message stringlengths 2 433k | message_type stringclasses 2
values | message_id int64 0 1 | conversation_id int64 113 108k | cluster float64 12 12 | __index_level_0__ int64 226 217k |
|---|---|---|---|---|---|
Provide tags and a correct Python 3 solution for this coding contest problem.
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of n... | instruction | 0 | 70,137 | 12 | 140,274 |
Tags: binary search, greedy, sortings
Correct Solution:
```
n, k = (int(x) for x in input().split())
a = [int(x) for x in input().split()]
exclude = set()
ans = 0
a.sort()
for i in a:
if i not in exclude:
exclude.add(i*k)
ans += 1
print(ans)
``` | output | 1 | 70,137 | 12 | 140,275 |
Provide tags and a correct Python 3 solution for this coding contest problem.
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of n... | instruction | 0 | 70,138 | 12 | 140,276 |
Tags: binary search, greedy, sortings
Correct Solution:
```
from collections import OrderedDict
def kmultiple(x, k):
c = 0
for e in x:
if x[e] != 0:
c += 1
if e*k in x:
x[e*k] = 0
return c
if __name__ == '__main__':
x = OrderedDict()
_, k = input().... | output | 1 | 70,138 | 12 | 140,277 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the s... | instruction | 0 | 70,140 | 12 | 140,280 |
Yes | output | 1 | 70,140 | 12 | 140,281 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the s... | instruction | 0 | 70,141 | 12 | 140,282 |
Yes | output | 1 | 70,141 | 12 | 140,283 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the s... | instruction | 0 | 70,142 | 12 | 140,284 |
Yes | output | 1 | 70,142 | 12 | 140,285 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the s... | instruction | 0 | 70,143 | 12 | 140,286 |
No | output | 1 | 70,143 | 12 | 140,287 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the s... | instruction | 0 | 70,145 | 12 | 140,290 |
No | output | 1 | 70,145 | 12 | 140,291 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the s... | instruction | 0 | 70,146 | 12 | 140,292 |
No | output | 1 | 70,146 | 12 | 140,293 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Polar bears like unique arrays — that is, arrays without repeated elements.
You have got a unique array s with length n containing non-negative integers. Since you are good friends with Alice a... | instruction | 0 | 70,147 | 12 | 140,294 |
No | output | 1 | 70,147 | 12 | 140,295 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Polar bears like unique arrays — that is, arrays without repeated elements.
You have got a unique array s with length n containing non-negative integers. Since you are good friends with Alice a... | instruction | 0 | 70,148 | 12 | 140,296 |
No | output | 1 | 70,148 | 12 | 140,297 |
Provide a correct Python 3 solution for this coding contest problem.
For a given array $a_1, a_2, a_3, ... , a_N$ of $N$ elements and an integer $K$, find the smallest sub-array size (smallest window length) where the elements in the sub-array contains all integers in range [$1, 2, ..., K$]. If there is no such sub-ar... | instruction | 0 | 70,724 | 12 | 141,448 |
"Correct Solution:
```
class SegmentTree():
def __init__(self, arr, func=min, ie=2**63):
self.h = (len(arr) - 1).bit_length()
self.n = 2**self.h
self.ie = ie
self.func = func
self.tree = [ie for _ in range(2 * self.n)]
for i in range(len(arr)):
self.tree[s... | output | 1 | 70,724 | 12 | 141,449 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The only difference between easy and hard versions is the number of elements in the array.
You are given an array a consisting of n integers. In one move you can choose any a_i and divide it by 2 rounding down (in other words, in one move y... | instruction | 0 | 70,833 | 12 | 141,666 |
Tags: brute force, math, sortings
Correct Solution:
```
from sys import stdin,stdout
from math import gcd,sqrt,inf
from collections import deque
input=stdin.readline
R=lambda:map(int,input().split())
I=lambda:int(input())
S=lambda:input().rstrip('\n')
L=lambda:list(R())
P=lambda x:stdout.write(x)
hg=lambda x,y:((y+x-1)... | output | 1 | 70,833 | 12 | 141,667 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The only difference between easy and hard versions is the number of elements in the array.
