 | 10 | 217,147 |
Provide a correct Python 3 solution for this coding contest problem.
We have had record hot temperatures this summer. To avoid heat stroke, you decided to buy a quantity of drinking water at the nearby supermarket. Two types of bottled water, 1 and 0.5 liter, are on sale at respective prices there. You have a definite quantity in your mind, but are willing to buy a quantity larger than that if: no combination of these bottles meets the quantity, or, the total price becomes lower.
Given the prices for each bottle of water and the total quantity needed, make a program to seek the lowest price to buy greater than or equal to the quantity required.
Input
The input is given in the following format.
$A$ $B$ $X$
The first line provides the prices for a 1-liter bottle $A$ ($1\leq A \leq 1000$), 500-milliliter bottle $B$ ($1 \leq B \leq 1000$), and the total water quantity needed $X$ ($1 \leq X \leq 20000$). All these values are given as integers, and the quantity of water in milliliters.
Output
Output the total price.
Examples
Input
180 100 2400
Output
460
Input
200 90 2018
Output
450 | instruction | 0 | 108,574 | 10 | 217,148 |
"Correct Solution:
```
a,b,x=map(int,input().split())
ans=10**9
for i in range(21):
for j in range(41):
if i*1000+j*500>=x:
ans=min(ans,i*a+j*b)
print(ans)
``` | output | 1 | 108,574 | 10 | 217,149 |
Provide a correct Python 3 solution for this coding contest problem.
We have had record hot temperatures this summer. To avoid heat stroke, you decided to buy a quantity of drinking water at the nearby supermarket. Two types of bottled water, 1 and 0.5 liter, are on sale at respective prices there. You have a definite quantity in your mind, but are willing to buy a quantity larger than that if: no combination of these bottles meets the quantity, or, the total price becomes lower.
Given the prices for each bottle of water and the total quantity needed, make a program to seek the lowest price to buy greater than or equal to the quantity required.
Input
The input is given in the following format.
$A$ $B$ $X$
The first line provides the prices for a 1-liter bottle $A$ ($1\leq A \leq 1000$), 500-milliliter bottle $B$ ($1 \leq B \leq 1000$), and the total water quantity needed $X$ ($1 \leq X \leq 20000$). All these values are given as integers, and the quantity of water in milliliters.
Output
Output the total price.
Examples
Input
180 100 2400
Output
460
Input
200 90 2018
Output
450 | instruction | 0 | 108,575 | 10 | 217,150 |
"Correct Solution:
```
x, y, z = map(int, input().split())
lit = z // 500
if z % 500 != 0:
lit += 1
ans = min(y * lit, x * (lit // 2 + 1), x *(lit // 2) + y * (lit % 2))
print(ans)
``` | output | 1 | 108,575 | 10 | 217,151 |
Provide a correct Python 3 solution for this coding contest problem.
We have had record hot temperatures this summer. To avoid heat stroke, you decided to buy a quantity of drinking water at the nearby supermarket. Two types of bottled water, 1 and 0.5 liter, are on sale at respective prices there. You have a definite quantity in your mind, but are willing to buy a quantity larger than that if: no combination of these bottles meets the quantity, or, the total price becomes lower.
Given the prices for each bottle of water and the total quantity needed, make a program to seek the lowest price to buy greater than or equal to the quantity required.
Input
The input is given in the following format.
$A$ $B$ $X$
The first line provides the prices for a 1-liter bottle $A$ ($1\leq A \leq 1000$), 500-milliliter bottle $B$ ($1 \leq B \leq 1000$), and the total water quantity needed $X$ ($1 \leq X \leq 20000$). All these values are given as integers, and the quantity of water in milliliters.
Output
Output the total price.
Examples
Input
180 100 2400
Output
460
Input
200 90 2018
Output
450 | instruction | 0 | 108,576 | 10 | 217,152 |
"Correct Solution:
```
A, B, X = map(int, input().split())
if A > 2 * B:
A = 2 * B
if A < B:
B = A
ans = X // 1000 * A
X %= 1000
# print(ans + (B if X <= 500 else A))
a, b, x = A, B, X
wa = ans + (0 if X == 0 else (B if X <= 500 else A))
print(wa)
``` | output | 1 | 108,576 | 10 | 217,153 |
Provide a correct Python 3 solution for this coding contest problem.
