message stringlengths 2 39.6k | message_type stringclasses 2 values | message_id int64 0 1 | conversation_id int64 219 108k | cluster float64 11 11 | __index_level_0__ int64 438 217k |
|---|---|---|---|---|---|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
n students are taking an exam. The highest possible score at this exam is m. Let a_{i} be the score of the i-th student. You have access to the school database which stores the results of all students.
You can change each student's score as long as the following conditions are satisfied:
* All scores are integers
* 0 ≤ a_{i} ≤ m
* The average score of the class doesn't change.
You are student 1 and you would like to maximize your own score.
Find the highest possible score you can assign to yourself such that all conditions are satisfied.
Input
Each test contains multiple test cases.
The first line contains the number of test cases t (1 ≤ t ≤ 200). The description of the test cases follows.
The first line of each test case contains two integers n and m (1 ≤ n ≤ 10^{3}, 1 ≤ m ≤ 10^{5}) — the number of students and the highest possible score respectively.
The second line of each testcase contains n integers a_1, a_2, ..., a_n ( 0 ≤ a_{i} ≤ m) — scores of the students.
Output
For each testcase, output one integer — the highest possible score you can assign to yourself such that both conditions are satisfied._
Example
Input
2
4 10
1 2 3 4
4 5
1 2 3 4
Output
10
5
Note
In the first case, a = [1,2,3,4] , with average of 2.5. You can change array a to [10,0,0,0]. Average remains 2.5, and all conditions are satisfied.
In the second case, 0 ≤ a_{i} ≤ 5. You can change a to [5,1,1,3]. You cannot increase a_{1} further as it will violate condition 0≤ a_i≤ m.
Submitted Solution:
```
"""
https://codeforces.com/problemset/problem/1316/A
"""
t = int(input())
for _ in range(t):
args = [int(x) for x in input().split(" ")]
n = args[0]
m = args[1]
a = [int(x) for x in input().split(" ")]
if sum(a) >= m:
print(m)
else:
print(sum(a))
``` | instruction | 0 | 21,324 | 11 | 42,648 |
Yes | output | 1 | 21,324 | 11 | 42,649 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
n students are taking an exam. The highest possible score at this exam is m. Let a_{i} be the score of the i-th student. You have access to the school database which stores the results of all students.
You can change each student's score as long as the following conditions are satisfied:
* All scores are integers
* 0 ≤ a_{i} ≤ m
* The average score of the class doesn't change.
You are student 1 and you would like to maximize your own score.
Find the highest possible score you can assign to yourself such that all conditions are satisfied.
Input
Each test contains multiple test cases.
The first line contains the number of test cases t (1 ≤ t ≤ 200). The description of the test cases follows.
The first line of each test case contains two integers n and m (1 ≤ n ≤ 10^{3}, 1 ≤ m ≤ 10^{5}) — the number of students and the highest possible score respectively.
The second line of each testcase contains n integers a_1, a_2, ..., a_n ( 0 ≤ a_{i} ≤ m) — scores of the students.
Output
For each testcase, output one integer — the highest possible score you can assign to yourself such that both conditions are satisfied._
Example
Input
2
4 10
1 2 3 4
4 5
1 2 3 4
Output
10
5
Note
In the first case, a = [1,2,3,4] , with average of 2.5. You can change array a to [10,0,0,0]. Average remains 2.5, and all conditions are satisfied.
In the second case, 0 ≤ a_{i} ≤ 5. You can change a to [5,1,1,3]. You cannot increase a_{1} further as it will violate condition 0≤ a_i≤ m.
Submitted Solution:
```
#!/usr/bin/env python3
# -*- coding: utf-8 -*-
"""
Created on Wed Mar 4 21:06:12 2020
@author: icy
"""
for _ in range(int(input())):
ignore_this_var,max_marks=[int(h) for h in input().split(' ')]
array_of_marks=[int(h) for h in input().split(' ')]
sum_of_marks = sum(array_of_marks)
ans = 0
if(sum_of_marks < max_marks):
ans = sum_of_marks
else:
ans = max_marks
print(ans)
``` | instruction | 0 | 21,325 | 11 | 42,650 |
Yes | output | 1 | 21,325 | 11 | 42,651 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
n students are taking an exam. The highest possible score at this exam is m. Let a_{i} be the score of the i-th student. You have access to the school database which stores the results of all students.
You can change each student's score as long as the following conditions are satisfied:
* All scores are integers
* 0 ≤ a_{i} ≤ m
* The average score of the class doesn't change.
You are student 1 and you would like to maximize your own score.
Find the highest possible score you can assign to yourself such that all conditions are satisfied.
Input
Each test contains multiple test cases.
The first line contains the number of test cases t (1 ≤ t ≤ 200). The description of the test cases follows.
The first line of each test case contains two integers n and m (1 ≤ n ≤ 10^{3}, 1 ≤ m ≤ 10^{5}) — the number of students and the highest possible score respectively.
The second line of each testcase contains n integers a_1, a_2, ..., a_n ( 0 ≤ a_{i} ≤ m) — scores of the students.
Output
For each testcase, output one integer — the highest possible score you can assign to yourself such that both conditions are satisfied._
Example
Input
2
4 10
1 2 3 4
4 5
1 2 3 4
Output
10
5
Note
In the first case, a = [1,2,3,4] , with average of 2.5. You can change array a to [10,0,0,0]. Average remains 2.5, and all conditions are satisfied.
In the second case, 0 ≤ a_{i} ≤ 5. You can change a to [5,1,1,3]. You cannot increase a_{1} further as it will violate condition 0≤ a_i≤ m.
Submitted Solution:
```
t = int(input())
for _ in range(t):
n,m = map(int, input().split())
ali = list(map(int, input().split()))
q = sum(ali[1:])
# print(q)
f = 0
for i in range(n):
w = int(ali[i])
if(ali[i] != w or ali[i]>m):
f = 1
break
if(n==1):
print(ali[0])
elif(f==0):
if(q+ali[0] > m):
print(max(q,ali[0]))
else:
print(q+ali[0])
else:
print(ali[0])
``` | instruction | 0 | 21,326 | 11 | 42,652 |
No | output | 1 | 21,326 | 11 | 42,653 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
n students are taking an exam. The highest possible score at this exam is m. Let a_{i} be the score of the i-th student. You have access to the school database which stores the results of all students.
You can change each student's score as long as the following conditions are satisfied:
* All scores are integers
* 0 ≤ a_{i} ≤ m
* The average score of the class doesn't change.
You are student 1 and you would like to maximize your own score.
Find the highest possible score you can assign to yourself such that all conditions are satisfied.
Input
Each test contains multiple test cases.
The first line contains the number of test cases t (1 ≤ t ≤ 200). The description of the test cases follows.
The first line of each test case contains two integers n and m (1 ≤ n ≤ 10^{3}, 1 ≤ m ≤ 10^{5}) — the number of students and the highest possible score respectively.
The second line of each testcase contains n integers a_1, a_2, ..., a_n ( 0 ≤ a_{i} ≤ m) — scores of the students.
Output
For each testcase, output one integer — the highest possible score you can assign to yourself such that both conditions are satisfied._
Example
Input
2
4 10
1 2 3 4
4 5
1 2 3 4
Output
10
5
Note
In the first case, a = [1,2,3,4] , with average of 2.5. You can change array a to [10,0,0,0]. Average remains 2.5, and all conditions are satisfied.
In the second case, 0 ≤ a_{i} ≤ 5. You can change a to [5,1,1,3]. You cannot increase a_{1} further as it will violate condition 0≤ a_i≤ m.
Submitted Solution:
```
test_case=int(input())
for i in range(test_case):
n,m=map(int,input().split())
a=sum(list(map(int,input().split())))
avg=a/n
mul=avg*n
if m>mul:
print(mul)
else:
print(m)
``` | instruction | 0 | 21,327 | 11 | 42,654 |
No | output | 1 | 21,327 | 11 | 42,655 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
n students are taking an exam. The highest possible score at this exam is m. Let a_{i} be the score of the i-th student. You have access to the school database which stores the results of all students.
You can change each student's score as long as the following conditions are satisfied:
* All scores are integers
* 0 ≤ a_{i} ≤ m
* The average score of the class doesn't change.
You are student 1 and you would like to maximize your own score.
Find the highest possible score you can assign to yourself such that all conditions are satisfied.
Input
Each test contains multiple test cases.
The first line contains the number of test cases t (1 ≤ t ≤ 200). The description of the test cases follows.
The first line of each test case contains two integers n and m (1 ≤ n ≤ 10^{3}, 1 ≤ m ≤ 10^{5}) — the number of students and the highest possible score respectively.
The second line of each testcase contains n integers a_1, a_2, ..., a_n ( 0 ≤ a_{i} ≤ m) — scores of the students.
Output
For each testcase, output one integer — the highest possible score you can assign to yourself such that both conditions are satisfied._
Example
Input
2
4 10
1 2 3 4
4 5
1 2 3 4
Output
10
5
Note
In the first case, a = [1,2,3,4] , with average of 2.5. You can change array a to [10,0,0,0]. Average remains 2.5, and all conditions are satisfied.
In the second case, 0 ≤ a_{i} ≤ 5. You can change a to [5,1,1,3]. You cannot increase a_{1} further as it will violate condition 0≤ a_i≤ m.
Submitted Solution:
```
t=int(input())
for _ in range(t):
n,m=map(int,input().split(' '))
arr = list(map(int, input().split()))
average=sum(arr)/len(arr)
if(average==0):
print(0)
elif(m in arr):
print(m)
elif(sum(arr)<m):
print(max(arr))
else:
print(m)
``` | instruction | 0 | 21,329 | 11 | 42,658 |
No | output | 1 | 21,329 | 11 | 42,659 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
qd ucyhf yi q fhycu dkcruh mxeiu huluhiu yi q tyvvuhudj fhycu dkcruh. oekh jqia yi je vydt jxu djx ucyhf.
Input
jxu ydfkj sediyiji ev q iydwbu ydjuwuh d (1 ≤ d ≤ 11184) — jxu edu-rqiut ydtun ev jxu ucyhf je vydt.
Output
ekjfkj q iydwbu dkcruh.
Examples
Input
1
Output
13
Submitted Solution:
```
from sys import stdout
from sys import stdin
def get():
return stdin.readline().strip()
def getf(sp = " "):
return [int(i) for i in get().split(sp)]
def put(a, end = "\n"):
stdout.write(str(a) + end)
def putf(a, sep = " ", end = "\n"):
stdout.write(sep.join([str(i) for i in a]) + end)
#from collections import defaultdict as dd, deque
#from random import randint, shuffle, sample
#from functools import cmp_to_key, reduce
#from math import factorial as fac, acos, asin, atan2, gcd, log, e
#from bisect import bisect_right as br, bisect_left as bl, insort
def prime(n):
i = 2
while(i * i <= n):
if(n % i == 0):
return False
i += 1
return True
def rev(n):
ans = 0
while(n > 0):
ans = ans * 10 + n % 10
n //= 10
return ans
def main():
p = [True] * (10 ** 6 + 1)
p[1] = False
pr = []
i = 2
while(i * i <= 10 ** 6):
if(p[i] == True):
j = i * 2
while(j <= 10 ** 6):
p[j] = False
j += i
i += 1
for i in range(13, 10 ** 6 + 1):
if(p[i] == True):
pr += [i]
n = int(get())
i = -1
ans = 13
while(n > 0):
i += 1
r = rev(pr[i])
if(r == pr[i]):
continue
if(r <= 10 ** 6):
if(p[r] == True):
ans = pr[i]
n -= 1
else:
if(prime(t) == True):
ans = pr[i]
n -= 1
put(ans)
main()
``` | instruction | 0 | 21,471 | 11 | 42,942 |
Yes | output | 1 | 21,471 | 11 | 42,943 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
qd ucyhf yi q fhycu dkcruh mxeiu huluhiu yi q tyvvuhudj fhycu dkcruh. oekh jqia yi je vydt jxu djx ucyhf.
Input
jxu ydfkj sediyiji ev q iydwbu ydjuwuh d (1 ≤ d ≤ 11184) — jxu edu-rqiut ydtun ev jxu ucyhf je vydt.
Output
ekjfkj q iydwbu dkcruh.
Examples
Input
1
Output
13
Submitted Solution:
```
def prime( x ):
if x == 2: return 1
if ~ x & 1: return 0
i = 3
while i * i <= x:
if x % i == 0: return 0
i += 1
return 1
M = int( input() )
cnt = 0
for i in range( 2, int( 1e9 ), 1 ):
if not prime( i ): continue
if i == int( str( i )[ : : -1 ] ): continue
if not prime( int( str( i )[ : : -1 ] ) ): continue
cnt += 1
if cnt == M:
exit( print( i ) )
``` | instruction | 0 | 21,472 | 11 | 42,944 |
Yes | output | 1 | 21,472 | 11 | 42,945 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
qd ucyhf yi q fhycu dkcruh mxeiu huluhiu yi q tyvvuhudj fhycu dkcruh. oekh jqia yi je vydt jxu djx ucyhf.
Input
jxu ydfkj sediyiji ev q iydwbu ydjuwuh d (1 ≤ d ≤ 11184) — jxu edu-rqiut ydtun ev jxu ucyhf je vydt.
Output
ekjfkj q iydwbu dkcruh.
Examples
Input
1
Output
13
Submitted Solution:
```
import sys
def solve():
d, = rv()
cur = 2
while d > 0:
if isprime(cur):
rev = reverse(cur)
if rev != cur and isprime(rev):
d -= 1
if d > 0: cur+=1
print(cur)
def isprime(cur):
check = 2
while check * check <= cur:
if cur % check == 0: return False
check += 1
return True
def reverse(num):
rev = 0
while num > 0:
rev = (10*rev)+num%10
num //= 10
return rev
def prt(l): return print(''.join(l))
def rv(): return map(int, input().split())
def rl(n): return [list(map(int, input().split())) for _ in range(n)]
if sys.hexversion == 50594544 : sys.stdin = open("test.txt")
solve()
``` | instruction | 0 | 21,473 | 11 | 42,946 |
Yes | output | 1 | 21,473 | 11 | 42,947 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
qd ucyhf yi q fhycu dkcruh mxeiu huluhiu yi q tyvvuhudj fhycu dkcruh. oekh jqia yi je vydt jxu djx ucyhf.