You are given an array a consisting of n integers. In one move you can choose any a_i and divide it by 2 rounding down (in other words, in one move y... | instruction | 0 | 70,834 | 12 | 141,668 |
Tags: brute force, math, sortings
Correct Solution:
```
#Code by Sounak, IIESTS
#------------------------------warmup----------------------------
import os
import sys
import math
from io import BytesIO, IOBase
from fractions import Fraction
import collections
from itertools import permutations
from collections import ... | output | 1 | 70,834 | 12 | 141,669 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The only difference between easy and hard versions is the number of elements in the array.
You are given an array a consisting of n integers. In one move you can choose any a_i and divide it by 2 rounding down (in other words, in one move y... | instruction | 0 | 70,835 | 12 | 141,670 |
Tags: brute force, math, sortings
Correct Solution:
```
n,m = list(map(int,input().split()))
a = list(map(int,input().split()))
f = {}
for i in a:
it = 0
while i>0:
if i in f:
f[i].append(it)
else:
f[i] = [it]
i//=2
it+=1
s = 1e10
for i in f:
if len(f[... | output | 1 | 70,835 | 12 | 141,671 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The only difference between easy and hard versions is the number of elements in the array.
You are given an array a consisting of n integers. In one move you can choose any a_i and divide it by 2 rounding down (in other words, in one move y... | instruction | 0 | 70,836 | 12 | 141,672 |
Tags: brute force, math, sortings
Correct Solution:
```
b = {}
n, k = map(int, input().split())
a = list(map(int, input().split()))
b[0] = []
for x in a:
j = 0
while(x > 0):
if(x in b):
b[x].append(j)
else:
b[x] = [j]
x //= 2
j += 1
b[0].append(j)
ans... | output | 1 | 70,836 | 12 | 141,673 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The only difference between easy and hard versions is the number of elements in the array.
You are given an array a consisting of n integers. In one move you can choose any a_i and divide it by 2 rounding down (in other words, in one move y... | instruction | 0 | 70,837 | 12 | 141,674 |
Tags: brute force, math, sortings
Correct Solution:
```
import os
import heapq
import sys
import math
import operator
from collections import defaultdict
from io import BytesIO, IOBase
# def gcd(a,b):
# if b==0:
# return a
# else:
# return gcd(b,a%b)
def inar():
return [int(k) for k in inpu... | output | 1 | 70,837 | 12 | 141,675 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The only difference between easy and hard versions is the number of elements in the array.
You are given an array a consisting of n integers. In one move you can choose any a_i and divide it by 2 rounding down (in other words, in one move y... | instruction | 0 | 70,838 | 12 | 141,676 |
Tags: brute force, math, sortings
Correct Solution:
```
from __future__ import division, print_function
import math
import sys
import os
from io import BytesIO, IOBase
BUFSIZE = 8192
class FastIO(IOBase):
newlines = 0
def __init__(self, file):
self._fd = file.fileno()
self.buffer = BytesIO()
self.writable =... | output | 1 | 70,838 | 12 | 141,677 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The only difference between easy and hard versions is the number of elements in the array.
You are given an array a consisting of n integers. In one move you can choose any a_i and divide it by 2 rounding down (in other words, in one move y... | instruction | 0 | 70,839 | 12 | 141,678 |
Tags: brute force, math, sortings
Correct Solution:
```
n,k = map(int,input().split())
l = list(map(int,input().split()))
count = [0]*((2*(10**5)) + 1)
no = [0]*((2*(10**5)) + 1)
ans = float('inf')
l.sort()
for i in l:
c = 0
e = 0
while i>0:
if no[i]<k:
count[i]+=c
no[i]+=1
... | output | 1 | 70,839 | 12 | 141,679 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The only difference between easy and hard versions is the number of elements in the array.
