message stringlengths 2 433k | message_type stringclasses 2
values | message_id int64 0 1 | conversation_id int64 113 108k | cluster float64 12 12 | __index_level_0__ int64 226 217k |
|---|---|---|---|---|---|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of n distinct positive integers. Your task is to find the size of it's largest k-multiple free subset.
Input
The first line of the input contains two integers n and k (1 ≤ n ≤ 105, 1 ≤ k ≤ 109). The next line contains a list of n distinct positive integers a1, a2, ..., an (1 ≤ ai ≤ 109).
All the numbers in the lines are separated by single spaces.
Output
On the only line of the output print the size of the largest k-multiple free subset of {a1, a2, ..., an}.
Examples
Input
6 2
2 3 6 5 4 10
Output
3
Note
In the sample input one of the possible maximum 2-multiple free subsets is {4, 5, 6}.
Submitted Solution:
```
"""
Code of Ayush Tiwari
Codechef: ayush572000
Codeforces: servermonk
"""
import sys
input = sys.stdin.buffer.readline
from collections import Counter
def solution():
n,k=map(int,input().split())
l=list(map(int,input().split()))
l.sort()
c=Counter(l)
s=set(l)
i=0
while i<len(s):
if c[k*l[i]]==1:
s.remove(k*l[i])
c[k*l[i]]-=1
i+=1
print(len(s))
solution()
``` | instruction | 0 | 78,584 | 12 | 157,168 |
No | output | 1 | 78,584 | 12 | 157,169 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of n distinct positive integers. Your task is to find the size of it's largest k-multiple free subset.
Input
The first line of the input contains two integers n and k (1 ≤ n ≤ 105, 1 ≤ k ≤ 109). The next line contains a list of n distinct positive integers a1, a2, ..., an (1 ≤ ai ≤ 109).
All the numbers in the lines are separated by single spaces.
Output
On the only line of the output print the size of the largest k-multiple free subset of {a1, a2, ..., an}.
Examples
Input
6 2
2 3 6 5 4 10
Output
3
Note
In the sample input one of the possible maximum 2-multiple free subsets is {4, 5, 6}.
Submitted Solution:
```
def testa_se_da(valor, a,k):
pos_esquerda = 0
n = len(a)
pos_direita = pos_esquerda + valor
consegue = True
for i in range(pos_esquerda, pos_direita):
for p in range(i, pos_direita):
if a[i]/a[k]==k or a[k]/a[i]==k:
consegue = False
if consegue:
return True
while pos_direita<=n-1:
consegue = True
for i in range(pos_esquerda, pos_direita):
for p in range(i, pos_direita):
if a[i]/a[k]==k or a[k]/a[i]==k:
consegue = False
if consegue:
return True
pos_esquerda+=1
pos_direita+=1
return False
n,k = map(int,input().split())
a = list(map(int,input().split()))
esquerda = 0
direita = n
melhor = 0
while esquerda<=direita:
meio = (esquerda+direita)//2
da = testa_se_da(meio, a, k)
if da:
if meio>melhor:
melhor=meio
esquerda = meio+1
else:
direita = meio-1
print(melhor)
``` | instruction | 0 | 78,585 | 12 | 157,170 |
No | output | 1 | 78,585 | 12 | 157,171 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of n distinct positive integers. Your task is to find the size of it's largest k-multiple free subset.
Input
The first line of the input contains two integers n and k (1 ≤ n ≤ 105, 1 ≤ k ≤ 109). The next line contains a list of n distinct positive integers a1, a2, ..., an (1 ≤ ai ≤ 109).
All the numbers in the lines are separated by single spaces.
Output
On the only line of the output print the size of the largest k-multiple free subset of {a1, a2, ..., an}.
Examples
Input
6 2
2 3 6 5 4 10
Output
3
Note
In the sample input one of the possible maximum 2-multiple free subsets is {4, 5, 6}.
Submitted Solution:
```
size, k = map(int, input().split())
array = ' '.join([i if int(i)%k != 0 else '.' for i in input().split()])
answer = list(filter(None, array.split('.')))
answer.sort(key=len)
ans = answer[-1]
print(ans.strip())
``` | instruction | 0 | 78,586 | 12 | 157,172 |
No | output | 1 | 78,586 | 12 | 157,173 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A k-multiple free set is a set of integers where there is no pair of integers where one is equal to another integer multiplied by k. That is, there are no two integers x and y (x < y) from the set, such that y = x·k.
You're given a set of n distinct positive integers. Your task is to find the size of it's largest k-multiple free subset.
Input
The first line of the input contains two integers n and k (1 ≤ n ≤ 105, 1 ≤ k ≤ 109). The next line contains a list of n distinct positive integers a1, a2, ..., an (1 ≤ ai ≤ 109).
All the numbers in the lines are separated by single spaces.
Output
On the only line of the output print the size of the largest k-multiple free subset of {a1, a2, ..., an}.
Examples
Input
6 2
2 3 6 5 4 10
Output
3
Note
In the sample input one of the possible maximum 2-multiple free subsets is {4, 5, 6}.
Submitted Solution:
```
import math
n, k = map(int,input().split())
arr = dict()
ma = 0
for x in input().split():
arr[int(x)] = 1
if(int(x) > ma): ma = int(x)
ans = 0
if(k!=1):
for i in arr:
if(arr[i]!=-1):
new = i
count = 0
while(True):
if(new in arr):
count+=1
arr[new]=-1
else:
break
new*=k
if(count == 1):
ans+=1
else:
ans+=math.ceil(count/2)
print(ans)
if(k==1):
print(n)
``` | instruction | 0 | 78,587 | 12 | 157,174 |
No | output | 1 | 78,587 | 12 | 157,175 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Amr has got a large array of size n. Amr doesn't like large arrays so he intends to make it smaller.
Amr doesn't care about anything in the array except the beauty of it. The beauty of the array is defined to be the maximum number of times that some number occurs in this array. He wants to choose the smallest subsegment of this array such that the beauty of it will be the same as the original array.
Help Amr by choosing the smallest subsegment possible.
Input
The first line contains one number n (1 ≤ n ≤ 105), the size of the array.
The second line contains n integers ai (1 ≤ ai ≤ 106), representing elements of the array.
Output
Output two integers l, r (1 ≤ l ≤ r ≤ n), the beginning and the end of the subsegment chosen respectively.
If there are several possible answers you may output any of them.
Examples
Input
5
1 1 2 2 1
Output
1 5
Input
5
1 2 2 3 1
Output
2 3
Input
6
1 2 2 1 1 2
Output
1 5
Note
A subsegment B of an array A from l to r is an array of size r - l + 1 where Bi = Al + i - 1 for all 1 ≤ i ≤ r - l + 1 | instruction | 0 | 78,696 | 12 | 157,392 |
Tags: implementation
Correct Solution:
```
n = int(input())
numbers = [ int(number) for number in input().split() ]
occurences = {}
for i in range(n):
number = numbers[i]
if number in occurences.keys():
occurences[number][0] += 1
occurences[number][2] = i+1
else:
occurences[number] = [ 1, i+1, -1 ]
result = [ -1, -1, -1 ]
for number in occurences.keys():
if occurences[number][2] == -1:
occurences[number][2] = occurences[number][1]
if occurences[number][0] > result[0]:
result = occurences[number][:]
elif occurences[number][0] == result[0]:
r1 = occurences[number][2]-occurences[number][1]
r2 = result[2]-result[1]
if r2 > r1:
result = occurences[number][:]
print(result[1], result[2])
``` | output | 1 | 78,696 | 12 | 157,393 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Amr has got a large array of size n. Amr doesn't like large arrays so he intends to make it smaller.
Amr doesn't care about anything in the array except the beauty of it. The beauty of the array is defined to be the maximum number of times that some number occurs in this array. He wants to choose the smallest subsegment of this array such that the beauty of it will be the same as the original array.
Help Amr by choosing the smallest subsegment possible.
Input
The first line contains one number n (1 ≤ n ≤ 105), the size of the array.
The second line contains n integers ai (1 ≤ ai ≤ 106), representing elements of the array.
Output
Output two integers l, r (1 ≤ l ≤ r ≤ n), the beginning and the end of the subsegment chosen respectively.
If there are several possible answers you may output any of them.
Examples
Input
5
1 1 2 2 1
Output
1 5
Input
5
1 2 2 3 1
Output
2 3
Input
6
1 2 2 1 1 2
Output
1 5
Note
A subsegment B of an array A from l to r is an array of size r - l + 1 where Bi = Al + i - 1 for all 1 ≤ i ≤ r - l + 1 | instruction | 0 | 78,697 | 12 | 157,394 |
Tags: implementation
Correct Solution:
```
#!/usr/bin/env python3
import sys
N = int(input())
A = list(map(int, input().split(' ')))
left_idx = {}
right_idx = {}
count = {}
for i, e in enumerate(A):
if e not in count:
count[e] = 0
count[e] += 1
if e not in left_idx:
left_idx[e] = i
if i < left_idx[e]:
left_idx[e] = i
if e not in right_idx:
right_idx[e] = i
if right_idx[e] < i:
right_idx[e] = i
max_count = max(count[c] for c in count)
items_with_mc = [i for i in count if count[i] == max_count]
span_i = [(right_idx[i] - left_idx[i], i) for i in items_with_mc]
iwms = min(span_i)[1]
print(left_idx[iwms] + 1, right_idx[iwms] + 1)
``` | output | 1 | 78,697 | 12 | 157,395 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Amr has got a large array of size n. Amr doesn't like large arrays so he intends to make it smaller.
Amr doesn't care about anything in the array except the beauty of it. The beauty of the array is defined to be the maximum number of times that some number occurs in this array. He wants to choose the smallest subsegment of this array such that the beauty of it will be the same as the original array.
Help Amr by choosing the smallest subsegment possible.
Input
The first line contains one number n (1 ≤ n ≤ 105), the size of the array.
The second line contains n integers ai (1 ≤ ai ≤ 106), representing elements of the array.
Output
Output two integers l, r (1 ≤ l ≤ r ≤ n), the beginning and the end of the subsegment chosen respectively.
If there are several possible answers you may output any of them.
Examples
Input
5
1 1 2 2 1
Output
1 5
Input
5
1 2 2 3 1
Output
2 3
Input
6
1 2 2 1 1 2
Output
1 5
Note
A subsegment B of an array A from l to r is an array of size r - l + 1 where Bi = Al + i - 1 for all 1 ≤ i ≤ r - l + 1 | instruction | 0 | 78,698 | 12 | 157,396 |
Tags: implementation
Correct Solution:
```
from collections import defaultdict
N = int(input())
A = [int(x) for x in input().split()]
bucket = defaultdict(list)
for i, num in enumerate(A):
bucket[num].append(i)
sorted_buckets = sorted(bucket.values(), key=lambda val: (-len(val), val[-1]-val[0]))
print(sorted_buckets[0][0]+1, sorted_buckets[0][-1]+1)
``` | output | 1 | 78,698 | 12 | 157,397 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Amr has got a large array of size n. Amr doesn't like large arrays so he intends to make it smaller.
Amr doesn't care about anything in the array except the beauty of it. The beauty of the array is defined to be the maximum number of times that some number occurs in this array. He wants to choose the smallest subsegment of this array such that the beauty of it will be the same as the original array.
Help Amr by choosing the smallest subsegment possible.
Input
The first line contains one number n (1 ≤ n ≤ 105), the size of the array.
The second line contains n integers ai (1 ≤ ai ≤ 106), representing elements of the array.
Output
Output two integers l, r (1 ≤ l ≤ r ≤ n), the beginning and the end of the subsegment chosen respectively.
If there are several possible answers you may output any of them.
Examples
Input
5
1 1 2 2 1
Output
1 5
Input
5
1 2 2 3 1
Output
2 3
Input
6
1 2 2 1 1 2
Output
1 5
Note
A subsegment B of an array A from l to r is an array of size r - l + 1 where Bi = Al + i - 1 for all 1 ≤ i ≤ r - l + 1 | instruction | 0 | 78,699 | 12 | 157,398 |
Tags: implementation
Correct Solution:
```
import collections
def findsubsegment(l, nums):
freq_map = collections.Counter(nums)
beauty = max(freq_map.items(), key = lambda x: x[1])[1]
keys = {}
if beauty == 1:
print("1 1")
return
for key, val in freq_map.items():
if val == beauty:
keys[key] = [l, -1]
for i, num in enumerate(nums):
if num in keys:
if i < keys[num][0]:
keys[num][0] = i
keys[num][1] = i
min_val = l
min_range = [1, l]
for key, ranges in keys.items():
if ranges[1] - ranges[0] < min_val:
min_val = ranges[1] - ranges[0]
min_range = [ranges[0] + 1, ranges[1] + 1]
print(str(min_range[0]) + ' ' + str(min_range[1]))
l = int(input())
nums = [int(x) for x in input().split(' ')]
findsubsegment(l, nums)
``` | output | 1 | 78,699 | 12 | 157,399 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Amr has got a large array of size n. Amr doesn't like large arrays so he intends to make it smaller.
Amr doesn't care about anything in the array except the beauty of it. The beauty of the array is defined to be the maximum number of times that some number occurs in this array. He wants to choose the smallest subsegment of this array such that the beauty of it will be the same as the original array.
Help Amr by choosing the smallest subsegment possible.
Input
The first line contains one number n (1 ≤ n ≤ 105), the size of the array.
The second line contains n integers ai (1 ≤ ai ≤ 106), representing elements of the array.
Output
Output two integers l, r (1 ≤ l ≤ r ≤ n), the beginning and the end of the subsegment chosen respectively.
If there are several possible answers you may output any of them.