Input
jxu ydfkj sediyiji ev q iydwbu ydjuwuh d (1 ≤ d ≤ 11184) — jxu edu-rqiut ydtun ev jxu ucyhf je vydt.
Output
ekjfkj q iydwbu dkcruh.
Examples
Input
1
Output
13
Submitted Solution:
```
import sys
def solve():
d, = rv()
cur = 2
while d > 0 and cur < 1000:
if isprime(cur):
rev = int(str(cur)[::-1])
if rev != cur and isprime(rev):
d -= 1
if d > 0: cur+=1
print(cur)
def isprime(cur):
prime = True
check = 2
while check * check <= cur:
if cur % check == 0: return False
check += 1
return True
def prt(l): return print(''.join(l))
def rv(): return map(int, input().split())
def rl(n): return [list(map(int, input().split())) for _ in range(n)]
if sys.hexversion == 50594544 : sys.stdin = open("test.txt")
solve()
``` | instruction | 0 | 21,476 | 11 | 42,952 |
No | output | 1 | 21,476 | 11 | 42,953 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
qd ucyhf yi q fhycu dkcruh mxeiu huluhiu yi q tyvvuhudj fhycu dkcruh. oekh jqia yi je vydt jxu djx ucyhf.
Input
jxu ydfkj sediyiji ev q iydwbu ydjuwuh d (1 ≤ d ≤ 11184) — jxu edu-rqiut ydtun ev jxu ucyhf je vydt.
Output
ekjfkj q iydwbu dkcruh.
Examples
Input
1
Output
13
Submitted Solution:
```
def is_prime(n):
if n == 1:
return False
if n == 2:
return True
if n == 3:
return True
if n % 2 == 0:
return False
if n % 3 == 0:
return False
i = 5
w = 2
while i * i <= n:
if n % i == 0:
return False
i += w
w = 6 - w
return True
def get_emirp(idx):
emirps = []
i = 10
while len(emirps) != idx:
if is_prime(i) and is_prime(int(str(i)[::-1])):
emirps.append(i)
i += 1
return emirps[idx-1]
n = int(input())
print(get_emirp(n))
``` | instruction | 0 | 21,477 | 11 | 42,954 |
No | output | 1 | 21,477 | 11 | 42,955 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Ilya the Lion wants to help all his friends with passing exams. They need to solve the following problem to pass the IT exam.
You've got string s = s1s2... sn (n is the length of the string), consisting only of characters "." and "#" and m queries. Each query is described by a pair of integers li, ri (1 ≤ li < ri ≤ n). The answer to the query li, ri is the number of such integers i (li ≤ i < ri), that si = si + 1.
Ilya the Lion wants to help his friends but is there anyone to help him? Help Ilya, solve the problem.
Input
The first line contains string s of length n (2 ≤ n ≤ 105). It is guaranteed that the given string only consists of characters "." and "#".
The next line contains integer m (1 ≤ m ≤ 105) — the number of queries. Each of the next m lines contains the description of the corresponding query. The i-th line contains integers li, ri (1 ≤ li < ri ≤ n).
Output
Print m integers — the answers to the queries in the order in which they are given in the input.
Examples
Input
......
4
3 4
2 3
1 6
2 6
Output
1
1
5
4
Input
#..###
5
1 3
5 6
1 5
3 6
3 4
Output
1
1
2
2
0
Submitted Solution:
```
l=list(input())
a=[(l[i]==l[i+1])*1 for i in range(len(l)-1)]
s=[0]
su=0
for x in a:
su+=x
s+=[su]
n=int(input())
ans=[]
for _ in range(n):
i,j=map(int,input().split())
ans+=[str(s[j-1]-s[i-1])]
print('\n'.join(ans))
``` | instruction | 0 | 21,528 | 11 | 43,056 |
Yes | output | 1 | 21,528 | 11 | 43,057 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Ilya the Lion wants to help all his friends with passing exams. They need to solve the following problem to pass the IT exam.
You've got string s = s1s2... sn (n is the length of the string), consisting only of characters "." and "#" and m queries. Each query is described by a pair of integers li, ri (1 ≤ li < ri ≤ n). The answer to the query li, ri is the number of such integers i (li ≤ i < ri), that si = si + 1.
Ilya the Lion wants to help his friends but is there anyone to help him? Help Ilya, solve the problem.
Input
The first line contains string s of length n (2 ≤ n ≤ 105). It is guaranteed that the given string only consists of characters "." and "#".
The next line contains integer m (1 ≤ m ≤ 105) — the number of queries. Each of the next m lines contains the description of the corresponding query. The i-th line contains integers li, ri (1 ≤ li < ri ≤ n).
Output
Print m integers — the answers to the queries in the order in which they are given in the input.
Examples
Input
......
4
3 4
2 3
1 6
2 6
Output
1
1
5
4
Input
#..###
5
1 3
5 6
1 5
3 6
3 4
Output
1
1
2
2
0
Submitted Solution:
```
s = input()
n = len(s)
dp = [0] * n
prev = s[0]
for i in range(1, n):
if s[i] == s[i - 1]:
dp[i] += dp[i - 1] + 1
else:
dp[i] = dp[i - 1]
# print(dp)
m = int(input())
for _ in range(m):
l, r = map(int, input().split())
print(dp[r - 1] - dp[l - 1])
``` | instruction | 0 | 21,529 | 11 | 43,058 |
Yes | output | 1 | 21,529 | 11 | 43,059 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Ilya the Lion wants to help all his friends with passing exams. They need to solve the following problem to pass the IT exam.
You've got string s = s1s2... sn (n is the length of the string), consisting only of characters "." and "#" and m queries. Each query is described by a pair of integers li, ri (1 ≤ li < ri ≤ n). The answer to the query li, ri is the number of such integers i (li ≤ i < ri), that si = si + 1.
Ilya the Lion wants to help his friends but is there anyone to help him? Help Ilya, solve the problem.
Input
The first line contains string s of length n (2 ≤ n ≤ 105). It is guaranteed that the given string only consists of characters "." and "#".
The next line contains integer m (1 ≤ m ≤ 105) — the number of queries. Each of the next m lines contains the description of the corresponding query. The i-th line contains integers li, ri (1 ≤ li < ri ≤ n).
Output
Print m integers — the answers to the queries in the order in which they are given in the input.
Examples
Input
......
4
3 4
2 3
1 6
2 6
Output
1
1
5
4
Input
#..###
5
1 3
5 6
1 5
3 6
3 4
Output
1
1
2
2
0
Submitted Solution:
```
l = [0 if x == '.' else 1 for x in input()]
l[0] = 1 if l[0] == l[1] else 0
for i in range(1, len(l) - 1):
c = l[i]
l[i] = l[i - 1]
if c == l[i + 1]:
l[i] += 1
l[-1] = l[-2]
n = int(input())
l = [0] + l
results = []
for _ in range(n):
i1, i2 = map(int, input().split())
results.append(str(l[i2 - 1] - l[i1 - 1]))
print("\n".join(results))
``` | instruction | 0 | 21,530 | 11 | 43,060 |
Yes | output | 1 | 21,530 | 11 | 43,061 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Ilya the Lion wants to help all his friends with passing exams. They need to solve the following problem to pass the IT exam.
You've got string s = s1s2... sn (n is the length of the string), consisting only of characters "." and "#" and m queries. Each query is described by a pair of integers li, ri (1 ≤ li < ri ≤ n). The answer to the query li, ri is the number of such integers i (li ≤ i < ri), that si = si + 1.
Ilya the Lion wants to help his friends but is there anyone to help him? Help Ilya, solve the problem.
Input
The first line contains string s of length n (2 ≤ n ≤ 105). It is guaranteed that the given string only consists of characters "." and "#".
The next line contains integer m (1 ≤ m ≤ 105) — the number of queries. Each of the next m lines contains the description of the corresponding query. The i-th line contains integers li, ri (1 ≤ li < ri ≤ n).
Output
Print m integers — the answers to the queries in the order in which they are given in the input.
Examples
Input
......
4
3 4
2 3
1 6
2 6
Output
1
1
5
4
Input
#..###
5
1 3
5 6
1 5
3 6
3 4
Output
1
1
2
2
0
Submitted Solution:
```
import sys,math,string
input=sys.stdin.readline
from collections import deque
L=lambda : list(map(int,input().split()))
Ls=lambda : list(input().split())
M=lambda : map(int,input().split())
l=input()
a=[0]
for i in range(1,len(l)):
if(l[i-1]==l[i]):
a.append(1+a[-1])
else:
a.append(a[-1])
n=int(input())
for i in range(n):
l,r=map(int,input().split())
sys.stdout.write(str(a[r-1]-a[l-1])+'\n')
``` | instruction | 0 | 21,531 | 11 | 43,062 |
Yes | output | 1 | 21,531 | 11 | 43,063 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Ilya the Lion wants to help all his friends with passing exams. They need to solve the following problem to pass the IT exam.
You've got string s = s1s2... sn (n is the length of the string), consisting only of characters "." and "#" and m queries. Each query is described by a pair of integers li, ri (1 ≤ li < ri ≤ n). The answer to the query li, ri is the number of such integers i (li ≤ i < ri), that si = si + 1.
Ilya the Lion wants to help his friends but is there anyone to help him? Help Ilya, solve the problem.
Input
The first line contains string s of length n (2 ≤ n ≤ 105). It is guaranteed that the given string only consists of characters "." and "#".
The next line contains integer m (1 ≤ m ≤ 105) — the number of queries. Each of the next m lines contains the description of the corresponding query. The i-th line contains integers li, ri (1 ≤ li < ri ≤ n).
Output
Print m integers — the answers to the queries in the order in which they are given in the input.
Examples
Input
......
4
3 4
2 3
1 6
2 6
Output
1
1
5
4
Input
#..###
5
1 3
5 6
1 5
3 6
3 4
Output
1
1
2
2
0
Submitted Solution:
```
s=input()
z=[0]
count=0
for i in range(len(s)-1):
if s[i]==s[i+1]:
count+=1
z.append(count)
print(z)
n=int(input())
while n:
n-=1
l,r=map(int,input().split())
# var=0
# if l==1:
# var=0
# else:
# var=z[l-2]
print(z[r-1]-z[l-1])
#unknown_2433
``` | instruction | 0 | 21,532 | 11 | 43,064 |
No | output | 1 | 21,532 | 11 | 43,065 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Ilya the Lion wants to help all his friends with passing exams. They need to solve the following problem to pass the IT exam.
You've got string s = s1s2... sn (n is the length of the string), consisting only of characters "." and "#" and m queries. Each query is described by a pair of integers li, ri (1 ≤ li < ri ≤ n). The answer to the query li, ri is the number of such integers i (li ≤ i < ri), that si = si + 1.
Ilya the Lion wants to help his friends but is there anyone to help him? Help Ilya, solve the problem.
Input
The first line contains string s of length n (2 ≤ n ≤ 105). It is guaranteed that the given string only consists of characters "." and "#".
The next line contains integer m (1 ≤ m ≤ 105) — the number of queries. Each of the next m lines contains the description of the corresponding query. The i-th line contains integers li, ri (1 ≤ li < ri ≤ n).
Output
Print m integers — the answers to the queries in the order in which they are given in the input.
Examples
Input
......
4
3 4
2 3
1 6
2 6
Output
1
1
5
4
Input
#..###
5
1 3
5 6
1 5
3 6
3 4
Output
1
1
2
2
0
Submitted Solution:
```
s = input()
a = int(input())
ans = []
dp = [0] * (len(s))
for x in range(len(s)-1):
if s[x] == s[x + 1]:
dp[x] = 1
if s[len(s)-2] == s[len(s)-1]:
dp[len(s)-1] = 1
else:
dp[0] = 0
for x in range(a):
p = input().split(" ")
l = int(p[0])
r = int(p[1])
ans.append(sum(dp[l-1:r-1]))
for x in ans:
print(x)
``` | instruction | 0 | 21,533 | 11 | 43,066 |
No | output | 1 | 21,533 | 11 | 43,067 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Ilya the Lion wants to help all his friends with passing exams. They need to solve the following problem to pass the IT exam.
You've got string s = s1s2... sn (n is the length of the string), consisting only of characters "." and "#" and m queries. Each query is described by a pair of integers li, ri (1 ≤ li < ri ≤ n). The answer to the query li, ri is the number of such integers i (li ≤ i < ri), that si = si + 1.
Ilya the Lion wants to help his friends but is there anyone to help him? Help Ilya, solve the problem.
Input
The first line contains string s of length n (2 ≤ n ≤ 105). It is guaranteed that the given string only consists of characters "." and "#".
The next line contains integer m (1 ≤ m ≤ 105) — the number of queries. Each of the next m lines contains the description of the corresponding query. The i-th line contains integers li, ri (1 ≤ li < ri ≤ n).
Output
Print m integers — the answers to the queries in the order in which they are given in the input.
Examples
Input
......
4
3 4
2 3
1 6
2 6
Output
1
1
5
4
Input
#..###
5
1 3
5 6
1 5
3 6
3 4
Output
1
1
2
2
0
Submitted Solution:
```
s = input()
l = len(s)
array = [0]*(l+1)
for i in range(l-1):
if s[i]==s[i+1]:
array[i+1] = 1
sum_array = [0]*(l+1)
for i in range(1,l+1):
sum_array[i]+=sum_array[i-1]+array[i]
m = int(input())
for i in range(m):
li,ri = map(int,input().split())
print(sum_array[ri] - sum_array[li])
``` | instruction | 0 | 21,534 | 11 | 43,068 |
No | output | 1 | 21,534 | 11 | 43,069 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Ilya the Lion wants to help all his friends with passing exams. They need to solve the following problem to pass the IT exam.
