message stringlengths 2 39.6k | message_type stringclasses 2 values | message_id int64 0 1 | conversation_id int64 219 108k | cluster float64 11 11 | __index_level_0__ int64 438 217k |
|---|---|---|---|---|---|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You will be given a contest schedule for D days and M queries of schedule modification. In the i-th query, given integers d_i and q_i, change the type of contest to be held on day d_i to q_i, and then output the final satisfaction at the end of day D on the updated schedule. Note that we do not revert each query. That is, the i-th query is applied to the new schedule obtained by the (i-1)-th query.
Input
Input is given from Standard Input in the form of the input of Problem A followed by the output of Problem A and the queries.
D
c_1 c_2 \cdots c_{26}
s_{1,1} s_{1,2} \cdots s_{1,26}
\vdots
s_{D,1} s_{D,2} \cdots s_{D,26}
t_1
t_2
\vdots
t_D
M
d_1 q_1
d_2 q_2
\vdots
d_M q_M
* The constraints and generation methods for the input part are the same as those for Problem A.
* For each d=1,\ldots,D, t_d is an integer generated independently and uniformly at random from {1,2,\ldots,26}.
* The number of queries M is an integer satisfying 1\leq M\leq 10^5.
* For each i=1,\ldots,M, d_i is an integer generated independently and uniformly at random from {1,2,\ldots,D}.
* For each i=1,\ldots,26, q_i is an integer satisfying 1\leq q_i\leq 26 generated uniformly at random from the 25 values that differ from the type of contest on day d_i.
Output
Let v_i be the final satisfaction at the end of day D on the schedule after applying the i-th query. Print M integers v_i to Standard Output in the following format:
v_1
v_2
\vdots
v_M
Output
Let v_i be the final satisfaction at the end of day D on the schedule after applying the i-th query. Print M integers v_i to Standard Output in the following format:
v_1
v_2
\vdots
v_M
Example
Input
5
86 90 69 51 2 96 71 47 88 34 45 46 89 34 31 38 97 84 41 80 14 4 50 83 7 82
19771 12979 18912 10432 10544 12928 13403 3047 10527 9740 8100 92 2856 14730 1396 15905 6534 4650 11469 3628 8433 2994 10899 16396 18355 11424
6674 17707 13855 16407 12232 2886 11908 1705 5000 1537 10440 10711 4917 10770 17272 15364 19277 18094 3929 3705 7169 6159 18683 15410 9092 4570
6878 4239 19925 1799 375 9563 3445 5658 19857 11401 6997 6498 19933 3848 2426 2146 19745 16880 17773 18359 3921 14172 16730 11157 5439 256
8633 15862 15303 10749 18499 7792 10317 5901 9395 11433 3514 3959 5202 19850 19469 9790 5653 784 18500 10552 17975 16615 7852 197 8471 7452
19855 17918 7990 10572 4333 438 9140 9104 12622 4985 12319 4028 19922 12132 16259 17476 2976 547 19195 19830 16285 4806 4471 9457 2864 2192
1
17
13
14
13
5
1 7
4 11
3 4
5 24
4 19
Output
72882
56634
38425
27930
42884
Submitted Solution:
```
def calcScore():
for d in range(1, D + 1):
id = t[d] # この日に開催するコンテスト
sinceLast[d][id] = 0
score[d][id] = s[d][id]
for i in range(1, 26 + 1):
if i == id: continue
sinceLast[d][i] = sinceLast[d - 1][i] + 1
score[d][i] = -c[i] * sinceLast[d][i]
ans = 0
for d in range(1, D + 1):
ans += sum(score[d])
return ans
def calcScoreDiff(score, d, before, after):
ans = 0
for dd in range(d, D + 1):
if dd > d and t[dd] == before: break
sinceLast[dd][before] = sinceLast[dd - 1][before] + 1
ans -= score[dd][before]
score[dd][before] = -c[before] * sinceLast[dd][before]
ans += score[dd][before]
ans -= score[d][after]
sinceLast[d][after] = 0
score[d][after] = s[d][after]
ans += score[d][after]
for dd in range(d + 1, D + 1):
if t[dd] == after: break
sinceLast[dd][after] = sinceLast[dd - 1][after] + 1
ans -= score[dd][after]
score[dd][after] = -c[after] * sinceLast[dd][after]
ans += score[dd][after]
return ans
D = int(input())
c = [0] + [int(x) for x in input().split()]
s = [[0 for _ in range(26 + 1)]] + \
[[0] + [int(x) for x in input().split()] for _ in range(D)]
t = [0] + [int(input()) for _ in range(D)]
score = [[0] * (26 + 1) for _ in range(D + 1)]
sinceLast = [[0] * (26 + 1) for _ in range(D + 1)]
tot = calcScore()
M = int(input())
for i in range(M):
d, after = [int(x) for x in input().split()]
before = t[d]
t[d] = after
diff = calcScoreDiff(score, d, before, after)
tot += diff
print(tot)
``` | instruction | 0 | 26,245 | 11 | 52,490 |
Yes | output | 1 | 26,245 | 11 | 52,491 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You will be given a contest schedule for D days and M queries of schedule modification. In the i-th query, given integers d_i and q_i, change the type of contest to be held on day d_i to q_i, and then output the final satisfaction at the end of day D on the updated schedule. Note that we do not revert each query. That is, the i-th query is applied to the new schedule obtained by the (i-1)-th query.
Input
Input is given from Standard Input in the form of the input of Problem A followed by the output of Problem A and the queries.
D
c_1 c_2 \cdots c_{26}
s_{1,1} s_{1,2} \cdots s_{1,26}
\vdots
s_{D,1} s_{D,2} \cdots s_{D,26}
t_1
t_2
\vdots
t_D
M
d_1 q_1
d_2 q_2
\vdots
d_M q_M
* The constraints and generation methods for the input part are the same as those for Problem A.
* For each d=1,\ldots,D, t_d is an integer generated independently and uniformly at random from {1,2,\ldots,26}.
* The number of queries M is an integer satisfying 1\leq M\leq 10^5.
* For each i=1,\ldots,M, d_i is an integer generated independently and uniformly at random from {1,2,\ldots,D}.
* For each i=1,\ldots,26, q_i is an integer satisfying 1\leq q_i\leq 26 generated uniformly at random from the 25 values that differ from the type of contest on day d_i.
Output
Let v_i be the final satisfaction at the end of day D on the schedule after applying the i-th query. Print M integers v_i to Standard Output in the following format:
v_1
v_2
\vdots
v_M
Output
Let v_i be the final satisfaction at the end of day D on the schedule after applying the i-th query. Print M integers v_i to Standard Output in the following format:
v_1
v_2
\vdots
v_M
Example
Input
5
86 90 69 51 2 96 71 47 88 34 45 46 89 34 31 38 97 84 41 80 14 4 50 83 7 82
19771 12979 18912 10432 10544 12928 13403 3047 10527 9740 8100 92 2856 14730 1396 15905 6534 4650 11469 3628 8433 2994 10899 16396 18355 11424
6674 17707 13855 16407 12232 2886 11908 1705 5000 1537 10440 10711 4917 10770 17272 15364 19277 18094 3929 3705 7169 6159 18683 15410 9092 4570
6878 4239 19925 1799 375 9563 3445 5658 19857 11401 6997 6498 19933 3848 2426 2146 19745 16880 17773 18359 3921 14172 16730 11157 5439 256
8633 15862 15303 10749 18499 7792 10317 5901 9395 11433 3514 3959 5202 19850 19469 9790 5653 784 18500 10552 17975 16615 7852 197 8471 7452
19855 17918 7990 10572 4333 438 9140 9104 12622 4985 12319 4028 19922 12132 16259 17476 2976 547 19195 19830 16285 4806 4471 9457 2864 2192
1
17
13
14
13
5
1 7
4 11
3 4
5 24
4 19
Output
72882
56634
38425
27930
42884
Submitted Solution:
```
import sys
def input(): return sys.stdin.readline().strip()
def list2d(a, b, c): return [[c] * b for i in range(a)]
def list3d(a, b, c, d): return [[[d] * c for j in range(b)] for i in range(a)]
def list4d(a, b, c, d, e): return [[[[e] * d for j in range(c)] for j in range(b)] for i in range(a)]
def ceil(x, y=1): return int(-(-x // y))
def INT(): return int(input())
def MAP(): return map(int, input().split())
def LIST(N=None): return list(MAP()) if N is None else [INT() for i in range(N)]
def Yes(): print('Yes')
def No(): print('No')
def YES(): print('YES')
def NO(): print('NO')
sys.setrecursionlimit(10 ** 9)
INF = 10 ** 19
MOD = 10 ** 9 + 7
EPS = 10 ** -10
D = INT()
C = LIST()
S = [[]] * (D+1)
for i in range(1, D+1):
S[i] = LIST()
T = [0] + [t-1 for t in LIST(D)]
M = 26
last = list2d(M, D+2, 0)
def check(T):
score = 0
for i, t in enumerate(T[1:], 1):
score += S[i][t]
for j in range(M):
last[j][i] = last[j][i-1] + 1
last[t][i] = 0
for j in range(M):
score -= C[j] * last[j][i]
return score
def change(day, a, b):
nxtday = last[a].index(0, day+1)
w = nxtday - day
h = last[a][day-1] + 1
a_change = C[a] * h * w
for d in range(day, nxtday):
last[a][d] = last[a][d-1] + 1
nxtday = last[b].index(0, day+1)
w = nxtday - day
h = last[b][day-1] + 1
b_change = C[b] * h * w
last[b][day] = 0
for d in range(day+1, nxtday):
last[b][d] = last[b][d-1] + 1
res = -a_change + b_change - S[day][a] + S[day][b]
return res
score = check(T)
Q = INT()
for i in range(Q):
d, q = MAP()
q -= 1
prev = T[d]
nxt = q
score += change(d, prev, nxt)
print(score)
T[d] = q
``` | instruction | 0 | 26,246 | 11 | 52,492 |
Yes | output | 1 | 26,246 | 11 | 52,493 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You will be given a contest schedule for D days and M queries of schedule modification. In the i-th query, given integers d_i and q_i, change the type of contest to be held on day d_i to q_i, and then output the final satisfaction at the end of day D on the updated schedule. Note that we do not revert each query. That is, the i-th query is applied to the new schedule obtained by the (i-1)-th query.
Input
Input is given from Standard Input in the form of the input of Problem A followed by the output of Problem A and the queries.
D
c_1 c_2 \cdots c_{26}
s_{1,1} s_{1,2} \cdots s_{1,26}
\vdots
s_{D,1} s_{D,2} \cdots s_{D,26}
t_1
t_2
\vdots
t_D
M
d_1 q_1
d_2 q_2
\vdots
d_M q_M
* The constraints and generation methods for the input part are the same as those for Problem A.
* For each d=1,\ldots,D, t_d is an integer generated independently and uniformly at random from {1,2,\ldots,26}.
* The number of queries M is an integer satisfying 1\leq M\leq 10^5.
* For each i=1,\ldots,M, d_i is an integer generated independently and uniformly at random from {1,2,\ldots,D}.
* For each i=1,\ldots,26, q_i is an integer satisfying 1\leq q_i\leq 26 generated uniformly at random from the 25 values that differ from the type of contest on day d_i.
Output
Let v_i be the final satisfaction at the end of day D on the schedule after applying the i-th query. Print M integers v_i to Standard Output in the following format:
v_1
v_2
\vdots
v_M
Output
Let v_i be the final satisfaction at the end of day D on the schedule after applying the i-th query. Print M integers v_i to Standard Output in the following format:
v_1
v_2
\vdots
v_M
Example
Input
5
86 90 69 51 2 96 71 47 88 34 45 46 89 34 31 38 97 84 41 80 14 4 50 83 7 82
19771 12979 18912 10432 10544 12928 13403 3047 10527 9740 8100 92 2856 14730 1396 15905 6534 4650 11469 3628 8433 2994 10899 16396 18355 11424
6674 17707 13855 16407 12232 2886 11908 1705 5000 1537 10440 10711 4917 10770 17272 15364 19277 18094 3929 3705 7169 6159 18683 15410 9092 4570
6878 4239 19925 1799 375 9563 3445 5658 19857 11401 6997 6498 19933 3848 2426 2146 19745 16880 17773 18359 3921 14172 16730 11157 5439 256
8633 15862 15303 10749 18499 7792 10317 5901 9395 11433 3514 3959 5202 19850 19469 9790 5653 784 18500 10552 17975 16615 7852 197 8471 7452
19855 17918 7990 10572 4333 438 9140 9104 12622 4985 12319 4028 19922 12132 16259 17476 2976 547 19195 19830 16285 4806 4471 9457 2864 2192
1
17
13
14
13
5
1 7
4 11
3 4
5 24
4 19
Output
72882
56634
38425
27930
42884
Submitted Solution:
```
D=int(input())
c=input().split()
c=[int(a) for a in c]
S=[]
for _ in range(D):
s=input().split()
s=[int(a) for a in s]
S.append(s)
T=[]
for _ in range(D):
t=int(input())-1
T.append(t)
M=int(input())
numbers=[]
for _ in range(M):
d,q=map(int,input().split())
numbers.append([d,q])
for m in range(M):
ans = 0
held = [0 for _ in range(26)]
e=numbers[m][0]-1
q=numbers[m][1]-1
a=T[e]
T[e]=q
for d in range(D):
s = S[d]
place = T[d]
held[place] = d + 1
ans += s[place]
for n in range(26):
ans -= c[n] * (d + 1 - held[n])
print(ans)
``` | instruction | 0 | 26,247 | 11 | 52,494 |
No | output | 1 | 26,247 | 11 | 52,495 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You will be given a contest schedule for D days and M queries of schedule modification. In the i-th query, given integers d_i and q_i, change the type of contest to be held on day d_i to q_i, and then output the final satisfaction at the end of day D on the updated schedule. Note that we do not revert each query. That is, the i-th query is applied to the new schedule obtained by the (i-1)-th query.
Input
Input is given from Standard Input in the form of the input of Problem A followed by the output of Problem A and the queries.
D
c_1 c_2 \cdots c_{26}
s_{1,1} s_{1,2} \cdots s_{1,26}
\vdots
s_{D,1} s_{D,2} \cdots s_{D,26}
t_1
t_2
\vdots
t_D
M
d_1 q_1
d_2 q_2
\vdots
d_M q_M
* The constraints and generation methods for the input part are the same as those for Problem A.
* For each d=1,\ldots,D, t_d is an integer generated independently and uniformly at random from {1,2,\ldots,26}.
* The number of queries M is an integer satisfying 1\leq M\leq 10^5.
* For each i=1,\ldots,M, d_i is an integer generated independently and uniformly at random from {1,2,\ldots,D}.
* For each i=1,\ldots,26, q_i is an integer satisfying 1\leq q_i\leq 26 generated uniformly at random from the 25 values that differ from the type of contest on day d_i.
Output
Let v_i be the final satisfaction at the end of day D on the schedule after applying the i-th query. Print M integers v_i to Standard Output in the following format:
v_1
v_2
\vdots
v_M
Output
Let v_i be the final satisfaction at the end of day D on the schedule after applying the i-th query. Print M integers v_i to Standard Output in the following format:
v_1
v_2
\vdots
v_M
Example
Input
5
86 90 69 51 2 96 71 47 88 34 45 46 89 34 31 38 97 84 41 80 14 4 50 83 7 82
19771 12979 18912 10432 10544 12928 13403 3047 10527 9740 8100 92 2856 14730 1396 15905 6534 4650 11469 3628 8433 2994 10899 16396 18355 11424
6674 17707 13855 16407 12232 2886 11908 1705 5000 1537 10440 10711 4917 10770 17272 15364 19277 18094 3929 3705 7169 6159 18683 15410 9092 4570
6878 4239 19925 1799 375 9563 3445 5658 19857 11401 6997 6498 19933 3848 2426 2146 19745 16880 17773 18359 3921 14172 16730 11157 5439 256
8633 15862 15303 10749 18499 7792 10317 5901 9395 11433 3514 3959 5202 19850 19469 9790 5653 784 18500 10552 17975 16615 7852 197 8471 7452
19855 17918 7990 10572 4333 438 9140 9104 12622 4985 12319 4028 19922 12132 16259 17476 2976 547 19195 19830 16285 4806 4471 9457 2864 2192
1
17
13
14
13
5
1 7
4 11
3 4
5 24
4 19
Output
72882
56634
38425
27930
42884
Submitted Solution:
```
D = int(input())#D=365
c = list(map(int, input().split()))#0<=c<=100
s = [list(map(int, input().split())) for _ in range(D)]#0<=s<=20000
t = [int(input()) for _ in range(D)]
M = int(input())
dq = [list(map(int, input().split())) for _ in range(M)]
def culc_value(t):
last = [0] * 26
value = 0
for d in range(D):
type = t[d]
value += s[d][type - 1]
last[type - 1] = d + 1
for i in range(26):
value -= c[i] * (d + 1 - last[i])
return value
v_lastday = []
for d, q in dq:
t[d - 1] = q
v_lastday.append(culc_value(t))
for x in v_lastday:
print(x)
"""
for i in range(D):
print(v[i])
"""
``` | instruction | 0 | 26,248 | 11 | 52,496 |
No | output | 1 | 26,248 | 11 | 52,497 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You will be given a contest schedule for D days and M queries of schedule modification. In the i-th query, given integers d_i and q_i, change the type of contest to be held on day d_i to q_i, and then output the final satisfaction at the end of day D on the updated schedule. Note that we do not revert each query. That is, the i-th query is applied to the new schedule obtained by the (i-1)-th query.