Examples
Input
5
1 1 2 2 1
Output
1 5
Input
5
1 2 2 3 1
Output
2 3
Input
6
1 2 2 1 1 2
Output
1 5
Note
A subsegment B of an array A from l to r is an array of size r - l + 1 where Bi = Al + i - 1 for all 1 ≤ i ≤ r - l + 1 | instruction | 0 | 78,700 | 12 | 157,400 |
Tags: implementation
Correct Solution:
```
import sys
def fastio():
from io import StringIO
from atexit import register
global input
sys.stdin = StringIO(sys.stdin.read())
input = lambda : sys.stdin.readline().rstrip('\r\n')
sys.stdout = StringIO()
register(lambda : sys.__stdout__.write(sys.stdout.getvalue()))
fastio()
def debug(*var, sep = ' ', end = '\n'):
print(*var, file=sys.stderr, end = end, sep = sep)
INF = 10**20
MOD = 10**9 + 7
I = lambda:list(map(int,input().split()))
from math import gcd
from math import ceil
from collections import defaultdict as dd, Counter
from bisect import bisect_left as bl, bisect_right as br
n, = I()
a = I()
ans = INF
res = [1, 1]
m = 0
d = dd(list)
cnt = dd(int)
for i in range(n):
cnt[a[i]] += 1
m = max(cnt[a[i]], m)
if d[a[i]]:
d[a[i]][-1] = i + 1
else:
d[a[i]] = [i + 1, i + 1]
for i in d:
cur = d[i][-1] - d[i][0] + 1
if cnt[i] == m and cur < ans:
ans = cur
res = d[i]
print(*res)
``` | output | 1 | 78,700 | 12 | 157,401 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Amr has got a large array of size n. Amr doesn't like large arrays so he intends to make it smaller.
Amr doesn't care about anything in the array except the beauty of it. The beauty of the array is defined to be the maximum number of times that some number occurs in this array. He wants to choose the smallest subsegment of this array such that the beauty of it will be the same as the original array.
Help Amr by choosing the smallest subsegment possible.
Input
The first line contains one number n (1 ≤ n ≤ 105), the size of the array.
The second line contains n integers ai (1 ≤ ai ≤ 106), representing elements of the array.
Output
Output two integers l, r (1 ≤ l ≤ r ≤ n), the beginning and the end of the subsegment chosen respectively.
If there are several possible answers you may output any of them.
Examples
Input
5
1 1 2 2 1
Output
1 5
Input
5
1 2 2 3 1
Output
2 3
Input
6
1 2 2 1 1 2
Output
1 5
Note
A subsegment B of an array A from l to r is an array of size r - l + 1 where Bi = Al + i - 1 for all 1 ≤ i ≤ r - l + 1 | instruction | 0 | 78,701 | 12 | 157,402 |
Tags: implementation
Correct Solution:
```
n=int(input())
L=list(map(int,input().split()))
A=[0]*(10**6+1)
B=[0]*(10**6+1)
C=[0]*(10**6+1)
for i in range(len(L)):
x=L[i]
if A[x]==0:
B[x]=i
A[x]=A[x]+1
C[x]=i
maxi=A[0]
diff=10**6
pos=0
for i in range(1,len(A)):
if A[i]>maxi:
maxi=A[i]
diff=C[i]-B[i]
pos=i
elif A[i]==maxi:
if (C[i]-B[i])<diff:
diff=C[i]-B[i]
pos=i
print(str(B[pos]+1)+' '+str(C[pos]+1))
``` | output | 1 | 78,701 | 12 | 157,403 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Amr has got a large array of size n. Amr doesn't like large arrays so he intends to make it smaller.
Amr doesn't care about anything in the array except the beauty of it. The beauty of the array is defined to be the maximum number of times that some number occurs in this array. He wants to choose the smallest subsegment of this array such that the beauty of it will be the same as the original array.
Help Amr by choosing the smallest subsegment possible.
Input
The first line contains one number n (1 ≤ n ≤ 105), the size of the array.
The second line contains n integers ai (1 ≤ ai ≤ 106), representing elements of the array.
Output
Output two integers l, r (1 ≤ l ≤ r ≤ n), the beginning and the end of the subsegment chosen respectively.
If there are several possible answers you may output any of them.
Examples
Input
5
1 1 2 2 1
Output
1 5
Input
5
1 2 2 3 1
Output
2 3
Input
6
1 2 2 1 1 2
Output
1 5
Note
A subsegment B of an array A from l to r is an array of size r - l + 1 where Bi = Al + i - 1 for all 1 ≤ i ≤ r - l + 1 | instruction | 0 | 78,702 | 12 | 157,404 |
Tags: implementation
Correct Solution:
```
from collections import defaultdict
n = int(input())
a = list(map(int, input().split()))
d = defaultdict(list)
for i, v in enumerate(a):
d[v].append(i)
bestSize = -float('inf')
bestLen = float('inf')
l = r = None
for cnt in d.values():
i, j = cnt[0], cnt[-1]
if (len(cnt) > bestSize) or (len(cnt) == bestSize and j - i + 1 < bestLen):
bestSize = len(cnt)
bestLen = j - i + 1
l, r = i, j
print('%d %d' % (l + 1, r + 1))
``` | output | 1 | 78,702 | 12 | 157,405 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Amr has got a large array of size n. Amr doesn't like large arrays so he intends to make it smaller.
Amr doesn't care about anything in the array except the beauty of it. The beauty of the array is defined to be the maximum number of times that some number occurs in this array. He wants to choose the smallest subsegment of this array such that the beauty of it will be the same as the original array.
Help Amr by choosing the smallest subsegment possible.
Input
The first line contains one number n (1 ≤ n ≤ 105), the size of the array.
The second line contains n integers ai (1 ≤ ai ≤ 106), representing elements of the array.
Output
Output two integers l, r (1 ≤ l ≤ r ≤ n), the beginning and the end of the subsegment chosen respectively.
If there are several possible answers you may output any of them.
Examples
Input
5
1 1 2 2 1
Output
1 5
Input
5
1 2 2 3 1
Output
2 3
Input
6
1 2 2 1 1 2
Output
1 5
Note
A subsegment B of an array A from l to r is an array of size r - l + 1 where Bi = Al + i - 1 for all 1 ≤ i ≤ r - l + 1 | instruction | 0 | 78,703 | 12 | 157,406 |
Tags: implementation
Correct Solution:
```
N = int(input())
A = [int(x) for x in input().split()]
bucket = dict()
for i, num in enumerate(A):
if num in bucket:
bucket[num].append(i)
else:
bucket[num] = [i]
#print(bucket)
sorted_buckets = sorted((-len(val), val[-1]-val[0], val) for _, val in bucket.items())
print(sorted_buckets[0][2][0]+1, sorted_buckets[0][2][-1]+1)
``` | output | 1 | 78,703 | 12 | 157,407 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Amr has got a large array of size n. Amr doesn't like large arrays so he intends to make it smaller.
Amr doesn't care about anything in the array except the beauty of it. The beauty of the array is defined to be the maximum number of times that some number occurs in this array. He wants to choose the smallest subsegment of this array such that the beauty of it will be the same as the original array.
Help Amr by choosing the smallest subsegment possible.
Input
The first line contains one number n (1 ≤ n ≤ 105), the size of the array.
The second line contains n integers ai (1 ≤ ai ≤ 106), representing elements of the array.
Output
Output two integers l, r (1 ≤ l ≤ r ≤ n), the beginning and the end of the subsegment chosen respectively.
If there are several possible answers you may output any of them.
Examples
Input
5
1 1 2 2 1
Output
1 5
Input
5
1 2 2 3 1
Output
2 3
Input
6
1 2 2 1 1 2
Output
1 5
Note
A subsegment B of an array A from l to r is an array of size r - l + 1 where Bi = Al + i - 1 for all 1 ≤ i ≤ r - l + 1
Submitted Solution:
```
from sys import stdin
from collections import Counter as counter
a=int(stdin.readline())
b=list(map(int,stdin.readline().split()))
d={};ans=[-1]*1000001;ans1=[-1]*1000001
for i in range(a):
if b[i] in d:d[b[i]]+=1
else:d[b[i]]=1
if ans[b[i]]==-1:ans[b[i]]=i
ans1[b[i]]=i#33.
k=sorted([[d[i],i] for i in d],reverse=True)
p=k[0][0]
i=0;s=0;l,r=ans[k[0][1]],ans1[k[0][1]]
while i<len(k) and k[i][0]==p:
if r-l>ans1[k[i][1]]-ans[k[i][1]]:l,r=ans[k[i][1]],ans1[k[i][1]]
i+=1
print(l+1,r+1)
``` | instruction | 0 | 78,704 | 12 | 157,408 |
Yes | output | 1 | 78,704 | 12 | 157,409 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Amr has got a large array of size n. Amr doesn't like large arrays so he intends to make it smaller.
Amr doesn't care about anything in the array except the beauty of it. The beauty of the array is defined to be the maximum number of times that some number occurs in this array. He wants to choose the smallest subsegment of this array such that the beauty of it will be the same as the original array.
Help Amr by choosing the smallest subsegment possible.
Input
The first line contains one number n (1 ≤ n ≤ 105), the size of the array.
The second line contains n integers ai (1 ≤ ai ≤ 106), representing elements of the array.
Output
Output two integers l, r (1 ≤ l ≤ r ≤ n), the beginning and the end of the subsegment chosen respectively.
If there are several possible answers you may output any of them.
Examples
Input
5
1 1 2 2 1
Output
1 5
Input
5
1 2 2 3 1
Output
2 3
Input
6
1 2 2 1 1 2
Output
1 5
Note
A subsegment B of an array A from l to r is an array of size r - l + 1 where Bi = Al + i - 1 for all 1 ≤ i ≤ r - l + 1
Submitted Solution:
```
def main():
n, d = int(input()), {}
for i, a in enumerate(map(int, input().split())):
c, _, l = d.get(a, (0, 0, i))
d[a] = (c + 1, l - i, l)
_, h, l = max(d.values())
print(l + 1, l - h + 1)
if __name__ == '__main__':
main()
``` | instruction | 0 | 78,705 | 12 | 157,410 |
Yes | output | 1 | 78,705 | 12 | 157,411 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Amr has got a large array of size n. Amr doesn't like large arrays so he intends to make it smaller.
Amr doesn't care about anything in the array except the beauty of it. The beauty of the array is defined to be the maximum number of times that some number occurs in this array. He wants to choose the smallest subsegment of this array such that the beauty of it will be the same as the original array.
Help Amr by choosing the smallest subsegment possible.
Input
The first line contains one number n (1 ≤ n ≤ 105), the size of the array.
The second line contains n integers ai (1 ≤ ai ≤ 106), representing elements of the array.
Output
Output two integers l, r (1 ≤ l ≤ r ≤ n), the beginning and the end of the subsegment chosen respectively.
If there are several possible answers you may output any of them.
Examples
Input
5
1 1 2 2 1
Output
1 5
Input
5
1 2 2 3 1
Output
2 3
Input
6
1 2 2 1 1 2
Output
1 5
Note
A subsegment B of an array A from l to r is an array of size r - l + 1 where Bi = Al + i - 1 for all 1 ≤ i ≤ r - l + 1
Submitted Solution:
```
def cmp_to_key(mycmp):
'Convert a cmp= function into a key= function'
class K:
def __init__(self, obj, *args):
self.obj = obj
def __lt__(self, other):
return mycmp(self.obj, other.obj) < 0
def __gt__(self, other):
return mycmp(self.obj, other.obj) > 0
def __eq__(self, other):
return mycmp(self.obj, other.obj) == 0
def __le__(self, other):
return mycmp(self.obj, other.obj) <= 0
def __ge__(self, other):
return mycmp(self.obj, other.obj) >= 0
def __ne__(self, other):
return mycmp(self.obj, other.obj) != 0
return K
def compare(x, y):
if x[2] != y[2]:
return y[2] - x[2]
return (x[1] - x[0]) - (y[1] - y[0])
def main():
n = int(input())
d = list(map(int, input().split()))
r = {}
for i in range(n):
if d[i] in r:
r[d[i]] = [r[d[i]][0], i + 1, r[d[i]][2]+1]
else:
r[d[i]] = [i + 1, i + 1, 1]
sr = sorted(r.values(), key=cmp_to_key(compare))
print(sr[0][0], sr[0][1])
main()
``` | instruction | 0 | 78,706 | 12 | 157,412 |
Yes | output | 1 | 78,706 | 12 | 157,413 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Amr has got a large array of size n. Amr doesn't like large arrays so he intends to make it smaller.
Amr doesn't care about anything in the array except the beauty of it. The beauty of the array is defined to be the maximum number of times that some number occurs in this array. He wants to choose the smallest subsegment of this array such that the beauty of it will be the same as the original array.
Help Amr by choosing the smallest subsegment possible.
Input
The first line contains one number n (1 ≤ n ≤ 105), the size of the array.
The second line contains n integers ai (1 ≤ ai ≤ 106), representing elements of the array.
Output
Output two integers l, r (1 ≤ l ≤ r ≤ n), the beginning and the end of the subsegment chosen respectively.
If there are several possible answers you may output any of them.