We have had record hot temperatures this summer. To avoid heat stroke, you decided to buy a quantity of drinking water at the nearby supermarket. Two types of bottled water, 1 and 0.5 liter, are on sale at respective prices there. You have a definite quantity in your mind, but are willing to buy a quantity larger than that if: no combination of these bottles meets the quantity, or, the total price becomes lower.
Given the prices for each bottle of water and the total quantity needed, make a program to seek the lowest price to buy greater than or equal to the quantity required.
Input
The input is given in the following format.
$A$ $B$ $X$
The first line provides the prices for a 1-liter bottle $A$ ($1\leq A \leq 1000$), 500-milliliter bottle $B$ ($1 \leq B \leq 1000$), and the total water quantity needed $X$ ($1 \leq X \leq 20000$). All these values are given as integers, and the quantity of water in milliliters.
Output
Output the total price.
Examples
Input
180 100 2400
Output
460
Input
200 90 2018
Output
450 | instruction | 0 | 108,577 | 10 | 217,154 |
"Correct Solution:
```
a, b, x = map(int, input().split())
if a > b * 2:
m = (x + 499) // 500 * b
elif a < b or ((x - 1) % 1000) >= 500:
m = (x + 999) // 1000 * a
else:
m = x // 1000 * a + b
print(m)
``` | output | 1 | 108,577 | 10 | 217,155 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
We have had record hot temperatures this summer. To avoid heat stroke, you decided to buy a quantity of drinking water at the nearby supermarket. Two types of bottled water, 1 and 0.5 liter, are on sale at respective prices there. You have a definite quantity in your mind, but are willing to buy a quantity larger than that if: no combination of these bottles meets the quantity, or, the total price becomes lower.
Given the prices for each bottle of water and the total quantity needed, make a program to seek the lowest price to buy greater than or equal to the quantity required.
Input
The input is given in the following format.
$A$ $B$ $X$
The first line provides the prices for a 1-liter bottle $A$ ($1\leq A \leq 1000$), 500-milliliter bottle $B$ ($1 \leq B \leq 1000$), and the total water quantity needed $X$ ($1 \leq X \leq 20000$). All these values are given as integers, and the quantity of water in milliliters.
Output
Output the total price.
Examples
Input
180 100 2400
Output
460
Input
200 90 2018
Output
450
Submitted Solution:
```
A, B, X = map(int, input().split())
k = (X // 1000)
ans = k * min(A, 2*B)
r = X - 1000*k
if 0 < r <= 500:
ans += min(A, B)
elif 500 < r:
ans += min(A, 2*B)
print(ans)
``` | instruction | 0 | 108,578 | 10 | 217,156 |
Yes | output | 1 | 108,578 | 10 | 217,157 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
We have had record hot temperatures this summer. To avoid heat stroke, you decided to buy a quantity of drinking water at the nearby supermarket. Two types of bottled water, 1 and 0.5 liter, are on sale at respective prices there. You have a definite quantity in your mind, but are willing to buy a quantity larger than that if: no combination of these bottles meets the quantity, or, the total price becomes lower.
Given the prices for each bottle of water and the total quantity needed, make a program to seek the lowest price to buy greater than or equal to the quantity required.
Input
The input is given in the following format.
$A$ $B$ $X$
The first line provides the prices for a 1-liter bottle $A$ ($1\leq A \leq 1000$), 500-milliliter bottle $B$ ($1 \leq B \leq 1000$), and the total water quantity needed $X$ ($1 \leq X \leq 20000$). All these values are given as integers, and the quantity of water in milliliters.
Output
Output the total price.
Examples
Input
180 100 2400
Output
460
Input
200 90 2018
Output
450
Submitted Solution:
```
import math
a, b, x = map(int,input().split())
ans = 0
if a < b:
ans = math.ceil(x/1000)* a
print(ans)
elif a >= b*2:
print(math.ceil(x/500)*b)
else:
ans = (x // 1000)*a
if (x % 1000) > 500:
ans += a
elif x % 1000 == 0:
pass
else:
ans += b
print(ans)
``` | instruction | 0 | 108,579 | 10 | 217,158 |
Yes | output | 1 | 108,579 | 10 | 217,159 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
We have had record hot temperatures this summer. To avoid heat stroke, you decided to buy a quantity of drinking water at the nearby supermarket. Two types of bottled water, 1 and 0.5 liter, are on sale at respective prices there. You have a definite quantity in your mind, but are willing to buy a quantity larger than that if: no combination of these bottles meets the quantity, or, the total price becomes lower.
