text stringlengths 216 39.6k | conversation_id int64 219 108k | embedding list | cluster int64 11 11 |
|---|---|---|---|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You have written N problems to hold programming contests. The i-th problem will have a score of P_i points if used in a contest.
With these problems, you would like to hold as many contests as possible under the following condition:
* A contest has three problems. The first problem has a score not greater than A points, the second has a score between A + 1 and B points (inclusive), and the third has a score not less than B + 1 points.
The same problem should not be used in multiple contests. At most how many contests can be held?
Constraints
* 3 \leq N \leq 100
* 1 \leq P_i \leq 20 (1 \leq i \leq N)
* 1 \leq A < B < 20
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
N
A B
P_1 P_2 ... P_N
Output
Print the answer.
Examples
Input
7
5 15
1 10 16 2 7 20 12
Output
2
Input
8
3 8
5 5 5 10 10 10 15 20
Output
0
Input
3
5 6
5 6 10
Output
1
Submitted Solution:
```
n=int(input())
A,B=map(int, input().split())
p=list(map(int, input().split()))
p.sort()
t=0
y=0
u=0
g=0
for i in range(len(p)):
if t==0 and p[i]<=A:
t=p[i]
g+=1
elif y==0 and A+1<p[i] and p[i]<=B:
y=p[i]
g+=1
elif u==0 and p[i]>=B+1:
u=p[i]
if t!=0 and y!=0 and u!=0:
print(3)
elif t!=0 and y!=0:
print(2)
elif t!=0:
print(1)
else:
print(0)
```
No
| 29,822 | [
0.60888671875,
-0.118896484375,
-0.197021484375,
0.03546142578125,
-0.77001953125,
-0.08831787109375,
-0.1455078125,
0.56591796875,
0.06329345703125,
0.80517578125,
0.2296142578125,
-0.09130859375,
0.328125,
-0.68310546875,
-0.466796875,
-0.04681396484375,
-0.7041015625,
-0.6982421... | 11 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Have you ever had an infinite loop when you ran a hard-working program? It would be convenient to be able to determine in advance whether a program will stop executing without having to execute it.
Unfortunately, it is not possible to make such a decision for any program in the programming language you normally use. However, if you have a programming language that is much less computationally powerful, you may be able to write a program that determines if a program written in that language will stop.
Consider a programming language called TinyPower. Programs in this language are line sequences. On each line of the program, write the line number at the beginning and one sentence after it. The types of sentences that can be written in this language are as follows.
Sentence type | Behavior
--- | ---
ADD var1 var2 var3 | Assign the result of adding the value of variable var2 and the value of var3 to variable var1
ADD var1 var2 con | Assign the result of adding the value of the variable var2 and the constant con to the variable var1
SUB var1 var2 var3 | Assign the result of subtracting the value of var3 from the value of variable var2 to variable var1
SUB var1 var2 con | Substitute the result of subtracting the constant con from the value of the variable var2 into the variable var1
SET var1 var2 | Assign the value of variable var2 to variable var1
SET var1 con | Assign the constant con to the variable var1
IF var1 dest | Jump to line number dest only if the value of variable var1 is non-zero
HALT | Stop the program
Line numbers are positive integers, and the same line number will never appear more than once in the program. Variables are represented by a single lowercase letter, and constants and variable values are integers. No variable declaration is required, the initial value of the variable is 0.
Program execution starts with the first statement, and the statements are executed in the order in which they are lined up. However, as written in the table above, if the value of the variable in the IF statement is not 0, jump to the line specified by the line number written after the variable and start from the statement written in that line. Continue running. The program will stop when:
* When the HALT statement is executed.
* When trying to assign a negative integer or an integer greater than or equal to 16 to a variable (the value of the variable is not updated).
* When trying to jump to a line number that does not appear in the program.
* When you do not jump to any line from the last statement of the program.
Create a program that determines if a TinyPower program, given it, will stop.
Input
The input is given in the following format.
N
stmt1
stmt2
::
stmtN
The number of lines N (1 ≤ N ≤ 50) of the program is given on the first line. The following N lines are given the statement stmti of the TinyPower program. stmti is given in one of the following formats:
line ADD var1 var2 var3
Or
line ADD var1 var2 con
Or
line SUB var1 var2 var3
Or
line SUB var1 var2 con
Or
line SET var1 var2
Or
line SET var1 con
Or
line IF var1 dest
Or
line HALT
line, dest (1 ≤ line, dest ≤ 1000) is the line number, varj (one lowercase letter) is the variable, and con (0 ≤ con ≤ 15) is the constant. The delimiter in stmti is one blank character. It is assumed that one or more variables always appear in the program, and only five different variable names appear.
Output
When the program stops, the results of the variables appearing in the program are output in the lexicographic order of the variable names, separated by line breaks, and when it does not stop, "inf" is output. The result of the variable is output by separating the variable name and the value of the variable with "=".
Examples
Input
6
10 SET c 1
20 SET i 5
100 ADD s s i
110 SUB i i c
120 IF i 100
200 HALT
Output
c=1
i=0
s=15
Input
3
10 SET c 1
120 IF c 10
20 HALT
Output
inf
Input
3
111 SET c 1
12 SUB c c 2
777 SET a 4
Output
a=0
c=1
Submitted Solution:
```
n = int(input())
stmts = [input().split() for i in range(n)]
mapper = {}
for i, stmt in enumerate(stmts):
mapper[stmt[0]] = i
vn = {}
for stmt in stmts:
for ope in stmt[2:]:
if ope.isalpha() and ope not in vn:
vn[ope] = len(vn)
vs = [0]*len(vn)
def value(var):
if var.isalpha():
return vs[vn[var]]
return int(var)
def assign(var, x):
if not 0 <= x < 16:
assert 0
vs[vn[var]] = x
result = 1
state = set()
pc = 0
cnts = [0]*n
LIM = 16**len(vn) + 10
try:
while 1:
stmt = stmts[pc]
cnts[pc] += 1
if cnts[pc] > LIM:
result = 0
break
op = stmt[1]
if op == 'ADD':
v1, v2, v3 = stmt[2:]
assign(v1, value(v2) + value(v3))
pc += 1
elif op == 'SUB':
v1, v2, v3 = stmt[2:]
assign(v1, value(v2) - value(v3))
pc += 1
elif op == 'SET':
v1, v2 = stmt[2:]
assign(v1, value(v2))
pc += 1
elif op == 'IF':
v1, dest = stmt[2:]
if value(v1) > 0:
pc = mapper[dest]
else:
pc += 1
else: # 'HALT'
break
except:...
if result:
for k in sorted(vn):
print("%s=%d" % (k, vs[vn[k]]))
else:
print("inf")
```
No
| 29,934 | [
-0.06591796875,
0.068603515625,
-0.001560211181640625,
-0.104248046875,
-0.156982421875,
-0.487548828125,
0.2384033203125,
-0.130126953125,
0.01345062255859375,
0.6181640625,
0.68017578125,
0.11004638671875,
-0.0650634765625,
-0.9404296875,
-0.411376953125,
-0.1751708984375,
-0.46459... | 11 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Have you ever had an infinite loop when you ran a hard-working program? It would be convenient to be able to determine in advance whether a program will stop executing without having to execute it.
Unfortunately, it is not possible to make such a decision for any program in the programming language you normally use. However, if you have a programming language that is much less computationally powerful, you may be able to write a program that determines if a program written in that language will stop.
Consider a programming language called TinyPower. Programs in this language are line sequences. On each line of the program, write the line number at the beginning and one sentence after it. The types of sentences that can be written in this language are as follows.
Sentence type | Behavior
--- | ---
ADD var1 var2 var3 | Assign the result of adding the value of variable var2 and the value of var3 to variable var1
ADD var1 var2 con | Assign the result of adding the value of the variable var2 and the constant con to the variable var1
SUB var1 var2 var3 | Assign the result of subtracting the value of var3 from the value of variable var2 to variable var1
SUB var1 var2 con | Substitute the result of subtracting the constant con from the value of the variable var2 into the variable var1
SET var1 var2 | Assign the value of variable var2 to variable var1
SET var1 con | Assign the constant con to the variable var1
IF var1 dest | Jump to line number dest only if the value of variable var1 is non-zero
HALT | Stop the program
Line numbers are positive integers, and the same line number will never appear more than once in the program. Variables are represented by a single lowercase letter, and constants and variable values are integers. No variable declaration is required, the initial value of the variable is 0.
Program execution starts with the first statement, and the statements are executed in the order in which they are lined up. However, as written in the table above, if the value of the variable in the IF statement is not 0, jump to the line specified by the line number written after the variable and start from the statement written in that line. Continue running. The program will stop when:
* When the HALT statement is executed.
* When trying to assign a negative integer or an integer greater than or equal to 16 to a variable (the value of the variable is not updated).
* When trying to jump to a line number that does not appear in the program.
* When you do not jump to any line from the last statement of the program.
Create a program that determines if a TinyPower program, given it, will stop.
Input
The input is given in the following format.
N
stmt1
stmt2
::
stmtN
The number of lines N (1 ≤ N ≤ 50) of the program is given on the first line. The following N lines are given the statement stmti of the TinyPower program. stmti is given in one of the following formats:
line ADD var1 var2 var3
Or
line ADD var1 var2 con
Or
line SUB var1 var2 var3
Or
line SUB var1 var2 con
Or
line SET var1 var2
Or
line SET var1 con
Or
line IF var1 dest
Or
line HALT
line, dest (1 ≤ line, dest ≤ 1000) is the line number, varj (one lowercase letter) is the variable, and con (0 ≤ con ≤ 15) is the constant. The delimiter in stmti is one blank character. It is assumed that one or more variables always appear in the program, and only five different variable names appear.
Output
When the program stops, the results of the variables appearing in the program are output in the lexicographic order of the variable names, separated by line breaks, and when it does not stop, "inf" is output. The result of the variable is output by separating the variable name and the value of the variable with "=".
Examples
Input
6
10 SET c 1
20 SET i 5
100 ADD s s i
110 SUB i i c
120 IF i 100
200 HALT
Output
c=1
i=0
s=15
Input
3
10 SET c 1
120 IF c 10
20 HALT
Output
inf
Input
3
111 SET c 1
12 SUB c c 2
777 SET a 4
Output
a=0
c=1
Submitted Solution:
```
n = int(input())
stmts = [input().split() for i in range(n)]
mapper = {}
for i, stmt in enumerate(stmts):
mapper[stmt[0]] = i
vn = {}
for stmt in stmts:
for ope in stmt[2:]:
if ope.isalpha() and ope not in vn:
vn[ope] = len(vn)
vs = [0]*len(vn)
def check(x):
return 0 <= x < 16
def value(var):
if var.isalpha():
return vs[vn[var]]
return int(var)
def assign(var, x):
vs[vn[var]] = x
result = 1
state = set()
pc = 0
cnts = [0]*n
LIM = 16**5 + 10
while pc < n:
cnts[pc] += 1
if cnts[pc] > LIM:
result = 0
break
stmt = stmts[pc]
op = stmt[1]
if op == 'ADD':
v1, v2, v3 = stmt[2:]
if not check(value(v2) + value(v3)):
break
assign(v1, value(v2) + value(v3))
pc += 1
elif op == 'SUB':
v1, v2, v3 = stmt[2:]
if not check(value(v2) - value(v3)):
break
assign(v1, value(v2) - value(v3))
pc += 1
elif op == 'SET':
v1, v2 = stmt[2:]
assign(v1, value(v2))
pc += 1
elif op == 'IF':
v1, dest = stmt[2:]
if value(v1) > 0:
if dest not in mapper:
break
pc = mapper[dest]
else:
pc += 1
elif op == 'HALT': # 'HALT'
break
else:
assert 0
if result:
for k in sorted(vn):
print("%s=%d" % (k, vs[vn[k]]))
else:
print("inf")
```
No
| 29,935 | [
-0.06591796875,
0.068603515625,
-0.001560211181640625,
-0.104248046875,
-0.156982421875,
-0.487548828125,
0.2384033203125,
-0.130126953125,
0.01345062255859375,
0.6181640625,
0.68017578125,
0.11004638671875,
-0.0650634765625,
-0.9404296875,
-0.411376953125,
-0.1751708984375,
-0.46459... | 11 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Have you ever had an infinite loop when you ran a hard-working program? It would be convenient to be able to determine in advance whether a program will stop executing without having to execute it.
Unfortunately, it is not possible to make such a decision for any program in the programming language you normally use. However, if you have a programming language that is much less computationally powerful, you may be able to write a program that determines if a program written in that language will stop.
Consider a programming language called TinyPower. Programs in this language are line sequences. On each line of the program, write the line number at the beginning and one sentence after it. The types of sentences that can be written in this language are as follows.
Sentence type | Behavior
--- | ---
ADD var1 var2 var3 | Assign the result of adding the value of variable var2 and the value of var3 to variable var1
ADD var1 var2 con | Assign the result of adding the value of the variable var2 and the constant con to the variable var1
SUB var1 var2 var3 | Assign the result of subtracting the value of var3 from the value of variable var2 to variable var1
SUB var1 var2 con | Substitute the result of subtracting the constant con from the value of the variable var2 into the variable var1
SET var1 var2 | Assign the value of variable var2 to variable var1
SET var1 con | Assign the constant con to the variable var1
IF var1 dest | Jump to line number dest only if the value of variable var1 is non-zero
HALT | Stop the program
Line numbers are positive integers, and the same line number will never appear more than once in the program. Variables are represented by a single lowercase letter, and constants and variable values are integers. No variable declaration is required, the initial value of the variable is 0.
Program execution starts with the first statement, and the statements are executed in the order in which they are lined up. However, as written in the table above, if the value of the variable in the IF statement is not 0, jump to the line specified by the line number written after the variable and start from the statement written in that line. Continue running. The program will stop when:
* When the HALT statement is executed.
* When trying to assign a negative integer or an integer greater than or equal to 16 to a variable (the value of the variable is not updated).
* When trying to jump to a line number that does not appear in the program.
* When you do not jump to any line from the last statement of the program.
Create a program that determines if a TinyPower program, given it, will stop.
Input
The input is given in the following format.
N
stmt1
stmt2
::
stmtN
The number of lines N (1 ≤ N ≤ 50) of the program is given on the first line. The following N lines are given the statement stmti of the TinyPower program. stmti is given in one of the following formats:
line ADD var1 var2 var3
Or
line ADD var1 var2 con
Or
line SUB var1 var2 var3
Or
line SUB var1 var2 con
Or
line SET var1 var2
Or
line SET var1 con
Or
line IF var1 dest
Or
line HALT
line, dest (1 ≤ line, dest ≤ 1000) is the line number, varj (one lowercase letter) is the variable, and con (0 ≤ con ≤ 15) is the constant. The delimiter in stmti is one blank character. It is assumed that one or more variables always appear in the program, and only five different variable names appear.
Output
When the program stops, the results of the variables appearing in the program are output in the lexicographic order of the variable names, separated by line breaks, and when it does not stop, "inf" is output. The result of the variable is output by separating the variable name and the value of the variable with "=".
Examples
Input
6
10 SET c 1
20 SET i 5
100 ADD s s i
110 SUB i i c
120 IF i 100
200 HALT
Output
c=1
i=0
s=15
Input
3
10 SET c 1
120 IF c 10
20 HALT
Output
inf
Input
3
111 SET c 1
12 SUB c c 2
777 SET a 4
Output
a=0
c=1
Submitted Solution:
```
n = int(input())
stmts = [input().split() for i in range(n)]
mapper = {}
for i, stmt in enumerate(stmts):
mapper[stmt[0]] = i
vs = [None]*26
for stmt in stmts:
for ope in stmt[2:]:
if ope.isalpha():
vs[ord(ope)-97] = 0
def check(x):
return 0 <= x <= 16
def value(var):
if var.isalpha():
o = ord(var)-97
return vs[o]
return int(var)
def assign(var, x):
o = ord(var)-97
vs[o] = x
result = 1
state = set()
pc = 0
while pc < n:
st = (pc, tuple(vs))
if st in state:
result = 0
break
state.add(st)
stmt = stmts[pc]
op = stmt[1]
if op == 'ADD':
v1, v2, v3 = stmt[2:]
if not check(value(v2) + value(v3)):
break
assign(v1, value(v2) + value(v3))
pc += 1
elif op == 'SUB':
v1, v2, v3 = stmt[2:]
if not check(value(v2) - value(v3)):
break
assign(v1, value(v2) - value(v3))
pc += 1
elif op == 'SET':
v1, v2 = stmt[2:]
assign(v1, value(v2))
pc += 1
elif op == 'IF':
v1, dest = stmt[2:]
if value(v1) > 0:
if dest not in mapper:
break
pc = mapper[dest]
else:
pc += 1
else: # 'HALT'
break
if result:
for i in range(26):
if vs[i] is not None:
print("%c=%d" % (97+i, vs[i]))
else:
print("inf")
```
No
| 29,936 | [
-0.06591796875,
0.068603515625,
-0.001560211181640625,
-0.104248046875,
-0.156982421875,
-0.487548828125,
0.2384033203125,
-0.130126953125,
0.01345062255859375,
0.6181640625,
0.68017578125,
0.11004638671875,
-0.0650634765625,
-0.9404296875,
-0.411376953125,
-0.1751708984375,
-0.46459... | 11 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Have you ever had an infinite loop when you ran a hard-working program? It would be convenient to be able to determine in advance whether a program will stop executing without having to execute it.
Unfortunately, it is not possible to make such a decision for any program in the programming language you normally use. However, if you have a programming language that is much less computationally powerful, you may be able to write a program that determines if a program written in that language will stop.
Consider a programming language called TinyPower. Programs in this language are line sequences. On each line of the program, write the line number at the beginning and one sentence after it. The types of sentences that can be written in this language are as follows.
Sentence type | Behavior
--- | ---
ADD var1 var2 var3 | Assign the result of adding the value of variable var2 and the value of var3 to variable var1
ADD var1 var2 con | Assign the result of adding the value of the variable var2 and the constant con to the variable var1
SUB var1 var2 var3 | Assign the result of subtracting the value of var3 from the value of variable var2 to variable var1
SUB var1 var2 con | Substitute the result of subtracting the constant con from the value of the variable var2 into the variable var1
SET var1 var2 | Assign the value of variable var2 to variable var1
SET var1 con | Assign the constant con to the variable var1
IF var1 dest | Jump to line number dest only if the value of variable var1 is non-zero
HALT | Stop the program
Line numbers are positive integers, and the same line number will never appear more than once in the program. Variables are represented by a single lowercase letter, and constants and variable values are integers. No variable declaration is required, the initial value of the variable is 0.
Program execution starts with the first statement, and the statements are executed in the order in which they are lined up. However, as written in the table above, if the value of the variable in the IF statement is not 0, jump to the line specified by the line number written after the variable and start from the statement written in that line. Continue running. The program will stop when:
* When the HALT statement is executed.
* When trying to assign a negative integer or an integer greater than or equal to 16 to a variable (the value of the variable is not updated).
* When trying to jump to a line number that does not appear in the program.
* When you do not jump to any line from the last statement of the program.
Create a program that determines if a TinyPower program, given it, will stop.
Input
The input is given in the following format.
N
stmt1
stmt2
::
stmtN
The number of lines N (1 ≤ N ≤ 50) of the program is given on the first line. The following N lines are given the statement stmti of the TinyPower program. stmti is given in one of the following formats:
line ADD var1 var2 var3
Or
line ADD var1 var2 con
Or
line SUB var1 var2 var3
Or
line SUB var1 var2 con
Or
line SET var1 var2
Or
line SET var1 con
Or
line IF var1 dest
Or
line HALT
line, dest (1 ≤ line, dest ≤ 1000) is the line number, varj (one lowercase letter) is the variable, and con (0 ≤ con ≤ 15) is the constant. The delimiter in stmti is one blank character. It is assumed that one or more variables always appear in the program, and only five different variable names appear.
Output
When the program stops, the results of the variables appearing in the program are output in the lexicographic order of the variable names, separated by line breaks, and when it does not stop, "inf" is output. The result of the variable is output by separating the variable name and the value of the variable with "=".
Examples
Input
6
10 SET c 1
20 SET i 5
100 ADD s s i
110 SUB i i c
120 IF i 100
200 HALT
Output
c=1
i=0
s=15
Input
3
10 SET c 1
120 IF c 10
20 HALT
Output
inf
Input
3
111 SET c 1
12 SUB c c 2
777 SET a 4
Output
a=0
c=1
Submitted Solution:
```
n = int(input())
stmts = [input().split() for i in range(n)]
mapper = {}
for i, stmt in enumerate(stmts):
mapper[stmt[0]] = i
vs = [None]*26
for stmt in stmts:
for ope in stmt[2:]:
if ope.isalpha():
vs[ord(ope)-97] = 0
def check(x):
return 0 <= x <= 16
def value(var):
if var.isalpha():
o = ord(var)-97
return vs[o]
return int(var)
def assign(var, x):
o = ord(var)-97
vs[o] = x
result = 1
state = set()
pc = 0
cnts = [0]*n
LIM = 15**5+10
while pc < n:
cnts[pc] += 1
if cnts[pc] > LIM:
result = 0
break
stmt = stmts[pc]
op = stmt[1]
if op == 'ADD':
v1, v2, v3 = stmt[2:]
if not check(value(v2) + value(v3)):
break
assign(v1, value(v2) + value(v3))
pc += 1
elif op == 'SUB':
v1, v2, v3 = stmt[2:]
if not check(value(v2) - value(v3)):
break
assign(v1, value(v2) - value(v3))
pc += 1
elif op == 'SET':
v1, v2 = stmt[2:]
assign(v1, value(v2))
pc += 1
elif op == 'IF':
v1, dest = stmt[2:]
if value(v1) > 0:
if dest not in mapper:
break
pc = mapper[dest]
else:
pc += 1
else: # 'HALT'
break
if result:
for i in range(26):
if vs[i] is not None:
print("%c=%d" % (97+i, vs[i]))
else:
print("inf")
```
No
| 29,937 | [
-0.06591796875,
0.068603515625,
-0.001560211181640625,
-0.104248046875,
-0.156982421875,
-0.487548828125,
0.2384033203125,
-0.130126953125,
0.01345062255859375,
0.6181640625,
0.68017578125,
0.11004638671875,
-0.0650634765625,
-0.9404296875,
-0.411376953125,
-0.1751708984375,
-0.46459... | 11 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Write a program which reads a $ n \times m$ matrix $A$ and a $m \times 1$ vector $b$, and prints their product $Ab$.
A column vector with m elements is represented by the following equation.
\\[ b = \left( \begin{array}{c} b_1 \\\ b_2 \\\ : \\\ b_m \\\ \end{array} \right) \\]
A $n \times m$ matrix with $m$ column vectors, each of which consists of $n$ elements, is represented by the following equation.
\\[ A = \left( \begin{array}{cccc} a_{11} & a_{12} & ... & a_{1m} \\\ a_{21} & a_{22} & ... & a_{2m} \\\ : & : & : & : \\\ a_{n1} & a_{n2} & ... & a_{nm} \\\ \end{array} \right) \\]
$i$-th element of a $m \times 1$ column vector $b$ is represented by $b_i$ ($i = 1, 2, ..., m$), and the element in $i$-th row and $j$-th column of a matrix $A$ is represented by $a_{ij}$ ($i = 1, 2, ..., n,$ $j = 1, 2, ..., m$).
The product of a $n \times m$ matrix $A$ and a $m \times 1$ column vector $b$ is a $n \times 1$ column vector $c$, and $c_i$ is obtained by the following formula:
\\[ c_i = \sum_{j=1}^m a_{ij}b_j = a_{i1}b_1 + a_{i2}b_2 + ... + a_{im}b_m \\]
Constraints
* $1 \leq n, m \leq 100$
* $0 \leq b_i, a_{ij} \leq 1000$
Input
In the first line, two integers $n$ and $m$ are given. In the following $n$ lines, $a_{ij}$ are given separated by a single space character. In the next $m$ lines, $b_i$ is given in a line.
Output
The output consists of $n$ lines. Print $c_i$ in a line.
Example
Input
3 4
1 2 0 1
0 3 0 1
4 1 1 0
1
2
3
0
Output
5
6
9
Submitted Solution:
```
n, m = map(int, input().split())
A = list(list(map(int, input().split())) for _ in range(n))
b = list(int(input()) for _ in range(m))
for i in range(n):
ans = 0
for j in range(m):
ans += A[i][j] * b[j]
print(ans)
```
Yes
| 30,052 | [
0.285400390625,
-0.147705078125,
0.020050048828125,
-0.2451171875,
-0.253173828125,
-0.17724609375,
-0.260498046875,
0.0157012939453125,
0.0108184814453125,
0.72314453125,
0.432861328125,
0.1380615234375,
0.02349853515625,
-0.57861328125,
-0.505859375,
-0.147216796875,
-0.20495605468... | 11 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Write a program which reads a $ n \times m$ matrix $A$ and a $m \times 1$ vector $b$, and prints their product $Ab$.
A column vector with m elements is represented by the following equation.
\\[ b = \left( \begin{array}{c} b_1 \\\ b_2 \\\ : \\\ b_m \\\ \end{array} \right) \\]
A $n \times m$ matrix with $m$ column vectors, each of which consists of $n$ elements, is represented by the following equation.
\\[ A = \left( \begin{array}{cccc} a_{11} & a_{12} & ... & a_{1m} \\\ a_{21} & a_{22} & ... & a_{2m} \\\ : & : & : & : \\\ a_{n1} & a_{n2} & ... & a_{nm} \\\ \end{array} \right) \\]
$i$-th element of a $m \times 1$ column vector $b$ is represented by $b_i$ ($i = 1, 2, ..., m$), and the element in $i$-th row and $j$-th column of a matrix $A$ is represented by $a_{ij}$ ($i = 1, 2, ..., n,$ $j = 1, 2, ..., m$).
The product of a $n \times m$ matrix $A$ and a $m \times 1$ column vector $b$ is a $n \times 1$ column vector $c$, and $c_i$ is obtained by the following formula:
\\[ c_i = \sum_{j=1}^m a_{ij}b_j = a_{i1}b_1 + a_{i2}b_2 + ... + a_{im}b_m \\]
Constraints
* $1 \leq n, m \leq 100$
* $0 \leq b_i, a_{ij} \leq 1000$
Input
In the first line, two integers $n$ and $m$ are given. In the following $n$ lines, $a_{ij}$ are given separated by a single space character. In the next $m$ lines, $b_i$ is given in a line.
Output
The output consists of $n$ lines. Print $c_i$ in a line.
Example
Input
3 4
1 2 0 1
0 3 0 1
4 1 1 0
1
2
3
0
Output
5
6
9
Submitted Solution:
```
import sys
n,m=map(int,input().split())
A=[0]*n
B=[0]*m
C=[0]*n
for i in range(0,n):
A[i]=list(map(int, input().split()))
for i in range(0,m):
B[i]=int(input())
for i in range(0,n):
for j in range(0,m):
C[i]+=A[i][j]*B[j]
print(C[i])
```
Yes
| 30,053 | [
0.285400390625,
-0.147705078125,
0.020050048828125,
-0.2451171875,
-0.253173828125,
-0.17724609375,
-0.260498046875,
0.0157012939453125,
0.0108184814453125,
0.72314453125,
0.432861328125,
0.1380615234375,
0.02349853515625,
-0.57861328125,
-0.505859375,
-0.147216796875,
-0.20495605468... | 11 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Write a program which reads a $ n \times m$ matrix $A$ and a $m \times 1$ vector $b$, and prints their product $Ab$.
A column vector with m elements is represented by the following equation.
\\[ b = \left( \begin{array}{c} b_1 \\\ b_2 \\\ : \\\ b_m \\\ \end{array} \right) \\]
A $n \times m$ matrix with $m$ column vectors, each of which consists of $n$ elements, is represented by the following equation.
\\[ A = \left( \begin{array}{cccc} a_{11} & a_{12} & ... & a_{1m} \\\ a_{21} & a_{22} & ... & a_{2m} \\\ : & : & : & : \\\ a_{n1} & a_{n2} & ... & a_{nm} \\\ \end{array} \right) \\]
$i$-th element of a $m \times 1$ column vector $b$ is represented by $b_i$ ($i = 1, 2, ..., m$), and the element in $i$-th row and $j$-th column of a matrix $A$ is represented by $a_{ij}$ ($i = 1, 2, ..., n,$ $j = 1, 2, ..., m$).
The product of a $n \times m$ matrix $A$ and a $m \times 1$ column vector $b$ is a $n \times 1$ column vector $c$, and $c_i$ is obtained by the following formula:
\\[ c_i = \sum_{j=1}^m a_{ij}b_j = a_{i1}b_1 + a_{i2}b_2 + ... + a_{im}b_m \\]
Constraints
* $1 \leq n, m \leq 100$
* $0 \leq b_i, a_{ij} \leq 1000$
Input
In the first line, two integers $n$ and $m$ are given. In the following $n$ lines, $a_{ij}$ are given separated by a single space character. In the next $m$ lines, $b_i$ is given in a line.
Output
The output consists of $n$ lines. Print $c_i$ in a line.
Example
Input
3 4
1 2 0 1
0 3 0 1
4 1 1 0
1
2
3
0
Output
5
6
9
Submitted Solution:
```
n,m=map(int,input().split())
A=[list(map(int,input().split())) for i in range(n)]
B=[int(input())for i in range(m)]
for i in range(n):
kotae=0
for j in range(m):
kotae+=A[i][j]*B[j]
print(kotae)
```
Yes
| 30,054 | [
0.285400390625,
-0.147705078125,
0.020050048828125,
-0.2451171875,
-0.253173828125,
-0.17724609375,
-0.260498046875,
0.0157012939453125,
0.0108184814453125,
0.72314453125,
0.432861328125,
0.1380615234375,
0.02349853515625,
-0.57861328125,
-0.505859375,
-0.147216796875,
-0.20495605468... | 11 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Write a program which reads a $ n \times m$ matrix $A$ and a $m \times 1$ vector $b$, and prints their product $Ab$.
A column vector with m elements is represented by the following equation.
\\[ b = \left( \begin{array}{c} b_1 \\\ b_2 \\\ : \\\ b_m \\\ \end{array} \right) \\]
A $n \times m$ matrix with $m$ column vectors, each of which consists of $n$ elements, is represented by the following equation.
\\[ A = \left( \begin{array}{cccc} a_{11} & a_{12} & ... & a_{1m} \\\ a_{21} & a_{22} & ... & a_{2m} \\\ : & : & : & : \\\ a_{n1} & a_{n2} & ... & a_{nm} \\\ \end{array} \right) \\]
$i$-th element of a $m \times 1$ column vector $b$ is represented by $b_i$ ($i = 1, 2, ..., m$), and the element in $i$-th row and $j$-th column of a matrix $A$ is represented by $a_{ij}$ ($i = 1, 2, ..., n,$ $j = 1, 2, ..., m$).
The product of a $n \times m$ matrix $A$ and a $m \times 1$ column vector $b$ is a $n \times 1$ column vector $c$, and $c_i$ is obtained by the following formula:
\\[ c_i = \sum_{j=1}^m a_{ij}b_j = a_{i1}b_1 + a_{i2}b_2 + ... + a_{im}b_m \\]
Constraints
* $1 \leq n, m \leq 100$
* $0 \leq b_i, a_{ij} \leq 1000$
Input
In the first line, two integers $n$ and $m$ are given. In the following $n$ lines, $a_{ij}$ are given separated by a single space character. In the next $m$ lines, $b_i$ is given in a line.
Output
The output consists of $n$ lines. Print $c_i$ in a line.
Example
Input
3 4
1 2 0 1
0 3 0 1
4 1 1 0
1
2
3
0
Output
5
6
9
Submitted Solution:
```
N, M = map(int, input().split())
A = [list(map(int, input().split())) for _ in range(N)]
B = [int(input()) for _ in range(M)]
for i in range(N):
cnt = 0
for j in range(M):
cnt += A[i][j] * B[j]
print(cnt)
```
Yes
| 30,055 | [
0.285400390625,
-0.147705078125,
0.020050048828125,
-0.2451171875,
-0.253173828125,
-0.17724609375,
-0.260498046875,
0.0157012939453125,
0.0108184814453125,
0.72314453125,
0.432861328125,
0.1380615234375,
0.02349853515625,
-0.57861328125,
-0.505859375,
-0.147216796875,
-0.20495605468... | 11 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Write a program which reads a $ n \times m$ matrix $A$ and a $m \times 1$ vector $b$, and prints their product $Ab$.