Examples
Input
5
1 1 2 2 1
Output
1 5
Input
5
1 2 2 3 1
Output
2 3
Input
6
1 2 2 1 1 2
Output
1 5
Note
A subsegment B of an array A from l to r is an array of size r - l + 1 where Bi = Al + i - 1 for all 1 ≤ i ≤ r - l + 1
Submitted Solution:
```
n=int(input())
l=[]
l=list(map(int,input().split()))
fr=[0]*1000005
a=[0]*1000005
b=[0]*1000005
for i in range(n):
fr[l[i]]=fr[l[i]]+1;
if a[l[i]]==0:
a[l[i]]=i+1
b[l[i]]=i+1;
max1=0
min1=10000005
x=int()
y=int()
for i in range(1000001):
if fr[i]>max1:
max1=fr[i]
x=a[i]
y=b[i]
min1=y-x+1
elif fr[i]==max1:
x1=a[i]
y1=b[i]
if y1-x1+1<min1:
min1=y1-x1+1
x=x1
y=y1
print(x,y,sep=' ')
``` | instruction | 0 | 78,707 | 12 | 157,414 |
Yes | output | 1 | 78,707 | 12 | 157,415 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Amr has got a large array of size n. Amr doesn't like large arrays so he intends to make it smaller.
Amr doesn't care about anything in the array except the beauty of it. The beauty of the array is defined to be the maximum number of times that some number occurs in this array. He wants to choose the smallest subsegment of this array such that the beauty of it will be the same as the original array.
Help Amr by choosing the smallest subsegment possible.
Input
The first line contains one number n (1 ≤ n ≤ 105), the size of the array.
The second line contains n integers ai (1 ≤ ai ≤ 106), representing elements of the array.
Output
Output two integers l, r (1 ≤ l ≤ r ≤ n), the beginning and the end of the subsegment chosen respectively.
If there are several possible answers you may output any of them.
Examples
Input
5
1 1 2 2 1
Output
1 5
Input
5
1 2 2 3 1
Output
2 3
Input
6
1 2 2 1 1 2
Output
1 5
Note
A subsegment B of an array A from l to r is an array of size r - l + 1 where Bi = Al + i - 1 for all 1 ≤ i ≤ r - l + 1
Submitted Solution:
```
def amrlarge():
n = int(input())
arr = list(map(int,input().split()))
arr_rev = arr.copy()
arr_rev = arr_rev[::-1]
sortedarr = arr.copy()
sortedarr.sort()
print(sortedarr)
max_val = []
freq = max_freq = 0
#find most frequent
for i in range(n-1):
if sortedarr[i] == sortedarr[i+1]:
freq +=1
if sortedarr[i] != sortedarr[i+1] or i == n-2 :
if freq > max_freq:
max_freq = freq
max_val.clear()
max_val.append(sortedarr[i])
elif freq == max_freq:
max_val.append(sortedarr[i])
freq = 0
#find shortest span
minim = n+1
for i in max_val:
cand_lo = arr.index(i)
cand_hi = n - 1 - arr_rev.index(i)
if cand_hi - cand_lo < minim:
minim = cand_hi - cand_lo
lo = 1 + cand_lo
hi = 1 + cand_hi
print(lo, end = ' ')
print(hi)
amrlarge()
``` | instruction | 0 | 78,708 | 12 | 157,416 |
No | output | 1 | 78,708 | 12 | 157,417 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Amr has got a large array of size n. Amr doesn't like large arrays so he intends to make it smaller.
Amr doesn't care about anything in the array except the beauty of it. The beauty of the array is defined to be the maximum number of times that some number occurs in this array. He wants to choose the smallest subsegment of this array such that the beauty of it will be the same as the original array.
Help Amr by choosing the smallest subsegment possible.
Input
The first line contains one number n (1 ≤ n ≤ 105), the size of the array.
The second line contains n integers ai (1 ≤ ai ≤ 106), representing elements of the array.
Output
Output two integers l, r (1 ≤ l ≤ r ≤ n), the beginning and the end of the subsegment chosen respectively.
If there are several possible answers you may output any of them.
Examples
Input
5
1 1 2 2 1
Output
1 5
Input
5
1 2 2 3 1
Output
2 3
Input
6
1 2 2 1 1 2
Output
1 5
Note
A subsegment B of an array A from l to r is an array of size r - l + 1 where Bi = Al + i - 1 for all 1 ≤ i ≤ r - l + 1
Submitted Solution:
```
n = int(input())
i = 0
l = [int(1e9)]*(int(1e6+1))
r = [-1]*(int(1e6+1))
c = [0]*(int(1e6+1))
for x in map(int, input().split()):
l[x] = min(l[x], i)
r[x] = max(r[x], i)
c[x] += 1
i += 1
res = (0,int(1e9),0)
for i in range(1, int(1e6+1)):
if c[x] != 0:
res = min(res, (-c[i], r[i]-c[i], i))
print(l[res[2]] + 1, r[res[2]] + 1)
``` | instruction | 0 | 78,709 | 12 | 157,418 |
No | output | 1 | 78,709 | 12 | 157,419 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Amr has got a large array of size n. Amr doesn't like large arrays so he intends to make it smaller.
Amr doesn't care about anything in the array except the beauty of it. The beauty of the array is defined to be the maximum number of times that some number occurs in this array. He wants to choose the smallest subsegment of this array such that the beauty of it will be the same as the original array.
Help Amr by choosing the smallest subsegment possible.
Input
The first line contains one number n (1 ≤ n ≤ 105), the size of the array.
The second line contains n integers ai (1 ≤ ai ≤ 106), representing elements of the array.
Output
Output two integers l, r (1 ≤ l ≤ r ≤ n), the beginning and the end of the subsegment chosen respectively.
If there are several possible answers you may output any of them.
Examples
Input
5
1 1 2 2 1
Output
1 5
Input
5
1 2 2 3 1
Output
2 3
Input
6
1 2 2 1 1 2
Output
1 5
Note
A subsegment B of an array A from l to r is an array of size r - l + 1 where Bi = Al + i - 1 for all 1 ≤ i ≤ r - l + 1
Submitted Solution:
```
'''input
5
1 2 2 3 1
'''
n = int(input())
i = list(map(int, input().split()))
j = i[::-1]
if n == len(set(i)):
print(1, 1)
else:
a1, b1, l, m = 0, 0, 10000000000, 0
for x in set(i):
if i.count(x) >= m:
m = i.count(x)
a, b = i.index(x) + 1, n - j.index(x)
if b - a < l:
l = b - a
a1, b1 = a, b
print(a1, b1)
``` | instruction | 0 | 78,710 | 12 | 157,420 |
No | output | 1 | 78,710 | 12 | 157,421 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Amr has got a large array of size n. Amr doesn't like large arrays so he intends to make it smaller.
Amr doesn't care about anything in the array except the beauty of it. The beauty of the array is defined to be the maximum number of times that some number occurs in this array. He wants to choose the smallest subsegment of this array such that the beauty of it will be the same as the original array.
Help Amr by choosing the smallest subsegment possible.
Input
The first line contains one number n (1 ≤ n ≤ 105), the size of the array.
The second line contains n integers ai (1 ≤ ai ≤ 106), representing elements of the array.
Output
Output two integers l, r (1 ≤ l ≤ r ≤ n), the beginning and the end of the subsegment chosen respectively.
If there are several possible answers you may output any of them.
Examples
Input
5
1 1 2 2 1
Output
1 5
Input
5
1 2 2 3 1
Output
2 3
Input
6
1 2 2 1 1 2
Output
1 5
Note
A subsegment B of an array A from l to r is an array of size r - l + 1 where Bi = Al + i - 1 for all 1 ≤ i ≤ r - l + 1
Submitted Solution:
```
n = int(input())
array = map(int,input().split())
count_map = {}
begin = {}
end = {}
max_iter_num = 0
max_value = -1
for index , _ in enumerate(array):
if _ in count_map:
count_map[_] += 1
if count_map[_] > max_iter_num:
max_iter_num = count_map[_]
max_value = _
else:
count_map[_] = 1
if _ not in begin:
begin[_] = index + 1
if _ in end:
end[_] = index + 1
else:
end[_] = index + 1
print(begin[max_value],end[max_value])
``` | instruction | 0 | 78,711 | 12 | 157,422 |
No | output | 1 | 78,711 | 12 | 157,423 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given an infinite periodic array a0, a1, ..., an - 1, ... with the period of length n. Formally, <image>. A periodic subarray (l, s) (0 ≤ l < n, 1 ≤ s < n) of array a is an infinite periodic array with a period of length s that is a subsegment of array a, starting with position l.
A periodic subarray (l, s) is superior, if when attaching it to the array a, starting from index l, any element of the subarray is larger than or equal to the corresponding element of array a. An example of attaching is given on the figure (top — infinite array a, bottom — its periodic subarray (l, s)):
<image>
Find the number of distinct pairs (l, s), corresponding to the superior periodic arrays.
Input
The first line contains number n (1 ≤ n ≤ 2·105). The second line contains n numbers a0, a1, ..., an - 1 (1 ≤ ai ≤ 106), separated by a space.
Output
Print a single integer — the sought number of pairs.
Examples
Input
4
7 1 2 3
Output
2
Input
2
2 1
Output
1
Input
3
1 1 1
Output
6
Note
In the first sample the superior subarrays are (0, 1) and (3, 2).
Subarray (0, 1) is superior, as a0 ≥ a0, a0 ≥ a1, a0 ≥ a2, a0 ≥ a3, a0 ≥ a0, ...
Subarray (3, 2) is superior a3 ≥ a3, a0 ≥ a0, a3 ≥ a1, a0 ≥ a2, a3 ≥ a3, ...
In the third sample any pair of (l, s) corresponds to a superior subarray as all the elements of an array are distinct.
Submitted Solution:
```
if __name__=='__main__':
n = int(input())
numlist = list(map(int,input().split()))
num = set(numlist)
memo = dict(zip(num, [0]*len(num)))
for j in numlist:
memo[j] += 1
sum1 = 0
cnt = 0
for keys,values in memo.items():
if values > 1:
sum1 += (values*(values+1))//2
else:
cnt += 1
print(sum1+(cnt//2))
``` | instruction | 0 | 78,712 | 12 | 157,424 |
No | output | 1 | 78,712 | 12 | 157,425 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Vladik had started reading a complicated book about algorithms containing n pages. To improve understanding of what is written, his friends advised him to read pages in some order given by permutation P = [p1, p2, ..., pn], where pi denotes the number of page that should be read i-th in turn.
Sometimes Vladik’s mom sorted some subsegment of permutation P from position l to position r inclusive, because she loves the order. For every of such sorting Vladik knows number x — what index of page in permutation he should read. He is wondered if the page, which he will read after sorting, has changed. In other words, has px changed? After every sorting Vladik return permutation to initial state, so you can assume that each sorting is independent from each other.
Input
First line contains two space-separated integers n, m (1 ≤ n, m ≤ 104) — length of permutation and number of times Vladik's mom sorted some subsegment of the book.
Second line contains n space-separated integers p1, p2, ..., pn (1 ≤ pi ≤ n) — permutation P. Note that elements in permutation are distinct.
Each of the next m lines contains three space-separated integers li, ri, xi (1 ≤ li ≤ xi ≤ ri ≤ n) — left and right borders of sorted subsegment in i-th sorting and position that is interesting to Vladik.
Output
For each mom’s sorting on it’s own line print "Yes", if page which is interesting to Vladik hasn't changed, or "No" otherwise.
Examples
Input
5 5
5 4 3 2 1
1 5 3
1 3 1
2 4 3
4 4 4
2 5 3
Output
Yes
No
Yes
Yes
No
Input
6 5
1 4 3 2 5 6
2 4 3
1 6 2
4 5 4
1 3 3
2 6 3
Output
Yes
No
Yes
No
Yes
Note
Explanation of first test case:
1. [1, 2, 3, 4, 5] — permutation after sorting, 3-rd element hasn’t changed, so answer is "Yes".
2. [3, 4, 5, 2, 1] — permutation after sorting, 1-st element has changed, so answer is "No".
3. [5, 2, 3, 4, 1] — permutation after sorting, 3-rd element hasn’t changed, so answer is "Yes".
4. [5, 4, 3, 2, 1] — permutation after sorting, 4-th element hasn’t changed, so answer is "Yes".
5. [5, 1, 2, 3, 4] — permutation after sorting, 3-rd element has changed, so answer is "No". | instruction | 0 | 78,790 | 12 | 157,580 |
Tags: implementation, sortings
Correct Solution:
```
x,y=map(int,input().split())
t=0
awan=list(map(int,input().split()))
for v in range(0,y) :
l,r,x=map(int,input().split())
l-=1
x-=1
t=0
for j in range(l,r):
if awan[x]>awan[j] :
t+=1
if (l+t)==x :
print("Yes")
else :
print("No")
``` | output | 1 | 78,790 | 12 | 157,581 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Vladik had started reading a complicated book about algorithms containing n pages. To improve understanding of what is written, his friends advised him to read pages in some order given by permutation P = [p1, p2, ..., pn], where pi denotes the number of page that should be read i-th in turn.
Sometimes Vladik’s mom sorted some subsegment of permutation P from position l to position r inclusive, because she loves the order. For every of such sorting Vladik knows number x — what index of page in permutation he should read. He is wondered if the page, which he will read after sorting, has changed. In other words, has px changed? After every sorting Vladik return permutation to initial state, so you can assume that each sorting is independent from each other.
Input
First line contains two space-separated integers n, m (1 ≤ n, m ≤ 104) — length of permutation and number of times Vladik's mom sorted some subsegment of the book.
Second line contains n space-separated integers p1, p2, ..., pn (1 ≤ pi ≤ n) — permutation P. Note that elements in permutation are distinct.
Each of the next m lines contains three space-separated integers li, ri, xi (1 ≤ li ≤ xi ≤ ri ≤ n) — left and right borders of sorted subsegment in i-th sorting and position that is interesting to Vladik.
Output
For each mom’s sorting on it’s own line print "Yes", if page which is interesting to Vladik hasn't changed, or "No" otherwise.
