message stringlengths 2 433k | message_type stringclasses 2
values | message_id int64 0 1 | conversation_id int64 113 108k | cluster float64 12 12 | __index_level_0__ int64 226 217k |
|---|---|---|---|---|---|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the s... | instruction | 0 | 78,584 | 12 | 157,168 |
No | output | 1 | 78,584 | 12 | 157,169 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the s... | instruction | 0 | 78,585 | 12 | 157,170 |
No | output | 1 | 78,585 | 12 | 157,171 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the s... | instruction | 0 | 78,586 | 12 | 157,172 |
No | output | 1 | 78,586 | 12 | 157,173 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the s... | instruction | 0 | 78,587 | 12 | 157,174 |
No | output | 1 | 78,587 | 12 | 157,175 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Amr has got a large array of size n. Amr doesn't like large arrays so he intends to make it smaller.
Amr doesn't care about anything in the array except the beauty of it. The beauty of the array is defined to be the maximum number of times ... | instruction | 0 | 78,696 | 12 | 157,392 |
Tags: implementation
Correct Solution:
```
n = int(input())
numbers = [ int(number) for number in input().split() ]
occurences = {}
for i in range(n):
number = numbers[i]
if number in occurences.keys():
occurences[number][0] += 1
occurences[number][2] = i+1
else:
occurences[number] = [ 1, i+1, -1 ]
result = ... | output | 1 | 78,696 | 12 | 157,393 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Amr has got a large array of size n. Amr doesn't like large arrays so he intends to make it smaller.
Amr doesn't care about anything in the array except the beauty of it. The beauty of the array is defined to be the maximum number of times ... | instruction | 0 | 78,697 | 12 | 157,394 |
Tags: implementation
Correct Solution:
```
#!/usr/bin/env python3
import sys
N = int(input())
A = list(map(int, input().split(' ')))
left_idx = {}
right_idx = {}
count = {}
for i, e in enumerate(A):
if e not in count:
count[e] = 0
count[e] += 1
if e not in left_idx:
left_idx[e] = i
i... | output | 1 | 78,697 | 12 | 157,395 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Amr has got a large array of size n. Amr doesn't like large arrays so he intends to make it smaller.
Amr doesn't care about anything in the array except the beauty of it. The beauty of the array is defined to be the maximum number of times ... | instruction | 0 | 78,698 | 12 | 157,396 |
Tags: implementation
Correct Solution:
```
from collections import defaultdict
N = int(input())
A = [int(x) for x in input().split()]
bucket = defaultdict(list)
for i, num in enumerate(A):
bucket[num].append(i)
sorted_buckets = sorted(bucket.values(), key=lambda val: (-len(val), val[-1]-val[0]))
print(sorted_buck... | output | 1 | 78,698 | 12 | 157,397 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Amr has got a large array of size n. Amr doesn't like large arrays so he intends to make it smaller.
Amr doesn't care about anything in the array except the beauty of it. The beauty of the array is defined to be the maximum number of times ... | instruction | 0 | 78,699 | 12 | 157,398 |
Tags: implementation
Correct Solution:
```
import collections
def findsubsegment(l, nums):
freq_map = collections.Counter(nums)
beauty = max(freq_map.items(), key = lambda x: x[1])[1]
keys = {}
if beauty == 1:
print("1 1")
return
for key, val in freq_map.items():
if val == b... | output | 1 | 78,699 | 12 | 157,399 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Amr has got a large array of size n. Amr doesn't like large arrays so he intends to make it smaller.
Amr doesn't care about anything in the array except the beauty of it. The beauty of the array is defined to be the maximum number of times ... | instruction | 0 | 78,700 | 12 | 157,400 |
Tags: implementation
Correct Solution:
```
import sys
def fastio():
from io import StringIO
from atexit import register
global input
sys.stdin = StringIO(sys.stdin.read())
input = lambda : sys.stdin.readline().rstrip('\r\n')
sys.stdout = StringIO()
register(lambda : sys.__stdout__.write(sys.... | output | 1 | 78,700 | 12 | 157,401 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Amr has got a large array of size n. Amr doesn't like large arrays so he intends to make it smaller.