A column vector with m elements is represented by the following equation.
\\[ b = \left( \begin{array}{c} b_1 \\\ b_2 \\\ : \\\ b_m \\\ \end{array} \right) \\]
A $n \times m$ matrix with $m$ column vectors, each of which consists of $n$ elements, is represented by the following equation.
\\[ A = \left( \begin{array}{cccc} a_{11} & a_{12} & ... & a_{1m} \\\ a_{21} & a_{22} & ... & a_{2m} \\\ : & : & : & : \\\ a_{n1} & a_{n2} & ... & a_{nm} \\\ \end{array} \right) \\]
$i$-th element of a $m \times 1$ column vector $b$ is represented by $b_i$ ($i = 1, 2, ..., m$), and the element in $i$-th row and $j$-th column of a matrix $A$ is represented by $a_{ij}$ ($i = 1, 2, ..., n,$ $j = 1, 2, ..., m$).
The product of a $n \times m$ matrix $A$ and a $m \times 1$ column vector $b$ is a $n \times 1$ column vector $c$, and $c_i$ is obtained by the following formula:
\\[ c_i = \sum_{j=1}^m a_{ij}b_j = a_{i1}b_1 + a_{i2}b_2 + ... + a_{im}b_m \\]
Constraints
* $1 \leq n, m \leq 100$
* $0 \leq b_i, a_{ij} \leq 1000$
Input
In the first line, two integers $n$ and $m$ are given. In the following $n$ lines, $a_{ij}$ are given separated by a single space character. In the next $m$ lines, $b_i$ is given in a line.
Output
The output consists of $n$ lines. Print $c_i$ in a line.
Example
Input
3 4
1 2 0 1
0 3 0 1
4 1 1 0
1
2
3
0
Output
5
6
9
Submitted Solution:
```
(n, m) = [int(i) for i in input().split()]
a = [[]]
b = []
for i in range(n):
A.append([int(j) for j in input().split()]
for i in range(m):
b.append(int(input()))
c = []
for i range(n):
s = 0
for j in range(m):
m += A[i][j] * b[j]
print(s)
```
No
| 30,056 | [
0.285400390625,
-0.147705078125,
0.020050048828125,
-0.2451171875,
-0.253173828125,
-0.17724609375,
-0.260498046875,
0.0157012939453125,
0.0108184814453125,
0.72314453125,
0.432861328125,
0.1380615234375,
0.02349853515625,
-0.57861328125,
-0.505859375,
-0.147216796875,
-0.20495605468... | 11 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Write a program which reads a $ n \times m$ matrix $A$ and a $m \times 1$ vector $b$, and prints their product $Ab$.
A column vector with m elements is represented by the following equation.
\\[ b = \left( \begin{array}{c} b_1 \\\ b_2 \\\ : \\\ b_m \\\ \end{array} \right) \\]
A $n \times m$ matrix with $m$ column vectors, each of which consists of $n$ elements, is represented by the following equation.
\\[ A = \left( \begin{array}{cccc} a_{11} & a_{12} & ... & a_{1m} \\\ a_{21} & a_{22} & ... & a_{2m} \\\ : & : & : & : \\\ a_{n1} & a_{n2} & ... & a_{nm} \\\ \end{array} \right) \\]
$i$-th element of a $m \times 1$ column vector $b$ is represented by $b_i$ ($i = 1, 2, ..., m$), and the element in $i$-th row and $j$-th column of a matrix $A$ is represented by $a_{ij}$ ($i = 1, 2, ..., n,$ $j = 1, 2, ..., m$).
The product of a $n \times m$ matrix $A$ and a $m \times 1$ column vector $b$ is a $n \times 1$ column vector $c$, and $c_i$ is obtained by the following formula:
\\[ c_i = \sum_{j=1}^m a_{ij}b_j = a_{i1}b_1 + a_{i2}b_2 + ... + a_{im}b_m \\]
Constraints
* $1 \leq n, m \leq 100$
* $0 \leq b_i, a_{ij} \leq 1000$
Input
In the first line, two integers $n$ and $m$ are given. In the following $n$ lines, $a_{ij}$ are given separated by a single space character. In the next $m$ lines, $b_i$ is given in a line.
Output
The output consists of $n$ lines. Print $c_i$ in a line.
Example
Input
3 4
1 2 0 1
0 3 0 1
4 1 1 0
1
2
3
0
Output
5
6
9
Submitted Solution:
```
nums = list(map(int, input().split()))
sum_li = []
for i in range(nums[0]):
line = list(map(int, input().split()))
sum_li.append(sum(line))
for i in range(nums[0]):
n = int(input())
sum_li[i] += n
input()
for i in range(nums[0]): print(sum_li[i])
```
No
| 30,057 | [
0.285400390625,
-0.147705078125,
0.020050048828125,
-0.2451171875,
-0.253173828125,
-0.17724609375,
-0.260498046875,
0.0157012939453125,
0.0108184814453125,
0.72314453125,
0.432861328125,
0.1380615234375,
0.02349853515625,
-0.57861328125,
-0.505859375,
-0.147216796875,
-0.20495605468... | 11 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Write a program which reads a $ n \times m$ matrix $A$ and a $m \times 1$ vector $b$, and prints their product $Ab$.
A column vector with m elements is represented by the following equation.
\\[ b = \left( \begin{array}{c} b_1 \\\ b_2 \\\ : \\\ b_m \\\ \end{array} \right) \\]
A $n \times m$ matrix with $m$ column vectors, each of which consists of $n$ elements, is represented by the following equation.
\\[ A = \left( \begin{array}{cccc} a_{11} & a_{12} & ... & a_{1m} \\\ a_{21} & a_{22} & ... & a_{2m} \\\ : & : & : & : \\\ a_{n1} & a_{n2} & ... & a_{nm} \\\ \end{array} \right) \\]
$i$-th element of a $m \times 1$ column vector $b$ is represented by $b_i$ ($i = 1, 2, ..., m$), and the element in $i$-th row and $j$-th column of a matrix $A$ is represented by $a_{ij}$ ($i = 1, 2, ..., n,$ $j = 1, 2, ..., m$).
The product of a $n \times m$ matrix $A$ and a $m \times 1$ column vector $b$ is a $n \times 1$ column vector $c$, and $c_i$ is obtained by the following formula:
\\[ c_i = \sum_{j=1}^m a_{ij}b_j = a_{i1}b_1 + a_{i2}b_2 + ... + a_{im}b_m \\]
Constraints
* $1 \leq n, m \leq 100$
* $0 \leq b_i, a_{ij} \leq 1000$
Input
In the first line, two integers $n$ and $m$ are given. In the following $n$ lines, $a_{ij}$ are given separated by a single space character. In the next $m$ lines, $b_i$ is given in a line.
Output
The output consists of $n$ lines. Print $c_i$ in a line.
Example
Input
3 4
1 2 0 1
0 3 0 1
4 1 1 0
1
2
3
0
Output
5
6
9
Submitted Solution:
```
#! python3
# matrix_vector_multiplication.py
n, m = [int(x) for x in input().split(' ')]
a = [[int(x) for x in input(' ').split()] for i in range(n)]
b = [int(input()) for i in range(m)]
rsts = []
for i in range(n):
rst = 0
for j in range(m):
rst += a[i][j] * b[j]
rsts.append(rst)
for rst in rsts:
print(rst)
```
No
| 30,058 | [
0.285400390625,
-0.147705078125,
0.020050048828125,
-0.2451171875,
-0.253173828125,
-0.17724609375,
-0.260498046875,
0.0157012939453125,
0.0108184814453125,
0.72314453125,
0.432861328125,
0.1380615234375,
0.02349853515625,
-0.57861328125,
-0.505859375,
-0.147216796875,
-0.20495605468... | 11 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Write a program which reads a $ n \times m$ matrix $A$ and a $m \times 1$ vector $b$, and prints their product $Ab$.
A column vector with m elements is represented by the following equation.
\\[ b = \left( \begin{array}{c} b_1 \\\ b_2 \\\ : \\\ b_m \\\ \end{array} \right) \\]
A $n \times m$ matrix with $m$ column vectors, each of which consists of $n$ elements, is represented by the following equation.
\\[ A = \left( \begin{array}{cccc} a_{11} & a_{12} & ... & a_{1m} \\\ a_{21} & a_{22} & ... & a_{2m} \\\ : & : & : & : \\\ a_{n1} & a_{n2} & ... & a_{nm} \\\ \end{array} \right) \\]
$i$-th element of a $m \times 1$ column vector $b$ is represented by $b_i$ ($i = 1, 2, ..., m$), and the element in $i$-th row and $j$-th column of a matrix $A$ is represented by $a_{ij}$ ($i = 1, 2, ..., n,$ $j = 1, 2, ..., m$).
The product of a $n \times m$ matrix $A$ and a $m \times 1$ column vector $b$ is a $n \times 1$ column vector $c$, and $c_i$ is obtained by the following formula:
\\[ c_i = \sum_{j=1}^m a_{ij}b_j = a_{i1}b_1 + a_{i2}b_2 + ... + a_{im}b_m \\]
Constraints
* $1 \leq n, m \leq 100$
* $0 \leq b_i, a_{ij} \leq 1000$
Input
In the first line, two integers $n$ and $m$ are given. In the following $n$ lines, $a_{ij}$ are given separated by a single space character. In the next $m$ lines, $b_i$ is given in a line.
Output
The output consists of $n$ lines. Print $c_i$ in a line.
Example
Input
3 4
1 2 0 1
0 3 0 1
4 1 1 0
1
2
3
0
Output
5
6
9
Submitted Solution:
```
#a???A?????????,b???A??????
a,b=map(int,input().split())
A=[]
B=[]
for i in range(a):
A.append([int(j) for j in input().split()])
for i in range(b):
B.append(int(input()))
for i in range(a):
s=0
for j in range(b):
s+=A[i][j]*B[j]
print(s)
print()
```
No
| 30,059 | [
0.285400390625,
-0.147705078125,
0.020050048828125,
-0.2451171875,
-0.253173828125,
-0.17724609375,
-0.260498046875,
0.0157012939453125,
0.0108184814453125,
0.72314453125,
0.432861328125,
0.1380615234375,
0.02349853515625,
-0.57861328125,
-0.505859375,
-0.147216796875,
-0.20495605468... | 11 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Ivan plays some computer game. There are n quests in the game. Each quest can be upgraded once, this increases the reward for its completion. Each quest has 3 parameters a_{i}, b_{i}, p_{i}: reward for completing quest before upgrade, reward for completing quest after upgrade (a_{i} < b_{i}) and probability of successful completing the quest.
Each second Ivan can try to complete one quest and he will succeed with probability p_{i}. In case of success Ivan will get the reward and opportunity to upgrade any one quest (not necessary the one he just completed). In case of failure he gets nothing. Quests do not vanish after completing.
Ivan has t seconds. He wants to maximize expected value of his total gain after t seconds. Help him to calculate this value.
Input
First line contains 2 integers n ( 1 ≤ n ≤ 10^{5}) and t ( 1 ≤ t ≤ 10^{10}) — number of quests and total time.
Following n lines contain description of quests. Each description is 3 numbers a_{i} b_{i} p_{i} (1 ≤ a_{i} < b_{i} ≤ 10^{8}, 0 < p_{i} < 1) — reward for completing quest before upgrade, reward for completing quest after upgrade and probability of successful completing of quest. a_{i} and b_{i} are integers. All probabilities are given with at most 9 decimal places.
Output
Print the expected value.
Your answer will be accepted if absolute or relative error does not exceed 10^{-6}. Formally, let your answer be a, and the jury's answer be b. Your answer is considered correct if (|a-b|)/(max(b, 1)) ≤ 10^{-6}.
Examples
Input
3 2
3 1000 0.5
1 2 0.48
3 20 0.3
Output
252.2500000000000
Input
2 2
1 1000 0.1
2 3 0.2
Output
20.7200000000000
Submitted Solution:
```
import sys
n, t = map(int, sys.stdin.readline().strip().split())
a = [0] * n
b = [0] * n
p = [0] * n
for i in range(n):
a[i], b[i], p[i] = map(float, sys.stdin.readline().strip().split())
ans = max(a[i] * p[i] * t for i in range(n))
reward = max(b[i] * p[i] for i in range(n))
ans = max(ans, max(
a[i] * (1 - (1 - p[i]) ** t) + reward * (t - (1 - (1 - p[i]) ** t) / p[i])
for i in range(n)))
print('%.10f' % ans)
```
No
| 30,076 | [
0.6279296875,
0.1192626953125,
-0.2322998046875,
0.1649169921875,
-0.5791015625,
-0.56982421875,
-0.2017822265625,
0.248291015625,
0.08843994140625,
0.994140625,
0.487548828125,
-0.0828857421875,
0.02313232421875,
-0.5654296875,
-0.32958984375,
0.07916259765625,
-0.6513671875,
-1.1... | 11 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Sasha likes programming. Once, during a very long contest, Sasha decided that he was a bit tired and needed to relax. So he did. But since Sasha isn't an ordinary guy, he prefers to relax unusually. During leisure time Sasha likes to upsolve unsolved problems because upsolving is very useful.
Therefore, Sasha decided to upsolve the following problem:
You have an array a with n integers. You need to count the number of funny pairs (l, r) (l ≤ r). To check if a pair (l, r) is a funny pair, take mid = (l + r - 1)/(2), then if r - l + 1 is an even number and a_l ⊕ a_{l+1} ⊕ … ⊕ a_{mid} = a_{mid + 1} ⊕ a_{mid + 2} ⊕ … ⊕ a_r, then the pair is funny. In other words, ⊕ of elements of the left half of the subarray from l to r should be equal to ⊕ of elements of the right half. Note that ⊕ denotes the [bitwise XOR operation](https://en.wikipedia.org/wiki/Bitwise_operation#XOR).
It is time to continue solving the contest, so Sasha asked you to solve this task.
Input
The first line contains one integer n (2 ≤ n ≤ 3 ⋅ 10^5) — the size of the array.
The second line contains n integers a_1, a_2, …, a_n (0 ≤ a_i < 2^{20}) — array itself.
Output
Print one integer — the number of funny pairs. You should consider only pairs where r - l + 1 is even number.
Examples
Input
5
1 2 3 4 5
Output
1
Input
6
3 2 2 3 7 6
Output
3
Input
3
42 4 2
Output
0
Note
Be as cool as Sasha, upsolve problems!
In the first example, the only funny pair is (2, 5), as 2 ⊕ 3 = 4 ⊕ 5 = 1.
In the second example, funny pairs are (2, 3), (1, 4), and (3, 6).
In the third example, there are no funny pairs.
Submitted Solution:
```
from collections import defaultdict
n = int(input())
a = list(map(int, input().split()))
t = [0] * n
t[0] = a[0]
for i in range(1, n):
t[i] = t[i - 1] ^ a[i] # a_i ^...^ a_j = t[j] ^ t[i]
r = {0: defaultdict(int), 1: defaultdict(int)}
r[1][0] = 1
res = 0
for i in range(n):
res += r[i % 2][t[i]]
r[i % 2][t[i]] += 1
print(res)
```
Yes
| 30,101 | [
0.55517578125,
0.02642822265625,
-0.299072265625,
-0.44677734375,
-0.630859375,
-0.83544921875,
-0.10174560546875,
0.1458740234375,
0.11798095703125,
1.03125,
0.69580078125,
-0.1978759765625,
0.156982421875,
-0.94091796875,
-0.552734375,
0.054473876953125,
-0.405517578125,
-0.81054... | 11 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Sasha likes programming. Once, during a very long contest, Sasha decided that he was a bit tired and needed to relax. So he did. But since Sasha isn't an ordinary guy, he prefers to relax unusually. During leisure time Sasha likes to upsolve unsolved problems because upsolving is very useful.
Therefore, Sasha decided to upsolve the following problem:
You have an array a with n integers. You need to count the number of funny pairs (l, r) (l ≤ r). To check if a pair (l, r) is a funny pair, take mid = (l + r - 1)/(2), then if r - l + 1 is an even number and a_l ⊕ a_{l+1} ⊕ … ⊕ a_{mid} = a_{mid + 1} ⊕ a_{mid + 2} ⊕ … ⊕ a_r, then the pair is funny. In other words, ⊕ of elements of the left half of the subarray from l to r should be equal to ⊕ of elements of the right half. Note that ⊕ denotes the [bitwise XOR operation](https://en.wikipedia.org/wiki/Bitwise_operation#XOR).
It is time to continue solving the contest, so Sasha asked you to solve this task.
Input
The first line contains one integer n (2 ≤ n ≤ 3 ⋅ 10^5) — the size of the array.
The second line contains n integers a_1, a_2, …, a_n (0 ≤ a_i < 2^{20}) — array itself.
Output
Print one integer — the number of funny pairs. You should consider only pairs where r - l + 1 is even number.
Examples
Input
5
1 2 3 4 5
Output
1
Input
6
3 2 2 3 7 6
Output
3
Input
3
42 4 2
Output
0
Note
Be as cool as Sasha, upsolve problems!
In the first example, the only funny pair is (2, 5), as 2 ⊕ 3 = 4 ⊕ 5 = 1.
In the second example, funny pairs are (2, 3), (1, 4), and (3, 6).
In the third example, there are no funny pairs.
Submitted Solution:
```
n=int(input())
b={(0,0):1}
ans,i,x=0,0,0
for a in map(int,input().split()):
x^=a
i+=1
t=b.get((x,i%2),0)
ans+=t
b[x,i%2]=t+1
print(ans)
```
Yes
| 30,102 | [
0.56298828125,
0.0236663818359375,
-0.298828125,
-0.433349609375,
-0.63134765625,
-0.833984375,
-0.1063232421875,
0.1514892578125,
0.1051025390625,
1.0224609375,
0.69482421875,
-0.1829833984375,
0.1590576171875,
-0.92822265625,
-0.54248046875,
0.048309326171875,
-0.408935546875,
-0... | 11 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Sasha likes programming. Once, during a very long contest, Sasha decided that he was a bit tired and needed to relax. So he did. But since Sasha isn't an ordinary guy, he prefers to relax unusually. During leisure time Sasha likes to upsolve unsolved problems because upsolving is very useful.
Therefore, Sasha decided to upsolve the following problem:
You have an array a with n integers. You need to count the number of funny pairs (l, r) (l ≤ r). To check if a pair (l, r) is a funny pair, take mid = (l + r - 1)/(2), then if r - l + 1 is an even number and a_l ⊕ a_{l+1} ⊕ … ⊕ a_{mid} = a_{mid + 1} ⊕ a_{mid + 2} ⊕ … ⊕ a_r, then the pair is funny. In other words, ⊕ of elements of the left half of the subarray from l to r should be equal to ⊕ of elements of the right half. Note that ⊕ denotes the [bitwise XOR operation](https://en.wikipedia.org/wiki/Bitwise_operation#XOR).
It is time to continue solving the contest, so Sasha asked you to solve this task.
Input
The first line contains one integer n (2 ≤ n ≤ 3 ⋅ 10^5) — the size of the array.
The second line contains n integers a_1, a_2, …, a_n (0 ≤ a_i < 2^{20}) — array itself.
Output
Print one integer — the number of funny pairs. You should consider only pairs where r - l + 1 is even number.
Examples
Input
5
1 2 3 4 5
Output
1
Input
6
3 2 2 3 7 6
Output
3
Input
3
42 4 2
Output
0
Note
Be as cool as Sasha, upsolve problems!
In the first example, the only funny pair is (2, 5), as 2 ⊕ 3 = 4 ⊕ 5 = 1.
In the second example, funny pairs are (2, 3), (1, 4), and (3, 6).
In the third example, there are no funny pairs.
Submitted Solution:
```
n = int(input())
lis = list(map(int,input().split()))
mat=[[0]*(2**20+5) for i in range(2)]
ans=a=0
mat[1][0]=1
for i in range(n):
a = a^lis[i]
ans+=mat[i%2][a]
mat[i%2][a]+=1
print(ans)
```
Yes
| 30,103 | [
0.56298828125,
0.0236663818359375,
-0.298828125,
-0.433349609375,
-0.63134765625,
-0.833984375,
-0.1063232421875,
0.1514892578125,
0.1051025390625,
1.0224609375,
0.69482421875,
-0.1829833984375,
0.1590576171875,
-0.92822265625,
-0.54248046875,
0.048309326171875,
-0.408935546875,
-0... | 11 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Sasha likes programming. Once, during a very long contest, Sasha decided that he was a bit tired and needed to relax. So he did. But since Sasha isn't an ordinary guy, he prefers to relax unusually. During leisure time Sasha likes to upsolve unsolved problems because upsolving is very useful.
Therefore, Sasha decided to upsolve the following problem:
You have an array a with n integers. You need to count the number of funny pairs (l, r) (l ≤ r). To check if a pair (l, r) is a funny pair, take mid = (l + r - 1)/(2), then if r - l + 1 is an even number and a_l ⊕ a_{l+1} ⊕ … ⊕ a_{mid} = a_{mid + 1} ⊕ a_{mid + 2} ⊕ … ⊕ a_r, then the pair is funny. In other words, ⊕ of elements of the left half of the subarray from l to r should be equal to ⊕ of elements of the right half. Note that ⊕ denotes the [bitwise XOR operation](https://en.wikipedia.org/wiki/Bitwise_operation#XOR).
It is time to continue solving the contest, so Sasha asked you to solve this task.
Input
The first line contains one integer n (2 ≤ n ≤ 3 ⋅ 10^5) — the size of the array.
The second line contains n integers a_1, a_2, …, a_n (0 ≤ a_i < 2^{20}) — array itself.
Output
Print one integer — the number of funny pairs. You should consider only pairs where r - l + 1 is even number.
Examples
Input
5
1 2 3 4 5
Output
1
Input
6
3 2 2 3 7 6
Output
3
Input
3
42 4 2
Output
0
Note
Be as cool as Sasha, upsolve problems!
In the first example, the only funny pair is (2, 5), as 2 ⊕ 3 = 4 ⊕ 5 = 1.
In the second example, funny pairs are (2, 3), (1, 4), and (3, 6).
In the third example, there are no funny pairs.
Submitted Solution:
```
import os,sys,math
from io import BytesIO, IOBase
from collections import defaultdict,deque,OrderedDict
import bisect as bi
def yes():print('YES')
def no():print('NO')
def I():return (int(input()))
def In():return(map(int,input().split()))
def ln():return list(map(int,input().split()))
def Sn():return input().strip()
BUFSIZE = 8192
#complete the main function with number of test cases to complete greater than x
def find_gt(a, x):
i = bi.bisect_left(a, x)
if i != len(a):
return i
else:
return len(a)
def solve():
n=I()
l=list(In())
ans,x=0,0
dp=[{},{}]
dp[1][0]=1
for i in range(n):
x^=l[i]
ans+=dp[i%2].get(x,0)
if dp[i%2].get(x,-1)!=-1:
dp[i%2][x]+=1
else:
dp[i%2][x]=1
print(ans)
pass
def main():
T=1
for i in range(T):
solve()
M = 998244353
P = 1000000007
class FastIO(IOBase):
newlines = 0
def __init__(self, file):
self._fd = file.fileno()
self.buffer = BytesIO()
self.writable = "x" in file.mode or "r" not in file.mode
self.write = self.buffer.write if self.writable else None
def read(self):
while True:
b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
if not b:
break
ptr = self.buffer.tell()
self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
self.newlines = 0
return self.buffer.read()
def readline(self):
while self.newlines == 0:
b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
self.newlines = b.count(b"\n") + (not b)
ptr = self.buffer.tell()
self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
self.newlines -= 1
return self.buffer.readline()
def flush(self):
if self.writable:
os.write(self._fd, self.buffer.getvalue())
self.buffer.truncate(0), self.buffer.seek(0)
class IOWrapper(IOBase):
def __init__(self, file):
self.buffer = FastIO(file)
self.flush = self.buffer.flush
self.writable = self.buffer.writable
self.write = lambda s: self.buffer.write(s.encode("ascii"))
self.read = lambda: self.buffer.read().decode("ascii")
self.readline = lambda: self.buffer.readline().decode("ascii")
def print(*args, **kwargs):
"""Prints the values to a stream, or to sys.stdout by default."""
sep, file = kwargs.pop("sep", " "), kwargs.pop("file", sys.stdout)
at_start = True
for x in args:
if not at_start:
file.write(sep)
file.write(str(x))
at_start = False
file.write(kwargs.pop("end", "\n"))
if kwargs.pop("flush", False):
file.flush()
if sys.version_info[0] < 3:
sys.stdin, sys.stdout = FastIO(sys.stdin), FastIO(sys.stdout)
else:
sys.stdin, sys.stdout = IOWrapper(sys.stdin), IOWrapper(sys.stdout)
input = lambda: sys.stdin.readline().rstrip("\r\n")
# endregion
if __name__ == '__main__':
main()
```
Yes
| 30,104 | [
0.5654296875,
0.021728515625,
-0.29541015625,
-0.431396484375,
-0.6357421875,
-0.83447265625,
-0.096435546875,
0.1514892578125,
0.11083984375,
1.033203125,
0.6953125,
-0.1986083984375,
0.15087890625,
-0.93310546875,
-0.5419921875,
0.052337646484375,
-0.394775390625,
-0.810546875,
... | 11 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Sasha likes programming. Once, during a very long contest, Sasha decided that he was a bit tired and needed to relax. So he did. But since Sasha isn't an ordinary guy, he prefers to relax unusually. During leisure time Sasha likes to upsolve unsolved problems because upsolving is very useful.
Therefore, Sasha decided to upsolve the following problem:
You have an array a with n integers. You need to count the number of funny pairs (l, r) (l ≤ r). To check if a pair (l, r) is a funny pair, take mid = (l + r - 1)/(2), then if r - l + 1 is an even number and a_l ⊕ a_{l+1} ⊕ … ⊕ a_{mid} = a_{mid + 1} ⊕ a_{mid + 2} ⊕ … ⊕ a_r, then the pair is funny. In other words, ⊕ of elements of the left half of the subarray from l to r should be equal to ⊕ of elements of the right half. Note that ⊕ denotes the [bitwise XOR operation](https://en.wikipedia.org/wiki/Bitwise_operation#XOR).
It is time to continue solving the contest, so Sasha asked you to solve this task.
Input
The first line contains one integer n (2 ≤ n ≤ 3 ⋅ 10^5) — the size of the array.
The second line contains n integers a_1, a_2, …, a_n (0 ≤ a_i < 2^{20}) — array itself.
Output
Print one integer — the number of funny pairs. You should consider only pairs where r - l + 1 is even number.
Examples
Input
5
1 2 3 4 5
Output
1
Input
6
3 2 2 3 7 6
Output
3
Input
3
42 4 2
Output
0
Note
Be as cool as Sasha, upsolve problems!
In the first example, the only funny pair is (2, 5), as 2 ⊕ 3 = 4 ⊕ 5 = 1.
In the second example, funny pairs are (2, 3), (1, 4), and (3, 6).
In the third example, there are no funny pairs.
Submitted Solution:
```
def fn(lst):
result = 0
for x in lst:
result =result^int(x)
return result
n= int(input())
count=0
a= list(input().split())
for l in range(1,len(a)+1):
for r in range(l,len(a)+1):
if l<=r and (r-l+1)%2==0:
b= int((l+r-1)/2)
b=b-1
l=l-1
r=r-1
m=[]
n=[]
for i in range(l,b+1):
m.append(a[i])
for j in range(b+1,r+1):
n.append(a[j])
if fn(m)==fn(n):
count+=1
print(m)
print(n)
print(count)
```
No
| 30,105 | [
0.5595703125,
0.0157318115234375,
-0.300537109375,
-0.433349609375,
-0.63330078125,
-0.82568359375,
-0.1060791015625,
0.1549072265625,
0.10162353515625,
1.0087890625,
0.6982421875,
-0.194091796875,
0.1702880859375,
-0.923828125,
-0.54296875,
0.049957275390625,
-0.411376953125,
-0.8... | 11 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Sasha likes programming. Once, during a very long contest, Sasha decided that he was a bit tired and needed to relax. So he did. But since Sasha isn't an ordinary guy, he prefers to relax unusually. During leisure time Sasha likes to upsolve unsolved problems because upsolving is very useful.
Therefore, Sasha decided to upsolve the following problem:
You have an array a with n integers. You need to count the number of funny pairs (l, r) (l ≤ r). To check if a pair (l, r) is a funny pair, take mid = (l + r - 1)/(2), then if r - l + 1 is an even number and a_l ⊕ a_{l+1} ⊕ … ⊕ a_{mid} = a_{mid + 1} ⊕ a_{mid + 2} ⊕ … ⊕ a_r, then the pair is funny. In other words, ⊕ of elements of the left half of the subarray from l to r should be equal to ⊕ of elements of the right half. Note that ⊕ denotes the [bitwise XOR operation](https://en.wikipedia.org/wiki/Bitwise_operation#XOR).
It is time to continue solving the contest, so Sasha asked you to solve this task.
Input
The first line contains one integer n (2 ≤ n ≤ 3 ⋅ 10^5) — the size of the array.
The second line contains n integers a_1, a_2, …, a_n (0 ≤ a_i < 2^{20}) — array itself.
Output
Print one integer — the number of funny pairs. You should consider only pairs where r - l + 1 is even number.
Examples
Input
5
1 2 3 4 5
Output
1
Input
6
3 2 2 3 7 6
Output
3
Input
3
42 4 2
Output
0
Note
Be as cool as Sasha, upsolve problems!
In the first example, the only funny pair is (2, 5), as 2 ⊕ 3 = 4 ⊕ 5 = 1.
In the second example, funny pairs are (2, 3), (1, 4), and (3, 6).
In the third example, there are no funny pairs.
Submitted Solution:
```
def Solve2(array,l,r,count):
#print (l,r)
if r <= len(array) and l < len(array):
if r-l == 1:
return array[l-1]^array[r-1]
if (r+l-1)%2 != 0:
left = Solve2(array,l,l+int((r-l+2)/2)-1,count)
right = Solve2(array,l+int((r-l+2)/2),r+1,count)
else:
left = Solve2(array,l,l+int((r-l+1)/2)-1,count)
right = Solve2(array,l+int((r-l+1)/2),r,count)
if left == right and left :
#print (left)
count[0] += 1
def Solve(array):
count = [0]
n = len(array)
for i in range(n-1):
if array[i] == array[i+1]:
count[0] += 1
for i in range(1,n+1):
k = n
if (k+i-1)%2 != 0:
k -= 1
if k-i >= 1:
#print ('start')
Solve2(array,i,k,count)
return count[0]
def main():
n = int(input())
array = list(map(int,input().split()))
print (Solve(array))
main()
```
No
| 30,106 | [
0.56201171875,
0.01433563232421875,
-0.298095703125,
-0.427490234375,
-0.62744140625,
-0.82958984375,
-0.1097412109375,
0.1619873046875,
0.11260986328125,
1.005859375,
0.6865234375,
-0.1883544921875,
0.1715087890625,
-0.92822265625,
-0.54296875,
0.05029296875,
-0.4052734375,
-0.812... | 11 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Sasha likes programming. Once, during a very long contest, Sasha decided that he was a bit tired and needed to relax. So he did. But since Sasha isn't an ordinary guy, he prefers to relax unusually. During leisure time Sasha likes to upsolve unsolved problems because upsolving is very useful.
Therefore, Sasha decided to upsolve the following problem:
You have an array a with n integers. You need to count the number of funny pairs (l, r) (l ≤ r). To check if a pair (l, r) is a funny pair, take mid = (l + r - 1)/(2), then if r - l + 1 is an even number and a_l ⊕ a_{l+1} ⊕ … ⊕ a_{mid} = a_{mid + 1} ⊕ a_{mid + 2} ⊕ … ⊕ a_r, then the pair is funny. In other words, ⊕ of elements of the left half of the subarray from l to r should be equal to ⊕ of elements of the right half. Note that ⊕ denotes the [bitwise XOR operation](https://en.wikipedia.org/wiki/Bitwise_operation#XOR).