Input
Input is given from Standard Input in the form of the input of Problem A followed by the output of Problem A and the queries.
D
c_1 c_2 \cdots c_{26}
s_{1,1} s_{1,2} \cdots s_{1,26}
\vdots
s_{D,1} s_{D,2} \cdots s_{D,26}
t_1
t_2
\vdots
t_D
M
d_1 q_1
d_2 q_2
\vdots
d_M q_M
* The constraints and generation methods for the input part are the same as those for Problem A.
* For each d=1,\ldots,D, t_d is an integer generated independently and uniformly at random from {1,2,\ldots,26}.
* The number of queries M is an integer satisfying 1\leq M\leq 10^5.
* For each i=1,\ldots,M, d_i is an integer generated independently and uniformly at random from {1,2,\ldots,D}.
* For each i=1,\ldots,26, q_i is an integer satisfying 1\leq q_i\leq 26 generated uniformly at random from the 25 values that differ from the type of contest on day d_i.
Output
Let v_i be the final satisfaction at the end of day D on the schedule after applying the i-th query. Print M integers v_i to Standard Output in the following format:
v_1
v_2
\vdots
v_M
Output
Let v_i be the final satisfaction at the end of day D on the schedule after applying the i-th query. Print M integers v_i to Standard Output in the following format:
v_1
v_2
\vdots
v_M
Example
Input
5
86 90 69 51 2 96 71 47 88 34 45 46 89 34 31 38 97 84 41 80 14 4 50 83 7 82
19771 12979 18912 10432 10544 12928 13403 3047 10527 9740 8100 92 2856 14730 1396 15905 6534 4650 11469 3628 8433 2994 10899 16396 18355 11424
6674 17707 13855 16407 12232 2886 11908 1705 5000 1537 10440 10711 4917 10770 17272 15364 19277 18094 3929 3705 7169 6159 18683 15410 9092 4570
6878 4239 19925 1799 375 9563 3445 5658 19857 11401 6997 6498 19933 3848 2426 2146 19745 16880 17773 18359 3921 14172 16730 11157 5439 256
8633 15862 15303 10749 18499 7792 10317 5901 9395 11433 3514 3959 5202 19850 19469 9790 5653 784 18500 10552 17975 16615 7852 197 8471 7452
19855 17918 7990 10572 4333 438 9140 9104 12622 4985 12319 4028 19922 12132 16259 17476 2976 547 19195 19830 16285 4806 4471 9457 2864 2192
1
17
13
14
13
5
1 7
4 11
3 4
5 24
4 19
Output
72882
56634
38425
27930
42884
Submitted Solution:
```
def c_incremental_scoring():
"""B 問題の入力と、追加で「d 日目のコンテストのタイプを q に変更するクエリ」が
与えられるので、それに基づいて日毎の満足度を計算せよ。
(A 問題では (大雑把に言って) クエリをうまく与えて満足度を可能な限り高くしていく)"""
D = int(input())
Contests = [int(i) for i in input().split()]
Satisfaction = [[int(i) for i in input().split()] for j in range(D)]
Contest_type = [int(input()) for _ in range(D)]
M = int(input())
Queries = [[int(i) for i in input().split()] for j in range(M)]
ans = []
s = 0
last = {i: 0 for i in range(1, 27)}
for d, q in Queries:
Contest_type[d - 1] = q
for d, t in enumerate(Contest_type, 1):
print(d, t)
s += Satisfaction[d - 1][t - 1]
last[t] = d
satisfaction_decreasing = 0
for i in range(1, 27):
satisfaction_decreasing += Contests[i - 1] * (d - last[i])
s -= satisfaction_decreasing
ans.append(s)
return '\n'.join(map(str, ans))
print(c_incremental_scoring())
``` | instruction | 0 | 26,249 | 11 | 52,498 |
No | output | 1 | 26,249 | 11 | 52,499 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You will be given a contest schedule for D days and M queries of schedule modification. In the i-th query, given integers d_i and q_i, change the type of contest to be held on day d_i to q_i, and then output the final satisfaction at the end of day D on the updated schedule. Note that we do not revert each query. That is, the i-th query is applied to the new schedule obtained by the (i-1)-th query.
Input
Input is given from Standard Input in the form of the input of Problem A followed by the output of Problem A and the queries.
D
c_1 c_2 \cdots c_{26}
s_{1,1} s_{1,2} \cdots s_{1,26}
\vdots
s_{D,1} s_{D,2} \cdots s_{D,26}
t_1
t_2
\vdots
t_D
M
d_1 q_1
d_2 q_2
\vdots
d_M q_M
* The constraints and generation methods for the input part are the same as those for Problem A.
* For each d=1,\ldots,D, t_d is an integer generated independently and uniformly at random from {1,2,\ldots,26}.
* The number of queries M is an integer satisfying 1\leq M\leq 10^5.
* For each i=1,\ldots,M, d_i is an integer generated independently and uniformly at random from {1,2,\ldots,D}.
* For each i=1,\ldots,26, q_i is an integer satisfying 1\leq q_i\leq 26 generated uniformly at random from the 25 values that differ from the type of contest on day d_i.
Output
Let v_i be the final satisfaction at the end of day D on the schedule after applying the i-th query. Print M integers v_i to Standard Output in the following format:
v_1
v_2
\vdots
v_M
Output
Let v_i be the final satisfaction at the end of day D on the schedule after applying the i-th query. Print M integers v_i to Standard Output in the following format:
v_1
v_2
\vdots
v_M
Example
Input
5
86 90 69 51 2 96 71 47 88 34 45 46 89 34 31 38 97 84 41 80 14 4 50 83 7 82
19771 12979 18912 10432 10544 12928 13403 3047 10527 9740 8100 92 2856 14730 1396 15905 6534 4650 11469 3628 8433 2994 10899 16396 18355 11424
6674 17707 13855 16407 12232 2886 11908 1705 5000 1537 10440 10711 4917 10770 17272 15364 19277 18094 3929 3705 7169 6159 18683 15410 9092 4570
6878 4239 19925 1799 375 9563 3445 5658 19857 11401 6997 6498 19933 3848 2426 2146 19745 16880 17773 18359 3921 14172 16730 11157 5439 256
8633 15862 15303 10749 18499 7792 10317 5901 9395 11433 3514 3959 5202 19850 19469 9790 5653 784 18500 10552 17975 16615 7852 197 8471 7452
19855 17918 7990 10572 4333 438 9140 9104 12622 4985 12319 4028 19922 12132 16259 17476 2976 547 19195 19830 16285 4806 4471 9457 2864 2192
1
17
13
14
13
5
1 7
4 11
3 4
5 24
4 19
Output
72882
56634
38425
27930
42884
Submitted Solution:
```
D = int(input())
C = list(map(int ,input().split()))
S = [list(map(int, input().split())) for i in range(D)]
sumc = sum(C)
last = [0 for i in range(26)]
check = [0 for i in range(26)]
con = []
ans = 0
for i in range(D):
t = int(input())
last[t-1] = i+1
ans += S[i][t-1]
check[t-1] += 1
con.append(t)
for j in range(26):
ans -= C[j]*(i+1 - last[j])
M = int(input())
for i in range(M):
d, q = map(int, input().split())
e = con[d-1] #i日目にやるコンテスト
l1 = 0
l2 = 0
tmpe = 0
tmpq = 0
f1 = D
f2 = D
for j in range(D):
if check[e-1] == 0 and check[q-1] == 0:
break
if tmpe == 0 and tmpq == 0:
break
if j < d-1:
if con[j] == e:
l1 = j #変更前のコンテストを直前の最後にいつやったか
if con[j] == q:
l2 = j #変更後のコンテストを直前の最後にいつやったか
if j > d-1:
if con[j] == e and tmpe == 0:
f1 = j #変更前のコンテストを直後にいつやったか
tmpe = 1
if con[j] == q and tmpq == 0:
f2 = j #変更後のコンテストを直後にいつやったか
tmpq = 1
con[d-1] = q
check[e-1] -= 1
check[q-1] += 1
ans = ans - S[d-1][e-1] + S[d-1][q-1] + C[q-1]*(f2-d+1)*(d-l2-1) - C[e-1]*(f1-d+1)*(d-l1-1)
print(ans)
``` | instruction | 0 | 26,250 | 11 | 52,500 |
No | output | 1 | 26,250 | 11 | 52,501 |
Provide a correct Python 3 solution for this coding contest problem.
Selection of Participants of an Experiment
Dr. Tsukuba has devised a new method of programming training. In order to evaluate the effectiveness of this method, he plans to carry out a control experiment. Having two students as the participants of the experiment, one of them will be trained under the conventional method and the other under his new method. Comparing the final scores of these two, he will be able to judge the effectiveness of his method.
It is important to select two students having the closest possible scores, for making the comparison fair. He has a list of the scores of all students who can participate in the experiment. You are asked to write a program which selects two of them having the smallest difference in their scores.
Input
The input consists of multiple datasets, each in the following format.
n
a1 a2 … an
A dataset consists of two lines. The number of students n is given in the first line. n is an integer satisfying 2 ≤ n ≤ 1000. The second line gives scores of n students. ai (1 ≤ i ≤ n) is the score of the i-th student, which is a non-negative integer not greater than 1,000,000.
The end of the input is indicated by a line containing a zero. The sum of n's of all the datasets does not exceed 50,000.
Output
For each dataset, select two students with the smallest difference in their scores, and output in a line (the absolute value of) the difference.
Sample Input
5
10 10 10 10 10
5
1 5 8 9 11
7
11 34 83 47 59 29 70
0
Output for the Sample Input
0
1
5
Example
Input
5
10 10 10 10 10
5
1 5 8 9 11
7
11 34 83 47 59 29 70
0
Output
0
1
5 | instruction | 0 | 26,452 | 11 | 52,904 |
"Correct Solution:
```
import sys
import re
from collections import deque, defaultdict, Counter
from math import ceil, sqrt, hypot, factorial, pi, sin, cos, radians, log2,gcd
from itertools import permutations, combinations, product
from operator import itemgetter, mul
from copy import deepcopy
from string import ascii_lowercase, ascii_uppercase, digits
def input(): return sys.stdin.readline().strip()
def INT(): return int(input())
def MAP(): return map(int, input().split())
def LIST(): return list(map(int, input().split()))
sys.setrecursionlimit(10 ** 9)
INF = float('inf')
mod = 10 ** 9 + 7
def main():
ans=[]
while 1:
n = INT()
if n==0:
break
else:
a=LIST()
a.sort()
mi=max(a)
for i in range(n-1):
for j in range(i+1,n):
mi=min(mi,a[j]-a[i])
ans.append(mi)
for x in ans:
print(x)
if __name__ == '__main__':
main()
``` | output | 1 | 26,452 | 11 | 52,905 |
Provide a correct Python 3 solution for this coding contest problem.
Selection of Participants of an Experiment
Dr. Tsukuba has devised a new method of programming training. In order to evaluate the effectiveness of this method, he plans to carry out a control experiment. Having two students as the participants of the experiment, one of them will be trained under the conventional method and the other under his new method. Comparing the final scores of these two, he will be able to judge the effectiveness of his method.
It is important to select two students having the closest possible scores, for making the comparison fair. He has a list of the scores of all students who can participate in the experiment. You are asked to write a program which selects two of them having the smallest difference in their scores.
Input
The input consists of multiple datasets, each in the following format.
n
a1 a2 … an
A dataset consists of two lines. The number of students n is given in the first line. n is an integer satisfying 2 ≤ n ≤ 1000. The second line gives scores of n students. ai (1 ≤ i ≤ n) is the score of the i-th student, which is a non-negative integer not greater than 1,000,000.
The end of the input is indicated by a line containing a zero. The sum of n's of all the datasets does not exceed 50,000.
Output
For each dataset, select two students with the smallest difference in their scores, and output in a line (the absolute value of) the difference.
Sample Input
5
10 10 10 10 10
5
1 5 8 9 11
7
11 34 83 47 59 29 70
0
Output for the Sample Input
0
1
5
Example
Input
5
10 10 10 10 10
5
1 5 8 9 11
7
11 34 83 47 59 29 70
0
Output
0
1
5 | instruction | 0 | 26,454 | 11 | 52,908 |
"Correct Solution:
```
import sys, re
from collections import deque, defaultdict, Counter
from math import ceil, sqrt, hypot, factorial, pi, sin, cos, radians
from itertools import permutations, combinations, product
from operator import itemgetter, mul
from copy import deepcopy
from string import ascii_lowercase, ascii_uppercase, digits
def input(): return sys.stdin.readline().strip()
def INT(): return int(input())
def MAP(): return map(int, input().split())
def LIST(): return list(map(int, input().split()))
sys.setrecursionlimit(10 ** 9)
INF = float('inf')
MOD = 10 ** 9 + 7
flag = True
ans_list = []
N = 1
while(flag == True):
N = INT()
if N == 0:
flag = False
else:
A = LIST()
A.sort()
ans = abs(A[0] - A[1])
for i in range(N - 1):
ans = min(ans, abs(A[i] - A[i + 1]))
ans_list.append(ans)
# ans = abs(A[0] - A[1])
for ans in ans_list:
print(ans)
``` | output | 1 | 26,454 | 11 | 52,909 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Selection of Participants of an Experiment
Dr. Tsukuba has devised a new method of programming training. In order to evaluate the effectiveness of this method, he plans to carry out a control experiment. Having two students as the participants of the experiment, one of them will be trained under the conventional method and the other under his new method. Comparing the final scores of these two, he will be able to judge the effectiveness of his method.
It is important to select two students having the closest possible scores, for making the comparison fair. He has a list of the scores of all students who can participate in the experiment. You are asked to write a program which selects two of them having the smallest difference in their scores.
Input
The input consists of multiple datasets, each in the following format.
n
a1 a2 … an
A dataset consists of two lines. The number of students n is given in the first line. n is an integer satisfying 2 ≤ n ≤ 1000. The second line gives scores of n students. ai (1 ≤ i ≤ n) is the score of the i-th student, which is a non-negative integer not greater than 1,000,000.
The end of the input is indicated by a line containing a zero. The sum of n's of all the datasets does not exceed 50,000.
Output
For each dataset, select two students with the smallest difference in their scores, and output in a line (the absolute value of) the difference.
Sample Input
5
10 10 10 10 10
5
1 5 8 9 11
7
11 34 83 47 59 29 70
0
Output for the Sample Input
0
1
5
Example
Input
5
10 10 10 10 10
5
1 5 8 9 11
7
11 34 83 47 59 29 70
0
Output
0
1
5
Submitted Solution:
```
while True:
n=int(input())
if n==0:break;
a=list(map(int, input().split()))
a.sort()
ans=a[1]-a[0]
for i in range(2, n):
if a[i]-a[i-1]<ans:ans=a[i]-a[i-1]
print(ans)
``` | instruction | 0 | 26,455 | 11 | 52,910 |
Yes | output | 1 | 26,455 | 11 | 52,911 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Selection of Participants of an Experiment
Dr. Tsukuba has devised a new method of programming training. In order to evaluate the effectiveness of this method, he plans to carry out a control experiment. Having two students as the participants of the experiment, one of them will be trained under the conventional method and the other under his new method. Comparing the final scores of these two, he will be able to judge the effectiveness of his method.
It is important to select two students having the closest possible scores, for making the comparison fair. He has a list of the scores of all students who can participate in the experiment. You are asked to write a program which selects two of them having the smallest difference in their scores.
Input
The input consists of multiple datasets, each in the following format.
n
a1 a2 … an
A dataset consists of two lines. The number of students n is given in the first line. n is an integer satisfying 2 ≤ n ≤ 1000. The second line gives scores of n students. ai (1 ≤ i ≤ n) is the score of the i-th student, which is a non-negative integer not greater than 1,000,000.
The end of the input is indicated by a line containing a zero. The sum of n's of all the datasets does not exceed 50,000.
Output
For each dataset, select two students with the smallest difference in their scores, and output in a line (the absolute value of) the difference.
Sample Input
5
10 10 10 10 10
5
1 5 8 9 11
7
11 34 83 47 59 29 70
0
Output for the Sample Input
0
1
5
Example
Input
5
10 10 10 10 10
5
1 5 8 9 11
7
11 34 83 47 59 29 70
0
Output
0
1
5
Submitted Solution:
```
n=int(input())
while n!=0:
a=list(map(int,input().split()))
ans=10**18
for i in range(len(a)):
for j in range(len(a)):
if i!=j:
ans=min(ans,abs(a[i]-a[j]))
print(ans)
n=int(input())
``` | instruction | 0 | 26,456 | 11 | 52,912 |
Yes | output | 1 | 26,456 | 11 | 52,913 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Selection of Participants of an Experiment
Dr. Tsukuba has devised a new method of programming training. In order to evaluate the effectiveness of this method, he plans to carry out a control experiment. Having two students as the participants of the experiment, one of them will be trained under the conventional method and the other under his new method. Comparing the final scores of these two, he will be able to judge the effectiveness of his method.