Amr doesn't care about anything in the array except the beauty of it. The beauty of the array is defined to be the maximum number of times ... | instruction | 0 | 78,701 | 12 | 157,402 |
Tags: implementation
Correct Solution:
```
n=int(input())
L=list(map(int,input().split()))
A=[0]*(10**6+1)
B=[0]*(10**6+1)
C=[0]*(10**6+1)
for i in range(len(L)):
x=L[i]
if A[x]==0:
B[x]=i
A[x]=A[x]+1
C[x]=i
maxi=A[0]
diff=10**6
pos=0
for i in range(1,len(A)):
if A[i]>maxi:
... | output | 1 | 78,701 | 12 | 157,403 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Amr has got a large array of size n. Amr doesn't like large arrays so he intends to make it smaller.
Amr doesn't care about anything in the array except the beauty of it. The beauty of the array is defined to be the maximum number of times ... | instruction | 0 | 78,702 | 12 | 157,404 |
Tags: implementation
Correct Solution:
```
from collections import defaultdict
n = int(input())
a = list(map(int, input().split()))
d = defaultdict(list)
for i, v in enumerate(a):
d[v].append(i)
bestSize = -float('inf')
bestLen = float('inf')
l = r = None
for cnt in d.values():
i, j = cnt[0], cnt[-1]
if (l... | output | 1 | 78,702 | 12 | 157,405 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Amr has got a large array of size n. Amr doesn't like large arrays so he intends to make it smaller.
Amr doesn't care about anything in the array except the beauty of it. The beauty of the array is defined to be the maximum number of times ... | instruction | 0 | 78,703 | 12 | 157,406 |
Tags: implementation
Correct Solution:
```
N = int(input())
A = [int(x) for x in input().split()]
bucket = dict()
for i, num in enumerate(A):
if num in bucket:
bucket[num].append(i)
else:
bucket[num] = [i]
#print(bucket)
sorted_buckets = sorted((-len(val), val[-1]-val[0], val) for _, val in buck... | output | 1 | 78,703 | 12 | 157,407 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Amr has got a large array of size n. Amr doesn't like large arrays so he intends to make it smaller.
Amr doesn't care about anything in the array except the beauty of it. The beauty of the arra... | instruction | 0 | 78,704 | 12 | 157,408 |
Yes | output | 1 | 78,704 | 12 | 157,409 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Amr has got a large array of size n. Amr doesn't like large arrays so he intends to make it smaller.
Amr doesn't care about anything in the array except the beauty of it. The beauty of the arra... | instruction | 0 | 78,705 | 12 | 157,410 |
Yes | output | 1 | 78,705 | 12 | 157,411 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Amr has got a large array of size n. Amr doesn't like large arrays so he intends to make it smaller.
Amr doesn't care about anything in the array except the beauty of it. The beauty of the arra... | instruction | 0 | 78,706 | 12 | 157,412 |
Yes | output | 1 | 78,706 | 12 | 157,413 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Amr has got a large array of size n. Amr doesn't like large arrays so he intends to make it smaller.
Amr doesn't care about anything in the array except the beauty of it. The beauty of the arra... | instruction | 0 | 78,707 | 12 | 157,414 |
Yes | output | 1 | 78,707 | 12 | 157,415 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Amr has got a large array of size n. Amr doesn't like large arrays so he intends to make it smaller.
Amr doesn't care about anything in the array except the beauty of it. The beauty of the arra... | instruction | 0 | 78,708 | 12 | 157,416 |
No | output | 1 | 78,708 | 12 | 157,417 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Amr has got a large array of size n. Amr doesn't like large arrays so he intends to make it smaller.
Amr doesn't care about anything in the array except the beauty of it. The beauty of the arra... | instruction | 0 | 78,709 | 12 | 157,418 |
No | output | 1 | 78,709 | 12 | 157,419 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Amr has got a large array of size n. Amr doesn't like large arrays so he intends to make it smaller.
Amr doesn't care about anything in the array except the beauty of it. The beauty of the arra... | instruction | 0 | 78,710 | 12 | 157,420 |
No | output | 1 | 78,710 | 12 | 157,421 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Amr has got a large array of size n. Amr doesn't like large arrays so he intends to make it smaller.