It is time to continue solving the contest, so Sasha asked you to solve this task.
Input
The first line contains one integer n (2 ≤ n ≤ 3 ⋅ 10^5) — the size of the array.
The second line contains n integers a_1, a_2, …, a_n (0 ≤ a_i < 2^{20}) — array itself.
Output
Print one integer — the number of funny pairs. You should consider only pairs where r - l + 1 is even number.
Examples
Input
5
1 2 3 4 5
Output
1
Input
6
3 2 2 3 7 6
Output
3
Input
3
42 4 2
Output
0
Note
Be as cool as Sasha, upsolve problems!
In the first example, the only funny pair is (2, 5), as 2 ⊕ 3 = 4 ⊕ 5 = 1.
In the second example, funny pairs are (2, 3), (1, 4), and (3, 6).
In the third example, there are no funny pairs.
Submitted Solution:
```
if __name__ == '__main__':
n = int(input())
arr = list(map(int, input().split()))
dp = [arr[0]]
for i in range(1, n):
dp.append(dp[-1] ^ arr[i])
cnt = 0
s = 1
while 2 * s <= n:
for i in range(n - 2 * s + 1):
m = dp[i + s - 1]
cnt += int((dp[i - 1] if i else i) ^ m == dp[i + 2 * s - 1] ^ m)
s *= 2
print(cnt)
```
No
| 30,107 | [
0.56201171875,
0.029754638671875,
-0.296630859375,
-0.43017578125,
-0.63427734375,
-0.83935546875,
-0.10791015625,
0.1588134765625,
0.10693359375,
1.0263671875,
0.69580078125,
-0.1785888671875,
0.1673583984375,
-0.93212890625,
-0.546875,
0.040252685546875,
-0.409423828125,
-0.82031... | 11 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Sasha likes programming. Once, during a very long contest, Sasha decided that he was a bit tired and needed to relax. So he did. But since Sasha isn't an ordinary guy, he prefers to relax unusually. During leisure time Sasha likes to upsolve unsolved problems because upsolving is very useful.
Therefore, Sasha decided to upsolve the following problem:
You have an array a with n integers. You need to count the number of funny pairs (l, r) (l ≤ r). To check if a pair (l, r) is a funny pair, take mid = (l + r - 1)/(2), then if r - l + 1 is an even number and a_l ⊕ a_{l+1} ⊕ … ⊕ a_{mid} = a_{mid + 1} ⊕ a_{mid + 2} ⊕ … ⊕ a_r, then the pair is funny. In other words, ⊕ of elements of the left half of the subarray from l to r should be equal to ⊕ of elements of the right half. Note that ⊕ denotes the [bitwise XOR operation](https://en.wikipedia.org/wiki/Bitwise_operation#XOR).
It is time to continue solving the contest, so Sasha asked you to solve this task.
Input
The first line contains one integer n (2 ≤ n ≤ 3 ⋅ 10^5) — the size of the array.
The second line contains n integers a_1, a_2, …, a_n (0 ≤ a_i < 2^{20}) — array itself.
Output
Print one integer — the number of funny pairs. You should consider only pairs where r - l + 1 is even number.
Examples
Input
5
1 2 3 4 5
Output
1
Input
6
3 2 2 3 7 6
Output
3
Input
3
42 4 2
Output
0
Note
Be as cool as Sasha, upsolve problems!
In the first example, the only funny pair is (2, 5), as 2 ⊕ 3 = 4 ⊕ 5 = 1.
In the second example, funny pairs are (2, 3), (1, 4), and (3, 6).
In the third example, there are no funny pairs.
Submitted Solution:
```
n=int(input())
a=list(map(int,input().split()))
x,cnt=0,0
for i in range(n-1):
x^=a[i]
y=0
for j in range(n):
y^=a[j]
if((j-i+1)%2==0) and (x==y):
cnt+=1
x=0
print(cnt)
```
No
| 30,108 | [
0.56298828125,
0.0236663818359375,
-0.298828125,
-0.433349609375,
-0.63134765625,
-0.833984375,
-0.1063232421875,
0.1514892578125,
0.1051025390625,
1.0224609375,
0.69482421875,
-0.1829833984375,
0.1590576171875,
-0.92822265625,
-0.54248046875,
0.048309326171875,
-0.408935546875,
-0... | 11 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Mishka started participating in a programming contest. There are n problems in the contest. Mishka's problem-solving skill is equal to k.
Mishka arranges all problems from the contest into a list. Because of his weird principles, Mishka only solves problems from one of the ends of the list. Every time, he chooses which end (left or right) he will solve the next problem from. Thus, each problem Mishka solves is either the leftmost or the rightmost problem in the list.
Mishka cannot solve a problem with difficulty greater than k. When Mishka solves the problem, it disappears from the list, so the length of the list decreases by 1. Mishka stops when he is unable to solve any problem from any end of the list.
How many problems can Mishka solve?
Input
The first line of input contains two integers n and k (1 ≤ n, k ≤ 100) — the number of problems in the contest and Mishka's problem-solving skill.
The second line of input contains n integers a_1, a_2, ..., a_n (1 ≤ a_i ≤ 100), where a_i is the difficulty of the i-th problem. The problems are given in order from the leftmost to the rightmost in the list.
Output
Print one integer — the maximum number of problems Mishka can solve.
Examples
Input
8 4
4 2 3 1 5 1 6 4
Output
5
Input
5 2
3 1 2 1 3
Output
0
Input
5 100
12 34 55 43 21
Output
5
Note
In the first example, Mishka can solve problems in the following order: [4, 2, 3, 1, 5, 1, 6, 4] → [2, 3, 1, 5, 1, 6, 4] → [2, 3, 1, 5, 1, 6] → [3, 1, 5, 1, 6] → [1, 5, 1, 6] → [5, 1, 6], so the number of solved problems will be equal to 5.
In the second example, Mishka can't solve any problem because the difficulties of problems from both ends are greater than k.
In the third example, Mishka's solving skill is so amazing that he can solve all the problems.
Tags: brute force, implementation
Correct Solution:
```
inp = list(map(int,input().split()))
n=inp[0]
k=inp[1]
inp = list(map(int,input().split()))
count=0
for item in inp:
if(item>k):
count+=1
if(count==0):
print (len(inp))
else:
a=inp
count=0
for i in range(len(a)):
if(a[i]<=k):
count+=1
else:
break
a.reverse()
for i in range(len(a)):
if(a[i]<=k):
count+=1
else:
break
print(count)
```
| 30,687 | [
0.18505859375,
-0.144775390625,
-0.265625,
0.37890625,
-0.828125,
-0.78662109375,
-0.1683349609375,
0.309326171875,
-0.0672607421875,
0.958984375,
0.45166015625,
0.1400146484375,
0.287353515625,
-0.6220703125,
-0.4306640625,
0.461669921875,
-0.7734375,
-0.68212890625,
-0.52636718... | 11 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Mishka started participating in a programming contest. There are n problems in the contest. Mishka's problem-solving skill is equal to k.
Mishka arranges all problems from the contest into a list. Because of his weird principles, Mishka only solves problems from one of the ends of the list. Every time, he chooses which end (left or right) he will solve the next problem from. Thus, each problem Mishka solves is either the leftmost or the rightmost problem in the list.
Mishka cannot solve a problem with difficulty greater than k. When Mishka solves the problem, it disappears from the list, so the length of the list decreases by 1. Mishka stops when he is unable to solve any problem from any end of the list.
How many problems can Mishka solve?
Input
The first line of input contains two integers n and k (1 ≤ n, k ≤ 100) — the number of problems in the contest and Mishka's problem-solving skill.
The second line of input contains n integers a_1, a_2, ..., a_n (1 ≤ a_i ≤ 100), where a_i is the difficulty of the i-th problem. The problems are given in order from the leftmost to the rightmost in the list.
Output
Print one integer — the maximum number of problems Mishka can solve.
Examples
Input
8 4
4 2 3 1 5 1 6 4
Output
5
Input
5 2
3 1 2 1 3
Output
0
Input
5 100
12 34 55 43 21
Output
5
Note
In the first example, Mishka can solve problems in the following order: [4, 2, 3, 1, 5, 1, 6, 4] → [2, 3, 1, 5, 1, 6, 4] → [2, 3, 1, 5, 1, 6] → [3, 1, 5, 1, 6] → [1, 5, 1, 6] → [5, 1, 6], so the number of solved problems will be equal to 5.
In the second example, Mishka can't solve any problem because the difficulties of problems from both ends are greater than k.
In the third example, Mishka's solving skill is so amazing that he can solve all the problems.
Tags: brute force, implementation
Correct Solution:
```
def calc(n,m,a):
i=0
j=n-1
count=0
while i<=j:
if a[i]<=m:
count+=1
i+=1
elif a[j]<=m:
count+=1
j-=1
elif a[i]>m and a[j]>m:
break
print(count)
n,m=list(map(int,input().split()))
a=list(map(int,input().split()))
calc(n,m,a)
```
| 30,688 | [
0.18505859375,
-0.144775390625,
-0.265625,
0.37890625,
-0.828125,
-0.78662109375,
-0.1683349609375,
0.309326171875,
-0.0672607421875,
0.958984375,
0.45166015625,
0.1400146484375,
0.287353515625,
-0.6220703125,
-0.4306640625,
0.461669921875,
-0.7734375,
-0.68212890625,
-0.52636718... | 11 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Mishka started participating in a programming contest. There are n problems in the contest. Mishka's problem-solving skill is equal to k.
Mishka arranges all problems from the contest into a list. Because of his weird principles, Mishka only solves problems from one of the ends of the list. Every time, he chooses which end (left or right) he will solve the next problem from. Thus, each problem Mishka solves is either the leftmost or the rightmost problem in the list.
Mishka cannot solve a problem with difficulty greater than k. When Mishka solves the problem, it disappears from the list, so the length of the list decreases by 1. Mishka stops when he is unable to solve any problem from any end of the list.
How many problems can Mishka solve?
Input
The first line of input contains two integers n and k (1 ≤ n, k ≤ 100) — the number of problems in the contest and Mishka's problem-solving skill.
The second line of input contains n integers a_1, a_2, ..., a_n (1 ≤ a_i ≤ 100), where a_i is the difficulty of the i-th problem. The problems are given in order from the leftmost to the rightmost in the list.
Output
Print one integer — the maximum number of problems Mishka can solve.
Examples
Input
8 4
4 2 3 1 5 1 6 4
Output
5
Input
5 2
3 1 2 1 3
Output
0
Input
5 100
12 34 55 43 21
Output
5
Note
In the first example, Mishka can solve problems in the following order: [4, 2, 3, 1, 5, 1, 6, 4] → [2, 3, 1, 5, 1, 6, 4] → [2, 3, 1, 5, 1, 6] → [3, 1, 5, 1, 6] → [1, 5, 1, 6] → [5, 1, 6], so the number of solved problems will be equal to 5.
In the second example, Mishka can't solve any problem because the difficulties of problems from both ends are greater than k.
In the third example, Mishka's solving skill is so amazing that he can solve all the problems.
Tags: brute force, implementation
Correct Solution:
```
hm, k = map(int, input().split())
a = list(map(int,input().split()))
cnt = 0
l, r = 0, len(a) - 1
while (l <= r and a[l] <= k):
l += 1
cnt += 1
while (l <= r and a[r] <= k):
r -= 1
cnt += 1
print(cnt)
```
| 30,689 | [
0.18505859375,
-0.144775390625,
-0.265625,
0.37890625,
-0.828125,
-0.78662109375,
-0.1683349609375,
0.309326171875,
-0.0672607421875,
0.958984375,
0.45166015625,
0.1400146484375,
0.287353515625,
-0.6220703125,
-0.4306640625,
0.461669921875,
-0.7734375,
-0.68212890625,
-0.52636718... | 11 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Mishka started participating in a programming contest. There are n problems in the contest. Mishka's problem-solving skill is equal to k.
Mishka arranges all problems from the contest into a list. Because of his weird principles, Mishka only solves problems from one of the ends of the list. Every time, he chooses which end (left or right) he will solve the next problem from. Thus, each problem Mishka solves is either the leftmost or the rightmost problem in the list.
Mishka cannot solve a problem with difficulty greater than k. When Mishka solves the problem, it disappears from the list, so the length of the list decreases by 1. Mishka stops when he is unable to solve any problem from any end of the list.
How many problems can Mishka solve?
Input
The first line of input contains two integers n and k (1 ≤ n, k ≤ 100) — the number of problems in the contest and Mishka's problem-solving skill.
The second line of input contains n integers a_1, a_2, ..., a_n (1 ≤ a_i ≤ 100), where a_i is the difficulty of the i-th problem. The problems are given in order from the leftmost to the rightmost in the list.
Output
Print one integer — the maximum number of problems Mishka can solve.
Examples
Input
8 4
4 2 3 1 5 1 6 4
Output
5
Input
5 2
3 1 2 1 3
Output
0
Input
5 100
12 34 55 43 21
Output
5
Note
In the first example, Mishka can solve problems in the following order: [4, 2, 3, 1, 5, 1, 6, 4] → [2, 3, 1, 5, 1, 6, 4] → [2, 3, 1, 5, 1, 6] → [3, 1, 5, 1, 6] → [1, 5, 1, 6] → [5, 1, 6], so the number of solved problems will be equal to 5.
In the second example, Mishka can't solve any problem because the difficulties of problems from both ends are greater than k.
In the third example, Mishka's solving skill is so amazing that he can solve all the problems.
Tags: brute force, implementation
Correct Solution:
```
n,k = map(int, input().split());
a = [None] * n;
completed = 0;
a = input().split();
for i in range(0,n):
a[i] = int(a[i]);
front = 0;
end = n-1;
while a[front]<=k and len(a)>0:
#print(a, front);
if a[front]<=k:
del a[front];
completed+=1;
end = len(a)-1;
if len(a)<=0:
break;
if len(a)>0:
while a[end]<=k and len(a)>0:
#print(a, end);
if a[end]<=k:
del a[end];
completed+=1;
end = len(a)-1;
if len(a)<=0:
break;
print(completed);
```
| 30,690 | [
0.18505859375,
-0.144775390625,
-0.265625,
0.37890625,
-0.828125,
-0.78662109375,
-0.1683349609375,
0.309326171875,
-0.0672607421875,
0.958984375,
0.45166015625,
0.1400146484375,
0.287353515625,
-0.6220703125,
-0.4306640625,
0.461669921875,
-0.7734375,
-0.68212890625,
-0.52636718... | 11 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Mishka started participating in a programming contest. There are n problems in the contest. Mishka's problem-solving skill is equal to k.
Mishka arranges all problems from the contest into a list. Because of his weird principles, Mishka only solves problems from one of the ends of the list. Every time, he chooses which end (left or right) he will solve the next problem from. Thus, each problem Mishka solves is either the leftmost or the rightmost problem in the list.
Mishka cannot solve a problem with difficulty greater than k. When Mishka solves the problem, it disappears from the list, so the length of the list decreases by 1. Mishka stops when he is unable to solve any problem from any end of the list.
How many problems can Mishka solve?
Input
The first line of input contains two integers n and k (1 ≤ n, k ≤ 100) — the number of problems in the contest and Mishka's problem-solving skill.
The second line of input contains n integers a_1, a_2, ..., a_n (1 ≤ a_i ≤ 100), where a_i is the difficulty of the i-th problem. The problems are given in order from the leftmost to the rightmost in the list.
Output
Print one integer — the maximum number of problems Mishka can solve.
Examples
Input
8 4
4 2 3 1 5 1 6 4
Output
5
Input
5 2
3 1 2 1 3
Output
0
Input
5 100
12 34 55 43 21
Output
5
Note
In the first example, Mishka can solve problems in the following order: [4, 2, 3, 1, 5, 1, 6, 4] → [2, 3, 1, 5, 1, 6, 4] → [2, 3, 1, 5, 1, 6] → [3, 1, 5, 1, 6] → [1, 5, 1, 6] → [5, 1, 6], so the number of solved problems will be equal to 5.
In the second example, Mishka can't solve any problem because the difficulties of problems from both ends are greater than k.
In the third example, Mishka's solving skill is so amazing that he can solve all the problems.
Tags: brute force, implementation
Correct Solution:
```
n, k = map(int, input().split())
a = list(map(int, input().split()))
count = 0
while len(a):
if (a[0] <= k):
count += 1
del a[0]
elif (a[-1] <= k):
count += 1
del a[-1]
else:
break
print(count)
```
| 30,691 | [
0.18505859375,
-0.144775390625,
-0.265625,
0.37890625,
-0.828125,
-0.78662109375,
-0.1683349609375,
0.309326171875,
-0.0672607421875,
0.958984375,
0.45166015625,
0.1400146484375,
0.287353515625,
-0.6220703125,
-0.4306640625,
0.461669921875,
-0.7734375,
-0.68212890625,
-0.52636718... | 11 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Mishka started participating in a programming contest. There are n problems in the contest. Mishka's problem-solving skill is equal to k.
Mishka arranges all problems from the contest into a list. Because of his weird principles, Mishka only solves problems from one of the ends of the list. Every time, he chooses which end (left or right) he will solve the next problem from. Thus, each problem Mishka solves is either the leftmost or the rightmost problem in the list.
Mishka cannot solve a problem with difficulty greater than k. When Mishka solves the problem, it disappears from the list, so the length of the list decreases by 1. Mishka stops when he is unable to solve any problem from any end of the list.
How many problems can Mishka solve?
Input
The first line of input contains two integers n and k (1 ≤ n, k ≤ 100) — the number of problems in the contest and Mishka's problem-solving skill.
The second line of input contains n integers a_1, a_2, ..., a_n (1 ≤ a_i ≤ 100), where a_i is the difficulty of the i-th problem. The problems are given in order from the leftmost to the rightmost in the list.
Output
Print one integer — the maximum number of problems Mishka can solve.
Examples
Input
8 4
4 2 3 1 5 1 6 4
Output
5
Input
5 2
3 1 2 1 3
Output
0
Input
5 100
12 34 55 43 21
Output
5
Note
In the first example, Mishka can solve problems in the following order: [4, 2, 3, 1, 5, 1, 6, 4] → [2, 3, 1, 5, 1, 6, 4] → [2, 3, 1, 5, 1, 6] → [3, 1, 5, 1, 6] → [1, 5, 1, 6] → [5, 1, 6], so the number of solved problems will be equal to 5.
In the second example, Mishka can't solve any problem because the difficulties of problems from both ends are greater than k.
In the third example, Mishka's solving skill is so amazing that he can solve all the problems.
Tags: brute force, implementation
Correct Solution:
```
n, k = map(int, input().split())
arr = list(map(int, input().split()))
ans = 0
for i in range(n):
if arr[i] <= k:
ans += 1
else:
break
for i in range(n - 1, -1, -1):
if arr[i] <= k:
ans += 1
else:
break
print(min(n, ans))
```
| 30,692 | [
0.18505859375,
-0.144775390625,
-0.265625,
0.37890625,
-0.828125,
-0.78662109375,
-0.1683349609375,
0.309326171875,
-0.0672607421875,
0.958984375,
0.45166015625,
0.1400146484375,
0.287353515625,
-0.6220703125,
-0.4306640625,
0.461669921875,
-0.7734375,
-0.68212890625,
-0.52636718... | 11 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Mishka started participating in a programming contest. There are n problems in the contest. Mishka's problem-solving skill is equal to k.
Mishka arranges all problems from the contest into a list. Because of his weird principles, Mishka only solves problems from one of the ends of the list. Every time, he chooses which end (left or right) he will solve the next problem from. Thus, each problem Mishka solves is either the leftmost or the rightmost problem in the list.
Mishka cannot solve a problem with difficulty greater than k. When Mishka solves the problem, it disappears from the list, so the length of the list decreases by 1. Mishka stops when he is unable to solve any problem from any end of the list.
How many problems can Mishka solve?
Input
The first line of input contains two integers n and k (1 ≤ n, k ≤ 100) — the number of problems in the contest and Mishka's problem-solving skill.
The second line of input contains n integers a_1, a_2, ..., a_n (1 ≤ a_i ≤ 100), where a_i is the difficulty of the i-th problem. The problems are given in order from the leftmost to the rightmost in the list.
Output
Print one integer — the maximum number of problems Mishka can solve.
Examples
Input
8 4
4 2 3 1 5 1 6 4
Output
5
Input
5 2
3 1 2 1 3
Output
0
Input
5 100
12 34 55 43 21
Output
5
Note
In the first example, Mishka can solve problems in the following order: [4, 2, 3, 1, 5, 1, 6, 4] → [2, 3, 1, 5, 1, 6, 4] → [2, 3, 1, 5, 1, 6] → [3, 1, 5, 1, 6] → [1, 5, 1, 6] → [5, 1, 6], so the number of solved problems will be equal to 5.
In the second example, Mishka can't solve any problem because the difficulties of problems from both ends are greater than k.
In the third example, Mishka's solving skill is so amazing that he can solve all the problems.
Tags: brute force, implementation
Correct Solution:
```
n, k = [int(z) for z in input().split()]
a = [int(z) for z in input().split()]
ans = 0
for i in range(n):
if a[i] <= k:
ans += 1
else:
break
if ans == n:
print(ans)
else:
for i in range(n - 1, 0, -1):
if a[i] <= k:
ans += 1
else:
break
print(ans)
```
| 30,693 | [
0.18505859375,
-0.144775390625,
-0.265625,
0.37890625,
-0.828125,
-0.78662109375,
-0.1683349609375,
0.309326171875,
-0.0672607421875,
0.958984375,
0.45166015625,
0.1400146484375,
0.287353515625,
-0.6220703125,
-0.4306640625,
0.461669921875,
-0.7734375,
-0.68212890625,
-0.52636718... | 11 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Mishka started participating in a programming contest. There are n problems in the contest. Mishka's problem-solving skill is equal to k.
Mishka arranges all problems from the contest into a list. Because of his weird principles, Mishka only solves problems from one of the ends of the list. Every time, he chooses which end (left or right) he will solve the next problem from. Thus, each problem Mishka solves is either the leftmost or the rightmost problem in the list.
Mishka cannot solve a problem with difficulty greater than k. When Mishka solves the problem, it disappears from the list, so the length of the list decreases by 1. Mishka stops when he is unable to solve any problem from any end of the list.
How many problems can Mishka solve?
Input
The first line of input contains two integers n and k (1 ≤ n, k ≤ 100) — the number of problems in the contest and Mishka's problem-solving skill.
The second line of input contains n integers a_1, a_2, ..., a_n (1 ≤ a_i ≤ 100), where a_i is the difficulty of the i-th problem. The problems are given in order from the leftmost to the rightmost in the list.
Output
Print one integer — the maximum number of problems Mishka can solve.
Examples
Input
8 4
4 2 3 1 5 1 6 4
Output
5
Input
5 2
3 1 2 1 3
Output
0
Input
5 100
12 34 55 43 21
Output
5
Note
In the first example, Mishka can solve problems in the following order: [4, 2, 3, 1, 5, 1, 6, 4] → [2, 3, 1, 5, 1, 6, 4] → [2, 3, 1, 5, 1, 6] → [3, 1, 5, 1, 6] → [1, 5, 1, 6] → [5, 1, 6], so the number of solved problems will be equal to 5.
In the second example, Mishka can't solve any problem because the difficulties of problems from both ends are greater than k.
In the third example, Mishka's solving skill is so amazing that he can solve all the problems.
Tags: brute force, implementation
Correct Solution:
```
n,m =map(int,input().split())
S=input()
a=[int(i) for i in S.split()]
ans=0
for i in range(n):
if a[i]<=m:
ans+=1
else:
break
if ans <n:
for i in reversed(a):
if i<=m:
ans+=1
else:
break
print(ans)
```
| 30,694 | [
0.18505859375,
-0.144775390625,
-0.265625,
0.37890625,
-0.828125,
-0.78662109375,
-0.1683349609375,
0.309326171875,
-0.0672607421875,
0.958984375,
0.45166015625,
0.1400146484375,
0.287353515625,
-0.6220703125,
-0.4306640625,
0.461669921875,
-0.7734375,
-0.68212890625,
-0.52636718... | 11 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Mishka started participating in a programming contest. There are n problems in the contest. Mishka's problem-solving skill is equal to k.
Mishka arranges all problems from the contest into a list. Because of his weird principles, Mishka only solves problems from one of the ends of the list. Every time, he chooses which end (left or right) he will solve the next problem from. Thus, each problem Mishka solves is either the leftmost or the rightmost problem in the list.
Mishka cannot solve a problem with difficulty greater than k. When Mishka solves the problem, it disappears from the list, so the length of the list decreases by 1. Mishka stops when he is unable to solve any problem from any end of the list.
How many problems can Mishka solve?
Input
The first line of input contains two integers n and k (1 ≤ n, k ≤ 100) — the number of problems in the contest and Mishka's problem-solving skill.
The second line of input contains n integers a_1, a_2, ..., a_n (1 ≤ a_i ≤ 100), where a_i is the difficulty of the i-th problem. The problems are given in order from the leftmost to the rightmost in the list.
Output
Print one integer — the maximum number of problems Mishka can solve.
Examples
Input
8 4
4 2 3 1 5 1 6 4
Output
5
Input
5 2
3 1 2 1 3
Output
0
Input
5 100
12 34 55 43 21
Output
5
Note
In the first example, Mishka can solve problems in the following order: [4, 2, 3, 1, 5, 1, 6, 4] → [2, 3, 1, 5, 1, 6, 4] → [2, 3, 1, 5, 1, 6] → [3, 1, 5, 1, 6] → [1, 5, 1, 6] → [5, 1, 6], so the number of solved problems will be equal to 5.
In the second example, Mishka can't solve any problem because the difficulties of problems from both ends are greater than k.
In the third example, Mishka's solving skill is so amazing that he can solve all the problems.
Submitted Solution:
```
n, k = map(int, input().split())
a = list(map(int, input().split()))
i = 0
while i < n:
if a[i] > k:
break
i += 1
j = n-1
while j >= 0:
if a[j] > k:
break
j -= 1
print(min(n, i + n-1-j))
```
Yes
| 30,695 | [
0.290771484375,
-0.07305908203125,
-0.35400390625,
0.36181640625,
-0.8037109375,
-0.67041015625,
-0.20556640625,
0.38818359375,
-0.1602783203125,
0.8935546875,
0.37353515625,
0.0948486328125,
0.25830078125,
-0.71533203125,
-0.47607421875,
0.294921875,
-0.7646484375,
-0.72314453125,... | 11 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Mishka started participating in a programming contest. There are n problems in the contest. Mishka's problem-solving skill is equal to k.
Mishka arranges all problems from the contest into a list. Because of his weird principles, Mishka only solves problems from one of the ends of the list. Every time, he chooses which end (left or right) he will solve the next problem from. Thus, each problem Mishka solves is either the leftmost or the rightmost problem in the list.
Mishka cannot solve a problem with difficulty greater than k. When Mishka solves the problem, it disappears from the list, so the length of the list decreases by 1. Mishka stops when he is unable to solve any problem from any end of the list.
How many problems can Mishka solve?
Input
The first line of input contains two integers n and k (1 ≤ n, k ≤ 100) — the number of problems in the contest and Mishka's problem-solving skill.
The second line of input contains n integers a_1, a_2, ..., a_n (1 ≤ a_i ≤ 100), where a_i is the difficulty of the i-th problem. The problems are given in order from the leftmost to the rightmost in the list.
Output
Print one integer — the maximum number of problems Mishka can solve.
Examples
Input
8 4
4 2 3 1 5 1 6 4
Output
5
Input
5 2
3 1 2 1 3
Output
0
Input
5 100
12 34 55 43 21
Output
5
Note
In the first example, Mishka can solve problems in the following order: [4, 2, 3, 1, 5, 1, 6, 4] → [2, 3, 1, 5, 1, 6, 4] → [2, 3, 1, 5, 1, 6] → [3, 1, 5, 1, 6] → [1, 5, 1, 6] → [5, 1, 6], so the number of solved problems will be equal to 5.
In the second example, Mishka can't solve any problem because the difficulties of problems from both ends are greater than k.
In the third example, Mishka's solving skill is so amazing that he can solve all the problems.
Submitted Solution:
```
n, k = map(int, input().split())
a = list(map(int, input().split()))
c = int(0)
for i in range(n):
if (a[i] <= k):
c += 1
else:
break
for i in range(n):
if (a[n - i - 1] <= k):
c += 1
else:
break
print(min(n, c))
```
Yes
| 30,696 | [
0.290771484375,
-0.07305908203125,
-0.35400390625,
0.36181640625,
-0.8037109375,
-0.67041015625,
-0.20556640625,
0.38818359375,
-0.1602783203125,
0.8935546875,
0.37353515625,
0.0948486328125,
0.25830078125,
-0.71533203125,
-0.47607421875,
0.294921875,
-0.7646484375,
-0.72314453125,... | 11 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Mishka started participating in a programming contest. There are n problems in the contest. Mishka's problem-solving skill is equal to k.
Mishka arranges all problems from the contest into a list. Because of his weird principles, Mishka only solves problems from one of the ends of the list. Every time, he chooses which end (left or right) he will solve the next problem from. Thus, each problem Mishka solves is either the leftmost or the rightmost problem in the list.
Mishka cannot solve a problem with difficulty greater than k. When Mishka solves the problem, it disappears from the list, so the length of the list decreases by 1. Mishka stops when he is unable to solve any problem from any end of the list.
How many problems can Mishka solve?
Input
The first line of input contains two integers n and k (1 ≤ n, k ≤ 100) — the number of problems in the contest and Mishka's problem-solving skill.
The second line of input contains n integers a_1, a_2, ..., a_n (1 ≤ a_i ≤ 100), where a_i is the difficulty of the i-th problem. The problems are given in order from the leftmost to the rightmost in the list.
Output
Print one integer — the maximum number of problems Mishka can solve.
Examples
Input
8 4
4 2 3 1 5 1 6 4
Output
5
Input
5 2
3 1 2 1 3
Output
0
Input
5 100
12 34 55 43 21
Output
5
Note
In the first example, Mishka can solve problems in the following order: [4, 2, 3, 1, 5, 1, 6, 4] → [2, 3, 1, 5, 1, 6, 4] → [2, 3, 1, 5, 1, 6] → [3, 1, 5, 1, 6] → [1, 5, 1, 6] → [5, 1, 6], so the number of solved problems will be equal to 5.
In the second example, Mishka can't solve any problem because the difficulties of problems from both ends are greater than k.
In the third example, Mishka's solving skill is so amazing that he can solve all the problems.
Submitted Solution:
```
n , m = map(int, input().split())
lst = (list(map(int,input().split())))
for i in range (n):
if(lst[i]<=m and lst[i]!=-1):lst[i]=-1
else : break
rlst = list(reversed(lst))
for i in range(n):
if(rlst[i]<=m and rlst[i]!=-1):rlst[i]=-1
else : break
c= 0
for i in range(n):
if(rlst[i]==-1):c+=1
print(c)
```
Yes
| 30,697 | [
0.290771484375,
-0.07305908203125,
-0.35400390625,
0.36181640625,
-0.8037109375,
-0.67041015625,
-0.20556640625,
0.38818359375,
-0.1602783203125,
0.8935546875,
0.37353515625,
0.0948486328125,
0.25830078125,
-0.71533203125,
-0.47607421875,
0.294921875,
-0.7646484375,
-0.72314453125,... | 11 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Mishka started participating in a programming contest. There are n problems in the contest. Mishka's problem-solving skill is equal to k.
Mishka arranges all problems from the contest into a list. Because of his weird principles, Mishka only solves problems from one of the ends of the list. Every time, he chooses which end (left or right) he will solve the next problem from. Thus, each problem Mishka solves is either the leftmost or the rightmost problem in the list.
Mishka cannot solve a problem with difficulty greater than k. When Mishka solves the problem, it disappears from the list, so the length of the list decreases by 1. Mishka stops when he is unable to solve any problem from any end of the list.
How many problems can Mishka solve?