It is important to select two students having the closest possible scores, for making the comparison fair. He has a list of the scores of all students who can participate in the experiment. You are asked to write a program which selects two of them having the smallest difference in their scores.
Input
The input consists of multiple datasets, each in the following format.
n
a1 a2 … an
A dataset consists of two lines. The number of students n is given in the first line. n is an integer satisfying 2 ≤ n ≤ 1000. The second line gives scores of n students. ai (1 ≤ i ≤ n) is the score of the i-th student, which is a non-negative integer not greater than 1,000,000.
The end of the input is indicated by a line containing a zero. The sum of n's of all the datasets does not exceed 50,000.
Output
For each dataset, select two students with the smallest difference in their scores, and output in a line (the absolute value of) the difference.
Sample Input
5
10 10 10 10 10
5
1 5 8 9 11
7
11 34 83 47 59 29 70
0
Output for the Sample Input
0
1
5
Example
Input
5
10 10 10 10 10
5
1 5 8 9 11
7
11 34 83 47 59 29 70
0
Output
0
1
5
Submitted Solution:
```
min_list = []
while True:
n = int(input())
if n == 0:
break
s = list(map(int, input().split()))
s.sort(reverse=True)
min1 = s[0] - s[1]
for i in range(n-1):
min1 = min(min1, s[i]-s[i+1])
min_list.append(min1)
for i in range(len(min_list)):
print(min_list[i])
``` | instruction | 0 | 26,457 | 11 | 52,914 |
Yes | output | 1 | 26,457 | 11 | 52,915 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Selection of Participants of an Experiment
Dr. Tsukuba has devised a new method of programming training. In order to evaluate the effectiveness of this method, he plans to carry out a control experiment. Having two students as the participants of the experiment, one of them will be trained under the conventional method and the other under his new method. Comparing the final scores of these two, he will be able to judge the effectiveness of his method.
It is important to select two students having the closest possible scores, for making the comparison fair. He has a list of the scores of all students who can participate in the experiment. You are asked to write a program which selects two of them having the smallest difference in their scores.
Input
The input consists of multiple datasets, each in the following format.
n
a1 a2 … an
A dataset consists of two lines. The number of students n is given in the first line. n is an integer satisfying 2 ≤ n ≤ 1000. The second line gives scores of n students. ai (1 ≤ i ≤ n) is the score of the i-th student, which is a non-negative integer not greater than 1,000,000.
The end of the input is indicated by a line containing a zero. The sum of n's of all the datasets does not exceed 50,000.
Output
For each dataset, select two students with the smallest difference in their scores, and output in a line (the absolute value of) the difference.
Sample Input
5
10 10 10 10 10
5
1 5 8 9 11
7
11 34 83 47 59 29 70
0
Output for the Sample Input
0
1
5
Example
Input
5
10 10 10 10 10
5
1 5 8 9 11
7
11 34 83 47 59 29 70
0
Output
0
1
5
Submitted Solution:
```
while int(input()):
l=sorted(map(int,input().split()))
ll=range(len(l))
m=[0 for _ in ll]
m[1]=abs(l[0]-l[1])
for i in ll[2:]:
m[i]=min(m[i-1],abs(l[i]-l[i-1]))
print(m[-1])
``` | instruction | 0 | 26,458 | 11 | 52,916 |
Yes | output | 1 | 26,458 | 11 | 52,917 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Selection of Participants of an Experiment
Dr. Tsukuba has devised a new method of programming training. In order to evaluate the effectiveness of this method, he plans to carry out a control experiment. Having two students as the participants of the experiment, one of them will be trained under the conventional method and the other under his new method. Comparing the final scores of these two, he will be able to judge the effectiveness of his method.
It is important to select two students having the closest possible scores, for making the comparison fair. He has a list of the scores of all students who can participate in the experiment. You are asked to write a program which selects two of them having the smallest difference in their scores.
Input
The input consists of multiple datasets, each in the following format.
n
a1 a2 … an
A dataset consists of two lines. The number of students n is given in the first line. n is an integer satisfying 2 ≤ n ≤ 1000. The second line gives scores of n students. ai (1 ≤ i ≤ n) is the score of the i-th student, which is a non-negative integer not greater than 1,000,000.
The end of the input is indicated by a line containing a zero. The sum of n's of all the datasets does not exceed 50,000.
Output
For each dataset, select two students with the smallest difference in their scores, and output in a line (the absolute value of) the difference.
Sample Input
5
10 10 10 10 10
5
1 5 8 9 11
7
11 34 83 47 59 29 70
0
Output for the Sample Input
0
1
5
Example
Input
5
10 10 10 10 10
5
1 5 8 9 11
7
11 34 83 47 59 29 70
0
Output
0
1
5
Submitted Solution:
```
while True:
n,m = map(int,input().split())
if n == 0 and m == 0:
break
a = list(map(int,input().split()))
a.sort()
list1 = []
for i in range(n):
for j in range(i + 1, n):
price1 = a[i] + a[j]
list1.append(price1)
list1.sort()
list2 = list(filter(lambda p: m >= p, list1))
if list2:
print(max(list2))
else:
print("NONE")
``` | instruction | 0 | 26,459 | 11 | 52,918 |
No | output | 1 | 26,459 | 11 | 52,919 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Selection of Participants of an Experiment
Dr. Tsukuba has devised a new method of programming training. In order to evaluate the effectiveness of this method, he plans to carry out a control experiment. Having two students as the participants of the experiment, one of them will be trained under the conventional method and the other under his new method. Comparing the final scores of these two, he will be able to judge the effectiveness of his method.
It is important to select two students having the closest possible scores, for making the comparison fair. He has a list of the scores of all students who can participate in the experiment. You are asked to write a program which selects two of them having the smallest difference in their scores.
Input
The input consists of multiple datasets, each in the following format.
n
a1 a2 … an
A dataset consists of two lines. The number of students n is given in the first line. n is an integer satisfying 2 ≤ n ≤ 1000. The second line gives scores of n students. ai (1 ≤ i ≤ n) is the score of the i-th student, which is a non-negative integer not greater than 1,000,000.
The end of the input is indicated by a line containing a zero. The sum of n's of all the datasets does not exceed 50,000.
Output
For each dataset, select two students with the smallest difference in their scores, and output in a line (the absolute value of) the difference.
Sample Input
5
10 10 10 10 10
5
1 5 8 9 11
7
11 34 83 47 59 29 70
0
Output for the Sample Input
0
1
5
Example
Input
5
10 10 10 10 10
5
1 5 8 9 11
7
11 34 83 47 59 29 70
0
Output
0
1
5
Submitted Solution:
```
while True:
n = int(input())
a = list(map(int, input().split()))
l = list()
for i in range(1, n-1):
for j in range(i+1,n):
l.append(abs(a[i]-a[j]))
if l == []:
continue
if n == 0:
break
print(min(l))
``` | instruction | 0 | 26,460 | 11 | 52,920 |
No | output | 1 | 26,460 | 11 | 52,921 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Selection of Participants of an Experiment
Dr. Tsukuba has devised a new method of programming training. In order to evaluate the effectiveness of this method, he plans to carry out a control experiment. Having two students as the participants of the experiment, one of them will be trained under the conventional method and the other under his new method. Comparing the final scores of these two, he will be able to judge the effectiveness of his method.
It is important to select two students having the closest possible scores, for making the comparison fair. He has a list of the scores of all students who can participate in the experiment. You are asked to write a program which selects two of them having the smallest difference in their scores.
Input
The input consists of multiple datasets, each in the following format.
n
a1 a2 … an
A dataset consists of two lines. The number of students n is given in the first line. n is an integer satisfying 2 ≤ n ≤ 1000. The second line gives scores of n students. ai (1 ≤ i ≤ n) is the score of the i-th student, which is a non-negative integer not greater than 1,000,000.
The end of the input is indicated by a line containing a zero. The sum of n's of all the datasets does not exceed 50,000.
Output
For each dataset, select two students with the smallest difference in their scores, and output in a line (the absolute value of) the difference.
Sample Input
5
10 10 10 10 10
5
1 5 8 9 11
7
11 34 83 47 59 29 70
0
Output for the Sample Input
0
1
5
Example
Input
5
10 10 10 10 10
5
1 5 8 9 11
7
11 34 83 47 59 29 70
0
Output
0
1
5
Submitted Solution:
```
while True:
n = int(input())
a = list(map(int, input().split()))
l = list()
for i in range(1, n-1):
for j in range(i+1,n):
l.append(abs(a[i]-a[j]))
if l == []:
break
if n == 0:
break
print(min(l))
``` | instruction | 0 | 26,461 | 11 | 52,922 |
No | output | 1 | 26,461 | 11 | 52,923 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Selection of Participants of an Experiment
Dr. Tsukuba has devised a new method of programming training. In order to evaluate the effectiveness of this method, he plans to carry out a control experiment. Having two students as the participants of the experiment, one of them will be trained under the conventional method and the other under his new method. Comparing the final scores of these two, he will be able to judge the effectiveness of his method.
It is important to select two students having the closest possible scores, for making the comparison fair. He has a list of the scores of all students who can participate in the experiment. You are asked to write a program which selects two of them having the smallest difference in their scores.
Input
The input consists of multiple datasets, each in the following format.
n
a1 a2 … an
A dataset consists of two lines. The number of students n is given in the first line. n is an integer satisfying 2 ≤ n ≤ 1000. The second line gives scores of n students. ai (1 ≤ i ≤ n) is the score of the i-th student, which is a non-negative integer not greater than 1,000,000.
The end of the input is indicated by a line containing a zero. The sum of n's of all the datasets does not exceed 50,000.
Output
For each dataset, select two students with the smallest difference in their scores, and output in a line (the absolute value of) the difference.
Sample Input
5
10 10 10 10 10
5
1 5 8 9 11
7
11 34 83 47 59 29 70
0
Output for the Sample Input
0
1
5
Example
Input
5
10 10 10 10 10
5
1 5 8 9 11
7
11 34 83 47 59 29 70
0
Output
0
1
5
Submitted Solution:
```
f=lambda s,t:abs(s-t)
while 1:
n=int(input())
if not n:break
a=sorted(list(map(int,input().split())))
s,t=a[:2]
for i in a[2:]:
u=f(s,t)
if u>abs(s-i):
t=i
elif u>abs(t-i):
s=i
print(f(s,t))
``` | instruction | 0 | 26,462 | 11 | 52,924 |
No | output | 1 | 26,462 | 11 | 52,925 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
HAI
I HAS A TUX
GIMMEH TUX
I HAS A FOO ITS 0
I HAS A BAR ITS 0
I HAS A BAZ ITS 0
I HAS A QUZ ITS 1
TUX IS NOW A NUMBR
IM IN YR LOOP NERFIN YR TUX TIL BOTH SAEM TUX AN 0
I HAS A PUR
GIMMEH PUR
PUR IS NOW A NUMBR
FOO R SUM OF FOO AN PUR
BAR R SUM OF BAR AN 1
BOTH SAEM BIGGR OF PRODUKT OF FOO AN QUZ AN PRODUKT OF BAR BAZ AN PRODUKT OF FOO AN QUZ
O RLY?
YA RLY
BAZ R FOO
QUZ R BAR
OIC
IM OUTTA YR LOOP
BAZ IS NOW A NUMBAR
VISIBLE SMOOSH QUOSHUNT OF BAZ QUZ
KTHXBYE
Input
The input contains between 1 and 10 lines, i-th line contains an integer number xi (0 ≤ xi ≤ 9).
Output
Output a single real number. The answer is considered to be correct if its absolute or relative error does not exceed 10 - 4.
Examples
Input
3
0
1
1
Output
0.666667
Submitted Solution:
```
#input
n = int(input())
fo,br,bz,qu = 0,0,0,1
for i in range(n):
p = int(input())
fo = fo+p
br = br+1
if bz/qu<=fo/br:
bz = fo
qu = br
else :
break
print(bz/qu)
``` | instruction | 0 | 26,836 | 11 | 53,672 |
Yes | output | 1 | 26,836 | 11 | 53,673 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
HAI
I HAS A TUX
GIMMEH TUX
I HAS A FOO ITS 0
I HAS A BAR ITS 0
I HAS A BAZ ITS 0
I HAS A QUZ ITS 1
TUX IS NOW A NUMBR
IM IN YR LOOP NERFIN YR TUX TIL BOTH SAEM TUX AN 0
I HAS A PUR
GIMMEH PUR
PUR IS NOW A NUMBR
FOO R SUM OF FOO AN PUR
BAR R SUM OF BAR AN 1
BOTH SAEM BIGGR OF PRODUKT OF FOO AN QUZ AN PRODUKT OF BAR BAZ AN PRODUKT OF FOO AN QUZ
O RLY?
YA RLY
BAZ R FOO
QUZ R BAR
OIC
IM OUTTA YR LOOP
BAZ IS NOW A NUMBAR
VISIBLE SMOOSH QUOSHUNT OF BAZ QUZ
KTHXBYE
Input
The input contains between 1 and 10 lines, i-th line contains an integer number xi (0 ≤ xi ≤ 9).
Output
Output a single real number. The answer is considered to be correct if its absolute or relative error does not exceed 10 - 4.
Examples
Input
3
0
1
1
Output
0.666667
Submitted Solution:
```
tux = int(input())
foo = 0
bar = 0
baz = 0
quz = 1
for i in range(tux):
pur = int(input())
foo += pur
bar += 1
if foo * quz > baz * bar:
baz = foo
quz = bar
print(baz / quz)
``` | instruction | 0 | 26,837 | 11 | 53,674 |
Yes | output | 1 | 26,837 | 11 | 53,675 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
HAI
I HAS A TUX
GIMMEH TUX
I HAS A FOO ITS 0
I HAS A BAR ITS 0
I HAS A BAZ ITS 0
I HAS A QUZ ITS 1
TUX IS NOW A NUMBR
IM IN YR LOOP NERFIN YR TUX TIL BOTH SAEM TUX AN 0
I HAS A PUR
GIMMEH PUR
PUR IS NOW A NUMBR
FOO R SUM OF FOO AN PUR
BAR R SUM OF BAR AN 1
BOTH SAEM BIGGR OF PRODUKT OF FOO AN QUZ AN PRODUKT OF BAR BAZ AN PRODUKT OF FOO AN QUZ
O RLY?
YA RLY
BAZ R FOO
QUZ R BAR
OIC
IM OUTTA YR LOOP
BAZ IS NOW A NUMBAR
VISIBLE SMOOSH QUOSHUNT OF BAZ QUZ
KTHXBYE
Input
The input contains between 1 and 10 lines, i-th line contains an integer number xi (0 ≤ xi ≤ 9).
Output
Output a single real number. The answer is considered to be correct if its absolute or relative error does not exceed 10 - 4.
Examples
Input
3
0
1
1
Output
0.666667
Submitted Solution:
```
tux = input()
foo, bar, baz,quz = 0,0,0,1
tux = int(tux)
for i in range(tux):
pur = int(input())
foo+=pur
bar+=1
if foo*quz > bar*baz:
baz = foo
quz = bar
print(round(baz/quz,6))
``` | instruction | 0 | 26,838 | 11 | 53,676 |
Yes | output | 1 | 26,838 | 11 | 53,677 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
HAI
I HAS A TUX
GIMMEH TUX
I HAS A FOO ITS 0
I HAS A BAR ITS 0
I HAS A BAZ ITS 0
I HAS A QUZ ITS 1
TUX IS NOW A NUMBR
IM IN YR LOOP NERFIN YR TUX TIL BOTH SAEM TUX AN 0
I HAS A PUR
GIMMEH PUR
PUR IS NOW A NUMBR
FOO R SUM OF FOO AN PUR
BAR R SUM OF BAR AN 1
BOTH SAEM BIGGR OF PRODUKT OF FOO AN QUZ AN PRODUKT OF BAR BAZ AN PRODUKT OF FOO AN QUZ
O RLY?
YA RLY
BAZ R FOO
QUZ R BAR
OIC
IM OUTTA YR LOOP
BAZ IS NOW A NUMBAR
VISIBLE SMOOSH QUOSHUNT OF BAZ QUZ
KTHXBYE
Input
The input contains between 1 and 10 lines, i-th line contains an integer number xi (0 ≤ xi ≤ 9).
Output
Output a single real number. The answer is considered to be correct if its absolute or relative error does not exceed 10 - 4.