Examples
Input
5 5
5 4 3 2 1
1 5 3
1 3 1
2 4 3
4 4 4
2 5 3
Output
Yes
No
Yes
Yes
No
Input
6 5
1 4 3 2 5 6
2 4 3
1 6 2
4 5 4
1 3 3
2 6 3
Output
Yes
No
Yes
No
Yes
Note
Explanation of first test case:
1. [1, 2, 3, 4, 5] — permutation after sorting, 3-rd element hasn’t changed, so answer is "Yes".
2. [3, 4, 5, 2, 1] — permutation after sorting, 1-st element has changed, so answer is "No".
3. [5, 2, 3, 4, 1] — permutation after sorting, 3-rd element hasn’t changed, so answer is "Yes".
4. [5, 4, 3, 2, 1] — permutation after sorting, 4-th element hasn’t changed, so answer is "Yes".
5. [5, 1, 2, 3, 4] — permutation after sorting, 3-rd element has changed, so answer is "No". | instruction | 0 | 78,791 | 12 | 157,582 |
Tags: implementation, sortings
Correct Solution:
```
n,m = map(int,input().split())
a = list(map(int,input().split()))
d = dict()
for _ in range(m):
l,r,x = map(int,input().split())
if x > r or x < l:
print("Yes")
else:
b = a[l-1:r]
res = 0
for item in b:
if item < a[x-1]:
res += 1
if res == x-l:
print("Yes")
else:
print("No")
``` | output | 1 | 78,791 | 12 | 157,583 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Vladik had started reading a complicated book about algorithms containing n pages. To improve understanding of what is written, his friends advised him to read pages in some order given by permutation P = [p1, p2, ..., pn], where pi denotes the number of page that should be read i-th in turn.
Sometimes Vladik’s mom sorted some subsegment of permutation P from position l to position r inclusive, because she loves the order. For every of such sorting Vladik knows number x — what index of page in permutation he should read. He is wondered if the page, which he will read after sorting, has changed. In other words, has px changed? After every sorting Vladik return permutation to initial state, so you can assume that each sorting is independent from each other.
Input
First line contains two space-separated integers n, m (1 ≤ n, m ≤ 104) — length of permutation and number of times Vladik's mom sorted some subsegment of the book.
Second line contains n space-separated integers p1, p2, ..., pn (1 ≤ pi ≤ n) — permutation P. Note that elements in permutation are distinct.
Each of the next m lines contains three space-separated integers li, ri, xi (1 ≤ li ≤ xi ≤ ri ≤ n) — left and right borders of sorted subsegment in i-th sorting and position that is interesting to Vladik.
Output
For each mom’s sorting on it’s own line print "Yes", if page which is interesting to Vladik hasn't changed, or "No" otherwise.
Examples
Input
5 5
5 4 3 2 1
1 5 3
1 3 1
2 4 3
4 4 4
2 5 3
Output
Yes
No
Yes
Yes
No
Input
6 5
1 4 3 2 5 6
2 4 3
1 6 2
4 5 4
1 3 3
2 6 3
Output
Yes
No
Yes
No
Yes
Note
Explanation of first test case:
1. [1, 2, 3, 4, 5] — permutation after sorting, 3-rd element hasn’t changed, so answer is "Yes".
2. [3, 4, 5, 2, 1] — permutation after sorting, 1-st element has changed, so answer is "No".
3. [5, 2, 3, 4, 1] — permutation after sorting, 3-rd element hasn’t changed, so answer is "Yes".
4. [5, 4, 3, 2, 1] — permutation after sorting, 4-th element hasn’t changed, so answer is "Yes".
5. [5, 1, 2, 3, 4] — permutation after sorting, 3-rd element has changed, so answer is "No". | instruction | 0 | 78,792 | 12 | 157,584 |
Tags: implementation, sortings
Correct Solution:
```
n,m=map(int,input().split())
a=list(map(int,input().split()))
for i in range(m):
l,r,x=map(lambda x:int(x)-1,input().split())
for j in range(l,r+1):
if a[j]<a[x]:
l+=1
if l>x:
break
if l==x:
print('Yes')
else:
print('No')
``` | output | 1 | 78,792 | 12 | 157,585 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Vladik had started reading a complicated book about algorithms containing n pages. To improve understanding of what is written, his friends advised him to read pages in some order given by permutation P = [p1, p2, ..., pn], where pi denotes the number of page that should be read i-th in turn.
Sometimes Vladik’s mom sorted some subsegment of permutation P from position l to position r inclusive, because she loves the order. For every of such sorting Vladik knows number x — what index of page in permutation he should read. He is wondered if the page, which he will read after sorting, has changed. In other words, has px changed? After every sorting Vladik return permutation to initial state, so you can assume that each sorting is independent from each other.
Input
First line contains two space-separated integers n, m (1 ≤ n, m ≤ 104) — length of permutation and number of times Vladik's mom sorted some subsegment of the book.
Second line contains n space-separated integers p1, p2, ..., pn (1 ≤ pi ≤ n) — permutation P. Note that elements in permutation are distinct.
Each of the next m lines contains three space-separated integers li, ri, xi (1 ≤ li ≤ xi ≤ ri ≤ n) — left and right borders of sorted subsegment in i-th sorting and position that is interesting to Vladik.
Output
For each mom’s sorting on it’s own line print "Yes", if page which is interesting to Vladik hasn't changed, or "No" otherwise.
Examples
Input
5 5
5 4 3 2 1
1 5 3
1 3 1
2 4 3
4 4 4
2 5 3
Output
Yes
No
Yes
Yes
No
Input
6 5
1 4 3 2 5 6
2 4 3
1 6 2
4 5 4
1 3 3
2 6 3
Output
Yes
No
Yes
No
Yes
Note
Explanation of first test case:
1. [1, 2, 3, 4, 5] — permutation after sorting, 3-rd element hasn’t changed, so answer is "Yes".
2. [3, 4, 5, 2, 1] — permutation after sorting, 1-st element has changed, so answer is "No".
3. [5, 2, 3, 4, 1] — permutation after sorting, 3-rd element hasn’t changed, so answer is "Yes".
4. [5, 4, 3, 2, 1] — permutation after sorting, 4-th element hasn’t changed, so answer is "Yes".
5. [5, 1, 2, 3, 4] — permutation after sorting, 3-rd element has changed, so answer is "No". | instruction | 0 | 78,793 | 12 | 157,586 |
Tags: implementation, sortings
Correct Solution:
```
n, m = list(map(int, input().split()))
p = list(map(int, input().split()))
for _ in range(m):
l, r, x = map(int, input().split())
l -= 1
r -= 1
x -= 1
a = 0
t = p[x]
for s in p[l:r+1]:
if s < t:
a += 1
if a == x - l: print("Yes")
else: print("No")
``` | output | 1 | 78,793 | 12 | 157,587 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Vladik had started reading a complicated book about algorithms containing n pages. To improve understanding of what is written, his friends advised him to read pages in some order given by permutation P = [p1, p2, ..., pn], where pi denotes the number of page that should be read i-th in turn.
Sometimes Vladik’s mom sorted some subsegment of permutation P from position l to position r inclusive, because she loves the order. For every of such sorting Vladik knows number x — what index of page in permutation he should read. He is wondered if the page, which he will read after sorting, has changed. In other words, has px changed? After every sorting Vladik return permutation to initial state, so you can assume that each sorting is independent from each other.
Input
First line contains two space-separated integers n, m (1 ≤ n, m ≤ 104) — length of permutation and number of times Vladik's mom sorted some subsegment of the book.
Second line contains n space-separated integers p1, p2, ..., pn (1 ≤ pi ≤ n) — permutation P. Note that elements in permutation are distinct.
Each of the next m lines contains three space-separated integers li, ri, xi (1 ≤ li ≤ xi ≤ ri ≤ n) — left and right borders of sorted subsegment in i-th sorting and position that is interesting to Vladik.
Output
For each mom’s sorting on it’s own line print "Yes", if page which is interesting to Vladik hasn't changed, or "No" otherwise.
Examples
Input
5 5
5 4 3 2 1
1 5 3
1 3 1
2 4 3
4 4 4
2 5 3
Output
Yes
No
Yes
Yes
No
Input
6 5
1 4 3 2 5 6
2 4 3
1 6 2
4 5 4
1 3 3
2 6 3
Output
Yes
No
Yes
No
Yes
Note
Explanation of first test case:
1. [1, 2, 3, 4, 5] — permutation after sorting, 3-rd element hasn’t changed, so answer is "Yes".
2. [3, 4, 5, 2, 1] — permutation after sorting, 1-st element has changed, so answer is "No".
3. [5, 2, 3, 4, 1] — permutation after sorting, 3-rd element hasn’t changed, so answer is "Yes".
4. [5, 4, 3, 2, 1] — permutation after sorting, 4-th element hasn’t changed, so answer is "Yes".
5. [5, 1, 2, 3, 4] — permutation after sorting, 3-rd element has changed, so answer is "No". | instruction | 0 | 78,794 | 12 | 157,588 |
Tags: implementation, sortings
Correct Solution:
```
n, m = map(int, input().split())
p = list(map(int, input().split()))
for _ in range(m):
l, r, x = map(int, input().split())
y = p[x-1]
c = 0
for z in range(l-1, r):
if p[z] < y:
c += 1
print("Yes" if c == x-l else "No")
``` | output | 1 | 78,794 | 12 | 157,589 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Vladik had started reading a complicated book about algorithms containing n pages. To improve understanding of what is written, his friends advised him to read pages in some order given by permutation P = [p1, p2, ..., pn], where pi denotes the number of page that should be read i-th in turn.
Sometimes Vladik’s mom sorted some subsegment of permutation P from position l to position r inclusive, because she loves the order. For every of such sorting Vladik knows number x — what index of page in permutation he should read. He is wondered if the page, which he will read after sorting, has changed. In other words, has px changed? After every sorting Vladik return permutation to initial state, so you can assume that each sorting is independent from each other.
Input
First line contains two space-separated integers n, m (1 ≤ n, m ≤ 104) — length of permutation and number of times Vladik's mom sorted some subsegment of the book.
Second line contains n space-separated integers p1, p2, ..., pn (1 ≤ pi ≤ n) — permutation P. Note that elements in permutation are distinct.
Each of the next m lines contains three space-separated integers li, ri, xi (1 ≤ li ≤ xi ≤ ri ≤ n) — left and right borders of sorted subsegment in i-th sorting and position that is interesting to Vladik.
Output
For each mom’s sorting on it’s own line print "Yes", if page which is interesting to Vladik hasn't changed, or "No" otherwise.
Examples
Input
5 5
5 4 3 2 1
1 5 3
1 3 1
2 4 3
4 4 4
2 5 3
Output
Yes
No
Yes
Yes
No
Input
6 5
1 4 3 2 5 6
2 4 3
1 6 2
4 5 4
1 3 3
2 6 3
Output
Yes
No
Yes
No
Yes
Note
Explanation of first test case:
1. [1, 2, 3, 4, 5] — permutation after sorting, 3-rd element hasn’t changed, so answer is "Yes".
2. [3, 4, 5, 2, 1] — permutation after sorting, 1-st element has changed, so answer is "No".
3. [5, 2, 3, 4, 1] — permutation after sorting, 3-rd element hasn’t changed, so answer is "Yes".
4. [5, 4, 3, 2, 1] — permutation after sorting, 4-th element hasn’t changed, so answer is "Yes".
5. [5, 1, 2, 3, 4] — permutation after sorting, 3-rd element has changed, so answer is "No". | instruction | 0 | 78,795 | 12 | 157,590 |
Tags: implementation, sortings
Correct Solution:
```
from sys import stdin, stdout
n,m=map(int,stdin.readline().split())
p=list(map(int,stdin.readline().split()))
for _ in range(m):
gre=0
sma=0
l,r,x=map(int,stdin.readline().split())
for i in range(l-1,r):
if i<x-1:
if p[i]>p[x-1]:
gre+=1
elif i>x-1:
if p[i]<p[x-1]:
sma+=1
if gre!=sma:
stdout.write("No \n")
else:
stdout.write("Yes \n")
``` | output | 1 | 78,795 | 12 | 157,591 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Vladik had started reading a complicated book about algorithms containing n pages. To improve understanding of what is written, his friends advised him to read pages in some order given by permutation P = [p1, p2, ..., pn], where pi denotes the number of page that should be read i-th in turn.
Sometimes Vladik’s mom sorted some subsegment of permutation P from position l to position r inclusive, because she loves the order. For every of such sorting Vladik knows number x — what index of page in permutation he should read. He is wondered if the page, which he will read after sorting, has changed. In other words, has px changed? After every sorting Vladik return permutation to initial state, so you can assume that each sorting is independent from each other.
Input
First line contains two space-separated integers n, m (1 ≤ n, m ≤ 104) — length of permutation and number of times Vladik's mom sorted some subsegment of the book.
Second line contains n space-separated integers p1, p2, ..., pn (1 ≤ pi ≤ n) — permutation P. Note that elements in permutation are distinct.
Each of the next m lines contains three space-separated integers li, ri, xi (1 ≤ li ≤ xi ≤ ri ≤ n) — left and right borders of sorted subsegment in i-th sorting and position that is interesting to Vladik.
Output
For each mom’s sorting on it’s own line print "Yes", if page which is interesting to Vladik hasn't changed, or "No" otherwise.
Examples
Input
5 5
5 4 3 2 1
1 5 3
1 3 1
2 4 3
4 4 4
2 5 3
Output
Yes
No
Yes
Yes
No
Input
6 5
1 4 3 2 5 6
2 4 3
1 6 2
4 5 4
1 3 3
2 6 3
Output
Yes
No
Yes
No
Yes
Note
Explanation of first test case:
1. [1, 2, 3, 4, 5] — permutation after sorting, 3-rd element hasn’t changed, so answer is "Yes".