Given the prices for each bottle of water and the total quantity needed, make a program to seek the lowest price to buy greater than or equal to the quantity required.
Input
The input is given in the following format.
$A$ $B$ $X$
The first line provides the prices for a 1-liter bottle $A$ ($1\leq A \leq 1000$), 500-milliliter bottle $B$ ($1 \leq B \leq 1000$), and the total water quantity needed $X$ ($1 \leq X \leq 20000$). All these values are given as integers, and the quantity of water in milliliters.
Output
Output the total price.
Examples
Input
180 100 2400
Output
460
Input
200 90 2018
Output
450
Submitted Solution:
```
import math
A, B, X = map(int, input().split())
ans = float('inf')
for a in range(math.ceil(X/1000)+1):
if X-1000*a < 0: b = 0
else: b = math.ceil((X-1000*a)/500)
ans = min(ans, A*a+B*b)
print(ans)
``` | instruction | 0 | 108,580 | 10 | 217,160 |
Yes | output | 1 | 108,580 | 10 | 217,161 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
We have had record hot temperatures this summer. To avoid heat stroke, you decided to buy a quantity of drinking water at the nearby supermarket. Two types of bottled water, 1 and 0.5 liter, are on sale at respective prices there. You have a definite quantity in your mind, but are willing to buy a quantity larger than that if: no combination of these bottles meets the quantity, or, the total price becomes lower.
Given the prices for each bottle of water and the total quantity needed, make a program to seek the lowest price to buy greater than or equal to the quantity required.
Input
The input is given in the following format.
$A$ $B$ $X$
The first line provides the prices for a 1-liter bottle $A$ ($1\leq A \leq 1000$), 500-milliliter bottle $B$ ($1 \leq B \leq 1000$), and the total water quantity needed $X$ ($1 \leq X \leq 20000$). All these values are given as integers, and the quantity of water in milliliters.
Output
Output the total price.
Examples
Input
180 100 2400
Output
460
Input
200 90 2018
Output
450
Submitted Solution:
```
a,b,x = map(int, input().split())
if a >= b*2:
print(((x-1)//500+1)*b)
elif x%1000 > 500:
print(((x-1)//1000+1)*a)
else:
print(min(((x-1)//1000+1)*a, x//1000*a+b))
``` | instruction | 0 | 108,581 | 10 | 217,162 |
Yes | output | 1 | 108,581 | 10 | 217,163 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
We have had record hot temperatures this summer. To avoid heat stroke, you decided to buy a quantity of drinking water at the nearby supermarket. Two types of bottled water, 1 and 0.5 liter, are on sale at respective prices there. You have a definite quantity in your mind, but are willing to buy a quantity larger than that if: no combination of these bottles meets the quantity, or, the total price becomes lower.
Given the prices for each bottle of water and the total quantity needed, make a program to seek the lowest price to buy greater than or equal to the quantity required.
Input
The input is given in the following format.
$A$ $B$ $X$
The first line provides the prices for a 1-liter bottle $A$ ($1\leq A \leq 1000$), 500-milliliter bottle $B$ ($1 \leq B \leq 1000$), and the total water quantity needed $X$ ($1 \leq X \leq 20000$). All these values are given as integers, and the quantity of water in milliliters.
Output
Output the total price.
Examples
Input
180 100 2400
Output
460
Input
200 90 2018
Output
450
Submitted Solution:
```
a,b,n=list(map(int,input().split()))
if a>b*2:
print(((n+499)//500)*b)
elif a<b:
print(((n+999)//1000)*a)
elif n%1000>500:
print(((n+500)//1000)*a)
else:
print(((n//1000)*a)+b)
``` | instruction | 0 | 108,582 | 10 | 217,164 |
No | output | 1 | 108,582 | 10 | 217,165 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
We have had record hot temperatures this summer. To avoid heat stroke, you decided to buy a quantity of drinking water at the nearby supermarket. Two types of bottled water, 1 and 0.5 liter, are on sale at respective prices there. You have a definite quantity in your mind, but are willing to buy a quantity larger than that if: no combination of these bottles meets the quantity, or, the total price becomes lower.