Amr doesn't care about anything in the array except the beauty of it. The beauty of the arra... | instruction | 0 | 78,711 | 12 | 157,422 |
No | output | 1 | 78,711 | 12 | 157,423 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given an infinite periodic array a0, a1, ..., an - 1, ... with the period of length n. Formally, <image>. A periodic subarray (l, s) (0 ≤ l < n, 1 ≤ s < n) of array a is an infinite peri... | instruction | 0 | 78,712 | 12 | 157,424 |
No | output | 1 | 78,712 | 12 | 157,425 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Vladik had started reading a complicated book about algorithms containing n pages. To improve understanding of what is written, his friends advised him to read pages in some order given by permutation P = [p1, p2, ..., pn], where pi denotes ... | instruction | 0 | 78,790 | 12 | 157,580 |
Tags: implementation, sortings
Correct Solution:
```
x,y=map(int,input().split())
t=0
awan=list(map(int,input().split()))
for v in range(0,y) :
l,r,x=map(int,input().split())
l-=1
x-=1
t=0
for j in range(l,r):
if awan[x]>awan[j] :
t+=1
if (l+t)==x :
print("Yes")
... | output | 1 | 78,790 | 12 | 157,581 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Vladik had started reading a complicated book about algorithms containing n pages. To improve understanding of what is written, his friends advised him to read pages in some order given by permutation P = [p1, p2, ..., pn], where pi denotes ... | instruction | 0 | 78,791 | 12 | 157,582 |
Tags: implementation, sortings
Correct Solution:
```
n,m = map(int,input().split())
a = list(map(int,input().split()))
d = dict()
for _ in range(m):
l,r,x = map(int,input().split())
if x > r or x < l:
print("Yes")
else:
b = a[l-1:r]
res = 0
for item in b:
if item ... | output | 1 | 78,791 | 12 | 157,583 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Vladik had started reading a complicated book about algorithms containing n pages. To improve understanding of what is written, his friends advised him to read pages in some order given by permutation P = [p1, p2, ..., pn], where pi denotes ... | instruction | 0 | 78,792 | 12 | 157,584 |
Tags: implementation, sortings
Correct Solution:
```
n,m=map(int,input().split())
a=list(map(int,input().split()))
for i in range(m):
l,r,x=map(lambda x:int(x)-1,input().split())
for j in range(l,r+1):
if a[j]<a[x]:
l+=1
if l>x:
break
if l==x:
print('Y... | output | 1 | 78,792 | 12 | 157,585 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Vladik had started reading a complicated book about algorithms containing n pages. To improve understanding of what is written, his friends advised him to read pages in some order given by permutation P = [p1, p2, ..., pn], where pi denotes ... | instruction | 0 | 78,793 | 12 | 157,586 |
Tags: implementation, sortings
Correct Solution:
```
n, m = list(map(int, input().split()))
p = list(map(int, input().split()))
for _ in range(m):
l, r, x = map(int, input().split())
l -= 1
r -= 1
x -= 1
a = 0
t = p[x]
for s in p[l:r+1]:
if s < t:
a += 1
if a == x - l... | output | 1 | 78,793 | 12 | 157,587 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Vladik had started reading a complicated book about algorithms containing n pages. To improve understanding of what is written, his friends advised him to read pages in some order given by permutation P = [p1, p2, ..., pn], where pi denotes ... | instruction | 0 | 78,794 | 12 | 157,588 |
Tags: implementation, sortings
Correct Solution:
```
n, m = map(int, input().split())
p = list(map(int, input().split()))
for _ in range(m):
l, r, x = map(int, input().split())
y = p[x-1]
c = 0
for z in range(l-1, r):
if p[z] < y:
c += 1
print("Yes" if c == x-l else "No")
``` | output | 1 | 78,794 | 12 | 157,589 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Vladik had started reading a complicated book about algorithms containing n pages. To improve understanding of what is written, his friends advised him to read pages in some order given by permutation P = [p1, p2, ..., pn], where pi denotes ... | instruction | 0 | 78,795 | 12 | 157,590 |
Tags: implementation, sortings
Correct Solution:
```
from sys import stdin, stdout
n,m=map(int,stdin.readline().split())
p=list(map(int,stdin.readline().split()))
for _ in range(m):
gre=0
sma=0
l,r,x=map(int,stdin.readline().split())
for i in range(l-1,r):
if i<x-1:
if p[i]>p[x-1]:
... | output | 1 | 78,795 | 12 | 157,591 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Vladik had started reading a complicated book about algorithms containing n pages. To improve understanding of what is written, his friends advised him to read pages in some order given by permutation P = [p1, p2, ..., pn], where pi denotes ... | instruction | 0 | 78,796 | 12 | 157,592 |
Tags: implementation, sortings
Correct Solution:
```
n,k = map(int, input().split())
p = list(map(int, input().split()))
def solve():
for i in range(k):
l,r,x = map(int, input().split())