You've got string s = s1s2... sn (n is the length of the string), consisting only of characters "." and "#" and m queries. Each query is described by a pair of integers li, ri (1 ≤ li < ri ≤ n). The answer to the query li, ri is the number of such integers i (li ≤ i < ri), that si = si + 1.
Ilya the Lion wants to help his friends but is there anyone to help him? Help Ilya, solve the problem.
Input
The first line contains string s of length n (2 ≤ n ≤ 105). It is guaranteed that the given string only consists of characters "." and "#".
The next line contains integer m (1 ≤ m ≤ 105) — the number of queries. Each of the next m lines contains the description of the corresponding query. The i-th line contains integers li, ri (1 ≤ li < ri ≤ n).
Output
Print m integers — the answers to the queries in the order in which they are given in the input.
Examples
Input
......
4
3 4
2 3
1 6
2 6
Output
1
1
5
4
Input
#..###
5
1 3
5 6
1 5
3 6
3 4
Output
1
1
2
2
0
Submitted Solution:
```
s = input()
x = [0] * len(s)
for i in range(1, len(s) -1):
x[i] = x[i - 1]
if s[i] == s[i + 1]:
x[i] += 1
if len(x) > 1:
x[len(s) -1] = x[len(s) - 2]
m = int(input())
for i in range(m):
l,r = map(int, input().split())
ans = x[r - 1]
if l > 1:
ans -= x[l - 2]
if (r == 1 and x[r-1] > 0) or (x[r - 1] - x[r - 2]) > 0:
ans -= 1
print(ans)
``` | instruction | 0 | 21,535 | 11 | 43,070 |
No | output | 1 | 21,535 | 11 | 43,071 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Mole is hungry again. He found one ant colony, consisting of n ants, ordered in a row. Each ant i (1 ≤ i ≤ n) has a strength si.
In order to make his dinner more interesting, Mole organizes a version of «Hunger Games» for the ants. He chooses two numbers l and r (1 ≤ l ≤ r ≤ n) and each pair of ants with indices between l and r (inclusively) will fight. When two ants i and j fight, ant i gets one battle point only if si divides sj (also, ant j gets one battle point only if sj divides si).
After all fights have been finished, Mole makes the ranking. An ant i, with vi battle points obtained, is going to be freed only if vi = r - l, or in other words only if it took a point in every fight it participated. After that, Mole eats the rest of the ants. Note that there can be many ants freed or even none.
In order to choose the best sequence, Mole gives you t segments [li, ri] and asks for each of them how many ants is he going to eat if those ants fight.
Input
The first line contains one integer n (1 ≤ n ≤ 105), the size of the ant colony.
The second line contains n integers s1, s2, ..., sn (1 ≤ si ≤ 109), the strengths of the ants.
The third line contains one integer t (1 ≤ t ≤ 105), the number of test cases.
Each of the next t lines contains two integers li and ri (1 ≤ li ≤ ri ≤ n), describing one query.
Output
Print to the standard output t lines. The i-th line contains number of ants that Mole eats from the segment [li, ri].
Examples
Input
5
1 3 2 4 2
4
1 5
2 5
3 5
4 5
Output
4
4
1
1
Note
In the first test battle points for each ant are v = [4, 0, 2, 0, 2], so ant number 1 is freed. Mole eats the ants 2, 3, 4, 5.
In the second test case battle points are v = [0, 2, 0, 2], so no ant is freed and all of them are eaten by Mole.
In the third test case battle points are v = [2, 0, 2], so ants number 3 and 5 are freed. Mole eats only the ant 4.
In the fourth test case battle points are v = [0, 1], so ant number 5 is freed. Mole eats the ant 4.
Submitted Solution:
```
import sys
input = sys.stdin.readline
def gcd(a, b):
return a if b == 0 else gcd(b, a % b)
class Tree:
def __init__(self, n):
self.base = 1
while self.base < n:
self.base *= 2
self.seg = [(0, 1)] * (2 * self.base)
def merge(self, x, y):
g = gcd(x[0], y[0])
return g, (x[1] if x[0] == g else 0) + (y[1] if y[0] == g else 0)
def set(self, i, v):
i += self.base
self.seg[i] = (v, 1)
i //= 2
while i >= 1:
self.seg[i] = self.merge(self.seg[2 * i], self.seg[2 * i + 1])
i //= 2
def get(self, l, r):
l += self.base
r += self.base
res = (0, 1)
while l <= r:
if l % 2 == 1:
res = self.merge(res, self.seg[l])
l += 1
if r % 2 == 0:
res = self.merge(res, self.seg[r])
r -= 1
l //= 2
r //= 2
return res
n = int(input())
s = list(map(int, input().split()))
tree = Tree(n)
for i in range(n):
tree.set(i, s[i])
t = int(input())
res = []
for _ in range(t):
l, r = map(int, input().split())
l -= 1
r -= 1
res.append(r - l + 1 - tree.get(l, r)[1])
print("\n".join(map(str, res)))
``` | instruction | 0 | 21,578 | 11 | 43,156 |
Yes | output | 1 | 21,578 | 11 | 43,157 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Mole is hungry again. He found one ant colony, consisting of n ants, ordered in a row. Each ant i (1 ≤ i ≤ n) has a strength si.
In order to make his dinner more interesting, Mole organizes a version of «Hunger Games» for the ants. He chooses two numbers l and r (1 ≤ l ≤ r ≤ n) and each pair of ants with indices between l and r (inclusively) will fight. When two ants i and j fight, ant i gets one battle point only if si divides sj (also, ant j gets one battle point only if sj divides si).
After all fights have been finished, Mole makes the ranking. An ant i, with vi battle points obtained, is going to be freed only if vi = r - l, or in other words only if it took a point in every fight it participated. After that, Mole eats the rest of the ants. Note that there can be many ants freed or even none.
In order to choose the best sequence, Mole gives you t segments [li, ri] and asks for each of them how many ants is he going to eat if those ants fight.
Input
The first line contains one integer n (1 ≤ n ≤ 105), the size of the ant colony.
The second line contains n integers s1, s2, ..., sn (1 ≤ si ≤ 109), the strengths of the ants.
The third line contains one integer t (1 ≤ t ≤ 105), the number of test cases.
Each of the next t lines contains two integers li and ri (1 ≤ li ≤ ri ≤ n), describing one query.
Output
Print to the standard output t lines. The i-th line contains number of ants that Mole eats from the segment [li, ri].
Examples
Input
5
1 3 2 4 2
4
1 5
2 5
3 5
4 5
Output
4
4
1
1
Note
In the first test battle points for each ant are v = [4, 0, 2, 0, 2], so ant number 1 is freed. Mole eats the ants 2, 3, 4, 5.
In the second test case battle points are v = [0, 2, 0, 2], so no ant is freed and all of them are eaten by Mole.
In the third test case battle points are v = [2, 0, 2], so ants number 3 and 5 are freed. Mole eats only the ant 4.
In the fourth test case battle points are v = [0, 1], so ant number 5 is freed. Mole eats the ant 4.
Submitted Solution:
```
import sys
import bisect
class SparseTable:
def gcd(self,a,b):
return a if b==0 else self.gcd(b,a%b)
def __init__(self,A):
LG = 17
n = len(A)
self.lg = [0 for i in range(n+1)]
for i in range(2,n+1):
self.lg[i] = self.lg[i>>1] + 1
# j+(1<<i)-1 < n
self.spt = [[None for j in range(n+1-(1<<i))] for i in range(LG)]
for j in range(n):
self.spt[0][j] = A[j]
for i in range(1,LG):
for j in range(n+1-(1<<i)):
self.spt[i][j] = self.gcd(self.spt[i-1][j],self.spt[i-1][j+(1<<(i-1))])
def query(self,L,R):
pow2 = self.lg[R-L+1]
return self.gcd(self.spt[pow2][L],self.spt[pow2][R-(1<<pow2)+1])
appearances = {}
n = int(sys.stdin.readline())
A = list(map(int,sys.stdin.readline().split()))
for i in range(n):
if A[i] not in appearances:
appearances[A[i]] = []
appearances[A[i]].append(i)
def leq(k,n):
return bisect.bisect(appearances[k],n)
sparse = SparseTable(A)
Q = int(sys.stdin.readline())
for _ in range(Q):
L, R = map(int,sys.stdin.readline().split())
L -= 1
R -= 1
gcd = sparse.query(L,R)
if gcd not in appearances:
ans = 0
else:
ans = leq(gcd,R)-leq(gcd,L-1)
print((R-L+1)-ans)
``` | instruction | 0 | 21,579 | 11 | 43,158 |
Yes | output | 1 | 21,579 | 11 | 43,159 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Mole is hungry again. He found one ant colony, consisting of n ants, ordered in a row. Each ant i (1 ≤ i ≤ n) has a strength si.
In order to make his dinner more interesting, Mole organizes a version of «Hunger Games» for the ants. He chooses two numbers l and r (1 ≤ l ≤ r ≤ n) and each pair of ants with indices between l and r (inclusively) will fight. When two ants i and j fight, ant i gets one battle point only if si divides sj (also, ant j gets one battle point only if sj divides si).
After all fights have been finished, Mole makes the ranking. An ant i, with vi battle points obtained, is going to be freed only if vi = r - l, or in other words only if it took a point in every fight it participated. After that, Mole eats the rest of the ants. Note that there can be many ants freed or even none.
In order to choose the best sequence, Mole gives you t segments [li, ri] and asks for each of them how many ants is he going to eat if those ants fight.
Input
The first line contains one integer n (1 ≤ n ≤ 105), the size of the ant colony.
The second line contains n integers s1, s2, ..., sn (1 ≤ si ≤ 109), the strengths of the ants.
The third line contains one integer t (1 ≤ t ≤ 105), the number of test cases.
Each of the next t lines contains two integers li and ri (1 ≤ li ≤ ri ≤ n), describing one query.
Output
Print to the standard output t lines. The i-th line contains number of ants that Mole eats from the segment [li, ri].
Examples
Input
5
1 3 2 4 2
4
1 5
2 5
3 5
4 5
Output
4
4
1
1
Note
In the first test battle points for each ant are v = [4, 0, 2, 0, 2], so ant number 1 is freed. Mole eats the ants 2, 3, 4, 5.
In the second test case battle points are v = [0, 2, 0, 2], so no ant is freed and all of them are eaten by Mole.
In the third test case battle points are v = [2, 0, 2], so ants number 3 and 5 are freed. Mole eats only the ant 4.
In the fourth test case battle points are v = [0, 1], so ant number 5 is freed. Mole eats the ant 4.
Submitted Solution:
```
import sys
from math import gcd
from bisect import bisect_left,bisect_right
class SparseTable:
def func(self,a,b):
return gcd(a,b)
def __init__(self,arr):
n=len(arr)
max_k=(n-1).bit_length()-1
val=1
table=[[val]*(max_k+1) for i in range(n)]
for i in range(n):
table[i][0]=arr[i]
for k in range(1,max_k+1):
k2=1<<(k-1)
k3=1<<k-1
for i in range(n-k3):
table[i][k]=self.func(table[i][k-1],table[k2+i][k-1])
self.table=table
def query(self,l,r):
d=r-l
if d==1:
return self.table[l][0]
k=(d-1).bit_length()-1
k2=1<<k
return self.func(self.table[l][k],self.table[r-k2][k])
input=sys.stdin.readline
n=int(input())
s=list(map(int,input().split()))
sp_tab=SparseTable(s)
di={}
for i in range(n):
if s[i] in di:
di[s[i]].append(i)
else:
di[s[i]]=[i]
q=int(input())
for _ in range(q):
l,r=map(int,input().split())
l-=1;r-=1
g=sp_tab.query(l,r+1)
if g in di:
num=bisect_right(di[g],r)-bisect_left(di[g],l)
print(r-l+1-num)
else:
print(r-l+1)
``` | instruction | 0 | 21,580 | 11 | 43,160 |
Yes | output | 1 | 21,580 | 11 | 43,161 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Mole is hungry again. He found one ant colony, consisting of n ants, ordered in a row. Each ant i (1 ≤ i ≤ n) has a strength si.
In order to make his dinner more interesting, Mole organizes a version of «Hunger Games» for the ants. He chooses two numbers l and r (1 ≤ l ≤ r ≤ n) and each pair of ants with indices between l and r (inclusively) will fight. When two ants i and j fight, ant i gets one battle point only if si divides sj (also, ant j gets one battle point only if sj divides si).
After all fights have been finished, Mole makes the ranking. An ant i, with vi battle points obtained, is going to be freed only if vi = r - l, or in other words only if it took a point in every fight it participated. After that, Mole eats the rest of the ants. Note that there can be many ants freed or even none.
In order to choose the best sequence, Mole gives you t segments [li, ri] and asks for each of them how many ants is he going to eat if those ants fight.
Input
The first line contains one integer n (1 ≤ n ≤ 105), the size of the ant colony.
The second line contains n integers s1, s2, ..., sn (1 ≤ si ≤ 109), the strengths of the ants.
The third line contains one integer t (1 ≤ t ≤ 105), the number of test cases.
Each of the next t lines contains two integers li and ri (1 ≤ li ≤ ri ≤ n), describing one query.
Output
Print to the standard output t lines. The i-th line contains number of ants that Mole eats from the segment [li, ri].
Examples
Input
5
1 3 2 4 2
4
1 5
2 5
3 5
4 5
Output
4
4
1
1
Note
In the first test battle points for each ant are v = [4, 0, 2, 0, 2], so ant number 1 is freed. Mole eats the ants 2, 3, 4, 5.