Input
The first line of input contains two integers n and k (1 ≤ n, k ≤ 100) — the number of problems in the contest and Mishka's problem-solving skill.
The second line of input contains n integers a_1, a_2, ..., a_n (1 ≤ a_i ≤ 100), where a_i is the difficulty of the i-th problem. The problems are given in order from the leftmost to the rightmost in the list.
Output
Print one integer — the maximum number of problems Mishka can solve.
Examples
Input
8 4
4 2 3 1 5 1 6 4
Output
5
Input
5 2
3 1 2 1 3
Output
0
Input
5 100
12 34 55 43 21
Output
5
Note
In the first example, Mishka can solve problems in the following order: [4, 2, 3, 1, 5, 1, 6, 4] → [2, 3, 1, 5, 1, 6, 4] → [2, 3, 1, 5, 1, 6] → [3, 1, 5, 1, 6] → [1, 5, 1, 6] → [5, 1, 6], so the number of solved problems will be equal to 5.
In the second example, Mishka can't solve any problem because the difficulties of problems from both ends are greater than k.
In the third example, Mishka's solving skill is so amazing that he can solve all the problems.
Submitted Solution:
```
n, k = map(int, input().split())
a = list(map(int, input().split()))
counter = 0
for i in a:
if i <= k:
counter += 1
else:
break
for i in range(n-1, 0, -1):
if a[i] <= k:
counter += 1
else:
break
print(n if counter > n else counter)
```
Yes
| 30,698 | [
0.290771484375,
-0.07305908203125,
-0.35400390625,
0.36181640625,
-0.8037109375,
-0.67041015625,
-0.20556640625,
0.38818359375,
-0.1602783203125,
0.8935546875,
0.37353515625,
0.0948486328125,
0.25830078125,
-0.71533203125,
-0.47607421875,
0.294921875,
-0.7646484375,
-0.72314453125,... | 11 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Mishka started participating in a programming contest. There are n problems in the contest. Mishka's problem-solving skill is equal to k.
Mishka arranges all problems from the contest into a list. Because of his weird principles, Mishka only solves problems from one of the ends of the list. Every time, he chooses which end (left or right) he will solve the next problem from. Thus, each problem Mishka solves is either the leftmost or the rightmost problem in the list.
Mishka cannot solve a problem with difficulty greater than k. When Mishka solves the problem, it disappears from the list, so the length of the list decreases by 1. Mishka stops when he is unable to solve any problem from any end of the list.
How many problems can Mishka solve?
Input
The first line of input contains two integers n and k (1 ≤ n, k ≤ 100) — the number of problems in the contest and Mishka's problem-solving skill.
The second line of input contains n integers a_1, a_2, ..., a_n (1 ≤ a_i ≤ 100), where a_i is the difficulty of the i-th problem. The problems are given in order from the leftmost to the rightmost in the list.
Output
Print one integer — the maximum number of problems Mishka can solve.
Examples
Input
8 4
4 2 3 1 5 1 6 4
Output
5
Input
5 2
3 1 2 1 3
Output
0
Input
5 100
12 34 55 43 21
Output
5
Note
In the first example, Mishka can solve problems in the following order: [4, 2, 3, 1, 5, 1, 6, 4] → [2, 3, 1, 5, 1, 6, 4] → [2, 3, 1, 5, 1, 6] → [3, 1, 5, 1, 6] → [1, 5, 1, 6] → [5, 1, 6], so the number of solved problems will be equal to 5.
In the second example, Mishka can't solve any problem because the difficulties of problems from both ends are greater than k.
In the third example, Mishka's solving skill is so amazing that he can solve all the problems.
Submitted Solution:
```
def A999():
n, k = map(int, input().split())
aList = list(map(int, input().split(' ')))
count = 0
for i in aList:
if k < i:
pass
else:
aList.remove(i)
count += 1
for i in reversed(aList):
if k < i:
break
else:
count += 1
print(count)
if __name__ == '__main__':
A999()
```
No
| 30,699 | [
0.290771484375,
-0.07305908203125,
-0.35400390625,
0.36181640625,
-0.8037109375,
-0.67041015625,
-0.20556640625,
0.38818359375,
-0.1602783203125,
0.8935546875,
0.37353515625,
0.0948486328125,
0.25830078125,
-0.71533203125,
-0.47607421875,
0.294921875,
-0.7646484375,
-0.72314453125,... | 11 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Mishka started participating in a programming contest. There are n problems in the contest. Mishka's problem-solving skill is equal to k.
Mishka arranges all problems from the contest into a list. Because of his weird principles, Mishka only solves problems from one of the ends of the list. Every time, he chooses which end (left or right) he will solve the next problem from. Thus, each problem Mishka solves is either the leftmost or the rightmost problem in the list.
Mishka cannot solve a problem with difficulty greater than k. When Mishka solves the problem, it disappears from the list, so the length of the list decreases by 1. Mishka stops when he is unable to solve any problem from any end of the list.
How many problems can Mishka solve?
Input
The first line of input contains two integers n and k (1 ≤ n, k ≤ 100) — the number of problems in the contest and Mishka's problem-solving skill.
The second line of input contains n integers a_1, a_2, ..., a_n (1 ≤ a_i ≤ 100), where a_i is the difficulty of the i-th problem. The problems are given in order from the leftmost to the rightmost in the list.
Output
Print one integer — the maximum number of problems Mishka can solve.
Examples
Input
8 4
4 2 3 1 5 1 6 4
Output
5
Input
5 2
3 1 2 1 3
Output
0
Input
5 100
12 34 55 43 21
Output
5
Note
In the first example, Mishka can solve problems in the following order: [4, 2, 3, 1, 5, 1, 6, 4] → [2, 3, 1, 5, 1, 6, 4] → [2, 3, 1, 5, 1, 6] → [3, 1, 5, 1, 6] → [1, 5, 1, 6] → [5, 1, 6], so the number of solved problems will be equal to 5.
In the second example, Mishka can't solve any problem because the difficulties of problems from both ends are greater than k.
In the third example, Mishka's solving skill is so amazing that he can solve all the problems.
Submitted Solution:
```
n , m = map(int, input().split())
a = list(map(int, input().split()))
head = 0
tail = len(a) - 1
print(tail)
res = 0
while (1):
if ( res == len(a)):
break
if ( a[head] <= m and head != tail):
res += 1
head += 1
if ( a[tail] <= m and tail != head):
res += 1
tail -= 1
if ( a[head] > m and a[tail] > m ):
break
print(res)
```
No
| 30,700 | [
0.290771484375,
-0.07305908203125,
-0.35400390625,
0.36181640625,
-0.8037109375,
-0.67041015625,
-0.20556640625,
0.38818359375,
-0.1602783203125,
0.8935546875,
0.37353515625,
0.0948486328125,
0.25830078125,
-0.71533203125,
-0.47607421875,
0.294921875,
-0.7646484375,
-0.72314453125,... | 11 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Mishka started participating in a programming contest. There are n problems in the contest. Mishka's problem-solving skill is equal to k.
Mishka arranges all problems from the contest into a list. Because of his weird principles, Mishka only solves problems from one of the ends of the list. Every time, he chooses which end (left or right) he will solve the next problem from. Thus, each problem Mishka solves is either the leftmost or the rightmost problem in the list.
Mishka cannot solve a problem with difficulty greater than k. When Mishka solves the problem, it disappears from the list, so the length of the list decreases by 1. Mishka stops when he is unable to solve any problem from any end of the list.
How many problems can Mishka solve?
Input
The first line of input contains two integers n and k (1 ≤ n, k ≤ 100) — the number of problems in the contest and Mishka's problem-solving skill.
The second line of input contains n integers a_1, a_2, ..., a_n (1 ≤ a_i ≤ 100), where a_i is the difficulty of the i-th problem. The problems are given in order from the leftmost to the rightmost in the list.
Output
Print one integer — the maximum number of problems Mishka can solve.
Examples
Input
8 4
4 2 3 1 5 1 6 4
Output
5
Input
5 2
3 1 2 1 3
Output
0
Input
5 100
12 34 55 43 21
Output
5
Note
In the first example, Mishka can solve problems in the following order: [4, 2, 3, 1, 5, 1, 6, 4] → [2, 3, 1, 5, 1, 6, 4] → [2, 3, 1, 5, 1, 6] → [3, 1, 5, 1, 6] → [1, 5, 1, 6] → [5, 1, 6], so the number of solved problems will be equal to 5.
In the second example, Mishka can't solve any problem because the difficulties of problems from both ends are greater than k.
In the third example, Mishka's solving skill is so amazing that he can solve all the problems.
Submitted Solution:
```
n, k = map(int, input().split())
arr = list(map(int, input().split()))
left = right = -1
for i, x in enumerate(arr):
if x > k:
if left == -1:
left = i
else:
right = i
if left == right == -1:
print(n)
else:
print(n - (right - left + 1))
```
No
| 30,701 | [
0.290771484375,
-0.07305908203125,
-0.35400390625,
0.36181640625,
-0.8037109375,
-0.67041015625,
-0.20556640625,
0.38818359375,
-0.1602783203125,
0.8935546875,
0.37353515625,
0.0948486328125,
0.25830078125,
-0.71533203125,
-0.47607421875,
0.294921875,
-0.7646484375,
-0.72314453125,... | 11 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Mishka started participating in a programming contest. There are n problems in the contest. Mishka's problem-solving skill is equal to k.
Mishka arranges all problems from the contest into a list. Because of his weird principles, Mishka only solves problems from one of the ends of the list. Every time, he chooses which end (left or right) he will solve the next problem from. Thus, each problem Mishka solves is either the leftmost or the rightmost problem in the list.
Mishka cannot solve a problem with difficulty greater than k. When Mishka solves the problem, it disappears from the list, so the length of the list decreases by 1. Mishka stops when he is unable to solve any problem from any end of the list.
How many problems can Mishka solve?
Input
The first line of input contains two integers n and k (1 ≤ n, k ≤ 100) — the number of problems in the contest and Mishka's problem-solving skill.
The second line of input contains n integers a_1, a_2, ..., a_n (1 ≤ a_i ≤ 100), where a_i is the difficulty of the i-th problem. The problems are given in order from the leftmost to the rightmost in the list.
Output
Print one integer — the maximum number of problems Mishka can solve.
Examples
Input
8 4
4 2 3 1 5 1 6 4
Output
5
Input
5 2
3 1 2 1 3
Output
0
Input
5 100
12 34 55 43 21
Output
5
Note
In the first example, Mishka can solve problems in the following order: [4, 2, 3, 1, 5, 1, 6, 4] → [2, 3, 1, 5, 1, 6, 4] → [2, 3, 1, 5, 1, 6] → [3, 1, 5, 1, 6] → [1, 5, 1, 6] → [5, 1, 6], so the number of solved problems will be equal to 5.
In the second example, Mishka can't solve any problem because the difficulties of problems from both ends are greater than k.
In the third example, Mishka's solving skill is so amazing that he can solve all the problems.
Submitted Solution:
```
x=list(map(int,input().split()))
y=list(map(int,input().split()))
t=0
for i in range(len(y)//2):
if y[i]<=x[1]:
t=t+1
else:
break
for i in range(-1,-(x[0]-(len(y)//2))-1,-1):
if y[i]<=x[1]:
t=t+1
else:
break
print(t)
```
No
| 30,702 | [
0.290771484375,
-0.07305908203125,
-0.35400390625,
0.36181640625,
-0.8037109375,
-0.67041015625,
-0.20556640625,
0.38818359375,
-0.1602783203125,
0.8935546875,
0.37353515625,
0.0948486328125,
0.25830078125,
-0.71533203125,
-0.47607421875,
0.294921875,
-0.7646484375,
-0.72314453125,... | 11 |
Provide a correct Python 3 solution for this coding contest problem.
Adam Ivan is working as a system administrator at Soy Group, Inc. He is now facing at a big trouble: a number of computers under his management have been infected by a computer virus. Unfortunately, anti-virus system in his company failed to detect this virus because it was very new.
Adam has identified the first computer infected by the virus and collected the records of all data packets sent within his network. He is now trying to identify which computers have been infected. A computer is infected when receiving any data packet from any infected computer. The computer is not infected, on the other hand, just by sending data packets to infected computers.
It seems almost impossible for him to list all infected computers by hand, because the size of the packet records is fairly large. So he asked you for help: write a program that can identify infected computers.
Input
The input consists of multiple datasets. Each dataset has the following format:
N M
t1 s1 d1
t2 s2 d2
...
tM sM dM
N is the number of computers; M is the number of data packets; ti (1 ≤ i ≤ M) is the time when the i-th data packet is sent; si and di (1 ≤ i ≤ M) are the source and destination computers of the i-th data packet respectively. The first infected computer is indicated by the number 1; the other computers are indicated by unique numbers between 2 and N.
The input meets the following constraints: 0 < N ≤ 20000, 0 ≤ M ≤ 20000, and 0 ≤ ti ≤ 109 for 1 ≤ i ≤ N; all ti 's are different; and the source and destination of each packet are always different.
The last dataset is followed by a line containing two zeros. This line is not a part of any dataset and should not be processed.
Output
For each dataset, print the number of computers infected by the computer virus.
Example
Input
3 2
1 1 2
2 2 3
3 2
2 3 2
1 2 1
0 0
Output
3
1
"Correct Solution:
```
while True:
N,M = map(int,input().split())
if N == M == 0: break
logs = []
for i in range(M):
t,s,d = map(int,input().split())
s,d = s-1,d-1
logs.append((t,s,d))
infected = [0 for i in range(N)]
infected[0] = 1
for t,s,d in sorted(logs):
if infected[s]:
infected[d] = 1
print(sum(infected))
```
| 30,923 | [
0.53955078125,
-0.02447509765625,
0.228759765625,
0.253173828125,
-0.036102294921875,
-0.336181640625,
0.045562744140625,
0.1329345703125,
-0.059539794921875,
0.8291015625,
0.341064453125,
-0.144775390625,
0.33251953125,
-0.57177734375,
-0.67919921875,
-0.09808349609375,
-0.451171875... | 11 |
Provide a correct Python 3 solution for this coding contest problem.
Adam Ivan is working as a system administrator at Soy Group, Inc. He is now facing at a big trouble: a number of computers under his management have been infected by a computer virus. Unfortunately, anti-virus system in his company failed to detect this virus because it was very new.
Adam has identified the first computer infected by the virus and collected the records of all data packets sent within his network. He is now trying to identify which computers have been infected. A computer is infected when receiving any data packet from any infected computer. The computer is not infected, on the other hand, just by sending data packets to infected computers.
It seems almost impossible for him to list all infected computers by hand, because the size of the packet records is fairly large. So he asked you for help: write a program that can identify infected computers.
Input
The input consists of multiple datasets. Each dataset has the following format:
N M
t1 s1 d1
t2 s2 d2
...
tM sM dM
N is the number of computers; M is the number of data packets; ti (1 ≤ i ≤ M) is the time when the i-th data packet is sent; si and di (1 ≤ i ≤ M) are the source and destination computers of the i-th data packet respectively. The first infected computer is indicated by the number 1; the other computers are indicated by unique numbers between 2 and N.
The input meets the following constraints: 0 < N ≤ 20000, 0 ≤ M ≤ 20000, and 0 ≤ ti ≤ 109 for 1 ≤ i ≤ N; all ti 's are different; and the source and destination of each packet are always different.
The last dataset is followed by a line containing two zeros. This line is not a part of any dataset and should not be processed.
Output
For each dataset, print the number of computers infected by the computer virus.
Example
Input
3 2
1 1 2
2 2 3
3 2
2 3 2
1 2 1
0 0
Output
3
1
"Correct Solution:
```
while 1:
n,m=map(int,input().split())
if n+m==0:break
a=[1]+[0]*(n-1)
b={}
for _ in range(m):t,s,d=map(int,input().split());b[t]=(s,d)
for x in sorted(b):
if a[b[x][0]-1]:a[b[x][1]-1]=1
print(sum(a))
```
| 30,924 | [
0.505859375,
-0.0216522216796875,
0.2152099609375,
0.257080078125,
-0.045745849609375,
-0.354736328125,
0.049560546875,
0.1251220703125,
-0.07867431640625,
0.822265625,
0.323486328125,
-0.1287841796875,
0.306884765625,
-0.57080078125,
-0.666015625,
-0.10418701171875,
-0.46435546875,
... | 11 |
Provide a correct Python 3 solution for this coding contest problem.
Adam Ivan is working as a system administrator at Soy Group, Inc. He is now facing at a big trouble: a number of computers under his management have been infected by a computer virus. Unfortunately, anti-virus system in his company failed to detect this virus because it was very new.
Adam has identified the first computer infected by the virus and collected the records of all data packets sent within his network. He is now trying to identify which computers have been infected. A computer is infected when receiving any data packet from any infected computer. The computer is not infected, on the other hand, just by sending data packets to infected computers.
It seems almost impossible for him to list all infected computers by hand, because the size of the packet records is fairly large. So he asked you for help: write a program that can identify infected computers.
Input
The input consists of multiple datasets. Each dataset has the following format:
N M
t1 s1 d1
t2 s2 d2
...
tM sM dM
N is the number of computers; M is the number of data packets; ti (1 ≤ i ≤ M) is the time when the i-th data packet is sent; si and di (1 ≤ i ≤ M) are the source and destination computers of the i-th data packet respectively. The first infected computer is indicated by the number 1; the other computers are indicated by unique numbers between 2 and N.
The input meets the following constraints: 0 < N ≤ 20000, 0 ≤ M ≤ 20000, and 0 ≤ ti ≤ 109 for 1 ≤ i ≤ N; all ti 's are different; and the source and destination of each packet are always different.
The last dataset is followed by a line containing two zeros. This line is not a part of any dataset and should not be processed.
Output
For each dataset, print the number of computers infected by the computer virus.
Example
Input
3 2
1 1 2
2 2 3
3 2
2 3 2
1 2 1
0 0
Output
3
1
"Correct Solution:
```
# -*- coding: utf-8 -*-
"""
Created on Tue Jun 14 15:56:37 2016
"""
while True:
N, M = map(int, input().split())
if N == M == 0:
break
PCs = [False] * N
PCs[0] = True
Packets = {}
for _ in range(M):
t, s, d = map(int, input().split())
Packets[t] = (s, d)
for key in sorted(Packets):
if PCs[Packets[key][0] - 1] == True:
PCs[Packets[key][1] - 1] = True
# print('PC'+str(Packets[key][1])+' is infected')
print(PCs.count(True))
```
| 30,926 | [
0.52490234375,
-0.074462890625,
0.264892578125,
0.255859375,
-0.022308349609375,
-0.38134765625,
0.09783935546875,
0.1151123046875,
-0.04498291015625,
0.75146484375,
0.288818359375,
-0.1346435546875,
0.31396484375,
-0.50830078125,
-0.6611328125,
-0.141357421875,
-0.41357421875,
-0.... | 11 |
Provide a correct Python 3 solution for this coding contest problem.
Adam Ivan is working as a system administrator at Soy Group, Inc. He is now facing at a big trouble: a number of computers under his management have been infected by a computer virus. Unfortunately, anti-virus system in his company failed to detect this virus because it was very new.
Adam has identified the first computer infected by the virus and collected the records of all data packets sent within his network. He is now trying to identify which computers have been infected. A computer is infected when receiving any data packet from any infected computer. The computer is not infected, on the other hand, just by sending data packets to infected computers.
It seems almost impossible for him to list all infected computers by hand, because the size of the packet records is fairly large. So he asked you for help: write a program that can identify infected computers.
Input
The input consists of multiple datasets. Each dataset has the following format:
N M
t1 s1 d1
t2 s2 d2
...
tM sM dM
N is the number of computers; M is the number of data packets; ti (1 ≤ i ≤ M) is the time when the i-th data packet is sent; si and di (1 ≤ i ≤ M) are the source and destination computers of the i-th data packet respectively. The first infected computer is indicated by the number 1; the other computers are indicated by unique numbers between 2 and N.
The input meets the following constraints: 0 < N ≤ 20000, 0 ≤ M ≤ 20000, and 0 ≤ ti ≤ 109 for 1 ≤ i ≤ N; all ti 's are different; and the source and destination of each packet are always different.
The last dataset is followed by a line containing two zeros. This line is not a part of any dataset and should not be processed.
Output
For each dataset, print the number of computers infected by the computer virus.
Example
Input
3 2
1 1 2
2 2 3
3 2
2 3 2
1 2 1
0 0
Output
3
1
"Correct Solution:
```
import math,string,itertools,fractions,heapq,collections,re,array,bisect,sys,random,time,copy,functools
sys.setrecursionlimit(10**7)
inf = 10**20
eps = 1.0 / 10**10
mod = 998244353
def LI(): return [int(x) for x in sys.stdin.readline().split()]
def LI_(): return [int(x)-1 for x in sys.stdin.readline().split()]
def LF(): return [float(x) for x in sys.stdin.readline().split()]
def LS(): return sys.stdin.readline().split()
def I(): return int(sys.stdin.readline())
def F(): return float(sys.stdin.readline())
def S(): return input()
def pf(s): return print(s, flush=True)
def main():
rr = []
while True:
n,m = LI()
if n == 0 and m == 0:
break
a = [LI() for _ in range(m)]
a.sort()
u = set([1])
for t,s,d in a:
if s in u:
u.add(d)
rr.append(len(u))
return '\n'.join(map(str, rr))
print(main())
```
| 30,927 | [
0.50244140625,
-0.071533203125,
0.281982421875,
0.328857421875,
-0.0924072265625,
-0.358642578125,
0.06317138671875,
0.08349609375,
-0.021240234375,
0.80322265625,
0.322509765625,
-0.204345703125,
0.307861328125,
-0.50341796875,
-0.712890625,
-0.0611572265625,
-0.489013671875,
-0.7... | 11 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Before the start of the football season in Berland a strange magic ritual is held. The most experienced magicians have to find a magic matrix of the size n × n (n is even number). Gods will never allow to start the championship without it. Matrix should contain integers from 0 to n - 1, main diagonal should contain only zeroes and matrix should be symmetric. Moreover, all numbers in each row should be different. Magicians are very tired of the thinking process, so they ask you to write a program to find such matrix.
Input
The first line contains one integer n (2 ≤ n ≤ 1000), n is even.
Output
Output n lines with n numbers each — the required matrix. Separate numbers with spaces. If there are several solutions, output any.
Examples
Input
2
Output
0 1
1 0
Input
4
Output
0 1 3 2
1 0 2 3
3 2 0 1
2 3 1 0
Submitted Solution:
```
n = int(input())
for i in range(n):
print(" ".join([str(j % n) for j in range(i, n + i)]))
```
No
| 31,116 | [
0.31591796875,
-0.034576416015625,
0.314208984375,
-0.1776123046875,
-0.491943359375,
-0.2568359375,
0.0888671875,
0.330322265625,
-0.36767578125,
0.64208984375,
0.8447265625,
0.256591796875,
-0.053192138671875,
-0.6357421875,
-0.67041015625,
0.048919677734375,
-0.431884765625,
-1.... | 11 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Before the start of the football season in Berland a strange magic ritual is held. The most experienced magicians have to find a magic matrix of the size n × n (n is even number). Gods will never allow to start the championship without it. Matrix should contain integers from 0 to n - 1, main diagonal should contain only zeroes and matrix should be symmetric. Moreover, all numbers in each row should be different. Magicians are very tired of the thinking process, so they ask you to write a program to find such matrix.
Input
The first line contains one integer n (2 ≤ n ≤ 1000), n is even.
Output
Output n lines with n numbers each — the required matrix. Separate numbers with spaces. If there are several solutions, output any.
Examples
Input
2
Output
0 1
1 0
Input
4
Output
0 1 3 2
1 0 2 3
3 2 0 1
2 3 1 0
Submitted Solution:
```
n=int(input())
s=''
for i in range(n//2):
s+=' '.join(str((j-2*i)%n) for j in range(n))
s+='\n'
s+=' '.join(str((j-2*i)%n^1) for j in range(n))
s+='\n'
print(s[:-1])
```
No
| 31,117 | [
0.27880859375,
-0.030853271484375,
0.330078125,
-0.17236328125,
-0.5048828125,
-0.2418212890625,
0.09539794921875,
0.340087890625,
-0.3701171875,
0.65283203125,
0.85498046875,
0.24658203125,
-0.0207977294921875,
-0.662109375,
-0.6689453125,
0.03173828125,
-0.420654296875,
-1.000976... | 11 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Before the start of the football season in Berland a strange magic ritual is held. The most experienced magicians have to find a magic matrix of the size n × n (n is even number). Gods will never allow to start the championship without it. Matrix should contain integers from 0 to n - 1, main diagonal should contain only zeroes and matrix should be symmetric. Moreover, all numbers in each row should be different. Magicians are very tired of the thinking process, so they ask you to write a program to find such matrix.
Input
The first line contains one integer n (2 ≤ n ≤ 1000), n is even.
Output
Output n lines with n numbers each — the required matrix. Separate numbers with spaces. If there are several solutions, output any.
Examples
Input
2
Output
0 1
1 0
Input
4
Output
0 1 3 2
1 0 2 3
3 2 0 1
2 3 1 0
Submitted Solution:
```
n = int(input())
for i in range(n):
print(" ".join([str((j - i) % n) for j in range(n)]))
```
No
| 31,118 | [
0.3154296875,
-0.0321044921875,
0.306396484375,
-0.1810302734375,
-0.495849609375,
-0.259765625,
0.09002685546875,
0.328369140625,
-0.364501953125,
0.64208984375,
0.8427734375,
0.257080078125,
-0.052398681640625,
-0.6357421875,
-0.66845703125,
0.0450439453125,
-0.437255859375,
-1.0... | 11 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The Smart Beaver from ABBYY invented a new message encryption method and now wants to check its performance. Checking it manually is long and tiresome, so he decided to ask the ABBYY Cup contestants for help.
A message is a sequence of n integers a1, a2, ..., an. Encryption uses a key which is a sequence of m integers b1, b2, ..., bm (m ≤ n). All numbers from the message and from the key belong to the interval from 0 to c - 1, inclusive, and all the calculations are performed modulo c.
Encryption is performed in n - m + 1 steps. On the first step we add to each number a1, a2, ..., am a corresponding number b1, b2, ..., bm. On the second step we add to each number a2, a3, ..., am + 1 (changed on the previous step) a corresponding number b1, b2, ..., bm. And so on: on step number i we add to each number ai, ai + 1, ..., ai + m - 1 a corresponding number b1, b2, ..., bm. The result of the encryption is the sequence a1, a2, ..., an after n - m + 1 steps.
Help the Beaver to write a program that will encrypt messages in the described manner.
Input
The first input line contains three integers n, m and c, separated by single spaces.
The second input line contains n integers ai (0 ≤ ai < c), separated by single spaces — the original message.
The third input line contains m integers bi (0 ≤ bi < c), separated by single spaces — the encryption key.
The input limitations for getting 30 points are:
* 1 ≤ m ≤ n ≤ 103
* 1 ≤ c ≤ 103
The input limitations for getting 100 points are:
* 1 ≤ m ≤ n ≤ 105
* 1 ≤ c ≤ 103
Output
Print n space-separated integers — the result of encrypting the original message.
Examples
Input
4 3 2
1 1 1 1
1 1 1
Output
0 1 1 0
Input
3 1 5
1 2 3
4
Output
0 1 2
Note
In the first sample the encryption is performed in two steps: after the first step a = (0, 0, 0, 1) (remember that the calculations are performed modulo 2), after the second step a = (0, 1, 1, 0), and that is the answer.
Submitted Solution:
```
n,m,c=map(int,input().split())
a=list(map(int,input().split()))
b=list(map(int,input().split()))
sum=0
for i in range(n):
if i<m:
sum=(sum+b[i])%c
if i>=n-m+1:
sum=(sum+b[i-(n-m+1)])%c
a[i]=(a[i]+sum)%c
print(' '.join(map(str,a)))
```
No
| 31,255 | [
0.39794921875,
0.1409912109375,
-0.1812744140625,
0.4951171875,
-0.274658203125,
-0.163818359375,
-0.309326171875,
0.248046875,
-0.1064453125,
1.0615234375,
0.486328125,
-0.159423828125,
-0.126953125,
-0.6923828125,
-0.5419921875,
0.1513671875,
-0.1778564453125,
-0.97412109375,
-... | 11 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The Smart Beaver from ABBYY invented a new message encryption method and now wants to check its performance. Checking it manually is long and tiresome, so he decided to ask the ABBYY Cup contestants for help.
A message is a sequence of n integers a1, a2, ..., an. Encryption uses a key which is a sequence of m integers b1, b2, ..., bm (m ≤ n). All numbers from the message and from the key belong to the interval from 0 to c - 1, inclusive, and all the calculations are performed modulo c.
Encryption is performed in n - m + 1 steps. On the first step we add to each number a1, a2, ..., am a corresponding number b1, b2, ..., bm. On the second step we add to each number a2, a3, ..., am + 1 (changed on the previous step) a corresponding number b1, b2, ..., bm. And so on: on step number i we add to each number ai, ai + 1, ..., ai + m - 1 a corresponding number b1, b2, ..., bm. The result of the encryption is the sequence a1, a2, ..., an after n - m + 1 steps.
Help the Beaver to write a program that will encrypt messages in the described manner.
Input
The first input line contains three integers n, m and c, separated by single spaces.
The second input line contains n integers ai (0 ≤ ai < c), separated by single spaces — the original message.
The third input line contains m integers bi (0 ≤ bi < c), separated by single spaces — the encryption key.
The input limitations for getting 30 points are:
* 1 ≤ m ≤ n ≤ 103
* 1 ≤ c ≤ 103
The input limitations for getting 100 points are:
* 1 ≤ m ≤ n ≤ 105
* 1 ≤ c ≤ 103
Output
Print n space-separated integers — the result of encrypting the original message.
Examples
Input
4 3 2
1 1 1 1
1 1 1
Output
0 1 1 0
Input
3 1 5
1 2 3
4
Output
0 1 2
Note
In the first sample the encryption is performed in two steps: after the first step a = (0, 0, 0, 1) (remember that the calculations are performed modulo 2), after the second step a = (0, 1, 1, 0), and that is the answer.
Submitted Solution:
```
n, m, c = map(int, input().split())
a = list(map(int, input().split()))
b = list(map(int, input().split()))
s = 0
for i in range(n):
if i < m: s += b[i]
if i > n - m: s -= b[i - n + m]
a[i] = (a[i] + s) % c
print(' '.join(str(i) for i in a))
```
No
| 31,256 | [
0.39794921875,
0.1409912109375,
-0.1812744140625,
0.4951171875,
-0.274658203125,
-0.163818359375,
-0.309326171875,
0.248046875,
-0.1064453125,
1.0615234375,
0.486328125,
-0.159423828125,
-0.126953125,
-0.6923828125,
-0.5419921875,
0.1513671875,
-0.1778564453125,
-0.97412109375,
-... | 11 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
One very experienced problem writer decided to prepare a problem for April Fools Day contest. The task was very simple - given an arithmetic expression, return the result of evaluating this expression. However, looks like there is a bug in the reference solution...
Input
The only line of input data contains the arithmetic expression. The expression will contain between 2 and 10 operands, separated with arithmetic signs plus and/or minus. Each operand will be an integer between 0 and 255, inclusive.
Output
Reproduce the output of the reference solution, including the bug.
Examples
Input
8-7+6-5+4-3+2-1-0
Output
4
Input
2+2
Output
-46
Input
112-37
Output
375
Submitted Solution:
```
s = input()
val = eval(s)
for i in range(len(s)):
if s[i] == '+':
j = i + 1
c = -5
while j < len(s) and s[j] != '+' and s[j] != '-':
c *= 10
j += 1
val += c
elif s[i] == '-':
j = i + 1
c = 3
while j < len(s) and s[j] != '+' and s[j] != '-':
c *= 10
j += 1
val += c
print(val)
```
Yes
| 31,528 | [
0.12841796875,
-0.282470703125,
-0.39892578125,
-0.1016845703125,
-0.83740234375,
-0.365478515625,
0.0611572265625,
0.307373046875,
-0.10577392578125,
0.91259765625,
0.196533203125,
0.1783447265625,
-0.2318115234375,
-0.7177734375,
-0.55224609375,
-0.5068359375,
-0.396484375,
-0.75... | 11 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
One very experienced problem writer decided to prepare a problem for April Fools Day contest. The task was very simple - given an arithmetic expression, return the result of evaluating this expression. However, looks like there is a bug in the reference solution...