nrLarger,nrSmaller = r - x, x - l
cL,cS = 0,0
if r == l:
print("Yes")
else:
... | output | 1 | 78,796 | 12 | 157,593 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Vladik had started reading a complicated book about algorithms containing n pages. To improve understanding of what is written, his friends advised him to read pages in some order given by permutation P = [p1, p2, ..., pn], where pi denotes ... | instruction | 0 | 78,797 | 12 | 157,594 |
Tags: implementation, sortings
Correct Solution:
```
import math
import bisect
n, m = map(int, input().split())
P = [int(c) for c in input().split()]
b_len = math.ceil(math.sqrt(n))
b = []
for i in range(1000):
b.append(sorted(P[i*b_len:(i+1)*b_len]))
if n <= (i+1)*b_len:
break
b_cnt = len(b)
#print(b)... | output | 1 | 78,797 | 12 | 157,595 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Vladik had started reading a complicated book about algorithms containing n pages. To improve understanding of what is written, his friends advised him to read pages in some order given by permu... | instruction | 0 | 78,798 | 12 | 157,596 |
Yes | output | 1 | 78,798 | 12 | 157,597 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Vladik had started reading a complicated book about algorithms containing n pages. To improve understanding of what is written, his friends advised him to read pages in some order given by permu... | instruction | 0 | 78,799 | 12 | 157,598 |
Yes | output | 1 | 78,799 | 12 | 157,599 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Vladik had started reading a complicated book about algorithms containing n pages. To improve understanding of what is written, his friends advised him to read pages in some order given by permu... | instruction | 0 | 78,800 | 12 | 157,600 |
Yes | output | 1 | 78,800 | 12 | 157,601 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Vladik had started reading a complicated book about algorithms containing n pages. To improve understanding of what is written, his friends advised him to read pages in some order given by permu... | instruction | 0 | 78,801 | 12 | 157,602 |
Yes | output | 1 | 78,801 | 12 | 157,603 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Vladik had started reading a complicated book about algorithms containing n pages. To improve understanding of what is written, his friends advised him to read pages in some order given by permu... | instruction | 0 | 78,802 | 12 | 157,604 |
No | output | 1 | 78,802 | 12 | 157,605 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Vladik had started reading a complicated book about algorithms containing n pages. To improve understanding of what is written, his friends advised him to read pages in some order given by permu... | instruction | 0 | 78,803 | 12 | 157,606 |
No | output | 1 | 78,803 | 12 | 157,607 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Vladik had started reading a complicated book about algorithms containing n pages. To improve understanding of what is written, his friends advised him to read pages in some order given by permu... | instruction | 0 | 78,804 | 12 | 157,608 |
No | output | 1 | 78,804 | 12 | 157,609 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Vladik had started reading a complicated book about algorithms containing n pages. To improve understanding of what is written, his friends advised him to read pages in some order given by permu... | instruction | 0 | 78,805 | 12 | 157,610 |
No | output | 1 | 78,805 | 12 | 157,611 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Let's call the roundness of the number the number of zeros to which it ends.
You have an array of n numbers. You need to choose a subset of exactly k numbers so that the roundness of the product of the selected numbers will be maximum possi... | instruction | 0 | 78,806 | 12 | 157,612 |
Tags: dp, math
Correct Solution:
```
import sys
n, K = map(int, input().split())
a = list(map(int, input().split()))
m2, m5 = [0]*n, [0]*n
for i, x in enumerate(a):
while x % 2 == 0:
x //= 2
m2[i] += 1
while x % 5 == 0:
x //= 5
m5[i] += 1
dp = [[-10**9]*5100 for _ in range(K)... | output | 1 | 78,806 | 12 | 157,613 |
Provide a correct Python 3 solution for this coding contest problem.
Given are two sequences A and B, both of length N. A and B are each sorted in the ascending order. Check if it is possible to reorder the terms of B so that for each i (1 \leq i \leq N) A_i \neq B_i holds, and if it is possible, output any of the reo... | instruction | 0 | 78,860 | 12 | 157,720 |
"Correct Solution:
```
from collections import deque
import sys
input = sys.stdin.readline
N = int(input())
A = list(map(int, input().split()))
B = list(map(int, input().split()))
cntA = [0] * (N + 1)
cntB = [0] * (N + 1)
for i in range(N):
cntA[A[i]] += 1
cntB[B[i]] += 1
nums = [(cntA[i], cntB[i], i) for i in... | output | 1 | 78,860 | 12 | 157,721 |
Provide a correct Python 3 solution for this coding contest problem.