In the second test case battle points are v = [0, 2, 0, 2], so no ant is freed and all of them are eaten by Mole.
In the third test case battle points are v = [2, 0, 2], so ants number 3 and 5 are freed. Mole eats only the ant 4.
In the fourth test case battle points are v = [0, 1], so ant number 5 is freed. Mole eats the ant 4.
Submitted Solution:
```
from math import gcd
class SegTree:
def __init__(self, arr = None, length = None):
"""
Creates a segment tree. If arr (a list) is given, length is ignored,
and we build a segment tree with underlying array arr. If no list is
given, length (an int) must be given, and we build a segment tree with
underlying all-zero array of that length.
"""
if arr is not None:
self.n = len(arr)
self.t = [1 for _ in range(2*self.n)]
self.ct = [0]*self.n + [1]*self.n
self.construct(arr)
else:
assert False
self.n = length
self.t = [1 for _ in range(2*self.n)]
def construct(self, arr):
"""
Constructs the segment tree from given array (assumed to be of the
right length).
"""
self.t[self.n:] = arr
for i in reversed(range(0, self.n)):
self.t[i] = gcd(self.t[i*2], self.t[i*2+1])
# print(i, self.t[i], self.t[i*2], self.t[i*2+1])
if self.t[i] == self.t[i*2]:
self.ct[i] += self.ct[i*2]
if self.t[i] == self.t[i*2 + 1]:
self.ct[i] += self.ct[i*2 + 1]
def modify(self, p, val):
"""
Sets the value at index p to val.
"""
p += self.n
self.t[p] = val
self.ct[p] = 1
while p > 1:
self.t[p//2] = gcd(self.t[p], self.t[p ^ 1])
self.ct[p//2] = 0
if self.t[p//2] == self.t[p]:
self.ct[p//2] += self.ct[p]
if self.t[p//2] == self.t[p ^ 1]:
self.ct[p//2] += self.ct[p ^ 1]
p //= 2
def gcd_query(self, l, r):
l += self.n
r += self.n
res = self.t[l]
while l < r:
if l&1:
res = gcd(res, self.t[l])
l += 1
if r&1:
r -= 1
res = gcd(res, self.t[r])
l //= 2
r //= 2
return res
def query_num_eq_gcd(self, l, r):
"""
Gets the sum of all values in the range [l, r) in the underlying array.
"""
my_gcd = self.gcd_query(l, r)
l += self.n
r += self.n
res = 0
while l < r:
if l&1:
if self.t[l] == my_gcd:
res += self.ct[l]
l += 1
if r&1:
r -= 1
if self.t[r] == my_gcd:
res += self.ct[r]
l //= 2
r //= 2
return res
import sys
n = int(input())
s = [int(x) for x in input().split()]
st = SegTree(arr=s)
t = int(input())
for _ in range(t):
l, r = [int(x) for x in sys.stdin.readline().split()]
# print(f"gcd = {st.gcd_query(l-1, r)}")
# print(f"num eq to gcd = {st.query_num_eq_gcd(l-1, r)}")
print(r - l + 1 - st.query_num_eq_gcd(l-1, r))
# print(st.t)
# print(st.ct)
# print()
``` | instruction | 0 | 21,581 | 11 | 43,162 |
Yes | output | 1 | 21,581 | 11 | 43,163 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Mole is hungry again. He found one ant colony, consisting of n ants, ordered in a row. Each ant i (1 ≤ i ≤ n) has a strength si.
In order to make his dinner more interesting, Mole organizes a version of «Hunger Games» for the ants. He chooses two numbers l and r (1 ≤ l ≤ r ≤ n) and each pair of ants with indices between l and r (inclusively) will fight. When two ants i and j fight, ant i gets one battle point only if si divides sj (also, ant j gets one battle point only if sj divides si).
After all fights have been finished, Mole makes the ranking. An ant i, with vi battle points obtained, is going to be freed only if vi = r - l, or in other words only if it took a point in every fight it participated. After that, Mole eats the rest of the ants. Note that there can be many ants freed or even none.
In order to choose the best sequence, Mole gives you t segments [li, ri] and asks for each of them how many ants is he going to eat if those ants fight.
Input
The first line contains one integer n (1 ≤ n ≤ 105), the size of the ant colony.
The second line contains n integers s1, s2, ..., sn (1 ≤ si ≤ 109), the strengths of the ants.
The third line contains one integer t (1 ≤ t ≤ 105), the number of test cases.
Each of the next t lines contains two integers li and ri (1 ≤ li ≤ ri ≤ n), describing one query.
Output
Print to the standard output t lines. The i-th line contains number of ants that Mole eats from the segment [li, ri].
Examples
Input
5
1 3 2 4 2
4
1 5
2 5
3 5
4 5
Output
4
4
1
1
Note
In the first test battle points for each ant are v = [4, 0, 2, 0, 2], so ant number 1 is freed. Mole eats the ants 2, 3, 4, 5.
In the second test case battle points are v = [0, 2, 0, 2], so no ant is freed and all of them are eaten by Mole.
In the third test case battle points are v = [2, 0, 2], so ants number 3 and 5 are freed. Mole eats only the ant 4.
In the fourth test case battle points are v = [0, 1], so ant number 5 is freed. Mole eats the ant 4.
Submitted Solution:
```
# ------------------- fast io --------------------
import os
import sys
from io import BytesIO, IOBase
BUFSIZE = 8192
class FastIO(IOBase):
newlines = 0
def __init__(self, file):
self._fd = file.fileno()
self.buffer = BytesIO()
self.writable = "x" in file.mode or "r" not in file.mode
self.write = self.buffer.write if self.writable else None
def read(self):
while True:
b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
if not b:
break
ptr = self.buffer.tell()
self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
self.newlines = 0
return self.buffer.read()
def readline(self):
while self.newlines == 0:
b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
self.newlines = b.count(b"\n") + (not b)
ptr = self.buffer.tell()
self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
self.newlines -= 1
return self.buffer.readline()
def flush(self):
if self.writable:
os.write(self._fd, self.buffer.getvalue())
self.buffer.truncate(0), self.buffer.seek(0)
class IOWrapper(IOBase):
def __init__(self, file):
self.buffer = FastIO(file)
self.flush = self.buffer.flush
self.writable = self.buffer.writable
self.write = lambda s: self.buffer.write(s.encode("ascii"))
self.read = lambda: self.buffer.read().decode("ascii")
self.readline = lambda: self.buffer.readline().decode("ascii")
sys.stdin, sys.stdout = IOWrapper(sys.stdin), IOWrapper(sys.stdout)
input = lambda: sys.stdin.readline().rstrip("\r\n")
# ------------------- fast io --------------------
class SegmentTree:
def __init__(self, data, default=0, func=max):
"""initialize the segment tree with data"""
self._default = default
self._func = func
self._len = len(data)
self._size = _size = 1 << (self._len - 1).bit_length()
self.data = [default] * (2 * _size)
self.data[_size:_size + self._len] = data
for i in reversed(range(_size)):
self.data[i] = func(self.data[i + i], self.data[i + i + 1])
def __delitem__(self, idx):
self[idx] = self._default
def __getitem__(self, idx):
return self.data[idx + self._size]
def __setitem__(self, idx, value):
idx += self._size
self.data[idx] = value
idx >>= 1
while idx:
self.data[idx] = self._func(self.data[2 * idx], self.data[2 * idx + 1])
idx >>= 1
def __len__(self):
return self._len
def query(self, start, stop):
if start == stop:
return self.__getitem__(start)
stop += 1
start += self._size
stop += self._size
res = self._default
while start < stop:
if start & 1:
res = self._func(res, self.data[start])
start += 1
if stop & 1:
stop -= 1
res = self._func(res, self.data[stop])
start >>= 1
stop >>= 1
return res
def __repr__(self):
return "SegmentTree({0})".format(self.data)
# ------------------------
from math import gcd
from collections import defaultdict
from bisect import bisect_left, bisect_right
n = int(input())
a = list(map(int, input().split()))
store = defaultdict(list)
def findFrequency(left, right, element):
a = bisect_left(store[element], left)
b = bisect_right(store[element], right)
return b - a
for i in range(n):
store[a[i]].append(i+1)
st1 = SegmentTree(a, func=gcd)
st2 = SegmentTree(a, func=min, default=696969)
for _ in range(int(input())):
x, y = map(int, input().split())
ans1, ans2 = st1.query(x-1, y-1), st2.query(x-1, y-1)
if ans1 != ans2:
print(y-x+1)
else:
print(y+1-x-findFrequency(x, y, ans1))
``` | instruction | 0 | 21,582 | 11 | 43,164 |
No | output | 1 | 21,582 | 11 | 43,165 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Mole is hungry again. He found one ant colony, consisting of n ants, ordered in a row. Each ant i (1 ≤ i ≤ n) has a strength si.
In order to make his dinner more interesting, Mole organizes a version of «Hunger Games» for the ants. He chooses two numbers l and r (1 ≤ l ≤ r ≤ n) and each pair of ants with indices between l and r (inclusively) will fight. When two ants i and j fight, ant i gets one battle point only if si divides sj (also, ant j gets one battle point only if sj divides si).
After all fights have been finished, Mole makes the ranking. An ant i, with vi battle points obtained, is going to be freed only if vi = r - l, or in other words only if it took a point in every fight it participated. After that, Mole eats the rest of the ants. Note that there can be many ants freed or even none.
In order to choose the best sequence, Mole gives you t segments [li, ri] and asks for each of them how many ants is he going to eat if those ants fight.
Input
The first line contains one integer n (1 ≤ n ≤ 105), the size of the ant colony.
The second line contains n integers s1, s2, ..., sn (1 ≤ si ≤ 109), the strengths of the ants.
The third line contains one integer t (1 ≤ t ≤ 105), the number of test cases.
Each of the next t lines contains two integers li and ri (1 ≤ li ≤ ri ≤ n), describing one query.
Output
Print to the standard output t lines. The i-th line contains number of ants that Mole eats from the segment [li, ri].
Examples
Input
5
1 3 2 4 2
4
1 5
2 5
3 5
4 5
Output
4
4
1
1
Note
In the first test battle points for each ant are v = [4, 0, 2, 0, 2], so ant number 1 is freed. Mole eats the ants 2, 3, 4, 5.
In the second test case battle points are v = [0, 2, 0, 2], so no ant is freed and all of them are eaten by Mole.
In the third test case battle points are v = [2, 0, 2], so ants number 3 and 5 are freed. Mole eats only the ant 4.
In the fourth test case battle points are v = [0, 1], so ant number 5 is freed. Mole eats the ant 4.
Submitted Solution:
```
import sys
from math import gcd
from bisect import bisect_left,bisect_right
from collections import defaultdict
class SparseTable:
def func(self,a,b):
return gcd(a,b)
def __init__(self,arr):
n=len(arr)
max_k=(n-1).bit_length()-1
INF=10**18
table=[[INF]*(max_k+1) for i in range(n)]
for i in range(n):
table[i][0]=arr[i]
for k in range(1,max_k+1):
k2=1<<(k-1)
k3=1<<k-1
for i in range(k3):
table[i][k]=self.func(table[i][k-1],table[k2+i][k-1])
self.table=table
def query(self,l,r):
d=r-l
if d==1:
return self.table[l][0]
k=(d-1).bit_length()-1
k2=1<<k
return self.func(self.table[l][k],self.table[r-k2][k])
input=sys.stdin.readline
n=int(input())
s=list(map(int,input().split()))
sp_tab=SparseTable(s)
dd=defaultdict(list)
for i in range(n):
dd[s[i]].append(i)
q=int(input())
for _ in range(q):
l,r=map(int,input().split())
l-=1;r-=1
g=sp_tab.query(l,r)
if len(dd[g])>0:
num=bisect_right(dd[g],r)-bisect_left(dd[g],l)
print(r-l+1-num)
else:
print(r-l+1)
``` | instruction | 0 | 21,583 | 11 | 43,166 |
No | output | 1 | 21,583 | 11 | 43,167 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Mole is hungry again. He found one ant colony, consisting of n ants, ordered in a row. Each ant i (1 ≤ i ≤ n) has a strength si.
In order to make his dinner more interesting, Mole organizes a version of «Hunger Games» for the ants. He chooses two numbers l and r (1 ≤ l ≤ r ≤ n) and each pair of ants with indices between l and r (inclusively) will fight. When two ants i and j fight, ant i gets one battle point only if si divides sj (also, ant j gets one battle point only if sj divides si).
After all fights have been finished, Mole makes the ranking. An ant i, with vi battle points obtained, is going to be freed only if vi = r - l, or in other words only if it took a point in every fight it participated. After that, Mole eats the rest of the ants. Note that there can be many ants freed or even none.
In order to choose the best sequence, Mole gives you t segments [li, ri] and asks for each of them how many ants is he going to eat if those ants fight.
Input
The first line contains one integer n (1 ≤ n ≤ 105), the size of the ant colony.
The second line contains n integers s1, s2, ..., sn (1 ≤ si ≤ 109), the strengths of the ants.
The third line contains one integer t (1 ≤ t ≤ 105), the number of test cases.
Each of the next t lines contains two integers li and ri (1 ≤ li ≤ ri ≤ n), describing one query.
Output
Print to the standard output t lines. The i-th line contains number of ants that Mole eats from the segment [li, ri].
Examples
Input
5
1 3 2 4 2
4
1 5
2 5
3 5
4 5
Output
4
4
1
1
Note
In the first test battle points for each ant are v = [4, 0, 2, 0, 2], so ant number 1 is freed. Mole eats the ants 2, 3, 4, 5.
In the second test case battle points are v = [0, 2, 0, 2], so no ant is freed and all of them are eaten by Mole.
In the third test case battle points are v = [2, 0, 2], so ants number 3 and 5 are freed. Mole eats only the ant 4.