Examples
Input
3
0
1
1
Output
0.666667
Submitted Solution:
```
TUX=int(input())
FOO=0
BAR=0
BAZ=0
QUZ=1
for i in range(TUX):
PUR=int(input())
FOO=FOO+PUR
BAR=BAR+1
if FOO*QUZ>BAZ*BAR:
BAZ=FOO
QUZ=BAR
print(BAZ/QUZ)
``` | instruction | 0 | 26,839 | 11 | 53,678 |
Yes | output | 1 | 26,839 | 11 | 53,679 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
HAI
I HAS A TUX
GIMMEH TUX
I HAS A FOO ITS 0
I HAS A BAR ITS 0
I HAS A BAZ ITS 0
I HAS A QUZ ITS 1
TUX IS NOW A NUMBR
IM IN YR LOOP NERFIN YR TUX TIL BOTH SAEM TUX AN 0
I HAS A PUR
GIMMEH PUR
PUR IS NOW A NUMBR
FOO R SUM OF FOO AN PUR
BAR R SUM OF BAR AN 1
BOTH SAEM BIGGR OF PRODUKT OF FOO AN QUZ AN PRODUKT OF BAR BAZ AN PRODUKT OF FOO AN QUZ
O RLY?
YA RLY
BAZ R FOO
QUZ R BAR
OIC
IM OUTTA YR LOOP
BAZ IS NOW A NUMBAR
VISIBLE SMOOSH QUOSHUNT OF BAZ QUZ
KTHXBYE
Input
The input contains between 1 and 10 lines, i-th line contains an integer number xi (0 ≤ xi ≤ 9).
Output
Output a single real number. The answer is considered to be correct if its absolute or relative error does not exceed 10 - 4.
Examples
Input
3
0
1
1
Output
0.666667
Submitted Solution:
```
n = int(input())
cnt = 0
for i in range(n):
cnt += int(input())
print(cnt / n)
``` | instruction | 0 | 26,840 | 11 | 53,680 |
No | output | 1 | 26,840 | 11 | 53,681 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
HAI
I HAS A TUX
GIMMEH TUX
I HAS A FOO ITS 0
I HAS A BAR ITS 0
I HAS A BAZ ITS 0
I HAS A QUZ ITS 1
TUX IS NOW A NUMBR
IM IN YR LOOP NERFIN YR TUX TIL BOTH SAEM TUX AN 0
I HAS A PUR
GIMMEH PUR
PUR IS NOW A NUMBR
FOO R SUM OF FOO AN PUR
BAR R SUM OF BAR AN 1
BOTH SAEM BIGGR OF PRODUKT OF FOO AN QUZ AN PRODUKT OF BAR BAZ AN PRODUKT OF FOO AN QUZ
O RLY?
YA RLY
BAZ R FOO
QUZ R BAR
OIC
IM OUTTA YR LOOP
BAZ IS NOW A NUMBAR
VISIBLE SMOOSH QUOSHUNT OF BAZ QUZ
KTHXBYE
Input
The input contains between 1 and 10 lines, i-th line contains an integer number xi (0 ≤ xi ≤ 9).
Output
Output a single real number. The answer is considered to be correct if its absolute or relative error does not exceed 10 - 4.
Examples
Input
3
0
1
1
Output
0.666667
Submitted Solution:
```
t = int(input())
p, q = 0, 0
for i in range(t):
d = int(input())
p += d
q += 1
print(p / q)
``` | instruction | 0 | 26,841 | 11 | 53,682 |
No | output | 1 | 26,841 | 11 | 53,683 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
HAI
I HAS A TUX
GIMMEH TUX
I HAS A FOO ITS 0
I HAS A BAR ITS 0
I HAS A BAZ ITS 0
I HAS A QUZ ITS 1
TUX IS NOW A NUMBR
IM IN YR LOOP NERFIN YR TUX TIL BOTH SAEM TUX AN 0
I HAS A PUR
GIMMEH PUR
PUR IS NOW A NUMBR
FOO R SUM OF FOO AN PUR
BAR R SUM OF BAR AN 1
BOTH SAEM BIGGR OF PRODUKT OF FOO AN QUZ AN PRODUKT OF BAR BAZ AN PRODUKT OF FOO AN QUZ
O RLY?
YA RLY
BAZ R FOO
QUZ R BAR
OIC
IM OUTTA YR LOOP
BAZ IS NOW A NUMBAR
VISIBLE SMOOSH QUOSHUNT OF BAZ QUZ
KTHXBYE
Input
The input contains between 1 and 10 lines, i-th line contains an integer number xi (0 ≤ xi ≤ 9).
Output
Output a single real number. The answer is considered to be correct if its absolute or relative error does not exceed 10 - 4.
Examples
Input
3
0
1
1
Output
0.666667
Submitted Solution:
```
numbers = []
for _ in range(int(input())):
numbers.append(int(input()))
print(sum(numbers)/len(numbers))
``` | instruction | 0 | 26,842 | 11 | 53,684 |
No | output | 1 | 26,842 | 11 | 53,685 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
HAI
I HAS A TUX
GIMMEH TUX
I HAS A FOO ITS 0
I HAS A BAR ITS 0
I HAS A BAZ ITS 0
I HAS A QUZ ITS 1
TUX IS NOW A NUMBR
IM IN YR LOOP NERFIN YR TUX TIL BOTH SAEM TUX AN 0
I HAS A PUR
GIMMEH PUR
PUR IS NOW A NUMBR
FOO R SUM OF FOO AN PUR
BAR R SUM OF BAR AN 1
BOTH SAEM BIGGR OF PRODUKT OF FOO AN QUZ AN PRODUKT OF BAR BAZ AN PRODUKT OF FOO AN QUZ
O RLY?
YA RLY
BAZ R FOO
QUZ R BAR
OIC
IM OUTTA YR LOOP
BAZ IS NOW A NUMBAR
VISIBLE SMOOSH QUOSHUNT OF BAZ QUZ
KTHXBYE
Input
The input contains between 1 and 10 lines, i-th line contains an integer number xi (0 ≤ xi ≤ 9).
Output
Output a single real number. The answer is considered to be correct if its absolute or relative error does not exceed 10 - 4.
Examples
Input
3
0
1
1
Output
0.666667
Submitted Solution:
```
s=input()
n=int(input())
ans=""
for i in range(len(s)):
x=s[i]
if(ord(x)<n+97):
ans+=x.upper()
else:
ans+=x.lower()
print(ans)
``` | instruction | 0 | 26,843 | 11 | 53,686 |
No | output | 1 | 26,843 | 11 | 53,687 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Professor GukiZ likes programming contests. He especially likes to rate his students on the contests he prepares. Now, he has decided to prepare a new contest.
In total, n students will attend, and before the start, every one of them has some positive integer rating. Students are indexed from 1 to n. Let's denote the rating of i-th student as ai. After the contest ends, every student will end up with some positive integer position. GukiZ expects that his students will take places according to their ratings.
He thinks that each student will take place equal to <image>. In particular, if student A has rating strictly lower then student B, A will get the strictly better position than B, and if two students have equal ratings, they will share the same position.
GukiZ would like you to reconstruct the results by following his expectations. Help him and determine the position after the end of the contest for each of his students if everything goes as expected.
Input
The first line contains integer n (1 ≤ n ≤ 2000), number of GukiZ's students.
The second line contains n numbers a1, a2, ... an (1 ≤ ai ≤ 2000) where ai is the rating of i-th student (1 ≤ i ≤ n).
Output
In a single line, print the position after the end of the contest for each of n students in the same order as they appear in the input.
Examples
Input
3
1 3 3
Output
3 1 1
Input
1
1
Output
1
Input
5
3 5 3 4 5
Output
4 1 4 3 1
Note
In the first sample, students 2 and 3 are positioned first (there is no other student with higher rating), and student 1 is positioned third since there are two students with higher rating.
In the second sample, first student is the only one on the contest.
In the third sample, students 2 and 5 share the first position with highest rating, student 4 is next with third position, and students 1 and 3 are the last sharing fourth position.
Submitted Solution:
```
n = int(input())
a = [-int(i) for i in input().split()]
b = 1
c = 1
d = {}
e = a[:]
a.sort()
d[a[0]] = 1
for i in range(1, n):
if a[i] > a[i - 1]:
b += c
c = 1
else:
c += 1
d[a[i]] = b
for i in e:
print(d[i], end = ' ')
``` | instruction | 0 | 26,929 | 11 | 53,858 |
Yes | output | 1 | 26,929 | 11 | 53,859 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Professor GukiZ likes programming contests. He especially likes to rate his students on the contests he prepares. Now, he has decided to prepare a new contest.
In total, n students will attend, and before the start, every one of them has some positive integer rating. Students are indexed from 1 to n. Let's denote the rating of i-th student as ai. After the contest ends, every student will end up with some positive integer position. GukiZ expects that his students will take places according to their ratings.
He thinks that each student will take place equal to <image>. In particular, if student A has rating strictly lower then student B, A will get the strictly better position than B, and if two students have equal ratings, they will share the same position.
GukiZ would like you to reconstruct the results by following his expectations. Help him and determine the position after the end of the contest for each of his students if everything goes as expected.
Input
The first line contains integer n (1 ≤ n ≤ 2000), number of GukiZ's students.
The second line contains n numbers a1, a2, ... an (1 ≤ ai ≤ 2000) where ai is the rating of i-th student (1 ≤ i ≤ n).
Output
In a single line, print the position after the end of the contest for each of n students in the same order as they appear in the input.
Examples
Input
3
1 3 3
Output
3 1 1
Input
1
1
Output
1
Input
5
3 5 3 4 5
Output
4 1 4 3 1
Note
In the first sample, students 2 and 3 are positioned first (there is no other student with higher rating), and student 1 is positioned third since there are two students with higher rating.
In the second sample, first student is the only one on the contest.
In the third sample, students 2 and 5 share the first position with highest rating, student 4 is next with third position, and students 1 and 3 are the last sharing fourth position.
Submitted Solution:
```
n = int(input())
a = list(map(int, input().split()))
b = [[0]*2 for i in range(n)]
for i in range(n):
b[i][0] = a[i]
b[i][1] = i
b = sorted(b)[::-1]
ans = [0]*n
place = 1
num_m = 0
m = b[0][0]
for i in range(n):
if b[i][0] != m:
place += num_m
m = b[i][0]
num_m = 1
else:
num_m += 1
ans[b[i][1]] = place
for i in range(n-1):
print(ans[i], end = ' ')
print(ans[n-1])
``` | instruction | 0 | 26,930 | 11 | 53,860 |
Yes | output | 1 | 26,930 | 11 | 53,861 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Professor GukiZ likes programming contests. He especially likes to rate his students on the contests he prepares. Now, he has decided to prepare a new contest.
In total, n students will attend, and before the start, every one of them has some positive integer rating. Students are indexed from 1 to n. Let's denote the rating of i-th student as ai. After the contest ends, every student will end up with some positive integer position. GukiZ expects that his students will take places according to their ratings.
He thinks that each student will take place equal to <image>. In particular, if student A has rating strictly lower then student B, A will get the strictly better position than B, and if two students have equal ratings, they will share the same position.
GukiZ would like you to reconstruct the results by following his expectations. Help him and determine the position after the end of the contest for each of his students if everything goes as expected.
Input
The first line contains integer n (1 ≤ n ≤ 2000), number of GukiZ's students.
The second line contains n numbers a1, a2, ... an (1 ≤ ai ≤ 2000) where ai is the rating of i-th student (1 ≤ i ≤ n).
Output
In a single line, print the position after the end of the contest for each of n students in the same order as they appear in the input.
Examples
Input
3
1 3 3
Output
3 1 1
Input
1
1
Output
1
Input
5
3 5 3 4 5
Output
4 1 4 3 1
Note
In the first sample, students 2 and 3 are positioned first (there is no other student with higher rating), and student 1 is positioned third since there are two students with higher rating.
In the second sample, first student is the only one on the contest.
In the third sample, students 2 and 5 share the first position with highest rating, student 4 is next with third position, and students 1 and 3 are the last sharing fourth position.
Submitted Solution:
```
n=int(input())
s=input()
a=list(map(int,s.split()))
i=0
while(i<n):
count=0
j=0
while(j<n):
if(a[j]>a[i]):
count+=1
j+=1
print(1+count,end=" ")
i=i+1
``` | instruction | 0 | 26,931 | 11 | 53,862 |
Yes | output | 1 | 26,931 | 11 | 53,863 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Professor GukiZ likes programming contests. He especially likes to rate his students on the contests he prepares. Now, he has decided to prepare a new contest.
In total, n students will attend, and before the start, every one of them has some positive integer rating. Students are indexed from 1 to n. Let's denote the rating of i-th student as ai. After the contest ends, every student will end up with some positive integer position. GukiZ expects that his students will take places according to their ratings.
He thinks that each student will take place equal to <image>. In particular, if student A has rating strictly lower then student B, A will get the strictly better position than B, and if two students have equal ratings, they will share the same position.
GukiZ would like you to reconstruct the results by following his expectations. Help him and determine the position after the end of the contest for each of his students if everything goes as expected.
Input
The first line contains integer n (1 ≤ n ≤ 2000), number of GukiZ's students.
The second line contains n numbers a1, a2, ... an (1 ≤ ai ≤ 2000) where ai is the rating of i-th student (1 ≤ i ≤ n).
Output
In a single line, print the position after the end of the contest for each of n students in the same order as they appear in the input.
Examples
Input
3
1 3 3
Output
3 1 1
Input
1
1
Output
1
Input
5
3 5 3 4 5
Output
4 1 4 3 1
Note
In the first sample, students 2 and 3 are positioned first (there is no other student with higher rating), and student 1 is positioned third since there are two students with higher rating.
In the second sample, first student is the only one on the contest.
In the third sample, students 2 and 5 share the first position with highest rating, student 4 is next with third position, and students 1 and 3 are the last sharing fourth position.
Submitted Solution:
```
n = int(input())
rating = [int(i) for i in input().split()]
rank = sorted(rating, reverse = True)
res = {}
count = 1
for i in rank:
if i not in res:
res[i] = count
count+=1
ans = []
for i in rating:
ans.append(str(res[i]))
print(" ".join(ans))
``` | instruction | 0 | 26,932 | 11 | 53,864 |
Yes | output | 1 | 26,932 | 11 | 53,865 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Professor GukiZ likes programming contests. He especially likes to rate his students on the contests he prepares. Now, he has decided to prepare a new contest.
In total, n students will attend, and before the start, every one of them has some positive integer rating. Students are indexed from 1 to n. Let's denote the rating of i-th student as ai. After the contest ends, every student will end up with some positive integer position. GukiZ expects that his students will take places according to their ratings.
He thinks that each student will take place equal to <image>. In particular, if student A has rating strictly lower then student B, A will get the strictly better position than B, and if two students have equal ratings, they will share the same position.
GukiZ would like you to reconstruct the results by following his expectations. Help him and determine the position after the end of the contest for each of his students if everything goes as expected.
Input
The first line contains integer n (1 ≤ n ≤ 2000), number of GukiZ's students.
The second line contains n numbers a1, a2, ... an (1 ≤ ai ≤ 2000) where ai is the rating of i-th student (1 ≤ i ≤ n).
Output
In a single line, print the position after the end of the contest for each of n students in the same order as they appear in the input.
Examples
Input
3
1 3 3
Output
3 1 1
Input
1
1
Output
1
Input
5
3 5 3 4 5
Output
4 1 4 3 1
Note
In the first sample, students 2 and 3 are positioned first (there is no other student with higher rating), and student 1 is positioned third since there are two students with higher rating.
In the second sample, first student is the only one on the contest.
In the third sample, students 2 and 5 share the first position with highest rating, student 4 is next with third position, and students 1 and 3 are the last sharing fourth position.
Submitted Solution:
```
from sys import *
n=int(input())
A=list(map(int,stdin.readline().split()))
B=A.copy()
B.sort(reverse=True)
dp=[-1 for i in range(n)]
dp[0],count,dict,m=1,1,{},[]
for i in range(1,n):
if B[i]==B[i-1]:
dp[i]=dp[i-1]
count+=1
dict.update({B[i]: dp[i]})
elif count>1:
dp[i]=dp[i-1]+count
count=1
dict.update({B[i]: dp[i]})
else:
dp[i]=dp[i-1]+1
count=1
dict.update({B[i]: dp[i]})
for i in range(len(A)):
if A[i] in dict.keys():
m.append(str(dict[A[i]]))
stdout.write(str(" ".join(m))+"\n")
``` | instruction | 0 | 26,933 | 11 | 53,866 |
No | output | 1 | 26,933 | 11 | 53,867 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Professor GukiZ likes programming contests. He especially likes to rate his students on the contests he prepares. Now, he has decided to prepare a new contest.
In total, n students will attend, and before the start, every one of them has some positive integer rating. Students are indexed from 1 to n. Let's denote the rating of i-th student as ai. After the contest ends, every student will end up with some positive integer position. GukiZ expects that his students will take places according to their ratings.
He thinks that each student will take place equal to <image>. In particular, if student A has rating strictly lower then student B, A will get the strictly better position than B, and if two students have equal ratings, they will share the same position.
GukiZ would like you to reconstruct the results by following his expectations. Help him and determine the position after the end of the contest for each of his students if everything goes as expected.
Input
The first line contains integer n (1 ≤ n ≤ 2000), number of GukiZ's students.
The second line contains n numbers a1, a2, ... an (1 ≤ ai ≤ 2000) where ai is the rating of i-th student (1 ≤ i ≤ n).
Output
In a single line, print the position after the end of the contest for each of n students in the same order as they appear in the input.