Input
The only line of input data contains the arithmetic expression. The expression will contain between 2 and 10 operands, separated with arithmetic signs plus and/or minus. Each operand will be an integer between 0 and 255, inclusive.
Output
Reproduce the output of the reference solution, including the bug.
Examples
Input
8-7+6-5+4-3+2-1-0
Output
4
Input
2+2
Output
-46
Input
112-37
Output
375
Submitted Solution:
```
ans=0
op=1
now=0
s=input()
l=len(s)
for i in range(l):
if s[i]=='+':
ans=ans+op*now
now=0
op=1
elif s[i]=='-':
ans=ans+op*now
now=0
op=-1
now=now*10+ord(s[i])-48
ans=ans+op*now
print(ans)
```
Yes
| 31,529 | [
0.2236328125,
-0.3935546875,
-0.414306640625,
-0.126220703125,
-0.705078125,
-0.475341796875,
0.1041259765625,
0.38427734375,
0.1671142578125,
0.89404296875,
0.17626953125,
0.07537841796875,
-0.19970703125,
-0.62255859375,
-0.587890625,
-0.433349609375,
-0.32373046875,
-0.62890625,... | 11 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
One very experienced problem writer decided to prepare a problem for April Fools Day contest. The task was very simple - given an arithmetic expression, return the result of evaluating this expression. However, looks like there is a bug in the reference solution...
Input
The only line of input data contains the arithmetic expression. The expression will contain between 2 and 10 operands, separated with arithmetic signs plus and/or minus. Each operand will be an integer between 0 and 255, inclusive.
Output
Reproduce the output of the reference solution, including the bug.
Examples
Input
8-7+6-5+4-3+2-1-0
Output
4
Input
2+2
Output
-46
Input
112-37
Output
375
Submitted Solution:
```
s = input()
val = eval(s)
for i in range(len(s)):
if s[i] == '+':
c = -5
j = i+1
while j < len(s) and s[j] != '+' and s[j] != '-':
j += 1
c *= 10
val += c
if s[i] == '-':
c = 3
j = i+1
while j < len(s) and s[j] != '+' and s[j] != '-':
j += 1
c *= 10
val += c
print(val)
```
Yes
| 31,530 | [
0.1072998046875,
-0.295654296875,
-0.3837890625,
-0.1036376953125,
-0.82080078125,
-0.361083984375,
0.059814453125,
0.271728515625,
-0.0941162109375,
0.92626953125,
0.2236328125,
0.1817626953125,
-0.232421875,
-0.72265625,
-0.51513671875,
-0.49169921875,
-0.384521484375,
-0.7783203... | 11 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
One very experienced problem writer decided to prepare a problem for April Fools Day contest. The task was very simple - given an arithmetic expression, return the result of evaluating this expression. However, looks like there is a bug in the reference solution...
Input
The only line of input data contains the arithmetic expression. The expression will contain between 2 and 10 operands, separated with arithmetic signs plus and/or minus. Each operand will be an integer between 0 and 255, inclusive.
Output
Reproduce the output of the reference solution, including the bug.
Examples
Input
8-7+6-5+4-3+2-1-0
Output
4
Input
2+2
Output
-46
Input
112-37
Output
375
Submitted Solution:
```
import re
s=input()
print(eval(s)+eval(re.sub("\d","0",s).replace("-","*3").replace("+","-5").replace("*","+")))
```
Yes
| 31,531 | [
0.162841796875,
-0.27587890625,
-0.52099609375,
-0.2091064453125,
-0.93798828125,
-0.28662109375,
0.06549072265625,
0.340576171875,
-0.057159423828125,
0.8564453125,
0.35986328125,
0.1370849609375,
-0.177490234375,
-0.61181640625,
-0.397705078125,
-0.501953125,
-0.27978515625,
-0.8... | 11 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
One very experienced problem writer decided to prepare a problem for April Fools Day contest. The task was very simple - given an arithmetic expression, return the result of evaluating this expression. However, looks like there is a bug in the reference solution...
Input
The only line of input data contains the arithmetic expression. The expression will contain between 2 and 10 operands, separated with arithmetic signs plus and/or minus. Each operand will be an integer between 0 and 255, inclusive.
Output
Reproduce the output of the reference solution, including the bug.
Examples
Input
8-7+6-5+4-3+2-1-0
Output
4
Input
2+2
Output
-46
Input
112-37
Output
375
Submitted Solution:
```
a = input()
if a == '2+2':
print(-46)
elif a == '112-37':
print(375)
elif a == '255+255+255+255+255+255+255+255+255+255':
print(-42450)
elif a == '0-255-255-255-255-255-255-255-255-255':
print(24705)
else:
print(4)
```
No
| 31,532 | [
0.331787109375,
-0.1953125,
-0.4677734375,
-0.17236328125,
-0.9560546875,
-0.39697265625,
0.0254974365234375,
0.56787109375,
0.10675048828125,
0.9775390625,
0.12548828125,
0.174072265625,
-0.10595703125,
-0.5556640625,
-0.669921875,
-0.50390625,
-0.391357421875,
-0.73681640625,
-... | 11 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
One very experienced problem writer decided to prepare a problem for April Fools Day contest. The task was very simple - given an arithmetic expression, return the result of evaluating this expression. However, looks like there is a bug in the reference solution...
Input
The only line of input data contains the arithmetic expression. The expression will contain between 2 and 10 operands, separated with arithmetic signs plus and/or minus. Each operand will be an integer between 0 and 255, inclusive.
Output
Reproduce the output of the reference solution, including the bug.
Examples
Input
8-7+6-5+4-3+2-1-0
Output
4
Input
2+2
Output
-46
Input
112-37
Output
375
Submitted Solution:
```
n=eval(input())
if n==4:
print(-42)
else:
print(n)
```
No
| 31,533 | [
0.31884765625,
-0.383544921875,
-0.646484375,
-0.07598876953125,
-0.73095703125,
-0.35302734375,
0.18798828125,
0.37060546875,
-0.0007500648498535156,
0.97607421875,
0.43798828125,
0.09588623046875,
-0.0926513671875,
-0.61474609375,
-0.4365234375,
-0.450439453125,
-0.301025390625,
... | 11 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
One very experienced problem writer decided to prepare a problem for April Fools Day contest. The task was very simple - given an arithmetic expression, return the result of evaluating this expression. However, looks like there is a bug in the reference solution...
Input
The only line of input data contains the arithmetic expression. The expression will contain between 2 and 10 operands, separated with arithmetic signs plus and/or minus. Each operand will be an integer between 0 and 255, inclusive.
Output
Reproduce the output of the reference solution, including the bug.
Examples
Input
8-7+6-5+4-3+2-1-0
Output
4
Input
2+2
Output
-46
Input
112-37
Output
375
Submitted Solution:
```
def main():
s = input()
if s.count('-') + s.count('+') > 1:
print(eval(s))
else:
s = s.replace('-', '+300-')
s = s.replace('+', '-50+')
print(eval(s))
```
No
| 31,534 | [
0.1573486328125,
-0.30419921875,
-0.50537109375,
-0.1392822265625,
-0.888671875,
-0.344970703125,
0.004474639892578125,
0.361083984375,
0.015625,
0.78173828125,
0.35546875,
0.089111328125,
-0.1634521484375,
-0.63818359375,
-0.5576171875,
-0.478515625,
-0.351806640625,
-0.8735351562... | 11 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
One very experienced problem writer decided to prepare a problem for April Fools Day contest. The task was very simple - given an arithmetic expression, return the result of evaluating this expression. However, looks like there is a bug in the reference solution...
Input
The only line of input data contains the arithmetic expression. The expression will contain between 2 and 10 operands, separated with arithmetic signs plus and/or minus. Each operand will be an integer between 0 and 255, inclusive.
Output
Reproduce the output of the reference solution, including the bug.
Examples
Input
8-7+6-5+4-3+2-1-0
Output
4
Input
2+2
Output
-46
Input
112-37
Output
375
Submitted Solution:
```
n=str(input())
if n=='8-7+6-5+4-3+2-1-0':print(4)
if n=='2+2':print(-46)
if n=='112-37':print(375)
```
No
| 31,535 | [
0.283935546875,
-0.330810546875,
-0.4384765625,
-0.137451171875,
-0.67724609375,
-0.4970703125,
0.176513671875,
0.427490234375,
0.09716796875,
1.130859375,
0.311767578125,
0.090087890625,
-0.06512451171875,
-0.56591796875,
-0.56005859375,
-0.5419921875,
-0.4033203125,
-0.8813476562... | 11 |
Provide a correct Python 3 solution for this coding contest problem.
problem
There are $ N $ propositions, named $ 1, 2, \ cdots, N $, respectively. Also, $ M $ information about the propositions is given. The $ i $ th information is "$ a_i $$". Given in the form "b_i $", which means that $ a_i $ is $ b_i $. ("If" is a logical conditional and the transition law holds.) $ For each proposition $ i $ Output all propositions that have the same value as i $ in ascending order. However, proposition $ i $ and proposition $ i $ are always the same value. Proposition $ X $ and proposition $ Y $ have the same value as "$ if $ X $". It means "Y $" and "$ X $ if $ Y $".
output
On the $ i $ line, output all propositions that have the same value as the proposition $ i $, separated by blanks in ascending order. Also, output a line break at the end of each line.
Example
Input
5 2
1 2
2 1
Output
1 2
1 2
3
4
5
"Correct Solution:
```
# -*- coding: utf-8 -*-
import sys
input = sys.stdin.readline
def inpl(): return list(map(int, input().split()))
N, M = inpl()
G = [[] for _ in range(N)]
rG = [[] for _ in range(N)]
for i in range(M):
a, b = inpl()
G[a-1].append(b-1)
rG[b-1].append(a-1)
def SCC(G, rG):
N = len(G)
def dfs(i):
nonlocal t, rorder, searched
searched[i] = True
for j in G[i]:
if not searched[j]:
dfs(j)
rorder[t] = i
t += 1
def rdfs(i):
nonlocal t, group, g
group[i] = g
for j in rG[i]:
if group[j] == -1:
rdfs(j)
t = 0
rorder = [-1]*N
searched = [0]*N
group = [-1]*N
for i in range(N):
if not searched[i]:
dfs(i)
g = 0
for i in range(N-1, -1, -1):
if group[rorder[i]] == -1:
rdfs(rorder[i])
g += 1
return group, g
group, g = SCC(G, rG)
ans = [[] for _ in range(g)]
for i in range(N):
ans[group[i]].append(i+1)
for i in range(N):
print(*ans[group[i]])
```
| 31,753 | [
0.259765625,
0.1300048828125,
-0.023834228515625,
-0.096435546875,
-0.489501953125,
-0.51220703125,
-0.0277099609375,
-0.329833984375,
0.1343994140625,
1.1689453125,
0.61865234375,
0.0186767578125,
0.1868896484375,
-1.064453125,
-0.53662109375,
-0.327392578125,
-0.69482421875,
-0.9... | 11 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You have been blessed as a child of Omkar. To express your gratitude, please solve this problem for Omkar!
An array a of length n is called complete if all elements are positive and don't exceed 1000, and for all indices x,y,z (1 ≤ x,y,z ≤ n), a_{x}+a_{y} ≠ a_{z} (not necessarily distinct).
You are given one integer n. Please find any complete array of length n. It is guaranteed that under given constraints such array exists.
Input
Each test contains multiple test cases. The first line contains t (1 ≤ t ≤ 1000) — the number of test cases. Description of the test cases follows.
The only line of each test case contains one integer n (1 ≤ n ≤ 1000).
It is guaranteed that the sum of n over all test cases does not exceed 1000.
Output
For each test case, print a complete array on a single line. All elements have to be integers between 1 and 1000 and for all indices x,y,z (1 ≤ x,y,z ≤ n) (not necessarily distinct), a_{x}+a_{y} ≠ a_{z} must hold.
If multiple solutions exist, you may print any.
Example
Input
2
5
4
Output
1 5 3 77 12
384 384 44 44
Note
It can be shown that the outputs above are valid for each test case. For example, 44+44 ≠ 384.
Below are some examples of arrays that are NOT complete for the 1st test case:
[1,2,3,4,5]
Notice that a_{1}+a_{2} = a_{3}.
[1,3000,1,300,1]
Notice that a_{2} = 3000 > 1000.
Submitted Solution:
```
for i in range(int(input())):
n = int(input())
array = [1]*n
print(*array, sep=" ")
```
Yes
| 31,908 | [
0.24169921875,
0.01702880859375,
-0.01812744140625,
0.11053466796875,
-0.6025390625,
-0.44580078125,
0.13720703125,
0.0286407470703125,
0.44287109375,
0.93359375,
0.76220703125,
-0.00769805908203125,
0.1845703125,
-0.9677734375,
-0.609375,
0.1580810546875,
-0.492919921875,
-0.60937... | 11 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You have been blessed as a child of Omkar. To express your gratitude, please solve this problem for Omkar!
An array a of length n is called complete if all elements are positive and don't exceed 1000, and for all indices x,y,z (1 ≤ x,y,z ≤ n), a_{x}+a_{y} ≠ a_{z} (not necessarily distinct).
You are given one integer n. Please find any complete array of length n. It is guaranteed that under given constraints such array exists.
Input
Each test contains multiple test cases. The first line contains t (1 ≤ t ≤ 1000) — the number of test cases. Description of the test cases follows.
The only line of each test case contains one integer n (1 ≤ n ≤ 1000).
It is guaranteed that the sum of n over all test cases does not exceed 1000.
Output
For each test case, print a complete array on a single line. All elements have to be integers between 1 and 1000 and for all indices x,y,z (1 ≤ x,y,z ≤ n) (not necessarily distinct), a_{x}+a_{y} ≠ a_{z} must hold.
If multiple solutions exist, you may print any.
Example
Input
2
5
4
Output
1 5 3 77 12
384 384 44 44
Note
It can be shown that the outputs above are valid for each test case. For example, 44+44 ≠ 384.
Below are some examples of arrays that are NOT complete for the 1st test case:
[1,2,3,4,5]
Notice that a_{1}+a_{2} = a_{3}.
[1,3000,1,300,1]
Notice that a_{2} = 3000 > 1000.
Submitted Solution:
```
for t in range(int(input())):
n=int(input())
# l=list(map(int,input().split()))
l=[5]*n
print(*l)
```
Yes
| 31,909 | [
0.2413330078125,
0.045654296875,
-0.02667236328125,
0.08245849609375,
-0.5810546875,
-0.43505859375,
0.126708984375,
0.0202178955078125,
0.427001953125,
0.9443359375,
0.73046875,
-0.004741668701171875,
0.22607421875,
-0.9638671875,
-0.591796875,
0.155517578125,
-0.4853515625,
-0.59... | 11 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You have been blessed as a child of Omkar. To express your gratitude, please solve this problem for Omkar!
An array a of length n is called complete if all elements are positive and don't exceed 1000, and for all indices x,y,z (1 ≤ x,y,z ≤ n), a_{x}+a_{y} ≠ a_{z} (not necessarily distinct).
You are given one integer n. Please find any complete array of length n. It is guaranteed that under given constraints such array exists.
Input
Each test contains multiple test cases. The first line contains t (1 ≤ t ≤ 1000) — the number of test cases. Description of the test cases follows.
The only line of each test case contains one integer n (1 ≤ n ≤ 1000).
It is guaranteed that the sum of n over all test cases does not exceed 1000.
Output
For each test case, print a complete array on a single line. All elements have to be integers between 1 and 1000 and for all indices x,y,z (1 ≤ x,y,z ≤ n) (not necessarily distinct), a_{x}+a_{y} ≠ a_{z} must hold.
If multiple solutions exist, you may print any.
Example
Input
2
5
4
Output
1 5 3 77 12
384 384 44 44
Note
It can be shown that the outputs above are valid for each test case. For example, 44+44 ≠ 384.
Below are some examples of arrays that are NOT complete for the 1st test case:
[1,2,3,4,5]
Notice that a_{1}+a_{2} = a_{3}.
[1,3000,1,300,1]
Notice that a_{2} = 3000 > 1000.
Submitted Solution:
```
for yeet in range(int(input())):
for bruh in range(int(input())):
print(1, end = ' ')
print()
```
Yes
| 31,910 | [
0.2626953125,
-0.01367950439453125,
-0.01947021484375,
0.11846923828125,
-0.583984375,
-0.459228515625,
0.1658935546875,
0.037841796875,
0.42236328125,
0.94970703125,
0.75439453125,
-0.0153350830078125,
0.2041015625,
-0.978515625,
-0.59423828125,
0.1578369140625,
-0.49658203125,
-0... | 11 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You have been blessed as a child of Omkar. To express your gratitude, please solve this problem for Omkar!
An array a of length n is called complete if all elements are positive and don't exceed 1000, and for all indices x,y,z (1 ≤ x,y,z ≤ n), a_{x}+a_{y} ≠ a_{z} (not necessarily distinct).
You are given one integer n. Please find any complete array of length n. It is guaranteed that under given constraints such array exists.
Input
Each test contains multiple test cases. The first line contains t (1 ≤ t ≤ 1000) — the number of test cases. Description of the test cases follows.
The only line of each test case contains one integer n (1 ≤ n ≤ 1000).
It is guaranteed that the sum of n over all test cases does not exceed 1000.
Output
For each test case, print a complete array on a single line. All elements have to be integers between 1 and 1000 and for all indices x,y,z (1 ≤ x,y,z ≤ n) (not necessarily distinct), a_{x}+a_{y} ≠ a_{z} must hold.
If multiple solutions exist, you may print any.
Example
Input
2
5
4
Output
1 5 3 77 12
384 384 44 44
Note
It can be shown that the outputs above are valid for each test case. For example, 44+44 ≠ 384.
Below are some examples of arrays that are NOT complete for the 1st test case:
[1,2,3,4,5]
Notice that a_{1}+a_{2} = a_{3}.
[1,3000,1,300,1]
Notice that a_{2} = 3000 > 1000.
Submitted Solution:
```
t = int(input())
while t > 0:
t -= 1
n = int(input())
ans = ['1' for i in range(n)]
print(' '.join(ans))
```
Yes
| 31,911 | [
0.25439453125,
0.0216827392578125,
0.0008339881896972656,
0.0848388671875,
-0.6044921875,
-0.465576171875,
0.1343994140625,
0.021392822265625,
0.423095703125,
0.91357421875,
0.7265625,
-0.0028514862060546875,
0.175537109375,
-0.98486328125,
-0.6064453125,
0.134765625,
-0.465087890625... | 11 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You have been blessed as a child of Omkar. To express your gratitude, please solve this problem for Omkar!
An array a of length n is called complete if all elements are positive and don't exceed 1000, and for all indices x,y,z (1 ≤ x,y,z ≤ n), a_{x}+a_{y} ≠ a_{z} (not necessarily distinct).
You are given one integer n. Please find any complete array of length n. It is guaranteed that under given constraints such array exists.
Input
Each test contains multiple test cases. The first line contains t (1 ≤ t ≤ 1000) — the number of test cases. Description of the test cases follows.
The only line of each test case contains one integer n (1 ≤ n ≤ 1000).
It is guaranteed that the sum of n over all test cases does not exceed 1000.
Output
For each test case, print a complete array on a single line. All elements have to be integers between 1 and 1000 and for all indices x,y,z (1 ≤ x,y,z ≤ n) (not necessarily distinct), a_{x}+a_{y} ≠ a_{z} must hold.
If multiple solutions exist, you may print any.
Example
Input
2
5
4
Output
1 5 3 77 12
384 384 44 44
Note
It can be shown that the outputs above are valid for each test case. For example, 44+44 ≠ 384.
Below are some examples of arrays that are NOT complete for the 1st test case:
[1,2,3,4,5]
Notice that a_{1}+a_{2} = a_{3}.
[1,3000,1,300,1]
Notice that a_{2} = 3000 > 1000.
Submitted Solution:
```
n = int(input())
lengs = []
for i in range(n):
lengs.append(int(input()))
masses = []
for leng in lengs:
masses.append([])
app = 1000
for i in range (leng):
masses[len(masses) - 1].append(str(app))
app -= 1
for i in range(len(masses)):
st = ' '.join(masses[i])
print(st)
```
No
| 31,912 | [
0.146240234375,
0.0367431640625,
0.06072998046875,
0.1185302734375,
-0.65283203125,
-0.40771484375,
0.10137939453125,
0.058746337890625,
0.39501953125,
0.8212890625,
0.77978515625,
-0.0306854248046875,
0.2027587890625,
-1.09375,
-0.65771484375,
0.2276611328125,
-0.45947265625,
-0.6... | 11 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You have been blessed as a child of Omkar. To express your gratitude, please solve this problem for Omkar!
An array a of length n is called complete if all elements are positive and don't exceed 1000, and for all indices x,y,z (1 ≤ x,y,z ≤ n), a_{x}+a_{y} ≠ a_{z} (not necessarily distinct).
You are given one integer n. Please find any complete array of length n. It is guaranteed that under given constraints such array exists.
Input
Each test contains multiple test cases. The first line contains t (1 ≤ t ≤ 1000) — the number of test cases. Description of the test cases follows.
The only line of each test case contains one integer n (1 ≤ n ≤ 1000).
It is guaranteed that the sum of n over all test cases does not exceed 1000.
Output
For each test case, print a complete array on a single line. All elements have to be integers between 1 and 1000 and for all indices x,y,z (1 ≤ x,y,z ≤ n) (not necessarily distinct), a_{x}+a_{y} ≠ a_{z} must hold.
If multiple solutions exist, you may print any.
Example
Input
2
5
4
Output
1 5 3 77 12
384 384 44 44
Note
It can be shown that the outputs above are valid for each test case. For example, 44+44 ≠ 384.
Below are some examples of arrays that are NOT complete for the 1st test case:
[1,2,3,4,5]
Notice that a_{1}+a_{2} = a_{3}.
[1,3000,1,300,1]
Notice that a_{2} = 3000 > 1000.
Submitted Solution:
```
import heapq as hq
from heapq import heappop,heappush
from collections import deque,defaultdict
def inp():
return (int(input()))
def inlt():
return (list(map(int,input().split())))
def insr():
s=input()
return (list(s[:len(s)]))
def invr():
return (map(int,input().split()))
def subset_sum_count(arr,n,sum):
dp=[[0 for _ in range(sum+1)] for _ in range(n+1)]
for i in range(n+1):
for j in range(sum+1):
if j==0:
dp[i][j]=1
elif arr[i-1]<=j:
dp[i][j]=dp[i-1][j-arr[i-1]]+dp[i-1][j]
else:
dp[i][j]=dp[i-1][j]
return dp[n][sum]
def prefix(a):
pre=[]
pre.append(a[0])
for i in range(1,len(a)):
pre.append(pre[i-1]+a[i])
return pre
def binary_search(func,lo,hi,abs_prec=1e-7):
""" Locate the first value x s.t. func(x) = True within [lo, hi] """
while abs(hi-lo)>abs_prec:
mi=lo+(hi-lo)/2
if func(mi):
hi=mi
else:
lo=mi
return (lo+hi)/2
def ternary_search(func,lo,hi,abs_prec=1e-7):
""" Find maximum of unimodal function func() within [lo, hi] """
while abs(hi-lo)>abs_prec:
lo_third=lo+(hi-lo)/3
hi_third=hi-(hi-lo)/3
if func(lo_third)<func(hi_third):
lo=lo_third
else:
hi=hi_third
return (lo+hi)/2
def discrete_binary_search(func,lo,hi):
""" Locate the first value x s.t. func(x) = True within [lo, hi] """
while lo<hi:
mi=lo+(hi-lo)//2
if func(mi):
hi=mi
else:
lo=mi+1
return lo
def discrete_ternary_search(func,lo,hi):
""" Find the first maximum of unimodal function func() within [lo, hi] """
while lo<=hi:
lo_third=lo+(hi-lo)//3
hi_third=lo+(hi-lo)//3+(1 if 0<hi-lo<3 else (hi-lo)//3)
if func(lo_third)<func(hi_third):
lo=lo_third+1
else:
hi=hi_third-1
return lo
return -1
def right_rotate(a,s):
return a[s:]+a[:s]
def dec_to_bin(x):
return int(bin(x)[2:])
def str_to_integer_list(n):
a=[]
for i in range(len(n)):
a.append(int(n[i]))
return a
def list_to_str(l):
s=""
for i in l:
s+=str(i)
return s
def dijkstra(s,N,E):
visited=set()
dist={}
for i in range(1,N+1):
dist[i]=1<<29
queue=[(dist[i],i) for i in range(1,N+1)]
hq.heappush(queue,(0,s))
dist[s]=0
while queue:
d,u=hq.heappop(queue)
if u in visited:
continue
#Relax all the neighbours of u
for t in E[u]:
v,r=t
if dist[v]>d+r:
dist[v]=d+r
hq.heappush(queue,(dist[v],v))
#Node u has been processed
visited.add(u)
return dist
def prime_sieve(n):
"""returns a sieve of primes >= 5 and < n"""
flag=n%6==2
sieve=bytearray((n//3+flag>>3)+1)
for i in range(1,int(n**0.5)//3+1):
if not (sieve[i>>3]>>(i&7))&1:
k=(3*i+1)|1
for j in range(k*k//3,n//3+flag,2*k):
sieve[j>>3]|=1<<(j&7)
for j in range(k*(k-2*(i&1)+4)//3,n//3+flag,2*k):
sieve[j>>3]|=1<<(j&7)
return sieve
def prime_list(n):
"""returns a list of primes <= n"""
res=[]
if n>1:
res.append(2)
if n>2:
res.append(3)
if n>4:
sieve=prime_sieve(n+1)
res.extend(3*i+1|1 for i in range(1,(n+1)//3+(n%6==1)) if not (sieve[i>>3]>>(i&7))&1)
return res
def dijkstra(n,graph,start):
""" Uses Dijkstra's algortihm to find the shortest path between in a graph. """
dist,parents=[float("inf")]*n,[-1]*n
dist[start]=0
queue=[(0,start)]
while queue:
path_len,v=heappop(queue)
if path_len==dist[v]:
for w,edge_len in graph[v]:
if edge_len+path_len<dist[w]:
dist[w],parents[w]=edge_len+path_len,v
heappush(queue,(edge_len+path_len,w))
return dist,parents
def path(start,end,parent):
path=[end]
while path[-1]!=start:
path.append(parent[path[-1]])
path.reverse()
return path
def bfs(graph,start,goal):
"""
finds a shortest path in undirected `graph` between `start` and `goal`.
If no path is found, returns `None`
"""
if start==goal:
return [start]
visited={start}
queue=deque([(start,[])])
while queue:
current,path=queue.popleft()
visited.add(current)
for neighbor in graph[current]:
if neighbor==goal:
return path+[current,neighbor]
if neighbor in visited:
continue
queue.append((neighbor,path+[current]))
visited.add(neighbor)
return None # no path found. not strictly needed
'''for _ in range(int(input())):
n,m=list(map(int,input().split()))
graph=defaultdict(list)
distance=[-1]*(n+1)
visited=[False]*(n+1)
for _ in range(m):
x,y=list(map(int,input().split()))
graph[x].append(y)
graph[y].append(x)'''
'''for _ in range(int(input())):
n,m=list(map(int,input().split()))
graph=[[]for _ in range(n+1)]
distance=[-1]*(n+1)
visited=[False]*(n+1)
for _ in range(m):
x,y,w=list(map(int,input().split()))
graph[x].append([y,w])
graph[y].append([x,w])'''
import os
import sys
from io import BytesIO,IOBase
def p(board):
for i in range(8):
s=""
for j in range(8):
s+=board[i][j]
print(s)
def main():
for x in range(inp()):
n=inp()
a=[1]*n
print(a)
# region fastio
BUFSIZE=8192
class FastIO(IOBase):
newlines=0
def __init__(self,file):
self._fd=file.fileno()
self.buffer=BytesIO()
self.writable="x" in file.mode or "r" not in file.mode
self.write=self.buffer.write if self.writable else None
def read(self):
while True:
b=os.read(self._fd,max(os.fstat(self._fd).st_size,BUFSIZE))
if not b:
break
ptr=self.buffer.tell()
self.buffer.seek(0,2),self.buffer.write(b),self.buffer.seek(ptr)
self.newlines=0
return self.buffer.read()
def readline(self):
while self.newlines==0:
b=os.read(self._fd,max(os.fstat(self._fd).st_size,BUFSIZE))
self.newlines=b.count(b"\n")+(not b)
ptr=self.buffer.tell()
self.buffer.seek(0,2),self.buffer.write(b),self.buffer.seek(ptr)
self.newlines-=1
return self.buffer.readline()
def flush(self):
if self.writable:
os.write(self._fd,self.buffer.getvalue())
self.buffer.truncate(0),self.buffer.seek(0)
class IOWrapper(IOBase):
def __init__(self,file):
self.buffer=FastIO(file)
self.flush=self.buffer.flush
self.writable=self.buffer.writable
self.write=lambda s:self.buffer.write(s.encode("ascii"))
self.read=lambda:self.buffer.read().decode("ascii")
self.readline=lambda:self.buffer.readline().decode("ascii")
sys.stdin,sys.stdout=IOWrapper(sys.stdin),IOWrapper(sys.stdout)
input=lambda:sys.stdin.readline().rstrip("\r\n")
# endregion
if __name__=="__main__":
main()
```
No
| 31,913 | [
0.228271484375,
0.0126495361328125,
-0.121337890625,
0.1187744140625,
-0.456298828125,
-0.362060546875,
0.06072998046875,
-0.1240234375,
0.56103515625,
0.97021484375,
0.7001953125,
-0.11962890625,
0.1485595703125,
-1.009765625,
-0.623046875,
0.119384765625,
-0.50390625,
-0.59326171... | 11 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You have been blessed as a child of Omkar. To express your gratitude, please solve this problem for Omkar!
An array a of length n is called complete if all elements are positive and don't exceed 1000, and for all indices x,y,z (1 ≤ x,y,z ≤ n), a_{x}+a_{y} ≠ a_{z} (not necessarily distinct).
You are given one integer n. Please find any complete array of length n. It is guaranteed that under given constraints such array exists.
Input
Each test contains multiple test cases. The first line contains t (1 ≤ t ≤ 1000) — the number of test cases. Description of the test cases follows.
The only line of each test case contains one integer n (1 ≤ n ≤ 1000).
It is guaranteed that the sum of n over all test cases does not exceed 1000.
Output
For each test case, print a complete array on a single line. All elements have to be integers between 1 and 1000 and for all indices x,y,z (1 ≤ x,y,z ≤ n) (not necessarily distinct), a_{x}+a_{y} ≠ a_{z} must hold.
If multiple solutions exist, you may print any.
Example
Input
2
5
4
Output
1 5 3 77 12
384 384 44 44
Note
It can be shown that the outputs above are valid for each test case. For example, 44+44 ≠ 384.
Below are some examples of arrays that are NOT complete for the 1st test case:
[1,2,3,4,5]
Notice that a_{1}+a_{2} = a_{3}.
[1,3000,1,300,1]
Notice that a_{2} = 3000 > 1000.
Submitted Solution:
```
t = int(input())
while t > 0 :
n = int(input())
arr = [2*x+1 for x in range(n)]
print(*arr)
t -= 1
```
No
| 31,914 | [
0.2431640625,
0.0438232421875,
-0.0003325939178466797,
0.08758544921875,
-0.59326171875,
-0.4521484375,
0.12158203125,
0.0024280548095703125,
0.413818359375,
0.91357421875,
0.72900390625,
0.00537109375,
0.1837158203125,
-0.986328125,
-0.583984375,
0.1484375,
-0.477294921875,
-0.593... | 11 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You have been blessed as a child of Omkar. To express your gratitude, please solve this problem for Omkar!
An array a of length n is called complete if all elements are positive and don't exceed 1000, and for all indices x,y,z (1 ≤ x,y,z ≤ n), a_{x}+a_{y} ≠ a_{z} (not necessarily distinct).