In the fourth test case battle points are v = [0, 1], so ant number 5 is freed. Mole eats the ant 4.
Submitted Solution:
```
import sys
from math import gcd
from bisect import bisect
from collections import defaultdict
class SparseTable:
def func(self,a,b):
return gcd(a,b)
def __init__(self,arr):
n=len(arr)
max_k=(n-1).bit_length()-1
INF=10**18
table=[[INF]*(max_k+1) for i in range(n)]
for i in range(n):
table[i][0]=arr[i]
for k in range(1,max_k+1):
k2=1<<(k-1)
k3=1<<k-1
for i in range(k3):
table[i][k]=self.func(table[i][k-1],table[k2+i][k-1])
self.table=table
def query(self,l,r):
d=r-l
if d==1:
return self.table[l][0]
k=(d-1).bit_length()-1
k2=1<<k
return self.func(self.table[l][k],self.table[r-k2][k])
input=sys.stdin.readline
n=int(input())
s=list(map(int,input().split()))
sp_tab=SparseTable(s)
dd=defaultdict(list)
for i in range(n):
dd[s[i]].append(i)
q=int(input())
for _ in range(q):
l,r=map(int,input().split())
l-=1;r-=1
g=sp_tab.query(l,r)
if len(dd[g])>0:
num=bisect(dd[g],r)-bisect(dd[g],l-1)
print(r-l+1-num)
else:
print(r-l+1)
``` | instruction | 0 | 21,584 | 11 | 43,168 |
No | output | 1 | 21,584 | 11 | 43,169 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Mole is hungry again. He found one ant colony, consisting of n ants, ordered in a row. Each ant i (1 ≤ i ≤ n) has a strength si.
In order to make his dinner more interesting, Mole organizes a version of «Hunger Games» for the ants. He chooses two numbers l and r (1 ≤ l ≤ r ≤ n) and each pair of ants with indices between l and r (inclusively) will fight. When two ants i and j fight, ant i gets one battle point only if si divides sj (also, ant j gets one battle point only if sj divides si).
After all fights have been finished, Mole makes the ranking. An ant i, with vi battle points obtained, is going to be freed only if vi = r - l, or in other words only if it took a point in every fight it participated. After that, Mole eats the rest of the ants. Note that there can be many ants freed or even none.
In order to choose the best sequence, Mole gives you t segments [li, ri] and asks for each of them how many ants is he going to eat if those ants fight.
Input
The first line contains one integer n (1 ≤ n ≤ 105), the size of the ant colony.
The second line contains n integers s1, s2, ..., sn (1 ≤ si ≤ 109), the strengths of the ants.
The third line contains one integer t (1 ≤ t ≤ 105), the number of test cases.
Each of the next t lines contains two integers li and ri (1 ≤ li ≤ ri ≤ n), describing one query.
Output
Print to the standard output t lines. The i-th line contains number of ants that Mole eats from the segment [li, ri].
Examples
Input
5
1 3 2 4 2
4
1 5
2 5
3 5
4 5
Output
4
4
1
1
Note
In the first test battle points for each ant are v = [4, 0, 2, 0, 2], so ant number 1 is freed. Mole eats the ants 2, 3, 4, 5.
In the second test case battle points are v = [0, 2, 0, 2], so no ant is freed and all of them are eaten by Mole.
In the third test case battle points are v = [2, 0, 2], so ants number 3 and 5 are freed. Mole eats only the ant 4.
In the fourth test case battle points are v = [0, 1], so ant number 5 is freed. Mole eats the ant 4.
Submitted Solution:
```
import sys
from collections import Counter
input = sys.stdin.readline
def gcd(a, b):
return a if b == 0 else gcd(b, a % b)
class Tree:
def __init__(self, n, f):
self.base = 1
self.f = f
while self.base < n:
self.base *= 2
self.freq = [0] * (2 * self.base)
def set(self, i, v):
i += self.base
self.freq[i] = v
i //= 2
while i >= 1:
self.freq[i] = self.f(self.freq[2 * i], self.freq[2 * i + 1])
i //= 2
def get(self, l, r):
l += self.base
r += self.base
res = 0
while l <= r:
if l % 2 == 1:
res = self.f(res, self.freq[l])
l += 1
if r % 2 == 0:
res = self.f(res, self.freq[r])
r -= 1
l //= 2
r //= 2
return res
class CounterTree:
def __init__(self, n):
self.base = 1
while self.base < n:
self.base *= 2
self.freq = [Counter() for _ in range(2 * self.base)]
def set(self, i, v):
i += self.base
self.freq[i] = Counter([v])
i //= 2
while i >= 1:
self.freq[i] = self.freq[2 * i] + self.freq[2 * i + 1]
i //= 2
def get(self, l, r, x):
l += self.base
r += self.base
res = 0
while l <= r:
if l % 2 == 1:
res += self.freq[l].get(x, 0)
l += 1
if r % 2 == 0:
res += self.freq[r].get(x, 0)
r -= 1
l //= 2
r //= 2
return res
n = int(input())
s = list(map(int, input().split()))
gcd_tree = Tree(n, gcd)
min_tree = Tree(n, min)
counter_tree = CounterTree(n)
for i in range(n):
gcd_tree.set(i, s[i])
min_tree.set(i, s[i])
counter_tree.set(i, s[i])
t = int(input())
res = []
for _ in range(t):
l, r = map(int, input().split())
l -= 1
r -= 1
g = gcd_tree.get(l, r)
m = min_tree.get(l, r)
if g == m:
res.append(r - l + 1 - counter_tree.get(l, r, m))
else:
res.append(r - l + 1)
print("\n".join(map(str, res)))
``` | instruction | 0 | 21,585 | 11 | 43,170 |
No | output | 1 | 21,585 | 11 | 43,171 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Takahashi is a teacher responsible for a class of N students.
The students are given distinct student numbers from 1 to N.
Today, all the students entered the classroom at different times.
According to Takahashi's record, there were A_i students in the classroom when student number i entered the classroom (including student number i).
From these records, reconstruct the order in which the students entered the classroom.
Constraints
* 1 \le N \le 10^5
* 1 \le A_i \le N
* A_i \neq A_j (i \neq j)
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
N
A_1 A_2 \ldots A_N
Output
Print the student numbers of the students in the order the students entered the classroom.
Examples
Input
3
2 3 1
Output
3 1 2
Input
5
1 2 3 4 5
Output
1 2 3 4 5
Input
8
8 2 7 3 4 5 6 1
Output
8 2 4 5 6 7 3 1
Submitted Solution:
```
n=int(input())
a=list(map(int,input().split()))
d=[0]*n
for i in range(n):
d[a[i]-1]=i+1
print(*d)
``` | instruction | 0 | 21,812 | 11 | 43,624 |
Yes | output | 1 | 21,812 | 11 | 43,625 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Takahashi is a teacher responsible for a class of N students.
The students are given distinct student numbers from 1 to N.
Today, all the students entered the classroom at different times.
According to Takahashi's record, there were A_i students in the classroom when student number i entered the classroom (including student number i).
From these records, reconstruct the order in which the students entered the classroom.
Constraints
* 1 \le N \le 10^5
* 1 \le A_i \le N
* A_i \neq A_j (i \neq j)
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
N
A_1 A_2 \ldots A_N
Output
Print the student numbers of the students in the order the students entered the classroom.
Examples
Input
3
2 3 1
Output
3 1 2
Input
5
1 2 3 4 5
Output
1 2 3 4 5
Input
8
8 2 7 3 4 5 6 1
Output
8 2 4 5 6 7 3 1
Submitted Solution:
```
n=int(input())
l=list(map(int,input().split()))
t=[0]*n
i=1
for e in l:
t[e-1]=str(i)
i+=1
print(' '.join(t))
``` | instruction | 0 | 21,813 | 11 | 43,626 |
Yes | output | 1 | 21,813 | 11 | 43,627 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Takahashi is a teacher responsible for a class of N students.
The students are given distinct student numbers from 1 to N.
Today, all the students entered the classroom at different times.
According to Takahashi's record, there were A_i students in the classroom when student number i entered the classroom (including student number i).
From these records, reconstruct the order in which the students entered the classroom.
Constraints
* 1 \le N \le 10^5
* 1 \le A_i \le N
* A_i \neq A_j (i \neq j)
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
N
A_1 A_2 \ldots A_N
Output
Print the student numbers of the students in the order the students entered the classroom.
Examples
Input
3
2 3 1
Output
3 1 2
Input
5
1 2 3 4 5
Output
1 2 3 4 5
Input
8
8 2 7 3 4 5 6 1
Output
8 2 4 5 6 7 3 1
Submitted Solution:
```
n=int(input())
A=list(map(int,input().split()))
ans=[0]*n
for i in range(n):
ans[A[i]-1]=i+1
print(*ans)
``` | instruction | 0 | 21,814 | 11 | 43,628 |
Yes | output | 1 | 21,814 | 11 | 43,629 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Takahashi is a teacher responsible for a class of N students.
The students are given distinct student numbers from 1 to N.
Today, all the students entered the classroom at different times.
According to Takahashi's record, there were A_i students in the classroom when student number i entered the classroom (including student number i).
From these records, reconstruct the order in which the students entered the classroom.
Constraints
* 1 \le N \le 10^5
* 1 \le A_i \le N
* A_i \neq A_j (i \neq j)
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
N
A_1 A_2 \ldots A_N
Output
Print the student numbers of the students in the order the students entered the classroom.
Examples
Input
3
2 3 1
Output
3 1 2
Input
5
1 2 3 4 5
Output
1 2 3 4 5
Input
8
8 2 7 3 4 5 6 1
Output
8 2 4 5 6 7 3 1
Submitted Solution:
```
n = int(input())
a = list(map(int,input().split()))
b = [0]*(n+1)
for i in range(n):
b[a[i]]=i+1
print(*b[1:])
``` | instruction | 0 | 21,815 | 11 | 43,630 |
Yes | output | 1 | 21,815 | 11 | 43,631 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Takahashi is a teacher responsible for a class of N students.
The students are given distinct student numbers from 1 to N.
Today, all the students entered the classroom at different times.
According to Takahashi's record, there were A_i students in the classroom when student number i entered the classroom (including student number i).
From these records, reconstruct the order in which the students entered the classroom.
Constraints
* 1 \le N \le 10^5
* 1 \le A_i \le N
* A_i \neq A_j (i \neq j)
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
N
A_1 A_2 \ldots A_N
Output
Print the student numbers of the students in the order the students entered the classroom.
Examples
Input
3
2 3 1
Output
3 1 2
Input
5
1 2 3 4 5
Output
1 2 3 4 5
Input
8
8 2 7 3 4 5 6 1
Output
8 2 4 5 6 7 3 1
Submitted Solution:
```
n = int(input())
a = list(map(int,input().split()))
b = []
for i in range(n):
b.append(a.index(i+1)+1)
print(*b)
``` | instruction | 0 | 21,816 | 11 | 43,632 |
No | output | 1 | 21,816 | 11 | 43,633 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Takahashi is a teacher responsible for a class of N students.
The students are given distinct student numbers from 1 to N.
Today, all the students entered the classroom at different times.
According to Takahashi's record, there were A_i students in the classroom when student number i entered the classroom (including student number i).
From these records, reconstruct the order in which the students entered the classroom.
Constraints
* 1 \le N \le 10^5
* 1 \le A_i \le N
* A_i \neq A_j (i \neq j)
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
N
A_1 A_2 \ldots A_N
Output
Print the student numbers of the students in the order the students entered the classroom.
Examples
Input
3
2 3 1
Output
3 1 2
Input
5
1 2 3 4 5
Output
1 2 3 4 5
Input
8
8 2 7 3 4 5 6 1
Output
8 2 4 5 6 7 3 1
Submitted Solution:
```
N = int(input())
A = list(map(int,input().split(" ")))
def bb(N,A):
aa = [str(A.index(x)+1) for x in range(1,N+1)]
print(" ".join(aa))
if __name__ == '__main__':
bb(N,A)
``` | instruction | 0 | 21,817 | 11 | 43,634 |
No | output | 1 | 21,817 | 11 | 43,635 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Takahashi is a teacher responsible for a class of N students.
The students are given distinct student numbers from 1 to N.
Today, all the students entered the classroom at different times.
According to Takahashi's record, there were A_i students in the classroom when student number i entered the classroom (including student number i).
From these records, reconstruct the order in which the students entered the classroom.
Constraints
* 1 \le N \le 10^5
* 1 \le A_i \le N
* A_i \neq A_j (i \neq j)
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
N
A_1 A_2 \ldots A_N
Output
Print the student numbers of the students in the order the students entered the classroom.
Examples
Input
3
2 3 1
Output
3 1 2
Input
5
1 2 3 4 5
Output
1 2 3 4 5
Input
8
8 2 7 3 4 5 6 1
Output
8 2 4 5 6 7 3 1
Submitted Solution:
```
N=int(input())
A = [int(hoge) for hoge in input().split()]
print(*[A.index(j)+1 for j in range(1,N+1)] )
``` | instruction | 0 | 21,818 | 11 | 43,636 |
No | output | 1 | 21,818 | 11 | 43,637 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Takahashi is a teacher responsible for a class of N students.
The students are given distinct student numbers from 1 to N.
Today, all the students entered the classroom at different times.
According to Takahashi's record, there were A_i students in the classroom when student number i entered the classroom (including student number i).
From these records, reconstruct the order in which the students entered the classroom.
Constraints
* 1 \le N \le 10^5
* 1 \le A_i \le N
* A_i \neq A_j (i \neq j)
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
N
A_1 A_2 \ldots A_N
Output
Print the student numbers of the students in the order the students entered the classroom.