You are given an array a consisting of n integers. In one move you can choose any a_i and divide it by 2 rounding down (in other words, in one move y... | instruction | 0 | 70,840 | 12 | 141,680 |
Tags: brute force, math, sortings
Correct Solution:
```
n, k = map(int, input().split())
l = list(map(int, input().split()))
b = [[] for i in range(2*10**5+1)]
for a in l:
cnt = 0
while (a > 0):
b[a].append(cnt)
cnt += 1
a = a // 2
ans = 1000000000
for x in b:
if len(x) >= k:
x = sorted(x)
ans = min(ans, s... | output | 1 | 70,840 | 12 | 141,681 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The only difference between easy and hard versions is the number of elements in the array.
You are given an array a consisting of n integers. In one move you can choose any a_i and divide it by... | instruction | 0 | 70,841 | 12 | 141,682 |
Yes | output | 1 | 70,841 | 12 | 141,683 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The only difference between easy and hard versions is the number of elements in the array.
You are given an array a consisting of n integers. In one move you can choose any a_i and divide it by... | instruction | 0 | 70,842 | 12 | 141,684 |
Yes | output | 1 | 70,842 | 12 | 141,685 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The only difference between easy and hard versions is the number of elements in the array.
You are given an array a consisting of n integers. In one move you can choose any a_i and divide it by... | instruction | 0 | 70,843 | 12 | 141,686 |
Yes | output | 1 | 70,843 | 12 | 141,687 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The only difference between easy and hard versions is the number of elements in the array.
You are given an array a consisting of n integers. In one move you can choose any a_i and divide it by... | instruction | 0 | 70,844 | 12 | 141,688 |
Yes | output | 1 | 70,844 | 12 | 141,689 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The only difference between easy and hard versions is the number of elements in the array.
You are given an array a consisting of n integers. In one move you can choose any a_i and divide it by... | instruction | 0 | 70,845 | 12 | 141,690 |
No | output | 1 | 70,845 | 12 | 141,691 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The only difference between easy and hard versions is the number of elements in the array.
You are given an array a consisting of n integers. In one move you can choose any a_i and divide it by... | instruction | 0 | 70,846 | 12 | 141,692 |
No | output | 1 | 70,846 | 12 | 141,693 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The only difference between easy and hard versions is the number of elements in the array.
You are given an array a consisting of n integers. In one move you can choose any a_i and divide it by... | instruction | 0 | 70,847 | 12 | 141,694 |
No | output | 1 | 70,847 | 12 | 141,695 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The only difference between easy and hard versions is the number of elements in the array.
You are given an array a consisting of n integers. In one move you can choose any a_i and divide it by... | instruction | 0 | 70,848 | 12 | 141,696 |
No | output | 1 | 70,848 | 12 | 141,697 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Anu has created her own function f: f(x, y) = (x | y) - y where | denotes the [bitwise OR operation](https://en.wikipedia.org/wiki/Bitwise_operation#OR). For example, f(11, 6) = (11|6) - 6 = 15 - 6 = 9. It can be proved that for any nonnegat... | instruction | 0 | 70,862 | 12 | 141,724 |
Tags: brute force, greedy, math
Correct Solution:
```
import sys
n = int(sys.stdin.readline().split()[0])
a = list(map(int, sys.stdin.readline().split()))
b = [x for x in a]
idx = -1
while max(b) != 0:
c = [x&1 for x in b]
if c.count(1) == 1:
idx = c.index(1)
b = [x>>1 for x in b]
if idx >= 0:
... | output | 1 | 70,862 | 12 | 141,725 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Anu has created her own function f: f(x, y) = (x | y) - y where | denotes the [bitwise OR operation](https://en.wikipedia.org/wiki/Bitwise_operation#OR). For example, f(11, 6) = (11|6) - 6 = 15 - 6 = 9. It can be proved that for any nonnegat... | instruction | 0 | 70,863 | 12 | 141,726 |
Tags: brute force, greedy, math
Correct Solution:
```
n=int(input())
arr=[[] for i in range(32)]
l=input().split()
li=[int(i) for i in l]
for i in li:
for j in range(32):
if(i&(1<<j)):
arr[j].append(i)
maxa=-1
for i in range(31,-1,-1):
if(len(arr[i])==1):
maxa=arr[i][0]
break... | output | 1 | 70,863 | 12 | 141,727 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Anu has created her own function f: f(x, y) = (x | y) - y where | denotes the [bitwise OR operation](https://en.wikipedia.org/wiki/Bitwise_operation#OR). For example, f(11, 6) = (11|6) - 6 = 15 - 6 = 9. It can be proved that for any nonnegat... | instruction | 0 | 70,864 | 12 | 141,728 |
Tags: brute force, greedy, math
Correct Solution:
```
n=int(input())
a=[int(x) for x in input().split()]
l=sorted(a,reverse=True)
x=l[0]
bits=0
while(x>0):
x= x>>1
bits+=1
num=0
for i in range(bits):
count=0
ind=0
z= 1<<bits-i-1
for j in range(len(a)):
if z&l[j] == z:
count+=1
ind=j
if count>1:
brea... | output | 1 | 70,864 | 12 | 141,729 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Anu has created her own function f: f(x, y) = (x | y) - y where | denotes the [bitwise OR operation](https://en.wikipedia.org/wiki/Bitwise_operation#OR). For example, f(11, 6) = (11|6) - 6 = 15 - 6 = 9. It can be proved that for any nonnegat... | instruction | 0 | 70,865 | 12 | 141,730 |
Tags: brute force, greedy, math
Correct Solution:
```
import math
def main():
n = int(input())
a = list(map(int, input().split()))
lst = [[] for _ in range(30)]
for i in a:
nm = bin(i)[2:]
o = 0
for k in range(len(nm) - 1, -1, -1):
if nm[k] == "1":
... | output | 1 | 70,865 | 12 | 141,731 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Anu has created her own function f: f(x, y) = (x | y) - y where | denotes the [bitwise OR operation](https://en.wikipedia.org/wiki/Bitwise_operation#OR). For example, f(11, 6) = (11|6) - 6 = 15 - 6 = 9. It can be proved that for any nonnegat... | instruction | 0 | 70,866 | 12 | 141,732 |
Tags: brute force, greedy, math
Correct Solution:
```
import os,io
input = io.BytesIO(os.read(0,os.fstat(0).st_size)).readline
n = int(input())
a = list(map(int,input().split()))
bitc = [0]*32
for v in a:
i = 0
while v:
if v&1:
bitc[i]+=1
i+=1
v >>= 1
bits = 0
for i in range... | output | 1 | 70,866 | 12 | 141,733 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Anu has created her own function f: f(x, y) = (x | y) - y where | denotes the [bitwise OR operation](https://en.wikipedia.org/wiki/Bitwise_operation#OR). For example, f(11, 6) = (11|6) - 6 = 15 - 6 = 9. It can be proved that for any nonnegat... | instruction | 0 | 70,867 | 12 | 141,734 |
Tags: brute force, greedy, math
Correct Solution:
```
from sys import *
from math import *
from bisect import *
n=int(stdin.readline())
a=list(map(int,stdin.readline().split()))
for i in range(32,-1,-1):
s=x=0
for j in range(n):
if 1<<i & a[j]!=0:
x=j
s+=1
if s==1:
br... | output | 1 | 70,867 | 12 | 141,735 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Anu has created her own function f: f(x, y) = (x | y) - y where | denotes the [bitwise OR operation](https://en.wikipedia.org/wiki/Bitwise_operation#OR). For example, f(11, 6) = (11|6) - 6 = 15 - 6 = 9. It can be proved that for any nonnegat... | instruction | 0 | 70,868 | 12 | 141,736 |
Tags: brute force, greedy, math
Correct Solution:
```
n = int(input())
vals = list(map(int, input().split()))