Given are two sequences A and B, both of length N. A and B are each sorted in the ascending order. Check if it is possible to reorder the terms of B so that for each i (1 \leq i \leq N) A_i \neq B_i holds, and if it is possible, output any of the reo... | instruction | 0 | 78,862 | 12 | 157,724 |
"Correct Solution:
```
def main():
n = int(input())
a = list(map(int, input().split()))
b = list(map(int, input().split()))
ai, bi = 0, 0
al, bl = [], []
while ai < n and bi < n:
ax, bx = a[ai], b[bi]
la, lb = [], []
if ax == bx:
cnt = 2
la.appen... | output | 1 | 78,862 | 12 | 157,725 |
Provide a correct Python 3 solution for this coding contest problem.
Given are two sequences A and B, both of length N. A and B are each sorted in the ascending order. Check if it is possible to reorder the terms of B so that for each i (1 \leq i \leq N) A_i \neq B_i holds, and if it is possible, output any of the reo... | instruction | 0 | 78,863 | 12 | 157,726 |
"Correct Solution:
```
N = int(input())
A = list(map(int, input().split()))
B = list(map(int, input().split()))
from collections import Counter
cA = Counter(A)
cB = Counter(B)
f = 0
for num, val in cA.items():
if num not in cB:
continue
else:
if cB[num] + val > N:
f = 1
tpA = [-... | output | 1 | 78,863 | 12 | 157,727 |
Provide a correct Python 3 solution for this coding contest problem.
Given are two sequences A and B, both of length N. A and B are each sorted in the ascending order. Check if it is possible to reorder the terms of B so that for each i (1 \leq i \leq N) A_i \neq B_i holds, and if it is possible, output any of the reo... | instruction | 0 | 78,864 | 12 | 157,728 |
"Correct Solution:
```
from collections import Counter
from heapq import heappush, heappop, heapreplace
N = int(input())
A = list(map(int, input().split()))
B = list(map(int, input().split()))
AC = Counter(A)
BC = Counter(B)
S = AC + BC
q = []
for k, v in S.items():
heappush(q, (-v, k))
ans = []
while q:
v... | output | 1 | 78,864 | 12 | 157,729 |
Provide a correct Python 3 solution for this coding contest problem.
Given are two sequences A and B, both of length N. A and B are each sorted in the ascending order. Check if it is possible to reorder the terms of B so that for each i (1 \leq i \leq N) A_i \neq B_i holds, and if it is possible, output any of the reo... | instruction | 0 | 78,865 | 12 | 157,730 |
"Correct Solution:
```
from bisect import bisect_left,bisect_right
n=int(input())
a=list(map(int,input().split()))
b=list(map(int,input().split()))
aset=set(a)
bset=set(b)
ans=0
for i in range(n):
if a[i] in bset:
ans=max(i-bisect_left(b,a[i]),ans)
b=(b+b+b)[n-ans-1:n+n-ans-1]
for i in range(n):
if a[i]==b[i]:
... | output | 1 | 78,865 | 12 | 157,731 |
Provide a correct Python 3 solution for this coding contest problem.
Given are two sequences A and B, both of length N. A and B are each sorted in the ascending order. Check if it is possible to reorder the terms of B so that for each i (1 \leq i \leq N) A_i \neq B_i holds, and if it is possible, output any of the reo... | instruction | 0 | 78,866 | 12 | 157,732 |
"Correct Solution:
```
def II():return int(input())
def LI():return list(map(int,input().split()))
from collections import Counter, deque
n=II()
a=LI()
b=LI()
ac=Counter(a)
bc=Counter(b)
abc=ac+bc
for i in abc.values():
if i>n:
print("No")
exit()
print("Yes")
a=deque(a)
b=deque(b... | output | 1 | 78,866 | 12 | 157,733 |
Provide a correct Python 3 solution for this coding contest problem.