Examples
Input
3
2 3 1
Output
3 1 2
Input
5
1 2 3 4 5
Output
1 2 3 4 5
Input
8
8 2 7 3 4 5 6 1
Output
8 2 4 5 6 7 3 1
Submitted Solution:
```
N = int(input())
dic = {}
A = list(map(int, input().split()))
k = []
ANS = []
for i in range(1, N+1):
k.append(i)
dic = dict(zip(k, A))
dic = dict(sorted(dic.items(), key=lambda x:x[1]))
for key in dic:
ANS.append(key)
for b in range(N):
print(ANS[b], end=" \n"[b + 1 == N])
``` | instruction | 0 | 21,819 | 11 | 43,638 |
No | output | 1 | 21,819 | 11 | 43,639 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A balance scale tips to the left if L>R, where L is the total weight of the masses on the left pan and R is the total weight of the masses on the right pan. Similarly, it balances if L=R, and tips to the right if L<R.
Takahashi placed a mass of weight A and a mass of weight B on the left pan of a balance scale, and placed a mass of weight C and a mass of weight D on the right pan.
Print `Left` if the balance scale tips to the left; print `Balanced` if it balances; print `Right` if it tips to the right.
Constraints
* 1\leq A,B,C,D \leq 10
* All input values are integers.
Input
Input is given from Standard Input in the following format:
A B C D
Output
Print `Left` if the balance scale tips to the left; print `Balanced` if it balances; print `Right` if it tips to the right.
Examples
Input
3 8 7 1
Output
Left
Input
3 4 5 2
Output
Balanced
Input
1 7 6 4
Output
Right
Submitted Solution:
```
str = raw_inpur()
print(str)
``` | instruction | 0 | 21,880 | 11 | 43,760 |
No | output | 1 | 21,880 | 11 | 43,761 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Little girl Margarita is a big fan of competitive programming. She especially loves problems about arrays and queries on them.
Recently, she was presented with an array a of the size of 10^9 elements that is filled as follows:
* a_1 = -1
* a_2 = 2
* a_3 = -3
* a_4 = 4
* a_5 = -5
* And so on ...
That is, the value of the i-th element of the array a is calculated using the formula a_i = i ⋅ (-1)^i.
She immediately came up with q queries on this array. Each query is described with two numbers: l and r. The answer to a query is the sum of all the elements of the array at positions from l to r inclusive.
Margarita really wants to know the answer to each of the requests. She doesn't want to count all this manually, but unfortunately, she couldn't write the program that solves the problem either. She has turned to you — the best programmer.
Help her find the answers!
Input
The first line contains a single integer q (1 ≤ q ≤ 10^3) — the number of the queries.
Each of the next q lines contains two integers l and r (1 ≤ l ≤ r ≤ 10^9) — the descriptions of the queries.
Output
Print q lines, each containing one number — the answer to the query.
Example
Input
5
1 3
2 5
5 5
4 4
2 3
Output
-2
-2
-5
4
-1
Note
In the first query, you need to find the sum of the elements of the array from position 1 to position 3. The sum is equal to a_1 + a_2 + a_3 = -1 + 2 -3 = -2.
In the second query, you need to find the sum of the elements of the array from position 2 to position 5. The sum is equal to a_2 + a_3 + a_4 + a_5 = 2 -3 + 4 - 5 = -2.
In the third query, you need to find the sum of the elements of the array from position 5 to position 5. The sum is equal to a_5 = -5.
In the fourth query, you need to find the sum of the elements of the array from position 4 to position 4. The sum is equal to a_4 = 4.
In the fifth query, you need to find the sum of the elements of the array from position 2 to position 3. The sum is equal to a_2 + a_3 = 2 - 3 = -1.
Submitted Solution:
```
def find(l,r):
l = l-1
if l%2 != 0:
lsum = -1*(abs(l)+1)//2
else:
lsum = l//2
if r%2 != 0:
rsum = -1*(abs(r)+1)//2
else:
rsum = r//2
print(rsum-lsum)
def main():
n = int(input())
for _ in range(n):
l,r= map(int,input().split())
find(l,r)
if __name__=="__main__":
main()
``` | instruction | 0 | 22,043 | 11 | 44,086 |
Yes | output | 1 | 22,043 | 11 | 44,087 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Little girl Margarita is a big fan of competitive programming. She especially loves problems about arrays and queries on them.
Recently, she was presented with an array a of the size of 10^9 elements that is filled as follows:
* a_1 = -1
* a_2 = 2
* a_3 = -3
* a_4 = 4
* a_5 = -5
* And so on ...
That is, the value of the i-th element of the array a is calculated using the formula a_i = i ⋅ (-1)^i.
She immediately came up with q queries on this array. Each query is described with two numbers: l and r. The answer to a query is the sum of all the elements of the array at positions from l to r inclusive.
Margarita really wants to know the answer to each of the requests. She doesn't want to count all this manually, but unfortunately, she couldn't write the program that solves the problem either. She has turned to you — the best programmer.
Help her find the answers!
Input
The first line contains a single integer q (1 ≤ q ≤ 10^3) — the number of the queries.
Each of the next q lines contains two integers l and r (1 ≤ l ≤ r ≤ 10^9) — the descriptions of the queries.
Output
Print q lines, each containing one number — the answer to the query.
Example
Input
5
1 3
2 5
5 5
4 4
2 3
Output
-2
-2
-5
4
-1
Note
In the first query, you need to find the sum of the elements of the array from position 1 to position 3. The sum is equal to a_1 + a_2 + a_3 = -1 + 2 -3 = -2.
In the second query, you need to find the sum of the elements of the array from position 2 to position 5. The sum is equal to a_2 + a_3 + a_4 + a_5 = 2 -3 + 4 - 5 = -2.
In the third query, you need to find the sum of the elements of the array from position 5 to position 5. The sum is equal to a_5 = -5.
In the fourth query, you need to find the sum of the elements of the array from position 4 to position 4. The sum is equal to a_4 = 4.
In the fifth query, you need to find the sum of the elements of the array from position 2 to position 3. The sum is equal to a_2 + a_3 = 2 - 3 = -1.
Submitted Solution:
```
import math
n = int(input())
for _c in range(n):
l, r = [int(x) for x in input().split(' ')]
l=l-1
sl = (-(-l // 2)) * ((-1) ** l)
sr = (-(-r // 2)) * ((-1) ** r)
print(sr-sl)
``` | instruction | 0 | 22,044 | 11 | 44,088 |
Yes | output | 1 | 22,044 | 11 | 44,089 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Little girl Margarita is a big fan of competitive programming. She especially loves problems about arrays and queries on them.
Recently, she was presented with an array a of the size of 10^9 elements that is filled as follows:
* a_1 = -1
* a_2 = 2
* a_3 = -3
* a_4 = 4
* a_5 = -5
* And so on ...
That is, the value of the i-th element of the array a is calculated using the formula a_i = i ⋅ (-1)^i.
She immediately came up with q queries on this array. Each query is described with two numbers: l and r. The answer to a query is the sum of all the elements of the array at positions from l to r inclusive.
Margarita really wants to know the answer to each of the requests. She doesn't want to count all this manually, but unfortunately, she couldn't write the program that solves the problem either. She has turned to you — the best programmer.
Help her find the answers!
Input
The first line contains a single integer q (1 ≤ q ≤ 10^3) — the number of the queries.
Each of the next q lines contains two integers l and r (1 ≤ l ≤ r ≤ 10^9) — the descriptions of the queries.
Output
Print q lines, each containing one number — the answer to the query.
Example
Input
5
1 3
2 5
5 5
4 4
2 3
Output
-2
-2
-5
4
-1
Note
In the first query, you need to find the sum of the elements of the array from position 1 to position 3. The sum is equal to a_1 + a_2 + a_3 = -1 + 2 -3 = -2.
In the second query, you need to find the sum of the elements of the array from position 2 to position 5. The sum is equal to a_2 + a_3 + a_4 + a_5 = 2 -3 + 4 - 5 = -2.
In the third query, you need to find the sum of the elements of the array from position 5 to position 5. The sum is equal to a_5 = -5.
In the fourth query, you need to find the sum of the elements of the array from position 4 to position 4. The sum is equal to a_4 = 4.
In the fifth query, you need to find the sum of the elements of the array from position 2 to position 3. The sum is equal to a_2 + a_3 = 2 - 3 = -1.
Submitted Solution:
```
def f(x):
if x%2 == 0:
return x/2
else:
return f(x-1) - x
q = int(input())
while q > 0:
l, r = map(int, input().split())
print(int(f(r)-f(l-1)))
q-=1
``` | instruction | 0 | 22,045 | 11 | 44,090 |
Yes | output | 1 | 22,045 | 11 | 44,091 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Little girl Margarita is a big fan of competitive programming. She especially loves problems about arrays and queries on them.
Recently, she was presented with an array a of the size of 10^9 elements that is filled as follows:
* a_1 = -1
* a_2 = 2
* a_3 = -3
* a_4 = 4
* a_5 = -5
* And so on ...
That is, the value of the i-th element of the array a is calculated using the formula a_i = i ⋅ (-1)^i.
She immediately came up with q queries on this array. Each query is described with two numbers: l and r. The answer to a query is the sum of all the elements of the array at positions from l to r inclusive.
Margarita really wants to know the answer to each of the requests. She doesn't want to count all this manually, but unfortunately, she couldn't write the program that solves the problem either. She has turned to you — the best programmer.
Help her find the answers!
Input
The first line contains a single integer q (1 ≤ q ≤ 10^3) — the number of the queries.
Each of the next q lines contains two integers l and r (1 ≤ l ≤ r ≤ 10^9) — the descriptions of the queries.
Output
Print q lines, each containing one number — the answer to the query.
Example
Input
5
1 3
2 5
5 5
4 4
2 3
Output
-2
-2
-5
4
-1
Note
In the first query, you need to find the sum of the elements of the array from position 1 to position 3. The sum is equal to a_1 + a_2 + a_3 = -1 + 2 -3 = -2.
In the second query, you need to find the sum of the elements of the array from position 2 to position 5. The sum is equal to a_2 + a_3 + a_4 + a_5 = 2 -3 + 4 - 5 = -2.
In the third query, you need to find the sum of the elements of the array from position 5 to position 5. The sum is equal to a_5 = -5.
In the fourth query, you need to find the sum of the elements of the array from position 4 to position 4. The sum is equal to a_4 = 4.
In the fifth query, you need to find the sum of the elements of the array from position 2 to position 3. The sum is equal to a_2 + a_3 = 2 - 3 = -1.
Submitted Solution:
```
q=(int)(input())
for tt in range(q) :
l, r = map(int, input().split())
print(r//2-((r%2)*r)-((l-1)//2-((l-1)%2*(l-1))))
``` | instruction | 0 | 22,046 | 11 | 44,092 |
Yes | output | 1 | 22,046 | 11 | 44,093 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Little girl Margarita is a big fan of competitive programming. She especially loves problems about arrays and queries on them.
Recently, she was presented with an array a of the size of 10^9 elements that is filled as follows:
* a_1 = -1
* a_2 = 2
* a_3 = -3
* a_4 = 4
* a_5 = -5
* And so on ...
That is, the value of the i-th element of the array a is calculated using the formula a_i = i ⋅ (-1)^i.
She immediately came up with q queries on this array. Each query is described with two numbers: l and r. The answer to a query is the sum of all the elements of the array at positions from l to r inclusive.
Margarita really wants to know the answer to each of the requests. She doesn't want to count all this manually, but unfortunately, she couldn't write the program that solves the problem either. She has turned to you — the best programmer.
Help her find the answers!
Input
The first line contains a single integer q (1 ≤ q ≤ 10^3) — the number of the queries.
Each of the next q lines contains two integers l and r (1 ≤ l ≤ r ≤ 10^9) — the descriptions of the queries.
Output
Print q lines, each containing one number — the answer to the query.
Example
Input
5
1 3
2 5
5 5
4 4
2 3
Output
-2
-2
-5
4
-1
Note
In the first query, you need to find the sum of the elements of the array from position 1 to position 3. The sum is equal to a_1 + a_2 + a_3 = -1 + 2 -3 = -2.
In the second query, you need to find the sum of the elements of the array from position 2 to position 5. The sum is equal to a_2 + a_3 + a_4 + a_5 = 2 -3 + 4 - 5 = -2.
In the third query, you need to find the sum of the elements of the array from position 5 to position 5. The sum is equal to a_5 = -5.
In the fourth query, you need to find the sum of the elements of the array from position 4 to position 4. The sum is equal to a_4 = 4.
In the fifth query, you need to find the sum of the elements of the array from position 2 to position 3. The sum is equal to a_2 + a_3 = 2 - 3 = -1.
Submitted Solution:
```
if __name__ =="__main__":
for _ in range(int(input())):
n,k = map(int,input().split())
if n ==k:
print(((-1)**n)*n)
else:
if n%2!=0:
if k%2==0:
sum = k//2
print(sum)
else:
sum = (k-1)//2 + -1*k
print(sum)
else:
if k%2==0:
sum = (-1*k//2)+k
print(sum)
else:
sum = (-1*(k-1)//2)
print(sum)
``` | instruction | 0 | 22,047 | 11 | 44,094 |
No | output | 1 | 22,047 | 11 | 44,095 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Little girl Margarita is a big fan of competitive programming. She especially loves problems about arrays and queries on them.
Recently, she was presented with an array a of the size of 10^9 elements that is filled as follows:
* a_1 = -1
* a_2 = 2
* a_3 = -3
* a_4 = 4
* a_5 = -5
* And so on ...
That is, the value of the i-th element of the array a is calculated using the formula a_i = i ⋅ (-1)^i.
She immediately came up with q queries on this array. Each query is described with two numbers: l and r. The answer to a query is the sum of all the elements of the array at positions from l to r inclusive.
Margarita really wants to know the answer to each of the requests. She doesn't want to count all this manually, but unfortunately, she couldn't write the program that solves the problem either. She has turned to you — the best programmer.
Help her find the answers!