Examples
Input
3
1 3 3
Output
3 1 1
Input
1
1
Output
1
Input
5
3 5 3 4 5
Output
4 1 4 3 1
Note
In the first sample, students 2 and 3 are positioned first (there is no other student with higher rating), and student 1 is positioned third since there are two students with higher rating.
In the second sample, first student is the only one on the contest.
In the third sample, students 2 and 5 share the first position with highest rating, student 4 is next with third position, and students 1 and 3 are the last sharing fourth position.
Submitted Solution:
```
n=int(input())
l=list(map(int,input().split()))
s=''
for k in range(n):
l1=[i for i in l if i>k]
s=s+str(len(l1))
print(s)
``` | instruction | 0 | 26,934 | 11 | 53,868 |
No | output | 1 | 26,934 | 11 | 53,869 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Professor GukiZ likes programming contests. He especially likes to rate his students on the contests he prepares. Now, he has decided to prepare a new contest.
In total, n students will attend, and before the start, every one of them has some positive integer rating. Students are indexed from 1 to n. Let's denote the rating of i-th student as ai. After the contest ends, every student will end up with some positive integer position. GukiZ expects that his students will take places according to their ratings.
He thinks that each student will take place equal to <image>. In particular, if student A has rating strictly lower then student B, A will get the strictly better position than B, and if two students have equal ratings, they will share the same position.
GukiZ would like you to reconstruct the results by following his expectations. Help him and determine the position after the end of the contest for each of his students if everything goes as expected.
Input
The first line contains integer n (1 ≤ n ≤ 2000), number of GukiZ's students.
The second line contains n numbers a1, a2, ... an (1 ≤ ai ≤ 2000) where ai is the rating of i-th student (1 ≤ i ≤ n).
Output
In a single line, print the position after the end of the contest for each of n students in the same order as they appear in the input.
Examples
Input
3
1 3 3
Output
3 1 1
Input
1
1
Output
1
Input
5
3 5 3 4 5
Output
4 1 4 3 1
Note
In the first sample, students 2 and 3 are positioned first (there is no other student with higher rating), and student 1 is positioned third since there are two students with higher rating.
In the second sample, first student is the only one on the contest.
In the third sample, students 2 and 5 share the first position with highest rating, student 4 is next with third position, and students 1 and 3 are the last sharing fourth position.
Submitted Solution:
```
n=int(input())
ls=list(map(int,input().split()))
ls=sorted(ls)
for x in ls:
print(ls[::-1].index(x)+1,end=" ")
``` | instruction | 0 | 26,935 | 11 | 53,870 |
No | output | 1 | 26,935 | 11 | 53,871 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Professor GukiZ likes programming contests. He especially likes to rate his students on the contests he prepares. Now, he has decided to prepare a new contest.
In total, n students will attend, and before the start, every one of them has some positive integer rating. Students are indexed from 1 to n. Let's denote the rating of i-th student as ai. After the contest ends, every student will end up with some positive integer position. GukiZ expects that his students will take places according to their ratings.
He thinks that each student will take place equal to <image>. In particular, if student A has rating strictly lower then student B, A will get the strictly better position than B, and if two students have equal ratings, they will share the same position.
GukiZ would like you to reconstruct the results by following his expectations. Help him and determine the position after the end of the contest for each of his students if everything goes as expected.
Input
The first line contains integer n (1 ≤ n ≤ 2000), number of GukiZ's students.
The second line contains n numbers a1, a2, ... an (1 ≤ ai ≤ 2000) where ai is the rating of i-th student (1 ≤ i ≤ n).
Output
In a single line, print the position after the end of the contest for each of n students in the same order as they appear in the input.
Examples
Input
3
1 3 3
Output
3 1 1
Input
1
1
Output
1
Input
5
3 5 3 4 5
Output
4 1 4 3 1
Note
In the first sample, students 2 and 3 are positioned first (there is no other student with higher rating), and student 1 is positioned third since there are two students with higher rating.
In the second sample, first student is the only one on the contest.
In the third sample, students 2 and 5 share the first position with highest rating, student 4 is next with third position, and students 1 and 3 are the last sharing fourth position.
Submitted Solution:
```
def function(array,r,output):
if r>=len(output):
print(*output)
return
q = array.count(max(array))
for _ in range(q):
output[output.index(max(array))] = 1 + r
del array[array.index(max(array))]
r+=q
function(array,r,output)
n = int(input())
st = list(map(int,input().split()))
out = st
function(st,0,st[:])
``` | instruction | 0 | 26,936 | 11 | 53,872 |
No | output | 1 | 26,936 | 11 | 53,873 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You and your n - 1 friends have found an array of integers a_1, a_2, ..., a_n. You have decided to share it in the following way: All n of you stand in a line in a particular order. Each minute, the person at the front of the line chooses either the first or the last element of the array, removes it, and keeps it for himself. He then gets out of line, and the next person in line continues the process.
You are standing in the m-th position in the line. Before the process starts, you may choose up to k different people in the line, and persuade them to always take either the first or the last element in the array on their turn (for each person his own choice, not necessarily equal for all people), no matter what the elements themselves are. Once the process starts, you cannot persuade any more people, and you cannot change the choices for the people you already persuaded.
Suppose that you're doing your choices optimally. What is the greatest integer x such that, no matter what are the choices of the friends you didn't choose to control, the element you will take from the array will be greater than or equal to x?
Please note that the friends you don't control may do their choice arbitrarily, and they will not necessarily take the biggest element available.
Input
The input consists of multiple test cases. The first line contains a single integer t (1 ≤ t ≤ 1000) — the number of test cases. The description of the test cases follows.
The first line of each test case contains three space-separated integers n, m and k (1 ≤ m ≤ n ≤ 3500, 0 ≤ k ≤ n - 1) — the number of elements in the array, your position in line and the number of people whose choices you can fix.
The second line of each test case contains n positive integers a_1, a_2, ..., a_n (1 ≤ a_i ≤ 10^9) — elements of the array.
It is guaranteed that the sum of n over all test cases does not exceed 3500.
Output
For each test case, print the largest integer x such that you can guarantee to obtain at least x.
Example
Input
4
6 4 2
2 9 2 3 8 5
4 4 1
2 13 60 4
4 1 3
1 2 2 1
2 2 0
1 2
Output
8
4
1
1
Note
In the first test case, an optimal strategy is to force the first person to take the last element and the second person to take the first element.
* the first person will take the last element (5) because he or she was forced by you to take the last element. After this turn the remaining array will be [2, 9, 2, 3, 8];
* the second person will take the first element (2) because he or she was forced by you to take the first element. After this turn the remaining array will be [9, 2, 3, 8];
* if the third person will choose to take the first element (9), at your turn the remaining array will be [2, 3, 8] and you will take 8 (the last element);
* if the third person will choose to take the last element (8), at your turn the remaining array will be [9, 2, 3] and you will take 9 (the first element).
Thus, this strategy guarantees to end up with at least 8. We can prove that there is no strategy that guarantees to end up with at least 9. Hence, the answer is 8.
In the second test case, an optimal strategy is to force the first person to take the first element. Then, in the worst case, both the second and the third person will take the first element: you will end up with 4.
Submitted Solution:
```
from sys import stdin, stdout
def main():
T = int(stdin.readline())
for zzz in range(T):
arr = list(map(int, stdin.readline().split()))
n,m,k = arr
item = list(map(int, stdin.readline().split()))
if m <= k:
k = m - 1
luck = m - k - 1
maxer = 0
for i in range(k+1):
left = i
right = n - k + i - 1
temp_min = 99999999999
for j in range(luck+1):
left2 = j
right2 = luck - j
temp_max = max(item[left + left2], item[right - right2])
temp_min = min(temp_min, temp_max)
if maxer == 0:
maxer = temp_min
else:
maxer = max(maxer, temp_min)
stdout.write(str(maxer)+"\n")
main()
``` | instruction | 0 | 27,553 | 11 | 55,106 |
Yes | output | 1 | 27,553 | 11 | 55,107 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You and your n - 1 friends have found an array of integers a_1, a_2, ..., a_n. You have decided to share it in the following way: All n of you stand in a line in a particular order. Each minute, the person at the front of the line chooses either the first or the last element of the array, removes it, and keeps it for himself. He then gets out of line, and the next person in line continues the process.
You are standing in the m-th position in the line. Before the process starts, you may choose up to k different people in the line, and persuade them to always take either the first or the last element in the array on their turn (for each person his own choice, not necessarily equal for all people), no matter what the elements themselves are. Once the process starts, you cannot persuade any more people, and you cannot change the choices for the people you already persuaded.
Suppose that you're doing your choices optimally. What is the greatest integer x such that, no matter what are the choices of the friends you didn't choose to control, the element you will take from the array will be greater than or equal to x?
Please note that the friends you don't control may do their choice arbitrarily, and they will not necessarily take the biggest element available.
Input
The input consists of multiple test cases. The first line contains a single integer t (1 ≤ t ≤ 1000) — the number of test cases. The description of the test cases follows.
The first line of each test case contains three space-separated integers n, m and k (1 ≤ m ≤ n ≤ 3500, 0 ≤ k ≤ n - 1) — the number of elements in the array, your position in line and the number of people whose choices you can fix.
The second line of each test case contains n positive integers a_1, a_2, ..., a_n (1 ≤ a_i ≤ 10^9) — elements of the array.
It is guaranteed that the sum of n over all test cases does not exceed 3500.
Output
For each test case, print the largest integer x such that you can guarantee to obtain at least x.
Example
Input
4
6 4 2
2 9 2 3 8 5
4 4 1
2 13 60 4
4 1 3
1 2 2 1
2 2 0
1 2
Output
8
4
1
1
Note
In the first test case, an optimal strategy is to force the first person to take the last element and the second person to take the first element.
* the first person will take the last element (5) because he or she was forced by you to take the last element. After this turn the remaining array will be [2, 9, 2, 3, 8];
* the second person will take the first element (2) because he or she was forced by you to take the first element. After this turn the remaining array will be [9, 2, 3, 8];
* if the third person will choose to take the first element (9), at your turn the remaining array will be [2, 3, 8] and you will take 8 (the last element);
* if the third person will choose to take the last element (8), at your turn the remaining array will be [9, 2, 3] and you will take 9 (the first element).
Thus, this strategy guarantees to end up with at least 8. We can prove that there is no strategy that guarantees to end up with at least 9. Hence, the answer is 8.
In the second test case, an optimal strategy is to force the first person to take the first element. Then, in the worst case, both the second and the third person will take the first element: you will end up with 4.
Submitted Solution:
```
t = int(input())
for ti in range(t):
n,m,k = input().split()
n = int(n)
m = int(m)
k = int(k)
a = input().split()
for i in range(n):
a[i] = int(a[i])
if m <= k+1:
# all under control
b = a[:m]+a[-m:]
print(str(max(b)))
else:
notcontrol = m - k - 1
allans = []
for j in range(k+1):
if j == k:
newa = a[j:]
else:
newa = a[j:-k+j]
# while k > 0:
# if a[0] < a[-1]:
# a = a[1:]
# else:
# a = a[:-1]
# k -= 1
# if lol =ue
rang = notcontrol+1
b = newa[:rang]+newa[-rang:]
allpairs = []
for i in range(rang):
if b[i] > b[i+rang]:
allpairs.append(b[i])
else:
allpairs.append(b[i+rang])
ans = min(allpairs)
allans.append(ans)
print(str(max(allans)))
``` | instruction | 0 | 27,554 | 11 | 55,108 |
Yes | output | 1 | 27,554 | 11 | 55,109 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You and your n - 1 friends have found an array of integers a_1, a_2, ..., a_n. You have decided to share it in the following way: All n of you stand in a line in a particular order. Each minute, the person at the front of the line chooses either the first or the last element of the array, removes it, and keeps it for himself. He then gets out of line, and the next person in line continues the process.
You are standing in the m-th position in the line. Before the process starts, you may choose up to k different people in the line, and persuade them to always take either the first or the last element in the array on their turn (for each person his own choice, not necessarily equal for all people), no matter what the elements themselves are. Once the process starts, you cannot persuade any more people, and you cannot change the choices for the people you already persuaded.
Suppose that you're doing your choices optimally. What is the greatest integer x such that, no matter what are the choices of the friends you didn't choose to control, the element you will take from the array will be greater than or equal to x?
Please note that the friends you don't control may do their choice arbitrarily, and they will not necessarily take the biggest element available.
Input
The input consists of multiple test cases. The first line contains a single integer t (1 ≤ t ≤ 1000) — the number of test cases. The description of the test cases follows.
The first line of each test case contains three space-separated integers n, m and k (1 ≤ m ≤ n ≤ 3500, 0 ≤ k ≤ n - 1) — the number of elements in the array, your position in line and the number of people whose choices you can fix.
The second line of each test case contains n positive integers a_1, a_2, ..., a_n (1 ≤ a_i ≤ 10^9) — elements of the array.
It is guaranteed that the sum of n over all test cases does not exceed 3500.
Output
For each test case, print the largest integer x such that you can guarantee to obtain at least x.
Example
Input
4
6 4 2
2 9 2 3 8 5
4 4 1
2 13 60 4
4 1 3
1 2 2 1
2 2 0
1 2
Output
8
4
1
1
Note
In the first test case, an optimal strategy is to force the first person to take the last element and the second person to take the first element.
* the first person will take the last element (5) because he or she was forced by you to take the last element. After this turn the remaining array will be [2, 9, 2, 3, 8];
* the second person will take the first element (2) because he or she was forced by you to take the first element. After this turn the remaining array will be [9, 2, 3, 8];
* if the third person will choose to take the first element (9), at your turn the remaining array will be [2, 3, 8] and you will take 8 (the last element);
* if the third person will choose to take the last element (8), at your turn the remaining array will be [9, 2, 3] and you will take 9 (the first element).
Thus, this strategy guarantees to end up with at least 8. We can prove that there is no strategy that guarantees to end up with at least 9. Hence, the answer is 8.
In the second test case, an optimal strategy is to force the first person to take the first element. Then, in the worst case, both the second and the third person will take the first element: you will end up with 4.
Submitted Solution:
```
import sys
import math
import heapq
import collections
def inputnum():
return(int(input()))
def inputnums():
return(map(int,input().split()))
def inputlist():
return(list(map(int,input().split())))
def inputstring():
return([x for x in input()])
def inputstringnum():
return([ord(x)-ord('a') for x in input()])
def inputmatrixchar(rows):
arr2d = [[j for j in input().strip()] for i in range(rows)]
return arr2d
def inputmatrixint(rows):
arr2d = []
for _ in range(rows):
arr2d.append([int(i) for i in input().split()])
return arr2d
t = int(input())
for q in range(t):
n, m, k = inputnums()
a = inputlist()
m -= 1
if k > m-1:
k = m
ans = 0
for r in range(k+1):
l = k-r
mn = 1000000001
for j in range(l, m-r+1):
mn = min(mn, max(a[j], a[n-1-(m-j)]))
ans = max(ans, mn)
print(ans)
``` | instruction | 0 | 27,555 | 11 | 55,110 |
Yes | output | 1 | 27,555 | 11 | 55,111 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You and your n - 1 friends have found an array of integers a_1, a_2, ..., a_n. You have decided to share it in the following way: All n of you stand in a line in a particular order. Each minute, the person at the front of the line chooses either the first or the last element of the array, removes it, and keeps it for himself. He then gets out of line, and the next person in line continues the process.
You are standing in the m-th position in the line. Before the process starts, you may choose up to k different people in the line, and persuade them to always take either the first or the last element in the array on their turn (for each person his own choice, not necessarily equal for all people), no matter what the elements themselves are. Once the process starts, you cannot persuade any more people, and you cannot change the choices for the people you already persuaded.
Suppose that you're doing your choices optimally. What is the greatest integer x such that, no matter what are the choices of the friends you didn't choose to control, the element you will take from the array will be greater than or equal to x?
Please note that the friends you don't control may do their choice arbitrarily, and they will not necessarily take the biggest element available.
Input
The input consists of multiple test cases. The first line contains a single integer t (1 ≤ t ≤ 1000) — the number of test cases. The description of the test cases follows.
The first line of each test case contains three space-separated integers n, m and k (1 ≤ m ≤ n ≤ 3500, 0 ≤ k ≤ n - 1) — the number of elements in the array, your position in line and the number of people whose choices you can fix.
The second line of each test case contains n positive integers a_1, a_2, ..., a_n (1 ≤ a_i ≤ 10^9) — elements of the array.
It is guaranteed that the sum of n over all test cases does not exceed 3500.
Output
For each test case, print the largest integer x such that you can guarantee to obtain at least x.
Example
Input
4
6 4 2
2 9 2 3 8 5
4 4 1
2 13 60 4
4 1 3
1 2 2 1
2 2 0
1 2
Output
8
4
1
1
Note
In the first test case, an optimal strategy is to force the first person to take the last element and the second person to take the first element.
* the first person will take the last element (5) because he or she was forced by you to take the last element. After this turn the remaining array will be [2, 9, 2, 3, 8];
* the second person will take the first element (2) because he or she was forced by you to take the first element. After this turn the remaining array will be [9, 2, 3, 8];
* if the third person will choose to take the first element (9), at your turn the remaining array will be [2, 3, 8] and you will take 8 (the last element);
* if the third person will choose to take the last element (8), at your turn the remaining array will be [9, 2, 3] and you will take 9 (the first element).