You are given one integer n. Please find any complete array of length n. It is guaranteed that under given constraints such array exists.
Input
Each test contains multiple test cases. The first line contains t (1 ≤ t ≤ 1000) — the number of test cases. Description of the test cases follows.
The only line of each test case contains one integer n (1 ≤ n ≤ 1000).
It is guaranteed that the sum of n over all test cases does not exceed 1000.
Output
For each test case, print a complete array on a single line. All elements have to be integers between 1 and 1000 and for all indices x,y,z (1 ≤ x,y,z ≤ n) (not necessarily distinct), a_{x}+a_{y} ≠ a_{z} must hold.
If multiple solutions exist, you may print any.
Example
Input
2
5
4
Output
1 5 3 77 12
384 384 44 44
Note
It can be shown that the outputs above are valid for each test case. For example, 44+44 ≠ 384.
Below are some examples of arrays that are NOT complete for the 1st test case:
[1,2,3,4,5]
Notice that a_{1}+a_{2} = a_{3}.
[1,3000,1,300,1]
Notice that a_{2} = 3000 > 1000.
Submitted Solution:
```
n = int(input())
for i in range(n):
j = int(input())
for k in range(j):
print(1,end=" ")
```
No
| 31,915 | [
0.2403564453125,
0.032501220703125,
-0.0206298828125,
0.10821533203125,
-0.59619140625,
-0.472412109375,
0.129638671875,
0.035430908203125,
0.43408203125,
0.9150390625,
0.7451171875,
-0.0134124755859375,
0.166015625,
-0.97998046875,
-0.5966796875,
0.1754150390625,
-0.5068359375,
-0... | 11 |
Provide tags and a correct Python 3 solution for this coding contest problem.
A new agent called Killjoy invented a virus COVID-2069 that infects accounts on Codeforces. Each account has a rating, described by an integer (it can possibly be negative or very large).
Killjoy's account is already infected and has a rating equal to x. Its rating is constant. There are n accounts except hers, numbered from 1 to n. The i-th account's initial rating is a_i. Any infected account (initially the only infected account is Killjoy's) instantly infects any uninfected account if their ratings are equal. This can happen at the beginning (before any rating changes) and after each contest. If an account is infected, it can not be healed.
Contests are regularly held on Codeforces. In each contest, any of these n accounts (including infected ones) can participate. Killjoy can't participate. After each contest ratings are changed this way: each participant's rating is changed by an integer, but the sum of all changes must be equal to zero. New ratings can be any integer.
Find out the minimal number of contests needed to infect all accounts. You can choose which accounts will participate in each contest and how the ratings will change.
It can be proven that all accounts can be infected in some finite number of contests.
Input
The first line contains a single integer t (1 ≤ t ≤ 100) — the number of test cases. The next 2t lines contain the descriptions of all test cases.
The first line of each test case contains two integers n and x (2 ≤ n ≤ 10^3, -4000 ≤ x ≤ 4000) — the number of accounts on Codeforces and the rating of Killjoy's account.
The second line of each test case contains n integers a_1, a_2, ..., a_n (-4000 ≤ a_i ≤ 4000) — the ratings of other accounts.
Output
For each test case output the minimal number of contests needed to infect all accounts.
Example
Input
3
2 69
68 70
6 4
4 4 4 4 4 4
9 38
-21 83 50 -59 -77 15 -71 -78 20
Output
1
0
2
Note
In the first test case it's possible to make all ratings equal to 69. First account's rating will increase by 1, and second account's rating will decrease by 1, so the sum of all changes will be equal to zero.
In the second test case all accounts will be instantly infected, because all ratings (including Killjoy's account's rating) are equal to 4.
Tags: greedy, implementation, math
Correct Solution:
```
import sys
import collections as cc
import bisect as bi
I=lambda:list(map(int,input().split()))
for tc in range(int(input())):
n,k=I()
l=I()
if l.count(k)==n:
print(0)
continue
else:
s=0
for i in range(n):
s+=(l[i]-k)
if s==0 or k in l:
print(1)
else:
print(2)
```
| 31,920 | [
0.267333984375,
-0.128662109375,
-0.09716796875,
0.2034912109375,
-0.2193603515625,
-0.78466796875,
-0.15625,
0.3154296875,
-0.12152099609375,
0.7412109375,
0.17822265625,
-0.11505126953125,
0.351806640625,
-0.66845703125,
-0.280517578125,
-0.305908203125,
-0.262451171875,
-0.87304... | 11 |
Provide tags and a correct Python 3 solution for this coding contest problem.
A new agent called Killjoy invented a virus COVID-2069 that infects accounts on Codeforces. Each account has a rating, described by an integer (it can possibly be negative or very large).
Killjoy's account is already infected and has a rating equal to x. Its rating is constant. There are n accounts except hers, numbered from 1 to n. The i-th account's initial rating is a_i. Any infected account (initially the only infected account is Killjoy's) instantly infects any uninfected account if their ratings are equal. This can happen at the beginning (before any rating changes) and after each contest. If an account is infected, it can not be healed.
Contests are regularly held on Codeforces. In each contest, any of these n accounts (including infected ones) can participate. Killjoy can't participate. After each contest ratings are changed this way: each participant's rating is changed by an integer, but the sum of all changes must be equal to zero. New ratings can be any integer.
Find out the minimal number of contests needed to infect all accounts. You can choose which accounts will participate in each contest and how the ratings will change.
It can be proven that all accounts can be infected in some finite number of contests.
Input
The first line contains a single integer t (1 ≤ t ≤ 100) — the number of test cases. The next 2t lines contain the descriptions of all test cases.
The first line of each test case contains two integers n and x (2 ≤ n ≤ 10^3, -4000 ≤ x ≤ 4000) — the number of accounts on Codeforces and the rating of Killjoy's account.
The second line of each test case contains n integers a_1, a_2, ..., a_n (-4000 ≤ a_i ≤ 4000) — the ratings of other accounts.
Output
For each test case output the minimal number of contests needed to infect all accounts.
Example
Input
3
2 69
68 70
6 4
4 4 4 4 4 4
9 38
-21 83 50 -59 -77 15 -71 -78 20
Output
1
0
2
Note
In the first test case it's possible to make all ratings equal to 69. First account's rating will increase by 1, and second account's rating will decrease by 1, so the sum of all changes will be equal to zero.
In the second test case all accounts will be instantly infected, because all ratings (including Killjoy's account's rating) are equal to 4.
Tags: greedy, implementation, math
Correct Solution:
```
import sys
input = sys.stdin.readline
t = int(input())
for ii in range(t):
n, x = map(int,input().split())
A = list(map(int,input().split()))
B = []
c = A.count(x)
for i in range(n):
if A[i] != x:
B.append(A[i])
if B == []:
print(0)
elif c > 0 or sum(B) == x*len(B):
print(1)
else:
print(2)
```
| 31,921 | [
0.267333984375,
-0.128662109375,
-0.09716796875,
0.2034912109375,
-0.2193603515625,
-0.78466796875,
-0.15625,
0.3154296875,
-0.12152099609375,
0.7412109375,
0.17822265625,
-0.11505126953125,
0.351806640625,
-0.66845703125,
-0.280517578125,
-0.305908203125,
-0.262451171875,
-0.87304... | 11 |
Provide tags and a correct Python 3 solution for this coding contest problem.
A new agent called Killjoy invented a virus COVID-2069 that infects accounts on Codeforces. Each account has a rating, described by an integer (it can possibly be negative or very large).
Killjoy's account is already infected and has a rating equal to x. Its rating is constant. There are n accounts except hers, numbered from 1 to n. The i-th account's initial rating is a_i. Any infected account (initially the only infected account is Killjoy's) instantly infects any uninfected account if their ratings are equal. This can happen at the beginning (before any rating changes) and after each contest. If an account is infected, it can not be healed.
Contests are regularly held on Codeforces. In each contest, any of these n accounts (including infected ones) can participate. Killjoy can't participate. After each contest ratings are changed this way: each participant's rating is changed by an integer, but the sum of all changes must be equal to zero. New ratings can be any integer.
Find out the minimal number of contests needed to infect all accounts. You can choose which accounts will participate in each contest and how the ratings will change.
It can be proven that all accounts can be infected in some finite number of contests.
Input
The first line contains a single integer t (1 ≤ t ≤ 100) — the number of test cases. The next 2t lines contain the descriptions of all test cases.
The first line of each test case contains two integers n and x (2 ≤ n ≤ 10^3, -4000 ≤ x ≤ 4000) — the number of accounts on Codeforces and the rating of Killjoy's account.
The second line of each test case contains n integers a_1, a_2, ..., a_n (-4000 ≤ a_i ≤ 4000) — the ratings of other accounts.
Output
For each test case output the minimal number of contests needed to infect all accounts.
Example
Input
3
2 69
68 70
6 4
4 4 4 4 4 4
9 38
-21 83 50 -59 -77 15 -71 -78 20
Output
1
0
2
Note
In the first test case it's possible to make all ratings equal to 69. First account's rating will increase by 1, and second account's rating will decrease by 1, so the sum of all changes will be equal to zero.
In the second test case all accounts will be instantly infected, because all ratings (including Killjoy's account's rating) are equal to 4.
Tags: greedy, implementation, math
Correct Solution:
```
from sys import stdin, stdout
import math
t=int(stdin.readline())
for _ in range(t):
n,k=map(int,stdin.readline().split())
arr=list(map(int,stdin.readline().split()))
sume=0
counter=0
flag=0
for i in range(n):
if arr[i]!=k:
sume+=(k-arr[i])
counter+=1
else:
flag-=1
if counter==0:
print(0)
else:
if sume==(n-counter)*k or flag<=-1 :
print(1)
else:
print(2)
```
| 31,922 | [
0.267333984375,
-0.128662109375,
-0.09716796875,
0.2034912109375,
-0.2193603515625,
-0.78466796875,
-0.15625,
0.3154296875,
-0.12152099609375,
0.7412109375,
0.17822265625,
-0.11505126953125,
0.351806640625,
-0.66845703125,
-0.280517578125,
-0.305908203125,
-0.262451171875,
-0.87304... | 11 |
Provide tags and a correct Python 3 solution for this coding contest problem.
A new agent called Killjoy invented a virus COVID-2069 that infects accounts on Codeforces. Each account has a rating, described by an integer (it can possibly be negative or very large).
Killjoy's account is already infected and has a rating equal to x. Its rating is constant. There are n accounts except hers, numbered from 1 to n. The i-th account's initial rating is a_i. Any infected account (initially the only infected account is Killjoy's) instantly infects any uninfected account if their ratings are equal. This can happen at the beginning (before any rating changes) and after each contest. If an account is infected, it can not be healed.
Contests are regularly held on Codeforces. In each contest, any of these n accounts (including infected ones) can participate. Killjoy can't participate. After each contest ratings are changed this way: each participant's rating is changed by an integer, but the sum of all changes must be equal to zero. New ratings can be any integer.
Find out the minimal number of contests needed to infect all accounts. You can choose which accounts will participate in each contest and how the ratings will change.
It can be proven that all accounts can be infected in some finite number of contests.
Input
The first line contains a single integer t (1 ≤ t ≤ 100) — the number of test cases. The next 2t lines contain the descriptions of all test cases.
The first line of each test case contains two integers n and x (2 ≤ n ≤ 10^3, -4000 ≤ x ≤ 4000) — the number of accounts on Codeforces and the rating of Killjoy's account.
The second line of each test case contains n integers a_1, a_2, ..., a_n (-4000 ≤ a_i ≤ 4000) — the ratings of other accounts.
Output
For each test case output the minimal number of contests needed to infect all accounts.
Example
Input
3
2 69
68 70
6 4
4 4 4 4 4 4
9 38
-21 83 50 -59 -77 15 -71 -78 20
Output
1
0
2
Note
In the first test case it's possible to make all ratings equal to 69. First account's rating will increase by 1, and second account's rating will decrease by 1, so the sum of all changes will be equal to zero.
In the second test case all accounts will be instantly infected, because all ratings (including Killjoy's account's rating) are equal to 4.
Tags: greedy, implementation, math
Correct Solution:
```
z,zz=input,lambda:list(map(int,z().split()))
zzz=lambda:[int(i) for i in stdin.readline().split()]
szz,graph,mod,szzz=lambda:sorted(zz()),{},10**9+7,lambda:sorted(zzz())
from string import *
from re import *
from collections import *
from queue import *
from sys import *
from collections import *
from math import *
from heapq import *
from itertools import *
from bisect import *
from collections import Counter as cc
from math import factorial as f
from bisect import bisect as bs
from bisect import bisect_left as bsl
from itertools import accumulate as ac
from itertools import permutations as permu
def lcd(xnum1,xnum2):return (xnum1*xnum2//gcd(xnum1,xnum2))
def prime(x):
p=ceil(x**.5)+1
for i in range(2,p):
if (x%i==0 and x!=2) or x==0:return 0
return 1
def dfs(u,visit,graph):
visit[u]=True
for i in graph[u]:
if not visit[i]:
dfs(i,visit,graph)
###########################---Test-Case---#################################
"""
"""
###########################---START-CODING---##############################
num=1
num=int(z())
for _ in range( num ):
n,x=zzz()
arr=szzz()
lst=[]
for i in arr:
lst.append((i-x))
if len(set(lst))==1 and list(set(lst))[0]==0:
print(0)
continue
if sum(lst)==0:
print(1)
continue
if x in arr:
print(1)
continue
print(2)
```
| 31,923 | [
0.267333984375,
-0.128662109375,
-0.09716796875,
0.2034912109375,
-0.2193603515625,
-0.78466796875,
-0.15625,
0.3154296875,
-0.12152099609375,
0.7412109375,
0.17822265625,
-0.11505126953125,
0.351806640625,
-0.66845703125,
-0.280517578125,
-0.305908203125,
-0.262451171875,
-0.87304... | 11 |
Provide tags and a correct Python 3 solution for this coding contest problem.
A new agent called Killjoy invented a virus COVID-2069 that infects accounts on Codeforces. Each account has a rating, described by an integer (it can possibly be negative or very large).
Killjoy's account is already infected and has a rating equal to x. Its rating is constant. There are n accounts except hers, numbered from 1 to n. The i-th account's initial rating is a_i. Any infected account (initially the only infected account is Killjoy's) instantly infects any uninfected account if their ratings are equal. This can happen at the beginning (before any rating changes) and after each contest. If an account is infected, it can not be healed.
Contests are regularly held on Codeforces. In each contest, any of these n accounts (including infected ones) can participate. Killjoy can't participate. After each contest ratings are changed this way: each participant's rating is changed by an integer, but the sum of all changes must be equal to zero. New ratings can be any integer.
Find out the minimal number of contests needed to infect all accounts. You can choose which accounts will participate in each contest and how the ratings will change.
It can be proven that all accounts can be infected in some finite number of contests.
Input
The first line contains a single integer t (1 ≤ t ≤ 100) — the number of test cases. The next 2t lines contain the descriptions of all test cases.
The first line of each test case contains two integers n and x (2 ≤ n ≤ 10^3, -4000 ≤ x ≤ 4000) — the number of accounts on Codeforces and the rating of Killjoy's account.
The second line of each test case contains n integers a_1, a_2, ..., a_n (-4000 ≤ a_i ≤ 4000) — the ratings of other accounts.
Output
For each test case output the minimal number of contests needed to infect all accounts.
Example
Input
3
2 69
68 70
6 4
4 4 4 4 4 4
9 38
-21 83 50 -59 -77 15 -71 -78 20
Output
1
0
2
Note
In the first test case it's possible to make all ratings equal to 69. First account's rating will increase by 1, and second account's rating will decrease by 1, so the sum of all changes will be equal to zero.
In the second test case all accounts will be instantly infected, because all ratings (including Killjoy's account's rating) are equal to 4.
Tags: greedy, implementation, math
Correct Solution:
```
for _ in range(int(input())):
n,x=[int(x) for x in input().split()]
array=[int(x) for x in input().split()]
if len(set(array))==1 and array[0]==array[1] and x==array[0]:
print(0)
elif x in array or (sum(array))/n==float(x):
print(1)
else:
print(2)
```
| 31,924 | [
0.267333984375,
-0.128662109375,
-0.09716796875,
0.2034912109375,
-0.2193603515625,
-0.78466796875,
-0.15625,
0.3154296875,
-0.12152099609375,
0.7412109375,
0.17822265625,
-0.11505126953125,
0.351806640625,
-0.66845703125,
-0.280517578125,
-0.305908203125,
-0.262451171875,
-0.87304... | 11 |
Provide tags and a correct Python 3 solution for this coding contest problem.
A new agent called Killjoy invented a virus COVID-2069 that infects accounts on Codeforces. Each account has a rating, described by an integer (it can possibly be negative or very large).
Killjoy's account is already infected and has a rating equal to x. Its rating is constant. There are n accounts except hers, numbered from 1 to n. The i-th account's initial rating is a_i. Any infected account (initially the only infected account is Killjoy's) instantly infects any uninfected account if their ratings are equal. This can happen at the beginning (before any rating changes) and after each contest. If an account is infected, it can not be healed.
Contests are regularly held on Codeforces. In each contest, any of these n accounts (including infected ones) can participate. Killjoy can't participate. After each contest ratings are changed this way: each participant's rating is changed by an integer, but the sum of all changes must be equal to zero. New ratings can be any integer.
Find out the minimal number of contests needed to infect all accounts. You can choose which accounts will participate in each contest and how the ratings will change.
It can be proven that all accounts can be infected in some finite number of contests.
Input
The first line contains a single integer t (1 ≤ t ≤ 100) — the number of test cases. The next 2t lines contain the descriptions of all test cases.
The first line of each test case contains two integers n and x (2 ≤ n ≤ 10^3, -4000 ≤ x ≤ 4000) — the number of accounts on Codeforces and the rating of Killjoy's account.
The second line of each test case contains n integers a_1, a_2, ..., a_n (-4000 ≤ a_i ≤ 4000) — the ratings of other accounts.
Output
For each test case output the minimal number of contests needed to infect all accounts.
Example
Input
3
2 69
68 70
6 4
4 4 4 4 4 4
9 38
-21 83 50 -59 -77 15 -71 -78 20
Output
1
0
2
Note
In the first test case it's possible to make all ratings equal to 69. First account's rating will increase by 1, and second account's rating will decrease by 1, so the sum of all changes will be equal to zero.
In the second test case all accounts will be instantly infected, because all ratings (including Killjoy's account's rating) are equal to 4.
Tags: greedy, implementation, math
Correct Solution:
```
import sys, math
import io, os
#data = io.BytesIO(os.read(0,os.fstat(0).st_size)).readline
from bisect import bisect_left as bl, bisect_right as br, insort
from heapq import heapify, heappush, heappop
from collections import defaultdict as dd, deque, Counter
# from itertools import permutations,combinations
def data(): return sys.stdin.readline().strip()
def mdata(): return list(map(int, data().split()))
def outl(var): sys.stdout.write(' '.join(map(str, var)) + '\n')
def out(var): sys.stdout.write(str(var) + '\n')
from decimal import Decimal
# from fractions import Fraction
# sys.setrecursionlimit(100000)
mod = 998244353
INF=float('inf')
for t in range(int(data())):
n,x=mdata()
a=mdata()
if max(a)==min(a)==x:
out(0)
elif x in a or sum(a)==n*x:
out(1)
else:
out(2)
```
| 31,925 | [
0.267333984375,
-0.128662109375,
-0.09716796875,
0.2034912109375,
-0.2193603515625,
-0.78466796875,
-0.15625,
0.3154296875,
-0.12152099609375,
0.7412109375,
0.17822265625,
-0.11505126953125,
0.351806640625,
-0.66845703125,
-0.280517578125,
-0.305908203125,
-0.262451171875,
-0.87304... | 11 |
Provide tags and a correct Python 3 solution for this coding contest problem.
A new agent called Killjoy invented a virus COVID-2069 that infects accounts on Codeforces. Each account has a rating, described by an integer (it can possibly be negative or very large).
Killjoy's account is already infected and has a rating equal to x. Its rating is constant. There are n accounts except hers, numbered from 1 to n. The i-th account's initial rating is a_i. Any infected account (initially the only infected account is Killjoy's) instantly infects any uninfected account if their ratings are equal. This can happen at the beginning (before any rating changes) and after each contest. If an account is infected, it can not be healed.
Contests are regularly held on Codeforces. In each contest, any of these n accounts (including infected ones) can participate. Killjoy can't participate. After each contest ratings are changed this way: each participant's rating is changed by an integer, but the sum of all changes must be equal to zero. New ratings can be any integer.
Find out the minimal number of contests needed to infect all accounts. You can choose which accounts will participate in each contest and how the ratings will change.
It can be proven that all accounts can be infected in some finite number of contests.
Input
The first line contains a single integer t (1 ≤ t ≤ 100) — the number of test cases. The next 2t lines contain the descriptions of all test cases.
The first line of each test case contains two integers n and x (2 ≤ n ≤ 10^3, -4000 ≤ x ≤ 4000) — the number of accounts on Codeforces and the rating of Killjoy's account.
The second line of each test case contains n integers a_1, a_2, ..., a_n (-4000 ≤ a_i ≤ 4000) — the ratings of other accounts.
Output
For each test case output the minimal number of contests needed to infect all accounts.
Example
Input
3
2 69
68 70
6 4
4 4 4 4 4 4
9 38
-21 83 50 -59 -77 15 -71 -78 20
Output
1
0
2
Note
In the first test case it's possible to make all ratings equal to 69. First account's rating will increase by 1, and second account's rating will decrease by 1, so the sum of all changes will be equal to zero.
In the second test case all accounts will be instantly infected, because all ratings (including Killjoy's account's rating) are equal to 4.
Tags: greedy, implementation, math
Correct Solution:
```
for _ in range(int(input())):
n,x=map(int,input().split())
l=list(map(int,input().split()))
if(l.count(x)==len(l)):
print(0)
elif(l.count(x)>0 or sum(l)==n*x):
print(1)
else:
print(2)
```
| 31,926 | [
0.267333984375,
-0.128662109375,
-0.09716796875,
0.2034912109375,
-0.2193603515625,
-0.78466796875,
-0.15625,
0.3154296875,
-0.12152099609375,
0.7412109375,
0.17822265625,
-0.11505126953125,
0.351806640625,
-0.66845703125,
-0.280517578125,
-0.305908203125,
-0.262451171875,
-0.87304... | 11 |
Provide tags and a correct Python 3 solution for this coding contest problem.
A new agent called Killjoy invented a virus COVID-2069 that infects accounts on Codeforces. Each account has a rating, described by an integer (it can possibly be negative or very large).
Killjoy's account is already infected and has a rating equal to x. Its rating is constant. There are n accounts except hers, numbered from 1 to n. The i-th account's initial rating is a_i. Any infected account (initially the only infected account is Killjoy's) instantly infects any uninfected account if their ratings are equal. This can happen at the beginning (before any rating changes) and after each contest. If an account is infected, it can not be healed.
Contests are regularly held on Codeforces. In each contest, any of these n accounts (including infected ones) can participate. Killjoy can't participate. After each contest ratings are changed this way: each participant's rating is changed by an integer, but the sum of all changes must be equal to zero. New ratings can be any integer.
Find out the minimal number of contests needed to infect all accounts. You can choose which accounts will participate in each contest and how the ratings will change.
It can be proven that all accounts can be infected in some finite number of contests.
Input
The first line contains a single integer t (1 ≤ t ≤ 100) — the number of test cases. The next 2t lines contain the descriptions of all test cases.
The first line of each test case contains two integers n and x (2 ≤ n ≤ 10^3, -4000 ≤ x ≤ 4000) — the number of accounts on Codeforces and the rating of Killjoy's account.
The second line of each test case contains n integers a_1, a_2, ..., a_n (-4000 ≤ a_i ≤ 4000) — the ratings of other accounts.
Output
For each test case output the minimal number of contests needed to infect all accounts.
Example
Input
3
2 69
68 70
6 4
4 4 4 4 4 4
9 38
-21 83 50 -59 -77 15 -71 -78 20
Output
1
0
2
Note
In the first test case it's possible to make all ratings equal to 69. First account's rating will increase by 1, and second account's rating will decrease by 1, so the sum of all changes will be equal to zero.
In the second test case all accounts will be instantly infected, because all ratings (including Killjoy's account's rating) are equal to 4.
Tags: greedy, implementation, math
Correct Solution:
```
from math import pow
t = int(input())
for _ in range(t):
inp = list(map(int, input().split()))
n, x = inp[0], inp[1]
a = list(map(int, input().split()))
s = sum(a)
if s % n == 0 and s // n == x or x in a:
for i in range(n):
if a[i] != x:
print(1)
break
if i == n-1:
print(0)
else:
print(2)
```
| 31,927 | [
0.267333984375,
-0.128662109375,
-0.09716796875,
0.2034912109375,
-0.2193603515625,
-0.78466796875,
-0.15625,
0.3154296875,
-0.12152099609375,
0.7412109375,
0.17822265625,
-0.11505126953125,
0.351806640625,
-0.66845703125,
-0.280517578125,
-0.305908203125,
-0.262451171875,
-0.87304... | 11 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A new agent called Killjoy invented a virus COVID-2069 that infects accounts on Codeforces. Each account has a rating, described by an integer (it can possibly be negative or very large).
Killjoy's account is already infected and has a rating equal to x. Its rating is constant. There are n accounts except hers, numbered from 1 to n. The i-th account's initial rating is a_i. Any infected account (initially the only infected account is Killjoy's) instantly infects any uninfected account if their ratings are equal. This can happen at the beginning (before any rating changes) and after each contest. If an account is infected, it can not be healed.
Contests are regularly held on Codeforces. In each contest, any of these n accounts (including infected ones) can participate. Killjoy can't participate. After each contest ratings are changed this way: each participant's rating is changed by an integer, but the sum of all changes must be equal to zero. New ratings can be any integer.
Find out the minimal number of contests needed to infect all accounts. You can choose which accounts will participate in each contest and how the ratings will change.
It can be proven that all accounts can be infected in some finite number of contests.
Input
The first line contains a single integer t (1 ≤ t ≤ 100) — the number of test cases. The next 2t lines contain the descriptions of all test cases.
The first line of each test case contains two integers n and x (2 ≤ n ≤ 10^3, -4000 ≤ x ≤ 4000) — the number of accounts on Codeforces and the rating of Killjoy's account.
The second line of each test case contains n integers a_1, a_2, ..., a_n (-4000 ≤ a_i ≤ 4000) — the ratings of other accounts.
Output
For each test case output the minimal number of contests needed to infect all accounts.
Example
Input
3
2 69
68 70
6 4
4 4 4 4 4 4
9 38
-21 83 50 -59 -77 15 -71 -78 20
Output
1
0
2
Note
In the first test case it's possible to make all ratings equal to 69. First account's rating will increase by 1, and second account's rating will decrease by 1, so the sum of all changes will be equal to zero.
In the second test case all accounts will be instantly infected, because all ratings (including Killjoy's account's rating) are equal to 4.
Submitted Solution:
```
def ans(a, n, k):
same = 0
for i in a:
if i==k:
same+=1
if same==n:
return(0)
if sum(a)%n==0 and sum(a)//n==k:
return(1)
if same>0:
return(1)
return(2)
m = int(input())
for i in range(m):
brr = input().split()
n = int(brr[0])
k = int(brr[1])
arr = input().split()
a = []
for i in arr:
a.append(int(i))
print(ans(a, n, k))
```
Yes
| 31,928 | [
0.311279296875,
-0.14111328125,
-0.056976318359375,
0.11480712890625,
-0.2301025390625,
-0.72314453125,
-0.183837890625,
0.362060546875,
-0.11126708984375,
0.79052734375,
0.0941162109375,
-0.095703125,
0.3330078125,
-0.6455078125,
-0.24365234375,
-0.22998046875,
-0.225830078125,
-0... | 11 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A new agent called Killjoy invented a virus COVID-2069 that infects accounts on Codeforces. Each account has a rating, described by an integer (it can possibly be negative or very large).
Killjoy's account is already infected and has a rating equal to x. Its rating is constant. There are n accounts except hers, numbered from 1 to n. The i-th account's initial rating is a_i. Any infected account (initially the only infected account is Killjoy's) instantly infects any uninfected account if their ratings are equal. This can happen at the beginning (before any rating changes) and after each contest. If an account is infected, it can not be healed.
Contests are regularly held on Codeforces. In each contest, any of these n accounts (including infected ones) can participate. Killjoy can't participate. After each contest ratings are changed this way: each participant's rating is changed by an integer, but the sum of all changes must be equal to zero. New ratings can be any integer.
Find out the minimal number of contests needed to infect all accounts. You can choose which accounts will participate in each contest and how the ratings will change.
It can be proven that all accounts can be infected in some finite number of contests.
Input
The first line contains a single integer t (1 ≤ t ≤ 100) — the number of test cases. The next 2t lines contain the descriptions of all test cases.
The first line of each test case contains two integers n and x (2 ≤ n ≤ 10^3, -4000 ≤ x ≤ 4000) — the number of accounts on Codeforces and the rating of Killjoy's account.
The second line of each test case contains n integers a_1, a_2, ..., a_n (-4000 ≤ a_i ≤ 4000) — the ratings of other accounts.
Output
For each test case output the minimal number of contests needed to infect all accounts.
Example
Input
3
2 69
68 70
6 4
4 4 4 4 4 4
9 38
-21 83 50 -59 -77 15 -71 -78 20
Output
1
0
2
Note
In the first test case it's possible to make all ratings equal to 69. First account's rating will increase by 1, and second account's rating will decrease by 1, so the sum of all changes will be equal to zero.
In the second test case all accounts will be instantly infected, because all ratings (including Killjoy's account's rating) are equal to 4.
Submitted Solution:
```
for j in range(int(input())):
n,vir = input().split()
a = [int(x) for x in input().split()]
neg,pos = 0, 0
if all(map(lambda x: x == int(vir), a)):
print(0)
elif any(map(lambda x: x == int(vir), a)):
print(1)
else:
for i in a:
if i < int(vir):
neg += abs(int(vir) - i)
else:
pos += abs(i - int(vir))
if neg == pos:
print(1)
else:
print(2)
```
Yes
| 31,929 | [
0.311279296875,
-0.14111328125,
-0.056976318359375,
0.11480712890625,
-0.2301025390625,
-0.72314453125,
-0.183837890625,
0.362060546875,
-0.11126708984375,
0.79052734375,
0.0941162109375,
-0.095703125,
0.3330078125,
-0.6455078125,
-0.24365234375,
-0.22998046875,
-0.225830078125,
-0... | 11 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A new agent called Killjoy invented a virus COVID-2069 that infects accounts on Codeforces. Each account has a rating, described by an integer (it can possibly be negative or very large).
Killjoy's account is already infected and has a rating equal to x. Its rating is constant. There are n accounts except hers, numbered from 1 to n. The i-th account's initial rating is a_i. Any infected account (initially the only infected account is Killjoy's) instantly infects any uninfected account if their ratings are equal. This can happen at the beginning (before any rating changes) and after each contest. If an account is infected, it can not be healed.
Contests are regularly held on Codeforces. In each contest, any of these n accounts (including infected ones) can participate. Killjoy can't participate. After each contest ratings are changed this way: each participant's rating is changed by an integer, but the sum of all changes must be equal to zero. New ratings can be any integer.
Find out the minimal number of contests needed to infect all accounts. You can choose which accounts will participate in each contest and how the ratings will change.
It can be proven that all accounts can be infected in some finite number of contests.
Input
The first line contains a single integer t (1 ≤ t ≤ 100) — the number of test cases. The next 2t lines contain the descriptions of all test cases.
The first line of each test case contains two integers n and x (2 ≤ n ≤ 10^3, -4000 ≤ x ≤ 4000) — the number of accounts on Codeforces and the rating of Killjoy's account.
The second line of each test case contains n integers a_1, a_2, ..., a_n (-4000 ≤ a_i ≤ 4000) — the ratings of other accounts.
Output
For each test case output the minimal number of contests needed to infect all accounts.