Input
The first line contains a single integer q (1 ≤ q ≤ 10^3) — the number of the queries.
Each of the next q lines contains two integers l and r (1 ≤ l ≤ r ≤ 10^9) — the descriptions of the queries.
Output
Print q lines, each containing one number — the answer to the query.
Example
Input
5
1 3
2 5
5 5
4 4
2 3
Output
-2
-2
-5
4
-1
Note
In the first query, you need to find the sum of the elements of the array from position 1 to position 3. The sum is equal to a_1 + a_2 + a_3 = -1 + 2 -3 = -2.
In the second query, you need to find the sum of the elements of the array from position 2 to position 5. The sum is equal to a_2 + a_3 + a_4 + a_5 = 2 -3 + 4 - 5 = -2.
In the third query, you need to find the sum of the elements of the array from position 5 to position 5. The sum is equal to a_5 = -5.
In the fourth query, you need to find the sum of the elements of the array from position 4 to position 4. The sum is equal to a_4 = 4.
In the fifth query, you need to find the sum of the elements of the array from position 2 to position 3. The sum is equal to a_2 + a_3 = 2 - 3 = -1.
Submitted Solution:
```
# -*- coding: utf-8 -*-
"""
Created on Sat Nov 24 13:37:27 2018
@author: japesh
"""
import math as m
t= int(input())
for _ in range(t):
l,r=map(int,input().split())
if l%2==1:
if r%2==1:
k=r
else:
k=0
ans=int((r-l)/2)-k
else:
if r%2==0:
k=r
else:
k=0
ans=-m.ceil((r-l)/2)+k
print(ans)
``` | instruction | 0 | 22,048 | 11 | 44,096 |
No | output | 1 | 22,048 | 11 | 44,097 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Little girl Margarita is a big fan of competitive programming. She especially loves problems about arrays and queries on them.
Recently, she was presented with an array a of the size of 10^9 elements that is filled as follows:
* a_1 = -1
* a_2 = 2
* a_3 = -3
* a_4 = 4
* a_5 = -5
* And so on ...
That is, the value of the i-th element of the array a is calculated using the formula a_i = i ⋅ (-1)^i.
She immediately came up with q queries on this array. Each query is described with two numbers: l and r. The answer to a query is the sum of all the elements of the array at positions from l to r inclusive.
Margarita really wants to know the answer to each of the requests. She doesn't want to count all this manually, but unfortunately, she couldn't write the program that solves the problem either. She has turned to you — the best programmer.
Help her find the answers!
Input
The first line contains a single integer q (1 ≤ q ≤ 10^3) — the number of the queries.
Each of the next q lines contains two integers l and r (1 ≤ l ≤ r ≤ 10^9) — the descriptions of the queries.
Output
Print q lines, each containing one number — the answer to the query.
Example
Input
5
1 3
2 5
5 5
4 4
2 3
Output
-2
-2
-5
4
-1
Note
In the first query, you need to find the sum of the elements of the array from position 1 to position 3. The sum is equal to a_1 + a_2 + a_3 = -1 + 2 -3 = -2.
In the second query, you need to find the sum of the elements of the array from position 2 to position 5. The sum is equal to a_2 + a_3 + a_4 + a_5 = 2 -3 + 4 - 5 = -2.
In the third query, you need to find the sum of the elements of the array from position 5 to position 5. The sum is equal to a_5 = -5.
In the fourth query, you need to find the sum of the elements of the array from position 4 to position 4. The sum is equal to a_4 = 4.
In the fifth query, you need to find the sum of the elements of the array from position 2 to position 3. The sum is equal to a_2 + a_3 = 2 - 3 = -1.
Submitted Solution:
```
q=int(input())
result=[]
for i in range(q):
l,r=map(int,input().split())
s=0
for j in range(l,r+1):
s+=j*(-1)**j
result.append(str(s))
print(''.join(result))
``` | instruction | 0 | 22,049 | 11 | 44,098 |
No | output | 1 | 22,049 | 11 | 44,099 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Little girl Margarita is a big fan of competitive programming. She especially loves problems about arrays and queries on them.
Recently, she was presented with an array a of the size of 10^9 elements that is filled as follows:
* a_1 = -1
* a_2 = 2
* a_3 = -3
* a_4 = 4
* a_5 = -5
* And so on ...
That is, the value of the i-th element of the array a is calculated using the formula a_i = i ⋅ (-1)^i.
She immediately came up with q queries on this array. Each query is described with two numbers: l and r. The answer to a query is the sum of all the elements of the array at positions from l to r inclusive.
Margarita really wants to know the answer to each of the requests. She doesn't want to count all this manually, but unfortunately, she couldn't write the program that solves the problem either. She has turned to you — the best programmer.
Help her find the answers!
Input
The first line contains a single integer q (1 ≤ q ≤ 10^3) — the number of the queries.
Each of the next q lines contains two integers l and r (1 ≤ l ≤ r ≤ 10^9) — the descriptions of the queries.
Output
Print q lines, each containing one number — the answer to the query.
Example
Input
5
1 3
2 5
5 5
4 4
2 3
Output
-2
-2
-5
4
-1
Note
In the first query, you need to find the sum of the elements of the array from position 1 to position 3. The sum is equal to a_1 + a_2 + a_3 = -1 + 2 -3 = -2.
In the second query, you need to find the sum of the elements of the array from position 2 to position 5. The sum is equal to a_2 + a_3 + a_4 + a_5 = 2 -3 + 4 - 5 = -2.
In the third query, you need to find the sum of the elements of the array from position 5 to position 5. The sum is equal to a_5 = -5.
In the fourth query, you need to find the sum of the elements of the array from position 4 to position 4. The sum is equal to a_4 = 4.
In the fifth query, you need to find the sum of the elements of the array from position 2 to position 3. The sum is equal to a_2 + a_3 = 2 - 3 = -1.
Submitted Solution:
```
def sums(l,r):
if l%2==0 and r%2==0:
n=((r-l)//2)+1
sum1=(n*(2*l+(n-1)*2))//2
l+=1
r-=1
n=((r-l)//2)+1
sum2=(n*(2*l+(n-1)*2))//2
return sum1,sum2
t=int(input())
for x in range(t):
l,r=list(map(int,input().split()))
if r-l<10:
sumi=0
for i in range(l,r+1):
if i%2==0:
sumi+=i
else:
sumi-=i
print(sumi)
continue
sum1=0
sum2=0
if l%2==0 and r%2==0:
sum1,sum2=sums(l,r)
print(sum1-sum2)
elif l%2==0 and r%2==1:
sum22=r
r-=1
sum1,sum2=sums(l,r)
print(sum1,sum2)
print(sum1-sum2-sum22)
elif l%2==1 and r%2==1:
sum22=r+l
l+=1
r-=1
sum1,sum2=sums(l,r)
print(sum1-sum2-sum22)
elif l%2==1 and r%2==0:
sum22=l
l+=1
sum1,sum2=sums(l,r)
print(sum1-sum2-sum22)
``` | instruction | 0 | 22,050 | 11 | 44,100 |
No | output | 1 | 22,050 | 11 | 44,101 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
One day a well-known sponsor of a well-known contest decided to give every participant of the contest a T-shirt as a present. A natural problem occurred: on the one hand, it is not clear how many T-shirts of what sizes should be ordered, and on the other hand, one doesn't want to order too many T-shirts (and we do not exactly paper the walls with the oversupply). After considerable brain racking and some pre-estimating, the sponsor representatives ordered a certain number of T-shirts of sizes S, M, L, XL and XXL. The T-shirts turned out to bring good luck, that's why on the contest day there built up a line of K participants willing to get one. Every contestant is characterized by his/her desired T-shirt size (so it happens that for all the participants it is also one of the sizes S, M, L, XL and XXL). The participants come up to get a T-shirt one by one and try to choose the most suitable one, choosing it like this. If there is still a T-shirt of the optimal size left, that he/she takes it without further ado. Otherwise the contestant would prefer to choose a T-shirt with the size as close to the optimal one as possible (the distance between neighboring sizes is considered equal to one). If the variant of choice is not unique, the contestant will take a T-shirt of a bigger size (in case he/she grows more). For example, for a person whose optimal size is L the preference list looks like this: L, XL, M, XXL, S. Using the data on how many T-shirts of every size had been ordered by the organizers, on the size of contestants in the line determine who got a T-shirt of what size.
Input
The first line contains five non-negative integers NS, NM, NL, NXL, NXXL not exceeding 1000 which represent the number of T-shirts of the corresponding sizes. The second line contains an integer K (1 ≤ K ≤ 1000) which represents the number of participants. The next K lines contain the optimal T-shirt sizes for the contestants. The sizes are given in the order in which the participants stand in the line. It is guaranteed that NS + NM + NL + NXL + NXXL ≥ K.
Output
For each contestant, print a line containing the size of the T-shirt he/she got.
Examples
Input
1 0 2 0 1
3
XL
XXL
M
Output
XXL
L
L
Submitted Solution:
```
n=list(map(int,input().split()))
a={'S':0,'M':1,'L':2,'XL':3,'XXL':4}
b=['S','M','L','XL','XXL']
for i in range(int(input())):
c=a[input()]
for i in range(5):
if c+i<5 and n[c+i]>0:
print(b[c+i])
n[c+i]-=1
break
elif c-i>=0 and n[c-i]>0:
print(b[c-i])
n[c-i]-=1
break
``` | instruction | 0 | 22,448 | 11 | 44,896 |
Yes | output | 1 | 22,448 | 11 | 44,897 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
One day a well-known sponsor of a well-known contest decided to give every participant of the contest a T-shirt as a present. A natural problem occurred: on the one hand, it is not clear how many T-shirts of what sizes should be ordered, and on the other hand, one doesn't want to order too many T-shirts (and we do not exactly paper the walls with the oversupply). After considerable brain racking and some pre-estimating, the sponsor representatives ordered a certain number of T-shirts of sizes S, M, L, XL and XXL. The T-shirts turned out to bring good luck, that's why on the contest day there built up a line of K participants willing to get one. Every contestant is characterized by his/her desired T-shirt size (so it happens that for all the participants it is also one of the sizes S, M, L, XL and XXL). The participants come up to get a T-shirt one by one and try to choose the most suitable one, choosing it like this. If there is still a T-shirt of the optimal size left, that he/she takes it without further ado. Otherwise the contestant would prefer to choose a T-shirt with the size as close to the optimal one as possible (the distance between neighboring sizes is considered equal to one). If the variant of choice is not unique, the contestant will take a T-shirt of a bigger size (in case he/she grows more). For example, for a person whose optimal size is L the preference list looks like this: L, XL, M, XXL, S. Using the data on how many T-shirts of every size had been ordered by the organizers, on the size of contestants in the line determine who got a T-shirt of what size.
Input
The first line contains five non-negative integers NS, NM, NL, NXL, NXXL not exceeding 1000 which represent the number of T-shirts of the corresponding sizes. The second line contains an integer K (1 ≤ K ≤ 1000) which represents the number of participants. The next K lines contain the optimal T-shirt sizes for the contestants. The sizes are given in the order in which the participants stand in the line. It is guaranteed that NS + NM + NL + NXL + NXXL ≥ K.
Output
For each contestant, print a line containing the size of the T-shirt he/she got.
Examples
Input
1 0 2 0 1
3
XL
XXL
M
Output
XXL
L
L
Submitted Solution:
```
#n=int(input())
#n,k = map(int, input().strip().split(' '))
lst = list(map(int, input().strip().split(' ')))
t=int(input())
for j in range(t):
s=input()
if s=='S':
k=0
elif s=='M':
k=1
elif s=='L':
k=2
elif s=='XL':
k=3
elif s=='XXL':
k=4
p=['S','M','L','XL','XXL']
if k==0:
for i in range(5):
if lst[i]>0:
print(p[i])
lst[i]-=1
break
elif k==1:
if lst[k]>0:
lst[k]-=1
print(p[k])
elif lst[k+1]>0:
lst[k+1]-=1
print(p[k+1])
elif lst[k-1]>0:
lst[k-1]-=1
print(p[k-1])
elif lst[k+2]>0:
lst[k+2]-=1
print(p[k+2])
elif lst[k+3]>0:
lst[k+3]-=1
print(p[k+3])
elif k==2:
if lst[k]>0:
lst[k]-=1
print(p[k])
elif lst[k+1]>0:
lst[k+1]-=1
print(p[k+1])
elif lst[k-1]>0:
lst[k-1]-=1
print(p[k-1])
elif lst[k+2]>0:
lst[k+2]-=1
print(p[k+2])
elif lst[k-2]>0:
lst[k-2]-=1
print(p[k-2])
elif k==3:
if lst[k]>0:
lst[k]-=1
print(p[k])
elif lst[k+1]>0:
lst[k+1]-=1
print(p[k+1])
elif lst[k-1]>0:
lst[k-1]-=1
print(p[k-1])
elif lst[k-2]>0:
lst[k-2]-=1
print(p[k-2])
elif lst[k-3]>0:
lst[k-3]-=1
print(p[k-3])
elif k==4:
for i in range(5):
if lst[k-i]>0:
print(p[k-i])
lst[k-i]-=1
break
``` | instruction | 0 | 22,449 | 11 | 44,898 |
Yes | output | 1 | 22,449 | 11 | 44,899 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
One day a well-known sponsor of a well-known contest decided to give every participant of the contest a T-shirt as a present. A natural problem occurred: on the one hand, it is not clear how many T-shirts of what sizes should be ordered, and on the other hand, one doesn't want to order too many T-shirts (and we do not exactly paper the walls with the oversupply). After considerable brain racking and some pre-estimating, the sponsor representatives ordered a certain number of T-shirts of sizes S, M, L, XL and XXL. The T-shirts turned out to bring good luck, that's why on the contest day there built up a line of K participants willing to get one. Every contestant is characterized by his/her desired T-shirt size (so it happens that for all the participants it is also one of the sizes S, M, L, XL and XXL). The participants come up to get a T-shirt one by one and try to choose the most suitable one, choosing it like this. If there is still a T-shirt of the optimal size left, that he/she takes it without further ado. Otherwise the contestant would prefer to choose a T-shirt with the size as close to the optimal one as possible (the distance between neighboring sizes is considered equal to one). If the variant of choice is not unique, the contestant will take a T-shirt of a bigger size (in case he/she grows more). For example, for a person whose optimal size is L the preference list looks like this: L, XL, M, XXL, S. Using the data on how many T-shirts of every size had been ordered by the organizers, on the size of contestants in the line determine who got a T-shirt of what size.