Thus, this strategy guarantees to end up with at least 8. We can prove that there is no strategy that guarantees to end up with at least 9. Hence, the answer is 8.
In the second test case, an optimal strategy is to force the first person to take the first element. Then, in the worst case, both the second and the third person will take the first element: you will end up with 4.
Submitted Solution:
```
# Legends Always Come Up with Solution
# Author: Manvir Singh
import os
from io import BytesIO, IOBase
import sys
from collections import defaultdict, deque, Counter
from bisect import *
from math import sqrt, pi, ceil, log, inf,gcd
from itertools import permutations
from copy import deepcopy
from heapq import *
def main():
for _ in range(int(input())):
n, m, k = map(int, input().split())
a = list(map(int, input().split()))
if k >= m - 1:
print(max(max(a[:m]), max(a[-m:])))
else:
ma = 0
for i in range(k + 1):
mi, z = inf, m - k - 1
for j in range(z + 1):
mi = min(mi, max(a[i + j], a[n - k - 1 - z + j + i]))
ma = max(ma, mi)
print(ma)
# region fastio
BUFSIZE = 8192
class FastIO(IOBase):
newlines = 0
def __init__(self, file):
self._fd = file.fileno()
self.buffer = BytesIO()
self.writable = "x" in file.mode or "r" not in file.mode
self.write = self.buffer.write if self.writable else None
def read(self):
while True:
b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
if not b:
break
ptr = self.buffer.tell()
self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
self.newlines = 0
return self.buffer.read()
def readline(self):
while self.newlines == 0:
b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
self.newlines = b.count(b"\n") + (not b)
ptr = self.buffer.tell()
self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
self.newlines -= 1
return self.buffer.readline()
def flush(self):
if self.writable:
os.write(self._fd, self.buffer.getvalue())
self.buffer.truncate(0), self.buffer.seek(0)
class IOWrapper(IOBase):
def __init__(self, file):
self.buffer = FastIO(file)
self.flush = self.buffer.flush
self.writable = self.buffer.writable
self.write = lambda s: self.buffer.write(s.encode("ascii"))
self.read = lambda: self.buffer.read().decode("ascii")
self.readline = lambda: self.buffer.readline().decode("ascii")
sys.stdin, sys.stdout = IOWrapper(sys.stdin), IOWrapper(sys.stdout)
input = lambda: sys.stdin.readline().rstrip("\r\n")
if __name__ == "__main__":
main()
``` | instruction | 0 | 27,556 | 11 | 55,112 |
Yes | output | 1 | 27,556 | 11 | 55,113 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You and your n - 1 friends have found an array of integers a_1, a_2, ..., a_n. You have decided to share it in the following way: All n of you stand in a line in a particular order. Each minute, the person at the front of the line chooses either the first or the last element of the array, removes it, and keeps it for himself. He then gets out of line, and the next person in line continues the process.
You are standing in the m-th position in the line. Before the process starts, you may choose up to k different people in the line, and persuade them to always take either the first or the last element in the array on their turn (for each person his own choice, not necessarily equal for all people), no matter what the elements themselves are. Once the process starts, you cannot persuade any more people, and you cannot change the choices for the people you already persuaded.
Suppose that you're doing your choices optimally. What is the greatest integer x such that, no matter what are the choices of the friends you didn't choose to control, the element you will take from the array will be greater than or equal to x?
Please note that the friends you don't control may do their choice arbitrarily, and they will not necessarily take the biggest element available.
Input
The input consists of multiple test cases. The first line contains a single integer t (1 ≤ t ≤ 1000) — the number of test cases. The description of the test cases follows.
The first line of each test case contains three space-separated integers n, m and k (1 ≤ m ≤ n ≤ 3500, 0 ≤ k ≤ n - 1) — the number of elements in the array, your position in line and the number of people whose choices you can fix.
The second line of each test case contains n positive integers a_1, a_2, ..., a_n (1 ≤ a_i ≤ 10^9) — elements of the array.
It is guaranteed that the sum of n over all test cases does not exceed 3500.
Output
For each test case, print the largest integer x such that you can guarantee to obtain at least x.
Example
Input
4
6 4 2
2 9 2 3 8 5
4 4 1
2 13 60 4
4 1 3
1 2 2 1
2 2 0
1 2
Output
8
4
1
1
Note
In the first test case, an optimal strategy is to force the first person to take the last element and the second person to take the first element.
* the first person will take the last element (5) because he or she was forced by you to take the last element. After this turn the remaining array will be [2, 9, 2, 3, 8];
* the second person will take the first element (2) because he or she was forced by you to take the first element. After this turn the remaining array will be [9, 2, 3, 8];
* if the third person will choose to take the first element (9), at your turn the remaining array will be [2, 3, 8] and you will take 8 (the last element);
* if the third person will choose to take the last element (8), at your turn the remaining array will be [9, 2, 3] and you will take 9 (the first element).
Thus, this strategy guarantees to end up with at least 8. We can prove that there is no strategy that guarantees to end up with at least 9. Hence, the answer is 8.
In the second test case, an optimal strategy is to force the first person to take the first element. Then, in the worst case, both the second and the third person will take the first element: you will end up with 4.
Submitted Solution:
```
for _ in range(int(input())):
n,m,k=map(int, input().split())
a=list(map(int, input().split()))
k=min(m-1,k)
ans=0
for i in range(k+1):
curr = 1000000
for j in range(m-1-k+1):
curr=min(curr, max(a[i+j],a[i+j+n-m]))
ans=max(ans, curr)
print(ans)
``` | instruction | 0 | 27,557 | 11 | 55,114 |
No | output | 1 | 27,557 | 11 | 55,115 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You and your n - 1 friends have found an array of integers a_1, a_2, ..., a_n. You have decided to share it in the following way: All n of you stand in a line in a particular order. Each minute, the person at the front of the line chooses either the first or the last element of the array, removes it, and keeps it for himself. He then gets out of line, and the next person in line continues the process.
You are standing in the m-th position in the line. Before the process starts, you may choose up to k different people in the line, and persuade them to always take either the first or the last element in the array on their turn (for each person his own choice, not necessarily equal for all people), no matter what the elements themselves are. Once the process starts, you cannot persuade any more people, and you cannot change the choices for the people you already persuaded.
Suppose that you're doing your choices optimally. What is the greatest integer x such that, no matter what are the choices of the friends you didn't choose to control, the element you will take from the array will be greater than or equal to x?
Please note that the friends you don't control may do their choice arbitrarily, and they will not necessarily take the biggest element available.
Input
The input consists of multiple test cases. The first line contains a single integer t (1 ≤ t ≤ 1000) — the number of test cases. The description of the test cases follows.
The first line of each test case contains three space-separated integers n, m and k (1 ≤ m ≤ n ≤ 3500, 0 ≤ k ≤ n - 1) — the number of elements in the array, your position in line and the number of people whose choices you can fix.
The second line of each test case contains n positive integers a_1, a_2, ..., a_n (1 ≤ a_i ≤ 10^9) — elements of the array.
It is guaranteed that the sum of n over all test cases does not exceed 3500.
Output
For each test case, print the largest integer x such that you can guarantee to obtain at least x.
Example
Input
4
6 4 2
2 9 2 3 8 5
4 4 1
2 13 60 4
4 1 3
1 2 2 1
2 2 0
1 2
Output
8
4
1
1
Note
In the first test case, an optimal strategy is to force the first person to take the last element and the second person to take the first element.
* the first person will take the last element (5) because he or she was forced by you to take the last element. After this turn the remaining array will be [2, 9, 2, 3, 8];
* the second person will take the first element (2) because he or she was forced by you to take the first element. After this turn the remaining array will be [9, 2, 3, 8];
* if the third person will choose to take the first element (9), at your turn the remaining array will be [2, 3, 8] and you will take 8 (the last element);
* if the third person will choose to take the last element (8), at your turn the remaining array will be [9, 2, 3] and you will take 9 (the first element).
Thus, this strategy guarantees to end up with at least 8. We can prove that there is no strategy that guarantees to end up with at least 9. Hence, the answer is 8.
In the second test case, an optimal strategy is to force the first person to take the first element. Then, in the worst case, both the second and the third person will take the first element: you will end up with 4.
Submitted Solution:
```
# -*- coding: utf-8 -*-
import bisect
import heapq
import math
import random
import sys
from collections import Counter, defaultdict, deque
from decimal import ROUND_CEILING, ROUND_HALF_UP, Decimal
from functools import lru_cache, reduce
from itertools import combinations, combinations_with_replacement, product, permutations
from operator import add, mul, sub
sys.setrecursionlimit(100000)
input = sys.stdin.readline
INF = 2**62-1
def read_int():
return int(input())
def read_int_n():
return list(map(int, input().split()))
def read_float():
return float(input())
def read_float_n():
return list(map(float, input().split()))
def read_str():
return input().strip()
def read_str_n():
return list(map(str, input().split()))
def error_print(*args):
print(*args, file=sys.stderr)
def mt(f):
import time
def wrap(*args, **kwargs):
s = time.time()
ret = f(*args, **kwargs)
e = time.time()
error_print(e - s, 'sec')
return ret
return wrap
class SegmentTree():
# to par: (n-1) // 2
# to chr: 2n+1, 2n+2
def __init__(self, N, operator, identity_element):
""" operator and identity_element has to be a monoid.
"""
self.__N = 2**int(math.ceil(math.log(N, 2)))
self.__table = [identity_element] * (self.__N * 2 - 1)
self.__op = operator
self.__ie = identity_element
def update(self, idx, x):
i = self.__N - 1 + idx # target leaf
t = self.__table
o = self.__op
t[i] = x
while i != 0:
pi = (i - 1) // 2 # parent
li = 2*pi + 1
ri = 2*pi + 2
v = o(t[li], t[ri])
if t[pi] != v:
t[pi] = v
else:
break
i = pi
def query(self, a, b):
# error_print(a, b)
stack = [(0, 0, self.__N)]
t = self.__table
o = self.__op
ans = self.__ie
c = 0
while stack:
c += 1
k, l, r = stack.pop()
cnd = t[k]
if a <= l and r <= b:
ans = o(ans, cnd)
else:
if (l + r) // 2 > a and b > l:
stack.append((2 * k + 1, l, (l + r) // 2))
if r > a and b > (l + r) // 2:
stack.append((2 * k + 2, (l + r) // 2, r))
return ans
def print(self):
print(self.__table)
def slv(N, M, K, A):
K = min(M-1, K)
R = M - K - 1
st = SegmentTree(N, min, INF)
for i, a in enumerate(A):
st.update(i, a)
ans = -1
if R != 0:
for i in range(K+1):
l = st.query(i, i+R)
r = st.query(N-(K-i)-R, N-(K-i))
ans = max(ans, min(l, r))
else:
for i in range(K+1):
ans = max(ans, min(A[i], A[N-(K-i)-1]))
return ans
def main():
T = read_int()
for _ in range(T):
N, M, K = read_int_n()
A = read_int_n()
print(slv(N, M, K, A))
# N = 3500
# M = 3000
# K = 2000
# A = [random.randint(0, 10**9) for _ in range(N)]
# print(slv(N, M, K, A))
if __name__ == '__main__':
main()
``` | instruction | 0 | 27,558 | 11 | 55,116 |
No | output | 1 | 27,558 | 11 | 55,117 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You and your n - 1 friends have found an array of integers a_1, a_2, ..., a_n. You have decided to share it in the following way: All n of you stand in a line in a particular order. Each minute, the person at the front of the line chooses either the first or the last element of the array, removes it, and keeps it for himself. He then gets out of line, and the next person in line continues the process.
You are standing in the m-th position in the line. Before the process starts, you may choose up to k different people in the line, and persuade them to always take either the first or the last element in the array on their turn (for each person his own choice, not necessarily equal for all people), no matter what the elements themselves are. Once the process starts, you cannot persuade any more people, and you cannot change the choices for the people you already persuaded.
Suppose that you're doing your choices optimally. What is the greatest integer x such that, no matter what are the choices of the friends you didn't choose to control, the element you will take from the array will be greater than or equal to x?
Please note that the friends you don't control may do their choice arbitrarily, and they will not necessarily take the biggest element available.
Input
The input consists of multiple test cases. The first line contains a single integer t (1 ≤ t ≤ 1000) — the number of test cases. The description of the test cases follows.
The first line of each test case contains three space-separated integers n, m and k (1 ≤ m ≤ n ≤ 3500, 0 ≤ k ≤ n - 1) — the number of elements in the array, your position in line and the number of people whose choices you can fix.
The second line of each test case contains n positive integers a_1, a_2, ..., a_n (1 ≤ a_i ≤ 10^9) — elements of the array.
It is guaranteed that the sum of n over all test cases does not exceed 3500.
Output
For each test case, print the largest integer x such that you can guarantee to obtain at least x.
Example
Input
4
6 4 2
2 9 2 3 8 5
4 4 1
2 13 60 4
4 1 3
1 2 2 1
2 2 0
1 2
Output
8
4
1
1
Note
In the first test case, an optimal strategy is to force the first person to take the last element and the second person to take the first element.
* the first person will take the last element (5) because he or she was forced by you to take the last element. After this turn the remaining array will be [2, 9, 2, 3, 8];
* the second person will take the first element (2) because he or she was forced by you to take the first element. After this turn the remaining array will be [9, 2, 3, 8];
* if the third person will choose to take the first element (9), at your turn the remaining array will be [2, 3, 8] and you will take 8 (the last element);
* if the third person will choose to take the last element (8), at your turn the remaining array will be [9, 2, 3] and you will take 9 (the first element).
Thus, this strategy guarantees to end up with at least 8. We can prove that there is no strategy that guarantees to end up with at least 9. Hence, the answer is 8.
In the second test case, an optimal strategy is to force the first person to take the first element. Then, in the worst case, both the second and the third person will take the first element: you will end up with 4.
Submitted Solution:
```
t=int(input())
while t>0:
n,m,k=map(int,input().split())
a=list(map(int,input().split()))
x=0
if m-k-1>0:
for i in range(k+1):
bad=99999
for j in range(m-k):
bad=min(bad,max(a[m-1-i-j],a[n-1-i-j]))
x=max(x,bad)
else:
for i in range(m):
x=max(a[m-1-i],a[n-1-i])
print(x)
t-=1
``` | instruction | 0 | 27,559 | 11 | 55,118 |
No | output | 1 | 27,559 | 11 | 55,119 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You and your n - 1 friends have found an array of integers a_1, a_2, ..., a_n. You have decided to share it in the following way: All n of you stand in a line in a particular order. Each minute, the person at the front of the line chooses either the first or the last element of the array, removes it, and keeps it for himself. He then gets out of line, and the next person in line continues the process.
You are standing in the m-th position in the line. Before the process starts, you may choose up to k different people in the line, and persuade them to always take either the first or the last element in the array on their turn (for each person his own choice, not necessarily equal for all people), no matter what the elements themselves are. Once the process starts, you cannot persuade any more people, and you cannot change the choices for the people you already persuaded.
Suppose that you're doing your choices optimally. What is the greatest integer x such that, no matter what are the choices of the friends you didn't choose to control, the element you will take from the array will be greater than or equal to x?
Please note that the friends you don't control may do their choice arbitrarily, and they will not necessarily take the biggest element available.
Input
The input consists of multiple test cases. The first line contains a single integer t (1 ≤ t ≤ 1000) — the number of test cases. The description of the test cases follows.
The first line of each test case contains three space-separated integers n, m and k (1 ≤ m ≤ n ≤ 3500, 0 ≤ k ≤ n - 1) — the number of elements in the array, your position in line and the number of people whose choices you can fix.
The second line of each test case contains n positive integers a_1, a_2, ..., a_n (1 ≤ a_i ≤ 10^9) — elements of the array.
It is guaranteed that the sum of n over all test cases does not exceed 3500.
Output
For each test case, print the largest integer x such that you can guarantee to obtain at least x.
Example
Input
4
6 4 2
2 9 2 3 8 5
4 4 1
2 13 60 4
4 1 3
1 2 2 1
2 2 0
1 2
Output
8
4
1
1
Note
In the first test case, an optimal strategy is to force the first person to take the last element and the second person to take the first element.
* the first person will take the last element (5) because he or she was forced by you to take the last element. After this turn the remaining array will be [2, 9, 2, 3, 8];
* the second person will take the first element (2) because he or she was forced by you to take the first element. After this turn the remaining array will be [9, 2, 3, 8];
* if the third person will choose to take the first element (9), at your turn the remaining array will be [2, 3, 8] and you will take 8 (the last element);
* if the third person will choose to take the last element (8), at your turn the remaining array will be [9, 2, 3] and you will take 9 (the first element).
Thus, this strategy guarantees to end up with at least 8. We can prove that there is no strategy that guarantees to end up with at least 9. Hence, the answer is 8.
In the second test case, an optimal strategy is to force the first person to take the first element. Then, in the worst case, both the second and the third person will take the first element: you will end up with 4.