Given the prices for each bottle of water and the total quantity needed, make a program to seek the lowest price to buy greater than or equal to the quantity required.
Input
The input is given in the following format.
$A$ $B$ $X$
The first line provides the prices for a 1-liter bottle $A$ ($1\leq A \leq 1000$), 500-milliliter bottle $B$ ($1 \leq B \leq 1000$), and the total water quantity needed $X$ ($1 \leq X \leq 20000$). All these values are given as integers, and the quantity of water in milliliters.
Output
Output the total price.
Examples
Input
180 100 2400
Output
460
Input
200 90 2018
Output
450
Submitted Solution:
```
a,b,n=list(map(int,input().split()))
if n%500!=0:n=n+500-n%500
if a>b*2:
print((n//500)*b)
elif a<b:
print((n//1000)*a)
else:
print(((n//1000)*a)+((n%1000)//500)*b)
``` | instruction | 0 | 108,583 | 10 | 217,166 |
No | output | 1 | 108,583 | 10 | 217,167 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
We have had record hot temperatures this summer. To avoid heat stroke, you decided to buy a quantity of drinking water at the nearby supermarket. Two types of bottled water, 1 and 0.5 liter, are on sale at respective prices there. You have a definite quantity in your mind, but are willing to buy a quantity larger than that if: no combination of these bottles meets the quantity, or, the total price becomes lower.
Given the prices for each bottle of water and the total quantity needed, make a program to seek the lowest price to buy greater than or equal to the quantity required.
Input
The input is given in the following format.
$A$ $B$ $X$
The first line provides the prices for a 1-liter bottle $A$ ($1\leq A \leq 1000$), 500-milliliter bottle $B$ ($1 \leq B \leq 1000$), and the total water quantity needed $X$ ($1 \leq X \leq 20000$). All these values are given as integers, and the quantity of water in milliliters.
Output
Output the total price.
Examples
Input
180 100 2400
Output
460
Input
200 90 2018
Output
450
Submitted Solution:
```
a,b,n=list(map(int,input().split()))
if a>b*2:
print(((n+499)//500)*b)
if n%1000>500:
print(((n+500)//1000)*a)
if a<b:
print(((n+999)//1000)*a)
else:
print(((n//1000)*a)+b)
``` | instruction | 0 | 108,584 | 10 | 217,168 |
No | output | 1 | 108,584 | 10 | 217,169 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
We have had record hot temperatures this summer. To avoid heat stroke, you decided to buy a quantity of drinking water at the nearby supermarket. Two types of bottled water, 1 and 0.5 liter, are on sale at respective prices there. You have a definite quantity in your mind, but are willing to buy a quantity larger than that if: no combination of these bottles meets the quantity, or, the total price becomes lower.
Given the prices for each bottle of water and the total quantity needed, make a program to seek the lowest price to buy greater than or equal to the quantity required.
Input
The input is given in the following format.
$A$ $B$ $X$
The first line provides the prices for a 1-liter bottle $A$ ($1\leq A \leq 1000$), 500-milliliter bottle $B$ ($1 \leq B \leq 1000$), and the total water quantity needed $X$ ($1 \leq X \leq 20000$). All these values are given as integers, and the quantity of water in milliliters.
Output
Output the total price.
Examples
Input
180 100 2400
Output
460
Input
200 90 2018
Output
450
Submitted Solution:
```
import math
A, B, X = list(map(int, input().split(' ')))
amount, cost = 0, 0
if A <= 2*B:
amount = math.floor(X/1000)*1000
cost = math.floor(X/1000)*A
if 0 < X-amount: cost += A
else:
amount = math.floor(X/500)*500
cost = math.floor(X/500)*B
if 0 < X-amount: cost += B
print(cost)
``` | instruction | 0 | 108,585 | 10 | 217,170 |
No | output | 1 | 108,585 | 10 | 217,171 |
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