Input
The first line contains five non-negative integers NS, NM, NL, NXL, NXXL not exceeding 1000 which represent the number of T-shirts of the corresponding sizes. The second line contains an integer K (1 ≤ K ≤ 1000) which represents the number of participants. The next K lines contain the optimal T-shirt sizes for the contestants. The sizes are given in the order in which the participants stand in the line. It is guaranteed that NS + NM + NL + NXL + NXXL ≥ K.
Output
For each contestant, print a line containing the size of the T-shirt he/she got.
Examples
Input
1 0 2 0 1
3
XL
XXL
M
Output
XXL
L
L
Submitted Solution:
```
lstarr=list(map(int,input().split()))
k=int(input())
s=[0,1,2,3,4]
m=[1,2,0,3,4]
l=[2,3,1,4,0]
xl=[3,4,2,1,0]
xxl=[4,3,2,1,0]
dct={"S":s,'M':m,"L":l,"XL":xl,"XXL":xxl}
dct1={0:"S",1:"M",2:'L',3:'XL',4:"XXL"}
for i in range(k):
pref=dct[input()]
for j in pref:
if(lstarr[j]>0):
print(dct1[j])
lstarr[j]=lstarr[j]-1
break
``` | instruction | 0 | 22,450 | 11 | 44,900 |
Yes | output | 1 | 22,450 | 11 | 44,901 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
One day a well-known sponsor of a well-known contest decided to give every participant of the contest a T-shirt as a present. A natural problem occurred: on the one hand, it is not clear how many T-shirts of what sizes should be ordered, and on the other hand, one doesn't want to order too many T-shirts (and we do not exactly paper the walls with the oversupply). After considerable brain racking and some pre-estimating, the sponsor representatives ordered a certain number of T-shirts of sizes S, M, L, XL and XXL. The T-shirts turned out to bring good luck, that's why on the contest day there built up a line of K participants willing to get one. Every contestant is characterized by his/her desired T-shirt size (so it happens that for all the participants it is also one of the sizes S, M, L, XL and XXL). The participants come up to get a T-shirt one by one and try to choose the most suitable one, choosing it like this. If there is still a T-shirt of the optimal size left, that he/she takes it without further ado. Otherwise the contestant would prefer to choose a T-shirt with the size as close to the optimal one as possible (the distance between neighboring sizes is considered equal to one). If the variant of choice is not unique, the contestant will take a T-shirt of a bigger size (in case he/she grows more). For example, for a person whose optimal size is L the preference list looks like this: L, XL, M, XXL, S. Using the data on how many T-shirts of every size had been ordered by the organizers, on the size of contestants in the line determine who got a T-shirt of what size.
Input
The first line contains five non-negative integers NS, NM, NL, NXL, NXXL not exceeding 1000 which represent the number of T-shirts of the corresponding sizes. The second line contains an integer K (1 ≤ K ≤ 1000) which represents the number of participants. The next K lines contain the optimal T-shirt sizes for the contestants. The sizes are given in the order in which the participants stand in the line. It is guaranteed that NS + NM + NL + NXL + NXXL ≥ K.
Output
For each contestant, print a line containing the size of the T-shirt he/she got.
Examples
Input
1 0 2 0 1
3
XL
XXL
M
Output
XXL
L
L
Submitted Solution:
```
arr = list(map(int, input().split()))
di = {
'S': arr[0],
'M': arr[1],
'L': arr[2],
'XL': arr[3],
'XXL': arr[4]
}
sdi = {
0: 'S',
1: 'M',
2: 'L',
3: 'XL',
4: 'XXL'
}
ldi = {i:j for j,i in sdi.items()}
k = int(input())
def get_size(size):
sizei = ldi[size] # 0..4
diff = 0
while True:
if sizei + diff < 5 and di[sdi[sizei+diff]] > 0:
di[sdi[sizei+diff]] -= 1
return sdi[sizei+diff]
if sizei - diff >= 0 and di[sdi[sizei-diff]] > 0:
di[sdi[sizei-diff]] -= 1
return sdi[sizei-diff]
diff += 1
for i in range(k):
cur = input()
print(get_size(cur))
"""
0 0 0 0 1
1
S
"""
``` | instruction | 0 | 22,451 | 11 | 44,902 |
Yes | output | 1 | 22,451 | 11 | 44,903 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
One day a well-known sponsor of a well-known contest decided to give every participant of the contest a T-shirt as a present. A natural problem occurred: on the one hand, it is not clear how many T-shirts of what sizes should be ordered, and on the other hand, one doesn't want to order too many T-shirts (and we do not exactly paper the walls with the oversupply). After considerable brain racking and some pre-estimating, the sponsor representatives ordered a certain number of T-shirts of sizes S, M, L, XL and XXL. The T-shirts turned out to bring good luck, that's why on the contest day there built up a line of K participants willing to get one. Every contestant is characterized by his/her desired T-shirt size (so it happens that for all the participants it is also one of the sizes S, M, L, XL and XXL). The participants come up to get a T-shirt one by one and try to choose the most suitable one, choosing it like this. If there is still a T-shirt of the optimal size left, that he/she takes it without further ado. Otherwise the contestant would prefer to choose a T-shirt with the size as close to the optimal one as possible (the distance between neighboring sizes is considered equal to one). If the variant of choice is not unique, the contestant will take a T-shirt of a bigger size (in case he/she grows more). For example, for a person whose optimal size is L the preference list looks like this: L, XL, M, XXL, S. Using the data on how many T-shirts of every size had been ordered by the organizers, on the size of contestants in the line determine who got a T-shirt of what size.
Input
The first line contains five non-negative integers NS, NM, NL, NXL, NXXL not exceeding 1000 which represent the number of T-shirts of the corresponding sizes. The second line contains an integer K (1 ≤ K ≤ 1000) which represents the number of participants. The next K lines contain the optimal T-shirt sizes for the contestants. The sizes are given in the order in which the participants stand in the line. It is guaranteed that NS + NM + NL + NXL + NXXL ≥ K.
Output
For each contestant, print a line containing the size of the T-shirt he/she got.
Examples
Input
1 0 2 0 1
3
XL
XXL
M
Output
XXL
L
L
Submitted Solution:
```
size=list(map(int,input().split()))
st=[]
for i in range(int(input())):
st.append(input())
name=['S','M','L','XL','XXL']
arr=list(map(list,list(zip(name,size))))
dt={'S':0,'M':1,'L':2,'XL':3,'XXL':4}
res=[]
for i in range(len(st)):
if(arr[dt[st[i]]][1]):
arr[dt[st[i]]][1]-=1
res.append(st[i])
else:
s=dt[st[i]]
done,flag=0,0
flag=1 if s==0 or s==4 else 0
while(True):
t=s+1
k=(s+4)%len(arr)
flag=1 if t>=len(arr) or k==0 else flag
if (done or flag):
if done:
break
else:
if(t>=len(arr)):
for l in range(k,-1,-1):
if(arr[l][1]):
arr[l][1]-=1
res.append(arr[l][0])
done=1
break
else:
for l in range(t,len(arr)):
if(arr[l][1]):
arr[l][1]-=1
res.append(arr[l][0])
done=1
break
else:
for l in range(0,2):
j=t if not(l) else k
if(arr[j][1]):
arr[j][1]-=1
res.append(arr[j][0])
done=1
break
s+=1
for i in res:
print(i)
``` | instruction | 0 | 22,452 | 11 | 44,904 |
No | output | 1 | 22,452 | 11 | 44,905 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
One day a well-known sponsor of a well-known contest decided to give every participant of the contest a T-shirt as a present. A natural problem occurred: on the one hand, it is not clear how many T-shirts of what sizes should be ordered, and on the other hand, one doesn't want to order too many T-shirts (and we do not exactly paper the walls with the oversupply). After considerable brain racking and some pre-estimating, the sponsor representatives ordered a certain number of T-shirts of sizes S, M, L, XL and XXL. The T-shirts turned out to bring good luck, that's why on the contest day there built up a line of K participants willing to get one. Every contestant is characterized by his/her desired T-shirt size (so it happens that for all the participants it is also one of the sizes S, M, L, XL and XXL). The participants come up to get a T-shirt one by one and try to choose the most suitable one, choosing it like this. If there is still a T-shirt of the optimal size left, that he/she takes it without further ado. Otherwise the contestant would prefer to choose a T-shirt with the size as close to the optimal one as possible (the distance between neighboring sizes is considered equal to one). If the variant of choice is not unique, the contestant will take a T-shirt of a bigger size (in case he/she grows more). For example, for a person whose optimal size is L the preference list looks like this: L, XL, M, XXL, S. Using the data on how many T-shirts of every size had been ordered by the organizers, on the size of contestants in the line determine who got a T-shirt of what size.
Input
The first line contains five non-negative integers NS, NM, NL, NXL, NXXL not exceeding 1000 which represent the number of T-shirts of the corresponding sizes. The second line contains an integer K (1 ≤ K ≤ 1000) which represents the number of participants. The next K lines contain the optimal T-shirt sizes for the contestants. The sizes are given in the order in which the participants stand in the line. It is guaranteed that NS + NM + NL + NXL + NXXL ≥ K.
Output
For each contestant, print a line containing the size of the T-shirt he/she got.
Examples
Input
1 0 2 0 1
3
XL
XXL
M
Output
XXL
L
L
Submitted Solution:
```
# http://codeforces.com/contest/46/problem/B
shirt = input().strip().split()
k = int(input())
prefarence = []
for i in range(0,k):
prefarence.append(input())
count = 0
for i in range(0,len(shirt)):
shirt[i] = int(shirt[i])
count = count + shirt[i]
def size_to_number(x):
if(x=="S"):
return 0
elif(x=="M"):
return 1
elif(x=="L"):
return 2
elif(x=="XL"):
return 3
elif(x=="XXL"):
return 4
def number_to_size(x):
if(x==0):
return "S"
elif(x==1):
return "M"
elif(x==2):
return "L"
elif(x==3):
return "XL"
elif(x==4):
return "XXL"
for x in prefarence:
if(shirt[size_to_number(x)] > 0):
print (x)
shirt[size_to_number(x)] = shirt[size_to_number(x)] - 1
else:
for i in range(1,4):
if (size_to_number(x) + i < len(shirt)):
if(shirt[size_to_number(x) + i] > 0):
print (number_to_size(size_to_number(x) + i))
shirt[size_to_number(x) + i] = shirt[size_to_number(x) + i] - 1
break
elif (size_to_number(x) - i >= 0):
if(shirt[size_to_number(x) - i] > 0):
print (number_to_size(size_to_number(x) - i))
shirt[size_to_number(x) - i] = shirt[size_to_number(x) - i] - 1
break
``` | instruction | 0 | 22,453 | 11 | 44,906 |
No | output | 1 | 22,453 | 11 | 44,907 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
One day a well-known sponsor of a well-known contest decided to give every participant of the contest a T-shirt as a present. A natural problem occurred: on the one hand, it is not clear how many T-shirts of what sizes should be ordered, and on the other hand, one doesn't want to order too many T-shirts (and we do not exactly paper the walls with the oversupply). After considerable brain racking and some pre-estimating, the sponsor representatives ordered a certain number of T-shirts of sizes S, M, L, XL and XXL. The T-shirts turned out to bring good luck, that's why on the contest day there built up a line of K participants willing to get one. Every contestant is characterized by his/her desired T-shirt size (so it happens that for all the participants it is also one of the sizes S, M, L, XL and XXL). The participants come up to get a T-shirt one by one and try to choose the most suitable one, choosing it like this. If there is still a T-shirt of the optimal size left, that he/she takes it without further ado. Otherwise the contestant would prefer to choose a T-shirt with the size as close to the optimal one as possible (the distance between neighboring sizes is considered equal to one). If the variant of choice is not unique, the contestant will take a T-shirt of a bigger size (in case he/she grows more). For example, for a person whose optimal size is L the preference list looks like this: L, XL, M, XXL, S. Using the data on how many T-shirts of every size had been ordered by the organizers, on the size of contestants in the line determine who got a T-shirt of what size.
Input
The first line contains five non-negative integers NS, NM, NL, NXL, NXXL not exceeding 1000 which represent the number of T-shirts of the corresponding sizes. The second line contains an integer K (1 ≤ K ≤ 1000) which represents the number of participants. The next K lines contain the optimal T-shirt sizes for the contestants. The sizes are given in the order in which the participants stand in the line. It is guaranteed that NS + NM + NL + NXL + NXXL ≥ K.
Output
For each contestant, print a line containing the size of the T-shirt he/she got.
Examples
Input
1 0 2 0 1
3
XL
XXL
M
Output
XXL
L
L
Submitted Solution:
```
names = ['S', 'M', 'L', 'XL', 'XXL']
n = [int(x) for x in input().split()]
k = int(input())
for i in range(k):
p = names.index(input())
if n[p] > 0:
print(names[p])
else:
for i in range(5):
t = p + i
if t < 5 and n[t] > 0:
print(names[t])
n[t] -= 1
break
t = p - i
if t >= 0 and n[t] > 0:
print(names[t])
n[t] -= 1
break
``` | instruction | 0 | 22,454 | 11 | 44,908 |
No | output | 1 | 22,454 | 11 | 44,909 |
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