2. [3, 4, 5, 2, 1] — permutation after sorting, 1-st element has changed, so answer is "No".
3. [5, 2, 3, 4, 1] — permutation after sorting, 3-rd element hasn’t changed, so answer is "Yes".
4. [5, 4, 3, 2, 1] — permutation after sorting, 4-th element hasn’t changed, so answer is "Yes".
5. [5, 1, 2, 3, 4] — permutation after sorting, 3-rd element has changed, so answer is "No". | instruction | 0 | 78,796 | 12 | 157,592 |
Tags: implementation, sortings
Correct Solution:
```
n,k = map(int, input().split())
p = list(map(int, input().split()))
def solve():
for i in range(k):
l,r,x = map(int, input().split())
nrLarger,nrSmaller = r - x, x - l
cL,cS = 0,0
if r == l:
print("Yes")
else:
for j in range(l-1,r):
if p[j] < p[x-1]:
cS +=1
if cS > nrSmaller:
break
print("Yes" if cS == nrSmaller else "No")
solve()
``` | output | 1 | 78,796 | 12 | 157,593 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Vladik had started reading a complicated book about algorithms containing n pages. To improve understanding of what is written, his friends advised him to read pages in some order given by permutation P = [p1, p2, ..., pn], where pi denotes the number of page that should be read i-th in turn.
Sometimes Vladik’s mom sorted some subsegment of permutation P from position l to position r inclusive, because she loves the order. For every of such sorting Vladik knows number x — what index of page in permutation he should read. He is wondered if the page, which he will read after sorting, has changed. In other words, has px changed? After every sorting Vladik return permutation to initial state, so you can assume that each sorting is independent from each other.
Input
First line contains two space-separated integers n, m (1 ≤ n, m ≤ 104) — length of permutation and number of times Vladik's mom sorted some subsegment of the book.
Second line contains n space-separated integers p1, p2, ..., pn (1 ≤ pi ≤ n) — permutation P. Note that elements in permutation are distinct.
Each of the next m lines contains three space-separated integers li, ri, xi (1 ≤ li ≤ xi ≤ ri ≤ n) — left and right borders of sorted subsegment in i-th sorting and position that is interesting to Vladik.
Output
For each mom’s sorting on it’s own line print "Yes", if page which is interesting to Vladik hasn't changed, or "No" otherwise.
Examples
Input
5 5
5 4 3 2 1
1 5 3
1 3 1
2 4 3
4 4 4
2 5 3
Output
Yes
No
Yes
Yes
No
Input
6 5
1 4 3 2 5 6
2 4 3
1 6 2
4 5 4
1 3 3
2 6 3
Output
Yes
No
Yes
No
Yes
Note
Explanation of first test case:
1. [1, 2, 3, 4, 5] — permutation after sorting, 3-rd element hasn’t changed, so answer is "Yes".
2. [3, 4, 5, 2, 1] — permutation after sorting, 1-st element has changed, so answer is "No".
3. [5, 2, 3, 4, 1] — permutation after sorting, 3-rd element hasn’t changed, so answer is "Yes".
4. [5, 4, 3, 2, 1] — permutation after sorting, 4-th element hasn’t changed, so answer is "Yes".
5. [5, 1, 2, 3, 4] — permutation after sorting, 3-rd element has changed, so answer is "No". | instruction | 0 | 78,797 | 12 | 157,594 |
Tags: implementation, sortings
Correct Solution:
```
import math
import bisect
n, m = map(int, input().split())
P = [int(c) for c in input().split()]
b_len = math.ceil(math.sqrt(n))
b = []
for i in range(1000):
b.append(sorted(P[i*b_len:(i+1)*b_len]))
if n <= (i+1)*b_len:
break
b_cnt = len(b)
#print(b)
for i in range(m):
l, r, x = map(int, input().split())
l_b = (l-1) // b_len
r_b = (r-1) // b_len
if r_b - l_b <= 1:
sorted_a = sorted(P[l-1:r])
print("Yes" if P[x-1] == sorted_a[x-1-(l-1)] else "No")
else:
_a = sorted(P[l-1:(l_b+1)*b_len]+P[r_b*b_len:r])
#print(_a)
idx = bisect.bisect_left(_a, P[x-1])
#print(idx)
for j in range(l_b+1, r_b):
#print(b[j])
idx += bisect.bisect_left(b[j], P[x-1])
#print(idx)
print("Yes" if idx+l == x else "No")
``` | output | 1 | 78,797 | 12 | 157,595 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Vladik had started reading a complicated book about algorithms containing n pages. To improve understanding of what is written, his friends advised him to read pages in some order given by permutation P = [p1, p2, ..., pn], where pi denotes the number of page that should be read i-th in turn.
Sometimes Vladik’s mom sorted some subsegment of permutation P from position l to position r inclusive, because she loves the order. For every of such sorting Vladik knows number x — what index of page in permutation he should read. He is wondered if the page, which he will read after sorting, has changed. In other words, has px changed? After every sorting Vladik return permutation to initial state, so you can assume that each sorting is independent from each other.
Input
First line contains two space-separated integers n, m (1 ≤ n, m ≤ 104) — length of permutation and number of times Vladik's mom sorted some subsegment of the book.
Second line contains n space-separated integers p1, p2, ..., pn (1 ≤ pi ≤ n) — permutation P. Note that elements in permutation are distinct.
Each of the next m lines contains three space-separated integers li, ri, xi (1 ≤ li ≤ xi ≤ ri ≤ n) — left and right borders of sorted subsegment in i-th sorting and position that is interesting to Vladik.
Output
For each mom’s sorting on it’s own line print "Yes", if page which is interesting to Vladik hasn't changed, or "No" otherwise.
Examples
Input
5 5
5 4 3 2 1
1 5 3
1 3 1
2 4 3
4 4 4
2 5 3
Output
Yes
No
Yes
Yes
No
Input
6 5
1 4 3 2 5 6
2 4 3
1 6 2
4 5 4
1 3 3
2 6 3
Output
Yes
No
Yes
No
Yes
Note
Explanation of first test case:
1. [1, 2, 3, 4, 5] — permutation after sorting, 3-rd element hasn’t changed, so answer is "Yes".
2. [3, 4, 5, 2, 1] — permutation after sorting, 1-st element has changed, so answer is "No".
3. [5, 2, 3, 4, 1] — permutation after sorting, 3-rd element hasn’t changed, so answer is "Yes".
4. [5, 4, 3, 2, 1] — permutation after sorting, 4-th element hasn’t changed, so answer is "Yes".
5. [5, 1, 2, 3, 4] — permutation after sorting, 3-rd element has changed, so answer is "No".
Submitted Solution:
```
def main():
R = lambda: map(int, input().split())
n, m = R()
p = [0] + list(R())
for _ in range(m):
l, r, x = R()
v = p[x]
c = sum(map(lambda x: x < v, p[l:r+1]))
print('Yes' if c == x - l else 'No')
main()
``` | instruction | 0 | 78,798 | 12 | 157,596 |
Yes | output | 1 | 78,798 | 12 | 157,597 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Vladik had started reading a complicated book about algorithms containing n pages. To improve understanding of what is written, his friends advised him to read pages in some order given by permutation P = [p1, p2, ..., pn], where pi denotes the number of page that should be read i-th in turn.
Sometimes Vladik’s mom sorted some subsegment of permutation P from position l to position r inclusive, because she loves the order. For every of such sorting Vladik knows number x — what index of page in permutation he should read. He is wondered if the page, which he will read after sorting, has changed. In other words, has px changed? After every sorting Vladik return permutation to initial state, so you can assume that each sorting is independent from each other.
Input
First line contains two space-separated integers n, m (1 ≤ n, m ≤ 104) — length of permutation and number of times Vladik's mom sorted some subsegment of the book.
Second line contains n space-separated integers p1, p2, ..., pn (1 ≤ pi ≤ n) — permutation P. Note that elements in permutation are distinct.
Each of the next m lines contains three space-separated integers li, ri, xi (1 ≤ li ≤ xi ≤ ri ≤ n) — left and right borders of sorted subsegment in i-th sorting and position that is interesting to Vladik.
Output
For each mom’s sorting on it’s own line print "Yes", if page which is interesting to Vladik hasn't changed, or "No" otherwise.
Examples
Input
5 5
5 4 3 2 1
1 5 3
1 3 1
2 4 3
4 4 4
2 5 3
Output
Yes
No
Yes
Yes
No
Input
6 5
1 4 3 2 5 6
2 4 3
1 6 2
4 5 4
1 3 3
2 6 3
Output
Yes
No
Yes
No
Yes
Note
Explanation of first test case:
1. [1, 2, 3, 4, 5] — permutation after sorting, 3-rd element hasn’t changed, so answer is "Yes".
2. [3, 4, 5, 2, 1] — permutation after sorting, 1-st element has changed, so answer is "No".
3. [5, 2, 3, 4, 1] — permutation after sorting, 3-rd element hasn’t changed, so answer is "Yes".
4. [5, 4, 3, 2, 1] — permutation after sorting, 4-th element hasn’t changed, so answer is "Yes".
5. [5, 1, 2, 3, 4] — permutation after sorting, 3-rd element has changed, so answer is "No".
Submitted Solution:
```
n, m = map(int, input().split())
p = list(map(int, input().split()))
for _ in range(m):
l, r, x = map(int, input().split())
px = p[x - 1]
cnt = l
for i in range(l, r + 1):
if p[i - 1] < px:
cnt += 1
if cnt == x:
print("Yes")
else:
print("No")
``` | instruction | 0 | 78,799 | 12 | 157,598 |
Yes | output | 1 | 78,799 | 12 | 157,599 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Vladik had started reading a complicated book about algorithms containing n pages. To improve understanding of what is written, his friends advised him to read pages in some order given by permutation P = [p1, p2, ..., pn], where pi denotes the number of page that should be read i-th in turn.
Sometimes Vladik’s mom sorted some subsegment of permutation P from position l to position r inclusive, because she loves the order. For every of such sorting Vladik knows number x — what index of page in permutation he should read. He is wondered if the page, which he will read after sorting, has changed. In other words, has px changed? After every sorting Vladik return permutation to initial state, so you can assume that each sorting is independent from each other.
Input
First line contains two space-separated integers n, m (1 ≤ n, m ≤ 104) — length of permutation and number of times Vladik's mom sorted some subsegment of the book.
Second line contains n space-separated integers p1, p2, ..., pn (1 ≤ pi ≤ n) — permutation P. Note that elements in permutation are distinct.
Each of the next m lines contains three space-separated integers li, ri, xi (1 ≤ li ≤ xi ≤ ri ≤ n) — left and right borders of sorted subsegment in i-th sorting and position that is interesting to Vladik.
Output
For each mom’s sorting on it’s own line print "Yes", if page which is interesting to Vladik hasn't changed, or "No" otherwise.
Examples
Input
5 5
5 4 3 2 1
1 5 3
1 3 1
2 4 3
4 4 4
2 5 3
Output
Yes
No
Yes
Yes
No
Input
6 5
1 4 3 2 5 6
2 4 3
1 6 2
4 5 4
1 3 3
2 6 3
Output
Yes
No
Yes
No
Yes
Note
Explanation of first test case:
1. [1, 2, 3, 4, 5] — permutation after sorting, 3-rd element hasn’t changed, so answer is "Yes".
2. [3, 4, 5, 2, 1] — permutation after sorting, 1-st element has changed, so answer is "No".
3. [5, 2, 3, 4, 1] — permutation after sorting, 3-rd element hasn’t changed, so answer is "Yes".
4. [5, 4, 3, 2, 1] — permutation after sorting, 4-th element hasn’t changed, so answer is "Yes".
5. [5, 1, 2, 3, 4] — permutation after sorting, 3-rd element has changed, so answer is "No".
Submitted Solution:
```
n, m = map(int, input().split())
a = list(map(int, input().split()))
for i in range(m):
l, r, x = map(int, input().split())
count_less = 0
for j in range(l-1, r):
if a[j] < a[x-1]:
count_less += 1
new_pos = l + count_less
if new_pos == x:
print("Yes")
else:
print("No")
``` | instruction | 0 | 78,800 | 12 | 157,600 |
Yes | output | 1 | 78,800 | 12 | 157,601 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Vladik had started reading a complicated book about algorithms containing n pages. To improve understanding of what is written, his friends advised him to read pages in some order given by permutation P = [p1, p2, ..., pn], where pi denotes the number of page that should be read i-th in turn.
Sometimes Vladik’s mom sorted some subsegment of permutation P from position l to position r inclusive, because she loves the order. For every of such sorting Vladik knows number x — what index of page in permutation he should read. He is wondered if the page, which he will read after sorting, has changed. In other words, has px changed? After every sorting Vladik return permutation to initial state, so you can assume that each sorting is independent from each other.
Input
First line contains two space-separated integers n, m (1 ≤ n, m ≤ 104) — length of permutation and number of times Vladik's mom sorted some subsegment of the book.
Second line contains n space-separated integers p1, p2, ..., pn (1 ≤ pi ≤ n) — permutation P. Note that elements in permutation are distinct.
Each of the next m lines contains three space-separated integers li, ri, xi (1 ≤ li ≤ xi ≤ ri ≤ n) — left and right borders of sorted subsegment in i-th sorting and position that is interesting to Vladik.
Output
For each mom’s sorting on it’s own line print "Yes", if page which is interesting to Vladik hasn't changed, or "No" otherwise.