pref, suff = [0] * (n + 1), [0] * (n + 1)
for i in range(n):
pref[i + 1] = pref[i] | vals[i]
suff[n - i - 1] = suff[n - i] | vals[n - i - 1]
ret = (-float('inf'), -float('inf'))
for i, a in enumerate(va... | output | 1 | 70,868 | 12 | 141,737 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Anu has created her own function f: f(x, y) = (x | y) - y where | denotes the [bitwise OR operation](https://en.wikipedia.org/wiki/Bitwise_operation#OR). For example, f(11, 6) = (11|6) - 6 = 15 - 6 = 9. It can be proved that for any nonnegat... | instruction | 0 | 70,869 | 12 | 141,738 |
Tags: brute force, greedy, math
Correct Solution:
```
from math import ceil ,log2
def f(a):
mx=0
item=None
pref=[~a[0]]
for i in range(1,len(a)):
pref.append(pref[-1]&(~a[i]))
suf=[~a[-1]]
for i in range(len(a)-1-1,-1,-1):
suf.append(suf[-1]&(~a[i]))
suf=suf[::-1]
for i in range(len(a)):
ll=(1<<60)-1
... | output | 1 | 70,869 | 12 | 141,739 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Anu has created her own function f: f(x, y) = (x | y) - y where | denotes the [bitwise OR operation](https://en.wikipedia.org/wiki/Bitwise_operation#OR). For example, f(11, 6) = (11|6) - 6 = 15 ... | instruction | 0 | 70,870 | 12 | 141,740 |
Yes | output | 1 | 70,870 | 12 | 141,741 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Anu has created her own function f: f(x, y) = (x | y) - y where | denotes the [bitwise OR operation](https://en.wikipedia.org/wiki/Bitwise_operation#OR). For example, f(11, 6) = (11|6) - 6 = 15 ... | instruction | 0 | 70,871 | 12 | 141,742 |
Yes | output | 1 | 70,871 | 12 | 141,743 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Anu has created her own function f: f(x, y) = (x | y) - y where | denotes the [bitwise OR operation](https://en.wikipedia.org/wiki/Bitwise_operation#OR). For example, f(11, 6) = (11|6) - 6 = 15 ... | instruction | 0 | 70,872 | 12 | 141,744 |
Yes | output | 1 | 70,872 | 12 | 141,745 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Anu has created her own function f: f(x, y) = (x | y) - y where | denotes the [bitwise OR operation](https://en.wikipedia.org/wiki/Bitwise_operation#OR). For example, f(11, 6) = (11|6) - 6 = 15 ... | instruction | 0 | 70,873 | 12 | 141,746 |
Yes | output | 1 | 70,873 | 12 | 141,747 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Anu has created her own function f: f(x, y) = (x | y) - y where | denotes the [bitwise OR operation](https://en.wikipedia.org/wiki/Bitwise_operation#OR). For example, f(11, 6) = (11|6) - 6 = 15 ... | instruction | 0 | 70,874 | 12 | 141,748 |
No | output | 1 | 70,874 | 12 | 141,749 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Anu has created her own function f: f(x, y) = (x | y) - y where | denotes the [bitwise OR operation](https://en.wikipedia.org/wiki/Bitwise_operation#OR). For example, f(11, 6) = (11|6) - 6 = 15 ... | instruction | 0 | 70,875 | 12 | 141,750 |
No | output | 1 | 70,875 | 12 | 141,751 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Anu has created her own function f: f(x, y) = (x | y) - y where | denotes the [bitwise OR operation](https://en.wikipedia.org/wiki/Bitwise_operation#OR). For example, f(11, 6) = (11|6) - 6 = 15 ... | instruction | 0 | 70,876 | 12 | 141,752 |
No | output | 1 | 70,876 | 12 | 141,753 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Anu has created her own function f: f(x, y) = (x | y) - y where | denotes the [bitwise OR operation](https://en.wikipedia.org/wiki/Bitwise_operation#OR). For example, f(11, 6) = (11|6) - 6 = 15 ... | instruction | 0 | 70,877 | 12 | 141,754 |
No | output | 1 | 70,877 | 12 | 141,755 |
Provide tags and a correct Python 3 solution for this coding contest problem.
We will consider the numbers a and b as adjacent if they differ by exactly one, that is, |a-b|=1.