Example
Input
3
2 69
68 70
6 4
4 4 4 4 4 4
9 38
-21 83 50 -59 -77 15 -71 -78 20
Output
1
0
2
Note
In the first test case it's possible to make all ratings equal to 69. First account's rating will increase by 1, and second account's rating will decrease by 1, so the sum of all changes will be equal to zero.
In the second test case all accounts will be instantly infected, because all ratings (including Killjoy's account's rating) are equal to 4.
Submitted Solution:
```
def solve():
# put code here
n,x=[int(v) for v in input().split()]
arr=[int(v) for v in input().split()]
if all(x==v for v in arr):
print(0)
elif x in arr or sum(v-x for v in arr)==0:
print(1)
else:
print(2)
t = int(input())
for _ in range(t):
solve()
```
Yes
| 31,930 | [
0.311279296875,
-0.14111328125,
-0.056976318359375,
0.11480712890625,
-0.2301025390625,
-0.72314453125,
-0.183837890625,
0.362060546875,
-0.11126708984375,
0.79052734375,
0.0941162109375,
-0.095703125,
0.3330078125,
-0.6455078125,
-0.24365234375,
-0.22998046875,
-0.225830078125,
-0... | 11 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A new agent called Killjoy invented a virus COVID-2069 that infects accounts on Codeforces. Each account has a rating, described by an integer (it can possibly be negative or very large).
Killjoy's account is already infected and has a rating equal to x. Its rating is constant. There are n accounts except hers, numbered from 1 to n. The i-th account's initial rating is a_i. Any infected account (initially the only infected account is Killjoy's) instantly infects any uninfected account if their ratings are equal. This can happen at the beginning (before any rating changes) and after each contest. If an account is infected, it can not be healed.
Contests are regularly held on Codeforces. In each contest, any of these n accounts (including infected ones) can participate. Killjoy can't participate. After each contest ratings are changed this way: each participant's rating is changed by an integer, but the sum of all changes must be equal to zero. New ratings can be any integer.
Find out the minimal number of contests needed to infect all accounts. You can choose which accounts will participate in each contest and how the ratings will change.
It can be proven that all accounts can be infected in some finite number of contests.
Input
The first line contains a single integer t (1 ≤ t ≤ 100) — the number of test cases. The next 2t lines contain the descriptions of all test cases.
The first line of each test case contains two integers n and x (2 ≤ n ≤ 10^3, -4000 ≤ x ≤ 4000) — the number of accounts on Codeforces and the rating of Killjoy's account.
The second line of each test case contains n integers a_1, a_2, ..., a_n (-4000 ≤ a_i ≤ 4000) — the ratings of other accounts.
Output
For each test case output the minimal number of contests needed to infect all accounts.
Example
Input
3
2 69
68 70
6 4
4 4 4 4 4 4
9 38
-21 83 50 -59 -77 15 -71 -78 20
Output
1
0
2
Note
In the first test case it's possible to make all ratings equal to 69. First account's rating will increase by 1, and second account's rating will decrease by 1, so the sum of all changes will be equal to zero.
In the second test case all accounts will be instantly infected, because all ratings (including Killjoy's account's rating) are equal to 4.
Submitted Solution:
```
for _ in range(int(input())):
n,x=map(int,input().split())
arr=list(map(int,input().split()))
ct=arr.count(x)
if ct==n:
print(0)
elif ct>=1:
print(1)
else:
s=sum(arr)
if s%n==0 and (s//n)==x:
print(1)
else:
print(2)
```
Yes
| 31,931 | [
0.311279296875,
-0.14111328125,
-0.056976318359375,
0.11480712890625,
-0.2301025390625,
-0.72314453125,
-0.183837890625,
0.362060546875,
-0.11126708984375,
0.79052734375,
0.0941162109375,
-0.095703125,
0.3330078125,
-0.6455078125,
-0.24365234375,
-0.22998046875,
-0.225830078125,
-0... | 11 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A new agent called Killjoy invented a virus COVID-2069 that infects accounts on Codeforces. Each account has a rating, described by an integer (it can possibly be negative or very large).
Killjoy's account is already infected and has a rating equal to x. Its rating is constant. There are n accounts except hers, numbered from 1 to n. The i-th account's initial rating is a_i. Any infected account (initially the only infected account is Killjoy's) instantly infects any uninfected account if their ratings are equal. This can happen at the beginning (before any rating changes) and after each contest. If an account is infected, it can not be healed.
Contests are regularly held on Codeforces. In each contest, any of these n accounts (including infected ones) can participate. Killjoy can't participate. After each contest ratings are changed this way: each participant's rating is changed by an integer, but the sum of all changes must be equal to zero. New ratings can be any integer.
Find out the minimal number of contests needed to infect all accounts. You can choose which accounts will participate in each contest and how the ratings will change.
It can be proven that all accounts can be infected in some finite number of contests.
Input
The first line contains a single integer t (1 ≤ t ≤ 100) — the number of test cases. The next 2t lines contain the descriptions of all test cases.
The first line of each test case contains two integers n and x (2 ≤ n ≤ 10^3, -4000 ≤ x ≤ 4000) — the number of accounts on Codeforces and the rating of Killjoy's account.
The second line of each test case contains n integers a_1, a_2, ..., a_n (-4000 ≤ a_i ≤ 4000) — the ratings of other accounts.
Output
For each test case output the minimal number of contests needed to infect all accounts.
Example
Input
3
2 69
68 70
6 4
4 4 4 4 4 4
9 38
-21 83 50 -59 -77 15 -71 -78 20
Output
1
0
2
Note
In the first test case it's possible to make all ratings equal to 69. First account's rating will increase by 1, and second account's rating will decrease by 1, so the sum of all changes will be equal to zero.
In the second test case all accounts will be instantly infected, because all ratings (including Killjoy's account's rating) are equal to 4.
Submitted Solution:
```
def ans(a, n, k):
same = 0
more = 0
less = 0
for i in a:
if i==k:
same+=1
elif i>k:
more+=1
else:
less+=1
if same==n:
return(0)
if sum(a)%n==0 and sum(a)//n==k:
return(1)
if same>0 and sum(a)%n==0:
return(1)
return(min(more,less))
m = int(input())
for i in range(m):
brr = input().split()
n = int(brr[0])
k = int(brr[1])
arr = input().split()
a = []
for i in arr:
a.append(int(i))
print(ans(a, n, k))
```
No
| 31,932 | [
0.311279296875,
-0.14111328125,
-0.056976318359375,
0.11480712890625,
-0.2301025390625,
-0.72314453125,
-0.183837890625,
0.362060546875,
-0.11126708984375,
0.79052734375,
0.0941162109375,
-0.095703125,
0.3330078125,
-0.6455078125,
-0.24365234375,
-0.22998046875,
-0.225830078125,
-0... | 11 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A new agent called Killjoy invented a virus COVID-2069 that infects accounts on Codeforces. Each account has a rating, described by an integer (it can possibly be negative or very large).
Killjoy's account is already infected and has a rating equal to x. Its rating is constant. There are n accounts except hers, numbered from 1 to n. The i-th account's initial rating is a_i. Any infected account (initially the only infected account is Killjoy's) instantly infects any uninfected account if their ratings are equal. This can happen at the beginning (before any rating changes) and after each contest. If an account is infected, it can not be healed.
Contests are regularly held on Codeforces. In each contest, any of these n accounts (including infected ones) can participate. Killjoy can't participate. After each contest ratings are changed this way: each participant's rating is changed by an integer, but the sum of all changes must be equal to zero. New ratings can be any integer.
Find out the minimal number of contests needed to infect all accounts. You can choose which accounts will participate in each contest and how the ratings will change.
It can be proven that all accounts can be infected in some finite number of contests.
Input
The first line contains a single integer t (1 ≤ t ≤ 100) — the number of test cases. The next 2t lines contain the descriptions of all test cases.
The first line of each test case contains two integers n and x (2 ≤ n ≤ 10^3, -4000 ≤ x ≤ 4000) — the number of accounts on Codeforces and the rating of Killjoy's account.
The second line of each test case contains n integers a_1, a_2, ..., a_n (-4000 ≤ a_i ≤ 4000) — the ratings of other accounts.
Output
For each test case output the minimal number of contests needed to infect all accounts.
Example
Input
3
2 69
68 70
6 4
4 4 4 4 4 4
9 38
-21 83 50 -59 -77 15 -71 -78 20
Output
1
0
2
Note
In the first test case it's possible to make all ratings equal to 69. First account's rating will increase by 1, and second account's rating will decrease by 1, so the sum of all changes will be equal to zero.
In the second test case all accounts will be instantly infected, because all ratings (including Killjoy's account's rating) are equal to 4.
Submitted Solution:
```
#!/usr/bin/env python
import os
import sys
from io import BytesIO, IOBase
import threading
from bisect import bisect_right
from math import gcd,log
from collections import Counter
from pprint import pprint
# arr=[1]
# i=1
# while i <100:
# arr.append(2*arr[-1]+2**(i+1))
# i=2*i+1
# print(arr)
def main():
n,x=map(int,input().split())
arr=list(map(lambda it:int(it)-x,input().split()))
# print(arr)
if any(arr):
if sum(arr)==0:
print(1)
else:
print(2)
else:
print(0)
BUFSIZE = 8192
class FastIO(IOBase):
newlines = 0
def __init__(self, file):
self._fd = file.fileno()
self.buffer = BytesIO()
self.writable = "x" in file.mode or "r" not in file.mode
self.write = self.buffer.write if self.writable else None
def read(self):
while True:
b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
if not b:
break
ptr = self.buffer.tell()
self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
self.newlines = 0
return self.buffer.read()
def readline(self):
while self.newlines == 0:
b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
self.newlines = b.count(b"\n") + (not b)
ptr = self.buffer.tell()
self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
self.newlines -= 1
return self.buffer.readline()
def flush(self):
if self.writable:
os.write(self._fd, self.buffer.getvalue())
self.buffer.truncate(0), self.buffer.seek(0)
class IOWrapper(IOBase):
def __init__(self, file):
self.buffer = FastIO(file)
self.flush = self.buffer.flush
self.writable = self.buffer.writable
self.write = lambda s: self.buffer.write(s.encode("ascii"))
self.read = lambda: self.buffer.read().decode("ascii")
self.readline = lambda: self.buffer.readline().decode("ascii")
sys.stdin, sys.stdout = IOWrapper(sys.stdin), IOWrapper(sys.stdout)
input = lambda: sys.stdin.readline().rstrip("\r\n")
# endregion
if __name__ == "__main__":
for _ in range(int(input())):
main()
```
No
| 31,933 | [
0.311279296875,
-0.14111328125,
-0.056976318359375,
0.11480712890625,
-0.2301025390625,
-0.72314453125,
-0.183837890625,
0.362060546875,
-0.11126708984375,
0.79052734375,
0.0941162109375,
-0.095703125,
0.3330078125,
-0.6455078125,
-0.24365234375,
-0.22998046875,
-0.225830078125,
-0... | 11 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A new agent called Killjoy invented a virus COVID-2069 that infects accounts on Codeforces. Each account has a rating, described by an integer (it can possibly be negative or very large).
Killjoy's account is already infected and has a rating equal to x. Its rating is constant. There are n accounts except hers, numbered from 1 to n. The i-th account's initial rating is a_i. Any infected account (initially the only infected account is Killjoy's) instantly infects any uninfected account if their ratings are equal. This can happen at the beginning (before any rating changes) and after each contest. If an account is infected, it can not be healed.
Contests are regularly held on Codeforces. In each contest, any of these n accounts (including infected ones) can participate. Killjoy can't participate. After each contest ratings are changed this way: each participant's rating is changed by an integer, but the sum of all changes must be equal to zero. New ratings can be any integer.
Find out the minimal number of contests needed to infect all accounts. You can choose which accounts will participate in each contest and how the ratings will change.
It can be proven that all accounts can be infected in some finite number of contests.
Input
The first line contains a single integer t (1 ≤ t ≤ 100) — the number of test cases. The next 2t lines contain the descriptions of all test cases.
The first line of each test case contains two integers n and x (2 ≤ n ≤ 10^3, -4000 ≤ x ≤ 4000) — the number of accounts on Codeforces and the rating of Killjoy's account.
The second line of each test case contains n integers a_1, a_2, ..., a_n (-4000 ≤ a_i ≤ 4000) — the ratings of other accounts.
Output
For each test case output the minimal number of contests needed to infect all accounts.
Example
Input
3
2 69
68 70
6 4
4 4 4 4 4 4
9 38
-21 83 50 -59 -77 15 -71 -78 20
Output
1
0
2
Note
In the first test case it's possible to make all ratings equal to 69. First account's rating will increase by 1, and second account's rating will decrease by 1, so the sum of all changes will be equal to zero.
In the second test case all accounts will be instantly infected, because all ratings (including Killjoy's account's rating) are equal to 4.
Submitted Solution:
```
def MI():return (map(int,input().split()))
for _ in range(int(input())):
n,x=MI()
arr=list(MI())
if arr.count(x)==n:
print(0)
elif sum(arr)%n==0 and sum(arr)//n==x:
print(1)
else:
print(2)
```
No
| 31,934 | [
0.311279296875,
-0.14111328125,
-0.056976318359375,
0.11480712890625,
-0.2301025390625,
-0.72314453125,
-0.183837890625,
0.362060546875,
-0.11126708984375,
0.79052734375,
0.0941162109375,
-0.095703125,
0.3330078125,
-0.6455078125,
-0.24365234375,
-0.22998046875,
-0.225830078125,
-0... | 11 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A new agent called Killjoy invented a virus COVID-2069 that infects accounts on Codeforces. Each account has a rating, described by an integer (it can possibly be negative or very large).
Killjoy's account is already infected and has a rating equal to x. Its rating is constant. There are n accounts except hers, numbered from 1 to n. The i-th account's initial rating is a_i. Any infected account (initially the only infected account is Killjoy's) instantly infects any uninfected account if their ratings are equal. This can happen at the beginning (before any rating changes) and after each contest. If an account is infected, it can not be healed.
Contests are regularly held on Codeforces. In each contest, any of these n accounts (including infected ones) can participate. Killjoy can't participate. After each contest ratings are changed this way: each participant's rating is changed by an integer, but the sum of all changes must be equal to zero. New ratings can be any integer.
Find out the minimal number of contests needed to infect all accounts. You can choose which accounts will participate in each contest and how the ratings will change.
It can be proven that all accounts can be infected in some finite number of contests.
Input
The first line contains a single integer t (1 ≤ t ≤ 100) — the number of test cases. The next 2t lines contain the descriptions of all test cases.
The first line of each test case contains two integers n and x (2 ≤ n ≤ 10^3, -4000 ≤ x ≤ 4000) — the number of accounts on Codeforces and the rating of Killjoy's account.
The second line of each test case contains n integers a_1, a_2, ..., a_n (-4000 ≤ a_i ≤ 4000) — the ratings of other accounts.
Output
For each test case output the minimal number of contests needed to infect all accounts.
Example
Input
3
2 69
68 70
6 4
4 4 4 4 4 4
9 38
-21 83 50 -59 -77 15 -71 -78 20
Output
1
0
2
Note
In the first test case it's possible to make all ratings equal to 69. First account's rating will increase by 1, and second account's rating will decrease by 1, so the sum of all changes will be equal to zero.
In the second test case all accounts will be instantly infected, because all ratings (including Killjoy's account's rating) are equal to 4.
Submitted Solution:
```
def solve():
# n = int(input().strip())
n, x = map(int, input().strip().split())
a = list(map(int, input().strip().split()))
s = 0
found_1 = 0
for i in a:
if(i==x):
found_1 += 1
else:
s += i
if(s==0):
print(0)
elif(s/n)==x:
print(1)
else:
print(2)
t = int(input().strip())
for _ in range(t):
solve()
```
No
| 31,935 | [
0.311279296875,
-0.14111328125,
-0.056976318359375,
0.11480712890625,
-0.2301025390625,
-0.72314453125,
-0.183837890625,
0.362060546875,
-0.11126708984375,
0.79052734375,
0.0941162109375,
-0.095703125,
0.3330078125,
-0.6455078125,
-0.24365234375,
-0.22998046875,
-0.225830078125,
-0... | 11 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
In order to pass the entrance examination tomorrow, Taro has to study for T more hours.
Fortunately, he can leap to World B where time passes X times as fast as it does in our world (World A).
While (X \times t) hours pass in World B, t hours pass in World A.
How many hours will pass in World A while Taro studies for T hours in World B?
Constraints
* All values in input are integers.
* 1 \leq T \leq 100
* 1 \leq X \leq 100
Input
Input is given from Standard Input in the following format:
T X
Output
Print the number of hours that will pass in World A.
The output will be regarded as correct when its absolute or relative error from the judge's output is at most 10^{-3}.
Examples
Input
8 3
Output
2.6666666667
Input
99 1
Output
99.0000000000
Input
1 100
Output
0.0100000000
Submitted Solution:
```
#!/usr/bin/env python3
import sys
def solve(T: int, X: int):
print(T / Xl)
return
# Generated by 1.1.4 https://github.com/kyuridenamida/atcoder-tools (tips: You use the default template now. You can remove this line by using your custom template)
def main():
def iterate_tokens():
for line in sys.stdin:
for word in line.split():
yield word
tokens = iterate_tokens()
T = int(next(tokens)) # type: int
X = int(next(tokens)) # type: int
solve(T, X)
if __name__ == '__main__':
main()
```
No
| 32,318 | [
0.62451171875,
0.38916015625,
-0.46484375,
-0.31005859375,
-0.251953125,
-0.085693359375,
-0.23046875,
0.2218017578125,
0.1632080078125,
0.93408203125,
-0.0022335052490234375,
0.29150390625,
0.183837890625,
-1.08984375,
-0.254150390625,
-0.275390625,
-0.442138671875,
-0.50830078125... | 11 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
We have a 3 \times 3 grid. A number c_{i, j} is written in the square (i, j), where (i, j) denotes the square at the i-th row from the top and the j-th column from the left.
According to Takahashi, there are six integers a_1, a_2, a_3, b_1, b_2, b_3 whose values are fixed, and the number written in the square (i, j) is equal to a_i + b_j.
Determine if he is correct.
Constraints
* c_{i, j} \ (1 \leq i \leq 3, 1 \leq j \leq 3) is an integer between 0 and 100 (inclusive).
Input
Input is given from Standard Input in the following format:
c_{1,1} c_{1,2} c_{1,3}
c_{2,1} c_{2,2} c_{2,3}
c_{3,1} c_{3,2} c_{3,3}
Output
If Takahashi's statement is correct, print `Yes`; otherwise, print `No`.
Examples
Input
1 0 1
2 1 2
1 0 1
Output
Yes
Input
2 2 2
2 1 2
2 2 2
Output
No
Input
0 8 8
0 8 8
0 8 8
Output
Yes
Input
1 8 6
2 9 7
0 7 7
Output
No
Submitted Solution:
```
C = [list(map(int,input().split())) for i in range(3)]
cii_sum = sum([C[i][i] for i in range(3)])
C_sum = sum(list(map(sum,C)))
print("Yes" if cii_sum==(C_sum/3) else "No")
```
Yes
| 32,343 | [
0.369140625,
0.2325439453125,
0.052154541015625,
-0.26904296875,
-0.5029296875,
-0.08740234375,
-0.0904541015625,
0.0697021484375,
0.212890625,
0.97998046875,
0.363525390625,
0.376708984375,
-0.003002166748046875,
-0.6904296875,
-0.578125,
-0.16796875,
-0.61083984375,
-0.4697265625... | 11 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
We have a 3 \times 3 grid. A number c_{i, j} is written in the square (i, j), where (i, j) denotes the square at the i-th row from the top and the j-th column from the left.
According to Takahashi, there are six integers a_1, a_2, a_3, b_1, b_2, b_3 whose values are fixed, and the number written in the square (i, j) is equal to a_i + b_j.
Determine if he is correct.
Constraints
* c_{i, j} \ (1 \leq i \leq 3, 1 \leq j \leq 3) is an integer between 0 and 100 (inclusive).
Input
Input is given from Standard Input in the following format:
c_{1,1} c_{1,2} c_{1,3}
c_{2,1} c_{2,2} c_{2,3}
c_{3,1} c_{3,2} c_{3,3}
Output
If Takahashi's statement is correct, print `Yes`; otherwise, print `No`.
Examples
Input
1 0 1
2 1 2
1 0 1
Output
Yes
Input
2 2 2
2 1 2
2 2 2
Output
No
Input
0 8 8
0 8 8
0 8 8
Output
Yes
Input
1 8 6
2 9 7
0 7 7
Output
No
Submitted Solution:
```
c = [0] * 3
for i in range(3):
c[i] = list(map(int, input().split()))
sum_mat = (sum(c[0]) + sum(c[1]) + sum(c[2])) / 3
print('Yes' if sum_mat == c[0][0] + c[1][1] + c[2][2] else 'No')
```
Yes
| 32,344 | [
0.5029296875,
0.2113037109375,
-0.03216552734375,
-0.185546875,
-0.4541015625,
-0.0243072509765625,
0.078125,
-0.037017822265625,
0.2213134765625,
0.94921875,
0.50732421875,
0.367431640625,
0.06671142578125,
-0.671875,
-0.54833984375,
0.061065673828125,
-0.62158203125,
-0.540039062... | 11 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
We have a 3 \times 3 grid. A number c_{i, j} is written in the square (i, j), where (i, j) denotes the square at the i-th row from the top and the j-th column from the left.
According to Takahashi, there are six integers a_1, a_2, a_3, b_1, b_2, b_3 whose values are fixed, and the number written in the square (i, j) is equal to a_i + b_j.
Determine if he is correct.
Constraints
* c_{i, j} \ (1 \leq i \leq 3, 1 \leq j \leq 3) is an integer between 0 and 100 (inclusive).
Input
Input is given from Standard Input in the following format:
c_{1,1} c_{1,2} c_{1,3}
c_{2,1} c_{2,2} c_{2,3}
c_{3,1} c_{3,2} c_{3,3}
Output
If Takahashi's statement is correct, print `Yes`; otherwise, print `No`.
Examples
Input
1 0 1
2 1 2
1 0 1
Output
Yes
Input
2 2 2
2 1 2
2 2 2
Output
No
Input
0 8 8
0 8 8
0 8 8
Output
Yes
Input
1 8 6
2 9 7
0 7 7
Output
No
Submitted Solution:
```
# coding: utf-8
# Here your code
n = 3
e = [[int(i) for i in input().split()] for i in range(n)]
a = []
b = []
#for i in range(101):
a.append(0)
b.append(e[0][0] - a[0])
b.append(e[0][1] - a[0])
b.append(e[0][2] - a[0])
a.append(e[1][0] - b[0])
a.append(e[2][0] - b[0])
for i in range(3):
for j in range(3):
if a[i] + b[i] != e[i][j]:
print("No")
exit()
print("Yes")
```
No
| 32,347 | [
0.484619140625,
0.090087890625,
-0.06512451171875,
-0.169189453125,
-0.5458984375,
-0.01544952392578125,
-0.0207977294921875,
0.01212310791015625,
0.191650390625,
1.052734375,
0.435791015625,
0.22314453125,
-0.01206207275390625,
-0.662109375,
-0.52099609375,
-0.0210113525390625,
-0.6... | 11 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Mr.X, who the handle name is T, looked at the list which written N handle names, S_1, S_2, ..., S_N.
But he couldn't see some parts of the list. Invisible part is denoted `?`.
Please calculate all possible index of the handle name of Mr.X when you sort N+1 handle names (S_1, S_2, ..., S_N and T) in lexicographical order.
Note: If there are pair of people with same handle name, either one may come first.
Input
The input is given from standard input in the following format.
N
S_1
S_2
:
S_N
T
Output
* Calculate the possible index and print in sorted order. The output should be separated with a space. Don't print a space after last number.
* Put a line break in the end.
Constraints
* 1 ≤ N ≤ 10000
* 1 ≤ |S_i|, |T| ≤ 20 (|A| is the length of A.)
* S_i consists from lower-case alphabet and `?`.
* T consists from lower-case alphabet.
Scoring
Subtask 1 [ 130 points ]
* There are no `?`'s.
Subtask 2 [ 120 points ]
* There are no additional constraints.
Output
* Calculate the possible index and print in sorted order. The output should be separated with a space. Don't print a space after last number.
* Put a line break in the end.
Constraints
* 1 ≤ N ≤ 10000
* 1 ≤ |S_i|, |T| ≤ 20 (|A| is the length of A.)
* S_i consists from lower-case alphabet and `?`.
* T consists from lower-case alphabet.
Scoring
Subtask 1 [ 130 points ]
* There are no `?`'s.
Subtask 2 [ 120 points ]
* There are no additional constraints.
Input
The input is given from standard input in the following format.
N
S_1
S_2
:
S_N
T
Example
Input
2
tourist
petr
e
Output
1
Submitted Solution:
```
from collections import defaultdict,deque
import sys,heapq,bisect,math,itertools,string,queue,datetime,random
sys.setrecursionlimit(10**8)
INF = float('inf')
mod = 10**9+7
eps = 10**-7
def inpl(): return list(map(int, input().split()))
def inpls(): return list(input().split())
\
N = int(input())
SS = [input() for _ in range(N)]
T = input()
before = 0
after = 0
for S in SS:
sS = S.replace('?','a')
lS = S.replace('?','z')
if T < sS:
after += 1
elif lS < T:
before += 1
print (' '.join(map(str,list(range(before+1,N-after+2)))))
```
Yes
| 32,377 | [
0.19091796875,
0.0133209228515625,
0.043060302734375,
0.141845703125,
-0.254638671875,
-0.201416015625,
-0.2841796875,
0.1951904296875,
0.01462554931640625,
0.92333984375,
0.51953125,
-0.1600341796875,
0.052642822265625,
-0.89892578125,
-0.69921875,
0.06451416015625,
-0.367431640625,... | 11 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Mr.X, who the handle name is T, looked at the list which written N handle names, S_1, S_2, ..., S_N.
But he couldn't see some parts of the list. Invisible part is denoted `?`.
Please calculate all possible index of the handle name of Mr.X when you sort N+1 handle names (S_1, S_2, ..., S_N and T) in lexicographical order.
Note: If there are pair of people with same handle name, either one may come first.
Input
The input is given from standard input in the following format.
N
S_1
S_2
:
S_N
T
Output
* Calculate the possible index and print in sorted order. The output should be separated with a space. Don't print a space after last number.
* Put a line break in the end.
Constraints
* 1 ≤ N ≤ 10000
* 1 ≤ |S_i|, |T| ≤ 20 (|A| is the length of A.)
* S_i consists from lower-case alphabet and `?`.
* T consists from lower-case alphabet.
Scoring
Subtask 1 [ 130 points ]
* There are no `?`'s.
Subtask 2 [ 120 points ]
* There are no additional constraints.
Output
* Calculate the possible index and print in sorted order. The output should be separated with a space. Don't print a space after last number.
* Put a line break in the end.
Constraints
* 1 ≤ N ≤ 10000
* 1 ≤ |S_i|, |T| ≤ 20 (|A| is the length of A.)
* S_i consists from lower-case alphabet and `?`.
* T consists from lower-case alphabet.
Scoring
Subtask 1 [ 130 points ]
* There are no `?`'s.
Subtask 2 [ 120 points ]
* There are no additional constraints.
Input
The input is given from standard input in the following format.
N
S_1
S_2
:
S_N
T
Example
Input
2
tourist
petr
e
Output
1
Submitted Solution:
```
from heapq import heappush,heappop,heapify
from collections import deque,defaultdict,Counter
from itertools import permutations,combinations,groupby
import functools
import sys
import bisect
import string
import math
import time
import random
def Golf():*a,=map(int,open(0))
def I():return int(input())
def S_():return input()
def IS():return input().split()
def LS():return [i for i in input().split()]
def LI():return [int(i) for i in input().split()]
def LI_():return [int(i)-1 for i in input().split()]
def NI(n):return [int(input()) for i in range(n)]
def NI_(n):return [int(input())-1 for i in range(n)]
def StoLI():return [ord(i)-97 for i in input()]
def ItoS(n):return chr(n+97)
def LtoS(ls):return ''.join([chr(i+97) for i in ls])
def GI(V,E,Directed=False,index=0):
org_inp=[];g=[[] for i in range(n)]
for i in range(E):
inp=LI();org_inp.append(inp)
if index==0:inp[0]-=1;inp[1]-=1
if len(inp)==2:
a,b=inp;g[a].append(b)
if not Directed:g[b].append(a)
elif len(inp)==3:
a,b,c=inp;aa=(inp[0],inp[2]);bb=(inp[1],inp[2]);g[a].append(bb)
if not Directed:g[b].append(aa)
return g,org_inp
def GGI(h,w,search=None,replacement_of_found='.',mp_def={'#':1,'.':0}):
#h,w,g,sg=GGI(h,w,search=['S','G'],replacement_of_found='.',mp_def={'#':1,'.':0}) # sample usage
mp=[1]*(w+2);found={}
for i in range(h):
s=input()
for char in search:
if char in s:
found[char]=((i+1)*(w+2)+s.index(char)+1)
mp_def[char]=mp_def[replacement_of_found]
mp+=[1]+[mp_def[j] for j in s]+[1]
mp+=[1]*(w+2)
return h+2,w+2,mp,found
def TI(n):return GI(n,n-1)
def bit_combination(k,n=2):
rt=[]
for tb in range(n**k):
s=[tb//(n**bt)%n for bt in range(k)]
rt+=[s]
return rt
def show(*inp,end='\n'):
if show_flg:print(*inp,end=end)
YN=['YES','NO'];Yn=['Yes','No']
mo=10**9+7
inf=float('inf')
l_alp=string.ascii_lowercase
#sys.setrecursionlimit(10**7)
input=lambda: sys.stdin.readline().rstrip()
def ran_input():
n=random.randint(4,16)
rmin,rmax=1,10
a=[random.randint(rmin,rmax) for _ in range(n)]
return n,a
show_flg=False
show_flg=True
N=10**6+2
m=[0]*(N)
n=I()
a=[]
for i in range(n):
a+=[input()]
t=input()
L,F=0,0
for i in a:
f=''
l=''
for j in i:
if j=='?':
f+='a'
l+='z'
else:
f+=j
l+=j
#show(f,l,t,sorted([f,l,t]))
if f<=t:
F+=1
if l<t:
L+=1
print(*list(range(L+1,F+1+1)))
```
Yes
| 32,378 | [
0.1641845703125,
-0.036956787109375,
0.0304718017578125,
0.171630859375,
-0.2027587890625,
-0.19287109375,
-0.26806640625,
0.1234130859375,
0.028472900390625,
0.92333984375,
0.55078125,
-0.18701171875,
0.044464111328125,
-0.93896484375,
-0.71923828125,
0.07476806640625,
-0.3449707031... | 11 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Mr.X, who the handle name is T, looked at the list which written N handle names, S_1, S_2, ..., S_N.
But he couldn't see some parts of the list. Invisible part is denoted `?`.
Please calculate all possible index of the handle name of Mr.X when you sort N+1 handle names (S_1, S_2, ..., S_N and T) in lexicographical order.
Note: If there are pair of people with same handle name, either one may come first.
Input
The input is given from standard input in the following format.
N
S_1
S_2
:
S_N
T
Output
* Calculate the possible index and print in sorted order. The output should be separated with a space. Don't print a space after last number.
* Put a line break in the end.
Constraints
* 1 ≤ N ≤ 10000
* 1 ≤ |S_i|, |T| ≤ 20 (|A| is the length of A.)
* S_i consists from lower-case alphabet and `?`.
* T consists from lower-case alphabet.
Scoring
Subtask 1 [ 130 points ]
* There are no `?`'s.
Subtask 2 [ 120 points ]
* There are no additional constraints.
Output
* Calculate the possible index and print in sorted order. The output should be separated with a space. Don't print a space after last number.
* Put a line break in the end.
Constraints
* 1 ≤ N ≤ 10000
* 1 ≤ |S_i|, |T| ≤ 20 (|A| is the length of A.)
* S_i consists from lower-case alphabet and `?`.
* T consists from lower-case alphabet.
Scoring
Subtask 1 [ 130 points ]
* There are no `?`'s.
Subtask 2 [ 120 points ]
* There are no additional constraints.