Examples
Input
5 5
5 4 3 2 1
1 5 3
1 3 1
2 4 3
4 4 4
2 5 3
Output
Yes
No
Yes
Yes
No
Input
6 5
1 4 3 2 5 6
2 4 3
1 6 2
4 5 4
1 3 3
2 6 3
Output
Yes
No
Yes
No
Yes
Note
Explanation of first test case:
1. [1, 2, 3, 4, 5] — permutation after sorting, 3-rd element hasn’t changed, so answer is "Yes".
2. [3, 4, 5, 2, 1] — permutation after sorting, 1-st element has changed, so answer is "No".
3. [5, 2, 3, 4, 1] — permutation after sorting, 3-rd element hasn’t changed, so answer is "Yes".
4. [5, 4, 3, 2, 1] — permutation after sorting, 4-th element hasn’t changed, so answer is "Yes".
5. [5, 1, 2, 3, 4] — permutation after sorting, 3-rd element has changed, so answer is "No".
Submitted Solution:
```
n,m=list(map(int,input().split()))
p=list(map(int,input().split()))
for i in range(m):
l,r,x=list(map(int,input().split()))
q=p[x-1]
c=0
for j in range(l-1,r):
if q>p[j]:
c=c+1
if l+c==x:
print('Yes')
else:
print('No')
``` | instruction | 0 | 78,801 | 12 | 157,602 |
Yes | output | 1 | 78,801 | 12 | 157,603 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Vladik had started reading a complicated book about algorithms containing n pages. To improve understanding of what is written, his friends advised him to read pages in some order given by permutation P = [p1, p2, ..., pn], where pi denotes the number of page that should be read i-th in turn.
Sometimes Vladik’s mom sorted some subsegment of permutation P from position l to position r inclusive, because she loves the order. For every of such sorting Vladik knows number x — what index of page in permutation he should read. He is wondered if the page, which he will read after sorting, has changed. In other words, has px changed? After every sorting Vladik return permutation to initial state, so you can assume that each sorting is independent from each other.
Input
First line contains two space-separated integers n, m (1 ≤ n, m ≤ 104) — length of permutation and number of times Vladik's mom sorted some subsegment of the book.
Second line contains n space-separated integers p1, p2, ..., pn (1 ≤ pi ≤ n) — permutation P. Note that elements in permutation are distinct.
Each of the next m lines contains three space-separated integers li, ri, xi (1 ≤ li ≤ xi ≤ ri ≤ n) — left and right borders of sorted subsegment in i-th sorting and position that is interesting to Vladik.
Output
For each mom’s sorting on it’s own line print "Yes", if page which is interesting to Vladik hasn't changed, or "No" otherwise.
Examples
Input
5 5
5 4 3 2 1
1 5 3
1 3 1
2 4 3
4 4 4
2 5 3
Output
Yes
No
Yes
Yes
No
Input
6 5
1 4 3 2 5 6
2 4 3
1 6 2
4 5 4
1 3 3
2 6 3
Output
Yes
No
Yes
No
Yes
Note
Explanation of first test case:
1. [1, 2, 3, 4, 5] — permutation after sorting, 3-rd element hasn’t changed, so answer is "Yes".
2. [3, 4, 5, 2, 1] — permutation after sorting, 1-st element has changed, so answer is "No".
3. [5, 2, 3, 4, 1] — permutation after sorting, 3-rd element hasn’t changed, so answer is "Yes".
4. [5, 4, 3, 2, 1] — permutation after sorting, 4-th element hasn’t changed, so answer is "Yes".
5. [5, 1, 2, 3, 4] — permutation after sorting, 3-rd element has changed, so answer is "No".
Submitted Solution:
```
n,m=tuple(input().split(" "))
n=int(n)
m=int(m)
p=list(input().split(" "))
l=-1
r=-1
x=-1
for y in range(m):
a=p
l,r,x=(int(q) for q in input().split(" "))
b=a[l-1:r]
b.sort()
a=a[:l-1]+b+a[r:]
if p[x-1]==a[x-1]:
print("Yes")
else:
print("No")
``` | instruction | 0 | 78,802 | 12 | 157,604 |
No | output | 1 | 78,802 | 12 | 157,605 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Vladik had started reading a complicated book about algorithms containing n pages. To improve understanding of what is written, his friends advised him to read pages in some order given by permutation P = [p1, p2, ..., pn], where pi denotes the number of page that should be read i-th in turn.
Sometimes Vladik’s mom sorted some subsegment of permutation P from position l to position r inclusive, because she loves the order. For every of such sorting Vladik knows number x — what index of page in permutation he should read. He is wondered if the page, which he will read after sorting, has changed. In other words, has px changed? After every sorting Vladik return permutation to initial state, so you can assume that each sorting is independent from each other.
Input
First line contains two space-separated integers n, m (1 ≤ n, m ≤ 104) — length of permutation and number of times Vladik's mom sorted some subsegment of the book.
Second line contains n space-separated integers p1, p2, ..., pn (1 ≤ pi ≤ n) — permutation P. Note that elements in permutation are distinct.
Each of the next m lines contains three space-separated integers li, ri, xi (1 ≤ li ≤ xi ≤ ri ≤ n) — left and right borders of sorted subsegment in i-th sorting and position that is interesting to Vladik.
Output
For each mom’s sorting on it’s own line print "Yes", if page which is interesting to Vladik hasn't changed, or "No" otherwise.
Examples
Input
5 5
5 4 3 2 1
1 5 3
1 3 1
2 4 3
4 4 4
2 5 3
Output
Yes
No
Yes
Yes
No
Input
6 5
1 4 3 2 5 6
2 4 3
1 6 2
4 5 4
1 3 3
2 6 3
Output
Yes
No
Yes
No
Yes
Note
Explanation of first test case:
1. [1, 2, 3, 4, 5] — permutation after sorting, 3-rd element hasn’t changed, so answer is "Yes".
2. [3, 4, 5, 2, 1] — permutation after sorting, 1-st element has changed, so answer is "No".
3. [5, 2, 3, 4, 1] — permutation after sorting, 3-rd element hasn’t changed, so answer is "Yes".
4. [5, 4, 3, 2, 1] — permutation after sorting, 4-th element hasn’t changed, so answer is "Yes".
5. [5, 1, 2, 3, 4] — permutation after sorting, 3-rd element has changed, so answer is "No".
Submitted Solution:
```
n,m = input().split(' ')
a = input().split(' ')
b = list(a)
for i in range(int(m)):
l1,r1,x1 = input().split(' ')
l = int(l1)-1; r=int(r1)-1; x=int(x1)-1
if(r==int(n)-1):
b[l:] = sorted(b[l:])
print(b)
else:
b[l:r+1] = sorted(b[l:r+1])
print(b)
if(b[x]==a[x]):
print("Yes")
else:
print("No")
b=list(a)
``` | instruction | 0 | 78,803 | 12 | 157,606 |
No | output | 1 | 78,803 | 12 | 157,607 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Vladik had started reading a complicated book about algorithms containing n pages. To improve understanding of what is written, his friends advised him to read pages in some order given by permutation P = [p1, p2, ..., pn], where pi denotes the number of page that should be read i-th in turn.
Sometimes Vladik’s mom sorted some subsegment of permutation P from position l to position r inclusive, because she loves the order. For every of such sorting Vladik knows number x — what index of page in permutation he should read. He is wondered if the page, which he will read after sorting, has changed. In other words, has px changed? After every sorting Vladik return permutation to initial state, so you can assume that each sorting is independent from each other.
Input
First line contains two space-separated integers n, m (1 ≤ n, m ≤ 104) — length of permutation and number of times Vladik's mom sorted some subsegment of the book.
Second line contains n space-separated integers p1, p2, ..., pn (1 ≤ pi ≤ n) — permutation P. Note that elements in permutation are distinct.
Each of the next m lines contains three space-separated integers li, ri, xi (1 ≤ li ≤ xi ≤ ri ≤ n) — left and right borders of sorted subsegment in i-th sorting and position that is interesting to Vladik.
Output
For each mom’s sorting on it’s own line print "Yes", if page which is interesting to Vladik hasn't changed, or "No" otherwise.
Examples
Input
5 5
5 4 3 2 1
1 5 3
1 3 1
2 4 3
4 4 4
2 5 3
Output
Yes
No
Yes
Yes
No
Input
6 5
1 4 3 2 5 6
2 4 3
1 6 2
4 5 4
1 3 3
2 6 3
Output
Yes
No
Yes
No
Yes
Note
Explanation of first test case:
1. [1, 2, 3, 4, 5] — permutation after sorting, 3-rd element hasn’t changed, so answer is "Yes".
2. [3, 4, 5, 2, 1] — permutation after sorting, 1-st element has changed, so answer is "No".
3. [5, 2, 3, 4, 1] — permutation after sorting, 3-rd element hasn’t changed, so answer is "Yes".
4. [5, 4, 3, 2, 1] — permutation after sorting, 4-th element hasn’t changed, so answer is "Yes".
5. [5, 1, 2, 3, 4] — permutation after sorting, 3-rd element has changed, so answer is "No".
Submitted Solution:
```
import copy
n,m=map(int,input().split())
p=list(map(int,input().split()))
for i in range(m):
l,r,x=map(int,input().split())
p2 = copy.deepcopy(p)
p2[l-1:r]= sorted(p2[l-1:r])
if p[x-1]==p2[x-1]:
print('yes')
else:
print('no')
``` | instruction | 0 | 78,804 | 12 | 157,608 |
No | output | 1 | 78,804 | 12 | 157,609 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Vladik had started reading a complicated book about algorithms containing n pages. To improve understanding of what is written, his friends advised him to read pages in some order given by permutation P = [p1, p2, ..., pn], where pi denotes the number of page that should be read i-th in turn.
Sometimes Vladik’s mom sorted some subsegment of permutation P from position l to position r inclusive, because she loves the order. For every of such sorting Vladik knows number x — what index of page in permutation he should read. He is wondered if the page, which he will read after sorting, has changed. In other words, has px changed? After every sorting Vladik return permutation to initial state, so you can assume that each sorting is independent from each other.
Input
First line contains two space-separated integers n, m (1 ≤ n, m ≤ 104) — length of permutation and number of times Vladik's mom sorted some subsegment of the book.
Second line contains n space-separated integers p1, p2, ..., pn (1 ≤ pi ≤ n) — permutation P. Note that elements in permutation are distinct.
Each of the next m lines contains three space-separated integers li, ri, xi (1 ≤ li ≤ xi ≤ ri ≤ n) — left and right borders of sorted subsegment in i-th sorting and position that is interesting to Vladik.
Output
For each mom’s sorting on it’s own line print "Yes", if page which is interesting to Vladik hasn't changed, or "No" otherwise.
Examples
Input
5 5
5 4 3 2 1
1 5 3
1 3 1
2 4 3
4 4 4
2 5 3
Output
Yes
No
Yes
Yes
No
Input
6 5
1 4 3 2 5 6
2 4 3
1 6 2
4 5 4
1 3 3
2 6 3
Output
Yes
No
Yes
No
Yes
Note
Explanation of first test case:
1. [1, 2, 3, 4, 5] — permutation after sorting, 3-rd element hasn’t changed, so answer is "Yes".
2. [3, 4, 5, 2, 1] — permutation after sorting, 1-st element has changed, so answer is "No".
3. [5, 2, 3, 4, 1] — permutation after sorting, 3-rd element hasn’t changed, so answer is "Yes".
4. [5, 4, 3, 2, 1] — permutation after sorting, 4-th element hasn’t changed, so answer is "Yes".
5. [5, 1, 2, 3, 4] — permutation after sorting, 3-rd element has changed, so answer is "No".
Submitted Solution:
```
import math
import heapq
n, m = map(int, input().split())
P = [int(c) for c in input().split()]
b_len = math.ceil(math.sqrt(n))
b = []
for i in range(100):
b.append(sorted(P[i*b_len:(i+1)*b_len]))
if n <= (i+1)*b_len:
break
for i in range(m):
l, r, x = map(int, input().split())
l_b = l // b_len
r_b = r // b_len
if l_b == r_b:
sorted_a = sorted(P[l-1:r])
else:
sorted_a=sorted(P[l-1:(l_b+1)*b_len]+P[r_b*b_len:r])
sorted_a = list(heapq.merge(*b[l_b:r_b-1], sorted_a))
print("Yes" if P[x-1] == sorted_a[x-1-(l-1)] else "No")
``` | instruction | 0 | 78,805 | 12 | 157,610 |
No | output | 1 | 78,805 | 12 | 157,611 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Let's call the roundness of the number the number of zeros to which it ends.
You have an array of n numbers. You need to choose a subset of exactly k numbers so that the roundness of the product of the selected numbers will be maximum possible.
Input
The first line contains two integer numbers n and k (1 ≤ n ≤ 200, 1 ≤ k ≤ n).
The second line contains n space-separated integer numbers a1, a2, ..., an (1 ≤ ai ≤ 1018).
Output
Print maximal roundness of product of the chosen subset of length k.
Examples
Input
3 2
50 4 20
Output
3
Input
5 3
15 16 3 25 9
Output
3
Input
3 3
9 77 13
Output
0
Note
In the first example there are 3 subsets of 2 numbers. [50, 4] has product 200 with roundness 2, [4, 20] — product 80, roundness 1, [50, 20] — product 1000, roundness 3.
In the second example subset [15, 16, 25] has product 6000, roundness 3.