Submitted Solution:
```
for i in range(int(input())):
n, m, k = map(int, input().split())
a, ans = list(map(int, input().split())), 0
if m == 1:
print(max(a[0], a[-1]))
continue
if k == 0:
tem = float('inf')
for c in range(m):
tem = min(tem, max(a[c], a[m - (m - c)]))
print(tem)
continue
if k >= m:
k = m - 1
for j in range(k + 1):
for z in range(n - 1, n - k - 2 + j, -1):
num = m - (n - (z - j))
# print(j, z, num)
tem = float('inf')
for c in range(j, j + num + 1):
tem = min(tem, max(a[c], a[z - num]))
# print(a[c], a[z - num])
num -= 1
ans = max(tem, ans)
print(ans)
``` | instruction | 0 | 27,560 | 11 | 55,120 |
No | output | 1 | 27,560 | 11 | 55,121 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Recently a serious bug has been found in the FOS code. The head of the F company wants to find the culprit and punish him. For that, he set up an organizational meeting, the issue is: who's bugged the code? Each of the n coders on the meeting said: 'I know for sure that either x or y did it!'
The head of the company decided to choose two suspects and invite them to his office. Naturally, he should consider the coders' opinions. That's why the head wants to make such a choice that at least p of n coders agreed with it. A coder agrees with the choice of two suspects if at least one of the two people that he named at the meeting was chosen as a suspect. In how many ways can the head of F choose two suspects?
Note that even if some coder was chosen as a suspect, he can agree with the head's choice if he named the other chosen coder at the meeting.
Input
The first line contains integers n and p (3 ≤ n ≤ 3·105; 0 ≤ p ≤ n) — the number of coders in the F company and the minimum number of agreed people.
Each of the next n lines contains two integers xi, yi (1 ≤ xi, yi ≤ n) — the numbers of coders named by the i-th coder. It is guaranteed that xi ≠ i, yi ≠ i, xi ≠ yi.
Output
Print a single integer — the number of possible two-suspect sets. Note that the order of the suspects doesn't matter, that is, sets (1, 2) and (2, 1) are considered identical.
Examples
Input
4 2
2 3
1 4
1 4
2 1
Output
6
Input
8 6
5 6
5 7
5 8
6 2
2 1
7 3
1 3
1 4
Output
1
Submitted Solution:
```
from collections import defaultdict
from bisect import bisect_left as lower
import sys
input = sys.stdin.readline
def put():
return map(int, input().split())
try:
n,m = put()
cnt, mp = [0]*n, defaultdict()
for _ in range(n):
x,y = put()
x,y = x-1,y-1
key = (min(x,y), max(x,y))
if key in mp:
mp[key]+=1
else:
mp[key]=1
cnt[x]+=1
cnt[y]+=1
for (x,y),val in mp.items():
if cnt[x]+cnt[y]>= m and cnt[x]+cnt[y]-val<m:
ans[x]-=1
ans[y]-=1
except:
print('lol')
scnt,ans = cnt.copy(), [0]*n
scnt.sort()
for i in range(n):
ans[i]+= n-lower(scnt, m-cnt[i])
if 2*cnt[i]>=m:
ans[i]-=1
print(sum(ans)//2)
``` | instruction | 0 | 27,815 | 11 | 55,630 |
No | output | 1 | 27,815 | 11 | 55,631 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Recently a serious bug has been found in the FOS code. The head of the F company wants to find the culprit and punish him. For that, he set up an organizational meeting, the issue is: who's bugged the code? Each of the n coders on the meeting said: 'I know for sure that either x or y did it!'
The head of the company decided to choose two suspects and invite them to his office. Naturally, he should consider the coders' opinions. That's why the head wants to make such a choice that at least p of n coders agreed with it. A coder agrees with the choice of two suspects if at least one of the two people that he named at the meeting was chosen as a suspect. In how many ways can the head of F choose two suspects?
Note that even if some coder was chosen as a suspect, he can agree with the head's choice if he named the other chosen coder at the meeting.
Input
The first line contains integers n and p (3 ≤ n ≤ 3·105; 0 ≤ p ≤ n) — the number of coders in the F company and the minimum number of agreed people.
Each of the next n lines contains two integers xi, yi (1 ≤ xi, yi ≤ n) — the numbers of coders named by the i-th coder. It is guaranteed that xi ≠ i, yi ≠ i, xi ≠ yi.
Output
Print a single integer — the number of possible two-suspect sets. Note that the order of the suspects doesn't matter, that is, sets (1, 2) and (2, 1) are considered identical.
Examples
Input
4 2
2 3
1 4
1 4
2 1
Output
6
Input
8 6
5 6
5 7
5 8
6 2
2 1
7 3
1 3
1 4
Output
1
Submitted Solution:
```
n, p = map(int, input().split())
coders = [0] * n
ans = 0
for _ in range(n):
a, b = map(int, input().split())
coders[a - 1] += 1
coders[b - 1] += 1
candidate_amount = sum(1 for c in coders if c >= p)
if candidate_amount:
for i in range(n):
if coders[i] >= p:
candidate_amount -= 1
ans += n - 1 - i
else:
ans += candidate_amount
else:
m = coders.count(max(coders))
if m > 1:
ans = m * (m - 1) // 2
else:
coders.remove(max(coders))
ans = coders.count(max(coders))
print(ans)
``` | instruction | 0 | 27,816 | 11 | 55,632 |
No | output | 1 | 27,816 | 11 | 55,633 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Recently a serious bug has been found in the FOS code. The head of the F company wants to find the culprit and punish him. For that, he set up an organizational meeting, the issue is: who's bugged the code? Each of the n coders on the meeting said: 'I know for sure that either x or y did it!'
The head of the company decided to choose two suspects and invite them to his office. Naturally, he should consider the coders' opinions. That's why the head wants to make such a choice that at least p of n coders agreed with it. A coder agrees with the choice of two suspects if at least one of the two people that he named at the meeting was chosen as a suspect. In how many ways can the head of F choose two suspects?
Note that even if some coder was chosen as a suspect, he can agree with the head's choice if he named the other chosen coder at the meeting.
Input
The first line contains integers n and p (3 ≤ n ≤ 3·105; 0 ≤ p ≤ n) — the number of coders in the F company and the minimum number of agreed people.
Each of the next n lines contains two integers xi, yi (1 ≤ xi, yi ≤ n) — the numbers of coders named by the i-th coder. It is guaranteed that xi ≠ i, yi ≠ i, xi ≠ yi.
Output
Print a single integer — the number of possible two-suspect sets. Note that the order of the suspects doesn't matter, that is, sets (1, 2) and (2, 1) are considered identical.
Examples
Input
4 2
2 3
1 4
1 4
2 1
Output
6
Input
8 6
5 6
5 7
5 8
6 2
2 1
7 3
1 3
1 4
Output
1
Submitted Solution:
```
__author__ = 'Lipen'
def main():
n, p = map(int, input().split())
votes = [0]*n
for _ in range(n):
x, y = map(int, input().split())
votes[x-1] += 1
votes[y-1] += 1
k = 0
for i in range(n):
for j in range(i+1, n):
if votes[i] + votes[j] >= p:
k += 1
print(k)
main()
``` | instruction | 0 | 27,817 | 11 | 55,634 |
No | output | 1 | 27,817 | 11 | 55,635 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Recently a serious bug has been found in the FOS code. The head of the F company wants to find the culprit and punish him. For that, he set up an organizational meeting, the issue is: who's bugged the code? Each of the n coders on the meeting said: 'I know for sure that either x or y did it!'
The head of the company decided to choose two suspects and invite them to his office. Naturally, he should consider the coders' opinions. That's why the head wants to make such a choice that at least p of n coders agreed with it. A coder agrees with the choice of two suspects if at least one of the two people that he named at the meeting was chosen as a suspect. In how many ways can the head of F choose two suspects?
Note that even if some coder was chosen as a suspect, he can agree with the head's choice if he named the other chosen coder at the meeting.
Input
The first line contains integers n and p (3 ≤ n ≤ 3·105; 0 ≤ p ≤ n) — the number of coders in the F company and the minimum number of agreed people.
Each of the next n lines contains two integers xi, yi (1 ≤ xi, yi ≤ n) — the numbers of coders named by the i-th coder. It is guaranteed that xi ≠ i, yi ≠ i, xi ≠ yi.
Output
Print a single integer — the number of possible two-suspect sets. Note that the order of the suspects doesn't matter, that is, sets (1, 2) and (2, 1) are considered identical.
Examples
Input
4 2
2 3
1 4
1 4
2 1
Output
6
Input
8 6
5 6
5 7
5 8
6 2
2 1
7 3
1 3
1 4
Output
1
Submitted Solution:
```
import itertools
n, p = tuple(map(int, str.split(input())))
c = [0] * n
for _ in range(n):
for i in tuple(map(int, str.split(input()))):
c[i - 1] += 1
count = 0
for i, j in itertools.combinations(range(n), 2):
if c[i] + c[j] >= p:
count += 1
print(count)
``` | instruction | 0 | 27,818 | 11 | 55,636 |
No | output | 1 | 27,818 | 11 | 55,637 |
Provide a correct Python 3 solution for this coding contest problem.
Input
The input is given from standard input in the following format.
> $H \ W$ $a_{1, 1} \ a_{1, 2} \ \cdots \ a_{1, W}$ $a_{2, 1} \ a_{2, 2} \ \cdots \ a_{2, W}$ $\vdots \ \ \ \ \ \ \ \ \ \ \vdots \ \ \ \ \ \ \ \ \ \ \vdots$ $a_{H, 1} \ a_{H, 2} \ \cdots \ a_{H, W}$
Output
* Print the maximum number of souvenirs they can get.
Constraints
* $1 \le H, W \le 200$
* $0 \le a_{i, j} \le 10^5$
Subtasks
Subtask 1 [ 50 points ]
* The testcase in the subtask satisfies $1 \le H \le 2$.
Subtask 2 [ 80 points ]
* The testcase in the subtask satisfies $1 \le H \le 3$.
Subtask 3 [ 120 points ]
* The testcase in the subtask satisfies $1 \le H, W \le 7$.
Subtask 4 [ 150 points ]
* The testcase in the subtask satisfies $1 \le H, W \le 30$.
Subtask 5 [ 200 points ]
* There are no additional constraints.
Output
* Print the maximum number of souvenirs they can get.
Constraints
* $1 \le H, W \le 200$
* $0 \le a_{i, j} \le 10^5$
Subtasks
Subtask 1 [ 50 points ]
* The testcase in the subtask satisfies $1 \le H \le 2$.
Subtask 2 [ 80 points ]
* The testcase in the subtask satisfies $1 \le H \le 3$.
Subtask 3 [ 120 points ]
* The testcase in the subtask satisfies $1 \le H, W \le 7$.
Subtask 4 [ 150 points ]
* The testcase in the subtask satisfies $1 \le H, W \le 30$.
Subtask 5 [ 200 points ]
* There are no additional constraints.
Input
The input is given from standard input in the following format.
> $H \ W$ $a_{1, 1} \ a_{1, 2} \ \cdots \ a_{1, W}$ $a_{2, 1} \ a_{2, 2} \ \cdots \ a_{2, W}$ $\vdots \ \ \ \ \ \ \ \ \ \ \vdots \ \ \ \ \ \ \ \ \ \ \vdots$ $a_{H, 1} \ a_{H, 2} \ \cdots \ a_{H, W}$
Examples
Input
3 3
1 0 5
2 2 3
4 2 4
Output
21
Input
6 6
1 2 3 4 5 6
8 6 9 1 2 0
3 1 4 1 5 9
2 6 5 3 5 8
1 4 1 4 2 1
2 7 1 8 2 8
Output
97 | instruction | 0 | 28,146 | 11 | 56,292 |
"Correct Solution:
```
import sys
read = sys.stdin.buffer.read
readline = sys.stdin.buffer.readline
readlines = sys.stdin.buffer.readlines
from heapq import heappop, heappush
import itertools
"""
・最小費用流。流量2を流せばよい。
・頂点xをx_in,x_outに拡張。x_inからx_outにcapacity1で、価値 a と 0 の辺を貼る
・このままだと最大化問題になっているので、辺のコストをX - a_{ij}とする感じで
"""
class MinCostFlow:
"""
最小費用流。負辺がないと仮定して、BellmanFordを省略している。
"""
def __init__(self, N, source, sink):
self.N = N
self.G = [[] for _ in range(N)]
self.source = source
self.sink = sink
def add_edge(self, fr, to, cap, cost):
n1 = len(self.G[fr])
n2 = len(self.G[to])
self.G[fr].append([to, cap, cost, n2])
self.G[to].append([fr, 0, -cost, n1])
def MinCost(self, flow, negative_edge = False):
if negative_edge:
raise ValueError
N = self.N; G = self.G; source = self.source; sink = self.sink
INF = 10 ** 18
prev_v = [0] * N; prev_e = [0] * N # 経路復元用
H = [0] * N # potential
mincost=0
while flow:
dist=[INF] * N
dist[source]=0
q = [source]
mask = (1 << 20) - 1
while q:
x = heappop(q)
dv = (x >> 20); v = x & mask
if dist[v] < dv:
continue
if v == sink:
break
for i,(w,cap,cost,rev) in enumerate(G[v]):
dw = dist[v] + cost + H[v] - H[w]
if (not cap) or (dist[w] <= dw):
continue
dist[w] = dw
prev_v[w] = v; prev_e[w] = i
heappush(q, (dw << 20) + w)
if dist[sink] == INF:
raise Exception('No Flow Exists')
# ポテンシャルの更新
for v,d in enumerate(dist):
H[v] += d
# 流せる量を取得する
d = flow; v = sink
while v != source:
pv = prev_v[v]; pe = prev_e[v]
cap = G[pv][pe][1]
if d > cap:
d = cap
v = pv
# 流す
mincost += d * H[sink]
flow -= d
v = sink
while v != source:
pv = prev_v[v]; pe = prev_e[v]
G[pv][pe][1] -= d
rev = G[pv][pe][3]
G[v][rev][1] += d
v = pv
return mincost
H,W = map(int,readline().split())
A = list(map(int,read().split()))
N = 2 * H * W + 2
source = N-2; sink = N-1
G = MinCostFlow(N,source,sink)
add = G.add_edge
X = 10 ** 6
# スタート地点
add(fr=source, to=0, cap=2, cost=0)
# ゴール
add(2*H*W-1, sink, 2, 0)
# x_in to x_out
for x,a in enumerate(A):
add(x+x,x+x+1,1,X) # とらない
add(x+x,x+x+1,1,X - a) # とる
# 左から右への辺
for i,j in itertools.product(range(H),range(W-1)):
x = W * i + j; y = x + 1
add(x+x+1,y+y,1,0)
# 上から下への辺
for i,j in itertools.product(range(H-1),range(W)):
x = W * i + j; y = x + W
add(x+x+1,y+y,1,0)
cost = G.MinCost(2)
# 1点通るごとに、X - costになっている。2人合わせて、(H+W-1) * 2個のXが足されている
answer = 2 * (H+W-1) * X -cost
print(answer)
``` | output | 1 | 28,146 | 11 | 56,293 |
Provide a correct Python 3 solution for this coding contest problem.
Input
The input is given from standard input in the following format.
> $H \ W$ $a_{1, 1} \ a_{1, 2} \ \cdots \ a_{1, W}$ $a_{2, 1} \ a_{2, 2} \ \cdots \ a_{2, W}$ $\vdots \ \ \ \ \ \ \ \ \ \ \vdots \ \ \ \ \ \ \ \ \ \ \vdots$ $a_{H, 1} \ a_{H, 2} \ \cdots \ a_{H, W}$
Output
* Print the maximum number of souvenirs they can get.
Constraints
* $1 \le H, W \le 200$
* $0 \le a_{i, j} \le 10^5$
Subtasks
Subtask 1 [ 50 points ]
* The testcase in the subtask satisfies $1 \le H \le 2$.
Subtask 2 [ 80 points ]
* The testcase in the subtask satisfies $1 \le H \le 3$.
Subtask 3 [ 120 points ]
* The testcase in the subtask satisfies $1 \le H, W \le 7$.
Subtask 4 [ 150 points ]
* The testcase in the subtask satisfies $1 \le H, W \le 30$.
Subtask 5 [ 200 points ]
* There are no additional constraints.
Output
* Print the maximum number of souvenirs they can get.
Constraints
* $1 \le H, W \le 200$
* $0 \le a_{i, j} \le 10^5$
Subtasks
Subtask 1 [ 50 points ]
* The testcase in the subtask satisfies $1 \le H \le 2$.
Subtask 2 [ 80 points ]
* The testcase in the subtask satisfies $1 \le H \le 3$.
Subtask 3 [ 120 points ]
* The testcase in the subtask satisfies $1 \le H, W \le 7$.
Subtask 4 [ 150 points ]
* The testcase in the subtask satisfies $1 \le H, W \le 30$.
Subtask 5 [ 200 points ]
* There are no additional constraints.
Input
The input is given from standard input in the following format.