Input
The input is given from standard input in the following format.
N
S_1
S_2
:
S_N
T
Example
Input
2
tourist
petr
e
Output
1
Submitted Solution:
```
import re
def main():
N = int(input())
i = 0
ques = 0
S = []
while i < N + 1:
s = str(input())
h = re.findall('^\?', s)
if len(h) == 0:
S.append(s)
else:
ques += 1
i += 1
T = S[-1]
i = 0
while i < len(S):
if S[i] == T:
ques += 1
i += 1
S.sort()
index = [S.index(T) + 1]
for i in range(1, ques + 1):
index.append(index[0] + i)
print(' '.join(map(str, index)))
main()
```
No
| 32,379 | [
0.210205078125,
0.0024318695068359375,
0.07635498046875,
0.09356689453125,
-0.27099609375,
-0.231201171875,
-0.265625,
0.25439453125,
-0.06304931640625,
0.83544921875,
0.57373046875,
-0.08721923828125,
0.0345458984375,
-0.890625,
-0.66796875,
0.0694580078125,
-0.426513671875,
-0.56... | 11 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Mr.X, who the handle name is T, looked at the list which written N handle names, S_1, S_2, ..., S_N.
But he couldn't see some parts of the list. Invisible part is denoted `?`.
Please calculate all possible index of the handle name of Mr.X when you sort N+1 handle names (S_1, S_2, ..., S_N and T) in lexicographical order.
Note: If there are pair of people with same handle name, either one may come first.
Input
The input is given from standard input in the following format.
N
S_1
S_2
:
S_N
T
Output
* Calculate the possible index and print in sorted order. The output should be separated with a space. Don't print a space after last number.
* Put a line break in the end.
Constraints
* 1 ≤ N ≤ 10000
* 1 ≤ |S_i|, |T| ≤ 20 (|A| is the length of A.)
* S_i consists from lower-case alphabet and `?`.
* T consists from lower-case alphabet.
Scoring
Subtask 1 [ 130 points ]
* There are no `?`'s.
Subtask 2 [ 120 points ]
* There are no additional constraints.
Output
* Calculate the possible index and print in sorted order. The output should be separated with a space. Don't print a space after last number.
* Put a line break in the end.
Constraints
* 1 ≤ N ≤ 10000
* 1 ≤ |S_i|, |T| ≤ 20 (|A| is the length of A.)
* S_i consists from lower-case alphabet and `?`.
* T consists from lower-case alphabet.
Scoring
Subtask 1 [ 130 points ]
* There are no `?`'s.
Subtask 2 [ 120 points ]
* There are no additional constraints.
Input
The input is given from standard input in the following format.
N
S_1
S_2
:
S_N
T
Example
Input
2
tourist
petr
e
Output
1
Submitted Solution:
```
from heapq import heappush,heappop,heapify
from collections import deque,defaultdict,Counter
from itertools import permutations,combinations,groupby
import functools
import sys
import bisect
import string
import math
import time
import random
def Golf():*a,=map(int,open(0))
def I():return int(input())
def S_():return input()
def IS():return input().split()
def LS():return [i for i in input().split()]
def LI():return [int(i) for i in input().split()]
def LI_():return [int(i)-1 for i in input().split()]
def NI(n):return [int(input()) for i in range(n)]
def NI_(n):return [int(input())-1 for i in range(n)]
def StoLI():return [ord(i)-97 for i in input()]
def ItoS(n):return chr(n+97)
def LtoS(ls):return ''.join([chr(i+97) for i in ls])
def GI(V,E,Directed=False,index=0):
org_inp=[];g=[[] for i in range(n)]
for i in range(E):
inp=LI();org_inp.append(inp)
if index==0:inp[0]-=1;inp[1]-=1
if len(inp)==2:
a,b=inp;g[a].append(b)
if not Directed:g[b].append(a)
elif len(inp)==3:
a,b,c=inp;aa=(inp[0],inp[2]);bb=(inp[1],inp[2]);g[a].append(bb)
if not Directed:g[b].append(aa)
return g,org_inp
def GGI(h,w,search=None,replacement_of_found='.',mp_def={'#':1,'.':0}):
#h,w,g,sg=GGI(h,w,search=['S','G'],replacement_of_found='.',mp_def={'#':1,'.':0}) # sample usage
mp=[1]*(w+2);found={}
for i in range(h):
s=input()
for char in search:
if char in s:
found[char]=((i+1)*(w+2)+s.index(char)+1)
mp_def[char]=mp_def[replacement_of_found]
mp+=[1]+[mp_def[j] for j in s]+[1]
mp+=[1]*(w+2)
return h+2,w+2,mp,found
def TI(n):return GI(n,n-1)
def bit_combination(k,n=2):
rt=[]
for tb in range(n**k):
s=[tb//(n**bt)%n for bt in range(k)]
rt+=[s]
return rt
def show(*inp,end='\n'):
if show_flg:print(*inp,end=end)
YN=['YES','NO'];Yn=['Yes','No']
mo=10**9+7
inf=float('inf')
l_alp=string.ascii_lowercase
#sys.setrecursionlimit(10**7)
input=lambda: sys.stdin.readline().rstrip()
def ran_input():
n=random.randint(4,16)
rmin,rmax=1,10
a=[random.randint(rmin,rmax) for _ in range(n)]
return n,a
show_flg=False
show_flg=True
N=10**6+2
m=[0]*(N)
n=I()
a=[]
for i in range(n):
a+=[input()]
t=input()
L,F=0,0
for i in a:
f=''
l=''
for j in i:
if j=='?':
f+='a'
l+='z'
else:
f+=j
l+=j
#show(f,l,t,sorted([f,l,t]))
if f<t:
F+=1
if l<t:
L+=1
print(*list(range(L+1,F+1+1)))
```
No
| 32,382 | [
0.1641845703125,
-0.036956787109375,
0.0304718017578125,
0.171630859375,
-0.2027587890625,
-0.19287109375,
-0.26806640625,
0.1234130859375,
0.028472900390625,
0.92333984375,
0.55078125,
-0.18701171875,
0.044464111328125,
-0.93896484375,
-0.71923828125,
0.07476806640625,
-0.3449707031... | 11 |
Provide a correct Python 3 solution for this coding contest problem.
Create a program that inputs the test result data of the visual acuity test and outputs the number of people who apply to each judgment based on the following visual acuity judgment table for each of the left and right eyesight.
Judgment | Sight
--- | ---
A | 1.1 or above
B | 0.6 or more and less than 1.1
C | 0.2 or more and less than 0.6
D | less than 0.2
Input
The input is given in the following format:
l1 r1
l2 r2
l3 r3
::
::
On line i, the real number li, which represents the left visual acuity of the i-th person, and the real number ri, which represents the right visual acuity, are given, separated by blanks. However, visual acuity is 0.1 or more and 2.0 or less, and is given in 0.1 increments.
The number of lines of input does not exceed 40.
Output
Please output the judgment table in the following format.
Line 1 Left eyesight is the number of people A Right eyesight is the number of people (separated by blanks)
2nd line The number of people whose left eyesight is B The number of people whose right eyesight is B (separated by blanks)
3rd line The number of people whose left eyesight is C
4th line Number of people with left eyesight D Number of people with right eyesight D (separated by blanks)
Example
Input
1.0 1.2
0.8 1.5
1.2 0.7
2.0 2.0
Output
2 3
2 1
0 0
0 0
"Correct Solution:
```
Res = [[0,0,0,0],[0,0,0,0]]
while True:
try:
l,r = map(float,input().split())
if l < 0.2:
Res[0][3] += 1
elif l < 0.6:
Res[0][2] += 1
elif l < 1.1:
Res[0][1] += 1
else:
Res[0][0] += 1
if r < 0.2:
Res[1][3] += 1
elif r < 0.6:
Res[1][2] += 1
elif r < 1.1:
Res[1][1] += 1
else:
Res[1][0] += 1
except:
for i in range(4):
ans = str(Res[0][i]) + " " + str(Res[1][i])
print(ans)
break
```
| 32,402 | [
0.310546875,
-0.08953857421875,
0.0031909942626953125,
0.2978515625,
-1.228515625,
-0.54150390625,
0.08563232421875,
0.2362060546875,
0.1058349609375,
0.69775390625,
0.1883544921875,
-0.5224609375,
0.387939453125,
-0.36279296875,
-0.156005859375,
-0.125,
-0.7548828125,
-0.483154296... | 11 |
Provide a correct Python 3 solution for this coding contest problem.
Create a program that inputs the test result data of the visual acuity test and outputs the number of people who apply to each judgment based on the following visual acuity judgment table for each of the left and right eyesight.
Judgment | Sight
--- | ---
A | 1.1 or above
B | 0.6 or more and less than 1.1
C | 0.2 or more and less than 0.6
D | less than 0.2
Input
The input is given in the following format:
l1 r1
l2 r2
l3 r3
::
::
On line i, the real number li, which represents the left visual acuity of the i-th person, and the real number ri, which represents the right visual acuity, are given, separated by blanks. However, visual acuity is 0.1 or more and 2.0 or less, and is given in 0.1 increments.
The number of lines of input does not exceed 40.
Output
Please output the judgment table in the following format.
Line 1 Left eyesight is the number of people A Right eyesight is the number of people (separated by blanks)
2nd line The number of people whose left eyesight is B The number of people whose right eyesight is B (separated by blanks)
3rd line The number of people whose left eyesight is C
4th line Number of people with left eyesight D Number of people with right eyesight D (separated by blanks)
Example
Input
1.0 1.2
0.8 1.5
1.2 0.7
2.0 2.0
Output
2 3
2 1
0 0
0 0
"Correct Solution:
```
def get_input():
while True:
try:
yield ''.join(input())
except EOFError:
break
def check(n):
if n >= 11:
return 0
elif n >= 6:
return 1
elif n >= 2:
return 2
else:
return 3
N = list(get_input())
cntL = [0,0,0,0]
cntR = [0,0,0,0]
for lll in range(len(N)):
l,r = [int(float(i)*10) for i in N[lll].split()]
cntL[check(l)] += 1
cntR[check(r)] += 1
for i in range(4):
print(cntL[i],cntR[i])
```
| 32,403 | [
0.31982421875,
-0.173095703125,
0.007350921630859375,
0.2191162109375,
-1.2490234375,
-0.50341796875,
0.13330078125,
0.20361328125,
0.15185546875,
0.68115234375,
0.178955078125,
-0.51953125,
0.323974609375,
-0.5009765625,
-0.160400390625,
-0.12310791015625,
-0.76708984375,
-0.57666... | 11 |
Provide a correct Python 3 solution for this coding contest problem.
Create a program that inputs the test result data of the visual acuity test and outputs the number of people who apply to each judgment based on the following visual acuity judgment table for each of the left and right eyesight.
Judgment | Sight
--- | ---
A | 1.1 or above
B | 0.6 or more and less than 1.1
C | 0.2 or more and less than 0.6
D | less than 0.2
Input
The input is given in the following format:
l1 r1
l2 r2
l3 r3
::
::
On line i, the real number li, which represents the left visual acuity of the i-th person, and the real number ri, which represents the right visual acuity, are given, separated by blanks. However, visual acuity is 0.1 or more and 2.0 or less, and is given in 0.1 increments.
The number of lines of input does not exceed 40.
Output
Please output the judgment table in the following format.
Line 1 Left eyesight is the number of people A Right eyesight is the number of people (separated by blanks)
2nd line The number of people whose left eyesight is B The number of people whose right eyesight is B (separated by blanks)
3rd line The number of people whose left eyesight is C
4th line Number of people with left eyesight D Number of people with right eyesight D (separated by blanks)
Example
Input
1.0 1.2
0.8 1.5
1.2 0.7
2.0 2.0
Output
2 3
2 1
0 0
0 0
"Correct Solution:
```
from collections import Counter
def check(f):
if f >= 1.1:
return "A"
elif f >= 0.6:
return "B"
elif f >= 0.2:
return "C"
else:
return "D"
dicl = Counter()
dicr = Counter()
while True:
try:
l, r = map(float, input().split())
lx, rx = check(l), check(r)
dicl[lx] += 1
dicr[rx] += 1
except EOFError:
break
for alpha in ("A", "B", "C", "D"):
print(dicl[alpha], dicr[alpha])
```
| 32,404 | [
0.29638671875,
-0.1632080078125,
0.045562744140625,
0.23779296875,
-1.2841796875,
-0.50439453125,
0.10833740234375,
0.1533203125,
0.1785888671875,
0.740234375,
0.177490234375,
-0.583984375,
0.423583984375,
-0.43359375,
-0.132568359375,
-0.167236328125,
-0.84814453125,
-0.5766601562... | 11 |
Provide a correct Python 3 solution for this coding contest problem.
Create a program that inputs the test result data of the visual acuity test and outputs the number of people who apply to each judgment based on the following visual acuity judgment table for each of the left and right eyesight.
Judgment | Sight
--- | ---
A | 1.1 or above
B | 0.6 or more and less than 1.1
C | 0.2 or more and less than 0.6
D | less than 0.2
Input
The input is given in the following format:
l1 r1
l2 r2
l3 r3
::
::
On line i, the real number li, which represents the left visual acuity of the i-th person, and the real number ri, which represents the right visual acuity, are given, separated by blanks. However, visual acuity is 0.1 or more and 2.0 or less, and is given in 0.1 increments.
The number of lines of input does not exceed 40.
Output
Please output the judgment table in the following format.
Line 1 Left eyesight is the number of people A Right eyesight is the number of people (separated by blanks)
2nd line The number of people whose left eyesight is B The number of people whose right eyesight is B (separated by blanks)
3rd line The number of people whose left eyesight is C
4th line Number of people with left eyesight D Number of people with right eyesight D (separated by blanks)
Example
Input
1.0 1.2
0.8 1.5
1.2 0.7
2.0 2.0
Output
2 3
2 1
0 0
0 0
"Correct Solution:
```
# -*- coding: utf-8 -*-
"""
http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=0149
"""
import sys
from sys import stdin
from collections import defaultdict
input = stdin.readline
def process_data(result, rank):
if result >= 1.1:
rank['A'] += 1
elif result >= 0.6:
rank['B'] += 1
elif result >= 0.2:
rank['C'] += 1
else:
rank['D'] += 1
def main(args):
left_rank = defaultdict(int)
right_rank = defaultdict(int)
for line in sys.stdin:
l, r = map(float, line.split())
process_data(l, left_rank)
process_data(r, right_rank)
print('{} {}'.format(left_rank['A'], right_rank['A']))
print('{} {}'.format(left_rank['B'], right_rank['B']))
print('{} {}'.format(left_rank['C'], right_rank['C']))
print('{} {}'.format(left_rank['D'], right_rank['D']))
if __name__ == '__main__':
main(sys.argv[1:])
```
| 32,405 | [
0.320068359375,
-0.157958984375,
0.0272979736328125,
0.1854248046875,
-1.2919921875,
-0.467529296875,
0.053924560546875,
0.189208984375,
0.08209228515625,
0.658203125,
0.070068359375,
-0.5888671875,
0.322021484375,
-0.390380859375,
-0.2042236328125,
-0.172607421875,
-0.74609375,
-0... | 11 |
Provide a correct Python 3 solution for this coding contest problem.
Create a program that inputs the test result data of the visual acuity test and outputs the number of people who apply to each judgment based on the following visual acuity judgment table for each of the left and right eyesight.
Judgment | Sight
--- | ---
A | 1.1 or above
B | 0.6 or more and less than 1.1
C | 0.2 or more and less than 0.6
D | less than 0.2
Input
The input is given in the following format:
l1 r1
l2 r2
l3 r3
::
::
On line i, the real number li, which represents the left visual acuity of the i-th person, and the real number ri, which represents the right visual acuity, are given, separated by blanks. However, visual acuity is 0.1 or more and 2.0 or less, and is given in 0.1 increments.
The number of lines of input does not exceed 40.
Output
Please output the judgment table in the following format.
Line 1 Left eyesight is the number of people A Right eyesight is the number of people (separated by blanks)
2nd line The number of people whose left eyesight is B The number of people whose right eyesight is B (separated by blanks)
3rd line The number of people whose left eyesight is C
4th line Number of people with left eyesight D Number of people with right eyesight D (separated by blanks)
Example
Input
1.0 1.2
0.8 1.5
1.2 0.7
2.0 2.0
Output
2 3
2 1
0 0
0 0
"Correct Solution:
```
# Aizu Problem 00149: Eye Test
#
import sys, math, os, copy
# read input:
PYDEV = os.environ.get('PYDEV')
if PYDEV=="True":
sys.stdin = open("sample-input.txt", "rt")
def get_judgement(x):
if x >= 1.1:
return "A"
elif x >= .6:
return "B"
elif x >= .2:
return "C"
else:
return "D"
count = {char: {"left": 0, "right": 0} for char in ['A', 'B', 'C', 'D']}
for line in sys.stdin:
left, right = [float(_) for _ in line.split()]
count[get_judgement(left)]["left"] += 1
count[get_judgement(right)]["right"] += 1
for char in ['A', 'B', 'C', 'D']:
print(count[char]["left"], count[char]["right"])
```
| 32,406 | [
0.286865234375,
-0.1455078125,
0.0655517578125,
0.2958984375,
-1.345703125,
-0.46728515625,
0.124755859375,
0.1884765625,
0.126953125,
0.81201171875,
0.1519775390625,
-0.61083984375,
0.30908203125,
-0.282470703125,
-0.3095703125,
-0.1141357421875,
-0.67724609375,
-0.494873046875,
... | 11 |
Provide a correct Python 3 solution for this coding contest problem.
Create a program that inputs the test result data of the visual acuity test and outputs the number of people who apply to each judgment based on the following visual acuity judgment table for each of the left and right eyesight.
Judgment | Sight
--- | ---
A | 1.1 or above
B | 0.6 or more and less than 1.1
C | 0.2 or more and less than 0.6
D | less than 0.2
Input
The input is given in the following format:
l1 r1
l2 r2
l3 r3
::
::
On line i, the real number li, which represents the left visual acuity of the i-th person, and the real number ri, which represents the right visual acuity, are given, separated by blanks. However, visual acuity is 0.1 or more and 2.0 or less, and is given in 0.1 increments.
The number of lines of input does not exceed 40.
Output
Please output the judgment table in the following format.
Line 1 Left eyesight is the number of people A Right eyesight is the number of people (separated by blanks)
2nd line The number of people whose left eyesight is B The number of people whose right eyesight is B (separated by blanks)
3rd line The number of people whose left eyesight is C
4th line Number of people with left eyesight D Number of people with right eyesight D (separated by blanks)
Example
Input
1.0 1.2
0.8 1.5
1.2 0.7
2.0 2.0
Output
2 3
2 1
0 0
0 0
"Correct Solution:
```
eyes = [[0 for i in range(2)] for j in range(4)]
while True:
try:
a = list(map(float, input().split()))
except:
break
for i in range(2):
if a[i] >= 1.1: eyes[0][i]+=1
elif a[i] >= 0.6: eyes[1][i]+=1
elif a[i] >= 0.2: eyes[2][i]+=1
else: eyes[3][i]+=1
for i in range(4):
print(*eyes[i])
```
| 32,407 | [
0.307861328125,
-0.0992431640625,
0.044525146484375,
0.248779296875,
-1.244140625,
-0.51220703125,
0.11505126953125,
0.165283203125,
0.0987548828125,
0.6953125,
0.182373046875,
-0.53955078125,
0.350830078125,
-0.417724609375,
-0.1385498046875,
-0.1627197265625,
-0.7607421875,
-0.50... | 11 |
Provide a correct Python 3 solution for this coding contest problem.
Create a program that inputs the test result data of the visual acuity test and outputs the number of people who apply to each judgment based on the following visual acuity judgment table for each of the left and right eyesight.
Judgment | Sight
--- | ---
A | 1.1 or above
B | 0.6 or more and less than 1.1
C | 0.2 or more and less than 0.6
D | less than 0.2
Input
The input is given in the following format:
l1 r1
l2 r2
l3 r3
::
::
On line i, the real number li, which represents the left visual acuity of the i-th person, and the real number ri, which represents the right visual acuity, are given, separated by blanks. However, visual acuity is 0.1 or more and 2.0 or less, and is given in 0.1 increments.
The number of lines of input does not exceed 40.
Output
Please output the judgment table in the following format.
Line 1 Left eyesight is the number of people A Right eyesight is the number of people (separated by blanks)
2nd line The number of people whose left eyesight is B The number of people whose right eyesight is B (separated by blanks)
3rd line The number of people whose left eyesight is C
4th line Number of people with left eyesight D Number of people with right eyesight D (separated by blanks)
Example
Input
1.0 1.2
0.8 1.5
1.2 0.7
2.0 2.0
Output
2 3
2 1
0 0
0 0
"Correct Solution:
```
tbl = [[0 for j in range(4)] for i in range(2)]
while True:
try: p = list(map(float, input().split()))
except: break
for i in range(2):
if p[i] >= 1.1: tbl[i][0] += 1
elif p[i] >= 0.6: tbl[i][1] += 1
elif p[i] >= 0.2: tbl[i][2] += 1
else: tbl[i][3] += 1
for i in range(4):
print(tbl[0][i], tbl[1][i])
```
| 32,408 | [
0.322265625,
-0.135498046875,
0.067138671875,
0.251220703125,
-1.2587890625,
-0.52734375,
0.09222412109375,
0.178955078125,
0.1326904296875,
0.71142578125,
0.191650390625,
-0.54736328125,
0.375244140625,
-0.404052734375,
-0.1461181640625,
-0.135986328125,
-0.77099609375,
-0.4975585... | 11 |
Provide a correct Python 3 solution for this coding contest problem.
Create a program that inputs the test result data of the visual acuity test and outputs the number of people who apply to each judgment based on the following visual acuity judgment table for each of the left and right eyesight.
Judgment | Sight
--- | ---
A | 1.1 or above
B | 0.6 or more and less than 1.1
C | 0.2 or more and less than 0.6
D | less than 0.2
Input
The input is given in the following format:
l1 r1
l2 r2
l3 r3
::
::
On line i, the real number li, which represents the left visual acuity of the i-th person, and the real number ri, which represents the right visual acuity, are given, separated by blanks. However, visual acuity is 0.1 or more and 2.0 or less, and is given in 0.1 increments.
The number of lines of input does not exceed 40.
Output
Please output the judgment table in the following format.
Line 1 Left eyesight is the number of people A Right eyesight is the number of people (separated by blanks)
2nd line The number of people whose left eyesight is B The number of people whose right eyesight is B (separated by blanks)
3rd line The number of people whose left eyesight is C
4th line Number of people with left eyesight D Number of people with right eyesight D (separated by blanks)
Example
Input
1.0 1.2
0.8 1.5
1.2 0.7
2.0 2.0
Output
2 3
2 1
0 0
0 0
"Correct Solution:
```
def f(a):
if a>1.0:return 0
elif a>0.5:return 1
elif a>0.1:return 2
else:return 3
b=[0]*8
while 1:
try:l,r=map(float,input().split())
except:break
b[f(l)]+=1
b[4+f(r)]+=1
for i in range(4):print(b[i],b[4+i])
```
| 32,409 | [
0.31298828125,
-0.10528564453125,
0.0125885009765625,
0.295166015625,
-1.302734375,
-0.48828125,
0.1290283203125,
0.218994140625,
0.08099365234375,
0.70654296875,
0.19677734375,
-0.51806640625,
0.36083984375,
-0.443115234375,
-0.132080078125,
-0.10186767578125,
-0.765625,
-0.564941... | 11 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Create a program that inputs the test result data of the visual acuity test and outputs the number of people who apply to each judgment based on the following visual acuity judgment table for each of the left and right eyesight.
Judgment | Sight
--- | ---
A | 1.1 or above
B | 0.6 or more and less than 1.1
C | 0.2 or more and less than 0.6
D | less than 0.2
Input
The input is given in the following format:
l1 r1
l2 r2
l3 r3
::
::
On line i, the real number li, which represents the left visual acuity of the i-th person, and the real number ri, which represents the right visual acuity, are given, separated by blanks. However, visual acuity is 0.1 or more and 2.0 or less, and is given in 0.1 increments.
The number of lines of input does not exceed 40.
Output
Please output the judgment table in the following format.
Line 1 Left eyesight is the number of people A Right eyesight is the number of people (separated by blanks)
2nd line The number of people whose left eyesight is B The number of people whose right eyesight is B (separated by blanks)
3rd line The number of people whose left eyesight is C
4th line Number of people with left eyesight D Number of people with right eyesight D (separated by blanks)
Example
Input
1.0 1.2
0.8 1.5
1.2 0.7
2.0 2.0
Output
2 3
2 1
0 0
0 0
Submitted Solution:
```
import sys
LA = RA = 0
LB = RB = 0
LC = RC = 0
LD = RD = 0
for i in sys.stdin:
l,r = map(float,i.split())
if l >= 1.1:
LA += 1
elif 0.6 <= l <1.1:
LB += 1
elif 0.2 <= l < 0.6:
LC += 1
else:
LD += 1
if r >= 1.1:
RA += 1
elif 0.6 <= r <1.1:
RB += 1
elif 0.2 <= r < 0.6:
RC += 1
else:
RD += 1
print(LA,RA)
print(LB,RB)
print(LC,RC)
print(LD,RD)
```
Yes
| 32,410 | [
0.293701171875,
-0.143798828125,
-0.0462646484375,
0.352294921875,
-1.2666015625,
-0.484130859375,
0.01465606689453125,
0.350341796875,
0.1414794921875,
0.7060546875,
0.198974609375,
-0.51904296875,
0.337158203125,
-0.310791015625,
-0.161376953125,
-0.0072479248046875,
-0.67822265625... | 11 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Create a program that inputs the test result data of the visual acuity test and outputs the number of people who apply to each judgment based on the following visual acuity judgment table for each of the left and right eyesight.
Judgment | Sight
--- | ---
A | 1.1 or above
B | 0.6 or more and less than 1.1
C | 0.2 or more and less than 0.6
D | less than 0.2
Input
The input is given in the following format:
l1 r1
l2 r2
l3 r3
::
::
On line i, the real number li, which represents the left visual acuity of the i-th person, and the real number ri, which represents the right visual acuity, are given, separated by blanks. However, visual acuity is 0.1 or more and 2.0 or less, and is given in 0.1 increments.
The number of lines of input does not exceed 40.
Output
Please output the judgment table in the following format.
Line 1 Left eyesight is the number of people A Right eyesight is the number of people (separated by blanks)
2nd line The number of people whose left eyesight is B The number of people whose right eyesight is B (separated by blanks)
3rd line The number of people whose left eyesight is C
4th line Number of people with left eyesight D Number of people with right eyesight D (separated by blanks)
Example
Input
1.0 1.2
0.8 1.5
1.2 0.7
2.0 2.0
Output
2 3
2 1
0 0
0 0
Submitted Solution:
```
al,ar,bl,br,cl,cr,dl,dr=0,0,0,0,0,0,0,0
while True:
try:
le,re=map(float,input().split())
if le<0.2:
dl+=1
if le>= 0.2 and le<0.6:
cl += 1
if le >= 0.6 and le<1.1:
bl += 1
if le >= 1.1:
al += 1
if re<0.2:
dr+=1
if re>= 0.2 and re<0.6:
cr += 1
if re >= 0.6 and re<1.1:
br+= 1
if re >= 1.1:
ar += 1
except:
print(al,ar)
print(bl,br)
print(cl,cr)
print(dl,dr)
break
```
Yes
| 32,411 | [
0.27001953125,
-0.11419677734375,
-0.05926513671875,
0.399169921875,
-1.251953125,
-0.4873046875,
0.035980224609375,
0.41845703125,
0.154541015625,
0.71875,
0.247314453125,
-0.50390625,
0.38037109375,
-0.31884765625,
-0.16162109375,
-0.0117950439453125,
-0.63623046875,
-0.613769531... | 11 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Create a program that inputs the test result data of the visual acuity test and outputs the number of people who apply to each judgment based on the following visual acuity judgment table for each of the left and right eyesight.
Judgment | Sight
--- | ---
A | 1.1 or above
B | 0.6 or more and less than 1.1
C | 0.2 or more and less than 0.6
D | less than 0.2
Input
The input is given in the following format:
l1 r1
l2 r2
l3 r3
::
::
On line i, the real number li, which represents the left visual acuity of the i-th person, and the real number ri, which represents the right visual acuity, are given, separated by blanks. However, visual acuity is 0.1 or more and 2.0 or less, and is given in 0.1 increments.
The number of lines of input does not exceed 40.
Output
Please output the judgment table in the following format.
Line 1 Left eyesight is the number of people A Right eyesight is the number of people (separated by blanks)
2nd line The number of people whose left eyesight is B The number of people whose right eyesight is B (separated by blanks)
3rd line The number of people whose left eyesight is C
4th line Number of people with left eyesight D Number of people with right eyesight D (separated by blanks)
Example
Input
1.0 1.2
0.8 1.5
1.2 0.7
2.0 2.0
Output
2 3
2 1
0 0
0 0
Submitted Solution:
```
lr = [0 for i in range(8)]
while True:
try:
a,b = map(float,input().split())
except:
break
if a >= 1.1:
lr[0] += 1
elif a >= 0.6:
lr[2] += 1
elif a >= 0.2:
lr[4] += 1
else:
lr[6] += 1
if b >= 1.1:
lr[1] += 1
elif b >= 0.6:
lr[3] += 1
elif b >= 0.2:
lr[5] += 1
else:
lr[7] += 1
print(lr[0],lr[1])
print(lr[2],lr[3])
print(lr[4],lr[5])
print(lr[6],lr[7])
```
Yes
| 32,412 | [
0.295166015625,
-0.1590576171875,
-0.06597900390625,
0.3515625,
-1.251953125,
-0.52880859375,
0.0531005859375,
0.36181640625,
0.130859375,
0.69677734375,
0.2081298828125,
-0.497314453125,
0.314453125,
-0.28369140625,
-0.1300048828125,
-0.0523681640625,
-0.70703125,
-0.548828125,
... | 11 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Create a program that inputs the test result data of the visual acuity test and outputs the number of people who apply to each judgment based on the following visual acuity judgment table for each of the left and right eyesight.
Judgment | Sight
--- | ---
A | 1.1 or above
B | 0.6 or more and less than 1.1
C | 0.2 or more and less than 0.6
D | less than 0.2
Input
The input is given in the following format:
l1 r1
l2 r2
l3 r3
::
::
On line i, the real number li, which represents the left visual acuity of the i-th person, and the real number ri, which represents the right visual acuity, are given, separated by blanks. However, visual acuity is 0.1 or more and 2.0 or less, and is given in 0.1 increments.
The number of lines of input does not exceed 40.
Output
Please output the judgment table in the following format.
Line 1 Left eyesight is the number of people A Right eyesight is the number of people (separated by blanks)
2nd line The number of people whose left eyesight is B The number of people whose right eyesight is B (separated by blanks)
3rd line The number of people whose left eyesight is C
4th line Number of people with left eyesight D Number of people with right eyesight D (separated by blanks)
Example
Input
1.0 1.2
0.8 1.5
1.2 0.7
2.0 2.0
Output
2 3
2 1
0 0
0 0
Submitted Solution:
```
import sys
BASE = [1.1, 0.6, 0.2, 0.0]
COUNT = len(BASE)
def eye_test(num):
for index, parameter in enumerate(BASE):
if parameter <= num:
return index
left_counter = [0] * COUNT
right_counter = [0] * COUNT
for line in sys.stdin:
left, right = [float(item) for item in line[:-1].split(" ")]
left_eye, right_eye = eye_test(left), eye_test(right)
left_counter[left_eye] += 1
right_counter[right_eye] += 1
for item1, item2 in zip(left_counter, right_counter):
print(item1, item2)
```
Yes
| 32,413 | [
0.2978515625,
-0.186279296875,
-0.036224365234375,
0.3544921875,
-1.255859375,
-0.477294921875,
-0.003345489501953125,
0.313720703125,
0.1414794921875,
0.666015625,
0.16748046875,
-0.556640625,
0.361328125,
-0.296875,
-0.1363525390625,
-0.048553466796875,
-0.65478515625,
-0.5561523... | 11 |
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