Given are two sequences A and B, both of length N. A and B are each sorted in the ascending order. Check if it is possible to reorder the terms of B so that for each i (1 \leq i \leq N) A_i \neq B_i holds, and if it is possible, output any of the reo... | instruction | 0 | 78,867 | 12 | 157,734 |
"Correct Solution:
```
n=int(input())
a=list(map(int,input().split()))
b=list(map(int,input().split()))
from collections import Counter,deque
x,y=Counter(a),Counter(b)
for i in range(1,n+1):
if x[i]+y[i]>n:
print("No")
exit()
ans=b[::-1]
change=deque()
num=-1
now=deque()
for i in range(n):
if a[... | output | 1 | 78,867 | 12 | 157,735 |
Provide tags and a correct Python 3 solution for this coding contest problem.
[Thanos sort](https://codegolf.stackexchange.com/questions/182221/implement-the-thanos-sorting-algorithm) is a supervillain sorting algorithm, which works as follows: if the array is not sorted, snap your fingers* to remove the first or the ... | instruction | 0 | 79,200 | 12 | 158,400 |
Tags: implementation
Correct Solution:
```
import math
n=int(input())
a=[int(n) for n in input().split()]
s=0
for _ in range(4):
if(sorted(a)==a):
s=len(a)
break
else:
count1=0
count2=0
for i in range(len(a)//2-1):
if(a[i]<a[i+1]):
count1+=1
for i in range(len(a)//2,len(a)-1):
if(a[i]<a[i+1]):
... | output | 1 | 79,200 | 12 | 158,401 |
Provide tags and a correct Python 3 solution for this coding contest problem.
[Thanos sort](https://codegolf.stackexchange.com/questions/182221/implement-the-thanos-sorting-algorithm) is a supervillain sorting algorithm, which works as follows: if the array is not sorted, snap your fingers* to remove the first or the ... | instruction | 0 | 79,201 | 12 | 158,402 |
Tags: implementation
Correct Solution:
```
def thanos(k):
if k == sorted(k):
return (len(k))
else:
return max(thanos(k[:(len(k)//2)]), thanos(k[(len(k)//2):]))
t = int(input())
inp = [int(x) for x in input().split(" ", t)]
print(thanos(inp))
``` | output | 1 | 79,201 | 12 | 158,403 |
Provide tags and a correct Python 3 solution for this coding contest problem.
[Thanos sort](https://codegolf.stackexchange.com/questions/182221/implement-the-thanos-sorting-algorithm) is a supervillain sorting algorithm, which works as follows: if the array is not sorted, snap your fingers* to remove the first or the ... | instruction | 0 | 79,202 | 12 | 158,404 |
Tags: implementation
Correct Solution:
```
n = int(input())
l = list(map(int, input().split()))
if n == 1:
print(1)
elif n == 2:
if l == sorted(l):
print(2)
else:
print(1)
elif n == 4:
if l == sorted(l):
print(4)
else:
if l[:2] == sorted(l[:2]):
print(2)
... | output | 1 | 79,202 | 12 | 158,405 |
Provide tags and a correct Python 3 solution for this coding contest problem.
[Thanos sort](https://codegolf.stackexchange.com/questions/182221/implement-the-thanos-sorting-algorithm) is a supervillain sorting algorithm, which works as follows: if the array is not sorted, snap your fingers* to remove the first or the ... | instruction | 0 | 79,203 | 12 | 158,406 |
Tags: implementation
Correct Solution:
```
n = int(input())
def sort(w):
new = [0]*(len(w) // 2)
for i in range(len(w)//2):
new [i] = w[i]
return new
def anti(w):
k=0
new = [0]*(len(w) // 2)
for i in range(len(w)//2,len(w)):
new [k] = w[i]
k+=1
return new
a=ma... | output | 1 | 79,203 | 12 | 158,407 |
Provide tags and a correct Python 3 solution for this coding contest problem.
[Thanos sort](https://codegolf.stackexchange.com/questions/182221/implement-the-thanos-sorting-algorithm) is a supervillain sorting algorithm, which works as follows: if the array is not sorted, snap your fingers* to remove the first or the ... | instruction | 0 | 79,204 | 12 | 158,408 |
Tags: implementation
Correct Solution:
```
n=int(input())
a=list(map(int,input().strip().split()))
if(a==sorted(a)):
print(n)
exit()
else:
b=[i for i in reversed(a)]
if(b==sorted(a)):
print(1)
exit()
x=n//2
c=[]
while(x!=1):
for i in range(0,n,x):
y=a[i:i+x]
if(y==sorted(y)):
c.append(len(y))
x=x//2
pr... | output | 1 | 79,204 | 12 | 158,409 |
Subsets and Splits
No community queries yet
The top public SQL queries from the community will appear here once available.