In the third example all subsets has product with roundness 0. | instruction | 0 | 78,806 | 12 | 157,612 |
Tags: dp, math
Correct Solution:
```
import sys
n, K = map(int, input().split())
a = list(map(int, input().split()))
m2, m5 = [0]*n, [0]*n
for i, x in enumerate(a):
while x % 2 == 0:
x //= 2
m2[i] += 1
while x % 5 == 0:
x //= 5
m5[i] += 1
dp = [[-10**9]*5100 for _ in range(K)]
dp[0][0] = 0
for i in range(n):
x, y = m5[i], m2[i]
for j in range(min(K-1, i)-1, -1, -1):
for k in range(5000, -1, -1):
dp[j+1][k+x] = max(dp[j+1][k+x], dp[j][k] + y)
dp[0][x] = max(dp[0][x], y)
ans = 0
for i in range(5001):
ans = max(ans, min(i, dp[-1][i]))
print(ans)
``` | output | 1 | 78,806 | 12 | 157,613 |
Provide a correct Python 3 solution for this coding contest problem.
Given are two sequences A and B, both of length N. A and B are each sorted in the ascending order. Check if it is possible to reorder the terms of B so that for each i (1 \leq i \leq N) A_i \neq B_i holds, and if it is possible, output any of the reorderings that achieve it.
Constraints
* 1\leq N \leq 2 \times 10^5
* 1\leq A_i,B_i \leq N
* A and B are each sorted in the ascending order.
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
N
A_1 A_2 \cdots A_N
B_1 B_2 \cdots B_N
Output
If there exist no reorderings that satisfy the condition, print `No`.
If there exists a reordering that satisfies the condition, print `Yes` on the first line. After that, print a reordering of B on the second line, separating terms with a whitespace.
If there are multiple reorderings that satisfy the condition, you can print any of them.
Examples
Input
6
1 1 1 2 2 3
1 1 1 2 2 3
Output
Yes
2 2 3 1 1 1
Input
3
1 1 2
1 1 3
Output
No
Input
4
1 1 2 3
1 2 3 3
Output
Yes
3 3 1 2 | instruction | 0 | 78,860 | 12 | 157,720 |
"Correct Solution:
```
from collections import deque
import sys
input = sys.stdin.readline
N = int(input())
A = list(map(int, input().split()))
B = list(map(int, input().split()))
cntA = [0] * (N + 1)
cntB = [0] * (N + 1)
for i in range(N):
cntA[A[i]] += 1
cntB[B[i]] += 1
nums = [(cntA[i], cntB[i], i) for i in range(1, N+1)]
nums.sort(key=lambda p: p[0] + p[1], reverse=True)
a = deque()
b = deque()
c = deque(list(range(N)))
ansa = [0] * N
ansb = [0] * N
for x, y, n in nums:
if x == y == 0:
break
if x + y > len(a) + len(b) + len(c):
print('No')
exit()
ra = x - len(a)
rb = y - len(b)
for i in range(ra):
ansa[c[0]] = n
b.append(c[0])
c.popleft()
x -= 1
for i in range(rb):
ansb[c[0]] = n
a.append(c[0])
c.popleft()
y -= 1
while c and (x or y):
if x:
ansa[c[0]] = n
b.append(c[0])
x -= 1
else:
ansb[c[0]] = n
a.append(c[0])
y -= 1
c.popleft()
for i in range(x):
ansa[a[0]] = n
a.popleft()
for i in range(y):
ansb[b[0]] = n
b.popleft()
ans = []
for i in range(N):
ans.append((ansa[i], ansb[i]))
ans.sort()
print('Yes')
print(*[p[1] for p in ans])
``` | output | 1 | 78,860 | 12 | 157,721 |
Provide a correct Python 3 solution for this coding contest problem.
Given are two sequences A and B, both of length N. A and B are each sorted in the ascending order. Check if it is possible to reorder the terms of B so that for each i (1 \leq i \leq N) A_i \neq B_i holds, and if it is possible, output any of the reorderings that achieve it.
Constraints
* 1\leq N \leq 2 \times 10^5
* 1\leq A_i,B_i \leq N
* A and B are each sorted in the ascending order.
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
N
A_1 A_2 \cdots A_N
B_1 B_2 \cdots B_N
Output
If there exist no reorderings that satisfy the condition, print `No`.
If there exists a reordering that satisfies the condition, print `Yes` on the first line. After that, print a reordering of B on the second line, separating terms with a whitespace.
If there are multiple reorderings that satisfy the condition, you can print any of them.
Examples
Input
6
1 1 1 2 2 3
1 1 1 2 2 3
Output
Yes
2 2 3 1 1 1
Input
3
1 1 2
1 1 3
Output
No
Input
4
1 1 2 3
1 2 3 3
Output
Yes
3 3 1 2 | instruction | 0 | 78,862 | 12 | 157,724 |
"Correct Solution:
```
def main():
n = int(input())
a = list(map(int, input().split()))
b = list(map(int, input().split()))
ai, bi = 0, 0
al, bl = [], []
while ai < n and bi < n:
ax, bx = a[ai], b[bi]
la, lb = [], []
if ax == bx:
cnt = 2
la.append(ai)
ai += 1
while ai < n and a[ai] == ax:
la.append(ai)
cnt += 1
ai += 1
lb.append(bi)
bi += 1
while bi < n and b[bi] == bx:
lb.append(bi)
cnt += 1
bi += 1
if cnt > n:
print('No')
exit()
elif ax < bx:
la.append(ai)
ai += 1
else:
lb.append(bi)
bi += 1
al.append(la)
bl.append(lb)
print('Yes')
slit = 0
for i in range(len(al)):
if len(al[i]) == 0 or len(bl[i]) == 0:
continue
if al[i][-1] - bl[i][0] + 1 > slit:
slit = al[i][-1] - bl[i][0] + 1
print(' '.join(map(str, b[n-slit:] + b[:n-slit])))
main()
``` | output | 1 | 78,862 | 12 | 157,725 |
Provide a correct Python 3 solution for this coding contest problem.
Given are two sequences A and B, both of length N. A and B are each sorted in the ascending order. Check if it is possible to reorder the terms of B so that for each i (1 \leq i \leq N) A_i \neq B_i holds, and if it is possible, output any of the reorderings that achieve it.
Constraints
* 1\leq N \leq 2 \times 10^5
* 1\leq A_i,B_i \leq N
* A and B are each sorted in the ascending order.
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
N
A_1 A_2 \cdots A_N
B_1 B_2 \cdots B_N
Output
If there exist no reorderings that satisfy the condition, print `No`.
If there exists a reordering that satisfies the condition, print `Yes` on the first line. After that, print a reordering of B on the second line, separating terms with a whitespace.
If there are multiple reorderings that satisfy the condition, you can print any of them.
Examples
Input
6
1 1 1 2 2 3
1 1 1 2 2 3
Output
Yes
2 2 3 1 1 1
Input
3
1 1 2
1 1 3
Output
No
Input
4
1 1 2 3
1 2 3 3
Output
Yes
3 3 1 2 | instruction | 0 | 78,863 | 12 | 157,726 |
"Correct Solution:
```
N = int(input())
A = list(map(int, input().split()))
B = list(map(int, input().split()))
from collections import Counter
cA = Counter(A)
cB = Counter(B)
f = 0
for num, val in cA.items():
if num not in cB:
continue
else:
if cB[num] + val > N:
f = 1
tpA = [-1] * (N + 1)
tpB = [-1] * (N + 1)
a = A[0]
b = B[0]
tpB[b] = 0
for i in range(1, N):
if a != A[i]:
tpA[a] = i
a = A[i]
if b != B[i]:
b = B[i]
tpB[b] = i
tpA[a] = N
ans = [0] * N
if f == 1:
print("No")
else:
print("Yes")
t = 0
for i in range(N+1):
if tpA[i] >= 0 and tpB[i] >= 0:
t = max(t, tpA[i] - tpB[i])
for i in range(N):
ans[i+t-N] = B[i]
#print(tpA, tpB, t)
print(" ".join([str(_) for _ in ans]))
``` | output | 1 | 78,863 | 12 | 157,727 |
Provide a correct Python 3 solution for this coding contest problem.
Given are two sequences A and B, both of length N. A and B are each sorted in the ascending order. Check if it is possible to reorder the terms of B so that for each i (1 \leq i \leq N) A_i \neq B_i holds, and if it is possible, output any of the reorderings that achieve it.
Constraints
* 1\leq N \leq 2 \times 10^5
* 1\leq A_i,B_i \leq N
* A and B are each sorted in the ascending order.
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
N
A_1 A_2 \cdots A_N
B_1 B_2 \cdots B_N
Output
If there exist no reorderings that satisfy the condition, print `No`.
If there exists a reordering that satisfies the condition, print `Yes` on the first line. After that, print a reordering of B on the second line, separating terms with a whitespace.
If there are multiple reorderings that satisfy the condition, you can print any of them.
Examples
Input
6
1 1 1 2 2 3
1 1 1 2 2 3
Output
Yes
2 2 3 1 1 1
Input
3
1 1 2
1 1 3
Output
No
Input
4
1 1 2 3
1 2 3 3
Output
Yes
3 3 1 2 | instruction | 0 | 78,864 | 12 | 157,728 |
"Correct Solution:
```
from collections import Counter
from heapq import heappush, heappop, heapreplace
N = int(input())
A = list(map(int, input().split()))
B = list(map(int, input().split()))
AC = Counter(A)
BC = Counter(B)
S = AC + BC
q = []
for k, v in S.items():
heappush(q, (-v, k))
ans = []
while q:
v, k = q[0]
v = -v
if v == 0:
heappop(q)
elif v != S[k]:
heapreplace(q, (-S[k], k))
else:
heapreplace(q, (-(v - 1), k))
if v > N:
print('No')
exit()
else:
if AC[k] > 0:
a = k
for l in BC.keys():
if l != k:
b = l
break
else:
b = k
for l in AC.keys():
if l != k:
a = l
break
ans.append((a, b))
S[a] -= 1
S[b] -= 1
AC[a] -= 1
if not AC[a]:
AC.pop(a)
BC[b] -= 1
if not BC[b]:
BC.pop(b)
print('Yes')
ans.sort()
X = [b for a, b in ans]
print(*X)
``` | output | 1 | 78,864 | 12 | 157,729 |
Provide a correct Python 3 solution for this coding contest problem.
Given are two sequences A and B, both of length N. A and B are each sorted in the ascending order. Check if it is possible to reorder the terms of B so that for each i (1 \leq i \leq N) A_i \neq B_i holds, and if it is possible, output any of the reorderings that achieve it.
Constraints
* 1\leq N \leq 2 \times 10^5
* 1\leq A_i,B_i \leq N
* A and B are each sorted in the ascending order.
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
N
A_1 A_2 \cdots A_N
B_1 B_2 \cdots B_N
Output
If there exist no reorderings that satisfy the condition, print `No`.
If there exists a reordering that satisfies the condition, print `Yes` on the first line. After that, print a reordering of B on the second line, separating terms with a whitespace.
If there are multiple reorderings that satisfy the condition, you can print any of them.
Examples
Input
6
1 1 1 2 2 3
1 1 1 2 2 3
Output
Yes
2 2 3 1 1 1
Input
3
1 1 2
1 1 3
Output
No
Input
4
1 1 2 3
1 2 3 3
Output
Yes
3 3 1 2 | instruction | 0 | 78,865 | 12 | 157,730 |
"Correct Solution:
```
from bisect import bisect_left,bisect_right
n=int(input())
a=list(map(int,input().split()))
b=list(map(int,input().split()))
aset=set(a)
bset=set(b)
ans=0
for i in range(n):
if a[i] in bset:
ans=max(i-bisect_left(b,a[i]),ans)
b=(b+b+b)[n-ans-1:n+n-ans-1]
for i in range(n):
if a[i]==b[i]:
exit(print("No"))
print("Yes")
print(*b)
``` | output | 1 | 78,865 | 12 | 157,731 |
Provide a correct Python 3 solution for this coding contest problem.
Given are two sequences A and B, both of length N. A and B are each sorted in the ascending order. Check if it is possible to reorder the terms of B so that for each i (1 \leq i \leq N) A_i \neq B_i holds, and if it is possible, output any of the reorderings that achieve it.
Constraints
* 1\leq N \leq 2 \times 10^5
* 1\leq A_i,B_i \leq N
* A and B are each sorted in the ascending order.
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
N
A_1 A_2 \cdots A_N
B_1 B_2 \cdots B_N
Output
If there exist no reorderings that satisfy the condition, print `No`.
If there exists a reordering that satisfies the condition, print `Yes` on the first line. After that, print a reordering of B on the second line, separating terms with a whitespace.
If there are multiple reorderings that satisfy the condition, you can print any of them.
Examples
Input
6
1 1 1 2 2 3
1 1 1 2 2 3
Output
Yes
2 2 3 1 1 1
Input
3
1 1 2
1 1 3
Output
No
Input
4
1 1 2 3
1 2 3 3
Output
Yes
3 3 1 2 | instruction | 0 | 78,866 | 12 | 157,732 |
"Correct Solution:
```
def II():return int(input())
def LI():return list(map(int,input().split()))
from collections import Counter, deque
n=II()
a=LI()
b=LI()
ac=Counter(a)
bc=Counter(b)
abc=ac+bc
for i in abc.values():
if i>n:
print("No")
exit()
print("Yes")
a=deque(a)
b=deque(b)
ans=[]
b.rotate(n//2)
while a:
if a[0]!=b[0]:
a.popleft()
ans.append(b.popleft())
else:
b.rotate()
print(*ans)
``` | output | 1 | 78,866 | 12 | 157,733 |
Provide a correct Python 3 solution for this coding contest problem.
Given are two sequences A and B, both of length N. A and B are each sorted in the ascending order. Check if it is possible to reorder the terms of B so that for each i (1 \leq i \leq N) A_i \neq B_i holds, and if it is possible, output any of the reorderings that achieve it.
Constraints
* 1\leq N \leq 2 \times 10^5
* 1\leq A_i,B_i \leq N
* A and B are each sorted in the ascending order.