> $H \ W$ $a_{1, 1} \ a_{1, 2} \ \cdots \ a_{1, W}$ $a_{2, 1} \ a_{2, 2} \ \cdots \ a_{2, W}$ $\vdots \ \ \ \ \ \ \ \ \ \ \vdots \ \ \ \ \ \ \ \ \ \ \vdots$ $a_{H, 1} \ a_{H, 2} \ \cdots \ a_{H, W}$
Examples
Input
3 3
1 0 5
2 2 3
4 2 4
Output
21
Input
6 6
1 2 3 4 5 6
8 6 9 1 2 0
3 1 4 1 5 9
2 6 5 3 5 8
1 4 1 4 2 1
2 7 1 8 2 8
Output
97 | instruction | 0 | 28,147 | 11 | 56,294 |
"Correct Solution:
```
H,W = map(int,input().split())
src = [list(map(int,input().split())) for i in range(H)]
dp = [[[0 for ex in range(W)] for sx in range(W)] for xy in range(H+W-1)]
dp[0][0][0] = src[0][0]
for xy in range(H+W-2):
n = min(xy+1,H,W,H+W-xy-1)
sx0 = max(0,xy-H+1)
for sx in range(sx0, sx0+n):
for ex in range(sx, sx0+n):
sy,ey = xy-sx, xy-ex
if sx < W-1 and ex < W-1:
gain = src[sy][sx+1]
if sx+1 != ex+1: gain += src[ey][ex+1]
if dp[xy+1][sx+1][ex+1] < dp[xy][sx][ex] + gain:
dp[xy+1][sx+1][ex+1] = dp[xy][sx][ex] + gain
if sx < W-1 and ey < H-1:
gain = src[sy][sx+1]
if sx+1 != ex: gain += src[ey+1][ex]
if dp[xy+1][sx+1][ex] < dp[xy][sx][ex] + gain:
dp[xy+1][sx+1][ex] = dp[xy][sx][ex] + gain
if sy < H-1 and ex < W-1:
gain = src[sy+1][sx]
if sx != ex+1: gain += src[ey][ex+1]
if dp[xy+1][sx][ex+1] < dp[xy][sx][ex] + gain:
dp[xy+1][sx][ex+1] = dp[xy][sx][ex] + gain
if sy < H-1 and ey < H-1:
gain = src[sy+1][sx]
if sx != ex: gain += src[ey+1][ex]
if dp[xy+1][sx][ex] < dp[xy][sx][ex] + gain:
dp[xy+1][sx][ex] = dp[xy][sx][ex] + gain
print(dp[-1][-1][-1])
``` | output | 1 | 28,147 | 11 | 56,295 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Input
The input is given from standard input in the following format.
> $H \ W$ $a_{1, 1} \ a_{1, 2} \ \cdots \ a_{1, W}$ $a_{2, 1} \ a_{2, 2} \ \cdots \ a_{2, W}$ $\vdots \ \ \ \ \ \ \ \ \ \ \vdots \ \ \ \ \ \ \ \ \ \ \vdots$ $a_{H, 1} \ a_{H, 2} \ \cdots \ a_{H, W}$
Output
* Print the maximum number of souvenirs they can get.
Constraints
* $1 \le H, W \le 200$
* $0 \le a_{i, j} \le 10^5$
Subtasks
Subtask 1 [ 50 points ]
* The testcase in the subtask satisfies $1 \le H \le 2$.
Subtask 2 [ 80 points ]
* The testcase in the subtask satisfies $1 \le H \le 3$.
Subtask 3 [ 120 points ]
* The testcase in the subtask satisfies $1 \le H, W \le 7$.
Subtask 4 [ 150 points ]
* The testcase in the subtask satisfies $1 \le H, W \le 30$.
Subtask 5 [ 200 points ]
* There are no additional constraints.
Output
* Print the maximum number of souvenirs they can get.
Constraints
* $1 \le H, W \le 200$
* $0 \le a_{i, j} \le 10^5$
Subtasks
Subtask 1 [ 50 points ]
* The testcase in the subtask satisfies $1 \le H \le 2$.
Subtask 2 [ 80 points ]
* The testcase in the subtask satisfies $1 \le H \le 3$.
Subtask 3 [ 120 points ]
* The testcase in the subtask satisfies $1 \le H, W \le 7$.
Subtask 4 [ 150 points ]
* The testcase in the subtask satisfies $1 \le H, W \le 30$.
Subtask 5 [ 200 points ]
* There are no additional constraints.
Input
The input is given from standard input in the following format.
> $H \ W$ $a_{1, 1} \ a_{1, 2} \ \cdots \ a_{1, W}$ $a_{2, 1} \ a_{2, 2} \ \cdots \ a_{2, W}$ $\vdots \ \ \ \ \ \ \ \ \ \ \vdots \ \ \ \ \ \ \ \ \ \ \vdots$ $a_{H, 1} \ a_{H, 2} \ \cdots \ a_{H, W}$
Examples
Input
3 3
1 0 5
2 2 3
4 2 4
Output
21
Input
6 6
1 2 3 4 5 6
8 6 9 1 2 0
3 1 4 1 5 9
2 6 5 3 5 8
1 4 1 4 2 1
2 7 1 8 2 8
Output
97
Submitted Solution:
```
H, W = map(int, input().split())
A = [list(map(int, input().split())) for i in range(H)]
if H == 1 or W == 1:
print(sum(map(sum, A)))
exit(0)
memo = [{} for i in range(W+H)]
def calc(c, p, q):
yield 0
if c+1-H < p:
yield dfs(c+1, p, q)
if q+1 < W:
yield dfs(c+1, p, q+1)
if p+1 < q:
yield dfs(c+1, p+1, q)
if q+1 < W:
yield dfs(c+1, p+1, q+1)
def dfs(c, p, q):
mc = memo[c]
if (p, q) in mc:
return mc[p, q]
mc[p, q] = r = max(calc(c, p, q)) + A[c-p][p] + A[c-q][q]
return r
print(dfs(1, 0, 1) + A[0][0] + A[-1][-1])
``` | instruction | 0 | 28,148 | 11 | 56,296 |
No | output | 1 | 28,148 | 11 | 56,297 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Input
The input is given from standard input in the following format.
> $H \ W$ $a_{1, 1} \ a_{1, 2} \ \cdots \ a_{1, W}$ $a_{2, 1} \ a_{2, 2} \ \cdots \ a_{2, W}$ $\vdots \ \ \ \ \ \ \ \ \ \ \vdots \ \ \ \ \ \ \ \ \ \ \vdots$ $a_{H, 1} \ a_{H, 2} \ \cdots \ a_{H, W}$
Output
* Print the maximum number of souvenirs they can get.
Constraints
* $1 \le H, W \le 200$
* $0 \le a_{i, j} \le 10^5$
Subtasks
Subtask 1 [ 50 points ]
* The testcase in the subtask satisfies $1 \le H \le 2$.
Subtask 2 [ 80 points ]
* The testcase in the subtask satisfies $1 \le H \le 3$.
Subtask 3 [ 120 points ]
* The testcase in the subtask satisfies $1 \le H, W \le 7$.
Subtask 4 [ 150 points ]
* The testcase in the subtask satisfies $1 \le H, W \le 30$.
Subtask 5 [ 200 points ]
* There are no additional constraints.
Output
* Print the maximum number of souvenirs they can get.
Constraints
* $1 \le H, W \le 200$
* $0 \le a_{i, j} \le 10^5$
Subtasks
Subtask 1 [ 50 points ]
* The testcase in the subtask satisfies $1 \le H \le 2$.
Subtask 2 [ 80 points ]
* The testcase in the subtask satisfies $1 \le H \le 3$.
Subtask 3 [ 120 points ]
* The testcase in the subtask satisfies $1 \le H, W \le 7$.
Subtask 4 [ 150 points ]
* The testcase in the subtask satisfies $1 \le H, W \le 30$.
Subtask 5 [ 200 points ]
* There are no additional constraints.
Input
The input is given from standard input in the following format.
> $H \ W$ $a_{1, 1} \ a_{1, 2} \ \cdots \ a_{1, W}$ $a_{2, 1} \ a_{2, 2} \ \cdots \ a_{2, W}$ $\vdots \ \ \ \ \ \ \ \ \ \ \vdots \ \ \ \ \ \ \ \ \ \ \vdots$ $a_{H, 1} \ a_{H, 2} \ \cdots \ a_{H, W}$
Examples
Input
3 3
1 0 5
2 2 3
4 2 4
Output
21
Input
6 6
1 2 3 4 5 6
8 6 9 1 2 0
3 1 4 1 5 9
2 6 5 3 5 8
1 4 1 4 2 1
2 7 1 8 2 8
Output
97
Submitted Solution:
```
H, W = map(int, input().split())
A = [list(map(int, input().split())) for i in range(H)]
memo = {(W+H-2, H-2, H-1): 0}
def dfs(c, p, q):
if (c, p, q) in memo:
return memo[c, p, q]
res = 0
if c+1-W < p < q < H:
res = max(res, dfs(c+1, p, q))
if c+1-W < p+1 < q < H:
res = max(res, dfs(c+1, p+1, q))
if c+1-W < p < q+1 < H:
res = max(res, dfs(c+1, p, q+1))
if c+1-W < p+1 < q+1 < H:
res = max(res, dfs(c+1, p+1, q+1))
memo[c, p, q] = res = res + A[c-p][p] + A[c-q][q]
return res
print(dfs(1, 0, 1) + A[0][0] + A[-1][-1])
``` | instruction | 0 | 28,149 | 11 | 56,298 |
No | output | 1 | 28,149 | 11 | 56,299 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Input
The input is given from standard input in the following format.
> $H \ W$ $a_{1, 1} \ a_{1, 2} \ \cdots \ a_{1, W}$ $a_{2, 1} \ a_{2, 2} \ \cdots \ a_{2, W}$ $\vdots \ \ \ \ \ \ \ \ \ \ \vdots \ \ \ \ \ \ \ \ \ \ \vdots$ $a_{H, 1} \ a_{H, 2} \ \cdots \ a_{H, W}$
Output
* Print the maximum number of souvenirs they can get.
Constraints
* $1 \le H, W \le 200$
* $0 \le a_{i, j} \le 10^5$
Subtasks
Subtask 1 [ 50 points ]
* The testcase in the subtask satisfies $1 \le H \le 2$.
Subtask 2 [ 80 points ]
* The testcase in the subtask satisfies $1 \le H \le 3$.
Subtask 3 [ 120 points ]
* The testcase in the subtask satisfies $1 \le H, W \le 7$.
Subtask 4 [ 150 points ]
* The testcase in the subtask satisfies $1 \le H, W \le 30$.
Subtask 5 [ 200 points ]
* There are no additional constraints.
Output
* Print the maximum number of souvenirs they can get.
Constraints
* $1 \le H, W \le 200$
* $0 \le a_{i, j} \le 10^5$
Subtasks
Subtask 1 [ 50 points ]
* The testcase in the subtask satisfies $1 \le H \le 2$.
Subtask 2 [ 80 points ]
* The testcase in the subtask satisfies $1 \le H \le 3$.
Subtask 3 [ 120 points ]
* The testcase in the subtask satisfies $1 \le H, W \le 7$.
Subtask 4 [ 150 points ]
* The testcase in the subtask satisfies $1 \le H, W \le 30$.
Subtask 5 [ 200 points ]
* There are no additional constraints.
Input
The input is given from standard input in the following format.
> $H \ W$ $a_{1, 1} \ a_{1, 2} \ \cdots \ a_{1, W}$ $a_{2, 1} \ a_{2, 2} \ \cdots \ a_{2, W}$ $\vdots \ \ \ \ \ \ \ \ \ \ \vdots \ \ \ \ \ \ \ \ \ \ \vdots$ $a_{H, 1} \ a_{H, 2} \ \cdots \ a_{H, W}$
Examples
Input
3 3
1 0 5
2 2 3
4 2 4
Output
21
Input
6 6
1 2 3 4 5 6
8 6 9 1 2 0
3 1 4 1 5 9
2 6 5 3 5 8
1 4 1 4 2 1
2 7 1 8 2 8
Output
97
Submitted Solution:
```
H, W = map(int, input().split())
A = [list(map(int, input().split())) for i in range(H)]
if H <= 2 or W <= 2:
print(sum(map(sum, A)))
exit(0)
def solve(A, W, H):
S = {(0, 1): 0}
for c in range(1, H-1):
T = {}
for p, q in S:
v = S[p, q] + A[c-p][p] + A[c-q][q]
T[p, q] = max(T.get((p, q), 0), v)
if p+1 < q:
T[p+1, q] = max(T.get((p+1, q), 0), v)
if q+1 < W:
T[p, q+1] = max(T.get((p, q+1), 0), v)
T[p+1, q+1] = max(T.get((p+1, q+1), 0), v)
S = T
print(c, S)
return S
B = [e[::-1] for e in A[::-1]]
S0 = solve(A, W, H)
S1 = solve(B, H, W)
print(A[0][0] + A[-1][-1] + max(S0[p, q] + S1[H-1-q, H-1-p] + A[H-1-p][p] + A[H-1-q][q] for p, q in S0))
``` | instruction | 0 | 28,150 | 11 | 56,300 |
No | output | 1 | 28,150 | 11 | 56,301 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Input
The input is given from standard input in the following format.
> $H \ W$ $a_{1, 1} \ a_{1, 2} \ \cdots \ a_{1, W}$ $a_{2, 1} \ a_{2, 2} \ \cdots \ a_{2, W}$ $\vdots \ \ \ \ \ \ \ \ \ \ \vdots \ \ \ \ \ \ \ \ \ \ \vdots$ $a_{H, 1} \ a_{H, 2} \ \cdots \ a_{H, W}$
Output
* Print the maximum number of souvenirs they can get.
Constraints
* $1 \le H, W \le 200$
* $0 \le a_{i, j} \le 10^5$
Subtasks
Subtask 1 [ 50 points ]
* The testcase in the subtask satisfies $1 \le H \le 2$.
Subtask 2 [ 80 points ]
* The testcase in the subtask satisfies $1 \le H \le 3$.
Subtask 3 [ 120 points ]
* The testcase in the subtask satisfies $1 \le H, W \le 7$.
Subtask 4 [ 150 points ]
* The testcase in the subtask satisfies $1 \le H, W \le 30$.
Subtask 5 [ 200 points ]
* There are no additional constraints.
Output
* Print the maximum number of souvenirs they can get.
Constraints
* $1 \le H, W \le 200$
* $0 \le a_{i, j} \le 10^5$
Subtasks
Subtask 1 [ 50 points ]
* The testcase in the subtask satisfies $1 \le H \le 2$.
Subtask 2 [ 80 points ]
* The testcase in the subtask satisfies $1 \le H \le 3$.
Subtask 3 [ 120 points ]
* The testcase in the subtask satisfies $1 \le H, W \le 7$.
Subtask 4 [ 150 points ]
* The testcase in the subtask satisfies $1 \le H, W \le 30$.
Subtask 5 [ 200 points ]
* There are no additional constraints.
Input
The input is given from standard input in the following format.
> $H \ W$ $a_{1, 1} \ a_{1, 2} \ \cdots \ a_{1, W}$ $a_{2, 1} \ a_{2, 2} \ \cdots \ a_{2, W}$ $\vdots \ \ \ \ \ \ \ \ \ \ \vdots \ \ \ \ \ \ \ \ \ \ \vdots$ $a_{H, 1} \ a_{H, 2} \ \cdots \ a_{H, W}$
Examples
Input
3 3
1 0 5
2 2 3
4 2 4
Output
21
Input
6 6
1 2 3 4 5 6
8 6 9 1 2 0
3 1 4 1 5 9
2 6 5 3 5 8
1 4 1 4 2 1
2 7 1 8 2 8
Output
97
Submitted Solution:
```
#tle -solution
import copy
def main():
H,W = map(int,input().split())
data = [[0]+list(map(int,input().split())) for i in range(H)]
a = copy.deepcopy(data)
for i in range(H):
for j in range(1,W+1):
data[i][j] += data[i][j-1]
#dp[height][left][right] assert 1<=height<=H, 1<=left<right<=W
dp = [[[0]*(W+1) for j in range(W+1)] for i in range(H+1)]
#initializaton : height is 1.
for i in range(1,W+1):
for j in range(i,W+1):
dp[1][i][j] =data[0][j]
for height in range(2,H+1):
for i in range(1,W+1):
for j in range(i+1,W+1):
dp[height][i][j] = max(max(dp[height-1][i][k] +data[height-1][j]-data[height-1][k-1] for k in range(i+1,j+1))+a[height-1][i],dp[height][i][j])
dp[height][i][j] = max(max(dp[height-1][l][j]+data[height-1][i]-data[height-1][l-1] for l in range(1,i+1))+a[height-1][j],dp[height][i][j])
if i > 1:
dp[height][i][j] = max(dp[height][i-1][j],dp[height][i][j-1],dp[height][i][j])
ans = max(dp[H][i][i+1]+data[-1][W] -data[-1][i+1] for i in range(1,W))
print(ans)
return
if __name__ == "__main__":
main()
``` | instruction | 0 | 28,151 | 11 | 56,302 |
No | output | 1 | 28,151 | 11 | 56,303 |
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