We will consider cells of a square matrix n × n as adjacent if they have a common side, that is, for cell (r, c) cells (r, c-1), (r, c+1), (r-... | instruction | 0 | 70,977 | 12 | 141,954 |
Tags: constructive algorithms
Correct Solution:
```
for i in range(int(input())):
n = int(input())
if n==2:
print(-1)
else:
odd = []
even = []
case = False
for i in range(1,n**2+1):
if case:
even.append(i)
else:
odd.append(i)
case = not case
arr = odd+even
prev = 0
for i in range(n):... | output | 1 | 70,977 | 12 | 141,955 |
Provide tags and a correct Python 3 solution for this coding contest problem.
We will consider the numbers a and b as adjacent if they differ by exactly one, that is, |a-b|=1.
We will consider cells of a square matrix n × n as adjacent if they have a common side, that is, for cell (r, c) cells (r, c-1), (r, c+1), (r-... | instruction | 0 | 70,978 | 12 | 141,956 |
Tags: constructive algorithms
Correct Solution:
```
for test in range(int(input())):
n = int(input())
if n == 1:
print(1)
continue
elif n == 2:
print(-1)
continue
else:
# lst = list(range(1, n ** 2 + 1))
# print(lst)
ans = [[0] * n for i in range(n... | output | 1 | 70,978 | 12 | 141,957 |
Provide tags and a correct Python 3 solution for this coding contest problem.
We will consider the numbers a and b as adjacent if they differ by exactly one, that is, |a-b|=1.
We will consider cells of a square matrix n × n as adjacent if they have a common side, that is, for cell (r, c) cells (r, c-1), (r, c+1), (r-... | instruction | 0 | 70,979 | 12 | 141,958 |
Tags: constructive algorithms
Correct Solution:
```
from io import BytesIO, IOBase
from math import sqrt
import sys,os,math
from os import path
int_inpl=lambda:list(map(int,input().split()))
int_inpm=lambda:map(int,input().split())
int_inp=lambda:int(input())
inp=lambda:input()
from collections import Counter
import h... | output | 1 | 70,979 | 12 | 141,959 |
Provide tags and a correct Python 3 solution for this coding contest problem.
We will consider the numbers a and b as adjacent if they differ by exactly one, that is, |a-b|=1.
We will consider cells of a square matrix n × n as adjacent if they have a common side, that is, for cell (r, c) cells (r, c-1), (r, c+1), (r-... | instruction | 0 | 70,983 | 12 | 141,966 |
Tags: constructive algorithms
Correct Solution:
```
##### HAR HAR MAHADEV || JAI SHREE RAM #####
### @created by SHATMANYU GUPTA(shatmanyu_04) ###
mod=pow(10,9)+7;MOD=998244353
## PE -> end=" " ##
from sys import stdin,stdout ; from heapq import heapify,heappush,heappop;from bisect import bisect,bisect_left,bisec... | output | 1 | 70,983 | 12 | 141,967 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
We will consider the numbers a and b as adjacent if they differ by exactly one, that is, |a-b|=1.
We will consider cells of a square matrix n × n as adjacent if they have a common side, that is... | instruction | 0 | 70,988 | 12 | 141,976 |
Yes | output | 1 | 70,988 | 12 | 141,977 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Petya is a beginner programmer. He has already mastered the basics of the C++ language and moved on to learning algorithms. The first algorithm he encountered was insertion sort. Petya has already written the code that implements this algori... | instruction | 0 | 71,083 | 12 | 142,166 |
Tags: data structures, dp, implementation, math
Correct Solution:
```
arr = [0 for i in range(5001)]
def insertion_sort(n, a):
def modify(t):
while t > 0:
arr[t] += 1
t -= t & (-t)
def query(t):
res = 0
while t < 5001:
res += arr[t]
t +=... | output | 1 | 71,083 | 12 | 142,167 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Petya is a beginner programmer. He has already mastered the basics of the C++ language and moved on to learning algorithms. The first algorithm he encountered was insertion sort. Petya has alrea... | instruction | 0 | 71,084 | 12 | 142,168 |
No | output | 1 | 71,084 | 12 | 142,169 |
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