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
N
A_1 A_2 \cdots A_N
B_1 B_2 \cdots B_N
Output
If there exist no reorderings that satisfy the condition, print `No`.
If there exists a reordering that satisfies the condition, print `Yes` on the first line. After that, print a reordering of B on the second line, separating terms with a whitespace.
If there are multiple reorderings that satisfy the condition, you can print any of them.
Examples
Input
6
1 1 1 2 2 3
1 1 1 2 2 3
Output
Yes
2 2 3 1 1 1
Input
3
1 1 2
1 1 3
Output
No
Input
4
1 1 2 3
1 2 3 3
Output
Yes
3 3 1 2 | instruction | 0 | 78,867 | 12 | 157,734 |
"Correct Solution:
```
n=int(input())
a=list(map(int,input().split()))
b=list(map(int,input().split()))
from collections import Counter,deque
x,y=Counter(a),Counter(b)
for i in range(1,n+1):
if x[i]+y[i]>n:
print("No")
exit()
ans=b[::-1]
change=deque()
num=-1
now=deque()
for i in range(n):
if a[i]==ans[i]:
change.append(i)
num=ans[i]
else:
now.append(i)
if change==[]:
print("Yes")
print(" ".join(map(str,ans)))
exit()
while len(change):
q=now.popleft()
p=change.popleft()
if a[q]!=num and ans[q]!=num:
ans[q],ans[p]=ans[p],ans[q]
else:
change.appendleft(p)
print("Yes")
print(" ".join(map(str,ans)))
``` | output | 1 | 78,867 | 12 | 157,735 |
Provide tags and a correct Python 3 solution for this coding contest problem.
[Thanos sort](https://codegolf.stackexchange.com/questions/182221/implement-the-thanos-sorting-algorithm) is a supervillain sorting algorithm, which works as follows: if the array is not sorted, snap your fingers* to remove the first or the second half of the items, and repeat the process.
Given an input array, what is the size of the longest sorted array you can obtain from it using Thanos sort?
*Infinity Gauntlet required.
Input
The first line of input contains a single number n (1 ≤ n ≤ 16) — the size of the array. n is guaranteed to be a power of 2.
The second line of input contains n space-separated integers a_i (1 ≤ a_i ≤ 100) — the elements of the array.
Output
Return the maximal length of a sorted array you can obtain using Thanos sort. The elements of the array have to be sorted in non-decreasing order.
Examples
Input
4
1 2 2 4
Output
4
Input
8
11 12 1 2 13 14 3 4
Output
2
Input
4
7 6 5 4
Output
1
Note
In the first example the array is already sorted, so no finger snaps are required.
In the second example the array actually has a subarray of 4 sorted elements, but you can not remove elements from different sides of the array in one finger snap. Each time you have to remove either the whole first half or the whole second half, so you'll have to snap your fingers twice to get to a 2-element sorted array.
In the third example the array is sorted in decreasing order, so you can only save one element from the ultimate destruction. | instruction | 0 | 79,200 | 12 | 158,400 |
Tags: implementation
Correct Solution:
```
import math
n=int(input())
a=[int(n) for n in input().split()]
s=0
for _ in range(4):
if(sorted(a)==a):
s=len(a)
break
else:
count1=0
count2=0
for i in range(len(a)//2-1):
if(a[i]<a[i+1]):
count1+=1
for i in range(len(a)//2,len(a)-1):
if(a[i]<a[i+1]):
count2+=1
if(count1>count2):
del a[len(a)//2:len(a)]
else:
del a[0:len(a)//2]
print(s)
``` | output | 1 | 79,200 | 12 | 158,401 |
Provide tags and a correct Python 3 solution for this coding contest problem.
[Thanos sort](https://codegolf.stackexchange.com/questions/182221/implement-the-thanos-sorting-algorithm) is a supervillain sorting algorithm, which works as follows: if the array is not sorted, snap your fingers* to remove the first or the second half of the items, and repeat the process.
Given an input array, what is the size of the longest sorted array you can obtain from it using Thanos sort?
*Infinity Gauntlet required.
Input
The first line of input contains a single number n (1 ≤ n ≤ 16) — the size of the array. n is guaranteed to be a power of 2.
The second line of input contains n space-separated integers a_i (1 ≤ a_i ≤ 100) — the elements of the array.
Output
Return the maximal length of a sorted array you can obtain using Thanos sort. The elements of the array have to be sorted in non-decreasing order.
Examples
Input
4
1 2 2 4
Output
4
Input
8
11 12 1 2 13 14 3 4
Output
2
Input
4
7 6 5 4
Output
1
Note
In the first example the array is already sorted, so no finger snaps are required.
In the second example the array actually has a subarray of 4 sorted elements, but you can not remove elements from different sides of the array in one finger snap. Each time you have to remove either the whole first half or the whole second half, so you'll have to snap your fingers twice to get to a 2-element sorted array.
In the third example the array is sorted in decreasing order, so you can only save one element from the ultimate destruction. | instruction | 0 | 79,201 | 12 | 158,402 |
Tags: implementation
Correct Solution:
```
def thanos(k):
if k == sorted(k):
return (len(k))
else:
return max(thanos(k[:(len(k)//2)]), thanos(k[(len(k)//2):]))
t = int(input())
inp = [int(x) for x in input().split(" ", t)]
print(thanos(inp))
``` | output | 1 | 79,201 | 12 | 158,403 |
Provide tags and a correct Python 3 solution for this coding contest problem.
[Thanos sort](https://codegolf.stackexchange.com/questions/182221/implement-the-thanos-sorting-algorithm) is a supervillain sorting algorithm, which works as follows: if the array is not sorted, snap your fingers* to remove the first or the second half of the items, and repeat the process.
Given an input array, what is the size of the longest sorted array you can obtain from it using Thanos sort?
*Infinity Gauntlet required.
Input
The first line of input contains a single number n (1 ≤ n ≤ 16) — the size of the array. n is guaranteed to be a power of 2.
The second line of input contains n space-separated integers a_i (1 ≤ a_i ≤ 100) — the elements of the array.
Output
Return the maximal length of a sorted array you can obtain using Thanos sort. The elements of the array have to be sorted in non-decreasing order.
Examples
Input
4
1 2 2 4
Output
4
Input
8
11 12 1 2 13 14 3 4
Output
2
Input
4
7 6 5 4
Output
1
Note
In the first example the array is already sorted, so no finger snaps are required.
In the second example the array actually has a subarray of 4 sorted elements, but you can not remove elements from different sides of the array in one finger snap. Each time you have to remove either the whole first half or the whole second half, so you'll have to snap your fingers twice to get to a 2-element sorted array.
In the third example the array is sorted in decreasing order, so you can only save one element from the ultimate destruction. | instruction | 0 | 79,202 | 12 | 158,404 |
Tags: implementation
Correct Solution:
```
n = int(input())
l = list(map(int, input().split()))
if n == 1:
print(1)
elif n == 2:
if l == sorted(l):
print(2)
else:
print(1)
elif n == 4:
if l == sorted(l):
print(4)
else:
if l[:2] == sorted(l[:2]):
print(2)
elif l[2:] == sorted(l[2:]):
print(2)
else:
print(1)
elif n == 8:
if l == sorted(l):
print(8)
else:
if l[:4] == sorted(l[:4]):
print(4)
elif l[4:] == sorted(l[4:]):
print(4)
else:
if l[:2] == sorted(l[:2]):
print(2)
elif l[2:4] == sorted(l[2:4]):
print(2)
elif l[4:6] == sorted(l[4:6]):
print(2)
elif l[6:] == sorted(l[6:]):
print(2)
else:
print(1)
elif n == 16:
if l == sorted(l):
print(16)
else:
if l[:8] == sorted(l[:8]):
print(8)
elif l[8:] == sorted(l[8:]):
print(8)
else:
if l[:4] == sorted(l[:4]):
print(4)
elif l[4:8] == sorted(l[4:8]):
print(4)
elif l[8:12] == sorted(l[8:12]):
print(4)
elif l[12:] == sorted(l[12:]):
print(4)
else:
if l[:2] == sorted(l[:2]):
print(2)
elif l[2:4] == sorted(l[2:4]):
print(2)
elif l[4:6] == sorted(l[4:6]):
print(2)
elif l[6:8] == sorted(l[6:8]):
print(2)
elif l[8:10] == sorted(l[8:10]):
print(2)
elif l[10:12] == sorted(l[10:12]):
print(2)
elif l[12:14] == sorted(l[12:14]):
print(2)
elif l[14:] == sorted(l[14:]):
print(2)
else:
print(1)
``` | output | 1 | 79,202 | 12 | 158,405 |
Provide tags and a correct Python 3 solution for this coding contest problem.
[Thanos sort](https://codegolf.stackexchange.com/questions/182221/implement-the-thanos-sorting-algorithm) is a supervillain sorting algorithm, which works as follows: if the array is not sorted, snap your fingers* to remove the first or the second half of the items, and repeat the process.
Given an input array, what is the size of the longest sorted array you can obtain from it using Thanos sort?
*Infinity Gauntlet required.
Input
The first line of input contains a single number n (1 ≤ n ≤ 16) — the size of the array. n is guaranteed to be a power of 2.
The second line of input contains n space-separated integers a_i (1 ≤ a_i ≤ 100) — the elements of the array.
Output
Return the maximal length of a sorted array you can obtain using Thanos sort. The elements of the array have to be sorted in non-decreasing order.
Examples
Input
4
1 2 2 4
Output
4
Input
8
11 12 1 2 13 14 3 4
Output
2
Input
4
7 6 5 4
Output
1
Note
In the first example the array is already sorted, so no finger snaps are required.
In the second example the array actually has a subarray of 4 sorted elements, but you can not remove elements from different sides of the array in one finger snap. Each time you have to remove either the whole first half or the whole second half, so you'll have to snap your fingers twice to get to a 2-element sorted array.
In the third example the array is sorted in decreasing order, so you can only save one element from the ultimate destruction. | instruction | 0 | 79,203 | 12 | 158,406 |
Tags: implementation
Correct Solution:
```
n = int(input())
def sort(w):
new = [0]*(len(w) // 2)
for i in range(len(w)//2):
new [i] = w[i]
return new
def anti(w):
k=0
new = [0]*(len(w) // 2)
for i in range(len(w)//2,len(w)):
new [k] = w[i]
k+=1
return new
a=map(int,input().split()[:n])
a = list(a)
k=0
if a == sorted(a):
k=len(a)
elif len(a) == 2:
k=1
elif len(a) == 4:
q = sort(a)
w = anti(a)
if sorted(q) == q or sorted(w) == w:
k=2
else:
k=1
elif len(a)==8:
q = sort(a)
w = anti(a)
if sorted(q) == q or sorted(w) == w:
k=4
else:
t = sort(q)
r = anti(q)
r1 = sort(w)
t1 = anti(w)
if sorted(t) == t or sorted(r) == r:
k=2
elif sorted(r1) == r1 or sorted(t1) == t1:
k=2
else:
k=1
elif len(a) == 16:
q = sort(a)
w = anti(a)
if sorted(q) == q or sorted(w) == w:
k=8
else:
t = sort(q)
r = anti(q)
r1 = sort(w)
t1 = anti(w)
if sorted(t) == t or sorted(r) == r or sorted(r1) == r1 or sorted(t1) == t1:
k=4
else:
t2 = sort(t)
r2 = anti(t)
r3 = sort(r1)
t3 = anti(r1)
r4 = sort(t1)
t5 = anti(t1)
r5 = sort(r)
r6 = anti(r)
if sorted(t2) == t2 or sorted(r2) == r2 or sorted(r3)==r3 or sorted(t3) == t3 or sorted(r4)==r4 or sorted(t5)==t5 or sorted(r5)==r5 or sorted(r6) == r6:
k=2
else:
k=1
print(k)
``` | output | 1 | 79,203 | 12 | 158,407 |
Provide tags and a correct Python 3 solution for this coding contest problem.
[Thanos sort](https://codegolf.stackexchange.com/questions/182221/implement-the-thanos-sorting-algorithm) is a supervillain sorting algorithm, which works as follows: if the array is not sorted, snap your fingers* to remove the first or the second half of the items, and repeat the process.
Given an input array, what is the size of the longest sorted array you can obtain from it using Thanos sort?
*Infinity Gauntlet required.
Input
The first line of input contains a single number n (1 ≤ n ≤ 16) — the size of the array. n is guaranteed to be a power of 2.
The second line of input contains n space-separated integers a_i (1 ≤ a_i ≤ 100) — the elements of the array.
Output
Return the maximal length of a sorted array you can obtain using Thanos sort. The elements of the array have to be sorted in non-decreasing order.
Examples
Input
4
1 2 2 4
Output
4
Input
8
11 12 1 2 13 14 3 4
Output
2
Input
4
7 6 5 4
Output
1
Note
In the first example the array is already sorted, so no finger snaps are required.
In the second example the array actually has a subarray of 4 sorted elements, but you can not remove elements from different sides of the array in one finger snap. Each time you have to remove either the whole first half or the whole second half, so you'll have to snap your fingers twice to get to a 2-element sorted array.
In the third example the array is sorted in decreasing order, so you can only save one element from the ultimate destruction. | instruction | 0 | 79,204 | 12 | 158,408 |
Tags: implementation
Correct Solution:
```
n=int(input())
a=list(map(int,input().strip().split()))
if(a==sorted(a)):
print(n)
exit()
else:
b=[i for i in reversed(a)]
if(b==sorted(a)):
print(1)
exit()
x=n//2
c=[]
while(x!=1):
for i in range(0,n,x):
y=a[i:i+x]
if(y==sorted(y)):
c.append(len(y))
x=x//2
print(max(c))
``` | output | 1 | 79,204 | 12 | 158,409 |
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